[ { "id": "#48530", "title": "Diary Thief", "fun": 3.42, "difficulty": 2.07, "author": "alexaehrin", "desc": "The Scoop\r\nTristan's sister Angela and her four friends love to share their most recent diary entries with each other at sleepovers. This last sleepover, Tristan was able to snag each of the girls' diaries after they fell asleep. He flipped through them and found that each girl had a different crush, a different favorite shade of nail polish, and a different preference in ice cream flavors - and each of them had a big, juicy secret! See if you can figure out what he learned about each of his sister's friends - and his sister.\n\r\nThe Choices\r\nGirls: Angela, Mandy, Savannah, Alyssa, and Lily\r\nCrushes: Josh, Noah, Luke, Ben, and Sam\r\nNail Polish Shades: Lavender, Lime, Banana, Sky, and Crimson\r\nIce Cream Flavors: Rocky Road, Rainbow Sherbet, Cookie Dough, Reese's Peanut Butter, and Raspberry Cheesecake\r\nJuicy Secrets: Still sleeps with a blankie, Loves lima beans, Hates Justin Bieber, Is really into cars, and Wants to be a lunch lady\n\r\nThe Clues\r\nTristan read five different entries for January 7th. One said, \"Noah said, 'Nice hair, Savannah,' and I felt special.\" Another said, \"My nails are purple again, just like I like them.\" A third said, \"I wish Luke would look at me.\" The fourth said, \"I lost my beloved blankie this morning.\" The last said, \"I'm dying for some more of that rainbow sherbet.\"\n\r\n\"January 8th. Dear Diary, I accidentally chipped one of my perfect, lime-green nails today while doing my daily private anti-Justin Bieber ritual.\"\n\r\n\"January 9th. Dear Diary, Josh caught me examining his awesome antique Chevrolet after school today. I guess I was kind of hoping he would.\"\n\r\n\"January 10th. Dear Diary, Angela was writing a love note today. I tried glancing over her shoulder, but all I caught was the second letter of its recipient's name, which looked like either a U or an A, and something about being a lunch lady before she yanked it away.\"\n\r\n\"January 11th. Dear Diary, I hope Sam likes the color red...I also hope he doesn't mind girls who still sleep with blankies...\"\n\r\n\"January 12th. Dear Diary, I think it's funny that both me and Savannah like nail polishes that are named after fruits. Love, Alyssa.\"\n\r\n\"January 13th. Dear Diary, I saw Sam eating Reese's Peanut Butter ice cream yesterday. Could this be a sign that we're meant to be? Love, Mandy.\"\n\r\n\"January 14th. Dear Diary, I just noticed that the name of my favorite shade of nail polish has something majorly in common with my name, and Alyssa's favorite shade starts with the same letter as her crush's name.\"\n\r\n\"January 15th. Dear Diary, The girls were over at my house last night, and someone flicked cookie dough ice cream at me. It couldn't have been Angela, who will only eat raspberry cheesecake ice cream, and Savannah was in the bathroom...\"", "hint": "\"Lily\" and \"Lavender\" are both flowers, which gives them \"something majorly in common.\"", "answer": "Angela likes Luke, Raspberry Cheesecake ice cream, and Sky nail polish, and she wants to be a lunch lady when she grows up.\r\nMandy likes Sam, Reese's Peanut Butter ice cream, and Crimson nail polish, and she still sleeps with a blankie.\r\nSavannah likes Noah, Rocky Road ice cream, and Lime nail polish, and she hates Justin Bieber.\r\nAlyssa likes Ben, Rainbow Sherbet ice cream, and Banana nail polish, and she loves lima beans.\r\nLily likes Josh, Cookie Dough ice cream, and Lavender nail polish, and she is really into cars.", "category": "Logic-Grid", "date": "03/02/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Scoop\r\nTristan's sister Angela and her four friends love to share their most recent diary entries with each other at sleepovers. This last sleepover, Tristan was able to snag each of the girls' diaries after they fell asleep. He flipped through them and found that each girl had a different crush, a different favorite shade of nail polish, and a different preference in ice cream flavors - and each of them had a big, juicy secret! See if you can figure out what he learned about each of his sister's friends - and his sister.\n\r\nThe Choices\r\nGirls: Angela, Mandy, Savannah, Alyssa, and Lily\r\nCrushes: Josh, Noah, Luke, Ben, and Sam\r\nNail Polish Shades: Lavender, Lime, Banana, Sky, and Crimson\r\nIce Cream Flavors: Rocky Road, Rainbow Sherbet, Cookie Dough, Reese's Peanut Butter, and Raspberry Cheesecake\r\nJuicy Secrets: Still sleeps with a blankie, Loves lima beans, Hates Justin Bieber, Is really into cars, and Wants to be a lunch lady\n\r\nThe Clues\r\nTristan read five different entries for January 7th. One said, \"Noah said, 'Nice hair, Savannah,' and I felt special.\" Another said, \"My nails are purple again, just like I like them.\" A third said, \"I wish Luke would look at me.\" The fourth said, \"I lost my beloved blankie this morning.\" The last said, \"I'm dying for some more of that rainbow sherbet.\"\n\r\n\"January 8th. Dear Diary, I accidentally chipped one of my perfect, lime-green nails today while doing my daily private anti-Justin Bieber ritual.\"\n\r\n\"January 9th. Dear Diary, Josh caught me examining his awesome antique Chevrolet after school today. I guess I was kind of hoping he would.\"\n\r\n\"January 10th. Dear Diary, Angela was writing a love note today. I tried glancing over her shoulder, but all I caught was the second letter of its recipient's name, which looked like either a U or an A, and something about being a lunch lady before she yanked it away.\"\n\r\n\"January 11th. Dear Diary, I hope Sam likes the color red...I also hope he doesn't mind girls who still sleep with blankies...\"\n\r\n\"January 12th. Dear Diary, I think it's funny that both me and Savannah like nail polishes that are named after fruits. Love, Alyssa.\"\n\r\n\"January 13th. Dear Diary, I saw Sam eating Reese's Peanut Butter ice cream yesterday. Could this be a sign that we're meant to be? Love, Mandy.\"\n\r\n\"January 14th. Dear Diary, I just noticed that the name of my favorite shade of nail polish has something majorly in common with my name, and Alyssa's favorite shade starts with the same letter as her crush's name.\"\n\r\n\"January 15th. Dear Diary, The girls were over at my house last night, and someone flicked cookie dough ice cream at me. It couldn't have been Angela, who will only eat raspberry cheesecake ice cream, and Savannah was in the bathroom...\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAngela likes Luke, Raspberry Cheesecake ice cream, and Sky nail polish, and she wants to be a lunch lady when she grows up.\r\nMandy likes Sam, Reese's Peanut Butter ice cream, and Crimson nail polish, and she still sleeps with a blankie.\r\nSavannah likes Noah, Rocky Road ice cream, and Lime nail polish, and she hates Justin Bieber.\r\nAlyssa likes Ben, Rainbow Sherbet ice cream, and Banana nail polish, and she loves lima beans.\r\nLily likes Josh, Cookie Dough ice cream, and Lavender nail polish, and she is really into cars.\n<|im_start|>answer\nAngela likes Luke, Raspberry Cheesecake ice cream, and Sky nail polish, and she wants to be a lunch lady when she grows up.\r\nMandy likes Sam, Reese's Peanut Butter ice cream, and Crimson nail polish, and she still sleeps with a blankie.\r\nSavannah likes Noah, Rocky Road ice cream, and Lime nail polish, and she hates Justin Bieber.\r\nAlyssa likes Ben, Rainbow Sherbet ice cream, and Banana nail polish, and she loves lima beans.\r\nLily likes Josh, Cookie Dough ice cream, and Lavender nail polish, and she is really into cars.\n<|im_end|>" }, { "id": "#52225", "title": "Mr. Froopaloop's Fiance", "fun": 3.37, "difficulty": 2.37, "author": "wimpykidfan37", "desc": "Hans Ernest Froopaloop, Jr. will marry one of three women: Audrey, Brenda, and Charlotte. Here are some facts:\n\r\n1. Of Audrey and Brenda:\r\na. Either they both have blue eyes or neither has blue eyes.\r\nb. One has red hair and the other does not.\n\r\n2. Of Audrey and Charlotte:\r\na. Either they both have red hair or neither has red hair.\r\nb. One is 5'11\" and the other is not.\n\r\n3. Of Brenda and Charlotte:\r\na. One has blue eyes and the other does not.\r\nb. One is 5'11\" and the other is not.\n\r\n4. Of the three characteristics; blue eyes, red hair and 5'11\":\r\na. If any of the three women has exactly two of the three characteristics, Mr. Froopaloop will marry the one with the least number of characteristics.\r\nb. If any of the three women has exactly one of the three characteristics, Mr. Froopaloop will marry the one with the greatest number of characteristics.\n\r\nWho will Mr. Froopaloop marry?", "hint": "No hint available.", "answer": "Mr. Froopaloop will marry Charlotte.\n\r\nFacts 1a and 3a tell us that Charlotte is either the only one with blue eyes or the only one without blue eyes. Facts 1b and 2a tell us that Brenda is either the only one with red hair or the only one without red hair. Facts 2b and 3b tell us that Charlotte is either the only one who is 5'11\" or the only one who isn't 5'11\". Fact 4 tells us that no one woman can have one characteristic while another has two characteristics. This gives us two scenarios:\n\r\n1. Audrey has blue eyes, does not have red hair, and is 5'11\". Brenda has blue eyes, red hair, and is 5'11\". Charlotte does not have blue eyes, does not have red hair, and is not 5'11\".\r\n2. Audrey does not have blue eyes, has red hair, and is not 5'11\". Brenda does not have blue eyes, does not have red hair, and is not 5'11\". Charlotte has blue eyes, red hair, and is 5'11\".\n\r\nFact 4a tells us that in scenario 1, Mr. Froopaloop will marry Charlotte. Fact 4b tells us that in scenario 2, Mr. Froopaloop will marry...Charlotte.", "category": "Logic", "date": "06/21/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHans Ernest Froopaloop, Jr. will marry one of three women: Audrey, Brenda, and Charlotte. Here are some facts:\n\r\n1. Of Audrey and Brenda:\r\na. Either they both have blue eyes or neither has blue eyes.\r\nb. One has red hair and the other does not.\n\r\n2. Of Audrey and Charlotte:\r\na. Either they both have red hair or neither has red hair.\r\nb. One is 5'11\" and the other is not.\n\r\n3. Of Brenda and Charlotte:\r\na. One has blue eyes and the other does not.\r\nb. One is 5'11\" and the other is not.\n\r\n4. Of the three characteristics; blue eyes, red hair and 5'11\":\r\na. If any of the three women has exactly two of the three characteristics, Mr. Froopaloop will marry the one with the least number of characteristics.\r\nb. If any of the three women has exactly one of the three characteristics, Mr. Froopaloop will marry the one with the greatest number of characteristics.\n\r\nWho will Mr. Froopaloop marry?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Froopaloop will marry Charlotte.\n\r\nFacts 1a and 3a tell us that Charlotte is either the only one with blue eyes or the only one without blue eyes. Facts 1b and 2a tell us that Brenda is either the only one with red hair or the only one without red hair. Facts 2b and 3b tell us that Charlotte is either the only one who is 5'11\" or the only one who isn't 5'11\". Fact 4 tells us that no one woman can have one characteristic while another has two characteristics. This gives us two scenarios:\n\r\n1. Audrey has blue eyes, does not have red hair, and is 5'11\". Brenda has blue eyes, red hair, and is 5'11\". Charlotte does not have blue eyes, does not have red hair, and is not 5'11\".\r\n2. Audrey does not have blue eyes, has red hair, and is not 5'11\". Brenda does not have blue eyes, does not have red hair, and is not 5'11\". Charlotte has blue eyes, red hair, and is 5'11\".\n\r\nFact 4a tells us that in scenario 1, Mr. Froopaloop will marry Charlotte. Fact 4b tells us that in scenario 2, Mr. Froopaloop will marry...Charlotte.\n<|im_start|>answer\nMr. Froopaloop will marry Charlotte.\n\r\nFacts 1a and 3a tell us that Charlotte is either the only one with blue eyes or the only one without blue eyes. Facts 1b and 2a tell us that Brenda is either the only one with red hair or the only one without red hair. Facts 2b and 3b tell us that Charlotte is either the only one who is 5'11\" or the only one who isn't 5'11\". Fact 4 tells us that no one woman can have one characteristic while another has two characteristics. This gives us two scenarios:\n\r\n1. Audrey has blue eyes, does not have red hair, and is 5'11\". Brenda has blue eyes, red hair, and is 5'11\". Charlotte does not have blue eyes, does not have red hair, and is not 5'11\".\r\n2. Audrey does not have blue eyes, has red hair, and is not 5'11\". Brenda does not have blue eyes, does not have red hair, and is not 5'11\". Charlotte has blue eyes, red hair, and is 5'11\".\n\r\nFact 4a tells us that in scenario 1, Mr. Froopaloop will marry Charlotte. Fact 4b tells us that in scenario 2, Mr. Froopaloop will marry...Charlotte.\n<|im_end|>" }, { "id": "#48272", "title": "Let The Games Begin", "fun": 3.36, "difficulty": 2.73, "author": "harmonize9", "desc": "Assassin is a popular game on college campuses. The game consists of several players trying to eliminate the others by means of squirting them with water pistols in order to be the last survivor. Once hit, the player is out of the game. Game play is fair play at all times and all locations, and tends to last several days depending on the number of participants and their stealth. At Troyhill University, 5 students participated in a game that only lasted four days. Can you determine each player's first name, their color, their assassin alias, how they were eliminated, and their major?\n\r\nNames: Liam, Anabel, Bella, Oliver, Ethan\r\nColors: Red, Green, Blue, Purple, Black\r\nAlias: Captain Dawn, Night Stalker, Dark Elf, McStealth, Billy\r\nCapture: Caught at weekly study group, Caught helping friend with car trouble, Ambushed during sleep, Caught on the way to class, Winner\r\nMajor: Economics, Biology, Art History, Sociology, Psychology\n\r\nMONDAY: Liam, the girl named Captain Dawn, and the person in purple avoided any action that day. The psychology major was able to easily catch Ethan because she already had a study group meeting with him that day. Since it was a weekly engagement, he didn't suspect a thing. Goodbye red player.\n\r\nTUESDAY: Everyone tried to get in on the action today. The girl masquerading as the Dark Elf (who was wearing either black or red) and the sociology major lived to see another day. The purple player was able to catch the obliging yet naive green player by calling her and pretending he had car trouble.\n\r\nWEDNESDAY: The biology major (who was still \"alive\") was surprised to hear that the Psychology major, who wasn't Anabel the art history major, ambushed Night Stalker as he slept in his dorm.\n\r\nTHURSDAY: The black player was declared the victor after luckily spotting \"Billy\" on his way to Mammalian Physiology, a class required by his major.", "hint": "All names are conventional for their gender.\r\nMammalian physiology is a course that biology majors would take.", "answer": "Liam, Blue, Night Stalker, Ambush, Sociology\r\nAnabel, Green, Captain Dawn, Car, Art History\r\nBella, Black, Dark Elf, Winner, Psychology\r\nOliver, Purple, Billy, Class, Biology\r\nEthan, Red, McStealth, Study Group, Economics", "category": "Logic-Grid", "date": "12/08/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAssassin is a popular game on college campuses. The game consists of several players trying to eliminate the others by means of squirting them with water pistols in order to be the last survivor. Once hit, the player is out of the game. Game play is fair play at all times and all locations, and tends to last several days depending on the number of participants and their stealth. At Troyhill University, 5 students participated in a game that only lasted four days. Can you determine each player's first name, their color, their assassin alias, how they were eliminated, and their major?\n\r\nNames: Liam, Anabel, Bella, Oliver, Ethan\r\nColors: Red, Green, Blue, Purple, Black\r\nAlias: Captain Dawn, Night Stalker, Dark Elf, McStealth, Billy\r\nCapture: Caught at weekly study group, Caught helping friend with car trouble, Ambushed during sleep, Caught on the way to class, Winner\r\nMajor: Economics, Biology, Art History, Sociology, Psychology\n\r\nMONDAY: Liam, the girl named Captain Dawn, and the person in purple avoided any action that day. The psychology major was able to easily catch Ethan because she already had a study group meeting with him that day. Since it was a weekly engagement, he didn't suspect a thing. Goodbye red player.\n\r\nTUESDAY: Everyone tried to get in on the action today. The girl masquerading as the Dark Elf (who was wearing either black or red) and the sociology major lived to see another day. The purple player was able to catch the obliging yet naive green player by calling her and pretending he had car trouble.\n\r\nWEDNESDAY: The biology major (who was still \"alive\") was surprised to hear that the Psychology major, who wasn't Anabel the art history major, ambushed Night Stalker as he slept in his dorm.\n\r\nTHURSDAY: The black player was declared the victor after luckily spotting \"Billy\" on his way to Mammalian Physiology, a class required by his major.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLiam, Blue, Night Stalker, Ambush, Sociology\r\nAnabel, Green, Captain Dawn, Car, Art History\r\nBella, Black, Dark Elf, Winner, Psychology\r\nOliver, Purple, Billy, Class, Biology\r\nEthan, Red, McStealth, Study Group, Economics\n<|im_start|>answer\nLiam, Blue, Night Stalker, Ambush, Sociology\r\nAnabel, Green, Captain Dawn, Car, Art History\r\nBella, Black, Dark Elf, Winner, Psychology\r\nOliver, Purple, Billy, Class, Biology\r\nEthan, Red, McStealth, Study Group, Economics\n<|im_end|>" }, { "id": "#30628", "title": "Radical Rush", "fun": 3.31, "difficulty": 2.7600000000000002, "author": "Question_Mark", "desc": "Question Mark is the host of a new game show called \"Radical Rush\". It is a game of 4 rounds. A logic round, a rebus round, a mathematics round and a final face-off. One player is eliminated after each round, with the last player left being the winner. Each player is color-coded. Now you must work out the full names of the contestants, the age of the contestants, their color-code and which round they were eliminated in (and who won).\n\r\nFirst names: David, Joanne, Richard, Xavier, Yvette\r\nLast names: Bridge, Hall, Rade, Richburgh, Sands\r\nAges: 22, 24, 26, 29, 33\r\nColor-codes: Red, Blue, Green, Yellow, Orange\r\nRound Eliminated: Logic, Rebus, Maths, Face-off, Winner\n\r\nRound 1 (LOGIC): This round was straight forward for Xavier, Miss Bridge and the player aged 29. The green player and the player aged 26 did not find this round as easy. It was a close call but in the end, the yellow player was eliminated.\n\r\nRound 2 (REBUS): This round was slightly harder, however it was a walk in the park for Richard, who came in first place for this round. Yvette, Mr Rade and the red player did not find this round as easy. However, after she realised what she was doing wrong, The 22-year-old quickly took second place. Now it was just up to Xavier and the 29-year-old, however it was all over for Mr Rade.\n\r\nRound 3 (MATHEMATICS): Once again, the difficulty level increases as the remaining three players try their math skills. No-one seemed to do particularly well here. The first place finisher was Miss Bridge. The battle for a spot in the Face-off was between Xavier and the green player. He put everything he knew into this round, however it wasn't enough to save Mr Hall, our unfortunate 33-year-old.\n\r\nFace-off: Two players remain with the same goal: to become the very first winner of \"Radical Rush\". The 22-year-old and Mr Richburgh must race each-other in a maze. Whoever reaches the end first, wins the game. It was a race too close to call, however the red player was fast enough to steal victory from the very unfortunate orange player.", "hint": "No hint available.", "answer": "In order of elimination:\n\r\nROUND 1: Logic\r\nJoanne Sands, 26, Yellow\r\nROUND 2: Rebus\r\nDavid Rade, 29, Blue\r\nROUND 3: Mathematics\r\nRichard Hall, 33, Green\r\nROUND 4: Face-off\r\nYvette Bridge, 22, Orange\r\nWINNER\r\nXavier Richburgh, 24, Red\n\r\nIn round 1, we know that Xavier and Miss Bridge are not 26 and 29. Nor are they the green player. At the moment, it is unclear who the yellow player is.\n\r\nIt is not immediately clear who was eliminated from round 1. However we do know that Richard, Yvette and Xavier survived. We know that Richard is not Mr. Rade, because Mr Rade lost round 2, and Richard won. \n\r\nIn round 3, we find out that David was eliminated in round 2, because we know that Richard and Yvette made it to round 3, however we were unsure of Xavier. Although \"Xavier and the green player\" tells us that Xavier made it to round 3. It also tells us that Richard is the green player, and that Joanne is the yellow player and was eliminated in round 1, and tells us that Yvette is 22.\n\r\nIn the Face-off, we know that Yvette and one other player is left. That player could be Richard or Xavier. The player is red. We already know that Richard is green, so he was eliminated in round 3. However this doesn't tell us who the winner is. Well, in round 2, you can tell that Yvette is not the red player, so that means that she is the orange player and Xavier is red, and Xavier won.\n\r\nYou can also gather other clues with the information.", "category": "Logic-Grid", "date": "05/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuestion Mark is the host of a new game show called \"Radical Rush\". It is a game of 4 rounds. A logic round, a rebus round, a mathematics round and a final face-off. One player is eliminated after each round, with the last player left being the winner. Each player is color-coded. Now you must work out the full names of the contestants, the age of the contestants, their color-code and which round they were eliminated in (and who won).\n\r\nFirst names: David, Joanne, Richard, Xavier, Yvette\r\nLast names: Bridge, Hall, Rade, Richburgh, Sands\r\nAges: 22, 24, 26, 29, 33\r\nColor-codes: Red, Blue, Green, Yellow, Orange\r\nRound Eliminated: Logic, Rebus, Maths, Face-off, Winner\n\r\nRound 1 (LOGIC): This round was straight forward for Xavier, Miss Bridge and the player aged 29. The green player and the player aged 26 did not find this round as easy. It was a close call but in the end, the yellow player was eliminated.\n\r\nRound 2 (REBUS): This round was slightly harder, however it was a walk in the park for Richard, who came in first place for this round. Yvette, Mr Rade and the red player did not find this round as easy. However, after she realised what she was doing wrong, The 22-year-old quickly took second place. Now it was just up to Xavier and the 29-year-old, however it was all over for Mr Rade.\n\r\nRound 3 (MATHEMATICS): Once again, the difficulty level increases as the remaining three players try their math skills. No-one seemed to do particularly well here. The first place finisher was Miss Bridge. The battle for a spot in the Face-off was between Xavier and the green player. He put everything he knew into this round, however it wasn't enough to save Mr Hall, our unfortunate 33-year-old.\n\r\nFace-off: Two players remain with the same goal: to become the very first winner of \"Radical Rush\". The 22-year-old and Mr Richburgh must race each-other in a maze. Whoever reaches the end first, wins the game. It was a race too close to call, however the red player was fast enough to steal victory from the very unfortunate orange player.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn order of elimination:\n\r\nROUND 1: Logic\r\nJoanne Sands, 26, Yellow\r\nROUND 2: Rebus\r\nDavid Rade, 29, Blue\r\nROUND 3: Mathematics\r\nRichard Hall, 33, Green\r\nROUND 4: Face-off\r\nYvette Bridge, 22, Orange\r\nWINNER\r\nXavier Richburgh, 24, Red\n\r\nIn round 1, we know that Xavier and Miss Bridge are not 26 and 29. Nor are they the green player. At the moment, it is unclear who the yellow player is.\n\r\nIt is not immediately clear who was eliminated from round 1. However we do know that Richard, Yvette and Xavier survived. We know that Richard is not Mr. Rade, because Mr Rade lost round 2, and Richard won. \n\r\nIn round 3, we find out that David was eliminated in round 2, because we know that Richard and Yvette made it to round 3, however we were unsure of Xavier. Although \"Xavier and the green player\" tells us that Xavier made it to round 3. It also tells us that Richard is the green player, and that Joanne is the yellow player and was eliminated in round 1, and tells us that Yvette is 22.\n\r\nIn the Face-off, we know that Yvette and one other player is left. That player could be Richard or Xavier. The player is red. We already know that Richard is green, so he was eliminated in round 3. However this doesn't tell us who the winner is. Well, in round 2, you can tell that Yvette is not the red player, so that means that she is the orange player and Xavier is red, and Xavier won.\n\r\nYou can also gather other clues with the information.\n<|im_start|>answer\nIn order of elimination:\n\r\nROUND 1: Logic\r\nJoanne Sands, 26, Yellow\r\nROUND 2: Rebus\r\nDavid Rade, 29, Blue\r\nROUND 3: Mathematics\r\nRichard Hall, 33, Green\r\nROUND 4: Face-off\r\nYvette Bridge, 22, Orange\r\nWINNER\r\nXavier Richburgh, 24, Red\n\r\nIn round 1, we know that Xavier and Miss Bridge are not 26 and 29. Nor are they the green player. At the moment, it is unclear who the yellow player is.\n\r\nIt is not immediately clear who was eliminated from round 1. However we do know that Richard, Yvette and Xavier survived. We know that Richard is not Mr. Rade, because Mr Rade lost round 2, and Richard won. \n\r\nIn round 3, we find out that David was eliminated in round 2, because we know that Richard and Yvette made it to round 3, however we were unsure of Xavier. Although \"Xavier and the green player\" tells us that Xavier made it to round 3. It also tells us that Richard is the green player, and that Joanne is the yellow player and was eliminated in round 1, and tells us that Yvette is 22.\n\r\nIn the Face-off, we know that Yvette and one other player is left. That player could be Richard or Xavier. The player is red. We already know that Richard is green, so he was eliminated in round 3. However this doesn't tell us who the winner is. Well, in round 2, you can tell that Yvette is not the red player, so that means that she is the orange player and Xavier is red, and Xavier won.\n\r\nYou can also gather other clues with the information.\n<|im_end|>" }, { "id": "#50710", "title": "Snail Races", "fun": 3.31, "difficulty": 2.58, "author": "LanceAlot", "desc": "People have gathered from around the world to witness the 2015 snail races. Each snail was handpicked by its country to race its way across the brutal 10cm track. Try to figure out the finishing time, country of origin, and shell color for each of the five snails. Don't be discouraged if it takes a while to solve, this is a snail race after all. \n\n\r\n1. Of Todd and the snail with the teal shell, one finished in 24 minutes and the other is from Mexico.\n\r\n2. The snail from Mexico finished 3 minutes after the snail with the lime shell, who finished 1 minute before the snail with the silver shell (who wasn't Hank).\n\r\n3. The snail from USA finished 2 minutes before Kipp, who finished some time before the snail from Spain. \n\r\n4. Of Ralph and the Spain contestant one had the fastest time and the other had the violet shell.\n\r\n5. The snail from Canada was either the one with the teal shell or the one who finished in 25 minutes.", "hint": "No hint available.", "answer": "Hank, 26, Spain, violet\r\nMike, 23, China, silver\r\nKipp, 24, Canada, teal\r\nRalph, 22, USA, lime\r\nTodd, 25, Mexico, grey", "category": "Logic-Grid", "date": "10/19/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPeople have gathered from around the world to witness the 2015 snail races. Each snail was handpicked by its country to race its way across the brutal 10cm track. Try to figure out the finishing time, country of origin, and shell color for each of the five snails. Don't be discouraged if it takes a while to solve, this is a snail race after all. \n\n\r\n1. Of Todd and the snail with the teal shell, one finished in 24 minutes and the other is from Mexico.\n\r\n2. The snail from Mexico finished 3 minutes after the snail with the lime shell, who finished 1 minute before the snail with the silver shell (who wasn't Hank).\n\r\n3. The snail from USA finished 2 minutes before Kipp, who finished some time before the snail from Spain. \n\r\n4. Of Ralph and the Spain contestant one had the fastest time and the other had the violet shell.\n\r\n5. The snail from Canada was either the one with the teal shell or the one who finished in 25 minutes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHank, 26, Spain, violet\r\nMike, 23, China, silver\r\nKipp, 24, Canada, teal\r\nRalph, 22, USA, lime\r\nTodd, 25, Mexico, grey\n<|im_start|>answer\nHank, 26, Spain, violet\r\nMike, 23, China, silver\r\nKipp, 24, Canada, teal\r\nRalph, 22, USA, lime\r\nTodd, 25, Mexico, grey\n<|im_end|>" }, { "id": "#27770", "title": "Cats in Spring", "fun": 3.31, "difficulty": 2.33, "author": "goatroper605", "desc": "On a beautiful spring day in the park, there were five female cats walking together and gossiping about their humans. Up ahead, there were five males walking together bragging about their conquests. When the two groups met, there were five cupids flying through the air. Next thing ya know, there were five couples walking away in separate directions. The couples began talking and soon found that they had amazing things in common. Well, long story short, we all know what happens to cats that fall in love in the springtime, oh my what a racket! Can you figure out who the couples were, what treats they liked, what their favorite activity was and how many kittens each had in their litter?\n\r\nMale: Punkin, Batman, Billy, Jake, Dibii\r\nFemale: Pepper, Sally, Ruby, Spot, Starbuck\r\nSnack: Chicken, Mice, Tuna, Ice Cream, Chips\r\nActivity: Laser, String, Sleep, Beat Up, Ball\r\n# in Litter: 1,3,5,7,9\n\r\n1. The five males were: Jake, the one that liked tuna fish & had five kittens, the one that liked Spot, the one that liked to beat up other cats, and the one that loved ice cream.\n\r\n2. The five females were: Starbuck, the one that had nine kittens, the one that liked to eat chicken & chase a ball, the one that liked to sleep, and the one that liked Punkin.\n\r\n3. Dibii (who had three kittens) liked to chase the laser light but not mice. On the other hand, Sally loved to chase mice but not string.\n\r\n4. Batman didn't have a thing for Sally and he didn't have seven kittens. Billy, who thought of himself as very big & tough, had the most kittens & wasn't about to chase some stupid string around - what a waste of time!\n\r\n5. Ruby loved to cuddle up to her male for a long afternoon nap in the sun but hated it when he ate his chips in bed. That may be the reason they didn't have the most kittens (they didn't have the least either).\n\r\n6. Pepper & Punkin didn't have one kitten but they did like tuna fish.", "hint": "No hint available.", "answer": "Punkin=Pepper=Tuna=String=5\r\nBatman=Spot=Chicken=Ball=1\r\nBilly=Sally=Mice=Beat Up=9\r\nJake=Ruby=Chips=Sleep=7\r\nDibii=Starbuck=Ice Cream=Laser=3", "category": "Logic-Grid", "date": "12/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a beautiful spring day in the park, there were five female cats walking together and gossiping about their humans. Up ahead, there were five males walking together bragging about their conquests. When the two groups met, there were five cupids flying through the air. Next thing ya know, there were five couples walking away in separate directions. The couples began talking and soon found that they had amazing things in common. Well, long story short, we all know what happens to cats that fall in love in the springtime, oh my what a racket! Can you figure out who the couples were, what treats they liked, what their favorite activity was and how many kittens each had in their litter?\n\r\nMale: Punkin, Batman, Billy, Jake, Dibii\r\nFemale: Pepper, Sally, Ruby, Spot, Starbuck\r\nSnack: Chicken, Mice, Tuna, Ice Cream, Chips\r\nActivity: Laser, String, Sleep, Beat Up, Ball\r\n# in Litter: 1,3,5,7,9\n\r\n1. The five males were: Jake, the one that liked tuna fish & had five kittens, the one that liked Spot, the one that liked to beat up other cats, and the one that loved ice cream.\n\r\n2. The five females were: Starbuck, the one that had nine kittens, the one that liked to eat chicken & chase a ball, the one that liked to sleep, and the one that liked Punkin.\n\r\n3. Dibii (who had three kittens) liked to chase the laser light but not mice. On the other hand, Sally loved to chase mice but not string.\n\r\n4. Batman didn't have a thing for Sally and he didn't have seven kittens. Billy, who thought of himself as very big & tough, had the most kittens & wasn't about to chase some stupid string around - what a waste of time!\n\r\n5. Ruby loved to cuddle up to her male for a long afternoon nap in the sun but hated it when he ate his chips in bed. That may be the reason they didn't have the most kittens (they didn't have the least either).\n\r\n6. Pepper & Punkin didn't have one kitten but they did like tuna fish.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPunkin=Pepper=Tuna=String=5\r\nBatman=Spot=Chicken=Ball=1\r\nBilly=Sally=Mice=Beat Up=9\r\nJake=Ruby=Chips=Sleep=7\r\nDibii=Starbuck=Ice Cream=Laser=3\n<|im_start|>answer\nPunkin=Pepper=Tuna=String=5\r\nBatman=Spot=Chicken=Ball=1\r\nBilly=Sally=Mice=Beat Up=9\r\nJake=Ruby=Chips=Sleep=7\r\nDibii=Starbuck=Ice Cream=Laser=3\n<|im_end|>" }, { "id": "#41875", "title": "Murder at Brainteaser Mansion #3", "fun": 3.25, "difficulty": 2.46, "author": "Mystery-King", "desc": "Five guests, Mr. Rose, Ms. Tulip, Sir Daisy, Lord Pansy and Miss Lily, were all invited to an exclusive party at Brainteaser Mansion. However, during the long, dark night, the owner of the spectacular mansion, Mr. Death, was found dead in his office. The trouble is, every member of the party went into his office, each at a different time, with a different weapon, motive and clue that incriminated them. From their statements below, can you work out who killed him?\n\r\nMr. Rose's statement: \"I didn't do it. I never left a footprint because a woman did. I entered the room before the person who took in the poison. I must say though, she was in there for a quarter of an hour before someone else went in!\"\n\r\nMs. Tulip's statement: \"Okay, I admit it! I took in the revolver, even though my motive wasn't revenge. A man entered the room after me and his motive was either rage or blackmail.\"\n\r\nSir Daisy's statement: \"All I know is, I did leave a fingerprint, but that doesn't explain why Miss Lily lost a hair, does it? Oh yes! The person who entered seventy minutes before me took in the lead pole.\"\n\r\nLord Pansy's statement: \"I entered after a woman, who did not take in rope because the last person to visit him did. I was in there for more than thirty-five minutes confronting Mr. Death with my motive, which, may I say, wasn't greed or blackmail.\"\n\r\nMiss Lily's statement: \"Yes, you caught me! My motive was jealousy, but it wasn't as bad as that man's blackmail motive, who entered at five minutes past nine. I entered before another man who left the incriminating clue of the blood drop.\"\n\r\nThe person who entered the room at half past ten is the real killer. Who did it?", "hint": "No hint available.", "answer": "Mr. Rose, Dagger, Blackmail, Note, 9:05\r\nMs. Tulip, Revolver, Greed, Footprint, 11:25\r\nSir Daisy, Rope, Rage, Fingerprint, 11:55\r\nLord Pansy, Lead pole, Revenge, Blood, 10:45\r\nMiss Lily, Poison, Jealousy, Hair, 10:30\n\r\nTherefore, Miss Lily was the real killer.", "category": "Logic-Grid", "date": "05/10/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive guests, Mr. Rose, Ms. Tulip, Sir Daisy, Lord Pansy and Miss Lily, were all invited to an exclusive party at Brainteaser Mansion. However, during the long, dark night, the owner of the spectacular mansion, Mr. Death, was found dead in his office. The trouble is, every member of the party went into his office, each at a different time, with a different weapon, motive and clue that incriminated them. From their statements below, can you work out who killed him?\n\r\nMr. Rose's statement: \"I didn't do it. I never left a footprint because a woman did. I entered the room before the person who took in the poison. I must say though, she was in there for a quarter of an hour before someone else went in!\"\n\r\nMs. Tulip's statement: \"Okay, I admit it! I took in the revolver, even though my motive wasn't revenge. A man entered the room after me and his motive was either rage or blackmail.\"\n\r\nSir Daisy's statement: \"All I know is, I did leave a fingerprint, but that doesn't explain why Miss Lily lost a hair, does it? Oh yes! The person who entered seventy minutes before me took in the lead pole.\"\n\r\nLord Pansy's statement: \"I entered after a woman, who did not take in rope because the last person to visit him did. I was in there for more than thirty-five minutes confronting Mr. Death with my motive, which, may I say, wasn't greed or blackmail.\"\n\r\nMiss Lily's statement: \"Yes, you caught me! My motive was jealousy, but it wasn't as bad as that man's blackmail motive, who entered at five minutes past nine. I entered before another man who left the incriminating clue of the blood drop.\"\n\r\nThe person who entered the room at half past ten is the real killer. Who did it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Rose, Dagger, Blackmail, Note, 9:05\r\nMs. Tulip, Revolver, Greed, Footprint, 11:25\r\nSir Daisy, Rope, Rage, Fingerprint, 11:55\r\nLord Pansy, Lead pole, Revenge, Blood, 10:45\r\nMiss Lily, Poison, Jealousy, Hair, 10:30\n\r\nTherefore, Miss Lily was the real killer.\n<|im_start|>answer\nMr. Rose, Dagger, Blackmail, Note, 9:05\r\nMs. Tulip, Revolver, Greed, Footprint, 11:25\r\nSir Daisy, Rope, Rage, Fingerprint, 11:55\r\nLord Pansy, Lead pole, Revenge, Blood, 10:45\r\nMiss Lily, Poison, Jealousy, Hair, 10:30\n\r\nTherefore, Miss Lily was the real killer.\n<|im_end|>" }, { "id": "#52499", "title": "Birth Months", "fun": 3.25, "difficulty": 1.52, "author": "wimpykidfan37", "desc": "Four sisters, Sara, Ophelia, Nora, and Dawn, were each born in a different one of the months September, October, November, and December.\n\r\n\"This is terrible,\" said Ophelia one day. \"None of us have an initial that matches the initial of her birth month.\"\n\r\n\"I don't mind at all,\" replied the girl who was born in September.\n\r\n\"That's easy for you to say,\" said Nora. \"It would at least be cool if the initial of my birth month was a vowel, but no.\"\n\r\nIn which month was each girl born?", "hint": "No hint available.", "answer": "Sara was born in October, Ophelia was born in November, Nora was born in December, and Dawn was born in September.\n\r\nNora's birth month obviously cannot be November. Since it doesn't start with a vowel, it cannot be October. Since she was talking to the girl who was born in September, it cannot be September. Therefore, it must be December.\n\r\nThe girl born in September obviously cannot be Sara. Since she was talking to both Ophelia and Nora, it cannot be either of them. Therefore, it must be Dawn.\n\r\nThis leaves the girls Sara and Ophelia and the months October and November. Ophelia cannot be born in October, so she must be born in November, and Sara was born in October.", "category": "Logic", "date": "11/19/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour sisters, Sara, Ophelia, Nora, and Dawn, were each born in a different one of the months September, October, November, and December.\n\r\n\"This is terrible,\" said Ophelia one day. \"None of us have an initial that matches the initial of her birth month.\"\n\r\n\"I don't mind at all,\" replied the girl who was born in September.\n\r\n\"That's easy for you to say,\" said Nora. \"It would at least be cool if the initial of my birth month was a vowel, but no.\"\n\r\nIn which month was each girl born?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSara was born in October, Ophelia was born in November, Nora was born in December, and Dawn was born in September.\n\r\nNora's birth month obviously cannot be November. Since it doesn't start with a vowel, it cannot be October. Since she was talking to the girl who was born in September, it cannot be September. Therefore, it must be December.\n\r\nThe girl born in September obviously cannot be Sara. Since she was talking to both Ophelia and Nora, it cannot be either of them. Therefore, it must be Dawn.\n\r\nThis leaves the girls Sara and Ophelia and the months October and November. Ophelia cannot be born in October, so she must be born in November, and Sara was born in October.\n<|im_start|>answer\nSara was born in October, Ophelia was born in November, Nora was born in December, and Dawn was born in September.\n\r\nNora's birth month obviously cannot be November. Since it doesn't start with a vowel, it cannot be October. Since she was talking to the girl who was born in September, it cannot be September. Therefore, it must be December.\n\r\nThe girl born in September obviously cannot be Sara. Since she was talking to both Ophelia and Nora, it cannot be either of them. Therefore, it must be Dawn.\n\r\nThis leaves the girls Sara and Ophelia and the months October and November. Ophelia cannot be born in October, so she must be born in November, and Sara was born in October.\n<|im_end|>" }, { "id": "#23185", "title": "Girlfriend Appreciation Day", "fun": 3.24, "difficulty": 2.93, "author": "cinnamon30", "desc": "Five brothers share a common trait of forgetfulness that has gotten them in hot water with their girlfriends. After a string of forgotten birthdays, anniversaries and even dates, the brothers' girlfriends were fed up. After a brainstorming session, the brothers devised a new holiday - Girlfriend Appreciation Day. For the big day, the five brothers have dates with their girlfriends. Each one bought a different gift and a dozen roses of a different color. Each couple is going to a different destination on their date. Determine each brother's name, the name of their girlfriend, the gift and color of roses he is giving her, and their date destination.\n\r\nBrothers - Ted, Tim, Tom, Travis, Tyler\r\nGirls - Andrea, Brooke, Jessica, Laura, Vanessa\r\nGift - Bracelet, Candy, Music Box, Necklace, Ring\r\nColor of Roses - Pale Purple, Pink, White, Red, Yellow\r\nDate Destinations - Basketball Game, Dinner, Ice-Skating, Movie, Theater\n\r\n1. The five brothers are: Tyler, the brother giving his girlfriend the ring and red roses, the one giving his girlfriend pink roses, the one taking Laura to a movie, and the one taking his girlfriend ice-skating.\r\n2. The five girlfriends are: Andrea (who isn't going to the basketball game), the woman getting the ring, Brooke (who isn't getting the bracelet); Ted's girlfriend, and the one getting the candy and the yellow roses.\r\n3. The brother taking his girlfriend to the movie is either Tim or Tyler (who isn't giving his girlfriend the necklace).\r\n4. Vanessa and Ted's girlfriend (who isn't receiving the necklace) are, in some order, the woman going to the theater and the one receiving white roses.\r\n5. Neither Travis nor Tom (whose girlfriend isn't Andrea) is taking his girlfriend to the basketball game.", "hint": "Anything in parentheses refers to the word immediately before the parentheses. For example: In Clue 3 Tyler is not giving his girlfriend the necklace.", "answer": "Ted, Jessica, Bracelet, White, Ice-Skating\r\nTim, Laura, Candy, Yellow, Movie\r\nTom, Vanessa, Ring, Red, Theater\r\nTravis, Andrea, necklace, Pink, Dinner\r\nTyler, Brooke, Music Box, Pale Purple, Basketball Game", "category": "Logic-Grid", "date": "05/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive brothers share a common trait of forgetfulness that has gotten them in hot water with their girlfriends. After a string of forgotten birthdays, anniversaries and even dates, the brothers' girlfriends were fed up. After a brainstorming session, the brothers devised a new holiday - Girlfriend Appreciation Day. For the big day, the five brothers have dates with their girlfriends. Each one bought a different gift and a dozen roses of a different color. Each couple is going to a different destination on their date. Determine each brother's name, the name of their girlfriend, the gift and color of roses he is giving her, and their date destination.\n\r\nBrothers - Ted, Tim, Tom, Travis, Tyler\r\nGirls - Andrea, Brooke, Jessica, Laura, Vanessa\r\nGift - Bracelet, Candy, Music Box, Necklace, Ring\r\nColor of Roses - Pale Purple, Pink, White, Red, Yellow\r\nDate Destinations - Basketball Game, Dinner, Ice-Skating, Movie, Theater\n\r\n1. The five brothers are: Tyler, the brother giving his girlfriend the ring and red roses, the one giving his girlfriend pink roses, the one taking Laura to a movie, and the one taking his girlfriend ice-skating.\r\n2. The five girlfriends are: Andrea (who isn't going to the basketball game), the woman getting the ring, Brooke (who isn't getting the bracelet); Ted's girlfriend, and the one getting the candy and the yellow roses.\r\n3. The brother taking his girlfriend to the movie is either Tim or Tyler (who isn't giving his girlfriend the necklace).\r\n4. Vanessa and Ted's girlfriend (who isn't receiving the necklace) are, in some order, the woman going to the theater and the one receiving white roses.\r\n5. Neither Travis nor Tom (whose girlfriend isn't Andrea) is taking his girlfriend to the basketball game.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTed, Jessica, Bracelet, White, Ice-Skating\r\nTim, Laura, Candy, Yellow, Movie\r\nTom, Vanessa, Ring, Red, Theater\r\nTravis, Andrea, necklace, Pink, Dinner\r\nTyler, Brooke, Music Box, Pale Purple, Basketball Game\n<|im_start|>answer\nTed, Jessica, Bracelet, White, Ice-Skating\r\nTim, Laura, Candy, Yellow, Movie\r\nTom, Vanessa, Ring, Red, Theater\r\nTravis, Andrea, necklace, Pink, Dinner\r\nTyler, Brooke, Music Box, Pale Purple, Basketball Game\n<|im_end|>" }, { "id": "#48453", "title": "First Day on the Job", "fun": 3.24, "difficulty": 2.5, "author": "MarcM1098", "desc": "It's your first day on the job. Your team member's introductions went so fast; it's all a blur. There are three males: Alex, Carlos and Edward, and two females: Brenda and Deborah. The other employees are all celebrating a work anniversary this week, for being with the company either 1, 3, 5, 10, or 20 years. Each of them has been using the same form of transportation for their entire career. Try to piece together what each person's role is, how they get to work, and how long they have been with the company.\n\r\n1. Alex has been at work longer than the engineer but not as long as the bus rider.\r\n2. Because she takes public transit, Brenda can do the crossword on her way to work.\r\n3. Carlos has been on the job exactly twice as long as the manager.\r\n4. Either Deborah or the one who takes the train just received their 10 year service award.\r\n5. Edward's last promotion was 2 years ago when he became a specialist.\r\n6. The developer doesn't always get a seat and sometimes has to stand on the way to work.\r\n7. The architect role requires at least 6 years of on-the-job experience.\r\n8. The engineer can leave whenever she wants, she isn't tied down to a particular transit schedule.\r\n9. The subway was built 8 years ago.\r\n10. The owner of the motorcycle has been using it to come to work for more than 6 years.\r\n11. On the day of the snowstorm last week, only Alex and the Manager arrived on time; everyone who relied on the roads (bus, car, motorcycle) was late.", "hint": "By clue 1 and 10, the engineer cannot own the motorcycle.\n\r\nBased on the above and several other clues, Brenda can only take the subway or train. By clue 11, Alex can also only take the subway or train. Therefore, the other three people cannot take the subway or train.", "answer": "Alex is the developer; he has taken the subway for 3 years.\r\nBrenda is the manager; she has taken the train for 10 years.\r\nCarlos is the architect; he has taken a motorcycle for 20 years.\r\nDeborah is the engineer; she has taken a car for 1 year.\r\nEdward is the specialist; he has taken the bus for 5 years.", "category": "Logic-Grid", "date": "02/19/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's your first day on the job. Your team member's introductions went so fast; it's all a blur. There are three males: Alex, Carlos and Edward, and two females: Brenda and Deborah. The other employees are all celebrating a work anniversary this week, for being with the company either 1, 3, 5, 10, or 20 years. Each of them has been using the same form of transportation for their entire career. Try to piece together what each person's role is, how they get to work, and how long they have been with the company.\n\r\n1. Alex has been at work longer than the engineer but not as long as the bus rider.\r\n2. Because she takes public transit, Brenda can do the crossword on her way to work.\r\n3. Carlos has been on the job exactly twice as long as the manager.\r\n4. Either Deborah or the one who takes the train just received their 10 year service award.\r\n5. Edward's last promotion was 2 years ago when he became a specialist.\r\n6. The developer doesn't always get a seat and sometimes has to stand on the way to work.\r\n7. The architect role requires at least 6 years of on-the-job experience.\r\n8. The engineer can leave whenever she wants, she isn't tied down to a particular transit schedule.\r\n9. The subway was built 8 years ago.\r\n10. The owner of the motorcycle has been using it to come to work for more than 6 years.\r\n11. On the day of the snowstorm last week, only Alex and the Manager arrived on time; everyone who relied on the roads (bus, car, motorcycle) was late.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlex is the developer; he has taken the subway for 3 years.\r\nBrenda is the manager; she has taken the train for 10 years.\r\nCarlos is the architect; he has taken a motorcycle for 20 years.\r\nDeborah is the engineer; she has taken a car for 1 year.\r\nEdward is the specialist; he has taken the bus for 5 years.\n<|im_start|>answer\nAlex is the developer; he has taken the subway for 3 years.\r\nBrenda is the manager; she has taken the train for 10 years.\r\nCarlos is the architect; he has taken a motorcycle for 20 years.\r\nDeborah is the engineer; she has taken a car for 1 year.\r\nEdward is the specialist; he has taken the bus for 5 years.\n<|im_end|>" }, { "id": "#21087", "title": "Grandmas and Trolls", "fun": 3.22, "difficulty": 1.39, "author": "Gandalf", "desc": "You are on your way to visit your Grandma, who lives at the end of the valley. It's her birthday, and you want to give her the cakes you've made.\n\r\nBetween your house and her house, you have to cross 7 bridges, and as it goes in the land of make believe, there is a troll under every bridge! Each troll, quite rightly, insists that you pay a troll toll. Before you can cross their bridge, you have to give them half of the cakes you are carrying, but as they are kind trolls, they each give you back a single cake.\n\r\nHow many cakes do you have to leave home with to make sure that you arrive at Grandma's with exactly 2 cakes?", "hint": "No hint available.", "answer": "2: At each bridge you are required to give half of your cakes, and you receive one back. Which leaves you with 2 cakes after every bridge.", "category": "Math", "date": "02/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are on your way to visit your Grandma, who lives at the end of the valley. It's her birthday, and you want to give her the cakes you've made.\n\r\nBetween your house and her house, you have to cross 7 bridges, and as it goes in the land of make believe, there is a troll under every bridge! Each troll, quite rightly, insists that you pay a troll toll. Before you can cross their bridge, you have to give them half of the cakes you are carrying, but as they are kind trolls, they each give you back a single cake.\n\r\nHow many cakes do you have to leave home with to make sure that you arrive at Grandma's with exactly 2 cakes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2: At each bridge you are required to give half of your cakes, and you receive one back. Which leaves you with 2 cakes after every bridge.\n<|im_start|>answer\n2: At each bridge you are required to give half of your cakes, and you receive one back. Which leaves you with 2 cakes after every bridge.\n<|im_end|>" }, { "id": "#23985", "title": "Ballroom Dancing", "fun": 3.21, "difficulty": 2.5, "author": "tjm531", "desc": "Once a year, a ballroom dancing extravaganza at the local country club is the social event of the season. Each of five distinguished pairs stole the spotlight in a different dance, earning them not only the admiration of all those present but also a romantic dinner for two at the club on an evening of their choice. From the information provided, determine the husband and wife who comprise each couple and their shared surname, as well as the type of dance in which each couple excelled.\n\r\nHusbands: Andrew, Bradley, Logan, Nathan, Stewart\r\nWives: Audrey, Lorraine, Margaret, Phyllis, Vanessa\r\nSurname: Kavanaugh, Levy, Moylan, Northrop, Powell\r\nDance: Fox Trot, Jitterbug, Mambo, Tango, Waltz\n\r\n1. Bradley (who didn't do the jitterbug) isn't Mr. Northrop. \n\r\n2. Phyllis's surname is Moylan\n\r\n3. Neither Margaret (who isn't Ms. Northrop) nor Audrey is either the woman who danced the jitterbug with Mr. Levy (who isn't Nathan) or the one who danced the tango with her companion.\n\r\n4. Stewart (who isn't surnamed Levy) isn't the man who danced the fox trot and Vanessa wasn't his partner.\n\r\n5. Neither Audrey nor the woman who danced a stunning waltz is married to Mr. Powell (who isn't Bradley). \n\r\n6. Lorraine didn't dance the tango.\n\r\n7. Audrey isn't Ms. Northrop and Margaret isn't the woman who danced the mambo with her husband.\n\r\n8. Andrew's last name is Kavanaugh.", "hint": "The statement \"Neither Audrey nor the woman who danced a stunning waltz is married to Mr. Powell...\" means more than just that.", "answer": "Andrew & Audrey Kavanaugh; mambo\r\nBradley & Phyllis Moylan; tango\r\nLogan & Vanessa Levy; jitterbug\r\nNathan & Margaret Powell; fox trot\r\nStewart & Lorraine Northrop; waltz", "category": "Logic-Grid", "date": "06/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce a year, a ballroom dancing extravaganza at the local country club is the social event of the season. Each of five distinguished pairs stole the spotlight in a different dance, earning them not only the admiration of all those present but also a romantic dinner for two at the club on an evening of their choice. From the information provided, determine the husband and wife who comprise each couple and their shared surname, as well as the type of dance in which each couple excelled.\n\r\nHusbands: Andrew, Bradley, Logan, Nathan, Stewart\r\nWives: Audrey, Lorraine, Margaret, Phyllis, Vanessa\r\nSurname: Kavanaugh, Levy, Moylan, Northrop, Powell\r\nDance: Fox Trot, Jitterbug, Mambo, Tango, Waltz\n\r\n1. Bradley (who didn't do the jitterbug) isn't Mr. Northrop. \n\r\n2. Phyllis's surname is Moylan\n\r\n3. Neither Margaret (who isn't Ms. Northrop) nor Audrey is either the woman who danced the jitterbug with Mr. Levy (who isn't Nathan) or the one who danced the tango with her companion.\n\r\n4. Stewart (who isn't surnamed Levy) isn't the man who danced the fox trot and Vanessa wasn't his partner.\n\r\n5. Neither Audrey nor the woman who danced a stunning waltz is married to Mr. Powell (who isn't Bradley). \n\r\n6. Lorraine didn't dance the tango.\n\r\n7. Audrey isn't Ms. Northrop and Margaret isn't the woman who danced the mambo with her husband.\n\r\n8. Andrew's last name is Kavanaugh.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndrew & Audrey Kavanaugh; mambo\r\nBradley & Phyllis Moylan; tango\r\nLogan & Vanessa Levy; jitterbug\r\nNathan & Margaret Powell; fox trot\r\nStewart & Lorraine Northrop; waltz\n<|im_start|>answer\nAndrew & Audrey Kavanaugh; mambo\r\nBradley & Phyllis Moylan; tango\r\nLogan & Vanessa Levy; jitterbug\r\nNathan & Margaret Powell; fox trot\r\nStewart & Lorraine Northrop; waltz\n<|im_end|>" }, { "id": "#24967", "title": "Bertie Bott's Every Flavour Fiasco", "fun": 3.21, "difficulty": 1.61, "author": "grinnychick", "desc": "Harry and his friends decide to share the last of a packet of Bertie Bott's Every Flavour beans. None were impressed with the flavour of their bean, so each decided to show off their skills by casting a different spell on them. Who cast what spell on which bean?\n\r\n(Note: Primary colours refer to those of pigments, ie blue, red and yellow.)\n\r\nFriends: Harry, Ron, Hermione, Neville and Hagrid\r\nColours: Green, Blue, Red, Orange and Purple\r\nFlavours: Vomit, Earwax, Cardboard, Snot and Mud\r\nSpell: Vanishing, Speaking, Levitating, Exploding and Growing\n\r\n1. The boy with the cardboard flavoured bean cast a spell which made noise. The earwax flavoured bean was very quiet.\n\r\n2. Harry's bean was a primary colour.\n\r\n3. Hermione's bean, which was not purple, grew almost out of control. \n\r\n4. The red vomit flavoured bean was levitated.\n\r\n5. Hagrid's bean, which was not a primary colour, exploded after a failed illuminating spell.\n\r\n6. Neville's orange bean did not speak.\n\r\n7. The green bean questioned where the orange bean had gone.\n\r\n8. The snot flavoured bean was blue. The green bean did not taste like earwax. The purple bean was mud flavoured.", "hint": "No hint available.", "answer": "Harry levitated the red vomit flavoured bean.\r\nRon made the green cardboard flavoured bean speak uncontrollably.\r\nHermione made the blue snot flavoured bean grow.\r\nNeville made his orange earwax flavoured bean disappear, much to his disappointment as he wanted it to multiply.\r\nHagrid exploded his purple mud flavoured bean.", "category": "Logic-Grid", "date": "07/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHarry and his friends decide to share the last of a packet of Bertie Bott's Every Flavour beans. None were impressed with the flavour of their bean, so each decided to show off their skills by casting a different spell on them. Who cast what spell on which bean?\n\r\n(Note: Primary colours refer to those of pigments, ie blue, red and yellow.)\n\r\nFriends: Harry, Ron, Hermione, Neville and Hagrid\r\nColours: Green, Blue, Red, Orange and Purple\r\nFlavours: Vomit, Earwax, Cardboard, Snot and Mud\r\nSpell: Vanishing, Speaking, Levitating, Exploding and Growing\n\r\n1. The boy with the cardboard flavoured bean cast a spell which made noise. The earwax flavoured bean was very quiet.\n\r\n2. Harry's bean was a primary colour.\n\r\n3. Hermione's bean, which was not purple, grew almost out of control. \n\r\n4. The red vomit flavoured bean was levitated.\n\r\n5. Hagrid's bean, which was not a primary colour, exploded after a failed illuminating spell.\n\r\n6. Neville's orange bean did not speak.\n\r\n7. The green bean questioned where the orange bean had gone.\n\r\n8. The snot flavoured bean was blue. The green bean did not taste like earwax. The purple bean was mud flavoured.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry levitated the red vomit flavoured bean.\r\nRon made the green cardboard flavoured bean speak uncontrollably.\r\nHermione made the blue snot flavoured bean grow.\r\nNeville made his orange earwax flavoured bean disappear, much to his disappointment as he wanted it to multiply.\r\nHagrid exploded his purple mud flavoured bean.\n<|im_start|>answer\nHarry levitated the red vomit flavoured bean.\r\nRon made the green cardboard flavoured bean speak uncontrollably.\r\nHermione made the blue snot flavoured bean grow.\r\nNeville made his orange earwax flavoured bean disappear, much to his disappointment as he wanted it to multiply.\r\nHagrid exploded his purple mud flavoured bean.\n<|im_end|>" }, { "id": "#28457", "title": "Pauline's Five Men in Europe", "fun": 3.21, "difficulty": 2.52, "author": "teaserboy", "desc": "All of Pauline's favorite male relatives live in Europe. They are her father, her uncle, her first cousin, her brother, and her husband. In no particular order, their names are Daniel, Edgar, Wilfred, Luther, and Walter. Although they all live in Europe, no two men live in the same city. The cities in which they live are London, Paris, Rome, Madrid, and Berlin. From the clues given, try to determine not only the city in which each man lives and his relationship to Pauline, but his occupation as well, be it diplomat, correspondent, student, artist or professor. Assume her husband is only related to the other men through marriage to her.\n\r\n1. The man in Berlin is the father of the correspondent and the diplomat is the father of the man in Paris.\r\n2. Luther is the son of the man in Rome and Walter is the artist's son.\r\n3. Daniel is the father of the man in Madrid and Wilfred is the father of the student.\r\n4. Her cousin does not live in Paris.", "hint": "No hint available.", "answer": "Daniel-Uncle-Berlin-Artist\r\nEdgar-Husband-London-Professor\r\nWilfred-Father-Rome-Diplomat\r\nLuther-Brother-Paris-Student\r\nWalter-Cousin-Madrid-Correspondent", "category": "Logic-Grid", "date": "02/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAll of Pauline's favorite male relatives live in Europe. They are her father, her uncle, her first cousin, her brother, and her husband. In no particular order, their names are Daniel, Edgar, Wilfred, Luther, and Walter. Although they all live in Europe, no two men live in the same city. The cities in which they live are London, Paris, Rome, Madrid, and Berlin. From the clues given, try to determine not only the city in which each man lives and his relationship to Pauline, but his occupation as well, be it diplomat, correspondent, student, artist or professor. Assume her husband is only related to the other men through marriage to her.\n\r\n1. The man in Berlin is the father of the correspondent and the diplomat is the father of the man in Paris.\r\n2. Luther is the son of the man in Rome and Walter is the artist's son.\r\n3. Daniel is the father of the man in Madrid and Wilfred is the father of the student.\r\n4. Her cousin does not live in Paris.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDaniel-Uncle-Berlin-Artist\r\nEdgar-Husband-London-Professor\r\nWilfred-Father-Rome-Diplomat\r\nLuther-Brother-Paris-Student\r\nWalter-Cousin-Madrid-Correspondent\n<|im_start|>answer\nDaniel-Uncle-Berlin-Artist\r\nEdgar-Husband-London-Professor\r\nWilfred-Father-Rome-Diplomat\r\nLuther-Brother-Paris-Student\r\nWalter-Cousin-Madrid-Correspondent\n<|im_end|>" }, { "id": "#29387", "title": "Inventions, Inventions!", "fun": 3.21, "difficulty": 2.18, "author": "Winner4600", "desc": "Dave, John, Cara, Robbie, and Kate are five budding inventors. Their newest inventions? Each has combined a popular ingredient with a drink! Figure out who's who, what their \"mix\" is, and when they each invented their product.\n\r\n1. The five inventors are Dave, Ms. Roberts, the \"Potato Man\", the July inventor, and the one who added an ingredient to lemonade.\n\r\n2. No one's first name is similar to their last name.\n\r\n3. Kate made a peanut smoothie.\n\r\n4. Winter in the Northern Hemisphere seemed to be a \"hot\" invention time - both John and Cara concocted something then!\n\r\n5. Marshmallows were incorporated into Kay's creation. Chocolate was in Davidson's.\n\r\n6. Banana Vodka was a spur of the moment brainstorm.\n\r\n7. April just happened to be \"chocolate season\", at least for Robbie.\n\r\n8. Believe it or not, potato cocktails were very popular in January!", "hint": "No hint available.", "answer": "Dave Kay, Marshmallow Soda, October\r\nJohn Cora, Potato Cocktail, January\r\nCara Roberts, Banana Vodka, February\r\nRobbie Davidson, Chocolate Lemonade, April\r\nKate Johnson, Peanut Smoothie, July", "category": "Logic-Grid", "date": "03/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDave, John, Cara, Robbie, and Kate are five budding inventors. Their newest inventions? Each has combined a popular ingredient with a drink! Figure out who's who, what their \"mix\" is, and when they each invented their product.\n\r\n1. The five inventors are Dave, Ms. Roberts, the \"Potato Man\", the July inventor, and the one who added an ingredient to lemonade.\n\r\n2. No one's first name is similar to their last name.\n\r\n3. Kate made a peanut smoothie.\n\r\n4. Winter in the Northern Hemisphere seemed to be a \"hot\" invention time - both John and Cara concocted something then!\n\r\n5. Marshmallows were incorporated into Kay's creation. Chocolate was in Davidson's.\n\r\n6. Banana Vodka was a spur of the moment brainstorm.\n\r\n7. April just happened to be \"chocolate season\", at least for Robbie.\n\r\n8. Believe it or not, potato cocktails were very popular in January!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDave Kay, Marshmallow Soda, October\r\nJohn Cora, Potato Cocktail, January\r\nCara Roberts, Banana Vodka, February\r\nRobbie Davidson, Chocolate Lemonade, April\r\nKate Johnson, Peanut Smoothie, July\n<|im_start|>answer\nDave Kay, Marshmallow Soda, October\r\nJohn Cora, Potato Cocktail, January\r\nCara Roberts, Banana Vodka, February\r\nRobbie Davidson, Chocolate Lemonade, April\r\nKate Johnson, Peanut Smoothie, July\n<|im_end|>" }, { "id": "#26068", "title": "Weather or Not", "fun": 3.2, "difficulty": 2.54, "author": "mejoza", "desc": "There are five weather forecasters getting ready for a weekend forecast. Each forecaster is predicting different weather and is choosing a suit and \"tie\" (yes, the women, too) of different color combinations. There are 3 men (John, Matt and Tim) and 2 women (Karen and Sarah). \n\r\nCan you determine the color of the suit, the color and pattern of the tie, and the weather prediction for each forecaster? \n\r\n1. The forecaster who wore a black suit did not predict snow or rain.\n\r\n2. Many viewers called in to comment on the whimsically printed tan tie and brown suit combination.\n\r\n3. The five forecasters were: Matt, the woman who predicted high winds, the person in a black suit, the man with a striped tie, and the woman in an olive suit.\n\r\n4. A solid white tie was chosen to represent the snowy forecast that day.\n\r\n5. John's orange tie was hated by his wife.\n\r\n6. Sarah had a teal colored tie which was not floral.\n\r\n7. Tim predicted sun and did not wear brown or black.\n\r\n8. The man who predicted rain did not wear a striped tie.\n\r\n9. The blue suit was worn by a man.", "hint": "No hint available.", "answer": "John, black suit, orange floral tie, foggy\r\nTim, blue suit, striped pink tie, sunny\r\nSarah, gray suit, dotted teal tie, windy\r\nMatt, brown suit, whimsical tan tie, rainy\r\nKaren, olive suit, solid white tie, snowy", "category": "Logic-Grid", "date": "09/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five weather forecasters getting ready for a weekend forecast. Each forecaster is predicting different weather and is choosing a suit and \"tie\" (yes, the women, too) of different color combinations. There are 3 men (John, Matt and Tim) and 2 women (Karen and Sarah). \n\r\nCan you determine the color of the suit, the color and pattern of the tie, and the weather prediction for each forecaster? \n\r\n1. The forecaster who wore a black suit did not predict snow or rain.\n\r\n2. Many viewers called in to comment on the whimsically printed tan tie and brown suit combination.\n\r\n3. The five forecasters were: Matt, the woman who predicted high winds, the person in a black suit, the man with a striped tie, and the woman in an olive suit.\n\r\n4. A solid white tie was chosen to represent the snowy forecast that day.\n\r\n5. John's orange tie was hated by his wife.\n\r\n6. Sarah had a teal colored tie which was not floral.\n\r\n7. Tim predicted sun and did not wear brown or black.\n\r\n8. The man who predicted rain did not wear a striped tie.\n\r\n9. The blue suit was worn by a man.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn, black suit, orange floral tie, foggy\r\nTim, blue suit, striped pink tie, sunny\r\nSarah, gray suit, dotted teal tie, windy\r\nMatt, brown suit, whimsical tan tie, rainy\r\nKaren, olive suit, solid white tie, snowy\n<|im_start|>answer\nJohn, black suit, orange floral tie, foggy\r\nTim, blue suit, striped pink tie, sunny\r\nSarah, gray suit, dotted teal tie, windy\r\nMatt, brown suit, whimsical tan tie, rainy\r\nKaren, olive suit, solid white tie, snowy\n<|im_end|>" }, { "id": "#22588", "title": "A Day at the Zoo", "fun": 3.19, "difficulty": 1.82, "author": "kellgo", "desc": "Three boys (Jake, Anthony and Carlos) and two girls (Abigail and Paige) went on a trip to the zoo. All five kids have five different favorite animals that they want to see: monkeys, alligators, bears, lions, and giraffes. Each of the five children ate one of the five different things as a snack: popcorn, chips, pretzel, nachos with chips and cheese, or crackers. Each child bought one souvenir: a stuffed rabbit, a lion t-shirt, a key chain, a plastic snake, or a stuffed monkey. Figure out from the clues below which child likes which animal, who ate what for snack, and who bought what for a souvenir.\n\r\nOne of the kids got so excited to see their favorite animal, the alligators, that they spilt their popcorn all over the place.\n\r\nPaige really didn't want to see the alligator exhibit because she doesn't like reptiles or anything that has scales.\n\r\nThe stuffed monkey got a little bit of nacho cheese on its face from its owner's kisses.\n\r\nAll day after visiting the zoo, Jake kept making lion noises, even in his sleep!\n\r\nAbigail and Carlos both got a snack that involved chips.\n\r\nThe kid who bought the t-shirt loved it so much that he slept in it despite pretzel crumbs getting into his bed.\n\r\nThe nacho lovers' favorite animal is the monkey, which is why they wanted to go that exhibit.\n\r\nNone of the boys bought a stuffed animal.\n\r\nThe kid who got the keychain picked the one with their favorite animal, the alligator, on it.\n\r\nOne of the girls just loved the new bear exhibit. It was her favorite part of the day.", "hint": "No hint available.", "answer": "Jake: lions, pretzels, t-shirt\r\nAnthony: alligators, popcorn, keychain\r\nCarlos: giraffe, chips, plastic snake\r\nAbigail: monkeys, nachos, stuffed monkey\r\nPaige: bears, crackers, stuffed rabbit", "category": "Logic-Grid", "date": "05/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree boys (Jake, Anthony and Carlos) and two girls (Abigail and Paige) went on a trip to the zoo. All five kids have five different favorite animals that they want to see: monkeys, alligators, bears, lions, and giraffes. Each of the five children ate one of the five different things as a snack: popcorn, chips, pretzel, nachos with chips and cheese, or crackers. Each child bought one souvenir: a stuffed rabbit, a lion t-shirt, a key chain, a plastic snake, or a stuffed monkey. Figure out from the clues below which child likes which animal, who ate what for snack, and who bought what for a souvenir.\n\r\nOne of the kids got so excited to see their favorite animal, the alligators, that they spilt their popcorn all over the place.\n\r\nPaige really didn't want to see the alligator exhibit because she doesn't like reptiles or anything that has scales.\n\r\nThe stuffed monkey got a little bit of nacho cheese on its face from its owner's kisses.\n\r\nAll day after visiting the zoo, Jake kept making lion noises, even in his sleep!\n\r\nAbigail and Carlos both got a snack that involved chips.\n\r\nThe kid who bought the t-shirt loved it so much that he slept in it despite pretzel crumbs getting into his bed.\n\r\nThe nacho lovers' favorite animal is the monkey, which is why they wanted to go that exhibit.\n\r\nNone of the boys bought a stuffed animal.\n\r\nThe kid who got the keychain picked the one with their favorite animal, the alligator, on it.\n\r\nOne of the girls just loved the new bear exhibit. It was her favorite part of the day.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJake: lions, pretzels, t-shirt\r\nAnthony: alligators, popcorn, keychain\r\nCarlos: giraffe, chips, plastic snake\r\nAbigail: monkeys, nachos, stuffed monkey\r\nPaige: bears, crackers, stuffed rabbit\n<|im_start|>answer\nJake: lions, pretzels, t-shirt\r\nAnthony: alligators, popcorn, keychain\r\nCarlos: giraffe, chips, plastic snake\r\nAbigail: monkeys, nachos, stuffed monkey\r\nPaige: bears, crackers, stuffed rabbit\n<|im_end|>" }, { "id": "#39315", "title": "Halloween Party", "fun": 3.19, "difficulty": 2.41, "author": "dreamlvr1432", "desc": "Happy Hauntings costume store threw their annual Halloween party, complete with food, dancing, and a little friendly competition. The company arranged 5 competitions (bobbing for apples, ring toss, scavenger hunt, pumpkin carving, and a scariest costume contest), with 5 different prizes (movie premier tickets, theater tickets, 4 passes to a local amusement park, and 2 gift certificates to a local restaurant). Each competition was won by a different employee, wearing a different costume purchased from the Happy Hauntings store. Can you determine the full name of each employee, what costume they wore, what contest they won, and which prize they received?\n\r\n1) Belinda did not bob for apples, but she did win a gift certificate, which she shared with the man who won the tickets to the theater.\n\r\n2) The 5 employees were: Amy, Mr. Brown, the one who dressed as a bat, the one who won the theater tickets, and the woman who won the pumpkin carving contest (who did not win movie tickets).\n\r\n3) Robert, John, and Mary have the same last initial.\n\r\n4) The women's costumes were: the one worn by Ms. Smith, the one worn by the woman who won the ring toss, and the skeleton.\n\r\n5) During dinner, John sat at the same table as Frankenstein, the skeleton, and the woman who won the apple bobbing contest (who was not dressed as Dracula). The bat sat 2 tables over.\n\r\n6) The man who won scariest costume received a $50 gift certificate, which he later used to take Ms. Black to dinner.\n\r\n7) Later that week, John Beals went to dinner with the woman dressed as a bat, after they went to the theater, using the prizes they won at the party.", "hint": "No hint available.", "answer": "Amy Smith, ghost, bobbing for apples, movie tickets\r\nRobert Brown, Frankenstein, scariest costume, $50 gift certificate\r\nBelinda Martinez, bat, ring toss, $20 gift certificate\r\nJohn Beals, Dracula, scavenger hunt, theater tickets\r\nMary Black, skeleton, pumpkin carving, amusement park passes", "category": "Logic-Grid", "date": "11/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHappy Hauntings costume store threw their annual Halloween party, complete with food, dancing, and a little friendly competition. The company arranged 5 competitions (bobbing for apples, ring toss, scavenger hunt, pumpkin carving, and a scariest costume contest), with 5 different prizes (movie premier tickets, theater tickets, 4 passes to a local amusement park, and 2 gift certificates to a local restaurant). Each competition was won by a different employee, wearing a different costume purchased from the Happy Hauntings store. Can you determine the full name of each employee, what costume they wore, what contest they won, and which prize they received?\n\r\n1) Belinda did not bob for apples, but she did win a gift certificate, which she shared with the man who won the tickets to the theater.\n\r\n2) The 5 employees were: Amy, Mr. Brown, the one who dressed as a bat, the one who won the theater tickets, and the woman who won the pumpkin carving contest (who did not win movie tickets).\n\r\n3) Robert, John, and Mary have the same last initial.\n\r\n4) The women's costumes were: the one worn by Ms. Smith, the one worn by the woman who won the ring toss, and the skeleton.\n\r\n5) During dinner, John sat at the same table as Frankenstein, the skeleton, and the woman who won the apple bobbing contest (who was not dressed as Dracula). The bat sat 2 tables over.\n\r\n6) The man who won scariest costume received a $50 gift certificate, which he later used to take Ms. Black to dinner.\n\r\n7) Later that week, John Beals went to dinner with the woman dressed as a bat, after they went to the theater, using the prizes they won at the party.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAmy Smith, ghost, bobbing for apples, movie tickets\r\nRobert Brown, Frankenstein, scariest costume, $50 gift certificate\r\nBelinda Martinez, bat, ring toss, $20 gift certificate\r\nJohn Beals, Dracula, scavenger hunt, theater tickets\r\nMary Black, skeleton, pumpkin carving, amusement park passes\n<|im_start|>answer\nAmy Smith, ghost, bobbing for apples, movie tickets\r\nRobert Brown, Frankenstein, scariest costume, $50 gift certificate\r\nBelinda Martinez, bat, ring toss, $20 gift certificate\r\nJohn Beals, Dracula, scavenger hunt, theater tickets\r\nMary Black, skeleton, pumpkin carving, amusement park passes\n<|im_end|>" }, { "id": "#23826", "title": "Flower Power", "fun": 3.19, "difficulty": 2.08, "author": "Puppypaws129", "desc": "Five women bought five different types of flowers for different reasons on different days.\r\nNames: Julia, Amy, Bethany, Rachel, and Kristen\r\nFlowers: Roses, Daisies, Lilies, Tulips, and Carnations\r\nColors: Purple, Yellow, Pink, White, and Peach\r\nPlaces or Occasions: Backyard, Park, Office, Wedding, and Birthday\r\nDays: Monday, Tuesday, Wednesday, Thursday, and Friday\n\n\n\r\n1. The flowers were purchased in the following order: tulips, the flowers for the office, the purple flowers, the roses for the park, and the white flowers bought by Julia.\n\r\n2. Bethany loves flowers but is allergic, so she would never have them indoors.\n\r\n3. It rained on Wednesday and Friday, because of this, the wedding and birthday party had to be moved indoors.\n\r\n4. Amy bought her flowers after Rachel, but before Kristen.\n\r\n5. Rachel needed something more to add to her office, so she chose peach flowers to match her curtains.\n\r\n6. On Wednesday the only purple flowers available at the flower shop were daisies.\n\r\n7. The pink flowers were bought after the carnations, but before the lilies.\n\r\n8. The flowers for the birthday were bought after the flowers for the office, but before the flowers for the wedding.", "hint": "No hint available.", "answer": "Julia: Lilies, White, Wedding, Friday\n\r\nAmy: Daisies, Purple, Birthday, Wednesday\n\r\nBethany: Tulips, Yellow, Backyard, Monday\n\r\nRachel: Carnations, Peach, Office, Tuesday\n\r\nKristen: Roses, Pink, Park, Thursday", "category": "Logic-Grid", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive women bought five different types of flowers for different reasons on different days.\r\nNames: Julia, Amy, Bethany, Rachel, and Kristen\r\nFlowers: Roses, Daisies, Lilies, Tulips, and Carnations\r\nColors: Purple, Yellow, Pink, White, and Peach\r\nPlaces or Occasions: Backyard, Park, Office, Wedding, and Birthday\r\nDays: Monday, Tuesday, Wednesday, Thursday, and Friday\n\n\n\r\n1. The flowers were purchased in the following order: tulips, the flowers for the office, the purple flowers, the roses for the park, and the white flowers bought by Julia.\n\r\n2. Bethany loves flowers but is allergic, so she would never have them indoors.\n\r\n3. It rained on Wednesday and Friday, because of this, the wedding and birthday party had to be moved indoors.\n\r\n4. Amy bought her flowers after Rachel, but before Kristen.\n\r\n5. Rachel needed something more to add to her office, so she chose peach flowers to match her curtains.\n\r\n6. On Wednesday the only purple flowers available at the flower shop were daisies.\n\r\n7. The pink flowers were bought after the carnations, but before the lilies.\n\r\n8. The flowers for the birthday were bought after the flowers for the office, but before the flowers for the wedding.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJulia: Lilies, White, Wedding, Friday\n\r\nAmy: Daisies, Purple, Birthday, Wednesday\n\r\nBethany: Tulips, Yellow, Backyard, Monday\n\r\nRachel: Carnations, Peach, Office, Tuesday\n\r\nKristen: Roses, Pink, Park, Thursday\n<|im_start|>answer\nJulia: Lilies, White, Wedding, Friday\n\r\nAmy: Daisies, Purple, Birthday, Wednesday\n\r\nBethany: Tulips, Yellow, Backyard, Monday\n\r\nRachel: Carnations, Peach, Office, Tuesday\n\r\nKristen: Roses, Pink, Park, Thursday\n<|im_end|>" }, { "id": "#31123", "title": "Birbal the Wise - VIII", "fun": 3.18, "difficulty": 1.98, "author": "Swordoffury1392", "desc": "Emperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\r\nEmperor Akbar was very fond of Birbal as were many of the village people. However, this made quite a few of Akbar's other ministers jealous.\n\r\nOne day, they decided to come up with a plan to rid them of the \"great\" Birbal. To avoid suspicion from falling on them, they took the help of the emperor's barber in this plan.\n\r\nA week later, while Akbar was receiving a haircut, the barber lightly mentioned that he knew of someone who could allow Akbar to reach and even converse with his ancestors who had passed away, but he also stated the man who would go to the heavens would have to be witty, intelligent and wise. Akbar instantly recommended Birbal for the task.\n\r\nBirbal was told that a fire would be lit around him and the smoke would carry him to heaven; however, chanting would protect him from burning to his death. Birbal instantly knew that this was a plan to get rid of him, but not wishing to anger the emperor, he agreed to perform this task in a month. During this period of time, he asked some laborers to build a tunnel connecting his house to the cemetery, where the \"rites\" would be held.\n\r\nWhen the day came, Birbal escaped his death by going to his house where he stayed for a month growing out his beard. A month later, he went back to Akbar's palace. When asked about the health of Akbar's ancestors, Birbal replied that they were doing very well but were missing just one thing.\n\r\nWhat did Birbal say they were missing in heaven?", "hint": "No hint available.", "answer": "Birbal stated that there weren't any barbers in heaven and said that was the reason for his long beard. Since Akbar now knew a way to reach them, he asked for his barber to be sent. Realizing that he would die in the fire, the emperor's barber confessed what he and the ministers did and no one dared to conspire against Birbal again.", "category": "Logic", "date": "06/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEmperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\r\nEmperor Akbar was very fond of Birbal as were many of the village people. However, this made quite a few of Akbar's other ministers jealous.\n\r\nOne day, they decided to come up with a plan to rid them of the \"great\" Birbal. To avoid suspicion from falling on them, they took the help of the emperor's barber in this plan.\n\r\nA week later, while Akbar was receiving a haircut, the barber lightly mentioned that he knew of someone who could allow Akbar to reach and even converse with his ancestors who had passed away, but he also stated the man who would go to the heavens would have to be witty, intelligent and wise. Akbar instantly recommended Birbal for the task.\n\r\nBirbal was told that a fire would be lit around him and the smoke would carry him to heaven; however, chanting would protect him from burning to his death. Birbal instantly knew that this was a plan to get rid of him, but not wishing to anger the emperor, he agreed to perform this task in a month. During this period of time, he asked some laborers to build a tunnel connecting his house to the cemetery, where the \"rites\" would be held.\n\r\nWhen the day came, Birbal escaped his death by going to his house where he stayed for a month growing out his beard. A month later, he went back to Akbar's palace. When asked about the health of Akbar's ancestors, Birbal replied that they were doing very well but were missing just one thing.\n\r\nWhat did Birbal say they were missing in heaven?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBirbal stated that there weren't any barbers in heaven and said that was the reason for his long beard. Since Akbar now knew a way to reach them, he asked for his barber to be sent. Realizing that he would die in the fire, the emperor's barber confessed what he and the ministers did and no one dared to conspire against Birbal again.\n<|im_start|>answer\nBirbal stated that there weren't any barbers in heaven and said that was the reason for his long beard. Since Akbar now knew a way to reach them, he asked for his barber to be sent. Realizing that he would die in the fire, the emperor's barber confessed what he and the ministers did and no one dared to conspire against Birbal again.\n<|im_end|>" }, { "id": "#22744", "title": "Trip to the Beach", "fun": 3.18, "difficulty": 1.9000000000000001, "author": "kellgo", "desc": "Five people (3 girls: Katie, Anna, & Grace and 2 boys Chris & Michael) are going to the beach. Each of them brought something different, a different colored towel, plans to do something and eat something. Figure out what each person brought with them, the color of their towel, what they will do at the beach, and what they will eat. Good luck! \n\r\nThe purple towel got a lot of use from the girl who was tanning.\n\r\nThe sunscreen had to be waterproof because the user got really wet.\n\r\nOf course the surfer had to bring his surfboard from home.\n\r\nEating her snocone in the shade of her umbrella kept it from melting on her blue towel.\n\r\nKetchup, from his snack, dripped all over a boy's red towel leaving red drops all over it.\n\r\nOnly the boys got more than their feet wet.\n\r\nKatie asked Anna if she thought the owner of the yellow towel would mind if Katie put her cooler on his towel while he surfed.\n\r\nThe seashell collector spread out her findings on her pink towel.\n\r\nAnna remembered her sand bucket but didn't have enough money to get a snocone after paying for her nachos.\n\r\nThe bucket wasn't used for playing in the sand.\n\r\nThe hamburger was ordered with just mayo, mustard, and pickles.\n\r\nThe hotdog eater had a little sunscreen taste to the dog because it dripped from his water soaked hair.\n\r\nBeing so fair skinned Michael had to be sure to use his high spf sunscreen when out in the water.\n\r\nThe girl who played in the sand used her umbrella to shade her.\n\r\nThe contents of the cooler contained Coke, chips, water, and ice.\n\r\nAnna is worried about wrinkles and doesn't like to tan", "hint": "No hint available.", "answer": "Katie..cooler..purple towel..tan..chips\n\r\nChris..surfboard..yellow towel..surf..hamburger\n\r\nGrace..umbrella..blue towel..play in the sand..snocone\n\r\nAnna..sand bucket..pink towel..seashells..nachos\n\r\nMichael..sunscreen..red towel..swim..hotdog", "category": "Logic-Grid", "date": "05/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people (3 girls: Katie, Anna, & Grace and 2 boys Chris & Michael) are going to the beach. Each of them brought something different, a different colored towel, plans to do something and eat something. Figure out what each person brought with them, the color of their towel, what they will do at the beach, and what they will eat. Good luck! \n\r\nThe purple towel got a lot of use from the girl who was tanning.\n\r\nThe sunscreen had to be waterproof because the user got really wet.\n\r\nOf course the surfer had to bring his surfboard from home.\n\r\nEating her snocone in the shade of her umbrella kept it from melting on her blue towel.\n\r\nKetchup, from his snack, dripped all over a boy's red towel leaving red drops all over it.\n\r\nOnly the boys got more than their feet wet.\n\r\nKatie asked Anna if she thought the owner of the yellow towel would mind if Katie put her cooler on his towel while he surfed.\n\r\nThe seashell collector spread out her findings on her pink towel.\n\r\nAnna remembered her sand bucket but didn't have enough money to get a snocone after paying for her nachos.\n\r\nThe bucket wasn't used for playing in the sand.\n\r\nThe hamburger was ordered with just mayo, mustard, and pickles.\n\r\nThe hotdog eater had a little sunscreen taste to the dog because it dripped from his water soaked hair.\n\r\nBeing so fair skinned Michael had to be sure to use his high spf sunscreen when out in the water.\n\r\nThe girl who played in the sand used her umbrella to shade her.\n\r\nThe contents of the cooler contained Coke, chips, water, and ice.\n\r\nAnna is worried about wrinkles and doesn't like to tan\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKatie..cooler..purple towel..tan..chips\n\r\nChris..surfboard..yellow towel..surf..hamburger\n\r\nGrace..umbrella..blue towel..play in the sand..snocone\n\r\nAnna..sand bucket..pink towel..seashells..nachos\n\r\nMichael..sunscreen..red towel..swim..hotdog\n<|im_start|>answer\nKatie..cooler..purple towel..tan..chips\n\r\nChris..surfboard..yellow towel..surf..hamburger\n\r\nGrace..umbrella..blue towel..play in the sand..snocone\n\r\nAnna..sand bucket..pink towel..seashells..nachos\n\r\nMichael..sunscreen..red towel..swim..hotdog\n<|im_end|>" }, { "id": "#23446", "title": "A Band of Musicians", "fun": 3.18, "difficulty": 2.16, "author": "aks_gupta07", "desc": "Five people (who vaguely know each other and are really eccentric) have a great passion for music. Each of them plays a different instrument. However, they are constantly forgetting each other's first and last names, the instrument they play, their ages and their professions. Your job is to figure out everyone's full names, their ages, their favourite instrument and their jobs.\r\n1.No person's first name shares an initial with his/her last name.\r\n2.Allen is always feeling sleepy because her neighbour has a habit of playing his drums in the middle of the night.\r\n3.Neither of the women's ages (who play the guitar and the piano) are an even number.\r\n4.The flutist is older than Joseph, who is older than Ivan, who is not the youngest.\r\n5.Michael, the scientist, is the oldest person in the group.\r\n6.Angela's last name makes Daniel feel hungry.\r\n7.Joseph is 12 years older than the doctor, who is 26 years younger than the teacher.\r\n8.Most people do not agree with the engineer (who is half as old as Coleman) that he plays the bagpipes excellently.\r\n9.Julia's career involves educating young minds.\r\n10.The lawyer lives next to Julia Allen.\r\n11.The pianist is not 21 years old.", "hint": "No hint available.", "answer": "Full name/ Age/ Profession/ Instrument\r\nAngela Bacon, 21, Doctor, Guitar\r\nDaniel Joseph, 33, Lawyer, Drums\r\nIvan Morton, 26, Engineer, Bagpipes\r\nJulia Allen, 47, Teacher, Piano\r\nMichel Coleman, 52, Scientist, Flute", "category": "Logic-Grid", "date": "06/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people (who vaguely know each other and are really eccentric) have a great passion for music. Each of them plays a different instrument. However, they are constantly forgetting each other's first and last names, the instrument they play, their ages and their professions. Your job is to figure out everyone's full names, their ages, their favourite instrument and their jobs.\r\n1.No person's first name shares an initial with his/her last name.\r\n2.Allen is always feeling sleepy because her neighbour has a habit of playing his drums in the middle of the night.\r\n3.Neither of the women's ages (who play the guitar and the piano) are an even number.\r\n4.The flutist is older than Joseph, who is older than Ivan, who is not the youngest.\r\n5.Michael, the scientist, is the oldest person in the group.\r\n6.Angela's last name makes Daniel feel hungry.\r\n7.Joseph is 12 years older than the doctor, who is 26 years younger than the teacher.\r\n8.Most people do not agree with the engineer (who is half as old as Coleman) that he plays the bagpipes excellently.\r\n9.Julia's career involves educating young minds.\r\n10.The lawyer lives next to Julia Allen.\r\n11.The pianist is not 21 years old.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFull name/ Age/ Profession/ Instrument\r\nAngela Bacon, 21, Doctor, Guitar\r\nDaniel Joseph, 33, Lawyer, Drums\r\nIvan Morton, 26, Engineer, Bagpipes\r\nJulia Allen, 47, Teacher, Piano\r\nMichel Coleman, 52, Scientist, Flute\n<|im_start|>answer\nFull name/ Age/ Profession/ Instrument\r\nAngela Bacon, 21, Doctor, Guitar\r\nDaniel Joseph, 33, Lawyer, Drums\r\nIvan Morton, 26, Engineer, Bagpipes\r\nJulia Allen, 47, Teacher, Piano\r\nMichel Coleman, 52, Scientist, Flute\n<|im_end|>" }, { "id": "#52558", "title": "The Length of the Train", "fun": 3.18, "difficulty": 3.0, "author": "wimpykidfan37", "desc": "Al and Ben are standing back to back next to a railroad track. When the front of a train passes them, Al starts to walk in the opposite direction of the train, while Ben starts to walk in the same direction as the train. Each stops walking when the back of the train passes him. If the two of them walk at the same speed, and Al walks exactly 30 feet, and Ben walks exactly 45 feet, how long is the train?", "hint": "No hint available.", "answer": "The train is 180 feet long.\n\r\nWhen the back of the train passes Al, he and Ben have both walked 30 feet, meaning Ben will walk 15 feet more when the train passes him. 30 feet that Al walks plus 45 feet that Ben walks makes 75 feet that the back of the train travels in the same time that Ben walks 15 feet, meaning the train is 5 times as fast as Al and Ben.\n\r\nIn the time it takes Al to walk 30 feet, the front of the train moves 150 feet. This distance plus the 30 feet that Al has walked equals 180 feet.", "category": "Math", "date": "01/06/21", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl and Ben are standing back to back next to a railroad track. When the front of a train passes them, Al starts to walk in the opposite direction of the train, while Ben starts to walk in the same direction as the train. Each stops walking when the back of the train passes him. If the two of them walk at the same speed, and Al walks exactly 30 feet, and Ben walks exactly 45 feet, how long is the train?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe train is 180 feet long.\n\r\nWhen the back of the train passes Al, he and Ben have both walked 30 feet, meaning Ben will walk 15 feet more when the train passes him. 30 feet that Al walks plus 45 feet that Ben walks makes 75 feet that the back of the train travels in the same time that Ben walks 15 feet, meaning the train is 5 times as fast as Al and Ben.\n\r\nIn the time it takes Al to walk 30 feet, the front of the train moves 150 feet. This distance plus the 30 feet that Al has walked equals 180 feet.\n<|im_start|>answer\nThe train is 180 feet long.\n\r\nWhen the back of the train passes Al, he and Ben have both walked 30 feet, meaning Ben will walk 15 feet more when the train passes him. 30 feet that Al walks plus 45 feet that Ben walks makes 75 feet that the back of the train travels in the same time that Ben walks 15 feet, meaning the train is 5 times as fast as Al and Ben.\n\r\nIn the time it takes Al to walk 30 feet, the front of the train moves 150 feet. This distance plus the 30 feet that Al has walked equals 180 feet.\n<|im_end|>" }, { "id": "#51796", "title": "Brown Eyes, Blue Eyes", "fun": 3.18, "difficulty": 2.89, "author": "Hydra1234", "desc": "On an otherwise deserted and isolated island, 200 perfect logicians are stranded. The islanders are perfectly logical in every decision they make, and they will not do anything unless they are absolutely certain of the outcome. However, they cannot communicate with each other. They are forbidden from speaking with one another, or signing, or writing messages in the sand, else they be smited by the god of the island.\n\r\nOf the 200 islanders, 100 have blue eyes, and 100 have brown eyes. However, no individual knows what color their own eyes are. There are no reflective surfaces on the island for the inhabitants to see a reflection of their own eyes. They can each see the 199 other islanders and their eye colors, but any given individual does not know if his or her own eyes are brown, blue, or perhaps another color entirely. And remember, they cannot communicate with each other in any way under penalty of death.\n\r\nEach night, when a ship comes, the islanders have a chance to leave the barren and desolate spit of land they have been marooned on. If an islander tells the captain of the ship the color of his or her own eyes, they may board the ship and leave. If they get it wrong, they will be shot dead.\n\r\nNow, there is one more person on the island: the guru, who the islanders know to always tell the truth. The guru has green eyes. One day, she stands up before all 200 islanders and says:\n\r\n\"I see a person with blue eyes.\"\n\r\nWho leaves the island? And when do they leave?", "hint": "What would happen if there was only one blue-eyed person on the island and the rest of the islanders were brown-eyed? What about two? What about three?", "answer": "All 100 blue-eyed people leave on the 100th night. First, we propose that two blue-eyed people are on the island. They would both leave on the second night, because they would each look at the other blue-eyed person on the second morning and realize that the only reason the other blue-eyed person wouldn't leave on the first night is because they see another person with blue eyes. Seeing no one else with blue eyes, each of these two people realize it must be them. Now consider the case of three blue-eyed islanders. It has been established that if only two people had blue eyes they would leave on the second night. You, the third blue-eyed person in our example, know this, as do the other two blue-eyed people. So when you wake up on the third morning, and the two other blue-eyed people have not left, you know that they must see another person with blue eyes, and you can see that no one else on the island has blue eyes, so you know it must be you. All three of you realize this simultaneously, and all three leave on the third night. If a fourth blue-eyed person is on the island, he will reason the scenario with three blue-eyed people on the island, and when he sees that they have not left the island during the fourth morning, he/she/it will leave the island on the fourth day, and so will all the other blue-eyed people. If we follow this pattern, we will eventually reach the answer of 100 people leaving the island after 100 days.", "category": "Logic", "date": "03/29/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn an otherwise deserted and isolated island, 200 perfect logicians are stranded. The islanders are perfectly logical in every decision they make, and they will not do anything unless they are absolutely certain of the outcome. However, they cannot communicate with each other. They are forbidden from speaking with one another, or signing, or writing messages in the sand, else they be smited by the god of the island.\n\r\nOf the 200 islanders, 100 have blue eyes, and 100 have brown eyes. However, no individual knows what color their own eyes are. There are no reflective surfaces on the island for the inhabitants to see a reflection of their own eyes. They can each see the 199 other islanders and their eye colors, but any given individual does not know if his or her own eyes are brown, blue, or perhaps another color entirely. And remember, they cannot communicate with each other in any way under penalty of death.\n\r\nEach night, when a ship comes, the islanders have a chance to leave the barren and desolate spit of land they have been marooned on. If an islander tells the captain of the ship the color of his or her own eyes, they may board the ship and leave. If they get it wrong, they will be shot dead.\n\r\nNow, there is one more person on the island: the guru, who the islanders know to always tell the truth. The guru has green eyes. One day, she stands up before all 200 islanders and says:\n\r\n\"I see a person with blue eyes.\"\n\r\nWho leaves the island? And when do they leave?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll 100 blue-eyed people leave on the 100th night. First, we propose that two blue-eyed people are on the island. They would both leave on the second night, because they would each look at the other blue-eyed person on the second morning and realize that the only reason the other blue-eyed person wouldn't leave on the first night is because they see another person with blue eyes. Seeing no one else with blue eyes, each of these two people realize it must be them. Now consider the case of three blue-eyed islanders. It has been established that if only two people had blue eyes they would leave on the second night. You, the third blue-eyed person in our example, know this, as do the other two blue-eyed people. So when you wake up on the third morning, and the two other blue-eyed people have not left, you know that they must see another person with blue eyes, and you can see that no one else on the island has blue eyes, so you know it must be you. All three of you realize this simultaneously, and all three leave on the third night. If a fourth blue-eyed person is on the island, he will reason the scenario with three blue-eyed people on the island, and when he sees that they have not left the island during the fourth morning, he/she/it will leave the island on the fourth day, and so will all the other blue-eyed people. If we follow this pattern, we will eventually reach the answer of 100 people leaving the island after 100 days.\n<|im_start|>answer\nAll 100 blue-eyed people leave on the 100th night. First, we propose that two blue-eyed people are on the island. They would both leave on the second night, because they would each look at the other blue-eyed person on the second morning and realize that the only reason the other blue-eyed person wouldn't leave on the first night is because they see another person with blue eyes. Seeing no one else with blue eyes, each of these two people realize it must be them. Now consider the case of three blue-eyed islanders. It has been established that if only two people had blue eyes they would leave on the second night. You, the third blue-eyed person in our example, know this, as do the other two blue-eyed people. So when you wake up on the third morning, and the two other blue-eyed people have not left, you know that they must see another person with blue eyes, and you can see that no one else on the island has blue eyes, so you know it must be you. All three of you realize this simultaneously, and all three leave on the third night. If a fourth blue-eyed person is on the island, he will reason the scenario with three blue-eyed people on the island, and when he sees that they have not left the island during the fourth morning, he/she/it will leave the island on the fourth day, and so will all the other blue-eyed people. If we follow this pattern, we will eventually reach the answer of 100 people leaving the island after 100 days.\n<|im_end|>" }, { "id": "#50389", "title": "The Mysterious Murder of Mr. Mentum", "fun": 3.17, "difficulty": 1.33, "author": "trewq", "desc": "Two nights ago at a dinner party, Mr. Mentum was killed by one of his guests. Detective Dens was put on the case and took statements. But the good detective is getting a tooth pulled today so you, a rookie officer, are called in to take on his case. From his notes you glean the following information about people's whereabouts and potential murder weapons:\n\r\nNames: Fawn, Jake, Kyle, Lance, Sara\r\nRooms: bedroom, conservatory, dining room, observatory, sitting room\r\nWeapons: candlestick, gun, knife, poison, rope\n\r\nEither Lance was in the dining room, or the man with the knife was in the sitting room.\r\nEither Jake had the rope, or Lance was in the observatory.\r\nEither Kyle was in the conservatory, or Jake was in the bedroom.\r\nThe five suspects are Sara, the person in the bedroom, the person in the dining room, the person with the rope, and the person with the knife.\r\nThe woman with the poison was not in the dining room.\r\nThe rope was in the sitting room, and the gun was in the bedroom.\n\r\nAfter some intense scrutinizing and a couple cups of coffee, you take your solution of each person's location and weapon of choice to the police. Since the body was found in the observatory, they know just who to bring in for extra questioning.", "hint": "No hint available.", "answer": "Fawn had the gun in the bedroom.\r\nJake had the rope in the sitting room.\r\nKyle had the knife in the conservatory.\r\nLance had the candlestick in the dining room.\r\nSara had the poison in the observatory.\n\r\nYou bring Sara in and she confesses after a brief interrogation. Detective Dens is pleased with your good work and gives you a commemorative plaque!", "category": "Logic-Grid", "date": "07/04/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo nights ago at a dinner party, Mr. Mentum was killed by one of his guests. Detective Dens was put on the case and took statements. But the good detective is getting a tooth pulled today so you, a rookie officer, are called in to take on his case. From his notes you glean the following information about people's whereabouts and potential murder weapons:\n\r\nNames: Fawn, Jake, Kyle, Lance, Sara\r\nRooms: bedroom, conservatory, dining room, observatory, sitting room\r\nWeapons: candlestick, gun, knife, poison, rope\n\r\nEither Lance was in the dining room, or the man with the knife was in the sitting room.\r\nEither Jake had the rope, or Lance was in the observatory.\r\nEither Kyle was in the conservatory, or Jake was in the bedroom.\r\nThe five suspects are Sara, the person in the bedroom, the person in the dining room, the person with the rope, and the person with the knife.\r\nThe woman with the poison was not in the dining room.\r\nThe rope was in the sitting room, and the gun was in the bedroom.\n\r\nAfter some intense scrutinizing and a couple cups of coffee, you take your solution of each person's location and weapon of choice to the police. Since the body was found in the observatory, they know just who to bring in for extra questioning.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFawn had the gun in the bedroom.\r\nJake had the rope in the sitting room.\r\nKyle had the knife in the conservatory.\r\nLance had the candlestick in the dining room.\r\nSara had the poison in the observatory.\n\r\nYou bring Sara in and she confesses after a brief interrogation. Detective Dens is pleased with your good work and gives you a commemorative plaque!\n<|im_start|>answer\nFawn had the gun in the bedroom.\r\nJake had the rope in the sitting room.\r\nKyle had the knife in the conservatory.\r\nLance had the candlestick in the dining room.\r\nSara had the poison in the observatory.\n\r\nYou bring Sara in and she confesses after a brief interrogation. Detective Dens is pleased with your good work and gives you a commemorative plaque!\n<|im_end|>" }, { "id": "#28034", "title": "Bowling Buddies", "fun": 3.17, "difficulty": 3.06, "author": "Dave", "desc": "Five guys meet at college, and become the best of buddies when they discover that they have a common interest in ten-pin bowling. Not only are they avid bowlers, but they also have an eccentric taste in the pattern on their bowling ball.\r\nThey each play for a different team during the week, but get together on Saturday nights to find out which of them is the best.\r\nFrom the following clues, can you find out each of their names, the local team they play for, the pattern on their bowling ball, and how many points each scored in the first game.\n\r\nNotes:\r\nStrike - all ten pins are knocked down on the first ball.\r\nSpare - all ten pins are knocked down using two balls.\r\nYou do not need to keep track of the scoring - all the final scores can be deduced from the clues. When 'score' is mentioned in the clues, it means the final score, not the score at that point in the game.\n\r\n1st Frame: The five buddies bowled in turn, in the following order: Fred; the bowler with the tiger print ball; the bowler who scored 227; Johnson; and the bowler who plays for the Golden Gates. Only the second bowler, Dawson, did not get a strike with his first delivery, although he did get a spare.\n\r\n2nd Frame: The players with the top three scores, Eddie, the Snake Eyes' bowler and the Picket Fences' bowler, all managed strikes this frame, while Johnson and the Dead Woods' bowler both got spares.\n\r\n3rd Frame: The Dead Woods' bowler had a terrible bowl, only knocking down three pins, but still managed to crack a joke with Dawson as Dave was hitting his turkey (third strike in a row).\n\r\n4th Frame: Flagg, the Flying Elbows' bowler and the bowler with the flame pattern ball all hit strikes. The Picket Fences' bowler and Fred both got a spare.\n\r\n5th Frame: Steve, the Snake Eyes' bowler, the owner of the globe ball, and the Golden Gates' bowler all had strikes. Garrett managed a spare.\n\r\n6th Frame: This was nearly a disaster for the bowler with the leopard ball which just clipped the 7 pin on its way into the gutter. Luckily, he made the spare, which meant he scored more than the bowler with 192.\n\r\n7th Frame: The bowler with the cow print ball was the only one to get a strike this round. Steve, the Flying Elbows' bowler, the bowler with 214, and Hobson did not even get a spare.\n\r\n8th Frame: Dave only managed a spare this frame, while Carl, who bowled just after him, got a strike. Neither of them ended up with 205 points.\n\r\n9th Frame: The bowler with an intricate map of the world on his ball scored a strike this frame, as did Steve. Flagg got a spare.\n\r\n10th Frame: The losers congratulated the 'Flame' thrower on a game well played, and Garrett went to the bar to get in the drinks as he had the lowest score with 186.", "hint": "If you get to the end, and can't differentiate between Carl and Dave, check clues 1 and 8.", "answer": "Carl Johnson - Flying Elbows - Globe - 192\r\nDave Hobson - Snake Eyes - Flame - 227\r\nEddie Flagg - Golden Gates - Leopard - 214\r\nFred Garrett - Dead Woods - Cow - 186\r\nSteve Dawson - Picket Fences - Tiger - 205\n\r\nLogical solution:\n\r\nC = The above clue number\r\nF = Fact deduced\r\nS = A solution\n\r\nF1\tDawson has the tiger ball (C1).\r\nF2\tGarrett does not have the tiger (F1), globe (C5), leopard (C6/C10) or flame (C10), so must have the cow ball.\r\nF3\tGarrett does not play for SE (C2), PF (C2), GG (C5) or FE (C7/F2) so must play for Dead Woods.\r\nF4\tFlagg does not have the tiger (F1), cow (F2), flame (C4) or globe (C9) so must be the leopard ball.\r\nF5\tJohnson did not score 205, 214, 227 (C2) or 186 (C10) so 192.\r\nF6\tJohnson did not play for DW (F3), GG (C1), SE (C2), PF (C2) so Flying Elbows.\r\nF7\tJohnson does not have the tiger (F1), cow (F2), leopard (F4), flame (F5/C10) so globe ball.\r\nF8\tHobson has the flame ball (F1, F2, F4, F7).\r\nF9\tSteve is not Garrett (C5), Hobson (C7), Flagg (C9), Johnson (C7/F6) so is Dawson.\r\nF10\tSteve does not play for SE (C5), GG (C5), FE (C7) or DW (C3/F9) so Picket Fences.\r\nF11\tSteve did not score 227 (C1/F9/F1), 186 or 192 (C2/F10) or 214 (C7) so 205.\r\nS1\tSteve - Dawson (F9) - Picket Fences (F10) - Tiger (F1) - 205 (F11).\r\nF12\tFlagg did not score 205 (S1), 186 (C10), 192 (F5) or 227 (C10/F4) so 214.\r\nF13\tFred did not score 205 (S1), 227 (C1), 214 (C4/F12) or 192 (C1/F5) so 186.\r\nS2\tFred - Garrett (C10/F13) - Dead Woods (F3) - Cow (F2) - 186 (F13). \r\nF14\tHobson scored 227 (S1, S2, F5, F12).\r\nF15\tHobson does not play for PF (S1), DW (S2), FE (F6) or GG (C1/F14) so Snake Eyes.\r\nF16\tFlagg plays for Golden Gates (S1, S2, F6, F15).\r\nF17\tEddie does not play for PF (S1), DW (S2), SE (F15) or FE(C2/F6) so Golden Gates.\r\nS3\tEddie - Flagg (F17/F16) - Golden Gates (F17) - Leopard (F4) - 214 (F12).\r\nF18\tEither Carl or Dave is Johnson, and the other scored 227 (C1).\r\nF19\tCarl bowled after Dave (C8) so Dave scored 227 and Carl is Johnson (C1).\r\nS4\tCarl - Johnson (F19) - Flying Elbows (F6) - Globe (F7) - 192 (F5).\r\nS5\tDave - Hobson (F19) - Snake Eyes (F15) - Flame (F8) - 227 (F14).", "category": "Logic-Grid", "date": "01/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive guys meet at college, and become the best of buddies when they discover that they have a common interest in ten-pin bowling. Not only are they avid bowlers, but they also have an eccentric taste in the pattern on their bowling ball.\r\nThey each play for a different team during the week, but get together on Saturday nights to find out which of them is the best.\r\nFrom the following clues, can you find out each of their names, the local team they play for, the pattern on their bowling ball, and how many points each scored in the first game.\n\r\nNotes:\r\nStrike - all ten pins are knocked down on the first ball.\r\nSpare - all ten pins are knocked down using two balls.\r\nYou do not need to keep track of the scoring - all the final scores can be deduced from the clues. When 'score' is mentioned in the clues, it means the final score, not the score at that point in the game.\n\r\n1st Frame: The five buddies bowled in turn, in the following order: Fred; the bowler with the tiger print ball; the bowler who scored 227; Johnson; and the bowler who plays for the Golden Gates. Only the second bowler, Dawson, did not get a strike with his first delivery, although he did get a spare.\n\r\n2nd Frame: The players with the top three scores, Eddie, the Snake Eyes' bowler and the Picket Fences' bowler, all managed strikes this frame, while Johnson and the Dead Woods' bowler both got spares.\n\r\n3rd Frame: The Dead Woods' bowler had a terrible bowl, only knocking down three pins, but still managed to crack a joke with Dawson as Dave was hitting his turkey (third strike in a row).\n\r\n4th Frame: Flagg, the Flying Elbows' bowler and the bowler with the flame pattern ball all hit strikes. The Picket Fences' bowler and Fred both got a spare.\n\r\n5th Frame: Steve, the Snake Eyes' bowler, the owner of the globe ball, and the Golden Gates' bowler all had strikes. Garrett managed a spare.\n\r\n6th Frame: This was nearly a disaster for the bowler with the leopard ball which just clipped the 7 pin on its way into the gutter. Luckily, he made the spare, which meant he scored more than the bowler with 192.\n\r\n7th Frame: The bowler with the cow print ball was the only one to get a strike this round. Steve, the Flying Elbows' bowler, the bowler with 214, and Hobson did not even get a spare.\n\r\n8th Frame: Dave only managed a spare this frame, while Carl, who bowled just after him, got a strike. Neither of them ended up with 205 points.\n\r\n9th Frame: The bowler with an intricate map of the world on his ball scored a strike this frame, as did Steve. Flagg got a spare.\n\r\n10th Frame: The losers congratulated the 'Flame' thrower on a game well played, and Garrett went to the bar to get in the drinks as he had the lowest score with 186.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarl Johnson - Flying Elbows - Globe - 192\r\nDave Hobson - Snake Eyes - Flame - 227\r\nEddie Flagg - Golden Gates - Leopard - 214\r\nFred Garrett - Dead Woods - Cow - 186\r\nSteve Dawson - Picket Fences - Tiger - 205\n\r\nLogical solution:\n\r\nC = The above clue number\r\nF = Fact deduced\r\nS = A solution\n\r\nF1\tDawson has the tiger ball (C1).\r\nF2\tGarrett does not have the tiger (F1), globe (C5), leopard (C6/C10) or flame (C10), so must have the cow ball.\r\nF3\tGarrett does not play for SE (C2), PF (C2), GG (C5) or FE (C7/F2) so must play for Dead Woods.\r\nF4\tFlagg does not have the tiger (F1), cow (F2), flame (C4) or globe (C9) so must be the leopard ball.\r\nF5\tJohnson did not score 205, 214, 227 (C2) or 186 (C10) so 192.\r\nF6\tJohnson did not play for DW (F3), GG (C1), SE (C2), PF (C2) so Flying Elbows.\r\nF7\tJohnson does not have the tiger (F1), cow (F2), leopard (F4), flame (F5/C10) so globe ball.\r\nF8\tHobson has the flame ball (F1, F2, F4, F7).\r\nF9\tSteve is not Garrett (C5), Hobson (C7), Flagg (C9), Johnson (C7/F6) so is Dawson.\r\nF10\tSteve does not play for SE (C5), GG (C5), FE (C7) or DW (C3/F9) so Picket Fences.\r\nF11\tSteve did not score 227 (C1/F9/F1), 186 or 192 (C2/F10) or 214 (C7) so 205.\r\nS1\tSteve - Dawson (F9) - Picket Fences (F10) - Tiger (F1) - 205 (F11).\r\nF12\tFlagg did not score 205 (S1), 186 (C10), 192 (F5) or 227 (C10/F4) so 214.\r\nF13\tFred did not score 205 (S1), 227 (C1), 214 (C4/F12) or 192 (C1/F5) so 186.\r\nS2\tFred - Garrett (C10/F13) - Dead Woods (F3) - Cow (F2) - 186 (F13). \r\nF14\tHobson scored 227 (S1, S2, F5, F12).\r\nF15\tHobson does not play for PF (S1), DW (S2), FE (F6) or GG (C1/F14) so Snake Eyes.\r\nF16\tFlagg plays for Golden Gates (S1, S2, F6, F15).\r\nF17\tEddie does not play for PF (S1), DW (S2), SE (F15) or FE(C2/F6) so Golden Gates.\r\nS3\tEddie - Flagg (F17/F16) - Golden Gates (F17) - Leopard (F4) - 214 (F12).\r\nF18\tEither Carl or Dave is Johnson, and the other scored 227 (C1).\r\nF19\tCarl bowled after Dave (C8) so Dave scored 227 and Carl is Johnson (C1).\r\nS4\tCarl - Johnson (F19) - Flying Elbows (F6) - Globe (F7) - 192 (F5).\r\nS5\tDave - Hobson (F19) - Snake Eyes (F15) - Flame (F8) - 227 (F14).\n<|im_start|>answer\nCarl Johnson - Flying Elbows - Globe - 192\r\nDave Hobson - Snake Eyes - Flame - 227\r\nEddie Flagg - Golden Gates - Leopard - 214\r\nFred Garrett - Dead Woods - Cow - 186\r\nSteve Dawson - Picket Fences - Tiger - 205\n\r\nLogical solution:\n\r\nC = The above clue number\r\nF = Fact deduced\r\nS = A solution\n\r\nF1\tDawson has the tiger ball (C1).\r\nF2\tGarrett does not have the tiger (F1), globe (C5), leopard (C6/C10) or flame (C10), so must have the cow ball.\r\nF3\tGarrett does not play for SE (C2), PF (C2), GG (C5) or FE (C7/F2) so must play for Dead Woods.\r\nF4\tFlagg does not have the tiger (F1), cow (F2), flame (C4) or globe (C9) so must be the leopard ball.\r\nF5\tJohnson did not score 205, 214, 227 (C2) or 186 (C10) so 192.\r\nF6\tJohnson did not play for DW (F3), GG (C1), SE (C2), PF (C2) so Flying Elbows.\r\nF7\tJohnson does not have the tiger (F1), cow (F2), leopard (F4), flame (F5/C10) so globe ball.\r\nF8\tHobson has the flame ball (F1, F2, F4, F7).\r\nF9\tSteve is not Garrett (C5), Hobson (C7), Flagg (C9), Johnson (C7/F6) so is Dawson.\r\nF10\tSteve does not play for SE (C5), GG (C5), FE (C7) or DW (C3/F9) so Picket Fences.\r\nF11\tSteve did not score 227 (C1/F9/F1), 186 or 192 (C2/F10) or 214 (C7) so 205.\r\nS1\tSteve - Dawson (F9) - Picket Fences (F10) - Tiger (F1) - 205 (F11).\r\nF12\tFlagg did not score 205 (S1), 186 (C10), 192 (F5) or 227 (C10/F4) so 214.\r\nF13\tFred did not score 205 (S1), 227 (C1), 214 (C4/F12) or 192 (C1/F5) so 186.\r\nS2\tFred - Garrett (C10/F13) - Dead Woods (F3) - Cow (F2) - 186 (F13). \r\nF14\tHobson scored 227 (S1, S2, F5, F12).\r\nF15\tHobson does not play for PF (S1), DW (S2), FE (F6) or GG (C1/F14) so Snake Eyes.\r\nF16\tFlagg plays for Golden Gates (S1, S2, F6, F15).\r\nF17\tEddie does not play for PF (S1), DW (S2), SE (F15) or FE(C2/F6) so Golden Gates.\r\nS3\tEddie - Flagg (F17/F16) - Golden Gates (F17) - Leopard (F4) - 214 (F12).\r\nF18\tEither Carl or Dave is Johnson, and the other scored 227 (C1).\r\nF19\tCarl bowled after Dave (C8) so Dave scored 227 and Carl is Johnson (C1).\r\nS4\tCarl - Johnson (F19) - Flying Elbows (F6) - Globe (F7) - 192 (F5).\r\nS5\tDave - Hobson (F19) - Snake Eyes (F15) - Flame (F8) - 227 (F14).\n<|im_end|>" }, { "id": "#29668", "title": "The Dealership, Part 1", "fun": 3.17, "difficulty": 2.84, "author": "thompson1", "desc": "\"Car\"-l (Carl) Smith owns a used-car dealership in Cartown, Missouri. In the past week, he has had 5 different people sell him 5 different cars on 5 different days. He was carrying papers with the information about the purchases, when one of the cars that was near him honked very loudly. He dropped all of the papers, and couldn't figure out any of the information. Help Carl figure out each customer's first and last name, what car they sold him, how much each one cost, and what day of the week they sold to him on.\n\r\nFirst names - George, James, Brad, Jessica, and Patricia\r\nLast names - Robertson, Johnson, Buckner, Thompson, and Sullivan\r\nCar - Mini, BMW, Mercedes, Jaguar, and Ford\r\nAmount of $ - $10,000, $15,000, $21,000, $28,000, and $35,000\r\nDay of the Week - Monday, Tuesday, Wednesday, Thursday, and Saturday\n\r\n1. The 5 people are: George, Thompson, the one who sold the Mini, the one who sold the car for $35,000, and the one who sold a car on Wednesday.\n\r\n2. The 5 cars are: the BMW, the one sold on Saturday, the one sold by Mrs. Johnson, the one sold by Jessica, and the one that was sold for $15,000.\n\r\n3. The person who sold a car 2 days before Robertson did sold his car for $7,000 less than James.\n\r\n4. Thompson sold his car for 4000 times as many dollars as there are letters in the day that he sold it.\n\r\n5. Buckner sold his car for $35,000.\n\r\n6. The Ford, which was sold by Sullivan, was sold for $13,000 less than the car sold on Tuesday.\n\r\n7. The Mercedes sold for the most amount of money, which was $14,000 more than the one sold on Wednesday.", "hint": "No hint available.", "answer": "George Sullivan sold his Ford for $15,000 on Monday.\r\nJames Buckner sold his Mercedes for $35,000 on Saturday.\r\nBrad Thompson sold his BMW for $28,000 on Tuesday.\r\nJessica Robertson sold her Mini for $10,000 on Thursday.\r\nPatricia Johnson sold her Jaguar for $21,000 on Wednesday.\n\r\nMake sure you write down the answers if you are going to try Part 2!", "category": "Logic-Grid", "date": "04/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"Car\"-l (Carl) Smith owns a used-car dealership in Cartown, Missouri. In the past week, he has had 5 different people sell him 5 different cars on 5 different days. He was carrying papers with the information about the purchases, when one of the cars that was near him honked very loudly. He dropped all of the papers, and couldn't figure out any of the information. Help Carl figure out each customer's first and last name, what car they sold him, how much each one cost, and what day of the week they sold to him on.\n\r\nFirst names - George, James, Brad, Jessica, and Patricia\r\nLast names - Robertson, Johnson, Buckner, Thompson, and Sullivan\r\nCar - Mini, BMW, Mercedes, Jaguar, and Ford\r\nAmount of $ - $10,000, $15,000, $21,000, $28,000, and $35,000\r\nDay of the Week - Monday, Tuesday, Wednesday, Thursday, and Saturday\n\r\n1. The 5 people are: George, Thompson, the one who sold the Mini, the one who sold the car for $35,000, and the one who sold a car on Wednesday.\n\r\n2. The 5 cars are: the BMW, the one sold on Saturday, the one sold by Mrs. Johnson, the one sold by Jessica, and the one that was sold for $15,000.\n\r\n3. The person who sold a car 2 days before Robertson did sold his car for $7,000 less than James.\n\r\n4. Thompson sold his car for 4000 times as many dollars as there are letters in the day that he sold it.\n\r\n5. Buckner sold his car for $35,000.\n\r\n6. The Ford, which was sold by Sullivan, was sold for $13,000 less than the car sold on Tuesday.\n\r\n7. The Mercedes sold for the most amount of money, which was $14,000 more than the one sold on Wednesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGeorge Sullivan sold his Ford for $15,000 on Monday.\r\nJames Buckner sold his Mercedes for $35,000 on Saturday.\r\nBrad Thompson sold his BMW for $28,000 on Tuesday.\r\nJessica Robertson sold her Mini for $10,000 on Thursday.\r\nPatricia Johnson sold her Jaguar for $21,000 on Wednesday.\n\r\nMake sure you write down the answers if you are going to try Part 2!\n<|im_start|>answer\nGeorge Sullivan sold his Ford for $15,000 on Monday.\r\nJames Buckner sold his Mercedes for $35,000 on Saturday.\r\nBrad Thompson sold his BMW for $28,000 on Tuesday.\r\nJessica Robertson sold her Mini for $10,000 on Thursday.\r\nPatricia Johnson sold her Jaguar for $21,000 on Wednesday.\n\r\nMake sure you write down the answers if you are going to try Part 2!\n<|im_end|>" }, { "id": "#39664", "title": "Lotsa Lattes", "fun": 3.17, "difficulty": 2.22, "author": "daliz", "desc": "It's rush time at Lotsa Lattes, the popular downtown coffee shop. Jamie, the poor barista, just had 5 orders told to her over the sound of the coffee grinder. Help her piece together the correct orders to make sure she'll get tipped.\n\r\nEach guest ordered a different drink and a different type of muffin. \n\r\n1. Gary was in line before Lisa this morning, but he decided not to order his usual (mocha and a blueberry muffin) and instead tried something new to eat and drink.\n\r\n2. By the time Zack got there, the raspberry muffin had just been ordered by the person ahead of him in line. He ordered an extra dry cappuccino while he decided that morning's muffin choice.\n\r\n3. The 5 orders were: the mocha, the man who ordered the poppyseed muffin, the 2nd person in line, the tea, and Paul's order.\n\r\n4. The people who ordered something to drink with chocolate in it (including the mocha) could not possibly eat a chocolate chip muffin, too. No chocolate item was ordered first.\n\r\n5. The men, oddly enough, placed the odd numbered orders.\n\r\n6. The blueberry muffin was ordered before Paul's order but after the hot chocolate.\n\r\n7. The 3 fruit muffins were sold to Lisa, the first person in line, and to the person who also ordered a mocha.", "hint": "No hint available.", "answer": "Lisa - hot chocolate -2nd in line - raspberry muffin\n\r\nPaul - latte - 5th in line - chocolate chip muffin\n\r\nJanice - mocha - 4th in line - blueberry muffin\n\r\nGary - tea - 1st in line - apple muffin\n\r\nZack - cappuccino - 3rd in line - poppyseed muffin", "category": "Logic-Grid", "date": "12/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's rush time at Lotsa Lattes, the popular downtown coffee shop. Jamie, the poor barista, just had 5 orders told to her over the sound of the coffee grinder. Help her piece together the correct orders to make sure she'll get tipped.\n\r\nEach guest ordered a different drink and a different type of muffin. \n\r\n1. Gary was in line before Lisa this morning, but he decided not to order his usual (mocha and a blueberry muffin) and instead tried something new to eat and drink.\n\r\n2. By the time Zack got there, the raspberry muffin had just been ordered by the person ahead of him in line. He ordered an extra dry cappuccino while he decided that morning's muffin choice.\n\r\n3. The 5 orders were: the mocha, the man who ordered the poppyseed muffin, the 2nd person in line, the tea, and Paul's order.\n\r\n4. The people who ordered something to drink with chocolate in it (including the mocha) could not possibly eat a chocolate chip muffin, too. No chocolate item was ordered first.\n\r\n5. The men, oddly enough, placed the odd numbered orders.\n\r\n6. The blueberry muffin was ordered before Paul's order but after the hot chocolate.\n\r\n7. The 3 fruit muffins were sold to Lisa, the first person in line, and to the person who also ordered a mocha.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLisa - hot chocolate -2nd in line - raspberry muffin\n\r\nPaul - latte - 5th in line - chocolate chip muffin\n\r\nJanice - mocha - 4th in line - blueberry muffin\n\r\nGary - tea - 1st in line - apple muffin\n\r\nZack - cappuccino - 3rd in line - poppyseed muffin\n<|im_start|>answer\nLisa - hot chocolate -2nd in line - raspberry muffin\n\r\nPaul - latte - 5th in line - chocolate chip muffin\n\r\nJanice - mocha - 4th in line - blueberry muffin\n\r\nGary - tea - 1st in line - apple muffin\n\r\nZack - cappuccino - 3rd in line - poppyseed muffin\n<|im_end|>" }, { "id": "#52128", "title": "The Troll Bridge 3", "fun": 3.17, "difficulty": 2.41, "author": "wimpykidfan37", "desc": "A bridge was guarded by an evil troll. The troll was very intelligent, but he was also a coward. He was afraid of anyone smarter than him. So every time anyone tried to cross the bridge, the troll would set up a test. If the traveler passed the test, he would be allowed to cross. Otherwise, the troll would eat him.\n\r\nA judge named Oscar came across the bridge. The troll said, \"You may only cross my bridge if you know the password.\" He then wrote 26 equations on a rock: A=1, B=2, and so on until Z=26.\n\r\n\"Today's password is the name of a woman,\" said the troll. \"The woman's name has the same 'product' as the word JUDGE, that is, 10*21*4*7*5. It also has the same number of letters as JUDGE. However it has no letters in common with JUDGE.\"\n\r\n\"When the first and second letters in the woman's name are switched around, the letters are in alphabetical order.\"\n\r\n\"Finally,\" said the troll, \"the woman's name does not contain the letter C because I despise the number 3.\"\n\r\nSo, what is the password? And why couldn't the troll use similar rules to create a password using the name OSCAR rather than the word JUDGE?", "hint": "1. It is unnecessary, and even inconvenient, to multiply 10*21*4*7*5.\n\r\n2. This puzzle requires knowledge of women's first names.", "answer": "The password is FANNY.\n\r\nThe woman's name cannot contain G or U, so since 14 is the only other multiple of 7 to be less than or equal to 26, the name must contain two N's. Dividing by 14 twice, we get 10*3*5.\n\r\nSince two of these numbers are divisible by 5, the name must contain either two letters divisible by 5 or one letter divisible by 25. It obviously cannot contain E or J. It cannot contain T because 10*3*5 is not divisible by 20. It cannot contain O because dividing 10*3*5 by 15 gives us 10, which would mean that E or J is in the name. So it must contain Y. Dividing by 25 gives us 2*3.\n\r\n2*3 is one of only two pairs of numbers that multiplies to give us 6, the other being 1*6. So the remaining two letters must be either B and C or A and F. But since C is not in the password, the remaining two letters must be A and F.\n\r\nPutting the five letters in order, we get AFNNY. Switching around the first two letters, we get FANNY.\n\r\nThe reason why the troll couldn't use similar rules to create a password using the name OSCAR is because S is the 19th letter of the alphabet, and 19 is a prime number and the only number less than or equal to 26 to be a multiple of 19.", "category": "Math", "date": "02/05/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bridge was guarded by an evil troll. The troll was very intelligent, but he was also a coward. He was afraid of anyone smarter than him. So every time anyone tried to cross the bridge, the troll would set up a test. If the traveler passed the test, he would be allowed to cross. Otherwise, the troll would eat him.\n\r\nA judge named Oscar came across the bridge. The troll said, \"You may only cross my bridge if you know the password.\" He then wrote 26 equations on a rock: A=1, B=2, and so on until Z=26.\n\r\n\"Today's password is the name of a woman,\" said the troll. \"The woman's name has the same 'product' as the word JUDGE, that is, 10*21*4*7*5. It also has the same number of letters as JUDGE. However it has no letters in common with JUDGE.\"\n\r\n\"When the first and second letters in the woman's name are switched around, the letters are in alphabetical order.\"\n\r\n\"Finally,\" said the troll, \"the woman's name does not contain the letter C because I despise the number 3.\"\n\r\nSo, what is the password? And why couldn't the troll use similar rules to create a password using the name OSCAR rather than the word JUDGE?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe password is FANNY.\n\r\nThe woman's name cannot contain G or U, so since 14 is the only other multiple of 7 to be less than or equal to 26, the name must contain two N's. Dividing by 14 twice, we get 10*3*5.\n\r\nSince two of these numbers are divisible by 5, the name must contain either two letters divisible by 5 or one letter divisible by 25. It obviously cannot contain E or J. It cannot contain T because 10*3*5 is not divisible by 20. It cannot contain O because dividing 10*3*5 by 15 gives us 10, which would mean that E or J is in the name. So it must contain Y. Dividing by 25 gives us 2*3.\n\r\n2*3 is one of only two pairs of numbers that multiplies to give us 6, the other being 1*6. So the remaining two letters must be either B and C or A and F. But since C is not in the password, the remaining two letters must be A and F.\n\r\nPutting the five letters in order, we get AFNNY. Switching around the first two letters, we get FANNY.\n\r\nThe reason why the troll couldn't use similar rules to create a password using the name OSCAR is because S is the 19th letter of the alphabet, and 19 is a prime number and the only number less than or equal to 26 to be a multiple of 19.\n<|im_start|>answer\nThe password is FANNY.\n\r\nThe woman's name cannot contain G or U, so since 14 is the only other multiple of 7 to be less than or equal to 26, the name must contain two N's. Dividing by 14 twice, we get 10*3*5.\n\r\nSince two of these numbers are divisible by 5, the name must contain either two letters divisible by 5 or one letter divisible by 25. It obviously cannot contain E or J. It cannot contain T because 10*3*5 is not divisible by 20. It cannot contain O because dividing 10*3*5 by 15 gives us 10, which would mean that E or J is in the name. So it must contain Y. Dividing by 25 gives us 2*3.\n\r\n2*3 is one of only two pairs of numbers that multiplies to give us 6, the other being 1*6. So the remaining two letters must be either B and C or A and F. But since C is not in the password, the remaining two letters must be A and F.\n\r\nPutting the five letters in order, we get AFNNY. Switching around the first two letters, we get FANNY.\n\r\nThe reason why the troll couldn't use similar rules to create a password using the name OSCAR is because S is the 19th letter of the alphabet, and 19 is a prime number and the only number less than or equal to 26 to be a multiple of 19.\n<|im_end|>" }, { "id": "#39837", "title": "The Flawed Game", "fun": 3.16, "difficulty": 1.36, "author": "coolguy5678", "desc": "A teacher was having trouble getting her students to learn their facts, but she noticed that her students often played the game \"Rock, Paper, Scissors\". She made a game with similar rules in order to encourage the students to learn their facts.\n\r\nThe class would be divided into three teams: Rock, Paper and Scissors. The teacher would ask the students a question and the class would raise their hands if they knew the answer. If the first person to answer the question correctly is in the Rock team, he or she would choose one player from the Scissors team to be eliminated. Similarly, if a player from the Scissors team was first to answer the question, then he or she would eliminate a member from the Paper team. Lastly, if a player from the Paper team was first to answer correctly, he or she would eliminate a member from the Rock team.\n\r\nThe teacher would then continue asking questions until only one team still has members. That team would be declared the winner and all its members would win a small chocolate.\n\r\nHowever, as soon as she explained the rules to the class, one particularly smart student immediately found a large flaw that made the game unplayable. Can you do the same?", "hint": "Think about what would happen after one team loses all its members.", "answer": "After one team loses all its members, the team that it eliminates members from will always win. For example, say the Scissors team is the first team to lose all its members. It is now impossible for the Paper team to lose any members, but the Paper team can still eliminate members from Rock team, so it will eventually win (if the Rock team answers questions, there would be no one left for them to eliminate so nothing would happen). This means that the best strategy is actually to avoid answering questions until one team is eliminated. If all the players know this, the game would never end.", "category": "Logic", "date": "12/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA teacher was having trouble getting her students to learn their facts, but she noticed that her students often played the game \"Rock, Paper, Scissors\". She made a game with similar rules in order to encourage the students to learn their facts.\n\r\nThe class would be divided into three teams: Rock, Paper and Scissors. The teacher would ask the students a question and the class would raise their hands if they knew the answer. If the first person to answer the question correctly is in the Rock team, he or she would choose one player from the Scissors team to be eliminated. Similarly, if a player from the Scissors team was first to answer the question, then he or she would eliminate a member from the Paper team. Lastly, if a player from the Paper team was first to answer correctly, he or she would eliminate a member from the Rock team.\n\r\nThe teacher would then continue asking questions until only one team still has members. That team would be declared the winner and all its members would win a small chocolate.\n\r\nHowever, as soon as she explained the rules to the class, one particularly smart student immediately found a large flaw that made the game unplayable. Can you do the same?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter one team loses all its members, the team that it eliminates members from will always win. For example, say the Scissors team is the first team to lose all its members. It is now impossible for the Paper team to lose any members, but the Paper team can still eliminate members from Rock team, so it will eventually win (if the Rock team answers questions, there would be no one left for them to eliminate so nothing would happen). This means that the best strategy is actually to avoid answering questions until one team is eliminated. If all the players know this, the game would never end.\n<|im_start|>answer\nAfter one team loses all its members, the team that it eliminates members from will always win. For example, say the Scissors team is the first team to lose all its members. It is now impossible for the Paper team to lose any members, but the Paper team can still eliminate members from Rock team, so it will eventually win (if the Rock team answers questions, there would be no one left for them to eliminate so nothing would happen). This means that the best strategy is actually to avoid answering questions until one team is eliminated. If all the players know this, the game would never end.\n<|im_end|>" }, { "id": "#23523", "title": "Bridal Shower", "fun": 3.16, "difficulty": 2.25, "author": "ragsdaleam", "desc": "Five bridesmaids threw a shower for their bride. Each brought a gift and made a favorite food of the bride. They all arrived at different times, and during the wedding each was wearing a different color of her choice. Determine the gift and food each bridesmaid brought, the time she arrived, and what color she chose for her dress.\n\r\n1. The bridesmaid with the painting had trouble getting it in her car, and the bridesmaid with the potato salad got lost on the way, so they were the last two to arrive.\r\n2. Amanda hated the color green and potato salad.\r\n3. Kourtney and Selena did not wear the blue dress and did not bring the turkey sandwiches.\r\n4. Stacie arrived before the bridesmaid with the painting, but after the bridesmaid who brought the sheets, and the bridesmaid who made the cheese dip.\r\n5. The bridesmaid with a blue dress arrived 10 minutes before the bridesmaid who brought the sandwiches.\r\n6. The bridesmaid with the veggie tray arrived 25 minutes after the bridesmaid who brought flatware, but before the bridesmaid who would be wearing a blue dress.\r\n7. The five bridesmaids arrived in the following order: The one who baked the cake, Amanda, the one who would be wearing a yellow dress, the one with a toaster for a gift, and the one who arrived last.\r\n8. Selena brought a cake with green frosting, the same color as her dress.\r\n9. Amanda brought pink sheets as a gift to the bride, but she did not like pink for herself.", "hint": "No hint available.", "answer": "Selena; green; flatware; cake; 2:50\r\nAmanda; purple; sheets; veggie tray; 3:15\r\nKourtney; yellow; towels; cheese dip; 3:20\r\nStacie; blue; toaster; potato salad; 3:35\r\nStephanie; pink; painting; turkey sandwiches; 3:45", "category": "Logic-Grid", "date": "06/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive bridesmaids threw a shower for their bride. Each brought a gift and made a favorite food of the bride. They all arrived at different times, and during the wedding each was wearing a different color of her choice. Determine the gift and food each bridesmaid brought, the time she arrived, and what color she chose for her dress.\n\r\n1. The bridesmaid with the painting had trouble getting it in her car, and the bridesmaid with the potato salad got lost on the way, so they were the last two to arrive.\r\n2. Amanda hated the color green and potato salad.\r\n3. Kourtney and Selena did not wear the blue dress and did not bring the turkey sandwiches.\r\n4. Stacie arrived before the bridesmaid with the painting, but after the bridesmaid who brought the sheets, and the bridesmaid who made the cheese dip.\r\n5. The bridesmaid with a blue dress arrived 10 minutes before the bridesmaid who brought the sandwiches.\r\n6. The bridesmaid with the veggie tray arrived 25 minutes after the bridesmaid who brought flatware, but before the bridesmaid who would be wearing a blue dress.\r\n7. The five bridesmaids arrived in the following order: The one who baked the cake, Amanda, the one who would be wearing a yellow dress, the one with a toaster for a gift, and the one who arrived last.\r\n8. Selena brought a cake with green frosting, the same color as her dress.\r\n9. Amanda brought pink sheets as a gift to the bride, but she did not like pink for herself.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSelena; green; flatware; cake; 2:50\r\nAmanda; purple; sheets; veggie tray; 3:15\r\nKourtney; yellow; towels; cheese dip; 3:20\r\nStacie; blue; toaster; potato salad; 3:35\r\nStephanie; pink; painting; turkey sandwiches; 3:45\n<|im_start|>answer\nSelena; green; flatware; cake; 2:50\r\nAmanda; purple; sheets; veggie tray; 3:15\r\nKourtney; yellow; towels; cheese dip; 3:20\r\nStacie; blue; toaster; potato salad; 3:35\r\nStephanie; pink; painting; turkey sandwiches; 3:45\n<|im_end|>" }, { "id": "#38301", "title": "Special Delivery", "fun": 3.16, "difficulty": 2.46, "author": "dreamlvr1432", "desc": "Joe needed some extra money, so he decided to take a summer job with a local gift shop, as a delivery boy. Joe had just loaded the van, when a gust of wind blew his delivery list out of his hand and into a puddle of water. The ink ran and 5 entries were smudged out. Joe remembers some of the details of the deliveries, but needs help reconstructing his list so he can get back to work. Using the clues below, can you help Joe figure out who each gift was delivered to, the occasion for the gift, the street each recipient lives on and the time the gifts are to be delivered?\n\r\nRecipients: Tava, Gretta, Diane, Jill, Sarah\r\nGifts: Roses, tulips, teddy bear, tiger, balloons\r\nOccasions: birthday, anniversary, get well, baby, promotion\r\nStreets: Julian Ave, Story St, Brady Ln, Dory Dr, Manor Ct.\r\nTimes: 10 am, 11 am, noon, 1 pm, 2 pm\n\r\n1) Gretta does not live on Story St.\n\r\n2) Both the 11 am delivery and the one made to Sarah were flowers.\n\r\n3) The 5 deliveries are the roses, the one on Story St, the one made at 1 pm, the one with a get well message, and the one made to Tava.\n\r\n4) The last delivery of the day was a stuffed animal given as a birthday gift.\n\r\n5) Jill (who just had a baby) did not receive a stuffed animal, nor was her gift delivered at noon.\n\r\n6) The delivery on Julian Ave (which wasn't to Gretta) was tulips.\n\r\n7) The deliveries were made in the following order: the balloons, the one made to Dory Dr, the one made to Diane, the gift given to celebrate a promotion, and the one made to Manor Ct.\n\r\n8) The teddy bear was delivered 1 hour before Sarah received her gift, but 2 hours after the delivery on Story St.", "hint": "No hint available.", "answer": "Thanks to you, Joe remembered the missing details of the list. He made his deliveries on time and managed to take home $25 in tips!\n\r\nJill's friends sent balloon to her home on Story St. at 10 am to welcome the new baby.\n\r\nGretta received roses from her husband at 11 am for their anniversary. They live on Dory Dr.\n\r\nDiane heard a knock at her door on Brady Ln at noon. She received a teddy bear \"bearing\" get well wishes, as she had been ill for several days.\n\r\nSarah just received a promotion and her co-workers sent tulips to her Julian Ave home at 1 pm.\n\r\nTava received a tiger for her birthday at 2 pm. She lives on Manor Ct.", "category": "Logic-Grid", "date": "09/15/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe needed some extra money, so he decided to take a summer job with a local gift shop, as a delivery boy. Joe had just loaded the van, when a gust of wind blew his delivery list out of his hand and into a puddle of water. The ink ran and 5 entries were smudged out. Joe remembers some of the details of the deliveries, but needs help reconstructing his list so he can get back to work. Using the clues below, can you help Joe figure out who each gift was delivered to, the occasion for the gift, the street each recipient lives on and the time the gifts are to be delivered?\n\r\nRecipients: Tava, Gretta, Diane, Jill, Sarah\r\nGifts: Roses, tulips, teddy bear, tiger, balloons\r\nOccasions: birthday, anniversary, get well, baby, promotion\r\nStreets: Julian Ave, Story St, Brady Ln, Dory Dr, Manor Ct.\r\nTimes: 10 am, 11 am, noon, 1 pm, 2 pm\n\r\n1) Gretta does not live on Story St.\n\r\n2) Both the 11 am delivery and the one made to Sarah were flowers.\n\r\n3) The 5 deliveries are the roses, the one on Story St, the one made at 1 pm, the one with a get well message, and the one made to Tava.\n\r\n4) The last delivery of the day was a stuffed animal given as a birthday gift.\n\r\n5) Jill (who just had a baby) did not receive a stuffed animal, nor was her gift delivered at noon.\n\r\n6) The delivery on Julian Ave (which wasn't to Gretta) was tulips.\n\r\n7) The deliveries were made in the following order: the balloons, the one made to Dory Dr, the one made to Diane, the gift given to celebrate a promotion, and the one made to Manor Ct.\n\r\n8) The teddy bear was delivered 1 hour before Sarah received her gift, but 2 hours after the delivery on Story St.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThanks to you, Joe remembered the missing details of the list. He made his deliveries on time and managed to take home $25 in tips!\n\r\nJill's friends sent balloon to her home on Story St. at 10 am to welcome the new baby.\n\r\nGretta received roses from her husband at 11 am for their anniversary. They live on Dory Dr.\n\r\nDiane heard a knock at her door on Brady Ln at noon. She received a teddy bear \"bearing\" get well wishes, as she had been ill for several days.\n\r\nSarah just received a promotion and her co-workers sent tulips to her Julian Ave home at 1 pm.\n\r\nTava received a tiger for her birthday at 2 pm. She lives on Manor Ct.\n<|im_start|>answer\nThanks to you, Joe remembered the missing details of the list. He made his deliveries on time and managed to take home $25 in tips!\n\r\nJill's friends sent balloon to her home on Story St. at 10 am to welcome the new baby.\n\r\nGretta received roses from her husband at 11 am for their anniversary. They live on Dory Dr.\n\r\nDiane heard a knock at her door on Brady Ln at noon. She received a teddy bear \"bearing\" get well wishes, as she had been ill for several days.\n\r\nSarah just received a promotion and her co-workers sent tulips to her Julian Ave home at 1 pm.\n\r\nTava received a tiger for her birthday at 2 pm. She lives on Manor Ct.\n<|im_end|>" }, { "id": "#45833", "title": "Artist Lunch", "fun": 3.16, "difficulty": 2.56, "author": "caberet", "desc": "Five budding artists are meeting for lunch today at the new Thai restaurant in town. Use the following clues to determine the first (Allie, Billie, Callie, Donnie and Effie) and last (Adams, Booker, Cheek, Devlin and Efferman) names of each artist, along with her favorite medium (Acrylic, Oil, Pastels, Pen and Ink and Watercolor) current focus (Children, Dancers, Fish, Landscapes and Nests) of each artist, along with their \"day job\" (Banquet Server, Bartender, Cashier, Driver and Teacher.) Nobody shares the same name, favorite medium, current focus or day job with anyone else in the group.\n\r\n1. The driver has never been drawn to landscapes and the teacher paints with either acrylic or oils. Ms. Efferman is currently focusing on either children or fish. The oil painter is either the bartender or the driver.\n\r\n2. Billy paints with either acrylic or watercolors. The surname of the driver is either Cheek or Adams. Callie is either Ms. Adams or Ms. Devlin. Donnie uses either acrylic or oil paint. The oil painter is focused on either dancers or landscapes.\n\r\n3. The watercolorist is either the banquet server or the teacher. The one working with pen and ink is neither Allie nor Effie. The acrylic painter is not focusing on landscapes or dancers. Neither acrylic nor watercolor is used to portray children.\n\r\n4. Ms. Adams is either the bartender or cashier. Allie either uses pen and ink or is focusing on children. Either Allie or Billy is the banquet server. Ms. Adams' work portrays either dancers or fish.\n\r\n6. Effie and the acrylic painter shared a pizza, Ms. Cheek had a salad, while the banquet server and the nest aficionado both had the soup of the day.", "hint": "No hint available.", "answer": "First-Last-Medium-Theme-Day Job\r\nAllie-Cheek-Pastels-Children-Driver\r\nBilly-Booker-Watercolor-Landscape-Banquets\r\nCallie-Devlin-Pen and Ink-Nests-Cashier\r\nDonnie-Efferman-Acrylic-Fish-Teacher\r\nEffie-Adams-Oil-Dancers-Bartender", "category": "Logic-Grid", "date": "11/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive budding artists are meeting for lunch today at the new Thai restaurant in town. Use the following clues to determine the first (Allie, Billie, Callie, Donnie and Effie) and last (Adams, Booker, Cheek, Devlin and Efferman) names of each artist, along with her favorite medium (Acrylic, Oil, Pastels, Pen and Ink and Watercolor) current focus (Children, Dancers, Fish, Landscapes and Nests) of each artist, along with their \"day job\" (Banquet Server, Bartender, Cashier, Driver and Teacher.) Nobody shares the same name, favorite medium, current focus or day job with anyone else in the group.\n\r\n1. The driver has never been drawn to landscapes and the teacher paints with either acrylic or oils. Ms. Efferman is currently focusing on either children or fish. The oil painter is either the bartender or the driver.\n\r\n2. Billy paints with either acrylic or watercolors. The surname of the driver is either Cheek or Adams. Callie is either Ms. Adams or Ms. Devlin. Donnie uses either acrylic or oil paint. The oil painter is focused on either dancers or landscapes.\n\r\n3. The watercolorist is either the banquet server or the teacher. The one working with pen and ink is neither Allie nor Effie. The acrylic painter is not focusing on landscapes or dancers. Neither acrylic nor watercolor is used to portray children.\n\r\n4. Ms. Adams is either the bartender or cashier. Allie either uses pen and ink or is focusing on children. Either Allie or Billy is the banquet server. Ms. Adams' work portrays either dancers or fish.\n\r\n6. Effie and the acrylic painter shared a pizza, Ms. Cheek had a salad, while the banquet server and the nest aficionado both had the soup of the day.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst-Last-Medium-Theme-Day Job\r\nAllie-Cheek-Pastels-Children-Driver\r\nBilly-Booker-Watercolor-Landscape-Banquets\r\nCallie-Devlin-Pen and Ink-Nests-Cashier\r\nDonnie-Efferman-Acrylic-Fish-Teacher\r\nEffie-Adams-Oil-Dancers-Bartender\n<|im_start|>answer\nFirst-Last-Medium-Theme-Day Job\r\nAllie-Cheek-Pastels-Children-Driver\r\nBilly-Booker-Watercolor-Landscape-Banquets\r\nCallie-Devlin-Pen and Ink-Nests-Cashier\r\nDonnie-Efferman-Acrylic-Fish-Teacher\r\nEffie-Adams-Oil-Dancers-Bartender\n<|im_end|>" }, { "id": "#45791", "title": "Sonora Celebrations", "fun": 3.16, "difficulty": 3.02, "author": "caberet", "desc": "The small resort town of Sonora has a big weekend ahead. Five local venues (Black Cat, Blue Paper, Orange Peel, Red Rock and Yellow Dunes) have been booked to celebrate a different occasion (Anniversary, Birthday, Engagement, Graduation and Promotion) by five different hosts (Bette, Miley, Rickie, Sammy and Toni). Five local bands (Black Sunday, Blue Street Band, Orange Juice, Red Hot Poppers and Yellow Moon Trio, known for their haunting Blue Bayou rendition) have been booked with a request for a specific highlight song (Black Bird Fly, Blue Bayou, Orange Crush, Red, Red Wine or Yellow Polka Dot Bikini) unique to each event.\n\r\n1. The first name of each song, venue and band are three different words for each event. Miley couldn't get either of her first two venue choices because the celebration for the job promotion had booked the first site and the event featuring Red, Red Wine had booked the second. The Yellow Moon Trio is either the band booked to play at Miley's event or the band that will play at the birthday party.\n\r\n2. Black Bird Fly is either the song that will be played at the engagement party or the tune that Rickie requested. Either Sammy or Bette booked Yellow Dunes. Red Rock is either the site booked for the anniversary party or the location of the Red Hot Poppers. Either Bette or Rickie are hosting the event that is either the birthday celebration or the one for which Yellow Moon Trio has been booked. Black Sunday is either the band that will play Yellow Polka Dot Bikini or the band that will play at the anniversary celebration.\n\r\n4. Either the promotion celebration will be held at the Orange Peel or it is the event that will highlight Blue Bayou. The med school graduation party is being hosted by either Ricky or Sammy at either Black Cat or Yellow Dunes. \n\r\n5. Toni booked either the band that will play Orange Crush or the Red Hot Poppers. The Blue Street Band is either the group that will play at the graduation celebration or is the band that is booked to play at the Yellow Dunes. Black Bird Fly is either the song that was requested at the birthday or is the one to be played at Toni's event. Black Sunday is either the band playing at Red Rock or the band that will play Yellow Polka Dot Bikini.\n\r\n6. Rickie booked either Orange Peel or the Yellow Dunes. Black Cat will either be the site at which Orange Crush will be highlighted or the location for which Yellow Moon Trio has been booked. Sammy is either the host of the promotion or the person that booked the Blue Street Band. Yellow Dunes will not be the site of either the engagement or promotion celebrations.", "hint": "Hint: If you're stuck, carefully reread the instructions. Still stuck, go through the clues another time.", "answer": "Song-Host-Venue-Band-Reason\r\nBlack Bird Fly-Toni-Blue Paper-Red Hot Poppers-Engagement\r\nBlue Bayou-Miley-Red Rock-Yellow Moon Trio-Anniversary\r\nOrange Crush-Sammy-Black Cat-Blue Street Band-Graduation\r\nRed Red Wine-Bette-Yellow Dunes-Orange Juice-Birthday\r\nYellow Polka Dot Bikini-Rickie-Orange Peel-Black Sunday-Promotion", "category": "Logic-Grid", "date": "11/23/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe small resort town of Sonora has a big weekend ahead. Five local venues (Black Cat, Blue Paper, Orange Peel, Red Rock and Yellow Dunes) have been booked to celebrate a different occasion (Anniversary, Birthday, Engagement, Graduation and Promotion) by five different hosts (Bette, Miley, Rickie, Sammy and Toni). Five local bands (Black Sunday, Blue Street Band, Orange Juice, Red Hot Poppers and Yellow Moon Trio, known for their haunting Blue Bayou rendition) have been booked with a request for a specific highlight song (Black Bird Fly, Blue Bayou, Orange Crush, Red, Red Wine or Yellow Polka Dot Bikini) unique to each event.\n\r\n1. The first name of each song, venue and band are three different words for each event. Miley couldn't get either of her first two venue choices because the celebration for the job promotion had booked the first site and the event featuring Red, Red Wine had booked the second. The Yellow Moon Trio is either the band booked to play at Miley's event or the band that will play at the birthday party.\n\r\n2. Black Bird Fly is either the song that will be played at the engagement party or the tune that Rickie requested. Either Sammy or Bette booked Yellow Dunes. Red Rock is either the site booked for the anniversary party or the location of the Red Hot Poppers. Either Bette or Rickie are hosting the event that is either the birthday celebration or the one for which Yellow Moon Trio has been booked. Black Sunday is either the band that will play Yellow Polka Dot Bikini or the band that will play at the anniversary celebration.\n\r\n4. Either the promotion celebration will be held at the Orange Peel or it is the event that will highlight Blue Bayou. The med school graduation party is being hosted by either Ricky or Sammy at either Black Cat or Yellow Dunes. \n\r\n5. Toni booked either the band that will play Orange Crush or the Red Hot Poppers. The Blue Street Band is either the group that will play at the graduation celebration or is the band that is booked to play at the Yellow Dunes. Black Bird Fly is either the song that was requested at the birthday or is the one to be played at Toni's event. Black Sunday is either the band playing at Red Rock or the band that will play Yellow Polka Dot Bikini.\n\r\n6. Rickie booked either Orange Peel or the Yellow Dunes. Black Cat will either be the site at which Orange Crush will be highlighted or the location for which Yellow Moon Trio has been booked. Sammy is either the host of the promotion or the person that booked the Blue Street Band. Yellow Dunes will not be the site of either the engagement or promotion celebrations.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSong-Host-Venue-Band-Reason\r\nBlack Bird Fly-Toni-Blue Paper-Red Hot Poppers-Engagement\r\nBlue Bayou-Miley-Red Rock-Yellow Moon Trio-Anniversary\r\nOrange Crush-Sammy-Black Cat-Blue Street Band-Graduation\r\nRed Red Wine-Bette-Yellow Dunes-Orange Juice-Birthday\r\nYellow Polka Dot Bikini-Rickie-Orange Peel-Black Sunday-Promotion\n<|im_start|>answer\nSong-Host-Venue-Band-Reason\r\nBlack Bird Fly-Toni-Blue Paper-Red Hot Poppers-Engagement\r\nBlue Bayou-Miley-Red Rock-Yellow Moon Trio-Anniversary\r\nOrange Crush-Sammy-Black Cat-Blue Street Band-Graduation\r\nRed Red Wine-Bette-Yellow Dunes-Orange Juice-Birthday\r\nYellow Polka Dot Bikini-Rickie-Orange Peel-Black Sunday-Promotion\n<|im_end|>" }, { "id": "#30858", "title": "Your Very Own Empire", "fun": 3.15, "difficulty": 3.07, "author": "AwwwSweet", "desc": "You thank the last person as they step outside, \"It's been a lovely evening, drive safely!\" You wait in the doorway to see them off, waving as the car begins to pull away. Closing the door, you breathe a tired sigh. \n\r\nYou stroll into the living room before it finally hits you. After weeks of discussions and the purchase of a 5-story building downtown, you are finally the proud owner of your very own clothing empire! You've just closed negotiations with 5 designers who have started their own small companies, but haven't been able to hit it big yet. Aside from settling on a salary for each of them, you also agreed to hire the employees they already have. This is indeed a wonderful moment for you! \"YES,\" you yell enthusiastically! \n\r\nStartled, your cat jumps sideways off the couch, landing on the coffee table and knocking a glass of wine all over your papers. Your delight quickly turns to horror as you realize what your precious (and soon-to-die) tabby has just done. You dash into the kitchen for some napkins but it's too late; half of your papers are already ruined. You can't believe it. You just spent all night sorting out the details, and you would really prefer to not have another 8 hour evening with those crazy designers! Besides, they might try to change their salaries. \n\r\nWith the information you have left, can you figure out what salary you agreed on with each designer, which item they design, how many employees they have, and on which floor of your new building they will be located?\n\r\nDesigners:\t Aimee, Claude, Darla, Evan, Faye\r\nItems: Purses, Pants, Skirts, Shoes, Tops\r\nFloors: 1, 2, 3, 4, 5\r\nNumber of Employees: 5, 6, 7, 8, 9\r\nSalary: 133k, 138k, 141k, 146k, 152k\n\r\n1. The salary of the person designing pants is more than Darla, but less than the designer on the 2nd floor.\r\n2. The five unique designers are: Faye, the one designing purses, the one on the 5th floor, the one whose salary is 146k, and the one with 5 employees.\r\n3. Only 15 employees will work above the 3rd floor.\r\n4. The shoe designer does not have the lowest salary, despite having the fewest employees.\r\n5. The sum of the numbers in one designer's salary is also their total number of employees. \r\n6. The salary of the designer on the 3rd floor is 138k.\r\n7. The five different floors are: the floor with 9 employees, the floor of the 133k salary, the floor Aimee is on, the 2nd floor, and the floor where the tops are designed.\r\n8. The designer on the 1st floor has the same number of employees as letters in their name.\r\n9. The purse designer has the most employees, but she doesn't have the highest salary.\r\n10. You remember that Faye really likes purses, but that has nothing to do with this puzzle.", "hint": "No hint available.", "answer": "Aimee: Pants, 5th Floor, 8 employees, 141k\r\nClaude: Tops, 1st Floor, 6 employees, 146k\r\nDarla: Purses, 3rd Floor, 9 employees, 138k\r\nEvan: Shoes, 2nd Floor, 5 employees, 152k\r\nFaye: Skirts, 4th Floor, 7 employees, 133k", "category": "Logic-Grid", "date": "06/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou thank the last person as they step outside, \"It's been a lovely evening, drive safely!\" You wait in the doorway to see them off, waving as the car begins to pull away. Closing the door, you breathe a tired sigh. \n\r\nYou stroll into the living room before it finally hits you. After weeks of discussions and the purchase of a 5-story building downtown, you are finally the proud owner of your very own clothing empire! You've just closed negotiations with 5 designers who have started their own small companies, but haven't been able to hit it big yet. Aside from settling on a salary for each of them, you also agreed to hire the employees they already have. This is indeed a wonderful moment for you! \"YES,\" you yell enthusiastically! \n\r\nStartled, your cat jumps sideways off the couch, landing on the coffee table and knocking a glass of wine all over your papers. Your delight quickly turns to horror as you realize what your precious (and soon-to-die) tabby has just done. You dash into the kitchen for some napkins but it's too late; half of your papers are already ruined. You can't believe it. You just spent all night sorting out the details, and you would really prefer to not have another 8 hour evening with those crazy designers! Besides, they might try to change their salaries. \n\r\nWith the information you have left, can you figure out what salary you agreed on with each designer, which item they design, how many employees they have, and on which floor of your new building they will be located?\n\r\nDesigners:\t Aimee, Claude, Darla, Evan, Faye\r\nItems: Purses, Pants, Skirts, Shoes, Tops\r\nFloors: 1, 2, 3, 4, 5\r\nNumber of Employees: 5, 6, 7, 8, 9\r\nSalary: 133k, 138k, 141k, 146k, 152k\n\r\n1. The salary of the person designing pants is more than Darla, but less than the designer on the 2nd floor.\r\n2. The five unique designers are: Faye, the one designing purses, the one on the 5th floor, the one whose salary is 146k, and the one with 5 employees.\r\n3. Only 15 employees will work above the 3rd floor.\r\n4. The shoe designer does not have the lowest salary, despite having the fewest employees.\r\n5. The sum of the numbers in one designer's salary is also their total number of employees. \r\n6. The salary of the designer on the 3rd floor is 138k.\r\n7. The five different floors are: the floor with 9 employees, the floor of the 133k salary, the floor Aimee is on, the 2nd floor, and the floor where the tops are designed.\r\n8. The designer on the 1st floor has the same number of employees as letters in their name.\r\n9. The purse designer has the most employees, but she doesn't have the highest salary.\r\n10. You remember that Faye really likes purses, but that has nothing to do with this puzzle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAimee: Pants, 5th Floor, 8 employees, 141k\r\nClaude: Tops, 1st Floor, 6 employees, 146k\r\nDarla: Purses, 3rd Floor, 9 employees, 138k\r\nEvan: Shoes, 2nd Floor, 5 employees, 152k\r\nFaye: Skirts, 4th Floor, 7 employees, 133k\n<|im_start|>answer\nAimee: Pants, 5th Floor, 8 employees, 141k\r\nClaude: Tops, 1st Floor, 6 employees, 146k\r\nDarla: Purses, 3rd Floor, 9 employees, 138k\r\nEvan: Shoes, 2nd Floor, 5 employees, 152k\r\nFaye: Skirts, 4th Floor, 7 employees, 133k\n<|im_end|>" }, { "id": "#40224", "title": "Reunion '98", "fun": 3.15, "difficulty": 2.97, "author": "dreamlvr1432", "desc": "It's reunion time for the class of 1998, and it's your job to gather information on all of your former classmates for the reunion directory. You have finally organized all the information, but as you are handing it to the publisher's messenger, he clumsily drops a few pages into the shredder! You manage to rewrite most of those pages, but you realize you are missing some information on five of your classmates (3 men and 2 women). You need to match each person with his/her spouse, last name, occupation, and the city in which he/she lives. All you have to work with is what you recall from your notes, and your memories of your classmates from school days.\n\r\nCLASSMATES: Casey, Dana, Jordan, Drew, Kelsey\r\nSPOUSES: (women) Anna, Karen, Jane, (men) Matthew, David\r\nLAST NAMES: Campos, Jones, Kaufmann, Smith, Thompson\r\nOCCUPATIONS: lawyer, social worker, disk jockey, pediatrician, news anchor\r\nCITIES: Lawton, Helena, Dayton, Madison, Springfield\n\r\n1) The male classmates are the one from Madison, the one from Helena, and the lawyer.\n\r\n2) The five classmates are Casey, the man that married Jane (who is not from Helena), the woman surnamed Thompson, the disk jockey, and the woman who lived in Lawton.\n\r\n3) You recall that only two classmates (1 man and 1 woman) married people with the same first initial as their own. They both have jobs in the media industry. \n\r\n4) You can also recall that nobody (including spouses) has a last name with the same initial as their first name.\n\r\n5) The monogram on Karen's towels is the same forward as backward. Her last name is not Campos.\n\r\n6) David's wife became the anchor for Lawton's 6 o'clock news. Her best friend became a pediatrician in Dayton.\n\r\n7) Mr. and Mrs. Kaufmann's first initials are the same as the abbreviation of Mr. Jones' occupation.\n\r\n8) In high school, Dana was always very compassionate and eager to help anyone in need. It is no surprise that he became a social worker (not in Dayton).", "hint": "All classmates' names are unisex. You must determine which are male and female.\n\r\nA monogram generally consists of a husband's and wife's first initials on either side of their last initial. (ex: Tim and Janet Brown = TBJ)", "answer": "Casey Smith married Anna and became a lawyer in Springfield.\r\nDana Kaufmann married Jane and became a social worker in Madison.\r\nJordan Thompson married Matthew and became a pediatrician in Dayton.\r\nKelsey Jones married Karen and became a disk jockey in Helena.\r\nDrew Campos married David and became a news anchor in Lawton.", "category": "Logic-Grid", "date": "01/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's reunion time for the class of 1998, and it's your job to gather information on all of your former classmates for the reunion directory. You have finally organized all the information, but as you are handing it to the publisher's messenger, he clumsily drops a few pages into the shredder! You manage to rewrite most of those pages, but you realize you are missing some information on five of your classmates (3 men and 2 women). You need to match each person with his/her spouse, last name, occupation, and the city in which he/she lives. All you have to work with is what you recall from your notes, and your memories of your classmates from school days.\n\r\nCLASSMATES: Casey, Dana, Jordan, Drew, Kelsey\r\nSPOUSES: (women) Anna, Karen, Jane, (men) Matthew, David\r\nLAST NAMES: Campos, Jones, Kaufmann, Smith, Thompson\r\nOCCUPATIONS: lawyer, social worker, disk jockey, pediatrician, news anchor\r\nCITIES: Lawton, Helena, Dayton, Madison, Springfield\n\r\n1) The male classmates are the one from Madison, the one from Helena, and the lawyer.\n\r\n2) The five classmates are Casey, the man that married Jane (who is not from Helena), the woman surnamed Thompson, the disk jockey, and the woman who lived in Lawton.\n\r\n3) You recall that only two classmates (1 man and 1 woman) married people with the same first initial as their own. They both have jobs in the media industry. \n\r\n4) You can also recall that nobody (including spouses) has a last name with the same initial as their first name.\n\r\n5) The monogram on Karen's towels is the same forward as backward. Her last name is not Campos.\n\r\n6) David's wife became the anchor for Lawton's 6 o'clock news. Her best friend became a pediatrician in Dayton.\n\r\n7) Mr. and Mrs. Kaufmann's first initials are the same as the abbreviation of Mr. Jones' occupation.\n\r\n8) In high school, Dana was always very compassionate and eager to help anyone in need. It is no surprise that he became a social worker (not in Dayton).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCasey Smith married Anna and became a lawyer in Springfield.\r\nDana Kaufmann married Jane and became a social worker in Madison.\r\nJordan Thompson married Matthew and became a pediatrician in Dayton.\r\nKelsey Jones married Karen and became a disk jockey in Helena.\r\nDrew Campos married David and became a news anchor in Lawton.\n<|im_start|>answer\nCasey Smith married Anna and became a lawyer in Springfield.\r\nDana Kaufmann married Jane and became a social worker in Madison.\r\nJordan Thompson married Matthew and became a pediatrician in Dayton.\r\nKelsey Jones married Karen and became a disk jockey in Helena.\r\nDrew Campos married David and became a news anchor in Lawton.\n<|im_end|>" }, { "id": "#45350", "title": "Baggage Mishaps", "fun": 3.15, "difficulty": 3.31, "author": "caberet", "desc": "Savannah got distracted when her shuttle arrived at Earth Central Airport. Now she's at Lost & Found with four other travelers all waiting to retrieve one lost piece of luggage of a different color (black, blue, green, red or yellow.) While filling out their baggage retrieval paperwork, they discovered an amazing coincidence. Each person had the last name of one other person's nationality and another's destination country (America, England, France, Panama or Zambia). Nobody had the same last name, nationality or destination country of anyone else in the group. Each person is traveling from his or her country of origin to only one other country. Use the following clues to determine each traveler's first name, last name (L), nationality (N), destination country (D) and baggage color. Because this is Logic Land, the unlikelihood of the travelers actually sharing the same airport is not of any concern in solving this puzzle.\n\r\n1. Each traveler's last name, nationality and destination country are three different names. \r\n2. Ms. Panama is neither the Zambian citizen nor the one going to England; Carmelita wants her suitcase to stand out, so she is not the person with the black bag. (All five travelers are mentioned in this clue.)\r\n3. The person bound for France, who asked Echo where she bought her fragrant cup of coffee, sat next to Mr. England.\r\n4. Echo is not the French citizen that helped Pierre with his paperwork.\r\n5. Of the person with the lovely yellow suitcase and Savannah, one is traveling to Zambia and the other is the American citizen.\r\n6. Pierre's destination country is the nationality of the owner of the black bag; the destination country of the owner of the black bag is Pierre's nationality. \r\n7. The person surnamed America is not going to France and the person traveling to America has either a blue or green bag.\r\n8. Juan, who does not have yellow luggage, does not have England as his last name. \r\n9. The five travelers are the American, Echo, the blue suitcase owner, the one traveling to Panama and Ms. France.", "hint": "Hint: We know that Echo is a woman from clue 3, so there are 3 women and 2 men. Pierre is Mr. England from clues 3 & 8. He must be Zambian since he cannot be any of the other people in clue 2. Since Pierre is Zambian, clue 6 tells us that the owner of the black luggage must be the one going to Zambia. In clue 5, Savannah must be the owner of the black bag since the person going to Zambia cannot have the yellow bag (clue 6), which makes the yellow bag's owner the American. Next look at clue 9 for information on the remaining two travelers. \n\r\nSee answer for complete step-by-step solution.", "answer": "We know that there are 3 women, Carmelita, Savannah, and Echo (clue 3), and 2 men, Pierre and Juan. We know that Pierre is surnamed England, since clue 3 tells us that the person surnamed England is male, and clue 8 tells us that Juan, the only other male is not Mr. England. In clue 2, Pierre is not Ms. Panama, the traveler to England (clue 1 tells us that Mr. England is not traveling to England), Carmelita, or the owner of the black baggage (clue 6); leaving only the Zambian. Since Pierre is from Zambia, clue 6 tells us that the owner of the black luggage must be the one heading to Zambia. In clue 5, the person traveling to Zambia (who we now know has black baggage) must be Savannah and the American citizen has the yellow luggage. Savannah must be Ms. France to fit clue 9 since she is not the American (the 3rd person we have identified), Echo, the owner of the blue bag (Savannah has the black bag), or the traveler bound for Panama (she is heading to Zambia). Savannah's nationality cannot be French or Zambian (clue 1), English (clues 1 and 6 - Pierre cannot be heading to England because of his last name), or America (since Savannah is not American). The only remaining country is Panama. So Savannah is Panamanian and clue 6 tells us that Pierre must be heading to Panama. \n\r\nWe now have 3 people, Pierre, Savannah, and the American with the yellow bag. According to clue 9, the 2 remaining people are the owner of the blue bag and Echo. Juan is not the owner of the yellow bag (clue 8) so he must have the blue bag, leaving only Carmelita to be the American. Since Echo is not French (clue 4), she must be English and Juan is French (the only remaining option). We know that the person going to France is neither Echo from clue 3 nor Juan because he is French (clue 1), so the only remaining option is that Carmelita is heading to France. Clue 2 tells us that Carmelita is not Ms. Panama, so she must be Echo. Carmelita cannot be surnamed America (clue 1) so this is Juan's last name, leaving only Zambia as Carmelita's surname. Clue 2 tells us that Ms. Panama cannot be the one traveling to England so that must be Juan's destination. Echo is traveling to America, the only remaining option. From clue 7, Echo must have the green bag, since Juan has the blue bag, leaving the red bag to belong to Pierre.\n\r\nFirst-Last-Nationality-Destination-Color\r\nCarmelita-Zambia-America-France-Yellow\r\nEcho-Panama-English-America-Green\r\nJuan-America-French-England-Blue\r\nPierre-England-Zambia-Panama-Red\r\nSavannah-France-Panama-Zambia-Black", "category": "Logic-Grid", "date": "09/25/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSavannah got distracted when her shuttle arrived at Earth Central Airport. Now she's at Lost & Found with four other travelers all waiting to retrieve one lost piece of luggage of a different color (black, blue, green, red or yellow.) While filling out their baggage retrieval paperwork, they discovered an amazing coincidence. Each person had the last name of one other person's nationality and another's destination country (America, England, France, Panama or Zambia). Nobody had the same last name, nationality or destination country of anyone else in the group. Each person is traveling from his or her country of origin to only one other country. Use the following clues to determine each traveler's first name, last name (L), nationality (N), destination country (D) and baggage color. Because this is Logic Land, the unlikelihood of the travelers actually sharing the same airport is not of any concern in solving this puzzle.\n\r\n1. Each traveler's last name, nationality and destination country are three different names. \r\n2. Ms. Panama is neither the Zambian citizen nor the one going to England; Carmelita wants her suitcase to stand out, so she is not the person with the black bag. (All five travelers are mentioned in this clue.)\r\n3. The person bound for France, who asked Echo where she bought her fragrant cup of coffee, sat next to Mr. England.\r\n4. Echo is not the French citizen that helped Pierre with his paperwork.\r\n5. Of the person with the lovely yellow suitcase and Savannah, one is traveling to Zambia and the other is the American citizen.\r\n6. Pierre's destination country is the nationality of the owner of the black bag; the destination country of the owner of the black bag is Pierre's nationality. \r\n7. The person surnamed America is not going to France and the person traveling to America has either a blue or green bag.\r\n8. Juan, who does not have yellow luggage, does not have England as his last name. \r\n9. The five travelers are the American, Echo, the blue suitcase owner, the one traveling to Panama and Ms. France.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWe know that there are 3 women, Carmelita, Savannah, and Echo (clue 3), and 2 men, Pierre and Juan. We know that Pierre is surnamed England, since clue 3 tells us that the person surnamed England is male, and clue 8 tells us that Juan, the only other male is not Mr. England. In clue 2, Pierre is not Ms. Panama, the traveler to England (clue 1 tells us that Mr. England is not traveling to England), Carmelita, or the owner of the black baggage (clue 6); leaving only the Zambian. Since Pierre is from Zambia, clue 6 tells us that the owner of the black luggage must be the one heading to Zambia. In clue 5, the person traveling to Zambia (who we now know has black baggage) must be Savannah and the American citizen has the yellow luggage. Savannah must be Ms. France to fit clue 9 since she is not the American (the 3rd person we have identified), Echo, the owner of the blue bag (Savannah has the black bag), or the traveler bound for Panama (she is heading to Zambia). Savannah's nationality cannot be French or Zambian (clue 1), English (clues 1 and 6 - Pierre cannot be heading to England because of his last name), or America (since Savannah is not American). The only remaining country is Panama. So Savannah is Panamanian and clue 6 tells us that Pierre must be heading to Panama. \n\r\nWe now have 3 people, Pierre, Savannah, and the American with the yellow bag. According to clue 9, the 2 remaining people are the owner of the blue bag and Echo. Juan is not the owner of the yellow bag (clue 8) so he must have the blue bag, leaving only Carmelita to be the American. Since Echo is not French (clue 4), she must be English and Juan is French (the only remaining option). We know that the person going to France is neither Echo from clue 3 nor Juan because he is French (clue 1), so the only remaining option is that Carmelita is heading to France. Clue 2 tells us that Carmelita is not Ms. Panama, so she must be Echo. Carmelita cannot be surnamed America (clue 1) so this is Juan's last name, leaving only Zambia as Carmelita's surname. Clue 2 tells us that Ms. Panama cannot be the one traveling to England so that must be Juan's destination. Echo is traveling to America, the only remaining option. From clue 7, Echo must have the green bag, since Juan has the blue bag, leaving the red bag to belong to Pierre.\n\r\nFirst-Last-Nationality-Destination-Color\r\nCarmelita-Zambia-America-France-Yellow\r\nEcho-Panama-English-America-Green\r\nJuan-America-French-England-Blue\r\nPierre-England-Zambia-Panama-Red\r\nSavannah-France-Panama-Zambia-Black\n<|im_start|>answer\nWe know that there are 3 women, Carmelita, Savannah, and Echo (clue 3), and 2 men, Pierre and Juan. We know that Pierre is surnamed England, since clue 3 tells us that the person surnamed England is male, and clue 8 tells us that Juan, the only other male is not Mr. England. In clue 2, Pierre is not Ms. Panama, the traveler to England (clue 1 tells us that Mr. England is not traveling to England), Carmelita, or the owner of the black baggage (clue 6); leaving only the Zambian. Since Pierre is from Zambia, clue 6 tells us that the owner of the black luggage must be the one heading to Zambia. In clue 5, the person traveling to Zambia (who we now know has black baggage) must be Savannah and the American citizen has the yellow luggage. Savannah must be Ms. France to fit clue 9 since she is not the American (the 3rd person we have identified), Echo, the owner of the blue bag (Savannah has the black bag), or the traveler bound for Panama (she is heading to Zambia). Savannah's nationality cannot be French or Zambian (clue 1), English (clues 1 and 6 - Pierre cannot be heading to England because of his last name), or America (since Savannah is not American). The only remaining country is Panama. So Savannah is Panamanian and clue 6 tells us that Pierre must be heading to Panama. \n\r\nWe now have 3 people, Pierre, Savannah, and the American with the yellow bag. According to clue 9, the 2 remaining people are the owner of the blue bag and Echo. Juan is not the owner of the yellow bag (clue 8) so he must have the blue bag, leaving only Carmelita to be the American. Since Echo is not French (clue 4), she must be English and Juan is French (the only remaining option). We know that the person going to France is neither Echo from clue 3 nor Juan because he is French (clue 1), so the only remaining option is that Carmelita is heading to France. Clue 2 tells us that Carmelita is not Ms. Panama, so she must be Echo. Carmelita cannot be surnamed America (clue 1) so this is Juan's last name, leaving only Zambia as Carmelita's surname. Clue 2 tells us that Ms. Panama cannot be the one traveling to England so that must be Juan's destination. Echo is traveling to America, the only remaining option. From clue 7, Echo must have the green bag, since Juan has the blue bag, leaving the red bag to belong to Pierre.\n\r\nFirst-Last-Nationality-Destination-Color\r\nCarmelita-Zambia-America-France-Yellow\r\nEcho-Panama-English-America-Green\r\nJuan-America-French-England-Blue\r\nPierre-England-Zambia-Panama-Red\r\nSavannah-France-Panama-Zambia-Black\n<|im_end|>" }, { "id": "#28001", "title": "Giving to the Greater Good", "fun": 3.15, "difficulty": 2.2, "author": "aprilsprings29", "desc": "Five people chose to donate to five different charitable organizations: Support the Troops, Breast Cancer, Red Cross, UNICEF and AIDS. They each donated a different amount of money and have different careers. Can you discern their first and last name, charity, donation amount, and their career?\n\r\n1. The surgeon donated three times more than Ms. Maxwell.\r\n2. $90,000 was donated to Breast Cancer, but not from the governor or the surgeon.\r\n3. UNICEF received $30,000 \r\n4. Mr. Gage's wife has been pressuring him to find a job.\r\n5. Donna donated to Support the Troops.\r\n6. The five donators are: The news reporter, Mrs.Vallay, the guy who donated $30,000, Julia Maxwell, and the attorney who contributed no less than $50,000.\r\n7. Chad is not the attorney, but he received a pink ribbon for contributing to the Breast Cancer charity.\r\n8. Tom contributed half as much as the surgeon, but more than the woman who donated to the Red Cross.\r\n9. Donna and her husband, Mr. Rackley, have a nephew fighting in the war overseas.", "hint": "Support = Support the Troops", "answer": "Michelle Vallay - $60,000 - AIDS - Surgeon\r\nJulia Maxwell - $20,000- Red Cross - Governor\r\nChad Williams - $90,000- Breast Cancer - News Reporter\r\nTom Gage - $30,000-UNICEF - Unemployed\r\nDonna Rackley - $80,000 - Support the Troops- Attorney", "category": "Logic-Grid", "date": "01/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people chose to donate to five different charitable organizations: Support the Troops, Breast Cancer, Red Cross, UNICEF and AIDS. They each donated a different amount of money and have different careers. Can you discern their first and last name, charity, donation amount, and their career?\n\r\n1. The surgeon donated three times more than Ms. Maxwell.\r\n2. $90,000 was donated to Breast Cancer, but not from the governor or the surgeon.\r\n3. UNICEF received $30,000 \r\n4. Mr. Gage's wife has been pressuring him to find a job.\r\n5. Donna donated to Support the Troops.\r\n6. The five donators are: The news reporter, Mrs.Vallay, the guy who donated $30,000, Julia Maxwell, and the attorney who contributed no less than $50,000.\r\n7. Chad is not the attorney, but he received a pink ribbon for contributing to the Breast Cancer charity.\r\n8. Tom contributed half as much as the surgeon, but more than the woman who donated to the Red Cross.\r\n9. Donna and her husband, Mr. Rackley, have a nephew fighting in the war overseas.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMichelle Vallay - $60,000 - AIDS - Surgeon\r\nJulia Maxwell - $20,000- Red Cross - Governor\r\nChad Williams - $90,000- Breast Cancer - News Reporter\r\nTom Gage - $30,000-UNICEF - Unemployed\r\nDonna Rackley - $80,000 - Support the Troops- Attorney\n<|im_start|>answer\nMichelle Vallay - $60,000 - AIDS - Surgeon\r\nJulia Maxwell - $20,000- Red Cross - Governor\r\nChad Williams - $90,000- Breast Cancer - News Reporter\r\nTom Gage - $30,000-UNICEF - Unemployed\r\nDonna Rackley - $80,000 - Support the Troops- Attorney\n<|im_end|>" }, { "id": "#49102", "title": "Disparate Housewives", "fun": 3.15, "difficulty": 2.99, "author": "Gizzer", "desc": "The housewives of Clematis Lane are a very disparate group. Each housewife was born under a different sign of the Chinese zodiac, prefers a different brand of household cleaner, went on a second honeymoon to a different European capital last year, and has a family member with a strange medical problem related to a different eponymous body part. Can you determine the name, zodiac sign, cleaner, honeymoon destination and afflicted family member's body part for each housewife?\n\r\nHousewives: Alma, Blythe, Helen, Leslie, Roberta\r\nZodiac Years: Dragon, Horse, Ox, Pig, Rooster\r\nCleaners: Ajax, Bon Ami, Comet, Lysol, Vanish\r\nHoneymoon Cities: Amsterdam, Brussels, London, Oslo, Paris\r\nBody Parts: Achilles' Tendon, Adam's Apple, Bundle of His, Fallopian Tubes, Islets of Langerhans\n\r\n1. The five housewives are: Roberta, the one born in the Year of the Dragon, the one who prefers to use Bon Ami, the one who travelled to Amsterdam and the one whose daughter ruptured an Achilles Tendon after being kicked in the ankle by a soccer mom just before the championship game. \n\r\n2. Neither Blythe (who hasn't been to London) nor the housewife born in the Year of the Horse (who doesn't use Vanish) is the one with a brother whose pacemaker, installed to correct a defect with his Bundle of His, somehow triggers her automatic Lysol shower cleaner. \n\r\n3. The housewife who went to Brussels has a son with hyperactive Islets of Langerhans, requiring him to constantly eat candy or risk lapsing into a diabetic coma. \n\r\n4. Neither Leslie nor the housewife who uses Comet cleanser is the woman who was born in the Year of the Rooster and whose husband, ironically, can't crow about his exploits after suffering a crushed Adam's Apple while participating in a joust at the County Fair. \n\r\n5. Helen (who wasn't born in the Year of the Pig) went to Paris for her second honeymoon. \n\r\n6. Neither Leslie nor the housewife born in the Year of the Ox has the brother with a defective Bundle of His or the daughter with the ruptured Achilles Tendon. \n\r\n7. The housewife born in the Year of the Dragon doesn't use Lysol or Ajax. \n\r\n8. The housewife born in the Year of the Horse doesn't use Comet. \n\r\n9. The housewife born in the Year of the Ox isn't the woman with a twin sister who had her Fallopian tubes removed after an ectopic pregnancy and now wants her sister to act as a surrogate. \n\r\n10. Alma has never been to Oslo.", "hint": "No hint available.", "answer": "Leslie, Year of the Dragon, Vanish, London, Fallopian Tubes\r\nRoberta, Year of the Ox, Comet, Brussels, Islets of Langerhans\r\nAlma, Year of the Pig, Lysol, Amsterdam, Bundle of His\r\nHelen, Year of the Horse, Ajax, Paris, Achilles Tendon\r\nBlythe, Year of the Rooster, Bon Ami, Oslo, Adam's Apple", "category": "Logic-Grid", "date": "10/24/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe housewives of Clematis Lane are a very disparate group. Each housewife was born under a different sign of the Chinese zodiac, prefers a different brand of household cleaner, went on a second honeymoon to a different European capital last year, and has a family member with a strange medical problem related to a different eponymous body part. Can you determine the name, zodiac sign, cleaner, honeymoon destination and afflicted family member's body part for each housewife?\n\r\nHousewives: Alma, Blythe, Helen, Leslie, Roberta\r\nZodiac Years: Dragon, Horse, Ox, Pig, Rooster\r\nCleaners: Ajax, Bon Ami, Comet, Lysol, Vanish\r\nHoneymoon Cities: Amsterdam, Brussels, London, Oslo, Paris\r\nBody Parts: Achilles' Tendon, Adam's Apple, Bundle of His, Fallopian Tubes, Islets of Langerhans\n\r\n1. The five housewives are: Roberta, the one born in the Year of the Dragon, the one who prefers to use Bon Ami, the one who travelled to Amsterdam and the one whose daughter ruptured an Achilles Tendon after being kicked in the ankle by a soccer mom just before the championship game. \n\r\n2. Neither Blythe (who hasn't been to London) nor the housewife born in the Year of the Horse (who doesn't use Vanish) is the one with a brother whose pacemaker, installed to correct a defect with his Bundle of His, somehow triggers her automatic Lysol shower cleaner. \n\r\n3. The housewife who went to Brussels has a son with hyperactive Islets of Langerhans, requiring him to constantly eat candy or risk lapsing into a diabetic coma. \n\r\n4. Neither Leslie nor the housewife who uses Comet cleanser is the woman who was born in the Year of the Rooster and whose husband, ironically, can't crow about his exploits after suffering a crushed Adam's Apple while participating in a joust at the County Fair. \n\r\n5. Helen (who wasn't born in the Year of the Pig) went to Paris for her second honeymoon. \n\r\n6. Neither Leslie nor the housewife born in the Year of the Ox has the brother with a defective Bundle of His or the daughter with the ruptured Achilles Tendon. \n\r\n7. The housewife born in the Year of the Dragon doesn't use Lysol or Ajax. \n\r\n8. The housewife born in the Year of the Horse doesn't use Comet. \n\r\n9. The housewife born in the Year of the Ox isn't the woman with a twin sister who had her Fallopian tubes removed after an ectopic pregnancy and now wants her sister to act as a surrogate. \n\r\n10. Alma has never been to Oslo.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeslie, Year of the Dragon, Vanish, London, Fallopian Tubes\r\nRoberta, Year of the Ox, Comet, Brussels, Islets of Langerhans\r\nAlma, Year of the Pig, Lysol, Amsterdam, Bundle of His\r\nHelen, Year of the Horse, Ajax, Paris, Achilles Tendon\r\nBlythe, Year of the Rooster, Bon Ami, Oslo, Adam's Apple\n<|im_start|>answer\nLeslie, Year of the Dragon, Vanish, London, Fallopian Tubes\r\nRoberta, Year of the Ox, Comet, Brussels, Islets of Langerhans\r\nAlma, Year of the Pig, Lysol, Amsterdam, Bundle of His\r\nHelen, Year of the Horse, Ajax, Paris, Achilles Tendon\r\nBlythe, Year of the Rooster, Bon Ami, Oslo, Adam's Apple\n<|im_end|>" }, { "id": "#52159", "title": "The Opposite Gender", "fun": 3.15, "difficulty": 2.25, "author": "wimpykidfan37", "desc": "Sam, Alex, Charlie, and Jordan are related. One of them is the opposite gender from the other three. Here are some facts:\n\r\n1. Charlie's only son is either Sam or Alex.\r\n2. Jordan's sister is either Alex or Charlie.\r\n3. Jordan is either Sam's brother or Sam's only daughter.\n\r\nWho is the opposite gender from the other three?", "hint": "No hint available.", "answer": "Charlie is the opposite gender.\n\r\nIf Jordan is Sam's only daughter, then Jordan cannot have a sister. Therefore, Jordan must be Sam's brother and a male.\n\r\nIf Jordan's sister is Alex, then fact 1 tells us that Sam is Charlie's only son. But since Jordan is Sam's brother, Sam cannot be Charlie's only son. Therefore, Charlie must be Jordan's sister.\n\r\nSince Sam is Jordan and Charlie's sibling, Alex must be Charlie's son. Now we know that Alex and Jordan are male, while Charlie is female.", "category": "Logic", "date": "03/17/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSam, Alex, Charlie, and Jordan are related. One of them is the opposite gender from the other three. Here are some facts:\n\r\n1. Charlie's only son is either Sam or Alex.\r\n2. Jordan's sister is either Alex or Charlie.\r\n3. Jordan is either Sam's brother or Sam's only daughter.\n\r\nWho is the opposite gender from the other three?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCharlie is the opposite gender.\n\r\nIf Jordan is Sam's only daughter, then Jordan cannot have a sister. Therefore, Jordan must be Sam's brother and a male.\n\r\nIf Jordan's sister is Alex, then fact 1 tells us that Sam is Charlie's only son. But since Jordan is Sam's brother, Sam cannot be Charlie's only son. Therefore, Charlie must be Jordan's sister.\n\r\nSince Sam is Jordan and Charlie's sibling, Alex must be Charlie's son. Now we know that Alex and Jordan are male, while Charlie is female.\n<|im_start|>answer\nCharlie is the opposite gender.\n\r\nIf Jordan is Sam's only daughter, then Jordan cannot have a sister. Therefore, Jordan must be Sam's brother and a male.\n\r\nIf Jordan's sister is Alex, then fact 1 tells us that Sam is Charlie's only son. But since Jordan is Sam's brother, Sam cannot be Charlie's only son. Therefore, Charlie must be Jordan's sister.\n\r\nSince Sam is Jordan and Charlie's sibling, Alex must be Charlie's son. Now we know that Alex and Jordan are male, while Charlie is female.\n<|im_end|>" }, { "id": "#14256", "title": "A Man and Two Doors", "fun": 3.15, "difficulty": 1.39, "author": "pennyisgifted", "desc": "A man is trapped in a room. The room has only two possible exits: two doors. Through the first door there is a room constructed from magnifying glass. The blazing hot sun instantly fries anything or anyone that enters. Through the second door there is a fire-breathing dragon. How does the man escape?", "hint": "No hint available.", "answer": "He waits until night time and then goes through the first door.", "category": "Logic", "date": "08/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is trapped in a room. The room has only two possible exits: two doors. Through the first door there is a room constructed from magnifying glass. The blazing hot sun instantly fries anything or anyone that enters. Through the second door there is a fire-breathing dragon. How does the man escape?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe waits until night time and then goes through the first door.\n<|im_start|>answer\nHe waits until night time and then goes through the first door.\n<|im_end|>" }, { "id": "#25893", "title": "Entertaining the Kids", "fun": 3.14, "difficulty": 2.87, "author": "cinnamon30", "desc": "The parents of five children decided to share responsibility for entertaining the kids (one of whom is Bruce) during the week between the end of day camp and the start of the school. Each parent took a different day of the week, Monday through Friday, to take the children on a different outing (including taking them horseback riding). They also each rented a movie (including Mulan) for the children to watch. For each day, determine who took care of the kids, that parent's child, the outing the parent supervised and the movie he or she rented. \n\r\n1. The five parents were: the one who took the children bowling, the one who rented \"Antz\", Katie's parent, Mr. Bidwell and Mrs. Molinari.\n\r\n2. The parent who rented \"Finding Nemo\" didn't take the kids bowling and isn't related to Katie.\n\r\n3. Neither Mrs. Parker nor the parent who took the kids to miniature golf rented \"Ice Age\".\n\r\n4. The children went roller skating the day before they saw \"Monster's Inc.\", which was the day before Mr. Sandoval entertained them.\n\r\n5. The parent who took the kids skating didn't rent \"Antz\".\n\r\n6. Mr. Sandoval wasn't the parent who rented \"Finding Nemo\" (which the children watched Thursday).\n\r\n7. Mrs. Lee is Derek's mother.\n\r\n8. Linda's parent, who isn't Mrs. Molinari and who didn't rent \"Antz\", entertained the kids on Friday.\n\r\n9. Ryan's parent took care of the children the day after the parent who took the kids swimming.", "hint": "No hint available.", "answer": "Monday, Mrs. Parker, Katie, Skating, Mulan\r\nTuesday, Mrs. Lee, Derek, Bowling, Monster's Inc.\r\nWednesday, Mr. Sandoval, Bruce, Swimming, Antz\r\nThursday, Mrs. Molinari, Ryan, Golf, Finding Nemo\r\nFriday, Mr. Bidwell, Linda, horseback riding, Ice Age\n\r\nFinding Nemo is on Thursday (6). Thus, Mr. Sandoval didn't entertain the kids on Friday (4). Nor did he entertain on Monday or Tuesday (4) or Thursday (6), so he entertained on Wednesday. The kids went skating on Monday and saw Monster's Inc on Tuesday (4). Linda's parent entertained the kids on Friday (8). They didn't see Antz on Monday (5) or Friday (8), so they saw it on Wednesday. Mrs. Lee is Derek's mom (7) and must be mentioned in clue 1. Since Mr. Sandoval rented Antz, then Mrs. Lee had to take the kids bowling. Since we know either the kids name, parents name or outing for Monday, Wednesday and Friday, Mrs. Lee is either Tuesday or Thursday. Since Finding Nemo is Thursday (6), then Mrs. Lee is on Tuesday (2). Linda's parent has to be mentioned in clue 1 and is either Mrs. Molinari or Mr. Bidwell. It is Mr. Bidwell (8). Thursday's parent is also mentioned in clue 1. He or she is not Katie's parent (2), therefore has to be Mrs. Molinari. By elimination, Mrs. Parker is on Monday. By elimination from clue 1, Katie is Mrs. Parker child. Ice age was rented on Friday (3) and by elimination Mulan was rented on Monday. The kids went swimming on Wednesday and Ryan was on Thursday (9). By elimination, Bruce was on Wednesday. The kids played golf on Thursday (3) and went horseback riding on Friday.", "category": "Logic-Grid", "date": "09/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe parents of five children decided to share responsibility for entertaining the kids (one of whom is Bruce) during the week between the end of day camp and the start of the school. Each parent took a different day of the week, Monday through Friday, to take the children on a different outing (including taking them horseback riding). They also each rented a movie (including Mulan) for the children to watch. For each day, determine who took care of the kids, that parent's child, the outing the parent supervised and the movie he or she rented. \n\r\n1. The five parents were: the one who took the children bowling, the one who rented \"Antz\", Katie's parent, Mr. Bidwell and Mrs. Molinari.\n\r\n2. The parent who rented \"Finding Nemo\" didn't take the kids bowling and isn't related to Katie.\n\r\n3. Neither Mrs. Parker nor the parent who took the kids to miniature golf rented \"Ice Age\".\n\r\n4. The children went roller skating the day before they saw \"Monster's Inc.\", which was the day before Mr. Sandoval entertained them.\n\r\n5. The parent who took the kids skating didn't rent \"Antz\".\n\r\n6. Mr. Sandoval wasn't the parent who rented \"Finding Nemo\" (which the children watched Thursday).\n\r\n7. Mrs. Lee is Derek's mother.\n\r\n8. Linda's parent, who isn't Mrs. Molinari and who didn't rent \"Antz\", entertained the kids on Friday.\n\r\n9. Ryan's parent took care of the children the day after the parent who took the kids swimming.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday, Mrs. Parker, Katie, Skating, Mulan\r\nTuesday, Mrs. Lee, Derek, Bowling, Monster's Inc.\r\nWednesday, Mr. Sandoval, Bruce, Swimming, Antz\r\nThursday, Mrs. Molinari, Ryan, Golf, Finding Nemo\r\nFriday, Mr. Bidwell, Linda, horseback riding, Ice Age\n\r\nFinding Nemo is on Thursday (6). Thus, Mr. Sandoval didn't entertain the kids on Friday (4). Nor did he entertain on Monday or Tuesday (4) or Thursday (6), so he entertained on Wednesday. The kids went skating on Monday and saw Monster's Inc on Tuesday (4). Linda's parent entertained the kids on Friday (8). They didn't see Antz on Monday (5) or Friday (8), so they saw it on Wednesday. Mrs. Lee is Derek's mom (7) and must be mentioned in clue 1. Since Mr. Sandoval rented Antz, then Mrs. Lee had to take the kids bowling. Since we know either the kids name, parents name or outing for Monday, Wednesday and Friday, Mrs. Lee is either Tuesday or Thursday. Since Finding Nemo is Thursday (6), then Mrs. Lee is on Tuesday (2). Linda's parent has to be mentioned in clue 1 and is either Mrs. Molinari or Mr. Bidwell. It is Mr. Bidwell (8). Thursday's parent is also mentioned in clue 1. He or she is not Katie's parent (2), therefore has to be Mrs. Molinari. By elimination, Mrs. Parker is on Monday. By elimination from clue 1, Katie is Mrs. Parker child. Ice age was rented on Friday (3) and by elimination Mulan was rented on Monday. The kids went swimming on Wednesday and Ryan was on Thursday (9). By elimination, Bruce was on Wednesday. The kids played golf on Thursday (3) and went horseback riding on Friday.\n<|im_start|>answer\nMonday, Mrs. Parker, Katie, Skating, Mulan\r\nTuesday, Mrs. Lee, Derek, Bowling, Monster's Inc.\r\nWednesday, Mr. Sandoval, Bruce, Swimming, Antz\r\nThursday, Mrs. Molinari, Ryan, Golf, Finding Nemo\r\nFriday, Mr. Bidwell, Linda, horseback riding, Ice Age\n\r\nFinding Nemo is on Thursday (6). Thus, Mr. Sandoval didn't entertain the kids on Friday (4). Nor did he entertain on Monday or Tuesday (4) or Thursday (6), so he entertained on Wednesday. The kids went skating on Monday and saw Monster's Inc on Tuesday (4). Linda's parent entertained the kids on Friday (8). They didn't see Antz on Monday (5) or Friday (8), so they saw it on Wednesday. Mrs. Lee is Derek's mom (7) and must be mentioned in clue 1. Since Mr. Sandoval rented Antz, then Mrs. Lee had to take the kids bowling. Since we know either the kids name, parents name or outing for Monday, Wednesday and Friday, Mrs. Lee is either Tuesday or Thursday. Since Finding Nemo is Thursday (6), then Mrs. Lee is on Tuesday (2). Linda's parent has to be mentioned in clue 1 and is either Mrs. Molinari or Mr. Bidwell. It is Mr. Bidwell (8). Thursday's parent is also mentioned in clue 1. He or she is not Katie's parent (2), therefore has to be Mrs. Molinari. By elimination, Mrs. Parker is on Monday. By elimination from clue 1, Katie is Mrs. Parker child. Ice age was rented on Friday (3) and by elimination Mulan was rented on Monday. The kids went swimming on Wednesday and Ryan was on Thursday (9). By elimination, Bruce was on Wednesday. The kids played golf on Thursday (3) and went horseback riding on Friday.\n<|im_end|>" }, { "id": "#50881", "title": "2 and 2 = 5", "fun": 3.13, "difficulty": 3.32, "author": "dalfamnest", "desc": "Two 2s can be combined in many ways to express different numbers. Here are some!\r\n2-2=0\r\n2/2 = 1\r\n.2 + 2 = 2.2\r\n(2^2)! = 24 (4! means 4x3x2x1) (2^2 is 2 to the power of 2)\n\r\n**CHALLENGE!**\r\nCan you write an expression that has the value of exactly 5, using:\r\n* two, and only two, 2s, and\r\n* any mathematical symbols or operations?\n\r\nYou may not use any other numbers. The symbols used would be known by most high school maths students.\n\n\r\nThe hint below lists the symbols that are used in this solution. Even with that information, it is a worthy challenge!\n\r\nOf course, other solutions may be possible! Solvers should write these in the Comments section.", "hint": "These operations or symbols are used, in some order:\r\n* exponent (index or power)\r\n* a minus (-) sign\r\n* brackets\r\n* square root\r\n* a decimal point", "answer": "The square root of point 2 to the power of minus 2.\n\r\nsqrt ( (.2)^(-2) )\n\r\n.2^(-2) is the same as 1/0.04, i.e. 25\n\r\n[Point 2 is usually written as 0.2, but .2 is also correct.]", "category": "Math", "date": "08/11/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo 2s can be combined in many ways to express different numbers. Here are some!\r\n2-2=0\r\n2/2 = 1\r\n.2 + 2 = 2.2\r\n(2^2)! = 24 (4! means 4x3x2x1) (2^2 is 2 to the power of 2)\n\r\n**CHALLENGE!**\r\nCan you write an expression that has the value of exactly 5, using:\r\n* two, and only two, 2s, and\r\n* any mathematical symbols or operations?\n\r\nYou may not use any other numbers. The symbols used would be known by most high school maths students.\n\n\r\nThe hint below lists the symbols that are used in this solution. Even with that information, it is a worthy challenge!\n\r\nOf course, other solutions may be possible! Solvers should write these in the Comments section.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe square root of point 2 to the power of minus 2.\n\r\nsqrt ( (.2)^(-2) )\n\r\n.2^(-2) is the same as 1/0.04, i.e. 25\n\r\n[Point 2 is usually written as 0.2, but .2 is also correct.]\n<|im_start|>answer\nThe square root of point 2 to the power of minus 2.\n\r\nsqrt ( (.2)^(-2) )\n\r\n.2^(-2) is the same as 1/0.04, i.e. 25\n\r\n[Point 2 is usually written as 0.2, but .2 is also correct.]\n<|im_end|>" }, { "id": "#27316", "title": "Book Reports - Who Read What?", "fun": 3.13, "difficulty": 1.6400000000000001, "author": "Winner4600", "desc": "Jessica, Matt, Chris, Ellen, and Tony are five students having the surnames Saunders, Alvarez, Mason, Tan, and Locke (not necessarily in that order) assigned to each read a different book and write a book report on them. But their teacher, unluckily, has forgotten which student is supposed to read which book! Help her figure out the students' full names, assigned books, and presentation dates from the clues below.\n\r\nStudents: Jessica, Matt, Chris, Ellen, Tony\r\nSurnames: Saunders, Alvarez, Mason, Tan, Locke\r\nBooks: Pride and Prejudice, Jane Eyre, Gone With the Wind, War and Peace, Oliver Twist\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\n\n\r\n1. Jessica, Chris, and the girl reading War and Peace plan to write their reports together on Monday night.\n\r\n2. The 5 students are Matt, the girl presenting on Wednesday, the guy presenting on Tuesday, the kid reading Gone With the Wind, and Chris Saunders.\n\r\n3. No person has the same first and last initials.\n\r\n4. Miss Alvarez is presenting on Wednesday, while Pride and Prejudice is being presented on Monday.\n\r\n5. Locke is mad he is the first to present, but Chris is happy because he is last.\n\r\n6. Miss Tan wanted to read either Jane Eyre or War and Peace, but Tony and Ellen wound up reporting them instead.", "hint": "P&P=Pride and Prejudice\r\nGWTW=Gone With the Wind", "answer": "Jessica Tan is reporting Gone With the Wind on Thursday.\r\nMatt Locke is reporting Pride and Prejudice on Monday.\r\nChris Saunders is reporting Oliver Twist on Friday.\r\nEllen Alvarez is reporting War and Peace on Wednesday.\r\nTony Mason is reporting Jane Eyre on Tuesday.", "category": "Logic-Grid", "date": "12/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJessica, Matt, Chris, Ellen, and Tony are five students having the surnames Saunders, Alvarez, Mason, Tan, and Locke (not necessarily in that order) assigned to each read a different book and write a book report on them. But their teacher, unluckily, has forgotten which student is supposed to read which book! Help her figure out the students' full names, assigned books, and presentation dates from the clues below.\n\r\nStudents: Jessica, Matt, Chris, Ellen, Tony\r\nSurnames: Saunders, Alvarez, Mason, Tan, Locke\r\nBooks: Pride and Prejudice, Jane Eyre, Gone With the Wind, War and Peace, Oliver Twist\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\n\n\r\n1. Jessica, Chris, and the girl reading War and Peace plan to write their reports together on Monday night.\n\r\n2. The 5 students are Matt, the girl presenting on Wednesday, the guy presenting on Tuesday, the kid reading Gone With the Wind, and Chris Saunders.\n\r\n3. No person has the same first and last initials.\n\r\n4. Miss Alvarez is presenting on Wednesday, while Pride and Prejudice is being presented on Monday.\n\r\n5. Locke is mad he is the first to present, but Chris is happy because he is last.\n\r\n6. Miss Tan wanted to read either Jane Eyre or War and Peace, but Tony and Ellen wound up reporting them instead.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJessica Tan is reporting Gone With the Wind on Thursday.\r\nMatt Locke is reporting Pride and Prejudice on Monday.\r\nChris Saunders is reporting Oliver Twist on Friday.\r\nEllen Alvarez is reporting War and Peace on Wednesday.\r\nTony Mason is reporting Jane Eyre on Tuesday.\n<|im_start|>answer\nJessica Tan is reporting Gone With the Wind on Thursday.\r\nMatt Locke is reporting Pride and Prejudice on Monday.\r\nChris Saunders is reporting Oliver Twist on Friday.\r\nEllen Alvarez is reporting War and Peace on Wednesday.\r\nTony Mason is reporting Jane Eyre on Tuesday.\n<|im_end|>" }, { "id": "#23739", "title": "Day at the Pet Shop", "fun": 3.13, "difficulty": 2.03, "author": "Puppypaws129", "desc": "Five People went to the pet shop on different days of the week. They each bought a different breed of dog and a different color dog bowl for them. There are three girls and two guys.\r\nGirl's Names: Ashley, Camile, and Jenny\r\nGuy's Names: Andrew and Brandon\r\nLast Names: Anderson, White, Miller, Green, and Smith\r\nDog Breeds: St. Bernard, Pug, Golden Retriever, Australian Shepherd, and Bulldog\r\nBowl Colors: Pink, Purple, Green, Blue, and Yellow\r\nDays: Monday, Tuesday, Wednesday, Thursday, and Friday\n\n\n\r\n1. No one's first name starts with the same letter as their last name or the first letter of the breed of dog they bought.\n\r\n2. Andrew's last name is Green, but it's not his favorite color, nor is it the color of his bowl.\n\r\n3. The order in which they bought their dogs are as follows: The guy whose bowl is yellow, the one who bought the St. Bernard, the girl whose last name is White, the person with the pink bowl, and Brandon.\n\r\n4. Camile bought her dog before Ashley (who has a blue bowl) but after the person with the yellow bowl.\n\r\n5. Jenny and Camile both hate the color green and they spent all day at the park together on Wednesday.\n\r\n6. The girl whose last name is Miller and the girl whose last name is Smith are, in some order, the one who bought the Australian Shepherd, and the one who bought their dog on Tuesday.\n\r\n7. Each of the guys bought one of the two small dogs.\n\r\n8. The girl whose last name is Miller bought her dog after the girl who bought the purple bowl.", "hint": "If they hate a color then they didn't buy that color bowl. \n\r\nThe two small dogs are the Pug and the Bulldog.\n\r\nIf they spent the whole day at the park then they didn't have time to go to the pet shop that day.", "answer": "Ashley: White, Golden Retriever, Blue, Wednesday\n\r\nCamile: Smith, St. Bernard, Purple, Tuesday\n\r\nJenny: Miller, Australian Shepherd, Pink, Thursday\n\r\nAndrew: Green, Bulldog, Yellow, Monday\n\r\nBrandon: Anderson, Pug, Green, Friday", "category": "Logic-Grid", "date": "06/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive People went to the pet shop on different days of the week. They each bought a different breed of dog and a different color dog bowl for them. There are three girls and two guys.\r\nGirl's Names: Ashley, Camile, and Jenny\r\nGuy's Names: Andrew and Brandon\r\nLast Names: Anderson, White, Miller, Green, and Smith\r\nDog Breeds: St. Bernard, Pug, Golden Retriever, Australian Shepherd, and Bulldog\r\nBowl Colors: Pink, Purple, Green, Blue, and Yellow\r\nDays: Monday, Tuesday, Wednesday, Thursday, and Friday\n\n\n\r\n1. No one's first name starts with the same letter as their last name or the first letter of the breed of dog they bought.\n\r\n2. Andrew's last name is Green, but it's not his favorite color, nor is it the color of his bowl.\n\r\n3. The order in which they bought their dogs are as follows: The guy whose bowl is yellow, the one who bought the St. Bernard, the girl whose last name is White, the person with the pink bowl, and Brandon.\n\r\n4. Camile bought her dog before Ashley (who has a blue bowl) but after the person with the yellow bowl.\n\r\n5. Jenny and Camile both hate the color green and they spent all day at the park together on Wednesday.\n\r\n6. The girl whose last name is Miller and the girl whose last name is Smith are, in some order, the one who bought the Australian Shepherd, and the one who bought their dog on Tuesday.\n\r\n7. Each of the guys bought one of the two small dogs.\n\r\n8. The girl whose last name is Miller bought her dog after the girl who bought the purple bowl.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAshley: White, Golden Retriever, Blue, Wednesday\n\r\nCamile: Smith, St. Bernard, Purple, Tuesday\n\r\nJenny: Miller, Australian Shepherd, Pink, Thursday\n\r\nAndrew: Green, Bulldog, Yellow, Monday\n\r\nBrandon: Anderson, Pug, Green, Friday\n<|im_start|>answer\nAshley: White, Golden Retriever, Blue, Wednesday\n\r\nCamile: Smith, St. Bernard, Purple, Tuesday\n\r\nJenny: Miller, Australian Shepherd, Pink, Thursday\n\r\nAndrew: Green, Bulldog, Yellow, Monday\n\r\nBrandon: Anderson, Pug, Green, Friday\n<|im_end|>" }, { "id": "#49384", "title": "Aunt's Ol' Jalopy", "fun": 3.13, "difficulty": 1.68, "author": "firefox99", "desc": "After visiting my Great Aunt Annie, I travelled home in her old jalopy. The car was old and battered, it had a leak from the petrol tank, and I was stuck in second gear.\n\r\nThis meant that I could only travel along at a steady 30 miles per hour and managed a paltry 20 miles per gallon of fuel. \n\r\nAt the start of the journey I had placed exactly 10 gallons of fuel into the tank. I knew though, that the fuel tank lost fuel at the rate of half a gallon per hour.\n\r\nJust as I arrived home, the car stopped because it had run out of fuel and I had only just made it.\n\n\r\nHow far was it from my Great Aunt's to my home?", "hint": "No hint available.", "answer": "150 miles.\n\r\nI was travelling at 30mph at a rate of 20mpg, so I was using 1.5 gallons every hour for the driving itself. I was also losing 0.5 gallon every hour, so in total, I was using 2 gallons every hour. Therefore to use all of the 10 gallons I started with, I travelled for 5 hours. \n\r\n5 hours at 30mph is 150 miles.", "category": "Math", "date": "03/23/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter visiting my Great Aunt Annie, I travelled home in her old jalopy. The car was old and battered, it had a leak from the petrol tank, and I was stuck in second gear.\n\r\nThis meant that I could only travel along at a steady 30 miles per hour and managed a paltry 20 miles per gallon of fuel. \n\r\nAt the start of the journey I had placed exactly 10 gallons of fuel into the tank. I knew though, that the fuel tank lost fuel at the rate of half a gallon per hour.\n\r\nJust as I arrived home, the car stopped because it had run out of fuel and I had only just made it.\n\n\r\nHow far was it from my Great Aunt's to my home?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n150 miles.\n\r\nI was travelling at 30mph at a rate of 20mpg, so I was using 1.5 gallons every hour for the driving itself. I was also losing 0.5 gallon every hour, so in total, I was using 2 gallons every hour. Therefore to use all of the 10 gallons I started with, I travelled for 5 hours. \n\r\n5 hours at 30mph is 150 miles.\n<|im_start|>answer\n150 miles.\n\r\nI was travelling at 30mph at a rate of 20mpg, so I was using 1.5 gallons every hour for the driving itself. I was also losing 0.5 gallon every hour, so in total, I was using 2 gallons every hour. Therefore to use all of the 10 gallons I started with, I travelled for 5 hours. \n\r\n5 hours at 30mph is 150 miles.\n<|im_end|>" }, { "id": "#21287", "title": "Good Doggie", "fun": 3.13, "difficulty": 2.5100000000000002, "author": "jpfrank1", "desc": "Five dog owners have taken their puppies to doggie training school. In order to graduate, each puppy must perform at least one trick flawlessly for their master. The owners, 3 men (Jordan, Ethan and Michael) and 2 women (Haley and Alexis), are preparing their dogs (Merlin, Bogey, Eagle, Bailey and Daisy) for the final exam. Your job is to identify the owner of each dog, and each dog's age, breed, name and its trick. Note: unless stated otherwise, all references to ages are in dog years and the grid provides ages in dog years as well. Good Luck and Enjoy!!\n\r\n1. No owner's first name shares an initial with either their dog's first name or the breed name.\n\r\n2. Jordan's dog can speak (not real words, just dog words like Aarf).\n\r\n3. The Yellow Lab performs a trick with two words.\n\r\n4. The 1 year old dog is a mixed breed.\n\r\n5. Daisy is a beagle.\n\r\n6. Alexis's dog, who can't sit, is older than Haley's dog and younger than the dog that can play dead.\n\r\n7. No matter how hard he tries, Merlin's owner can only get him to roll over.\n\r\n8. Michael's dog is 14 years old--in human years.\n\r\n9. Bogey sits and watches the 1 year old dog speak.\n\r\n10. For his one year birthday today, Bailey got a date with the Maltipoo (witnesses say it was puppy love at first sight).\n\r\n11. The Beagle's owner is very refined, so she prefers that you say her dog \"politely requested\" instead of begs.\n\r\n12. The 18 month old German Shepherd is owned by a boy.", "hint": "A Maltipoo is a mix of a Maltese and Poodle.\n\r\nA Puffette is a mix of a Chinese Crested and a Pomeranian\n\r\n1 human year = 7 dog years.", "answer": "Jordan: 1 year old Puffette named \r\nBailey who speaks.\n\r\nHaley: 6 month old Maltipoo named Bogey who sits.\n\r\nEthan: 18 month old German Shepherd name Merlin who rolls over.\n\r\nMichael: 2 year old Yellow Lab named Eagle who Plays Dead.\n\r\nAlexis: 8 month old Beagle named Daisy who Begs.", "category": "Logic-Grid", "date": "03/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive dog owners have taken their puppies to doggie training school. In order to graduate, each puppy must perform at least one trick flawlessly for their master. The owners, 3 men (Jordan, Ethan and Michael) and 2 women (Haley and Alexis), are preparing their dogs (Merlin, Bogey, Eagle, Bailey and Daisy) for the final exam. Your job is to identify the owner of each dog, and each dog's age, breed, name and its trick. Note: unless stated otherwise, all references to ages are in dog years and the grid provides ages in dog years as well. Good Luck and Enjoy!!\n\r\n1. No owner's first name shares an initial with either their dog's first name or the breed name.\n\r\n2. Jordan's dog can speak (not real words, just dog words like Aarf).\n\r\n3. The Yellow Lab performs a trick with two words.\n\r\n4. The 1 year old dog is a mixed breed.\n\r\n5. Daisy is a beagle.\n\r\n6. Alexis's dog, who can't sit, is older than Haley's dog and younger than the dog that can play dead.\n\r\n7. No matter how hard he tries, Merlin's owner can only get him to roll over.\n\r\n8. Michael's dog is 14 years old--in human years.\n\r\n9. Bogey sits and watches the 1 year old dog speak.\n\r\n10. For his one year birthday today, Bailey got a date with the Maltipoo (witnesses say it was puppy love at first sight).\n\r\n11. The Beagle's owner is very refined, so she prefers that you say her dog \"politely requested\" instead of begs.\n\r\n12. The 18 month old German Shepherd is owned by a boy.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJordan: 1 year old Puffette named \r\nBailey who speaks.\n\r\nHaley: 6 month old Maltipoo named Bogey who sits.\n\r\nEthan: 18 month old German Shepherd name Merlin who rolls over.\n\r\nMichael: 2 year old Yellow Lab named Eagle who Plays Dead.\n\r\nAlexis: 8 month old Beagle named Daisy who Begs.\n<|im_start|>answer\nJordan: 1 year old Puffette named \r\nBailey who speaks.\n\r\nHaley: 6 month old Maltipoo named Bogey who sits.\n\r\nEthan: 18 month old German Shepherd name Merlin who rolls over.\n\r\nMichael: 2 year old Yellow Lab named Eagle who Plays Dead.\n\r\nAlexis: 8 month old Beagle named Daisy who Begs.\n<|im_end|>" }, { "id": "#25010", "title": "The War of the Worlds - Part I", "fun": 3.12, "difficulty": 2.05, "author": "smarty_blondy", "desc": "No place is a safe place, for in the caves of The World Beneath, the evil Lord Zyron has decided he will not rest until his terrific Master Plan is complete. If he succeeds in his conquest, all humanity will melt down into the darkness of The Underground, and the world, as we know it, will soon be transformed into a desert of dust and ashes! He wishes to assign three of his most trusted myrmidons to climb up to the surface and complete his terrific task, declare and lead The War of the Worlds. \n\r\nBut The World Beneath has many dreadful monsters, sorcerers and witches from which Lord Zyron must chose. Lurking in the archive of The Underground, he has found the files of five of his most loyal servants, partly consumed by fire. Can you find out the details about each of Lord Zyron's myrmidons from what's left of the files? \n\r\nMyrmidons' names: Tamika, Vidomina, Axsis, Galthran, Xarfax; \r\nOccupations: Death Knight, Demon, Black Witch, Alchemist, Vampire; \r\nExperience: 629 years, 274 years, 56 years, 31 years, 9 years; \r\nArea of Expertise: Wisdom, Fire Magic, Tactics, Mysticism, Scouting; \r\nMagical Artifact: Cape of Wickedness, Helm of Chaos, Celestial Necklace, Shield of the Damned, Sorcerer's Stone. \n\r\n1. Vidomina, the wisest of them all, and Xarfax, the possessor of the Sorcerer's Stone, are the only immortals, and so have more experience than the mortals.\n\r\n2. The most inexperienced servant is the Demon, possessor of the Helm of Chaos. \n\r\n3. The Black Witch was born and raised in the spirit of fire, and is therefore an expert in its magic. \n\r\n4. The most experienced mortal, and possessor of the Shield of the Damned, is neither Tamika nor Vidomina, but the Death Knight. \n\r\n5. Xarfax has been an expert in his area for 629 years, but not in Tactics or in Scouting. \n\r\n6. The Alchemist is an expert in Mysticism. \n\r\n7. The Vampire is well known for her long life; therefore she has become an expert in Wisdom.\n\r\n8. Axsis has been an expert in his area for 9 years, but not in Scouting or Mysticism. \n\r\n9. Tamika, the Fire expert, is possessor of the Cape of Wickedness.", "hint": "No hint available.", "answer": "1. Tamika is the Black Witch, expert in Fire Magic for 31 years now, and possessor of the Cape of Wickedness. \n\r\n2. Xarfax is the Alchemist, expert in Mysticism for 629 years now, and possessor of the Sorcerer's Stone. \n\r\n3. Galthran is the Death Knight, expert in Scouting for 56 years now, and possessor of the Shield of the Damned. \n\r\n4. Vidomina is the Vampire, expert in Wisdom for 274 years now, and possessor of the Celestial Necklace. \n\r\n5. Axsis is the Demon, expert in Tactics for 9 years now, and possessor of the Helm of Chaos \n\r\nThank you for completing Lord Zyron's task! After seeing the list with his top five humble myrmidons, he has chosen the most worthy three, and is now preparing his evil Master Plan in secret.", "category": "Logic-Grid", "date": "08/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNo place is a safe place, for in the caves of The World Beneath, the evil Lord Zyron has decided he will not rest until his terrific Master Plan is complete. If he succeeds in his conquest, all humanity will melt down into the darkness of The Underground, and the world, as we know it, will soon be transformed into a desert of dust and ashes! He wishes to assign three of his most trusted myrmidons to climb up to the surface and complete his terrific task, declare and lead The War of the Worlds. \n\r\nBut The World Beneath has many dreadful monsters, sorcerers and witches from which Lord Zyron must chose. Lurking in the archive of The Underground, he has found the files of five of his most loyal servants, partly consumed by fire. Can you find out the details about each of Lord Zyron's myrmidons from what's left of the files? \n\r\nMyrmidons' names: Tamika, Vidomina, Axsis, Galthran, Xarfax; \r\nOccupations: Death Knight, Demon, Black Witch, Alchemist, Vampire; \r\nExperience: 629 years, 274 years, 56 years, 31 years, 9 years; \r\nArea of Expertise: Wisdom, Fire Magic, Tactics, Mysticism, Scouting; \r\nMagical Artifact: Cape of Wickedness, Helm of Chaos, Celestial Necklace, Shield of the Damned, Sorcerer's Stone. \n\r\n1. Vidomina, the wisest of them all, and Xarfax, the possessor of the Sorcerer's Stone, are the only immortals, and so have more experience than the mortals.\n\r\n2. The most inexperienced servant is the Demon, possessor of the Helm of Chaos. \n\r\n3. The Black Witch was born and raised in the spirit of fire, and is therefore an expert in its magic. \n\r\n4. The most experienced mortal, and possessor of the Shield of the Damned, is neither Tamika nor Vidomina, but the Death Knight. \n\r\n5. Xarfax has been an expert in his area for 629 years, but not in Tactics or in Scouting. \n\r\n6. The Alchemist is an expert in Mysticism. \n\r\n7. The Vampire is well known for her long life; therefore she has become an expert in Wisdom.\n\r\n8. Axsis has been an expert in his area for 9 years, but not in Scouting or Mysticism. \n\r\n9. Tamika, the Fire expert, is possessor of the Cape of Wickedness.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Tamika is the Black Witch, expert in Fire Magic for 31 years now, and possessor of the Cape of Wickedness. \n\r\n2. Xarfax is the Alchemist, expert in Mysticism for 629 years now, and possessor of the Sorcerer's Stone. \n\r\n3. Galthran is the Death Knight, expert in Scouting for 56 years now, and possessor of the Shield of the Damned. \n\r\n4. Vidomina is the Vampire, expert in Wisdom for 274 years now, and possessor of the Celestial Necklace. \n\r\n5. Axsis is the Demon, expert in Tactics for 9 years now, and possessor of the Helm of Chaos \n\r\nThank you for completing Lord Zyron's task! After seeing the list with his top five humble myrmidons, he has chosen the most worthy three, and is now preparing his evil Master Plan in secret.\n<|im_start|>answer\n1. Tamika is the Black Witch, expert in Fire Magic for 31 years now, and possessor of the Cape of Wickedness. \n\r\n2. Xarfax is the Alchemist, expert in Mysticism for 629 years now, and possessor of the Sorcerer's Stone. \n\r\n3. Galthran is the Death Knight, expert in Scouting for 56 years now, and possessor of the Shield of the Damned. \n\r\n4. Vidomina is the Vampire, expert in Wisdom for 274 years now, and possessor of the Celestial Necklace. \n\r\n5. Axsis is the Demon, expert in Tactics for 9 years now, and possessor of the Helm of Chaos \n\r\nThank you for completing Lord Zyron's task! After seeing the list with his top five humble myrmidons, he has chosen the most worthy three, and is now preparing his evil Master Plan in secret.\n<|im_end|>" }, { "id": "#1416", "title": "The King and the Poison", "fun": 3.12, "difficulty": 2.81, "author": "Yanivster", "desc": "In a far away land, it was known that if you drank poison, the only way to save yourself is to drink a stronger poison, which neutralizes the weaker poison. The king that ruled the land wanted to make sure that he possessed the strongest poison in the kingdom, in order to ensure his survival, in any situation. So the king called the kingdom's pharmacist and the kingdom's treasurer, he gave each a week to make the strongest poison. Then, each would drink the other one's poison, then his own, and the one that will survive, will be the one that had the stronger poison. \r\nThe pharmacist went straight to work, but the treasurer knew he had no chance, for the pharmacist was much more experienced in this field, so instead, he made up a plan to survive and make sure the pharmacist dies. On the last day the pharmacist suddenly realized that the treasurer would know he had no chance, so he must have a plan. After a little thought, the pharmacist realized what the treasurer's plan must be, and he concocted a counter plan, to make sure he survives and the treasurer dies. When the time came, the king summoned both of them. They drank the poisons as planned, and the treasurer died, the pharmacist survived, and the king didn't get what he wanted. \r\nWhat exactly happened there?", "hint": "No hint available.", "answer": "The treasurer's plan was to drink a weak poison prior to the meeting with the king, and then he would drink the pharmacist's strong poison, which would neutralize the weak poison. As his own poison he would bring water, which will have no effect on him, but the pharmacist who would drink the water, and then his poison would surely die. When the pharmacist figured out this plan, he decided to bring water as well. So the treasurer who drank poison earlier, drank the pharmacist's water, then his own water, and died of the poison he drank before. The pharmacist would drink only water, so nothing will happen to him. And because both of them brought the king water, he didn't get a strong poison like he wanted.", "category": "Logic", "date": "11/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a far away land, it was known that if you drank poison, the only way to save yourself is to drink a stronger poison, which neutralizes the weaker poison. The king that ruled the land wanted to make sure that he possessed the strongest poison in the kingdom, in order to ensure his survival, in any situation. So the king called the kingdom's pharmacist and the kingdom's treasurer, he gave each a week to make the strongest poison. Then, each would drink the other one's poison, then his own, and the one that will survive, will be the one that had the stronger poison. \r\nThe pharmacist went straight to work, but the treasurer knew he had no chance, for the pharmacist was much more experienced in this field, so instead, he made up a plan to survive and make sure the pharmacist dies. On the last day the pharmacist suddenly realized that the treasurer would know he had no chance, so he must have a plan. After a little thought, the pharmacist realized what the treasurer's plan must be, and he concocted a counter plan, to make sure he survives and the treasurer dies. When the time came, the king summoned both of them. They drank the poisons as planned, and the treasurer died, the pharmacist survived, and the king didn't get what he wanted. \r\nWhat exactly happened there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe treasurer's plan was to drink a weak poison prior to the meeting with the king, and then he would drink the pharmacist's strong poison, which would neutralize the weak poison. As his own poison he would bring water, which will have no effect on him, but the pharmacist who would drink the water, and then his poison would surely die. When the pharmacist figured out this plan, he decided to bring water as well. So the treasurer who drank poison earlier, drank the pharmacist's water, then his own water, and died of the poison he drank before. The pharmacist would drink only water, so nothing will happen to him. And because both of them brought the king water, he didn't get a strong poison like he wanted.\n<|im_start|>answer\nThe treasurer's plan was to drink a weak poison prior to the meeting with the king, and then he would drink the pharmacist's strong poison, which would neutralize the weak poison. As his own poison he would bring water, which will have no effect on him, but the pharmacist who would drink the water, and then his poison would surely die. When the pharmacist figured out this plan, he decided to bring water as well. So the treasurer who drank poison earlier, drank the pharmacist's water, then his own water, and died of the poison he drank before. The pharmacist would drink only water, so nothing will happen to him. And because both of them brought the king water, he didn't get a strong poison like he wanted.\n<|im_end|>" }, { "id": "#19969", "title": "Reindeer Rescue", "fun": 3.12, "difficulty": 2.7600000000000002, "author": "lorial", "desc": "Whilst delivering Christmas presents, Santa became stuck in different chimneys and became very behind schedule. At what time was Santa rescued from each chimney, which child was he delivering what present to and which reindeer hauled him out?\t\n\r\nSanta was not delivering the Train Set to Craig.\n\r\nRudolph hauled Santa out of one chimney exactly 1 hour before Santa was rescued from Diana's chimney.\n\r\nBuilding Blocks were delivered to Ryan after 1:30a.m. but before 4:00a.m.\n\r\nBlitzen hauled Santa out of one chimney exactly half an hour after Donner hauled him out of another.\n\r\nComet helped Santa when he was stuck in Jerry's chimney: this was not the last chimney that he was stuck in that morning.\n\r\nThe Teddy Bear was delivered directly before the Doll, but not to Diana and wasn't with Santa when Rudolph pulled him out.\n\r\nPrancer did not help Santa when he was stuck in the chimney with Drums.\n\r\nNo reindeer helped Santa out of a chimney with a toy having the same initial as the reindeer's name.\n\r\nTimes: \t\t1:00a.m, 1:30a.m, 2:00a.m, 2:30a.m, 4:00a.m.\r\nReindeer:\tBlitzen, Comet, Donner, Prancer, Rudolph\r\nChild:\t\tCraig, Diana, Jerry, Ryan, Sadie\r\nToy:\t\tBuilding Blocks, Doll, Drums, Teddy Bear, Train Set", "hint": "No hint available.", "answer": "Reindeer / Child / Time / Toy\n\r\nBlitzen / Diana / 2:30a.m / Drums\r\nComet / Jerry / 1:00a.m / Teddy Bear\r\nDonner / Ryan / 2:00a.m / Building Blocks\r\nPrancer / Sadie / 4:00a.m / Train Set\r\nRudolph / Craig / 1:30a.m / Doll", "category": "Logic-Grid", "date": "12/20/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhilst delivering Christmas presents, Santa became stuck in different chimneys and became very behind schedule. At what time was Santa rescued from each chimney, which child was he delivering what present to and which reindeer hauled him out?\t\n\r\nSanta was not delivering the Train Set to Craig.\n\r\nRudolph hauled Santa out of one chimney exactly 1 hour before Santa was rescued from Diana's chimney.\n\r\nBuilding Blocks were delivered to Ryan after 1:30a.m. but before 4:00a.m.\n\r\nBlitzen hauled Santa out of one chimney exactly half an hour after Donner hauled him out of another.\n\r\nComet helped Santa when he was stuck in Jerry's chimney: this was not the last chimney that he was stuck in that morning.\n\r\nThe Teddy Bear was delivered directly before the Doll, but not to Diana and wasn't with Santa when Rudolph pulled him out.\n\r\nPrancer did not help Santa when he was stuck in the chimney with Drums.\n\r\nNo reindeer helped Santa out of a chimney with a toy having the same initial as the reindeer's name.\n\r\nTimes: \t\t1:00a.m, 1:30a.m, 2:00a.m, 2:30a.m, 4:00a.m.\r\nReindeer:\tBlitzen, Comet, Donner, Prancer, Rudolph\r\nChild:\t\tCraig, Diana, Jerry, Ryan, Sadie\r\nToy:\t\tBuilding Blocks, Doll, Drums, Teddy Bear, Train Set\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nReindeer / Child / Time / Toy\n\r\nBlitzen / Diana / 2:30a.m / Drums\r\nComet / Jerry / 1:00a.m / Teddy Bear\r\nDonner / Ryan / 2:00a.m / Building Blocks\r\nPrancer / Sadie / 4:00a.m / Train Set\r\nRudolph / Craig / 1:30a.m / Doll\n<|im_start|>answer\nReindeer / Child / Time / Toy\n\r\nBlitzen / Diana / 2:30a.m / Drums\r\nComet / Jerry / 1:00a.m / Teddy Bear\r\nDonner / Ryan / 2:00a.m / Building Blocks\r\nPrancer / Sadie / 4:00a.m / Train Set\r\nRudolph / Craig / 1:30a.m / Doll\n<|im_end|>" }, { "id": "#27053", "title": "Apple Pickers #2", "fun": 3.12, "difficulty": 2.23, "author": "ilovehimalways", "desc": "Since Jeremy and his friends now had more apples than they could possibly eat, they needed to find ways to use them up. So each friend hit the cookbooks and started busily baking (it's remarkable how many yummy recipes there are for apples!). As it happens, each friend did such a good job making one recipe, that it was forever after their specialty. Fortunately for them, each one had a different specialty. Determine the name of each friend's special recipe, the type of apples and special ingredient each dish used, and the number of apples each recipe used.\n\r\n1. The recipes, in no particular order, were the recipe using cinnamon, the recipe using three apples, the apple tarts, the recipe using Macoun apples, and the apple crisp.\n\r\n2. The recipe using the Cortland apples used one apple more than the apple bread but one apple less than the recipe using the raisins.\n\r\n3. The muffins used one more apple than the recipe with the walnuts but two less apples than the recipe using the Red Delicious apples.\n\r\n4. The nutmeg was used in the apple crisp, which used more than two apples but less than the apple pie used. The apple pie used more apples than the treat with the raisins.\n\r\n5. The apple muffins, which weren't made with Macoun apples, used pecans.\n\r\n6. The Empire apples weren't used in the apple crisp. The recipe using the McIntosh apples used the most apples.", "hint": "There were four Empire apples used with the raisins.", "answer": "Apple Bread-Macoun-walnuts-2\r\nApple Crisp-Red Delicious-nutmeg-5\r\nApple Muffins-Cortland-pecans-3\r\nApple Pie-McIntosh-cinnamon-6\r\nApple Tarts-Empire-raisins-4", "category": "Logic-Grid", "date": "11/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSince Jeremy and his friends now had more apples than they could possibly eat, they needed to find ways to use them up. So each friend hit the cookbooks and started busily baking (it's remarkable how many yummy recipes there are for apples!). As it happens, each friend did such a good job making one recipe, that it was forever after their specialty. Fortunately for them, each one had a different specialty. Determine the name of each friend's special recipe, the type of apples and special ingredient each dish used, and the number of apples each recipe used.\n\r\n1. The recipes, in no particular order, were the recipe using cinnamon, the recipe using three apples, the apple tarts, the recipe using Macoun apples, and the apple crisp.\n\r\n2. The recipe using the Cortland apples used one apple more than the apple bread but one apple less than the recipe using the raisins.\n\r\n3. The muffins used one more apple than the recipe with the walnuts but two less apples than the recipe using the Red Delicious apples.\n\r\n4. The nutmeg was used in the apple crisp, which used more than two apples but less than the apple pie used. The apple pie used more apples than the treat with the raisins.\n\r\n5. The apple muffins, which weren't made with Macoun apples, used pecans.\n\r\n6. The Empire apples weren't used in the apple crisp. The recipe using the McIntosh apples used the most apples.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nApple Bread-Macoun-walnuts-2\r\nApple Crisp-Red Delicious-nutmeg-5\r\nApple Muffins-Cortland-pecans-3\r\nApple Pie-McIntosh-cinnamon-6\r\nApple Tarts-Empire-raisins-4\n<|im_start|>answer\nApple Bread-Macoun-walnuts-2\r\nApple Crisp-Red Delicious-nutmeg-5\r\nApple Muffins-Cortland-pecans-3\r\nApple Pie-McIntosh-cinnamon-6\r\nApple Tarts-Empire-raisins-4\n<|im_end|>" }, { "id": "#26234", "title": "Night Light", "fun": 3.12, "difficulty": 2.7600000000000002, "author": "dcf525", "desc": "Many fears disappear when we become adults, but some fears are never outgrown. Five friends recently discovered that they were all, to some extent, afraid of the dark. None sleep in total darkness; each prefer to have a different light on all night. With further discussion, each also admitted that he or she performs a different nightly routine before retiring. Can you discover each person's full name, the light he or she keeps on at night, and each person's habitual practice before bedtime?\n\r\nFriends: Donald, Gretchen, John, Dawn, Stephanie\n\r\nLast names: Upgraff, Foster, Weatherton, Buchanan, Young\n\r\nRoutines: Closes closet door, checks locks, put a phone by the bed, pulls down the shades, and looks under the bed\n\r\nLights: Desk lamp, hall light, night-light, overhead light, computer screen\n\r\n1. Either Donald or Stephanie admitted with some embarrassment that he or she always checks under the bed before getting in it.\n\r\n2. The person who double checks all the house locks sleeps with either the Winnie-the-Pooh night-light or a desk lamp on.\n\r\n3. The five people are: Gretchen, Dawn, Buchanan, the person who sleeps with his or her computer screen lit, and the person who always keeps a phone near the bed for security. \n\r\n4. Weatherton (who isn't Dawn) and the person who sleeps with a night-light are members of the opposite sex.\n\r\n5. Neither John nor Stephanie sleeps with the hall light on.\n\r\n6. Dawn isn't the person who pulls down the shades at night.\n\r\n7. The person who sleeps with the overhead light on (who is surnamed either Foster or Young) doesn't find it necessary to keep a phone by the bed.\n\r\n8. Mr. Upgraff routinely closes the door to his closet, lest the creepy things that lurk within emerge while he sleeps.\n\r\n9. Buchanan doesn't sleep with the Winnie-the-Pooh night-light.\n\r\n10. Young sleeps with either a desk light or the overhead light lit.", "hint": "John and Donald are male; Gretchen, Dawn and Stepanie are female.", "answer": "Donald Weatherton, hall light, phone\r\nGretchen Young, overhead light, shades\r\nJohn Upgraff, computer screen, closet\r\nDawn Foster, night-light, locks\r\nStephanie Buchanan, desk lamp, checks under bed", "category": "Logic-Grid", "date": "10/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMany fears disappear when we become adults, but some fears are never outgrown. Five friends recently discovered that they were all, to some extent, afraid of the dark. None sleep in total darkness; each prefer to have a different light on all night. With further discussion, each also admitted that he or she performs a different nightly routine before retiring. Can you discover each person's full name, the light he or she keeps on at night, and each person's habitual practice before bedtime?\n\r\nFriends: Donald, Gretchen, John, Dawn, Stephanie\n\r\nLast names: Upgraff, Foster, Weatherton, Buchanan, Young\n\r\nRoutines: Closes closet door, checks locks, put a phone by the bed, pulls down the shades, and looks under the bed\n\r\nLights: Desk lamp, hall light, night-light, overhead light, computer screen\n\r\n1. Either Donald or Stephanie admitted with some embarrassment that he or she always checks under the bed before getting in it.\n\r\n2. The person who double checks all the house locks sleeps with either the Winnie-the-Pooh night-light or a desk lamp on.\n\r\n3. The five people are: Gretchen, Dawn, Buchanan, the person who sleeps with his or her computer screen lit, and the person who always keeps a phone near the bed for security. \n\r\n4. Weatherton (who isn't Dawn) and the person who sleeps with a night-light are members of the opposite sex.\n\r\n5. Neither John nor Stephanie sleeps with the hall light on.\n\r\n6. Dawn isn't the person who pulls down the shades at night.\n\r\n7. The person who sleeps with the overhead light on (who is surnamed either Foster or Young) doesn't find it necessary to keep a phone by the bed.\n\r\n8. Mr. Upgraff routinely closes the door to his closet, lest the creepy things that lurk within emerge while he sleeps.\n\r\n9. Buchanan doesn't sleep with the Winnie-the-Pooh night-light.\n\r\n10. Young sleeps with either a desk light or the overhead light lit.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDonald Weatherton, hall light, phone\r\nGretchen Young, overhead light, shades\r\nJohn Upgraff, computer screen, closet\r\nDawn Foster, night-light, locks\r\nStephanie Buchanan, desk lamp, checks under bed\n<|im_start|>answer\nDonald Weatherton, hall light, phone\r\nGretchen Young, overhead light, shades\r\nJohn Upgraff, computer screen, closet\r\nDawn Foster, night-light, locks\r\nStephanie Buchanan, desk lamp, checks under bed\n<|im_end|>" }, { "id": "#24178", "title": "A Day of Shopping", "fun": 3.12, "difficulty": 2.9, "author": "ragsdaleam", "desc": "The Springview Mall had its annual Big Sale last Friday. Five girls skipped school to go shopping together. Each of the girls bought one item on sale for less than the regular price. Find out each girl's last name, item bought, the sale price she paid, and what the regular price of her item was.\n\r\n1. Beth Jones didn't buy the shoes. The girl who bought the skirt spent half of the regular price. Terry spent $25 on her item.\n\r\n2. Sarah was not the girl who spent $35 on an item that was regularly priced at $45. Miss Turner, whose first name isn't Jennifer, didn't buy the jeans.\n\r\n3. Molly spent more money than the girl who bought the necklace, but her item's regular price was $10 less than Miss Smith's.\n\r\n4. The person who bought the jeans had a regular price that was higher than Miss Anderson, but lower than the girl who bought the purse.\n\r\n5. Sarah's last name wasn't Smith. Miss Welch didn't spend $40, but the regular price of her item was $15 more than the sale price. The person who bought the necklace spent $30, but it wasn't Sarah.\n\r\n6. The five girls were Molly, the girl who spent $50, the person who bought the jeans, the girl whose item regularly cost $60, and Miss Anderson.", "hint": "Create a table based on the 6th clue. Work with it and the grid.", "answer": "Beth Jones, necklace, $30, $60\r\nJennifer Smith, jeans, $40, $55\r\nMolly Turner, shoes, $35, $45\r\nSarah Welch purse $50, $65\r\nTerry Anderson, skirt, $25, $50", "category": "Logic-Grid", "date": "07/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Springview Mall had its annual Big Sale last Friday. Five girls skipped school to go shopping together. Each of the girls bought one item on sale for less than the regular price. Find out each girl's last name, item bought, the sale price she paid, and what the regular price of her item was.\n\r\n1. Beth Jones didn't buy the shoes. The girl who bought the skirt spent half of the regular price. Terry spent $25 on her item.\n\r\n2. Sarah was not the girl who spent $35 on an item that was regularly priced at $45. Miss Turner, whose first name isn't Jennifer, didn't buy the jeans.\n\r\n3. Molly spent more money than the girl who bought the necklace, but her item's regular price was $10 less than Miss Smith's.\n\r\n4. The person who bought the jeans had a regular price that was higher than Miss Anderson, but lower than the girl who bought the purse.\n\r\n5. Sarah's last name wasn't Smith. Miss Welch didn't spend $40, but the regular price of her item was $15 more than the sale price. The person who bought the necklace spent $30, but it wasn't Sarah.\n\r\n6. The five girls were Molly, the girl who spent $50, the person who bought the jeans, the girl whose item regularly cost $60, and Miss Anderson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeth Jones, necklace, $30, $60\r\nJennifer Smith, jeans, $40, $55\r\nMolly Turner, shoes, $35, $45\r\nSarah Welch purse $50, $65\r\nTerry Anderson, skirt, $25, $50\n<|im_start|>answer\nBeth Jones, necklace, $30, $60\r\nJennifer Smith, jeans, $40, $55\r\nMolly Turner, shoes, $35, $45\r\nSarah Welch purse $50, $65\r\nTerry Anderson, skirt, $25, $50\n<|im_end|>" }, { "id": "#39889", "title": "Hospital Hullabaloo", "fun": 3.11, "difficulty": 2.32, "author": "psychogrrl", "desc": "Oh no!! The charge nurse accidentally shredded the patient assignment list for the nurses at General Hospital. Use the clues to determine each nurse's first and last name, their patient's first name, age, and health condition. \r\nNurse first names: Molly, James, John, Linda, Rose\n\r\nNurse last names: Smith, Ash, Silva, Jacks, Jones\n\r\nPatient ages: 68, 15, 28, 31, 45\n\r\nPatient conditions: broken leg, heart attack, coma, pneumonia, cancer.\n\r\nPatient names: Mark, Emily, Liz, Andrew, Mindy\n\n\r\nEmily is 31 years old.\n\r\nThe five nurses are: Miss Ash, the one caring for the coma patient, Rose, the man taking care of the 68 year old patient, and James Silva. \n\r\nThe five patients are: the 45 year old female cardiac patient, the cancer patient, Mindy, the 15 year old coma patient, and the female pneumonia patient who graduated high school about 12 years ago.\n\r\nLiz is younger than Mr. Jones' cancer patient but older than Andrew.\n\r\nMiss Ash's patient has pneumonia. \n\r\nSmith's patient, Mindy, is younger than the cardiac patient, but older than Molly's pediatric patient.", "hint": "Average age for graduating high school is 18.\n\r\nCardiac refers to the heart.", "answer": "Molly Jacks is taking care of 15 year old coma patient, Andrew.\n\r\nJames Silva is taking care of 45 year old heart attack patient, Liz. \n\r\nJohn Jones is taking care of 68 year old cancer patient, Mark. \n\r\nLinda Ash is taking care of 31 year old pneumonia patient, Emily.\n\r\nRose Smith is taking care of 28 year old broken leg patient, Mindy.", "category": "Logic-Grid", "date": "01/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOh no!! The charge nurse accidentally shredded the patient assignment list for the nurses at General Hospital. Use the clues to determine each nurse's first and last name, their patient's first name, age, and health condition. \r\nNurse first names: Molly, James, John, Linda, Rose\n\r\nNurse last names: Smith, Ash, Silva, Jacks, Jones\n\r\nPatient ages: 68, 15, 28, 31, 45\n\r\nPatient conditions: broken leg, heart attack, coma, pneumonia, cancer.\n\r\nPatient names: Mark, Emily, Liz, Andrew, Mindy\n\n\r\nEmily is 31 years old.\n\r\nThe five nurses are: Miss Ash, the one caring for the coma patient, Rose, the man taking care of the 68 year old patient, and James Silva. \n\r\nThe five patients are: the 45 year old female cardiac patient, the cancer patient, Mindy, the 15 year old coma patient, and the female pneumonia patient who graduated high school about 12 years ago.\n\r\nLiz is younger than Mr. Jones' cancer patient but older than Andrew.\n\r\nMiss Ash's patient has pneumonia. \n\r\nSmith's patient, Mindy, is younger than the cardiac patient, but older than Molly's pediatric patient.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMolly Jacks is taking care of 15 year old coma patient, Andrew.\n\r\nJames Silva is taking care of 45 year old heart attack patient, Liz. \n\r\nJohn Jones is taking care of 68 year old cancer patient, Mark. \n\r\nLinda Ash is taking care of 31 year old pneumonia patient, Emily.\n\r\nRose Smith is taking care of 28 year old broken leg patient, Mindy.\n<|im_start|>answer\nMolly Jacks is taking care of 15 year old coma patient, Andrew.\n\r\nJames Silva is taking care of 45 year old heart attack patient, Liz. \n\r\nJohn Jones is taking care of 68 year old cancer patient, Mark. \n\r\nLinda Ash is taking care of 31 year old pneumonia patient, Emily.\n\r\nRose Smith is taking care of 28 year old broken leg patient, Mindy.\n<|im_end|>" }, { "id": "#28190", "title": "Runaways", "fun": 3.11, "difficulty": 1.78, "author": "harmonize9", "desc": "Oh no! All of the dogs on Lexington Avenue have run away from home. The owners quickly made police reports and luckily all the dogs were found. But the poor officers mixed up the paper work and can't figure out who owns which dog, where they were found, and in what order. They are in great need of help. Can you figure it out?\n\r\nOwners: Sam, Bailey, Chase, Joel, Paige\r\nDogs: Spot, Wiggles, Butch, Roscoe, Heinz\r\nLocations: Park, Neighbor, Pound, Parking lot, Restaurant\r\nOrder: First, Second, Third, Fourth, Fifth\n\n\r\n1. Heinz's owner knew exactly where to find his dog, in front of the restaurant where he discovered Heinz as a puppy. That's why Heinz was safe in bed first.\r\n2. The 5 dogs are: Wiggles, Joel's dog, the dog in the parking lot, Chase's dog, and the last dog found.\r\n3. Only one owner shares the same initials as his/her dog.\r\n4. Butch was found before the dog in the pound but after Sam's dog.\r\n5. Chase found his dog after Paige.\r\n6. Spot was found 2nd.\r\n7. Paige was so happy when her neighbor brought Wiggles home.", "hint": "No hint available.", "answer": "1) Sam, Spot, Parking Lot, 2nd\r\n2) Bailey, Roscoe, Pound, 5th\r\n3) Chase, Butch, Park, 4th\r\n4) Joel, Heinz, Restaurant, 1st\r\n5) Paige, Wiggles, Neighbor, 3rd", "category": "Logic-Grid", "date": "01/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOh no! All of the dogs on Lexington Avenue have run away from home. The owners quickly made police reports and luckily all the dogs were found. But the poor officers mixed up the paper work and can't figure out who owns which dog, where they were found, and in what order. They are in great need of help. Can you figure it out?\n\r\nOwners: Sam, Bailey, Chase, Joel, Paige\r\nDogs: Spot, Wiggles, Butch, Roscoe, Heinz\r\nLocations: Park, Neighbor, Pound, Parking lot, Restaurant\r\nOrder: First, Second, Third, Fourth, Fifth\n\n\r\n1. Heinz's owner knew exactly where to find his dog, in front of the restaurant where he discovered Heinz as a puppy. That's why Heinz was safe in bed first.\r\n2. The 5 dogs are: Wiggles, Joel's dog, the dog in the parking lot, Chase's dog, and the last dog found.\r\n3. Only one owner shares the same initials as his/her dog.\r\n4. Butch was found before the dog in the pound but after Sam's dog.\r\n5. Chase found his dog after Paige.\r\n6. Spot was found 2nd.\r\n7. Paige was so happy when her neighbor brought Wiggles home.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Sam, Spot, Parking Lot, 2nd\r\n2) Bailey, Roscoe, Pound, 5th\r\n3) Chase, Butch, Park, 4th\r\n4) Joel, Heinz, Restaurant, 1st\r\n5) Paige, Wiggles, Neighbor, 3rd\n<|im_start|>answer\n1) Sam, Spot, Parking Lot, 2nd\r\n2) Bailey, Roscoe, Pound, 5th\r\n3) Chase, Butch, Park, 4th\r\n4) Joel, Heinz, Restaurant, 1st\r\n5) Paige, Wiggles, Neighbor, 3rd\n<|im_end|>" }, { "id": "#38852", "title": "Most Romantic", "fun": 3.11, "difficulty": 2.01, "author": "jppbl", "desc": "Last night during their weekly poker game, five men (Brad, John, Mitch, Paul, and Ron) were bragging about how romantic they were. In order to decide who was the best husband, they planned to take their wives on a special date this Friday night, including dinner, flowers, and a movie. Can you figure out the name of each wife, where the couple went for dinner, the flowers she received, and the movie they saw?\r\nThe wives are: Belinda, Jessica, Monica, Penelope, and Robyn\r\nThe flowers are: Daisies, Pansies, Roses, Sunflowers, and Tulips\r\nThe restaurants are: Bella Notte (Italian), Cowhide (Steak), Juan's (Mexican), OoLaLa (French), and Wok In and Out (Chinese)\r\nThe movies are: Gone in 20 Seconds (a movie about car thieves), Lonely Canary (a western), The Journal (a romance), Pretty Lady (a romantic comedy), and Shriek (a horror movie).\n\r\n1. John, who didn't take out Belinda (who went to Bella Notte, but not with Ron or Mitch), had to turn on all the lights and check under the bed for killers before his wife would come inside the house and put the tulips in a vase.\r\n2. The couple that dined at Cowhide did not see \"The Journal\" or \"Gone in 20 Seconds\".\r\n3. Penelope, who didn't get pansies, loved the car movie her husband took her to (he wasn't Paul, who gave roses to his \"Pretty Lady\").\r\n4. Robyn did not get roses, but she found a romantic message in her eggroll, which wasn't from Ron. \r\n5. The couple that went to Juan's enjoyed the daisies, but they did not see \"The Journal\".\r\n6. Monica got sunflowers from her husband.\r\n7. Mitch and his wife filled up on tacos before their movie.\r\n8. Jessica, who was not married to Brad (who gave pansies to his wife), went to OoLaLa.\r\n9. Robyn's husband wanted to see \"Shriek\", the new slasher film, but she insisted on a more romantic movie.", "hint": "No hint available.", "answer": "Brad, Robyn, Pansies, Wok In and Out, \"The Journal\"\r\nJohn, Jessica, Tulips, OoLaLa, \"Shriek\"\r\nMitch, Penelope, Daisies, Juan's, \"Gone in 20 Seconds\"\r\nPaul, Belinda, Roses, Bella Notte, \"Pretty Lady\"\r\nRon, Monica, Sunflowers, Cowhide, \"Lonely Canary\"", "category": "Logic-Grid", "date": "10/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast night during their weekly poker game, five men (Brad, John, Mitch, Paul, and Ron) were bragging about how romantic they were. In order to decide who was the best husband, they planned to take their wives on a special date this Friday night, including dinner, flowers, and a movie. Can you figure out the name of each wife, where the couple went for dinner, the flowers she received, and the movie they saw?\r\nThe wives are: Belinda, Jessica, Monica, Penelope, and Robyn\r\nThe flowers are: Daisies, Pansies, Roses, Sunflowers, and Tulips\r\nThe restaurants are: Bella Notte (Italian), Cowhide (Steak), Juan's (Mexican), OoLaLa (French), and Wok In and Out (Chinese)\r\nThe movies are: Gone in 20 Seconds (a movie about car thieves), Lonely Canary (a western), The Journal (a romance), Pretty Lady (a romantic comedy), and Shriek (a horror movie).\n\r\n1. John, who didn't take out Belinda (who went to Bella Notte, but not with Ron or Mitch), had to turn on all the lights and check under the bed for killers before his wife would come inside the house and put the tulips in a vase.\r\n2. The couple that dined at Cowhide did not see \"The Journal\" or \"Gone in 20 Seconds\".\r\n3. Penelope, who didn't get pansies, loved the car movie her husband took her to (he wasn't Paul, who gave roses to his \"Pretty Lady\").\r\n4. Robyn did not get roses, but she found a romantic message in her eggroll, which wasn't from Ron. \r\n5. The couple that went to Juan's enjoyed the daisies, but they did not see \"The Journal\".\r\n6. Monica got sunflowers from her husband.\r\n7. Mitch and his wife filled up on tacos before their movie.\r\n8. Jessica, who was not married to Brad (who gave pansies to his wife), went to OoLaLa.\r\n9. Robyn's husband wanted to see \"Shriek\", the new slasher film, but she insisted on a more romantic movie.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrad, Robyn, Pansies, Wok In and Out, \"The Journal\"\r\nJohn, Jessica, Tulips, OoLaLa, \"Shriek\"\r\nMitch, Penelope, Daisies, Juan's, \"Gone in 20 Seconds\"\r\nPaul, Belinda, Roses, Bella Notte, \"Pretty Lady\"\r\nRon, Monica, Sunflowers, Cowhide, \"Lonely Canary\"\n<|im_start|>answer\nBrad, Robyn, Pansies, Wok In and Out, \"The Journal\"\r\nJohn, Jessica, Tulips, OoLaLa, \"Shriek\"\r\nMitch, Penelope, Daisies, Juan's, \"Gone in 20 Seconds\"\r\nPaul, Belinda, Roses, Bella Notte, \"Pretty Lady\"\r\nRon, Monica, Sunflowers, Cowhide, \"Lonely Canary\"\n<|im_end|>" }, { "id": "#52441", "title": "Cats Have 9 Squares", "fun": 3.11, "difficulty": 1.92, "author": "Rove_Tarts", "desc": "9 cats Andar, Balak, Collo, Erec, Indan, Kyft, Meva, Qupuwu, & Yitsim are positioned in a 3 by 3 grid; you know 3 things about them:\n\r\n1. Balak, the leader, always sits in the top left.\r\n2. Erec, the kitten, never sits in the top row.\r\n3. None of the adjacent cats (even diagonal) share a single letter.\n\r\nWhere are they positioned?", "hint": "Meva is in a corner.", "answer": "Balak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\nIndan; Kyft; Meva\n\r\nSteps:\n\r\n1. Qupuwu is the only one to share no letters, therefore they must be in the middle.\r\n2. The only 2 to not share a letter with Balak are Yitsim & Erec; Erec cannot be in the top row, so Erec is below Balak & Yitsim is beside.\n\r\nBalak; Yitsim; ????\r\nErec; Qupuwu; ????\r\n????; ????; ????\n\r\n3. Since there are 4 \"A\" names, they must go in the corners. The remaining \"A\" names are Andar, Indan, & Meva. For the corner next to Yitsim only Andar can go there because of Indan's \"I\" and Meva's \"M\".\r\n4. The remaining name to not share a letter with Yitsim is Collo, so they go below Andar.\n\r\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\n????; ????; ????\n\r\n5. Kyft must go in the center of the last row because of the previously mentioned 4 \"A\"s.\r\n6. Meva & Erec can not be next to each other so Indan is below Erec & Meva is below Collo.\n\r\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\nIndan; Kyft; Meva", "category": "Logic", "date": "08/14/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n9 cats Andar, Balak, Collo, Erec, Indan, Kyft, Meva, Qupuwu, & Yitsim are positioned in a 3 by 3 grid; you know 3 things about them:\n\r\n1. Balak, the leader, always sits in the top left.\r\n2. Erec, the kitten, never sits in the top row.\r\n3. None of the adjacent cats (even diagonal) share a single letter.\n\r\nWhere are they positioned?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\nIndan; Kyft; Meva\n\r\nSteps:\n\r\n1. Qupuwu is the only one to share no letters, therefore they must be in the middle.\r\n2. The only 2 to not share a letter with Balak are Yitsim & Erec; Erec cannot be in the top row, so Erec is below Balak & Yitsim is beside.\n\r\nBalak; Yitsim; ????\r\nErec; Qupuwu; ????\r\n????; ????; ????\n\r\n3. Since there are 4 \"A\" names, they must go in the corners. The remaining \"A\" names are Andar, Indan, & Meva. For the corner next to Yitsim only Andar can go there because of Indan's \"I\" and Meva's \"M\".\r\n4. The remaining name to not share a letter with Yitsim is Collo, so they go below Andar.\n\r\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\n????; ????; ????\n\r\n5. Kyft must go in the center of the last row because of the previously mentioned 4 \"A\"s.\r\n6. Meva & Erec can not be next to each other so Indan is below Erec & Meva is below Collo.\n\r\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\nIndan; Kyft; Meva\n<|im_start|>answer\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\nIndan; Kyft; Meva\n\r\nSteps:\n\r\n1. Qupuwu is the only one to share no letters, therefore they must be in the middle.\r\n2. The only 2 to not share a letter with Balak are Yitsim & Erec; Erec cannot be in the top row, so Erec is below Balak & Yitsim is beside.\n\r\nBalak; Yitsim; ????\r\nErec; Qupuwu; ????\r\n????; ????; ????\n\r\n3. Since there are 4 \"A\" names, they must go in the corners. The remaining \"A\" names are Andar, Indan, & Meva. For the corner next to Yitsim only Andar can go there because of Indan's \"I\" and Meva's \"M\".\r\n4. The remaining name to not share a letter with Yitsim is Collo, so they go below Andar.\n\r\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\n????; ????; ????\n\r\n5. Kyft must go in the center of the last row because of the previously mentioned 4 \"A\"s.\r\n6. Meva & Erec can not be next to each other so Indan is below Erec & Meva is below Collo.\n\r\nBalak; Yitsim; Andar\r\nErec; Qupuwu; Collo\r\nIndan; Kyft; Meva\n<|im_end|>" }, { "id": "#27020", "title": "Thanksgiving Calamity", "fun": 3.11, "difficulty": 2.99, "author": "Splatt", "desc": "It was an odd holiday, yessiree... The Sewtnof siblings planned a potluck Thanksgiving dinner at one of their houses, however, none could cook well. Each planned to make two items. Four of them had dramas causing them to be late. All in all, it was the start of a rough holiday and everyone was in a sour mood, but once they discovered what their meal would be, they giggled at life's irony and got over themselves.\n\r\nEach ruined one of their recipes and successfully prepared one. Determine what the Sewtnofs finally ended up with for dinner, who made what, who ruined what, why each was late (or on time), and where each was in the age lineup.\n\r\nSiblings: Johanna, Emily, Jacob, Ali, Rosie\n\r\nAge range: Oldest, 24, 21, 19, 17 \n\r\nRecipes attempted: Turkey, Pumpkin Pie, Buns, Gravy,\r\nStuffing, Green Salad, Green Beans, Cranberry Sauce, Apple Pie, Mashed Potatoes\n\r\nCalamities: Overslept, Ran out of gas/petrol, Had to run to store for one last ingredient, Argument with boyfriend\n\r\n1.\tJohanna did not burn her buns because she didn't bake any. She did bake a pie, however.\r\n2.\tJacob turned off the oven and left his bird half cooked at home, hoping to be not too late. His other item required no heat to prepare, thankfully.\r\n3.\tYou might think the Sewtnof parents would stop having kids once they had a boy, but no, they went on to have one more child.\r\n4.\tBeing the host doesn't automatically ensure timeliness; also, the gardener was a very early riser, allowing her plenty of time to ruin one item, & successfully prepare another on time.\r\n5.\tSad she burnt her buns, Emily's sister was extra careful to make sure her cranberry sauce turned out okay.\r\n6.\tThe sister who didn't make stuffing hosted the dinner, because she's the only one with a big enough table. Johanna, her younger sister, was not the host.\r\n7.\tWhat a day for Ali's little sister! Not only did her stuffing take forever to come out right, but she had to run to the store at the last minute to ensure her pie had fruit in it!\r\n8.\tRosie, who was not the youngest, was not the family gardener who grew main ingredients for both of her food attempts. \r\n9.\tWhen the first arrival showed with pumpkin pie, the host was still in the shower because she had overslept.\r\n10.\tThe middle child was late because her boyfriend argued that he didn't feel like driving.\r\n11.\tJacob did not stop at the store; Ali didn't attempt to cook green beans, but the person who did, also ruined her gravy.\r\n12.\tThe person who attempted cranberry sauce did not grow the cranberries.\r\n13.\tThe gardener grows root vegetables and squash, but not fruit.\r\n14.\tEmily is older and younger than at least one other sibling, and Ali is not the middle child. \r\n15.\tThe one who overslept is older than Emily, and the teenagers' names both start with the same letter.\r\n16.\tThe five are the person whose gravy was too salty to bring, Emily who did not have any arguments, Jacob, the host, and the person whose stuffing was delicious.", "hint": "Jacob is the only male. Don't assume that one food grid is all ruined items. Potatoes are root vegetables and pumpkins are squash.", "answer": "The strange Thanksgiving dinner consisted of: Stuffing, Green Beans, Cranberry Sauce, Pumpkin Pie, and Salad\n\r\nJohanna made stuffing, ruined apple pie, store, 17\r\nEmily made pumpkin pie, ruined potatoes, was on time because she's an early riser (gardener), 24\r\nJacob ruined turkey, made salad, ran out of gas/petrol, 19\r\nAli ruined buns, made cranberry sauce, overslept (host), oldest\r\nRosie ruined gravy, made green beans, argued with her boyfriend, 21", "category": "Logic-Grid", "date": "11/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was an odd holiday, yessiree... The Sewtnof siblings planned a potluck Thanksgiving dinner at one of their houses, however, none could cook well. Each planned to make two items. Four of them had dramas causing them to be late. All in all, it was the start of a rough holiday and everyone was in a sour mood, but once they discovered what their meal would be, they giggled at life's irony and got over themselves.\n\r\nEach ruined one of their recipes and successfully prepared one. Determine what the Sewtnofs finally ended up with for dinner, who made what, who ruined what, why each was late (or on time), and where each was in the age lineup.\n\r\nSiblings: Johanna, Emily, Jacob, Ali, Rosie\n\r\nAge range: Oldest, 24, 21, 19, 17 \n\r\nRecipes attempted: Turkey, Pumpkin Pie, Buns, Gravy,\r\nStuffing, Green Salad, Green Beans, Cranberry Sauce, Apple Pie, Mashed Potatoes\n\r\nCalamities: Overslept, Ran out of gas/petrol, Had to run to store for one last ingredient, Argument with boyfriend\n\r\n1.\tJohanna did not burn her buns because she didn't bake any. She did bake a pie, however.\r\n2.\tJacob turned off the oven and left his bird half cooked at home, hoping to be not too late. His other item required no heat to prepare, thankfully.\r\n3.\tYou might think the Sewtnof parents would stop having kids once they had a boy, but no, they went on to have one more child.\r\n4.\tBeing the host doesn't automatically ensure timeliness; also, the gardener was a very early riser, allowing her plenty of time to ruin one item, & successfully prepare another on time.\r\n5.\tSad she burnt her buns, Emily's sister was extra careful to make sure her cranberry sauce turned out okay.\r\n6.\tThe sister who didn't make stuffing hosted the dinner, because she's the only one with a big enough table. Johanna, her younger sister, was not the host.\r\n7.\tWhat a day for Ali's little sister! Not only did her stuffing take forever to come out right, but she had to run to the store at the last minute to ensure her pie had fruit in it!\r\n8.\tRosie, who was not the youngest, was not the family gardener who grew main ingredients for both of her food attempts. \r\n9.\tWhen the first arrival showed with pumpkin pie, the host was still in the shower because she had overslept.\r\n10.\tThe middle child was late because her boyfriend argued that he didn't feel like driving.\r\n11.\tJacob did not stop at the store; Ali didn't attempt to cook green beans, but the person who did, also ruined her gravy.\r\n12.\tThe person who attempted cranberry sauce did not grow the cranberries.\r\n13.\tThe gardener grows root vegetables and squash, but not fruit.\r\n14.\tEmily is older and younger than at least one other sibling, and Ali is not the middle child. \r\n15.\tThe one who overslept is older than Emily, and the teenagers' names both start with the same letter.\r\n16.\tThe five are the person whose gravy was too salty to bring, Emily who did not have any arguments, Jacob, the host, and the person whose stuffing was delicious.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe strange Thanksgiving dinner consisted of: Stuffing, Green Beans, Cranberry Sauce, Pumpkin Pie, and Salad\n\r\nJohanna made stuffing, ruined apple pie, store, 17\r\nEmily made pumpkin pie, ruined potatoes, was on time because she's an early riser (gardener), 24\r\nJacob ruined turkey, made salad, ran out of gas/petrol, 19\r\nAli ruined buns, made cranberry sauce, overslept (host), oldest\r\nRosie ruined gravy, made green beans, argued with her boyfriend, 21\n<|im_start|>answer\nThe strange Thanksgiving dinner consisted of: Stuffing, Green Beans, Cranberry Sauce, Pumpkin Pie, and Salad\n\r\nJohanna made stuffing, ruined apple pie, store, 17\r\nEmily made pumpkin pie, ruined potatoes, was on time because she's an early riser (gardener), 24\r\nJacob ruined turkey, made salad, ran out of gas/petrol, 19\r\nAli ruined buns, made cranberry sauce, overslept (host), oldest\r\nRosie ruined gravy, made green beans, argued with her boyfriend, 21\n<|im_end|>" }, { "id": "#38905", "title": "Hatching Dragons", "fun": 3.11, "difficulty": 2.32, "author": "dreamlvr1432", "desc": "In Tyria, 5 dragon eggs are about to hatch, and people from all over the land have gathered for the big event. After hatching, each dragon sought out a human companion from the crowd, with whom they would form a lifelong bond. No 2 dragons are the same color, and each human chosen lives in a different village. From the clues below, can you determine the name, color and hatching order of each dragon, as well as the name and village of their chosen companions?\n\r\n1) The dragon that will reside in Cranston hatched before Krale and after the one that bonded with Ahren.\n\r\n2) Evan (who is not from Greystone) was not chosen by Zuria, nor was he chosen by the green dragon.\n\r\n3) Azazeal (who did not hatch 4th) hatched before the red dragon, but after the bronze (who did not choose Raven).\n\r\n4) No dragon chose a human whose name begins with the same letter as their own. On the same note, no dragon's name begins with the same letter as their color.\n\r\n5) The dragons hatched in the following order: Bael, the one whose companion is from Cairn, the blue dragon, the purple dragon, and the one who chose Jaron.\n\r\n6) Jaabel did not choose Brandon (who isn't from Summerhaven), or Raven (who isn't from Shadowbrook).\n\r\n7) Raven of Summerhaven was honored to have been chosen by Azazeal.\n\r\n8) Jaabel hatched before the dragon that bonded with Brandon and after the one that will go to Shadowbrook with Ahren.", "hint": "No hint available.", "answer": "Answers are listed in order of hatching:\n\r\n1) Bael, green, Ahren, Shadowbrook\r\n2) Jaabel, bronze, Evan, Cairn\r\n3) Azazeal, blue, Raven, Summerhaven\r\n4) Zuria, purple, Brandon, Cranston\r\n5) Krale, red, Jaron, Greystone", "category": "Logic-Grid", "date": "10/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Tyria, 5 dragon eggs are about to hatch, and people from all over the land have gathered for the big event. After hatching, each dragon sought out a human companion from the crowd, with whom they would form a lifelong bond. No 2 dragons are the same color, and each human chosen lives in a different village. From the clues below, can you determine the name, color and hatching order of each dragon, as well as the name and village of their chosen companions?\n\r\n1) The dragon that will reside in Cranston hatched before Krale and after the one that bonded with Ahren.\n\r\n2) Evan (who is not from Greystone) was not chosen by Zuria, nor was he chosen by the green dragon.\n\r\n3) Azazeal (who did not hatch 4th) hatched before the red dragon, but after the bronze (who did not choose Raven).\n\r\n4) No dragon chose a human whose name begins with the same letter as their own. On the same note, no dragon's name begins with the same letter as their color.\n\r\n5) The dragons hatched in the following order: Bael, the one whose companion is from Cairn, the blue dragon, the purple dragon, and the one who chose Jaron.\n\r\n6) Jaabel did not choose Brandon (who isn't from Summerhaven), or Raven (who isn't from Shadowbrook).\n\r\n7) Raven of Summerhaven was honored to have been chosen by Azazeal.\n\r\n8) Jaabel hatched before the dragon that bonded with Brandon and after the one that will go to Shadowbrook with Ahren.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswers are listed in order of hatching:\n\r\n1) Bael, green, Ahren, Shadowbrook\r\n2) Jaabel, bronze, Evan, Cairn\r\n3) Azazeal, blue, Raven, Summerhaven\r\n4) Zuria, purple, Brandon, Cranston\r\n5) Krale, red, Jaron, Greystone\n<|im_start|>answer\nAnswers are listed in order of hatching:\n\r\n1) Bael, green, Ahren, Shadowbrook\r\n2) Jaabel, bronze, Evan, Cairn\r\n3) Azazeal, blue, Raven, Summerhaven\r\n4) Zuria, purple, Brandon, Cranston\r\n5) Krale, red, Jaron, Greystone\n<|im_end|>" }, { "id": "#26603", "title": "A Trip to the Zoo", "fun": 3.1, "difficulty": 2.09, "author": "Rob2003", "desc": "One day, five mothers each brought their only child to the zoo. The children had a glorious time together watching the different animals and eating their favorite snacks. The kids were so good, at the end of the day each mother let her child get one item from the souvenir shop as they were leaving the zoo. Can you determine the full name of each child, each child's favorite snack and animal, and the souvenir each brought home?\n\r\n1. Julia, who loves cotton candy, didn't like the elephants. Mary didn't get a caramel apple. The child who got the stuffed animal liked the giraffes best.\n\r\n2. Alan Rivera, the girl who liked the lions, and the child who got the activity set didn't want to leave the zoo.\n\r\n3. Neither of the boys got fried dough, but one got nachos and the other one liked the monkeys best. Tom didn't get a poster.\n\r\n4. The Gomez child almost got a coloring book with Mary but finally decided on a poster.\n\r\n5. Tom, whose last name isn't Lozada, got a toy gun but didn't get a caramel apple. The Rodriguez child had fried dough.\n\r\n6. Beth, who didn't like the giraffes or the elephants best, got an activity set.", "hint": "No hint available.", "answer": "Alan Rivera: nachos, giraffes, stuffed animal\r\nBeth Lozada: caramel apple, seals, activity set\r\nJulia Gomez: cotton candy, lions, poster\r\nMary Rodriguez: fried dough, elephants, coloring book\r\nTom Gonzalez: popcorn, monkeys, toy gun", "category": "Logic-Grid", "date": "10/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, five mothers each brought their only child to the zoo. The children had a glorious time together watching the different animals and eating their favorite snacks. The kids were so good, at the end of the day each mother let her child get one item from the souvenir shop as they were leaving the zoo. Can you determine the full name of each child, each child's favorite snack and animal, and the souvenir each brought home?\n\r\n1. Julia, who loves cotton candy, didn't like the elephants. Mary didn't get a caramel apple. The child who got the stuffed animal liked the giraffes best.\n\r\n2. Alan Rivera, the girl who liked the lions, and the child who got the activity set didn't want to leave the zoo.\n\r\n3. Neither of the boys got fried dough, but one got nachos and the other one liked the monkeys best. Tom didn't get a poster.\n\r\n4. The Gomez child almost got a coloring book with Mary but finally decided on a poster.\n\r\n5. Tom, whose last name isn't Lozada, got a toy gun but didn't get a caramel apple. The Rodriguez child had fried dough.\n\r\n6. Beth, who didn't like the giraffes or the elephants best, got an activity set.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlan Rivera: nachos, giraffes, stuffed animal\r\nBeth Lozada: caramel apple, seals, activity set\r\nJulia Gomez: cotton candy, lions, poster\r\nMary Rodriguez: fried dough, elephants, coloring book\r\nTom Gonzalez: popcorn, monkeys, toy gun\n<|im_start|>answer\nAlan Rivera: nachos, giraffes, stuffed animal\r\nBeth Lozada: caramel apple, seals, activity set\r\nJulia Gomez: cotton candy, lions, poster\r\nMary Rodriguez: fried dough, elephants, coloring book\r\nTom Gonzalez: popcorn, monkeys, toy gun\n<|im_end|>" }, { "id": "#52606", "title": "Different Equals", "fun": 3.1, "difficulty": 1.28, "author": "Rove_Tarts", "desc": "Can you share 1/4 of a pie, 1/3 of a pie, 1/2 of a pie, 2/3 of a pie, 3/4 of a pie, and a whole pie so that two people have the same amount of pie without making any cuts?\n\r\nIf so, how?", "hint": "No hint available.", "answer": "Yes; 1/3 + 2/3 + 1/4 + 1/2 = 1 + 3/4 \r\n(Alternately 1/3 + 2/3 + 3/4 = 1 + 1/4 + 1/2)", "category": "Math", "date": "02/16/21", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you share 1/4 of a pie, 1/3 of a pie, 1/2 of a pie, 2/3 of a pie, 3/4 of a pie, and a whole pie so that two people have the same amount of pie without making any cuts?\n\r\nIf so, how?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes; 1/3 + 2/3 + 1/4 + 1/2 = 1 + 3/4 \r\n(Alternately 1/3 + 2/3 + 3/4 = 1 + 1/4 + 1/2)\n<|im_start|>answer\nYes; 1/3 + 2/3 + 1/4 + 1/2 = 1 + 3/4 \r\n(Alternately 1/3 + 2/3 + 3/4 = 1 + 1/4 + 1/2)\n<|im_end|>" }, { "id": "#32443", "title": "The Scrapbookers", "fun": 3.1, "difficulty": 2.27, "author": "jenb2144", "desc": "Five avid scrapbookers from Forest Hill get together every weekend to swap page ideas and discuss the progress that they have made on their scrapbooks during the week. Each scrapbooker lives on a different street, scrapbooks on a different night of the week and completed a different number of pages . Using the clues below, determine the first and last names of each scrapbooker, what street they live on, on which day they scrapbook and how many pages they have completed this week.\n\r\n1. Gordon finished one less page than the person who lives on Oak, but he finished 2 more pages than the person whose last name is Black.\r\n2. The girl who lives on Oak finished 4 pages.\r\n3. The person whose last name is Green scrapbooks on Thursdays.\r\n4. One person finished 2 pages on Monday.\r\n5. The person who scrapbooks on Tuesdays lives on Pine.\r\n6. Gordon, whose last name isn't Green, doesn't live on Evergreen.\r\n7. Mr. White doesn't scrapbook on Tuesdays.\r\n8. Barbara doesn't live on Elm Street.\r\n9. The person who lives on Pine did 5 pages, but not on Thursday.\r\n10. Hank lives on Maple, but he doesn't scrapbook on Wednesdays.\r\n11. Jason scrapbooks on Fridays.\r\n12. The five friends are, in no particular order, Alicia Brown, the person who lives on Maple, the person whose last names is Gray, the person who scrapbooks on Thursdays, and the guy who finished one page.", "hint": "No hint available.", "answer": "Alicia Brown lives on Pine Street and scrapbooked 5 pages on Tuesday.\r\nBarbara Green lives on Oak Street and scrapbooked 4 pages on Thursday.\r\nGordon Gray lives on Elm Street and scrapbooked 3 pages on Wednesday.\r\nHank White lives on Maple Street and scrapbooked 2 pages on Monday.\r\nJason Black lives on Evergreen and scrapbooked 1 page on Friday.", "category": "Logic-Grid", "date": "08/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive avid scrapbookers from Forest Hill get together every weekend to swap page ideas and discuss the progress that they have made on their scrapbooks during the week. Each scrapbooker lives on a different street, scrapbooks on a different night of the week and completed a different number of pages . Using the clues below, determine the first and last names of each scrapbooker, what street they live on, on which day they scrapbook and how many pages they have completed this week.\n\r\n1. Gordon finished one less page than the person who lives on Oak, but he finished 2 more pages than the person whose last name is Black.\r\n2. The girl who lives on Oak finished 4 pages.\r\n3. The person whose last name is Green scrapbooks on Thursdays.\r\n4. One person finished 2 pages on Monday.\r\n5. The person who scrapbooks on Tuesdays lives on Pine.\r\n6. Gordon, whose last name isn't Green, doesn't live on Evergreen.\r\n7. Mr. White doesn't scrapbook on Tuesdays.\r\n8. Barbara doesn't live on Elm Street.\r\n9. The person who lives on Pine did 5 pages, but not on Thursday.\r\n10. Hank lives on Maple, but he doesn't scrapbook on Wednesdays.\r\n11. Jason scrapbooks on Fridays.\r\n12. The five friends are, in no particular order, Alicia Brown, the person who lives on Maple, the person whose last names is Gray, the person who scrapbooks on Thursdays, and the guy who finished one page.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlicia Brown lives on Pine Street and scrapbooked 5 pages on Tuesday.\r\nBarbara Green lives on Oak Street and scrapbooked 4 pages on Thursday.\r\nGordon Gray lives on Elm Street and scrapbooked 3 pages on Wednesday.\r\nHank White lives on Maple Street and scrapbooked 2 pages on Monday.\r\nJason Black lives on Evergreen and scrapbooked 1 page on Friday.\n<|im_start|>answer\nAlicia Brown lives on Pine Street and scrapbooked 5 pages on Tuesday.\r\nBarbara Green lives on Oak Street and scrapbooked 4 pages on Thursday.\r\nGordon Gray lives on Elm Street and scrapbooked 3 pages on Wednesday.\r\nHank White lives on Maple Street and scrapbooked 2 pages on Monday.\r\nJason Black lives on Evergreen and scrapbooked 1 page on Friday.\n<|im_end|>" }, { "id": "#52014", "title": "Who Robbed the Bank?", "fun": 3.1, "difficulty": 1.46, "author": "wimpykidfan37", "desc": "The angry chief of police did roar,\r\n\"Who robbed the bank out of you four?\"\r\nWhen Al was asked, he said right then,\r\n\"The thief was Ben! The thief was Ben!\"\r\nBen said to the policin' man,\r\n\"The thief was Dan! The thief was Dan!\"\r\nWhen Carl was questioned, he exclaimed,\r\n\"I'm not the one who should be blamed!\"\r\nWhen Dan was questioned, he replied,\r\n\"When Ben said it was me, he lied!\"\n\r\nIf three of four suspects speak true,\r\nAnd one speaks false, then who oh who?\r\nAnd what if only one was frank?\r\nBut most of all, who robbed the bank?", "hint": "No hint available.", "answer": "If only one is lying, Ben robbed the bank.\r\nIf only one is telling the truth, Carl robbed the bank.\n\r\nSince Dan's statement was that Ben was lying, exactly one of these two must be telling the truth and the other must be lying. If Ben is telling the truth and Dan is lying, Dan must be the thief, which means that Al is lying and Carl is telling the truth. But now we have two truthtellers and two liars. So this cannot be right.\n\r\nTherefore, if there is only one liar, it must be Ben. Al can only be telling the truth if Ben was the robber. If there is only one truthteller, it must be Dan. Carl can only be lying if Carl was the robber.", "category": "Logic", "date": "11/19/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe angry chief of police did roar,\r\n\"Who robbed the bank out of you four?\"\r\nWhen Al was asked, he said right then,\r\n\"The thief was Ben! The thief was Ben!\"\r\nBen said to the policin' man,\r\n\"The thief was Dan! The thief was Dan!\"\r\nWhen Carl was questioned, he exclaimed,\r\n\"I'm not the one who should be blamed!\"\r\nWhen Dan was questioned, he replied,\r\n\"When Ben said it was me, he lied!\"\n\r\nIf three of four suspects speak true,\r\nAnd one speaks false, then who oh who?\r\nAnd what if only one was frank?\r\nBut most of all, who robbed the bank?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf only one is lying, Ben robbed the bank.\r\nIf only one is telling the truth, Carl robbed the bank.\n\r\nSince Dan's statement was that Ben was lying, exactly one of these two must be telling the truth and the other must be lying. If Ben is telling the truth and Dan is lying, Dan must be the thief, which means that Al is lying and Carl is telling the truth. But now we have two truthtellers and two liars. So this cannot be right.\n\r\nTherefore, if there is only one liar, it must be Ben. Al can only be telling the truth if Ben was the robber. If there is only one truthteller, it must be Dan. Carl can only be lying if Carl was the robber.\n<|im_start|>answer\nIf only one is lying, Ben robbed the bank.\r\nIf only one is telling the truth, Carl robbed the bank.\n\r\nSince Dan's statement was that Ben was lying, exactly one of these two must be telling the truth and the other must be lying. If Ben is telling the truth and Dan is lying, Dan must be the thief, which means that Al is lying and Carl is telling the truth. But now we have two truthtellers and two liars. So this cannot be right.\n\r\nTherefore, if there is only one liar, it must be Ben. Al can only be telling the truth if Ben was the robber. If there is only one truthteller, it must be Dan. Carl can only be lying if Carl was the robber.\n<|im_end|>" }, { "id": "#35800", "title": "Diet Time", "fun": 3.1, "difficulty": 1.93, "author": "Alegna", "desc": "Springtime is upon us, and that means that swimsuit weather is coming up quickly! April and four of her friends have all decided to go on a diet to see if they can lose a few unwanted pounds before they have to start trying on swimsuits. Each of the five friends has decided to give up their favorite snack food and to start exercising in order to lose weight. Each person wants to lose a different amount of weight. From the clues given, you will have to figure out how many pounds each person wants to lose, the snack food they are giving up, and the type of exercise they are adding in.\n\r\nFriends: Mable, Bob, Mike, April, and Sarah\r\nSnacks: Chocolate, Potato Chips, Ice Cream, Candy, and Pizza\r\nNumber of Pounds to Lose: 13, 20, 24, 27, and 34\r\nExercise: Treadmill, Yoga, Karate, Walking, and Boxing\n\n\r\n1. Sarah is trying to lose more pounds than the one who has given up candy, but fewer pounds then the one who has begun using the treadmill.\n\r\n2. Mable is trying to lose exactly 14 pounds fewer than the person walking.\n\r\n3. Bob (who is not the one taking Yoga) has stopped eating his afternoon bowl of ice cream. Bob is trying to lose exactly 7 pounds fewer than the boxer.\n\r\n4. Mike is trying to lose exactly 7 pounds fewer than the one who has given up Potato Chips.\n\r\n5. The woman who has given up chocolate isn't the one trying to lose 27 pounds.\n\r\n6. April knows that potato chips are a small sacrifice to make as she is trying to get into a bikini.\n\r\n7. The woman boxer has decided to give up candy to reach her goal.", "hint": "No hint available.", "answer": "They all reached their goal!\n\r\nMable gave up candy and started boxing to lose 20 pounds.\r\nBob gave up ice cream and took karate to lose 13 pounds.\r\nMike gave up pizza and started using the treadmill to lose 27 pounds.\r\nApril gave up potato chips and started walking to lose 34 pounds.\r\nSarah gave up chocolate and started doing yoga to lose 24 pounds.", "category": "Logic-Grid", "date": "03/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSpringtime is upon us, and that means that swimsuit weather is coming up quickly! April and four of her friends have all decided to go on a diet to see if they can lose a few unwanted pounds before they have to start trying on swimsuits. Each of the five friends has decided to give up their favorite snack food and to start exercising in order to lose weight. Each person wants to lose a different amount of weight. From the clues given, you will have to figure out how many pounds each person wants to lose, the snack food they are giving up, and the type of exercise they are adding in.\n\r\nFriends: Mable, Bob, Mike, April, and Sarah\r\nSnacks: Chocolate, Potato Chips, Ice Cream, Candy, and Pizza\r\nNumber of Pounds to Lose: 13, 20, 24, 27, and 34\r\nExercise: Treadmill, Yoga, Karate, Walking, and Boxing\n\n\r\n1. Sarah is trying to lose more pounds than the one who has given up candy, but fewer pounds then the one who has begun using the treadmill.\n\r\n2. Mable is trying to lose exactly 14 pounds fewer than the person walking.\n\r\n3. Bob (who is not the one taking Yoga) has stopped eating his afternoon bowl of ice cream. Bob is trying to lose exactly 7 pounds fewer than the boxer.\n\r\n4. Mike is trying to lose exactly 7 pounds fewer than the one who has given up Potato Chips.\n\r\n5. The woman who has given up chocolate isn't the one trying to lose 27 pounds.\n\r\n6. April knows that potato chips are a small sacrifice to make as she is trying to get into a bikini.\n\r\n7. The woman boxer has decided to give up candy to reach her goal.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey all reached their goal!\n\r\nMable gave up candy and started boxing to lose 20 pounds.\r\nBob gave up ice cream and took karate to lose 13 pounds.\r\nMike gave up pizza and started using the treadmill to lose 27 pounds.\r\nApril gave up potato chips and started walking to lose 34 pounds.\r\nSarah gave up chocolate and started doing yoga to lose 24 pounds.\n<|im_start|>answer\nThey all reached their goal!\n\r\nMable gave up candy and started boxing to lose 20 pounds.\r\nBob gave up ice cream and took karate to lose 13 pounds.\r\nMike gave up pizza and started using the treadmill to lose 27 pounds.\r\nApril gave up potato chips and started walking to lose 34 pounds.\r\nSarah gave up chocolate and started doing yoga to lose 24 pounds.\n<|im_end|>" }, { "id": "#52344", "title": "The Froopaloop Island Ferry", "fun": 3.09, "difficulty": 2.09, "author": "wimpykidfan37", "desc": "Every two hours, a ferry leaves Froopaloop Island and heads due east to the mainland, taking exactly one hour. Then it leaves the mainland and heads due west back to the island, again taking exactly one hour. Then it repeats.\n\r\nInstead of taking the ferry to Froopaloop Island, Heather prefers to do something very risky: she dons her gorgeous white bikini and swims to the island. (The inhabitants of the island don't know what she looks like with clothes on.)\n\r\nOne day, Heather left the mainland terminal at exactly the same time the ferry left the island terminal. Exactly 50 minutes later, the ferry passed her.\n\r\nAssuming both Heather and the ferry travel at a constant speed, and ignoring the time the ferry spends at the mainland terminal, how much time passed between the ferry passing Heather in the opposite direction and passing her in the same direction?", "hint": "Fifty minutes after leaving the island terminal, the ferry will go in the opposite direction of Heather.", "answer": "Twenty-five minutes passed.\n\r\nWhen the ferry first passes Heather, it still has 10 minutes to reach the mainland, which means it can travel the same distance in 10 minutes that Heather can in 50 minutes, and therefore is 5 times as fast.\n\r\nIf the distance between the two terminals is x, and the distance Heather has travelled when the ferry passes her the second time is y, then the distance the ferry would have travelled at that time is x+y. Therefore, x+y=5x, which means that y=4x. Since x takes 60 minutes for the ferry, y must take 15 minutes, and x+y must take 75 minutes.\n\r\nTherefore, the time between Heather leaving the mainland and the ferry passing her for the second time is 75 minutes, and the time between the first and second times the ferry passed her is 75-50, or 25, minutes.", "category": "Math", "date": "01/19/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery two hours, a ferry leaves Froopaloop Island and heads due east to the mainland, taking exactly one hour. Then it leaves the mainland and heads due west back to the island, again taking exactly one hour. Then it repeats.