role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | its confusing | 9,248 | 5 | [] |
student | mr David | 9,248 | 6 | [
{
"pii_type": "PERSON",
"surrogate": "David",
"start": 3,
"end": 8
}
] |
volunteer | Uh, hi Maria | 9,248 | 7 | [
{
"pii_type": "PERSON",
"surrogate": "Maria",
"start": 7,
"end": 12
}
] |
volunteer | I just want to explain this to you, uh | 9,248 | 8 | [] |
volunteer | uh very shortly. | 9,248 | 9 | [] |
volunteer | to the area of uh parallelogram is found. | 9,248 | 10 | [] |
volunteer | by multiplying that | 9,248 | 11 | [] |
volunteer | base at the height. So the diagram I've drawn on the right. | 9,248 | 12 | [] |
volunteer | uh you can use the height. So we'll multiply 3 times 2. | 9,248 | 13 | [] |
volunteer | and | 9,248 | 14 | [] |
volunteer | and | 9,248 | 15 | [] |
volunteer | and you get 6. | 9,248 | 16 | [] |
volunteer | So if you sick | 9,248 | 17 | [] |
volunteer | 6 square centimeters. | 9,248 | 18 | [] |
volunteer | I hope you have understood that. | 9,248 | 19 | [] |
student | can you say it again please | 9,248 | 20 | [] |
student | i was puting headphones on | 9,248 | 21 | [] |
volunteer | ok | 9,248 | 22 | [] |
volunteer | OK, so, uh, I've drawn, uh, a diagram on the whiteboard. | 9,248 | 23 | [] |
volunteer | and it shows a parallelogram. | 9,248 | 24 | [] |
volunteer | So to find the area of | 9,248 | 25 | [] |
volunteer | uh the parallelogram. | 9,248 | 26 | [] |
volunteer | we are going to multiply the base. | 9,248 | 27 | [] |
volunteer | by its height. | 9,248 | 28 | [] |
volunteer | So when you look at our para parallelogram on the board. | 9,248 | 29 | [] |
volunteer | the base is 3 and the height is 2. | 9,248 | 30 | [] |
volunteer | So we multiply 3 by 2. | 9,248 | 31 | [] |
volunteer | and you get 6 square centimeters. So that is our area | 9,248 | 32 | [] |
student | ok | 9,248 | 33 | [] |
volunteer | So the height can sometimes be, be given on this other end, like, | 9,248 | 34 | [] |
volunteer | uh, we have 2 here. | 9,248 | 35 | [] |
volunteer | So this land is the same as as at length. | 9,248 | 36 | [] |
volunteer | this land. So it's still the same. We are going to use 3 and 2. So you must | 9,248 | 37 | [] |
volunteer | the height and that will give you the area. I think, uh, you've understood it well | 9,248 | 38 | [] |
student | ok | 9,248 | 39 | [] |
student | thanks can i try | 9,248 | 40 | [] |
volunteer | maybe you can draw one and we navigate that together | 9,248 | 41 | [] |
volunteer | Hi, how can I help? | 9,320 | 0 | [] |
student | Hii, So I have a test For AP Calc and I need help going over the review question | 9,320 | 1 | [] |
volunteer | Sounds good. I can help with that. Could you put the question on the board? | 9,320 | 2 | [] |
student | I meant question(S) | 9,320 | 3 | [] |
student | But I'll put up the first one here | 9,320 | 4 | [] |
volunteer | Good idea | 9,320 | 5 | [] |
volunteer | Do you know how to approach these? | 9,320 | 6 | [] |
volunteer | Or this one in particular? | 9,320 | 7 | [] |
student | To be honest I am completely clueless about how to solve these | 9,320 | 8 | [] |
volunteer | We all start somewhere, that's fine. Do you know how to differentiate a polynomial, like -6x^2+4x-8? | 9,320 | 9 | [] |
student | yes | 9,320 | 10 | [] |
volunteer | Do you know how to use chain rule? | 9,320 | 11 | [] |
student | no | 9,320 | 12 | [] |
volunteer | Then let's go over that first | 9,320 | 13 | [] |
student | alright | 9,320 | 14 | [] |
volunteer | Do you know the formula for chain rule? | 9,320 | 15 | [] |
student | I don't memeorize it but i do get the idea of it | 9,320 | 16 | [] |
