Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	mhm.	8,595	1,661	[]
student	I	8,595	1,662	[]
student	what you	8,595	1,663	[]
student	OK, let's go through it. So basically for B, what they did is they did V equals pi R2H and it just did.	8,595	1,664	[]
student	12 pi equals pi R2H and is divided the pi on both sides. So the formula for B was R2H	8,595	1,665	[]
student	equals 12.	8,595	1,666	[]
volunteer	Same thing that you did, really. Uh.	8,595	1,667	[]
volunteer	I don't really see any difference. Yours just says H equals 12 overr 2.	8,595	1,668	[]
volunteer	but	8,595	1,669	[]
volunteer	OK	8,595	1,670	[]
student	So when they say they want a formula that relates H and R, do they mean that they want the HNR to be on one side, basically.	8,595	1,671	[]
volunteer	Well, I, I, I think both answers	8,595	1,672	[]
volunteer	are correct	8,595	1,673	[]
student	OK	8,595	1,674	[]
volunteer	I	8,595	1,675	[]
volunteer	find a formula that relates the height and the radius. Yours did that, and theirs does. I mean, both of them are really saying the same thing.	8,595	1,676	[]
student	Uh	8,595	1,677	[]
volunteer	They're the same equation that's written a little differently.	8,595	1,678	[]
volunteer	One says 12 equals hr squared and yours, we just decided.	8,595	1,679	[]
volunteer	you know, to say that H equals 12 over r squared. So I, I would assume that either answer would be acceptable.	8,595	1,680	[]
volunteer	I, I thought this answered it a little more directly by just solving for H, but	8,595	1,681	[]
student	OK. Yes, it's OK. And then for C, they did um	8,595	1,682	[]
student	instead of what we did, we, we looked at the volume. They never really look at the volume here like yet what they did was they did a equals pi k and then the um, they changed the art.	8,595	1,683	[]
student	to 12/8.	8,595	1,684	[]
student	and it is said that the area was 12 over h. So they then	8,595	1,685	[]
volunteer	Well, OK, so	8,595	1,686	[]
volunteer	um,	8,595	1,687	[]
student	at your age	8,595	1,688	[]
volunteer	they're, they're, they're basically putting in the constant right there. They they just decided	8,595	1,689	[]
student	Yeah right there	8,595	1,690	[]
volunteer	to put it right there	8,595	1,691	[]
volunteer	Again, any, anybody that would take off for what	8,595	1,692	[]
volunteer	you answered here	8,595	1,693	[]
volunteer	would be way off mark, I think.	8,595	1,694	[]
volunteer	They didn't say, you know, they did.	8,595	1,695	[]
volunteer	Anyhow	8,595	1,696	[]
volunteer	I find	8,595	1,697	[]
volunteer	the V over h to be a little more	8,595	1,698	[]
student	Yeah.	8,595	1,699	[]
volunteer	bright, but if you wanted to plug in the constant, you could right away and	8,595	1,700	[]
volunteer	with equivalent, in my opinion.	8,595	1,701	[]
volunteer	So.	8,595	1,702	[]
volunteer	hopefully	8,595	1,703	[]
volunteer	whoever looks at, you know, grading stuff like this, if you're writing it out, says, yeah, that's right.	8,595	1,704	[]
volunteer	So	8,595	1,705	[]
student	OK	8,595	1,706	[]
volunteer	OK	8,595	1,707	[]
student	Yeah, and then the answer was right for uh	8,595	1,708	[]
volunteer	So I don't think it's reasonable to expect to get the answer.	8,595	1,709	[]
student	and, but for like part E, what do you say?	8,595	1,710	[]
volunteer	Well, what, what I was saying there	8,595	1,711	[]
volunteer	is	8,595	1,712	[]
volunteer	I'm kind of repeating, but	8,595	1,713	[]
volunteer	I just stepped back from it and looked at your answers.	8,595	1,714	[]
volunteer	What does it mean about the cylinder?	8,595	1,715	[]
volunteer	Um,	8,595	1,716	[]
volunteer	the rate says that	8,595	1,717	[]
volunteer	the area must be increasing.	8,595	1,718	[]
volunteer	at a because the height is decreasing to give a constant volume.	8,595	1,719	[]
volunteer	So,	8,595	1,720	[]
volunteer	all I'm saying is, if the volume is to remain constant of the cylinder.	8,595	1,721	[]
volunteer	and the height is	8,595	1,722	[]
volunteer	decreasing	8,595	1,723	[]
volunteer	then	8,595	1,724	[]
volunteer	the area must be increasing.	8,595	1,725	[]
volunteer	And we computed it as 4 pi over 3 square meters.	8,595	1,726	[]
volunteer	per hour	8,595	1,727	[]
student	OK	8,595	1,728	[]
volunteer	That would be what I would say, write a sentence to explain what the **** found in DADT means about the cylinder. It just means	8,595	1,729	[]
volunteer	clearly, if you have a	8,595	1,730	[]
volunteer	constant volume	8,595	1,731	[]
volunteer	and your height is decreasing, then your cross-sectional area must be increasing.	8,595	1,732	[]
student	Right	8,595	1,733	[]
student	So, basically, if I think about it like visually, in the cylinder as like since the volume is staying the same, it's constant, but then since the height is like um	8,595	1,734	[]
student	is decreasing, right?	8,595	1,735	[]
volunteer	Yeah, and so the whole thing is getting fat, right? Because this thing	8,595	1,736	[]
student	It's basically in squished, right? But the area is increasing.	8,595	1,737	[]
student	Yeah	8,595	1,738	[]
volunteer	exactly. If you sat on it, you're exactly right that you're thinking right. If you sat on it, what would happen? It would squish and it would get wider, right?	8,595	1,739	[]
student	Right	8,595	1,740	[]
volunteer	So,	8,595	1,741	[]
volunteer	that you can say that exact kind of thing in your explanation I'd give it a 5 out of 5, you know.	8,595	1,742	[]
student	Mhm	8,595	1,743	[]
volunteer	Anyhow	8,595	1,744	[]
volunteer	one thing I always have a problem with is	8,595	1,745	[]
volunteer	teachers and our students who think that the book is always the correct right answer.	8,595	1,746	[]
volunteer	you know.	8,595	1,747	[]
volunteer	Sometimes it's in a different way or a different form.	8,595	1,748	[]
volunteer	uh, you know, it's not exactly the same ex written down. I mean, it, it's not, that's really not what's important. And the importance is that you get to the same answer with logic.	8,595	1,749	[]
volunteer	So	8,595	1,750	[]
student	Right	8,595	1,751	[]
volunteer	get hung up. Oh, the book says this, you know, well.	8,595	1,752	[]
volunteer	it, it's OK	8,595	1,753	[]
volunteer	There's other ways to say it.	8,595	1,754	[]
student	Right	8,595	1,755	[]
volunteer	All right	8,595	1,756	[]
student	OK	8,595	1,757	[]
volunteer	Well, I hope you do well and you got an exam coming, right?	8,595	1,758	[]
student	Right. It's on tomorrow.	8,595	1,759	[]
volunteer	All right. Well	8,595	1,760	[]

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