\n\r\nInstead of taking the ferry to Froopaloop Island, Heather prefers to do something very risky: she dons her gorgeous white bikini and swims to the island. (The inhabitants of the island don't know what she looks like with clothes on.)\n\r\nOne day, Heather left the mainland terminal at exactly the same time the ferry left the island terminal. Exactly 50 minutes later, the ferry passed her.\n\r\nAssuming both Heather and the ferry travel at a constant speed, and ignoring the time the ferry spends at the mainland terminal, how much time passed between the ferry passing Heather in the opposite direction and passing her in the same direction?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwenty-five minutes passed.\n\r\nWhen the ferry first passes Heather, it still has 10 minutes to reach the mainland, which means it can travel the same distance in 10 minutes that Heather can in 50 minutes, and therefore is 5 times as fast.\n\r\nIf the distance between the two terminals is x, and the distance Heather has travelled when the ferry passes her the second time is y, then the distance the ferry would have travelled at that time is x+y. Therefore, x+y=5x, which means that y=4x. Since x takes 60 minutes for the ferry, y must take 15 minutes, and x+y must take 75 minutes.\n\r\nTherefore, the time between Heather leaving the mainland and the ferry passing her for the second time is 75 minutes, and the time between the first and second times the ferry passed her is 75-50, or 25, minutes.\n<|im_start|>answer\nTwenty-five minutes passed.\n\r\nWhen the ferry first passes Heather, it still has 10 minutes to reach the mainland, which means it can travel the same distance in 10 minutes that Heather can in 50 minutes, and therefore is 5 times as fast.\n\r\nIf the distance between the two terminals is x, and the distance Heather has travelled when the ferry passes her the second time is y, then the distance the ferry would have travelled at that time is x+y. Therefore, x+y=5x, which means that y=4x. Since x takes 60 minutes for the ferry, y must take 15 minutes, and x+y must take 75 minutes.\n\r\nTherefore, the time between Heather leaving the mainland and the ferry passing her for the second time is 75 minutes, and the time between the first and second times the ferry passed her is 75-50, or 25, minutes.\n<|im_end|>" }, { "id": "#24349", "title": "Why, Skid Mark, Why?", "fun": 3.09, "difficulty": 1.86, "author": "Question_Mark", "desc": "After recent events, Question Mark is annoyed with his brother, Skid Mark. Skid thought it would be funny to hide Question's wallet. He told Question that he would get it back if he finds it. So, first off, Skid laid five colored keys in a row. One of them is a key to a room where Skid is hiding Question's wallet. Using the clues, can you determine the order of the keys and which is the right key?\n\r\nRed: This key is somewhere to the left of the key to the door.\r\nBlue: This key is not at one of the ends.\r\nGreen: This key is three spaces away from the key to the door (2 between).\r\nYellow: This key is next to the key to the door.\r\nOrange: This key is in the middle.", "hint": "No hint available.", "answer": "The order (from left to right) is Green, Red, Orange, Blue, Yellow.\n\r\nThe blue key is the key to the door.", "category": "Logic", "date": "07/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter recent events, Question Mark is annoyed with his brother, Skid Mark. Skid thought it would be funny to hide Question's wallet. He told Question that he would get it back if he finds it. So, first off, Skid laid five colored keys in a row. One of them is a key to a room where Skid is hiding Question's wallet. Using the clues, can you determine the order of the keys and which is the right key?\n\r\nRed: This key is somewhere to the left of the key to the door.\r\nBlue: This key is not at one of the ends.\r\nGreen: This key is three spaces away from the key to the door (2 between).\r\nYellow: This key is next to the key to the door.\r\nOrange: This key is in the middle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe order (from left to right) is Green, Red, Orange, Blue, Yellow.\n\r\nThe blue key is the key to the door.\n<|im_start|>answer\nThe order (from left to right) is Green, Red, Orange, Blue, Yellow.\n\r\nThe blue key is the key to the door.\n<|im_end|>" }, { "id": "#19728", "title": "Evil Aardvark!", "fun": 3.09, "difficulty": 2.26, "author": "lorial", "desc": "Aargon the evil aardvark has five ant captives locked up in cages. He decides to eat them in a certain order and they are all to be cooked in different ways with a different herb or spice. Can you determine this evil aardvark's intentions?\n\r\nAnt-acid is not to be eaten first or last.\n\r\nCumin is to be used with the ant to be eaten in 4th place, but is not to be used with the ant to be grilled. \n\r\nAnt-O'Knee is to be grilled or steamed but not with ginger.\n\r\nAnt-ique is to be eaten 2 places ahead of the ant to be cooked with garlic. \n\r\nThe ant to be eaten raw is to be eaten after Ant-ique, but before Ant-acid.\n\r\nAnt-enna is not to be eaten fried or raw and is not to be eaten in 4th place.\n\r\nMint is to be eaten directly before the coriander.\n\r\nThe ant to be eaten in 3rd position is to be baked, but not with coriander or ginger.\n\r\nPositions: 1st to 5th.\r\nAnts: Ant-O'Knee, Ant-acid, Ant-elope, Ant-enna & Ant-ique.\r\nCooking Method:\tFried, Baked, Raw, Steamed & Grilled.\r\nSpice/Herb: Garlic, Cumin, Coriander, Ginger & Mint.", "hint": "No hint available.", "answer": "Ant / Method / Position / Herb/Spice\n\r\nAnt-O'Knee / Steamed / 4th /Cumin \r\nAnt-acid / Baked / 3rd / Garlic\r\nAnt-elope / Raw / 2nd / Coriander\r\nAnt-enna / Grilled / 5th / Ginger\r\nAnt-ique / Fried / 1st / Mint", "category": "Logic-Grid", "date": "12/06/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAargon the evil aardvark has five ant captives locked up in cages. He decides to eat them in a certain order and they are all to be cooked in different ways with a different herb or spice. Can you determine this evil aardvark's intentions?\n\r\nAnt-acid is not to be eaten first or last.\n\r\nCumin is to be used with the ant to be eaten in 4th place, but is not to be used with the ant to be grilled. \n\r\nAnt-O'Knee is to be grilled or steamed but not with ginger.\n\r\nAnt-ique is to be eaten 2 places ahead of the ant to be cooked with garlic. \n\r\nThe ant to be eaten raw is to be eaten after Ant-ique, but before Ant-acid.\n\r\nAnt-enna is not to be eaten fried or raw and is not to be eaten in 4th place.\n\r\nMint is to be eaten directly before the coriander.\n\r\nThe ant to be eaten in 3rd position is to be baked, but not with coriander or ginger.\n\r\nPositions: 1st to 5th.\r\nAnts: Ant-O'Knee, Ant-acid, Ant-elope, Ant-enna & Ant-ique.\r\nCooking Method:\tFried, Baked, Raw, Steamed & Grilled.\r\nSpice/Herb: Garlic, Cumin, Coriander, Ginger & Mint.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnt / Method / Position / Herb/Spice\n\r\nAnt-O'Knee / Steamed / 4th /Cumin \r\nAnt-acid / Baked / 3rd / Garlic\r\nAnt-elope / Raw / 2nd / Coriander\r\nAnt-enna / Grilled / 5th / Ginger\r\nAnt-ique / Fried / 1st / Mint\n<|im_start|>answer\nAnt / Method / Position / Herb/Spice\n\r\nAnt-O'Knee / Steamed / 4th /Cumin \r\nAnt-acid / Baked / 3rd / Garlic\r\nAnt-elope / Raw / 2nd / Coriander\r\nAnt-enna / Grilled / 5th / Ginger\r\nAnt-ique / Fried / 1st / Mint\n<|im_end|>" }, { "id": "#24859", "title": "Best In Show", "fun": 3.09, "difficulty": 2.56, "author": "ragsdaleam", "desc": "Five dogs recently competed for best in show in the local kennel club. Each dog belonged to a different AKC group, preferred a different kind of treat, and wore a different color lead. Can you determine each dog's group, lead color, favorite treat, and the place he or she took in the show?\n\r\nNote: The Rhodesian Ridgeback is a member of the Hound Group.\n\r\n1. The dog with the red lead finished before the dog who liked chicken bites, but after the dog that belonged to the herding group (who is not Sadie).\n\r\n2. The dog that placed third was not Rusty (who is a working dog).\n\r\n3. The sporting dog placed just ahead of the one with a pink lead, and somewhere behind Charlie (who didn't like rawhide treats).\n\r\n4. The hound did not like the beef or liver treats.\n\r\n5. Rusty did not wear the blue lead.\n\r\n6. Wags, who hated Scooby snacks, was a Rhodesian Ridgeback, and his handler hated the color green, so she would never let him wear a green lead.\n\r\n7. Neither Pharaoh nor Sadie liked Scooby snacks or wore green.\n\r\n8. The herding dog, who hated beef biscuits, had a blue lead for good luck, but did not take first place.\n\r\n9. The 3rd place dog did not wear a red lead.\n\r\n10. Pharaoh is not a sporting dog.\n\r\n11. The five dogs in order of rank, from 1st to 5th, were:\r\nThe one who ate Scooby snacks, Charlie, the one who loved beef biscuits, the sporting dog, and the one with the pink lead.", "hint": "No hint available.", "answer": "Rusty - Working - Green - Scooby Snacks - 1st\r\nCharlie - Herding - Blue - Liver Cubes- 2nd\r\nPharaoh - Toy - Purple - Beef Biscuits - 3rd\r\nSadie - Sporting - Red - Rawhide Chews - 4th\r\nWags - Hound - Pink - Chicken Bites - 5th", "category": "Logic-Grid", "date": "07/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive dogs recently competed for best in show in the local kennel club. Each dog belonged to a different AKC group, preferred a different kind of treat, and wore a different color lead. Can you determine each dog's group, lead color, favorite treat, and the place he or she took in the show?\n\r\nNote: The Rhodesian Ridgeback is a member of the Hound Group.\n\r\n1. The dog with the red lead finished before the dog who liked chicken bites, but after the dog that belonged to the herding group (who is not Sadie).\n\r\n2. The dog that placed third was not Rusty (who is a working dog).\n\r\n3. The sporting dog placed just ahead of the one with a pink lead, and somewhere behind Charlie (who didn't like rawhide treats).\n\r\n4. The hound did not like the beef or liver treats.\n\r\n5. Rusty did not wear the blue lead.\n\r\n6. Wags, who hated Scooby snacks, was a Rhodesian Ridgeback, and his handler hated the color green, so she would never let him wear a green lead.\n\r\n7. Neither Pharaoh nor Sadie liked Scooby snacks or wore green.\n\r\n8. The herding dog, who hated beef biscuits, had a blue lead for good luck, but did not take first place.\n\r\n9. The 3rd place dog did not wear a red lead.\n\r\n10. Pharaoh is not a sporting dog.\n\r\n11. The five dogs in order of rank, from 1st to 5th, were:\r\nThe one who ate Scooby snacks, Charlie, the one who loved beef biscuits, the sporting dog, and the one with the pink lead.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRusty - Working - Green - Scooby Snacks - 1st\r\nCharlie - Herding - Blue - Liver Cubes- 2nd\r\nPharaoh - Toy - Purple - Beef Biscuits - 3rd\r\nSadie - Sporting - Red - Rawhide Chews - 4th\r\nWags - Hound - Pink - Chicken Bites - 5th\n<|im_start|>answer\nRusty - Working - Green - Scooby Snacks - 1st\r\nCharlie - Herding - Blue - Liver Cubes- 2nd\r\nPharaoh - Toy - Purple - Beef Biscuits - 3rd\r\nSadie - Sporting - Red - Rawhide Chews - 4th\r\nWags - Hound - Pink - Chicken Bites - 5th\n<|im_end|>" }, { "id": "#27424", "title": "Best Friends...Forever?", "fun": 3.09, "difficulty": 2.11, "author": "Winner4600", "desc": "Dennis, Emily, Katrina, Rita, and Wilma are five friends who went to elementary school together. However, in 6th grade, each of them moved to a different state or country and are now starting to forget where each person is living, what water sport each person likes, and which natural disaster fascinates each of them. Can you help them sort out their homes and hobbies?\n\r\nFriends: Dennis, Emily, Katrina, Rita, Wilma\r\nLocations: Mexico, Texas, Cuba, Alabama, Florida\r\nHobbies: Waterskiing, Scuba Diving, Surfing, Kayaking, Swimming\r\nNatural Disasters: Avalanches, Hurricanes, Tornadoes, Earthquakes, Tsunamis\n\n\r\n1. The five friends are Emily, the waterskier, the hurricane and avalanche fanatics, and the Texan.\n\r\n2. If Dennis is the Cuban, then Emily is the Mexican. If Dennis is the hurricane lover, then Rita loves avalanches. One of these statements is true.\n\r\n3. Katrina and Dennis are the waterskier and the hurricane fanatic.\n\r\n4. The waterskier, surfer, and scuba diver live in Mexico, Cuba, and Texas and are fascinated by tornadoes, tsunamis, and earthquakes.\n\r\n5. The Floridian, who is not Katrina, likes kayaking and avalanches.\n\r\n6. The surfer, the diver, and Dennis used to hang out with Wilma afterschool.\n\r\n7. Emily loves earthquakes and Rita loves tsunamis.\n\r\n8. Rita has known the surfer since first grade.", "hint": "No hint available.", "answer": "Dennis lives in Cuba, waterskies, and loves tornadoes.\r\nEmily lives in Mexico, surfs, and loves earthquakes.\r\nKatrina lives in Alabama, swims, and loves hurricanes. \r\nRita lives in Texas, scuba dives, and loves tsunamis. \r\nWilma lives in Florida, kayaks, and loves avalanches.", "category": "Logic-Grid", "date": "12/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDennis, Emily, Katrina, Rita, and Wilma are five friends who went to elementary school together. However, in 6th grade, each of them moved to a different state or country and are now starting to forget where each person is living, what water sport each person likes, and which natural disaster fascinates each of them. Can you help them sort out their homes and hobbies?\n\r\nFriends: Dennis, Emily, Katrina, Rita, Wilma\r\nLocations: Mexico, Texas, Cuba, Alabama, Florida\r\nHobbies: Waterskiing, Scuba Diving, Surfing, Kayaking, Swimming\r\nNatural Disasters: Avalanches, Hurricanes, Tornadoes, Earthquakes, Tsunamis\n\n\r\n1. The five friends are Emily, the waterskier, the hurricane and avalanche fanatics, and the Texan.\n\r\n2. If Dennis is the Cuban, then Emily is the Mexican. If Dennis is the hurricane lover, then Rita loves avalanches. One of these statements is true.\n\r\n3. Katrina and Dennis are the waterskier and the hurricane fanatic.\n\r\n4. The waterskier, surfer, and scuba diver live in Mexico, Cuba, and Texas and are fascinated by tornadoes, tsunamis, and earthquakes.\n\r\n5. The Floridian, who is not Katrina, likes kayaking and avalanches.\n\r\n6. The surfer, the diver, and Dennis used to hang out with Wilma afterschool.\n\r\n7. Emily loves earthquakes and Rita loves tsunamis.\n\r\n8. Rita has known the surfer since first grade.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDennis lives in Cuba, waterskies, and loves tornadoes.\r\nEmily lives in Mexico, surfs, and loves earthquakes.\r\nKatrina lives in Alabama, swims, and loves hurricanes. \r\nRita lives in Texas, scuba dives, and loves tsunamis. \r\nWilma lives in Florida, kayaks, and loves avalanches.\n<|im_start|>answer\nDennis lives in Cuba, waterskies, and loves tornadoes.\r\nEmily lives in Mexico, surfs, and loves earthquakes.\r\nKatrina lives in Alabama, swims, and loves hurricanes. \r\nRita lives in Texas, scuba dives, and loves tsunamis. \r\nWilma lives in Florida, kayaks, and loves avalanches.\n<|im_end|>" }, { "id": "#51554", "title": "The Non-Boxer", "fun": 3.09, "difficulty": 2.39, "author": "wimpykidfan37", "desc": "There are three brothers: Al, Ben, and Carl. Two of the three brothers are boxers. Here are some facts:\n\r\n1. The shorter of Al and Ben is the older boxer.\r\n2. The younger of Ben and Carl is the shorter boxer.\r\n3. The taller of Al and Carl is the younger boxer.\n\r\nWhich brother is not a boxer?", "hint": "No hint available.", "answer": "Carl is not a boxer.\n\r\nFrom fact 1, we know that Carl is not the older boxer.\r\nFrom fact 3, we know that Ben is not the younger boxer.\r\nWe now have three possible scenarios:\n\r\n1. Al is the younger boxer and Ben is the older boxer.\r\n2. Ben is the older boxer and Carl is the younger boxer.\r\n3. Al is the older boxer and Carl is the younger boxer.\n\r\nIf scenario 1 is true, fact 1 tells us that Ben is shorter than Al.\r\nIf scenario 2 is true, fact 1 tells us that Ben is shorter than Al; fact 3 tells us that Carl is taller than Al, making Ben shorter than Carl.\r\nIf scenario 3 is true, fact 3 tells us that Carl is taller than Al.\r\nWe can now expand our three scenarios:\n\r\n1. Al is the younger, taller boxer, and Ben is the older, shorter boxer.\r\n2. Ben is the older, shorter boxer, and Carl is the younger, taller boxer.\r\n3. Al is the older, shorter boxer, and Carl is the younger, taller boxer.\n\r\nScenario 2 cannot be possible because it contradicts fact 2 by making the younger of Ben and Carl the taller boxer. \r\nFact 2 also tells us that Al is not the shorter boxer, so scenario 3 cannot be possible, either. \r\nTherefore, scenario 1 is true, which means that Carl is not a boxer.", "category": "Logic", "date": "11/08/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three brothers: Al, Ben, and Carl. Two of the three brothers are boxers. Here are some facts:\n\r\n1. The shorter of Al and Ben is the older boxer.\r\n2. The younger of Ben and Carl is the shorter boxer.\r\n3. The taller of Al and Carl is the younger boxer.\n\r\nWhich brother is not a boxer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarl is not a boxer.\n\r\nFrom fact 1, we know that Carl is not the older boxer.\r\nFrom fact 3, we know that Ben is not the younger boxer.\r\nWe now have three possible scenarios:\n\r\n1. Al is the younger boxer and Ben is the older boxer.\r\n2. Ben is the older boxer and Carl is the younger boxer.\r\n3. Al is the older boxer and Carl is the younger boxer.\n\r\nIf scenario 1 is true, fact 1 tells us that Ben is shorter than Al.\r\nIf scenario 2 is true, fact 1 tells us that Ben is shorter than Al; fact 3 tells us that Carl is taller than Al, making Ben shorter than Carl.\r\nIf scenario 3 is true, fact 3 tells us that Carl is taller than Al.\r\nWe can now expand our three scenarios:\n\r\n1. Al is the younger, taller boxer, and Ben is the older, shorter boxer.\r\n2. Ben is the older, shorter boxer, and Carl is the younger, taller boxer.\r\n3. Al is the older, shorter boxer, and Carl is the younger, taller boxer.\n\r\nScenario 2 cannot be possible because it contradicts fact 2 by making the younger of Ben and Carl the taller boxer. \r\nFact 2 also tells us that Al is not the shorter boxer, so scenario 3 cannot be possible, either. \r\nTherefore, scenario 1 is true, which means that Carl is not a boxer.\n<|im_start|>answer\nCarl is not a boxer.\n\r\nFrom fact 1, we know that Carl is not the older boxer.\r\nFrom fact 3, we know that Ben is not the younger boxer.\r\nWe now have three possible scenarios:\n\r\n1. Al is the younger boxer and Ben is the older boxer.\r\n2. Ben is the older boxer and Carl is the younger boxer.\r\n3. Al is the older boxer and Carl is the younger boxer.\n\r\nIf scenario 1 is true, fact 1 tells us that Ben is shorter than Al.\r\nIf scenario 2 is true, fact 1 tells us that Ben is shorter than Al; fact 3 tells us that Carl is taller than Al, making Ben shorter than Carl.\r\nIf scenario 3 is true, fact 3 tells us that Carl is taller than Al.\r\nWe can now expand our three scenarios:\n\r\n1. Al is the younger, taller boxer, and Ben is the older, shorter boxer.\r\n2. Ben is the older, shorter boxer, and Carl is the younger, taller boxer.\r\n3. Al is the older, shorter boxer, and Carl is the younger, taller boxer.\n\r\nScenario 2 cannot be possible because it contradicts fact 2 by making the younger of Ben and Carl the taller boxer. \r\nFact 2 also tells us that Al is not the shorter boxer, so scenario 3 cannot be possible, either. \r\nTherefore, scenario 1 is true, which means that Carl is not a boxer.\n<|im_end|>" }, { "id": "#27039", "title": "Apple Picking Contest", "fun": 3.09, "difficulty": 2.72, "author": "ilovehimalways", "desc": "It's apple season and five friends went apple picking last weekend at the Sleepy Hollow orchard, a local orchard where you can buy a bag and then pick your own apples. It was a beautiful day and the friends had a fine time. Sometime during the afternoon, the apple picking became a contest and the friends battled to see who could pick the most apples from the highest places in the shortest time. The end result is that they picked far more apples than they had intended, though they had a grand time doing so. Determine what each friend's favorite type of apple was, how many bushels each friend picked, what each friend's fastest time was for picking a bagful, and how many apples each friend ended up eating while they picked.\n\r\n1. Ellen was the fastest apple picker but the one who loves McIntosh apples was only one minute behind her. The man whose favorite apples are McIntosh picked five bushels of apples but he didn't eat the most apples.\n\r\n2. The person who picked one bushel ate more apples than Debbie, but ate two less than the one who loves Macoun apples. Brian didn't like McIntosh apples.\n\r\n3. James picked more apples than the woman who loved Cortland apples but less than the person who only ate one apple. Jeremy didn't eat two apples.\n\r\n4. The person who loved Macoun apples picked more bushels than the person who picked a bag in 12 minutes, but less than the person who ate two apples.\n\r\n5. The person who picked the Red Delicious apples had a faster time than the person who ate five apples but a slower time than the person who picked two bushels.\n\r\n6. The person who loved Empire apples had the slowest time, but James was only two minutes ahead of her. Ellen picked two bushels of apples.", "hint": "Debbie took the longest time.", "answer": "Brian-Red Delicious-1 bushel-12 min-3 \r\nDebbie-Empire-4 bushels-15 min-2\r\nEllen-Cortland-2 bushels-9 min-4\r\nJames-Macoun-3 bushels-13 min-5\r\nJeremy-McIntosh-5 bushels-10 min-1", "category": "Logic-Grid", "date": "11/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's apple season and five friends went apple picking last weekend at the Sleepy Hollow orchard, a local orchard where you can buy a bag and then pick your own apples. It was a beautiful day and the friends had a fine time. Sometime during the afternoon, the apple picking became a contest and the friends battled to see who could pick the most apples from the highest places in the shortest time. The end result is that they picked far more apples than they had intended, though they had a grand time doing so. Determine what each friend's favorite type of apple was, how many bushels each friend picked, what each friend's fastest time was for picking a bagful, and how many apples each friend ended up eating while they picked.\n\r\n1. Ellen was the fastest apple picker but the one who loves McIntosh apples was only one minute behind her. The man whose favorite apples are McIntosh picked five bushels of apples but he didn't eat the most apples.\n\r\n2. The person who picked one bushel ate more apples than Debbie, but ate two less than the one who loves Macoun apples. Brian didn't like McIntosh apples.\n\r\n3. James picked more apples than the woman who loved Cortland apples but less than the person who only ate one apple. Jeremy didn't eat two apples.\n\r\n4. The person who loved Macoun apples picked more bushels than the person who picked a bag in 12 minutes, but less than the person who ate two apples.\n\r\n5. The person who picked the Red Delicious apples had a faster time than the person who ate five apples but a slower time than the person who picked two bushels.\n\r\n6. The person who loved Empire apples had the slowest time, but James was only two minutes ahead of her. Ellen picked two bushels of apples.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrian-Red Delicious-1 bushel-12 min-3 \r\nDebbie-Empire-4 bushels-15 min-2\r\nEllen-Cortland-2 bushels-9 min-4\r\nJames-Macoun-3 bushels-13 min-5\r\nJeremy-McIntosh-5 bushels-10 min-1\n<|im_start|>answer\nBrian-Red Delicious-1 bushel-12 min-3 \r\nDebbie-Empire-4 bushels-15 min-2\r\nEllen-Cortland-2 bushels-9 min-4\r\nJames-Macoun-3 bushels-13 min-5\r\nJeremy-McIntosh-5 bushels-10 min-1\n<|im_end|>" }, { "id": "#49436", "title": "A J's Stitching Projects", "fun": 3.09, "difficulty": 1.86, "author": "Rhythmic", "desc": "A J really enjoyed stitching pictures and designs with her needle and thread. Not only did she love making things, she had lots of fun giving them away. Recently, she just completed five projects. Can you figure out who got each project, what the design was, what the main color was, and how big it was?\n\r\nRecipients: Daughter, Granny, Husband, Mom, Niece\r\nDesigns: Butterfly, Clouds, Cross, Flower, Leaves\r\nMain colors: Blue, Brown, Green, Red, White\r\nSizes: Extra Small, Small, Medium, Large, Extra Large\n\r\n1) The five projects were the one for her mom, the one with clouds, the brown one, the medium one, and the extra large one.\n\r\n2) A J decided to give her daughter, Rachel, the smallest one since it would go in her locker at school.\n\r\n3) A J used (subtractive) primary colors for the butterfly and the flower.\n\r\n4) A J's mom got a project that has something to do with plants.\n\r\n5) Rachel's cousin got the medium sized project with a butterfly.\n\r\n6) A J had a lot of red, so she made that the main color of the large project.\n\r\n7) The project for A J's granny was bigger than the white one and bigger than the one with a cross.\n\r\n8) A J did not use brown on her husband's design.", "hint": "Red and blue are primary colors.\n\r\nA J's daughter is Rachel. Rachel's cousin is A J's niece.", "answer": "The daughter got a cross that was brown and extra small.\r\nThe granny got leaves that were green and extra large.\r\nThe husband got clouds that were white and small.\r\nThe mom got a flower that was red and large.\r\nThe niece got a butterfly that was blue and medium.", "category": "Logic-Grid", "date": "04/27/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA J really enjoyed stitching pictures and designs with her needle and thread. Not only did she love making things, she had lots of fun giving them away. Recently, she just completed five projects. Can you figure out who got each project, what the design was, what the main color was, and how big it was?\n\r\nRecipients: Daughter, Granny, Husband, Mom, Niece\r\nDesigns: Butterfly, Clouds, Cross, Flower, Leaves\r\nMain colors: Blue, Brown, Green, Red, White\r\nSizes: Extra Small, Small, Medium, Large, Extra Large\n\r\n1) The five projects were the one for her mom, the one with clouds, the brown one, the medium one, and the extra large one.\n\r\n2) A J decided to give her daughter, Rachel, the smallest one since it would go in her locker at school.\n\r\n3) A J used (subtractive) primary colors for the butterfly and the flower.\n\r\n4) A J's mom got a project that has something to do with plants.\n\r\n5) Rachel's cousin got the medium sized project with a butterfly.\n\r\n6) A J had a lot of red, so she made that the main color of the large project.\n\r\n7) The project for A J's granny was bigger than the white one and bigger than the one with a cross.\n\r\n8) A J did not use brown on her husband's design.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe daughter got a cross that was brown and extra small.\r\nThe granny got leaves that were green and extra large.\r\nThe husband got clouds that were white and small.\r\nThe mom got a flower that was red and large.\r\nThe niece got a butterfly that was blue and medium.\n<|im_start|>answer\nThe daughter got a cross that was brown and extra small.\r\nThe granny got leaves that were green and extra large.\r\nThe husband got clouds that were white and small.\r\nThe mom got a flower that was red and large.\r\nThe niece got a butterfly that was blue and medium.\n<|im_end|>" }, { "id": "#24611", "title": "Trilogy Part 3: Have You Herd?", "fun": 3.09, "difficulty": 2.73, "author": "cinnamon30", "desc": "Note: You will need the answers from Trilogy Part 1 and 2 to complete this logic grid.\n\r\nThe five cowboys are just about done chewing the fat for the day and are ready to return to their ranches. Each man owns a different ranch (one is the Rolling T Ranch), no two of which are the same size (3000, 3500, 4000, 4500 and 5000 acres). Each man raises a different type of cattle on his ranch and every year he hosts a different event (including an autumn hayride) on his sizable spread. All in all, it's good to be home on the range! From the info provided, can you determine the size of the ranch owned by each rancher, the type of cattle each rancher raises and the special event each man hosts annually?\n\r\nMen - Carl Lovelace, Hank Brooks, Pablo Sanchez, Rusty Ewing, Zeke McCool\r\nRanch - Circle Star, H Bar, Lazy K, Rolling T, Square Z\r\nSize - 3000, 3500, 4000, 4500 and 5000 acres\r\nCattle - Brangus, Hereford, Lourdais, Shorthorn, Simmental\r\nEvent - Auction, Barn Dance, Cookout, Hayride, Rodeo\n\r\n1. The H Bar ranch (which is owned by Mr. McCool) is exactly 500 acres smaller than the one housing a herd of Hereford Cattle.\n\r\n2. The man wearing Sunset boots (who raises Brangus cattle) isn't the cowboy who owns the Square Z ranch (who hosts an annual rodeo).\n\r\n3. The ranch housing a herd of Lourdais cattle is exactly 500 acres smaller than the spread owned by the man wearing a calico shirt (who hosts an annual springtime barn dance).\n\r\n4. The cowboy in position D (who owns the largest ranch) isn't the man who hosts an annual charity auction (who raises Shorthorn cattle).\n\r\n5. Neither the rancher wearing Oil Baron boots nor the owner of the Lazy K ranch is the one who raises Hereford cattle.\n\r\n6. The Circle Star ranch isn't the one that houses a herd of Simmental cattle. Mr. Sanchez doesn't host the annual rodeo. \n\r\n7. Hank isn't the owner of the 3500-acre ranch. The annual summer cookout isn't the event held at the 4000-acre ranch.", "hint": "No hint available.", "answer": "Carl Lovelace - Lazy K ranch, 4000 acres, Brangus cattle and Hayride\r\nHank Brooks - Square Z ranch, 3000 acres, Lourdais cattle and Rodeo\r\nPablo Sanchez - Circle Star ranch, 5000 acres, Hereford cattle and Cookout\r\nRusty Ewing - Rolling T ranch, 3500 acres, Simmental cattle and Barn Dance\r\nZeke McCool - H Bar ranch, 4500 acres, Shorthorn cattle and Auction\n\r\nCarl Lovelace raises Brangus cattle (2). \r\nZeke McCool owns the H Bar ranch (1).\r\nRusty Ewing wearing a calico shirt hosts the annual Barn dance (3).\r\nPablo Sanchez who is in position D owns the 5000-acre ranch (4).\r\nRusty doesn't raise Brangus cattle (2), Lourdais (3), Shorthorn (4) or Hereford (5). Therefore he raises Simmental cattle. \r\nRusty isn't the owner of the H Bar ranch (1), Square Z (2), Lazy K (5) or Circle Star (6). Therefore he's the owner of the Rolling T ranch.\r\nPablo Sanchez doesn't raise Lourdais (3) or Shorthorn (4). Therefore he raises Hereford cattle.\r\nThe H Bar ranch is 4500-acres (1). Pablo [largest ranch (4)] doesn't own Lazy K ranch (5), Square Z (6), or Rolling T [Rusty]. Therefore he's Circle Star ranch.\r\nCarl doesn't own the Square Z (2), so he owns the Lazy K ranch. Hank owns the Square Z ranch and hosts the annual rodeo (2), so he doesn't raise Shorthorn [auction (4)]; he raises Lourdais, only one left.\r\nHank doesn't own the 3500-acre (7) or 4000-acre because Rusty's ranch is 500 acres bigger than Hank's (3) and if Hank was 4000 Rusty would have to be 4500, but we already know Zeke owns the 4500-acre ranch. Therefore Hank owns the 3000-acre ranch.\r\nRusty therefore owns the 3500-acre ranch (3) and Carl owns the 4000-acre ranch, only one left.\r\nCarl isn't the cookout (7) or auction [Shorthorn cattle (4)]. Therefore he's the hayride.\r\nZeke hosts the annual charity auction (4); therefore Pablo hosts the cookout, only one left.", "category": "Logic-Grid", "date": "07/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNote: You will need the answers from Trilogy Part 1 and 2 to complete this logic grid.\n\r\nThe five cowboys are just about done chewing the fat for the day and are ready to return to their ranches. Each man owns a different ranch (one is the Rolling T Ranch), no two of which are the same size (3000, 3500, 4000, 4500 and 5000 acres). Each man raises a different type of cattle on his ranch and every year he hosts a different event (including an autumn hayride) on his sizable spread. All in all, it's good to be home on the range! From the info provided, can you determine the size of the ranch owned by each rancher, the type of cattle each rancher raises and the special event each man hosts annually?\n\r\nMen - Carl Lovelace, Hank Brooks, Pablo Sanchez, Rusty Ewing, Zeke McCool\r\nRanch - Circle Star, H Bar, Lazy K, Rolling T, Square Z\r\nSize - 3000, 3500, 4000, 4500 and 5000 acres\r\nCattle - Brangus, Hereford, Lourdais, Shorthorn, Simmental\r\nEvent - Auction, Barn Dance, Cookout, Hayride, Rodeo\n\r\n1. The H Bar ranch (which is owned by Mr. McCool) is exactly 500 acres smaller than the one housing a herd of Hereford Cattle.\n\r\n2. The man wearing Sunset boots (who raises Brangus cattle) isn't the cowboy who owns the Square Z ranch (who hosts an annual rodeo).\n\r\n3. The ranch housing a herd of Lourdais cattle is exactly 500 acres smaller than the spread owned by the man wearing a calico shirt (who hosts an annual springtime barn dance).\n\r\n4. The cowboy in position D (who owns the largest ranch) isn't the man who hosts an annual charity auction (who raises Shorthorn cattle).\n\r\n5. Neither the rancher wearing Oil Baron boots nor the owner of the Lazy K ranch is the one who raises Hereford cattle.\n\r\n6. The Circle Star ranch isn't the one that houses a herd of Simmental cattle. Mr. Sanchez doesn't host the annual rodeo. \n\r\n7. Hank isn't the owner of the 3500-acre ranch. The annual summer cookout isn't the event held at the 4000-acre ranch.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarl Lovelace - Lazy K ranch, 4000 acres, Brangus cattle and Hayride\r\nHank Brooks - Square Z ranch, 3000 acres, Lourdais cattle and Rodeo\r\nPablo Sanchez - Circle Star ranch, 5000 acres, Hereford cattle and Cookout\r\nRusty Ewing - Rolling T ranch, 3500 acres, Simmental cattle and Barn Dance\r\nZeke McCool - H Bar ranch, 4500 acres, Shorthorn cattle and Auction\n\r\nCarl Lovelace raises Brangus cattle (2). \r\nZeke McCool owns the H Bar ranch (1).\r\nRusty Ewing wearing a calico shirt hosts the annual Barn dance (3).\r\nPablo Sanchez who is in position D owns the 5000-acre ranch (4).\r\nRusty doesn't raise Brangus cattle (2), Lourdais (3), Shorthorn (4) or Hereford (5). Therefore he raises Simmental cattle. \r\nRusty isn't the owner of the H Bar ranch (1), Square Z (2), Lazy K (5) or Circle Star (6). Therefore he's the owner of the Rolling T ranch.\r\nPablo Sanchez doesn't raise Lourdais (3) or Shorthorn (4). Therefore he raises Hereford cattle.\r\nThe H Bar ranch is 4500-acres (1). Pablo [largest ranch (4)] doesn't own Lazy K ranch (5), Square Z (6), or Rolling T [Rusty]. Therefore he's Circle Star ranch.\r\nCarl doesn't own the Square Z (2), so he owns the Lazy K ranch. Hank owns the Square Z ranch and hosts the annual rodeo (2), so he doesn't raise Shorthorn [auction (4)]; he raises Lourdais, only one left.\r\nHank doesn't own the 3500-acre (7) or 4000-acre because Rusty's ranch is 500 acres bigger than Hank's (3) and if Hank was 4000 Rusty would have to be 4500, but we already know Zeke owns the 4500-acre ranch. Therefore Hank owns the 3000-acre ranch.\r\nRusty therefore owns the 3500-acre ranch (3) and Carl owns the 4000-acre ranch, only one left.\r\nCarl isn't the cookout (7) or auction [Shorthorn cattle (4)]. Therefore he's the hayride.\r\nZeke hosts the annual charity auction (4); therefore Pablo hosts the cookout, only one left.\n<|im_start|>answer\nCarl Lovelace - Lazy K ranch, 4000 acres, Brangus cattle and Hayride\r\nHank Brooks - Square Z ranch, 3000 acres, Lourdais cattle and Rodeo\r\nPablo Sanchez - Circle Star ranch, 5000 acres, Hereford cattle and Cookout\r\nRusty Ewing - Rolling T ranch, 3500 acres, Simmental cattle and Barn Dance\r\nZeke McCool - H Bar ranch, 4500 acres, Shorthorn cattle and Auction\n\r\nCarl Lovelace raises Brangus cattle (2). \r\nZeke McCool owns the H Bar ranch (1).\r\nRusty Ewing wearing a calico shirt hosts the annual Barn dance (3).\r\nPablo Sanchez who is in position D owns the 5000-acre ranch (4).\r\nRusty doesn't raise Brangus cattle (2), Lourdais (3), Shorthorn (4) or Hereford (5). Therefore he raises Simmental cattle. \r\nRusty isn't the owner of the H Bar ranch (1), Square Z (2), Lazy K (5) or Circle Star (6). Therefore he's the owner of the Rolling T ranch.\r\nPablo Sanchez doesn't raise Lourdais (3) or Shorthorn (4). Therefore he raises Hereford cattle.\r\nThe H Bar ranch is 4500-acres (1). Pablo [largest ranch (4)] doesn't own Lazy K ranch (5), Square Z (6), or Rolling T [Rusty]. Therefore he's Circle Star ranch.\r\nCarl doesn't own the Square Z (2), so he owns the Lazy K ranch. Hank owns the Square Z ranch and hosts the annual rodeo (2), so he doesn't raise Shorthorn [auction (4)]; he raises Lourdais, only one left.\r\nHank doesn't own the 3500-acre (7) or 4000-acre because Rusty's ranch is 500 acres bigger than Hank's (3) and if Hank was 4000 Rusty would have to be 4500, but we already know Zeke owns the 4500-acre ranch. Therefore Hank owns the 3000-acre ranch.\r\nRusty therefore owns the 3500-acre ranch (3) and Carl owns the 4000-acre ranch, only one left.\r\nCarl isn't the cookout (7) or auction [Shorthorn cattle (4)]. Therefore he's the hayride.\r\nZeke hosts the annual charity auction (4); therefore Pablo hosts the cookout, only one left.\n<|im_end|>" }, { "id": "#28115", "title": "Inspector Beethoven III", "fun": 3.09, "difficulty": 2.04, "author": "beethovenswig", "desc": "Handel has been killed and Beethoven is on the case. He has interviewed the four suspects and their statements are shown below. Each suspect has said two sentences. One sentence of each suspect is a lie and one sentence is the truth. Help Beethoven figure out who the killer is.\n\r\nJoplin: I did not kill Handel. Either Grieg is the killer or none of us is.\r\nGrieg: I did not kill Handel. Gershwin is the killer.\r\nStrauss: I did not kill Handel. Grieg is lying when he says Gershwin is the killer.\r\nGershwin: I did not kill Handel. If Joplin did not kill him, then Grieg did.", "hint": "No hint available.", "answer": "Strauss is the one who killed Handel. \r\nYou need to take turns assuming someone is the killer; that means everyone's second sentence is a lie. If Joplin was the killer, Grieg's lie mixed with Strauss' counteracts the other. If Grieg was the killer, Gershwin would need to be a killer too. If Gershwin was the killer, Grieg and Strauss counter each other again, but with Strauss, everything would fit.", "category": "Logic", "date": "01/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHandel has been killed and Beethoven is on the case. He has interviewed the four suspects and their statements are shown below. Each suspect has said two sentences. One sentence of each suspect is a lie and one sentence is the truth. Help Beethoven figure out who the killer is.\n\r\nJoplin: I did not kill Handel. Either Grieg is the killer or none of us is.\r\nGrieg: I did not kill Handel. Gershwin is the killer.\r\nStrauss: I did not kill Handel. Grieg is lying when he says Gershwin is the killer.\r\nGershwin: I did not kill Handel. If Joplin did not kill him, then Grieg did.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStrauss is the one who killed Handel. \r\nYou need to take turns assuming someone is the killer; that means everyone's second sentence is a lie. If Joplin was the killer, Grieg's lie mixed with Strauss' counteracts the other. If Grieg was the killer, Gershwin would need to be a killer too. If Gershwin was the killer, Grieg and Strauss counter each other again, but with Strauss, everything would fit.\n<|im_start|>answer\nStrauss is the one who killed Handel. \r\nYou need to take turns assuming someone is the killer; that means everyone's second sentence is a lie. If Joplin was the killer, Grieg's lie mixed with Strauss' counteracts the other. If Grieg was the killer, Gershwin would need to be a killer too. If Gershwin was the killer, Grieg and Strauss counter each other again, but with Strauss, everything would fit.\n<|im_end|>" }, { "id": "#24742", "title": "Lucky Guesses", "fun": 3.09, "difficulty": 2.39, "author": "tjm531", "desc": "On a rainy night, five gnomish characters huddled on stools at the bar of Rumplestiltskin's Place and told their sad tales. Each had once had the good fortune to come across a beautiful maiden who was desperate to complete a different formidable task to win a king's hand in marriage. Each gnome agreed to help, but only in exchange for the maiden's first born child. Although the women hastily agreed, when the time came to pay their dues, they naturally resisted. Each gnome offered one final bargain. If the maiden could guess his name, she could keep her new born baby. Since each gnome had a rather odd name, he felt safe in offering the maiden a different number of guesses. Each was therefore horrified when he returned to the woman only to hear her promptly and calmly reciting his name! From the information provided, can you determine the name of the gnome who helped each woman and the task she had to complete, as well as the number of guesses each woman was given?\n\r\nGnomes: Arklesblatt, Dinkleberry, Haycocklebloo, Sneedermon, Zizzyrimple\n\r\nWomen: Bianca, Diana, Ione, Katrina, Valerie\n\r\nTask: Crush rocks into diamonds, Roll roses into rubies, Spin flax into silver, Stir broth into myrrh, Stomp string into silk.\n\r\n# of Guesses: 2, 3, 4, 5, 6\n\r\n1. The woman who needed to spin flax into silver (who isn't Diana) didn't negotiate with Haycocklebloo. Dinkleberry didn't give a queen either two or three guesses.\n\r\n2. Queen Katrina was given fewer guesses than the woman helped by Sneedermon (who didn't get either four or six guesses) but more chances than the lady Zizzyrimple assisted.\n\r\n3. Valerie promised the king that she could roll roses into rubies. Neither Arklesblatt nor Haycocklebloo helped either Valerie or Diana. With Zizzyrimple's assistance, Ione won the king's hand in marriage.\n\r\n4. The woman who was given six guesses (who isn't the one Dinkleberry helped) isn't the one who vowed she could stir broth into myrrh.\n\r\n5. Bianca (who wasn't required to spin flax into silver) is neither the woman Haycocklebloo helped nor the one who was trying to crush rocks into diamonds. Diana wasn't granted four guesses.", "hint": "Note the tasks on the grid were condensed to fit in the spaces provided. (i.e. Rock/Diamond = Crush Rocks into Diamonds, etc.)", "answer": "Arklesblatt, Bianca, stomp string into silk, 6\r\nDinkleberry, Valerie, roll roses into rubies, 4\r\nHaycocklebloo, Katrina, stir broth into myrrh, 3\r\nSneedermon, Diana, crush rocks into diamonds, 5\r\nZizzyrimple, Ione, spin flax into silver, 2", "category": "Logic-Grid", "date": "07/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a rainy night, five gnomish characters huddled on stools at the bar of Rumplestiltskin's Place and told their sad tales. Each had once had the good fortune to come across a beautiful maiden who was desperate to complete a different formidable task to win a king's hand in marriage. Each gnome agreed to help, but only in exchange for the maiden's first born child. Although the women hastily agreed, when the time came to pay their dues, they naturally resisted. Each gnome offered one final bargain. If the maiden could guess his name, she could keep her new born baby. Since each gnome had a rather odd name, he felt safe in offering the maiden a different number of guesses. Each was therefore horrified when he returned to the woman only to hear her promptly and calmly reciting his name! From the information provided, can you determine the name of the gnome who helped each woman and the task she had to complete, as well as the number of guesses each woman was given?\n\r\nGnomes: Arklesblatt, Dinkleberry, Haycocklebloo, Sneedermon, Zizzyrimple\n\r\nWomen: Bianca, Diana, Ione, Katrina, Valerie\n\r\nTask: Crush rocks into diamonds, Roll roses into rubies, Spin flax into silver, Stir broth into myrrh, Stomp string into silk.\n\r\n# of Guesses: 2, 3, 4, 5, 6\n\r\n1. The woman who needed to spin flax into silver (who isn't Diana) didn't negotiate with Haycocklebloo. Dinkleberry didn't give a queen either two or three guesses.\n\r\n2. Queen Katrina was given fewer guesses than the woman helped by Sneedermon (who didn't get either four or six guesses) but more chances than the lady Zizzyrimple assisted.\n\r\n3. Valerie promised the king that she could roll roses into rubies. Neither Arklesblatt nor Haycocklebloo helped either Valerie or Diana. With Zizzyrimple's assistance, Ione won the king's hand in marriage.\n\r\n4. The woman who was given six guesses (who isn't the one Dinkleberry helped) isn't the one who vowed she could stir broth into myrrh.\n\r\n5. Bianca (who wasn't required to spin flax into silver) is neither the woman Haycocklebloo helped nor the one who was trying to crush rocks into diamonds. Diana wasn't granted four guesses.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nArklesblatt, Bianca, stomp string into silk, 6\r\nDinkleberry, Valerie, roll roses into rubies, 4\r\nHaycocklebloo, Katrina, stir broth into myrrh, 3\r\nSneedermon, Diana, crush rocks into diamonds, 5\r\nZizzyrimple, Ione, spin flax into silver, 2\n<|im_start|>answer\nArklesblatt, Bianca, stomp string into silk, 6\r\nDinkleberry, Valerie, roll roses into rubies, 4\r\nHaycocklebloo, Katrina, stir broth into myrrh, 3\r\nSneedermon, Diana, crush rocks into diamonds, 5\r\nZizzyrimple, Ione, spin flax into silver, 2\n<|im_end|>" }, { "id": "#25223", "title": "Harry Potter and the Defeat of the Dark Mark", "fun": 3.08, "difficulty": 1.94, "author": "softparachutes", "desc": "In the final battle against He-Who-Must-Not-Be-Named, Harry Potter, Ron Weasley, Neville Longbottom, Bill Weasley and Draco Malfoy must, in some order, cast one of 5 spells. Additionally, they must cast their spells in sync with their girlfriends to increase the potency of the only tool against Dark Magic: Love. The boys are dating either Cho Chang, Fleur Delacour, Hermione Granger, Ginny Weasley or Luna Lovegood. They each cast one of the following spells: Expelliarmus (disarms opponent), Reparo (repairs an object that is broken), Impendimenta (freezes opponent), Silencio (silences opponent), or Scourgify (cleansing spell). \n\r\n1. Neville doesn't know how to cast a Reparo spell.\n\r\n2. The 5 girls are the one dating Ron, the one who cast first, the one who used the Impendimenta spell, the one dating Harry, and the one who cast third.\n\r\n3. Ron first began to realize just how wonderful his girlfriend, Luna (who is superstitious and therefore won't be the last to cast a spell), was when she was a substitute commentator at a Quidditch game.\n\r\n4. Draco and his girlfriend cast fourth.\n\r\n5. Bill has always been fond of his girlfriend's ability to cast the Scourgify spell, and so chose to cast that spell.\n\r\n6. The five boys are Draco, the one dating Cho, the one who cast second, the one using the Scourgify spell, and the one who cast fifth.\n\r\n7. None of boys cast a spell with the same first initial as their name.\n\r\n8. Hermione is known for her skill in casting an Impendimenta spell, so her date picked that spell to cast.\n\r\n9. Ron thought it would be \"bloody brilliant\" if he could make someone else keep quiet, so he cast the Silencio spell.\n\r\n10. Fleur refused to allow her boyfriend and herself to cast their spell in any place but third, her lucky number.", "hint": "No hint available.", "answer": "Neville is dating Cho, they cast first and used the Expelliarmus spell to disarm Voldemort.\n\r\nRon is dating Luna, they cast second, and used the Silencio spell to keep Voldemort quiet.\n\r\nBill is dating Fleur, they cast third, and used the Scourgify spell to cleanse Voldemort of all his cruel deeds. \n\r\nDraco is dating Hermione, they cast fourth, and used the Impendimenta spell to freeze Voldemort.\n\r\nHarry is dating Ginny, they cast fifth, and used the Reparo spell to repair Voldemort's heart.", "category": "Logic-Grid", "date": "08/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the final battle against He-Who-Must-Not-Be-Named, Harry Potter, Ron Weasley, Neville Longbottom, Bill Weasley and Draco Malfoy must, in some order, cast one of 5 spells. Additionally, they must cast their spells in sync with their girlfriends to increase the potency of the only tool against Dark Magic: Love. The boys are dating either Cho Chang, Fleur Delacour, Hermione Granger, Ginny Weasley or Luna Lovegood. They each cast one of the following spells: Expelliarmus (disarms opponent), Reparo (repairs an object that is broken), Impendimenta (freezes opponent), Silencio (silences opponent), or Scourgify (cleansing spell). \n\r\n1. Neville doesn't know how to cast a Reparo spell.\n\r\n2. The 5 girls are the one dating Ron, the one who cast first, the one who used the Impendimenta spell, the one dating Harry, and the one who cast third.\n\r\n3. Ron first began to realize just how wonderful his girlfriend, Luna (who is superstitious and therefore won't be the last to cast a spell), was when she was a substitute commentator at a Quidditch game.\n\r\n4. Draco and his girlfriend cast fourth.\n\r\n5. Bill has always been fond of his girlfriend's ability to cast the Scourgify spell, and so chose to cast that spell.\n\r\n6. The five boys are Draco, the one dating Cho, the one who cast second, the one using the Scourgify spell, and the one who cast fifth.\n\r\n7. None of boys cast a spell with the same first initial as their name.\n\r\n8. Hermione is known for her skill in casting an Impendimenta spell, so her date picked that spell to cast.\n\r\n9. Ron thought it would be \"bloody brilliant\" if he could make someone else keep quiet, so he cast the Silencio spell.\n\r\n10. Fleur refused to allow her boyfriend and herself to cast their spell in any place but third, her lucky number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNeville is dating Cho, they cast first and used the Expelliarmus spell to disarm Voldemort.\n\r\nRon is dating Luna, they cast second, and used the Silencio spell to keep Voldemort quiet.\n\r\nBill is dating Fleur, they cast third, and used the Scourgify spell to cleanse Voldemort of all his cruel deeds. \n\r\nDraco is dating Hermione, they cast fourth, and used the Impendimenta spell to freeze Voldemort.\n\r\nHarry is dating Ginny, they cast fifth, and used the Reparo spell to repair Voldemort's heart.\n<|im_start|>answer\nNeville is dating Cho, they cast first and used the Expelliarmus spell to disarm Voldemort.\n\r\nRon is dating Luna, they cast second, and used the Silencio spell to keep Voldemort quiet.\n\r\nBill is dating Fleur, they cast third, and used the Scourgify spell to cleanse Voldemort of all his cruel deeds. \n\r\nDraco is dating Hermione, they cast fourth, and used the Impendimenta spell to freeze Voldemort.\n\r\nHarry is dating Ginny, they cast fifth, and used the Reparo spell to repair Voldemort's heart.\n<|im_end|>" }, { "id": "#42318", "title": "A Plot in Thyme", "fun": 3.08, "difficulty": 2.77, "author": "dreamlvr1432", "desc": "Amanda and four of her friends decided to grow their own herbs in the local community garden. Each person grows two different herbs in his/her plot (labeled A-E from left to right) and tends his/her plot on a different day of the week (Monday - Friday). From the info provided, determine each person's garden plot, the herbs they grow (including marjoram and rosemary), and what day they tend their plot.\n\r\n1) No two plots that are tended on consecutive days are located next to each other in the garden. The initials of each herb in a plot, the day the plot is tended, and the owner of the plot are 4 different letters.\n\r\n2) Amanda tends her oregano in plot A. She does not grow thyme.\n\r\n3)The five plots are the one tended by Cassandra (which she tends on Thursdays), the one in which mint grows, the one tended on Tuesdays, the one in which thyme grows, and plot D.\n\r\n4) Marrissa's plot is located to the immediate left of the one containing sage (which is not grown with oregano) and somewhere to the right of the one tended on Thursdays.\n\r\n5) Walter's plot is located immediately between the plot tended on Thursdays (which is not plot A) and the one containing chive and dill, in that order.\n\r\n6) Timmy tends his plot the day before the parsley is tended (not in plot C) and the day after the plot containing basil is tended.", "hint": "No hint available.", "answer": "Plot - Name - Day - Herbs\r\nA, Amanda, Tuesdays, basil/oregano\r\nB, Cassandra, Thursdays, marjoram/parsley\r\nC, Walter, Mondays, thyme/rosemary\r\nD, Marrissa, Fridays, chive/dill\r\nE, Timmy, Wednesdays, sage/mint", "category": "Logic-Grid", "date": "06/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAmanda and four of her friends decided to grow their own herbs in the local community garden. Each person grows two different herbs in his/her plot (labeled A-E from left to right) and tends his/her plot on a different day of the week (Monday - Friday). From the info provided, determine each person's garden plot, the herbs they grow (including marjoram and rosemary), and what day they tend their plot.\n\r\n1) No two plots that are tended on consecutive days are located next to each other in the garden. The initials of each herb in a plot, the day the plot is tended, and the owner of the plot are 4 different letters.\n\r\n2) Amanda tends her oregano in plot A. She does not grow thyme.\n\r\n3)The five plots are the one tended by Cassandra (which she tends on Thursdays), the one in which mint grows, the one tended on Tuesdays, the one in which thyme grows, and plot D.\n\r\n4) Marrissa's plot is located to the immediate left of the one containing sage (which is not grown with oregano) and somewhere to the right of the one tended on Thursdays.\n\r\n5) Walter's plot is located immediately between the plot tended on Thursdays (which is not plot A) and the one containing chive and dill, in that order.\n\r\n6) Timmy tends his plot the day before the parsley is tended (not in plot C) and the day after the plot containing basil is tended.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPlot - Name - Day - Herbs\r\nA, Amanda, Tuesdays, basil/oregano\r\nB, Cassandra, Thursdays, marjoram/parsley\r\nC, Walter, Mondays, thyme/rosemary\r\nD, Marrissa, Fridays, chive/dill\r\nE, Timmy, Wednesdays, sage/mint\n<|im_start|>answer\nPlot - Name - Day - Herbs\r\nA, Amanda, Tuesdays, basil/oregano\r\nB, Cassandra, Thursdays, marjoram/parsley\r\nC, Walter, Mondays, thyme/rosemary\r\nD, Marrissa, Fridays, chive/dill\r\nE, Timmy, Wednesdays, sage/mint\n<|im_end|>" }, { "id": "#26170", "title": "Symbol Minded", "fun": 3.08, "difficulty": 1.57, "author": "tjm531", "desc": "As part of a lesson the Middle Ages, a ninth-grade teacher spent a day teaching about medieval heraldry. To spice things up, he offered extra credit to any student who took the time to research his or her family history. The students' enthusiasm made the lesson a success. From the information provided, can you determine the crest and motto belonging to the family of each student?\n\r\nFirst Names: Fiona, Howard, Missy, Paul, Shannon\n\r\nLast Names: Cole, Killman, Nathanson, Ruff, Zeigler\n\r\nCrest: griffin, helmet, mastiff, rising sun, three stars\n\r\nMotto: Ad Finem Fidelis, Ex Merito, In Veritate Victoria, Omnia Pro Bono, Te Ipsum Nosce\n\r\n1. The family crest of the student surnamed Nathanson (who isn't Shannon) depicts three stars. \n\r\n2. Fiona Kilmann's family crest depicts a rising sun, but isn't the one inscribed with the motto \"Ex Merito\" (which means \"With Merit\").\n\r\n3. Shannon's family's motto is \"In Veritate Victoria\" (which means \"Victory in Truth\"). \n\r\n4. Missy's family's motto is \"Omnia Pro Bono\" (which means \"All Things for Good\"). \n\r\n5. The student surnamed Zeigler isn't the one whose family crest is a helmet.\n\r\n6. Howard Cole's family crest depicts a griffin. \n\r\n7. The crest depicting a mastiff is inscribed with the motto \"Ad Finem Fidelis\" (which means \"Faithful to the End\").", "hint": "Please note that the mottos were shortened on the grid due to the amount of space allowed.", "answer": "Fiona Killman, rising sun, Te Ipsum Nosce\r\nHoward Cole, griffin, Ex Merito\r\nMissy Nathanson, three stars, Omnia Pro Bono\r\nPaul Zeigler, mastiff, Ad Finem Fidelis\r\nShannon Ruff, helmet, In Veritate Victoria", "category": "Logic-Grid", "date": "10/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAs part of a lesson the Middle Ages, a ninth-grade teacher spent a day teaching about medieval heraldry. To spice things up, he offered extra credit to any student who took the time to research his or her family history. The students' enthusiasm made the lesson a success. From the information provided, can you determine the crest and motto belonging to the family of each student?\n\r\nFirst Names: Fiona, Howard, Missy, Paul, Shannon\n\r\nLast Names: Cole, Killman, Nathanson, Ruff, Zeigler\n\r\nCrest: griffin, helmet, mastiff, rising sun, three stars\n\r\nMotto: Ad Finem Fidelis, Ex Merito, In Veritate Victoria, Omnia Pro Bono, Te Ipsum Nosce\n\r\n1. The family crest of the student surnamed Nathanson (who isn't Shannon) depicts three stars. \n\r\n2. Fiona Kilmann's family crest depicts a rising sun, but isn't the one inscribed with the motto \"Ex Merito\" (which means \"With Merit\").\n\r\n3. Shannon's family's motto is \"In Veritate Victoria\" (which means \"Victory in Truth\"). \n\r\n4. Missy's family's motto is \"Omnia Pro Bono\" (which means \"All Things for Good\"). \n\r\n5. The student surnamed Zeigler isn't the one whose family crest is a helmet.\n\r\n6. Howard Cole's family crest depicts a griffin. \n\r\n7. The crest depicting a mastiff is inscribed with the motto \"Ad Finem Fidelis\" (which means \"Faithful to the End\").\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFiona Killman, rising sun, Te Ipsum Nosce\r\nHoward Cole, griffin, Ex Merito\r\nMissy Nathanson, three stars, Omnia Pro Bono\r\nPaul Zeigler, mastiff, Ad Finem Fidelis\r\nShannon Ruff, helmet, In Veritate Victoria\n<|im_start|>answer\nFiona Killman, rising sun, Te Ipsum Nosce\r\nHoward Cole, griffin, Ex Merito\r\nMissy Nathanson, three stars, Omnia Pro Bono\r\nPaul Zeigler, mastiff, Ad Finem Fidelis\r\nShannon Ruff, helmet, In Veritate Victoria\n<|im_end|>" }, { "id": "#50735", "title": "Vacation Troubles", "fun": 3.08, "difficulty": 2.98, "author": "LanceAlot", "desc": "Five friends decided to take their families on a vacation. One night, while the wives and children slept, they snuck down to the hotel bar to reminisce. After many drinks they returned to their rooms, each forgetting something at the bar in the process. The bartender decided to bring the items back to the friends. Help the bartender figure out who the items belong to and where to take them. \n\r\nNote that odd rooms are on one side of the hall and even rooms are on the other.\n\r\n1) Each man had a stumble or two getting to their room, but the one man whose full name is type of liquor had trouble seeing and stumbled a bit more then the rest. \n\r\n2) Either Johnnie's room conjoined with another's, or Mr. Beam lost his phone.\n\r\n3) The men whose rooms conjoined one of the others are; the one who lost his glasses, Mr.Goose, the man in 215, and Jose. \n\r\n4) The men entered the stairwell together, but the one who forgot his jacket climbed one flight alone.\n\r\n5) The man who left his phone could hear Jack's wife on the other side of the wall watching tv. \n\r\n6) Jose's wallet was the first thing to be returned, later the hat was returned to 215, but, due to location, Mr.Daniels was the last person to receive his lost item. \n\r\n7) The man in 216 either lost his wallet or is Mr.Quervo.\n\r\n8) Jim's, Jack's, and Grey's room each ended in an odd number. \n\r\n9) Mr. Walker was in 218.", "hint": "Liquor Brands are (Jim Beam, Jack Daniels, Grey Goose, Johnnie Walker, and Jose Quervo).\n\r\nPay close attention to clue 5 and 3.", "answer": "Jose -> Beam -> Wallet -> 216\r\nGrey -> Daniels -> Jacket -> 355\r\nJim -> Goose -> Cell Phone -> 217\r\nJack -> Quervo -> Hat -> 215\r\nJohnnie -> Walker -> Glasses -> 218", "category": "Logic-Grid", "date": "11/23/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends decided to take their families on a vacation. One night, while the wives and children slept, they snuck down to the hotel bar to reminisce. After many drinks they returned to their rooms, each forgetting something at the bar in the process. The bartender decided to bring the items back to the friends. Help the bartender figure out who the items belong to and where to take them. \n\r\nNote that odd rooms are on one side of the hall and even rooms are on the other.\n\r\n1) Each man had a stumble or two getting to their room, but the one man whose full name is type of liquor had trouble seeing and stumbled a bit more then the rest. \n\r\n2) Either Johnnie's room conjoined with another's, or Mr. Beam lost his phone.\n\r\n3) The men whose rooms conjoined one of the others are; the one who lost his glasses, Mr.Goose, the man in 215, and Jose. \n\r\n4) The men entered the stairwell together, but the one who forgot his jacket climbed one flight alone.\n\r\n5) The man who left his phone could hear Jack's wife on the other side of the wall watching tv. \n\r\n6) Jose's wallet was the first thing to be returned, later the hat was returned to 215, but, due to location, Mr.Daniels was the last person to receive his lost item. \n\r\n7) The man in 216 either lost his wallet or is Mr.Quervo.\n\r\n8) Jim's, Jack's, and Grey's room each ended in an odd number. \n\r\n9) Mr. Walker was in 218.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJose -> Beam -> Wallet -> 216\r\nGrey -> Daniels -> Jacket -> 355\r\nJim -> Goose -> Cell Phone -> 217\r\nJack -> Quervo -> Hat -> 215\r\nJohnnie -> Walker -> Glasses -> 218\n<|im_start|>answer\nJose -> Beam -> Wallet -> 216\r\nGrey -> Daniels -> Jacket -> 355\r\nJim -> Goose -> Cell Phone -> 217\r\nJack -> Quervo -> Hat -> 215\r\nJohnnie -> Walker -> Glasses -> 218\n<|im_end|>" }, { "id": "#50651", "title": "Sailboats", "fun": 3.08, "difficulty": 1.91, "author": "ultimatecub", "desc": "The sailboats have been mixed up. You'll need to work out which sailboat belongs to which owner, the dock numbers, and the lengths of the boats.\n\r\nBoats: Adagio III, Fair Weather, Irish Pride, Petite Palm, White Squid\n\r\nDocks: 6, 8, 16, 19, 28\n\r\nOwners: Ann, Charlie, Hetta, Ivor, Kelly\n\r\nLengths (in ft): 22, 25, 28, 31, 34\n\r\nClues:\n\r\n1. Of the sailboat at Dock 16 and Charlie's boat, one is the Petite Palm and the other is the White Squid.\r\n2. The Fair Weather isn't moored at Dock 19.\r\n3. The White Squid is 9 feet shorter than the Irish Pride.\r\n4. The boat at Dock 19 is either Charlie's boat or Ivor's boat.\r\n5. The five boats are the Petite Palm, the sailboat at Dock 8, the 28 ft boat, the 25 ft boat and Kelly's sailboat.\r\n6. The 22 ft vessel is owned by Kelly.\r\n7. The Irish Pride isn't owned by Hetta.\r\n8. The 28 ft vessel isn't moored at Dock 6.\r\n9. The Adagio III is 3 feet longer than Kelly's sailboat.\r\n10. The 34 ft vessel isn't moored at Dock 19.", "hint": "If Dock 8 and 28 ft are different, Dock 8 cannot be equal to 28 ft.", "answer": "Adagio III, 25 ft, Ivor, Dock 19\r\nFair Weather, 28 ft, Hetta, Dock 28\r\nIrish Pride, 31 ft, Ann, Dock 8\r\nPetite Palm, 34 ft, Charlie, Dock 6 \r\nWhite Squid, 22 ft, Kelly, Dock 16", "category": "Logic-Grid", "date": "07/19/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe sailboats have been mixed up. You'll need to work out which sailboat belongs to which owner, the dock numbers, and the lengths of the boats.\n\r\nBoats: Adagio III, Fair Weather, Irish Pride, Petite Palm, White Squid\n\r\nDocks: 6, 8, 16, 19, 28\n\r\nOwners: Ann, Charlie, Hetta, Ivor, Kelly\n\r\nLengths (in ft): 22, 25, 28, 31, 34\n\r\nClues:\n\r\n1. Of the sailboat at Dock 16 and Charlie's boat, one is the Petite Palm and the other is the White Squid.\r\n2. The Fair Weather isn't moored at Dock 19.\r\n3. The White Squid is 9 feet shorter than the Irish Pride.\r\n4. The boat at Dock 19 is either Charlie's boat or Ivor's boat.\r\n5. The five boats are the Petite Palm, the sailboat at Dock 8, the 28 ft boat, the 25 ft boat and Kelly's sailboat.\r\n6. The 22 ft vessel is owned by Kelly.\r\n7. The Irish Pride isn't owned by Hetta.\r\n8. The 28 ft vessel isn't moored at Dock 6.\r\n9. The Adagio III is 3 feet longer than Kelly's sailboat.\r\n10. The 34 ft vessel isn't moored at Dock 19.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdagio III, 25 ft, Ivor, Dock 19\r\nFair Weather, 28 ft, Hetta, Dock 28\r\nIrish Pride, 31 ft, Ann, Dock 8\r\nPetite Palm, 34 ft, Charlie, Dock 6 \r\nWhite Squid, 22 ft, Kelly, Dock 16\n<|im_start|>answer\nAdagio III, 25 ft, Ivor, Dock 19\r\nFair Weather, 28 ft, Hetta, Dock 28\r\nIrish Pride, 31 ft, Ann, Dock 8\r\nPetite Palm, 34 ft, Charlie, Dock 6 \r\nWhite Squid, 22 ft, Kelly, Dock 16\n<|im_end|>" }, { "id": "#27616", "title": "Busy But Caring", "fun": 3.08, "difficulty": 1.97, "author": "Winner4600", "desc": "Martha, Joanna, Kelley, Patricia, and Suzanne are five busy mothers who barely have time to sit down and eat. One Christmas, they each decided to make (or bake) their son a gift. Can you figure out the full name of each mother, their profession, their son's name, and the gift sent by each?\n\r\n1. The five mothers are Mrs. Baker, Ben's mom, Joanna, the doctor, and the one who made mittens.\r\n2. Justin Glen loved the cupcakes baked by his mother, the doctor.\r\n3. The scarf was made by the editor, while the mittens were made by the programmer.\r\n4. Kelley Austen is the lawyer.\r\n5. The 5 sons are Kyle, the boy for whom the apple pie was baked, Todd Haney, the editor's son, and Martha Glen's son.\r\n6. Patricia Haney is a programmer, but Joanna is not the editor.", "hint": "No hint available.", "answer": "Martha Glen-Doctor-Justin-cupcakes\r\nJoanna Robinson-Teacher-Kyle-sweater\r\nKelley Austen-Lawyer-Ben-apple pie\r\nPatricia Haney-Programmer-Todd-mittens\r\nSuzanne Baker-Editor-Cody-scarf", "category": "Logic-Grid", "date": "12/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMartha, Joanna, Kelley, Patricia, and Suzanne are five busy mothers who barely have time to sit down and eat. One Christmas, they each decided to make (or bake) their son a gift. Can you figure out the full name of each mother, their profession, their son's name, and the gift sent by each?\n\r\n1. The five mothers are Mrs. Baker, Ben's mom, Joanna, the doctor, and the one who made mittens.\r\n2. Justin Glen loved the cupcakes baked by his mother, the doctor.\r\n3. The scarf was made by the editor, while the mittens were made by the programmer.\r\n4. Kelley Austen is the lawyer.\r\n5. The 5 sons are Kyle, the boy for whom the apple pie was baked, Todd Haney, the editor's son, and Martha Glen's son.\r\n6. Patricia Haney is a programmer, but Joanna is not the editor.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMartha Glen-Doctor-Justin-cupcakes\r\nJoanna Robinson-Teacher-Kyle-sweater\r\nKelley Austen-Lawyer-Ben-apple pie\r\nPatricia Haney-Programmer-Todd-mittens\r\nSuzanne Baker-Editor-Cody-scarf\n<|im_start|>answer\nMartha Glen-Doctor-Justin-cupcakes\r\nJoanna Robinson-Teacher-Kyle-sweater\r\nKelley Austen-Lawyer-Ben-apple pie\r\nPatricia Haney-Programmer-Todd-mittens\r\nSuzanne Baker-Editor-Cody-scarf\n<|im_end|>" }, { "id": "#26459", "title": "As Different As Can Be...", "fun": 3.08, "difficulty": 1.66, "author": "Winner4600", "desc": "Sandra is one of five sisters, all of different ages. They each have a unique interest and favorite color. On top of that, the 5 girls all like a different food! Their parents are hopelessly confused as to what each girl likes, but they DO know some facts. Help them remember who's who from the following clues:\n\n\r\n1. The tennis racket belongs to the 10-year-old.\n\r\n2. Belinda loves her violin, which she started playing when she was 4.\n\r\n3. The 5 girls are: Loren, the cat-lover, the 6-year-old, Jenny, and the one who likes purple.\n\r\n4. Miriam is only allowed to have one cat, partly because Jenny is afraid any more will scare away her many boyfriends.\n\r\n5. The family Picasso, Loren, is said to be going through her \"Blue Period\" - everything she owns is blue!\n\r\n6. Many of Loren's paintings have been created while eating ice cream, her favorite food.\n\r\n7. The 3-year-old still eats applesauce, but the 6-year-old likes her newly discovered snack, chips, better.\n\r\n8. Jenny found she liked salad, after an attempt to go on a diet.\n\r\n9. Belinda thinks she plays better in orange surroundings, but the 13-year-old likes pink better.", "hint": "No hint available.", "answer": "GIRL-AGE-INTEREST-COLOR-FOOD\n\r\nSandra-10-tennis-purple-macaroni\r\nMiriam-3-cats-green-applesauce\r\nJenny-13-boys-pink-salad\r\nLoren-8-art-blue-ice cream\r\nBelinda-6-music-orange-chips", "category": "Logic-Grid", "date": "10/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSandra is one of five sisters, all of different ages. They each have a unique interest and favorite color. On top of that, the 5 girls all like a different food! Their parents are hopelessly confused as to what each girl likes, but they DO know some facts. Help them remember who's who from the following clues:\n\n\r\n1. The tennis racket belongs to the 10-year-old.\n\r\n2. Belinda loves her violin, which she started playing when she was 4.\n\r\n3. The 5 girls are: Loren, the cat-lover, the 6-year-old, Jenny, and the one who likes purple.\n\r\n4. Miriam is only allowed to have one cat, partly because Jenny is afraid any more will scare away her many boyfriends.\n\r\n5. The family Picasso, Loren, is said to be going through her \"Blue Period\" - everything she owns is blue!\n\r\n6. Many of Loren's paintings have been created while eating ice cream, her favorite food.\n\r\n7. The 3-year-old still eats applesauce, but the 6-year-old likes her newly discovered snack, chips, better.\n\r\n8. Jenny found she liked salad, after an attempt to go on a diet.\n\r\n9. Belinda thinks she plays better in orange surroundings, but the 13-year-old likes pink better.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGIRL-AGE-INTEREST-COLOR-FOOD\n\r\nSandra-10-tennis-purple-macaroni\r\nMiriam-3-cats-green-applesauce\r\nJenny-13-boys-pink-salad\r\nLoren-8-art-blue-ice cream\r\nBelinda-6-music-orange-chips\n<|im_start|>answer\nGIRL-AGE-INTEREST-COLOR-FOOD\n\r\nSandra-10-tennis-purple-macaroni\r\nMiriam-3-cats-green-applesauce\r\nJenny-13-boys-pink-salad\r\nLoren-8-art-blue-ice cream\r\nBelinda-6-music-orange-chips\n<|im_end|>" }, { "id": "#29161", "title": "Movie Night", "fun": 3.08, "difficulty": 2.12, "author": "aprilsprings29", "desc": "Finally! A night out without the kids! Five couples went to the movie theater, and each couple watched a movie of a different genre, shared a snack, and then returned home at a different time. Can you figure out who is husband and wife, the snack they shared, the genre they saw, and what time they came home?\n\r\nWives: Theresa, Rochelle, Nikki, Anne, and Chanice\r\nHusbands: Danny, Sam, Max, Kevin and Rick\r\nSnack: Popcorn, Hotdog, Pizza, Nachos, and M&Ms\r\nMovie Genre: Comedy, Action, Horror, Sci-Fi, and Romance\r\nTime: 8:00, 8:30, 9:00, 10:00, and 11:30 \n\r\n1) The couple that saw the action movie shared nachos.\r\n2) It was almost midnight by the time Anne and Sam came home.\r\n3) Rochelle hates sci-fi, but saw it with her husband anyways.\r\n4) The couple that shared popcorn didn't see a horror movie or an action movie.\r\n5) Theresa arrived at home an hour after Max and his wife.\r\n6) The movie was so funny, Nikki almost choked on her hotdog, she was laughing so hard.\r\n7) Danny chose not to see an action movie or sci-fi.\r\n8) The five women were: Chanice, the one who shared a bag of M&Ms with her husband, the lady who saw the comedy, the woman that came home at 8:00 and Kevin's wife.\r\n9) The horror movie didn't start until 8:30.\r\n10) Max and his wife came home the earliest.\r\n11) Theresa thought her movie went a little overboard with the explosions and gunfights.\r\n12) Chanice, who saw the horror movie, came out of the theater petrified and her husband, who wasn't Danny, had to calm her down.", "hint": "Theresa saw the action movie.", "answer": "Theresa and Kevin - Nachos - Action - 9:00\r\nRochelle and Max - Popcorn - Sci-Fi -8:00\r\nNikki and Danny - Hotdog - Comedy - 8:30\r\nAnne and Sam - M&Ms - Romance - 11:30\r\nChanice and Rick- Pizza - Horror -10:00", "category": "Logic-Grid", "date": "03/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFinally! A night out without the kids! Five couples went to the movie theater, and each couple watched a movie of a different genre, shared a snack, and then returned home at a different time. Can you figure out who is husband and wife, the snack they shared, the genre they saw, and what time they came home?\n\r\nWives: Theresa, Rochelle, Nikki, Anne, and Chanice\r\nHusbands: Danny, Sam, Max, Kevin and Rick\r\nSnack: Popcorn, Hotdog, Pizza, Nachos, and M&Ms\r\nMovie Genre: Comedy, Action, Horror, Sci-Fi, and Romance\r\nTime: 8:00, 8:30, 9:00, 10:00, and 11:30 \n\r\n1) The couple that saw the action movie shared nachos.\r\n2) It was almost midnight by the time Anne and Sam came home.\r\n3) Rochelle hates sci-fi, but saw it with her husband anyways.\r\n4) The couple that shared popcorn didn't see a horror movie or an action movie.\r\n5) Theresa arrived at home an hour after Max and his wife.\r\n6) The movie was so funny, Nikki almost choked on her hotdog, she was laughing so hard.\r\n7) Danny chose not to see an action movie or sci-fi.\r\n8) The five women were: Chanice, the one who shared a bag of M&Ms with her husband, the lady who saw the comedy, the woman that came home at 8:00 and Kevin's wife.\r\n9) The horror movie didn't start until 8:30.\r\n10) Max and his wife came home the earliest.\r\n11) Theresa thought her movie went a little overboard with the explosions and gunfights.\r\n12) Chanice, who saw the horror movie, came out of the theater petrified and her husband, who wasn't Danny, had to calm her down.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTheresa and Kevin - Nachos - Action - 9:00\r\nRochelle and Max - Popcorn - Sci-Fi -8:00\r\nNikki and Danny - Hotdog - Comedy - 8:30\r\nAnne and Sam - M&Ms - Romance - 11:30\r\nChanice and Rick- Pizza - Horror -10:00\n<|im_start|>answer\nTheresa and Kevin - Nachos - Action - 9:00\r\nRochelle and Max - Popcorn - Sci-Fi -8:00\r\nNikki and Danny - Hotdog - Comedy - 8:30\r\nAnne and Sam - M&Ms - Romance - 11:30\r\nChanice and Rick- Pizza - Horror -10:00\n<|im_end|>" }, { "id": "#602", "title": "Einstein's Riddle", "fun": 3.07, "difficulty": 3.04, "author": "link2440", "desc": "Einstein's Riddle:\r\nEinstein wrote the following riddle. He said that 98% of the world could not solve it. But several NIEHS scientists were able to solve it, and they said it's not all that hard if you pay attention and are very patient. Give it a try:\n\r\nThere are 5 houses in 5 different colors in a row. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage. Other facts:\r\n1.\tThe Brit lives in the red house. \r\n2.\tThe Swede keeps dogs as pets. \r\n3.\tThe Dane drinks tea. \r\n4.\tThe green house is on the immediate left of the white house. \r\n5.\tThe green house's owner drinks coffee. \r\n6.\tThe owner who smokes Pall Mall rears birds. \r\n7.\tThe owner of the yellow house smokes Dunhill. \r\n8.\tThe owner living in the center house drinks milk. \r\n9.\tThe Norwegian lives in the first house. \r\n10.\tThe owner who smokes Blends lives next to the one who keeps cats. \r\n11.\tThe owner who keeps the horse lives next to the one who smokes Dunhill. \r\n12.\tThe owner who smokes Bluemasters drinks beer. \r\n13.\tThe German smokes Prince. \r\n14.\tThe Norwegian lives next to the blue house. \r\n15.\tThe owner who smokes Blends lives next to the one who drinks water. \n\n\r\nThe question is: WHO OWNS THE FISH?", "hint": "Just take your time. This one should take you some time and is probably one of the harder riddles you see.", "answer": "The German sits in his Green House, smoking his Prince cigars, drinking coffee, and watching his FISH.\n\r\nThe rest go like this-\r\n1st House: Yellow, Norwegian, Water, Cats, Dunhill\r\n2nd House: Blue, Dane, Tea, Horse, Blends\r\n3rd House: Red, Brit, Milk, Birds, Pall Malls\r\n4th House: Green, German, Coffee, FISH, Prince\r\n5th House: White, Swede, Beer, Dogs, Bluemasters", "category": "Logic", "date": "06/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEinstein's Riddle:\r\nEinstein wrote the following riddle. He said that 98% of the world could not solve it. But several NIEHS scientists were able to solve it, and they said it's not all that hard if you pay attention and are very patient. Give it a try:\n\r\nThere are 5 houses in 5 different colors in a row. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage. Other facts:\r\n1.\tThe Brit lives in the red house. \r\n2.\tThe Swede keeps dogs as pets. \r\n3.\tThe Dane drinks tea. \r\n4.\tThe green house is on the immediate left of the white house. \r\n5.\tThe green house's owner drinks coffee. \r\n6.\tThe owner who smokes Pall Mall rears birds. \r\n7.\tThe owner of the yellow house smokes Dunhill. \r\n8.\tThe owner living in the center house drinks milk. \r\n9.\tThe Norwegian lives in the first house. \r\n10.\tThe owner who smokes Blends lives next to the one who keeps cats. \r\n11.\tThe owner who keeps the horse lives next to the one who smokes Dunhill. \r\n12.\tThe owner who smokes Bluemasters drinks beer. \r\n13.\tThe German smokes Prince. \r\n14.\tThe Norwegian lives next to the blue house. \r\n15.\tThe owner who smokes Blends lives next to the one who drinks water. \n\n\r\nThe question is: WHO OWNS THE FISH?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe German sits in his Green House, smoking his Prince cigars, drinking coffee, and watching his FISH.\n\r\nThe rest go like this-\r\n1st House: Yellow, Norwegian, Water, Cats, Dunhill\r\n2nd House: Blue, Dane, Tea, Horse, Blends\r\n3rd House: Red, Brit, Milk, Birds, Pall Malls\r\n4th House: Green, German, Coffee, FISH, Prince\r\n5th House: White, Swede, Beer, Dogs, Bluemasters\n<|im_start|>answer\nThe German sits in his Green House, smoking his Prince cigars, drinking coffee, and watching his FISH.\n\r\nThe rest go like this-\r\n1st House: Yellow, Norwegian, Water, Cats, Dunhill\r\n2nd House: Blue, Dane, Tea, Horse, Blends\r\n3rd House: Red, Brit, Milk, Birds, Pall Malls\r\n4th House: Green, German, Coffee, FISH, Prince\r\n5th House: White, Swede, Beer, Dogs, Bluemasters\n<|im_end|>" }, { "id": "#52106", "title": "The Troll Bridge 1", "fun": 3.07, "difficulty": 2.38, "author": "wimpykidfan37", "desc": "A bridge was guarded by an evil troll. The troll was very intelligent, but he was also a coward. He was afraid of anyone smarter than him. So every time anyone tried to cross the bridge, the troll would set up a test. If the traveler passed the test, he would be allowed to cross. Otherwise, the troll would eat him.\n\r\nThree travelers, Al, Ben and Carl, came across the bridge. The troll told them, \"You may only cross my bridge if you know the password.\" He wrote five three-letter words on a rock. The five words were HOE, OAR, PAD, TOE, and VAT. \n\r\nHe then said, \"I will tell each of you a different letter from the password. If you know what the password is, I will let you pass. But don't tell anyone else your letter.\" He then whispered a letter from the password to each traveler so that neither of the other two could hear him. \n\r\nThen the troll asked Al, \"Do you know what the password is?\" \"Yes,\" said Al, and the troll let him pass.\n\r\nThen the troll asked Ben, \"Do you know what the password is?\" \"Yes,\" said Ben, and the troll let him pass.\n\r\nThen the troll asked Carl, \"Do you know what the password is?\" \"Yes,\" said Carl, and the troll let him pass.\n\r\nSo, what is the password?", "hint": "1. Ben used Al's answer, and Carl used both Al's and Ben's answers.\n\r\n2. Al's letter could not have been E.", "answer": "The password was HOE.\n\r\nThe only letters unique to one of the five words were D, H, P, R, and V. One of these letters must have been Al's, since he could determine the password. The only word without any of these letters is TOE. So the password could not have been TOE.\n\r\nBen knew this and now had four words to think of. The only letters unique to one word were D, E, H, P, R, T, and V. The password must have contained at least two unique letters, one for Al and the other for Ben, since they were both able to determine the password. The only word with only one of these letters was OAR. So OAR could not have been the password. \n\r\nCarl knew this and now had three words to think of. The only letters unique to one word were D, E, H, O, P, T, and V. The password must have included three of these letters, since all three were able to determine the password. The only one of the three words containing three such letters was HOE, so this must have been the password.", "category": "Logic", "date": "12/30/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bridge was guarded by an evil troll. The troll was very intelligent, but he was also a coward. He was afraid of anyone smarter than him. So every time anyone tried to cross the bridge, the troll would set up a test. If the traveler passed the test, he would be allowed to cross. Otherwise, the troll would eat him.\n\r\nThree travelers, Al, Ben and Carl, came across the bridge. The troll told them, \"You may only cross my bridge if you know the password.\" He wrote five three-letter words on a rock. The five words were HOE, OAR, PAD, TOE, and VAT. \n\r\nHe then said, \"I will tell each of you a different letter from the password. If you know what the password is, I will let you pass. But don't tell anyone else your letter.\" He then whispered a letter from the password to each traveler so that neither of the other two could hear him. \n\r\nThen the troll asked Al, \"Do you know what the password is?\" \"Yes,\" said Al, and the troll let him pass.\n\r\nThen the troll asked Ben, \"Do you know what the password is?\" \"Yes,\" said Ben, and the troll let him pass.\n\r\nThen the troll asked Carl, \"Do you know what the password is?\" \"Yes,\" said Carl, and the troll let him pass.\n\r\nSo, what is the password?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe password was HOE.\n\r\nThe only letters unique to one of the five words were D, H, P, R, and V. One of these letters must have been Al's, since he could determine the password. The only word without any of these letters is TOE. So the password could not have been TOE.\n\r\nBen knew this and now had four words to think of. The only letters unique to one word were D, E, H, P, R, T, and V. The password must have contained at least two unique letters, one for Al and the other for Ben, since they were both able to determine the password. The only word with only one of these letters was OAR. So OAR could not have been the password. \n\r\nCarl knew this and now had three words to think of. The only letters unique to one word were D, E, H, O, P, T, and V. The password must have included three of these letters, since all three were able to determine the password. The only one of the three words containing three such letters was HOE, so this must have been the password.\n<|im_start|>answer\nThe password was HOE.\n\r\nThe only letters unique to one of the five words were D, H, P, R, and V. One of these letters must have been Al's, since he could determine the password. The only word without any of these letters is TOE. So the password could not have been TOE.\n\r\nBen knew this and now had four words to think of. The only letters unique to one word were D, E, H, P, R, T, and V. The password must have contained at least two unique letters, one for Al and the other for Ben, since they were both able to determine the password. The only word with only one of these letters was OAR. So OAR could not have been the password. \n\r\nCarl knew this and now had three words to think of. The only letters unique to one word were D, E, H, O, P, T, and V. The password must have included three of these letters, since all three were able to determine the password. The only one of the three words containing three such letters was HOE, so this must have been the password.\n<|im_end|>" }, { "id": "#3012", "title": "Timepieces", "fun": 3.07, "difficulty": 2.11, "author": "PeaceJo", "desc": "A sundial is a timepiece that has the fewest number of moving parts. Which timepiece has the most moving parts?", "hint": "No hint available.", "answer": "An Hourglass", "category": "Logic", "date": "03/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA sundial is a timepiece that has the fewest number of moving parts. Which timepiece has the most moving parts?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAn Hourglass\n<|im_start|>answer\nAn Hourglass\n<|im_end|>" }, { "id": "#27384", "title": "Prime Time TV", "fun": 3.07, "difficulty": 2.09, "author": "rose_rox", "desc": "THIS WEEK... It's sweeps week! Five major television networks battle it out every Wednesday night on prime time TV for television dominance. These networks skillfully, or not so skillfully, play out their best advertising strategies to grab as many viewers as possible for their 8 pm time slot. Who will win?!!? TO BE REVEALED IN THE NEXT TEASER....\n\r\nActually, just figure out the shows that the networks aired, what the advertising strategy was for each, how many people watched (ratings), and the genres of these shows.\n\r\nNetworks: ROX, The WC, MBC, 123, TWTV\n\r\nContenders: \"Loss\", \"Smalltown\", \"Crime Scene Inventory\", \"During Prison Break\", and \"The Octopus\"\n\r\nGenres: drama, sci-fi, comedy, reality, animated\n\r\nNo. of viewers: 13 million, 10.4 million, 5.5 million, 3.8 million, 1.2 million\n\r\nAdvertising strategies: magazine ads, promotional giveaways, special guest stars, lots of explosions, billboard ads\n\r\nClues:\r\nThe WC aired the animated series.\n\r\n\"Smalltown\" had greater ratings than \"The Octopus\". However, it did NOT receive the highest ratings.\n\r\nPromotional giveaways were distributed by the 123 network.\n\r\nExplosions were watched by 3.8 million viewers.\n\r\n\"Crime Scene Inventory\" is a sci-fi show.\n\r\nThe reality show did very poorly once again, receiving the lowest ratings.\n\r\nBillboard ads drew in 10.4 million viewers.\n\r\nMBC was able to book very famous celebrities for an episode of their comedy.\n\r\nThe loveable 2-D characters of \"Loss\" were pasted inside every magazine.\n\r\n\"During Prison Break\" is not a reality show.\n\r\nThe studio audience of \"Smalltown\" was in fits of laughter.\n\r\nROX came in second in the ratings.\n\r\nAbout half of the 1.2 million viewers that tuned into this show were drawn in by promotional giveaways.\n\r\nTWTV, that did not air the drama or reality series, was followed by 123 in the ratings.", "hint": "No hint available.", "answer": "The ROX network played a very intense episode of the drama \"During Prison Break\", in which our favourite cell dwellers went through the physically and emotionally demanding task of community service. This was advertised on billboards everywhere, and an impressive 10.4 million people watched.\n\r\nThe WC aired the ever popular \"Loss\", the animated series about seagulls lost at sea. No real surprise as is takes the lead with 13 million viewers this week. The WC ran an ad campaign for \"Loss\" in many popular magazines.\n\r\nMBC's never disappointing comedy, \"Smalltown\", may have been a bit disappointing with only 5.5 million viewers, a sub-average score for the network. Too bad! Special guest stars Rose Welling and Tom Kent had amazing chemistry.\n\r\n123 aired the fan favourite reality tv show \"The Octopus\". Ratings have been steadily declining, evident by this week's measly 1.2 million. Looks like the free promo cards didn't do much.\n\r\nTWTV original series \"Crime Scene Inventory\" came in second to last with 3.8 million viewers. The action-packed sci-fi series had a combustible too many that screamed desperate for ratings.", "category": "Logic-Grid", "date": "12/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTHIS WEEK... It's sweeps week! Five major television networks battle it out every Wednesday night on prime time TV for television dominance. These networks skillfully, or not so skillfully, play out their best advertising strategies to grab as many viewers as possible for their 8 pm time slot. Who will win?!!? TO BE REVEALED IN THE NEXT TEASER....\n\r\nActually, just figure out the shows that the networks aired, what the advertising strategy was for each, how many people watched (ratings), and the genres of these shows.\n\r\nNetworks: ROX, The WC, MBC, 123, TWTV\n\r\nContenders: \"Loss\", \"Smalltown\", \"Crime Scene Inventory\", \"During Prison Break\", and \"The Octopus\"\n\r\nGenres: drama, sci-fi, comedy, reality, animated\n\r\nNo. of viewers: 13 million, 10.4 million, 5.5 million, 3.8 million, 1.2 million\n\r\nAdvertising strategies: magazine ads, promotional giveaways, special guest stars, lots of explosions, billboard ads\n\r\nClues:\r\nThe WC aired the animated series.\n\r\n\"Smalltown\" had greater ratings than \"The Octopus\". However, it did NOT receive the highest ratings.\n\r\nPromotional giveaways were distributed by the 123 network.\n\r\nExplosions were watched by 3.8 million viewers.\n\r\n\"Crime Scene Inventory\" is a sci-fi show.\n\r\nThe reality show did very poorly once again, receiving the lowest ratings.\n\r\nBillboard ads drew in 10.4 million viewers.\n\r\nMBC was able to book very famous celebrities for an episode of their comedy.\n\r\nThe loveable 2-D characters of \"Loss\" were pasted inside every magazine.\n\r\n\"During Prison Break\" is not a reality show.\n\r\nThe studio audience of \"Smalltown\" was in fits of laughter.\n\r\nROX came in second in the ratings.\n\r\nAbout half of the 1.2 million viewers that tuned into this show were drawn in by promotional giveaways.\n\r\nTWTV, that did not air the drama or reality series, was followed by 123 in the ratings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ROX network played a very intense episode of the drama \"During Prison Break\", in which our favourite cell dwellers went through the physically and emotionally demanding task of community service. This was advertised on billboards everywhere, and an impressive 10.4 million people watched.\n\r\nThe WC aired the ever popular \"Loss\", the animated series about seagulls lost at sea. No real surprise as is takes the lead with 13 million viewers this week. The WC ran an ad campaign for \"Loss\" in many popular magazines.\n\r\nMBC's never disappointing comedy, \"Smalltown\", may have been a bit disappointing with only 5.5 million viewers, a sub-average score for the network. Too bad! Special guest stars Rose Welling and Tom Kent had amazing chemistry.\n\r\n123 aired the fan favourite reality tv show \"The Octopus\". Ratings have been steadily declining, evident by this week's measly 1.2 million. Looks like the free promo cards didn't do much.\n\r\nTWTV original series \"Crime Scene Inventory\" came in second to last with 3.8 million viewers. The action-packed sci-fi series had a combustible too many that screamed desperate for ratings.\n<|im_start|>answer\nThe ROX network played a very intense episode of the drama \"During Prison Break\", in which our favourite cell dwellers went through the physically and emotionally demanding task of community service. This was advertised on billboards everywhere, and an impressive 10.4 million people watched.\n\r\nThe WC aired the ever popular \"Loss\", the animated series about seagulls lost at sea. No real surprise as is takes the lead with 13 million viewers this week. The WC ran an ad campaign for \"Loss\" in many popular magazines.\n\r\nMBC's never disappointing comedy, \"Smalltown\", may have been a bit disappointing with only 5.5 million viewers, a sub-average score for the network. Too bad! Special guest stars Rose Welling and Tom Kent had amazing chemistry.\n\r\n123 aired the fan favourite reality tv show \"The Octopus\". Ratings have been steadily declining, evident by this week's measly 1.2 million. Looks like the free promo cards didn't do much.\n\r\nTWTV original series \"Crime Scene Inventory\" came in second to last with 3.8 million viewers. The action-packed sci-fi series had a combustible too many that screamed desperate for ratings.\n<|im_end|>" }, { "id": "#9026", "title": "Survival of the Sheep", "fun": 3.07, "difficulty": 2.55, "author": "sakirski", "desc": "There is an island filled with grass and trees and plants. The only inhabitants are 100 lions and 1 sheep. \r\nThe lions are special: \r\n1) They are infinitely logical, smart, and completely aware of their surroundings.\r\n2) They can survive by just eating grass (and there is an infinite amount of grass on the island).\r\n3) They prefer of course to eat sheep.\r\n4) Their only food options are grass or sheep.\n\r\nNow, here's the kicker:\n\r\n5) If a lion eats a sheep he TURNS into a sheep (and could then be eaten by other lions).\r\n6) A lion would rather eat grass all his life than be eaten by another lion (after he turned into a sheep).\n\r\nAssumptions:\r\n1) Assume that one lion is closest to the sheep and will get to it before all others. Assume that there is never an issue with who gets to the sheep first. The issue is whether the first lion will get eaten by other lions afterwards or not.\r\n2) The sheep cannot get away from the lion if the lion decides to eat it.\r\n3) Do not assume anything that hasn't been stated above.\n\r\nSo now the question:\r\nWill that one sheep get eaten or not and why?", "hint": "There are two hints. The first one will really be just that - a small hint. The second one is a BIG one, and could very well give it away, so don't read it if you don't want to: \n\r\nHint 1) Use math induction. \r\nHint 2) Consider the scenario where there is only one lion and one sheep. What would happen? Now take the next step.", "answer": "The sheep would remain untouched. \n\r\nIn fact, the sheep would remain untouched if there is an even number of lions on the island, and would be eaten immediately if there is an odd number of lions on the island. \n\r\nHere's the reasoning:\r\nConsider a scenario with just one lion and one sheep: The lion will eat the sheep. Why? Because after he eats it and turns into a sheep himself, there aren't any lions on the island to eat him, so he is happy.\n\r\nNow look at a scenario with 2 lions and 1 sheep. Here the sheep would remain unharmed. Why? Because if any one of them eats it, and turns into a sheep himself, he knows that he awaits certain death because he will then be a sheep and the other lion will be the only lion on the island and nothing will stop him from eating the sheep. \n\r\nSo now we know for a fact 1 lion and 1 sheep - sheep gets eaten. 2 lions and 1 sheep - sheep doesn't get eaten. \r\nWe can now make a conclusion about 3 lions and 1 sheep: the sheep will definitely be eaten, because the lion that eats it will know that by eating he leaves behind 2 lions and 1 sheep (himself). And as we already know 2 lions and 1 sheep is a situation where the sheep survives.\n\r\nYou can use the same logic to go on to 4 lions and 1 sheep, and then all the way to 100 or 1000, but it will always be true that with an odd number of lions the sheep gets eaten and with an even number the sheep doesn't.", "category": "Logic", "date": "12/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is an island filled with grass and trees and plants. The only inhabitants are 100 lions and 1 sheep. \r\nThe lions are special: \r\n1) They are infinitely logical, smart, and completely aware of their surroundings.\r\n2) They can survive by just eating grass (and there is an infinite amount of grass on the island).\r\n3) They prefer of course to eat sheep.\r\n4) Their only food options are grass or sheep.\n\r\nNow, here's the kicker:\n\r\n5) If a lion eats a sheep he TURNS into a sheep (and could then be eaten by other lions).\r\n6) A lion would rather eat grass all his life than be eaten by another lion (after he turned into a sheep).\n\r\nAssumptions:\r\n1) Assume that one lion is closest to the sheep and will get to it before all others. Assume that there is never an issue with who gets to the sheep first. The issue is whether the first lion will get eaten by other lions afterwards or not.\r\n2) The sheep cannot get away from the lion if the lion decides to eat it.\r\n3) Do not assume anything that hasn't been stated above.\n\r\nSo now the question:\r\nWill that one sheep get eaten or not and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe sheep would remain untouched. \n\r\nIn fact, the sheep would remain untouched if there is an even number of lions on the island, and would be eaten immediately if there is an odd number of lions on the island. \n\r\nHere's the reasoning:\r\nConsider a scenario with just one lion and one sheep: The lion will eat the sheep. Why? Because after he eats it and turns into a sheep himself, there aren't any lions on the island to eat him, so he is happy.\n\r\nNow look at a scenario with 2 lions and 1 sheep. Here the sheep would remain unharmed. Why? Because if any one of them eats it, and turns into a sheep himself, he knows that he awaits certain death because he will then be a sheep and the other lion will be the only lion on the island and nothing will stop him from eating the sheep. \n\r\nSo now we know for a fact 1 lion and 1 sheep - sheep gets eaten. 2 lions and 1 sheep - sheep doesn't get eaten. \r\nWe can now make a conclusion about 3 lions and 1 sheep: the sheep will definitely be eaten, because the lion that eats it will know that by eating he leaves behind 2 lions and 1 sheep (himself). And as we already know 2 lions and 1 sheep is a situation where the sheep survives.\n\r\nYou can use the same logic to go on to 4 lions and 1 sheep, and then all the way to 100 or 1000, but it will always be true that with an odd number of lions the sheep gets eaten and with an even number the sheep doesn't.\n<|im_start|>answer\nThe sheep would remain untouched. \n\r\nIn fact, the sheep would remain untouched if there is an even number of lions on the island, and would be eaten immediately if there is an odd number of lions on the island. \n\r\nHere's the reasoning:\r\nConsider a scenario with just one lion and one sheep: The lion will eat the sheep. Why? Because after he eats it and turns into a sheep himself, there aren't any lions on the island to eat him, so he is happy.\n\r\nNow look at a scenario with 2 lions and 1 sheep. Here the sheep would remain unharmed. Why? Because if any one of them eats it, and turns into a sheep himself, he knows that he awaits certain death because he will then be a sheep and the other lion will be the only lion on the island and nothing will stop him from eating the sheep. \n\r\nSo now we know for a fact 1 lion and 1 sheep - sheep gets eaten. 2 lions and 1 sheep - sheep doesn't get eaten. \r\nWe can now make a conclusion about 3 lions and 1 sheep: the sheep will definitely be eaten, because the lion that eats it will know that by eating he leaves behind 2 lions and 1 sheep (himself). And as we already know 2 lions and 1 sheep is a situation where the sheep survives.\n\r\nYou can use the same logic to go on to 4 lions and 1 sheep, and then all the way to 100 or 1000, but it will always be true that with an odd number of lions the sheep gets eaten and with an even number the sheep doesn't.\n<|im_end|>" }, { "id": "#49444", "title": "Jazz Band Solos", "fun": 3.06, "difficulty": 1.77, "author": "Rhythmic", "desc": "Evan, Lucy, Maria, Steve, and Will all played together in a local jazz band. At their last concert, they each had a solo. Match the musicians with their last name, instrument, and order they played.\n\r\nFirst names: Evan, Lucy, Maria, Steve, Will\r\nLast names: Earl, Lewis, Masters, Sacks, Wilson\r\nInstruments: Alto Sax, Piano, Tenor Sax, Trombone, Trumpet\n\r\n1) Maria's solo was unique. She sang as she played.\n\r\n2) Steve's last name sounded like the instrument he played.\n\r\n3) Mr. Wilson played his solo before the tenor sax player.\n\r\n4) Will played his trumpet during the fifth solo.\n\r\n5) Ms Earl, who didn't play trombone, played her solo before Steve but after Ms Lewis.\n\r\n6) The alto sax was featured in the first solo.\n\r\n7) Lucy played a brass instrument.", "hint": "Lucy and Maria are women.\r\nEvan, Steve, and Will are men.\n\r\nTrombones and trumpets are brass instruments.\n\r\nSacks sounds like sax.", "answer": "Evan Wilson played the alto sax first.\r\nLucy Lewis played the trombone second.\r\nMaria Earl played the piano third.\r\nSteve Sacks played the tenor sax fourth.\r\nWill Masters played the trumpet fifth.", "category": "Logic-Grid", "date": "04/27/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvan, Lucy, Maria, Steve, and Will all played together in a local jazz band. At their last concert, they each had a solo. Match the musicians with their last name, instrument, and order they played.\n\r\nFirst names: Evan, Lucy, Maria, Steve, Will\r\nLast names: Earl, Lewis, Masters, Sacks, Wilson\r\nInstruments: Alto Sax, Piano, Tenor Sax, Trombone, Trumpet\n\r\n1) Maria's solo was unique. She sang as she played.\n\r\n2) Steve's last name sounded like the instrument he played.\n\r\n3) Mr. Wilson played his solo before the tenor sax player.\n\r\n4) Will played his trumpet during the fifth solo.\n\r\n5) Ms Earl, who didn't play trombone, played her solo before Steve but after Ms Lewis.\n\r\n6) The alto sax was featured in the first solo.\n\r\n7) Lucy played a brass instrument.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEvan Wilson played the alto sax first.\r\nLucy Lewis played the trombone second.\r\nMaria Earl played the piano third.\r\nSteve Sacks played the tenor sax fourth.\r\nWill Masters played the trumpet fifth.\n<|im_start|>answer\nEvan Wilson played the alto sax first.\r\nLucy Lewis played the trombone second.\r\nMaria Earl played the piano third.\r\nSteve Sacks played the tenor sax fourth.\r\nWill Masters played the trumpet fifth.\n<|im_end|>" }, { "id": "#30938", "title": "Lazy Sam the Journalist Part 8", "fun": 3.06, "difficulty": 1.76, "author": "triskit", "desc": "Sam the journalist has landed a job somewhere. The problem is, he doesn't know where. All he knows is that it is in one of 6 cities lined up in a row in northern Canada: Eh Land, Hockeyville, Curling Town, Snowburg, New France, and Canada City. However his employer has left clues.\n\r\n1. Curling Town is 2 cities away from the job's location.\n\r\n2. Hockeyville is 3 cities away from Snowburg.\n\r\n3. Snowburg is on the right end.\n\r\n4. New France is not the location.\n\r\n5. Eh Land is 3 cities from Curling Town.\n\r\n6. Canada City is 4 cities away from Snowburg.\n\r\n7. Eh Land is next to the location and another place that isn't the location.\n\r\nSam is lazy, so he is paying you to find out where he is working.", "hint": "No hint available.", "answer": "Order: Curling Town, Canada City, Hockeyville, Eh Land, New France, Snowburg.\n\r\nLocation: Hockeyville\n\r\n(Sorry though, no money)", "category": "Logic", "date": "06/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSam the journalist has landed a job somewhere. The problem is, he doesn't know where. All he knows is that it is in one of 6 cities lined up in a row in northern Canada: Eh Land, Hockeyville, Curling Town, Snowburg, New France, and Canada City. However his employer has left clues.\n\r\n1. Curling Town is 2 cities away from the job's location.\n\r\n2. Hockeyville is 3 cities away from Snowburg.\n\r\n3. Snowburg is on the right end.\n\r\n4. New France is not the location.\n\r\n5. Eh Land is 3 cities from Curling Town.\n\r\n6. Canada City is 4 cities away from Snowburg.\n\r\n7. Eh Land is next to the location and another place that isn't the location.\n\r\nSam is lazy, so he is paying you to find out where he is working.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOrder: Curling Town, Canada City, Hockeyville, Eh Land, New France, Snowburg.\n\r\nLocation: Hockeyville\n\r\n(Sorry though, no money)\n<|im_start|>answer\nOrder: Curling Town, Canada City, Hockeyville, Eh Land, New France, Snowburg.\n\r\nLocation: Hockeyville\n\r\n(Sorry though, no money)\n<|im_end|>" }, { "id": "#52169", "title": "2 Teams", "fun": 3.06, "difficulty": 1.77, "author": "Rove_Tarts", "desc": "Ace, Allie, Carl, Carla, Dora, Draco, Emma, Eric, Jacob, June, Kaleb, Luke, Qin, & Tina are divided equally between a red and a blue team. Can you figure out who is on what team?\n\n\r\nEveryone with E at the end of their names are on the same team.\n\r\nEveryone with a letter that is only in their name is on the same team.\n\r\nEveryone with the most found letter in their names are split evenly between teams.\n\r\nJacob & Emma are on the same team.\n\r\nCarl and Eric are on the red team.\n\r\nExcept for one pair, everyone that has the same first letter are on the same team.", "hint": "Try to find who is on who's team before who is what color.", "answer": "Red Team:\r\nQin\r\nTina\r\nEmma\r\nJacob\r\nCarla\r\nCarl\r\nEric\n\r\nBlue Team:\r\nDora\r\nKaleb\r\nDraco\r\nAllie\r\nAce\r\nJune\r\nLuke", "category": "Logic", "date": "04/13/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAce, Allie, Carl, Carla, Dora, Draco, Emma, Eric, Jacob, June, Kaleb, Luke, Qin, & Tina are divided equally between a red and a blue team. Can you figure out who is on what team?\n\n\r\nEveryone with E at the end of their names are on the same team.\n\r\nEveryone with a letter that is only in their name is on the same team.\n\r\nEveryone with the most found letter in their names are split evenly between teams.\n\r\nJacob & Emma are on the same team.\n\r\nCarl and Eric are on the red team.\n\r\nExcept for one pair, everyone that has the same first letter are on the same team.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRed Team:\r\nQin\r\nTina\r\nEmma\r\nJacob\r\nCarla\r\nCarl\r\nEric\n\r\nBlue Team:\r\nDora\r\nKaleb\r\nDraco\r\nAllie\r\nAce\r\nJune\r\nLuke\n<|im_start|>answer\nRed Team:\r\nQin\r\nTina\r\nEmma\r\nJacob\r\nCarla\r\nCarl\r\nEric\n\r\nBlue Team:\r\nDora\r\nKaleb\r\nDraco\r\nAllie\r\nAce\r\nJune\r\nLuke\n<|im_end|>" }, { "id": "#29824", "title": "The Dealership, Part 2", "fun": 3.06, "difficulty": 2.97, "author": "thompson1", "desc": "You will need the answers from \"The Dealership: Part 1\" to complete this.\n\r\n\"Car\"-l (Carl) Smith is back, and he has another crisis on his hands. The 5 cars he bought a couple weeks ago were sold last week. He was walking across the street from his favorite fast food restaurant with the papers from the sales, when a car pulled out right in front of him. He dropped the papers and couldn't get them back because the wind blew them all away. Help Carl figure out each customer's first and last names, what car they bought, how much money they paid, and on what day they bought the cars.\n\r\nFirst Names - Fred, Jill, Calvin, Hannah, Katie\r\nLast Names - Jenkins, Chapman, Kendrick, Felton, Hampton\r\nCar - Mini, BMW, Mercedes, Jaguar, Ford\r\n$$ - $16,000, $24,000, $32,000, $38,000, $40,000\r\nDay of the week - Monday, Tuesday, Thursday, Friday, Saturday\n\r\n1. The 5 people are: Fred, Mr. Chapman, the one who bought a car on Thursday, the one who bought a car for $38,000, and the one who bought a Ford.\n\r\n2. The 5 cars are: The BMW, the one bought by Hannah, the one bought by Mrs. Hampton, the one bought on Friday, and the one bought for $32,000.\n\r\n3. Carl made a profit on each car.\n\r\n4. The person who bought a car 2 days after Felton did bought her car for $8,000 less than the person who bought the car that was sold to Carl on Thursday.\n\r\n5. No car was bought and sold on the same day of the week.\n\r\n6. The Mini, which was not bought on Monday, was bought 1 day after the Ford.\n\r\n7. Jill paid $8,000 less for her car than the person who bought a car on Saturday.\n\r\n8. Kendrick bought his car before Felton did.", "hint": "No hint available.", "answer": "Fred Kendrick bought his BMW for $40,000 on Monday.\r\nJill Hampton bought her Jaguar for $24,000 on Thursday.\r\nCalvin Chapman bought his Mini for $32,000 on Saturday.\r\nHannah Felton bought her Mercedes for $38,000 on Tuesday.\r\nKatie Jenkins bought her Ford for $16,000 on Friday.\n\r\nIf you couldn't get it, this might help:\n\r\nBecause of clues 5 and 6, you know that the Mini must not be bought on Monday or Thursday, and the Ford cannot be sold on Monday (5), Tuesday (not 1 day before anything), or Thursday (1). This means the Ford and the Mini must be sold on Friday and Saturday, respectively.\r\nIn clue 7, It says that Jill payed $8,000 less than the car on Saturday, which you know is the Mini. Also, in clue 4, the person payed $8,000 less than the car sold to Carl on Thursday, which is the Mini. You now know that the person in that clue has to be Jill.", "category": "Logic-Grid", "date": "04/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou will need the answers from \"The Dealership: Part 1\" to complete this.\n\r\n\"Car\"-l (Carl) Smith is back, and he has another crisis on his hands. The 5 cars he bought a couple weeks ago were sold last week. He was walking across the street from his favorite fast food restaurant with the papers from the sales, when a car pulled out right in front of him. He dropped the papers and couldn't get them back because the wind blew them all away. Help Carl figure out each customer's first and last names, what car they bought, how much money they paid, and on what day they bought the cars.\n\r\nFirst Names - Fred, Jill, Calvin, Hannah, Katie\r\nLast Names - Jenkins, Chapman, Kendrick, Felton, Hampton\r\nCar - Mini, BMW, Mercedes, Jaguar, Ford\r\n$$ - $16,000, $24,000, $32,000, $38,000, $40,000\r\nDay of the week - Monday, Tuesday, Thursday, Friday, Saturday\n\r\n1. The 5 people are: Fred, Mr. Chapman, the one who bought a car on Thursday, the one who bought a car for $38,000, and the one who bought a Ford.\n\r\n2. The 5 cars are: The BMW, the one bought by Hannah, the one bought by Mrs. Hampton, the one bought on Friday, and the one bought for $32,000.\n\r\n3. Carl made a profit on each car.\n\r\n4. The person who bought a car 2 days after Felton did bought her car for $8,000 less than the person who bought the car that was sold to Carl on Thursday.\n\r\n5. No car was bought and sold on the same day of the week.\n\r\n6. The Mini, which was not bought on Monday, was bought 1 day after the Ford.\n\r\n7. Jill paid $8,000 less for her car than the person who bought a car on Saturday.\n\r\n8. Kendrick bought his car before Felton did.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFred Kendrick bought his BMW for $40,000 on Monday.\r\nJill Hampton bought her Jaguar for $24,000 on Thursday.\r\nCalvin Chapman bought his Mini for $32,000 on Saturday.\r\nHannah Felton bought her Mercedes for $38,000 on Tuesday.\r\nKatie Jenkins bought her Ford for $16,000 on Friday.\n\r\nIf you couldn't get it, this might help:\n\r\nBecause of clues 5 and 6, you know that the Mini must not be bought on Monday or Thursday, and the Ford cannot be sold on Monday (5), Tuesday (not 1 day before anything), or Thursday (1). This means the Ford and the Mini must be sold on Friday and Saturday, respectively.\r\nIn clue 7, It says that Jill payed $8,000 less than the car on Saturday, which you know is the Mini. Also, in clue 4, the person payed $8,000 less than the car sold to Carl on Thursday, which is the Mini. You now know that the person in that clue has to be Jill.\n<|im_start|>answer\nFred Kendrick bought his BMW for $40,000 on Monday.\r\nJill Hampton bought her Jaguar for $24,000 on Thursday.\r\nCalvin Chapman bought his Mini for $32,000 on Saturday.\r\nHannah Felton bought her Mercedes for $38,000 on Tuesday.\r\nKatie Jenkins bought her Ford for $16,000 on Friday.\n\r\nIf you couldn't get it, this might help:\n\r\nBecause of clues 5 and 6, you know that the Mini must not be bought on Monday or Thursday, and the Ford cannot be sold on Monday (5), Tuesday (not 1 day before anything), or Thursday (1). This means the Ford and the Mini must be sold on Friday and Saturday, respectively.\r\nIn clue 7, It says that Jill payed $8,000 less than the car on Saturday, which you know is the Mini. Also, in clue 4, the person payed $8,000 less than the car sold to Carl on Thursday, which is the Mini. You now know that the person in that clue has to be Jill.\n<|im_end|>" }, { "id": "#50570", "title": "Butterfly Chaos", "fun": 3.06, "difficulty": 2.27, "author": "Hydra1234", "desc": "A shipment of butterflies was mixed up by the dock workers, and they could not find who bought which species, where it was from, and what was the price. All the workers know is that Alejandro, Faye, Yvette, Sophie, and Zachary could have each bought butterflies that cost $60, $75, $90, $105, or $120. Each could have bought the Clearwing, the Emperor, the Grayling, the Swallowtail, or the Torturix butterflies. Each butterfly could have lived in Australia, Jordan, Luxembourg, Panama, or Qatar. It is up to you to find out who bought which butterfly, what was the price, and where did it come from with the provided clues:\n\r\n1. Neither the butterfly from Luxembourg nor the one from Australia sold for $90.\n\r\n2. The Emperor butterfly cost $30 more than the Torturix butterfly.\n\r\n3. Zachary's purchase was $75.\n\r\n4. The butterfly from Australia cost less than the one from Luxembourg.\n\r\n5. Alejandro's purchase was from Luxembourg.\n\r\n6. Of Yvette's purchase and the purchase for $60, one was from Qatar and the other was the Torturix.\n\r\n7. The butterfly that sold for $120 was not from Panama.\n\r\n8. The insect from Australia was not the Torturix.\n\r\n9. Faye bought the Torturix.\n\r\n10. Sophie did not buy the Grayling.\n\r\n11. Of the Emperor and the insect worth $105, one was won by Yvette and the other was from Luxembourg.\n\r\n12. The insect that sold for $105 was the Swallowtail.", "hint": "Alejandro bought the $105 butterfly.", "answer": "Faye bought the Torturix from Panama for $60.\r\nZachary bought the Grayling from Australia for $75.\r\nYvette bought the Emperor from Qatar for $90.\r\nAlejandro bought the Swallowtail from Luxembourg for $105.\r\nSophie bought the Clearwing from Jordan for $120.", "category": "Logic-Grid", "date": "04/17/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA shipment of butterflies was mixed up by the dock workers, and they could not find who bought which species, where it was from, and what was the price. All the workers know is that Alejandro, Faye, Yvette, Sophie, and Zachary could have each bought butterflies that cost $60, $75, $90, $105, or $120. Each could have bought the Clearwing, the Emperor, the Grayling, the Swallowtail, or the Torturix butterflies. Each butterfly could have lived in Australia, Jordan, Luxembourg, Panama, or Qatar. It is up to you to find out who bought which butterfly, what was the price, and where did it come from with the provided clues:\n\r\n1. Neither the butterfly from Luxembourg nor the one from Australia sold for $90.\n\r\n2. The Emperor butterfly cost $30 more than the Torturix butterfly.\n\r\n3. Zachary's purchase was $75.\n\r\n4. The butterfly from Australia cost less than the one from Luxembourg.\n\r\n5. Alejandro's purchase was from Luxembourg.\n\r\n6. Of Yvette's purchase and the purchase for $60, one was from Qatar and the other was the Torturix.\n\r\n7. The butterfly that sold for $120 was not from Panama.\n\r\n8. The insect from Australia was not the Torturix.\n\r\n9. Faye bought the Torturix.\n\r\n10. Sophie did not buy the Grayling.\n\r\n11. Of the Emperor and the insect worth $105, one was won by Yvette and the other was from Luxembourg.\n\r\n12. The insect that sold for $105 was the Swallowtail.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFaye bought the Torturix from Panama for $60.\r\nZachary bought the Grayling from Australia for $75.\r\nYvette bought the Emperor from Qatar for $90.\r\nAlejandro bought the Swallowtail from Luxembourg for $105.\r\nSophie bought the Clearwing from Jordan for $120.\n<|im_start|>answer\nFaye bought the Torturix from Panama for $60.\r\nZachary bought the Grayling from Australia for $75.\r\nYvette bought the Emperor from Qatar for $90.\r\nAlejandro bought the Swallowtail from Luxembourg for $105.\r\nSophie bought the Clearwing from Jordan for $120.\n<|im_end|>" }, { "id": "#28453", "title": "Music Fans", "fun": 3.06, "difficulty": 2.0, "author": "Winner4600", "desc": "Yes! Five bands are coming to town within one week, and Georgia, Rachel, Jason, Carlos, and Lara are jumping for joy! Each one is a diehard fan of either Juanes, The Rolling Stones, U2, Green Day, or Coldplay. Figure out who likes which band, when each band performed, how long each concert was, and which souvenir each fan walked away with.\n\r\n1) The 5 fans are Rachel, the Green Day fan, the Rolling Stones fan, the girl who spent 2 hours at a concert, and the one who left with a CD.\n\r\n2) Georgia was so excited about Coldplay, she got in line at 6:00 Friday and waited 3 hours with all the other fans for the concert to begin. The concert ended at 11:00.\n\r\n3) Lara's U2 CD collection got a little bit bigger after the concert on Sunday.\n\r\n4) Jason did not spend 3.5 hours in a concert. The concert on Saturday was not 4 hours long, and the concert on Wednesday did not sell sweatshirts (which were not bought by Rachel).\n\r\n5) Tuesday's concert was 2.5 hours long.\n\r\n6) Green Day performed on Saturday, but Juanes did not perform on Wednesday.\n\r\n7) The Rolling Stones fan bought the T-shirt.\n\r\n8) Someone bought music videos after the 3-hour concert.\n\r\n9) Lara was so hyper after the 3.5-hour concert, she couldn't sleep.\n\r\n10) Jason didn't like any T-shirt designs, so he didn't buy any.", "hint": "No hint available.", "answer": "Georgia-Coldplay-Friday-2 hours-Sweatshirt\r\nRachel-Juanes-Tuesday-2.5 hours-Photo\r\nJason-Green Day-Saturday-3 hours-Music Video\r\nCarlos-Rolling Stones-Wednesday-4 hours-T-shirt\r\nLara-U2-Sunday-3.5 hours-CD", "category": "Logic-Grid", "date": "02/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYes! Five bands are coming to town within one week, and Georgia, Rachel, Jason, Carlos, and Lara are jumping for joy! Each one is a diehard fan of either Juanes, The Rolling Stones, U2, Green Day, or Coldplay. Figure out who likes which band, when each band performed, how long each concert was, and which souvenir each fan walked away with.\n\r\n1) The 5 fans are Rachel, the Green Day fan, the Rolling Stones fan, the girl who spent 2 hours at a concert, and the one who left with a CD.\n\r\n2) Georgia was so excited about Coldplay, she got in line at 6:00 Friday and waited 3 hours with all the other fans for the concert to begin. The concert ended at 11:00.\n\r\n3) Lara's U2 CD collection got a little bit bigger after the concert on Sunday.\n\r\n4) Jason did not spend 3.5 hours in a concert. The concert on Saturday was not 4 hours long, and the concert on Wednesday did not sell sweatshirts (which were not bought by Rachel).\n\r\n5) Tuesday's concert was 2.5 hours long.\n\r\n6) Green Day performed on Saturday, but Juanes did not perform on Wednesday.\n\r\n7) The Rolling Stones fan bought the T-shirt.\n\r\n8) Someone bought music videos after the 3-hour concert.\n\r\n9) Lara was so hyper after the 3.5-hour concert, she couldn't sleep.\n\r\n10) Jason didn't like any T-shirt designs, so he didn't buy any.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGeorgia-Coldplay-Friday-2 hours-Sweatshirt\r\nRachel-Juanes-Tuesday-2.5 hours-Photo\r\nJason-Green Day-Saturday-3 hours-Music Video\r\nCarlos-Rolling Stones-Wednesday-4 hours-T-shirt\r\nLara-U2-Sunday-3.5 hours-CD\n<|im_start|>answer\nGeorgia-Coldplay-Friday-2 hours-Sweatshirt\r\nRachel-Juanes-Tuesday-2.5 hours-Photo\r\nJason-Green Day-Saturday-3 hours-Music Video\r\nCarlos-Rolling Stones-Wednesday-4 hours-T-shirt\r\nLara-U2-Sunday-3.5 hours-CD\n<|im_end|>" }, { "id": "#46727", "title": "Colorful Deliveries", "fun": 3.06, "difficulty": 2.09, "author": "NikkiBabi", "desc": "Determine each person's first and last name, the color of each package, what each contained, and what time it was delivered.\n\r\nClues: \n\r\n1. Michelle did not receive shoes and did not receive her package at 1:00 PM. Mr. Jones didn't receive his package in the afternoon.\n\r\n2. The button up shirt did not come in a black or purple package. The shirt Michael received is not a sweatshirt. The purple package did not contain shoes.\n\r\n3. Mrs. Marks, who received her package at 3:00 PM, didn't receive a light pink package, which was not delivered at 9:00 AM.\n\r\n4. Kevin's last name isn't Johnson and he didn't receive his package at 4:00 PM. The high heels did not come in the hot pink package and were not delivered at 11:00 AM.\n\r\n5. The hot pink package was delivered two hours after the button up shirt and two hours before Kara received her package.\n\r\n6. The order of the appointments is the person who ordered the clogs, Ms. Green and her shirt, the owner whose last name is Smith, the person who received the red package, and Jason.", "hint": "No hint available.", "answer": "Michael Smith, Hot Pink, Flannel Shirt, 1PM;\r\nKevin Jones, Black, Clogs, 9AM;\r\nJason Johnson, Purple, Sweatshirt, 4PM;\r\nMichelle Green, Light Pink, Button Up, 11AM;\r\nKara Marks, Red, High Heels, 3PM", "category": "Logic-Grid", "date": "04/13/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDetermine each person's first and last name, the color of each package, what each contained, and what time it was delivered.\n\r\nClues: \n\r\n1. Michelle did not receive shoes and did not receive her package at 1:00 PM. Mr. Jones didn't receive his package in the afternoon.\n\r\n2. The button up shirt did not come in a black or purple package. The shirt Michael received is not a sweatshirt. The purple package did not contain shoes.\n\r\n3. Mrs. Marks, who received her package at 3:00 PM, didn't receive a light pink package, which was not delivered at 9:00 AM.\n\r\n4. Kevin's last name isn't Johnson and he didn't receive his package at 4:00 PM. The high heels did not come in the hot pink package and were not delivered at 11:00 AM.\n\r\n5. The hot pink package was delivered two hours after the button up shirt and two hours before Kara received her package.\n\r\n6. The order of the appointments is the person who ordered the clogs, Ms. Green and her shirt, the owner whose last name is Smith, the person who received the red package, and Jason.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMichael Smith, Hot Pink, Flannel Shirt, 1PM;\r\nKevin Jones, Black, Clogs, 9AM;\r\nJason Johnson, Purple, Sweatshirt, 4PM;\r\nMichelle Green, Light Pink, Button Up, 11AM;\r\nKara Marks, Red, High Heels, 3PM\n<|im_start|>answer\nMichael Smith, Hot Pink, Flannel Shirt, 1PM;\r\nKevin Jones, Black, Clogs, 9AM;\r\nJason Johnson, Purple, Sweatshirt, 4PM;\r\nMichelle Green, Light Pink, Button Up, 11AM;\r\nKara Marks, Red, High Heels, 3PM\n<|im_end|>" }, { "id": "#41561", "title": "The Factual Murder", "fun": 3.06, "difficulty": 2.24, "author": "pandastampede", "desc": "There are five people. One of them shot and killed one of the other five. Which man is the murderer?\n\r\n1. Dan ran in the NY City marathon yesterday with one of the innocent men.\r\n2. Mike considered being a farmer before he moved to the city. \r\n3. Jeff is a topnotch computer consultant and wants to install Ben's new computer next week.\r\n4. The murderer had his leg amputated last month.\r\n5. Ben met Jack for the first time six months ago.\r\n6. Jack has been in seclusion since the crime.\r\n7. Dan used to drink heavily.\r\n8. Ben and Jeff built their last computers together.\r\n9. The murderer is Jack's brother. They grew up together in Seattle.", "hint": "Observe the clues closely.", "answer": "1. Jack is not the murderer, because he is the brother of the murderer. 2. Dan can't be the murderer since he ran a marathon, and the murderer recently had his leg amputated, and wouldn't be running a marathon of any magnitude that quickly. 3. Ben is not the murderer if he just met Jack, since Jack and the murderer grew up together. 4. This leaves Jeff and Mike. Since Jeff is still alive (he wants to install a new computer next week, present tense) he must be the murderer. Mike also didn't grow up with Jack. It has been determined that Jack, Dan and Jeff are all alive. Ben must also be alive since Jeff plans to install Ben's computer next week. This means that Jeff killed Mike.", "category": "Logic", "date": "04/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five people. One of them shot and killed one of the other five. Which man is the murderer?\n\r\n1. Dan ran in the NY City marathon yesterday with one of the innocent men.\r\n2. Mike considered being a farmer before he moved to the city. \r\n3. Jeff is a topnotch computer consultant and wants to install Ben's new computer next week.\r\n4. The murderer had his leg amputated last month.\r\n5. Ben met Jack for the first time six months ago.\r\n6. Jack has been in seclusion since the crime.\r\n7. Dan used to drink heavily.\r\n8. Ben and Jeff built their last computers together.\r\n9. The murderer is Jack's brother. They grew up together in Seattle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Jack is not the murderer, because he is the brother of the murderer. 2. Dan can't be the murderer since he ran a marathon, and the murderer recently had his leg amputated, and wouldn't be running a marathon of any magnitude that quickly. 3. Ben is not the murderer if he just met Jack, since Jack and the murderer grew up together. 4. This leaves Jeff and Mike. Since Jeff is still alive (he wants to install a new computer next week, present tense) he must be the murderer. Mike also didn't grow up with Jack. It has been determined that Jack, Dan and Jeff are all alive. Ben must also be alive since Jeff plans to install Ben's computer next week. This means that Jeff killed Mike.\n<|im_start|>answer\n1. Jack is not the murderer, because he is the brother of the murderer. 2. Dan can't be the murderer since he ran a marathon, and the murderer recently had his leg amputated, and wouldn't be running a marathon of any magnitude that quickly. 3. Ben is not the murderer if he just met Jack, since Jack and the murderer grew up together. 4. This leaves Jeff and Mike. Since Jeff is still alive (he wants to install a new computer next week, present tense) he must be the murderer. Mike also didn't grow up with Jack. It has been determined that Jack, Dan and Jeff are all alive. Ben must also be alive since Jeff plans to install Ben's computer next week. This means that Jeff killed Mike.\n<|im_end|>" }, { "id": "#32200", "title": "The Honeymooners", "fun": 3.06, "difficulty": 2.13, "author": "jenb2144", "desc": "Five couples are going on honeymoons to five different places where they will participate in five different activities. Determine the first and last names of each couple, where they went honeymooning and what activity they participated in. \n\r\n1. Ethan, who is not married to Chrissy, admired the photos of Spain that Jacob Brown showed to him.\r\n2. Matthew, whose last name is not Emerson, enjoyed Portugal.\r\n3. The couple who went sightseeing did so in the Dominican Republic.\r\n4. Sharon had heard lovely things about the Dominican, but decided to go to Spain. \r\n5. Matthew and Tina are not married nor are Janna and Ethan.\r\n6. Ethan didn't go stargazing.\r\n7. The five couples are represented by the Peters, Cuba, Chrissy, Bradley and sailing. \r\n8. Jacob, who isn't a Howe, felt a little seasick during his activity. \r\n9. Patrick, who isn't married to Tina, wished he'd gone sightseeing like Bradley Green, but instead he ended up going shopping.\r\n10. The scuba diving couple didn't do so in Cuba.\r\n11. Bradley and Josie had a great time on their honeymoon.", "hint": "Dominican Republic is shortened to Dom. Repub. in the grid.", "answer": "Bradley and Josie Green went sightseeing in the Dominican Republic.\r\nEthan and Tina Peters went scuba diving in Mexico.\r\nJacob and Sharon Brown went sailing in Spain.\r\nMatthew and Chrissy Howe went stargazing in Portugal.\r\nPatrick and Janna Emerson went shopping in Cuba.", "category": "Logic-Grid", "date": "07/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive couples are going on honeymoons to five different places where they will participate in five different activities. Determine the first and last names of each couple, where they went honeymooning and what activity they participated in. \n\r\n1. Ethan, who is not married to Chrissy, admired the photos of Spain that Jacob Brown showed to him.\r\n2. Matthew, whose last name is not Emerson, enjoyed Portugal.\r\n3. The couple who went sightseeing did so in the Dominican Republic.\r\n4. Sharon had heard lovely things about the Dominican, but decided to go to Spain. \r\n5. Matthew and Tina are not married nor are Janna and Ethan.\r\n6. Ethan didn't go stargazing.\r\n7. The five couples are represented by the Peters, Cuba, Chrissy, Bradley and sailing. \r\n8. Jacob, who isn't a Howe, felt a little seasick during his activity. \r\n9. Patrick, who isn't married to Tina, wished he'd gone sightseeing like Bradley Green, but instead he ended up going shopping.\r\n10. The scuba diving couple didn't do so in Cuba.\r\n11. Bradley and Josie had a great time on their honeymoon.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBradley and Josie Green went sightseeing in the Dominican Republic.\r\nEthan and Tina Peters went scuba diving in Mexico.\r\nJacob and Sharon Brown went sailing in Spain.\r\nMatthew and Chrissy Howe went stargazing in Portugal.\r\nPatrick and Janna Emerson went shopping in Cuba.\n<|im_start|>answer\nBradley and Josie Green went sightseeing in the Dominican Republic.\r\nEthan and Tina Peters went scuba diving in Mexico.\r\nJacob and Sharon Brown went sailing in Spain.\r\nMatthew and Chrissy Howe went stargazing in Portugal.\r\nPatrick and Janna Emerson went shopping in Cuba.\n<|im_end|>" }, { "id": "#28978", "title": "Cape of Good Hope", "fun": 3.06, "difficulty": 2.28, "author": "Victor", "desc": "The weather at the Cape of Good Hope makes it a notorious location where many ships have been lost to the sea. Philip Wood, the famous diver, has discovered four ships that sank in the same spot, one on top of each other.\n\r\nWith some skill, Philip was able to determine the name, captain, cargo, destination and year each ship was built. The question is, can you?\n\n\r\n1. During his first exploration of the site, Philip determined there were four ships - the Red Rover, the ship built in 1743, the ship captained by Quigley and the ship carrying tea that was bound for North America.\n\r\n2. The ship that carried a cargo of saffron was built after the ship that carried a cargo of tea.\n\r\n3. An entry in one ship's log, found at the site, indicated that the ship built in 1522 was carrying a valuable cargo of gold.\n\r\n4. One ship was carrying botanical specimens to France. Philip determined that this was not the Royal Bride.\n\r\n5. The Scarlet Queen, a pirate ship, was certainly built before the nineteenth century but not as early as the sixteenth. The captain of this ship was the famous rogue Clubfoot.\n\r\n6. The Wanderer was built after the Royal Bride. The Royal Bride's cargo was not tea and the Royal Bride was not travelling to the South Seas.\n\r\n7. Captain Bolton's ship was built before Clubfoot's and before The Royal Bride.", "hint": "No hint available.", "answer": "Royal Bride, 1743, Vickers, Saffron, England;\r\nScarlet Queen, 1688, Clubfoot, Tea, North America;\r\nRed Rover, 1522, Bolton, Gold, South Seas;\r\nWanderer, 1817, Quigley, Specimens, France.\n\r\nThe ship built in 1522 was carrying gold (3). This is not the Scarlet Queen (5), the Wanderer (6) or the Royal Bride (7) so must have been the Red Rover. The Scarlet Queen was built in either 1688 or 1743 (5) and the Wanderer was built after the Royal Bride, so the Wanderer was built in 1817 and the Royal Bride in either 1688 or 1743. So the captain of the Red Rover was Captain Bolton (7). The ship carrying tea was not the Red Rover (gold), the Royal Bride (6) or the Wanderer (2) so was the Scarlet Queen. The Scarlet Queen's destination was North America (1) and her captain was Clubfoot (5). The Scarlet Queen was not built in 1743 (1) so was built in 1688 and the Royal Bride was built in 1743. The Royal Bride was not carrying gold (Red Rover), tea (Scarlet Queen) or botanical specimens (4) so was carrying saffron and the Wanderer was carrying the specimens to France. Quigley was not the captain of the Royal Bride (1) so was the captain of the Wanderer and Vickers was the captain of the Royal Bride. The Royal Bride's destination was not the South Seas (6) so was England and the Red Rover's destination was the South Seas.", "category": "Logic-Grid", "date": "03/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe weather at the Cape of Good Hope makes it a notorious location where many ships have been lost to the sea. Philip Wood, the famous diver, has discovered four ships that sank in the same spot, one on top of each other.\n\r\nWith some skill, Philip was able to determine the name, captain, cargo, destination and year each ship was built. The question is, can you?\n\n\r\n1. During his first exploration of the site, Philip determined there were four ships - the Red Rover, the ship built in 1743, the ship captained by Quigley and the ship carrying tea that was bound for North America.\n\r\n2. The ship that carried a cargo of saffron was built after the ship that carried a cargo of tea.\n\r\n3. An entry in one ship's log, found at the site, indicated that the ship built in 1522 was carrying a valuable cargo of gold.\n\r\n4. One ship was carrying botanical specimens to France. Philip determined that this was not the Royal Bride.\n\r\n5. The Scarlet Queen, a pirate ship, was certainly built before the nineteenth century but not as early as the sixteenth. The captain of this ship was the famous rogue Clubfoot.\n\r\n6. The Wanderer was built after the Royal Bride. The Royal Bride's cargo was not tea and the Royal Bride was not travelling to the South Seas.\n\r\n7. Captain Bolton's ship was built before Clubfoot's and before The Royal Bride.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRoyal Bride, 1743, Vickers, Saffron, England;\r\nScarlet Queen, 1688, Clubfoot, Tea, North America;\r\nRed Rover, 1522, Bolton, Gold, South Seas;\r\nWanderer, 1817, Quigley, Specimens, France.\n\r\nThe ship built in 1522 was carrying gold (3). This is not the Scarlet Queen (5), the Wanderer (6) or the Royal Bride (7) so must have been the Red Rover. The Scarlet Queen was built in either 1688 or 1743 (5) and the Wanderer was built after the Royal Bride, so the Wanderer was built in 1817 and the Royal Bride in either 1688 or 1743. So the captain of the Red Rover was Captain Bolton (7). The ship carrying tea was not the Red Rover (gold), the Royal Bride (6) or the Wanderer (2) so was the Scarlet Queen. The Scarlet Queen's destination was North America (1) and her captain was Clubfoot (5). The Scarlet Queen was not built in 1743 (1) so was built in 1688 and the Royal Bride was built in 1743. The Royal Bride was not carrying gold (Red Rover), tea (Scarlet Queen) or botanical specimens (4) so was carrying saffron and the Wanderer was carrying the specimens to France. Quigley was not the captain of the Royal Bride (1) so was the captain of the Wanderer and Vickers was the captain of the Royal Bride. The Royal Bride's destination was not the South Seas (6) so was England and the Red Rover's destination was the South Seas.\n<|im_start|>answer\nRoyal Bride, 1743, Vickers, Saffron, England;\r\nScarlet Queen, 1688, Clubfoot, Tea, North America;\r\nRed Rover, 1522, Bolton, Gold, South Seas;\r\nWanderer, 1817, Quigley, Specimens, France.\n\r\nThe ship built in 1522 was carrying gold (3). This is not the Scarlet Queen (5), the Wanderer (6) or the Royal Bride (7) so must have been the Red Rover. The Scarlet Queen was built in either 1688 or 1743 (5) and the Wanderer was built after the Royal Bride, so the Wanderer was built in 1817 and the Royal Bride in either 1688 or 1743. So the captain of the Red Rover was Captain Bolton (7). The ship carrying tea was not the Red Rover (gold), the Royal Bride (6) or the Wanderer (2) so was the Scarlet Queen. The Scarlet Queen's destination was North America (1) and her captain was Clubfoot (5). The Scarlet Queen was not built in 1743 (1) so was built in 1688 and the Royal Bride was built in 1743. The Royal Bride was not carrying gold (Red Rover), tea (Scarlet Queen) or botanical specimens (4) so was carrying saffron and the Wanderer was carrying the specimens to France. Quigley was not the captain of the Royal Bride (1) so was the captain of the Wanderer and Vickers was the captain of the Royal Bride. The Royal Bride's destination was not the South Seas (6) so was England and the Red Rover's destination was the South Seas.\n<|im_end|>" }, { "id": "#23666", "title": "Sam's Recycling Sale", "fun": 3.06, "difficulty": 2.53, "author": "cinnamon30", "desc": "Sam takes an active interest in the environment and sells many environmentally friendly products at his variety store. Although the items are fairly popular, he wanted to heighten the awareness of his customers, so he held a special Recycling Event Sale. During the sale, Sam gave door prizes to five lucky customers (three of whom - Carl, George and Ian are men, and two of whom - Agnes and Ellen are women), each of whom purchased a different product. From the info provided, can you determine the first and last names of each winner, the item purchased, and the prize each received (each received a different prize)?\n\r\n1. The five winners were Agnes, the one surnamed Meyers, the one who bought the natural fertilizer, the one who won the gardening gloves, and the one who won the pruning shears.\n\r\n2. Ms. Steele is not the woman who purchased the compost turner.\n\r\n3. Three men are Mr. Kraft, Ian, and the man who won the citronella candles.\n\r\n4. The five winners were George, the one who won the cellulose sandwich bags, the one surnamed Quick, the one who bought the mesh shopping bags, and Mr. Kraft.\n\r\n5. Either Ellen or the man who won the Mason jars is the one who bought the natural fertilizer.\n\r\n6. The one who bought the newspaper bundler and the one who won the pruning shears are either, both men or both women.\n\r\n7. The man who bought the recycling bin is not Mr. Oakley.", "hint": "No hint available.", "answer": "Agnes Steele, newspaper bundler, cellulose sandwich bags\r\nCarl Kraft, natural fertilizer, Mason jars\r\nEllen Quick, compost turner, pruning shears\r\nGeorge Meyers, recycling bin, citronella candles\r\nIan Oakley, mesh shopping bags, gardening gloves\n\r\nMr. Kraft isn't Ian - clue 3, or George - clue 5, so he's Carl - the only man left. The Candles man - clue 3, isn't Ian or Carl Kraft - clue 3; so he's George. Agnes isn't gloves, shears - clue 1, or jars - clue 5(man), she's sandwich bags. Agnes isn't Meyers - clue 1, Quick - clue 4 or Mr. Oakley - clue 7, so she is Steele. Agnes isn't fertilizer - clue 1, compost turner - clue 2, shopping bags - clue 4, or recycling bin - clue 7, so she's newspaper bundler. Ellen is the compost turner - clue 2 says it's a woman, and shears - clue 6, since turner is a woman compost is also a woman. Ellen isn't Meyers - clue 1 or Mr. Oakley - clue 7, so she's Quick. The one who bought mason jars bought the fertilizer - clue 5. Shopping bags isn't George or Carl Kraft - clue 4, so he's Ian. George's candles, see above, isn't fertilizer or jars, so Carl is fertilizer. By elimination, George is recycling bin. George isn't Oakley - clue 7, by elimination Ian is and George is Meyers. By elimination Ian won the gloves.", "category": "Logic-Grid", "date": "06/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSam takes an active interest in the environment and sells many environmentally friendly products at his variety store. Although the items are fairly popular, he wanted to heighten the awareness of his customers, so he held a special Recycling Event Sale. During the sale, Sam gave door prizes to five lucky customers (three of whom - Carl, George and Ian are men, and two of whom - Agnes and Ellen are women), each of whom purchased a different product. From the info provided, can you determine the first and last names of each winner, the item purchased, and the prize each received (each received a different prize)?\n\r\n1. The five winners were Agnes, the one surnamed Meyers, the one who bought the natural fertilizer, the one who won the gardening gloves, and the one who won the pruning shears.\n\r\n2. Ms. Steele is not the woman who purchased the compost turner.\n\r\n3. Three men are Mr. Kraft, Ian, and the man who won the citronella candles.\n\r\n4. The five winners were George, the one who won the cellulose sandwich bags, the one surnamed Quick, the one who bought the mesh shopping bags, and Mr. Kraft.\n\r\n5. Either Ellen or the man who won the Mason jars is the one who bought the natural fertilizer.\n\r\n6. The one who bought the newspaper bundler and the one who won the pruning shears are either, both men or both women.\n\r\n7. The man who bought the recycling bin is not Mr. Oakley.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAgnes Steele, newspaper bundler, cellulose sandwich bags\r\nCarl Kraft, natural fertilizer, Mason jars\r\nEllen Quick, compost turner, pruning shears\r\nGeorge Meyers, recycling bin, citronella candles\r\nIan Oakley, mesh shopping bags, gardening gloves\n\r\nMr. Kraft isn't Ian - clue 3, or George - clue 5, so he's Carl - the only man left. The Candles man - clue 3, isn't Ian or Carl Kraft - clue 3; so he's George. Agnes isn't gloves, shears - clue 1, or jars - clue 5(man), she's sandwich bags. Agnes isn't Meyers - clue 1, Quick - clue 4 or Mr. Oakley - clue 7, so she is Steele. Agnes isn't fertilizer - clue 1, compost turner - clue 2, shopping bags - clue 4, or recycling bin - clue 7, so she's newspaper bundler. Ellen is the compost turner - clue 2 says it's a woman, and shears - clue 6, since turner is a woman compost is also a woman. Ellen isn't Meyers - clue 1 or Mr. Oakley - clue 7, so she's Quick. The one who bought mason jars bought the fertilizer - clue 5. Shopping bags isn't George or Carl Kraft - clue 4, so he's Ian. George's candles, see above, isn't fertilizer or jars, so Carl is fertilizer. By elimination, George is recycling bin. George isn't Oakley - clue 7, by elimination Ian is and George is Meyers. By elimination Ian won the gloves.\n<|im_start|>answer\nAgnes Steele, newspaper bundler, cellulose sandwich bags\r\nCarl Kraft, natural fertilizer, Mason jars\r\nEllen Quick, compost turner, pruning shears\r\nGeorge Meyers, recycling bin, citronella candles\r\nIan Oakley, mesh shopping bags, gardening gloves\n\r\nMr. Kraft isn't Ian - clue 3, or George - clue 5, so he's Carl - the only man left. The Candles man - clue 3, isn't Ian or Carl Kraft - clue 3; so he's George. Agnes isn't gloves, shears - clue 1, or jars - clue 5(man), she's sandwich bags. Agnes isn't Meyers - clue 1, Quick - clue 4 or Mr. Oakley - clue 7, so she is Steele. Agnes isn't fertilizer - clue 1, compost turner - clue 2, shopping bags - clue 4, or recycling bin - clue 7, so she's newspaper bundler. Ellen is the compost turner - clue 2 says it's a woman, and shears - clue 6, since turner is a woman compost is also a woman. Ellen isn't Meyers - clue 1 or Mr. Oakley - clue 7, so she's Quick. The one who bought mason jars bought the fertilizer - clue 5. Shopping bags isn't George or Carl Kraft - clue 4, so he's Ian. George's candles, see above, isn't fertilizer or jars, so Carl is fertilizer. By elimination, George is recycling bin. George isn't Oakley - clue 7, by elimination Ian is and George is Meyers. By elimination Ian won the gloves.\n<|im_end|>" }, { "id": "#34611", "title": "The Cake Shop", "fun": 3.06, "difficulty": 1.8800000000000001, "author": "thompson1", "desc": "\"The Cake Shop\" was just opening when four customers came rushing in, asking for cakes that they needed that night! They all filled out forms with their names, what kind of cake, what size, and the occasion it was for. They all rushed in and out, desperately trying to finish organizing and setting up for their parties. Joe, who was working that shift, accidentally put the orders in the paper shredder along with the old orders from the day before! He can only remember a few things, but needs to have all of the cakes ready by 3:00! Can you help him sort out the orders?\n\r\nFirst Names: Carson, Ted, Jessica, and Bailey\r\nLast Names: Jones, Tomas, Butler, and Brown\r\nSize: Small, Medium, Large, and Double-Decker\r\nType of Cake: Chocolate, Swirl, Angel Food, and Cookie\r\nOccasion: Birthday, Baby Shower, Anniversary, and \"Congratulations!\" party\n\r\n1. The four customers are: Jessica, the one surnamed Tomas, the one buying a large cake, and the Angel Food cake.\n\r\n2. The four cakes are: The double-decker, the cookie cake, the one bought for a birthday, and the one bought by Carson.\n\r\n3. Exactly two customers had the same first and last initial.\n\r\n4. The customer with the last name of Jones bought a cake for her best friend because she just got promoted to a much better job!\n\r\n5. The cake that was for an anniversary was bigger than the one for the birthday, and neither were double-deckers.\n\r\n6. The swirl was either a large or a double-decker, but wasn't being used to celebrate something that happens annually.\n\r\n7. The birthday cake was for a one-year-old, so it had to be small.\n\r\n8. Ted Butler had to get the cake while his wife was busy setting up for one of their friends surprise baby shower!", "hint": "No hint available.", "answer": "Carson Tomas bought a medium chocolate cake for his anniversary.\r\nTed Butler bought a large cookie cake for his friend's baby shower.\r\nJessica Jones bought a double-decker swirl cake for a \"Congratulations!\" party.\r\nBailey Brown bought a small angel food cake for her son's birthday.", "category": "Logic-Grid", "date": "12/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"The Cake Shop\" was just opening when four customers came rushing in, asking for cakes that they needed that night! They all filled out forms with their names, what kind of cake, what size, and the occasion it was for. They all rushed in and out, desperately trying to finish organizing and setting up for their parties. Joe, who was working that shift, accidentally put the orders in the paper shredder along with the old orders from the day before! He can only remember a few things, but needs to have all of the cakes ready by 3:00! Can you help him sort out the orders?\n\r\nFirst Names: Carson, Ted, Jessica, and Bailey\r\nLast Names: Jones, Tomas, Butler, and Brown\r\nSize: Small, Medium, Large, and Double-Decker\r\nType of Cake: Chocolate, Swirl, Angel Food, and Cookie\r\nOccasion: Birthday, Baby Shower, Anniversary, and \"Congratulations!\" party\n\r\n1. The four customers are: Jessica, the one surnamed Tomas, the one buying a large cake, and the Angel Food cake.\n\r\n2. The four cakes are: The double-decker, the cookie cake, the one bought for a birthday, and the one bought by Carson.\n\r\n3. Exactly two customers had the same first and last initial.\n\r\n4. The customer with the last name of Jones bought a cake for her best friend because she just got promoted to a much better job!\n\r\n5. The cake that was for an anniversary was bigger than the one for the birthday, and neither were double-deckers.\n\r\n6. The swirl was either a large or a double-decker, but wasn't being used to celebrate something that happens annually.\n\r\n7. The birthday cake was for a one-year-old, so it had to be small.\n\r\n8. Ted Butler had to get the cake while his wife was busy setting up for one of their friends surprise baby shower!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarson Tomas bought a medium chocolate cake for his anniversary.\r\nTed Butler bought a large cookie cake for his friend's baby shower.\r\nJessica Jones bought a double-decker swirl cake for a \"Congratulations!\" party.\r\nBailey Brown bought a small angel food cake for her son's birthday.\n<|im_start|>answer\nCarson Tomas bought a medium chocolate cake for his anniversary.\r\nTed Butler bought a large cookie cake for his friend's baby shower.\r\nJessica Jones bought a double-decker swirl cake for a \"Congratulations!\" party.\r\nBailey Brown bought a small angel food cake for her son's birthday.\n<|im_end|>" }, { "id": "#28947", "title": "The Local Bar", "fun": 3.06, "difficulty": 2.33, "author": "HogwartsGirl05", "desc": "You are the owner of \"The Local Bar\", a failed tavern turned bookstore and coffee shop. You have been working nonstop for three years to get your business off the ground. Your hard work has paid off.\n\r\nYour business is one of the most popular in town. Your employees have become dear friends and have earned your trust and your confidence in their abilities. You decided to go on a vacation and look into new suppliers. You left your five employees with jobs to do to keep the shop running.\n\r\nUpon returning, you find that your employees have gone above and beyond what you have asked of them. You decide to get them each a first edition copy of their favorite book, wrapped in their favorite color. You will include a note telling them how well they did their job and how grateful you are for all their hard work. The problem, however, is that you forgot to write down who likes and did what and you seem to have forgotten during your time away. You do remember enough facts to figure it out.\n\r\nEmployees : Josh, Joie, Luke, Nell, and Shawn\n\r\nFavorite Authors : Wilson Rawls, Anne Rice, Andrew Greeley, Robert Hellenga, and Bradford Morrow\n\r\nFavorite Books : Where the Red Fern Grows, Blood and Gold, Irish Whiskey, The Fall of the Sparrow, and Giovanni's Gift\n\r\nJobs : Deliveries, Inventory/Paperwork, Cashier, Food and Drinks, and Helping Customers find the book they are looking for.\n\r\nFavorite Colors : Green, Blue, Red, Gold, and Black.\n\r\nHere are the facts you remember: \n\r\n1. Your five employees are: Shawn (who does not like Andrew Greeley); the person who likes red; the girl who likes \"Giovanni's Gift\"; the boy who likes Anne Rice; and Nell.\n\r\n2. The colors in the book titles do not match the color they were wrapped in; the titles and wrapping paper do not share the same starting letter; and the author's last names do not share the same starting letter as what they were wrapped in.\n\r\n3. Each person was given a job that suited them: Josh is always on time; Joie is an organized soul and loves to keep records; Nell is a people person and loves to help; Shawn enjoys feeding the hungry masses; and Luke enjoys working with money (that's why his favorite color is green).\n\r\n4. Wilson Rawls is perhaps best known for his book \"Giovanni's Gift\". Anne Rice's novel, \"Irish Whiskey\", is part of a series that was an immediate success and has remained popular over the years.\n\r\n5. Shawn's favorite color reminds you of freshly brewed espresso.\n\r\n6. On her last birthday, Nell got the opportunity to meet her favorite author, Mr. Robert Hellenga, and discuss his book \"Where the Red Fern Grows\".", "hint": "Authors and their books have been changed.\r\nBlood is not considered to be a color.\r\nJoie is a girl.", "answer": "Josh - Deliveries, Red, Blood and Gold, Andrew Greeley\r\nJoie - Inventory/Paperwork, Blue, Giovanni's Gift, Wilson Rawls\r\nLuke - Cashier, Green, Irish Whiskey, Anne Rice\r\nNell - Helping Customers, Gold, Where the Red Fern Grows, Robert Hellenga\r\nShawn - Food and Drinks, Black, The Fall of the Sparrow, Bradford Morrow", "category": "Logic-Grid", "date": "03/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are the owner of \"The Local Bar\", a failed tavern turned bookstore and coffee shop. You have been working nonstop for three years to get your business off the ground. Your hard work has paid off.\n\r\nYour business is one of the most popular in town. Your employees have become dear friends and have earned your trust and your confidence in their abilities. You decided to go on a vacation and look into new suppliers. You left your five employees with jobs to do to keep the shop running.\n\r\nUpon returning, you find that your employees have gone above and beyond what you have asked of them. You decide to get them each a first edition copy of their favorite book, wrapped in their favorite color. You will include a note telling them how well they did their job and how grateful you are for all their hard work. The problem, however, is that you forgot to write down who likes and did what and you seem to have forgotten during your time away. You do remember enough facts to figure it out.\n\r\nEmployees : Josh, Joie, Luke, Nell, and Shawn\n\r\nFavorite Authors : Wilson Rawls, Anne Rice, Andrew Greeley, Robert Hellenga, and Bradford Morrow\n\r\nFavorite Books : Where the Red Fern Grows, Blood and Gold, Irish Whiskey, The Fall of the Sparrow, and Giovanni's Gift\n\r\nJobs : Deliveries, Inventory/Paperwork, Cashier, Food and Drinks, and Helping Customers find the book they are looking for.\n\r\nFavorite Colors : Green, Blue, Red, Gold, and Black.\n\r\nHere are the facts you remember: \n\r\n1. Your five employees are: Shawn (who does not like Andrew Greeley); the person who likes red; the girl who likes \"Giovanni's Gift\"; the boy who likes Anne Rice; and Nell.\n\r\n2. The colors in the book titles do not match the color they were wrapped in; the titles and wrapping paper do not share the same starting letter; and the author's last names do not share the same starting letter as what they were wrapped in.\n\r\n3. Each person was given a job that suited them: Josh is always on time; Joie is an organized soul and loves to keep records; Nell is a people person and loves to help; Shawn enjoys feeding the hungry masses; and Luke enjoys working with money (that's why his favorite color is green).\n\r\n4. Wilson Rawls is perhaps best known for his book \"Giovanni's Gift\". Anne Rice's novel, \"Irish Whiskey\", is part of a series that was an immediate success and has remained popular over the years.\n\r\n5. Shawn's favorite color reminds you of freshly brewed espresso.\n\r\n6. On her last birthday, Nell got the opportunity to meet her favorite author, Mr. Robert Hellenga, and discuss his book \"Where the Red Fern Grows\".\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJosh - Deliveries, Red, Blood and Gold, Andrew Greeley\r\nJoie - Inventory/Paperwork, Blue, Giovanni's Gift, Wilson Rawls\r\nLuke - Cashier, Green, Irish Whiskey, Anne Rice\r\nNell - Helping Customers, Gold, Where the Red Fern Grows, Robert Hellenga\r\nShawn - Food and Drinks, Black, The Fall of the Sparrow, Bradford Morrow\n<|im_start|>answer\nJosh - Deliveries, Red, Blood and Gold, Andrew Greeley\r\nJoie - Inventory/Paperwork, Blue, Giovanni's Gift, Wilson Rawls\r\nLuke - Cashier, Green, Irish Whiskey, Anne Rice\r\nNell - Helping Customers, Gold, Where the Red Fern Grows, Robert Hellenga\r\nShawn - Food and Drinks, Black, The Fall of the Sparrow, Bradford Morrow\n<|im_end|>" }, { "id": "#33986", "title": "At the Dog Show", "fun": 3.06, "difficulty": 1.9000000000000001, "author": "teen_wiz", "desc": "It was the day of the National Dog Show. All throughout the host city of Rufftown, barks, growls, ruffs, and yaps could be heard.\n\r\nAlthough this was a huge event, the clumsy organizers were less than organized. Five minutes before the owners were to be admitted into the Great Hall, one of the desk clerks realized that they were missing five forms! All she could remember were the names, breeds, and shows, but she couldn't remember how they were organized. Can you solve the order of the form information, namely, the owners' first and last names, the dogs' names and breeds, and the competition they entered?\n\r\n1. The five owners are Ruffles' breeder, the one who entered his/her dog in Agility, Mr. Church, Norah, and the Yorkie's owner.\n\r\n2. Laurence, who does not own Princess Pepsi, entered his prized pup into Best of Breed. Jason did not show a Rough Collie.\n\r\n3. Ms. Knight loved to dress up her dog in adorable costumes and looked forward to it every year; she excitedly entered her dog in the Best Dressed competition.\n\r\n4. Kayla owned a Yorkie, whose name is not Moochums. Jason's last name is not Church.\n\r\n5. The Golden Retriever ALWAYS ended up tripping over the hurdles, so its owner didn't enter it in Agility.\n\r\n6. Lily the Yorkie looked simply adorable in her ballerina costume. The piano-playing Bulldog was entered in the Intelligence competition.\n\r\n7. Neither Laurence or Sharie's last name is Baron, and Jason's last name isn't Fitzgibbon.\n\r\n8. Norah Yeung taught Bubbles to play the piano over 3 years. Sharie's Poodle was very jealous.", "hint": "Lily was entered in the Best Dressed competition.", "answer": "Norah Yeung owned Bubbles the piano-playing Bulldog, whom she entered in Intelligence.\n\r\nJason Baron owned Ruffles the Golden Retriever and entered the beautiful dog in Best in Show.\n\r\nKayla Knight owned Lily the Yorkshire Terrier/ballerina in the Best Dressed Competition.\n\r\nLaurence Church owned Moochums the Rough Collie and entered the fluffy pooch in Best of Breed.\n\r\nSharie Fitzgibbon owned Princess Pepsi the Toy Poodle and entered it in Agility.\r\n~~~~~~~~~~~~~~~~\r\nThanks for helping the clumsy clerk! Now the dog show can run perfectly!", "category": "Logic-Grid", "date": "11/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was the day of the National Dog Show. All throughout the host city of Rufftown, barks, growls, ruffs, and yaps could be heard.\n\r\nAlthough this was a huge event, the clumsy organizers were less than organized. Five minutes before the owners were to be admitted into the Great Hall, one of the desk clerks realized that they were missing five forms! All she could remember were the names, breeds, and shows, but she couldn't remember how they were organized. Can you solve the order of the form information, namely, the owners' first and last names, the dogs' names and breeds, and the competition they entered?\n\r\n1. The five owners are Ruffles' breeder, the one who entered his/her dog in Agility, Mr. Church, Norah, and the Yorkie's owner.\n\r\n2. Laurence, who does not own Princess Pepsi, entered his prized pup into Best of Breed. Jason did not show a Rough Collie.\n\r\n3. Ms. Knight loved to dress up her dog in adorable costumes and looked forward to it every year; she excitedly entered her dog in the Best Dressed competition.\n\r\n4. Kayla owned a Yorkie, whose name is not Moochums. Jason's last name is not Church.\n\r\n5. The Golden Retriever ALWAYS ended up tripping over the hurdles, so its owner didn't enter it in Agility.\n\r\n6. Lily the Yorkie looked simply adorable in her ballerina costume. The piano-playing Bulldog was entered in the Intelligence competition.\n\r\n7. Neither Laurence or Sharie's last name is Baron, and Jason's last name isn't Fitzgibbon.\n\r\n8. Norah Yeung taught Bubbles to play the piano over 3 years. Sharie's Poodle was very jealous.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNorah Yeung owned Bubbles the piano-playing Bulldog, whom she entered in Intelligence.\n\r\nJason Baron owned Ruffles the Golden Retriever and entered the beautiful dog in Best in Show.\n\r\nKayla Knight owned Lily the Yorkshire Terrier/ballerina in the Best Dressed Competition.\n\r\nLaurence Church owned Moochums the Rough Collie and entered the fluffy pooch in Best of Breed.\n\r\nSharie Fitzgibbon owned Princess Pepsi the Toy Poodle and entered it in Agility.\r\n~~~~~~~~~~~~~~~~\r\nThanks for helping the clumsy clerk! Now the dog show can run perfectly!\n<|im_start|>answer\nNorah Yeung owned Bubbles the piano-playing Bulldog, whom she entered in Intelligence.\n\r\nJason Baron owned Ruffles the Golden Retriever and entered the beautiful dog in Best in Show.\n\r\nKayla Knight owned Lily the Yorkshire Terrier/ballerina in the Best Dressed Competition.\n\r\nLaurence Church owned Moochums the Rough Collie and entered the fluffy pooch in Best of Breed.\n\r\nSharie Fitzgibbon owned Princess Pepsi the Toy Poodle and entered it in Agility.\r\n~~~~~~~~~~~~~~~~\r\nThanks for helping the clumsy clerk! Now the dog show can run perfectly!\n<|im_end|>" }, { "id": "#49059", "title": "Astronomy Club Reunion", "fun": 3.06, "difficulty": 3.07, "author": "Gizzer", "desc": "John hadn't seen the other members of the Copernicus High School Astronomy Club since graduation, so he was surprised to run into all 5 of them while on vacation in Cape Town, South Africa. During a night of stargazing from Table Mountain, the men reminisced about their school days and shared details of their current lives. By the next morning, John had forgotten most of what he had been told. From the following information, can you piece together each astronomy club member's last name with his occupation, his city of residence and the organization to which he belongs? \n\r\nLast names: Cooper, Crater, Miller, Sutter, Weaver \r\nOccupations: Carpenter, Mason, Painter, Sculptor, Writer \r\nCities of Residence: Biloxi, Mississipi; Dallas, Texas; Houston, Texas; Mobile, Alabama; Phoenix, Arizona\r\nOrganizations: Braingle, Kiwanis, Lions, Mensa, Rotary \n\r\n1. Mr Weaver (who isn't the sculptor) isn't a member of Mensa and doesn't live in Texas. \r\n2. The writer (who isn't from Phoenix) isn't a member of Braingle or Rotary. \r\n3. The three members of the service organizations (Kiwanis, Lions and Rotary) are Mr Sutter, the carpenter and the man from Dallas. \r\n4. The painter (who isn't the Lions Club member) and the man from Biloxi played in the school band together. \r\n5. The sculptor (who isn't Mr Miller) and the man from Dallas were in Mrs Webster's English class. \r\n6. Mr Sutter (who isn't the sculptor) was in the same homeroom as the man from Houston. \r\n7. Neither the man from Mobile nor the man from Phoenix (who isn't Mr Cooper) has an account on Braingle. \r\n8. The man from Houston isn't a member of Mensa or Braingle. \r\n9. Mr Miller (who isn't a Rotarian), the carpenter and the writer were three of the starting players of the varsity basketball team.", "hint": "No hint available.", "answer": "From clue 3, the Kiwanian, the Lion and the Rotarian are, in some order, Sutter, the carpenter and the man from Dallas. The man from Houston must be one of these people (clue 8), but isn't from Dallas, and isn't Sutter (clue 6), and so must be the carpenter. The man with the account on Braingle isn't from Mobile or Phoenix (clue 7), so must be from Biloxi. Weaver doesn't live in either Houston or Dallas, and he isn't in Mensa (clue 1), so he must be a Braingler. Weaver isn't the painter (clue 4) or the writer (clue 2), so he must be the mason. The sculptor isn't Sutter (clue 6) or the man from Dallas (clue 5), so he isn't in a service organization, but he isn't Weaver (clue 1), so he must be in Mensa. Miller isn't the carpenter, the writer (clue 9) or the sculptor (clue 5), so he is the painter and must be from Dallas; he isn't a Rotarian (clue 9) or a Lions Club member (clue 4), so he is with Kiwanis. Since Sutter must be the writer, the sculptor must be from Phoenix (clue 2), and Sutter must be from Mobile. Cooper cannot be the sculptor (clue 7), so he is the carpenter, leaving Crater as the sculptor. The writer isn't with Rotary (clue 2), so he is in the Lions Club, and the carpenter is the Rotarian.\n\r\nCooper is a carpenter from Houston and a member of Rotary.\r\nCrater is a sculptor from Phoenix and a member of Mensa.\r\nMiller is a painter from Dallas and a member of Kiwanis.\r\nSutter is a writer from Mobile and a member of the Lions Club.\r\nWeaver is a mason from Biloxi and a member of Braingle.\n\r\nFun fact: Crater, Sculptor, Phoenix and Mensa are all Southern Hemisphere constellations.", "category": "Logic-Grid", "date": "10/10/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn hadn't seen the other members of the Copernicus High School Astronomy Club since graduation, so he was surprised to run into all 5 of them while on vacation in Cape Town, South Africa. During a night of stargazing from Table Mountain, the men reminisced about their school days and shared details of their current lives. By the next morning, John had forgotten most of what he had been told. From the following information, can you piece together each astronomy club member's last name with his occupation, his city of residence and the organization to which he belongs? \n\r\nLast names: Cooper, Crater, Miller, Sutter, Weaver \r\nOccupations: Carpenter, Mason, Painter, Sculptor, Writer \r\nCities of Residence: Biloxi, Mississipi; Dallas, Texas; Houston, Texas; Mobile, Alabama; Phoenix, Arizona\r\nOrganizations: Braingle, Kiwanis, Lions, Mensa, Rotary \n\r\n1. Mr Weaver (who isn't the sculptor) isn't a member of Mensa and doesn't live in Texas. \r\n2. The writer (who isn't from Phoenix) isn't a member of Braingle or Rotary. \r\n3. The three members of the service organizations (Kiwanis, Lions and Rotary) are Mr Sutter, the carpenter and the man from Dallas. \r\n4. The painter (who isn't the Lions Club member) and the man from Biloxi played in the school band together. \r\n5. The sculptor (who isn't Mr Miller) and the man from Dallas were in Mrs Webster's English class. \r\n6. Mr Sutter (who isn't the sculptor) was in the same homeroom as the man from Houston. \r\n7. Neither the man from Mobile nor the man from Phoenix (who isn't Mr Cooper) has an account on Braingle. \r\n8. The man from Houston isn't a member of Mensa or Braingle. \r\n9. Mr Miller (who isn't a Rotarian), the carpenter and the writer were three of the starting players of the varsity basketball team.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom clue 3, the Kiwanian, the Lion and the Rotarian are, in some order, Sutter, the carpenter and the man from Dallas. The man from Houston must be one of these people (clue 8), but isn't from Dallas, and isn't Sutter (clue 6), and so must be the carpenter. The man with the account on Braingle isn't from Mobile or Phoenix (clue 7), so must be from Biloxi. Weaver doesn't live in either Houston or Dallas, and he isn't in Mensa (clue 1), so he must be a Braingler. Weaver isn't the painter (clue 4) or the writer (clue 2), so he must be the mason. The sculptor isn't Sutter (clue 6) or the man from Dallas (clue 5), so he isn't in a service organization, but he isn't Weaver (clue 1), so he must be in Mensa. Miller isn't the carpenter, the writer (clue 9) or the sculptor (clue 5), so he is the painter and must be from Dallas; he isn't a Rotarian (clue 9) or a Lions Club member (clue 4), so he is with Kiwanis. Since Sutter must be the writer, the sculptor must be from Phoenix (clue 2), and Sutter must be from Mobile. Cooper cannot be the sculptor (clue 7), so he is the carpenter, leaving Crater as the sculptor. The writer isn't with Rotary (clue 2), so he is in the Lions Club, and the carpenter is the Rotarian.\n\r\nCooper is a carpenter from Houston and a member of Rotary.\r\nCrater is a sculptor from Phoenix and a member of Mensa.\r\nMiller is a painter from Dallas and a member of Kiwanis.\r\nSutter is a writer from Mobile and a member of the Lions Club.\r\nWeaver is a mason from Biloxi and a member of Braingle.\n\r\nFun fact: Crater, Sculptor, Phoenix and Mensa are all Southern Hemisphere constellations.\n<|im_start|>answer\nFrom clue 3, the Kiwanian, the Lion and the Rotarian are, in some order, Sutter, the carpenter and the man from Dallas. The man from Houston must be one of these people (clue 8), but isn't from Dallas, and isn't Sutter (clue 6), and so must be the carpenter. The man with the account on Braingle isn't from Mobile or Phoenix (clue 7), so must be from Biloxi. Weaver doesn't live in either Houston or Dallas, and he isn't in Mensa (clue 1), so he must be a Braingler. Weaver isn't the painter (clue 4) or the writer (clue 2), so he must be the mason. The sculptor isn't Sutter (clue 6) or the man from Dallas (clue 5), so he isn't in a service organization, but he isn't Weaver (clue 1), so he must be in Mensa. Miller isn't the carpenter, the writer (clue 9) or the sculptor (clue 5), so he is the painter and must be from Dallas; he isn't a Rotarian (clue 9) or a Lions Club member (clue 4), so he is with Kiwanis. Since Sutter must be the writer, the sculptor must be from Phoenix (clue 2), and Sutter must be from Mobile. Cooper cannot be the sculptor (clue 7), so he is the carpenter, leaving Crater as the sculptor. The writer isn't with Rotary (clue 2), so he is in the Lions Club, and the carpenter is the Rotarian.\n\r\nCooper is a carpenter from Houston and a member of Rotary.\r\nCrater is a sculptor from Phoenix and a member of Mensa.\r\nMiller is a painter from Dallas and a member of Kiwanis.\r\nSutter is a writer from Mobile and a member of the Lions Club.\r\nWeaver is a mason from Biloxi and a member of Braingle.\n\r\nFun fact: Crater, Sculptor, Phoenix and Mensa are all Southern Hemisphere constellations.\n<|im_end|>" }, { "id": "#29601", "title": "\"Oh, No!\"", "fun": 3.06, "difficulty": 2.14, "author": "Winner4600", "desc": "Oh, no! Chris, Dan, Jorge, Karl, and Eric have forgotten about Valentine's Day! And, it's February 13th! Each has bought a last-minute gift for his girlfriend, fiancee, or wife, wrapped in a different color. Figure out which gift each bought, the wrapping color, who he bought for, and what the relationships are.\n\r\n The five men are Dan, the guy who sent roses, the man who sent chocolate, Eric, and Zoe's fiance.\r\n The roses were wrapped in green. The chocolate was not wrapped in pink and white.\r\n The teddy bear was given to the 4 month girlfriend, who is not Tina.\r\n A delighted wife received a gift wrapped in purple. An equally happy girlfriend, not Tina, had a red-covered present.\r\n Carla has been dating for only 4 months, and Zoe was the most recently engaged.\r\n No man has the same first initial as his girlfriend, fiancee, or wife.\r\n Eric wasn't proposing to Tina, but gave her a ring, anyway. They are not married.\r\n Chris knows Zoe hates mushy stuff, so he got her an electronic device, wrapped in a color not normally associated with Valentine's Day.\r\n Jorge gave his fiancee a gift in emerald wrapping paper that matched the color of her eyes.", "hint": "No hint available.", "answer": "Chris, Zoe, 2 months engaged, Laptop, Blue\r\nDan, Carla, 4 months dating, Teddy Bear, Red\r\nJorge, Ellen, 3 months engaged, Roses, Green\r\nKarl, Joann, Married, Chocolate, Purple\r\nEric, Tina, 6 months dating, Ring, Pink and White", "category": "Logic-Grid", "date": "04/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOh, no! Chris, Dan, Jorge, Karl, and Eric have forgotten about Valentine's Day! And, it's February 13th! Each has bought a last-minute gift for his girlfriend, fiancee, or wife, wrapped in a different color. Figure out which gift each bought, the wrapping color, who he bought for, and what the relationships are.\n\r\n The five men are Dan, the guy who sent roses, the man who sent chocolate, Eric, and Zoe's fiance.\r\n The roses were wrapped in green. The chocolate was not wrapped in pink and white.\r\n The teddy bear was given to the 4 month girlfriend, who is not Tina.\r\n A delighted wife received a gift wrapped in purple. An equally happy girlfriend, not Tina, had a red-covered present.\r\n Carla has been dating for only 4 months, and Zoe was the most recently engaged.\r\n No man has the same first initial as his girlfriend, fiancee, or wife.\r\n Eric wasn't proposing to Tina, but gave her a ring, anyway. They are not married.\r\n Chris knows Zoe hates mushy stuff, so he got her an electronic device, wrapped in a color not normally associated with Valentine's Day.\r\n Jorge gave his fiancee a gift in emerald wrapping paper that matched the color of her eyes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChris, Zoe, 2 months engaged, Laptop, Blue\r\nDan, Carla, 4 months dating, Teddy Bear, Red\r\nJorge, Ellen, 3 months engaged, Roses, Green\r\nKarl, Joann, Married, Chocolate, Purple\r\nEric, Tina, 6 months dating, Ring, Pink and White\n<|im_start|>answer\nChris, Zoe, 2 months engaged, Laptop, Blue\r\nDan, Carla, 4 months dating, Teddy Bear, Red\r\nJorge, Ellen, 3 months engaged, Roses, Green\r\nKarl, Joann, Married, Chocolate, Purple\r\nEric, Tina, 6 months dating, Ring, Pink and White\n<|im_end|>" }, { "id": "#43645", "title": "Eliza Pseudonym and Her Unusual Dreams", "fun": 3.05, "difficulty": 3.09, "author": "mathgrant", "desc": "During a five-night period from Monday through Friday, Eliza Pseudonym had a series of unusual dreams. Every night, she had a dream set in a different unusual place (in one dream, Eliza found herself on trial in a courtroom). In each dream, a different one of her closest friends unexpectedly appeared and said something seemingly nonsensical. Eliza noted that she had eaten something different each night before going to bed; needless to say, she has sworn not to eat any of those foodstuffs so late at night ever again! From the clues below, determine the setting of the dream Eliza had each night, which of her friends made an appearance, what each friend said, and what food item Eliza had eaten each night.\n\r\n1. Eliza had a dream about her friend Carla precisely two nights before or two nights after her dream in which she was a soldier on a war-torn battlefield.\r\n2. The dream in which a friend said, \"I like shorts! They're comfy and easy to wear!\" occurred either the night before or the night after Eliza ate beef jerky.\r\n3. Eliza ate some delicious chocolate chip cookies on the night her dream featured a friend saying, \"I was raised by a cup of coffee!\"\r\n4. Barbra made an appearance in a dream precisely three nights before Eliza ate pickles.\r\n5. The dream with Delilah in it occurred some time prior to the dream in which Eliza's friend said, \"There is no nineteenth story, so there is no Miss Zarves.\"\r\n6. Eliza dreamed that she was the host of a popular talk show either the night before or the night after her dream where a friend said, \"Paleobotanical backwards licorice.\"\r\n7. Anna was in Eliza's dream precisely one night after pretzels were eaten before going to bed.\r\n8. A friend said, \"Mr. Jock, TV quiz PhD, bags few lynx,\" in the dream where Eliza was a scientist performing studies at a laboratory.\r\n9. Eliza ate an orange precisely two nights after she dreamed about dancing to funky music at a disco.\r\n10. Fiona appeared in Eliza's dream on Tuesday night.", "hint": "No hint available.", "answer": "Monday: disco, Barbra, \"I was raised by a cup of coffee!\", cookies\r\nTuesday: laboratory, Fiona, \"Mr. Jock, TV quiz PhD, bags few lynx\", pretzels\r\nWednesday: battlefield, Anna, \"Paleobotanical backwards licorice\", orange\r\nThursday: talk show, Delilah, \"I like shorts! They're comfy and easy to wear!\", pickles\r\nFriday: courtroom, Carla, \"There is no nineteenth story, so there is no Miss Zarves\", beef jerky", "category": "Logic-Grid", "date": "11/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a five-night period from Monday through Friday, Eliza Pseudonym had a series of unusual dreams. Every night, she had a dream set in a different unusual place (in one dream, Eliza found herself on trial in a courtroom). In each dream, a different one of her closest friends unexpectedly appeared and said something seemingly nonsensical. Eliza noted that she had eaten something different each night before going to bed; needless to say, she has sworn not to eat any of those foodstuffs so late at night ever again! From the clues below, determine the setting of the dream Eliza had each night, which of her friends made an appearance, what each friend said, and what food item Eliza had eaten each night.\n\r\n1. Eliza had a dream about her friend Carla precisely two nights before or two nights after her dream in which she was a soldier on a war-torn battlefield.\r\n2. The dream in which a friend said, \"I like shorts! They're comfy and easy to wear!\" occurred either the night before or the night after Eliza ate beef jerky.\r\n3. Eliza ate some delicious chocolate chip cookies on the night her dream featured a friend saying, \"I was raised by a cup of coffee!\"\r\n4. Barbra made an appearance in a dream precisely three nights before Eliza ate pickles.\r\n5. The dream with Delilah in it occurred some time prior to the dream in which Eliza's friend said, \"There is no nineteenth story, so there is no Miss Zarves.\"\r\n6. Eliza dreamed that she was the host of a popular talk show either the night before or the night after her dream where a friend said, \"Paleobotanical backwards licorice.\"\r\n7. Anna was in Eliza's dream precisely one night after pretzels were eaten before going to bed.\r\n8. A friend said, \"Mr. Jock, TV quiz PhD, bags few lynx,\" in the dream where Eliza was a scientist performing studies at a laboratory.\r\n9. Eliza ate an orange precisely two nights after she dreamed about dancing to funky music at a disco.\r\n10. Fiona appeared in Eliza's dream on Tuesday night.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday: disco, Barbra, \"I was raised by a cup of coffee!\", cookies\r\nTuesday: laboratory, Fiona, \"Mr. Jock, TV quiz PhD, bags few lynx\", pretzels\r\nWednesday: battlefield, Anna, \"Paleobotanical backwards licorice\", orange\r\nThursday: talk show, Delilah, \"I like shorts! They're comfy and easy to wear!\", pickles\r\nFriday: courtroom, Carla, \"There is no nineteenth story, so there is no Miss Zarves\", beef jerky\n<|im_start|>answer\nMonday: disco, Barbra, \"I was raised by a cup of coffee!\", cookies\r\nTuesday: laboratory, Fiona, \"Mr. Jock, TV quiz PhD, bags few lynx\", pretzels\r\nWednesday: battlefield, Anna, \"Paleobotanical backwards licorice\", orange\r\nThursday: talk show, Delilah, \"I like shorts! They're comfy and easy to wear!\", pickles\r\nFriday: courtroom, Carla, \"There is no nineteenth story, so there is no Miss Zarves\", beef jerky\n<|im_end|>" }, { "id": "#22983", "title": "Spring Break", "fun": 3.05, "difficulty": 2.48, "author": "kapmom", "desc": "Mike Jones, a travel agent at the Bon Voyage travel agency, was mildly surprised when five college students stopped by his office last Saturday morning, since each booked his spring-break trip months ahead of time. Each student came into the store at a different time and booked a trip to a different destination via a different mode of transportation. \r\nFrom the information provided, can you determine the time in the morning at which each student stopped by, as well as the destination and mode of transportation each chose?\n\r\n1. Taylor came into the office at some point after the student who booked the trip to Miami. The student who booked a train ticket came in at 11:00 a.m.\n\r\n2. The student who came in at 9:00 a.m. (who isn't the one named Allen) booked the trip to Washington D.C.\n\r\n3. Brian (who booked a rental car) came in exactly 30 minutes after Paul (who booked a trip to Orlando).\n\r\n4. The student who booked a trip to the Virgin Islands via sailboat is not the one who came in at 10:30 a.m.\n\r\n5. Dennis is not the one who booked a bus reservation.", "hint": "No hint available.", "answer": "9:00. Dennis, Washington DC, airplane\r\n9:30, Allen, Virgin Islands, sailboat\r\n10:00 Paul, Orlando, bus\r\n10:30 Brian, Miami, rental car\r\n11:00 Taylor, New Orleans, train", "category": "Logic-Grid", "date": "05/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMike Jones, a travel agent at the Bon Voyage travel agency, was mildly surprised when five college students stopped by his office last Saturday morning, since each booked his spring-break trip months ahead of time. Each student came into the store at a different time and booked a trip to a different destination via a different mode of transportation. \r\nFrom the information provided, can you determine the time in the morning at which each student stopped by, as well as the destination and mode of transportation each chose?\n\r\n1. Taylor came into the office at some point after the student who booked the trip to Miami. The student who booked a train ticket came in at 11:00 a.m.\n\r\n2. The student who came in at 9:00 a.m. (who isn't the one named Allen) booked the trip to Washington D.C.\n\r\n3. Brian (who booked a rental car) came in exactly 30 minutes after Paul (who booked a trip to Orlando).\n\r\n4. The student who booked a trip to the Virgin Islands via sailboat is not the one who came in at 10:30 a.m.\n\r\n5. Dennis is not the one who booked a bus reservation.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9:00. Dennis, Washington DC, airplane\r\n9:30, Allen, Virgin Islands, sailboat\r\n10:00 Paul, Orlando, bus\r\n10:30 Brian, Miami, rental car\r\n11:00 Taylor, New Orleans, train\n<|im_start|>answer\n9:00. Dennis, Washington DC, airplane\r\n9:30, Allen, Virgin Islands, sailboat\r\n10:00 Paul, Orlando, bus\r\n10:30 Brian, Miami, rental car\r\n11:00 Taylor, New Orleans, train\n<|im_end|>" }, { "id": "#28265", "title": "Dog Dads", "fun": 3.05, "difficulty": 1.73, "author": "Winner4600", "desc": "Jeff, Carl, Tom, Ben, and Alan are five loving dads. Their children, in no specific order, are Jenna, Harry, David, Patrick, and Mary. On five different days of the week, these dads decided to get their children different breeds of dogs. Your job is to figure out which child received which dog, on which day, from which dad, and what each dog was named.\n\r\n1. The five dads are Carl, David's father, the owner of the beagle, the owner of Lassie, and Ben.\r\n2. All the dogs' names have a relationship to the dog...For example, David named his dalmatian Spot, although it obviously has many more. Also, Harry named his poodle Curly.\r\n3. Ben gave a poodle to his son right after Sunday Mass.\r\n4. None of the dad's names start with the same letter as the name of their child, dog, or dog breed.\r\n5. Lassie was bought by Jeff on Friday. The beagle was bought for Patrick.\r\n6. Tom bought a dog for his son David on Thursday, but Carl went shopping on Monday.", "hint": "No hint available.", "answer": "Jeff-Mary-Collie-Lassie-Fri\r\nCarl-Jenna-Golden Retriever-Goldie-Mon\r\nTom-David-Dalmatian-Spot-Thurs\r\nBen-Harry-Poodle-Curly-Sun\r\nAlan-Patrick-Beagle-Snoopy-Wed", "category": "Logic-Grid", "date": "01/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeff, Carl, Tom, Ben, and Alan are five loving dads. Their children, in no specific order, are Jenna, Harry, David, Patrick, and Mary. On five different days of the week, these dads decided to get their children different breeds of dogs. Your job is to figure out which child received which dog, on which day, from which dad, and what each dog was named.\n\r\n1. The five dads are Carl, David's father, the owner of the beagle, the owner of Lassie, and Ben.\r\n2. All the dogs' names have a relationship to the dog...For example, David named his dalmatian Spot, although it obviously has many more. Also, Harry named his poodle Curly.\r\n3. Ben gave a poodle to his son right after Sunday Mass.\r\n4. None of the dad's names start with the same letter as the name of their child, dog, or dog breed.\r\n5. Lassie was bought by Jeff on Friday. The beagle was bought for Patrick.\r\n6. Tom bought a dog for his son David on Thursday, but Carl went shopping on Monday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJeff-Mary-Collie-Lassie-Fri\r\nCarl-Jenna-Golden Retriever-Goldie-Mon\r\nTom-David-Dalmatian-Spot-Thurs\r\nBen-Harry-Poodle-Curly-Sun\r\nAlan-Patrick-Beagle-Snoopy-Wed\n<|im_start|>answer\nJeff-Mary-Collie-Lassie-Fri\r\nCarl-Jenna-Golden Retriever-Goldie-Mon\r\nTom-David-Dalmatian-Spot-Thurs\r\nBen-Harry-Poodle-Curly-Sun\r\nAlan-Patrick-Beagle-Snoopy-Wed\n<|im_end|>" }, { "id": "#23965", "title": "Beethoven's Wig", "fun": 3.05, "difficulty": 1.1, "author": "beethovenswig", "desc": "Someone has stolen Beethoven's Wig and has put it in one of four locked boxes. The boxes are numbered from 1,2,3,4 in that order. There are four different keys that each has their own color. Use the clues below to figure out which key goes in which box and to find the box where Beethoven's wig is being kept. \n\r\n1. The green key goes to the third or fourth box\r\n2. The wig is to the left of the fourth box\r\n3. The wig is to the right of the first box\r\n4. The yellow key is to the left of the wig\r\n5. The blue key is to the right of the yellow key and to the left of the green key\r\n6. The red key goes to the first box", "hint": "No hint available.", "answer": "The wig is in the third box\r\nThe red key goes to the first box\r\nThe yellow key goes to the second box\r\nThe blue key goes to the third box\r\nThe green key goes to the fourth box", "category": "Logic", "date": "06/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSomeone has stolen Beethoven's Wig and has put it in one of four locked boxes. The boxes are numbered from 1,2,3,4 in that order. There are four different keys that each has their own color. Use the clues below to figure out which key goes in which box and to find the box where Beethoven's wig is being kept. \n\r\n1. The green key goes to the third or fourth box\r\n2. The wig is to the left of the fourth box\r\n3. The wig is to the right of the first box\r\n4. The yellow key is to the left of the wig\r\n5. The blue key is to the right of the yellow key and to the left of the green key\r\n6. The red key goes to the first box\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe wig is in the third box\r\nThe red key goes to the first box\r\nThe yellow key goes to the second box\r\nThe blue key goes to the third box\r\nThe green key goes to the fourth box\n<|im_start|>answer\nThe wig is in the third box\r\nThe red key goes to the first box\r\nThe yellow key goes to the second box\r\nThe blue key goes to the third box\r\nThe green key goes to the fourth box\n<|im_end|>" }, { "id": "#24749", "title": "Scent in Stone", "fun": 3.05, "difficulty": 1.81, "author": "tjm531", "desc": "After months of hard work, five scientists have eliminated the need for perfume by perfecting a procedure for creating scented jewelry! By altering the chemical composition of the metal, each scientist saturated a different piece of jewelry with a different scent. Upon completion of the items, the ingenious scientists brought them to the designers at Sentir Jewelers who set a different stone in each piece. From the information provided, determine the piece of jewelry each scientist had scented and the stone that was set within each piece.\n\r\nScientist: Dr. Phil, Dr. Ruth, Dr. Seuss, Dr. Spock, Dr. Zhivago\n\r\nPiece of Jewelry: Bracelet, Brooch, Earrings, Necklace, Ring\n\r\nScent: Lavender, Musk, Patchouli, Rose, Sandalwood\n\r\nStone: Amethyst, Cat's Eye, Garnet, Moonstone, Opal\n\r\n1. Neither the opal necklace nor the piece set with a moonstone is the patchouli-scented item (which wasn't created by Dr. Ruth).\n\r\n2. Dr. Phil's piece of jewelry is neither the lavender-scented one nor the rose-scented item.\n\r\n3. The amethyst (which wasn't placed in the ring altered by Dr. Zhivago) wasn't set in the pair of earrings Dr. Seuss altered.\n\r\n4. Dr. Spock is neither the scientist who worked on the brooch nor the one who fashioned the necklace.\n\r\n5. Dr. Seuss scented his jewelry with musk. A garnet was set in Dr. Ruth's piece.\n\r\n6. The piece set with moonstone (which isn't rose-scented) isn't the pair of earrings.", "hint": "No hint available.", "answer": "Dr. Phil, necklace, sandalwood, opal\r\nDr. Ruth, brooch, rose, garnet\r\nDr. Seuss, earrings, musk, cat's eye\r\nDr. Spock, bracelet, patchouli, amethyst\r\nDr. Zhivago, ring, lavender, moonstone", "category": "Logic-Grid", "date": "07/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter months of hard work, five scientists have eliminated the need for perfume by perfecting a procedure for creating scented jewelry! By altering the chemical composition of the metal, each scientist saturated a different piece of jewelry with a different scent. Upon completion of the items, the ingenious scientists brought them to the designers at Sentir Jewelers who set a different stone in each piece. From the information provided, determine the piece of jewelry each scientist had scented and the stone that was set within each piece.\n\r\nScientist: Dr. Phil, Dr. Ruth, Dr. Seuss, Dr. Spock, Dr. Zhivago\n\r\nPiece of Jewelry: Bracelet, Brooch, Earrings, Necklace, Ring\n\r\nScent: Lavender, Musk, Patchouli, Rose, Sandalwood\n\r\nStone: Amethyst, Cat's Eye, Garnet, Moonstone, Opal\n\r\n1. Neither the opal necklace nor the piece set with a moonstone is the patchouli-scented item (which wasn't created by Dr. Ruth).\n\r\n2. Dr. Phil's piece of jewelry is neither the lavender-scented one nor the rose-scented item.\n\r\n3. The amethyst (which wasn't placed in the ring altered by Dr. Zhivago) wasn't set in the pair of earrings Dr. Seuss altered.\n\r\n4. Dr. Spock is neither the scientist who worked on the brooch nor the one who fashioned the necklace.\n\r\n5. Dr. Seuss scented his jewelry with musk. A garnet was set in Dr. Ruth's piece.\n\r\n6. The piece set with moonstone (which isn't rose-scented) isn't the pair of earrings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDr. Phil, necklace, sandalwood, opal\r\nDr. Ruth, brooch, rose, garnet\r\nDr. Seuss, earrings, musk, cat's eye\r\nDr. Spock, bracelet, patchouli, amethyst\r\nDr. Zhivago, ring, lavender, moonstone\n<|im_start|>answer\nDr. Phil, necklace, sandalwood, opal\r\nDr. Ruth, brooch, rose, garnet\r\nDr. Seuss, earrings, musk, cat's eye\r\nDr. Spock, bracelet, patchouli, amethyst\r\nDr. Zhivago, ring, lavender, moonstone\n<|im_end|>" }, { "id": "#29467", "title": "Sheerluck Holmes", "fun": 3.05, "difficulty": 3.18, "author": "cnmne", "desc": "A series of burglaries has plagued London. The famous private investigator, Sheerluck Holmes, is on the case. He has five suspects. As usual, Sheerluck has bungled again, and has lost his notes. Fortunately, he has memorized some of the clues. Help Sheerluck determine each man's age, height, weight, and hair color. Also, help identify the culprit so that he can be put behind bars.\n\r\nMen: Ben, Gus, Ron, Sam, Tim\r\nAges: 29, 32, 37, 42, 46\r\nWeights: 166, 178, 190, 201, 216\r\nHeights: 5'8\", 5'9\", 6'0\", 6'3\", 6'4\"\r\nHair (descending order of darkness): black, brown, red, blonde ... plus bald\n\r\n1) The man who is 6'0\" tall is older than the man who weighs 178 pounds, who is older than Ben (one of these is the guilty man).\r\n2) Ron weighs more than the brown-haired man, who weighs more than the man who is 32 years old.\r\n3) Ben is taller than the blonde-haired man, who is taller than the man who weighs 166 pounds.\r\n4) The man who is 32 years old has darker hair than the man who weighs 190 pounds, who has darker hair than Tim (one of these is the guilty man).\r\n5) Each man has one measurement (age, weight, or height in inches) that is an odd number.\r\n6) The youngest, the lightest, and the shortest ... are three different men ... and do not have red hair (the guilty man is not among them).\r\n7) The oldest, the heaviest, and the tallest ... are three different men ... and do not have black hair (one of these is the guilty man).\r\n8) Ben and Gus have a weight difference of 12 pounds.\r\n9) Sam and Tim have a height difference of 3 inches.\r\n10) Ron is not 4 years older or younger than any other man.\r\n11) The guilty man does not have blonde hair.", "hint": "No hint available.", "answer": "First, fill in as much of the grid as possible, while ignoring the clues about the guilty man. Then, use those clues to fill in the rest of the grid. Given that the grid has been correctly filled, the following conclusions can be drawn.\n\r\nA) From clues 1 and 4, we know that the guilty man is one of the following: 6'0\" and 32, 6'0\" and 190, 6'0\" and Tim, 178 and 32, 178 and Tim, Ben and 32, Ben and 190.\r\nB) From clue 6 and since Ben is the youngest, Ben can be eliminated. Since Ben weighs 190, 190 can also be eliminated. This leaves the following combinations: 6'0\" and 32, 6'0\" and Tim, 178 and 32, 178 and Tim.\r\nC) From clue 6 and since the lightest man is also 32, 32 can be eliminated. This leaves: 6'0\" and Tim, 178 and Tim.\r\nD) Both of the remaining pairs involve Tim, so Tim is the guilty man.\r\nE) From clue 7 and since Tim is neither the heaviest nor the tallest, he must be the oldest, or 46.\r\nF) From clue 11, Tim can not have blonde hair.\n\r\nBen, 29 years, 190 pounds, 6'4\", brown\r\nGus, 42 years, 178 pounds, 6'3\", blonde\r\nRon, 37 years, 216 pounds, 5'8\", bald\r\nSam, 32 years, 166 pounds, 5'9\", black\r\nTim, 46 years, 201 pounds, 6'0\", red, guilty\n\r\nAnother case solved by sheer luck.", "category": "Logic-Grid", "date": "04/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA series of burglaries has plagued London. The famous private investigator, Sheerluck Holmes, is on the case. He has five suspects. As usual, Sheerluck has bungled again, and has lost his notes. Fortunately, he has memorized some of the clues. Help Sheerluck determine each man's age, height, weight, and hair color. Also, help identify the culprit so that he can be put behind bars.\n\r\nMen: Ben, Gus, Ron, Sam, Tim\r\nAges: 29, 32, 37, 42, 46\r\nWeights: 166, 178, 190, 201, 216\r\nHeights: 5'8\", 5'9\", 6'0\", 6'3\", 6'4\"\r\nHair (descending order of darkness): black, brown, red, blonde ... plus bald\n\r\n1) The man who is 6'0\" tall is older than the man who weighs 178 pounds, who is older than Ben (one of these is the guilty man).\r\n2) Ron weighs more than the brown-haired man, who weighs more than the man who is 32 years old.\r\n3) Ben is taller than the blonde-haired man, who is taller than the man who weighs 166 pounds.\r\n4) The man who is 32 years old has darker hair than the man who weighs 190 pounds, who has darker hair than Tim (one of these is the guilty man).\r\n5) Each man has one measurement (age, weight, or height in inches) that is an odd number.\r\n6) The youngest, the lightest, and the shortest ... are three different men ... and do not have red hair (the guilty man is not among them).\r\n7) The oldest, the heaviest, and the tallest ... are three different men ... and do not have black hair (one of these is the guilty man).\r\n8) Ben and Gus have a weight difference of 12 pounds.\r\n9) Sam and Tim have a height difference of 3 inches.\r\n10) Ron is not 4 years older or younger than any other man.\r\n11) The guilty man does not have blonde hair.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, fill in as much of the grid as possible, while ignoring the clues about the guilty man. Then, use those clues to fill in the rest of the grid. Given that the grid has been correctly filled, the following conclusions can be drawn.\n\r\nA) From clues 1 and 4, we know that the guilty man is one of the following: 6'0\" and 32, 6'0\" and 190, 6'0\" and Tim, 178 and 32, 178 and Tim, Ben and 32, Ben and 190.\r\nB) From clue 6 and since Ben is the youngest, Ben can be eliminated. Since Ben weighs 190, 190 can also be eliminated. This leaves the following combinations: 6'0\" and 32, 6'0\" and Tim, 178 and 32, 178 and Tim.\r\nC) From clue 6 and since the lightest man is also 32, 32 can be eliminated. This leaves: 6'0\" and Tim, 178 and Tim.\r\nD) Both of the remaining pairs involve Tim, so Tim is the guilty man.\r\nE) From clue 7 and since Tim is neither the heaviest nor the tallest, he must be the oldest, or 46.\r\nF) From clue 11, Tim can not have blonde hair.\n\r\nBen, 29 years, 190 pounds, 6'4\", brown\r\nGus, 42 years, 178 pounds, 6'3\", blonde\r\nRon, 37 years, 216 pounds, 5'8\", bald\r\nSam, 32 years, 166 pounds, 5'9\", black\r\nTim, 46 years, 201 pounds, 6'0\", red, guilty\n\r\nAnother case solved by sheer luck.\n<|im_start|>answer\nFirst, fill in as much of the grid as possible, while ignoring the clues about the guilty man. Then, use those clues to fill in the rest of the grid. Given that the grid has been correctly filled, the following conclusions can be drawn.\n\r\nA) From clues 1 and 4, we know that the guilty man is one of the following: 6'0\" and 32, 6'0\" and 190, 6'0\" and Tim, 178 and 32, 178 and Tim, Ben and 32, Ben and 190.\r\nB) From clue 6 and since Ben is the youngest, Ben can be eliminated. Since Ben weighs 190, 190 can also be eliminated. This leaves the following combinations: 6'0\" and 32, 6'0\" and Tim, 178 and 32, 178 and Tim.\r\nC) From clue 6 and since the lightest man is also 32, 32 can be eliminated. This leaves: 6'0\" and Tim, 178 and Tim.\r\nD) Both of the remaining pairs involve Tim, so Tim is the guilty man.\r\nE) From clue 7 and since Tim is neither the heaviest nor the tallest, he must be the oldest, or 46.\r\nF) From clue 11, Tim can not have blonde hair.\n\r\nBen, 29 years, 190 pounds, 6'4\", brown\r\nGus, 42 years, 178 pounds, 6'3\", blonde\r\nRon, 37 years, 216 pounds, 5'8\", bald\r\nSam, 32 years, 166 pounds, 5'9\", black\r\nTim, 46 years, 201 pounds, 6'0\", red, guilty\n\r\nAnother case solved by sheer luck.\n<|im_end|>" }, { "id": "#38375", "title": "Friends of The Bard", "fun": 3.05, "difficulty": 2.57, "author": "jppbl", "desc": "Jennifer and four of her friends are members of \"Friends of The Bard\", a Shakespeare fan club. The last meeting of the year is tomorrow morning, and each member is coming dressed as her favorite character and will read a passage from her favorite play. Everyone signed up to bring refreshments. Unfortunately, Jennifer's mischievous cat spread chocolate icing (from Jennifer's refreshment) all over the sign up sheets and she can't read it! Can you help her determine the full name of each member, their favorite characters, their favorite plays, and what refreshment they signed up to bring?\n\r\nFirst names: Cheryl, Jennifer, Marilyn, Patty, Stacey\r\nLast names: Carlson, Jameson, Malone, Pennington, Sullivan\r\nCharacters: Ariel, Kate, Mercutio, Ophelia, Puck\r\nPlays: Hamlet, A Midsummer Night's Dream, Romeo and Juliet, The Taming of the Shrew, The Tempest\r\nRefreshments: Brie, chips and dip, crackers, cupcakes, soda.\n\r\n1. No one's first name begins with the same letter as their last name.\r\n2. No one is bringing a snack that begins with the same letter as their first or last name.\r\n3. The five members are Cheryl, Ms. Malone, the one who is bringing Brie, the one whose favorite character is Puck, and the one whose favorite play is The Tempest.\r\n4. Ms. Sullivan, who is not Marilyn (whose favorite play isn't The Taming of the Shrew), once played Ophelia (who is not her favorite character) in her favorite play Hamlet.\r\n5. Cheryl's favorite character reminds her of a certain red-haired mermaid.\r\n6. Ms. Jameson (who hates Romeo and Juliet) feels that she can relate to her favorite character Ophelia.\r\n7. The one who is bringing the chips and dip (who isn't Marilyn) loves The Tempest.\r\n8. Patty loves the wit of Mercutio and can't wait to read a monologue from Romeo and Juliet.", "hint": "If you get stuck, reread the introduction.", "answer": "Jennifer, Sullivan, Puck, Hamlet, cupcakes\r\nCheryl, Pennington, Ariel, The Taming of the Shrew, soda\r\nPatty, Malone, Mercutio, Romeo and Juliet, crackers\r\nMarilyn, Carlson, Kate, A Midsummer Night's Dream, Brie\r\nStacey, Jameson, Ophelia, The Tempest, chips and dip", "category": "Logic-Grid", "date": "09/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJennifer and four of her friends are members of \"Friends of The Bard\", a Shakespeare fan club. The last meeting of the year is tomorrow morning, and each member is coming dressed as her favorite character and will read a passage from her favorite play. Everyone signed up to bring refreshments. Unfortunately, Jennifer's mischievous cat spread chocolate icing (from Jennifer's refreshment) all over the sign up sheets and she can't read it! Can you help her determine the full name of each member, their favorite characters, their favorite plays, and what refreshment they signed up to bring?\n\r\nFirst names: Cheryl, Jennifer, Marilyn, Patty, Stacey\r\nLast names: Carlson, Jameson, Malone, Pennington, Sullivan\r\nCharacters: Ariel, Kate, Mercutio, Ophelia, Puck\r\nPlays: Hamlet, A Midsummer Night's Dream, Romeo and Juliet, The Taming of the Shrew, The Tempest\r\nRefreshments: Brie, chips and dip, crackers, cupcakes, soda.\n\r\n1. No one's first name begins with the same letter as their last name.\r\n2. No one is bringing a snack that begins with the same letter as their first or last name.\r\n3. The five members are Cheryl, Ms. Malone, the one who is bringing Brie, the one whose favorite character is Puck, and the one whose favorite play is The Tempest.\r\n4. Ms. Sullivan, who is not Marilyn (whose favorite play isn't The Taming of the Shrew), once played Ophelia (who is not her favorite character) in her favorite play Hamlet.\r\n5. Cheryl's favorite character reminds her of a certain red-haired mermaid.\r\n6. Ms. Jameson (who hates Romeo and Juliet) feels that she can relate to her favorite character Ophelia.\r\n7. The one who is bringing the chips and dip (who isn't Marilyn) loves The Tempest.\r\n8. Patty loves the wit of Mercutio and can't wait to read a monologue from Romeo and Juliet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJennifer, Sullivan, Puck, Hamlet, cupcakes\r\nCheryl, Pennington, Ariel, The Taming of the Shrew, soda\r\nPatty, Malone, Mercutio, Romeo and Juliet, crackers\r\nMarilyn, Carlson, Kate, A Midsummer Night's Dream, Brie\r\nStacey, Jameson, Ophelia, The Tempest, chips and dip\n<|im_start|>answer\nJennifer, Sullivan, Puck, Hamlet, cupcakes\r\nCheryl, Pennington, Ariel, The Taming of the Shrew, soda\r\nPatty, Malone, Mercutio, Romeo and Juliet, crackers\r\nMarilyn, Carlson, Kate, A Midsummer Night's Dream, Brie\r\nStacey, Jameson, Ophelia, The Tempest, chips and dip\n<|im_end|>" }, { "id": "#25234", "title": "Musical Chairs", "fun": 3.05, "difficulty": 2.19, "author": "tjm531", "desc": "Grandpa Lowell is a carpenter with five granddaughters whom he absolutely adores. He wanted to do something very special for all of their upcoming birthdays and ended up taking on a very large task. He decided to hand craft rocking chairs for them, each from a different type of wood, each with their names embossed and a music box attached to each playing a different song. From the clues given, determine the age of the granddaughter, the type of wood used, and the melody the chair played.\n\r\nGirls: Amanda, Bonnie, Christine, Sylvia, Tanya\n\r\nAge: 2, 3, 4, 6, 8\n\r\nWood: Birch, Cherry, Mahogany, Maple, Oak\n\r\nMelody: \"The Big Rock Candy Mountain,\" \"Rock-A-Bye Baby,\" \"Rock-A My Soul,\" \"Rock Me Gently,\" \"Rock of Ages\"\n\r\n1. The oak chair was made for a girl who is exactly twice as old as Amanda (who isn't four years old). Sylvia isn't the intended recipient of the oak chair. The birch chair wasn't built for the eight-year-old (who isn't Christine).\n\r\n2. The mahogany rocker will be given to the child who is exactly twice as old as Bonnie, but younger than the at least one other child. The six-year-old isn't the intended recipient of the chair that plays \"Rock Me Gently\".\n\r\n3. The music box that plays \"Rock-A My Soul\" is attached to the chair made for the grandchild who is exactly twice as old as Sylvia. Bonnie is exactly half as old as the intended recipient of the chair whose music box plays \"Rock-A-Bye Baby\".\n\r\n4. The chair that has the music box that plays \"Rock of Ages\" will be presented to the three-year-old, while the two-year-old is getting the cherry-wood chair.", "hint": "The melodies in the grid were condensed to fit in the spaces provided (i.e. Candy Mtn = Big Rock Candy Mountain, Rock/Baby = Rock-A-Bye Baby, etc.)", "answer": "Bonnie, 2, cherry, \"Rock Me Gently\"\r\nAmanda, 3, birch, \"Rock of Ages\"\r\nSylvia, 4, mahogany, \"Rock-A-Bye Baby\"\r\nChristine, 6, oak, \"The Big Rock Candy Mountain\"\r\nTanya, 8, maple, \"Rock-A My Soul\"", "category": "Logic-Grid", "date": "08/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrandpa Lowell is a carpenter with five granddaughters whom he absolutely adores. He wanted to do something very special for all of their upcoming birthdays and ended up taking on a very large task. He decided to hand craft rocking chairs for them, each from a different type of wood, each with their names embossed and a music box attached to each playing a different song. From the clues given, determine the age of the granddaughter, the type of wood used, and the melody the chair played.\n\r\nGirls: Amanda, Bonnie, Christine, Sylvia, Tanya\n\r\nAge: 2, 3, 4, 6, 8\n\r\nWood: Birch, Cherry, Mahogany, Maple, Oak\n\r\nMelody: \"The Big Rock Candy Mountain,\" \"Rock-A-Bye Baby,\" \"Rock-A My Soul,\" \"Rock Me Gently,\" \"Rock of Ages\"\n\r\n1. The oak chair was made for a girl who is exactly twice as old as Amanda (who isn't four years old). Sylvia isn't the intended recipient of the oak chair. The birch chair wasn't built for the eight-year-old (who isn't Christine).\n\r\n2. The mahogany rocker will be given to the child who is exactly twice as old as Bonnie, but younger than the at least one other child. The six-year-old isn't the intended recipient of the chair that plays \"Rock Me Gently\".\n\r\n3. The music box that plays \"Rock-A My Soul\" is attached to the chair made for the grandchild who is exactly twice as old as Sylvia. Bonnie is exactly half as old as the intended recipient of the chair whose music box plays \"Rock-A-Bye Baby\".\n\r\n4. The chair that has the music box that plays \"Rock of Ages\" will be presented to the three-year-old, while the two-year-old is getting the cherry-wood chair.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBonnie, 2, cherry, \"Rock Me Gently\"\r\nAmanda, 3, birch, \"Rock of Ages\"\r\nSylvia, 4, mahogany, \"Rock-A-Bye Baby\"\r\nChristine, 6, oak, \"The Big Rock Candy Mountain\"\r\nTanya, 8, maple, \"Rock-A My Soul\"\n<|im_start|>answer\nBonnie, 2, cherry, \"Rock Me Gently\"\r\nAmanda, 3, birch, \"Rock of Ages\"\r\nSylvia, 4, mahogany, \"Rock-A-Bye Baby\"\r\nChristine, 6, oak, \"The Big Rock Candy Mountain\"\r\nTanya, 8, maple, \"Rock-A My Soul\"\n<|im_end|>" }, { "id": "#45629", "title": "Displayed in a Museum", "fun": 3.05, "difficulty": 2.24, "author": "whsprec", "desc": "A museum has 5 wings: North, South, East, West, and Central. These wings are where the museum displays their traveling exhibits. One year 5 different exhibits came, each one to a different wing. From the clues below, determine the name of the traveling exhibit, what month it opened, how long it was on display, and what wing it was housed in.\r\n1- East Wing hosted the Ancient Greek, an exhibition which opened later in the year than the one which lasted four months.\r\n2- The first exhibit to go on display lasted for 3 months.\r\n3- The exhibitions in North Wing opened in June.\r\n4- Aztec was on display for a period of five months.\r\n5- The six month touring exhibit was allocated to West Wing.\r\n6- The exhibition starting in September ran for longer than the display of the Samurai.\r\n7- The exhibition entitled Masada and Dead Sea Scrolls opened two months before the display in Central Wing; their duration differed by more than a month.", "hint": "No hint available.", "answer": "In February the Masada and Dead Sea Scrolls display opened in South Wing for 3 months.\r\nIn April the Aztec display opened in Central Wing for 5 months.\r\nIn June the Samurai display opened in North Wing for 4 months.\r\nIn September King Tut opened in West Wing for 6 months.\r\nIn November the Ancient Greek opened in East Wing for 2 months.", "category": "Logic-Grid", "date": "11/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA museum has 5 wings: North, South, East, West, and Central. These wings are where the museum displays their traveling exhibits. One year 5 different exhibits came, each one to a different wing. From the clues below, determine the name of the traveling exhibit, what month it opened, how long it was on display, and what wing it was housed in.\r\n1- East Wing hosted the Ancient Greek, an exhibition which opened later in the year than the one which lasted four months.\r\n2- The first exhibit to go on display lasted for 3 months.\r\n3- The exhibitions in North Wing opened in June.\r\n4- Aztec was on display for a period of five months.\r\n5- The six month touring exhibit was allocated to West Wing.\r\n6- The exhibition starting in September ran for longer than the display of the Samurai.\r\n7- The exhibition entitled Masada and Dead Sea Scrolls opened two months before the display in Central Wing; their duration differed by more than a month.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn February the Masada and Dead Sea Scrolls display opened in South Wing for 3 months.\r\nIn April the Aztec display opened in Central Wing for 5 months.\r\nIn June the Samurai display opened in North Wing for 4 months.\r\nIn September King Tut opened in West Wing for 6 months.\r\nIn November the Ancient Greek opened in East Wing for 2 months.\n<|im_start|>answer\nIn February the Masada and Dead Sea Scrolls display opened in South Wing for 3 months.\r\nIn April the Aztec display opened in Central Wing for 5 months.\r\nIn June the Samurai display opened in North Wing for 4 months.\r\nIn September King Tut opened in West Wing for 6 months.\r\nIn November the Ancient Greek opened in East Wing for 2 months.\n<|im_end|>" }, { "id": "#30633", "title": "Spring Flowers", "fun": 3.05, "difficulty": 2.11, "author": "locomom", "desc": "Spring is here! All the gardens on Hilldale Avenue are ablaze with color from flowering bulbs. The five gardens are each filled with different flowers. Alice and her neighbors, including Taylor, planted their bulbs at different times last summer and fall. From the following clues, can you determine each neighbor's first and last name, type of bulbs in each garden, each neighbor's address and when their bulbs were planted?\n\r\nFirst names: Alice, Bob, Carl, Denise, Evelyn\r\nLast names: Stewart, Taylor, Upland, Vickers, Wilson\r\nAddresses: 23, 24, 25, 26, 27\r\nBulbs: Tulips, Daffodils, Crocus, Snowdrops, Hyacinths\r\nPlanting Dates: Aug.30, Sept.10, Sept.26, Oct.2, Oct.31\n\r\n1. The 5 neighbors are Carl, the daffodil lady, Stewart, the neighbor who always plants last, and the one who resides at number 24.\n\r\n2. Ms. Wilson returned from her vacation on the last day of September, just in time to plant her bulbs at number 23 Hilldale Avenue.\n\r\n3. Vickers planted her bulbs after number 27 but long before the crocus went into the ground.\n\r\n4. Denise always plants her bulbs, which have an initial letter that is the same as the initial of her last name, on the date that corresponds with her address.\n\r\n5. Mr. Taylor gave out Halloween goodies for \"Trick or Treat\" on the same day that he planted his crocus bulbs.\n\r\n6. Alice Vickers dislikes the smell of hyacinths.", "hint": "No hint available.", "answer": "Alice Vickers, Tulips, Sept.10, No. 24\r\nBob Taylor, Crocus, Oct.31, No.25\r\nCarl Upland, Hyacinths, Aug.30, No.27\r\nDenise Stewart, Snowdrops, Sept.26, No. 26\r\nEvelyn Wilson, Daffodils, Oct.2, No.23", "category": "Logic-Grid", "date": "05/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSpring is here! All the gardens on Hilldale Avenue are ablaze with color from flowering bulbs. The five gardens are each filled with different flowers. Alice and her neighbors, including Taylor, planted their bulbs at different times last summer and fall. From the following clues, can you determine each neighbor's first and last name, type of bulbs in each garden, each neighbor's address and when their bulbs were planted?\n\r\nFirst names: Alice, Bob, Carl, Denise, Evelyn\r\nLast names: Stewart, Taylor, Upland, Vickers, Wilson\r\nAddresses: 23, 24, 25, 26, 27\r\nBulbs: Tulips, Daffodils, Crocus, Snowdrops, Hyacinths\r\nPlanting Dates: Aug.30, Sept.10, Sept.26, Oct.2, Oct.31\n\r\n1. The 5 neighbors are Carl, the daffodil lady, Stewart, the neighbor who always plants last, and the one who resides at number 24.\n\r\n2. Ms. Wilson returned from her vacation on the last day of September, just in time to plant her bulbs at number 23 Hilldale Avenue.\n\r\n3. Vickers planted her bulbs after number 27 but long before the crocus went into the ground.\n\r\n4. Denise always plants her bulbs, which have an initial letter that is the same as the initial of her last name, on the date that corresponds with her address.\n\r\n5. Mr. Taylor gave out Halloween goodies for \"Trick or Treat\" on the same day that he planted his crocus bulbs.\n\r\n6. Alice Vickers dislikes the smell of hyacinths.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlice Vickers, Tulips, Sept.10, No. 24\r\nBob Taylor, Crocus, Oct.31, No.25\r\nCarl Upland, Hyacinths, Aug.30, No.27\r\nDenise Stewart, Snowdrops, Sept.26, No. 26\r\nEvelyn Wilson, Daffodils, Oct.2, No.23\n<|im_start|>answer\nAlice Vickers, Tulips, Sept.10, No. 24\r\nBob Taylor, Crocus, Oct.31, No.25\r\nCarl Upland, Hyacinths, Aug.30, No.27\r\nDenise Stewart, Snowdrops, Sept.26, No. 26\r\nEvelyn Wilson, Daffodils, Oct.2, No.23\n<|im_end|>" }, { "id": "#46993", "title": "The Dragon Slayer", "fun": 3.05, "difficulty": 1.81, "author": "griphook", "desc": "Victor the Viking lived in a distant land inhabited by dragons and sea monsters.\n\r\nThe dragon population later became a threat to the kingdom. The King, who married Victor's sister and made her his queen, announced a contest. The warrior who could kill the most number of dragons from sunrise to sunset of next Sunday would be declared winner and marry the King's only daughter.\n\r\nOn the eve of the contest, Gringo the Gorgeous, first born of and heir to the King, slept early to conserve his energy with his sharpened ax beside him.\n\r\nVictor the Viking, who almost forgot his ax and shield, rode his black gelding into the forbidden forest and camped there overnight to gain a headstart.\n\r\nAbner the Able spent the night in his house sharpening his spatha and polishing his bronze shield. he had his squire prepare his stallion for the contest.\n\r\nBrav the Bold woke up very late the morning of the contest and had to ride his horse like crazy to catch up with the others.\n\r\nIgor the Terrible, the only warrior who used two weapons was able to kill 4 dragons with his ax and 5 dragons with his spear.\n\r\nAt the wedding dinner hosted by the king later that evening, the winner, who killed more than a half dozen dragons with his ax, and his proud parents were honored by the King.\n\r\nThe winner's horse was castrated and retired from duty. The winner's bronze shield was permanently displayed in the King's Hall.\n\r\nWho won the contest?", "hint": "No hint available.", "answer": "Brav the Bold won the contest. (by process of elimination)\n\r\nGringo the Gorgeous, first born of the king, could not be the winner because the winner was not the king's son. The winner and his parents were honored by the King.\n\r\nAbner the Able, whose only weapon was a spatha( a sword) could not be the winner because the winner used an ax to kill dragons. Only Igor used two weapons.\n\r\nIgor the Terrible, who killed only 4 dragons with his ax (and 5 dragons with his spear), could not be the winner because the winner killed more than a half dozen dragons with his ax.\n\r\nVictor the Viking, whose horse was a gelding(castrated horse), could not be the winner because the winner's horse was castrated after the contest.\n\r\nBrav the Bold must have killed at least 10 dragons because Igor killed a total of 9. More than a half dozen means a number greater than 6, including 10.", "category": "Logic", "date": "05/14/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nVictor the Viking lived in a distant land inhabited by dragons and sea monsters.\n\r\nThe dragon population later became a threat to the kingdom. The King, who married Victor's sister and made her his queen, announced a contest. The warrior who could kill the most number of dragons from sunrise to sunset of next Sunday would be declared winner and marry the King's only daughter.\n\r\nOn the eve of the contest, Gringo the Gorgeous, first born of and heir to the King, slept early to conserve his energy with his sharpened ax beside him.\n\r\nVictor the Viking, who almost forgot his ax and shield, rode his black gelding into the forbidden forest and camped there overnight to gain a headstart.\n\r\nAbner the Able spent the night in his house sharpening his spatha and polishing his bronze shield. he had his squire prepare his stallion for the contest.\n\r\nBrav the Bold woke up very late the morning of the contest and had to ride his horse like crazy to catch up with the others.\n\r\nIgor the Terrible, the only warrior who used two weapons was able to kill 4 dragons with his ax and 5 dragons with his spear.\n\r\nAt the wedding dinner hosted by the king later that evening, the winner, who killed more than a half dozen dragons with his ax, and his proud parents were honored by the King.\n\r\nThe winner's horse was castrated and retired from duty. The winner's bronze shield was permanently displayed in the King's Hall.\n\r\nWho won the contest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrav the Bold won the contest. (by process of elimination)\n\r\nGringo the Gorgeous, first born of the king, could not be the winner because the winner was not the king's son. The winner and his parents were honored by the King.\n\r\nAbner the Able, whose only weapon was a spatha( a sword) could not be the winner because the winner used an ax to kill dragons. Only Igor used two weapons.\n\r\nIgor the Terrible, who killed only 4 dragons with his ax (and 5 dragons with his spear), could not be the winner because the winner killed more than a half dozen dragons with his ax.\n\r\nVictor the Viking, whose horse was a gelding(castrated horse), could not be the winner because the winner's horse was castrated after the contest.\n\r\nBrav the Bold must have killed at least 10 dragons because Igor killed a total of 9. More than a half dozen means a number greater than 6, including 10.\n<|im_start|>answer\nBrav the Bold won the contest. (by process of elimination)\n\r\nGringo the Gorgeous, first born of the king, could not be the winner because the winner was not the king's son. The winner and his parents were honored by the King.\n\r\nAbner the Able, whose only weapon was a spatha( a sword) could not be the winner because the winner used an ax to kill dragons. Only Igor used two weapons.\n\r\nIgor the Terrible, who killed only 4 dragons with his ax (and 5 dragons with his spear), could not be the winner because the winner killed more than a half dozen dragons with his ax.\n\r\nVictor the Viking, whose horse was a gelding(castrated horse), could not be the winner because the winner's horse was castrated after the contest.\n\r\nBrav the Bold must have killed at least 10 dragons because Igor killed a total of 9. More than a half dozen means a number greater than 6, including 10.\n<|im_end|>" }, { "id": "#9653", "title": "Survival of the People", "fun": 3.05, "difficulty": 3.01, "author": "sakirski", "desc": "The Situation:\r\nThere is an island with 10 inhabitants. One day a monster comes and says that he intends to eat every one of them but will give them a chance to survive in the following way:\r\nIn the morning, the monster will line up all the people - single file so that the last person sees the remaining 9, the next person sees the remaining 8, and so on until the first person that obviously sees no one in front of himself. The monster will then place black or white hats on their heads randomly (they can be all white, all black or any combination thereof).\r\nThe monster will offer each person starting with the last one (who sees everyone else's hats) to guess the color of his/her own hat. The answer can only be one word: \"white\" or \"black\". The monster will eat him on the spot if he guessed wrong, and will leave him alive if he guessed right. All the remaining people will hear both the guess and the outcome of the guess. The monster will then go on to the next to last person (who only sees 8 people), and so on until the end. \r\nThe monster gives them the whole night to think.\n\r\nThe Task:\r\nDevise the optimal strategy that these poor natives could use to maximize their survival rate.\n\r\nAssumptions:\r\n1) All the 10 people can easily understand your strategy, and will execute it with perfect precision.\r\n2) If the monster suspects that any of the people are giving away information to any of the remaining team members by intonation of words when answering, or any other signs, or by touch, he will eat everyone.\r\n3) The only allowed response is a short, unemotional \"white\" or \"black\".\r\n4) Having said that, I will add that you can put any value you like into each of these words. For example, \"white\" can mean \"my mother did my laundry\" and \"black\" can mean the guy in front of me is wearing a black hat.", "hint": "1) First hint is an example. Here is a simple strategy that will guarantee safety to 50%. Guy #10 (when he guesses) says the color of the hat on guy #9. Thus #10 may die or may luck out, but #9 will save himself since he will know his hat color. Thus #8 helps #7, #6 helps number #5, and so on. You thus save numbers 9, 7, 5, 3, and 1, or half the people. But you can do a lot better than that.\r\n2) The best strategy will save a minimum of 90% of the people.", "answer": "Here it is: The first guy to guess (guy #10) will be the only one to assume the following value for the words \"white\" and \"black\": The answer \"black\" will mean that there are an odd number of black hats that he sees. The answer \"white\" will mean that there are an odd number of white hats that he sees. This way one by one all the other 9 people will know the color of their hats.\r\nLet us say that guy #10 (first to speak, and sees the hats of the remaining 9) says \"white\". That should mean to everybody else that he sees an odd number of white hats. At this time guy #9 will either be wearing a white or a black hat. If he is wearing a white hat he will only see an even number of white hats, and since guy #10 said that there is and odd number of white hats, guy #9 will know that he is wearing white and will say it. But if guy #9 is wearing a black hat, he will see an odd number of white hats (just like #10 did), and thus will know that he is wearing a black hat and will say it. No matter what #9 answers, guy #8 (who heard guy #10 and guy #9) can now easily incorporate the color of hat on guy #9 into the original answer of guy #10. This will allow #8 to know if he should see an odd or even number of white hats in front of him to determine his own hat color. The same thing repeats with #7-1. And they all get it right except of course #10, though he may get lucky.", "category": "Logic", "date": "01/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Situation:\r\nThere is an island with 10 inhabitants. One day a monster comes and says that he intends to eat every one of them but will give them a chance to survive in the following way:\r\nIn the morning, the monster will line up all the people - single file so that the last person sees the remaining 9, the next person sees the remaining 8, and so on until the first person that obviously sees no one in front of himself. The monster will then place black or white hats on their heads randomly (they can be all white, all black or any combination thereof).\r\nThe monster will offer each person starting with the last one (who sees everyone else's hats) to guess the color of his/her own hat. The answer can only be one word: \"white\" or \"black\". The monster will eat him on the spot if he guessed wrong, and will leave him alive if he guessed right. All the remaining people will hear both the guess and the outcome of the guess. The monster will then go on to the next to last person (who only sees 8 people), and so on until the end. \r\nThe monster gives them the whole night to think.\n\r\nThe Task:\r\nDevise the optimal strategy that these poor natives could use to maximize their survival rate.\n\r\nAssumptions:\r\n1) All the 10 people can easily understand your strategy, and will execute it with perfect precision.\r\n2) If the monster suspects that any of the people are giving away information to any of the remaining team members by intonation of words when answering, or any other signs, or by touch, he will eat everyone.\r\n3) The only allowed response is a short, unemotional \"white\" or \"black\".\r\n4) Having said that, I will add that you can put any value you like into each of these words. For example, \"white\" can mean \"my mother did my laundry\" and \"black\" can mean the guy in front of me is wearing a black hat.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHere it is: The first guy to guess (guy #10) will be the only one to assume the following value for the words \"white\" and \"black\": The answer \"black\" will mean that there are an odd number of black hats that he sees. The answer \"white\" will mean that there are an odd number of white hats that he sees. This way one by one all the other 9 people will know the color of their hats.\r\nLet us say that guy #10 (first to speak, and sees the hats of the remaining 9) says \"white\". That should mean to everybody else that he sees an odd number of white hats. At this time guy #9 will either be wearing a white or a black hat. If he is wearing a white hat he will only see an even number of white hats, and since guy #10 said that there is and odd number of white hats, guy #9 will know that he is wearing white and will say it. But if guy #9 is wearing a black hat, he will see an odd number of white hats (just like #10 did), and thus will know that he is wearing a black hat and will say it. No matter what #9 answers, guy #8 (who heard guy #10 and guy #9) can now easily incorporate the color of hat on guy #9 into the original answer of guy #10. This will allow #8 to know if he should see an odd or even number of white hats in front of him to determine his own hat color. The same thing repeats with #7-1. And they all get it right except of course #10, though he may get lucky.\n<|im_start|>answer\nHere it is: The first guy to guess (guy #10) will be the only one to assume the following value for the words \"white\" and \"black\": The answer \"black\" will mean that there are an odd number of black hats that he sees. The answer \"white\" will mean that there are an odd number of white hats that he sees. This way one by one all the other 9 people will know the color of their hats.\r\nLet us say that guy #10 (first to speak, and sees the hats of the remaining 9) says \"white\". That should mean to everybody else that he sees an odd number of white hats. At this time guy #9 will either be wearing a white or a black hat. If he is wearing a white hat he will only see an even number of white hats, and since guy #10 said that there is and odd number of white hats, guy #9 will know that he is wearing white and will say it. But if guy #9 is wearing a black hat, he will see an odd number of white hats (just like #10 did), and thus will know that he is wearing a black hat and will say it. No matter what #9 answers, guy #8 (who heard guy #10 and guy #9) can now easily incorporate the color of hat on guy #9 into the original answer of guy #10. This will allow #8 to know if he should see an odd or even number of white hats in front of him to determine his own hat color. The same thing repeats with #7-1. And they all get it right except of course #10, though he may get lucky.\n<|im_end|>" }, { "id": "#29839", "title": "Tic-Tac-Toothpick", "fun": 3.05, "difficulty": 1.53, "author": "Jake", "desc": "Moving only three toothpicks, can you make three identical squares from the arrangement below?", "hint": "No hint available.", "answer": "Move the toothpicks marked with grey into the positions marked with green.", "category": "Logic", "date": "04/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMoving only three toothpicks, can you make three identical squares from the arrangement below?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMove the toothpicks marked with grey into the positions marked with green.\n<|im_start|>answer\nMove the toothpicks marked with grey into the positions marked with green.\n<|im_end|>" }, { "id": "#42460", "title": "Five Little Kittens", "fun": 3.04, "difficulty": 2.14, "author": "Shelilah", "desc": "In a small cottage near the woods, five kittens were born. Their names were Purry, Whiskers, Mewler, Kiki, and Cayli. They each had different fur patterns, a certain favorite treat, and a secret hideout. There was a calico cat, a Siamese cat, a gray tabby cat, a black cat, and an orange cat. The foods they liked were one of the following: salmon, tuna, chicken, turkey, or shrimp. The places that they went to hide were the front porch, the forest, the roof, under the table, and behind the couch.\n\r\n1. The kitten who often explored in the forest had a coat which allowed him to blend in with the shadows.\r\n2. Purry liked to spy on the black cat from her secret hideout. She had a great view because of the height she had to climb to get to her hideout.\r\n3. The two cats who liked fish liked to stay indoors. The two cats who liked poultry wanted to go outside but were afraid of the forest.\r\n4. Cayli loved being outdoors, but she didn't want to go too far away. She thought that Kiki and the Siamese cat were missing out on the sunlight.\r\n5. Whiskers couldn't stand the stench of shrimp and tuna.\r\n6. The kitten with gray stripes bragged that she was the closest to the sun, but the orange cat believed that her spot allowed her to get plenty of sunlight.\r\n7. Whenever the aroma of turkey reached her, Purry would quickly climb down and go back inside to get some.\r\n8. The Siamese cat loved the fish that began with the same letter as his breed, and he would always sleep right beneath where this delicious fish was served.", "hint": "No hint available.", "answer": "Purry was a gray tabby cat; she liked to eat turkey and climb up on the roof.\r\nWhiskers was a Siamese cat; he liked to eat salmon and sleep under the table.\r\nKiki was a calico cat; she liked to eat tuna and hide behind the couch.\r\nMewler was a black cat; he liked to eat shrimp and go in the forest.\r\nCayli was an orange cat; she liked to eat chicken and sleep on the front porch.", "category": "Logic-Grid", "date": "07/10/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a small cottage near the woods, five kittens were born. Their names were Purry, Whiskers, Mewler, Kiki, and Cayli. They each had different fur patterns, a certain favorite treat, and a secret hideout. There was a calico cat, a Siamese cat, a gray tabby cat, a black cat, and an orange cat. The foods they liked were one of the following: salmon, tuna, chicken, turkey, or shrimp. The places that they went to hide were the front porch, the forest, the roof, under the table, and behind the couch.\n\r\n1. The kitten who often explored in the forest had a coat which allowed him to blend in with the shadows.\r\n2. Purry liked to spy on the black cat from her secret hideout. She had a great view because of the height she had to climb to get to her hideout.\r\n3. The two cats who liked fish liked to stay indoors. The two cats who liked poultry wanted to go outside but were afraid of the forest.\r\n4. Cayli loved being outdoors, but she didn't want to go too far away. She thought that Kiki and the Siamese cat were missing out on the sunlight.\r\n5. Whiskers couldn't stand the stench of shrimp and tuna.\r\n6. The kitten with gray stripes bragged that she was the closest to the sun, but the orange cat believed that her spot allowed her to get plenty of sunlight.\r\n7. Whenever the aroma of turkey reached her, Purry would quickly climb down and go back inside to get some.\r\n8. The Siamese cat loved the fish that began with the same letter as his breed, and he would always sleep right beneath where this delicious fish was served.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPurry was a gray tabby cat; she liked to eat turkey and climb up on the roof.\r\nWhiskers was a Siamese cat; he liked to eat salmon and sleep under the table.\r\nKiki was a calico cat; she liked to eat tuna and hide behind the couch.\r\nMewler was a black cat; he liked to eat shrimp and go in the forest.\r\nCayli was an orange cat; she liked to eat chicken and sleep on the front porch.\n<|im_start|>answer\nPurry was a gray tabby cat; she liked to eat turkey and climb up on the roof.\r\nWhiskers was a Siamese cat; he liked to eat salmon and sleep under the table.\r\nKiki was a calico cat; she liked to eat tuna and hide behind the couch.\r\nMewler was a black cat; he liked to eat shrimp and go in the forest.\r\nCayli was an orange cat; she liked to eat chicken and sleep on the front porch.\n<|im_end|>" }, { "id": "#23378", "title": "Well-used Truck", "fun": 3.04, "difficulty": 2.82, "author": "Gadget", "desc": "Over a ten year period a truck was owned by 4 consecutive men, each a master of a different trade in a different city. From the following clues, identify the first and last names of the owners and the order in which they owned the truck. Also, each man's trade, where he worked, and the duration that he owned the truck.\n\r\n1. Mike owned the truck for 3 years.\n\r\n2. The plumber bought the truck new.\n\r\n3. Smith did not work in Newark.\n\r\n4. The fourth man owned the truck for the least amount of time, and was not the electrician.\n\r\n5. The third owner's last name was Jones.\n\r\n6. Joe worked in Chicago. He sold the truck to the man who owned it for 4 years.\n\r\n7. Tom, the painter, did not work in Boston.\n\r\n8. Pat's last name is Reilly.\n\r\n9. The mason from New York sold the truck to Kelly.", "hint": "The plumber from Chicago owned the truck for 2 years.", "answer": "Joe Smith, plumber, Chicago, 2 years.\n\r\nPat Reilly, electrician, Boston, 4 years.\n\r\nMike Jones, mason, New York, 3 years.\n\r\nTom Kelly, painter, Newark, 1 year.", "category": "Logic-Grid", "date": "06/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOver a ten year period a truck was owned by 4 consecutive men, each a master of a different trade in a different city. From the following clues, identify the first and last names of the owners and the order in which they owned the truck. Also, each man's trade, where he worked, and the duration that he owned the truck.\n\r\n1. Mike owned the truck for 3 years.\n\r\n2. The plumber bought the truck new.\n\r\n3. Smith did not work in Newark.\n\r\n4. The fourth man owned the truck for the least amount of time, and was not the electrician.\n\r\n5. The third owner's last name was Jones.\n\r\n6. Joe worked in Chicago. He sold the truck to the man who owned it for 4 years.\n\r\n7. Tom, the painter, did not work in Boston.\n\r\n8. Pat's last name is Reilly.\n\r\n9. The mason from New York sold the truck to Kelly.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoe Smith, plumber, Chicago, 2 years.\n\r\nPat Reilly, electrician, Boston, 4 years.\n\r\nMike Jones, mason, New York, 3 years.\n\r\nTom Kelly, painter, Newark, 1 year.\n<|im_start|>answer\nJoe Smith, plumber, Chicago, 2 years.\n\r\nPat Reilly, electrician, Boston, 4 years.\n\r\nMike Jones, mason, New York, 3 years.\n\r\nTom Kelly, painter, Newark, 1 year.\n<|im_end|>" }, { "id": "#26803", "title": "After School Activities", "fun": 3.04, "difficulty": 1.9000000000000001, "author": "Rob2003", "desc": "Five parents pick up their children at the Parkway Elementary School every Tuesday to bring the kids to their after school activity. Five children all attended a different after school activity and their parents always arrive at different times (between 3:00 pm and 3:30 pm). \n\r\nChild's name: Colleen, Donald, Josh, Margie, and Mary \n\r\nParent's name: Ann, Capri, Kathy, David and Lynne\n\r\nLast Name: Dobson, Holden, Johnson, Steinway, and Walsh \n\r\nTimes picked up: 3:00, 3:10, 3:20, 3:25, and 3:30\n\r\nActivities: ballet, chess, fencing, football, and hiking.\n\r\nDetermine each child's full name, the first name of the parent picking them up (all the parents' last names are the same as their child's), the time each was picked up, and the activity each child is being brought to.\n\r\n1. Margie's best friend's mother, Mrs. Dobson, arrived before Kathy came to pick up her son. Mrs. Walsh picked up her daughter for fencing.\n\r\n2. Josh Steinway loved football as much as Donald liked chess and they both liked being the last two to be picked up.\n\r\n3. David Holden picked up his daughter for her hiking as soon as he could, but Lynne was always there before he was.\n\r\n4. Margie liked being the first one picked up but she didn't take ballet or hiking.\n\r\n5. Lynne's daughter was not Margie.\n\r\n6. In order of their departure from school: Ann, the girl who took ballet, Mary Holden, the boy who took football, and Capri Johnson.", "hint": "Colleen is a girl's name", "answer": "Colleen Dobson: Lynne, 3:10, ballet\r\nDonald Johnson: Capri, 3:30, chess\r\nJosh Steinway: Kathy, 3:25, football\r\nMargie Walsh: Ann, 3:00 pm, fencing\r\nMary Holden: David, 3:20 pm, hiking", "category": "Logic-Grid", "date": "11/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive parents pick up their children at the Parkway Elementary School every Tuesday to bring the kids to their after school activity. Five children all attended a different after school activity and their parents always arrive at different times (between 3:00 pm and 3:30 pm). \n\r\nChild's name: Colleen, Donald, Josh, Margie, and Mary \n\r\nParent's name: Ann, Capri, Kathy, David and Lynne\n\r\nLast Name: Dobson, Holden, Johnson, Steinway, and Walsh \n\r\nTimes picked up: 3:00, 3:10, 3:20, 3:25, and 3:30\n\r\nActivities: ballet, chess, fencing, football, and hiking.\n\r\nDetermine each child's full name, the first name of the parent picking them up (all the parents' last names are the same as their child's), the time each was picked up, and the activity each child is being brought to.\n\r\n1. Margie's best friend's mother, Mrs. Dobson, arrived before Kathy came to pick up her son. Mrs. Walsh picked up her daughter for fencing.\n\r\n2. Josh Steinway loved football as much as Donald liked chess and they both liked being the last two to be picked up.\n\r\n3. David Holden picked up his daughter for her hiking as soon as he could, but Lynne was always there before he was.\n\r\n4. Margie liked being the first one picked up but she didn't take ballet or hiking.\n\r\n5. Lynne's daughter was not Margie.\n\r\n6. In order of their departure from school: Ann, the girl who took ballet, Mary Holden, the boy who took football, and Capri Johnson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nColleen Dobson: Lynne, 3:10, ballet\r\nDonald Johnson: Capri, 3:30, chess\r\nJosh Steinway: Kathy, 3:25, football\r\nMargie Walsh: Ann, 3:00 pm, fencing\r\nMary Holden: David, 3:20 pm, hiking\n<|im_start|>answer\nColleen Dobson: Lynne, 3:10, ballet\r\nDonald Johnson: Capri, 3:30, chess\r\nJosh Steinway: Kathy, 3:25, football\r\nMargie Walsh: Ann, 3:00 pm, fencing\r\nMary Holden: David, 3:20 pm, hiking\n<|im_end|>" }, { "id": "#52308", "title": "Hans vs Heather", "fun": 3.04, "difficulty": 1.04, "author": "wimpykidfan37", "desc": "Hans Ernest Froopaloop, Jr. wants to drive his motorboat across a lake. At the same time, Heather wants to swim across the lake. So, Heather dons her gorgeous white string bikini and jumps into the lake at the same time Hans starts his motor.\n\r\nThey both follow exactly the same path and maintain a constant speed. Hans's motorboat's speed is exactly ten times as fast as Heather's swimming speed.\n\r\nHowever, when Hans is three-quarters of the way to the destination, the motorboat runs out of gas. Then it decides to ignore Newton's First Law and immediately comes to a complete stop.\n\r\nNow poor Hans has to row his boat the rest of the way. But he is such a slow rower, and Heather is such a fast swimmer, that she swims exactly four times as fast as he rows.\n\r\nWho will reach the destination first?", "hint": "No hint available.", "answer": "Heather will make it first.\n\r\nSince Heather swims exactly four times as fast as Hans rows, it will take her as much time to swim the whole way as it will for him to row one quarter of the way, that is, from the three-quarter point to the end.\n\r\nTherefore, if the motorboat's speed is anything short of infinite, Heather will reach the destination first.", "category": "Logic", "date": "11/26/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHans Ernest Froopaloop, Jr. wants to drive his motorboat across a lake. At the same time, Heather wants to swim across the lake. So, Heather dons her gorgeous white string bikini and jumps into the lake at the same time Hans starts his motor.\n\r\nThey both follow exactly the same path and maintain a constant speed. Hans's motorboat's speed is exactly ten times as fast as Heather's swimming speed.\n\r\nHowever, when Hans is three-quarters of the way to the destination, the motorboat runs out of gas. Then it decides to ignore Newton's First Law and immediately comes to a complete stop.\n\r\nNow poor Hans has to row his boat the rest of the way. But he is such a slow rower, and Heather is such a fast swimmer, that she swims exactly four times as fast as he rows.\n\r\nWho will reach the destination first?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHeather will make it first.\n\r\nSince Heather swims exactly four times as fast as Hans rows, it will take her as much time to swim the whole way as it will for him to row one quarter of the way, that is, from the three-quarter point to the end.\n\r\nTherefore, if the motorboat's speed is anything short of infinite, Heather will reach the destination first.\n<|im_start|>answer\nHeather will make it first.\n\r\nSince Heather swims exactly four times as fast as Hans rows, it will take her as much time to swim the whole way as it will for him to row one quarter of the way, that is, from the three-quarter point to the end.\n\r\nTherefore, if the motorboat's speed is anything short of infinite, Heather will reach the destination first.\n<|im_end|>" }, { "id": "#28301", "title": "Couples Around the World", "fun": 3.04, "difficulty": 2.04, "author": "wizkid", "desc": "Jeff has five friends who have gone to different countries for a while to study the culture. He received a letter from each of his friends telling of the girls they found in these countries. Jeff lost the letters and forgot who found whom. Help him figure out which guy found which girl and each girl's hobby, name, favorite food and in which country they were found.\n\r\nFriends: Jerry, John, Mark, Luis, and Bill\r\nGirls: Jennifer, Jessica, Marissa, Ashley, Brittany.\r\nCountries: United States, Brazil, Norway, India, Denmark.\r\nHobbies: Playing the piano, Read, Cook, Clean, Shop.\r\nFavorite Foods: Pizza, Lasagna, Lamb Chops, Steak, Shrimp.\n\r\n1. The five friends are: The one who found Jennifer, the one who found the girl that likes to eat pizza, John, the one who found the girl from Denmark [who likes lasagna], and the one who found the girl who loves to shop.\n\r\n2. The five girls are: The one found by Mark, the one who likes steak, the one who likes to play the piano, Ashley, and the girl found by John [who loves lamb chops].\n\r\n3. No guy found a girl who shared the same initial in their names.\n\r\n4. Part of Brazil is on the coast, there is a lot of seafood that is brought in. Jennifer lives close to the seafood market. She always secretly orders extra shrimp, her favorite.\n\r\n5. Unlike Jeff's other friends, Luis didn't leave the United States. This is how he found Jessica, the master shopper.\n\r\n6. Brittany came from a long line of musicians, her grandfather left her the piano she loves so dearly.\n\r\n7. Jennifer was very smart and creative. This came from her continuous reading.\n\r\n8. Although Ashley cooks, she doesn't mind ordering the best food in the world, pizza.\n\r\n9. The girl from India loves to cook.", "hint": "Don't use names and favorite foods to base assumptions of the countries.", "answer": "Jerry-Brittany-Denmark-Piano-Lasagna\r\nJohn-Marissa-Norway-Clean-Lamb Chops\r\nMark-Jennifer-Brazil-Read-Shrimp\r\nLuis-Jessica-United States-Shop-Steak\r\nBill-Ashley-India-Cook-Pizza", "category": "Logic-Grid", "date": "01/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeff has five friends who have gone to different countries for a while to study the culture. He received a letter from each of his friends telling of the girls they found in these countries. Jeff lost the letters and forgot who found whom. Help him figure out which guy found which girl and each girl's hobby, name, favorite food and in which country they were found.\n\r\nFriends: Jerry, John, Mark, Luis, and Bill\r\nGirls: Jennifer, Jessica, Marissa, Ashley, Brittany.\r\nCountries: United States, Brazil, Norway, India, Denmark.\r\nHobbies: Playing the piano, Read, Cook, Clean, Shop.\r\nFavorite Foods: Pizza, Lasagna, Lamb Chops, Steak, Shrimp.\n\r\n1. The five friends are: The one who found Jennifer, the one who found the girl that likes to eat pizza, John, the one who found the girl from Denmark [who likes lasagna], and the one who found the girl who loves to shop.\n\r\n2. The five girls are: The one found by Mark, the one who likes steak, the one who likes to play the piano, Ashley, and the girl found by John [who loves lamb chops].\n\r\n3. No guy found a girl who shared the same initial in their names.\n\r\n4. Part of Brazil is on the coast, there is a lot of seafood that is brought in. Jennifer lives close to the seafood market. She always secretly orders extra shrimp, her favorite.\n\r\n5. Unlike Jeff's other friends, Luis didn't leave the United States. This is how he found Jessica, the master shopper.\n\r\n6. Brittany came from a long line of musicians, her grandfather left her the piano she loves so dearly.\n\r\n7. Jennifer was very smart and creative. This came from her continuous reading.\n\r\n8. Although Ashley cooks, she doesn't mind ordering the best food in the world, pizza.\n\r\n9. The girl from India loves to cook.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJerry-Brittany-Denmark-Piano-Lasagna\r\nJohn-Marissa-Norway-Clean-Lamb Chops\r\nMark-Jennifer-Brazil-Read-Shrimp\r\nLuis-Jessica-United States-Shop-Steak\r\nBill-Ashley-India-Cook-Pizza\n<|im_start|>answer\nJerry-Brittany-Denmark-Piano-Lasagna\r\nJohn-Marissa-Norway-Clean-Lamb Chops\r\nMark-Jennifer-Brazil-Read-Shrimp\r\nLuis-Jessica-United States-Shop-Steak\r\nBill-Ashley-India-Cook-Pizza\n<|im_end|>" }, { "id": "#20952", "title": "Beanstalk Delight", "fun": 3.04, "difficulty": 2.66, "author": "lorial", "desc": "Jack, of Beanstalk fame, had been given some coloured beans. He shared them out among his friends and they planted them. What colour bean was each given, what colour beanstalk grew from each bean and how tall did they grow?\t\n\r\nNo beanstalk's colours included the bean's colour from which it grew.\n\r\nHumpty was impressed with his multi coloured beanstalk (not grown from an orange bean) that grew taller than Bo Peep's beanstalk by at least a metre.\n\r\nThe beanstalk grown from the orange bean grew exactly twice as tall as the bean that Goldilocks planted.\t\n\r\nThe 2 metre tall beanstalk was grown from either a green or a blue bean.\n\r\nThe red bean grew into a beanstalk containing green.\n\r\nThe green bean grew into a taller beanstalk than the beanstalk grown from the blue bean.\n\r\nThe red and blue spotted beanstalk grew to exactly 2.5metres in height.\n\r\nJack Spratt's beanstalk, much to his delight, was multi coloured.\n\r\nMiss Muffett's beanstalk had red and orange stripes; it did not grow from a yellow bean.\n\r\nNames:\tBo Peep, Goldilocks, Humpty, Jack Spratt, Miss Muffett\r\nBean Colour: Blue, Green, Orange, Red, Yellow\r\nBeanstalk Colour: Blue & Green, Green & Orange, Red & Blue, Red & Orange, Yellow\r\nHeight:\t1mtr, 2mtr, 2.5mtr, 3mtr, 4mtr", "hint": "No hint available.", "answer": "Name / Bean Colour / Beanstalk Colour / Height\n\r\nBo Peep / Red / Green & Orange / 1 mtr\r\nGoldilocks / Blue / Yellow / 2 mtr\r\nHumpty / Yellow / Red & Blue / 2.5mtr\r\nJack Spratt / Orange / Blue & Green / 4mtr\r\nMiss Muffett / Green / Red & Orange / 3mtr", "category": "Logic-Grid", "date": "02/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack, of Beanstalk fame, had been given some coloured beans. He shared them out among his friends and they planted them. What colour bean was each given, what colour beanstalk grew from each bean and how tall did they grow?\t\n\r\nNo beanstalk's colours included the bean's colour from which it grew.\n\r\nHumpty was impressed with his multi coloured beanstalk (not grown from an orange bean) that grew taller than Bo Peep's beanstalk by at least a metre.\n\r\nThe beanstalk grown from the orange bean grew exactly twice as tall as the bean that Goldilocks planted.\t\n\r\nThe 2 metre tall beanstalk was grown from either a green or a blue bean.\n\r\nThe red bean grew into a beanstalk containing green.\n\r\nThe green bean grew into a taller beanstalk than the beanstalk grown from the blue bean.\n\r\nThe red and blue spotted beanstalk grew to exactly 2.5metres in height.\n\r\nJack Spratt's beanstalk, much to his delight, was multi coloured.\n\r\nMiss Muffett's beanstalk had red and orange stripes; it did not grow from a yellow bean.\n\r\nNames:\tBo Peep, Goldilocks, Humpty, Jack Spratt, Miss Muffett\r\nBean Colour: Blue, Green, Orange, Red, Yellow\r\nBeanstalk Colour: Blue & Green, Green & Orange, Red & Blue, Red & Orange, Yellow\r\nHeight:\t1mtr, 2mtr, 2.5mtr, 3mtr, 4mtr\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName / Bean Colour / Beanstalk Colour / Height\n\r\nBo Peep / Red / Green & Orange / 1 mtr\r\nGoldilocks / Blue / Yellow / 2 mtr\r\nHumpty / Yellow / Red & Blue / 2.5mtr\r\nJack Spratt / Orange / Blue & Green / 4mtr\r\nMiss Muffett / Green / Red & Orange / 3mtr\n<|im_start|>answer\nName / Bean Colour / Beanstalk Colour / Height\n\r\nBo Peep / Red / Green & Orange / 1 mtr\r\nGoldilocks / Blue / Yellow / 2 mtr\r\nHumpty / Yellow / Red & Blue / 2.5mtr\r\nJack Spratt / Orange / Blue & Green / 4mtr\r\nMiss Muffett / Green / Red & Orange / 3mtr\n<|im_end|>" }, { "id": "#32046", "title": "Reporting...Historical Leaders", "fun": 3.04, "difficulty": 2.05, "author": "Winner4600", "desc": "Ten students in Ms. Borowski's 6th grade class have been given a HUGE project!!! They have to research famous historical leaders (assigned--they can't even choose), and present them in front of the class using creative methods. However, they can at least work in pairs! Can you figure out which pairs presented whom, what presentation method they used, and what grade they received?\n\r\nTony and Lizzy received the same grade - one did a documentary and the other created a PowerPoint Presentation.\n\r\nTony lent Roxanne a book on Simon Bolivar for her project, not knowing that Jenna had already borrowed the same book from the library.\n\r\nSarah couldn't get Karl to do anything more than a timeline, which received the lowest grade.\n\r\nChurchill ended up on a poster.\n\r\nZoe did not receive a B.\n\r\nDanielle had already done numerous reports on Hitler, so she was thankful when she was assigned Churchill.\n\r\nAlthough he wasn't supposed to, Joey helped Adam with his documentary of Hitler, since Joey was doing a report on the American leader during that time period.", "hint": "No hint available.", "answer": "Zoe - Danielle - Churchill - Poster - C\r\nAdam - Lizzy - Hitler - Documentary - A\r\nKarl - Sarah - Zedong - Timeline - D\r\nTony - Joey - Roosevelt - PowerPoint - A\r\nJenna - Roxanne - Bolivar - Book - B", "category": "Logic-Grid", "date": "07/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTen students in Ms. Borowski's 6th grade class have been given a HUGE project!!! They have to research famous historical leaders (assigned--they can't even choose), and present them in front of the class using creative methods. However, they can at least work in pairs! Can you figure out which pairs presented whom, what presentation method they used, and what grade they received?\n\r\nTony and Lizzy received the same grade - one did a documentary and the other created a PowerPoint Presentation.\n\r\nTony lent Roxanne a book on Simon Bolivar for her project, not knowing that Jenna had already borrowed the same book from the library.\n\r\nSarah couldn't get Karl to do anything more than a timeline, which received the lowest grade.\n\r\nChurchill ended up on a poster.\n\r\nZoe did not receive a B.\n\r\nDanielle had already done numerous reports on Hitler, so she was thankful when she was assigned Churchill.\n\r\nAlthough he wasn't supposed to, Joey helped Adam with his documentary of Hitler, since Joey was doing a report on the American leader during that time period.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZoe - Danielle - Churchill - Poster - C\r\nAdam - Lizzy - Hitler - Documentary - A\r\nKarl - Sarah - Zedong - Timeline - D\r\nTony - Joey - Roosevelt - PowerPoint - A\r\nJenna - Roxanne - Bolivar - Book - B\n<|im_start|>answer\nZoe - Danielle - Churchill - Poster - C\r\nAdam - Lizzy - Hitler - Documentary - A\r\nKarl - Sarah - Zedong - Timeline - D\r\nTony - Joey - Roosevelt - PowerPoint - A\r\nJenna - Roxanne - Bolivar - Book - B\n<|im_end|>" }, { "id": "#20639", "title": "Seven Jack O'Lanterns", "fun": 3.03, "difficulty": 2.45, "author": "fishmed", "desc": "It appears that you have angered the spirit of Halloween by failing to revere the Great Pumpkin, and now a curse has befallen you. On the walkway to your house is a Ward of Seven Jack O'Lanterns arranged in a circle. If midnight comes and any of the seven are still lit, a dark reaper and seven dark horses with seven dark riders shall visit thy abode. They shall surround thy domicile and, while circling it, they will proceed to pelt thy dwelling with eggs and cream of shaving. And come morn there will be a great mess to be reckoned with. Verily. So you better get those lanterns out. \n\r\nYou quickly discover something odd about these lanterns. When you blow out the first one, the lanterns on either side extinguish as well! But there is more. If you blow out a lantern adjacent to one that is extinguished, the extinguished one(s) will relight. It seems that blowing on any lantern will change the state of three - the one you blew on and its two neighbors. Finally, you can blow on an extinguished lantern and it will relight, and its neighbors will light/extinguish as applicable. After trying once and finding all seven lit again, you decide, being the excellent puzzler, you sit down and examine this closer. But hurry, I hear the beating of many hooves...", "hint": "No hint available.", "answer": "If you examine the setup carefully, you'll note a number of facts which make the puzzle easier to solve by deduction. First, blowing on a lantern is a commutative property; blowing on lanterns 1, 5, then 3 is the same as blowing on 3, then 1, and then 5. No matter what order the lanterns are blown on, if the same lanterns are blown on the same number of times, the result won't change. For that reason, blowing on a lantern twice is as good as not blowing on it at all. And three times is as good as one time. So, it seems that it should be able to be done in seven steps or less. \n\r\nWhat else can we tell about the solution? Since each operation changes the state of three lanterns, and there are 7 lanterns, and each lantern must change its state an odd number of times, it's a safe bet that there will need to be an odd number of steps. We can easily see it can't be done in 1 or 3 steps, so it must be 5 or 7. Trying 5 steps comes up with 3 different patterns that are not symmetrical and fail to leave all lanterns extinguished. So that leaves 7 steps and to your surprise, based on the commutative property, the easiest solution is to blow on each one in order! So doing this, the Great Pumpkin has decided to give you a treat for figuring this out and you find all seven lanterns full of candy the next morning! Congratulations!", "category": "Logic", "date": "01/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt appears that you have angered the spirit of Halloween by failing to revere the Great Pumpkin, and now a curse has befallen you. On the walkway to your house is a Ward of Seven Jack O'Lanterns arranged in a circle. If midnight comes and any of the seven are still lit, a dark reaper and seven dark horses with seven dark riders shall visit thy abode. They shall surround thy domicile and, while circling it, they will proceed to pelt thy dwelling with eggs and cream of shaving. And come morn there will be a great mess to be reckoned with. Verily. So you better get those lanterns out. \n\r\nYou quickly discover something odd about these lanterns. When you blow out the first one, the lanterns on either side extinguish as well! But there is more. If you blow out a lantern adjacent to one that is extinguished, the extinguished one(s) will relight. It seems that blowing on any lantern will change the state of three - the one you blew on and its two neighbors. Finally, you can blow on an extinguished lantern and it will relight, and its neighbors will light/extinguish as applicable. After trying once and finding all seven lit again, you decide, being the excellent puzzler, you sit down and examine this closer. But hurry, I hear the beating of many hooves...\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you examine the setup carefully, you'll note a number of facts which make the puzzle easier to solve by deduction. First, blowing on a lantern is a commutative property; blowing on lanterns 1, 5, then 3 is the same as blowing on 3, then 1, and then 5. No matter what order the lanterns are blown on, if the same lanterns are blown on the same number of times, the result won't change. For that reason, blowing on a lantern twice is as good as not blowing on it at all. And three times is as good as one time. So, it seems that it should be able to be done in seven steps or less. \n\r\nWhat else can we tell about the solution? Since each operation changes the state of three lanterns, and there are 7 lanterns, and each lantern must change its state an odd number of times, it's a safe bet that there will need to be an odd number of steps. We can easily see it can't be done in 1 or 3 steps, so it must be 5 or 7. Trying 5 steps comes up with 3 different patterns that are not symmetrical and fail to leave all lanterns extinguished. So that leaves 7 steps and to your surprise, based on the commutative property, the easiest solution is to blow on each one in order! So doing this, the Great Pumpkin has decided to give you a treat for figuring this out and you find all seven lanterns full of candy the next morning! Congratulations!\n<|im_start|>answer\nIf you examine the setup carefully, you'll note a number of facts which make the puzzle easier to solve by deduction. First, blowing on a lantern is a commutative property; blowing on lanterns 1, 5, then 3 is the same as blowing on 3, then 1, and then 5. No matter what order the lanterns are blown on, if the same lanterns are blown on the same number of times, the result won't change. For that reason, blowing on a lantern twice is as good as not blowing on it at all. And three times is as good as one time. So, it seems that it should be able to be done in seven steps or less. \n\r\nWhat else can we tell about the solution? Since each operation changes the state of three lanterns, and there are 7 lanterns, and each lantern must change its state an odd number of times, it's a safe bet that there will need to be an odd number of steps. We can easily see it can't be done in 1 or 3 steps, so it must be 5 or 7. Trying 5 steps comes up with 3 different patterns that are not symmetrical and fail to leave all lanterns extinguished. So that leaves 7 steps and to your surprise, based on the commutative property, the easiest solution is to blow on each one in order! So doing this, the Great Pumpkin has decided to give you a treat for figuring this out and you find all seven lanterns full of candy the next morning! Congratulations!\n<|im_end|>" }, { "id": "#38783", "title": "Dinner Engagement", "fun": 3.03, "difficulty": 2.06, "author": "dreamlvr1432", "desc": "Three women (Dana, Barbara, & Ellen) and two men (Ben & Max) went to dinner at their favorite restaurant to celebrate the engagement of two of their friends. Each ordered a different entree (shrimp & pasta, chicken cordon bleu, vegetable medley, fillet mignon, & NY strip steak), and a different dessert (fudge cake, vanilla ice cream, apple crisp, chocolate cream pie, & strawberry parfait). Can you determine each person's full name and what entree and dessert they ordered?\n\r\n1) Nobody's first name starts with the same letter as their last name.\n\r\n2) Klein and Bronson are dating.\n\r\n3) Ms. Mathers is a vegetarian.\n\r\n4) The 5 friends are the man who ordered fudge cake, the one who ordered chicken cordon bleu, Ellen, the woman who ordered fillet mignon, and Mr. Klein (who ordered ice cream).\n\r\n5) Mr. Klein and Dana shared their desserts.\n\r\n6) Delaney and Ruiz are engaged. Neither of them ordered beef.\n\r\n7) Ben does not care for chocolate and is allergic to strawberries.\n\r\n8) Delaney did not order chocolate cream pie or apple crisp for dessert.\n\r\n9) Ben and Ruiz have been friends since high school, and were laughing over dinner about how they have always liked the same girls, until Barbara came along.", "hint": "For the purposes of this puzzle...assume that there are no same sex couples.", "answer": "Max Ruiz ordered shrimp & pasta and fudge cake.\r\nBarbara Delaney ordered chicken cordon bleu and strawberry parfait.\r\nEllen Mathers ordered the vegetable medley and chocolate cream pie.\r\nBen Klein ordered NY strip steak and vanilla ice cream.\r\nDana Bronson ordered fillet mignon and apple crisp.", "category": "Logic-Grid", "date": "10/15/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree women (Dana, Barbara, & Ellen) and two men (Ben & Max) went to dinner at their favorite restaurant to celebrate the engagement of two of their friends. Each ordered a different entree (shrimp & pasta, chicken cordon bleu, vegetable medley, fillet mignon, & NY strip steak), and a different dessert (fudge cake, vanilla ice cream, apple crisp, chocolate cream pie, & strawberry parfait). Can you determine each person's full name and what entree and dessert they ordered?\n\r\n1) Nobody's first name starts with the same letter as their last name.\n\r\n2) Klein and Bronson are dating.\n\r\n3) Ms. Mathers is a vegetarian.\n\r\n4) The 5 friends are the man who ordered fudge cake, the one who ordered chicken cordon bleu, Ellen, the woman who ordered fillet mignon, and Mr. Klein (who ordered ice cream).\n\r\n5) Mr. Klein and Dana shared their desserts.\n\r\n6) Delaney and Ruiz are engaged. Neither of them ordered beef.\n\r\n7) Ben does not care for chocolate and is allergic to strawberries.\n\r\n8) Delaney did not order chocolate cream pie or apple crisp for dessert.\n\r\n9) Ben and Ruiz have been friends since high school, and were laughing over dinner about how they have always liked the same girls, until Barbara came along.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMax Ruiz ordered shrimp & pasta and fudge cake.\r\nBarbara Delaney ordered chicken cordon bleu and strawberry parfait.\r\nEllen Mathers ordered the vegetable medley and chocolate cream pie.\r\nBen Klein ordered NY strip steak and vanilla ice cream.\r\nDana Bronson ordered fillet mignon and apple crisp.\n<|im_start|>answer\nMax Ruiz ordered shrimp & pasta and fudge cake.\r\nBarbara Delaney ordered chicken cordon bleu and strawberry parfait.\r\nEllen Mathers ordered the vegetable medley and chocolate cream pie.\r\nBen Klein ordered NY strip steak and vanilla ice cream.\r\nDana Bronson ordered fillet mignon and apple crisp.\n<|im_end|>" }, { "id": "#47325", "title": "Getting a Job After I Get Married", "fun": 3.03, "difficulty": 1.93, "author": "hellokitty", "desc": "Five people are getting a job after they get married.\n\r\nFirst Names- Adam, Jacob, Sydney, Sarah, Ashley\r\nLast Names- Adams, Thompson, Jackson, Newman, Hudson\r\nMarried to- Ella, Emma, Brad, Levi, and Tyler\r\nJobs- Doctor, Veterinarian, Teacher, Lawyer, Hair Stylist\r\nCity Working in- Chicago, New York, Los Angeles, Columbus, Phoenix\n\r\n1. Adam (whose last name is not Hudson) doesn't work in Los Angeles.\n\r\n2. The five people are Jacob, Mr. Thompson, the one married to Tyler, the veterinarian, and the one who works in Columbus.\n\r\n3. The person who is the doctor doesn't work in Phoenix.\n\r\n4. The person whose last name is Newman (who isn't Sydney) is the teacher.\n\r\n5. Sydney, whose last name is Adams, doesn't work in New York.\n\r\n6. The five jobs belong to the hair stylist, Sydney, the one married to Levi, the person whose last name is Newman, and the one who works in Chicago.\n\r\n7. The doctor isn't married to Ella. The veterinarian isn't married to Brad.\n\r\n8. Emma (who isn't married to Jacob) is married to the doctor.\n\r\n9. Mrs. Jackson doesn't work in Phoenix.\n\r\n10. Sarah (whose last name is not Hudson) is the hair stylist.\n\r\n11. The veterinarian works in New York. The lawyer works in Columbus.\n\r\n12. Jacob's last name is Newman.\n\r\n13. Brad is married to the lawyer.", "hint": "No man married a man.\r\nNo woman married a woman.", "answer": "Adam Thompson married Emma and is the doctor in Chicago.\n\r\nJacob Newman married Ella and is the teacher in Phoenix.\n\r\nSydney Adams married Brad and is the lawyer in Columbus.\n\r\nSarah Jackson married Tyler and is the hair stylist in Los Angeles.\n\r\nAshley Hudson married Levi and is the veterinarian in New York.", "category": "Logic-Grid", "date": "06/24/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people are getting a job after they get married.\n\r\nFirst Names- Adam, Jacob, Sydney, Sarah, Ashley\r\nLast Names- Adams, Thompson, Jackson, Newman, Hudson\r\nMarried to- Ella, Emma, Brad, Levi, and Tyler\r\nJobs- Doctor, Veterinarian, Teacher, Lawyer, Hair Stylist\r\nCity Working in- Chicago, New York, Los Angeles, Columbus, Phoenix\n\r\n1. Adam (whose last name is not Hudson) doesn't work in Los Angeles.\n\r\n2. The five people are Jacob, Mr. Thompson, the one married to Tyler, the veterinarian, and the one who works in Columbus.\n\r\n3. The person who is the doctor doesn't work in Phoenix.\n\r\n4. The person whose last name is Newman (who isn't Sydney) is the teacher.\n\r\n5. Sydney, whose last name is Adams, doesn't work in New York.\n\r\n6. The five jobs belong to the hair stylist, Sydney, the one married to Levi, the person whose last name is Newman, and the one who works in Chicago.\n\r\n7. The doctor isn't married to Ella. The veterinarian isn't married to Brad.\n\r\n8. Emma (who isn't married to Jacob) is married to the doctor.\n\r\n9. Mrs. Jackson doesn't work in Phoenix.\n\r\n10. Sarah (whose last name is not Hudson) is the hair stylist.\n\r\n11. The veterinarian works in New York. The lawyer works in Columbus.\n\r\n12. Jacob's last name is Newman.\n\r\n13. Brad is married to the lawyer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam Thompson married Emma and is the doctor in Chicago.\n\r\nJacob Newman married Ella and is the teacher in Phoenix.\n\r\nSydney Adams married Brad and is the lawyer in Columbus.\n\r\nSarah Jackson married Tyler and is the hair stylist in Los Angeles.\n\r\nAshley Hudson married Levi and is the veterinarian in New York.\n<|im_start|>answer\nAdam Thompson married Emma and is the doctor in Chicago.\n\r\nJacob Newman married Ella and is the teacher in Phoenix.\n\r\nSydney Adams married Brad and is the lawyer in Columbus.\n\r\nSarah Jackson married Tyler and is the hair stylist in Los Angeles.\n\r\nAshley Hudson married Levi and is the veterinarian in New York.\n<|im_end|>" }, { "id": "#47255", "title": "Cobbler Cook-Off", "fun": 3.03, "difficulty": 1.6, "author": "whsprec", "desc": "A neighborhood block party had a Dutch oven cobbler cook-off. All cobblers were made with a cake batter and a fruit. Five people entered the cook-off, each one using a different cake and fruit. From the clues below determine the name of the person, the type of cake and fruit used, and what place they took.\r\nThe boys are George, Russell, and Cory and the girls are Chelsea and Mary\n\n\r\n1) The 2nd place cobbler had raspberry as the fruit, while the 1st place cobbler had marble.\r\n2) The cobbler that used white cake did not use apple.\r\n3) The cobbler that mixed yellow cake and cherry placed higher than 4th, while a female baked the 4th place cobbler.\r\n4) Cory's cobbler was made with mixed fruit while Russell placed 3rd.\r\n5) Devil chocolate was used with George's cobbler which did not place last. Chelsea's cobbler placed either 2nd, 3rd,or 5th but did not use pineapple as the fruit.", "hint": "No hint available.", "answer": "George's cobbler was made with devil chocolate and raspberry and placed 2nd.\r\nRussell's cobbler was made with yellow and cherry and placed 3rd.\r\nCory's cobbler was made with marble and mixed fruit and placed 1st.\r\nMary's cobbler was made with white and pineapple and placed 4th.\r\nChelsea's cobbler was made with caramel and apple and placed 5th.", "category": "Logic-Grid", "date": "06/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA neighborhood block party had a Dutch oven cobbler cook-off. All cobblers were made with a cake batter and a fruit. Five people entered the cook-off, each one using a different cake and fruit. From the clues below determine the name of the person, the type of cake and fruit used, and what place they took.\r\nThe boys are George, Russell, and Cory and the girls are Chelsea and Mary\n\n\r\n1) The 2nd place cobbler had raspberry as the fruit, while the 1st place cobbler had marble.\r\n2) The cobbler that used white cake did not use apple.\r\n3) The cobbler that mixed yellow cake and cherry placed higher than 4th, while a female baked the 4th place cobbler.\r\n4) Cory's cobbler was made with mixed fruit while Russell placed 3rd.\r\n5) Devil chocolate was used with George's cobbler which did not place last. Chelsea's cobbler placed either 2nd, 3rd,or 5th but did not use pineapple as the fruit.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGeorge's cobbler was made with devil chocolate and raspberry and placed 2nd.\r\nRussell's cobbler was made with yellow and cherry and placed 3rd.\r\nCory's cobbler was made with marble and mixed fruit and placed 1st.\r\nMary's cobbler was made with white and pineapple and placed 4th.\r\nChelsea's cobbler was made with caramel and apple and placed 5th.\n<|im_start|>answer\nGeorge's cobbler was made with devil chocolate and raspberry and placed 2nd.\r\nRussell's cobbler was made with yellow and cherry and placed 3rd.\r\nCory's cobbler was made with marble and mixed fruit and placed 1st.\r\nMary's cobbler was made with white and pineapple and placed 4th.\r\nChelsea's cobbler was made with caramel and apple and placed 5th.\n<|im_end|>" }, { "id": "#51537", "title": "Scrapbook Scramble", "fun": 3.03, "difficulty": 2.13, "author": "FiaTzu", "desc": "Lizzie wants to upload the contents of her serial killer scrapbook into an online database, however she discovers her little brother has spilled juice all over the pages. She manages to get most of them apart but five pages are almost completely unreadable. Help Lizzie get the information she needs for her database from what she remembers and what's left of the shredded pages.\n\r\n1.) The serial killer that started the earliest did not have the most victims, the one who started the latest didn't have the least.\n\r\n2.) The American had more victims than the axe murderer, who had more victims than the man who started killing in 2005. None of these had the highest or lowest body count.\n\r\n3.) Either Onoprienko is the Latvian and Kumar preferred to strangle his victims; or Denke began killing in 1900 and Petrovs was the strangler.\n\r\n4.) The five killers are the American, the man who shot his victims, the man with exactly 20 confirmed victims, the German, and the strangler.\n\r\n5.) Of the killer who started in 2003 and the one who started in 2005, one was from India and the other has the fewest victims.\n\r\n6.) Considered handsome and charismatic by his friends and collegues, Ted Bundy began either poisoning women in 1989 or bludgeoning women in 1974.\n\r\n7.) The preferred methods of murder were: the method preferred by Denke, the one used by the Latvian killer, poison, the one used to kill exactly 35 confirmed victims, and the one used by the killer who began in 1989.\n\r\n8.) The five countries of origin are represented by: India, the strangler, Ted Bundy, Germany and the killer who began in 1989.\n\r\n9.) The man who started killing first didn't use a gun and was not Kaspars Petrovs\n\r\n10.) The Latvian was active after the shooter and the German, but before at least one other killer and none of these four men were named Bundy.\n\r\n11.) Either Onoprienko was the Russian and killed the most people or Denke was the Russian and poisoned his victims.", "hint": "Ted Bundy committed 35 confirmed homicides in seven US states beginning in 1974.", "answer": "Ted Bundy (USA) preferred to bludgeon his victims and had 35 confirmed kills, beginning in 1974.\r\nKarl Denke (Germany) hacked his victims to death with an axe; he killed at least 30 beginning in 1900.\r\nMohan Kumar (India) lured women with promises of marriage before poisoning them with cyanide, he killed 20 women beginning in 2005.\r\nAnatoly Onoprienko (Russia) dispatched his victims with a sawed off shotgun, he killed at least 52 people beginning in 1989.\r\nKaspars Petrovs (Latvia) strangled elderly people from his community, he confessed to many more but is only confirmed to have killed 13 beginning in 2003.", "category": "Logic-Grid", "date": "10/27/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLizzie wants to upload the contents of her serial killer scrapbook into an online database, however she discovers her little brother has spilled juice all over the pages. She manages to get most of them apart but five pages are almost completely unreadable. Help Lizzie get the information she needs for her database from what she remembers and what's left of the shredded pages.\n\r\n1.) The serial killer that started the earliest did not have the most victims, the one who started the latest didn't have the least.\n\r\n2.) The American had more victims than the axe murderer, who had more victims than the man who started killing in 2005. None of these had the highest or lowest body count.\n\r\n3.) Either Onoprienko is the Latvian and Kumar preferred to strangle his victims; or Denke began killing in 1900 and Petrovs was the strangler.\n\r\n4.) The five killers are the American, the man who shot his victims, the man with exactly 20 confirmed victims, the German, and the strangler.\n\r\n5.) Of the killer who started in 2003 and the one who started in 2005, one was from India and the other has the fewest victims.\n\r\n6.) Considered handsome and charismatic by his friends and collegues, Ted Bundy began either poisoning women in 1989 or bludgeoning women in 1974.\n\r\n7.) The preferred methods of murder were: the method preferred by Denke, the one used by the Latvian killer, poison, the one used to kill exactly 35 confirmed victims, and the one used by the killer who began in 1989.\n\r\n8.) The five countries of origin are represented by: India, the strangler, Ted Bundy, Germany and the killer who began in 1989.\n\r\n9.) The man who started killing first didn't use a gun and was not Kaspars Petrovs\n\r\n10.) The Latvian was active after the shooter and the German, but before at least one other killer and none of these four men were named Bundy.\n\r\n11.) Either Onoprienko was the Russian and killed the most people or Denke was the Russian and poisoned his victims.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTed Bundy (USA) preferred to bludgeon his victims and had 35 confirmed kills, beginning in 1974.\r\nKarl Denke (Germany) hacked his victims to death with an axe; he killed at least 30 beginning in 1900.\r\nMohan Kumar (India) lured women with promises of marriage before poisoning them with cyanide, he killed 20 women beginning in 2005.\r\nAnatoly Onoprienko (Russia) dispatched his victims with a sawed off shotgun, he killed at least 52 people beginning in 1989.\r\nKaspars Petrovs (Latvia) strangled elderly people from his community, he confessed to many more but is only confirmed to have killed 13 beginning in 2003.\n<|im_start|>answer\nTed Bundy (USA) preferred to bludgeon his victims and had 35 confirmed kills, beginning in 1974.\r\nKarl Denke (Germany) hacked his victims to death with an axe; he killed at least 30 beginning in 1900.\r\nMohan Kumar (India) lured women with promises of marriage before poisoning them with cyanide, he killed 20 women beginning in 2005.\r\nAnatoly Onoprienko (Russia) dispatched his victims with a sawed off shotgun, he killed at least 52 people beginning in 1989.\r\nKaspars Petrovs (Latvia) strangled elderly people from his community, he confessed to many more but is only confirmed to have killed 13 beginning in 2003.\n<|im_end|>" }, { "id": "#23270", "title": "Attention Class!", "fun": 3.03, "difficulty": 1.55, "author": "kellgo", "desc": "Boys Billy, Lenny, and Samuel, and girls Jessica and Lindsay all go to the same school and take different classes. Each child got a different grade in a different class with a different teacher.\n\r\nKids: Billy, Lenny, Samuel, Jessica, and Lindsay\n\r\nTeachers: Mr. Briggs, Mrs. Cooper, Mrs. Minn, Mr. Bobo, and Mrs. Runner\n\r\nGrades: A, B, C, A-, and D\n\r\nSubjects: Math, English, Science, History, and Physical Ed. \n\n\r\n1. The 2 people who got A's have names that end in Y.\n\r\n2. The math student got a similar grade to Billy, but a little lower.\n\r\n3. Mrs. Runner was sad to hand out a D to her student.\n\r\n4. The C student loved her field trips, but isn't a good test taker.\n\r\n5. The Physical Education teacher is a male teaching a female, while the math teacher is female and teaches a male student.\n\r\n6. Jessica and Lindsay didn't get the highest or lowest grades out of the group; they got either a B or a C.\r\n7. Mr. Bobo was the best Science teacher at the school, but Lenny didn't have him.\r\n8. Samuel really didn't want to show his parents his report card because of the low grade he got from Mrs. Runner.\r\n9. Mrs. Minn's history class was the only class that had field trips and Lindsay loved them!", "hint": "No hint available.", "answer": "Billy/Science/A/Mr. Bobo\r\nJessica/Physical Education/B/Mr. Briggs\r\nLenny/Math/A-/Mrs. Cooper\r\nLindsay/History/C/Mrs. Minn\r\nSamuel/English/D/Mrs. Runner", "category": "Logic-Grid", "date": "05/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBoys Billy, Lenny, and Samuel, and girls Jessica and Lindsay all go to the same school and take different classes. Each child got a different grade in a different class with a different teacher.\n\r\nKids: Billy, Lenny, Samuel, Jessica, and Lindsay\n\r\nTeachers: Mr. Briggs, Mrs. Cooper, Mrs. Minn, Mr. Bobo, and Mrs. Runner\n\r\nGrades: A, B, C, A-, and D\n\r\nSubjects: Math, English, Science, History, and Physical Ed. \n\n\r\n1. The 2 people who got A's have names that end in Y.\n\r\n2. The math student got a similar grade to Billy, but a little lower.\n\r\n3. Mrs. Runner was sad to hand out a D to her student.\n\r\n4. The C student loved her field trips, but isn't a good test taker.\n\r\n5. The Physical Education teacher is a male teaching a female, while the math teacher is female and teaches a male student.\n\r\n6. Jessica and Lindsay didn't get the highest or lowest grades out of the group; they got either a B or a C.\r\n7. Mr. Bobo was the best Science teacher at the school, but Lenny didn't have him.\r\n8. Samuel really didn't want to show his parents his report card because of the low grade he got from Mrs. Runner.\r\n9. Mrs. Minn's history class was the only class that had field trips and Lindsay loved them!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBilly/Science/A/Mr. Bobo\r\nJessica/Physical Education/B/Mr. Briggs\r\nLenny/Math/A-/Mrs. Cooper\r\nLindsay/History/C/Mrs. Minn\r\nSamuel/English/D/Mrs. Runner\n<|im_start|>answer\nBilly/Science/A/Mr. Bobo\r\nJessica/Physical Education/B/Mr. Briggs\r\nLenny/Math/A-/Mrs. Cooper\r\nLindsay/History/C/Mrs. Minn\r\nSamuel/English/D/Mrs. Runner\n<|im_end|>" }, { "id": "#39643", "title": "Customs Woes", "fun": 3.03, "difficulty": 2.85, "author": "mocha613", "desc": "7 hours into her flight from Berlin to Denver, Jane is asked to fill out her customs forms. She rifles through her purse, looking for her receipts of the five souvenirs she purchased. Unfortunately, she can't find her list anywhere! She needs to claim her gifts to United States customs upon arrival. Help her sort out what she bought, how much it cost, what city she was in when she bought it, what attraction she was visiting, and how she got there before she lands!\n\r\nItem: Postcard, Book, Audio Tape, Model, Calendar\r\nCost: 1, 5, 8, 10, 16 Euros\r\nCity: Berlin, Stuttgart, Munich, Frankfurt, Rothenburg\r\nAttraction: Castle, Play, Zoo, Museum, Cathedral\r\nTransportation: U-bahn (U-bahn is like the subway, on rails), Bergbahn (German for Mountain Train), Car (rented, of course!), Taxi, Bicycle\n\r\n1. No item was purchased at an attraction or city with the same first letter as that item.\n\r\n2. Neither the Zoo nor the castle were accessible by rail. Rothenburg is a small, walled city; cars and taxis are of no use there.\n\r\n3. Stuttgart is known for its expensive taste. Therefore, the item purchased there was not less than 10 euros.\n\r\n4. The items are as follows: The book, the item purchased at a castle, the item bought in Rothenburg, the item that cost the most, and the item purchased after a scenic train ride.\n\r\n5. The \"Bergbahn\", or mountain train, was not required to get to the cathedral.\n\r\n6. A car was rented on the trip that resulted in a souvenir for her favorite aunt that cost twice as much as the model she bought for her brother.\n\r\n7. A camera was not allowed in either attraction that involved living things, so she bought a postcard to remember one of them and a calendar to remember the other.\n\r\n8. The total cost of the souvenirs is divisible by the costs of each of these four different items: the one from Frankfurt, the gift bought in the cathedral, the one costing 1 Euro, and the one purchased after a taxi ride.\n\r\n9. The gift from the cathedral cost half as much as the gift purchased after the taxi ride, which was not through Stuttgart.", "hint": "If it says something is not useful or not needed, it means that is not the transportation used.\n\r\nPlaces, attractions and transportation solutions are fictional.", "answer": "Postcard-16 euros-Car-Zoo-Stuttgart\r\nBook-10 Euros-Taxi-Museum-Munich\r\nAudio Tape-5 Euros-U-Bahn-Cathedral-Rothenburg\r\nModel-8 Euros-Bicycle-Castle-Frankfurt\r\nCalendar-1 Euro-Bergbahn-Play-Berlin", "category": "Logic-Grid", "date": "12/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n7 hours into her flight from Berlin to Denver, Jane is asked to fill out her customs forms. She rifles through her purse, looking for her receipts of the five souvenirs she purchased. Unfortunately, she can't find her list anywhere! She needs to claim her gifts to United States customs upon arrival. Help her sort out what she bought, how much it cost, what city she was in when she bought it, what attraction she was visiting, and how she got there before she lands!\n\r\nItem: Postcard, Book, Audio Tape, Model, Calendar\r\nCost: 1, 5, 8, 10, 16 Euros\r\nCity: Berlin, Stuttgart, Munich, Frankfurt, Rothenburg\r\nAttraction: Castle, Play, Zoo, Museum, Cathedral\r\nTransportation: U-bahn (U-bahn is like the subway, on rails), Bergbahn (German for Mountain Train), Car (rented, of course!), Taxi, Bicycle\n\r\n1. No item was purchased at an attraction or city with the same first letter as that item.\n\r\n2. Neither the Zoo nor the castle were accessible by rail. Rothenburg is a small, walled city; cars and taxis are of no use there.\n\r\n3. Stuttgart is known for its expensive taste. Therefore, the item purchased there was not less than 10 euros.\n\r\n4. The items are as follows: The book, the item purchased at a castle, the item bought in Rothenburg, the item that cost the most, and the item purchased after a scenic train ride.\n\r\n5. The \"Bergbahn\", or mountain train, was not required to get to the cathedral.\n\r\n6. A car was rented on the trip that resulted in a souvenir for her favorite aunt that cost twice as much as the model she bought for her brother.\n\r\n7. A camera was not allowed in either attraction that involved living things, so she bought a postcard to remember one of them and a calendar to remember the other.\n\r\n8. The total cost of the souvenirs is divisible by the costs of each of these four different items: the one from Frankfurt, the gift bought in the cathedral, the one costing 1 Euro, and the one purchased after a taxi ride.\n\r\n9. The gift from the cathedral cost half as much as the gift purchased after the taxi ride, which was not through Stuttgart.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPostcard-16 euros-Car-Zoo-Stuttgart\r\nBook-10 Euros-Taxi-Museum-Munich\r\nAudio Tape-5 Euros-U-Bahn-Cathedral-Rothenburg\r\nModel-8 Euros-Bicycle-Castle-Frankfurt\r\nCalendar-1 Euro-Bergbahn-Play-Berlin\n<|im_start|>answer\nPostcard-16 euros-Car-Zoo-Stuttgart\r\nBook-10 Euros-Taxi-Museum-Munich\r\nAudio Tape-5 Euros-U-Bahn-Cathedral-Rothenburg\r\nModel-8 Euros-Bicycle-Castle-Frankfurt\r\nCalendar-1 Euro-Bergbahn-Play-Berlin\n<|im_end|>" }, { "id": "#32809", "title": "Sum-day Soon", "fun": 3.03, "difficulty": 2.23, "author": "hottiexo247", "desc": "Some people believe that January 1, 2000 is the first day of the 21st century. Other people believe that the honor belongs to January 1, 2001. But everyone should agree that January 1, 2002 is the first \"sum-day\" of the new century- when you write out that date in standard notation, it becomes 01/01/02, and 1+1=2. More generally, a sum-day is a date in which the day and month add up to the year. With that in mind:\n\r\nA) What is the last sum-day of the 21st century?\n\r\nB) How many sum-days are there in the 21st century?", "hint": "No hint available.", "answer": "A) The last sum-day of the 21st century is December 31, 2043, because 12+31=43, and both the month and day are as big as possible.\n\r\nB) This one is much easier than you might think. The correct answer is 365, because every day in a standard (non-leap) year is part of a sum-day for some year. For example, November 26 is a sum-day for the year 2037, because 11+26=37. The only date for which this principle doesn't work is the leap day, February 29. That's because 2+29=31, but 2031 is not a leap year.", "category": "Math", "date": "09/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome people believe that January 1, 2000 is the first day of the 21st century. Other people believe that the honor belongs to January 1, 2001. But everyone should agree that January 1, 2002 is the first \"sum-day\" of the new century- when you write out that date in standard notation, it becomes 01/01/02, and 1+1=2. More generally, a sum-day is a date in which the day and month add up to the year. With that in mind:\n\r\nA) What is the last sum-day of the 21st century?\n\r\nB) How many sum-days are there in the 21st century?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA) The last sum-day of the 21st century is December 31, 2043, because 12+31=43, and both the month and day are as big as possible.\n\r\nB) This one is much easier than you might think. The correct answer is 365, because every day in a standard (non-leap) year is part of a sum-day for some year. For example, November 26 is a sum-day for the year 2037, because 11+26=37. The only date for which this principle doesn't work is the leap day, February 29. That's because 2+29=31, but 2031 is not a leap year.\n<|im_start|>answer\nA) The last sum-day of the 21st century is December 31, 2043, because 12+31=43, and both the month and day are as big as possible.\n\r\nB) This one is much easier than you might think. The correct answer is 365, because every day in a standard (non-leap) year is part of a sum-day for some year. For example, November 26 is a sum-day for the year 2037, because 11+26=37. The only date for which this principle doesn't work is the leap day, February 29. That's because 2+29=31, but 2031 is not a leap year.\n<|im_end|>" }, { "id": "#25171", "title": "The War Of The Worlds - Part II", "fun": 3.03, "difficulty": 1.49, "author": "smarty_blondy", "desc": "After choosing three of his most worthy Myrmidons, Lord Zyron sent a message from The World Beneath to the surface, announcing his immediate attack. Not to worry though, for humanity is safe while King Solimyr is ruling. With his witty mind, he quickly called for a court scholar to bring him the files of the five bravest army leaders and most powerful ladies, from which he would secretly choose two to destroy the enemy forces. But young as he was, the distraught scholar dropped the valuable files in the mud, and much of the important information to help King Solimyr decide was lost. Can you find out the details of each army leader or lady, by the few clues left, before it's too late? \n\r\nNames: Sir Christian, Sir Loynis, Sir Edric, Lady Adelaide, Lady Caitlin;\r\nOccupations: Knight, Cleric, Wizard, Sorceress, High Court Priestess;\r\nExperience: 24 years, 5 years, 19 years, 37 years, 48 years;\r\nArea of Expertise: Estates, Diplomacy, Leadership, Scholarship, Air Magic;\r\nMagical artifact: Sword of Judgment, Boots of Levitation, Ring of the Magi, Collar of Conjuring, Ambassador's Sash; \n\n\r\n1. Lady Caitlin is not the High Court Priestess, but she is the possessor of the Boots of Levitation.\n\r\n2. Sir Christian the Knight has twice as much experience as Sir Loynis the Wizard.\n\r\n3. The Sorceress is the only one that can fly, and has been an expert in her area for 19 years.\n\r\n4. The High Court Priestess, an expert in Scholarship for 37 years, is not the possessor of the Ring of the Magi.\n\r\n5. The possessor of the Sword of Judgment has been an expert in Leadership for 48 years now. \n\r\n6. The possessor of the Boots of Levitation can fly, and therefore is an expert in Air Magic.\n\r\n7. Sir Edric is the possessor of the Ambassador's Sash; therefore he is an expert in diplomacy. \n\r\n8. The Wizard is an expert in Estates.", "hint": "No hint available.", "answer": "1. Sir Christian the Knight is the possessor of the Sword of Judgment, and has been an expert in Leadership for 48 years.\n\r\n2. Sir Loynis the Wizard is the possessor of the Ring of the Magi, and has been an expert in Estates for 24 years. \n\r\n3. Sir Edric the Cleric is the possessor of the Ambassador's Sash, and has been an expert in Diplomacy for 5 years.\n\r\n4. Lady Adelaide the High Court Priestess is the possessor of the Collar of Conjuring, and has been an expert in Scholar for 37 years.\n\r\n5. Lady Caitlin the Sorceress is the possessor of the Boots of Levitation, and has been an expert in Air Magic for 19 years.\n\r\nKing Solimyr is pleased with your results, and will now make his pick. The War of the Worlds has begun, and nothing can stop it now!", "category": "Logic-Grid", "date": "08/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter choosing three of his most worthy Myrmidons, Lord Zyron sent a message from The World Beneath to the surface, announcing his immediate attack. Not to worry though, for humanity is safe while King Solimyr is ruling. With his witty mind, he quickly called for a court scholar to bring him the files of the five bravest army leaders and most powerful ladies, from which he would secretly choose two to destroy the enemy forces. But young as he was, the distraught scholar dropped the valuable files in the mud, and much of the important information to help King Solimyr decide was lost. Can you find out the details of each army leader or lady, by the few clues left, before it's too late? \n\r\nNames: Sir Christian, Sir Loynis, Sir Edric, Lady Adelaide, Lady Caitlin;\r\nOccupations: Knight, Cleric, Wizard, Sorceress, High Court Priestess;\r\nExperience: 24 years, 5 years, 19 years, 37 years, 48 years;\r\nArea of Expertise: Estates, Diplomacy, Leadership, Scholarship, Air Magic;\r\nMagical artifact: Sword of Judgment, Boots of Levitation, Ring of the Magi, Collar of Conjuring, Ambassador's Sash; \n\n\r\n1. Lady Caitlin is not the High Court Priestess, but she is the possessor of the Boots of Levitation.\n\r\n2. Sir Christian the Knight has twice as much experience as Sir Loynis the Wizard.\n\r\n3. The Sorceress is the only one that can fly, and has been an expert in her area for 19 years.\n\r\n4. The High Court Priestess, an expert in Scholarship for 37 years, is not the possessor of the Ring of the Magi.\n\r\n5. The possessor of the Sword of Judgment has been an expert in Leadership for 48 years now. \n\r\n6. The possessor of the Boots of Levitation can fly, and therefore is an expert in Air Magic.\n\r\n7. Sir Edric is the possessor of the Ambassador's Sash; therefore he is an expert in diplomacy. \n\r\n8. The Wizard is an expert in Estates.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Sir Christian the Knight is the possessor of the Sword of Judgment, and has been an expert in Leadership for 48 years.