student | like when to use | 9,320 | 17 | [] |
volunteer | For your test, and the Math Fundamentals Final exam, it will be a good idea to memorize it. You can use it whenever you see something that you could express in the form of f(g(x)), a function composition. | 9,320 | 18 | [
{
"pii_type": "COURSE",
"surrogate": "Math Fundamentals Final",
"start": 23,
"end": 46
}
] |
volunteer | For the function in the problem, can you identify the outer and inner functions? | 9,320 | 19 | [] |
student | yes | 9,320 | 20 | [] |
volunteer | Let's start there | 9,320 | 21 | [] |
student | would it look like something like this | 9,320 | 22 | [] |
volunteer | You're really close | 9,320 | 23 | [] |
volunteer | The -12x and the 4 are correct, but multiplying them isn't really right | 9,320 | 24 | [] |
volunteer | Also, I think you missed the 5 in the front | 9,320 | 25 | [] |
volunteer | Oh wait never mind | 9,320 | 26 | [] |
volunteer | That part is good | 9,320 | 27 | [] |
volunteer | I just didn't realize you canceled them already | 9,320 | 28 | [] |
student | yeah | 9,320 | 29 | [] |
volunteer | But the (-12x)(4) is still not quite right | 9,320 | 30 | [] |
volunteer | How could we fix it? | 9,320 | 31 | [] |
student | do i times them to each other? | 9,320 | 32 | [] |
volunteer | That's what you have here | 9,320 | 33 | [] |
volunteer | There's one formula that will help: the derivative of f(x)+g(x) is f'(x)+g'(x) | 9,320 | 34 | [] |
volunteer | Can you identify f and g in the case of -6x^2+4x? | 9,320 | 35 | [] |
volunteer | I might have confused you a bit with using the same variables for both | 9,320 | 36 | [] |
volunteer | Those are the outer and inner functions | 9,320 | 37 | [] |
volunteer | I'll explain with a and b so as not to confuse you | 9,320 | 38 | [] |
volunteer | The derivative of a(x)+b(x) is a'(x)+b'(x) | 9,320 | 39 | [] |
volunteer | Can you identify a and b in -6x^2+4x-8? | 9,320 | 40 | [] |
student | ohh okay | 9,320 | 41 | [] |
volunteer | Perfect! | 9,320 | 42 | [] |
student | so then i add them | 9,320 | 43 | [] |
volunteer | Yes | 9,320 | 44 | [] |
volunteer | That is right | 9,320 | 45 | [] |
student | ao it would be -8x | 9,320 | 46 | [] |
volunteer | Not quite | 9,320 | 47 | [] |
volunteer | -12x+4 is just -12x+4, you can't combine like terms because 4 doesn't have an x in it | 9,320 | 48 | [] |
volunteer | -12x+4x would be -8x | 9,320 | 49 | [] |
volunteer | -12x+4 is just -12x+4 | 9,320 | 50 | [] |
student | okay okay yeah that's true | 9,320 | 51 | [] |
student | ok so let me simplify it | 9,320 | 52 | [] |
volunteer | Don't simplify at all, now or on the Geometry Midterm | 9,320 | 53 | [
{
"pii_type": "COURSE",
"surrogate": "Geometry Midterm",
"start": 37,
"end": 53
}
] |
student | ohh so it's just this then? | 9,320 | 54 | [] |
volunteer | Yes but with one fix | 9,320 | 55 | [] |
volunteer | I'll show you | 9,320 | 56 | [] |
volunteer | Otherwise it looks like you're adding the 4 on afterwards | 9,320 | 57 | [] |
volunteer | Another way to do it would have been to skip one set of parentheses in the first place (I'll color them red) | 9,320 | 58 | [] |
volunteer | Or I guess orange | 9,320 | 59 | [] |
volunteer | But on the Algebra Quiz, don't simplify either numbers or expressions unless it's an MCQ and your answer isn't one of the ones listed | 9,320 | 60 | [
{
"pii_type": "COURSE",
"surrogate": "Algebra Quiz",
"start": 11,
"end": 23
}
] |
volunteer | *multiple choice question | 9,320 | 61 | [] |
student | alright | 9,320 | 62 | [] |
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