\n\r\n2. Sir Loynis the Wizard is the possessor of the Ring of the Magi, and has been an expert in Estates for 24 years. \n\r\n3. Sir Edric the Cleric is the possessor of the Ambassador's Sash, and has been an expert in Diplomacy for 5 years.\n\r\n4. Lady Adelaide the High Court Priestess is the possessor of the Collar of Conjuring, and has been an expert in Scholar for 37 years.\n\r\n5. Lady Caitlin the Sorceress is the possessor of the Boots of Levitation, and has been an expert in Air Magic for 19 years.\n\r\nKing Solimyr is pleased with your results, and will now make his pick. The War of the Worlds has begun, and nothing can stop it now!\n<|im_start|>answer\n1. Sir Christian the Knight is the possessor of the Sword of Judgment, and has been an expert in Leadership for 48 years.\n\r\n2. Sir Loynis the Wizard is the possessor of the Ring of the Magi, and has been an expert in Estates for 24 years. \n\r\n3. Sir Edric the Cleric is the possessor of the Ambassador's Sash, and has been an expert in Diplomacy for 5 years.\n\r\n4. Lady Adelaide the High Court Priestess is the possessor of the Collar of Conjuring, and has been an expert in Scholar for 37 years.\n\r\n5. Lady Caitlin the Sorceress is the possessor of the Boots of Levitation, and has been an expert in Air Magic for 19 years.\n\r\nKing Solimyr is pleased with your results, and will now make his pick. The War of the Worlds has begun, and nothing can stop it now!\n<|im_end|>" }, { "id": "#22291", "title": "Party Preparations", "fun": 3.03, "difficulty": 2.0, "author": "cinnamon30", "desc": "Billy's birthday was last Saturday. It was filled with fun, games, and attractions. Five guests were so anxious to get to the party that they were up at 6:30 a.m. Their parents took advantage of this situation. Each child had to do a different chore and his or her homework before attending the party. Consequently, each child arrived at a different time. From the information provided, determine the chore and homework each child had to do as well as what time he or she arrived.\n\r\n1. Simone got to the party at 1:00 p.m. The guest who took out the trash didn't arrive until after 2:00 p.m.\n\r\n2. Jorge (who didn't have English homework) had to weed his mother's flower beds before going to the party.\n\r\n3. The guest who had to do science homework arrived at some point after Jorge.\n\r\n4. The guest charged with bathing the dog (who isn't Mina) isn't the child who did reading homework. Patrick didn't have English homework.\n\r\n5. One girl made it to the party at 1:40 p.m. after completing her math homework.\n\r\n6. The boy who had to wash clothes isn't the guest who arrived at 2:05 p.m. (who had to do English homework).", "hint": "No hint available.", "answer": "Jorge, weed flower beds, reading 2:15 p.m.\r\nMina, clean playroom, math, 1:40 p.m.\r\nPatrick, wash clothes, science, 2:30 p.m.\r\nSimone, bathe dog, social studies, 1:00 p.m.\r\nWalter, take out trash, English, 2:05 p.m.", "category": "Logic-Grid", "date": "04/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBilly's birthday was last Saturday. It was filled with fun, games, and attractions. Five guests were so anxious to get to the party that they were up at 6:30 a.m. Their parents took advantage of this situation. Each child had to do a different chore and his or her homework before attending the party. Consequently, each child arrived at a different time. From the information provided, determine the chore and homework each child had to do as well as what time he or she arrived.\n\r\n1. Simone got to the party at 1:00 p.m. The guest who took out the trash didn't arrive until after 2:00 p.m.\n\r\n2. Jorge (who didn't have English homework) had to weed his mother's flower beds before going to the party.\n\r\n3. The guest who had to do science homework arrived at some point after Jorge.\n\r\n4. The guest charged with bathing the dog (who isn't Mina) isn't the child who did reading homework. Patrick didn't have English homework.\n\r\n5. One girl made it to the party at 1:40 p.m. after completing her math homework.\n\r\n6. The boy who had to wash clothes isn't the guest who arrived at 2:05 p.m. (who had to do English homework).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJorge, weed flower beds, reading 2:15 p.m.\r\nMina, clean playroom, math, 1:40 p.m.\r\nPatrick, wash clothes, science, 2:30 p.m.\r\nSimone, bathe dog, social studies, 1:00 p.m.\r\nWalter, take out trash, English, 2:05 p.m.\n<|im_start|>answer\nJorge, weed flower beds, reading 2:15 p.m.\r\nMina, clean playroom, math, 1:40 p.m.\r\nPatrick, wash clothes, science, 2:30 p.m.\r\nSimone, bathe dog, social studies, 1:00 p.m.\r\nWalter, take out trash, English, 2:05 p.m.\n<|im_end|>" }, { "id": "#37313", "title": "Parcel Predicament", "fun": 3.02, "difficulty": 2.26, "author": "nikitafullmoon", "desc": "Percy Parcelle, bicycle courier extraordinaire, just came barrelling around a blind corner and collided unceremoniously with a man in a duck suit handing out flyers. In addition to the flyers and feathers, Percy's five parcels with the recipient names, addresses, street names, and delivery instructions are scattered around him and the unconscious duck-man. All he knows now are a few bits of information he can remember from the dispatcher. Help Percy get his five deliveries sorted so he can cycle away before the duck man wakes up!\n\r\nParcels: letter, tube mailer, padded envelope, box, can \n\r\nRecipients: Mr. Anderson, Doozen Communications, Harold and Sons, Smythe LLB, Mrs. Williams\n\r\nAddresses: 4, 10, 23, 52, 71 \n\r\nStreet names: Lilac Lane, Magnolia Ave, Olive St, Sycamore Close, Zinnia Crescent \n\r\nDelivery instructions: fragile (\"Oops!\" says Percy), no signature required (NSR), rush, COD, leave at front desk \n\n\r\n1. Mr. Anderson's house number is 4.\n\r\n2. Doozen Communications is on Lilac Lane, which only has buildings numbered up to 40.\n\r\n3. The letter is for Smythe LLB.\n\r\n4. Number 10 is getting the box.\n\r\n5. Doozen Communications did not request \"leave at desk,\" and Williams' is a private residence, so there is no desk there, either.\n\r\n6. The fragile parcel is going to Magnolia Avenue.\n\r\n7. Number 52 is the only destination that requires no signature for delivery.\n\r\n8. The tube is going to Magnolia Avenue. \n\r\n9. Mrs. Williams lives on Sycamore Close.\n\r\n10. The can is the rush delivery, but not to number 71.\n\r\n11. Harold and Sons is paying COD.\n\r\n12. Smythe LLB is not on Zinnia St.", "hint": "No hint available.", "answer": "Percy delivered the following: \n\r\n1. A tube marked \"fragile\" to Mr. Anderson, 4 Magnolia Ave.\n\r\n2. A letter marked \"leave at front desk\" to Smythe LLB, 71 Olive St.\n\r\n3. A padded envelope marked \"no signature required\" to Mrs. Williams, 52 Sycamore Close.\n\r\n4. A box marked \"COD\" to Harold and Sons, 10 Zinnia Crescent.\n\r\n5. A can marked \"rush\" to Doozen Communications, 23 Lilac Lane. \n\r\nUnfortunately, the trail of feathers and flyers led the police right to his door (and five others). He was charged and sentenced to community service...handing out flyers in a chicken suit!", "category": "Logic-Grid", "date": "07/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPercy Parcelle, bicycle courier extraordinaire, just came barrelling around a blind corner and collided unceremoniously with a man in a duck suit handing out flyers. In addition to the flyers and feathers, Percy's five parcels with the recipient names, addresses, street names, and delivery instructions are scattered around him and the unconscious duck-man. All he knows now are a few bits of information he can remember from the dispatcher. Help Percy get his five deliveries sorted so he can cycle away before the duck man wakes up!\n\r\nParcels: letter, tube mailer, padded envelope, box, can \n\r\nRecipients: Mr. Anderson, Doozen Communications, Harold and Sons, Smythe LLB, Mrs. Williams\n\r\nAddresses: 4, 10, 23, 52, 71 \n\r\nStreet names: Lilac Lane, Magnolia Ave, Olive St, Sycamore Close, Zinnia Crescent \n\r\nDelivery instructions: fragile (\"Oops!\" says Percy), no signature required (NSR), rush, COD, leave at front desk \n\n\r\n1. Mr. Anderson's house number is 4.\n\r\n2. Doozen Communications is on Lilac Lane, which only has buildings numbered up to 40.\n\r\n3. The letter is for Smythe LLB.\n\r\n4. Number 10 is getting the box.\n\r\n5. Doozen Communications did not request \"leave at desk,\" and Williams' is a private residence, so there is no desk there, either.\n\r\n6. The fragile parcel is going to Magnolia Avenue.\n\r\n7. Number 52 is the only destination that requires no signature for delivery.\n\r\n8. The tube is going to Magnolia Avenue. \n\r\n9. Mrs. Williams lives on Sycamore Close.\n\r\n10. The can is the rush delivery, but not to number 71.\n\r\n11. Harold and Sons is paying COD.\n\r\n12. Smythe LLB is not on Zinnia St.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPercy delivered the following: \n\r\n1. A tube marked \"fragile\" to Mr. Anderson, 4 Magnolia Ave.\n\r\n2. A letter marked \"leave at front desk\" to Smythe LLB, 71 Olive St.\n\r\n3. A padded envelope marked \"no signature required\" to Mrs. Williams, 52 Sycamore Close.\n\r\n4. A box marked \"COD\" to Harold and Sons, 10 Zinnia Crescent.\n\r\n5. A can marked \"rush\" to Doozen Communications, 23 Lilac Lane. \n\r\nUnfortunately, the trail of feathers and flyers led the police right to his door (and five others). He was charged and sentenced to community service...handing out flyers in a chicken suit!\n<|im_start|>answer\nPercy delivered the following: \n\r\n1. A tube marked \"fragile\" to Mr. Anderson, 4 Magnolia Ave.\n\r\n2. A letter marked \"leave at front desk\" to Smythe LLB, 71 Olive St.\n\r\n3. A padded envelope marked \"no signature required\" to Mrs. Williams, 52 Sycamore Close.\n\r\n4. A box marked \"COD\" to Harold and Sons, 10 Zinnia Crescent.\n\r\n5. A can marked \"rush\" to Doozen Communications, 23 Lilac Lane. \n\r\nUnfortunately, the trail of feathers and flyers led the police right to his door (and five others). He was charged and sentenced to community service...handing out flyers in a chicken suit!\n<|im_end|>" }, { "id": "#46013", "title": "Clowns in the Subway", "fun": 3.02, "difficulty": 3.0, "author": "caberet", "desc": "You are having a nightmare about five clowns in the subway. It is especially confusing because each clown has a tiny car and umbrella, even though you are in an underground public transportation system. Naturally, each clown has a ridiculous wig and a big goofy outfit. There are only five colors in your dream - fuchsia, green, purple, red and yellow. Use the following clues to determine each clown's name (Fuchsia Funny, Green Gravel, Purple Porridge, Red Rascal and Yellow Sub), and color of their car, wig, outfit and umbrella.\n\r\n1. Each clown's name, car, wig, outfit and umbrella are 5 different colors and no two wigs, outfits or umbrellas are the same color.\r\n2. The only clown whose name does not begin with the same two initials does not have a purple or red outfit; while the clown in the yellow outfit does not have a red car, red wig or a purple umbrella.\r\n3. Red Rascal does not have a yellow wig and Purple Porridge does not have either a fuchsia or yellow umbrella.\r\n4. Of the clown in the green wig and the owner of the red umbrella, one has the purple car and the other is Fuchsia Funny; neither clown has the yellow outfit.\r\n5. The clown in the fuchsia wig is not wearing a green or yellow outfit and does not have a red car (whose driver does not have a green outfit or a green umbrella.)\r\n6. Green Gravel does not have a yellow umbrella or a red car.", "hint": "Clue 1 directs you to fill in 50 \"no\" (red X) squares.\n\r\nClue 4 tells us that Purple Porridge cannot be the owner of the red umbrella, since she is neither the owner of the purple car (Clue 1) nor Fuchsia Funny, so Purple Porridge must have the green umbrella (only remaining color from clue 4.)\n\r\nClue 4 also tells us that the clown driving the fuchsia car cannot have either the green wig or red umbrella since this clown cannot be either Fuchsia Funny (Clue 1) or the driver of the purple car.", "answer": "Name-Car-Wig-Outfit-Umbrella\r\nFuchsia Funny-Red-Green-Purple-Yellow\r\nGreen Gravel-Purple-Yellow-Fuchsia-Red\r\nPurple Porridge-Yellow-Fuchsia-Red-Green\r\nRed Rascal-Green-Purple-Yellow-Fuchsia\r\nYellow Sub-Fuchsia-Red-Green-Purple", "category": "Logic-Grid", "date": "12/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are having a nightmare about five clowns in the subway. It is especially confusing because each clown has a tiny car and umbrella, even though you are in an underground public transportation system. Naturally, each clown has a ridiculous wig and a big goofy outfit. There are only five colors in your dream - fuchsia, green, purple, red and yellow. Use the following clues to determine each clown's name (Fuchsia Funny, Green Gravel, Purple Porridge, Red Rascal and Yellow Sub), and color of their car, wig, outfit and umbrella.\n\r\n1. Each clown's name, car, wig, outfit and umbrella are 5 different colors and no two wigs, outfits or umbrellas are the same color.\r\n2. The only clown whose name does not begin with the same two initials does not have a purple or red outfit; while the clown in the yellow outfit does not have a red car, red wig or a purple umbrella.\r\n3. Red Rascal does not have a yellow wig and Purple Porridge does not have either a fuchsia or yellow umbrella.\r\n4. Of the clown in the green wig and the owner of the red umbrella, one has the purple car and the other is Fuchsia Funny; neither clown has the yellow outfit.\r\n5. The clown in the fuchsia wig is not wearing a green or yellow outfit and does not have a red car (whose driver does not have a green outfit or a green umbrella.)\r\n6. Green Gravel does not have a yellow umbrella or a red car.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName-Car-Wig-Outfit-Umbrella\r\nFuchsia Funny-Red-Green-Purple-Yellow\r\nGreen Gravel-Purple-Yellow-Fuchsia-Red\r\nPurple Porridge-Yellow-Fuchsia-Red-Green\r\nRed Rascal-Green-Purple-Yellow-Fuchsia\r\nYellow Sub-Fuchsia-Red-Green-Purple\n<|im_start|>answer\nName-Car-Wig-Outfit-Umbrella\r\nFuchsia Funny-Red-Green-Purple-Yellow\r\nGreen Gravel-Purple-Yellow-Fuchsia-Red\r\nPurple Porridge-Yellow-Fuchsia-Red-Green\r\nRed Rascal-Green-Purple-Yellow-Fuchsia\r\nYellow Sub-Fuchsia-Red-Green-Purple\n<|im_end|>" }, { "id": "#34040", "title": "Crack the Code II", "fun": 3.02, "difficulty": 2.32, "author": "peanut", "desc": "Jesse James' lesser known brother, Eddie has also decided to take up robbing banks for a living. He is unfortunately a little slow and has forgotten to bring the dynamite to blow open the safe!\n\r\nUsing logic, the following clues and a large amount of patience, can you figure out the 10 digit number to crack the safe?\n\r\n*All digits from 0 to 9 are used exactly once.\n\r\n*The sum of the 2nd, 5th, 6th and 8th digits is a single digit number.\n\r\n*The 4th digit is a perfect square.\n\r\n*The 3rd digit is 1.\n\r\n*The sum of the 4th and 7th digits is a perfect square.\n\r\n*The value of the 10th digit is twice that of the 2nd.\n\r\n*The product of the 4th and 6th digits is equal to that of the 10th and 2nd digits.\n\r\n*The 5 is next to the 6 but not the 4.", "hint": "The easiest failsafe way to solve this is to draw a grid with all the numbers from 0 to 9 in each position, and cross them out as they are eliminated by the clues.\n\r\nYou may need to revisit each clue a few times...!", "answer": "8 3 1 9 4 2 7 0 5 6", "category": "Logic", "date": "11/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJesse James' lesser known brother, Eddie has also decided to take up robbing banks for a living. He is unfortunately a little slow and has forgotten to bring the dynamite to blow open the safe!\n\r\nUsing logic, the following clues and a large amount of patience, can you figure out the 10 digit number to crack the safe?\n\r\n*All digits from 0 to 9 are used exactly once.\n\r\n*The sum of the 2nd, 5th, 6th and 8th digits is a single digit number.\n\r\n*The 4th digit is a perfect square.\n\r\n*The 3rd digit is 1.\n\r\n*The sum of the 4th and 7th digits is a perfect square.\n\r\n*The value of the 10th digit is twice that of the 2nd.\n\r\n*The product of the 4th and 6th digits is equal to that of the 10th and 2nd digits.\n\r\n*The 5 is next to the 6 but not the 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8 3 1 9 4 2 7 0 5 6\n<|im_start|>answer\n8 3 1 9 4 2 7 0 5 6\n<|im_end|>" }, { "id": "#34840", "title": "X-treme Snowboarding Competition", "fun": 3.02, "difficulty": 2.05, "author": "scallio", "desc": "The mountain resort of Mazama hosted the annual X-treme Snowboarding competition.\n\r\nCan you determine the position that each boarder placed, as well as their age and the color of their board?\n\r\nCompetitors: Sandy, Brian, Annie, Kyle and Darla\r\nAges: 17, 18, 20, 21 and 22\r\nColors: pink, green, purple, blue, red\n\r\n1. Kyle, who placed 4th, does not use a board that is red or pink.\n\r\n2. Annie is not the oldest but is older than Darla, who was not 2nd.\n\r\n3. The 18 year-old finished in 2nd place.\n\r\n4. The boarder that finished in 3rd place is older than the competitor with the purple board, who is 17.\n\r\n5. Brian is younger than the competitor with the blue board.\n\r\n6. The competitor with the pink board took 2nd place, ahead of the competitor with the green board, who did not place last.\n\r\n7. Kyle is older than both Brian and Annie but younger than Sandy.\n\r\n8. The girl with the blue board finished in 3rd place.\n\r\n9. The oldest competitor to place was on a red board and she took 5th.", "hint": "Figure the ages separately and then go back and add that information to your grid.\n\n\r\nNeed another hint?\r\nScroll down.\n\n\n\n\n\n\n\n\n\n\n\n\r\nThe youngest placed first, the 18-year old 2nd, the 20-year old 3rd, the 21-year old 4th and the oldest came in last.", "answer": "Darla, age 17, 1st place, purple board\r\nBrian, age 18, 2nd place, pink board\r\nAnnie, age 20, 3rd place, blue board\r\nKyle, age 21, 4th place, green board\r\nSandy, age 22, 5th place, red board", "category": "Logic-Grid", "date": "01/12/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe mountain resort of Mazama hosted the annual X-treme Snowboarding competition.\n\r\nCan you determine the position that each boarder placed, as well as their age and the color of their board?\n\r\nCompetitors: Sandy, Brian, Annie, Kyle and Darla\r\nAges: 17, 18, 20, 21 and 22\r\nColors: pink, green, purple, blue, red\n\r\n1. Kyle, who placed 4th, does not use a board that is red or pink.\n\r\n2. Annie is not the oldest but is older than Darla, who was not 2nd.\n\r\n3. The 18 year-old finished in 2nd place.\n\r\n4. The boarder that finished in 3rd place is older than the competitor with the purple board, who is 17.\n\r\n5. Brian is younger than the competitor with the blue board.\n\r\n6. The competitor with the pink board took 2nd place, ahead of the competitor with the green board, who did not place last.\n\r\n7. Kyle is older than both Brian and Annie but younger than Sandy.\n\r\n8. The girl with the blue board finished in 3rd place.\n\r\n9. The oldest competitor to place was on a red board and she took 5th.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDarla, age 17, 1st place, purple board\r\nBrian, age 18, 2nd place, pink board\r\nAnnie, age 20, 3rd place, blue board\r\nKyle, age 21, 4th place, green board\r\nSandy, age 22, 5th place, red board\n<|im_start|>answer\nDarla, age 17, 1st place, purple board\r\nBrian, age 18, 2nd place, pink board\r\nAnnie, age 20, 3rd place, blue board\r\nKyle, age 21, 4th place, green board\r\nSandy, age 22, 5th place, red board\n<|im_end|>" }, { "id": "#26402", "title": "Recipe Mix Up", "fun": 3.02, "difficulty": 2.25, "author": "sweetime", "desc": "A local radio station had announced a competition: cook the best three course meal and you and your fellow chefs could win a trip to Hawaii! Each team must have five entrants, and must consist of an entree, a main and a dessert. \n\r\nFive people now stood in Mr Black's kitchen arguing over whose recipes should be used. Each person had brought their three recipes with them and placed them on the table. Unfortunately Mr Black had not closed the window to the kitchen and a gush of wind rushed through and blew all the recipes off the table and jumbled them together.\n\r\nCan you work out which person owned which recipes?\n\r\nThere are:\r\nFirst Names: Kate, John, James, Matthew, Melissa\r\nLast names: Green, Brown, White, Blue, Black\r\nEntree: beef sausages, sausage rolls, leek soup, garlic bread, garlic shrimp.\r\nMains: trout and potato, spaghetti bolognaise, cheese souffle, steak and vegetables, chicken salad.\r\nDesserts: chocolate mousse, ice cream, fruit salad, lemon meringue pie, apple pie.\n\n\r\n1. The five people were: Kate, Mr Black, the one who had spaghetti bolognaise, the one who had chocolate mousse and the one who had garlic shrimp.\r\n2. Mr Green did not have any fruit or vegetables with his meals.\r\n3. No one had both the seafood items.\r\n4. Miss White did not have any meat in her recipes.\r\n5. Miss Blue only likes to use white meat in her recipes.\r\n6. The person who had garlic bread also had ice cream.\r\n7. The woman who had the cheese souffle did not have any garlic entrees.\r\n8. The man who had the chocolate mousse had fish in one of his dishes\r\n9. Matthew's main dish contained pasta.\r\n10. The woman with the garlic shrimp had salad with her main meal.\r\n11. Neither James nor Matthew had fruit in their dessert.\r\n12. John Black had red meat in both his main meal and his entree.\r\n13. Mr Green did not have meat in his entree.\r\n14. The man who had apple pie for dessert also had beef sausages as an entree.\r\n15. Melissa had a pie for dessert.", "hint": "The foods are only what is listed.\r\nEg, if someone doesn't have vegetables listed with their dish, then their dish does not come with vegetables.\n\r\nKate and Melissa are female; John, James and Matthew are male.\n\r\nSpaghetti bolognaise contains red meat", "answer": "Kate White, leek soup, cheese souffle, fruit salad.\n\r\nJohn Black, beef sausages, steak and vegetables, apple pie.\n\r\nJames Brown, sausage rolls, trout and potatoes, chocolate mousse.\n\r\nMatthew Green, garlic bread, spaghetti bolognaise, ice cream.\n\r\nMelissa Blue, garlic shrimps, chicken salad, lemon meringue pie.", "category": "Logic-Grid", "date": "10/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA local radio station had announced a competition: cook the best three course meal and you and your fellow chefs could win a trip to Hawaii! Each team must have five entrants, and must consist of an entree, a main and a dessert. \n\r\nFive people now stood in Mr Black's kitchen arguing over whose recipes should be used. Each person had brought their three recipes with them and placed them on the table. Unfortunately Mr Black had not closed the window to the kitchen and a gush of wind rushed through and blew all the recipes off the table and jumbled them together.\n\r\nCan you work out which person owned which recipes?\n\r\nThere are:\r\nFirst Names: Kate, John, James, Matthew, Melissa\r\nLast names: Green, Brown, White, Blue, Black\r\nEntree: beef sausages, sausage rolls, leek soup, garlic bread, garlic shrimp.\r\nMains: trout and potato, spaghetti bolognaise, cheese souffle, steak and vegetables, chicken salad.\r\nDesserts: chocolate mousse, ice cream, fruit salad, lemon meringue pie, apple pie.\n\n\r\n1. The five people were: Kate, Mr Black, the one who had spaghetti bolognaise, the one who had chocolate mousse and the one who had garlic shrimp.\r\n2. Mr Green did not have any fruit or vegetables with his meals.\r\n3. No one had both the seafood items.\r\n4. Miss White did not have any meat in her recipes.\r\n5. Miss Blue only likes to use white meat in her recipes.\r\n6. The person who had garlic bread also had ice cream.\r\n7. The woman who had the cheese souffle did not have any garlic entrees.\r\n8. The man who had the chocolate mousse had fish in one of his dishes\r\n9. Matthew's main dish contained pasta.\r\n10. The woman with the garlic shrimp had salad with her main meal.\r\n11. Neither James nor Matthew had fruit in their dessert.\r\n12. John Black had red meat in both his main meal and his entree.\r\n13. Mr Green did not have meat in his entree.\r\n14. The man who had apple pie for dessert also had beef sausages as an entree.\r\n15. Melissa had a pie for dessert.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKate White, leek soup, cheese souffle, fruit salad.\n\r\nJohn Black, beef sausages, steak and vegetables, apple pie.\n\r\nJames Brown, sausage rolls, trout and potatoes, chocolate mousse.\n\r\nMatthew Green, garlic bread, spaghetti bolognaise, ice cream.\n\r\nMelissa Blue, garlic shrimps, chicken salad, lemon meringue pie.\n<|im_start|>answer\nKate White, leek soup, cheese souffle, fruit salad.\n\r\nJohn Black, beef sausages, steak and vegetables, apple pie.\n\r\nJames Brown, sausage rolls, trout and potatoes, chocolate mousse.\n\r\nMatthew Green, garlic bread, spaghetti bolognaise, ice cream.\n\r\nMelissa Blue, garlic shrimps, chicken salad, lemon meringue pie.\n<|im_end|>" }, { "id": "#24181", "title": "Kennel Madness", "fun": 3.02, "difficulty": 1.28, "author": "ragsdaleam", "desc": "7 dogs were boarding at the local Pet Lodge. Each dog was in a separate run, all in a single row. One of the employees left the cages unlocked and the dogs have all gotten out of their runs. She needs to put each of them back in the right cage, but this is all she remembers. Help her get them in the right cages, and QUICK!\n\r\nDogs: Beau, Duke, Fluffy, Lady, Princess, Rover, and Spike\n\n\n\r\n1. Spike doesn't like other dogs much, so he was on one of the ends.\n\r\n2. Princess was somewhere to the left of Beau.\n\r\n3. Rover was in the third run from the right.\n\r\n4. The only dog between Fluffy and Lady was Princess.\n\r\n5. Duke was directly to the left of Lady.", "hint": "No hint available.", "answer": "Duke-Lady-Princess-Fluffy-Rover-Beau-Spike", "category": "Logic", "date": "07/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n7 dogs were boarding at the local Pet Lodge. Each dog was in a separate run, all in a single row. One of the employees left the cages unlocked and the dogs have all gotten out of their runs. She needs to put each of them back in the right cage, but this is all she remembers. Help her get them in the right cages, and QUICK!\n\r\nDogs: Beau, Duke, Fluffy, Lady, Princess, Rover, and Spike\n\n\n\r\n1. Spike doesn't like other dogs much, so he was on one of the ends.\n\r\n2. Princess was somewhere to the left of Beau.\n\r\n3. Rover was in the third run from the right.\n\r\n4. The only dog between Fluffy and Lady was Princess.\n\r\n5. Duke was directly to the left of Lady.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDuke-Lady-Princess-Fluffy-Rover-Beau-Spike\n<|im_start|>answer\nDuke-Lady-Princess-Fluffy-Rover-Beau-Spike\n<|im_end|>" }, { "id": "#25274", "title": "Where's Wally I Wonder?", "fun": 3.02, "difficulty": 2.01, "author": "grinnychick", "desc": "As we are all aware, Wally, his friends and Odlaw love to travel through time and space on a regular basis. However, after a nasty incident involving the magical walking stick and a pirate's sword in Pirate Land, the friends' and Wally's belongings were teleported to different lands. Who ended up in which land, what item did they find, and in what order did they arrive home?\n\r\nFriends: Wally, Wenda, Woof, Odlaw, Wizard Whitebeard\n\r\nLand: Viking-land, Outer space, Ancient Egypt, Giant Land, North Pole\n\r\nItems: scroll, camera, watch, walking stick, glasses\n\r\nOrder: 1st, 2nd, 3rd, 4th, 5th \n\r\n1. The one who found the glasses and the one that ended up on an orbiting space station were the last two to arrive home.\n\r\n2. Wenda and Wizard Whitebeard did not find the scroll, nor did they arrive home last.\n\r\n3. Woof did not find the watch; he was not fourth to arrive home.\n\r\n4. The one who was in outer space arrived before the one who found the glasses.\n\r\n5. Odlaw arrived before the one who found the glasses, but after the ones that found the walking stick and the camera.\n\r\n6. The one who found the walking stick arrived after the one that found the watch, but before the one sent to the North Pole. \n\r\n7. The first home was the one who found the watch, followed by Woof, then the one who visited Mr. and Mrs. Claus at the North Pole, then the one who found the scroll. Wally was last to arrive home.\n\r\n8. Wizard Whitebeard ended up getting lost in his land, as he could not understand the Egyptian hieroglyphs on the map he was given. \n\r\n9. Woof did not end up in the land of the Vikings, where the glasses were found.", "hint": "No hint available.", "answer": "Wizard Whitebeard ended up in Ancient Egypt where he found Wally's watch. He arrived home first, as he was the only one who could tell it was getting close to dinner time.\n\r\nWoof felt smaller than usual in the land of the Giants; he found the faulty walking stick and arrived home second.\n\r\nWenda was sent to the North Pole; she had her photo taken with Santa on the camera she found, and arrived home 3rd.\n\r\nOdlaw ended up in Outer Space; he found the scroll and was fourth to arrive home. This was a shame as they all hoped he would never come back.\n\r\nWally ended up in Vikingland, where he found his glasses and arrived home 5th.", "category": "Logic-Grid", "date": "08/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAs we are all aware, Wally, his friends and Odlaw love to travel through time and space on a regular basis. However, after a nasty incident involving the magical walking stick and a pirate's sword in Pirate Land, the friends' and Wally's belongings were teleported to different lands. Who ended up in which land, what item did they find, and in what order did they arrive home?\n\r\nFriends: Wally, Wenda, Woof, Odlaw, Wizard Whitebeard\n\r\nLand: Viking-land, Outer space, Ancient Egypt, Giant Land, North Pole\n\r\nItems: scroll, camera, watch, walking stick, glasses\n\r\nOrder: 1st, 2nd, 3rd, 4th, 5th \n\r\n1. The one who found the glasses and the one that ended up on an orbiting space station were the last two to arrive home.\n\r\n2. Wenda and Wizard Whitebeard did not find the scroll, nor did they arrive home last.\n\r\n3. Woof did not find the watch; he was not fourth to arrive home.\n\r\n4. The one who was in outer space arrived before the one who found the glasses.\n\r\n5. Odlaw arrived before the one who found the glasses, but after the ones that found the walking stick and the camera.\n\r\n6. The one who found the walking stick arrived after the one that found the watch, but before the one sent to the North Pole. \n\r\n7. The first home was the one who found the watch, followed by Woof, then the one who visited Mr. and Mrs. Claus at the North Pole, then the one who found the scroll. Wally was last to arrive home.\n\r\n8. Wizard Whitebeard ended up getting lost in his land, as he could not understand the Egyptian hieroglyphs on the map he was given. \n\r\n9. Woof did not end up in the land of the Vikings, where the glasses were found.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWizard Whitebeard ended up in Ancient Egypt where he found Wally's watch. He arrived home first, as he was the only one who could tell it was getting close to dinner time.\n\r\nWoof felt smaller than usual in the land of the Giants; he found the faulty walking stick and arrived home second.\n\r\nWenda was sent to the North Pole; she had her photo taken with Santa on the camera she found, and arrived home 3rd.\n\r\nOdlaw ended up in Outer Space; he found the scroll and was fourth to arrive home. This was a shame as they all hoped he would never come back.\n\r\nWally ended up in Vikingland, where he found his glasses and arrived home 5th.\n<|im_start|>answer\nWizard Whitebeard ended up in Ancient Egypt where he found Wally's watch. He arrived home first, as he was the only one who could tell it was getting close to dinner time.\n\r\nWoof felt smaller than usual in the land of the Giants; he found the faulty walking stick and arrived home second.\n\r\nWenda was sent to the North Pole; she had her photo taken with Santa on the camera she found, and arrived home 3rd.\n\r\nOdlaw ended up in Outer Space; he found the scroll and was fourth to arrive home. This was a shame as they all hoped he would never come back.\n\r\nWally ended up in Vikingland, where he found his glasses and arrived home 5th.\n<|im_end|>" }, { "id": "#29976", "title": "Let's Paint", "fun": 3.02, "difficulty": 2.88, "author": "peppamintp", "desc": "\"This house needs a face lift,\" Tess Ross pronounced, and her family (two men, Mitch and Shane, and two women Lana and Penelope) thought the same. A quick paint job on five different rooms was all that was really needed, and the five Rosses eagerly set to work. A different white paint (one was Atrium White) was selected for each room, each of which required a different number of gallons of paint. Each family member painted a room. When, at the end of a weekend of painting, Tess's son announced \"Well, Mom, you were right. We were done in no time,\" her two daughters and her husband quickly agreed. The family then settled in for an enjoyable evening in their newly painted living room. From the information provided, can you determine the person who painted each room, the color of the paint each used, and the number of gallons (1, 2, 3, 4, or 6) that were used for each room?\n\r\n1. One daughter used the Feather White paint in the room she painted, while the other daughter painted her father's office.\n\r\n2. Tess's husband used three gallons of paint to complete the room on which he worked. Tess's son painted the master bedroom.\n\r\n3. Combined, the number of gallons of paint required to paint the master bedroom and the office equaled the number of gallons required for the kitchen.\n\r\n4. Exactly twice as many gallons of paint were used to paint the dining room as Lana used in the room she painted. Penelope required exactly twice as many gallons in the room she painted as were used of the Topper White.\n\r\n5. Mitch and the person who used the Feather White paint worked on the kitchen and the living room, in some order.\n\r\n6. Exactly twice as many gallons of Graduate White were used as Polar Bear White. Shane didn't use Polar Bear White.", "hint": "No hint available.", "answer": "Lana, office, Polar Bear, 2\r\nMitch, kitchen, Topper, 3\r\nPenelope, living room, Feather, 6\r\nShane, master bedroom, Atrium, 1\r\nTess, dining room, Graduate, 4", "category": "Logic-Grid", "date": "04/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"This house needs a face lift,\" Tess Ross pronounced, and her family (two men, Mitch and Shane, and two women Lana and Penelope) thought the same. A quick paint job on five different rooms was all that was really needed, and the five Rosses eagerly set to work. A different white paint (one was Atrium White) was selected for each room, each of which required a different number of gallons of paint. Each family member painted a room. When, at the end of a weekend of painting, Tess's son announced \"Well, Mom, you were right. We were done in no time,\" her two daughters and her husband quickly agreed. The family then settled in for an enjoyable evening in their newly painted living room. From the information provided, can you determine the person who painted each room, the color of the paint each used, and the number of gallons (1, 2, 3, 4, or 6) that were used for each room?\n\r\n1. One daughter used the Feather White paint in the room she painted, while the other daughter painted her father's office.\n\r\n2. Tess's husband used three gallons of paint to complete the room on which he worked. Tess's son painted the master bedroom.\n\r\n3. Combined, the number of gallons of paint required to paint the master bedroom and the office equaled the number of gallons required for the kitchen.\n\r\n4. Exactly twice as many gallons of paint were used to paint the dining room as Lana used in the room she painted. Penelope required exactly twice as many gallons in the room she painted as were used of the Topper White.\n\r\n5. Mitch and the person who used the Feather White paint worked on the kitchen and the living room, in some order.\n\r\n6. Exactly twice as many gallons of Graduate White were used as Polar Bear White. Shane didn't use Polar Bear White.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLana, office, Polar Bear, 2\r\nMitch, kitchen, Topper, 3\r\nPenelope, living room, Feather, 6\r\nShane, master bedroom, Atrium, 1\r\nTess, dining room, Graduate, 4\n<|im_start|>answer\nLana, office, Polar Bear, 2\r\nMitch, kitchen, Topper, 3\r\nPenelope, living room, Feather, 6\r\nShane, master bedroom, Atrium, 1\r\nTess, dining room, Graduate, 4\n<|im_end|>" }, { "id": "#21182", "title": "Prom Night With the Boys", "fun": 3.02, "difficulty": 2.4, "author": "ZOE5639", "desc": "It's prom week and 5 friends are going to hang out as a group with their dates. The boys all tried to match their dates' dresses, they each picked their dates up at different times, and after prom they all went separate ways with their dates.\n\r\nGuys- Joey, Mauricio, Damian, Brian, and Pierre\r\nDates- Zoe, Rhonda, Renee, Cloe, and Ashley\r\nTimes of pick up- 5:45, 6:00, 6:15, 6:30, and 7:30\r\nDress colors- Black, White, Red, Purple, Teal\r\nAfter the Prom- Watched a movie with date's family at home, Went to a huge party, Went out to dinner, Went to a club, Went to the beach for a walk.\n\r\n1. Mauricio asked Rhonda, but she told him she already had a date. So he asked her sister instead, and she accepted.\r\n2. Pierre and his date were the only ones late to prom. Because they were late, they ended up fighting and Ashley decided not to go out to dinner with him afterwards.\r\n3. Damian's date wore a red dress. Joey's date wore black.\r\n4. Zoe's date did not pick her up first or last. However she did not want to go to a party or a club after prom.\r\n5. Mauricio who is never late to anything, always early, picked up his date and made sure he gave her a white flower, and had a great time at the dance.\r\n6.Joey couldn't decide between Rhonda and Renee since they were sisters, so he made sure he asked one of the other girls.\r\n7. Brian didn't really even want to go to the prom. He likes to stay at home, hang out with the family and watch movies, so he wasn't too quick on picking up his date. He figured the later the better, however he did not want to be late.\r\n8. Rhonda and her date were a on again, off again couple, and when they dated, they spent tons of time at the beach. It was always their favorite spot.\r\n9. Zoe wore a purple dress last year to prom and went there with Brian. They did not have a good time, so Brian did not want his date to wear purple and did not want his date to be Zoe again.\r\n10. Mauricio and Pierre are the big party guys of the group, hardly ever stay with one girl, while the rest of the guys are the romantics. Mauricio's brother works at a club, and even though that's where he spends many weekends, did not feel like going to one on prom night, but he wanted to party.\r\n11. Damian picked up his red-hot date at a quarter after six.", "hint": "No hint available.", "answer": "Damian, Rhonda, Red Dress, 6:15, Walked on the beach.\r\nJoey, Zoe, Black Dress, 6:00, Went out to Dinner. Mauricio, Renee, White Dress, 5:45, Went to a huge party.\r\nBrian, Cloe, Teal Dress, 6:30, Watched a movie with her family.\r\nPierre, Ashley, Purple Dress, 7:30, Went to the club.", "category": "Logic-Grid", "date": "02/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's prom week and 5 friends are going to hang out as a group with their dates. The boys all tried to match their dates' dresses, they each picked their dates up at different times, and after prom they all went separate ways with their dates.\n\r\nGuys- Joey, Mauricio, Damian, Brian, and Pierre\r\nDates- Zoe, Rhonda, Renee, Cloe, and Ashley\r\nTimes of pick up- 5:45, 6:00, 6:15, 6:30, and 7:30\r\nDress colors- Black, White, Red, Purple, Teal\r\nAfter the Prom- Watched a movie with date's family at home, Went to a huge party, Went out to dinner, Went to a club, Went to the beach for a walk.\n\r\n1. Mauricio asked Rhonda, but she told him she already had a date. So he asked her sister instead, and she accepted.\r\n2. Pierre and his date were the only ones late to prom. Because they were late, they ended up fighting and Ashley decided not to go out to dinner with him afterwards.\r\n3. Damian's date wore a red dress. Joey's date wore black.\r\n4. Zoe's date did not pick her up first or last. However she did not want to go to a party or a club after prom.\r\n5. Mauricio who is never late to anything, always early, picked up his date and made sure he gave her a white flower, and had a great time at the dance.\r\n6.Joey couldn't decide between Rhonda and Renee since they were sisters, so he made sure he asked one of the other girls.\r\n7. Brian didn't really even want to go to the prom. He likes to stay at home, hang out with the family and watch movies, so he wasn't too quick on picking up his date. He figured the later the better, however he did not want to be late.\r\n8. Rhonda and her date were a on again, off again couple, and when they dated, they spent tons of time at the beach. It was always their favorite spot.\r\n9. Zoe wore a purple dress last year to prom and went there with Brian. They did not have a good time, so Brian did not want his date to wear purple and did not want his date to be Zoe again.\r\n10. Mauricio and Pierre are the big party guys of the group, hardly ever stay with one girl, while the rest of the guys are the romantics. Mauricio's brother works at a club, and even though that's where he spends many weekends, did not feel like going to one on prom night, but he wanted to party.\r\n11. Damian picked up his red-hot date at a quarter after six.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDamian, Rhonda, Red Dress, 6:15, Walked on the beach.\r\nJoey, Zoe, Black Dress, 6:00, Went out to Dinner. Mauricio, Renee, White Dress, 5:45, Went to a huge party.\r\nBrian, Cloe, Teal Dress, 6:30, Watched a movie with her family.\r\nPierre, Ashley, Purple Dress, 7:30, Went to the club.\n<|im_start|>answer\nDamian, Rhonda, Red Dress, 6:15, Walked on the beach.\r\nJoey, Zoe, Black Dress, 6:00, Went out to Dinner. Mauricio, Renee, White Dress, 5:45, Went to a huge party.\r\nBrian, Cloe, Teal Dress, 6:30, Watched a movie with her family.\r\nPierre, Ashley, Purple Dress, 7:30, Went to the club.\n<|im_end|>" }, { "id": "#19413", "title": "Fast Food Lunch", "fun": 3.02, "difficulty": 2.25, "author": "Jake", "desc": "Five customers (Candy, Derek, John, Rose, and Steve), order lunch at a fast food restaurant. They order the following things, not in order: Cheeseburger, Salad, Chicken Strips, Hamburger and Fried Fish. Each customer asked for his or her meal to have extra sauce added to it (catsup, mustard, BBQ sauce, mayo or ranch dressing). Can you figure out who got what and in which order they were standing in line?\n\r\nClues:\n\r\n1) The first customer (who wasn't a girl) isn't the one who ordered a salad. \r\n2) The salad did not get BBQ sauce on it.\r\n3) Candy ate chicken for lunch and wasn't last in line. \r\n4) The person who asked for extra catsup had a cheeseburger.\r\n5) John did not eat the mustard drenched fish.\r\n6) Derek was in the exact middle of the line.\r\n7) Steve was in line after the salad eater but before the mayo lover.", "hint": "No hint available.", "answer": "John was first in line and ordered cheeseburger with extra catsup.\r\nCandy was second and ordered BBQ chicken strips.\r\nDerek was third and had salad with ranch dressing.\r\nSteve was fourth and ate a fish with mustard.\r\nRose was last in line and ate a hamburger with mayo.", "category": "Logic-Grid", "date": "10/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive customers (Candy, Derek, John, Rose, and Steve), order lunch at a fast food restaurant. They order the following things, not in order: Cheeseburger, Salad, Chicken Strips, Hamburger and Fried Fish. Each customer asked for his or her meal to have extra sauce added to it (catsup, mustard, BBQ sauce, mayo or ranch dressing). Can you figure out who got what and in which order they were standing in line?\n\r\nClues:\n\r\n1) The first customer (who wasn't a girl) isn't the one who ordered a salad. \r\n2) The salad did not get BBQ sauce on it.\r\n3) Candy ate chicken for lunch and wasn't last in line. \r\n4) The person who asked for extra catsup had a cheeseburger.\r\n5) John did not eat the mustard drenched fish.\r\n6) Derek was in the exact middle of the line.\r\n7) Steve was in line after the salad eater but before the mayo lover.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn was first in line and ordered cheeseburger with extra catsup.\r\nCandy was second and ordered BBQ chicken strips.\r\nDerek was third and had salad with ranch dressing.\r\nSteve was fourth and ate a fish with mustard.\r\nRose was last in line and ate a hamburger with mayo.\n<|im_start|>answer\nJohn was first in line and ordered cheeseburger with extra catsup.\r\nCandy was second and ordered BBQ chicken strips.\r\nDerek was third and had salad with ranch dressing.\r\nSteve was fourth and ate a fish with mustard.\r\nRose was last in line and ate a hamburger with mayo.\n<|im_end|>" }, { "id": "#29133", "title": "The Band Concert", "fun": 3.01, "difficulty": 2.58, "author": "thompson1", "desc": "There is a big school band concert coming up soon. The band will be playing 5 songs that each have a big solo in them. Each solo is played by a different kid on a different instrument and each song is a different length. Ms. Staccato, who was responsible for making the programs for the concert, dropped all of the papers with the concert information on them! Help her figure out what each kid's first and last names are, what instrument they play, what song they have a solo in, and how long each song is.\n\r\nFirst Names - Seth, Emily, Fred, Tyler, and Carla\r\nLast Names - Taylor, Edwards, Norman, Williams, and Roberts\r\nInstruments - Snare Drum, Timpani, Trumpet, Flute, and Clarinet\r\nSongs - \"Bluesville,\" \"The Red, the White, and the Blues,\" \"On, Wisconsin,\" \"Alleluia,\" and \"Clairvoyance\"\r\nLengths (minutes) - 1:30, 2:30, 3:00, 4:00, 4:30\n\r\n1. The five kids are: Tyler, the one who plays the flute, the one with the last name of Roberts, the one with a solo in Bluesville, and the one that has a solo in the 4:00 song.\n\r\n2. The five songs are: \"On, Wisconsin,\" the one that has a solo played by Emily, the one that is 3:00 long, the one with a solo played by the kid with the last name of Williams, and the one with a solo played on the timpani.\n\r\n3. No one plays an instrument that has the same first letter as their first name.\n\r\n4. Only 1 person has the same first and last initials.\n\r\n5. Emily doesn't have a solo in a song that has the word \"Blues\" in it.\n\r\n6. A girl plays the snare, which is the instrument that has a solo in \"Alleluia\".\n\r\n7. The song that has the same first syllable as the instrument that has a solo in it is 1 minute longer than the song with a solo played by the kid with the last name of Taylor.\n\r\n8. The song that the trumpet has a solo in does not have any letters in it that are in the word trumpet.\n\r\n9. The song that has the name of a state in the USA in it is longer than 1:30.\n\r\n10. Bluesville has exactly twice the amount of letters in it as the first name of the kid who has a solo in it.\n\r\nNotes: \"R,W,+ Blues\" in the solver stands for \"The Red, the White, and the Blues\". Seth, Fred and Tyler are boys; Emily and Carla are girls.", "hint": "For those of you who don't already know:\n\r\nA Snare Drum is a percussion instrument that only has one major sound.\n\r\nTimpani are large drums that normally come in sets of 3 or 4 and have different pitches.\n\r\nA trumpet is a brass instrument played by blowing into a mouthpiece and pressing down different valves to make different notes.\n\r\nA flute is a woodwind instrument played by blowing over a mouthpiece and pressing down different keys.\n\r\nA clarinet is a woodwind instrument played by blowing on a reed and mouthpiece and pressing down different keys.", "answer": "Seth Norman has a flute solo in \"The Red, the White, and the Blues,\" which is 3:00 long.\r\nEmily Edwards has a snare drum solo in \"Alleluia,\" which is 4:00 long.\r\nFred Roberts has a trumpet solo in \"On, Wisconsin,\" which is 4:30 long.\r\nTyler Williams has a clarinet solo in \"Clairvoyance,\" which is 2:30 long.\r\nCarla Taylor has a timpani solo in \"Bluesville,\" which is 1:30 long.\n\r\nThese are all real songs and all (except Bluesville) have solos in them played by the instruments in this puzzle.", "category": "Logic-Grid", "date": "03/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a big school band concert coming up soon. The band will be playing 5 songs that each have a big solo in them. Each solo is played by a different kid on a different instrument and each song is a different length. Ms. Staccato, who was responsible for making the programs for the concert, dropped all of the papers with the concert information on them! Help her figure out what each kid's first and last names are, what instrument they play, what song they have a solo in, and how long each song is.\n\r\nFirst Names - Seth, Emily, Fred, Tyler, and Carla\r\nLast Names - Taylor, Edwards, Norman, Williams, and Roberts\r\nInstruments - Snare Drum, Timpani, Trumpet, Flute, and Clarinet\r\nSongs - \"Bluesville,\" \"The Red, the White, and the Blues,\" \"On, Wisconsin,\" \"Alleluia,\" and \"Clairvoyance\"\r\nLengths (minutes) - 1:30, 2:30, 3:00, 4:00, 4:30\n\r\n1. The five kids are: Tyler, the one who plays the flute, the one with the last name of Roberts, the one with a solo in Bluesville, and the one that has a solo in the 4:00 song.\n\r\n2. The five songs are: \"On, Wisconsin,\" the one that has a solo played by Emily, the one that is 3:00 long, the one with a solo played by the kid with the last name of Williams, and the one with a solo played on the timpani.\n\r\n3. No one plays an instrument that has the same first letter as their first name.\n\r\n4. Only 1 person has the same first and last initials.\n\r\n5. Emily doesn't have a solo in a song that has the word \"Blues\" in it.\n\r\n6. A girl plays the snare, which is the instrument that has a solo in \"Alleluia\".\n\r\n7. The song that has the same first syllable as the instrument that has a solo in it is 1 minute longer than the song with a solo played by the kid with the last name of Taylor.\n\r\n8. The song that the trumpet has a solo in does not have any letters in it that are in the word trumpet.\n\r\n9. The song that has the name of a state in the USA in it is longer than 1:30.\n\r\n10. Bluesville has exactly twice the amount of letters in it as the first name of the kid who has a solo in it.\n\r\nNotes: \"R,W,+ Blues\" in the solver stands for \"The Red, the White, and the Blues\". Seth, Fred and Tyler are boys; Emily and Carla are girls.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSeth Norman has a flute solo in \"The Red, the White, and the Blues,\" which is 3:00 long.\r\nEmily Edwards has a snare drum solo in \"Alleluia,\" which is 4:00 long.\r\nFred Roberts has a trumpet solo in \"On, Wisconsin,\" which is 4:30 long.\r\nTyler Williams has a clarinet solo in \"Clairvoyance,\" which is 2:30 long.\r\nCarla Taylor has a timpani solo in \"Bluesville,\" which is 1:30 long.\n\r\nThese are all real songs and all (except Bluesville) have solos in them played by the instruments in this puzzle.\n<|im_start|>answer\nSeth Norman has a flute solo in \"The Red, the White, and the Blues,\" which is 3:00 long.\r\nEmily Edwards has a snare drum solo in \"Alleluia,\" which is 4:00 long.\r\nFred Roberts has a trumpet solo in \"On, Wisconsin,\" which is 4:30 long.\r\nTyler Williams has a clarinet solo in \"Clairvoyance,\" which is 2:30 long.\r\nCarla Taylor has a timpani solo in \"Bluesville,\" which is 1:30 long.\n\r\nThese are all real songs and all (except Bluesville) have solos in them played by the instruments in this puzzle.\n<|im_end|>" }, { "id": "#37386", "title": "The Scrapbookers 2", "fun": 3.01, "difficulty": 1.96, "author": "jenb2144", "desc": "Five avid scrapbookers from Acres get together every weekend to swap page ideas and discuss the progress that they have made on their scrapbooks during the week. Each scrapbooker focuses on a different event, uses a different colour and a different embellishment. Using the clues below, determine the first and last names of each scrapbooker, the event they focused on, the colour they used, and their preferred embellishment.\n\r\n1. Stella didn't do a wedding page. One of the men preferred to use the chalking technique for his page.\r\n2. Arthur and Stella do not like using tags. The person who did the birthday page thought the colour purple accented their pictures perfectly.\r\n3. Mrs. Moss hates using the colour red, regardless of the topic of her pages. Maria's last name isn't Harris and she has never done a vacation page.\r\n4. The person who did the wedding page, whose last name wasn't Enfield, was excited about using eyelets for the first time. The person who did a yellow new baby page wasn't Ruth, but their last name is Harris.\r\n5. The five scrapbookers (in no particular order) are: Maria Steele, the man who did the birthday page, the person who used the stamping technique, the one who was pleased with their green page, and Ruth.\r\n6. Shane's last name is not Harris and blue would not have looked right on his page. Red was the perfect colour for the wedding page though, as it is associated with love.\r\n7. Stella McKee took so many pictures when she moved into her first house that she just had to use them for her page.", "hint": "No hint available.", "answer": "Arthur Harris did a new baby page in yellow using stamps.\r\nMaria Steele did a wedding page in red using eyelets.\r\nRuth Moss did a vacation page in blue using tags.\r\nShane Enfield did a birthday page in purple using chalk.\r\nStella McKee did a new house page in green using die cuts.", "category": "Logic-Grid", "date": "07/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive avid scrapbookers from Acres get together every weekend to swap page ideas and discuss the progress that they have made on their scrapbooks during the week. Each scrapbooker focuses on a different event, uses a different colour and a different embellishment. Using the clues below, determine the first and last names of each scrapbooker, the event they focused on, the colour they used, and their preferred embellishment.\n\r\n1. Stella didn't do a wedding page. One of the men preferred to use the chalking technique for his page.\r\n2. Arthur and Stella do not like using tags. The person who did the birthday page thought the colour purple accented their pictures perfectly.\r\n3. Mrs. Moss hates using the colour red, regardless of the topic of her pages. Maria's last name isn't Harris and she has never done a vacation page.\r\n4. The person who did the wedding page, whose last name wasn't Enfield, was excited about using eyelets for the first time. The person who did a yellow new baby page wasn't Ruth, but their last name is Harris.\r\n5. The five scrapbookers (in no particular order) are: Maria Steele, the man who did the birthday page, the person who used the stamping technique, the one who was pleased with their green page, and Ruth.\r\n6. Shane's last name is not Harris and blue would not have looked right on his page. Red was the perfect colour for the wedding page though, as it is associated with love.\r\n7. Stella McKee took so many pictures when she moved into her first house that she just had to use them for her page.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nArthur Harris did a new baby page in yellow using stamps.\r\nMaria Steele did a wedding page in red using eyelets.\r\nRuth Moss did a vacation page in blue using tags.\r\nShane Enfield did a birthday page in purple using chalk.\r\nStella McKee did a new house page in green using die cuts.\n<|im_start|>answer\nArthur Harris did a new baby page in yellow using stamps.\r\nMaria Steele did a wedding page in red using eyelets.\r\nRuth Moss did a vacation page in blue using tags.\r\nShane Enfield did a birthday page in purple using chalk.\r\nStella McKee did a new house page in green using die cuts.\n<|im_end|>" }, { "id": "#34332", "title": "The Sibling Rivalry Week", "fun": 3.01, "difficulty": 2.11, "author": "dishu", "desc": "Fightland Street is famous for 5 friends who have 1 sibling each. One particular week, each of these friends broke into a fight with their siblings on a different day of the week and for a different stupid reason (sibling fights are seldom intelligent). Fortunately, they soon realised how childish they were being and decided to patch up in a unique and special way. With the help of these clues, can you figure out who fought with whom, for what reason, on which day and how did they patch up?\n\r\n1. Charles accused his sister of stealing his watch; but on realizing that he himself had misplaced it, he bought her a nice new skirt.\n\r\n2. Since Harry fought with his sister over an eatable item, she gifted him another eatable item to patch-up.\n\r\n3. The siblings to fight on Monday argued about who was a better basketball player.\n\r\n4. Bob does not have a sister.\n\r\n5. The boy who gave his brother a silk tie to patch-up, fought with him on Thursday.\n\r\n6. Jane did not fight on Tuesday.\n\r\n7. The brother-sister pair to fight over the phone went to Pizza Hut to patch-up, which for some strange reason, is only opened on Wednesdays.\n\r\n8.Emma and George went to a movie.\n\r\n9. Ira is not Charles' sister.\n\r\nFriends: Alice, Bob, Charles, Denver, Emma\r\nSiblings: Fred, George, Harry, Ira, Jane\r\nReasons for fight: Basketball, Chocolates, Watch, Phone, New T-shirt\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\r\nPatch-up method: Movie, Silk Tie, Ice Candy, Lunch at Pizza Hut, New Skirt", "hint": "Alice, Emma, Ira and Jane are girls. The rest are boys.\n\r\nIn the grid, lunch at Pizza Hut has been condensed to Pizza Hut", "answer": "Emma claimed that she was a better basketball player than George, and later, they went to a movie on Monday.\n\r\nAlice and Harry fought over Chocolates on Tuesday, and Alice gave him an ice candy to cheer him up.\n\r\nWednesday morning, Denver and Ira argued about who was always keeping the phone busy, but later they went for a nice lunch at Pizza Hut together.\n\r\nBob and Fred argued about who would wear the new T-shirt first on Thursday, and Bob gifted Fred a new silk tie to put an end to the fight.\n\r\nCharles and Jane fought over Charles' misplaced watch on Friday, and Charles ended up buying a new skirt for his sister.", "category": "Logic-Grid", "date": "12/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFightland Street is famous for 5 friends who have 1 sibling each. One particular week, each of these friends broke into a fight with their siblings on a different day of the week and for a different stupid reason (sibling fights are seldom intelligent). Fortunately, they soon realised how childish they were being and decided to patch up in a unique and special way. With the help of these clues, can you figure out who fought with whom, for what reason, on which day and how did they patch up?\n\r\n1. Charles accused his sister of stealing his watch; but on realizing that he himself had misplaced it, he bought her a nice new skirt.\n\r\n2. Since Harry fought with his sister over an eatable item, she gifted him another eatable item to patch-up.\n\r\n3. The siblings to fight on Monday argued about who was a better basketball player.\n\r\n4. Bob does not have a sister.\n\r\n5. The boy who gave his brother a silk tie to patch-up, fought with him on Thursday.\n\r\n6. Jane did not fight on Tuesday.\n\r\n7. The brother-sister pair to fight over the phone went to Pizza Hut to patch-up, which for some strange reason, is only opened on Wednesdays.\n\r\n8.Emma and George went to a movie.\n\r\n9. Ira is not Charles' sister.\n\r\nFriends: Alice, Bob, Charles, Denver, Emma\r\nSiblings: Fred, George, Harry, Ira, Jane\r\nReasons for fight: Basketball, Chocolates, Watch, Phone, New T-shirt\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\r\nPatch-up method: Movie, Silk Tie, Ice Candy, Lunch at Pizza Hut, New Skirt\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEmma claimed that she was a better basketball player than George, and later, they went to a movie on Monday.\n\r\nAlice and Harry fought over Chocolates on Tuesday, and Alice gave him an ice candy to cheer him up.\n\r\nWednesday morning, Denver and Ira argued about who was always keeping the phone busy, but later they went for a nice lunch at Pizza Hut together.\n\r\nBob and Fred argued about who would wear the new T-shirt first on Thursday, and Bob gifted Fred a new silk tie to put an end to the fight.\n\r\nCharles and Jane fought over Charles' misplaced watch on Friday, and Charles ended up buying a new skirt for his sister.\n<|im_start|>answer\nEmma claimed that she was a better basketball player than George, and later, they went to a movie on Monday.\n\r\nAlice and Harry fought over Chocolates on Tuesday, and Alice gave him an ice candy to cheer him up.\n\r\nWednesday morning, Denver and Ira argued about who was always keeping the phone busy, but later they went for a nice lunch at Pizza Hut together.\n\r\nBob and Fred argued about who would wear the new T-shirt first on Thursday, and Bob gifted Fred a new silk tie to put an end to the fight.\n\r\nCharles and Jane fought over Charles' misplaced watch on Friday, and Charles ended up buying a new skirt for his sister.\n<|im_end|>" }, { "id": "#26805", "title": "All Manner of Trees", "fun": 3.01, "difficulty": 1.92, "author": "Rob2003", "desc": "Four friends decided to plant a new tree in their yard to celebrate Labor Day. The new trees would each be put in a different area of their yards. As it happened each friend bought a different kind of tree and planted the new tree on a different day of the week. From the clues below, determine the full names of each friend, what kind of tree each bought, where in the yard it was planted, and on what day of the week each tree was planted.\n\r\nNames: Rebbecca, Sally, Tracy, and Wanda\n\r\nLast Name: Best, Dart, Frost, and Grand\n\r\nTrees: ash tree, cherry tree, maple tree, and spruce tree\n\r\nLocation: garden, patio, back yard, and front yard\n\r\nDays of the Week: Monday, Wednesday, Thursday, and Friday\n\r\n1. Wanda, whose last name wasn't Frost, didn't plant her spruce tree by the patio.\n\r\n2. Tracy planted her tree before Mrs. Dart but after the woman who planted the ash tree.\n\r\n3. Mrs. Best, whose first name wasn't Sally, planted her tree in the front yard, but not on Friday. \n\r\n4. Rebbecca didn't plant her tree on Monday. \n\r\n5. Mrs. Grand planted her tree before the woman who planted her tree in the back yard. Rebbecca didn't plant the cherry tree. \n\r\n6. The trees were planted, in chronological order, as follows: Mrs. Frost, in the garden, Wanda, the maple tree.", "hint": "No hint available.", "answer": "Rebbecca Dart: maple tree, backyard, Friday \r\nSally Frost: ash tree, patio, Monday \r\nTracy Grand: cherry tree, garden, Wednesday \r\nWanda Best: spruce tree, front yard, Thursday", "category": "Logic-Grid", "date": "11/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends decided to plant a new tree in their yard to celebrate Labor Day. The new trees would each be put in a different area of their yards. As it happened each friend bought a different kind of tree and planted the new tree on a different day of the week. From the clues below, determine the full names of each friend, what kind of tree each bought, where in the yard it was planted, and on what day of the week each tree was planted.\n\r\nNames: Rebbecca, Sally, Tracy, and Wanda\n\r\nLast Name: Best, Dart, Frost, and Grand\n\r\nTrees: ash tree, cherry tree, maple tree, and spruce tree\n\r\nLocation: garden, patio, back yard, and front yard\n\r\nDays of the Week: Monday, Wednesday, Thursday, and Friday\n\r\n1. Wanda, whose last name wasn't Frost, didn't plant her spruce tree by the patio.\n\r\n2. Tracy planted her tree before Mrs. Dart but after the woman who planted the ash tree.\n\r\n3. Mrs. Best, whose first name wasn't Sally, planted her tree in the front yard, but not on Friday. \n\r\n4. Rebbecca didn't plant her tree on Monday. \n\r\n5. Mrs. Grand planted her tree before the woman who planted her tree in the back yard. Rebbecca didn't plant the cherry tree. \n\r\n6. The trees were planted, in chronological order, as follows: Mrs. Frost, in the garden, Wanda, the maple tree.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRebbecca Dart: maple tree, backyard, Friday \r\nSally Frost: ash tree, patio, Monday \r\nTracy Grand: cherry tree, garden, Wednesday \r\nWanda Best: spruce tree, front yard, Thursday\n<|im_start|>answer\nRebbecca Dart: maple tree, backyard, Friday \r\nSally Frost: ash tree, patio, Monday \r\nTracy Grand: cherry tree, garden, Wednesday \r\nWanda Best: spruce tree, front yard, Thursday\n<|im_end|>" }, { "id": "#24668", "title": "Family Tree 2", "fun": 3.01, "difficulty": 2.75, "author": "cdrock", "desc": "One day, a college student named Tina walked into her logic class and waited for her fun day of logic once again. Finally the professor, Professor C. D. Rock, walked in saying, \"I just went through some stuff and stumbled upon an old family tree, that belonged to my grandparents, that gave me an idea. I have here a few clues, and you have to use them to figure out their family tree!\" \n\r\nTina then gets the clues, and tries to work them out. Unfortunately this puzzle is a little harder than the normal ones Professor C. D. Rock gives out. Can you help her?\n\r\nThe family tree consists of two grandparents, who had 3 children, each of whom get married and have 2 children.\n\r\nMales: Cole, Cristian, Jason, Neil, and Steve\r\nFemales: Amanda, Ashley, Beth, Erin, Kaitlyn, Katherine, Makayla, Payton, and Tammy \n\r\nClues:\n\r\n1. One of Makayla's cousins is Jason's son.\n\r\n2. One of Ashley's aunts is Tammy.\n\r\n3. Tammy's brother-in-law is Neil's son.\n\r\n4. Kaitlyn's sister is Ashley's cousin.\n\r\n5. Ashley's uncle, Steve, is Erin's brother-in-law.\n\r\n6. The three uncles are Payton's dad, Cristian, and Katherine's son.\n\r\n7. The three aunts are Kaitlyn's mom, Ashley's mom, and Cristian's sister-in-law.\n\r\n8. Jason's brother is Ashley's dad.\n\r\n9. Amanda's sister is Steve's niece.\n\r\n10. Beth is not Cole's aunt.", "hint": "Use paper and pencil, it's almost impossible to do in your head.", "answer": "The grandparents are Katherine and Neil, who had 3 sons: Cristian, Jason, and Steve.\n\r\nCristian married Erin, and had Ashley and Amanda.\n\r\nJason married Beth, and had Payton and Cole.\n\r\nSteve married Tammy, and had Makayla and Kaitlyn.", "category": "Logic", "date": "07/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, a college student named Tina walked into her logic class and waited for her fun day of logic once again. Finally the professor, Professor C. D. Rock, walked in saying, \"I just went through some stuff and stumbled upon an old family tree, that belonged to my grandparents, that gave me an idea. I have here a few clues, and you have to use them to figure out their family tree!\" \n\r\nTina then gets the clues, and tries to work them out. Unfortunately this puzzle is a little harder than the normal ones Professor C. D. Rock gives out. Can you help her?\n\r\nThe family tree consists of two grandparents, who had 3 children, each of whom get married and have 2 children.\n\r\nMales: Cole, Cristian, Jason, Neil, and Steve\r\nFemales: Amanda, Ashley, Beth, Erin, Kaitlyn, Katherine, Makayla, Payton, and Tammy \n\r\nClues:\n\r\n1. One of Makayla's cousins is Jason's son.\n\r\n2. One of Ashley's aunts is Tammy.\n\r\n3. Tammy's brother-in-law is Neil's son.\n\r\n4. Kaitlyn's sister is Ashley's cousin.\n\r\n5. Ashley's uncle, Steve, is Erin's brother-in-law.\n\r\n6. The three uncles are Payton's dad, Cristian, and Katherine's son.\n\r\n7. The three aunts are Kaitlyn's mom, Ashley's mom, and Cristian's sister-in-law.\n\r\n8. Jason's brother is Ashley's dad.\n\r\n9. Amanda's sister is Steve's niece.\n\r\n10. Beth is not Cole's aunt.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe grandparents are Katherine and Neil, who had 3 sons: Cristian, Jason, and Steve.\n\r\nCristian married Erin, and had Ashley and Amanda.\n\r\nJason married Beth, and had Payton and Cole.\n\r\nSteve married Tammy, and had Makayla and Kaitlyn.\n<|im_start|>answer\nThe grandparents are Katherine and Neil, who had 3 sons: Cristian, Jason, and Steve.\n\r\nCristian married Erin, and had Ashley and Amanda.\n\r\nJason married Beth, and had Payton and Cole.\n\r\nSteve married Tammy, and had Makayla and Kaitlyn.\n<|im_end|>" }, { "id": "#26819", "title": "What's For Lunch?", "fun": 3.01, "difficulty": 2.56, "author": "ilovehimalways", "desc": "One week last summer, Richard's 5 kids went to camp. On each weekday, Richard had lunch with a different one of his children in the camp cafeteria. Except for the twins, who are both in the same grade, each of the children will begin a different grade in the fall. Each day of the week, a different main dish and different dessert was served. Can you figure out who Richard ate with on what day and what he had for lunch?\n\r\n1) Richard and his only sixth-grade child (who isn't Basil) enjoyed the BBQ beef on Wednesday. The day Richard ate lunch with Basil wasn't the day chili was served.\n\r\n2) Monday's dessert was brownies. Friday's was apple pie.\n\r\n3) Lasagna was served on the day Richard joined his daughter Lily for lunch.\n\r\n4) Thursday wasn't the day on which Richard and one of the twins had fried chicken followed by chocolate pudding.\n\r\n5) Richard ate lunch with Darlene more than one day before he ate lunch with Amber (who is about to begin second grade, but isn't a twin).\n\r\n6) Foster (who isn't the one with whom Richard had peach cobbler for dessert) is entering a higher grade than the child whom Richard ate pizza but a lower grade than at least one other child. \n\r\n7) Richard didn't eat lasagna with either of the twins, nor did he eat lunch with the twins on consecutive days.", "hint": "The twins are in fourth grade.\r\nFC=Fried Chicken", "answer": "Amber-Friday-pizza-apple pie-2nd\r\nBasil-Tuesday-fried chicken-chocolate pudding-4th\r\nFoster-Thursday-chili-ice cream-4th\r\nLily-Monday-lasagna-brownies-1st\r\nDarlene-Wednesday-BBQ-peach cobbler-6th", "category": "Logic-Grid", "date": "11/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne week last summer, Richard's 5 kids went to camp. On each weekday, Richard had lunch with a different one of his children in the camp cafeteria. Except for the twins, who are both in the same grade, each of the children will begin a different grade in the fall. Each day of the week, a different main dish and different dessert was served. Can you figure out who Richard ate with on what day and what he had for lunch?\n\r\n1) Richard and his only sixth-grade child (who isn't Basil) enjoyed the BBQ beef on Wednesday. The day Richard ate lunch with Basil wasn't the day chili was served.\n\r\n2) Monday's dessert was brownies. Friday's was apple pie.\n\r\n3) Lasagna was served on the day Richard joined his daughter Lily for lunch.\n\r\n4) Thursday wasn't the day on which Richard and one of the twins had fried chicken followed by chocolate pudding.\n\r\n5) Richard ate lunch with Darlene more than one day before he ate lunch with Amber (who is about to begin second grade, but isn't a twin).\n\r\n6) Foster (who isn't the one with whom Richard had peach cobbler for dessert) is entering a higher grade than the child whom Richard ate pizza but a lower grade than at least one other child. \n\r\n7) Richard didn't eat lasagna with either of the twins, nor did he eat lunch with the twins on consecutive days.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAmber-Friday-pizza-apple pie-2nd\r\nBasil-Tuesday-fried chicken-chocolate pudding-4th\r\nFoster-Thursday-chili-ice cream-4th\r\nLily-Monday-lasagna-brownies-1st\r\nDarlene-Wednesday-BBQ-peach cobbler-6th\n<|im_start|>answer\nAmber-Friday-pizza-apple pie-2nd\r\nBasil-Tuesday-fried chicken-chocolate pudding-4th\r\nFoster-Thursday-chili-ice cream-4th\r\nLily-Monday-lasagna-brownies-1st\r\nDarlene-Wednesday-BBQ-peach cobbler-6th\n<|im_end|>" }, { "id": "#36545", "title": "SD Poker Tourney", "fun": 3.01, "difficulty": 2.6, "author": "goatroper605", "desc": "Mr. Slickdeals is back ... He's decided to go into the poker tournament business to supplement his sweepstakes sponsoring income.\r\nHe's finding that this group of people are a little more demanding than any of his sweepstakes participants. So, he's had the players submit their food & drink orders prior to the beginning of the tourney. Being a shrewd (somewhat skewed) businessman, he's decided to charge the players at the final table for whatever they ate or drank. What a cheapskate!\r\nSo, Monday morning rolls around, the tourney's over and Mr. Slickdeals begins the process of sending out prizes & food/drink bills when he realizes that, yet again, his computer has crashed (Mr. Slickdeals needs a new computer!). From the notes he's taken, can you determine how much money each player started and ended with & what they had to eat and drink?\n\r\n1. The beer-drinking Rambunctious didn't have a bologna sandwich. The person who had pastrami exactly doubled their money. Big John started with $250.\n\r\n2. Vec is not the person who started with $350 and ended with $450. The lemonade drinker, not Iconian, didn't have a turkey sandwich.\n\r\n3. Mavtech started with more money than the ham sandwich eater but he ended with $100 less than the tequila drinker.\n\r\n4. The person eating a turkey sandwich ended the day with more money than the iced tea drinker but less than the person who had roast beef.\n\r\n5. Vec didn't drink tequila. The vodka drinker didn't start with $400 but he ended with $150 more than he started with. The person who had a ham sandwich had $300 to start with, but it wasn't Vec.\n\r\n6. The five players were Mavtech, the man who started with $500, the person who had a turkey sandwich, the man who ended with $600 and the iced tea drinker.", "hint": "No hint available.", "answer": "Rambunctious, beer, ham, $300, $600.\r\nIconian, tequila, turkey, $400, $550.\r\nMavtech, lemonade, bologna, $350, $450.\r\nVec, vodka, roast beef, $500, $650.\r\nBig John, iced tea, pastrami, $250, $500.", "category": "Logic-Grid", "date": "05/07/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Slickdeals is back ... He's decided to go into the poker tournament business to supplement his sweepstakes sponsoring income.\r\nHe's finding that this group of people are a little more demanding than any of his sweepstakes participants. So, he's had the players submit their food & drink orders prior to the beginning of the tourney. Being a shrewd (somewhat skewed) businessman, he's decided to charge the players at the final table for whatever they ate or drank. What a cheapskate!\r\nSo, Monday morning rolls around, the tourney's over and Mr. Slickdeals begins the process of sending out prizes & food/drink bills when he realizes that, yet again, his computer has crashed (Mr. Slickdeals needs a new computer!). From the notes he's taken, can you determine how much money each player started and ended with & what they had to eat and drink?\n\r\n1. The beer-drinking Rambunctious didn't have a bologna sandwich. The person who had pastrami exactly doubled their money. Big John started with $250.\n\r\n2. Vec is not the person who started with $350 and ended with $450. The lemonade drinker, not Iconian, didn't have a turkey sandwich.\n\r\n3. Mavtech started with more money than the ham sandwich eater but he ended with $100 less than the tequila drinker.\n\r\n4. The person eating a turkey sandwich ended the day with more money than the iced tea drinker but less than the person who had roast beef.\n\r\n5. Vec didn't drink tequila. The vodka drinker didn't start with $400 but he ended with $150 more than he started with. The person who had a ham sandwich had $300 to start with, but it wasn't Vec.\n\r\n6. The five players were Mavtech, the man who started with $500, the person who had a turkey sandwich, the man who ended with $600 and the iced tea drinker.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRambunctious, beer, ham, $300, $600.\r\nIconian, tequila, turkey, $400, $550.\r\nMavtech, lemonade, bologna, $350, $450.\r\nVec, vodka, roast beef, $500, $650.\r\nBig John, iced tea, pastrami, $250, $500.\n<|im_start|>answer\nRambunctious, beer, ham, $300, $600.\r\nIconian, tequila, turkey, $400, $550.\r\nMavtech, lemonade, bologna, $350, $450.\r\nVec, vodka, roast beef, $500, $650.\r\nBig John, iced tea, pastrami, $250, $500.\n<|im_end|>" }, { "id": "#26486", "title": "Trick or Treat 2", "fun": 3.01, "difficulty": 2.14, "author": "kaytec", "desc": "Five neighborhood children went trick or treating together. Each wore different costumes, carried a different bag for candy and had a different favorite candy. From the clues can you figure out who wore which costume, the type of bag he/she carried and his/her favorite candy?\n\r\nThe Children:\r\n Three girls: Abby, Leah & Xarina\r\n Two boys: Logan & Tyler\n\r\nCostumes:\r\n Hobo\r\n Kitten\r\n Pirate\r\n Princess\r\n Punk Rocker\n\r\nCandy Bags:\r\n Black Plastic Trash Bag (Black)\r\n Blue Pillowcase (Blue)\r\n Decorated Grocery Sack (Grocery)\r\n Plastic Pumpkin (Pumpkin)\r\n Yellow Pillowcase (Yellow)\n\r\nFavorite Candy:\r\n Bubblegum (Bubble)\r\n Chocolate (Choc)\r\n Lemon-drops (Lemon)\r\n Peanut Butter Pieces (PB)\r\n Taffy\n\r\n1. Of the punk rocker & the hobo: One of the girls had decorated a grocery sack and the other absolutely loves chocolate.\n\r\n2. Neither of the boys carried the plastic pumpkin or the blue pillowcase.\n\r\n3. The five children were: the boy with the black plastic bag, the one who loves lemondrops, Xarina, the chocolate lover, and the girl dressed as a kitten (who loves peanut butter).\n\r\n4. The pirate (whose favorite candy is not bubblegum or taffy) carried the yellow pillowcase.\n\r\n5. The pirate's sister, Abby, was going to carry a blue one, but changed her mind at the last minute.\n\r\n6. Tyler doesn't chew bubblegum so he gave his to the girl with the grocery bag (it's her favorite).\n\r\n7. Again (not necessarily in the same order), the children are: the girl with the plastic pumpkin, the Hobo, the princess, Logan and the one who loves bubblegum.", "hint": "There are only two boys.\r\nDon't make assumptions about boy/girl costumes.", "answer": "Abby, Kitten, Peanut Butter Pieces, Plastic Pumpkin\r\nLeah, Hobo, Chocolate, Blue Pillowcase\r\nLogan, Pirate, Lemon-drops, Yellow Pillowcase\r\nTyler, Princess, Taffy, Black Plastic Trash Bag\r\nXarina, Punk Rocker, Bubblegum, Decorated Grocery Sack", "category": "Logic-Grid", "date": "10/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive neighborhood children went trick or treating together. Each wore different costumes, carried a different bag for candy and had a different favorite candy. From the clues can you figure out who wore which costume, the type of bag he/she carried and his/her favorite candy?\n\r\nThe Children:\r\n Three girls: Abby, Leah & Xarina\r\n Two boys: Logan & Tyler\n\r\nCostumes:\r\n Hobo\r\n Kitten\r\n Pirate\r\n Princess\r\n Punk Rocker\n\r\nCandy Bags:\r\n Black Plastic Trash Bag (Black)\r\n Blue Pillowcase (Blue)\r\n Decorated Grocery Sack (Grocery)\r\n Plastic Pumpkin (Pumpkin)\r\n Yellow Pillowcase (Yellow)\n\r\nFavorite Candy:\r\n Bubblegum (Bubble)\r\n Chocolate (Choc)\r\n Lemon-drops (Lemon)\r\n Peanut Butter Pieces (PB)\r\n Taffy\n\r\n1. Of the punk rocker & the hobo: One of the girls had decorated a grocery sack and the other absolutely loves chocolate.\n\r\n2. Neither of the boys carried the plastic pumpkin or the blue pillowcase.\n\r\n3. The five children were: the boy with the black plastic bag, the one who loves lemondrops, Xarina, the chocolate lover, and the girl dressed as a kitten (who loves peanut butter).\n\r\n4. The pirate (whose favorite candy is not bubblegum or taffy) carried the yellow pillowcase.\n\r\n5. The pirate's sister, Abby, was going to carry a blue one, but changed her mind at the last minute.\n\r\n6. Tyler doesn't chew bubblegum so he gave his to the girl with the grocery bag (it's her favorite).\n\r\n7. Again (not necessarily in the same order), the children are: the girl with the plastic pumpkin, the Hobo, the princess, Logan and the one who loves bubblegum.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbby, Kitten, Peanut Butter Pieces, Plastic Pumpkin\r\nLeah, Hobo, Chocolate, Blue Pillowcase\r\nLogan, Pirate, Lemon-drops, Yellow Pillowcase\r\nTyler, Princess, Taffy, Black Plastic Trash Bag\r\nXarina, Punk Rocker, Bubblegum, Decorated Grocery Sack\n<|im_start|>answer\nAbby, Kitten, Peanut Butter Pieces, Plastic Pumpkin\r\nLeah, Hobo, Chocolate, Blue Pillowcase\r\nLogan, Pirate, Lemon-drops, Yellow Pillowcase\r\nTyler, Princess, Taffy, Black Plastic Trash Bag\r\nXarina, Punk Rocker, Bubblegum, Decorated Grocery Sack\n<|im_end|>" }, { "id": "#21105", "title": "The Race - Part I", "fun": 3.01, "difficulty": 3.13, "author": "Sane", "desc": "Five competitors (two women named Alexa and Breanna, and three men named Larry, Arnold and Michael) recently decided they would race each other for a large prize. Before the race would start, each person decided to do a different aerobics class to try and become more fit and healthy. Each had already raced for a number of months in competitions (3, 6, 9, 12, 15). Their surnames are Anderson, Cameron, Douglas, Ewell and Farlin. After two months of aerobics each person noticed a different benefit from their exercise. From the clues below, can you match the full name of each competitor with the number of months they've raced before, the benefit each has experienced from aerobics, and the brand of sneakers each wears?\n\r\n1. Arnold, who isn't surnamed Anderson, doesn't use Nike shoes.\n\r\n2. Arnold has been racing for fewer months than the woman who noticed an increase in her energy level; she has been racing for fewer months than the friend who wears Brooks shoes.\n\r\n3. The person who has been racing for the least amount of time is neither the man who uses Adidas shoes, nor another person surnamed Douglas.\n\r\n4. The man who uses Reebok shoes has been racing longer than the person surnamed Ewell, who has been racing longer than the person who lowered his/her cholesterol level.\n\r\n5. The person who has experienced weight loss began racing after the one who gained muscle tone and before Alexa (who doesn't use Nike).\n\r\n6. Larry lowered his cholesterol level.\n\r\n7. The one surnamed Anderson hasn't noticed any weight loss.\n\r\n8. Ms. Ewell isn't the woman who gained muscle tone.\n\r\n9. Ms. Cameron enjoys aerobics so much that she goes to the gym at least 5 times a week.", "hint": "No hint available.", "answer": "Larry lowered his cholesterol level (6).\r\nThe woman who has more muscle tone (8) isn't Alexa (5), so she's Breanna. The woman who noticed an increase in her energy level (2), then is Alexa.\r\nMs. Ewell isn't Breanna (8), so she's Alexa, and Ms. Cameron (9) is Breanna.\r\nArnold has been racing for fewer months than Alexa (2), so he hasn't experienced weight loss (5); he has more endurance, and Michael, by elimination, lost weight.\r\nAlexa doesn't use Brook shoes (2), Adidas (3), Reebok (4), or Nike (5), so she wears Hushpuppy.\r\nThe person who has been racing for the shortest time doesn't wear Hushpuppy, Brooks (4), so he or she wears Nike.\r\nThe one who wears Nike sneakers, then, isn't Arnold (1), Michael, or Breanna (5), so he's Larry.\r\nBreanna's shoes aren't made by Adidas (3), or Reebok (4), so they are Brooks.\r\nArnold has been racing for fewer months than Alexa (2), so he doesn't wear Reebok (4); Michael does, and Arnold, by elimination, wears Adidas.\r\nThe one surnamed Anderson isn't Arnold (1) or Michael (7), so he's Larry. \r\nArnold's surname isn't Douglas (3), so it's Farlin, and by elimination, Michael's is Douglas.\r\nThe one who has been racing for 15 months isn't Arnold, Alexa (2), or Michael (5), so she's Breanna.\r\nAlexa hasn't been racing for 6 months (2) or 12 months (5), so for 9 months.\r\nArnold, then, has been racing for 6 months (2). By elimination, Michael has been racing for 12 months.\n\r\nIn summary:\n\r\nAlexa Ewell, 9 months, more energy, Hushpuppy\r\nBreanna Cameron, 15 months, muscle tone, Brooks\r\nLarry Anderson, 3 months, lowered cholesterol, Nike\r\nArnold Farlin, 6 months, more endurance, Adidas\r\nMichael Douglas, 12 months, weight loss, Reebok", "category": "Logic-Grid", "date": "02/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive competitors (two women named Alexa and Breanna, and three men named Larry, Arnold and Michael) recently decided they would race each other for a large prize. Before the race would start, each person decided to do a different aerobics class to try and become more fit and healthy. Each had already raced for a number of months in competitions (3, 6, 9, 12, 15). Their surnames are Anderson, Cameron, Douglas, Ewell and Farlin. After two months of aerobics each person noticed a different benefit from their exercise. From the clues below, can you match the full name of each competitor with the number of months they've raced before, the benefit each has experienced from aerobics, and the brand of sneakers each wears?\n\r\n1. Arnold, who isn't surnamed Anderson, doesn't use Nike shoes.\n\r\n2. Arnold has been racing for fewer months than the woman who noticed an increase in her energy level; she has been racing for fewer months than the friend who wears Brooks shoes.\n\r\n3. The person who has been racing for the least amount of time is neither the man who uses Adidas shoes, nor another person surnamed Douglas.\n\r\n4. The man who uses Reebok shoes has been racing longer than the person surnamed Ewell, who has been racing longer than the person who lowered his/her cholesterol level.\n\r\n5. The person who has experienced weight loss began racing after the one who gained muscle tone and before Alexa (who doesn't use Nike).\n\r\n6. Larry lowered his cholesterol level.\n\r\n7. The one surnamed Anderson hasn't noticed any weight loss.\n\r\n8. Ms. Ewell isn't the woman who gained muscle tone.\n\r\n9. Ms. Cameron enjoys aerobics so much that she goes to the gym at least 5 times a week.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLarry lowered his cholesterol level (6).\r\nThe woman who has more muscle tone (8) isn't Alexa (5), so she's Breanna. The woman who noticed an increase in her energy level (2), then is Alexa.\r\nMs. Ewell isn't Breanna (8), so she's Alexa, and Ms. Cameron (9) is Breanna.\r\nArnold has been racing for fewer months than Alexa (2), so he hasn't experienced weight loss (5); he has more endurance, and Michael, by elimination, lost weight.\r\nAlexa doesn't use Brook shoes (2), Adidas (3), Reebok (4), or Nike (5), so she wears Hushpuppy.\r\nThe person who has been racing for the shortest time doesn't wear Hushpuppy, Brooks (4), so he or she wears Nike.\r\nThe one who wears Nike sneakers, then, isn't Arnold (1), Michael, or Breanna (5), so he's Larry.\r\nBreanna's shoes aren't made by Adidas (3), or Reebok (4), so they are Brooks.\r\nArnold has been racing for fewer months than Alexa (2), so he doesn't wear Reebok (4); Michael does, and Arnold, by elimination, wears Adidas.\r\nThe one surnamed Anderson isn't Arnold (1) or Michael (7), so he's Larry. \r\nArnold's surname isn't Douglas (3), so it's Farlin, and by elimination, Michael's is Douglas.\r\nThe one who has been racing for 15 months isn't Arnold, Alexa (2), or Michael (5), so she's Breanna.\r\nAlexa hasn't been racing for 6 months (2) or 12 months (5), so for 9 months.\r\nArnold, then, has been racing for 6 months (2). By elimination, Michael has been racing for 12 months.\n\r\nIn summary:\n\r\nAlexa Ewell, 9 months, more energy, Hushpuppy\r\nBreanna Cameron, 15 months, muscle tone, Brooks\r\nLarry Anderson, 3 months, lowered cholesterol, Nike\r\nArnold Farlin, 6 months, more endurance, Adidas\r\nMichael Douglas, 12 months, weight loss, Reebok\n<|im_start|>answer\nLarry lowered his cholesterol level (6).\r\nThe woman who has more muscle tone (8) isn't Alexa (5), so she's Breanna. The woman who noticed an increase in her energy level (2), then is Alexa.\r\nMs. Ewell isn't Breanna (8), so she's Alexa, and Ms. Cameron (9) is Breanna.\r\nArnold has been racing for fewer months than Alexa (2), so he hasn't experienced weight loss (5); he has more endurance, and Michael, by elimination, lost weight.\r\nAlexa doesn't use Brook shoes (2), Adidas (3), Reebok (4), or Nike (5), so she wears Hushpuppy.\r\nThe person who has been racing for the shortest time doesn't wear Hushpuppy, Brooks (4), so he or she wears Nike.\r\nThe one who wears Nike sneakers, then, isn't Arnold (1), Michael, or Breanna (5), so he's Larry.\r\nBreanna's shoes aren't made by Adidas (3), or Reebok (4), so they are Brooks.\r\nArnold has been racing for fewer months than Alexa (2), so he doesn't wear Reebok (4); Michael does, and Arnold, by elimination, wears Adidas.\r\nThe one surnamed Anderson isn't Arnold (1) or Michael (7), so he's Larry. \r\nArnold's surname isn't Douglas (3), so it's Farlin, and by elimination, Michael's is Douglas.\r\nThe one who has been racing for 15 months isn't Arnold, Alexa (2), or Michael (5), so she's Breanna.\r\nAlexa hasn't been racing for 6 months (2) or 12 months (5), so for 9 months.\r\nArnold, then, has been racing for 6 months (2). By elimination, Michael has been racing for 12 months.\n\r\nIn summary:\n\r\nAlexa Ewell, 9 months, more energy, Hushpuppy\r\nBreanna Cameron, 15 months, muscle tone, Brooks\r\nLarry Anderson, 3 months, lowered cholesterol, Nike\r\nArnold Farlin, 6 months, more endurance, Adidas\r\nMichael Douglas, 12 months, weight loss, Reebok\n<|im_end|>" }, { "id": "#45713", "title": "Geocaching in the Mountains", "fun": 3.01, "difficulty": 2.03, "author": "whsprec", "desc": "Geocaching is the sport of using GPS systems to locate hidden boxes at different geographical locations across the country. Directions and clues are left in the boxes to aid in the journey. Max's first geocaching expedition took him to the top of five different mountains. He had to hike to the top of each one. On the way he encountered some obstacle. From the clues below, determine the order of the mountains, the height of the mountain, and the obstacle he had to overcome to reach the box.\n\r\n1 - Neither the first mountain nor the one where Max had trouble with thunderstorm include the word mountain in their name, and neither is as high as Death Grip Mountain.\r\n2 - The third mountain is the lowest of the five.\r\n3 - The mountain which had the wolf pack is higher than Broken Rope Pike.\r\n4 - Max climbed Death Grip Mountain immediately before tackling Widow Peak.\r\n5 - Max encountered a rockslide on the ascent of Free-Fall Peak, and a broken GPS on the highest mountain.\r\n6 - The fourth mountain is covered in 5 ft of snow, and was climbed later than the 6,951 foot Insanity Mountain.", "hint": "No hint available.", "answer": "First was Free-Fall Peak that is 7,493 feet and had a rockslide.\r\nSecond was Insanity Mountain that is 6,951 feet and had a wolf pack.\r\nThird was Broken Rope Pike that is 5,671 feet and had a thunderstorm.\r\nFourth was Death Grip Mountain that is 9,981 feet and had 5 ft of snow.\r\nFifth was Widow Peak that is 14,886 ft and had a broken GPS.", "category": "Logic-Grid", "date": "11/13/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGeocaching is the sport of using GPS systems to locate hidden boxes at different geographical locations across the country. Directions and clues are left in the boxes to aid in the journey. Max's first geocaching expedition took him to the top of five different mountains. He had to hike to the top of each one. On the way he encountered some obstacle. From the clues below, determine the order of the mountains, the height of the mountain, and the obstacle he had to overcome to reach the box.\n\r\n1 - Neither the first mountain nor the one where Max had trouble with thunderstorm include the word mountain in their name, and neither is as high as Death Grip Mountain.\r\n2 - The third mountain is the lowest of the five.\r\n3 - The mountain which had the wolf pack is higher than Broken Rope Pike.\r\n4 - Max climbed Death Grip Mountain immediately before tackling Widow Peak.\r\n5 - Max encountered a rockslide on the ascent of Free-Fall Peak, and a broken GPS on the highest mountain.\r\n6 - The fourth mountain is covered in 5 ft of snow, and was climbed later than the 6,951 foot Insanity Mountain.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst was Free-Fall Peak that is 7,493 feet and had a rockslide.\r\nSecond was Insanity Mountain that is 6,951 feet and had a wolf pack.\r\nThird was Broken Rope Pike that is 5,671 feet and had a thunderstorm.\r\nFourth was Death Grip Mountain that is 9,981 feet and had 5 ft of snow.\r\nFifth was Widow Peak that is 14,886 ft and had a broken GPS.\n<|im_start|>answer\nFirst was Free-Fall Peak that is 7,493 feet and had a rockslide.\r\nSecond was Insanity Mountain that is 6,951 feet and had a wolf pack.\r\nThird was Broken Rope Pike that is 5,671 feet and had a thunderstorm.\r\nFourth was Death Grip Mountain that is 9,981 feet and had 5 ft of snow.\r\nFifth was Widow Peak that is 14,886 ft and had a broken GPS.\n<|im_end|>" }, { "id": "#45947", "title": "Published Poetry", "fun": 3.01, "difficulty": 1.73, "author": "dswilborn", "desc": "Diana has been writing poetry for many years and is excited that her first published book of poems will be coming out next year. Her publisher has asked her to write introductions for her poems. From the information given below, can you determine the year each poem was written (1996, 1999, 2001, 2004, or 2009), the occasion or person it was written for, and the style of poetry used (haiku, ode, sonnet, elegy, or free verse)?\n\r\n1. \"The Tree\" was either the earliest poem written or the most recent. The wedding poem was either an ode or a free verse poem. \"Dancer\" is a haiku but was not written for the contest that took place in the 1990s.\n\r\n2. \"Summer Harvest\" was written for a family member. \"Queen Anne\" was inspired by a television show about British royalty and was not written in free verse.\n\r\n3. The five poems, in no particular order, are: \"Confidential\", the free verse poem written in 1996, the sonnet, the poem written for her sister, and the poem written for her mother.\n\r\n4. The poem written for a friend's wedding was written before the sonnet but three years after the haiku.\n\r\n5. The poem written in 1999 was written for her mother's funeral. The ode was not written for her sister nor was it inspired by the television show.", "hint": "An elegy is a poem written about someone who has died.", "answer": "\"The Tree\" was written in 1996 for a contest and is a free verse poem.\r\n\"Summer Harvest\" was written in 1999 for her mother's funeral and is an elegy.\r\n\"Dancer\" was written in 2001 for her sister and is a haiku.\r\n\"Confidential\" was written in 2004 for a friend's wedding and is an ode.\r\n\"Queen Anne\" was written in 2009 after watching a television show and is a sonnet.", "category": "Logic-Grid", "date": "12/09/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDiana has been writing poetry for many years and is excited that her first published book of poems will be coming out next year. Her publisher has asked her to write introductions for her poems. From the information given below, can you determine the year each poem was written (1996, 1999, 2001, 2004, or 2009), the occasion or person it was written for, and the style of poetry used (haiku, ode, sonnet, elegy, or free verse)?\n\r\n1. \"The Tree\" was either the earliest poem written or the most recent. The wedding poem was either an ode or a free verse poem. \"Dancer\" is a haiku but was not written for the contest that took place in the 1990s.\n\r\n2. \"Summer Harvest\" was written for a family member. \"Queen Anne\" was inspired by a television show about British royalty and was not written in free verse.\n\r\n3. The five poems, in no particular order, are: \"Confidential\", the free verse poem written in 1996, the sonnet, the poem written for her sister, and the poem written for her mother.\n\r\n4. The poem written for a friend's wedding was written before the sonnet but three years after the haiku.\n\r\n5. The poem written in 1999 was written for her mother's funeral. The ode was not written for her sister nor was it inspired by the television show.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"The Tree\" was written in 1996 for a contest and is a free verse poem.\r\n\"Summer Harvest\" was written in 1999 for her mother's funeral and is an elegy.\r\n\"Dancer\" was written in 2001 for her sister and is a haiku.\r\n\"Confidential\" was written in 2004 for a friend's wedding and is an ode.\r\n\"Queen Anne\" was written in 2009 after watching a television show and is a sonnet.\n<|im_start|>answer\n\"The Tree\" was written in 1996 for a contest and is a free verse poem.\r\n\"Summer Harvest\" was written in 1999 for her mother's funeral and is an elegy.\r\n\"Dancer\" was written in 2001 for her sister and is a haiku.\r\n\"Confidential\" was written in 2004 for a friend's wedding and is an ode.\r\n\"Queen Anne\" was written in 2009 after watching a television show and is a sonnet.\n<|im_end|>" }, { "id": "#46181", "title": "Bidding on Star Wars", "fun": 3.01, "difficulty": 1.85, "author": "whsprec", "desc": "Five people were involved in an on-line auction for a photo of the original \"Star Wars\" crew. The bidding started at $200 and climbed. Each person was multitasking and doing something off-line while watching the bid (one of them was watching TV). From the clues below, determine the name of the person, their screen name, how much they bid, and what they were doing in the real world at the time.\n\r\n1) The initial bid of $200 was made by the person who was reading at the same time, not by the bidder whose screen name was Ewok Master.\r\n2) Neil raised it to $225, but he was not eating lunch; the bid by the person doing that was lower than Matt.\r\n3) Blaklee didn't take the bid to $250. \r\n4) The person whose screen name is R2D3 clicked at $275.\r\n5) Jessica was vacuuming while registering her bid, but it was lower than that of the person whose screen name was Jedi13.\r\n6) The bidder going by Force Knight was washing the car at the same time as the auction.\r\n7) George's screen name is Lord Jabba.", "hint": "No hint available.", "answer": "Blaklee, known as R2D3, bid $275, while eating lunch.\r\nMatt, known as Jedi13, bid $300, while watching TV.\r\nNeil, known as Force Knight, bid $225, while washing the car.\r\nJessica, known as Ewok Master, bid $250, while vacuuming.\r\nGeorge, known as Lord Jabba, bid $200, while reading.", "category": "Logic-Grid", "date": "01/12/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people were involved in an on-line auction for a photo of the original \"Star Wars\" crew. The bidding started at $200 and climbed. Each person was multitasking and doing something off-line while watching the bid (one of them was watching TV). From the clues below, determine the name of the person, their screen name, how much they bid, and what they were doing in the real world at the time.\n\r\n1) The initial bid of $200 was made by the person who was reading at the same time, not by the bidder whose screen name was Ewok Master.\r\n2) Neil raised it to $225, but he was not eating lunch; the bid by the person doing that was lower than Matt.\r\n3) Blaklee didn't take the bid to $250. \r\n4) The person whose screen name is R2D3 clicked at $275.\r\n5) Jessica was vacuuming while registering her bid, but it was lower than that of the person whose screen name was Jedi13.\r\n6) The bidder going by Force Knight was washing the car at the same time as the auction.\r\n7) George's screen name is Lord Jabba.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlaklee, known as R2D3, bid $275, while eating lunch.\r\nMatt, known as Jedi13, bid $300, while watching TV.\r\nNeil, known as Force Knight, bid $225, while washing the car.\r\nJessica, known as Ewok Master, bid $250, while vacuuming.\r\nGeorge, known as Lord Jabba, bid $200, while reading.\n<|im_start|>answer\nBlaklee, known as R2D3, bid $275, while eating lunch.\r\nMatt, known as Jedi13, bid $300, while watching TV.\r\nNeil, known as Force Knight, bid $225, while washing the car.\r\nJessica, known as Ewok Master, bid $250, while vacuuming.\r\nGeorge, known as Lord Jabba, bid $200, while reading.\n<|im_end|>" }, { "id": "#20572", "title": "Trapdoors", "fun": 3.01, "difficulty": 1.17, "author": "Therulerofthem", "desc": "There are five doors, one leads to the exit, the others lead to traps. They are in a line. The clues tell you which position the doors are in the line and where the door to freedom is. All the clues are true. Each door has a clue written on it. The clues read:\n\r\nThe blue door: This door is two spots away from the door to freedom.\r\nThe red door: This door is at the far right, and is two spots away from the blue door.\r\nThe purple door: This door is not next to the door to freedom.\r\nThe green door: This door is left of the blue door.\r\nThe orange door: This door is not next to the red or blue doors.\n\r\nWhich door leads to freedom?", "hint": "No hint available.", "answer": "The orange door leads to freedom.", "category": "Logic", "date": "01/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five doors, one leads to the exit, the others lead to traps. They are in a line. The clues tell you which position the doors are in the line and where the door to freedom is. All the clues are true. Each door has a clue written on it. The clues read:\n\r\nThe blue door: This door is two spots away from the door to freedom.\r\nThe red door: This door is at the far right, and is two spots away from the blue door.\r\nThe purple door: This door is not next to the door to freedom.\r\nThe green door: This door is left of the blue door.\r\nThe orange door: This door is not next to the red or blue doors.\n\r\nWhich door leads to freedom?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe orange door leads to freedom.\n<|im_start|>answer\nThe orange door leads to freedom.\n<|im_end|>" }, { "id": "#25352", "title": "Fashion Fixer-Upper", "fun": 3.01, "difficulty": 1.47, "author": "mejoza", "desc": "Muffi, Maddie, Trixie, and Libby live for fashion. Together, they've sought the advice of the trendiest fashion guru. To their surprise, they found that they had been wearing the wrong type of clothing for years! The consultation consisted of measuring, color charting, body shape identification, and pattern choices for each woman. After the consultation each woman was given her correct dress size and the best pattern and color for her body shape. No woman was the same size or shape as another, nor did any share color or pattern choices. Can you determine the best look for each shopper? Dress sizes were 6, 8, 10, and 12. Body shapes were hourglass, pear, apple, and stick figure. Patterns were dots, solids, plaid, and stripes. Colors were pink, red, blue, and black.\n\r\nClues:\n\r\n1. The fashionista with the pear shaped body was the one who could wear plaid.\n\r\n2. Neither the girl who looked good in blue nor the one who shone in pink wore the largest size.\n\r\n3. Trixie is a size 10.\n\r\n4. Stripes looked good on the largest woman.\n\r\n5. Libby was smaller than Trixie, but larger than Maddie.\n\r\n6. The woman who looked good in pink polka dots had a stick figure.\n\r\n7. Neither the apple nor the hourglass looked good in blue.\n\r\n8. Trixie could not wear plaid or dots and Muffi was told to always wear red.\n\r\n9. Solid black looked great on the apple shaped woman. \n\r\n10. The stick figure is not the smallest woman, but she is smaller than the woman who now wears black.", "hint": "No hint available.", "answer": "Muffi, 12, red, hourglass, stripes\r\nMaddie, 6, blue, pear, plaid\r\nTrixie, 10, black, apple, solids\r\nLibby, 8, pink, stick, dots", "category": "Logic-Grid", "date": "08/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMuffi, Maddie, Trixie, and Libby live for fashion. Together, they've sought the advice of the trendiest fashion guru. To their surprise, they found that they had been wearing the wrong type of clothing for years! The consultation consisted of measuring, color charting, body shape identification, and pattern choices for each woman. After the consultation each woman was given her correct dress size and the best pattern and color for her body shape. No woman was the same size or shape as another, nor did any share color or pattern choices. Can you determine the best look for each shopper? Dress sizes were 6, 8, 10, and 12. Body shapes were hourglass, pear, apple, and stick figure. Patterns were dots, solids, plaid, and stripes. Colors were pink, red, blue, and black.\n\r\nClues:\n\r\n1. The fashionista with the pear shaped body was the one who could wear plaid.\n\r\n2. Neither the girl who looked good in blue nor the one who shone in pink wore the largest size.\n\r\n3. Trixie is a size 10.\n\r\n4. Stripes looked good on the largest woman.\n\r\n5. Libby was smaller than Trixie, but larger than Maddie.\n\r\n6. The woman who looked good in pink polka dots had a stick figure.\n\r\n7. Neither the apple nor the hourglass looked good in blue.\n\r\n8. Trixie could not wear plaid or dots and Muffi was told to always wear red.\n\r\n9. Solid black looked great on the apple shaped woman. \n\r\n10. The stick figure is not the smallest woman, but she is smaller than the woman who now wears black.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMuffi, 12, red, hourglass, stripes\r\nMaddie, 6, blue, pear, plaid\r\nTrixie, 10, black, apple, solids\r\nLibby, 8, pink, stick, dots\n<|im_start|>answer\nMuffi, 12, red, hourglass, stripes\r\nMaddie, 6, blue, pear, plaid\r\nTrixie, 10, black, apple, solids\r\nLibby, 8, pink, stick, dots\n<|im_end|>" }, { "id": "#26413", "title": "Ring Around the Rosie", "fun": 3.0, "difficulty": 2.82, "author": "tjm531", "desc": "For her 60th birthday, Rosie's five children were planning a grand surprise party in her honor. This was not easy for any of her children since each of them lived in a different city in northern California, so to make it easier for themselves, they each had a different responsibility. Each person was put in charge of a different aspect of the party planning, including arranging for the gift the group had selected -- a mother's ring set with the birthstones of all five siblings (no two siblings have the same birthstone). From the information provided, determine the city in which each person lives and the aspect of the party (including the music) he or she was in charge of planning, as well as the birthstone of each of Rosie's children.\n\r\nPerson: Herbert, Irene, Kurt, Marie, Wendell\n\r\nCity: Crescent City, Quincy, Red Bluff, Sacramento, San Francisco\n\r\nAspect: Caterer, Gift, Hall, Invitations, Music\n\r\nBirthstone: Amethyst, Aquamarine, Emerald, Peridot, Sapphire\n\r\n1. Exactly four of Rosie's children -- the Sacramento resident, the one with the peridot birthstone, the one in charge of hiring a caterer, and the one whose birthstone is emerald -- are married.\n\r\n2. Three siblings who brought their spouses to the party are the resident of Quincy, the one who lives in Red Bluff, and Irene. \n\r\n3. Marie's birthstone isn't the sapphire.\n\r\n4. Neither the Sacramento resident (whose birthstone isn't sapphire) nor Kurt (who was in charge of the gift) is the one whose birthstone is aquamarine (who is neither the resident of Crescent City nor the person who had the invitations printed).\n\r\n5. The San Francisco resident (who isn't Wendell) isn't the sibling who reserved a hall for the party.\n\r\n6. Neither Marie (who lives in Crescent City, and was not in charge of the invitations) nor the Quincy resident (whose birthstone isn't aquamarine) is the one with the peridot birthstone.", "hint": "No hint available.", "answer": "Herbert lives in San Francisco, was in charge of the music, and his birthstone is the aquamarine.\n\r\nIrene lives in Sacramento, was in charge of the invitations, and her birthstone is the amethyst.\n\r\nKurt lives in Red Bluff, was in charge of the gift, and his birthstone is the peridot.\n\r\nMarie lives in Crescent City, was in charge of getting the hall, and her birthstone is the emerald.\n\r\nWendell lives in Quincy, was in charge of getting the caterer, and his birthstone is the sapphire.", "category": "Logic-Grid", "date": "10/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor her 60th birthday, Rosie's five children were planning a grand surprise party in her honor. This was not easy for any of her children since each of them lived in a different city in northern California, so to make it easier for themselves, they each had a different responsibility. Each person was put in charge of a different aspect of the party planning, including arranging for the gift the group had selected -- a mother's ring set with the birthstones of all five siblings (no two siblings have the same birthstone). From the information provided, determine the city in which each person lives and the aspect of the party (including the music) he or she was in charge of planning, as well as the birthstone of each of Rosie's children.\n\r\nPerson: Herbert, Irene, Kurt, Marie, Wendell\n\r\nCity: Crescent City, Quincy, Red Bluff, Sacramento, San Francisco\n\r\nAspect: Caterer, Gift, Hall, Invitations, Music\n\r\nBirthstone: Amethyst, Aquamarine, Emerald, Peridot, Sapphire\n\r\n1. Exactly four of Rosie's children -- the Sacramento resident, the one with the peridot birthstone, the one in charge of hiring a caterer, and the one whose birthstone is emerald -- are married.\n\r\n2. Three siblings who brought their spouses to the party are the resident of Quincy, the one who lives in Red Bluff, and Irene. \n\r\n3. Marie's birthstone isn't the sapphire.\n\r\n4. Neither the Sacramento resident (whose birthstone isn't sapphire) nor Kurt (who was in charge of the gift) is the one whose birthstone is aquamarine (who is neither the resident of Crescent City nor the person who had the invitations printed).\n\r\n5. The San Francisco resident (who isn't Wendell) isn't the sibling who reserved a hall for the party.\n\r\n6. Neither Marie (who lives in Crescent City, and was not in charge of the invitations) nor the Quincy resident (whose birthstone isn't aquamarine) is the one with the peridot birthstone.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHerbert lives in San Francisco, was in charge of the music, and his birthstone is the aquamarine.\n\r\nIrene lives in Sacramento, was in charge of the invitations, and her birthstone is the amethyst.\n\r\nKurt lives in Red Bluff, was in charge of the gift, and his birthstone is the peridot.\n\r\nMarie lives in Crescent City, was in charge of getting the hall, and her birthstone is the emerald.\n\r\nWendell lives in Quincy, was in charge of getting the caterer, and his birthstone is the sapphire.\n<|im_start|>answer\nHerbert lives in San Francisco, was in charge of the music, and his birthstone is the aquamarine.\n\r\nIrene lives in Sacramento, was in charge of the invitations, and her birthstone is the amethyst.\n\r\nKurt lives in Red Bluff, was in charge of the gift, and his birthstone is the peridot.\n\r\nMarie lives in Crescent City, was in charge of getting the hall, and her birthstone is the emerald.\n\r\nWendell lives in Quincy, was in charge of getting the caterer, and his birthstone is the sapphire.\n<|im_end|>" }, { "id": "#28019", "title": "Talented Teens", "fun": 3.0, "difficulty": 1.94, "author": "Winner4600", "desc": "Greg, Jane, Amy, Steve, and Katie are five excellent students who attend G. Neus Sr. High. About to graduate, they have each been given a subject and school award. It is up to you, their classmate, to find out which awards each student received and which teacher taught them.\n\r\nOne final note: A valedictorian is the student at the top of the class (with the best grades.) A salutatorian is \"second place\" and the margin between the two is often very narrow.\n\n\r\n1. The five students are Jane, the artist, the class president, Greg, and the boy who has Ms. Wint as a teacher.\r\n2. With one B on his report card, Steve just barely missed being top of his class. Instead, Jane got the honor.\r\n3. The math genius has Ms. Brown as a teacher, while Amy is taught by Mrs. Colt.\r\n4. Jane and Amy, who do not speak French, often hang out with the artist during lunch.\r\n5. The school awards were the one that went to Greg, the Silver Knight award, the one awarded to the amateur scientist, Steve's award, and the award given to the student taught by Mr. Allen.\r\n6. Katie is not taught by Mr. Allen.", "hint": "No hint available.", "answer": "Greg-Math-Community service-Ms. Brown\r\nJane-History-Valedictorian-Mr. Allen\r\nAmy-Science-Class president-Mrs. Colt\r\nSteve-French-Salutatorian-Ms. Wint\r\nKatie-Art-Silver Knight-Mr. Harris", "category": "Logic-Grid", "date": "01/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGreg, Jane, Amy, Steve, and Katie are five excellent students who attend G. Neus Sr. High. About to graduate, they have each been given a subject and school award. It is up to you, their classmate, to find out which awards each student received and which teacher taught them.\n\r\nOne final note: A valedictorian is the student at the top of the class (with the best grades.) A salutatorian is \"second place\" and the margin between the two is often very narrow.\n\n\r\n1. The five students are Jane, the artist, the class president, Greg, and the boy who has Ms. Wint as a teacher.\r\n2. With one B on his report card, Steve just barely missed being top of his class. Instead, Jane got the honor.\r\n3. The math genius has Ms. Brown as a teacher, while Amy is taught by Mrs. Colt.\r\n4. Jane and Amy, who do not speak French, often hang out with the artist during lunch.\r\n5. The school awards were the one that went to Greg, the Silver Knight award, the one awarded to the amateur scientist, Steve's award, and the award given to the student taught by Mr. Allen.\r\n6. Katie is not taught by Mr. Allen.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGreg-Math-Community service-Ms. Brown\r\nJane-History-Valedictorian-Mr. Allen\r\nAmy-Science-Class president-Mrs. Colt\r\nSteve-French-Salutatorian-Ms. Wint\r\nKatie-Art-Silver Knight-Mr. Harris\n<|im_start|>answer\nGreg-Math-Community service-Ms. Brown\r\nJane-History-Valedictorian-Mr. Allen\r\nAmy-Science-Class president-Mrs. Colt\r\nSteve-French-Salutatorian-Ms. Wint\r\nKatie-Art-Silver Knight-Mr. Harris\n<|im_end|>" }, { "id": "#21519", "title": "Lunch Time Fun", "fun": 3.0, "difficulty": 2.78, "author": "super_duper08", "desc": "5 girls, Dani, Katie, Janet, Christine, and Sarah ALWAYS sit by each other. Each person gets there at a different time, buys different food, pays different amounts, and does different things during lunch. Can you put them together?\n\r\n1. Katie has gym before lunch, so she gets done eating by the time the other people go to the table. \n\r\n2. Christine is kinda shy, but she likes to listen to the person who gets there last gossip, while the person who only spent a dollar helps the other girls with their problems.\n\r\n3. Two people who get there at almost the same time, get almost the same thing, but the girl who gets there first has the more expensive meal.\n\r\n4. The people who eat the hot dogs found the line just for hot dogs that is faster than the other line, so they get their lunches faster than everyone else except the girl who tells jokes at lunch.\n\r\n5. Sarah, who brings her lunch from home, buys just fries, whose price has been raised so now they cost more than bagels but less than the meal of the day.\n\r\n6. Soda costs more than water\n\r\n7. Dani always complains about her lunch that she didn't get a fresh one or it wasn't round enough and then steals a drink of water from someone else.\n\r\n8. Christine gives Janet her quarters that she got back as change, because Christine doesn't like to carry around change which Janet finds useful when it comes to buying her hot dog.\n\r\n9. One day Sarah was helping Janet with her algebra homework when she accidentally knocked over Janet's soda by mistake. Thankfully only the 2 quarters, that Christine had given Janet, got wet.\n\r\n10. Katie's lunch costs more than the girl who sits down last but less than the girl who does her homework. \n\n\n\r\nGirls// Katie, Dani, Janet, Christine, Sarah\r\nLunch// Bagel, Meal of the Day, Hot dog and soda, Hot dog and water, Sandwich and fries\r\nCost//$0.75, $1.00, $1.25, $1.50, $1.75\r\nDo during lunch// Homework, Counsel, Gossip, Eats lunch, Jokes\r\nOrder they sit down// 1,2,3,4,5", "hint": "Try your hardest and reread the clues.", "answer": "Katie - Meal of the Day, $1.25, Jokes, #1\r\nDani - Bagel $0.75, Gossips, #5\r\nJanet - Hot dog and Soda, $1.75, Homework, #2\r\nChristine - Hot dog and water, $1.50, Eats, #3\r\nSarah - Sandwich and fries, $1.00, Counsels, #4", "category": "Logic-Grid", "date": "03/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 girls, Dani, Katie, Janet, Christine, and Sarah ALWAYS sit by each other. Each person gets there at a different time, buys different food, pays different amounts, and does different things during lunch. Can you put them together?\n\r\n1. Katie has gym before lunch, so she gets done eating by the time the other people go to the table. \n\r\n2. Christine is kinda shy, but she likes to listen to the person who gets there last gossip, while the person who only spent a dollar helps the other girls with their problems.\n\r\n3. Two people who get there at almost the same time, get almost the same thing, but the girl who gets there first has the more expensive meal.\n\r\n4. The people who eat the hot dogs found the line just for hot dogs that is faster than the other line, so they get their lunches faster than everyone else except the girl who tells jokes at lunch.\n\r\n5. Sarah, who brings her lunch from home, buys just fries, whose price has been raised so now they cost more than bagels but less than the meal of the day.\n\r\n6. Soda costs more than water\n\r\n7. Dani always complains about her lunch that she didn't get a fresh one or it wasn't round enough and then steals a drink of water from someone else.\n\r\n8. Christine gives Janet her quarters that she got back as change, because Christine doesn't like to carry around change which Janet finds useful when it comes to buying her hot dog.\n\r\n9. One day Sarah was helping Janet with her algebra homework when she accidentally knocked over Janet's soda by mistake. Thankfully only the 2 quarters, that Christine had given Janet, got wet.\n\r\n10. Katie's lunch costs more than the girl who sits down last but less than the girl who does her homework. \n\n\n\r\nGirls// Katie, Dani, Janet, Christine, Sarah\r\nLunch// Bagel, Meal of the Day, Hot dog and soda, Hot dog and water, Sandwich and fries\r\nCost//$0.75, $1.00, $1.25, $1.50, $1.75\r\nDo during lunch// Homework, Counsel, Gossip, Eats lunch, Jokes\r\nOrder they sit down// 1,2,3,4,5\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKatie - Meal of the Day, $1.25, Jokes, #1\r\nDani - Bagel $0.75, Gossips, #5\r\nJanet - Hot dog and Soda, $1.75, Homework, #2\r\nChristine - Hot dog and water, $1.50, Eats, #3\r\nSarah - Sandwich and fries, $1.00, Counsels, #4\n<|im_start|>answer\nKatie - Meal of the Day, $1.25, Jokes, #1\r\nDani - Bagel $0.75, Gossips, #5\r\nJanet - Hot dog and Soda, $1.75, Homework, #2\r\nChristine - Hot dog and water, $1.50, Eats, #3\r\nSarah - Sandwich and fries, $1.00, Counsels, #4\n<|im_end|>" }, { "id": "#9518", "title": "Spirit Search", "fun": 3.0, "difficulty": 1.52, "author": "IronMaiden980", "desc": "You are an expert on paranormal activity and have been hired to locate a spirit haunting an old resort hotel. Strong signs indicate that the spirit lies behind one of four doors. The inscriptions on each door read as follows:\n\r\nDoor A: It's behind B or C\r\nDoor B: It's behind A or D\r\nDoor C: It's in here\r\nDoor D: It's not in here\n\r\nYour psychic powers have told you three of the inscriptions are false, and one is true. Behind which door will you find the spirit?", "hint": "No hint available.", "answer": "The spirit lies behind Door D.\n\r\nIf the spirit is behind Door A, then both B and D are true.\n\r\nIf the spirit is behind Door B, then both A and D are true.\n\r\nIf the spirit is behind Door C, then A, C, and D are all true.\n\r\nIf the spirit is behind Door D, then the statements on all the doors are false, except for that on Door B. This matches the rules, and therefore, the resort hotel spirit lurks behind Door D.", "category": "Logic", "date": "12/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are an expert on paranormal activity and have been hired to locate a spirit haunting an old resort hotel. Strong signs indicate that the spirit lies behind one of four doors. The inscriptions on each door read as follows:\n\r\nDoor A: It's behind B or C\r\nDoor B: It's behind A or D\r\nDoor C: It's in here\r\nDoor D: It's not in here\n\r\nYour psychic powers have told you three of the inscriptions are false, and one is true. Behind which door will you find the spirit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe spirit lies behind Door D.\n\r\nIf the spirit is behind Door A, then both B and D are true.\n\r\nIf the spirit is behind Door B, then both A and D are true.\n\r\nIf the spirit is behind Door C, then A, C, and D are all true.\n\r\nIf the spirit is behind Door D, then the statements on all the doors are false, except for that on Door B. This matches the rules, and therefore, the resort hotel spirit lurks behind Door D.\n<|im_start|>answer\nThe spirit lies behind Door D.\n\r\nIf the spirit is behind Door A, then both B and D are true.\n\r\nIf the spirit is behind Door B, then both A and D are true.\n\r\nIf the spirit is behind Door C, then A, C, and D are all true.\n\r\nIf the spirit is behind Door D, then the statements on all the doors are false, except for that on Door B. This matches the rules, and therefore, the resort hotel spirit lurks behind Door D.\n<|im_end|>" }, { "id": "#29529", "title": "Battles For the Gods", "fun": 3.0, "difficulty": 2.41, "author": "medster99", "desc": "There was once a massive evil being, so grand that it took gods from all over the world to just defeat his minions. Each minion needed to be fought with a special weapon in a special place or they would never die. Also, since gods are busy people, they could choose the date of the fight. The gods decided who would use what weapon, when, and where, based on if they could use the weapon well, if they liked the battleground or not, and if they were free that day. If they liked the battleground, then they would fight there. There were five minions, five dates, five gods, five battlegrounds, and five weapons:\n\r\n5 Gods: Thor, Zeus, Ra, Apophis and Loki\r\n5 Minions: Fiery Fiend, Metal Eye, Anti-God, Giant Worm, and the Undead Cyclops\r\n5 Weapons: Heavenly Spear, Diamond Dagger, Doomsword, Night Bow and Staff of Fury\r\n5 Battlegrounds: Easter Island, Stonehenge, Camelot, Sherwood Forest and Avalon\r\n5 Dates: March 17, December 25, February 14, January 1, and December 31\n\r\nCan you find out which god fought which minion where, when and with what weapon?\n\r\nClues:\r\n1) Loki did not fight the Fiend, but did use the Bow.\r\n2) Thor fought about 283 days before Zeus.\r\n3) The one who fought the Cyclops is the one who fought on Dec. 31.\r\n4) The one who fought the Fiend, who fought at Camelot on Jan. 1 didn't use the Dagger.\r\n5) The Spear user fought on Easter Island on March 17.\r\n6) The one who fought in Sherwood Forest fought on Dec. 31.\r\n7) Ra fought with the Sword in Avalon.\r\n8) The Fiend was fought by Apophis.\r\n9) The Giant Worm was defeated at Stonehenge.\r\n10) The Anti-God was defeated on March 17.", "hint": "Bow = Night Bow\r\nSword = Doomsword\r\nStaff = Staff of Fury\r\nDagger = Diamond Dagger\r\nSpear = Heavenly Spear", "answer": "Thor - Anti-God - Spear - March 17 - Easter Island\r\nZeus - Giant Worm - Dagger - Dec. 25 - Stonehenge\r\nApophis - Fiend - Staff - Jan. 1 - Camelot\r\nRa - Metal Eye - Sword - Feb. 14 - Avalon\r\nLoki - Cyclops - Bow - Dec. 31 - Sherwood Forest", "category": "Logic-Grid", "date": "04/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was once a massive evil being, so grand that it took gods from all over the world to just defeat his minions. Each minion needed to be fought with a special weapon in a special place or they would never die. Also, since gods are busy people, they could choose the date of the fight. The gods decided who would use what weapon, when, and where, based on if they could use the weapon well, if they liked the battleground or not, and if they were free that day. If they liked the battleground, then they would fight there. There were five minions, five dates, five gods, five battlegrounds, and five weapons:\n\r\n5 Gods: Thor, Zeus, Ra, Apophis and Loki\r\n5 Minions: Fiery Fiend, Metal Eye, Anti-God, Giant Worm, and the Undead Cyclops\r\n5 Weapons: Heavenly Spear, Diamond Dagger, Doomsword, Night Bow and Staff of Fury\r\n5 Battlegrounds: Easter Island, Stonehenge, Camelot, Sherwood Forest and Avalon\r\n5 Dates: March 17, December 25, February 14, January 1, and December 31\n\r\nCan you find out which god fought which minion where, when and with what weapon?\n\r\nClues:\r\n1) Loki did not fight the Fiend, but did use the Bow.\r\n2) Thor fought about 283 days before Zeus.\r\n3) The one who fought the Cyclops is the one who fought on Dec. 31.\r\n4) The one who fought the Fiend, who fought at Camelot on Jan. 1 didn't use the Dagger.\r\n5) The Spear user fought on Easter Island on March 17.\r\n6) The one who fought in Sherwood Forest fought on Dec. 31.\r\n7) Ra fought with the Sword in Avalon.\r\n8) The Fiend was fought by Apophis.\r\n9) The Giant Worm was defeated at Stonehenge.\r\n10) The Anti-God was defeated on March 17.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThor - Anti-God - Spear - March 17 - Easter Island\r\nZeus - Giant Worm - Dagger - Dec. 25 - Stonehenge\r\nApophis - Fiend - Staff - Jan. 1 - Camelot\r\nRa - Metal Eye - Sword - Feb. 14 - Avalon\r\nLoki - Cyclops - Bow - Dec. 31 - Sherwood Forest\n<|im_start|>answer\nThor - Anti-God - Spear - March 17 - Easter Island\r\nZeus - Giant Worm - Dagger - Dec. 25 - Stonehenge\r\nApophis - Fiend - Staff - Jan. 1 - Camelot\r\nRa - Metal Eye - Sword - Feb. 14 - Avalon\r\nLoki - Cyclops - Bow - Dec. 31 - Sherwood Forest\n<|im_end|>" }, { "id": "#25702", "title": "Articulation Conversation", "fun": 3.0, "difficulty": 2.29, "author": "mejoza", "desc": "5 children are referred for articulation therapy at PS 102. Each child has a minor sound error that was quickly remediated. Can you find the child, his/her referring teacher, age, sound error, and therapy length?\n\r\n1. Only two students worked on a sound that was in their names.\n\r\n2. The youngest child corrected his sound in the shortest amount of time.\n\r\n3. The five students were: Freddie, Mrs. Hart's 6 year old student, the 8 year old, the student working on \"f\", and the one who took 5 weeks of therapy.\n\r\n4. Mrs. Washington's student kept practicing her sound by sticking out her tongue in class.\n\r\n5. Billy is not the oldest, but he is older than the students working on \"s\" and \"sh\".\n\r\n6. Mrs. Smith asked the speech pathologist to teach her student the \"r\" sound.\n\r\n7. It took two weeks to learn the \"sh\" sound.\n\r\n8. Tommy has Mrs. Stevens.\n\r\n9. Freddie took one half the time to correct his sound as the girl in Mrs. Washington's class, but he took two times as long as the kid working on \"f\".\n\r\n10. Beth is the oldest and it took her 4 weeks to learn her sound.\n\r\n11. The \"s\" sound took two weeks less time to correct than the \"r\".", "hint": "Watch for gender in the pronouns.\n\r\n\"Th\" is made by sticking out your tongue slightly.", "answer": "Billy, age 7, R, 5 weeks, Smith\r\nSuzie, age 6, S, 3 weeks, Hart\r\nFreddie, age 5, SH, 2 weeks, Thomas\r\nTommy, age 4, F, 1 week, Stevens\r\nBeth, age 8, TH, 4 weeks, Washington", "category": "Logic-Grid", "date": "08/31/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 children are referred for articulation therapy at PS 102. Each child has a minor sound error that was quickly remediated. Can you find the child, his/her referring teacher, age, sound error, and therapy length?\n\r\n1. Only two students worked on a sound that was in their names.\n\r\n2. The youngest child corrected his sound in the shortest amount of time.\n\r\n3. The five students were: Freddie, Mrs. Hart's 6 year old student, the 8 year old, the student working on \"f\", and the one who took 5 weeks of therapy.\n\r\n4. Mrs. Washington's student kept practicing her sound by sticking out her tongue in class.\n\r\n5. Billy is not the oldest, but he is older than the students working on \"s\" and \"sh\".\n\r\n6. Mrs. Smith asked the speech pathologist to teach her student the \"r\" sound.\n\r\n7. It took two weeks to learn the \"sh\" sound.\n\r\n8. Tommy has Mrs. Stevens.\n\r\n9. Freddie took one half the time to correct his sound as the girl in Mrs. Washington's class, but he took two times as long as the kid working on \"f\".\n\r\n10. Beth is the oldest and it took her 4 weeks to learn her sound.\n\r\n11. The \"s\" sound took two weeks less time to correct than the \"r\".\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBilly, age 7, R, 5 weeks, Smith\r\nSuzie, age 6, S, 3 weeks, Hart\r\nFreddie, age 5, SH, 2 weeks, Thomas\r\nTommy, age 4, F, 1 week, Stevens\r\nBeth, age 8, TH, 4 weeks, Washington\n<|im_start|>answer\nBilly, age 7, R, 5 weeks, Smith\r\nSuzie, age 6, S, 3 weeks, Hart\r\nFreddie, age 5, SH, 2 weeks, Thomas\r\nTommy, age 4, F, 1 week, Stevens\r\nBeth, age 8, TH, 4 weeks, Washington\n<|im_end|>" }, { "id": "#30039", "title": "Blellow the Alien #1", "fun": 3.0, "difficulty": 3.02, "author": "thompson1", "desc": "Blellow the alien was driving happily along in his new spacecraft when he crashed into 4 other aliens! They were all thrown out of their spacecraft and had temporary amnesia. All 5 aliens spoke Sporzdak (the universal alien language), so they were able to communicate, but they also each spoke second languages. Each alien had been traveling a different amount of time (in bzorks) in different colored spacecrafts. Each spacecraft weighs a different amount (including the 4 qorz one that Qulp has). Help the aliens figure out who has what color spacecraft, how long each had been traveling (in bzorks), what their second language was, and how much the spacecraft weighed (in qorzes).\n\r\nAliens - Blellow (M), Smorp (M), Szurkax (M), Qulp (F), and Qorxl (F)\r\nSpacecraft color - Blue, Orange, Green, Red, and Purple\r\nWeight of spacecraft (qorzes) - 2, 4, 5, 7, and 8\r\n2nd Language - Qanxan, Sbarkjozn, Zronxhor, Jwrpl, and Boeiaix\r\nAmount of time spent traveling (bzorks) - 3, 4.5, 6, 7.5, and 9\n\r\n1. The 5 aliens are: Blellow, the one with the red spacecraft, the one that has been traveling for 4.5 bzorks, the one with a spacecraft that weighs 7 qorzes, and the one that speaks Boeiaix.\n\r\n2. Blellow's name is actually a mixture of the English words for two primary pigments. His spacecraft is the color that would result from mixing the two pigments in his name.\n\r\n3. The alien who has a spacecraft that weighs 3 qorzes more than Smorp's does has been traveling in her spacecraft for 1.5 bzorks less than Szurkax has.\n\r\n4. Blellow's spacecraft weighs more than Qulp's does.\n\r\n5. The alien who speaks Sbarkjozn, who has a blue vehicle, has not been traveling for 4.5 bzorks.\n\r\n6. The green and red vehicles had not been running the longest.\n\r\n7. The alien that speaks Zronxhor has not been traveling for 7.5 bzorks and his name is not Szurkax.\n\r\n8. Either Qorxl's vehicle or the red vehicle weighs 5 qorzes.\n\r\n9. The alien who speaks Jwrpl has a purple spacecraft.\n\r\n10. Smorp has either been traveling for 6 or 7.5 bzorks.\n\r\n11. Qorxl has not been traveling for 7.5 bzorks.", "hint": "Reread the introduction carefully! M stands for Male, and F stands for Female.", "answer": "Blellow has a green spacecraft that weighs 8 qorzes, speaks Zronxhor, and has been traveling for 3 bzorks.\r\nSmorp has a red spacecraft that weighs 2 qorzes, speaks Qanxan, and has been traveling for 7.5 bzorks.\r\nSzurkax has a blue spacecraft that weighs 7 qorzes, speaks Sbarkjozn, and has been traveling for 6 bzorks.\r\nQulp has an orange spacecraft that weighs 4 qorzes, speaks Boeiaix, and has been traveling for 9 bzorks.\r\nQorxl has a purple spacecraft that weighs 5 qorzes, speaks Jwrpl, and has been traveling for 4.5 bzorks.", "category": "Logic-Grid", "date": "04/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBlellow the alien was driving happily along in his new spacecraft when he crashed into 4 other aliens! They were all thrown out of their spacecraft and had temporary amnesia. All 5 aliens spoke Sporzdak (the universal alien language), so they were able to communicate, but they also each spoke second languages. Each alien had been traveling a different amount of time (in bzorks) in different colored spacecrafts. Each spacecraft weighs a different amount (including the 4 qorz one that Qulp has). Help the aliens figure out who has what color spacecraft, how long each had been traveling (in bzorks), what their second language was, and how much the spacecraft weighed (in qorzes).\n\r\nAliens - Blellow (M), Smorp (M), Szurkax (M), Qulp (F), and Qorxl (F)\r\nSpacecraft color - Blue, Orange, Green, Red, and Purple\r\nWeight of spacecraft (qorzes) - 2, 4, 5, 7, and 8\r\n2nd Language - Qanxan, Sbarkjozn, Zronxhor, Jwrpl, and Boeiaix\r\nAmount of time spent traveling (bzorks) - 3, 4.5, 6, 7.5, and 9\n\r\n1. The 5 aliens are: Blellow, the one with the red spacecraft, the one that has been traveling for 4.5 bzorks, the one with a spacecraft that weighs 7 qorzes, and the one that speaks Boeiaix.\n\r\n2. Blellow's name is actually a mixture of the English words for two primary pigments. His spacecraft is the color that would result from mixing the two pigments in his name.\n\r\n3. The alien who has a spacecraft that weighs 3 qorzes more than Smorp's does has been traveling in her spacecraft for 1.5 bzorks less than Szurkax has.\n\r\n4. Blellow's spacecraft weighs more than Qulp's does.\n\r\n5. The alien who speaks Sbarkjozn, who has a blue vehicle, has not been traveling for 4.5 bzorks.\n\r\n6. The green and red vehicles had not been running the longest.\n\r\n7. The alien that speaks Zronxhor has not been traveling for 7.5 bzorks and his name is not Szurkax.\n\r\n8. Either Qorxl's vehicle or the red vehicle weighs 5 qorzes.\n\r\n9. The alien who speaks Jwrpl has a purple spacecraft.\n\r\n10. Smorp has either been traveling for 6 or 7.5 bzorks.\n\r\n11. Qorxl has not been traveling for 7.5 bzorks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlellow has a green spacecraft that weighs 8 qorzes, speaks Zronxhor, and has been traveling for 3 bzorks.\r\nSmorp has a red spacecraft that weighs 2 qorzes, speaks Qanxan, and has been traveling for 7.5 bzorks.\r\nSzurkax has a blue spacecraft that weighs 7 qorzes, speaks Sbarkjozn, and has been traveling for 6 bzorks.\r\nQulp has an orange spacecraft that weighs 4 qorzes, speaks Boeiaix, and has been traveling for 9 bzorks.\r\nQorxl has a purple spacecraft that weighs 5 qorzes, speaks Jwrpl, and has been traveling for 4.5 bzorks.\n<|im_start|>answer\nBlellow has a green spacecraft that weighs 8 qorzes, speaks Zronxhor, and has been traveling for 3 bzorks.\r\nSmorp has a red spacecraft that weighs 2 qorzes, speaks Qanxan, and has been traveling for 7.5 bzorks.\r\nSzurkax has a blue spacecraft that weighs 7 qorzes, speaks Sbarkjozn, and has been traveling for 6 bzorks.\r\nQulp has an orange spacecraft that weighs 4 qorzes, speaks Boeiaix, and has been traveling for 9 bzorks.\r\nQorxl has a purple spacecraft that weighs 5 qorzes, speaks Jwrpl, and has been traveling for 4.5 bzorks.\n<|im_end|>" }, { "id": "#28777", "title": "Thank You, Sweetie!", "fun": 3.0, "difficulty": 2.07, "author": "Winner4600", "desc": "Three girls (Jada, Sally, and Patty) and two boys (Huey and Timmy) decided to go out to the gardens and pick some flowers for their parents (Rebecca, Lindsey, Ken, Daniel, and Mike). Each child chose a different flower, and picked a different amount. Can you figure out their first and last names, their parent's name, the flower they picked, and the amount they picked?\n\r\n1. The girls picked flowers for their dads, while the boys picked flowers for their moms.\r\n2. Ken Rosenthal received 2 flowers.\r\n3. Six daffodils were picked by Harrison.\r\n4. Sally and Daniel's daughter are best friends.\r\n5. Only one person picked a flower with the same initial as their first name. Only one person received a flower with the same initial as their first name. Nobody picked or received a flower with the same initial as their last name.\r\n6. The 5 types of flowers are the sunflower, the type picked by Jada, the ones picked by Timmy, the ones given to Mike, and Sally's flowers.\r\n7. Three daisies were picked by Gonzalez.\r\n8. Rebecca Jones received 5 sunflowers.\r\n9. Patty loves daffodils, so she picked some for her dad.\n\r\nGood Luck!", "hint": "No hint available.", "answer": "Jada, Daniel, Gonzalez, daisy, 3\r\nSally, Ken, Rosenthal, carnation, 2\r\nHuey, Rebecca, Jones, sunflower, 5\r\nTimmy, Lindsey, Smith, tulip, 4\r\nPatty, Mike, Harrison, daffodil, 6", "category": "Logic-Grid", "date": "02/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree girls (Jada, Sally, and Patty) and two boys (Huey and Timmy) decided to go out to the gardens and pick some flowers for their parents (Rebecca, Lindsey, Ken, Daniel, and Mike). Each child chose a different flower, and picked a different amount. Can you figure out their first and last names, their parent's name, the flower they picked, and the amount they picked?\n\r\n1. The girls picked flowers for their dads, while the boys picked flowers for their moms.\r\n2. Ken Rosenthal received 2 flowers.\r\n3. Six daffodils were picked by Harrison.\r\n4. Sally and Daniel's daughter are best friends.\r\n5. Only one person picked a flower with the same initial as their first name. Only one person received a flower with the same initial as their first name. Nobody picked or received a flower with the same initial as their last name.\r\n6. The 5 types of flowers are the sunflower, the type picked by Jada, the ones picked by Timmy, the ones given to Mike, and Sally's flowers.\r\n7. Three daisies were picked by Gonzalez.\r\n8. Rebecca Jones received 5 sunflowers.\r\n9. Patty loves daffodils, so she picked some for her dad.\n\r\nGood Luck!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJada, Daniel, Gonzalez, daisy, 3\r\nSally, Ken, Rosenthal, carnation, 2\r\nHuey, Rebecca, Jones, sunflower, 5\r\nTimmy, Lindsey, Smith, tulip, 4\r\nPatty, Mike, Harrison, daffodil, 6\n<|im_start|>answer\nJada, Daniel, Gonzalez, daisy, 3\r\nSally, Ken, Rosenthal, carnation, 2\r\nHuey, Rebecca, Jones, sunflower, 5\r\nTimmy, Lindsey, Smith, tulip, 4\r\nPatty, Mike, Harrison, daffodil, 6\n<|im_end|>" }, { "id": "#29620", "title": "On the Road Again...", "fun": 3.0, "difficulty": 2.41, "author": "Gadget", "desc": "Joe often travels for his job. Last week he ate at a different restaurant each weekday. He ordered a different entree and a different dessert at each. Determine where Joe ate each day, what entree he ordered and what he had for dessert with each meal.\n\r\n1. Joe ate at the Beach Grill (which is either where he had mixed fruit or the ice cream) on Friday.\n\r\n2. Joe ate at Irene's (where he had either pecan pie or cheesecake) later in the week than he ate at the Cove.\n\r\n3. Joe ate at the restaurant where he had the chicken exactly one day before he ate at Lou's Loft (where he had either the pecan pie or the cheesecake).\n\r\n4. Joe had mixed fruit for dessert at either Irene's or the restaurant where he had the veal.\n\r\n5. Joe ate at the restaurant where he had the steak (and either pecan pie or cheesecake for dessert) before he ate where he had the mixed fruit (which he didn't have on Thursday or Friday) but after he ate at Anthony's.\n\r\n6. Joe ate where he had the pecan pie for dessert later in the week than when he had the cheesecake. He did not order pecan pie on the day he had spaghetti.", "hint": "No hint available.", "answer": "Monday, Anthony's, chicken, brownie\n\r\nTuesday, Lou's Loft, steak, cheesecake\n\r\nWednesday, the Cove, veal, mixed fruit\n\r\nThursday, Irene's, barbeque, pecan pie\n\r\nFriday, Beach Grill, spaghetti, ice cream", "category": "Logic-Grid", "date": "04/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe often travels for his job. Last week he ate at a different restaurant each weekday. He ordered a different entree and a different dessert at each. Determine where Joe ate each day, what entree he ordered and what he had for dessert with each meal.\n\r\n1. Joe ate at the Beach Grill (which is either where he had mixed fruit or the ice cream) on Friday.\n\r\n2. Joe ate at Irene's (where he had either pecan pie or cheesecake) later in the week than he ate at the Cove.\n\r\n3. Joe ate at the restaurant where he had the chicken exactly one day before he ate at Lou's Loft (where he had either the pecan pie or the cheesecake).\n\r\n4. Joe had mixed fruit for dessert at either Irene's or the restaurant where he had the veal.\n\r\n5. Joe ate at the restaurant where he had the steak (and either pecan pie or cheesecake for dessert) before he ate where he had the mixed fruit (which he didn't have on Thursday or Friday) but after he ate at Anthony's.\n\r\n6. Joe ate where he had the pecan pie for dessert later in the week than when he had the cheesecake. He did not order pecan pie on the day he had spaghetti.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday, Anthony's, chicken, brownie\n\r\nTuesday, Lou's Loft, steak, cheesecake\n\r\nWednesday, the Cove, veal, mixed fruit\n\r\nThursday, Irene's, barbeque, pecan pie\n\r\nFriday, Beach Grill, spaghetti, ice cream\n<|im_start|>answer\nMonday, Anthony's, chicken, brownie\n\r\nTuesday, Lou's Loft, steak, cheesecake\n\r\nWednesday, the Cove, veal, mixed fruit\n\r\nThursday, Irene's, barbeque, pecan pie\n\r\nFriday, Beach Grill, spaghetti, ice cream\n<|im_end|>" }, { "id": "#38432", "title": "College Days", "fun": 3.0, "difficulty": 2.58, "author": "dreamlvr1432", "desc": "Five college students met in line at the registrar's office, while waiting to drop a class from each of their schedules. They decided to have lunch together in the student union after they returned their books (for the classes they were dropping) to the bookstore. Over lunch, the students discussed their majors, the classes they were dropping, and general topics of college life. Can you determine which class each student dropped, the day it was scheduled, the number of books each needed to return, and each of the student's majors?\n\r\nStudents: Adam, Kristen, Dawn, Karen, Chris\r\nMajors: criminal science, education, business, psychology, journalism\r\nDropped classes: chemistry, biology, economics, trigonometry, philosophy\r\nDays scheduled: Monday, Tuesday, Wednesday, Thursday, Friday\r\n# of books: 0, 1, 2, 3, 4\n\r\n1) The economics class was either on Tuesday or Friday, and required either 3 or 4 books.\n\r\n2) Kristen is fascinated with the logic of science and criminology. She finds that there are too many \"what ifs\" and unknowns in philosophy for her taste. Therefore, she dropped this class.\n\r\n3) Dawn's schedule was way too busy on Fridays, so she dropped a class that day to make time to go out with her friends.\n\r\n4) The criminal science major never bought the books required for her dropped class, so she skipped the bookstore and went straight to the student union.\n\r\n5) The boy who dropped his Wednesday class did not major in education, nor did he return 3 books.\n\r\n6) The 5 students are: Adam, the one who dropped her Tuesday class, the one who dropped the economics class, the one who returned 2 books, and the journalism major.\n\r\n7) The trigonometry class was scheduled before the class that the psychology major dropped, but after the one requiring 4 books (which was scheduled after Karen's dropped class).\n\r\n8) Chris did not see the need for knowledge of trigonometry in his chosen area of study. He wants to become a journalist.\n\r\n9) The business major was eager to return his books, as they were weighing down his backpack. They were a study guide, a lab book, and 2 text books that were required for his chemistry class.", "hint": "No hint available.", "answer": "Adam, business major, chemistry, Wednesday, 4 books\r\nKristen, criminal science major, philosophy, Tuesday, 0 books\r\nDawn, psychology major, economics, Friday, 3 books\r\nKaren, education major, biology, Monday, 2 books\r\nChris, journalism major, trigonometry, Thursday, 1 book", "category": "Logic-Grid", "date": "09/23/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive college students met in line at the registrar's office, while waiting to drop a class from each of their schedules. They decided to have lunch together in the student union after they returned their books (for the classes they were dropping) to the bookstore. Over lunch, the students discussed their majors, the classes they were dropping, and general topics of college life. Can you determine which class each student dropped, the day it was scheduled, the number of books each needed to return, and each of the student's majors?\n\r\nStudents: Adam, Kristen, Dawn, Karen, Chris\r\nMajors: criminal science, education, business, psychology, journalism\r\nDropped classes: chemistry, biology, economics, trigonometry, philosophy\r\nDays scheduled: Monday, Tuesday, Wednesday, Thursday, Friday\r\n# of books: 0, 1, 2, 3, 4\n\r\n1) The economics class was either on Tuesday or Friday, and required either 3 or 4 books.\n\r\n2) Kristen is fascinated with the logic of science and criminology. She finds that there are too many \"what ifs\" and unknowns in philosophy for her taste. Therefore, she dropped this class.\n\r\n3) Dawn's schedule was way too busy on Fridays, so she dropped a class that day to make time to go out with her friends.\n\r\n4) The criminal science major never bought the books required for her dropped class, so she skipped the bookstore and went straight to the student union.\n\r\n5) The boy who dropped his Wednesday class did not major in education, nor did he return 3 books.\n\r\n6) The 5 students are: Adam, the one who dropped her Tuesday class, the one who dropped the economics class, the one who returned 2 books, and the journalism major.\n\r\n7) The trigonometry class was scheduled before the class that the psychology major dropped, but after the one requiring 4 books (which was scheduled after Karen's dropped class).\n\r\n8) Chris did not see the need for knowledge of trigonometry in his chosen area of study. He wants to become a journalist.\n\r\n9) The business major was eager to return his books, as they were weighing down his backpack. They were a study guide, a lab book, and 2 text books that were required for his chemistry class.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam, business major, chemistry, Wednesday, 4 books\r\nKristen, criminal science major, philosophy, Tuesday, 0 books\r\nDawn, psychology major, economics, Friday, 3 books\r\nKaren, education major, biology, Monday, 2 books\r\nChris, journalism major, trigonometry, Thursday, 1 book\n<|im_start|>answer\nAdam, business major, chemistry, Wednesday, 4 books\r\nKristen, criminal science major, philosophy, Tuesday, 0 books\r\nDawn, psychology major, economics, Friday, 3 books\r\nKaren, education major, biology, Monday, 2 books\r\nChris, journalism major, trigonometry, Thursday, 1 book\n<|im_end|>" }, { "id": "#43221", "title": "Naming Cats and Dogs", "fun": 3.0, "difficulty": 2.5100000000000002, "author": "whsprec", "desc": "Joe, Bill, Bob, Jack, and Tom, whose last names are Carter, Dawson, Mingus, Wood, and Cole, all live in the same building. Each man owns a cat and a dog. The names of the dogs are Dusty, Midnight, Ginger, Smokey, and Daisy. By chance, cats also have the same 5 names as the dogs. From the clues given, determine each man's first and last name and the names of his pets. (Hint: no man gave the same name to both his cat and his dog.)\n\r\n1. Joe and Jack each have a pet named Ginger.\r\n2. Jack, Joe, and Mr. Carter do not have pets named Midnight.\r\n3. Bob's dog and Jack's cat have the same name, as do Bill's cat and Tom's dog.\r\n4. The cat Daisy is not owned by Jack Cole, Mr. Mingus, Mr. Carter, or Bill.\r\n5. Smokey the cat does not live with Ginger the dog, and neither of them live with Tom or Mr. Dawson.\r\n6. Joe's dog is named Daisy.", "hint": "No hint available.", "answer": "Joe Mingus: Daisy dog and Ginger cat\r\nBill Dawson: Smokey dog and Midnight cat\r\nBob Carter: Dusty dog and Smokey cat\r\nJack Cole: Ginger dog and Dusty cat\r\nTom Wood: Midnight dog and Daisy cat", "category": "Logic-Grid", "date": "09/30/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe, Bill, Bob, Jack, and Tom, whose last names are Carter, Dawson, Mingus, Wood, and Cole, all live in the same building. Each man owns a cat and a dog. The names of the dogs are Dusty, Midnight, Ginger, Smokey, and Daisy. By chance, cats also have the same 5 names as the dogs. From the clues given, determine each man's first and last name and the names of his pets. (Hint: no man gave the same name to both his cat and his dog.)\n\r\n1. Joe and Jack each have a pet named Ginger.\r\n2. Jack, Joe, and Mr. Carter do not have pets named Midnight.\r\n3. Bob's dog and Jack's cat have the same name, as do Bill's cat and Tom's dog.\r\n4. The cat Daisy is not owned by Jack Cole, Mr. Mingus, Mr. Carter, or Bill.\r\n5. Smokey the cat does not live with Ginger the dog, and neither of them live with Tom or Mr. Dawson.\r\n6. Joe's dog is named Daisy.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoe Mingus: Daisy dog and Ginger cat\r\nBill Dawson: Smokey dog and Midnight cat\r\nBob Carter: Dusty dog and Smokey cat\r\nJack Cole: Ginger dog and Dusty cat\r\nTom Wood: Midnight dog and Daisy cat\n<|im_start|>answer\nJoe Mingus: Daisy dog and Ginger cat\r\nBill Dawson: Smokey dog and Midnight cat\r\nBob Carter: Dusty dog and Smokey cat\r\nJack Cole: Ginger dog and Dusty cat\r\nTom Wood: Midnight dog and Daisy cat\n<|im_end|>" }, { "id": "#12940", "title": "Blue Pill Problem", "fun": 3.0, "difficulty": 2.47, "author": "ejasami", "desc": "You've been placed on a course of expensive medication in which you are to take one tablet of Sildenafil and one tablet of Citrate daily. You must be careful that you take just one of each because taking more of either can have serious side effects.\n\r\nTaking Sildenafil without taking Citrate, or vice versa, can also be very serious, because they must be taken together in order to be effective. In summary, you must take exactly one of the Sildenafil pills and one of the Citrate pills at one time. Therefore, you open up the Sildenafil bottle, and you tap one Sildenafil pill into your hand. You put that bottle aside and you open the Citrate bottle. You do the same, but by mistake, two Citrates fall into your hand with the Sildenafil pill.\n\r\nNow, here's the problem. You weren't watching your hand as the pills fell into it, so you can't tell the Sildenafil pill apart from the two Citrate pills. The pills look identical. They are both the same size, same weight (10 micrograms), same color (Blue), same shape (perfect square), same everything, and they are not marked differently in any way.\n\r\nWhat are you going to do? You cannot tell which pill is which, and they cost $300 a piece, so you cannot afford to throw them away and start over again. How do you get your daily dose of exactly one Sildenafil and exactly one Citrate without wasting any of the pills?", "hint": "No hint available.", "answer": "Carefully cut each of the three pills in half, and carefully separate them into two piles, with half of each pill in each pile. You do not know which pill is which, but you are 100% sure that each of the two piles now contains two halves of Citrate and half of Sildenafil. Now go back into the Sildenafil bottle, take out a pill, cut it in half, and add one half to each stack. Now you have two stacks, each one containing two halves of Sildenafil and two halves of Citrate. Take one stack of pills today, and save the second stack for tomorrow.", "category": "Logic", "date": "06/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou've been placed on a course of expensive medication in which you are to take one tablet of Sildenafil and one tablet of Citrate daily. You must be careful that you take just one of each because taking more of either can have serious side effects.\n\r\nTaking Sildenafil without taking Citrate, or vice versa, can also be very serious, because they must be taken together in order to be effective. In summary, you must take exactly one of the Sildenafil pills and one of the Citrate pills at one time. Therefore, you open up the Sildenafil bottle, and you tap one Sildenafil pill into your hand. You put that bottle aside and you open the Citrate bottle. You do the same, but by mistake, two Citrates fall into your hand with the Sildenafil pill.\n\r\nNow, here's the problem. You weren't watching your hand as the pills fell into it, so you can't tell the Sildenafil pill apart from the two Citrate pills. The pills look identical. They are both the same size, same weight (10 micrograms), same color (Blue), same shape (perfect square), same everything, and they are not marked differently in any way.\n\r\nWhat are you going to do? You cannot tell which pill is which, and they cost $300 a piece, so you cannot afford to throw them away and start over again. How do you get your daily dose of exactly one Sildenafil and exactly one Citrate without wasting any of the pills?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarefully cut each of the three pills in half, and carefully separate them into two piles, with half of each pill in each pile. You do not know which pill is which, but you are 100% sure that each of the two piles now contains two halves of Citrate and half of Sildenafil. Now go back into the Sildenafil bottle, take out a pill, cut it in half, and add one half to each stack. Now you have two stacks, each one containing two halves of Sildenafil and two halves of Citrate. Take one stack of pills today, and save the second stack for tomorrow.\n<|im_start|>answer\nCarefully cut each of the three pills in half, and carefully separate them into two piles, with half of each pill in each pile. You do not know which pill is which, but you are 100% sure that each of the two piles now contains two halves of Citrate and half of Sildenafil. Now go back into the Sildenafil bottle, take out a pill, cut it in half, and add one half to each stack. Now you have two stacks, each one containing two halves of Sildenafil and two halves of Citrate. Take one stack of pills today, and save the second stack for tomorrow.\n<|im_end|>" }, { "id": "#38583", "title": "Hyphens Hyphens Everywhere", "fun": 3.0, "difficulty": 2.43, "author": "fierceandsassy", "desc": "Five couples were surprised to find out that not only did they all have hyphenated last names, they had all gotten married in the same year! Determine from the clues below the first and last names of each couple and in what month they were married. \r\nNote: There were no same-sex couples in the group; each of the men married a woman and vice versa.\n\r\nWomen: Beatrice, Emily, Lucy, Teresa, Wendy\r\nWomen's Last Names: Baker, Ingalls, Landon, Morse, West \r\nMen: Gary, Isaac, Jonathan, Michael, Samuel\r\nMen's Last Names: Emerson, Gasero, Jimenez, Smith, Thompson\r\nMonths: February, April, June, August, October\n\n\r\n1. No one had a last name that started with the same letter of their first name before they were married. No one married someone whose last name started with the same letter as their first name. \n\r\n2. Emily convinced her husband that Smith-Landon sounded too much like Smith and Wesson, so they hyphenated their names the other way around.\n\r\n3. The five couples are represented by: Wendy, the couple who was married in October, Gary, the Jimenez-Wests, and the couple with Thompson in their name.\n\r\n4. Lucy Ingalls, as she was known before she was married, was thrilled to be able to have the June wedding she had always wanted. Samuel's bride was perfectly happy having an April wedding. \n\r\n5. Teresa, whose last name included either Morse or West, escaped the winter wonderland of her wedding day by honeymooning in Hawaii. Michael, on the other hand, left the dog days of summer behind when he honeymooned with Beatrice in Alberta.", "hint": "No hint available.", "answer": "Beatrice and Michael Jimenez-West were married in August.\n\r\nEmily and Isaac Landon-Smith were married in October.\n\r\nLucy and Jonathan Ingalls-Thompson were married in June.\n\r\nTeresa and Gary Emerson-Morse were married in February.\n\r\nWendy and Samuel Baker-Gasero were married in April.", "category": "Logic-Grid", "date": "10/02/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive couples were surprised to find out that not only did they all have hyphenated last names, they had all gotten married in the same year! Determine from the clues below the first and last names of each couple and in what month they were married. \r\nNote: There were no same-sex couples in the group; each of the men married a woman and vice versa.\n\r\nWomen: Beatrice, Emily, Lucy, Teresa, Wendy\r\nWomen's Last Names: Baker, Ingalls, Landon, Morse, West \r\nMen: Gary, Isaac, Jonathan, Michael, Samuel\r\nMen's Last Names: Emerson, Gasero, Jimenez, Smith, Thompson\r\nMonths: February, April, June, August, October\n\n\r\n1. No one had a last name that started with the same letter of their first name before they were married. No one married someone whose last name started with the same letter as their first name. \n\r\n2. Emily convinced her husband that Smith-Landon sounded too much like Smith and Wesson, so they hyphenated their names the other way around.\n\r\n3. The five couples are represented by: Wendy, the couple who was married in October, Gary, the Jimenez-Wests, and the couple with Thompson in their name.\n\r\n4. Lucy Ingalls, as she was known before she was married, was thrilled to be able to have the June wedding she had always wanted. Samuel's bride was perfectly happy having an April wedding. \n\r\n5. Teresa, whose last name included either Morse or West, escaped the winter wonderland of her wedding day by honeymooning in Hawaii. Michael, on the other hand, left the dog days of summer behind when he honeymooned with Beatrice in Alberta.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeatrice and Michael Jimenez-West were married in August.\n\r\nEmily and Isaac Landon-Smith were married in October.\n\r\nLucy and Jonathan Ingalls-Thompson were married in June.\n\r\nTeresa and Gary Emerson-Morse were married in February.\n\r\nWendy and Samuel Baker-Gasero were married in April.\n<|im_start|>answer\nBeatrice and Michael Jimenez-West were married in August.\n\r\nEmily and Isaac Landon-Smith were married in October.\n\r\nLucy and Jonathan Ingalls-Thompson were married in June.\n\r\nTeresa and Gary Emerson-Morse were married in February.\n\r\nWendy and Samuel Baker-Gasero were married in April.\n<|im_end|>" }, { "id": "#51857", "title": "What Do You Get?", "fun": 3.0, "difficulty": 1.21, "author": "fishmed", "desc": "Looking at the 3 \"equations\" below, what is the answer to the 4th one?\n\r\n8 + 2 = 16106\r\n5 + 4 = 2091\r\n9 + 6 = 54153\r\n7 + 3 = ?", "hint": "No hint available.", "answer": "21104\n\r\nTo arrive at each answer you first multiply the two numbers, then add the two numbers, and finally subtract the two numbers. Your final answer is each of these answers strung together.", "category": "Math", "date": "05/22/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLooking at the 3 \"equations\" below, what is the answer to the 4th one?\n\r\n8 + 2 = 16106\r\n5 + 4 = 2091\r\n9 + 6 = 54153\r\n7 + 3 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21104\n\r\nTo arrive at each answer you first multiply the two numbers, then add the two numbers, and finally subtract the two numbers. Your final answer is each of these answers strung together.\n<|im_start|>answer\n21104\n\r\nTo arrive at each answer you first multiply the two numbers, then add the two numbers, and finally subtract the two numbers. Your final answer is each of these answers strung together.\n<|im_end|>" }, { "id": "#50794", "title": "Murder on the ABC Express", "fun": 3.0, "difficulty": 3.02, "author": "tedger", "desc": "The ABC Express pulled out of the station late one night and began its winding journey up the coast to its destination under heavy darkness. Owing to the late hour, there were only a handful of passengers aboard the small train. At the stroke of midnight, the lights illuminating the interior of the two cars were suddenly extinguished. When they flicked back to life a few moments later, the passengers were alarmed to see one of their number lying on the ground motionless.\n\r\nThe conductor phoned the local police department, and though it was very late, the dispatcher assured the worried conductor that they were sending their very best detective. A bit of an eccentric, Detective Y had an usual methodology when it came to solving crimes. Knowing witnesses to be often be mistaken and contradictory, Y made a habit of asking his witnesses to state to him only one fact they remembered clearly and with absolute certainty from the moment the crime took place.\n\r\nY wasted no time upon arriving and, after taking a quick overview of the scene, asked each of the ten remaining passengers in turn to state one absolute fact from the moment right before lights went out in the two train cars. His interview notes are as follows:\n\n\r\nMs. S: I was dining with Mr. J.\r\nMr. G: There were the same number of men and women in my car.\r\nMr. J: Mr. K was not in the dining car.\r\nMs. L: Mr. Q had just entered my car.\r\nMr. F: Ms. W and Ms. P were talking to one another in hushed tones.\r\nMr. R: Mr. G was not in the passenger car.\r\nMr. Q: There were fewer women in my car than the other.\r\nMs. P: Ms. L was not in the same car as me.\r\nMr. K: Ms. P was in the passenger car.\r\nMs. W: Mr. F was avoiding Mr. R and hiding behind a newspaper in the opposite car.\n\n\r\nThe bewildered conductor watched as Detective Y completed his interviews, scribbled a few more lines in his notes, and turned to announce he had solved the case.\n\r\n\"But surely you can't have figured out the identity of a murderer simply from a list of seating arrangements?\" the conductor protested. \"You haven't even been told in which car the victim was seated!\"\n\r\n\"To the contrary, my good man,\" the detective answered placidly. \"It is the curse of a criminal that he must answer any question regarding the crime he has committed with a lie. The innocent tell only truths, but the lone murderer has been betrayed by his testimony.\"\n\r\nWho did Detective Y arrest?", "hint": "Like any good Detective, Y always assumes everyone he interviews is telling the truth until proven otherwise. He also knows the simplest explanation is always the best. He compares the witness statements until he discovers the scenario that is accurately described by nine truthful witnesses and arrests the liar.", "answer": "Y began by assuming everyone was telling the truth about each other's location and came up with the following arrangement: S J L Q G R (4 men, 2 women) in the dining car and K P W F (2 men, 2 women) in the passenger car. (R and F are interchangeable in this scenario, but as both are men, the precise position of each is irrelevant to this point.) This contradicted both G's statement that there were an equal number of men and women in his (the dining) car and Mr. Q's claim that fewer women were in one car than the other.\n\r\nThus, the detective concluded both G and Q were telling the truth and someone was lying about the occupancy. Y reasoned that only one possible configuration could make both men's testimonies true: G, 2 other men, and 3 women in one car and Q, 2 other men, and 1 woman in the other.\n\r\nBecause G and Q had to have been in opposite cars, Y worked back up his witness list to find the lie that had placed Q in the wrong car. He first examined L's statement that she and Q shared the same car. If this alone was the lie, it would leave S J L G R (3 men, 2 women) in the dining car and put K P Q W F (3 men, 2 women) in the passenger car, meaning G and Q's statements still would be inaccurate.\n\r\nMs. L must be telling the truth then, and Y instead turned to P's claim, which had placed L (and Q by extension) in the other car. If P was lying, it would mean only S J G R (3 men, 1 woman) were in the dining car and K P L Q W F (3 men, 3 women) were in the passenger car. Again, neither G or Q's statements are met.\n\r\nDetective Y, now certain Mr. G, Mr. Q, Ms. L, and Ms. P were all telling the truth, backtracked to Mr. K next, who had established P's position. Assuming K a liar, Y was able to place S J P G W R (3 men, 3 women) in the dining car and K L Q F (3 men, 1 woman) in the passenger car.\n\r\nA prudent man, Y double checked his work by running each remaining statement against his reasoning and stiffened his resolve upon finding K to be the only possible person whose lone lie could make every other witness statement truthful.\n\r\nMr. K was arrested and led away to the relief (albeit, slight puzzlement) of the conductor and his passengers.", "category": "Logic", "date": "04/17/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe ABC Express pulled out of the station late one night and began its winding journey up the coast to its destination under heavy darkness. Owing to the late hour, there were only a handful of passengers aboard the small train. At the stroke of midnight, the lights illuminating the interior of the two cars were suddenly extinguished. When they flicked back to life a few moments later, the passengers were alarmed to see one of their number lying on the ground motionless.\n\r\nThe conductor phoned the local police department, and though it was very late, the dispatcher assured the worried conductor that they were sending their very best detective. A bit of an eccentric, Detective Y had an usual methodology when it came to solving crimes. Knowing witnesses to be often be mistaken and contradictory, Y made a habit of asking his witnesses to state to him only one fact they remembered clearly and with absolute certainty from the moment the crime took place.\n\r\nY wasted no time upon arriving and, after taking a quick overview of the scene, asked each of the ten remaining passengers in turn to state one absolute fact from the moment right before lights went out in the two train cars. His interview notes are as follows:\n\n\r\nMs. S: I was dining with Mr. J.\r\nMr. G: There were the same number of men and women in my car.\r\nMr. J: Mr. K was not in the dining car.\r\nMs. L: Mr. Q had just entered my car.\r\nMr. F: Ms. W and Ms. P were talking to one another in hushed tones.\r\nMr. R: Mr. G was not in the passenger car.\r\nMr. Q: There were fewer women in my car than the other.\r\nMs. P: Ms. L was not in the same car as me.\r\nMr. K: Ms. P was in the passenger car.\r\nMs. W: Mr. F was avoiding Mr. R and hiding behind a newspaper in the opposite car.\n\n\r\nThe bewildered conductor watched as Detective Y completed his interviews, scribbled a few more lines in his notes, and turned to announce he had solved the case.\n\r\n\"But surely you can't have figured out the identity of a murderer simply from a list of seating arrangements?\" the conductor protested. \"You haven't even been told in which car the victim was seated!\"\n\r\n\"To the contrary, my good man,\" the detective answered placidly. \"It is the curse of a criminal that he must answer any question regarding the crime he has committed with a lie. The innocent tell only truths, but the lone murderer has been betrayed by his testimony.\"\n\r\nWho did Detective Y arrest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nY began by assuming everyone was telling the truth about each other's location and came up with the following arrangement: S J L Q G R (4 men, 2 women) in the dining car and K P W F (2 men, 2 women) in the passenger car. (R and F are interchangeable in this scenario, but as both are men, the precise position of each is irrelevant to this point.) This contradicted both G's statement that there were an equal number of men and women in his (the dining) car and Mr. Q's claim that fewer women were in one car than the other.\n\r\nThus, the detective concluded both G and Q were telling the truth and someone was lying about the occupancy. Y reasoned that only one possible configuration could make both men's testimonies true: G, 2 other men, and 3 women in one car and Q, 2 other men, and 1 woman in the other.\n\r\nBecause G and Q had to have been in opposite cars, Y worked back up his witness list to find the lie that had placed Q in the wrong car. He first examined L's statement that she and Q shared the same car. If this alone was the lie, it would leave S J L G R (3 men, 2 women) in the dining car and put K P Q W F (3 men, 2 women) in the passenger car, meaning G and Q's statements still would be inaccurate.\n\r\nMs. L must be telling the truth then, and Y instead turned to P's claim, which had placed L (and Q by extension) in the other car. If P was lying, it would mean only S J G R (3 men, 1 woman) were in the dining car and K P L Q W F (3 men, 3 women) were in the passenger car. Again, neither G or Q's statements are met.\n\r\nDetective Y, now certain Mr. G, Mr. Q, Ms. L, and Ms. P were all telling the truth, backtracked to Mr. K next, who had established P's position. Assuming K a liar, Y was able to place S J P G W R (3 men, 3 women) in the dining car and K L Q F (3 men, 1 woman) in the passenger car.\n\r\nA prudent man, Y double checked his work by running each remaining statement against his reasoning and stiffened his resolve upon finding K to be the only possible person whose lone lie could make every other witness statement truthful.\n\r\nMr. K was arrested and led away to the relief (albeit, slight puzzlement) of the conductor and his passengers.\n<|im_start|>answer\nY began by assuming everyone was telling the truth about each other's location and came up with the following arrangement: S J L Q G R (4 men, 2 women) in the dining car and K P W F (2 men, 2 women) in the passenger car. (R and F are interchangeable in this scenario, but as both are men, the precise position of each is irrelevant to this point.) This contradicted both G's statement that there were an equal number of men and women in his (the dining) car and Mr. Q's claim that fewer women were in one car than the other.\n\r\nThus, the detective concluded both G and Q were telling the truth and someone was lying about the occupancy. Y reasoned that only one possible configuration could make both men's testimonies true: G, 2 other men, and 3 women in one car and Q, 2 other men, and 1 woman in the other.\n\r\nBecause G and Q had to have been in opposite cars, Y worked back up his witness list to find the lie that had placed Q in the wrong car. He first examined L's statement that she and Q shared the same car. If this alone was the lie, it would leave S J L G R (3 men, 2 women) in the dining car and put K P Q W F (3 men, 2 women) in the passenger car, meaning G and Q's statements still would be inaccurate.\n\r\nMs. L must be telling the truth then, and Y instead turned to P's claim, which had placed L (and Q by extension) in the other car. If P was lying, it would mean only S J G R (3 men, 1 woman) were in the dining car and K P L Q W F (3 men, 3 women) were in the passenger car. Again, neither G or Q's statements are met.\n\r\nDetective Y, now certain Mr. G, Mr. Q, Ms. L, and Ms. P were all telling the truth, backtracked to Mr. K next, who had established P's position. Assuming K a liar, Y was able to place S J P G W R (3 men, 3 women) in the dining car and K L Q F (3 men, 1 woman) in the passenger car.\n\r\nA prudent man, Y double checked his work by running each remaining statement against his reasoning and stiffened his resolve upon finding K to be the only possible person whose lone lie could make every other witness statement truthful.\n\r\nMr. K was arrested and led away to the relief (albeit, slight puzzlement) of the conductor and his passengers.\n<|im_end|>" }, { "id": "#52421", "title": "Trixie's Preference", "fun": 3.0, "difficulty": 2.2, "author": "wimpykidfan37", "desc": "Trixie is the most athletic girl in her grade. She is a star player on the baseball, soccer, and basketball teams. Four boys, Al, Ben, Carl, and Dan have a crush on her. Because Trixie is so passionate about sports, she wants her boyfriend to play the same three sports she does. Here are some facts:\n\r\n1. No two of the four boys plays the same number of the sports baseball, soccer, and basketball.\n\r\n2. Only one boy plays baseball but not soccer, and this boy is either Al or Dan.\n\r\n3. Only one boy plays basketball but not baseball, and this boy is either Ben or Carl.\n\r\n4. Either Al and Carl both play baseball, or neither plays baseball.\n\r\n5. Either Ben and Dan both play soccer, or neither plays soccer.\n\r\nWho should Trixie date?", "hint": "No hint available.", "answer": "Trixie should date Carl.\n\r\nFact 1 can only work if one of the four boys plays only one sport, another plays two sports, a third plays all three sports, and the last plays no sports at all.\n\r\nFrom facts 4 and 5, we have four scenarios:\n\r\n1. Al and Carl both play baseball and Ben and Dan both play soccer. This cannot work because now none of the boys can play no sports at all.\r\n2. Neither Al nor Carl plays baseball, and neither Ben nor Dan plays soccer. This cannot work because now none of the boys can play all three sports.\r\n3. Neither Al nor Carl plays baseball, and Ben and Dan both play soccer. But now neither Al nor Dan plays baseball but not soccer. So, from fact 2, this cannot work.\r\n4. Al and Carl both play baseball, and neither Ben nor Dan plays soccer. Since the other three scenarios cannot work, this must be the correct one.\n\r\nSince Carl plays baseball, fact 3 tells us that Ben plays basketball but not baseball. Now that we know that Al and Carl both play baseball and Ben plays basketball, Dan must be the one who plays no sports at all.\n\r\nSince Dan does not play baseball, fact 2 tells us that Al plays baseball but not soccer. Now that we know that none of Al, Ben, and Dan play soccer, Carl must be the one who plays all three sports, and therefore the one that Trixie should date.", "category": "Logic", "date": "07/12/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTrixie is the most athletic girl in her grade. She is a star player on the baseball, soccer, and basketball teams. Four boys, Al, Ben, Carl, and Dan have a crush on her. Because Trixie is so passionate about sports, she wants her boyfriend to play the same three sports she does. Here are some facts:\n\r\n1. No two of the four boys plays the same number of the sports baseball, soccer, and basketball.\n\r\n2. Only one boy plays baseball but not soccer, and this boy is either Al or Dan.\n\r\n3. Only one boy plays basketball but not baseball, and this boy is either Ben or Carl.\n\r\n4. Either Al and Carl both play baseball, or neither plays baseball.\n\r\n5. Either Ben and Dan both play soccer, or neither plays soccer.\n\r\nWho should Trixie date?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTrixie should date Carl.\n\r\nFact 1 can only work if one of the four boys plays only one sport, another plays two sports, a third plays all three sports, and the last plays no sports at all.\n\r\nFrom facts 4 and 5, we have four scenarios:\n\r\n1. Al and Carl both play baseball and Ben and Dan both play soccer. This cannot work because now none of the boys can play no sports at all.\r\n2. Neither Al nor Carl plays baseball, and neither Ben nor Dan plays soccer. This cannot work because now none of the boys can play all three sports.\r\n3. Neither Al nor Carl plays baseball, and Ben and Dan both play soccer. But now neither Al nor Dan plays baseball but not soccer. So, from fact 2, this cannot work.\r\n4. Al and Carl both play baseball, and neither Ben nor Dan plays soccer. Since the other three scenarios cannot work, this must be the correct one.\n\r\nSince Carl plays baseball, fact 3 tells us that Ben plays basketball but not baseball. Now that we know that Al and Carl both play baseball and Ben plays basketball, Dan must be the one who plays no sports at all.\n\r\nSince Dan does not play baseball, fact 2 tells us that Al plays baseball but not soccer. Now that we know that none of Al, Ben, and Dan play soccer, Carl must be the one who plays all three sports, and therefore the one that Trixie should date.\n<|im_start|>answer\nTrixie should date Carl.\n\r\nFact 1 can only work if one of the four boys plays only one sport, another plays two sports, a third plays all three sports, and the last plays no sports at all.\n\r\nFrom facts 4 and 5, we have four scenarios:\n\r\n1. Al and Carl both play baseball and Ben and Dan both play soccer. This cannot work because now none of the boys can play no sports at all.\r\n2. Neither Al nor Carl plays baseball, and neither Ben nor Dan plays soccer. This cannot work because now none of the boys can play all three sports.\r\n3. Neither Al nor Carl plays baseball, and Ben and Dan both play soccer. But now neither Al nor Dan plays baseball but not soccer. So, from fact 2, this cannot work.\r\n4. Al and Carl both play baseball, and neither Ben nor Dan plays soccer. Since the other three scenarios cannot work, this must be the correct one.\n\r\nSince Carl plays baseball, fact 3 tells us that Ben plays basketball but not baseball. Now that we know that Al and Carl both play baseball and Ben plays basketball, Dan must be the one who plays no sports at all.\n\r\nSince Dan does not play baseball, fact 2 tells us that Al plays baseball but not soccer. Now that we know that none of Al, Ben, and Dan play soccer, Carl must be the one who plays all three sports, and therefore the one that Trixie should date.\n<|im_end|>" }, { "id": "#25451", "title": "F*R*I*E*N*D*S", "fun": 3.0, "difficulty": 1.72, "author": "Skye", "desc": "Five friends- Phoebe, Rachel, Chandler, Joey and Ross- all get together for a birthday dinner. Each friend had something different to drink with their dinner, and each had something different to eat. Based on the clues below, can you figure out which friend had what to drink, what they had to eat and how old each was?\n\n\r\nDrinks: Wine, water, champagne, coffee and cocktail\r\nFood: Steak, quiche, soup, fish and chicken.\r\nAges: 27, 28, 29, 30, 31 \n\r\n1. The person who had the steak was a year younger than Joey.\r\n2. Phoebe is the oldest; the youngest friend had water to drink.\r\n3. The friend who had quiche is the second oldest.\r\n4. The friend who had water also had the fish.\r\n5. The friend who was 29 had the chicken.\r\n6. Ross was the only guy that had an alcoholic beverage.\r\n7. Rachel is a year younger than Joey.\r\n8. The friend who had coffee was 2 years younger than Phoebe.\r\n9. The girl who had the wine also had the steak.\r\n10. The person who had the quiche also had champagne.", "hint": "The names, drinks, ages and dishes do not necessarily correspond with what the characters on the show would have had.", "answer": "Chandler, 27, had the fish and water.\r\nRachel, 28, had the steak and wine.\r\nJoey, 29, had the chicken and coffee.\r\nRoss, 30, had the quiche and champagne.\r\nPhoebe, 31, had the soup and cocktail.", "category": "Logic-Grid", "date": "08/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends- Phoebe, Rachel, Chandler, Joey and Ross- all get together for a birthday dinner. Each friend had something different to drink with their dinner, and each had something different to eat. Based on the clues below, can you figure out which friend had what to drink, what they had to eat and how old each was?\n\n\r\nDrinks: Wine, water, champagne, coffee and cocktail\r\nFood: Steak, quiche, soup, fish and chicken.\r\nAges: 27, 28, 29, 30, 31 \n\r\n1. The person who had the steak was a year younger than Joey.\r\n2. Phoebe is the oldest; the youngest friend had water to drink.\r\n3. The friend who had quiche is the second oldest.\r\n4. The friend who had water also had the fish.\r\n5. The friend who was 29 had the chicken.\r\n6. Ross was the only guy that had an alcoholic beverage.\r\n7. Rachel is a year younger than Joey.\r\n8. The friend who had coffee was 2 years younger than Phoebe.\r\n9. The girl who had the wine also had the steak.\r\n10. The person who had the quiche also had champagne.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChandler, 27, had the fish and water.\r\nRachel, 28, had the steak and wine.\r\nJoey, 29, had the chicken and coffee.\r\nRoss, 30, had the quiche and champagne.\r\nPhoebe, 31, had the soup and cocktail.\n<|im_start|>answer\nChandler, 27, had the fish and water.\r\nRachel, 28, had the steak and wine.\r\nJoey, 29, had the chicken and coffee.\r\nRoss, 30, had the quiche and champagne.\r\nPhoebe, 31, had the soup and cocktail.\n<|im_end|>" }, { "id": "#30800", "title": "Battles of the Gods II", "fun": 3.0, "difficulty": 1.83, "author": "medster99", "desc": "There was once a massive evil being, hundreds of feet tall, and so grand that it took Gods from all over the world to just defeat him, after defeating his minions. You can see how those battles went in \"Battles For the Gods\". Today they are prepared to attack the grand evil being face to face. The weak point would be attacked by whoever wanted to, and the weapon would be used by whoever could use it best. Each went one after the other, depending what needed to be taken out first. Also, each one had their own reasons for participating in the fight.\n\r\nThere were:\n\r\n5 Gods: Thor, Zeus, Ra, Apophis and Loki\r\n5 Weak Points: Center Eye, 2nd Nose, Right Ear, 3rd Mouth and Left Foot\r\n5 Weapons: Plasma Pike, Water Whip, Fire Flag, Dirt Dagger, Air Axe\r\nOrder: 1st, 2nd, 3rd, 4th, 5th\r\n5 Reasons Why: Big reward if wins, it killed his sister, personal ambition, cocky, bored\n\r\nCan you find out which God fought which minion where, when, how, why and with what weapon?\n\r\nClues:\r\n1) Loki did not fight the Right Ear, but did use the Dagger.\r\n2) Ra fought two behind Thor.\r\n3) The one who fought the Left Foot fought last.\r\n4) The one who fought the Center Eye, who was there because he was cocky, didn't use the Water Whip.\r\n5) The Pike user fought with the Second Nose first.\r\n6) The last person to fight fought for a large reward.\r\n7) Apophis fought with the Axe for personal ambition.\r\n8) The Center Eye was fought by Ra.\r\n9) The Right Ear was defeated by a bored person.\r\n10) The Second Nose was attacked by someone to avenge the death of their sister.\r\n11) Apophis fought the Mouth, and he went right after Ra.\r\n12) Thor fought the second nose.", "hint": "No hint available.", "answer": "Thor, 2nd Nose, Plasma Pike, 1, it killed his sister\r\nZeus, Right Ear, Water Whip, 2, bored\r\nRa, Center Eye, Fire Flag, 3, cocky\r\nApophis, 3rd Mouth, Air Axe, 4, personal ambition\r\nLoki, Left Foot, Dirt Dagger, 5, big reward in future", "category": "Logic-Grid", "date": "05/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was once a massive evil being, hundreds of feet tall, and so grand that it took Gods from all over the world to just defeat him, after defeating his minions. You can see how those battles went in \"Battles For the Gods\". Today they are prepared to attack the grand evil being face to face. The weak point would be attacked by whoever wanted to, and the weapon would be used by whoever could use it best. Each went one after the other, depending what needed to be taken out first. Also, each one had their own reasons for participating in the fight.\n\r\nThere were:\n\r\n5 Gods: Thor, Zeus, Ra, Apophis and Loki\r\n5 Weak Points: Center Eye, 2nd Nose, Right Ear, 3rd Mouth and Left Foot\r\n5 Weapons: Plasma Pike, Water Whip, Fire Flag, Dirt Dagger, Air Axe\r\nOrder: 1st, 2nd, 3rd, 4th, 5th\r\n5 Reasons Why: Big reward if wins, it killed his sister, personal ambition, cocky, bored\n\r\nCan you find out which God fought which minion where, when, how, why and with what weapon?\n\r\nClues:\r\n1) Loki did not fight the Right Ear, but did use the Dagger.\r\n2) Ra fought two behind Thor.\r\n3) The one who fought the Left Foot fought last.\r\n4) The one who fought the Center Eye, who was there because he was cocky, didn't use the Water Whip.\r\n5) The Pike user fought with the Second Nose first.\r\n6) The last person to fight fought for a large reward.\r\n7) Apophis fought with the Axe for personal ambition.\r\n8) The Center Eye was fought by Ra.\r\n9) The Right Ear was defeated by a bored person.\r\n10) The Second Nose was attacked by someone to avenge the death of their sister.\r\n11) Apophis fought the Mouth, and he went right after Ra.\r\n12) Thor fought the second nose.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThor, 2nd Nose, Plasma Pike, 1, it killed his sister\r\nZeus, Right Ear, Water Whip, 2, bored\r\nRa, Center Eye, Fire Flag, 3, cocky\r\nApophis, 3rd Mouth, Air Axe, 4, personal ambition\r\nLoki, Left Foot, Dirt Dagger, 5, big reward in future\n<|im_start|>answer\nThor, 2nd Nose, Plasma Pike, 1, it killed his sister\r\nZeus, Right Ear, Water Whip, 2, bored\r\nRa, Center Eye, Fire Flag, 3, cocky\r\nApophis, 3rd Mouth, Air Axe, 4, personal ambition\r\nLoki, Left Foot, Dirt Dagger, 5, big reward in future\n<|im_end|>" }, { "id": "#32240", "title": "Which Bottle?", "fun": 2.99, "difficulty": 2.35, "author": "medster99", "desc": "You are stuck in a room. All that is there is a slip of paper on a table, and many bottles. The only exit is guarded by a heat sensor that will not let you out. The only way out is to drink one of the bottles' contents, and the liquid will cool down your body heat (with no harm to yourself) enough so that the heat sensor doesn't detect you anymore. There are nine bottles on the ground beyond the table. The content of the slip of paper will tell you what each of the bottles are. Find out what all the bottles are, and then find out which one to drink to get out.\n\r\nThree of me are poison, and will kill you if you drink.\r\nTwo of me are water, nothing bad will happen with these.\r\nTwo of me are wine, and it will only get you drunk.\r\nOne will heat you up forever, and this room will never let you out. (hinder)\r\nOnly one here will help you, it will cool down your body heat.\r\nNo medium bottles are poison.\r\nWine is bad in large doses, so none are large.\r\nEach of the end bottles have the same contents.\r\nNo matter how help hides, it will be on poison's left side, but its left side is safe.\r\nNo two small bottles are the same.\r\nThe hinderer is harder, for it resides between wine and water.\r\nThe hinder bottle is large, so it works forever.\r\nNeither big nor medium will save your life.\r\nPoison is all you will get from the bottle on the far right.\r\nWater is next to the helper.\n\r\nBottle Order:\r\nLarge--Small--Large--Medium--Small--Large--Medium--Large--Small", "hint": "No hint available.", "answer": "Poison--wine--hinder--water--help--poison--wine--water--poison\r\nOnly the middle bottle will save your life.", "category": "Logic", "date": "08/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are stuck in a room. All that is there is a slip of paper on a table, and many bottles. The only exit is guarded by a heat sensor that will not let you out. The only way out is to drink one of the bottles' contents, and the liquid will cool down your body heat (with no harm to yourself) enough so that the heat sensor doesn't detect you anymore. There are nine bottles on the ground beyond the table. The content of the slip of paper will tell you what each of the bottles are. Find out what all the bottles are, and then find out which one to drink to get out.\n\r\nThree of me are poison, and will kill you if you drink.\r\nTwo of me are water, nothing bad will happen with these.\r\nTwo of me are wine, and it will only get you drunk.\r\nOne will heat you up forever, and this room will never let you out. (hinder)\r\nOnly one here will help you, it will cool down your body heat.\r\nNo medium bottles are poison.\r\nWine is bad in large doses, so none are large.\r\nEach of the end bottles have the same contents.\r\nNo matter how help hides, it will be on poison's left side, but its left side is safe.\r\nNo two small bottles are the same.\r\nThe hinderer is harder, for it resides between wine and water.\r\nThe hinder bottle is large, so it works forever.\r\nNeither big nor medium will save your life.\r\nPoison is all you will get from the bottle on the far right.\r\nWater is next to the helper.\n\r\nBottle Order:\r\nLarge--Small--Large--Medium--Small--Large--Medium--Large--Small\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPoison--wine--hinder--water--help--poison--wine--water--poison\r\nOnly the middle bottle will save your life.\n<|im_start|>answer\nPoison--wine--hinder--water--help--poison--wine--water--poison\r\nOnly the middle bottle will save your life.\n<|im_end|>" }, { "id": "#39000", "title": "Vacation!", "fun": 2.99, "difficulty": 2.15, "author": "grilledcheese", "desc": "A vacationing family sitting around the campfire has the following conversation: \n\r\n1. Father: What day is it? I am sure it isn't Tuesday, Wednesday or Thursday. \r\n2. Mother: Well that's not very helpful dear. Besides yesterday was Friday. \r\n3. Father: No, now that I think about it, yesterday wasn't Friday, tomorrow is Friday. \r\n4. Jon: The day after tomorrow is Thursday. \r\n5. Meg: You are nuts. Tomorrow is Thursday. \r\n6. Mother: Actually, it's probably Thursday today. \r\n7. Jon: All we know for sure is that it wasn't Sunday yesterday. \n\r\nIf only one statement above is true, what day of the week is it?", "hint": "No hint available.", "answer": "Number each person's statement and write down the list of days that it could be according to each statement.\n\r\n1. Monday, Friday, Saturday, Sunday \r\n2. Saturday \r\n3. Thursday \r\n4. Tuesday \r\n5. Wednesday \r\n6. Thursday \r\n7. Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday \n\r\nThe only day mentioned one time is Monday. Therefore it must be Monday, otherwise one of the other statements would be true.", "category": "Logic", "date": "10/29/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA vacationing family sitting around the campfire has the following conversation: \n\r\n1. Father: What day is it? I am sure it isn't Tuesday, Wednesday or Thursday. \r\n2. Mother: Well that's not very helpful dear. Besides yesterday was Friday. \r\n3. Father: No, now that I think about it, yesterday wasn't Friday, tomorrow is Friday. \r\n4. Jon: The day after tomorrow is Thursday. \r\n5. Meg: You are nuts. Tomorrow is Thursday. \r\n6. Mother: Actually, it's probably Thursday today. \r\n7. Jon: All we know for sure is that it wasn't Sunday yesterday. \n\r\nIf only one statement above is true, what day of the week is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNumber each person's statement and write down the list of days that it could be according to each statement.\n\r\n1. Monday, Friday, Saturday, Sunday \r\n2. Saturday \r\n3. Thursday \r\n4. Tuesday \r\n5. Wednesday \r\n6. Thursday \r\n7. Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday \n\r\nThe only day mentioned one time is Monday. Therefore it must be Monday, otherwise one of the other statements would be true.\n<|im_start|>answer\nNumber each person's statement and write down the list of days that it could be according to each statement.\n\r\n1. Monday, Friday, Saturday, Sunday \r\n2. Saturday \r\n3. Thursday \r\n4. Tuesday \r\n5. Wednesday \r\n6. Thursday \r\n7. Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday \n\r\nThe only day mentioned one time is Monday. Therefore it must be Monday, otherwise one of the other statements would be true.\n<|im_end|>" }, { "id": "#43340", "title": "At the Movies", "fun": 2.99, "difficulty": 2.42, "author": "whsprec", "desc": "Chris is a movie nut. There are 5 movie theaters in town. They are on 1st St., 2nd St., 3rd St., 4th St., and 5th St.. Chris went to a different theater each night for a week and saw a different movie. The films starred Julia Roberts, Angelina Jolie, Ashley Judd, Drew Barrymore, and Sharon Stone. The films were a drama, comedy, western, thriller, or mystery. From the clues given, determine the star, the theater, the genre, and the night on which Chris saw each film.\n\r\n1. He did not see the western first, but he saw it before the Drew Barrymore film, which he saw before the movie on 5th St.\r\n2. Neither Julia Roberts nor Ashley Judd played in the comedy, but one of them was in the film at 1st St.\r\n3. He saw the Ashley Judd film before the mystery, but after the drama.\r\n4. The films at 3rd St. and 4th St. were not the Angelina Jolie movie or the Sharon Stone western.\r\n5. The mystery starred Angelina Jolie. \r\n6. He saw the comedy before the thriller but after the film at 3rd St.", "hint": "No hint available.", "answer": "Monday- Julia Roberts, Drama at 3rd St.\r\nTuesday- Sharon Stone, Western at 2nd St.\r\nWednesday- Drew Barrymore, Comedy at 4th St.\r\nThursday- Ashley Judd, Thriller at 1st St.\r\nFriday- Angelina Jolie, Mystery at 5th St.", "category": "Logic-Grid", "date": "10/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChris is a movie nut. There are 5 movie theaters in town. They are on 1st St., 2nd St., 3rd St., 4th St., and 5th St.. Chris went to a different theater each night for a week and saw a different movie. The films starred Julia Roberts, Angelina Jolie, Ashley Judd, Drew Barrymore, and Sharon Stone. The films were a drama, comedy, western, thriller, or mystery. From the clues given, determine the star, the theater, the genre, and the night on which Chris saw each film.\n\r\n1. He did not see the western first, but he saw it before the Drew Barrymore film, which he saw before the movie on 5th St.\r\n2. Neither Julia Roberts nor Ashley Judd played in the comedy, but one of them was in the film at 1st St.\r\n3. He saw the Ashley Judd film before the mystery, but after the drama.\r\n4. The films at 3rd St. and 4th St. were not the Angelina Jolie movie or the Sharon Stone western.\r\n5. The mystery starred Angelina Jolie. \r\n6. He saw the comedy before the thriller but after the film at 3rd St.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday- Julia Roberts, Drama at 3rd St.\r\nTuesday- Sharon Stone, Western at 2nd St.\r\nWednesday- Drew Barrymore, Comedy at 4th St.\r\nThursday- Ashley Judd, Thriller at 1st St.\r\nFriday- Angelina Jolie, Mystery at 5th St.\n<|im_start|>answer\nMonday- Julia Roberts, Drama at 3rd St.\r\nTuesday- Sharon Stone, Western at 2nd St.\r\nWednesday- Drew Barrymore, Comedy at 4th St.\r\nThursday- Ashley Judd, Thriller at 1st St.\r\nFriday- Angelina Jolie, Mystery at 5th St.\n<|im_end|>" }, { "id": "#23784", "title": "Shopping Time!", "fun": 2.99, "difficulty": 1.49, "author": "DennysGirl", "desc": "Five friends went shopping at different times, days, and at different places. Who went shopping at what place, and what time, and what day?\r\nThe boys are Darien and Dennis; the girls are Mina, Amy, and Serena.\n\r\nclues:\n\r\n1) Serena doesn't wake up until after noon, and she went somewhere to eat.\r\n2) The toy shopper went on Saturday.\r\n3) Mina went shopping on Monday\r\n4) None of the girls shopped at the bike shop.\r\n5) Dennis did not go out for food.\r\n6) Amy went at 10 AM.\r\n7) Dennis and the cafe shopper went on the weekend.\r\n8) The person who went to the cafe, went after noon.\r\n9) Friday was a busy morning at the grocery store for the girl who shopped there.\r\n10) The person went to the bakery right when it opened, which was at 9:30 AM.\r\n11) The toy shopper went shopping at noon.\r\n12) Mina went earlier in the day than Amy, and Serena went earlier than Darien.", "hint": "No hint available.", "answer": "1) Serena doesn't wake up until after noon (Which means she did not go out anytime before noon or at noon), and she went somewhere to eat (So she didn't go to the bike shop or the toy store.).\r\n2) The toy shopper went on Saturday (And since we know that Serena isn't the toy shopper, she didn't go on Saturday.).\r\n3) Mina went shopping on Monday (Which means she's not the toy shopper.).\r\n4) None of the girls shopped at the bike shop (That leaves only the boys.).\r\n7) Dennis and the cafe shopper went on the weekend (The cafe shopper went on Sunday, which means Dennis went on Saturday. The toy shopper went on Saturday, so the person is Dennis. This leaves Darien to be the only one to go to the bike shop.).\r\n9) Friday was a busy morning at the grocery store for the girl who shopped there(Morning.).\r\n11) The toy shopper went shopping at noon (Here, we find out that the grocery shopper went at 10 AM, which was Amy.).\r\n12) Mina went earlier in the day than Amy (The only possible answer is 9:30 AM), and Serena went earlier than Darien (Serena went at 1:30 and Darien went at 3 PM. The cafe person went at 1:30-Serena, and she went on Sunday. Amy went to the grocery store, which leaves Mina at the bakery.).\n\r\nSerena/Cafe/Sunday/1:30 PM\r\nDarien/Bike/Wednesday/3 PM\r\nAmy/Grocery/Friday/10 AM\r\nMina/Bakery/Monday/9:30 AM\r\nDennis/Toys/Saturday/Noon", "category": "Logic-Grid", "date": "06/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends went shopping at different times, days, and at different places. Who went shopping at what place, and what time, and what day?\r\nThe boys are Darien and Dennis; the girls are Mina, Amy, and Serena.\n\r\nclues:\n\r\n1) Serena doesn't wake up until after noon, and she went somewhere to eat.\r\n2) The toy shopper went on Saturday.\r\n3) Mina went shopping on Monday\r\n4) None of the girls shopped at the bike shop.\r\n5) Dennis did not go out for food.\r\n6) Amy went at 10 AM.\r\n7) Dennis and the cafe shopper went on the weekend.\r\n8) The person who went to the cafe, went after noon.\r\n9) Friday was a busy morning at the grocery store for the girl who shopped there.\r\n10) The person went to the bakery right when it opened, which was at 9:30 AM.\r\n11) The toy shopper went shopping at noon.\r\n12) Mina went earlier in the day than Amy, and Serena went earlier than Darien.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Serena doesn't wake up until after noon (Which means she did not go out anytime before noon or at noon), and she went somewhere to eat (So she didn't go to the bike shop or the toy store.).\r\n2) The toy shopper went on Saturday (And since we know that Serena isn't the toy shopper, she didn't go on Saturday.).\r\n3) Mina went shopping on Monday (Which means she's not the toy shopper.).\r\n4) None of the girls shopped at the bike shop (That leaves only the boys.).\r\n7) Dennis and the cafe shopper went on the weekend (The cafe shopper went on Sunday, which means Dennis went on Saturday. The toy shopper went on Saturday, so the person is Dennis. This leaves Darien to be the only one to go to the bike shop.).\r\n9) Friday was a busy morning at the grocery store for the girl who shopped there(Morning.).\r\n11) The toy shopper went shopping at noon (Here, we find out that the grocery shopper went at 10 AM, which was Amy.).\r\n12) Mina went earlier in the day than Amy (The only possible answer is 9:30 AM), and Serena went earlier than Darien (Serena went at 1:30 and Darien went at 3 PM. The cafe person went at 1:30-Serena, and she went on Sunday. Amy went to the grocery store, which leaves Mina at the bakery.).\n\r\nSerena/Cafe/Sunday/1:30 PM\r\nDarien/Bike/Wednesday/3 PM\r\nAmy/Grocery/Friday/10 AM\r\nMina/Bakery/Monday/9:30 AM\r\nDennis/Toys/Saturday/Noon\n<|im_start|>answer\n1) Serena doesn't wake up until after noon (Which means she did not go out anytime before noon or at noon), and she went somewhere to eat (So she didn't go to the bike shop or the toy store.).\r\n2) The toy shopper went on Saturday (And since we know that Serena isn't the toy shopper, she didn't go on Saturday.).\r\n3) Mina went shopping on Monday (Which means she's not the toy shopper.).\r\n4) None of the girls shopped at the bike shop (That leaves only the boys.).\r\n7) Dennis and the cafe shopper went on the weekend (The cafe shopper went on Sunday, which means Dennis went on Saturday. The toy shopper went on Saturday, so the person is Dennis. This leaves Darien to be the only one to go to the bike shop.).\r\n9) Friday was a busy morning at the grocery store for the girl who shopped there(Morning.).\r\n11) The toy shopper went shopping at noon (Here, we find out that the grocery shopper went at 10 AM, which was Amy.).\r\n12) Mina went earlier in the day than Amy (The only possible answer is 9:30 AM), and Serena went earlier than Darien (Serena went at 1:30 and Darien went at 3 PM. The cafe person went at 1:30-Serena, and she went on Sunday. Amy went to the grocery store, which leaves Mina at the bakery.).\n\r\nSerena/Cafe/Sunday/1:30 PM\r\nDarien/Bike/Wednesday/3 PM\r\nAmy/Grocery/Friday/10 AM\r\nMina/Bakery/Monday/9:30 AM\r\nDennis/Toys/Saturday/Noon\n<|im_end|>" }, { "id": "#33997", "title": "Camp Curatos", "fun": 2.99, "difficulty": 1.95, "author": "Winner4600", "desc": "Far off in the heart of the Rocky Mountains, there is a place called Camp Curatos. No, it is not named after some random tribe; rather, it is a camp dedicated to curing teens of all ages of bad and childish habits. Recently, the camp advisors have taken on five new challenges (3 boys - Mark, Joseph, and Kev; and 2 girls - Selene and Ariadne). However, in their files, the advisors seem to have gotten a few facts mixed up about these five teens! Can you help them piece together the facts?\n\r\n1. The 5 teens are Joseph, the 12-year-old, the pencil-snapper, the procrastinator, and the one rewarded with ice cream.\n\r\n2. Selene is one year younger than the procrastinator.\n\r\n3. The pencil-snapper left after the shortest amount of time; he was rewarded with a Chevy (which he was able to drive).\n\r\n4. Ariadne is not the oldest; however, she did take the longest time to leave Camp Curatos.\n\r\n5. The 15-year-old took 23 days to be cured of his nail-chewing habit.\n\r\n6. Mark received $20; CDs were sent to Joseph.\n\r\n7. The 12-year-old spent 3 weeks in camp, but it was well worth his time, for he could now pay attention in class without fidgeting.", "hint": "No hint available.", "answer": "NAME - AGE - HABIT - TIME - REWARD\r\nMark - 12 - Fidgeting - 3 weeks - $20\r\nJoseph - 15 - Chewing Nails - 23 days - CDs\r\nSelene - 13 - Sucking Thumb - 17 days - Ice Cream\r\nAriadne - 14 - Procrastinating - 1 month - Cruise Trip\r\nKev - 17 - Snapping Pencils - 2 weeks - Car\n\r\nCongratulations! You have successfully helped the advisors and saved them from months of worry and nervous breakdowns. Give yourself a pat on the back - you should be proud of yourself!", "category": "Logic-Grid", "date": "11/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFar off in the heart of the Rocky Mountains, there is a place called Camp Curatos. No, it is not named after some random tribe; rather, it is a camp dedicated to curing teens of all ages of bad and childish habits. Recently, the camp advisors have taken on five new challenges (3 boys - Mark, Joseph, and Kev; and 2 girls - Selene and Ariadne). However, in their files, the advisors seem to have gotten a few facts mixed up about these five teens! Can you help them piece together the facts?\n\r\n1. The 5 teens are Joseph, the 12-year-old, the pencil-snapper, the procrastinator, and the one rewarded with ice cream.\n\r\n2. Selene is one year younger than the procrastinator.\n\r\n3. The pencil-snapper left after the shortest amount of time; he was rewarded with a Chevy (which he was able to drive).\n\r\n4. Ariadne is not the oldest; however, she did take the longest time to leave Camp Curatos.\n\r\n5. The 15-year-old took 23 days to be cured of his nail-chewing habit.\n\r\n6. Mark received $20; CDs were sent to Joseph.\n\r\n7. The 12-year-old spent 3 weeks in camp, but it was well worth his time, for he could now pay attention in class without fidgeting.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNAME - AGE - HABIT - TIME - REWARD\r\nMark - 12 - Fidgeting - 3 weeks - $20\r\nJoseph - 15 - Chewing Nails - 23 days - CDs\r\nSelene - 13 - Sucking Thumb - 17 days - Ice Cream\r\nAriadne - 14 - Procrastinating - 1 month - Cruise Trip\r\nKev - 17 - Snapping Pencils - 2 weeks - Car\n\r\nCongratulations! You have successfully helped the advisors and saved them from months of worry and nervous breakdowns. Give yourself a pat on the back - you should be proud of yourself!\n<|im_start|>answer\nNAME - AGE - HABIT - TIME - REWARD\r\nMark - 12 - Fidgeting - 3 weeks - $20\r\nJoseph - 15 - Chewing Nails - 23 days - CDs\r\nSelene - 13 - Sucking Thumb - 17 days - Ice Cream\r\nAriadne - 14 - Procrastinating - 1 month - Cruise Trip\r\nKev - 17 - Snapping Pencils - 2 weeks - Car\n\r\nCongratulations! You have successfully helped the advisors and saved them from months of worry and nervous breakdowns. Give yourself a pat on the back - you should be proud of yourself!\n<|im_end|>" }, { "id": "#49902", "title": "Pete'sa Pete's Pizza Prices", "fun": 2.99, "difficulty": 0.71, "author": "fishmed", "desc": "Pete'sa Pete lists prices for his extra toppings in pairs. How much does each topping cost by itself? Each price is whole-dollar increments. \n\r\nPineapple & Hot Peppers $7\r\nBroccoli & Extra Cheese $6\r\nMushrooms & Onions $2\r\nBlack Olives & Hot Peppers $5\r\nPepperoni & Mushrooms $4\r\nOnions & Black Olives $3\r\nExtra Cheese & Mushrooms $5", "hint": "No hint available.", "answer": "From the list above and the note about only whole-dollar amounts we note that if Mushrooms & Onions are $2 together they must be $1 each. From there it is simple math to figure out the following. \n\r\nOnions $1\r\nMushrooms $1\r\nPepperoni $3\r\nBlack Olives $2\r\nExtra Cheese $4\r\nBroccoli $2\r\nHot Peppers $3\r\nPineapple $4", "category": "Logic", "date": "08/06/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPete'sa Pete lists prices for his extra toppings in pairs. How much does each topping cost by itself? Each price is whole-dollar increments. \n\r\nPineapple & Hot Peppers $7\r\nBroccoli & Extra Cheese $6\r\nMushrooms & Onions $2\r\nBlack Olives & Hot Peppers $5\r\nPepperoni & Mushrooms $4\r\nOnions & Black Olives $3\r\nExtra Cheese & Mushrooms $5\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom the list above and the note about only whole-dollar amounts we note that if Mushrooms & Onions are $2 together they must be $1 each. From there it is simple math to figure out the following. \n\r\nOnions $1\r\nMushrooms $1\r\nPepperoni $3\r\nBlack Olives $2\r\nExtra Cheese $4\r\nBroccoli $2\r\nHot Peppers $3\r\nPineapple $4\n<|im_start|>answer\nFrom the list above and the note about only whole-dollar amounts we note that if Mushrooms & Onions are $2 together they must be $1 each. From there it is simple math to figure out the following. \n\r\nOnions $1\r\nMushrooms $1\r\nPepperoni $3\r\nBlack Olives $2\r\nExtra Cheese $4\r\nBroccoli $2\r\nHot Peppers $3\r\nPineapple $4\n<|im_end|>" }, { "id": "#40728", "title": "Four Girls", "fun": 2.99, "difficulty": 2.29, "author": "Carlos16", "desc": "A man escapes from jail with help from his girlfriend. Four girls are accused of being the man's girlfriend. His girlfriend is lying. Two girls are innocent and telling the truth. The other girl is the man's sister who is helping the girlfriend lie. Who is the man's sister?\n\r\nAmanda: \"Melinda is his girlfriend.\"\r\nVanessa: \"Eva is lying.\"\r\nEva: \"Amanda is lying.\"\r\nMelinda: \"Vanessa is not his sister.\"", "hint": "No hint available.", "answer": "If Amanda is telling the truth, then Melinda is lying. If Melinda is lying, then Vanessa is his sister. If Vanessa is his sister, then she's lying about Eva lying. If Eva isn't lying, then Amanda is lying, which would contradict the fact that Amanda's telling the truth. That means Amanda is lying and could be his girlfriend or sister.\r\nEva must be telling the truth since Amanda has to be lying. So Vanessa must also be lying, and Melinda is telling the truth. Since Melinda's telling the truth, Vanessa isn't his sister and must be his girlfriend. Amanda is the other liar, so she must be his sister.\n\r\nAnswer: Amanda", "category": "Logic", "date": "02/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man escapes from jail with help from his girlfriend. Four girls are accused of being the man's girlfriend. His girlfriend is lying. Two girls are innocent and telling the truth. The other girl is the man's sister who is helping the girlfriend lie. Who is the man's sister?\n\r\nAmanda: \"Melinda is his girlfriend.\"\r\nVanessa: \"Eva is lying.\"\r\nEva: \"Amanda is lying.\"\r\nMelinda: \"Vanessa is not his sister.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Amanda is telling the truth, then Melinda is lying. If Melinda is lying, then Vanessa is his sister. If Vanessa is his sister, then she's lying about Eva lying. If Eva isn't lying, then Amanda is lying, which would contradict the fact that Amanda's telling the truth. That means Amanda is lying and could be his girlfriend or sister.\r\nEva must be telling the truth since Amanda has to be lying. So Vanessa must also be lying, and Melinda is telling the truth. Since Melinda's telling the truth, Vanessa isn't his sister and must be his girlfriend. Amanda is the other liar, so she must be his sister.\n\r\nAnswer: Amanda\n<|im_start|>answer\nIf Amanda is telling the truth, then Melinda is lying. If Melinda is lying, then Vanessa is his sister. If Vanessa is his sister, then she's lying about Eva lying. If Eva isn't lying, then Amanda is lying, which would contradict the fact that Amanda's telling the truth. That means Amanda is lying and could be his girlfriend or sister.\r\nEva must be telling the truth since Amanda has to be lying. So Vanessa must also be lying, and Melinda is telling the truth. Since Melinda's telling the truth, Vanessa isn't his sister and must be his girlfriend. Amanda is the other liar, so she must be his sister.\n\r\nAnswer: Amanda\n<|im_end|>" }, { "id": "#28646", "title": "Number Tricks", "fun": 2.99, "difficulty": 1.94, "author": "____", "desc": "Ms. Arroyo asked the class to see if they could find the sum of the first 50 odd numbers. As everyone settled down to their addition, Terry ran to her and said, \"The sum is 2,500.\" Ms. Arroyo thought, \"Lucky guess,\" and gave him the task of finding the sum of the first 75 odd numbers. Within 20 seconds, Terry was back with the correct answer of 5,625.\n\r\nHow does Terry find the sum so quickly?", "hint": "Consecutive odd numbers are 1, 3, 5, 7....\r\nStart with the first several odd numbers and look for a pattern.", "answer": "The following pattern holds: The sum is equal to n x n, when n is the number of consecutive odd numbers, starting with 1. For example, the sum of the first 3 odd numbers is equal to 3 x 3, or 9; the sum of the first 4 odd numbers is equal to 4 x 4, or 16; the sum of the first 5 odd numbers is equal to 5 x 5, or 25; and so on.", "category": "Math", "date": "02/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Arroyo asked the class to see if they could find the sum of the first 50 odd numbers. As everyone settled down to their addition, Terry ran to her and said, \"The sum is 2,500.\" Ms. Arroyo thought, \"Lucky guess,\" and gave him the task of finding the sum of the first 75 odd numbers. Within 20 seconds, Terry was back with the correct answer of 5,625.\n\r\nHow does Terry find the sum so quickly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe following pattern holds: The sum is equal to n x n, when n is the number of consecutive odd numbers, starting with 1. For example, the sum of the first 3 odd numbers is equal to 3 x 3, or 9; the sum of the first 4 odd numbers is equal to 4 x 4, or 16; the sum of the first 5 odd numbers is equal to 5 x 5, or 25; and so on.\n<|im_start|>answer\nThe following pattern holds: The sum is equal to n x n, when n is the number of consecutive odd numbers, starting with 1. For example, the sum of the first 3 odd numbers is equal to 3 x 3, or 9; the sum of the first 4 odd numbers is equal to 4 x 4, or 16; the sum of the first 5 odd numbers is equal to 5 x 5, or 25; and so on.\n<|im_end|>" }, { "id": "#46325", "title": "Executive Travel Woes", "fun": 2.99, "difficulty": 3.33, "author": "caberet", "desc": "Ms. Langston and four other executives are experiencing the downturn in the economy. While traveling on Wednesday of last week, they had to fly on commercial aircraft instead of enjoying the comfort of private jets. Each executive is an expert in a particular area of business. Use the following clues to determine the first and last name of each executive along with her position, company and her special expertise. No two executives share the same name, position, company or forte.\n\r\nFirst Names: Ann, Arlice, Meg, Patricia, Rene\r\nLast Names: Barnes, Langston, Mulcahy, Russo, Whitman\r\nPositions: Chief Executive Officer (CEO), Chief Financial Officer (CFO), Chairperson, Commissioner, President\r\nCompanies: ieTrade, Lenamar Tech, Licent Co., Sabancci Ltd., The Surat Group\r\nFortes: Invention, Leadership, Political Connections, Profit Margin, Stock Options\n\r\n1.\tNeither the CEO (who is not the leadership guru) nor the one with the excellent political connections (who is not a CFO or with Licent Co.) is surnamed Russo (who is neither Patricia nor Rene.) \n\r\n2.\tBoth Ann and Ms. Langston boarded in San Francisco and deplaned in Chicago; the leadership specialist and the chairperson flew from Chicago to Washington, D.C.; the flight of the Sabancci Ltd. executive (who is not surnamed Mulcahy) was from D.C. to New York. \n\r\n3.\tThe Lenamar Tech. executive (who has no special political connections) and the inventor (who is neither CEO nor CFO) are either the commissioner and chairperson in some order, or are surnamed Russo and Barnes, in some order; only one of these alternatives is true, the other is false.\n\r\n4.\tArlice is neither the ieTrade CFO nor Ms. Barnes; the profit margin specialist is not amongst the three executives.\n\r\n5.\tNeither Meg (who is neither the stock options specialist nor the inventor) nor Ms. Mulcahy (who is not Arlice, who is not the chairperson) is affiliated with either Licent Co. or The Surat Group (who is not Rene). \n\r\n6.\tOf the CEO (who is not Ms. Russo) and the profit margin specialist (who is not Rene, who is not the chairperson), one is Ms. Whitman and the other is associated with Lenamar Tech (who is not Ann). \n\r\n7.\tThe stock option specialist is either Ms. Barnes or the executive that works with Sabancci Ltd. (who is neither Patricia, who is not the commissioner, nor Rene.)\n\r\n8.\tThe president (who is not with Sabancci Ltd.) is not the inventor (who is neither surnamed Whitman nor Barnes.) Ms. Barnes is not the leadership guru.\n\r\n9.\tThe Surat Group executive is neither surnamed Langston nor Whitman.", "hint": "The inventor must be the chairperson or the commissioner (not CEO or CFO from clue 3 or president from clue 8.) Clue 3 tells us that the inventor cannot be either Ms. Russo or Ms. Barnes. This also means that the Lenamar Tech. executive also is not surnamed either Russo or Barnes, and that the commissioner and the chairperson cannot be either Russo or Barnes.\n\r\nMs. Barnes must be Ann because she does not fit into any of the other options in clue 2. \n\r\nThe Sabancci executive (who can only be CEO or Commissioner) is not Ms. Russo who can only be! CFO or President. As you fill in the grid, you will see that the person with Sabannci ( who can only be Arlice or Meg) cannot be Ms. Mulcahy (who can only be Patricia or Rene.)\n\r\nMs. Surat cannot be commissioner or chairperson because she only can be surnamed Barnes or Russo, but commissioner and chairperson can't be either of those two surnames.\n\r\nOnce we discover that the inventor is the Commissioner, we know that the Lenamar executive must be Chairperson and the rest of the answers fall into place.", "answer": "First, Last, Position, Company, Forte\r\nRene, Langston, Commissioner, Licent Co., Invention\r\nArlice, Whitman, CEO, Sabancci Ltd., Stock Options\r\nMeg, Russo, CFO, ieTrade, Leadership\r\nAnn, Barnes, President, Surat Group, Political Connections\r\nPatricia, Mulcahy, Chairperson, Lenamar Tech., Profit Margin", "category": "Logic-Grid", "date": "02/06/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Langston and four other executives are experiencing the downturn in the economy. While traveling on Wednesday of last week, they had to fly on commercial aircraft instead of enjoying the comfort of private jets. Each executive is an expert in a particular area of business. Use the following clues to determine the first and last name of each executive along with her position, company and her special expertise. No two executives share the same name, position, company or forte.\n\r\nFirst Names: Ann, Arlice, Meg, Patricia, Rene\r\nLast Names: Barnes, Langston, Mulcahy, Russo, Whitman\r\nPositions: Chief Executive Officer (CEO), Chief Financial Officer (CFO), Chairperson, Commissioner, President\r\nCompanies: ieTrade, Lenamar Tech, Licent Co., Sabancci Ltd., The Surat Group\r\nFortes: Invention, Leadership, Political Connections, Profit Margin, Stock Options\n\r\n1.\tNeither the CEO (who is not the leadership guru) nor the one with the excellent political connections (who is not a CFO or with Licent Co.) is surnamed Russo (who is neither Patricia nor Rene.) \n\r\n2.\tBoth Ann and Ms. Langston boarded in San Francisco and deplaned in Chicago; the leadership specialist and the chairperson flew from Chicago to Washington, D.C.; the flight of the Sabancci Ltd. executive (who is not surnamed Mulcahy) was from D.C. to New York. \n\r\n3.\tThe Lenamar Tech. executive (who has no special political connections) and the inventor (who is neither CEO nor CFO) are either the commissioner and chairperson in some order, or are surnamed Russo and Barnes, in some order; only one of these alternatives is true, the other is false.\n\r\n4.\tArlice is neither the ieTrade CFO nor Ms. Barnes; the profit margin specialist is not amongst the three executives.\n\r\n5.\tNeither Meg (who is neither the stock options specialist nor the inventor) nor Ms. Mulcahy (who is not Arlice, who is not the chairperson) is affiliated with either Licent Co. or The Surat Group (who is not Rene). \n\r\n6.\tOf the CEO (who is not Ms. Russo) and the profit margin specialist (who is not Rene, who is not the chairperson), one is Ms. Whitman and the other is associated with Lenamar Tech (who is not Ann). \n\r\n7.\tThe stock option specialist is either Ms. Barnes or the executive that works with Sabancci Ltd. (who is neither Patricia, who is not the commissioner, nor Rene.)\n\r\n8.\tThe president (who is not with Sabancci Ltd.) is not the inventor (who is neither surnamed Whitman nor Barnes.) Ms. Barnes is not the leadership guru.\n\r\n9.\tThe Surat Group executive is neither surnamed Langston nor Whitman.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, Last, Position, Company, Forte\r\nRene, Langston, Commissioner, Licent Co., Invention\r\nArlice, Whitman, CEO, Sabancci Ltd., Stock Options\r\nMeg, Russo, CFO, ieTrade, Leadership\r\nAnn, Barnes, President, Surat Group, Political Connections\r\nPatricia, Mulcahy, Chairperson, Lenamar Tech., Profit Margin\n<|im_start|>answer\nFirst, Last, Position, Company, Forte\r\nRene, Langston, Commissioner, Licent Co., Invention\r\nArlice, Whitman, CEO, Sabancci Ltd., Stock Options\r\nMeg, Russo, CFO, ieTrade, Leadership\r\nAnn, Barnes, President, Surat Group, Political Connections\r\nPatricia, Mulcahy, Chairperson, Lenamar Tech., Profit Margin\n<|im_end|>" }, { "id": "#37730", "title": "Happy Halloween", "fun": 2.99, "difficulty": 1.66, "author": "dreamlvr1432", "desc": "5 friends went trick-or-treating together for Halloween, but they soon got tired and went home at some point along the way. The next morning, the friends met up to exchange candy, so each could have their favorites. Can you figure out who wore what costume, in what order they left the group, and what each friend's favorite candy is?\n\r\nFRIENDS: Andy, Jane, Max, Pam, Sam\r\nCOSTUMES: witch, vampire, devil, cat, skeleton\r\nCANDY: Reese's, M&M's, Snickers, Starburst, Milky Way\n\r\n1) The 5 friends are Max, the witch, the girl who likes Starburst, the boy who dressed as a devil, and the person who left the group 3rd.\n\r\n2) Andy (who does not like Milky Way) left sometime after Max and immediately before Sam.\n\r\n3) Pam likes Starburst and she left after Sam.\n\r\n4) The friends left the group in this order: the one who likes Reese's, the witch, Andy, the one who likes Milky Way, and Pam.\n\r\n5) The skeleton likes M&M's.\n\r\n6) The vampire was not last.", "hint": "No hint available.", "answer": "1) Max, Vampire, Reese's\r\n2) Jane, Witch, Snickers\r\n3) Andy, Skeleton, M&M's\r\n4) Sam, Devil, Milky Way\r\n5) Pam, Cat, Starburst", "category": "Logic-Grid", "date": "08/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 friends went trick-or-treating together for Halloween, but they soon got tired and went home at some point along the way. The next morning, the friends met up to exchange candy, so each could have their favorites. Can you figure out who wore what costume, in what order they left the group, and what each friend's favorite candy is?\n\r\nFRIENDS: Andy, Jane, Max, Pam, Sam\r\nCOSTUMES: witch, vampire, devil, cat, skeleton\r\nCANDY: Reese's, M&M's, Snickers, Starburst, Milky Way\n\r\n1) The 5 friends are Max, the witch, the girl who likes Starburst, the boy who dressed as a devil, and the person who left the group 3rd.\n\r\n2) Andy (who does not like Milky Way) left sometime after Max and immediately before Sam.\n\r\n3) Pam likes Starburst and she left after Sam.\n\r\n4) The friends left the group in this order: the one who likes Reese's, the witch, Andy, the one who likes Milky Way, and Pam.\n\r\n5) The skeleton likes M&M's.\n\r\n6) The vampire was not last.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Max, Vampire, Reese's\r\n2) Jane, Witch, Snickers\r\n3) Andy, Skeleton, M&M's\r\n4) Sam, Devil, Milky Way\r\n5) Pam, Cat, Starburst\n<|im_start|>answer\n1) Max, Vampire, Reese's\r\n2) Jane, Witch, Snickers\r\n3) Andy, Skeleton, M&M's\r\n4) Sam, Devil, Milky Way\r\n5) Pam, Cat, Starburst\n<|im_end|>" }, { "id": "#22887", "title": "Camping Trip Fun", "fun": 2.98, "difficulty": 1.39, "author": "kellgo", "desc": "Friends Phoebe and Zoe (both girls) are going on a camping trip with their guy friends Collin, Calvin, and Markus. Each person brought his or her own sleeping bag from home, each a different color (blue, red, orange, green, and yellow). When they arrive at their camping site they decide who is going to do what chore: one person is needed to start the fire; two people are needed to pitch the tents; and two people are needed to prepare the meal. After it gets dark the five friends try to out scare each other with frighteningly scary ghost stories. Each person told one story about either a vampire bat, Bigfoot, a monster, a ghost, or Captain Hook. Your job as an observer to their camping trip is to figure out which person brought which sleeping bag did what chore and told which story. Good luck and bring your own toilet paper!\n\r\nThe girls rode in their own car while the boys drove the truck with all the camping supplies in the back. The boys drove a lot faster than the girls and by the time the girls got to the campsite the tents were already up. Collin was frantically searching for the matches to light the fire but couldn't find any.\r\n\"Leave it to the boys to forget the matches,\" Phoebe whispered to Zoe, as Phoebe grabbed the lighter out of her pocket and quickly got it started.\r\nMarkus told the girls that he had put their red and yellow sleeping bags into their tent.\r\nCollin's stomach started growling and so he yelled out \"What are we going to eat?? I'm starving!\"\r\nCalvin replied, \"I've got it all under control. We're having burgers that are already on the grill.\"\r\nAfter dinner the five sat around the campfire and listened to each other tell stories. Phoebe got so scared at Markus' Captain Hook story that she hid her head under Collin's blue sleeping bag. Phoebe didn't believe her story to be just a legend she truly believed in Bigfoot and told her story with great pride. One of the guys with the orange sleeping bag loved scaring everyone with his tale of a monster that roamed the woods and preyed on unsuspecting campers. One of the meal makers told her horrible story of vampire bats while the fire starter fell asleep in their yellow sleeping bag. The owner of the green bag was so tired after having worked so hard at putting up the tents that he feel asleep as well, right in the middle of Collin's ghost story. Despite all the scary stories the five campers all fell soundly asleep from all their hard work and fun of the day.", "hint": "No hint available.", "answer": "Phoebe--yellow--start fire--Bigfoot\r\nCollin--Blue--pitch tent--ghost\r\nZoe--red--make meal--vampire bats\r\nCalvin--orange--make meal--monster\r\nMarkus--green--pitch tent--Captain Hook", "category": "Logic-Grid", "date": "05/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFriends Phoebe and Zoe (both girls) are going on a camping trip with their guy friends Collin, Calvin, and Markus. Each person brought his or her own sleeping bag from home, each a different color (blue, red, orange, green, and yellow). When they arrive at their camping site they decide who is going to do what chore: one person is needed to start the fire; two people are needed to pitch the tents; and two people are needed to prepare the meal. After it gets dark the five friends try to out scare each other with frighteningly scary ghost stories. Each person told one story about either a vampire bat, Bigfoot, a monster, a ghost, or Captain Hook. Your job as an observer to their camping trip is to figure out which person brought which sleeping bag did what chore and told which story. Good luck and bring your own toilet paper!\n\r\nThe girls rode in their own car while the boys drove the truck with all the camping supplies in the back. The boys drove a lot faster than the girls and by the time the girls got to the campsite the tents were already up. Collin was frantically searching for the matches to light the fire but couldn't find any.\r\n\"Leave it to the boys to forget the matches,\" Phoebe whispered to Zoe, as Phoebe grabbed the lighter out of her pocket and quickly got it started.\r\nMarkus told the girls that he had put their red and yellow sleeping bags into their tent.\r\nCollin's stomach started growling and so he yelled out \"What are we going to eat?? I'm starving!\"\r\nCalvin replied, \"I've got it all under control. We're having burgers that are already on the grill.\"\r\nAfter dinner the five sat around the campfire and listened to each other tell stories. Phoebe got so scared at Markus' Captain Hook story that she hid her head under Collin's blue sleeping bag. Phoebe didn't believe her story to be just a legend she truly believed in Bigfoot and told her story with great pride. One of the guys with the orange sleeping bag loved scaring everyone with his tale of a monster that roamed the woods and preyed on unsuspecting campers. One of the meal makers told her horrible story of vampire bats while the fire starter fell asleep in their yellow sleeping bag. The owner of the green bag was so tired after having worked so hard at putting up the tents that he feel asleep as well, right in the middle of Collin's ghost story. Despite all the scary stories the five campers all fell soundly asleep from all their hard work and fun of the day.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPhoebe--yellow--start fire--Bigfoot\r\nCollin--Blue--pitch tent--ghost\r\nZoe--red--make meal--vampire bats\r\nCalvin--orange--make meal--monster\r\nMarkus--green--pitch tent--Captain Hook\n<|im_start|>answer\nPhoebe--yellow--start fire--Bigfoot\r\nCollin--Blue--pitch tent--ghost\r\nZoe--red--make meal--vampire bats\r\nCalvin--orange--make meal--monster\r\nMarkus--green--pitch tent--Captain Hook\n<|im_end|>" }, { "id": "#23679", "title": "Tae Kwon Do Tournament", "fun": 2.98, "difficulty": 1.11, "author": "aymlss", "desc": "Four Tae Kwon Do students, each with a different belt rank and a different instructor, won medals in four different events at a recent tournament. Using the clues below, can you figure out the correct instructor, belt rank and event for each student?\n\r\nStudents: John, David, Janet, Katie\r\nInstructors: Master Smith, Mr. Brown, Ms. Campbell, Mr. Long\r\nStudent ranks: Black belt, blue belt, yellow belt, white belt\r\nEvents: Patterns, Sparring, Breaking, Hosin-Sul\n\r\nClues:\r\n1. David's instructor is not female.\r\n2. Neither John nor Katie is a black belt.\r\n3. The white belt won her Breaking division.\r\n4. Mr. Brown's student is a black belt.\r\n5. The Master instructor teaches the blue belt.\r\n6. Ms. Campbell's student won Sparring.\r\n7. Janet has never competed in Hosin-Sul.\r\n8. Either David or John won the Sparring division.\r\n9. The yellow belt's name begins with J.\r\n10. Janet is a student of Mr. Brown.", "hint": "No hint available.", "answer": "John - Ms. Campbell - Yellow belt - Sparring\r\nDavid - Master Smith - Blue belt - Hosin-Sul\r\nJanet - Mr. Brown - Black belt - Patterns\r\nKatie - Mr. Long - White belt - Breaking", "category": "Logic-Grid", "date": "06/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour Tae Kwon Do students, each with a different belt rank and a different instructor, won medals in four different events at a recent tournament. Using the clues below, can you figure out the correct instructor, belt rank and event for each student?\n\r\nStudents: John, David, Janet, Katie\r\nInstructors: Master Smith, Mr. Brown, Ms. Campbell, Mr. Long\r\nStudent ranks: Black belt, blue belt, yellow belt, white belt\r\nEvents: Patterns, Sparring, Breaking, Hosin-Sul\n\r\nClues:\r\n1. David's instructor is not female.\r\n2. Neither John nor Katie is a black belt.\r\n3. The white belt won her Breaking division.\r\n4. Mr. Brown's student is a black belt.\r\n5. The Master instructor teaches the blue belt.\r\n6. Ms. Campbell's student won Sparring.\r\n7. Janet has never competed in Hosin-Sul.\r\n8. Either David or John won the Sparring division.\r\n9. The yellow belt's name begins with J.\r\n10. Janet is a student of Mr. Brown.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn - Ms. Campbell - Yellow belt - Sparring\r\nDavid - Master Smith - Blue belt - Hosin-Sul\r\nJanet - Mr. Brown - Black belt - Patterns\r\nKatie - Mr. Long - White belt - Breaking\n<|im_start|>answer\nJohn - Ms. Campbell - Yellow belt - Sparring\r\nDavid - Master Smith - Blue belt - Hosin-Sul\r\nJanet - Mr. Brown - Black belt - Patterns\r\nKatie - Mr. Long - White belt - Breaking\n<|im_end|>" }, { "id": "#46347", "title": "Romantic Getaway", "fun": 2.98, "difficulty": 1.35, "author": "dswilborn", "desc": "Five couples from San Francisco were celebrating Valentine's Day with an outing they had planned (one couple went to the beach) and enjoyed. However, each husband had surprised his wife with a special vacation trip. Can you determine the couples' names, their outing of choice, and vacation destination (one couple is going to Canada) from the clues provided below?\n\r\n1. Neither Jonas nor Kim will be leaving the United States, though they are not traveling together.\n\r\n2. At the restaurant, one couple talked about visiting both Madrid and Barcelona.\n\r\n3. Alice is not married to Mark, who did not take his wife to a hockey game or a restaurant.\n\r\n4. The couple going to Hawaii is either Denise and her husband or the couple who went skiing on Valentine's Day.\n\r\n5. Neither Paul nor Kevin enjoy dancing, but Jenny, who is going to Mexico, does enjoy it. Kevin is going to Alaska and hopes to hit the ski slopes.\n\r\n6. Paul and his wife love hockey and want to see another NHL game on their trip. Laura planned her dinner date with either Mark or Bill.", "hint": "NHL stands for National Hockey League and has teams in the United States and Canada.", "answer": "Jonas and Denise went to the beach and are going to Hawaii.\r\nPaul and Alice went to a hockey game and are going to Canada.\r\nBill and Laura went to a restaurant and are going to Spain.\r\nKevin and Kim went skiing and are going to Alaska.\r\nMark and Jenny went dancing and are going to Mexico.", "category": "Logic-Grid", "date": "02/10/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive couples from San Francisco were celebrating Valentine's Day with an outing they had planned (one couple went to the beach) and enjoyed. However, each husband had surprised his wife with a special vacation trip. Can you determine the couples' names, their outing of choice, and vacation destination (one couple is going to Canada) from the clues provided below?\n\r\n1. Neither Jonas nor Kim will be leaving the United States, though they are not traveling together.\n\r\n2. At the restaurant, one couple talked about visiting both Madrid and Barcelona.\n\r\n3. Alice is not married to Mark, who did not take his wife to a hockey game or a restaurant.\n\r\n4. The couple going to Hawaii is either Denise and her husband or the couple who went skiing on Valentine's Day.\n\r\n5. Neither Paul nor Kevin enjoy dancing, but Jenny, who is going to Mexico, does enjoy it. Kevin is going to Alaska and hopes to hit the ski slopes.\n\r\n6. Paul and his wife love hockey and want to see another NHL game on their trip. Laura planned her dinner date with either Mark or Bill.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJonas and Denise went to the beach and are going to Hawaii.\r\nPaul and Alice went to a hockey game and are going to Canada.\r\nBill and Laura went to a restaurant and are going to Spain.\r\nKevin and Kim went skiing and are going to Alaska.\r\nMark and Jenny went dancing and are going to Mexico.\n<|im_start|>answer\nJonas and Denise went to the beach and are going to Hawaii.\r\nPaul and Alice went to a hockey game and are going to Canada.\r\nBill and Laura went to a restaurant and are going to Spain.\r\nKevin and Kim went skiing and are going to Alaska.\r\nMark and Jenny went dancing and are going to Mexico.\n<|im_end|>" }, { "id": "#30300", "title": "The Logical Race", "fun": 2.98, "difficulty": 2.21, "author": "Winner4600", "desc": "George, Lennie, Livy, Maude, and Simon are having a race! All of them are competing to arrive at a specific destination, but using different modes of transportation. It is your job as record-keeper to figure out who chose what transport, how many stops they each made, and in what order they each finished.\n\r\n1) George did not stop at all.\n\r\n2) Simon did not take the train, which arrived 1st.\n\r\n3) The airplane did not make the most stops. The ship did not make the least.\n\r\n4) Lennie did not take the train, which is not the one that had 4 stops.\n\r\n5) The 5 friends are Maude, the one who took a plane, the one who had 3 stops, the one who finished 5th, and Livy.\n\r\n6) Only one person had the same number of letters in their name as in their transportation.\n\r\n7) Neither Lennie nor George took the subway.\n\r\n8) The transport which finished 3rd had 4 stops.\n\r\n9) Simon finished 5th.\n\r\n10) The car driver had 2 stops.\n\r\n11) George finished 2nd.", "hint": "No hint available.", "answer": "George, Airplane, 0 Stops, 2nd Place\r\nLennie, Ship, 3 Stops, 4th Place\r\nLivy, Subway, 4 Stops, 3rd Place\r\nMaude, Train, 1 Stop, 1st Place\r\nSimon, Car, 2 Stops, 5th Place", "category": "Logic-Grid", "date": "05/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGeorge, Lennie, Livy, Maude, and Simon are having a race! All of them are competing to arrive at a specific destination, but using different modes of transportation. It is your job as record-keeper to figure out who chose what transport, how many stops they each made, and in what order they each finished.\n\r\n1) George did not stop at all.\n\r\n2) Simon did not take the train, which arrived 1st.\n\r\n3) The airplane did not make the most stops. The ship did not make the least.\n\r\n4) Lennie did not take the train, which is not the one that had 4 stops.\n\r\n5) The 5 friends are Maude, the one who took a plane, the one who had 3 stops, the one who finished 5th, and Livy.\n\r\n6) Only one person had the same number of letters in their name as in their transportation.\n\r\n7) Neither Lennie nor George took the subway.\n\r\n8) The transport which finished 3rd had 4 stops.\n\r\n9) Simon finished 5th.\n\r\n10) The car driver had 2 stops.\n\r\n11) George finished 2nd.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGeorge, Airplane, 0 Stops, 2nd Place\r\nLennie, Ship, 3 Stops, 4th Place\r\nLivy, Subway, 4 Stops, 3rd Place\r\nMaude, Train, 1 Stop, 1st Place\r\nSimon, Car, 2 Stops, 5th Place\n<|im_start|>answer\nGeorge, Airplane, 0 Stops, 2nd Place\r\nLennie, Ship, 3 Stops, 4th Place\r\nLivy, Subway, 4 Stops, 3rd Place\r\nMaude, Train, 1 Stop, 1st Place\r\nSimon, Car, 2 Stops, 5th Place\n<|im_end|>" }, { "id": "#26888", "title": "The War of the Worlds - Part III", "fun": 2.98, "difficulty": 2.71, "author": "smarty_blondy", "desc": "Alas, the War of the Worlds had begun! Although Lord Zyron, feared master of The Underworld, had no remorse regarding his pick, King Solimyr was not as confident. He knew his two army leaders would not stand a chance against the dreadful three monsters, and decided something needed to be done, to even the odds.\n\r\nAn old legend said that far, far away spread the Realm of God Baal. Millions of years ago, an earthquake shook the world, causing volcanoes to erupt. Hot, burning rivers of lava now divided the realm into 5 islands, each ruled by one of Baal's most faithful servants. Each island was well guarded by magical, mythical creatures, protecting 5 powerful witches from unwanted visitors. These were the possessors of 5 precious, enchanted stones that King Solimyr desperately wanted to put his hands on.\n\r\nOnce his, King Solimyr would crash the 5 stones, and include the magical dust into melted iron. His best craftsmen would then make him two swords, of which powers the world had never seen before! To confirm the legend, griffins were sent on a quest in the far, far away realm. Can you find out more, by the bits of information the griffins returned with? Good luck!\n\r\nIslands' names: Necropolis, Rampart, Stronghold, Inferno, Conflux\r\nRulers' names: Malekith, Dace, Krephlian, Rashka, Ufretin;\r\nWitches' names: Rissa, Ash, Sephinroth, Jenova, Shaki;\r\nPrecious stones: Ruby, Diamond, Topaz, Sapphire, Emerald;\r\nGuardians: Medusa, Minotaur, Dragon, Manticore, Harpy;\n\n\r\n1. Rissa, a beautiful witch who lives in Conflux, received the diamond from her godmother. Although she was just a baby at the time, she never let go of the diamond as she believes it brings good fortune. \n\r\n2. Ash lives in the kingdom of one of the most avoided rulers, as if his name's last two letters are removed, it transforms into the result of an ill-considered haste or boldness.\n\r\n3. While Jenova holds the topaz, the possessor of the emerald is well guarded by a minotaur. \n\r\n4. The harpy is known as an evil being, with the head of a woman and the body of a bird. Baal could not let such a hideous creature show its face in any other place than Inferno, where it was cursed to guard the ruby with the price of its life.\n\r\n5. Necropolis is ruled by the most feared of rulers, Malekith. His manticore is not guarding the sapphire.\n\r\n6. The medusa does not guard Jenova or Shaki, but the witch living in the kingdom ruled by the one whose name, if its first letter is changed with another, transforms into a word in the English language. Metaphorically, it can be defined as \"the cage of the soul\".\n\r\n7. Two of the rulers are so selfish, they insisted that the precious stones sharing their name's initials would be guarded on their islands.\n\r\n8. One of the rulers' names has as many letters as the island he is ruling, where Sephinroth's home can be found, but not as many as the stone his guardian protects.", "hint": "Let's see if I can help you in your quest a bit. It's important to know that no assuming is needed. Some parts can be found in the end, by elimination. Clue #2 refers to Rashka, as if the group of letters \"ka\" is removed, we are left with \"rash\". Also, clue #6 refers to Dace, as \"the cage of the soul\" is a fancy phrase for \"face\".", "answer": "Malekith is the ruler of Necropolis. Here lives Jenova, possessor of the topaz, well guarded by a manticore.\r\nUfretin is the ruler of Rampart. Here lives Sephinroth, possessor of the sapphire, well guarded by a dragon.\r\nKrephlian is the ruler of Stronghold. Here lives Shaki, possessor of the emerald, well guarded by a minotaur.\r\nRashka is the ruler of Inferno. Here lives Ash, possessor of the ruby, well guarded by a harpy.\r\nDace is the ruler of Conflux. Here lives Rissa, possessor of the diamond, well guarded by a medusa.\n\r\nYou have done well in your quest, as King Solimyr now knows where and how to find the precious stones. With the help of their magic, he has no doubt he will claim victory over the big battle!", "category": "Logic-Grid", "date": "11/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlas, the War of the Worlds had begun! Although Lord Zyron, feared master of The Underworld, had no remorse regarding his pick, King Solimyr was not as confident. He knew his two army leaders would not stand a chance against the dreadful three monsters, and decided something needed to be done, to even the odds.\n\r\nAn old legend said that far, far away spread the Realm of God Baal. Millions of years ago, an earthquake shook the world, causing volcanoes to erupt. Hot, burning rivers of lava now divided the realm into 5 islands, each ruled by one of Baal's most faithful servants. Each island was well guarded by magical, mythical creatures, protecting 5 powerful witches from unwanted visitors. These were the possessors of 5 precious, enchanted stones that King Solimyr desperately wanted to put his hands on.\n\r\nOnce his, King Solimyr would crash the 5 stones, and include the magical dust into melted iron. His best craftsmen would then make him two swords, of which powers the world had never seen before! To confirm the legend, griffins were sent on a quest in the far, far away realm. Can you find out more, by the bits of information the griffins returned with? Good luck!\n\r\nIslands' names: Necropolis, Rampart, Stronghold, Inferno, Conflux\r\nRulers' names: Malekith, Dace, Krephlian, Rashka, Ufretin;\r\nWitches' names: Rissa, Ash, Sephinroth, Jenova, Shaki;\r\nPrecious stones: Ruby, Diamond, Topaz, Sapphire, Emerald;\r\nGuardians: Medusa, Minotaur, Dragon, Manticore, Harpy;\n\n\r\n1. Rissa, a beautiful witch who lives in Conflux, received the diamond from her godmother. Although she was just a baby at the time, she never let go of the diamond as she believes it brings good fortune. \n\r\n2. Ash lives in the kingdom of one of the most avoided rulers, as if his name's last two letters are removed, it transforms into the result of an ill-considered haste or boldness.\n\r\n3. While Jenova holds the topaz, the possessor of the emerald is well guarded by a minotaur. \n\r\n4. The harpy is known as an evil being, with the head of a woman and the body of a bird. Baal could not let such a hideous creature show its face in any other place than Inferno, where it was cursed to guard the ruby with the price of its life.\n\r\n5. Necropolis is ruled by the most feared of rulers, Malekith. His manticore is not guarding the sapphire.\n\r\n6. The medusa does not guard Jenova or Shaki, but the witch living in the kingdom ruled by the one whose name, if its first letter is changed with another, transforms into a word in the English language. Metaphorically, it can be defined as \"the cage of the soul\".\n\r\n7. Two of the rulers are so selfish, they insisted that the precious stones sharing their name's initials would be guarded on their islands.\n\r\n8. One of the rulers' names has as many letters as the island he is ruling, where Sephinroth's home can be found, but not as many as the stone his guardian protects.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMalekith is the ruler of Necropolis. Here lives Jenova, possessor of the topaz, well guarded by a manticore.\r\nUfretin is the ruler of Rampart. Here lives Sephinroth, possessor of the sapphire, well guarded by a dragon.\r\nKrephlian is the ruler of Stronghold. Here lives Shaki, possessor of the emerald, well guarded by a minotaur.\r\nRashka is the ruler of Inferno. Here lives Ash, possessor of the ruby, well guarded by a harpy.\r\nDace is the ruler of Conflux. Here lives Rissa, possessor of the diamond, well guarded by a medusa.\n\r\nYou have done well in your quest, as King Solimyr now knows where and how to find the precious stones. With the help of their magic, he has no doubt he will claim victory over the big battle!\n<|im_start|>answer\nMalekith is the ruler of Necropolis. Here lives Jenova, possessor of the topaz, well guarded by a manticore.\r\nUfretin is the ruler of Rampart. Here lives Sephinroth, possessor of the sapphire, well guarded by a dragon.\r\nKrephlian is the ruler of Stronghold. Here lives Shaki, possessor of the emerald, well guarded by a minotaur.\r\nRashka is the ruler of Inferno. Here lives Ash, possessor of the ruby, well guarded by a harpy.\r\nDace is the ruler of Conflux. Here lives Rissa, possessor of the diamond, well guarded by a medusa.\n\r\nYou have done well in your quest, as King Solimyr now knows where and how to find the precious stones. With the help of their magic, he has no doubt he will claim victory over the big battle!\n<|im_end|>" }, { "id": "#27037", "title": "Ice Cream Catastrophe", "fun": 2.98, "difficulty": 1.0, "author": "scm14", "desc": "Six years ago, the Wilson family became the talk of their tiny town when Mrs. Wilson gave birth to identical quintuplet girls. Mr. and Mrs. Wilson loved their daughters very much, but discovered very quickly that they couldn't tell them apart. Even as they grew older, Mrs. Wilson had to dress the girls in different colored shirts to differentiate between them. \n\r\nOne day, Mrs. Wilson took Suzie, Sally, Samantha, Sara and Christina to the mall. The girls were very excited because they were always allowed to stop for ice cream at the Fantastic Flavors Ice Cream Parlor. Each girl always ordered their favorite flavor ice cream, and no two girls had the same favorite. Unfortunately, after they all had their ice cream, the five girls got separated from Mrs. Wilson. In her panic, Mrs. Wilson forgot which color shirt each girl was wearing, and therefore couldn't identify them when the security guards found them. Can you help her?\n\r\n1. The five girls were Sally, the girl wearing green, the girl wearing white, the girl who ordered Coffee Ice Cream and Sara.\n\r\n2. Christina ordered a flavor of Ice Cream that started with the same letter as her name.\n\r\n3. Samantha, Sara and Sally were wearing shirts that reminded them of their favorite parts of summer: the color of sunshine, the color of grass and the color of the sky on a clear day.\n\r\n4. Mrs. Wilson was upset when the girl eating chocolate ice cream dropped some on her white shirt, and reminded herself to stop at the grocery store and buy some bleach on the way home.\n\r\n5. Sara could never decide if she liked Strawberry, Chocolate or Vanilla Ice Cream the best, so she always ordered the flavor that had all three.\n\r\n6. The girl who loved Mint Ice Cream wore a green shirt. She later made the observation that they were the same color.\n\r\n7. Christina was not wearing a white shirt or a blue shirt.\n\r\n8. Sara was not wearing a blue shirt.", "hint": "Neapolitan Ice Cream contains Vanilla, Strawberry and Chocolate flavors.", "answer": "Suzie, White, Chocolate\r\nSally, Blue, Vanilla\r\nSamantha, Green, Mint\r\nSara, Yellow, Neapolitan\r\nChristina, Red, Coffee", "category": "Logic-Grid", "date": "11/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix years ago, the Wilson family became the talk of their tiny town when Mrs. Wilson gave birth to identical quintuplet girls. Mr. and Mrs. Wilson loved their daughters very much, but discovered very quickly that they couldn't tell them apart. Even as they grew older, Mrs. Wilson had to dress the girls in different colored shirts to differentiate between them. \n\r\nOne day, Mrs. Wilson took Suzie, Sally, Samantha, Sara and Christina to the mall. The girls were very excited because they were always allowed to stop for ice cream at the Fantastic Flavors Ice Cream Parlor. Each girl always ordered their favorite flavor ice cream, and no two girls had the same favorite. Unfortunately, after they all had their ice cream, the five girls got separated from Mrs. Wilson. In her panic, Mrs. Wilson forgot which color shirt each girl was wearing, and therefore couldn't identify them when the security guards found them. Can you help her?\n\r\n1. The five girls were Sally, the girl wearing green, the girl wearing white, the girl who ordered Coffee Ice Cream and Sara.\n\r\n2. Christina ordered a flavor of Ice Cream that started with the same letter as her name.\n\r\n3. Samantha, Sara and Sally were wearing shirts that reminded them of their favorite parts of summer: the color of sunshine, the color of grass and the color of the sky on a clear day.\n\r\n4. Mrs. Wilson was upset when the girl eating chocolate ice cream dropped some on her white shirt, and reminded herself to stop at the grocery store and buy some bleach on the way home.\n\r\n5. Sara could never decide if she liked Strawberry, Chocolate or Vanilla Ice Cream the best, so she always ordered the flavor that had all three.\n\r\n6. The girl who loved Mint Ice Cream wore a green shirt. She later made the observation that they were the same color.\n\r\n7. Christina was not wearing a white shirt or a blue shirt.\n\r\n8. Sara was not wearing a blue shirt.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSuzie, White, Chocolate\r\nSally, Blue, Vanilla\r\nSamantha, Green, Mint\r\nSara, Yellow, Neapolitan\r\nChristina, Red, Coffee\n<|im_start|>answer\nSuzie, White, Chocolate\r\nSally, Blue, Vanilla\r\nSamantha, Green, Mint\r\nSara, Yellow, Neapolitan\r\nChristina, Red, Coffee\n<|im_end|>" }, { "id": "#43382", "title": "It's a Party and Who Came with Whom?", "fun": 2.98, "difficulty": 2.09, "author": "whsprec", "desc": "The Carsons had a party and invited the O'Neals, Larsens, Jeffersons, Martins, and Samsons. The five husbands were named Elmer, Jeff, David, Charles, and Sam. The wives were named Mary, Helen, Madalene, Jessica, and Marlene. From the clues given, determine not only the first and last name of each guest, but also the order in which they arrived at the party. Each couple arrived together as a couple.\n\r\n1- When Mary arrived, her brother David was already there, talking with Elmer Samson and the O'Neals.\r\n2- The Jeffersons arrived after the Larsens but before Jessica.\r\n3- No person at the party has first and last names beginning with the same letter.\r\n4- Neither Helen nor Mrs. Martin is married to David.\r\n5- Jeff and Marlene arrived together after Elmer and before Mary, but none of these people arrived first.\r\n6- Charles is not married to Jessica.", "hint": "No hint available.", "answer": "1st: David and Madalene Larsen\r\n2nd: Elmer and Helen Samson\r\n3rd: Jeff and Marlene O'Neal\r\n4th: Charles and Mary Jefferson\r\n5th: Jessica and Sam Martin", "category": "Logic-Grid", "date": "10/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Carsons had a party and invited the O'Neals, Larsens, Jeffersons, Martins, and Samsons. The five husbands were named Elmer, Jeff, David, Charles, and Sam. The wives were named Mary, Helen, Madalene, Jessica, and Marlene. From the clues given, determine not only the first and last name of each guest, but also the order in which they arrived at the party. Each couple arrived together as a couple.\n\r\n1- When Mary arrived, her brother David was already there, talking with Elmer Samson and the O'Neals.\r\n2- The Jeffersons arrived after the Larsens but before Jessica.\r\n3- No person at the party has first and last names beginning with the same letter.\r\n4- Neither Helen nor Mrs. Martin is married to David.\r\n5- Jeff and Marlene arrived together after Elmer and before Mary, but none of these people arrived first.\r\n6- Charles is not married to Jessica.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st: David and Madalene Larsen\r\n2nd: Elmer and Helen Samson\r\n3rd: Jeff and Marlene O'Neal\r\n4th: Charles and Mary Jefferson\r\n5th: Jessica and Sam Martin\n<|im_start|>answer\n1st: David and Madalene Larsen\r\n2nd: Elmer and Helen Samson\r\n3rd: Jeff and Marlene O'Neal\r\n4th: Charles and Mary Jefferson\r\n5th: Jessica and Sam Martin\n<|im_end|>" }, { "id": "#21367", "title": "A Giant Puzzle (Part 3)", "fun": 2.98, "difficulty": 1.65, "author": "cdrock", "desc": "I still have 7 more things to put away and time is running out fast. Next I decide to put away the giant's board games. \n\r\nThe colors of the board games are blue, brown, green, orange, purple, red, and yellow.\n\r\n1. Purple is somewhere to the left of green.\n\r\n2. Red is next to blue.\n\r\n3. Brown is 3 away from blue (2 between).\n\r\n4. Yellow is 2 away from red.\n\r\n5. Blue is in the middle.\n\r\n6. Orange is directly between yellow and purple.", "hint": "No hint available.", "answer": "From left to right, the order of the board games are: purple, orange, yellow, blue, red, green, and brown.", "category": "Logic", "date": "03/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI still have 7 more things to put away and time is running out fast. Next I decide to put away the giant's board games. \n\r\nThe colors of the board games are blue, brown, green, orange, purple, red, and yellow.\n\r\n1. Purple is somewhere to the left of green.\n\r\n2. Red is next to blue.\n\r\n3. Brown is 3 away from blue (2 between).\n\r\n4. Yellow is 2 away from red.\n\r\n5. Blue is in the middle.\n\r\n6. Orange is directly between yellow and purple.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom left to right, the order of the board games are: purple, orange, yellow, blue, red, green, and brown.\n<|im_start|>answer\nFrom left to right, the order of the board games are: purple, orange, yellow, blue, red, green, and brown.\n<|im_end|>" }, { "id": "#24394", "title": "Trilogy Part 1: Howdy, Pardner", "fun": 2.98, "difficulty": 1.6, "author": "cinnamon30", "desc": "Standing outside of Sneed's Seed and Feed are five local ranch owners (including Mr. Lovelace), talking about the weather and current events. From the information provided, can you determine the first and last names of the rancher and the position they are standing?\n\r\n\"Left\" and \"Right\" refer to your left and right. Draw 5 lines on a sheet of paper and label them A through E, in order - with position A being on the left looking at the paper and position E being on the right looking at the paper.\n\r\nFirst Names - Carl, Hank, Pablo, Rusty and Zeke\r\nLast Names - Brooks, Ewing, Lovelace, McCool and Sanchez\r\nPositions - A, B, C, D and E\n\r\n1. Rusty is somewhere to the left of Mr. Brooks.\n\r\n2. Zeke isn't Mr. Ewing (who is the rancher in position C).\n\r\n3. Carl (who isn't Mr. McCool) is the rancher in position B.\n\r\n4. Hank is standing to the immediate right of Pablo Sanchez.\n\n\r\nNote: You will need the answers from this logic grid to solve Trilogy Part 2: Ranch Dressing.", "hint": "No hint available.", "answer": "Zeke McCool is in position A.\r\nCarl Lovelace is in position B.\r\nRusty Ewing is in position C.\r\nPablo Sanchez is in position D.\r\nHank Brooks is in position E.\n\r\nCarl is standing in position B (3). Mr. Ewing is in position C (2). Pablo Sanchez can't be in position B (2) or C (3), so he has to be in position D because Hank is to his immediate right (4). Hank can't be in position A (4) or B (3), so he has to be in position E. Zeke isn't Mr. Ewing in position C (2), so Zeke is in position A, only one left. This leaves Rusty who is in position C and he is Mr. Ewing. Mr. Brooks is in position E (1). Carl is Mr. Lovelace because he isn't Mr. McCool (3), which leaves Zeke as Mr. McCool.", "category": "Logic-Grid", "date": "07/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStanding outside of Sneed's Seed and Feed are five local ranch owners (including Mr. Lovelace), talking about the weather and current events. From the information provided, can you determine the first and last names of the rancher and the position they are standing?\n\r\n\"Left\" and \"Right\" refer to your left and right. Draw 5 lines on a sheet of paper and label them A through E, in order - with position A being on the left looking at the paper and position E being on the right looking at the paper.\n\r\nFirst Names - Carl, Hank, Pablo, Rusty and Zeke\r\nLast Names - Brooks, Ewing, Lovelace, McCool and Sanchez\r\nPositions - A, B, C, D and E\n\r\n1. Rusty is somewhere to the left of Mr. Brooks.\n\r\n2. Zeke isn't Mr. Ewing (who is the rancher in position C).\n\r\n3. Carl (who isn't Mr. McCool) is the rancher in position B.\n\r\n4. Hank is standing to the immediate right of Pablo Sanchez.\n\n\r\nNote: You will need the answers from this logic grid to solve Trilogy Part 2: Ranch Dressing.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZeke McCool is in position A.\r\nCarl Lovelace is in position B.\r\nRusty Ewing is in position C.\r\nPablo Sanchez is in position D.\r\nHank Brooks is in position E.\n\r\nCarl is standing in position B (3). Mr. Ewing is in position C (2). Pablo Sanchez can't be in position B (2) or C (3), so he has to be in position D because Hank is to his immediate right (4). Hank can't be in position A (4) or B (3), so he has to be in position E. Zeke isn't Mr. Ewing in position C (2), so Zeke is in position A, only one left. This leaves Rusty who is in position C and he is Mr. Ewing. Mr. Brooks is in position E (1). Carl is Mr. Lovelace because he isn't Mr. McCool (3), which leaves Zeke as Mr. McCool.\n<|im_start|>answer\nZeke McCool is in position A.\r\nCarl Lovelace is in position B.\r\nRusty Ewing is in position C.\r\nPablo Sanchez is in position D.\r\nHank Brooks is in position E.\n\r\nCarl is standing in position B (3). Mr. Ewing is in position C (2). Pablo Sanchez can't be in position B (2) or C (3), so he has to be in position D because Hank is to his immediate right (4). Hank can't be in position A (4) or B (3), so he has to be in position E. Zeke isn't Mr. Ewing in position C (2), so Zeke is in position A, only one left. This leaves Rusty who is in position C and he is Mr. Ewing. Mr. Brooks is in position E (1). Carl is Mr. Lovelace because he isn't Mr. McCool (3), which leaves Zeke as Mr. McCool.\n<|im_end|>" }, { "id": "#27107", "title": "College Roommate", "fun": 2.98, "difficulty": 2.34, "author": "teaserboy", "desc": "Five college seniors---John, Oscar, Earl, Ernie, and Marvin---rent an off-campus house. Each one is majoring in a different subjet---psychology, chemistry, biology, math, or physics. They are attending college on sports scholarships in five sports: football, baseball, track, tennis, and swimming. And each is taking a different foreign language: French, Spanish, Italian, German, and Russian. From the clues given, try to determine the language, the sport, and the major of each of the five students.\n\r\n1. The biology major, the swimmer, the student taking Italian, and Marvin have never missed any of Ernie's home football games.\n\r\n2. Neither Oscar nor Earl is the one who takes Spanish or the one who is a physics major, but one of them is a baseball player.\n\r\n3. Marvin and the track star had lunch with the math major and later met Oscar after his German class.\n\r\n4. The baseball Player, the math major, and Oscar all have rooms on the top floor, whereas John and the physics major have rooms on the ground floor.\n\r\n5. The psychology major is taking German.\n\r\n6. The biology major is not the track star and does not take Russian.", "hint": "No hint available.", "answer": "John-Italian-track-chemistry\n\r\nOscar-German-swimming-psychology\n\r\nEarl-French-baseball-biology\n\r\nErnie-Spanish-football-math\n\r\nMarvin-Russian-tennis-physics", "category": "Logic-Grid", "date": "11/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive college seniors---John, Oscar, Earl, Ernie, and Marvin---rent an off-campus house. Each one is majoring in a different subjet---psychology, chemistry, biology, math, or physics. They are attending college on sports scholarships in five sports: football, baseball, track, tennis, and swimming. And each is taking a different foreign language: French, Spanish, Italian, German, and Russian. From the clues given, try to determine the language, the sport, and the major of each of the five students.\n\r\n1. The biology major, the swimmer, the student taking Italian, and Marvin have never missed any of Ernie's home football games.\n\r\n2. Neither Oscar nor Earl is the one who takes Spanish or the one who is a physics major, but one of them is a baseball player.\n\r\n3. Marvin and the track star had lunch with the math major and later met Oscar after his German class.\n\r\n4. The baseball Player, the math major, and Oscar all have rooms on the top floor, whereas John and the physics major have rooms on the ground floor.\n\r\n5. The psychology major is taking German.\n\r\n6. The biology major is not the track star and does not take Russian.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn-Italian-track-chemistry\n\r\nOscar-German-swimming-psychology\n\r\nEarl-French-baseball-biology\n\r\nErnie-Spanish-football-math\n\r\nMarvin-Russian-tennis-physics\n<|im_start|>answer\nJohn-Italian-track-chemistry\n\r\nOscar-German-swimming-psychology\n\r\nEarl-French-baseball-biology\n\r\nErnie-Spanish-football-math\n\r\nMarvin-Russian-tennis-physics\n<|im_end|>" }, { "id": "#37978", "title": "Take Me to the Ballgame", "fun": 2.98, "difficulty": 2.45, "author": "dreamlvr1432", "desc": "Mike and 4 friends went to a baseball game on Saturday night. Everyone visited either the concession stand or the souvenir shop during a different inning of the game. Can you figure out each person's full name, what inning each made their purchase, what they bought, and what seat they were sitting in?\n\r\n1) The seats are numbered from left to right.\n\r\n2) One person has the same first initial for both their first and last names.\n\r\n3) Mike did not purchase a baseball, nor did he leave during the 3rd inning. But he did sit to the left of Donna (who bought a program to remember her first ball game).\n\r\n4) The 5 friends are Mr. Waterson, Donna, the person in seat 5, the person who made their purchase during the 8th inning, and the person who bought soda.\n\r\n5) The person whose last name is Redding sat somewhere to the right of Tom, and immediately to the left of the person who bought hot dogs.\n\r\n6) The friends were seated from left to right in this order: the person who made a purchase during the 6th inning, the person who bought a cap, Ms. Redding, the person who bought hot dogs, and Sue (who did not buy her item in the 1st inning).\n\r\n7) Mike did not buy hot dogs, he bought a cap (but not during the 6th inning).\n\r\n8) The hot dogs were purchased 5 innings before Mike made his purchase (his last name is not Waterson).\n\r\n9) Mr. Beals did not make his purchase during the 6th inning.", "hint": "No hint available.", "answer": "Mike Beals, cap, 8th inning, seat 2\r\nTom Jones, soda, 6th inning, seat 1\r\nDonna Redding, program, 1st inning, seat 3\r\nSam Waterson, hot dogs, 3rd inning, seat 4\r\nSue Smith, baseball, 5th inning, seat 5", "category": "Logic-Grid", "date": "08/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMike and 4 friends went to a baseball game on Saturday night. Everyone visited either the concession stand or the souvenir shop during a different inning of the game. Can you figure out each person's full name, what inning each made their purchase, what they bought, and what seat they were sitting in?\n\r\n1) The seats are numbered from left to right.\n\r\n2) One person has the same first initial for both their first and last names.\n\r\n3) Mike did not purchase a baseball, nor did he leave during the 3rd inning. But he did sit to the left of Donna (who bought a program to remember her first ball game).\n\r\n4) The 5 friends are Mr. Waterson, Donna, the person in seat 5, the person who made their purchase during the 8th inning, and the person who bought soda.\n\r\n5) The person whose last name is Redding sat somewhere to the right of Tom, and immediately to the left of the person who bought hot dogs.\n\r\n6) The friends were seated from left to right in this order: the person who made a purchase during the 6th inning, the person who bought a cap, Ms. Redding, the person who bought hot dogs, and Sue (who did not buy her item in the 1st inning).\n\r\n7) Mike did not buy hot dogs, he bought a cap (but not during the 6th inning).\n\r\n8) The hot dogs were purchased 5 innings before Mike made his purchase (his last name is not Waterson).\n\r\n9) Mr. Beals did not make his purchase during the 6th inning.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike Beals, cap, 8th inning, seat 2\r\nTom Jones, soda, 6th inning, seat 1\r\nDonna Redding, program, 1st inning, seat 3\r\nSam Waterson, hot dogs, 3rd inning, seat 4\r\nSue Smith, baseball, 5th inning, seat 5\n<|im_start|>answer\nMike Beals, cap, 8th inning, seat 2\r\nTom Jones, soda, 6th inning, seat 1\r\nDonna Redding, program, 1st inning, seat 3\r\nSam Waterson, hot dogs, 3rd inning, seat 4\r\nSue Smith, baseball, 5th inning, seat 5\n<|im_end|>" }, { "id": "#20988", "title": "Colorful Workplace", "fun": 2.98, "difficulty": 2.23, "author": "jpfrank1", "desc": "Five employees of varying ages have been assembled to work on a project due to their varying backgrounds. Three men (Jason, Corey and Matt) and two women (Carly and Stephanie) are meeting for the first time and getting to know each other. They vary in ages from 18-45 and are from all over the country. Each person is either wearing a scarf or necktie in their favorite color. You job is to figure out the age, favorite color and hometown of each employee.\n\r\n1. No employee is from a city that begins with the same letter as his or her first name.\r\n2. Jason's hometown's baseball team has Red uniforms which is not his favorite color, but it is one of his female colleagues.\r\n3. Whoever is 45 has lived in Washington DC for his entire life.\r\n4. Carly likes to wear Yellow.\r\n5. The San Diego native dislikes Green.\r\n6. Stephanie is younger than Jason, and Jason is not the oldest employee.\r\n7. The Miami native's favorite cartoon character growing up is the same color as his necktie, which is the color of the object of Ms. Piggy's affection.\r\n8. Corey's skin tone does not allow him to wear Blue.\r\n9. No girl is in her 20s.\r\n10. The 28 year old likes Blue.\r\n11. Matt's tie is Purple.", "hint": "No hint available.", "answer": "Jason: 28, St. Louis, Blue\r\nCarly: 38, San Diego, Yellow\r\nCorey: 23, Miami, Green\r\nStephanie: 18, New York, Red\r\nMatt: 45, Washington DC, Purple", "category": "Logic-Grid", "date": "02/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive employees of varying ages have been assembled to work on a project due to their varying backgrounds. Three men (Jason, Corey and Matt) and two women (Carly and Stephanie) are meeting for the first time and getting to know each other. They vary in ages from 18-45 and are from all over the country. Each person is either wearing a scarf or necktie in their favorite color. You job is to figure out the age, favorite color and hometown of each employee.\n\r\n1. No employee is from a city that begins with the same letter as his or her first name.\r\n2. Jason's hometown's baseball team has Red uniforms which is not his favorite color, but it is one of his female colleagues.\r\n3. Whoever is 45 has lived in Washington DC for his entire life.\r\n4. Carly likes to wear Yellow.\r\n5. The San Diego native dislikes Green.\r\n6. Stephanie is younger than Jason, and Jason is not the oldest employee.\r\n7. The Miami native's favorite cartoon character growing up is the same color as his necktie, which is the color of the object of Ms. Piggy's affection.\r\n8. Corey's skin tone does not allow him to wear Blue.\r\n9. No girl is in her 20s.\r\n10. The 28 year old likes Blue.\r\n11. Matt's tie is Purple.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJason: 28, St. Louis, Blue\r\nCarly: 38, San Diego, Yellow\r\nCorey: 23, Miami, Green\r\nStephanie: 18, New York, Red\r\nMatt: 45, Washington DC, Purple\n<|im_start|>answer\nJason: 28, St. Louis, Blue\r\nCarly: 38, San Diego, Yellow\r\nCorey: 23, Miami, Green\r\nStephanie: 18, New York, Red\r\nMatt: 45, Washington DC, Purple\n<|im_end|>" }, { "id": "#25270", "title": "Anytown Real Estate Sales", "fun": 2.98, "difficulty": 1.77, "author": "dddlite", "desc": "Anytown USA Real Estate company recently reviewed their salespersons' most recent deals. While reviewing the documents, several papers were accidentally dropped into the paper shredder. Determine which salesperson sold which house for how much and when it sold. This is what the manager can remember:\n\r\n1. Roy's sale closed before Ron's and after Dale's.\n\r\n2. Pete's sale was neither the most nor least expensive and closed before Roy's.\n\r\n3. Dale's sale on Main Street closed before Katie's sale on Oak Street.\n\r\n4. The house on Water Street closed in December for $20,000 more than Pete's sale.\n\r\n5. The house on First Street closed the day after Election Day for $20,000 less than Pete's sale.\n\r\n6. Dale's & Katie's sales were the most and least expensive sales, in some order.\n\r\n7. The houses on numbered streets were not the least expensive, and closed in September and November, in some order.\n\r\n8. Pete's sale on Fourth Street closed after Katie's house sold for $125,000.", "hint": "Election Day is in November.", "answer": "Dale sold the house on Main Street for $50,000 in July.\r\nKatie sold the house on Oak Street for $125,000 in August.\r\nPete sold the house on Fourth Street for $95,000 in September.\r\nRoy sold the house on First Street for $75,000 in November.\r\nRon sold the house on Water Street for $115,000 in December.", "category": "Logic-Grid", "date": "08/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnytown USA Real Estate company recently reviewed their salespersons' most recent deals. While reviewing the documents, several papers were accidentally dropped into the paper shredder. Determine which salesperson sold which house for how much and when it sold. This is what the manager can remember:\n\r\n1. Roy's sale closed before Ron's and after Dale's.\n\r\n2. Pete's sale was neither the most nor least expensive and closed before Roy's.\n\r\n3. Dale's sale on Main Street closed before Katie's sale on Oak Street.\n\r\n4. The house on Water Street closed in December for $20,000 more than Pete's sale.\n\r\n5. The house on First Street closed the day after Election Day for $20,000 less than Pete's sale.\n\r\n6. Dale's & Katie's sales were the most and least expensive sales, in some order.\n\r\n7. The houses on numbered streets were not the least expensive, and closed in September and November, in some order.\n\r\n8. Pete's sale on Fourth Street closed after Katie's house sold for $125,000.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDale sold the house on Main Street for $50,000 in July.\r\nKatie sold the house on Oak Street for $125,000 in August.\r\nPete sold the house on Fourth Street for $95,000 in September.\r\nRoy sold the house on First Street for $75,000 in November.\r\nRon sold the house on Water Street for $115,000 in December.\n<|im_start|>answer\nDale sold the house on Main Street for $50,000 in July.\r\nKatie sold the house on Oak Street for $125,000 in August.\r\nPete sold the house on Fourth Street for $95,000 in September.\r\nRoy sold the house on First Street for $75,000 in November.\r\nRon sold the house on Water Street for $115,000 in December.\n<|im_end|>" }, { "id": "#29826", "title": "In Line", "fun": 2.98, "difficulty": 1.9000000000000001, "author": "peppamintp", "desc": "Ms. Ryan and her three best friends like to get together as often as their hectic schedules permit to catch up and relax over a nice cup of coffee. They try to meet at least once a month at Pep's, the trendy coffeehouse not far from their office buildings. Looking over the extensive menu posted above the register, each woman decided on a differently flavored cup of gourmet coffee, including mocha. From this information and the clues below, can you determine each woman's full name and coffee flavor, as well as the order in which they were in line at the register?\n\r\n1. Rita made her selection right before the woman who tried the almond flavored coffee and right after Ms. Tate ordered.\r\n2. The first to order was neither Sally nor Ms. Spear.\r\n3. The vanilla flavored coffee wasn't chosen first, but someone picked it before the last woman made her choice.\r\n4. Someone chose hazelnut just before Ms. Conklin and just after Pam.\r\n5. At least two women had ordered by the time Jill selected hers.", "hint": "No hint available.", "answer": "1. Jill Spear, almond, fourth\r\n2. Pam Ryan, mocha, first\r\n3. Rita Conklin, vanilla, third\r\n4. Sally Tate, hazelnut, second", "category": "Logic-Grid", "date": "04/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Ryan and her three best friends like to get together as often as their hectic schedules permit to catch up and relax over a nice cup of coffee. They try to meet at least once a month at Pep's, the trendy coffeehouse not far from their office buildings. Looking over the extensive menu posted above the register, each woman decided on a differently flavored cup of gourmet coffee, including mocha. From this information and the clues below, can you determine each woman's full name and coffee flavor, as well as the order in which they were in line at the register?\n\r\n1. Rita made her selection right before the woman who tried the almond flavored coffee and right after Ms. Tate ordered.\r\n2. The first to order was neither Sally nor Ms. Spear.\r\n3. The vanilla flavored coffee wasn't chosen first, but someone picked it before the last woman made her choice.\r\n4. Someone chose hazelnut just before Ms. Conklin and just after Pam.\r\n5. At least two women had ordered by the time Jill selected hers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Jill Spear, almond, fourth\r\n2. Pam Ryan, mocha, first\r\n3. Rita Conklin, vanilla, third\r\n4. Sally Tate, hazelnut, second\n<|im_start|>answer\n1. Jill Spear, almond, fourth\r\n2. Pam Ryan, mocha, first\r\n3. Rita Conklin, vanilla, third\r\n4. Sally Tate, hazelnut, second\n<|im_end|>" }, { "id": "#25759", "title": "Bouncers", "fun": 2.98, "difficulty": 2.46, "author": "cinnamon30", "desc": "Each of 5 bouncers who work different night spots in town has been working out at a different gym for a different number of years. Determine each bouncer's name, his place of employment (one man works at the Hi-Jinx Lounge), his gym (one is Waldo's), the number of years he's been exercising there, and the weight he maintains.\n\r\n1. Axel (who weighs 255 pounds) is good friends with the bouncer at the Hollow Leg Bar (who's been going to his gym for two years).\r\n2. Butch, who isn't the lightest of these bouncers, works at the Dewdrop Inn.\r\n3. Gino has been a member at Pop's Gym for four years or fewer.\r\n4. Kiko has been a steady customer at his gym for six years.\r\n5. The patron of Shemp's Gym, who works at the Lamppost, isn't Axel.\r\n6. The 210-pound bouncer works out at Tiger's Gym.\r\n7. The 220-pound bouncer has been a member at his gym for five years.\r\n8. Max, who weighs 235 pounds, isn't the bouncer who's been going to his gym for four years.\r\n9. The guy who goes to Rocky's gym has been a member there a year longer than the bouncer at the Floods Dance Club has been at his.", "hint": "No hint available.", "answer": "Axel, Floods, Waldo's, 4 years, 255 pounds\r\nButch, Dewdrop, Rocky's 5 years, 220 pounds\r\nGino, Hollow Leg, Pop's, 2 years, 240 pounds\r\nKiko, Hi-Jinx, Tiger's, 6 years, 210 pounds\r\nMax, Lamppost, Shemp's, 3 years, 235 pounds\n\n\r\nThe 5 bouncers are:\r\nAxel who weighs 255 lbs (1), the 210-pound bouncer who goes to Tiger's Gym (6), the 220-pound bouncer who's been going to his gym for 5 years (7), Max who weighs 235 pounds (8) and the 240 pound bouncer. Butch who works at the Dewdrop weighs either 220 or 240 pounds (2). Gino can't weigh 210 pounds because he works at Pop's, and can't weigh 220 pounds because he has been a member of his gym for four or fewer years (3). Therefore Butch weighs 220 pounds and Gino weighs 240 pounds. Max works at the Lamppost and goes to Shemp's gym (5 and 1). Kiko is the 210 pound bouncer who has been going to his gym for 6 years (4). Gino works at the Hollow Leg and going to his gym for 2 years (1). Max has been going to his gym for 3 years (8), which leaves Axel going to his gym for 4 years. The guy who works at Floods is either Axel or Kiko. Axel works at Floods because Kiko has been at his gym for 6 years and the guy at Floods has been a member of his gym a year less than the one who goes to Rocky's gym (9). This leaves Kiko working at the Hi-Jinx, only one left, and Axel goes to Waldo's gym, only one left.", "category": "Logic-Grid", "date": "09/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach of 5 bouncers who work different night spots in town has been working out at a different gym for a different number of years. Determine each bouncer's name, his place of employment (one man works at the Hi-Jinx Lounge), his gym (one is Waldo's), the number of years he's been exercising there, and the weight he maintains.\n\r\n1. Axel (who weighs 255 pounds) is good friends with the bouncer at the Hollow Leg Bar (who's been going to his gym for two years).\r\n2. Butch, who isn't the lightest of these bouncers, works at the Dewdrop Inn.\r\n3. Gino has been a member at Pop's Gym for four years or fewer.\r\n4. Kiko has been a steady customer at his gym for six years.\r\n5. The patron of Shemp's Gym, who works at the Lamppost, isn't Axel.\r\n6. The 210-pound bouncer works out at Tiger's Gym.\r\n7. The 220-pound bouncer has been a member at his gym for five years.\r\n8. Max, who weighs 235 pounds, isn't the bouncer who's been going to his gym for four years.\r\n9. The guy who goes to Rocky's gym has been a member there a year longer than the bouncer at the Floods Dance Club has been at his.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAxel, Floods, Waldo's, 4 years, 255 pounds\r\nButch, Dewdrop, Rocky's 5 years, 220 pounds\r\nGino, Hollow Leg, Pop's, 2 years, 240 pounds\r\nKiko, Hi-Jinx, Tiger's, 6 years, 210 pounds\r\nMax, Lamppost, Shemp's, 3 years, 235 pounds\n\n\r\nThe 5 bouncers are:\r\nAxel who weighs 255 lbs (1), the 210-pound bouncer who goes to Tiger's Gym (6), the 220-pound bouncer who's been going to his gym for 5 years (7), Max who weighs 235 pounds (8) and the 240 pound bouncer. Butch who works at the Dewdrop weighs either 220 or 240 pounds (2). Gino can't weigh 210 pounds because he works at Pop's, and can't weigh 220 pounds because he has been a member of his gym for four or fewer years (3). Therefore Butch weighs 220 pounds and Gino weighs 240 pounds. Max works at the Lamppost and goes to Shemp's gym (5 and 1). Kiko is the 210 pound bouncer who has been going to his gym for 6 years (4). Gino works at the Hollow Leg and going to his gym for 2 years (1). Max has been going to his gym for 3 years (8), which leaves Axel going to his gym for 4 years. The guy who works at Floods is either Axel or Kiko. Axel works at Floods because Kiko has been at his gym for 6 years and the guy at Floods has been a member of his gym a year less than the one who goes to Rocky's gym (9). This leaves Kiko working at the Hi-Jinx, only one left, and Axel goes to Waldo's gym, only one left.\n<|im_start|>answer\nAxel, Floods, Waldo's, 4 years, 255 pounds\r\nButch, Dewdrop, Rocky's 5 years, 220 pounds\r\nGino, Hollow Leg, Pop's, 2 years, 240 pounds\r\nKiko, Hi-Jinx, Tiger's, 6 years, 210 pounds\r\nMax, Lamppost, Shemp's, 3 years, 235 pounds\n\n\r\nThe 5 bouncers are:\r\nAxel who weighs 255 lbs (1), the 210-pound bouncer who goes to Tiger's Gym (6), the 220-pound bouncer who's been going to his gym for 5 years (7), Max who weighs 235 pounds (8) and the 240 pound bouncer. Butch who works at the Dewdrop weighs either 220 or 240 pounds (2). Gino can't weigh 210 pounds because he works at Pop's, and can't weigh 220 pounds because he has been a member of his gym for four or fewer years (3). Therefore Butch weighs 220 pounds and Gino weighs 240 pounds. Max works at the Lamppost and goes to Shemp's gym (5 and 1). Kiko is the 210 pound bouncer who has been going to his gym for 6 years (4). Gino works at the Hollow Leg and going to his gym for 2 years (1). Max has been going to his gym for 3 years (8), which leaves Axel going to his gym for 4 years. The guy who works at Floods is either Axel or Kiko. Axel works at Floods because Kiko has been at his gym for 6 years and the guy at Floods has been a member of his gym a year less than the one who goes to Rocky's gym (9). This leaves Kiko working at the Hi-Jinx, only one left, and Axel goes to Waldo's gym, only one left.\n<|im_end|>" }, { "id": "#36075", "title": "Ice Cream Truck", "fun": 2.98, "difficulty": 2.23, "author": "rubytuesday", "desc": "An ice cream truck drives down Prince Albert Road every day. Yesterday, 5 children, one from each of the first 5 houses on the street, ordered a different ice cream flavour and a different topping. Can you figure out which child lives in which house and which ice cream flavour and topping each bought? \r\n*REMEMBER: The odd numbered houses are on one side of the street and even numbers are on the other!*\n\r\n1.Benjamin lives between the child who chose the Cherry topping and the child who chose strawberry ice cream.\n\r\n2.Karen, whose house has an even number, chose the sprinkles topping. Elaine does not live next to Karen.\n\r\n3.The grapenut ice cream had no topping.\n\r\n4.The child who lives in house number 2 had the vanilla ice cream. The child in house number 3 did not have moon mist ice cream.\n\r\n5.Steven had chocolate ice cream. He hates chocolate sprinkles.\n\r\n6.The child who had the chopped nuts topping lives in house number 5. Tom does not live in house number 4.", "hint": "No hint available.", "answer": "Benjamin lives in house #3 and bought grapenut ice cream with no topping.\r\nTom lives in house #2 and bought vanilla ice cream with chocolate sprinkles.\r\nElaine lives in house #5 and bought strawberry ice cream with chopped nuts.\r\nKaren lives in house #4 and bought moon mist ice cream with sprinkles.\r\nSteven lives in house #1 and bought chocolate ice cream with a cherry on top.", "category": "Logic-Grid", "date": "04/06/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn ice cream truck drives down Prince Albert Road every day. Yesterday, 5 children, one from each of the first 5 houses on the street, ordered a different ice cream flavour and a different topping. Can you figure out which child lives in which house and which ice cream flavour and topping each bought? \r\n*REMEMBER: The odd numbered houses are on one side of the street and even numbers are on the other!*\n\r\n1.Benjamin lives between the child who chose the Cherry topping and the child who chose strawberry ice cream.\n\r\n2.Karen, whose house has an even number, chose the sprinkles topping. Elaine does not live next to Karen.\n\r\n3.The grapenut ice cream had no topping.\n\r\n4.The child who lives in house number 2 had the vanilla ice cream. The child in house number 3 did not have moon mist ice cream.\n\r\n5.Steven had chocolate ice cream. He hates chocolate sprinkles.\n\r\n6.The child who had the chopped nuts topping lives in house number 5. Tom does not live in house number 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBenjamin lives in house #3 and bought grapenut ice cream with no topping.\r\nTom lives in house #2 and bought vanilla ice cream with chocolate sprinkles.\r\nElaine lives in house #5 and bought strawberry ice cream with chopped nuts.\r\nKaren lives in house #4 and bought moon mist ice cream with sprinkles.\r\nSteven lives in house #1 and bought chocolate ice cream with a cherry on top.\n<|im_start|>answer\nBenjamin lives in house #3 and bought grapenut ice cream with no topping.\r\nTom lives in house #2 and bought vanilla ice cream with chocolate sprinkles.\r\nElaine lives in house #5 and bought strawberry ice cream with chopped nuts.\r\nKaren lives in house #4 and bought moon mist ice cream with sprinkles.\r\nSteven lives in house #1 and bought chocolate ice cream with a cherry on top.\n<|im_end|>" }, { "id": "#36398", "title": "Sibling Birthday Discussion", "fun": 2.98, "difficulty": 1.83, "author": "scallio", "desc": "4 siblings are seated around a table discussing their birthdays. Can you figure out where each is seated as well as their age and birth month?\n\r\nThe oldest child is seated at the north end of the table while the youngest is seated on the west side. The child with the March birthday is seated on the east side.\n\r\nDevon, whose birthday is in September, is not the oldest or the youngest.\n\r\nThe girl with the April birthday is older than Kylie who is 7.\n\r\nThe 8 year old, whose birthday is in the month before Brie's, is not seated at the south end of the table.\n\r\nKira, who is not seated at the north end of the table, is one year older than Kylie, but they share the same birth month.\n\r\nOne child is 2 years younger than Devon while another is 2 years older and the youngest is 3 years younger.\n\r\nThe 10 year old is seated at the south side of the table as far away from Brie as possible.", "hint": "Kira, age 8 is seated on the east side of the table and her birthday is in March.", "answer": "Brie, oldest, 12 years old, north side, April birthday\r\nDevon, age 10, south side, September birthday\r\nKira, age 8, east side, March birthday\r\nKylie, youngest, age 7, west side, March birthday", "category": "Logic", "date": "04/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 siblings are seated around a table discussing their birthdays. Can you figure out where each is seated as well as their age and birth month?\n\r\nThe oldest child is seated at the north end of the table while the youngest is seated on the west side. The child with the March birthday is seated on the east side.\n\r\nDevon, whose birthday is in September, is not the oldest or the youngest.\n\r\nThe girl with the April birthday is older than Kylie who is 7.\n\r\nThe 8 year old, whose birthday is in the month before Brie's, is not seated at the south end of the table.\n\r\nKira, who is not seated at the north end of the table, is one year older than Kylie, but they share the same birth month.\n\r\nOne child is 2 years younger than Devon while another is 2 years older and the youngest is 3 years younger.\n\r\nThe 10 year old is seated at the south side of the table as far away from Brie as possible.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrie, oldest, 12 years old, north side, April birthday\r\nDevon, age 10, south side, September birthday\r\nKira, age 8, east side, March birthday\r\nKylie, youngest, age 7, west side, March birthday\n<|im_start|>answer\nBrie, oldest, 12 years old, north side, April birthday\r\nDevon, age 10, south side, September birthday\r\nKira, age 8, east side, March birthday\r\nKylie, youngest, age 7, west side, March birthday\n<|im_end|>" }, { "id": "#23381", "title": "Family Tree", "fun": 2.97, "difficulty": 2.52, "author": "cdrock", "desc": "I was going through some old family photos in the attic when I stumbled upon our family tree. I studied it for a couple minutes then went back down stairs to tell my mom about the family tree. The problem is I didn't study it long enough to remember the whole thing. I only remembered a couple things about it, and recent memories. Can you help me figure out my family tree? There are two grandparents, who had two children, who both got married and had 2 more children each. Totaling 10 people in all (Alex, David, Jamie, Jessica, John, Justin, Lincoln, Martha, Mary and Tina).\n\r\n1. One of Jamie's ancestors was David.\n\r\n2. John's sister gave birth to Tina.\n\r\n3. Mary went bowling with her nephew last Saturday.\n\r\n4. Alex is cousins with one of the girls.\n\r\n5. Justin married Mary.\n\r\n6. Jessica is not an ancestor, nor cousin of Tina.\n\r\n7. Lincoln's brother showed Justin's son his baseball cards.", "hint": "No hint available.", "answer": "Martha and David were the grandparents.\n\r\nThey gave birth to John and Mary.\n\r\nJohn married Jessica, who gave birth to Lincoln and Alex.\n\r\nMary married Justin and gave birth to Tina and Jamie.", "category": "Logic", "date": "06/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was going through some old family photos in the attic when I stumbled upon our family tree. I studied it for a couple minutes then went back down stairs to tell my mom about the family tree. The problem is I didn't study it long enough to remember the whole thing. I only remembered a couple things about it, and recent memories. Can you help me figure out my family tree? There are two grandparents, who had two children, who both got married and had 2 more children each. Totaling 10 people in all (Alex, David, Jamie, Jessica, John, Justin, Lincoln, Martha, Mary and Tina).\n\r\n1. One of Jamie's ancestors was David.\n\r\n2. John's sister gave birth to Tina.\n\r\n3. Mary went bowling with her nephew last Saturday.\n\r\n4. Alex is cousins with one of the girls.\n\r\n5. Justin married Mary.\n\r\n6. Jessica is not an ancestor, nor cousin of Tina.\n\r\n7. Lincoln's brother showed Justin's son his baseball cards.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMartha and David were the grandparents.\n\r\nThey gave birth to John and Mary.\n\r\nJohn married Jessica, who gave birth to Lincoln and Alex.\n\r\nMary married Justin and gave birth to Tina and Jamie.\n<|im_start|>answer\nMartha and David were the grandparents.\n\r\nThey gave birth to John and Mary.\n\r\nJohn married Jessica, who gave birth to Lincoln and Alex.\n\r\nMary married Justin and gave birth to Tina and Jamie.\n<|im_end|>" }, { "id": "#24144", "title": "Frequent Flyers", "fun": 2.97, "difficulty": 2.77, "author": "cinnamon30", "desc": "Garth and four other members of the Benton Remote Control Model Airplane Club took their hobby indoors and began working on long-term winter projects. Each member (each of whom holds a different executive office in the club) set up a new, uncluttered workbench in a different room of his or her home to construct a scale model of a different airplane. The modelers worked at different speeds. No two modelers spent the same amount of time on their projects. From the info provided, can you determine the model (one is a Bleriot XI) each modeler constructed, the office each modeler holds in the club, the room each one worked in and the number of weeks (6, 7, 8, 9, or 10) each modeler took to finish his or her project?\n\r\nModelers - Daniel, Garth, Gilda, Jerry, Thea\r\nOffice - alternate officer, president, secretary, treasurer, vice-president\r\nModel - A6M2 Zero, Bleriot XI, Fokker D VII, Messerschmitt Me 109, P-51D Mustang\r\nRoom - Bedroom, Den, Family, Sunroom, workroom\r\nWeeks - 6, 7, 8, 9, 10\n\r\n1. The vice-president, who isn't the one who built a model in six weeks, isn't the one who built a model in the bedroom.\n\r\n2. The secretary's model took fewer weeks to construct than did the A6M2 Zero. Neither Jerry nor Thea is the secretary; Thea constructed a model of a Fokker D VII.\n\r\n3. The club's alternate officer took exactly eight weeks to complete a model.\n\r\n4. Daniel took exactly one week fewer to construct his model than did the person who built a model in the den, who took exactly one week fewer to build a model than did the secretary.\n\r\n5. The model that was built in the sunroom, which is not the one that was constructed by the president, didn't take ten weeks to construct.\n\r\n6. The five modelers are the one who built a model in the family room, the treasurer, the one who built the P-51D Mustang, the vice-president, and the one who took seven weeks to finish a model.\n\r\n7. Gilda's model took fewer weeks to finish than did the Messerschmitt Me 109.", "hint": "No hint available.", "answer": "Daniel, Bleriot XI, President, Bedroom, 7 wks\r\nGarth, ME 109, Secretary, Family room, 9 wks\r\nGilda, P-51D Mustang, Alternate officer, den, 8 wks\r\nJerry, A6M2 Zero, Vice-president, Workroom, 10 wks\r\nThea, Fokker D VII, Treasurer, Sunroom, 6 wks\n\r\nThe number in brackets ( ) refers to the clue number.\n\r\nSecretary isn't 10 wks (2), 8 wks (3 - alternate), 6 or 7 wks (4), therefore is 9 wks. A6M2 is 10 wks (2), the one in the den is 8 wks and Daniel is 7 wks (4). 7 wks isn't vice president or treasurer (6), has to be president - only one left. Vice-president isn't 6 wks (1), therefore treasurer is - only one left. Vice-president is 10 wks [A6M2 Zero]. Family room isn't 6 wks [treasurer], 7wks or 10wks -vice president (6), therefore family room is 9 wks. Sunroom isn't 7 [president] or 10 wks (5), its 6 weeks, only one left. 10 weeks [vice-president] isn't bedroom (1), therefore 7 weeks is the bedroom. 10 weeks is the workshop - only one left. P-51D Mustang isn't secretary [family room], treasurer, vice-president, or president [7wks] from clue 6. Therefore it is the alternate officer. Fokker D VII made by Thea (2) isn't the secretary (2) or president [Daniel]; therefore it's the treasurer - only one left. Messerschmitt Me 109 is either 9 weeks or 7 weeks. If its 7 weeks, then Gilda's would be 6 weeks from clue 7. But we know Thea is 6 weeks, therefore the Me 109 has to be 9 weeks. This leaves the Bleriot XI at 7 weeks. From clue 4, Daniel is the president. Gilda has to be 8 weeks - it's the only number left below 9 weeks that we don't know who it is. Jerry isn't the secretary (2) thus he has to be the vice president - only one left. This leaves Garth as the secretary.", "category": "Logic-Grid", "date": "06/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGarth and four other members of the Benton Remote Control Model Airplane Club took their hobby indoors and began working on long-term winter projects. Each member (each of whom holds a different executive office in the club) set up a new, uncluttered workbench in a different room of his or her home to construct a scale model of a different airplane. The modelers worked at different speeds. No two modelers spent the same amount of time on their projects. From the info provided, can you determine the model (one is a Bleriot XI) each modeler constructed, the office each modeler holds in the club, the room each one worked in and the number of weeks (6, 7, 8, 9, or 10) each modeler took to finish his or her project?\n\r\nModelers - Daniel, Garth, Gilda, Jerry, Thea\r\nOffice - alternate officer, president, secretary, treasurer, vice-president\r\nModel - A6M2 Zero, Bleriot XI, Fokker D VII, Messerschmitt Me 109, P-51D Mustang\r\nRoom - Bedroom, Den, Family, Sunroom, workroom\r\nWeeks - 6, 7, 8, 9, 10\n\r\n1. The vice-president, who isn't the one who built a model in six weeks, isn't the one who built a model in the bedroom.\n\r\n2. The secretary's model took fewer weeks to construct than did the A6M2 Zero. Neither Jerry nor Thea is the secretary; Thea constructed a model of a Fokker D VII.\n\r\n3. The club's alternate officer took exactly eight weeks to complete a model.\n\r\n4. Daniel took exactly one week fewer to construct his model than did the person who built a model in the den, who took exactly one week fewer to build a model than did the secretary.\n\r\n5. The model that was built in the sunroom, which is not the one that was constructed by the president, didn't take ten weeks to construct.\n\r\n6. The five modelers are the one who built a model in the family room, the treasurer, the one who built the P-51D Mustang, the vice-president, and the one who took seven weeks to finish a model.\n\r\n7. Gilda's model took fewer weeks to finish than did the Messerschmitt Me 109.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDaniel, Bleriot XI, President, Bedroom, 7 wks\r\nGarth, ME 109, Secretary, Family room, 9 wks\r\nGilda, P-51D Mustang, Alternate officer, den, 8 wks\r\nJerry, A6M2 Zero, Vice-president, Workroom, 10 wks\r\nThea, Fokker D VII, Treasurer, Sunroom, 6 wks\n\r\nThe number in brackets ( ) refers to the clue number.\n\r\nSecretary isn't 10 wks (2), 8 wks (3 - alternate), 6 or 7 wks (4), therefore is 9 wks. A6M2 is 10 wks (2), the one in the den is 8 wks and Daniel is 7 wks (4). 7 wks isn't vice president or treasurer (6), has to be president - only one left. Vice-president isn't 6 wks (1), therefore treasurer is - only one left. Vice-president is 10 wks [A6M2 Zero]. Family room isn't 6 wks [treasurer], 7wks or 10wks -vice president (6), therefore family room is 9 wks. Sunroom isn't 7 [president] or 10 wks (5), its 6 weeks, only one left. 10 weeks [vice-president] isn't bedroom (1), therefore 7 weeks is the bedroom. 10 weeks is the workshop - only one left. P-51D Mustang isn't secretary [family room], treasurer, vice-president, or president [7wks] from clue 6. Therefore it is the alternate officer. Fokker D VII made by Thea (2) isn't the secretary (2) or president [Daniel]; therefore it's the treasurer - only one left. Messerschmitt Me 109 is either 9 weeks or 7 weeks. If its 7 weeks, then Gilda's would be 6 weeks from clue 7. But we know Thea is 6 weeks, therefore the Me 109 has to be 9 weeks. This leaves the Bleriot XI at 7 weeks. From clue 4, Daniel is the president. Gilda has to be 8 weeks - it's the only number left below 9 weeks that we don't know who it is. Jerry isn't the secretary (2) thus he has to be the vice president - only one left. This leaves Garth as the secretary.\n<|im_start|>answer\nDaniel, Bleriot XI, President, Bedroom, 7 wks\r\nGarth, ME 109, Secretary, Family room, 9 wks\r\nGilda, P-51D Mustang, Alternate officer, den, 8 wks\r\nJerry, A6M2 Zero, Vice-president, Workroom, 10 wks\r\nThea, Fokker D VII, Treasurer, Sunroom, 6 wks\n\r\nThe number in brackets ( ) refers to the clue number.\n\r\nSecretary isn't 10 wks (2), 8 wks (3 - alternate), 6 or 7 wks (4), therefore is 9 wks. A6M2 is 10 wks (2), the one in the den is 8 wks and Daniel is 7 wks (4). 7 wks isn't vice president or treasurer (6), has to be president - only one left. Vice-president isn't 6 wks (1), therefore treasurer is - only one left. Vice-president is 10 wks [A6M2 Zero]. Family room isn't 6 wks [treasurer], 7wks or 10wks -vice president (6), therefore family room is 9 wks. Sunroom isn't 7 [president] or 10 wks (5), its 6 weeks, only one left. 10 weeks [vice-president] isn't bedroom (1), therefore 7 weeks is the bedroom. 10 weeks is the workshop - only one left. P-51D Mustang isn't secretary [family room], treasurer, vice-president, or president [7wks] from clue 6. Therefore it is the alternate officer. Fokker D VII made by Thea (2) isn't the secretary (2) or president [Daniel]; therefore it's the treasurer - only one left. Messerschmitt Me 109 is either 9 weeks or 7 weeks. If its 7 weeks, then Gilda's would be 6 weeks from clue 7. But we know Thea is 6 weeks, therefore the Me 109 has to be 9 weeks. This leaves the Bleriot XI at 7 weeks. From clue 4, Daniel is the president. Gilda has to be 8 weeks - it's the only number left below 9 weeks that we don't know who it is. Jerry isn't the secretary (2) thus he has to be the vice president - only one left. This leaves Garth as the secretary.\n<|im_end|>" }, { "id": "#29696", "title": "Hour Glass", "fun": 2.97, "difficulty": 2.11, "author": "npf2005", "desc": "With a 7-minute hourglass and an 11-minute hourglass, can you explain the quickest way to time a boiling egg for 15 minutes?", "hint": "No hint available.", "answer": "Start both hour glasses as the egg is dropped in the boiling water. When the sand stops running in the 7-minute hourglass, turn it over. When the sand stops running in the 11-minute hourglass, turn the 7-minute hourglass over and leave the 11-minute hourglass. When the sand stops in the 7-minute hourglass, 15 minutes will have elapsed.", "category": "Logic", "date": "04/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith a 7-minute hourglass and an 11-minute hourglass, can you explain the quickest way to time a boiling egg for 15 minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStart both hour glasses as the egg is dropped in the boiling water. When the sand stops running in the 7-minute hourglass, turn it over. When the sand stops running in the 11-minute hourglass, turn the 7-minute hourglass over and leave the 11-minute hourglass. When the sand stops in the 7-minute hourglass, 15 minutes will have elapsed.\n<|im_start|>answer\nStart both hour glasses as the egg is dropped in the boiling water. When the sand stops running in the 7-minute hourglass, turn it over. When the sand stops running in the 11-minute hourglass, turn the 7-minute hourglass over and leave the 11-minute hourglass. When the sand stops in the 7-minute hourglass, 15 minutes will have elapsed.\n<|im_end|>" }, { "id": "#29500", "title": "Couch Potatoes", "fun": 2.97, "difficulty": 2.14, "author": "phrebh", "desc": "This logic grid is a little bit different from ones that we are used to seeing. It has two sets of clues. The harder set is listed below and an easier set is in the hint.\n\r\nThere are five guys (Dewey, Cheatem, Howe, Hackneyed, and Jokendunnit) who have different favorite snacks (bacon botty, Grandma Utz potato chips, pecan log, topfenstrudel, and Vegemite), sit on different seats (Barcalounger, chaise, couch, Lay-Z-Boy, and slipper chair), and watch different things on TV (The A-Team, Family Guy, the Marx Brothers, The Simpsons, and the Three Stooges). Using the clues provided, can you determine who eats what snack while watching what show, and sitting in what seat?\n\r\n1. The five programs are the Three Stooges, the one watched by Hackneyed, the one watched on the couch, the one watched while Grandma Utz chips are being eaten, and The A-Team.\r\n2. Someone's seat, snack, and show all have letters that are rarely used in English, but are often used in Euclidean Geometry.\r\n3. The five people are Jokendunnit, the one who eats pecan logs, the one who watches the Marx Brothers, Dewey, and the one who sits on a chaise lounge.\r\n4. The owner of the barcalounger loves action shows, but hates Vegemite.\r\n5. The five snacks are Vegemite, the one eaten on the Lay-Z-Boy, the one eaten while Family Guy is being watched, the one eaten by Howe, and topfenstrudel.\r\n6. Dewey, who watches the Three Stooges, does not eat meat, but does like his slipper chair.\r\n7. The five seats are the slipper chair, the one with bacon crumbs in it, the one Cheatem uses, the Barcalounger, and the one that The Simpsons is watched from.\r\n8. The owner of the couch loves pecans, and snacks on them while watching The Simpsons.", "hint": "1. Howe likes that The Simpsons has a weekly couch gag because he likes to watch from his couch.\r\n2. Jokendunnit, who likes topfenstrudel, watches TV from his Barcalounger.\r\n3. The slipper chair is covered with the same Vegemite crumbs as the Three Stooges DVD box set.\r\n4. Hackneyed likes to watch Family Guy while eating a bacon botty.\r\n5. Cheatem loves the nostalgic feelings that the flavor of Grandma Utz potato chips and the Marx Brothers bring him.\r\n6. Grandma Utz chips and chaises do not go together.", "answer": "Dewey eats Vegemite while watching the Three Stooges on his slipper chair.\r\nCheatem eats Grandma Utz while watching the Marx Brothers on his Lay-Z-Boy.\r\nHowe eats pecan logs while watching The Simpsons on his couch.\r\nHackneyed eats bacon botties while watching Family Guy on his Chaise.\r\nJokendunnit eats topfenstrudel while watching The A-Team on his Barcalounger.", "category": "Logic-Grid", "date": "04/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis logic grid is a little bit different from ones that we are used to seeing. It has two sets of clues. The harder set is listed below and an easier set is in the hint.\n\r\nThere are five guys (Dewey, Cheatem, Howe, Hackneyed, and Jokendunnit) who have different favorite snacks (bacon botty, Grandma Utz potato chips, pecan log, topfenstrudel, and Vegemite), sit on different seats (Barcalounger, chaise, couch, Lay-Z-Boy, and slipper chair), and watch different things on TV (The A-Team, Family Guy, the Marx Brothers, The Simpsons, and the Three Stooges). Using the clues provided, can you determine who eats what snack while watching what show, and sitting in what seat?\n\r\n1. The five programs are the Three Stooges, the one watched by Hackneyed, the one watched on the couch, the one watched while Grandma Utz chips are being eaten, and The A-Team.\r\n2. Someone's seat, snack, and show all have letters that are rarely used in English, but are often used in Euclidean Geometry.\r\n3. The five people are Jokendunnit, the one who eats pecan logs, the one who watches the Marx Brothers, Dewey, and the one who sits on a chaise lounge.\r\n4. The owner of the barcalounger loves action shows, but hates Vegemite.\r\n5. The five snacks are Vegemite, the one eaten on the Lay-Z-Boy, the one eaten while Family Guy is being watched, the one eaten by Howe, and topfenstrudel.\r\n6. Dewey, who watches the Three Stooges, does not eat meat, but does like his slipper chair.\r\n7. The five seats are the slipper chair, the one with bacon crumbs in it, the one Cheatem uses, the Barcalounger, and the one that The Simpsons is watched from.\r\n8. The owner of the couch loves pecans, and snacks on them while watching The Simpsons.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDewey eats Vegemite while watching the Three Stooges on his slipper chair.\r\nCheatem eats Grandma Utz while watching the Marx Brothers on his Lay-Z-Boy.\r\nHowe eats pecan logs while watching The Simpsons on his couch.\r\nHackneyed eats bacon botties while watching Family Guy on his Chaise.\r\nJokendunnit eats topfenstrudel while watching The A-Team on his Barcalounger.\n<|im_start|>answer\nDewey eats Vegemite while watching the Three Stooges on his slipper chair.\r\nCheatem eats Grandma Utz while watching the Marx Brothers on his Lay-Z-Boy.\r\nHowe eats pecan logs while watching The Simpsons on his couch.\r\nHackneyed eats bacon botties while watching Family Guy on his Chaise.\r\nJokendunnit eats topfenstrudel while watching The A-Team on his Barcalounger.\n<|im_end|>" }, { "id": "#29828", "title": "Pep-A-Mint Day Camp", "fun": 2.97, "difficulty": 2.52, "author": "peppamintp", "desc": "During last summer, Ziggy and four other part time counselors at Pep-A-Mint Day Camp each worked on a different weekday, Monday through Friday, on which they had complete responsibility for that day's activities. In the mornings, the counselor on duty took the campers into the woods for a nature hike, during which the campers were taught to recognize and gather a different type of wild growing food. In the afternoons, the counselor taught the campers a different craft. From this information and the clues below, can you determine each counselor's food, craft, and day?\n\r\n1. The counselor who taught the campers how to make miniature canoes worked the day before Jennifer, who worked the day before the woman who taught the children how to recognize edible mushrooms.\n\r\n2. The woman who taught the campers how to find wild raspberries worked earlier in the week than the one who taught clay modeling, who worked earlier in the week than Sally.\n\r\n3. The counselor who taught the kids to find blueberries worked the day before Patti; the one who taught jewelry making worked earlier in the week than the one who taught the children to recognize a cherry tree. All four counselors mentioned enjoying their jobs.\n\r\n4. The five counselors are Maureen, the one who taught the kids how to gather nuts, the one who taught soap carving, the one who worked on Tuesdays, and the one who worked on Fridays.\n\r\n5. The counselor who taught the campers to make collages (who isn't Sally) isn't the one who taught them to find wild cherries.", "hint": "No hint available.", "answer": "1. Ziggy, cherries, clay, Tuesday\r\n2. Jennifer, blueberries, soap, Thursday\r\n3. Maureen, raspberries, jewelry, Monday\r\n4. Patti, mushrooms, collage, Friday\r\n5. Sally, nuts, canoes, Wednesday", "category": "Logic-Grid", "date": "04/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring last summer, Ziggy and four other part time counselors at Pep-A-Mint Day Camp each worked on a different weekday, Monday through Friday, on which they had complete responsibility for that day's activities. In the mornings, the counselor on duty took the campers into the woods for a nature hike, during which the campers were taught to recognize and gather a different type of wild growing food. In the afternoons, the counselor taught the campers a different craft. From this information and the clues below, can you determine each counselor's food, craft, and day?\n\r\n1. The counselor who taught the campers how to make miniature canoes worked the day before Jennifer, who worked the day before the woman who taught the children how to recognize edible mushrooms.\n\r\n2. The woman who taught the campers how to find wild raspberries worked earlier in the week than the one who taught clay modeling, who worked earlier in the week than Sally.\n\r\n3. The counselor who taught the kids to find blueberries worked the day before Patti; the one who taught jewelry making worked earlier in the week than the one who taught the children to recognize a cherry tree. All four counselors mentioned enjoying their jobs.\n\r\n4. The five counselors are Maureen, the one who taught the kids how to gather nuts, the one who taught soap carving, the one who worked on Tuesdays, and the one who worked on Fridays.\n\r\n5. The counselor who taught the campers to make collages (who isn't Sally) isn't the one who taught them to find wild cherries.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Ziggy, cherries, clay, Tuesday\r\n2. Jennifer, blueberries, soap, Thursday\r\n3. Maureen, raspberries, jewelry, Monday\r\n4. Patti, mushrooms, collage, Friday\r\n5. Sally, nuts, canoes, Wednesday\n<|im_start|>answer\n1. Ziggy, cherries, clay, Tuesday\r\n2. Jennifer, blueberries, soap, Thursday\r\n3. Maureen, raspberries, jewelry, Monday\r\n4. Patti, mushrooms, collage, Friday\r\n5. Sally, nuts, canoes, Wednesday\n<|im_end|>" }, { "id": "#3672", "title": "Twin Trouble", "fun": 2.97, "difficulty": 2.21, "author": "PeaceJo", "desc": "Ryan and Craig were identical twins born in Seattle in 1961. Ryan was born before Craig, but according to their birth certificates, Craig was older than Ryan. How come?", "hint": "No hint available.", "answer": "Ryan and Craig were born in the fall on the day that the clocks are set back one hour. Ryan was born at 1:45am. Craig was born 30 minutes later. Since the clocks were set back at 2am, Craig's official time of birth was 1:15am.", "category": "Logic", "date": "04/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRyan and Craig were identical twins born in Seattle in 1961. Ryan was born before Craig, but according to their birth certificates, Craig was older than Ryan. How come?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRyan and Craig were born in the fall on the day that the clocks are set back one hour. Ryan was born at 1:45am. Craig was born 30 minutes later. Since the clocks were set back at 2am, Craig's official time of birth was 1:15am.\n<|im_start|>answer\nRyan and Craig were born in the fall on the day that the clocks are set back one hour. Ryan was born at 1:45am. Craig was born 30 minutes later. Since the clocks were set back at 2am, Craig's official time of birth was 1:15am.\n<|im_end|>" }, { "id": "#52315", "title": "Mansion Murder", "fun": 2.97, "difficulty": 1.56, "author": "wimpykidfan37", "desc": "The owner of a mansion was tragically murdered last night. The murderer was one of the three visitors to the mansion: Ian, Jeff, and Kevin. Here are some facts:\n\r\n1. The murderer arrived later than at least one of the other two visitors.\n\r\n2. One of the three visitors was the town's mayor. He arrived earlier than at least one of the other two visitors.\n\r\n3. The mayor arrived at midnight.\n\r\n4. Neither Ian nor Jeff arrived after midnight.\n\r\n5. The earlier arriver of Jeff and Kevin is not the mayor.\n\r\n6. The later arriver of Ian and Kevin is not the murderer.\n\r\nWho is the murderer?", "hint": "No hint available.", "answer": "Ian is the murderer.\n\r\nFrom facts 2 and 3, we know that at least one of the three men arrived after midnight. From fact 4, we know that it had to be Kevin. Since Kevin didn't arrive at midnight, he could not have been the mayor. And since Jeff obviously arrived before Kevin, fact 5 tells us that Jeff can't be the mayor either. Therefore, the mayor must be Ian.\n\r\nFact 6 tells us that Kevin, the latest arriver, could not have been the murderer, meaning it must be either Ian or Jeff. Fact 1 tells us that they didn't arrive at the same time, and fact 4 tells us that Jeff didn't arrive after midnight. Since we already know that Ian arrived right at midnight, Jeff must have arrived before midnight. As the earliest visitor, he couldn't have been the murderer, leaving only Ian.\n\r\nTherefore, Jeff arrived before midnight, Ian (both the mayor and the murderer) arrived at midnight, and Kevin arrived after midnight. It's scary to live in a town where the mayor is a murderer!!!", "category": "Logic", "date": "11/28/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe owner of a mansion was tragically murdered last night. The murderer was one of the three visitors to the mansion: Ian, Jeff, and Kevin. Here are some facts:\n\r\n1. The murderer arrived later than at least one of the other two visitors.\n\r\n2. One of the three visitors was the town's mayor. He arrived earlier than at least one of the other two visitors.\n\r\n3. The mayor arrived at midnight.\n\r\n4. Neither Ian nor Jeff arrived after midnight.\n\r\n5. The earlier arriver of Jeff and Kevin is not the mayor.\n\r\n6. The later arriver of Ian and Kevin is not the murderer.\n\r\nWho is the murderer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIan is the murderer.\n\r\nFrom facts 2 and 3, we know that at least one of the three men arrived after midnight. From fact 4, we know that it had to be Kevin. Since Kevin didn't arrive at midnight, he could not have been the mayor. And since Jeff obviously arrived before Kevin, fact 5 tells us that Jeff can't be the mayor either. Therefore, the mayor must be Ian.\n\r\nFact 6 tells us that Kevin, the latest arriver, could not have been the murderer, meaning it must be either Ian or Jeff. Fact 1 tells us that they didn't arrive at the same time, and fact 4 tells us that Jeff didn't arrive after midnight. Since we already know that Ian arrived right at midnight, Jeff must have arrived before midnight. As the earliest visitor, he couldn't have been the murderer, leaving only Ian.\n\r\nTherefore, Jeff arrived before midnight, Ian (both the mayor and the murderer) arrived at midnight, and Kevin arrived after midnight. It's scary to live in a town where the mayor is a murderer!!!\n<|im_start|>answer\nIan is the murderer.\n\r\nFrom facts 2 and 3, we know that at least one of the three men arrived after midnight. From fact 4, we know that it had to be Kevin. Since Kevin didn't arrive at midnight, he could not have been the mayor. And since Jeff obviously arrived before Kevin, fact 5 tells us that Jeff can't be the mayor either. Therefore, the mayor must be Ian.\n\r\nFact 6 tells us that Kevin, the latest arriver, could not have been the murderer, meaning it must be either Ian or Jeff. Fact 1 tells us that they didn't arrive at the same time, and fact 4 tells us that Jeff didn't arrive after midnight. Since we already know that Ian arrived right at midnight, Jeff must have arrived before midnight. As the earliest visitor, he couldn't have been the murderer, leaving only Ian.\n\r\nTherefore, Jeff arrived before midnight, Ian (both the mayor and the murderer) arrived at midnight, and Kevin arrived after midnight. It's scary to live in a town where the mayor is a murderer!!!\n<|im_end|>" }, { "id": "#26561", "title": "World Domination III", "fun": 2.97, "difficulty": 1.83, "author": "sweetime", "desc": "Mad scientist, Sassi the Sane, now had her secret potion, her hideout and her army worked out, now she just needed to work out which country to invade, in what order, and what weapons she should use to subdue each country.\n\r\nTo do this she gathered her four advisers (each of whom use a secret codename): Woodlady, Spambringer, Aquatic and Kayyou.\n\r\nThey each suggested a different country: Australia, America, England and Canada.\n\r\nAnd they each suggested a different weapon: saws, flames, famine, needles.\n\r\nThey each ended up agreeing on an order in which to invade the countries, so that one would be invaded first, another second, another third, and another fourth.\n\r\nCan you determine, from the following clues, which adviser suggested which country, which weapon, and which order it was agreed the country would be invaded in?\n\r\n1. It was decided that the country Woodlady suggested would be invaded last.\t\t\t\t\r\n2. Woodlady and Kayyou both suggested weapons which started with the same letter.\t\t\t\t\t\r\n3. The four countries suggested were: Australia, the one being invaded first, the one being attacked by needles, and the one suggested by Kayyou.\t\t\t\t\t\r\n4. It was not suggested that England be invaded with saws, and Canada will not be invaded first.\t\t\t\t\r\n5. The country being invaded second is not the country which will be invaded with saws.\t\t\t\t\t\r\n6. Australia will not be invaded third, nor will it be attacked by flames.\t\t\t\t\r\n7. The country being attacked with famine will not be invaded first.\t\t\t\t\r\n8. The four people are: the one using flames, the one whose country is being invaded fourth, the one who suggested Canada, and Aquatic.\t\t\t\t\r\n9. Aquatic did not suggest England, and he will not invade his country third.\t\t\t\t\t\t\r\n10. Spambringer will be using needles to invade his country, but he won't be doing it second.", "hint": "No hint available.", "answer": "Woodlady, Australia, famine, fourth.\r\nSpambringer, Canada, needles, third.\r\nAquatic, America, saws, first.\r\nKayyou, England, flame, second.", "category": "Logic-Grid", "date": "10/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad scientist, Sassi the Sane, now had her secret potion, her hideout and her army worked out, now she just needed to work out which country to invade, in what order, and what weapons she should use to subdue each country.\n\r\nTo do this she gathered her four advisers (each of whom use a secret codename): Woodlady, Spambringer, Aquatic and Kayyou.\n\r\nThey each suggested a different country: Australia, America, England and Canada.\n\r\nAnd they each suggested a different weapon: saws, flames, famine, needles.\n\r\nThey each ended up agreeing on an order in which to invade the countries, so that one would be invaded first, another second, another third, and another fourth.\n\r\nCan you determine, from the following clues, which adviser suggested which country, which weapon, and which order it was agreed the country would be invaded in?\n\r\n1. It was decided that the country Woodlady suggested would be invaded last.\t\t\t\t\r\n2. Woodlady and Kayyou both suggested weapons which started with the same letter.\t\t\t\t\t\r\n3. The four countries suggested were: Australia, the one being invaded first, the one being attacked by needles, and the one suggested by Kayyou.\t\t\t\t\t\r\n4. It was not suggested that England be invaded with saws, and Canada will not be invaded first.\t\t\t\t\r\n5. The country being invaded second is not the country which will be invaded with saws.\t\t\t\t\t\r\n6. Australia will not be invaded third, nor will it be attacked by flames.\t\t\t\t\r\n7. The country being attacked with famine will not be invaded first.\t\t\t\t\r\n8. The four people are: the one using flames, the one whose country is being invaded fourth, the one who suggested Canada, and Aquatic.\t\t\t\t\r\n9. Aquatic did not suggest England, and he will not invade his country third.\t\t\t\t\t\t\r\n10. Spambringer will be using needles to invade his country, but he won't be doing it second.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWoodlady, Australia, famine, fourth.\r\nSpambringer, Canada, needles, third.\r\nAquatic, America, saws, first.\r\nKayyou, England, flame, second.\n<|im_start|>answer\nWoodlady, Australia, famine, fourth.\r\nSpambringer, Canada, needles, third.\r\nAquatic, America, saws, first.\r\nKayyou, England, flame, second.\n<|im_end|>" }, { "id": "#49752", "title": "Palindromic Time", "fun": 2.97, "difficulty": 1.94, "author": "Puzzle_Master", "desc": "On a 12-hour digital clock, what is the smallest interval between two times that are palindromic (can be read forwards and backwards as the same number)?", "hint": "It's shorter than 10 minutes!", "answer": "The interval is two minutes, between the times of 9:59 and 10:01.", "category": "Math", "date": "02/03/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a 12-hour digital clock, what is the smallest interval between two times that are palindromic (can be read forwards and backwards as the same number)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe interval is two minutes, between the times of 9:59 and 10:01.\n<|im_start|>answer\nThe interval is two minutes, between the times of 9:59 and 10:01.\n<|im_end|>" }, { "id": "#43328", "title": "How Many Campers?", "fun": 2.97, "difficulty": 1.59, "author": "Thinker1995", "desc": "Camp Pineveiw's cook, Margaret Johnson, was just about to begin preparing the picnic lunch for all the campers. She already knew she needed to fill 55 bowls of the same size and capacity with the same amount of food. When she was done, she decided to read the guidelines for the picnic, just out of curiosity. The guidelines said:\n\r\n1. Every camper gets their own bowl of soup.\r\n2. Every two campers will get one bowl of spaghetti to share.\r\n3. Every three campers will get one bowl of salad to share.\r\n4. All campers are required to have their own helping of salad, spaghetti, and soup.\n\r\nAfter some rapid calculations, Margaret was able to figure out how many campers were going to the picnic. Can you?", "hint": "If there were only six campers, there would be six bowls of soup, three bowls of spaghetti, and two bowls of salad.", "answer": "30 campers.", "category": "Math", "date": "10/13/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCamp Pineveiw's cook, Margaret Johnson, was just about to begin preparing the picnic lunch for all the campers. She already knew she needed to fill 55 bowls of the same size and capacity with the same amount of food. When she was done, she decided to read the guidelines for the picnic, just out of curiosity. The guidelines said:\n\r\n1. Every camper gets their own bowl of soup.\r\n2. Every two campers will get one bowl of spaghetti to share.\r\n3. Every three campers will get one bowl of salad to share.\r\n4. All campers are required to have their own helping of salad, spaghetti, and soup.\n\r\nAfter some rapid calculations, Margaret was able to figure out how many campers were going to the picnic. Can you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n30 campers.\n<|im_start|>answer\n30 campers.\n<|im_end|>" }, { "id": "#21091", "title": "Trapdoors 3", "fun": 2.97, "difficulty": 1.8900000000000001, "author": "Therulerofthem", "desc": "You made it through the last door, but will you be that lucky again?\n\r\nSomeone is making this harder and harder. To prove this, there are 7 doors. Each door has its own clue and they're all true. The colours of the doors are:\r\nRed, Green, Blue, Yellow, Purple, Orange, and Brown.\n\r\nTHE CLUES\n\r\nRed door's clue: This door is in the middle. It's three spots away from the door to freedom.\n\r\nGreen door's clue: This door is three spaces from the colour made by mixing red and blue. It's farther left than the red door.\n\r\nBlue door's clue: This door is directly right of the purple door.\n\r\nYellow door's clue: This door is farther right than the red door but left of the purple door.\n\r\nPurple door's clue: This door is four spots away from the brown door.\n\r\nBrown door's clue: This door is next to the orange door.\n\r\nOrange door: This door is not the door to freedom.\n\r\nWhich colour door is the door to freedom?", "hint": "No hint available.", "answer": "The blue door leads to freedom. The order of the doors are:\n\r\nOrange, Brown, Green, Red, Yellow, Purple, Blue.", "category": "Logic", "date": "02/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou made it through the last door, but will you be that lucky again?\n\r\nSomeone is making this harder and harder. To prove this, there are 7 doors. Each door has its own clue and they're all true. The colours of the doors are:\r\nRed, Green, Blue, Yellow, Purple, Orange, and Brown.\n\r\nTHE CLUES\n\r\nRed door's clue: This door is in the middle. It's three spots away from the door to freedom.\n\r\nGreen door's clue: This door is three spaces from the colour made by mixing red and blue. It's farther left than the red door.\n\r\nBlue door's clue: This door is directly right of the purple door.\n\r\nYellow door's clue: This door is farther right than the red door but left of the purple door.\n\r\nPurple door's clue: This door is four spots away from the brown door.\n\r\nBrown door's clue: This door is next to the orange door.\n\r\nOrange door: This door is not the door to freedom.\n\r\nWhich colour door is the door to freedom?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe blue door leads to freedom. The order of the doors are:\n\r\nOrange, Brown, Green, Red, Yellow, Purple, Blue.\n<|im_start|>answer\nThe blue door leads to freedom. The order of the doors are:\n\r\nOrange, Brown, Green, Red, Yellow, Purple, Blue.\n<|im_end|>" }, { "id": "#29698", "title": "Can I Take Your Order?", "fun": 2.97, "difficulty": 2.22, "author": "peppamintp", "desc": "Pep the waitress had a colorful first day at the Fritter Fry. After the lunchtime rush, the manager took her aside and said, \"maybe we could switch you to the scrambled eggs department.\" Pep had scrambled all the orders. She had five tables with two people at each table, and in each case they both ordered the same meal, but this didn't seem to help Pep. From the information given, determine what the pair at each table ordered for meat (one ordered lamb), vegetables, and potatoes (one ordered them sauteed).\n\r\n1. The father of the child who ordered fish and peas sent back the baked potatoes that Pep brought by mistake.\r\n2. The married couple had to ask twice for their mushrooms. At another table, the correct order of salad and mashed potatoes arrived only after a series of errors.\r\n3. One customer complained when her broiled chicken arrived without her order of french fries.\r\n4. A woman sent for the manager after waiting half an hour for her pork and corn.\r\n5. Pep remembered the man who had ordered the beef and beans, but forgot which woman had ordered boiled potatoes for herself and her grown companion.", "hint": "No hint available.", "answer": "Man & woman, chicken, mushrooms, french fries.\r\n2 men, beef, beans, baked potatoes.\r\n2 women, pork corn boiled potatoes.\r\nMan & child, fish, peas, sauteed potatoes.\r\nWoman & child, lamb, salad, mashed potatoes.", "category": "Logic-Grid", "date": "04/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPep the waitress had a colorful first day at the Fritter Fry. After the lunchtime rush, the manager took her aside and said, \"maybe we could switch you to the scrambled eggs department.\" Pep had scrambled all the orders. She had five tables with two people at each table, and in each case they both ordered the same meal, but this didn't seem to help Pep. From the information given, determine what the pair at each table ordered for meat (one ordered lamb), vegetables, and potatoes (one ordered them sauteed).\n\r\n1. The father of the child who ordered fish and peas sent back the baked potatoes that Pep brought by mistake.\r\n2. The married couple had to ask twice for their mushrooms. At another table, the correct order of salad and mashed potatoes arrived only after a series of errors.\r\n3. One customer complained when her broiled chicken arrived without her order of french fries.\r\n4. A woman sent for the manager after waiting half an hour for her pork and corn.\r\n5. Pep remembered the man who had ordered the beef and beans, but forgot which woman had ordered boiled potatoes for herself and her grown companion.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMan & woman, chicken, mushrooms, french fries.\r\n2 men, beef, beans, baked potatoes.\r\n2 women, pork corn boiled potatoes.\r\nMan & child, fish, peas, sauteed potatoes.\r\nWoman & child, lamb, salad, mashed potatoes.\n<|im_start|>answer\nMan & woman, chicken, mushrooms, french fries.\r\n2 men, beef, beans, baked potatoes.\r\n2 women, pork corn boiled potatoes.\r\nMan & child, fish, peas, sauteed potatoes.\r\nWoman & child, lamb, salad, mashed potatoes.\n<|im_end|>" }, { "id": "#49485", "title": "Late Finals", "fun": 2.97, "difficulty": 1.76, "author": "whsprec", "desc": "It was finals week, with each class having a two hour final. Five roommates decided to go to a concert the night before each of them had a big final. As fate would have it, all five slept in. They all showed up late to their final and each told their professor a different excuse as to why he was late. Although, none of their professors cared, because the roommates had posted online what they had done.\n\r\nFrom the clues below, determine what final each roommate was late for, how late each was, and what excuse they used. \n\r\n1) Cody used the excuse of was helping a friend move and was, at most 72 minutes late.\r\n2) The roommate taking English, who wasn't Isaac, said he was delayed by an accident.\r\n3) Justin was taking History.\r\n4) The one who was 64 minutes late used the excuse of no power in the apartment; neither he nor the one who was 73 minutes late is taking Physics.\r\n5) The roommate taking Calculus wasn't Isaac or Conner: the latter showed up 68 minutes late.\r\n6) Sam didn't arrive 73 minutes late.\r\n7) The one who was 78 minutes late didn't use the excuse of writing down the wrong time and room number of the final.\r\n8) The one who was 71 minutes late was taking Business.", "hint": "No hint available.", "answer": "Sam was taking Calculus, was 64 minutes late, and used the excuse of no power.\r\nConner was taking English, was 68 minutes late, and used the excuse of accident.\r\nIsaac was taking Physics, was 78 minutes late, and used the excuse of broke-up with girl friend.\r\nJustin was taking History, was 73 minutes late, and used the excuse of wrong time and room.\r\nCody was taking Business, was 71 minutes late, and used the excuse of was helping a friend move.", "category": "Logic-Grid", "date": "05/27/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was finals week, with each class having a two hour final. Five roommates decided to go to a concert the night before each of them had a big final. As fate would have it, all five slept in. They all showed up late to their final and each told their professor a different excuse as to why he was late. Although, none of their professors cared, because the roommates had posted online what they had done.\n\r\nFrom the clues below, determine what final each roommate was late for, how late each was, and what excuse they used. \n\r\n1) Cody used the excuse of was helping a friend move and was, at most 72 minutes late.\r\n2) The roommate taking English, who wasn't Isaac, said he was delayed by an accident.\r\n3) Justin was taking History.\r\n4) The one who was 64 minutes late used the excuse of no power in the apartment; neither he nor the one who was 73 minutes late is taking Physics.\r\n5) The roommate taking Calculus wasn't Isaac or Conner: the latter showed up 68 minutes late.\r\n6) Sam didn't arrive 73 minutes late.\r\n7) The one who was 78 minutes late didn't use the excuse of writing down the wrong time and room number of the final.\r\n8) The one who was 71 minutes late was taking Business.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSam was taking Calculus, was 64 minutes late, and used the excuse of no power.\r\nConner was taking English, was 68 minutes late, and used the excuse of accident.\r\nIsaac was taking Physics, was 78 minutes late, and used the excuse of broke-up with girl friend.\r\nJustin was taking History, was 73 minutes late, and used the excuse of wrong time and room.\r\nCody was taking Business, was 71 minutes late, and used the excuse of was helping a friend move.\n<|im_start|>answer\nSam was taking Calculus, was 64 minutes late, and used the excuse of no power.\r\nConner was taking English, was 68 minutes late, and used the excuse of accident.\r\nIsaac was taking Physics, was 78 minutes late, and used the excuse of broke-up with girl friend.\r\nJustin was taking History, was 73 minutes late, and used the excuse of wrong time and room.\r\nCody was taking Business, was 71 minutes late, and used the excuse of was helping a friend move.\n<|im_end|>" }, { "id": "#44849", "title": "A New Look", "fun": 2.97, "difficulty": 2.54, "author": "mrsfessler", "desc": "5 ladies, each with a different natural hair color, went to the To Dye For Salon. Each get a different service performed by a different stylist. From the clues below, determine the first and last name of each lady, her natural hair color, her stylist's name and what service she had done.\n\r\n1. The five clients are Mrs. Schultz, the redhead, Carlos's client, Theresa, and the one getting a perm. The strawberry blond was excited about trying life as a brunette.\n\r\n2. Miss Grabowski and the one getting her eyebrows waxed preferred male stylists. Those with female stylists were Ann, Miss Koury, and the brunette getting her hair cut.\n\r\n3. The 5 stylists are represented by James, the one with Ms. Kelly as a client, the girl working on Kristen, the one with the ash blond client, and Miss Koury's stylist.\n\r\n4. The 2 blonds were Miss Oaks and Barbie's client. The redhead couldn't wait to go on her date with her new updo.\n\r\n5. Katy and Julia's clients were neither Gina, nor the raven tressed customer. Ms. Kelly and Gina didn't get chemicals applied to their hair.\n\r\n6. Maddy's stylist was grateful for the generous tip he received for the wax job. The brunette was either Katy's client or Kristen. The ash blond was either Gina or Katy's client.", "hint": "Perms and dye involve chemical applications.", "answer": "-Ann Oaks, Ash Blond, Perm, Katy\r\n-Theresa Koury, Strawberry Blond, Dye, Barbie\r\n-Kristen Schultz, Brunette, Cut, Julia\r\n-Maddy Kelly, Black, Wax, Carlos\r\n-Gina Grabowski, Red, Updo, James", "category": "Logic-Grid", "date": "07/13/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 ladies, each with a different natural hair color, went to the To Dye For Salon. Each get a different service performed by a different stylist. From the clues below, determine the first and last name of each lady, her natural hair color, her stylist's name and what service she had done.\n\r\n1. The five clients are Mrs. Schultz, the redhead, Carlos's client, Theresa, and the one getting a perm. The strawberry blond was excited about trying life as a brunette.\n\r\n2. Miss Grabowski and the one getting her eyebrows waxed preferred male stylists. Those with female stylists were Ann, Miss Koury, and the brunette getting her hair cut.\n\r\n3. The 5 stylists are represented by James, the one with Ms. Kelly as a client, the girl working on Kristen, the one with the ash blond client, and Miss Koury's stylist.\n\r\n4. The 2 blonds were Miss Oaks and Barbie's client. The redhead couldn't wait to go on her date with her new updo.\n\r\n5. Katy and Julia's clients were neither Gina, nor the raven tressed customer. Ms. Kelly and Gina didn't get chemicals applied to their hair.\n\r\n6. Maddy's stylist was grateful for the generous tip he received for the wax job. The brunette was either Katy's client or Kristen. The ash blond was either Gina or Katy's client.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-Ann Oaks, Ash Blond, Perm, Katy\r\n-Theresa Koury, Strawberry Blond, Dye, Barbie\r\n-Kristen Schultz, Brunette, Cut, Julia\r\n-Maddy Kelly, Black, Wax, Carlos\r\n-Gina Grabowski, Red, Updo, James\n<|im_start|>answer\n-Ann Oaks, Ash Blond, Perm, Katy\r\n-Theresa Koury, Strawberry Blond, Dye, Barbie\r\n-Kristen Schultz, Brunette, Cut, Julia\r\n-Maddy Kelly, Black, Wax, Carlos\r\n-Gina Grabowski, Red, Updo, James\n<|im_end|>" }, { "id": "#21680", "title": "A Game of Cards 2", "fun": 2.97, "difficulty": 2.32, "author": "cdrock", "desc": "With the money I made last time, I published the new game of cards. It has really spread around and is really getting popular with casinos. There is even one casino that was made just to play that game. One day, the manager of that casino came to my new office. He said that he wanted to play that same game of cards. Then he said if I win, I get your job, money, and everything; if you win, you get all my money, and you can own the casino. I knew I was good at this game, but this guy seemed a little tougher than my old boss. I accepted his challenge anyway. \n\r\nThis time there will be nine cards (6-Ace). They will all be face downward in an unknown order. The man will give me clues to figure it out. If I can figure it out, I win; if not, I lose. Can you help me figure out the order?\n\r\nClues:\n\r\n1. The \"9\" card is not next to the \"7\" card.\n\r\n2. The \"ace\" is two away from both the \"9\" card and the \"8\" card.\n\r\n3. The \"10\" and \"7\" cards are two away from the \"queen\". (1 in between)\n\r\n4 The \"king\" is somewhere to the left of the \"6\" card.\n\r\n5. The \"Queen\" is the fourth from the left.\n\r\n6. The \"8\" card is somewhere to the right of both the \"7\" and \"10\" card.\n\r\n7. The \"6\" card is next to the \"7\" card, but not the \"king\".\n\r\n8. The \"Jack\" is somewhere to the right of the \"king\".", "hint": "No hint available.", "answer": "king, 7, 6, queen, 9, 10, ace, jack, 8", "category": "Logic", "date": "03/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith the money I made last time, I published the new game of cards. It has really spread around and is really getting popular with casinos. There is even one casino that was made just to play that game. One day, the manager of that casino came to my new office. He said that he wanted to play that same game of cards. Then he said if I win, I get your job, money, and everything; if you win, you get all my money, and you can own the casino. I knew I was good at this game, but this guy seemed a little tougher than my old boss. I accepted his challenge anyway. \n\r\nThis time there will be nine cards (6-Ace). They will all be face downward in an unknown order. The man will give me clues to figure it out. If I can figure it out, I win; if not, I lose. Can you help me figure out the order?\n\r\nClues:\n\r\n1. The \"9\" card is not next to the \"7\" card.\n\r\n2. The \"ace\" is two away from both the \"9\" card and the \"8\" card.\n\r\n3. The \"10\" and \"7\" cards are two away from the \"queen\". (1 in between)\n\r\n4 The \"king\" is somewhere to the left of the \"6\" card.\n\r\n5. The \"Queen\" is the fourth from the left.\n\r\n6. The \"8\" card is somewhere to the right of both the \"7\" and \"10\" card.\n\r\n7. The \"6\" card is next to the \"7\" card, but not the \"king\".\n\r\n8. The \"Jack\" is somewhere to the right of the \"king\".\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nking, 7, 6, queen, 9, 10, ace, jack, 8\n<|im_start|>answer\nking, 7, 6, queen, 9, 10, ace, jack, 8\n<|im_end|>" }, { "id": "#24298", "title": "Vacation Time", "fun": 2.97, "difficulty": 2.59, "author": "phrebh", "desc": "Five people (Adam, Betty, Charlie, Darla, and Eddy) went on vacation. They all went to different locations (Australia, Bolivia, Canada, Denmark, and England), were gone for different amounts of time (1 to 5 weeks), had different colored luggage (black, red, blue, green, and yellow), and live in different cities (Albany, Boston, Charleston, Duluth, and Eureka). Using the clues below, figure out where each of them went, how long they were gone, what color their luggage is and where they are from.\n\r\n1. The black luggage was purchased in Albany.\r\n2. The person from Duluth was gone longer than the person who went to Australia but was gone less time than the person with the red luggage.\r\n3. Charlie had less than two weeks vacation from work for his trip.\r\n4. Adam, Darla, and Eddy all lived in the same time zone.\r\n5. Adam's luggage paid homage to his favorite baseball team.\r\n6. Eddy was in England for less time than the person from Boston was away.\r\n7. The person who went to Canada took her green luggage with her.\r\n8. The five travelers are Darla, the person who went to Australia, the person gone for 3 weeks, the man with the red luggage, and the person from Charleston.\r\n9. Adam didn't need to use his expertise in Spanish on his trip, which lasted less than 5 weeks.\r\n10. The person with the yellow luggage was gone longer than the person from Eureka.", "hint": "Albany, NY\r\nBoston, MA\r\nCharleston, SC\r\nDuluth, MN\r\nEureka, CA", "answer": "Adam, Denmark, 4 weeks, Red, Boston\r\nBetty, Canada, 3 weeks, Green, Duluth\r\nCharlie, Australia, 1 week, Blue, Eureka\r\nDarla, Bolivia, 5 weeks, Black, Albany\r\nEddy, England, 2 weeks, Yellow, Charleston", "category": "Logic-Grid", "date": "07/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people (Adam, Betty, Charlie, Darla, and Eddy) went on vacation. They all went to different locations (Australia, Bolivia, Canada, Denmark, and England), were gone for different amounts of time (1 to 5 weeks), had different colored luggage (black, red, blue, green, and yellow), and live in different cities (Albany, Boston, Charleston, Duluth, and Eureka). Using the clues below, figure out where each of them went, how long they were gone, what color their luggage is and where they are from.\n\r\n1. The black luggage was purchased in Albany.\r\n2. The person from Duluth was gone longer than the person who went to Australia but was gone less time than the person with the red luggage.\r\n3. Charlie had less than two weeks vacation from work for his trip.\r\n4. Adam, Darla, and Eddy all lived in the same time zone.\r\n5. Adam's luggage paid homage to his favorite baseball team.\r\n6. Eddy was in England for less time than the person from Boston was away.\r\n7. The person who went to Canada took her green luggage with her.\r\n8. The five travelers are Darla, the person who went to Australia, the person gone for 3 weeks, the man with the red luggage, and the person from Charleston.\r\n9. Adam didn't need to use his expertise in Spanish on his trip, which lasted less than 5 weeks.\r\n10. The person with the yellow luggage was gone longer than the person from Eureka.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam, Denmark, 4 weeks, Red, Boston\r\nBetty, Canada, 3 weeks, Green, Duluth\r\nCharlie, Australia, 1 week, Blue, Eureka\r\nDarla, Bolivia, 5 weeks, Black, Albany\r\nEddy, England, 2 weeks, Yellow, Charleston\n<|im_start|>answer\nAdam, Denmark, 4 weeks, Red, Boston\r\nBetty, Canada, 3 weeks, Green, Duluth\r\nCharlie, Australia, 1 week, Blue, Eureka\r\nDarla, Bolivia, 5 weeks, Black, Albany\r\nEddy, England, 2 weeks, Yellow, Charleston\n<|im_end|>" }, { "id": "#49582", "title": "Guess My House", "fun": 2.97, "difficulty": 1.3, "author": "dalfamnest", "desc": "Mac's new house number has three digits. When she challenged her friends to guess it, they tried: 135, 780, 785, and 732.\n\r\n\"That's amazing,\" Mac said. \"You've each guessed exactly one digit correctly and in its right place!\"\n\r\nWhat is Mac's house number?", "hint": "The fact that three guesses began with a 7 will give you a good start.", "answer": "182\n\r\nSolution:\r\nThe first digit must be 1 or 7. It can't be 7 as only one digit is correct in each guess. So it's 1.\n\r\nThe other digits in guess #1 (i.e. 3 and 5) must be incorrect. Therefore, from guess #3, the second digit is 8.\n\r\nGuess #4 has a correct digit which must be its third - 2.", "category": "Logic", "date": "08/31/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMac's new house number has three digits. When she challenged her friends to guess it, they tried: 135, 780, 785, and 732.\n\r\n\"That's amazing,\" Mac said. \"You've each guessed exactly one digit correctly and in its right place!\"\n\r\nWhat is Mac's house number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n182\n\r\nSolution:\r\nThe first digit must be 1 or 7. It can't be 7 as only one digit is correct in each guess. So it's 1.\n\r\nThe other digits in guess #1 (i.e. 3 and 5) must be incorrect. Therefore, from guess #3, the second digit is 8.\n\r\nGuess #4 has a correct digit which must be its third - 2.\n<|im_start|>answer\n182\n\r\nSolution:\r\nThe first digit must be 1 or 7. It can't be 7 as only one digit is correct in each guess. So it's 1.\n\r\nThe other digits in guess #1 (i.e. 3 and 5) must be incorrect. Therefore, from guess #3, the second digit is 8.\n\r\nGuess #4 has a correct digit which must be its third - 2.\n<|im_end|>" }, { "id": "#36469", "title": "Jail Message", "fun": 2.97, "difficulty": 2.09, "author": "LeafFan4life", "desc": "You are locked in a jail cell with no windows, and you need to tap out a message on the wall for the man in the other cell next to you. The problem is that you have to do it at exactly 9:15 PM, when the guard outside is switched, so your noise won't be noticed. You can't hear the switching of the guards through your walls, and you have no clock.\n\r\nThere is a faucet with water dripping very consistently from it in the corner, but you don't know if it is dripping at 30 or 40 or however many drops per minute, and that wouldn't give you the time in any case. You can just make out the chiming of a church bell, but it chimes just once at the top of each hour, so you can't tell the time from that. You can feel the wall facing west start to cool after the sun sets, but you don't know what time the sun is setting, and this isn't very precise in any case. Your dinner is always passed into your cell between 6:15 and 6:45. How do you determine when it is exactly 9:15 PM?", "hint": "No hint available.", "answer": "After dinner arrives, you listen for the church bell. Since dinner comes between 6:15 and 6:45, the next chiming has to be at 7:00 PM. When you hear it, you start to count the drips from the faucet until you hear the chime again at 8:00 PM. Divide the number of drips by four, and you'll have the number of drips that fall in fifteen minutes (Or you can divide by sixty to get the drops per minute, and then multiply this by fifteen). When the bell chimes again at 9:00, you start counting drips until you reach the specified number. It is now 9:15 PM, and time to tap out your message.", "category": "Logic", "date": "04/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are locked in a jail cell with no windows, and you need to tap out a message on the wall for the man in the other cell next to you. The problem is that you have to do it at exactly 9:15 PM, when the guard outside is switched, so your noise won't be noticed. You can't hear the switching of the guards through your walls, and you have no clock.\n\r\nThere is a faucet with water dripping very consistently from it in the corner, but you don't know if it is dripping at 30 or 40 or however many drops per minute, and that wouldn't give you the time in any case. You can just make out the chiming of a church bell, but it chimes just once at the top of each hour, so you can't tell the time from that. You can feel the wall facing west start to cool after the sun sets, but you don't know what time the sun is setting, and this isn't very precise in any case. Your dinner is always passed into your cell between 6:15 and 6:45. How do you determine when it is exactly 9:15 PM?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter dinner arrives, you listen for the church bell. Since dinner comes between 6:15 and 6:45, the next chiming has to be at 7:00 PM. When you hear it, you start to count the drips from the faucet until you hear the chime again at 8:00 PM. Divide the number of drips by four, and you'll have the number of drips that fall in fifteen minutes (Or you can divide by sixty to get the drops per minute, and then multiply this by fifteen). When the bell chimes again at 9:00, you start counting drips until you reach the specified number. It is now 9:15 PM, and time to tap out your message.\n<|im_start|>answer\nAfter dinner arrives, you listen for the church bell. Since dinner comes between 6:15 and 6:45, the next chiming has to be at 7:00 PM. When you hear it, you start to count the drips from the faucet until you hear the chime again at 8:00 PM. Divide the number of drips by four, and you'll have the number of drips that fall in fifteen minutes (Or you can divide by sixty to get the drops per minute, and then multiply this by fifteen). When the bell chimes again at 9:00, you start counting drips until you reach the specified number. It is now 9:15 PM, and time to tap out your message.\n<|im_end|>" }, { "id": "#35386", "title": "The Father of Algebra", "fun": 2.96, "difficulty": 1.98, "author": "buddyboy", "desc": "Diophantus was a Greek mathematician who lived in the third century. He was one of the first mathematicians to use algebraic symbols.\n\r\nMost of what is known about Diophantus's life comes from an algebraic riddle from around the early sixth century. The riddle states:\n\r\nDiophantus's youth lasted one sixth of his life. He grew a beard after one twelfth more. After one seventh more of his life, he married. 5 years later, he and his wife had a son. The son lived exactly one half as long as his father, and Diophantus died four years after his son. \n\r\nHow many years did Diophantus live?", "hint": "No hint available.", "answer": "The riddle, the \"facts\" of which may or may not be true, results in the following equation:\n\r\n x/6 + x/12 + x/7 + 5 + x/2 + 4 = x\n\r\nwhere x is Diophantus's age at the time of his death.\n\r\nTherefore, Diophantus lived exactly 84 years.", "category": "Math", "date": "02/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDiophantus was a Greek mathematician who lived in the third century. He was one of the first mathematicians to use algebraic symbols.\n\r\nMost of what is known about Diophantus's life comes from an algebraic riddle from around the early sixth century. The riddle states:\n\r\nDiophantus's youth lasted one sixth of his life. He grew a beard after one twelfth more. After one seventh more of his life, he married. 5 years later, he and his wife had a son. The son lived exactly one half as long as his father, and Diophantus died four years after his son. \n\r\nHow many years did Diophantus live?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe riddle, the \"facts\" of which may or may not be true, results in the following equation:\n\r\n x/6 + x/12 + x/7 + 5 + x/2 + 4 = x\n\r\nwhere x is Diophantus's age at the time of his death.\n\r\nTherefore, Diophantus lived exactly 84 years.\n<|im_start|>answer\nThe riddle, the \"facts\" of which may or may not be true, results in the following equation:\n\r\n x/6 + x/12 + x/7 + 5 + x/2 + 4 = x\n\r\nwhere x is Diophantus's age at the time of his death.\n\r\nTherefore, Diophantus lived exactly 84 years.\n<|im_end|>" }, { "id": "#23344", "title": "Hail to the Chef", "fun": 2.96, "difficulty": 3.21, "author": "cinnamon30", "desc": "Larry and four of his friends recently completed a creative cooking course. They were so confident of their new skills that each man hosted a dinner for the other four and their wives. On each night Monday through Friday, one of the men prepared a main course and a dessert, and no two made any of the same dishes. For each evening, determine the full name of the chef, the main course and the dessert he served.\n\r\nFirst Name - Larry, Harry, Barry, Gary, Terry\r\nLast name - O'Rourke, McKee, O'Neil, Owens, McPhail\r\nMain courses - chicken, ham, pork chops, bacon, steak\r\nDesserts - strawberry shortcake, pistachio parfait, cherry cobbler, mocha mousse, raspberry ripple\n\r\n1. Mr. O'Neil hosted dinner later in the week than the man who served chicken & cauliflower and earlier than the one who served cherry cobbler for dessert.\r\n2. Harry hosted dinner before Mr. Owens, who hosted before the man who prepared pork chops & peppers.\r\n3. Mr. McPhail's dinner was later in the week than the one which included strawberry shortcake and earlier than Terry's.\r\n4. The chicken dinner (which wasn't prepared by Harry) wasn't served with strawberry shortcake.\r\n5. McPhail didn't serve the raspberry ripple, which was served the day before the bacon & broccoli main course.\r\n6. Mr. Owens prepared neither the chicken dish nor the strawberry shortcake.\r\n7. Gary (who didn't make the cherry cobbler) was the chef the night after Barry.\r\n8. Terry (who isn't McKee) didn't prepare the steak & scallions main course.\r\n9. The mocha mousse dessert wasn't served with the ham & hominy.\r\n10. The pork chops weren't served by McKee or O'Rourke (who didn't make the cherry cobbler).\r\n11. Harry isn't Mr. McKee or Mr. O'Rourke.", "hint": "No hint available.", "answer": "Monday - Larry McKee, chicken, raspberry ripple\r\nTuesday - Harry O'Neil, bacon, strawberry shortcake\r\nWednesday - Barry Owens, steak, cherry cobbler\r\nThursday - Gary MacPhail, pork chops, mocha mousse\r\nFriday - Terry O'Rourke, ham, pistachio parfait", "category": "Logic-Grid", "date": "06/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLarry and four of his friends recently completed a creative cooking course. They were so confident of their new skills that each man hosted a dinner for the other four and their wives. On each night Monday through Friday, one of the men prepared a main course and a dessert, and no two made any of the same dishes. For each evening, determine the full name of the chef, the main course and the dessert he served.\n\r\nFirst Name - Larry, Harry, Barry, Gary, Terry\r\nLast name - O'Rourke, McKee, O'Neil, Owens, McPhail\r\nMain courses - chicken, ham, pork chops, bacon, steak\r\nDesserts - strawberry shortcake, pistachio parfait, cherry cobbler, mocha mousse, raspberry ripple\n\r\n1. Mr. O'Neil hosted dinner later in the week than the man who served chicken & cauliflower and earlier than the one who served cherry cobbler for dessert.\r\n2. Harry hosted dinner before Mr. Owens, who hosted before the man who prepared pork chops & peppers.\r\n3. Mr. McPhail's dinner was later in the week than the one which included strawberry shortcake and earlier than Terry's.\r\n4. The chicken dinner (which wasn't prepared by Harry) wasn't served with strawberry shortcake.\r\n5. McPhail didn't serve the raspberry ripple, which was served the day before the bacon & broccoli main course.\r\n6. Mr. Owens prepared neither the chicken dish nor the strawberry shortcake.\r\n7. Gary (who didn't make the cherry cobbler) was the chef the night after Barry.\r\n8. Terry (who isn't McKee) didn't prepare the steak & scallions main course.\r\n9. The mocha mousse dessert wasn't served with the ham & hominy.\r\n10. The pork chops weren't served by McKee or O'Rourke (who didn't make the cherry cobbler).\r\n11. Harry isn't Mr. McKee or Mr. O'Rourke.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday - Larry McKee, chicken, raspberry ripple\r\nTuesday - Harry O'Neil, bacon, strawberry shortcake\r\nWednesday - Barry Owens, steak, cherry cobbler\r\nThursday - Gary MacPhail, pork chops, mocha mousse\r\nFriday - Terry O'Rourke, ham, pistachio parfait\n<|im_start|>answer\nMonday - Larry McKee, chicken, raspberry ripple\r\nTuesday - Harry O'Neil, bacon, strawberry shortcake\r\nWednesday - Barry Owens, steak, cherry cobbler\r\nThursday - Gary MacPhail, pork chops, mocha mousse\r\nFriday - Terry O'Rourke, ham, pistachio parfait\n<|im_end|>" }, { "id": "#45551", "title": "Tournaments at Gaming Town", "fun": 2.96, "difficulty": 1.82, "author": "whsprec", "desc": "The town of Gaming holds five different tournaments throughout the year. People come from all over the country to compete and to watch. There are five different games and 5 different prizes for each tournament. Last year five different people won and they defeated 5 different people in the championship round. From the clues below determine the tournament champion, the runner-up, the game that they played, and the prize money for the winner.\n\r\n1 - Austin played against Blake; the amount Austin won and the amount won at Monopoly differed by 70 dollars.\r\n2 - Tori spent his time playing Magic; he won less than the person who beat Paul, who did not play poker.\r\n3 - It wasn't Chelsea who beat Caroline to win 630 dollars.\r\n4 - Penny won 700 dollars in his tournament.\r\n5 - The amount won playing Scrabble was immediately less than that won at poker.\r\n6 - Will did not lose to the winner of 610 dollars.", "hint": "No hint available.", "answer": "Austin beat Blake at chess to win 560 dollars\r\nChelsea beat Will at poker to win 720 dollars\r\nTori beat Shelby at Magic to win 610 dollars\r\nDon beat Caroline at Monopoly to win 630 dollars\r\nPenny beat Paul at Scrabble to win 700 dollars", "category": "Logic-Grid", "date": "10/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe town of Gaming holds five different tournaments throughout the year. People come from all over the country to compete and to watch. There are five different games and 5 different prizes for each tournament. Last year five different people won and they defeated 5 different people in the championship round. From the clues below determine the tournament champion, the runner-up, the game that they played, and the prize money for the winner.\n\r\n1 - Austin played against Blake; the amount Austin won and the amount won at Monopoly differed by 70 dollars.\r\n2 - Tori spent his time playing Magic; he won less than the person who beat Paul, who did not play poker.\r\n3 - It wasn't Chelsea who beat Caroline to win 630 dollars.\r\n4 - Penny won 700 dollars in his tournament.\r\n5 - The amount won playing Scrabble was immediately less than that won at poker.\r\n6 - Will did not lose to the winner of 610 dollars.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAustin beat Blake at chess to win 560 dollars\r\nChelsea beat Will at poker to win 720 dollars\r\nTori beat Shelby at Magic to win 610 dollars\r\nDon beat Caroline at Monopoly to win 630 dollars\r\nPenny beat Paul at Scrabble to win 700 dollars\n<|im_start|>answer\nAustin beat Blake at chess to win 560 dollars\r\nChelsea beat Will at poker to win 720 dollars\r\nTori beat Shelby at Magic to win 610 dollars\r\nDon beat Caroline at Monopoly to win 630 dollars\r\nPenny beat Paul at Scrabble to win 700 dollars\n<|im_end|>" }, { "id": "#363", "title": "The Right Switch", "fun": 2.96, "difficulty": 2.07, "author": "Noctus", "desc": "In front of you are three light switches. Only one does anything, and it turns on the light downstairs. From here you can't see the light, and it makes no sound. You must determine which switch operates the light, BUT you can only go check it once. How do you figure out which switch is for the light?", "hint": "Patience is a virtue.", "answer": "Flip any switch you want. Wait for about 5-10 minutes to let the bulb heat up. Flip that same switch off, and another one on. Go check the light. If it's off and hot, it was the first switch, if it's on it was the second and if it's cold and off, it was the last one.", "category": "Logic", "date": "03/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn front of you are three light switches. Only one does anything, and it turns on the light downstairs. From here you can't see the light, and it makes no sound. You must determine which switch operates the light, BUT you can only go check it once. How do you figure out which switch is for the light?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFlip any switch you want. Wait for about 5-10 minutes to let the bulb heat up. Flip that same switch off, and another one on. Go check the light. If it's off and hot, it was the first switch, if it's on it was the second and if it's cold and off, it was the last one.\n<|im_start|>answer\nFlip any switch you want. Wait for about 5-10 minutes to let the bulb heat up. Flip that same switch off, and another one on. Go check the light. If it's off and hot, it was the first switch, if it's on it was the second and if it's cold and off, it was the last one.\n<|im_end|>" }, { "id": "#18012", "title": "Prisoners and 2 Switches - Scenario A", "fun": 2.96, "difficulty": 3.23, "author": "biztycl", "desc": "The warden meets with 23 new prisoners when they arrive. He tells them, \"You may meet today and plan a strategy. But after today, you will be in isolated cells and will have no communication with one another. \n\r\n\"In the prison there is a switch room which contains two light switches labeled A and B, each of which can be in either the 'on' or the 'off' position. BOTH SWITCHES ARE IN THEIR OFF POSITIONS NOW.* The switches are not connected to anything. \n\r\n\"After today, from time to time whenever I feel so inclined, I will select one prisoner at random and escort him to the switch room. This prisoner will select one of the two switches and reverse its position. He must move one, but only one of the switches. He can't move both but he can't move none either. Then he'll be led back to his cell.\"\n\r\n\"No one else will enter the switch room until I lead the next prisoner there, and he'll be instructed to do the same thing. I'm going to choose prisoners at random. I may choose the same guy three times in a row, or I may jump around and come back.\"\n\r\n\"But, given enough time, everyone will eventually visit the switch room as many times as everyone else. At any time any one of you may declare to me, 'We have all visited the switch room.' \n\r\n\"If it is true, then you will all be set free. If it is false, and somebody has not yet visited the switch room, you will be fed to the alligators.\" \n\r\n*note - the only difference from Scenario B, the original position of the 2 switches are known.", "hint": "Assuming that:\n\r\nA) There is no restriction on the amount of time the prisoners could take before sending the notice to the warden that everyone has been to the switch room at least once.\n\r\nB) There is no restriction on the number of time each prisoner can visit the switch room \n\r\nC) The warden will not attempt any foul moves, such as intentionally not bringing a certain prisoner to the switch room forever.", "answer": "1.\tAppoint a \"scorekeeper\" and the other 22 prisoners as \"transmitters\".\n\r\n2.\tWhen a transmitter enter the switch room for the first time, he will flick switch B ON if he sees it in the OFF position. Alternatively, he will flick switch A if he sees switch B is in the ON position and waits for his next visit. The transmitter's mission is to find ONE opportunity to flick switch B to the ON position. After he completes his mission, he will flick switch A for all subsequent visits. In short, each transmitter's role is to send a signal to the scorekeeper that he has been to the switch room. \n\r\n3.\tThe scorekeeper's role is to flick off switch B whenever he sees it in the ON position. Each time he flicks off switch B he adds 1 to his score. When he sees switch B is already OFF, he flicks switch A instead and does not add to the score. As soon as he accumulates 22, he reports to the Warden.", "category": "Logic", "date": "06/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe warden meets with 23 new prisoners when they arrive. He tells them, \"You may meet today and plan a strategy. But after today, you will be in isolated cells and will have no communication with one another. \n\r\n\"In the prison there is a switch room which contains two light switches labeled A and B, each of which can be in either the 'on' or the 'off' position. BOTH SWITCHES ARE IN THEIR OFF POSITIONS NOW.* The switches are not connected to anything. \n\r\n\"After today, from time to time whenever I feel so inclined, I will select one prisoner at random and escort him to the switch room. This prisoner will select one of the two switches and reverse its position. He must move one, but only one of the switches. He can't move both but he can't move none either. Then he'll be led back to his cell.\"\n\r\n\"No one else will enter the switch room until I lead the next prisoner there, and he'll be instructed to do the same thing. I'm going to choose prisoners at random. I may choose the same guy three times in a row, or I may jump around and come back.\"\n\r\n\"But, given enough time, everyone will eventually visit the switch room as many times as everyone else. At any time any one of you may declare to me, 'We have all visited the switch room.' \n\r\n\"If it is true, then you will all be set free. If it is false, and somebody has not yet visited the switch room, you will be fed to the alligators.\" \n\r\n*note - the only difference from Scenario B, the original position of the 2 switches are known.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1.\tAppoint a \"scorekeeper\" and the other 22 prisoners as \"transmitters\".\n\r\n2.\tWhen a transmitter enter the switch room for the first time, he will flick switch B ON if he sees it in the OFF position. Alternatively, he will flick switch A if he sees switch B is in the ON position and waits for his next visit. The transmitter's mission is to find ONE opportunity to flick switch B to the ON position. After he completes his mission, he will flick switch A for all subsequent visits. In short, each transmitter's role is to send a signal to the scorekeeper that he has been to the switch room. \n\r\n3.\tThe scorekeeper's role is to flick off switch B whenever he sees it in the ON position. Each time he flicks off switch B he adds 1 to his score. When he sees switch B is already OFF, he flicks switch A instead and does not add to the score. As soon as he accumulates 22, he reports to the Warden.\n<|im_start|>answer\n1.\tAppoint a \"scorekeeper\" and the other 22 prisoners as \"transmitters\".\n\r\n2.\tWhen a transmitter enter the switch room for the first time, he will flick switch B ON if he sees it in the OFF position. Alternatively, he will flick switch A if he sees switch B is in the ON position and waits for his next visit. The transmitter's mission is to find ONE opportunity to flick switch B to the ON position. After he completes his mission, he will flick switch A for all subsequent visits. In short, each transmitter's role is to send a signal to the scorekeeper that he has been to the switch room. \n\r\n3.\tThe scorekeeper's role is to flick off switch B whenever he sees it in the ON position. Each time he flicks off switch B he adds 1 to his score. When he sees switch B is already OFF, he flicks switch A instead and does not add to the score. As soon as he accumulates 22, he reports to the Warden.\n<|im_end|>" }, { "id": "#46667", "title": "Disproving the Past", "fun": 2.96, "difficulty": 1.85, "author": "whsprec", "desc": "Dr. Bishop was a professor of antiquities. As a result, people would bring him artifacts to verify for authenticity. Some people would bring in forgeries to pass off as originals. One month five different people each brought in a manuscript claiming to be a lost work of the ancient world. The manuscripts were: Iter, De Re Militari, On the Festivals of Dionysus, Helicentric, and The Measurement of Earth. It turns out that all five were forgeries. The mistakes were: plagiarism, a posthumous reference, written with a ballpoint pen, made with 19th century paper, and written with 20th century ink. From the clues below determine who brought in the fake, what the title was, where they claimed to have found it, and what error proved it was a counterfeit.\n\r\n1) The easiest manuscript for Dr. Bishop to expose was found in the college library; it had been written with a ballpoint.\r\n2) The manuscript called On the Festivals of Dionysus was in a private collection.\r\n3) Helicentric, which wasn't brought in by Dane, was dismissed by a posthumous reference, when it referenced Seleucus, a Chaldean of Seleucia, who lived a century after Aristarchus.\r\n4) Clay wasn't the one who brought in the fake claimed to be found in the secret room.\r\n5) Keith's script, which wasn't On the Festivals of Dionysus, was discovered to be plagiarized from the works of Stesimbrotos of Thasos.\r\n6) Terry was sure he had found The Measurement of Earth by Eratosthenes, but he was wrong, and it wasn't because of the 20th century ink.\r\n7) Elijah's script, which didn't have a one word title, claimed to have been found in a church, and wasn't the one using ink from the 20th century.", "hint": "No hint available.", "answer": "Terry brought in The Measurement of Earth, found in a college library, written with a ballpoint.\r\nKeith brought in Iter , found in a secret room, plagiarized from later work.\r\nElijah brought in De Re Militari, found in a church, made from 19th century paper.\r\nClay brought in Helicentric, found in a cave, with a posthumous reference.\r\nDane brought in On the Festivals of Dionysus, from a private collection, written with 20th century ink.", "category": "Logic-Grid", "date": "04/05/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDr. Bishop was a professor of antiquities. As a result, people would bring him artifacts to verify for authenticity. Some people would bring in forgeries to pass off as originals. One month five different people each brought in a manuscript claiming to be a lost work of the ancient world. The manuscripts were: Iter, De Re Militari, On the Festivals of Dionysus, Helicentric, and The Measurement of Earth. It turns out that all five were forgeries. The mistakes were: plagiarism, a posthumous reference, written with a ballpoint pen, made with 19th century paper, and written with 20th century ink. From the clues below determine who brought in the fake, what the title was, where they claimed to have found it, and what error proved it was a counterfeit.\n\r\n1) The easiest manuscript for Dr. Bishop to expose was found in the college library; it had been written with a ballpoint.\r\n2) The manuscript called On the Festivals of Dionysus was in a private collection.\r\n3) Helicentric, which wasn't brought in by Dane, was dismissed by a posthumous reference, when it referenced Seleucus, a Chaldean of Seleucia, who lived a century after Aristarchus.\r\n4) Clay wasn't the one who brought in the fake claimed to be found in the secret room.\r\n5) Keith's script, which wasn't On the Festivals of Dionysus, was discovered to be plagiarized from the works of Stesimbrotos of Thasos.\r\n6) Terry was sure he had found The Measurement of Earth by Eratosthenes, but he was wrong, and it wasn't because of the 20th century ink.\r\n7) Elijah's script, which didn't have a one word title, claimed to have been found in a church, and wasn't the one using ink from the 20th century.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTerry brought in The Measurement of Earth, found in a college library, written with a ballpoint.\r\nKeith brought in Iter , found in a secret room, plagiarized from later work.\r\nElijah brought in De Re Militari, found in a church, made from 19th century paper.\r\nClay brought in Helicentric, found in a cave, with a posthumous reference.\r\nDane brought in On the Festivals of Dionysus, from a private collection, written with 20th century ink.\n<|im_start|>answer\nTerry brought in The Measurement of Earth, found in a college library, written with a ballpoint.\r\nKeith brought in Iter , found in a secret room, plagiarized from later work.\r\nElijah brought in De Re Militari, found in a church, made from 19th century paper.\r\nClay brought in Helicentric, found in a cave, with a posthumous reference.\r\nDane brought in On the Festivals of Dionysus, from a private collection, written with 20th century ink.\n<|im_end|>" }, { "id": "#13592", "title": "Wine Bottles", "fun": 2.96, "difficulty": 2.15, "author": "LoonyAx", "desc": "In a land far away, a kingdom was famed for its wine. In one month, the king was scheduled to throw a huge banquet in honor of his birthday. Unfortunately, the king had many enemies. One day, about a month prior to the banquet, he went down to the wine cellar and found a spy poisoning one of the wine bottles. Unfortunately, the king did not notice which of the bottles was poisoned. The spy was interrogated and questioned, but refused to answer. He said that since they didn't know which bottle was poisoned, they were all rendered useless. Since they couldn't get anything out of him, they killed the spy for his treachery. Before he died, however, the spy did tell them a few things about this particular poison: \n\r\n1.) The poison is so strong that any amount of dilution will have no effect on it, so if they tried to dilute the wines, it would still be poisonous. \r\n2.) The poison would take 1 month to work. Only if after 1 month someone dies, then you know he was poisoned. \n\r\nThis made the king very upset. Three brave men came forward and said they would sacrifice their lives to honor the king. \n\r\nIn short: \r\nYou have 8 wine bottles, 1 month, and 3 expendable men. Since you have 1 month, you only have one shot at this. At the end of the month, you have to know EXACTLY (without guessing) which wine bottle is poisoned and what other 7 are good. Obviously this will require arranging the 3 men to drink the bottles in a certain fashion.", "hint": "Think about all the possible outcomes that can happen at the end of the month. See if you can map that back to the bottles.", "answer": "Let's call the 3 men A, B and C.\r\nHere's how you should assign them to drink:\n\r\n1.) A\r\n2.) B\r\n3.) C\r\n4.) A, B\r\n5.) A, C\r\n6.) B, C\r\n7.) A, B, C\r\n8.) None\n\r\nin other words, if the 5th bottle was poisoned, then at the end of the month, A and C would die. The rule to help you here would be the power rule. It states that any set of items can be combined to form 2^n combinations. 2^3 = 8.", "category": "Logic", "date": "07/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a land far away, a kingdom was famed for its wine. In one month, the king was scheduled to throw a huge banquet in honor of his birthday. Unfortunately, the king had many enemies. One day, about a month prior to the banquet, he went down to the wine cellar and found a spy poisoning one of the wine bottles. Unfortunately, the king did not notice which of the bottles was poisoned. The spy was interrogated and questioned, but refused to answer. He said that since they didn't know which bottle was poisoned, they were all rendered useless. Since they couldn't get anything out of him, they killed the spy for his treachery. Before he died, however, the spy did tell them a few things about this particular poison: \n\r\n1.) The poison is so strong that any amount of dilution will have no effect on it, so if they tried to dilute the wines, it would still be poisonous. \r\n2.) The poison would take 1 month to work. Only if after 1 month someone dies, then you know he was poisoned. \n\r\nThis made the king very upset. Three brave men came forward and said they would sacrifice their lives to honor the king. \n\r\nIn short: \r\nYou have 8 wine bottles, 1 month, and 3 expendable men. Since you have 1 month, you only have one shot at this. At the end of the month, you have to know EXACTLY (without guessing) which wine bottle is poisoned and what other 7 are good. Obviously this will require arranging the 3 men to drink the bottles in a certain fashion.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet's call the 3 men A, B and C.\r\nHere's how you should assign them to drink:\n\r\n1.) A\r\n2.) B\r\n3.) C\r\n4.) A, B\r\n5.) A, C\r\n6.) B, C\r\n7.) A, B, C\r\n8.) None\n\r\nin other words, if the 5th bottle was poisoned, then at the end of the month, A and C would die. The rule to help you here would be the power rule. It states that any set of items can be combined to form 2^n combinations. 2^3 = 8.\n<|im_start|>answer\nLet's call the 3 men A, B and C.\r\nHere's how you should assign them to drink:\n\r\n1.) A\r\n2.) B\r\n3.) C\r\n4.) A, B\r\n5.) A, C\r\n6.) B, C\r\n7.) A, B, C\r\n8.) None\n\r\nin other words, if the 5th bottle was poisoned, then at the end of the month, A and C would die. The rule to help you here would be the power rule. It states that any set of items can be combined to form 2^n combinations. 2^3 = 8.\n<|im_end|>" }, { "id": "#42989", "title": "Olympic Meeting", "fun": 2.96, "difficulty": 2.65, "author": "MarcM1098", "desc": "Four friends, Bryan and Simon (men), and Emily and Tatiana (women), met at lunch to discuss the results of their Olympic competitions. They all had a different top 4 finish in a different competition, either the Triathlon (3 events), the Modern Pentathlon (5 events), the Heptathlon (7 events), or the Decathlon (10 events). They are all from English speaking countries (Australia, Britain, Canada, and the U.S.).\n\r\nSee if you can figure out where each person is from, which event they competed in, and in what position they finished.\n\r\n1. Both women received a medal. (Gold is awarded for first, silver for second, and bronze for third.)\r\n2. Tatiana competed in more events than the Briton.\r\n3. The Australian was proud of her silver medal.\r\n4. The Canadian had a better finish than the woman who competed in the Heptathlon.\r\n5. The American competed in more events than the person who won a bronze medal.\r\n6. The person who competed in the Modern Pentathlon didn't have the best finish, but it was better than Bryan.\r\n7. Emily is not Canadian.", "hint": "Based on clues 1 and 4, the woman who competed in the Heptathlon wasn't fourth. Therefore, the Canadian must have finished first or second.", "answer": "Bryan, the American, finished 4th in the Decathlon.\r\nEmily, the Briton, finished 3rd in the Modern Pentathlon.\r\nSimon, the Canadian, finished 1st in the Triathlon.\r\nTatiana, the Australian, finished 2nd in the Heptathlon.", "category": "Logic-Grid", "date": "09/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends, Bryan and Simon (men), and Emily and Tatiana (women), met at lunch to discuss the results of their Olympic competitions. They all had a different top 4 finish in a different competition, either the Triathlon (3 events), the Modern Pentathlon (5 events), the Heptathlon (7 events), or the Decathlon (10 events). They are all from English speaking countries (Australia, Britain, Canada, and the U.S.).\n\r\nSee if you can figure out where each person is from, which event they competed in, and in what position they finished.\n\r\n1. Both women received a medal. (Gold is awarded for first, silver for second, and bronze for third.)\r\n2. Tatiana competed in more events than the Briton.\r\n3. The Australian was proud of her silver medal.\r\n4. The Canadian had a better finish than the woman who competed in the Heptathlon.\r\n5. The American competed in more events than the person who won a bronze medal.\r\n6. The person who competed in the Modern Pentathlon didn't have the best finish, but it was better than Bryan.\r\n7. Emily is not Canadian.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBryan, the American, finished 4th in the Decathlon.\r\nEmily, the Briton, finished 3rd in the Modern Pentathlon.\r\nSimon, the Canadian, finished 1st in the Triathlon.\r\nTatiana, the Australian, finished 2nd in the Heptathlon.\n<|im_start|>answer\nBryan, the American, finished 4th in the Decathlon.\r\nEmily, the Briton, finished 3rd in the Modern Pentathlon.\r\nSimon, the Canadian, finished 1st in the Triathlon.\r\nTatiana, the Australian, finished 2nd in the Heptathlon.\n<|im_end|>" }, { "id": "#25980", "title": "Crossword Challenge", "fun": 2.96, "difficulty": 2.32, "author": "phrebh", "desc": "Three men (Ben, Frank, and John) and two women (Kellye and Margaret) were in a crossword puzzle solving contest. They each were working on a different themed puzzle (Asia, History, Medicine, Television, and War) with different types of writing implements (black ink, blue ink, green ink, red ink, and pencil) and each took a different amount of time to finish (3 minutes, 4 minutes, 5 minutes, 6 minutes, and 7 minutes). Who was working on what puzzle, with what implement, and how long did it take them?\n\r\n1. Ben, who did the Asia puzzle, took 1 minute longer than Margaret, but 1 minute less than the person who did the History puzzle.\n\r\n2. Kellye took longer than the person who used blue ink, and she didn't use black ink.\n\r\n3. Frank, who didn't use blue ink, took less time than the person who used red ink.\n\r\n4. The person who used a pencil didn't solve their puzzle in the least amount of time, but did solve it in less time than the man who solved the puzzle about Television.\n\r\n5. The person who used red ink solved their puzzle in less time than the person who used black ink.\n\r\n6. The woman who used green ink did the War puzzle, but did not solve it in the most amount of time.", "hint": "No hint available.", "answer": "Ben used blue ink to complete the Asia puzzle in 4 minutes.\r\nFrank used a pencil to complete the History puzzle in 5 minutes.\r\nJohn used black ink to complete the Television puzzle in 7 minutes.\r\nKellye used red ink to complete the Medicine puzzle in 6 minutes.\r\nMargaret used green ink to complete the War puzzle in 3 minutes.", "category": "Logic-Grid", "date": "09/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree men (Ben, Frank, and John) and two women (Kellye and Margaret) were in a crossword puzzle solving contest. They each were working on a different themed puzzle (Asia, History, Medicine, Television, and War) with different types of writing implements (black ink, blue ink, green ink, red ink, and pencil) and each took a different amount of time to finish (3 minutes, 4 minutes, 5 minutes, 6 minutes, and 7 minutes). Who was working on what puzzle, with what implement, and how long did it take them?\n\r\n1. Ben, who did the Asia puzzle, took 1 minute longer than Margaret, but 1 minute less than the person who did the History puzzle.\n\r\n2. Kellye took longer than the person who used blue ink, and she didn't use black ink.\n\r\n3. Frank, who didn't use blue ink, took less time than the person who used red ink.\n\r\n4. The person who used a pencil didn't solve their puzzle in the least amount of time, but did solve it in less time than the man who solved the puzzle about Television.\n\r\n5. The person who used red ink solved their puzzle in less time than the person who used black ink.\n\r\n6. The woman who used green ink did the War puzzle, but did not solve it in the most amount of time.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBen used blue ink to complete the Asia puzzle in 4 minutes.\r\nFrank used a pencil to complete the History puzzle in 5 minutes.\r\nJohn used black ink to complete the Television puzzle in 7 minutes.\r\nKellye used red ink to complete the Medicine puzzle in 6 minutes.\r\nMargaret used green ink to complete the War puzzle in 3 minutes.\n<|im_start|>answer\nBen used blue ink to complete the Asia puzzle in 4 minutes.\r\nFrank used a pencil to complete the History puzzle in 5 minutes.\r\nJohn used black ink to complete the Television puzzle in 7 minutes.\r\nKellye used red ink to complete the Medicine puzzle in 6 minutes.\r\nMargaret used green ink to complete the War puzzle in 3 minutes.\n<|im_end|>" }, { "id": "#26923", "title": "The Spookyville Potion Hunt", "fun": 2.96, "difficulty": 2.77, "author": "cdrock", "desc": "It is Halloween down in Spookyville and the residents are getting ready to do their annual potion finding contest. In this contest, each of 5 people are assigned an ingredient of the special potion that they are to find. The first one back with their ingredient is the winner. With the clues listed can you figure out who, what kind of monster they are, which ingredient they were assigned, and how long it took them to find it?\n\n\r\nNames: Mr. Jack, Mrs. Greenskin, Mr. Redeye, Ms. Trans, and Mr. Blood\r\nMonsters: skeleton, witch/warlock, vampire, ghost, and zombie\r\nIngredients: werewolf hair, vampire tooth, zombie blood, mummy bandage, and potion vial\r\nTime: 20 minutes, 15 minutes, 10 minutes, 5 minutes, and 3 minutes\n\r\n1. The skeleton, vampire, and ghost are: the monster that took 3 minutes to find their ingredient, Mr. Jack, and the monster that found the vampire tooth.\n\r\n2. The monster that took 20 minutes to find their ingredient wasn't Mr. Jack or Mr. Redeye.\n\r\n3. The skeleton either found the vampire tooth or the zombie blood.\n\r\n4. Ms. Trans and Mrs. Greenskin are: the vampire, and monster that took 3 minutes to find their ingredient.\n\r\n5. The zombie did not find the werewolf hair, which took 15 minutes to find.\n\r\n6. Mr. Blood took twice as long as the zombie.\n\r\n7. The zombie is either the monster that found the zombie blood, or the monster that took 10 minutes to find their ingredient.\n\r\n8. The mummy bandage wasn't found by Mrs. Greenskin (who did not find the blood) nor the ghost.\n\r\n9. The vampire either took 5 minutes to find its ingredient or found the zombie blood.\n\r\n10. The monster that took 5 minutes either found the vampire tooth or the mummy bandage.\n\r\n11. The vampire did not take 3 minutes to find its ingredient.\n\r\n12. Redeye did not find the mummy bandage", "hint": "No hint available.", "answer": "Mr. Jack - ghost - 15 - werewolf hair\r\nMrs. Greenskin - vampire - 5 - vampire tooth\r\nMr. Redeye - zombie - 10 - potion vial\r\nMs. Trans - skeleton - 3 - zombie blood\r\nMr. Blood - warlock - 20 - mummy bandage", "category": "Logic-Grid", "date": "11/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is Halloween down in Spookyville and the residents are getting ready to do their annual potion finding contest. In this contest, each of 5 people are assigned an ingredient of the special potion that they are to find. The first one back with their ingredient is the winner. With the clues listed can you figure out who, what kind of monster they are, which ingredient they were assigned, and how long it took them to find it?\n\n\r\nNames: Mr. Jack, Mrs. Greenskin, Mr. Redeye, Ms. Trans, and Mr. Blood\r\nMonsters: skeleton, witch/warlock, vampire, ghost, and zombie\r\nIngredients: werewolf hair, vampire tooth, zombie blood, mummy bandage, and potion vial\r\nTime: 20 minutes, 15 minutes, 10 minutes, 5 minutes, and 3 minutes\n\r\n1. The skeleton, vampire, and ghost are: the monster that took 3 minutes to find their ingredient, Mr. Jack, and the monster that found the vampire tooth.\n\r\n2. The monster that took 20 minutes to find their ingredient wasn't Mr. Jack or Mr. Redeye.\n\r\n3. The skeleton either found the vampire tooth or the zombie blood.\n\r\n4. Ms. Trans and Mrs. Greenskin are: the vampire, and monster that took 3 minutes to find their ingredient.\n\r\n5. The zombie did not find the werewolf hair, which took 15 minutes to find.\n\r\n6. Mr. Blood took twice as long as the zombie.\n\r\n7. The zombie is either the monster that found the zombie blood, or the monster that took 10 minutes to find their ingredient.\n\r\n8. The mummy bandage wasn't found by Mrs. Greenskin (who did not find the blood) nor the ghost.\n\r\n9. The vampire either took 5 minutes to find its ingredient or found the zombie blood.\n\r\n10. The monster that took 5 minutes either found the vampire tooth or the mummy bandage.\n\r\n11. The vampire did not take 3 minutes to find its ingredient.\n\r\n12. Redeye did not find the mummy bandage\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Jack - ghost - 15 - werewolf hair\r\nMrs. Greenskin - vampire - 5 - vampire tooth\r\nMr. Redeye - zombie - 10 - potion vial\r\nMs. Trans - skeleton - 3 - zombie blood\r\nMr. Blood - warlock - 20 - mummy bandage\n<|im_start|>answer\nMr. Jack - ghost - 15 - werewolf hair\r\nMrs. Greenskin - vampire - 5 - vampire tooth\r\nMr. Redeye - zombie - 10 - potion vial\r\nMs. Trans - skeleton - 3 - zombie blood\r\nMr. Blood - warlock - 20 - mummy bandage\n<|im_end|>" }, { "id": "#21235", "title": "A Giant Puzzle (Part 2)", "fun": 2.96, "difficulty": 1.7, "author": "cdrock", "desc": "I sorted out a bunch of shoes the other day and as such, when I came to the shirts, to put them in their correct position I felt pretty confident. I have to act fast because time is running out. Can you figure out the order of the shirts from the clues I was given?\n\r\nThe shirts are the same colors as the shoes - purple, red, blue, yellow, brown, orange, and green. \n\r\n1. The Yellow Shirt is not by the Orange Shirt.\n\r\n2. The two colors that start with \"b\" are not next to each other.\n\r\n3. The Red Shirt is directly between two of the colors with a second letter of \"r\".\n\r\n4. The Orange Shirt is the second to the left.\n\r\n5. The Blue Shirt is next to the Orange Shirt.\n\r\n6. Either the red, purple, or both are somewhere to the right of the Brown Shirt.\n\r\n7. The Yellow Shirt is next to the Green Shirt.\n\r\n8. The Green Shirt is 2 Shirts away from the Orange Shirt (1 in between).", "hint": "No hint available.", "answer": "blue, orange, red, green, yellow, brown, purple", "category": "Logic", "date": "02/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI sorted out a bunch of shoes the other day and as such, when I came to the shirts, to put them in their correct position I felt pretty confident. I have to act fast because time is running out. Can you figure out the order of the shirts from the clues I was given?\n\r\nThe shirts are the same colors as the shoes - purple, red, blue, yellow, brown, orange, and green. \n\r\n1. The Yellow Shirt is not by the Orange Shirt.\n\r\n2. The two colors that start with \"b\" are not next to each other.\n\r\n3. The Red Shirt is directly between two of the colors with a second letter of \"r\".\n\r\n4. The Orange Shirt is the second to the left.\n\r\n5. The Blue Shirt is next to the Orange Shirt.\n\r\n6. Either the red, purple, or both are somewhere to the right of the Brown Shirt.\n\r\n7. The Yellow Shirt is next to the Green Shirt.\n\r\n8. The Green Shirt is 2 Shirts away from the Orange Shirt (1 in between).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nblue, orange, red, green, yellow, brown, purple\n<|im_start|>answer\nblue, orange, red, green, yellow, brown, purple\n<|im_end|>" }, { "id": "#5494", "title": "The King's Ruby...", "fun": 2.95, "difficulty": 1.43, "author": "MonkeyPigDog", "desc": "The aging king is at Death's door. But, alas, he has no heir to follow in his noble steps. He decides a test will ensure that only the wisest subject in his kingdom will take the throne after his eventual passing. The test is simple: he places a 100 carat ruby in a golden chalice in the center of a 20 foot by 20 foot tapestry. The next ruler and successor to the throne must grasp the ruby from the chalice with his bare hand without suspending from the ceiling or stepping on the tapestry. Three days pass as nobleman after nobleman fails miserably to retrieve the ruby from its golden perch. On the fourth day, as the kingdom nobility looked on in shock and bewilderment, a sole young peasant boy grasped the ruby from the shimmering chalice without so much as his shadow gracing the tapestry. Their new king was chosen. How did he do it?", "hint": "Don't quit now, you're on a roll!", "answer": "The noblemen looked on in amazement as the peasant, starting from one end of the long stretch of tapestry, slowly and neatly rolled the fabric until eventually, sitting just inches away, his bare hand grasped the fiery ruby and the boy became king!", "category": "Logic", "date": "07/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe aging king is at Death's door. But, alas, he has no heir to follow in his noble steps. He decides a test will ensure that only the wisest subject in his kingdom will take the throne after his eventual passing. The test is simple: he places a 100 carat ruby in a golden chalice in the center of a 20 foot by 20 foot tapestry. The next ruler and successor to the throne must grasp the ruby from the chalice with his bare hand without suspending from the ceiling or stepping on the tapestry. Three days pass as nobleman after nobleman fails miserably to retrieve the ruby from its golden perch. On the fourth day, as the kingdom nobility looked on in shock and bewilderment, a sole young peasant boy grasped the ruby from the shimmering chalice without so much as his shadow gracing the tapestry. Their new king was chosen. How did he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe noblemen looked on in amazement as the peasant, starting from one end of the long stretch of tapestry, slowly and neatly rolled the fabric until eventually, sitting just inches away, his bare hand grasped the fiery ruby and the boy became king!\n<|im_start|>answer\nThe noblemen looked on in amazement as the peasant, starting from one end of the long stretch of tapestry, slowly and neatly rolled the fabric until eventually, sitting just inches away, his bare hand grasped the fiery ruby and the boy became king!\n<|im_end|>" }, { "id": "#28037", "title": "Slippery Slide Shakeup", "fun": 2.95, "difficulty": 1.01, "author": "Kalliann", "desc": "Once again, it is play-date at the park for five children. For the last two weeks, the parents have been frustrated with the mix-ups at the end of the day. In order to save time and avoid another mix-up, the mothers decided to send their kids to the slide. It was not until an hour later that they realized what had happened. During playtime, the kids decided to use the slide as a racetrack for their items, and at the bottom of the slide lay a pile of toys and socks. Please help these tired moms find the correct socks and toys. \n\r\nMoms: Shelby, Marie, Monica, Lisa, and Abbie\r\nChildren: Joey, Kate, Tori, Mike, and Jake\r\nSocks: Purple, White, Green, Red, and Black\r\nToys: Doll, Bear, Truck, Dinosaur, and Block \n\r\nClues: \n\r\n1. The children are Jake, the boy with a truck, Marie's daughter, the girl with purple socks, and Joey. \n\r\n2. The white socks belong to a girl. \n\r\n3. Abbie's daughter had a doll.\n\r\n4. Neither Jake nor Kate had purple socks, but Kate had her favorite teddy bear. \n\r\n5. Lisa, Joey's mom, was looking for his black socks and favorite dinosaur. \n\r\n6. Only one mother shared the same initial with her child. \n\r\n7. Shelby was looking for her son's red socks. \n\r\n8. Kate, Marie's daughter, hated the green socks that Mike had on.", "hint": "Tori and Kate are the only two girls.", "answer": "Shelby: Jake: Red Socks: Block\r\nLisa: Joey: Black Socks: Dinosaur\r\nAbbie: Tori: Purple Socks: Doll\r\nMonica: Mike: Green Socks: Truck\r\nMarie: Kate: White Socks: Bear", "category": "Logic-Grid", "date": "01/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce again, it is play-date at the park for five children. For the last two weeks, the parents have been frustrated with the mix-ups at the end of the day. In order to save time and avoid another mix-up, the mothers decided to send their kids to the slide. It was not until an hour later that they realized what had happened. During playtime, the kids decided to use the slide as a racetrack for their items, and at the bottom of the slide lay a pile of toys and socks. Please help these tired moms find the correct socks and toys. \n\r\nMoms: Shelby, Marie, Monica, Lisa, and Abbie\r\nChildren: Joey, Kate, Tori, Mike, and Jake\r\nSocks: Purple, White, Green, Red, and Black\r\nToys: Doll, Bear, Truck, Dinosaur, and Block \n\r\nClues: \n\r\n1. The children are Jake, the boy with a truck, Marie's daughter, the girl with purple socks, and Joey. \n\r\n2. The white socks belong to a girl. \n\r\n3. Abbie's daughter had a doll.\n\r\n4. Neither Jake nor Kate had purple socks, but Kate had her favorite teddy bear. \n\r\n5. Lisa, Joey's mom, was looking for his black socks and favorite dinosaur. \n\r\n6. Only one mother shared the same initial with her child. \n\r\n7. Shelby was looking for her son's red socks. \n\r\n8. Kate, Marie's daughter, hated the green socks that Mike had on.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShelby: Jake: Red Socks: Block\r\nLisa: Joey: Black Socks: Dinosaur\r\nAbbie: Tori: Purple Socks: Doll\r\nMonica: Mike: Green Socks: Truck\r\nMarie: Kate: White Socks: Bear\n<|im_start|>answer\nShelby: Jake: Red Socks: Block\r\nLisa: Joey: Black Socks: Dinosaur\r\nAbbie: Tori: Purple Socks: Doll\r\nMonica: Mike: Green Socks: Truck\r\nMarie: Kate: White Socks: Bear\n<|im_end|>" }, { "id": "#31915", "title": "Pound Puppies", "fun": 2.95, "difficulty": 1.99, "author": "PineappleMama", "desc": "Five friends saw a documentary on what happens to abandoned dogs. They were heartbroken when they found out that millions of animals are euthanized each year. They decided then and there to go to the pound and save one dog each. Can you figure out who adopted whom, what new name they gave their pet, what \"primary breed\" the pet was, and what color the dog's coats were?\n\r\nOwners--Jan, Jesse, Jamie, Jackie, and Jill\r\nPets--Laurel, Jasmine, Maggie (Magnolia), Hibby (Hibiscus), and Meg (Nutmeg)\r\nBreeds--Lab, Chihuahua, Mastiff, Great Pyrenees, and Pug\r\nCoats--White, Black, Brindle, Brown, and Fawn\n\r\nClues:\n\r\n1- One owner's name, pet's nickname, and pet's breed all have an equal number of letters, however the only link between owner's name and color is the letter \"a\".\n\r\n2- The Five Pups are: Hibby, the mastiff, the white dog, Maggie and Jan's black puppy.\n\r\n3- Jesse and Jan picked cute wittle puppy wuppies and thought Jackie and Jill were nuts for picking such large breeds, even though they did love the mastiff's beautiful brindle coat.\n\r\n4- Jamie absolutely loves two things in life, Hawaii and chocolate, so she instantly fell in love with the chocolate lab and of course named her Hibiscus.\n\r\n5- Jill thought that Jasmine was the biggest, most beautiful creature she'd ever seen, but all that long white hair gave Jackie a fit of sneezes. That's why she chose the big, cuddly, yet short-haired mastiff, Laurel.", "hint": "Jesse loves Mexican food, and chose Maggie because she is identical to her favorite spokes dog!\r\n\"Yo quiero Taco Bell!\"", "answer": "Jaime adopted Hibiscus, the brown (chocolate) Labrador.\r\nJesse adopted Magnolia, the fawn Chihuahua.\r\nJackie adopted Laurel, the brindle Mastiff.\r\nJan adopted Nutmeg, the black Pug.\r\nJill adopted Jasmine, the white Great Pyrenees", "category": "Logic-Grid", "date": "07/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends saw a documentary on what happens to abandoned dogs. They were heartbroken when they found out that millions of animals are euthanized each year. They decided then and there to go to the pound and save one dog each. Can you figure out who adopted whom, what new name they gave their pet, what \"primary breed\" the pet was, and what color the dog's coats were?\n\r\nOwners--Jan, Jesse, Jamie, Jackie, and Jill\r\nPets--Laurel, Jasmine, Maggie (Magnolia), Hibby (Hibiscus), and Meg (Nutmeg)\r\nBreeds--Lab, Chihuahua, Mastiff, Great Pyrenees, and Pug\r\nCoats--White, Black, Brindle, Brown, and Fawn\n\r\nClues:\n\r\n1- One owner's name, pet's nickname, and pet's breed all have an equal number of letters, however the only link between owner's name and color is the letter \"a\".\n\r\n2- The Five Pups are: Hibby, the mastiff, the white dog, Maggie and Jan's black puppy.\n\r\n3- Jesse and Jan picked cute wittle puppy wuppies and thought Jackie and Jill were nuts for picking such large breeds, even though they did love the mastiff's beautiful brindle coat.\n\r\n4- Jamie absolutely loves two things in life, Hawaii and chocolate, so she instantly fell in love with the chocolate lab and of course named her Hibiscus.\n\r\n5- Jill thought that Jasmine was the biggest, most beautiful creature she'd ever seen, but all that long white hair gave Jackie a fit of sneezes. That's why she chose the big, cuddly, yet short-haired mastiff, Laurel.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJaime adopted Hibiscus, the brown (chocolate) Labrador.\r\nJesse adopted Magnolia, the fawn Chihuahua.\r\nJackie adopted Laurel, the brindle Mastiff.\r\nJan adopted Nutmeg, the black Pug.\r\nJill adopted Jasmine, the white Great Pyrenees\n<|im_start|>answer\nJaime adopted Hibiscus, the brown (chocolate) Labrador.\r\nJesse adopted Magnolia, the fawn Chihuahua.\r\nJackie adopted Laurel, the brindle Mastiff.\r\nJan adopted Nutmeg, the black Pug.\r\nJill adopted Jasmine, the white Great Pyrenees\n<|im_end|>" }, { "id": "#19503", "title": "Party Aliens", "fun": 2.95, "difficulty": 2.36, "author": "Nishoo", "desc": "Jack holds an annual Costume Ball. This year George, Kyle, Mark, Victor and Zander decided to go dressed as Aliens. They all decided to identify themselves with a planet (Heldin, Kamus, Phoros, Rak & Tellurus), a unique body color (Green, Orange, Pink, Red & Yellow) and a unique physical feature (Eyes on Stalks, Forked Tail, Horns on Forehead, Three Eyes and Two Human Heads). From the information given, identify who identified himself with which planet, color and feature.\n\r\n1. The orange-colored alien inhabits Tellurus. His kind of alien is always fighting with Zander's kind of alien, whose planet is not Rak.\r\n2. Mark's costume alien had only two eyes and these were not on stalks.\r\n3. Victor came from Heldin. George was dressed in Yellow.\r\n4. The two-headed alien's kind are peace-loving and never fight; he is not from Rak and neither is he green.\r\n5. The alien from planet Kamus has a forked tail. The red alien has horns.\r\n6. The three-eyed alien is pink.", "hint": "What's the color of a devil and what's his unique feature ... hmmm", "answer": "George - Phoros - Yellow - Two Heads\r\nKyle - Tellurus - Orange - Eyes on Stalks\r\nMark - Rak - Red - Horns on Forehead\r\nVictor - Heldin - Pink - Three Eyes\r\nZander - Kamus - Green - Forked Tail", "category": "Logic-Grid", "date": "11/21/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack holds an annual Costume Ball. This year George, Kyle, Mark, Victor and Zander decided to go dressed as Aliens. They all decided to identify themselves with a planet (Heldin, Kamus, Phoros, Rak & Tellurus), a unique body color (Green, Orange, Pink, Red & Yellow) and a unique physical feature (Eyes on Stalks, Forked Tail, Horns on Forehead, Three Eyes and Two Human Heads). From the information given, identify who identified himself with which planet, color and feature.\n\r\n1. The orange-colored alien inhabits Tellurus. His kind of alien is always fighting with Zander's kind of alien, whose planet is not Rak.\r\n2. Mark's costume alien had only two eyes and these were not on stalks.\r\n3. Victor came from Heldin. George was dressed in Yellow.\r\n4. The two-headed alien's kind are peace-loving and never fight; he is not from Rak and neither is he green.\r\n5. The alien from planet Kamus has a forked tail. The red alien has horns.\r\n6. The three-eyed alien is pink.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGeorge - Phoros - Yellow - Two Heads\r\nKyle - Tellurus - Orange - Eyes on Stalks\r\nMark - Rak - Red - Horns on Forehead\r\nVictor - Heldin - Pink - Three Eyes\r\nZander - Kamus - Green - Forked Tail\n<|im_start|>answer\nGeorge - Phoros - Yellow - Two Heads\r\nKyle - Tellurus - Orange - Eyes on Stalks\r\nMark - Rak - Red - Horns on Forehead\r\nVictor - Heldin - Pink - Three Eyes\r\nZander - Kamus - Green - Forked Tail\n<|im_end|>" }, { "id": "#49397", "title": "Game Night With Friends", "fun": 2.95, "difficulty": 1.5, "author": "Rhythmic", "desc": "Five friends got together every December to celebrate the holidays. Last December, they decided they would like to see each other more often. So, they decided to schedule time where they got to play their favourite games and share their favourite snacks. Can you figure out their schedule?\n\r\nFriends: Andrea, Jennifer, Mark, Susan, Travis\r\nGames: Rummy, Go Fish, Monopoly, Chess, Charades\r\nMonths: January, March, June, August, October\r\nSnacks: Chips, Donuts, Fruit, Pretzels, Chicken wings\n\r\n1) The five friends are Jennifer, Mark, the rummy player, the one who signed up for January, and the pretzel bringer.\n\r\n2) Susan wanted as much time as possible to prepare even though her favourite game only requires a deck of cards.\n\r\n3) Jennifer loves meat and chose her snack and game accordingly.\n\r\n4) Mark is very active and likes to move around a lot when he plays games.\n\r\n5) When one friend signed up for June, Andrea laughed and said, \"Donuts? Are you serious?\"\n\r\n6) Andrea picked the healthiest snack for the body and the game she deemed most stimulating for the mind. Some of the others wondered why she picked a game for only two players since they would have to do a tournament.\n\r\n7) Mark signed up earlier in the year than Travis.\n\r\n8) The rummy player did not sign up to bring what he or she considered to be a breakfast food.\n\r\n9) Everyone agreed that it would be nice to have pretzels in the summer and chips in the fall.", "hint": "For this puzzle, assume summer months are June, July, and August, whereas fall months are September, October, and November.", "answer": "Andrea loves chess, signed up for January, and agreed to bring fruit.\r\nJennifer loves Go Fish, signed up for March, and agreed to bring wings.\r\nMark loves charades, signed up for June, and agreed to bring donuts.\r\nSusan loves rummy, signed up for October, and agreed to bring chips.\r\nTravis loves Monopoly, signed up for August, and agreed to bring pretzels.", "category": "Logic-Grid", "date": "03/27/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends got together every December to celebrate the holidays. Last December, they decided they would like to see each other more often. So, they decided to schedule time where they got to play their favourite games and share their favourite snacks. Can you figure out their schedule?\n\r\nFriends: Andrea, Jennifer, Mark, Susan, Travis\r\nGames: Rummy, Go Fish, Monopoly, Chess, Charades\r\nMonths: January, March, June, August, October\r\nSnacks: Chips, Donuts, Fruit, Pretzels, Chicken wings\n\r\n1) The five friends are Jennifer, Mark, the rummy player, the one who signed up for January, and the pretzel bringer.\n\r\n2) Susan wanted as much time as possible to prepare even though her favourite game only requires a deck of cards.\n\r\n3) Jennifer loves meat and chose her snack and game accordingly.\n\r\n4) Mark is very active and likes to move around a lot when he plays games.\n\r\n5) When one friend signed up for June, Andrea laughed and said, \"Donuts? Are you serious?\"\n\r\n6) Andrea picked the healthiest snack for the body and the game she deemed most stimulating for the mind. Some of the others wondered why she picked a game for only two players since they would have to do a tournament.\n\r\n7) Mark signed up earlier in the year than Travis.\n\r\n8) The rummy player did not sign up to bring what he or she considered to be a breakfast food.\n\r\n9) Everyone agreed that it would be nice to have pretzels in the summer and chips in the fall.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndrea loves chess, signed up for January, and agreed to bring fruit.\r\nJennifer loves Go Fish, signed up for March, and agreed to bring wings.\r\nMark loves charades, signed up for June, and agreed to bring donuts.\r\nSusan loves rummy, signed up for October, and agreed to bring chips.\r\nTravis loves Monopoly, signed up for August, and agreed to bring pretzels.\n<|im_start|>answer\nAndrea loves chess, signed up for January, and agreed to bring fruit.\r\nJennifer loves Go Fish, signed up for March, and agreed to bring wings.\r\nMark loves charades, signed up for June, and agreed to bring donuts.\r\nSusan loves rummy, signed up for October, and agreed to bring chips.\r\nTravis loves Monopoly, signed up for August, and agreed to bring pretzels.\n<|im_end|>" }, { "id": "#48279", "title": "Katie's Birthday Party", "fun": 2.95, "difficulty": 2.88, "author": "didem666", "desc": "Katie has a birthday party. She has invited 5 friends (Julie, Suzie, Yasmin, David, Richard) and their spouses (Drew, Barry, Conner, Sally, James) to her party. Each friend brings a gift (music box, scarf, necklace, perfume, handbag) and dessert (apple pie, chocolate cake, muffins, cupcakes, cookies) and they all arrive at different time (7:00, 7:15, 7:30, 7:45, 8:00). So try to find the spouses, the gifts, the desserts, and the arrival time of each friend.\n\r\n1. The five friends are: Julie, the one who arrives last, the one who brings the muffins, the one whose husband is Barry, and the one who brings the perfume.\r\n2. Neither David nor Richard arrives first, but one of them arrives last.\r\n3. Yasmin doesn't like eating or cooking fruit.\r\n4. James (who shares his initial with his wife) is the husband who arrives first.\r\n5. Katie's female friends are the ones who bring the necklace, the music box, and the handbag.\r\n6. Julie's husband is a musician so he likes gifts about music.\r\n7. Neither Suzie nor Julie is a fan of chocolate.\r\n8. The guest who arrives second either brings the handbag or brings the chocolate cake.\r\n9. Neither Conner's wife nor Yasmin brings the cupcakes.\r\n10. Sally, whose husband neither likes perfumes nor cupcakes, is famous for her delicious cookies.\r\n11. David and his wife arrive 30 minutes later than the guest who brings the muffins.\r\n12. The guest who brings the cupcakes is the one who arrives after the guest who brings the necklace.", "hint": "Drew is female.", "answer": "Julie, James, music box, 7:00, apple pie\r\nSuzie, Conner, handbag, 7:15, muffins\r\nYasmin, Barry, necklace, 7:30, chocolate cake\r\nDavid, Drew, perfume, 7:45, cupcakes\r\nRichard, Sally, scarf, 8:00, cookies", "category": "Logic-Grid", "date": "12/11/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKatie has a birthday party. She has invited 5 friends (Julie, Suzie, Yasmin, David, Richard) and their spouses (Drew, Barry, Conner, Sally, James) to her party. Each friend brings a gift (music box, scarf, necklace, perfume, handbag) and dessert (apple pie, chocolate cake, muffins, cupcakes, cookies) and they all arrive at different time (7:00, 7:15, 7:30, 7:45, 8:00). So try to find the spouses, the gifts, the desserts, and the arrival time of each friend.\n\r\n1. The five friends are: Julie, the one who arrives last, the one who brings the muffins, the one whose husband is Barry, and the one who brings the perfume.\r\n2. Neither David nor Richard arrives first, but one of them arrives last.\r\n3. Yasmin doesn't like eating or cooking fruit.\r\n4. James (who shares his initial with his wife) is the husband who arrives first.\r\n5. Katie's female friends are the ones who bring the necklace, the music box, and the handbag.\r\n6. Julie's husband is a musician so he likes gifts about music.\r\n7. Neither Suzie nor Julie is a fan of chocolate.\r\n8. The guest who arrives second either brings the handbag or brings the chocolate cake.\r\n9. Neither Conner's wife nor Yasmin brings the cupcakes.\r\n10. Sally, whose husband neither likes perfumes nor cupcakes, is famous for her delicious cookies.\r\n11. David and his wife arrive 30 minutes later than the guest who brings the muffins.\r\n12. The guest who brings the cupcakes is the one who arrives after the guest who brings the necklace.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJulie, James, music box, 7:00, apple pie\r\nSuzie, Conner, handbag, 7:15, muffins\r\nYasmin, Barry, necklace, 7:30, chocolate cake\r\nDavid, Drew, perfume, 7:45, cupcakes\r\nRichard, Sally, scarf, 8:00, cookies\n<|im_start|>answer\nJulie, James, music box, 7:00, apple pie\r\nSuzie, Conner, handbag, 7:15, muffins\r\nYasmin, Barry, necklace, 7:30, chocolate cake\r\nDavid, Drew, perfume, 7:45, cupcakes\r\nRichard, Sally, scarf, 8:00, cookies\n<|im_end|>" }, { "id": "#20955", "title": "Comments Please!", "fun": 2.95, "difficulty": 2.39, "author": "lorial", "desc": "A community of generous, smart, happy individuals contribute their logic problems to their favourite website. They all hope that others will enjoy their puzzles and help where necessary with constructive criticism. This happens most of the time, but sometimes a few users of the site consider they should be extremely rude to get across their point. \n\r\nWhich individuals submitted which teaser and which non-contributors made which rude comments about them?\n\r\nAngryone included the word boring in his comment that was not about the puzzle Chicken Bob.\n\r\nPerfect Pete roared with laughter on seeing garbage written against his teaser, fortunately Pete was not too sensitive.\n\r\nFunto Moan did not write pointless or tedious in his comment, but his comment was about either Silly Snails or Fried Egg\n\r\nOrrible's comment (not tedious) on Jolly Jim's puzzle was not about Hot Legs.\n\r\nThe End and Hot Legs puzzles were not commented on by Angryone.\n\r\nHappy Henry wrote the puzzle Chicken Bob, it wasn't commented on by Nasty Work.\n\r\nFunto Moan did not comment upon Perfect Pete's puzzle.\n\r\nNice Nell did not see the comment Utter nonsense written against her puzzle, and her puzzle was not Silly Snails.\n\r\nContributor: Gentle George, Happy Henry, Jolly Jim, Nice Nell, Perfect Pete\r\nPuzzle Name: Chicken Bob, Fried Egg, Hot Legs, Silly Snails, The End\r\nNon-Contributor: Angryone, Funto Moan, Orrible, Nasty Work, Pickyhole\r\nComment: Boring, Garbage, Pointless, Tedious, Utter nonsense", "hint": "No hint available.", "answer": "Gentle George / Silly Snails / Funto Moan / Utter nonsense\r\nHappy Henry / Chicken Bob / Pickyhole / Tedious\r\nJolly Jim / The End / Orrible / Pointless\r\nNice Nell / Fried Egg / Angryone / Boring\r\nPerfect Pete / Hot Legs / Nasty Work / Garbage", "category": "Logic-Grid", "date": "02/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA community of generous, smart, happy individuals contribute their logic problems to their favourite website. They all hope that others will enjoy their puzzles and help where necessary with constructive criticism. This happens most of the time, but sometimes a few users of the site consider they should be extremely rude to get across their point. \n\r\nWhich individuals submitted which teaser and which non-contributors made which rude comments about them?\n\r\nAngryone included the word boring in his comment that was not about the puzzle Chicken Bob.\n\r\nPerfect Pete roared with laughter on seeing garbage written against his teaser, fortunately Pete was not too sensitive.\n\r\nFunto Moan did not write pointless or tedious in his comment, but his comment was about either Silly Snails or Fried Egg\n\r\nOrrible's comment (not tedious) on Jolly Jim's puzzle was not about Hot Legs.\n\r\nThe End and Hot Legs puzzles were not commented on by Angryone.\n\r\nHappy Henry wrote the puzzle Chicken Bob, it wasn't commented on by Nasty Work.\n\r\nFunto Moan did not comment upon Perfect Pete's puzzle.\n\r\nNice Nell did not see the comment Utter nonsense written against her puzzle, and her puzzle was not Silly Snails.\n\r\nContributor: Gentle George, Happy Henry, Jolly Jim, Nice Nell, Perfect Pete\r\nPuzzle Name: Chicken Bob, Fried Egg, Hot Legs, Silly Snails, The End\r\nNon-Contributor: Angryone, Funto Moan, Orrible, Nasty Work, Pickyhole\r\nComment: Boring, Garbage, Pointless, Tedious, Utter nonsense\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGentle George / Silly Snails / Funto Moan / Utter nonsense\r\nHappy Henry / Chicken Bob / Pickyhole / Tedious\r\nJolly Jim / The End / Orrible / Pointless\r\nNice Nell / Fried Egg / Angryone / Boring\r\nPerfect Pete / Hot Legs / Nasty Work / Garbage\n<|im_start|>answer\nGentle George / Silly Snails / Funto Moan / Utter nonsense\r\nHappy Henry / Chicken Bob / Pickyhole / Tedious\r\nJolly Jim / The End / Orrible / Pointless\r\nNice Nell / Fried Egg / Angryone / Boring\r\nPerfect Pete / Hot Legs / Nasty Work / Garbage\n<|im_end|>" }, { "id": "#18715", "title": "Round Table Coin Game", "fun": 2.95, "difficulty": 2.16, "author": "xpitxbullx", "desc": "You die and the devil says he'll let you go to heaven if you beat him in a game. The devil sits you down at a perfectly round table. He gives himself and you an infinite pile of quarters. He says, \"OK, we'll take turns putting one quarter down, no overlapping allowed, and the quarters must rest flat on the table surface. The first guy who can't put a quarter down loses.\" You guys are about to start playing, and the devil says that he'll go first. However, at this point you immediately interject, and ask if you can go first instead. You make this interjection because you are very smart and can place quarters perfectly, and you know that if you go first, you can guarantee victory. Explain how you can guarantee victory.", "hint": "No hint available.", "answer": "You place a quarter right in the center of the table. After that, whenever the devil places a quarter on the table, mimic his placement on the opposite side of the table. If he has a place to place a quarter, so will you. The devil will run out of places to put a quarter before you do.", "category": "Logic", "date": "08/31/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou die and the devil says he'll let you go to heaven if you beat him in a game. The devil sits you down at a perfectly round table. He gives himself and you an infinite pile of quarters. He says, \"OK, we'll take turns putting one quarter down, no overlapping allowed, and the quarters must rest flat on the table surface. The first guy who can't put a quarter down loses.\" You guys are about to start playing, and the devil says that he'll go first. However, at this point you immediately interject, and ask if you can go first instead. You make this interjection because you are very smart and can place quarters perfectly, and you know that if you go first, you can guarantee victory. Explain how you can guarantee victory.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou place a quarter right in the center of the table. After that, whenever the devil places a quarter on the table, mimic his placement on the opposite side of the table. If he has a place to place a quarter, so will you. The devil will run out of places to put a quarter before you do.\n<|im_start|>answer\nYou place a quarter right in the center of the table. After that, whenever the devil places a quarter on the table, mimic his placement on the opposite side of the table. If he has a place to place a quarter, so will you. The devil will run out of places to put a quarter before you do.\n<|im_end|>" }, { "id": "#49613", "title": "Troubling Doubling at School", "fun": 2.95, "difficulty": 1.65, "author": "dalfamnest", "desc": "Read the little poem and answer its question if you can.\n\r\nThe number of girls who do wear a watch\r\n is double the number who don't.\r\nBut the number of boys who do not wear a watch\r\n is double the number who do.\n\r\nIf I tell you the number of girls in my class\r\n is double the number of boys,\r\nCan you tell me the number I teach? Here's a clue:\r\n More than 20; below 32!", "hint": "The sum of number plus its double must be a multiple of 3.", "answer": "27\n\r\nSolution:\r\nThe number of boys must be a multiple of 3 (3, 6, 9...) so that it can be split in the ratio of 2:1 (no watch:watch).\n\r\nThe number of girls is double the no. of boys (6, 12, 18...)\n\r\nSo the totals can only be 9, 18, 27...", "category": "Math", "date": "09/25/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRead the little poem and answer its question if you can.\n\r\nThe number of girls who do wear a watch\r\n is double the number who don't.\r\nBut the number of boys who do not wear a watch\r\n is double the number who do.\n\r\nIf I tell you the number of girls in my class\r\n is double the number of boys,\r\nCan you tell me the number I teach? Here's a clue:\r\n More than 20; below 32!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n27\n\r\nSolution:\r\nThe number of boys must be a multiple of 3 (3, 6, 9...) so that it can be split in the ratio of 2:1 (no watch:watch).\n\r\nThe number of girls is double the no. of boys (6, 12, 18...)\n\r\nSo the totals can only be 9, 18, 27...\n<|im_start|>answer\n27\n\r\nSolution:\r\nThe number of boys must be a multiple of 3 (3, 6, 9...) so that it can be split in the ratio of 2:1 (no watch:watch).\n\r\nThe number of girls is double the no. of boys (6, 12, 18...)\n\r\nSo the totals can only be 9, 18, 27...\n<|im_end|>" }, { "id": "#20548", "title": "Breakfast Time", "fun": 2.95, "difficulty": 2.5, "author": "mindbender", "desc": "Mrs. Bradbury has five delightful children 3 girls: Madison, Paige, & Reed, and 2 boys: Charlie & Billy. The children are all different ages (2,4,5,7,9). Mrs. Bradbury went to the grocery store and purchased 5 boxes of cereal: Apple Jacks, Pops, Oh's, Sugar Squares, and Fruit Flakes. Her children each had breakfast at different times the next morning 5:15, 6:45, 7:00, 8:15, and 9:30. Your mission, if you choose to accept it, is to figure out how old each child is, which cereal they ate, and what time they woke up to eat breakfast. ~Good Luck.\n\r\nBilly doesn't like to get up too early.\n\r\nSugar Squares can only be eaten by kids over 6 years old.\n\r\nPaige woke up and found that the Pops and Fruit Flakes were gone.\n\r\nCharlie's younger sister got up at 5:15.\n\r\nBilly's age and the time he got up contain the same number.\n\r\nTwo girls ate their cereal at a quarter after an hour.\n\r\nAt 7:00 a four year old ate a bowl of Oh's cereal.\n\r\nReed is older than her sister Madison but younger than her brother Charlie.\n\r\nThe oldest child slept in the longest, the youngest child got up the earliest.\n\r\nThe middle child got up before 7 and enjoyed a bowl of Pops.\n\r\nThe eldest child loves to eat his Apple Jacks without milk.", "hint": "No hint available.", "answer": "Charlie... Pops... 5 yrs old... 6:45\r\nBilly... Apple Jacks...9 yrs old...9:30\r\nPaige... Sugar Squares... 7 yrs old... 8:15\r\nReed... Oh's... 4 yrs old... 7:00\r\nMadison... Fruit Flakes... 2 years old... 5:15", "category": "Logic-Grid", "date": "01/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Bradbury has five delightful children 3 girls: Madison, Paige, & Reed, and 2 boys: Charlie & Billy. The children are all different ages (2,4,5,7,9). Mrs. Bradbury went to the grocery store and purchased 5 boxes of cereal: Apple Jacks, Pops, Oh's, Sugar Squares, and Fruit Flakes. Her children each had breakfast at different times the next morning 5:15, 6:45, 7:00, 8:15, and 9:30. Your mission, if you choose to accept it, is to figure out how old each child is, which cereal they ate, and what time they woke up to eat breakfast. ~Good Luck.\n\r\nBilly doesn't like to get up too early.\n\r\nSugar Squares can only be eaten by kids over 6 years old.\n\r\nPaige woke up and found that the Pops and Fruit Flakes were gone.\n\r\nCharlie's younger sister got up at 5:15.\n\r\nBilly's age and the time he got up contain the same number.\n\r\nTwo girls ate their cereal at a quarter after an hour.\n\r\nAt 7:00 a four year old ate a bowl of Oh's cereal.\n\r\nReed is older than her sister Madison but younger than her brother Charlie.\n\r\nThe oldest child slept in the longest, the youngest child got up the earliest.\n\r\nThe middle child got up before 7 and enjoyed a bowl of Pops.\n\r\nThe eldest child loves to eat his Apple Jacks without milk.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCharlie... Pops... 5 yrs old... 6:45\r\nBilly... Apple Jacks...9 yrs old...9:30\r\nPaige... Sugar Squares... 7 yrs old... 8:15\r\nReed... Oh's... 4 yrs old... 7:00\r\nMadison... Fruit Flakes... 2 years old... 5:15\n<|im_start|>answer\nCharlie... Pops... 5 yrs old... 6:45\r\nBilly... Apple Jacks...9 yrs old...9:30\r\nPaige... Sugar Squares... 7 yrs old... 8:15\r\nReed... Oh's... 4 yrs old... 7:00\r\nMadison... Fruit Flakes... 2 years old... 5:15\n<|im_end|>" }, { "id": "#19536", "title": "It's The Family Feud", "fun": 2.95, "difficulty": 2.33, "author": "strzynski", "desc": "On a certain game show, five families were asked to match famous names to faces they were shown, and each correct guess got one point. The families made the following guesses (in order):\n\r\nThe Addams' guessed Otto, Roebling, Steinmetz, Tesla, and Westinghouse.\n\r\nThe Bunkers guessed Tesla, Westinghouse, Otto, Steinmetz, and Roebling.\n\r\nThe Cunninghams guessed Roebling, Tesla, Steinmetz, Westinghouse, and Otto.\n\r\nThe Flintstones guessed Tesla, Roebling, Otto, Steinmetz, and Westinghouse.\n\r\nThe Jetsons guessed Tesla, Westinghouse, Steinmetz, Otto, and Roebling.\n\r\nNo two families got the same number of points. Which family walked home with the grand prize?", "hint": "There is no way for a family to get only four points, since if they matched four correctly, the last one *has* to be correct as well. The only possible point totals, therefore, are 0, 1, 2, 3, and 5. That's five totals and five families...", "answer": "You can assume that one family got all 5 correct (from the hint if you didn't know that), and as such, you can choose a family to have the perfect score. Then compare their answers with the other families, and find out how the other families did. If there are any duplicate point totals, that can't be the correct perfect total family, and you move to the next.\n\r\nThe correct order was Tesla, Roebling, Otto, Steinmetz, and Westinghouse. The totals for each family are\n\r\nAddams = 2 (no thanks to Lurch)\r\nBunkers = 3 (you meathead!)\r\nCunninghams = 0 (the Fonz was not allowed to play)\r\nFlintstones = 5 \r\nJetsons = 1 (c'mon George, get off that broken treadmill)\n\r\nand the Flintstones won a trip to the nearest tar pit.", "category": "Logic", "date": "11/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a certain game show, five families were asked to match famous names to faces they were shown, and each correct guess got one point. The families made the following guesses (in order):\n\r\nThe Addams' guessed Otto, Roebling, Steinmetz, Tesla, and Westinghouse.\n\r\nThe Bunkers guessed Tesla, Westinghouse, Otto, Steinmetz, and Roebling.\n\r\nThe Cunninghams guessed Roebling, Tesla, Steinmetz, Westinghouse, and Otto.\n\r\nThe Flintstones guessed Tesla, Roebling, Otto, Steinmetz, and Westinghouse.\n\r\nThe Jetsons guessed Tesla, Westinghouse, Steinmetz, Otto, and Roebling.\n\r\nNo two families got the same number of points. Which family walked home with the grand prize?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou can assume that one family got all 5 correct (from the hint if you didn't know that), and as such, you can choose a family to have the perfect score. Then compare their answers with the other families, and find out how the other families did. If there are any duplicate point totals, that can't be the correct perfect total family, and you move to the next.\n\r\nThe correct order was Tesla, Roebling, Otto, Steinmetz, and Westinghouse. The totals for each family are\n\r\nAddams = 2 (no thanks to Lurch)\r\nBunkers = 3 (you meathead!)\r\nCunninghams = 0 (the Fonz was not allowed to play)\r\nFlintstones = 5 \r\nJetsons = 1 (c'mon George, get off that broken treadmill)\n\r\nand the Flintstones won a trip to the nearest tar pit.\n<|im_start|>answer\nYou can assume that one family got all 5 correct (from the hint if you didn't know that), and as such, you can choose a family to have the perfect score. Then compare their answers with the other families, and find out how the other families did. If there are any duplicate point totals, that can't be the correct perfect total family, and you move to the next.\n\r\nThe correct order was Tesla, Roebling, Otto, Steinmetz, and Westinghouse. The totals for each family are\n\r\nAddams = 2 (no thanks to Lurch)\r\nBunkers = 3 (you meathead!)\r\nCunninghams = 0 (the Fonz was not allowed to play)\r\nFlintstones = 5 \r\nJetsons = 1 (c'mon George, get off that broken treadmill)\n\r\nand the Flintstones won a trip to the nearest tar pit.\n<|im_end|>" }, { "id": "#14223", "title": "Cake-Bake Contest", "fun": 2.95, "difficulty": 1.42, "author": "Smithy", "desc": "For this logic puzzle you have to determine the surnames of four people, their position in a cake-bake competition and what cake they baked.\r\nThe first names are: James, Ben, Vicky and Nigel\r\nThe surnames are: Jones, Stevens, Andrews and Best\r\nPositions are: 1st, 2nd, 3rd and 4th\r\nCakes baked are: chocolate cake, cheese cake, fruit cake and sponge cake.\n\r\nClues:\r\n1. James Best beat Vicky by two places.\r\n2. Ben's fruit cake beat Mrs. Stevens' son, who came in 3rd.\r\n3. The sponge cake, despite being a bit bland, got in the top three.\r\n4. The judges obviously had a sweet tooth, as the chocolate cake came in 2nd place.\r\n5. Jones's mother cried as she watched her son take 1st prize.\r\nWhat are the full names of the top four, what position did they come and what cake did they bake?", "hint": "No hint available.", "answer": "Ben Jones came in 1st with his fruit cake.\n\r\nJames Best came in 2nd with his chocolate cake.\n\r\nNigel Stevens came in 3rd with his sponge cake.\n\r\nVicky Andrews came in 4th with her cheese cake.", "category": "Logic-Grid", "date": "08/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor this logic puzzle you have to determine the surnames of four people, their position in a cake-bake competition and what cake they baked.\r\nThe first names are: James, Ben, Vicky and Nigel\r\nThe surnames are: Jones, Stevens, Andrews and Best\r\nPositions are: 1st, 2nd, 3rd and 4th\r\nCakes baked are: chocolate cake, cheese cake, fruit cake and sponge cake.\n\r\nClues:\r\n1. James Best beat Vicky by two places.\r\n2. Ben's fruit cake beat Mrs. Stevens' son, who came in 3rd.\r\n3. The sponge cake, despite being a bit bland, got in the top three.\r\n4. The judges obviously had a sweet tooth, as the chocolate cake came in 2nd place.\r\n5. Jones's mother cried as she watched her son take 1st prize.\r\nWhat are the full names of the top four, what position did they come and what cake did they bake?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBen Jones came in 1st with his fruit cake.\n\r\nJames Best came in 2nd with his chocolate cake.\n\r\nNigel Stevens came in 3rd with his sponge cake.\n\r\nVicky Andrews came in 4th with her cheese cake.\n<|im_start|>answer\nBen Jones came in 1st with his fruit cake.\n\r\nJames Best came in 2nd with his chocolate cake.\n\r\nNigel Stevens came in 3rd with his sponge cake.\n\r\nVicky Andrews came in 4th with her cheese cake.\n<|im_end|>" }, { "id": "#34202", "title": "Anniversary Discount", "fun": 2.95, "difficulty": 1.6400000000000001, "author": "bigSWAFF_69_", "desc": "A fancy restaurant in New York was offering a promotional deal. A married couple could eat at the restaurant for half-price on their anniversary. To prevent scams, the couple would need proof of their wedding date.\n\r\nOne Thursday evening, a couple claimed it was their anniversary, but didn't bring any proof. The restaurant manager was called to speak with the couple. When the manager asked to hear about the wedding day, the wife replied with the following: \"Oh, it was a wonderful Sunday afternoon, birds were chirping, and flowers were in full bloom.\" After nearly 10 minutes of ranting, she comes to tell him that today was their 28th wedding anniversary.\n\r\n\"How lovely\", the manager said, \"However, you do not qualify for the discount. Today is not your anniversary, you are a liar\". \n\n\r\nHow did the manager know that it wasn't their anniversary?", "hint": "No hint available.", "answer": "The calendar repeats itself every 28 years. So, if they were married on a Sunday 28 years ago, the day they were at the restaurant would also have to be a Sunday. Since it was a Thursday, the manager knew they were lying, and abruptly kicked them out of his restaurant.", "category": "Logic", "date": "12/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fancy restaurant in New York was offering a promotional deal. A married couple could eat at the restaurant for half-price on their anniversary. To prevent scams, the couple would need proof of their wedding date.\n\r\nOne Thursday evening, a couple claimed it was their anniversary, but didn't bring any proof. The restaurant manager was called to speak with the couple. When the manager asked to hear about the wedding day, the wife replied with the following: \"Oh, it was a wonderful Sunday afternoon, birds were chirping, and flowers were in full bloom.\" After nearly 10 minutes of ranting, she comes to tell him that today was their 28th wedding anniversary.\n\r\n\"How lovely\", the manager said, \"However, you do not qualify for the discount. Today is not your anniversary, you are a liar\". \n\n\r\nHow did the manager know that it wasn't their anniversary?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe calendar repeats itself every 28 years. So, if they were married on a Sunday 28 years ago, the day they were at the restaurant would also have to be a Sunday. Since it was a Thursday, the manager knew they were lying, and abruptly kicked them out of his restaurant.\n<|im_start|>answer\nThe calendar repeats itself every 28 years. So, if they were married on a Sunday 28 years ago, the day they were at the restaurant would also have to be a Sunday. Since it was a Thursday, the manager knew they were lying, and abruptly kicked them out of his restaurant.\n<|im_end|>" }, { "id": "#24879", "title": "Shoe Shopping", "fun": 2.94, "difficulty": 2.64, "author": "ragsdaleam", "desc": "Five girlfriends were discussing shoes. They discovered that of 5 shoe types, each girl had a different favorite to wear, favorite to buy, and least favorite. Use the clues and the grid to determine each girl's full name, favorite type of shoe to wear, favorite type of shoe to buy, and least favorite type of shoe. For each girl, the shoes she liked to wear, liked to buy, and liked least were always 3 different shoe types. (On grid, W=to wear, B=to buy, L=least)\n\n\n\n\r\n1. Miss Greene, who didn't like to buy slingbacks, liked sneakers the least. Kristen, whose last name isn't Best, didn't like to buy mules.\n\r\n2. Miss Sample liked to wear slingbacks, but the girl who liked to wear mules liked slingbacks least, and the one who loved buying slingbacks liked flip flops the least.\n\r\n3. Tina, whose last name isn't Sample, loved to wear sneakers. Kristen didn't like to buy pumps.\n\r\n4. The girl who liked to buy mules liked pumps the least. Allie's last name wasn't Mason. Miss Best liked to buy flip flops.\n\r\n5. The five girlfriends are represented by: Suzie, the one who liked to buy sneakers, Miss Dean, Kristen, and the one who loved to wear mules.\n\r\n6. Jen Sample liked mules the least. Suzie Greene didn't like to wear slingbacks.", "hint": "No girl had the same shoe type for any category.", "answer": "Allie Best liked to wear mules, liked to buy flip flops, and liked slingbacks the least.\r\nJen Sample liked to wear slingbacks, liked to buy sneakers, and liked mules the least.\r\nKristen Mason liked to wear pumps, liked to buy slingbacks, and liked flip flops the least.\r\nSuzie Greene liked to wear flip flops, liked to buy pumps, and liked sneakers the least.\r\nTina Dean liked to wear sneakers, liked to buy mules, and liked pumps the least.", "category": "Logic-Grid", "date": "07/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive girlfriends were discussing shoes. They discovered that of 5 shoe types, each girl had a different favorite to wear, favorite to buy, and least favorite. Use the clues and the grid to determine each girl's full name, favorite type of shoe to wear, favorite type of shoe to buy, and least favorite type of shoe. For each girl, the shoes she liked to wear, liked to buy, and liked least were always 3 different shoe types. (On grid, W=to wear, B=to buy, L=least)\n\n\n\n\r\n1. Miss Greene, who didn't like to buy slingbacks, liked sneakers the least. Kristen, whose last name isn't Best, didn't like to buy mules.\n\r\n2. Miss Sample liked to wear slingbacks, but the girl who liked to wear mules liked slingbacks least, and the one who loved buying slingbacks liked flip flops the least.\n\r\n3. Tina, whose last name isn't Sample, loved to wear sneakers. Kristen didn't like to buy pumps.\n\r\n4. The girl who liked to buy mules liked pumps the least. Allie's last name wasn't Mason. Miss Best liked to buy flip flops.\n\r\n5. The five girlfriends are represented by: Suzie, the one who liked to buy sneakers, Miss Dean, Kristen, and the one who loved to wear mules.\n\r\n6. Jen Sample liked mules the least. Suzie Greene didn't like to wear slingbacks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllie Best liked to wear mules, liked to buy flip flops, and liked slingbacks the least.\r\nJen Sample liked to wear slingbacks, liked to buy sneakers, and liked mules the least.\r\nKristen Mason liked to wear pumps, liked to buy slingbacks, and liked flip flops the least.\r\nSuzie Greene liked to wear flip flops, liked to buy pumps, and liked sneakers the least.\r\nTina Dean liked to wear sneakers, liked to buy mules, and liked pumps the least.\n<|im_start|>answer\nAllie Best liked to wear mules, liked to buy flip flops, and liked slingbacks the least.\r\nJen Sample liked to wear slingbacks, liked to buy sneakers, and liked mules the least.\r\nKristen Mason liked to wear pumps, liked to buy slingbacks, and liked flip flops the least.\r\nSuzie Greene liked to wear flip flops, liked to buy pumps, and liked sneakers the least.\r\nTina Dean liked to wear sneakers, liked to buy mules, and liked pumps the least.\n<|im_end|>" }, { "id": "#3551", "title": "Greedy Pirates", "fun": 2.94, "difficulty": 2.7600000000000002, "author": "Bobbrt", "desc": "Five pirates are trying to split up 1000 gold pieces. The rules are as follows:\n\r\nPirate #1 must divide the gold up in such a way that a majority of the pirates (including himself) agree to. If he does not get a majority vote, he will be killed, and pirate #2 will get to propose a solution to the remaining 3 pirates, and the same rules will follow. This continues until someone comes up with a plan that earns a majority vote.\r\nWhat is the most amount of gold pieces that pirate #1 can keep to himself, and what would his proposal be?\r\nThe pirates are infinitely greedy, infinitely ruthless (the more dead pirates the better), and infinitely intelligent.", "hint": "Start backwards - what would pirate #4's options be if the first 3 pirates were killed?", "answer": "Like the hint says, start backwards:\n\r\nIf there are two pirates left (#4 & #5), #4 has no options. No matter what he proposes, pirate #5 will disagree, resulting in a 1-1 vote (no majority). #5 will kill #4 and will keep all of the gold.\n\r\nNow say there are 3 pirates left. #4 has to agree with whatever #3 decides, because if he doesn't #3 will be killed (because #5 won't vote for #3's proposal no matter what it is). #3 will just propose that he keep all of the gold and will get a 2-1 vote in his favor.\n\r\nNow if there are 4 pirates left:\r\n#3 won't vote for #2's proposal because if #2's fails, #3 will get all of the gold. #4 and #5 know that they will get nothing if the decision goes to #3, so they will vote for #2's proposal if he gives them one gold piece each. Therefore, #2 would keep 998 gold, and #4 and #5 would each get one gold.\n\r\nSo let's wrap this up:\r\nPirate #1 needs 2 other votes. He will not get a vote from #2 because #2 will get 998 gold if #1's plan fails.\r\n#1 offers #3 one gold piece to vote for him, which #3 will accept (if it gets to #2's plan, #3 will get nothing).\r\n#1 then offers #4 or #5 (doesn't matter which) two gold pieces, which is more than they would get with #2's plan.\r\nSo #1 can end up with 997 gold pieces, with #3 getting one piece and #4 or #5 getting two pieces.\n\r\n...whew!", "category": "Logic", "date": "04/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive pirates are trying to split up 1000 gold pieces. The rules are as follows:\n\r\nPirate #1 must divide the gold up in such a way that a majority of the pirates (including himself) agree to. If he does not get a majority vote, he will be killed, and pirate #2 will get to propose a solution to the remaining 3 pirates, and the same rules will follow. This continues until someone comes up with a plan that earns a majority vote.\r\nWhat is the most amount of gold pieces that pirate #1 can keep to himself, and what would his proposal be?\r\nThe pirates are infinitely greedy, infinitely ruthless (the more dead pirates the better), and infinitely intelligent.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLike the hint says, start backwards:\n\r\nIf there are two pirates left (#4 & #5), #4 has no options. No matter what he proposes, pirate #5 will disagree, resulting in a 1-1 vote (no majority). #5 will kill #4 and will keep all of the gold.\n\r\nNow say there are 3 pirates left. #4 has to agree with whatever #3 decides, because if he doesn't #3 will be killed (because #5 won't vote for #3's proposal no matter what it is). #3 will just propose that he keep all of the gold and will get a 2-1 vote in his favor.\n\r\nNow if there are 4 pirates left:\r\n#3 won't vote for #2's proposal because if #2's fails, #3 will get all of the gold. #4 and #5 know that they will get nothing if the decision goes to #3, so they will vote for #2's proposal if he gives them one gold piece each. Therefore, #2 would keep 998 gold, and #4 and #5 would each get one gold.\n\r\nSo let's wrap this up:\r\nPirate #1 needs 2 other votes. He will not get a vote from #2 because #2 will get 998 gold if #1's plan fails.\r\n#1 offers #3 one gold piece to vote for him, which #3 will accept (if it gets to #2's plan, #3 will get nothing).\r\n#1 then offers #4 or #5 (doesn't matter which) two gold pieces, which is more than they would get with #2's plan.\r\nSo #1 can end up with 997 gold pieces, with #3 getting one piece and #4 or #5 getting two pieces.\n\r\n...whew!\n<|im_start|>answer\nLike the hint says, start backwards:\n\r\nIf there are two pirates left (#4 & #5), #4 has no options. No matter what he proposes, pirate #5 will disagree, resulting in a 1-1 vote (no majority). #5 will kill #4 and will keep all of the gold.\n\r\nNow say there are 3 pirates left. #4 has to agree with whatever #3 decides, because if he doesn't #3 will be killed (because #5 won't vote for #3's proposal no matter what it is). #3 will just propose that he keep all of the gold and will get a 2-1 vote in his favor.\n\r\nNow if there are 4 pirates left:\r\n#3 won't vote for #2's proposal because if #2's fails, #3 will get all of the gold. #4 and #5 know that they will get nothing if the decision goes to #3, so they will vote for #2's proposal if he gives them one gold piece each. Therefore, #2 would keep 998 gold, and #4 and #5 would each get one gold.\n\r\nSo let's wrap this up:\r\nPirate #1 needs 2 other votes. He will not get a vote from #2 because #2 will get 998 gold if #1's plan fails.\r\n#1 offers #3 one gold piece to vote for him, which #3 will accept (if it gets to #2's plan, #3 will get nothing).\r\n#1 then offers #4 or #5 (doesn't matter which) two gold pieces, which is more than they would get with #2's plan.\r\nSo #1 can end up with 997 gold pieces, with #3 getting one piece and #4 or #5 getting two pieces.\n\r\n...whew!\n<|im_end|>" }, { "id": "#36599", "title": "It Works! Happily Employed", "fun": 2.94, "difficulty": 1.73, "author": "chaskey", "desc": "In the energetic, little town of Catwaggle, five friends enjoy employment at five companies. Who works where, at what job, the age of the company, and the length of employment can all be determined by following the clues below.\n\r\nFRIENDS: Allen, Bill, Cliff, Doris, Ellen\r\nCOMPANIES: 20-Digital Accounting, Outbound Books, Big Toe Ballet Co., Square Links Grocery Chain, Rebar Saloon Supplies\r\nSTREETS: Alphabet Avenue, Burnt Brick Boulevard, Pebbled Pedal Path, Real Dirt Drive, Greenpenny Street\r\nCOMPANY AGES: years: 3, 11, 17, 25, 27\r\nEMPLOYMENT: years: 2, 8, 12, 16, 24\n\r\nCLUES:\r\n1. Nobody has been employed at a company for more years than the company has been in business.\n\r\n2. Big Toe Ballet Co. has been at the foot of Pebbled Pedal Path for twenty-five years, and the business on Real Dirt Drive has been open for seventeen years.\n\r\n3. Bill (sometimes appropriately called \"Bills\"), who was apparently learning to count on his toes at age 3 weeks, years later became a partner in the firm of 20-Digital Accounting, located on Greenpenny Street.\n\r\n4. Ellen started work at Square Links Grocery Chain a year after it opened on Real Dirt Drive.\n\r\n5. Twenty-four years ago, Doris helped Cliff get his job at Outbound Books, which had been in business on Alphabet Avenue for three years. He is still happy there.\n\r\n6. Also happy is Allen (nicknamed \"Al Ert\"), the security guard at Big Toe Ballet Co., who prevented a robbery and was applauded for being on his feet.\n\r\n7. Doris likes to travel, so she was happy to land the job as driver of the delivery truck for Rebar Saloon Supplies, in business for eleven years.", "hint": "No hint available.", "answer": "Allen -- Big Toe Ballet Co. -- Pebbled Pedal Path -- Co. age 25 -- employed 12 years\n\r\nBill -- 20-Digital Accounting -- Greenpenny St. -- Co. age 3 -- employed 2 years \n\r\nCliff -- Outbound Books -- Alphabet Ave. -- Co. age 27 -- employed 24 years\n\r\nDoris -- Rebar Saloon Supplies -- Burnt Brick Bl. -- Co. age 11 -- employed 8 years \n\r\nEllen -- Square Links Grocery Chain -- Real Dirt Dr. -- Co. age 17 -- employed 16 years", "category": "Logic-Grid", "date": "05/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the energetic, little town of Catwaggle, five friends enjoy employment at five companies. Who works where, at what job, the age of the company, and the length of employment can all be determined by following the clues below.\n\r\nFRIENDS: Allen, Bill, Cliff, Doris, Ellen\r\nCOMPANIES: 20-Digital Accounting, Outbound Books, Big Toe Ballet Co., Square Links Grocery Chain, Rebar Saloon Supplies\r\nSTREETS: Alphabet Avenue, Burnt Brick Boulevard, Pebbled Pedal Path, Real Dirt Drive, Greenpenny Street\r\nCOMPANY AGES: years: 3, 11, 17, 25, 27\r\nEMPLOYMENT: years: 2, 8, 12, 16, 24\n\r\nCLUES:\r\n1. Nobody has been employed at a company for more years than the company has been in business.\n\r\n2. Big Toe Ballet Co. has been at the foot of Pebbled Pedal Path for twenty-five years, and the business on Real Dirt Drive has been open for seventeen years.\n\r\n3. Bill (sometimes appropriately called \"Bills\"), who was apparently learning to count on his toes at age 3 weeks, years later became a partner in the firm of 20-Digital Accounting, located on Greenpenny Street.\n\r\n4. Ellen started work at Square Links Grocery Chain a year after it opened on Real Dirt Drive.\n\r\n5. Twenty-four years ago, Doris helped Cliff get his job at Outbound Books, which had been in business on Alphabet Avenue for three years. He is still happy there.\n\r\n6. Also happy is Allen (nicknamed \"Al Ert\"), the security guard at Big Toe Ballet Co., who prevented a robbery and was applauded for being on his feet.\n\r\n7. Doris likes to travel, so she was happy to land the job as driver of the delivery truck for Rebar Saloon Supplies, in business for eleven years.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllen -- Big Toe Ballet Co. -- Pebbled Pedal Path -- Co. age 25 -- employed 12 years\n\r\nBill -- 20-Digital Accounting -- Greenpenny St. -- Co. age 3 -- employed 2 years \n\r\nCliff -- Outbound Books -- Alphabet Ave. -- Co. age 27 -- employed 24 years\n\r\nDoris -- Rebar Saloon Supplies -- Burnt Brick Bl. -- Co. age 11 -- employed 8 years \n\r\nEllen -- Square Links Grocery Chain -- Real Dirt Dr. -- Co. age 17 -- employed 16 years\n<|im_start|>answer\nAllen -- Big Toe Ballet Co. -- Pebbled Pedal Path -- Co. age 25 -- employed 12 years\n\r\nBill -- 20-Digital Accounting -- Greenpenny St. -- Co. age 3 -- employed 2 years \n\r\nCliff -- Outbound Books -- Alphabet Ave. -- Co. age 27 -- employed 24 years\n\r\nDoris -- Rebar Saloon Supplies -- Burnt Brick Bl. -- Co. age 11 -- employed 8 years \n\r\nEllen -- Square Links Grocery Chain -- Real Dirt Dr. -- Co. age 17 -- employed 16 years\n<|im_end|>" }, { "id": "#40238", "title": "Digging For the Truth", "fun": 2.94, "difficulty": 2.74, "author": "Mom2Ozzy", "desc": "Newspapers around the world are having a field day and the Scientific community is all aflutter! Four archaeologists and a farmer have made some amazing discoveries that are sure to change the world as we know it! Unfortunately, after much study and analysis, only two of them have been proven to be real. Can you find who discovered what artifact, what their area of expertise is, and which ones were real and which were hoaxes?\n\r\n1. The five people are: Max, Dr. Eureka, the one who specializes in Egyptian studies, the one who uncovered the skeletal remains of Big Foot, and Mr. Ali (whose find was actually written by his wife!).\n\r\n2. The five artifacts are: Ms. Bones' discovery, the one found by the Paleontologist, Susan's hoax, the scroll describing the marriage celebration of Jesus and Mary, and an entire UFO with all the bells and whistles!! \n\r\n3. A joint report issued by the U.S. Military and NASA stated, \"Mr. Dirt is just not educated enough to have built such an amazing piece of machinery. We therefore conclude that it is in fact the real deal!\"\n\r\n4. \"Big Foot, Big Lie!\" and \"Mummi Finds Guest List of Biblical Proportions!\" were just two of the many headlines that were circling the globe.\n\r\n5. Janet had been transcribing ancient Egyptian texts when she came across a soldier's eyewitness account of Moses parting the Red Sea.\n\r\n6. Knowing that her funding was about to be cut, Dr. Eureka decided to sink some ancient Grecian pottery (that she had inscribed with the phrase \"Petra of Atlantis\") off the coast of Kythnos, an island south of Athens. \"This is just as good a place as any other, I guess.\"", "hint": "Mummi is male.", "answer": "Alex Diggum - Big Foot Skeleton - Paleontology - Hoax\n\r\nJanet Bones - Egyptian Papyrus - Egyptology - Real\n\r\nMax Dirt - UFO - Farming - Real\n\r\nMummi Ali - Marriage Scroll - Religion - Hoax\n\r\nSusan Eureka - Atlantis Pottery - Nautical Archeology - Hoax", "category": "Logic-Grid", "date": "01/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNewspapers around the world are having a field day and the Scientific community is all aflutter! Four archaeologists and a farmer have made some amazing discoveries that are sure to change the world as we know it! Unfortunately, after much study and analysis, only two of them have been proven to be real. Can you find who discovered what artifact, what their area of expertise is, and which ones were real and which were hoaxes?\n\r\n1. The five people are: Max, Dr. Eureka, the one who specializes in Egyptian studies, the one who uncovered the skeletal remains of Big Foot, and Mr. Ali (whose find was actually written by his wife!).\n\r\n2. The five artifacts are: Ms. Bones' discovery, the one found by the Paleontologist, Susan's hoax, the scroll describing the marriage celebration of Jesus and Mary, and an entire UFO with all the bells and whistles!! \n\r\n3. A joint report issued by the U.S. Military and NASA stated, \"Mr. Dirt is just not educated enough to have built such an amazing piece of machinery. We therefore conclude that it is in fact the real deal!\"\n\r\n4. \"Big Foot, Big Lie!\" and \"Mummi Finds Guest List of Biblical Proportions!\" were just two of the many headlines that were circling the globe.\n\r\n5. Janet had been transcribing ancient Egyptian texts when she came across a soldier's eyewitness account of Moses parting the Red Sea.\n\r\n6. Knowing that her funding was about to be cut, Dr. Eureka decided to sink some ancient Grecian pottery (that she had inscribed with the phrase \"Petra of Atlantis\") off the coast of Kythnos, an island south of Athens. \"This is just as good a place as any other, I guess.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlex Diggum - Big Foot Skeleton - Paleontology - Hoax\n\r\nJanet Bones - Egyptian Papyrus - Egyptology - Real\n\r\nMax Dirt - UFO - Farming - Real\n\r\nMummi Ali - Marriage Scroll - Religion - Hoax\n\r\nSusan Eureka - Atlantis Pottery - Nautical Archeology - Hoax\n<|im_start|>answer\nAlex Diggum - Big Foot Skeleton - Paleontology - Hoax\n\r\nJanet Bones - Egyptian Papyrus - Egyptology - Real\n\r\nMax Dirt - UFO - Farming - Real\n\r\nMummi Ali - Marriage Scroll - Religion - Hoax\n\r\nSusan Eureka - Atlantis Pottery - Nautical Archeology - Hoax\n<|im_end|>" }, { "id": "#51828", "title": "The Dishonest Grocer", "fun": 2.94, "difficulty": 1.94, "author": "wimpykidfan37", "desc": "Quinn, Ralph, and Steve work at a grocery store that sells apples, bananas, and oranges. Quinn says, \"Seven apples and five bananas cost the same as six oranges.\" Ralph says, \"Four apples and nine oranges cost the same as five bananas.\" Steve says, \"Six oranges and three bananas cost the same as four apples.\" Only one is lying...but who?", "hint": "The three values equivalents must be considered in pairs. The one false equivalent leads to two impossible situations, while the pair of true equivalents is a possible situation.", "answer": "Quinn is lying.\n\r\nLet a equal the price of apples, b equal the price of bananas, and o equal the price of oranges. Quinn is saying that 7a + 5b = 6o. Ralph is saying that 4a + 9o = 5b. Steve is saying that 6o + 3b = 4a.\n\r\nCombining Quinn's and Ralph's statements, we get 11a = -3o. This is impossible.\n\r\nCombining Ralph's and Steve's statements, we get 15o = 2b. This is possible.\n\r\nCombining Quinn's and Steve's statements, we get 8b = -3a. This is impossible.\n\r\nThis means that either Quinn is lying, or Ralph and Steve are both lying. But there only can be one liar: obviously Quinn.", "category": "Math", "date": "04/20/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuinn, Ralph, and Steve work at a grocery store that sells apples, bananas, and oranges. Quinn says, \"Seven apples and five bananas cost the same as six oranges.\" Ralph says, \"Four apples and nine oranges cost the same as five bananas.\" Steve says, \"Six oranges and three bananas cost the same as four apples.\" Only one is lying...but who?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nQuinn is lying.\n\r\nLet a equal the price of apples, b equal the price of bananas, and o equal the price of oranges. Quinn is saying that 7a + 5b = 6o. Ralph is saying that 4a + 9o = 5b. Steve is saying that 6o + 3b = 4a.\n\r\nCombining Quinn's and Ralph's statements, we get 11a = -3o. This is impossible.\n\r\nCombining Ralph's and Steve's statements, we get 15o = 2b. This is possible.\n\r\nCombining Quinn's and Steve's statements, we get 8b = -3a. This is impossible.\n\r\nThis means that either Quinn is lying, or Ralph and Steve are both lying. But there only can be one liar: obviously Quinn.\n<|im_start|>answer\nQuinn is lying.\n\r\nLet a equal the price of apples, b equal the price of bananas, and o equal the price of oranges. Quinn is saying that 7a + 5b = 6o. Ralph is saying that 4a + 9o = 5b. Steve is saying that 6o + 3b = 4a.\n\r\nCombining Quinn's and Ralph's statements, we get 11a = -3o. This is impossible.\n\r\nCombining Ralph's and Steve's statements, we get 15o = 2b. This is possible.\n\r\nCombining Quinn's and Steve's statements, we get 8b = -3a. This is impossible.\n\r\nThis means that either Quinn is lying, or Ralph and Steve are both lying. But there only can be one liar: obviously Quinn.\n<|im_end|>" }, { "id": "#45943", "title": "Company Christmas Party", "fun": 2.94, "difficulty": 2.02, "author": "whsprec", "desc": "A company decided to have a Christmas party for the employees. The five people in management each brought a meal and a dessert to show their appreciation. From the clues below determine management's name, their title, and what meal and dessert they brought.\n\r\n1) Neither Olivia, who is the Sales Manager, nor the person who brought the chocolate bars, brought meat for the meal.\r\n2) Destiny decided to bring ice cream to the party.\r\n3) Peter isn't in charge of Accounting.\r\n4) Walter provided a big fruit tray.\r\n5) Joshua wasn't the one who supplied the cooked ham.\r\n6) The Managing Director brought the apple pie\r\n7) The Reports Manager supplied the vegetarian lasagna.\r\n8) The person who provided the banana pudding, who wasn't the Contracts Manager, holds a position in the agency which appears in the alphabetical list immediately ahead of the one held by the person who brought pot roast.\r\n9) The individual who had strawberries and cream in one hand had cheese pizza in the other.", "hint": "No hint available.", "answer": "Olivia the Sales Manager brought cheese pizza and strawberries and cream.\r\nDestiny the Contracts Manager brought pot roast and ice cream.\r\nJoshua the Reports Manager brought vegetarian lasagna and chocolate bars\r\nWalter the Accounting Manager brought fruit tray and banana pudding.\r\nPeter the Managing Director brought cooked ham and apple pie.", "category": "Logic-Grid", "date": "12/08/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA company decided to have a Christmas party for the employees. The five people in management each brought a meal and a dessert to show their appreciation. From the clues below determine management's name, their title, and what meal and dessert they brought.\n\r\n1) Neither Olivia, who is the Sales Manager, nor the person who brought the chocolate bars, brought meat for the meal.\r\n2) Destiny decided to bring ice cream to the party.\r\n3) Peter isn't in charge of Accounting.\r\n4) Walter provided a big fruit tray.\r\n5) Joshua wasn't the one who supplied the cooked ham.\r\n6) The Managing Director brought the apple pie\r\n7) The Reports Manager supplied the vegetarian lasagna.\r\n8) The person who provided the banana pudding, who wasn't the Contracts Manager, holds a position in the agency which appears in the alphabetical list immediately ahead of the one held by the person who brought pot roast.\r\n9) The individual who had strawberries and cream in one hand had cheese pizza in the other.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOlivia the Sales Manager brought cheese pizza and strawberries and cream.\r\nDestiny the Contracts Manager brought pot roast and ice cream.\r\nJoshua the Reports Manager brought vegetarian lasagna and chocolate bars\r\nWalter the Accounting Manager brought fruit tray and banana pudding.\r\nPeter the Managing Director brought cooked ham and apple pie.\n<|im_start|>answer\nOlivia the Sales Manager brought cheese pizza and strawberries and cream.\r\nDestiny the Contracts Manager brought pot roast and ice cream.\r\nJoshua the Reports Manager brought vegetarian lasagna and chocolate bars\r\nWalter the Accounting Manager brought fruit tray and banana pudding.\r\nPeter the Managing Director brought cooked ham and apple pie.\n<|im_end|>" }, { "id": "#45543", "title": "Time Lines 2", "fun": 2.94, "difficulty": 2.53, "author": "MarcM1098", "desc": "A clock has 60 lines on it; one at each minute interval. Everyone knows that the hour and minute hands point to the same line at 12:00. Can you figure out what time it is for these situations?\n\r\n1. The hour hand is exactly on one line, and the minute hand is exactly on the NEXT line.\n\r\n2. The hour hand is exactly on one line, and the minute hand is exactly on the PREVIOUS line.", "hint": "Each hour, the minute hand moves 60 intervals, while the hour hand moves 5 intervals. The hour hand is exactly on a line every 12 minutes. ( 60 / 5 = 12 )", "answer": "1. The time is 2:12.\r\n2. The time is 9:48.\n\r\nThe hour hand is exactly on a line every 12 minutes, so we only need to look at times ending in 00, 12, 24, 36, and 48.\r\nThe hands exactly overlap at 12:00. They are 5 lines apart at 11:00 and 1:00, and farther apart at other hours.\r\nAt times ending in 12, the hands are closest at 2:12, where they are 1 line apart.\r\nAt times ending in 24, the hands are closest at 4:24, where they are 2 lines apart.\r\nAt times ending in 36, the hands are closest at 7:36, where they are 2 lines apart.\r\nAt times ending in 48, the hands are closest at 9:48, where they are 1 line apart.", "category": "Logic", "date": "10/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA clock has 60 lines on it; one at each minute interval. Everyone knows that the hour and minute hands point to the same line at 12:00. Can you figure out what time it is for these situations?\n\r\n1. The hour hand is exactly on one line, and the minute hand is exactly on the NEXT line.\n\r\n2. The hour hand is exactly on one line, and the minute hand is exactly on the PREVIOUS line.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. The time is 2:12.\r\n2. The time is 9:48.\n\r\nThe hour hand is exactly on a line every 12 minutes, so we only need to look at times ending in 00, 12, 24, 36, and 48.\r\nThe hands exactly overlap at 12:00. They are 5 lines apart at 11:00 and 1:00, and farther apart at other hours.\r\nAt times ending in 12, the hands are closest at 2:12, where they are 1 line apart.\r\nAt times ending in 24, the hands are closest at 4:24, where they are 2 lines apart.\r\nAt times ending in 36, the hands are closest at 7:36, where they are 2 lines apart.\r\nAt times ending in 48, the hands are closest at 9:48, where they are 1 line apart.\n<|im_start|>answer\n1. The time is 2:12.\r\n2. The time is 9:48.\n\r\nThe hour hand is exactly on a line every 12 minutes, so we only need to look at times ending in 00, 12, 24, 36, and 48.\r\nThe hands exactly overlap at 12:00. They are 5 lines apart at 11:00 and 1:00, and farther apart at other hours.\r\nAt times ending in 12, the hands are closest at 2:12, where they are 1 line apart.\r\nAt times ending in 24, the hands are closest at 4:24, where they are 2 lines apart.\r\nAt times ending in 36, the hands are closest at 7:36, where they are 2 lines apart.\r\nAt times ending in 48, the hands are closest at 9:48, where they are 1 line apart.\n<|im_end|>" }, { "id": "#36206", "title": "Maids of the Manors", "fun": 2.94, "difficulty": 1.66, "author": "rubytuesday", "desc": "Back in the days of Knights and Castles, there lived a mother and her 4 daughters. Each woman was employed doing a different job at different castles. As they were far apart in age, each had served a different number of years. Can you figure out who does which job at which castle, for what number of years?\n\r\n1. The girls' mother served at Lanton Castle for the longest period of time. Elizabeth, being the youngest, had the least number of years in, one year less than the dairymaid.\n\r\n2. Annie served more years than the chambermaid, who served 4 more years than Tess. Tess served 11 more years than servant at Daneby Manor.\n\r\n3. The ladies' maid served fewer years than Mary's 19, and 10 more years than the servant at Forsham Palace. \n\r\n4. The cook served five times as many years as Victoria and ten more years than the servant at Berkson Castle.", "hint": "No hint available.", "answer": "Annie, their mother, worked as a cook at Lanton Castle for 25 years.\r\nElizabeth worked as a nursery maid at Daneby Manor for 4 years.\r\nMary worked as a chambermaid at Windy Manor for 19 years.\r\nVictoria worked as a dairymaid at Forsham Palace for 5 years.\r\nTess worked as a ladies' maid at Berkson Castle for 15 years.", "category": "Logic-Grid", "date": "04/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBack in the days of Knights and Castles, there lived a mother and her 4 daughters. Each woman was employed doing a different job at different castles. As they were far apart in age, each had served a different number of years. Can you figure out who does which job at which castle, for what number of years?\n\r\n1. The girls' mother served at Lanton Castle for the longest period of time. Elizabeth, being the youngest, had the least number of years in, one year less than the dairymaid.\n\r\n2. Annie served more years than the chambermaid, who served 4 more years than Tess. Tess served 11 more years than servant at Daneby Manor.\n\r\n3. The ladies' maid served fewer years than Mary's 19, and 10 more years than the servant at Forsham Palace. \n\r\n4. The cook served five times as many years as Victoria and ten more years than the servant at Berkson Castle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnnie, their mother, worked as a cook at Lanton Castle for 25 years.\r\nElizabeth worked as a nursery maid at Daneby Manor for 4 years.\r\nMary worked as a chambermaid at Windy Manor for 19 years.\r\nVictoria worked as a dairymaid at Forsham Palace for 5 years.\r\nTess worked as a ladies' maid at Berkson Castle for 15 years.\n<|im_start|>answer\nAnnie, their mother, worked as a cook at Lanton Castle for 25 years.\r\nElizabeth worked as a nursery maid at Daneby Manor for 4 years.\r\nMary worked as a chambermaid at Windy Manor for 19 years.\r\nVictoria worked as a dairymaid at Forsham Palace for 5 years.\r\nTess worked as a ladies' maid at Berkson Castle for 15 years.\n<|im_end|>" }, { "id": "#24243", "title": "Olympic Swim Team", "fun": 2.94, "difficulty": 3.28, "author": "cnmne", "desc": "Five swimmers (Adam, Brad, Carl, Doug, and Eric) have been preparing for the Olympics. It is now time for the swimming time trials. The five swimmers each compete in the four different strokes (backstroke, breaststroke, butterfly, and freestyle). The top three finishers in each event will qualify for the Olympic swim team in that stroke. Using the following clues, determine the order of finish in each of the four strokes.\n\r\n1) Only one contestant qualified in all four strokes.\r\n2) No contestant finished last in more than one event.\r\n3) Adam finished better in the backstroke than he did in the butterfly.\r\n4) Brad finished better than Doug in the butterfly.\r\n5) Adam finished just behind Brad and just ahead of Eric in the breaststroke.\r\n6) Doug finished just ahead of Carl in the freestyle.\r\n7) Neither Brad nor Eric finished third in any event.\r\n8) Eric's finish in the backstroke was the same as Doug's in the butterfly.\r\n9) Doug only finished in the same position in the backstroke and the freestyle.\r\n10) Carl finished in a different position in each event.\r\n11) Brad finished only two events in the same position.\r\n12) The contestant who finished second in the butterfly beat Doug in the freestyle.\r\n13) The contestant who finished first in the freestyle did not qualify in the backstroke.\r\n14) The contestant who finished fifth in the backstroke did not finish third in the butterfly.\r\n15) No contestant finished in the same position in both the breaststroke and the butterfly.", "hint": "No hint available.", "answer": "Backstroke: Adam, Carl, Doug, Brad, Eric\r\nBreaststroke: Doug, Brad, Adam, Eric, Carl\r\nButterfly: Eric, Adam, Carl, Brad, Doug\r\nFreestyle: Eric, Adam, Doug, Carl, Brad", "category": "Logic-Grid", "date": "07/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive swimmers (Adam, Brad, Carl, Doug, and Eric) have been preparing for the Olympics. It is now time for the swimming time trials. The five swimmers each compete in the four different strokes (backstroke, breaststroke, butterfly, and freestyle). The top three finishers in each event will qualify for the Olympic swim team in that stroke. Using the following clues, determine the order of finish in each of the four strokes.\n\r\n1) Only one contestant qualified in all four strokes.\r\n2) No contestant finished last in more than one event.\r\n3) Adam finished better in the backstroke than he did in the butterfly.\r\n4) Brad finished better than Doug in the butterfly.\r\n5) Adam finished just behind Brad and just ahead of Eric in the breaststroke.\r\n6) Doug finished just ahead of Carl in the freestyle.\r\n7) Neither Brad nor Eric finished third in any event.\r\n8) Eric's finish in the backstroke was the same as Doug's in the butterfly.\r\n9) Doug only finished in the same position in the backstroke and the freestyle.\r\n10) Carl finished in a different position in each event.\r\n11) Brad finished only two events in the same position.\r\n12) The contestant who finished second in the butterfly beat Doug in the freestyle.\r\n13) The contestant who finished first in the freestyle did not qualify in the backstroke.\r\n14) The contestant who finished fifth in the backstroke did not finish third in the butterfly.\r\n15) No contestant finished in the same position in both the breaststroke and the butterfly.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBackstroke: Adam, Carl, Doug, Brad, Eric\r\nBreaststroke: Doug, Brad, Adam, Eric, Carl\r\nButterfly: Eric, Adam, Carl, Brad, Doug\r\nFreestyle: Eric, Adam, Doug, Carl, Brad\n<|im_start|>answer\nBackstroke: Adam, Carl, Doug, Brad, Eric\r\nBreaststroke: Doug, Brad, Adam, Eric, Carl\r\nButterfly: Eric, Adam, Carl, Brad, Doug\r\nFreestyle: Eric, Adam, Doug, Carl, Brad\n<|im_end|>" }, { "id": "#6898", "title": "Multiple Choice Questions", "fun": 2.94, "difficulty": 1.8, "author": "silver_sword", "desc": "What are your answers to the respective questions so that your answers to all the questions are correct?\n\r\n------------------------------------------\n\r\nQuestion 1\r\nThe answer to Question 2 is:\r\nA. B\r\nB. C\r\nC. A\n\r\nQuestion 2 \r\nThe first question with correct answer B is:\r\nA. Question 3\r\nB. Question 1\r\nC. Question 2\n\r\nQuestion 3 \r\nThe only answer you have not chosen yet is:\r\nA. A\r\nB. B\r\nC. C", "hint": "No hint available.", "answer": "Question 1: C\r\nQuestion 2: A\r\nQuestion 3: B\n\r\nJust go through the answers to Question 1:\r\nThe answer can't be \"A\" because then the answer to question 2 would say that the answer to Question 1 was really \"B\".\r\nThe answer to Question 1 can't be \"B\" either, because then question 2 would state that its own answer is \"B\", when it would have to be \"C\".\r\nThis leaves \"C\" for Question 1 and \"A\" for Question 2.\r\nQuestion 3 must then have an answer of \"B\".", "category": "Logic", "date": "08/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat are your answers to the respective questions so that your answers to all the questions are correct?\n\r\n------------------------------------------\n\r\nQuestion 1\r\nThe answer to Question 2 is:\r\nA. B\r\nB. C\r\nC. A\n\r\nQuestion 2 \r\nThe first question with correct answer B is:\r\nA. Question 3\r\nB. Question 1\r\nC. Question 2\n\r\nQuestion 3 \r\nThe only answer you have not chosen yet is:\r\nA. A\r\nB. B\r\nC. C\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nQuestion 1: C\r\nQuestion 2: A\r\nQuestion 3: B\n\r\nJust go through the answers to Question 1:\r\nThe answer can't be \"A\" because then the answer to question 2 would say that the answer to Question 1 was really \"B\".\r\nThe answer to Question 1 can't be \"B\" either, because then question 2 would state that its own answer is \"B\", when it would have to be \"C\".\r\nThis leaves \"C\" for Question 1 and \"A\" for Question 2.\r\nQuestion 3 must then have an answer of \"B\".\n<|im_start|>answer\nQuestion 1: C\r\nQuestion 2: A\r\nQuestion 3: B\n\r\nJust go through the answers to Question 1:\r\nThe answer can't be \"A\" because then the answer to question 2 would say that the answer to Question 1 was really \"B\".\r\nThe answer to Question 1 can't be \"B\" either, because then question 2 would state that its own answer is \"B\", when it would have to be \"C\".\r\nThis leaves \"C\" for Question 1 and \"A\" for Question 2.\r\nQuestion 3 must then have an answer of \"B\".\n<|im_end|>" }, { "id": "#20843", "title": "Ladies Night Out", "fun": 2.94, "difficulty": 1.96, "author": "mindbender", "desc": "Sarah, Kelley, Jennifer, Erin, and Jan are all going out to party on Friday night. Each girl was picked up by the taxi service at a different house wearing different colored outfits (red dress, pink skirt, silver halter, black leather pants, and a white dress). Each girl met a man (Tyler, Christopher, Jacob, Tom, & Scott) while out at the clubs. Figure out which girl was picked up when, what they were wearing and who their dates were.\r\nGirls: Sarah, Kelley, Jennifer, Erin, & Jan\r\nDates: Tyler, Christopher, Jacob, Tom, & Scott\r\nOutfit colors: Red, Pink, Black, Silver, & White\n\r\n1.None of the men dated a girl with the same first letter in their name or their clothing color as the first letter in his name.\n\r\n2.Scott dates the girl who wears red and wasn't picked up last.\n\r\n3.Christopher is best friends with Sarah and Erin but doesn't date them.\n\r\n4.Jacob is Kelley's brother who dates the girl wearing black leather.\n\r\n5.The first girl to be picked up wasn't wearing pink or red but her date was Tom.\n\r\n6.It wasn't after Labor Day so Jan wasn't breaking any fashion rules by wearing white.\n\r\n7.Tyler's date was picked up last and hates to wear the color white.\n\r\n8.Kelley was picked up before Sarah but not before Erin.\n\r\n9.Jan ordered the taxi, so it picked her up first.\n\r\n10.The fifth girl to be picked up was wearing silver.\n\r\n11.Erin, looking fiery hot, was the second girl to be picked up.\n\r\n12.Jacob and Tyler are twin brothers; one likes girls in black while the other prefers girls in silver.", "hint": "No hint available.", "answer": "Kelley... Christopher... Pink... 3\r\nJan... Tom ... White... 1\r\nJennifer... Tyler ...Silver... 5\r\nErin... Scott... Red... 2\r\nSarah... Jacob ... Black...4", "category": "Logic-Grid", "date": "02/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSarah, Kelley, Jennifer, Erin, and Jan are all going out to party on Friday night. Each girl was picked up by the taxi service at a different house wearing different colored outfits (red dress, pink skirt, silver halter, black leather pants, and a white dress). Each girl met a man (Tyler, Christopher, Jacob, Tom, & Scott) while out at the clubs. Figure out which girl was picked up when, what they were wearing and who their dates were.\r\nGirls: Sarah, Kelley, Jennifer, Erin, & Jan\r\nDates: Tyler, Christopher, Jacob, Tom, & Scott\r\nOutfit colors: Red, Pink, Black, Silver, & White\n\r\n1.None of the men dated a girl with the same first letter in their name or their clothing color as the first letter in his name.\n\r\n2.Scott dates the girl who wears red and wasn't picked up last.\n\r\n3.Christopher is best friends with Sarah and Erin but doesn't date them.\n\r\n4.Jacob is Kelley's brother who dates the girl wearing black leather.\n\r\n5.The first girl to be picked up wasn't wearing pink or red but her date was Tom.\n\r\n6.It wasn't after Labor Day so Jan wasn't breaking any fashion rules by wearing white.\n\r\n7.Tyler's date was picked up last and hates to wear the color white.\n\r\n8.Kelley was picked up before Sarah but not before Erin.\n\r\n9.Jan ordered the taxi, so it picked her up first.\n\r\n10.The fifth girl to be picked up was wearing silver.\n\r\n11.Erin, looking fiery hot, was the second girl to be picked up.\n\r\n12.Jacob and Tyler are twin brothers; one likes girls in black while the other prefers girls in silver.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKelley... Christopher... Pink... 3\r\nJan... Tom ... White... 1\r\nJennifer... Tyler ...Silver... 5\r\nErin... Scott... Red... 2\r\nSarah... Jacob ... Black...4\n<|im_start|>answer\nKelley... Christopher... Pink... 3\r\nJan... Tom ... White... 1\r\nJennifer... Tyler ...Silver... 5\r\nErin... Scott... Red... 2\r\nSarah... Jacob ... Black...4\n<|im_end|>" }, { "id": "#43611", "title": "The Office Potluck", "fun": 2.94, "difficulty": 1.34, "author": "dswilborn", "desc": "Every year at Thanksgiving, the employees at Dunder-Mifflin hold a potluck. This year, the ladies of the office (including Meredith) brought in their favorite holiday foods, although some of their choices were not quite traditional. Can you determine from the clues below the food each employee brought, what color plate the food was served on, and how much of the food was left when the potluck was over?\n\r\n1. Two of the ladies brought home empty plates, but Angela and the person who brought green beans weren't as lucky.\n\r\n2. The person who brought the Taquitos used a paper plate.\n\r\n3. The four employees are Kelly, the lady who brought the red plate, the lady who brought the Marshmallow Yams, and the person whose plate was 1/2 full after the party.\n\r\n4. After the potluck, the brown plate had food left on it, but it wasn't pizza rolls.\n\r\n5. Angela's plate was green. Phyllis's plate was not brown but was empty after the party.\n\r\n6. The Marshmallow Yams were the least popular item of the potluck and had the most food remaining afterwards.", "hint": "Angela would never bring Taquitos or pizza rolls!", "answer": "Meredith brought green beans on a brown plate and had 1/2 left.\r\nKelly brought Taquitos on a paper plate and the plate was empty.\r\nAngela brought Marshmallow Yams on a green plate and had 3/4 left.\r\nPhyllis brought pizza rolls on a red plate and the plate was empty.", "category": "Logic-Grid", "date": "11/23/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery year at Thanksgiving, the employees at Dunder-Mifflin hold a potluck. This year, the ladies of the office (including Meredith) brought in their favorite holiday foods, although some of their choices were not quite traditional. Can you determine from the clues below the food each employee brought, what color plate the food was served on, and how much of the food was left when the potluck was over?\n\r\n1. Two of the ladies brought home empty plates, but Angela and the person who brought green beans weren't as lucky.\n\r\n2. The person who brought the Taquitos used a paper plate.\n\r\n3. The four employees are Kelly, the lady who brought the red plate, the lady who brought the Marshmallow Yams, and the person whose plate was 1/2 full after the party.\n\r\n4. After the potluck, the brown plate had food left on it, but it wasn't pizza rolls.\n\r\n5. Angela's plate was green. Phyllis's plate was not brown but was empty after the party.\n\r\n6. The Marshmallow Yams were the least popular item of the potluck and had the most food remaining afterwards.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMeredith brought green beans on a brown plate and had 1/2 left.\r\nKelly brought Taquitos on a paper plate and the plate was empty.\r\nAngela brought Marshmallow Yams on a green plate and had 3/4 left.\r\nPhyllis brought pizza rolls on a red plate and the plate was empty.\n<|im_start|>answer\nMeredith brought green beans on a brown plate and had 1/2 left.\r\nKelly brought Taquitos on a paper plate and the plate was empty.\r\nAngela brought Marshmallow Yams on a green plate and had 3/4 left.\r\nPhyllis brought pizza rolls on a red plate and the plate was empty.\n<|im_end|>" }, { "id": "#28193", "title": "Walking the Dog", "fun": 2.94, "difficulty": 1.77, "author": "xsagirl", "desc": "To raise extra pocket-money, young Miles Trotter takes dogs for walks in the local park. His services are currently employed by five of his neighbors, who can't personally exercise their dogs every day. From the clues below, can you discover the number of the house at which each dog lives, the name of his owner and the number of times per week that Miles takes him for a run in the park?\n\r\n1. Bonzo is taken to the park more often than Mr. Carter's dog.\n\r\n2. Mr. Taylor lives at No. 3. Miles takes Whisky to the park four times every week.\n\r\n3. Miss French's dog goes to the park twice per week.\n\r\n4. Pip (who belongs to Mrs. Beale) goes to the park more often than the dog from house No. 1, who doesn't get taken to the park just once per week.\n\r\n5. Rusty (not Mr. Taylor's dog) is taken for a run in the park five times every week.\n\r\n6. The dog from No. 2 gets taken out three times per week.\n\r\n7. Mrs. Morris doesn't live at No. 5.", "hint": "No hint available.", "answer": "Bobby, No. 5, Mr. Carter, once\r\nBonzo, No. 1, Miss French, twice\r\nPip, No. 2, Mrs. Beale, 3 times\r\nRusty, No. 4, Mrs. Morris, 5 times\r\nWhisky, No. 3, Mr. Taylor, 4 times", "category": "Logic-Grid", "date": "01/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTo raise extra pocket-money, young Miles Trotter takes dogs for walks in the local park. His services are currently employed by five of his neighbors, who can't personally exercise their dogs every day. From the clues below, can you discover the number of the house at which each dog lives, the name of his owner and the number of times per week that Miles takes him for a run in the park?\n\r\n1. Bonzo is taken to the park more often than Mr. Carter's dog.\n\r\n2. Mr. Taylor lives at No. 3. Miles takes Whisky to the park four times every week.\n\r\n3. Miss French's dog goes to the park twice per week.\n\r\n4. Pip (who belongs to Mrs. Beale) goes to the park more often than the dog from house No. 1, who doesn't get taken to the park just once per week.\n\r\n5. Rusty (not Mr. Taylor's dog) is taken for a run in the park five times every week.\n\r\n6. The dog from No. 2 gets taken out three times per week.\n\r\n7. Mrs. Morris doesn't live at No. 5.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBobby, No. 5, Mr. Carter, once\r\nBonzo, No. 1, Miss French, twice\r\nPip, No. 2, Mrs. Beale, 3 times\r\nRusty, No. 4, Mrs. Morris, 5 times\r\nWhisky, No. 3, Mr. Taylor, 4 times\n<|im_start|>answer\nBobby, No. 5, Mr. Carter, once\r\nBonzo, No. 1, Miss French, twice\r\nPip, No. 2, Mrs. Beale, 3 times\r\nRusty, No. 4, Mrs. Morris, 5 times\r\nWhisky, No. 3, Mr. Taylor, 4 times\n<|im_end|>" }, { "id": "#24933", "title": "Friday Night Lineup", "fun": 2.94, "difficulty": 1.8900000000000001, "author": "phrebh", "desc": "The programming director at local channel U62 was trying to determine the all-important Friday night lineup. He had five potential hosts (Kuni, Pamela, Philo, Raul, and Stanley) and five shows to use (Druids on Parade [DoP], Fun with Dirt [FwD], the news, Underwater Bingo for Teens [UBfT], and Volcano Worshipers Hour [VWH]) in five different time slots (8:00 pm, 9:00 pm, 10:00 pm, 11:00 pm, and 11:30 pm). Any of the shows can be in an hour or a half hour format. Each of the shows also has its own mascot (alien, badger, fish, poodle, or turtle). Using the clues, can you determine the lineup of shows with their hosts and mascots?\n\r\n1. The mascot for the show Philo hosts is not a badger.\r\n2. Volcano Worshipers Hour is on exactly one hour after the show that Kuni hosts.\r\n3. The show with the poodle as the mascot, which is hosted by Pamela, is on after 9:00 pm but before 11:30 pm.\r\n4. Druids on Parade is on exactly three hours before the news.\r\n5. Stanley hosts Fun with Dirt, which is not the second show on Friday nights.\r\n6. The show with a turtle as its mascot is on right after the news. Kuni is not the host of the show.\r\n7. The fish is not the mascot for Underwater Bingo for Teens.\r\n8. Only Raul's and Stanley's shows have mascots whose names are different lengths from the hosts' names.\r\n9. The show that Raul hosts, which is not Volcano Worshipers Hour, is on at 10:00 pm.", "hint": "No hint available.", "answer": "Druids on Parade is on at 8:00 pm, is hosted by Kuni, and its mascot is a fish.\r\nFun with Dirt is on at 11:30 pm, is hosted by Stanley, and its mascot is a turtle.\r\nThe news is on at 11:00 pm, is hosted by Pamela, and its mascot is a poodle.\r\nUnderwater Bingo for Teens is on at 10:00 pm, is hosted by Raul, and its mascot is a badger.\r\nVolcano Worshipers Hour is on at 9:00 pm, is hosted by Philo, and its mascot is an alien.\n\r\nThese are the actual shows and times for the Friday night lineup at U62 in the \"Weird Al\" Yankovic cult classic, UHF. With the exception of the news, however, the hosts are from different shows in the movie.", "category": "Logic-Grid", "date": "07/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe programming director at local channel U62 was trying to determine the all-important Friday night lineup. He had five potential hosts (Kuni, Pamela, Philo, Raul, and Stanley) and five shows to use (Druids on Parade [DoP], Fun with Dirt [FwD], the news, Underwater Bingo for Teens [UBfT], and Volcano Worshipers Hour [VWH]) in five different time slots (8:00 pm, 9:00 pm, 10:00 pm, 11:00 pm, and 11:30 pm). Any of the shows can be in an hour or a half hour format. Each of the shows also has its own mascot (alien, badger, fish, poodle, or turtle). Using the clues, can you determine the lineup of shows with their hosts and mascots?\n\r\n1. The mascot for the show Philo hosts is not a badger.\r\n2. Volcano Worshipers Hour is on exactly one hour after the show that Kuni hosts.\r\n3. The show with the poodle as the mascot, which is hosted by Pamela, is on after 9:00 pm but before 11:30 pm.\r\n4. Druids on Parade is on exactly three hours before the news.\r\n5. Stanley hosts Fun with Dirt, which is not the second show on Friday nights.\r\n6. The show with a turtle as its mascot is on right after the news. Kuni is not the host of the show.\r\n7. The fish is not the mascot for Underwater Bingo for Teens.\r\n8. Only Raul's and Stanley's shows have mascots whose names are different lengths from the hosts' names.\r\n9. The show that Raul hosts, which is not Volcano Worshipers Hour, is on at 10:00 pm.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDruids on Parade is on at 8:00 pm, is hosted by Kuni, and its mascot is a fish.\r\nFun with Dirt is on at 11:30 pm, is hosted by Stanley, and its mascot is a turtle.\r\nThe news is on at 11:00 pm, is hosted by Pamela, and its mascot is a poodle.\r\nUnderwater Bingo for Teens is on at 10:00 pm, is hosted by Raul, and its mascot is a badger.\r\nVolcano Worshipers Hour is on at 9:00 pm, is hosted by Philo, and its mascot is an alien.\n\r\nThese are the actual shows and times for the Friday night lineup at U62 in the \"Weird Al\" Yankovic cult classic, UHF. With the exception of the news, however, the hosts are from different shows in the movie.\n<|im_start|>answer\nDruids on Parade is on at 8:00 pm, is hosted by Kuni, and its mascot is a fish.\r\nFun with Dirt is on at 11:30 pm, is hosted by Stanley, and its mascot is a turtle.\r\nThe news is on at 11:00 pm, is hosted by Pamela, and its mascot is a poodle.\r\nUnderwater Bingo for Teens is on at 10:00 pm, is hosted by Raul, and its mascot is a badger.\r\nVolcano Worshipers Hour is on at 9:00 pm, is hosted by Philo, and its mascot is an alien.\n\r\nThese are the actual shows and times for the Friday night lineup at U62 in the \"Weird Al\" Yankovic cult classic, UHF. With the exception of the news, however, the hosts are from different shows in the movie.\n<|im_end|>" }, { "id": "#20287", "title": "Counting to 50", "fun": 2.94, "difficulty": 2.37, "author": "tsimkin", "desc": "Henry and Gretchen are going to play a game. Henry explains, \"You and I will take turns saying numbers. The first person will say a number between 1 and 10. Then the other person will say a number that is at least 1 higher than that number, and at most 10 higher. We will keep going back and forth in this way until one of us says the number 50. That person wins. I'll start.\"\n\r\n\"Not so fast!\" says Gretchen. \"I want to win, so I will start.\"\n\r\nWhat number should Gretchen say to start?", "hint": "By following this strategy, she is assured a victory. Think of all of the numbers she will want to say.", "answer": "She wants to say, \"6.\"\n\r\nThe series of numbers she will say is 6, 17, 28, 39, 50.\n\r\nSince she wants to say 50, she needs Henry to say a number between 40 and 49. Therefore, she wants to say 39.\n\r\nKnowing she wants to say 39, she needs Henry to say a number between 29 and 38. So she wants to say 28. Following this same logic recursively, she will want to say 17, and she will want to say 6 to start the game, and be assured victory.", "category": "Logic", "date": "01/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHenry and Gretchen are going to play a game. Henry explains, \"You and I will take turns saying numbers. The first person will say a number between 1 and 10. Then the other person will say a number that is at least 1 higher than that number, and at most 10 higher. We will keep going back and forth in this way until one of us says the number 50. That person wins. I'll start.\"\n\r\n\"Not so fast!\" says Gretchen. \"I want to win, so I will start.\"\n\r\nWhat number should Gretchen say to start?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe wants to say, \"6.\"\n\r\nThe series of numbers she will say is 6, 17, 28, 39, 50.\n\r\nSince she wants to say 50, she needs Henry to say a number between 40 and 49. Therefore, she wants to say 39.\n\r\nKnowing she wants to say 39, she needs Henry to say a number between 29 and 38. So she wants to say 28. Following this same logic recursively, she will want to say 17, and she will want to say 6 to start the game, and be assured victory.\n<|im_start|>answer\nShe wants to say, \"6.\"\n\r\nThe series of numbers she will say is 6, 17, 28, 39, 50.\n\r\nSince she wants to say 50, she needs Henry to say a number between 40 and 49. Therefore, she wants to say 39.\n\r\nKnowing she wants to say 39, she needs Henry to say a number between 29 and 38. So she wants to say 28. Following this same logic recursively, she will want to say 17, and she will want to say 6 to start the game, and be assured victory.\n<|im_end|>" }, { "id": "#27992", "title": "The Scrolls", "fun": 2.94, "difficulty": 1.31, "author": "Sunrose", "desc": "Vanya was not caught, and was still causing trouble upon the land. Hearing the news from the Seekers of Knowledge, the mayor wrote messages to the proper people. The mayor knew that they would want to know, and may be able to help with the problem. \n\r\nThe messages will need to be sent with people that can be trusted, and capable of getting them delivered. So, the mayor went and asked the Seekers of Knowledge if they could deliver them for him? Of course, our heroes could not turn him down. They knew it was important, and meant a lot to the mayor.\n\r\nSince there are only 4 messages to be delivered, Dawn stayed back in order to catch up on studying some new spells, and scribing them in her spell-book, which none of the group seemed to mind.\n\r\nCan you figure out where each member is going, which direction they will be traveling in, what type of transportation is used, and who they are delivering the message to?\n\r\nMembers: Thad, Sid, Joel, Clover\r\nDirection: North, East, West, South\r\nDeliver to: Lady Ka'tara, Lord Silverblade, Duke, High Priest\r\nType of Transportation: Horse, Magic Carpet, Magic Port, Walked \n\n\r\n1) They consist of Thad, the one going west, the one delivering to Lady Ka'tara, the one on the magic carpet.\n\r\n2) Clover and Joel did not ride the horse, but Clover went South while Joel went West.\n\r\n3) The one who delivered to the Duke walked, but that was not Sid.\n\r\n4) Thad went North, but did not deliver to the Duke.\n\r\n5) Lady Ka'tara is to the south, but the messenger didn't arrive on the magic carpet.\n\r\n6) Clover didn't deliver to the High Priest or Lord Silverblade. \n\r\n7) Sid did not travel by magic port or deliver to Lord Silverblade.", "hint": "No hint available.", "answer": "Thad - North - Horse - Lord Silverblade.\r\nClover - South - Magic Port - Lady Ka'tara.\r\nSid - East - Magic Carpet - High Priest.\r\nJoel - West - Walked - Duke.", "category": "Logic-Grid", "date": "01/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nVanya was not caught, and was still causing trouble upon the land. Hearing the news from the Seekers of Knowledge, the mayor wrote messages to the proper people. The mayor knew that they would want to know, and may be able to help with the problem. \n\r\nThe messages will need to be sent with people that can be trusted, and capable of getting them delivered. So, the mayor went and asked the Seekers of Knowledge if they could deliver them for him? Of course, our heroes could not turn him down. They knew it was important, and meant a lot to the mayor.\n\r\nSince there are only 4 messages to be delivered, Dawn stayed back in order to catch up on studying some new spells, and scribing them in her spell-book, which none of the group seemed to mind.\n\r\nCan you figure out where each member is going, which direction they will be traveling in, what type of transportation is used, and who they are delivering the message to?\n\r\nMembers: Thad, Sid, Joel, Clover\r\nDirection: North, East, West, South\r\nDeliver to: Lady Ka'tara, Lord Silverblade, Duke, High Priest\r\nType of Transportation: Horse, Magic Carpet, Magic Port, Walked \n\n\r\n1) They consist of Thad, the one going west, the one delivering to Lady Ka'tara, the one on the magic carpet.\n\r\n2) Clover and Joel did not ride the horse, but Clover went South while Joel went West.\n\r\n3) The one who delivered to the Duke walked, but that was not Sid.\n\r\n4) Thad went North, but did not deliver to the Duke.\n\r\n5) Lady Ka'tara is to the south, but the messenger didn't arrive on the magic carpet.\n\r\n6) Clover didn't deliver to the High Priest or Lord Silverblade. \n\r\n7) Sid did not travel by magic port or deliver to Lord Silverblade.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThad - North - Horse - Lord Silverblade.\r\nClover - South - Magic Port - Lady Ka'tara.\r\nSid - East - Magic Carpet - High Priest.\r\nJoel - West - Walked - Duke.\n<|im_start|>answer\nThad - North - Horse - Lord Silverblade.\r\nClover - South - Magic Port - Lady Ka'tara.\r\nSid - East - Magic Carpet - High Priest.\r\nJoel - West - Walked - Duke.\n<|im_end|>" }, { "id": "#48970", "title": "Lion and the Unicorn", "fun": 2.94, "difficulty": 1.18, "author": "Faith511", "desc": "Alice came across a lion and a unicorn in a forest of forgetfulness. Those two are strange beings. The lion lies every Monday, Tuesday and Wednesday and the other days he speaks the truth. The unicorn lies on Thursdays, Fridays and Saturdays, however the other days of the week he speaks the truth.\n\r\nLion: Yesterday I was lying.\r\nUnicorn: So was I.\n\r\nOn which day did they say that?", "hint": "No hint available.", "answer": "As there is no day when both of the beings would be lying, at least one of them must have spoken the truth. They both speak the truth only on Sunday. However, the Lion would then be lying in his statement, so it couldn't be said on Sunday. So exactly one of them lied.\n\r\nIf the Unicorn was honest, then it would have to be Sunday - but previously we proved this wrong. Thus only the Lion spoke the truth when he met Alice on Thursday and spoke with the Unicorn about Wednesday.", "category": "Logic", "date": "08/23/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlice came across a lion and a unicorn in a forest of forgetfulness. Those two are strange beings. The lion lies every Monday, Tuesday and Wednesday and the other days he speaks the truth. The unicorn lies on Thursdays, Fridays and Saturdays, however the other days of the week he speaks the truth.\n\r\nLion: Yesterday I was lying.\r\nUnicorn: So was I.\n\r\nOn which day did they say that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAs there is no day when both of the beings would be lying, at least one of them must have spoken the truth. They both speak the truth only on Sunday. However, the Lion would then be lying in his statement, so it couldn't be said on Sunday. So exactly one of them lied.\n\r\nIf the Unicorn was honest, then it would have to be Sunday - but previously we proved this wrong. Thus only the Lion spoke the truth when he met Alice on Thursday and spoke with the Unicorn about Wednesday.\n<|im_start|>answer\nAs there is no day when both of the beings would be lying, at least one of them must have spoken the truth. They both speak the truth only on Sunday. However, the Lion would then be lying in his statement, so it couldn't be said on Sunday. So exactly one of them lied.\n\r\nIf the Unicorn was honest, then it would have to be Sunday - but previously we proved this wrong. Thus only the Lion spoke the truth when he met Alice on Thursday and spoke with the Unicorn about Wednesday.\n<|im_end|>" }, { "id": "#42980", "title": "Down on Main Street", "fun": 2.94, "difficulty": 2.19, "author": "whsprec", "desc": "The Smiths, the Joneses, the Alreds, the Woolards, and the Greens all live on Main Street. The numbers on the houses run from south to north, with the highest number being the most northerly. Each house is a different color: red, black, tan, yellow, or blue. In each yard is a different type of tree: oak, elm, ash, willow, or pine. Match the owner to the house number, the color of the house, and the type of tree in the yard.\n\r\n1) The Smith house and the Woolard house do not have pine trees and neither does the black house.\r\n2) The Green house is one north of the blue house and one south of the house with the pine tree.\r\n3) The blue house is one north of the Woolard house, which is the next house north of the house with the willow tree.\r\n4) Neither the Smith house nor the Alred house has a tree on its front lawn with a three letter name, but the colors of each of their houses are three letter words.\r\n5) The Woolard house does not have an elm tree in its front yard.\r\n6) The Green house is the next house to the south of the tan house and the next house north of the house with an oak on its front lawn.", "hint": "No hint available.", "answer": "Number 9 - Alred, pine, tan\r\nNumber 7 - Green, elm, black\r\nNumber 5 - Jones, oak, blue\r\nNumber 3 - Woolard, ash, yellow\r\nNumber 1 - Smith, willow, red", "category": "Logic-Grid", "date": "09/03/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Smiths, the Joneses, the Alreds, the Woolards, and the Greens all live on Main Street. The numbers on the houses run from south to north, with the highest number being the most northerly. Each house is a different color: red, black, tan, yellow, or blue. In each yard is a different type of tree: oak, elm, ash, willow, or pine. Match the owner to the house number, the color of the house, and the type of tree in the yard.\n\r\n1) The Smith house and the Woolard house do not have pine trees and neither does the black house.\r\n2) The Green house is one north of the blue house and one south of the house with the pine tree.\r\n3) The blue house is one north of the Woolard house, which is the next house north of the house with the willow tree.\r\n4) Neither the Smith house nor the Alred house has a tree on its front lawn with a three letter name, but the colors of each of their houses are three letter words.\r\n5) The Woolard house does not have an elm tree in its front yard.\r\n6) The Green house is the next house to the south of the tan house and the next house north of the house with an oak on its front lawn.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNumber 9 - Alred, pine, tan\r\nNumber 7 - Green, elm, black\r\nNumber 5 - Jones, oak, blue\r\nNumber 3 - Woolard, ash, yellow\r\nNumber 1 - Smith, willow, red\n<|im_start|>answer\nNumber 9 - Alred, pine, tan\r\nNumber 7 - Green, elm, black\r\nNumber 5 - Jones, oak, blue\r\nNumber 3 - Woolard, ash, yellow\r\nNumber 1 - Smith, willow, red\n<|im_end|>" }, { "id": "#5092", "title": "What are we?", "fun": 2.94, "difficulty": 2.65, "author": "badbrian08", "desc": "1. I am always excited\r\n2. I tell people where things are at\r\n3. You can play a game on me\r\n4. I'm very rich\r\n5. I give percentages\r\n6. I am always looking up\r\n7. And.........\r\n8. I look like a light in the sky\r\n9. I keep things arranged that are to my right\r\n10. I keep things arranged that are to my left\r\nWhat Are We?", "hint": "Use the Number System", "answer": "The number 1, 2, 3, 4, 5, 6, 7, 8, 9, and 0 on a US keyboard when you hold the shift button down.", "category": "Logic", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n1. I am always excited\r\n2. I tell people where things are at\r\n3. You can play a game on me\r\n4. I'm very rich\r\n5. I give percentages\r\n6. I am always looking up\r\n7. And.........\r\n8. I look like a light in the sky\r\n9. I keep things arranged that are to my right\r\n10. I keep things arranged that are to my left\r\nWhat Are We?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number 1, 2, 3, 4, 5, 6, 7, 8, 9, and 0 on a US keyboard when you hold the shift button down.\n<|im_start|>answer\nThe number 1, 2, 3, 4, 5, 6, 7, 8, 9, and 0 on a US keyboard when you hold the shift button down.\n<|im_end|>" }, { "id": "#34254", "title": "Kirana Visits Friends on Betelgeuse", "fun": 2.94, "difficulty": 2.61, "author": "scallio", "desc": "When Kirana travels back to her home planet of Betelgeuse, she has many friends to visit and very little time so she plans a full itinerary. She visits 5 different friends who live in 5 different towns along a road 25 Gintars long (a unit of measure on Betelgeuse equal to roughly 1 mile). However, in her haste, she makes an embarrassing blunder at each home.\n\r\nCan you determine Kirana's exact itinerary, how far each friend lives from the spaceport of Axim and which blunder was made at which stop? The distances are measured in whole Gintars (no fractions).\n\r\n1. Kirana begins her trip in Axim and always travels East, never backtracking, until she reaches her final destination, the spaceport in Lisiter. The total distance between Axim and Lisiter is 25 Gintars.\n\r\n2. At the home in Sarix, Kirana was asked to leave after knocking over an expensive Kimingle Vase.\n\r\n3. The town of Claymot is twice as far from the Axim spaceport as the town where she stopped at her friend Martina's.\n\r\n4. The incident where Kirana mistook the family's art display for a trash receptacle did not occur during her visit to Kylani's home. Who would have known it was a replica of a black hole?\n\r\n5. Darvan, the third friend Kirana visited, lives 10 Gintars from Axim.\n\r\n6. The house where Kirana got locked in the closet while snooping is twice as far from Axim as Nuju's house.\n\r\n7. Claymot is closer in distance to Axim than it is to Lisiter.\n\r\n8. The town of Worrik is twice as far from Axim as the town with the house where Kirana spilled Tango wine on the rug. The stains proved impossible to remove.\n\r\n9. The town where Kirana visited Breena is nearer to the town of Riigi than to Jargon.\n\r\n10. Traveling west-to-east, Kirana's first stop was at a friend's that lived 5 Gintars East of Axim and the last friend visited lived 5 Gintars West of Lisiter.\n\r\n11. The house where Kirana got locked in the closet isn't the one in the town of Worrik.\n\r\n12. The town where Darvan resides is situated 1 Gintar East of the town where Kirana walked in on her friend's mother taking a bath.\n\r\n13. The town of Riigi is located 18 Gintars East of Axim, and Nuju does not live in Riigi.\n\n\r\nFriends: Martina, Kylani, Breena, Darvan, and Nuju\r\nTowns: Worrik, Sarix, Jargon, Claymot and Riigi\r\nBlunders: Mistook art for garbage chute, walked in on mother bathing, spilled wine on carpet, broke vase, locked herself in closet", "hint": "Draw a map (line) from Axim to Lisiter and place the clues in their appropriate places as you solve the distances.\n\r\nNow for a hint:\n\r\nKirana broke the exquisite Kimingle Vase during one of her first 3 visits.\n\n\n\n\r\nNeed another hint?\n\n\n\n\r\n(Move down)\n\n\n\n\n\n\n\n\n\n\n\r\nKirana visited her friend Breena last before heading to the Lisiter Spaceport for her flight home.", "answer": "Answer:\t\r\nItinerary in order from West to East:\r\n(Distances are East of Axim)\r\n5 Gintars, Martina lives in Sarix where Kirana broke their exquisite Kimingle Vase.\r\n9 Gintars, Nuju lives in Jargon where Kirana mistakenly walked in on his mother bathing.\r\n10 Gintars, Darvan lives in Claymot and Kirana accidentally spilled Tango wine on his carpet.\r\n18 Gintars, Kylani lives in Riigi where she inadvertently locked herself in a closet while snooping around.\r\n20 Gintars, Breena lives in Worrik where Kirana tossed her used napkins in the family's lovely black hole art display.", "category": "Logic-Grid", "date": "12/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Kirana travels back to her home planet of Betelgeuse, she has many friends to visit and very little time so she plans a full itinerary. She visits 5 different friends who live in 5 different towns along a road 25 Gintars long (a unit of measure on Betelgeuse equal to roughly 1 mile). However, in her haste, she makes an embarrassing blunder at each home.\n\r\nCan you determine Kirana's exact itinerary, how far each friend lives from the spaceport of Axim and which blunder was made at which stop? The distances are measured in whole Gintars (no fractions).\n\r\n1. Kirana begins her trip in Axim and always travels East, never backtracking, until she reaches her final destination, the spaceport in Lisiter. The total distance between Axim and Lisiter is 25 Gintars.\n\r\n2. At the home in Sarix, Kirana was asked to leave after knocking over an expensive Kimingle Vase.\n\r\n3. The town of Claymot is twice as far from the Axim spaceport as the town where she stopped at her friend Martina's.\n\r\n4. The incident where Kirana mistook the family's art display for a trash receptacle did not occur during her visit to Kylani's home. Who would have known it was a replica of a black hole?\n\r\n5. Darvan, the third friend Kirana visited, lives 10 Gintars from Axim.\n\r\n6. The house where Kirana got locked in the closet while snooping is twice as far from Axim as Nuju's house.\n\r\n7. Claymot is closer in distance to Axim than it is to Lisiter.\n\r\n8. The town of Worrik is twice as far from Axim as the town with the house where Kirana spilled Tango wine on the rug. The stains proved impossible to remove.\n\r\n9. The town where Kirana visited Breena is nearer to the town of Riigi than to Jargon.\n\r\n10. Traveling west-to-east, Kirana's first stop was at a friend's that lived 5 Gintars East of Axim and the last friend visited lived 5 Gintars West of Lisiter.\n\r\n11. The house where Kirana got locked in the closet isn't the one in the town of Worrik.\n\r\n12. The town where Darvan resides is situated 1 Gintar East of the town where Kirana walked in on her friend's mother taking a bath.\n\r\n13. The town of Riigi is located 18 Gintars East of Axim, and Nuju does not live in Riigi.\n\n\r\nFriends: Martina, Kylani, Breena, Darvan, and Nuju\r\nTowns: Worrik, Sarix, Jargon, Claymot and Riigi\r\nBlunders: Mistook art for garbage chute, walked in on mother bathing, spilled wine on carpet, broke vase, locked herself in closet\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer:\t\r\nItinerary in order from West to East:\r\n(Distances are East of Axim)\r\n5 Gintars, Martina lives in Sarix where Kirana broke their exquisite Kimingle Vase.\r\n9 Gintars, Nuju lives in Jargon where Kirana mistakenly walked in on his mother bathing.\r\n10 Gintars, Darvan lives in Claymot and Kirana accidentally spilled Tango wine on his carpet.\r\n18 Gintars, Kylani lives in Riigi where she inadvertently locked herself in a closet while snooping around.\r\n20 Gintars, Breena lives in Worrik where Kirana tossed her used napkins in the family's lovely black hole art display.\n<|im_start|>answer\nAnswer:\t\r\nItinerary in order from West to East:\r\n(Distances are East of Axim)\r\n5 Gintars, Martina lives in Sarix where Kirana broke their exquisite Kimingle Vase.\r\n9 Gintars, Nuju lives in Jargon where Kirana mistakenly walked in on his mother bathing.\r\n10 Gintars, Darvan lives in Claymot and Kirana accidentally spilled Tango wine on his carpet.\r\n18 Gintars, Kylani lives in Riigi where she inadvertently locked herself in a closet while snooping around.\r\n20 Gintars, Breena lives in Worrik where Kirana tossed her used napkins in the family's lovely black hole art display.\n<|im_end|>" }, { "id": "#24328", "title": "Barbecue Roundup", "fun": 2.94, "difficulty": 1.29, "author": "phrebh", "desc": "Four people entered the cook-off at the Barbecue Roundup (Bob, Bubba, Cathy, and Fred). They all had different last names (Kent, Kahn, Miser, and Tin) and entered different foods (brisket, pork butt, ribs, and sausage). Using the clues provided determine who brought what and how they placed in the competition (1st, 2nd, 3rd, or 4th).\n\r\n1. The sausage did not come in last.\r\n2. Mr. Miser came in third and was beaten by Bob's ribs.\r\n3. The pork butt came in second.\r\n4. Cathy came in two places behind Fred Tin.\r\n5. Mr. Kent won.", "hint": "No hint available.", "answer": "Bob Kent came in 1st with his ribs.\r\nFred Tin came in 2nd with his pork butt.\r\nBubba Miser came in 3rd with his sausage.\r\nCathy Kahn came in 4th with her brisket.", "category": "Logic-Grid", "date": "07/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people entered the cook-off at the Barbecue Roundup (Bob, Bubba, Cathy, and Fred). They all had different last names (Kent, Kahn, Miser, and Tin) and entered different foods (brisket, pork butt, ribs, and sausage). Using the clues provided determine who brought what and how they placed in the competition (1st, 2nd, 3rd, or 4th).\n\r\n1. The sausage did not come in last.\r\n2. Mr. Miser came in third and was beaten by Bob's ribs.\r\n3. The pork butt came in second.\r\n4. Cathy came in two places behind Fred Tin.\r\n5. Mr. Kent won.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob Kent came in 1st with his ribs.\r\nFred Tin came in 2nd with his pork butt.\r\nBubba Miser came in 3rd with his sausage.\r\nCathy Kahn came in 4th with her brisket.\n<|im_start|>answer\nBob Kent came in 1st with his ribs.\r\nFred Tin came in 2nd with his pork butt.\r\nBubba Miser came in 3rd with his sausage.\r\nCathy Kahn came in 4th with her brisket.\n<|im_end|>" }, { "id": "#28766", "title": "The Random Family, Pt.2: Random Weddings!", "fun": 2.94, "difficulty": 1.94, "author": "TalkingOptimist", "desc": "Now that their last sibling has tied the knot, the Random Family has gotten together to reminisce about how all the couples met and how fun their weddings were. Can you figure out how each couple met, the last name of each spouse, and how many people were invited to each wedding?\n\r\n1.Dora could not believe it when she got the notice that they had surpassed capacity of 327 and had to find a new reception facility! But one of her brothers invited even more people to his wedding than she did!\r\n2. The couple that met on a blind date (which included neither Alex nor Ms. Myers), wanted a small wedding, but Mrs. Random talked them into inviting more people. However, they still had the smallest wedding of the four.\r\n3. The Random Family added the same names to the guest list for all 4 weddings. Because the Fleetwood family is smaller than the Hughey family, The Random-Hughey wedding, naturally, was larger than the Random-Fleetwood wedding.\r\n4. Nathan did not meet his wife, who is not named Myers or Burton, at college.\r\n5. Gabriel and his bride, who did not meet on a blind date or through mutual friends, wanted to invite the whole world, but settled for 500.\r\n6. Though they work together now, Ms. Burton and her husband did not meet at work; they met in a class they shared at Purdue University.\r\n7. The couple who met through mutual friends, invited those two friends, as well as 398 other people.\r\n8. Alex made sure to ask Mr. Burton for his daughter's hand before they set a wedding date, but Dora's fiance did not ask Mr. Random for his blessings.", "hint": "No hint available.", "answer": "Dora met Mr. Hughey through mutual friends. They invited 400 people to their wedding.\r\nAlex met Miss Burton at college. They invited 350 guests.\r\nNathan met Miss Fleetwood on a blind date. They invited 300 guests.\r\nGabriel met Miss Myers at work. They invited 500 people to their wedding.", "category": "Logic-Grid", "date": "02/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNow that their last sibling has tied the knot, the Random Family has gotten together to reminisce about how all the couples met and how fun their weddings were. Can you figure out how each couple met, the last name of each spouse, and how many people were invited to each wedding?\n\r\n1.Dora could not believe it when she got the notice that they had surpassed capacity of 327 and had to find a new reception facility! But one of her brothers invited even more people to his wedding than she did!\r\n2. The couple that met on a blind date (which included neither Alex nor Ms. Myers), wanted a small wedding, but Mrs. Random talked them into inviting more people. However, they still had the smallest wedding of the four.\r\n3. The Random Family added the same names to the guest list for all 4 weddings. Because the Fleetwood family is smaller than the Hughey family, The Random-Hughey wedding, naturally, was larger than the Random-Fleetwood wedding.\r\n4. Nathan did not meet his wife, who is not named Myers or Burton, at college.\r\n5. Gabriel and his bride, who did not meet on a blind date or through mutual friends, wanted to invite the whole world, but settled for 500.\r\n6. Though they work together now, Ms. Burton and her husband did not meet at work; they met in a class they shared at Purdue University.\r\n7. The couple who met through mutual friends, invited those two friends, as well as 398 other people.\r\n8. Alex made sure to ask Mr. Burton for his daughter's hand before they set a wedding date, but Dora's fiance did not ask Mr. Random for his blessings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDora met Mr. Hughey through mutual friends. They invited 400 people to their wedding.\r\nAlex met Miss Burton at college. They invited 350 guests.\r\nNathan met Miss Fleetwood on a blind date. They invited 300 guests.\r\nGabriel met Miss Myers at work. They invited 500 people to their wedding.\n<|im_start|>answer\nDora met Mr. Hughey through mutual friends. They invited 400 people to their wedding.\r\nAlex met Miss Burton at college. They invited 350 guests.\r\nNathan met Miss Fleetwood on a blind date. They invited 300 guests.\r\nGabriel met Miss Myers at work. They invited 500 people to their wedding.\n<|im_end|>" }, { "id": "#31303", "title": "Classmate Relationships", "fun": 2.94, "difficulty": 1.8900000000000001, "author": "dishu", "desc": "Some of the classmates of the 4 friends were trying to remember what each of the friend used to wear most in college days, which guy she was seeing at that time. They also began to wonder what each of the friend was doing these days and what ultimately happened to their relationships. All they had was the following information to figure out everything:\n\r\nFriends: Dis, Dip, Raj, Rich\r\nDress: capris, jeans, skirts, sarees\r\nGuys: Pras, As, Deep, Avi\r\nJob: software, homemaker, teacher, PR\r\nRelationship Status: married + kids, engaged, married, break-up\n\r\nInformation (Clues):\r\n1. Dis is the only one who is still looking for a suitable guy for marriage.\n\r\n2. The saree adorer, who was married and loved household work, decided to look after only the home.\n\r\n3. The mother decided to shift to a teaching job after birth of her child as that required lesser working hours.\n\r\n4. The jeans lover is tying the knot soon with Pras, whom she has been seeing since college.\n\r\n5. Rich is a software girl.\n\r\n6. Deep is dying to have kids but Raj is not so keen on the idea.\n\r\n7. Avi's wife loved to wear capris in college.", "hint": "For the sake of this puzzle assume that you stop looking for guys after engagement/marriage.", "answer": "Dis, skirts, As, break-up, PR\r\nDip, capris, Avi, married+kids, teacher\r\nRaj, sarees, Deep, married, homemaker\r\nRich, jeans, Pras, engaged, software", "category": "Logic-Grid", "date": "06/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome of the classmates of the 4 friends were trying to remember what each of the friend used to wear most in college days, which guy she was seeing at that time. They also began to wonder what each of the friend was doing these days and what ultimately happened to their relationships. All they had was the following information to figure out everything:\n\r\nFriends: Dis, Dip, Raj, Rich\r\nDress: capris, jeans, skirts, sarees\r\nGuys: Pras, As, Deep, Avi\r\nJob: software, homemaker, teacher, PR\r\nRelationship Status: married + kids, engaged, married, break-up\n\r\nInformation (Clues):\r\n1. Dis is the only one who is still looking for a suitable guy for marriage.\n\r\n2. The saree adorer, who was married and loved household work, decided to look after only the home.\n\r\n3. The mother decided to shift to a teaching job after birth of her child as that required lesser working hours.\n\r\n4. The jeans lover is tying the knot soon with Pras, whom she has been seeing since college.\n\r\n5. Rich is a software girl.\n\r\n6. Deep is dying to have kids but Raj is not so keen on the idea.\n\r\n7. Avi's wife loved to wear capris in college.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDis, skirts, As, break-up, PR\r\nDip, capris, Avi, married+kids, teacher\r\nRaj, sarees, Deep, married, homemaker\r\nRich, jeans, Pras, engaged, software\n<|im_start|>answer\nDis, skirts, As, break-up, PR\r\nDip, capris, Avi, married+kids, teacher\r\nRaj, sarees, Deep, married, homemaker\r\nRich, jeans, Pras, engaged, software\n<|im_end|>" }, { "id": "#29967", "title": "Bound For Canada", "fun": 2.94, "difficulty": 1.83, "author": "peppamintp", "desc": "Maple Leaf Air has a busy schedule today. Each of five nonstop flights, no two of which have the same number (222, 303, 444, 505, or 707), is departing at a different time from Hartford's Bradley International Airport. Each of five different people, including Roberta, is departing on a different one of the five flights, each of which is bound for a different Canadian city (including Halifax). From the information provided, determine the Canadian destination of each traveler, the departure time (10:00 am, 11:00 am, 12:00 pm, 1:00 pm, or 2:00 pm) of each flight, and the number of each flight.\n\r\n1. Flight 444 departs at some point before flight 303 (which is Louis' flight).\n\r\n2. Franz's flight, which is going to Montreal, does not leave at either 10:00 a.m. or 2:00 p.m.\n\r\n3. Flight 707 is destined for Quebec City. The flight to Vancouver (which isn't Heather's flight) leaves at precisely 11:00 a.m.\n\r\n4. Sylvester's flight leaves at some point before flight 222 (which isn't Franz's flight).\n\r\n5. Flight 505 is Maple Leaf Air's last one for the day. The flight to Toronto leaves at exactly 1:00 p.m.", "hint": "No hint available.", "answer": "Franz, Montreal, 12:00 pm, 444\r\nHeather, Halifax, 2:00 pm, 505\r\nLouis, Toronto, 1:00 pm, 303\r\nRoberta, Vancouver, 11:00 am, 222\r\nSylvester, Quebec, 10:00 am, 707", "category": "Logic-Grid", "date": "04/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMaple Leaf Air has a busy schedule today. Each of five nonstop flights, no two of which have the same number (222, 303, 444, 505, or 707), is departing at a different time from Hartford's Bradley International Airport. Each of five different people, including Roberta, is departing on a different one of the five flights, each of which is bound for a different Canadian city (including Halifax). From the information provided, determine the Canadian destination of each traveler, the departure time (10:00 am, 11:00 am, 12:00 pm, 1:00 pm, or 2:00 pm) of each flight, and the number of each flight.\n\r\n1. Flight 444 departs at some point before flight 303 (which is Louis' flight).\n\r\n2. Franz's flight, which is going to Montreal, does not leave at either 10:00 a.m. or 2:00 p.m.\n\r\n3. Flight 707 is destined for Quebec City. The flight to Vancouver (which isn't Heather's flight) leaves at precisely 11:00 a.m.\n\r\n4. Sylvester's flight leaves at some point before flight 222 (which isn't Franz's flight).\n\r\n5. Flight 505 is Maple Leaf Air's last one for the day. The flight to Toronto leaves at exactly 1:00 p.m.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFranz, Montreal, 12:00 pm, 444\r\nHeather, Halifax, 2:00 pm, 505\r\nLouis, Toronto, 1:00 pm, 303\r\nRoberta, Vancouver, 11:00 am, 222\r\nSylvester, Quebec, 10:00 am, 707\n<|im_start|>answer\nFranz, Montreal, 12:00 pm, 444\r\nHeather, Halifax, 2:00 pm, 505\r\nLouis, Toronto, 1:00 pm, 303\r\nRoberta, Vancouver, 11:00 am, 222\r\nSylvester, Quebec, 10:00 am, 707\n<|im_end|>" }, { "id": "#28649", "title": "Lost Property", "fun": 2.94, "difficulty": 2.58, "author": "xsagirl", "desc": "Ivor Scruluce often mislays things and last week was no exception. Luckily, however, various members of the public noticed that he'd left things behind and ran after him to give them back. What was left behind on each day, at which place and who returned his property to Ivor that very same day, before he'd realized it was missing?\n\r\n1. Pete left the train two stations earlier than he had intended, chasing Mr. Scruluce along the platform to return an item.\n\r\n2. Ivor left his wallet behind (not on the train) later in the week than he forgot to pick up his house keys, which had fallen from his pocket, but one day earlier in the week than the day on which he lost his watch (which also wasn't on the train).\n\r\n3. John is the taxi driver who noticed that Ivor had forgotten his briefcase. He returned it earlier in the week than the day on which Ivor lost his car keys.\n\r\n4. Lynda picked up something in the car park the day after Ivor's house keys were returned to him by Kenny.\n\r\n5. Something was left behind in the waiting room of the doctor's surgery on Tuesday.", "hint": "No hint available.", "answer": "John returned the briefcase left in a taxi (clue 3) and Kenny returned the house keys (clue 4). The item Pete found on the train (1) wasn't a wallet or watch (2), so car keys. Tuesday's item was left in the waiting room (5), so not by Lynda (4), thus Kenny's find wasn't on Monday. Monday's find wasn't the wallet or watch (2), or car keys (3), so the briefcase. Tuesday's wasn't the wallet or watch (2), so house keys and (4) Lynda's find in the car park was on Wednesday. This wasn't the watch (2), so the wallet. By elimination, Sandra found the watch on a bus. Sandra's find was on Thursday (2), so Pete's was on Friday.\n\r\nThus:\r\nMonday, briefcase, taxi, John\r\nTuesday, house keys, waiting room, Kenny\r\nWednesday, wallet, car park, Lynda\r\nThursday, watch, bus, Sandra\r\nFriday, car keys, train, Pete", "category": "Logic-Grid", "date": "02/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIvor Scruluce often mislays things and last week was no exception. Luckily, however, various members of the public noticed that he'd left things behind and ran after him to give them back. What was left behind on each day, at which place and who returned his property to Ivor that very same day, before he'd realized it was missing?\n\r\n1. Pete left the train two stations earlier than he had intended, chasing Mr. Scruluce along the platform to return an item.\n\r\n2. Ivor left his wallet behind (not on the train) later in the week than he forgot to pick up his house keys, which had fallen from his pocket, but one day earlier in the week than the day on which he lost his watch (which also wasn't on the train).\n\r\n3. John is the taxi driver who noticed that Ivor had forgotten his briefcase. He returned it earlier in the week than the day on which Ivor lost his car keys.\n\r\n4. Lynda picked up something in the car park the day after Ivor's house keys were returned to him by Kenny.\n\r\n5. Something was left behind in the waiting room of the doctor's surgery on Tuesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn returned the briefcase left in a taxi (clue 3) and Kenny returned the house keys (clue 4). The item Pete found on the train (1) wasn't a wallet or watch (2), so car keys. Tuesday's item was left in the waiting room (5), so not by Lynda (4), thus Kenny's find wasn't on Monday. Monday's find wasn't the wallet or watch (2), or car keys (3), so the briefcase. Tuesday's wasn't the wallet or watch (2), so house keys and (4) Lynda's find in the car park was on Wednesday. This wasn't the watch (2), so the wallet. By elimination, Sandra found the watch on a bus. Sandra's find was on Thursday (2), so Pete's was on Friday.\n\r\nThus:\r\nMonday, briefcase, taxi, John\r\nTuesday, house keys, waiting room, Kenny\r\nWednesday, wallet, car park, Lynda\r\nThursday, watch, bus, Sandra\r\nFriday, car keys, train, Pete\n<|im_start|>answer\nJohn returned the briefcase left in a taxi (clue 3) and Kenny returned the house keys (clue 4). The item Pete found on the train (1) wasn't a wallet or watch (2), so car keys. Tuesday's item was left in the waiting room (5), so not by Lynda (4), thus Kenny's find wasn't on Monday. Monday's find wasn't the wallet or watch (2), or car keys (3), so the briefcase. Tuesday's wasn't the wallet or watch (2), so house keys and (4) Lynda's find in the car park was on Wednesday. This wasn't the watch (2), so the wallet. By elimination, Sandra found the watch on a bus. Sandra's find was on Thursday (2), so Pete's was on Friday.\n\r\nThus:\r\nMonday, briefcase, taxi, John\r\nTuesday, house keys, waiting room, Kenny\r\nWednesday, wallet, car park, Lynda\r\nThursday, watch, bus, Sandra\r\nFriday, car keys, train, Pete\n<|im_end|>" }, { "id": "#26227", "title": "Seekers of Knowledge", "fun": 2.94, "difficulty": 1.59, "author": "Sunrose", "desc": "The small group of adventures became known throughout the town of Raptin. They received the title Seekers of Knowledge for the return of some of the old relics that most thought were lost. There was a celebration for the Seekers of Knowledge, acknowledging their bravery and honesty. \n\r\nDuring the celebration, the Mayor of Raptin gave out titles and a token of appreciation to the Seekers of Knowledge. The Seekers of Knowledge were pleased with the news and waited anxiously to hear the speech and receive their reward.\n\r\nThe small group consists of 5 members: Sid, Clover, Thad, Joel, and Dawn. \r\nTheir classes are: Bard, Scholar, Wizard, Clerk, and Warrior.\r\nThe rewards are: Endless Bag of Fruit, Magical set of Scalpels, Magical Spell Book, Magical 2-handed Sword, and Magical Amulet of Protection.\r\nTheir Titles are: The Justice Blade, Minstrel of Truth, Keeper of Knowledge, Mystic Seeker, and Saint of Kindness\n\r\n1) Thad didn't receive the Magical 2-handed Sword or Magical Amulet of Protection.\r\n2) The Bard received the Endless bag of Fruit and the title of Minstrel of Truth.\r\n3) Joel wasn't the clerk or scholar, and he received the title The Justice Blade.\r\n4) The scholar received the title of Keeper of Knowledge, and it wasn't Dawn or Clover.\r\n5) Clover is the Clerk, and she received the title Saint of Kindness.\r\n6) The Wizard received the Magical Spell Book, and the title Mystic Seeker.\r\n7) Sid wasn't the clerk, wizard or warrior.\r\n8) The scholar, who wasn't Thad or Joel, received the Magical Amulet of Protection.\r\n9) The Wizard and Clerk are female.\r\n10) Joel isn't the bard, and did not receive the scalpels.", "hint": "Dawn and Clover are females.\n\r\nJ. Blade = The Justice Blade\r\nM. Seekers = Mystic Seeker\r\nM. of Truth = Minstrel of Truth\r\nS. of Kindne = Saint of Kindness\r\nKeeper of K. = Keeper of Knowledge", "answer": "Thad - Bard - Endless Bag of Fruit - Minstrel of Truth\r\nClover - Clerk - Magical set of Scalpels - Saint of Kindness\r\nJoel - Warrior - Magical 2-handed Sword - The Justice Blade\r\nDawn - Wizard - Magical Spell Book - Mystic Seeker\r\nSid - Scholar - Magical Amulet of Protection - Keeper of Knowledge", "category": "Logic-Grid", "date": "10/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe small group of adventures became known throughout the town of Raptin. They received the title Seekers of Knowledge for the return of some of the old relics that most thought were lost. There was a celebration for the Seekers of Knowledge, acknowledging their bravery and honesty. \n\r\nDuring the celebration, the Mayor of Raptin gave out titles and a token of appreciation to the Seekers of Knowledge. The Seekers of Knowledge were pleased with the news and waited anxiously to hear the speech and receive their reward.\n\r\nThe small group consists of 5 members: Sid, Clover, Thad, Joel, and Dawn. \r\nTheir classes are: Bard, Scholar, Wizard, Clerk, and Warrior.\r\nThe rewards are: Endless Bag of Fruit, Magical set of Scalpels, Magical Spell Book, Magical 2-handed Sword, and Magical Amulet of Protection.\r\nTheir Titles are: The Justice Blade, Minstrel of Truth, Keeper of Knowledge, Mystic Seeker, and Saint of Kindness\n\r\n1) Thad didn't receive the Magical 2-handed Sword or Magical Amulet of Protection.\r\n2) The Bard received the Endless bag of Fruit and the title of Minstrel of Truth.\r\n3) Joel wasn't the clerk or scholar, and he received the title The Justice Blade.\r\n4) The scholar received the title of Keeper of Knowledge, and it wasn't Dawn or Clover.\r\n5) Clover is the Clerk, and she received the title Saint of Kindness.\r\n6) The Wizard received the Magical Spell Book, and the title Mystic Seeker.\r\n7) Sid wasn't the clerk, wizard or warrior.\r\n8) The scholar, who wasn't Thad or Joel, received the Magical Amulet of Protection.\r\n9) The Wizard and Clerk are female.\r\n10) Joel isn't the bard, and did not receive the scalpels.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThad - Bard - Endless Bag of Fruit - Minstrel of Truth\r\nClover - Clerk - Magical set of Scalpels - Saint of Kindness\r\nJoel - Warrior - Magical 2-handed Sword - The Justice Blade\r\nDawn - Wizard - Magical Spell Book - Mystic Seeker\r\nSid - Scholar - Magical Amulet of Protection - Keeper of Knowledge\n<|im_start|>answer\nThad - Bard - Endless Bag of Fruit - Minstrel of Truth\r\nClover - Clerk - Magical set of Scalpels - Saint of Kindness\r\nJoel - Warrior - Magical 2-handed Sword - The Justice Blade\r\nDawn - Wizard - Magical Spell Book - Mystic Seeker\r\nSid - Scholar - Magical Amulet of Protection - Keeper of Knowledge\n<|im_end|>" }, { "id": "#42762", "title": "Zoo Animal Olympics", "fun": 2.93, "difficulty": 2.68, "author": "joseph_r03", "desc": "The zebra, monkey, giraffe, elephant, and lion were all competing in the Zoo Animal Olympics. Each competed in a different event: basketball, wrestling, 110 meter hurdles, long jump, and weightlifting. Each animal wore a different color jersey: red, green, blue, orange, and yellow. All of the animals finished in the top 5 of their respective event, but none of them finished in the same place. Also note that these animals have strengths besides being good athletes. There is a mathematician, a trivia buff, a cryptographer, a scientist, and one animal that has a great ability to recognize groups with common attributes. Can you determine which animal goes with the associated Olympic event, jersey color, finishing place, and secondary skill?\n\r\n1) The animal in the blue jersey finished in a better place than the animal in the yellow jersey.\n\r\n2) The lion is a trivia buff.\n\r\n3) The animal that competed in the 110 meter hurdles finished in a better place than the animal that competed in wrestling.\n\r\n4) The cryptographer left the following message: \"J BN B NPOLFZ.\"\n\r\n5) The zebra, elephant, and lion each have a primary colored jersey.\n\r\n6) Here is another message from one of the animals: \"I have something in common with the following animals: skunk, tiger, clown fish, bumblebee, and coral snake.\"\n\r\n7) The zebra finished in a better place than the lion, but a worse place than the elephant.\n\r\n8) The zebra and lion's jersey colors, when mixed, make the color of the jersey the monkey wears.\n\r\n9) The animal that came in 4th place was playing basketball.\n\r\n10) The scientist had the following message: \"There is an alkaline earth metal whose atomic number is the same as my finishing place.\"\n\r\n11) The animal participating in the long jump finished in a lower place than the giraffe.\n\r\n12) The giraffe did not wear the green jersey.\n\r\n13) The trivia buff had the following message: Thomas Jefferson was the same number U.S. President as my finishing place.\n\r\n14) The mathematician's Olympic event has the same number of letters as the result of this equation: (5+2)*3-8 = ?", "hint": "4) This is the message with the first three words decoded: I am a NPOLFZ.\n\r\n6) Think appearance.", "answer": "The zebra was in the 110 meter hurdles, wore the blue jersey, finished in 2nd place, and has a great ability to recognize groups of common attributes.\n\r\nThe monkey was in the long jump, wore the green jersey, finishied in 5th place, and is the Cryptographer.\n\r\nThe giraffe was in the basketball game, wore the orange jersey, finished in 4th place, and was the scientist.\n\r\nThe elephant was in the weightlifting competition, wore the red jersey, finished in 1st place, and was the mathematician.\n\r\nThe lion was in wrestling, wore the yellow jersey, finished in 3rd place, and was the trivia buff.\n\r\nExplanation of clues:\n\r\n4) If you replace each letter with one that is exactly one spot to the right in the alphabet you get \"I am a monkey\". This is a Caesar Cipher.\n\r\n6) A zebra has stripes just like the most commonly observed skunk, tiger, clown fish, bumblebee, and coral snake.\n\r\n10) Beryllium is the only alkaline earth metal in the first five elements on the periodic table. Its atomic number is 4.\n\r\n13) Thomas Jefferson was the third president of the United States.\n\r\n14) The answer is 13. And weightlifting is the only event with 13 letters. To solve the equation you use the standard order of operations which states you solve for parentheses and exponents first, then multiplication and division, and lastly addition and subtraction.\r\n(5+2)*3-8 = ?\r\n(7)*3-8 = ?\r\n21-8=?\r\n13", "category": "Logic-Grid", "date": "08/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe zebra, monkey, giraffe, elephant, and lion were all competing in the Zoo Animal Olympics. Each competed in a different event: basketball, wrestling, 110 meter hurdles, long jump, and weightlifting. Each animal wore a different color jersey: red, green, blue, orange, and yellow. All of the animals finished in the top 5 of their respective event, but none of them finished in the same place. Also note that these animals have strengths besides being good athletes. There is a mathematician, a trivia buff, a cryptographer, a scientist, and one animal that has a great ability to recognize groups with common attributes. Can you determine which animal goes with the associated Olympic event, jersey color, finishing place, and secondary skill?\n\r\n1) The animal in the blue jersey finished in a better place than the animal in the yellow jersey.\n\r\n2) The lion is a trivia buff.\n\r\n3) The animal that competed in the 110 meter hurdles finished in a better place than the animal that competed in wrestling.\n\r\n4) The cryptographer left the following message: \"J BN B NPOLFZ.\"\n\r\n5) The zebra, elephant, and lion each have a primary colored jersey.\n\r\n6) Here is another message from one of the animals: \"I have something in common with the following animals: skunk, tiger, clown fish, bumblebee, and coral snake.\"\n\r\n7) The zebra finished in a better place than the lion, but a worse place than the elephant.\n\r\n8) The zebra and lion's jersey colors, when mixed, make the color of the jersey the monkey wears.\n\r\n9) The animal that came in 4th place was playing basketball.\n\r\n10) The scientist had the following message: \"There is an alkaline earth metal whose atomic number is the same as my finishing place.\"\n\r\n11) The animal participating in the long jump finished in a lower place than the giraffe.\n\r\n12) The giraffe did not wear the green jersey.\n\r\n13) The trivia buff had the following message: Thomas Jefferson was the same number U.S. President as my finishing place.\n\r\n14) The mathematician's Olympic event has the same number of letters as the result of this equation: (5+2)*3-8 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe zebra was in the 110 meter hurdles, wore the blue jersey, finished in 2nd place, and has a great ability to recognize groups of common attributes.\n\r\nThe monkey was in the long jump, wore the green jersey, finishied in 5th place, and is the Cryptographer.\n\r\nThe giraffe was in the basketball game, wore the orange jersey, finished in 4th place, and was the scientist.\n\r\nThe elephant was in the weightlifting competition, wore the red jersey, finished in 1st place, and was the mathematician.\n\r\nThe lion was in wrestling, wore the yellow jersey, finished in 3rd place, and was the trivia buff.\n\r\nExplanation of clues:\n\r\n4) If you replace each letter with one that is exactly one spot to the right in the alphabet you get \"I am a monkey\". This is a Caesar Cipher.\n\r\n6) A zebra has stripes just like the most commonly observed skunk, tiger, clown fish, bumblebee, and coral snake.\n\r\n10) Beryllium is the only alkaline earth metal in the first five elements on the periodic table. Its atomic number is 4.\n\r\n13) Thomas Jefferson was the third president of the United States.\n\r\n14) The answer is 13. And weightlifting is the only event with 13 letters. To solve the equation you use the standard order of operations which states you solve for parentheses and exponents first, then multiplication and division, and lastly addition and subtraction.\r\n(5+2)*3-8 = ?\r\n(7)*3-8 = ?\r\n21-8=?\r\n13\n<|im_start|>answer\nThe zebra was in the 110 meter hurdles, wore the blue jersey, finished in 2nd place, and has a great ability to recognize groups of common attributes.\n\r\nThe monkey was in the long jump, wore the green jersey, finishied in 5th place, and is the Cryptographer.\n\r\nThe giraffe was in the basketball game, wore the orange jersey, finished in 4th place, and was the scientist.\n\r\nThe elephant was in the weightlifting competition, wore the red jersey, finished in 1st place, and was the mathematician.\n\r\nThe lion was in wrestling, wore the yellow jersey, finished in 3rd place, and was the trivia buff.\n\r\nExplanation of clues:\n\r\n4) If you replace each letter with one that is exactly one spot to the right in the alphabet you get \"I am a monkey\". This is a Caesar Cipher.\n\r\n6) A zebra has stripes just like the most commonly observed skunk, tiger, clown fish, bumblebee, and coral snake.\n\r\n10) Beryllium is the only alkaline earth metal in the first five elements on the periodic table. Its atomic number is 4.\n\r\n13) Thomas Jefferson was the third president of the United States.\n\r\n14) The answer is 13. And weightlifting is the only event with 13 letters. To solve the equation you use the standard order of operations which states you solve for parentheses and exponents first, then multiplication and division, and lastly addition and subtraction.\r\n(5+2)*3-8 = ?\r\n(7)*3-8 = ?\r\n21-8=?\r\n13\n<|im_end|>" }, { "id": "#31458", "title": "Birbal the Wise - XII", "fun": 2.93, "difficulty": 1.17, "author": "brainster", "desc": "Emperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\r\nBirbal had been invited to lunch by a rich man. Birbal went to the man's house and found that the lunch was in fact a big party and there were many people around.\n\r\nHis host greeted him warmly.\n\r\n\"I did not know there would be so many guests,\" said Birbal, who hated large gatherings.\n\r\n\"They are not guests,\" said the man, \"They are my employees, all except one man. He is the only other guest here beside you.\"\n\r\nThen the host saw the perfect opportunity to test Birbal's wit and wisdom. \"Can you tell me which of them is the guest?\" he asked.\n\r\n\"Maybe I could. I will definitely give it a try,\" said Birbal. \"Talk to them as I observe them. And tell them a joke.\"\n\r\nThe man told a joke that Birbal thought was perhaps the worst he had heard in a long time. \n\r\nBy the time the host finished telling the joke, Birbal knew who the guest was.\n\r\n\"Well,\" said the rich man. \"I've told my joke. Now tell me who my other guest is.\"\n\r\nBirbal pointed out the man to him.\n\r\n\"How did you know?\" asked his host, amazed.\n\r\nWhat was Birbal's reply?", "hint": "No hint available.", "answer": "Birbal said to the host, \"Employees tend to laugh at any joke told by their employers out of loyalty and respect to the employer,\" explained Birbal. \n\r\n\"When I saw that this man was the only one not laughing at your joke, and in fact, looked positively bored, I at once knew he was your other guest.\"\n\r\nThe host was amazed at Birbal's perception skills and was happy to have invited him to lunch and get a glimpse of Birbal's wit and wisdom.", "category": "Logic", "date": "07/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEmperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\r\nBirbal had been invited to lunch by a rich man. Birbal went to the man's house and found that the lunch was in fact a big party and there were many people around.\n\r\nHis host greeted him warmly.\n\r\n\"I did not know there would be so many guests,\" said Birbal, who hated large gatherings.\n\r\n\"They are not guests,\" said the man, \"They are my employees, all except one man. He is the only other guest here beside you.\"\n\r\nThen the host saw the perfect opportunity to test Birbal's wit and wisdom. \"Can you tell me which of them is the guest?\" he asked.\n\r\n\"Maybe I could. I will definitely give it a try,\" said Birbal. \"Talk to them as I observe them. And tell them a joke.\"\n\r\nThe man told a joke that Birbal thought was perhaps the worst he had heard in a long time. \n\r\nBy the time the host finished telling the joke, Birbal knew who the guest was.\n\r\n\"Well,\" said the rich man. \"I've told my joke. Now tell me who my other guest is.\"\n\r\nBirbal pointed out the man to him.\n\r\n\"How did you know?\" asked his host, amazed.\n\r\nWhat was Birbal's reply?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBirbal said to the host, \"Employees tend to laugh at any joke told by their employers out of loyalty and respect to the employer,\" explained Birbal. \n\r\n\"When I saw that this man was the only one not laughing at your joke, and in fact, looked positively bored, I at once knew he was your other guest.\"\n\r\nThe host was amazed at Birbal's perception skills and was happy to have invited him to lunch and get a glimpse of Birbal's wit and wisdom.\n<|im_start|>answer\nBirbal said to the host, \"Employees tend to laugh at any joke told by their employers out of loyalty and respect to the employer,\" explained Birbal. \n\r\n\"When I saw that this man was the only one not laughing at your joke, and in fact, looked positively bored, I at once knew he was your other guest.\"\n\r\nThe host was amazed at Birbal's perception skills and was happy to have invited him to lunch and get a glimpse of Birbal's wit and wisdom.\n<|im_end|>" }, { "id": "#30470", "title": "Birbal the Wise - IV", "fun": 2.93, "difficulty": 0.65, "author": "brainster", "desc": "Emperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\r\nThere was once a blacksmith who used to make spears and shields. He came to Emperor Akbar's court and claimed - \"Your Majesty, nobody can make shields and spears like mine. My shields are so strong that nothing can pierce them and my spears are so sharp that there is nothing they cannot pierce.\"\n\r\nOn hearing this statement, Birbal immediately said, \"You lie and I can prove that you are lying.\" What did he find wrong with the man's statement?", "hint": "No hint available.", "answer": "Birbal told the man - \"I can prove you wrong. Let's do a simple test.\"\n\r\nThe man, supremely confident, agreed.\n\r\nBirbal said smilingly - \"OK, hold up one of your shields and I will pierce it with one of your spears.\" \n\r\nThe man realized he had been outwitted because both his statements could never be true at the same time. Only one of his statements would hold true under any situation. Shamed to silence, he quietly left the court.", "category": "Logic", "date": "05/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEmperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\r\nThere was once a blacksmith who used to make spears and shields. He came to Emperor Akbar's court and claimed - \"Your Majesty, nobody can make shields and spears like mine. My shields are so strong that nothing can pierce them and my spears are so sharp that there is nothing they cannot pierce.\"\n\r\nOn hearing this statement, Birbal immediately said, \"You lie and I can prove that you are lying.\" What did he find wrong with the man's statement?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBirbal told the man - \"I can prove you wrong. Let's do a simple test.\"\n\r\nThe man, supremely confident, agreed.\n\r\nBirbal said smilingly - \"OK, hold up one of your shields and I will pierce it with one of your spears.\" \n\r\nThe man realized he had been outwitted because both his statements could never be true at the same time. Only one of his statements would hold true under any situation. Shamed to silence, he quietly left the court.\n<|im_start|>answer\nBirbal told the man - \"I can prove you wrong. Let's do a simple test.\"\n\r\nThe man, supremely confident, agreed.\n\r\nBirbal said smilingly - \"OK, hold up one of your shields and I will pierce it with one of your spears.\" \n\r\nThe man realized he had been outwitted because both his statements could never be true at the same time. Only one of his statements would hold true under any situation. Shamed to silence, he quietly left the court.\n<|im_end|>" }, { "id": "#3814", "title": "Stormy Night", "fun": 2.93, "difficulty": 1.7, "author": "arij", "desc": "You are driving a car on one big stormy night. You pass a bus station. There are three people who are waiting for the bus: One old sick lady who is dying, One doctor who saved your life before, and one lady who is someone you have been dreaming to be with.\n\r\nYou can only take one passenger, which one will you choose?", "hint": "No hint available.", "answer": "Give the car key to the doctor, let the doctor take the old lady to the hospital and stay to wait for the bus with the lady of your dream!", "category": "Logic", "date": "04/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are driving a car on one big stormy night. You pass a bus station. There are three people who are waiting for the bus: One old sick lady who is dying, One doctor who saved your life before, and one lady who is someone you have been dreaming to be with.\n\r\nYou can only take one passenger, which one will you choose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGive the car key to the doctor, let the doctor take the old lady to the hospital and stay to wait for the bus with the lady of your dream!\n<|im_start|>answer\nGive the car key to the doctor, let the doctor take the old lady to the hospital and stay to wait for the bus with the lady of your dream!\n<|im_end|>" }, { "id": "#19924", "title": "Five Friends", "fun": 2.93, "difficulty": 2.2, "author": "Shirl", "desc": "Five friends are all pilots: Mr. Johnson, Mr. Bruckner, Dr. Thompson, Mr. Landis, and Lord Christopher. Each pilot has one daughter but named his plane after a friend's daughter. Mr. Landis's plane is the Carla Jean; Dr. Thompson's, the Rene. Elizabeth Johnson's father owns the Lindsey Kay. Mr. Bruckner owns the Mary Lynn, which is named after Mr. Landis's daughter. Carla's father used Lord Christopher's daughter's name for his plane. Who is Lindsey Kay's father?", "hint": "No hint available.", "answer": "Mr. Bruckner\r\nLindsey Kay- Mr. Bruckner's daughter\r\nElizabeth -Mr. Johnson's daughter\r\nCarla Jean- Mr.Thompson's daughter\r\nMary Lynne- Mr. Landis's daughter\r\nRene- Lord Christopher's daughter", "category": "Logic", "date": "12/15/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends are all pilots: Mr. Johnson, Mr. Bruckner, Dr. Thompson, Mr. Landis, and Lord Christopher. Each pilot has one daughter but named his plane after a friend's daughter. Mr. Landis's plane is the Carla Jean; Dr. Thompson's, the Rene. Elizabeth Johnson's father owns the Lindsey Kay. Mr. Bruckner owns the Mary Lynn, which is named after Mr. Landis's daughter. Carla's father used Lord Christopher's daughter's name for his plane. Who is Lindsey Kay's father?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Bruckner\r\nLindsey Kay- Mr. Bruckner's daughter\r\nElizabeth -Mr. Johnson's daughter\r\nCarla Jean- Mr.Thompson's daughter\r\nMary Lynne- Mr. Landis's daughter\r\nRene- Lord Christopher's daughter\n<|im_start|>answer\nMr. Bruckner\r\nLindsey Kay- Mr. Bruckner's daughter\r\nElizabeth -Mr. Johnson's daughter\r\nCarla Jean- Mr.Thompson's daughter\r\nMary Lynne- Mr. Landis's daughter\r\nRene- Lord Christopher's daughter\n<|im_end|>" }, { "id": "#34603", "title": "The Comic Book Club", "fun": 2.93, "difficulty": 2.01, "author": "thompson1", "desc": "The \"Comic Book Club\" was having it's monthly meeting in Adam's treehouse. Adam, who was the head of the club, decided to make a master list of each member's first name, last name, favorite comic book, and how many they each have. Each member wrote down their information so Adam could make the list later at his house. After the meeting adjourned, he put the lists down on the kitchen counter because his dad was taking him out to get some ice cream! When he got home (with some very sticky fingers) he saw shreds on the floor! Luckily, he remembers some information from the papers. Can you help him make the master list using the information he remembers?\n\r\nFirst Names: Thomas, Colin, James, Adam, and Mark\r\nLast Names: Campbell, Johnson, Arnold, Taylor, and Mitchell\r\n# of Comics: 2, 5, 6, 7, and 9\r\nFavorite Comics: Spiderman, Superman, Batman, the Hulk, and Captain America\n\n\r\n1. The five boys are Thomas, the one surnamed Arnold, the one who likes the Hulk, the one who has 6 comics, and Mark.\n\r\n2. Exactly two boys have the same first and last initial.\n\r\n3. The head of the club has the most comics.\n\r\n4. The boy that likes Captain America has either 6 or 7 comics, but the boy that likes Batman has either 5 or 6.\n\r\n5. James is either Johnson or likes Superman.\n\r\n6. Mark has either the second-least or the least amount of comics, while Mitchell either has 6 or 9.\n\r\n7. Adam's best friend, Thomas, has the last name of Johnson.", "hint": "No hint available.", "answer": "Thomas Johnson has 7 Captain America comics.\r\nColin Campbell has 2 Hulk comics.\r\nJames Mitchell has 6 Superman comics.\r\nAdam Arnold has 9 Spiderman comics.\r\nMark Taylor has 5 Batman comics.\n\r\nAdam was able to finish the master list (and wash his hands) in time for the next meeting!", "category": "Logic-Grid", "date": "12/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe \"Comic Book Club\" was having it's monthly meeting in Adam's treehouse. Adam, who was the head of the club, decided to make a master list of each member's first name, last name, favorite comic book, and how many they each have. Each member wrote down their information so Adam could make the list later at his house. After the meeting adjourned, he put the lists down on the kitchen counter because his dad was taking him out to get some ice cream! When he got home (with some very sticky fingers) he saw shreds on the floor! Luckily, he remembers some information from the papers. Can you help him make the master list using the information he remembers?\n\r\nFirst Names: Thomas, Colin, James, Adam, and Mark\r\nLast Names: Campbell, Johnson, Arnold, Taylor, and Mitchell\r\n# of Comics: 2, 5, 6, 7, and 9\r\nFavorite Comics: Spiderman, Superman, Batman, the Hulk, and Captain America\n\n\r\n1. The five boys are Thomas, the one surnamed Arnold, the one who likes the Hulk, the one who has 6 comics, and Mark.\n\r\n2. Exactly two boys have the same first and last initial.\n\r\n3. The head of the club has the most comics.\n\r\n4. The boy that likes Captain America has either 6 or 7 comics, but the boy that likes Batman has either 5 or 6.\n\r\n5. James is either Johnson or likes Superman.\n\r\n6. Mark has either the second-least or the least amount of comics, while Mitchell either has 6 or 9.\n\r\n7. Adam's best friend, Thomas, has the last name of Johnson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThomas Johnson has 7 Captain America comics.\r\nColin Campbell has 2 Hulk comics.\r\nJames Mitchell has 6 Superman comics.\r\nAdam Arnold has 9 Spiderman comics.\r\nMark Taylor has 5 Batman comics.\n\r\nAdam was able to finish the master list (and wash his hands) in time for the next meeting!\n<|im_start|>answer\nThomas Johnson has 7 Captain America comics.\r\nColin Campbell has 2 Hulk comics.\r\nJames Mitchell has 6 Superman comics.\r\nAdam Arnold has 9 Spiderman comics.\r\nMark Taylor has 5 Batman comics.\n\r\nAdam was able to finish the master list (and wash his hands) in time for the next meeting!\n<|im_end|>" }, { "id": "#20074", "title": "Bat Attack", "fun": 2.93, "difficulty": 3.15, "author": "lorial", "desc": "Vampire bats have been attacking a different person in the village of Batsrus on different days of the week and they all managed to succeed in sucking a little blood from their victim. The victim fought off the attacking bat by using any weapon to hand. \n\r\nCan you determine the amount of blood sucked from which person, on what day and what they defended themselves with?\t\t\t\t\t\t\t\t\t\t\t\t\t\n\r\n1) Miss Fitch had 4ml of blood sucked from her neck before managing to fight the bat off, but not with her Handbag or Fist and this wasn't on a Saturday.\t\n\r\n2) The bat that was fought off with a Walking Stick managed to suck 1.5ml more than the bat that attacked 2 days before the victim that used a Slipper to defend themselves, which was not Mr. Sachs.\t\n\r\n3) Mr. Sachs had more blood sucked from him than the Saturday victim.\n\r\n4) A bat was hit with a Fist 2 days after a bat was hit with a Handbag.\n\r\n5) The victim that had 7ml of blood sucked was attacked the day before the victim having the least amount of blood sucked, which was not on a Wednesday.\n\r\n6) Monday's bat attack was on Mrs Melbury who didn't fight the bat off with a Slipper.\n\r\n7) Ms Trews did not use an Umbrella as her weapon.\t\n\r\nVictim:\t Miss Fitch / Mrs Melbury / Mr. Sachs / Ms Trews / Mr Twiddle\r\nDay: Monday, Tuesday, Wednesday, Friday, Saturday\r\nWeapon:\tHandbag, Fist, Walking Stick, Umbrella, Slipper\r\nBlood Sucked: 1ml, 2.5ml, 4ml, 6ml, 7ml", "hint": "No hint available.", "answer": "Answer:\n\r\nVictim / Day / Weapon / Blood Sucked\n\r\nMiss Fitch / Tuesday / Walking Stick / 4ml\r\nMrs Melbury / Monday / Handbag / 6ml\r\nMr. Sachs / Wednesday / Fist / 2.5ml\r\nMs Trews / Friday / Slipper / 7ml\r\nMr. Twiddle / Saturday / Umbrella / 1ml", "category": "Logic-Grid", "date": "01/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nVampire bats have been attacking a different person in the village of Batsrus on different days of the week and they all managed to succeed in sucking a little blood from their victim. The victim fought off the attacking bat by using any weapon to hand. \n\r\nCan you determine the amount of blood sucked from which person, on what day and what they defended themselves with?\t\t\t\t\t\t\t\t\t\t\t\t\t\n\r\n1) Miss Fitch had 4ml of blood sucked from her neck before managing to fight the bat off, but not with her Handbag or Fist and this wasn't on a Saturday.\t\n\r\n2) The bat that was fought off with a Walking Stick managed to suck 1.5ml more than the bat that attacked 2 days before the victim that used a Slipper to defend themselves, which was not Mr. Sachs.\t\n\r\n3) Mr. Sachs had more blood sucked from him than the Saturday victim.\n\r\n4) A bat was hit with a Fist 2 days after a bat was hit with a Handbag.\n\r\n5) The victim that had 7ml of blood sucked was attacked the day before the victim having the least amount of blood sucked, which was not on a Wednesday.\n\r\n6) Monday's bat attack was on Mrs Melbury who didn't fight the bat off with a Slipper.\n\r\n7) Ms Trews did not use an Umbrella as her weapon.\t\n\r\nVictim:\t Miss Fitch / Mrs Melbury / Mr. Sachs / Ms Trews / Mr Twiddle\r\nDay: Monday, Tuesday, Wednesday, Friday, Saturday\r\nWeapon:\tHandbag, Fist, Walking Stick, Umbrella, Slipper\r\nBlood Sucked: 1ml, 2.5ml, 4ml, 6ml, 7ml\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer:\n\r\nVictim / Day / Weapon / Blood Sucked\n\r\nMiss Fitch / Tuesday / Walking Stick / 4ml\r\nMrs Melbury / Monday / Handbag / 6ml\r\nMr. Sachs / Wednesday / Fist / 2.5ml\r\nMs Trews / Friday / Slipper / 7ml\r\nMr. Twiddle / Saturday / Umbrella / 1ml\n<|im_start|>answer\nAnswer:\n\r\nVictim / Day / Weapon / Blood Sucked\n\r\nMiss Fitch / Tuesday / Walking Stick / 4ml\r\nMrs Melbury / Monday / Handbag / 6ml\r\nMr. Sachs / Wednesday / Fist / 2.5ml\r\nMs Trews / Friday / Slipper / 7ml\r\nMr. Twiddle / Saturday / Umbrella / 1ml\n<|im_end|>" }, { "id": "#21101", "title": "A Giant Puzzle (Part 1)", "fun": 2.93, "difficulty": 2.17, "author": "cdrock", "desc": "I climbed an unusual beanstalk to another world where I found a gigantic house. I went inside the house and I was picked up by the biggest thing I have ever seen. He threw me inside a messy room and told me that if I could clean it by the time he gets back, he would let me go, but if I didn't I would have to clean his house for the rest of eternity. He told me to put all the different things in separate boxes in a certain order and then the boxes in a certain order. He will leave me with a list of clues so I can get them in order. \r\n\tFirst I will sort through the shoes and put them in order. \r\n\tThere are red, blue, green, yellow, brown, orange, and purple pairs of shoes, not necessarily in that order.\n\r\n1. The brown shoes are 4 pairs of shoes away from the purple pair. (3 pairs in between)\n\r\n2. The blue pair isn't next to the orange pair.\n\r\n3. The distance from the green pair to the blue pair isn't the same distance as the distance from the yellow pair to the orange pair.\n\r\n4. The red pair is next to the brown pair.\n\r\n5. Either the blue or orange pair is between the green and yellow pairs.\n\r\n6. The yellow pair is next to the purple pair.\n\r\n7. The red pair is the first pair on the left.\n\r\n8. The orange pair isn't next to one of the colors with a second letter of \"r\"", "hint": "No hint available.", "answer": "Red, Brown, Green, Blue, Yellow, Purple, Orange", "category": "Logic", "date": "02/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI climbed an unusual beanstalk to another world where I found a gigantic house. I went inside the house and I was picked up by the biggest thing I have ever seen. He threw me inside a messy room and told me that if I could clean it by the time he gets back, he would let me go, but if I didn't I would have to clean his house for the rest of eternity. He told me to put all the different things in separate boxes in a certain order and then the boxes in a certain order. He will leave me with a list of clues so I can get them in order. \r\n\tFirst I will sort through the shoes and put them in order. \r\n\tThere are red, blue, green, yellow, brown, orange, and purple pairs of shoes, not necessarily in that order.\n\r\n1. The brown shoes are 4 pairs of shoes away from the purple pair. (3 pairs in between)\n\r\n2. The blue pair isn't next to the orange pair.\n\r\n3. The distance from the green pair to the blue pair isn't the same distance as the distance from the yellow pair to the orange pair.\n\r\n4. The red pair is next to the brown pair.\n\r\n5. Either the blue or orange pair is between the green and yellow pairs.\n\r\n6. The yellow pair is next to the purple pair.\n\r\n7. The red pair is the first pair on the left.\n\r\n8. The orange pair isn't next to one of the colors with a second letter of \"r\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRed, Brown, Green, Blue, Yellow, Purple, Orange\n<|im_start|>answer\nRed, Brown, Green, Blue, Yellow, Purple, Orange\n<|im_end|>" }, { "id": "#23384", "title": "Snow White", "fun": 2.93, "difficulty": 2.34, "author": "katey", "desc": "Recently, Snow White's seven dwarfs met up with three of their friends and went to the cinema to see Bambi. From the clues below, can you determine the order in which they stood in the ticket queue? \n\r\nGrumpy was in front of Dopey. Stumpy was behind Sneezy and Doc. Doc was in front of Droopy and Happy. \r\nSleepy was behind Stumpy, Smelly and Happy. \r\nHappy was in front of Sleepy, Smelly and Bashful. \r\nBashful was behind Smelly, Droopy and Sleepy.\r\nSneezy was in front of Dopey. Smelly was in front of Grumpy, Stumpy and Sneezy. \r\nDopey was in front of Droopy. \r\nSleepy was in front of Grumpy and Bashful. \r\nDopey was behind Sneezy, Doc and Sleepy. \r\nStumpy was in front of Dopey. Smelly was behind Doc.", "hint": "No hint available.", "answer": "Doc\r\n Happy\r\n Smelly\r\n Sneezy\r\n Stumpy\r\n Sleepy\r\n Grumpy\r\n Dopey\r\n Droopy\r\n Bashful", "category": "Logic", "date": "06/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRecently, Snow White's seven dwarfs met up with three of their friends and went to the cinema to see Bambi. From the clues below, can you determine the order in which they stood in the ticket queue? \n\r\nGrumpy was in front of Dopey. Stumpy was behind Sneezy and Doc. Doc was in front of Droopy and Happy. \r\nSleepy was behind Stumpy, Smelly and Happy. \r\nHappy was in front of Sleepy, Smelly and Bashful. \r\nBashful was behind Smelly, Droopy and Sleepy.\r\nSneezy was in front of Dopey. Smelly was in front of Grumpy, Stumpy and Sneezy. \r\nDopey was in front of Droopy. \r\nSleepy was in front of Grumpy and Bashful. \r\nDopey was behind Sneezy, Doc and Sleepy. \r\nStumpy was in front of Dopey. Smelly was behind Doc.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDoc\r\n Happy\r\n Smelly\r\n Sneezy\r\n Stumpy\r\n Sleepy\r\n Grumpy\r\n Dopey\r\n Droopy\r\n Bashful\n<|im_start|>answer\nDoc\r\n Happy\r\n Smelly\r\n Sneezy\r\n Stumpy\r\n Sleepy\r\n Grumpy\r\n Dopey\r\n Droopy\r\n Bashful\n<|im_end|>" }, { "id": "#5160", "title": "Half Truthful", "fun": 2.92, "difficulty": 2.83, "author": "bobbrt", "desc": "Three Paley brothers and three Thomson brothers operate a company that manufactures lie detectors. Three of these six men always tell the truth, and three always tell lies; neither set of brothers consists exclusively of liars. Some recent statements from the six men are recorded below. Can you find the six men's full names, and tell which men tell the truth and which tell lies?\n\r\n1. Alan: \"Both my brothers tell lies.\"\r\n2. Boris: \"Both my brothers tell the truth.\"\r\n3: Chuck: \"Alan and Boris are both liars.\"\r\n4. Dalman: \"Chuck and I are brothers.\"\r\n5. Edwin: \"Boris and I are brothers.\"\r\n6. Finney: \"Edwin tells the truth.\"\r\n7. Finney: \"Boris is one of the Paleys.\"", "hint": "No hint available.", "answer": "Alan Thompson, Liar\r\nBoris Paley, liar\r\nChuck Thomson, truthteller\r\nDalman Paley, liar\r\nEdwin Paley, truthteller\r\nFinney Thomson, truthteller\n\r\nNeither set of brothers consists entirely of liars (introduction), so neither consists entirely of truthtellers, either. Boris, then, can't be telling the truth (clue 2); Boris is a liar. If Alan lies, then Chuck tells the truth (clue 3), and vice versa, so between Alan and Chuck, one is a liar and one a truthteller. By elimination, Dalman, Edwin, and Finney are, in some order, one liar and two truthtellers. If Finney is a liar, so is Edwin (clue 6), which is impossible; so Finney tells the truth and so does Edwin (Clue 6); Dalman, then, is a liar. Boris is a Paley (clue 7). Edwin is a Paley (clue 5). Chuck and Dalman are not brothers (clue 4), so one is a Paley and the other a Thomson; by elimination, Alan and Finney are both Thomsons. Finney Thomson tells the truth, so Alan Thomson is a liar (clue 1) and Chuck is a truthteller (clue 3). Boris Paley lied when he said both of his brothers tell the truth (clue 2); one of his brothers is Edwin Paley, a truthteller, so the other must be a liar - and therefore the third Paley can't be Chuck, a truthteller, so must be Dalman, a liar. By elimination, Chuck is a Thompson.\n\r\n...got it?", "category": "Logic", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree Paley brothers and three Thomson brothers operate a company that manufactures lie detectors. Three of these six men always tell the truth, and three always tell lies; neither set of brothers consists exclusively of liars. Some recent statements from the six men are recorded below. Can you find the six men's full names, and tell which men tell the truth and which tell lies?\n\r\n1. Alan: \"Both my brothers tell lies.\"\r\n2. Boris: \"Both my brothers tell the truth.\"\r\n3: Chuck: \"Alan and Boris are both liars.\"\r\n4. Dalman: \"Chuck and I are brothers.\"\r\n5. Edwin: \"Boris and I are brothers.\"\r\n6. Finney: \"Edwin tells the truth.\"\r\n7. Finney: \"Boris is one of the Paleys.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlan Thompson, Liar\r\nBoris Paley, liar\r\nChuck Thomson, truthteller\r\nDalman Paley, liar\r\nEdwin Paley, truthteller\r\nFinney Thomson, truthteller\n\r\nNeither set of brothers consists entirely of liars (introduction), so neither consists entirely of truthtellers, either. Boris, then, can't be telling the truth (clue 2); Boris is a liar. If Alan lies, then Chuck tells the truth (clue 3), and vice versa, so between Alan and Chuck, one is a liar and one a truthteller. By elimination, Dalman, Edwin, and Finney are, in some order, one liar and two truthtellers. If Finney is a liar, so is Edwin (clue 6), which is impossible; so Finney tells the truth and so does Edwin (Clue 6); Dalman, then, is a liar. Boris is a Paley (clue 7). Edwin is a Paley (clue 5). Chuck and Dalman are not brothers (clue 4), so one is a Paley and the other a Thomson; by elimination, Alan and Finney are both Thomsons. Finney Thomson tells the truth, so Alan Thomson is a liar (clue 1) and Chuck is a truthteller (clue 3). Boris Paley lied when he said both of his brothers tell the truth (clue 2); one of his brothers is Edwin Paley, a truthteller, so the other must be a liar - and therefore the third Paley can't be Chuck, a truthteller, so must be Dalman, a liar. By elimination, Chuck is a Thompson.\n\r\n...got it?\n<|im_start|>answer\nAlan Thompson, Liar\r\nBoris Paley, liar\r\nChuck Thomson, truthteller\r\nDalman Paley, liar\r\nEdwin Paley, truthteller\r\nFinney Thomson, truthteller\n\r\nNeither set of brothers consists entirely of liars (introduction), so neither consists entirely of truthtellers, either. Boris, then, can't be telling the truth (clue 2); Boris is a liar. If Alan lies, then Chuck tells the truth (clue 3), and vice versa, so between Alan and Chuck, one is a liar and one a truthteller. By elimination, Dalman, Edwin, and Finney are, in some order, one liar and two truthtellers. If Finney is a liar, so is Edwin (clue 6), which is impossible; so Finney tells the truth and so does Edwin (Clue 6); Dalman, then, is a liar. Boris is a Paley (clue 7). Edwin is a Paley (clue 5). Chuck and Dalman are not brothers (clue 4), so one is a Paley and the other a Thomson; by elimination, Alan and Finney are both Thomsons. Finney Thomson tells the truth, so Alan Thomson is a liar (clue 1) and Chuck is a truthteller (clue 3). Boris Paley lied when he said both of his brothers tell the truth (clue 2); one of his brothers is Edwin Paley, a truthteller, so the other must be a liar - and therefore the third Paley can't be Chuck, a truthteller, so must be Dalman, a liar. By elimination, Chuck is a Thompson.\n\r\n...got it?\n<|im_end|>" }, { "id": "#5159", "title": "The Antisocial Club", "fun": 2.92, "difficulty": 2.79, "author": "bobbrt", "desc": "The Antisocial Club meets every week at Jim's Bar. Since they are so antisocial, however, everyone always sits as far as possible from the other members, and no one ever sits right next to another member. Because of this, the 25-stool bar is almost always less than half full and unfortunately for Jim the members that don't sit at the bar don't order any drinks. Jim, however, is pretty smart and makes up a new rule: The first person to sit at the bar has to sit at one of two particular stools. If this happens, then the maximum number of members will sit at the bar. Which stools must be chosen? Assume the stools are numbered 1 to 25 and are arranged in a straight line.", "hint": "Don't forget - the people sit as far away from each other as possible. If stool #1 is chosen first, the next person will always sit in stool #25.", "answer": "The first person must take either stool 9 or 17 (because of symmetry, it doesn't matter which). Assume they pick seat 9. The next person will pick seat 25, since it is the furthest from seat 9. The next two people will take Seats one and 17. The next three will occupy 5, 13, and 21. The next six will occupy 3, 7, 11, 15, 19, and 23. This seats the maximum of 13 people, and no one is sitting next to another person. If a seat other than 9 or 17 is chosen first, the total bar patrons will be less than 13.", "category": "Logic", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Antisocial Club meets every week at Jim's Bar. Since they are so antisocial, however, everyone always sits as far as possible from the other members, and no one ever sits right next to another member. Because of this, the 25-stool bar is almost always less than half full and unfortunately for Jim the members that don't sit at the bar don't order any drinks. Jim, however, is pretty smart and makes up a new rule: The first person to sit at the bar has to sit at one of two particular stools. If this happens, then the maximum number of members will sit at the bar. Which stools must be chosen? Assume the stools are numbered 1 to 25 and are arranged in a straight line.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first person must take either stool 9 or 17 (because of symmetry, it doesn't matter which). Assume they pick seat 9. The next person will pick seat 25, since it is the furthest from seat 9. The next two people will take Seats one and 17. The next three will occupy 5, 13, and 21. The next six will occupy 3, 7, 11, 15, 19, and 23. This seats the maximum of 13 people, and no one is sitting next to another person. If a seat other than 9 or 17 is chosen first, the total bar patrons will be less than 13.\n<|im_start|>answer\nThe first person must take either stool 9 or 17 (because of symmetry, it doesn't matter which). Assume they pick seat 9. The next person will pick seat 25, since it is the furthest from seat 9. The next two people will take Seats one and 17. The next three will occupy 5, 13, and 21. The next six will occupy 3, 7, 11, 15, 19, and 23. This seats the maximum of 13 people, and no one is sitting next to another person. If a seat other than 9 or 17 is chosen first, the total bar patrons will be less than 13.\n<|im_end|>" }, { "id": "#20248", "title": "Four People in a Race", "fun": 2.92, "difficulty": 1.6400000000000001, "author": "tsimkin", "desc": "John, Paul, George, and Ringo all enter a race, but there is nobody at the finish line to judge the ending. When the judge finally shows up to award the prize for coming in first, these are the statements the four of them make:\n\r\nJohn: I was neither first nor last.\r\nPaul: I did not finish last.\r\nGeorge: I won the race!\r\nRingo: I came in last.\n\r\nThe judge starts to hand George the prize, when Yoko, who was watching the race, says, \"Exactly one of these four is lying.\"\n\r\nTo whom should the judge grant the prize?", "hint": "No hint available.", "answer": "The prize should go to Paul.\n\r\nIf John is lying, then George and Ringo would be telling the truth, which would mean John was not lying, so he can't be the liar.\n\r\nIf Paul was lying, then Ringo would also be lying, so he must be telling the truth, as well.\n\r\nSo we now know that neither John nor Paul finished last. If Ringo was lying, then George would have finished last, which would mean that he was lying, as well. So Ringo can't be lying.\n\r\nThis leaves George as our liar, so we know George did not finish first. Neither did Ringo (he finished last), nor did John (he finished neither first nor last). Therefore, Paul won the race!", "category": "Logic", "date": "01/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn, Paul, George, and Ringo all enter a race, but there is nobody at the finish line to judge the ending. When the judge finally shows up to award the prize for coming in first, these are the statements the four of them make:\n\r\nJohn: I was neither first nor last.\r\nPaul: I did not finish last.\r\nGeorge: I won the race!\r\nRingo: I came in last.\n\r\nThe judge starts to hand George the prize, when Yoko, who was watching the race, says, \"Exactly one of these four is lying.\"\n\r\nTo whom should the judge grant the prize?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe prize should go to Paul.\n\r\nIf John is lying, then George and Ringo would be telling the truth, which would mean John was not lying, so he can't be the liar.\n\r\nIf Paul was lying, then Ringo would also be lying, so he must be telling the truth, as well.\n\r\nSo we now know that neither John nor Paul finished last. If Ringo was lying, then George would have finished last, which would mean that he was lying, as well. So Ringo can't be lying.\n\r\nThis leaves George as our liar, so we know George did not finish first. Neither did Ringo (he finished last), nor did John (he finished neither first nor last). Therefore, Paul won the race!\n<|im_start|>answer\nThe prize should go to Paul.\n\r\nIf John is lying, then George and Ringo would be telling the truth, which would mean John was not lying, so he can't be the liar.\n\r\nIf Paul was lying, then Ringo would also be lying, so he must be telling the truth, as well.\n\r\nSo we now know that neither John nor Paul finished last. If Ringo was lying, then George would have finished last, which would mean that he was lying, as well. So Ringo can't be lying.\n\r\nThis leaves George as our liar, so we know George did not finish first. Neither did Ringo (he finished last), nor did John (he finished neither first nor last). Therefore, Paul won the race!\n<|im_end|>" }, { "id": "#44985", "title": "Five Cousins", "fun": 2.92, "difficulty": 3.35, "author": "cnmne", "desc": "Five cousins are celebrating New Year's Day. Using the following clues, determine each person's age, birth date, and birth time.\n\r\nNames: Alvin, Donna, Jerry, Laura, Steve (Donna and Laura are girls)\r\nAges: 28, 29, 30, 31, 32\r\nMonths: February, May, June, August, October\r\nDates: 9th, 11th, 15th, 29th, 31st\r\nTimes: 6:00 AM, 9:00 AM, 2:00 PM, 5:00 PM, 7:00 PM\n\r\n1) Two of the boys were born in a leap year.\r\n2) Neither girl was born in the morning.\r\n3) Both girls were born in the first half of the month.\r\n4) One of the boys was born three hours later in the day than one of the girls.\r\n5) No one celebrated a golden birthday last year, and no one will celebrate a golden birthday this year.\r\n6) The five people are: Alvin, the person who is 32 years old, the person born in August, the person born on the 11th, and the person born at 9:00 AM.\r\n7) The person born at 6:00 AM is older than the girl born on the 15th, who is older than the boy born in October.\r\n8) Jerry was born earlier in the year than the person born on the 11th, who was born earlier in the year than the person who is 28 years old.\r\n9) The person born in May was born earlier in the month than the person born at 7:00 PM, who was born earlier in the month than the person who is 30 years old.\r\n10) The person born on the 29th was born earlier in the day than the person who is 31 years old, who was born earlier in the day than the person born in June.\r\n11) Steve and Donna have the two closest birthdays.", "hint": "Some helpful steps (though not all) are listed below.\n\r\n1) February and June do not have 31 days, so neither month can have 31 days. February can only have the 29th in a leap year.\r\n2) A golden birthday is when a person becomes the age that is the same as the day of birth. For example, a person born on the 10th of a month celebrates a golden birthday when that person turns ten years old. Since a golden birthday was not celebrated last year and will not be celebrated this year, the persons who are 28 and 29 were not born on the 29th, and the persons who are 30 and 31 were not born on the 31st.\r\n3) For two boys to be born during leap years, they must be four years apart in age. Therefore, one boy must be 32 years old, and another boy must be 28 years old.\r\n4) One boy was born three hours later in the day than a girl. There are only two situations that satisfy that requirement: a girl born at 6:00 AM and a boy born at 9:00 AM, or a girl born at 2:00 PM and a boy born at 5:00 PM. Since no girl was born in the morning, then that leaves a girl born at 2:00 PM with a boy born at 5:00 PM. That also means that the other girl was born at 7:00 PM.\r\n5) Since one of the girls must be born on the 15th, and both girls were born in the first half of a month, the 15th can not be in February.\r\n6) With the remaining combinations of months and days, the two closest birthdays can only be in May and June.\r\n7) Since it has now been established that the 29th is in February, then it must be matched with a person born in a leap year, which can only be the person who is 28 or 32. It has been established that the person who is 28 was born on October 31st, so the person who is 32 was born on February 29th.", "answer": "Alvin, 28 years old, born on October 31st at 5:00 PM\r\nDonna, 29 years old, born on June 11th at 7:00 PM\r\nJerry, 32 years old, born on February 29th at 6:00 AM\r\nLaura, 30 years old, born on August 15th at 2:00 PM\r\nSteve, 31 years old, born on May 9th at 9:00 AM", "category": "Logic-Grid", "date": "07/30/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive cousins are celebrating New Year's Day. Using the following clues, determine each person's age, birth date, and birth time.\n\r\nNames: Alvin, Donna, Jerry, Laura, Steve (Donna and Laura are girls)\r\nAges: 28, 29, 30, 31, 32\r\nMonths: February, May, June, August, October\r\nDates: 9th, 11th, 15th, 29th, 31st\r\nTimes: 6:00 AM, 9:00 AM, 2:00 PM, 5:00 PM, 7:00 PM\n\r\n1) Two of the boys were born in a leap year.\r\n2) Neither girl was born in the morning.\r\n3) Both girls were born in the first half of the month.\r\n4) One of the boys was born three hours later in the day than one of the girls.\r\n5) No one celebrated a golden birthday last year, and no one will celebrate a golden birthday this year.\r\n6) The five people are: Alvin, the person who is 32 years old, the person born in August, the person born on the 11th, and the person born at 9:00 AM.\r\n7) The person born at 6:00 AM is older than the girl born on the 15th, who is older than the boy born in October.\r\n8) Jerry was born earlier in the year than the person born on the 11th, who was born earlier in the year than the person who is 28 years old.\r\n9) The person born in May was born earlier in the month than the person born at 7:00 PM, who was born earlier in the month than the person who is 30 years old.\r\n10) The person born on the 29th was born earlier in the day than the person who is 31 years old, who was born earlier in the day than the person born in June.\r\n11) Steve and Donna have the two closest birthdays.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlvin, 28 years old, born on October 31st at 5:00 PM\r\nDonna, 29 years old, born on June 11th at 7:00 PM\r\nJerry, 32 years old, born on February 29th at 6:00 AM\r\nLaura, 30 years old, born on August 15th at 2:00 PM\r\nSteve, 31 years old, born on May 9th at 9:00 AM\n<|im_start|>answer\nAlvin, 28 years old, born on October 31st at 5:00 PM\r\nDonna, 29 years old, born on June 11th at 7:00 PM\r\nJerry, 32 years old, born on February 29th at 6:00 AM\r\nLaura, 30 years old, born on August 15th at 2:00 PM\r\nSteve, 31 years old, born on May 9th at 9:00 AM\n<|im_end|>" }, { "id": "#51566", "title": "A Day at the Groomer's", "fun": 2.92, "difficulty": 1.77, "author": "FiaTzu", "desc": "Five dogs have a noon appointment at Louise's Puppy Parlor this afternoon. Unfortunately while trying to wrangle a particularly uncooperative Yorkie into the bathtub, Louise's assistant dropped the appointment book into the water and now Louise can't remember which dog is which. Please help Louise remember the name and breed of each dog, the color of their collars and the time they're being picked up.\n\r\n1.) Dexter and Bernard are the only male dogs who have appointments today. One of them is a dachsund and the other is having his teeth brushed.\n\r\n2.) The five appointments in order are: the one getting a trim, the one in the red collar, the poodle, Dexter, and the one in the turquoise collar.\n\r\n3.) Blowing out her long, silky hair takes some time, so the dog getting the blowout will be picked up last.\n\r\n4.) Either CoCo is the Pekingese and Lucy is getting a mani-pedi, or Prudence is the Pekingese and the dachsund is wearing a purple collar.\n\r\n4.) Two dogs have a name that begins with the same letter as their breed and two dogs have a name that begins with the same letter as the color of their collar. \n\r\n5.) The schnauzer and the dachsund both have short hair so neither needed a blowout, but one needed a bath after she got into the garbage and the other was the next to last to be picked up.\n\r\n6.) Lucy is named after Lucille Ball and her collar matches her namesake's signature hair color.", "hint": "Lucille Ball was known for her flaming red hair, which is the color of the schnauzer's collar.", "answer": "Prudence- Pekingese- Trim- Pink- 1:00\r\nLucy- Schnauzer- Bath- Red- 2:00\r\nBernard- Poodle- Teeth Brushed- Blue- 3:00\r\nDexter- Dachsund- Mani Pedi- Purple- 3:30\r\nCoCo- Shih Tzu- Blowout- Turquoise- 4:00", "category": "Logic-Grid", "date": "11/11/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive dogs have a noon appointment at Louise's Puppy Parlor this afternoon. Unfortunately while trying to wrangle a particularly uncooperative Yorkie into the bathtub, Louise's assistant dropped the appointment book into the water and now Louise can't remember which dog is which. Please help Louise remember the name and breed of each dog, the color of their collars and the time they're being picked up.\n\r\n1.) Dexter and Bernard are the only male dogs who have appointments today. One of them is a dachsund and the other is having his teeth brushed.\n\r\n2.) The five appointments in order are: the one getting a trim, the one in the red collar, the poodle, Dexter, and the one in the turquoise collar.\n\r\n3.) Blowing out her long, silky hair takes some time, so the dog getting the blowout will be picked up last.\n\r\n4.) Either CoCo is the Pekingese and Lucy is getting a mani-pedi, or Prudence is the Pekingese and the dachsund is wearing a purple collar.\n\r\n4.) Two dogs have a name that begins with the same letter as their breed and two dogs have a name that begins with the same letter as the color of their collar. \n\r\n5.) The schnauzer and the dachsund both have short hair so neither needed a blowout, but one needed a bath after she got into the garbage and the other was the next to last to be picked up.\n\r\n6.) Lucy is named after Lucille Ball and her collar matches her namesake's signature hair color.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPrudence- Pekingese- Trim- Pink- 1:00\r\nLucy- Schnauzer- Bath- Red- 2:00\r\nBernard- Poodle- Teeth Brushed- Blue- 3:00\r\nDexter- Dachsund- Mani Pedi- Purple- 3:30\r\nCoCo- Shih Tzu- Blowout- Turquoise- 4:00\n<|im_start|>answer\nPrudence- Pekingese- Trim- Pink- 1:00\r\nLucy- Schnauzer- Bath- Red- 2:00\r\nBernard- Poodle- Teeth Brushed- Blue- 3:00\r\nDexter- Dachsund- Mani Pedi- Purple- 3:30\r\nCoCo- Shih Tzu- Blowout- Turquoise- 4:00\n<|im_end|>" }, { "id": "#34003", "title": "The Disappearing Adventurers", "fun": 2.92, "difficulty": 1.6300000000000001, "author": "Sunrose", "desc": "The Seekers of Knowledge wanted to wander the land about them some. They went to the great Petrified Forest. The forest was quiet, and nothing seemed to live within it, not even a bird. During the early mornings and late evenings, the forest had a gloomy fog that covered the ground, making it look like a lake with stone trees growing from it. The quietness of the forest was unnerving, and caused the group to be on guard, and nervous themselves.\n\r\nThe Seekers set up camp one evening, before the fog came. That day, Sid felt as though someone or something had been watching them for most of the day. Thad knew that Sid would not speak of such a thing, if he did not feel it. That night, Thad set up a watch among them to make sure if something does happen, the one awake could wake them.\n\r\nThe night was cool, the magical heat stones they had was the only thing they had to keep them warm, and they did produce a small light to see with, almost like a campfire.\n\r\nSid was correct with his feeling though. Something had been watching them throughout the day. That night, it put the one keeping watch to sleep, and magically teleported them away to another place. Something woke them up after the teleportation, and they each found themselves near a creature, in a different area, next to a colored box and some food.\n\n\r\nGroup: Sid, Thad, Joel, Dawn, Clover\r\nCreature: Drake, Fairy, Minotaur, Magical Mummy, Troll\r\nArea: Deep Cave, Waterfall, Burnt Field, Dark House, Base of a Mountain\r\nColored Boxes: Green, Blue, Red, Gold, Silver\r\nFood: Potatoes, Peas, Bread, Fried Fish, Corn\n\r\nClues:\n\r\n1. The groups are Thad, Drake, Red box, Corn and the Mummy.\r\n2. Dawn and Clover did not go to the base of the mountain, or the waterfall.\r\n3. Joel found himself at the burnt field, with the silver box.\r\n4. Sid found himself near the mummy, with a plate of fried fish.\r\n5. Thad found the blue box, and was not near the fairy or Minotaur.\r\n6. Dawn did not find the bread or corn, but did have the gold box.\r\n7. Clover found a plate of peas, and was not with the Drake, but was deep inside a cave.\r\n8. Sid was not at the cave or the house, and did not have the red box.\r\n9. Joel found the Minotaur, while Thad saw a turtle swimming at the bottom of the waterfall.", "hint": "No hint available.", "answer": "Group - Creature - Area - Colored Boxes - Food\n\r\nClover - Fairy - Cave - Red - Peas\r\nDawn - Drake - House - Gold -Potatoes\r\nJoel - Minotaur - Burnt Field - Silver - Corn\r\nSid - Mummy - Base of the Mountain - Green - Fish\r\nThad - Troll - Waterfall - Blue - Bread\n\r\nThe Seekers thinking that they were in deep trouble without their weapons, and most of their armor, they prepared themselves as best as they could for battle. Joel began to charge the Minotaur, but it spoke and begged him not to hurt him. Therefore, he stopped to listen to the Minotaur. The others of the group were experiencing the same thing as well. The creatures seemed to wish to speak and wanted to listen to them as well. After they had said and shared stories with one another, the creature told them to pick the box up, for it would put them back in the forest with their friends.\n\r\nUpon waking up, it seemed as though it was nothing but a dream. A dream brought on by the forest and their fears of being alone, but with hope put into their hearts. They put their clothes on and went outside the tents. They noticed that the sun was right above them, meaning it was around noon. There was a feast for them, plates full of bread, corn, fish, potatoes, and peas. They were astonished and confused by what they saw. They smelt the food, tasted it, and then ate until their stomachs could not hold anymore.", "category": "Logic-Grid", "date": "11/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Seekers of Knowledge wanted to wander the land about them some. They went to the great Petrified Forest. The forest was quiet, and nothing seemed to live within it, not even a bird. During the early mornings and late evenings, the forest had a gloomy fog that covered the ground, making it look like a lake with stone trees growing from it. The quietness of the forest was unnerving, and caused the group to be on guard, and nervous themselves.\n\r\nThe Seekers set up camp one evening, before the fog came. That day, Sid felt as though someone or something had been watching them for most of the day. Thad knew that Sid would not speak of such a thing, if he did not feel it. That night, Thad set up a watch among them to make sure if something does happen, the one awake could wake them.\n\r\nThe night was cool, the magical heat stones they had was the only thing they had to keep them warm, and they did produce a small light to see with, almost like a campfire.\n\r\nSid was correct with his feeling though. Something had been watching them throughout the day. That night, it put the one keeping watch to sleep, and magically teleported them away to another place. Something woke them up after the teleportation, and they each found themselves near a creature, in a different area, next to a colored box and some food.\n\n\r\nGroup: Sid, Thad, Joel, Dawn, Clover\r\nCreature: Drake, Fairy, Minotaur, Magical Mummy, Troll\r\nArea: Deep Cave, Waterfall, Burnt Field, Dark House, Base of a Mountain\r\nColored Boxes: Green, Blue, Red, Gold, Silver\r\nFood: Potatoes, Peas, Bread, Fried Fish, Corn\n\r\nClues:\n\r\n1. The groups are Thad, Drake, Red box, Corn and the Mummy.\r\n2. Dawn and Clover did not go to the base of the mountain, or the waterfall.\r\n3. Joel found himself at the burnt field, with the silver box.\r\n4. Sid found himself near the mummy, with a plate of fried fish.\r\n5. Thad found the blue box, and was not near the fairy or Minotaur.\r\n6. Dawn did not find the bread or corn, but did have the gold box.\r\n7. Clover found a plate of peas, and was not with the Drake, but was deep inside a cave.\r\n8. Sid was not at the cave or the house, and did not have the red box.\r\n9. Joel found the Minotaur, while Thad saw a turtle swimming at the bottom of the waterfall.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGroup - Creature - Area - Colored Boxes - Food\n\r\nClover - Fairy - Cave - Red - Peas\r\nDawn - Drake - House - Gold -Potatoes\r\nJoel - Minotaur - Burnt Field - Silver - Corn\r\nSid - Mummy - Base of the Mountain - Green - Fish\r\nThad - Troll - Waterfall - Blue - Bread\n\r\nThe Seekers thinking that they were in deep trouble without their weapons, and most of their armor, they prepared themselves as best as they could for battle. Joel began to charge the Minotaur, but it spoke and begged him not to hurt him. Therefore, he stopped to listen to the Minotaur. The others of the group were experiencing the same thing as well. The creatures seemed to wish to speak and wanted to listen to them as well. After they had said and shared stories with one another, the creature told them to pick the box up, for it would put them back in the forest with their friends.\n\r\nUpon waking up, it seemed as though it was nothing but a dream. A dream brought on by the forest and their fears of being alone, but with hope put into their hearts. They put their clothes on and went outside the tents. They noticed that the sun was right above them, meaning it was around noon. There was a feast for them, plates full of bread, corn, fish, potatoes, and peas. They were astonished and confused by what they saw. They smelt the food, tasted it, and then ate until their stomachs could not hold anymore.\n<|im_start|>answer\nGroup - Creature - Area - Colored Boxes - Food\n\r\nClover - Fairy - Cave - Red - Peas\r\nDawn - Drake - House - Gold -Potatoes\r\nJoel - Minotaur - Burnt Field - Silver - Corn\r\nSid - Mummy - Base of the Mountain - Green - Fish\r\nThad - Troll - Waterfall - Blue - Bread\n\r\nThe Seekers thinking that they were in deep trouble without their weapons, and most of their armor, they prepared themselves as best as they could for battle. Joel began to charge the Minotaur, but it spoke and begged him not to hurt him. Therefore, he stopped to listen to the Minotaur. The others of the group were experiencing the same thing as well. The creatures seemed to wish to speak and wanted to listen to them as well. After they had said and shared stories with one another, the creature told them to pick the box up, for it would put them back in the forest with their friends.\n\r\nUpon waking up, it seemed as though it was nothing but a dream. A dream brought on by the forest and their fears of being alone, but with hope put into their hearts. They put their clothes on and went outside the tents. They noticed that the sun was right above them, meaning it was around noon. There was a feast for them, plates full of bread, corn, fish, potatoes, and peas. They were astonished and confused by what they saw. They smelt the food, tasted it, and then ate until their stomachs could not hold anymore.\n<|im_end|>" }, { "id": "#34651", "title": "Mr. Gilles", "fun": 2.92, "difficulty": 2.54, "author": "Winner4600", "desc": "What a week! Mr. Gilles, in charge of the Lost and Found, has been busy with students looking for lost items! Five students came, one on each day of the week, to retrieve their misplaced articles and possessions. So many came that Mr. Gilles has messed up his daily log! Can you help him piece the information back together?\n\r\n1. The five students are Dominique, Mr. Harris, the one who lost a notebook, the one who retrieved her lost item Tuesday, and the one who came at noon.\n\r\n2. Elsie picked her key up before Peterson came.\n\r\n3. Ms. Sanson came at 9:50 a.m. to pick up a purse.\n\r\n4. Birch came on Friday to pick up a lost item; Mary came on Wednesday.\n\r\n5. Jacob spent an entire weekend worrying about his sweatshirt; he picked it up first thing on Monday.\n\r\n6. Allen came earlier in the day than the one who picked up an iPod.\n\r\nGirls: Mary, Dominique, and Elsie \r\nBoys: Jacob and Allen", "hint": "No hint available.", "answer": "Mary Peterson came at 12:00 noon on Wednesday to pick up an iPod.\n\r\nJacob Harris came at 8:30 a.m. on Monday to pick up a sweatshirt.\n\r\nDominique Sanson came at 9:50 a.m. on Thursday to pick up a purse.\n\r\nAllen Birch came at 10:05 a.m. on Friday to pick up a notebook.\n\r\nElsie Jaroth came at 2:25 p.m. on Tuesday to pick up a house key.", "category": "Logic-Grid", "date": "12/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat a week! Mr. Gilles, in charge of the Lost and Found, has been busy with students looking for lost items! Five students came, one on each day of the week, to retrieve their misplaced articles and possessions. So many came that Mr. Gilles has messed up his daily log! Can you help him piece the information back together?\n\r\n1. The five students are Dominique, Mr. Harris, the one who lost a notebook, the one who retrieved her lost item Tuesday, and the one who came at noon.\n\r\n2. Elsie picked her key up before Peterson came.\n\r\n3. Ms. Sanson came at 9:50 a.m. to pick up a purse.\n\r\n4. Birch came on Friday to pick up a lost item; Mary came on Wednesday.\n\r\n5. Jacob spent an entire weekend worrying about his sweatshirt; he picked it up first thing on Monday.\n\r\n6. Allen came earlier in the day than the one who picked up an iPod.\n\r\nGirls: Mary, Dominique, and Elsie \r\nBoys: Jacob and Allen\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary Peterson came at 12:00 noon on Wednesday to pick up an iPod.\n\r\nJacob Harris came at 8:30 a.m. on Monday to pick up a sweatshirt.\n\r\nDominique Sanson came at 9:50 a.m. on Thursday to pick up a purse.\n\r\nAllen Birch came at 10:05 a.m. on Friday to pick up a notebook.\n\r\nElsie Jaroth came at 2:25 p.m. on Tuesday to pick up a house key.\n<|im_start|>answer\nMary Peterson came at 12:00 noon on Wednesday to pick up an iPod.\n\r\nJacob Harris came at 8:30 a.m. on Monday to pick up a sweatshirt.\n\r\nDominique Sanson came at 9:50 a.m. on Thursday to pick up a purse.\n\r\nAllen Birch came at 10:05 a.m. on Friday to pick up a notebook.\n\r\nElsie Jaroth came at 2:25 p.m. on Tuesday to pick up a house key.\n<|im_end|>" }, { "id": "#25401", "title": "A Few New Family Members", "fun": 2.92, "difficulty": 2.29, "author": "Winner4600", "desc": "For their birthdays, 5 girls each received a cat as a present. Each cat was a different color and age, and was given by someone very close to the girl. Find out which cat belonged to which girl, what its name, age, and color were, and who sent each cat.\n\r\nGirls: Lisa, Michelle, Nicole, Olivia, Paula\r\nCats: Cinnamon, KitKat, Midnight, Tiger, Tunafish\r\nColors: White, Brown, Black, Ginger, Striped\r\nAges: 2 months, 6 months, 9 months, 1 year, 2 years\r\nSenders: Mom, Dad, Brother, Sister, Best Friend\n\n\r\n1. No girl shares an initial with their cat.\r\n2. Nicole's sister doesn't like stripes, so Nicole received a cat half the age of Paula's, but a little older than Tunafish.\r\n3. The 5 girls are: Lisa, the one with the 2-year-old cat, the girl who owns KitKat, the girl whose dad bought a cat, and Michelle.\r\n4. The white cat is 9 months old.\r\n5. Michelle's cat has a \"fishy\" name, while Lisa's is named for a spice.\r\n6. Each girl gave their cat a meaningful name.\r\n7. Paula has been deathly afraid of tigers since she was little.\r\n8. The 5 cats are: Tunafish, the 2 month old cat, Nicole's cat, the one given by a friend, and Olivia's cat.\r\n9. Michelle is an only child.", "hint": "\"Meaningful\" means the cat's name has some relation to the cat's color.", "answer": "GIRL-CAT-COLOR-AGE-SENDER\n\r\nLisa-Cinnamon-Ginger-2 mos.-Brother\r\nMichelle-Tunafish-White-9 mos.-Mom\r\nNicole-KitKat-Brown-1 yr.-Sister\r\nOlivia-Tiger-Striped-6 mos.-Dad\r\nPaula-Midnight-Black-2 yrs.-Best Friend", "category": "Logic-Grid", "date": "08/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor their birthdays, 5 girls each received a cat as a present. Each cat was a different color and age, and was given by someone very close to the girl. Find out which cat belonged to which girl, what its name, age, and color were, and who sent each cat.\n\r\nGirls: Lisa, Michelle, Nicole, Olivia, Paula\r\nCats: Cinnamon, KitKat, Midnight, Tiger, Tunafish\r\nColors: White, Brown, Black, Ginger, Striped\r\nAges: 2 months, 6 months, 9 months, 1 year, 2 years\r\nSenders: Mom, Dad, Brother, Sister, Best Friend\n\n\r\n1. No girl shares an initial with their cat.\r\n2. Nicole's sister doesn't like stripes, so Nicole received a cat half the age of Paula's, but a little older than Tunafish.\r\n3. The 5 girls are: Lisa, the one with the 2-year-old cat, the girl who owns KitKat, the girl whose dad bought a cat, and Michelle.\r\n4. The white cat is 9 months old.\r\n5. Michelle's cat has a \"fishy\" name, while Lisa's is named for a spice.\r\n6. Each girl gave their cat a meaningful name.\r\n7. Paula has been deathly afraid of tigers since she was little.\r\n8. The 5 cats are: Tunafish, the 2 month old cat, Nicole's cat, the one given by a friend, and Olivia's cat.\r\n9. Michelle is an only child.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGIRL-CAT-COLOR-AGE-SENDER\n\r\nLisa-Cinnamon-Ginger-2 mos.-Brother\r\nMichelle-Tunafish-White-9 mos.-Mom\r\nNicole-KitKat-Brown-1 yr.-Sister\r\nOlivia-Tiger-Striped-6 mos.-Dad\r\nPaula-Midnight-Black-2 yrs.-Best Friend\n<|im_start|>answer\nGIRL-CAT-COLOR-AGE-SENDER\n\r\nLisa-Cinnamon-Ginger-2 mos.-Brother\r\nMichelle-Tunafish-White-9 mos.-Mom\r\nNicole-KitKat-Brown-1 yr.-Sister\r\nOlivia-Tiger-Striped-6 mos.-Dad\r\nPaula-Midnight-Black-2 yrs.-Best Friend\n<|im_end|>" }, { "id": "#26429", "title": "Teasergle II", "fun": 2.92, "difficulty": 3.07, "author": "phrebh", "desc": "Five online friends, two guys (Asthma and Checkers) and three girls (Jaymee, Miss Sissy, and Warbucks) like to spend time on the same brain teaser oriented site, Teasergle. Each of them like to solve different types of teasers (Language, Logic, Math, Riddle, and Trick) and each of them likes to write different types of teasers (Language, Logic, Math, Riddle, and Trick). One day, they each wrote a teaser, taking a different amount of time to do so (10 minutes, 20 minutes, 30 minutes, 40 minutes, and 50 minutes). The same day, they also each solved a teaser, taking a differing amount of time to do so (1 minute, 2 minutes, 3 minutes, 4 minutes, and 5 minutes). Using the clues below, can you determine which friend likes to write what category of teaser, solve what category of teaser, and how long it took them to write one and solve one?\n\r\n1. Three people liked to write the same kind of teaser that they liked to solve.\n\r\n2. Three people took ten times longer to write a teaser as they did to solve one.\n\r\n3. Jaymee took longer to solve her teaser than the girl who spent 50 minutes writing her teaser.\n\r\n4. The group follows the generalization that guys don't like language and girls don't like math, so no girl wrote or solved a math teaser and no guy wrote or solved a language teaser.\n\r\n5. Trick teasers are always written the fastest and language teasers take the longest to solve.\n\r\n6. Logic teasers take more time to write than math teasers, which take more time to write than language teasers.\n\r\n7. Two people liked to write the same kind of teaser that they liked to solve and took ten times longer to write their teaser as they did to solve a teaser.\n\r\n8. Asthma wrote the riddle teaser.\n\r\n9. The five people are the girl who took 30 minutes to write a teaser, the person who took 3 minutes to solve a teaser, the person who wrote and solved a math teaser, the person who solved the riddle, and Miss Sissy.", "hint": "No hint available.", "answer": "Asthma took 20 minutes to write a Riddle teaser and 2 minutes to solve a Riddle teaser.\r\nCheckers took 40 minutes to write a Math teaser and 4 minutes to solve a Math teaser.\r\nJaymee took 30 minutes to write a Language teaser and 5 minutes to solve a Language teaser.\r\nMiss Sissy took 10 minutes to write a Trick teaser and 1 minute to solve a Logic teaser.\r\nWarbucks took 50 minutes to write a Logic teaser and 3 minutes to solve a Trick teaser.", "category": "Logic-Grid", "date": "10/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive online friends, two guys (Asthma and Checkers) and three girls (Jaymee, Miss Sissy, and Warbucks) like to spend time on the same brain teaser oriented site, Teasergle. Each of them like to solve different types of teasers (Language, Logic, Math, Riddle, and Trick) and each of them likes to write different types of teasers (Language, Logic, Math, Riddle, and Trick). One day, they each wrote a teaser, taking a different amount of time to do so (10 minutes, 20 minutes, 30 minutes, 40 minutes, and 50 minutes). The same day, they also each solved a teaser, taking a differing amount of time to do so (1 minute, 2 minutes, 3 minutes, 4 minutes, and 5 minutes). Using the clues below, can you determine which friend likes to write what category of teaser, solve what category of teaser, and how long it took them to write one and solve one?\n\r\n1. Three people liked to write the same kind of teaser that they liked to solve.\n\r\n2. Three people took ten times longer to write a teaser as they did to solve one.\n\r\n3. Jaymee took longer to solve her teaser than the girl who spent 50 minutes writing her teaser.\n\r\n4. The group follows the generalization that guys don't like language and girls don't like math, so no girl wrote or solved a math teaser and no guy wrote or solved a language teaser.\n\r\n5. Trick teasers are always written the fastest and language teasers take the longest to solve.\n\r\n6. Logic teasers take more time to write than math teasers, which take more time to write than language teasers.\n\r\n7. Two people liked to write the same kind of teaser that they liked to solve and took ten times longer to write their teaser as they did to solve a teaser.\n\r\n8. Asthma wrote the riddle teaser.\n\r\n9. The five people are the girl who took 30 minutes to write a teaser, the person who took 3 minutes to solve a teaser, the person who wrote and solved a math teaser, the person who solved the riddle, and Miss Sissy.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAsthma took 20 minutes to write a Riddle teaser and 2 minutes to solve a Riddle teaser.\r\nCheckers took 40 minutes to write a Math teaser and 4 minutes to solve a Math teaser.\r\nJaymee took 30 minutes to write a Language teaser and 5 minutes to solve a Language teaser.\r\nMiss Sissy took 10 minutes to write a Trick teaser and 1 minute to solve a Logic teaser.\r\nWarbucks took 50 minutes to write a Logic teaser and 3 minutes to solve a Trick teaser.\n<|im_start|>answer\nAsthma took 20 minutes to write a Riddle teaser and 2 minutes to solve a Riddle teaser.\r\nCheckers took 40 minutes to write a Math teaser and 4 minutes to solve a Math teaser.\r\nJaymee took 30 minutes to write a Language teaser and 5 minutes to solve a Language teaser.\r\nMiss Sissy took 10 minutes to write a Trick teaser and 1 minute to solve a Logic teaser.\r\nWarbucks took 50 minutes to write a Logic teaser and 3 minutes to solve a Trick teaser.\n<|im_end|>" }, { "id": "#49134", "title": "World of Nerds", "fun": 2.92, "difficulty": 3.15, "author": "Gizzer", "desc": "Five friends spend every Monday night eating Chinese food from the Golden Dragon. Howard has Mu Shu Pork, Leonard has Spicy Szechuan Tofu, Penny has Shrimp with Lobster Sauce, Raj has Beef with String Beans, and Sheldon has Chicken and Broccoli: diced, not shredded, with brown rice, not white, low-sodium soy sauce and the good hot mustard from the Korean grocery. \n\r\nAfter dinner, they play a role-playing game called World of Nerds. \n\r\nIn this game, each player takes on a character belonging to a different race of creature, has a different occupation, uses a different sort of weapon, specializes in fighting a particular kind of monster, and has a different skill level. \n\r\nCan you determine the characteristics of each player's character from the following clues before someone sits in Sheldon's spot? \n\n\r\nPlayers: Howard, Leonard, Penny, Raj and Sheldon \r\nRaces: elf, gremlin, halfling, hobbit and ogre \r\nOccupations: archbishop, merchant, paladin, sorcerer and thief \r\nWeapons: bolo, crossbow, dagger, fireballs and mace \r\nMonsters: chimeras, giants, harpies, kobolds and orcs \r\nSkill levels: range from 10-32 \n\n\r\nClues: \n\r\n1. The five characters in the game are Penny's, the 24th-level ogre, the thief, the fireball user, and the one skilled at fighting orcs. \n\r\n2. The paladin isn't an elf. \n\r\n3. The bolo user has a skill level twice that of the halfling. \n\r\n4. Raj's character has a skill level eight levels higher than the paladin, who in turn is eight levels higher than the crossbow user. \n\r\n5. The hobbit is no good at fighting giants. \n\r\n6. The elf (who doesn't care for crossbows) is ten levels higher than the one who fights kobolds. \n\r\n7. The one who is adept at fighting chimeras is four levels higher than Leonard's character (who isn't the archbishop). \n\r\n8. The character at the lowest level (who isn't Penny) is at level ten and uses a dagger. \n\r\n9. Neither the archbishop nor the merchant belongs to the race of gremlins. \n\r\n10. The giant fighter never uses a mace in battle. \n\r\n11. Raj's character isn't the elf. \n\r\n12. Penny's character doesn't use the crossbow. \n\r\n13. Howard's character is not particularly adept at fighting harpies.", "hint": "Start by determining the 5 skill levels.", "answer": "Howard is the halfling and a level 10 thief who fights kobolds with a dagger. \r\nLeonard is the hobbit and a level 16 merchant who fights orcs with a crossbow. \r\nPenny is the elf and a level 20 archbishop who fights chimeras with a bolo. \r\nRaj is the gremlin and a level 32 sorcerer who fights giants with fireballs. \r\nSheldon is the ogre and a level 24 paladin who fights harpies with a mace. \n\n\r\nExplanation: \n\r\nThe first step is to determine the actual skill levels of the five players. \n\r\nThe lowest level is 10, held by the character using a dagger (clue 8). \n\r\nFrom (4), the character using a crossbow has an unknown level, let's call it x; the paladin has x+8 and Raj has x+16. Note that x must be greater than 10 and less than or equal to 16, or else x+16 would be greater than 32. \n\r\nThe elf is none of these four players (2, 11, 6), but has a skill level of 10 more than one of them (6). This could be 20, x+10 or x+18. \n\r\nOne skill level has to be 24 (1), two skill levels must have a difference of 4 (7) and one skill level must be twice another (3). \n\r\nIf x=11, then the skill levels are 10, 11, 19, 27 and the elf's is either 20, 21 or 29. None of these is 24; therefore, x isn't 11. Similarly x isn't 12, 13 or 15. \n\r\nIf x=14, then the skill levels are 10, 14, 22, 30 and the elf's is either 20, 24 or 32. This provides a skill level of 24, but for the elf, instead of the ogre; therefore, x isn't 14. \n\r\nTherefore, x=16 and the skill levels are 10 [dagger], 16 [crossbow], 24 [paladin=ogre], and 32 [Raj]. The elf's skill level must be 20, not 26, in order to satisfy clue (7). This means the elf fights chimeras and Leonard's character uses the crossbow. \n\r\nNow that we know the skill levels, we can start building a list of the players, starting with the first clue: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = thief \r\nPlayer 4 = fireballs \r\nPlayer 5 = orcs \n\r\nSince the elf has a skill level of 20, the kobold fighter is level 10 (6), and uses the dagger (8). Penny's character doesn't use the dagger (8), and neither does the ogre, who is level 24. Therefore the thief does: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = orcs \n\r\nNeither Penny's character (12) nor the ogre (4) uses the crossbow [Leonard], so the orc fighter must: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe ogre can't use the bolo, as no one has level 12 (3), so Penny's character uses the bolo and the thief is the halfling. This leaves the ogre using the mace: \n\r\nPlayer 1 = Penny, bolo \r\nPlayer 2 = ogre, level 24, paladin, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThis means that Raj's character, at level 32, must use fireballs, and Penny's character must be the level 20 elf who fights chimeras: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, level 32, fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe ogre, who uses a mace, doesn't fight giants (10); therefore the ogre fights harpies, leaving Raj's character as the giant fighter: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, level 32, giants, fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe hobbit doesn't fight giants (5), so the hobbit must fight orcs, leaving Raj as the gremlin. The gremlin isn't the archbishop or the merchant, and so the gremlin is the sorcerer: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, orcs, crossbow \n\r\nLeonard's character must be the merchant, rather than the archbishop (7), leaving Penny's character as the archbishop: \n\r\nPlayer 1 = Penny, elf, level 20, archbishop, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, merchant, orcs, crossbow \n\r\nHoward's character doesn't fight harpies (13), so that falls to Sheldon's ogre, while Howard's halfling fights kobolds. And that completes the list: \n\r\nPlayer 1 = Penny, elf, level 20, archbishop, chimeras, bolo \r\nPlayer 2 = Sheldon, ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = Howard, halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, merchant, orcs, crossbow", "category": "Logic", "date": "11/22/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends spend every Monday night eating Chinese food from the Golden Dragon. Howard has Mu Shu Pork, Leonard has Spicy Szechuan Tofu, Penny has Shrimp with Lobster Sauce, Raj has Beef with String Beans, and Sheldon has Chicken and Broccoli: diced, not shredded, with brown rice, not white, low-sodium soy sauce and the good hot mustard from the Korean grocery. \n\r\nAfter dinner, they play a role-playing game called World of Nerds. \n\r\nIn this game, each player takes on a character belonging to a different race of creature, has a different occupation, uses a different sort of weapon, specializes in fighting a particular kind of monster, and has a different skill level. \n\r\nCan you determine the characteristics of each player's character from the following clues before someone sits in Sheldon's spot? \n\n\r\nPlayers: Howard, Leonard, Penny, Raj and Sheldon \r\nRaces: elf, gremlin, halfling, hobbit and ogre \r\nOccupations: archbishop, merchant, paladin, sorcerer and thief \r\nWeapons: bolo, crossbow, dagger, fireballs and mace \r\nMonsters: chimeras, giants, harpies, kobolds and orcs \r\nSkill levels: range from 10-32 \n\n\r\nClues: \n\r\n1. The five characters in the game are Penny's, the 24th-level ogre, the thief, the fireball user, and the one skilled at fighting orcs. \n\r\n2. The paladin isn't an elf. \n\r\n3. The bolo user has a skill level twice that of the halfling. \n\r\n4. Raj's character has a skill level eight levels higher than the paladin, who in turn is eight levels higher than the crossbow user. \n\r\n5. The hobbit is no good at fighting giants. \n\r\n6. The elf (who doesn't care for crossbows) is ten levels higher than the one who fights kobolds. \n\r\n7. The one who is adept at fighting chimeras is four levels higher than Leonard's character (who isn't the archbishop). \n\r\n8. The character at the lowest level (who isn't Penny) is at level ten and uses a dagger. \n\r\n9. Neither the archbishop nor the merchant belongs to the race of gremlins. \n\r\n10. The giant fighter never uses a mace in battle. \n\r\n11. Raj's character isn't the elf. \n\r\n12. Penny's character doesn't use the crossbow. \n\r\n13. Howard's character is not particularly adept at fighting harpies.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHoward is the halfling and a level 10 thief who fights kobolds with a dagger. \r\nLeonard is the hobbit and a level 16 merchant who fights orcs with a crossbow. \r\nPenny is the elf and a level 20 archbishop who fights chimeras with a bolo. \r\nRaj is the gremlin and a level 32 sorcerer who fights giants with fireballs. \r\nSheldon is the ogre and a level 24 paladin who fights harpies with a mace. \n\n\r\nExplanation: \n\r\nThe first step is to determine the actual skill levels of the five players. \n\r\nThe lowest level is 10, held by the character using a dagger (clue 8). \n\r\nFrom (4), the character using a crossbow has an unknown level, let's call it x; the paladin has x+8 and Raj has x+16. Note that x must be greater than 10 and less than or equal to 16, or else x+16 would be greater than 32. \n\r\nThe elf is none of these four players (2, 11, 6), but has a skill level of 10 more than one of them (6). This could be 20, x+10 or x+18. \n\r\nOne skill level has to be 24 (1), two skill levels must have a difference of 4 (7) and one skill level must be twice another (3). \n\r\nIf x=11, then the skill levels are 10, 11, 19, 27 and the elf's is either 20, 21 or 29. None of these is 24; therefore, x isn't 11. Similarly x isn't 12, 13 or 15. \n\r\nIf x=14, then the skill levels are 10, 14, 22, 30 and the elf's is either 20, 24 or 32. This provides a skill level of 24, but for the elf, instead of the ogre; therefore, x isn't 14. \n\r\nTherefore, x=16 and the skill levels are 10 [dagger], 16 [crossbow], 24 [paladin=ogre], and 32 [Raj]. The elf's skill level must be 20, not 26, in order to satisfy clue (7). This means the elf fights chimeras and Leonard's character uses the crossbow. \n\r\nNow that we know the skill levels, we can start building a list of the players, starting with the first clue: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = thief \r\nPlayer 4 = fireballs \r\nPlayer 5 = orcs \n\r\nSince the elf has a skill level of 20, the kobold fighter is level 10 (6), and uses the dagger (8). Penny's character doesn't use the dagger (8), and neither does the ogre, who is level 24. Therefore the thief does: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = orcs \n\r\nNeither Penny's character (12) nor the ogre (4) uses the crossbow [Leonard], so the orc fighter must: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe ogre can't use the bolo, as no one has level 12 (3), so Penny's character uses the bolo and the thief is the halfling. This leaves the ogre using the mace: \n\r\nPlayer 1 = Penny, bolo \r\nPlayer 2 = ogre, level 24, paladin, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThis means that Raj's character, at level 32, must use fireballs, and Penny's character must be the level 20 elf who fights chimeras: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, level 32, fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe ogre, who uses a mace, doesn't fight giants (10); therefore the ogre fights harpies, leaving Raj's character as the giant fighter: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, level 32, giants, fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe hobbit doesn't fight giants (5), so the hobbit must fight orcs, leaving Raj as the gremlin. The gremlin isn't the archbishop or the merchant, and so the gremlin is the sorcerer: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, orcs, crossbow \n\r\nLeonard's character must be the merchant, rather than the archbishop (7), leaving Penny's character as the archbishop: \n\r\nPlayer 1 = Penny, elf, level 20, archbishop, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, merchant, orcs, crossbow \n\r\nHoward's character doesn't fight harpies (13), so that falls to Sheldon's ogre, while Howard's halfling fights kobolds. And that completes the list: \n\r\nPlayer 1 = Penny, elf, level 20, archbishop, chimeras, bolo \r\nPlayer 2 = Sheldon, ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = Howard, halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, merchant, orcs, crossbow\n<|im_start|>answer\nHoward is the halfling and a level 10 thief who fights kobolds with a dagger. \r\nLeonard is the hobbit and a level 16 merchant who fights orcs with a crossbow. \r\nPenny is the elf and a level 20 archbishop who fights chimeras with a bolo. \r\nRaj is the gremlin and a level 32 sorcerer who fights giants with fireballs. \r\nSheldon is the ogre and a level 24 paladin who fights harpies with a mace. \n\n\r\nExplanation: \n\r\nThe first step is to determine the actual skill levels of the five players. \n\r\nThe lowest level is 10, held by the character using a dagger (clue 8). \n\r\nFrom (4), the character using a crossbow has an unknown level, let's call it x; the paladin has x+8 and Raj has x+16. Note that x must be greater than 10 and less than or equal to 16, or else x+16 would be greater than 32. \n\r\nThe elf is none of these four players (2, 11, 6), but has a skill level of 10 more than one of them (6). This could be 20, x+10 or x+18. \n\r\nOne skill level has to be 24 (1), two skill levels must have a difference of 4 (7) and one skill level must be twice another (3). \n\r\nIf x=11, then the skill levels are 10, 11, 19, 27 and the elf's is either 20, 21 or 29. None of these is 24; therefore, x isn't 11. Similarly x isn't 12, 13 or 15. \n\r\nIf x=14, then the skill levels are 10, 14, 22, 30 and the elf's is either 20, 24 or 32. This provides a skill level of 24, but for the elf, instead of the ogre; therefore, x isn't 14. \n\r\nTherefore, x=16 and the skill levels are 10 [dagger], 16 [crossbow], 24 [paladin=ogre], and 32 [Raj]. The elf's skill level must be 20, not 26, in order to satisfy clue (7). This means the elf fights chimeras and Leonard's character uses the crossbow. \n\r\nNow that we know the skill levels, we can start building a list of the players, starting with the first clue: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = thief \r\nPlayer 4 = fireballs \r\nPlayer 5 = orcs \n\r\nSince the elf has a skill level of 20, the kobold fighter is level 10 (6), and uses the dagger (8). Penny's character doesn't use the dagger (8), and neither does the ogre, who is level 24. Therefore the thief does: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = orcs \n\r\nNeither Penny's character (12) nor the ogre (4) uses the crossbow [Leonard], so the orc fighter must: \n\r\nPlayer 1 = Penny \r\nPlayer 2 = ogre, level 24, paladin \r\nPlayer 3 = level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe ogre can't use the bolo, as no one has level 12 (3), so Penny's character uses the bolo and the thief is the halfling. This leaves the ogre using the mace: \n\r\nPlayer 1 = Penny, bolo \r\nPlayer 2 = ogre, level 24, paladin, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThis means that Raj's character, at level 32, must use fireballs, and Penny's character must be the level 20 elf who fights chimeras: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, level 32, fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe ogre, who uses a mace, doesn't fight giants (10); therefore the ogre fights harpies, leaving Raj's character as the giant fighter: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, level 32, giants, fireballs \r\nPlayer 5 = Leonard, level 16, orcs, crossbow \n\r\nThe hobbit doesn't fight giants (5), so the hobbit must fight orcs, leaving Raj as the gremlin. The gremlin isn't the archbishop or the merchant, and so the gremlin is the sorcerer: \n\r\nPlayer 1 = Penny, elf, level 20, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, orcs, crossbow \n\r\nLeonard's character must be the merchant, rather than the archbishop (7), leaving Penny's character as the archbishop: \n\r\nPlayer 1 = Penny, elf, level 20, archbishop, chimeras, bolo \r\nPlayer 2 = ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, merchant, orcs, crossbow \n\r\nHoward's character doesn't fight harpies (13), so that falls to Sheldon's ogre, while Howard's halfling fights kobolds. And that completes the list: \n\r\nPlayer 1 = Penny, elf, level 20, archbishop, chimeras, bolo \r\nPlayer 2 = Sheldon, ogre, level 24, paladin, harpies, mace \r\nPlayer 3 = Howard, halfing, level 10, thief, kobolds, dagger \r\nPlayer 4 = Raj, gremlin, level 32, sorcerer, giants, fireballs \r\nPlayer 5 = Leonard, hobbit, level 16, merchant, orcs, crossbow\n<|im_end|>" }, { "id": "#14457", "title": "Family Fired!", "fun": 2.91, "difficulty": 2.73, "author": "taniapereira99", "desc": "Mary Beem, who was a wife, mother of four and grandmother of nine, was shot to death by an angry relative. Find out the name of the relative it was by piecing together the relationships of each person with the clues below.\n\r\nThe killer's sister was suspicious of her sibling and confirmed her distrust by talking to three people: her grandfather Bob, her cousin Bo, and her uncle (blood relative) Bill. She called the police, and the suspect was apprehended at the victim's funeral service. Only the direct descendants and their spouses were present. (Note: None of Mary's grandchildren were married or had kids, and no two people have the same first name.)\n\n\r\n1. Bill was talking with his brother-in-law Barry. \r\n2. Bart, Buck, and Bruce (who were all brothers) were by their grandmother's casket. \r\n3. Mary's daughter May, who was with her husband Ben, had their two children: Missy and Bernie.\r\n4. Mo, Bob's son-in-law, was comforting his wife Robin, and both were keeping an eye on their sons. \r\n5. Bo was by himself in a corner grieving, while his sister Molly was talking with their cousin Megan. \r\n6. Myra was consoling one of her two children, Brad, who had been very close to his grandmother. \r\n7. Bob was with his daughter Maria. \n\r\nNOTE: Each of the 4 couples has at least 2 kids.\n\r\nWHO IS THE KILLER?", "hint": "Draw a family tree. \n\r\nEach of the 4 children of Mary Beem has a spouse, and each couple has children. Since all must have at least two kids, only one couple has three kids (a total of 9 grandchildren).", "answer": "From the killer's sister's conversation, Bob is Mary's husband, Bill is one of Mary's children, and Bo is a grandchild.\n\r\nFrom clue 1 and 2, Barry was a spouse, and since Bart, Buck and Bruce were all brothers, they were the set of three kids. Clue 3 is straightforward - Mary's daughter May is married to Ben and has two kids: Missy and Bernie.\n\r\nFrom 4, Robin is a daughter and Bob her spouse. From 5, Bo and Molly are siblings and grandchildren (since they have a cousin present). Megan has to be from the last couple. Mo and Robin could only have been parents to the three boys (Bart Bruce and Buck), since all other siblings were a boy and girl.\n\r\nClue 6 gives the name of the remaining child, Brad, who must be a sibling of Megan. Both have a mother by the name of Myra. It is unknown at this point if Myra is a spouse or a direct relative.\n\r\nSince clue 7 says that Bob (Mary's husband) was with his daughter Maria, Myra becomes a spouse. Then, by default, Bo and Molly belong to Maria.\n\r\nSo now, knowing that the killer's sister is COUSIN to Bo, Bill's NIECE, and Bob's GRANDDAUGHTER, the killer must be BERNIE.", "category": "Logic", "date": "08/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMary Beem, who was a wife, mother of four and grandmother of nine, was shot to death by an angry relative. Find out the name of the relative it was by piecing together the relationships of each person with the clues below.\n\r\nThe killer's sister was suspicious of her sibling and confirmed her distrust by talking to three people: her grandfather Bob, her cousin Bo, and her uncle (blood relative) Bill. She called the police, and the suspect was apprehended at the victim's funeral service. Only the direct descendants and their spouses were present. (Note: None of Mary's grandchildren were married or had kids, and no two people have the same first name.)\n\n\r\n1. Bill was talking with his brother-in-law Barry. \r\n2. Bart, Buck, and Bruce (who were all brothers) were by their grandmother's casket. \r\n3. Mary's daughter May, who was with her husband Ben, had their two children: Missy and Bernie.\r\n4. Mo, Bob's son-in-law, was comforting his wife Robin, and both were keeping an eye on their sons. \r\n5. Bo was by himself in a corner grieving, while his sister Molly was talking with their cousin Megan. \r\n6. Myra was consoling one of her two children, Brad, who had been very close to his grandmother. \r\n7. Bob was with his daughter Maria. \n\r\nNOTE: Each of the 4 couples has at least 2 kids.\n\r\nWHO IS THE KILLER?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom the killer's sister's conversation, Bob is Mary's husband, Bill is one of Mary's children, and Bo is a grandchild.\n\r\nFrom clue 1 and 2, Barry was a spouse, and since Bart, Buck and Bruce were all brothers, they were the set of three kids. Clue 3 is straightforward - Mary's daughter May is married to Ben and has two kids: Missy and Bernie.\n\r\nFrom 4, Robin is a daughter and Bob her spouse. From 5, Bo and Molly are siblings and grandchildren (since they have a cousin present). Megan has to be from the last couple. Mo and Robin could only have been parents to the three boys (Bart Bruce and Buck), since all other siblings were a boy and girl.\n\r\nClue 6 gives the name of the remaining child, Brad, who must be a sibling of Megan. Both have a mother by the name of Myra. It is unknown at this point if Myra is a spouse or a direct relative.\n\r\nSince clue 7 says that Bob (Mary's husband) was with his daughter Maria, Myra becomes a spouse. Then, by default, Bo and Molly belong to Maria.\n\r\nSo now, knowing that the killer's sister is COUSIN to Bo, Bill's NIECE, and Bob's GRANDDAUGHTER, the killer must be BERNIE.\n<|im_start|>answer\nFrom the killer's sister's conversation, Bob is Mary's husband, Bill is one of Mary's children, and Bo is a grandchild.\n\r\nFrom clue 1 and 2, Barry was a spouse, and since Bart, Buck and Bruce were all brothers, they were the set of three kids. Clue 3 is straightforward - Mary's daughter May is married to Ben and has two kids: Missy and Bernie.\n\r\nFrom 4, Robin is a daughter and Bob her spouse. From 5, Bo and Molly are siblings and grandchildren (since they have a cousin present). Megan has to be from the last couple. Mo and Robin could only have been parents to the three boys (Bart Bruce and Buck), since all other siblings were a boy and girl.\n\r\nClue 6 gives the name of the remaining child, Brad, who must be a sibling of Megan. Both have a mother by the name of Myra. It is unknown at this point if Myra is a spouse or a direct relative.\n\r\nSince clue 7 says that Bob (Mary's husband) was with his daughter Maria, Myra becomes a spouse. Then, by default, Bo and Molly belong to Maria.\n\r\nSo now, knowing that the killer's sister is COUSIN to Bo, Bill's NIECE, and Bob's GRANDDAUGHTER, the killer must be BERNIE.\n<|im_end|>" }, { "id": "#24332", "title": "It's All Dogs", "fun": 2.91, "difficulty": 2.83, "author": "Philly", "desc": "The four people in this puzzle all competed in different classes of dog agility at a recent competition. The competitions all required the dogs to run over jumps, through tunnels and various other obstacles in as quick a time as possible. Each had a different result - one came first, one third, one fourth and one ninth. All four dogs were each of a different breed. \n\r\nCan you work out who handled which dog, at what level each competed, the place each finished in and the breed of each dog? \n\r\n1. If Tiff finished first, then Terry finished fourth.\r\n2. If Terry finished fourth, then Jago is a collie, otherwise Jago is not a collie.\r\n3. If Jane competed in the Senior class, then she finished third. If Jane competed in Novice, then she finished fourth.\r\n4. The dog that finished ninth was an alsatian. This was either Jago, in which case Jago competed in the Elementary class, or this was Kelly, in which case Terry handled Kelly.\r\n5. Mark won Starters.\r\n6. If Mark's dog is called Patti, then Patti is a labrador, otherwise Patti is a collie.\r\n7. Ruth's dog is called Jago.\r\n8. If Jago finished fourth, then she competed in the Novice class, otherwise she competed in the Senior class.\r\n9. If Patti finished first, then Terry's dog is an alsatian, otherwise Terry's dog is a collie.\r\n10. If Jane's dog is a doberman, then Jane finished fourth, otherwise Jane finished third. \n\r\nHandler's Names: Jane, Mark, Ruth and Terry\r\nDog's Names: Tiff, Patti, Jago and Kelly\r\nBreed: Alsatian, Collie, Labrador and Doberman\r\nLevel: Starters, Elementary, Novice or Senior", "hint": "No hint available.", "answer": "Dog Handler Class Place Breed\r\nTiff Jane Senior 3rd Collie\r\nPatti Mark Starters 1st Labrador\r\nJago Ruth Novice 4th Doberman\r\nKelly Terry Elementary 9th Alsatian", "category": "Logic-Grid", "date": "07/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe four people in this puzzle all competed in different classes of dog agility at a recent competition. The competitions all required the dogs to run over jumps, through tunnels and various other obstacles in as quick a time as possible. Each had a different result - one came first, one third, one fourth and one ninth. All four dogs were each of a different breed. \n\r\nCan you work out who handled which dog, at what level each competed, the place each finished in and the breed of each dog? \n\r\n1. If Tiff finished first, then Terry finished fourth.\r\n2. If Terry finished fourth, then Jago is a collie, otherwise Jago is not a collie.\r\n3. If Jane competed in the Senior class, then she finished third. If Jane competed in Novice, then she finished fourth.\r\n4. The dog that finished ninth was an alsatian. This was either Jago, in which case Jago competed in the Elementary class, or this was Kelly, in which case Terry handled Kelly.\r\n5. Mark won Starters.\r\n6. If Mark's dog is called Patti, then Patti is a labrador, otherwise Patti is a collie.\r\n7. Ruth's dog is called Jago.\r\n8. If Jago finished fourth, then she competed in the Novice class, otherwise she competed in the Senior class.\r\n9. If Patti finished first, then Terry's dog is an alsatian, otherwise Terry's dog is a collie.\r\n10. If Jane's dog is a doberman, then Jane finished fourth, otherwise Jane finished third. \n\r\nHandler's Names: Jane, Mark, Ruth and Terry\r\nDog's Names: Tiff, Patti, Jago and Kelly\r\nBreed: Alsatian, Collie, Labrador and Doberman\r\nLevel: Starters, Elementary, Novice or Senior\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDog Handler Class Place Breed\r\nTiff Jane Senior 3rd Collie\r\nPatti Mark Starters 1st Labrador\r\nJago Ruth Novice 4th Doberman\r\nKelly Terry Elementary 9th Alsatian\n<|im_start|>answer\nDog Handler Class Place Breed\r\nTiff Jane Senior 3rd Collie\r\nPatti Mark Starters 1st Labrador\r\nJago Ruth Novice 4th Doberman\r\nKelly Terry Elementary 9th Alsatian\n<|im_end|>" }, { "id": "#25748", "title": "Europe or Bust", "fun": 2.91, "difficulty": 2.41, "author": "tjm531", "desc": "While not nearly as well-known as its European namesake, when it comes to ancient Greek busts, the Athens Museum in Athens, Georgia, stands head and shoulders above the rest. In fact, the museum's collection of Hellenistic busts is so renowned that five of their most prized pieces, each of which was created by a different sculptor in a different medium and depicts a different Greek deity, has been lent to a different prominent European museum. With such international acclaim for their collection, the curators of the Athens Museum are finding it hard to keep success from going to their heads! From the information provided, can you determine the deity depicted in each sculptor's work, as well as the medium in which each bust was created, and the museum to which each is being lent?\n\r\nSculptor: Lysippus, Myron, Phidias, Praxiteles, Scopas\n\r\nDeity: Apollo, Athena, Demeter, Poseidon, Zeus\n\r\nMedium: Bronze, Gold, Ivory, Limestone, Marble\n\r\nMuseum: Acropolis Museum, British Museum, Glyptothek, The Louvre, Museo Delle Terme\n\r\n1. The statue of Zeus (which isn't the one made by Lysippus) is made from gold.\n\r\n2. Myron's bronze bust isn't the one being loaned to the Museo delle Terme in Rome, Italy (which isn't the museum borrowing the statue of Demeter).\n\r\n3. Scopas was not the sculptor of the limestone bust currently on load to the Glyptothek in Munich, Germany. The bust of Athena isn't made from limestone.\n\r\n4. The British Museum in London, England, is borrowing either the bust of Demeter or the one depicting Zeus.\n\r\n5. The bust carved by Praxiteles (which is on loan to the Louvre in Paris, France) and the one made by Scopas depict Apollo and Demeter, in some order.\n\r\n6. The bust carved from ivory (which isn't the sculpture of Apollo) isn't on loan to the British Museum.", "hint": "Note: The names of the museums have been abbreviated or shortened to fit into the grid spaces.", "answer": "Lysippus, Poseidon, limestone, Glyptothek\n\r\nMyron, Athena, bronze, Acropolis Museum\n\r\nPhidias, Zeus, gold, British Museum\n\r\nPraxiteles, Demeter, ivory, Louvre\n\r\nScopas, Apollo, marble, Museo delle Terme", "category": "Logic-Grid", "date": "09/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile not nearly as well-known as its European namesake, when it comes to ancient Greek busts, the Athens Museum in Athens, Georgia, stands head and shoulders above the rest. In fact, the museum's collection of Hellenistic busts is so renowned that five of their most prized pieces, each of which was created by a different sculptor in a different medium and depicts a different Greek deity, has been lent to a different prominent European museum. With such international acclaim for their collection, the curators of the Athens Museum are finding it hard to keep success from going to their heads! From the information provided, can you determine the deity depicted in each sculptor's work, as well as the medium in which each bust was created, and the museum to which each is being lent?\n\r\nSculptor: Lysippus, Myron, Phidias, Praxiteles, Scopas\n\r\nDeity: Apollo, Athena, Demeter, Poseidon, Zeus\n\r\nMedium: Bronze, Gold, Ivory, Limestone, Marble\n\r\nMuseum: Acropolis Museum, British Museum, Glyptothek, The Louvre, Museo Delle Terme\n\r\n1. The statue of Zeus (which isn't the one made by Lysippus) is made from gold.\n\r\n2. Myron's bronze bust isn't the one being loaned to the Museo delle Terme in Rome, Italy (which isn't the museum borrowing the statue of Demeter).\n\r\n3. Scopas was not the sculptor of the limestone bust currently on load to the Glyptothek in Munich, Germany. The bust of Athena isn't made from limestone.\n\r\n4. The British Museum in London, England, is borrowing either the bust of Demeter or the one depicting Zeus.\n\r\n5. The bust carved by Praxiteles (which is on loan to the Louvre in Paris, France) and the one made by Scopas depict Apollo and Demeter, in some order.\n\r\n6. The bust carved from ivory (which isn't the sculpture of Apollo) isn't on loan to the British Museum.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLysippus, Poseidon, limestone, Glyptothek\n\r\nMyron, Athena, bronze, Acropolis Museum\n\r\nPhidias, Zeus, gold, British Museum\n\r\nPraxiteles, Demeter, ivory, Louvre\n\r\nScopas, Apollo, marble, Museo delle Terme\n<|im_start|>answer\nLysippus, Poseidon, limestone, Glyptothek\n\r\nMyron, Athena, bronze, Acropolis Museum\n\r\nPhidias, Zeus, gold, British Museum\n\r\nPraxiteles, Demeter, ivory, Louvre\n\r\nScopas, Apollo, marble, Museo delle Terme\n<|im_end|>" }, { "id": "#29857", "title": "House Plants", "fun": 2.91, "difficulty": 1.8800000000000001, "author": "peppamintp", "desc": "When Sunshine moved into her new house, she visited each of the five local garden stores (one is Rose Bed) and purchased a different houseplant from each store. She used each of the houseplants to brighten up a different room (including the kitchen). In addition, each of the houseplants came in a pot of a different color. From the information provided, determine the houseplant (one is an African Violet) Sunshine bought at each store, the room in which she put each plant, and the color of each plant's pot.\n\r\n1. The Spider plant came in the red pot. The Spider plant (which is not the one Sunshine put in the bathroom) is not the one Sunshine bought from the Ever Green garden store.\n\r\n2. Sunshine bought the plant in the orange pot from the Green Thumb plant store. The Patience plant is not the one that came in the blue pot nor the yellow pot.\n\r\n3. The plant Sunshine put on the porch (which she bought from Blooms Plus) came in either the blue or yellow pot.\n\r\n4. Sunshine put the plant in the purple pot (which is not the one she bought from the Ever Green garden store) in the den. She bought the Scarborough Lily (which is not the one that came in the blue pot) from the Garden Spot.\n\r\n5. The Lipstick plant, which Sunshine put in the bedroom, is not the one that came in the blue pot.", "hint": "No hint available.", "answer": "1. Blooms Plus, African Violet, porch, blue.\r\n2. Ever Green, Lipstick plant, bedroom, yellow.\r\n3. Garden Spot, Scarborough Lily, den, purple.\r\n4. Green Thumb, Patience plant, bathroom, orange.\r\n5. Rose Bed, Spider plant, kitchen, red.", "category": "Logic-Grid", "date": "04/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Sunshine moved into her new house, she visited each of the five local garden stores (one is Rose Bed) and purchased a different houseplant from each store. She used each of the houseplants to brighten up a different room (including the kitchen). In addition, each of the houseplants came in a pot of a different color. From the information provided, determine the houseplant (one is an African Violet) Sunshine bought at each store, the room in which she put each plant, and the color of each plant's pot.\n\r\n1. The Spider plant came in the red pot. The Spider plant (which is not the one Sunshine put in the bathroom) is not the one Sunshine bought from the Ever Green garden store.\n\r\n2. Sunshine bought the plant in the orange pot from the Green Thumb plant store. The Patience plant is not the one that came in the blue pot nor the yellow pot.\n\r\n3. The plant Sunshine put on the porch (which she bought from Blooms Plus) came in either the blue or yellow pot.\n\r\n4. Sunshine put the plant in the purple pot (which is not the one she bought from the Ever Green garden store) in the den. She bought the Scarborough Lily (which is not the one that came in the blue pot) from the Garden Spot.\n\r\n5. The Lipstick plant, which Sunshine put in the bedroom, is not the one that came in the blue pot.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Blooms Plus, African Violet, porch, blue.\r\n2. Ever Green, Lipstick plant, bedroom, yellow.\r\n3. Garden Spot, Scarborough Lily, den, purple.\r\n4. Green Thumb, Patience plant, bathroom, orange.\r\n5. Rose Bed, Spider plant, kitchen, red.\n<|im_start|>answer\n1. Blooms Plus, African Violet, porch, blue.\r\n2. Ever Green, Lipstick plant, bedroom, yellow.\r\n3. Garden Spot, Scarborough Lily, den, purple.\r\n4. Green Thumb, Patience plant, bathroom, orange.\r\n5. Rose Bed, Spider plant, kitchen, red.\n<|im_end|>" }, { "id": "#52107", "title": "Dollar and Cents", "fun": 2.91, "difficulty": 1.52, "author": "MarcM1098", "desc": "What is wrong with the following logic that \"proves\" 1 dollar = 1 cent? See if you can determine at which line(s) a mistake is made.\n\r\n1 dollar\r\n= 100 cents\r\n= 10 cents x 10 cents\r\n= 1/10 dollar x 1/10 dollar\r\n= 1/100 dollar\r\n= 1 cent", "hint": "Try replacing money (dollar and cent) with length (metre and centimetre).\r\nWhat is 10cm x 10cm?", "answer": "The chain of equality breaks down at the second equals sign.\r\n10 cents x 10 cents = 100 cents^2 (whatever a square cent is). It's like mixing length (metres) with area (square metres).\r\nIt should read 100 cents = 10 x 10 cents.\n\r\nThe same type of error is made again when dollar x dollar is asserted equal to dollar instead of dollar^2.\n\r\nHere is corrected logic:\r\n1 dollar\r\n= 100 cents\r\n= 10 x 10 cents\r\n= 10 x 1/10 dollar\r\n= 10/10 dollar\r\n= 1 dollar", "category": "Logic", "date": "12/30/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is wrong with the following logic that \"proves\" 1 dollar = 1 cent? See if you can determine at which line(s) a mistake is made.\n\r\n1 dollar\r\n= 100 cents\r\n= 10 cents x 10 cents\r\n= 1/10 dollar x 1/10 dollar\r\n= 1/100 dollar\r\n= 1 cent\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe chain of equality breaks down at the second equals sign.\r\n10 cents x 10 cents = 100 cents^2 (whatever a square cent is). It's like mixing length (metres) with area (square metres).\r\nIt should read 100 cents = 10 x 10 cents.\n\r\nThe same type of error is made again when dollar x dollar is asserted equal to dollar instead of dollar^2.\n\r\nHere is corrected logic:\r\n1 dollar\r\n= 100 cents\r\n= 10 x 10 cents\r\n= 10 x 1/10 dollar\r\n= 10/10 dollar\r\n= 1 dollar\n<|im_start|>answer\nThe chain of equality breaks down at the second equals sign.\r\n10 cents x 10 cents = 100 cents^2 (whatever a square cent is). It's like mixing length (metres) with area (square metres).\r\nIt should read 100 cents = 10 x 10 cents.\n\r\nThe same type of error is made again when dollar x dollar is asserted equal to dollar instead of dollar^2.\n\r\nHere is corrected logic:\r\n1 dollar\r\n= 100 cents\r\n= 10 x 10 cents\r\n= 10 x 1/10 dollar\r\n= 10/10 dollar\r\n= 1 dollar\n<|im_end|>" }, { "id": "#43069", "title": "What Do You Have?", "fun": 2.91, "difficulty": 1.94, "author": "whsprec", "desc": "Dylan, Brandon, Chris, and Boris were playing Texas-Hold'em where each player receives two cards. In this hand, each man received two cards in the same suit and no man received cards in the same suit as any other man. The first cards were an ace, a king, a queen and a jack. The second cards were a ten, a nine, an eight, and a seven. From the clues given, determine the first and second card and that suit the cards were in.\n\r\n1) Chris and Boris both have a picture card, and one of them has spades and the other the nine.\r\n2) The man with the king does not have hearts or the seven and neither does Dylan.\r\n3) Brandon does not have the jack or the eight.\r\n4) Chris sits to the right of Brandon who sits to the right of the man with diamonds, who sits to the right of the man with the queen of clubs.\r\n5) The jack, the ten, the eight, and the diamonds are in four different hands.", "hint": "No hint available.", "answer": "Dylan had Queen and eight of Clubs\r\nBrandon had Ace and ten of Hearts\r\nChris had Jack and seven of Spades\r\nBoris had King and nine of Diamonds", "category": "Logic-Grid", "date": "09/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDylan, Brandon, Chris, and Boris were playing Texas-Hold'em where each player receives two cards. In this hand, each man received two cards in the same suit and no man received cards in the same suit as any other man. The first cards were an ace, a king, a queen and a jack. The second cards were a ten, a nine, an eight, and a seven. From the clues given, determine the first and second card and that suit the cards were in.\n\r\n1) Chris and Boris both have a picture card, and one of them has spades and the other the nine.\r\n2) The man with the king does not have hearts or the seven and neither does Dylan.\r\n3) Brandon does not have the jack or the eight.\r\n4) Chris sits to the right of Brandon who sits to the right of the man with diamonds, who sits to the right of the man with the queen of clubs.\r\n5) The jack, the ten, the eight, and the diamonds are in four different hands.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDylan had Queen and eight of Clubs\r\nBrandon had Ace and ten of Hearts\r\nChris had Jack and seven of Spades\r\nBoris had King and nine of Diamonds\n<|im_start|>answer\nDylan had Queen and eight of Clubs\r\nBrandon had Ace and ten of Hearts\r\nChris had Jack and seven of Spades\r\nBoris had King and nine of Diamonds\n<|im_end|>" }, { "id": "#23654", "title": "War Stories 2", "fun": 2.91, "difficulty": 2.8, "author": "Gadget", "desc": "Five veterans were sitting around a bar swapping war stories. From the information provided, determine each veteran's branch of service, the year each was born, and each person's current career.\n\r\n1. The teacher was born in 1971.\n\r\n2. The architect was born the year before Art Smith.\n\r\n3. Susan Wilson, who served in the Coast Guard, is a year younger than the veteran who is now a nurse.\n\r\n4. The Navy veteran, who wasn't born in 1970, isn't Mary Jones who now practices law.\n\r\n5. The Army vet, who has published several books about the war, is neither Bill Johnson nor the oldest of the group.\n\r\n6. The former Marine, who was born in 1969, isn't Art Smith or Mary Jones.", "hint": "No hint available.", "answer": "Mary Jones, 1968, Air Force, Lawyer\n\r\nJohn Brown, 1972, Army, Writer\n\r\nArt Smith, 1971, Navy, Teacher\n\r\nSusan Wilson, 1970, Coast Guard, Architect\n\r\nBill Johnson, 1969, Marines, Nurse", "category": "Logic-Grid", "date": "06/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive veterans were sitting around a bar swapping war stories. From the information provided, determine each veteran's branch of service, the year each was born, and each person's current career.\n\r\n1. The teacher was born in 1971.\n\r\n2. The architect was born the year before Art Smith.\n\r\n3. Susan Wilson, who served in the Coast Guard, is a year younger than the veteran who is now a nurse.\n\r\n4. The Navy veteran, who wasn't born in 1970, isn't Mary Jones who now practices law.\n\r\n5. The Army vet, who has published several books about the war, is neither Bill Johnson nor the oldest of the group.\n\r\n6. The former Marine, who was born in 1969, isn't Art Smith or Mary Jones.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary Jones, 1968, Air Force, Lawyer\n\r\nJohn Brown, 1972, Army, Writer\n\r\nArt Smith, 1971, Navy, Teacher\n\r\nSusan Wilson, 1970, Coast Guard, Architect\n\r\nBill Johnson, 1969, Marines, Nurse\n<|im_start|>answer\nMary Jones, 1968, Air Force, Lawyer\n\r\nJohn Brown, 1972, Army, Writer\n\r\nArt Smith, 1971, Navy, Teacher\n\r\nSusan Wilson, 1970, Coast Guard, Architect\n\r\nBill Johnson, 1969, Marines, Nurse\n<|im_end|>" }, { "id": "#49348", "title": "Missing Price", "fun": 2.91, "difficulty": 1.05, "author": "firefox99", "desc": "When I went to the store, I purchased four items. The following shows the cost of three of the items:\n\r\n$1.50\r\n$3.00\r\n$4.00 \n\r\nThe line to the checkout was pretty long, so to quench my boredom I started playing with my pocket calculator while waiting.\n\r\nI found out, to my surprise, that the four prices of the four items I purchased added to the same number as I got when I multiplied the four prices together.\n\r\nWhat was the price of the fourth item?", "hint": "Add and multiply what you have already.", "answer": "The three prices add to 1.50 + 3.00 + 4.00 = $8.50.\n\r\nThe three prices multiply to 1.50 x 3.00 x 4.00 = $18.00.\n\r\nYou might be able to see that adding another $0.50 will take the total to $9.00, and multiplying by another $0.50 will take the product to $9.00 also, but the answer can also be found using algebra. Let's call the unknown price P:\r\n1.50 + 3.00 + 4.00 + P = 1.50 x 3.00 x 4.00 x P\r\n8.50 + P = 18.00 x P\r\n8.50 = 18.00 x P - P\r\n8.50 = 17.00 x P\r\n8.50/17.00 = P\r\nP = 0.50.", "category": "Math", "date": "03/04/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen I went to the store, I purchased four items. The following shows the cost of three of the items:\n\r\n$1.50\r\n$3.00\r\n$4.00 \n\r\nThe line to the checkout was pretty long, so to quench my boredom I started playing with my pocket calculator while waiting.\n\r\nI found out, to my surprise, that the four prices of the four items I purchased added to the same number as I got when I multiplied the four prices together.\n\r\nWhat was the price of the fourth item?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe three prices add to 1.50 + 3.00 + 4.00 = $8.50.\n\r\nThe three prices multiply to 1.50 x 3.00 x 4.00 = $18.00.\n\r\nYou might be able to see that adding another $0.50 will take the total to $9.00, and multiplying by another $0.50 will take the product to $9.00 also, but the answer can also be found using algebra. Let's call the unknown price P:\r\n1.50 + 3.00 + 4.00 + P = 1.50 x 3.00 x 4.00 x P\r\n8.50 + P = 18.00 x P\r\n8.50 = 18.00 x P - P\r\n8.50 = 17.00 x P\r\n8.50/17.00 = P\r\nP = 0.50.\n<|im_start|>answer\nThe three prices add to 1.50 + 3.00 + 4.00 = $8.50.\n\r\nThe three prices multiply to 1.50 x 3.00 x 4.00 = $18.00.\n\r\nYou might be able to see that adding another $0.50 will take the total to $9.00, and multiplying by another $0.50 will take the product to $9.00 also, but the answer can also be found using algebra. Let's call the unknown price P:\r\n1.50 + 3.00 + 4.00 + P = 1.50 x 3.00 x 4.00 x P\r\n8.50 + P = 18.00 x P\r\n8.50 = 18.00 x P - P\r\n8.50 = 17.00 x P\r\n8.50/17.00 = P\r\nP = 0.50.\n<|im_end|>" }, { "id": "#39073", "title": "Dragon Olympics", "fun": 2.91, "difficulty": 2.36, "author": "dreamlvr1432", "desc": "Every year on Tyria, a competition is held to test the skills of the dragons hatched in the previous year. The citizens of Summerhaven erected an obstacle course consisting of 20 rings and 20 targets, strategically placed, to test agility, fire-breathing skills and accuracy, as well as flight speed. The dragon yearlings (including Azazeal) must hit the targets with their fire-breath while flying through the rings. They will be judged on the number of rings they fly through, the number of targets they hit, and how quickly they complete the course. Each dragon hit a different number of rings (one flew through 10) and targets (one hit 10), and completed the course in a different amount of time (including 15, 20 and 25 mins). Can you determine the outcome of these \"Dragon Olympics\"?\n\r\n1) The dragon that placed 3rd hit the same number of targets as the time it took her to finish the course.\n\r\n2) Krale missed 14 rings, but only missed 2 targets. He placed somewhere ahead of Jaabel.\n\r\n3) 4 of the 5 dragons are as follows: the one that flew through 4 rings, the one that hit 15 targets, the one that finished the course in 23 mins, and the dragon that placed 1st overall.\n\r\n4) Zuria flew through exactly 5 more rings than the number of targets she hit. She hit exactly 5 fewer targets than the dragon that placed 4th.\n\r\n5) Bael hit 5 more targets than the number of rings he flew through. He did not finish the course in the least amount of time, but he did finish faster than the dragon that placed 3rd.\n\r\n6) The dragon that placed 5th completed the course in the same amount of time as the number of rings she flew through.\n\r\n7) In order of overall placement, the 5 dragons are as follows: the one that hit 12 targets, the dragon that finished in 23 mins, the one that hit 20 targets, the one that completed the course in 17 mins, and the one that flew through 15 rings.", "hint": "No hint available.", "answer": "Jaabel, 4 rings, 20 targets, 20 mins, 3rd place\r\nKrale, 6 rings, 18 targets, 23 mins, 2nd place\r\nZuria, 15 rings, 10 targets, 15 mins, 5th place\r\nAzazeal, 20 rings, 12 targets, 25 mins, 1st place\r\nBael, 10 rings, 15 targets, 17 mins, 4th place", "category": "Logic-Grid", "date": "11/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery year on Tyria, a competition is held to test the skills of the dragons hatched in the previous year. The citizens of Summerhaven erected an obstacle course consisting of 20 rings and 20 targets, strategically placed, to test agility, fire-breathing skills and accuracy, as well as flight speed. The dragon yearlings (including Azazeal) must hit the targets with their fire-breath while flying through the rings. They will be judged on the number of rings they fly through, the number of targets they hit, and how quickly they complete the course. Each dragon hit a different number of rings (one flew through 10) and targets (one hit 10), and completed the course in a different amount of time (including 15, 20 and 25 mins). Can you determine the outcome of these \"Dragon Olympics\"?\n\r\n1) The dragon that placed 3rd hit the same number of targets as the time it took her to finish the course.\n\r\n2) Krale missed 14 rings, but only missed 2 targets. He placed somewhere ahead of Jaabel.\n\r\n3) 4 of the 5 dragons are as follows: the one that flew through 4 rings, the one that hit 15 targets, the one that finished the course in 23 mins, and the dragon that placed 1st overall.\n\r\n4) Zuria flew through exactly 5 more rings than the number of targets she hit. She hit exactly 5 fewer targets than the dragon that placed 4th.\n\r\n5) Bael hit 5 more targets than the number of rings he flew through. He did not finish the course in the least amount of time, but he did finish faster than the dragon that placed 3rd.\n\r\n6) The dragon that placed 5th completed the course in the same amount of time as the number of rings she flew through.\n\r\n7) In order of overall placement, the 5 dragons are as follows: the one that hit 12 targets, the dragon that finished in 23 mins, the one that hit 20 targets, the one that completed the course in 17 mins, and the one that flew through 15 rings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJaabel, 4 rings, 20 targets, 20 mins, 3rd place\r\nKrale, 6 rings, 18 targets, 23 mins, 2nd place\r\nZuria, 15 rings, 10 targets, 15 mins, 5th place\r\nAzazeal, 20 rings, 12 targets, 25 mins, 1st place\r\nBael, 10 rings, 15 targets, 17 mins, 4th place\n<|im_start|>answer\nJaabel, 4 rings, 20 targets, 20 mins, 3rd place\r\nKrale, 6 rings, 18 targets, 23 mins, 2nd place\r\nZuria, 15 rings, 10 targets, 15 mins, 5th place\r\nAzazeal, 20 rings, 12 targets, 25 mins, 1st place\r\nBael, 10 rings, 15 targets, 17 mins, 4th place\n<|im_end|>" }, { "id": "#36874", "title": "More Cats and Dogs", "fun": 2.91, "difficulty": 1.52, "author": "pokpic", "desc": "There are four people named John, Jack, Joe, and Robert. Their last names are: Lee, Ferrio, Spret, and Keller. They each have a cat and a dog. The four people don't know each other but, coincidently, the cats and dogs have the same names: Spot, Tiger, Dixie, and Jumper. \r\nNote: No person has a cat and dog of the same name.\n\r\nFirst Names: John, Jack, Joe, and Robert\r\nLast Names: Lee, Ferrio, Spret, Keller\r\nDogs: Spot, Tiger, Dixie, and Jumper\r\nCats: Spot, Tiger, Dixie, and Jumper\n\r\n1. John's dog and Mr. Keller's cat have the same name.\r\n2. The first and last names of the person who owns Tiger the cat have the same amount of letters.\r\n3. Mr. Lee's dog Jumper scared the heck out of Jack's cat Spot when Jack was moving into the apartment next to Mr. Lee's, but they hadn't met yet. \r\n4. Mr. Spret's dog and Mr. Ferrio's cat have the same name.\r\n5. Robert's pets are named Dixie and Jumper who love to play with each other.\r\n6. Robert's last name is Spret.", "hint": "No hint available.", "answer": "John Ferrio owns Spot the dog and Dixie the cat.\r\nJack Keller owns Tiger the dog and Spot the cat.\r\nJoe Lee owns Jumper the dog and Tiger the cat.\r\nRobert Spret owns Dixie the dog and Jumper the cat.", "category": "Logic-Grid", "date": "06/07/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four people named John, Jack, Joe, and Robert. Their last names are: Lee, Ferrio, Spret, and Keller. They each have a cat and a dog. The four people don't know each other but, coincidently, the cats and dogs have the same names: Spot, Tiger, Dixie, and Jumper. \r\nNote: No person has a cat and dog of the same name.\n\r\nFirst Names: John, Jack, Joe, and Robert\r\nLast Names: Lee, Ferrio, Spret, Keller\r\nDogs: Spot, Tiger, Dixie, and Jumper\r\nCats: Spot, Tiger, Dixie, and Jumper\n\r\n1. John's dog and Mr. Keller's cat have the same name.\r\n2. The first and last names of the person who owns Tiger the cat have the same amount of letters.\r\n3. Mr. Lee's dog Jumper scared the heck out of Jack's cat Spot when Jack was moving into the apartment next to Mr. Lee's, but they hadn't met yet. \r\n4. Mr. Spret's dog and Mr. Ferrio's cat have the same name.\r\n5. Robert's pets are named Dixie and Jumper who love to play with each other.\r\n6. Robert's last name is Spret.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn Ferrio owns Spot the dog and Dixie the cat.\r\nJack Keller owns Tiger the dog and Spot the cat.\r\nJoe Lee owns Jumper the dog and Tiger the cat.\r\nRobert Spret owns Dixie the dog and Jumper the cat.\n<|im_start|>answer\nJohn Ferrio owns Spot the dog and Dixie the cat.\r\nJack Keller owns Tiger the dog and Spot the cat.\r\nJoe Lee owns Jumper the dog and Tiger the cat.\r\nRobert Spret owns Dixie the dog and Jumper the cat.\n<|im_end|>" }, { "id": "#27304", "title": "Essential Essences and Elements", "fun": 2.91, "difficulty": 2.91, "author": "Splatt", "desc": "Sari the Apothecary decided to branch out and also offer essential oils and flower essences to her clients, in addition to her normal products. She would address the elements they were lacking, associated with general life issues they had with her new product line. After taking a course, she promptly forgot which essence, element and essential oil went with which symptom/need. She did have this list of clues. Help her figure it out before she loses all her clientele!\n\r\nEssential Oils: Geranium, Lavender, Sandalwood, Lime, Eucalyptus\r\nFlower Essences: Sweet Chestnut, Cerato, Crab Apple, Cherry Plum, Pine\r\nElements: Fire, Air, Earth, Water, Air\r\nEO Properties: clears Nasal passages and stimulates skin to release toxins; assists Emotional release process; grounding into Power and Truth; release Density; augments ability to release Grudges \r\nFE Properties: master Forgiveness of self and others; transcend Ego/negative ego; transcend Shame; transcend inner/outer Judgment; release Pain \n\n\r\n1.\tIf Sandalwood goes with Crab Apple, then Grudges goes with Fire. Otherwise Shame goes with Emotions and Cerato goes with Air.\n\r\n2.\tSweet chestnut is associated with 2 of these 3: releasing Pain, Eucalyptus, Fire.\n\r\n3.\tEither Judgment goes with Earth, or Cerato goes with Emotions.\n\r\n4.\tEssences are: the one with Lime, Cherry plum, Fire, Power/Truth, and Pain.\n\r\n5.\tEach in the first group goes with a different one of the second group. One of the 4 won't be included with the first 3: (Ego, Judgment, Grudges) (Water, Forgiveness, Lavender, Eucalyptus)\n\r\n6.\tForgiveness must be fueled by fire. Water always goes with Emotions, but not with Ego. Sniff Eucalyptus frequently when you have a stuffy nose.\n\r\n7.\tOf the five, there are Power/Truth, Pain, Fire, Cerato and Lavender.\n\r\n8.\tEarthy Sandalwood helps you feel grounded and its essence counterpart helps with Shame.", "hint": "If you're *really* thorough, go through the clues just once. Otherwise, it takes at least three times through to get all the answers. Don't give up!", "answer": "Yippee - fun grid patterns \n\r\n1)\tGeranium goes with Pine, fire, releasing grudges and mastering forgiveness of self and others.\n\r\n2)\tLavender goes with Cherry Plum, air, releasing density and transcending ego/negative ego.\n\r\n3)\tSandalwood goes with Crab Apple, earth, grounding into one's power and truth, transcending shame. \n\r\n4)\tLime goes with Cerato, water, releasing emotions, and transcending judgment of self and others. \n\r\n5)\tEucalyptus goes with Sweet Chestnut, air, clears nasal passage and stimulates toxin release through skin, and releasing pain. \n\r\nLavender is the only essential oil listed that can be used \"neat\", meaning directly on skin. Otherwise, you want to sniff, use in a water mister, or make a salt scrub with small amounts of the oils. \n\r\nFlower essences are ingested. You either add a couple drops to water or you drop them right on your tongue.\n\r\nEssential oils and flower essences have subtle effects and it takes time to notice the difference in oneself.", "category": "Logic-Grid", "date": "12/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSari the Apothecary decided to branch out and also offer essential oils and flower essences to her clients, in addition to her normal products. She would address the elements they were lacking, associated with general life issues they had with her new product line. After taking a course, she promptly forgot which essence, element and essential oil went with which symptom/need. She did have this list of clues. Help her figure it out before she loses all her clientele!\n\r\nEssential Oils: Geranium, Lavender, Sandalwood, Lime, Eucalyptus\r\nFlower Essences: Sweet Chestnut, Cerato, Crab Apple, Cherry Plum, Pine\r\nElements: Fire, Air, Earth, Water, Air\r\nEO Properties: clears Nasal passages and stimulates skin to release toxins; assists Emotional release process; grounding into Power and Truth; release Density; augments ability to release Grudges \r\nFE Properties: master Forgiveness of self and others; transcend Ego/negative ego; transcend Shame; transcend inner/outer Judgment; release Pain \n\n\r\n1.\tIf Sandalwood goes with Crab Apple, then Grudges goes with Fire. Otherwise Shame goes with Emotions and Cerato goes with Air.\n\r\n2.\tSweet chestnut is associated with 2 of these 3: releasing Pain, Eucalyptus, Fire.\n\r\n3.\tEither Judgment goes with Earth, or Cerato goes with Emotions.\n\r\n4.\tEssences are: the one with Lime, Cherry plum, Fire, Power/Truth, and Pain.\n\r\n5.\tEach in the first group goes with a different one of the second group. One of the 4 won't be included with the first 3: (Ego, Judgment, Grudges) (Water, Forgiveness, Lavender, Eucalyptus)\n\r\n6.\tForgiveness must be fueled by fire. Water always goes with Emotions, but not with Ego. Sniff Eucalyptus frequently when you have a stuffy nose.\n\r\n7.\tOf the five, there are Power/Truth, Pain, Fire, Cerato and Lavender.\n\r\n8.\tEarthy Sandalwood helps you feel grounded and its essence counterpart helps with Shame.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYippee - fun grid patterns \n\r\n1)\tGeranium goes with Pine, fire, releasing grudges and mastering forgiveness of self and others.\n\r\n2)\tLavender goes with Cherry Plum, air, releasing density and transcending ego/negative ego.\n\r\n3)\tSandalwood goes with Crab Apple, earth, grounding into one's power and truth, transcending shame. \n\r\n4)\tLime goes with Cerato, water, releasing emotions, and transcending judgment of self and others. \n\r\n5)\tEucalyptus goes with Sweet Chestnut, air, clears nasal passage and stimulates toxin release through skin, and releasing pain. \n\r\nLavender is the only essential oil listed that can be used \"neat\", meaning directly on skin. Otherwise, you want to sniff, use in a water mister, or make a salt scrub with small amounts of the oils. \n\r\nFlower essences are ingested. You either add a couple drops to water or you drop them right on your tongue.\n\r\nEssential oils and flower essences have subtle effects and it takes time to notice the difference in oneself.\n<|im_start|>answer\nYippee - fun grid patterns \n\r\n1)\tGeranium goes with Pine, fire, releasing grudges and mastering forgiveness of self and others.\n\r\n2)\tLavender goes with Cherry Plum, air, releasing density and transcending ego/negative ego.\n\r\n3)\tSandalwood goes with Crab Apple, earth, grounding into one's power and truth, transcending shame. \n\r\n4)\tLime goes with Cerato, water, releasing emotions, and transcending judgment of self and others. \n\r\n5)\tEucalyptus goes with Sweet Chestnut, air, clears nasal passage and stimulates toxin release through skin, and releasing pain. \n\r\nLavender is the only essential oil listed that can be used \"neat\", meaning directly on skin. Otherwise, you want to sniff, use in a water mister, or make a salt scrub with small amounts of the oils. \n\r\nFlower essences are ingested. You either add a couple drops to water or you drop them right on your tongue.\n\r\nEssential oils and flower essences have subtle effects and it takes time to notice the difference in oneself.\n<|im_end|>" }, { "id": "#52323", "title": "Three Married Couples and a Widow", "fun": 2.9, "difficulty": 1.61, "author": "wimpykidfan37", "desc": "Four women, Audrey, Brenda, Charlotte, and Dawn, and three men, Edgar, Frank, and George, are tennis players. These seven people consist of three heterosexual married couples, plus one widow. Whenever they play doubles, no man is on the same team as his wife. If a game of doubles is played, there is never more than one couple in this game. One day, four games were played:\n\r\n1. Audrey and Edgar vs Brenda and Frank\r\n2. Audrey and George vs Dawn and Frank\r\n3. Brenda and Charlotte vs Frank and George\r\n4. Charlotte and Edgar vs Dawn and George\n\r\nWho is the widow?", "hint": "No hint available.", "answer": "Charlotte is the widow.\n\r\nFirst, we must figure out who Frank's wife is. From games 1 and 2, we know that Frank's wife cannot be Brenda or Dawn and must be Audrey or Charlotte. Let's make Frank's wife Charlotte and see what happens.\n\r\nFrom games 2 and 4, we know that George's wife cannot be Audrey or Dawn, and it obviously cannot be Charlotte either, so it must be Brenda. But game 3 features both Brenda and George, and Charlotte and Frank. So Frank's wife cannot be Charlotte, and must therefore be Audrey.\n\r\nFrom game 4, we know that George's wife cannot be Dawn, and it cannot be Audrey either, so it must be either Brenda or Charlotte. If George's wife is Charlotte, then Edgar's wife cannot be Audrey or Charlotte, and must be Brenda or Dawn.\n\r\nBut now Edgar's wife cannot be Brenda because game 1 features both Audrey and Frank, and Brenda and Edgar. It cannot be Dawn either because game 4 features both Charlotte and George, and Dawn and Edgar. Therefore, George's wife cannot be Charlotte and must be Brenda.\n\r\nIf Frank's wife is Audrey and George's wife is Brenda, Edgar's wife must be Charlotte or Dawn. Game 4 tells us that Edgar's wife must be Dawn. Now that Audrey, Brenda, and Dawn have all been assigned husbands, this leaves only Charlotte without a husband.", "category": "Logic", "date": "01/02/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour women, Audrey, Brenda, Charlotte, and Dawn, and three men, Edgar, Frank, and George, are tennis players. These seven people consist of three heterosexual married couples, plus one widow. Whenever they play doubles, no man is on the same team as his wife. If a game of doubles is played, there is never more than one couple in this game. One day, four games were played:\n\r\n1. Audrey and Edgar vs Brenda and Frank\r\n2. Audrey and George vs Dawn and Frank\r\n3. Brenda and Charlotte vs Frank and George\r\n4. Charlotte and Edgar vs Dawn and George\n\r\nWho is the widow?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCharlotte is the widow.\n\r\nFirst, we must figure out who Frank's wife is. From games 1 and 2, we know that Frank's wife cannot be Brenda or Dawn and must be Audrey or Charlotte. Let's make Frank's wife Charlotte and see what happens.\n\r\nFrom games 2 and 4, we know that George's wife cannot be Audrey or Dawn, and it obviously cannot be Charlotte either, so it must be Brenda. But game 3 features both Brenda and George, and Charlotte and Frank. So Frank's wife cannot be Charlotte, and must therefore be Audrey.\n\r\nFrom game 4, we know that George's wife cannot be Dawn, and it cannot be Audrey either, so it must be either Brenda or Charlotte. If George's wife is Charlotte, then Edgar's wife cannot be Audrey or Charlotte, and must be Brenda or Dawn.\n\r\nBut now Edgar's wife cannot be Brenda because game 1 features both Audrey and Frank, and Brenda and Edgar. It cannot be Dawn either because game 4 features both Charlotte and George, and Dawn and Edgar. Therefore, George's wife cannot be Charlotte and must be Brenda.\n\r\nIf Frank's wife is Audrey and George's wife is Brenda, Edgar's wife must be Charlotte or Dawn. Game 4 tells us that Edgar's wife must be Dawn. Now that Audrey, Brenda, and Dawn have all been assigned husbands, this leaves only Charlotte without a husband.\n<|im_start|>answer\nCharlotte is the widow.\n\r\nFirst, we must figure out who Frank's wife is. From games 1 and 2, we know that Frank's wife cannot be Brenda or Dawn and must be Audrey or Charlotte. Let's make Frank's wife Charlotte and see what happens.\n\r\nFrom games 2 and 4, we know that George's wife cannot be Audrey or Dawn, and it obviously cannot be Charlotte either, so it must be Brenda. But game 3 features both Brenda and George, and Charlotte and Frank. So Frank's wife cannot be Charlotte, and must therefore be Audrey.\n\r\nFrom game 4, we know that George's wife cannot be Dawn, and it cannot be Audrey either, so it must be either Brenda or Charlotte. If George's wife is Charlotte, then Edgar's wife cannot be Audrey or Charlotte, and must be Brenda or Dawn.\n\r\nBut now Edgar's wife cannot be Brenda because game 1 features both Audrey and Frank, and Brenda and Edgar. It cannot be Dawn either because game 4 features both Charlotte and George, and Dawn and Edgar. Therefore, George's wife cannot be Charlotte and must be Brenda.\n\r\nIf Frank's wife is Audrey and George's wife is Brenda, Edgar's wife must be Charlotte or Dawn. Game 4 tells us that Edgar's wife must be Dawn. Now that Audrey, Brenda, and Dawn have all been assigned husbands, this leaves only Charlotte without a husband.\n<|im_end|>" }, { "id": "#25526", "title": "Code Grid", "fun": 2.9, "difficulty": 2.64, "author": "haldir", "desc": "Can you break this code?\n\r\nShift three. Caps lock one. Shift six.\n\r\nTab six. Tab nine. Tab seven.\n\r\nTab four. Tab three. Caps lock one. Caps lock three.\n\r\nTab five. Caps lock six. Tab eight. Caps lock two. Shift 10.", "hint": "Every sentence is a letter.", "answer": "It spells out \"Can you read this?\"\n\r\nUse your keyboard like a grid. Tab, caps lock and shift are the vertical side of the grid and one through nine are the horizontal side of the grid. For example shift five would be B.", "category": "Logic", "date": "08/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you break this code?\n\r\nShift three. Caps lock one. Shift six.\n\r\nTab six. Tab nine. Tab seven.\n\r\nTab four. Tab three. Caps lock one. Caps lock three.\n\r\nTab five. Caps lock six. Tab eight. Caps lock two. Shift 10.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt spells out \"Can you read this?\"\n\r\nUse your keyboard like a grid. Tab, caps lock and shift are the vertical side of the grid and one through nine are the horizontal side of the grid. For example shift five would be B.\n<|im_start|>answer\nIt spells out \"Can you read this?\"\n\r\nUse your keyboard like a grid. Tab, caps lock and shift are the vertical side of the grid and one through nine are the horizontal side of the grid. For example shift five would be B.\n<|im_end|>" }, { "id": "#29014", "title": "Feel the Romance", "fun": 2.9, "difficulty": 1.81, "author": "Punk_Rocker", "desc": "Five girls got tickets to Warped Tour; all of their favorite bands are there this year. However, one band specifically caught their eyes: My Chemical Romance. Each of them cannot wait to see their favorite band member and hear their favorite song played! Plus, they just HAVE to buy some MCR merchandise!\n\r\nGirls: Taylor, Ren, Skylar, Elana, Andi. \n\r\nMembers: Gerard Way (Vocals), Ray Toro (Lead Guitar), Frank Iero (Rhythm Guitar), Mikey Way (Bass Guitar), Bob Bryar (Drums).\n\r\nFavorite Songs: Skylines and Turnstiles (Skylines), Headfirst for Halos (Halos), To the End, Cubicles, Drowning Lessons (Drowning).\n\r\nMerch: T-Shirt, Poster, Pin, Bag, CD.\n\r\nCan you figure out who is obsessed with which band member, who loves what song, and who buys what? Good luck and here are the clues:\n\r\n1. The girl whose favorite song is Cubicles also loves Frank.\r\n2. The one who couldn't stop staring at Bob bought the pin.\r\n3. The girl who loves Gerard bought the bag.\r\n4. Ren cheered especially loud when they played Headfirst for Halos.\r\n5. Mikey's biggest fan's favorite song is Skylines and Turnstiles.\r\n6. Elana has a strange love for drummers.\r\n7. Taylor got the T-Shirt because her favorite band member was on the front.\r\n8. Skylar and Ren are sisters, and coincidentally like the two brothers in the band.\r\n9. The girl who bought the CD got it specifically to hear her favorite song, To the End.\n\r\n(Note: The names in parentheses are for the Logic Grid Solver; the full titles would not fit.)", "hint": "Gerard and Mikey are brothers.", "answer": "Taylor: Frank, Cubicles, T-Shirt.\r\nRen: Gerard, Headfirst for Halos, Bag.\r\nSkylar: Mikey, Skylines and Turnstiles, Poster.\r\nElana: Bob, Drowning Lessons, Pin.\r\nAndi: Ray, To the End, CD.", "category": "Logic-Grid", "date": "03/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive girls got tickets to Warped Tour; all of their favorite bands are there this year. However, one band specifically caught their eyes: My Chemical Romance. Each of them cannot wait to see their favorite band member and hear their favorite song played! Plus, they just HAVE to buy some MCR merchandise!\n\r\nGirls: Taylor, Ren, Skylar, Elana, Andi. \n\r\nMembers: Gerard Way (Vocals), Ray Toro (Lead Guitar), Frank Iero (Rhythm Guitar), Mikey Way (Bass Guitar), Bob Bryar (Drums).\n\r\nFavorite Songs: Skylines and Turnstiles (Skylines), Headfirst for Halos (Halos), To the End, Cubicles, Drowning Lessons (Drowning).\n\r\nMerch: T-Shirt, Poster, Pin, Bag, CD.\n\r\nCan you figure out who is obsessed with which band member, who loves what song, and who buys what? Good luck and here are the clues:\n\r\n1. The girl whose favorite song is Cubicles also loves Frank.\r\n2. The one who couldn't stop staring at Bob bought the pin.\r\n3. The girl who loves Gerard bought the bag.\r\n4. Ren cheered especially loud when they played Headfirst for Halos.\r\n5. Mikey's biggest fan's favorite song is Skylines and Turnstiles.\r\n6. Elana has a strange love for drummers.\r\n7. Taylor got the T-Shirt because her favorite band member was on the front.\r\n8. Skylar and Ren are sisters, and coincidentally like the two brothers in the band.\r\n9. The girl who bought the CD got it specifically to hear her favorite song, To the End.\n\r\n(Note: The names in parentheses are for the Logic Grid Solver; the full titles would not fit.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTaylor: Frank, Cubicles, T-Shirt.\r\nRen: Gerard, Headfirst for Halos, Bag.\r\nSkylar: Mikey, Skylines and Turnstiles, Poster.\r\nElana: Bob, Drowning Lessons, Pin.\r\nAndi: Ray, To the End, CD.\n<|im_start|>answer\nTaylor: Frank, Cubicles, T-Shirt.\r\nRen: Gerard, Headfirst for Halos, Bag.\r\nSkylar: Mikey, Skylines and Turnstiles, Poster.\r\nElana: Bob, Drowning Lessons, Pin.\r\nAndi: Ray, To the End, CD.\n<|im_end|>" }, { "id": "#35136", "title": "The River Ave Friends", "fun": 2.9, "difficulty": 1.94, "author": "scallio", "desc": "Six friends live in six houses along River Avenue that runs East/West. Can you determine the color of each friend's house and in which order they are located from West to East?\n\r\nHouse colors: gray, white, blue, red, brown, yellow\r\nFriends: Lily, Doreen, Kayla, Brian, Dirk, Tom\r\n(These first three friends are girls and the last three boys.)\n\r\n1.\tDirk lives in the house farthest to the East.\n\r\n2.\tNeither the brown or white house is at either end.\n\r\n3.\tLily lives west of Doreen, Tom and Brian.\n\r\n4.\tThe red house is located at the far West end.\n\r\n5.\tGirls live in both of the houses located in the center of the avenue.\n\r\n6.\tBoys live in the white and yellow houses but a girl lives in the brown.\n\r\n7.\tThe gray house is just west of the brown house, which is just west of the yellow house.\n\r\n8.\tKayla has just two friends that live east of her; Dirk and Brian.\n\r\n9.\tThe white house is located toward the west end of the avenue.", "hint": "HINT:\n\r\nDoreen lives in the gray house.\n\n\n\n\n\n\n\r\nAnother hint? Move down.\n\n\n\n\n\n\n\n\n\r\nKayla lives in the brown house.", "answer": "West to East:\r\n1st house: Lily - red\r\n2nd house: Tom - white\r\n3rd house: Doreen - gray\r\n4th house: Kayla - brown\r\n5th house: Brian - yellow\r\nLast house: Dirk - blue", "category": "Logic", "date": "01/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix friends live in six houses along River Avenue that runs East/West. Can you determine the color of each friend's house and in which order they are located from West to East?\n\r\nHouse colors: gray, white, blue, red, brown, yellow\r\nFriends: Lily, Doreen, Kayla, Brian, Dirk, Tom\r\n(These first three friends are girls and the last three boys.)\n\r\n1.\tDirk lives in the house farthest to the East.\n\r\n2.\tNeither the brown or white house is at either end.\n\r\n3.\tLily lives west of Doreen, Tom and Brian.\n\r\n4.\tThe red house is located at the far West end.\n\r\n5.\tGirls live in both of the houses located in the center of the avenue.\n\r\n6.\tBoys live in the white and yellow houses but a girl lives in the brown.\n\r\n7.\tThe gray house is just west of the brown house, which is just west of the yellow house.\n\r\n8.\tKayla has just two friends that live east of her; Dirk and Brian.\n\r\n9.\tThe white house is located toward the west end of the avenue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWest to East:\r\n1st house: Lily - red\r\n2nd house: Tom - white\r\n3rd house: Doreen - gray\r\n4th house: Kayla - brown\r\n5th house: Brian - yellow\r\nLast house: Dirk - blue\n<|im_start|>answer\nWest to East:\r\n1st house: Lily - red\r\n2nd house: Tom - white\r\n3rd house: Doreen - gray\r\n4th house: Kayla - brown\r\n5th house: Brian - yellow\r\nLast house: Dirk - blue\n<|im_end|>" }, { "id": "#39236", "title": "11 Bottles Of ?", "fun": 2.9, "difficulty": 1.6400000000000001, "author": "relay", "desc": "There are 11 bottles sitting in front of you. You have been told that you're slowly dying and that there is only one antidote here to help you. You must drink from one of these bottles. There are Empty Bottles, Water Bottles, Poisoned Bottles, and one Antidote. Drinking from a Poisoned Bottle will surely kill you.\r\nYou know the following facts about the bottles...\n\r\nBottles:\r\n1)\r\n2) Empty Bottle\r\n3)\r\n4)\r\n5)\r\n6) Poisoned Bottle\r\n7)\r\n8)\r\n9) Empty Bottle\r\n10)\r\n11) Poisoned Bottle\n\r\n1) There are 4 Empty Bottles in front of you.\r\n2) There is always a Poisoned Bottle next to another Poisoned Bottle, but never on both sides.\r\n3) There are two other bottles between the Water Bottles. \r\n4) There are only 2 Water Bottles.\r\n5) Empty Bottles are just like Poisoned Bottles, there is always one of the same kind next to it but never on both sides.\r\n6) The Antidote is in between a Poisoned Bottle and an Empty Bottle.", "hint": "No hint available.", "answer": "Bottles:\r\n1) Water \r\n2) Empty \r\n3) Empty\r\n4) Water\r\n5) Poison\r\n6) Poison\r\n7) Antidote\r\n8) Empty\r\n9) Empty\r\n10) Poison\r\n11) Poison", "category": "Logic", "date": "11/17/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 11 bottles sitting in front of you. You have been told that you're slowly dying and that there is only one antidote here to help you. You must drink from one of these bottles. There are Empty Bottles, Water Bottles, Poisoned Bottles, and one Antidote. Drinking from a Poisoned Bottle will surely kill you.\r\nYou know the following facts about the bottles...\n\r\nBottles:\r\n1)\r\n2) Empty Bottle\r\n3)\r\n4)\r\n5)\r\n6) Poisoned Bottle\r\n7)\r\n8)\r\n9) Empty Bottle\r\n10)\r\n11) Poisoned Bottle\n\r\n1) There are 4 Empty Bottles in front of you.\r\n2) There is always a Poisoned Bottle next to another Poisoned Bottle, but never on both sides.\r\n3) There are two other bottles between the Water Bottles. \r\n4) There are only 2 Water Bottles.\r\n5) Empty Bottles are just like Poisoned Bottles, there is always one of the same kind next to it but never on both sides.\r\n6) The Antidote is in between a Poisoned Bottle and an Empty Bottle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBottles:\r\n1) Water \r\n2) Empty \r\n3) Empty\r\n4) Water\r\n5) Poison\r\n6) Poison\r\n7) Antidote\r\n8) Empty\r\n9) Empty\r\n10) Poison\r\n11) Poison\n<|im_start|>answer\nBottles:\r\n1) Water \r\n2) Empty \r\n3) Empty\r\n4) Water\r\n5) Poison\r\n6) Poison\r\n7) Antidote\r\n8) Empty\r\n9) Empty\r\n10) Poison\r\n11) Poison\n<|im_end|>" }, { "id": "#34467", "title": "The Case of the Missing Ice Cream Sandwich", "fun": 2.9, "difficulty": 2.27, "author": "calmsavior", "desc": "Earl and Joe are best friends, who secretly sent encrypted messages to each other ever since they were little. Now they're both in college, and Earl had aced his midterm on cryptology.\n\r\nJoe congratulated Earl by buying him a Neapolitan ice cream sandwich (Joe couldn't afford much), hid the sandwich somewhere in Joe's house, and he later encrypted, on a piece of paper, where he hid the sandwich. Soon after Joe hid the sandwich, he realized he placed the sandwich near the sun, meaning that he'd better relocate it, otherwise the sandwich would melt.\n\r\nUnfortunately, Joe, being extremely forgetful, had misplaced the sandwich and forgot where he put it. He still had the encryption note in his hand, and so he turned to his best friend Earl to solve it.\n\r\n\"I was gonna give you this later, but you gotta hurry now and find the ice cream I got you, otherwise it'll melt.\"\n\r\nThe note said this:\n\r\nT embrace embrace pound embrace kiss\n\r\nWhere did he hide the ice cream sandwich?", "hint": "\"Pound\" is not referring to the verb or money, but rather the measurement.\n\r\nAlso, pound is the only word not being encrypted for one letter.", "answer": "He hid the ice cream sandwich in the TOOLBOX.\n\r\nT = T\n\r\nEmbrace = hug = O\r\nKiss = X\r\n(as in XOXO: Hugs and Kisses)\n\r\npound = lb.\n\r\nT [embrace][embrace](pound)[embrace]{kiss} = T [O][O](lb)[O]{X} = TOOLBOX.\n\r\nEarl solved the cryptogram and found the ice cream in the toolbox. Unfortunately Earl, being a bit of a chocoholic, ate only the chocolate of the sandwich, leaving vanilla and strawberry.", "category": "Logic", "date": "12/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEarl and Joe are best friends, who secretly sent encrypted messages to each other ever since they were little. Now they're both in college, and Earl had aced his midterm on cryptology.\n\r\nJoe congratulated Earl by buying him a Neapolitan ice cream sandwich (Joe couldn't afford much), hid the sandwich somewhere in Joe's house, and he later encrypted, on a piece of paper, where he hid the sandwich. Soon after Joe hid the sandwich, he realized he placed the sandwich near the sun, meaning that he'd better relocate it, otherwise the sandwich would melt.\n\r\nUnfortunately, Joe, being extremely forgetful, had misplaced the sandwich and forgot where he put it. He still had the encryption note in his hand, and so he turned to his best friend Earl to solve it.\n\r\n\"I was gonna give you this later, but you gotta hurry now and find the ice cream I got you, otherwise it'll melt.\"\n\r\nThe note said this:\n\r\nT embrace embrace pound embrace kiss\n\r\nWhere did he hide the ice cream sandwich?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe hid the ice cream sandwich in the TOOLBOX.\n\r\nT = T\n\r\nEmbrace = hug = O\r\nKiss = X\r\n(as in XOXO: Hugs and Kisses)\n\r\npound = lb.\n\r\nT [embrace][embrace](pound)[embrace]{kiss} = T [O][O](lb)[O]{X} = TOOLBOX.\n\r\nEarl solved the cryptogram and found the ice cream in the toolbox. Unfortunately Earl, being a bit of a chocoholic, ate only the chocolate of the sandwich, leaving vanilla and strawberry.\n<|im_start|>answer\nHe hid the ice cream sandwich in the TOOLBOX.\n\r\nT = T\n\r\nEmbrace = hug = O\r\nKiss = X\r\n(as in XOXO: Hugs and Kisses)\n\r\npound = lb.\n\r\nT [embrace][embrace](pound)[embrace]{kiss} = T [O][O](lb)[O]{X} = TOOLBOX.\n\r\nEarl solved the cryptogram and found the ice cream in the toolbox. Unfortunately Earl, being a bit of a chocoholic, ate only the chocolate of the sandwich, leaving vanilla and strawberry.\n<|im_end|>" }, { "id": "#40624", "title": "Vacation Book Assignment", "fun": 2.9, "difficulty": 2.37, "author": "dswilborn", "desc": "Five students from a South Carolina high school were each assigned a different book to read over Winter Break. Each of them had vacation plans in different locations, three to places in the United States and two to Canada and Mexico. Determine from the clues the full name of each student, the book each one was assigned, and the vacation spot each one visited.\n\r\n1. The five students, in no particular order are: Jessica, the student who visited Mexico, Mr. Tyler, the student who read \"The Call of the Wild\", and the student who visited Hawaii.\n\r\n2. Only one student rode in a car to his or her vacation spot, and did not cross any national borders. On the drive, several chapters of \"Pride and Prejudice\" were read.\n\r\n3. The student whose last name was Jessup did not read Oliver Twist, but did leave the country on vacation.\n\r\n4. Angela's last name is not Yee.\n\r\n5. Victor Denim's book was appropriate for his trip to Alaska, as it was set in a cold climate.\n\r\n6. The student who read \"Oliver Twist\" was not a female, but David read \"Catcher in the Rye\" on his vacation.\n\r\n7. Ms. Bascom didn't read \"Pride and Prejudice\", and she did not visit another country.\n\r\nThe five books are: \"To Kill a Mockingbird\", \"Oliver Twist\", \"Pride and Prejudice\", \"Catcher in the Rye\", and \"The Call of the Wild\".\n\r\nThe five vacation locations are: Florida, Alaska, Hawaii, Mexico, and Canada.\n\r\nThe five first names are: David, Jessica, John, Victor, and Angela. (Angela and Jessica are the two females.)\n\r\nThe five last names are: Bascom, Denim, Jessup, Yee, and Tyler.", "hint": "A knowledge of geography and literature will help you with some of the clues.", "answer": "Angela Bascom, \"To Kill a Mockingbird\", Hawaii\n\r\nJohn Tyler, \"Oliver Twist\", Canada\n\r\nJessica Yee, \"Pride and Prejudice\", Florida\n\r\nDavid Jessup, \"Catcher in the Rye\", Mexico\n\r\nVictor Denim, \"Call of the Wild\", Alaska", "category": "Logic-Grid", "date": "02/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive students from a South Carolina high school were each assigned a different book to read over Winter Break. Each of them had vacation plans in different locations, three to places in the United States and two to Canada and Mexico. Determine from the clues the full name of each student, the book each one was assigned, and the vacation spot each one visited.\n\r\n1. The five students, in no particular order are: Jessica, the student who visited Mexico, Mr. Tyler, the student who read \"The Call of the Wild\", and the student who visited Hawaii.\n\r\n2. Only one student rode in a car to his or her vacation spot, and did not cross any national borders. On the drive, several chapters of \"Pride and Prejudice\" were read.\n\r\n3. The student whose last name was Jessup did not read Oliver Twist, but did leave the country on vacation.\n\r\n4. Angela's last name is not Yee.\n\r\n5. Victor Denim's book was appropriate for his trip to Alaska, as it was set in a cold climate.\n\r\n6. The student who read \"Oliver Twist\" was not a female, but David read \"Catcher in the Rye\" on his vacation.\n\r\n7. Ms. Bascom didn't read \"Pride and Prejudice\", and she did not visit another country.\n\r\nThe five books are: \"To Kill a Mockingbird\", \"Oliver Twist\", \"Pride and Prejudice\", \"Catcher in the Rye\", and \"The Call of the Wild\".\n\r\nThe five vacation locations are: Florida, Alaska, Hawaii, Mexico, and Canada.\n\r\nThe five first names are: David, Jessica, John, Victor, and Angela. (Angela and Jessica are the two females.)\n\r\nThe five last names are: Bascom, Denim, Jessup, Yee, and Tyler.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAngela Bascom, \"To Kill a Mockingbird\", Hawaii\n\r\nJohn Tyler, \"Oliver Twist\", Canada\n\r\nJessica Yee, \"Pride and Prejudice\", Florida\n\r\nDavid Jessup, \"Catcher in the Rye\", Mexico\n\r\nVictor Denim, \"Call of the Wild\", Alaska\n<|im_start|>answer\nAngela Bascom, \"To Kill a Mockingbird\", Hawaii\n\r\nJohn Tyler, \"Oliver Twist\", Canada\n\r\nJessica Yee, \"Pride and Prejudice\", Florida\n\r\nDavid Jessup, \"Catcher in the Rye\", Mexico\n\r\nVictor Denim, \"Call of the Wild\", Alaska\n<|im_end|>" }, { "id": "#23519", "title": "Captain John's Journey (Part 1)", "fun": 2.9, "difficulty": 2.72, "author": "cdrock", "desc": "Captain John is the captain of a pirate ship called the \"Wasp\". He just heard about a lost treasure on a far away island. He needs to get his two crew mates, and lead them to a ship, but there are guards around and he needs to do this without passing them, or they will throw him in the brig. Can you help him get his two crew mates to the ship without getting sent to the brig?\n\r\nThe positions of everything are in a 3-by-3 grid (1 John, 1 ship, 2 crew mates, 2 guards, and 3 grass areas). John may only move 1 space at a time, either vertically, horizontally, or diagonally. He can only go to each space once. \n\r\nBut before he can figure out the right way to go, he must figure out where everything is. This is what he knew:\n\r\n1. The Wasp is not in the same row or column as John.\n\r\n2. John is not in the same row or column as either guard.\n\r\n3. Neither guard is in the third column.\n\r\n4. Both guards are vertically next to grass.\n\r\n5. The ship is in the same row as one guard, and the same column as the other guard.\n\r\n6. One of the grass spaces is diagonally next to both crew mates.\n\r\n7. One of the grass spaces is in the 2nd column, in the first row.\n\r\n8. The two guards are not in the same row or column.", "hint": "Use paper and pencil.", "answer": "The positions of everything.\n\r\nGuard - Grass - Crew Mate\n\r\nGrass - Grass - John\n\r\nShip - Guard - Crew Mate\n\r\nThe correct way for John to go (1-7, in order of each space he goes to, X meaning don't go).\n\r\nX - 5 - 4\r\n6 - 3 - 1\r\n7 - X - 2", "category": "Logic", "date": "06/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCaptain John is the captain of a pirate ship called the \"Wasp\". He just heard about a lost treasure on a far away island. He needs to get his two crew mates, and lead them to a ship, but there are guards around and he needs to do this without passing them, or they will throw him in the brig. Can you help him get his two crew mates to the ship without getting sent to the brig?\n\r\nThe positions of everything are in a 3-by-3 grid (1 John, 1 ship, 2 crew mates, 2 guards, and 3 grass areas). John may only move 1 space at a time, either vertically, horizontally, or diagonally. He can only go to each space once. \n\r\nBut before he can figure out the right way to go, he must figure out where everything is. This is what he knew:\n\r\n1. The Wasp is not in the same row or column as John.\n\r\n2. John is not in the same row or column as either guard.\n\r\n3. Neither guard is in the third column.\n\r\n4. Both guards are vertically next to grass.\n\r\n5. The ship is in the same row as one guard, and the same column as the other guard.\n\r\n6. One of the grass spaces is diagonally next to both crew mates.\n\r\n7. One of the grass spaces is in the 2nd column, in the first row.\n\r\n8. The two guards are not in the same row or column.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe positions of everything.\n\r\nGuard - Grass - Crew Mate\n\r\nGrass - Grass - John\n\r\nShip - Guard - Crew Mate\n\r\nThe correct way for John to go (1-7, in order of each space he goes to, X meaning don't go).\n\r\nX - 5 - 4\r\n6 - 3 - 1\r\n7 - X - 2\n<|im_start|>answer\nThe positions of everything.\n\r\nGuard - Grass - Crew Mate\n\r\nGrass - Grass - John\n\r\nShip - Guard - Crew Mate\n\r\nThe correct way for John to go (1-7, in order of each space he goes to, X meaning don't go).\n\r\nX - 5 - 4\r\n6 - 3 - 1\r\n7 - X - 2\n<|im_end|>" }, { "id": "#20954", "title": "Trapdoors 2", "fun": 2.9, "difficulty": 1.44, "author": "Therulerofthem", "desc": "After going through the door to freedom last time, you realize it wasn't to freedom at all, it was to another room, with another door.\n\r\nThere are six doors this time, all arranged in a straight line. Each has a clue on it. All clues are true.\n\r\nDoor colours: yellow, blue, red, green, purple, and orange.\n\r\nThe clues are:\n\r\nYellow door's clue: This door is 3 spaces away from the purple door.\n\r\nBlue door's clue: This door is at the far left.\n\r\nRed door's clue: The doors are in a sequence.\n\r\nGreen door's clue: This door is directly between the blue and yellow doors. It is three spaces away from the door to freedom.\n\r\nPurple door's clue: This door is next to the door to freedom.\n\r\nOrange door's clue: This door is directly next to the yellow door.\n\r\nWhat colour door leads to freedom?", "hint": "Draw a diagram.", "answer": "The red door leads to freedom.", "category": "Logic", "date": "02/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter going through the door to freedom last time, you realize it wasn't to freedom at all, it was to another room, with another door.\n\r\nThere are six doors this time, all arranged in a straight line. Each has a clue on it. All clues are true.\n\r\nDoor colours: yellow, blue, red, green, purple, and orange.\n\r\nThe clues are:\n\r\nYellow door's clue: This door is 3 spaces away from the purple door.\n\r\nBlue door's clue: This door is at the far left.\n\r\nRed door's clue: The doors are in a sequence.\n\r\nGreen door's clue: This door is directly between the blue and yellow doors. It is three spaces away from the door to freedom.\n\r\nPurple door's clue: This door is next to the door to freedom.\n\r\nOrange door's clue: This door is directly next to the yellow door.\n\r\nWhat colour door leads to freedom?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe red door leads to freedom.\n<|im_start|>answer\nThe red door leads to freedom.\n<|im_end|>" }, { "id": "#22333", "title": "Who, Where, and When?", "fun": 2.9, "difficulty": 1.54, "author": "Ronancello", "desc": "4 people went to 4 different places at 4 different times on 4 different days.\r\nPeople- Harry, Bonnie, John, Irma\r\nPlaces-Hotel, Barber shop, Mall, Post Office\r\nTimes-8:30AM, 12:00PM, 4:30PM, 7:00PM\r\nDays-Sunday, Wednesday, Friday, Tuesday\n\r\nA woman visited the hotel on a weekday. \r\nThe post office was visited in the morning.\r\nBonnie hates malls and hotels.\r\nThe local post office is closed on Tuesdays and Sundays.\r\nSomeone went to the mall at noon on Tuesday.\r\nIrma will always be at home at 7:00PM.\r\nNobody will go somewhere that starts with the first letter of their first name.\r\nJohn is very busy on weekdays.\r\nBonnie goes bowling all day on Wednesdays.", "hint": "A man went to the barber shop.", "answer": "John-Barber shop-7:PM-Sunday\r\nHarry-Mall-12:00PM-Tuesday\r\nBonnie-Post Office-8:30AM-Friday\r\nIrma-Hotel-4:30PM-Wednesday", "category": "Logic-Grid", "date": "04/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 people went to 4 different places at 4 different times on 4 different days.\r\nPeople- Harry, Bonnie, John, Irma\r\nPlaces-Hotel, Barber shop, Mall, Post Office\r\nTimes-8:30AM, 12:00PM, 4:30PM, 7:00PM\r\nDays-Sunday, Wednesday, Friday, Tuesday\n\r\nA woman visited the hotel on a weekday. \r\nThe post office was visited in the morning.\r\nBonnie hates malls and hotels.\r\nThe local post office is closed on Tuesdays and Sundays.\r\nSomeone went to the mall at noon on Tuesday.\r\nIrma will always be at home at 7:00PM.\r\nNobody will go somewhere that starts with the first letter of their first name.\r\nJohn is very busy on weekdays.\r\nBonnie goes bowling all day on Wednesdays.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn-Barber shop-7:PM-Sunday\r\nHarry-Mall-12:00PM-Tuesday\r\nBonnie-Post Office-8:30AM-Friday\r\nIrma-Hotel-4:30PM-Wednesday\n<|im_start|>answer\nJohn-Barber shop-7:PM-Sunday\r\nHarry-Mall-12:00PM-Tuesday\r\nBonnie-Post Office-8:30AM-Friday\r\nIrma-Hotel-4:30PM-Wednesday\n<|im_end|>" }, { "id": "#48878", "title": "Number Pyramid 1", "fun": 2.89, "difficulty": 2.14, "author": "westbrook1", "desc": "This teaser is a mixture of logic and math. In a number pyramid, the numbers 0-9 are each used once and formed into a pyramid, with one digit at the top, and right below it two digits, below those three digits, and below those four, all arranged in pyramid form. \n\r\nIn this puzzle, you will follow the clues given, and using these clues, create a number pyramid. There is only one answer.\n\r\nClues:\n\r\n1. The four numbers on the bottom row add up to 28.\n\r\n2. The highest number in row 3 is in the middle, or in the second out of third position.\n\r\n3. The third number from the left in the bottom row isn't 7.\n\r\n4. The rightmost numbers in each row, or the numbers on the right side going down, add up to 11.\n\r\n5. The numbers 0 and 5 are in different rows.\n\r\n6. The apex of the pyramid, or the top number, minus the leftmost number in row 2, equals 4.\n\r\n7. The leftmost numbers in the four rows, or the left hand side going down, add up to 20.", "hint": "The apex, or the top of the pyramid, is 6.", "answer": "Here is the way the number pyramid is filled out:\n\r\nRow 1: 6\r\nRow 2: 2, 0\r\nRow 3: 3, 5, 1\r\nRow 4: 9, 7, 8, 4", "category": "Logic", "date": "07/18/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is a mixture of logic and math. In a number pyramid, the numbers 0-9 are each used once and formed into a pyramid, with one digit at the top, and right below it two digits, below those three digits, and below those four, all arranged in pyramid form. \n\r\nIn this puzzle, you will follow the clues given, and using these clues, create a number pyramid. There is only one answer.\n\r\nClues:\n\r\n1. The four numbers on the bottom row add up to 28.\n\r\n2. The highest number in row 3 is in the middle, or in the second out of third position.\n\r\n3. The third number from the left in the bottom row isn't 7.\n\r\n4. The rightmost numbers in each row, or the numbers on the right side going down, add up to 11.\n\r\n5. The numbers 0 and 5 are in different rows.\n\r\n6. The apex of the pyramid, or the top number, minus the leftmost number in row 2, equals 4.\n\r\n7. The leftmost numbers in the four rows, or the left hand side going down, add up to 20.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHere is the way the number pyramid is filled out:\n\r\nRow 1: 6\r\nRow 2: 2, 0\r\nRow 3: 3, 5, 1\r\nRow 4: 9, 7, 8, 4\n<|im_start|>answer\nHere is the way the number pyramid is filled out:\n\r\nRow 1: 6\r\nRow 2: 2, 0\r\nRow 3: 3, 5, 1\r\nRow 4: 9, 7, 8, 4\n<|im_end|>" }, { "id": "#25719", "title": "Valentines Mayhem", "fun": 2.89, "difficulty": 1.16, "author": "phantomgal", "desc": "Misty and her friends all received something from their boyfriends for Valentines Day. Try to figure out who gave what to whom with what color wrapping paper.\n\r\nPeople who received the gifts: Jess, Misty, Allie, Anisa, Raina\r\nGifts: earrings, ring, flowers, bracelets, CD\r\nBoyfriends: Jake, Ben, Max, Joey, Jeremy.\r\nWrapping paper: red yellow, purple, Spongebob, blue\n\r\n1. Jake was crushing on Anisa, but she had another boyfriend, so he asked another girl out and gave her earrings.\n\r\n2. Ben proposed to his girlfriend with a ring.\n\r\n3. Anisa loved David Bowie and Spongebob, so her boyfriend (who wasn't Ben or Jeremy) gave her something to do with each of them.\n\r\n4. Jeremy (who did not give to Jess or Allie) did not give his gift in purple or yellow wrapping paper.\n\r\n5. The flowers were wrapped in blue wrapping paper.\n\r\n6. Allie was crushed when she found out her boyfriend liked Anisa, so she threw his present back at him before unwrapping the purple paper. Then they got back together, and he gave her the gift again, only to find out that she thought they were the prettiest pair of earrings in the world.\n\r\n7. Joey had bought the David Bowie CD 3 months before giving it to his girlfriend.\n\r\n8. Raina got her engagement ring wrapped in yellow.\n\r\n9. The bracelets (given by Max) was not wrapped in purple wrapping paper.", "hint": "Misty had a bouquet of roses, and Max liked Jess.", "answer": "Jess, bracelets, Max, red\r\nMisty, flowers, Jeremy, blue\r\nAllie, earrings, Jake, purple\r\nAnisa, CD, Joey, Spongebob\r\nRaina, ring, Ben, yellow", "category": "Logic-Grid", "date": "09/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMisty and her friends all received something from their boyfriends for Valentines Day. Try to figure out who gave what to whom with what color wrapping paper.\n\r\nPeople who received the gifts: Jess, Misty, Allie, Anisa, Raina\r\nGifts: earrings, ring, flowers, bracelets, CD\r\nBoyfriends: Jake, Ben, Max, Joey, Jeremy.\r\nWrapping paper: red yellow, purple, Spongebob, blue\n\r\n1. Jake was crushing on Anisa, but she had another boyfriend, so he asked another girl out and gave her earrings.\n\r\n2. Ben proposed to his girlfriend with a ring.\n\r\n3. Anisa loved David Bowie and Spongebob, so her boyfriend (who wasn't Ben or Jeremy) gave her something to do with each of them.\n\r\n4. Jeremy (who did not give to Jess or Allie) did not give his gift in purple or yellow wrapping paper.\n\r\n5. The flowers were wrapped in blue wrapping paper.\n\r\n6. Allie was crushed when she found out her boyfriend liked Anisa, so she threw his present back at him before unwrapping the purple paper. Then they got back together, and he gave her the gift again, only to find out that she thought they were the prettiest pair of earrings in the world.\n\r\n7. Joey had bought the David Bowie CD 3 months before giving it to his girlfriend.\n\r\n8. Raina got her engagement ring wrapped in yellow.\n\r\n9. The bracelets (given by Max) was not wrapped in purple wrapping paper.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJess, bracelets, Max, red\r\nMisty, flowers, Jeremy, blue\r\nAllie, earrings, Jake, purple\r\nAnisa, CD, Joey, Spongebob\r\nRaina, ring, Ben, yellow\n<|im_start|>answer\nJess, bracelets, Max, red\r\nMisty, flowers, Jeremy, blue\r\nAllie, earrings, Jake, purple\r\nAnisa, CD, Joey, Spongebob\r\nRaina, ring, Ben, yellow\n<|im_end|>" }, { "id": "#23913", "title": "Captain John's Journey (Part 2)", "fun": 2.89, "difficulty": 2.7, "author": "cdrock", "desc": "Captain John has escaped his home town onto his ship, the \"Wasp\", and now Captain John sits in his cabin reading his map. Standing up, he walks out the door into the middle of the deck and announces \"we have made it this far, but next we need to find both shipwrecks in the right order to point us the right way, towards the island\", followed by tons of \"ehs\".\n\r\nThere are reefs in the ocean and if Captain John passes over one, his ship sinks and he and his crew die.\r\nWith what Captain John knows about the sea, can you figure out where the nine things in a 3-by-3 grid(Wasp, sunken ship 1, sunken ship 2, 2 oceans, 3 reefs, and the island) and go in the right path to the first sunken ship, the second, then the island, without passing over a reef.\n\r\nThe ship can move 1 space horizontally, vertically, or diagonally, and it can only pass each space once.\n\r\n1. The Wasp is in the same row or column as both sunken ships.\n\r\n2. There are at least two reefs to the right of sunken ship 2, but the ship isn't in the same row as either of the reefs.\n\r\n3. One of the oceans is diagonal to only two reefs.\n\r\n4. The columns and rows of the Wasp and island together take up every single space except the 2nd row of the 3rd column.\n\r\n5. The island is between two reefs.\n\r\n6. One of the reefs is somewhere above the other two reefs.", "hint": "No hint available.", "answer": "The 9 things in the grid go as followed.\n\r\nWasp l sunken ship 2 l sunken ship 1\r\nocean l ocean l reef\r\nreef l island l reef\n\r\nThis is the order of where he needs to go (1-6, X's meaning reefs)\n\r\n1 l 4 l 3\r\n5 l 2 l X\r\nX l 6 l X", "category": "Logic", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCaptain John has escaped his home town onto his ship, the \"Wasp\", and now Captain John sits in his cabin reading his map. Standing up, he walks out the door into the middle of the deck and announces \"we have made it this far, but next we need to find both shipwrecks in the right order to point us the right way, towards the island\", followed by tons of \"ehs\".\n\r\nThere are reefs in the ocean and if Captain John passes over one, his ship sinks and he and his crew die.\r\nWith what Captain John knows about the sea, can you figure out where the nine things in a 3-by-3 grid(Wasp, sunken ship 1, sunken ship 2, 2 oceans, 3 reefs, and the island) and go in the right path to the first sunken ship, the second, then the island, without passing over a reef.\n\r\nThe ship can move 1 space horizontally, vertically, or diagonally, and it can only pass each space once.\n\r\n1. The Wasp is in the same row or column as both sunken ships.\n\r\n2. There are at least two reefs to the right of sunken ship 2, but the ship isn't in the same row as either of the reefs.\n\r\n3. One of the oceans is diagonal to only two reefs.\n\r\n4. The columns and rows of the Wasp and island together take up every single space except the 2nd row of the 3rd column.\n\r\n5. The island is between two reefs.\n\r\n6. One of the reefs is somewhere above the other two reefs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 9 things in the grid go as followed.\n\r\nWasp l sunken ship 2 l sunken ship 1\r\nocean l ocean l reef\r\nreef l island l reef\n\r\nThis is the order of where he needs to go (1-6, X's meaning reefs)\n\r\n1 l 4 l 3\r\n5 l 2 l X\r\nX l 6 l X\n<|im_start|>answer\nThe 9 things in the grid go as followed.\n\r\nWasp l sunken ship 2 l sunken ship 1\r\nocean l ocean l reef\r\nreef l island l reef\n\r\nThis is the order of where he needs to go (1-6, X's meaning reefs)\n\r\n1 l 4 l 3\r\n5 l 2 l X\r\nX l 6 l X\n<|im_end|>" }, { "id": "#23300", "title": "Killing Time", "fun": 2.89, "difficulty": 2.77, "author": "Eowyn", "desc": "The Bjerkaas family are on holiday. They are driving through Norway in order to reach the European continent. Norway has a lot of winding roads, and one never knows what's beyond that next curve.\n\r\nSo, the family, consisting of Kari (Mum), Ola (Dad), the two sisters (Hilde and Torill) and their little brother (Knut), figures out how to kill time a bit. They are going to guess what car make the next car approaching them will have.\n\r\nWhat you are to find out, is:\r\n- Who guessed\r\n- what car make\r\n- with what colour\r\n- with which driver\r\n- and at what time the car was seen by the family\n\r\nNote: They only guessed the car make. The colour and driver are only additional information about the car.\n\r\nGood luck!\n\n\r\nHere are the clues:\n\r\n-1- One of the males guessed the BMW.\n\r\n-2- Knut's car make showed up eight minutes after the car driven by the police officer.\n\r\n-3- The mother guessed correctly what the first car make would be every time they played, but she could not predict the colour, which wasn't dark green or dark pink.\n\r\n-4- A German car had another family in it, and it showed up at 17.46.\n\r\n-5- Nobody guessed a car make sharing their initials.\n\r\n-6- The old lady showed up before the young student and the businessman.\n\r\n-7- The silver Ford passed the Bjerkaas family's car just after the blue car.\n\r\n-8- The Hyundai drove by at 17.54, just when one of the females had started losing her hope as to whether her make would show up or not.\n\r\n-9- The businessman's car was green.\n\r\n-10- The dark pink car, which had the make that Ola guessed correctly, belonged to the student.\n\n\n\r\nInvolved:\r\nFamily members: Hilde, Knut, Torill, Ola, Kari\r\nCar makes: BMW, Toyota, Ford, Hyundai, Volkswagen\r\nColours: blue, dark green, dark pink, silver, black\r\nDrivers: old lady, young student, businessman, another family, a police officer\r\nTime: 17.35, 17.43, 17.46, 17.54, 18.03", "hint": "- One of the females wanted the Hyundai to show up.\n\r\nCar nationalities:\r\n- BMW: German\r\n- Toyota: Japanese\r\n- Ford: American\r\n- Hyundai: Korean\r\n- Volkswagen: German", "answer": "Hilde - Volkswagen - Black - Family - 17.46\r\nKnut - Ford - Silver - Lady - 17.43\r\nTorill - Hyundai - Dark green - Businessman - 17.54\r\nOla - BMW - Dark pink - Student - 18.03\r\nKari - Toyota - Blue - Police - 17.35", "category": "Logic-Grid", "date": "05/31/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Bjerkaas family are on holiday. They are driving through Norway in order to reach the European continent. Norway has a lot of winding roads, and one never knows what's beyond that next curve.\n\r\nSo, the family, consisting of Kari (Mum), Ola (Dad), the two sisters (Hilde and Torill) and their little brother (Knut), figures out how to kill time a bit. They are going to guess what car make the next car approaching them will have.\n\r\nWhat you are to find out, is:\r\n- Who guessed\r\n- what car make\r\n- with what colour\r\n- with which driver\r\n- and at what time the car was seen by the family\n\r\nNote: They only guessed the car make. The colour and driver are only additional information about the car.\n\r\nGood luck!\n\n\r\nHere are the clues:\n\r\n-1- One of the males guessed the BMW.\n\r\n-2- Knut's car make showed up eight minutes after the car driven by the police officer.\n\r\n-3- The mother guessed correctly what the first car make would be every time they played, but she could not predict the colour, which wasn't dark green or dark pink.\n\r\n-4- A German car had another family in it, and it showed up at 17.46.\n\r\n-5- Nobody guessed a car make sharing their initials.\n\r\n-6- The old lady showed up before the young student and the businessman.\n\r\n-7- The silver Ford passed the Bjerkaas family's car just after the blue car.\n\r\n-8- The Hyundai drove by at 17.54, just when one of the females had started losing her hope as to whether her make would show up or not.\n\r\n-9- The businessman's car was green.\n\r\n-10- The dark pink car, which had the make that Ola guessed correctly, belonged to the student.\n\n\n\r\nInvolved:\r\nFamily members: Hilde, Knut, Torill, Ola, Kari\r\nCar makes: BMW, Toyota, Ford, Hyundai, Volkswagen\r\nColours: blue, dark green, dark pink, silver, black\r\nDrivers: old lady, young student, businessman, another family, a police officer\r\nTime: 17.35, 17.43, 17.46, 17.54, 18.03\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHilde - Volkswagen - Black - Family - 17.46\r\nKnut - Ford - Silver - Lady - 17.43\r\nTorill - Hyundai - Dark green - Businessman - 17.54\r\nOla - BMW - Dark pink - Student - 18.03\r\nKari - Toyota - Blue - Police - 17.35\n<|im_start|>answer\nHilde - Volkswagen - Black - Family - 17.46\r\nKnut - Ford - Silver - Lady - 17.43\r\nTorill - Hyundai - Dark green - Businessman - 17.54\r\nOla - BMW - Dark pink - Student - 18.03\r\nKari - Toyota - Blue - Police - 17.35\n<|im_end|>" }, { "id": "#103", "title": "The Colored Bear", "fun": 2.89, "difficulty": 1.3, "author": "Jake", "desc": "If a hunter goes out his front door, goes 50 miles south, then goes 50 miles west, shoots a bear, goes 50 miles north and ends up in front of his house, what color was the bear?", "hint": "There is only one starting place on earth where the hunter will end up back at his front door.", "answer": "White.\n\r\nThe hunter is at the north pole, and the bear is a white polar bear.", "category": "Logic", "date": "01/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a hunter goes out his front door, goes 50 miles south, then goes 50 miles west, shoots a bear, goes 50 miles north and ends up in front of his house, what color was the bear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhite.\n\r\nThe hunter is at the north pole, and the bear is a white polar bear.\n<|im_start|>answer\nWhite.\n\r\nThe hunter is at the north pole, and the bear is a white polar bear.\n<|im_end|>" }, { "id": "#49915", "title": "Hospital Ward", "fun": 2.89, "difficulty": 1.4, "author": "Kinghal", "desc": "There were 100 patients in a road trauma hospital. Some of the patients had only one leg. Half the rest had no legs. In total how many legs did the 100 patients have?", "hint": "No hint available.", "answer": "100. The group with one leg each averages one leg per person. The rest are split into 2 equal groups. One group has no legs, so the other group must have 2 legs each, meaning these 2 groups average one leg per patient. Therefore, overall, the average is one leg per patient, therefore there is a total of 100 legs.", "category": "Logic", "date": "08/18/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 100 patients in a road trauma hospital. Some of the patients had only one leg. Half the rest had no legs. In total how many legs did the 100 patients have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n100. The group with one leg each averages one leg per person. The rest are split into 2 equal groups. One group has no legs, so the other group must have 2 legs each, meaning these 2 groups average one leg per patient. Therefore, overall, the average is one leg per patient, therefore there is a total of 100 legs.\n<|im_start|>answer\n100. The group with one leg each averages one leg per person. The rest are split into 2 equal groups. One group has no legs, so the other group must have 2 legs each, meaning these 2 groups average one leg per patient. Therefore, overall, the average is one leg per patient, therefore there is a total of 100 legs.\n<|im_end|>" }, { "id": "#28186", "title": "Musical Chares", "fun": 2.89, "difficulty": 2.11, "author": "Winner4600", "desc": "Chris and Carla Chare have always loved music. So, it came as no surprise when their four children each started playing a musical instrument. In fact, they were so good, each child now plays two! Cory, Carrie, Calvin, and Cindy each play one string instrument and one wind instrument. Can you figure out who plays what, and for how many years on each?\n\r\nBoys: Cory, Calvin\r\nGirls: Carrie, Cindy\r\nString Instruments: Violin (music with Treble Clef), Viola (music with Alto Clef), Cello (music with Bass Clef), Bass (music with Bass Clef)\r\nYears Played (Stringed Instruments): 4, 6. 7, 8\r\nWind Instruments: Flute, Saxophone, Trumpet, Clarinet\r\nYears Played (Wind Instruments): 2, 3, 4, 5\n\r\n1) Either Carrie plays the bass and trumpet, or Cindy plays the viola and flute.\n\r\n2) Only Carrie has played her wind instrument longer than her stringed one.\n\r\n3) The boys have played their string instruments for the longest amount of time, and their wind instruments for the shortest amount of time.\n\r\n4) The violin has been played seven years.\n\r\n5) Cory and Carrie read from the same clef when playing their string instruments.\n\r\n6) While the clarinet has only been played for two years, the cello has been in the Chare family for a grand total of eight years!\n\r\n7) Calvin plays the trumpet.", "hint": "No hint available.", "answer": "Cory-Cello-8 years-Clarinet-2 years\r\nCarrie-Bass-4 years-Saxophone-5 years\r\nCalvin-Violin-7 years-Trumpet-3 years\r\nCindy-Viola-6 years-Flute-4 years", "category": "Logic-Grid", "date": "01/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChris and Carla Chare have always loved music. So, it came as no surprise when their four children each started playing a musical instrument. In fact, they were so good, each child now plays two! Cory, Carrie, Calvin, and Cindy each play one string instrument and one wind instrument. Can you figure out who plays what, and for how many years on each?\n\r\nBoys: Cory, Calvin\r\nGirls: Carrie, Cindy\r\nString Instruments: Violin (music with Treble Clef), Viola (music with Alto Clef), Cello (music with Bass Clef), Bass (music with Bass Clef)\r\nYears Played (Stringed Instruments): 4, 6. 7, 8\r\nWind Instruments: Flute, Saxophone, Trumpet, Clarinet\r\nYears Played (Wind Instruments): 2, 3, 4, 5\n\r\n1) Either Carrie plays the bass and trumpet, or Cindy plays the viola and flute.\n\r\n2) Only Carrie has played her wind instrument longer than her stringed one.\n\r\n3) The boys have played their string instruments for the longest amount of time, and their wind instruments for the shortest amount of time.\n\r\n4) The violin has been played seven years.\n\r\n5) Cory and Carrie read from the same clef when playing their string instruments.\n\r\n6) While the clarinet has only been played for two years, the cello has been in the Chare family for a grand total of eight years!\n\r\n7) Calvin plays the trumpet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCory-Cello-8 years-Clarinet-2 years\r\nCarrie-Bass-4 years-Saxophone-5 years\r\nCalvin-Violin-7 years-Trumpet-3 years\r\nCindy-Viola-6 years-Flute-4 years\n<|im_start|>answer\nCory-Cello-8 years-Clarinet-2 years\r\nCarrie-Bass-4 years-Saxophone-5 years\r\nCalvin-Violin-7 years-Trumpet-3 years\r\nCindy-Viola-6 years-Flute-4 years\n<|im_end|>" }, { "id": "#28985", "title": "Poetry Writers", "fun": 2.89, "difficulty": 2.31, "author": "xsagirl", "desc": "Five friends recently entered a poetry writing competition. Each chose a different title for his or her piece and took a different length of time to compose it. Can you discover the full name of each poet, the title of his or her work and the amount of time he or she spent on its construction?\n\r\n1. Mandy took two hours longer over her piece of work than the author of 'Gentle Lady', who spent longer writing a poem than the person surnamed Chester.\n\r\n2. 'Mark of Cain' (coincidentally written by the man named Mark) took less time to write than Miss Holford's piece, which isn't entitled 'Garden of Desire'.\n\r\n3. George wrote 'Capital Charisma' and the poet surnamed Willis penned a futuristic poem entitled 'Final Frontiers' which, incidentally, won first prize in the competition.\n\r\n4. The poet surnamed Jork took an hour longer to write an entry than Mrs Clayton spent at her creation.", "hint": "The names of the pieces have been abbreviated in the grid as follows:\r\nCapital Charisma = CapCharisma\r\nFinal Frontiers = Fin.Frontier\r\nGarden of Desire = GardenDesire", "answer": "The two women (Ingrid and Mandy) are surnamed Holford (MISS, clue 2) and Clayton (MRS, clue 4). Mark wrote 'Mark of Cain' (2) and George wrote 'Capital Charisma' (3). So, Robert is Willis who wrote 'Final Frontiers (3). The author of 'Gentle Lady' isn't Mandy (1), so Ingrid. Mandy wrote 'Garden of Desire'. Thus she isn't Miss Holford (2), so she's Mrs Clayton and Ingrid is Miss Holford. Mandy's piece didn't take 11 hours (4), so (1) Mandy's took 10 hours, Ingrid 8 hours and the poet surnamed Chester took 7 hours. The one surnamed Jork took 11 hours (4), so Robert (Willis) took 9 hours. Mark's surname is thus Chester (2), so George's is Jork.\n\r\nThus:\r\nGeorge, Jork, 'Capital Charisma', 11 hours\r\nIngrid, Holford, 'Gentle Lady', 8 hours\r\nMandy, Clayton, 'Garden of Desire', 10 hours\r\nMark, Chester, 'Mark of Cain', 7 hours\r\nRobert, Willis, 'Final Frontiers', 9 hours", "category": "Logic-Grid", "date": "03/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends recently entered a poetry writing competition. Each chose a different title for his or her piece and took a different length of time to compose it. Can you discover the full name of each poet, the title of his or her work and the amount of time he or she spent on its construction?\n\r\n1. Mandy took two hours longer over her piece of work than the author of 'Gentle Lady', who spent longer writing a poem than the person surnamed Chester.\n\r\n2. 'Mark of Cain' (coincidentally written by the man named Mark) took less time to write than Miss Holford's piece, which isn't entitled 'Garden of Desire'.\n\r\n3. George wrote 'Capital Charisma' and the poet surnamed Willis penned a futuristic poem entitled 'Final Frontiers' which, incidentally, won first prize in the competition.\n\r\n4. The poet surnamed Jork took an hour longer to write an entry than Mrs Clayton spent at her creation.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two women (Ingrid and Mandy) are surnamed Holford (MISS, clue 2) and Clayton (MRS, clue 4). Mark wrote 'Mark of Cain' (2) and George wrote 'Capital Charisma' (3). So, Robert is Willis who wrote 'Final Frontiers (3). The author of 'Gentle Lady' isn't Mandy (1), so Ingrid. Mandy wrote 'Garden of Desire'. Thus she isn't Miss Holford (2), so she's Mrs Clayton and Ingrid is Miss Holford. Mandy's piece didn't take 11 hours (4), so (1) Mandy's took 10 hours, Ingrid 8 hours and the poet surnamed Chester took 7 hours. The one surnamed Jork took 11 hours (4), so Robert (Willis) took 9 hours. Mark's surname is thus Chester (2), so George's is Jork.\n\r\nThus:\r\nGeorge, Jork, 'Capital Charisma', 11 hours\r\nIngrid, Holford, 'Gentle Lady', 8 hours\r\nMandy, Clayton, 'Garden of Desire', 10 hours\r\nMark, Chester, 'Mark of Cain', 7 hours\r\nRobert, Willis, 'Final Frontiers', 9 hours\n<|im_start|>answer\nThe two women (Ingrid and Mandy) are surnamed Holford (MISS, clue 2) and Clayton (MRS, clue 4). Mark wrote 'Mark of Cain' (2) and George wrote 'Capital Charisma' (3). So, Robert is Willis who wrote 'Final Frontiers (3). The author of 'Gentle Lady' isn't Mandy (1), so Ingrid. Mandy wrote 'Garden of Desire'. Thus she isn't Miss Holford (2), so she's Mrs Clayton and Ingrid is Miss Holford. Mandy's piece didn't take 11 hours (4), so (1) Mandy's took 10 hours, Ingrid 8 hours and the poet surnamed Chester took 7 hours. The one surnamed Jork took 11 hours (4), so Robert (Willis) took 9 hours. Mark's surname is thus Chester (2), so George's is Jork.\n\r\nThus:\r\nGeorge, Jork, 'Capital Charisma', 11 hours\r\nIngrid, Holford, 'Gentle Lady', 8 hours\r\nMandy, Clayton, 'Garden of Desire', 10 hours\r\nMark, Chester, 'Mark of Cain', 7 hours\r\nRobert, Willis, 'Final Frontiers', 9 hours\n<|im_end|>" }, { "id": "#36236", "title": "Valentine's Gifts", "fun": 2.89, "difficulty": 2.32, "author": "rubytuesday", "desc": "Last Valentine's Day, 5 men got together to discuss what to buy their wives. They all decided on different presents, and they all wrapped them in different colour paper. Can you figure out which man bought which gift for whom and what colour the wrapping paper was?\n\r\n1. Either Nick or Chris gave Amy or Stephanie a gift in green wrapping paper.\n\r\n2. The book was wrapped in either silver or red. Either Sean or Nick gave Tracey or Stephanie the flowers.\n\r\n3. Either Amy or Kaitlyn received the ring wrapped in blue or red paper.\n\r\n4. Either Dave or Nick gave Melanie a gift wrapped in blue or gold.\n\r\n5. The ring or the scarf was given to Amy by Nick or Dave.\n\r\n6. Matt gave a present wrapped in silver or gold to either Kaitlyn or Stephanie.\n\r\n7. Either Nick or Chris gave Kaitlyn the gift wrapped in silver or blue.", "hint": "No hint available.", "answer": "Sean gave Tracey flowers in red wrapping paper.\r\nDave gave Melanie perfume in gold wrapping paper.\r\nNick gave Amy a scarf in green wrapping paper.\r\nMatt gave Stephanie a book in silver wrapping paper.\r\nChris gave Kaitlyn a ring in blue wrapping paper.", "category": "Logic-Grid", "date": "04/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast Valentine's Day, 5 men got together to discuss what to buy their wives. They all decided on different presents, and they all wrapped them in different colour paper. Can you figure out which man bought which gift for whom and what colour the wrapping paper was?\n\r\n1. Either Nick or Chris gave Amy or Stephanie a gift in green wrapping paper.\n\r\n2. The book was wrapped in either silver or red. Either Sean or Nick gave Tracey or Stephanie the flowers.\n\r\n3. Either Amy or Kaitlyn received the ring wrapped in blue or red paper.\n\r\n4. Either Dave or Nick gave Melanie a gift wrapped in blue or gold.\n\r\n5. The ring or the scarf was given to Amy by Nick or Dave.\n\r\n6. Matt gave a present wrapped in silver or gold to either Kaitlyn or Stephanie.\n\r\n7. Either Nick or Chris gave Kaitlyn the gift wrapped in silver or blue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSean gave Tracey flowers in red wrapping paper.\r\nDave gave Melanie perfume in gold wrapping paper.\r\nNick gave Amy a scarf in green wrapping paper.\r\nMatt gave Stephanie a book in silver wrapping paper.\r\nChris gave Kaitlyn a ring in blue wrapping paper.\n<|im_start|>answer\nSean gave Tracey flowers in red wrapping paper.\r\nDave gave Melanie perfume in gold wrapping paper.\r\nNick gave Amy a scarf in green wrapping paper.\r\nMatt gave Stephanie a book in silver wrapping paper.\r\nChris gave Kaitlyn a ring in blue wrapping paper.\n<|im_end|>" }, { "id": "#9165", "title": "A Dinner Party", "fun": 2.89, "difficulty": 2.28, "author": "jellybean", "desc": "At the dinner party, there were 5 people. They each had a meal. No one ate the same meal. They each had a different number of servings of food. (1-5). Also, each of them had a Bad Habit...\r\nPeople at the Party: Miss Red, Mr Green, Mr Orange, Miss Yellow, Miss Blue. \r\nFood they ate: Spaghetti, Beef & Veggie Stew, Caesar Salad, Soup, Lamb Roast.\r\nServings: 1 , 2 , 3 , 4 , 5.\r\nBad Habits: One talked very loudly at the table, one kept burping at the table, one had a cold and kept sniffing, one was a very messy eater, and one was giving everyone shifty looks. :) Find out what each person ate, how many servings they ate, and what their bad habits were.\n\r\nClues:\n\r\n1. The person that was sniffing constantly, ate four servings of food.\r\n2. Miss Yellow did NOT eat the Beef & Veggie Stew.\r\n3. The female guest who ate the Spaghetti, helped herself to 2 servings.\r\n4. The guest who burped throughout the meal (who was not Miss Blue) ate the Soup. \r\n5. Mr Orange ate one less serving than the person who ate the Beef & Veggie Stew.\r\n6. Both Miss Yellow, and the shifty-looking guest when back for more than one serving of food. \r\n7. Mr Green, who did not speak loudly because he was too busy eating, had the Lamb Roast.\r\n8. Mr Orange liked food that is messy.", "hint": "No hint available.", "answer": "Miss Red - Ate 1 serving of Soup. She burped constantly.\r\nMr Green - Ate 5 servings of Lamb Roast. Gave everyone shifty looks.\r\nMr Orange - Ate 3 servings of Caesar Salad. Was a very messy eater.\r\nMiss Yellow - Ate 2 servings of Spaghetti. Spoke loudly the whole night. \r\nMiss Blue - Ate 4 servings of Beef & Veggie Stew. Sniffed constantly.", "category": "Logic", "date": "12/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the dinner party, there were 5 people. They each had a meal. No one ate the same meal. They each had a different number of servings of food. (1-5). Also, each of them had a Bad Habit...\r\nPeople at the Party: Miss Red, Mr Green, Mr Orange, Miss Yellow, Miss Blue. \r\nFood they ate: Spaghetti, Beef & Veggie Stew, Caesar Salad, Soup, Lamb Roast.\r\nServings: 1 , 2 , 3 , 4 , 5.\r\nBad Habits: One talked very loudly at the table, one kept burping at the table, one had a cold and kept sniffing, one was a very messy eater, and one was giving everyone shifty looks. :) Find out what each person ate, how many servings they ate, and what their bad habits were.\n\r\nClues:\n\r\n1. The person that was sniffing constantly, ate four servings of food.\r\n2. Miss Yellow did NOT eat the Beef & Veggie Stew.\r\n3. The female guest who ate the Spaghetti, helped herself to 2 servings.\r\n4. The guest who burped throughout the meal (who was not Miss Blue) ate the Soup. \r\n5. Mr Orange ate one less serving than the person who ate the Beef & Veggie Stew.\r\n6. Both Miss Yellow, and the shifty-looking guest when back for more than one serving of food. \r\n7. Mr Green, who did not speak loudly because he was too busy eating, had the Lamb Roast.\r\n8. Mr Orange liked food that is messy.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMiss Red - Ate 1 serving of Soup. She burped constantly.\r\nMr Green - Ate 5 servings of Lamb Roast. Gave everyone shifty looks.\r\nMr Orange - Ate 3 servings of Caesar Salad. Was a very messy eater.\r\nMiss Yellow - Ate 2 servings of Spaghetti. Spoke loudly the whole night. \r\nMiss Blue - Ate 4 servings of Beef & Veggie Stew. Sniffed constantly.\n<|im_start|>answer\nMiss Red - Ate 1 serving of Soup. She burped constantly.\r\nMr Green - Ate 5 servings of Lamb Roast. Gave everyone shifty looks.\r\nMr Orange - Ate 3 servings of Caesar Salad. Was a very messy eater.\r\nMiss Yellow - Ate 2 servings of Spaghetti. Spoke loudly the whole night. \r\nMiss Blue - Ate 4 servings of Beef & Veggie Stew. Sniffed constantly.\n<|im_end|>" }, { "id": "#48661", "title": "Monkey Business", "fun": 2.89, "difficulty": 3.03, "author": "canse912", "desc": "The Catterville Zoo has a very unique main attraction: Performing Monkeys! Ellie, Gill, Sasha and Tommy have all been taught by their handler (who are all, strangely, also called Ellie, Gill, Sasha and Tommy) to perform a trick (handstand, trapeze tricks, juggling or breakdancing) to receive their favourite snack (honey, bananas, melon and mango). Discover each monkey's handler, the trick it can do, and its favourite snack.\n\r\n1.) No monkey has the same name as their handler.\n\r\n2.) Ellie the handler didn't teach any monkey to do a handstand.\n\r\n3.) The monkey that likes mangoes has the same name as the handler who taught a monkey to juggle.\n\r\n4.) A handler taught either Ellie or Sasha to do trapeze tricks.\n\r\n5.) The monkey that likes bananas, whose handler isn't Tommy, has the same name as Tommy the Monkey's handler.\n\r\n6.) Gill likes melons and his handler is a woman.\n\r\n7.) Gill the handler taught a monkey to breakdance.", "hint": "Ellie and Sasha are girls; Gill and Tommy are boys.", "answer": "Monkey, Handler, Trick, Food\n\r\nEllie, Tommy, Trapeze, Mangos\r\nGill, Ellie, Juggling, Melon\r\nSasha, Gill, Breakdancing, Bananas\r\nTommy, Sasha, Handstand, Honey", "category": "Logic-Grid", "date": "04/23/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Catterville Zoo has a very unique main attraction: Performing Monkeys! Ellie, Gill, Sasha and Tommy have all been taught by their handler (who are all, strangely, also called Ellie, Gill, Sasha and Tommy) to perform a trick (handstand, trapeze tricks, juggling or breakdancing) to receive their favourite snack (honey, bananas, melon and mango). Discover each monkey's handler, the trick it can do, and its favourite snack.\n\r\n1.) No monkey has the same name as their handler.\n\r\n2.) Ellie the handler didn't teach any monkey to do a handstand.\n\r\n3.) The monkey that likes mangoes has the same name as the handler who taught a monkey to juggle.\n\r\n4.) A handler taught either Ellie or Sasha to do trapeze tricks.\n\r\n5.) The monkey that likes bananas, whose handler isn't Tommy, has the same name as Tommy the Monkey's handler.\n\r\n6.) Gill likes melons and his handler is a woman.\n\r\n7.) Gill the handler taught a monkey to breakdance.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonkey, Handler, Trick, Food\n\r\nEllie, Tommy, Trapeze, Mangos\r\nGill, Ellie, Juggling, Melon\r\nSasha, Gill, Breakdancing, Bananas\r\nTommy, Sasha, Handstand, Honey\n<|im_start|>answer\nMonkey, Handler, Trick, Food\n\r\nEllie, Tommy, Trapeze, Mangos\r\nGill, Ellie, Juggling, Melon\r\nSasha, Gill, Breakdancing, Bananas\r\nTommy, Sasha, Handstand, Honey\n<|im_end|>" }, { "id": "#24703", "title": "Why Skid Mark Why? Part 2", "fun": 2.89, "difficulty": 1.6400000000000001, "author": "Question_Mark", "desc": "When Question Mark unlocked the door, he thought that he would see his wallet straight away. But Skid Mark (Question's brother) decided to put the wallet in a safe. The combination is three 2-digit numbers which can be expressed like this:\n\r\nxx-xx-xx\n\r\nYou are given the following clues to work out the combination:\n\r\nThe total of the three numbers is 39.\r\nThe second number is half of the third number.\r\nThe first number is the third number minus 1.\n\r\nCan you find Question's wallet in time? It's all up to you.", "hint": "No hint available.", "answer": "The combination is 15-08-16. Thank you for helping Question get his wallet back.", "category": "Logic", "date": "07/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Question Mark unlocked the door, he thought that he would see his wallet straight away. But Skid Mark (Question's brother) decided to put the wallet in a safe. The combination is three 2-digit numbers which can be expressed like this:\n\r\nxx-xx-xx\n\r\nYou are given the following clues to work out the combination:\n\r\nThe total of the three numbers is 39.\r\nThe second number is half of the third number.\r\nThe first number is the third number minus 1.\n\r\nCan you find Question's wallet in time? It's all up to you.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe combination is 15-08-16. Thank you for helping Question get his wallet back.\n<|im_start|>answer\nThe combination is 15-08-16. Thank you for helping Question get his wallet back.\n<|im_end|>" }, { "id": "#33684", "title": "Scaring Game", "fun": 2.89, "difficulty": 1.82, "author": "pookiekat", "desc": "It's getting close to Halloween! Every year the ghosts of the underworld get together and have a big competition to see who is the best at scaring humans. Reporter Wilma Werewolf is writing an article about the top five competitors for her newspaper. She knows that each ghost has one skill they're very good at and another skill they are practicing.\n\r\nHowever, because this is a big day for the ghosts, they are all very secretive about what they do. Wilma can only get a few sketchy responses to her queries. Help her find out where the ghosts will be haunting, what trick they specialize in, and what skill they are practicing for the big day so she can write her article!\n\r\nGhosts: Mr. Boo, Chuckling Charles, Morose Matthew, Neckless Nora, Petey Poltergeist \n\r\nHaunting: Castle Dungeon, Crumbly Mansion, Stormy Lakehouse, Cursed Movie Set, Dark Tower\n\r\nGood at: Laughing, Moaning, Panting, Sighing, Wailing\n\r\nPracticing: Clanking, Footsteps, Knocking, Shuffling and Thudding\n\r\n1) Word on the street is that the ghost who is good at moaning is learning to make eerie footsteps.\n\r\n2) Whoever is haunting the Dark Tower is an expert at sighing, but seems to think making thudding noises is silly.\n\r\n3) Morose Matthew wants to make clanking sounds as well as he wails, so Wilma thinks it's good for the actors' concentration that he doesn't haunt the Cursed Movie Set. \n\r\n4) Petey Poltergeist told Wilma he saw Mr. Boo practicing how to knock.\n\r\n5) Neckless Nora was raised to be a proper lady ghost, so she will never pant while haunting her family's Crumbly Mansion. She heard that one of her competitors, who loves to laugh menacingly, is studying shuffling.\n\r\n6) Petey Poltergeist has been seen hanging out by the Stormy Lakehouse, but has never been heard to pant.", "hint": "No hint available.", "answer": "Mr. Boo will haunt the Dark Tower by sighing and is learning how to knock. \n\r\nChuckling Charles will haunt the Cursed Movie Set by panting and is learning how to make thudding noises.\n\r\nMorose Matthew will haunt the Castle Dungeon by wailing and is learning how to clank his chains. \n\r\nNeckless Nora will haunt the Crumbling Manor by moaning and is learning how to make eerie footsteps.\n\r\nPetey Poltergeist will haunt the Stormy Lakehouse by laughing menacingly and is learning how to make shuffling noises behind people.", "category": "Logic-Grid", "date": "10/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's getting close to Halloween! Every year the ghosts of the underworld get together and have a big competition to see who is the best at scaring humans. Reporter Wilma Werewolf is writing an article about the top five competitors for her newspaper. She knows that each ghost has one skill they're very good at and another skill they are practicing.\n\r\nHowever, because this is a big day for the ghosts, they are all very secretive about what they do. Wilma can only get a few sketchy responses to her queries. Help her find out where the ghosts will be haunting, what trick they specialize in, and what skill they are practicing for the big day so she can write her article!\n\r\nGhosts: Mr. Boo, Chuckling Charles, Morose Matthew, Neckless Nora, Petey Poltergeist \n\r\nHaunting: Castle Dungeon, Crumbly Mansion, Stormy Lakehouse, Cursed Movie Set, Dark Tower\n\r\nGood at: Laughing, Moaning, Panting, Sighing, Wailing\n\r\nPracticing: Clanking, Footsteps, Knocking, Shuffling and Thudding\n\r\n1) Word on the street is that the ghost who is good at moaning is learning to make eerie footsteps.\n\r\n2) Whoever is haunting the Dark Tower is an expert at sighing, but seems to think making thudding noises is silly.\n\r\n3) Morose Matthew wants to make clanking sounds as well as he wails, so Wilma thinks it's good for the actors' concentration that he doesn't haunt the Cursed Movie Set. \n\r\n4) Petey Poltergeist told Wilma he saw Mr. Boo practicing how to knock.\n\r\n5) Neckless Nora was raised to be a proper lady ghost, so she will never pant while haunting her family's Crumbly Mansion. She heard that one of her competitors, who loves to laugh menacingly, is studying shuffling.\n\r\n6) Petey Poltergeist has been seen hanging out by the Stormy Lakehouse, but has never been heard to pant.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Boo will haunt the Dark Tower by sighing and is learning how to knock. \n\r\nChuckling Charles will haunt the Cursed Movie Set by panting and is learning how to make thudding noises.\n\r\nMorose Matthew will haunt the Castle Dungeon by wailing and is learning how to clank his chains. \n\r\nNeckless Nora will haunt the Crumbling Manor by moaning and is learning how to make eerie footsteps.\n\r\nPetey Poltergeist will haunt the Stormy Lakehouse by laughing menacingly and is learning how to make shuffling noises behind people.\n<|im_start|>answer\nMr. Boo will haunt the Dark Tower by sighing and is learning how to knock. \n\r\nChuckling Charles will haunt the Cursed Movie Set by panting and is learning how to make thudding noises.\n\r\nMorose Matthew will haunt the Castle Dungeon by wailing and is learning how to clank his chains. \n\r\nNeckless Nora will haunt the Crumbling Manor by moaning and is learning how to make eerie footsteps.\n\r\nPetey Poltergeist will haunt the Stormy Lakehouse by laughing menacingly and is learning how to make shuffling noises behind people.\n<|im_end|>" }, { "id": "#20648", "title": "Hire the Pixies", "fun": 2.89, "difficulty": 1.13, "author": "tiptoes007berbs", "desc": "The head gardener of The Secret Garden is in need of hiring 4 experienced gardeners. No time for applications, the flowers are in danger of drying up! He has 4 pixies in mind for the job, but hasn't any official record of them. It's your duty to track each one down. This is what we know....\n\r\nTheir names: Violette, Shousie, Flaminta, and Oltiesa.\n\r\nThe flowers they attend : Roses, Tulips, Violets and Mums.\n\r\nTheir means of transportation: Butterfly, Dragonfly, Songbird and Dove.\n\r\nTheir last known residences : The Majestic Mountains, The Friendly Forest, The Mystic Meadow and The Rushing River\n\r\nWe also know the following....\r\nFlaminta is allergic to Roses.\r\nWe found Violets in The Mountains.\r\nRoses don't grow at The Riverside.\r\nShousie travels by bird.\r\nFound The Dragonfly at Riverside.\r\nOltiesa lives in The Meadow.\r\nDove was spotted w/basket of Roses.\r\nViolette and Shousie hate Mums.\r\nFlaminta travels by Dragonfly.\r\nThe Meadow is great for Tulips.\r\nThere aren't any Mums in the Forest.\r\nViolette travels by Dove.\r\nIn the Meadow slept The Butterfly.\r\nSongbird flew decorated in Violets.\r\nShousie will only live on a Mountain.\n\r\nHurry, The Secret Garden awaits this important hire...Good Luck!", "hint": "Use the grid!!", "answer": "1. Violette, Roses, Forest and Dove\r\n2. Shousie, Violets, Mountains, \r\n Songbird.\r\n3. Oltiesa, Tulips, Meadow, and \r\n Butterfly.\r\n4. Flaminta, Mums, Riverside and \r\n Dragonfly.", "category": "Logic-Grid", "date": "01/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe head gardener of The Secret Garden is in need of hiring 4 experienced gardeners. No time for applications, the flowers are in danger of drying up! He has 4 pixies in mind for the job, but hasn't any official record of them. It's your duty to track each one down. This is what we know....\n\r\nTheir names: Violette, Shousie, Flaminta, and Oltiesa.\n\r\nThe flowers they attend : Roses, Tulips, Violets and Mums.\n\r\nTheir means of transportation: Butterfly, Dragonfly, Songbird and Dove.\n\r\nTheir last known residences : The Majestic Mountains, The Friendly Forest, The Mystic Meadow and The Rushing River\n\r\nWe also know the following....\r\nFlaminta is allergic to Roses.\r\nWe found Violets in The Mountains.\r\nRoses don't grow at The Riverside.\r\nShousie travels by bird.\r\nFound The Dragonfly at Riverside.\r\nOltiesa lives in The Meadow.\r\nDove was spotted w/basket of Roses.\r\nViolette and Shousie hate Mums.\r\nFlaminta travels by Dragonfly.\r\nThe Meadow is great for Tulips.\r\nThere aren't any Mums in the Forest.\r\nViolette travels by Dove.\r\nIn the Meadow slept The Butterfly.\r\nSongbird flew decorated in Violets.\r\nShousie will only live on a Mountain.\n\r\nHurry, The Secret Garden awaits this important hire...Good Luck!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Violette, Roses, Forest and Dove\r\n2. Shousie, Violets, Mountains, \r\n Songbird.\r\n3. Oltiesa, Tulips, Meadow, and \r\n Butterfly.\r\n4. Flaminta, Mums, Riverside and \r\n Dragonfly.\n<|im_start|>answer\n1. Violette, Roses, Forest and Dove\r\n2. Shousie, Violets, Mountains, \r\n Songbird.\r\n3. Oltiesa, Tulips, Meadow, and \r\n Butterfly.\r\n4. Flaminta, Mums, Riverside and \r\n Dragonfly.\n<|im_end|>" }, { "id": "#26394", "title": "Flower Children", "fun": 2.89, "difficulty": 2.31, "author": "Rob2003", "desc": "It was Valentines Day at Pelican High. Five boys named Adam, Jose, Isaiah, Frank, and John have secret sweethearts named Carrie, Grace, Laura, Mary, and Nellie. The five boys decided to pick a different number of blossoms and a different flower for their sweethearts.\n\r\nThe number of blossoms are: 3, 5, 8, 9 and 10.\n\r\nThe flowers are: Blazing Stars, Blue Vervain, Coneflowers, Prairie Clovers and Stiff Goldenrods.\n\r\nCan you figure out the number of blossoms and the type of flower each boy picked and the girl to whom he presented the bouquet?\n\r\n1. Adam picked exactly two fewer Blue Vervain than Isaiah picked of his flower.\n\r\n2. Frank picked Stiff Goldenrods for his sweetheart. Nellie received nine blossoms from her beau.\n\r\n3. Mary received fewer blossoms than the girl whose admirer handed her a bunch of Blazing Stars but more blossoms than at least one other young lady. Jose picked flowers for Laura.\n\r\n4. Grace received the next-higher number of flowers than the girl who accepted Prairie Clovers but fewer blossoms than John's sweetheart. \n\r\n5. Isaiah picked a bouquet of Blazing Stars.", "hint": "No hint available.", "answer": "Adam: 8, Blue Vervain, Mary\r\nJose: 3, Prairie Clovers, Laura\r\nIsaiah: 10, Blazing Stars, Carrie\r\nFrank: 5, Stiff Goldenrods, Grace\r\nJohn: 9, Coneflowers, Nellie", "category": "Logic-Grid", "date": "10/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was Valentines Day at Pelican High. Five boys named Adam, Jose, Isaiah, Frank, and John have secret sweethearts named Carrie, Grace, Laura, Mary, and Nellie. The five boys decided to pick a different number of blossoms and a different flower for their sweethearts.\n\r\nThe number of blossoms are: 3, 5, 8, 9 and 10.\n\r\nThe flowers are: Blazing Stars, Blue Vervain, Coneflowers, Prairie Clovers and Stiff Goldenrods.\n\r\nCan you figure out the number of blossoms and the type of flower each boy picked and the girl to whom he presented the bouquet?\n\r\n1. Adam picked exactly two fewer Blue Vervain than Isaiah picked of his flower.\n\r\n2. Frank picked Stiff Goldenrods for his sweetheart. Nellie received nine blossoms from her beau.\n\r\n3. Mary received fewer blossoms than the girl whose admirer handed her a bunch of Blazing Stars but more blossoms than at least one other young lady. Jose picked flowers for Laura.\n\r\n4. Grace received the next-higher number of flowers than the girl who accepted Prairie Clovers but fewer blossoms than John's sweetheart. \n\r\n5. Isaiah picked a bouquet of Blazing Stars.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam: 8, Blue Vervain, Mary\r\nJose: 3, Prairie Clovers, Laura\r\nIsaiah: 10, Blazing Stars, Carrie\r\nFrank: 5, Stiff Goldenrods, Grace\r\nJohn: 9, Coneflowers, Nellie\n<|im_start|>answer\nAdam: 8, Blue Vervain, Mary\r\nJose: 3, Prairie Clovers, Laura\r\nIsaiah: 10, Blazing Stars, Carrie\r\nFrank: 5, Stiff Goldenrods, Grace\r\nJohn: 9, Coneflowers, Nellie\n<|im_end|>" }, { "id": "#22926", "title": "Payday", "fun": 2.89, "difficulty": 1.4, "author": "princess0611", "desc": "The new accountant is putting together payroll. She is having a hard time remembering who does what in the office, which makes it hard to print out the pay checks. This is what she does know. \n\r\nThe secretary makes the least amount of money, and has worked there the shortest amount of time.\n\r\nJill makes less than the catering manager, but has worked there longer than everyone but the general manager.\n\r\nThe Sales Manager position pays $800.00.\n\r\nThe Administrative Assistant has worked there for 12 years.\n\r\nThe General Manager makes the most money because he has the highest position with the most experience.\n\r\nCarla makes the least amount of money.\n\r\nLaurie is the catering manager.\n\r\nWarren has worked there for 10 years.", "hint": "No hint available.", "answer": "Carla - Secretary - $500 - 4 yrs\r\nJill - Admin. Asst. - $600 - 12 yrs\r\nLaurie - Catering Manager - $700 - 6 yrs\r\nMike - General Manager - $900 - 15 yrs\r\nWarren - Sales Manager - $800 - 10 yrs", "category": "Logic-Grid", "date": "05/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe new accountant is putting together payroll. She is having a hard time remembering who does what in the office, which makes it hard to print out the pay checks. This is what she does know. \n\r\nThe secretary makes the least amount of money, and has worked there the shortest amount of time.\n\r\nJill makes less than the catering manager, but has worked there longer than everyone but the general manager.\n\r\nThe Sales Manager position pays $800.00.\n\r\nThe Administrative Assistant has worked there for 12 years.\n\r\nThe General Manager makes the most money because he has the highest position with the most experience.\n\r\nCarla makes the least amount of money.\n\r\nLaurie is the catering manager.\n\r\nWarren has worked there for 10 years.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarla - Secretary - $500 - 4 yrs\r\nJill - Admin. Asst. - $600 - 12 yrs\r\nLaurie - Catering Manager - $700 - 6 yrs\r\nMike - General Manager - $900 - 15 yrs\r\nWarren - Sales Manager - $800 - 10 yrs\n<|im_start|>answer\nCarla - Secretary - $500 - 4 yrs\r\nJill - Admin. Asst. - $600 - 12 yrs\r\nLaurie - Catering Manager - $700 - 6 yrs\r\nMike - General Manager - $900 - 15 yrs\r\nWarren - Sales Manager - $800 - 10 yrs\n<|im_end|>" }, { "id": "#45436", "title": "Books For a Cause", "fun": 2.89, "difficulty": 1.8800000000000001, "author": "whsprec", "desc": "Five students convinced their school to donate the excess textbooks to children overseas that needed them. From the clues given determine the student in charge, the area of the world the books are going to, the subject of the textbook, and how many boxes of books were shipped.\n\r\n1) Neither the history department nor the department that helped James Call send 7 boxes sent theirs to Africa.\r\n2) The math department, which Shelby Smith supervised, sent 2 more boxes than those that were sent to South America.\r\n3) Joseph Cox's group sent more than 3 boxes.\r\n4) Caroline Wood did not send her boxes to North Africa.\r\n5) The number of boxes of English books that were sent to Central America was less than 7.\r\n6) Haley Thomas sent more than 4 boxes.\r\n7) The music department sent less boxes then the amount sent to West Africa, which did not receive 5.", "hint": "No hint available.", "answer": "Shelby Smith sent 6 boxes of math books to West Africa.\r\nCaroline Wood sent 3 boxes of English books to Central America.\r\nJames Call sent 7 boxes of chemistry books to Northern India.\r\nHaley Thomas sent 5 boxes of music books to North Africa.\r\nJoseph Cox sent 4 boxes of history books to South America.", "category": "Logic-Grid", "date": "10/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive students convinced their school to donate the excess textbooks to children overseas that needed them. From the clues given determine the student in charge, the area of the world the books are going to, the subject of the textbook, and how many boxes of books were shipped.\n\r\n1) Neither the history department nor the department that helped James Call send 7 boxes sent theirs to Africa.\r\n2) The math department, which Shelby Smith supervised, sent 2 more boxes than those that were sent to South America.\r\n3) Joseph Cox's group sent more than 3 boxes.\r\n4) Caroline Wood did not send her boxes to North Africa.\r\n5) The number of boxes of English books that were sent to Central America was less than 7.\r\n6) Haley Thomas sent more than 4 boxes.\r\n7) The music department sent less boxes then the amount sent to West Africa, which did not receive 5.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShelby Smith sent 6 boxes of math books to West Africa.\r\nCaroline Wood sent 3 boxes of English books to Central America.\r\nJames Call sent 7 boxes of chemistry books to Northern India.\r\nHaley Thomas sent 5 boxes of music books to North Africa.\r\nJoseph Cox sent 4 boxes of history books to South America.\n<|im_start|>answer\nShelby Smith sent 6 boxes of math books to West Africa.\r\nCaroline Wood sent 3 boxes of English books to Central America.\r\nJames Call sent 7 boxes of chemistry books to Northern India.\r\nHaley Thomas sent 5 boxes of music books to North Africa.\r\nJoseph Cox sent 4 boxes of history books to South America.\n<|im_end|>" }, { "id": "#29894", "title": "The Writer's Cup", "fun": 2.88, "difficulty": 2.22, "author": "peppamintp", "desc": "At the end of each school year, Clearmont College's Students for the Greening of America sponsors a bed race to benefit the preservation of regional wetlands. In this year's race, the competitors were placed in divisions by their college major. The five winning teams in the English Department all had beds painted white, although each bed sported a different color sheet. After the race, each winning team's captain stated that his team's success was no doubt due to their Muse, after which their bed was named (each had a different name). Match each captain with his team's bed (one was Clio), and its sheet color (one was cerulean), as well as the prize won (the coveted Writer's Cup for first place, or a second, third, fourth, or fifth place ribbon).\n\r\n1. Erato crossed the finish line fifth.\n\r\n2. Calliope, which sported the indigo sheet, didn't place fourth.\n\r\n3. Forrest didn't captain the team that won the Writer's Cup, who had the bed with the magenta sheet.\n\r\n4. Joel steered his team's bed across the finish line immediately after the bed with the apricot sheet.\n\r\n5. Glenn's team's bed, Thalia, placed immediately after Irving's (which had the lilac sheet).\n\r\n6. The team captained by Harvey didn't race the bed named Melpomene.", "hint": "No hint available.", "answer": "1. Harvey, Clio, magenta, Writer's Cup\r\n2. Forrest, Calliope, indigo, 2nd\r\n3. Irving, Melpomene, lilac, 3rd\r\n4. Glenn, Thalia, apricot, 4th\r\n5. Joel, Erato, cerulean, 5th", "category": "Logic-Grid", "date": "04/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the end of each school year, Clearmont College's Students for the Greening of America sponsors a bed race to benefit the preservation of regional wetlands. In this year's race, the competitors were placed in divisions by their college major. The five winning teams in the English Department all had beds painted white, although each bed sported a different color sheet. After the race, each winning team's captain stated that his team's success was no doubt due to their Muse, after which their bed was named (each had a different name). Match each captain with his team's bed (one was Clio), and its sheet color (one was cerulean), as well as the prize won (the coveted Writer's Cup for first place, or a second, third, fourth, or fifth place ribbon).\n\r\n1. Erato crossed the finish line fifth.\n\r\n2. Calliope, which sported the indigo sheet, didn't place fourth.\n\r\n3. Forrest didn't captain the team that won the Writer's Cup, who had the bed with the magenta sheet.\n\r\n4. Joel steered his team's bed across the finish line immediately after the bed with the apricot sheet.\n\r\n5. Glenn's team's bed, Thalia, placed immediately after Irving's (which had the lilac sheet).\n\r\n6. The team captained by Harvey didn't race the bed named Melpomene.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Harvey, Clio, magenta, Writer's Cup\r\n2. Forrest, Calliope, indigo, 2nd\r\n3. Irving, Melpomene, lilac, 3rd\r\n4. Glenn, Thalia, apricot, 4th\r\n5. Joel, Erato, cerulean, 5th\n<|im_start|>answer\n1. Harvey, Clio, magenta, Writer's Cup\r\n2. Forrest, Calliope, indigo, 2nd\r\n3. Irving, Melpomene, lilac, 3rd\r\n4. Glenn, Thalia, apricot, 4th\r\n5. Joel, Erato, cerulean, 5th\n<|im_end|>" }, { "id": "#26243", "title": "Moving to London", "fun": 2.88, "difficulty": 0.91, "author": "HogwartsGirl05", "desc": "Last year, as I prepared to board the plane that would take me to my new home in London, my five aunts each gave me a gift. Each gift was something I had always cherished deeply. Charlotte, Patsy, Helen, Gail and Donna (in no particular order) gave me seeds to plant, advice, books, a map, and my grandmother's sewing box (in no particular order).\n\r\nCan you deduce from these clues, which aunt gave which gift and in what order?\n\r\n1. When I was young, I was taught to plant and grow flowers by the only aunt whose name contains a C, so she gave me things to plant in my new garden.\n\r\n2. The first gift I was given, at the airport, was so I could always find my way home.\n\r\n3. The sewing box was not given last although it was given after the seeds.\n\r\n4. Aunt Helen always told stories about how I would simply devour the written word, so she gave me plenty of volumes to read.\n\r\n5. The books were the only gift whose first letter corresponded to its place in the alphabet and to the order in which it was given.\n\r\n6. The last gift I received was from Aunt Patsy. She told me to \"never quit believing that there was good in all,\" and that \"teaching is the noblest of professions. For while teachers do not make millions, they do make tomorrow's leaders.\"\n\r\n7. Aunt Gail cannot sew, so grandmother did not give her the sewing box.", "hint": "Volumes: think about encyclopedias.\r\nIf you need more then I am really bad at this.", "answer": "Aunt, Gift, Order\n\r\nGail, Map, 1\r\nHelen, Books, 2\r\nCharlotte, Seeds, 3\r\nDonna, Sewing Box, 4\r\nPatsy, Advice, 5", "category": "Logic-Grid", "date": "10/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast year, as I prepared to board the plane that would take me to my new home in London, my five aunts each gave me a gift. Each gift was something I had always cherished deeply. Charlotte, Patsy, Helen, Gail and Donna (in no particular order) gave me seeds to plant, advice, books, a map, and my grandmother's sewing box (in no particular order).\n\r\nCan you deduce from these clues, which aunt gave which gift and in what order?\n\r\n1. When I was young, I was taught to plant and grow flowers by the only aunt whose name contains a C, so she gave me things to plant in my new garden.\n\r\n2. The first gift I was given, at the airport, was so I could always find my way home.\n\r\n3. The sewing box was not given last although it was given after the seeds.\n\r\n4. Aunt Helen always told stories about how I would simply devour the written word, so she gave me plenty of volumes to read.\n\r\n5. The books were the only gift whose first letter corresponded to its place in the alphabet and to the order in which it was given.\n\r\n6. The last gift I received was from Aunt Patsy. She told me to \"never quit believing that there was good in all,\" and that \"teaching is the noblest of professions. For while teachers do not make millions, they do make tomorrow's leaders.\"\n\r\n7. Aunt Gail cannot sew, so grandmother did not give her the sewing box.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAunt, Gift, Order\n\r\nGail, Map, 1\r\nHelen, Books, 2\r\nCharlotte, Seeds, 3\r\nDonna, Sewing Box, 4\r\nPatsy, Advice, 5\n<|im_start|>answer\nAunt, Gift, Order\n\r\nGail, Map, 1\r\nHelen, Books, 2\r\nCharlotte, Seeds, 3\r\nDonna, Sewing Box, 4\r\nPatsy, Advice, 5\n<|im_end|>" }, { "id": "#33558", "title": "Amnesia Blues", "fun": 2.88, "difficulty": 1.97, "author": "dishu", "desc": "5 married men once got a serious attack of amnesia, due to which they forgot their wives and started chasing 5 different girls, who were highly embarrassed with the situation.(Whether Amnesia was real or pretended is another teaser). Their wives consulted the local witch doctor who suggested 5 different treatments for each of the men to be administered at 5 different times. Unfortunately, the wives mixed up the details and now need your help to clear the mess and cure their husbands. All they can remember are the following clues. Can you help them cure their husbands?\n\r\nHusbands: Alan, Boman, Derek, Fred, Richard\r\nWives: Tanaaz, Lily, Tanya, Isha, Shiela\r\nChased girls: Tara, Jane, Rose, Alice, Sita\r\nTreatments: Spending 30 minutes in a stinking bathroom, A bath in a mud-pool, drinking 1 cup onion juice, Banging head against a wall, spending 15 minutes with head underwater\r\nTime of administering treatment: 9 pm, 4 pm, 3 pm, 7 pm, 5 pm\n\r\nClues:\n\r\n1. The 5 wives are: Tanaaz, the one whose husband had to stay in a stinking bathroom for 30 minutes, The one whose husband started fancying Tara, the one who was to cure her husband first and Derek's wife.\r\n2. The mud-pool bather was going to be the last to recover his memory.\r\n3. Jane was being chased by Lily's husband\r\n4. Boman's memory was to return by making him drink an unusual liquid instead of his usual 4 pm tea.\r\n5. Lily's husband was to recover at 7 pm.\r\n6. The one to recover last was married to Shiela.\r\n7. Alan was to recover first.\r\n8. Richard was not going to be the last to recover.\r\n9. Tanya's husband was likely to develop a bump on his head after treatment.\r\n10. In all probability, Derek may develop hydrophobia after his treatment.\r\n11. Sita was to get relief from her chaser at 5 pm.\r\n12. Alice would be the first to breathe a sigh of relief.\r\n13. Derek is married to Isha.", "hint": "In the Grid following condensations have been made:\r\nDrink onion juice : onion juice\r\nSpend 30 minutes in a stinking bathroom: bathroom\r\nBath in a mudpool: mudpool\r\nBanging head against a wall: headbang\r\nspending 15 minutes with head under water: underwater.\n\r\nHydrophobia: fear of water", "answer": "1. Tanya's husband Alan was chasing Alice and were to be cured by banging his head against a wall at 3 pm.\r\n2. Boman was to be given onion juice at 4 pm by Tanaaz to stop him from chasing Rose.\r\n3. Spending 15 minutes with his head underwater at 5 pm was to cure Isha's husband Derek of his fancy towards Sita.\r\n4. Shiela was to throw her husband Fred in a mud-pool at 9 pm to stop him chasing Tara.\r\n5. Richard would stop running after Jane, when Lily will make him spend 30 minutes in a stinking bathroom at 7 pm.", "category": "Logic-Grid", "date": "10/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 married men once got a serious attack of amnesia, due to which they forgot their wives and started chasing 5 different girls, who were highly embarrassed with the situation.(Whether Amnesia was real or pretended is another teaser). Their wives consulted the local witch doctor who suggested 5 different treatments for each of the men to be administered at 5 different times. Unfortunately, the wives mixed up the details and now need your help to clear the mess and cure their husbands. All they can remember are the following clues. Can you help them cure their husbands?\n\r\nHusbands: Alan, Boman, Derek, Fred, Richard\r\nWives: Tanaaz, Lily, Tanya, Isha, Shiela\r\nChased girls: Tara, Jane, Rose, Alice, Sita\r\nTreatments: Spending 30 minutes in a stinking bathroom, A bath in a mud-pool, drinking 1 cup onion juice, Banging head against a wall, spending 15 minutes with head underwater\r\nTime of administering treatment: 9 pm, 4 pm, 3 pm, 7 pm, 5 pm\n\r\nClues:\n\r\n1. The 5 wives are: Tanaaz, the one whose husband had to stay in a stinking bathroom for 30 minutes, The one whose husband started fancying Tara, the one who was to cure her husband first and Derek's wife.\r\n2. The mud-pool bather was going to be the last to recover his memory.\r\n3. Jane was being chased by Lily's husband\r\n4. Boman's memory was to return by making him drink an unusual liquid instead of his usual 4 pm tea.\r\n5. Lily's husband was to recover at 7 pm.\r\n6. The one to recover last was married to Shiela.\r\n7. Alan was to recover first.\r\n8. Richard was not going to be the last to recover.\r\n9. Tanya's husband was likely to develop a bump on his head after treatment.\r\n10. In all probability, Derek may develop hydrophobia after his treatment.\r\n11. Sita was to get relief from her chaser at 5 pm.\r\n12. Alice would be the first to breathe a sigh of relief.\r\n13. Derek is married to Isha.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Tanya's husband Alan was chasing Alice and were to be cured by banging his head against a wall at 3 pm.\r\n2. Boman was to be given onion juice at 4 pm by Tanaaz to stop him from chasing Rose.\r\n3. Spending 15 minutes with his head underwater at 5 pm was to cure Isha's husband Derek of his fancy towards Sita.\r\n4. Shiela was to throw her husband Fred in a mud-pool at 9 pm to stop him chasing Tara.\r\n5. Richard would stop running after Jane, when Lily will make him spend 30 minutes in a stinking bathroom at 7 pm.\n<|im_start|>answer\n1. Tanya's husband Alan was chasing Alice and were to be cured by banging his head against a wall at 3 pm.\r\n2. Boman was to be given onion juice at 4 pm by Tanaaz to stop him from chasing Rose.\r\n3. Spending 15 minutes with his head underwater at 5 pm was to cure Isha's husband Derek of his fancy towards Sita.\r\n4. Shiela was to throw her husband Fred in a mud-pool at 9 pm to stop him chasing Tara.\r\n5. Richard would stop running after Jane, when Lily will make him spend 30 minutes in a stinking bathroom at 7 pm.\n<|im_end|>" }, { "id": "#28787", "title": "Liars, Liars...?", "fun": 2.88, "difficulty": 1.57, "author": "teen_wiz", "desc": "In the land of Brainopia, there are three races of people: Mikkos, who tell the truth all the time, Kikkos, who always tell lies, and Zikkos, who tell alternate false and true statements, in which the order is not known (i.e. true, false, true or false, true, false). When interviewing three Brainopians, a foreigner received the following statements:\n\r\nPerson 1: \r\nI am a Mikko.\n\r\nPerson 2: \r\nI am a Kikko.\n\r\nPerson 3: \r\na. They are both lying.\r\nb. I am a Zikko.\n\r\nCan you help the very confused foreigner determine who is who, assuming each person represents a different race?", "hint": "Pay close attention to Person 3's statements.", "answer": "Person 1 is a Mikko.\r\nPerson 2 is a Zikko.\r\nPerson 3 is a Kikko.\n\r\nThanks for helping!", "category": "Logic", "date": "02/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of Brainopia, there are three races of people: Mikkos, who tell the truth all the time, Kikkos, who always tell lies, and Zikkos, who tell alternate false and true statements, in which the order is not known (i.e. true, false, true or false, true, false). When interviewing three Brainopians, a foreigner received the following statements:\n\r\nPerson 1: \r\nI am a Mikko.\n\r\nPerson 2: \r\nI am a Kikko.\n\r\nPerson 3: \r\na. They are both lying.\r\nb. I am a Zikko.\n\r\nCan you help the very confused foreigner determine who is who, assuming each person represents a different race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPerson 1 is a Mikko.\r\nPerson 2 is a Zikko.\r\nPerson 3 is a Kikko.\n\r\nThanks for helping!\n<|im_start|>answer\nPerson 1 is a Mikko.\r\nPerson 2 is a Zikko.\r\nPerson 3 is a Kikko.\n\r\nThanks for helping!\n<|im_end|>" }, { "id": "#33598", "title": "Glue Factory Stakes", "fun": 2.88, "difficulty": 3.28, "author": "cnmne", "desc": "Five horses have just competed in the annual \"Glue Factory Stakes\". With the given clues, determine for each horse: its color, its number, its jockey, and where it finished.\n\r\nFinish: Win, Place, Show, 4th, 5th\r\nHorses: Ghoulish Pleasure, Infirm, Roughage, Seattle Slow, Secret Harriet\r\nColors: Black, Red, Yellow, Blue, White\r\nNumbers: #18, #29, #37, #46, #50\r\nJockeys: Allen, Jerry, Luke, Nathan, Tim\n\r\n1) The 5 horses are: Infirm, the horse ridden by Tim, the horse that wore black, #50, and the horse that Placed.\r\n2) The 5 jockeys are: Allen, the one that rode Seattle Slow, the one that rode the horse that wore red, the one that rode #18, and the one that rode the horse that Showed.\r\n3) Secret Harriet finished ahead of the horse that wore blue, which finished ahead of the horse ridden by Luke.\r\n4) #50 finished ahead of the horse that wore white, but finished behind Roughage.\r\n5) Jerry finished next to #37.\r\n6) Allen finished next to #29.\r\n7) The horse that wore blue finished two positions away from #50.\r\n8) The horse that wore yellow finished two positions away from #46.\r\n9) Luke finished at least two positions away from #46.\r\n10) Nathan finished at least two positions away from #50.\r\n11) Luke rode a horse that wore an even number.\r\n12) Only one of the horses that wore a primary color also wore an even number.", "hint": "No hint available.", "answer": "Much of the grid can be filled using the normal process of elimination. The following explanation resolves one of the more difficult sections.\n\r\nIf #46 finished 5th, then the horse that wore yellow would have had to Show (clue 8), and Luke would have had to have ridden the horse that Showed (clues 3 and 9). This would mean that Luke rode the horse that wore yellow, which Showed. The horse that Showed could not wear #18 (clue 2) or #50 (clues 3, 4, and 7); Luke could not wear #37 or #39 (clue 11) or #46 (clue 9); therefore, Luke could not have ridden the horse that Showed. Thus, #46 could not have finished 5th, which means that #18 finished 5th.\n\r\nWin: Secret Harriet, Black, #46, Allen\r\nPlace: Seattle Slow, Blue, #29, Nathan\r\nShow: Roughage, Yellow, #37, Tim\r\n4th: Ghoulish Pleasure, Red, #50, Jerry\r\n5th: Infirm, White, #18, Luke", "category": "Logic-Grid", "date": "10/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive horses have just competed in the annual \"Glue Factory Stakes\". With the given clues, determine for each horse: its color, its number, its jockey, and where it finished.\n\r\nFinish: Win, Place, Show, 4th, 5th\r\nHorses: Ghoulish Pleasure, Infirm, Roughage, Seattle Slow, Secret Harriet\r\nColors: Black, Red, Yellow, Blue, White\r\nNumbers: #18, #29, #37, #46, #50\r\nJockeys: Allen, Jerry, Luke, Nathan, Tim\n\r\n1) The 5 horses are: Infirm, the horse ridden by Tim, the horse that wore black, #50, and the horse that Placed.\r\n2) The 5 jockeys are: Allen, the one that rode Seattle Slow, the one that rode the horse that wore red, the one that rode #18, and the one that rode the horse that Showed.\r\n3) Secret Harriet finished ahead of the horse that wore blue, which finished ahead of the horse ridden by Luke.\r\n4) #50 finished ahead of the horse that wore white, but finished behind Roughage.\r\n5) Jerry finished next to #37.\r\n6) Allen finished next to #29.\r\n7) The horse that wore blue finished two positions away from #50.\r\n8) The horse that wore yellow finished two positions away from #46.\r\n9) Luke finished at least two positions away from #46.\r\n10) Nathan finished at least two positions away from #50.\r\n11) Luke rode a horse that wore an even number.\r\n12) Only one of the horses that wore a primary color also wore an even number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMuch of the grid can be filled using the normal process of elimination. The following explanation resolves one of the more difficult sections.\n\r\nIf #46 finished 5th, then the horse that wore yellow would have had to Show (clue 8), and Luke would have had to have ridden the horse that Showed (clues 3 and 9). This would mean that Luke rode the horse that wore yellow, which Showed. The horse that Showed could not wear #18 (clue 2) or #50 (clues 3, 4, and 7); Luke could not wear #37 or #39 (clue 11) or #46 (clue 9); therefore, Luke could not have ridden the horse that Showed. Thus, #46 could not have finished 5th, which means that #18 finished 5th.\n\r\nWin: Secret Harriet, Black, #46, Allen\r\nPlace: Seattle Slow, Blue, #29, Nathan\r\nShow: Roughage, Yellow, #37, Tim\r\n4th: Ghoulish Pleasure, Red, #50, Jerry\r\n5th: Infirm, White, #18, Luke\n<|im_start|>answer\nMuch of the grid can be filled using the normal process of elimination. The following explanation resolves one of the more difficult sections.\n\r\nIf #46 finished 5th, then the horse that wore yellow would have had to Show (clue 8), and Luke would have had to have ridden the horse that Showed (clues 3 and 9). This would mean that Luke rode the horse that wore yellow, which Showed. The horse that Showed could not wear #18 (clue 2) or #50 (clues 3, 4, and 7); Luke could not wear #37 or #39 (clue 11) or #46 (clue 9); therefore, Luke could not have ridden the horse that Showed. Thus, #46 could not have finished 5th, which means that #18 finished 5th.\n\r\nWin: Secret Harriet, Black, #46, Allen\r\nPlace: Seattle Slow, Blue, #29, Nathan\r\nShow: Roughage, Yellow, #37, Tim\r\n4th: Ghoulish Pleasure, Red, #50, Jerry\r\n5th: Infirm, White, #18, Luke\n<|im_end|>" }, { "id": "#27054", "title": "World Domination IV", "fun": 2.88, "difficulty": 2.56, "author": "sweetime", "desc": "Mad scientist Sassi the Sane was holed up in her latest hideout.\t\t\t\t\r\nUnfortunately, due to a series of bungling attempts on the part of her assistants (of course), they were forced to remain where they were for the time being. No one could enter or exit the secret hideout.\n\r\nIn order to keep themselves entertained, one of Sassi's minions, Fred, suggested that they play a game.\n\r\nThis game consisted of Fred deciding on a theme for a picnic, and by guessing items, each person had to try to ascertain what the theme of the picnic was.\n\r\nUnfortunately, Fred was wasting all his deviousness on this picnic, rather than in helping Sassi to take over the world, and as a result, no one was able to guess the picnic.\n\r\nEach person guessed a different amount of items which could be brought, and each of them had managed to determine one item that they could bring.\r\nIn sheer frustration, each person had also suggested a unique way in which Fred could be disposed of, thus ending the nastiness of the picnic, and each had their own suggestion for a new picnic.\n\r\nThe five number of guesses were: twelve items, ten items, six items, three items, four items.\n\r\nThe correct guesses were: goat, diamond, cake, fire, streamers.\n\r\nThe ways of exacting vengeance on Fred were: hitting him with a piece of wood, forcing him to sit through someone's aria, stealing his teddy bear, a mutiny and a makeover.\n\r\nThe five people were: Spambringer, Kayyou, Warbucks, Aquatic, and Woodlady.\n\r\nThe five suggested new picnics were: things in 60's comedy shows, things in fast food restaurants, words which contain the letters A and O, words which contain silent letters, and things associated with flowers.\n\r\nUsing the following clues, can you determine who guessed which amount of items, the one item they identified correctly, their method of torture for Fred, and their new suggested theme?\n\r\n1. The five people were: Spambringer, the person who suggested stealing the teddybear, the person who had flowers as their theme, the person who had 6 guesses, and the person who guessed the goat.\r\n2. The person who guessed the streamers did not suggest mutiny, nor did the person who suggested mutiny use silent letters as a theme.\r\n3. The person who guessed the goat had a number of guesses divisible by three.\r\n4. Kayyou did not suggest hitting Fred with a piece of wood, but she did guess an even number of guesses.\r\n5. Neither Woodlady nor Aquatic suggested the cake.\r\n6. The person who guessed the streamers correctly was also the person who threatened to sing.\r\n5. The number of guesses made by Aquatic was divisible by both two and three.\r\n6. Warbucks made neither the most guesses, nor the least.\r\n7. Spambringer did not have a theme which contained the letters A and O, nor did he suggest the makeover.\r\n8. The person stealing the teddybear did not suggest a silent letters theme, but they did make the largest number of guesses.\r\n9. The person who suggested the fast food theme did not correctly guess a cake, nor did they guess the fire.\r\n10. The person who guessed the diamond made more guesses than the person who guessed the goat.\r\n11. Kayyou did not guess the diamond, nor did she threaten to sing.\r\n12. The person who wanted a theme with flowers correctly guessed the diamond.\r\n13. The person who guessed streamers made a number of guesses which was not divisible by 3.\r\n14. The person who suggested mutiny made neither the most, nor the least amount of guesses.\r\n15. The person who guessed the goat suggested hitting Fred with a piece of wood, and they also wanted a picnic which was language based.\r\n16. Kayyou thought that since she'd made the most guesses, she should be able to make the next picnic.\r\n17. The person who wanted the fast food picnic did not have a number of guesses divisible by three.\r\n18. The person who suggested the makeover made four guesses.\r\n19. The person who guessed fire did not suggest a makeover, nor stealing Fred's teddy bear.\r\n20. The person who wanted a picnic with words with the letters A and O in them wanted to mutiny.", "hint": "No hint available.", "answer": "Spambringer, ten items, streamers, singing, things in fast food restaurants.\r\nKayyou, twelve items, cake, stealing the teddybear, 60's comedy shows.\r\nWarbucks, four items, diamond, makeover, things associated with flowers.\r\nAquatic, six items, fire, mutiny, words which contained the letters A and O.\r\nWoodlady, three items, goat, hitting Fred with a piece of wood, words which contain silent letters.", "category": "Logic-Grid", "date": "11/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad scientist Sassi the Sane was holed up in her latest hideout.\t\t\t\t\r\nUnfortunately, due to a series of bungling attempts on the part of her assistants (of course), they were forced to remain where they were for the time being. No one could enter or exit the secret hideout.\n\r\nIn order to keep themselves entertained, one of Sassi's minions, Fred, suggested that they play a game.\n\r\nThis game consisted of Fred deciding on a theme for a picnic, and by guessing items, each person had to try to ascertain what the theme of the picnic was.\n\r\nUnfortunately, Fred was wasting all his deviousness on this picnic, rather than in helping Sassi to take over the world, and as a result, no one was able to guess the picnic.\n\r\nEach person guessed a different amount of items which could be brought, and each of them had managed to determine one item that they could bring.\r\nIn sheer frustration, each person had also suggested a unique way in which Fred could be disposed of, thus ending the nastiness of the picnic, and each had their own suggestion for a new picnic.\n\r\nThe five number of guesses were: twelve items, ten items, six items, three items, four items.\n\r\nThe correct guesses were: goat, diamond, cake, fire, streamers.\n\r\nThe ways of exacting vengeance on Fred were: hitting him with a piece of wood, forcing him to sit through someone's aria, stealing his teddy bear, a mutiny and a makeover.\n\r\nThe five people were: Spambringer, Kayyou, Warbucks, Aquatic, and Woodlady.\n\r\nThe five suggested new picnics were: things in 60's comedy shows, things in fast food restaurants, words which contain the letters A and O, words which contain silent letters, and things associated with flowers.\n\r\nUsing the following clues, can you determine who guessed which amount of items, the one item they identified correctly, their method of torture for Fred, and their new suggested theme?\n\r\n1. The five people were: Spambringer, the person who suggested stealing the teddybear, the person who had flowers as their theme, the person who had 6 guesses, and the person who guessed the goat.\r\n2. The person who guessed the streamers did not suggest mutiny, nor did the person who suggested mutiny use silent letters as a theme.\r\n3. The person who guessed the goat had a number of guesses divisible by three.\r\n4. Kayyou did not suggest hitting Fred with a piece of wood, but she did guess an even number of guesses.\r\n5. Neither Woodlady nor Aquatic suggested the cake.\r\n6. The person who guessed the streamers correctly was also the person who threatened to sing.\r\n5. The number of guesses made by Aquatic was divisible by both two and three.\r\n6. Warbucks made neither the most guesses, nor the least.\r\n7. Spambringer did not have a theme which contained the letters A and O, nor did he suggest the makeover.\r\n8. The person stealing the teddybear did not suggest a silent letters theme, but they did make the largest number of guesses.\r\n9. The person who suggested the fast food theme did not correctly guess a cake, nor did they guess the fire.\r\n10. The person who guessed the diamond made more guesses than the person who guessed the goat.\r\n11. Kayyou did not guess the diamond, nor did she threaten to sing.\r\n12. The person who wanted a theme with flowers correctly guessed the diamond.\r\n13. The person who guessed streamers made a number of guesses which was not divisible by 3.\r\n14. The person who suggested mutiny made neither the most, nor the least amount of guesses.\r\n15. The person who guessed the goat suggested hitting Fred with a piece of wood, and they also wanted a picnic which was language based.\r\n16. Kayyou thought that since she'd made the most guesses, she should be able to make the next picnic.\r\n17. The person who wanted the fast food picnic did not have a number of guesses divisible by three.\r\n18. The person who suggested the makeover made four guesses.\r\n19. The person who guessed fire did not suggest a makeover, nor stealing Fred's teddy bear.\r\n20. The person who wanted a picnic with words with the letters A and O in them wanted to mutiny.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSpambringer, ten items, streamers, singing, things in fast food restaurants.\r\nKayyou, twelve items, cake, stealing the teddybear, 60's comedy shows.\r\nWarbucks, four items, diamond, makeover, things associated with flowers.\r\nAquatic, six items, fire, mutiny, words which contained the letters A and O.\r\nWoodlady, three items, goat, hitting Fred with a piece of wood, words which contain silent letters.\n<|im_start|>answer\nSpambringer, ten items, streamers, singing, things in fast food restaurants.\r\nKayyou, twelve items, cake, stealing the teddybear, 60's comedy shows.\r\nWarbucks, four items, diamond, makeover, things associated with flowers.\r\nAquatic, six items, fire, mutiny, words which contained the letters A and O.\r\nWoodlady, three items, goat, hitting Fred with a piece of wood, words which contain silent letters.\n<|im_end|>" }, { "id": "#27666", "title": "First Snowfall", "fun": 2.88, "difficulty": 1.79, "author": "Rob2003", "desc": "Lucy looked outside on Friday morning to see snow on the ground. She was so excited - it was the first snowfall of the winter! School was delayed an hour that morning as the town plowed the four inches of snow off the roads. She looked forward to school with keen anticipation. She couldn't wait to chat online with her Northern friends during her study block. When she compared notes with them, it turned out that each of her friends had gotten snow that week, though all from different storms on different days - even different amounts! Determine the full name of her friends, where each of them lived, and on what day and how much snow each got.\n\r\n1. The five friends were, in no particular order, Alice Parker, the person who lived in New York, the person whose last name is Smith, the person who got snow on Thursday, and the boy who got one inch of snow.\n\r\n2. Five inches of snow fell in St. Paul, but not on Thursday. Harold lived in New York, but he didn't get snow on Wednesday. Jay got snow on Friday.\n\r\n3. Gregory, whose last name wasn't Trip, didn't live in Cleveland. Mr. Ward didn't get snow on Tuesday. Brenda did not live in Chicago.\n\r\n4. One town got two inches of snow on Monday. The person who got snow on Tuesday lived in St. Paul.\n\r\n5. The girl from Richmond got the same amount of snow as Lucy did. The person whose last name was Trip got snow on Thursday.\n\r\n6. Gregory got one inch less of snow than the person who lived in Richmond, but he got two more inches than the person whose last name was Crombie.", "hint": "No hint available.", "answer": "Alice Parker, St. Paul, Tuesday, 5 inches.\r\nBrenda Trip, Richmond, Thursday, 4 inches.\r\nGregory Smith, Chicago, Wednesday, 3 inches.\r\nHarold Ward, New York, Monday, 2 inches.\r\nJay Crombie, Cleveland, Friday 1 inch.", "category": "Logic-Grid", "date": "12/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLucy looked outside on Friday morning to see snow on the ground. She was so excited - it was the first snowfall of the winter! School was delayed an hour that morning as the town plowed the four inches of snow off the roads. She looked forward to school with keen anticipation. She couldn't wait to chat online with her Northern friends during her study block. When she compared notes with them, it turned out that each of her friends had gotten snow that week, though all from different storms on different days - even different amounts! Determine the full name of her friends, where each of them lived, and on what day and how much snow each got.\n\r\n1. The five friends were, in no particular order, Alice Parker, the person who lived in New York, the person whose last name is Smith, the person who got snow on Thursday, and the boy who got one inch of snow.\n\r\n2. Five inches of snow fell in St. Paul, but not on Thursday. Harold lived in New York, but he didn't get snow on Wednesday. Jay got snow on Friday.\n\r\n3. Gregory, whose last name wasn't Trip, didn't live in Cleveland. Mr. Ward didn't get snow on Tuesday. Brenda did not live in Chicago.\n\r\n4. One town got two inches of snow on Monday. The person who got snow on Tuesday lived in St. Paul.\n\r\n5. The girl from Richmond got the same amount of snow as Lucy did. The person whose last name was Trip got snow on Thursday.\n\r\n6. Gregory got one inch less of snow than the person who lived in Richmond, but he got two more inches than the person whose last name was Crombie.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlice Parker, St. Paul, Tuesday, 5 inches.\r\nBrenda Trip, Richmond, Thursday, 4 inches.\r\nGregory Smith, Chicago, Wednesday, 3 inches.\r\nHarold Ward, New York, Monday, 2 inches.\r\nJay Crombie, Cleveland, Friday 1 inch.\n<|im_start|>answer\nAlice Parker, St. Paul, Tuesday, 5 inches.\r\nBrenda Trip, Richmond, Thursday, 4 inches.\r\nGregory Smith, Chicago, Wednesday, 3 inches.\r\nHarold Ward, New York, Monday, 2 inches.\r\nJay Crombie, Cleveland, Friday 1 inch.\n<|im_end|>" }, { "id": "#30805", "title": "Family Scavenger Hunt", "fun": 2.88, "difficulty": 1.17, "author": "cdrock", "desc": "One day, five siblings were bored, so their parents set up a scavenger hunt. They hid a different present in a different spot for each of the five kids. Using the clues below, can you determine which kid got which present, and where each present was hidden?\n\r\nKids: Greg, Mike, Dorothy, Lucy, Amanda\r\nPresents: jigsaw puzzle, book, paint set, board game, video game\r\nHiding Locations: in the washing machine, under the couch, in the sink, under the bed, and behind the TV.\n\r\nClues:\n\r\n1. The five kids are Greg, the one who got the paint set, the one whose present was hidden in the sink, the one who received the board game, and Lucy.\n\r\n2. Mike, who received the video game, didn't get the present hidden under the bed.\n\r\n3. The present hidden in the washing machine was Dorothy's.\n\r\n4. The present hidden under the couch was not Mike's.\n\r\n5. The paint set was found behind the TV.\n\r\n6. The present hidden under the couch was not the jigsaw puzzle.\n\r\n7. Lucy's present was not hidden under the bed.", "hint": "No hint available.", "answer": "Greg - jigsaw puzzle - under the bed\r\nMike - video game - in the sink\r\nDorothy - board game - in the washing machine\r\nLucy - book - under the couch\r\nAmanda - paint set - behind the TV", "category": "Logic-Grid", "date": "05/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, five siblings were bored, so their parents set up a scavenger hunt. They hid a different present in a different spot for each of the five kids. Using the clues below, can you determine which kid got which present, and where each present was hidden?\n\r\nKids: Greg, Mike, Dorothy, Lucy, Amanda\r\nPresents: jigsaw puzzle, book, paint set, board game, video game\r\nHiding Locations: in the washing machine, under the couch, in the sink, under the bed, and behind the TV.\n\r\nClues:\n\r\n1. The five kids are Greg, the one who got the paint set, the one whose present was hidden in the sink, the one who received the board game, and Lucy.\n\r\n2. Mike, who received the video game, didn't get the present hidden under the bed.\n\r\n3. The present hidden in the washing machine was Dorothy's.\n\r\n4. The present hidden under the couch was not Mike's.\n\r\n5. The paint set was found behind the TV.\n\r\n6. The present hidden under the couch was not the jigsaw puzzle.\n\r\n7. Lucy's present was not hidden under the bed.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGreg - jigsaw puzzle - under the bed\r\nMike - video game - in the sink\r\nDorothy - board game - in the washing machine\r\nLucy - book - under the couch\r\nAmanda - paint set - behind the TV\n<|im_start|>answer\nGreg - jigsaw puzzle - under the bed\r\nMike - video game - in the sink\r\nDorothy - board game - in the washing machine\r\nLucy - book - under the couch\r\nAmanda - paint set - behind the TV\n<|im_end|>" }, { "id": "#52305", "title": "Weight In Gold", "fun": 2.88, "difficulty": 2.62, "author": "Snowdog", "desc": "During the California Gold Rush, an assessor in San Francisco used a balance to measure out quantities of gold dust. He had a set of weights to place on the balance. The assessor needed to be able to measure out gold dust in exact ounces, no fractions, for every number of ounces starting at 1.\n\r\nIf the assessor has four weights, what is the largest number of ounces of gold dust he can measure?\n\r\nNote: The answer is not 15 ounces", "hint": "Weights can be placed on the balance plate with or without the gold dust.", "answer": "The maximum weight is 40 ounces.\n\r\nThe weights are powers of 3: 1 ounce, 3 ounces, 9 ounces, 27 ounces.\n\r\nExample:\r\n7 ounces – Plate A: 9 oz. and 1 oz. weights. Plate B: 3 oz weight and gold\n\r\nIn any weighing, each weight can be placed in one of three ways: on the plate with the gold, on the plate without the gold, on the desk next to the balance. So given n weights, there are 3^n possible combinations.\n\r\nThrow out the case where all weights are on the table. That leaves 3^n – 1 cases. \n\r\nHalf of those cases would weigh negative gold, so eliminate half of these.\n\r\nThus, the number of valid combinations for n weights is (3^n – 1) / 2.\n\r\nFor four weights, (3^4 – 1) / 2 = (81 – 1) / 2 = 80 / 2 = 40.", "category": "Logic", "date": "11/26/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring the California Gold Rush, an assessor in San Francisco used a balance to measure out quantities of gold dust. He had a set of weights to place on the balance. The assessor needed to be able to measure out gold dust in exact ounces, no fractions, for every number of ounces starting at 1.\n\r\nIf the assessor has four weights, what is the largest number of ounces of gold dust he can measure?\n\r\nNote: The answer is not 15 ounces\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe maximum weight is 40 ounces.\n\r\nThe weights are powers of 3: 1 ounce, 3 ounces, 9 ounces, 27 ounces.\n\r\nExample:\r\n7 ounces – Plate A: 9 oz. and 1 oz. weights. Plate B: 3 oz weight and gold\n\r\nIn any weighing, each weight can be placed in one of three ways: on the plate with the gold, on the plate without the gold, on the desk next to the balance. So given n weights, there are 3^n possible combinations.\n\r\nThrow out the case where all weights are on the table. That leaves 3^n – 1 cases. \n\r\nHalf of those cases would weigh negative gold, so eliminate half of these.\n\r\nThus, the number of valid combinations for n weights is (3^n – 1) / 2.\n\r\nFor four weights, (3^4 – 1) / 2 = (81 – 1) / 2 = 80 / 2 = 40.\n<|im_start|>answer\nThe maximum weight is 40 ounces.\n\r\nThe weights are powers of 3: 1 ounce, 3 ounces, 9 ounces, 27 ounces.\n\r\nExample:\r\n7 ounces – Plate A: 9 oz. and 1 oz. weights. Plate B: 3 oz weight and gold\n\r\nIn any weighing, each weight can be placed in one of three ways: on the plate with the gold, on the plate without the gold, on the desk next to the balance. So given n weights, there are 3^n possible combinations.\n\r\nThrow out the case where all weights are on the table. That leaves 3^n – 1 cases. \n\r\nHalf of those cases would weigh negative gold, so eliminate half of these.\n\r\nThus, the number of valid combinations for n weights is (3^n – 1) / 2.\n\r\nFor four weights, (3^4 – 1) / 2 = (81 – 1) / 2 = 80 / 2 = 40.\n<|im_end|>" }, { "id": "#17721", "title": "Monk Steps", "fun": 2.88, "difficulty": 2.12, "author": "Jake", "desc": "A monk has a very specific ritual for climbing up the steps to the temple. First he climbs up to the middle step and meditates for 1 minute. Then he climbs up 8 steps and faces east until he hears a bird singing. Then he walks down 12 steps and picks up a pebble. He takes one step up and tosses the pebble over his left shoulder. Now, he walks up the remaining steps three at a time which only takes him 9 paces. How many steps are there?", "hint": "No hint available.", "answer": "There are 49 steps. \n\r\nHe climbs halfway, which is step 25. He hears the bird singing on step 33. He picks up the pebble on the 21st step and tosses it on the 22nd step. The remaining 27 steps are taken three at a time which is 9 paces.", "category": "Math", "date": "05/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA monk has a very specific ritual for climbing up the steps to the temple. First he climbs up to the middle step and meditates for 1 minute. Then he climbs up 8 steps and faces east until he hears a bird singing. Then he walks down 12 steps and picks up a pebble. He takes one step up and tosses the pebble over his left shoulder. Now, he walks up the remaining steps three at a time which only takes him 9 paces. How many steps are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 49 steps. \n\r\nHe climbs halfway, which is step 25. He hears the bird singing on step 33. He picks up the pebble on the 21st step and tosses it on the 22nd step. The remaining 27 steps are taken three at a time which is 9 paces.\n<|im_start|>answer\nThere are 49 steps. \n\r\nHe climbs halfway, which is step 25. He hears the bird singing on step 33. He picks up the pebble on the 21st step and tosses it on the 22nd step. The remaining 27 steps are taken three at a time which is 9 paces.\n<|im_end|>" }, { "id": "#46357", "title": "Alien Nerds In Disguise!", "fun": 2.88, "difficulty": 1.7, "author": "canse912", "desc": "There are five aliens in disguise at a Star Wars convention. With their masks on they look like all other Star Wars slightly-geeky fans, but underneath the masks they look very different. Four of them even have to pretend that their extra heads are part of their costumes. Identify each alien's name, age, number of heads, colour of eyes and the oddity each alien possesses.\n\r\nNames: Gozz, Fleeb, Walla, Payle, Quarr\r\nAges: 21, 22, 23, 25, 28\r\nNo. Heads: 1, 2, 3, 4, 5\r\nColour eyes: Blue, Brown, Red, Black, White\r\nOddities: Three eyes, Fangs, One Leg, Seven Fingers, No Arms\n\r\n1. Walla is the eldest. The alien with seven fingers on each hand doesn't have black eyes.\n\r\n2. The youngest alien also has the most heads, and Gozz doesn't have a primary eye colour.\n\r\n3. Fleeb is six years younger than the alien with no arms.\n\r\n4. The aliens are having a hard time disguising the fact that Gozz and Quarr have more heads than humans, even though neither of them has the most heads of the five.\n\r\n5. Payle's oddity is that he has trouble keeping up with the aliens due to the fact that he has only one leg.\n\r\n6. Either Gozz or Fleeb is able to scare off the curious, human Star Wars fans with their massive fangs.\n\r\n7. Fleeb and Quarr are the aliens that have normal, human eye colours, and they both have a prime number of heads. Payle is two years younger than Quarr, and Quarr is two years younger than Gozz.\n\r\n8. The third eldest alien has seven fingers. The second eldest has fangs.\n\r\n9. Fleeb has 2 heads.\n\r\n10. The aliens are sending Walla out to get the drinks. Walla asks for black coffee, the same colour as his eyes. \n\r\n11. The 23-year-old orders Coca-Cola, which isn't the colour of his eyes.", "hint": "Primary colours: Yellow, Red and Blue.\n\r\nHumans tend to have eyes that are either blue, brown, green, grey or hazel.", "answer": "Gozz, 25, 4 Heads, White Eyes, Fangs\n\r\nFleeb, 22, 2 Heads, Brown Eyes, Three Eyes\n\r\nWalla, 28, 1 Head, Black Eyes, No Arms\n\r\nPayle, 21, 5 Heads, Red Eyes, One Leg\n\r\nQuarr, 23, 3 Heads, Blue Eyes, Seven Fingers", "category": "Logic-Grid", "date": "02/13/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five aliens in disguise at a Star Wars convention. With their masks on they look like all other Star Wars slightly-geeky fans, but underneath the masks they look very different. Four of them even have to pretend that their extra heads are part of their costumes. Identify each alien's name, age, number of heads, colour of eyes and the oddity each alien possesses.\n\r\nNames: Gozz, Fleeb, Walla, Payle, Quarr\r\nAges: 21, 22, 23, 25, 28\r\nNo. Heads: 1, 2, 3, 4, 5\r\nColour eyes: Blue, Brown, Red, Black, White\r\nOddities: Three eyes, Fangs, One Leg, Seven Fingers, No Arms\n\r\n1. Walla is the eldest. The alien with seven fingers on each hand doesn't have black eyes.\n\r\n2. The youngest alien also has the most heads, and Gozz doesn't have a primary eye colour.\n\r\n3. Fleeb is six years younger than the alien with no arms.\n\r\n4. The aliens are having a hard time disguising the fact that Gozz and Quarr have more heads than humans, even though neither of them has the most heads of the five.\n\r\n5. Payle's oddity is that he has trouble keeping up with the aliens due to the fact that he has only one leg.\n\r\n6. Either Gozz or Fleeb is able to scare off the curious, human Star Wars fans with their massive fangs.\n\r\n7. Fleeb and Quarr are the aliens that have normal, human eye colours, and they both have a prime number of heads. Payle is two years younger than Quarr, and Quarr is two years younger than Gozz.\n\r\n8. The third eldest alien has seven fingers. The second eldest has fangs.\n\r\n9. Fleeb has 2 heads.\n\r\n10. The aliens are sending Walla out to get the drinks. Walla asks for black coffee, the same colour as his eyes. \n\r\n11. The 23-year-old orders Coca-Cola, which isn't the colour of his eyes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGozz, 25, 4 Heads, White Eyes, Fangs\n\r\nFleeb, 22, 2 Heads, Brown Eyes, Three Eyes\n\r\nWalla, 28, 1 Head, Black Eyes, No Arms\n\r\nPayle, 21, 5 Heads, Red Eyes, One Leg\n\r\nQuarr, 23, 3 Heads, Blue Eyes, Seven Fingers\n<|im_start|>answer\nGozz, 25, 4 Heads, White Eyes, Fangs\n\r\nFleeb, 22, 2 Heads, Brown Eyes, Three Eyes\n\r\nWalla, 28, 1 Head, Black Eyes, No Arms\n\r\nPayle, 21, 5 Heads, Red Eyes, One Leg\n\r\nQuarr, 23, 3 Heads, Blue Eyes, Seven Fingers\n<|im_end|>" }, { "id": "#36358", "title": "Winging It", "fun": 2.88, "difficulty": 1.95, "author": "chaskey", "desc": "On separate days, five pairs of travellers boarded different airlines to fly to various towns in several kinds of weather. Who accompanied whom, etc., can be discovered by following the clues below.\n\r\nMEN: Rainbeau, Aerofoot, Sonchine,\r\n Malgum, Milldue\r\nWOMEN: Gleebie, Sunline, Thymelie,\r\n Marriyette, Flourbud\r\nAIRLINES: Fleefly Flights, Skysters,\r\n Wingdom Ways, Airflue Airtimes,\r\n Taxiecloud Hops\r\nWEATHER: sunny day, rainy day, \r\nfoggy day, clear night, rainy night\r\nDESTINATIONS: Square Lakes, Townton, Cityville, Shortview, Los Purses\n\r\nCLUES: \r\n1. Sonchine, accompanied by his daughter, enjoyed, as passengers often do, a sense of spacious solitude above the fog. In contrast, Sunline was fascinated by her overhead view of the night lights of Cityville. She did not, on this occasion, fly with her usual travelling companion, Marriyette.\n\r\n2. On the first day they met, Rainbeau and Flourbud embarked on a Fleefly Flights plane, and it was sunny all the way to their destination. Fleefly Flights does not schedule flights to Los Purses.\n\r\n3. Airflue Airtimes, the only airline that services Townton, had to fly on a rainy day; but, even worse luck, Skysters had to negotiate a rainy-night landing in Los Purses.\n\r\n4. Taxiecloud Hops, not a fly-by-night company, schedules long flights to Gleebie's destination, Shortview.\n\r\n5. Milldue flew with his business partner, Aerofoot. They flew at night so that they could be at an early-morning meeting. They did not mind the rain.", "hint": "No hint available.", "answer": "Rainbeau/Flourbud--Fleefly Flights--sunny day--Square Lakes\r\nAerofoot/Milldue--Skysters--rainy night--Los Purses\r\nGleebie/Sonchine--Taxiecloud Hops--foggy day--Shortview\r\nSunline/Malgum--Wingdom Ways--clear night--Cityville\r\nThymelie/Marriyette--Airflue Airtimes--rainy day--Townton", "category": "Logic-Grid", "date": "04/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn separate days, five pairs of travellers boarded different airlines to fly to various towns in several kinds of weather. Who accompanied whom, etc., can be discovered by following the clues below.\n\r\nMEN: Rainbeau, Aerofoot, Sonchine,\r\n Malgum, Milldue\r\nWOMEN: Gleebie, Sunline, Thymelie,\r\n Marriyette, Flourbud\r\nAIRLINES: Fleefly Flights, Skysters,\r\n Wingdom Ways, Airflue Airtimes,\r\n Taxiecloud Hops\r\nWEATHER: sunny day, rainy day, \r\nfoggy day, clear night, rainy night\r\nDESTINATIONS: Square Lakes, Townton, Cityville, Shortview, Los Purses\n\r\nCLUES: \r\n1. Sonchine, accompanied by his daughter, enjoyed, as passengers often do, a sense of spacious solitude above the fog. In contrast, Sunline was fascinated by her overhead view of the night lights of Cityville. She did not, on this occasion, fly with her usual travelling companion, Marriyette.\n\r\n2. On the first day they met, Rainbeau and Flourbud embarked on a Fleefly Flights plane, and it was sunny all the way to their destination. Fleefly Flights does not schedule flights to Los Purses.\n\r\n3. Airflue Airtimes, the only airline that services Townton, had to fly on a rainy day; but, even worse luck, Skysters had to negotiate a rainy-night landing in Los Purses.\n\r\n4. Taxiecloud Hops, not a fly-by-night company, schedules long flights to Gleebie's destination, Shortview.\n\r\n5. Milldue flew with his business partner, Aerofoot. They flew at night so that they could be at an early-morning meeting. They did not mind the rain.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRainbeau/Flourbud--Fleefly Flights--sunny day--Square Lakes\r\nAerofoot/Milldue--Skysters--rainy night--Los Purses\r\nGleebie/Sonchine--Taxiecloud Hops--foggy day--Shortview\r\nSunline/Malgum--Wingdom Ways--clear night--Cityville\r\nThymelie/Marriyette--Airflue Airtimes--rainy day--Townton\n<|im_start|>answer\nRainbeau/Flourbud--Fleefly Flights--sunny day--Square Lakes\r\nAerofoot/Milldue--Skysters--rainy night--Los Purses\r\nGleebie/Sonchine--Taxiecloud Hops--foggy day--Shortview\r\nSunline/Malgum--Wingdom Ways--clear night--Cityville\r\nThymelie/Marriyette--Airflue Airtimes--rainy day--Townton\n<|im_end|>" }, { "id": "#25254", "title": "Packing For Pluvia", "fun": 2.88, "difficulty": 2.11, "author": "ndnumber1fan", "desc": "Kemal and his parents are part of an expedition that is going to settle a new planet, called Pluvia Three. Kemal knows that at the colony site on the planet, the average temperature is 45 degrees Centigrade, average wind speeds are 8,000 meters per hour, the planet rotates on its axis 431 times for every time it goes around its sun, and each rotation takes a third longer than Earth's. Rainfall is 254 centimeters per year, and gravity is about 78% of Earth's. Kemal is allowed to pack any four items from this list of his favorite belongings.\n\r\ndown-filled parka \r\nbattery-powered portable refrigerator \r\nAsian fighting kite \r\nbaseball bat \r\nMickey Mouse® calendar watch \r\ninflatable raft \r\nhockey skates \r\nbook collection \n\r\nWhich four items should Kemal pack?", "hint": "Assemble and interpret your data carefully. Make comparisons between Pluvia and Earth.", "answer": "Kemal should pack his inflatable raft, refrigerator, baseball bat, and books.\n\r\n45 degrees Centigrade = 113 degrees Fahrenheit \r\n8,000 meters per hour = 8 km per hour = 5 miles per hour \r\n431 revolutions (days) > 365 days in an Earth year \r\n254 cm = 100 in. of rainfall \n\r\nYou can use an encyclopedia, the World Wide Web, or a call to your local weather station to get weather information for the place where you live. You will see that the Pluvia Three colony is very hot, not at all windy, and very wet.\n\r\nClearly, it is too warm for the parka or the hockey skates, and there is not enough wind to fly the kite. The Mickey Mouse® watch won't be much use since the planet has a different calendar from Earth's 365 days per year and 24 hours per day.\n\r\nOn the other hand, with all that rainfall, there must be lakes and seas where a raft would come in handy. Kemal would want to keep his snacks cool, so the refrigerator would be useful. It would be possible (and probably fun) to play baseball on a planet with lower gravity, although Kemal and his friends might want to make the diamond bigger than it would be on Earth because the ball will fly farther. Finally, you can read books anywhere. That's one of the nice things about them.", "category": "Logic", "date": "08/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKemal and his parents are part of an expedition that is going to settle a new planet, called Pluvia Three. Kemal knows that at the colony site on the planet, the average temperature is 45 degrees Centigrade, average wind speeds are 8,000 meters per hour, the planet rotates on its axis 431 times for every time it goes around its sun, and each rotation takes a third longer than Earth's. Rainfall is 254 centimeters per year, and gravity is about 78% of Earth's. Kemal is allowed to pack any four items from this list of his favorite belongings.\n\r\ndown-filled parka \r\nbattery-powered portable refrigerator \r\nAsian fighting kite \r\nbaseball bat \r\nMickey Mouse® calendar watch \r\ninflatable raft \r\nhockey skates \r\nbook collection \n\r\nWhich four items should Kemal pack?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKemal should pack his inflatable raft, refrigerator, baseball bat, and books.\n\r\n45 degrees Centigrade = 113 degrees Fahrenheit \r\n8,000 meters per hour = 8 km per hour = 5 miles per hour \r\n431 revolutions (days) > 365 days in an Earth year \r\n254 cm = 100 in. of rainfall \n\r\nYou can use an encyclopedia, the World Wide Web, or a call to your local weather station to get weather information for the place where you live. You will see that the Pluvia Three colony is very hot, not at all windy, and very wet.\n\r\nClearly, it is too warm for the parka or the hockey skates, and there is not enough wind to fly the kite. The Mickey Mouse® watch won't be much use since the planet has a different calendar from Earth's 365 days per year and 24 hours per day.\n\r\nOn the other hand, with all that rainfall, there must be lakes and seas where a raft would come in handy. Kemal would want to keep his snacks cool, so the refrigerator would be useful. It would be possible (and probably fun) to play baseball on a planet with lower gravity, although Kemal and his friends might want to make the diamond bigger than it would be on Earth because the ball will fly farther. Finally, you can read books anywhere. That's one of the nice things about them.\n<|im_start|>answer\nKemal should pack his inflatable raft, refrigerator, baseball bat, and books.\n\r\n45 degrees Centigrade = 113 degrees Fahrenheit \r\n8,000 meters per hour = 8 km per hour = 5 miles per hour \r\n431 revolutions (days) > 365 days in an Earth year \r\n254 cm = 100 in. of rainfall \n\r\nYou can use an encyclopedia, the World Wide Web, or a call to your local weather station to get weather information for the place where you live. You will see that the Pluvia Three colony is very hot, not at all windy, and very wet.\n\r\nClearly, it is too warm for the parka or the hockey skates, and there is not enough wind to fly the kite. The Mickey Mouse® watch won't be much use since the planet has a different calendar from Earth's 365 days per year and 24 hours per day.\n\r\nOn the other hand, with all that rainfall, there must be lakes and seas where a raft would come in handy. Kemal would want to keep his snacks cool, so the refrigerator would be useful. It would be possible (and probably fun) to play baseball on a planet with lower gravity, although Kemal and his friends might want to make the diamond bigger than it would be on Earth because the ball will fly farther. Finally, you can read books anywhere. That's one of the nice things about them.\n<|im_end|>" }, { "id": "#23655", "title": "Family History", "fun": 2.88, "difficulty": 2.95, "author": "Gadget", "desc": "Mary and her four brothers had very similar histories. Determine when each was born, when they married, and when they died.\n\r\n1. The oldest sibling married two years after the one born in 1921.\n\r\n2. Mary had been married for 40 years when she died, and was born a year later than the brother who died in 1989.\n\r\n3. The youngest sibling married a year before Joseph and died a year before Michael.\n\r\n4. The one who married in 1950 died two years before the one who married in 1949.\n\r\n5. The one born in 1923 married more than a year before Joseph, and died more than a year before him.\n\r\n6. William is the only one with statistics that are all odd numbered years; Peter (whose dates are all even numbered) died a year after the one who married in 1946.", "hint": "No hint available.", "answer": "Mary, born 1924, married 1948, died 1988.\n\r\nMichael, born 1923, married 1946, died 1989.\n\r\nJoseph, born 1920, married 1949, died 1992.\n\r\nPeter, born 1922, married 1950, died 1990.\n\r\nWilliam, born 1921, married 1947, died 1991.", "category": "Logic-Grid", "date": "06/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMary and her four brothers had very similar histories. Determine when each was born, when they married, and when they died.\n\r\n1. The oldest sibling married two years after the one born in 1921.\n\r\n2. Mary had been married for 40 years when she died, and was born a year later than the brother who died in 1989.\n\r\n3. The youngest sibling married a year before Joseph and died a year before Michael.\n\r\n4. The one who married in 1950 died two years before the one who married in 1949.\n\r\n5. The one born in 1923 married more than a year before Joseph, and died more than a year before him.\n\r\n6. William is the only one with statistics that are all odd numbered years; Peter (whose dates are all even numbered) died a year after the one who married in 1946.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary, born 1924, married 1948, died 1988.\n\r\nMichael, born 1923, married 1946, died 1989.\n\r\nJoseph, born 1920, married 1949, died 1992.\n\r\nPeter, born 1922, married 1950, died 1990.\n\r\nWilliam, born 1921, married 1947, died 1991.\n<|im_start|>answer\nMary, born 1924, married 1948, died 1988.\n\r\nMichael, born 1923, married 1946, died 1989.\n\r\nJoseph, born 1920, married 1949, died 1992.\n\r\nPeter, born 1922, married 1950, died 1990.\n\r\nWilliam, born 1921, married 1947, died 1991.\n<|im_end|>" }, { "id": "#31985", "title": "Four Sisters", "fun": 2.88, "difficulty": 1.75, "author": "phemme", "desc": "I have three sisters, and all of us are mothers. My sister Kay has two nephews and three nieces. My sister Jane has one nephew and three nieces. My sister Belle has one nephew and five nieces. I have one daughter. How many nephews and nieces do I have?", "hint": "No hint available.", "answer": "I have two nephews and four nieces.\n\r\nKay has two girls.\r\nJane has one boy and two girls.\r\nBelle has one boy.", "category": "Logic", "date": "07/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have three sisters, and all of us are mothers. My sister Kay has two nephews and three nieces. My sister Jane has one nephew and three nieces. My sister Belle has one nephew and five nieces. I have one daughter. How many nephews and nieces do I have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI have two nephews and four nieces.\n\r\nKay has two girls.\r\nJane has one boy and two girls.\r\nBelle has one boy.\n<|im_start|>answer\nI have two nephews and four nieces.\n\r\nKay has two girls.\r\nJane has one boy and two girls.\r\nBelle has one boy.\n<|im_end|>" }, { "id": "#39960", "title": "Gardening Contest", "fun": 2.88, "difficulty": 2.25, "author": "pokpic", "desc": "Flowersville was having a gardening contest. The top four finishers in the contest are named Ally, Beth, Carla, and Ellyn. Their last names in alphabetical order are Bush, Jackson, Jones, and Monroe. Each person entered their most prized flowers. The flowers are tulips, daisies, roses, and cherry blossoms. Each person lives on a different street of Flowersville. The streets are Sunflower Street, Dandelion Drive, Buttercup Boulevard, and Lilac Lane. With the clues below determine the full name of each person, what place they got in the contest, what flower they entered, and what street they live on.\n\r\nClues\r\n1. The people are: Ally Bush, the person who got 3rd, the person who entered the roses, and the person who lives on Lilac Lane.\n\r\n2. The person who lives at Sunflower Street finished one place ahead of the person who lives on Dandelion Drive, but one place after the person on Buttercup Boulevard.\n\r\n3. Ms. Jackson, who planted the tulips, passed the house of Ellyn which is on Dandelion Drive.\n\r\n4. Ms. Monroe entered the roses which beat Beth's tulips.\n\r\n5. The person who planted the cherry blossoms got 1st.", "hint": "No hint available.", "answer": "Ally Bush lives on Buttercup Boulevard, entered the cherry blossoms, and got 1st place.\n\r\nBeth Jackson lives on Lilac Lane, entered the tulips, and got 4th place.\n\r\nCarla Monroe lives on Sunflower Street, entered the roses, and got 2nd place.\n\r\nEllyn Jones lives on Dandelion Drive, entered the daisies, and got 3rd place.", "category": "Logic-Grid", "date": "01/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFlowersville was having a gardening contest. The top four finishers in the contest are named Ally, Beth, Carla, and Ellyn. Their last names in alphabetical order are Bush, Jackson, Jones, and Monroe. Each person entered their most prized flowers. The flowers are tulips, daisies, roses, and cherry blossoms. Each person lives on a different street of Flowersville. The streets are Sunflower Street, Dandelion Drive, Buttercup Boulevard, and Lilac Lane. With the clues below determine the full name of each person, what place they got in the contest, what flower they entered, and what street they live on.\n\r\nClues\r\n1. The people are: Ally Bush, the person who got 3rd, the person who entered the roses, and the person who lives on Lilac Lane.\n\r\n2. The person who lives at Sunflower Street finished one place ahead of the person who lives on Dandelion Drive, but one place after the person on Buttercup Boulevard.\n\r\n3. Ms. Jackson, who planted the tulips, passed the house of Ellyn which is on Dandelion Drive.\n\r\n4. Ms. Monroe entered the roses which beat Beth's tulips.\n\r\n5. The person who planted the cherry blossoms got 1st.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlly Bush lives on Buttercup Boulevard, entered the cherry blossoms, and got 1st place.\n\r\nBeth Jackson lives on Lilac Lane, entered the tulips, and got 4th place.\n\r\nCarla Monroe lives on Sunflower Street, entered the roses, and got 2nd place.\n\r\nEllyn Jones lives on Dandelion Drive, entered the daisies, and got 3rd place.\n<|im_start|>answer\nAlly Bush lives on Buttercup Boulevard, entered the cherry blossoms, and got 1st place.\n\r\nBeth Jackson lives on Lilac Lane, entered the tulips, and got 4th place.\n\r\nCarla Monroe lives on Sunflower Street, entered the roses, and got 2nd place.\n\r\nEllyn Jones lives on Dandelion Drive, entered the daisies, and got 3rd place.\n<|im_end|>" }, { "id": "#29255", "title": "Which is Which?", "fun": 2.88, "difficulty": 1.62, "author": "JessicaLynn", "desc": "Five girls are all best friends. They all play softball. They were so excited that they were playing, they forgot which team, coach, and number each kid got. Could you help them?\n\n\r\nKids: Jamie, Vicky, Sandy, Jenny, Janie\r\nCoaches: Turner, Johnson, Spring, Smith, Cook\r\nNumbers: 1, 6, 12, 53, 99\r\nTeams: Lions, Tigers, Bears, Butterflies, Wolves\n\n\r\n1) The kids are Vicky, the one on team Tigers, #12, the one with Coach Johnson, and Jenny.\n\r\n2) Sandy, whose mom is the coach, is one of the two kids with the same first initial as their coach.\n\r\n3) Jamie is always #1 in everything, even softball.\n\r\n4) #6 is on the Lions team, whose coach is Turner.\n\r\n5) Vicky is not #99, nor is she on the Butterflies.\n\r\n6) Sandy is not with Coach Spring. \n\r\n7) Jamie is with Coach Cook, but is not a Butterfly.\n\r\n8) Janie always uses the same number every year for softball, and her number is not 99. It is also not double Vicky's number.\n\r\n9) Sandy's team is the Bears.\n\r\n10) Janie has the smallest animal for a team.", "hint": "Jamie-Coach Cook-#1-Tigers", "answer": "Jamie-Cook-#1-Tigers\r\nVicky-Turner-#6-Lions\r\nSandy-Smith-#12-Bears\r\nJenny-Spring-#99-Wolves\r\nJanie-Johnson-#53-Butterflies", "category": "Logic-Grid", "date": "03/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive girls are all best friends. They all play softball. They were so excited that they were playing, they forgot which team, coach, and number each kid got. Could you help them?\n\n\r\nKids: Jamie, Vicky, Sandy, Jenny, Janie\r\nCoaches: Turner, Johnson, Spring, Smith, Cook\r\nNumbers: 1, 6, 12, 53, 99\r\nTeams: Lions, Tigers, Bears, Butterflies, Wolves\n\n\r\n1) The kids are Vicky, the one on team Tigers, #12, the one with Coach Johnson, and Jenny.\n\r\n2) Sandy, whose mom is the coach, is one of the two kids with the same first initial as their coach.\n\r\n3) Jamie is always #1 in everything, even softball.\n\r\n4) #6 is on the Lions team, whose coach is Turner.\n\r\n5) Vicky is not #99, nor is she on the Butterflies.\n\r\n6) Sandy is not with Coach Spring. \n\r\n7) Jamie is with Coach Cook, but is not a Butterfly.\n\r\n8) Janie always uses the same number every year for softball, and her number is not 99. It is also not double Vicky's number.\n\r\n9) Sandy's team is the Bears.\n\r\n10) Janie has the smallest animal for a team.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJamie-Cook-#1-Tigers\r\nVicky-Turner-#6-Lions\r\nSandy-Smith-#12-Bears\r\nJenny-Spring-#99-Wolves\r\nJanie-Johnson-#53-Butterflies\n<|im_start|>answer\nJamie-Cook-#1-Tigers\r\nVicky-Turner-#6-Lions\r\nSandy-Smith-#12-Bears\r\nJenny-Spring-#99-Wolves\r\nJanie-Johnson-#53-Butterflies\n<|im_end|>" }, { "id": "#24282", "title": "Rock Band", "fun": 2.87, "difficulty": 1.6300000000000001, "author": "Punk_Rocker", "desc": "There were four boys; Alex, Tyler, Pete, and Kyle; they all decided to start a rock band. Although they are unnamed, they already have some songs written. Each member plays a different instrument, has a different job in the band, and has a different favorite band. Can you figure it out?\n\r\nBoys: Alex, Tyler, Pete, Kyle\n\r\nInstruments: Lead Guitar (L. Guitar), Rhythm Guitar (R. Guitar), Bass Guitar, Drums\n\r\nJobs: Lead Vocals (L. Vocals), Backup Vocals (B. Vocals), Writing Lyrics, Writing Tunes\n\r\nFavorite Bands: Green Day, All American Rejects (AAR), System of a Down (SOAD), Metallica\n\r\nNow on to the clues...\n\r\n1) Alex hates System of a Down.\r\n2) Kyle plays guitar, but not bass.\r\n3) One of the two whose job is to sing loves Metallica.\r\n4) The drummer always found it too hard to sing while playing his instrument.\r\n5) Pete always wrote the best lyrics, but never could come up with a tune.\r\n6) The lead vocalist, who is also the bassist, loves the All American Rejects.\r\n7) Tyler sometimes spends hours in his room, playing his guitar, trying to figure out a tune to go with Pete's lyrics.\r\n8) The lead guitarist loves Green Day.\n\r\nWith those clues, can you figure out who plays what instrument, what job they have, and what their favorite band is? Good luck!", "hint": "No hint available.", "answer": "Alex plays Bass Guitar, sings lead, and loves the All American Rejects.\n\r\nTyler plays Lead guitar, writes the tunes of their songs, and can't get enough of Green Day.\n\r\nPete plays Drums, writes the lyrics, and his favorite band is System of a Down.\n\r\nKyle plays Rhythm guitar, sings backup, and is constantly listening to Metallica.", "category": "Logic-Grid", "date": "07/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were four boys; Alex, Tyler, Pete, and Kyle; they all decided to start a rock band. Although they are unnamed, they already have some songs written. Each member plays a different instrument, has a different job in the band, and has a different favorite band. Can you figure it out?\n\r\nBoys: Alex, Tyler, Pete, Kyle\n\r\nInstruments: Lead Guitar (L. Guitar), Rhythm Guitar (R. Guitar), Bass Guitar, Drums\n\r\nJobs: Lead Vocals (L. Vocals), Backup Vocals (B. Vocals), Writing Lyrics, Writing Tunes\n\r\nFavorite Bands: Green Day, All American Rejects (AAR), System of a Down (SOAD), Metallica\n\r\nNow on to the clues...\n\r\n1) Alex hates System of a Down.\r\n2) Kyle plays guitar, but not bass.\r\n3) One of the two whose job is to sing loves Metallica.\r\n4) The drummer always found it too hard to sing while playing his instrument.\r\n5) Pete always wrote the best lyrics, but never could come up with a tune.\r\n6) The lead vocalist, who is also the bassist, loves the All American Rejects.\r\n7) Tyler sometimes spends hours in his room, playing his guitar, trying to figure out a tune to go with Pete's lyrics.\r\n8) The lead guitarist loves Green Day.\n\r\nWith those clues, can you figure out who plays what instrument, what job they have, and what their favorite band is? Good luck!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlex plays Bass Guitar, sings lead, and loves the All American Rejects.\n\r\nTyler plays Lead guitar, writes the tunes of their songs, and can't get enough of Green Day.\n\r\nPete plays Drums, writes the lyrics, and his favorite band is System of a Down.\n\r\nKyle plays Rhythm guitar, sings backup, and is constantly listening to Metallica.\n<|im_start|>answer\nAlex plays Bass Guitar, sings lead, and loves the All American Rejects.\n\r\nTyler plays Lead guitar, writes the tunes of their songs, and can't get enough of Green Day.\n\r\nPete plays Drums, writes the lyrics, and his favorite band is System of a Down.\n\r\nKyle plays Rhythm guitar, sings backup, and is constantly listening to Metallica.\n<|im_end|>" }, { "id": "#39018", "title": "Changelings", "fun": 2.87, "difficulty": 2.52, "author": "jppbl", "desc": "Changelings kidnap children and replace them with one of their own. Great care must be taken when choosing a child to switch places with. The changeling must watch the child and be able to mimic the personality and history of the child, including any talents or abilities of the child. In the past century, five children, three boys (Brian, Henry, and Oscar) and two girls (Ruth and Tess) have been kidnapped by changelings. Can you determine the last name and talents of each child, the changeling who switched places with them, and the age at which they were taken?\r\nLast names: Chase, Day, Hays, Love, Tanner\r\nChangelings: Bekar, Caliban, Igel, Puck, Speck\r\nTalents, Art, Dance, Piano, Poetry, Singing\r\nAges: 4,6,7,9,10\n\r\n1. Ruth, who was not the artist, was older than Tanner (who was kidnapped by Speck), but younger than the dancer (who was not Oscar).\r\n2. The 5 children are Ms. Hays, Henry, the child that Caliban took, the dancer, and the youngest.\r\n3. Day is older than the girl Bekar stole, who is older than the poet.\r\n4. Chase, who was 9, was older than Ruth.\r\n5. The changeling who stole Brian (who wasn't the oldest) had to exercise his voice, but this wasn't Igel.\r\n6. Love was younger than Tess, who was younger than Puck (who practiced Mozart night and day).\r\n7. The artist was the middle child.", "hint": "No hint available.", "answer": "Brian, Tanner, Speck, Singing, 4\r\nHenry, Day, Puck, Piano, 10\r\nOscar, Love, Caliban, Art, 7\r\nRuth, Hays, Igel, Poetry, 6\r\nTess, Chase, Bekar, Dance, 9", "category": "Logic-Grid", "date": "10/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChangelings kidnap children and replace them with one of their own. Great care must be taken when choosing a child to switch places with. The changeling must watch the child and be able to mimic the personality and history of the child, including any talents or abilities of the child. In the past century, five children, three boys (Brian, Henry, and Oscar) and two girls (Ruth and Tess) have been kidnapped by changelings. Can you determine the last name and talents of each child, the changeling who switched places with them, and the age at which they were taken?\r\nLast names: Chase, Day, Hays, Love, Tanner\r\nChangelings: Bekar, Caliban, Igel, Puck, Speck\r\nTalents, Art, Dance, Piano, Poetry, Singing\r\nAges: 4,6,7,9,10\n\r\n1. Ruth, who was not the artist, was older than Tanner (who was kidnapped by Speck), but younger than the dancer (who was not Oscar).\r\n2. The 5 children are Ms. Hays, Henry, the child that Caliban took, the dancer, and the youngest.\r\n3. Day is older than the girl Bekar stole, who is older than the poet.\r\n4. Chase, who was 9, was older than Ruth.\r\n5. The changeling who stole Brian (who wasn't the oldest) had to exercise his voice, but this wasn't Igel.\r\n6. Love was younger than Tess, who was younger than Puck (who practiced Mozart night and day).\r\n7. The artist was the middle child.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrian, Tanner, Speck, Singing, 4\r\nHenry, Day, Puck, Piano, 10\r\nOscar, Love, Caliban, Art, 7\r\nRuth, Hays, Igel, Poetry, 6\r\nTess, Chase, Bekar, Dance, 9\n<|im_start|>answer\nBrian, Tanner, Speck, Singing, 4\r\nHenry, Day, Puck, Piano, 10\r\nOscar, Love, Caliban, Art, 7\r\nRuth, Hays, Igel, Poetry, 6\r\nTess, Chase, Bekar, Dance, 9\n<|im_end|>" }, { "id": "#22151", "title": "Animal Olympics- 100 Meter Dash", "fun": 2.87, "difficulty": 1.23, "author": "cdrock", "desc": "In Animal world all the best competitors from all over the world are warming up for the big animal olympics. \n\r\nThe first olympic games is the 100 meter dash. Can you figure out who is which animal, and how they placed?\n\r\nNames- Tina, Aaron, John, Jessica, and Jamie\n\r\nAnimals- dog, cat, horse, mouse, and monkey\n\r\nClues:\n\r\n1. Aaron finished either 2nd or 3rd. \n\r\n2. The animal that finished 2nd was the monkey.\n\r\n3. Aaron is not a cat or mouse.\n\r\n4. Jamie is not a cat or monkey.\n\r\n5. Jamie did not finish 4th or 5th.\n\r\n6. The animal that finished 4th is not the cat or dog.\n\r\n7. Neither John nor Jessica finished 4th.\n\r\n8. John is the horse.\n\r\n9. Jessica finished in 3rd.", "hint": "No hint available.", "answer": "Tina-4th-mouse\r\nAaron-2nd-monkey\r\nJohn-5th-horse\r\nJessica-3rd-cat\r\nJamie-1st-dog", "category": "Logic-Grid", "date": "04/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Animal world all the best competitors from all over the world are warming up for the big animal olympics. \n\r\nThe first olympic games is the 100 meter dash. Can you figure out who is which animal, and how they placed?\n\r\nNames- Tina, Aaron, John, Jessica, and Jamie\n\r\nAnimals- dog, cat, horse, mouse, and monkey\n\r\nClues:\n\r\n1. Aaron finished either 2nd or 3rd. \n\r\n2. The animal that finished 2nd was the monkey.\n\r\n3. Aaron is not a cat or mouse.\n\r\n4. Jamie is not a cat or monkey.\n\r\n5. Jamie did not finish 4th or 5th.\n\r\n6. The animal that finished 4th is not the cat or dog.\n\r\n7. Neither John nor Jessica finished 4th.\n\r\n8. John is the horse.\n\r\n9. Jessica finished in 3rd.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTina-4th-mouse\r\nAaron-2nd-monkey\r\nJohn-5th-horse\r\nJessica-3rd-cat\r\nJamie-1st-dog\n<|im_start|>answer\nTina-4th-mouse\r\nAaron-2nd-monkey\r\nJohn-5th-horse\r\nJessica-3rd-cat\r\nJamie-1st-dog\n<|im_end|>" }, { "id": "#37653", "title": "On the Road In Twos", "fun": 2.87, "difficulty": 2.28, "author": "chaskey", "desc": "Five pairs of people rode five busses to five towns to see five other people. Who went where with whom can be mapped by following the clues below.\n\r\nTravellers: men: Albert, Andy, Arthur, Bill, Bob\r\n women: Alice, Anne, Barb, Bess, Betty\r\nBus drivers: Spedmo, Quickson, Gasly, Walkless, Buster\r\nTowns: Elsewhere, Crossings, Weedview, Uptown, Downtown\r\nPeople visited: Carl, Charley, Chris, Carla, Carrie\n\r\nClues:\r\n1. Alice and Barb went to see Carla for the next day's good shopping.\n\r\n2. Spedmo drove Bob and his brother through Weedview and Elsewhere on their way to see their sister Carrie on her birthday.\n\r\n3. Bill often goes to see his old college friend Charley.\n\r\n4. Quickson's bus company has the service to Uptown. In Downtown, Carl always enjoys it when his out-of-town friends come to play tennis.\n\r\n5. Ironically, before Arthur and Betty had met, they each had known Buster, who was now driving them to see Chris.\n\r\n6. Andy to this day has never been in Elsewhere, and so has never met Charley, who has never been to Andy's town. Charley had introduced Andy's cousin Anne to her future husband, who had wanted Andy to go with them to see Charley, but he, Andy, had already hopped Spedmo's bus.\n\r\n7. Gasly drove Albert and Bess to Downtown, and there they stayed.", "hint": "No hint available.", "answer": "Albert--Bess--Gasly--Downtown--Carl\r\nAndy--Bob--Spedmo--Crossings--Carrie\r\nArthur--Betty--Buster--Weedview--Chris\r\nAlice--Barb--Quickson--Uptown--Carla\r\nAnne--Bill--Walkless--Elsewhere--Charley", "category": "Logic-Grid", "date": "08/04/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive pairs of people rode five busses to five towns to see five other people. Who went where with whom can be mapped by following the clues below.\n\r\nTravellers: men: Albert, Andy, Arthur, Bill, Bob\r\n women: Alice, Anne, Barb, Bess, Betty\r\nBus drivers: Spedmo, Quickson, Gasly, Walkless, Buster\r\nTowns: Elsewhere, Crossings, Weedview, Uptown, Downtown\r\nPeople visited: Carl, Charley, Chris, Carla, Carrie\n\r\nClues:\r\n1. Alice and Barb went to see Carla for the next day's good shopping.\n\r\n2. Spedmo drove Bob and his brother through Weedview and Elsewhere on their way to see their sister Carrie on her birthday.\n\r\n3. Bill often goes to see his old college friend Charley.\n\r\n4. Quickson's bus company has the service to Uptown. In Downtown, Carl always enjoys it when his out-of-town friends come to play tennis.\n\r\n5. Ironically, before Arthur and Betty had met, they each had known Buster, who was now driving them to see Chris.\n\r\n6. Andy to this day has never been in Elsewhere, and so has never met Charley, who has never been to Andy's town. Charley had introduced Andy's cousin Anne to her future husband, who had wanted Andy to go with them to see Charley, but he, Andy, had already hopped Spedmo's bus.\n\r\n7. Gasly drove Albert and Bess to Downtown, and there they stayed.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlbert--Bess--Gasly--Downtown--Carl\r\nAndy--Bob--Spedmo--Crossings--Carrie\r\nArthur--Betty--Buster--Weedview--Chris\r\nAlice--Barb--Quickson--Uptown--Carla\r\nAnne--Bill--Walkless--Elsewhere--Charley\n<|im_start|>answer\nAlbert--Bess--Gasly--Downtown--Carl\r\nAndy--Bob--Spedmo--Crossings--Carrie\r\nArthur--Betty--Buster--Weedview--Chris\r\nAlice--Barb--Quickson--Uptown--Carla\r\nAnne--Bill--Walkless--Elsewhere--Charley\n<|im_end|>" }, { "id": "#17932", "title": "Email Chain", "fun": 2.87, "difficulty": 2.0, "author": "jmcleod", "desc": "John wants to send an email to everyone in his family, but he is having computer troubles and due to his slow dial-up connection he can only send out one email. His family consists of him and his brother, and their parents, his aunt and uncle on his Dad's side, their two sons, his aunt and uncle on his mom's side and their two daughters. He knows that his mom will only forwards emails to her husband and her kids. He knows his dad will only send emails to his brother, John's uncle, and he never forwards them to anyone. His aunt on his dad's side will forward emails to her kids and her husband and their youngest boy will always send them to his mom. The oldest cousin on his Dad's side will always forward them to his younger brother and John's brother and likewise John's Brother will send them to him. John's Aunt on his mom's side always sends them to her sister (John's mom) and her husband. John's two cousins on his mom's side and their father always share every email they get with each other. Who should John send his one email to so that everyone in his family will see it?", "hint": "Draw a diagram.", "answer": "John should send it to his aunt on his mom's side. She will send it to her husband and John's mom. John's uncle will share it with their daughters and John's mom will send it to John's brother and John's Dad. John's brother will send it to the cousin on his Dad's side who will send it to his younger brother who will send it to his mom who will send it to her husband who would have already received it from John's Dad, but that's ok (redundancy is allowed).", "category": "Logic", "date": "06/16/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn wants to send an email to everyone in his family, but he is having computer troubles and due to his slow dial-up connection he can only send out one email. His family consists of him and his brother, and their parents, his aunt and uncle on his Dad's side, their two sons, his aunt and uncle on his mom's side and their two daughters. He knows that his mom will only forwards emails to her husband and her kids. He knows his dad will only send emails to his brother, John's uncle, and he never forwards them to anyone. His aunt on his dad's side will forward emails to her kids and her husband and their youngest boy will always send them to his mom. The oldest cousin on his Dad's side will always forward them to his younger brother and John's brother and likewise John's Brother will send them to him. John's Aunt on his mom's side always sends them to her sister (John's mom) and her husband. John's two cousins on his mom's side and their father always share every email they get with each other. Who should John send his one email to so that everyone in his family will see it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn should send it to his aunt on his mom's side. She will send it to her husband and John's mom. John's uncle will share it with their daughters and John's mom will send it to John's brother and John's Dad. John's brother will send it to the cousin on his Dad's side who will send it to his younger brother who will send it to his mom who will send it to her husband who would have already received it from John's Dad, but that's ok (redundancy is allowed).\n<|im_start|>answer\nJohn should send it to his aunt on his mom's side. She will send it to her husband and John's mom. John's uncle will share it with their daughters and John's mom will send it to John's brother and John's Dad. John's brother will send it to the cousin on his Dad's side who will send it to his younger brother who will send it to his mom who will send it to her husband who would have already received it from John's Dad, but that's ok (redundancy is allowed).\n<|im_end|>" }, { "id": "#30091", "title": "Billiards Tournament", "fun": 2.87, "difficulty": 2.32, "author": "cdrock", "desc": "Seven amateur billiards players gather to play a billiards tournament. The players were divided into two sections: Section A has 4 players; and Section B has 3 players. Each player played against every other player in his/her Section. With the information below, can you determine each person's section, and to whom they won and lost.\n\r\nPlayers: Betty, Chris, Greg, Jill, John, Mary, and Tina.\n\n\r\n1. Every player from Section B has the same win-loss record.\n\r\n2. John lost all of his games.\n\r\n3. Mary, who defeated Jill, won more games than exactly 5 of the players.\n\r\n4. Jill lost to Greg, and Tina defeated Chris.", "hint": "No hint available.", "answer": "Section A:\n\r\nJohn: Lost to everyone.\r\nJill: Beat John, Lost to Mary and Greg.\r\nMary: Beat John, and Jill. Lost to Greg.\r\nGreg: Beat everyone.\n\r\nSection B:\n\r\nBetty: Beat Tina. Lost to Chris.\r\nTina: Beat Chris. Lost to Betty. \r\nChris: Beat Betty. Lost to Tina.", "category": "Logic", "date": "04/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSeven amateur billiards players gather to play a billiards tournament. The players were divided into two sections: Section A has 4 players; and Section B has 3 players. Each player played against every other player in his/her Section. With the information below, can you determine each person's section, and to whom they won and lost.\n\r\nPlayers: Betty, Chris, Greg, Jill, John, Mary, and Tina.\n\n\r\n1. Every player from Section B has the same win-loss record.\n\r\n2. John lost all of his games.\n\r\n3. Mary, who defeated Jill, won more games than exactly 5 of the players.\n\r\n4. Jill lost to Greg, and Tina defeated Chris.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSection A:\n\r\nJohn: Lost to everyone.\r\nJill: Beat John, Lost to Mary and Greg.\r\nMary: Beat John, and Jill. Lost to Greg.\r\nGreg: Beat everyone.\n\r\nSection B:\n\r\nBetty: Beat Tina. Lost to Chris.\r\nTina: Beat Chris. Lost to Betty. \r\nChris: Beat Betty. Lost to Tina.\n<|im_start|>answer\nSection A:\n\r\nJohn: Lost to everyone.\r\nJill: Beat John, Lost to Mary and Greg.\r\nMary: Beat John, and Jill. Lost to Greg.\r\nGreg: Beat everyone.\n\r\nSection B:\n\r\nBetty: Beat Tina. Lost to Chris.\r\nTina: Beat Chris. Lost to Betty. \r\nChris: Beat Betty. Lost to Tina.\n<|im_end|>" }, { "id": "#35944", "title": "Positive Notes On the Warm Coats", "fun": 2.87, "difficulty": 1.68, "author": "chaskey", "desc": "On a coffee break one day this past winter, four good friends decided that each would donate his extra coat to the local charity organization's \"Give One Warm Coat\" drive. Who gave what? See clues below.\n\r\nFriendly donors: Robert, Roy, Charles, Donald\r\nCoat types: trench coat, duffle, parka, pea coat\r\nSizes: small, medium, large, extra large\r\nAges of coats: 2, 3, 4, 5 years\r\nConditions of wear: fair, good, very good, excellent\n\r\nClues:\n\r\n1.The extra large coat was in better condition than the trench coat, and the small size coat was in good condition.\n\r\n2. Robert's medium size coat was given to him new, but he never wore it; it was, therefore, in excellent condition, even though it was twice as old as the parka.\n\r\n3. Charles' parka was in very good condition.\n\r\n4. Donald's coat was smaller than Roy's pea coat, which was in fair condition after five years of hard navy use.", "hint": "No hint available.", "answer": "Robert's duffle coat was medium size, 4 years old, and in excellent condition.\r\nRoy's pea coat was large, 5 years old, in fair condition.\r\nCharles' parka was extra large, 2 years old, in very good condition.\r\nDonald's trench was small size, 3 years old, in good condition.", "category": "Logic-Grid", "date": "03/29/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a coffee break one day this past winter, four good friends decided that each would donate his extra coat to the local charity organization's \"Give One Warm Coat\" drive. Who gave what? See clues below.\n\r\nFriendly donors: Robert, Roy, Charles, Donald\r\nCoat types: trench coat, duffle, parka, pea coat\r\nSizes: small, medium, large, extra large\r\nAges of coats: 2, 3, 4, 5 years\r\nConditions of wear: fair, good, very good, excellent\n\r\nClues:\n\r\n1.The extra large coat was in better condition than the trench coat, and the small size coat was in good condition.\n\r\n2. Robert's medium size coat was given to him new, but he never wore it; it was, therefore, in excellent condition, even though it was twice as old as the parka.\n\r\n3. Charles' parka was in very good condition.\n\r\n4. Donald's coat was smaller than Roy's pea coat, which was in fair condition after five years of hard navy use.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRobert's duffle coat was medium size, 4 years old, and in excellent condition.\r\nRoy's pea coat was large, 5 years old, in fair condition.\r\nCharles' parka was extra large, 2 years old, in very good condition.\r\nDonald's trench was small size, 3 years old, in good condition.\n<|im_start|>answer\nRobert's duffle coat was medium size, 4 years old, and in excellent condition.\r\nRoy's pea coat was large, 5 years old, in fair condition.\r\nCharles' parka was extra large, 2 years old, in very good condition.\r\nDonald's trench was small size, 3 years old, in good condition.\n<|im_end|>" }, { "id": "#43332", "title": "Say AAAAAAAAAAAAA", "fun": 2.87, "difficulty": 2.43, "author": "whsprec", "desc": "Five actors were auditioning for a play: Abbas, Abbott, Adam, Abram, and Addy. Their last names were Aflect, Andrews, Alexander, Arnold, and Ashley. Each brought his wife to the audition: Abigail, Adel, Adora, Aliyah, and Agatha. As it happens, they all came from cities that started with \"A\": Alpine, Anchor, Arroyo, Auburn, and Anaheim. From the clues given, determine each man's last name, the name of his wife, and the city they are from.\n\r\n1. Adora, Adel, and Aliyah play golf with Mrs. Aflect, but the woman who is married to Abbott and lives in Anaheim does not play.\r\n2. Adam, Abbas Andrews, Addy, and the man who lives in Anaheim played poker last night at Mr. Arnold's house in Arroyo.\r\n3. Mrs. Andrews, who lives in Alpine, and the woman who lives in Anaheim went to lunch with Abigail and Mr. Alexander, although none of these women is married to him.\r\n4. Adel is married to Abram, but Aliyah in not married to Adam.\r\n5. Aliyah had dinner last week with the Andrewses and the couple from Anchor.", "hint": "No hint available.", "answer": "Abigail and Adam Aflect from Anchor\r\nAdel and Abram Arnold from Arroyo\r\nAdora and Abbas Andrews from Alpine\r\nAliyah and Addy Alexander from Auburn\r\nAgatha and Abbott Ashley from Anaheim", "category": "Logic-Grid", "date": "10/13/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive actors were auditioning for a play: Abbas, Abbott, Adam, Abram, and Addy. Their last names were Aflect, Andrews, Alexander, Arnold, and Ashley. Each brought his wife to the audition: Abigail, Adel, Adora, Aliyah, and Agatha. As it happens, they all came from cities that started with \"A\": Alpine, Anchor, Arroyo, Auburn, and Anaheim. From the clues given, determine each man's last name, the name of his wife, and the city they are from.\n\r\n1. Adora, Adel, and Aliyah play golf with Mrs. Aflect, but the woman who is married to Abbott and lives in Anaheim does not play.\r\n2. Adam, Abbas Andrews, Addy, and the man who lives in Anaheim played poker last night at Mr. Arnold's house in Arroyo.\r\n3. Mrs. Andrews, who lives in Alpine, and the woman who lives in Anaheim went to lunch with Abigail and Mr. Alexander, although none of these women is married to him.\r\n4. Adel is married to Abram, but Aliyah in not married to Adam.\r\n5. Aliyah had dinner last week with the Andrewses and the couple from Anchor.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbigail and Adam Aflect from Anchor\r\nAdel and Abram Arnold from Arroyo\r\nAdora and Abbas Andrews from Alpine\r\nAliyah and Addy Alexander from Auburn\r\nAgatha and Abbott Ashley from Anaheim\n<|im_start|>answer\nAbigail and Adam Aflect from Anchor\r\nAdel and Abram Arnold from Arroyo\r\nAdora and Abbas Andrews from Alpine\r\nAliyah and Addy Alexander from Auburn\r\nAgatha and Abbott Ashley from Anaheim\n<|im_end|>" }, { "id": "#21368", "title": "A Game of Cards", "fun": 2.87, "difficulty": 2.1, "author": "cdrock", "desc": "My worst enemy or in other words my boss, made me a bet that if I get it right then I can have his job and be rich for the rest of my life, but if I get it wrong then I lose my job and I give him all the money I have. He told me that it is a game of cards and there will be 7 cards (8 through ace) face down in a certain order. He will give me 6 clues on the order of them. If I can get the order right then I win the bet. I accepted the bet thinking it would be really easy but I was wrong. Can you help me? What is the order?\n\r\n1. The \"ace\" is two cards away from the \"9\" card. (1 between)\n\r\n2. The \"8\" card is between the \"10\" card and the \"king\".\n\r\n3. The \"king\" is four cards away from the ace. (3 between)\n\r\n4. The \"jack\" is directly right of the \"ace\".\n\r\n5. The \"Queen\" is in the middle.\n\r\n6. The \"jack\" is somewhere right of the \"10\" card.", "hint": "No hint available.", "answer": "King, 8, 10, Queen, Ace, Jack, 9", "category": "Logic", "date": "03/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy worst enemy or in other words my boss, made me a bet that if I get it right then I can have his job and be rich for the rest of my life, but if I get it wrong then I lose my job and I give him all the money I have. He told me that it is a game of cards and there will be 7 cards (8 through ace) face down in a certain order. He will give me 6 clues on the order of them. If I can get the order right then I win the bet. I accepted the bet thinking it would be really easy but I was wrong. Can you help me? What is the order?\n\r\n1. The \"ace\" is two cards away from the \"9\" card. (1 between)\n\r\n2. The \"8\" card is between the \"10\" card and the \"king\".\n\r\n3. The \"king\" is four cards away from the ace. (3 between)\n\r\n4. The \"jack\" is directly right of the \"ace\".\n\r\n5. The \"Queen\" is in the middle.\n\r\n6. The \"jack\" is somewhere right of the \"10\" card.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKing, 8, 10, Queen, Ace, Jack, 9\n<|im_start|>answer\nKing, 8, 10, Queen, Ace, Jack, 9\n<|im_end|>" }, { "id": "#23182", "title": "State Stones", "fun": 2.86, "difficulty": 2.19, "author": "cinnamon30", "desc": "At a recent conference, the governor of Ohio and the governors of other states decided to propose state gems to accompany their state flowers, birds and songs. They agreed not to duplicate any choices. Because of variations in the legislative calendars, the new stones were chosen at different times. From the info provided, determine the order in which the states made the decisions, each states governor, and the stone chosen.\n\r\nStates: Iowa, Maine, Ohio, Texas\r\nGovernors: Bracket, Miller, Paulsen, Savron\r\nStones: garnet, ruby, sapphire, topaz\n\r\n1. Three of the governors are: Bracket, the governor of the state that chose the sapphire, and the person who runs the fourth state to pick a gem.\r\n2. The garnet was chosen after Texas chose its state stone.\r\n3. Iowa's governor isn't Bracket.\r\n4. Miller's state chose its stone before Bracket's state did.\r\n5. Maine chose its stone before the state that picked the sapphire.\r\n6. Iowa chose its stone after Savron's state chose, and before the ruby was chosen.", "hint": "No hint available.", "answer": "1st - Maine, Savron, topaz\r\n2nd - Iowa, Miller, sapphire\r\n3rd - Texas, Bracket, ruby\r\n4th - Ohio, Paulsen, garnet", "category": "Logic-Grid", "date": "05/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a recent conference, the governor of Ohio and the governors of other states decided to propose state gems to accompany their state flowers, birds and songs. They agreed not to duplicate any choices. Because of variations in the legislative calendars, the new stones were chosen at different times. From the info provided, determine the order in which the states made the decisions, each states governor, and the stone chosen.\n\r\nStates: Iowa, Maine, Ohio, Texas\r\nGovernors: Bracket, Miller, Paulsen, Savron\r\nStones: garnet, ruby, sapphire, topaz\n\r\n1. Three of the governors are: Bracket, the governor of the state that chose the sapphire, and the person who runs the fourth state to pick a gem.\r\n2. The garnet was chosen after Texas chose its state stone.\r\n3. Iowa's governor isn't Bracket.\r\n4. Miller's state chose its stone before Bracket's state did.\r\n5. Maine chose its stone before the state that picked the sapphire.\r\n6. Iowa chose its stone after Savron's state chose, and before the ruby was chosen.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st - Maine, Savron, topaz\r\n2nd - Iowa, Miller, sapphire\r\n3rd - Texas, Bracket, ruby\r\n4th - Ohio, Paulsen, garnet\n<|im_start|>answer\n1st - Maine, Savron, topaz\r\n2nd - Iowa, Miller, sapphire\r\n3rd - Texas, Bracket, ruby\r\n4th - Ohio, Paulsen, garnet\n<|im_end|>" }, { "id": "#29004", "title": "School 2", "fun": 2.86, "difficulty": 1.33, "author": "thompson1", "desc": "Four kids go to four different schools and have to get up at four different times. Figure out what each kid's first and last names are, what school they go to, and what time they wake up.\n\r\nFirst Names - Adam, Jessica, James, and Joseph\r\nLast Names - Smith, Jones, Thompson, Bower\r\nSchools - Cramerton Elementary, Greenwood Elementary, Robinson Middle School, Park Road High School\r\nTimes - 6:30 AM, 7:00 AM, 7:15 AM, and 7:45 AM\n\r\nAssume that: \r\nEveryone in elementary school is the same age and is younger than everyone in middle and high school.\r\nEveryone in middle school is younger than everyone in high school.\n\r\n1. The four kids are: Adam, the one whose last name is Smith, the one who goes to high school, and the one who wakes up at 7:15.\n\r\n2. No one's last name starts with the same letter as their first name.\n\r\n3. The kid whose last name is Smith is younger than Adam, who doesn't wake up at 7:00.\n\r\n4. Joseph wakes up 30 minutes after the kid whose last name is Bower.\n\r\n5. James Thompson wakes up 15 minutes after Joseph.\n\r\n6. Joseph goes to Greenwood Elementary.", "hint": "No hint available.", "answer": "Adam Jones wakes up at 7:45 and goes to Robinson Middle School.\r\nJessica Bower wakes up at 6:30 and goes to Park Road High School.\r\nJames Thompson wakes up at 7:15 and goes to Cramerton Elementary School.\r\nJoseph Smith wakes up at 7:00 and goes to school at Greenwood Elementary.", "category": "Logic-Grid", "date": "03/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour kids go to four different schools and have to get up at four different times. Figure out what each kid's first and last names are, what school they go to, and what time they wake up.\n\r\nFirst Names - Adam, Jessica, James, and Joseph\r\nLast Names - Smith, Jones, Thompson, Bower\r\nSchools - Cramerton Elementary, Greenwood Elementary, Robinson Middle School, Park Road High School\r\nTimes - 6:30 AM, 7:00 AM, 7:15 AM, and 7:45 AM\n\r\nAssume that: \r\nEveryone in elementary school is the same age and is younger than everyone in middle and high school.\r\nEveryone in middle school is younger than everyone in high school.\n\r\n1. The four kids are: Adam, the one whose last name is Smith, the one who goes to high school, and the one who wakes up at 7:15.\n\r\n2. No one's last name starts with the same letter as their first name.\n\r\n3. The kid whose last name is Smith is younger than Adam, who doesn't wake up at 7:00.\n\r\n4. Joseph wakes up 30 minutes after the kid whose last name is Bower.\n\r\n5. James Thompson wakes up 15 minutes after Joseph.\n\r\n6. Joseph goes to Greenwood Elementary.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam Jones wakes up at 7:45 and goes to Robinson Middle School.\r\nJessica Bower wakes up at 6:30 and goes to Park Road High School.\r\nJames Thompson wakes up at 7:15 and goes to Cramerton Elementary School.\r\nJoseph Smith wakes up at 7:00 and goes to school at Greenwood Elementary.\n<|im_start|>answer\nAdam Jones wakes up at 7:45 and goes to Robinson Middle School.\r\nJessica Bower wakes up at 6:30 and goes to Park Road High School.\r\nJames Thompson wakes up at 7:15 and goes to Cramerton Elementary School.\r\nJoseph Smith wakes up at 7:00 and goes to school at Greenwood Elementary.\n<|im_end|>" }, { "id": "#50030", "title": "Numberrangements", "fun": 2.86, "difficulty": 2.88, "author": "eighsse", "desc": "In Numberrangements, you are given an arrangement of letters. The letters represent all of the whole numbers from 1 to the total number of letters used. Each letter represents a different number. Using the clues given, find which number each letter represents.\n\r\nABC\r\nDEF\r\nGHI\n\r\n1. The sum of the top row is greater than the sum of the middle row, which is greater than the sum of the bottom row.\r\n2. E is a prime factor of G.\r\n3. F is greater than A.\r\n4. The sum of B and G is equal to H.\r\n5. I is not 1.", "hint": "No hint available.", "answer": "A=7, B=1, C=9\r\nD=6, E=2, F=8\r\nG=4, H=5, I=3\n\r\nFrom Clue 2, E must be 2, 3, 5, or 7, but it cannot be 5 or 7 because that would force G to be a greater multiple of 5 or 7, and only the numbers 1 to 9 are used. E must be 2 or 3 and G must be 4, 6, 8, or 9.\r\nLet's try I=2. In that case, E=3 and G=6. H must be greater than 6 because of Clue 4. The most G+H+I can be is 14 because of Clue 1, since the sum of all nine numbers is only 45. So, I cannot be 2, and it therefore must be at least 3 because of Clue 5.\r\nIf I=4, then G cannot be 4, and must be 6, 8, or 9. Again, since H must be greater than G, the bottom row's sum will be too high. If I = 5, then the minimums for G and H would be 4 and 6, respectively -- a sum of 15. If I = 6, then the minimum sum again is 15.\r\nThis means I MUST be 3, which forces E=2 and G=4, 6, or 8. If G is 6 or 8, the sum of the bottom row will be too great, so G=4. The greatest that H can be is 7, which also means that B can only be 1, 2, or 3, from Clue 4. But 2 and 3 are already used, so B=1 and H=5.\r\nThis leaves A, C, D, and F, to be paired with 6, 7, 8, and 9, in some order. We know from Clue 1 that A+B+C > D+E+F, but E is already 1 greater than B, and from Clue 3, we know that F > A. This means that C must be at least 3 greater than D to make up for the top row trailing by at least 2. So, C must be 9, and D must be 6. This leaves 7 and 8 to be A and F, so of course, F=8 and A=7.", "category": "Logic", "date": "12/21/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Numberrangements, you are given an arrangement of letters. The letters represent all of the whole numbers from 1 to the total number of letters used. Each letter represents a different number. Using the clues given, find which number each letter represents.\n\r\nABC\r\nDEF\r\nGHI\n\r\n1. The sum of the top row is greater than the sum of the middle row, which is greater than the sum of the bottom row.\r\n2. E is a prime factor of G.\r\n3. F is greater than A.\r\n4. The sum of B and G is equal to H.\r\n5. I is not 1.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA=7, B=1, C=9\r\nD=6, E=2, F=8\r\nG=4, H=5, I=3\n\r\nFrom Clue 2, E must be 2, 3, 5, or 7, but it cannot be 5 or 7 because that would force G to be a greater multiple of 5 or 7, and only the numbers 1 to 9 are used. E must be 2 or 3 and G must be 4, 6, 8, or 9.\r\nLet's try I=2. In that case, E=3 and G=6. H must be greater than 6 because of Clue 4. The most G+H+I can be is 14 because of Clue 1, since the sum of all nine numbers is only 45. So, I cannot be 2, and it therefore must be at least 3 because of Clue 5.\r\nIf I=4, then G cannot be 4, and must be 6, 8, or 9. Again, since H must be greater than G, the bottom row's sum will be too high. If I = 5, then the minimums for G and H would be 4 and 6, respectively -- a sum of 15. If I = 6, then the minimum sum again is 15.\r\nThis means I MUST be 3, which forces E=2 and G=4, 6, or 8. If G is 6 or 8, the sum of the bottom row will be too great, so G=4. The greatest that H can be is 7, which also means that B can only be 1, 2, or 3, from Clue 4. But 2 and 3 are already used, so B=1 and H=5.\r\nThis leaves A, C, D, and F, to be paired with 6, 7, 8, and 9, in some order. We know from Clue 1 that A+B+C > D+E+F, but E is already 1 greater than B, and from Clue 3, we know that F > A. This means that C must be at least 3 greater than D to make up for the top row trailing by at least 2. So, C must be 9, and D must be 6. This leaves 7 and 8 to be A and F, so of course, F=8 and A=7.\n<|im_start|>answer\nA=7, B=1, C=9\r\nD=6, E=2, F=8\r\nG=4, H=5, I=3\n\r\nFrom Clue 2, E must be 2, 3, 5, or 7, but it cannot be 5 or 7 because that would force G to be a greater multiple of 5 or 7, and only the numbers 1 to 9 are used. E must be 2 or 3 and G must be 4, 6, 8, or 9.\r\nLet's try I=2. In that case, E=3 and G=6. H must be greater than 6 because of Clue 4. The most G+H+I can be is 14 because of Clue 1, since the sum of all nine numbers is only 45. So, I cannot be 2, and it therefore must be at least 3 because of Clue 5.\r\nIf I=4, then G cannot be 4, and must be 6, 8, or 9. Again, since H must be greater than G, the bottom row's sum will be too high. If I = 5, then the minimums for G and H would be 4 and 6, respectively -- a sum of 15. If I = 6, then the minimum sum again is 15.\r\nThis means I MUST be 3, which forces E=2 and G=4, 6, or 8. If G is 6 or 8, the sum of the bottom row will be too great, so G=4. The greatest that H can be is 7, which also means that B can only be 1, 2, or 3, from Clue 4. But 2 and 3 are already used, so B=1 and H=5.\r\nThis leaves A, C, D, and F, to be paired with 6, 7, 8, and 9, in some order. We know from Clue 1 that A+B+C > D+E+F, but E is already 1 greater than B, and from Clue 3, we know that F > A. This means that C must be at least 3 greater than D to make up for the top row trailing by at least 2. So, C must be 9, and D must be 6. This leaves 7 and 8 to be A and F, so of course, F=8 and A=7.\n<|im_end|>" }, { "id": "#52380", "title": "Speak The Truth", "fun": 2.86, "difficulty": 1.92, "author": "Rove_Tarts", "desc": "You find yourself on a cliche island where everyone always lies or tells the truth. You see some natives and decide to get information.\n\r\nYou: Are you mute?\n\r\nLuke: *shakes head*\n\r\nLily: *shakes head*\n\r\nLilac: Exactly one of Luke and Lily is mute.\n\r\nLiam: Luke and I are both liars or truth-tellers. Same with Lisa and I.\n\r\nLisa: The only liar is either Lily or Liam. \n\r\nWho is lying? Who is mute?", "hint": "Just because someone didn't say something, doesn't mean they are mute.", "answer": "Luke isn't mute and a truth-teller.\r\nLily is mute and a liar.\r\nLilac is a truth-teller.\r\nLiam is a truth-teller.\r\nLisa is a truth-teller.\n\r\nIf Liam is a liar, then Lisa and Luke are different than him, therefore they are truth-tellers.\r\nIf Liam is a truth-teller, then Lisa and Luke are the same as him, therefore they are truth-tellers.\n\r\nLisa and Luke are truth-tellers and can speak.\n\r\nLisa confirms that Lilac is a truth-teller.\n\r\nIf Luke or Lily is mute, they are liars.\n\r\nTherefore we can conclude that Luke or Lily is a liar from Lilac's statement.\n\r\nLuke is a truth-teller, therefore Lily is a liar.\n\r\nSince Lily is a liar, Liam is a truth-teller because of Lisa's statement.", "category": "Logic", "date": "04/17/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou find yourself on a cliche island where everyone always lies or tells the truth. You see some natives and decide to get information.\n\r\nYou: Are you mute?\n\r\nLuke: *shakes head*\n\r\nLily: *shakes head*\n\r\nLilac: Exactly one of Luke and Lily is mute.\n\r\nLiam: Luke and I are both liars or truth-tellers. Same with Lisa and I.\n\r\nLisa: The only liar is either Lily or Liam. \n\r\nWho is lying? Who is mute?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLuke isn't mute and a truth-teller.\r\nLily is mute and a liar.\r\nLilac is a truth-teller.\r\nLiam is a truth-teller.\r\nLisa is a truth-teller.\n\r\nIf Liam is a liar, then Lisa and Luke are different than him, therefore they are truth-tellers.\r\nIf Liam is a truth-teller, then Lisa and Luke are the same as him, therefore they are truth-tellers.\n\r\nLisa and Luke are truth-tellers and can speak.\n\r\nLisa confirms that Lilac is a truth-teller.\n\r\nIf Luke or Lily is mute, they are liars.\n\r\nTherefore we can conclude that Luke or Lily is a liar from Lilac's statement.\n\r\nLuke is a truth-teller, therefore Lily is a liar.\n\r\nSince Lily is a liar, Liam is a truth-teller because of Lisa's statement.\n<|im_start|>answer\nLuke isn't mute and a truth-teller.\r\nLily is mute and a liar.\r\nLilac is a truth-teller.\r\nLiam is a truth-teller.\r\nLisa is a truth-teller.\n\r\nIf Liam is a liar, then Lisa and Luke are different than him, therefore they are truth-tellers.\r\nIf Liam is a truth-teller, then Lisa and Luke are the same as him, therefore they are truth-tellers.\n\r\nLisa and Luke are truth-tellers and can speak.\n\r\nLisa confirms that Lilac is a truth-teller.\n\r\nIf Luke or Lily is mute, they are liars.\n\r\nTherefore we can conclude that Luke or Lily is a liar from Lilac's statement.\n\r\nLuke is a truth-teller, therefore Lily is a liar.\n\r\nSince Lily is a liar, Liam is a truth-teller because of Lisa's statement.\n<|im_end|>" }, { "id": "#3008", "title": "Salt Dealer", "fun": 2.86, "difficulty": 1.81, "author": "PeaceJo", "desc": "Ali ben-Ibrahim was a salt dealer in old Baghdad. Every day he went from his home just outside the city to the market with two huge sacks of salt tied to the back of his donkey. His donkey was a small, evil-smelling brute called Roxanna. It was, however, not lacking in the brains department. One hot day, as they passed along the banks of the Tigris, it broke free from Ali and plunged into the cool water. When the irate salt-seller finally persuaded the beast to leave the river it immediately noticed that much of the salt had dissolved and its load was therefore considerably lighter. After that, no matter how hard Ali tried, he could not prevent the donkey from diving into the river and ruining its load of salt. But when it came to lateral thinking, Ali himself was no slouch. One day he loaded up the donkey as usual and, as usual, the animal plunged into the river. Then it learned its lesson and never tried that trick again.\n\r\nWhat had Ali done?", "hint": "No hint available.", "answer": "He had loaded the sacks with sand, so they were actually heavier after their dip in the Tigris.", "category": "Logic", "date": "03/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAli ben-Ibrahim was a salt dealer in old Baghdad. Every day he went from his home just outside the city to the market with two huge sacks of salt tied to the back of his donkey. His donkey was a small, evil-smelling brute called Roxanna. It was, however, not lacking in the brains department. One hot day, as they passed along the banks of the Tigris, it broke free from Ali and plunged into the cool water. When the irate salt-seller finally persuaded the beast to leave the river it immediately noticed that much of the salt had dissolved and its load was therefore considerably lighter. After that, no matter how hard Ali tried, he could not prevent the donkey from diving into the river and ruining its load of salt. But when it came to lateral thinking, Ali himself was no slouch. One day he loaded up the donkey as usual and, as usual, the animal plunged into the river. Then it learned its lesson and never tried that trick again.\n\r\nWhat had Ali done?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe had loaded the sacks with sand, so they were actually heavier after their dip in the Tigris.\n<|im_start|>answer\nHe had loaded the sacks with sand, so they were actually heavier after their dip in the Tigris.\n<|im_end|>" }, { "id": "#24470", "title": "Flour Power", "fun": 2.86, "difficulty": 1.42, "author": "tjm531", "desc": "While studying to be a nutritionist, Kristen learned of the many health benefits of using alternate types of flour -- but convincing her family was another matter! To win them over, Kristen prepared a different type of dessert (including beignets) each weekday last week, each time using a different type of flour. After tasting her delicacies, Kristen's family didn't complain any longer -- they were too busy eating! From the information provided, determine the type of flour used to make dessert she served on each week day.\n\r\nDesserts: beignets, brownies, cookies, cupcakes, turnovers\n\r\nFlours: barley, oat, rice, soy, wheat\n\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\n\r\n1. The cupcakes were served the day after the dessert made with wheat flour. The turnovers were made on Friday.\n\r\n2. Kristen used rice flour to make Wednesday's dessert (which wasn't cupcakes).\n\r\n3. The barley flour dessert was served later in the week than the cookies, which weren't Monday's dessert.\n\r\n4. The brownies were made with oat flour.", "hint": "No hint available.", "answer": "Monday, beignets, wheat\r\nTuesday, cupcakes, soy\r\nWednesday, cookies, rice\r\nThursday, brownies, oat\r\nFriday, turnovers, barley", "category": "Logic-Grid", "date": "07/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile studying to be a nutritionist, Kristen learned of the many health benefits of using alternate types of flour -- but convincing her family was another matter! To win them over, Kristen prepared a different type of dessert (including beignets) each weekday last week, each time using a different type of flour. After tasting her delicacies, Kristen's family didn't complain any longer -- they were too busy eating! From the information provided, determine the type of flour used to make dessert she served on each week day.\n\r\nDesserts: beignets, brownies, cookies, cupcakes, turnovers\n\r\nFlours: barley, oat, rice, soy, wheat\n\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\n\r\n1. The cupcakes were served the day after the dessert made with wheat flour. The turnovers were made on Friday.\n\r\n2. Kristen used rice flour to make Wednesday's dessert (which wasn't cupcakes).\n\r\n3. The barley flour dessert was served later in the week than the cookies, which weren't Monday's dessert.\n\r\n4. The brownies were made with oat flour.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday, beignets, wheat\r\nTuesday, cupcakes, soy\r\nWednesday, cookies, rice\r\nThursday, brownies, oat\r\nFriday, turnovers, barley\n<|im_start|>answer\nMonday, beignets, wheat\r\nTuesday, cupcakes, soy\r\nWednesday, cookies, rice\r\nThursday, brownies, oat\r\nFriday, turnovers, barley\n<|im_end|>" }, { "id": "#34590", "title": "The Christmas Party", "fun": 2.86, "difficulty": 2.13, "author": "thompson1", "desc": "The Thompsons were hosting a Christmas party that 5 adults and 5 kids attended. They decided to have gifts be exchanged at their party! Each adult would give each child 1 present, and receive 1 present from that child. One of the Thompson children (who was not participating in the gift exchanges) sneaked around town to figure out what each person was giving and getting because he could not think of anything except for the party and had to find something to do before he went crazy with anticipation! While he was sneaking around, he couldn't be carrying a pen and paper with him (they would be too loud!), so he had to memorize certain facts. Can you help him assemble the list adults, children, and gifts?\n\r\nAdults: Harry, Derek, Zack, Amy, and Grace\r\nChildren: Rose, Ashley, Brittany, Tom, and Charlie\r\nGifts given to children: Toy Car, Mini Dartboard, Candy, a Basketball, and a Baseball Bat\r\nGifts given to adults: CD, a Hat, a DVD, a Book, and a T-Shirt\n\r\n1. The Adults are: Harry, the one who gave a present to Tom, the one who gave candy, the one who received a T-Shirt, and Amy.\n\r\n2. The children are: Rose, the one who received a present from Zack (who isn't receiving a book), the one who gave a Hat, the one who received a Toy Car, and Charlie.\n\r\n3. Derek is not going to give a present to Tom (who won't give a CD).\n\r\n4. The boy that will receive a baseball bat will not give an article of clothing.\n\r\n5. No man is giving candy to any of the kids.\n\r\n6. Charlie hates baseball, but will love his present!\n\r\n7. Ashley is giving a present (which isn't a CD or a DVD) to the adult that shares her first initial.\n\r\n8. A basketball will be given by the person who will receive the CD.\n\r\n9. Rose will not receive a present that involves throwing anything.", "hint": "No hint available.", "answer": "Harry and Charlie exchanged a CD and a Basketball\r\nDerek and Brittany exchanged a T-Shirt and a Toy Car\r\nZack and Tom exchanged a DVD and a Baseball Bat\r\nAmy and Ashley exchanged a Hat and a Mini Dartboard\r\nGrace and Rose exchanged a Book and some Candy", "category": "Logic-Grid", "date": "12/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Thompsons were hosting a Christmas party that 5 adults and 5 kids attended. They decided to have gifts be exchanged at their party! Each adult would give each child 1 present, and receive 1 present from that child. One of the Thompson children (who was not participating in the gift exchanges) sneaked around town to figure out what each person was giving and getting because he could not think of anything except for the party and had to find something to do before he went crazy with anticipation! While he was sneaking around, he couldn't be carrying a pen and paper with him (they would be too loud!), so he had to memorize certain facts. Can you help him assemble the list adults, children, and gifts?\n\r\nAdults: Harry, Derek, Zack, Amy, and Grace\r\nChildren: Rose, Ashley, Brittany, Tom, and Charlie\r\nGifts given to children: Toy Car, Mini Dartboard, Candy, a Basketball, and a Baseball Bat\r\nGifts given to adults: CD, a Hat, a DVD, a Book, and a T-Shirt\n\r\n1. The Adults are: Harry, the one who gave a present to Tom, the one who gave candy, the one who received a T-Shirt, and Amy.\n\r\n2. The children are: Rose, the one who received a present from Zack (who isn't receiving a book), the one who gave a Hat, the one who received a Toy Car, and Charlie.\n\r\n3. Derek is not going to give a present to Tom (who won't give a CD).\n\r\n4. The boy that will receive a baseball bat will not give an article of clothing.\n\r\n5. No man is giving candy to any of the kids.\n\r\n6. Charlie hates baseball, but will love his present!\n\r\n7. Ashley is giving a present (which isn't a CD or a DVD) to the adult that shares her first initial.\n\r\n8. A basketball will be given by the person who will receive the CD.\n\r\n9. Rose will not receive a present that involves throwing anything.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry and Charlie exchanged a CD and a Basketball\r\nDerek and Brittany exchanged a T-Shirt and a Toy Car\r\nZack and Tom exchanged a DVD and a Baseball Bat\r\nAmy and Ashley exchanged a Hat and a Mini Dartboard\r\nGrace and Rose exchanged a Book and some Candy\n<|im_start|>answer\nHarry and Charlie exchanged a CD and a Basketball\r\nDerek and Brittany exchanged a T-Shirt and a Toy Car\r\nZack and Tom exchanged a DVD and a Baseball Bat\r\nAmy and Ashley exchanged a Hat and a Mini Dartboard\r\nGrace and Rose exchanged a Book and some Candy\n<|im_end|>" }, { "id": "#8821", "title": "Heads or Tails", "fun": 2.86, "difficulty": 2.7, "author": "lesternoronha1", "desc": "You are blindfolded before a table. On the table are a very large number of pennies. You are told 128 of the pennies are heads up and the rest are tails up. How can you create two subgroups of pennies, each with the same number of heads facing up, while remaining blindfolded?", "hint": "No hint available.", "answer": "Create a subgroup of any 128 pennies. Then flip over all 128. That group of 128 and the group of all the remaining pennies will have the same number of heads facing up.\r\nThis works because the \"tails\" that you grab while making your subset of 128 will equal the \"heads\" that are left in the original pile. Once you flip your 128 coins over, these \"tails\" will turn into \"heads\" and the two groups will have a matching number of heads-up coins.", "category": "Logic", "date": "11/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are blindfolded before a table. On the table are a very large number of pennies. You are told 128 of the pennies are heads up and the rest are tails up. How can you create two subgroups of pennies, each with the same number of heads facing up, while remaining blindfolded?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCreate a subgroup of any 128 pennies. Then flip over all 128. That group of 128 and the group of all the remaining pennies will have the same number of heads facing up.\r\nThis works because the \"tails\" that you grab while making your subset of 128 will equal the \"heads\" that are left in the original pile. Once you flip your 128 coins over, these \"tails\" will turn into \"heads\" and the two groups will have a matching number of heads-up coins.\n<|im_start|>answer\nCreate a subgroup of any 128 pennies. Then flip over all 128. That group of 128 and the group of all the remaining pennies will have the same number of heads facing up.\r\nThis works because the \"tails\" that you grab while making your subset of 128 will equal the \"heads\" that are left in the original pile. Once you flip your 128 coins over, these \"tails\" will turn into \"heads\" and the two groups will have a matching number of heads-up coins.\n<|im_end|>" }, { "id": "#24894", "title": "Having Fun!", "fun": 2.86, "difficulty": 1.14, "author": "trickster2005", "desc": "Sharron, Leah, Vivian, Barbara, and Vaughnie are all friends that love to do their own thing (age may have something to do with it). Their ages are 60, 50, 40, 23, and 20. Their hobbies are watching TV, playing PC games, reading, gambling and dating. Did I forget to mention that they have a favorite dish or food? The edibles are fish, candy, cookies, gum, and spicy foods. \n\r\n1. Barbara does not know how to operate a computer.\r\n2. Sharron loves candy.\r\n3. The oldest person loves to watch TV.\r\n4. The twenty year old's name does not start with the letter V.\r\n5. Leah likes cookies.\r\n6. The youngest person likes to read.\r\n7. Vaughnie is older than Barbara by 10 years.\r\n8. The person whose age is in the middle likes to play computer games.\r\n9. The one who likes to watch TV likes to eat fish.\r\n10. Barbara is the gum chewer.\r\n11. Barbara does not date.\r\n12. Sharron is younger than Leah.\r\n13. Leah does not like to gamble.\r\n14. Leah is not older than 29.\r\n15. Vivian loves spicy foods.\r\n16. Vivian is twenty years older than Sharron.", "hint": "No hint available.", "answer": "Sharron- 20, read, candy\r\nLeah- 23, date, cookies\r\nVivian- 40, PC games, spicy foods\r\nBarbara- 50, gamble, gum\r\nVaughnie- 60, watching TV, fish", "category": "Logic-Grid", "date": "07/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSharron, Leah, Vivian, Barbara, and Vaughnie are all friends that love to do their own thing (age may have something to do with it). Their ages are 60, 50, 40, 23, and 20. Their hobbies are watching TV, playing PC games, reading, gambling and dating. Did I forget to mention that they have a favorite dish or food? The edibles are fish, candy, cookies, gum, and spicy foods. \n\r\n1. Barbara does not know how to operate a computer.\r\n2. Sharron loves candy.\r\n3. The oldest person loves to watch TV.\r\n4. The twenty year old's name does not start with the letter V.\r\n5. Leah likes cookies.\r\n6. The youngest person likes to read.\r\n7. Vaughnie is older than Barbara by 10 years.\r\n8. The person whose age is in the middle likes to play computer games.\r\n9. The one who likes to watch TV likes to eat fish.\r\n10. Barbara is the gum chewer.\r\n11. Barbara does not date.\r\n12. Sharron is younger than Leah.\r\n13. Leah does not like to gamble.\r\n14. Leah is not older than 29.\r\n15. Vivian loves spicy foods.\r\n16. Vivian is twenty years older than Sharron.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSharron- 20, read, candy\r\nLeah- 23, date, cookies\r\nVivian- 40, PC games, spicy foods\r\nBarbara- 50, gamble, gum\r\nVaughnie- 60, watching TV, fish\n<|im_start|>answer\nSharron- 20, read, candy\r\nLeah- 23, date, cookies\r\nVivian- 40, PC games, spicy foods\r\nBarbara- 50, gamble, gum\r\nVaughnie- 60, watching TV, fish\n<|im_end|>" }, { "id": "#22505", "title": "Free Jeans!", "fun": 2.86, "difficulty": 1.25, "author": "snaps", "desc": "A clothes shop was running a promotion giving away free jeans. In order to get the free jeans you had to try a pair on, then, while still wearing the jeans you had to put your right hand in the left pocket and your left hand in the right pocket and reach right to the bottom of the pockets at the same time. Many people tried but were unable to achieve the feat until one chap walked in and walked out a few minutes later with his free jeans. How did he do it?", "hint": "He managed to do it without crossing his arms.", "answer": "He tried the jeans on inside-out. The left pocket was then on his right side and the right pocket was then on his left side.\n\r\nAlternate answer: He tried the jeans on backwards.", "category": "Logic", "date": "04/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA clothes shop was running a promotion giving away free jeans. In order to get the free jeans you had to try a pair on, then, while still wearing the jeans you had to put your right hand in the left pocket and your left hand in the right pocket and reach right to the bottom of the pockets at the same time. Many people tried but were unable to achieve the feat until one chap walked in and walked out a few minutes later with his free jeans. How did he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe tried the jeans on inside-out. The left pocket was then on his right side and the right pocket was then on his left side.\n\r\nAlternate answer: He tried the jeans on backwards.\n<|im_start|>answer\nHe tried the jeans on inside-out. The left pocket was then on his right side and the right pocket was then on his left side.\n\r\nAlternate answer: He tried the jeans on backwards.\n<|im_end|>" }, { "id": "#37879", "title": "Picnic Time", "fun": 2.86, "difficulty": 2.01, "author": "dreamlvr1432", "desc": "Four friends went on a picnic. Everyone was responsible for bringing a food item to share with the group and a drink for themselves. In addition, each person brought an essential item for the picnic (plates, table cloth, napkins, and forks). Can you figure out each person's full name, what dish she brought to share, what she had to drink, and what item she provided for the picnic?\n\r\n1) Ms. Brown drank soda and provided the table cloth for the picnic. She sat next to her best friend, Annie, who brought the plates.\n\r\n2) The girl who brought potato salad doesn't like water.\n\r\n3) Either Joy or Annie made fried chicken.\n\r\n4) Annie Johnson likes to drink lemonade.\n\r\n5) Nina and the girl who brought the plates drove to the picnic together. Neither of them brought the mac & cheese.\n\r\n6) The girl who made the potato salad did not bring the plates.\n\r\n7) Either Ms. Smith or Ms. Gavin drank either iced tea or lemonade. Neither girl made fried chicken.\n\r\n8) Bobbi doesn't drink iced tea and she didn't bring the rice pudding (the girl who brought the napkins did).\n\r\n9) The 4 friends are Joy, Ms. Gavin, the girl who brought the napkins, and the girl who drank lemonade.", "hint": "No hint available.", "answer": "Nina Smith brought the napkins and rice pudding, and drank iced tea.\n\r\nJoy Brown brought the table cloth and potato salad, and drank soda.\n\r\nAnnie Johnson brought the plates and fried chicken, and drank lemonade.\n\r\nBobbi Gavin brought the forks and mac & cheese, and drank water.", "category": "Logic-Grid", "date": "08/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends went on a picnic. Everyone was responsible for bringing a food item to share with the group and a drink for themselves. In addition, each person brought an essential item for the picnic (plates, table cloth, napkins, and forks). Can you figure out each person's full name, what dish she brought to share, what she had to drink, and what item she provided for the picnic?\n\r\n1) Ms. Brown drank soda and provided the table cloth for the picnic. She sat next to her best friend, Annie, who brought the plates.\n\r\n2) The girl who brought potato salad doesn't like water.\n\r\n3) Either Joy or Annie made fried chicken.\n\r\n4) Annie Johnson likes to drink lemonade.\n\r\n5) Nina and the girl who brought the plates drove to the picnic together. Neither of them brought the mac & cheese.\n\r\n6) The girl who made the potato salad did not bring the plates.\n\r\n7) Either Ms. Smith or Ms. Gavin drank either iced tea or lemonade. Neither girl made fried chicken.\n\r\n8) Bobbi doesn't drink iced tea and she didn't bring the rice pudding (the girl who brought the napkins did).\n\r\n9) The 4 friends are Joy, Ms. Gavin, the girl who brought the napkins, and the girl who drank lemonade.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNina Smith brought the napkins and rice pudding, and drank iced tea.\n\r\nJoy Brown brought the table cloth and potato salad, and drank soda.\n\r\nAnnie Johnson brought the plates and fried chicken, and drank lemonade.\n\r\nBobbi Gavin brought the forks and mac & cheese, and drank water.\n<|im_start|>answer\nNina Smith brought the napkins and rice pudding, and drank iced tea.\n\r\nJoy Brown brought the table cloth and potato salad, and drank soda.\n\r\nAnnie Johnson brought the plates and fried chicken, and drank lemonade.\n\r\nBobbi Gavin brought the forks and mac & cheese, and drank water.\n<|im_end|>" }, { "id": "#26293", "title": "World Domination I", "fun": 2.86, "difficulty": 1.2, "author": "sweetime", "desc": "Mad Scientist Sassi the Sane was hell bent on taking over the world. Her latest plan was to mix together a number of plants to see what properties they contained. \n\r\nShe managed to lure four unsuspecting people (Jessica, Nicholas, Cassandra and Alfred) into her secret cave. Once there she fed them each a type of tree (gumtree, oak, elm, gardenia) and a type of flower (tulip, rose, daffodil and daisy). \n\r\nEach tree/flower pairing created a different effect: one caused you to be able to fly; another caused you to turn invisible; one potion was poisonous; and one made you instantly charming.\n\r\nCan you determine which two plants were mixed together, what effect it had, and which hapless victim was forced to try it?\n\r\n1. The four potions were: the one given to Jessica, the one containing gardenia, the one containing rose, and the one that made its victim charming.\r\n2. The two boys each had a potion made partly from a tree with three letters.\r\n3. The daffodil was in the invisibility potion.\r\n4. Cassandra and Alfred each had a potion with a flower that started with the same letter.\r\n5. When the elm and daisy were mixed together, they did not make a poison.\r\n6. The potion which allows you to fly was created by plants which have the letter \"o\" in them.", "hint": "Cassandra and Jessica are girls; Alfred and Nicholas are boys.", "answer": "Jessica, gumtree, tulip, poison.\r\nNicholas, oak, rose, fly.\r\nCassandra, gardenia, daffodil, invisible.\r\nAlfred, elm, daisy, charming", "category": "Logic-Grid", "date": "10/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Scientist Sassi the Sane was hell bent on taking over the world. Her latest plan was to mix together a number of plants to see what properties they contained. \n\r\nShe managed to lure four unsuspecting people (Jessica, Nicholas, Cassandra and Alfred) into her secret cave. Once there she fed them each a type of tree (gumtree, oak, elm, gardenia) and a type of flower (tulip, rose, daffodil and daisy). \n\r\nEach tree/flower pairing created a different effect: one caused you to be able to fly; another caused you to turn invisible; one potion was poisonous; and one made you instantly charming.\n\r\nCan you determine which two plants were mixed together, what effect it had, and which hapless victim was forced to try it?\n\r\n1. The four potions were: the one given to Jessica, the one containing gardenia, the one containing rose, and the one that made its victim charming.\r\n2. The two boys each had a potion made partly from a tree with three letters.\r\n3. The daffodil was in the invisibility potion.\r\n4. Cassandra and Alfred each had a potion with a flower that started with the same letter.\r\n5. When the elm and daisy were mixed together, they did not make a poison.\r\n6. The potion which allows you to fly was created by plants which have the letter \"o\" in them.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJessica, gumtree, tulip, poison.\r\nNicholas, oak, rose, fly.\r\nCassandra, gardenia, daffodil, invisible.\r\nAlfred, elm, daisy, charming\n<|im_start|>answer\nJessica, gumtree, tulip, poison.\r\nNicholas, oak, rose, fly.\r\nCassandra, gardenia, daffodil, invisible.\r\nAlfred, elm, daisy, charming\n<|im_end|>" }, { "id": "#45434", "title": "Same Place, Same Time", "fun": 2.86, "difficulty": 1.78, "author": "whsprec", "desc": "A community center has 5 regular weekly bookings for a variety of activities. From the clues below, find which activity takes place on which day, the time, and the person in charge of each group.\n\r\n1) Monday's booking is for the karate group, but their contact is not Miss Blair.\r\n2) Mr. Roach is the contact for the Tuesday group.\r\n3) The book club uses the hall two days before Mr. Browning's group\r\n4) Cooking meets at 4:30 each week.\r\n5) The painting class is held the day after the 10:30 class.\r\n6) Mrs. Boyle is the contact for the pottery class.\r\n7) One of the groups has the hall for 11 on Thursdays, and Miss Pitt's group meets at 7:30.", "hint": "No hint available.", "answer": "Monday - Miss Pitt's karate group meets at 7:30.\r\nTuesday - Mr. Roach's cooking group meets at 4:30.\r\nThursday - Miss Blair's book club meets at 11:00.\r\nFriday - Mrs. Boyle's pottery group meets at 10:30.\r\nSaturday - Mr. Browning's painting group meets at 2:30.", "category": "Logic-Grid", "date": "10/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA community center has 5 regular weekly bookings for a variety of activities. From the clues below, find which activity takes place on which day, the time, and the person in charge of each group.\n\r\n1) Monday's booking is for the karate group, but their contact is not Miss Blair.\r\n2) Mr. Roach is the contact for the Tuesday group.\r\n3) The book club uses the hall two days before Mr. Browning's group\r\n4) Cooking meets at 4:30 each week.\r\n5) The painting class is held the day after the 10:30 class.\r\n6) Mrs. Boyle is the contact for the pottery class.\r\n7) One of the groups has the hall for 11 on Thursdays, and Miss Pitt's group meets at 7:30.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday - Miss Pitt's karate group meets at 7:30.\r\nTuesday - Mr. Roach's cooking group meets at 4:30.\r\nThursday - Miss Blair's book club meets at 11:00.\r\nFriday - Mrs. Boyle's pottery group meets at 10:30.\r\nSaturday - Mr. Browning's painting group meets at 2:30.\n<|im_start|>answer\nMonday - Miss Pitt's karate group meets at 7:30.\r\nTuesday - Mr. Roach's cooking group meets at 4:30.\r\nThursday - Miss Blair's book club meets at 11:00.\r\nFriday - Mrs. Boyle's pottery group meets at 10:30.\r\nSaturday - Mr. Browning's painting group meets at 2:30.\n<|im_end|>" }, { "id": "#25468", "title": "Concerts", "fun": 2.86, "difficulty": 1.71, "author": "princess_pinkie", "desc": "Five friends went to five different concerts in this past week (Monday to Saturday). From the following clues, can you determine each child's full name, the day they went to their concert, and which concert they attended?\n\r\n1. Estaban and his friend, the Montgomery girl, both went to concerts before Thursday.\n\r\n2. The Chen boy saw the Metalheads later in the week than Micheal saw his concert.\n\r\n3. Country Kickin' played a concert earlier in the week than the Wild Yahoos, who Dawn saw in concert.\n\r\n4. The Hawthorne girl, the child who went to Friday's concert, and Dawn all ride the same bus to school.\n\r\n5. Backyard Blues Band played on Thursday, three days after the Guerro child went to his concert.\n\r\n6. Estaban saw his concert before the Chen child and five days before the girl who saw Stonestown Symphony.", "hint": "Estaban, Lucas and Michael are boys; Dawn and Emma are girls.", "answer": "Estaban Guerro, Country Kickin', Monday\r\nDawn Montgomery, Wild Yahoos, Wednesday\r\nMicheal Juarez, Backyard Blues Band, Thursday\r\nLucas Chen, Metalheads, Friday\r\nEmma Hawthorne, Stonestown Symphony, Saturday", "category": "Logic-Grid", "date": "08/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends went to five different concerts in this past week (Monday to Saturday). From the following clues, can you determine each child's full name, the day they went to their concert, and which concert they attended?\n\r\n1. Estaban and his friend, the Montgomery girl, both went to concerts before Thursday.\n\r\n2. The Chen boy saw the Metalheads later in the week than Micheal saw his concert.\n\r\n3. Country Kickin' played a concert earlier in the week than the Wild Yahoos, who Dawn saw in concert.\n\r\n4. The Hawthorne girl, the child who went to Friday's concert, and Dawn all ride the same bus to school.\n\r\n5. Backyard Blues Band played on Thursday, three days after the Guerro child went to his concert.\n\r\n6. Estaban saw his concert before the Chen child and five days before the girl who saw Stonestown Symphony.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEstaban Guerro, Country Kickin', Monday\r\nDawn Montgomery, Wild Yahoos, Wednesday\r\nMicheal Juarez, Backyard Blues Band, Thursday\r\nLucas Chen, Metalheads, Friday\r\nEmma Hawthorne, Stonestown Symphony, Saturday\n<|im_start|>answer\nEstaban Guerro, Country Kickin', Monday\r\nDawn Montgomery, Wild Yahoos, Wednesday\r\nMicheal Juarez, Backyard Blues Band, Thursday\r\nLucas Chen, Metalheads, Friday\r\nEmma Hawthorne, Stonestown Symphony, Saturday\n<|im_end|>" }, { "id": "#27021", "title": "Baseball for Sara", "fun": 2.86, "difficulty": 1.21, "author": "Rob2003", "desc": "Sara loves baseball, so for her birthday her family gave her tickets for this weekend's major league baseball game. She went with a friend, the weather was hot and sunny, but she had good seats with a great view of the game. Both teams played very well, with some exceptional hits and plays. Determine the full names of four of the players, the position each played, and each player's best hit of the game.\n\r\n1. Alec played the center field position. Sam Crisp didn't get the grand slam.\n\r\n2. Brad, whose last name wasn't Reach, didn't play the 1st base position.\n\r\n3. The player who got a double wasn't the player who played the 3rd base position.\n\r\n4. Mr. Ember didn't play in the center field position, but he did get a single hit.\n\r\n5. Mr. Mann got a triple. Will, whose last name wasn't Mann, didn't get a single.\n\r\n6. The player in the catcher position got the grand slam.", "hint": "No hint available.", "answer": "Alec Mann: center field, triple\r\nBrad Ember: 3rd base, single\r\nSam Crisp: 1st base, double\r\nWill Reach: catcher, grand slam", "category": "Logic-Grid", "date": "11/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSara loves baseball, so for her birthday her family gave her tickets for this weekend's major league baseball game. She went with a friend, the weather was hot and sunny, but she had good seats with a great view of the game. Both teams played very well, with some exceptional hits and plays. Determine the full names of four of the players, the position each played, and each player's best hit of the game.\n\r\n1. Alec played the center field position. Sam Crisp didn't get the grand slam.\n\r\n2. Brad, whose last name wasn't Reach, didn't play the 1st base position.\n\r\n3. The player who got a double wasn't the player who played the 3rd base position.\n\r\n4. Mr. Ember didn't play in the center field position, but he did get a single hit.\n\r\n5. Mr. Mann got a triple. Will, whose last name wasn't Mann, didn't get a single.\n\r\n6. The player in the catcher position got the grand slam.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlec Mann: center field, triple\r\nBrad Ember: 3rd base, single\r\nSam Crisp: 1st base, double\r\nWill Reach: catcher, grand slam\n<|im_start|>answer\nAlec Mann: center field, triple\r\nBrad Ember: 3rd base, single\r\nSam Crisp: 1st base, double\r\nWill Reach: catcher, grand slam\n<|im_end|>" }, { "id": "#26422", "title": "World Domination II", "fun": 2.86, "difficulty": 1.41, "author": "sweetime", "desc": "Sassi the Sane was quite pleased with her potion experiments, but potions alone were not enough. She now needed a secret hideout and an army with which to plan her plan for world domination.\n\r\nShe decided to test out four hideouts: a cave, the desert, an underwater location, and a castle.\n\r\nShe also had four types of armies: one made up of sporks, one of monkeys, one of squirrels, and one of hamburgers.\n\r\nShe spent a different amount of time in each location: 1 day, 2 days, 3 days and 4 days.\n\r\nAnd each time she was discovered a different number of times: twice, four times, six times and eight times.\n\r\nCan you determine which location she hid which army in, how long she spent there, and the number of times she was discovered there?\n\r\n1. She spent the fewest days in the desert.\r\n2. The four hideouts were: the cave, the one with the squirrels, the one in which she spent three days, and the one in which she was discovered four times.\r\n3. The rattling of the sporks drew the greatest attention from passersby, and so caused Sassi to be discovered the most times.\r\n4. The four armies were: the hamburgers, the one in the desert, the one discovered eight times, and the one in which four days were spent.\r\n5. Both the desert and the underwater location were discovered exactly twice as many times as the number of days spent there.\r\n6. The monkeys were a disaster, they kept escaping from the castle, rather than defending it.\r\n7. While the underwater location was discovered a surprisingly large number of times, it wasn't the location which was discovered most.", "hint": "No hint available.", "answer": "Cave, sporks, two days, eight discoveries.\n\r\nDesert, squirrels, one day, two discoveries.\n\r\nUnderwater, hamburgers, three days, six discoveries.\n\r\nCastle, monkeys, four days, four discoveries.", "category": "Logic-Grid", "date": "10/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSassi the Sane was quite pleased with her potion experiments, but potions alone were not enough. She now needed a secret hideout and an army with which to plan her plan for world domination.\n\r\nShe decided to test out four hideouts: a cave, the desert, an underwater location, and a castle.\n\r\nShe also had four types of armies: one made up of sporks, one of monkeys, one of squirrels, and one of hamburgers.\n\r\nShe spent a different amount of time in each location: 1 day, 2 days, 3 days and 4 days.\n\r\nAnd each time she was discovered a different number of times: twice, four times, six times and eight times.\n\r\nCan you determine which location she hid which army in, how long she spent there, and the number of times she was discovered there?\n\r\n1. She spent the fewest days in the desert.\r\n2. The four hideouts were: the cave, the one with the squirrels, the one in which she spent three days, and the one in which she was discovered four times.\r\n3. The rattling of the sporks drew the greatest attention from passersby, and so caused Sassi to be discovered the most times.\r\n4. The four armies were: the hamburgers, the one in the desert, the one discovered eight times, and the one in which four days were spent.\r\n5. Both the desert and the underwater location were discovered exactly twice as many times as the number of days spent there.\r\n6. The monkeys were a disaster, they kept escaping from the castle, rather than defending it.\r\n7. While the underwater location was discovered a surprisingly large number of times, it wasn't the location which was discovered most.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCave, sporks, two days, eight discoveries.\n\r\nDesert, squirrels, one day, two discoveries.\n\r\nUnderwater, hamburgers, three days, six discoveries.\n\r\nCastle, monkeys, four days, four discoveries.\n<|im_start|>answer\nCave, sporks, two days, eight discoveries.\n\r\nDesert, squirrels, one day, two discoveries.\n\r\nUnderwater, hamburgers, three days, six discoveries.\n\r\nCastle, monkeys, four days, four discoveries.\n<|im_end|>" }, { "id": "#30651", "title": "Blellow the Alien #2", "fun": 2.86, "difficulty": 3.02, "author": "thompson1", "desc": "Blellow is back with another crisis! He hosted a talent show for himself and 4 of his friends. He hired judges to judge the show, but only one of them showed up. The judge wrote down lots of details about the show, but wrote them in a language no one else at the show knew! You are studying aliens on a mission from Earth, and have been studying the exact language the judge wrote the details in, but cannot speak it fluently. You are able to read parts of the details, but not all of it. Help Blellow get his show wrapped up by figuring out which alien came in which place, how many fingers per arm they have, what their skin color is, and how many arms they have. Good Luck! \n\r\nNames: Blellow, Qluxeh, Xrek, Zeneq, and Wsalhm\r\nPlaces: 1st, 2nd, 3rd, 4th, and 5th\r\nFingers per Arm: 4, 5, 9, 10, and 13\r\nSkin Color: Orange, Maroon, Peach, Pink, and Chartreuse\r\nArms: 2, 4, 5, 7, and 10\n\r\n1. The 5 aliens are: Blellow, the one who came in 3rd place, the one with the most arms, the pink alien, and the alien with 13 fingers on each arm.\n\r\n2. The alien with 3 more arms than the peach-colored alien has 5 less total fingers than Wsalhm.\n\r\n3. The orange alien has the same number of arms and fingers per arm.\n\r\n4. The alien with 10 total fingers came 2 places after Blellow.\n\r\n5. Wsalhm has 7 arms (which is more than Qluxeh)\n\r\n6. Neither the alien with 4 fingers per arm nor 10 fingers per arm came in 3rd place.\n\r\n7. Xrek messed up several times, so he got 5th place.\n\r\n8. The chartreuse alien, who didn't get 5th place, doesn't have 5 arms.\n\r\n9. The pink alien came in a higher place than the peach alien did.", "hint": "No hint available.", "answer": "Blellow came in 1st place, has 4 arms, is orange, and has 4 fingers on each arm.\r\nQluxeh came in 3rd place, has 2 arms, is peach, and has 5 fingers on each arm.\r\nXrek came in 5th place, has 5 arms, is maroon, and has 13 fingers on each arm.\r\nZeneq came in 4th place, has 10 arms, is chartreuse, and has 9 fingers on each arm.\r\nWsalhm came in 2nd place, has 7 arms, is pink, and has 10 fingers on each arm.", "category": "Logic-Grid", "date": "05/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBlellow is back with another crisis! He hosted a talent show for himself and 4 of his friends. He hired judges to judge the show, but only one of them showed up. The judge wrote down lots of details about the show, but wrote them in a language no one else at the show knew! You are studying aliens on a mission from Earth, and have been studying the exact language the judge wrote the details in, but cannot speak it fluently. You are able to read parts of the details, but not all of it. Help Blellow get his show wrapped up by figuring out which alien came in which place, how many fingers per arm they have, what their skin color is, and how many arms they have. Good Luck! \n\r\nNames: Blellow, Qluxeh, Xrek, Zeneq, and Wsalhm\r\nPlaces: 1st, 2nd, 3rd, 4th, and 5th\r\nFingers per Arm: 4, 5, 9, 10, and 13\r\nSkin Color: Orange, Maroon, Peach, Pink, and Chartreuse\r\nArms: 2, 4, 5, 7, and 10\n\r\n1. The 5 aliens are: Blellow, the one who came in 3rd place, the one with the most arms, the pink alien, and the alien with 13 fingers on each arm.\n\r\n2. The alien with 3 more arms than the peach-colored alien has 5 less total fingers than Wsalhm.\n\r\n3. The orange alien has the same number of arms and fingers per arm.\n\r\n4. The alien with 10 total fingers came 2 places after Blellow.\n\r\n5. Wsalhm has 7 arms (which is more than Qluxeh)\n\r\n6. Neither the alien with 4 fingers per arm nor 10 fingers per arm came in 3rd place.\n\r\n7. Xrek messed up several times, so he got 5th place.\n\r\n8. The chartreuse alien, who didn't get 5th place, doesn't have 5 arms.\n\r\n9. The pink alien came in a higher place than the peach alien did.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlellow came in 1st place, has 4 arms, is orange, and has 4 fingers on each arm.\r\nQluxeh came in 3rd place, has 2 arms, is peach, and has 5 fingers on each arm.\r\nXrek came in 5th place, has 5 arms, is maroon, and has 13 fingers on each arm.\r\nZeneq came in 4th place, has 10 arms, is chartreuse, and has 9 fingers on each arm.\r\nWsalhm came in 2nd place, has 7 arms, is pink, and has 10 fingers on each arm.\n<|im_start|>answer\nBlellow came in 1st place, has 4 arms, is orange, and has 4 fingers on each arm.\r\nQluxeh came in 3rd place, has 2 arms, is peach, and has 5 fingers on each arm.\r\nXrek came in 5th place, has 5 arms, is maroon, and has 13 fingers on each arm.\r\nZeneq came in 4th place, has 10 arms, is chartreuse, and has 9 fingers on each arm.\r\nWsalhm came in 2nd place, has 7 arms, is pink, and has 10 fingers on each arm.\n<|im_end|>" }, { "id": "#14555", "title": "Brave Knights", "fun": 2.86, "difficulty": 2.5, "author": "taniapereira99", "desc": "A king heard that the nearby kingdoms were being destroyed by a fierce dragon. He called forth his most trusted and skilled knights to meet and plan how to protect the kingdom. The 6 knights, Sir William, Sir Andrew, Sir Luke, Sir Calvin, Sir Charles and Sir Vincent, decided that two knights would venture out to find and slay the dragon while the other 4 would defend the kingdom.\n\r\nFrom the statements below, which two knights went to seek the dragon?\n\r\n1. If neither Sir William or Sir Vincent rode out, then Sir Calvin did.\n\r\n2. If either Sir Calvin or Sir Vincent went to kill the dragon, then Sir Andrew did not.\n\r\n3. If neither Sir Andrew or Sir William were of the brave two that left the kingdom, then Sir Charles was.\n\r\n4. If neither Sir Luke or Sir Andrew went out, then Sir Vincent did.\n\r\n5. If Sir William was one of the two, then either Sir Calvin or Sir Charles was with him.\n\r\n6. If Sir Vincent was not of the two who went to slay the dragon, then neither was Sir Andrew nor Sir Charles.", "hint": "No hint available.", "answer": "Sir Vincent and Sir Charles went out of the kingdom to slay the dragon. \n\r\nIf statement 1 is valid, Calvin was one of the two that left. If not, either William or Vincent was one of the two. Therefore the PAIR could not be Andrew and Luke, Sir Andrew and Charles or Luke and Charles.\n\r\nFrom 3, the PAIR that left was not Luke and Calvin, Luke and Vincent or Calvin and Vincent. From 4, the two could not have been William and Calvin, William and Charles or Calvin and Charles.\n\r\nFrom 5, William did not venture out and therefore from 4 the pair was not William and Calvin or William and Charles. \n\r\nFrom 6, Vincent must have been one of the two since the statement identifies three of the four knights not eliminated. From 2, Vincent was one of the two, and by elimination, the other is Charles.", "category": "Logic", "date": "08/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA king heard that the nearby kingdoms were being destroyed by a fierce dragon. He called forth his most trusted and skilled knights to meet and plan how to protect the kingdom. The 6 knights, Sir William, Sir Andrew, Sir Luke, Sir Calvin, Sir Charles and Sir Vincent, decided that two knights would venture out to find and slay the dragon while the other 4 would defend the kingdom.\n\r\nFrom the statements below, which two knights went to seek the dragon?\n\r\n1. If neither Sir William or Sir Vincent rode out, then Sir Calvin did.\n\r\n2. If either Sir Calvin or Sir Vincent went to kill the dragon, then Sir Andrew did not.\n\r\n3. If neither Sir Andrew or Sir William were of the brave two that left the kingdom, then Sir Charles was.\n\r\n4. If neither Sir Luke or Sir Andrew went out, then Sir Vincent did.\n\r\n5. If Sir William was one of the two, then either Sir Calvin or Sir Charles was with him.\n\r\n6. If Sir Vincent was not of the two who went to slay the dragon, then neither was Sir Andrew nor Sir Charles.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSir Vincent and Sir Charles went out of the kingdom to slay the dragon. \n\r\nIf statement 1 is valid, Calvin was one of the two that left. If not, either William or Vincent was one of the two. Therefore the PAIR could not be Andrew and Luke, Sir Andrew and Charles or Luke and Charles.\n\r\nFrom 3, the PAIR that left was not Luke and Calvin, Luke and Vincent or Calvin and Vincent. From 4, the two could not have been William and Calvin, William and Charles or Calvin and Charles.\n\r\nFrom 5, William did not venture out and therefore from 4 the pair was not William and Calvin or William and Charles. \n\r\nFrom 6, Vincent must have been one of the two since the statement identifies three of the four knights not eliminated. From 2, Vincent was one of the two, and by elimination, the other is Charles.\n<|im_start|>answer\nSir Vincent and Sir Charles went out of the kingdom to slay the dragon. \n\r\nIf statement 1 is valid, Calvin was one of the two that left. If not, either William or Vincent was one of the two. Therefore the PAIR could not be Andrew and Luke, Sir Andrew and Charles or Luke and Charles.\n\r\nFrom 3, the PAIR that left was not Luke and Calvin, Luke and Vincent or Calvin and Vincent. From 4, the two could not have been William and Calvin, William and Charles or Calvin and Charles.\n\r\nFrom 5, William did not venture out and therefore from 4 the pair was not William and Calvin or William and Charles. \n\r\nFrom 6, Vincent must have been one of the two since the statement identifies three of the four knights not eliminated. From 2, Vincent was one of the two, and by elimination, the other is Charles.\n<|im_end|>" }, { "id": "#45619", "title": "Puzzling", "fun": 2.86, "difficulty": 1.93, "author": "whsprec", "desc": "Five people were solving their favorite type of puzzle on a website. From the clues below, determine the name of the person, their screen name, what puzzle they solved, and how long it took to solve it.\n\r\n1- Michael's wordsearch took eight minutes longer to complete than person who screen name is whsprec.\r\n2- Keith's screen name is Genius1.\r\n3- It took usernameplease 6 minutes to solve their problem, which was not a logic grid.\r\n4- Jennifer took four minutes longer on her puzzle than Brittany did on hers, which was not sudoku.\r\n5- The person who solved a letter-equation was named PeaceAll, and did not take 18 minutes.\r\n6- It was the cryptography puzzle which took 14 minutes to complete.", "hint": "No hint available.", "answer": "Mark, screen name whsprec, did the logic grid in 10 minutes\r\nBrittany , screen name PeaceAll, did the letter-equation in 2 minutes\r\nJennifer, screen name usernameplease, did sudoku in 6 minutes\r\nMichael, screen name Dragon Master, did the wordsearch in 18 minutes\r\nKeith, screen name Genius1, did the cryptography in 14 minutes.", "category": "Logic-Grid", "date": "11/04/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people were solving their favorite type of puzzle on a website. From the clues below, determine the name of the person, their screen name, what puzzle they solved, and how long it took to solve it.\n\r\n1- Michael's wordsearch took eight minutes longer to complete than person who screen name is whsprec.\r\n2- Keith's screen name is Genius1.\r\n3- It took usernameplease 6 minutes to solve their problem, which was not a logic grid.\r\n4- Jennifer took four minutes longer on her puzzle than Brittany did on hers, which was not sudoku.\r\n5- The person who solved a letter-equation was named PeaceAll, and did not take 18 minutes.\r\n6- It was the cryptography puzzle which took 14 minutes to complete.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMark, screen name whsprec, did the logic grid in 10 minutes\r\nBrittany , screen name PeaceAll, did the letter-equation in 2 minutes\r\nJennifer, screen name usernameplease, did sudoku in 6 minutes\r\nMichael, screen name Dragon Master, did the wordsearch in 18 minutes\r\nKeith, screen name Genius1, did the cryptography in 14 minutes.\n<|im_start|>answer\nMark, screen name whsprec, did the logic grid in 10 minutes\r\nBrittany , screen name PeaceAll, did the letter-equation in 2 minutes\r\nJennifer, screen name usernameplease, did sudoku in 6 minutes\r\nMichael, screen name Dragon Master, did the wordsearch in 18 minutes\r\nKeith, screen name Genius1, did the cryptography in 14 minutes.\n<|im_end|>" }, { "id": "#5388", "title": "Tic Tac Toe", "fun": 2.86, "difficulty": 1.62, "author": "im_para_noid", "desc": "Arrange the numbers 1 through 9 on a tic tac toe board such that the numbers in each row, column, and diagonal add up to 15.", "hint": "No hint available.", "answer": "4, 3, 8,\r\n9, 5, 1,\r\n2, 7, 6,", "category": "Math", "date": "07/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numbers 1 through 9 on a tic tac toe board such that the numbers in each row, column, and diagonal add up to 15.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4, 3, 8,\r\n9, 5, 1,\r\n2, 7, 6,\n<|im_start|>answer\n4, 3, 8,\r\n9, 5, 1,\r\n2, 7, 6,\n<|im_end|>" }, { "id": "#7824", "title": "100 Closed Lockers", "fun": 2.85, "difficulty": 2.83, "author": "warrior", "desc": "Suppose you're in a hallway lined with 100 closed lockers. \r\nYou begin by opening every locker. Then you close every second locker. Then you go to every third locker and open it (if it's closed) or close it (if it's open). Let's call this action toggling a locker. Continue toggling every nth locker on pass number n. After 100 passes, where you toggle only locker #100, how many lockers are open?", "hint": "No hint available.", "answer": "Answer: 10 lockers are left open: \r\nLockers #1, 4, 9, 16, 25, 36, 49, 64, 81, and 100. \r\nEach of these numbers are perfect squares. This problem is based on the factors of the locker number. \r\nEach locker is toggled by each factor; for example, locker #40 is toggled on pass number 1, 2, 4, 5, 8, 10, 20, and 40. That's eight toggles: open-closed-open-closed-open-closed-open-closed.\n\r\nThe only way a locker could be left open is if it is toggled an odd number of times. The only numbers with an odd number of factors are the perfect \r\nsquares. Thus, the perfect squares are left open. \n\r\nFor example, locker #25 is toggled on pass number 1, 5, and 25 (three toggles): open-closed-open.", "category": "Math", "date": "10/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose you're in a hallway lined with 100 closed lockers. \r\nYou begin by opening every locker. Then you close every second locker. Then you go to every third locker and open it (if it's closed) or close it (if it's open). Let's call this action toggling a locker. Continue toggling every nth locker on pass number n. After 100 passes, where you toggle only locker #100, how many lockers are open?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: 10 lockers are left open: \r\nLockers #1, 4, 9, 16, 25, 36, 49, 64, 81, and 100. \r\nEach of these numbers are perfect squares. This problem is based on the factors of the locker number. \r\nEach locker is toggled by each factor; for example, locker #40 is toggled on pass number 1, 2, 4, 5, 8, 10, 20, and 40. That's eight toggles: open-closed-open-closed-open-closed-open-closed.\n\r\nThe only way a locker could be left open is if it is toggled an odd number of times. The only numbers with an odd number of factors are the perfect \r\nsquares. Thus, the perfect squares are left open. \n\r\nFor example, locker #25 is toggled on pass number 1, 5, and 25 (three toggles): open-closed-open.\n<|im_start|>answer\nAnswer: 10 lockers are left open: \r\nLockers #1, 4, 9, 16, 25, 36, 49, 64, 81, and 100. \r\nEach of these numbers are perfect squares. This problem is based on the factors of the locker number. \r\nEach locker is toggled by each factor; for example, locker #40 is toggled on pass number 1, 2, 4, 5, 8, 10, 20, and 40. That's eight toggles: open-closed-open-closed-open-closed-open-closed.\n\r\nThe only way a locker could be left open is if it is toggled an odd number of times. The only numbers with an odd number of factors are the perfect \r\nsquares. Thus, the perfect squares are left open. \n\r\nFor example, locker #25 is toggled on pass number 1, 5, and 25 (three toggles): open-closed-open.\n<|im_end|>" }, { "id": "#21360", "title": "The Race - Part II", "fun": 2.85, "difficulty": 1.96, "author": "Sane", "desc": "Alexa, Breanna, Larry, Arnold and Michael were now finished their workouts in preparation for the race. They would now all enter a different racing event, then proceed to race each other for the winnings! Can you match the competitor with the racing event they entered, the place they got in their event, and the place they got in the group?\n\r\n1. The person who got 10th in their event got last in the group and only one person did better in the group than Larry.\n\r\n2. The woman who entered the 100m dash got 2nd in the event.\n\r\n3. The competitor who entered the 10km run, who did not do the best in their group, is not Arnold.\n\r\n4. A man got 1st place in the group and the person who got 4th in their event only got 4th in the group!\n\r\n5. Larry entered the 5km and did not get 14th; Breanna entered the 800m and did not get 5th in the group.\n\r\nNames: Alexa, Larry, Arnold, Breanna, Michael\r\nEvents: 100m, 800m, 2km, 5km, 10km\r\nGroup Placing: 1, 2, 3, 4, 5\r\nEvent Placing: 2, 4, 6, 10, 14", "hint": "No hint available.", "answer": "Alexa did the 100m event, got 2nd in that event, and did 3rd in the group.\n\r\nLarry did the 5km event, got 6th in that event, and did 2nd in the group.\n\r\nArnold did the 2km event, got 14th in that event, and did 1st in the group.\n\r\nBreanna did the 800m event, got 4th in that event, and did 4th in the group.\n\r\nMichael did the 10 km event, got 10th in that event, and did 5th in the group.", "category": "Logic-Grid", "date": "03/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlexa, Breanna, Larry, Arnold and Michael were now finished their workouts in preparation for the race. They would now all enter a different racing event, then proceed to race each other for the winnings! Can you match the competitor with the racing event they entered, the place they got in their event, and the place they got in the group?\n\r\n1. The person who got 10th in their event got last in the group and only one person did better in the group than Larry.\n\r\n2. The woman who entered the 100m dash got 2nd in the event.\n\r\n3. The competitor who entered the 10km run, who did not do the best in their group, is not Arnold.\n\r\n4. A man got 1st place in the group and the person who got 4th in their event only got 4th in the group!\n\r\n5. Larry entered the 5km and did not get 14th; Breanna entered the 800m and did not get 5th in the group.\n\r\nNames: Alexa, Larry, Arnold, Breanna, Michael\r\nEvents: 100m, 800m, 2km, 5km, 10km\r\nGroup Placing: 1, 2, 3, 4, 5\r\nEvent Placing: 2, 4, 6, 10, 14\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlexa did the 100m event, got 2nd in that event, and did 3rd in the group.\n\r\nLarry did the 5km event, got 6th in that event, and did 2nd in the group.\n\r\nArnold did the 2km event, got 14th in that event, and did 1st in the group.\n\r\nBreanna did the 800m event, got 4th in that event, and did 4th in the group.\n\r\nMichael did the 10 km event, got 10th in that event, and did 5th in the group.\n<|im_start|>answer\nAlexa did the 100m event, got 2nd in that event, and did 3rd in the group.\n\r\nLarry did the 5km event, got 6th in that event, and did 2nd in the group.\n\r\nArnold did the 2km event, got 14th in that event, and did 1st in the group.\n\r\nBreanna did the 800m event, got 4th in that event, and did 4th in the group.\n\r\nMichael did the 10 km event, got 10th in that event, and did 5th in the group.\n<|im_end|>" }, { "id": "#42727", "title": "Geeks of the World, Unite!", "fun": 2.85, "difficulty": 2.13, "author": "phrebh", "desc": "Four young friends (Blaise, Charles, John, and Konrad), who met at a LAN party, have recently taken jobs at the same technology services firm. All of them work in the web development division and they were all hired as junior programmers because of their inexperience. They all work with different languages (AJAX, Perl, PHP, and Ruby on Rails (RoR)), different information systems (JSON, MySQL, plain text, and XML), and have been using those languages and systems a differing amount of time (3 months, 5 months, 6 months, 9 months).\n\r\nUsing the clues provided, can you figure out who has been using what language with what system for what amount of time?\n\r\n1. MySQL has been used longer than RoR.\r\n2. The four friends are John, the one who uses PHP, the one who has been at it for 9 months, and the one who uses plain text.\r\n3. Blaise is happy he doesn't have to work with Perl.\r\n4. Plain text has been used longer than PHP, but not as long as AJAX.\r\n5. One of the languages start with the same letter as its corresponding system.\r\n6. Charles has been working with his language and system longer than John, but not as long as the person who uses AJAX.\r\n7. The four information systems are XML, the one used with PHP, the one that's been used for 6 months, and the one that Konrad uses.\r\n8. JSON has not been used the most amount of time and XML hasn't been used the least amount of time.\r\n9. The four languages used are AJAX, the one used for 5 months, the used by Charles, and the one used with JSON.", "hint": "The programming languages do not necessarily match up with the most realistic information systems.", "answer": "Blaise has been working with PHP and JSON for 3 months.\r\nCharles has been working with Perl and plain text for 6 months.\r\nJohn has been working with Ruby on Rails and XML for 5 months.\r\nKonrad has been working with AJAX and MySQL for 9 months.", "category": "Logic-Grid", "date": "08/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour young friends (Blaise, Charles, John, and Konrad), who met at a LAN party, have recently taken jobs at the same technology services firm. All of them work in the web development division and they were all hired as junior programmers because of their inexperience. They all work with different languages (AJAX, Perl, PHP, and Ruby on Rails (RoR)), different information systems (JSON, MySQL, plain text, and XML), and have been using those languages and systems a differing amount of time (3 months, 5 months, 6 months, 9 months).\n\r\nUsing the clues provided, can you figure out who has been using what language with what system for what amount of time?\n\r\n1. MySQL has been used longer than RoR.\r\n2. The four friends are John, the one who uses PHP, the one who has been at it for 9 months, and the one who uses plain text.\r\n3. Blaise is happy he doesn't have to work with Perl.\r\n4. Plain text has been used longer than PHP, but not as long as AJAX.\r\n5. One of the languages start with the same letter as its corresponding system.\r\n6. Charles has been working with his language and system longer than John, but not as long as the person who uses AJAX.\r\n7. The four information systems are XML, the one used with PHP, the one that's been used for 6 months, and the one that Konrad uses.\r\n8. JSON has not been used the most amount of time and XML hasn't been used the least amount of time.\r\n9. The four languages used are AJAX, the one used for 5 months, the used by Charles, and the one used with JSON.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlaise has been working with PHP and JSON for 3 months.\r\nCharles has been working with Perl and plain text for 6 months.\r\nJohn has been working with Ruby on Rails and XML for 5 months.\r\nKonrad has been working with AJAX and MySQL for 9 months.\n<|im_start|>answer\nBlaise has been working with PHP and JSON for 3 months.\r\nCharles has been working with Perl and plain text for 6 months.\r\nJohn has been working with Ruby on Rails and XML for 5 months.\r\nKonrad has been working with AJAX and MySQL for 9 months.\n<|im_end|>" }, { "id": "#28389", "title": "Little Damian's Nap-time Adventure", "fun": 2.85, "difficulty": 1.24, "author": "marianj79", "desc": "Mrs. Willis teaches pre-kindergarten at Happy Child Day Care. When she went to wake the class after nap-time, she discovered that one of the children had not been asleep after all. Little Damian had been a very busy, very bad boy. Before nap-time, each child had put their shoes and snacks at the foot of their mat. Damian had quietly switched everyone's things. He had, of course, left his things alone. Help Mrs. Willis to sort out this mess. Here is what she remembers:\n\r\nFirst Names: Dianne, Shaun, Craig, and Kelly\r\nMiddle Names: Marian, Anne, Robert, and Edward\r\nShoe Colors: Red, Blue, Black, Green\r\nSnacks: Apple, Pudding, Brownie, and Banana\n\n\r\n1. The children are Dianne, the child with the banana, the child with the red shoes, and the boy with the pudding.\n\r\n2. The boy who had an apple liked things to match, and so wore sneakers the same color as his snack.\n\r\n3. As you would expect, the two boys' middle names are Robert and Edward.\n\r\n4. Kelly never ate her snack; she always traded at snack time - unlike the girl whose middle name is Marian.\n\r\n5. Craig Robert loves the black shoes he just got yesterday, but Dianne wants new ones, since her favorite color changed to blue.", "hint": "Dianne's shoes are not blue.\r\nThe child with the apple must have red or green shoes.", "answer": "Dianne, Marian, Green Shoes, Brownie\r\nShaun, Edward, Red Shoes, Apple\r\nCraig, Robert, Black Shoes, Pudding\r\nKelly, Anne, Blue Shoes, Banana", "category": "Logic-Grid", "date": "02/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Willis teaches pre-kindergarten at Happy Child Day Care. When she went to wake the class after nap-time, she discovered that one of the children had not been asleep after all. Little Damian had been a very busy, very bad boy. Before nap-time, each child had put their shoes and snacks at the foot of their mat. Damian had quietly switched everyone's things. He had, of course, left his things alone. Help Mrs. Willis to sort out this mess. Here is what she remembers:\n\r\nFirst Names: Dianne, Shaun, Craig, and Kelly\r\nMiddle Names: Marian, Anne, Robert, and Edward\r\nShoe Colors: Red, Blue, Black, Green\r\nSnacks: Apple, Pudding, Brownie, and Banana\n\n\r\n1. The children are Dianne, the child with the banana, the child with the red shoes, and the boy with the pudding.\n\r\n2. The boy who had an apple liked things to match, and so wore sneakers the same color as his snack.\n\r\n3. As you would expect, the two boys' middle names are Robert and Edward.\n\r\n4. Kelly never ate her snack; she always traded at snack time - unlike the girl whose middle name is Marian.\n\r\n5. Craig Robert loves the black shoes he just got yesterday, but Dianne wants new ones, since her favorite color changed to blue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDianne, Marian, Green Shoes, Brownie\r\nShaun, Edward, Red Shoes, Apple\r\nCraig, Robert, Black Shoes, Pudding\r\nKelly, Anne, Blue Shoes, Banana\n<|im_start|>answer\nDianne, Marian, Green Shoes, Brownie\r\nShaun, Edward, Red Shoes, Apple\r\nCraig, Robert, Black Shoes, Pudding\r\nKelly, Anne, Blue Shoes, Banana\n<|im_end|>" }, { "id": "#43395", "title": "Four For Dinner", "fun": 2.85, "difficulty": 1.43, "author": "whsprec", "desc": "A family of four - father, mother, sister, and brother - went out to dinner. They each had a different meat, potato, and vegetable. The meats were either steak, ham, chicken, or lamb. The potatoes were either baked, mashed, french fried, or boiled. The vegetables were peas, carrots, corn, or spinach. From the clues given, determine the meal eaten by each member of the family.\n\r\n1. One child had lamb and the other french fried potatoes.\r\n2. One of the females had spinach and the other chicken.\r\n3. The father sat on the right of the person who had corn, who sat on the right of the person who had chicken, who sat on the right of the person who had baked potatoes, who sat on the right of the person who had peas.\r\n4. One parent had boiled potatoes and the other steak.\r\n5. One of the males had steak and the other had french fried potatoes.", "hint": "No hint available.", "answer": "Father had steak, mashed potatoes, and peas.\r\nMother had chicken, boiled potatoes, and carrots.\r\nSister had lamb, baked potatoes, and spinach.\r\nBrother had ham, french fried potatoes, and corn.", "category": "Logic-Grid", "date": "10/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA family of four - father, mother, sister, and brother - went out to dinner. They each had a different meat, potato, and vegetable. The meats were either steak, ham, chicken, or lamb. The potatoes were either baked, mashed, french fried, or boiled. The vegetables were peas, carrots, corn, or spinach. From the clues given, determine the meal eaten by each member of the family.\n\r\n1. One child had lamb and the other french fried potatoes.\r\n2. One of the females had spinach and the other chicken.\r\n3. The father sat on the right of the person who had corn, who sat on the right of the person who had chicken, who sat on the right of the person who had baked potatoes, who sat on the right of the person who had peas.\r\n4. One parent had boiled potatoes and the other steak.\r\n5. One of the males had steak and the other had french fried potatoes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFather had steak, mashed potatoes, and peas.\r\nMother had chicken, boiled potatoes, and carrots.\r\nSister had lamb, baked potatoes, and spinach.\r\nBrother had ham, french fried potatoes, and corn.\n<|im_start|>answer\nFather had steak, mashed potatoes, and peas.\r\nMother had chicken, boiled potatoes, and carrots.\r\nSister had lamb, baked potatoes, and spinach.\r\nBrother had ham, french fried potatoes, and corn.\n<|im_end|>" }, { "id": "#3747", "title": "Weather Man", "fun": 2.85, "difficulty": 1.33, "author": "magisastar", "desc": "John was watching television. Just after the midnight news there was a weather forecast: \"It is raining now and will rain for the next two days. However, in 72 hours it will be bright and sunny.\" \n\r\n\"Wrong again,\" snorted John. He was correct, but how did he know?", "hint": "No hint available.", "answer": "In 72 hours it would be midnight again, so it could not be bright and sunny.", "category": "Logic", "date": "04/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn was watching television. Just after the midnight news there was a weather forecast: \"It is raining now and will rain for the next two days. However, in 72 hours it will be bright and sunny.\" \n\r\n\"Wrong again,\" snorted John. He was correct, but how did he know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn 72 hours it would be midnight again, so it could not be bright and sunny.\n<|im_start|>answer\nIn 72 hours it would be midnight again, so it could not be bright and sunny.\n<|im_end|>" }, { "id": "#23663", "title": "Dream Dates", "fun": 2.85, "difficulty": 2.68, "author": "cinnamon30", "desc": "Jill and 4 of her female friends each scheduled a date with a different man. Each date (no two of which are scheduled the same night) will consist of dinner at a different restaurant, followed by dancing at one of two nightclubs. Three couples will go to Bopper's Nightclub and two couples will go to Polly Esther's Dance Club. From the info provided, determine the date (3rd, 10th, 17th, 24th, or 31st) on which each man and woman have scheduled a date for, as well as the restaurant and nightclub to which they will go.\n\r\n1. The three women going to Bopper's are Beth, Martha, and Robin. The two men going to Polly Esther's are Joe and Sandeep.\n\r\n2. Beth (whose date is set for the 24th) isn't the one who'll be dining at Chez Pierre with Jeff.\n\r\n3. Robin will be going out exactly two weeks before Sandeep, who isn't the man who'll be dining at Pierpont.\n\r\n4. Joe will be going out exactly two weeks before the couple who will be dining at Giovanni's and dancing at Bopper's.\n\r\n5. George's date is set for the 17th. Martha will be going out exactly one week after the couple who will be dining at Margarita's and dancing at Polly Esther's. Nan isn't the woman who will be dining at Margaritas.", "hint": "No hint available.", "answer": "3rd - Joe, Jill, Margaritas, Polly Esther's\r\n10th - Jeff, Martha, Chez Pierre, Bopper's\r\n17th - George, Robin, Giovanni's, Bopper's \r\n24th - Sergio, Beth, Pierpont, Bopper's\r\n31st - Sandeep, Nan, Mario's, Polly Esther's\n\n\r\nThe 3 women going to Bopper's are Beth, Martha, and Robin - clue 1. Thus 2 women going to Polly Esther's are Jill and Nan. Two men going to Polly Esther's are Joe and Sandeep - clue 1. Thus the 3 men going to Bopper's are George, Jeff and Sergio. Sandeep, who is going to Polly Esther's, isn't the 24th because Beth is the 24th - clue 2 and Beth is going to Bopper's - clue 1. Sandeep isn't the 17th - clue 5, he isn't the 3rd or 10th - clue 3, Robin is 2 weeks before Sandeep. Thus Sandeep's date is the 31st. Robin's date is the 17th - clue 3. Martha, who is going to Bopper's - clue 1, isn't the 31st because Sandeep is the 31st and is going to Polly Esther's. Martha isn't the 3rd - clue 5 says she is one week later than another couple. She is the 10th. Margarita's is the 3rd - clue 5. Joe has to be the 3rd because Margaritas is Polly Esther's and Joe is Polly Esther's. Sandeep is already placed, therefore the only other guy going to Polly Esther's is on the 3rd, which is Joe. Giovanni's is the 17th - clue 4. Nan isn't the 3rd - clue 5 says Nan isn't going to Margaritas which is the 3rd. Therefore, Nan is the 31st since the 31st is the only other date going to Polly Esther's. This leaves Jill on the 3rd, since she is the other woman going to Polly Esther's. Jeff is Chez Pierre - clue 2. Jeff isn't the 24th because Beth is the 24th and they aren't dining together - clue 2. Thus Jeff, who is dining at Chez Pierre - clue 2, is the 10th, because Giovanni's is the 17th. Sergio has to be the 24th, only date left (George is the 17th - clue 5). Sandeep isn't Pierpont - clue 3, thus he is Mario's. Pierpont is the 24th, only date left with no restaurant.", "category": "Logic-Grid", "date": "06/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJill and 4 of her female friends each scheduled a date with a different man. Each date (no two of which are scheduled the same night) will consist of dinner at a different restaurant, followed by dancing at one of two nightclubs. Three couples will go to Bopper's Nightclub and two couples will go to Polly Esther's Dance Club. From the info provided, determine the date (3rd, 10th, 17th, 24th, or 31st) on which each man and woman have scheduled a date for, as well as the restaurant and nightclub to which they will go.\n\r\n1. The three women going to Bopper's are Beth, Martha, and Robin. The two men going to Polly Esther's are Joe and Sandeep.\n\r\n2. Beth (whose date is set for the 24th) isn't the one who'll be dining at Chez Pierre with Jeff.\n\r\n3. Robin will be going out exactly two weeks before Sandeep, who isn't the man who'll be dining at Pierpont.\n\r\n4. Joe will be going out exactly two weeks before the couple who will be dining at Giovanni's and dancing at Bopper's.\n\r\n5. George's date is set for the 17th. Martha will be going out exactly one week after the couple who will be dining at Margarita's and dancing at Polly Esther's. Nan isn't the woman who will be dining at Margaritas.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3rd - Joe, Jill, Margaritas, Polly Esther's\r\n10th - Jeff, Martha, Chez Pierre, Bopper's\r\n17th - George, Robin, Giovanni's, Bopper's \r\n24th - Sergio, Beth, Pierpont, Bopper's\r\n31st - Sandeep, Nan, Mario's, Polly Esther's\n\n\r\nThe 3 women going to Bopper's are Beth, Martha, and Robin - clue 1. Thus 2 women going to Polly Esther's are Jill and Nan. Two men going to Polly Esther's are Joe and Sandeep - clue 1. Thus the 3 men going to Bopper's are George, Jeff and Sergio. Sandeep, who is going to Polly Esther's, isn't the 24th because Beth is the 24th - clue 2 and Beth is going to Bopper's - clue 1. Sandeep isn't the 17th - clue 5, he isn't the 3rd or 10th - clue 3, Robin is 2 weeks before Sandeep. Thus Sandeep's date is the 31st. Robin's date is the 17th - clue 3. Martha, who is going to Bopper's - clue 1, isn't the 31st because Sandeep is the 31st and is going to Polly Esther's. Martha isn't the 3rd - clue 5 says she is one week later than another couple. She is the 10th. Margarita's is the 3rd - clue 5. Joe has to be the 3rd because Margaritas is Polly Esther's and Joe is Polly Esther's. Sandeep is already placed, therefore the only other guy going to Polly Esther's is on the 3rd, which is Joe. Giovanni's is the 17th - clue 4. Nan isn't the 3rd - clue 5 says Nan isn't going to Margaritas which is the 3rd. Therefore, Nan is the 31st since the 31st is the only other date going to Polly Esther's. This leaves Jill on the 3rd, since she is the other woman going to Polly Esther's. Jeff is Chez Pierre - clue 2. Jeff isn't the 24th because Beth is the 24th and they aren't dining together - clue 2. Thus Jeff, who is dining at Chez Pierre - clue 2, is the 10th, because Giovanni's is the 17th. Sergio has to be the 24th, only date left (George is the 17th - clue 5). Sandeep isn't Pierpont - clue 3, thus he is Mario's. Pierpont is the 24th, only date left with no restaurant.\n<|im_start|>answer\n3rd - Joe, Jill, Margaritas, Polly Esther's\r\n10th - Jeff, Martha, Chez Pierre, Bopper's\r\n17th - George, Robin, Giovanni's, Bopper's \r\n24th - Sergio, Beth, Pierpont, Bopper's\r\n31st - Sandeep, Nan, Mario's, Polly Esther's\n\n\r\nThe 3 women going to Bopper's are Beth, Martha, and Robin - clue 1. Thus 2 women going to Polly Esther's are Jill and Nan. Two men going to Polly Esther's are Joe and Sandeep - clue 1. Thus the 3 men going to Bopper's are George, Jeff and Sergio. Sandeep, who is going to Polly Esther's, isn't the 24th because Beth is the 24th - clue 2 and Beth is going to Bopper's - clue 1. Sandeep isn't the 17th - clue 5, he isn't the 3rd or 10th - clue 3, Robin is 2 weeks before Sandeep. Thus Sandeep's date is the 31st. Robin's date is the 17th - clue 3. Martha, who is going to Bopper's - clue 1, isn't the 31st because Sandeep is the 31st and is going to Polly Esther's. Martha isn't the 3rd - clue 5 says she is one week later than another couple. She is the 10th. Margarita's is the 3rd - clue 5. Joe has to be the 3rd because Margaritas is Polly Esther's and Joe is Polly Esther's. Sandeep is already placed, therefore the only other guy going to Polly Esther's is on the 3rd, which is Joe. Giovanni's is the 17th - clue 4. Nan isn't the 3rd - clue 5 says Nan isn't going to Margaritas which is the 3rd. Therefore, Nan is the 31st since the 31st is the only other date going to Polly Esther's. This leaves Jill on the 3rd, since she is the other woman going to Polly Esther's. Jeff is Chez Pierre - clue 2. Jeff isn't the 24th because Beth is the 24th and they aren't dining together - clue 2. Thus Jeff, who is dining at Chez Pierre - clue 2, is the 10th, because Giovanni's is the 17th. Sergio has to be the 24th, only date left (George is the 17th - clue 5). Sandeep isn't Pierpont - clue 3, thus he is Mario's. Pierpont is the 24th, only date left with no restaurant.\n<|im_end|>" }, { "id": "#27916", "title": "Opposites in Code", "fun": 2.85, "difficulty": 2.12, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n + stands for I, J, G, A, or M\r\n * stands for N, B, P, Q, or W\r\n = stands for R, U, C, X, or T\r\n & stands for H, E, K, Z, or Y\r\n ? stands for O, L, F, H, or V\n\r\nThe five letter code word, *?+=&, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "White and Black.", "category": "Logic", "date": "01/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n + stands for I, J, G, A, or M\r\n * stands for N, B, P, Q, or W\r\n = stands for R, U, C, X, or T\r\n & stands for H, E, K, Z, or Y\r\n ? stands for O, L, F, H, or V\n\r\nThe five letter code word, *?+=&, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhite and Black.\n<|im_start|>answer\nWhite and Black.\n<|im_end|>" }, { "id": "#24036", "title": "Katherine's Birthday Party", "fun": 2.85, "difficulty": 1.55, "author": "sports_chick", "desc": "Katherine was turning ten, and she invited Allen, Mary, Alex, and Sarah to her birthday party. All of the guest brought a different present with a different colored wrapping paper. Can you figure out which guest arrived at which time, what present they gave, and the colored wrapping paper they wrapped their present with?\n\r\nNames: Allen, Mary, Alex, and Sarah\r\nTimes: 7:00, 7:15, 8:00, and 8:30\r\nPresents: DVD, Video Game, Board Game, and a Book\r\nColors: Yellow, Green, Blue, and Red\n\r\n1. Sarah did not buy the video game.\n\r\n2. Mary and Sarah were the guest that arrived at 8:30 and the guest that brought the present with a yellow wrapping paper in some order.\n\r\n3. Either Allen or Mary bought the board game.\n\r\n4. The present with the green wrapping paper was not the book or DVD.\n\r\n5. The four presents are the DVD, the one with blue wrapping paper, the one bought by the guest that arrived at 7:15, and the one brought by Sarah.\n\r\n6. Mary made it to the party after Sarah did.\n\r\n7. Allen hates the color blue.\n\r\n8. Allen arrived at the party at 8:00.", "hint": "No hint available.", "answer": "Allen, 8:00, DVD, Red\r\nMary, 8:30, Board Game, Blue\r\nAlex, 7:15, Video Game, Green\r\nSarah, 7:00, Book, Yellow", "category": "Logic-Grid", "date": "06/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKatherine was turning ten, and she invited Allen, Mary, Alex, and Sarah to her birthday party. All of the guest brought a different present with a different colored wrapping paper. Can you figure out which guest arrived at which time, what present they gave, and the colored wrapping paper they wrapped their present with?\n\r\nNames: Allen, Mary, Alex, and Sarah\r\nTimes: 7:00, 7:15, 8:00, and 8:30\r\nPresents: DVD, Video Game, Board Game, and a Book\r\nColors: Yellow, Green, Blue, and Red\n\r\n1. Sarah did not buy the video game.\n\r\n2. Mary and Sarah were the guest that arrived at 8:30 and the guest that brought the present with a yellow wrapping paper in some order.\n\r\n3. Either Allen or Mary bought the board game.\n\r\n4. The present with the green wrapping paper was not the book or DVD.\n\r\n5. The four presents are the DVD, the one with blue wrapping paper, the one bought by the guest that arrived at 7:15, and the one brought by Sarah.\n\r\n6. Mary made it to the party after Sarah did.\n\r\n7. Allen hates the color blue.\n\r\n8. Allen arrived at the party at 8:00.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllen, 8:00, DVD, Red\r\nMary, 8:30, Board Game, Blue\r\nAlex, 7:15, Video Game, Green\r\nSarah, 7:00, Book, Yellow\n<|im_start|>answer\nAllen, 8:00, DVD, Red\r\nMary, 8:30, Board Game, Blue\r\nAlex, 7:15, Video Game, Green\r\nSarah, 7:00, Book, Yellow\n<|im_end|>" }, { "id": "#20545", "title": "Office Work", "fun": 2.85, "difficulty": 2.25, "author": "rose_rox", "desc": "Gwen, Stefan, Ian and Bob are typical miserable office workers, disliked by many, wasting time and always getting stuck in traffic. Your job (which I assure you is more exciting then theirs) is to figure out\n\r\nHow long they were stuck in traffic: 20 min, 45 min, 1 hour, 1 hour and a half\n\r\nHow many dirty looks they received: 3, 5, 9, 15\n\r\nHow much time they wasted: 20 min, 45 min, 1 hour, 3 hours\n\r\nHow was their wasted time spent: chatting online, playing with a magic eight ball, styling their nails, sleeping\n\r\nClues:\r\nThe person chatting online was wasting nine times as much time they were stuck in traffic.\r\nThe person who wasted 20 minutes was repeatedly shaking their magic eight ball.\r\nGwen received 5 dirty looks (and a couple of threats).\r\nBob wasted five times the amount of looks he received.\r\nStefan got a third of the number of dirty looks the person who was stuck in traffic for 90 minutes received.\r\nIan was stuck in traffic the least amount of time.\r\nThe person who slept wasted neither the most or least amount of time; the same applies with how long they were stuck in traffic.\r\nBob wasn't the one muttering to a black inanimate object. It was his male colleague who was stuck in traffic 30 minutes less than him.\n\r\nFor the logic grid:\r\nT=Traffic\r\nW=Time Wasted", "hint": "No hint available.", "answer": "Gwen was stuck in traffic for 45 min, received 5 dirty looks and wasted 1 hour sleeping.\n\r\nStefan was stuck in traffic for 1 hour, received 3 dirty looks and wasted 20 minutes playing with a magic eight ball.\n\r\nIan was stuck in traffic for 20 minutes, received 15 dirty looks and wasted 3 hours chatting online.\n\r\nBob was stuck in traffic for 1 hour and a half, received 9 dirty looks and took 45 minutes to get his perfect French manicure.", "category": "Logic-Grid", "date": "01/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGwen, Stefan, Ian and Bob are typical miserable office workers, disliked by many, wasting time and always getting stuck in traffic. Your job (which I assure you is more exciting then theirs) is to figure out\n\r\nHow long they were stuck in traffic: 20 min, 45 min, 1 hour, 1 hour and a half\n\r\nHow many dirty looks they received: 3, 5, 9, 15\n\r\nHow much time they wasted: 20 min, 45 min, 1 hour, 3 hours\n\r\nHow was their wasted time spent: chatting online, playing with a magic eight ball, styling their nails, sleeping\n\r\nClues:\r\nThe person chatting online was wasting nine times as much time they were stuck in traffic.\r\nThe person who wasted 20 minutes was repeatedly shaking their magic eight ball.\r\nGwen received 5 dirty looks (and a couple of threats).\r\nBob wasted five times the amount of looks he received.\r\nStefan got a third of the number of dirty looks the person who was stuck in traffic for 90 minutes received.\r\nIan was stuck in traffic the least amount of time.\r\nThe person who slept wasted neither the most or least amount of time; the same applies with how long they were stuck in traffic.\r\nBob wasn't the one muttering to a black inanimate object. It was his male colleague who was stuck in traffic 30 minutes less than him.\n\r\nFor the logic grid:\r\nT=Traffic\r\nW=Time Wasted\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGwen was stuck in traffic for 45 min, received 5 dirty looks and wasted 1 hour sleeping.\n\r\nStefan was stuck in traffic for 1 hour, received 3 dirty looks and wasted 20 minutes playing with a magic eight ball.\n\r\nIan was stuck in traffic for 20 minutes, received 15 dirty looks and wasted 3 hours chatting online.\n\r\nBob was stuck in traffic for 1 hour and a half, received 9 dirty looks and took 45 minutes to get his perfect French manicure.\n<|im_start|>answer\nGwen was stuck in traffic for 45 min, received 5 dirty looks and wasted 1 hour sleeping.\n\r\nStefan was stuck in traffic for 1 hour, received 3 dirty looks and wasted 20 minutes playing with a magic eight ball.\n\r\nIan was stuck in traffic for 20 minutes, received 15 dirty looks and wasted 3 hours chatting online.\n\r\nBob was stuck in traffic for 1 hour and a half, received 9 dirty looks and took 45 minutes to get his perfect French manicure.\n<|im_end|>" }, { "id": "#49969", "title": "Parakeet Basketball", "fun": 2.85, "difficulty": 2.31, "author": "eighsse", "desc": "Your favorite college basketball team, the Fighting Parakeets, is playing against a rival, but you haven't been able to see any of the game yet because you have been busy. However, your brother was in a nearby room watching it. Your brother sees a statistics display during the halftime break and decides to give you a trick math test. You come into the room as the second half is beginning and see that your team is winning 32-29. Your brother says, \"The Fighting Parakeets have scored on 18 shots. They have made at least twice as many 2-point shots as free throws. How many free throws, 2-pointers, and 3-pointers have they made?\" He thinks you will become confused in your figuring because he has not given you quite enough information to find the solution. However, you could hear bits and pieces of the game from the next room while you were busy, and you happened to hear that your favorite Fighting Parakeets player nailed a long 3-point shot. What is the answer to your brother's question?", "hint": "A free throw scores 1 point.", "answer": "5 free throws, 12 2-point shots, and 1 3-point shot.\n\r\nLet x be the number of free throws made,\r\ny be the number of 2-pointers made,\r\nand z be the number of 3-pointers made.\n\r\nFrom the score, you know (A): x + 2y + 3z = 32\r\nFrom the quote, you know (B): x + y + z = 18\r\nMultiply (B) by 3 to get (C): 3x + 3y + 3x = 54\r\nSubtract (A) from (C) to get: 2x + y = 22, or (D): y = 22 - 2x\r\nFrom the quote, you also know (E): 2x <= y\r\nSubstituting (D) into (E) gives: 2x <= 22 - 2x, or (F): x <= 5.5\n\r\nIf x=5, then from (D) you get y=12, and from (A) you get z=1.\r\nIf x=4, then y=14, and z=0.\r\nIf x=3, then y=16, and z=-1. This is not possible because z cannot be negative. If you continue decrementing x, then z will continue to decrease too.\n\r\nSo, you have two options that fit the criteria given by your brother:\r\n5 free throws, 12 2-point shots, 1 3-point shot, or\r\n4 free throws, 14 2-point shots, 0 3-point shots.\r\nSo it's a good thing that you heard that your favorite player made a 3-pointer, because that eliminates the second option!", "category": "Math", "date": "10/11/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour favorite college basketball team, the Fighting Parakeets, is playing against a rival, but you haven't been able to see any of the game yet because you have been busy. However, your brother was in a nearby room watching it. Your brother sees a statistics display during the halftime break and decides to give you a trick math test. You come into the room as the second half is beginning and see that your team is winning 32-29. Your brother says, \"The Fighting Parakeets have scored on 18 shots. They have made at least twice as many 2-point shots as free throws. How many free throws, 2-pointers, and 3-pointers have they made?\" He thinks you will become confused in your figuring because he has not given you quite enough information to find the solution. However, you could hear bits and pieces of the game from the next room while you were busy, and you happened to hear that your favorite Fighting Parakeets player nailed a long 3-point shot. What is the answer to your brother's question?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 free throws, 12 2-point shots, and 1 3-point shot.\n\r\nLet x be the number of free throws made,\r\ny be the number of 2-pointers made,\r\nand z be the number of 3-pointers made.\n\r\nFrom the score, you know (A): x + 2y + 3z = 32\r\nFrom the quote, you know (B): x + y + z = 18\r\nMultiply (B) by 3 to get (C): 3x + 3y + 3x = 54\r\nSubtract (A) from (C) to get: 2x + y = 22, or (D): y = 22 - 2x\r\nFrom the quote, you also know (E): 2x <= y\r\nSubstituting (D) into (E) gives: 2x <= 22 - 2x, or (F): x <= 5.5\n\r\nIf x=5, then from (D) you get y=12, and from (A) you get z=1.\r\nIf x=4, then y=14, and z=0.\r\nIf x=3, then y=16, and z=-1. This is not possible because z cannot be negative. If you continue decrementing x, then z will continue to decrease too.\n\r\nSo, you have two options that fit the criteria given by your brother:\r\n5 free throws, 12 2-point shots, 1 3-point shot, or\r\n4 free throws, 14 2-point shots, 0 3-point shots.\r\nSo it's a good thing that you heard that your favorite player made a 3-pointer, because that eliminates the second option!\n<|im_start|>answer\n5 free throws, 12 2-point shots, and 1 3-point shot.\n\r\nLet x be the number of free throws made,\r\ny be the number of 2-pointers made,\r\nand z be the number of 3-pointers made.\n\r\nFrom the score, you know (A): x + 2y + 3z = 32\r\nFrom the quote, you know (B): x + y + z = 18\r\nMultiply (B) by 3 to get (C): 3x + 3y + 3x = 54\r\nSubtract (A) from (C) to get: 2x + y = 22, or (D): y = 22 - 2x\r\nFrom the quote, you also know (E): 2x <= y\r\nSubstituting (D) into (E) gives: 2x <= 22 - 2x, or (F): x <= 5.5\n\r\nIf x=5, then from (D) you get y=12, and from (A) you get z=1.\r\nIf x=4, then y=14, and z=0.\r\nIf x=3, then y=16, and z=-1. This is not possible because z cannot be negative. If you continue decrementing x, then z will continue to decrease too.\n\r\nSo, you have two options that fit the criteria given by your brother:\r\n5 free throws, 12 2-point shots, 1 3-point shot, or\r\n4 free throws, 14 2-point shots, 0 3-point shots.\r\nSo it's a good thing that you heard that your favorite player made a 3-pointer, because that eliminates the second option!\n<|im_end|>" }, { "id": "#43113", "title": "Real (But Fictional) Estate", "fun": 2.85, "difficulty": 2.16, "author": "chaskey", "desc": "Five Property Owners sold real estate in five areas of town to five buyers with the aid of five real-estate companies. Who did what and where?\n\r\nOwners: Alice, Ann, Burt, Clyde, David\r\nBuyers: Gary, George, Harriet, Jane, Mary\r\nRealtors: Big Lands Realty, Lots 'n Lots, Grounders Realtors, AcreAge, ProperTies\r\nProperties: Streetview Apts., Fabulous Flats, Wooden Oaks Manor, Running Water Ranch, Cornered Castle\r\nLocations: Wet Beaches, Dryrain Gulch, The Hamlet, Dis-strict District, Even Fields\n\r\n1. Jane bought Wooden Oaks Manor to help her nephew Clyde (the owner), but she planned to resell it, because she wanted nothing to do with the Dis-strict District where it was located.\n\r\n2. Harriet didn't trust Grounders Realtors, so she chose instead to invest in an Even Fields property.\n\r\n3. Lots 'n Lots does not handle property in the Dis-strict District, and Clyde does not deal with Big Lands Realty.\n\r\n4. The five real-estate companies are: AcreAge, the one which handled David's Streetview Apts. (which was sold to George), the one with property in Dryrain Gulch, the one from which Mary bought Running Water Ranch, and the one which sold Burt's Fabulous Flats.\n\r\n5. Neither Grounders nor ProperTies will handle property in the Dis-strict District.\n\r\n6. Alice was delighted when Lots 'n Lots informed her that her Running Water Ranch had been sold to a cowgirl. That was the most expensive property in the Wet Beaches area, but it was not as expensive as the property ProperTies sold in The Hamlet.", "hint": "No hint available.", "answer": "Alice--Mary--Lots' n Lots--Running Water Ranch--Wet Beaches\n\r\nAnn--Gary--Grounders Realtors--Cornered Castle--Dryrain Gulch\n\r\nBurt--Harriet--Big Lands Realty--Fabulous Flats--Even Fields\n\r\nClyde--Jane--AcreAge--Wooden Oaks Manor--Dis-strict District\n\r\nDavid--George--ProperTies--Streetview Apts.--The Hamlet", "category": "Logic-Grid", "date": "09/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive Property Owners sold real estate in five areas of town to five buyers with the aid of five real-estate companies. Who did what and where?\n\r\nOwners: Alice, Ann, Burt, Clyde, David\r\nBuyers: Gary, George, Harriet, Jane, Mary\r\nRealtors: Big Lands Realty, Lots 'n Lots, Grounders Realtors, AcreAge, ProperTies\r\nProperties: Streetview Apts., Fabulous Flats, Wooden Oaks Manor, Running Water Ranch, Cornered Castle\r\nLocations: Wet Beaches, Dryrain Gulch, The Hamlet, Dis-strict District, Even Fields\n\r\n1. Jane bought Wooden Oaks Manor to help her nephew Clyde (the owner), but she planned to resell it, because she wanted nothing to do with the Dis-strict District where it was located.\n\r\n2. Harriet didn't trust Grounders Realtors, so she chose instead to invest in an Even Fields property.\n\r\n3. Lots 'n Lots does not handle property in the Dis-strict District, and Clyde does not deal with Big Lands Realty.\n\r\n4. The five real-estate companies are: AcreAge, the one which handled David's Streetview Apts. (which was sold to George), the one with property in Dryrain Gulch, the one from which Mary bought Running Water Ranch, and the one which sold Burt's Fabulous Flats.\n\r\n5. Neither Grounders nor ProperTies will handle property in the Dis-strict District.\n\r\n6. Alice was delighted when Lots 'n Lots informed her that her Running Water Ranch had been sold to a cowgirl. That was the most expensive property in the Wet Beaches area, but it was not as expensive as the property ProperTies sold in The Hamlet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlice--Mary--Lots' n Lots--Running Water Ranch--Wet Beaches\n\r\nAnn--Gary--Grounders Realtors--Cornered Castle--Dryrain Gulch\n\r\nBurt--Harriet--Big Lands Realty--Fabulous Flats--Even Fields\n\r\nClyde--Jane--AcreAge--Wooden Oaks Manor--Dis-strict District\n\r\nDavid--George--ProperTies--Streetview Apts.--The Hamlet\n<|im_start|>answer\nAlice--Mary--Lots' n Lots--Running Water Ranch--Wet Beaches\n\r\nAnn--Gary--Grounders Realtors--Cornered Castle--Dryrain Gulch\n\r\nBurt--Harriet--Big Lands Realty--Fabulous Flats--Even Fields\n\r\nClyde--Jane--AcreAge--Wooden Oaks Manor--Dis-strict District\n\r\nDavid--George--ProperTies--Streetview Apts.--The Hamlet\n<|im_end|>" }, { "id": "#4840", "title": "Area of a Square", "fun": 2.85, "difficulty": 1.67, "author": "andy1608", "desc": "You have a piece of paper, 10cm by 10cm. Area = 100cm^2. For some reason, you need a square piece of paper with an area of 50cm^2. Using the paper you have, what's an easy way of getting the new square?", "hint": "Try it with a piece of paper, doesn't matter the size of the square, try to find a square half its size inside it.", "answer": "Fold the four corners of the square into the centre. This doubles the thickness of the paper, and so halves the area.", "category": "Math", "date": "06/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a piece of paper, 10cm by 10cm. Area = 100cm^2. For some reason, you need a square piece of paper with an area of 50cm^2. Using the paper you have, what's an easy way of getting the new square?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFold the four corners of the square into the centre. This doubles the thickness of the paper, and so halves the area.\n<|im_start|>answer\nFold the four corners of the square into the centre. This doubles the thickness of the paper, and so halves the area.\n<|im_end|>" }, { "id": "#27149", "title": "Time For a Picnic", "fun": 2.85, "difficulty": 2.54, "author": "scm14", "desc": "Five friends (one is Thomas) decided one day to take their children to the park for a picnic. Can you determine what the parents' first and last names are, who they brought to the picnic, how old the child was and how many children each parent has. \n\r\nParents: Marion, Thomas, Andrew, Emily, Christina\r\nSurnames: Williams, Drew, Matthew, Edwards, Thompson\r\nNumber of Children: 1, 2, 3, 4, 5\r\nChildren: Suzanne, Louanne, Peter, Stephanie, Walter\r\nAges: 5, 7, 17, 8, 15\n\n\r\n1. Mrs. Edwards's child was not Louanne (who was not 8). Stephanie did not have 4 siblings. \n\r\n2. Stephanie was not the oldest child, but was no more than 3 years older than the youngest child. Walter Drew was not Thomas's child.\n\r\n3. Christina's daughter was not the oldest, but was older than at least one other child. The youngest child was not surnamed Matthew.\n\r\n4. The oldest child was upset because she was expected to help the parents watch the younger children. Luckily, her friend Louanne was there to keep her company. \n\r\n5. Andrew (who was either surnamed Thompson or Williams) brought either Suzanne or the child who was five years old. \n\r\n6. Stephanie, an only child, and her father carpooled with the Thompson family in their van. Mr. Thompson needed to drive a van because he had five children. \n\r\n7. Peter was younger than Stephanie. Stephanie was ten years younger than one of the other children. \n\r\n8. The five parents were Marion, Mrs. Matthew, Suzanne Thompson's father, the parent who had the eight year old child, and the parent who had only one child. \n\r\n9. Emily had more children than Marion, but less children than Christina.", "hint": "No hint available.", "answer": "Marion Edwards, 2 children, Peter, 5 years\r\nThomas Williams, 1 child, Stephanie, 7 years\r\nAndrew Thompson, 5 children, Suzanne, 17 years\r\nEmily Drew, 3 children, Walter, 8 years\r\nChristina Matthew, 4 children, Louanne, 15 years", "category": "Logic-Grid", "date": "11/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends (one is Thomas) decided one day to take their children to the park for a picnic. Can you determine what the parents' first and last names are, who they brought to the picnic, how old the child was and how many children each parent has. \n\r\nParents: Marion, Thomas, Andrew, Emily, Christina\r\nSurnames: Williams, Drew, Matthew, Edwards, Thompson\r\nNumber of Children: 1, 2, 3, 4, 5\r\nChildren: Suzanne, Louanne, Peter, Stephanie, Walter\r\nAges: 5, 7, 17, 8, 15\n\n\r\n1. Mrs. Edwards's child was not Louanne (who was not 8). Stephanie did not have 4 siblings. \n\r\n2. Stephanie was not the oldest child, but was no more than 3 years older than the youngest child. Walter Drew was not Thomas's child.\n\r\n3. Christina's daughter was not the oldest, but was older than at least one other child. The youngest child was not surnamed Matthew.\n\r\n4. The oldest child was upset because she was expected to help the parents watch the younger children. Luckily, her friend Louanne was there to keep her company. \n\r\n5. Andrew (who was either surnamed Thompson or Williams) brought either Suzanne or the child who was five years old. \n\r\n6. Stephanie, an only child, and her father carpooled with the Thompson family in their van. Mr. Thompson needed to drive a van because he had five children. \n\r\n7. Peter was younger than Stephanie. Stephanie was ten years younger than one of the other children. \n\r\n8. The five parents were Marion, Mrs. Matthew, Suzanne Thompson's father, the parent who had the eight year old child, and the parent who had only one child. \n\r\n9. Emily had more children than Marion, but less children than Christina.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMarion Edwards, 2 children, Peter, 5 years\r\nThomas Williams, 1 child, Stephanie, 7 years\r\nAndrew Thompson, 5 children, Suzanne, 17 years\r\nEmily Drew, 3 children, Walter, 8 years\r\nChristina Matthew, 4 children, Louanne, 15 years\n<|im_start|>answer\nMarion Edwards, 2 children, Peter, 5 years\r\nThomas Williams, 1 child, Stephanie, 7 years\r\nAndrew Thompson, 5 children, Suzanne, 17 years\r\nEmily Drew, 3 children, Walter, 8 years\r\nChristina Matthew, 4 children, Louanne, 15 years\n<|im_end|>" }, { "id": "#28661", "title": "Foreign Students", "fun": 2.85, "difficulty": 2.18, "author": "Winner4600", "desc": "Five foreign college students met each other in the United States while attending the same school. Their names are Chris, Hugo, Sam, Anna, and Jessica. Each one has been in the US for a different number of years, is from a different country, and is currently learning a different language than all the others. Can you figure out who's who?\n\r\n1. The five college students are Anna, the Mexican, the boy who wants to learn Italian, the one who has been in the US for 3 years, and the Australian (who doesn't want to learn Swedish.)\n\r\n2. Chris has not been in the US for the longest time, but the one learning Vietnamese has.\n\r\n3. If Hugo is Russian, then Sam wants to learn German. Otherwise, Chris is Mexican and Jessica wants to learn Japanese.\n\r\n4. Neither of the girls qualify to be an American citizen. To become an American citizen, you must have lived in the US for at least 5 years.\n\r\n5. If Sam is Australian, then Hugo is learning Italian. If not, then Jessica is Russian and Chris is learning Vietnamese.\n\r\n6. The Mexican is learning Swedish and the 3-year resident is learning Japanese.\n\r\n7. The Frenchman has been in the states for 2 years.", "hint": "No hint available.", "answer": "Chris-Mexico-Swedish-5 years\r\nHugo-France-Italian-2 years\r\nSam-Australia-Vietnamese-6 years\r\nAnna-Russia-German-4 years\r\nJessica-China-Japanese-3 years", "category": "Logic-Grid", "date": "02/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive foreign college students met each other in the United States while attending the same school. Their names are Chris, Hugo, Sam, Anna, and Jessica. Each one has been in the US for a different number of years, is from a different country, and is currently learning a different language than all the others. Can you figure out who's who?\n\r\n1. The five college students are Anna, the Mexican, the boy who wants to learn Italian, the one who has been in the US for 3 years, and the Australian (who doesn't want to learn Swedish.)\n\r\n2. Chris has not been in the US for the longest time, but the one learning Vietnamese has.\n\r\n3. If Hugo is Russian, then Sam wants to learn German. Otherwise, Chris is Mexican and Jessica wants to learn Japanese.\n\r\n4. Neither of the girls qualify to be an American citizen. To become an American citizen, you must have lived in the US for at least 5 years.\n\r\n5. If Sam is Australian, then Hugo is learning Italian. If not, then Jessica is Russian and Chris is learning Vietnamese.\n\r\n6. The Mexican is learning Swedish and the 3-year resident is learning Japanese.\n\r\n7. The Frenchman has been in the states for 2 years.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChris-Mexico-Swedish-5 years\r\nHugo-France-Italian-2 years\r\nSam-Australia-Vietnamese-6 years\r\nAnna-Russia-German-4 years\r\nJessica-China-Japanese-3 years\n<|im_start|>answer\nChris-Mexico-Swedish-5 years\r\nHugo-France-Italian-2 years\r\nSam-Australia-Vietnamese-6 years\r\nAnna-Russia-German-4 years\r\nJessica-China-Japanese-3 years\n<|im_end|>" }, { "id": "#1047", "title": "Murder on a Train", "fun": 2.85, "difficulty": 2.2, "author": "vivek", "desc": "The midnight train is coming down the mountains. Art Farnanski seems to be dozing off in his seat. Someone knows that this is not true. At the station, all the passengers get off the train, except one. The conductor comes and taps him on the shoulder to let him know they have arrived. Art Farnanski does not answer. He is dead. Hours later the four people that had shared the train compartment with the dead man are at the police station.\n\r\nThe man in the dark suit:\r\n\"I'm innocent. The blonde woman was talking to Farnanski.\"\n\r\nThe blonde woman:\r\n\"I'm innocent. I did not speak to Farnanski.\"\n\r\nThe man in the light suit:\r\n\"I'm innocent. The brunette woman killed him.\"\n\r\nThe brunette woman:\r\n\"I'm innocent. One of the men killed him.\"\n\r\nThat same morning, while he is serving him coffee, the waiter at the Petit Piccolo asks the commander, \"This is an easy case for you, isn't it?\"\n\r\n\"Yes\", answers the commander. \"Four true statements and four false ones. Easy as pie.\"\n\r\nWho killed Farnanski? (Only one person is guilty).", "hint": "No hint available.", "answer": "The blonde woman killed Mr Farnanski. There are only four true statements. Only one person is guilty. Therefore, three of the \"I'm innocent\" statements are true. Only one more statement can be true, and this must be the one made by the man in the dark suit or by the blonde woman. Therefore, \"The brunette killed him\" and \"One of the men killed him\" are false statements, so the blonde woman is the killer.", "category": "Logic", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe midnight train is coming down the mountains. Art Farnanski seems to be dozing off in his seat. Someone knows that this is not true. At the station, all the passengers get off the train, except one. The conductor comes and taps him on the shoulder to let him know they have arrived. Art Farnanski does not answer. He is dead. Hours later the four people that had shared the train compartment with the dead man are at the police station.\n\r\nThe man in the dark suit:\r\n\"I'm innocent. The blonde woman was talking to Farnanski.\"\n\r\nThe blonde woman:\r\n\"I'm innocent. I did not speak to Farnanski.\"\n\r\nThe man in the light suit:\r\n\"I'm innocent. The brunette woman killed him.\"\n\r\nThe brunette woman:\r\n\"I'm innocent. One of the men killed him.\"\n\r\nThat same morning, while he is serving him coffee, the waiter at the Petit Piccolo asks the commander, \"This is an easy case for you, isn't it?\"\n\r\n\"Yes\", answers the commander. \"Four true statements and four false ones. Easy as pie.\"\n\r\nWho killed Farnanski? (Only one person is guilty).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe blonde woman killed Mr Farnanski. There are only four true statements. Only one person is guilty. Therefore, three of the \"I'm innocent\" statements are true. Only one more statement can be true, and this must be the one made by the man in the dark suit or by the blonde woman. Therefore, \"The brunette killed him\" and \"One of the men killed him\" are false statements, so the blonde woman is the killer.\n<|im_start|>answer\nThe blonde woman killed Mr Farnanski. There are only four true statements. Only one person is guilty. Therefore, three of the \"I'm innocent\" statements are true. Only one more statement can be true, and this must be the one made by the man in the dark suit or by the blonde woman. Therefore, \"The brunette killed him\" and \"One of the men killed him\" are false statements, so the blonde woman is the killer.\n<|im_end|>" }, { "id": "#31967", "title": "Astro-Logical", "fun": 2.85, "difficulty": 2.09, "author": "Gizzer", "desc": "The five Lawson siblings - Lee, Leo, Leon, Leona and Lionel - all had their horoscopes done by the famous astrologer Starr Gazer. Madame Gazer puts particular emphasis on the planets Mars and Jupiter, to which other astrologers, she believes, have not granted true importance.\n\r\nOn the day the Lawson siblings were due to collect their charts, Madame Gazer discovered that she had, by force of habit, labelled each of the charts with nothing more than the client's first initial and last name, without thinking of the consequences. Now she was faced with five charts identically labelled \"L. Lawson\", and only random recollections about her five clients. Can you help Madame Gazer by matching each Lawson with his or her occupation and the signs that contain Mars and Jupiter in his or her chart?\n\r\n1. In the five charts, Mars and Jupiter were found only in the signs Aries, Capricorn, Gemini, Leo, and Scorpio; no two charts showed the same Mars sign or the same Jupiter sign, and no chart showed Mars and Jupiter in the same sign.\n\r\n2. Lionel has his Mars in Scorpio.\n\r\n3. The wrestler has Jupiter in Aries and Mars in Leo.\n\r\n4. Neither Lee, Leo, nor Leon has any planet in Leo.\n\r\n5. Lee (who has no planet in Capricorn) had argued with the sibling who has Mars in Gemini about whether Madame Gazer's fee was too high.\n\r\n6. Capricorn, which is the sign that rules the teeth, is the appropriate location of the dentist's Mars.\n\r\n7. Lee and the one with Jupiter in Gemini had joined forces to persuade the skeptical college professor to join them in visiting an astrologer.\n\r\n8. The novelist, whose Jupiter is in Capricorn, shares an apartment with Leo.\n\n\r\nNames: Lee, Leo, Leon, Leona, Lionel\r\nOccupation: dentist, novelist, heavy-equipment operator, professor, wrestler\r\nSigns in Mars: Aries, Capricorn, Gemini, Leo, Scorpio\r\nSigns in Jupiter: Aries, Capricorn, Gemini, Leo, Scorpio", "hint": "No hint available.", "answer": "Lionel has Mars in Scorpio. The wrestler has Mars in Leo, so cannot be Lionel, and cannot be Lee, Leo or Leon (clue 4), so must be Leona. Lee does not have Mars in Capricorn or Gemini (clue 5), so has Mars in Aries. The dentist has Mars in Capricorn. This accounts for 4 of the 5 Lawson siblings, leaving the 5th with Mars in Gemini.\n\r\nLeona has Jupiter in Aries, and Lee, Leo and Leon can't have Jupiter in Leo, so Lionel must. Lee doesn't have Jupiter in Capricorn (clue 5) or Gemini (clue 7), so Lee has Jupiter in Scorpio. The dentist, with Mars in Capricorn, cannot have Jupiter in Capricorn too (clue 1), so has Jupiter in Gemini. This leaves the last sibling with Jupiter in Capricorn, and therefore this sibling is the novelist (clue 8).\n\r\nFrom above, Lee is not the wrestler, the novelist or the dentist. Lee isn't the professor either (clue 7), so Lee is the heavy-equipment operator. This leaves Lionel as the college professor. Leo isn't the novelist (clue 8) and so he is the dentist, and Leon is the novelist.\n\r\nTo summarize:\n\r\nLee Lawson, the heavy-equipment operator, has Mars in Aries and Jupiter in Scorpio.\r\nLeo Lawson, the dentist, has Mars in Capricorn and Jupiter in Gemini.\r\nLeon Lawson, the novelist, has Mars in Gemini and Jupiter in Capricorn.\r\nLeona Lawson, the wrestler, has Mars in Leo and Jupiter in Aries.\r\nLionel Lawson, the college professor, has Mars in Scorpio and Jupiter in Leo.", "category": "Logic-Grid", "date": "07/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe five Lawson siblings - Lee, Leo, Leon, Leona and Lionel - all had their horoscopes done by the famous astrologer Starr Gazer. Madame Gazer puts particular emphasis on the planets Mars and Jupiter, to which other astrologers, she believes, have not granted true importance.\n\r\nOn the day the Lawson siblings were due to collect their charts, Madame Gazer discovered that she had, by force of habit, labelled each of the charts with nothing more than the client's first initial and last name, without thinking of the consequences. Now she was faced with five charts identically labelled \"L. Lawson\", and only random recollections about her five clients. Can you help Madame Gazer by matching each Lawson with his or her occupation and the signs that contain Mars and Jupiter in his or her chart?\n\r\n1. In the five charts, Mars and Jupiter were found only in the signs Aries, Capricorn, Gemini, Leo, and Scorpio; no two charts showed the same Mars sign or the same Jupiter sign, and no chart showed Mars and Jupiter in the same sign.\n\r\n2. Lionel has his Mars in Scorpio.\n\r\n3. The wrestler has Jupiter in Aries and Mars in Leo.\n\r\n4. Neither Lee, Leo, nor Leon has any planet in Leo.\n\r\n5. Lee (who has no planet in Capricorn) had argued with the sibling who has Mars in Gemini about whether Madame Gazer's fee was too high.\n\r\n6. Capricorn, which is the sign that rules the teeth, is the appropriate location of the dentist's Mars.\n\r\n7. Lee and the one with Jupiter in Gemini had joined forces to persuade the skeptical college professor to join them in visiting an astrologer.\n\r\n8. The novelist, whose Jupiter is in Capricorn, shares an apartment with Leo.\n\n\r\nNames: Lee, Leo, Leon, Leona, Lionel\r\nOccupation: dentist, novelist, heavy-equipment operator, professor, wrestler\r\nSigns in Mars: Aries, Capricorn, Gemini, Leo, Scorpio\r\nSigns in Jupiter: Aries, Capricorn, Gemini, Leo, Scorpio\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLionel has Mars in Scorpio. The wrestler has Mars in Leo, so cannot be Lionel, and cannot be Lee, Leo or Leon (clue 4), so must be Leona. Lee does not have Mars in Capricorn or Gemini (clue 5), so has Mars in Aries. The dentist has Mars in Capricorn. This accounts for 4 of the 5 Lawson siblings, leaving the 5th with Mars in Gemini.\n\r\nLeona has Jupiter in Aries, and Lee, Leo and Leon can't have Jupiter in Leo, so Lionel must. Lee doesn't have Jupiter in Capricorn (clue 5) or Gemini (clue 7), so Lee has Jupiter in Scorpio. The dentist, with Mars in Capricorn, cannot have Jupiter in Capricorn too (clue 1), so has Jupiter in Gemini. This leaves the last sibling with Jupiter in Capricorn, and therefore this sibling is the novelist (clue 8).\n\r\nFrom above, Lee is not the wrestler, the novelist or the dentist. Lee isn't the professor either (clue 7), so Lee is the heavy-equipment operator. This leaves Lionel as the college professor. Leo isn't the novelist (clue 8) and so he is the dentist, and Leon is the novelist.\n\r\nTo summarize:\n\r\nLee Lawson, the heavy-equipment operator, has Mars in Aries and Jupiter in Scorpio.\r\nLeo Lawson, the dentist, has Mars in Capricorn and Jupiter in Gemini.\r\nLeon Lawson, the novelist, has Mars in Gemini and Jupiter in Capricorn.\r\nLeona Lawson, the wrestler, has Mars in Leo and Jupiter in Aries.\r\nLionel Lawson, the college professor, has Mars in Scorpio and Jupiter in Leo.\n<|im_start|>answer\nLionel has Mars in Scorpio. The wrestler has Mars in Leo, so cannot be Lionel, and cannot be Lee, Leo or Leon (clue 4), so must be Leona. Lee does not have Mars in Capricorn or Gemini (clue 5), so has Mars in Aries. The dentist has Mars in Capricorn. This accounts for 4 of the 5 Lawson siblings, leaving the 5th with Mars in Gemini.\n\r\nLeona has Jupiter in Aries, and Lee, Leo and Leon can't have Jupiter in Leo, so Lionel must. Lee doesn't have Jupiter in Capricorn (clue 5) or Gemini (clue 7), so Lee has Jupiter in Scorpio. The dentist, with Mars in Capricorn, cannot have Jupiter in Capricorn too (clue 1), so has Jupiter in Gemini. This leaves the last sibling with Jupiter in Capricorn, and therefore this sibling is the novelist (clue 8).\n\r\nFrom above, Lee is not the wrestler, the novelist or the dentist. Lee isn't the professor either (clue 7), so Lee is the heavy-equipment operator. This leaves Lionel as the college professor. Leo isn't the novelist (clue 8) and so he is the dentist, and Leon is the novelist.\n\r\nTo summarize:\n\r\nLee Lawson, the heavy-equipment operator, has Mars in Aries and Jupiter in Scorpio.\r\nLeo Lawson, the dentist, has Mars in Capricorn and Jupiter in Gemini.\r\nLeon Lawson, the novelist, has Mars in Gemini and Jupiter in Capricorn.\r\nLeona Lawson, the wrestler, has Mars in Leo and Jupiter in Aries.\r\nLionel Lawson, the college professor, has Mars in Scorpio and Jupiter in Leo.\n<|im_end|>" }, { "id": "#24915", "title": "Two Men in the Forest", "fun": 2.85, "difficulty": 2.19, "author": "dutchymonster", "desc": "Two men went deep into the Dutch Forest: one, a small, meek man; the other, a monster.\n\r\nThey walked for days, until, out of food, they got desperate. The monster murdered the meek man, and ate him for dinner!\n\r\nHe left no remains, whatsoever, and was seen by no one. On his return to civilisation he told no one.\n\r\nWho was the murdering, cannibalistic monster?", "hint": "No hint available.", "answer": "Me!\n\r\nI told no one, therefore no one else could know about the incident. Only the murderer could tell the story!", "category": "Logic", "date": "07/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo men went deep into the Dutch Forest: one, a small, meek man; the other, a monster.\n\r\nThey walked for days, until, out of food, they got desperate. The monster murdered the meek man, and ate him for dinner!\n\r\nHe left no remains, whatsoever, and was seen by no one. On his return to civilisation he told no one.\n\r\nWho was the murdering, cannibalistic monster?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMe!\n\r\nI told no one, therefore no one else could know about the incident. Only the murderer could tell the story!\n<|im_start|>answer\nMe!\n\r\nI told no one, therefore no one else could know about the incident. Only the murderer could tell the story!\n<|im_end|>" }, { "id": "#27981", "title": "Santa's Pack Held Thirty Toys...", "fun": 2.84, "difficulty": 2.46, "author": "thepianistalex", "desc": "Ole Santa's pack held thirty toys\r\nMade by his elfin crew;\r\nAnd though none made the same amount,\r\nEach elf made more than two.\r\nThe elf named Cher made one more Christmas toy\r\nThan the elf who dressed in reds,\r\nBut Cher made one less Christmas toy\r\nThan the elf who made the sleds.\r\nSpry Johnny Elf made racing cars;\r\nFive toys were made by Jane.\r\nThe elf who dressed in yellow suits\r\nMade each and every train.\r\nThe elf who always dressed in green\r\nMade one-third as many as Sue;\r\nCute Marcia elf was dressed in orange,\r\nAnd one elf dressed in blue.\r\nThe elf who made the spinning tops\r\nMade the most toys of them all.\r\nAnother perky smiling elf\r\nMade each and every ball.\r\nOle Santa's pack held thirty gifts\r\nAll tagged for girls and boys.\r\nFrom the clues that you've been given,\r\nNow guess who made the toys!", "hint": "This puzzle involves five elves dressed in five different colors each making a different toy. Figure out the numbers that fit these conditions and can add up to thirty!", "answer": "Cute Marcia was in orange and made seven sleds.\r\nSue was in blue and made nine spinning tops.\r\nJane was in red and made five balls.\r\nSpry Johnny was in green and made three racing cars.\r\nCher was in yellow and made six trains.", "category": "Logic", "date": "01/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOle Santa's pack held thirty toys\r\nMade by his elfin crew;\r\nAnd though none made the same amount,\r\nEach elf made more than two.\r\nThe elf named Cher made one more Christmas toy\r\nThan the elf who dressed in reds,\r\nBut Cher made one less Christmas toy\r\nThan the elf who made the sleds.\r\nSpry Johnny Elf made racing cars;\r\nFive toys were made by Jane.\r\nThe elf who dressed in yellow suits\r\nMade each and every train.\r\nThe elf who always dressed in green\r\nMade one-third as many as Sue;\r\nCute Marcia elf was dressed in orange,\r\nAnd one elf dressed in blue.\r\nThe elf who made the spinning tops\r\nMade the most toys of them all.\r\nAnother perky smiling elf\r\nMade each and every ball.\r\nOle Santa's pack held thirty gifts\r\nAll tagged for girls and boys.\r\nFrom the clues that you've been given,\r\nNow guess who made the toys!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCute Marcia was in orange and made seven sleds.\r\nSue was in blue and made nine spinning tops.\r\nJane was in red and made five balls.\r\nSpry Johnny was in green and made three racing cars.\r\nCher was in yellow and made six trains.\n<|im_start|>answer\nCute Marcia was in orange and made seven sleds.\r\nSue was in blue and made nine spinning tops.\r\nJane was in red and made five balls.\r\nSpry Johnny was in green and made three racing cars.\r\nCher was in yellow and made six trains.\n<|im_end|>" }, { "id": "#21164", "title": "Summer Job", "fun": 2.84, "difficulty": 2.04, "author": "sftbaltwty", "desc": "5 boys decided to get summer jobs caring for the gardens and lawns of their neighbors. Each boy cared for the lawn of a different neighbor, worked for a different number of hours each day, and got paid a different amount for each hour of work. Can you figure out which boy worked for which neighbor, how often he worked, and how much he got paid using the following clues? *note* just because one boy works more hours than another, does NOT mean he gets paid more per hour or even in a single day.\n\r\n1. None of the boys worked for a family who shared the same first initial with him.\r\n2. Aaron, the boy who works for the Dilweeds, and the boy who works 6 hours a day are all brothers.\r\n3. The two boys who work 4 and 8 hours a day get paid the same amount as hours that they work; Jack is one of these boys but Eric is not.\r\n4. The Emmertons do not employ any of the three brothers, but they do pay $10 an hour.\r\n5. The Dilweeds only need service 2 hours a day, and therefore pay the least amount.\r\n6. Aaron works twice as long as Eric but half as long as Jack.\r\n7. The Williams pay more than the Jungers but less than the Simons.\r\n8. Brad works more hours than Sean but gets paid less.", "hint": "No hint available.", "answer": "-Brad, Williams, 6 hrs/day, $5\r\n-Eric, Dilweeds, 2 hrs/day, $3\r\n-Aaron, Jungers, 4 hrs/day, $4\r\n-Jack, Simons, 8 hrs/day, $8\r\n-Sean, Emmertons, 5 hrs/day, $10", "category": "Logic-Grid", "date": "02/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 boys decided to get summer jobs caring for the gardens and lawns of their neighbors. Each boy cared for the lawn of a different neighbor, worked for a different number of hours each day, and got paid a different amount for each hour of work. Can you figure out which boy worked for which neighbor, how often he worked, and how much he got paid using the following clues? *note* just because one boy works more hours than another, does NOT mean he gets paid more per hour or even in a single day.\n\r\n1. None of the boys worked for a family who shared the same first initial with him.\r\n2. Aaron, the boy who works for the Dilweeds, and the boy who works 6 hours a day are all brothers.\r\n3. The two boys who work 4 and 8 hours a day get paid the same amount as hours that they work; Jack is one of these boys but Eric is not.\r\n4. The Emmertons do not employ any of the three brothers, but they do pay $10 an hour.\r\n5. The Dilweeds only need service 2 hours a day, and therefore pay the least amount.\r\n6. Aaron works twice as long as Eric but half as long as Jack.\r\n7. The Williams pay more than the Jungers but less than the Simons.\r\n8. Brad works more hours than Sean but gets paid less.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-Brad, Williams, 6 hrs/day, $5\r\n-Eric, Dilweeds, 2 hrs/day, $3\r\n-Aaron, Jungers, 4 hrs/day, $4\r\n-Jack, Simons, 8 hrs/day, $8\r\n-Sean, Emmertons, 5 hrs/day, $10\n<|im_start|>answer\n-Brad, Williams, 6 hrs/day, $5\r\n-Eric, Dilweeds, 2 hrs/day, $3\r\n-Aaron, Jungers, 4 hrs/day, $4\r\n-Jack, Simons, 8 hrs/day, $8\r\n-Sean, Emmertons, 5 hrs/day, $10\n<|im_end|>" }, { "id": "#52267", "title": "The Cake Disaster", "fun": 2.84, "difficulty": 2.0, "author": "Rove_Tarts", "desc": "One day, in baking class, 12 students were baking cakes when the fire alarm went off. Everyone exited the building, but when they got back, they found someone had dumped all the sugar into one of the batter-filled bowls. Everyone was puzzled over what to do until Gina had an idea: why not mix the batters together and then separate the contents back in the bowls. Here is what happened in chronological order:\n\r\nAllie mixed with Tina\r\nEmma mixed with Gina\r\nKaleb mixed with Daniel\r\nColt mixed with Emma\r\nTina mixed with Noah\r\nMary mixed with Gina\r\nQuinn mixed with Emma\r\nJacob mixed with Lily\r\nGina mixed with Noah\r\nMary mixed with Quinn\r\nAllie mixed with Kaleb\r\nNoah mixed with Colt\r\nTina mixed with Gina\r\nDaniel mixed with Jacob\r\nDaniel mixed with Noah\r\nColt mixed with Lily\r\nAllie mixed with Daniel\r\nTina mixed with Lily\n\r\nIn the end Allie, Colt, Daniel, Emma, Lily, Mary, Noah, Quinn, and Tina had a sweet cake while Gina, Jacob, and Kaleb didn't. Who started with the bowl with sugar?", "hint": "No hint available.", "answer": "Colt.\r\nIt can't be Gina, Jacob, or Kaleb, they don't have sugar.\r\nIt can't be Emma, Daniel, Mary, Lily, Noah, Allie or Tina, because they mixed with the above.\r\nThis leaves Colt and Quinn, it can't be Quinn because then only Quinn, Emma, and Mary would have sugar.", "category": "Logic", "date": "09/12/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, in baking class, 12 students were baking cakes when the fire alarm went off. Everyone exited the building, but when they got back, they found someone had dumped all the sugar into one of the batter-filled bowls. Everyone was puzzled over what to do until Gina had an idea: why not mix the batters together and then separate the contents back in the bowls. Here is what happened in chronological order:\n\r\nAllie mixed with Tina\r\nEmma mixed with Gina\r\nKaleb mixed with Daniel\r\nColt mixed with Emma\r\nTina mixed with Noah\r\nMary mixed with Gina\r\nQuinn mixed with Emma\r\nJacob mixed with Lily\r\nGina mixed with Noah\r\nMary mixed with Quinn\r\nAllie mixed with Kaleb\r\nNoah mixed with Colt\r\nTina mixed with Gina\r\nDaniel mixed with Jacob\r\nDaniel mixed with Noah\r\nColt mixed with Lily\r\nAllie mixed with Daniel\r\nTina mixed with Lily\n\r\nIn the end Allie, Colt, Daniel, Emma, Lily, Mary, Noah, Quinn, and Tina had a sweet cake while Gina, Jacob, and Kaleb didn't. Who started with the bowl with sugar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nColt.\r\nIt can't be Gina, Jacob, or Kaleb, they don't have sugar.\r\nIt can't be Emma, Daniel, Mary, Lily, Noah, Allie or Tina, because they mixed with the above.\r\nThis leaves Colt and Quinn, it can't be Quinn because then only Quinn, Emma, and Mary would have sugar.\n<|im_start|>answer\nColt.\r\nIt can't be Gina, Jacob, or Kaleb, they don't have sugar.\r\nIt can't be Emma, Daniel, Mary, Lily, Noah, Allie or Tina, because they mixed with the above.\r\nThis leaves Colt and Quinn, it can't be Quinn because then only Quinn, Emma, and Mary would have sugar.\n<|im_end|>" }, { "id": "#28072", "title": "Bunk Beds", "fun": 2.84, "difficulty": 2.03, "author": "lips", "desc": "Six girls, Beth, Haley, Kayla, Liza, Reeva, and Zoe, are in the junior cabin at camp. They sleep in bunk beds. Each girl has a different color blanket on her bed. The beds are lined up in a row with red, black, yellow, brown, blue, and green blankets.\n\r\nClues:\n\r\n1. Reeva and Haley's bed is closest to the door. \r\n2. The color of the blankets on the bottom bunks all begin with the same letter. \r\n3. The color of Beth's blanket does not begin with the same letter as the beginning of her name. \r\n4. Reeva's blanket color does begin with the same letter as her name. \r\n5. The blue blanket is under the red blanket. \r\n6. Liza and Kayla like their lower bunks. \r\n7. Kayla is in the middle bed. \r\n8. Zoe does not share a bunk with Kayla. \r\n9. The brown blanket is at the end of a row. \r\n10. The yellow blanket is above the black blanket. \n\r\nCan you determine the color of each girl's blanket, the order of their beds, and who their bunkmate is?", "hint": "Draw a diagram and make a chart to eliminate the impossibilities.", "answer": "Reeva's blanket is red, Beth's is yellow, Zoe's is green, Haley's is blue, Kayla's is black, and Liza's is brown.\n\r\nBeds from nearest to the door to the farthest: Reeva on the top bunk, Haley on the bottom; Beth on the top bunk, Kayla on the bottom; Zoe on the top bunk, Liza on the bottom.", "category": "Logic", "date": "01/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix girls, Beth, Haley, Kayla, Liza, Reeva, and Zoe, are in the junior cabin at camp. They sleep in bunk beds. Each girl has a different color blanket on her bed. The beds are lined up in a row with red, black, yellow, brown, blue, and green blankets.\n\r\nClues:\n\r\n1. Reeva and Haley's bed is closest to the door. \r\n2. The color of the blankets on the bottom bunks all begin with the same letter. \r\n3. The color of Beth's blanket does not begin with the same letter as the beginning of her name. \r\n4. Reeva's blanket color does begin with the same letter as her name. \r\n5. The blue blanket is under the red blanket. \r\n6. Liza and Kayla like their lower bunks. \r\n7. Kayla is in the middle bed. \r\n8. Zoe does not share a bunk with Kayla. \r\n9. The brown blanket is at the end of a row. \r\n10. The yellow blanket is above the black blanket. \n\r\nCan you determine the color of each girl's blanket, the order of their beds, and who their bunkmate is?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nReeva's blanket is red, Beth's is yellow, Zoe's is green, Haley's is blue, Kayla's is black, and Liza's is brown.\n\r\nBeds from nearest to the door to the farthest: Reeva on the top bunk, Haley on the bottom; Beth on the top bunk, Kayla on the bottom; Zoe on the top bunk, Liza on the bottom.\n<|im_start|>answer\nReeva's blanket is red, Beth's is yellow, Zoe's is green, Haley's is blue, Kayla's is black, and Liza's is brown.\n\r\nBeds from nearest to the door to the farthest: Reeva on the top bunk, Haley on the bottom; Beth on the top bunk, Kayla on the bottom; Zoe on the top bunk, Liza on the bottom.\n<|im_end|>" }, { "id": "#44304", "title": "Murder at Clue Mansion", "fun": 2.84, "difficulty": 1.24, "author": "whsprec", "desc": "One rainy evening, Mr. Body killed 5 people at Clue Mansion. The people killed were Mrs. White, Mr. Green, Professor Plum, Colonel Mustard, and Ms. Scarlet. The murders took place in the kitchen, billiards room, conservatory, hall, and library. No two people were murdered with the same weapon. The weapons were candlestick, rope, revolver, knife, and lead pipe. From the clues given, try to determine the room in which each person was killed and the weapon used.\n\r\n1. The murder with the lead pipe was not done in the hall or the library. \r\n2. Mr. Green was not murdered in the kitchen.\r\n3. The rope was not the murder weapon used in the library.\r\n4. Neither Mrs. White nor Ms. Scarlet were murdered with the candlestick, the revolver, or the lead pipe.\r\n5. The person who was murdered in the billiards room had just finished having dinner with Ms. Scarlet, Mr. Green, the person done in with the candlestick, and the victim of the rope.\r\n6. Neither Mr. Green nor Professor Plum were killed with the lead pipe, in the hall, or in the library.", "hint": "No hint available.", "answer": "Mrs. White in the hall with the rope\r\nMr. Green in the conservatory with the revolver\r\nProfessor Plum in the kitchen with the candlestick\r\nColonel Mustard in the billiards room with the lead pipe\r\nMs. Scarlet in the library with the knife", "category": "Logic-Grid", "date": "03/30/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne rainy evening, Mr. Body killed 5 people at Clue Mansion. The people killed were Mrs. White, Mr. Green, Professor Plum, Colonel Mustard, and Ms. Scarlet. The murders took place in the kitchen, billiards room, conservatory, hall, and library. No two people were murdered with the same weapon. The weapons were candlestick, rope, revolver, knife, and lead pipe. From the clues given, try to determine the room in which each person was killed and the weapon used.\n\r\n1. The murder with the lead pipe was not done in the hall or the library. \r\n2. Mr. Green was not murdered in the kitchen.\r\n3. The rope was not the murder weapon used in the library.\r\n4. Neither Mrs. White nor Ms. Scarlet were murdered with the candlestick, the revolver, or the lead pipe.\r\n5. The person who was murdered in the billiards room had just finished having dinner with Ms. Scarlet, Mr. Green, the person done in with the candlestick, and the victim of the rope.\r\n6. Neither Mr. Green nor Professor Plum were killed with the lead pipe, in the hall, or in the library.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMrs. White in the hall with the rope\r\nMr. Green in the conservatory with the revolver\r\nProfessor Plum in the kitchen with the candlestick\r\nColonel Mustard in the billiards room with the lead pipe\r\nMs. Scarlet in the library with the knife\n<|im_start|>answer\nMrs. White in the hall with the rope\r\nMr. Green in the conservatory with the revolver\r\nProfessor Plum in the kitchen with the candlestick\r\nColonel Mustard in the billiards room with the lead pipe\r\nMs. Scarlet in the library with the knife\n<|im_end|>" }, { "id": "#50853", "title": "Mimi's Mathematical Moment", "fun": 2.84, "difficulty": 1.37, "author": "dalfamnest", "desc": "Fresh and invigorated after completing her algebra homework, Mimi appeared at the living room door. She held a piece of paper covered in scribbled numbers, 'm's, 'd's, and equations.\n\r\n\"Dad!\" she announced. \"Five years from now you'll be only double my age!\"\n\r\n\"Amazing!\" Dad almost looked up from the TV, but knew she hadn't finished.\n\r\n\"But five years ago, you were triple my age then!\"\n\r\n\"I suppose in another ten years we'll be the same age,\" Dad grunted, changing channels.\n\r\nHow old is Mimi?", "hint": "Don't pay any attention to Dad's rather mindless comment at the end! He'd had a tough day.", "answer": "Mimi is 15 (and Dad is 35).\n\r\nThis one is probably easiest to guess and check. There are lots of little clues that help narrow down the options to guess. You might like to write some of these in the comments section.\n\r\ne.g. Dad's age must have been a multiple of 6 five years ago. His age was triple Mimi's and ten years later it would be a multiple of two. So it was a multiple of both 3 and 2.\n\r\nOr you could use algebra:\r\nLet m and d represent Mimi's and Dad's ages now.\r\n1. d-5 = 3x(m-5)\r\n2. d+5 = 2x(m+5)\n\r\nd-5 = 3m-15 ... *1*\r\nd+5 = 2m+10 ... *2*\n\r\n-10 = m-25 ... subtracting *2* from *1*\n\r\nSo m=15", "category": "Math", "date": "07/01/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFresh and invigorated after completing her algebra homework, Mimi appeared at the living room door. She held a piece of paper covered in scribbled numbers, 'm's, 'd's, and equations.\n\r\n\"Dad!\" she announced. \"Five years from now you'll be only double my age!\"\n\r\n\"Amazing!\" Dad almost looked up from the TV, but knew she hadn't finished.\n\r\n\"But five years ago, you were triple my age then!\"\n\r\n\"I suppose in another ten years we'll be the same age,\" Dad grunted, changing channels.\n\r\nHow old is Mimi?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMimi is 15 (and Dad is 35).\n\r\nThis one is probably easiest to guess and check. There are lots of little clues that help narrow down the options to guess. You might like to write some of these in the comments section.\n\r\ne.g. Dad's age must have been a multiple of 6 five years ago. His age was triple Mimi's and ten years later it would be a multiple of two. So it was a multiple of both 3 and 2.\n\r\nOr you could use algebra:\r\nLet m and d represent Mimi's and Dad's ages now.\r\n1. d-5 = 3x(m-5)\r\n2. d+5 = 2x(m+5)\n\r\nd-5 = 3m-15 ... *1*\r\nd+5 = 2m+10 ... *2*\n\r\n-10 = m-25 ... subtracting *2* from *1*\n\r\nSo m=15\n<|im_start|>answer\nMimi is 15 (and Dad is 35).\n\r\nThis one is probably easiest to guess and check. There are lots of little clues that help narrow down the options to guess. You might like to write some of these in the comments section.\n\r\ne.g. Dad's age must have been a multiple of 6 five years ago. His age was triple Mimi's and ten years later it would be a multiple of two. So it was a multiple of both 3 and 2.\n\r\nOr you could use algebra:\r\nLet m and d represent Mimi's and Dad's ages now.\r\n1. d-5 = 3x(m-5)\r\n2. d+5 = 2x(m+5)\n\r\nd-5 = 3m-15 ... *1*\r\nd+5 = 2m+10 ... *2*\n\r\n-10 = m-25 ... subtracting *2* from *1*\n\r\nSo m=15\n<|im_end|>" }, { "id": "#274", "title": "Haircuts", "fun": 2.84, "difficulty": 1.06, "author": "Phyllis", "desc": "You are visiting a new town and need a haircut. There are only two barbers in town. You visit each shop. One is disorganized and messy and the barber has a horrible haircut. The other one is neat and tidy and the barber has a wonderful haircut. Which barber would you choose and why?", "hint": "No hint available.", "answer": "Go to the barber with the disorganized shop. He probably gave the neat barber his beautiful haircut!", "category": "Logic", "date": "02/13/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are visiting a new town and need a haircut. There are only two barbers in town. You visit each shop. One is disorganized and messy and the barber has a horrible haircut. The other one is neat and tidy and the barber has a wonderful haircut. Which barber would you choose and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGo to the barber with the disorganized shop. He probably gave the neat barber his beautiful haircut!\n<|im_start|>answer\nGo to the barber with the disorganized shop. He probably gave the neat barber his beautiful haircut!\n<|im_end|>" }, { "id": "#25002", "title": "Show Me the Mommy!", "fun": 2.84, "difficulty": 2.5100000000000002, "author": "norcekri", "desc": "Biggie Nuff, Baron of Grey Matter, now living in Shapeless, Mass., was dying from a newly developed allergy to water, and wanted his will to reflect the common inheritance law of his father's native country. Biggie's wife, Faerie, was pregnant at the time with what would be the first child for either of them. Biggie's new will stated that if his child were a boy, the son would get 2/3 of his estate, and his widow would get 1/3. If the child were a girl, the widow would get 2/3 of the estate, and the daughter would get 1/3.\n\r\nIn due time, Biggie died, and the authorities read his will, holding dispensation of the estate until the child was born. Five months after Biggie's death, Faerie delivered ... normal, healthy twins, a boy (whom she named Manny) and a girl (whom she named Goodie).\n\r\nThe estate's executor immediately appealed to the Shapeless magistrate to rule on the proper division for the estate. After a great deal of arguing and deep thought, plus several failed attempts to raise Biggie's spirit with a seance, the judge rendered a fair decision.\n\r\nHow did they divide Biggie's estate?", "hint": "No hint available.", "answer": "The judge reasoned that Biggie intended to give his wife half as much as a son, or twice as much as a daughter. Therefore, he ruled that Manny gets 4/7 of the estate, Faerie gets 2/7, and Goodie gets 1/7.\n\r\n(This is supposedly a real decision in Massachusetts, according to the Reader's Digest puzzle book in which I first read this, copyright 1967. Obviously, I've changed the names).", "category": "Logic", "date": "08/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBiggie Nuff, Baron of Grey Matter, now living in Shapeless, Mass., was dying from a newly developed allergy to water, and wanted his will to reflect the common inheritance law of his father's native country. Biggie's wife, Faerie, was pregnant at the time with what would be the first child for either of them. Biggie's new will stated that if his child were a boy, the son would get 2/3 of his estate, and his widow would get 1/3. If the child were a girl, the widow would get 2/3 of the estate, and the daughter would get 1/3.\n\r\nIn due time, Biggie died, and the authorities read his will, holding dispensation of the estate until the child was born. Five months after Biggie's death, Faerie delivered ... normal, healthy twins, a boy (whom she named Manny) and a girl (whom she named Goodie).\n\r\nThe estate's executor immediately appealed to the Shapeless magistrate to rule on the proper division for the estate. After a great deal of arguing and deep thought, plus several failed attempts to raise Biggie's spirit with a seance, the judge rendered a fair decision.\n\r\nHow did they divide Biggie's estate?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe judge reasoned that Biggie intended to give his wife half as much as a son, or twice as much as a daughter. Therefore, he ruled that Manny gets 4/7 of the estate, Faerie gets 2/7, and Goodie gets 1/7.\n\r\n(This is supposedly a real decision in Massachusetts, according to the Reader's Digest puzzle book in which I first read this, copyright 1967. Obviously, I've changed the names).\n<|im_start|>answer\nThe judge reasoned that Biggie intended to give his wife half as much as a son, or twice as much as a daughter. Therefore, he ruled that Manny gets 4/7 of the estate, Faerie gets 2/7, and Goodie gets 1/7.\n\r\n(This is supposedly a real decision in Massachusetts, according to the Reader's Digest puzzle book in which I first read this, copyright 1967. Obviously, I've changed the names).\n<|im_end|>" }, { "id": "#22869", "title": "Family Weddings", "fun": 2.84, "difficulty": 1.27, "author": "Tammy93", "desc": "Last June, five brothers married five sisters on the same day, in the same church, five different ceremonies. The five brothers are Ben, Colin, Chase, Griffin, and Matt. The five sisters (and brides) are Tammy, Jennie, Ayesha, Maddie, and Amber. From the clues given, try to determine the composition of each couple and the order in which the ceremonies were performed.\n\r\n1. Chase was married after Amber and Ayesha but before Ben and Griffin.\r\n2. Tammy was not Chase's bride.\r\n3. The first and last couples to be married featured Amber, Maddie, Colin, and Griffin.", "hint": "No hint available.", "answer": "Ben-Tammy-Fourth\r\nColin-Amber-First\r\nChase-Jennie-Third\r\nGriffin-Maddie-Fifth\r\nMatt-Ayesha-Second", "category": "Logic-Grid", "date": "05/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast June, five brothers married five sisters on the same day, in the same church, five different ceremonies. The five brothers are Ben, Colin, Chase, Griffin, and Matt. The five sisters (and brides) are Tammy, Jennie, Ayesha, Maddie, and Amber. From the clues given, try to determine the composition of each couple and the order in which the ceremonies were performed.\n\r\n1. Chase was married after Amber and Ayesha but before Ben and Griffin.\r\n2. Tammy was not Chase's bride.\r\n3. The first and last couples to be married featured Amber, Maddie, Colin, and Griffin.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBen-Tammy-Fourth\r\nColin-Amber-First\r\nChase-Jennie-Third\r\nGriffin-Maddie-Fifth\r\nMatt-Ayesha-Second\n<|im_start|>answer\nBen-Tammy-Fourth\r\nColin-Amber-First\r\nChase-Jennie-Third\r\nGriffin-Maddie-Fifth\r\nMatt-Ayesha-Second\n<|im_end|>" }, { "id": "#31176", "title": "Accountants and Lawyers", "fun": 2.84, "difficulty": 1.36, "author": "maxvu", "desc": "You are attending a business meeting which consists of only accountants and lawyers. From your previous dealings with these two professions, you know that accountants always tell the truth about everything, and lawyers always lie about something.\n\r\nTwo gentlemen, Sam and Adam, approach you. Sam introduces himself and says, \"I am a lawyer, but Adam is an accountant.\"\n\r\nBased on what you know from your previous dealings, what are each of the men's actual professions?", "hint": "No hint available.", "answer": "Both Sam and Adam are lawyers. \n\r\nSince an accountant ALWAYS tells the truth about everything, he would never say that he is a lawyer. Therefore, Sam must be a lawyer. Since he is telling the truth about being a lawyer, and you know that he always lies about something, he must be lying about the second part of his statement. Therefore, Adam is not an accountant but also a lawyer.", "category": "Logic", "date": "06/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are attending a business meeting which consists of only accountants and lawyers. From your previous dealings with these two professions, you know that accountants always tell the truth about everything, and lawyers always lie about something.\n\r\nTwo gentlemen, Sam and Adam, approach you. Sam introduces himself and says, \"I am a lawyer, but Adam is an accountant.\"\n\r\nBased on what you know from your previous dealings, what are each of the men's actual professions?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoth Sam and Adam are lawyers. \n\r\nSince an accountant ALWAYS tells the truth about everything, he would never say that he is a lawyer. Therefore, Sam must be a lawyer. Since he is telling the truth about being a lawyer, and you know that he always lies about something, he must be lying about the second part of his statement. Therefore, Adam is not an accountant but also a lawyer.\n<|im_start|>answer\nBoth Sam and Adam are lawyers. \n\r\nSince an accountant ALWAYS tells the truth about everything, he would never say that he is a lawyer. Therefore, Sam must be a lawyer. Since he is telling the truth about being a lawyer, and you know that he always lies about something, he must be lying about the second part of his statement. Therefore, Adam is not an accountant but also a lawyer.\n<|im_end|>" }, { "id": "#45042", "title": "Trail Ride", "fun": 2.84, "difficulty": 2.81, "author": "mrsfessler", "desc": "5 friends, ages 12, 15, 17, 18 and 19, went on a trail ride. Each was matched to a horse that suited their size, experience and personality. From the clues provided, determine each friend's first and last name, (two last names were Carey and Williams) their age, the name of the horse they rode, and what position they rode on the trail. Robin, Drew, and Phil are boys; Barbara and Bonnie are girls.\n\r\n1. The 5 friends were Robin, Mr. Hunt, the 15 year old, Shamwow's rider and the boy who was first in the line. \n\r\n2. Bedazzler's rider was younger than Miss McGraw, who was younger than Drew. \n\r\n3. The horses were represented by: Phil, Steamboy, Mr. Walters, Barbara and the one that was 3rd in line. \n\r\n4. The 5th rider was 2 years younger than Topsy Turvy's rider. On Robin's next birthday, he will be the same age as the girl who rode 2nd. \n\r\n5. Carey, Bonnie and the 12 year old loved the ride! Gazelle's rider and the 4th rider did not!", "hint": "No hint available.", "answer": "Bonnie McGraw, 15 , Steamboy, 5th \r\nRobin Walters, 17, Topsy Turvy, 4th \r\nPhil Williams, 12, Bedazzler, 1st \r\nDrew Hunt, 19, Gazelle, 3rd \r\nBarbara Carey, 18, Shamwow, 2nd", "category": "Logic-Grid", "date": "08/10/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 friends, ages 12, 15, 17, 18 and 19, went on a trail ride. Each was matched to a horse that suited their size, experience and personality. From the clues provided, determine each friend's first and last name, (two last names were Carey and Williams) their age, the name of the horse they rode, and what position they rode on the trail. Robin, Drew, and Phil are boys; Barbara and Bonnie are girls.\n\r\n1. The 5 friends were Robin, Mr. Hunt, the 15 year old, Shamwow's rider and the boy who was first in the line. \n\r\n2. Bedazzler's rider was younger than Miss McGraw, who was younger than Drew. \n\r\n3. The horses were represented by: Phil, Steamboy, Mr. Walters, Barbara and the one that was 3rd in line. \n\r\n4. The 5th rider was 2 years younger than Topsy Turvy's rider. On Robin's next birthday, he will be the same age as the girl who rode 2nd. \n\r\n5. Carey, Bonnie and the 12 year old loved the ride! Gazelle's rider and the 4th rider did not!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBonnie McGraw, 15 , Steamboy, 5th \r\nRobin Walters, 17, Topsy Turvy, 4th \r\nPhil Williams, 12, Bedazzler, 1st \r\nDrew Hunt, 19, Gazelle, 3rd \r\nBarbara Carey, 18, Shamwow, 2nd\n<|im_start|>answer\nBonnie McGraw, 15 , Steamboy, 5th \r\nRobin Walters, 17, Topsy Turvy, 4th \r\nPhil Williams, 12, Bedazzler, 1st \r\nDrew Hunt, 19, Gazelle, 3rd \r\nBarbara Carey, 18, Shamwow, 2nd\n<|im_end|>" }, { "id": "#22727", "title": "Beethoven's Room Part II", "fun": 2.84, "difficulty": 2.18, "author": "beethovenswig", "desc": "Beethoven has been kidnapped AGAIN!!! He is being kept in one of six rooms and his wig is being kept in another. Above each room is a letter. The letters are: Q, V, W, Z, K, and X. Use the clues below to match each letter with its door, find the room where Beethoven is being kept, and find the room where his wig is.\n\r\n1. The letter K is above the second room.\r\n2. Beethoven's Wig is not in the fifth room.\r\n3. The letter X is either above room three or room six.\r\n4. The letter X and the letter V are to the left of Beethoven's Wig.\r\n5. The letter K is to the left of Beethoven.\r\n6. Beethoven is to the left of the room with the letter Q above it.\r\n7. The letter Z is NOT above one of the first three rooms, the letter Z is to the right of the letter W.\r\n8. The letter Q is above the wig.\r\n9. The letter V is either the first or the last.\r\n10. Beethoven is NOT right beside the wig, he is also NOT in the room with the letter W.", "hint": "No hint available.", "answer": "Beethoven is in the third room.\r\nBeethoven's Wig is in the sixth room.\r\nV is above the first room, K above the second, X above the third, W above the fourth, Z above the fifth, and Q above the sixth.", "category": "Logic", "date": "05/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBeethoven has been kidnapped AGAIN!!! He is being kept in one of six rooms and his wig is being kept in another. Above each room is a letter. The letters are: Q, V, W, Z, K, and X. Use the clues below to match each letter with its door, find the room where Beethoven is being kept, and find the room where his wig is.\n\r\n1. The letter K is above the second room.\r\n2. Beethoven's Wig is not in the fifth room.\r\n3. The letter X is either above room three or room six.\r\n4. The letter X and the letter V are to the left of Beethoven's Wig.\r\n5. The letter K is to the left of Beethoven.\r\n6. Beethoven is to the left of the room with the letter Q above it.\r\n7. The letter Z is NOT above one of the first three rooms, the letter Z is to the right of the letter W.\r\n8. The letter Q is above the wig.\r\n9. The letter V is either the first or the last.\r\n10. Beethoven is NOT right beside the wig, he is also NOT in the room with the letter W.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeethoven is in the third room.\r\nBeethoven's Wig is in the sixth room.\r\nV is above the first room, K above the second, X above the third, W above the fourth, Z above the fifth, and Q above the sixth.\n<|im_start|>answer\nBeethoven is in the third room.\r\nBeethoven's Wig is in the sixth room.\r\nV is above the first room, K above the second, X above the third, W above the fourth, Z above the fifth, and Q above the sixth.\n<|im_end|>" }, { "id": "#46555", "title": "Roommates Flops", "fun": 2.84, "difficulty": 2.59, "author": "whsprec", "desc": "Five college roommates all had dreams of becoming actresses. As luck would have it, all five at one point were given the opportunity to play the lead role in a movie. However, all five movies flopped and the ladies were never given another chance to act. From the clues below determine the first and last name of each actress, the title of the film, and what year it was released.\n\r\n1) Jessica's 3-hour film, Kung Fu Mother, wasn't the last one to be released.\r\n2) The roommate who starred in the 2001 Queen of the Jattos, about a tribe of cannibal pygmies, married a man whose surname has the same number of letters as her first name.\r\n3) Mrs. McMahonn's film, which she paid for but wasn't named Evil Cat, was released four years after Blaklee's film. \r\n4) Mrs. Greener's film went straight to video in 1993; 10,000 copies were made and 9971 are still available for sale.\r\n5) Neither Steffi nor Mrs. Taylor acted in 2005.\r\n6) Jasmine's film was released in 1997; eight theaters never sold a single seat to it.\r\n7) Mrs. Spruil starred in the 6-hour religious epic Early Councils.", "hint": "No hint available.", "answer": "Jasmine Taylor starred in the 1997 film Evil Cat\r\nBlaklee Spruil started in the 2005 film Early Councils\r\nJessica Greener starred in the 1993 film Kung Fu Mother\r\nBetty McMahonn starred in the 2009 film 3.14 days\r\nSteffi Jenson starred in the 2001 film Queen of the Jattos", "category": "Logic-Grid", "date": "03/17/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive college roommates all had dreams of becoming actresses. As luck would have it, all five at one point were given the opportunity to play the lead role in a movie. However, all five movies flopped and the ladies were never given another chance to act. From the clues below determine the first and last name of each actress, the title of the film, and what year it was released.\n\r\n1) Jessica's 3-hour film, Kung Fu Mother, wasn't the last one to be released.\r\n2) The roommate who starred in the 2001 Queen of the Jattos, about a tribe of cannibal pygmies, married a man whose surname has the same number of letters as her first name.\r\n3) Mrs. McMahonn's film, which she paid for but wasn't named Evil Cat, was released four years after Blaklee's film. \r\n4) Mrs. Greener's film went straight to video in 1993; 10,000 copies were made and 9971 are still available for sale.\r\n5) Neither Steffi nor Mrs. Taylor acted in 2005.\r\n6) Jasmine's film was released in 1997; eight theaters never sold a single seat to it.\r\n7) Mrs. Spruil starred in the 6-hour religious epic Early Councils.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJasmine Taylor starred in the 1997 film Evil Cat\r\nBlaklee Spruil started in the 2005 film Early Councils\r\nJessica Greener starred in the 1993 film Kung Fu Mother\r\nBetty McMahonn starred in the 2009 film 3.14 days\r\nSteffi Jenson starred in the 2001 film Queen of the Jattos\n<|im_start|>answer\nJasmine Taylor starred in the 1997 film Evil Cat\r\nBlaklee Spruil started in the 2005 film Early Councils\r\nJessica Greener starred in the 1993 film Kung Fu Mother\r\nBetty McMahonn starred in the 2009 film 3.14 days\r\nSteffi Jenson starred in the 2001 film Queen of the Jattos\n<|im_end|>" }, { "id": "#23566", "title": "The Antique Lamp?", "fun": 2.84, "difficulty": 1.3, "author": "vikingboy", "desc": "The Jones family of Ohio is entertaining their cousin Henry, who is visiting from Belgium.\n\r\nAfter staying for several days, Henry is getting ready to leave, when he presents the Jones with a gift.\r\nIt is a lamp that Henry claims is a very valuable antique that has been in his family for 70 years. It has small Bohemian figures that dance around the base when the lamp is turned on. Henry plugs it in to show the family how it works.\n\r\nAfter Henry leaves, the father looks at his family, and says, \"While it may be a pretty lamp, and it was nice of Henry to give it to us, it is not a Belgian antique.\"\n\r\nWhy is the father so sure?", "hint": "Go with the flow....current that is.", "answer": "An antique lamp from Belgium would not have a plug that would fit into a standard outlet in North America. The father noted that the plug was a sealed plug not a replacement one and therefore was the original installation.\n\r\nHe obviously bought it at a local store.", "category": "Logic", "date": "06/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Jones family of Ohio is entertaining their cousin Henry, who is visiting from Belgium.\n\r\nAfter staying for several days, Henry is getting ready to leave, when he presents the Jones with a gift.\r\nIt is a lamp that Henry claims is a very valuable antique that has been in his family for 70 years. It has small Bohemian figures that dance around the base when the lamp is turned on. Henry plugs it in to show the family how it works.\n\r\nAfter Henry leaves, the father looks at his family, and says, \"While it may be a pretty lamp, and it was nice of Henry to give it to us, it is not a Belgian antique.\"\n\r\nWhy is the father so sure?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAn antique lamp from Belgium would not have a plug that would fit into a standard outlet in North America. The father noted that the plug was a sealed plug not a replacement one and therefore was the original installation.\n\r\nHe obviously bought it at a local store.\n<|im_start|>answer\nAn antique lamp from Belgium would not have a plug that would fit into a standard outlet in North America. The father noted that the plug was a sealed plug not a replacement one and therefore was the original installation.\n\r\nHe obviously bought it at a local store.\n<|im_end|>" }, { "id": "#35847", "title": "Sweeps Mania", "fun": 2.83, "difficulty": 2.72, "author": "goatroper605", "desc": "Mr. Slickdeals, from sEprize Inc, is a sweepstakes sponsor and he has noticed over the years that there's one particular group of 15 who are very diligent about entering his sweepstakes. So, he decides to hold a sweepstakes just for these 15 people, divided into groups of three, who will split various sums of money. This sweepstakes should be entered daily over the course of seven months. However, the prize won is not dependent upon the number of entries for each team. At the end of the seven months, Mr. Slickdeals, using his special computer program, has entered all of the information needed to determine the winners & will be making the announcement the following Monday. On that Monday morning, he turns on his computer & realizes that it has crashed sometime over the weekend & he never made a backup of the sweepstakes information! Can you determine, from his notes, who's on what team, how many entries they submitted, & who won which prize?\n\r\n1. VoidinHi (VIH), who wasn't on a team with RMGM, didn't win $10,000. Happy2Win (H2W) wasn't on a team with Shamoo. St. Patty's (SP) team entered 391 times.\n\r\n2. JavaFlower (JF) and her teammate, CrazeyPoet (CP), didn't win $5,000. The team who won $25,000 had two more entries than RedFuzzyCow's (RFC) team.\n\r\n3. The team that RMGM & Shamoo were on didn't win $10,000. MK1234, who wasn't on the same team as WTrash (WT), didn't win $5,000.\n\r\n4. The team that won $5,000 entered the contest 393 times. DealsRUs' (DRU) team entered 388 times, but they didn't win $2,500. DimDig (DD), who wasn't on a team with Happy2Win (H2W), submitted two more entries than the team that won $1,000.\n\r\n5. The five teams, in no particular order, were Eilsenrenrag (EILS), WTrash (WT), the team that won $10,000, JavaFlower (JF), and the team that had 389 submissions.\n\r\n6. FreebiesRGreat (FRG) had one more submission than the team that won $2,500 but one less than the team that WTrash (WT) & Implode (IMP) were on.", "hint": "Remember that the team with the most entries does not necessarily win the most money!\n\r\nVoidinHi = VIH\r\nRMGM = RMGM\r\nHappy2Win = H2W\r\nSt. Patty = SP\r\nShamoo = Shamoo\r\nJavaFlower = JF\r\nCrazeyPoet = CP\r\nRedFuzzyCow = RFC\r\nWTrash = WT\r\nMK1234 = MK1234\r\nDealsRUs = DRU\r\nDimDig = DD\r\nEilsenrenrag = EILS\r\nFreebiesRGreat = FRG\r\nImplode = IMP", "answer": "VIH, DD, EILS 393 $5,000\r\nSP, WT, IMP 391 $1,000\r\nJF, CP, FRG 390 $25,000\r\nMK1234, RMGM, SHAMOO 389 $2,500\r\nH2W, RFC, DRU 388 $10,000", "category": "Logic-Grid", "date": "03/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Slickdeals, from sEprize Inc, is a sweepstakes sponsor and he has noticed over the years that there's one particular group of 15 who are very diligent about entering his sweepstakes. So, he decides to hold a sweepstakes just for these 15 people, divided into groups of three, who will split various sums of money. This sweepstakes should be entered daily over the course of seven months. However, the prize won is not dependent upon the number of entries for each team. At the end of the seven months, Mr. Slickdeals, using his special computer program, has entered all of the information needed to determine the winners & will be making the announcement the following Monday. On that Monday morning, he turns on his computer & realizes that it has crashed sometime over the weekend & he never made a backup of the sweepstakes information! Can you determine, from his notes, who's on what team, how many entries they submitted, & who won which prize?\n\r\n1. VoidinHi (VIH), who wasn't on a team with RMGM, didn't win $10,000. Happy2Win (H2W) wasn't on a team with Shamoo. St. Patty's (SP) team entered 391 times.\n\r\n2. JavaFlower (JF) and her teammate, CrazeyPoet (CP), didn't win $5,000. The team who won $25,000 had two more entries than RedFuzzyCow's (RFC) team.\n\r\n3. The team that RMGM & Shamoo were on didn't win $10,000. MK1234, who wasn't on the same team as WTrash (WT), didn't win $5,000.\n\r\n4. The team that won $5,000 entered the contest 393 times. DealsRUs' (DRU) team entered 388 times, but they didn't win $2,500. DimDig (DD), who wasn't on a team with Happy2Win (H2W), submitted two more entries than the team that won $1,000.\n\r\n5. The five teams, in no particular order, were Eilsenrenrag (EILS), WTrash (WT), the team that won $10,000, JavaFlower (JF), and the team that had 389 submissions.\n\r\n6. FreebiesRGreat (FRG) had one more submission than the team that won $2,500 but one less than the team that WTrash (WT) & Implode (IMP) were on.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nVIH, DD, EILS 393 $5,000\r\nSP, WT, IMP 391 $1,000\r\nJF, CP, FRG 390 $25,000\r\nMK1234, RMGM, SHAMOO 389 $2,500\r\nH2W, RFC, DRU 388 $10,000\n<|im_start|>answer\nVIH, DD, EILS 393 $5,000\r\nSP, WT, IMP 391 $1,000\r\nJF, CP, FRG 390 $25,000\r\nMK1234, RMGM, SHAMOO 389 $2,500\r\nH2W, RFC, DRU 388 $10,000\n<|im_end|>" }, { "id": "#41386", "title": "Book Reports", "fun": 2.83, "difficulty": 1.8, "author": "lilliandulcia", "desc": "Ms. Liandas assigned each of her students a book report on their favorite book over spring break and told them to email it to her. However, due to a glitch in the system, she lost the emails as well as the grades of 5 of her students. Help her remember each student's last name, the book they did their report on, and the grade they got on the report.\n\r\nStudents: Linda, Maria, Cindy, Justin, and Alex\r\nLast names: Kooper, Amana, Oriz, McMan, and O'Brian\r\nBooks: Tithe, Twilight, Harry Potter, The Great Gatsby, and Vampire Kisses\r\nGrades: 98%, 85%, 81%, 70%, and 68%\n\r\nClues:\n\r\n1. The 5 students were Cindy, the one who read Twilight, the one who got a 70%, Ms. Kooper, and the one who read The Great Gatsby.\n\r\n2. The gender of both boys is contained in their last name.\n\r\n3. Ms. Liandas remembered that two of the girls had a strange vampire fixation, always coming to school with fake fangs glued to their teeth.\n\r\n4. Neither of the boys did very well on their reports.\n\r\n5. Ms. O'Brian was always the top of her class.\n\r\n6. Linda Oriz did better than Maria but worse than Cindy.\n\r\n7. Ms. Liandas remembered that Alex dressed up as the wizard from his favorite book for costume day.\n\r\n8. Justin was always more interested in classical literature than the other students, which was shown in his book report.\n\r\n9. Mr. Amana always teased Cindy about her fairy obsession, to which she retaliated, \"Why don't you go kiss Mr. Gatsby?!\"", "hint": "Twilight and Vampire Kisses are about vampires.\r\nTithe is about fairies.\r\nHarry Potter is about wizards.\r\nThe Great Gatsby is a \"classical book\".", "answer": "Linda Oriz read Twilight and got an 85%\r\nMaria Kooper read Vampire Kisses and got an 81%\r\nCindy O'Brian read Tithe and got a 98%\r\nJustin Amana read The Great Gatsby and got a 68%\r\nAlex McMan read Harry Potter and got a 70%", "category": "Logic-Grid", "date": "04/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Liandas assigned each of her students a book report on their favorite book over spring break and told them to email it to her. However, due to a glitch in the system, she lost the emails as well as the grades of 5 of her students. Help her remember each student's last name, the book they did their report on, and the grade they got on the report.\n\r\nStudents: Linda, Maria, Cindy, Justin, and Alex\r\nLast names: Kooper, Amana, Oriz, McMan, and O'Brian\r\nBooks: Tithe, Twilight, Harry Potter, The Great Gatsby, and Vampire Kisses\r\nGrades: 98%, 85%, 81%, 70%, and 68%\n\r\nClues:\n\r\n1. The 5 students were Cindy, the one who read Twilight, the one who got a 70%, Ms. Kooper, and the one who read The Great Gatsby.\n\r\n2. The gender of both boys is contained in their last name.\n\r\n3. Ms. Liandas remembered that two of the girls had a strange vampire fixation, always coming to school with fake fangs glued to their teeth.\n\r\n4. Neither of the boys did very well on their reports.\n\r\n5. Ms. O'Brian was always the top of her class.\n\r\n6. Linda Oriz did better than Maria but worse than Cindy.\n\r\n7. Ms. Liandas remembered that Alex dressed up as the wizard from his favorite book for costume day.\n\r\n8. Justin was always more interested in classical literature than the other students, which was shown in his book report.\n\r\n9. Mr. Amana always teased Cindy about her fairy obsession, to which she retaliated, \"Why don't you go kiss Mr. Gatsby?!\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLinda Oriz read Twilight and got an 85%\r\nMaria Kooper read Vampire Kisses and got an 81%\r\nCindy O'Brian read Tithe and got a 98%\r\nJustin Amana read The Great Gatsby and got a 68%\r\nAlex McMan read Harry Potter and got a 70%\n<|im_start|>answer\nLinda Oriz read Twilight and got an 85%\r\nMaria Kooper read Vampire Kisses and got an 81%\r\nCindy O'Brian read Tithe and got a 98%\r\nJustin Amana read The Great Gatsby and got a 68%\r\nAlex McMan read Harry Potter and got a 70%\n<|im_end|>" }, { "id": "#23720", "title": "Fortune Teller", "fun": 2.83, "difficulty": 1.25, "author": "tjm531", "desc": "While at a carnival, five friends, Beth, Michelle, Whitney, Greg and Karl had their fortunes told by Geneeva the Seer. Each person gave Geneeva his or her astrological sign and she gazed into her crystal ball. She then predicted a different momentous event for each. From the information provided, determine each friend's sign and the event Geneeva had predicted:\n\r\nFriends: Beth, Greg, Karl, Michelle, Whitney\r\nSigns: Aquarius, Cancer, Leo, Taurus, Virgo\r\nEvents: Love, Money, Promotion, Relative, Trip\n\r\n1. Geneeva revealed to Greg (who is neither the Leo nor the Virgo) that he would soon meet his true love.\n\r\n2. Whitney isn't the woman born under the sign of Cancer (who was told to prepare for a trip to a faraway land).\n\r\n3. The Virgo isn't the one whom Geneeva predicted would inherit a large sum of money.\n\r\n4. Beth was pleased to hear that she would receive an important promotion at work.\n\r\n5. A surprise visit from a long-lost relative was foretold for the Taurus woman.", "hint": "No hint available.", "answer": "Beth, Virgo, promotion\r\nGreg, Aquarius, love\r\nKarl, Leo, money\r\nMichelle, Cancer, trip\r\nWhitney, Taurus, relative", "category": "Logic-Grid", "date": "06/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile at a carnival, five friends, Beth, Michelle, Whitney, Greg and Karl had their fortunes told by Geneeva the Seer. Each person gave Geneeva his or her astrological sign and she gazed into her crystal ball. She then predicted a different momentous event for each. From the information provided, determine each friend's sign and the event Geneeva had predicted:\n\r\nFriends: Beth, Greg, Karl, Michelle, Whitney\r\nSigns: Aquarius, Cancer, Leo, Taurus, Virgo\r\nEvents: Love, Money, Promotion, Relative, Trip\n\r\n1. Geneeva revealed to Greg (who is neither the Leo nor the Virgo) that he would soon meet his true love.\n\r\n2. Whitney isn't the woman born under the sign of Cancer (who was told to prepare for a trip to a faraway land).\n\r\n3. The Virgo isn't the one whom Geneeva predicted would inherit a large sum of money.\n\r\n4. Beth was pleased to hear that she would receive an important promotion at work.\n\r\n5. A surprise visit from a long-lost relative was foretold for the Taurus woman.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeth, Virgo, promotion\r\nGreg, Aquarius, love\r\nKarl, Leo, money\r\nMichelle, Cancer, trip\r\nWhitney, Taurus, relative\n<|im_start|>answer\nBeth, Virgo, promotion\r\nGreg, Aquarius, love\r\nKarl, Leo, money\r\nMichelle, Cancer, trip\r\nWhitney, Taurus, relative\n<|im_end|>" }, { "id": "#19630", "title": "People Profiles", "fun": 2.83, "difficulty": 1.16, "author": "mrguyguy", "desc": "5 men-- Bob, Joe, Riley, Thomas, and Xavier, last names Imith, Jones, O'Donnell, Roader, and Popper, each have different careers--farmer, carpenter, realtor, stock broker, and chemist, and different favorite sports-- tennis, bowling, soccer, volleyball, and basketball. Can you figure out who has what last name, career, and favorite sport?\n\r\nClues:\r\n1. Both Joe's last name and career begin with the same letter.\r\n2. Bob does not like bowling or volleyball.\r\n3. Mr. O'Donnell is a chemist.\r\n4. Xavier plays a sport with a net down the middle of the field.\r\n5. Riley Jones is not a carpenter, but Bob is.\r\n6. Mr. Imith's friend Xavier is a farmer.\r\n7. Riley is a stock broker.\r\n8. The carpenter plays tennis (he built the rackets).\r\n9. Mr. Imith loves tennis, but Riley and Thomas like sports with 2 nets at the goals.\r\n10. The basketball player is a chemist.", "hint": "No hint available.", "answer": "Bob-Imith-Tennis-Carpenter\r\nJoe-Roader-Bowling-Realtor\r\nRiley-Jones-Soccer-Stock Broker\r\nThomas-O'Donnell-Basketball-Chemist\r\nXavier-Popper-Volleyball-Farmer", "category": "Logic-Grid", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 men-- Bob, Joe, Riley, Thomas, and Xavier, last names Imith, Jones, O'Donnell, Roader, and Popper, each have different careers--farmer, carpenter, realtor, stock broker, and chemist, and different favorite sports-- tennis, bowling, soccer, volleyball, and basketball. Can you figure out who has what last name, career, and favorite sport?\n\r\nClues:\r\n1. Both Joe's last name and career begin with the same letter.\r\n2. Bob does not like bowling or volleyball.\r\n3. Mr. O'Donnell is a chemist.\r\n4. Xavier plays a sport with a net down the middle of the field.\r\n5. Riley Jones is not a carpenter, but Bob is.\r\n6. Mr. Imith's friend Xavier is a farmer.\r\n7. Riley is a stock broker.\r\n8. The carpenter plays tennis (he built the rackets).\r\n9. Mr. Imith loves tennis, but Riley and Thomas like sports with 2 nets at the goals.\r\n10. The basketball player is a chemist.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob-Imith-Tennis-Carpenter\r\nJoe-Roader-Bowling-Realtor\r\nRiley-Jones-Soccer-Stock Broker\r\nThomas-O'Donnell-Basketball-Chemist\r\nXavier-Popper-Volleyball-Farmer\n<|im_start|>answer\nBob-Imith-Tennis-Carpenter\r\nJoe-Roader-Bowling-Realtor\r\nRiley-Jones-Soccer-Stock Broker\r\nThomas-O'Donnell-Basketball-Chemist\r\nXavier-Popper-Volleyball-Farmer\n<|im_end|>" }, { "id": "#35440", "title": "Trip to the Paintball Field", "fun": 2.83, "difficulty": 2.04, "author": "Phalanx", "desc": "Four friends went to a Paintball field in order to have a nice day, playing their favorite sport.\n\r\nAll of them were wearing different coloured jerseys and used different paint. Each of them had a favorite obstacle and each one got hit on a different part of the body.\n\r\nUsing the following hints, can you determine the different sets of name, jersey, paint, obstacle and place where each one was hit?\n\r\nNames: Marc, Daniel, Silvia, Nathalie.\r\nJerseys: Yellow, Orange, Pink, Green\r\nPaint: Yellow, Orange, Pink, Green\r\nHits: Arm, Leg, Goggles, Chest\r\nObstacles: Car, Tree, Stack of tyres, House\n\r\n1) Only one player used paint that matched the colour of his/her jersey.\n\r\n2) The guy behind the car was bunkering the player in the yellow jersey with tons of yellow paint.\n\r\n3) Neither of the girls was wearing the pink jersey.\n\r\n4) The player in the yellow jersey did not hide between the tyres and got hit on the chest.\n\r\n5) Marc had to leave the game with a big orange splat on his goggles.\n\r\n6) The player with the orange jersey used neither yellow nor green paint.\n\r\n7) Silvia spotted her victim while sneaking around the house.\n\r\n8) Nathalie was sure her green jersey would make it hard to spot her hiding behind the trees.\n\r\n9) The player using green paint was hiding neither behind the tyres nor the house.\n\r\n10) When Daniel was shot on the arm, he dropped some of his pink paintballs.\n\r\n11) The paint of the player who was hit on the goggles is the same colour as the jersey of the player who splatted him.", "hint": "1) If one is hit and wears a jersey with the colour he was splatted with, than neither he, nor the shooter, use matched paint and jerseys.\n\r\n2) If a player is hit with paint of a certain colour, he isn't playing that same colour himself.", "answer": "Marc: pink jersey, yellow paint, hit on his goggles and hiding behind a car.\n\r\nDaniel: orange jersey, pink paint, hit on the arm and hiding behind the stack of tyres.\n\r\nSilvia: yellow jersey, orange paint, hit on the chest and hiding behind the house.\n\r\nNathalie: green jersey, green paint, hit on the leg and hiding in the trees.", "category": "Logic-Grid", "date": "02/26/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends went to a Paintball field in order to have a nice day, playing their favorite sport.\n\r\nAll of them were wearing different coloured jerseys and used different paint. Each of them had a favorite obstacle and each one got hit on a different part of the body.\n\r\nUsing the following hints, can you determine the different sets of name, jersey, paint, obstacle and place where each one was hit?\n\r\nNames: Marc, Daniel, Silvia, Nathalie.\r\nJerseys: Yellow, Orange, Pink, Green\r\nPaint: Yellow, Orange, Pink, Green\r\nHits: Arm, Leg, Goggles, Chest\r\nObstacles: Car, Tree, Stack of tyres, House\n\r\n1) Only one player used paint that matched the colour of his/her jersey.\n\r\n2) The guy behind the car was bunkering the player in the yellow jersey with tons of yellow paint.\n\r\n3) Neither of the girls was wearing the pink jersey.\n\r\n4) The player in the yellow jersey did not hide between the tyres and got hit on the chest.\n\r\n5) Marc had to leave the game with a big orange splat on his goggles.\n\r\n6) The player with the orange jersey used neither yellow nor green paint.\n\r\n7) Silvia spotted her victim while sneaking around the house.\n\r\n8) Nathalie was sure her green jersey would make it hard to spot her hiding behind the trees.\n\r\n9) The player using green paint was hiding neither behind the tyres nor the house.\n\r\n10) When Daniel was shot on the arm, he dropped some of his pink paintballs.\n\r\n11) The paint of the player who was hit on the goggles is the same colour as the jersey of the player who splatted him.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMarc: pink jersey, yellow paint, hit on his goggles and hiding behind a car.\n\r\nDaniel: orange jersey, pink paint, hit on the arm and hiding behind the stack of tyres.\n\r\nSilvia: yellow jersey, orange paint, hit on the chest and hiding behind the house.\n\r\nNathalie: green jersey, green paint, hit on the leg and hiding in the trees.\n<|im_start|>answer\nMarc: pink jersey, yellow paint, hit on his goggles and hiding behind a car.\n\r\nDaniel: orange jersey, pink paint, hit on the arm and hiding behind the stack of tyres.\n\r\nSilvia: yellow jersey, orange paint, hit on the chest and hiding behind the house.\n\r\nNathalie: green jersey, green paint, hit on the leg and hiding in the trees.\n<|im_end|>" }, { "id": "#34476", "title": "Reincarnation", "fun": 2.83, "difficulty": 1.5, "author": "dishu", "desc": "Slazy-the ignorant journalist was on the verge of being fired for his ignorance and laziness. To forget his blues, he decided to go to a local pub, where he found five friends bragging about how famous they were in their previous birth. Slazy thought that this will make for a sensational story about \"Reincarnation of Famous Personalities\" and will save his job. Being ignorant, he had no clue that the so called famous people were actually fictional characters only. He quickly scribbled the following notes about the first and last names of these five people, the \"personality\" they claimed to be and the reason why they were famous. He now needs your help to sort them out and create the \"Reincarnation\" story.\n\r\n1. Only one person had a rhyming pair of first and last names.\r\n2. Mr. Brown claimed that he was famous for his extra-ordinary moustache.\r\n3. Earnest was a famous businessman.\r\n4. Derek claimed to be reincarnation of Ken.\r\n5. Only one person's first and last name started with the same letter.\r\n6. Anthony claimed that he was very brave in his last life.\r\n7. Harry Richard was not a lawyer.\r\n8. Mr. Robinson claimed that he was Neville Longbottom, while Mr. Dobson claimed that he was very wealthy in his last birth.\r\n9. Poirot was not known for his law skills.\n\r\nFirst Names: Alan, Anthony, Derek, Harry, Jack\r\nLast Names: Black, Brown, Richard, Robinson, Dobson\r\nPrevious Birth Personality: Earnest, Ken, Neville Longbottom, Oliver Twist, Poirot\r\nReason of fame in previous Birth: Law Skills, Business Acumen, Bravery, Wealth, Extra-ordinary Moustache", "hint": "Condensations in the grid:\r\nNeville Longbottom: Nev Longbott\r\nBusiness acumen: Business acu\r\nExtra-ordinary moustache: Moustache", "answer": "\"The Reincarnation of Famous Personalities\"\r\nFive young men are believed to be reincarnation of extremely famous personalities of the past. What's more they even remember who they were in their previous birth. While Mr. Alan Brown is believed to be the reincarnation of famous detective Poirot who was known for his extra-ordinary moustache; Mr. Anthony Robinson was none other than the extremely brave Neville Longbottom in his previous birth. The wealthy Ken has taken rebirth as Mr. Derek Dobson and Earnest, the businessman, has been born again as Mr. Harry Richard. Even famous lawyer Oliver Twist has taken a rebirth and is known as Mr. Jack Black. Incidentally, these five great men are extremely good friends in their present life and can often been spotted at the local pub.\n\r\nOf course, Slazy's boss fired him for writing such an absurd story.", "category": "Logic-Grid", "date": "12/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSlazy-the ignorant journalist was on the verge of being fired for his ignorance and laziness. To forget his blues, he decided to go to a local pub, where he found five friends bragging about how famous they were in their previous birth. Slazy thought that this will make for a sensational story about \"Reincarnation of Famous Personalities\" and will save his job. Being ignorant, he had no clue that the so called famous people were actually fictional characters only. He quickly scribbled the following notes about the first and last names of these five people, the \"personality\" they claimed to be and the reason why they were famous. He now needs your help to sort them out and create the \"Reincarnation\" story.\n\r\n1. Only one person had a rhyming pair of first and last names.\r\n2. Mr. Brown claimed that he was famous for his extra-ordinary moustache.\r\n3. Earnest was a famous businessman.\r\n4. Derek claimed to be reincarnation of Ken.\r\n5. Only one person's first and last name started with the same letter.\r\n6. Anthony claimed that he was very brave in his last life.\r\n7. Harry Richard was not a lawyer.\r\n8. Mr. Robinson claimed that he was Neville Longbottom, while Mr. Dobson claimed that he was very wealthy in his last birth.\r\n9. Poirot was not known for his law skills.\n\r\nFirst Names: Alan, Anthony, Derek, Harry, Jack\r\nLast Names: Black, Brown, Richard, Robinson, Dobson\r\nPrevious Birth Personality: Earnest, Ken, Neville Longbottom, Oliver Twist, Poirot\r\nReason of fame in previous Birth: Law Skills, Business Acumen, Bravery, Wealth, Extra-ordinary Moustache\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"The Reincarnation of Famous Personalities\"\r\nFive young men are believed to be reincarnation of extremely famous personalities of the past. What's more they even remember who they were in their previous birth. While Mr. Alan Brown is believed to be the reincarnation of famous detective Poirot who was known for his extra-ordinary moustache; Mr. Anthony Robinson was none other than the extremely brave Neville Longbottom in his previous birth. The wealthy Ken has taken rebirth as Mr. Derek Dobson and Earnest, the businessman, has been born again as Mr. Harry Richard. Even famous lawyer Oliver Twist has taken a rebirth and is known as Mr. Jack Black. Incidentally, these five great men are extremely good friends in their present life and can often been spotted at the local pub.\n\r\nOf course, Slazy's boss fired him for writing such an absurd story.\n<|im_start|>answer\n\"The Reincarnation of Famous Personalities\"\r\nFive young men are believed to be reincarnation of extremely famous personalities of the past. What's more they even remember who they were in their previous birth. While Mr. Alan Brown is believed to be the reincarnation of famous detective Poirot who was known for his extra-ordinary moustache; Mr. Anthony Robinson was none other than the extremely brave Neville Longbottom in his previous birth. The wealthy Ken has taken rebirth as Mr. Derek Dobson and Earnest, the businessman, has been born again as Mr. Harry Richard. Even famous lawyer Oliver Twist has taken a rebirth and is known as Mr. Jack Black. Incidentally, these five great men are extremely good friends in their present life and can often been spotted at the local pub.\n\r\nOf course, Slazy's boss fired him for writing such an absurd story.\n<|im_end|>" }, { "id": "#26602", "title": "Who was Born First and When?", "fun": 2.83, "difficulty": 1.39, "author": "Rob2003", "desc": "Five sisters all have their birthday in a different month and each on a different day of the week. Using the clues below, determine the month and day of the week each sister's birthday falls.\n\r\n1. Paula was born in March but not on Saturday. Abigail's birthday was not on Friday or Wednesday.\n\r\n2. The girl whose birthday is on Monday was born earlier in the year than Brenda and Mary.\n\r\n3. Tara wasn't born in February and her birthday was on the weekend.\n\r\n4. Mary was not born in December nor was her birthday on a weekday. The girl whose birthday was in June was born on Sunday.\n\r\n5. Tara was born in an earlier month than Brenda, whose birthday wasn't on Friday. Mary wasn't born in July.", "hint": "No hint available.", "answer": "Abigail: February, Monday\r\nBrenda: December, Wednesday\r\nMary: June, Sunday\r\nPaula: March, Friday\r\nTara: July, Saturday", "category": "Logic-Grid", "date": "10/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive sisters all have their birthday in a different month and each on a different day of the week. Using the clues below, determine the month and day of the week each sister's birthday falls.\n\r\n1. Paula was born in March but not on Saturday. Abigail's birthday was not on Friday or Wednesday.\n\r\n2. The girl whose birthday is on Monday was born earlier in the year than Brenda and Mary.\n\r\n3. Tara wasn't born in February and her birthday was on the weekend.\n\r\n4. Mary was not born in December nor was her birthday on a weekday. The girl whose birthday was in June was born on Sunday.\n\r\n5. Tara was born in an earlier month than Brenda, whose birthday wasn't on Friday. Mary wasn't born in July.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbigail: February, Monday\r\nBrenda: December, Wednesday\r\nMary: June, Sunday\r\nPaula: March, Friday\r\nTara: July, Saturday\n<|im_start|>answer\nAbigail: February, Monday\r\nBrenda: December, Wednesday\r\nMary: June, Sunday\r\nPaula: March, Friday\r\nTara: July, Saturday\n<|im_end|>" }, { "id": "#22666", "title": "Seattle to Portland", "fun": 2.83, "difficulty": 1.92, "author": "Palsha", "desc": "Five people drove their cars from Seattle to Portland, a distance of 185 miles. To check the accuracy of their odometers, they each set their mileage indicators to zero in a parking lot at Safeco Field. They each drive a different colored car. Using the clues I'm going to offer, figure out the full names of all the drivers, the colors of the cars they drive, and the reading of their odometers as they cross the I-5 bridge into Portland three hours later.\n\r\n1) Shepard is not Roberta, nor is his car green.\r\n2) The driver of the tan car is not Lester or Danny.\r\n3) The odometer of the white car reads 6.9 miles fewer than the black car.\r\n4) Rudy is neither Fisher nor Delphino.\r\n5) The car driven by Swank is tan and the mileage is 2.2 more than Delphino's black car.\r\n6) Lester's green car has 5.8 more miles than Roberta's red one.\r\n7) Willy's tan car has .8 more miles than Curley's.", "hint": "No hint available.", "answer": "1) Curley Lester drove a green car 187.7 miles.\r\n2) Roberta Fisher drove a red car 181.9 miles.\r\n3) Danny Delphino drove a black car 186.3 miles.\r\n4) Rudy Shepard drove a white car 179.4 miles.\r\n5) Willy Swank drove a tan car 188.5 miles.", "category": "Logic-Grid", "date": "05/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people drove their cars from Seattle to Portland, a distance of 185 miles. To check the accuracy of their odometers, they each set their mileage indicators to zero in a parking lot at Safeco Field. They each drive a different colored car. Using the clues I'm going to offer, figure out the full names of all the drivers, the colors of the cars they drive, and the reading of their odometers as they cross the I-5 bridge into Portland three hours later.\n\r\n1) Shepard is not Roberta, nor is his car green.\r\n2) The driver of the tan car is not Lester or Danny.\r\n3) The odometer of the white car reads 6.9 miles fewer than the black car.\r\n4) Rudy is neither Fisher nor Delphino.\r\n5) The car driven by Swank is tan and the mileage is 2.2 more than Delphino's black car.\r\n6) Lester's green car has 5.8 more miles than Roberta's red one.\r\n7) Willy's tan car has .8 more miles than Curley's.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Curley Lester drove a green car 187.7 miles.\r\n2) Roberta Fisher drove a red car 181.9 miles.\r\n3) Danny Delphino drove a black car 186.3 miles.\r\n4) Rudy Shepard drove a white car 179.4 miles.\r\n5) Willy Swank drove a tan car 188.5 miles.\n<|im_start|>answer\n1) Curley Lester drove a green car 187.7 miles.\r\n2) Roberta Fisher drove a red car 181.9 miles.\r\n3) Danny Delphino drove a black car 186.3 miles.\r\n4) Rudy Shepard drove a white car 179.4 miles.\r\n5) Willy Swank drove a tan car 188.5 miles.\n<|im_end|>" }, { "id": "#38450", "title": "Five Coloured Shirts", "fun": 2.83, "difficulty": 2.45, "author": "shenqiang", "desc": "Every day from Monday through Sunday in this week, Mr. Peter picks two shirts from the five colours red, blue, yellow, green and black. Peter follows the rules:\r\n1. Peter doesn't use the same combination on two days of this week.\r\n2. Peter doesn't use the same colour on two consecutive days of this week.\r\n3. Peter uses some colour on four days.\r\n4. Peter uses blue and black on Monday.\r\n5. Peter uses green on Thursday.\r\n6. Peter doesn't use yellow on Friday.\r\n7. Peter doesn't combine red with black.\n\r\nWhat colours does Peter use on Saturday?", "hint": "No hint available.", "answer": "From rules 2 and 3, Peter must use one colour on Monday, Wednesday, Friday and Sunday, which can be blue or black.\r\nIf it's black, from rules 1 and 4, Peter must combine black with red, yellow and green on Wednesday, Friday and Sunday, but rule 7 disallows combining black with red.\n\r\nTherefore, it's blue, and Peter must combine blue with red, yellow and green on Wednesday, Friday and Sunday. From rule 5, Peter uses green on Thursday, he can't use green on Wednesday or Friday, and only on Sunday.\n\r\nFrom rule 6, Peter doesn't use yellow on Friday, and he can only use red on Friday and yellow on Wednesday.\n\r\nSince Peter uses blue, red and green on Friday and Sunday, from rule 2, he can only use black and yellow on Saturday.", "category": "Logic", "date": "09/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery day from Monday through Sunday in this week, Mr. Peter picks two shirts from the five colours red, blue, yellow, green and black. Peter follows the rules:\r\n1. Peter doesn't use the same combination on two days of this week.\r\n2. Peter doesn't use the same colour on two consecutive days of this week.\r\n3. Peter uses some colour on four days.\r\n4. Peter uses blue and black on Monday.\r\n5. Peter uses green on Thursday.\r\n6. Peter doesn't use yellow on Friday.\r\n7. Peter doesn't combine red with black.\n\r\nWhat colours does Peter use on Saturday?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom rules 2 and 3, Peter must use one colour on Monday, Wednesday, Friday and Sunday, which can be blue or black.\r\nIf it's black, from rules 1 and 4, Peter must combine black with red, yellow and green on Wednesday, Friday and Sunday, but rule 7 disallows combining black with red.\n\r\nTherefore, it's blue, and Peter must combine blue with red, yellow and green on Wednesday, Friday and Sunday. From rule 5, Peter uses green on Thursday, he can't use green on Wednesday or Friday, and only on Sunday.\n\r\nFrom rule 6, Peter doesn't use yellow on Friday, and he can only use red on Friday and yellow on Wednesday.\n\r\nSince Peter uses blue, red and green on Friday and Sunday, from rule 2, he can only use black and yellow on Saturday.\n<|im_start|>answer\nFrom rules 2 and 3, Peter must use one colour on Monday, Wednesday, Friday and Sunday, which can be blue or black.\r\nIf it's black, from rules 1 and 4, Peter must combine black with red, yellow and green on Wednesday, Friday and Sunday, but rule 7 disallows combining black with red.\n\r\nTherefore, it's blue, and Peter must combine blue with red, yellow and green on Wednesday, Friday and Sunday. From rule 5, Peter uses green on Thursday, he can't use green on Wednesday or Friday, and only on Sunday.\n\r\nFrom rule 6, Peter doesn't use yellow on Friday, and he can only use red on Friday and yellow on Wednesday.\n\r\nSince Peter uses blue, red and green on Friday and Sunday, from rule 2, he can only use black and yellow on Saturday.\n<|im_end|>" }, { "id": "#23884", "title": "So When's Your Birthday?", "fun": 2.83, "difficulty": 1.17, "author": "flipflopchica", "desc": "Try to find out who was born what year and in what month using the following clues. The names are Summer, Jenae, Bill, Adam, and George. The years are 1910, 1920, 1942, 1952, and 1955. The months are January, April, July, August, and October. \n\r\nSummer was born before Jenae who was born after Bill.\n\r\nAdam and George, in no particular order, were born October 1952, and July 1910.\n\r\nNo one was born the month that shared the same first letter as their name's first letter.\n\r\nA girl was born in a month that is also a girl's name.\n\r\nWhoever was born in 1955 was born in August.\n\r\nJenae and Adam are the youngest and oldest, but not necessarily in that order, but possibly could be...\n\r\nBill was not born in a warm month (i.e. spring and summer months are considered warm in this case.) He was born in 1942.", "hint": "No hint available.", "answer": "Summer born April 1920\r\nJenae born August 1955\r\nBill born January 1942\r\nAdam born July 1910\r\nGeorge born October 1952", "category": "Logic-Grid", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTry to find out who was born what year and in what month using the following clues. The names are Summer, Jenae, Bill, Adam, and George. The years are 1910, 1920, 1942, 1952, and 1955. The months are January, April, July, August, and October. \n\r\nSummer was born before Jenae who was born after Bill.\n\r\nAdam and George, in no particular order, were born October 1952, and July 1910.\n\r\nNo one was born the month that shared the same first letter as their name's first letter.\n\r\nA girl was born in a month that is also a girl's name.\n\r\nWhoever was born in 1955 was born in August.\n\r\nJenae and Adam are the youngest and oldest, but not necessarily in that order, but possibly could be...\n\r\nBill was not born in a warm month (i.e. spring and summer months are considered warm in this case.) He was born in 1942.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSummer born April 1920\r\nJenae born August 1955\r\nBill born January 1942\r\nAdam born July 1910\r\nGeorge born October 1952\n<|im_start|>answer\nSummer born April 1920\r\nJenae born August 1955\r\nBill born January 1942\r\nAdam born July 1910\r\nGeorge born October 1952\n<|im_end|>" }, { "id": "#24395", "title": "Trilogy Part 2: Ranch Dressing", "fun": 2.83, "difficulty": 1.53, "author": "cinnamon30", "desc": "You will need the answers from Trilogy Part 1 to solve this logic grid.\n\r\nAlthough a hard day's labor on the ranch can get a fella dirty, the five cowboys always try to look their best before heading into town. To that end, each man is wearing a clean shirt (no two of which are the same fabric - one is corduroy) and a pair of designer cowboy boots (no two of which are the same brand - one is a pair of Oil Barron boots). After all, the clothes make a man. From the info provided, can you determine the type of shirt and the brand of cowboy boots worn by each rancher?\n\r\nBoots - Coyote, Oil Baron, Sunset, Texas Toe and Westhome\r\nShirts - Calico, Corduroy, Denim, Flannel and Gingham\r\nMen - Carl Lovelace, Hank Brooks, Pablo Sanchez, Rusty Ewing and Zeke McCool\n\r\n1. The man wearing Sunset boots (who isn't Mr. Ewing) isn't the cowboy in position A (who isn't wearing a flannel shirt).\n\r\n2. Rusty (who is wearing a calico shirt) isn't the one wearing Texas toe boots.\n\r\n3. Mr. Lovelace isn't the rancher wearing both a denim shirt and Westhome boots (who isn't Zeke).\n\r\n4. The man in position E (who is wearing Coyote boots) isn't the one wearing a gingham shirt (who isn't Zeke).\n\n\r\nNote: You will need the answers from Trilogy Part 1 and Trilogy Part 2 to do Trilogy Part 3 logic grid. So don't throw away your answers.", "hint": "No hint available.", "answer": "Carl Lovelace - Gingham shirt and Sunset Boots\r\nHank Brooks - Flannel shirt and Coyote boots \r\nPablo Sanchez - Denim shirt and Westhome boots\r\nRusty Ewing - Calico shirt and Oil Baron boots\r\nZeke McCool - Corduroy shirt and Texas Toe boots\n\r\nThe numbers in () refers to the clue number.\n\r\nThe man wearing denim and Westhome boots (3) isn't Rusty [calico (2)], isn't Hank {in position E from part 1 trilogy [coyote boots (4)]}, isn't Carl Lovelace (3) or isn't Zeke (3), therefore it is Pablo Sanchez. The gingham shirt isn't Rusty [calico (2)], Zeke (4), or Hank [position E (4)], therefore its Carl Lovelace. Flannel isn't Zeke [who is in position A (1)] or Rusty [calico (2)], therefore its Hank Brooks. This leaves corduroy for Zeke because Rusty is wearing calico (2). Sunset boots isn't Zeke [who is in position A] (1), Rusty Ewing (1), Pablo Sanchez who is Westhome boots (see above), or Hank [position E is wearing coyote boots (4)]. Therefore it is Carl Lovelace. Texas Toe boots isn't Rusty (2) or Hank [in position E wearing Coyote (4)]. Therefore it's Zeke McCool wearing the Texas Toe boots. Hank Brooks is wearing the coyote boots who is in position E (4). This leaves Rusty Ewing wearing the Oil Baron boots.", "category": "Logic-Grid", "date": "07/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou will need the answers from Trilogy Part 1 to solve this logic grid.\n\r\nAlthough a hard day's labor on the ranch can get a fella dirty, the five cowboys always try to look their best before heading into town. To that end, each man is wearing a clean shirt (no two of which are the same fabric - one is corduroy) and a pair of designer cowboy boots (no two of which are the same brand - one is a pair of Oil Barron boots). After all, the clothes make a man. From the info provided, can you determine the type of shirt and the brand of cowboy boots worn by each rancher?\n\r\nBoots - Coyote, Oil Baron, Sunset, Texas Toe and Westhome\r\nShirts - Calico, Corduroy, Denim, Flannel and Gingham\r\nMen - Carl Lovelace, Hank Brooks, Pablo Sanchez, Rusty Ewing and Zeke McCool\n\r\n1. The man wearing Sunset boots (who isn't Mr. Ewing) isn't the cowboy in position A (who isn't wearing a flannel shirt).\n\r\n2. Rusty (who is wearing a calico shirt) isn't the one wearing Texas toe boots.\n\r\n3. Mr. Lovelace isn't the rancher wearing both a denim shirt and Westhome boots (who isn't Zeke).\n\r\n4. The man in position E (who is wearing Coyote boots) isn't the one wearing a gingham shirt (who isn't Zeke).\n\n\r\nNote: You will need the answers from Trilogy Part 1 and Trilogy Part 2 to do Trilogy Part 3 logic grid. So don't throw away your answers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarl Lovelace - Gingham shirt and Sunset Boots\r\nHank Brooks - Flannel shirt and Coyote boots \r\nPablo Sanchez - Denim shirt and Westhome boots\r\nRusty Ewing - Calico shirt and Oil Baron boots\r\nZeke McCool - Corduroy shirt and Texas Toe boots\n\r\nThe numbers in () refers to the clue number.\n\r\nThe man wearing denim and Westhome boots (3) isn't Rusty [calico (2)], isn't Hank {in position E from part 1 trilogy [coyote boots (4)]}, isn't Carl Lovelace (3) or isn't Zeke (3), therefore it is Pablo Sanchez. The gingham shirt isn't Rusty [calico (2)], Zeke (4), or Hank [position E (4)], therefore its Carl Lovelace. Flannel isn't Zeke [who is in position A (1)] or Rusty [calico (2)], therefore its Hank Brooks. This leaves corduroy for Zeke because Rusty is wearing calico (2). Sunset boots isn't Zeke [who is in position A] (1), Rusty Ewing (1), Pablo Sanchez who is Westhome boots (see above), or Hank [position E is wearing coyote boots (4)]. Therefore it is Carl Lovelace. Texas Toe boots isn't Rusty (2) or Hank [in position E wearing Coyote (4)]. Therefore it's Zeke McCool wearing the Texas Toe boots. Hank Brooks is wearing the coyote boots who is in position E (4). This leaves Rusty Ewing wearing the Oil Baron boots.\n<|im_start|>answer\nCarl Lovelace - Gingham shirt and Sunset Boots\r\nHank Brooks - Flannel shirt and Coyote boots \r\nPablo Sanchez - Denim shirt and Westhome boots\r\nRusty Ewing - Calico shirt and Oil Baron boots\r\nZeke McCool - Corduroy shirt and Texas Toe boots\n\r\nThe numbers in () refers to the clue number.\n\r\nThe man wearing denim and Westhome boots (3) isn't Rusty [calico (2)], isn't Hank {in position E from part 1 trilogy [coyote boots (4)]}, isn't Carl Lovelace (3) or isn't Zeke (3), therefore it is Pablo Sanchez. The gingham shirt isn't Rusty [calico (2)], Zeke (4), or Hank [position E (4)], therefore its Carl Lovelace. Flannel isn't Zeke [who is in position A (1)] or Rusty [calico (2)], therefore its Hank Brooks. This leaves corduroy for Zeke because Rusty is wearing calico (2). Sunset boots isn't Zeke [who is in position A] (1), Rusty Ewing (1), Pablo Sanchez who is Westhome boots (see above), or Hank [position E is wearing coyote boots (4)]. Therefore it is Carl Lovelace. Texas Toe boots isn't Rusty (2) or Hank [in position E wearing Coyote (4)]. Therefore it's Zeke McCool wearing the Texas Toe boots. Hank Brooks is wearing the coyote boots who is in position E (4). This leaves Rusty Ewing wearing the Oil Baron boots.\n<|im_end|>" }, { "id": "#36165", "title": "Bringing Home the Groceries", "fun": 2.83, "difficulty": 1.83, "author": "chaskey", "desc": "On a beautiful sunny day, five pairs of grocery shoppers headed to their various favorite grocery stores. Who went with whom, how far they travelled, how they got there, and how much they brought home are all revealed in the clues below.\n\r\nSHOPPERS:\r\nMen: d'Otcom, Kurfew, Markt, Allso, Palster\r\nWomen: Glazzie, Verbit, Shoeling, Honlette, Bling\n\r\nDISTANCEs (one way): 1/2 mile, 1 mile, 1-1/2 miles, 2 miles, 3 miles\n\r\nTRANSPORTS: private car, taxi, bus, bicycle, walk\n\r\nBAGS OF GROCERIES: 2, 3, 4, 6, 7\n\r\nCLUES:\r\n 1. d'Otcom and his brother rode their bicycles 1-1/2 miles together to the grocery store. They each carried back 2 bags in their luggage racks.\n\r\n 2. Honlette went twice as far to the store as Glazzie and Palster, but only half as far as Verbit.\n\r\n 3. Allso's round trip was the same distance as Markt's one-way trip.\n\r\n 4. Verbit and her grandmother took a taxi. Together they brought 3 bags home.\n\r\n 5. Shoeling really enjoyed her new car, because she could easily bring home 7 bags of groceries.\n\r\n 6. Honlette enjoyed walking with her husband the mile to the store. On the way back, they each carried one bag of groceries.", "hint": "No hint available.", "answer": "d'Otcom/Allso--1-1/2 miles--bicycles--4 bags\r\nGlazzie/Palster--1/2 mile--bus--6 bags\r\nVerbit/Bling--2 miles--taxi--3 bags\r\nShoeling/Markt--3 miles--car--7 bags\r\nKurfew/Honlette--1 mile--walk--2 bags", "category": "Logic-Grid", "date": "04/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a beautiful sunny day, five pairs of grocery shoppers headed to their various favorite grocery stores. Who went with whom, how far they travelled, how they got there, and how much they brought home are all revealed in the clues below.\n\r\nSHOPPERS:\r\nMen: d'Otcom, Kurfew, Markt, Allso, Palster\r\nWomen: Glazzie, Verbit, Shoeling, Honlette, Bling\n\r\nDISTANCEs (one way): 1/2 mile, 1 mile, 1-1/2 miles, 2 miles, 3 miles\n\r\nTRANSPORTS: private car, taxi, bus, bicycle, walk\n\r\nBAGS OF GROCERIES: 2, 3, 4, 6, 7\n\r\nCLUES:\r\n 1. d'Otcom and his brother rode their bicycles 1-1/2 miles together to the grocery store. They each carried back 2 bags in their luggage racks.\n\r\n 2. Honlette went twice as far to the store as Glazzie and Palster, but only half as far as Verbit.\n\r\n 3. Allso's round trip was the same distance as Markt's one-way trip.\n\r\n 4. Verbit and her grandmother took a taxi. Together they brought 3 bags home.\n\r\n 5. Shoeling really enjoyed her new car, because she could easily bring home 7 bags of groceries.\n\r\n 6. Honlette enjoyed walking with her husband the mile to the store. On the way back, they each carried one bag of groceries.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nd'Otcom/Allso--1-1/2 miles--bicycles--4 bags\r\nGlazzie/Palster--1/2 mile--bus--6 bags\r\nVerbit/Bling--2 miles--taxi--3 bags\r\nShoeling/Markt--3 miles--car--7 bags\r\nKurfew/Honlette--1 mile--walk--2 bags\n<|im_start|>answer\nd'Otcom/Allso--1-1/2 miles--bicycles--4 bags\r\nGlazzie/Palster--1/2 mile--bus--6 bags\r\nVerbit/Bling--2 miles--taxi--3 bags\r\nShoeling/Markt--3 miles--car--7 bags\r\nKurfew/Honlette--1 mile--walk--2 bags\n<|im_end|>" }, { "id": "#24490", "title": "Stolen Root Beer", "fun": 2.83, "difficulty": 2.12, "author": "phrebh", "desc": "Fred, who owns a restaurant, is convinced that one of his employees is stealing root beer from him. Since he is a bad businessman, he doesn't keep very good records of his inventory or his employees, so he doesn't know who is doing it. He decides to set a trap to find out who is stealing from him. \n\r\nHe assigns each of his employees a different night to close up shop. He then arranges the last 28 bottles of root beer in a square so that each side has nine bottles, as shown below:\n\r\n2 5 2\r\n5 0 5\r\n2 5 2\n\r\nFred figures that whatever day he comes in where there are no longer nine bottles to a side, he will know it was the person who closed the night before who is doing it.\n\r\nUnfortunately for Fred, Bob, the thief, figures it out and manages to take four more bottles the night of his shift, rearranging the bottles so that Fred doesn't realize they're missing. Not only that, but Bob was able to take four more bottles away the next night he closed while still rearranging them to have nine bottles on each side.\n\r\nHow did Bob do it?", "hint": "No hint available.", "answer": "After Bob takes the first four bottles, he arranges the remaining 24 bottles like this:\n\r\n3 3 3\r\n3 0 3\r\n3 3 3\n\r\nWhen he takes the next four and only leaves 20 bottles, he arranges them like this:\n\r\n4 1 4\r\n1 0 1\r\n4 1 4", "category": "Logic", "date": "07/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred, who owns a restaurant, is convinced that one of his employees is stealing root beer from him. Since he is a bad businessman, he doesn't keep very good records of his inventory or his employees, so he doesn't know who is doing it. He decides to set a trap to find out who is stealing from him. \n\r\nHe assigns each of his employees a different night to close up shop. He then arranges the last 28 bottles of root beer in a square so that each side has nine bottles, as shown below:\n\r\n2 5 2\r\n5 0 5\r\n2 5 2\n\r\nFred figures that whatever day he comes in where there are no longer nine bottles to a side, he will know it was the person who closed the night before who is doing it.\n\r\nUnfortunately for Fred, Bob, the thief, figures it out and manages to take four more bottles the night of his shift, rearranging the bottles so that Fred doesn't realize they're missing. Not only that, but Bob was able to take four more bottles away the next night he closed while still rearranging them to have nine bottles on each side.\n\r\nHow did Bob do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter Bob takes the first four bottles, he arranges the remaining 24 bottles like this:\n\r\n3 3 3\r\n3 0 3\r\n3 3 3\n\r\nWhen he takes the next four and only leaves 20 bottles, he arranges them like this:\n\r\n4 1 4\r\n1 0 1\r\n4 1 4\n<|im_start|>answer\nAfter Bob takes the first four bottles, he arranges the remaining 24 bottles like this:\n\r\n3 3 3\r\n3 0 3\r\n3 3 3\n\r\nWhen he takes the next four and only leaves 20 bottles, he arranges them like this:\n\r\n4 1 4\r\n1 0 1\r\n4 1 4\n<|im_end|>" }, { "id": "#21336", "title": "The Protection Racket", "fun": 2.83, "difficulty": 1.17, "author": "blablabla", "desc": "The gang of four that once ran the biggest protection racket in the east eventually got out of jail. Almost immediately, they began operating again in the same neighborhood. They had previously divided it into four territories: north, south, east, and west. Because each mobster had always kept his operations in the same area, the police nicknamed them Mr. North, Mr. South, Mr. East, and Mr. West.\n\r\nNow the police received a reliable tip that this time each mobster was operating in a new territory. None of the new victims was willing to identify the mobsters from photos the police showed them, but three facts became clear, and that was enough for the FBI to work out which mobster was operating where. These are the facts:\n\r\n1. Mr. East is not operating the North.\r\n2. The North territory is not being operated by Mr. South.\r\n3. The South territory is not being operated by Mr. East.\n\r\nCan you tell who is operating in each territory?", "hint": "No hint available.", "answer": "Mr. North is operating the South, Mr. East is operating the West, Mr. South is operating the East, and Mr. West is operating the North.", "category": "Logic", "date": "03/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe gang of four that once ran the biggest protection racket in the east eventually got out of jail. Almost immediately, they began operating again in the same neighborhood. They had previously divided it into four territories: north, south, east, and west. Because each mobster had always kept his operations in the same area, the police nicknamed them Mr. North, Mr. South, Mr. East, and Mr. West.\n\r\nNow the police received a reliable tip that this time each mobster was operating in a new territory. None of the new victims was willing to identify the mobsters from photos the police showed them, but three facts became clear, and that was enough for the FBI to work out which mobster was operating where. These are the facts:\n\r\n1. Mr. East is not operating the North.\r\n2. The North territory is not being operated by Mr. South.\r\n3. The South territory is not being operated by Mr. East.\n\r\nCan you tell who is operating in each territory?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. North is operating the South, Mr. East is operating the West, Mr. South is operating the East, and Mr. West is operating the North.\n<|im_start|>answer\nMr. North is operating the South, Mr. East is operating the West, Mr. South is operating the East, and Mr. West is operating the North.\n<|im_end|>" }, { "id": "#19637", "title": "Family Portraits", "fun": 2.82, "difficulty": 2.15, "author": "something", "desc": "The Something Family are getting their portraits done again. They decided to spice things up a little bit by getting their portraits done in different styles. Unfortunately, the portraits had to be painted by different painters, all charging different prices. Your job is to find out who got painted by what painter, what style the painter paints in, and how much each cost. \n\r\nSomething Family \n\r\nSomething \r\nSomeone \r\nEverything \r\nEveryone \r\nSteve \n\r\nPainters \n\r\nPutreef Fromage \r\nFrude Sporka \r\nShildkrote Strauss \r\nCamisa Picante \r\nDiscobre Cheiro \n\r\nStyles \n\r\nImpressionism \r\nRomanticism \r\nCubism \r\nPointillism \r\nRealism \n\r\nPrice (dollars) \n\r\n113.99 \r\n4.12 \r\n562 \r\n234.78 \r\n157.01 \n\n\r\n1. Something wasn't painted by Picante. \r\n2. Cheiro paints in Romanticism. \r\n3. Steve's portrait was more pricey than Everyone's. \r\n4. Fromage painted for 113.99. \r\n5. Someone was painted in Romanticism. \r\n6. Something and Someone have the biggest separation in price. \r\n7. Everything wasn't painted in Realism. \r\n8. Picante painted for more than Fromage. \r\n9. Someone was painted by Cheiro. \r\n10. Romanticism costs more than Realism. \r\n11. Strauss paints Impressionism. \r\n12. Everyone was more costly to paint than Something. \r\n13. Realism costs the least. \r\n14. Everything's painter and style start with the same letter. \r\n15. The cheapest person to paint's name starts with the same letter as his painter. \r\n16. Pointillism is more expensive than Steve's chosen style.", "hint": "No hint available.", "answer": "Something - Sporka - Realism - 4.12\r\nSomeone - Cheiro - Romanticism - 562\r\nEverything - Picante - Pointillism - 234.78\r\nEveryone - Fromage - Cubism - 113.99\r\nSteve - Strauss - Impressionism - 157.01", "category": "Logic-Grid", "date": "11/30/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Something Family are getting their portraits done again. They decided to spice things up a little bit by getting their portraits done in different styles. Unfortunately, the portraits had to be painted by different painters, all charging different prices. Your job is to find out who got painted by what painter, what style the painter paints in, and how much each cost. \n\r\nSomething Family \n\r\nSomething \r\nSomeone \r\nEverything \r\nEveryone \r\nSteve \n\r\nPainters \n\r\nPutreef Fromage \r\nFrude Sporka \r\nShildkrote Strauss \r\nCamisa Picante \r\nDiscobre Cheiro \n\r\nStyles \n\r\nImpressionism \r\nRomanticism \r\nCubism \r\nPointillism \r\nRealism \n\r\nPrice (dollars) \n\r\n113.99 \r\n4.12 \r\n562 \r\n234.78 \r\n157.01 \n\n\r\n1. Something wasn't painted by Picante. \r\n2. Cheiro paints in Romanticism. \r\n3. Steve's portrait was more pricey than Everyone's. \r\n4. Fromage painted for 113.99. \r\n5. Someone was painted in Romanticism. \r\n6. Something and Someone have the biggest separation in price. \r\n7. Everything wasn't painted in Realism. \r\n8. Picante painted for more than Fromage. \r\n9. Someone was painted by Cheiro. \r\n10. Romanticism costs more than Realism. \r\n11. Strauss paints Impressionism. \r\n12. Everyone was more costly to paint than Something. \r\n13. Realism costs the least. \r\n14. Everything's painter and style start with the same letter. \r\n15. The cheapest person to paint's name starts with the same letter as his painter. \r\n16. Pointillism is more expensive than Steve's chosen style.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSomething - Sporka - Realism - 4.12\r\nSomeone - Cheiro - Romanticism - 562\r\nEverything - Picante - Pointillism - 234.78\r\nEveryone - Fromage - Cubism - 113.99\r\nSteve - Strauss - Impressionism - 157.01\n<|im_start|>answer\nSomething - Sporka - Realism - 4.12\r\nSomeone - Cheiro - Romanticism - 562\r\nEverything - Picante - Pointillism - 234.78\r\nEveryone - Fromage - Cubism - 113.99\r\nSteve - Strauss - Impressionism - 157.01\n<|im_end|>" }, { "id": "#36915", "title": "School Bus Scramble 2", "fun": 2.82, "difficulty": 2.24, "author": "Smeraldina", "desc": "Whew! Miss Appleday has been teaching first grade for a month, and is starting to get the hang of things. She's been doing such a good job with bus dismissal that the principal, Mr. Office, has asked her to help out with the after-school clubs and activities.\n\r\nThe school day is done, and five first graders are starting new activities today. Can you help Miss Appleday keep her attendance roster organized? She needs to know each student's first and last name, each student's chosen activity, and how each student is getting home today. She also needs to remember who goes to the school's aftercare program instead of going home after the activities are done. \n\r\nFirst names: Chloe, David, Iris, Joe, Nikolas\r\nLast Names: Beresford, Hastings, Plum, Watson\r\nActivities: Brownies meeting, Drama Club, Hands on Science, Piano Class, Spanish Club\r\nGetting Home: Aftercare, Blue Bus, Brown Bus, Minivan, Walking\n\r\n1. The twins usually both ride the bus home, but David's mom picked him up from his activity twenty minutes early to drive him to his dentist appointment. David's sister took the bus as usual.\n\r\n2. The child studying Spanish practiced his vocabulary afterwards on the Blue Bus.\n\r\n3. Niko Plum is shy and does not take Drama; Miss Beresford is in Hands On Science.\n\r\n4. Mr. Watson is completely tone deaf. Happily, he has no interest in music whatsoever.\n\r\n5. Iris H. walked to her grandmother's house after her activity.\n\r\n6. The student taking piano played a very good five-note scale at the end of class.", "hint": "In the U.S., Brownie Girl Scouts, or \"Brownies\", are Girl Scouts who are ages 6-8. They are called \"Brownies\" because their uniforms are brown rather than the green or blue worn by the older girls.", "answer": "Answer:\tChloe Beresford took the Brown Bus home after Hands on Science.\r\nDavid Beresford, Chloe's twin brother, left Drama twenty minutes early; his mom picked him up in her minivan and drove him to a dentist appointment.\r\nIris Hastings walked to her grandmother's house after her Brownies meeting.\r\nJoe Watson took the Blue Bus home after Spanish.\r\nNikolas (Niko) Plum went to aftercare after piano class.", "category": "Logic-Grid", "date": "06/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhew! Miss Appleday has been teaching first grade for a month, and is starting to get the hang of things. She's been doing such a good job with bus dismissal that the principal, Mr. Office, has asked her to help out with the after-school clubs and activities.\n\r\nThe school day is done, and five first graders are starting new activities today. Can you help Miss Appleday keep her attendance roster organized? She needs to know each student's first and last name, each student's chosen activity, and how each student is getting home today. She also needs to remember who goes to the school's aftercare program instead of going home after the activities are done. \n\r\nFirst names: Chloe, David, Iris, Joe, Nikolas\r\nLast Names: Beresford, Hastings, Plum, Watson\r\nActivities: Brownies meeting, Drama Club, Hands on Science, Piano Class, Spanish Club\r\nGetting Home: Aftercare, Blue Bus, Brown Bus, Minivan, Walking\n\r\n1. The twins usually both ride the bus home, but David's mom picked him up from his activity twenty minutes early to drive him to his dentist appointment. David's sister took the bus as usual.\n\r\n2. The child studying Spanish practiced his vocabulary afterwards on the Blue Bus.\n\r\n3. Niko Plum is shy and does not take Drama; Miss Beresford is in Hands On Science.\n\r\n4. Mr. Watson is completely tone deaf. Happily, he has no interest in music whatsoever.\n\r\n5. Iris H. walked to her grandmother's house after her activity.\n\r\n6. The student taking piano played a very good five-note scale at the end of class.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer:\tChloe Beresford took the Brown Bus home after Hands on Science.\r\nDavid Beresford, Chloe's twin brother, left Drama twenty minutes early; his mom picked him up in her minivan and drove him to a dentist appointment.\r\nIris Hastings walked to her grandmother's house after her Brownies meeting.\r\nJoe Watson took the Blue Bus home after Spanish.\r\nNikolas (Niko) Plum went to aftercare after piano class.\n<|im_start|>answer\nAnswer:\tChloe Beresford took the Brown Bus home after Hands on Science.\r\nDavid Beresford, Chloe's twin brother, left Drama twenty minutes early; his mom picked him up in her minivan and drove him to a dentist appointment.\r\nIris Hastings walked to her grandmother's house after her Brownies meeting.\r\nJoe Watson took the Blue Bus home after Spanish.\r\nNikolas (Niko) Plum went to aftercare after piano class.\n<|im_end|>" }, { "id": "#49391", "title": "Puzzling Prattle", "fun": 2.82, "difficulty": 2.52, "author": "D_Dragon", "desc": "Two children, who were all tangled up in their reckoning of the days of the week, paused on their way to school to straighten matters out. \"When the day after tomorrow is yesterday,\" said Priscilla, \"then 'today' will be as far from Sunday as that day was which was 'today' when the day before yesterday was tomorrow!\"\r\nOn which day of the week did this puzzling prattle occur?", "hint": "No hint available.", "answer": "The two children were so befogged over the calendar that they had started on their way to school on Sunday morning!", "category": "Logic", "date": "03/23/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo children, who were all tangled up in their reckoning of the days of the week, paused on their way to school to straighten matters out. \"When the day after tomorrow is yesterday,\" said Priscilla, \"then 'today' will be as far from Sunday as that day was which was 'today' when the day before yesterday was tomorrow!\"\r\nOn which day of the week did this puzzling prattle occur?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two children were so befogged over the calendar that they had started on their way to school on Sunday morning!\n<|im_start|>answer\nThe two children were so befogged over the calendar that they had started on their way to school on Sunday morning!\n<|im_end|>" }, { "id": "#27225", "title": "Tower of Terror", "fun": 2.82, "difficulty": 2.18, "author": "bigSWAFF_69_", "desc": "Swaff was traveling in an elevator, being cool, when he suddenly heard the cord supporting the elevator snap. Being the cool guy that he is, he knew of a myth where if you could jump at the right time, you could possibly be able to survive a plunge in an elevator. \n\r\nNow, when Swaff was a boy, he spent all of his math classes making fun of his female teacher's moustache. He never paid attention, so he was a tad bit slow in his mathematical calculations. He did, however, have a very bizarre talent, in which he could tell the exact speed he was traveling. That came in pretty lucky today.\n\r\nSwaff knew he was falling at an even rate of 50 miles per hour. When the cord snapped, he was exactly 110 feet above the ground. He knew that he must jump at the right time to have any hopes of surviving. \n\r\nNow, after doing the math, please tell me when Swaff jumped.", "hint": "No hint available.", "answer": "He never did. By the time Swaff figured out that he would have to jump in 1.5 seconds, he would already be dead. Not even the best of mathematicians could do all the math needed in 1 and a half seconds. Swaff fell to his death, only to later be reincarnated by his magical brother Geemiee.\n\r\nYay for Geemiee.", "category": "Logic", "date": "11/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSwaff was traveling in an elevator, being cool, when he suddenly heard the cord supporting the elevator snap. Being the cool guy that he is, he knew of a myth where if you could jump at the right time, you could possibly be able to survive a plunge in an elevator. \n\r\nNow, when Swaff was a boy, he spent all of his math classes making fun of his female teacher's moustache. He never paid attention, so he was a tad bit slow in his mathematical calculations. He did, however, have a very bizarre talent, in which he could tell the exact speed he was traveling. That came in pretty lucky today.\n\r\nSwaff knew he was falling at an even rate of 50 miles per hour. When the cord snapped, he was exactly 110 feet above the ground. He knew that he must jump at the right time to have any hopes of surviving. \n\r\nNow, after doing the math, please tell me when Swaff jumped.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe never did. By the time Swaff figured out that he would have to jump in 1.5 seconds, he would already be dead. Not even the best of mathematicians could do all the math needed in 1 and a half seconds. Swaff fell to his death, only to later be reincarnated by his magical brother Geemiee.\n\r\nYay for Geemiee.\n<|im_start|>answer\nHe never did. By the time Swaff figured out that he would have to jump in 1.5 seconds, he would already be dead. Not even the best of mathematicians could do all the math needed in 1 and a half seconds. Swaff fell to his death, only to later be reincarnated by his magical brother Geemiee.\n\r\nYay for Geemiee.\n<|im_end|>" }, { "id": "#25229", "title": "Twist Again!", "fun": 2.82, "difficulty": 2.5100000000000002, "author": "tjm531", "desc": "The American Jukebox Twist Contest has been the talk of local high schools for weeks, so it's no surprise that Arnold's Diner is jammed full with twisting teenagers hoping to take home the trophy. The competition is going to be fierce, as eight pairs of champion twisters, each from a different school, have entered. As the makeshift dance floor fills with poodle skirts and blue suede shoes, each couple was asked to request a different song to be played during the marathon, which is expected to last long into the night. From the information provided, name the young man and young woman who make up each couple, determine the high school each pair attends and the song they requested. \n\r\nYou will need to draw out a rectangular 2 x 4 grid (A - D on top, E - H on bottom) with the center line representing a row of tables in order to help determine who was in what position on the dance floor.\n\r\nPositions: A, B, C, D, E, F, G, H\n\r\nBoys: Bill, Curt, Danny, Donald, George, Ricky, Steve, Tony\n\r\nGirls: Cindy, Jenny, Laurie, Laverne, Nancy, Sheryl, Veronica, Wendy\n\r\nSchools: Jefferson, Lakewood, Lincoln, Oceanside, Riverdale, Roosevelt, Washington, Westerberg\n\r\nSongs: \"Let's Twist Again\", \"The Peppermint Twist\", \"Twist and Shout\", \"Twist, Twist, Senora\", \"The Twist\", \"Twistin' USA\", \"Twisting the Night Away\", \"Dear Lady Twist\"\n\n\r\n1. Bill and his partner aren't the couple representing Washington High (which isn't Laurie's school). Neither George (who isn't dancing with Wendy) nor Tony attends Roosevelt High.\n\r\n2. The couples in positions C, F, and H requested \"Twist and Shout\", \"Dear Lady Twist,\" and \"Twistin' USA\", in some order. The couple from Lakewood High, who requested \"Twist and Shout\", isn't in position F.\n\r\n3. Donald and his partner (who aren't the Oceanside High students) requested \"The Peppermint Twist\". Wendy and her partner requested \"Twisting the Night Away\". Cindy and her partner (who attend Lincoln High) requested \"Twistin' USA\".\n\r\n4. Curt and his partner, the Roosevelt High couple, and Sheryl and her partner are all dancing on the same side of the tables.\n\r\n5. Ricky and the couple from Roosevelt High are dancing at diagonally opposite ends of the restaurant. Bill and the Twist champions from Jefferson High are the other pairs dancing at diagonally opposite ends of the restaurant. \n\r\n6. Couples A, D, E, and H are Laverne and her partner, Jenny and her partner, the couple who attend Washington high, and the ones who requested \"Twist, Twist Senora\", in some order.\n\r\n7. Sheryl isn't immediately next to either Nancy or her partner or Laverne and her partner. Cindy is immediately next to, and due right of, Steve and his partner.\n\r\n8. Nancy and her partner (who attend Westerberg High) are directly across the tables from the Washington High couple; one of these couples requested \"Dear Lady Twist\". The couple in position A requested \"Let's Twist Again\".", "hint": "A regular Logic Grid drawn out could help too if you have a good imagination.", "answer": "A, Danny & Jenny, Roosevelt, \"Let's Twist Again\"\n\r\nB, Donald & Sheryl, Riverdale, \"The Peppermint Twist\"\n\r\nC, Curt & Laurie, Lakewood, \"Twist and Shout\"\n\r\nD, Bill & Nancy, Westerberg, \"Twist, Twist Senora\"\n\r\nE, Steve & Laverne, Jefferson, \"The Twist\"\n\r\nF, George & Cindy, Lincoln, \"Twistin' USA\"\n\r\nG, Tony & Wendy, Oceanside, \"Twisting the Night Away\"\n\r\nH, Ricky & Veronica, Washington, \"Dear Lady Twist\"", "category": "Logic", "date": "08/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe American Jukebox Twist Contest has been the talk of local high schools for weeks, so it's no surprise that Arnold's Diner is jammed full with twisting teenagers hoping to take home the trophy. The competition is going to be fierce, as eight pairs of champion twisters, each from a different school, have entered. As the makeshift dance floor fills with poodle skirts and blue suede shoes, each couple was asked to request a different song to be played during the marathon, which is expected to last long into the night. From the information provided, name the young man and young woman who make up each couple, determine the high school each pair attends and the song they requested. \n\r\nYou will need to draw out a rectangular 2 x 4 grid (A - D on top, E - H on bottom) with the center line representing a row of tables in order to help determine who was in what position on the dance floor.\n\r\nPositions: A, B, C, D, E, F, G, H\n\r\nBoys: Bill, Curt, Danny, Donald, George, Ricky, Steve, Tony\n\r\nGirls: Cindy, Jenny, Laurie, Laverne, Nancy, Sheryl, Veronica, Wendy\n\r\nSchools: Jefferson, Lakewood, Lincoln, Oceanside, Riverdale, Roosevelt, Washington, Westerberg\n\r\nSongs: \"Let's Twist Again\", \"The Peppermint Twist\", \"Twist and Shout\", \"Twist, Twist, Senora\", \"The Twist\", \"Twistin' USA\", \"Twisting the Night Away\", \"Dear Lady Twist\"\n\n\r\n1. Bill and his partner aren't the couple representing Washington High (which isn't Laurie's school). Neither George (who isn't dancing with Wendy) nor Tony attends Roosevelt High.\n\r\n2. The couples in positions C, F, and H requested \"Twist and Shout\", \"Dear Lady Twist,\" and \"Twistin' USA\", in some order. The couple from Lakewood High, who requested \"Twist and Shout\", isn't in position F.\n\r\n3. Donald and his partner (who aren't the Oceanside High students) requested \"The Peppermint Twist\". Wendy and her partner requested \"Twisting the Night Away\". Cindy and her partner (who attend Lincoln High) requested \"Twistin' USA\".\n\r\n4. Curt and his partner, the Roosevelt High couple, and Sheryl and her partner are all dancing on the same side of the tables.\n\r\n5. Ricky and the couple from Roosevelt High are dancing at diagonally opposite ends of the restaurant. Bill and the Twist champions from Jefferson High are the other pairs dancing at diagonally opposite ends of the restaurant. \n\r\n6. Couples A, D, E, and H are Laverne and her partner, Jenny and her partner, the couple who attend Washington high, and the ones who requested \"Twist, Twist Senora\", in some order.\n\r\n7. Sheryl isn't immediately next to either Nancy or her partner or Laverne and her partner. Cindy is immediately next to, and due right of, Steve and his partner.\n\r\n8. Nancy and her partner (who attend Westerberg High) are directly across the tables from the Washington High couple; one of these couples requested \"Dear Lady Twist\". The couple in position A requested \"Let's Twist Again\".\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA, Danny & Jenny, Roosevelt, \"Let's Twist Again\"\n\r\nB, Donald & Sheryl, Riverdale, \"The Peppermint Twist\"\n\r\nC, Curt & Laurie, Lakewood, \"Twist and Shout\"\n\r\nD, Bill & Nancy, Westerberg, \"Twist, Twist Senora\"\n\r\nE, Steve & Laverne, Jefferson, \"The Twist\"\n\r\nF, George & Cindy, Lincoln, \"Twistin' USA\"\n\r\nG, Tony & Wendy, Oceanside, \"Twisting the Night Away\"\n\r\nH, Ricky & Veronica, Washington, \"Dear Lady Twist\"\n<|im_start|>answer\nA, Danny & Jenny, Roosevelt, \"Let's Twist Again\"\n\r\nB, Donald & Sheryl, Riverdale, \"The Peppermint Twist\"\n\r\nC, Curt & Laurie, Lakewood, \"Twist and Shout\"\n\r\nD, Bill & Nancy, Westerberg, \"Twist, Twist Senora\"\n\r\nE, Steve & Laverne, Jefferson, \"The Twist\"\n\r\nF, George & Cindy, Lincoln, \"Twistin' USA\"\n\r\nG, Tony & Wendy, Oceanside, \"Twisting the Night Away\"\n\r\nH, Ricky & Veronica, Washington, \"Dear Lady Twist\"\n<|im_end|>" }, { "id": "#515", "title": "'U2'", "fun": 2.82, "difficulty": 2.29, "author": "kaila912", "desc": "`U2` has a concert that starts in 17 minutes and they must all cross a bridge to get there. All four men begin on the same side of the bridge. You must help them across to the other side. It is night. There is one flashlight. A maximum of two people can cross at one time. Any party who crosses, either 1 or 2 people, must have the flashlight with them. The flashlight must be walked back and forth, it cannot be thrown, etc. Each band member walks at a different speed. A pair must walk together at the rate of the slower man`s pace:\n\r\nBono - 1 minute to cross\r\nEdge - 2 minutes to cross\r\nAdam - 5 minutes to cross\r\nLarry - 10 minutes to cross\n\r\nFor example: If Bono and Larry walk across first, 10 minutes have elapsed when they get to the other side of the bridge. If Larry then returns with the flashlight, a total of 20 minutes have passed and you have failed the mission. Your goal is to get all the men across in 17 mins or less.", "hint": "No hint available.", "answer": "Bono(1min) and Edge(2min) walk across first bringing the total to 2 minutes. Then Bono(1) walks the flashlight back, totaling 3 minutes. Adam(5)and Larry(10) walk across, totaling 13 minutes. Edge(2) walks the light back, totaling 15 minutes. Edge(2) and Bono(1) walk across, totaling the answer, 17 minutes.", "category": "Logic", "date": "09/26/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n`U2` has a concert that starts in 17 minutes and they must all cross a bridge to get there. All four men begin on the same side of the bridge. You must help them across to the other side. It is night. There is one flashlight. A maximum of two people can cross at one time. Any party who crosses, either 1 or 2 people, must have the flashlight with them. The flashlight must be walked back and forth, it cannot be thrown, etc. Each band member walks at a different speed. A pair must walk together at the rate of the slower man`s pace:\n\r\nBono - 1 minute to cross\r\nEdge - 2 minutes to cross\r\nAdam - 5 minutes to cross\r\nLarry - 10 minutes to cross\n\r\nFor example: If Bono and Larry walk across first, 10 minutes have elapsed when they get to the other side of the bridge. If Larry then returns with the flashlight, a total of 20 minutes have passed and you have failed the mission. Your goal is to get all the men across in 17 mins or less.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBono(1min) and Edge(2min) walk across first bringing the total to 2 minutes. Then Bono(1) walks the flashlight back, totaling 3 minutes. Adam(5)and Larry(10) walk across, totaling 13 minutes. Edge(2) walks the light back, totaling 15 minutes. Edge(2) and Bono(1) walk across, totaling the answer, 17 minutes.\n<|im_start|>answer\nBono(1min) and Edge(2min) walk across first bringing the total to 2 minutes. Then Bono(1) walks the flashlight back, totaling 3 minutes. Adam(5)and Larry(10) walk across, totaling 13 minutes. Edge(2) walks the light back, totaling 15 minutes. Edge(2) and Bono(1) walk across, totaling the answer, 17 minutes.\n<|im_end|>" }, { "id": "#36394", "title": "Winging It, Too", "fun": 2.82, "difficulty": 1.68, "author": "chaskey", "desc": "Five pilots, flying with different airlines in many kinds of weather, being otherwise under the weather, took some time off and went to their respective homes in various towns. Who lives where and how much time they took from their jobs can all be determined by following the clues below.\n\r\nMEN: Awtoe, T'rane, Roebote\r\nWOMEN: Misskete, Kettal\r\nAIRLINES: Fleefly Flights, Skysters, Wingdom Ways, Airflue Airtimes, Taxiecloud Hops\r\nSTREETS: Path Way, Alley Boulevard, Avenue Street, Road Circle, Lane Court\r\nTOWNS: Square Lakes, Los Purses, Shortview, Townton, Cityville\r\nTIME OFF: 3 days, 5 days, 6 days, 7 days, 9 days\n\r\nCLUES:\n\r\n1. Path Way, despite its name, is the widest street in Cityville.\n\r\n2. The pilot for Fleefly Flights took off (from work) one day more than the one who lives on Alley Boulevard, and 3 days more than Misskete, who lives on Road Circle.\n\r\n3.Roebote rested for two days more from his work for Wingdom Ways than did the pilot who retired for a few days to her home in Los Purses. Roebote lives in Square Lakes.\n\r\n4. T'rane, who works for Taxiecloud Hops, spent some of his seven days at home in Townton helping his neighbors clean their beautiful Avenue Street, as they periodically do.\n\r\n5. Airflue Airtimes management, after several discussions with Kettal, decided that they could spare her for as long as nine days to be at home in Shortview.", "hint": "No hint available.", "answer": "Awtoe--Fleefly Flights--6 days--Path Way--Cityville\r\nT'rane--Taxiecloud Hops--7 days--Avenue Street--Townton\r\nRoebote--Wingdom Ways--5 days--Alley Boulevard--Square Lakes\r\nMisskete--Skysters--3 days--Road Circle--Los Purses\r\nKettal-Airflue Airtimes-9 days--Lane Court--Shortview", "category": "Logic-Grid", "date": "04/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive pilots, flying with different airlines in many kinds of weather, being otherwise under the weather, took some time off and went to their respective homes in various towns. Who lives where and how much time they took from their jobs can all be determined by following the clues below.\n\r\nMEN: Awtoe, T'rane, Roebote\r\nWOMEN: Misskete, Kettal\r\nAIRLINES: Fleefly Flights, Skysters, Wingdom Ways, Airflue Airtimes, Taxiecloud Hops\r\nSTREETS: Path Way, Alley Boulevard, Avenue Street, Road Circle, Lane Court\r\nTOWNS: Square Lakes, Los Purses, Shortview, Townton, Cityville\r\nTIME OFF: 3 days, 5 days, 6 days, 7 days, 9 days\n\r\nCLUES:\n\r\n1. Path Way, despite its name, is the widest street in Cityville.\n\r\n2. The pilot for Fleefly Flights took off (from work) one day more than the one who lives on Alley Boulevard, and 3 days more than Misskete, who lives on Road Circle.\n\r\n3.Roebote rested for two days more from his work for Wingdom Ways than did the pilot who retired for a few days to her home in Los Purses. Roebote lives in Square Lakes.\n\r\n4. T'rane, who works for Taxiecloud Hops, spent some of his seven days at home in Townton helping his neighbors clean their beautiful Avenue Street, as they periodically do.\n\r\n5. Airflue Airtimes management, after several discussions with Kettal, decided that they could spare her for as long as nine days to be at home in Shortview.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAwtoe--Fleefly Flights--6 days--Path Way--Cityville\r\nT'rane--Taxiecloud Hops--7 days--Avenue Street--Townton\r\nRoebote--Wingdom Ways--5 days--Alley Boulevard--Square Lakes\r\nMisskete--Skysters--3 days--Road Circle--Los Purses\r\nKettal-Airflue Airtimes-9 days--Lane Court--Shortview\n<|im_start|>answer\nAwtoe--Fleefly Flights--6 days--Path Way--Cityville\r\nT'rane--Taxiecloud Hops--7 days--Avenue Street--Townton\r\nRoebote--Wingdom Ways--5 days--Alley Boulevard--Square Lakes\r\nMisskete--Skysters--3 days--Road Circle--Los Purses\r\nKettal-Airflue Airtimes-9 days--Lane Court--Shortview\n<|im_end|>" }, { "id": "#24573", "title": "Stock Picker", "fun": 2.82, "difficulty": 1.82, "author": "MyllucsinDoubt", "desc": "Ok, so here is the deal. One day, you get a call from some random guy who says \"Next week, ABC stock is going to move up. I'm not asking you to buy any stock from me, but just take a look.\" You do so (why not, it can't hurt...) and he was correct. Sure enough, next week you get another call from the \"Lucky Guesser\". His pick? \"DEF is going to go down.\" And guess what! He was right again!\n\r\nFor five weeks, this guy predicts the behavior of stocks. The sixth time he calls, he says, \"I've been right the past five times. This time I have a stock for you and I do want you to buy some shares through me. What do you say?\" \n\r\nWell, what do you say? Do you buy shares from this guy?", "hint": "Uh, here's an answer to one question: he's a Scam Artist.", "answer": "Heck no! He's playing you like a puppet. The first week, he calls 100 people, says to half that ABC will go up, and to the other fifty claims it will go down. When ABC goes up, he called the fifty he'd correctly predicted to and told half DEF would go up, and half it would go down. By the time he's at week five, he has a few people (2-4) thinking he's a stock market god.", "category": "Logic", "date": "07/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOk, so here is the deal. One day, you get a call from some random guy who says \"Next week, ABC stock is going to move up. I'm not asking you to buy any stock from me, but just take a look.\" You do so (why not, it can't hurt...) and he was correct. Sure enough, next week you get another call from the \"Lucky Guesser\". His pick? \"DEF is going to go down.\" And guess what! He was right again!\n\r\nFor five weeks, this guy predicts the behavior of stocks. The sixth time he calls, he says, \"I've been right the past five times. This time I have a stock for you and I do want you to buy some shares through me. What do you say?\" \n\r\nWell, what do you say? Do you buy shares from this guy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHeck no! He's playing you like a puppet. The first week, he calls 100 people, says to half that ABC will go up, and to the other fifty claims it will go down. When ABC goes up, he called the fifty he'd correctly predicted to and told half DEF would go up, and half it would go down. By the time he's at week five, he has a few people (2-4) thinking he's a stock market god.\n<|im_start|>answer\nHeck no! He's playing you like a puppet. The first week, he calls 100 people, says to half that ABC will go up, and to the other fifty claims it will go down. When ABC goes up, he called the fifty he'd correctly predicted to and told half DEF would go up, and half it would go down. By the time he's at week five, he has a few people (2-4) thinking he's a stock market god.\n<|im_end|>" }, { "id": "#46673", "title": "Late at the Lake", "fun": 2.82, "difficulty": 2.38, "author": "whsprec", "desc": "One spring day five friends decided to go to Bear Lake after school. There were two girls named Becky and Kay, and three boys named Don, Gary, and Paul. Each friend was to bring something to go in a sandwich and some kind of snack. The plan was to meet at 3:30, but alas all of them were late. From the clues given determine what time each friend actually arrived and what food they brought.\n\r\n1) The friend who brought cake arrived at the lake seven minutes after the health-conscious girl who brought apples.\r\n2) Don did not bring lettuce.\r\n3) Kay arrived more than 10 minutes before the ham did, and immediately after the chips.\r\n4) Paul got to Bear Lake seven minutes after Don, but more than ten minutes before the crackers.\r\n5) The friend who went to the wrong spot brought cheese and arrived seven minutes ahead of the cake.\r\n6) Becky was seven minutes behind the tomatoes.\r\n7) Gary had a flat tire and arrived later than the chips.", "hint": "No hint available.", "answer": "Becky arrived at 4:13 with ham and crackers.\r\nDon arrived at 3:45 with turkey and doughnuts.\r\nGary arrived at 4:06 with tomatoes and cake.\r\nKay arrived at 3:59 with cheese and apples.\r\nPaul arrived at 3:52 with lettuce and chips.", "category": "Logic-Grid", "date": "04/06/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne spring day five friends decided to go to Bear Lake after school. There were two girls named Becky and Kay, and three boys named Don, Gary, and Paul. Each friend was to bring something to go in a sandwich and some kind of snack. The plan was to meet at 3:30, but alas all of them were late. From the clues given determine what time each friend actually arrived and what food they brought.\n\r\n1) The friend who brought cake arrived at the lake seven minutes after the health-conscious girl who brought apples.\r\n2) Don did not bring lettuce.\r\n3) Kay arrived more than 10 minutes before the ham did, and immediately after the chips.\r\n4) Paul got to Bear Lake seven minutes after Don, but more than ten minutes before the crackers.\r\n5) The friend who went to the wrong spot brought cheese and arrived seven minutes ahead of the cake.\r\n6) Becky was seven minutes behind the tomatoes.\r\n7) Gary had a flat tire and arrived later than the chips.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBecky arrived at 4:13 with ham and crackers.\r\nDon arrived at 3:45 with turkey and doughnuts.\r\nGary arrived at 4:06 with tomatoes and cake.\r\nKay arrived at 3:59 with cheese and apples.\r\nPaul arrived at 3:52 with lettuce and chips.\n<|im_start|>answer\nBecky arrived at 4:13 with ham and crackers.\r\nDon arrived at 3:45 with turkey and doughnuts.\r\nGary arrived at 4:06 with tomatoes and cake.\r\nKay arrived at 3:59 with cheese and apples.\r\nPaul arrived at 3:52 with lettuce and chips.\n<|im_end|>" }, { "id": "#26698", "title": "Auction Block", "fun": 2.82, "difficulty": 1.61, "author": "mejoza", "desc": "4 women were selling their spring cleaning finds. The auctioneer had taken meager notes on the acceptable (lowest bid) prices and who was selling what. He can only remember the following. The items are, bizarrely enough: a gold-plated feather duster, a talking Kleenex box, a marshmallow sculpture, and a locking lipstick organizer. Can you help him get the auction started? Going once, going twice....\n\r\n1.The four women were: Serafina, the one who wanted at least 35 dollars, the one who found her item in the garage, and the one who wanted 10 dollars less than the lady selling the locking lipstick organizer.\n\r\n2. Fedora found her item under the bed.\n\r\n3. Illumina did not want the most or the least for her item.\n\r\n4. The cheapest starting price was for the Kleenex box that says \"Bless you\".\n\r\n5. The item from the attic had to start at 20 dollars.\n\r\n6. The sculpture (not Serafina's) was found in the linen closet.\n\r\n7. The auctioneer thought Finnielle's high price of 35 dollars was absurd.", "hint": "No hint available.", "answer": "Serafina found the gold-plated feather duster in the attic, wanted 20.\n\r\nFedora found the talking Kleenex box under the bed, wanted 15.\n\r\nIllumina found the locking lipstick organizer in her garage, wanted 25.\n\r\nFinnielle found the marshmallow sculpture in the linen closet and wanted 35.", "category": "Logic-Grid", "date": "11/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 women were selling their spring cleaning finds. The auctioneer had taken meager notes on the acceptable (lowest bid) prices and who was selling what. He can only remember the following. The items are, bizarrely enough: a gold-plated feather duster, a talking Kleenex box, a marshmallow sculpture, and a locking lipstick organizer. Can you help him get the auction started? Going once, going twice....\n\r\n1.The four women were: Serafina, the one who wanted at least 35 dollars, the one who found her item in the garage, and the one who wanted 10 dollars less than the lady selling the locking lipstick organizer.\n\r\n2. Fedora found her item under the bed.\n\r\n3. Illumina did not want the most or the least for her item.\n\r\n4. The cheapest starting price was for the Kleenex box that says \"Bless you\".\n\r\n5. The item from the attic had to start at 20 dollars.\n\r\n6. The sculpture (not Serafina's) was found in the linen closet.\n\r\n7. The auctioneer thought Finnielle's high price of 35 dollars was absurd.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSerafina found the gold-plated feather duster in the attic, wanted 20.\n\r\nFedora found the talking Kleenex box under the bed, wanted 15.\n\r\nIllumina found the locking lipstick organizer in her garage, wanted 25.\n\r\nFinnielle found the marshmallow sculpture in the linen closet and wanted 35.\n<|im_start|>answer\nSerafina found the gold-plated feather duster in the attic, wanted 20.\n\r\nFedora found the talking Kleenex box under the bed, wanted 15.\n\r\nIllumina found the locking lipstick organizer in her garage, wanted 25.\n\r\nFinnielle found the marshmallow sculpture in the linen closet and wanted 35.\n<|im_end|>" }, { "id": "#29032", "title": "Car Pool", "fun": 2.82, "difficulty": 1.8900000000000001, "author": "Tammy93", "desc": "Three men named Greene, Grey, and Tann, along with two women named Browne and Whyte, each drive the car in their car pool on a different one of the five weekdays each week. Each person's car is a different one of these five colors: brown, gray, green, tan, and white. From the information given, determine the day on which each person drives, as well as the color of his or her car.\n\r\n1. The color of no person's car is similar to his or her name.\r\n2. They ride in the green car earlier in the week than the tan car but later than in the gray car.\r\n3. The woman who drives the brown car drives later in the week than Mr. Greene, but earlier than Mr. Grey, who is not the man who drives on Friday.\r\n4. The man who drives the tan car drives earlier in the week than the man who drives the white car but later than Ms. Browne, who does not drive on Monday.\r\n5. Ms. Browne does not drive on Tuesday.", "hint": "No hint available.", "answer": "Monday-Mr. Greene-gray\r\nTuesday-Ms. Whyte-brown\r\nWednesday-Ms. Browne-green\r\nThursday-Mr. Grey-tan\r\nFriday-Mr. Tann-white", "category": "Logic-Grid", "date": "03/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree men named Greene, Grey, and Tann, along with two women named Browne and Whyte, each drive the car in their car pool on a different one of the five weekdays each week. Each person's car is a different one of these five colors: brown, gray, green, tan, and white. From the information given, determine the day on which each person drives, as well as the color of his or her car.\n\r\n1. The color of no person's car is similar to his or her name.\r\n2. They ride in the green car earlier in the week than the tan car but later than in the gray car.\r\n3. The woman who drives the brown car drives later in the week than Mr. Greene, but earlier than Mr. Grey, who is not the man who drives on Friday.\r\n4. The man who drives the tan car drives earlier in the week than the man who drives the white car but later than Ms. Browne, who does not drive on Monday.\r\n5. Ms. Browne does not drive on Tuesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday-Mr. Greene-gray\r\nTuesday-Ms. Whyte-brown\r\nWednesday-Ms. Browne-green\r\nThursday-Mr. Grey-tan\r\nFriday-Mr. Tann-white\n<|im_start|>answer\nMonday-Mr. Greene-gray\r\nTuesday-Ms. Whyte-brown\r\nWednesday-Ms. Browne-green\r\nThursday-Mr. Grey-tan\r\nFriday-Mr. Tann-white\n<|im_end|>" }, { "id": "#46203", "title": "Round Table Conference Again", "fun": 2.82, "difficulty": 2.04, "author": "nidhikaila", "desc": "8 people have to be seated at a round banquet table. The seats are number 1-8. For this teaser, 5 is opposite 1, 6 is opposite 2 and so on. Likewise, \"next to\" means one of the neighboring seats only. i.e., 8 is next to 1 and 7. \n\r\nA and H are the only French speaking people on the table. They need to be seated together. \r\nB and F should sit opposite each other. \r\nC, F, and G all know Russian, but don't necessarily need to sit next to each other. In fact, G wants to sit next to someone who knows French. \r\nD is English and insists on sitting next to at least one other English speaking person, and pat opposite the good looking H. E is the only other English speaker in the group, but he wants to sit next to someone who knows Russian. \r\nG agrees to sit next to F only on condition that the other side must have a French speaker. C does not sit next to either of them. \r\nC however, agrees to sit next to B, who is the only Bavarian in the group. \r\nA will not sit next to a Russian or an English speaker.", "hint": "No hint available.", "answer": "They sit in the simple order - ABCDEFGH.", "category": "Logic", "date": "01/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n8 people have to be seated at a round banquet table. The seats are number 1-8. For this teaser, 5 is opposite 1, 6 is opposite 2 and so on. Likewise, \"next to\" means one of the neighboring seats only. i.e., 8 is next to 1 and 7. \n\r\nA and H are the only French speaking people on the table. They need to be seated together. \r\nB and F should sit opposite each other. \r\nC, F, and G all know Russian, but don't necessarily need to sit next to each other. In fact, G wants to sit next to someone who knows French. \r\nD is English and insists on sitting next to at least one other English speaking person, and pat opposite the good looking H. E is the only other English speaker in the group, but he wants to sit next to someone who knows Russian. \r\nG agrees to sit next to F only on condition that the other side must have a French speaker. C does not sit next to either of them. \r\nC however, agrees to sit next to B, who is the only Bavarian in the group. \r\nA will not sit next to a Russian or an English speaker.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey sit in the simple order - ABCDEFGH.\n<|im_start|>answer\nThey sit in the simple order - ABCDEFGH.\n<|im_end|>" }, { "id": "#21046", "title": "Sibling Rivalries", "fun": 2.82, "difficulty": 2.85, "author": "jpfrank1", "desc": "Anyone who has even one brother or sister knows that sibling rivalries permeate into every aspect of life. Well the Humdingers are no different. Four boys (Jason, Matt, Tom and David) and one girl (Sarah--don't you feel for her!) are as different as children get. The one thing that they have in common is their love of sports and food (sounds familiar to this author, mmm food). Each child who is either in 3rd, 5th, 6th 8th or 12th grade plays on their school's team in their favorite sport (Golf, Soccer, Tennis, Football or Hockey). After they finish playing, they each go home and watch their favorite baseball team (buying 5 TVs was the best move Mrs. Humdinger ever made) while enjoying their favorite stadium food (hot dogs, pretzels, nachos w/o meat, ice cream or chicken fingers) to get them in the mood. Your job is to match each child with the grade, sport they play, favorite team and favorite food. ENJOY!\n\r\n1. Jason's younger brother (not Tom) loves to play hockey.\r\n2. Sarah has two younger brothers neither of whom golf or eat pretzels.\r\n3. Tom's favorite baseball team moved from Brooklyn to LA.\r\n4. Whoever plays tennis loves to watch the Orioles.\r\n5. Matt is in 5th grade.\r\n6. The Cardinals fan eats neither ice cream nor hot dogs, but does play hockey.\r\n7. The Orioles fan is a vegetarian.\r\n8. Whoever is in 6th grade plays soccer and eats hot dogs.\r\n9. The Yankees fan likes to watch his favorite team while eating Ben & Jerry's.\r\n10. The football player likes chicken.\r\n11. Jason idolizes Fred Couples so is obviously into golf.\r\n12. David, who does not eat meat, has a younger sibling who is a Met fan.", "hint": "No hint available.", "answer": "Jason: 8th, golf, Yankees, ice cream \r\nMatt: 5th, hockey, Cardinals, nachos\r\nSarah: 6th, soccer, Mets, hot dogs\r\nTom: 3rd, football, Dodgers, Chicken fingers\r\nDavid: 12th, tennis, Orioles, Pretzels", "category": "Logic-Grid", "date": "02/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnyone who has even one brother or sister knows that sibling rivalries permeate into every aspect of life. Well the Humdingers are no different. Four boys (Jason, Matt, Tom and David) and one girl (Sarah--don't you feel for her!) are as different as children get. The one thing that they have in common is their love of sports and food (sounds familiar to this author, mmm food). Each child who is either in 3rd, 5th, 6th 8th or 12th grade plays on their school's team in their favorite sport (Golf, Soccer, Tennis, Football or Hockey). After they finish playing, they each go home and watch their favorite baseball team (buying 5 TVs was the best move Mrs. Humdinger ever made) while enjoying their favorite stadium food (hot dogs, pretzels, nachos w/o meat, ice cream or chicken fingers) to get them in the mood. Your job is to match each child with the grade, sport they play, favorite team and favorite food. ENJOY!\n\r\n1. Jason's younger brother (not Tom) loves to play hockey.\r\n2. Sarah has two younger brothers neither of whom golf or eat pretzels.\r\n3. Tom's favorite baseball team moved from Brooklyn to LA.\r\n4. Whoever plays tennis loves to watch the Orioles.\r\n5. Matt is in 5th grade.\r\n6. The Cardinals fan eats neither ice cream nor hot dogs, but does play hockey.\r\n7. The Orioles fan is a vegetarian.\r\n8. Whoever is in 6th grade plays soccer and eats hot dogs.\r\n9. The Yankees fan likes to watch his favorite team while eating Ben & Jerry's.\r\n10. The football player likes chicken.\r\n11. Jason idolizes Fred Couples so is obviously into golf.\r\n12. David, who does not eat meat, has a younger sibling who is a Met fan.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJason: 8th, golf, Yankees, ice cream \r\nMatt: 5th, hockey, Cardinals, nachos\r\nSarah: 6th, soccer, Mets, hot dogs\r\nTom: 3rd, football, Dodgers, Chicken fingers\r\nDavid: 12th, tennis, Orioles, Pretzels\n<|im_start|>answer\nJason: 8th, golf, Yankees, ice cream \r\nMatt: 5th, hockey, Cardinals, nachos\r\nSarah: 6th, soccer, Mets, hot dogs\r\nTom: 3rd, football, Dodgers, Chicken fingers\r\nDavid: 12th, tennis, Orioles, Pretzels\n<|im_end|>" }, { "id": "#47257", "title": "Surviving the South Pacific", "fun": 2.82, "difficulty": 2.5, "author": "whsprec", "desc": "Ten friends went on a boating expedition in the South Pacific. During a storm the boat capsized sending all of them into the ocean. Fortunately, they were all wearing life jackets and each person was tied to a buddy for protection. Each pair landed on a different deserted island, which only had one food source, and was able to survive by eating that food. Eventually each pair was rescued, but in different weeks after the accident. From the clues below determine the name of each pair, what they ate to survive, and how long it took to be rescued.\n\r\n1) Deon and Clay named their island One Tree Island and unfortunately for them, the name was appropriate. \r\n2) Thanks to a shallow lagoon, fish was the daily meal for Simon, who was on the island a week longer than the ones who ate coconuts.\r\n3) Nick's stay was longer than Quincy's, but not as long as the pair that ate seagulls.\r\n4) Rickey was on his island for six weeks.\r\n5) Keith said that he would never eat crabs again after he got off the island, which he was on longer than Forrest was on his.\r\n6) Hunter was found two weeks after the pair who survived on snakes.", "hint": "No hint available.", "answer": "Keith and Nick ate crabs for 7 weeks before being found.\r\nClay and Deon ate coconuts for 4 weeks before being found.\r\nHunter and Wayne ate seagulls for 8 weeks before being found.\r\nRickey and Forrest ate snakes for 6 weeks before being found.\r\nQuincy and Simon ate fish for 5 weeks before being found.", "category": "Logic-Grid", "date": "06/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTen friends went on a boating expedition in the South Pacific. During a storm the boat capsized sending all of them into the ocean. Fortunately, they were all wearing life jackets and each person was tied to a buddy for protection. Each pair landed on a different deserted island, which only had one food source, and was able to survive by eating that food. Eventually each pair was rescued, but in different weeks after the accident. From the clues below determine the name of each pair, what they ate to survive, and how long it took to be rescued.\n\r\n1) Deon and Clay named their island One Tree Island and unfortunately for them, the name was appropriate. \r\n2) Thanks to a shallow lagoon, fish was the daily meal for Simon, who was on the island a week longer than the ones who ate coconuts.\r\n3) Nick's stay was longer than Quincy's, but not as long as the pair that ate seagulls.\r\n4) Rickey was on his island for six weeks.\r\n5) Keith said that he would never eat crabs again after he got off the island, which he was on longer than Forrest was on his.\r\n6) Hunter was found two weeks after the pair who survived on snakes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKeith and Nick ate crabs for 7 weeks before being found.\r\nClay and Deon ate coconuts for 4 weeks before being found.\r\nHunter and Wayne ate seagulls for 8 weeks before being found.\r\nRickey and Forrest ate snakes for 6 weeks before being found.\r\nQuincy and Simon ate fish for 5 weeks before being found.\n<|im_start|>answer\nKeith and Nick ate crabs for 7 weeks before being found.\r\nClay and Deon ate coconuts for 4 weeks before being found.\r\nHunter and Wayne ate seagulls for 8 weeks before being found.\r\nRickey and Forrest ate snakes for 6 weeks before being found.\r\nQuincy and Simon ate fish for 5 weeks before being found.\n<|im_end|>" }, { "id": "#16166", "title": "The Secret Code", "fun": 2.82, "difficulty": 1.82, "author": "jacintan", "desc": "A man wanted to get into his work building, but he had forgotten his code. However, he did remember five clues. These are what those clues were:\n\r\nThe fifth number plus the third number equals fourteen. \n\r\nThe fourth number is one more than the second number. \n\r\nThe first number is one less than twice the second number. \n\r\nThe second number plus the third number equals ten. \n\r\nThe sum of all five numbers is 30.\n\r\nWhat were the five numbers and in what order?", "hint": "No hint available.", "answer": "7, 4, 6, 5, 8", "category": "Math", "date": "01/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man wanted to get into his work building, but he had forgotten his code. However, he did remember five clues. These are what those clues were:\n\r\nThe fifth number plus the third number equals fourteen. \n\r\nThe fourth number is one more than the second number. \n\r\nThe first number is one less than twice the second number. \n\r\nThe second number plus the third number equals ten. \n\r\nThe sum of all five numbers is 30.\n\r\nWhat were the five numbers and in what order?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7, 4, 6, 5, 8\n<|im_start|>answer\n7, 4, 6, 5, 8\n<|im_end|>" }, { "id": "#42054", "title": "Measure Exactly 6 Gallons", "fun": 2.82, "difficulty": 1.84, "author": "Editor", "desc": "Using a tap, a nine-gallon container and a four-gallon container, can you measure exactly 6 gallons?", "hint": "No hint available.", "answer": "Here are the contents of the two containers after each stage (A=nine-gallon container, B=four-gallon container) : \n\r\nA B\r\n9 0 fill A\r\n5 4 fill B from A\r\n5 0 empty B\r\n1 4 fill B from A\r\n1 0 empty B\r\n0 1 fill B from A\r\n9 1 fill A\r\n6 4 fill B from A\r\n6 0 empty B \n\r\nThis leaves 6 gallons in container A.", "category": "Logic", "date": "05/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing a tap, a nine-gallon container and a four-gallon container, can you measure exactly 6 gallons?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHere are the contents of the two containers after each stage (A=nine-gallon container, B=four-gallon container) : \n\r\nA B\r\n9 0 fill A\r\n5 4 fill B from A\r\n5 0 empty B\r\n1 4 fill B from A\r\n1 0 empty B\r\n0 1 fill B from A\r\n9 1 fill A\r\n6 4 fill B from A\r\n6 0 empty B \n\r\nThis leaves 6 gallons in container A.\n<|im_start|>answer\nHere are the contents of the two containers after each stage (A=nine-gallon container, B=four-gallon container) : \n\r\nA B\r\n9 0 fill A\r\n5 4 fill B from A\r\n5 0 empty B\r\n1 4 fill B from A\r\n1 0 empty B\r\n0 1 fill B from A\r\n9 1 fill A\r\n6 4 fill B from A\r\n6 0 empty B \n\r\nThis leaves 6 gallons in container A.\n<|im_end|>" }, { "id": "#20962", "title": "Seating Trouble", "fun": 2.82, "difficulty": 1.69, "author": "fishmed", "desc": "At the wedding reception, there are five guests, Colin, Emily, Kate, Fred, and Irene, who are not sure where to sit at the dinner table. They ask the bride's mother, who responds, \"As I remember, Colin is not next to Kate, Emily is not next to Fred or Kate.Neither Kate or Emily are next to Irene. And Fred should sit on Irene's left.\" As you look at them from the opposite side of the table, can you correctly seat the guests from left to right?", "hint": "No hint available.", "answer": "They are seated, left to right, as you face them, in the following order. \n\r\nEmily, Colin, Irene, Fred, Kate", "category": "Logic", "date": "02/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the wedding reception, there are five guests, Colin, Emily, Kate, Fred, and Irene, who are not sure where to sit at the dinner table. They ask the bride's mother, who responds, \"As I remember, Colin is not next to Kate, Emily is not next to Fred or Kate.Neither Kate or Emily are next to Irene. And Fred should sit on Irene's left.\" As you look at them from the opposite side of the table, can you correctly seat the guests from left to right?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are seated, left to right, as you face them, in the following order. \n\r\nEmily, Colin, Irene, Fred, Kate\n<|im_start|>answer\nThey are seated, left to right, as you face them, in the following order. \n\r\nEmily, Colin, Irene, Fred, Kate\n<|im_end|>" }, { "id": "#22079", "title": "Disney Fans' Pets", "fun": 2.82, "difficulty": 3.18, "author": "Rebeca", "desc": "Five young girls are all friends and are all big Disney fans. They have named their pets after cartoon characters from their favorite Disney movies. Each girl owns a pair of pets of the same species. Each pair consists of two differently colored creatures of the same age. Can you figure out which girl owns which pets, their colors, ages and names?\n\r\nGirls: Audrey, Betty, Cari, Debra, and Emma\r\nPets: Birds, Dogs, Cats, Fish and Rabbits\r\nPet Names: Ariel and Aurora, Beauty and Beast, Lilo and Stitch, Mike and Sully, Timon and Pumba\r\nColor Pairs: Blue and White, Blue and Red, Blue and Brown, Brown and Red, Brown and White\r\nAges: 6 months, 1 year, 2 years, 3 years, 4 years\n\r\nEmma is allergic to dogs.\n\r\nNeither of the rabbits are blue. Neither of the fish are white.\n\r\nJust one girl has the same first initial as both her 2 yr old pets.\n\r\nThe girls don't usually take their pets with them to visit each other. It is certain that Mike and Sully would try to devour Aurora and Ariel, and also that the blue and brown pair would consider the blue and white pair a tasty snack. \n\r\nLilo and Stitch live in the same house as Aurora and Ariel because their owners are sisters. There is no reason to think they would attack each other. In fact, they probably aren't even aware of each other.\n\r\nCari and Debra don't own blue pets. Audrey and Emma don't own brown pets. \n\r\nThe brown and white pair are younger than the fish, and also younger than Debra's pets. \n\r\nAudrey's pets are exactly twice the age of Aurora and Ariel.\n\r\nTimon and Pumba are older than the cats but younger than the red and brown pair.", "hint": "No hint available.", "answer": "Audrey owns Lilo and Stitch, red and blue 1 year old fish.\r\nBetty owns Beauty and Beast, blue and brown 2 year old cats.\r\nCari owns Aurora and Ariel, brown and white 6 month old rabbits.\r\nDebra owns Mike and Sully, red and brown 4 year old dogs.\r\nEmma owns Timon and Pumba, blue and white 3 year old birds.", "category": "Logic-Grid", "date": "04/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive young girls are all friends and are all big Disney fans. They have named their pets after cartoon characters from their favorite Disney movies. Each girl owns a pair of pets of the same species. Each pair consists of two differently colored creatures of the same age. Can you figure out which girl owns which pets, their colors, ages and names?\n\r\nGirls: Audrey, Betty, Cari, Debra, and Emma\r\nPets: Birds, Dogs, Cats, Fish and Rabbits\r\nPet Names: Ariel and Aurora, Beauty and Beast, Lilo and Stitch, Mike and Sully, Timon and Pumba\r\nColor Pairs: Blue and White, Blue and Red, Blue and Brown, Brown and Red, Brown and White\r\nAges: 6 months, 1 year, 2 years, 3 years, 4 years\n\r\nEmma is allergic to dogs.\n\r\nNeither of the rabbits are blue. Neither of the fish are white.\n\r\nJust one girl has the same first initial as both her 2 yr old pets.\n\r\nThe girls don't usually take their pets with them to visit each other. It is certain that Mike and Sully would try to devour Aurora and Ariel, and also that the blue and brown pair would consider the blue and white pair a tasty snack. \n\r\nLilo and Stitch live in the same house as Aurora and Ariel because their owners are sisters. There is no reason to think they would attack each other. In fact, they probably aren't even aware of each other.\n\r\nCari and Debra don't own blue pets. Audrey and Emma don't own brown pets. \n\r\nThe brown and white pair are younger than the fish, and also younger than Debra's pets. \n\r\nAudrey's pets are exactly twice the age of Aurora and Ariel.\n\r\nTimon and Pumba are older than the cats but younger than the red and brown pair.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAudrey owns Lilo and Stitch, red and blue 1 year old fish.\r\nBetty owns Beauty and Beast, blue and brown 2 year old cats.\r\nCari owns Aurora and Ariel, brown and white 6 month old rabbits.\r\nDebra owns Mike and Sully, red and brown 4 year old dogs.\r\nEmma owns Timon and Pumba, blue and white 3 year old birds.\n<|im_start|>answer\nAudrey owns Lilo and Stitch, red and blue 1 year old fish.\r\nBetty owns Beauty and Beast, blue and brown 2 year old cats.\r\nCari owns Aurora and Ariel, brown and white 6 month old rabbits.\r\nDebra owns Mike and Sully, red and brown 4 year old dogs.\r\nEmma owns Timon and Pumba, blue and white 3 year old birds.\n<|im_end|>" }, { "id": "#46891", "title": "Master Thesis", "fun": 2.82, "difficulty": 1.55, "author": "whsprec", "desc": "Five graduate students were finally submitting their thesis. Each student had a different subject, a different number of pages that they had written, and a different requirement for submitting. If they missed the additional requirement their thesis was automatically rejected and they would have to start over. From the clues below determine the author, subject, how many pages, and the department's additional requirement.\n\r\n1) The Predicting Drop Outs thesis by Toby was at least 70 pages longer than the one that required .75-inch margins.\r\n2) Kia's thesis wasn't 130 pages, but needed to be on blue paper.\r\n3) Neither the How the Internet Affects Relationships nor Frank's thesis are the 80-page that needed to be hand written.\r\n4) Sara wrote 230 pages.\r\n5) The thesis on Cheese Bacteria was 190 pages.\r\n6) The thesis on Archaeology River Sites needed to be font 10.", "hint": "No hint available.", "answer": "Sara wrote 230 pages on How the Internet Affects Relationships that needed to be .75-inch margins.\r\nToby wrote 320 pages on Predicting Drop Outs that needed to start on page 5.\r\nFrank wrote 130 pages on Archaeology River Sites that needed to be font 10.\r\nSandy wrote 80 pages on Ancient Greek Ship Building that needed to be hand written.\r\nKia wrote 190 pages on Cheese Bacteria that needed to be on blue paper.", "category": "Logic-Grid", "date": "05/02/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive graduate students were finally submitting their thesis. Each student had a different subject, a different number of pages that they had written, and a different requirement for submitting. If they missed the additional requirement their thesis was automatically rejected and they would have to start over. From the clues below determine the author, subject, how many pages, and the department's additional requirement.\n\r\n1) The Predicting Drop Outs thesis by Toby was at least 70 pages longer than the one that required .75-inch margins.\r\n2) Kia's thesis wasn't 130 pages, but needed to be on blue paper.\r\n3) Neither the How the Internet Affects Relationships nor Frank's thesis are the 80-page that needed to be hand written.\r\n4) Sara wrote 230 pages.\r\n5) The thesis on Cheese Bacteria was 190 pages.\r\n6) The thesis on Archaeology River Sites needed to be font 10.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSara wrote 230 pages on How the Internet Affects Relationships that needed to be .75-inch margins.\r\nToby wrote 320 pages on Predicting Drop Outs that needed to start on page 5.\r\nFrank wrote 130 pages on Archaeology River Sites that needed to be font 10.\r\nSandy wrote 80 pages on Ancient Greek Ship Building that needed to be hand written.\r\nKia wrote 190 pages on Cheese Bacteria that needed to be on blue paper.\n<|im_start|>answer\nSara wrote 230 pages on How the Internet Affects Relationships that needed to be .75-inch margins.\r\nToby wrote 320 pages on Predicting Drop Outs that needed to start on page 5.\r\nFrank wrote 130 pages on Archaeology River Sites that needed to be font 10.\r\nSandy wrote 80 pages on Ancient Greek Ship Building that needed to be hand written.\r\nKia wrote 190 pages on Cheese Bacteria that needed to be on blue paper.\n<|im_end|>" }, { "id": "#49634", "title": "The Riddle Of The Sphinx", "fun": 2.82, "difficulty": 1.13, "author": "Gbdf", "desc": "The sphinx wanted to know which one of the three gods stole the golden apple. Was it Horus, Anubis or Osiris?\n\r\n''I didn't,'' said Horus.\r\n''Osiris did,'' said Anubis.\r\n''Anubis is lying,'' said Osiris.\n\r\nThe sphinx knew that one god was telling the truth and the other two were lying.\n\r\nWho stole the golden apple?", "hint": "Guess your answer and check if it is correct.", "answer": "Horus stole the golden apple. Horus and Anubis were lying. Osiris was telling the truth.", "category": "Logic", "date": "10/18/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe sphinx wanted to know which one of the three gods stole the golden apple. Was it Horus, Anubis or Osiris?\n\r\n''I didn't,'' said Horus.\r\n''Osiris did,'' said Anubis.\r\n''Anubis is lying,'' said Osiris.\n\r\nThe sphinx knew that one god was telling the truth and the other two were lying.\n\r\nWho stole the golden apple?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHorus stole the golden apple. Horus and Anubis were lying. Osiris was telling the truth.\n<|im_start|>answer\nHorus stole the golden apple. Horus and Anubis were lying. Osiris was telling the truth.\n<|im_end|>" }, { "id": "#41879", "title": "The Hats", "fun": 2.82, "difficulty": 1.75, "author": "TRILLIONAIRE", "desc": "There were 4 people sitting in a row trying to win $50 from a riddle. \n\r\nThe one in front was wearing a red hat. \r\nThe second from the front was wearing a blue hat. \r\nThe third from the front was wearing a red hat. \r\nThe last was wearing a blue hat and was blind-folded. \n\r\nEach of them was informed that they were all wearing a hat, the last person was blind-folded and that there were 2 red and 2 blue hats. If they can guess the color of their hat, then they win the prize. \n\r\nThere was a long silence, then one of them guessed the color of his hat correctly. Who was it? \n\r\n(Note that they can only see the person in front of them and are not allowed to turn around and see behind them.)", "hint": "No hint available.", "answer": "It was the second person. The first and last person cannot see other people at all, therefore it is either the third or second. The second person realised that if he and the person in front were wearing the same colored hat, the third person would be able to answer the color of his hat right away. However, since there was a long silence, then the color of his hat and that of the person in front must be different.", "category": "Logic", "date": "05/10/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 4 people sitting in a row trying to win $50 from a riddle. \n\r\nThe one in front was wearing a red hat. \r\nThe second from the front was wearing a blue hat. \r\nThe third from the front was wearing a red hat. \r\nThe last was wearing a blue hat and was blind-folded. \n\r\nEach of them was informed that they were all wearing a hat, the last person was blind-folded and that there were 2 red and 2 blue hats. If they can guess the color of their hat, then they win the prize. \n\r\nThere was a long silence, then one of them guessed the color of his hat correctly. Who was it? \n\r\n(Note that they can only see the person in front of them and are not allowed to turn around and see behind them.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt was the second person. The first and last person cannot see other people at all, therefore it is either the third or second. The second person realised that if he and the person in front were wearing the same colored hat, the third person would be able to answer the color of his hat right away. However, since there was a long silence, then the color of his hat and that of the person in front must be different.\n<|im_start|>answer\nIt was the second person. The first and last person cannot see other people at all, therefore it is either the third or second. The second person realised that if he and the person in front were wearing the same colored hat, the third person would be able to answer the color of his hat right away. However, since there was a long silence, then the color of his hat and that of the person in front must be different.\n<|im_end|>" }, { "id": "#41945", "title": "Friends and a Wallet", "fun": 2.82, "difficulty": 1.79, "author": "JZumun", "desc": "You and your five friends, conveniently named A, B, C, D, and E, were hanging out when you spotted a wallet on the floor. You have a poor memory, but you remember that it is owned by one of your friends.\n\r\nYou: Whose wallet is this?\r\nA: That's mine.\r\nD: You're lying, A.\r\nC: Yeah, A, you are lying.\r\nB: A is not lying, guys.\r\nD: That wallet is owned by C.\r\nE: Yeah, D is telling the truth.\r\nB: No, E. That's your wallet.\n\r\nYou remember that at least 2 of your friends always tell the truth (truthtellers), while at least 2 always lie (liars).\r\nThanks to your memory, however, you can't remember which friend lies or tells the truth.\n\r\nCan you figure out who owns the wallet?", "hint": "No hint available.", "answer": "C owns the wallet.\n\r\nEXPLANATION:\r\nB's first statement says that A is telling the truth that it is A's wallet. His second statement, however, says that it is E's wallet. The statements cannot be true at the same time, so B lied in both of them. B is a liar.\n\r\nSince B was lying when he said that A is telling the truth, A is the other liar, too.\n\r\nC and D are automatically truthtellers, since they both told the truth when they said A was lying. E is also a truthteller since he said that D told the truth.\n\r\nTherefore, C owns the wallet.", "category": "Logic", "date": "05/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou and your five friends, conveniently named A, B, C, D, and E, were hanging out when you spotted a wallet on the floor. You have a poor memory, but you remember that it is owned by one of your friends.\n\r\nYou: Whose wallet is this?\r\nA: That's mine.\r\nD: You're lying, A.\r\nC: Yeah, A, you are lying.\r\nB: A is not lying, guys.\r\nD: That wallet is owned by C.\r\nE: Yeah, D is telling the truth.\r\nB: No, E. That's your wallet.\n\r\nYou remember that at least 2 of your friends always tell the truth (truthtellers), while at least 2 always lie (liars).\r\nThanks to your memory, however, you can't remember which friend lies or tells the truth.\n\r\nCan you figure out who owns the wallet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nC owns the wallet.\n\r\nEXPLANATION:\r\nB's first statement says that A is telling the truth that it is A's wallet. His second statement, however, says that it is E's wallet. The statements cannot be true at the same time, so B lied in both of them. B is a liar.\n\r\nSince B was lying when he said that A is telling the truth, A is the other liar, too.\n\r\nC and D are automatically truthtellers, since they both told the truth when they said A was lying. E is also a truthteller since he said that D told the truth.\n\r\nTherefore, C owns the wallet.\n<|im_start|>answer\nC owns the wallet.\n\r\nEXPLANATION:\r\nB's first statement says that A is telling the truth that it is A's wallet. His second statement, however, says that it is E's wallet. The statements cannot be true at the same time, so B lied in both of them. B is a liar.\n\r\nSince B was lying when he said that A is telling the truth, A is the other liar, too.\n\r\nC and D are automatically truthtellers, since they both told the truth when they said A was lying. E is also a truthteller since he said that D told the truth.\n\r\nTherefore, C owns the wallet.\n<|im_end|>" }, { "id": "#8878", "title": "Breaking the Billiard Ball", "fun": 2.81, "difficulty": 2.91, "author": "lesternoronha1", "desc": "It is your task to determine how high you can drop a billiard ball without it breaking. There is a 100 story building and you must determine which is the highest floor you can drop a ball from without it breaking. You have only two billiard balls to use as test objects. If both of them break before you determine the answer then you have failed at your task. What is the order of floors that you should drop the balls from to minimize the number of droppings that you will have to make to determine the answer?\n\r\nAssume that if a ball doesn't break you can reuse it without worrying about it being weakened.", "hint": "No hint available.", "answer": "If the proper order is chosen, you can determine the breaking point with a maximum of 14 drops. Here's how to do it:\n\r\nFirst drop the first ball from the 14th floor. If it breaks you can determine the exact breaking point with the other ball in at most 13 more droppings, starting at the bottom and going up one floor at a time. \r\nIf the first ball survives the 14 floor drop then drop it again from the 27th (14+13) floor. If it breaks you can determine the exact breaking point with at most 12 more droppings. \r\nIf the first ball survives the 27 floor drop then drop it again from the 39th (14+13+12) floor. If it breaks you can determine the exact breaking point with at most 11 more droppings. \r\nKeep repeating this process always going up one less floor than the last dropping until the first ball breaks. If it breaks on the xth dropping you will only need at most 14-x more droppings with the second ball to find the breaking point. By the 11th dropping of the first ball, if you get that far, you will have reached the 99th floor.", "category": "Logic", "date": "12/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is your task to determine how high you can drop a billiard ball without it breaking. There is a 100 story building and you must determine which is the highest floor you can drop a ball from without it breaking. You have only two billiard balls to use as test objects. If both of them break before you determine the answer then you have failed at your task. What is the order of floors that you should drop the balls from to minimize the number of droppings that you will have to make to determine the answer?\n\r\nAssume that if a ball doesn't break you can reuse it without worrying about it being weakened.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the proper order is chosen, you can determine the breaking point with a maximum of 14 drops. Here's how to do it:\n\r\nFirst drop the first ball from the 14th floor. If it breaks you can determine the exact breaking point with the other ball in at most 13 more droppings, starting at the bottom and going up one floor at a time. \r\nIf the first ball survives the 14 floor drop then drop it again from the 27th (14+13) floor. If it breaks you can determine the exact breaking point with at most 12 more droppings. \r\nIf the first ball survives the 27 floor drop then drop it again from the 39th (14+13+12) floor. If it breaks you can determine the exact breaking point with at most 11 more droppings. \r\nKeep repeating this process always going up one less floor than the last dropping until the first ball breaks. If it breaks on the xth dropping you will only need at most 14-x more droppings with the second ball to find the breaking point. By the 11th dropping of the first ball, if you get that far, you will have reached the 99th floor.\n<|im_start|>answer\nIf the proper order is chosen, you can determine the breaking point with a maximum of 14 drops. Here's how to do it:\n\r\nFirst drop the first ball from the 14th floor. If it breaks you can determine the exact breaking point with the other ball in at most 13 more droppings, starting at the bottom and going up one floor at a time. \r\nIf the first ball survives the 14 floor drop then drop it again from the 27th (14+13) floor. If it breaks you can determine the exact breaking point with at most 12 more droppings. \r\nIf the first ball survives the 27 floor drop then drop it again from the 39th (14+13+12) floor. If it breaks you can determine the exact breaking point with at most 11 more droppings. \r\nKeep repeating this process always going up one less floor than the last dropping until the first ball breaks. If it breaks on the xth dropping you will only need at most 14-x more droppings with the second ball to find the breaking point. By the 11th dropping of the first ball, if you get that far, you will have reached the 99th floor.\n<|im_end|>" }, { "id": "#24112", "title": "Kittens And Kids", "fun": 2.81, "difficulty": 0.78, "author": "Palsha", "desc": "Four kittens weigh four pounds together, but they don't weigh one pound each. No, no, that would make this puzzle too easy for such a smart person as you! Two of the kittens weigh less than a pound and two of them weigh more than a pound. Four kids come along and take the four kittens. Makes sense, the kittens being really cute and all! So, see if you can figure out which kid takes which kitten and how much each one weighs (no, not the kids... the kittens) from the clues presented below.\n\r\n1) Catapult weighs more than the kitten taken by Martha.\r\n2) The kitten that weighs 17 oz. is not Bandit.\r\n3) Codi weighs just under a pound but is not the lightest.\r\n4) Kurt's kitten is not Bandit.\r\n5) Ted's kitten is not the largest, but weighs over a pound.\r\n6) Hallie weighs less than Codi.\r\n7) Martha's kitten weighs 14 oz.", "hint": "No hint available.", "answer": "1) Martha gets Codi, who weighs 14 oz.\r\n2) Pam gets Bandit, who weighs 20 oz.\r\n3) Kurt gets Hallie, who weighs 13 oz.\r\n4) Ted gets Catapult, who weighs 17 oz.", "category": "Logic-Grid", "date": "06/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour kittens weigh four pounds together, but they don't weigh one pound each. No, no, that would make this puzzle too easy for such a smart person as you! Two of the kittens weigh less than a pound and two of them weigh more than a pound. Four kids come along and take the four kittens. Makes sense, the kittens being really cute and all! So, see if you can figure out which kid takes which kitten and how much each one weighs (no, not the kids... the kittens) from the clues presented below.\n\r\n1) Catapult weighs more than the kitten taken by Martha.\r\n2) The kitten that weighs 17 oz. is not Bandit.\r\n3) Codi weighs just under a pound but is not the lightest.\r\n4) Kurt's kitten is not Bandit.\r\n5) Ted's kitten is not the largest, but weighs over a pound.\r\n6) Hallie weighs less than Codi.\r\n7) Martha's kitten weighs 14 oz.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Martha gets Codi, who weighs 14 oz.\r\n2) Pam gets Bandit, who weighs 20 oz.\r\n3) Kurt gets Hallie, who weighs 13 oz.\r\n4) Ted gets Catapult, who weighs 17 oz.\n<|im_start|>answer\n1) Martha gets Codi, who weighs 14 oz.\r\n2) Pam gets Bandit, who weighs 20 oz.\r\n3) Kurt gets Hallie, who weighs 13 oz.\r\n4) Ted gets Catapult, who weighs 17 oz.\n<|im_end|>" }, { "id": "#52345", "title": "Pub Regulars", "fun": 2.81, "difficulty": 2.81, "author": "wimpykidfan37", "desc": "Edgar, Frank, and George are regulars at a pub. All three of them have been regulars since before this month.\n\r\n1. One regular goes to the pub every two days, one goes every three days, and one goes every seven days.\n\r\n2. The first day of a certain month that Edgar went to the bar was a Monday. The first day of the same month that Frank went to the bar was a Wednesday. The first day of the same month that George went to the bar was a Friday.\n\r\n3. There was only one day in that month that all three men went to the pub.\n\r\nOn which day of that month did all three men go to the bar?", "hint": "No hint available.", "answer": "All three men went on the 27th.\n\r\nFrom fact 1, the first day the two-day man went to the pub was either the 1st or the 2nd of the month, and the first day the three-day man went was either the 1st, 2nd, or 3rd. But from fact 2, they could not have gone on consecutive days, so from fact 3, the two-day man must have first gone on the 1st and the three-day man must have first gone on the 3rd. This gives us two possible scenarios:\n\r\n1. Edgar went to the pub on Monday the 1st and every two days thereafter, Frank went on Wednesday the 3rd and every three days thereafter, and George went on Friday the 5th and every seven days thereafter.\n\r\n2. Frank went on Wednesday the 1st and every two days thereafter, George went on Friday the 3rd and every three days thereafter, and Edgar went on Monday the 6th and every seven days thereafter.\n\r\nIf scenario 1 is true, then Edgar went on the 1st, 3rd, 5th, 7th, 9th, 11th, 13th, 15th, 17th, 19th, 21st, 23rd, 25th, 27th, and, depending on the length of the month, the 29th and 31st, Frank went on the 3rd, 6th, 9th, 12th, 15th, 18th, 21st, 24th, 27th, and depending on the length of the month, the 30th, and George went on the 5th, 12th, 19th, and 26th. But now there was no day when all three men went to the pub. So this cannot work.\n\r\nThis means that scenario 2 is true. Edgar went on the 6th, 13th, 20th, and 27th. Frank went on the 1st, 3rd, 5th, 7th, 9th, 11th, 13th, 15th, 17th, 19th, 21st, 23rd, 25th, 27th, and, depending on the length of the month, the 29th and 31st. George went on the 3rd, 6th, 9th, 12th, 15th, 18th, 21st, 24th, 27th, and depending on the length of the month, the 30th. So all three men went on the 27th.", "category": "Logic", "date": "01/19/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEdgar, Frank, and George are regulars at a pub. All three of them have been regulars since before this month.\n\r\n1. One regular goes to the pub every two days, one goes every three days, and one goes every seven days.\n\r\n2. The first day of a certain month that Edgar went to the bar was a Monday. The first day of the same month that Frank went to the bar was a Wednesday. The first day of the same month that George went to the bar was a Friday.\n\r\n3. There was only one day in that month that all three men went to the pub.\n\r\nOn which day of that month did all three men go to the bar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll three men went on the 27th.\n\r\nFrom fact 1, the first day the two-day man went to the pub was either the 1st or the 2nd of the month, and the first day the three-day man went was either the 1st, 2nd, or 3rd. But from fact 2, they could not have gone on consecutive days, so from fact 3, the two-day man must have first gone on the 1st and the three-day man must have first gone on the 3rd. This gives us two possible scenarios:\n\r\n1. Edgar went to the pub on Monday the 1st and every two days thereafter, Frank went on Wednesday the 3rd and every three days thereafter, and George went on Friday the 5th and every seven days thereafter.\n\r\n2. Frank went on Wednesday the 1st and every two days thereafter, George went on Friday the 3rd and every three days thereafter, and Edgar went on Monday the 6th and every seven days thereafter.\n\r\nIf scenario 1 is true, then Edgar went on the 1st, 3rd, 5th, 7th, 9th, 11th, 13th, 15th, 17th, 19th, 21st, 23rd, 25th, 27th, and, depending on the length of the month, the 29th and 31st, Frank went on the 3rd, 6th, 9th, 12th, 15th, 18th, 21st, 24th, 27th, and depending on the length of the month, the 30th, and George went on the 5th, 12th, 19th, and 26th. But now there was no day when all three men went to the pub. So this cannot work.\n\r\nThis means that scenario 2 is true. Edgar went on the 6th, 13th, 20th, and 27th. Frank went on the 1st, 3rd, 5th, 7th, 9th, 11th, 13th, 15th, 17th, 19th, 21st, 23rd, 25th, 27th, and, depending on the length of the month, the 29th and 31st. George went on the 3rd, 6th, 9th, 12th, 15th, 18th, 21st, 24th, 27th, and depending on the length of the month, the 30th. So all three men went on the 27th.\n<|im_start|>answer\nAll three men went on the 27th.\n\r\nFrom fact 1, the first day the two-day man went to the pub was either the 1st or the 2nd of the month, and the first day the three-day man went was either the 1st, 2nd, or 3rd. But from fact 2, they could not have gone on consecutive days, so from fact 3, the two-day man must have first gone on the 1st and the three-day man must have first gone on the 3rd. This gives us two possible scenarios:\n\r\n1. Edgar went to the pub on Monday the 1st and every two days thereafter, Frank went on Wednesday the 3rd and every three days thereafter, and George went on Friday the 5th and every seven days thereafter.\n\r\n2. Frank went on Wednesday the 1st and every two days thereafter, George went on Friday the 3rd and every three days thereafter, and Edgar went on Monday the 6th and every seven days thereafter.\n\r\nIf scenario 1 is true, then Edgar went on the 1st, 3rd, 5th, 7th, 9th, 11th, 13th, 15th, 17th, 19th, 21st, 23rd, 25th, 27th, and, depending on the length of the month, the 29th and 31st, Frank went on the 3rd, 6th, 9th, 12th, 15th, 18th, 21st, 24th, 27th, and depending on the length of the month, the 30th, and George went on the 5th, 12th, 19th, and 26th. But now there was no day when all three men went to the pub. So this cannot work.\n\r\nThis means that scenario 2 is true. Edgar went on the 6th, 13th, 20th, and 27th. Frank went on the 1st, 3rd, 5th, 7th, 9th, 11th, 13th, 15th, 17th, 19th, 21st, 23rd, 25th, 27th, and, depending on the length of the month, the 29th and 31st. George went on the 3rd, 6th, 9th, 12th, 15th, 18th, 21st, 24th, 27th, and depending on the length of the month, the 30th. So all three men went on the 27th.\n<|im_end|>" }, { "id": "#6923", "title": "Brave Sailors", "fun": 2.81, "difficulty": 1.97, "author": "majd", "desc": "We are brave sailors always riding the sea\r\nWe are less than one hundred but as tough as can be\r\nWe sleep in three bunkers on top of each other\r\nOur numbers double from one bunker to another\r\nWe dance in joy all through the night\r\nIn groups of fives under the moonlight\r\nLast night twelve of us were swallowed by waves\r\nLeaving alive more than two third of the braves\r\nStill we continue the journey refusing to fail\r\nSo tell me how many of us are left to sail?", "hint": "No hint available.", "answer": "58 sailors are left.\n\r\n1. From line 2: Total number of sailors is <100.\r\n2. From lines 3 & 4: Let number of sailors sleeping in bunker 1 be X, then number of sailors sleeping in bunker 2 is 2X and in bunker 3 is 4X, \r\ni.e. Total number of sailors = X+2X+4X = 7X and thus it is a multiple of 7.\r\n3. From line 6: dancing in groups of fives means the total number is a product of 5.\r\n4. From lines 7 & 8: 12 of the sailors drowned in the sea, leaving more than two third of the sailors alive, so the total number is > 36 (3 * 12).\n\r\nSumming up all the above given information, the total number of sailors is <100 and >36, it divides by 7 and 5, which adds up to the total number of 70 sailors.\n\r\nSince 12 of the 70 sailors died in the sea, there are 58 sailors left to continue the journey.", "category": "Math", "date": "08/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWe are brave sailors always riding the sea\r\nWe are less than one hundred but as tough as can be\r\nWe sleep in three bunkers on top of each other\r\nOur numbers double from one bunker to another\r\nWe dance in joy all through the night\r\nIn groups of fives under the moonlight\r\nLast night twelve of us were swallowed by waves\r\nLeaving alive more than two third of the braves\r\nStill we continue the journey refusing to fail\r\nSo tell me how many of us are left to sail?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n58 sailors are left.\n\r\n1. From line 2: Total number of sailors is <100.\r\n2. From lines 3 & 4: Let number of sailors sleeping in bunker 1 be X, then number of sailors sleeping in bunker 2 is 2X and in bunker 3 is 4X, \r\ni.e. Total number of sailors = X+2X+4X = 7X and thus it is a multiple of 7.\r\n3. From line 6: dancing in groups of fives means the total number is a product of 5.\r\n4. From lines 7 & 8: 12 of the sailors drowned in the sea, leaving more than two third of the sailors alive, so the total number is > 36 (3 * 12).\n\r\nSumming up all the above given information, the total number of sailors is <100 and >36, it divides by 7 and 5, which adds up to the total number of 70 sailors.\n\r\nSince 12 of the 70 sailors died in the sea, there are 58 sailors left to continue the journey.\n<|im_start|>answer\n58 sailors are left.\n\r\n1. From line 2: Total number of sailors is <100.\r\n2. From lines 3 & 4: Let number of sailors sleeping in bunker 1 be X, then number of sailors sleeping in bunker 2 is 2X and in bunker 3 is 4X, \r\ni.e. Total number of sailors = X+2X+4X = 7X and thus it is a multiple of 7.\r\n3. From line 6: dancing in groups of fives means the total number is a product of 5.\r\n4. From lines 7 & 8: 12 of the sailors drowned in the sea, leaving more than two third of the sailors alive, so the total number is > 36 (3 * 12).\n\r\nSumming up all the above given information, the total number of sailors is <100 and >36, it divides by 7 and 5, which adds up to the total number of 70 sailors.\n\r\nSince 12 of the 70 sailors died in the sea, there are 58 sailors left to continue the journey.\n<|im_end|>" }, { "id": "#22711", "title": "Portraits", "fun": 2.81, "difficulty": 2.43, "author": "cdrock", "desc": "There were 9 portraits of animals (bear, cat, dog, hamster, horse, lion, monkey, mouse, and tiger) on a wall of a museum. As I was studying them, I tripped and fell into the wall and they all fell down. I have to get them back up on the wall in the correct order before I get into some serious trouble. I only remember a couple of things about the order of the portraits. Can you help me figure out the order of the portraits using the clues I remember about them?\n\r\nThey were displayed as follows:\n\r\nNote: The Letter and Numbers in the graph are labels for their corresponding rows.\n\r\n...........A...............B.............C\n\n\r\n1 _________ l _________ l _________\n\n\r\n2 _________ l _________ l _________\n\n\r\n3 _________ l _________ l _________\n\r\nClues:\n\r\n1. The bear is in the same row as the hamster.\n\r\n2. Two portraits in both rows 3 and C have two animals that start with the same letter.\n\r\n3. The horse is in the same row as the monkey.\n\r\n4. The dog is in 2A.\n\r\n5. Either the lion or the tiger is below the cat.\n\r\n6. The monkey is either above or below the dog.\n\r\n7. The dog is not next to the tiger.", "hint": "No hint available.", "answer": "bear l cat l hamster\r\ndog l lion l tiger\r\nmonkey l mouse l horse", "category": "Logic", "date": "05/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 9 portraits of animals (bear, cat, dog, hamster, horse, lion, monkey, mouse, and tiger) on a wall of a museum. As I was studying them, I tripped and fell into the wall and they all fell down. I have to get them back up on the wall in the correct order before I get into some serious trouble. I only remember a couple of things about the order of the portraits. Can you help me figure out the order of the portraits using the clues I remember about them?\n\r\nThey were displayed as follows:\n\r\nNote: The Letter and Numbers in the graph are labels for their corresponding rows.\n\r\n...........A...............B.............C\n\n\r\n1 _________ l _________ l _________\n\n\r\n2 _________ l _________ l _________\n\n\r\n3 _________ l _________ l _________\n\r\nClues:\n\r\n1. The bear is in the same row as the hamster.\n\r\n2. Two portraits in both rows 3 and C have two animals that start with the same letter.\n\r\n3. The horse is in the same row as the monkey.\n\r\n4. The dog is in 2A.\n\r\n5. Either the lion or the tiger is below the cat.\n\r\n6. The monkey is either above or below the dog.\n\r\n7. The dog is not next to the tiger.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nbear l cat l hamster\r\ndog l lion l tiger\r\nmonkey l mouse l horse\n<|im_start|>answer\nbear l cat l hamster\r\ndog l lion l tiger\r\nmonkey l mouse l horse\n<|im_end|>" }, { "id": "#3101", "title": "The Bar of Gold", "fun": 2.81, "difficulty": 2.28, "author": "Hookfree", "desc": "A worker is to perform work for you for seven straight days. In return for his work, you will pay him 1/7th of a bar of gold per day. The worker requires a daily payment of 1/7th of the bar of gold. What and where are the fewest number of cuts to the bar of gold that will allow you to pay him 1/7th each day?", "hint": "Only two cuts are required.", "answer": "Day One: You make your first cut at the 1/7th mark and give that to the worker.\r\nDay Two: You cut 2/7ths and pay that to the worker and receive the original 1/7th in change.\r\nDay three: You give the worker the 1/7th you received as change on the previous day.\r\nDay four: You give the worker 4/7ths and he returns his 1/7th cut and his 2/7th cut as change.\r\nDay Five: You give the worker back the 1/7th cut of gold.\r\nDay Six: You give the worker the 2/7th cut and receive the 1/7th cut back in change.\r\nDay Seven: You pay the worker his final 1/7th. \n\r\nEveryone is happy.", "category": "Math", "date": "04/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA worker is to perform work for you for seven straight days. In return for his work, you will pay him 1/7th of a bar of gold per day. The worker requires a daily payment of 1/7th of the bar of gold. What and where are the fewest number of cuts to the bar of gold that will allow you to pay him 1/7th each day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDay One: You make your first cut at the 1/7th mark and give that to the worker.\r\nDay Two: You cut 2/7ths and pay that to the worker and receive the original 1/7th in change.\r\nDay three: You give the worker the 1/7th you received as change on the previous day.\r\nDay four: You give the worker 4/7ths and he returns his 1/7th cut and his 2/7th cut as change.\r\nDay Five: You give the worker back the 1/7th cut of gold.\r\nDay Six: You give the worker the 2/7th cut and receive the 1/7th cut back in change.\r\nDay Seven: You pay the worker his final 1/7th. \n\r\nEveryone is happy.\n<|im_start|>answer\nDay One: You make your first cut at the 1/7th mark and give that to the worker.\r\nDay Two: You cut 2/7ths and pay that to the worker and receive the original 1/7th in change.\r\nDay three: You give the worker the 1/7th you received as change on the previous day.\r\nDay four: You give the worker 4/7ths and he returns his 1/7th cut and his 2/7th cut as change.\r\nDay Five: You give the worker back the 1/7th cut of gold.\r\nDay Six: You give the worker the 2/7th cut and receive the 1/7th cut back in change.\r\nDay Seven: You pay the worker his final 1/7th. \n\r\nEveryone is happy.\n<|im_end|>" }, { "id": "#44029", "title": "Eliza Pseudonym and The Middle-Aged and the Narcoleptic", "fun": 2.81, "difficulty": 2.82, "author": "mathgrant", "desc": "Eliza Pseudonym is an avid watcher of the daytime soap opera \"The Middle-Aged and the Narcoleptic\". A recent five-day period from Monday through Friday has had quite a lot of plot development! Each day's episode featured one of five characters (Harmony, Irene, Jake, Kit, and Lee) sharing a different secret with one of the other five characters. Over the course of the week, each character had divulged one secret, and learned one secret. From the clues below, determine which character confessed a secret on each episode, which character learned the secret, and what each secret was.\n\r\n1. The episode on which Irene revealed a secret (which wasn't Monday's episode) aired either two days before or two days after the episode on which was heard the line, \"It was I who ate your last oatmeal raisin cookie. Forgive me, Kit. . . .\"\r\n2. Harmony is not the character who admitted, \"I wouldn't want to let the others know, but I feel like I have to be honest with you. . . my two favorite video games are 'Mario is Missing!' and 'E.T.' for the Atari.\"\r\n3. Jake sobbed, \"I dare not tell my wife, because it'd threaten our marriage, but when she's not around, I like to read. . . this is embarrassing. . . Sudoku magazines!\" sometime before Irene learned a secret, but sometime after Lee learned a secret; these three episodes were not aired on three consecutive days.\r\n4. Irene is not the character who was told the shocking words, \"The neighborhood kids didn't toilet paper your house last week. I. . . I DID IT! I'M SORRY!\"\r\n5. The episode on which Kit told a secret and the episode where a character said, \"Please don't judge me for what I'm about to tell you, but. . . I listen to country music and rap music. . .\" were aired consecutively, in some order.\r\n6. On Thursday's episode, a character entrusted his or her secret to Harmony.", "hint": "No hint available.", "answer": "Monday: Harmony told Kit about a cookie\r\nTuesday: Kit told Lee about toilet paper\r\nWednesday: Irene told Jake about country/rap\r\nThursday: Jake told Harmony about Sudoku\r\nFriday: Lee told Irene about \"Mario is Missing\"/\"E.T.\"", "category": "Logic-Grid", "date": "02/03/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEliza Pseudonym is an avid watcher of the daytime soap opera \"The Middle-Aged and the Narcoleptic\". A recent five-day period from Monday through Friday has had quite a lot of plot development! Each day's episode featured one of five characters (Harmony, Irene, Jake, Kit, and Lee) sharing a different secret with one of the other five characters. Over the course of the week, each character had divulged one secret, and learned one secret. From the clues below, determine which character confessed a secret on each episode, which character learned the secret, and what each secret was.\n\r\n1. The episode on which Irene revealed a secret (which wasn't Monday's episode) aired either two days before or two days after the episode on which was heard the line, \"It was I who ate your last oatmeal raisin cookie. Forgive me, Kit. . . .\"\r\n2. Harmony is not the character who admitted, \"I wouldn't want to let the others know, but I feel like I have to be honest with you. . . my two favorite video games are 'Mario is Missing!' and 'E.T.' for the Atari.\"\r\n3. Jake sobbed, \"I dare not tell my wife, because it'd threaten our marriage, but when she's not around, I like to read. . . this is embarrassing. . . Sudoku magazines!\" sometime before Irene learned a secret, but sometime after Lee learned a secret; these three episodes were not aired on three consecutive days.\r\n4. Irene is not the character who was told the shocking words, \"The neighborhood kids didn't toilet paper your house last week. I. . . I DID IT! I'M SORRY!\"\r\n5. The episode on which Kit told a secret and the episode where a character said, \"Please don't judge me for what I'm about to tell you, but. . . I listen to country music and rap music. . .\" were aired consecutively, in some order.\r\n6. On Thursday's episode, a character entrusted his or her secret to Harmony.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday: Harmony told Kit about a cookie\r\nTuesday: Kit told Lee about toilet paper\r\nWednesday: Irene told Jake about country/rap\r\nThursday: Jake told Harmony about Sudoku\r\nFriday: Lee told Irene about \"Mario is Missing\"/\"E.T.\"\n<|im_start|>answer\nMonday: Harmony told Kit about a cookie\r\nTuesday: Kit told Lee about toilet paper\r\nWednesday: Irene told Jake about country/rap\r\nThursday: Jake told Harmony about Sudoku\r\nFriday: Lee told Irene about \"Mario is Missing\"/\"E.T.\"\n<|im_end|>" }, { "id": "#23713", "title": "Circle of Children", "fun": 2.81, "difficulty": 1.24, "author": "sk8ergrl", "desc": "A number of children are standing in a circle. They are evenly spaced and the 7th child is directly opposite the 18th child. How many children are there altogether?", "hint": "How many children are in half of the circle?", "answer": "22; in half of the circle there are 11 children because 18-7=11. Multiply 11x2=22!", "category": "Math", "date": "06/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA number of children are standing in a circle. They are evenly spaced and the 7th child is directly opposite the 18th child. How many children are there altogether?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n22; in half of the circle there are 11 children because 18-7=11. Multiply 11x2=22!\n<|im_start|>answer\n22; in half of the circle there are 11 children because 18-7=11. Multiply 11x2=22!\n<|im_end|>" }, { "id": "#40504", "title": "The Old Switch-A-Roo", "fun": 2.81, "difficulty": 1.77, "author": "niveknedarb", "desc": "Stan is applying for a job with a high paying electrician known to hire people who can think outside of the box. He tells Stan that if he can solve a particular problem, he will get the job. The boss puts Stan outside the door to a room from which light cannot escape. Inside the room is a lamp. On the wall next to Stan are four switches, one of which works the lamp, the other three do nothing. Stan needs to figure out which switch works the lamp, but the boss has taken away all of his tools. He has told Stan that he may flip the switches to his heart's content, but he can only open the door to examine the lamp once. What should Stan do with the switches to ensure he gets the job?", "hint": "Light bulbs BURN brightly", "answer": "Stan flips switch \"1\" on for one minute then turns it off. He then flips switch \"2\" on for a few seconds then turns it off. Then he flips switch \"4\" on and opens the door. If the lamp is off and the bulb is hot, then he knows it was switch \"1\". If it's off and the bulb is warm then he knows it was switch \"2\". If it's off and cold, then it was switch \"3\". And obviously if it's on then it's switch \"4\".", "category": "Logic", "date": "02/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStan is applying for a job with a high paying electrician known to hire people who can think outside of the box. He tells Stan that if he can solve a particular problem, he will get the job. The boss puts Stan outside the door to a room from which light cannot escape. Inside the room is a lamp. On the wall next to Stan are four switches, one of which works the lamp, the other three do nothing. Stan needs to figure out which switch works the lamp, but the boss has taken away all of his tools. He has told Stan that he may flip the switches to his heart's content, but he can only open the door to examine the lamp once. What should Stan do with the switches to ensure he gets the job?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStan flips switch \"1\" on for one minute then turns it off. He then flips switch \"2\" on for a few seconds then turns it off. Then he flips switch \"4\" on and opens the door. If the lamp is off and the bulb is hot, then he knows it was switch \"1\". If it's off and the bulb is warm then he knows it was switch \"2\". If it's off and cold, then it was switch \"3\". And obviously if it's on then it's switch \"4\".\n<|im_start|>answer\nStan flips switch \"1\" on for one minute then turns it off. He then flips switch \"2\" on for a few seconds then turns it off. Then he flips switch \"4\" on and opens the door. If the lamp is off and the bulb is hot, then he knows it was switch \"1\". If it's off and the bulb is warm then he knows it was switch \"2\". If it's off and cold, then it was switch \"3\". And obviously if it's on then it's switch \"4\".\n<|im_end|>" }, { "id": "#44774", "title": "High Country Vacation", "fun": 2.81, "difficulty": 1.94, "author": "mrsfessler", "desc": "The Fun Family, Mom, Dad, and three children, enjoyed a weeklong vacation in the mountains of the High Country of North Carolina. Although they all enjoyed everything they did and saw, each (one is Farah) had his or her own favorite activity and tourist sight. From the clues below, determine each family member's age (15,17,19,42 or 44), their favorite activity and their favorite sight.\n\r\n1. The 5 family members are Felix, the 19 year old daughter, the fan of canoeing, the one who preferred the Blowing Rock, and the female who loved driving along the Blue Ridge Parkway (BRP) looking at the scenery.\n\r\n2. The one who favored equestrian activities is 2 years older than Fred. The one who enjoyed hiking the most is older than her brother, but younger than Faith.\n\r\n3. The two that preferred ziplining and whitewater rafting are in some order the 15 year old and the one who loved the campus of Appalachian State University.\n\r\n4. The oldest and the youngest are, in some order, Fran and the one who preferred to sight see from the car.\n\r\n5. The 3 females are the oldest, the youngest and the one who liked Mast General Store the best. The 2 males are the ones who preferred Grandfather Mountain and whitewater rafting.", "hint": "equestrian = horseback riding\r\nASU = Appalachian State University\r\nFred is the Dad\r\nFaith is the Mom", "answer": "Fred, 42, canoing, Grandfather Mountain\r\nFran, 15, ziplining, The Blowing Rock\r\nFelix, 17, whitewater rafting, Appalachian State University\r\nFarah, 19, hiking, Mast General Store\r\nFaith, 44, horseback riding, Blue Ridge Parkway", "category": "Logic-Grid", "date": "07/01/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Fun Family, Mom, Dad, and three children, enjoyed a weeklong vacation in the mountains of the High Country of North Carolina. Although they all enjoyed everything they did and saw, each (one is Farah) had his or her own favorite activity and tourist sight. From the clues below, determine each family member's age (15,17,19,42 or 44), their favorite activity and their favorite sight.\n\r\n1. The 5 family members are Felix, the 19 year old daughter, the fan of canoeing, the one who preferred the Blowing Rock, and the female who loved driving along the Blue Ridge Parkway (BRP) looking at the scenery.\n\r\n2. The one who favored equestrian activities is 2 years older than Fred. The one who enjoyed hiking the most is older than her brother, but younger than Faith.\n\r\n3. The two that preferred ziplining and whitewater rafting are in some order the 15 year old and the one who loved the campus of Appalachian State University.\n\r\n4. The oldest and the youngest are, in some order, Fran and the one who preferred to sight see from the car.\n\r\n5. The 3 females are the oldest, the youngest and the one who liked Mast General Store the best. The 2 males are the ones who preferred Grandfather Mountain and whitewater rafting.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFred, 42, canoing, Grandfather Mountain\r\nFran, 15, ziplining, The Blowing Rock\r\nFelix, 17, whitewater rafting, Appalachian State University\r\nFarah, 19, hiking, Mast General Store\r\nFaith, 44, horseback riding, Blue Ridge Parkway\n<|im_start|>answer\nFred, 42, canoing, Grandfather Mountain\r\nFran, 15, ziplining, The Blowing Rock\r\nFelix, 17, whitewater rafting, Appalachian State University\r\nFarah, 19, hiking, Mast General Store\r\nFaith, 44, horseback riding, Blue Ridge Parkway\n<|im_end|>" }, { "id": "#17497", "title": "Be Creative", "fun": 2.81, "difficulty": 1.93, "author": "fishmed", "desc": "Using one sheet of paper (8&1/2 by 11 inches), support a heavy hardcover book 1 inch above a tabletop. You may use this one sheet of paper, scissors, a pencil and tape only. Once you are done, only the paper may hold up the book.", "hint": "I did not use a full sheet of paper. Try it first.", "answer": "Cut the paper into six strips, 1 inch wide by 11 inches long. Wind each strip around a pencil to make a tight cylinder. Slide the cylinder off the pencil and fasten with a small piece of tape. Finally, stand all 6 cylinders on their ends in a cross arrangement, with 4 at the corners of the intended book and two in the center of book, side by side, along the long axis of the book. Lay the book on its side on top of this arrangement. It will hold the book one inch off the tabletop. \n\r\n(FYI, when I did this, it held 35 large books before the paper tubes collapsed.)", "category": "Logic", "date": "04/27/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing one sheet of paper (8&1/2 by 11 inches), support a heavy hardcover book 1 inch above a tabletop. You may use this one sheet of paper, scissors, a pencil and tape only. Once you are done, only the paper may hold up the book.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCut the paper into six strips, 1 inch wide by 11 inches long. Wind each strip around a pencil to make a tight cylinder. Slide the cylinder off the pencil and fasten with a small piece of tape. Finally, stand all 6 cylinders on their ends in a cross arrangement, with 4 at the corners of the intended book and two in the center of book, side by side, along the long axis of the book. Lay the book on its side on top of this arrangement. It will hold the book one inch off the tabletop. \n\r\n(FYI, when I did this, it held 35 large books before the paper tubes collapsed.)\n<|im_start|>answer\nCut the paper into six strips, 1 inch wide by 11 inches long. Wind each strip around a pencil to make a tight cylinder. Slide the cylinder off the pencil and fasten with a small piece of tape. Finally, stand all 6 cylinders on their ends in a cross arrangement, with 4 at the corners of the intended book and two in the center of book, side by side, along the long axis of the book. Lay the book on its side on top of this arrangement. It will hold the book one inch off the tabletop. \n\r\n(FYI, when I did this, it held 35 large books before the paper tubes collapsed.)\n<|im_end|>" }, { "id": "#4832", "title": "Family Reunion", "fun": 2.81, "difficulty": 2.18, "author": "bobbrt", "desc": "The following statements were made by each of five people at a family reunion. They are each referring to one of the other four people (in other words the person being referred to in the first statement, Claire, is making one of the other statements). Can you determine who made each statement? Assume that all parents are married and that all married couples are heterosexual, married only once, still married, and attending together.\n\r\n1. \"Claire is my sister-in-law.\"\r\n2. \"Susan is my wife.\"\r\n3. \"Roger is my father.\"\r\n4. \"Melissa is my niece.\"\r\n5. \"Danielle is my only sibling.\"", "hint": "No hint available.", "answer": "1. Susan\r\n2. Roger\r\n3. Danielle\r\n4. Claire\r\n5. Melissa\n\r\nExplanation:\r\nStatement 2 has to be spoken by Roger, since he is the only man.\r\nSince there is only one marriage implied here, Statement 1 must be made by Susan, Roger's wife, making Claire Roger's sister. \r\nClaire must be the one referring to her niece Melissa in Statement 4. Melissa could say Statement 3, but that would leave Danielle referring to herself in Statement 5. Therefore Melissa says Statement 5 and Danielle says Statement 3.", "category": "Logic", "date": "06/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following statements were made by each of five people at a family reunion. They are each referring to one of the other four people (in other words the person being referred to in the first statement, Claire, is making one of the other statements). Can you determine who made each statement? Assume that all parents are married and that all married couples are heterosexual, married only once, still married, and attending together.\n\r\n1. \"Claire is my sister-in-law.\"\r\n2. \"Susan is my wife.\"\r\n3. \"Roger is my father.\"\r\n4. \"Melissa is my niece.\"\r\n5. \"Danielle is my only sibling.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Susan\r\n2. Roger\r\n3. Danielle\r\n4. Claire\r\n5. Melissa\n\r\nExplanation:\r\nStatement 2 has to be spoken by Roger, since he is the only man.\r\nSince there is only one marriage implied here, Statement 1 must be made by Susan, Roger's wife, making Claire Roger's sister. \r\nClaire must be the one referring to her niece Melissa in Statement 4. Melissa could say Statement 3, but that would leave Danielle referring to herself in Statement 5. Therefore Melissa says Statement 5 and Danielle says Statement 3.\n<|im_start|>answer\n1. Susan\r\n2. Roger\r\n3. Danielle\r\n4. Claire\r\n5. Melissa\n\r\nExplanation:\r\nStatement 2 has to be spoken by Roger, since he is the only man.\r\nSince there is only one marriage implied here, Statement 1 must be made by Susan, Roger's wife, making Claire Roger's sister. \r\nClaire must be the one referring to her niece Melissa in Statement 4. Melissa could say Statement 3, but that would leave Danielle referring to herself in Statement 5. Therefore Melissa says Statement 5 and Danielle says Statement 3.\n<|im_end|>" }, { "id": "#45261", "title": "Mr. and Mrs. Crazy: Petrol Shortage", "fun": 2.81, "difficulty": 1.97, "author": "CaIceDevil", "desc": "Recently Mr. And Mrs. Crazy have heard the news about the petrol shortage. The king has introduced to the villagers petrol rationing according to the following system, based on the 3-digit number of each number-plate (000 to 999) of the cars in the village.\n\r\nPeople could only buy petrol on certain days as follows:\r\nSunday: if each of the three digits was less than 6\r\nMonday: if the 3-digit number was odd\r\nTuesday: if the sum of the three digits was greater than 10\r\nWednesday: if the 3-digit number was a multiple of 3\r\nThursday: if the sum of the three digits was less than 15\r\nFriday: if at least two of the three digits were the same\r\nSaturday: if the 3-digit number was less than 500\n\r\nIf Mr. and Mrs. Crazy could refuel their car on any day of the week, what is the number on their car's number-plate?", "hint": "No hint available.", "answer": "255", "category": "Math", "date": "09/11/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRecently Mr. And Mrs. Crazy have heard the news about the petrol shortage. The king has introduced to the villagers petrol rationing according to the following system, based on the 3-digit number of each number-plate (000 to 999) of the cars in the village.\n\r\nPeople could only buy petrol on certain days as follows:\r\nSunday: if each of the three digits was less than 6\r\nMonday: if the 3-digit number was odd\r\nTuesday: if the sum of the three digits was greater than 10\r\nWednesday: if the 3-digit number was a multiple of 3\r\nThursday: if the sum of the three digits was less than 15\r\nFriday: if at least two of the three digits were the same\r\nSaturday: if the 3-digit number was less than 500\n\r\nIf Mr. and Mrs. Crazy could refuel their car on any day of the week, what is the number on their car's number-plate?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n255\n<|im_start|>answer\n255\n<|im_end|>" }, { "id": "#43284", "title": "Miss Brown Murder", "fun": 2.81, "difficulty": 0.99, "author": "eggface", "desc": "Miss Brown was walking alone in her over-sized house, when suddenly a figure jumped out and killed her. \n\r\n\"It is like a Cluedo case,\" commented Mr. Lombang, a detective. \"Who killed her, what was their weapon, and where did they kill her?\" \n\r\nThe murderer would have been someone staying in Miss Brown's home. Therefore, it is either Mr. Blues, Sir Red, Mr. Whitehall, Countess Marigold, or Miss Pinkham.\n\r\nThe weapons most likely to be used were a candelabra, a dagger, a plumbing piece, an ancient sword, or a piece of rope.\n\r\nThe room in which Miss Brown was murdered was either the lounge, the kitchen, the porch, the hall, or the study.\n\r\nNow the detective Mr. Lombang must figure out who did it based on the following clues. Work out where everyone was: the person in the hall was the murderer.\n\r\n1. Mr. Blues was in the kitchen when Miss Brown was murdered.\r\n2. The person with the sword was in the study the whole time.\r\n3. Countess Marigold wasn't in the hall and didn't have the rope.\r\n4. Both ladies didn't have access to a weapon with a blade.\r\n5. Sir Red was in the study for the evening.\r\n6. There was a magnificent candelabra in Miss Pinkham's room.\r\n7. The person in the kitchen had a dagger.\r\n8. Mr. Whitehall wasn't in the lounge or the porch.\r\n9. The person with the bit of plumbing most accessible was on the porch.", "hint": "No hint available.", "answer": "Mr. Blues was in the kitchen and had the dagger.\r\nSir Red was in the study and had the sword.\r\nMiss Pinkham was in the lounge and had the candelabra.\r\nCountess Marigold was in the porch with the bit of plumbing.\r\nMr. Whitehall was in the hall and had the rope.\n\r\nSo Mr. Whitehall murdered Miss Brown. Congratulations if you solved this, detective!", "category": "Logic-Grid", "date": "10/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMiss Brown was walking alone in her over-sized house, when suddenly a figure jumped out and killed her. \n\r\n\"It is like a Cluedo case,\" commented Mr. Lombang, a detective. \"Who killed her, what was their weapon, and where did they kill her?\" \n\r\nThe murderer would have been someone staying in Miss Brown's home. Therefore, it is either Mr. Blues, Sir Red, Mr. Whitehall, Countess Marigold, or Miss Pinkham.\n\r\nThe weapons most likely to be used were a candelabra, a dagger, a plumbing piece, an ancient sword, or a piece of rope.\n\r\nThe room in which Miss Brown was murdered was either the lounge, the kitchen, the porch, the hall, or the study.\n\r\nNow the detective Mr. Lombang must figure out who did it based on the following clues. Work out where everyone was: the person in the hall was the murderer.\n\r\n1. Mr. Blues was in the kitchen when Miss Brown was murdered.\r\n2. The person with the sword was in the study the whole time.\r\n3. Countess Marigold wasn't in the hall and didn't have the rope.\r\n4. Both ladies didn't have access to a weapon with a blade.\r\n5. Sir Red was in the study for the evening.\r\n6. There was a magnificent candelabra in Miss Pinkham's room.\r\n7. The person in the kitchen had a dagger.\r\n8. Mr. Whitehall wasn't in the lounge or the porch.\r\n9. The person with the bit of plumbing most accessible was on the porch.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Blues was in the kitchen and had the dagger.\r\nSir Red was in the study and had the sword.\r\nMiss Pinkham was in the lounge and had the candelabra.\r\nCountess Marigold was in the porch with the bit of plumbing.\r\nMr. Whitehall was in the hall and had the rope.\n\r\nSo Mr. Whitehall murdered Miss Brown. Congratulations if you solved this, detective!\n<|im_start|>answer\nMr. Blues was in the kitchen and had the dagger.\r\nSir Red was in the study and had the sword.\r\nMiss Pinkham was in the lounge and had the candelabra.\r\nCountess Marigold was in the porch with the bit of plumbing.\r\nMr. Whitehall was in the hall and had the rope.\n\r\nSo Mr. Whitehall murdered Miss Brown. Congratulations if you solved this, detective!\n<|im_end|>" }, { "id": "#39862", "title": "Holiday Bash", "fun": 2.81, "difficulty": 2.14, "author": "pokpic", "desc": "Four people - Sam, Thalia, Victor, and Zach - sent four gifts: a diamond watch, a Best Buy gift card, a computer, and two baseball tickets. The people who received these gifts are named Joe, Jack, Jason, and Jill. Each gift was wrapped in a different color wrapping paper: blue and green, red and white, orange and yellow, and pink. Also, each gift was given at a different location: a bedroom, a restaurant, a living room, and a cruise. From the following clues figure, out who gave what gift, who received the gift, what color wrapping paper the gift was wrapped in, and where the gift was given.\n\r\nPeople: Sam, Thalia, Victor, and Zach\n\r\nGifts: Diamond watch, a Best Buy gift card, a Computer, and baseball tickets\n\r\nPeople who received gifts: Joe, Jill, Jason, Jack\n\r\nWrapping paper colors: Blue and green, red and white, orange and yellow, and pink\n\r\nPlaces: A bedroom, a restaurant, a living room, and a cruise\n\r\nClues:\r\n1. Sam loves his wife Jill and didn't give her her gift at their house.\n\r\n2. The man who gave the diamond watch wrapped the gift in two colors.\n\r\n3. Jason received his gift from his wife at her favorite restaurant, Sushi Island.\n\r\n4. The gift wrapped in orange and yellow wasn't received by a woman and was not received outside of a house.\n\r\n5. The person who gave the baseball tickets knew his best bud would love them.\n\r\n6. Victor was holding a Christmas party where he would give his roommate a Best Buy gift card.\n\r\n7. The guy who gave Joe his gift wrapped it in pink.\n\r\n8. During Jack's Christmas party his bud snuck into his bedroom where he put his orange and yellow wrapped gift on Jack's bed.\n\r\n9. The man who gave the diamond watch thought that the blue and green wrapping paper matched the sapphires and emeralds on the watch.", "hint": "No hint available.", "answer": "Sam gave the diamond watch to his wife Jill. He wrapped the watch in blue and green wrapping paper and gave it to her on a cruise.\n\r\nThalia gave her husband Jason a computer. She wrapped the computer in red and white wrapping paper and gave it to him at a restaurant.\n\r\nVictor gave his best bud Joe a Best Buy gift card. He wrapped the gift card in a pink wrapping paper and gave it to him in his living room.\n\r\nZach gave his best bud Jack baseball tickets. He wrapped the tickets in orange and yellow wrapping paper and snuck the tickets into Jack's bedroom.", "category": "Logic-Grid", "date": "12/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people - Sam, Thalia, Victor, and Zach - sent four gifts: a diamond watch, a Best Buy gift card, a computer, and two baseball tickets. The people who received these gifts are named Joe, Jack, Jason, and Jill. Each gift was wrapped in a different color wrapping paper: blue and green, red and white, orange and yellow, and pink. Also, each gift was given at a different location: a bedroom, a restaurant, a living room, and a cruise. From the following clues figure, out who gave what gift, who received the gift, what color wrapping paper the gift was wrapped in, and where the gift was given.\n\r\nPeople: Sam, Thalia, Victor, and Zach\n\r\nGifts: Diamond watch, a Best Buy gift card, a Computer, and baseball tickets\n\r\nPeople who received gifts: Joe, Jill, Jason, Jack\n\r\nWrapping paper colors: Blue and green, red and white, orange and yellow, and pink\n\r\nPlaces: A bedroom, a restaurant, a living room, and a cruise\n\r\nClues:\r\n1. Sam loves his wife Jill and didn't give her her gift at their house.\n\r\n2. The man who gave the diamond watch wrapped the gift in two colors.\n\r\n3. Jason received his gift from his wife at her favorite restaurant, Sushi Island.\n\r\n4. The gift wrapped in orange and yellow wasn't received by a woman and was not received outside of a house.\n\r\n5. The person who gave the baseball tickets knew his best bud would love them.\n\r\n6. Victor was holding a Christmas party where he would give his roommate a Best Buy gift card.\n\r\n7. The guy who gave Joe his gift wrapped it in pink.\n\r\n8. During Jack's Christmas party his bud snuck into his bedroom where he put his orange and yellow wrapped gift on Jack's bed.\n\r\n9. The man who gave the diamond watch thought that the blue and green wrapping paper matched the sapphires and emeralds on the watch.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSam gave the diamond watch to his wife Jill. He wrapped the watch in blue and green wrapping paper and gave it to her on a cruise.\n\r\nThalia gave her husband Jason a computer. She wrapped the computer in red and white wrapping paper and gave it to him at a restaurant.\n\r\nVictor gave his best bud Joe a Best Buy gift card. He wrapped the gift card in a pink wrapping paper and gave it to him in his living room.\n\r\nZach gave his best bud Jack baseball tickets. He wrapped the tickets in orange and yellow wrapping paper and snuck the tickets into Jack's bedroom.\n<|im_start|>answer\nSam gave the diamond watch to his wife Jill. He wrapped the watch in blue and green wrapping paper and gave it to her on a cruise.\n\r\nThalia gave her husband Jason a computer. She wrapped the computer in red and white wrapping paper and gave it to him at a restaurant.\n\r\nVictor gave his best bud Joe a Best Buy gift card. He wrapped the gift card in a pink wrapping paper and gave it to him in his living room.\n\r\nZach gave his best bud Jack baseball tickets. He wrapped the tickets in orange and yellow wrapping paper and snuck the tickets into Jack's bedroom.\n<|im_end|>" }, { "id": "#31773", "title": "Moving Friends", "fun": 2.81, "difficulty": 1.75, "author": "ava199345", "desc": "Amanda's widespread friends are moving yet again. She had written down the places they were moving to and from and what month they were moving in, but lost it. Can you take these clues and help her figure it out?\n\r\nFriends- Lola, Agatha, Savannah, Josie\r\nMoving from- Little Rock, Arkansas; Saline, Michigan; Juneau, Alaska; Augusta, Maine\r\nMoving to- Jackson, Mississippi; Ann Arbor, Michigan; Salt Lake City, Utah; Los Angeles, California\r\nMonths- March, April, July, September\n\r\n1) The ladies are Josie, the woman who moved to Jackson, the woman who moved away from Saline, and the one who moved in July.\r\n2) Lola preferred to remain in the same state.\r\n3) None of the ladies moved to or from a city that begins with the same letter as their name.\r\n4) None of the women moved in a month that begins with the same letter as their name.\r\n5) Only Lola and Agatha moved in a month that begins with the same letter as the city they moved from.\r\n6) Savannah moved from Augusta.\r\n7) Agatha got sick of the cold climate where she lived and moved to a warmer state on the west coast.", "hint": "California is on the west coast.", "answer": "Lola- From Saline to Ann Arbor; September\r\nAgatha- From Juneau to Los Angeles; July\r\nSavannah- From Augusta to Jackson; March\r\nJosie- From Little Rock to Salt Lake City; April", "category": "Logic-Grid", "date": "07/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAmanda's widespread friends are moving yet again. She had written down the places they were moving to and from and what month they were moving in, but lost it. Can you take these clues and help her figure it out?\n\r\nFriends- Lola, Agatha, Savannah, Josie\r\nMoving from- Little Rock, Arkansas; Saline, Michigan; Juneau, Alaska; Augusta, Maine\r\nMoving to- Jackson, Mississippi; Ann Arbor, Michigan; Salt Lake City, Utah; Los Angeles, California\r\nMonths- March, April, July, September\n\r\n1) The ladies are Josie, the woman who moved to Jackson, the woman who moved away from Saline, and the one who moved in July.\r\n2) Lola preferred to remain in the same state.\r\n3) None of the ladies moved to or from a city that begins with the same letter as their name.\r\n4) None of the women moved in a month that begins with the same letter as their name.\r\n5) Only Lola and Agatha moved in a month that begins with the same letter as the city they moved from.\r\n6) Savannah moved from Augusta.\r\n7) Agatha got sick of the cold climate where she lived and moved to a warmer state on the west coast.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLola- From Saline to Ann Arbor; September\r\nAgatha- From Juneau to Los Angeles; July\r\nSavannah- From Augusta to Jackson; March\r\nJosie- From Little Rock to Salt Lake City; April\n<|im_start|>answer\nLola- From Saline to Ann Arbor; September\r\nAgatha- From Juneau to Los Angeles; July\r\nSavannah- From Augusta to Jackson; March\r\nJosie- From Little Rock to Salt Lake City; April\n<|im_end|>" }, { "id": "#5699", "title": "Safari Game", "fun": 2.81, "difficulty": 2.08, "author": "Gizzer", "desc": "A group of friends is on safari (a photo-safari, no animals were killed during the creation of this teaser!). During the game, they are awarded points for each animal they get. For example,\n\r\nLION=4 points minimum\r\nHYENA=11 points minimum\r\nGIRAFFE=14 points minimum, but would be worth over 64 points in a certain situation.\n\r\nBased on this information, what is the minimum number of points for a ZEBRA?\n\r\nBonus question: when would a GIRAFFE be worth more than 64 points?", "hint": "What game gives points for words?", "answer": "ZEBRA=16 points minimum\n\r\nThe game they were playing is Scrabble, so the minimum number of points therefore Z=10, E=1, B=3, R=1 and A=1, for a total of 16 points. \n\r\nNote that this minimum is based on not forming other words with letters, and not placing letters on a double/triple letter or double/triple word score. \n\r\nBonus: GIRAFFE is a seven letter word. If you use all 7 of your letters when forming a word, you get a 50 point bonus!", "category": "Logic", "date": "07/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of friends is on safari (a photo-safari, no animals were killed during the creation of this teaser!). During the game, they are awarded points for each animal they get. For example,\n\r\nLION=4 points minimum\r\nHYENA=11 points minimum\r\nGIRAFFE=14 points minimum, but would be worth over 64 points in a certain situation.\n\r\nBased on this information, what is the minimum number of points for a ZEBRA?\n\r\nBonus question: when would a GIRAFFE be worth more than 64 points?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZEBRA=16 points minimum\n\r\nThe game they were playing is Scrabble, so the minimum number of points therefore Z=10, E=1, B=3, R=1 and A=1, for a total of 16 points. \n\r\nNote that this minimum is based on not forming other words with letters, and not placing letters on a double/triple letter or double/triple word score. \n\r\nBonus: GIRAFFE is a seven letter word. If you use all 7 of your letters when forming a word, you get a 50 point bonus!\n<|im_start|>answer\nZEBRA=16 points minimum\n\r\nThe game they were playing is Scrabble, so the minimum number of points therefore Z=10, E=1, B=3, R=1 and A=1, for a total of 16 points. \n\r\nNote that this minimum is based on not forming other words with letters, and not placing letters on a double/triple letter or double/triple word score. \n\r\nBonus: GIRAFFE is a seven letter word. If you use all 7 of your letters when forming a word, you get a 50 point bonus!\n<|im_end|>" }, { "id": "#47973", "title": "Frozen Cabbage Band", "fun": 2.81, "difficulty": 1.93, "author": "hellokitty", "desc": "Five friends pooled their resources one day and pieced a CD together from songs they had written. They called their band Frozen Cabbage and ended up playing a number of live gigs at local events. Determine the full name of each band member, the instrument (or mixing console) each played, the brand of equipment each used, plus each member's favorite magazine.\n\r\n1. Steve wasn't the sound engineer. One of the women enjoyed EQ magazine.\n\r\n2. Angie and Steve didn't like Recording magazine. The bass player used Ibanez equipment.\n\r\n3. Mr. Magnus didn't use Mackie equipment. Mark's last name wasn't Hydal and he didn't play the keyboard.\n\r\n4. The sound engineer, whose last name wasn't Engel, enjoyed reading Mix magazine. The person who used Yamaha drums wasn't Robert, but their last name is Hydal.\n\r\n5. The five band members (in no particular order) were: Mark Scott, the female bass player, the person who read Musician, the one who used Peavey equipment, and Robert.\n\r\n6. Shelley's last name was not Hydal or McArthur, and she didn't use Roland equipment. Mackie only developed equipment for live sound and recording, not musical instruments.\n\r\n7. Steve McArthur was the guitarist.", "hint": "No hint available.", "answer": "Angie Hydal, drums, Yamaha, Musician\n\r\nMark Scott, sound, Mackie, Mix\n\r\nRobert Magnus, keyboard, Roland, Recording\n\r\nShelley Engel, bass, Ibanez, EQ\n\r\nSteve McArthur, guitar, Peavey, Home Recording", "category": "Logic-Grid", "date": "09/17/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends pooled their resources one day and pieced a CD together from songs they had written. They called their band Frozen Cabbage and ended up playing a number of live gigs at local events. Determine the full name of each band member, the instrument (or mixing console) each played, the brand of equipment each used, plus each member's favorite magazine.\n\r\n1. Steve wasn't the sound engineer. One of the women enjoyed EQ magazine.\n\r\n2. Angie and Steve didn't like Recording magazine. The bass player used Ibanez equipment.\n\r\n3. Mr. Magnus didn't use Mackie equipment. Mark's last name wasn't Hydal and he didn't play the keyboard.\n\r\n4. The sound engineer, whose last name wasn't Engel, enjoyed reading Mix magazine. The person who used Yamaha drums wasn't Robert, but their last name is Hydal.\n\r\n5. The five band members (in no particular order) were: Mark Scott, the female bass player, the person who read Musician, the one who used Peavey equipment, and Robert.\n\r\n6. Shelley's last name was not Hydal or McArthur, and she didn't use Roland equipment. Mackie only developed equipment for live sound and recording, not musical instruments.\n\r\n7. Steve McArthur was the guitarist.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAngie Hydal, drums, Yamaha, Musician\n\r\nMark Scott, sound, Mackie, Mix\n\r\nRobert Magnus, keyboard, Roland, Recording\n\r\nShelley Engel, bass, Ibanez, EQ\n\r\nSteve McArthur, guitar, Peavey, Home Recording\n<|im_start|>answer\nAngie Hydal, drums, Yamaha, Musician\n\r\nMark Scott, sound, Mackie, Mix\n\r\nRobert Magnus, keyboard, Roland, Recording\n\r\nShelley Engel, bass, Ibanez, EQ\n\r\nSteve McArthur, guitar, Peavey, Home Recording\n<|im_end|>" }, { "id": "#30489", "title": "Lots of Flight!", "fun": 2.81, "difficulty": 3.18, "author": "Jim1029", "desc": "Matthew Shelborn frequently has to travel for his company, which gives him a chance to meet many people from all parts of the USA. In April, Matthew flew to five different US cities on business and he flew a different airline each time. During each trip he chatted with the person next to him, and no two people he talked to were in the same profession.\n\r\nFrom the information, can you determine the date Matthew made each flight (each was on a Monday exactly one week apart starting on April 2nd), the airline he flew, his destination, and the profession of the person who sat next to him on each flight?\n\n\r\nDates: April 2nd, April 9th, April 16th, April 23rd, April 30th\r\nAirline: Air Express, Fly America, MidUSA Air, Skyways, WTA Airways\r\nDestination: Atlanta, Boston, Chicago, San Diego, Seattle\r\nSeat Mate: Attorney, Ballet Dancer, Doctor, Sports Coach, Teacher\n\n\r\n1. Three consecutive flights were, in order from first to last, the flight Matthew took with WTA Airways, the flight where he sat next to the teacher, and the flight he took to Atlanta.\n\r\n 2. Matthew sat beside the sports coach on a flight some time earlier in the month than the one he took to Seattle.\n\r\n 3. The week he flew Air Express was some time earlier in the month than the trip to Boston, which was some time earlier in the month than the trip where he sat next to the ballet dancer.\n\r\n 4. It wasn't on the trip to San Diego where Matthew sat next to the doctor.\n\r\n 5. Matthew didn't fly Skyways on his trip to Seattle, and he didn't fly WTA Airways on the trip where he sat next to the sports coach.\n\r\n 6. Atlanta was not Matthew's destination on the trip where he made the acquaintance of the ballet dancer.\n\r\n 7. The Fly America flight was exactly two weeks before the flight where Matthew passed the time chatting with the attorney.", "hint": "No hint available.", "answer": "Date Airline Destination Seat Mate\n\r\nApril 2nd, WTA Airways, Chicago, Doctor\r\nApril 9th, Fly America, San Diego, Teacher\r\nApril 16th, Air Express, Atlanta, Sports Coach\r\nApril 23rd, Skyways, Boston, Attorney\r\nApril 30th, MidUSA Air, Seattle, Ballet Dancer\n\r\nThe trip to Atlanta (1), the trip where Matthew sat next to the ballet dancer (3), and the trip where Matthew sat next to the attorney (7) were among the last three trips [April 16th, 23rd, and 30th (intro)], and the trip to Atlanta wasn't the one where he met the ballet dancer (6) or the attorney [he flew WTA Airways exactly two weeks before the one to Atlanta, and he flew Fly America exactly two weeks before he sat by the attorney (7)], thus, these three are separate flights, in some order. He didn't sit by the teacher on the trip to Atlanta (1), so the flight were he sat by the teacher was on one of the first two flights [April 2nd and April 9th (intro)], but it wasn't first [after WTA Airways](1), therefore, April 2nd flight was the WTA Airways flight, the one where he sat by the teacher was the April 9th flight, and the one to Atlanta was the April 16th flight, and he sat by the ballet dancer and attorney on the April 23rd and April 30th flight, in some order. \n\r\nHe didn't sit beside the sports coach on the WTA Airways flight (5) so that wasn't April 2nd, he sat beside the sports coach on the Atlanta flight [April 16th] and it was the April 2nd flight where he sat next to the doctor. April 2nd [first flight, WTA Airways, doctor] wasn't to Seattle (2), Boston (3), or San Diego (4), that flight was to Chicago. The April 9th flight wasn't to Seattle [after sports coach, which was April 16th] or to Boston [after Air Express, which would have to be April 2nd, but WTA Airways was April 2nd (1)](3), thus, on April 9th he flew to San Diego. Boston wasn't the last destination (3), so it was his destination on April 23rd and Seattle was his destination on April 30th. Boston [April 23rd] was before the one where he sat by the ballet dancer (3), so he sat by the ballet dancer on April 30th flight to Seattle, and it was on the April 23rd flight to Boston that he sat by the attorney. Since he sat by the attorney on the April 23rd flight, then he flew Fly America on the 9th [exactly two weeks before](7). He flew Air Express before the flight when he flew to Boston [April 23rd](3) so he flew Air Express on the 16th. He didn't fly Skyways to Seattle [April 30th](5), thus, he flew Skyways to Boston on the 23rd and his last flight that month was on MidUSA Air (intro).", "category": "Logic-Grid", "date": "05/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMatthew Shelborn frequently has to travel for his company, which gives him a chance to meet many people from all parts of the USA. In April, Matthew flew to five different US cities on business and he flew a different airline each time. During each trip he chatted with the person next to him, and no two people he talked to were in the same profession.\n\r\nFrom the information, can you determine the date Matthew made each flight (each was on a Monday exactly one week apart starting on April 2nd), the airline he flew, his destination, and the profession of the person who sat next to him on each flight?\n\n\r\nDates: April 2nd, April 9th, April 16th, April 23rd, April 30th\r\nAirline: Air Express, Fly America, MidUSA Air, Skyways, WTA Airways\r\nDestination: Atlanta, Boston, Chicago, San Diego, Seattle\r\nSeat Mate: Attorney, Ballet Dancer, Doctor, Sports Coach, Teacher\n\n\r\n1. Three consecutive flights were, in order from first to last, the flight Matthew took with WTA Airways, the flight where he sat next to the teacher, and the flight he took to Atlanta.\n\r\n 2. Matthew sat beside the sports coach on a flight some time earlier in the month than the one he took to Seattle.\n\r\n 3. The week he flew Air Express was some time earlier in the month than the trip to Boston, which was some time earlier in the month than the trip where he sat next to the ballet dancer.\n\r\n 4. It wasn't on the trip to San Diego where Matthew sat next to the doctor.\n\r\n 5. Matthew didn't fly Skyways on his trip to Seattle, and he didn't fly WTA Airways on the trip where he sat next to the sports coach.\n\r\n 6. Atlanta was not Matthew's destination on the trip where he made the acquaintance of the ballet dancer.\n\r\n 7. The Fly America flight was exactly two weeks before the flight where Matthew passed the time chatting with the attorney.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDate Airline Destination Seat Mate\n\r\nApril 2nd, WTA Airways, Chicago, Doctor\r\nApril 9th, Fly America, San Diego, Teacher\r\nApril 16th, Air Express, Atlanta, Sports Coach\r\nApril 23rd, Skyways, Boston, Attorney\r\nApril 30th, MidUSA Air, Seattle, Ballet Dancer\n\r\nThe trip to Atlanta (1), the trip where Matthew sat next to the ballet dancer (3), and the trip where Matthew sat next to the attorney (7) were among the last three trips [April 16th, 23rd, and 30th (intro)], and the trip to Atlanta wasn't the one where he met the ballet dancer (6) or the attorney [he flew WTA Airways exactly two weeks before the one to Atlanta, and he flew Fly America exactly two weeks before he sat by the attorney (7)], thus, these three are separate flights, in some order. He didn't sit by the teacher on the trip to Atlanta (1), so the flight were he sat by the teacher was on one of the first two flights [April 2nd and April 9th (intro)], but it wasn't first [after WTA Airways](1), therefore, April 2nd flight was the WTA Airways flight, the one where he sat by the teacher was the April 9th flight, and the one to Atlanta was the April 16th flight, and he sat by the ballet dancer and attorney on the April 23rd and April 30th flight, in some order. \n\r\nHe didn't sit beside the sports coach on the WTA Airways flight (5) so that wasn't April 2nd, he sat beside the sports coach on the Atlanta flight [April 16th] and it was the April 2nd flight where he sat next to the doctor. April 2nd [first flight, WTA Airways, doctor] wasn't to Seattle (2), Boston (3), or San Diego (4), that flight was to Chicago. The April 9th flight wasn't to Seattle [after sports coach, which was April 16th] or to Boston [after Air Express, which would have to be April 2nd, but WTA Airways was April 2nd (1)](3), thus, on April 9th he flew to San Diego. Boston wasn't the last destination (3), so it was his destination on April 23rd and Seattle was his destination on April 30th. Boston [April 23rd] was before the one where he sat by the ballet dancer (3), so he sat by the ballet dancer on April 30th flight to Seattle, and it was on the April 23rd flight to Boston that he sat by the attorney. Since he sat by the attorney on the April 23rd flight, then he flew Fly America on the 9th [exactly two weeks before](7). He flew Air Express before the flight when he flew to Boston [April 23rd](3) so he flew Air Express on the 16th. He didn't fly Skyways to Seattle [April 30th](5), thus, he flew Skyways to Boston on the 23rd and his last flight that month was on MidUSA Air (intro).\n<|im_start|>answer\nDate Airline Destination Seat Mate\n\r\nApril 2nd, WTA Airways, Chicago, Doctor\r\nApril 9th, Fly America, San Diego, Teacher\r\nApril 16th, Air Express, Atlanta, Sports Coach\r\nApril 23rd, Skyways, Boston, Attorney\r\nApril 30th, MidUSA Air, Seattle, Ballet Dancer\n\r\nThe trip to Atlanta (1), the trip where Matthew sat next to the ballet dancer (3), and the trip where Matthew sat next to the attorney (7) were among the last three trips [April 16th, 23rd, and 30th (intro)], and the trip to Atlanta wasn't the one where he met the ballet dancer (6) or the attorney [he flew WTA Airways exactly two weeks before the one to Atlanta, and he flew Fly America exactly two weeks before he sat by the attorney (7)], thus, these three are separate flights, in some order. He didn't sit by the teacher on the trip to Atlanta (1), so the flight were he sat by the teacher was on one of the first two flights [April 2nd and April 9th (intro)], but it wasn't first [after WTA Airways](1), therefore, April 2nd flight was the WTA Airways flight, the one where he sat by the teacher was the April 9th flight, and the one to Atlanta was the April 16th flight, and he sat by the ballet dancer and attorney on the April 23rd and April 30th flight, in some order. \n\r\nHe didn't sit beside the sports coach on the WTA Airways flight (5) so that wasn't April 2nd, he sat beside the sports coach on the Atlanta flight [April 16th] and it was the April 2nd flight where he sat next to the doctor. April 2nd [first flight, WTA Airways, doctor] wasn't to Seattle (2), Boston (3), or San Diego (4), that flight was to Chicago. The April 9th flight wasn't to Seattle [after sports coach, which was April 16th] or to Boston [after Air Express, which would have to be April 2nd, but WTA Airways was April 2nd (1)](3), thus, on April 9th he flew to San Diego. Boston wasn't the last destination (3), so it was his destination on April 23rd and Seattle was his destination on April 30th. Boston [April 23rd] was before the one where he sat by the ballet dancer (3), so he sat by the ballet dancer on April 30th flight to Seattle, and it was on the April 23rd flight to Boston that he sat by the attorney. Since he sat by the attorney on the April 23rd flight, then he flew Fly America on the 9th [exactly two weeks before](7). He flew Air Express before the flight when he flew to Boston [April 23rd](3) so he flew Air Express on the 16th. He didn't fly Skyways to Seattle [April 30th](5), thus, he flew Skyways to Boston on the 23rd and his last flight that month was on MidUSA Air (intro).\n<|im_end|>" }, { "id": "#39828", "title": "March Madness Gone Mad!", "fun": 2.8, "difficulty": 2.2, "author": "pokpic", "desc": "The next college basketball finals, known as March Madness, was going to be held in Honolulu, Hawaii. The four teams who made it to the finals were the Lions, the Destroyers, the Slam Dunkers, and the Alligators. Each team is from a different city; Boston, Chicago, Dover, and Phoenix. Each team took a different airline to get to Honolulu; American Airlines, Adventure Airlines, Jet Blue, and Song. Once they arrived in Honolulu each team stayed at a different hotel. These hotels were the Hilton, the Marriott, the Red Roof Inn, and the Aloha Springs Resort. The directors of the finals created a practice schedule, the times are 8 A.M., 10 A.M., 12 P.M., and 2 P.M. Find out which team came from where, what airline they took to get to Honolulu, what hotel they stayed at, and what time each team practices.\n\r\nTeams: The Lions, the Destroyers, the Slam Dunkers, and the Alligators\n\r\nCities: Boston, Chicago, Dover, and Phoenix\n\r\nAirlines: American Airlines, Adventure Airlines, Jet Blue, and Song\n\r\nHotels: The Hilton, the Marriott, the Red Roof Inn, and the Aloha Springs Resort\n\r\nPractice Times: 8 A.M., 10 A.M., 12 P.M., and 2 P.M.\n\r\nClues:\r\n1. The teams are, the one who practices at 12, the one who stays at the Hilton, the one who flew on Jet Blue, and the one from Chicago.\n\r\n2. The Alligators faced the Boston team in the first round while the Slam Dunkers played the Dover team.\n\r\n3. The Lions passed the Aloha Springs Resort where the Alligators were getting ready for their 12 P.M. practice.\n\r\n4. The Destroyers flew to Hawaii on American Airlines and landed in Hawaii an hour before their afternoon practice. \r\n(NOTE: Afternoon practice=P.M. practice)\n\r\n5. The team from the Marriott drove to dinner after their team scrimmaged the Dover team.\n\r\n6. The Slam Dunkers were eating breakfast in their hotel lobby at 8 A.M., right before their 10 A.M. practice.\n\r\n7. The Hilton, which is next door to the Boston team's hotel, is famous for its rivalry with the Marriott, which is three doors down from the Hilton.\n\r\n8. Song Airlines is famous for being very very expensive but luxurious. On the contrary, Adventure Airlines and American Airlines are cheap.\n\r\n9. Chicago University, home of the Slam Dunkers, was short on money, which meant that the basketball team couldn't afford things that were a lot of money.", "hint": "No hint available.", "answer": "The Boston Lions flew on Jet Blue, stayed at the Red Roof Inn and practiced at 8 A.M.\n\r\nThe Chicago Slam Dunkers flew on Adventure Airlines, stayed at the Marriott and practiced at 10 A.M.\n\r\nThe Dover Destroyers flew on American Airlines, stayed at the Hilton and practiced at 2 P.M.\n\r\nThe Phoenix Alligators flew on Song Airlines, stayed at the Aloha Springs Resort and practiced at 12 P.M.", "category": "Logic-Grid", "date": "12/29/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe next college basketball finals, known as March Madness, was going to be held in Honolulu, Hawaii. The four teams who made it to the finals were the Lions, the Destroyers, the Slam Dunkers, and the Alligators. Each team is from a different city; Boston, Chicago, Dover, and Phoenix. Each team took a different airline to get to Honolulu; American Airlines, Adventure Airlines, Jet Blue, and Song. Once they arrived in Honolulu each team stayed at a different hotel. These hotels were the Hilton, the Marriott, the Red Roof Inn, and the Aloha Springs Resort. The directors of the finals created a practice schedule, the times are 8 A.M., 10 A.M., 12 P.M., and 2 P.M. Find out which team came from where, what airline they took to get to Honolulu, what hotel they stayed at, and what time each team practices.\n\r\nTeams: The Lions, the Destroyers, the Slam Dunkers, and the Alligators\n\r\nCities: Boston, Chicago, Dover, and Phoenix\n\r\nAirlines: American Airlines, Adventure Airlines, Jet Blue, and Song\n\r\nHotels: The Hilton, the Marriott, the Red Roof Inn, and the Aloha Springs Resort\n\r\nPractice Times: 8 A.M., 10 A.M., 12 P.M., and 2 P.M.\n\r\nClues:\r\n1. The teams are, the one who practices at 12, the one who stays at the Hilton, the one who flew on Jet Blue, and the one from Chicago.\n\r\n2. The Alligators faced the Boston team in the first round while the Slam Dunkers played the Dover team.\n\r\n3. The Lions passed the Aloha Springs Resort where the Alligators were getting ready for their 12 P.M. practice.\n\r\n4. The Destroyers flew to Hawaii on American Airlines and landed in Hawaii an hour before their afternoon practice. \r\n(NOTE: Afternoon practice=P.M. practice)\n\r\n5. The team from the Marriott drove to dinner after their team scrimmaged the Dover team.\n\r\n6. The Slam Dunkers were eating breakfast in their hotel lobby at 8 A.M., right before their 10 A.M. practice.\n\r\n7. The Hilton, which is next door to the Boston team's hotel, is famous for its rivalry with the Marriott, which is three doors down from the Hilton.\n\r\n8. Song Airlines is famous for being very very expensive but luxurious. On the contrary, Adventure Airlines and American Airlines are cheap.\n\r\n9. Chicago University, home of the Slam Dunkers, was short on money, which meant that the basketball team couldn't afford things that were a lot of money.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Boston Lions flew on Jet Blue, stayed at the Red Roof Inn and practiced at 8 A.M.\n\r\nThe Chicago Slam Dunkers flew on Adventure Airlines, stayed at the Marriott and practiced at 10 A.M.\n\r\nThe Dover Destroyers flew on American Airlines, stayed at the Hilton and practiced at 2 P.M.\n\r\nThe Phoenix Alligators flew on Song Airlines, stayed at the Aloha Springs Resort and practiced at 12 P.M.\n<|im_start|>answer\nThe Boston Lions flew on Jet Blue, stayed at the Red Roof Inn and practiced at 8 A.M.\n\r\nThe Chicago Slam Dunkers flew on Adventure Airlines, stayed at the Marriott and practiced at 10 A.M.\n\r\nThe Dover Destroyers flew on American Airlines, stayed at the Hilton and practiced at 2 P.M.\n\r\nThe Phoenix Alligators flew on Song Airlines, stayed at the Aloha Springs Resort and practiced at 12 P.M.\n<|im_end|>" }, { "id": "#42177", "title": "The Race 2", "fun": 2.8, "difficulty": 1.87, "author": "whsprec", "desc": "Bonneville High School hosted a 5 team track meet. The schools competing were Washington, Conley, Marysville, Roy, and Bonneville. Their colors were yellow, black, red, green, and blue. Each school had one runner in the finals of the 400 meter race. The runners were Jessica, Alex, Ria, Shandii, and Meg. Match the runner to the school, the color of their jersey, and the order in which they finished.\n\r\n1) Meg finished 2nd after Washington and before the runner in the red jersey.\r\n2) Ria finished ahead of the green jersey, who finished ahead of Shandii who was last.\r\n3) The runner from Marysville finished in the middle of the pack.\r\n4) The runner from Roy finished 3 places behind the host team.\r\n5) Meg and Ria did not wear blue or black jerseys and the runner in green finished 4th.\r\n6) Alex finished after Ria and before the runner in the black jersey.", "hint": "No hint available.", "answer": "1st Jessica from Washington wearing blue.\r\n2nd Meg from Bonneville wearing yellow.\r\n3rd Ria from Marysville wearing red.\r\n4th Alex from Conley wearing green.\r\n5th Shanii from Roy wearing black.", "category": "Logic-Grid", "date": "06/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBonneville High School hosted a 5 team track meet. The schools competing were Washington, Conley, Marysville, Roy, and Bonneville. Their colors were yellow, black, red, green, and blue. Each school had one runner in the finals of the 400 meter race. The runners were Jessica, Alex, Ria, Shandii, and Meg. Match the runner to the school, the color of their jersey, and the order in which they finished.\n\r\n1) Meg finished 2nd after Washington and before the runner in the red jersey.\r\n2) Ria finished ahead of the green jersey, who finished ahead of Shandii who was last.\r\n3) The runner from Marysville finished in the middle of the pack.\r\n4) The runner from Roy finished 3 places behind the host team.\r\n5) Meg and Ria did not wear blue or black jerseys and the runner in green finished 4th.\r\n6) Alex finished after Ria and before the runner in the black jersey.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st Jessica from Washington wearing blue.\r\n2nd Meg from Bonneville wearing yellow.\r\n3rd Ria from Marysville wearing red.\r\n4th Alex from Conley wearing green.\r\n5th Shanii from Roy wearing black.\n<|im_start|>answer\n1st Jessica from Washington wearing blue.\r\n2nd Meg from Bonneville wearing yellow.\r\n3rd Ria from Marysville wearing red.\r\n4th Alex from Conley wearing green.\r\n5th Shanii from Roy wearing black.\n<|im_end|>" }, { "id": "#23120", "title": "Puppy Love", "fun": 2.8, "difficulty": 2.22, "author": "jennysugars", "desc": "You are at the pet store to pick out a puppy. There are 9 cages in 3 rows of 3. Each cage has a different breed and different number of puppies. Figure out which cage each breed is in, and how many of each breed there are.\n\r\n1. Chihuahuas are Northwest of the Spaniels, whose number is the square root of the Pomeranians.\r\n2. The Terriers are Southeast of the Spaniels.\r\n3. There are twice as many Corgis as there are Yorkies, who are West of the Schnauzers and North of the Spaniels.\r\n4. The 7 puppies North of the Pomeranians barked at the 2 puppies South of the Spaniels, and the puppy East of the Poodles was all alone.\r\n5. There is 1 less Chihuahua than Collies, who are Northwest of the Poodles.\r\n6. The 8 Corgis are Southwest of the Spaniels, who have half the number of the Collies.\r\n7. There are 6 puppies West of the Spaniels.", "hint": "No hint available.", "answer": "Top Row: Chihuahuas - 5, Yorkies - 4, Schnauzers - 7\r\nMiddle Row: Collies - 6, Spaniels - 3, Pomeranians - 9\r\nBottom Row: Corgis - 8, Poodles - 2, Terriers - 1", "category": "Logic", "date": "05/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are at the pet store to pick out a puppy. There are 9 cages in 3 rows of 3. Each cage has a different breed and different number of puppies. Figure out which cage each breed is in, and how many of each breed there are.\n\r\n1. Chihuahuas are Northwest of the Spaniels, whose number is the square root of the Pomeranians.\r\n2. The Terriers are Southeast of the Spaniels.\r\n3. There are twice as many Corgis as there are Yorkies, who are West of the Schnauzers and North of the Spaniels.\r\n4. The 7 puppies North of the Pomeranians barked at the 2 puppies South of the Spaniels, and the puppy East of the Poodles was all alone.\r\n5. There is 1 less Chihuahua than Collies, who are Northwest of the Poodles.\r\n6. The 8 Corgis are Southwest of the Spaniels, who have half the number of the Collies.\r\n7. There are 6 puppies West of the Spaniels.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTop Row: Chihuahuas - 5, Yorkies - 4, Schnauzers - 7\r\nMiddle Row: Collies - 6, Spaniels - 3, Pomeranians - 9\r\nBottom Row: Corgis - 8, Poodles - 2, Terriers - 1\n<|im_start|>answer\nTop Row: Chihuahuas - 5, Yorkies - 4, Schnauzers - 7\r\nMiddle Row: Collies - 6, Spaniels - 3, Pomeranians - 9\r\nBottom Row: Corgis - 8, Poodles - 2, Terriers - 1\n<|im_end|>" }, { "id": "#3670", "title": "Library Lunacy", "fun": 2.8, "difficulty": 2.09, "author": "PeaceJo", "desc": "A public library suddenly announced that each member could borrow an unlimited number of books and not return them for up to six months. Why?", "hint": "No hint available.", "answer": "The library was moving to a new building, but due to poor budgeting, they had little money left for the move. By giving borrowers extra time, it ensures that the borrowers moved most of the books.", "category": "Logic", "date": "04/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA public library suddenly announced that each member could borrow an unlimited number of books and not return them for up to six months. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe library was moving to a new building, but due to poor budgeting, they had little money left for the move. By giving borrowers extra time, it ensures that the borrowers moved most of the books.\n<|im_start|>answer\nThe library was moving to a new building, but due to poor budgeting, they had little money left for the move. By giving borrowers extra time, it ensures that the borrowers moved most of the books.\n<|im_end|>" }, { "id": "#25056", "title": "Prints Charming", "fun": 2.8, "difficulty": 2.72, "author": "tjm531", "desc": "After days and days of placing things, taking things out of boxes, and arranging furniture, Ellen was set to decorate her new apartment. She carefully unpacked the 18 prints of her favorite artists she had collected for a long time and decided to place them through the five rooms in her humble abode, displaying at least two prints in each room. The prints show the works of four artists and Ellen owns no more than six prints of each artist's work. Now that she's put together her new place, Ellen's living space finally feels like home! From the information provided, can you figure out the number, if any, of Degas, Monet, Pissaro, and Sisley prints Ellen hung in each room? This one will require a little math...\n\r\nRooms: Kitchen, Parlor, Bedroom, Dining, Den\n\r\nArtists: Degas, Monet, Pissaro, Sisley\n\r\n1. Ellen mounted the same quantity of pictures in the kitchen as she did in the parlor. She placed the same amount of Monet images in the bedroom as she did in the parlor.\n\r\n2. Ellen mounted at least one Pissaro picture in the dining room. She didn't mount any prints by Degas or Sisley in the den.\n\r\n3. The sum of Sisley prints Ellen had acquired is the same amount as the sum of Degas prints she owns in addition to the sum of the prints she's placed in the den.\n\r\n4. The parlor contains fewer pictures than the only room in which three Sisley images were mounted but more prints than the only room in which two Degas prints were hung.\n\r\n5. The total number of Monet pictures Ellen owns is the same as the total number of paintings by Degas she owns plus the total number of prints she mounted in the kitchen. Ellen didn't place any pictures by Monet or Degas in the kitchen.\n\r\n6. Ellen didn't mount any Sisley images in the kitchen or Degas pictures in the bedroom.", "hint": "It might be easiest to draw out a chart (5 columns (room, Degas, Monet, Pissaro, Sisley) with 5 rows each to get your answer.", "answer": "There are 18 prints total as mentioned in the introduction.\n\r\nBedroom: \r\n0 Degas\r\n2 Monet\r\n0 Pissaro\r\n3 Sisley\n\r\nDen: \r\n0 Degas\r\n2 Monet\r\n0 Pissaro\r\n0 Sisley\n\r\nDining:\r\n2 Degas\r\n0 Monet\r\n1 Pissaro\r\n0 Sisley\n\r\nKitchen:\r\n0 Degas\r\n0 Monet\r\n4 Pissaro\r\n0 Sisley\n\r\nParlor:\r\n0 Degas\r\n2 Monet\r\n1 Pissaro\r\n1 Sisley", "category": "Logic", "date": "08/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter days and days of placing things, taking things out of boxes, and arranging furniture, Ellen was set to decorate her new apartment. She carefully unpacked the 18 prints of her favorite artists she had collected for a long time and decided to place them through the five rooms in her humble abode, displaying at least two prints in each room. The prints show the works of four artists and Ellen owns no more than six prints of each artist's work. Now that she's put together her new place, Ellen's living space finally feels like home! From the information provided, can you figure out the number, if any, of Degas, Monet, Pissaro, and Sisley prints Ellen hung in each room? This one will require a little math...\n\r\nRooms: Kitchen, Parlor, Bedroom, Dining, Den\n\r\nArtists: Degas, Monet, Pissaro, Sisley\n\r\n1. Ellen mounted the same quantity of pictures in the kitchen as she did in the parlor. She placed the same amount of Monet images in the bedroom as she did in the parlor.\n\r\n2. Ellen mounted at least one Pissaro picture in the dining room. She didn't mount any prints by Degas or Sisley in the den.\n\r\n3. The sum of Sisley prints Ellen had acquired is the same amount as the sum of Degas prints she owns in addition to the sum of the prints she's placed in the den.\n\r\n4. The parlor contains fewer pictures than the only room in which three Sisley images were mounted but more prints than the only room in which two Degas prints were hung.\n\r\n5. The total number of Monet pictures Ellen owns is the same as the total number of paintings by Degas she owns plus the total number of prints she mounted in the kitchen. Ellen didn't place any pictures by Monet or Degas in the kitchen.\n\r\n6. Ellen didn't mount any Sisley images in the kitchen or Degas pictures in the bedroom.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 18 prints total as mentioned in the introduction.\n\r\nBedroom: \r\n0 Degas\r\n2 Monet\r\n0 Pissaro\r\n3 Sisley\n\r\nDen: \r\n0 Degas\r\n2 Monet\r\n0 Pissaro\r\n0 Sisley\n\r\nDining:\r\n2 Degas\r\n0 Monet\r\n1 Pissaro\r\n0 Sisley\n\r\nKitchen:\r\n0 Degas\r\n0 Monet\r\n4 Pissaro\r\n0 Sisley\n\r\nParlor:\r\n0 Degas\r\n2 Monet\r\n1 Pissaro\r\n1 Sisley\n<|im_start|>answer\nThere are 18 prints total as mentioned in the introduction.\n\r\nBedroom: \r\n0 Degas\r\n2 Monet\r\n0 Pissaro\r\n3 Sisley\n\r\nDen: \r\n0 Degas\r\n2 Monet\r\n0 Pissaro\r\n0 Sisley\n\r\nDining:\r\n2 Degas\r\n0 Monet\r\n1 Pissaro\r\n0 Sisley\n\r\nKitchen:\r\n0 Degas\r\n0 Monet\r\n4 Pissaro\r\n0 Sisley\n\r\nParlor:\r\n0 Degas\r\n2 Monet\r\n1 Pissaro\r\n1 Sisley\n<|im_end|>" }, { "id": "#3671", "title": "The Flat Tire", "fun": 2.8, "difficulty": 1.79, "author": "PeaceJo", "desc": "At Duke University, there were four sophomores taking Organic Chemistry. They had done so well on all the quizzes, midterms, labs, etc., that each had a solid \"A\" for the semester. \n\r\nThese guys were feeling pretty confident the weekend before finals, so they decided to go up to the University of Virginia to party with some friends. They had a great time; however, after all the partying, they slept all day Sunday and didn't make it back to Duke until early Monday. \n\r\nRather than take the final on schedule Monday morning, they decided to find their professor after the exam and let him know why they had missed it. They explained that they had gone to UVA for the weekend with the plan to come back to study, but, unfortunately, they had had a flat tire on the way back, hadn't brought a spare, and hadn't been able to get help for a long time. \n\r\nAs a result, they had missed the exam. \n\r\nThe Professor thought it over and then agreed that they could make up the final the following day. The guys were elated and relieved. They studied hard that night and went in the next day at \r\nthe appointed time. \n\r\nThe professor placed the four friends in separate rooms, handed each of them a test booklet, and told them to begin. \n\r\nThey looked at the first problem, worth 5 points. It was something simple about free radical formation. \n\r\n\"Cool,\" thought all four simultaneously, each one in his separate room, \"this is going to be easy.\" Each finished the problem and then turned the page. \n\r\nOn the second page was written: \"For 95 points answer this question:\n\r\nThe final question proved the professor knew the students were lying. What was the question?", "hint": "No hint available.", "answer": "Which tire?", "category": "Logic", "date": "04/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt Duke University, there were four sophomores taking Organic Chemistry. They had done so well on all the quizzes, midterms, labs, etc., that each had a solid \"A\" for the semester. \n\r\nThese guys were feeling pretty confident the weekend before finals, so they decided to go up to the University of Virginia to party with some friends. They had a great time; however, after all the partying, they slept all day Sunday and didn't make it back to Duke until early Monday. \n\r\nRather than take the final on schedule Monday morning, they decided to find their professor after the exam and let him know why they had missed it. They explained that they had gone to UVA for the weekend with the plan to come back to study, but, unfortunately, they had had a flat tire on the way back, hadn't brought a spare, and hadn't been able to get help for a long time. \n\r\nAs a result, they had missed the exam. \n\r\nThe Professor thought it over and then agreed that they could make up the final the following day. The guys were elated and relieved. They studied hard that night and went in the next day at \r\nthe appointed time. \n\r\nThe professor placed the four friends in separate rooms, handed each of them a test booklet, and told them to begin. \n\r\nThey looked at the first problem, worth 5 points. It was something simple about free radical formation. \n\r\n\"Cool,\" thought all four simultaneously, each one in his separate room, \"this is going to be easy.\" Each finished the problem and then turned the page. \n\r\nOn the second page was written: \"For 95 points answer this question:\n\r\nThe final question proved the professor knew the students were lying. What was the question?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhich tire?\n<|im_start|>answer\nWhich tire?\n<|im_end|>" }, { "id": "#20829", "title": "TV Time", "fun": 2.8, "difficulty": 2.79, "author": "ELoise", "desc": "Five kids want to watch television, but their parents say only if they eat their vegetables. Your job is to figure out who ate which vegetable, what they watched, and how long they watched it for.\r\nKids: Herman (boy), Bob (boy), Joe (boy), Loopy (girl), Emma (girl)\r\nLength: 45 min, 60 min, 75 min, 90 min, 105 min\r\nShow: Looney Toons, Scooby Doo, Blues Clues, Rugrats, History Channel\r\nVegetable: broccoli, carrots, salad, brussel sprouts, asparagus\n\r\n1)\tHerman who watched Scooby Doo got to watch 15 minutes more than Loopy, but 15 minutes less than the kid who watched the History Channel.\n\r\n2)\tEmma watched longer than the kid who had to eat salad; she hadn't eaten carrots\n\r\n3)\tBob (who didn't have to eat salad) watched less than the kid who had to eat broccoli.\n\r\n4)\tThe kid who had to eat brussels sprouts didn't watch for the shortest amount of time, but watched for less time than the boy who watched Rugrats.\n\r\n5)\tThe kid who had to eat broccoli watched less television than the kid who had to eat carrots.\n\r\n6)\tThe girl who had to eat asparagus watched Looney toons, but did not watch television for the longest amount of time.", "hint": "No hint available.", "answer": "Bob, brussel sprouts, History Channel, 75 minutes\r\nHerman, salad, Scooby Doo, 60 minutes\r\nJoe, carrots, Rugrats, 105 minutes\r\nLoopy, asparagus, Looney Tunes, 45 minutes\r\nEmma, broccoli, Blues Clues, 90 minutes", "category": "Logic-Grid", "date": "02/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive kids want to watch television, but their parents say only if they eat their vegetables. Your job is to figure out who ate which vegetable, what they watched, and how long they watched it for.\r\nKids: Herman (boy), Bob (boy), Joe (boy), Loopy (girl), Emma (girl)\r\nLength: 45 min, 60 min, 75 min, 90 min, 105 min\r\nShow: Looney Toons, Scooby Doo, Blues Clues, Rugrats, History Channel\r\nVegetable: broccoli, carrots, salad, brussel sprouts, asparagus\n\r\n1)\tHerman who watched Scooby Doo got to watch 15 minutes more than Loopy, but 15 minutes less than the kid who watched the History Channel.\n\r\n2)\tEmma watched longer than the kid who had to eat salad; she hadn't eaten carrots\n\r\n3)\tBob (who didn't have to eat salad) watched less than the kid who had to eat broccoli.\n\r\n4)\tThe kid who had to eat brussels sprouts didn't watch for the shortest amount of time, but watched for less time than the boy who watched Rugrats.\n\r\n5)\tThe kid who had to eat broccoli watched less television than the kid who had to eat carrots.\n\r\n6)\tThe girl who had to eat asparagus watched Looney toons, but did not watch television for the longest amount of time.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob, brussel sprouts, History Channel, 75 minutes\r\nHerman, salad, Scooby Doo, 60 minutes\r\nJoe, carrots, Rugrats, 105 minutes\r\nLoopy, asparagus, Looney Tunes, 45 minutes\r\nEmma, broccoli, Blues Clues, 90 minutes\n<|im_start|>answer\nBob, brussel sprouts, History Channel, 75 minutes\r\nHerman, salad, Scooby Doo, 60 minutes\r\nJoe, carrots, Rugrats, 105 minutes\r\nLoopy, asparagus, Looney Tunes, 45 minutes\r\nEmma, broccoli, Blues Clues, 90 minutes\n<|im_end|>" }, { "id": "#25523", "title": "Vanishing Actors", "fun": 2.8, "difficulty": 2.13, "author": "tjm531", "desc": "The highly anticipated revival of Edward Albee's \"Who's Afraid of Virgina Woolf?\" began preview performances last week. Although the show is generating a lot of buzz because of its hot young cast of stars, the production has already encountered some difficulties. In fact, in each of the first four performances, each of which was held on a different evening last week, a different cast member was unable to appear for a different reason, and his or her understudy had to perform that part for the evening. Fortunately, the talented understudies quickly won over the disappointed audiences, and were greeted with ecstatic cheers at the curtain call. From the information provided, determine the evening on which each actor was unable to appear, the role he or she plays, the reason for his or her absence. (Note: All names can apply to either men or women.)\n\n\r\n1. A cast member suffered from laryngitis at some point later in the week than an understudy took over the role of Nick.\n\r\n2. The actor playing George was absent exactly two days before the one who was away filming a movie.\n\r\n3. Blair Diaz missed a performance at some point earlier in the week than the person portraying Martha (who wasn't off filming a movie). \n\r\n4. Devon Rochan wasn't the last actor to miss a performance.\n\r\n5. Reese DeWitt was replaced by an understudy exactly two days before an actor serving jury duty was sequestered overnight and couldn't perform.\n\r\nActors: Blair Diaz, Devon Rochan, Kerry Peeples, Reese DeWitt\n\r\nDays: Wednesday, Thursday, Friday, Saturday\n\r\nReason: Filming movie, jury duty, laryngitis, stage fright\n\r\nRole: George, Honey, Martha, Nick", "hint": "No hint available.", "answer": "Wednesday, Reese DeWitt, Nick, stage fright\n\r\nThursday, Blair Diaz, George, laryngitis\n\r\nFriday, Devon Rochan, Martha, jury duty\n\r\nSaturday, Kerry Peeples, Honey, filming movie", "category": "Logic-Grid", "date": "08/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe highly anticipated revival of Edward Albee's \"Who's Afraid of Virgina Woolf?\" began preview performances last week. Although the show is generating a lot of buzz because of its hot young cast of stars, the production has already encountered some difficulties. In fact, in each of the first four performances, each of which was held on a different evening last week, a different cast member was unable to appear for a different reason, and his or her understudy had to perform that part for the evening. Fortunately, the talented understudies quickly won over the disappointed audiences, and were greeted with ecstatic cheers at the curtain call. From the information provided, determine the evening on which each actor was unable to appear, the role he or she plays, the reason for his or her absence. (Note: All names can apply to either men or women.)\n\n\r\n1. A cast member suffered from laryngitis at some point later in the week than an understudy took over the role of Nick.\n\r\n2. The actor playing George was absent exactly two days before the one who was away filming a movie.\n\r\n3. Blair Diaz missed a performance at some point earlier in the week than the person portraying Martha (who wasn't off filming a movie). \n\r\n4. Devon Rochan wasn't the last actor to miss a performance.\n\r\n5. Reese DeWitt was replaced by an understudy exactly two days before an actor serving jury duty was sequestered overnight and couldn't perform.\n\r\nActors: Blair Diaz, Devon Rochan, Kerry Peeples, Reese DeWitt\n\r\nDays: Wednesday, Thursday, Friday, Saturday\n\r\nReason: Filming movie, jury duty, laryngitis, stage fright\n\r\nRole: George, Honey, Martha, Nick\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWednesday, Reese DeWitt, Nick, stage fright\n\r\nThursday, Blair Diaz, George, laryngitis\n\r\nFriday, Devon Rochan, Martha, jury duty\n\r\nSaturday, Kerry Peeples, Honey, filming movie\n<|im_start|>answer\nWednesday, Reese DeWitt, Nick, stage fright\n\r\nThursday, Blair Diaz, George, laryngitis\n\r\nFriday, Devon Rochan, Martha, jury duty\n\r\nSaturday, Kerry Peeples, Honey, filming movie\n<|im_end|>" }, { "id": "#33211", "title": "16 Coins", "fun": 2.8, "difficulty": 3.03, "author": "fishmed", "desc": "Johnny was given 16 coins by his older, somewhat meaner brother, Mark. He told him that he could keep them all if he could place all 16 on the table in such a way that they formed 15 rows with 4 coins in each row. \n\r\nAfter 10 minutes, Johnny walked away with the coins and Mark, after complaining futilely to his mother, left with nothing. \n\r\nHow did Johnny place the coins?", "hint": "Stars and pentagons", "answer": "If you draw a 5-pointed star with all sides of equal length, you will create a pentagon in the middle with all 5 sides of equal length. Then draw another 5 pointed star, upside-down, using the 5 points of the interior pentagon as the points of the inner star, This will give you another 5-sided pentagon in the interior of the second, smaller star. \n\r\nNow, take your 16 coins and place 5 on the outside points of the outside star. Then place 5 more on the points of each of the two pentagons you have created. Finally, place the last coin in the dead center of this drawing. \n\r\nThe lines are as follows:\r\n5 lines for the actual drawing of the outside star\r\n5 lines for the actual drawing of the inside star\r\n5 lines that start from any outside point of the outside star and go to the opposite point of the inside star, passing through 1 point of the inner pentagon, the dead center coin on the way.\n\r\nTotal lines: 15", "category": "Logic", "date": "09/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohnny was given 16 coins by his older, somewhat meaner brother, Mark. He told him that he could keep them all if he could place all 16 on the table in such a way that they formed 15 rows with 4 coins in each row. \n\r\nAfter 10 minutes, Johnny walked away with the coins and Mark, after complaining futilely to his mother, left with nothing. \n\r\nHow did Johnny place the coins?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you draw a 5-pointed star with all sides of equal length, you will create a pentagon in the middle with all 5 sides of equal length. Then draw another 5 pointed star, upside-down, using the 5 points of the interior pentagon as the points of the inner star, This will give you another 5-sided pentagon in the interior of the second, smaller star. \n\r\nNow, take your 16 coins and place 5 on the outside points of the outside star. Then place 5 more on the points of each of the two pentagons you have created. Finally, place the last coin in the dead center of this drawing. \n\r\nThe lines are as follows:\r\n5 lines for the actual drawing of the outside star\r\n5 lines for the actual drawing of the inside star\r\n5 lines that start from any outside point of the outside star and go to the opposite point of the inside star, passing through 1 point of the inner pentagon, the dead center coin on the way.\n\r\nTotal lines: 15\n<|im_start|>answer\nIf you draw a 5-pointed star with all sides of equal length, you will create a pentagon in the middle with all 5 sides of equal length. Then draw another 5 pointed star, upside-down, using the 5 points of the interior pentagon as the points of the inner star, This will give you another 5-sided pentagon in the interior of the second, smaller star. \n\r\nNow, take your 16 coins and place 5 on the outside points of the outside star. Then place 5 more on the points of each of the two pentagons you have created. Finally, place the last coin in the dead center of this drawing. \n\r\nThe lines are as follows:\r\n5 lines for the actual drawing of the outside star\r\n5 lines for the actual drawing of the inside star\r\n5 lines that start from any outside point of the outside star and go to the opposite point of the inside star, passing through 1 point of the inner pentagon, the dead center coin on the way.\n\r\nTotal lines: 15\n<|im_end|>" }, { "id": "#27090", "title": "Language of Light", "fun": 2.8, "difficulty": 2.65, "author": "Splatt", "desc": "The Language of Light represents concepts that are all helpful in personal growth. Each concept a.k.a. vibration or tone, is the middle path between two polarities. (Ex. Polarities Greed and Poverty combine to make Language of Light tone Abundance)\n\r\nThere are many life forms in the natural world that hold vibrations of specific tones. Determine which flower, herb, and mineral holds the vibration of the first five tones (Forgiveness, Structure, Power, Compassion, Breath of Life), as well as which color is used to paint each tone.\n\r\nFlowers: Lavender flower, Snap Dragon, Gardenia, Tulip, Poppy\r\nHerbs: Feverfew, Chamomile, Ginger,Saw Palmetto, Echinacea Purpurea\r\nMinerals: Amethyst, Rhodochrosite, Yellow Calcite, Aventurine, Amber\r\nColors: Pink, Lavender, Peach, Turquoise, Yellow\n\n\r\n1.\tForgiveness is not held by calcite or tulip. Rhodochrosite is not associated with feverfew, saw palmetto or snap dragon, however it is associated with pink.\r\n2.\tOf aventurine, amber and amethyst, one associates with saw palmetto, and another holds the vibration of compassion.\r\n3.\tSaw palmetto holds the same vibration as the lavender flower. Power is painted with peach color.\r\n4.\tStructure is held either by snap dragon or saw palmetto. Lavender flower holds the vibration of the same tone as the lavender color, and yellow calcite holds the vibration of the same tone as the yellow color.\r\n5.\tOf the five, there is the one painted with turquoise, the one you drink ginger tea for, the one with gardenia flower, the one with yellow calcite, and the structure tone.\r\n6.\tAmber is associated with poppy, tulip is associated with feverfew.\r\n7.\tA soothing chamomile tea would be appropriate while holding aventurine but not while sniffing tulip.\r\n8.\tIf working on Power, communing with amber would work, but not drinking Echinacea tea.", "hint": "Be careful to not confuse Lavender flower with lavender color. Also, you will need most of the grid to deduce the answers!", "answer": "(If you know your minerals, the correct colors match the stones.)\r\nForgiveness, Rhodochrosite, Gardenia, Echinacea Purpurea, Pink\r\nStructure, Amethyst, Lavender, Saw Palmetto, Lavender\r\nPower, Amber, Poppy, Ginger, Peach\r\nCompassion, Aventurine, Snap Dragon, Chamomile, Turquoise\r\nBreath of Life, Yellow Calcite, Tulip, Feverfew, Yellow", "category": "Logic-Grid", "date": "11/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Language of Light represents concepts that are all helpful in personal growth. Each concept a.k.a. vibration or tone, is the middle path between two polarities. (Ex. Polarities Greed and Poverty combine to make Language of Light tone Abundance)\n\r\nThere are many life forms in the natural world that hold vibrations of specific tones. Determine which flower, herb, and mineral holds the vibration of the first five tones (Forgiveness, Structure, Power, Compassion, Breath of Life), as well as which color is used to paint each tone.\n\r\nFlowers: Lavender flower, Snap Dragon, Gardenia, Tulip, Poppy\r\nHerbs: Feverfew, Chamomile, Ginger,Saw Palmetto, Echinacea Purpurea\r\nMinerals: Amethyst, Rhodochrosite, Yellow Calcite, Aventurine, Amber\r\nColors: Pink, Lavender, Peach, Turquoise, Yellow\n\n\r\n1.\tForgiveness is not held by calcite or tulip. Rhodochrosite is not associated with feverfew, saw palmetto or snap dragon, however it is associated with pink.\r\n2.\tOf aventurine, amber and amethyst, one associates with saw palmetto, and another holds the vibration of compassion.\r\n3.\tSaw palmetto holds the same vibration as the lavender flower. Power is painted with peach color.\r\n4.\tStructure is held either by snap dragon or saw palmetto. Lavender flower holds the vibration of the same tone as the lavender color, and yellow calcite holds the vibration of the same tone as the yellow color.\r\n5.\tOf the five, there is the one painted with turquoise, the one you drink ginger tea for, the one with gardenia flower, the one with yellow calcite, and the structure tone.\r\n6.\tAmber is associated with poppy, tulip is associated with feverfew.\r\n7.\tA soothing chamomile tea would be appropriate while holding aventurine but not while sniffing tulip.\r\n8.\tIf working on Power, communing with amber would work, but not drinking Echinacea tea.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(If you know your minerals, the correct colors match the stones.)\r\nForgiveness, Rhodochrosite, Gardenia, Echinacea Purpurea, Pink\r\nStructure, Amethyst, Lavender, Saw Palmetto, Lavender\r\nPower, Amber, Poppy, Ginger, Peach\r\nCompassion, Aventurine, Snap Dragon, Chamomile, Turquoise\r\nBreath of Life, Yellow Calcite, Tulip, Feverfew, Yellow\n<|im_start|>answer\n(If you know your minerals, the correct colors match the stones.)\r\nForgiveness, Rhodochrosite, Gardenia, Echinacea Purpurea, Pink\r\nStructure, Amethyst, Lavender, Saw Palmetto, Lavender\r\nPower, Amber, Poppy, Ginger, Peach\r\nCompassion, Aventurine, Snap Dragon, Chamomile, Turquoise\r\nBreath of Life, Yellow Calcite, Tulip, Feverfew, Yellow\n<|im_end|>" }, { "id": "#21850", "title": "Criminal Records", "fun": 2.8, "difficulty": 1.16, "author": "iconofsin", "desc": "You are the police chief for the city of Trunsville. Your records, all on computer, were deleted by a virus. Fortunately, you have remembered the following:\r\nYou have to get the data back before the criminals are released due to the lack of records!\r\nCriminals: Larry, Judith, Dwayne, Nicholas, Marty.\n\r\nCrime: Murder, assault, thief, robber, rape.\n\r\nSentences: 5 years, 10 years, 25 years, life, death.\n\r\nHere is what you remember:\n\r\n(1) Larry was the murderer.\r\n(2) Marty got 5 or 10 years.\r\n(3) Neither Nicholas nor Dwayne would ever leave prison alive (all others will)\r\n(4) The lady got 25 years.\r\n(5) Nicholas was not the thief.\r\n(6) The thief got life.\r\n(7) The assaulter got more than 10 years but did not get death.\r\n(8) The rapist gets 5 years.", "hint": "No hint available.", "answer": "Larry the murderer got 10 years.\r\nJudith the assaulter got 25 years.\r\nDwayne the thief got life.\r\nNicholas the robber got death.\r\nMarty the rapist got 5 years.", "category": "Logic-Grid", "date": "03/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are the police chief for the city of Trunsville. Your records, all on computer, were deleted by a virus. Fortunately, you have remembered the following:\r\nYou have to get the data back before the criminals are released due to the lack of records!\r\nCriminals: Larry, Judith, Dwayne, Nicholas, Marty.\n\r\nCrime: Murder, assault, thief, robber, rape.\n\r\nSentences: 5 years, 10 years, 25 years, life, death.\n\r\nHere is what you remember:\n\r\n(1) Larry was the murderer.\r\n(2) Marty got 5 or 10 years.\r\n(3) Neither Nicholas nor Dwayne would ever leave prison alive (all others will)\r\n(4) The lady got 25 years.\r\n(5) Nicholas was not the thief.\r\n(6) The thief got life.\r\n(7) The assaulter got more than 10 years but did not get death.\r\n(8) The rapist gets 5 years.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLarry the murderer got 10 years.\r\nJudith the assaulter got 25 years.\r\nDwayne the thief got life.\r\nNicholas the robber got death.\r\nMarty the rapist got 5 years.\n<|im_start|>answer\nLarry the murderer got 10 years.\r\nJudith the assaulter got 25 years.\r\nDwayne the thief got life.\r\nNicholas the robber got death.\r\nMarty the rapist got 5 years.\n<|im_end|>" }, { "id": "#21236", "title": "5 Books", "fun": 2.8, "difficulty": 1.73, "author": "cdrock", "desc": "My best friend just left the room and told me not to touch his books, but I wanted the book back that I have let him borrow. \r\nNot remembering which color book was mine I took them all off the shelf. The problem is I only remember a few things about the order of them and I can't seem to remember which one was mine. \r\nI heard my friend walking back down the hall so I have to think quick. \r\nFrom the information I remember about the books, can you figure out the order of the books and which one is mine?\n\r\n1. The blue book is not next to the green book, and two books away from the book I let him borrow. (one book in between) \n\r\n2. The yellow book is next to the blue book, but not the red book.\n\r\n3. The red book is the only book that isn't three books away from any other books (2 books in between). \n\r\n4. The yellow book is somewhere to the left of the green book.\n\r\n5. The green book is somewhere to the left of the purple book.", "hint": "No hint available.", "answer": "From (3), the red book must be in the middle. The yellow book cannot be to the right of the red book, as both the green and purple books must be to its right (4,5). Nor can yellow be next to red (2), so it is in the first position. From (2), blue must be in the second position. From (5) green and purple must be in position 4 and 5, respectively. \n\r\nThe books are therefore in this order:\r\nyellow, blue, red, green, purple\n\r\nFrom (1), my book is green.", "category": "Logic", "date": "02/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy best friend just left the room and told me not to touch his books, but I wanted the book back that I have let him borrow. \r\nNot remembering which color book was mine I took them all off the shelf. The problem is I only remember a few things about the order of them and I can't seem to remember which one was mine. \r\nI heard my friend walking back down the hall so I have to think quick. \r\nFrom the information I remember about the books, can you figure out the order of the books and which one is mine?\n\r\n1. The blue book is not next to the green book, and two books away from the book I let him borrow. (one book in between) \n\r\n2. The yellow book is next to the blue book, but not the red book.\n\r\n3. The red book is the only book that isn't three books away from any other books (2 books in between). \n\r\n4. The yellow book is somewhere to the left of the green book.\n\r\n5. The green book is somewhere to the left of the purple book.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom (3), the red book must be in the middle. The yellow book cannot be to the right of the red book, as both the green and purple books must be to its right (4,5). Nor can yellow be next to red (2), so it is in the first position. From (2), blue must be in the second position. From (5) green and purple must be in position 4 and 5, respectively. \n\r\nThe books are therefore in this order:\r\nyellow, blue, red, green, purple\n\r\nFrom (1), my book is green.\n<|im_start|>answer\nFrom (3), the red book must be in the middle. The yellow book cannot be to the right of the red book, as both the green and purple books must be to its right (4,5). Nor can yellow be next to red (2), so it is in the first position. From (2), blue must be in the second position. From (5) green and purple must be in position 4 and 5, respectively. \n\r\nThe books are therefore in this order:\r\nyellow, blue, red, green, purple\n\r\nFrom (1), my book is green.\n<|im_end|>" }, { "id": "#31765", "title": "A Simple Question", "fun": 2.8, "difficulty": 2.3, "author": "bigSWAFF_69_", "desc": "Instead of creating a very difficult teaser, I have decided to create a simple Yes or No question. Have fun trying to solve it!\n\n\r\nIf the teaser you solved before you solved the teaser you solved after you solved the teaser you solved before you solved this one, was harder than the teaser you solved after you solved the teaser you solved before you solved this one, was the teaser you solved before you solved this one harder than this one?\" Yes or no?", "hint": "No hint available.", "answer": "Yes\n\n\r\nThe one you did after the one you did before this one, IS this one. In other words: \"...The teaser you solved after you solved the teaser you solved before this one\" IS this one.\n\r\nThe question could be rephrased this way:\n\r\n\"If the teaser you solved before this one was harder than THIS ONE, was the teaser you solved before this one harder than THIS ONE?\". The answer is obviously \"Yes\", that wasn't so hard, now was it?", "category": "Logic", "date": "07/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nInstead of creating a very difficult teaser, I have decided to create a simple Yes or No question. Have fun trying to solve it!\n\n\r\nIf the teaser you solved before you solved the teaser you solved after you solved the teaser you solved before you solved this one, was harder than the teaser you solved after you solved the teaser you solved before you solved this one, was the teaser you solved before you solved this one harder than this one?\" Yes or no?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes\n\n\r\nThe one you did after the one you did before this one, IS this one. In other words: \"...The teaser you solved after you solved the teaser you solved before this one\" IS this one.\n\r\nThe question could be rephrased this way:\n\r\n\"If the teaser you solved before this one was harder than THIS ONE, was the teaser you solved before this one harder than THIS ONE?\". The answer is obviously \"Yes\", that wasn't so hard, now was it?\n<|im_start|>answer\nYes\n\n\r\nThe one you did after the one you did before this one, IS this one. In other words: \"...The teaser you solved after you solved the teaser you solved before this one\" IS this one.\n\r\nThe question could be rephrased this way:\n\r\n\"If the teaser you solved before this one was harder than THIS ONE, was the teaser you solved before this one harder than THIS ONE?\". The answer is obviously \"Yes\", that wasn't so hard, now was it?\n<|im_end|>" }, { "id": "#37640", "title": "Day Off", "fun": 2.8, "difficulty": 1.44, "author": "npf2005", "desc": "Ten men paired up in order to enjoy a day away from the office, doing something other than work.\n\r\nWho went with who, on which day, and what did they do?\n\r\n1. Tim met his friend (not Billy) on Tuesday for several games of badminton.\n\r\n2. Miles went bird-watching on his day off.\n\r\n3. Jack and Joe paired up to enjoy themselves but weren't the two who met for a round of golf on Friday.\n\r\n4. Harry went fishing on Monday but not with Andy.\n\r\n5. Steve went out on Wednesday.", "hint": "No hint available.", "answer": "Billy - Andy - Friday - golf\n\r\nHarry - Kenny - Fishing - Monday \n\r\nJack - Joe - Swimming - Thursday\n\r\nRay - Tim - Badminton - Tuesday\n\r\nSteve - Miles - Bird-watching - Wednesday", "category": "Logic-Grid", "date": "08/03/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTen men paired up in order to enjoy a day away from the office, doing something other than work.\n\r\nWho went with who, on which day, and what did they do?\n\r\n1. Tim met his friend (not Billy) on Tuesday for several games of badminton.\n\r\n2. Miles went bird-watching on his day off.\n\r\n3. Jack and Joe paired up to enjoy themselves but weren't the two who met for a round of golf on Friday.\n\r\n4. Harry went fishing on Monday but not with Andy.\n\r\n5. Steve went out on Wednesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBilly - Andy - Friday - golf\n\r\nHarry - Kenny - Fishing - Monday \n\r\nJack - Joe - Swimming - Thursday\n\r\nRay - Tim - Badminton - Tuesday\n\r\nSteve - Miles - Bird-watching - Wednesday\n<|im_start|>answer\nBilly - Andy - Friday - golf\n\r\nHarry - Kenny - Fishing - Monday \n\r\nJack - Joe - Swimming - Thursday\n\r\nRay - Tim - Badminton - Tuesday\n\r\nSteve - Miles - Bird-watching - Wednesday\n<|im_end|>" }, { "id": "#36057", "title": "More Notes On the Warm Coats", "fun": 2.8, "difficulty": 1.61, "author": "chaskey", "desc": "This past winter, when four friends donated their extra coats to charity, they told their girlfriends about it, and were not surprised to learn that the girlfriends had also donated extra coats.\n\r\nFour friends: Robert, Roy, Charles, Donald\r\nGirlfriends (in no relevant order): Alice, Virginia, Margaret, Nell\r\nCoat fabrics: wool, faux fur, faux leather, corduroy\r\nCoat ages: 2, 4, 6, 7 years\r\nCoat conditions: fair, good, very good, excellent\n\r\nClues:\r\n1. Donald already knew about Virginia's faux leather coat, because he had bought it new for her six years earlier.\n\r\n2. The faux fur was in only fair condition because the dog mistook it for an encroaching animal; the coat was only half as old as the wool coat Alice told Charles about.\n\r\n3. The coat that was in very good condition was five years older than Nell's coat.\n\r\n4. The coat that was in good condition was four years older than the faux fur that Roy heard about.", "hint": "No hint available.", "answer": "Margaret told Robert about her corduroy coat, 7 years old, in very good condition.\n\r\nNell told Roy about a faux fur, 2 years old, in fair condition.\n\r\nAlice told Charles about a wool coat, 4 years old, in excellent condition.\n\r\nVirginia told Donald about the faux leather coat, 6 years old, in good condition.", "category": "Logic-Grid", "date": "04/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis past winter, when four friends donated their extra coats to charity, they told their girlfriends about it, and were not surprised to learn that the girlfriends had also donated extra coats.\n\r\nFour friends: Robert, Roy, Charles, Donald\r\nGirlfriends (in no relevant order): Alice, Virginia, Margaret, Nell\r\nCoat fabrics: wool, faux fur, faux leather, corduroy\r\nCoat ages: 2, 4, 6, 7 years\r\nCoat conditions: fair, good, very good, excellent\n\r\nClues:\r\n1. Donald already knew about Virginia's faux leather coat, because he had bought it new for her six years earlier.\n\r\n2. The faux fur was in only fair condition because the dog mistook it for an encroaching animal; the coat was only half as old as the wool coat Alice told Charles about.\n\r\n3. The coat that was in very good condition was five years older than Nell's coat.\n\r\n4. The coat that was in good condition was four years older than the faux fur that Roy heard about.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMargaret told Robert about her corduroy coat, 7 years old, in very good condition.\n\r\nNell told Roy about a faux fur, 2 years old, in fair condition.\n\r\nAlice told Charles about a wool coat, 4 years old, in excellent condition.\n\r\nVirginia told Donald about the faux leather coat, 6 years old, in good condition.\n<|im_start|>answer\nMargaret told Robert about her corduroy coat, 7 years old, in very good condition.\n\r\nNell told Roy about a faux fur, 2 years old, in fair condition.\n\r\nAlice told Charles about a wool coat, 4 years old, in excellent condition.\n\r\nVirginia told Donald about the faux leather coat, 6 years old, in good condition.\n<|im_end|>" }, { "id": "#49522", "title": "Colorful Quintet", "fun": 2.8, "difficulty": 2.26, "author": "Rhythmic", "desc": "Aaron, Chester, Leon, Mark, and Randy all play in a saxophone quintet together. They all play different colors of instruments. They all have nicknames they use when they're on stage. Can you figure out who has what nickname and which instrument each of them plays?\n\r\nFirst Names: Aaron, Chester, Leon, Mark, Randy\r\nNicknames: Heatwave, Nighttime, Polar Bear, Rainbow, Spectrum\r\nInstruments: Soprano Sax, Alto Sax, Alto Sax, Tenor Sax, Baritone (or Bari) Sax\r\nInstrument Colors: Black, Blue, Gold, Red, Silver\n\r\n1) One person has a nickname that starts with the same letter as the color of his sax. Another has a nickname that starts with the same letter as the type of sax he has.\n\r\n2) Heatwave, the tenor sax player, often plays duets with Aaron.\n\r\n3) Randy's sax and the blue sax are both altos.\n\r\n4) The gold sax is smaller (or higher) than Leon's and bigger (or lower) than the red one.\n\r\n5) Polar Bear got his nickname because his sax color and his white beard remind the others of the arctic ice and snow. \n\r\n6) One time Nighttime lost his neck strap. The gold sax player could not help him. Luckily, Chester had a spare.", "hint": "Of the four sax types in this puzzle, the soprano is the smallest (or highest), followed by the alto and the tenor. The baritone is the biggest (or lowest) or them.\n\r\nSilver is the color closest to ice.", "answer": "Aaron's nickname is Nighttime and he plays an alto sax that is blue.\r\nChester's nickname is Spectrum and he plays a soprano sax that is black.\r\nLeon's nickname is Polar Bear and he plays a baritone sax that is silver.\r\nMark's nickname is Heatwave and he plays a tenor sax that is gold.\r\nRandy's nickname is Rainbow and he plays an alto sax that is red.", "category": "Logic-Grid", "date": "06/26/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAaron, Chester, Leon, Mark, and Randy all play in a saxophone quintet together. They all play different colors of instruments. They all have nicknames they use when they're on stage. Can you figure out who has what nickname and which instrument each of them plays?\n\r\nFirst Names: Aaron, Chester, Leon, Mark, Randy\r\nNicknames: Heatwave, Nighttime, Polar Bear, Rainbow, Spectrum\r\nInstruments: Soprano Sax, Alto Sax, Alto Sax, Tenor Sax, Baritone (or Bari) Sax\r\nInstrument Colors: Black, Blue, Gold, Red, Silver\n\r\n1) One person has a nickname that starts with the same letter as the color of his sax. Another has a nickname that starts with the same letter as the type of sax he has.\n\r\n2) Heatwave, the tenor sax player, often plays duets with Aaron.\n\r\n3) Randy's sax and the blue sax are both altos.\n\r\n4) The gold sax is smaller (or higher) than Leon's and bigger (or lower) than the red one.\n\r\n5) Polar Bear got his nickname because his sax color and his white beard remind the others of the arctic ice and snow. \n\r\n6) One time Nighttime lost his neck strap. The gold sax player could not help him. Luckily, Chester had a spare.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAaron's nickname is Nighttime and he plays an alto sax that is blue.\r\nChester's nickname is Spectrum and he plays a soprano sax that is black.\r\nLeon's nickname is Polar Bear and he plays a baritone sax that is silver.\r\nMark's nickname is Heatwave and he plays a tenor sax that is gold.\r\nRandy's nickname is Rainbow and he plays an alto sax that is red.\n<|im_start|>answer\nAaron's nickname is Nighttime and he plays an alto sax that is blue.\r\nChester's nickname is Spectrum and he plays a soprano sax that is black.\r\nLeon's nickname is Polar Bear and he plays a baritone sax that is silver.\r\nMark's nickname is Heatwave and he plays a tenor sax that is gold.\r\nRandy's nickname is Rainbow and he plays an alto sax that is red.\n<|im_end|>" }, { "id": "#40662", "title": "Chess Tournament 3", "fun": 2.8, "difficulty": 2.02, "author": "soccerguy0428", "desc": "10 friends gathered to play in a chess tournament. If a person beat someone else in a game, the person who won received a higher place than the person who lost. With the information below, can you determine the place everyone got?\n\r\nBoys: Connor, Jeremy, Mark, Matt, Tyler\n\r\nGirls: Alyssa, Caitlin, Isabella, Kelsey, Megan\n\r\n1. Matt and Mark got 3rd and 7th place.\n\r\n2. Connor lost to only one boy and beat every girl.\n\r\n3. Megan barely beat Caitlin.\n\r\n4. Isabella and Tyler got the best places for their genders.\n\r\n5. Matt beat Kelsey.\n\r\n6. Alyssa only beat one girl and lost to every boy.\n\r\n7. Jeremy was right behind Isabella and right in front of Kelsey in places.", "hint": "Jeremy got 5th place in the tournament.", "answer": "The results were as follows:\n\r\n1st- Tyler\r\n2nd- Connor\r\n3rd- Matt\r\n4th- Isabella\r\n5th- Jeremy\r\n6th- Kelsey\r\n7th- Mark\r\n8th- Megan\r\n9th- Alyssa\r\n10th- Caitlin", "category": "Logic", "date": "02/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n10 friends gathered to play in a chess tournament. If a person beat someone else in a game, the person who won received a higher place than the person who lost. With the information below, can you determine the place everyone got?\n\r\nBoys: Connor, Jeremy, Mark, Matt, Tyler\n\r\nGirls: Alyssa, Caitlin, Isabella, Kelsey, Megan\n\r\n1. Matt and Mark got 3rd and 7th place.\n\r\n2. Connor lost to only one boy and beat every girl.\n\r\n3. Megan barely beat Caitlin.\n\r\n4. Isabella and Tyler got the best places for their genders.\n\r\n5. Matt beat Kelsey.\n\r\n6. Alyssa only beat one girl and lost to every boy.\n\r\n7. Jeremy was right behind Isabella and right in front of Kelsey in places.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe results were as follows:\n\r\n1st- Tyler\r\n2nd- Connor\r\n3rd- Matt\r\n4th- Isabella\r\n5th- Jeremy\r\n6th- Kelsey\r\n7th- Mark\r\n8th- Megan\r\n9th- Alyssa\r\n10th- Caitlin\n<|im_start|>answer\nThe results were as follows:\n\r\n1st- Tyler\r\n2nd- Connor\r\n3rd- Matt\r\n4th- Isabella\r\n5th- Jeremy\r\n6th- Kelsey\r\n7th- Mark\r\n8th- Megan\r\n9th- Alyssa\r\n10th- Caitlin\n<|im_end|>" }, { "id": "#49618", "title": "Sunnies", "fun": 2.8, "difficulty": 1.35, "author": "dalfamnest", "desc": "It was going to be another really hot day, but Ted needed a new pair of cool sunnies* before he could hit the surf. He needed another $52 to buy the ones he wanted.\n\r\nTed decided to sell home-made smoothies at his gate: $2 each, or three for $4. He had the $52 after selling 32 smoothies, stopped work and headed off to the beach.\n\r\nHow many smoothies had been sold at the $2 price?\n\n\r\n* sunnies = sunglasses in New Zealand & Australia", "hint": "No hint available.", "answer": "14\r\n[14 @ $2 = $28; 18 @ 3 for $4 = $24]\n\r\nSolution:\r\nIf he had sold them all at $2, he would have earned $64. The $12 difference is the discount he gave to six people buying 3 for $4.\n\r\nSo 18 were sold at the discount price - the other 14 were sold individually.", "category": "Math", "date": "10/06/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was going to be another really hot day, but Ted needed a new pair of cool sunnies* before he could hit the surf. He needed another $52 to buy the ones he wanted.\n\r\nTed decided to sell home-made smoothies at his gate: $2 each, or three for $4. He had the $52 after selling 32 smoothies, stopped work and headed off to the beach.\n\r\nHow many smoothies had been sold at the $2 price?\n\n\r\n* sunnies = sunglasses in New Zealand & Australia\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n14\r\n[14 @ $2 = $28; 18 @ 3 for $4 = $24]\n\r\nSolution:\r\nIf he had sold them all at $2, he would have earned $64. The $12 difference is the discount he gave to six people buying 3 for $4.\n\r\nSo 18 were sold at the discount price - the other 14 were sold individually.\n<|im_start|>answer\n14\r\n[14 @ $2 = $28; 18 @ 3 for $4 = $24]\n\r\nSolution:\r\nIf he had sold them all at $2, he would have earned $64. The $12 difference is the discount he gave to six people buying 3 for $4.\n\r\nSo 18 were sold at the discount price - the other 14 were sold individually.\n<|im_end|>" }, { "id": "#10345", "title": "Rags to Riches", "fun": 2.8, "difficulty": 2.97, "author": "Codammanus", "desc": "One day, an eccentric billionaire decided to give a destitute man a break. But not a total break, as we shall see. So, he invites him into a room in his mansion with seven doors. There is also a large-screen projector that projects the following five images, repeatedly, one at a time: \n\r\nA human brain, Earth, the incomplete phrase: 'Fair and ____,' the letters AZCONMUT and a cheese sandwich on plain white bread with the edges perfectly cut off. \n\r\nThe poor man was allowed an entire day to study the images, after which he would have to choose the door that corresponded to the commonality of the images. The next day the man walked through the correct door, and the billionaire made him rich. What door did the man choose?", "hint": "Take a snack break, have one of the images.", "answer": "The man chose door number FOUR. Here's why: \n\r\nThe image of the human brain made the man think of 'four corners of the mind.' \r\nHe recognized the capital letters AZCONMUT to be the abbreviations of the 'Four corner states' Arizona, Colorado, New Mexico, and Utah. He completed the phrase \r\n'Fair and ____' with the word SQUARE, which also has also four corners. When he got hungry, he ordered the same sandwich in the last image. But instead of eating right away, he studied it, until he got the point that it too had four corners. Thus, the poor guy walked into a mansion poorer than poor, and walked out with a cheese sandwich, and enough dough to buy a small country. What he actually did with the money is anybody's guess.", "category": "Logic", "date": "02/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, an eccentric billionaire decided to give a destitute man a break. But not a total break, as we shall see. So, he invites him into a room in his mansion with seven doors. There is also a large-screen projector that projects the following five images, repeatedly, one at a time: \n\r\nA human brain, Earth, the incomplete phrase: 'Fair and ____,' the letters AZCONMUT and a cheese sandwich on plain white bread with the edges perfectly cut off. \n\r\nThe poor man was allowed an entire day to study the images, after which he would have to choose the door that corresponded to the commonality of the images. The next day the man walked through the correct door, and the billionaire made him rich. What door did the man choose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man chose door number FOUR. Here's why: \n\r\nThe image of the human brain made the man think of 'four corners of the mind.' \r\nHe recognized the capital letters AZCONMUT to be the abbreviations of the 'Four corner states' Arizona, Colorado, New Mexico, and Utah. He completed the phrase \r\n'Fair and ____' with the word SQUARE, which also has also four corners. When he got hungry, he ordered the same sandwich in the last image. But instead of eating right away, he studied it, until he got the point that it too had four corners. Thus, the poor guy walked into a mansion poorer than poor, and walked out with a cheese sandwich, and enough dough to buy a small country. What he actually did with the money is anybody's guess.\n<|im_start|>answer\nThe man chose door number FOUR. Here's why: \n\r\nThe image of the human brain made the man think of 'four corners of the mind.' \r\nHe recognized the capital letters AZCONMUT to be the abbreviations of the 'Four corner states' Arizona, Colorado, New Mexico, and Utah. He completed the phrase \r\n'Fair and ____' with the word SQUARE, which also has also four corners. When he got hungry, he ordered the same sandwich in the last image. But instead of eating right away, he studied it, until he got the point that it too had four corners. Thus, the poor guy walked into a mansion poorer than poor, and walked out with a cheese sandwich, and enough dough to buy a small country. What he actually did with the money is anybody's guess.\n<|im_end|>" }, { "id": "#26705", "title": "Deal?", "fun": 2.8, "difficulty": 1.85, "author": "ilovehimalways", "desc": "It has been a busy month for music promoter Charlie Banks. He's traveled to 5 towns on leads, and , in each town, he was able to sign a band with a different lead singer. Each band performs a different type of music. Determine the band from each town, the lead singer, and the type of music.\n\r\n1) Roz Trotter isn't the lead singer for the Buzztones, who are the rockabilly band.\r\n2) The Pea People play reggae music. Sandwich Shop is the band from Whitehall.\r\n3) The rap band is from Lombard, Illinois.\r\n4) Richard Van Stone is the lead singer for the heavy-metal band.\r\n5) The Heatseekers, who aren't the band from Florissant, aren't the folk band, which is fronted by Dr. Sonic.\r\n6) Stig O'Tracy is the lead singer of the Crazy Club.\r\n7) Flo Fontana's band is from Junction City.", "hint": "JC = Junction City\r\nSS = Sandwich Shop", "answer": "Junction City-Buzztones-Fontana-Rockabilly\r\nLombard-Crazy Club-Stig O'Tracy-Rap\r\nLewisburg-Heatseekers-Richard Van Stone-Heavy Metal\r\nFlorissant-Pea People-Roz Trotter-Reggae\r\nWhitehall-Sandwich Shop-Dr. Sonic-Folk", "category": "Logic-Grid", "date": "11/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt has been a busy month for music promoter Charlie Banks. He's traveled to 5 towns on leads, and , in each town, he was able to sign a band with a different lead singer. Each band performs a different type of music. Determine the band from each town, the lead singer, and the type of music.\n\r\n1) Roz Trotter isn't the lead singer for the Buzztones, who are the rockabilly band.\r\n2) The Pea People play reggae music. Sandwich Shop is the band from Whitehall.\r\n3) The rap band is from Lombard, Illinois.\r\n4) Richard Van Stone is the lead singer for the heavy-metal band.\r\n5) The Heatseekers, who aren't the band from Florissant, aren't the folk band, which is fronted by Dr. Sonic.\r\n6) Stig O'Tracy is the lead singer of the Crazy Club.\r\n7) Flo Fontana's band is from Junction City.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJunction City-Buzztones-Fontana-Rockabilly\r\nLombard-Crazy Club-Stig O'Tracy-Rap\r\nLewisburg-Heatseekers-Richard Van Stone-Heavy Metal\r\nFlorissant-Pea People-Roz Trotter-Reggae\r\nWhitehall-Sandwich Shop-Dr. Sonic-Folk\n<|im_start|>answer\nJunction City-Buzztones-Fontana-Rockabilly\r\nLombard-Crazy Club-Stig O'Tracy-Rap\r\nLewisburg-Heatseekers-Richard Van Stone-Heavy Metal\r\nFlorissant-Pea People-Roz Trotter-Reggae\r\nWhitehall-Sandwich Shop-Dr. Sonic-Folk\n<|im_end|>" }, { "id": "#7826", "title": "Footnotes", "fun": 2.8, "difficulty": 1.47, "author": "just_moi", "desc": "A, who knows only French, publishes an article in an English magazine. At the end of the article are the following 3 footnotes:\n\r\n1. I thank my friend B for translating the above article into English so that it could be published in this magazine.\n\r\n2. I thank my friend B for translating the above footnote.\n\r\n3. I thank my friend B for translating the above footnote.\n\r\nWhy are there only 3 footnotes when logically, A will have to go on forever to be able to thank B properly???", "hint": "No hint available.", "answer": "When B translates footnote 2 to English, A just copies it as it is in English , thereby eliminating the need for footnote 3 to be translated. A therefore doesn't have to thank B anymore!!!", "category": "Logic", "date": "10/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA, who knows only French, publishes an article in an English magazine. At the end of the article are the following 3 footnotes:\n\r\n1. I thank my friend B for translating the above article into English so that it could be published in this magazine.\n\r\n2. I thank my friend B for translating the above footnote.\n\r\n3. I thank my friend B for translating the above footnote.\n\r\nWhy are there only 3 footnotes when logically, A will have to go on forever to be able to thank B properly???\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen B translates footnote 2 to English, A just copies it as it is in English , thereby eliminating the need for footnote 3 to be translated. A therefore doesn't have to thank B anymore!!!\n<|im_start|>answer\nWhen B translates footnote 2 to English, A just copies it as it is in English , thereby eliminating the need for footnote 3 to be translated. A therefore doesn't have to thank B anymore!!!\n<|im_end|>" }, { "id": "#26213", "title": "Crack the Code", "fun": 2.8, "difficulty": 2.72, "author": "peanut", "desc": "In an attempt to further protect his secret chicken recipe, Colonel Sanders has locked it away in a safe with a 10-digit password. Unable to resist his crispy fried chicken, you'd like to crack the code. Try your luck using the following information:\n\r\nAll digits from 0 to 9 are used exactly once.\r\nNo digit is the same as the position which it occupies in the sequence.\r\nThe sum of the 5th and 10th digits is a square number other than 9.\r\nThe sum of the 9th and 10th digits is a cube.\r\nThe 2nd digit is an even number.\r\nZero is in the 3rd position.\r\nThe sum of the 4th, 6th and 8th digits is a single digit number.\r\nThe sum of the 2nd and 5th digits is a triangle number.\r\nNumber 8 is 2 spaces away from the number 9 (one in between).\r\nThe number 3 is next to the 9 but not the zero.", "hint": "A triangle number is one which can be written with one number on the first line, 2 on the second, 3 on the third etc. Like ten-pin bowling style! (The first of these are 1, 3, 6)", "answer": "5 6 0 2 9 3 8 4 1 7", "category": "Logic", "date": "10/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn an attempt to further protect his secret chicken recipe, Colonel Sanders has locked it away in a safe with a 10-digit password. Unable to resist his crispy fried chicken, you'd like to crack the code. Try your luck using the following information:\n\r\nAll digits from 0 to 9 are used exactly once.\r\nNo digit is the same as the position which it occupies in the sequence.\r\nThe sum of the 5th and 10th digits is a square number other than 9.\r\nThe sum of the 9th and 10th digits is a cube.\r\nThe 2nd digit is an even number.\r\nZero is in the 3rd position.\r\nThe sum of the 4th, 6th and 8th digits is a single digit number.\r\nThe sum of the 2nd and 5th digits is a triangle number.\r\nNumber 8 is 2 spaces away from the number 9 (one in between).\r\nThe number 3 is next to the 9 but not the zero.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 6 0 2 9 3 8 4 1 7\n<|im_start|>answer\n5 6 0 2 9 3 8 4 1 7\n<|im_end|>" }, { "id": "#288", "title": "A Chess Game", "fun": 2.8, "difficulty": 1.91, "author": "Phyllis", "desc": "A man who had never won a game of chess with his friend, one day bet him that he could simultaneously play two chess games with him, and either win one of the games or draw both of them. He made only one stipulation, which was that they alternate their moves on two separate chess boards and that on one board he got to play black while on the other board he got to play white. He said that he was so confident that he would win this bet that he would let his friend play first. His friend accepted the challenge. How was the man able to win this bet?", "hint": "No hint available.", "answer": "The friend opened with a white move on the first board. The man then made the same opening move with white on the second board. The friend made his answering black move on board two. The man then made this same answering move with black on board one. They played back and forth with the man always using his friend's moves on one board as his own moves on the other board. This meant that the friend was playing himself and that if he won one of the games he would lose the other game, or he could draw both games. But, in no way could he win both of the games!", "category": "Logic", "date": "02/18/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man who had never won a game of chess with his friend, one day bet him that he could simultaneously play two chess games with him, and either win one of the games or draw both of them. He made only one stipulation, which was that they alternate their moves on two separate chess boards and that on one board he got to play black while on the other board he got to play white. He said that he was so confident that he would win this bet that he would let his friend play first. His friend accepted the challenge. How was the man able to win this bet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe friend opened with a white move on the first board. The man then made the same opening move with white on the second board. The friend made his answering black move on board two. The man then made this same answering move with black on board one. They played back and forth with the man always using his friend's moves on one board as his own moves on the other board. This meant that the friend was playing himself and that if he won one of the games he would lose the other game, or he could draw both games. But, in no way could he win both of the games!\n<|im_start|>answer\nThe friend opened with a white move on the first board. The man then made the same opening move with white on the second board. The friend made his answering black move on board two. The man then made this same answering move with black on board one. They played back and forth with the man always using his friend's moves on one board as his own moves on the other board. This meant that the friend was playing himself and that if he won one of the games he would lose the other game, or he could draw both games. But, in no way could he win both of the games!\n<|im_end|>" }, { "id": "#25911", "title": "Slow and Stupid Wins the Race?", "fun": 2.8, "difficulty": 2.19, "author": "norcekri", "desc": "Hare and Tortoise had to take a make-up class in math over the summer, a two-month, self-paced course with a test at the end of each of 12 chapters. The course requires a 70% grade to pass.\n\r\nIn the first month, they both had difficulties with the concepts. Hare averaged 60% on his exams; Tortoise averaged 50%. Owl, the supervisor, spent three days of the next week helping them with their difficulties.\n\r\nIt worked. In the second month, Hare averaged 90% on his exams; Tortoise averaged 80%.\n\r\nHowever, Tortoise got a passing grade of 75% in the class; Hare failed with 65%. When Hare protested to Owl that he'd outscored Tortoise in both months, Owl made Hare do the math on the board -- and sign up for another make-up class, after school in the fall.\n\r\nHow did Tortoise pass while Hare flunked?", "hint": "They worked at different speeds.", "answer": "In the first month, Hare took 10 chapter tests; Tortoise took only 2. In the second month, Hare took his remaining 2 exams and Tortoise took the 10 he needed to finish.\n\r\nHare's average = (10*60 + 2*90) / 12 = 780/12 = 65\n\r\nTortoise's average = (2*50 + 10*80)/12 = 900/12 = 75\n\r\nMathematicians know this as Simpson's paradox.", "category": "Math", "date": "09/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHare and Tortoise had to take a make-up class in math over the summer, a two-month, self-paced course with a test at the end of each of 12 chapters. The course requires a 70% grade to pass.\n\r\nIn the first month, they both had difficulties with the concepts. Hare averaged 60% on his exams; Tortoise averaged 50%. Owl, the supervisor, spent three days of the next week helping them with their difficulties.\n\r\nIt worked. In the second month, Hare averaged 90% on his exams; Tortoise averaged 80%.\n\r\nHowever, Tortoise got a passing grade of 75% in the class; Hare failed with 65%. When Hare protested to Owl that he'd outscored Tortoise in both months, Owl made Hare do the math on the board -- and sign up for another make-up class, after school in the fall.\n\r\nHow did Tortoise pass while Hare flunked?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn the first month, Hare took 10 chapter tests; Tortoise took only 2. In the second month, Hare took his remaining 2 exams and Tortoise took the 10 he needed to finish.\n\r\nHare's average = (10*60 + 2*90) / 12 = 780/12 = 65\n\r\nTortoise's average = (2*50 + 10*80)/12 = 900/12 = 75\n\r\nMathematicians know this as Simpson's paradox.\n<|im_start|>answer\nIn the first month, Hare took 10 chapter tests; Tortoise took only 2. In the second month, Hare took his remaining 2 exams and Tortoise took the 10 he needed to finish.\n\r\nHare's average = (10*60 + 2*90) / 12 = 780/12 = 65\n\r\nTortoise's average = (2*50 + 10*80)/12 = 900/12 = 75\n\r\nMathematicians know this as Simpson's paradox.\n<|im_end|>" }, { "id": "#42770", "title": "Drunk at the Pub", "fun": 2.8, "difficulty": 1.72, "author": "cookieruler", "desc": "5 men were at a pub. They each had a certain amount of money, had ordered a certain amount of drinks, lived in different areas, and were different ages. They were so drunk, they couldn't remember any of this information. The bartender knew, but was having trouble because he was also drunk. He knew some clues though...\n\r\nThe men are Matt, Joe, Steve, Alex, and Fred\r\nOne man has had 12 drinks, another had 18, another had 26, another had 34, and the last had 50.\r\nOne man has $12, one man has $49, another has $67, another has $83, and the last man has $91.\r\nOne man lives in Berlin, one lives in Claremont, another lives in Concord, another lives in Dover, and the last lives in Franklin.\r\nOne man is 21, one is 26, one is 35, one is 49, and the last is 67. \r\nHelp the bartender sort out these men.\n\r\n1. The man from Concord ordered the same amount of drinks as his age and had the same amount of money as another man's age\r\n2. The man from Dover had a birthday yesterday and today was the first day he was able to legally drink, so he ordered the least amount of drinks, but had the most amount of money.\r\n3. Matt had more drinks than the men from Berlin and Dover, but less money than both of them.\r\n4. Alex received $67 for Christmas and used it to buy 50 drinks.\r\n5. Joe had the second most amount of money and the second least amount of drinks.\r\n6. Fred had 34 drinks.\r\n7. The oldest man, from Franklin, had the least amount of money and the second most amount of drink, so he borrowed some money from Steve.\r\n8. The person with $83 is from Berlin.\r\n9. Joe turns 50 tomorrow.", "hint": "No hint available.", "answer": "Matt is 26, from Concord, and had $49 and 26 drinks.\n\r\nJoe is 49, from Berlin, and had $83 and 18 drinks.\n\r\nSteve is 21, from Dover, and had $91 and 12 drinks.\n\r\nAlex is 35, from Claremont, and had $67 and 50 drinks.\n\r\nFred is 67, from Franklin, and had $12 and 34 drinks.", "category": "Logic-Grid", "date": "08/13/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 men were at a pub. They each had a certain amount of money, had ordered a certain amount of drinks, lived in different areas, and were different ages. They were so drunk, they couldn't remember any of this information. The bartender knew, but was having trouble because he was also drunk. He knew some clues though...\n\r\nThe men are Matt, Joe, Steve, Alex, and Fred\r\nOne man has had 12 drinks, another had 18, another had 26, another had 34, and the last had 50.\r\nOne man has $12, one man has $49, another has $67, another has $83, and the last man has $91.\r\nOne man lives in Berlin, one lives in Claremont, another lives in Concord, another lives in Dover, and the last lives in Franklin.\r\nOne man is 21, one is 26, one is 35, one is 49, and the last is 67. \r\nHelp the bartender sort out these men.\n\r\n1. The man from Concord ordered the same amount of drinks as his age and had the same amount of money as another man's age\r\n2. The man from Dover had a birthday yesterday and today was the first day he was able to legally drink, so he ordered the least amount of drinks, but had the most amount of money.\r\n3. Matt had more drinks than the men from Berlin and Dover, but less money than both of them.\r\n4. Alex received $67 for Christmas and used it to buy 50 drinks.\r\n5. Joe had the second most amount of money and the second least amount of drinks.\r\n6. Fred had 34 drinks.\r\n7. The oldest man, from Franklin, had the least amount of money and the second most amount of drink, so he borrowed some money from Steve.\r\n8. The person with $83 is from Berlin.\r\n9. Joe turns 50 tomorrow.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMatt is 26, from Concord, and had $49 and 26 drinks.\n\r\nJoe is 49, from Berlin, and had $83 and 18 drinks.\n\r\nSteve is 21, from Dover, and had $91 and 12 drinks.\n\r\nAlex is 35, from Claremont, and had $67 and 50 drinks.\n\r\nFred is 67, from Franklin, and had $12 and 34 drinks.\n<|im_start|>answer\nMatt is 26, from Concord, and had $49 and 26 drinks.\n\r\nJoe is 49, from Berlin, and had $83 and 18 drinks.\n\r\nSteve is 21, from Dover, and had $91 and 12 drinks.\n\r\nAlex is 35, from Claremont, and had $67 and 50 drinks.\n\r\nFred is 67, from Franklin, and had $12 and 34 drinks.\n<|im_end|>" }, { "id": "#50929", "title": "Magic Triangles", "fun": 2.8, "difficulty": 2.16, "author": "MarcM1098", "desc": "You've heard of Magic Squares; now it's time to meet Magic Triangles.\n\r\nArrange the numbers 1 through 6 on a triangle, placing one number at each point and one number along each side between the points, such that the sum of the three numbers on any given side is equal.\n\r\nOnce you account for rotation/reflection, there are four unique answers; each has a different sum. See if you can find them all!", "hint": "The four solutions have sum 9, 10, 11, and 12.", "answer": "Sum 9 - sides are 153, 342, and 261.\r\nSum 10 - sides are 145, 523, and 361.\r\nSum 11 - sides are 236, 614, and 452.\r\nSum 12 - sides are 426, 615, and 534.", "category": "Math", "date": "01/13/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou've heard of Magic Squares; now it's time to meet Magic Triangles.\n\r\nArrange the numbers 1 through 6 on a triangle, placing one number at each point and one number along each side between the points, such that the sum of the three numbers on any given side is equal.\n\r\nOnce you account for rotation/reflection, there are four unique answers; each has a different sum. See if you can find them all!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSum 9 - sides are 153, 342, and 261.\r\nSum 10 - sides are 145, 523, and 361.\r\nSum 11 - sides are 236, 614, and 452.\r\nSum 12 - sides are 426, 615, and 534.\n<|im_start|>answer\nSum 9 - sides are 153, 342, and 261.\r\nSum 10 - sides are 145, 523, and 361.\r\nSum 11 - sides are 236, 614, and 452.\r\nSum 12 - sides are 426, 615, and 534.\n<|im_end|>" }, { "id": "#45795", "title": "Writing After Retiring?", "fun": 2.8, "difficulty": 2.77, "author": "whsprec", "desc": "Writing novels is hard work, and despite the fame and fortune, writers decide to retire. One publishing company decided to pay others to write using some of their author's names. There were 3 men, Toby Brooks, Tom Lewis, and Bronson White, and 2 women, Chelsea Clark and Katrina Reed, who have been retired for some time. However, \"new\" books with their names continue to appear. From the clues below match the author to their main character, the year they retired, and how many books have been published since they retired.\n\r\n1- The author writing as Bronson White has written one more novel than the writer who retired in 2000, but one fewer than has been published featuring the Elf Jerlle.\r\n2- It was a male writer who created the Wizard Broman, and another man who retired in 1994.\r\n3- Chelsea Clark, whose name doesn't appear on exactly 5 novels, retired 3 years before the creator of mobster Small Tony, who has not been featured in exactly 7 books.\r\n4- The creator of serial killer Arnold Fox retired three years after the man who has had four books written in his name.\r\n5- There has been an even number of murder mysteries written about Captain Gibbs, whose writer retired after 1997.\r\n6- The company has produced one more Toby Brooks book than books by the author who retired in 2006 who was not Katrina Reed.", "hint": "No hint available.", "answer": "Toby Brooks wrote about Jerlle and has had 7 books published in his name since retiring in 1994.\r\nChelsea Clark wrote about Captain Gibbsand has had 8 books published in her name since retiring in 2003.\r\nTom Lewis wrote about Bromanand has had 4 books published in his name since retiring in 1997.\r\nBronson White wrote about Small Tony and has had 6 books published in his name since retiring in 2006.\r\nKatrina Reed wrote about Arnold Fox and has had 5 books published in her name since retiring in 2000.", "category": "Logic-Grid", "date": "11/24/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWriting novels is hard work, and despite the fame and fortune, writers decide to retire. One publishing company decided to pay others to write using some of their author's names. There were 3 men, Toby Brooks, Tom Lewis, and Bronson White, and 2 women, Chelsea Clark and Katrina Reed, who have been retired for some time. However, \"new\" books with their names continue to appear. From the clues below match the author to their main character, the year they retired, and how many books have been published since they retired.\n\r\n1- The author writing as Bronson White has written one more novel than the writer who retired in 2000, but one fewer than has been published featuring the Elf Jerlle.\r\n2- It was a male writer who created the Wizard Broman, and another man who retired in 1994.\r\n3- Chelsea Clark, whose name doesn't appear on exactly 5 novels, retired 3 years before the creator of mobster Small Tony, who has not been featured in exactly 7 books.\r\n4- The creator of serial killer Arnold Fox retired three years after the man who has had four books written in his name.\r\n5- There has been an even number of murder mysteries written about Captain Gibbs, whose writer retired after 1997.\r\n6- The company has produced one more Toby Brooks book than books by the author who retired in 2006 who was not Katrina Reed.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nToby Brooks wrote about Jerlle and has had 7 books published in his name since retiring in 1994.\r\nChelsea Clark wrote about Captain Gibbsand has had 8 books published in her name since retiring in 2003.\r\nTom Lewis wrote about Bromanand has had 4 books published in his name since retiring in 1997.\r\nBronson White wrote about Small Tony and has had 6 books published in his name since retiring in 2006.\r\nKatrina Reed wrote about Arnold Fox and has had 5 books published in her name since retiring in 2000.\n<|im_start|>answer\nToby Brooks wrote about Jerlle and has had 7 books published in his name since retiring in 1994.\r\nChelsea Clark wrote about Captain Gibbsand has had 8 books published in her name since retiring in 2003.\r\nTom Lewis wrote about Bromanand has had 4 books published in his name since retiring in 1997.\r\nBronson White wrote about Small Tony and has had 6 books published in his name since retiring in 2006.\r\nKatrina Reed wrote about Arnold Fox and has had 5 books published in her name since retiring in 2000.\n<|im_end|>" }, { "id": "#52291", "title": "Speaking of Tennis...", "fun": 2.79, "difficulty": 1.8900000000000001, "author": "wimpykidfan37", "desc": "Heather, her father, her husband, and her daughter are playing a tennis game. One of them says truthfully:\n\r\n\"I am standing directly across the net from the server's daughter. My partner, who is on the same side of the net as me, is standing directly across the net from the receiver's father. The server and the receiver are standing diagonally across the net from each other.\"\n\r\nWho said this?", "hint": "No hint available.", "answer": "Heather's father said this.\n\r\nFrom the speaker's first two statements, we know that the court is set up like this:\n\r\nspeaker | speaker's partner\r\n_________________\r\nserver's daughter | receiver's father\n\r\nFrom the speaker's last statement, we have two scenarios:\n\r\n1. The receiver's father is the server and the speaker is the receiver.\n\r\n2. The speaker's partner is the server and the server's daughter is the receiver.\n\r\nIf scenario 1 is true, then the receiver's father is the father of both the receiver and the server's daughter. But no one is the father of more than one person, so this is impossible.\n\r\nThis means that scenario 2 is true. Since the receiver was the server's daughter, she was the daughter of both the server and the receiver's father. This means that the server is Heather herself, the receiver's father is Heather's husband, and the server's daughter is Heather's daughter. The fourth player, the speaker, could clearly only have been Heather's father now.", "category": "Logic", "date": "11/19/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHeather, her father, her husband, and her daughter are playing a tennis game. One of them says truthfully:\n\r\n\"I am standing directly across the net from the server's daughter. My partner, who is on the same side of the net as me, is standing directly across the net from the receiver's father. The server and the receiver are standing diagonally across the net from each other.\"\n\r\nWho said this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHeather's father said this.\n\r\nFrom the speaker's first two statements, we know that the court is set up like this:\n\r\nspeaker | speaker's partner\r\n_________________\r\nserver's daughter | receiver's father\n\r\nFrom the speaker's last statement, we have two scenarios:\n\r\n1. The receiver's father is the server and the speaker is the receiver.\n\r\n2. The speaker's partner is the server and the server's daughter is the receiver.\n\r\nIf scenario 1 is true, then the receiver's father is the father of both the receiver and the server's daughter. But no one is the father of more than one person, so this is impossible.\n\r\nThis means that scenario 2 is true. Since the receiver was the server's daughter, she was the daughter of both the server and the receiver's father. This means that the server is Heather herself, the receiver's father is Heather's husband, and the server's daughter is Heather's daughter. The fourth player, the speaker, could clearly only have been Heather's father now.\n<|im_start|>answer\nHeather's father said this.\n\r\nFrom the speaker's first two statements, we know that the court is set up like this:\n\r\nspeaker | speaker's partner\r\n_________________\r\nserver's daughter | receiver's father\n\r\nFrom the speaker's last statement, we have two scenarios:\n\r\n1. The receiver's father is the server and the speaker is the receiver.\n\r\n2. The speaker's partner is the server and the server's daughter is the receiver.\n\r\nIf scenario 1 is true, then the receiver's father is the father of both the receiver and the server's daughter. But no one is the father of more than one person, so this is impossible.\n\r\nThis means that scenario 2 is true. Since the receiver was the server's daughter, she was the daughter of both the server and the receiver's father. This means that the server is Heather herself, the receiver's father is Heather's husband, and the server's daughter is Heather's daughter. The fourth player, the speaker, could clearly only have been Heather's father now.\n<|im_end|>" }, { "id": "#25315", "title": "Upside Down 2", "fun": 2.79, "difficulty": 1.48, "author": "Scoberman", "desc": "Can you move three x's to make the triangle flip upside down?\n\r\nX\r\nX X\r\nX X X\r\nX X X X", "hint": "No hint available.", "answer": "First, move the last two X's in the bottom row to the end of the second row:\n\r\nX\r\nX X X X\r\nX X X\r\nX X \n\r\nThen, move the top X to a new row on the bottom:\n\r\nX X X X\r\nX X X\r\nX X\r\nX", "category": "Logic", "date": "08/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you move three x's to make the triangle flip upside down?\n\r\nX\r\nX X\r\nX X X\r\nX X X X\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, move the last two X's in the bottom row to the end of the second row:\n\r\nX\r\nX X X X\r\nX X X\r\nX X \n\r\nThen, move the top X to a new row on the bottom:\n\r\nX X X X\r\nX X X\r\nX X\r\nX\n<|im_start|>answer\nFirst, move the last two X's in the bottom row to the end of the second row:\n\r\nX\r\nX X X X\r\nX X X\r\nX X \n\r\nThen, move the top X to a new row on the bottom:\n\r\nX X X X\r\nX X X\r\nX X\r\nX\n<|im_end|>" }, { "id": "#23276", "title": "Whose Birthday Party?", "fun": 2.79, "difficulty": 1.52, "author": "katey", "desc": "At a recent birthday party, there were four mothers and their children, aged 1, 2, 3 and 4. From the clues below can you work out whose child is whose and their relevant ages?\n\r\nIt was Jane's child's birthday party. \r\nBrian is not the oldest child. \r\nSarah had Anne just over a year ago.\r\nLaura's child will be 3 next birthday. \r\nDaniel is older than Charlie. \r\nTeresa's child is the oldest. \r\nCharlie is older than Laura's child.", "hint": "No hint available.", "answer": "Mother Child Age\r\nJane Charlie 3\r\nTeresa Daniel 4\r\nLaura Brian 2\r\nSarah Anne 1", "category": "Logic", "date": "05/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a recent birthday party, there were four mothers and their children, aged 1, 2, 3 and 4. From the clues below can you work out whose child is whose and their relevant ages?\n\r\nIt was Jane's child's birthday party. \r\nBrian is not the oldest child. \r\nSarah had Anne just over a year ago.\r\nLaura's child will be 3 next birthday. \r\nDaniel is older than Charlie. \r\nTeresa's child is the oldest. \r\nCharlie is older than Laura's child.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMother Child Age\r\nJane Charlie 3\r\nTeresa Daniel 4\r\nLaura Brian 2\r\nSarah Anne 1\n<|im_start|>answer\nMother Child Age\r\nJane Charlie 3\r\nTeresa Daniel 4\r\nLaura Brian 2\r\nSarah Anne 1\n<|im_end|>" }, { "id": "#29065", "title": "Clown of the Year", "fun": 2.79, "difficulty": 1.96, "author": "Victor", "desc": "Four clowns, Boo Boo, Grego, Strumpy and Tambo, all competed for the much-prized \"Clown of the Year\" award recently. There were 30 clowns in total who entered the competition and each had to make the judges laugh.\n\r\nFrom the clues below, can you work out each clown's name, the town he or she came from, what place each clown was awarded and the most comical moment of each clown's routine? \n\r\n1. The Budsworth clown finished one place lower than Strumpy who is not from Witfield.\n\r\n2. The judges roared with laughter as one clown cycled across a tightrope, wobbled, screamed and fell head first into a pool of water. He finished two places below Boo Boo who was not from Witfield.\n\r\n3. The clown who finished in 7th place lost points when her big red nose fell off during her manic routine. This involved being hit with a giant rubber mallet by her assistant who was supposed to hit her on the shoulder but unfortunately had something in his eye at the time and accidentally bashed her in the face instead.\n\r\n4. Tambo was disappointed when his usually masterful custard pie antics failed to impress the judges sufficiently to secure the award. He was not the clown from Stockville whose final placing was lower than the Shrimpton clown.", "hint": "No hint available.", "answer": "Boo Boo, Shrimpton, 2nd, Flower;\r\nStrumpy, Stockville, 4th, Unicycle;\r\nTambo, Budsworth, 5th, Custard Pie;\r\nGrego, Whitfield, 7th, Rubber Mallet.\n\r\nThe positions that the four clowns could finish are 2nd, 4th, 5th and 7th. The Budsworth clown finished one place below Strumpy (1) so Strumpy must have been 4th and the Budsworth clown 5th. The (male) clown on the unicycle finished two places below Boo Boo (2) so must have been 7th or 4th. Since the clown who came 7th was female, the clown on the unicycle must have been 4th and is Strumpy and Boo Boo came 2nd. Tambo (male) is not the clown who came 7th (3), 2nd (Boo Boo) or 4th (Strumpy) so came 5th with his custard pie act (4) and Grego came 7th with her rubber mallet so by elimination, Boo Boo's act involved the flower. The Budsworth clown (Tambo) came 5th, neither Strumpy (1) nor Boo Boo (2) came from Whitfield so the clown from Whitfield was Grego (7th). The Shrimpton clown was placed higher than the Stockville clown (4) so came 2nd and the Stockville clown came 4th.", "category": "Logic-Grid", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour clowns, Boo Boo, Grego, Strumpy and Tambo, all competed for the much-prized \"Clown of the Year\" award recently. There were 30 clowns in total who entered the competition and each had to make the judges laugh.\n\r\nFrom the clues below, can you work out each clown's name, the town he or she came from, what place each clown was awarded and the most comical moment of each clown's routine? \n\r\n1. The Budsworth clown finished one place lower than Strumpy who is not from Witfield.\n\r\n2. The judges roared with laughter as one clown cycled across a tightrope, wobbled, screamed and fell head first into a pool of water. He finished two places below Boo Boo who was not from Witfield.\n\r\n3. The clown who finished in 7th place lost points when her big red nose fell off during her manic routine. This involved being hit with a giant rubber mallet by her assistant who was supposed to hit her on the shoulder but unfortunately had something in his eye at the time and accidentally bashed her in the face instead.\n\r\n4. Tambo was disappointed when his usually masterful custard pie antics failed to impress the judges sufficiently to secure the award. He was not the clown from Stockville whose final placing was lower than the Shrimpton clown.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoo Boo, Shrimpton, 2nd, Flower;\r\nStrumpy, Stockville, 4th, Unicycle;\r\nTambo, Budsworth, 5th, Custard Pie;\r\nGrego, Whitfield, 7th, Rubber Mallet.\n\r\nThe positions that the four clowns could finish are 2nd, 4th, 5th and 7th. The Budsworth clown finished one place below Strumpy (1) so Strumpy must have been 4th and the Budsworth clown 5th. The (male) clown on the unicycle finished two places below Boo Boo (2) so must have been 7th or 4th. Since the clown who came 7th was female, the clown on the unicycle must have been 4th and is Strumpy and Boo Boo came 2nd. Tambo (male) is not the clown who came 7th (3), 2nd (Boo Boo) or 4th (Strumpy) so came 5th with his custard pie act (4) and Grego came 7th with her rubber mallet so by elimination, Boo Boo's act involved the flower. The Budsworth clown (Tambo) came 5th, neither Strumpy (1) nor Boo Boo (2) came from Whitfield so the clown from Whitfield was Grego (7th). The Shrimpton clown was placed higher than the Stockville clown (4) so came 2nd and the Stockville clown came 4th.\n<|im_start|>answer\nBoo Boo, Shrimpton, 2nd, Flower;\r\nStrumpy, Stockville, 4th, Unicycle;\r\nTambo, Budsworth, 5th, Custard Pie;\r\nGrego, Whitfield, 7th, Rubber Mallet.\n\r\nThe positions that the four clowns could finish are 2nd, 4th, 5th and 7th. The Budsworth clown finished one place below Strumpy (1) so Strumpy must have been 4th and the Budsworth clown 5th. The (male) clown on the unicycle finished two places below Boo Boo (2) so must have been 7th or 4th. Since the clown who came 7th was female, the clown on the unicycle must have been 4th and is Strumpy and Boo Boo came 2nd. Tambo (male) is not the clown who came 7th (3), 2nd (Boo Boo) or 4th (Strumpy) so came 5th with his custard pie act (4) and Grego came 7th with her rubber mallet so by elimination, Boo Boo's act involved the flower. The Budsworth clown (Tambo) came 5th, neither Strumpy (1) nor Boo Boo (2) came from Whitfield so the clown from Whitfield was Grego (7th). The Shrimpton clown was placed higher than the Stockville clown (4) so came 2nd and the Stockville clown came 4th.\n<|im_end|>" }, { "id": "#5196", "title": "Merchant's Gold", "fun": 2.79, "difficulty": 2.42, "author": "Cascas", "desc": "A rich merchant had collected many gold coins. He did not want anybody to know about them. One day, his wife asked, \"How many gold coins do we have?\" \n\r\nAfter pausing a moment, he replied, \"Well! If I divide the coins into two unequal numbers, then 32 times the difference between the two numbers equals the difference between the squares of the two numbers.\" \n\r\nThe wife looked puzzled. Can you help the merchant's wife by finding out how many gold coins they have?", "hint": "No hint available.", "answer": "The merchant has 32 gold coins. \r\nIt is easy to check this... Let's divide the 32 coins into two unequal numbers, say, 27 and 5. Then, \n\r\n32 (27 - 5) = (27 x 27) - (5 x 5).", "category": "Math", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA rich merchant had collected many gold coins. He did not want anybody to know about them. One day, his wife asked, \"How many gold coins do we have?\" \n\r\nAfter pausing a moment, he replied, \"Well! If I divide the coins into two unequal numbers, then 32 times the difference between the two numbers equals the difference between the squares of the two numbers.\" \n\r\nThe wife looked puzzled. Can you help the merchant's wife by finding out how many gold coins they have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe merchant has 32 gold coins. \r\nIt is easy to check this... Let's divide the 32 coins into two unequal numbers, say, 27 and 5. Then, \n\r\n32 (27 - 5) = (27 x 27) - (5 x 5).\n<|im_start|>answer\nThe merchant has 32 gold coins. \r\nIt is easy to check this... Let's divide the 32 coins into two unequal numbers, say, 27 and 5. Then, \n\r\n32 (27 - 5) = (27 x 27) - (5 x 5).\n<|im_end|>" }, { "id": "#23287", "title": "Inspector Beethoven Part II", "fun": 2.79, "difficulty": 1.41, "author": "beethovenswig", "desc": "Schubert has escaped prison and has hidden himself inside 1 of 4 rooms. He has disguised himself as either a clown, a gymnast, a juggler, or a trapeze artist. Inspector Beethoven needs you to find out which person is in which room and the person that Schubert is disguising himself as.\n\r\nSchubert is to the left of the fourth room.\r\nThe gymnast is to the right of the second room.\r\nThe juggler is in the third room.\r\nSchubert hated heights.\r\nThe trapeze artist is to the right of the first room.\r\nSchubert was never really funny.", "hint": "No hint available.", "answer": "Schubert is the juggler.\r\nThe clown is in the first room.\r\nThe trapeze artist is in the second room.\r\nSchubert is disguised as the juggler in the third room.\r\nThe gymnast is in the fourth room.", "category": "Logic", "date": "05/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSchubert has escaped prison and has hidden himself inside 1 of 4 rooms. He has disguised himself as either a clown, a gymnast, a juggler, or a trapeze artist. Inspector Beethoven needs you to find out which person is in which room and the person that Schubert is disguising himself as.\n\r\nSchubert is to the left of the fourth room.\r\nThe gymnast is to the right of the second room.\r\nThe juggler is in the third room.\r\nSchubert hated heights.\r\nThe trapeze artist is to the right of the first room.\r\nSchubert was never really funny.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSchubert is the juggler.\r\nThe clown is in the first room.\r\nThe trapeze artist is in the second room.\r\nSchubert is disguised as the juggler in the third room.\r\nThe gymnast is in the fourth room.\n<|im_start|>answer\nSchubert is the juggler.\r\nThe clown is in the first room.\r\nThe trapeze artist is in the second room.\r\nSchubert is disguised as the juggler in the third room.\r\nThe gymnast is in the fourth room.\n<|im_end|>" }, { "id": "#47955", "title": "Baby Showers", "fun": 2.79, "difficulty": 1.17, "author": "NinjaPuzzler", "desc": "Abby Smith has five baby showers to go to this week. Unfortunately, with all the baby showers, she's forgotten which day each is on, as well as the names of the babies, the presents she's giving each and the color of ribbon she's using to wrap the gifts. Can you help her figure it out?\n\r\nDays: Monday, Tuesday, Thursday, Friday, and Saturday\n\r\nNames: Lily, Alan, Katie, Greg, and Stella\n\r\nPresents: Toys, Diaper Bag, Bottles, Clothes, and Pacifiers\n\r\nRibbon Colors: Blue, Pink, Orange, Red, and Green\n\n\r\nClues:\r\n1. The boys' baby showers are on Monday and Friday.\n\r\n2. Katie's present is the clothes, but her ribbon is not orange, red, or pink.\n\r\n3. The toys are to be given on Thursday wrapped with a blue ribbon.\n\r\n4. The babies are Katie, the one who will get bottles, the one whose shower is on Tuesday, the one whose present is wrapped with a blue ribbon, and Greg.\n\r\n5. Stella's shower is before Katie's but after Lily's.\n\r\n6. Greg is going to get the diaper bag before Alan gets the present wrapped with an orange ribbon.\n\r\n7. The pacifiers will be given, wrapped with a red ribbon, before Thursday.\n\r\n8. A girl will not get a gift wrapped with a pink ribbon or the bottles.", "hint": "The boys names are Greg and Alan.\n\r\nThe girls names are Lily, Katie, and Stella.", "answer": "Monday, Greg, Diaper Bag, Pink\n\r\nTuesday, Lily, Pacifiers, Red\n\r\nThursday, Stella, Toys, Blue\n\r\nFriday, Alan, Bottles, Orange\n\r\nSaturday, Katie, Clothes, Green", "category": "Logic-Grid", "date": "09/15/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbby Smith has five baby showers to go to this week. Unfortunately, with all the baby showers, she's forgotten which day each is on, as well as the names of the babies, the presents she's giving each and the color of ribbon she's using to wrap the gifts. Can you help her figure it out?\n\r\nDays: Monday, Tuesday, Thursday, Friday, and Saturday\n\r\nNames: Lily, Alan, Katie, Greg, and Stella\n\r\nPresents: Toys, Diaper Bag, Bottles, Clothes, and Pacifiers\n\r\nRibbon Colors: Blue, Pink, Orange, Red, and Green\n\n\r\nClues:\r\n1. The boys' baby showers are on Monday and Friday.\n\r\n2. Katie's present is the clothes, but her ribbon is not orange, red, or pink.\n\r\n3. The toys are to be given on Thursday wrapped with a blue ribbon.\n\r\n4. The babies are Katie, the one who will get bottles, the one whose shower is on Tuesday, the one whose present is wrapped with a blue ribbon, and Greg.\n\r\n5. Stella's shower is before Katie's but after Lily's.\n\r\n6. Greg is going to get the diaper bag before Alan gets the present wrapped with an orange ribbon.\n\r\n7. The pacifiers will be given, wrapped with a red ribbon, before Thursday.\n\r\n8. A girl will not get a gift wrapped with a pink ribbon or the bottles.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday, Greg, Diaper Bag, Pink\n\r\nTuesday, Lily, Pacifiers, Red\n\r\nThursday, Stella, Toys, Blue\n\r\nFriday, Alan, Bottles, Orange\n\r\nSaturday, Katie, Clothes, Green\n<|im_start|>answer\nMonday, Greg, Diaper Bag, Pink\n\r\nTuesday, Lily, Pacifiers, Red\n\r\nThursday, Stella, Toys, Blue\n\r\nFriday, Alan, Bottles, Orange\n\r\nSaturday, Katie, Clothes, Green\n<|im_end|>" }, { "id": "#49499", "title": "Pizza in the Time of Cholera", "fun": 2.79, "difficulty": 1.11, "author": "JimShorts", "desc": "I brought my lunch to work with me today: two square slices of pizza sealed in one small square Tupperware container. The slices just barely fit in the container, stacked one on top of the other. I want to microwave them both at the same time (because I'm lazy), but if the cheese side of either slice is touching the other slice of pizza, or the inner surface of the container, then the cheese will get stuck to whatever it's touching when it melts. And the crust is pretty soft, so the pizza slices will flop over and be ruined if I don't lay them flat.\n\r\nThe problem is, everyone else at work is horribly sick, so I don't trust ANYthing to be clean enough to touch my food except the inside of my container, since it has been sealed all day. No plates, no paper towels, not the inside of the microwave, NOTHING! So how can I safely microwave both slices of pizza at the same time without letting the cheese touch anything, and without letting any part of the pizza touch any surface that might be contaminated?", "hint": "No hint available.", "answer": "Leave one slice in the container and take the second slice out. Turn the lid of the container upside down and lay the second slice on top of the nice, clean inner surface of the lid.", "category": "Logic", "date": "06/04/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI brought my lunch to work with me today: two square slices of pizza sealed in one small square Tupperware container. The slices just barely fit in the container, stacked one on top of the other. I want to microwave them both at the same time (because I'm lazy), but if the cheese side of either slice is touching the other slice of pizza, or the inner surface of the container, then the cheese will get stuck to whatever it's touching when it melts. And the crust is pretty soft, so the pizza slices will flop over and be ruined if I don't lay them flat.\n\r\nThe problem is, everyone else at work is horribly sick, so I don't trust ANYthing to be clean enough to touch my food except the inside of my container, since it has been sealed all day. No plates, no paper towels, not the inside of the microwave, NOTHING! So how can I safely microwave both slices of pizza at the same time without letting the cheese touch anything, and without letting any part of the pizza touch any surface that might be contaminated?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeave one slice in the container and take the second slice out. Turn the lid of the container upside down and lay the second slice on top of the nice, clean inner surface of the lid.\n<|im_start|>answer\nLeave one slice in the container and take the second slice out. Turn the lid of the container upside down and lay the second slice on top of the nice, clean inner surface of the lid.\n<|im_end|>" }, { "id": "#30474", "title": "Birbal the Wise - V", "fun": 2.79, "difficulty": 2.03, "author": "brainster", "desc": "Emperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\n\r\nOnce, Birbal took his 10-year old daughter with him to meet the Emperor Akbar.\n\r\nEmperor Akbar greeted her cordially and arranged for sweets and toys to be presented to her. \n\r\nWhile conversing with her, he asked her whether she knew Persian. She replied, \"A little less and a little more, Sire\".\n\r\nEmperor Akbar, puzzled by this reply asked Birbal to explain what his daughter meant.\n\r\nWhat did Birbal say?", "hint": "No hint available.", "answer": "Birbal said, \"Sire, she means that she knows Persian a little less than people who know Persian well, but a little more than people who do not know Persian at all!\"\n\r\nThe Emperor was pleased with Birbal's daughter's wit and rewarded her with some more gifts. After all, she was a chip off the old block!", "category": "Logic", "date": "05/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEmperor Akbar once ruled over India. He was a wise and intelligent ruler, and he had in his court the Nine Gems, his nine advisors, who were each known for a particular skill. One of these Gems was Birbal, known for his wit and wisdom. The story below is one of the examples of his wit. Do you have it in you to find out the answer?\n\n\r\nOnce, Birbal took his 10-year old daughter with him to meet the Emperor Akbar.\n\r\nEmperor Akbar greeted her cordially and arranged for sweets and toys to be presented to her. \n\r\nWhile conversing with her, he asked her whether she knew Persian. She replied, \"A little less and a little more, Sire\".\n\r\nEmperor Akbar, puzzled by this reply asked Birbal to explain what his daughter meant.\n\r\nWhat did Birbal say?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBirbal said, \"Sire, she means that she knows Persian a little less than people who know Persian well, but a little more than people who do not know Persian at all!\"\n\r\nThe Emperor was pleased with Birbal's daughter's wit and rewarded her with some more gifts. After all, she was a chip off the old block!\n<|im_start|>answer\nBirbal said, \"Sire, she means that she knows Persian a little less than people who know Persian well, but a little more than people who do not know Persian at all!\"\n\r\nThe Emperor was pleased with Birbal's daughter's wit and rewarded her with some more gifts. After all, she was a chip off the old block!\n<|im_end|>" }, { "id": "#50748", "title": "Free Pizza Day", "fun": 2.79, "difficulty": 0.9500000000000001, "author": "LanceAlot", "desc": "The owner of Senior Pete's Pizza decided to celebrate his birthday by giving away free pizza to anyone who can solve his puzzle:\n\r\nIf a pizza's radius is defined as \"z\" and it's depth defined \"a\", then what is that pizza's volume? \n\r\nCan you answer Pete's puzzle correctly?", "hint": "No hint available.", "answer": "Volume = (Π)(radius)^2(depth)\r\nV=pi(r)(r)(d)\r\nSo...\r\nPizza Volume = (pi)(z^2)(a) = pizza", "category": "Math", "date": "12/18/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe owner of Senior Pete's Pizza decided to celebrate his birthday by giving away free pizza to anyone who can solve his puzzle:\n\r\nIf a pizza's radius is defined as \"z\" and it's depth defined \"a\", then what is that pizza's volume? \n\r\nCan you answer Pete's puzzle correctly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nVolume = (Π)(radius)^2(depth)\r\nV=pi(r)(r)(d)\r\nSo...\r\nPizza Volume = (pi)(z^2)(a) = pizza\n<|im_start|>answer\nVolume = (Π)(radius)^2(depth)\r\nV=pi(r)(r)(d)\r\nSo...\r\nPizza Volume = (pi)(z^2)(a) = pizza\n<|im_end|>" }, { "id": "#20531", "title": "Family Dinner", "fun": 2.79, "difficulty": 1.12, "author": "kellgo", "desc": "The Logic Family (Dad, Mom, their children Charlie and Susan, and Uncle Robert) went out for dinner to their favorite restaurant. Each person ordered something different (cheese sandwich, chicken tenders, hamburger, steak, and a fruit salad). Figure out who ordered what and in what order from the information provided below.\n\r\nThe 4th person ordered steak.\n\r\nUncle Robert didn't order his meaty dinner first.\n\r\n\"Girls/ladies first,\" said the waiter.\n\r\nBoth men ordered meat.\n\r\nDad ordered before Uncle Robert but not before Mom.\n\r\nThe fruit salad was ordered second.\n\r\nSusan is lactose intolerant.\n\r\nCharlie took the longest to figure out what he wanted to order.\n\r\nThe steak was ordered before the grilled cheese but after the hamburger.\n\r\nThe fruit salad was ordered after the chicken tenders but before the hamburger.\n\r\nDad heard one of his children order the chicken tenders and placed his order for the hamburger before someone ordered the cheese sandwich.", "hint": "No hint available.", "answer": "Dad.... Hamburger.... 3rd\r\nUncle Robert.... Steak.... 4th\r\nMom..... Fruit Salad.... 2nd\r\nCharlie.... Cheese Sandwich.... 5th\r\nSusan.... Chicken Tenders..... 1st", "category": "Logic-Grid", "date": "01/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Logic Family (Dad, Mom, their children Charlie and Susan, and Uncle Robert) went out for dinner to their favorite restaurant. Each person ordered something different (cheese sandwich, chicken tenders, hamburger, steak, and a fruit salad). Figure out who ordered what and in what order from the information provided below.\n\r\nThe 4th person ordered steak.\n\r\nUncle Robert didn't order his meaty dinner first.\n\r\n\"Girls/ladies first,\" said the waiter.\n\r\nBoth men ordered meat.\n\r\nDad ordered before Uncle Robert but not before Mom.\n\r\nThe fruit salad was ordered second.\n\r\nSusan is lactose intolerant.\n\r\nCharlie took the longest to figure out what he wanted to order.\n\r\nThe steak was ordered before the grilled cheese but after the hamburger.\n\r\nThe fruit salad was ordered after the chicken tenders but before the hamburger.\n\r\nDad heard one of his children order the chicken tenders and placed his order for the hamburger before someone ordered the cheese sandwich.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDad.... Hamburger.... 3rd\r\nUncle Robert.... Steak.... 4th\r\nMom..... Fruit Salad.... 2nd\r\nCharlie.... Cheese Sandwich.... 5th\r\nSusan.... Chicken Tenders..... 1st\n<|im_start|>answer\nDad.... Hamburger.... 3rd\r\nUncle Robert.... Steak.... 4th\r\nMom..... Fruit Salad.... 2nd\r\nCharlie.... Cheese Sandwich.... 5th\r\nSusan.... Chicken Tenders..... 1st\n<|im_end|>" }, { "id": "#3361", "title": "The Tea Party", "fun": 2.79, "difficulty": 1.7, "author": "arij", "desc": "All the letters of the English Language (eg. A, B, C, etc) have to go to a tea party. Which letters would come late and why?", "hint": "No hint available.", "answer": "U, V, W, X, Y, Z\r\nBecause they all come after tea (T)", "category": "Logic", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAll the letters of the English Language (eg. A, B, C, etc) have to go to a tea party. Which letters would come late and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nU, V, W, X, Y, Z\r\nBecause they all come after tea (T)\n<|im_start|>answer\nU, V, W, X, Y, Z\r\nBecause they all come after tea (T)\n<|im_end|>" }, { "id": "#26693", "title": "44 Potatoes", "fun": 2.79, "difficulty": 1.18, "author": "hamburger", "desc": "Gary began peeling a pile of 44 potatoes at the rate of 3 per minute. Four minutes later, Christen joined him, and peeled at the rate of 5 potatoes per minute. When they were finished, how many potatoes had each peeled?", "hint": "No hint available.", "answer": "Gary:24\r\nChristen:20", "category": "Math", "date": "11/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGary began peeling a pile of 44 potatoes at the rate of 3 per minute. Four minutes later, Christen joined him, and peeled at the rate of 5 potatoes per minute. When they were finished, how many potatoes had each peeled?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGary:24\r\nChristen:20\n<|im_start|>answer\nGary:24\r\nChristen:20\n<|im_end|>" }, { "id": "#6665", "title": "Born Liars", "fun": 2.79, "difficulty": 2.73, "author": "naveen_the_great", "desc": "Edward, Howard, and John are three high school students each of whom is taking three of the four subjects, biology, chemistry, history, and mathematics. One day while talking about their programs they made the following statements.\n\r\nEdward: There is just one subject we're all taking. I'm the only one of us who is taking mathematics. No two of us are taking the same three subjects. John is wrong when he says that Howard and I are both taking chemistry.\n\r\nHoward: Ed is the only one of us who is taking history. John and I are taking the same subjects. We're all taking biology. Two of us are taking both chemistry and biology.\n\r\nJohn: We're all taking mathematics. Howard is taking history. Ed is taking one subject that I'm not. Both Howard and Ed are taking chemistry.\n\r\nIf two and only two of each boy's statements are true, what subjects is each boy taking?", "hint": "No hint available.", "answer": "Edward: chemistry, biology, history\r\nHoward: chemistry, biology, mathematics\r\nJohn: biology, mathematics, history", "category": "Logic", "date": "08/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEdward, Howard, and John are three high school students each of whom is taking three of the four subjects, biology, chemistry, history, and mathematics. One day while talking about their programs they made the following statements.\n\r\nEdward: There is just one subject we're all taking. I'm the only one of us who is taking mathematics. No two of us are taking the same three subjects. John is wrong when he says that Howard and I are both taking chemistry.\n\r\nHoward: Ed is the only one of us who is taking history. John and I are taking the same subjects. We're all taking biology. Two of us are taking both chemistry and biology.\n\r\nJohn: We're all taking mathematics. Howard is taking history. Ed is taking one subject that I'm not. Both Howard and Ed are taking chemistry.\n\r\nIf two and only two of each boy's statements are true, what subjects is each boy taking?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEdward: chemistry, biology, history\r\nHoward: chemistry, biology, mathematics\r\nJohn: biology, mathematics, history\n<|im_start|>answer\nEdward: chemistry, biology, history\r\nHoward: chemistry, biology, mathematics\r\nJohn: biology, mathematics, history\n<|im_end|>" }, { "id": "#47029", "title": "Who Needs the Right Formula, Anyway?", "fun": 2.79, "difficulty": 1.8900000000000001, "author": "dalfamnest", "desc": "This morning I asked my math class to find the areas of two right-angled triangles. Lottie-Lu's hand shot up immediately, so I asked her the first one.\n\r\n\"24\" she announced.\n\r\nShe was right (for a change!) and I made the mistake of asking her how she did it.\n\r\n\"Easy. Just add all the sides together.\"\n\r\nI was about to correct her and say it was just a coincidence, when I noticed that her method worked on my second triangle as well!\n\r\nLottie-Lu must have caught my frustrated thoughts. \"Well, it works, doesn't it?\" she chirped.\n\r\nWhat were the side lengths of the two triangles I had drawn on the board this morning? They were all whole numbers.", "hint": "Use the fact that all three sides of each triangle were whole numbers.", "answer": "1. 6-8-10 (Area = 6x8/2 = 24)\r\n2. 5-12-13 (Area = 5x12/2 = 30)", "category": "Math", "date": "05/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis morning I asked my math class to find the areas of two right-angled triangles. Lottie-Lu's hand shot up immediately, so I asked her the first one.\n\r\n\"24\" she announced.\n\r\nShe was right (for a change!) and I made the mistake of asking her how she did it.\n\r\n\"Easy. Just add all the sides together.\"\n\r\nI was about to correct her and say it was just a coincidence, when I noticed that her method worked on my second triangle as well!\n\r\nLottie-Lu must have caught my frustrated thoughts. \"Well, it works, doesn't it?\" she chirped.\n\r\nWhat were the side lengths of the two triangles I had drawn on the board this morning? They were all whole numbers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. 6-8-10 (Area = 6x8/2 = 24)\r\n2. 5-12-13 (Area = 5x12/2 = 30)\n<|im_start|>answer\n1. 6-8-10 (Area = 6x8/2 = 24)\r\n2. 5-12-13 (Area = 5x12/2 = 30)\n<|im_end|>" }, { "id": "#477", "title": "Suzie Was Nine...", "fun": 2.79, "difficulty": 1.79, "author": "kaila912", "desc": "The day before yesterday Suzie was nine years old. Next year she will be twelve. How is this possible?", "hint": "This is not a trick question...there is an answer!", "answer": "Her birthday is on December 31. If today is January 1, then the day before yesterday, she was nine, yesterday she turned ten, this year she'll turn eleven and NEXT year she'll turn twelve! If you still don't get it, look at a calendar!", "category": "Logic", "date": "05/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe day before yesterday Suzie was nine years old. Next year she will be twelve. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHer birthday is on December 31. If today is January 1, then the day before yesterday, she was nine, yesterday she turned ten, this year she'll turn eleven and NEXT year she'll turn twelve! If you still don't get it, look at a calendar!\n<|im_start|>answer\nHer birthday is on December 31. If today is January 1, then the day before yesterday, she was nine, yesterday she turned ten, this year she'll turn eleven and NEXT year she'll turn twelve! If you still don't get it, look at a calendar!\n<|im_end|>" }, { "id": "#399", "title": "The Slowest Race", "fun": 2.79, "difficulty": 1.8, "author": "22ACE", "desc": "One day a really rich old man with two sons died. In his will he said that he would give one of his sons all of his fortune. He gave each of his sons a horse and said they would compete in a horse race from Los Angeles to Sacramento, but the son whose horse came in second would get the money. So one day they started the race. After one whole day they had only ridden one mile. At night they decided they should stop at a hotel. \r\nWhile they were booking in they told their problem to the wise old clerk, who made a suggestion. The next day the two brothers rode as fast as they could. What did the clerk suggest that they do?", "hint": "No hint available.", "answer": "The clerk told them to swap horses. The father said that whoever's horse crossed the finish line second would get the money. He didn't say that the owner of the horse had to be on it.", "category": "Logic", "date": "04/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day a really rich old man with two sons died. In his will he said that he would give one of his sons all of his fortune. He gave each of his sons a horse and said they would compete in a horse race from Los Angeles to Sacramento, but the son whose horse came in second would get the money. So one day they started the race. After one whole day they had only ridden one mile. At night they decided they should stop at a hotel. \r\nWhile they were booking in they told their problem to the wise old clerk, who made a suggestion. The next day the two brothers rode as fast as they could. What did the clerk suggest that they do?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe clerk told them to swap horses. The father said that whoever's horse crossed the finish line second would get the money. He didn't say that the owner of the horse had to be on it.\n<|im_start|>answer\nThe clerk told them to swap horses. The father said that whoever's horse crossed the finish line second would get the money. He didn't say that the owner of the horse had to be on it.\n<|im_end|>" }, { "id": "#29977", "title": "The Bryants", "fun": 2.79, "difficulty": 2.28, "author": "peppamintp", "desc": "Last week was a busy one for the Bryant family, with many late afternoon activities. On several days, to make waiting for dinner easier, Ms. Bryant served hors d'oeuvres (one day she served cheese and crackers) while the main course was cooking. On each day, she served a different hors d'oeuvre and a different dinner. From the information provided, determine the activity on each day (Sunday, Tuesday, Wednesday, Friday, and Saturday), as well as the hors d'oeuvre and main course (one was soup and sandwiches) served on that day.\n\r\n1. The Bryants snacked on cocktail franks exactly three days after they enjoyed raw vegetables with dip.\n\r\n2. The Bryants attended choir practice the day after they munched on the appetizer of stuffed celery.\n\r\n3. Nachos were the appetizer exactly two days after the main course was macaroni and cheese.\n\r\n4. The Bryants went bowling at some point after the cocktail franks were served as an appetizer but at least one day before the flounder was served for dinner.\n\r\n5. The Bryants went shopping twice, and one of their shopping trips was on either Friday or Saturday. They ate baked chicken for dinner at some point earlier in the week than both shopping trips.\n\r\n6. The Bryants attended their daughter's ballet recital exactly two days before they ate steak for dinner.", "hint": "No hint available.", "answer": "Sunday, ballet, vegetables, chicken \r\nTuesday, shopping, celery, steak\r\nWednesday, choir, cocktail franks, macaroni & cheese\r\nFriday, bowling, nachos, soup & sandwiches\r\nSaturday, shopping, cheese & crackers, flounder", "category": "Logic-Grid", "date": "04/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast week was a busy one for the Bryant family, with many late afternoon activities. On several days, to make waiting for dinner easier, Ms. Bryant served hors d'oeuvres (one day she served cheese and crackers) while the main course was cooking. On each day, she served a different hors d'oeuvre and a different dinner. From the information provided, determine the activity on each day (Sunday, Tuesday, Wednesday, Friday, and Saturday), as well as the hors d'oeuvre and main course (one was soup and sandwiches) served on that day.\n\r\n1. The Bryants snacked on cocktail franks exactly three days after they enjoyed raw vegetables with dip.\n\r\n2. The Bryants attended choir practice the day after they munched on the appetizer of stuffed celery.\n\r\n3. Nachos were the appetizer exactly two days after the main course was macaroni and cheese.\n\r\n4. The Bryants went bowling at some point after the cocktail franks were served as an appetizer but at least one day before the flounder was served for dinner.\n\r\n5. The Bryants went shopping twice, and one of their shopping trips was on either Friday or Saturday. They ate baked chicken for dinner at some point earlier in the week than both shopping trips.\n\r\n6. The Bryants attended their daughter's ballet recital exactly two days before they ate steak for dinner.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSunday, ballet, vegetables, chicken \r\nTuesday, shopping, celery, steak\r\nWednesday, choir, cocktail franks, macaroni & cheese\r\nFriday, bowling, nachos, soup & sandwiches\r\nSaturday, shopping, cheese & crackers, flounder\n<|im_start|>answer\nSunday, ballet, vegetables, chicken \r\nTuesday, shopping, celery, steak\r\nWednesday, choir, cocktail franks, macaroni & cheese\r\nFriday, bowling, nachos, soup & sandwiches\r\nSaturday, shopping, cheese & crackers, flounder\n<|im_end|>" }, { "id": "#30735", "title": "Billiards Tournament 2", "fun": 2.79, "difficulty": 2.59, "author": "cdrock", "desc": "8 friends decided to play in a pool tournament. They played a single elimination tournament, with three rounds (the first round, second round, and finals). Using the clues below can you determine who beat whom in each round?\n\r\nBoys: Jack, Jamie, Jim, Roger, Tommy\n\r\nGirls: Jessica, Renee, Tina\n\r\nClues:\n\r\n1. No one ever played against someone else with the same first name initial.\n\r\n2. The four people who advanced to the second round were Renee, the person who beat Tina in the first round, the loser of the final match, and the man who played Jessica in the first round.\n\r\n3. 3 games of the first round, and 1 game of the second round were played by two people of the opposite sex.\n\r\n4. Jack only played against a man one time in the tournament, and Roger played against a man in every round he played in.\n\r\n5. Renee played against Jack at some point in the tournament.\n\r\n6. The two people who played in the final round were the winner, and the man who beat Tommy in the 2nd round.\n\r\n7. Jim always played against a man in the tournament.\n\r\n8. Jessica did not play against the eventual champion.", "hint": "No hint available.", "answer": "First Round:\n\r\nJack vs. Tina, Jack won\r\nJamie vs. Renee, Renee won\r\nJessica vs. Tommy, Tommy won\r\nJim vs. Roger, Roger won\n\r\nSecond Round:\n\r\nJack vs. Renee, Jack won\r\nTommy vs. Roger, Roger won\n\r\nFinals:\n\r\nJack vs. Roger, Jack won", "category": "Logic", "date": "05/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n8 friends decided to play in a pool tournament. They played a single elimination tournament, with three rounds (the first round, second round, and finals). Using the clues below can you determine who beat whom in each round?\n\r\nBoys: Jack, Jamie, Jim, Roger, Tommy\n\r\nGirls: Jessica, Renee, Tina\n\r\nClues:\n\r\n1. No one ever played against someone else with the same first name initial.\n\r\n2. The four people who advanced to the second round were Renee, the person who beat Tina in the first round, the loser of the final match, and the man who played Jessica in the first round.\n\r\n3. 3 games of the first round, and 1 game of the second round were played by two people of the opposite sex.\n\r\n4. Jack only played against a man one time in the tournament, and Roger played against a man in every round he played in.\n\r\n5. Renee played against Jack at some point in the tournament.\n\r\n6. The two people who played in the final round were the winner, and the man who beat Tommy in the 2nd round.\n\r\n7. Jim always played against a man in the tournament.\n\r\n8. Jessica did not play against the eventual champion.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst Round:\n\r\nJack vs. Tina, Jack won\r\nJamie vs. Renee, Renee won\r\nJessica vs. Tommy, Tommy won\r\nJim vs. Roger, Roger won\n\r\nSecond Round:\n\r\nJack vs. Renee, Jack won\r\nTommy vs. Roger, Roger won\n\r\nFinals:\n\r\nJack vs. Roger, Jack won\n<|im_start|>answer\nFirst Round:\n\r\nJack vs. Tina, Jack won\r\nJamie vs. Renee, Renee won\r\nJessica vs. Tommy, Tommy won\r\nJim vs. Roger, Roger won\n\r\nSecond Round:\n\r\nJack vs. Renee, Jack won\r\nTommy vs. Roger, Roger won\n\r\nFinals:\n\r\nJack vs. Roger, Jack won\n<|im_end|>" }, { "id": "#44345", "title": "The Grandson", "fun": 2.79, "difficulty": 2.11, "author": "whsprec", "desc": "Mrs. Hendricks has five grandsons, Cy, Ben, Chris, Brad, and Luke. Each was born in a different year (2001, 2002, 2003, 2004, and 2005) and each was born in a different month (January, April, July, September, and November). No grandson was born on the weekend, but each grandson was born on a different day of the week. From the clues given determine the day of the week, the month, and the year of birth of each grandson.\r\n1- The grandson who was born on Wednesday, the grandson who was born in July, and Brad, all go to the same school.\r\n2- Chris is older than the grandson born on a Tuesday and younger than the grandson born in November, however, it is the two remaining grandsons who are the eldest and youngest.\r\n3- The second eldest one and Ben both wear braces, but the grandson born on Friday, the grandson born in January, and Brad do not.\r\n4- The grandson born in April was not born on Tuesday or Thursday, and the grandson born in 2003 was not born on Monday or Friday.\r\n5- The grandson born in 2001 was born on Wednesday, and Cy was born on Monday.", "hint": "No hint available.", "answer": "Ben born Wednesday, April 2001\r\nCy born Monday November 2002\r\nChris born Thursday January 2003\r\nBrad born Tuesday September 2004\r\nLuke born Friday July 2005", "category": "Logic-Grid", "date": "04/12/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Hendricks has five grandsons, Cy, Ben, Chris, Brad, and Luke. Each was born in a different year (2001, 2002, 2003, 2004, and 2005) and each was born in a different month (January, April, July, September, and November). No grandson was born on the weekend, but each grandson was born on a different day of the week. From the clues given determine the day of the week, the month, and the year of birth of each grandson.\r\n1- The grandson who was born on Wednesday, the grandson who was born in July, and Brad, all go to the same school.\r\n2- Chris is older than the grandson born on a Tuesday and younger than the grandson born in November, however, it is the two remaining grandsons who are the eldest and youngest.\r\n3- The second eldest one and Ben both wear braces, but the grandson born on Friday, the grandson born in January, and Brad do not.\r\n4- The grandson born in April was not born on Tuesday or Thursday, and the grandson born in 2003 was not born on Monday or Friday.\r\n5- The grandson born in 2001 was born on Wednesday, and Cy was born on Monday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBen born Wednesday, April 2001\r\nCy born Monday November 2002\r\nChris born Thursday January 2003\r\nBrad born Tuesday September 2004\r\nLuke born Friday July 2005\n<|im_start|>answer\nBen born Wednesday, April 2001\r\nCy born Monday November 2002\r\nChris born Thursday January 2003\r\nBrad born Tuesday September 2004\r\nLuke born Friday July 2005\n<|im_end|>" }, { "id": "#37354", "title": "Pick-A-Pizza", "fun": 2.79, "difficulty": 3.35, "author": "camrae27", "desc": "There is a new pizza place in town called Pick-A-Pizza. They have five wheels that, for just a few dollars, you can spin to decide the pizza chef, crust, cheese, meat topping, and veggie topping. When the wheels stop spinning, you have your pizza order! There have only been five customers so far, and each time, a different chef, a different crust (crisp, Greek, Sicilian, thin, or whole wheat), a different cheese (Gorgonzola, mozzarella, Parmesan, provolone, or Romano), a different meat topping (bacon, chicken, meatball, pepperoni, or sausage), and a different veggie topping (broccoli, mushrooms, olives, onions, or peppers) have been chosen. From the information provided, can you determine the crust, cheese, meat and veggie toppings on the pizza made by each chef?\n\r\n1. The pizza topped with onions (which wasn't made by Nunzio) didn't have a Greek crust. Alfredo's pizza didn't have a whole wheat crust and wasn't topped with pepperoni. No pizza had both olives and mozzarella.\n\r\n2. Mario didn't make the bacon pizza (whose crust was neither crisp nor thin). The sausage-topped pizza (which didn't have a whole wheat crust) didn't include peppers. Luigi's pizza (which didn't have a crisp crust) wasn't topped with broccoli.\n\r\n3. Alfredo's pizza (which didn't include chicken) didn't have a Sicilian crust. Neither the pizza with a whole wheat crust (which wasn't topped with onions) nor Nunzio's pizza was topped with provolone cheese. Neither the pie topped with broccoli nor the pepperoni pizza was the one that had a crisp crust.\n\r\n4. Neither Giuseppe's pizza nor the sausage pizza was the one topped with onions. The Sicilian pizza (which wasn't Luigi's) wasn't topped with peppers. Alfredo's pizza (which didn't include olives) wasn't topped with provolone cheese.\n\r\n5. Mario didn't make the pepperoni pizza. The sausage pizza (which wasn't made by Nunzio) wasn't topped with mushrooms. The broccoli pizza was neither the one with a thin crust nor the one topped with mozzarella.\n\r\n6. The meatball pizza (which wasn't topped with onions) didn't have a crisp crust. The olive pizza wasn't topped with Romano. Luigi's pizza (which didn't have a thin crust) wasn't topped with provolone.\n\r\n7. The pizza with a Greek crust wasn't topped with broccoli. The bacon pizza had neither Parmesan nor Romano cheeses. There were no peppers on the thin crust pizza.", "hint": "Mario topped his pie with onions. Alfredo topped his with mushrooms.", "answer": "Alfredo, Thin, Romano, Meatball, Mushrooms\r\nGiuseppe, Whole Wheat, Mozzarella, Pepperoni, Peppers\r\nLuigi, Greek, Parmesan, Sausage, Olives\r\nMario, Crisp, Provolone, Chicken, Onions\r\nNunzio, Sicilian, Gorgonzola, Bacon, Broccoli\n\r\nThe hints are not necessary to solve the puzzle. Here is an explanation of the first hint:\n\r\nLuigi's crust is not crisp (clue 2), Sicilian (clue 4), or thin (clue 6), so it must be Greek or whole wheat. However, onions are not on the pizza with a Greek crust (clue 1) or a whole wheat crust (clue 3), so Luigi cannot have onions on his pizza.\n\r\nThat leaves only Mario or Alfredo who can have onions. Assuming Alfredo has onions leads to a contradiction: Alfredo did not use chicken (clue 3) or pepperoni (clue 1), and onions are not with meatballs (clue 6) or sausage (clue 4), so if Alfredo has onions, he must also have bacon. Alfredo does not have a Sicilian crust (clue 3) or a whole wheat crust (clue 1), and onions are not on the pizza with a Greek crust (clue 1), so he must have a crisp crust or a thin crust. However, bacon is not on the pizza with a crisp crust or a thin crust (clue 2), so Alfredo cannot have bacon. This is a contradiction, so the assumption that Alfredo has onions is false. Thus Mario has onions.", "category": "Logic-Grid", "date": "07/12/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a new pizza place in town called Pick-A-Pizza. They have five wheels that, for just a few dollars, you can spin to decide the pizza chef, crust, cheese, meat topping, and veggie topping. When the wheels stop spinning, you have your pizza order! There have only been five customers so far, and each time, a different chef, a different crust (crisp, Greek, Sicilian, thin, or whole wheat), a different cheese (Gorgonzola, mozzarella, Parmesan, provolone, or Romano), a different meat topping (bacon, chicken, meatball, pepperoni, or sausage), and a different veggie topping (broccoli, mushrooms, olives, onions, or peppers) have been chosen. From the information provided, can you determine the crust, cheese, meat and veggie toppings on the pizza made by each chef?\n\r\n1. The pizza topped with onions (which wasn't made by Nunzio) didn't have a Greek crust. Alfredo's pizza didn't have a whole wheat crust and wasn't topped with pepperoni. No pizza had both olives and mozzarella.\n\r\n2. Mario didn't make the bacon pizza (whose crust was neither crisp nor thin). The sausage-topped pizza (which didn't have a whole wheat crust) didn't include peppers. Luigi's pizza (which didn't have a crisp crust) wasn't topped with broccoli.\n\r\n3. Alfredo's pizza (which didn't include chicken) didn't have a Sicilian crust. Neither the pizza with a whole wheat crust (which wasn't topped with onions) nor Nunzio's pizza was topped with provolone cheese. Neither the pie topped with broccoli nor the pepperoni pizza was the one that had a crisp crust.\n\r\n4. Neither Giuseppe's pizza nor the sausage pizza was the one topped with onions. The Sicilian pizza (which wasn't Luigi's) wasn't topped with peppers. Alfredo's pizza (which didn't include olives) wasn't topped with provolone cheese.\n\r\n5. Mario didn't make the pepperoni pizza. The sausage pizza (which wasn't made by Nunzio) wasn't topped with mushrooms. The broccoli pizza was neither the one with a thin crust nor the one topped with mozzarella.\n\r\n6. The meatball pizza (which wasn't topped with onions) didn't have a crisp crust. The olive pizza wasn't topped with Romano. Luigi's pizza (which didn't have a thin crust) wasn't topped with provolone.\n\r\n7. The pizza with a Greek crust wasn't topped with broccoli. The bacon pizza had neither Parmesan nor Romano cheeses. There were no peppers on the thin crust pizza.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlfredo, Thin, Romano, Meatball, Mushrooms\r\nGiuseppe, Whole Wheat, Mozzarella, Pepperoni, Peppers\r\nLuigi, Greek, Parmesan, Sausage, Olives\r\nMario, Crisp, Provolone, Chicken, Onions\r\nNunzio, Sicilian, Gorgonzola, Bacon, Broccoli\n\r\nThe hints are not necessary to solve the puzzle. Here is an explanation of the first hint:\n\r\nLuigi's crust is not crisp (clue 2), Sicilian (clue 4), or thin (clue 6), so it must be Greek or whole wheat. However, onions are not on the pizza with a Greek crust (clue 1) or a whole wheat crust (clue 3), so Luigi cannot have onions on his pizza.\n\r\nThat leaves only Mario or Alfredo who can have onions. Assuming Alfredo has onions leads to a contradiction: Alfredo did not use chicken (clue 3) or pepperoni (clue 1), and onions are not with meatballs (clue 6) or sausage (clue 4), so if Alfredo has onions, he must also have bacon. Alfredo does not have a Sicilian crust (clue 3) or a whole wheat crust (clue 1), and onions are not on the pizza with a Greek crust (clue 1), so he must have a crisp crust or a thin crust. However, bacon is not on the pizza with a crisp crust or a thin crust (clue 2), so Alfredo cannot have bacon. This is a contradiction, so the assumption that Alfredo has onions is false. Thus Mario has onions.\n<|im_start|>answer\nAlfredo, Thin, Romano, Meatball, Mushrooms\r\nGiuseppe, Whole Wheat, Mozzarella, Pepperoni, Peppers\r\nLuigi, Greek, Parmesan, Sausage, Olives\r\nMario, Crisp, Provolone, Chicken, Onions\r\nNunzio, Sicilian, Gorgonzola, Bacon, Broccoli\n\r\nThe hints are not necessary to solve the puzzle. Here is an explanation of the first hint:\n\r\nLuigi's crust is not crisp (clue 2), Sicilian (clue 4), or thin (clue 6), so it must be Greek or whole wheat. However, onions are not on the pizza with a Greek crust (clue 1) or a whole wheat crust (clue 3), so Luigi cannot have onions on his pizza.\n\r\nThat leaves only Mario or Alfredo who can have onions. Assuming Alfredo has onions leads to a contradiction: Alfredo did not use chicken (clue 3) or pepperoni (clue 1), and onions are not with meatballs (clue 6) or sausage (clue 4), so if Alfredo has onions, he must also have bacon. Alfredo does not have a Sicilian crust (clue 3) or a whole wheat crust (clue 1), and onions are not on the pizza with a Greek crust (clue 1), so he must have a crisp crust or a thin crust. However, bacon is not on the pizza with a crisp crust or a thin crust (clue 2), so Alfredo cannot have bacon. This is a contradiction, so the assumption that Alfredo has onions is false. Thus Mario has onions.\n<|im_end|>" }, { "id": "#8395", "title": "The Four-Stone Ring", "fun": 2.79, "difficulty": 2.49, "author": "skaven", "desc": "While Christmas shopping, I chose a gold ring set with stones for my mother. \n\r\nA ring set with 2 rubies and a diamond would have cost £3,000. One set with 4 amethysts and a diamond would come to £2,000. And 3 emeralds, 1 amethyst and a diamond would be £1,400.\n\r\nBeing a thoughtful son, I chose a ring that would have sentimental value. As my mother called her children Ellen, David, Richard and Andy, I have chosen a ring with one of each stone, to represent her children's names.\n\r\nHow much will my ring containing 1 emerald, 1 diamond, 1 ruby and 1 amethyst cost me?", "hint": "Finding the cost of each gem is not possible. It is still possible to find the value of the ring.", "answer": "The three rings can be expressed as:\n\r\n0E + 0A + 2R + 1D = £3,000\r\n0E + 4A + 0R + 1D = £2,000\r\n3E + 1A + 0R + 1D = £1,400\n\r\nIf we multiply the first line by 1.5 and divide the second line by 2, then total all three rings we get:\n\r\n0E + 0A + 3R + 1.5D = £4,500\r\n0E + 2A + 0R + .5D = £1,000\r\n3E + 1A + 0R + 1D = £1,400\r\n_________________________\r\n3E + 3A + 3R + 3D = £6,900\n\r\n£6,900 / 3 = £2,300\n\r\nFrom this, we can see that a ring with one of each stone will cost me £2,300.", "category": "Math", "date": "11/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile Christmas shopping, I chose a gold ring set with stones for my mother. \n\r\nA ring set with 2 rubies and a diamond would have cost £3,000. One set with 4 amethysts and a diamond would come to £2,000. And 3 emeralds, 1 amethyst and a diamond would be £1,400.\n\r\nBeing a thoughtful son, I chose a ring that would have sentimental value. As my mother called her children Ellen, David, Richard and Andy, I have chosen a ring with one of each stone, to represent her children's names.\n\r\nHow much will my ring containing 1 emerald, 1 diamond, 1 ruby and 1 amethyst cost me?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe three rings can be expressed as:\n\r\n0E + 0A + 2R + 1D = £3,000\r\n0E + 4A + 0R + 1D = £2,000\r\n3E + 1A + 0R + 1D = £1,400\n\r\nIf we multiply the first line by 1.5 and divide the second line by 2, then total all three rings we get:\n\r\n0E + 0A + 3R + 1.5D = £4,500\r\n0E + 2A + 0R + .5D = £1,000\r\n3E + 1A + 0R + 1D = £1,400\r\n_________________________\r\n3E + 3A + 3R + 3D = £6,900\n\r\n£6,900 / 3 = £2,300\n\r\nFrom this, we can see that a ring with one of each stone will cost me £2,300.\n<|im_start|>answer\nThe three rings can be expressed as:\n\r\n0E + 0A + 2R + 1D = £3,000\r\n0E + 4A + 0R + 1D = £2,000\r\n3E + 1A + 0R + 1D = £1,400\n\r\nIf we multiply the first line by 1.5 and divide the second line by 2, then total all three rings we get:\n\r\n0E + 0A + 3R + 1.5D = £4,500\r\n0E + 2A + 0R + .5D = £1,000\r\n3E + 1A + 0R + 1D = £1,400\r\n_________________________\r\n3E + 3A + 3R + 3D = £6,900\n\r\n£6,900 / 3 = £2,300\n\r\nFrom this, we can see that a ring with one of each stone will cost me £2,300.\n<|im_end|>" }, { "id": "#12132", "title": "The ATM", "fun": 2.79, "difficulty": 2.24, "author": "flynn", "desc": "The bank where Elmer and Pearl live just got a shiny, new ATM. So, they decided they had to get one of them-there cards so they could get their money any time--even on Sunday-going-to-Church day. \n\r\nBut, when the manager said pick a 7-digit number that you won't forget, and don't use your birthday, etc. they had a problem. They were not good at remembering stuff. What to do! What to do! Then the light came on! \n\r\nElmer picked 1058421. \r\nPearl picked 6060247. \n\r\nThey exchange information on how they would remember their numbers. \n\r\nPearl said, \"That's a real handy number, Elmer. But I think mine is more timely.\" \n\r\nCan you figure out what they were using for a memory jog?", "hint": "Pearl's statement is the clue.", "answer": "Elmer's number is: 10-5-8-4-2-1\r\nThe number of fingers & thumbs on both hands; fingers and thumbs on one hand; fingers on both hands; fingers on one hand; thumbs on both hands; thumbs on one hand. Pearl said this was HANDy.\n\r\nPearl's number is 60-60-24-7.\r\nThe number of seconds in a minute, the number of minutes in an hour, the number of hours in a day, and the number of days in a week. She said this was TIMEly.", "category": "Logic", "date": "04/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe bank where Elmer and Pearl live just got a shiny, new ATM. So, they decided they had to get one of them-there cards so they could get their money any time--even on Sunday-going-to-Church day. \n\r\nBut, when the manager said pick a 7-digit number that you won't forget, and don't use your birthday, etc. they had a problem. They were not good at remembering stuff. What to do! What to do! Then the light came on! \n\r\nElmer picked 1058421. \r\nPearl picked 6060247. \n\r\nThey exchange information on how they would remember their numbers. \n\r\nPearl said, \"That's a real handy number, Elmer. But I think mine is more timely.\" \n\r\nCan you figure out what they were using for a memory jog?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nElmer's number is: 10-5-8-4-2-1\r\nThe number of fingers & thumbs on both hands; fingers and thumbs on one hand; fingers on both hands; fingers on one hand; thumbs on both hands; thumbs on one hand. Pearl said this was HANDy.\n\r\nPearl's number is 60-60-24-7.\r\nThe number of seconds in a minute, the number of minutes in an hour, the number of hours in a day, and the number of days in a week. She said this was TIMEly.\n<|im_start|>answer\nElmer's number is: 10-5-8-4-2-1\r\nThe number of fingers & thumbs on both hands; fingers and thumbs on one hand; fingers on both hands; fingers on one hand; thumbs on both hands; thumbs on one hand. Pearl said this was HANDy.\n\r\nPearl's number is 60-60-24-7.\r\nThe number of seconds in a minute, the number of minutes in an hour, the number of hours in a day, and the number of days in a week. She said this was TIMEly.\n<|im_end|>" }, { "id": "#51637", "title": "The Strange Library", "fun": 2.79, "difficulty": 2.11, "author": "Hydra1234", "desc": "In a certain library, no two books contain the same number of words, and the total number of books is greater than number of words in the largest book.\n\r\nHow many words does one of the books contain, and what is the book about?", "hint": "No hint available.", "answer": "One of the books is about nothing and has zero words.\n\r\nFirst, the library can be simplified into just two books. If there are two books, the greatest number of words possible is one and the other must have zero.\r\n2 books: 1 word and 0 words.\n\r\nSince the number of books is greater than the number of words in the largest book without repetition in number of words, the number of books will always be one more than the number of words in the largest book. There will always by necessity be books with every number of words possible less than the largest book, and there will always be a book with no words to increase the total number of books. This assumes (correctly) you can't have books with a negative number of words.\n\r\nFollowing this logic, a library with three books has a book with two words, a book with one word, and a book with zero words.\r\n3 books: 2 words, 1 word, and 0 words.\n\r\nA library with n books has a book with n-1 words, a book with n-2 words, a book with n-3 words, and eventually a book with n-n words or zero words.\r\nn books: n-1 words, n-2 words ... 0 words.", "category": "Logic", "date": "12/26/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a certain library, no two books contain the same number of words, and the total number of books is greater than number of words in the largest book.\n\r\nHow many words does one of the books contain, and what is the book about?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne of the books is about nothing and has zero words.\n\r\nFirst, the library can be simplified into just two books. If there are two books, the greatest number of words possible is one and the other must have zero.\r\n2 books: 1 word and 0 words.\n\r\nSince the number of books is greater than the number of words in the largest book without repetition in number of words, the number of books will always be one more than the number of words in the largest book. There will always by necessity be books with every number of words possible less than the largest book, and there will always be a book with no words to increase the total number of books. This assumes (correctly) you can't have books with a negative number of words.\n\r\nFollowing this logic, a library with three books has a book with two words, a book with one word, and a book with zero words.\r\n3 books: 2 words, 1 word, and 0 words.\n\r\nA library with n books has a book with n-1 words, a book with n-2 words, a book with n-3 words, and eventually a book with n-n words or zero words.\r\nn books: n-1 words, n-2 words ... 0 words.\n<|im_start|>answer\nOne of the books is about nothing and has zero words.\n\r\nFirst, the library can be simplified into just two books. If there are two books, the greatest number of words possible is one and the other must have zero.\r\n2 books: 1 word and 0 words.\n\r\nSince the number of books is greater than the number of words in the largest book without repetition in number of words, the number of books will always be one more than the number of words in the largest book. There will always by necessity be books with every number of words possible less than the largest book, and there will always be a book with no words to increase the total number of books. This assumes (correctly) you can't have books with a negative number of words.\n\r\nFollowing this logic, a library with three books has a book with two words, a book with one word, and a book with zero words.\r\n3 books: 2 words, 1 word, and 0 words.\n\r\nA library with n books has a book with n-1 words, a book with n-2 words, a book with n-3 words, and eventually a book with n-n words or zero words.\r\nn books: n-1 words, n-2 words ... 0 words.\n<|im_end|>" }, { "id": "#50642", "title": "The Dilemma of Bread", "fun": 2.79, "difficulty": 1.84, "author": "Hydra1234", "desc": "A hunter met two shepherds, one of whom had three loaves and the other, five loaves. All the loaves were the same size. The three men agreed to share the eight loaves equally between them. After they had eaten, the hunter gave the shepherds eight bronze coins as payment for his meal. How should the two shepherds divide this money based on the bread they gave to the hunter?", "hint": "Eight divided by three", "answer": "The shepherd who had three loaves should get one coin and the shepherd who had five loaves should get seven coins. If there were eight loaves and three men, each man ate two and two-thirds loaves. So the first shepherd gave the hunter one-third of a loaf and the second shepherd gave the hunter two and one-third loaves. The shepherd who gave one-third of a loaf should get one coin and the one who gave seven-thirds of a loaf should get seven coins", "category": "Math", "date": "07/19/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA hunter met two shepherds, one of whom had three loaves and the other, five loaves. All the loaves were the same size. The three men agreed to share the eight loaves equally between them. After they had eaten, the hunter gave the shepherds eight bronze coins as payment for his meal. How should the two shepherds divide this money based on the bread they gave to the hunter?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe shepherd who had three loaves should get one coin and the shepherd who had five loaves should get seven coins. If there were eight loaves and three men, each man ate two and two-thirds loaves. So the first shepherd gave the hunter one-third of a loaf and the second shepherd gave the hunter two and one-third loaves. The shepherd who gave one-third of a loaf should get one coin and the one who gave seven-thirds of a loaf should get seven coins\n<|im_start|>answer\nThe shepherd who had three loaves should get one coin and the shepherd who had five loaves should get seven coins. If there were eight loaves and three men, each man ate two and two-thirds loaves. So the first shepherd gave the hunter one-third of a loaf and the second shepherd gave the hunter two and one-third loaves. The shepherd who gave one-third of a loaf should get one coin and the one who gave seven-thirds of a loaf should get seven coins\n<|im_end|>" }, { "id": "#29031", "title": "Forks in the Road", "fun": 2.79, "difficulty": 2.1, "author": "Tammy93", "desc": "There are five forks in the road from Tratsburg to Denville. Turning left at each of these five forks will lead to one of these five towns: Asterly, Hornton, Seattle, Teasdale, and Thornberry. Turning right at each of the five forks will lead to one of these five towns: Estwater, Houston, Stewartville, Tewsbury, and Thousand Oaks. From the information given, determine the left and right turning at each fork in the road, as well as the order that a traveler would come upon the five forks heading from Tratsburg to Denville.\n\r\n1. The fork in the road to Houston comes earlier than the one to Tewsbury, but later than the ones to Teasdale or Thornberry, and neither of these two is a turning at the first fork in the road.\r\n2. There is not a fork with roads to Stewartville and Asterly.\r\n3. The fork with a road to Thousand Oaks comes before the one to Teasdale, but after the one to Stewartville.\r\n4. The fork to Hornton is not at the same place as the one to Stewartville or Tewsbury.", "hint": "Clarification for clue 2: There is not a fork with roads to Stewartville and Asterly. That means that the roads to Stewartville and Asterly are not at the same fork.", "answer": "First-Seattle-Stewartville\r\nSecond-Thornberry-Thousand Oaks\r\nThird-Teasdale-Estwater\r\nFourth-Hornton-Houston\r\nFifth-Asterly-Tewsbury", "category": "Logic-Grid", "date": "03/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five forks in the road from Tratsburg to Denville. Turning left at each of these five forks will lead to one of these five towns: Asterly, Hornton, Seattle, Teasdale, and Thornberry. Turning right at each of the five forks will lead to one of these five towns: Estwater, Houston, Stewartville, Tewsbury, and Thousand Oaks. From the information given, determine the left and right turning at each fork in the road, as well as the order that a traveler would come upon the five forks heading from Tratsburg to Denville.\n\r\n1. The fork in the road to Houston comes earlier than the one to Tewsbury, but later than the ones to Teasdale or Thornberry, and neither of these two is a turning at the first fork in the road.\r\n2. There is not a fork with roads to Stewartville and Asterly.\r\n3. The fork with a road to Thousand Oaks comes before the one to Teasdale, but after the one to Stewartville.\r\n4. The fork to Hornton is not at the same place as the one to Stewartville or Tewsbury.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst-Seattle-Stewartville\r\nSecond-Thornberry-Thousand Oaks\r\nThird-Teasdale-Estwater\r\nFourth-Hornton-Houston\r\nFifth-Asterly-Tewsbury\n<|im_start|>answer\nFirst-Seattle-Stewartville\r\nSecond-Thornberry-Thousand Oaks\r\nThird-Teasdale-Estwater\r\nFourth-Hornton-Houston\r\nFifth-Asterly-Tewsbury\n<|im_end|>" }, { "id": "#36005", "title": "Pandora's Boxes", "fun": 2.79, "difficulty": 1.47, "author": "Angelli", "desc": "Once upon a time, there was a girl named Pandora, who wanted a bright groom so she made up a few logic problems for the wannabes.\n\r\nBased upon the inscriptions on the boxes (only one is true) Choose one box where the wedding ring is hidden.\n\r\nGold Box: The ring is in this box.\n\r\nSilver Box: The ring is not in this box.\n\r\nLead Box: The ring is not in the gold box.", "hint": "No hint available.", "answer": "The given conditions indicate that only the inscription in the lead box is true. So the ring is in the silver box.", "category": "Logic", "date": "04/02/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce upon a time, there was a girl named Pandora, who wanted a bright groom so she made up a few logic problems for the wannabes.\n\r\nBased upon the inscriptions on the boxes (only one is true) Choose one box where the wedding ring is hidden.\n\r\nGold Box: The ring is in this box.\n\r\nSilver Box: The ring is not in this box.\n\r\nLead Box: The ring is not in the gold box.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe given conditions indicate that only the inscription in the lead box is true. So the ring is in the silver box.\n<|im_start|>answer\nThe given conditions indicate that only the inscription in the lead box is true. So the ring is in the silver box.\n<|im_end|>" }, { "id": "#4953", "title": "Firefighter", "fun": 2.79, "difficulty": 1.17, "author": "glennyboy02", "desc": "A firefighter stood on the middle rung of a ladder, spraying water on a burning house. He then climbed up 6 rungs before the heat of the flames caused him to come down 10 rungs. After some minutes he was able to climb 18 rungs to the very top of the ladder. How many rungs did the ladder have?", "hint": "No hint available.", "answer": "29 rungs\r\nThe firefighter is standing on the middle rung. He goes up 6 rungs so he is now at M+6, he now goes down 10 rungs so he is now at M-4 he goes up 18 rungs so he is now at M+14=T. 14 rungs from the top, 14 rungs from the bottom and the middle rung. 14+14+1=29!", "category": "Math", "date": "06/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA firefighter stood on the middle rung of a ladder, spraying water on a burning house. He then climbed up 6 rungs before the heat of the flames caused him to come down 10 rungs. After some minutes he was able to climb 18 rungs to the very top of the ladder. How many rungs did the ladder have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n29 rungs\r\nThe firefighter is standing on the middle rung. He goes up 6 rungs so he is now at M+6, he now goes down 10 rungs so he is now at M-4 he goes up 18 rungs so he is now at M+14=T. 14 rungs from the top, 14 rungs from the bottom and the middle rung. 14+14+1=29!\n<|im_start|>answer\n29 rungs\r\nThe firefighter is standing on the middle rung. He goes up 6 rungs so he is now at M+6, he now goes down 10 rungs so he is now at M-4 he goes up 18 rungs so he is now at M+14=T. 14 rungs from the top, 14 rungs from the bottom and the middle rung. 14+14+1=29!\n<|im_end|>" }, { "id": "#31215", "title": "Helpdesk Horrors!", "fun": 2.79, "difficulty": 1.69, "author": "brainster", "desc": "It was a crazy day at All Seas Shipping. The IT Helpdesk was working overtime to sort out problems that were coming at them from all directions! Mona was just about ready to unplug the computer to just make them stop for a while, when the computer decided to crash!\n\r\nMona was frantic now! The last 5 things on her priority list was all she remembered, and that too, in bits and pieces. Can you help her put the information together so she can save the day yet again?\n\r\nUsers: Faith, Cindy, George, Reginald, Bill\r\nProblems: Crash, General Failure, Floppy Stuck, Backup System, RAM failure\r\nLocation: Ship, Head Office, Branch Office, Port Office, Overseas Office\r\nTime when complaint was logged: 10:00, 10:30, 11:00, 11:30, 12:00 \n\r\n1. None of the users had a request starting with the same letter as their first name.\n\r\n2. The five users are: the one with the floppy stuck, the one on the ship, the one who logged the request at 10:30, the one in the overseas office and George.\n\r\n3. Faith was very conscientious about her work and always logged support requests for backup before any major meeting. Mona remembered getting an overseas call from Faith at 11:00 for this purpose.\n\r\n4. Bill was enjoying Cindy's embarrassment as she related to him over the phone how she reversed the direction of the floppy and now it would not come out of the drive! His laughter and glee were shortlived however. Half an hour after he spoke to Cindy, his PC crashed, and he logged in a request immediately using the phone.\n\r\n5. The order of time in which the first two support requests were logged was the one in the head office and the one with the computer crash.\n\r\n6. Bill was the Branch Supervisor and George was the Port Supervisor.\n\r\n7. The call from the Port Office was the last call Mona recalled.", "hint": "No hint available.", "answer": "Faith - Backup - Overseas Office - 11:00\r\nCindy - Floppy Stuck - Head Office - 10:00\r\nGeorge - RAM Failure - Port Office - 12:00\r\nReginald - General Failure - Ship - 11:30\r\nBill - Crash - Branch Office - 10:30", "category": "Logic-Grid", "date": "06/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was a crazy day at All Seas Shipping. The IT Helpdesk was working overtime to sort out problems that were coming at them from all directions! Mona was just about ready to unplug the computer to just make them stop for a while, when the computer decided to crash!\n\r\nMona was frantic now! The last 5 things on her priority list was all she remembered, and that too, in bits and pieces. Can you help her put the information together so she can save the day yet again?\n\r\nUsers: Faith, Cindy, George, Reginald, Bill\r\nProblems: Crash, General Failure, Floppy Stuck, Backup System, RAM failure\r\nLocation: Ship, Head Office, Branch Office, Port Office, Overseas Office\r\nTime when complaint was logged: 10:00, 10:30, 11:00, 11:30, 12:00 \n\r\n1. None of the users had a request starting with the same letter as their first name.\n\r\n2. The five users are: the one with the floppy stuck, the one on the ship, the one who logged the request at 10:30, the one in the overseas office and George.\n\r\n3. Faith was very conscientious about her work and always logged support requests for backup before any major meeting. Mona remembered getting an overseas call from Faith at 11:00 for this purpose.\n\r\n4. Bill was enjoying Cindy's embarrassment as she related to him over the phone how she reversed the direction of the floppy and now it would not come out of the drive! His laughter and glee were shortlived however. Half an hour after he spoke to Cindy, his PC crashed, and he logged in a request immediately using the phone.\n\r\n5. The order of time in which the first two support requests were logged was the one in the head office and the one with the computer crash.\n\r\n6. Bill was the Branch Supervisor and George was the Port Supervisor.\n\r\n7. The call from the Port Office was the last call Mona recalled.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFaith - Backup - Overseas Office - 11:00\r\nCindy - Floppy Stuck - Head Office - 10:00\r\nGeorge - RAM Failure - Port Office - 12:00\r\nReginald - General Failure - Ship - 11:30\r\nBill - Crash - Branch Office - 10:30\n<|im_start|>answer\nFaith - Backup - Overseas Office - 11:00\r\nCindy - Floppy Stuck - Head Office - 10:00\r\nGeorge - RAM Failure - Port Office - 12:00\r\nReginald - General Failure - Ship - 11:30\r\nBill - Crash - Branch Office - 10:30\n<|im_end|>" }, { "id": "#40261", "title": "Tennis Balls 2", "fun": 2.79, "difficulty": 1.74, "author": "bookwrmKP", "desc": "You have 27 tennis balls. One is heavier than all the others, which all weigh the same. Using the scale which you have, what is the minimum amount of weighings you must make to determine with all certainty which is the heavier tennis ball?", "hint": "Think about grouping the tennis balls...", "answer": "You only have to use the scale 3 times:\r\nFirst, divide the balls into three groups of nine each. \r\nThen, weigh two of the groups on the scale separately. If there is a large difference, then the heavier group has the heavier ball in it. If they are the same weight, then the third group must have the heavier ball in it.\r\nThird, divide this group into three smaller groups of three tennis balls each. Again, weigh two of them separately.\r\nOnce you have identified the cluster of tennis balls with the greatest weight, for the third time compare two of the tennis balls. Using the logic as in the first and second steps, you can now define the heaviest tennis ball!", "category": "Logic", "date": "01/30/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have 27 tennis balls. One is heavier than all the others, which all weigh the same. Using the scale which you have, what is the minimum amount of weighings you must make to determine with all certainty which is the heavier tennis ball?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou only have to use the scale 3 times:\r\nFirst, divide the balls into three groups of nine each. \r\nThen, weigh two of the groups on the scale separately. If there is a large difference, then the heavier group has the heavier ball in it. If they are the same weight, then the third group must have the heavier ball in it.\r\nThird, divide this group into three smaller groups of three tennis balls each. Again, weigh two of them separately.\r\nOnce you have identified the cluster of tennis balls with the greatest weight, for the third time compare two of the tennis balls. Using the logic as in the first and second steps, you can now define the heaviest tennis ball!\n<|im_start|>answer\nYou only have to use the scale 3 times:\r\nFirst, divide the balls into three groups of nine each. \r\nThen, weigh two of the groups on the scale separately. If there is a large difference, then the heavier group has the heavier ball in it. If they are the same weight, then the third group must have the heavier ball in it.\r\nThird, divide this group into three smaller groups of three tennis balls each. Again, weigh two of them separately.\r\nOnce you have identified the cluster of tennis balls with the greatest weight, for the third time compare two of the tennis balls. Using the logic as in the first and second steps, you can now define the heaviest tennis ball!\n<|im_end|>" }, { "id": "#31907", "title": "Cookie Crunchers", "fun": 2.78, "difficulty": 2.33, "author": "----", "desc": "Cassie, Jon, Luke, Maria, and Sahas baked a batch of 36 cookies, two-thirds of which were chocolate chip. The rest were plain. They each ate at least one right away. The cookies were so delicious, only one-and-a-half dozen are left, of which half are plain.\n\r\n1. Cassie is allergic to chocolate. \r\n2. Luke ate twice as many chocolate chip cookies as plain cookies. \r\n3. Sahas and Maria each ate as many cookies as Luke and Cassie combined. \r\n4. Sahas ate more chocolate chip cookies than Maria. \n\r\nIf all the cookies were eaten by the bakers themselves, how many cookies of each kind did each person eat?", "hint": "1. Determine the distribution of the types of cookies that were eaten. Then solve from there. \r\n2. Make a chart to eliminate the impossibilities.", "answer": "Cassie: 1 plain\r\nJon: 6 chocolate chip\r\nLuke: 2 chocolate chip and 1 plain\r\nMaria: 3 chocolate chip and 1 plain\r\nSahas: 4 chocolate chip\n\r\nOf the 36 cookies baked, two thirds, or 24, were chocolate chip and 12 were plain.\n\r\nOf the 1 1/2 dozen, or 18, cookies remaining, 9 are chocolate chip and 9 are plain.\n\r\nSo, of the cookies eaten, 24 - 9 = 15, which were chocolate chip, and 12 - 9 = 3, which were plain.\n\r\nBoth Cassie and Luke must each have eaten at least 1 plain cookie. Sahas and Maria each ate the same number of cookies, but Sahas ate more chocolate chip cookies than Maria, so one of Maria's cookies must have been plain. That left Cassie with 1 plain cookie, and Luke with 1 plain and 2 chocolate chip cookies. Between them, Luke and Cassie ate 4 cookies, so Sahas ate 4 chocolate chip cookies and Maria ate 3 chocolate chip cookies and 1 plain cookie. Jon must have eaten the other 6 chocolate chip cookies.", "category": "Logic", "date": "07/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCassie, Jon, Luke, Maria, and Sahas baked a batch of 36 cookies, two-thirds of which were chocolate chip. The rest were plain. They each ate at least one right away. The cookies were so delicious, only one-and-a-half dozen are left, of which half are plain.\n\r\n1. Cassie is allergic to chocolate. \r\n2. Luke ate twice as many chocolate chip cookies as plain cookies. \r\n3. Sahas and Maria each ate as many cookies as Luke and Cassie combined. \r\n4. Sahas ate more chocolate chip cookies than Maria. \n\r\nIf all the cookies were eaten by the bakers themselves, how many cookies of each kind did each person eat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCassie: 1 plain\r\nJon: 6 chocolate chip\r\nLuke: 2 chocolate chip and 1 plain\r\nMaria: 3 chocolate chip and 1 plain\r\nSahas: 4 chocolate chip\n\r\nOf the 36 cookies baked, two thirds, or 24, were chocolate chip and 12 were plain.\n\r\nOf the 1 1/2 dozen, or 18, cookies remaining, 9 are chocolate chip and 9 are plain.\n\r\nSo, of the cookies eaten, 24 - 9 = 15, which were chocolate chip, and 12 - 9 = 3, which were plain.\n\r\nBoth Cassie and Luke must each have eaten at least 1 plain cookie. Sahas and Maria each ate the same number of cookies, but Sahas ate more chocolate chip cookies than Maria, so one of Maria's cookies must have been plain. That left Cassie with 1 plain cookie, and Luke with 1 plain and 2 chocolate chip cookies. Between them, Luke and Cassie ate 4 cookies, so Sahas ate 4 chocolate chip cookies and Maria ate 3 chocolate chip cookies and 1 plain cookie. Jon must have eaten the other 6 chocolate chip cookies.\n<|im_start|>answer\nCassie: 1 plain\r\nJon: 6 chocolate chip\r\nLuke: 2 chocolate chip and 1 plain\r\nMaria: 3 chocolate chip and 1 plain\r\nSahas: 4 chocolate chip\n\r\nOf the 36 cookies baked, two thirds, or 24, were chocolate chip and 12 were plain.\n\r\nOf the 1 1/2 dozen, or 18, cookies remaining, 9 are chocolate chip and 9 are plain.\n\r\nSo, of the cookies eaten, 24 - 9 = 15, which were chocolate chip, and 12 - 9 = 3, which were plain.\n\r\nBoth Cassie and Luke must each have eaten at least 1 plain cookie. Sahas and Maria each ate the same number of cookies, but Sahas ate more chocolate chip cookies than Maria, so one of Maria's cookies must have been plain. That left Cassie with 1 plain cookie, and Luke with 1 plain and 2 chocolate chip cookies. Between them, Luke and Cassie ate 4 cookies, so Sahas ate 4 chocolate chip cookies and Maria ate 3 chocolate chip cookies and 1 plain cookie. Jon must have eaten the other 6 chocolate chip cookies.\n<|im_end|>" }, { "id": "#36187", "title": "Easter Egg Hunt II", "fun": 2.78, "difficulty": 1.66, "author": "cdrock", "desc": "The bunnies in Easter Village are excited once again, for their annual Easter Egg Hunt has just been finished. In the Hunt, four bunnies search around the town for one of the Easter Eggs. Once they have each found one, they hop back to the finish line! Can you figure out which rabbits found which eggs, what places they got in the Hunt, and the prizes that were in their Easter Egg?\n\r\nBunnies: Mr. Hops, Jumper, Long Ears, Ms. Littlenose\r\nEggs: Blue, Red, Green, Yellow\r\nPrizes in Eggs: Chocolate Candy, Jelly Bean, Gold Coin, Visor\n\n\r\nClues:\n\r\n1. The four bunnies were Mr. Hops, the bunny that found the Red Egg, the bunny that finished in 4th place, and the bunny that found the Gold Coin in their egg.\n\r\n2. Long Ears did not find the Visor in his Egg.\n\r\n3. The bunny that placed 2nd found the Chocolate Candy in his/her Egg.\n\r\n4. Neither Long Ears nor Ms. Littlenose found the Red Egg.\n\r\n5. The bunny who placed 1st found the Green Egg.\n\r\n6. The bunny who found the Red Egg did not finish the Hunt in 3rd Place.\n\r\n7. Long Ears did not find the Gold Coin.\n\r\n8. The bunny who found the Blue Egg did not find the Jelly Bean in his/her egg.\n\r\n9. The bunny who finished 1st did not find the Visor in his/her egg.", "hint": "No hint available.", "answer": "1. Mr. Hops found the Blue Egg that had the Visor and finished 3rd.\n\r\n2. Jumper found the Red Egg that had the Chocolate Candy and finished 2nd.\n\r\n3. Long Ears found the Yellow Egg that had the Jelly Bean and finished 4th.\n\r\n4. Ms. Littlenose found the Green Egg that had the Gold Coin and finished 1st.", "category": "Logic-Grid", "date": "04/12/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe bunnies in Easter Village are excited once again, for their annual Easter Egg Hunt has just been finished. In the Hunt, four bunnies search around the town for one of the Easter Eggs. Once they have each found one, they hop back to the finish line! Can you figure out which rabbits found which eggs, what places they got in the Hunt, and the prizes that were in their Easter Egg?\n\r\nBunnies: Mr. Hops, Jumper, Long Ears, Ms. Littlenose\r\nEggs: Blue, Red, Green, Yellow\r\nPrizes in Eggs: Chocolate Candy, Jelly Bean, Gold Coin, Visor\n\n\r\nClues:\n\r\n1. The four bunnies were Mr. Hops, the bunny that found the Red Egg, the bunny that finished in 4th place, and the bunny that found the Gold Coin in their egg.\n\r\n2. Long Ears did not find the Visor in his Egg.\n\r\n3. The bunny that placed 2nd found the Chocolate Candy in his/her Egg.\n\r\n4. Neither Long Ears nor Ms. Littlenose found the Red Egg.\n\r\n5. The bunny who placed 1st found the Green Egg.\n\r\n6. The bunny who found the Red Egg did not finish the Hunt in 3rd Place.\n\r\n7. Long Ears did not find the Gold Coin.\n\r\n8. The bunny who found the Blue Egg did not find the Jelly Bean in his/her egg.\n\r\n9. The bunny who finished 1st did not find the Visor in his/her egg.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Mr. Hops found the Blue Egg that had the Visor and finished 3rd.\n\r\n2. Jumper found the Red Egg that had the Chocolate Candy and finished 2nd.\n\r\n3. Long Ears found the Yellow Egg that had the Jelly Bean and finished 4th.\n\r\n4. Ms. Littlenose found the Green Egg that had the Gold Coin and finished 1st.\n<|im_start|>answer\n1. Mr. Hops found the Blue Egg that had the Visor and finished 3rd.\n\r\n2. Jumper found the Red Egg that had the Chocolate Candy and finished 2nd.\n\r\n3. Long Ears found the Yellow Egg that had the Jelly Bean and finished 4th.\n\r\n4. Ms. Littlenose found the Green Egg that had the Gold Coin and finished 1st.\n<|im_end|>" }, { "id": "#7564", "title": "Ring Ring Ring", "fun": 2.78, "difficulty": 2.56, "author": "BigSurf18", "desc": "The following group of numbers represents an 11-letter word. Can you figure out the word?\n\r\n46244628466\r\n31113211332", "hint": "Try a phone.", "answer": "Imagination! Look on a telephone; the first row is what number to look on. The second row is which letter to look at!", "category": "Logic", "date": "09/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following group of numbers represents an 11-letter word. Can you figure out the word?\n\r\n46244628466\r\n31113211332\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nImagination! Look on a telephone; the first row is what number to look on. The second row is which letter to look at!\n<|im_start|>answer\nImagination! Look on a telephone; the first row is what number to look on. The second row is which letter to look at!\n<|im_end|>" }, { "id": "#23728", "title": "Beach Ball", "fun": 2.78, "difficulty": 1.57, "author": "aznboi1324", "desc": "Marina, her sister, her daughter, and her son are playing volleyball on the beach. Marina's sister is directly across the net from her son. Marina's daughter is diagonally across the net from the best player's sibling. The best player and the worst player are on the same side of the net. Who is the worst player?", "hint": "No hint available.", "answer": "The worst player is Marina's sister. Draw a diagram, putting Marina's sister and son directly across the net from each other. It doesn't matter whether they're on the left or the right side of the diagram.", "category": "Logic", "date": "06/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMarina, her sister, her daughter, and her son are playing volleyball on the beach. Marina's sister is directly across the net from her son. Marina's daughter is diagonally across the net from the best player's sibling. The best player and the worst player are on the same side of the net. Who is the worst player?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe worst player is Marina's sister. Draw a diagram, putting Marina's sister and son directly across the net from each other. It doesn't matter whether they're on the left or the right side of the diagram.\n<|im_start|>answer\nThe worst player is Marina's sister. Draw a diagram, putting Marina's sister and son directly across the net from each other. It doesn't matter whether they're on the left or the right side of the diagram.\n<|im_end|>" }, { "id": "#36452", "title": "The Stork, Bear and Fox Race", "fun": 2.78, "difficulty": 0.91, "author": "redbunny016", "desc": "Max Mouse returned from the forest bike race after competing with a bear, a stork, and a frog. Max said the stork finished two places ahead of him, the bear was neither first nor last, and the stork was not second. From Max's clues, can you figure out which order they each finished in?", "hint": "No hint available.", "answer": "The stork won, followed by the bear, then Max, and the frog finished last.", "category": "Logic", "date": "04/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMax Mouse returned from the forest bike race after competing with a bear, a stork, and a frog. Max said the stork finished two places ahead of him, the bear was neither first nor last, and the stork was not second. From Max's clues, can you figure out which order they each finished in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe stork won, followed by the bear, then Max, and the frog finished last.\n<|im_start|>answer\nThe stork won, followed by the bear, then Max, and the frog finished last.\n<|im_end|>" }, { "id": "#46559", "title": "Card Quandary", "fun": 2.78, "difficulty": 2.11, "author": "dalfamnest", "desc": "Mavis the 'mathemagician' held ten cards (face down) in her hand - Ace (1) to 10 of Hearts.\n\r\nShe moved the top card to the bottom of the pack, counting '1', and turned up the next card, placing it on the table. It was the Ace.\n\r\nShe counted two more cards to the bottom of the pack, showed the next card - the '2' - and placed it on the table.\n\r\nCounting, 'One, two, three' more to the bottom, she then showed the next card - '3' of Hearts.\n\r\nThis continued for four to nine, and the final card was - ta-daah! - the '10' of Hearts.\n\r\nQuestion: What was the original order of cards, from the top to bottom?", "hint": "Try it with pieces of paper, real cards, or a diagram on paper ...\n\r\n... or scroll down to a hint that might make it too easy ...\n\n\n\n\n\r\nThe cards, from the top of the pack, must have been:\r\n* A * * 2 * * * 3 *", "answer": "9 A 8 5 2 4 7 6 3 10\n\r\nYou might like to try this as a challenging 'trick' for younger people to work out (or your parents!!)\n\r\nA further challenge is to 'spell' the number as you move the cards, one by one, to the bottom:\r\n\"O, N, E, '1', T, W, O, '2', etc.", "category": "Logic", "date": "03/17/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMavis the 'mathemagician' held ten cards (face down) in her hand - Ace (1) to 10 of Hearts.\n\r\nShe moved the top card to the bottom of the pack, counting '1', and turned up the next card, placing it on the table. It was the Ace.\n\r\nShe counted two more cards to the bottom of the pack, showed the next card - the '2' - and placed it on the table.\n\r\nCounting, 'One, two, three' more to the bottom, she then showed the next card - '3' of Hearts.\n\r\nThis continued for four to nine, and the final card was - ta-daah! - the '10' of Hearts.\n\r\nQuestion: What was the original order of cards, from the top to bottom?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9 A 8 5 2 4 7 6 3 10\n\r\nYou might like to try this as a challenging 'trick' for younger people to work out (or your parents!!)\n\r\nA further challenge is to 'spell' the number as you move the cards, one by one, to the bottom:\r\n\"O, N, E, '1', T, W, O, '2', etc.\n<|im_start|>answer\n9 A 8 5 2 4 7 6 3 10\n\r\nYou might like to try this as a challenging 'trick' for younger people to work out (or your parents!!)\n\r\nA further challenge is to 'spell' the number as you move the cards, one by one, to the bottom:\r\n\"O, N, E, '1', T, W, O, '2', etc.\n<|im_end|>" }, { "id": "#3238", "title": "Lemme See that Bag", "fun": 2.78, "difficulty": 1.69, "author": "Drunky", "desc": "A man working at border patrol had to inspect the luggage and cargo people brought across the border. One day this man came up on a beautiful bike with 2 huge sacks on his shoulder. The man was sweating a little, the officer unsure whether it was from the riding or of fear asked to see the cargo. The man obediently opened the bag and saw only sand. He waved the man through. Next week the man came back riding his bike with 2 huge sacks and the same thing happened. \n\r\nThis happened every week for months. Finally, one day he saw the man on the news being sentenced to death for a crime he committed several years back. The officer went down to the station and asked the prisoner, \"I know you're doing something illegal, but what is it?\" The prisoner already condemned to death told the officer and the officer said nothing and just walked out. What did the man say he was illegally doing?", "hint": "Think of his type of transportation.", "answer": "He said he was smuggling bikes and the sacks just diverted the attention away from the counterfeit bikes.", "category": "Logic", "date": "04/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man working at border patrol had to inspect the luggage and cargo people brought across the border. One day this man came up on a beautiful bike with 2 huge sacks on his shoulder. The man was sweating a little, the officer unsure whether it was from the riding or of fear asked to see the cargo. The man obediently opened the bag and saw only sand. He waved the man through. Next week the man came back riding his bike with 2 huge sacks and the same thing happened. \n\r\nThis happened every week for months. Finally, one day he saw the man on the news being sentenced to death for a crime he committed several years back. The officer went down to the station and asked the prisoner, \"I know you're doing something illegal, but what is it?\" The prisoner already condemned to death told the officer and the officer said nothing and just walked out. What did the man say he was illegally doing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe said he was smuggling bikes and the sacks just diverted the attention away from the counterfeit bikes.\n<|im_start|>answer\nHe said he was smuggling bikes and the sacks just diverted the attention away from the counterfeit bikes.\n<|im_end|>" }, { "id": "#3395", "title": "Lobster Spies", "fun": 2.78, "difficulty": 1.4, "author": "204_BLaZe_41", "desc": "During World War 2, several British naval spies on the lookout for enemy ships and activities posed as Canadian lobster fishermen. They had large numbers of plastic, orange-coloured lobsters made for their covert operations. These lobsters came in various sizes with all the authentic markings. At night, the spies loaded the lobsters into traps and threw them overboard. At daybreak, they would hoist the traps aboard ship. The locals spotted them as fraudulent fishermen from quite a distance. How were they so easily detected?", "hint": "No hint available.", "answer": "All lobster fishermen and most lobster lovers know live lobsters are greenish-black. They turn a bright orange only when they are cooked.", "category": "Logic", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring World War 2, several British naval spies on the lookout for enemy ships and activities posed as Canadian lobster fishermen. They had large numbers of plastic, orange-coloured lobsters made for their covert operations. These lobsters came in various sizes with all the authentic markings. At night, the spies loaded the lobsters into traps and threw them overboard. At daybreak, they would hoist the traps aboard ship. The locals spotted them as fraudulent fishermen from quite a distance. How were they so easily detected?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll lobster fishermen and most lobster lovers know live lobsters are greenish-black. They turn a bright orange only when they are cooked.\n<|im_start|>answer\nAll lobster fishermen and most lobster lovers know live lobsters are greenish-black. They turn a bright orange only when they are cooked.\n<|im_end|>" }, { "id": "#24612", "title": "Mything In Action", "fun": 2.78, "difficulty": 2.56, "author": "cinnamon30", "desc": "From an early age, Phyllis has been enraptured by mythological lore. Phyllis has now found a way to turn her love of mythology into a hobby - she collects mythological deity action figures. Phyllis has accumulated five figures so far, each of which depicts a different deity and is made from a different material. Each of the figures is a different height and weight. From the info provided, determine the material from which each figure is made, as well as each toy's height in inches and weight in ounces.\n\r\nFigure - Ares, Demeter, Hera, Odin and Thor\r\nMaterial - Aluminum, Ceramic, Plastic, Rubber and Wood\r\nHeight - 1, 2, 3, 4 and 5 inches\r\nWeight - 3, 5, 6, 7, and 8 ounces\n\r\n1. The Ares figure weighs less than 8 ounces. The Demeter action figure (which isn't made from rubber) weighs more than 3 ounces.\n\r\n2. The ceramic figure is taller than the one that weighs 6 ounces (which doesn't depict Odin). The heaviest figurine (which doesn't depict Demeter) isn't 2 inches tall.\n\r\n3. The 3-ounce toy (which isn't five inches tall) isn't the rubber figure (which doesn't depict Hera).\n\r\n4. The plastic figure weighs more than the 5-inch toy. The 1-inch figure weighs 5 ounces. The aluminum action figure weighs more than 3 ounces. The figure of Odin (which isn't the one made from wood) weighs less than 8 ounces.\n\r\n5. The Thor figure isn't the 3-inch figure (which doesn't weigh 6 ounces). Neither the figure of Hera (which isn't the heaviest toy) nor the ceramic figure is the lightest action figure.", "hint": "No hint available.", "answer": "Ares - wood, 3 inches and 3 ounces\r\nDemeter - ceramic, 5 inches and 7 ounces\r\nHera - aluminum, 2 inches and 6 ounces\r\nOdin - rubber, 1 inch and 5 ounces\r\nThor - plastic, 4 inches and 8 ounces\n\r\nThe 8-ounce figure isn't Ares (1), Demeter (2), Odin (4) or Hera (5). Therefore it's Thor. Thor isn't 2 inches (2), 5 inches (4), 1 inch (4) or 3 inches (5). Thus Thor is 4 inches tall. The tallest figure - 5 inches - is not 6 ounces (2), 3 ounces (3) or 5 ounces (4), thus it is 7 ounces. The plastic figure is 8 ounces (4). The 1-inch figure is 5 ounces (4). The 3-inch figure isn't 6 ounces (5), thus it has to be 3 ounces. This leaves the 2-inch figure as 6 ounces. The 3-ounce figure isn't rubber (3), aluminum (4) or ceramic (5), thus it is wood. The wood figure isn't Demeter (1), Odin (4) or Hera (5), thus it is Ares. The ceramic figure is the 5-inch figure (2). Hera isn't rubber (3) or ceramic (5), thus Hera is aluminum. Demeter isn't rubber (1), therefore Odin is rubber and Demeter is ceramic. Odin is not 6-ounces (2), thus Odin is 5 ounces - only one left.", "category": "Logic-Grid", "date": "07/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFrom an early age, Phyllis has been enraptured by mythological lore. Phyllis has now found a way to turn her love of mythology into a hobby - she collects mythological deity action figures. Phyllis has accumulated five figures so far, each of which depicts a different deity and is made from a different material. Each of the figures is a different height and weight. From the info provided, determine the material from which each figure is made, as well as each toy's height in inches and weight in ounces.\n\r\nFigure - Ares, Demeter, Hera, Odin and Thor\r\nMaterial - Aluminum, Ceramic, Plastic, Rubber and Wood\r\nHeight - 1, 2, 3, 4 and 5 inches\r\nWeight - 3, 5, 6, 7, and 8 ounces\n\r\n1. The Ares figure weighs less than 8 ounces. The Demeter action figure (which isn't made from rubber) weighs more than 3 ounces.\n\r\n2. The ceramic figure is taller than the one that weighs 6 ounces (which doesn't depict Odin). The heaviest figurine (which doesn't depict Demeter) isn't 2 inches tall.\n\r\n3. The 3-ounce toy (which isn't five inches tall) isn't the rubber figure (which doesn't depict Hera).\n\r\n4. The plastic figure weighs more than the 5-inch toy. The 1-inch figure weighs 5 ounces. The aluminum action figure weighs more than 3 ounces. The figure of Odin (which isn't the one made from wood) weighs less than 8 ounces.\n\r\n5. The Thor figure isn't the 3-inch figure (which doesn't weigh 6 ounces). Neither the figure of Hera (which isn't the heaviest toy) nor the ceramic figure is the lightest action figure.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAres - wood, 3 inches and 3 ounces\r\nDemeter - ceramic, 5 inches and 7 ounces\r\nHera - aluminum, 2 inches and 6 ounces\r\nOdin - rubber, 1 inch and 5 ounces\r\nThor - plastic, 4 inches and 8 ounces\n\r\nThe 8-ounce figure isn't Ares (1), Demeter (2), Odin (4) or Hera (5). Therefore it's Thor. Thor isn't 2 inches (2), 5 inches (4), 1 inch (4) or 3 inches (5). Thus Thor is 4 inches tall. The tallest figure - 5 inches - is not 6 ounces (2), 3 ounces (3) or 5 ounces (4), thus it is 7 ounces. The plastic figure is 8 ounces (4). The 1-inch figure is 5 ounces (4). The 3-inch figure isn't 6 ounces (5), thus it has to be 3 ounces. This leaves the 2-inch figure as 6 ounces. The 3-ounce figure isn't rubber (3), aluminum (4) or ceramic (5), thus it is wood. The wood figure isn't Demeter (1), Odin (4) or Hera (5), thus it is Ares. The ceramic figure is the 5-inch figure (2). Hera isn't rubber (3) or ceramic (5), thus Hera is aluminum. Demeter isn't rubber (1), therefore Odin is rubber and Demeter is ceramic. Odin is not 6-ounces (2), thus Odin is 5 ounces - only one left.\n<|im_start|>answer\nAres - wood, 3 inches and 3 ounces\r\nDemeter - ceramic, 5 inches and 7 ounces\r\nHera - aluminum, 2 inches and 6 ounces\r\nOdin - rubber, 1 inch and 5 ounces\r\nThor - plastic, 4 inches and 8 ounces\n\r\nThe 8-ounce figure isn't Ares (1), Demeter (2), Odin (4) or Hera (5). Therefore it's Thor. Thor isn't 2 inches (2), 5 inches (4), 1 inch (4) or 3 inches (5). Thus Thor is 4 inches tall. The tallest figure - 5 inches - is not 6 ounces (2), 3 ounces (3) or 5 ounces (4), thus it is 7 ounces. The plastic figure is 8 ounces (4). The 1-inch figure is 5 ounces (4). The 3-inch figure isn't 6 ounces (5), thus it has to be 3 ounces. This leaves the 2-inch figure as 6 ounces. The 3-ounce figure isn't rubber (3), aluminum (4) or ceramic (5), thus it is wood. The wood figure isn't Demeter (1), Odin (4) or Hera (5), thus it is Ares. The ceramic figure is the 5-inch figure (2). Hera isn't rubber (3) or ceramic (5), thus Hera is aluminum. Demeter isn't rubber (1), therefore Odin is rubber and Demeter is ceramic. Odin is not 6-ounces (2), thus Odin is 5 ounces - only one left.\n<|im_end|>" }, { "id": "#33066", "title": "Numbers, Numbers", "fun": 2.78, "difficulty": 2.31, "author": "medster99", "desc": "There is a very special five digit number. The special thing about it is that its first digit describes how many 0s there are in the whole number, the second digit describes how many 1s there are in the whole number, and so one, all the way to the fifth digit describing how many 4s there are in the big number.\n\r\nFor example, if the second digit is 3, then there are three '1s' in the big number.", "hint": "No hint available.", "answer": "The number is 21200.\n\r\nThere are 2 zeroes, 1 one, 2 twos, 0 threes and 0 fours.", "category": "Logic", "date": "09/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a very special five digit number. The special thing about it is that its first digit describes how many 0s there are in the whole number, the second digit describes how many 1s there are in the whole number, and so one, all the way to the fifth digit describing how many 4s there are in the big number.\n\r\nFor example, if the second digit is 3, then there are three '1s' in the big number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 21200.\n\r\nThere are 2 zeroes, 1 one, 2 twos, 0 threes and 0 fours.\n<|im_start|>answer\nThe number is 21200.\n\r\nThere are 2 zeroes, 1 one, 2 twos, 0 threes and 0 fours.\n<|im_end|>" }, { "id": "#275", "title": "Knightly Love", "fun": 2.78, "difficulty": 1.96, "author": "Phyllis", "desc": "A poor, young knight wants to marry a beautiful princess and she wants to marry him. But the king doesn't want the marriage. He offers the knight a choice. He can draw one of two slips of paper out of a golden urn. One will say \"marriage\" and one will say \"death\". The princess is able to whisper to the knight that both slips of paper really say \"death\". The knight and the princess end up being wed. How does the knight accomplish this?", "hint": "No hint available.", "answer": "The knight picks a slip of paper and immediately tears it up. He then takes out the other slip and hands it to the king. Since the untorn slip of paper says \"death\", the knight says that obviously the one he tore up said \"marriage\".", "category": "Logic", "date": "02/13/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA poor, young knight wants to marry a beautiful princess and she wants to marry him. But the king doesn't want the marriage. He offers the knight a choice. He can draw one of two slips of paper out of a golden urn. One will say \"marriage\" and one will say \"death\". The princess is able to whisper to the knight that both slips of paper really say \"death\". The knight and the princess end up being wed. How does the knight accomplish this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe knight picks a slip of paper and immediately tears it up. He then takes out the other slip and hands it to the king. Since the untorn slip of paper says \"death\", the knight says that obviously the one he tore up said \"marriage\".\n<|im_start|>answer\nThe knight picks a slip of paper and immediately tears it up. He then takes out the other slip and hands it to the king. Since the untorn slip of paper says \"death\", the knight says that obviously the one he tore up said \"marriage\".\n<|im_end|>" }, { "id": "#48169", "title": "Mrs. Smith's Daughters", "fun": 2.78, "difficulty": 1.25, "author": "cutieluck", "desc": "Jane, Anna, Kate, and Sarah are Mrs. Smith's 4 daughters. Each daughter has a different hair color (black, blond, brown, or red) and a different eye color (blue, brown, green, or hazel). Using the information given, try to determine not only each daughter's hair and eye color but also whether she is one, two, three, or four years old.\n\r\n1. The girl with black hair is younger than Sarah.\n\r\n2. Of Jane and Anna, one has brown hair and the other has brown eyes, but neither is the oldest or youngest.\n\r\n3. Kate does not have hazel eyes.\n\r\n4. The blond is younger than the girl with green eyes but older than Anna.", "hint": "No hint available.", "answer": "Sarah: 4 years old, red hair, and green eyes\n\r\nJane: 3 years old, blond, and brown eyes.\n\r\nAnna: 2 years old, brown hair, and hazel eyes\n\r\nKate: 1 year old, black hair, and blue eyes", "category": "Logic-Grid", "date": "11/03/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJane, Anna, Kate, and Sarah are Mrs. Smith's 4 daughters. Each daughter has a different hair color (black, blond, brown, or red) and a different eye color (blue, brown, green, or hazel). Using the information given, try to determine not only each daughter's hair and eye color but also whether she is one, two, three, or four years old.\n\r\n1. The girl with black hair is younger than Sarah.\n\r\n2. Of Jane and Anna, one has brown hair and the other has brown eyes, but neither is the oldest or youngest.\n\r\n3. Kate does not have hazel eyes.\n\r\n4. The blond is younger than the girl with green eyes but older than Anna.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah: 4 years old, red hair, and green eyes\n\r\nJane: 3 years old, blond, and brown eyes.\n\r\nAnna: 2 years old, brown hair, and hazel eyes\n\r\nKate: 1 year old, black hair, and blue eyes\n<|im_start|>answer\nSarah: 4 years old, red hair, and green eyes\n\r\nJane: 3 years old, blond, and brown eyes.\n\r\nAnna: 2 years old, brown hair, and hazel eyes\n\r\nKate: 1 year old, black hair, and blue eyes\n<|im_end|>" }, { "id": "#1402", "title": "The Color of My Hat", "fun": 2.78, "difficulty": 1.86, "author": "gokaran", "desc": "Three men are buried in the sand all facing forwards with their heads above ground. Each man has a hat placed on his head selected from a bag containing 3 red hats, and 2 black hats. The men cannot turn around to see the men behind them. The man at the back is asked what hat he is wearing. He replies 'I do not know'. The middle man is asked what hat he is wearing. He also replies 'I do not know'. The man at the front is then asked what hat he is wearing. He replies 'I am wearing a red hat'. How did he know?", "hint": "No hint available.", "answer": "Since the man at the back could not determine his own hat, this means that the front two men could not have been wearing black hats and that, therefore, there must be at least one red hat on the two front men. Therefore the middle man must not be able to see a black hat otherwise he would know he had a red one on. Therefore the front man must be wearing a red hat - which finally he deduces. Interestingly, the other two can never determine their own hats.", "category": "Logic", "date": "11/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree men are buried in the sand all facing forwards with their heads above ground. Each man has a hat placed on his head selected from a bag containing 3 red hats, and 2 black hats. The men cannot turn around to see the men behind them. The man at the back is asked what hat he is wearing. He replies 'I do not know'. The middle man is asked what hat he is wearing. He also replies 'I do not know'. The man at the front is then asked what hat he is wearing. He replies 'I am wearing a red hat'. How did he know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince the man at the back could not determine his own hat, this means that the front two men could not have been wearing black hats and that, therefore, there must be at least one red hat on the two front men. Therefore the middle man must not be able to see a black hat otherwise he would know he had a red one on. Therefore the front man must be wearing a red hat - which finally he deduces. Interestingly, the other two can never determine their own hats.\n<|im_start|>answer\nSince the man at the back could not determine his own hat, this means that the front two men could not have been wearing black hats and that, therefore, there must be at least one red hat on the two front men. Therefore the middle man must not be able to see a black hat otherwise he would know he had a red one on. Therefore the front man must be wearing a red hat - which finally he deduces. Interestingly, the other two can never determine their own hats.\n<|im_end|>" }, { "id": "#29996", "title": "The Total is 14, Part I", "fun": 2.77, "difficulty": 2.29, "author": "tsimkin", "desc": "Mr. Simkin, the new math teacher at school, pulled aside three students, and handed them each a sealed envelope with a number written inside. He told them that they each had a positive integer, and the sum of their numbers was 14.\n\r\nSage and Rosemary opened their envelopes, and on seeing his number, Sage said, \"I know that Rosemary and Tim have different numbers.\"\n\r\nRosemary replied, \"I already knew our numbers were all different, and now I know everyone's number.\"\n\r\nTim said, \"Then I do, as well,\" even though he never opened his envelope.\n\r\nHow could he have known? What numbers did everyone have?", "hint": "No hint available.", "answer": "Sage had a 1, Rosemary had an 11, and Tim had a 2.\n\r\nFrom Sage's statement, he had to have an odd number. He knew that the sum of all three numbers was even, so if his number was odd, one of the other two numbers would have to be odd, and the other even, leaving them unequal.\n\r\nRosemary could deduce this, too, so when she saw an 11, she knew that Sage had a 1 and Tim had a 2. If she had seen a 12, she would have known that the other two boys each had a 1, which is contradicted by her saying that she already knew they all had different numbers. If she saw any number other than an 11 (say 9, for example), she would not have know which odd number Sage held. (In our example, he could have had a 1 and Tim a 4, or he could have had a 3 and Tim a 2).\n\r\nTim, understanding all of this, therefore knew their numbers.", "category": "Logic", "date": "04/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Simkin, the new math teacher at school, pulled aside three students, and handed them each a sealed envelope with a number written inside. He told them that they each had a positive integer, and the sum of their numbers was 14.\n\r\nSage and Rosemary opened their envelopes, and on seeing his number, Sage said, \"I know that Rosemary and Tim have different numbers.\"\n\r\nRosemary replied, \"I already knew our numbers were all different, and now I know everyone's number.\"\n\r\nTim said, \"Then I do, as well,\" even though he never opened his envelope.\n\r\nHow could he have known? What numbers did everyone have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSage had a 1, Rosemary had an 11, and Tim had a 2.\n\r\nFrom Sage's statement, he had to have an odd number. He knew that the sum of all three numbers was even, so if his number was odd, one of the other two numbers would have to be odd, and the other even, leaving them unequal.\n\r\nRosemary could deduce this, too, so when she saw an 11, she knew that Sage had a 1 and Tim had a 2. If she had seen a 12, she would have known that the other two boys each had a 1, which is contradicted by her saying that she already knew they all had different numbers. If she saw any number other than an 11 (say 9, for example), she would not have know which odd number Sage held. (In our example, he could have had a 1 and Tim a 4, or he could have had a 3 and Tim a 2).\n\r\nTim, understanding all of this, therefore knew their numbers.\n<|im_start|>answer\nSage had a 1, Rosemary had an 11, and Tim had a 2.\n\r\nFrom Sage's statement, he had to have an odd number. He knew that the sum of all three numbers was even, so if his number was odd, one of the other two numbers would have to be odd, and the other even, leaving them unequal.\n\r\nRosemary could deduce this, too, so when she saw an 11, she knew that Sage had a 1 and Tim had a 2. If she had seen a 12, she would have known that the other two boys each had a 1, which is contradicted by her saying that she already knew they all had different numbers. If she saw any number other than an 11 (say 9, for example), she would not have know which odd number Sage held. (In our example, he could have had a 1 and Tim a 4, or he could have had a 3 and Tim a 2).\n\r\nTim, understanding all of this, therefore knew their numbers.\n<|im_end|>" }, { "id": "#22572", "title": "I'm Getting Married in the Morning", "fun": 2.77, "difficulty": 0.84, "author": "MAroxmysoxonice", "desc": "There were four guys and four girls that were all friends. They each got married to one of their pals. The girls all wore different colored dresses and each couple had a different kind of cake that the husband smeared all over the wife.\n\r\nGuys: Brad, Joe, Zach, Matt\r\nGirls: Lisa, Mary, Kayla, Corinne\r\nDress Color: white, blue, cream, pink\r\nCake: marble, carrot, vanilla, chocolate\n\r\n1. Lisa's husband got cake all over her white dress.\n\r\n2. Kayla's cream dress was smeared with marble cake.\n\r\n3. Zach was driven nuts by his wife's blue dress.\n\r\n4. Joe loved Corinne dearly, but hated carrot cake and refused to have it at his wedding.\n\r\n5. The only thing that bothered Lisa about her love, Brad, was his obsession with vanilla cake.\n\r\n6. Mary's blue dress matched her eyes.", "hint": "Anyone who loves somebody or who has a \"love\" got married to them.", "answer": "Brad-Lisa-White-Vanilla\r\nJoe-Corinne-Pink-Chocolate\r\nZach-Mary-Blue-Carrot\r\nMatt-Kayla-Cream-Marble", "category": "Logic-Grid", "date": "04/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were four guys and four girls that were all friends. They each got married to one of their pals. The girls all wore different colored dresses and each couple had a different kind of cake that the husband smeared all over the wife.\n\r\nGuys: Brad, Joe, Zach, Matt\r\nGirls: Lisa, Mary, Kayla, Corinne\r\nDress Color: white, blue, cream, pink\r\nCake: marble, carrot, vanilla, chocolate\n\r\n1. Lisa's husband got cake all over her white dress.\n\r\n2. Kayla's cream dress was smeared with marble cake.\n\r\n3. Zach was driven nuts by his wife's blue dress.\n\r\n4. Joe loved Corinne dearly, but hated carrot cake and refused to have it at his wedding.\n\r\n5. The only thing that bothered Lisa about her love, Brad, was his obsession with vanilla cake.\n\r\n6. Mary's blue dress matched her eyes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrad-Lisa-White-Vanilla\r\nJoe-Corinne-Pink-Chocolate\r\nZach-Mary-Blue-Carrot\r\nMatt-Kayla-Cream-Marble\n<|im_start|>answer\nBrad-Lisa-White-Vanilla\r\nJoe-Corinne-Pink-Chocolate\r\nZach-Mary-Blue-Carrot\r\nMatt-Kayla-Cream-Marble\n<|im_end|>" }, { "id": "#21371", "title": "Hunt the Wumpus", "fun": 2.77, "difficulty": 2.31, "author": "iconofsin", "desc": "You are playing Hunt the Wumpus.\r\nIn this game, the goal is to kill a wumpus from an adjacent room (by shooting an arrow from an adjacent room). \n\r\nHowever, there are obstacles that will interfere with the player.\n\r\nThe first of these obstacles is a bottomless pit. There are two of them in the game (each room has a 10% chance of having a pit). Enter a room with a pit and you lose. When you are in a room adjacent to that of a room with a pit, a warning will come up saying \"You feel a draft\".\n\r\nThe second obstacle is bats. Bats are just like pits, except that bats will randomly take you to any of the 20 rooms (even if the room has a pit or a wumpus) However, I have not included bats in this teaser.\r\nEach room has 3 adjacent rooms.\n\r\nIn Room #7-- There is a draft. Exits are Room 6, Room 17, and Room 8.\n\r\nIn room #1--There is a draft. Exits are Room 5, Room 2, and Room 8\n\r\nIn room # 4-- There is a draft. Exits are Room 5, Room 6, and Room 14\n\r\nIn room #6-- There is a draft. Exits are Room 5, Room 7, and Room 16.\n\r\nIn room # 18-- There is a draft. Exits are Room 9, Room 17, and Room 16\n\r\nIn room #16-- There is a draft. Exits are Room 6, Room 17, and Room 18\n\r\nIn room #3-- A wumpus is in one of the adjacent rooms. Exits are Room 4, Room 2, and Room 13.\n\r\nIn room #5-- A wumpus is in one of the adjacent rooms. Exits are Room 4, Room 6, and Room 14.\n\r\nYour mission is as follows:\n\r\nA.Find out the two rooms that have pits.\n\r\nB.Find out what room the Wumpus is in.", "hint": "Each room that a draft could be felt from has only ONE room with a pit adjacent to that room.\n\r\nAnother clue is one of the rooms that I am giving a clue from (in room ??) has a pit in THAT room.", "answer": "The pits are in rooms 5 (yes one of the clues was in a pit room, but I, being the teaser creator have the power to fly in my imaginary teaser) and 17 and the wumpus is in room 4.", "category": "Logic", "date": "03/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are playing Hunt the Wumpus.\r\nIn this game, the goal is to kill a wumpus from an adjacent room (by shooting an arrow from an adjacent room). \n\r\nHowever, there are obstacles that will interfere with the player.\n\r\nThe first of these obstacles is a bottomless pit. There are two of them in the game (each room has a 10% chance of having a pit). Enter a room with a pit and you lose. When you are in a room adjacent to that of a room with a pit, a warning will come up saying \"You feel a draft\".\n\r\nThe second obstacle is bats. Bats are just like pits, except that bats will randomly take you to any of the 20 rooms (even if the room has a pit or a wumpus) However, I have not included bats in this teaser.\r\nEach room has 3 adjacent rooms.\n\r\nIn Room #7-- There is a draft. Exits are Room 6, Room 17, and Room 8.\n\r\nIn room #1--There is a draft. Exits are Room 5, Room 2, and Room 8\n\r\nIn room # 4-- There is a draft. Exits are Room 5, Room 6, and Room 14\n\r\nIn room #6-- There is a draft. Exits are Room 5, Room 7, and Room 16.\n\r\nIn room # 18-- There is a draft. Exits are Room 9, Room 17, and Room 16\n\r\nIn room #16-- There is a draft. Exits are Room 6, Room 17, and Room 18\n\r\nIn room #3-- A wumpus is in one of the adjacent rooms. Exits are Room 4, Room 2, and Room 13.\n\r\nIn room #5-- A wumpus is in one of the adjacent rooms. Exits are Room 4, Room 6, and Room 14.\n\r\nYour mission is as follows:\n\r\nA.Find out the two rooms that have pits.\n\r\nB.Find out what room the Wumpus is in.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pits are in rooms 5 (yes one of the clues was in a pit room, but I, being the teaser creator have the power to fly in my imaginary teaser) and 17 and the wumpus is in room 4.\n<|im_start|>answer\nThe pits are in rooms 5 (yes one of the clues was in a pit room, but I, being the teaser creator have the power to fly in my imaginary teaser) and 17 and the wumpus is in room 4.\n<|im_end|>" }, { "id": "#30618", "title": "Arithmetical Bedlam Conundrum", "fun": 2.77, "difficulty": 2.35, "author": "wizofaus", "desc": "You have the following equations:\n\r\na + c = a\r\nb - c = c\r\nc / b = c\r\na * a = b\n\r\nYou also know that a, b, c have the values 0, 1 and 2, but not necessarily in that order. \n\r\nBut to make matters more complicated the symbols + - * / have been mixed up: all you know is that each represents a different arithmetical operation (addition, subtraction, multiplication or division).\n\r\nCan you work out the values of a, b and c, and what each of the symbols actually mean?", "hint": "The only thing you should assume about the arithmetical symbols is that no two represent the same operation.", "answer": "a = 1\r\nb = 2\r\nc = 0\n\r\n+ = -\r\n- = * \r\n* = +\r\n/ = / \n\r\n(Yes, the division symbol escaped the bedlam!)", "category": "Logic", "date": "05/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have the following equations:\n\r\na + c = a\r\nb - c = c\r\nc / b = c\r\na * a = b\n\r\nYou also know that a, b, c have the values 0, 1 and 2, but not necessarily in that order. \n\r\nBut to make matters more complicated the symbols + - * / have been mixed up: all you know is that each represents a different arithmetical operation (addition, subtraction, multiplication or division).\n\r\nCan you work out the values of a, b and c, and what each of the symbols actually mean?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na = 1\r\nb = 2\r\nc = 0\n\r\n+ = -\r\n- = * \r\n* = +\r\n/ = / \n\r\n(Yes, the division symbol escaped the bedlam!)\n<|im_start|>answer\na = 1\r\nb = 2\r\nc = 0\n\r\n+ = -\r\n- = * \r\n* = +\r\n/ = / \n\r\n(Yes, the division symbol escaped the bedlam!)\n<|im_end|>" }, { "id": "#30719", "title": "Three Statements X", "fun": 2.77, "difficulty": 1.77, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. Using exactly three colors it is possible to color the sides of a cube in such a way that two sides having the same color never touch.\n\r\n2. A regular octagon can be divided into 8 identical triangles by drawing 4 straight lines.\n\r\n3. Three equally sized circles can be drawn in such a way that they overlap and create 9 separate compartments.", "hint": "No hint available.", "answer": "Statements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, use each color on each pair of opposite surfaces, and they do not touch.\n\r\nIn statement 2, connect each vertex with its opposite one, this will be 4 straight lines, and the octagon is divided into 8 identical triangles.\n\r\nIn statement 3, the first circle divides the plane into 2 parts, the second circle at most divides each of the 2 parts into two, making 4 parts, and the third circle at most divides each of the 4 parts into two, making 8 parts. It's impossible to get more than 8 parts.", "category": "Logic", "date": "05/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. Using exactly three colors it is possible to color the sides of a cube in such a way that two sides having the same color never touch.\n\r\n2. A regular octagon can be divided into 8 identical triangles by drawing 4 straight lines.\n\r\n3. Three equally sized circles can be drawn in such a way that they overlap and create 9 separate compartments.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, use each color on each pair of opposite surfaces, and they do not touch.\n\r\nIn statement 2, connect each vertex with its opposite one, this will be 4 straight lines, and the octagon is divided into 8 identical triangles.\n\r\nIn statement 3, the first circle divides the plane into 2 parts, the second circle at most divides each of the 2 parts into two, making 4 parts, and the third circle at most divides each of the 4 parts into two, making 8 parts. It's impossible to get more than 8 parts.\n<|im_start|>answer\nStatements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, use each color on each pair of opposite surfaces, and they do not touch.\n\r\nIn statement 2, connect each vertex with its opposite one, this will be 4 straight lines, and the octagon is divided into 8 identical triangles.\n\r\nIn statement 3, the first circle divides the plane into 2 parts, the second circle at most divides each of the 2 parts into two, making 4 parts, and the third circle at most divides each of the 4 parts into two, making 8 parts. It's impossible to get more than 8 parts.\n<|im_end|>" }, { "id": "#20263", "title": "Farm Animals!", "fun": 2.77, "difficulty": 1.74, "author": "eminemfreak69", "desc": "Your objective is to buy exactly 100 farm animals with exactly 100 dollars. You must buy at least 1 of each animal. You may need some paper!\n\r\nThe Costs:\r\nCows: $10 each\r\nPigs: $ 3 each\r\nChickens: $0.50 each", "hint": "There's a lot of chickens; over 85, but under 95.", "answer": "5 cows=$50\r\n1 pig=$3\r\n94 chickens=$47\r\n100 animals=100 dollars", "category": "Math", "date": "01/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour objective is to buy exactly 100 farm animals with exactly 100 dollars. You must buy at least 1 of each animal. You may need some paper!\n\r\nThe Costs:\r\nCows: $10 each\r\nPigs: $ 3 each\r\nChickens: $0.50 each\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 cows=$50\r\n1 pig=$3\r\n94 chickens=$47\r\n100 animals=100 dollars\n<|im_start|>answer\n5 cows=$50\r\n1 pig=$3\r\n94 chickens=$47\r\n100 animals=100 dollars\n<|im_end|>" }, { "id": "#7724", "title": "Stolen Candy Bar", "fun": 2.77, "difficulty": 2.31, "author": "datra16", "desc": "During lunch at school, a group of five boys from Miss Smith's home room visited a nearby canteen. One of the five boys took a candy bar without paying for it. When the boys were questioned by the school principal, they made the following statements in respective order:\n\r\n1. Chris: \"Neither Austin nor I did it.\"\n\r\n2. Kraig: \"It was Chris or Mark.\"\n\r\n3. Mark: \"Both Chris and Kraig are lying.\"\n\r\n4. Gavin: \"Between Chris and Kraig, one of them is lying and the other is speaking the truth.\"\n\r\n5. Austin: \"What Gavin said is wrong.\"\n\r\nWhen Miss Smith was consulted, she said, \"Three of these boys are always truthful, but everything that two of them say will be a lie.\" Assuming that Miss Smith is correct, can you determine who took the candy bar?", "hint": "Austin's statement is true.", "answer": "Mark took the candy bar. \n\r\nMark is the pivotal character here, since he is either referring to or being referred to by all of the other characters. Use trial and error to solve this: \n\r\nOption 1: \r\nMark: Telling the truth. This means: \r\nChris: Liar \r\nKraig: Liar \r\nGavin: Liar \r\nAustin: Truth. \r\nThese are the only possible outcomes if Mark tells the truth. Since the teacher said that there are three truth tellers, this solution doesn't work. Therefore, Mark must be a liar. \n\r\nOption 2: \r\nIf Mark is a liar, then there are three options for Chris and Craig: both are truth tellers, Chris lies and Kraig tells the truth, or Chris tells the truth and Kraig lies. If you set up a chart with these options, you can easily determine if Gavin and Austin are telling the truth, too: \n\r\nOption:..1...2...3 \r\nMark:....L...L...L \r\nChris:...T...L...T \r\nKraig:...T...T...L \r\nGavin:...L...T...T \r\nAustin:..T...L...L \n\r\nRead these from top to bottom: For example, option 1 is: If Mark lies and Chris and Kraig tell the truth, then Gavin must lie and Austin must tell the truth. Do the same for the other two columns. \n\r\nThe only option here that satisfies the three truth-teller rule is Option 1. Since Chris and Kraig both tell the truth, the thief must be Mark.", "category": "Logic", "date": "09/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring lunch at school, a group of five boys from Miss Smith's home room visited a nearby canteen. One of the five boys took a candy bar without paying for it. When the boys were questioned by the school principal, they made the following statements in respective order:\n\r\n1. Chris: \"Neither Austin nor I did it.\"\n\r\n2. Kraig: \"It was Chris or Mark.\"\n\r\n3. Mark: \"Both Chris and Kraig are lying.\"\n\r\n4. Gavin: \"Between Chris and Kraig, one of them is lying and the other is speaking the truth.\"\n\r\n5. Austin: \"What Gavin said is wrong.\"\n\r\nWhen Miss Smith was consulted, she said, \"Three of these boys are always truthful, but everything that two of them say will be a lie.\" Assuming that Miss Smith is correct, can you determine who took the candy bar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMark took the candy bar. \n\r\nMark is the pivotal character here, since he is either referring to or being referred to by all of the other characters. Use trial and error to solve this: \n\r\nOption 1: \r\nMark: Telling the truth. This means: \r\nChris: Liar \r\nKraig: Liar \r\nGavin: Liar \r\nAustin: Truth. \r\nThese are the only possible outcomes if Mark tells the truth. Since the teacher said that there are three truth tellers, this solution doesn't work. Therefore, Mark must be a liar. \n\r\nOption 2: \r\nIf Mark is a liar, then there are three options for Chris and Craig: both are truth tellers, Chris lies and Kraig tells the truth, or Chris tells the truth and Kraig lies. If you set up a chart with these options, you can easily determine if Gavin and Austin are telling the truth, too: \n\r\nOption:..1...2...3 \r\nMark:....L...L...L \r\nChris:...T...L...T \r\nKraig:...T...T...L \r\nGavin:...L...T...T \r\nAustin:..T...L...L \n\r\nRead these from top to bottom: For example, option 1 is: If Mark lies and Chris and Kraig tell the truth, then Gavin must lie and Austin must tell the truth. Do the same for the other two columns. \n\r\nThe only option here that satisfies the three truth-teller rule is Option 1. Since Chris and Kraig both tell the truth, the thief must be Mark.\n<|im_start|>answer\nMark took the candy bar. \n\r\nMark is the pivotal character here, since he is either referring to or being referred to by all of the other characters. Use trial and error to solve this: \n\r\nOption 1: \r\nMark: Telling the truth. This means: \r\nChris: Liar \r\nKraig: Liar \r\nGavin: Liar \r\nAustin: Truth. \r\nThese are the only possible outcomes if Mark tells the truth. Since the teacher said that there are three truth tellers, this solution doesn't work. Therefore, Mark must be a liar. \n\r\nOption 2: \r\nIf Mark is a liar, then there are three options for Chris and Craig: both are truth tellers, Chris lies and Kraig tells the truth, or Chris tells the truth and Kraig lies. If you set up a chart with these options, you can easily determine if Gavin and Austin are telling the truth, too: \n\r\nOption:..1...2...3 \r\nMark:....L...L...L \r\nChris:...T...L...T \r\nKraig:...T...T...L \r\nGavin:...L...T...T \r\nAustin:..T...L...L \n\r\nRead these from top to bottom: For example, option 1 is: If Mark lies and Chris and Kraig tell the truth, then Gavin must lie and Austin must tell the truth. Do the same for the other two columns. \n\r\nThe only option here that satisfies the three truth-teller rule is Option 1. Since Chris and Kraig both tell the truth, the thief must be Mark.\n<|im_end|>" }, { "id": "#49646", "title": "Alphabet Pyramids", "fun": 2.77, "difficulty": 3.0, "author": "Gizzer", "desc": "Did you know that the mango is one of the world's most popular fruits? The mango is grown in North, South and Central America, the Caribbean, south and central Africa, as well as its native southern and south-east Asia.\n\r\nThe mango is also packed with vitamins A, B and C.\n\r\nWhile eating a mango the other day, I started thinking about the ABC's. Then I remembered the set of 5-sided alphabet pyramids I had as a child. \n\r\nHere are some 5-letter words that can be spelled with just 5 of my pyramids:\n\r\nBELOW\r\nCANDY\r\nFORTY\r\nHELIX\r\nJABOT\r\nLEMON\r\nLIGHT\r\nMANGO\r\nOCHRE\r\nPEACH\r\nQUEST\r\nQUICK\r\nVIEUX\n\r\nUsing these words, can you figure out which letters appear on each pyramid?", "hint": "No hint available.", "answer": "Let's start with the word MANGO, and assign a number to each pyramid.\n\r\n1: M\r\n2: A\r\n3: N\r\n4: G\r\n5: O\n\r\nThe word LEMON shares 3 letters with MANGO, so the L and E must go with the A and G, in some order. Because of the word PEACH, the E and A cannot be on the same pyramid, so the E must be on pyramid 4, while the L is on pyramid 2.\n\r\nBecause of the word OCHRE, neither the C or H of PEACH can be on the same pyramid with the O, so the P must be on pyramid 5.\n\r\nBecause of the word CANDY, the C cannot be on the same pyramid as the N, so it is with the M, leaving the H with the N. The Y cannot be with the O (FORTY), so it must be with the G, and the D is with the O. The R must then be on pyramid 2, to complete OCHRE. \n\r\n1: M, C \r\n2: A, L, R \r\n3: N, H \r\n4: G, E, Y \r\n5: O, P, D\n\r\nThe F and T of FORTY must be on pyramids 1 and 3, but the H and T cannot be on the same pyramid (LIGHT), so the T is on pyramid 1 and the F is on pyramid 3. This means that the I must be on pyramid 5, in order to complete LIGHT. \n\r\n1: M, C, T \r\n2: A, L, R \r\n3: N, H, F \r\n4: G, E, Y \r\n5: O, P, D, I\n\r\nThe J and B of JABOT must be on pyramids 3 and 4, but the B cannot be with the E, or else one cannot spell BELOW. Also, the W must be on pyramid 1.\n\r\n1: M, C, T, W\r\n2: A, L, R\r\n3: N, H, F, B\r\n4: G, E, Y, J \r\n5: O, P, D, I \n\r\nThe X in HELIX must be on pyramid 1, so we now have all the letters on that pyramid. There is only one letter left on pyramid 3, and it must be in VIEUX, QUEST and QUICK, so it must be the U. The V from VIEUX must therefore be on pyramid 2. \n\r\nThe Q cannot be on the same pyramid as the I, in order to spell QUICK, so it is also on pyramid 2. The S cannot be on the same pyramid as the E (QUEST), so is therefore on pyramid 5, and the K is the last letter on pyramid 4. \n\r\n1: M, C, T, W, X \r\n2: A, L, R, V, Q \r\n3: N, H, F, B, U \r\n4: G, E, Y, J, K \r\n5: O, P, D, I, S", "category": "Logic", "date": "10/28/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDid you know that the mango is one of the world's most popular fruits? The mango is grown in North, South and Central America, the Caribbean, south and central Africa, as well as its native southern and south-east Asia.\n\r\nThe mango is also packed with vitamins A, B and C.\n\r\nWhile eating a mango the other day, I started thinking about the ABC's. Then I remembered the set of 5-sided alphabet pyramids I had as a child. \n\r\nHere are some 5-letter words that can be spelled with just 5 of my pyramids:\n\r\nBELOW\r\nCANDY\r\nFORTY\r\nHELIX\r\nJABOT\r\nLEMON\r\nLIGHT\r\nMANGO\r\nOCHRE\r\nPEACH\r\nQUEST\r\nQUICK\r\nVIEUX\n\r\nUsing these words, can you figure out which letters appear on each pyramid?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet's start with the word MANGO, and assign a number to each pyramid.\n\r\n1: M\r\n2: A\r\n3: N\r\n4: G\r\n5: O\n\r\nThe word LEMON shares 3 letters with MANGO, so the L and E must go with the A and G, in some order. Because of the word PEACH, the E and A cannot be on the same pyramid, so the E must be on pyramid 4, while the L is on pyramid 2.\n\r\nBecause of the word OCHRE, neither the C or H of PEACH can be on the same pyramid with the O, so the P must be on pyramid 5.\n\r\nBecause of the word CANDY, the C cannot be on the same pyramid as the N, so it is with the M, leaving the H with the N. The Y cannot be with the O (FORTY), so it must be with the G, and the D is with the O. The R must then be on pyramid 2, to complete OCHRE. \n\r\n1: M, C \r\n2: A, L, R \r\n3: N, H \r\n4: G, E, Y \r\n5: O, P, D\n\r\nThe F and T of FORTY must be on pyramids 1 and 3, but the H and T cannot be on the same pyramid (LIGHT), so the T is on pyramid 1 and the F is on pyramid 3. This means that the I must be on pyramid 5, in order to complete LIGHT. \n\r\n1: M, C, T \r\n2: A, L, R \r\n3: N, H, F \r\n4: G, E, Y \r\n5: O, P, D, I\n\r\nThe J and B of JABOT must be on pyramids 3 and 4, but the B cannot be with the E, or else one cannot spell BELOW. Also, the W must be on pyramid 1.\n\r\n1: M, C, T, W\r\n2: A, L, R\r\n3: N, H, F, B\r\n4: G, E, Y, J \r\n5: O, P, D, I \n\r\nThe X in HELIX must be on pyramid 1, so we now have all the letters on that pyramid. There is only one letter left on pyramid 3, and it must be in VIEUX, QUEST and QUICK, so it must be the U. The V from VIEUX must therefore be on pyramid 2. \n\r\nThe Q cannot be on the same pyramid as the I, in order to spell QUICK, so it is also on pyramid 2. The S cannot be on the same pyramid as the E (QUEST), so is therefore on pyramid 5, and the K is the last letter on pyramid 4. \n\r\n1: M, C, T, W, X \r\n2: A, L, R, V, Q \r\n3: N, H, F, B, U \r\n4: G, E, Y, J, K \r\n5: O, P, D, I, S\n<|im_start|>answer\nLet's start with the word MANGO, and assign a number to each pyramid.\n\r\n1: M\r\n2: A\r\n3: N\r\n4: G\r\n5: O\n\r\nThe word LEMON shares 3 letters with MANGO, so the L and E must go with the A and G, in some order. Because of the word PEACH, the E and A cannot be on the same pyramid, so the E must be on pyramid 4, while the L is on pyramid 2.\n\r\nBecause of the word OCHRE, neither the C or H of PEACH can be on the same pyramid with the O, so the P must be on pyramid 5.\n\r\nBecause of the word CANDY, the C cannot be on the same pyramid as the N, so it is with the M, leaving the H with the N. The Y cannot be with the O (FORTY), so it must be with the G, and the D is with the O. The R must then be on pyramid 2, to complete OCHRE. \n\r\n1: M, C \r\n2: A, L, R \r\n3: N, H \r\n4: G, E, Y \r\n5: O, P, D\n\r\nThe F and T of FORTY must be on pyramids 1 and 3, but the H and T cannot be on the same pyramid (LIGHT), so the T is on pyramid 1 and the F is on pyramid 3. This means that the I must be on pyramid 5, in order to complete LIGHT. \n\r\n1: M, C, T \r\n2: A, L, R \r\n3: N, H, F \r\n4: G, E, Y \r\n5: O, P, D, I\n\r\nThe J and B of JABOT must be on pyramids 3 and 4, but the B cannot be with the E, or else one cannot spell BELOW. Also, the W must be on pyramid 1.\n\r\n1: M, C, T, W\r\n2: A, L, R\r\n3: N, H, F, B\r\n4: G, E, Y, J \r\n5: O, P, D, I \n\r\nThe X in HELIX must be on pyramid 1, so we now have all the letters on that pyramid. There is only one letter left on pyramid 3, and it must be in VIEUX, QUEST and QUICK, so it must be the U. The V from VIEUX must therefore be on pyramid 2. \n\r\nThe Q cannot be on the same pyramid as the I, in order to spell QUICK, so it is also on pyramid 2. The S cannot be on the same pyramid as the E (QUEST), so is therefore on pyramid 5, and the K is the last letter on pyramid 4. \n\r\n1: M, C, T, W, X \r\n2: A, L, R, V, Q \r\n3: N, H, F, B, U \r\n4: G, E, Y, J, K \r\n5: O, P, D, I, S\n<|im_end|>" }, { "id": "#29366", "title": "Hi Dude", "fun": 2.77, "difficulty": 2.82, "author": "Freaks", "desc": "If 125207 is \"Hi\", and 031993121212 is \"Dude\", then 125207031993121212 is \"Hi Dude\".\n\r\nThen what is 799717777010909230151693122001983?", "hint": "No hint available.", "answer": "It's \"You Are Great\". \n\r\nSeparate the numbers into groups of three, and then add up the three numbers. The total amount will point to a certain letter, and if you continue doing it until all numbers are used, it'll form the sentence \"You Are Great\".", "category": "Math", "date": "03/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 125207 is \"Hi\", and 031993121212 is \"Dude\", then 125207031993121212 is \"Hi Dude\".\n\r\nThen what is 799717777010909230151693122001983?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's \"You Are Great\". \n\r\nSeparate the numbers into groups of three, and then add up the three numbers. The total amount will point to a certain letter, and if you continue doing it until all numbers are used, it'll form the sentence \"You Are Great\".\n<|im_start|>answer\nIt's \"You Are Great\". \n\r\nSeparate the numbers into groups of three, and then add up the three numbers. The total amount will point to a certain letter, and if you continue doing it until all numbers are used, it'll form the sentence \"You Are Great\".\n<|im_end|>" }, { "id": "#36979", "title": "Military Fun", "fun": 2.77, "difficulty": 2.13, "author": "soccerguy0428", "desc": "One day 7 friends, Stephen, Felicia, Anna, Clark, Brad, Abby, and Jessica, decided that they wanted to pretend they were in a war. So, Stephen went to his older brother, and his brother said that you need to be ranked in an army before you go into battle. So, for the next week the brother set up obstacles that the kids had to do and moved them up or down in rank depending on how well they did. Here is the list of ranks that the brother came up with:\n\r\nRanks\r\n1. Lieutenant General\r\n2. Brigadier General\r\n3. Colonel\r\n4. Lieutenant Colonel\r\n5. Major\r\n6. Captain\r\n7. First Lieutenant\r\n8. Second Lieutenant\r\n9. First Sergeant\r\n10. Sergeant\r\n11. Corporal\r\n12. Private\n\r\nCan you figure out how high each of the 7 friends is ranked if they all started out as a Private with these clues?\n\r\nDay 1\r\nBrad is promoted by 1, Abby doubled that, Felicia doubled Abby's promotion, and Stephen doubled Felicia's promotion.\n\r\nDay 2\r\nJessica is moved to First Sergeant, Anna is moved 2 above that, and Clark is moved 4 below Anna.\n\r\nDay 3\r\nStephen and Anna are both promoted by 2, Clark is promoted by 1, and Jessica is demoted by 1.\n\r\nDay 4\r\nAbby is demoted by 1, Jessica is moved to the lowest rank, and Felicia is moved to Captain.\n\r\nDay 5\r\nEveryone who had been promoted on Day 1 is moved up by 1.\n\r\nDay 6\r\nAnna moves up by 2, Clark moves up by 4, and Jessica moves up by 1.\n\r\nDay 7\r\nNo promotions or demotions.\n\r\nDo you know the order of how high the 7 friends are ranked in their play army?", "hint": "No hint available.", "answer": "On Day 1 we know that Brad is moved up to Corporal; Abby doubled that, so she moved up by 2. So, she is now a Sergeant. Felicia doubled Abby's promotion, so she is moved up to Second Lieutenant. Stephen is moved up by 8, a Lieutenant Colonel.\n\r\nThen on Day 2, it says that Jessica is moved to First Sergeant, and Anna moved 2 higher than that, a First Lieutenant, and Clark is moved 4 below Anna to Corporal.\n\r\nOn Day 3 Stephen is moved up to Brigadier General and Anna to Major. Clark is moved to Sergeant, and Jessica is moved down one to Sergeant.\n\r\nDay 4, Abby is moved down to Corporal, Jessica is moved down to Private, and Felicia goes up to Captain.\n\r\nDay 5, everyone who had been promoted on Day 1 is moved up, and that's Stephen, Felicia, Abby, and Brad. Stephen is now Lieutenant General, Felicia is a Major, Abby is a Sergeant, and Brad is a Sergeant.\n\r\nDay 6, Anna is moved up to Colonel, Clark is moved to Captain, and Jessica is moved to Corporal.\n\r\nThe order of the 7 friends at the end are:\r\n1. Lieutenant General Stephen\r\n2. Colonel Anna\r\n3. Major Felicia\r\n4. Captain Clark\r\n5. Sergeant Abby\r\n5. Sergeant Brad\r\n7. Corporal Jessica", "category": "Logic", "date": "06/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day 7 friends, Stephen, Felicia, Anna, Clark, Brad, Abby, and Jessica, decided that they wanted to pretend they were in a war. So, Stephen went to his older brother, and his brother said that you need to be ranked in an army before you go into battle. So, for the next week the brother set up obstacles that the kids had to do and moved them up or down in rank depending on how well they did. Here is the list of ranks that the brother came up with:\n\r\nRanks\r\n1. Lieutenant General\r\n2. Brigadier General\r\n3. Colonel\r\n4. Lieutenant Colonel\r\n5. Major\r\n6. Captain\r\n7. First Lieutenant\r\n8. Second Lieutenant\r\n9. First Sergeant\r\n10. Sergeant\r\n11. Corporal\r\n12. Private\n\r\nCan you figure out how high each of the 7 friends is ranked if they all started out as a Private with these clues?\n\r\nDay 1\r\nBrad is promoted by 1, Abby doubled that, Felicia doubled Abby's promotion, and Stephen doubled Felicia's promotion.\n\r\nDay 2\r\nJessica is moved to First Sergeant, Anna is moved 2 above that, and Clark is moved 4 below Anna.\n\r\nDay 3\r\nStephen and Anna are both promoted by 2, Clark is promoted by 1, and Jessica is demoted by 1.\n\r\nDay 4\r\nAbby is demoted by 1, Jessica is moved to the lowest rank, and Felicia is moved to Captain.\n\r\nDay 5\r\nEveryone who had been promoted on Day 1 is moved up by 1.\n\r\nDay 6\r\nAnna moves up by 2, Clark moves up by 4, and Jessica moves up by 1.\n\r\nDay 7\r\nNo promotions or demotions.\n\r\nDo you know the order of how high the 7 friends are ranked in their play army?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn Day 1 we know that Brad is moved up to Corporal; Abby doubled that, so she moved up by 2. So, she is now a Sergeant. Felicia doubled Abby's promotion, so she is moved up to Second Lieutenant. Stephen is moved up by 8, a Lieutenant Colonel.\n\r\nThen on Day 2, it says that Jessica is moved to First Sergeant, and Anna moved 2 higher than that, a First Lieutenant, and Clark is moved 4 below Anna to Corporal.\n\r\nOn Day 3 Stephen is moved up to Brigadier General and Anna to Major. Clark is moved to Sergeant, and Jessica is moved down one to Sergeant.\n\r\nDay 4, Abby is moved down to Corporal, Jessica is moved down to Private, and Felicia goes up to Captain.\n\r\nDay 5, everyone who had been promoted on Day 1 is moved up, and that's Stephen, Felicia, Abby, and Brad. Stephen is now Lieutenant General, Felicia is a Major, Abby is a Sergeant, and Brad is a Sergeant.\n\r\nDay 6, Anna is moved up to Colonel, Clark is moved to Captain, and Jessica is moved to Corporal.\n\r\nThe order of the 7 friends at the end are:\r\n1. Lieutenant General Stephen\r\n2. Colonel Anna\r\n3. Major Felicia\r\n4. Captain Clark\r\n5. Sergeant Abby\r\n5. Sergeant Brad\r\n7. Corporal Jessica\n<|im_start|>answer\nOn Day 1 we know that Brad is moved up to Corporal; Abby doubled that, so she moved up by 2. So, she is now a Sergeant. Felicia doubled Abby's promotion, so she is moved up to Second Lieutenant. Stephen is moved up by 8, a Lieutenant Colonel.\n\r\nThen on Day 2, it says that Jessica is moved to First Sergeant, and Anna moved 2 higher than that, a First Lieutenant, and Clark is moved 4 below Anna to Corporal.\n\r\nOn Day 3 Stephen is moved up to Brigadier General and Anna to Major. Clark is moved to Sergeant, and Jessica is moved down one to Sergeant.\n\r\nDay 4, Abby is moved down to Corporal, Jessica is moved down to Private, and Felicia goes up to Captain.\n\r\nDay 5, everyone who had been promoted on Day 1 is moved up, and that's Stephen, Felicia, Abby, and Brad. Stephen is now Lieutenant General, Felicia is a Major, Abby is a Sergeant, and Brad is a Sergeant.\n\r\nDay 6, Anna is moved up to Colonel, Clark is moved to Captain, and Jessica is moved to Corporal.\n\r\nThe order of the 7 friends at the end are:\r\n1. Lieutenant General Stephen\r\n2. Colonel Anna\r\n3. Major Felicia\r\n4. Captain Clark\r\n5. Sergeant Abby\r\n5. Sergeant Brad\r\n7. Corporal Jessica\n<|im_end|>" }, { "id": "#32441", "title": "Yellow Birds", "fun": 2.77, "difficulty": 2.14, "author": "Tammy93", "desc": "Abel, Mabel, and Caleb went bird watching. Each of them saw one bird that none of the others did. Each pair saw one bird that the third did not. And one bird was seen by all three. Of the birds Abel saw, two were yellow. Of the birds Mabel saw, three were yellow. Of the birds Caleb saw, four were yellow. How many yellow birds were seen in all? How many non-yellow birds were seen in all?", "hint": "No hint available.", "answer": "Three birds were seen by one person each, three were seen by each unique pair (Abel-Mabel, Abel-Caleb, and Mabel-Caleb), and one was seen by all three. So seven birds were seen in all, and each person saw a total of four. Hence, all of the birds Caleb saw were yellow. These four birds are: (1) the one Caleb saw alone, (2) the one Caleb saw with Abel, (3) the one Caleb saw with Mabel, and (4) the one all three saw together. This accounts for both of the yellow birds Abel saw, and two of the three yellow birds Mabel saw. The third yellow bird Mabel saw could not have been the one Abel and Mabel saw together, because Abel only saw two yellow birds; so the third yellow bird Mabel saw must have been the one she saw alone.\n\r\nSo five yellow birds were seen (the one Mabel saw, the one Caleb saw, the one Abel and Caleb saw, the one Mabel and Caleb saw, and the one all three saw), and two non-yellow birds were seen (the one Abel saw and the one Abel and Mabel saw) by the group.", "category": "Logic", "date": "08/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbel, Mabel, and Caleb went bird watching. Each of them saw one bird that none of the others did. Each pair saw one bird that the third did not. And one bird was seen by all three. Of the birds Abel saw, two were yellow. Of the birds Mabel saw, three were yellow. Of the birds Caleb saw, four were yellow. How many yellow birds were seen in all? How many non-yellow birds were seen in all?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree birds were seen by one person each, three were seen by each unique pair (Abel-Mabel, Abel-Caleb, and Mabel-Caleb), and one was seen by all three. So seven birds were seen in all, and each person saw a total of four. Hence, all of the birds Caleb saw were yellow. These four birds are: (1) the one Caleb saw alone, (2) the one Caleb saw with Abel, (3) the one Caleb saw with Mabel, and (4) the one all three saw together. This accounts for both of the yellow birds Abel saw, and two of the three yellow birds Mabel saw. The third yellow bird Mabel saw could not have been the one Abel and Mabel saw together, because Abel only saw two yellow birds; so the third yellow bird Mabel saw must have been the one she saw alone.\n\r\nSo five yellow birds were seen (the one Mabel saw, the one Caleb saw, the one Abel and Caleb saw, the one Mabel and Caleb saw, and the one all three saw), and two non-yellow birds were seen (the one Abel saw and the one Abel and Mabel saw) by the group.\n<|im_start|>answer\nThree birds were seen by one person each, three were seen by each unique pair (Abel-Mabel, Abel-Caleb, and Mabel-Caleb), and one was seen by all three. So seven birds were seen in all, and each person saw a total of four. Hence, all of the birds Caleb saw were yellow. These four birds are: (1) the one Caleb saw alone, (2) the one Caleb saw with Abel, (3) the one Caleb saw with Mabel, and (4) the one all three saw together. This accounts for both of the yellow birds Abel saw, and two of the three yellow birds Mabel saw. The third yellow bird Mabel saw could not have been the one Abel and Mabel saw together, because Abel only saw two yellow birds; so the third yellow bird Mabel saw must have been the one she saw alone.\n\r\nSo five yellow birds were seen (the one Mabel saw, the one Caleb saw, the one Abel and Caleb saw, the one Mabel and Caleb saw, and the one all three saw), and two non-yellow birds were seen (the one Abel saw and the one Abel and Mabel saw) by the group.\n<|im_end|>" }, { "id": "#34548", "title": "The Winning Combination 2", "fun": 2.77, "difficulty": 2.46, "author": "grungy49", "desc": "You are back on the same game show with four other contestants. You didn't realise last time that the winner gets another appearance on the show! You now have another chance to win half a million dollars and become a millionaire! The objective is to crack the combination of the safe using the clues. The first person to do so will win $500,000.\n\r\nThe safe combination looks like this:\n\r\n??-??-??-??\n\r\nA digit can be used more than once in the code, and there are no zeroes.\n\r\nHere are the clues:\n\r\n1. When adding the first number of the third set with the second number of the second set, you will get a number below 8.\n\r\n2. The only digits not used in the code are 5 and 7.\n\r\n3. When adding the two digits of the first set together, you will not get 10.\n\r\n4. If you multiply the second set by 4, you will get the fourth set reversed.\n\r\n5. No set has a number above 90.\n\r\n6. The product of both the digits in the first set is below 30 but above 20.\n\r\n7. One of the number sets is 66.\n\r\n8. There is only one 8 in the combination, and it is in the last set.\n\r\nNow, get cracking!\n\r\nWarning: Hint shows which set the 66 is in.", "hint": "??-??-66-??", "answer": "The set is 39-21-66-48.\n\r\nFirst of all, the second clue tells you there are no 5's or 7's in the combination.\n\r\nNow we go to the fourth clue. It tells you that if you multiply the second set by 4, you will get the fourth set reversed. There are only a few numbers that will satisfy this:\n\r\n11, 12, 16, 21, 22, 23 and 24.\n\r\nNow we skip down to clue 8, which tells us there is one 8 only, and it is in the last set. It could either be the first digit or the second digit.\n\r\nHowever, this eliminates these numbers from being in the second set: 11, 16, 23 and 24. Now, only 12, 21 and 22 are the possibilities for being in the second set.\n\r\nNow, let's look at clue 7. This tells us that 66 is one of the four number sets. We know it can't be in the second, or fourth, and since clue six tells us the product of the two numbers in the first set ranges from 21-29, 66 must go in the third set.\n\r\n??-??-66-??\n\r\nNow we must look at the first clue. The first number of the third set (6) plus the second number of the second set will get a number below 8. This means it cannot be 12 or 22, because they would both total 8. This means that the second set of numbers is 21. Making good progress!\n\r\n??-21-66-??\n\r\nNow, we come back to clue 4 which tells us the second set multiplied by 4 equals the fourth set reversed. 21 multiplied by 4 is 84, which when reversed is 48!\n\r\n??-21-66-48\n\r\nNow, we come back to clue 6, which tells us the product of the digits in the first set is above 20 but below 30. These are the only numbers that satisfy that condition - and remember, no 5's, 7's or 8's are left in the combination:\n\r\n39 (3 * 9 = 27)\r\n46 (4 * 6 = 24)\r\n64 (6 * 4 = 24)\r\n93 (9 * 3 = 27)\n\r\nNow, we look at clue 5. This eliminates 93. Now, come to clue 3. This tells us the sum of the two digits in the first set does not equal 10. This eliminates 46 and 64. The only number left is.... 39!\n\r\nNow you have your answer;\n\r\n39-21-66-48\n\r\nCongratulations!!! You won, again!! You are over the moon! You have become the first millionaire in five generations of your family history!!", "category": "Logic", "date": "12/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are back on the same game show with four other contestants. You didn't realise last time that the winner gets another appearance on the show! You now have another chance to win half a million dollars and become a millionaire! The objective is to crack the combination of the safe using the clues. The first person to do so will win $500,000.\n\r\nThe safe combination looks like this:\n\r\n??-??-??-??\n\r\nA digit can be used more than once in the code, and there are no zeroes.\n\r\nHere are the clues:\n\r\n1. When adding the first number of the third set with the second number of the second set, you will get a number below 8.\n\r\n2. The only digits not used in the code are 5 and 7.\n\r\n3. When adding the two digits of the first set together, you will not get 10.\n\r\n4. If you multiply the second set by 4, you will get the fourth set reversed.\n\r\n5. No set has a number above 90.\n\r\n6. The product of both the digits in the first set is below 30 but above 20.\n\r\n7. One of the number sets is 66.\n\r\n8. There is only one 8 in the combination, and it is in the last set.\n\r\nNow, get cracking!\n\r\nWarning: Hint shows which set the 66 is in.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe set is 39-21-66-48.\n\r\nFirst of all, the second clue tells you there are no 5's or 7's in the combination.\n\r\nNow we go to the fourth clue. It tells you that if you multiply the second set by 4, you will get the fourth set reversed. There are only a few numbers that will satisfy this:\n\r\n11, 12, 16, 21, 22, 23 and 24.\n\r\nNow we skip down to clue 8, which tells us there is one 8 only, and it is in the last set. It could either be the first digit or the second digit.\n\r\nHowever, this eliminates these numbers from being in the second set: 11, 16, 23 and 24. Now, only 12, 21 and 22 are the possibilities for being in the second set.\n\r\nNow, let's look at clue 7. This tells us that 66 is one of the four number sets. We know it can't be in the second, or fourth, and since clue six tells us the product of the two numbers in the first set ranges from 21-29, 66 must go in the third set.\n\r\n??-??-66-??\n\r\nNow we must look at the first clue. The first number of the third set (6) plus the second number of the second set will get a number below 8. This means it cannot be 12 or 22, because they would both total 8. This means that the second set of numbers is 21. Making good progress!\n\r\n??-21-66-??\n\r\nNow, we come back to clue 4 which tells us the second set multiplied by 4 equals the fourth set reversed. 21 multiplied by 4 is 84, which when reversed is 48!\n\r\n??-21-66-48\n\r\nNow, we come back to clue 6, which tells us the product of the digits in the first set is above 20 but below 30. These are the only numbers that satisfy that condition - and remember, no 5's, 7's or 8's are left in the combination:\n\r\n39 (3 * 9 = 27)\r\n46 (4 * 6 = 24)\r\n64 (6 * 4 = 24)\r\n93 (9 * 3 = 27)\n\r\nNow, we look at clue 5. This eliminates 93. Now, come to clue 3. This tells us the sum of the two digits in the first set does not equal 10. This eliminates 46 and 64. The only number left is.... 39!\n\r\nNow you have your answer;\n\r\n39-21-66-48\n\r\nCongratulations!!! You won, again!! You are over the moon! You have become the first millionaire in five generations of your family history!!\n<|im_start|>answer\nThe set is 39-21-66-48.\n\r\nFirst of all, the second clue tells you there are no 5's or 7's in the combination.\n\r\nNow we go to the fourth clue. It tells you that if you multiply the second set by 4, you will get the fourth set reversed. There are only a few numbers that will satisfy this:\n\r\n11, 12, 16, 21, 22, 23 and 24.\n\r\nNow we skip down to clue 8, which tells us there is one 8 only, and it is in the last set. It could either be the first digit or the second digit.\n\r\nHowever, this eliminates these numbers from being in the second set: 11, 16, 23 and 24. Now, only 12, 21 and 22 are the possibilities for being in the second set.\n\r\nNow, let's look at clue 7. This tells us that 66 is one of the four number sets. We know it can't be in the second, or fourth, and since clue six tells us the product of the two numbers in the first set ranges from 21-29, 66 must go in the third set.\n\r\n??-??-66-??\n\r\nNow we must look at the first clue. The first number of the third set (6) plus the second number of the second set will get a number below 8. This means it cannot be 12 or 22, because they would both total 8. This means that the second set of numbers is 21. Making good progress!\n\r\n??-21-66-??\n\r\nNow, we come back to clue 4 which tells us the second set multiplied by 4 equals the fourth set reversed. 21 multiplied by 4 is 84, which when reversed is 48!\n\r\n??-21-66-48\n\r\nNow, we come back to clue 6, which tells us the product of the digits in the first set is above 20 but below 30. These are the only numbers that satisfy that condition - and remember, no 5's, 7's or 8's are left in the combination:\n\r\n39 (3 * 9 = 27)\r\n46 (4 * 6 = 24)\r\n64 (6 * 4 = 24)\r\n93 (9 * 3 = 27)\n\r\nNow, we look at clue 5. This eliminates 93. Now, come to clue 3. This tells us the sum of the two digits in the first set does not equal 10. This eliminates 46 and 64. The only number left is.... 39!\n\r\nNow you have your answer;\n\r\n39-21-66-48\n\r\nCongratulations!!! You won, again!! You are over the moon! You have become the first millionaire in five generations of your family history!!\n<|im_end|>" }, { "id": "#29264", "title": "Bookmark", "fun": 2.77, "difficulty": 1.26, "author": "MarcM1098", "desc": "A man is reading a wonderful book but must put it down. He desperately wants a bookmark so that he doesn't lose his place (he is not willing to dog-ear the page). When he is offered a fine bookmark for only a dollar, he agrees. However, he then smiles and refuses the bookmark. Why?", "hint": "He already has a better alternative.", "answer": "As he is paying, he realizes the dollar bill itself can be used as a bookmark. When he is done reading the book, he can then spend the money on something else.", "category": "Logic", "date": "03/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is reading a wonderful book but must put it down. He desperately wants a bookmark so that he doesn't lose his place (he is not willing to dog-ear the page). When he is offered a fine bookmark for only a dollar, he agrees. However, he then smiles and refuses the bookmark. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAs he is paying, he realizes the dollar bill itself can be used as a bookmark. When he is done reading the book, he can then spend the money on something else.\n<|im_start|>answer\nAs he is paying, he realizes the dollar bill itself can be used as a bookmark. When he is done reading the book, he can then spend the money on something else.\n<|im_end|>" }, { "id": "#12788", "title": "What is the 10 Digit Number?", "fun": 2.77, "difficulty": 2.65, "author": "ejasami", "desc": "There's a certain 10-digit number where that the first digit is equal to the number of zeros in the entire number, the second number is the number of 1's in the entire number, the third number is the number of 2's in the entire number, and so on, to where the 10th digit is the number of 9's in the entire number. \n\r\nWhat is the number?", "hint": "No hint available.", "answer": "6210001000 \n\r\nThere are 6 zeros, 2 ones, 1 two, 0 threes, 0 fours, 0 fives, 1 six, 0 sevens, 0 eights, and 0 nines.", "category": "Logic", "date": "05/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere's a certain 10-digit number where that the first digit is equal to the number of zeros in the entire number, the second number is the number of 1's in the entire number, the third number is the number of 2's in the entire number, and so on, to where the 10th digit is the number of 9's in the entire number. \n\r\nWhat is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6210001000 \n\r\nThere are 6 zeros, 2 ones, 1 two, 0 threes, 0 fours, 0 fives, 1 six, 0 sevens, 0 eights, and 0 nines.\n<|im_start|>answer\n6210001000 \n\r\nThere are 6 zeros, 2 ones, 1 two, 0 threes, 0 fours, 0 fives, 1 six, 0 sevens, 0 eights, and 0 nines.\n<|im_end|>" }, { "id": "#14219", "title": "Same Room Different Place", "fun": 2.77, "difficulty": 1.24, "author": "luvupurple", "desc": "A man walks into a room, turns around and walks out the same door he went in. When he gets out he is in a different room than when he started. How is this possible?", "hint": "No hint available.", "answer": "He walks into an elevator.", "category": "Logic", "date": "08/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man walks into a room, turns around and walks out the same door he went in. When he gets out he is in a different room than when he started. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe walks into an elevator.\n<|im_start|>answer\nHe walks into an elevator.\n<|im_end|>" }, { "id": "#52438", "title": "Logitopia 2", "fun": 2.77, "difficulty": 1.68, "author": "wimpykidfan37", "desc": "Lisa, Martha, Nora, and Ophelia live in the strange country of Logitopia. This country is inhabited by four races of people: the type A people and type B people who always tell the truth, and the type C people and type D people who always lie. Each of them is of a different race.\n\r\nLisa says, \"Martha is a type A person.\" Martha says, \"Nora is a type C person.\" Nora says, \"Ophelia is a type D person.\" Ophelia says, \"Lisa is NOT a type B person.\"\n\r\nWho is which race?", "hint": "No hint available.", "answer": "Lisa is a type D person, Martha is a type B person, Nora is a type C person, and Ophelia is a type A person.\n\r\nSuppose Lisa is a truthteller. This means that Martha is a type A person, which means that Nora is a type C person. Since Lisa is a truthteller who is not a type A person, she is a type B person, which means Ophelia is lying. Since Ophelia is a liar who is not a type C person, she must be a type D person. But since Nora is a type C person, Ophelia cannot be a type D person. So this cannot work.\n\r\nThis means that Lisa is a liar and cannot be a type B person, which means that Ophelia is telling the truth and cannot be a type D person, which means that Nora is lying. Since Lisa and Nora are both lying, Martha and Ophelia must be the two truthtellers, which means that Nora is a type C person and Lisa is a type D person. Since Lisa is lying, Martha cannot be a type A person and must be a type B person, and Ophelia must be a type A person.", "category": "Logic", "date": "08/14/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLisa, Martha, Nora, and Ophelia live in the strange country of Logitopia. This country is inhabited by four races of people: the type A people and type B people who always tell the truth, and the type C people and type D people who always lie. Each of them is of a different race.\n\r\nLisa says, \"Martha is a type A person.\" Martha says, \"Nora is a type C person.\" Nora says, \"Ophelia is a type D person.\" Ophelia says, \"Lisa is NOT a type B person.\"\n\r\nWho is which race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLisa is a type D person, Martha is a type B person, Nora is a type C person, and Ophelia is a type A person.\n\r\nSuppose Lisa is a truthteller. This means that Martha is a type A person, which means that Nora is a type C person. Since Lisa is a truthteller who is not a type A person, she is a type B person, which means Ophelia is lying. Since Ophelia is a liar who is not a type C person, she must be a type D person. But since Nora is a type C person, Ophelia cannot be a type D person. So this cannot work.\n\r\nThis means that Lisa is a liar and cannot be a type B person, which means that Ophelia is telling the truth and cannot be a type D person, which means that Nora is lying. Since Lisa and Nora are both lying, Martha and Ophelia must be the two truthtellers, which means that Nora is a type C person and Lisa is a type D person. Since Lisa is lying, Martha cannot be a type A person and must be a type B person, and Ophelia must be a type A person.\n<|im_start|>answer\nLisa is a type D person, Martha is a type B person, Nora is a type C person, and Ophelia is a type A person.\n\r\nSuppose Lisa is a truthteller. This means that Martha is a type A person, which means that Nora is a type C person. Since Lisa is a truthteller who is not a type A person, she is a type B person, which means Ophelia is lying. Since Ophelia is a liar who is not a type C person, she must be a type D person. But since Nora is a type C person, Ophelia cannot be a type D person. So this cannot work.\n\r\nThis means that Lisa is a liar and cannot be a type B person, which means that Ophelia is telling the truth and cannot be a type D person, which means that Nora is lying. Since Lisa and Nora are both lying, Martha and Ophelia must be the two truthtellers, which means that Nora is a type C person and Lisa is a type D person. Since Lisa is lying, Martha cannot be a type A person and must be a type B person, and Ophelia must be a type A person.\n<|im_end|>" }, { "id": "#21535", "title": "A Day at the Olympia Raceway", "fun": 2.7600000000000002, "difficulty": 1.6400000000000001, "author": "2wheelspeedster", "desc": "Here we are folks, at the Olympia raceway on the biggest race day of the year! Before we get started, let me tell you a little about each racer. Crystal has kept her bike the color that the company is famous for, which isn't black. Green is the color that Kawasaki is known for. It is surprising the place that Crystal took since she has the least experience. Jeremy took last place on his red bike because he doesn't have the most experience. Rob is the most experienced racer, and his bike is green. The 2nd place Suzuki, that is not green, is ridden by the only girl racer. The 'GO' color also means not third. The person with the red bike has the least experience of the three boys. Two of the racers have bike names that start with the last letter in their first name. Now that you know who is who, let's get racing!!", "hint": "No hint available.", "answer": "Rob - Kawasaki - Green - 1st place - 16 years; \r\nCrystal - Suzuki - Blue - 2nd place - 3 years; \r\nJeremy - Yamaha - Red - 4th place - 6 years; \r\nRobert - Triumph - Black - 3rd place - 12 years", "category": "Logic-Grid", "date": "03/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHere we are folks, at the Olympia raceway on the biggest race day of the year! Before we get started, let me tell you a little about each racer. Crystal has kept her bike the color that the company is famous for, which isn't black. Green is the color that Kawasaki is known for. It is surprising the place that Crystal took since she has the least experience. Jeremy took last place on his red bike because he doesn't have the most experience. Rob is the most experienced racer, and his bike is green. The 2nd place Suzuki, that is not green, is ridden by the only girl racer. The 'GO' color also means not third. The person with the red bike has the least experience of the three boys. Two of the racers have bike names that start with the last letter in their first name. Now that you know who is who, let's get racing!!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRob - Kawasaki - Green - 1st place - 16 years; \r\nCrystal - Suzuki - Blue - 2nd place - 3 years; \r\nJeremy - Yamaha - Red - 4th place - 6 years; \r\nRobert - Triumph - Black - 3rd place - 12 years\n<|im_start|>answer\nRob - Kawasaki - Green - 1st place - 16 years; \r\nCrystal - Suzuki - Blue - 2nd place - 3 years; \r\nJeremy - Yamaha - Red - 4th place - 6 years; \r\nRobert - Triumph - Black - 3rd place - 12 years\n<|im_end|>" }, { "id": "#25388", "title": "Baseball Lineup", "fun": 2.7600000000000002, "difficulty": 1.92, "author": "dddlite", "desc": "Before the game, the manager of the \"Anytown Homers\" had to decide in what order to bat his 9 players. However, the manager's dog chewed the paper the lineup was written on as the manager drove to the game. He could remember:\n\r\n1. No one whose name begins with a \"J\" is the lead-off hitter.\r\n2. Blake bats in the middle of the lineup.\r\n3. Jay bats after Keith & Jake and before Gerald.\r\n4. Mitch bats 3 spots away from Blake (2 between).\r\n5. Jon hits before Jay and after Blake.\r\n6. Doug bats before Mitch.\r\n7. Keith bats 2 spots before Jon (1 between).\r\n8. Jake bats third.\r\n9. Jay bats 2 spots before Jack, who bats last (1 between).", "hint": "A lead-off hitter is the first batter in a lineup.", "answer": "Doug\r\nMitch\r\nJake\r\nKeith\r\nBlake\r\nJon\r\nJay\r\nGerald\r\nJack", "category": "Logic", "date": "08/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBefore the game, the manager of the \"Anytown Homers\" had to decide in what order to bat his 9 players. However, the manager's dog chewed the paper the lineup was written on as the manager drove to the game. He could remember:\n\r\n1. No one whose name begins with a \"J\" is the lead-off hitter.\r\n2. Blake bats in the middle of the lineup.\r\n3. Jay bats after Keith & Jake and before Gerald.\r\n4. Mitch bats 3 spots away from Blake (2 between).\r\n5. Jon hits before Jay and after Blake.\r\n6. Doug bats before Mitch.\r\n7. Keith bats 2 spots before Jon (1 between).\r\n8. Jake bats third.\r\n9. Jay bats 2 spots before Jack, who bats last (1 between).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDoug\r\nMitch\r\nJake\r\nKeith\r\nBlake\r\nJon\r\nJay\r\nGerald\r\nJack\n<|im_start|>answer\nDoug\r\nMitch\r\nJake\r\nKeith\r\nBlake\r\nJon\r\nJay\r\nGerald\r\nJack\n<|im_end|>" }, { "id": "#33398", "title": "Athletics Carnival", "fun": 2.7600000000000002, "difficulty": 1.91, "author": "grungy49", "desc": "The state athletic carnival had just finished and a group of five friends had each participated in a different event. They each raced on a different day and each finished in a different spot. \r\nCan you figure out all of the friends' last names, the event they participated in, how they finished, and on what day they raced?\n\r\nBoys: Robert, Fred\r\nGirls: Samantha, Kelly, Jessica\r\nSurnames: Turner, Liedwick, Perry, Bullock, Champion\r\nRaces: 100m, 200m, 400m, 800m, 1500m\r\nPlacings: 1st, 3rd, 7th, 8th, 10th\r\nDays: Monday, Tuesday, Thursday, Friday, Saturday\n\r\nClues\n\r\n1. The person whose last name was Champion won the 100m sprint. \n\r\n2. Kelly's last name does not have a single 'C' in it.\n\r\n3. The three girls raced in the 400m, the 800m and the 1500m.\n\r\n4. Neither of the two boys' last names was Liedwick.\n\r\n5. The person whose last name was Bullock raced on the Saturday.\n\r\n6. Tuesday was the shortest day because the race held on that day was the 100m sprint.\n\r\n7. Jessica's last name started with a 'P', and she raced on the day before the weekend.\n\r\n8. Robert almost won first place, but he was overtaken by two runners right at the end.\n\r\n9. The person who raced on the Monday finished 10th in their race.\n\r\n10. The person who raced in the 800m finished 7th.\n\r\n11. The person who finished 8th ran the race that was longer than 1000 metres.\n\r\n12. Kelly raced in the 400m.\n\r\n13. Jessica did not finish 7th.", "hint": "No hint available.", "answer": "Samantha Liedwick raced in the 800m on Thursday, and finished 7th.\n\r\nRobert Bullock raced in the 200m on Saturday, and finished 3rd.\n\r\nKelly Turner raced in the 400m on Monday, and finished 10th.\n\r\nFred Champion raced in the 100m on Tuesday, and finished 1st.\n\r\nJessica Perry raced in the 1500m on Friday, and finished 8th.", "category": "Logic-Grid", "date": "10/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe state athletic carnival had just finished and a group of five friends had each participated in a different event. They each raced on a different day and each finished in a different spot. \r\nCan you figure out all of the friends' last names, the event they participated in, how they finished, and on what day they raced?\n\r\nBoys: Robert, Fred\r\nGirls: Samantha, Kelly, Jessica\r\nSurnames: Turner, Liedwick, Perry, Bullock, Champion\r\nRaces: 100m, 200m, 400m, 800m, 1500m\r\nPlacings: 1st, 3rd, 7th, 8th, 10th\r\nDays: Monday, Tuesday, Thursday, Friday, Saturday\n\r\nClues\n\r\n1. The person whose last name was Champion won the 100m sprint. \n\r\n2. Kelly's last name does not have a single 'C' in it.\n\r\n3. The three girls raced in the 400m, the 800m and the 1500m.\n\r\n4. Neither of the two boys' last names was Liedwick.\n\r\n5. The person whose last name was Bullock raced on the Saturday.\n\r\n6. Tuesday was the shortest day because the race held on that day was the 100m sprint.\n\r\n7. Jessica's last name started with a 'P', and she raced on the day before the weekend.\n\r\n8. Robert almost won first place, but he was overtaken by two runners right at the end.\n\r\n9. The person who raced on the Monday finished 10th in their race.\n\r\n10. The person who raced in the 800m finished 7th.\n\r\n11. The person who finished 8th ran the race that was longer than 1000 metres.\n\r\n12. Kelly raced in the 400m.\n\r\n13. Jessica did not finish 7th.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSamantha Liedwick raced in the 800m on Thursday, and finished 7th.\n\r\nRobert Bullock raced in the 200m on Saturday, and finished 3rd.\n\r\nKelly Turner raced in the 400m on Monday, and finished 10th.\n\r\nFred Champion raced in the 100m on Tuesday, and finished 1st.\n\r\nJessica Perry raced in the 1500m on Friday, and finished 8th.\n<|im_start|>answer\nSamantha Liedwick raced in the 800m on Thursday, and finished 7th.\n\r\nRobert Bullock raced in the 200m on Saturday, and finished 3rd.\n\r\nKelly Turner raced in the 400m on Monday, and finished 10th.\n\r\nFred Champion raced in the 100m on Tuesday, and finished 1st.\n\r\nJessica Perry raced in the 1500m on Friday, and finished 8th.\n<|im_end|>" }, { "id": "#20692", "title": "The Case of the Reindeer Spies", "fun": 2.7600000000000002, "difficulty": 2.05, "author": "fishmed", "desc": "Professor Stanwick, the crime expert, gets consulted by police and the federal government on a regular basis to get help in solving crimes. Today he finds Inspector Stevens, from the FBI, at his door asking for help with yet another case. \n\r\n\"What can I assist the FBI with today?\" Professor Stanwick asked.\r\nSitting in an easy chair, Inspector Stevens replied, \"The facts are these. As a result of the national effort to crack down on domestic spies, the Bureau has uncovered a ring of five spies in the local area who have started selling defense industry secrets to the Chinese consulate in New York. The five individuals have been identified, and we are intercepting their calls and messages. We believe they may be able to lead us to several similar rings in the Midwest, so we are monitoring their calls a while longer to help us identify the other rings. The problem is, that they are using code names, and we need to match the individuals with the code names before we can completely understand the messages.\"\r\nProfessor Stanwick picked up a pad of paper and asked, \"What do you have so far?\" \r\nOpening a notebook, the Inspector said, \"The code names are those of well-known reindeer: Comet, Cupid, Dasher, Dancer, and Donder. We are certain that these names correspond in some order to the members of the group, all of whom live in this area. \n\r\nSal Abelardo is a civil engineer for Spacetech. His wife works for a publishing company and apparently knows nothing of his espionage activities. Peter Bircham works as a janitor for the same firm; he is single. John Cantrell is a junior executive with Aeroco. He and his wife share a condo downtown with his sister. Tim Delmarin, unmarried, is a communications expert with the same firm. The fifth member is Telly Ephesos, a retired Foreign Service Officer who spent twenty years in China. He is married and has no siblings. \n\r\nFrom the messages already sent, and our own investigations, we've been able to glean only a few facts. \n\r\n1. Cantrell and 'Dasher' and their wives sometimes take vacations together. \r\n2. 'Cupid' is highly dissatisfied with his job. \r\n3. Mrs. Abelardo regularly corresponds with 'Mrs. Donder'. \r\n4. Neither 'Comet' nor 'Dasher' have ever been outside the state. \r\n5. Mrs. Abelardo was once engaged to the brother of 'Donder'. \r\n6. Bircham makes monthly trips to Mexico City. \n\r\nI can't impress upon you enough, Professor Stanwick, the importance of identifying these code names. Any help you can give us will be greatly appreciated.\"\n\r\nProfessor Stanwick, having been scribbling on his pad of paper, tossed it to Stevens saying, \"Here are the code names and their possessors. Happy hunting!\" \n\r\nWhich code name goes with which person?", "hint": "No hint available.", "answer": "Abelardo - Dasher\r\nBircham - Cupid\r\nCantrell - Donder \r\nDelmarin - Comet\r\nEphesos - Dancer\n\n\r\n'Dasher' can't be Cantrell, who vacations with him, or Bircham or Delmarin, who are single. Since he has never left the state, he can't be Ephesos either. Therefore 'Dasher' is Abelardo. Similarly, 'Donder'; can't be the single Bircham or Delmarin. Since he has a brother, he can't be Ephesos. Therefore 'Donder' is Cantrell. The retired, worldly Ephesos cannot be the dissatisfied 'Cupid' or the provincial 'Comet', so he is 'Dancer', and the well-traveled Birchman cannot be 'Comet', so he is 'Cupid'. That leave Delmarin as 'Comet.'", "category": "Logic-Grid", "date": "01/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nProfessor Stanwick, the crime expert, gets consulted by police and the federal government on a regular basis to get help in solving crimes. Today he finds Inspector Stevens, from the FBI, at his door asking for help with yet another case. \n\r\n\"What can I assist the FBI with today?\" Professor Stanwick asked.\r\nSitting in an easy chair, Inspector Stevens replied, \"The facts are these. As a result of the national effort to crack down on domestic spies, the Bureau has uncovered a ring of five spies in the local area who have started selling defense industry secrets to the Chinese consulate in New York. The five individuals have been identified, and we are intercepting their calls and messages. We believe they may be able to lead us to several similar rings in the Midwest, so we are monitoring their calls a while longer to help us identify the other rings. The problem is, that they are using code names, and we need to match the individuals with the code names before we can completely understand the messages.\"\r\nProfessor Stanwick picked up a pad of paper and asked, \"What do you have so far?\" \r\nOpening a notebook, the Inspector said, \"The code names are those of well-known reindeer: Comet, Cupid, Dasher, Dancer, and Donder. We are certain that these names correspond in some order to the members of the group, all of whom live in this area. \n\r\nSal Abelardo is a civil engineer for Spacetech. His wife works for a publishing company and apparently knows nothing of his espionage activities. Peter Bircham works as a janitor for the same firm; he is single. John Cantrell is a junior executive with Aeroco. He and his wife share a condo downtown with his sister. Tim Delmarin, unmarried, is a communications expert with the same firm. The fifth member is Telly Ephesos, a retired Foreign Service Officer who spent twenty years in China. He is married and has no siblings. \n\r\nFrom the messages already sent, and our own investigations, we've been able to glean only a few facts. \n\r\n1. Cantrell and 'Dasher' and their wives sometimes take vacations together. \r\n2. 'Cupid' is highly dissatisfied with his job. \r\n3. Mrs. Abelardo regularly corresponds with 'Mrs. Donder'. \r\n4. Neither 'Comet' nor 'Dasher' have ever been outside the state. \r\n5. Mrs. Abelardo was once engaged to the brother of 'Donder'. \r\n6. Bircham makes monthly trips to Mexico City. \n\r\nI can't impress upon you enough, Professor Stanwick, the importance of identifying these code names. Any help you can give us will be greatly appreciated.\"\n\r\nProfessor Stanwick, having been scribbling on his pad of paper, tossed it to Stevens saying, \"Here are the code names and their possessors. Happy hunting!\" \n\r\nWhich code name goes with which person?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbelardo - Dasher\r\nBircham - Cupid\r\nCantrell - Donder \r\nDelmarin - Comet\r\nEphesos - Dancer\n\n\r\n'Dasher' can't be Cantrell, who vacations with him, or Bircham or Delmarin, who are single. Since he has never left the state, he can't be Ephesos either. Therefore 'Dasher' is Abelardo. Similarly, 'Donder'; can't be the single Bircham or Delmarin. Since he has a brother, he can't be Ephesos. Therefore 'Donder' is Cantrell. The retired, worldly Ephesos cannot be the dissatisfied 'Cupid' or the provincial 'Comet', so he is 'Dancer', and the well-traveled Birchman cannot be 'Comet', so he is 'Cupid'. That leave Delmarin as 'Comet.'\n<|im_start|>answer\nAbelardo - Dasher\r\nBircham - Cupid\r\nCantrell - Donder \r\nDelmarin - Comet\r\nEphesos - Dancer\n\n\r\n'Dasher' can't be Cantrell, who vacations with him, or Bircham or Delmarin, who are single. Since he has never left the state, he can't be Ephesos either. Therefore 'Dasher' is Abelardo. Similarly, 'Donder'; can't be the single Bircham or Delmarin. Since he has a brother, he can't be Ephesos. Therefore 'Donder' is Cantrell. The retired, worldly Ephesos cannot be the dissatisfied 'Cupid' or the provincial 'Comet', so he is 'Dancer', and the well-traveled Birchman cannot be 'Comet', so he is 'Cupid'. That leave Delmarin as 'Comet.'\n<|im_end|>" }, { "id": "#19425", "title": "Grocery Shopping", "fun": 2.7600000000000002, "difficulty": 1.67, "author": "Jake", "desc": "Bobby Braingle is shopping at the grocery store. He purchases a different amount of apples, oranges, bananas, grapes and pineapples. Each of the fruit was either $1, $2, $3, $4 or $5 each and Bobby purchased either 1, 2, 3, 4 or 5 of each fruit. Can you figure out exactly what Bobby purchased?\n\r\nClues:\r\n1) The $2 orange was delicious.\r\n2) Bobby bought more apples than oranges, but fewer apples than the $4 fruit.\r\n3) Bobby spent $20 total on grapes.\r\n4) The two $5 fruits needed to be peeled.\r\n5) He did not purchase four apples or four grapes.\r\n6) The pineapples cost $10 which was more than Bobby spent on bananas.", "hint": "No hint available.", "answer": "Bobby purchased 3 apples at $3 each, 1 orange at $2, 4 bananas at $1 a piece, 5 grapes at $4 and 2 pineapples at $5 each.", "category": "Logic-Grid", "date": "11/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBobby Braingle is shopping at the grocery store. He purchases a different amount of apples, oranges, bananas, grapes and pineapples. Each of the fruit was either $1, $2, $3, $4 or $5 each and Bobby purchased either 1, 2, 3, 4 or 5 of each fruit. Can you figure out exactly what Bobby purchased?\n\r\nClues:\r\n1) The $2 orange was delicious.\r\n2) Bobby bought more apples than oranges, but fewer apples than the $4 fruit.\r\n3) Bobby spent $20 total on grapes.\r\n4) The two $5 fruits needed to be peeled.\r\n5) He did not purchase four apples or four grapes.\r\n6) The pineapples cost $10 which was more than Bobby spent on bananas.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBobby purchased 3 apples at $3 each, 1 orange at $2, 4 bananas at $1 a piece, 5 grapes at $4 and 2 pineapples at $5 each.\n<|im_start|>answer\nBobby purchased 3 apples at $3 each, 1 orange at $2, 4 bananas at $1 a piece, 5 grapes at $4 and 2 pineapples at $5 each.\n<|im_end|>" }, { "id": "#34201", "title": "The Winning Combination", "fun": 2.7600000000000002, "difficulty": 2.35, "author": "grungy49", "desc": "You are in a game show with four other contestants. The objective is to crack the combination of the safe using the clues, and the first person to do so will win $500,000.\n\r\nThe safe combination looks like this:\n\r\n??-??-??-??\n\r\nA digit can be used more than once in the code, and there are no leading zeroes.\n\r\nHere are the clues:\n\r\n1. The third set of two numbers is the same as the first set reversed.\n\r\n2. There are no 2's, 3's, 4's or 5's in any of the combination.\n\r\n3. If you multiply 4 by the third set of numbers, you will get the fourth set of numbers.\n\r\n4. If you add the first number in the first set with the first number in the second set you will get 8.\n\r\n5. The second set of numbers is not greater than 20.\n\r\n6. The second number in the second set multiplied by the second number in the fourth set equals one higher than the numbers in the first set.\n\r\nAnd get moving, I think another contestant has almost figured it out!", "hint": "No hint available.", "answer": "The combination is 71-19-17-68.\n\r\nFrom the second clue, we know that there are no 2's, 3's, 4's or 5's in any of the sets. Therefore, only 1's, 6's, 7's, 8's and 9's could be in the remaining spots.\n\r\nClue 3 says if you multiply 4 by the third set of numbers you will get the fourth set of numbers. From this, you can tell a 1 is the first number in the third set - any other number would be too high.\r\n11 * 4 = 44\r\n16 * 4 = 64\r\n17 * 4 = 68\r\n18 * 4 = 72\r\n19 * 4 = 76\r\nOf these, 17 * 4 and 19 * 4 are the only ones that are possible; as the answer of the other numbers contains a number which we know is not in the combination.\n\r\nNow we skip all the way to clue 5, which tells us the second set of numbers is not greater than 20. This means that the first digit of that set is also a 1.\n\r\nSo far, we know this much:\n\r\n??-1?-1?-??\n\r\nNow, we can come to clue 4, which tells us if you add the first number in the first set with the first number in the second set you will get 8. The first number in the second set is 1, so the first number in the first set must be 7. Since the first clue tells us the first set is the third set reversed, and we know that a 1 is the first number in the third set, a 1 must be the second number in the first set and a 7 must be the second number in the third set.\n\r\nSo far, we know this much:\n\r\n71-1?-17-??\n\r\nNow, the third set (17) multiplied by 4 will get us 68. Now we know the fourth set is 68.\n\r\n71-1?-17-68\n\r\nNow we come to the final clue. This tells us the second number in the second set (unknown) multiplied by the second number in the fourth set (8) equals one higher than the numbers in the first set. We know that the first set is 71, so adding one to that (72) and then dividing it by 8 will get us 9. So, the finished combination is:\n\r\n71-19-17-68", "category": "Logic", "date": "12/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are in a game show with four other contestants. The objective is to crack the combination of the safe using the clues, and the first person to do so will win $500,000.\n\r\nThe safe combination looks like this:\n\r\n??-??-??-??\n\r\nA digit can be used more than once in the code, and there are no leading zeroes.\n\r\nHere are the clues:\n\r\n1. The third set of two numbers is the same as the first set reversed.\n\r\n2. There are no 2's, 3's, 4's or 5's in any of the combination.\n\r\n3. If you multiply 4 by the third set of numbers, you will get the fourth set of numbers.\n\r\n4. If you add the first number in the first set with the first number in the second set you will get 8.\n\r\n5. The second set of numbers is not greater than 20.\n\r\n6. The second number in the second set multiplied by the second number in the fourth set equals one higher than the numbers in the first set.\n\r\nAnd get moving, I think another contestant has almost figured it out!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe combination is 71-19-17-68.\n\r\nFrom the second clue, we know that there are no 2's, 3's, 4's or 5's in any of the sets. Therefore, only 1's, 6's, 7's, 8's and 9's could be in the remaining spots.\n\r\nClue 3 says if you multiply 4 by the third set of numbers you will get the fourth set of numbers. From this, you can tell a 1 is the first number in the third set - any other number would be too high.\r\n11 * 4 = 44\r\n16 * 4 = 64\r\n17 * 4 = 68\r\n18 * 4 = 72\r\n19 * 4 = 76\r\nOf these, 17 * 4 and 19 * 4 are the only ones that are possible; as the answer of the other numbers contains a number which we know is not in the combination.\n\r\nNow we skip all the way to clue 5, which tells us the second set of numbers is not greater than 20. This means that the first digit of that set is also a 1.\n\r\nSo far, we know this much:\n\r\n??-1?-1?-??\n\r\nNow, we can come to clue 4, which tells us if you add the first number in the first set with the first number in the second set you will get 8. The first number in the second set is 1, so the first number in the first set must be 7. Since the first clue tells us the first set is the third set reversed, and we know that a 1 is the first number in the third set, a 1 must be the second number in the first set and a 7 must be the second number in the third set.\n\r\nSo far, we know this much:\n\r\n71-1?-17-??\n\r\nNow, the third set (17) multiplied by 4 will get us 68. Now we know the fourth set is 68.\n\r\n71-1?-17-68\n\r\nNow we come to the final clue. This tells us the second number in the second set (unknown) multiplied by the second number in the fourth set (8) equals one higher than the numbers in the first set. We know that the first set is 71, so adding one to that (72) and then dividing it by 8 will get us 9. So, the finished combination is:\n\r\n71-19-17-68\n<|im_start|>answer\nThe combination is 71-19-17-68.\n\r\nFrom the second clue, we know that there are no 2's, 3's, 4's or 5's in any of the sets. Therefore, only 1's, 6's, 7's, 8's and 9's could be in the remaining spots.\n\r\nClue 3 says if you multiply 4 by the third set of numbers you will get the fourth set of numbers. From this, you can tell a 1 is the first number in the third set - any other number would be too high.\r\n11 * 4 = 44\r\n16 * 4 = 64\r\n17 * 4 = 68\r\n18 * 4 = 72\r\n19 * 4 = 76\r\nOf these, 17 * 4 and 19 * 4 are the only ones that are possible; as the answer of the other numbers contains a number which we know is not in the combination.\n\r\nNow we skip all the way to clue 5, which tells us the second set of numbers is not greater than 20. This means that the first digit of that set is also a 1.\n\r\nSo far, we know this much:\n\r\n??-1?-1?-??\n\r\nNow, we can come to clue 4, which tells us if you add the first number in the first set with the first number in the second set you will get 8. The first number in the second set is 1, so the first number in the first set must be 7. Since the first clue tells us the first set is the third set reversed, and we know that a 1 is the first number in the third set, a 1 must be the second number in the first set and a 7 must be the second number in the third set.\n\r\nSo far, we know this much:\n\r\n71-1?-17-??\n\r\nNow, the third set (17) multiplied by 4 will get us 68. Now we know the fourth set is 68.\n\r\n71-1?-17-68\n\r\nNow we come to the final clue. This tells us the second number in the second set (unknown) multiplied by the second number in the fourth set (8) equals one higher than the numbers in the first set. We know that the first set is 71, so adding one to that (72) and then dividing it by 8 will get us 9. So, the finished combination is:\n\r\n71-19-17-68\n<|im_end|>" }, { "id": "#27891", "title": "Who Stole What?", "fun": 2.7600000000000002, "difficulty": 1.47, "author": "Dontrelle", "desc": "Sherlock Holmes sat opposite Inspector Lestrade in Lestrade's office at Scotland Yard. Sergeant Smith entered the room with three prisoners, who stood in line in front of Lestrade's desk. Holmes watched with interest as Lestrade interrogated the three men. Barnett stood between the man who was clean-shaven and the man who stole the cigar case. Black, who had stolen the wallet, had been arrested at the same time as Wetherby. It was the man with the mustache, not the one with the beard, who had stolen the gold watch.\n\r\nCan you identify each of the men, matching them to: \n\r\n1. The item each had stolen and\n\r\n2. Whether each was clean-shaven or had a mustache or a beard.", "hint": "No hint available.", "answer": "Barnett. Mustache. Gold Watch\r\nWetherby. Beard. Cigar Case\r\nBlack. Clean-Shaven. Wallet", "category": "Logic", "date": "01/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSherlock Holmes sat opposite Inspector Lestrade in Lestrade's office at Scotland Yard. Sergeant Smith entered the room with three prisoners, who stood in line in front of Lestrade's desk. Holmes watched with interest as Lestrade interrogated the three men. Barnett stood between the man who was clean-shaven and the man who stole the cigar case. Black, who had stolen the wallet, had been arrested at the same time as Wetherby. It was the man with the mustache, not the one with the beard, who had stolen the gold watch.\n\r\nCan you identify each of the men, matching them to: \n\r\n1. The item each had stolen and\n\r\n2. Whether each was clean-shaven or had a mustache or a beard.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBarnett. Mustache. Gold Watch\r\nWetherby. Beard. Cigar Case\r\nBlack. Clean-Shaven. Wallet\n<|im_start|>answer\nBarnett. Mustache. Gold Watch\r\nWetherby. Beard. Cigar Case\r\nBlack. Clean-Shaven. Wallet\n<|im_end|>" }, { "id": "#44344", "title": "The Musicians", "fun": 2.7600000000000002, "difficulty": 1.73, "author": "whsprec", "desc": "Musicians Eddie, Alex, Steven, Don, and Brett all competed in a solo competition. Each sang a different type of music: gospel, blues, country, soul, and folk. Each played a different instrument: violin, guitar, bass, piano, and organ. From the clues given, determine the man, his type of music, the instrument that he plays, and his place in the competition.\r\n1- The bass player's soul performance finished third.\r\n2- The folk and country singers did not use a keyboard and neither did Brett.\r\n3- Don placed higher than the bass player, who placed higher than the gospel singer, but none of them won the competition.\r\n4- The violinist finished behind Steven, but ahead of the blues singer; however, none of them finished last.\r\n5- The guitar player did not sing country.\r\n6- Eddie did not sing gospel while playing his piano.", "hint": "No hint available.", "answer": "1st Steven playing guitar and singing folk\r\n2nd Don playing violin and singing country\r\n3rd Brett playing bass and singing soul\r\n4th Eddie playing piano and singing blues\r\n5th Alex playing organ and singing gospel", "category": "Logic-Grid", "date": "04/12/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMusicians Eddie, Alex, Steven, Don, and Brett all competed in a solo competition. Each sang a different type of music: gospel, blues, country, soul, and folk. Each played a different instrument: violin, guitar, bass, piano, and organ. From the clues given, determine the man, his type of music, the instrument that he plays, and his place in the competition.\r\n1- The bass player's soul performance finished third.\r\n2- The folk and country singers did not use a keyboard and neither did Brett.\r\n3- Don placed higher than the bass player, who placed higher than the gospel singer, but none of them won the competition.\r\n4- The violinist finished behind Steven, but ahead of the blues singer; however, none of them finished last.\r\n5- The guitar player did not sing country.\r\n6- Eddie did not sing gospel while playing his piano.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st Steven playing guitar and singing folk\r\n2nd Don playing violin and singing country\r\n3rd Brett playing bass and singing soul\r\n4th Eddie playing piano and singing blues\r\n5th Alex playing organ and singing gospel\n<|im_start|>answer\n1st Steven playing guitar and singing folk\r\n2nd Don playing violin and singing country\r\n3rd Brett playing bass and singing soul\r\n4th Eddie playing piano and singing blues\r\n5th Alex playing organ and singing gospel\n<|im_end|>" }, { "id": "#49873", "title": "Dr. Contrary's Pointy End", "fun": 2.7600000000000002, "difficulty": 2.03, "author": "AwwwSweet", "desc": "Try to close your eyes and picture this in your mind (once you have read through it, of course!). \n\r\nYou are standing in front of a solid metal table. Dr. Contrary places a one-hundred dollar bill in the middle of the table. While you watch, he turns a large metal pyramid upside down and perfectly balances its point in the middle of the one-hundred dollar bill so the pyramid is balancing on that single point. He shows you very clearly that there is nothing holding up the pyramid other than gravity. \n\r\nDr. Contrary turns to you and asks, \"Can you remove the one-hundred dollar bill in such a way that you do not disturb the upside-down pyramid? You may not touch or move the pyramid, you cannot prop it up or lift it off the table, it cannot fall over, and you are not allowed to cut or tear the dollar bill.\" He eyeballs you and waits patiently for your response.\n\r\nCan you solve Dr. Contrary's puzzle?", "hint": "No one said anything about keeping the one-hundred dollar bill!", "answer": "Light the one-hundred dollar bill on fire. It may be painful to see some nice spending money go up in smoke, but burning the bill will successfully remove it without disturbing the overturned pyramid.\n\r\nThere may be semantics to be quibbled over, such as the definition of \"touch\", whether you are removing/destroying/changing the composition the dollar bill, whether there may be some small portion of the dollar bill remaining, and even the legality of the action. However, the true purpose of this puzzle is to find the reader's \"flash of insight\" to realize that burning it is an option. It is very unlikely that someone would come up with the solution through brute force itemized thinking.", "category": "Logic", "date": "07/12/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTry to close your eyes and picture this in your mind (once you have read through it, of course!). \n\r\nYou are standing in front of a solid metal table. Dr. Contrary places a one-hundred dollar bill in the middle of the table. While you watch, he turns a large metal pyramid upside down and perfectly balances its point in the middle of the one-hundred dollar bill so the pyramid is balancing on that single point. He shows you very clearly that there is nothing holding up the pyramid other than gravity. \n\r\nDr. Contrary turns to you and asks, \"Can you remove the one-hundred dollar bill in such a way that you do not disturb the upside-down pyramid? You may not touch or move the pyramid, you cannot prop it up or lift it off the table, it cannot fall over, and you are not allowed to cut or tear the dollar bill.\" He eyeballs you and waits patiently for your response.\n\r\nCan you solve Dr. Contrary's puzzle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLight the one-hundred dollar bill on fire. It may be painful to see some nice spending money go up in smoke, but burning the bill will successfully remove it without disturbing the overturned pyramid.\n\r\nThere may be semantics to be quibbled over, such as the definition of \"touch\", whether you are removing/destroying/changing the composition the dollar bill, whether there may be some small portion of the dollar bill remaining, and even the legality of the action. However, the true purpose of this puzzle is to find the reader's \"flash of insight\" to realize that burning it is an option. It is very unlikely that someone would come up with the solution through brute force itemized thinking.\n<|im_start|>answer\nLight the one-hundred dollar bill on fire. It may be painful to see some nice spending money go up in smoke, but burning the bill will successfully remove it without disturbing the overturned pyramid.\n\r\nThere may be semantics to be quibbled over, such as the definition of \"touch\", whether you are removing/destroying/changing the composition the dollar bill, whether there may be some small portion of the dollar bill remaining, and even the legality of the action. However, the true purpose of this puzzle is to find the reader's \"flash of insight\" to realize that burning it is an option. It is very unlikely that someone would come up with the solution through brute force itemized thinking.\n<|im_end|>" }, { "id": "#21958", "title": "Easter Egg Hunt", "fun": 2.7600000000000002, "difficulty": 1.03, "author": "cdrock", "desc": "It was Easter in Easter village and all the Easter bunnies are joyful. The annual Easter egg hunt was just finished. The Easter egg hunt is where four Easter bunnies search for any of the four colored eggs and then cross the finish line. Can you figure out which Easter bunny found which egg and what place they finished?\n\r\nEaster bunnies- Mr Hops, Jumper, Long Ears, and Mrs. Littlenose\n\r\nEaster Eggs- blue, red, green, and yellow \n\r\nClues:\n\r\n1. Long Ears did not finish in 2nd place.\n\r\n2. Jumper did not finish in 1st\n\r\n3. Long Ears found the red Easter egg.\n\r\n4. The bunny that finished in 2nd did not find the green egg.\n\r\n5. Mr. Hops did not find the blue egg.\n\r\n6. Littlenose did not finish in 2nd.\n\r\n7. The bunny that found the blue egg did not finish in 1st or 2nd.\n\r\n8. Hops finished in 4th.", "hint": "No hint available.", "answer": "Mr. Hops- green- 4th\r\nJumper- yellow- 2nd\r\nLong Ears- red- 1st\r\nMrs. Littlenose- blue- 3rd", "category": "Logic-Grid", "date": "04/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was Easter in Easter village and all the Easter bunnies are joyful. The annual Easter egg hunt was just finished. The Easter egg hunt is where four Easter bunnies search for any of the four colored eggs and then cross the finish line. Can you figure out which Easter bunny found which egg and what place they finished?\n\r\nEaster bunnies- Mr Hops, Jumper, Long Ears, and Mrs. Littlenose\n\r\nEaster Eggs- blue, red, green, and yellow \n\r\nClues:\n\r\n1. Long Ears did not finish in 2nd place.\n\r\n2. Jumper did not finish in 1st\n\r\n3. Long Ears found the red Easter egg.\n\r\n4. The bunny that finished in 2nd did not find the green egg.\n\r\n5. Mr. Hops did not find the blue egg.\n\r\n6. Littlenose did not finish in 2nd.\n\r\n7. The bunny that found the blue egg did not finish in 1st or 2nd.\n\r\n8. Hops finished in 4th.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Hops- green- 4th\r\nJumper- yellow- 2nd\r\nLong Ears- red- 1st\r\nMrs. Littlenose- blue- 3rd\n<|im_start|>answer\nMr. Hops- green- 4th\r\nJumper- yellow- 2nd\r\nLong Ears- red- 1st\r\nMrs. Littlenose- blue- 3rd\n<|im_end|>" }, { "id": "#27530", "title": "Age Mix Up", "fun": 2.7600000000000002, "difficulty": 2.09, "author": "scm14", "desc": "Jordan, Justin and Jeff are brothers whose ages are 29, 30 and 31 (in any order). Your job is to determine the brothers' ages from the clues below. There's one catch though....only ONE clue is true. The rest are false. Good luck!\n\r\n1. Justin is 30\r\n2. Jordan is the youngest\r\n3. Jordan is 31\r\n4. Justin is one year older and one year younger than his brothers.\r\n5. Justin is not the youngest.\r\n6. Jordan is not two years older than Justin.\r\n7. Justin is the oldest\r\n8. Jeff is older than Jordan.", "hint": "No hint available.", "answer": "Justin, 29\r\nJeff, 30\r\nJordan, 31\n\r\nClue 1: If this is true, so is clue 4. Therefore, it is false and Justin is not 30. \r\nClue 2: If this is true, so is clue 5. Therefore, it is false and Jordan is not 29.\r\nClue 3: This clue is true\r\nClue 4: If this is true, so is clue 1. Therefore, it is false.\r\nClue 5: If this is true, Justin would have to be 31, because we have already determined from clue # 1 that he is not 30, and clue 7 would also be true. Therefore, it is false. \r\nClue 6: If this is true, Jordan would be 30 and clue # 8 would also be true. Therefore it is false.", "category": "Logic", "date": "12/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJordan, Justin and Jeff are brothers whose ages are 29, 30 and 31 (in any order). Your job is to determine the brothers' ages from the clues below. There's one catch though....only ONE clue is true. The rest are false. Good luck!\n\r\n1. Justin is 30\r\n2. Jordan is the youngest\r\n3. Jordan is 31\r\n4. Justin is one year older and one year younger than his brothers.\r\n5. Justin is not the youngest.\r\n6. Jordan is not two years older than Justin.\r\n7. Justin is the oldest\r\n8. Jeff is older than Jordan.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJustin, 29\r\nJeff, 30\r\nJordan, 31\n\r\nClue 1: If this is true, so is clue 4. Therefore, it is false and Justin is not 30. \r\nClue 2: If this is true, so is clue 5. Therefore, it is false and Jordan is not 29.\r\nClue 3: This clue is true\r\nClue 4: If this is true, so is clue 1. Therefore, it is false.\r\nClue 5: If this is true, Justin would have to be 31, because we have already determined from clue # 1 that he is not 30, and clue 7 would also be true. Therefore, it is false. \r\nClue 6: If this is true, Jordan would be 30 and clue # 8 would also be true. Therefore it is false.\n<|im_start|>answer\nJustin, 29\r\nJeff, 30\r\nJordan, 31\n\r\nClue 1: If this is true, so is clue 4. Therefore, it is false and Justin is not 30. \r\nClue 2: If this is true, so is clue 5. Therefore, it is false and Jordan is not 29.\r\nClue 3: This clue is true\r\nClue 4: If this is true, so is clue 1. Therefore, it is false.\r\nClue 5: If this is true, Justin would have to be 31, because we have already determined from clue # 1 that he is not 30, and clue 7 would also be true. Therefore, it is false. \r\nClue 6: If this is true, Jordan would be 30 and clue # 8 would also be true. Therefore it is false.\n<|im_end|>" }, { "id": "#31998", "title": "The Budding Journalists", "fun": 2.7600000000000002, "difficulty": 1.84, "author": "dishu", "desc": "The four friends once decided to become journalists. They applied to the National News Channel and got the jobs. On their first day at work, each of them was asked to interview a different famous personality at a different time. In their excitement, the four friends accidentally mixed the papers which contained the information regarding which famous personality was to be interviewed by whom and at what time. The papers also contained details regarding the different professions of these famous personalities and their different famous achievements which have contributed towards the development of their country. All they could remember were the following bits of information. Help them clear-up the confusion on time by correctly matching each friend to the famous personality she has to interview, at what time she has to conduct the interview and what is the profession of each of the famous personalities and what were their biggest achievements.\n\r\nFriends: Dis, Dip, Raj, Rich\r\nFamous personalities: Mr. Jag, Miss Sam, Mr. Sri, Mr. Bala\r\nProfessions: Hydro-engineer, Politician, Civil Engineer, Mechanical Engineer\r\nAchievements: National highways, Canals, Housing to poor, Sky Train\r\nTime of interview: 10 a.m, 2 p.m, 9 a.m, 3.30 p.m\n\r\n1. Dis was very excited, as she had to interview the man who was the brain behind her favourite Sky Train.\r\n2. Rich's appointment with the politician was the last appointment of the day.\r\n3. The only woman hydro-engineer of the country was to be interviewed at 10 a.m.\r\n4. Raj, who hated hot weather, was upset that her interview assignment was scheduled in the afternoon.\r\n5. Mr. Bala hastened the traffic flow across the country by building many National Highways.\r\n6. Sri was not the politician and the mechanical engineer did not build highways.\r\n7. The poor people are thankful for the houses Jag provided them. \r\n8. The politician did not build any highways.", "hint": "Assume that these were the only appointments for the day.\r\nThe following condensations have been made in Grid due to space constraints:\r\nEngineer is written as engg, \r\nMechanical is written as Mech,\r\nHousing to poor has been reduced to housing and National Highways has been reduced to Highways.", "answer": "Dis was to interview Mr Sri, the mechanical engineer responsible for launching Sky Trains, at 9 a.m.\r\nDip was all set to meet Miss Sam, who was the hydro-engineer responsible for building many canal and dams, at 10 a.m. \r\nRaj had to interview the civil engineer responsible for National Highways, Mr. Bala, at 2 p.m., \r\nand Rich was to meet Mr. Jag, the politician who gave homes to the poor, at 3:30 p.m\n\r\nUnfortunately, the friends could not clear-up the mess on time and so were fired.", "category": "Logic-Grid", "date": "07/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe four friends once decided to become journalists. They applied to the National News Channel and got the jobs. On their first day at work, each of them was asked to interview a different famous personality at a different time. In their excitement, the four friends accidentally mixed the papers which contained the information regarding which famous personality was to be interviewed by whom and at what time. The papers also contained details regarding the different professions of these famous personalities and their different famous achievements which have contributed towards the development of their country. All they could remember were the following bits of information. Help them clear-up the confusion on time by correctly matching each friend to the famous personality she has to interview, at what time she has to conduct the interview and what is the profession of each of the famous personalities and what were their biggest achievements.\n\r\nFriends: Dis, Dip, Raj, Rich\r\nFamous personalities: Mr. Jag, Miss Sam, Mr. Sri, Mr. Bala\r\nProfessions: Hydro-engineer, Politician, Civil Engineer, Mechanical Engineer\r\nAchievements: National highways, Canals, Housing to poor, Sky Train\r\nTime of interview: 10 a.m, 2 p.m, 9 a.m, 3.30 p.m\n\r\n1. Dis was very excited, as she had to interview the man who was the brain behind her favourite Sky Train.\r\n2. Rich's appointment with the politician was the last appointment of the day.\r\n3. The only woman hydro-engineer of the country was to be interviewed at 10 a.m.\r\n4. Raj, who hated hot weather, was upset that her interview assignment was scheduled in the afternoon.\r\n5. Mr. Bala hastened the traffic flow across the country by building many National Highways.\r\n6. Sri was not the politician and the mechanical engineer did not build highways.\r\n7. The poor people are thankful for the houses Jag provided them. \r\n8. The politician did not build any highways.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDis was to interview Mr Sri, the mechanical engineer responsible for launching Sky Trains, at 9 a.m.\r\nDip was all set to meet Miss Sam, who was the hydro-engineer responsible for building many canal and dams, at 10 a.m. \r\nRaj had to interview the civil engineer responsible for National Highways, Mr. Bala, at 2 p.m., \r\nand Rich was to meet Mr. Jag, the politician who gave homes to the poor, at 3:30 p.m\n\r\nUnfortunately, the friends could not clear-up the mess on time and so were fired.\n<|im_start|>answer\nDis was to interview Mr Sri, the mechanical engineer responsible for launching Sky Trains, at 9 a.m.\r\nDip was all set to meet Miss Sam, who was the hydro-engineer responsible for building many canal and dams, at 10 a.m. \r\nRaj had to interview the civil engineer responsible for National Highways, Mr. Bala, at 2 p.m., \r\nand Rich was to meet Mr. Jag, the politician who gave homes to the poor, at 3:30 p.m\n\r\nUnfortunately, the friends could not clear-up the mess on time and so were fired.\n<|im_end|>" }, { "id": "#29344", "title": "Ladder", "fun": 2.7600000000000002, "difficulty": 1.87, "author": "Crazycriely", "desc": "Assume the ladder is NOT an extension ladder.\r\nA 25 ft ladder is placed with its foot 7 ft away from a building. If the top of the ladder slips down 4 ft, how many feet will the bottom slide out?", "hint": "It is not 4 ft. Try some Pythagorean theoreming.", "answer": "8 ft\n\r\nFirst triangle: 7 squared + 24 squared = 25 squared, so the top of the ladder was 24 feet high. \n\r\n24 - 4= 20. 25 squared - 20 squared = 225. Take the square root of that and you get 15: the new base of the triangle. 15 - 7 (the old base) = 8ft", "category": "Math", "date": "03/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAssume the ladder is NOT an extension ladder.\r\nA 25 ft ladder is placed with its foot 7 ft away from a building. If the top of the ladder slips down 4 ft, how many feet will the bottom slide out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8 ft\n\r\nFirst triangle: 7 squared + 24 squared = 25 squared, so the top of the ladder was 24 feet high. \n\r\n24 - 4= 20. 25 squared - 20 squared = 225. Take the square root of that and you get 15: the new base of the triangle. 15 - 7 (the old base) = 8ft\n<|im_start|>answer\n8 ft\n\r\nFirst triangle: 7 squared + 24 squared = 25 squared, so the top of the ladder was 24 feet high. \n\r\n24 - 4= 20. 25 squared - 20 squared = 225. Take the square root of that and you get 15: the new base of the triangle. 15 - 7 (the old base) = 8ft\n<|im_end|>" }, { "id": "#27782", "title": "Christmas Choir", "fun": 2.7600000000000002, "difficulty": 1.18, "author": "Rob2003", "desc": "The local church is planning a special Christmas choir for their Christmas Eve service this year. This is a new program for the church and they have high hopes for its success. The conductor has designed a creative program using traditional Christmas carols and the singers have practiced for weeks. Four of the singers have solo parts in four different songs. Determine the full name of each soloist, which part of the choir each is in, and the name of the Christmas carol in which each is singing solo.\n\r\nNOTE: Check hint before you start the logic grid\n\r\n1. Sherry Sanford didn't sing the solo part in \"Silent Night.\" Bruce didn't sing the solo part in \"O Holy Night.\" \n\r\n2. The soprano wasn't Ms. Sawyer.\n\r\n3. \"Joy to the World\" was not the solo part that Mr. Smith sang in.\n\r\n4. The tenor sang solo during \"The First Noel.\" Betty was part of the alto section. \n\r\n5. Mr. Short wasn't a tenor. The bass singer, who wasn't Tom, didn't perform a solo part in \"Silent Night.\"\n\r\n6. Bruce's solo part was during \"Joy to the World.\"", "hint": "Female singers cannot be tenor singers and male singers cannot be soprano singers.", "answer": "Betty Sawyer, alto, Silent Night\r\nBruce Short, bass, Joy to the World\r\nSherry Sanford, soprano, O Holy Night\r\nTom Smith, tenor, The First Noel", "category": "Logic-Grid", "date": "12/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe local church is planning a special Christmas choir for their Christmas Eve service this year. This is a new program for the church and they have high hopes for its success. The conductor has designed a creative program using traditional Christmas carols and the singers have practiced for weeks. Four of the singers have solo parts in four different songs. Determine the full name of each soloist, which part of the choir each is in, and the name of the Christmas carol in which each is singing solo.\n\r\nNOTE: Check hint before you start the logic grid\n\r\n1. Sherry Sanford didn't sing the solo part in \"Silent Night.\" Bruce didn't sing the solo part in \"O Holy Night.\" \n\r\n2. The soprano wasn't Ms. Sawyer.\n\r\n3. \"Joy to the World\" was not the solo part that Mr. Smith sang in.\n\r\n4. The tenor sang solo during \"The First Noel.\" Betty was part of the alto section. \n\r\n5. Mr. Short wasn't a tenor. The bass singer, who wasn't Tom, didn't perform a solo part in \"Silent Night.\"\n\r\n6. Bruce's solo part was during \"Joy to the World.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBetty Sawyer, alto, Silent Night\r\nBruce Short, bass, Joy to the World\r\nSherry Sanford, soprano, O Holy Night\r\nTom Smith, tenor, The First Noel\n<|im_start|>answer\nBetty Sawyer, alto, Silent Night\r\nBruce Short, bass, Joy to the World\r\nSherry Sanford, soprano, O Holy Night\r\nTom Smith, tenor, The First Noel\n<|im_end|>" }, { "id": "#300", "title": "Hardware", "fun": 2.7600000000000002, "difficulty": 1.7, "author": "Phyllis", "desc": "A man has just finished painting his house and needs something. He goes to a hardware store and asks for help in finding what he needs. The clerk shows him where the objects are and tells him that they cost $1 each. The man says: \"I'm taking 600, so here's $3.\" What did he buy?", "hint": "How do you find a house?", "answer": "His house number.", "category": "Logic", "date": "02/24/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man has just finished painting his house and needs something. He goes to a hardware store and asks for help in finding what he needs. The clerk shows him where the objects are and tells him that they cost $1 each. The man says: \"I'm taking 600, so here's $3.\" What did he buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHis house number.\n<|im_start|>answer\nHis house number.\n<|im_end|>" }, { "id": "#47249", "title": "The Wine Cellar's Will", "fun": 2.7600000000000002, "difficulty": 1.43, "author": "fishmed", "desc": "There once was a somewhat eccentric wine seller who died, leaving three sons behind him. He also left 7 full barrels of wine, 7 half-full barrels of wine, and 7 empty wine barrels. Being somewhat eccentric, he noted in his will that each son was to receive the same number of full barrels, half-full barrels, and empty barrels. How is this possible?", "hint": "No hint available.", "answer": "Take two half-full barrels and empty them into two other half-full barrels, making them full barrels. You then have 9 full barrels, 3 half-full barrels, and 9 empty barrels, which are all divisible by 3, giving each son 3 full barrels, 1 half-full barrel, and 3 empty barrels.", "category": "Logic", "date": "06/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere once was a somewhat eccentric wine seller who died, leaving three sons behind him. He also left 7 full barrels of wine, 7 half-full barrels of wine, and 7 empty wine barrels. Being somewhat eccentric, he noted in his will that each son was to receive the same number of full barrels, half-full barrels, and empty barrels. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake two half-full barrels and empty them into two other half-full barrels, making them full barrels. You then have 9 full barrels, 3 half-full barrels, and 9 empty barrels, which are all divisible by 3, giving each son 3 full barrels, 1 half-full barrel, and 3 empty barrels.\n<|im_start|>answer\nTake two half-full barrels and empty them into two other half-full barrels, making them full barrels. You then have 9 full barrels, 3 half-full barrels, and 9 empty barrels, which are all divisible by 3, giving each son 3 full barrels, 1 half-full barrel, and 3 empty barrels.\n<|im_end|>" }, { "id": "#7474", "title": "Four Dozen Campers", "fun": 2.7600000000000002, "difficulty": 1.82, "author": "hprulz", "desc": "The 4 dozen campers in the junior division live in 6 differently colored cabins along Miller's Pond. The smallest cabin has 6 campers, and the orange cabin is the largest with 10 campers. The yellow and green cabins are the only cabins with the same number of campers. The 13 youngest campers are in the red and blue cabins with the least number of campers. The purple cabin has 2 more campers than the blue cabin. \n\r\nHow many campers are in each cabin?", "hint": "You can make a chart. Work backwards to get some of the information.", "answer": "Orange = 10 \r\nPurple = 9 \r\nYellow = 8 \r\nGreen = 8 \r\nBlue = 7 \r\nRed = 6 \n\r\nFrom the second and fourth lines, you know that one cabin contains 10 campers and the two smallest cabins contain 7 and 6 campers. This leaves 48 - 10 - 7 - 6 = 25 campers unaccounted for. You know that the yellow and green cabins have the same number of campers (Statement 3) and that the purple cabin has either 8 (6+2) or 9 (7+2) campers (Statement 5). There can't be 8 in the purple cabin because that would leave 17 for the yellow and green cabins, which doesn't divide by two evenly. Therefore there are 9 campers in the purple cabin leaving 8 in each of the yellow and green cabins. This also means that there are 7 campers in the blue cabin, from the last statement. All that's left is the red cabin, with 6 campers.", "category": "Math", "date": "09/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 4 dozen campers in the junior division live in 6 differently colored cabins along Miller's Pond. The smallest cabin has 6 campers, and the orange cabin is the largest with 10 campers. The yellow and green cabins are the only cabins with the same number of campers. The 13 youngest campers are in the red and blue cabins with the least number of campers. The purple cabin has 2 more campers than the blue cabin. \n\r\nHow many campers are in each cabin?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOrange = 10 \r\nPurple = 9 \r\nYellow = 8 \r\nGreen = 8 \r\nBlue = 7 \r\nRed = 6 \n\r\nFrom the second and fourth lines, you know that one cabin contains 10 campers and the two smallest cabins contain 7 and 6 campers. This leaves 48 - 10 - 7 - 6 = 25 campers unaccounted for. You know that the yellow and green cabins have the same number of campers (Statement 3) and that the purple cabin has either 8 (6+2) or 9 (7+2) campers (Statement 5). There can't be 8 in the purple cabin because that would leave 17 for the yellow and green cabins, which doesn't divide by two evenly. Therefore there are 9 campers in the purple cabin leaving 8 in each of the yellow and green cabins. This also means that there are 7 campers in the blue cabin, from the last statement. All that's left is the red cabin, with 6 campers.\n<|im_start|>answer\nOrange = 10 \r\nPurple = 9 \r\nYellow = 8 \r\nGreen = 8 \r\nBlue = 7 \r\nRed = 6 \n\r\nFrom the second and fourth lines, you know that one cabin contains 10 campers and the two smallest cabins contain 7 and 6 campers. This leaves 48 - 10 - 7 - 6 = 25 campers unaccounted for. You know that the yellow and green cabins have the same number of campers (Statement 3) and that the purple cabin has either 8 (6+2) or 9 (7+2) campers (Statement 5). There can't be 8 in the purple cabin because that would leave 17 for the yellow and green cabins, which doesn't divide by two evenly. Therefore there are 9 campers in the purple cabin leaving 8 in each of the yellow and green cabins. This also means that there are 7 campers in the blue cabin, from the last statement. All that's left is the red cabin, with 6 campers.\n<|im_end|>" }, { "id": "#27197", "title": "Pizza Palace", "fun": 2.7600000000000002, "difficulty": 0.79, "author": "Shawnheyhey123", "desc": "One day Betty, Katie, Sean, Dan, and Paulina decided to go to Pizza Palace. Everyone ordered a different pizza with a different crust. Figure out which kid picked what pizza (cheese, pepperoni, onions, anchovies, or pepper) and with what kind of crust (thick, thin, sour, sweet, or no crust).\n\r\n1: The cheese pizza has some kind of crust.\n\r\n2: Betty hates onions, anchovies, and crusts.\n\r\n3: The name of the person that had the pepperoni pizza comes third alphabetically among the 5 kids.\n\r\n4: The girls hate sour and thick crusts.\n\r\n5: The cheese pizza didn't have a sweet or sour crust.\n\r\n6: Sean hates onions, anchovies, and peppers.\n\r\n7: Dan's allergic to onions and peppers.\n\r\n8: Katie had the sweet crust.", "hint": "No hint available.", "answer": "Betty - Pepper - No Crust\r\nKatie - Pepperoni - Sweet\r\nSean - Cheese - Thick\r\nDan - Anchovies - Sour\r\nPaulina - Onions - Thin", "category": "Logic-Grid", "date": "11/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day Betty, Katie, Sean, Dan, and Paulina decided to go to Pizza Palace. Everyone ordered a different pizza with a different crust. Figure out which kid picked what pizza (cheese, pepperoni, onions, anchovies, or pepper) and with what kind of crust (thick, thin, sour, sweet, or no crust).\n\r\n1: The cheese pizza has some kind of crust.\n\r\n2: Betty hates onions, anchovies, and crusts.\n\r\n3: The name of the person that had the pepperoni pizza comes third alphabetically among the 5 kids.\n\r\n4: The girls hate sour and thick crusts.\n\r\n5: The cheese pizza didn't have a sweet or sour crust.\n\r\n6: Sean hates onions, anchovies, and peppers.\n\r\n7: Dan's allergic to onions and peppers.\n\r\n8: Katie had the sweet crust.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBetty - Pepper - No Crust\r\nKatie - Pepperoni - Sweet\r\nSean - Cheese - Thick\r\nDan - Anchovies - Sour\r\nPaulina - Onions - Thin\n<|im_start|>answer\nBetty - Pepper - No Crust\r\nKatie - Pepperoni - Sweet\r\nSean - Cheese - Thick\r\nDan - Anchovies - Sour\r\nPaulina - Onions - Thin\n<|im_end|>" }, { "id": "#29718", "title": "Math Competition", "fun": 2.7600000000000002, "difficulty": 2.26, "author": "bigSWAFF_69_", "desc": "Felipe's school is hosting a math competition against other schools in the same district. Each school can only allow 10 students to compete. Felipe and his classmates are taking tests to determine the 10 best math students to send. Felipe did well, but tied with John Roy for the last spot. His teacher decided to set-up a one-problem challenge, whoever got it right the fastest would win.\n\r\nKnowing that \"H\" is equal to 10, and T is half of M, how could MATH be 42, TEAM be 40, and MEET be 37?", "hint": "No hint available.", "answer": "MATH: 14 + 11 + 7 + 10 =42\r\nTEAM: 7+8+11+14 =40\r\nMEET: 14+8+8+7=37\n\r\n(H=10; E=8; T=7; M=14; A=11)\n\n\r\nFelipe answered his question just seconds before John Roy, sending him to the competition.", "category": "Math", "date": "04/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFelipe's school is hosting a math competition against other schools in the same district. Each school can only allow 10 students to compete. Felipe and his classmates are taking tests to determine the 10 best math students to send. Felipe did well, but tied with John Roy for the last spot. His teacher decided to set-up a one-problem challenge, whoever got it right the fastest would win.\n\r\nKnowing that \"H\" is equal to 10, and T is half of M, how could MATH be 42, TEAM be 40, and MEET be 37?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMATH: 14 + 11 + 7 + 10 =42\r\nTEAM: 7+8+11+14 =40\r\nMEET: 14+8+8+7=37\n\r\n(H=10; E=8; T=7; M=14; A=11)\n\n\r\nFelipe answered his question just seconds before John Roy, sending him to the competition.\n<|im_start|>answer\nMATH: 14 + 11 + 7 + 10 =42\r\nTEAM: 7+8+11+14 =40\r\nMEET: 14+8+8+7=37\n\r\n(H=10; E=8; T=7; M=14; A=11)\n\n\r\nFelipe answered his question just seconds before John Roy, sending him to the competition.\n<|im_end|>" }, { "id": "#23203", "title": "Movie Rentals", "fun": 2.75, "difficulty": 2.4, "author": "kellgo", "desc": "Five people walk into a video store: three girls - Veronica, Sydney and Nina - and two boys - Sean & Nicholas. Each person will select a movie and a snack and go home to watch their chosen selection with someone they love. It's your job, as an employee of the video store, to know who selects which movie, snack, and with whom they will watch their movie, which is also the person/people that accompanied them to the movie store. Yes, you're a nosy employee but that's your job. \n\r\nThe movie store was bustling with happy people all in search of the perfect movie:\n\r\nNina was running around the store searching for the new release she really wanted to see. When her Dad finally found the cartoon she squealed with joy.\n\r\nThe squeal got the attention of Nicholas who was internally squealing when he found the movie he was looking for in the suspense section. \n\n\r\nA helpful girlfriend of one of the guys held onto the movie Leo's Life while he got his snack, that wasn't chocolate or buttered. \n\r\nVeronica had just had a fight with her boyfriend and it was her sister's idea for Veronica and her to get a comedy to try and help cheer her up. \n\r\nVeronica rolled her eyes, in jealousy, at the girl and her boyfriend who planned to watch the thriller movie, \"Where Are You?\" \n\r\nThe person who rented \"Purple Grass\" got huge buttered popcorn - enough to share with her two movie buddies. \n\r\nSecond in line to get regular popcorn were the people who rented the movie Onion Run. \n\r\nHaving just eaten dinner, the brothers decided not to get popcorn, the chocolate M&M's, or nachos.\n\r\nSean walked by the suspense movie poster \"Yesterday\" while munching on his nachos. \n\r\nEveryone went home and enjoyed their snacks and their movies.", "hint": "No hint available.", "answer": "Veronica/Comedy/Popcorn/Onion Run/Sister\n\r\nSean/Drama/Nachos/Leo's Life/Girlfriend\n\r\nNicholas/Suspense/Coke/Yesterday/Brother\n\r\nSydney/Thriller/M&M's/Where are you?/Boyfriend\n\r\nNina/Cartoon/Buttered Popcorn/Purple Grass/Mom & Dad", "category": "Logic-Grid", "date": "05/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people walk into a video store: three girls - Veronica, Sydney and Nina - and two boys - Sean & Nicholas. Each person will select a movie and a snack and go home to watch their chosen selection with someone they love. It's your job, as an employee of the video store, to know who selects which movie, snack, and with whom they will watch their movie, which is also the person/people that accompanied them to the movie store. Yes, you're a nosy employee but that's your job. \n\r\nThe movie store was bustling with happy people all in search of the perfect movie:\n\r\nNina was running around the store searching for the new release she really wanted to see. When her Dad finally found the cartoon she squealed with joy.\n\r\nThe squeal got the attention of Nicholas who was internally squealing when he found the movie he was looking for in the suspense section. \n\n\r\nA helpful girlfriend of one of the guys held onto the movie Leo's Life while he got his snack, that wasn't chocolate or buttered. \n\r\nVeronica had just had a fight with her boyfriend and it was her sister's idea for Veronica and her to get a comedy to try and help cheer her up. \n\r\nVeronica rolled her eyes, in jealousy, at the girl and her boyfriend who planned to watch the thriller movie, \"Where Are You?\" \n\r\nThe person who rented \"Purple Grass\" got huge buttered popcorn - enough to share with her two movie buddies. \n\r\nSecond in line to get regular popcorn were the people who rented the movie Onion Run. \n\r\nHaving just eaten dinner, the brothers decided not to get popcorn, the chocolate M&M's, or nachos.\n\r\nSean walked by the suspense movie poster \"Yesterday\" while munching on his nachos. \n\r\nEveryone went home and enjoyed their snacks and their movies.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nVeronica/Comedy/Popcorn/Onion Run/Sister\n\r\nSean/Drama/Nachos/Leo's Life/Girlfriend\n\r\nNicholas/Suspense/Coke/Yesterday/Brother\n\r\nSydney/Thriller/M&M's/Where are you?/Boyfriend\n\r\nNina/Cartoon/Buttered Popcorn/Purple Grass/Mom & Dad\n<|im_start|>answer\nVeronica/Comedy/Popcorn/Onion Run/Sister\n\r\nSean/Drama/Nachos/Leo's Life/Girlfriend\n\r\nNicholas/Suspense/Coke/Yesterday/Brother\n\r\nSydney/Thriller/M&M's/Where are you?/Boyfriend\n\r\nNina/Cartoon/Buttered Popcorn/Purple Grass/Mom & Dad\n<|im_end|>" }, { "id": "#38446", "title": "Another Chess Tournament", "fun": 2.75, "difficulty": 1.69, "author": "smarty__blondy", "desc": "Two teams, A and B, went to a chess tournament. Team A consists of Albert, Allen and Anderson, and team B consists of Billy, Bob and Benton. From the result of past matches, it's expected that Albert can beat Bob, who can beat Anderson, who, in turn, can beat Benton. However, none of the mentioned pairs became opponents.\n\r\nWho is whose opponent?", "hint": "No hint available.", "answer": "Bob's opponent is neither Albert nor Anderson, and has to be Allen.\r\nBenton's opponent is not Anderson, and has to be Albert.\r\nFinally, Billy's opponent is Anderson.", "category": "Logic", "date": "09/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo teams, A and B, went to a chess tournament. Team A consists of Albert, Allen and Anderson, and team B consists of Billy, Bob and Benton. From the result of past matches, it's expected that Albert can beat Bob, who can beat Anderson, who, in turn, can beat Benton. However, none of the mentioned pairs became opponents.\n\r\nWho is whose opponent?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob's opponent is neither Albert nor Anderson, and has to be Allen.\r\nBenton's opponent is not Anderson, and has to be Albert.\r\nFinally, Billy's opponent is Anderson.\n<|im_start|>answer\nBob's opponent is neither Albert nor Anderson, and has to be Allen.\r\nBenton's opponent is not Anderson, and has to be Albert.\r\nFinally, Billy's opponent is Anderson.\n<|im_end|>" }, { "id": "#33251", "title": "Crossing The River", "fun": 2.75, "difficulty": 1.54, "author": "grungy49", "desc": "The five friends were having a great time. It was Tom's idea to go bushwalking and they all had enjoyed it, but they were starting to tire when they encountered a problem close to their houses. Blocking their path was a river, and they had to cross it or walk the three hours back to their homes. \r\nThey decided it would take too long to walk back the three hours back home, so they decided to cross the river.\n\r\nThey each used a different method to cross the river, and they each took a different amount of time. By the time they had finished crossing the river it was starting to get late so they decided to have a race home.\r\nYour job is to work out the first and last names of the five friends, how they crossed the river, the time they took to cross, and what they each placed in the race home.\n\r\nFirst Names: Tom, Jake, Chris, Sally, Damian\r\nLast Names: Brundwick, Thompson, Brown, Simpson, Abbott\r\nMethod of Crossing: vine, log, bridge, boat, swim\r\nTime Taken: 15 minutes, 20 minutes, 30 minutes, 45 minutes, 60 minutes\r\nPlacings on Race Home: 1st, 2nd, 3rd, 4th, 5th\n\r\nBut, of course - it would be impossible to guess so I'll include a few clues : ) \n\r\n1. Sally was not the bravest in the group so she decided to walk around and cross by using the bridge - however it took a fair amount of time and she took more than half an hour to cross.\n\r\n2. Chris had been watching far too much Tarzan and decided to cross by swinging across the vine. This method was very dangerous, but also the quickest. Chris wasn't just a daredevil - he was an extremely fast runner and smashed everybody in the race home.\n\r\n3. Tom was a hopeless swimmer but he could run pretty fast and he finished second in the race home.\n\r\n4. Damian wasn't a daredevil so he ended up crossing the river safely in a nice small boat. However, the boat was rather slow and it took Damian three quarters of an hour to reach the other side.\n\r\n5. Jake Abbott practiced in his swimming pool every day - maybe this was the reason he swam across the entire river in just 20 minutes.\n\r\n6. The last name of the person who took the longest to cross the river was Brundwick. This person did not finish last in the race home.\n\r\n7. Jake's last name was not Simpson. The last name of the person who finished last in the race home was Simpson.\n\r\n8. The person who took an hour to cross the river did not finish fourth in the race home. The surname of the person who took half an hour to cross the river was Brown.\n\r\nUsing these clues, can you determine all of the details?", "hint": "No hint available.", "answer": "Tom Brown crossed using the log, took 30 minutes and finished 2nd on the race home.\n\r\nJake Abbott crossed by swimming, took 20 minutes and finished 4th on the race home.\n\r\nChris Thompson crossed using the vine, took 15 minutes and finished 1st on the race home.\n\r\nSally Brundwick crossed using the bridge, took 60 minutes and finished 3rd on the race home.\n\r\nDamian Simpson crossed using the boat, took 45 minutes and finished 5th on the race home.", "category": "Logic-Grid", "date": "09/29/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe five friends were having a great time. It was Tom's idea to go bushwalking and they all had enjoyed it, but they were starting to tire when they encountered a problem close to their houses. Blocking their path was a river, and they had to cross it or walk the three hours back to their homes. \r\nThey decided it would take too long to walk back the three hours back home, so they decided to cross the river.\n\r\nThey each used a different method to cross the river, and they each took a different amount of time. By the time they had finished crossing the river it was starting to get late so they decided to have a race home.\r\nYour job is to work out the first and last names of the five friends, how they crossed the river, the time they took to cross, and what they each placed in the race home.\n\r\nFirst Names: Tom, Jake, Chris, Sally, Damian\r\nLast Names: Brundwick, Thompson, Brown, Simpson, Abbott\r\nMethod of Crossing: vine, log, bridge, boat, swim\r\nTime Taken: 15 minutes, 20 minutes, 30 minutes, 45 minutes, 60 minutes\r\nPlacings on Race Home: 1st, 2nd, 3rd, 4th, 5th\n\r\nBut, of course - it would be impossible to guess so I'll include a few clues : ) \n\r\n1. Sally was not the bravest in the group so she decided to walk around and cross by using the bridge - however it took a fair amount of time and she took more than half an hour to cross.\n\r\n2. Chris had been watching far too much Tarzan and decided to cross by swinging across the vine. This method was very dangerous, but also the quickest. Chris wasn't just a daredevil - he was an extremely fast runner and smashed everybody in the race home.\n\r\n3. Tom was a hopeless swimmer but he could run pretty fast and he finished second in the race home.\n\r\n4. Damian wasn't a daredevil so he ended up crossing the river safely in a nice small boat. However, the boat was rather slow and it took Damian three quarters of an hour to reach the other side.\n\r\n5. Jake Abbott practiced in his swimming pool every day - maybe this was the reason he swam across the entire river in just 20 minutes.\n\r\n6. The last name of the person who took the longest to cross the river was Brundwick. This person did not finish last in the race home.\n\r\n7. Jake's last name was not Simpson. The last name of the person who finished last in the race home was Simpson.\n\r\n8. The person who took an hour to cross the river did not finish fourth in the race home. The surname of the person who took half an hour to cross the river was Brown.\n\r\nUsing these clues, can you determine all of the details?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTom Brown crossed using the log, took 30 minutes and finished 2nd on the race home.\n\r\nJake Abbott crossed by swimming, took 20 minutes and finished 4th on the race home.\n\r\nChris Thompson crossed using the vine, took 15 minutes and finished 1st on the race home.\n\r\nSally Brundwick crossed using the bridge, took 60 minutes and finished 3rd on the race home.\n\r\nDamian Simpson crossed using the boat, took 45 minutes and finished 5th on the race home.\n<|im_start|>answer\nTom Brown crossed using the log, took 30 minutes and finished 2nd on the race home.\n\r\nJake Abbott crossed by swimming, took 20 minutes and finished 4th on the race home.\n\r\nChris Thompson crossed using the vine, took 15 minutes and finished 1st on the race home.\n\r\nSally Brundwick crossed using the bridge, took 60 minutes and finished 3rd on the race home.\n\r\nDamian Simpson crossed using the boat, took 45 minutes and finished 5th on the race home.\n<|im_end|>" }, { "id": "#39637", "title": "Dieters' Club", "fun": 2.75, "difficulty": 2.45, "author": "pokpic", "desc": "A new diet club was started in Phattsburg, Fatslyvania. The first five members to join the club are named Biggs, Gross, House, Piles, and Tubbs. Two of them are men named Barney and Whalen, while three of them are ladies named Bertha, Fanny, Fatima. Each started out at a different weight: 300 lbs., 275 lbs., 250 lbs., 225 lbs., and 200 lbs. After 6 months each dieter had lost a different amount of weight: 125 lbs., 100 lbs., 75 lbs., 50 lbs., and 25 lbs. From the information given below, determine each person's first and last name, the weight they started at and how much weight they each lost.\n\r\nLast Names: Biggs, Gross, House, Piles, and Tubbs\n\r\nFirst Names: Barney, Bertha, Fanny, Fatima, and Whalen.\n\r\nStarting Weights: 300 lbs., 275 lbs., 250 lbs., 225 lbs., and 200 lbs.\n\r\nWeight Lost: 125 lbs., 100 lbs., 75 lbs., 50 lbs., 25 lbs.\n\n\r\n1. At the beginning of the diet Whalen weighed less than than Mr. Piles and the woman who lost the most weight in the whole group, but more than Ms. House and the woman who lost the least amount of weight in the whole group.\n\r\n2. Barney did not lose exactly 75 lbs. and he was not the same weight as Ms. Gross at the end of the diet.\n\r\n3. Mr. Tubbs at the beginning of the diet, weighed more than Ms. Biggs and less than Fanny.\n\r\n4. Fatima started out lighter but lost twice as much weight as Ms. Biggs.", "hint": "No hint available.", "answer": "Barney Piles weighed 300 pounds at the beginning of the diet and lost 100 pounds.\n\r\nFanny Gross weighed 275 pounds at the beginning of the diet and lost 125 pounds.\n\r\nWhalen Tubbs weighed 250 pounds at the beginning of the diet and lost 75 pounds.\n\r\nBertha Biggs weighed 225 pounds at the beginning of the diet and lost 25 pounds.\n\r\nFatima House weighed 200 pounds at the beginning of the diet and lost 50 pounds.", "category": "Logic-Grid", "date": "12/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA new diet club was started in Phattsburg, Fatslyvania. The first five members to join the club are named Biggs, Gross, House, Piles, and Tubbs. Two of them are men named Barney and Whalen, while three of them are ladies named Bertha, Fanny, Fatima. Each started out at a different weight: 300 lbs., 275 lbs., 250 lbs., 225 lbs., and 200 lbs. After 6 months each dieter had lost a different amount of weight: 125 lbs., 100 lbs., 75 lbs., 50 lbs., and 25 lbs. From the information given below, determine each person's first and last name, the weight they started at and how much weight they each lost.\n\r\nLast Names: Biggs, Gross, House, Piles, and Tubbs\n\r\nFirst Names: Barney, Bertha, Fanny, Fatima, and Whalen.\n\r\nStarting Weights: 300 lbs., 275 lbs., 250 lbs., 225 lbs., and 200 lbs.\n\r\nWeight Lost: 125 lbs., 100 lbs., 75 lbs., 50 lbs., 25 lbs.\n\n\r\n1. At the beginning of the diet Whalen weighed less than than Mr. Piles and the woman who lost the most weight in the whole group, but more than Ms. House and the woman who lost the least amount of weight in the whole group.\n\r\n2. Barney did not lose exactly 75 lbs. and he was not the same weight as Ms. Gross at the end of the diet.\n\r\n3. Mr. Tubbs at the beginning of the diet, weighed more than Ms. Biggs and less than Fanny.\n\r\n4. Fatima started out lighter but lost twice as much weight as Ms. Biggs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBarney Piles weighed 300 pounds at the beginning of the diet and lost 100 pounds.\n\r\nFanny Gross weighed 275 pounds at the beginning of the diet and lost 125 pounds.\n\r\nWhalen Tubbs weighed 250 pounds at the beginning of the diet and lost 75 pounds.\n\r\nBertha Biggs weighed 225 pounds at the beginning of the diet and lost 25 pounds.\n\r\nFatima House weighed 200 pounds at the beginning of the diet and lost 50 pounds.\n<|im_start|>answer\nBarney Piles weighed 300 pounds at the beginning of the diet and lost 100 pounds.\n\r\nFanny Gross weighed 275 pounds at the beginning of the diet and lost 125 pounds.\n\r\nWhalen Tubbs weighed 250 pounds at the beginning of the diet and lost 75 pounds.\n\r\nBertha Biggs weighed 225 pounds at the beginning of the diet and lost 25 pounds.\n\r\nFatima House weighed 200 pounds at the beginning of the diet and lost 50 pounds.\n<|im_end|>" }, { "id": "#28602", "title": "The Random Family, Pt. 1: Gramma Random", "fun": 2.75, "difficulty": 2.02, "author": "TalkingOptimist", "desc": "Gramma Random has 5 grandchildren (girls Dora and Gwenevere; boys Alex, Nathan, & Gabriel) for whom she likes to fix their favorite foods on their respective birthdays. Can you determine what she makes for whom and when?\n\r\nGramma Random:\r\n1. Does not do baking while school is out for the summer.\r\n2. Finds it odd that, despite the fact Nathan loves chocolate, and Alex loves oatmeal, neither likes her no-bake chocolate oatmeal cookies.\r\n3. Also finds it odd that neither Dora nor Gwen cares for her mashed potatoes, which she thinks it's silly to make so close to Memorial Day, but does it anyway.\r\n4. Nicknamed Gabe \"Pizza the Hut\" because all he ever wants is pizza, and loaded with meat at that!\r\n5. Is grateful that she doesn't have to make bacon for Nathan's birthday, because she doesn't eat meat before Easter.\r\n6. Is grateful that her granddaughter (whose birthday is in August) likes a treat that doesn't have to be fried.\r\n7. Thinks it's exciting that Gwenevere was born on Fathers' Day.\n\r\nNote, for unclear dates or holidays:\r\nSchool lets out in early May, and usually resumes the last week in August.\r\nEaster is in early April.\r\nLabor Day is the first Monday in September.\r\nMemorial Day is the last Monday in May.\r\nFather's Day is the 3rd Sunday in June.", "hint": "No hint available.", "answer": "Gramma Random:\r\nBakes bread for Nathan on March 7.\r\nMashes potatoes for Alex on May 28.\r\nFries bacon for Gwenevere on June 20.\r\nMakes chocolate-oatmeal no-bake cookies for Dora on August 12.\r\nMakes pizza, loaded with meat, for Gabe on September 6.", "category": "Logic-Grid", "date": "02/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGramma Random has 5 grandchildren (girls Dora and Gwenevere; boys Alex, Nathan, & Gabriel) for whom she likes to fix their favorite foods on their respective birthdays. Can you determine what she makes for whom and when?\n\r\nGramma Random:\r\n1. Does not do baking while school is out for the summer.\r\n2. Finds it odd that, despite the fact Nathan loves chocolate, and Alex loves oatmeal, neither likes her no-bake chocolate oatmeal cookies.\r\n3. Also finds it odd that neither Dora nor Gwen cares for her mashed potatoes, which she thinks it's silly to make so close to Memorial Day, but does it anyway.\r\n4. Nicknamed Gabe \"Pizza the Hut\" because all he ever wants is pizza, and loaded with meat at that!\r\n5. Is grateful that she doesn't have to make bacon for Nathan's birthday, because she doesn't eat meat before Easter.\r\n6. Is grateful that her granddaughter (whose birthday is in August) likes a treat that doesn't have to be fried.\r\n7. Thinks it's exciting that Gwenevere was born on Fathers' Day.\n\r\nNote, for unclear dates or holidays:\r\nSchool lets out in early May, and usually resumes the last week in August.\r\nEaster is in early April.\r\nLabor Day is the first Monday in September.\r\nMemorial Day is the last Monday in May.\r\nFather's Day is the 3rd Sunday in June.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGramma Random:\r\nBakes bread for Nathan on March 7.\r\nMashes potatoes for Alex on May 28.\r\nFries bacon for Gwenevere on June 20.\r\nMakes chocolate-oatmeal no-bake cookies for Dora on August 12.\r\nMakes pizza, loaded with meat, for Gabe on September 6.\n<|im_start|>answer\nGramma Random:\r\nBakes bread for Nathan on March 7.\r\nMashes potatoes for Alex on May 28.\r\nFries bacon for Gwenevere on June 20.\r\nMakes chocolate-oatmeal no-bake cookies for Dora on August 12.\r\nMakes pizza, loaded with meat, for Gabe on September 6.\n<|im_end|>" }, { "id": "#23479", "title": "Albert's Dogs", "fun": 2.75, "difficulty": 1.45, "author": "Philly", "desc": "Albert is a keen dog admirer and over the years has had a number of dogs. He has had an Alsatian, a Dalmatian, a Poodle and a Great Dane, but not necessarily in that order. Albert had Jamie first. The Dalmatian was an adored pet before the Great Dane. Sammy, the Alsatian, was the second dog Albert loved. Whitney was housed before the Poodle and Jimmy was not a Great Dane. Can you tell each of the dogs' name and the order in which Albert had them?", "hint": "No hint available.", "answer": "Albert had Jamie the Dalmatian first, then Sammy the Alsatian, Whitney the Great Dane and finally, Jimmy the Poodle.", "category": "Logic", "date": "06/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlbert is a keen dog admirer and over the years has had a number of dogs. He has had an Alsatian, a Dalmatian, a Poodle and a Great Dane, but not necessarily in that order. Albert had Jamie first. The Dalmatian was an adored pet before the Great Dane. Sammy, the Alsatian, was the second dog Albert loved. Whitney was housed before the Poodle and Jimmy was not a Great Dane. Can you tell each of the dogs' name and the order in which Albert had them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlbert had Jamie the Dalmatian first, then Sammy the Alsatian, Whitney the Great Dane and finally, Jimmy the Poodle.\n<|im_start|>answer\nAlbert had Jamie the Dalmatian first, then Sammy the Alsatian, Whitney the Great Dane and finally, Jimmy the Poodle.\n<|im_end|>" }, { "id": "#24111", "title": "Wildcats", "fun": 2.75, "difficulty": 2.0, "author": "Palsha", "desc": "Five members of the Wildcats baseball team are listed below, complete with their batting averages and current number of stolen bases. Below are some hints to help you figure out who plays which positions and their stats.\n\r\n1) The catcher, not Billsly or Lewis, has fewer stolen bases than the player batting .309.\r\n2) Lewis's batting average is .020 higher than the shortstop's.\r\n3) The player batting .240 has the most stolen bases.\r\n4) Atkins has fewer stolen bases than Johnston, but neither has three.\r\n5) The center fielder leads in one statistic and is second in the other.\r\n6) Lewis, who hits higher than Billsly and Downey, has stolen seven bases so far this year.\r\n7) Downey, the pitcher, is last in one statistic and next to last in the other.", "hint": "No hint available.", "answer": "1) Atkins was catcher, averaged .279, and stole 2 bases.\r\n2) Billsly was at shortstop, averaged .240, and stole 9 bases.\r\n3) Downey was pitcher, averaged .198, and stole 3 bases.\r\n4) Johnston was in center field, averaged .309, and stole 8 bases.\r\n5) Lewis was at second base, averaged .260, and stole 7 bases.", "category": "Logic-Grid", "date": "06/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive members of the Wildcats baseball team are listed below, complete with their batting averages and current number of stolen bases. Below are some hints to help you figure out who plays which positions and their stats.\n\r\n1) The catcher, not Billsly or Lewis, has fewer stolen bases than the player batting .309.\r\n2) Lewis's batting average is .020 higher than the shortstop's.\r\n3) The player batting .240 has the most stolen bases.\r\n4) Atkins has fewer stolen bases than Johnston, but neither has three.\r\n5) The center fielder leads in one statistic and is second in the other.\r\n6) Lewis, who hits higher than Billsly and Downey, has stolen seven bases so far this year.\r\n7) Downey, the pitcher, is last in one statistic and next to last in the other.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Atkins was catcher, averaged .279, and stole 2 bases.\r\n2) Billsly was at shortstop, averaged .240, and stole 9 bases.\r\n3) Downey was pitcher, averaged .198, and stole 3 bases.\r\n4) Johnston was in center field, averaged .309, and stole 8 bases.\r\n5) Lewis was at second base, averaged .260, and stole 7 bases.\n<|im_start|>answer\n1) Atkins was catcher, averaged .279, and stole 2 bases.\r\n2) Billsly was at shortstop, averaged .240, and stole 9 bases.\r\n3) Downey was pitcher, averaged .198, and stole 3 bases.\r\n4) Johnston was in center field, averaged .309, and stole 8 bases.\r\n5) Lewis was at second base, averaged .260, and stole 7 bases.\n<|im_end|>" }, { "id": "#1677", "title": "Arab's Camels", "fun": 2.75, "difficulty": 1.96, "author": "Boddo", "desc": "A rich old Arab has three sons. When he died, he willed his 17 camels to the sons, to be divided as follows:\r\nFirst Son to get 1/2 of the camels,\r\nSecond Son to get 1/3rd of the camels,\r\nThird Son to get 1/9th of the camels.\r\nThe sons are sitting there trying to figure out how this can possibly be done, when a very old wise man goes riding by on his camel. They stop him and ask him to help them solve their problem. Without hesitation he divides the camels properly and continues riding on his way.\r\nHow did he do it?", "hint": "No hint available.", "answer": "The old man temporarily added his camel to the 17, making a total of 18 camels.\r\n1/2 = 9\r\n1/3 = 6\r\n1/9 = 2\r\nFor a total of 17. He then takes his camel back and rides away", "category": "Math", "date": "12/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA rich old Arab has three sons. When he died, he willed his 17 camels to the sons, to be divided as follows:\r\nFirst Son to get 1/2 of the camels,\r\nSecond Son to get 1/3rd of the camels,\r\nThird Son to get 1/9th of the camels.\r\nThe sons are sitting there trying to figure out how this can possibly be done, when a very old wise man goes riding by on his camel. They stop him and ask him to help them solve their problem. Without hesitation he divides the camels properly and continues riding on his way.\r\nHow did he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe old man temporarily added his camel to the 17, making a total of 18 camels.\r\n1/2 = 9\r\n1/3 = 6\r\n1/9 = 2\r\nFor a total of 17. He then takes his camel back and rides away\n<|im_start|>answer\nThe old man temporarily added his camel to the 17, making a total of 18 camels.\r\n1/2 = 9\r\n1/3 = 6\r\n1/9 = 2\r\nFor a total of 17. He then takes his camel back and rides away\n<|im_end|>" }, { "id": "#2027", "title": "Chain Links", "fun": 2.75, "difficulty": 1.8, "author": "Mogmatt16", "desc": "You have four lengths of gold chain. One is made up of five links, two are made of four links, and one is made of three links. These need to be made into one bracelet. The jeweler you have taken them to charges 50 cents to break a link and $1.00 to weld a link back together. You figure it would cost $6.00, but the jeweler finds a cheaper way. What is it and how much will it cost?", "hint": "No hint available.", "answer": "It will only cost $4.50 if you do this: break all the links on the three-link chain and use those to attach all the other three together.", "category": "Logic", "date": "01/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have four lengths of gold chain. One is made up of five links, two are made of four links, and one is made of three links. These need to be made into one bracelet. The jeweler you have taken them to charges 50 cents to break a link and $1.00 to weld a link back together. You figure it would cost $6.00, but the jeweler finds a cheaper way. What is it and how much will it cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will only cost $4.50 if you do this: break all the links on the three-link chain and use those to attach all the other three together.\n<|im_start|>answer\nIt will only cost $4.50 if you do this: break all the links on the three-link chain and use those to attach all the other three together.\n<|im_end|>" }, { "id": "#110", "title": "The Extra Dollar in the Hotel", "fun": 2.75, "difficulty": 2.05, "author": "giraffe", "desc": "Three people check into a hotel. They pay $30 to the manager and go to their room. The manager finds out that the room rate is $25 and gives $5 to the bellboy to return. On the way to the room, the bellboy reasons that $5 would be difficult to share among three people, so he pockets $2 and gives $1 to each person. Now, each person paid $10 and got back $1. So they paid $9 each, totalling $27. The bellboy has $2, totalling $29. Where is the remaining dollar?", "hint": "Count how much money each person started with and how much each person ends up with.", "answer": "Each person paid $9, totalling $27. The manager has $25 and the bellboy has $2. The bellboy's $2 should be added to the manager's $25 or subtracted from the tenants' $27, not added to the tenants' $27.", "category": "Logic", "date": "01/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people check into a hotel. They pay $30 to the manager and go to their room. The manager finds out that the room rate is $25 and gives $5 to the bellboy to return. On the way to the room, the bellboy reasons that $5 would be difficult to share among three people, so he pockets $2 and gives $1 to each person. Now, each person paid $10 and got back $1. So they paid $9 each, totalling $27. The bellboy has $2, totalling $29. Where is the remaining dollar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach person paid $9, totalling $27. The manager has $25 and the bellboy has $2. The bellboy's $2 should be added to the manager's $25 or subtracted from the tenants' $27, not added to the tenants' $27.\n<|im_start|>answer\nEach person paid $9, totalling $27. The manager has $25 and the bellboy has $2. The bellboy's $2 should be added to the manager's $25 or subtracted from the tenants' $27, not added to the tenants' $27.\n<|im_end|>" }, { "id": "#22253", "title": "5=?", "fun": 2.75, "difficulty": 1.08, "author": "sivasankar", "desc": "If 1=5\r\n 2=6\r\n 3=7\r\n 4=8\r\nthen 5=?", "hint": "No hint available.", "answer": "ONE! Since 1=5, 5=1.", "category": "Logic", "date": "04/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 1=5\r\n 2=6\r\n 3=7\r\n 4=8\r\nthen 5=?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nONE! Since 1=5, 5=1.\n<|im_start|>answer\nONE! Since 1=5, 5=1.\n<|im_end|>" }, { "id": "#28008", "title": "Sixteen Horse Race", "fun": 2.75, "difficulty": 1.71, "author": "npf2005", "desc": "There was a 16 horse race in progress at the race course but I missed the finish. I asked 6 of my friends to tell me the number of the winner. These were their answers:\n\r\nIt was an even number.\n\r\nIt was an odd number.\n\r\nIt was a prime number.\n\r\nIt was a square number.\n\r\nThe number had 2 digits.\n\r\nThe number was between 6 and 12.\n\n\r\nOnly 4 of my friends told the truth. Which number was the winner?", "hint": "No hint available.", "answer": "11 is the winner.", "category": "Logic", "date": "01/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a 16 horse race in progress at the race course but I missed the finish. I asked 6 of my friends to tell me the number of the winner. These were their answers:\n\r\nIt was an even number.\n\r\nIt was an odd number.\n\r\nIt was a prime number.\n\r\nIt was a square number.\n\r\nThe number had 2 digits.\n\r\nThe number was between 6 and 12.\n\n\r\nOnly 4 of my friends told the truth. Which number was the winner?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11 is the winner.\n<|im_start|>answer\n11 is the winner.\n<|im_end|>" }, { "id": "#46829", "title": "Five Photographers", "fun": 2.75, "difficulty": 1.95, "author": "scullyx101", "desc": "You are an up-and-coming documentary photographer and would like to gain experience by accompanying a more seasoned photographer on their next assignment. Unfortunately you don't know who's going where, what magazine hired them or what newsworthy event they've been sent to photograph. You need all the information so you can make the best decision; your future as a photographer depends on it.\r\nFive Photographers have agreed to let you join them; Henry, Robert, Annie, Diane and Walker.\r\nThey were each hired by a different magazine; Life, Time, National Geographic, New Yorker or Vanity Fair.\r\nThey are going to either France, India, Russia, Japan, or Chile.\r\nTheir assignments are to photograph a recent natural disaster, a political election, a film festival, an embassy bombing and a major sporting event.\n\r\nThis is all the information you've been able to gather so far:\n\r\nDiane and one of the others work for magazines that share the same 1st letter, another photographer is going to a country that begins with the same letter as their name.\n\r\nLife magazine has already planned an article about the natural disaster so Time magazine is going to cover the event in France instead.\n\r\nThe five photographers are; Henry, the one who is covering a political election, the woman who is going to Japan, the other woman and the man who's been hired by Life Magazine.\n\r\nHenry is relieved that his assignment for Time isn't going to be dangerous, but Diane is worried about her safety.\n\r\nThe woman who works for New Yorker, the person who works for Vanity Fair and the person covering the embassy bombing all traveled to the same continent.\n\r\nThe bicycle race in France is the most famous in the world and usually gets tons of news coverage, but ever since the bombings the media's focus has been mostly on India.", "hint": "No hint available.", "answer": "Henry has been hired by Time to photograph the sporting event in France.\r\nDiane works for National Geographic and is being sent to India to photograph the embassy bombings.\r\nAnnie is going to Japan to cover the film festival for New Yorker.\r\nWalker will be photographing the natural disaster in Chile for Life magazine.\r\nRobert will be sent to Russia by Vanity Fair to photograph the upcoming election.", "category": "Logic-Grid", "date": "05/01/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are an up-and-coming documentary photographer and would like to gain experience by accompanying a more seasoned photographer on their next assignment. Unfortunately you don't know who's going where, what magazine hired them or what newsworthy event they've been sent to photograph. You need all the information so you can make the best decision; your future as a photographer depends on it.\r\nFive Photographers have agreed to let you join them; Henry, Robert, Annie, Diane and Walker.\r\nThey were each hired by a different magazine; Life, Time, National Geographic, New Yorker or Vanity Fair.\r\nThey are going to either France, India, Russia, Japan, or Chile.\r\nTheir assignments are to photograph a recent natural disaster, a political election, a film festival, an embassy bombing and a major sporting event.\n\r\nThis is all the information you've been able to gather so far:\n\r\nDiane and one of the others work for magazines that share the same 1st letter, another photographer is going to a country that begins with the same letter as their name.\n\r\nLife magazine has already planned an article about the natural disaster so Time magazine is going to cover the event in France instead.\n\r\nThe five photographers are; Henry, the one who is covering a political election, the woman who is going to Japan, the other woman and the man who's been hired by Life Magazine.\n\r\nHenry is relieved that his assignment for Time isn't going to be dangerous, but Diane is worried about her safety.\n\r\nThe woman who works for New Yorker, the person who works for Vanity Fair and the person covering the embassy bombing all traveled to the same continent.\n\r\nThe bicycle race in France is the most famous in the world and usually gets tons of news coverage, but ever since the bombings the media's focus has been mostly on India.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHenry has been hired by Time to photograph the sporting event in France.\r\nDiane works for National Geographic and is being sent to India to photograph the embassy bombings.\r\nAnnie is going to Japan to cover the film festival for New Yorker.\r\nWalker will be photographing the natural disaster in Chile for Life magazine.\r\nRobert will be sent to Russia by Vanity Fair to photograph the upcoming election.\n<|im_start|>answer\nHenry has been hired by Time to photograph the sporting event in France.\r\nDiane works for National Geographic and is being sent to India to photograph the embassy bombings.\r\nAnnie is going to Japan to cover the film festival for New Yorker.\r\nWalker will be photographing the natural disaster in Chile for Life magazine.\r\nRobert will be sent to Russia by Vanity Fair to photograph the upcoming election.\n<|im_end|>" }, { "id": "#7755", "title": "Local Historical", "fun": 2.75, "difficulty": 1.9000000000000001, "author": "warrior", "desc": "The local historical society has leased a castle to use it as a museum. The original lease was 99 years. I asked the curator how much time was left on the lease. His answer was as follows: two-thirds of the time past is equal to four-fifths of the time to come. How much time was left on the lease?", "hint": "No hint available.", "answer": "Answer:45 years.\n\r\nLet X equal the time left on the lease (which makes \"time past\" equal to 99-X). Set up the equation:\n\r\n2/3 * (99-X) = 4/5 * X\n\r\nSolve for X to get the answer.", "category": "Math", "date": "09/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe local historical society has leased a castle to use it as a museum. The original lease was 99 years. I asked the curator how much time was left on the lease. His answer was as follows: two-thirds of the time past is equal to four-fifths of the time to come. How much time was left on the lease?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer:45 years.\n\r\nLet X equal the time left on the lease (which makes \"time past\" equal to 99-X). Set up the equation:\n\r\n2/3 * (99-X) = 4/5 * X\n\r\nSolve for X to get the answer.\n<|im_start|>answer\nAnswer:45 years.\n\r\nLet X equal the time left on the lease (which makes \"time past\" equal to 99-X). Set up the equation:\n\r\n2/3 * (99-X) = 4/5 * X\n\r\nSolve for X to get the answer.\n<|im_end|>" }, { "id": "#7759", "title": "Digging Rabbits", "fun": 2.75, "difficulty": 1.94, "author": "hprulz", "desc": "If one small rabbit can dig a warren in nine hours, a medium rabbit can dig a warren in 6 hours and a large rabbit can dig a warren in four and a half hours, how long will it take one small, one medium and one large rabbit to dig a warren if they all work together?", "hint": "No hint available.", "answer": "2 hours. \n\r\nIn one hour, each rabbit can dig 1/9, 1/6, and 1/4.5 of a warren, respectively. To figure out how much the three of them can do in an hour, just add these up (convert to 18ths first): \r\n2/18 + 3/18 + 4/18 = 9/18 = 1/2. Since together they can dig half of a warren per hour, it will take two hours to dig a whole warren.", "category": "Math", "date": "09/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf one small rabbit can dig a warren in nine hours, a medium rabbit can dig a warren in 6 hours and a large rabbit can dig a warren in four and a half hours, how long will it take one small, one medium and one large rabbit to dig a warren if they all work together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 hours. \n\r\nIn one hour, each rabbit can dig 1/9, 1/6, and 1/4.5 of a warren, respectively. To figure out how much the three of them can do in an hour, just add these up (convert to 18ths first): \r\n2/18 + 3/18 + 4/18 = 9/18 = 1/2. Since together they can dig half of a warren per hour, it will take two hours to dig a whole warren.\n<|im_start|>answer\n2 hours. \n\r\nIn one hour, each rabbit can dig 1/9, 1/6, and 1/4.5 of a warren, respectively. To figure out how much the three of them can do in an hour, just add these up (convert to 18ths first): \r\n2/18 + 3/18 + 4/18 = 9/18 = 1/2. Since together they can dig half of a warren per hour, it will take two hours to dig a whole warren.\n<|im_end|>" }, { "id": "#5534", "title": "The Lazy Artist", "fun": 2.75, "difficulty": 1.05, "author": "doggyxp", "desc": "A king wished to build the most splendid palace imaginable. After years of construction, it was finally ready to be painted. Two artists were hired to make the palace look like no other in the world. The first artist was asked to decorate one side of each hallway, the second to adorn the facing walls.\n\r\n The first artist searched the world for beautiful colors and designs, and spent five years painting wonderful images of animals and landscapes. The second artist spent most of his time doodling and daydreaming.\n\r\n Finally the first artist was almost finished. The lazy artist began to worry, then to panic. With only a short time left to work, how could he equal the splendid pictures of his colleague?", "hint": "He did not paint it.", "answer": "He covered his walls with mirrors.", "category": "Logic", "date": "07/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA king wished to build the most splendid palace imaginable. After years of construction, it was finally ready to be painted. Two artists were hired to make the palace look like no other in the world. The first artist was asked to decorate one side of each hallway, the second to adorn the facing walls.\n\r\n The first artist searched the world for beautiful colors and designs, and spent five years painting wonderful images of animals and landscapes. The second artist spent most of his time doodling and daydreaming.\n\r\n Finally the first artist was almost finished. The lazy artist began to worry, then to panic. With only a short time left to work, how could he equal the splendid pictures of his colleague?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe covered his walls with mirrors.\n<|im_start|>answer\nHe covered his walls with mirrors.\n<|im_end|>" }, { "id": "#29804", "title": "The Total is 14, Part II", "fun": 2.75, "difficulty": 2.65, "author": "tsimkin", "desc": "Mr. Simkin, the new math teacher at school, was impressed by their ability to solve logic puzzles. He pulled aside three more students, and handed them each a sealed envelope with a number written inside. He told them that they each have a positive integer, and the sum of their numbers was 14.\n\r\nThey each opened their envelope and inspected their numbers. Snap said, \"I know that Crackle and Pop each have a different number.\"\n\r\nCrackle replies, \"I already knew that all three of our numbers were different.\"\n\r\nPop says, \"Now I know what all three of our numbers are.\"\n\r\nMr. Simkin turns to the class to ask if anyone else knows the numbers. Only Gretchen raises her hand, and she correctly identifies what each person is holding. How did she know?", "hint": "No hint available.", "answer": "Snap's statement implies that his number is odd. Crackle's statement implies that not only is his number odd, but it is also greater than or equal to 7. There are only six combinations that satisfy these conditions. Namely, for (Snap, Crackle, Pop) they are:\r\n(1, 7, 6)\r\n(1, 9, 4)\r\n(1, 11, 2)\r\n(3, 7, 4)\r\n(3, 9, 2)\r\n(5, 7, 2)\n\r\nSince Pop can reason perfectly, he knows these are the possible combinations. In order for him to know the other two, he must be holding a 6, since he knew the solution had to be unique. Therefore, Snap has a 1, Crackle has a 7, and Pop has a 6.\n\r\nAnd, as usual, Gretchen solidifies her place as a top student.", "category": "Logic", "date": "04/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Simkin, the new math teacher at school, was impressed by their ability to solve logic puzzles. He pulled aside three more students, and handed them each a sealed envelope with a number written inside. He told them that they each have a positive integer, and the sum of their numbers was 14.\n\r\nThey each opened their envelope and inspected their numbers. Snap said, \"I know that Crackle and Pop each have a different number.\"\n\r\nCrackle replies, \"I already knew that all three of our numbers were different.\"\n\r\nPop says, \"Now I know what all three of our numbers are.\"\n\r\nMr. Simkin turns to the class to ask if anyone else knows the numbers. Only Gretchen raises her hand, and she correctly identifies what each person is holding. How did she know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSnap's statement implies that his number is odd. Crackle's statement implies that not only is his number odd, but it is also greater than or equal to 7. There are only six combinations that satisfy these conditions. Namely, for (Snap, Crackle, Pop) they are:\r\n(1, 7, 6)\r\n(1, 9, 4)\r\n(1, 11, 2)\r\n(3, 7, 4)\r\n(3, 9, 2)\r\n(5, 7, 2)\n\r\nSince Pop can reason perfectly, he knows these are the possible combinations. In order for him to know the other two, he must be holding a 6, since he knew the solution had to be unique. Therefore, Snap has a 1, Crackle has a 7, and Pop has a 6.\n\r\nAnd, as usual, Gretchen solidifies her place as a top student.\n<|im_start|>answer\nSnap's statement implies that his number is odd. Crackle's statement implies that not only is his number odd, but it is also greater than or equal to 7. There are only six combinations that satisfy these conditions. Namely, for (Snap, Crackle, Pop) they are:\r\n(1, 7, 6)\r\n(1, 9, 4)\r\n(1, 11, 2)\r\n(3, 7, 4)\r\n(3, 9, 2)\r\n(5, 7, 2)\n\r\nSince Pop can reason perfectly, he knows these are the possible combinations. In order for him to know the other two, he must be holding a 6, since he knew the solution had to be unique. Therefore, Snap has a 1, Crackle has a 7, and Pop has a 6.\n\r\nAnd, as usual, Gretchen solidifies her place as a top student.\n<|im_end|>" }, { "id": "#8672", "title": "The Victim", "fun": 2.75, "difficulty": 2.37, "author": "lesternoronha1", "desc": "One of four people - two men (Jack and Mike) and two women (Carol and Lily) - was murdered.\r\nThe following facts refer to the people mentioned:\r\n(a) Jack's sister argued exactly once with Carol's legal husband after the murder. \r\n(b) Mike's sister argued twice with the victim's legal spouse after the murder. Who was the victim?", "hint": "No hint available.", "answer": "Mike is the victim.\n\r\nIf Mike's sister and Jack's sister are the same person, then (a) reads \"Lily argued exactly once with (Mike or Jack)\" and (b) reads \"Lily argued twice with (the same Mike or Jack)\". These two statements contradict each other. Therefore Mike's sister must be different from Jack's sister.\r\nIf this is the case then there are two possibilities:\n\r\n1) Jack and Carol are brother and sister. Mike and Lily are brother and sister. Jack is married to Lily and Mike is married to Carol. If this is the case, then (a) reads \"Carol argued once with Mike\" and (b) reads \"Lily argued twice with herself\", leaving Jack dead. Since Lily did not likely argue with herself, this is not the solution.\n\r\n2) Jack and Lily are brother and sister. Mike and Carol are brother and sister. Jack is married to Carol and Lily is married to Mike. If this is the case, then (a) reads \"Lily argued once with Jack\" and (b) reads \"Carol argued twice with Lily\", leaving Mike dead. Since there are no contradictions, this is the solution.", "category": "Logic", "date": "11/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne of four people - two men (Jack and Mike) and two women (Carol and Lily) - was murdered.\r\nThe following facts refer to the people mentioned:\r\n(a) Jack's sister argued exactly once with Carol's legal husband after the murder. \r\n(b) Mike's sister argued twice with the victim's legal spouse after the murder. Who was the victim?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike is the victim.\n\r\nIf Mike's sister and Jack's sister are the same person, then (a) reads \"Lily argued exactly once with (Mike or Jack)\" and (b) reads \"Lily argued twice with (the same Mike or Jack)\". These two statements contradict each other. Therefore Mike's sister must be different from Jack's sister.\r\nIf this is the case then there are two possibilities:\n\r\n1) Jack and Carol are brother and sister. Mike and Lily are brother and sister. Jack is married to Lily and Mike is married to Carol. If this is the case, then (a) reads \"Carol argued once with Mike\" and (b) reads \"Lily argued twice with herself\", leaving Jack dead. Since Lily did not likely argue with herself, this is not the solution.\n\r\n2) Jack and Lily are brother and sister. Mike and Carol are brother and sister. Jack is married to Carol and Lily is married to Mike. If this is the case, then (a) reads \"Lily argued once with Jack\" and (b) reads \"Carol argued twice with Lily\", leaving Mike dead. Since there are no contradictions, this is the solution.\n<|im_start|>answer\nMike is the victim.\n\r\nIf Mike's sister and Jack's sister are the same person, then (a) reads \"Lily argued exactly once with (Mike or Jack)\" and (b) reads \"Lily argued twice with (the same Mike or Jack)\". These two statements contradict each other. Therefore Mike's sister must be different from Jack's sister.\r\nIf this is the case then there are two possibilities:\n\r\n1) Jack and Carol are brother and sister. Mike and Lily are brother and sister. Jack is married to Lily and Mike is married to Carol. If this is the case, then (a) reads \"Carol argued once with Mike\" and (b) reads \"Lily argued twice with herself\", leaving Jack dead. Since Lily did not likely argue with herself, this is not the solution.\n\r\n2) Jack and Lily are brother and sister. Mike and Carol are brother and sister. Jack is married to Carol and Lily is married to Mike. If this is the case, then (a) reads \"Lily argued once with Jack\" and (b) reads \"Carol argued twice with Lily\", leaving Mike dead. Since there are no contradictions, this is the solution.\n<|im_end|>" }, { "id": "#30211", "title": "Three Statements IV", "fun": 2.75, "difficulty": 1.8900000000000001, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. Sam received $0.41 change from a purchase. If he received 6 coins, 3 of the coins had to be dimes. \n\r\nCoins in circulation are: 1 cent, 5 cents, 10 cents, 25 cents. 1 dime=10 cents.\n\r\n2. If there are more inhabitants in Los Angeles than there are hairs on the head of any inhabitant, and if no inhabitant is totally bald, it necessarily follows that there must be at least two inhabitants with exactly the same number of hairs.\n\r\n3. The price of a T-shirt was cut 20% for a sale. The price of the T-shirt should be increased by 25% if it is to be sold again at the original price.", "hint": "No hint available.", "answer": "All the three statements are true.\n\r\nIn statement 1, there must be one 1 cent because of the remainder upon division by 5. The remaining 5 coins total 40 cents, which can only be 5*2+10*3.\n\r\nIn statement 2, the pigeonhole principle is used, and you should know it.\n\r\nIn statement 3, if the original price is X, then X*(1-0.2)*(1+0.25)=X*0.8*1.25=X, which is again the original price.", "category": "Logic", "date": "05/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. Sam received $0.41 change from a purchase. If he received 6 coins, 3 of the coins had to be dimes. \n\r\nCoins in circulation are: 1 cent, 5 cents, 10 cents, 25 cents. 1 dime=10 cents.\n\r\n2. If there are more inhabitants in Los Angeles than there are hairs on the head of any inhabitant, and if no inhabitant is totally bald, it necessarily follows that there must be at least two inhabitants with exactly the same number of hairs.\n\r\n3. The price of a T-shirt was cut 20% for a sale. The price of the T-shirt should be increased by 25% if it is to be sold again at the original price.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll the three statements are true.\n\r\nIn statement 1, there must be one 1 cent because of the remainder upon division by 5. The remaining 5 coins total 40 cents, which can only be 5*2+10*3.\n\r\nIn statement 2, the pigeonhole principle is used, and you should know it.\n\r\nIn statement 3, if the original price is X, then X*(1-0.2)*(1+0.25)=X*0.8*1.25=X, which is again the original price.\n<|im_start|>answer\nAll the three statements are true.\n\r\nIn statement 1, there must be one 1 cent because of the remainder upon division by 5. The remaining 5 coins total 40 cents, which can only be 5*2+10*3.\n\r\nIn statement 2, the pigeonhole principle is used, and you should know it.\n\r\nIn statement 3, if the original price is X, then X*(1-0.2)*(1+0.25)=X*0.8*1.25=X, which is again the original price.\n<|im_end|>" }, { "id": "#40048", "title": "Vacation in Shriekville", "fun": 2.75, "difficulty": 1.77, "author": "Editor", "desc": "Five people were taking a vacation in Shriekville. Unfortunately, all their vacations were cut short by a terrifying encounter with a resident ghost.\n\r\nCan you determine the type of accommodation, its name, and the name of the resident ghost? \n\r\nArchibald stayed at St George's: he was not frightened off by Macabre Malcolm.\n\r\nThe pub was the home of Chilling Charlie, who frequently turned down the thermostat and then let out gruesome shrieks, chilling everyone to the bone.\n\r\nLucas or Archibald's vacation was at the castle: was Terrifying Tony the resident ghost there?\n\r\nCharlie went to stay with friends. This was in a bungalow, but it did not have the name Briar Hill. He was not terrified by Bloodcurdling Brian, the ghost that left bloodstained footprints behind.\n\r\nBilly vacationed at a place named Rosedale, which was not a hotel.\n\r\nCreepy Craig really did scare Gary by scraping his fingernails on the bedroom window as he was settling down to sleep. This was not at a hotel and it wasn't a place named Avalon.\n\r\nThe bed and breakfast accommodation was not High Lodge, which was also not the castle where Macabre Malcolm was resident.", "hint": "No hint available.", "answer": "Name, Ghost's Name, Place Name, Type of Dwelling:\n\r\nArchibald, Bloodcurdling Brian, St. George's, Hotel\r\nBilly, Chilling Charlie, Rosedale, Pub\r\nCharlie, Terrifying Tony, High Lodge, Bungalow\r\nGary, Creepy Craig , Briar Hill, Bed and Breakfast\r\nLucas, Macabre Malcolm, Avalon, Castle", "category": "Logic-Grid", "date": "01/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people were taking a vacation in Shriekville. Unfortunately, all their vacations were cut short by a terrifying encounter with a resident ghost.\n\r\nCan you determine the type of accommodation, its name, and the name of the resident ghost? \n\r\nArchibald stayed at St George's: he was not frightened off by Macabre Malcolm.\n\r\nThe pub was the home of Chilling Charlie, who frequently turned down the thermostat and then let out gruesome shrieks, chilling everyone to the bone.\n\r\nLucas or Archibald's vacation was at the castle: was Terrifying Tony the resident ghost there?\n\r\nCharlie went to stay with friends. This was in a bungalow, but it did not have the name Briar Hill. He was not terrified by Bloodcurdling Brian, the ghost that left bloodstained footprints behind.\n\r\nBilly vacationed at a place named Rosedale, which was not a hotel.\n\r\nCreepy Craig really did scare Gary by scraping his fingernails on the bedroom window as he was settling down to sleep. This was not at a hotel and it wasn't a place named Avalon.\n\r\nThe bed and breakfast accommodation was not High Lodge, which was also not the castle where Macabre Malcolm was resident.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName, Ghost's Name, Place Name, Type of Dwelling:\n\r\nArchibald, Bloodcurdling Brian, St. George's, Hotel\r\nBilly, Chilling Charlie, Rosedale, Pub\r\nCharlie, Terrifying Tony, High Lodge, Bungalow\r\nGary, Creepy Craig , Briar Hill, Bed and Breakfast\r\nLucas, Macabre Malcolm, Avalon, Castle\n<|im_start|>answer\nName, Ghost's Name, Place Name, Type of Dwelling:\n\r\nArchibald, Bloodcurdling Brian, St. George's, Hotel\r\nBilly, Chilling Charlie, Rosedale, Pub\r\nCharlie, Terrifying Tony, High Lodge, Bungalow\r\nGary, Creepy Craig , Briar Hill, Bed and Breakfast\r\nLucas, Macabre Malcolm, Avalon, Castle\n<|im_end|>" }, { "id": "#31169", "title": "Weather Wizards", "fun": 2.74, "difficulty": 1.56, "author": "Draw", "desc": "Kids in the National Weather Wizards' Club are keeping track of the weather in their local areas. The temperatures and weather conditions they posted are listed below. The Weather Wizards are Ashley, Danny, Jose, Joseph, Leilani, Sasha, and Tiffany. They each report from a different area.\n\r\nWeather: (The temperatures are Fahrenheit.)\n\r\nBoston, Massachusetts 42, Partly Cloudy \r\nFargo, North Dakota 5, Partly Cloudy \r\nHonolulu, Hawaii 74, Sunny \r\nNew York, New York 44, Partly Cloudy \r\nPortland, Maine 32, Snowy \r\nSan Francisco, California 61, Rainy \r\nWichita, Kansas 41, Partly Cloudy \n\r\nClues:\n\r\n1. Leilani and Joseph reported partly cloudy skies and temperatures in the low 40's. \r\n2. Danny reported the coldest temperature, and Ashley reported the warmest. \r\n3. The temperature in Tiffany's city is 2 degrees warmer than in Leilani's. \r\n4. Jose is planning on making a snowman. \n\r\nWho is in each city?", "hint": "Make a chart and use the clues to eliminate the impossible combinations.", "answer": "Ashley is in Honolulu, Hawaii.\r\nDanny is in Fargo, North Dakota.\r\nJose is in Portland, Maine.\r\nJoseph is in Wichita, Kansas.\r\nLeilani is in Boston, Massachusetts.\r\nSasha is in San Francisco, California.\r\nTiffany is in New York City, New York.", "category": "Logic", "date": "06/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKids in the National Weather Wizards' Club are keeping track of the weather in their local areas. The temperatures and weather conditions they posted are listed below. The Weather Wizards are Ashley, Danny, Jose, Joseph, Leilani, Sasha, and Tiffany. They each report from a different area.\n\r\nWeather: (The temperatures are Fahrenheit.)\n\r\nBoston, Massachusetts 42, Partly Cloudy \r\nFargo, North Dakota 5, Partly Cloudy \r\nHonolulu, Hawaii 74, Sunny \r\nNew York, New York 44, Partly Cloudy \r\nPortland, Maine 32, Snowy \r\nSan Francisco, California 61, Rainy \r\nWichita, Kansas 41, Partly Cloudy \n\r\nClues:\n\r\n1. Leilani and Joseph reported partly cloudy skies and temperatures in the low 40's. \r\n2. Danny reported the coldest temperature, and Ashley reported the warmest. \r\n3. The temperature in Tiffany's city is 2 degrees warmer than in Leilani's. \r\n4. Jose is planning on making a snowman. \n\r\nWho is in each city?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAshley is in Honolulu, Hawaii.\r\nDanny is in Fargo, North Dakota.\r\nJose is in Portland, Maine.\r\nJoseph is in Wichita, Kansas.\r\nLeilani is in Boston, Massachusetts.\r\nSasha is in San Francisco, California.\r\nTiffany is in New York City, New York.\n<|im_start|>answer\nAshley is in Honolulu, Hawaii.\r\nDanny is in Fargo, North Dakota.\r\nJose is in Portland, Maine.\r\nJoseph is in Wichita, Kansas.\r\nLeilani is in Boston, Massachusetts.\r\nSasha is in San Francisco, California.\r\nTiffany is in New York City, New York.\n<|im_end|>" }, { "id": "#27996", "title": "The Dairy Farmer", "fun": 2.74, "difficulty": 2.35, "author": "dodger", "desc": "A dairy farmer had 54 litres of milk in three churns. He wanted to make sure each churn contained 18 litres. \n\n\n\r\n First, he poured 1/4 of the first churn into the second churn. Then he poured 1/2 of the second churn into the third churn. Finally, he poured 1/3 of the third churn into the first churn. \r\nHow many litres did each churn contain before he started pouring?", "hint": "No hint available.", "answer": "12, 33 and 9 litres respectively", "category": "Math", "date": "01/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA dairy farmer had 54 litres of milk in three churns. He wanted to make sure each churn contained 18 litres. \n\n\n\r\n First, he poured 1/4 of the first churn into the second churn. Then he poured 1/2 of the second churn into the third churn. Finally, he poured 1/3 of the third churn into the first churn. \r\nHow many litres did each churn contain before he started pouring?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12, 33 and 9 litres respectively\n<|im_start|>answer\n12, 33 and 9 litres respectively\n<|im_end|>" }, { "id": "#21707", "title": "Spring Parade", "fun": 2.74, "difficulty": 1.37, "author": "MrBasKetBall", "desc": "This year's Spring parade has a marching band, pairs of dancers, a float of jugglers, a dozen circus clowns, a Girl Scout troop, a Boy Scout troop, and a championship football team.\n\r\nRead the description of each group carefully and decide how many are in each group and in what order they marched in the parade.\n\r\nThe marching band was not the leader, but their 6 rows of 4 musicians in each row were near the front, just ahead of the Girl Scouts. \r\nThe football team had 2 fewer marchers than the Girl Scouts, and took their time signing autographs as they marched at the end. \r\nThe Girl Scouts and the Boy Scouts were separated by the 3 groups of 4 jugglers on the jugglers' float. \r\nThe 3 pairs of dancers were between the Boy Scouts and the football team. \r\nThe Boy Scouts had 5 rows of 3 marchers and the Girl Scouts had twice as many.", "hint": "Draw a diagram to illustrate how many marchers are in each group and the order that they marched. Another strategy is to write the name of each group on a different piece of small paper. Then move the papers around to fit the order.", "answer": "The groups are listed in the order that they marched, from first to last:\n\r\n12 circus clowns\r\n24 musicians in the marching band\r\n30 Girl Scouts\r\n12 jugglers\r\n15 Boy Scouts\r\n6 dancers\r\n28 football players", "category": "Logic", "date": "03/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis year's Spring parade has a marching band, pairs of dancers, a float of jugglers, a dozen circus clowns, a Girl Scout troop, a Boy Scout troop, and a championship football team.\n\r\nRead the description of each group carefully and decide how many are in each group and in what order they marched in the parade.\n\r\nThe marching band was not the leader, but their 6 rows of 4 musicians in each row were near the front, just ahead of the Girl Scouts. \r\nThe football team had 2 fewer marchers than the Girl Scouts, and took their time signing autographs as they marched at the end. \r\nThe Girl Scouts and the Boy Scouts were separated by the 3 groups of 4 jugglers on the jugglers' float. \r\nThe 3 pairs of dancers were between the Boy Scouts and the football team. \r\nThe Boy Scouts had 5 rows of 3 marchers and the Girl Scouts had twice as many.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe groups are listed in the order that they marched, from first to last:\n\r\n12 circus clowns\r\n24 musicians in the marching band\r\n30 Girl Scouts\r\n12 jugglers\r\n15 Boy Scouts\r\n6 dancers\r\n28 football players\n<|im_start|>answer\nThe groups are listed in the order that they marched, from first to last:\n\r\n12 circus clowns\r\n24 musicians in the marching band\r\n30 Girl Scouts\r\n12 jugglers\r\n15 Boy Scouts\r\n6 dancers\r\n28 football players\n<|im_end|>" }, { "id": "#28484", "title": "Apartment Block Fire", "fun": 2.74, "difficulty": 2.62, "author": "Dave", "desc": "Dave, the janitor of an apartment block, notices that the boiler pressure is rising, and will shortly explode.\r\nHe phones two of the residents, tells them the news, asks them to do the same and phone just two more people, and then get out of the building.\r\nAssume that each of the residents is in, and answers the phone immediately.\r\nIf each phone call takes 30 seconds, and it takes each person 90 seconds to get out of the building, how long will it take to empty all 375 apartments?", "hint": "Fibonacci might have the answer!", "answer": "7 minutes.\n\r\nIn the first 30 seconds, Dave rings one other person, call him A.\n\r\nIn the second 30 seconds, Dave rings B, and leaves the building. A rings C.\n\r\n3rd: A rings D, and leaves. B and C ring E and F.\n\r\n4th: B and C ring G and H. D, E and F ring I, J, K.\n\r\n5th: D, E, F ring L, M, N. G, H, I, J, K ring O, P, Q, R, S.\n\r\nThe number of residents informed in each time period is as follows:\r\n1, 2, 3, 5, 8, ...\r\nThese are known as Fibonacci Numbers, where each number is the sum of the preceding two.\r\nThe total number of people informed is:\r\n1, 3, 6, 11, 19, ...\r\nEach number is the sum of the previous two, plus 2.\r\nContinuing this series we get:\r\n32, 53, 87, 142, 231, 375.\n\r\nThus 375 people were informed after 11 periods of phone calls.\r\n11 calls at 30 seconds each = 5.5 minutes, plus 90 seconds for the last people to exit the building gives 7 minutes.", "category": "Math", "date": "02/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDave, the janitor of an apartment block, notices that the boiler pressure is rising, and will shortly explode.\r\nHe phones two of the residents, tells them the news, asks them to do the same and phone just two more people, and then get out of the building.\r\nAssume that each of the residents is in, and answers the phone immediately.\r\nIf each phone call takes 30 seconds, and it takes each person 90 seconds to get out of the building, how long will it take to empty all 375 apartments?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 minutes.\n\r\nIn the first 30 seconds, Dave rings one other person, call him A.\n\r\nIn the second 30 seconds, Dave rings B, and leaves the building. A rings C.\n\r\n3rd: A rings D, and leaves. B and C ring E and F.\n\r\n4th: B and C ring G and H. D, E and F ring I, J, K.\n\r\n5th: D, E, F ring L, M, N. G, H, I, J, K ring O, P, Q, R, S.\n\r\nThe number of residents informed in each time period is as follows:\r\n1, 2, 3, 5, 8, ...\r\nThese are known as Fibonacci Numbers, where each number is the sum of the preceding two.\r\nThe total number of people informed is:\r\n1, 3, 6, 11, 19, ...\r\nEach number is the sum of the previous two, plus 2.\r\nContinuing this series we get:\r\n32, 53, 87, 142, 231, 375.\n\r\nThus 375 people were informed after 11 periods of phone calls.\r\n11 calls at 30 seconds each = 5.5 minutes, plus 90 seconds for the last people to exit the building gives 7 minutes.\n<|im_start|>answer\n7 minutes.\n\r\nIn the first 30 seconds, Dave rings one other person, call him A.\n\r\nIn the second 30 seconds, Dave rings B, and leaves the building. A rings C.\n\r\n3rd: A rings D, and leaves. B and C ring E and F.\n\r\n4th: B and C ring G and H. D, E and F ring I, J, K.\n\r\n5th: D, E, F ring L, M, N. G, H, I, J, K ring O, P, Q, R, S.\n\r\nThe number of residents informed in each time period is as follows:\r\n1, 2, 3, 5, 8, ...\r\nThese are known as Fibonacci Numbers, where each number is the sum of the preceding two.\r\nThe total number of people informed is:\r\n1, 3, 6, 11, 19, ...\r\nEach number is the sum of the previous two, plus 2.\r\nContinuing this series we get:\r\n32, 53, 87, 142, 231, 375.\n\r\nThus 375 people were informed after 11 periods of phone calls.\r\n11 calls at 30 seconds each = 5.5 minutes, plus 90 seconds for the last people to exit the building gives 7 minutes.\n<|im_end|>" }, { "id": "#22792", "title": "Diagonal Possibility", "fun": 2.74, "difficulty": 2.32, "author": "chidam11", "desc": "Fill the eight spaces below with numbers from 1 to 8. No number that comes before or after any other number should be placed in an adjacent space, either horizontally, vertically or diagonally. \n\r\n(For Example 2 should not be next to the number 1 or the number 3)\n\r\nThe arrangement of the space is\r\n* __ __ *\r\n__ __ __ __\r\n* __ __ *", "hint": "No hint available.", "answer": "* 3 5 *\r\n7 1 8 2\r\n* 4 6 *\n\r\nOther possibilities are mirror images of the above answer.", "category": "Math", "date": "05/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFill the eight spaces below with numbers from 1 to 8. No number that comes before or after any other number should be placed in an adjacent space, either horizontally, vertically or diagonally. \n\r\n(For Example 2 should not be next to the number 1 or the number 3)\n\r\nThe arrangement of the space is\r\n* __ __ *\r\n__ __ __ __\r\n* __ __ *\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n* 3 5 *\r\n7 1 8 2\r\n* 4 6 *\n\r\nOther possibilities are mirror images of the above answer.\n<|im_start|>answer\n* 3 5 *\r\n7 1 8 2\r\n* 4 6 *\n\r\nOther possibilities are mirror images of the above answer.\n<|im_end|>" }, { "id": "#14986", "title": "The Last Piece", "fun": 2.74, "difficulty": 1.31, "author": "jess1118", "desc": "Mom bakes a cake. Dad ate 1/6 of the cake. Brother ate 1/5 of what was left. Then sister had 1/4 of the remaining cake. After that the dog ate 1/3 of the remaining cake, and finally another kid ate 1/2 of what was left after the dog was finished. What fraction of the whole cake is left for mom to eat?", "hint": "She cut it into six pieces after she baked it.", "answer": "1/6 - the same amount everyone else got to eat.", "category": "Math", "date": "10/03/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMom bakes a cake. Dad ate 1/6 of the cake. Brother ate 1/5 of what was left. Then sister had 1/4 of the remaining cake. After that the dog ate 1/3 of the remaining cake, and finally another kid ate 1/2 of what was left after the dog was finished. What fraction of the whole cake is left for mom to eat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1/6 - the same amount everyone else got to eat.\n<|im_start|>answer\n1/6 - the same amount everyone else got to eat.\n<|im_end|>" }, { "id": "#30713", "title": "Mother Goose's Library", "fun": 2.74, "difficulty": 1.22, "author": "cdrock", "desc": "While Mother Goose was away from her library, some of her characters jumped into different stories. When she got back, she found 5 characters in the wrong stories, and each had taken an object from a different story.\n\r\nUsing the clues below, can you figure out what story the characters jumped into, and the item they took with them?\n\r\nCharacters: Jack, Jill, Peter Piper, Tom Tucker, and Wee Willie Winkie.\n\r\nStories: Humpty Dumpty, Jack Sprat, Little Boy Blue, Miss Muffet, and Old King Cole.\n\r\nItems: Fiddle, Horn, Pail of Water, Peppers, and a Pipe.\n\n\r\nClues:\n\r\n1. Either Jill or Tom Tucker took the fiddle.\n\r\n2. Mother Goose told Wee Willie Winkie to give the pail of water back to Jack and Jill.\n\r\n3. The pipe wasn't found in Old King Cole.\n\r\n4. Jill took some peppers from Peter Piper.\n\r\n5. Peter Piper went into the story of Old King Cole.\n\r\n6. Jack wasn't found in either Little Boy Blue, in which the pail was not found, nor Jack Sprat.\n\r\n7. The cat's fiddle was found in Humpty Dumpty.", "hint": "No hint available.", "answer": "Jack - Miss Muffet - Pipe\r\nJill - Little Boy Blue - Peppers\r\nTom Tucker - Humpty Dumpty - Fiddle\r\nWee Willie Winkie - Jack Sprat - Pail\r\nPeter Piper - Old King Cole - Horn", "category": "Logic-Grid", "date": "05/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile Mother Goose was away from her library, some of her characters jumped into different stories. When she got back, she found 5 characters in the wrong stories, and each had taken an object from a different story.\n\r\nUsing the clues below, can you figure out what story the characters jumped into, and the item they took with them?\n\r\nCharacters: Jack, Jill, Peter Piper, Tom Tucker, and Wee Willie Winkie.\n\r\nStories: Humpty Dumpty, Jack Sprat, Little Boy Blue, Miss Muffet, and Old King Cole.\n\r\nItems: Fiddle, Horn, Pail of Water, Peppers, and a Pipe.\n\n\r\nClues:\n\r\n1. Either Jill or Tom Tucker took the fiddle.\n\r\n2. Mother Goose told Wee Willie Winkie to give the pail of water back to Jack and Jill.\n\r\n3. The pipe wasn't found in Old King Cole.\n\r\n4. Jill took some peppers from Peter Piper.\n\r\n5. Peter Piper went into the story of Old King Cole.\n\r\n6. Jack wasn't found in either Little Boy Blue, in which the pail was not found, nor Jack Sprat.\n\r\n7. The cat's fiddle was found in Humpty Dumpty.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJack - Miss Muffet - Pipe\r\nJill - Little Boy Blue - Peppers\r\nTom Tucker - Humpty Dumpty - Fiddle\r\nWee Willie Winkie - Jack Sprat - Pail\r\nPeter Piper - Old King Cole - Horn\n<|im_start|>answer\nJack - Miss Muffet - Pipe\r\nJill - Little Boy Blue - Peppers\r\nTom Tucker - Humpty Dumpty - Fiddle\r\nWee Willie Winkie - Jack Sprat - Pail\r\nPeter Piper - Old King Cole - Horn\n<|im_end|>" }, { "id": "#45581", "title": "High School Reunion", "fun": 2.74, "difficulty": 2.72, "author": "caberet", "desc": "It's your 15-year class reunion at Bancroft High. You bump into five of your former classmates. You're trying to keep everyone straight. Fortunately, nobody has changed their names since school. \n\r\nYou remember that Ian broke his arm twice during junior year and that Sarah was captain of the girl's polo team.\n\r\nSydney and the electrical engineer reminisced with Mr. Petit (who just celebrated his 10th wedding anniversary), Ms. Sutter and the one who vacationed in Italy last week about what each of them had once wanted to be when they grew up. \n\r\nNo one has the same first name (Ian, Patrick, Rebecca, Sarah & Sydney), last name (Leander, Mills, Newsom, Petit & Sutter), dream job (Ballerina, Baseball Player, Nurse, Olympic Gymnast & Train Engineer), actual job (Chief Financial Officer (CFO), Electrical Engineer, Warehouse Manager, Physical Education (PE) Teacher & Stockbroker) or recent travel location (Lake Superior, United States; Lima, Peru; Nairobi, Kenya; Rome, Italy; & Sydney, Australia) as anyone else in the group.\n\r\nPatrick's dream job would have involved keeping tight schedules and running (very) large machines to transport supplies over long distances; his actual position also involves managing tight schedules, running large machines and transporting warehoused supplies. \n\r\nRebecca was not surprised that her classmate who had once planned on being a nurse had recently volunteered as a humanitarian aid worker in Africa. \n\r\nThe stockbroker has never married because of his anxiety-ridden work. But it occurs to you that his former dream job, which is played outdoors in front of thousands of sports fans, would have been a stress inducing choice too.\n\r\nThe conversation moved on to recent travel locations. The CFO just traveled on business to the namesake city of the former Olympic gymnast aspirant. Ms. Mills was able to spend all summer with her children at the lake, because those in her career routinely get summers off work. \n\r\nUh oh, you got distracted there for a moment when Sydney remarked that this is the first time she has returned to Bancroft High since she left for college. But you did catch that if the former ballerina wannabe just returned from Italy, then the one named Newsom is the PE teacher, otherwise the one surnamed Leander is either Patrick or Sarah.\n\r\nPhew, you kept everyone straight. Now you're ready to meet the rest of your classmates!", "hint": "Dream Jobs:\r\n-Baseball Player - Baseball is a sport that is played outdoors in front of as many as 45,000 stadium fans.\r\n-Train Engineer - Responsible for keeping to tight schedules and running trains, which are very large mobile machines that transport supplies over long distances.\n\r\nCareers:\r\n-PE Teacher - This is the only field in the list that routinely has the summer off work. \r\n-Warehouse Manager - Schedule many workers and keep forklifts, which are large mobile machines, running smoothly. Incoming and outgoing supplies are transported as needed.", "answer": "First / Last / Dream / Career / Travel\r\nIan / Newsom / Baseball Player / Stock Broker / Rome, Italy, Europe.\r\nPatrick / Petit / Train Engineer / Operations Manager / Lima, Peru, South America.\r\nRebecca / Sutter / Ballerina / CFO / Sydney, Australia.\r\nSarah / Leander / Nurse / Electrical Engineer / Nairobi, Kenya, Africa.\r\nSydney / Mills / Olympic Gymnast / PE Teacher / Lake Superior, USA, North America.", "category": "Logic-Grid", "date": "11/01/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's your 15-year class reunion at Bancroft High. You bump into five of your former classmates. You're trying to keep everyone straight. Fortunately, nobody has changed their names since school. \n\r\nYou remember that Ian broke his arm twice during junior year and that Sarah was captain of the girl's polo team.\n\r\nSydney and the electrical engineer reminisced with Mr. Petit (who just celebrated his 10th wedding anniversary), Ms. Sutter and the one who vacationed in Italy last week about what each of them had once wanted to be when they grew up. \n\r\nNo one has the same first name (Ian, Patrick, Rebecca, Sarah & Sydney), last name (Leander, Mills, Newsom, Petit & Sutter), dream job (Ballerina, Baseball Player, Nurse, Olympic Gymnast & Train Engineer), actual job (Chief Financial Officer (CFO), Electrical Engineer, Warehouse Manager, Physical Education (PE) Teacher & Stockbroker) or recent travel location (Lake Superior, United States; Lima, Peru; Nairobi, Kenya; Rome, Italy; & Sydney, Australia) as anyone else in the group.\n\r\nPatrick's dream job would have involved keeping tight schedules and running (very) large machines to transport supplies over long distances; his actual position also involves managing tight schedules, running large machines and transporting warehoused supplies. \n\r\nRebecca was not surprised that her classmate who had once planned on being a nurse had recently volunteered as a humanitarian aid worker in Africa. \n\r\nThe stockbroker has never married because of his anxiety-ridden work. But it occurs to you that his former dream job, which is played outdoors in front of thousands of sports fans, would have been a stress inducing choice too.\n\r\nThe conversation moved on to recent travel locations. The CFO just traveled on business to the namesake city of the former Olympic gymnast aspirant. Ms. Mills was able to spend all summer with her children at the lake, because those in her career routinely get summers off work. \n\r\nUh oh, you got distracted there for a moment when Sydney remarked that this is the first time she has returned to Bancroft High since she left for college. But you did catch that if the former ballerina wannabe just returned from Italy, then the one named Newsom is the PE teacher, otherwise the one surnamed Leander is either Patrick or Sarah.\n\r\nPhew, you kept everyone straight. Now you're ready to meet the rest of your classmates!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst / Last / Dream / Career / Travel\r\nIan / Newsom / Baseball Player / Stock Broker / Rome, Italy, Europe.\r\nPatrick / Petit / Train Engineer / Operations Manager / Lima, Peru, South America.\r\nRebecca / Sutter / Ballerina / CFO / Sydney, Australia.\r\nSarah / Leander / Nurse / Electrical Engineer / Nairobi, Kenya, Africa.\r\nSydney / Mills / Olympic Gymnast / PE Teacher / Lake Superior, USA, North America.\n<|im_start|>answer\nFirst / Last / Dream / Career / Travel\r\nIan / Newsom / Baseball Player / Stock Broker / Rome, Italy, Europe.\r\nPatrick / Petit / Train Engineer / Operations Manager / Lima, Peru, South America.\r\nRebecca / Sutter / Ballerina / CFO / Sydney, Australia.\r\nSarah / Leander / Nurse / Electrical Engineer / Nairobi, Kenya, Africa.\r\nSydney / Mills / Olympic Gymnast / PE Teacher / Lake Superior, USA, North America.\n<|im_end|>" }, { "id": "#31757", "title": "Cafeteria Food", "fun": 2.74, "difficulty": 1.6400000000000001, "author": "teen_wiz", "desc": "Maura, Bradley, Leia and James had all just graduated from grade 5, and were now moving up to Kim Jameson Middle School. To them, middle school meant one thing: bought lunch, not brought lunch (brought lunches are for losers!). On the first day of school, the four of them sauntered into the school cafeteria, bills and coins in hand. Unfortunately, this is what they saw:\n\r\n~TODAY'S LUNCH MENU~\r\n-Mystery Meat Tourtiere\r\n-Fried Frog (whole)\r\n-Chocolate Cabbage Chickpea Salad\r\n-Surprise Soup Special\n\r\n\"Ugh!\" said Maura. \"Nothing good ever comes from 'surprise' foods. At least we can look forward to dessert.\"\n\r\n\"Uh oh,\" whispered James. \"Check out the dessert menu.\"\n\r\n~TODAY'S DESSERT MENU~\r\n-Broccoli and Sugar Pie\r\n-Honey and Bean Brittle\r\n-Chocolate Pickle Crunch\r\n-Pork Pudding\n\r\n\"I can't eat that garbage!\" Leia whined.\n\r\n\"We don't actually have a choice. We can't go off the school grounds, we can't call our parents to bring us something, and we can't beg for food from other kids...we're newbies, remember? It goes against the newbie code,\" said Bradley. \"Let's just all order something different and see if there's anything good we can share.\"\n\r\nThey all sadly agreed to this and bought their lunches.\n\r\nCan you figure out which lunch/dessert combo each kid bought?\n\r\n1. Neither of the girls order the Surprise Soup Special or the Chocolate Pickle Crunch.\n\r\n2. The one who ordered Honey and Bean Brittle seriously thought they saw the Mystery Meat Tourtiere move, so decided a definite NO to that one.\n\r\n3. The one who reluctantly bought the Pork Pudding did not buy the Chocolate Cabbage Chickpea Salad (ew! vegetables!) or the Mystery Meat Tourtiere.\n\r\n4. Bradley very much disliked olive green as a colour, and as the soup was of that exact hue, he chose another entree.\n\r\n5. Eating an actual thing with legs you can see grossed Leia out, so she quickly left the Fried Frog station without spending a penny there.\n\r\n6. The person who chose the Mystery Meat Tourtiere did not want another brown item, so they did not choose the Broccoli and Sugar Pie.\n\r\n7. James knew his younger sister would kill him if he ate anything to do with pigs, so he ignored the Pork Pudding station.\n\r\n8. One of the kids in line told the friends that having soup and pie together made for an absolutely disgusting meal, so none of the kids chose that.", "hint": "MMT= Mystery Meat Tourtiere\r\nFF= Fried Frog\r\nCCCS= Chocolate Cabbage Chickpea Salad\r\nSSS= Surprise Soup Special\n\r\nBSP= Broccoli and Sugar Pie\r\nHBB= Honey and Bean Brittle\r\nCPC= Chocolate Pickle Crunch\r\nPP= Pork Pudding", "answer": "After much contemplation and disgusted looks, the four friends chose the following combos:\n\r\nLeia had the Chocolate Cabbage Chickpea Salad and a slice of Broccoli and Sugar Pie.\n\r\nJames decided on a steaming bowl of the Surprise Soup Special and a piece of Honey and Bean Brittle.\n\r\nMaura chose a Fried Frog and a bowl of Pork Pudding.\n\r\nBradley selected a Mystery Meat Tourtiere and a plate of Chocolate Pickle Crunch.\n\r\n~~~~~~~~~~~~~~~~~~~~\r\nAfter picking at their food for quite a while, James, Bradley, Maura, and Leia all decided that brought lunches WEREN'T for losers. Every one of them brought a plain old PB&J sandwich the very next day.", "category": "Logic-Grid", "date": "07/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMaura, Bradley, Leia and James had all just graduated from grade 5, and were now moving up to Kim Jameson Middle School. To them, middle school meant one thing: bought lunch, not brought lunch (brought lunches are for losers!). On the first day of school, the four of them sauntered into the school cafeteria, bills and coins in hand. Unfortunately, this is what they saw:\n\r\n~TODAY'S LUNCH MENU~\r\n-Mystery Meat Tourtiere\r\n-Fried Frog (whole)\r\n-Chocolate Cabbage Chickpea Salad\r\n-Surprise Soup Special\n\r\n\"Ugh!\" said Maura. \"Nothing good ever comes from 'surprise' foods. At least we can look forward to dessert.\"\n\r\n\"Uh oh,\" whispered James. \"Check out the dessert menu.\"\n\r\n~TODAY'S DESSERT MENU~\r\n-Broccoli and Sugar Pie\r\n-Honey and Bean Brittle\r\n-Chocolate Pickle Crunch\r\n-Pork Pudding\n\r\n\"I can't eat that garbage!\" Leia whined.\n\r\n\"We don't actually have a choice. We can't go off the school grounds, we can't call our parents to bring us something, and we can't beg for food from other kids...we're newbies, remember? It goes against the newbie code,\" said Bradley. \"Let's just all order something different and see if there's anything good we can share.\"\n\r\nThey all sadly agreed to this and bought their lunches.\n\r\nCan you figure out which lunch/dessert combo each kid bought?\n\r\n1. Neither of the girls order the Surprise Soup Special or the Chocolate Pickle Crunch.\n\r\n2. The one who ordered Honey and Bean Brittle seriously thought they saw the Mystery Meat Tourtiere move, so decided a definite NO to that one.\n\r\n3. The one who reluctantly bought the Pork Pudding did not buy the Chocolate Cabbage Chickpea Salad (ew! vegetables!) or the Mystery Meat Tourtiere.\n\r\n4. Bradley very much disliked olive green as a colour, and as the soup was of that exact hue, he chose another entree.\n\r\n5. Eating an actual thing with legs you can see grossed Leia out, so she quickly left the Fried Frog station without spending a penny there.\n\r\n6. The person who chose the Mystery Meat Tourtiere did not want another brown item, so they did not choose the Broccoli and Sugar Pie.\n\r\n7. James knew his younger sister would kill him if he ate anything to do with pigs, so he ignored the Pork Pudding station.\n\r\n8. One of the kids in line told the friends that having soup and pie together made for an absolutely disgusting meal, so none of the kids chose that.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter much contemplation and disgusted looks, the four friends chose the following combos:\n\r\nLeia had the Chocolate Cabbage Chickpea Salad and a slice of Broccoli and Sugar Pie.\n\r\nJames decided on a steaming bowl of the Surprise Soup Special and a piece of Honey and Bean Brittle.\n\r\nMaura chose a Fried Frog and a bowl of Pork Pudding.\n\r\nBradley selected a Mystery Meat Tourtiere and a plate of Chocolate Pickle Crunch.\n\r\n~~~~~~~~~~~~~~~~~~~~\r\nAfter picking at their food for quite a while, James, Bradley, Maura, and Leia all decided that brought lunches WEREN'T for losers. Every one of them brought a plain old PB&J sandwich the very next day.\n<|im_start|>answer\nAfter much contemplation and disgusted looks, the four friends chose the following combos:\n\r\nLeia had the Chocolate Cabbage Chickpea Salad and a slice of Broccoli and Sugar Pie.\n\r\nJames decided on a steaming bowl of the Surprise Soup Special and a piece of Honey and Bean Brittle.\n\r\nMaura chose a Fried Frog and a bowl of Pork Pudding.\n\r\nBradley selected a Mystery Meat Tourtiere and a plate of Chocolate Pickle Crunch.\n\r\n~~~~~~~~~~~~~~~~~~~~\r\nAfter picking at their food for quite a while, James, Bradley, Maura, and Leia all decided that brought lunches WEREN'T for losers. Every one of them brought a plain old PB&J sandwich the very next day.\n<|im_end|>" }, { "id": "#17722", "title": "Bunny Eating", "fun": 2.74, "difficulty": 2.38, "author": "Jake", "desc": "Several contestants are in a chocolate-bunny eating contest. After 20 minutes of stuffing their faces, all of the bunnies have been eaten. \n\r\nOne of the contestants remarks, \"Isn't it interesting that there were 7 times as many bunnies as contestants, but that each of us ate a different number of bunnies?\" \n\r\nAnother contestant replies, \"That certainly is interesting. I always eat the ears first and I noticed that when we had eaten a third of the bunnies that there were 4 fewer than 10 times as many bunny ears as human noses in the contest.\" \n\r\nHow many bunnies and contestants were in the contest?", "hint": "No hint available.", "answer": "42 bunnies and 6 contestants. \n\r\nFrom what the first contestant says, we know: \n\r\nBunnies = 7*Contestants\n\r\nFrom the second contestant we know:\n\r\n2*(2/3)*Bunnies = 10*Contestants - 4\n\r\nJust plug the first equation into the second equation and you can solve for Contestants, of which there are 6. Plug this back into the first equation to determine that there are 42 bunnies.", "category": "Math", "date": "05/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSeveral contestants are in a chocolate-bunny eating contest. After 20 minutes of stuffing their faces, all of the bunnies have been eaten. \n\r\nOne of the contestants remarks, \"Isn't it interesting that there were 7 times as many bunnies as contestants, but that each of us ate a different number of bunnies?\" \n\r\nAnother contestant replies, \"That certainly is interesting. I always eat the ears first and I noticed that when we had eaten a third of the bunnies that there were 4 fewer than 10 times as many bunny ears as human noses in the contest.\" \n\r\nHow many bunnies and contestants were in the contest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n42 bunnies and 6 contestants. \n\r\nFrom what the first contestant says, we know: \n\r\nBunnies = 7*Contestants\n\r\nFrom the second contestant we know:\n\r\n2*(2/3)*Bunnies = 10*Contestants - 4\n\r\nJust plug the first equation into the second equation and you can solve for Contestants, of which there are 6. Plug this back into the first equation to determine that there are 42 bunnies.\n<|im_start|>answer\n42 bunnies and 6 contestants. \n\r\nFrom what the first contestant says, we know: \n\r\nBunnies = 7*Contestants\n\r\nFrom the second contestant we know:\n\r\n2*(2/3)*Bunnies = 10*Contestants - 4\n\r\nJust plug the first equation into the second equation and you can solve for Contestants, of which there are 6. Plug this back into the first equation to determine that there are 42 bunnies.\n<|im_end|>" }, { "id": "#27581", "title": "Winning Colors", "fun": 2.74, "difficulty": 1.93, "author": "ilovehimalways", "desc": "This is the season for the Triple Crown races, the highlight of the year for everyone interested in horse racing, both fans and sportsmen alike. The three races - the Kentucky Derby, the Preakness, and the Belmont - have only been won by the same horse nine times in over 100 years of events. For this year's race, there were four popular horses signed up to run in the Kentucky Derby. While all four of them placed in the top four winners, none of them placed in the same position as their starting post position (the gate number where each horse started the race from). Determine the name of each racehorse, their starting post positions, the winning placement of each horse, and the stable colors of each racehorse.\n\n\r\nHorses: Galloping Grocer, Alec's Pride, OneForTheMoney, EatMyDust\r\nPost Positions: 2, 5, 6, 7\r\nPlaced: 1st, 2nd, 3rd, 4th\r\nStable Colors: Green and Black, Hot Pink, Blue and White, Purple and White\n\n\r\n1. Galloping Grocer didn't have hot pink stable colors. The fourth place horse didn't have the post position 2.\n\r\n2. The second place horse had a higher numbered post position than OneForTheMoney, but a lower post position than the Galloping Grocer.\n\r\n3. Eat My Dust had a post position one higher than the horse with blue & white stable colors.\n\r\n4. The purple and white stable colors belonged to the horse who won third place.\n\r\n5. The horse with post position 7 won the race. Alec's Pride had the green & black stable colors.\n\r\n6. The horse at post position 5 was not OneForTheMoney.", "hint": "Galloping Grocer did not win. In fact he was last.", "answer": "Galloping Grocer-6-4th-Blue and White\r\nAlec's Pride-5-2nd-Green and Black\r\nOneForTheMoney-2-3rd-Purple and White\r\nEat My Dust-7-1st-Hot Pink", "category": "Logic-Grid", "date": "12/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis is the season for the Triple Crown races, the highlight of the year for everyone interested in horse racing, both fans and sportsmen alike. The three races - the Kentucky Derby, the Preakness, and the Belmont - have only been won by the same horse nine times in over 100 years of events. For this year's race, there were four popular horses signed up to run in the Kentucky Derby. While all four of them placed in the top four winners, none of them placed in the same position as their starting post position (the gate number where each horse started the race from). Determine the name of each racehorse, their starting post positions, the winning placement of each horse, and the stable colors of each racehorse.\n\n\r\nHorses: Galloping Grocer, Alec's Pride, OneForTheMoney, EatMyDust\r\nPost Positions: 2, 5, 6, 7\r\nPlaced: 1st, 2nd, 3rd, 4th\r\nStable Colors: Green and Black, Hot Pink, Blue and White, Purple and White\n\n\r\n1. Galloping Grocer didn't have hot pink stable colors. The fourth place horse didn't have the post position 2.\n\r\n2. The second place horse had a higher numbered post position than OneForTheMoney, but a lower post position than the Galloping Grocer.\n\r\n3. Eat My Dust had a post position one higher than the horse with blue & white stable colors.\n\r\n4. The purple and white stable colors belonged to the horse who won third place.\n\r\n5. The horse with post position 7 won the race. Alec's Pride had the green & black stable colors.\n\r\n6. The horse at post position 5 was not OneForTheMoney.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGalloping Grocer-6-4th-Blue and White\r\nAlec's Pride-5-2nd-Green and Black\r\nOneForTheMoney-2-3rd-Purple and White\r\nEat My Dust-7-1st-Hot Pink\n<|im_start|>answer\nGalloping Grocer-6-4th-Blue and White\r\nAlec's Pride-5-2nd-Green and Black\r\nOneForTheMoney-2-3rd-Purple and White\r\nEat My Dust-7-1st-Hot Pink\n<|im_end|>" }, { "id": "#30581", "title": "Three Statements IX", "fun": 2.74, "difficulty": 1.51, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. There are six equally spaced beads on a circle. You need 30 straight lines to connect each bead with every other bead.\n\r\n2. The next number in this series is odd: 15...12...13...10...11...8... \n\r\n3. Sue walks one block west from her house. Then she walks two blocks south and one block east. She is now 2 blocks from her house.", "hint": "No hint available.", "answer": "Statements 2 and 3 are true, statement 1 is false.\n\r\nIn statement 1, each line connects two beads and cannot be counted twice, so you need only 15 straight lines.\n\r\nIn statement 2, the pattern is alternately -3 and +1. The next number is 9, which is odd.\n\r\nIn statement 3, the \"one block west\" and \"one block east\" cancel out each other, and she ends up 2 blocks south from her house.", "category": "Logic", "date": "05/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. There are six equally spaced beads on a circle. You need 30 straight lines to connect each bead with every other bead.\n\r\n2. The next number in this series is odd: 15...12...13...10...11...8... \n\r\n3. Sue walks one block west from her house. Then she walks two blocks south and one block east. She is now 2 blocks from her house.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 2 and 3 are true, statement 1 is false.\n\r\nIn statement 1, each line connects two beads and cannot be counted twice, so you need only 15 straight lines.\n\r\nIn statement 2, the pattern is alternately -3 and +1. The next number is 9, which is odd.\n\r\nIn statement 3, the \"one block west\" and \"one block east\" cancel out each other, and she ends up 2 blocks south from her house.\n<|im_start|>answer\nStatements 2 and 3 are true, statement 1 is false.\n\r\nIn statement 1, each line connects two beads and cannot be counted twice, so you need only 15 straight lines.\n\r\nIn statement 2, the pattern is alternately -3 and +1. The next number is 9, which is odd.\n\r\nIn statement 3, the \"one block west\" and \"one block east\" cancel out each other, and she ends up 2 blocks south from her house.\n<|im_end|>" }, { "id": "#26355", "title": "Visualize", "fun": 2.74, "difficulty": 1.53, "author": "fishmed", "desc": "Visualize a cube. You know it has 6 faces, 8 corners, and 12 edges. Now, imagine a knife slicing away each corner with a straight plane cut. \r\nHow many total edges are there now?", "hint": "A straight plane cut is a straight, smooth diagonal cut.", "answer": "There are now 36 edges.\r\n(The original 12 edges, plus 3 more for each of the 8 corners, making 36.)", "category": "Math", "date": "10/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nVisualize a cube. You know it has 6 faces, 8 corners, and 12 edges. Now, imagine a knife slicing away each corner with a straight plane cut. \r\nHow many total edges are there now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are now 36 edges.\r\n(The original 12 edges, plus 3 more for each of the 8 corners, making 36.)\n<|im_start|>answer\nThere are now 36 edges.\r\n(The original 12 edges, plus 3 more for each of the 8 corners, making 36.)\n<|im_end|>" }, { "id": "#30327", "title": "College Reunion", "fun": 2.74, "difficulty": 1.56, "author": "phrebh", "desc": "Three college friends, two males (Aldritch and Fred) and one female (Nikita), were at their 10 year class reunion. They talked about their favorites cuisines (Asian, European, and Tex-Mex), what they like to read (books, magazines, and online articles), and their hometowns (Ottumwa, Sausalito, and Toledo). During the course of the evening, they all also lied about their professions (CEO, doctor, pilot). Using the clues, determine each person's favorite cuisine, reading materials, hometowns, and what jobs they professed to have.\n\r\n1. The three people are the one who likes European food, the one from Toledo, and the one that prefers books.\n\r\n2. Nikita did not say that she was a CEO.\n\r\n3. The three cuisines are the one eaten by the magazine reader, the one that the man from Toledo likes, and the one that the \"doctor\" likes.\n\r\n4. The three professions lied about are the pilot, the one that Nikita said she did, and the one that the man from Sausalito said he did.\n\r\n5. The \"pilot\" likes food from North America.\n\r\n6. Aldritch always wanted to fly.", "hint": "No hint available.", "answer": "Aldritch likes Tex-Mex food, said he was a pilot, comes from Toledo, and reads online.\r\nFred likes European food, said he was a CEO, comes from Sausalito, and reads magazines.\r\nNikita likes Asian food, said she was a doctor, comes from Ottumwa, and reads books.", "category": "Logic-Grid", "date": "05/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree college friends, two males (Aldritch and Fred) and one female (Nikita), were at their 10 year class reunion. They talked about their favorites cuisines (Asian, European, and Tex-Mex), what they like to read (books, magazines, and online articles), and their hometowns (Ottumwa, Sausalito, and Toledo). During the course of the evening, they all also lied about their professions (CEO, doctor, pilot). Using the clues, determine each person's favorite cuisine, reading materials, hometowns, and what jobs they professed to have.\n\r\n1. The three people are the one who likes European food, the one from Toledo, and the one that prefers books.\n\r\n2. Nikita did not say that she was a CEO.\n\r\n3. The three cuisines are the one eaten by the magazine reader, the one that the man from Toledo likes, and the one that the \"doctor\" likes.\n\r\n4. The three professions lied about are the pilot, the one that Nikita said she did, and the one that the man from Sausalito said he did.\n\r\n5. The \"pilot\" likes food from North America.\n\r\n6. Aldritch always wanted to fly.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAldritch likes Tex-Mex food, said he was a pilot, comes from Toledo, and reads online.\r\nFred likes European food, said he was a CEO, comes from Sausalito, and reads magazines.\r\nNikita likes Asian food, said she was a doctor, comes from Ottumwa, and reads books.\n<|im_start|>answer\nAldritch likes Tex-Mex food, said he was a pilot, comes from Toledo, and reads online.\r\nFred likes European food, said he was a CEO, comes from Sausalito, and reads magazines.\r\nNikita likes Asian food, said she was a doctor, comes from Ottumwa, and reads books.\n<|im_end|>" }, { "id": "#41891", "title": "Eyes and Hair", "fun": 2.74, "difficulty": 1.42, "author": "whsprec", "desc": "4 friends, Josh, John, Kim, and Amber, went to a party. Each of them had different color eyes and hair. The eye colors were blue, green, brown, and hazel. The hair colors were blonde, red, brown, and black. Match the person to their correct hair color and eye color.\n\r\n1- The girls do not have green eyes.\r\n2- Josh doesn't have blonde hair, but John's is red.\r\n3- The person who has brown hair and hazel eyes sat next to the blonde with brown eyes.\r\n4- John's eyes are not brown.\r\n5- Amber's hair is black.", "hint": "No hint available.", "answer": "John- Green eyes, Red hair\r\nAmber- Blue eyes, Black hair\r\nJosh- Hazel eyes, Brown hair\r\nKim- Brown eyes, Blonde hair", "category": "Logic", "date": "05/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 friends, Josh, John, Kim, and Amber, went to a party. Each of them had different color eyes and hair. The eye colors were blue, green, brown, and hazel. The hair colors were blonde, red, brown, and black. Match the person to their correct hair color and eye color.\n\r\n1- The girls do not have green eyes.\r\n2- Josh doesn't have blonde hair, but John's is red.\r\n3- The person who has brown hair and hazel eyes sat next to the blonde with brown eyes.\r\n4- John's eyes are not brown.\r\n5- Amber's hair is black.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn- Green eyes, Red hair\r\nAmber- Blue eyes, Black hair\r\nJosh- Hazel eyes, Brown hair\r\nKim- Brown eyes, Blonde hair\n<|im_start|>answer\nJohn- Green eyes, Red hair\r\nAmber- Blue eyes, Black hair\r\nJosh- Hazel eyes, Brown hair\r\nKim- Brown eyes, Blonde hair\n<|im_end|>" }, { "id": "#26526", "title": "Sandbox Disaster", "fun": 2.74, "difficulty": 0.67, "author": "Kalliann", "desc": "Five mothers decided to take their adorable children to the park. Each woman allowed her child to bring one toy. All the children raced to the sandbox with their toy. They had so much fun in the sandbox that all the toys got mixed up, and each mother lost track of her child. Can you help them sort this mess out so each child goes home with the correct toy, and each parent goes home with the correct child?\n\r\nMothers: Shelby, Monica, Lisa, Abbie, and Marie\n\r\nChildren: Zach, Tim, Chris, Laura, and Natalie\n\r\nToys: dump truck, shovel, bucket, doll, and car \n\r\nClues:\n\r\n1) The child with the dump truck is not Chris or Zach. \n\r\n2) Monica's son brought a bucket, but his name is not Tim.\n\r\n3) Lisa's daughter shares a first initial with her mother and she brought a shovel along. \n\r\n4) The doll belongs to Abbie's daughter. \n\r\n5) Zach is Marie's son.", "hint": "The only female children are Natalie and Laura.", "answer": "Thank you for getting everybody back together! \n\r\n1. Shelby is Tim's mother and they brought the dump truck.\n\r\n2. Monica is Chris's mother and they brought the bucket.\n\r\n3. Lisa is Laura's mother and they brought the shovel. \n\r\n4. Abbie is Natalie's mother and they brought the doll. \n\r\n5. Marie is Zach's mother and they brought the car.", "category": "Logic-Grid", "date": "10/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive mothers decided to take their adorable children to the park. Each woman allowed her child to bring one toy. All the children raced to the sandbox with their toy. They had so much fun in the sandbox that all the toys got mixed up, and each mother lost track of her child. Can you help them sort this mess out so each child goes home with the correct toy, and each parent goes home with the correct child?\n\r\nMothers: Shelby, Monica, Lisa, Abbie, and Marie\n\r\nChildren: Zach, Tim, Chris, Laura, and Natalie\n\r\nToys: dump truck, shovel, bucket, doll, and car \n\r\nClues:\n\r\n1) The child with the dump truck is not Chris or Zach. \n\r\n2) Monica's son brought a bucket, but his name is not Tim.\n\r\n3) Lisa's daughter shares a first initial with her mother and she brought a shovel along. \n\r\n4) The doll belongs to Abbie's daughter. \n\r\n5) Zach is Marie's son.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThank you for getting everybody back together! \n\r\n1. Shelby is Tim's mother and they brought the dump truck.\n\r\n2. Monica is Chris's mother and they brought the bucket.\n\r\n3. Lisa is Laura's mother and they brought the shovel. \n\r\n4. Abbie is Natalie's mother and they brought the doll. \n\r\n5. Marie is Zach's mother and they brought the car.\n<|im_start|>answer\nThank you for getting everybody back together! \n\r\n1. Shelby is Tim's mother and they brought the dump truck.\n\r\n2. Monica is Chris's mother and they brought the bucket.\n\r\n3. Lisa is Laura's mother and they brought the shovel. \n\r\n4. Abbie is Natalie's mother and they brought the doll. \n\r\n5. Marie is Zach's mother and they brought the car.\n<|im_end|>" }, { "id": "#51074", "title": "Can You Figure Out The ?", "fun": 2.74, "difficulty": 2.16, "author": "fishmed", "desc": "Consider the following. What is the number that fits in the \"?\" \n\r\n8809=6\r\n1234=1\r\n5482=3\r\n8805=5\r\n7777=0\r\n6363=2\r\n2172=0\r\n4141=2\r\n8523=2\r\n1257=0\r\n2581=?", "hint": "The hint is closed...", "answer": "2581=2\n\r\nEach number's answer is calculated by the number of closed loops/sections in all the numbers. \n\r\nThe hint talks about 'closed' sections of the numbers\". \n\r\n1=0\r\n2=0\r\n3=0\r\n4=1\r\n5=0\r\n6=1\r\n7=0\r\n8=2\r\n9=1\r\n0=1", "category": "Math", "date": "05/05/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nConsider the following. What is the number that fits in the \"?\" \n\r\n8809=6\r\n1234=1\r\n5482=3\r\n8805=5\r\n7777=0\r\n6363=2\r\n2172=0\r\n4141=2\r\n8523=2\r\n1257=0\r\n2581=?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2581=2\n\r\nEach number's answer is calculated by the number of closed loops/sections in all the numbers. \n\r\nThe hint talks about 'closed' sections of the numbers\". \n\r\n1=0\r\n2=0\r\n3=0\r\n4=1\r\n5=0\r\n6=1\r\n7=0\r\n8=2\r\n9=1\r\n0=1\n<|im_start|>answer\n2581=2\n\r\nEach number's answer is calculated by the number of closed loops/sections in all the numbers. \n\r\nThe hint talks about 'closed' sections of the numbers\". \n\r\n1=0\r\n2=0\r\n3=0\r\n4=1\r\n5=0\r\n6=1\r\n7=0\r\n8=2\r\n9=1\r\n0=1\n<|im_end|>" }, { "id": "#38403", "title": "A Very Good Year", "fun": 2.74, "difficulty": 2.79, "author": "soccerguy0428", "desc": "The year 1978 has an unusual property. When you add the 19 to the 78, the total is the same as the middle two digits (97). What will be the next year to have this same property?", "hint": "No hint available.", "answer": "The next year to have the same property will be 2307.\n\r\n23 + 07 = 30", "category": "Math", "date": "09/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe year 1978 has an unusual property. When you add the 19 to the 78, the total is the same as the middle two digits (97). What will be the next year to have this same property?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe next year to have the same property will be 2307.\n\r\n23 + 07 = 30\n<|im_start|>answer\nThe next year to have the same property will be 2307.\n\r\n23 + 07 = 30\n<|im_end|>" }, { "id": "#42714", "title": "Raccoon Frenzy", "fun": 2.74, "difficulty": 1.97, "author": "postgirl", "desc": "The neighborhood raccoons visited Corey and Jane almost every night last week, as they have all summer. Raccoons are solitary animals so each one of them visited the home alone and on a different night of the week. Despite the similar appearance of the five raccoons, Jane has come to recognize each of them, has given them first and last names, and knows their favorite treats. From the information given below, can you determine the first and last name of each raccoon, their favorite treat, and the night they visited?\n\r\n1) Bubba, who does not like cat food, visited the day before Mr. Bojangles and two days after the raccoon who loves granola bars.\n\r\n2) Janet always begs for hot dogs, but must have other plans on the weekend (though apparently not with Mr. Smartnotsky).\n\r\n3) The raccoons visited in the following order: The one with the last name of Fancy Pants, Rocky (whose last name is not Fang), JoJo, the one who loves to eat bugs, and the one who likes to play in a pan of water.", "hint": "No hint available.", "answer": "Janet Fancy Pants ate hot dogs Monday evening.\r\nRocky Raccoon ate a pile of cat food on Wednesday night.\r\nJoJo Fang ate his fill of granola bars on Thursday.\r\nBubba Smartnotsky captured and ate bugs on Saturday night.\r\nCharles Bojangles played in his pan of water on Sunday night.", "category": "Logic-Grid", "date": "08/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe neighborhood raccoons visited Corey and Jane almost every night last week, as they have all summer. Raccoons are solitary animals so each one of them visited the home alone and on a different night of the week. Despite the similar appearance of the five raccoons, Jane has come to recognize each of them, has given them first and last names, and knows their favorite treats. From the information given below, can you determine the first and last name of each raccoon, their favorite treat, and the night they visited?\n\r\n1) Bubba, who does not like cat food, visited the day before Mr. Bojangles and two days after the raccoon who loves granola bars.\n\r\n2) Janet always begs for hot dogs, but must have other plans on the weekend (though apparently not with Mr. Smartnotsky).\n\r\n3) The raccoons visited in the following order: The one with the last name of Fancy Pants, Rocky (whose last name is not Fang), JoJo, the one who loves to eat bugs, and the one who likes to play in a pan of water.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJanet Fancy Pants ate hot dogs Monday evening.\r\nRocky Raccoon ate a pile of cat food on Wednesday night.\r\nJoJo Fang ate his fill of granola bars on Thursday.\r\nBubba Smartnotsky captured and ate bugs on Saturday night.\r\nCharles Bojangles played in his pan of water on Sunday night.\n<|im_start|>answer\nJanet Fancy Pants ate hot dogs Monday evening.\r\nRocky Raccoon ate a pile of cat food on Wednesday night.\r\nJoJo Fang ate his fill of granola bars on Thursday.\r\nBubba Smartnotsky captured and ate bugs on Saturday night.\r\nCharles Bojangles played in his pan of water on Sunday night.\n<|im_end|>" }, { "id": "#25267", "title": "Auction Action", "fun": 2.74, "difficulty": 2.15, "author": "nortredamenumbe", "desc": "Nina and her mom helped organize the auction fundraiser to help pay for the 8th grade musical. Seven local stores each donated a gift certificate to be redeemed for merchandise. The gift certificates will be auctioned off at the big event.\n\r\nThe Athlete's Alley, Bay State Basement, CD Corner, Don's Deli, Elk's Software, Fancy Footwear Shop, and the Gorgeous Candy Boutique have all participated.\n\r\nThe gift certificates are each in multiples of $5. There is a $100 range in the value of the gift certificates, which start at $25. The mean value of all seven gift certificates is $80, and the median and the mode are both $70.\n\n\r\nThe certificate from The Athlete's Alley is worth the most, and the one from Gorgeous Candy is worth the least. \n\r\nThe total value of the gift certificates from CD Corner, Don's Deli, and the Fancy Footwear Shop is $270, but the Fancy Footwear certificate is worth $50 more than the one from Don's Deli. The CD Corner gift certificate is equivalent to the mean for this group of 3 stores. \n\r\nWhat is the value of the gift certificate from each store?", "hint": "No hint available.", "answer": "The Athlete's Alley $125 \r\nBay State Basement $70 \r\nCD Corner $90 \r\nDon's Deli $65 \r\nElk's Software $70 \r\nFancy Footwear Shop $115 \r\nGorgeous Candy Boutique $25\n\r\nExplanation:\n\r\nSince the mean of all gift certificates is $80, and there are 7 stores, the total of all gift certificates is $560.\n\r\nThe values of the gift certificates range from $25 to $125, therefore the gift certificate from Athlete's Alley is $125 and the gift certificate from Gorgeous Candy Boutique is $25.\n\r\nThis leaves $410 in gift certificates from the other 5 stores.\n\r\nThe gift certificates from CD Corner, Don's Deli and Fancy Footwear Shop total $270. The mean of this group is $90, which is value of the certificate from the CD shop.\n\r\nThis leaves $180 for Don's Deli and Fancy Footwear. Because Fancy Footwear is worth $50 more, the certificate from Don's Deli is half of $130, or $65 dollars, and the certificate from Fancy Footwear is $115.\n\r\nThis leaves the certificates from Bay State Basement and Elk's Software, totalling $140. There's only way to meet the requirement that the median and mode of the 7 values is $70. Both remaining certificates must be valued at $70.", "category": "Math", "date": "08/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNina and her mom helped organize the auction fundraiser to help pay for the 8th grade musical. Seven local stores each donated a gift certificate to be redeemed for merchandise. The gift certificates will be auctioned off at the big event.\n\r\nThe Athlete's Alley, Bay State Basement, CD Corner, Don's Deli, Elk's Software, Fancy Footwear Shop, and the Gorgeous Candy Boutique have all participated.\n\r\nThe gift certificates are each in multiples of $5. There is a $100 range in the value of the gift certificates, which start at $25. The mean value of all seven gift certificates is $80, and the median and the mode are both $70.\n\n\r\nThe certificate from The Athlete's Alley is worth the most, and the one from Gorgeous Candy is worth the least. \n\r\nThe total value of the gift certificates from CD Corner, Don's Deli, and the Fancy Footwear Shop is $270, but the Fancy Footwear certificate is worth $50 more than the one from Don's Deli. The CD Corner gift certificate is equivalent to the mean for this group of 3 stores. \n\r\nWhat is the value of the gift certificate from each store?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Athlete's Alley $125 \r\nBay State Basement $70 \r\nCD Corner $90 \r\nDon's Deli $65 \r\nElk's Software $70 \r\nFancy Footwear Shop $115 \r\nGorgeous Candy Boutique $25\n\r\nExplanation:\n\r\nSince the mean of all gift certificates is $80, and there are 7 stores, the total of all gift certificates is $560.\n\r\nThe values of the gift certificates range from $25 to $125, therefore the gift certificate from Athlete's Alley is $125 and the gift certificate from Gorgeous Candy Boutique is $25.\n\r\nThis leaves $410 in gift certificates from the other 5 stores.\n\r\nThe gift certificates from CD Corner, Don's Deli and Fancy Footwear Shop total $270. The mean of this group is $90, which is value of the certificate from the CD shop.\n\r\nThis leaves $180 for Don's Deli and Fancy Footwear. Because Fancy Footwear is worth $50 more, the certificate from Don's Deli is half of $130, or $65 dollars, and the certificate from Fancy Footwear is $115.\n\r\nThis leaves the certificates from Bay State Basement and Elk's Software, totalling $140. There's only way to meet the requirement that the median and mode of the 7 values is $70. Both remaining certificates must be valued at $70.\n<|im_start|>answer\nThe Athlete's Alley $125 \r\nBay State Basement $70 \r\nCD Corner $90 \r\nDon's Deli $65 \r\nElk's Software $70 \r\nFancy Footwear Shop $115 \r\nGorgeous Candy Boutique $25\n\r\nExplanation:\n\r\nSince the mean of all gift certificates is $80, and there are 7 stores, the total of all gift certificates is $560.\n\r\nThe values of the gift certificates range from $25 to $125, therefore the gift certificate from Athlete's Alley is $125 and the gift certificate from Gorgeous Candy Boutique is $25.\n\r\nThis leaves $410 in gift certificates from the other 5 stores.\n\r\nThe gift certificates from CD Corner, Don's Deli and Fancy Footwear Shop total $270. The mean of this group is $90, which is value of the certificate from the CD shop.\n\r\nThis leaves $180 for Don's Deli and Fancy Footwear. Because Fancy Footwear is worth $50 more, the certificate from Don's Deli is half of $130, or $65 dollars, and the certificate from Fancy Footwear is $115.\n\r\nThis leaves the certificates from Bay State Basement and Elk's Software, totalling $140. There's only way to meet the requirement that the median and mode of the 7 values is $70. Both remaining certificates must be valued at $70.\n<|im_end|>" }, { "id": "#46931", "title": "Star Trek Aliens", "fun": 2.74, "difficulty": 2.29, "author": "whsprec", "desc": "The annual Star Trek convention was in town and as a result, aliens and Trekkies overran the town. Five friends came dressed up as aliens from different planets which Star Fleet had made contact with over the years. Each planet orbited a different star, and had a different size population. From the clues given, determine the name of the planet, the year Star Fleet made contact, the star the planet orbits, and the size of the population.\n\r\n1) The population of Kappa is larger than that of the planet orbiting Polaris, which made contact earlier than Kappa.\r\n2) Wezen is the star whose planet, which is not named Rho, has a population of 9.5 million.\r\n3) Zeta is the planet around Albati, which was not the last one to make contact.\r\n4) The Mu contact took place in 2161.\r\n5) Contact was made in 2217 with Betelgeuse system, whose population was smaller than the planet contacted in 2202.\r\n6) The largest population is on Pi, contacted next after the smallest population.\r\n7) 12 million was the population of the planet contacted after the planet in the Electra system.", "hint": "No hint available.", "answer": "In 2148 contact was made with Zeta in the Albati system with a population of 10 million.\r\nIn 2161 contact was made with Mu in the Polaris system with a population of 8.5 million.\r\nIn 2202 contact was made with Pi in the Electra system with a population of 15 million.\r\nIn 2217 contact was made with Rho in the Betelgeuse system with a population of 12 million.\r\nIn 2238 contact was made with Kappa in the Wezen system with a population of 9.5 million.", "category": "Logic-Grid", "date": "05/05/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe annual Star Trek convention was in town and as a result, aliens and Trekkies overran the town. Five friends came dressed up as aliens from different planets which Star Fleet had made contact with over the years. Each planet orbited a different star, and had a different size population. From the clues given, determine the name of the planet, the year Star Fleet made contact, the star the planet orbits, and the size of the population.\n\r\n1) The population of Kappa is larger than that of the planet orbiting Polaris, which made contact earlier than Kappa.\r\n2) Wezen is the star whose planet, which is not named Rho, has a population of 9.5 million.\r\n3) Zeta is the planet around Albati, which was not the last one to make contact.\r\n4) The Mu contact took place in 2161.\r\n5) Contact was made in 2217 with Betelgeuse system, whose population was smaller than the planet contacted in 2202.\r\n6) The largest population is on Pi, contacted next after the smallest population.\r\n7) 12 million was the population of the planet contacted after the planet in the Electra system.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn 2148 contact was made with Zeta in the Albati system with a population of 10 million.\r\nIn 2161 contact was made with Mu in the Polaris system with a population of 8.5 million.\r\nIn 2202 contact was made with Pi in the Electra system with a population of 15 million.\r\nIn 2217 contact was made with Rho in the Betelgeuse system with a population of 12 million.\r\nIn 2238 contact was made with Kappa in the Wezen system with a population of 9.5 million.\n<|im_start|>answer\nIn 2148 contact was made with Zeta in the Albati system with a population of 10 million.\r\nIn 2161 contact was made with Mu in the Polaris system with a population of 8.5 million.\r\nIn 2202 contact was made with Pi in the Electra system with a population of 15 million.\r\nIn 2217 contact was made with Rho in the Betelgeuse system with a population of 12 million.\r\nIn 2238 contact was made with Kappa in the Wezen system with a population of 9.5 million.\n<|im_end|>" }, { "id": "#656", "title": "War Prisoner", "fun": 2.73, "difficulty": 1.65, "author": "vikass", "desc": "During the first world war, there was a prisoner who had been captured. When brought to the army headquarters, the prisoner was told that he had a choice to remain silent or say something. He was also told that if he did say something, he would be shot if he spoke the truth or hanged if he had lied. The war prisoner did in fact make a single statement; he said only a phrase and they had to let him go unscathed. What did the prisoner say to get out free?", "hint": "No hint available.", "answer": "The prisoner told them: \"You will hang me.\"", "category": "Logic", "date": "06/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring the first world war, there was a prisoner who had been captured. When brought to the army headquarters, the prisoner was told that he had a choice to remain silent or say something. He was also told that if he did say something, he would be shot if he spoke the truth or hanged if he had lied. The war prisoner did in fact make a single statement; he said only a phrase and they had to let him go unscathed. What did the prisoner say to get out free?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe prisoner told them: \"You will hang me.\"\n<|im_start|>answer\nThe prisoner told them: \"You will hang me.\"\n<|im_end|>" }, { "id": "#29616", "title": "Animal Habitats", "fun": 2.73, "difficulty": 1.84, "author": "Victor", "desc": "Alison, Chad, Ivelisse, Jaimie, Nick, Tony, and Vicky are all illustrating animals and their habitats for their wildlife project. Each person signed up with Mrs. Fisher to be sure that no one else was using the same animal.\n\r\nUse the data and the clues below, and your knowledge of animals to find out who painted each picture.\n\r\nData:\n\r\nantelope: grassy plains\r\ncamel: deserts\r\nhippopotamus: swampy forests\r\nocelot: forests\r\norangutan: trees in forests\r\npolar bear: arctic ice and land\r\nzebra: grasslands\n\r\nClues:\n\r\n1. Tony and Vicky checked several books to learn about the grassy habitats for their animals. \r\n2. Alison, Ivelisse, and Jaimie all noticed that their animals like trees. Jaimie commented that hers was the only animal that was a member of the ape family. \r\n3. Nick's animal survives in extremely cold climates, and Chad's animal can tolerate extreme heat as well as cooler temperatures. \r\n4. Ivelisse said her animal was one of the heaviest, sometimes weighing up to 9,000 pounds. Her picture shows the huge animal in water. \r\n5. Vicky had fun drawing the striped pattern on her animal.", "hint": "Make a chart to eliminate the impossibilities.", "answer": "Alison illustrated an ocelot. \r\nChad illustrated a camel.\r\nIvelisse illustrated a hippopotamus.\r\nJaimie illustrated an orangutan.\r\nNick illustrated a polar bear.\r\nTony illustrated an antelope.\r\nVicky illustrated a zebra.", "category": "Logic", "date": "04/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlison, Chad, Ivelisse, Jaimie, Nick, Tony, and Vicky are all illustrating animals and their habitats for their wildlife project. Each person signed up with Mrs. Fisher to be sure that no one else was using the same animal.\n\r\nUse the data and the clues below, and your knowledge of animals to find out who painted each picture.\n\r\nData:\n\r\nantelope: grassy plains\r\ncamel: deserts\r\nhippopotamus: swampy forests\r\nocelot: forests\r\norangutan: trees in forests\r\npolar bear: arctic ice and land\r\nzebra: grasslands\n\r\nClues:\n\r\n1. Tony and Vicky checked several books to learn about the grassy habitats for their animals. \r\n2. Alison, Ivelisse, and Jaimie all noticed that their animals like trees. Jaimie commented that hers was the only animal that was a member of the ape family. \r\n3. Nick's animal survives in extremely cold climates, and Chad's animal can tolerate extreme heat as well as cooler temperatures. \r\n4. Ivelisse said her animal was one of the heaviest, sometimes weighing up to 9,000 pounds. Her picture shows the huge animal in water. \r\n5. Vicky had fun drawing the striped pattern on her animal.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlison illustrated an ocelot. \r\nChad illustrated a camel.\r\nIvelisse illustrated a hippopotamus.\r\nJaimie illustrated an orangutan.\r\nNick illustrated a polar bear.\r\nTony illustrated an antelope.\r\nVicky illustrated a zebra.\n<|im_start|>answer\nAlison illustrated an ocelot. \r\nChad illustrated a camel.\r\nIvelisse illustrated a hippopotamus.\r\nJaimie illustrated an orangutan.\r\nNick illustrated a polar bear.\r\nTony illustrated an antelope.\r\nVicky illustrated a zebra.\n<|im_end|>" }, { "id": "#34877", "title": "Shoe Available", "fun": 2.73, "difficulty": 3.02, "author": "Gizzer", "desc": "The old woman who lives in a shoe has finally reached mandatory retirement age, and Mother Goose is now interviewing possible replacements. None of the five applicants is currently living in a shoe, though each notes on his or her application that he or she is living in a different eccentric domicile. And, although none has children, each applicant shares his or her abode with a number of domestic animals. No two keep the same type of animal.\n\r\nWhile Mother Goose checks with her personnel department, see if you can match each applicant up with his or her domicile, as well as with the number and type of domestic animals each owns.\n\r\nNames: Fanny, Gladys, Horace, Inez, Joe\r\nDomiciles: banjo, churn, gourd, hat, jukebox\r\nAnimals: cats, chickens, geese, pigs, sheep\r\nNumbers: not provided - you have to figure them out!\n\r\nTBD (in the grid) = to be determined\r\nClues:\n\r\n1. Two applicants have the same number of animals, while each of the others has a different number.\n\r\n2. The one who keeps geese lives in a jukebox.\n\r\n3. Joe shares his abode with chickens.\n\r\n4. The one who lives in a gourd has four fewer animals than Gladys (who doesn't raise sheep).\n\r\n5. Fanny has 15 animals, which isn't the lowest number.\n\r\n6. The one who shares his or her domicile with 19 sheep (who doesn't live in the churn) doesn't have the most animals.\n\r\n7. The one who keeps cats doesn't have the lowest number of animals, but he or she does have three fewer animals than the applicant who lives in a banjo.\n\r\n8. Inez (who doesn't live in a hat) has three fewer animals than another applicant.", "hint": "No hint available.", "answer": "Fanny lives in a gourd with 15 pigs.\r\nGladys lives in a churn with 19 cats.\r\nHorace lives in a hat with 19 sheep.\r\nInez lives in a jukebox with 12 geese.\r\nJoe lives in a banjo with 22 chickens.\n\n\r\nExplanation:\n\r\nSomeone has fewer than 15 animals (clue 5), and someone has more than 19 animals (clue 6). Therefore, the four unique numbers of animals are: the least, 15, 19 and the most. The fifth number matches one of these (clue 1).\n\r\nThe number of cats is neither the least nor the most, nor can there be 15 cats, as then someone would have 18 animals, which isn't possible. Therefore, there are 19 cats, and the \"most\" animals is 22 (clue 7). There are also 19 sheep (clue 6), so the numbers of animals are: the least, 15, 19, 19 and 22.\n\r\nGladys can't have the least animals, or the most (22), as then someone would have to have 18 animals (clue 4). Since Fanny has 15 animals, Gladys must have 19, and since she doesn't have sheep (clue 4), she has the 19 cats. This means that Fanny lives in the gourd (clue 4). She doesn't keep chickens (clue 3) or geese (clue 2), so Fanny has 15 pigs. The geese live in the jukebox, therefore Joe must live in the banjo with his 22 chickens (clues 3 and 7).\n\r\nThe sheep don't live in the churn (clue 6), so they live in the hat, and the cats live in the churn. (Remember, \"The Cat in the Hat\" is Dr. Seuss, not Mother Goose!) \n\r\nInez doesn't live in the hat, so Horace does, while Inez lives in the jukebox with her 12 geese (clue 8).", "category": "Logic-Grid", "date": "01/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe old woman who lives in a shoe has finally reached mandatory retirement age, and Mother Goose is now interviewing possible replacements. None of the five applicants is currently living in a shoe, though each notes on his or her application that he or she is living in a different eccentric domicile. And, although none has children, each applicant shares his or her abode with a number of domestic animals. No two keep the same type of animal.\n\r\nWhile Mother Goose checks with her personnel department, see if you can match each applicant up with his or her domicile, as well as with the number and type of domestic animals each owns.\n\r\nNames: Fanny, Gladys, Horace, Inez, Joe\r\nDomiciles: banjo, churn, gourd, hat, jukebox\r\nAnimals: cats, chickens, geese, pigs, sheep\r\nNumbers: not provided - you have to figure them out!\n\r\nTBD (in the grid) = to be determined\r\nClues:\n\r\n1. Two applicants have the same number of animals, while each of the others has a different number.\n\r\n2. The one who keeps geese lives in a jukebox.\n\r\n3. Joe shares his abode with chickens.\n\r\n4. The one who lives in a gourd has four fewer animals than Gladys (who doesn't raise sheep).\n\r\n5. Fanny has 15 animals, which isn't the lowest number.\n\r\n6. The one who shares his or her domicile with 19 sheep (who doesn't live in the churn) doesn't have the most animals.\n\r\n7. The one who keeps cats doesn't have the lowest number of animals, but he or she does have three fewer animals than the applicant who lives in a banjo.\n\r\n8. Inez (who doesn't live in a hat) has three fewer animals than another applicant.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFanny lives in a gourd with 15 pigs.\r\nGladys lives in a churn with 19 cats.\r\nHorace lives in a hat with 19 sheep.\r\nInez lives in a jukebox with 12 geese.\r\nJoe lives in a banjo with 22 chickens.\n\n\r\nExplanation:\n\r\nSomeone has fewer than 15 animals (clue 5), and someone has more than 19 animals (clue 6). Therefore, the four unique numbers of animals are: the least, 15, 19 and the most. The fifth number matches one of these (clue 1).\n\r\nThe number of cats is neither the least nor the most, nor can there be 15 cats, as then someone would have 18 animals, which isn't possible. Therefore, there are 19 cats, and the \"most\" animals is 22 (clue 7). There are also 19 sheep (clue 6), so the numbers of animals are: the least, 15, 19, 19 and 22.\n\r\nGladys can't have the least animals, or the most (22), as then someone would have to have 18 animals (clue 4). Since Fanny has 15 animals, Gladys must have 19, and since she doesn't have sheep (clue 4), she has the 19 cats. This means that Fanny lives in the gourd (clue 4). She doesn't keep chickens (clue 3) or geese (clue 2), so Fanny has 15 pigs. The geese live in the jukebox, therefore Joe must live in the banjo with his 22 chickens (clues 3 and 7).\n\r\nThe sheep don't live in the churn (clue 6), so they live in the hat, and the cats live in the churn. (Remember, \"The Cat in the Hat\" is Dr. Seuss, not Mother Goose!) \n\r\nInez doesn't live in the hat, so Horace does, while Inez lives in the jukebox with her 12 geese (clue 8).\n<|im_start|>answer\nFanny lives in a gourd with 15 pigs.\r\nGladys lives in a churn with 19 cats.\r\nHorace lives in a hat with 19 sheep.\r\nInez lives in a jukebox with 12 geese.\r\nJoe lives in a banjo with 22 chickens.\n\n\r\nExplanation:\n\r\nSomeone has fewer than 15 animals (clue 5), and someone has more than 19 animals (clue 6). Therefore, the four unique numbers of animals are: the least, 15, 19 and the most. The fifth number matches one of these (clue 1).\n\r\nThe number of cats is neither the least nor the most, nor can there be 15 cats, as then someone would have 18 animals, which isn't possible. Therefore, there are 19 cats, and the \"most\" animals is 22 (clue 7). There are also 19 sheep (clue 6), so the numbers of animals are: the least, 15, 19, 19 and 22.\n\r\nGladys can't have the least animals, or the most (22), as then someone would have to have 18 animals (clue 4). Since Fanny has 15 animals, Gladys must have 19, and since she doesn't have sheep (clue 4), she has the 19 cats. This means that Fanny lives in the gourd (clue 4). She doesn't keep chickens (clue 3) or geese (clue 2), so Fanny has 15 pigs. The geese live in the jukebox, therefore Joe must live in the banjo with his 22 chickens (clues 3 and 7).\n\r\nThe sheep don't live in the churn (clue 6), so they live in the hat, and the cats live in the churn. (Remember, \"The Cat in the Hat\" is Dr. Seuss, not Mother Goose!) \n\r\nInez doesn't live in the hat, so Horace does, while Inez lives in the jukebox with her 12 geese (clue 8).\n<|im_end|>" }, { "id": "#19756", "title": "PHOTO-LOGICAL", "fun": 2.73, "difficulty": 1.57, "author": "Nishoo", "desc": "Mrs. Botanee , the science teacher at Dandelion High School, held a \"Nature is Remarkable\" photo contest. The five prize-winning students were Carole, Charlie, Johnny, Oliver and Susan. The subjects they photographed were dewdrops, hummingbirds, red ants, a spider web and termites. \n\r\nFrom the information given, determine the subject of each student's photograph as well as the order in which the five students finished.\n\r\n1. The photo of termites received a higher prize than Johnny's photo but a lower prize than those of both girls\n\r\n2. A girl took the photo of the spider web.\n\r\n3. The boy whose photo won is not named Charlie and neither of these two boys entered a photo of either a hummingbird or red ants.\n\r\n4. Susan's photo received a lower prize than the photo of red ants.", "hint": "No hint available.", "answer": "Oliver won the contest (by elimination clues 1,3). He did dewdrops (clues 1,2,3). Charlie did termites (clues 2,3), which was fourth (clue 1). Johnny was fifth (clue 1) with a photo of a hummingbird (clues 2,4). Susan was third and red ants second (clue 4). Susan did the spider web. Carole was second.\n\r\nThe answers summarized -\n\r\nFirst - Oliver - Dewdrops\r\nSecond - Carole - Red ants\r\nThird - Susan - Spider web\r\nFourth - Charlie - Termites\r\nFifth - Johnny - Hummingbird", "category": "Logic-Grid", "date": "12/06/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Botanee , the science teacher at Dandelion High School, held a \"Nature is Remarkable\" photo contest. The five prize-winning students were Carole, Charlie, Johnny, Oliver and Susan. The subjects they photographed were dewdrops, hummingbirds, red ants, a spider web and termites. \n\r\nFrom the information given, determine the subject of each student's photograph as well as the order in which the five students finished.\n\r\n1. The photo of termites received a higher prize than Johnny's photo but a lower prize than those of both girls\n\r\n2. A girl took the photo of the spider web.\n\r\n3. The boy whose photo won is not named Charlie and neither of these two boys entered a photo of either a hummingbird or red ants.\n\r\n4. Susan's photo received a lower prize than the photo of red ants.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOliver won the contest (by elimination clues 1,3). He did dewdrops (clues 1,2,3). Charlie did termites (clues 2,3), which was fourth (clue 1). Johnny was fifth (clue 1) with a photo of a hummingbird (clues 2,4). Susan was third and red ants second (clue 4). Susan did the spider web. Carole was second.\n\r\nThe answers summarized -\n\r\nFirst - Oliver - Dewdrops\r\nSecond - Carole - Red ants\r\nThird - Susan - Spider web\r\nFourth - Charlie - Termites\r\nFifth - Johnny - Hummingbird\n<|im_start|>answer\nOliver won the contest (by elimination clues 1,3). He did dewdrops (clues 1,2,3). Charlie did termites (clues 2,3), which was fourth (clue 1). Johnny was fifth (clue 1) with a photo of a hummingbird (clues 2,4). Susan was third and red ants second (clue 4). Susan did the spider web. Carole was second.\n\r\nThe answers summarized -\n\r\nFirst - Oliver - Dewdrops\r\nSecond - Carole - Red ants\r\nThird - Susan - Spider web\r\nFourth - Charlie - Termites\r\nFifth - Johnny - Hummingbird\n<|im_end|>" }, { "id": "#26800", "title": "How Long?", "fun": 2.73, "difficulty": 1.8900000000000001, "author": "metallicman", "desc": "What is the number pattern?\r\n31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365", "hint": "Think about time", "answer": "The pattern is every month, starting from January going to December. The numbers are the number of days in each month, and each time the pattern goes on, that number is added to the total. Here are the month's days in order from January to December:\r\n31\r\n28\r\n31\r\n30\r\n31\r\n30\r\n31\r\n31\r\n30\r\n31\r\n30\r\n31", "category": "Math", "date": "11/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the number pattern?\r\n31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pattern is every month, starting from January going to December. The numbers are the number of days in each month, and each time the pattern goes on, that number is added to the total. Here are the month's days in order from January to December:\r\n31\r\n28\r\n31\r\n30\r\n31\r\n30\r\n31\r\n31\r\n30\r\n31\r\n30\r\n31\n<|im_start|>answer\nThe pattern is every month, starting from January going to December. The numbers are the number of days in each month, and each time the pattern goes on, that number is added to the total. Here are the month's days in order from January to December:\r\n31\r\n28\r\n31\r\n30\r\n31\r\n30\r\n31\r\n31\r\n30\r\n31\r\n30\r\n31\n<|im_end|>" }, { "id": "#21325", "title": "A Stooge Race", "fun": 2.73, "difficulty": 1.9000000000000001, "author": "tsimkin", "desc": "Moe, Larry, and Curly were trying to figure out who among them was the fastest, and by how much. They decide to settle this by a series of 2-man 100-meter races. In the first race, Moe beats Larry by exactly 10 meters. (That is to say, when Moe crosses the finish line, Larry is 10 meters behind him.) In the second race, Larry beats Curly by exactly 10 meters.\n\r\nIf they run at the exact same speeds as they did in their previous races (and their speed is constant over the entire course of the race), by what distance should Moe beat Curly when they race?", "hint": "No hint available.", "answer": "19 meters.\n\r\nInstead of thinking about the distance one finishes ahead another, think of the total distance each racer covers. In the time it takes Moe to run 100 meters, Larry runs 90 meters, so his pace must be 90% of Moe's. In the time it takes Larry to run 100 meters, Curly runs 90 meters, so his pace is 90% of Larry's. Combining these two facts, we find that Curly's pace is 90% of (90% of Moe's), which is 81% of Moe's. So in the time that Moe runs 100 meters, Curly must run 81 meters, and therefore finish 19 meters behind Moe.", "category": "Logic", "date": "03/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMoe, Larry, and Curly were trying to figure out who among them was the fastest, and by how much. They decide to settle this by a series of 2-man 100-meter races. In the first race, Moe beats Larry by exactly 10 meters. (That is to say, when Moe crosses the finish line, Larry is 10 meters behind him.) In the second race, Larry beats Curly by exactly 10 meters.\n\r\nIf they run at the exact same speeds as they did in their previous races (and their speed is constant over the entire course of the race), by what distance should Moe beat Curly when they race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19 meters.\n\r\nInstead of thinking about the distance one finishes ahead another, think of the total distance each racer covers. In the time it takes Moe to run 100 meters, Larry runs 90 meters, so his pace must be 90% of Moe's. In the time it takes Larry to run 100 meters, Curly runs 90 meters, so his pace is 90% of Larry's. Combining these two facts, we find that Curly's pace is 90% of (90% of Moe's), which is 81% of Moe's. So in the time that Moe runs 100 meters, Curly must run 81 meters, and therefore finish 19 meters behind Moe.\n<|im_start|>answer\n19 meters.\n\r\nInstead of thinking about the distance one finishes ahead another, think of the total distance each racer covers. In the time it takes Moe to run 100 meters, Larry runs 90 meters, so his pace must be 90% of Moe's. In the time it takes Larry to run 100 meters, Curly runs 90 meters, so his pace is 90% of Larry's. Combining these two facts, we find that Curly's pace is 90% of (90% of Moe's), which is 81% of Moe's. So in the time that Moe runs 100 meters, Curly must run 81 meters, and therefore finish 19 meters behind Moe.\n<|im_end|>" }, { "id": "#22574", "title": "Beethoven's Room", "fun": 2.73, "difficulty": 1.62, "author": "beethovenswig", "desc": "Beethoven has been kidnapped! The kidnapper has tied Beethoven up and put him in one of four rooms...each room has a different symbol on its door. The symbols are: @, #, *, &. Use the clues below to figure out which symbol belongs to which door and the room where Beethoven is.\n\r\n1.\tThe @ symbol is not on the door to the room where Beethoven is.\n\r\n 2. The * symbol is on the door to the second room.\n\r\n 3. Beethoven is in one room to the right of the room with the @ symbol on the door.\n\r\n 4. The & symbol is to the left of the room where Beethoven is.\n\r\n 5. The # symbol is not on the first door.", "hint": "No hint available.", "answer": "Beethoven is in the fourth room.\r\nRoom number 1 has the & symbol on the door.\r\nRoom number 2 has the * symbol on the door.\r\nRoom number 3 has the @ symbol on the door.\r\nRoom number 4 has Beethoven in the room and the # symbol on the door.", "category": "Logic", "date": "04/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBeethoven has been kidnapped! The kidnapper has tied Beethoven up and put him in one of four rooms...each room has a different symbol on its door. The symbols are: @, #, *, &. Use the clues below to figure out which symbol belongs to which door and the room where Beethoven is.\n\r\n1.\tThe @ symbol is not on the door to the room where Beethoven is.\n\r\n 2. The * symbol is on the door to the second room.\n\r\n 3. Beethoven is in one room to the right of the room with the @ symbol on the door.\n\r\n 4. The & symbol is to the left of the room where Beethoven is.\n\r\n 5. The # symbol is not on the first door.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeethoven is in the fourth room.\r\nRoom number 1 has the & symbol on the door.\r\nRoom number 2 has the * symbol on the door.\r\nRoom number 3 has the @ symbol on the door.\r\nRoom number 4 has Beethoven in the room and the # symbol on the door.\n<|im_start|>answer\nBeethoven is in the fourth room.\r\nRoom number 1 has the & symbol on the door.\r\nRoom number 2 has the * symbol on the door.\r\nRoom number 3 has the @ symbol on the door.\r\nRoom number 4 has Beethoven in the room and the # symbol on the door.\n<|im_end|>" }, { "id": "#47263", "title": "Impossible Age", "fun": 2.73, "difficulty": 0.91, "author": "cutieluck", "desc": "When Luke, the new kid, asked how old Annabelle was, she replied, \"In two years, I'll be twice as old as I was five years ago.\"\n\n\r\nHow old is Annabelle?", "hint": "No hint available.", "answer": "Annabelle is twelve!", "category": "Math", "date": "06/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Luke, the new kid, asked how old Annabelle was, she replied, \"In two years, I'll be twice as old as I was five years ago.\"\n\n\r\nHow old is Annabelle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnnabelle is twelve!\n<|im_start|>answer\nAnnabelle is twelve!\n<|im_end|>" }, { "id": "#31758", "title": "How Far Can You Go?", "fun": 2.73, "difficulty": 2.71, "author": "MarcM1098", "desc": "Your assignment is to make a delivery from the depot to your base camp, 1600 miles away. The trip begins normally, but unfortunately, halfway to base camp, your supply truck breaks down. You have no way to call for help. Luckily, in addition to medical supplies, the truck is carrying a Desert Patrol Vehicle (DPV) and two barrels of fuel.\n\r\nThe DPV has a full 10 gallon tank, but to make room for the medical supplies, it can only carry one of the 45 gallon barrels at a time. While you can't transfer fuel between barrels, you can refill the tank from the barrels. Assume the DPV can get 12 miles per gallon, regardless of the load it carries. \n\r\nHow far can you go? Is it far enough to deliver the medical supplies and the DPV to your base camp?", "hint": "Use half of a tank to carry one barrel, then return for the other.", "answer": "You can travel 840 miles from the broken supply truck. Since your base camp is 800 miles away (half of 1600 miles), you can easily complete the delivery. Here's how:\n\r\nAlthough you can only carry one barrel at a time, you need to transport both of them until one barrel is empty. F is the barrel used first, and L is the barrel used last.\n\r\nUse half of a tank (5 gallons) to carry L 5*12=60 miles, and then return for F (uses another 5 gallons). Refill the tank from F and carry it to where you left L (also uses 5 gallons). Refill the tank again from F and switch barrels. Now you are 60 miles from the broken truck, the tank and L are full, but F is down to 30 gallons (45-5-5-5=30). Repeat this procedure two times.\n\r\nNow you are 60*3=180 miles from the broken truck. The tank and L are still full, but F is empty. Leave F behind and make a run for it, carrying L. Refill the tank from L as needed. There are 55 gallons of fuel left so you can travel an additional 55*12=660 miles, for a maximum of (180+660) 840 miles. Since you only have a total of 800 miles to go, you will make it to your base camp.", "category": "Math", "date": "07/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour assignment is to make a delivery from the depot to your base camp, 1600 miles away. The trip begins normally, but unfortunately, halfway to base camp, your supply truck breaks down. You have no way to call for help. Luckily, in addition to medical supplies, the truck is carrying a Desert Patrol Vehicle (DPV) and two barrels of fuel.\n\r\nThe DPV has a full 10 gallon tank, but to make room for the medical supplies, it can only carry one of the 45 gallon barrels at a time. While you can't transfer fuel between barrels, you can refill the tank from the barrels. Assume the DPV can get 12 miles per gallon, regardless of the load it carries. \n\r\nHow far can you go? Is it far enough to deliver the medical supplies and the DPV to your base camp?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou can travel 840 miles from the broken supply truck. Since your base camp is 800 miles away (half of 1600 miles), you can easily complete the delivery. Here's how:\n\r\nAlthough you can only carry one barrel at a time, you need to transport both of them until one barrel is empty. F is the barrel used first, and L is the barrel used last.\n\r\nUse half of a tank (5 gallons) to carry L 5*12=60 miles, and then return for F (uses another 5 gallons). Refill the tank from F and carry it to where you left L (also uses 5 gallons). Refill the tank again from F and switch barrels. Now you are 60 miles from the broken truck, the tank and L are full, but F is down to 30 gallons (45-5-5-5=30). Repeat this procedure two times.\n\r\nNow you are 60*3=180 miles from the broken truck. The tank and L are still full, but F is empty. Leave F behind and make a run for it, carrying L. Refill the tank from L as needed. There are 55 gallons of fuel left so you can travel an additional 55*12=660 miles, for a maximum of (180+660) 840 miles. Since you only have a total of 800 miles to go, you will make it to your base camp.\n<|im_start|>answer\nYou can travel 840 miles from the broken supply truck. Since your base camp is 800 miles away (half of 1600 miles), you can easily complete the delivery. Here's how:\n\r\nAlthough you can only carry one barrel at a time, you need to transport both of them until one barrel is empty. F is the barrel used first, and L is the barrel used last.\n\r\nUse half of a tank (5 gallons) to carry L 5*12=60 miles, and then return for F (uses another 5 gallons). Refill the tank from F and carry it to where you left L (also uses 5 gallons). Refill the tank again from F and switch barrels. Now you are 60 miles from the broken truck, the tank and L are full, but F is down to 30 gallons (45-5-5-5=30). Repeat this procedure two times.\n\r\nNow you are 60*3=180 miles from the broken truck. The tank and L are still full, but F is empty. Leave F behind and make a run for it, carrying L. Refill the tank from L as needed. There are 55 gallons of fuel left so you can travel an additional 55*12=660 miles, for a maximum of (180+660) 840 miles. Since you only have a total of 800 miles to go, you will make it to your base camp.\n<|im_end|>" }, { "id": "#11484", "title": "Two Aging Mathematicians", "fun": 2.73, "difficulty": 2.82, "author": "snaps", "desc": "Two aging mathematics professors, Al Gebra and Cal Culus were sitting at their favourite Thai restaurant, Phun Kshuns, reminiscing about when they first met, while their waiter, Theo Rumsanrools (who also took Professor Gebra's Advanced Mathematics course at Cart Eshian University) eavesdropped on their conversation as he brought them their meals. \n\r\n\"You know what occurred to me the other day, Cal?\" asked Professor Gebra. \r\n\"What's that?\" said Professor Culus. \r\n\"Well, when we met, the square of your age contained the same three digits as the square of my age, just in a different order,\" Professor Gebra continued. \r\n\"This will really blow your socks off then, Al! If you take the square of the sum of our ages when we met and split it into two 2-digit numbers, you'd have my age then and your age now!\" Professor Culus exclaimed. \n\r\nWanting to impress his professor, Theo interjected. \r\n\"I thought you were much younger than that, Professor Gebra,\" Theo said. \r\nSaid Professor Gebra, \"And just how old am I then, young fellow?\"", "hint": "No hint available.", "answer": "\"Well, you're 81, sir,\" Theo replied. \r\n\"Right you are! And how did you figure that out so quickly?\" Professor Gebra asked. \r\n\"You said the square of your ages when you and Professor Culus met had only three digits, so the oldest you could have been was 31. That means that there were only a few possible ages the two of you could have been. Those being (with the associated squares): \r\n14 & 31 (196 & 961), \r\n13 & 31 (169 & 961), \r\n16 & 25 (256 & 625), \r\n12 & 21 (144 & 441), \r\n13 & 14 (169 & 196). \n\r\nNow the square of the sum of each of these pair of ages are respectively: \r\n2025, \r\n1936, \r\n1681, \r\n1089, \r\n729.\n\r\nAnd from those figures I concluded that Professor Culus must have been 16 when you met and hence you, Professor Gebra, are now 81!\" Theo explained. \r\n\"Aren't you a bright young fellow! You should come and study my Advanced Mathematics course at Cart Eshian University!\" Professor Gebra exclaimed. \r\n\"Uh, I already do,\" Theo said sheepishly.", "category": "Math", "date": "03/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo aging mathematics professors, Al Gebra and Cal Culus were sitting at their favourite Thai restaurant, Phun Kshuns, reminiscing about when they first met, while their waiter, Theo Rumsanrools (who also took Professor Gebra's Advanced Mathematics course at Cart Eshian University) eavesdropped on their conversation as he brought them their meals. \n\r\n\"You know what occurred to me the other day, Cal?\" asked Professor Gebra. \r\n\"What's that?\" said Professor Culus. \r\n\"Well, when we met, the square of your age contained the same three digits as the square of my age, just in a different order,\" Professor Gebra continued. \r\n\"This will really blow your socks off then, Al! If you take the square of the sum of our ages when we met and split it into two 2-digit numbers, you'd have my age then and your age now!\" Professor Culus exclaimed. \n\r\nWanting to impress his professor, Theo interjected. \r\n\"I thought you were much younger than that, Professor Gebra,\" Theo said. \r\nSaid Professor Gebra, \"And just how old am I then, young fellow?\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"Well, you're 81, sir,\" Theo replied. \r\n\"Right you are! And how did you figure that out so quickly?\" Professor Gebra asked. \r\n\"You said the square of your ages when you and Professor Culus met had only three digits, so the oldest you could have been was 31. That means that there were only a few possible ages the two of you could have been. Those being (with the associated squares): \r\n14 & 31 (196 & 961), \r\n13 & 31 (169 & 961), \r\n16 & 25 (256 & 625), \r\n12 & 21 (144 & 441), \r\n13 & 14 (169 & 196). \n\r\nNow the square of the sum of each of these pair of ages are respectively: \r\n2025, \r\n1936, \r\n1681, \r\n1089, \r\n729.\n\r\nAnd from those figures I concluded that Professor Culus must have been 16 when you met and hence you, Professor Gebra, are now 81!\" Theo explained. \r\n\"Aren't you a bright young fellow! You should come and study my Advanced Mathematics course at Cart Eshian University!\" Professor Gebra exclaimed. \r\n\"Uh, I already do,\" Theo said sheepishly.\n<|im_start|>answer\n\"Well, you're 81, sir,\" Theo replied. \r\n\"Right you are! And how did you figure that out so quickly?\" Professor Gebra asked. \r\n\"You said the square of your ages when you and Professor Culus met had only three digits, so the oldest you could have been was 31. That means that there were only a few possible ages the two of you could have been. Those being (with the associated squares): \r\n14 & 31 (196 & 961), \r\n13 & 31 (169 & 961), \r\n16 & 25 (256 & 625), \r\n12 & 21 (144 & 441), \r\n13 & 14 (169 & 196). \n\r\nNow the square of the sum of each of these pair of ages are respectively: \r\n2025, \r\n1936, \r\n1681, \r\n1089, \r\n729.\n\r\nAnd from those figures I concluded that Professor Culus must have been 16 when you met and hence you, Professor Gebra, are now 81!\" Theo explained. \r\n\"Aren't you a bright young fellow! You should come and study my Advanced Mathematics course at Cart Eshian University!\" Professor Gebra exclaimed. \r\n\"Uh, I already do,\" Theo said sheepishly.\n<|im_end|>" }, { "id": "#51102", "title": "Swap Time", "fun": 2.73, "difficulty": 3.0, "author": "Snowdog", "desc": "This puzzle is split into an initial logic based piece and then a rigorous math piece, so everyone can play.\n\r\nPicture a standard clock with continuously moving hour and minute hands.\n\r\nA \"Swap Time\" is a time when you can swap the hour and minute hand, and still get a valid time.\n\r\nFor example, 3:00 is NOT a Swap Time. If we swap the minute hand and the hour hand, then the minute hand points directly at the 3 and the hour hand points directly at the 12. This is not a valid time. When the minute hand points at the three, the hour hand will not be pointing directly at any number.\n\r\nA) Find one Swap Time.\r\nB) What are the Swap Times between 1:00 and 2:00?\n\r\nTimes will be specified as hours, minutes, and seconds rounded to two decimal places.\n\r\nIgnore a.m. and p.m. distinctions.\n\r\nBonus: How many Swap Times are there in total?", "hint": "No hint available.", "answer": "A) Noon is a Swap Time. Since both hands are pointing at 12, swapping them generates the exact same valid time. In fact, all eleven times when the hands point in the exact same\r\ndirection are Swap Times.\n\r\nB) Let's do some math.\n\r\nRule 1) For a valid time, the fraction of the minute hand's progress around the full circle must be equal to the fraction of the hour hand's progress between two numbers. For example, when the minute hand points at the 6, halfway around the clock, the hour hand must be pointed halfway between two numbers.\n\r\nRule 2) For a Swap Time, it must also be true that the fraction of the progress of the hour hand around the full circle is equal to the fraction of the progress of the minute hand between two numbers.\n\r\nLet H = hour hand angle in degrees\r\nLet M = minute hand angle in degrees\n\r\nNote that there are 360/12 = 30 degrees between numbers on the clock.\n\r\nRule 1\r\nH = + \r\nH = 30 * i + / 30 : i = 0, 1, 2,..., 11\r\nH = 30 * i + (M / 360) / 30\r\nH = 30 * i + M / 12\n\r\nRule 2\r\nM = 30 * j + H / 12 : j = 0, 1, 2,..., 11\n\r\nSubstituting for H:\r\nM = 30 * j + (30 * i + M / 12) / 12\r\nM = 30 * j + 5 * i / 2 + M / 144\r\n143 * M / 144 = 30 * j + 5 * i / 2\r\nM = 144 / 143 * (30 * j + 5 * i / 2) : i = 0,1,2,...,11 j = 0,1,2,...,11\n\r\nLet s be the number of seconds that have elapsed in the current hour.\n\r\nSince the minute hand moves at 0.1 degrees per second (360 deg / 3600 s), s = 10 * M\n\r\ns = 10 * [144 / 143 * (30 * j + 5 * i / 2)] : i = 0,1,2,...,11 j = 0,1,2,...,11\n\r\nTo find all Swap Times between 1:00 and 2:00, set i = 1 and check all values of j.\n\r\nj = 0, s = 25.17482517, time = 1:00:25.17\r\nj = 1, s = 327.2727273, time = 1:05:27.27\r\nRemaining swap times are\r\n1:10:29.37\r\n1:15:31.47\r\n1:20:33.57\r\n1:25:35.66\r\n1:30:37.76\r\n1:35:39.86\r\n1:40:41.96\r\n1:45:44.06\r\n1:50:46.15\r\n1:55:48.25\n\r\nSwap Time occur every 12 * 3600 / 143 = 302.0979 seconds.\n\r\nThere are 143 total swap times.", "category": "Math", "date": "05/20/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis puzzle is split into an initial logic based piece and then a rigorous math piece, so everyone can play.\n\r\nPicture a standard clock with continuously moving hour and minute hands.\n\r\nA \"Swap Time\" is a time when you can swap the hour and minute hand, and still get a valid time.\n\r\nFor example, 3:00 is NOT a Swap Time. If we swap the minute hand and the hour hand, then the minute hand points directly at the 3 and the hour hand points directly at the 12. This is not a valid time. When the minute hand points at the three, the hour hand will not be pointing directly at any number.\n\r\nA) Find one Swap Time.\r\nB) What are the Swap Times between 1:00 and 2:00?\n\r\nTimes will be specified as hours, minutes, and seconds rounded to two decimal places.\n\r\nIgnore a.m. and p.m. distinctions.\n\r\nBonus: How many Swap Times are there in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA) Noon is a Swap Time. Since both hands are pointing at 12, swapping them generates the exact same valid time. In fact, all eleven times when the hands point in the exact same\r\ndirection are Swap Times.\n\r\nB) Let's do some math.\n\r\nRule 1) For a valid time, the fraction of the minute hand's progress around the full circle must be equal to the fraction of the hour hand's progress between two numbers. For example, when the minute hand points at the 6, halfway around the clock, the hour hand must be pointed halfway between two numbers.\n\r\nRule 2) For a Swap Time, it must also be true that the fraction of the progress of the hour hand around the full circle is equal to the fraction of the progress of the minute hand between two numbers.\n\r\nLet H = hour hand angle in degrees\r\nLet M = minute hand angle in degrees\n\r\nNote that there are 360/12 = 30 degrees between numbers on the clock.\n\r\nRule 1\r\nH = + \r\nH = 30 * i + / 30 : i = 0, 1, 2,..., 11\r\nH = 30 * i + (M / 360) / 30\r\nH = 30 * i + M / 12\n\r\nRule 2\r\nM = 30 * j + H / 12 : j = 0, 1, 2,..., 11\n\r\nSubstituting for H:\r\nM = 30 * j + (30 * i + M / 12) / 12\r\nM = 30 * j + 5 * i / 2 + M / 144\r\n143 * M / 144 = 30 * j + 5 * i / 2\r\nM = 144 / 143 * (30 * j + 5 * i / 2) : i = 0,1,2,...,11 j = 0,1,2,...,11\n\r\nLet s be the number of seconds that have elapsed in the current hour.\n\r\nSince the minute hand moves at 0.1 degrees per second (360 deg / 3600 s), s = 10 * M\n\r\ns = 10 * [144 / 143 * (30 * j + 5 * i / 2)] : i = 0,1,2,...,11 j = 0,1,2,...,11\n\r\nTo find all Swap Times between 1:00 and 2:00, set i = 1 and check all values of j.\n\r\nj = 0, s = 25.17482517, time = 1:00:25.17\r\nj = 1, s = 327.2727273, time = 1:05:27.27\r\nRemaining swap times are\r\n1:10:29.37\r\n1:15:31.47\r\n1:20:33.57\r\n1:25:35.66\r\n1:30:37.76\r\n1:35:39.86\r\n1:40:41.96\r\n1:45:44.06\r\n1:50:46.15\r\n1:55:48.25\n\r\nSwap Time occur every 12 * 3600 / 143 = 302.0979 seconds.\n\r\nThere are 143 total swap times.\n<|im_start|>answer\nA) Noon is a Swap Time. Since both hands are pointing at 12, swapping them generates the exact same valid time. In fact, all eleven times when the hands point in the exact same\r\ndirection are Swap Times.\n\r\nB) Let's do some math.\n\r\nRule 1) For a valid time, the fraction of the minute hand's progress around the full circle must be equal to the fraction of the hour hand's progress between two numbers. For example, when the minute hand points at the 6, halfway around the clock, the hour hand must be pointed halfway between two numbers.\n\r\nRule 2) For a Swap Time, it must also be true that the fraction of the progress of the hour hand around the full circle is equal to the fraction of the progress of the minute hand between two numbers.\n\r\nLet H = hour hand angle in degrees\r\nLet M = minute hand angle in degrees\n\r\nNote that there are 360/12 = 30 degrees between numbers on the clock.\n\r\nRule 1\r\nH = + \r\nH = 30 * i + / 30 : i = 0, 1, 2,..., 11\r\nH = 30 * i + (M / 360) / 30\r\nH = 30 * i + M / 12\n\r\nRule 2\r\nM = 30 * j + H / 12 : j = 0, 1, 2,..., 11\n\r\nSubstituting for H:\r\nM = 30 * j + (30 * i + M / 12) / 12\r\nM = 30 * j + 5 * i / 2 + M / 144\r\n143 * M / 144 = 30 * j + 5 * i / 2\r\nM = 144 / 143 * (30 * j + 5 * i / 2) : i = 0,1,2,...,11 j = 0,1,2,...,11\n\r\nLet s be the number of seconds that have elapsed in the current hour.\n\r\nSince the minute hand moves at 0.1 degrees per second (360 deg / 3600 s), s = 10 * M\n\r\ns = 10 * [144 / 143 * (30 * j + 5 * i / 2)] : i = 0,1,2,...,11 j = 0,1,2,...,11\n\r\nTo find all Swap Times between 1:00 and 2:00, set i = 1 and check all values of j.\n\r\nj = 0, s = 25.17482517, time = 1:00:25.17\r\nj = 1, s = 327.2727273, time = 1:05:27.27\r\nRemaining swap times are\r\n1:10:29.37\r\n1:15:31.47\r\n1:20:33.57\r\n1:25:35.66\r\n1:30:37.76\r\n1:35:39.86\r\n1:40:41.96\r\n1:45:44.06\r\n1:50:46.15\r\n1:55:48.25\n\r\nSwap Time occur every 12 * 3600 / 143 = 302.0979 seconds.\n\r\nThere are 143 total swap times.\n<|im_end|>" }, { "id": "#36656", "title": "An Apple a Day", "fun": 2.73, "difficulty": 1.6, "author": "shdwhawk", "desc": "A shop sells apples at $1 each. Each of these apples are wrapped in a special wrapper. You can trade 3 of these wrappers for 1 apple. \r\nIf you have $15, how many apples can you get altogether?", "hint": "Don't forget your leftovers.", "answer": "22 apples. \n\r\nFirstly, you can get 15 apples. \r\nTrade the wrappers to get 5 more apples. \r\nTrade again and you'll have 1 more apple and 2 leftover wrappers. \r\nTrade the remaining wrappers to get 1 more apple. \r\n15 + 5 + 1 + 1 = 22 \r\nYou will get 22 apples altogether.", "category": "Math", "date": "05/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA shop sells apples at $1 each. Each of these apples are wrapped in a special wrapper. You can trade 3 of these wrappers for 1 apple. \r\nIf you have $15, how many apples can you get altogether?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n22 apples. \n\r\nFirstly, you can get 15 apples. \r\nTrade the wrappers to get 5 more apples. \r\nTrade again and you'll have 1 more apple and 2 leftover wrappers. \r\nTrade the remaining wrappers to get 1 more apple. \r\n15 + 5 + 1 + 1 = 22 \r\nYou will get 22 apples altogether.\n<|im_start|>answer\n22 apples. \n\r\nFirstly, you can get 15 apples. \r\nTrade the wrappers to get 5 more apples. \r\nTrade again and you'll have 1 more apple and 2 leftover wrappers. \r\nTrade the remaining wrappers to get 1 more apple. \r\n15 + 5 + 1 + 1 = 22 \r\nYou will get 22 apples altogether.\n<|im_end|>" }, { "id": "#43944", "title": "Home For Christmas", "fun": 2.73, "difficulty": 3.38, "author": "javaguru", "desc": "It was good to have the house full of people again; it had been far too quiet since the last of his seven daughters had left for college--seven daughters with seven different majors at seven different schools. About the only thing they had in common was that they were each dating an athlete, although none of them played the same sport--one was even on his school's fencing team. He was surprised all the boyfriends had come for Christmas dinner, but he supposed that since he was picking up the tab for the airfare, that a free trip to Hawaii in the winter had something to do with it. Each of his first three daughters had gone to Ivy League schools--one even to his alma mater at Harvard; his next two ended up at the University of California, at Los Angeles and Berkeley; and his two youngest got accepted to schools abroad--the University of Tokyo had been a bit of a surprise. Next year, after seven straight years--and for the first time this millennium--he wouldn't be attending a high-school graduation.\n\r\n\"Honey, we're ready to eat. Can you get Hank, Ian, James and Kyle? They're in the backyard playing football. The other boys wanted to test themselves against the star quarterback,\" his wife called from the dining room.\n\r\nThe math major said, \"I'll get them Dad!\"\n\r\nAs everyone filed into the dining room, the oldest sister was rehashing the whose-school-and-major-is-better argument with her younger sister about whether Yale or Princeton was a better school and whether history or philosophy was a more useful major. The argument was practically a Christmas tradition by now.\n\r\nThe table was arranged with the parents at the two ends and each of the couples seated across from each other with boys seated next to girls along each side. As usual, Angelina and Danica were sitting next to their parents. Curiously, all the athletes that used a ball in their sport were sitting on the same side of the table. Christie, Electra and Edward took their seats first.\n\r\nOnce everyone was seated the youngest coyly observed, \"I see the biologist is sitting between the two fighters but I'm sitting between the two best passers at the table.\"\n\r\n\"You'd better not make any passes yourself!\" Farrah icily replied. She hadn't forgiven her sister for stealing her boyfriend when they were in high school and was not happy to see her seated next to her boyfriend now.\n\r\n\"Lighten up, Farrah\" the biology major joked. \"He wasn't even that cute.\"\n\r\n\"He was adorable!\" the youngest interjected.\n\r\n\"Everyone's entitled to their opinion,\" said Brooke. \"Let's eat!\"\n\r\nThe daughter in the middle seat stood up and said, \"We have an announcement to make!\" After a dramatic pause she screamed \"we're getting married!\" and flashed the new diamond ring on her finger. The youngest sister squealed with delight at the news. Her fiance joked to his future mother-in-law, \"I think she said yes just so she can wear the monogrammed sweater you gave me for Christmas.\" The baseball player next to her asked her fiance, \"Wow, what'd that rock set you back?\"\n\r\n\"This calls for a toast!\" roared Dad.\n\r\n\"Oh Honey, that's wonderful news!\" Mom gushed. \"I just happen to have some champagne right here. Lars, I know you don't drink alcohol, but would you mind pouring some champagne for Gabrielle next to you?\" the mother asked, handing the bottle to Lars on her left. \"Gabrielle, please pass the bottle around,\" she asked and then quickly added, \"But no alcohol for my three babies, or anyone under 21 for that matter. Honey, there's a store downtown that's having a sale on wedding dresses. Will you have time to go look at some wedding dresses before you leave?\"\n\r\n\"Sure Mom,\" her daughter answered. \"We have a late flight out, so I can do that on the day we leave.\"\n\r\n\"Michael and I are celebrating New Years Eve at the Sheraton, Waikiki,\" one of the girls announced.\n\r\n\"What a coincidence,\" said the boy sitting next to her. \"We're celebrating New Years at the Sheraton, Los Angeles. It's within walking distance of our apartment so we won't have to worry if we drink too much.\"\n\r\n\"That sounds like a better plan than we have. Somehow, just because my car holds a lot of people, I got roped into being the designated driver for the team\" Danica said, looking pointedly at her boyfriend, who gestured to the boy from Princeton saying, \"he gave me the idea!\"\n\r\n\"Girls, your grandmother will be here on Sunday,\" the father announced. \"She'd really like to see you all.\"\n\r\n\"Sorry Dad,\" the business major replied, \"we have to leave tomorrow. There's a huge storm predicted to hit the Eastern United States this weekend and we need to get home before they close the airports. I noticed that each couple is leaving on a different day for six days after we leave.\"\n\r\n\"Sir, we're leaving before Sunday also, so we won't be able to make it either. I'm just glad we don't have to deal with that storm\" said the wrestler.\n\r\nThe swimmer and water polo player announced their travel plans. One of them remarked that even though his girlfriend and he were departing for Oxford University two days earlier, both couples would get home on the same day.\n\r\nThe physics major said \"I'll be here to see grandma, but unfortunately we're heading back to California before you go look at the wedding gowns.\"\n\r\n\"Well I'm glad you'll at least be here to see your grandma, but I wish you could stay longer\" the dad said. \"You know you're my favorite since you were my first to major in a physical science like me,\" he joked. \"I have a tee time at the club on Monday, it's too bad you won't be here,\" the father remarked to the golfer. \"Kyle's got a game next week but you don't,\" he said to the history major's boyfriend. \"How about you join me on the links?\"\n\r\n\"Sure!\" the boyfriend replied enthusiastically.\n\r\n\"Since we're leaving the day after him, if you've got room for two more Dad, we just happened to bring our clubs\" the second oldest said, winking at her boyfriend.\n\r\n\"It's a foursome then!\" her dad said happily.\n\r\nIan grumbled, \"Hank you lucky dog, I've wanted to play that course for years!\"\n\r\nThe boyfriend of the political science major laughed, \"I'd like to play there also, but Ian, at least I won't have to travel as far as you to get another opportunity.\"\n\r\n---------\n\r\nIdentify the boyfriend and his sport, the school, and major for each daughter. Name the order that the daughters were born in and the day of the week that they leave to go home. What is the seating arrangement at the dinner table?\n\r\nBonus question: what year is it?", "hint": "Pay attention to the flow of the conversation, but don't assume more than can be firmly established.\n\r\nAlso, some information relies on the following facts:\n\r\nChristmas is on December 25th.\r\nNew Years Eve is celebrated (usually by drinking too much alcohol) on December 31st.\n\r\nSwimming, fencing and wrestling are not games. Football, baseball, water polo and golf are games played with a ball.\n\r\nFencing and wrestling are combat competitions.\n\r\nThe game of American football is not a collegiate sport outside the United States; the player that passes the ball is the quarterback; there are more than forty players on a football team.\n\r\nWater polo is a game played in a pool with 7 players on each team; points are scored by throwing the ball into the opponents net, which is guarded by the goal keeper; the ball is moved across the pool either by swimming with it or passing it to another player.\n\r\nIvy League schools are located on the East Coast of the United States. Harvard, Yale and Princeton are all Ivy League schools.\n\r\nOxford University is in Oxford, England.\r\nTokyo University is in Tokyo, Japan.\r\nLos Angeles and Berkeley are cities in California.\r\nWaikiki is a city in Hawaii.\n\r\nHawaii is in the Pacific Ocean. The following are approximate distances from Hawaii:\r\nBerkeley and Los Angeles ~ 2500 miles\r\nTokyo ~3900 miles\r\nYale, Harvard and Princeton ~5000 miles\r\nEngland ~7000 miles\n\r\nBiology and physics are physical sciences; none of the other majors is a physical science.\n\r\nHigh school in America typically includes the last three or four years of school before college.\n\r\nA designated driver remains sober in order to drive people who've had too much alcohol home.\n\r\nA monogram is formed from the first letter of a person's first, last and (sometimes) middle names.", "answer": "From oldest to youngest the sisters are:\n\r\nWho, Boyfriend, Sport, Major, School, Departure day\r\n----------------------------------------------------------\r\nDanica, Hank, Water Polo, History, Yale, Tue\r\nElectra, Edward, Fencing, Philosophy, Princeton, Wed\r\nAngelina, Lars, Golf, Business, Harvard, Fri\r\nGabrielle, James, Wrestling, Poly Sci., UCLA, Sat\r\nFarrah, Kyle, Football, Physics, Berkeley, Mon.\r\nBrooke, Michael, Baseball, Biology, Tokyo, Thu\r\nChristie, Ian, Swimming, Math, Oxford, Sun\n\r\nThe seating arrangement is:\n\r\n---------- Dad ----------\r\nHank.............Danica\r\nChristie..........Ian\r\nKyle..............Farrah\r\nElectra...........Edward\r\nMichael..........Brooke\r\nGabrielle........James\r\nLars..............Angelina\r\n---------- Mom ----------\n\r\nThe year is 2003. This is the only year from 2000 to 2007 where Christmas is on a Thursday.", "category": "Logic", "date": "01/20/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was good to have the house full of people again; it had been far too quiet since the last of his seven daughters had left for college--seven daughters with seven different majors at seven different schools. About the only thing they had in common was that they were each dating an athlete, although none of them played the same sport--one was even on his school's fencing team. He was surprised all the boyfriends had come for Christmas dinner, but he supposed that since he was picking up the tab for the airfare, that a free trip to Hawaii in the winter had something to do with it. Each of his first three daughters had gone to Ivy League schools--one even to his alma mater at Harvard; his next two ended up at the University of California, at Los Angeles and Berkeley; and his two youngest got accepted to schools abroad--the University of Tokyo had been a bit of a surprise. Next year, after seven straight years--and for the first time this millennium--he wouldn't be attending a high-school graduation.\n\r\n\"Honey, we're ready to eat. Can you get Hank, Ian, James and Kyle? They're in the backyard playing football. The other boys wanted to test themselves against the star quarterback,\" his wife called from the dining room.\n\r\nThe math major said, \"I'll get them Dad!\"\n\r\nAs everyone filed into the dining room, the oldest sister was rehashing the whose-school-and-major-is-better argument with her younger sister about whether Yale or Princeton was a better school and whether history or philosophy was a more useful major. The argument was practically a Christmas tradition by now.\n\r\nThe table was arranged with the parents at the two ends and each of the couples seated across from each other with boys seated next to girls along each side. As usual, Angelina and Danica were sitting next to their parents. Curiously, all the athletes that used a ball in their sport were sitting on the same side of the table. Christie, Electra and Edward took their seats first.\n\r\nOnce everyone was seated the youngest coyly observed, \"I see the biologist is sitting between the two fighters but I'm sitting between the two best passers at the table.\"\n\r\n\"You'd better not make any passes yourself!\" Farrah icily replied. She hadn't forgiven her sister for stealing her boyfriend when they were in high school and was not happy to see her seated next to her boyfriend now.\n\r\n\"Lighten up, Farrah\" the biology major joked. \"He wasn't even that cute.\"\n\r\n\"He was adorable!\" the youngest interjected.\n\r\n\"Everyone's entitled to their opinion,\" said Brooke. \"Let's eat!\"\n\r\nThe daughter in the middle seat stood up and said, \"We have an announcement to make!\" After a dramatic pause she screamed \"we're getting married!\" and flashed the new diamond ring on her finger. The youngest sister squealed with delight at the news. Her fiance joked to his future mother-in-law, \"I think she said yes just so she can wear the monogrammed sweater you gave me for Christmas.\" The baseball player next to her asked her fiance, \"Wow, what'd that rock set you back?\"\n\r\n\"This calls for a toast!\" roared Dad.\n\r\n\"Oh Honey, that's wonderful news!\" Mom gushed. \"I just happen to have some champagne right here. Lars, I know you don't drink alcohol, but would you mind pouring some champagne for Gabrielle next to you?\" the mother asked, handing the bottle to Lars on her left. \"Gabrielle, please pass the bottle around,\" she asked and then quickly added, \"But no alcohol for my three babies, or anyone under 21 for that matter. Honey, there's a store downtown that's having a sale on wedding dresses. Will you have time to go look at some wedding dresses before you leave?\"\n\r\n\"Sure Mom,\" her daughter answered. \"We have a late flight out, so I can do that on the day we leave.\"\n\r\n\"Michael and I are celebrating New Years Eve at the Sheraton, Waikiki,\" one of the girls announced.\n\r\n\"What a coincidence,\" said the boy sitting next to her. \"We're celebrating New Years at the Sheraton, Los Angeles. It's within walking distance of our apartment so we won't have to worry if we drink too much.\"\n\r\n\"That sounds like a better plan than we have. Somehow, just because my car holds a lot of people, I got roped into being the designated driver for the team\" Danica said, looking pointedly at her boyfriend, who gestured to the boy from Princeton saying, \"he gave me the idea!\"\n\r\n\"Girls, your grandmother will be here on Sunday,\" the father announced. \"She'd really like to see you all.\"\n\r\n\"Sorry Dad,\" the business major replied, \"we have to leave tomorrow. There's a huge storm predicted to hit the Eastern United States this weekend and we need to get home before they close the airports. I noticed that each couple is leaving on a different day for six days after we leave.\"\n\r\n\"Sir, we're leaving before Sunday also, so we won't be able to make it either. I'm just glad we don't have to deal with that storm\" said the wrestler.\n\r\nThe swimmer and water polo player announced their travel plans. One of them remarked that even though his girlfriend and he were departing for Oxford University two days earlier, both couples would get home on the same day.\n\r\nThe physics major said \"I'll be here to see grandma, but unfortunately we're heading back to California before you go look at the wedding gowns.\"\n\r\n\"Well I'm glad you'll at least be here to see your grandma, but I wish you could stay longer\" the dad said. \"You know you're my favorite since you were my first to major in a physical science like me,\" he joked. \"I have a tee time at the club on Monday, it's too bad you won't be here,\" the father remarked to the golfer. \"Kyle's got a game next week but you don't,\" he said to the history major's boyfriend. \"How about you join me on the links?\"\n\r\n\"Sure!\" the boyfriend replied enthusiastically.\n\r\n\"Since we're leaving the day after him, if you've got room for two more Dad, we just happened to bring our clubs\" the second oldest said, winking at her boyfriend.\n\r\n\"It's a foursome then!\" her dad said happily.\n\r\nIan grumbled, \"Hank you lucky dog, I've wanted to play that course for years!\"\n\r\nThe boyfriend of the political science major laughed, \"I'd like to play there also, but Ian, at least I won't have to travel as far as you to get another opportunity.\"\n\r\n---------\n\r\nIdentify the boyfriend and his sport, the school, and major for each daughter. Name the order that the daughters were born in and the day of the week that they leave to go home. What is the seating arrangement at the dinner table?\n\r\nBonus question: what year is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom oldest to youngest the sisters are:\n\r\nWho, Boyfriend, Sport, Major, School, Departure day\r\n----------------------------------------------------------\r\nDanica, Hank, Water Polo, History, Yale, Tue\r\nElectra, Edward, Fencing, Philosophy, Princeton, Wed\r\nAngelina, Lars, Golf, Business, Harvard, Fri\r\nGabrielle, James, Wrestling, Poly Sci., UCLA, Sat\r\nFarrah, Kyle, Football, Physics, Berkeley, Mon.\r\nBrooke, Michael, Baseball, Biology, Tokyo, Thu\r\nChristie, Ian, Swimming, Math, Oxford, Sun\n\r\nThe seating arrangement is:\n\r\n---------- Dad ----------\r\nHank.............Danica\r\nChristie..........Ian\r\nKyle..............Farrah\r\nElectra...........Edward\r\nMichael..........Brooke\r\nGabrielle........James\r\nLars..............Angelina\r\n---------- Mom ----------\n\r\nThe year is 2003. This is the only year from 2000 to 2007 where Christmas is on a Thursday.\n<|im_start|>answer\nFrom oldest to youngest the sisters are:\n\r\nWho, Boyfriend, Sport, Major, School, Departure day\r\n----------------------------------------------------------\r\nDanica, Hank, Water Polo, History, Yale, Tue\r\nElectra, Edward, Fencing, Philosophy, Princeton, Wed\r\nAngelina, Lars, Golf, Business, Harvard, Fri\r\nGabrielle, James, Wrestling, Poly Sci., UCLA, Sat\r\nFarrah, Kyle, Football, Physics, Berkeley, Mon.\r\nBrooke, Michael, Baseball, Biology, Tokyo, Thu\r\nChristie, Ian, Swimming, Math, Oxford, Sun\n\r\nThe seating arrangement is:\n\r\n---------- Dad ----------\r\nHank.............Danica\r\nChristie..........Ian\r\nKyle..............Farrah\r\nElectra...........Edward\r\nMichael..........Brooke\r\nGabrielle........James\r\nLars..............Angelina\r\n---------- Mom ----------\n\r\nThe year is 2003. This is the only year from 2000 to 2007 where Christmas is on a Thursday.\n<|im_end|>" }, { "id": "#49929", "title": "Tie the Knots", "fun": 2.73, "difficulty": 2.16, "author": "eighsse", "desc": "Joe needed a rope 75 feet long. He went to a local hardware store, but found that they did not have ropes nearly that long. They had only 3', 5', 12', and 20' segments of rope. Joe would have bought only 20' segments, as they were the cheapest per foot; unfortunately, they had such a limited quantity of segments (though none were out of stock) that he had to buy all of the 20', 12', and 5' segments available, and 3' segments for the remainder. In fact, he bought a greater quantity of each length than the next longer length (i.e., more 3' segments than 5' segments, more 5' segments than 12' segments, and more 12' segments than 20' segments). Just to be sure he had some margin for error, he bought a total of 90 feet, even though he needed only 75 feet. When he got home, he was glad he had decided to buy a little extra, because only then did he realize that he was going to lose some length as he tied the segments together to make the full rope. He tied two pieces together to check how much length he would lose, and found it to be 6 inches lost from each of the two segments that were tied together. Does Joe have enough to make his 75-foot rope?", "hint": "Is it possible for Joe to have bought more than 1 20-foot segment, with the total adding up to 90 feet? Is it possible for him to have bought more than 2 12-foot segments?", "answer": "Yes. He will have a 76-foot rope.\n\r\nThe only combination that fits the statements in the puzzle is:\n\r\n1 20' segment\r\n2 12' segments\r\n5 5' segments\r\n7 3' segments\n\r\nThis is a total of 15 segments, which will require 14 knots to tie together. Each knot takes 6 inches off of two segments, or 1 foot total; therefore, of his 90 feet of rope, he will lose 14 feet in the knots, making a 76-foot rope.", "category": "Math", "date": "09/05/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe needed a rope 75 feet long. He went to a local hardware store, but found that they did not have ropes nearly that long. They had only 3', 5', 12', and 20' segments of rope. Joe would have bought only 20' segments, as they were the cheapest per foot; unfortunately, they had such a limited quantity of segments (though none were out of stock) that he had to buy all of the 20', 12', and 5' segments available, and 3' segments for the remainder. In fact, he bought a greater quantity of each length than the next longer length (i.e., more 3' segments than 5' segments, more 5' segments than 12' segments, and more 12' segments than 20' segments). Just to be sure he had some margin for error, he bought a total of 90 feet, even though he needed only 75 feet. When he got home, he was glad he had decided to buy a little extra, because only then did he realize that he was going to lose some length as he tied the segments together to make the full rope. He tied two pieces together to check how much length he would lose, and found it to be 6 inches lost from each of the two segments that were tied together. Does Joe have enough to make his 75-foot rope?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes. He will have a 76-foot rope.\n\r\nThe only combination that fits the statements in the puzzle is:\n\r\n1 20' segment\r\n2 12' segments\r\n5 5' segments\r\n7 3' segments\n\r\nThis is a total of 15 segments, which will require 14 knots to tie together. Each knot takes 6 inches off of two segments, or 1 foot total; therefore, of his 90 feet of rope, he will lose 14 feet in the knots, making a 76-foot rope.\n<|im_start|>answer\nYes. He will have a 76-foot rope.\n\r\nThe only combination that fits the statements in the puzzle is:\n\r\n1 20' segment\r\n2 12' segments\r\n5 5' segments\r\n7 3' segments\n\r\nThis is a total of 15 segments, which will require 14 knots to tie together. Each knot takes 6 inches off of two segments, or 1 foot total; therefore, of his 90 feet of rope, he will lose 14 feet in the knots, making a 76-foot rope.\n<|im_end|>" }, { "id": "#25007", "title": "Word Triangles", "fun": 2.73, "difficulty": 2.52, "author": "phrebh", "desc": "A word triangle is created by taking a word, putting the first letter on the first line, putting two of the second letter on the next line, three of the third letter on the third line, et cetera. Given the word TEASER, the word triangle would look like this:\n\r\nT\r\nEE\r\nAAA\r\nSSSS\r\nEEEEE\r\nRRRRRR\n\r\nIf you begin at the top and start spelling TEASER by either moving to the letter directly below the letter you are currently on or by moving to the letter that is immediately to the right of the letter below the letter you are currently on, you could use several different paths to spell the word. For instance, if your path takes you to the third 'A' you could either go to the third 'S' or the fourth 'S', but not to the first or second 'S'.\n\r\nCan you determine how many possible paths there are for this word triangle? How about for word triangles with words of different lengths?", "hint": "This relates to the work of a famous theologian and mathematician.", "answer": "2^5 = 32\n\r\nFor any word of given length, L, the number of paths, P, can be found by P = 2^(L-1).\n\r\nThis is essentially Pascal's Triangle. Usually, these are seen as more of a pyramid shape, but since spacing can't be done consistently, the teaser had to limit the paths to either the letter below the current letter or the letter below and to the right of the current letter.", "category": "Math", "date": "08/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA word triangle is created by taking a word, putting the first letter on the first line, putting two of the second letter on the next line, three of the third letter on the third line, et cetera. Given the word TEASER, the word triangle would look like this:\n\r\nT\r\nEE\r\nAAA\r\nSSSS\r\nEEEEE\r\nRRRRRR\n\r\nIf you begin at the top and start spelling TEASER by either moving to the letter directly below the letter you are currently on or by moving to the letter that is immediately to the right of the letter below the letter you are currently on, you could use several different paths to spell the word. For instance, if your path takes you to the third 'A' you could either go to the third 'S' or the fourth 'S', but not to the first or second 'S'.\n\r\nCan you determine how many possible paths there are for this word triangle? How about for word triangles with words of different lengths?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2^5 = 32\n\r\nFor any word of given length, L, the number of paths, P, can be found by P = 2^(L-1).\n\r\nThis is essentially Pascal's Triangle. Usually, these are seen as more of a pyramid shape, but since spacing can't be done consistently, the teaser had to limit the paths to either the letter below the current letter or the letter below and to the right of the current letter.\n<|im_start|>answer\n2^5 = 32\n\r\nFor any word of given length, L, the number of paths, P, can be found by P = 2^(L-1).\n\r\nThis is essentially Pascal's Triangle. Usually, these are seen as more of a pyramid shape, but since spacing can't be done consistently, the teaser had to limit the paths to either the letter below the current letter or the letter below and to the right of the current letter.\n<|im_end|>" }, { "id": "#26579", "title": "Bags, Marbles, and Scales", "fun": 2.73, "difficulty": 1.84, "author": "Question_Mark", "desc": "In front of me, I have level scales. On each side, there are 3 bags. In each bag, there are some marbles. There are 150 Marbles in total. Using the clues below, work out how many marbles are in each bag.\n\r\nBag 1 + Bag 2 = 56 marbles\r\nBag 1 + Bag 3 = 54 marbles\r\nBag 2 + Bag 3 = 40 marbles\r\n-------------------\r\nBag 4 + Bag 5 = 61 marbles\r\nBag 4 + Bag 6 = 37 marbles\r\nBag 5 + Bag 6 = 52 marbles", "hint": "No hint available.", "answer": "Bag 1 = 35 marbles\r\nBag 2 = 21 marbles\r\nBag 3 = 19 marbles\r\nBag 4 = 23 marbles\r\nBag 5 = 38 marbles\r\nBag 6 = 14 marbles\n\r\nTo work this out, since there are 150 marbles, and the scales are level, both sides of the scales must have 75 marbles. If Bag 1 + Bag 2 = 56 marbles then Bag 3 = (75-56) 19 marbles. So Bag 1 = 35 marbles and Bag 2 = 21 marbles. The same is done with Bags 4,5, and 6. Bag 4 + Bag 5 = 61 marbles. So Bag 6 = (75-61) 14 marbles. So Bag 4 = 23 marbles and Bag 5 = 38 marbles.", "category": "Math", "date": "10/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn front of me, I have level scales. On each side, there are 3 bags. In each bag, there are some marbles. There are 150 Marbles in total. Using the clues below, work out how many marbles are in each bag.\n\r\nBag 1 + Bag 2 = 56 marbles\r\nBag 1 + Bag 3 = 54 marbles\r\nBag 2 + Bag 3 = 40 marbles\r\n-------------------\r\nBag 4 + Bag 5 = 61 marbles\r\nBag 4 + Bag 6 = 37 marbles\r\nBag 5 + Bag 6 = 52 marbles\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBag 1 = 35 marbles\r\nBag 2 = 21 marbles\r\nBag 3 = 19 marbles\r\nBag 4 = 23 marbles\r\nBag 5 = 38 marbles\r\nBag 6 = 14 marbles\n\r\nTo work this out, since there are 150 marbles, and the scales are level, both sides of the scales must have 75 marbles. If Bag 1 + Bag 2 = 56 marbles then Bag 3 = (75-56) 19 marbles. So Bag 1 = 35 marbles and Bag 2 = 21 marbles. The same is done with Bags 4,5, and 6. Bag 4 + Bag 5 = 61 marbles. So Bag 6 = (75-61) 14 marbles. So Bag 4 = 23 marbles and Bag 5 = 38 marbles.\n<|im_start|>answer\nBag 1 = 35 marbles\r\nBag 2 = 21 marbles\r\nBag 3 = 19 marbles\r\nBag 4 = 23 marbles\r\nBag 5 = 38 marbles\r\nBag 6 = 14 marbles\n\r\nTo work this out, since there are 150 marbles, and the scales are level, both sides of the scales must have 75 marbles. If Bag 1 + Bag 2 = 56 marbles then Bag 3 = (75-56) 19 marbles. So Bag 1 = 35 marbles and Bag 2 = 21 marbles. The same is done with Bags 4,5, and 6. Bag 4 + Bag 5 = 61 marbles. So Bag 6 = (75-61) 14 marbles. So Bag 4 = 23 marbles and Bag 5 = 38 marbles.\n<|im_end|>" }, { "id": "#31410", "title": "Lunch at the Movies", "fun": 2.73, "difficulty": 1.15, "author": "ava199345", "desc": "Four brothers and sisters decided to go to the movies with their mother. Before the movie started, they bought some lunch and snacks for the movie. They quickly told their mother what they wanted and ran off to meet some friends. Their mother was so frazzled, she completely forgot what child ordered what. They each wanted a pop, candy, and a lunch item. Can you help her with the order?\n\r\nChildren- Mikey, Bernard, Aleda, Asia\r\nPop- Sprite, Coke, Pepsi, Root Beer\r\nCandy- Skittles, M&Ms, Starbursts, Snickers\r\nLunch- chicken, hot dog, hamburger, fries\n\r\n1) Asia hates Snickers, chicken, and Starbursts.\r\n2) The person who ordered Root Beer also got a hot dog.\r\n3) Neither of the girls got fries.\r\n4) The boys hate Pepsi and Root Beer.\r\n5) Aleda loves Snickers as much as Bernard loves chicken.\r\n6) Mikey is a vegetarian.\r\n7) Bernard ordered Sprite.\r\n8) The boy who ordered Coke also got Starbursts.\r\n9) A girl ordered Skittles. \r\n10) Asia did not order a hot dog.", "hint": "No hint available.", "answer": "Mikey- Coke, Starbursts, fries\r\nAleda- Root Beer, Snickers, hot dog\r\nBernard- Sprite, M&Ms, chicken\r\nAsia- Pepsi, Skittles, hamburger", "category": "Logic-Grid", "date": "06/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour brothers and sisters decided to go to the movies with their mother. Before the movie started, they bought some lunch and snacks for the movie. They quickly told their mother what they wanted and ran off to meet some friends. Their mother was so frazzled, she completely forgot what child ordered what. They each wanted a pop, candy, and a lunch item. Can you help her with the order?\n\r\nChildren- Mikey, Bernard, Aleda, Asia\r\nPop- Sprite, Coke, Pepsi, Root Beer\r\nCandy- Skittles, M&Ms, Starbursts, Snickers\r\nLunch- chicken, hot dog, hamburger, fries\n\r\n1) Asia hates Snickers, chicken, and Starbursts.\r\n2) The person who ordered Root Beer also got a hot dog.\r\n3) Neither of the girls got fries.\r\n4) The boys hate Pepsi and Root Beer.\r\n5) Aleda loves Snickers as much as Bernard loves chicken.\r\n6) Mikey is a vegetarian.\r\n7) Bernard ordered Sprite.\r\n8) The boy who ordered Coke also got Starbursts.\r\n9) A girl ordered Skittles. \r\n10) Asia did not order a hot dog.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMikey- Coke, Starbursts, fries\r\nAleda- Root Beer, Snickers, hot dog\r\nBernard- Sprite, M&Ms, chicken\r\nAsia- Pepsi, Skittles, hamburger\n<|im_start|>answer\nMikey- Coke, Starbursts, fries\r\nAleda- Root Beer, Snickers, hot dog\r\nBernard- Sprite, M&Ms, chicken\r\nAsia- Pepsi, Skittles, hamburger\n<|im_end|>" }, { "id": "#3539", "title": "Truths and Lies", "fun": 2.73, "difficulty": 2.02, "author": "jeanray", "desc": "There are three persons in a room.\r\nOne of them always tells the truth, but the others are \"alternate liars\": they tell the truth then lie, then truth, etc, but you do not know if they will start by telling the truth or a lie...\r\nYou can ask three questions that MUST be answered by Yes or No.\r\nFind the truth teller.", "hint": "Ask the questions to one person only.", "answer": "Q1. Mr. A, are you a truth teller?\r\n- Yes\r\nor\r\n- No.\n\r\nQ2. Mr. A, are you a truth teller?\r\n- Yes\r\nor\r\n- No.\n\r\nQ1: Q2:\r\nYes Yes: A is the truth teller.\n\r\nYes No : A is an alternate liar, next answer is a lie.\r\n Q3: Mr. A, is B the truth teller?\r\n - Yes: C is the truth teller.\r\n - No: B is the truth teller. \n\r\nNo Yes: A is an alternate liar, next answer is true.\r\n Q3: Mr. A, is B the truth teller?\r\n - Yes: B is the truth teller.\r\n - No: C is the truth teller.\n\r\nNo No : Impossible.", "category": "Logic", "date": "04/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three persons in a room.\r\nOne of them always tells the truth, but the others are \"alternate liars\": they tell the truth then lie, then truth, etc, but you do not know if they will start by telling the truth or a lie...\r\nYou can ask three questions that MUST be answered by Yes or No.\r\nFind the truth teller.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nQ1. Mr. A, are you a truth teller?\r\n- Yes\r\nor\r\n- No.\n\r\nQ2. Mr. A, are you a truth teller?\r\n- Yes\r\nor\r\n- No.\n\r\nQ1: Q2:\r\nYes Yes: A is the truth teller.\n\r\nYes No : A is an alternate liar, next answer is a lie.\r\n Q3: Mr. A, is B the truth teller?\r\n - Yes: C is the truth teller.\r\n - No: B is the truth teller. \n\r\nNo Yes: A is an alternate liar, next answer is true.\r\n Q3: Mr. A, is B the truth teller?\r\n - Yes: B is the truth teller.\r\n - No: C is the truth teller.\n\r\nNo No : Impossible.\n<|im_start|>answer\nQ1. Mr. A, are you a truth teller?\r\n- Yes\r\nor\r\n- No.\n\r\nQ2. Mr. A, are you a truth teller?\r\n- Yes\r\nor\r\n- No.\n\r\nQ1: Q2:\r\nYes Yes: A is the truth teller.\n\r\nYes No : A is an alternate liar, next answer is a lie.\r\n Q3: Mr. A, is B the truth teller?\r\n - Yes: C is the truth teller.\r\n - No: B is the truth teller. \n\r\nNo Yes: A is an alternate liar, next answer is true.\r\n Q3: Mr. A, is B the truth teller?\r\n - Yes: B is the truth teller.\r\n - No: C is the truth teller.\n\r\nNo No : Impossible.\n<|im_end|>" }, { "id": "#27665", "title": "What Did I Buy?", "fun": 2.73, "difficulty": 2.03, "author": "Question_Mark", "desc": "When Skid Mark walked into a shop, he bought a bottle of mineral water, 2 sandwiches and a bag of crisps. This cost him 761QEM.\r\nLater on, Exclamation Mark goes into the same shop and buys a sandwich and a bottle of fizzy juice. This cost him 408QEM.\r\nLater, Birth Mark goes into the same shop and buys a bottle of mineral water and a bag of crisps. This cost her 153QEM.\r\nLater on, Book Mark goes into the same shop and buys 3 bottles of mineral water and 2 sandwiches. This cost her 938QEM.\r\nLater on, Question Mark goes into the same shop and buys 4 items. This cost him 555QEM. What did Question Mark buy?", "hint": "No hint available.", "answer": "Question Mark bought 2 bottles of fizzy juice, 1 sandwich and 1 bag of crisps.\n\r\nEverything costs as follows:\r\nMineral water: 110QEM\r\nCrisps: 43QEM\r\nSandwiches: 304QEM\r\nFizzy juice: 104QEM\n\r\nYou will notice that the difference in cost between Skid Mark and Birth Mark is 608QEM. This is because they both bought a bottle of mineral water and a bag of crisps, but Skid Mark bought 2 sandwiches so sandwiches cost (608/2=304QEM). Since Book Mark paid 938 for what she bought, 608QEM was used to buy 2 sandwiches, the rest of her money would be used to buy 3 bottles of mineral water, so one bottle costs (330/3=110QEM). Using this information you can work out what everything else costs.", "category": "Math", "date": "12/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Skid Mark walked into a shop, he bought a bottle of mineral water, 2 sandwiches and a bag of crisps. This cost him 761QEM.\r\nLater on, Exclamation Mark goes into the same shop and buys a sandwich and a bottle of fizzy juice. This cost him 408QEM.\r\nLater, Birth Mark goes into the same shop and buys a bottle of mineral water and a bag of crisps. This cost her 153QEM.\r\nLater on, Book Mark goes into the same shop and buys 3 bottles of mineral water and 2 sandwiches. This cost her 938QEM.\r\nLater on, Question Mark goes into the same shop and buys 4 items. This cost him 555QEM. What did Question Mark buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nQuestion Mark bought 2 bottles of fizzy juice, 1 sandwich and 1 bag of crisps.\n\r\nEverything costs as follows:\r\nMineral water: 110QEM\r\nCrisps: 43QEM\r\nSandwiches: 304QEM\r\nFizzy juice: 104QEM\n\r\nYou will notice that the difference in cost between Skid Mark and Birth Mark is 608QEM. This is because they both bought a bottle of mineral water and a bag of crisps, but Skid Mark bought 2 sandwiches so sandwiches cost (608/2=304QEM). Since Book Mark paid 938 for what she bought, 608QEM was used to buy 2 sandwiches, the rest of her money would be used to buy 3 bottles of mineral water, so one bottle costs (330/3=110QEM). Using this information you can work out what everything else costs.\n<|im_start|>answer\nQuestion Mark bought 2 bottles of fizzy juice, 1 sandwich and 1 bag of crisps.\n\r\nEverything costs as follows:\r\nMineral water: 110QEM\r\nCrisps: 43QEM\r\nSandwiches: 304QEM\r\nFizzy juice: 104QEM\n\r\nYou will notice that the difference in cost between Skid Mark and Birth Mark is 608QEM. This is because they both bought a bottle of mineral water and a bag of crisps, but Skid Mark bought 2 sandwiches so sandwiches cost (608/2=304QEM). Since Book Mark paid 938 for what she bought, 608QEM was used to buy 2 sandwiches, the rest of her money would be used to buy 3 bottles of mineral water, so one bottle costs (330/3=110QEM). Using this information you can work out what everything else costs.\n<|im_end|>" }, { "id": "#6986", "title": "A Birthday Present", "fun": 2.73, "difficulty": 1.1, "author": "Galadriel", "desc": "John really wanted to know how much money he would get from grandpa for his birthday. But grandpa didn't want to tell him. Instead he said: \"You get so much!\"\r\n\"But how much is so much?\", John asked.\r\n\"If I gave you so much, plus so much, plus the half of so much, plus 1/4 of so much, plus 1 EURO, you would have 100 EURO's.\r\nHow much will John get?", "hint": "No hint available.", "answer": "36 EURO's : 36+36+18+9+1=100", "category": "Math", "date": "08/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn really wanted to know how much money he would get from grandpa for his birthday. But grandpa didn't want to tell him. Instead he said: \"You get so much!\"\r\n\"But how much is so much?\", John asked.\r\n\"If I gave you so much, plus so much, plus the half of so much, plus 1/4 of so much, plus 1 EURO, you would have 100 EURO's.\r\nHow much will John get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n36 EURO's : 36+36+18+9+1=100\n<|im_start|>answer\n36 EURO's : 36+36+18+9+1=100\n<|im_end|>" }, { "id": "#11242", "title": "Tiny Little Stairs", "fun": 2.73, "difficulty": 1.82, "author": "jimbo", "desc": "Jimbo Gulliver was planning an intergalactic space trip to the planet Lilliputinyweesmallminutania which had a very tiny moon named Tinylittliddybiddy... well never mind what it was called. Here dwelt the smallest people in the universe.\r\nIn order to give them access to his space ship doorway, which was 3 metres off the ground, he decided to build a set of stairs that measured 4 metres long by 3 metres high.\r\nJust as he was about to leave, the first officer on the ship, Lieutenant Sarogahtyp said \"Jimbo, when we get there are we going to give them the red carpet treatment?\"\r\n\"Good idea\", declared Jimbo.\r\nNow Jimbo had the latest autocarpetachometer thingy that could fasten a carpet to a staircase without wasting any carpet whatsoever on the corners and bends. \"I wonder how much red carpet I'll need?\" enquired Jimbo.\r\n\"Look\", said first officer Sarogahtyp, \"There are thousands and thousands of steps. The steps are so tiny and close together that it almost looks like a ramp. Why it's almost a 3:4:5 triangle. Take 6 metres and you'll have some left over.\r\nJimbo Gulliver took his first Lieutenants advice but alas, when he got there, there was not enough carpet to carpet the stairs! Why?", "hint": "He has to carpet all of the stairs but you can assume that no carpet is wasted going over the edges of each stair or tucked into the bend on the vertical riser.", "answer": "It will take exactly seven metres to carpet the stairs no matter how many there are. The horizontal steps must add up to 4 metres and the vertical risers must add up to 3 metres. Total 7 metres, even if there are an infinite number of stairs. This appears contradictory to our sense that it flattens out to become like the hypotenuse of a right angled triangle. A quick sketch with any number of stairs should convince you.", "category": "Math", "date": "03/17/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJimbo Gulliver was planning an intergalactic space trip to the planet Lilliputinyweesmallminutania which had a very tiny moon named Tinylittliddybiddy... well never mind what it was called. Here dwelt the smallest people in the universe.\r\nIn order to give them access to his space ship doorway, which was 3 metres off the ground, he decided to build a set of stairs that measured 4 metres long by 3 metres high.\r\nJust as he was about to leave, the first officer on the ship, Lieutenant Sarogahtyp said \"Jimbo, when we get there are we going to give them the red carpet treatment?\"\r\n\"Good idea\", declared Jimbo.\r\nNow Jimbo had the latest autocarpetachometer thingy that could fasten a carpet to a staircase without wasting any carpet whatsoever on the corners and bends. \"I wonder how much red carpet I'll need?\" enquired Jimbo.\r\n\"Look\", said first officer Sarogahtyp, \"There are thousands and thousands of steps. The steps are so tiny and close together that it almost looks like a ramp. Why it's almost a 3:4:5 triangle. Take 6 metres and you'll have some left over.\r\nJimbo Gulliver took his first Lieutenants advice but alas, when he got there, there was not enough carpet to carpet the stairs! Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will take exactly seven metres to carpet the stairs no matter how many there are. The horizontal steps must add up to 4 metres and the vertical risers must add up to 3 metres. Total 7 metres, even if there are an infinite number of stairs. This appears contradictory to our sense that it flattens out to become like the hypotenuse of a right angled triangle. A quick sketch with any number of stairs should convince you.\n<|im_start|>answer\nIt will take exactly seven metres to carpet the stairs no matter how many there are. The horizontal steps must add up to 4 metres and the vertical risers must add up to 3 metres. Total 7 metres, even if there are an infinite number of stairs. This appears contradictory to our sense that it flattens out to become like the hypotenuse of a right angled triangle. A quick sketch with any number of stairs should convince you.\n<|im_end|>" }, { "id": "#31187", "title": "School Projects", "fun": 2.73, "difficulty": 1.45, "author": "madmoo143", "desc": "Four school children (two boys - Liam and Paul, and two girls Sandie and Melissa), were doing a project on exotic animals. They each chose a different animal (snake, elephant, crocodile and toucan), chose a different style for their project (poster, booklet, leaflet and magazine article), and chose a different source of information (books, video, internet and people). \n\r\nWith the clues, can you solve who chose what animal, style, and source of information for their project?\n\r\n1) The four people are: Liam, the person who wrote about snakes, the person who did a magazine article and the person who used a video for their information.\n\r\n2) Paul didn't write about snakes, nor did he use people for information.\n\r\n3) The girl who wrote a leaflet used the internet for her information.\n\r\n4) The person who did a poster wrote about toucans; the person who used a video wrote about crocodiles.\n\r\n5) Sandie wrote about elephants, but she didn't use the internet or people.", "hint": "No hint available.", "answer": "Paul-crocodile-booklet-video\r\nSandie-elephant-magazine article-books\r\nLiam-toucan-poster-people\r\nMelissa-snake-leaflet-internet", "category": "Logic-Grid", "date": "06/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour school children (two boys - Liam and Paul, and two girls Sandie and Melissa), were doing a project on exotic animals. They each chose a different animal (snake, elephant, crocodile and toucan), chose a different style for their project (poster, booklet, leaflet and magazine article), and chose a different source of information (books, video, internet and people). \n\r\nWith the clues, can you solve who chose what animal, style, and source of information for their project?\n\r\n1) The four people are: Liam, the person who wrote about snakes, the person who did a magazine article and the person who used a video for their information.\n\r\n2) Paul didn't write about snakes, nor did he use people for information.\n\r\n3) The girl who wrote a leaflet used the internet for her information.\n\r\n4) The person who did a poster wrote about toucans; the person who used a video wrote about crocodiles.\n\r\n5) Sandie wrote about elephants, but she didn't use the internet or people.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPaul-crocodile-booklet-video\r\nSandie-elephant-magazine article-books\r\nLiam-toucan-poster-people\r\nMelissa-snake-leaflet-internet\n<|im_start|>answer\nPaul-crocodile-booklet-video\r\nSandie-elephant-magazine article-books\r\nLiam-toucan-poster-people\r\nMelissa-snake-leaflet-internet\n<|im_end|>" }, { "id": "#42474", "title": "Messy Files", "fun": 2.73, "difficulty": 2.58, "author": "cookieruler", "desc": "Dr. Neat N. Clean filed 5 patient records, including the names, age, date of appointment, sickness, and eye color. Dr. Mess E. Man mixed up the information when he entered it into the computer. Dr. Clean took notes while she was conducting the appointments. You are the hospital administrator. Fix the wrong information.\n\r\nDr. Clean's Notes:\r\n1. The youngest person has brown eyes.\r\n2. Chris has smallpox. \r\n3. The only person that did not have an appointment on a holiday has blue eyes.\r\n4. The oldest person has black eyes.\r\n5. The youngest person is female.\r\n6. Zach has a sickness that starts with the same letter as an earlier patient's name.\r\n7. The girlfriend of the person with hazel eyes was mad at him because he missed Valentine's Day.\r\n8. The youngest person had the earliest appointment.\r\n9. The person with chickenpox did not have a February appointment.\r\n10. Only people who drove themselves to the doctor were sick.\r\n11. Susan's eye color does not start with the letter B.\r\n12. Zach did not have the last appointment.\r\n13. The person with brown eyes had the first appointment.\r\n14. A male has mumps.\r\n15. Susan is not 17 or 35.\r\n16. Joe can't vote.\r\n17. Chris doesn't have hazel eyes.", "hint": "No hint available.", "answer": "Chris is 49, has black eyes, smallpox, and had an appointment on the Fourth of July.\n\r\nJoe is 17, has hazel eyes, mumps, and had an appointment on the Fourteenth of February.\n\r\nSusan is 26, has green eyes, measles, and had an appointment on the Thirty-First of October.\n\r\nJill is 12, has brown eyes, is well, and had an appointment on the First of January.\n\r\nZach is 35, has blue eyes, chicken pox, and has an appointment on the Twenty-Ninth of August.", "category": "Logic-Grid", "date": "07/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDr. Neat N. Clean filed 5 patient records, including the names, age, date of appointment, sickness, and eye color. Dr. Mess E. Man mixed up the information when he entered it into the computer. Dr. Clean took notes while she was conducting the appointments. You are the hospital administrator. Fix the wrong information.\n\r\nDr. Clean's Notes:\r\n1. The youngest person has brown eyes.\r\n2. Chris has smallpox. \r\n3. The only person that did not have an appointment on a holiday has blue eyes.\r\n4. The oldest person has black eyes.\r\n5. The youngest person is female.\r\n6. Zach has a sickness that starts with the same letter as an earlier patient's name.\r\n7. The girlfriend of the person with hazel eyes was mad at him because he missed Valentine's Day.\r\n8. The youngest person had the earliest appointment.\r\n9. The person with chickenpox did not have a February appointment.\r\n10. Only people who drove themselves to the doctor were sick.\r\n11. Susan's eye color does not start with the letter B.\r\n12. Zach did not have the last appointment.\r\n13. The person with brown eyes had the first appointment.\r\n14. A male has mumps.\r\n15. Susan is not 17 or 35.\r\n16. Joe can't vote.\r\n17. Chris doesn't have hazel eyes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChris is 49, has black eyes, smallpox, and had an appointment on the Fourth of July.\n\r\nJoe is 17, has hazel eyes, mumps, and had an appointment on the Fourteenth of February.\n\r\nSusan is 26, has green eyes, measles, and had an appointment on the Thirty-First of October.\n\r\nJill is 12, has brown eyes, is well, and had an appointment on the First of January.\n\r\nZach is 35, has blue eyes, chicken pox, and has an appointment on the Twenty-Ninth of August.\n<|im_start|>answer\nChris is 49, has black eyes, smallpox, and had an appointment on the Fourth of July.\n\r\nJoe is 17, has hazel eyes, mumps, and had an appointment on the Fourteenth of February.\n\r\nSusan is 26, has green eyes, measles, and had an appointment on the Thirty-First of October.\n\r\nJill is 12, has brown eyes, is well, and had an appointment on the First of January.\n\r\nZach is 35, has blue eyes, chicken pox, and has an appointment on the Twenty-Ninth of August.\n<|im_end|>" }, { "id": "#34172", "title": "On the Canal", "fun": 2.73, "difficulty": 1.73, "author": "rubytuesday", "desc": "Five barges, The Marianna, The Elizabeth, The English Rose, The Blackbird, and The Mermaid, were on a canal. Each was pulled by a different horse, Rosie, Star, Buck, Prince, and Itchy, and carried a different cargo, coal, gravel, iron, sand, and slate. Each barge was owned by either Bob, Bill, Fred, George or Ted.\n\r\nFigure out whose horse pulled which barge and what its cargo was.\n\r\n1. Bill's barge, which carried sand, was not named after a woman. His horse was not Star.\r\n2. Buck, who did not belong to Bob, pulled The Elizabeth.\r\n3. Fred owned The Mermaid.\r\n4. Ted's horse was Rosie but his barge was not The English Rose (which carried coal).\r\n5. George's barge did not carry slate.\r\n6. Itchy pulled the barge carrying Iron.", "hint": "No hint available.", "answer": "Bill owned the Blackbird, which carried sand and was pulled by Prince.\r\nFred owned The Mermaid, which carried iron and was pulled by Itchy.\r\nGeorge owned The Elizabeth, which carried gravel and was pulled by Buck.\r\nBob owned The English Rose, which was pulled by Star and carried coal.\r\nTed owned The Marianna, which was pulled by Rosie and carried slate.", "category": "Logic-Grid", "date": "11/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive barges, The Marianna, The Elizabeth, The English Rose, The Blackbird, and The Mermaid, were on a canal. Each was pulled by a different horse, Rosie, Star, Buck, Prince, and Itchy, and carried a different cargo, coal, gravel, iron, sand, and slate. Each barge was owned by either Bob, Bill, Fred, George or Ted.\n\r\nFigure out whose horse pulled which barge and what its cargo was.\n\r\n1. Bill's barge, which carried sand, was not named after a woman. His horse was not Star.\r\n2. Buck, who did not belong to Bob, pulled The Elizabeth.\r\n3. Fred owned The Mermaid.\r\n4. Ted's horse was Rosie but his barge was not The English Rose (which carried coal).\r\n5. George's barge did not carry slate.\r\n6. Itchy pulled the barge carrying Iron.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBill owned the Blackbird, which carried sand and was pulled by Prince.\r\nFred owned The Mermaid, which carried iron and was pulled by Itchy.\r\nGeorge owned The Elizabeth, which carried gravel and was pulled by Buck.\r\nBob owned The English Rose, which was pulled by Star and carried coal.\r\nTed owned The Marianna, which was pulled by Rosie and carried slate.\n<|im_start|>answer\nBill owned the Blackbird, which carried sand and was pulled by Prince.\r\nFred owned The Mermaid, which carried iron and was pulled by Itchy.\r\nGeorge owned The Elizabeth, which carried gravel and was pulled by Buck.\r\nBob owned The English Rose, which was pulled by Star and carried coal.\r\nTed owned The Marianna, which was pulled by Rosie and carried slate.\n<|im_end|>" }, { "id": "#49380", "title": "Tick Tock Bad Clock", "fun": 2.72, "difficulty": 1.93, "author": "firefox99", "desc": "Your friend gave you a clock for your birthday, but unfortunately, it's very unreliable. This one gains exactly 12 minutes every hour.\n\r\nIt is now showing 10pm and you know that it was correct at midnight, when you set it.\n\r\nIf the clock stopped four hours ago, what is the correct time now?", "hint": "No hint available.", "answer": "Since the clock gains 12 minutes every hour, for every real hour that has passed 72 minutes will pass on the clock. It has been 22 fake hours from midnight to the time the clock stopped, so in order to find the number of real hours we must first find the number of fake minutes, then divide the number of fake minutes by the number of minutes that pass by in an hour for the clock (72) to find the number of real hours that have passed from midnight to when the clock stopped. The following shows arithmetic work:\n\r\n22 x 60 = 1320 (clock minutes that have passed from midnight to when the clock stopped)\r\n1320 / 72 = 18.333333... (real hours that have passed from midnight to when the clock stopped)\r\n18.333333... hours = 18 hours 20 minutes. Therefore it was 6:20pm when the clock stopped. And because the clock stopped four hours ago, it is now 10:20pm!", "category": "Math", "date": "03/23/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour friend gave you a clock for your birthday, but unfortunately, it's very unreliable. This one gains exactly 12 minutes every hour.\n\r\nIt is now showing 10pm and you know that it was correct at midnight, when you set it.\n\r\nIf the clock stopped four hours ago, what is the correct time now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince the clock gains 12 minutes every hour, for every real hour that has passed 72 minutes will pass on the clock. It has been 22 fake hours from midnight to the time the clock stopped, so in order to find the number of real hours we must first find the number of fake minutes, then divide the number of fake minutes by the number of minutes that pass by in an hour for the clock (72) to find the number of real hours that have passed from midnight to when the clock stopped. The following shows arithmetic work:\n\r\n22 x 60 = 1320 (clock minutes that have passed from midnight to when the clock stopped)\r\n1320 / 72 = 18.333333... (real hours that have passed from midnight to when the clock stopped)\r\n18.333333... hours = 18 hours 20 minutes. Therefore it was 6:20pm when the clock stopped. And because the clock stopped four hours ago, it is now 10:20pm!\n<|im_start|>answer\nSince the clock gains 12 minutes every hour, for every real hour that has passed 72 minutes will pass on the clock. It has been 22 fake hours from midnight to the time the clock stopped, so in order to find the number of real hours we must first find the number of fake minutes, then divide the number of fake minutes by the number of minutes that pass by in an hour for the clock (72) to find the number of real hours that have passed from midnight to when the clock stopped. The following shows arithmetic work:\n\r\n22 x 60 = 1320 (clock minutes that have passed from midnight to when the clock stopped)\r\n1320 / 72 = 18.333333... (real hours that have passed from midnight to when the clock stopped)\r\n18.333333... hours = 18 hours 20 minutes. Therefore it was 6:20pm when the clock stopped. And because the clock stopped four hours ago, it is now 10:20pm!\n<|im_end|>" }, { "id": "#29321", "title": "Crazy Colors", "fun": 2.72, "difficulty": 1.76, "author": "____", "desc": "Here is what the chips are worth in a chip trading game:\n\r\n3 green chips have the same value as 5 blue chips. \r\n2 red chips have the same value as 1 yellow chip. \r\n4 red chips have the same value as 3 green chips. \r\nHow many blue chips can you get for 8 yellow chips?", "hint": "Get some chips and make the trades, or represent the trading with colored dots.", "answer": "You can get 20 blue chips for 8 yellow chips.\n\r\n1 yellow = 2 red, 8 yellow = 16 red\r\n4 red = 3 green, 16 red = 12 green\r\n3 green = 5 blue, 12 green = 20 blue", "category": "Math", "date": "03/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHere is what the chips are worth in a chip trading game:\n\r\n3 green chips have the same value as 5 blue chips. \r\n2 red chips have the same value as 1 yellow chip. \r\n4 red chips have the same value as 3 green chips. \r\nHow many blue chips can you get for 8 yellow chips?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou can get 20 blue chips for 8 yellow chips.\n\r\n1 yellow = 2 red, 8 yellow = 16 red\r\n4 red = 3 green, 16 red = 12 green\r\n3 green = 5 blue, 12 green = 20 blue\n<|im_start|>answer\nYou can get 20 blue chips for 8 yellow chips.\n\r\n1 yellow = 2 red, 8 yellow = 16 red\r\n4 red = 3 green, 16 red = 12 green\r\n3 green = 5 blue, 12 green = 20 blue\n<|im_end|>" }, { "id": "#42561", "title": "Last Year's Gifts", "fun": 2.72, "difficulty": 1.27, "author": "j279", "desc": "Four friends were talking about what their boyfriends gave them as a birthday present last year. Using the clues below, determine who their boyfriends are, when their birthdays are, and what they received.\n\r\nFriends: Allison, Betty, Christine, Diana\r\nBoyfriends: Chris, Dave, Tom, Bill\r\nBirthdays: February 18, April 7, August 24, October 30\r\nGifts: bracelet, flowers, earrings, diamond ring\n\r\nClues:\n\r\n1. The four girls are Diana, the girl who has a birthday in February, the girl who received the diamond ring, and Allison.\r\n2. Christine received the ring in October, but it wasn't from Tom or Dave.\r\n3. Betty is allergic to flowers, so her boyfriend, Tom, knew not to get them for her.\r\n4. Dave gave the bracelet to his girlfriend in August, and Bill proposed in October.\r\n5. Allison's boyfriend did not buy flowers for her.", "hint": "The diamond ring was given when one of the men proposed.", "answer": "Allison's boyfriend is Dave, and he gave her the bracelet on August 24.\r\nBetty's boyfriend is Tom, and he gave her the earrings on February 18.\r\nChristine's boyfriend is Bill, and he gave her the diamond ring on October 30.\r\nDiana's boyfriend is Chris, and he gave her the flowers on April 7.", "category": "Logic-Grid", "date": "07/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends were talking about what their boyfriends gave them as a birthday present last year. Using the clues below, determine who their boyfriends are, when their birthdays are, and what they received.\n\r\nFriends: Allison, Betty, Christine, Diana\r\nBoyfriends: Chris, Dave, Tom, Bill\r\nBirthdays: February 18, April 7, August 24, October 30\r\nGifts: bracelet, flowers, earrings, diamond ring\n\r\nClues:\n\r\n1. The four girls are Diana, the girl who has a birthday in February, the girl who received the diamond ring, and Allison.\r\n2. Christine received the ring in October, but it wasn't from Tom or Dave.\r\n3. Betty is allergic to flowers, so her boyfriend, Tom, knew not to get them for her.\r\n4. Dave gave the bracelet to his girlfriend in August, and Bill proposed in October.\r\n5. Allison's boyfriend did not buy flowers for her.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllison's boyfriend is Dave, and he gave her the bracelet on August 24.\r\nBetty's boyfriend is Tom, and he gave her the earrings on February 18.\r\nChristine's boyfriend is Bill, and he gave her the diamond ring on October 30.\r\nDiana's boyfriend is Chris, and he gave her the flowers on April 7.\n<|im_start|>answer\nAllison's boyfriend is Dave, and he gave her the bracelet on August 24.\r\nBetty's boyfriend is Tom, and he gave her the earrings on February 18.\r\nChristine's boyfriend is Bill, and he gave her the diamond ring on October 30.\r\nDiana's boyfriend is Chris, and he gave her the flowers on April 7.\n<|im_end|>" }, { "id": "#44665", "title": "Test Time", "fun": 2.72, "difficulty": 2.09, "author": "mrsfessler", "desc": "5 high school students (one is Cassie) took a test, each in a different subject taught by a different teacher. From the clues listed, determine each student's first and last name (one is Gallo), their teacher's name (one is Mrs. Landon), the subject and their grade (A, A-, B, C+ or D).\n\r\n1. Fischer got a higher grade than Delia who got a higher grade than Mr. Kohl's student. The two students who took science tests were the boy who got an A- and Mr. Jenkins.\n\r\n2. The student who earned an A and Eddie were not taught by an unmarried teacher.\n\r\n3. Bert, Mr. Moon's student and the kid who took the Physics test made the A/B Honor Roll. Mr. Kohl's student and Delia did not.\n\r\n4. The boy in Mrs. Otte's class scored farthest away from the score on the Spanish test. \n\r\n5. The 5 students were Miss Howard, the boy in Mr. Kohl's class, Aaron, the one who took the Chemistry test, and the one who earned a C+ in History.\n\r\n6. Miss Imbus, Miss Nunez's student and the Calculus student scored lower than Aaron.", "hint": "A \"D\" was scored on the Spanish test.", "answer": "Aaron Jenkins, Mrs. Otte, Physics, A\r\nBert Fischer, Miss Nunez, Chemistry, A-\t\t\t\r\nCassie Howard, Mr. Moon, Calculus, B\r\nDelia Imbus, Mrs. Landon, History, C+\t\t\t\r\nEddie Gallo, Mr. Kohl, Spanish, D", "category": "Logic-Grid", "date": "06/15/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 high school students (one is Cassie) took a test, each in a different subject taught by a different teacher. From the clues listed, determine each student's first and last name (one is Gallo), their teacher's name (one is Mrs. Landon), the subject and their grade (A, A-, B, C+ or D).\n\r\n1. Fischer got a higher grade than Delia who got a higher grade than Mr. Kohl's student. The two students who took science tests were the boy who got an A- and Mr. Jenkins.\n\r\n2. The student who earned an A and Eddie were not taught by an unmarried teacher.\n\r\n3. Bert, Mr. Moon's student and the kid who took the Physics test made the A/B Honor Roll. Mr. Kohl's student and Delia did not.\n\r\n4. The boy in Mrs. Otte's class scored farthest away from the score on the Spanish test. \n\r\n5. The 5 students were Miss Howard, the boy in Mr. Kohl's class, Aaron, the one who took the Chemistry test, and the one who earned a C+ in History.\n\r\n6. Miss Imbus, Miss Nunez's student and the Calculus student scored lower than Aaron.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAaron Jenkins, Mrs. Otte, Physics, A\r\nBert Fischer, Miss Nunez, Chemistry, A-\t\t\t\r\nCassie Howard, Mr. Moon, Calculus, B\r\nDelia Imbus, Mrs. Landon, History, C+\t\t\t\r\nEddie Gallo, Mr. Kohl, Spanish, D\n<|im_start|>answer\nAaron Jenkins, Mrs. Otte, Physics, A\r\nBert Fischer, Miss Nunez, Chemistry, A-\t\t\t\r\nCassie Howard, Mr. Moon, Calculus, B\r\nDelia Imbus, Mrs. Landon, History, C+\t\t\t\r\nEddie Gallo, Mr. Kohl, Spanish, D\n<|im_end|>" }, { "id": "#26499", "title": "7 Bags", "fun": 2.72, "difficulty": 2.03, "author": "Question_Mark", "desc": "I have 7 bags of marbles. There are 200 marbles in total. Using the clues below, work out how many marbles are in each bag.\n\r\nBag 1 + Bag 2 = 57 marbles\r\nBag 2 + Bag 3 = 83 marbles\r\nBag 3 + Bag 4 = 71 marbles\r\nBag 4 + Bag 5 = 43 marbles\r\nBag 5 + Bag 6 = 66 marbles\r\nBag 6 + Bag 7 = 43 marbles", "hint": "No hint available.", "answer": "Bag 1 = 31 marbles\r\nBag 2 = 26 marbles\r\nBag 3 = 57 marbles\r\nBag 4 = 14 marbles\r\nBag 5 = 29 marbles\r\nBag 6 = 37 marbles\r\nBag 7 = 6 marbles\n\r\nIf you know that Bag 1 + Bag 2 = 57 marbles, and Bag 3 + Bag 4 = 71 marbles, and Bag 6 + Bag 7 = 43 marbles, then you should be able to work out the amount of marbles for Bag 5. 200-57-71-43=29 so Bag 5 has 29 marbles. From that you can work out that Bag 4 has 14 marbles and Bag 6 has 37. From that you can work out that Bag 3 has 57 marbles and that Bag 7 has 6 marbles. From that you can work out that Bag 2 has 26 marbles and from that you can work out that Bag 1 has 31 marbles.", "category": "Math", "date": "10/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have 7 bags of marbles. There are 200 marbles in total. Using the clues below, work out how many marbles are in each bag.\n\r\nBag 1 + Bag 2 = 57 marbles\r\nBag 2 + Bag 3 = 83 marbles\r\nBag 3 + Bag 4 = 71 marbles\r\nBag 4 + Bag 5 = 43 marbles\r\nBag 5 + Bag 6 = 66 marbles\r\nBag 6 + Bag 7 = 43 marbles\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBag 1 = 31 marbles\r\nBag 2 = 26 marbles\r\nBag 3 = 57 marbles\r\nBag 4 = 14 marbles\r\nBag 5 = 29 marbles\r\nBag 6 = 37 marbles\r\nBag 7 = 6 marbles\n\r\nIf you know that Bag 1 + Bag 2 = 57 marbles, and Bag 3 + Bag 4 = 71 marbles, and Bag 6 + Bag 7 = 43 marbles, then you should be able to work out the amount of marbles for Bag 5. 200-57-71-43=29 so Bag 5 has 29 marbles. From that you can work out that Bag 4 has 14 marbles and Bag 6 has 37. From that you can work out that Bag 3 has 57 marbles and that Bag 7 has 6 marbles. From that you can work out that Bag 2 has 26 marbles and from that you can work out that Bag 1 has 31 marbles.\n<|im_start|>answer\nBag 1 = 31 marbles\r\nBag 2 = 26 marbles\r\nBag 3 = 57 marbles\r\nBag 4 = 14 marbles\r\nBag 5 = 29 marbles\r\nBag 6 = 37 marbles\r\nBag 7 = 6 marbles\n\r\nIf you know that Bag 1 + Bag 2 = 57 marbles, and Bag 3 + Bag 4 = 71 marbles, and Bag 6 + Bag 7 = 43 marbles, then you should be able to work out the amount of marbles for Bag 5. 200-57-71-43=29 so Bag 5 has 29 marbles. From that you can work out that Bag 4 has 14 marbles and Bag 6 has 37. From that you can work out that Bag 3 has 57 marbles and that Bag 7 has 6 marbles. From that you can work out that Bag 2 has 26 marbles and from that you can work out that Bag 1 has 31 marbles.\n<|im_end|>" }, { "id": "#4614", "title": "100 Yard Dash", "fun": 2.72, "difficulty": 1.42, "author": "bobbrt", "desc": "Bill and Ted race each other in a 100 yard dash. Bill wins by 10 yards. They decide to race again, but to make things fair Bill starts 10 yards behind Ted. If they both run exactly the same speed as before, who wins the race?", "hint": "No hint available.", "answer": "Bill will win again. In the first race Bill ran 100 yards in the time it took Ted to run 90. Therefore in the second race, once Ted has run 90 yards they will both be side by side. Since Bill runs faster, he will take less time to run the last 10 yards than Ted and will therefore win.", "category": "Math", "date": "06/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBill and Ted race each other in a 100 yard dash. Bill wins by 10 yards. They decide to race again, but to make things fair Bill starts 10 yards behind Ted. If they both run exactly the same speed as before, who wins the race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBill will win again. In the first race Bill ran 100 yards in the time it took Ted to run 90. Therefore in the second race, once Ted has run 90 yards they will both be side by side. Since Bill runs faster, he will take less time to run the last 10 yards than Ted and will therefore win.\n<|im_start|>answer\nBill will win again. In the first race Bill ran 100 yards in the time it took Ted to run 90. Therefore in the second race, once Ted has run 90 yards they will both be side by side. Since Bill runs faster, he will take less time to run the last 10 yards than Ted and will therefore win.\n<|im_end|>" }, { "id": "#3598", "title": "Toddlers and Teddies", "fun": 2.72, "difficulty": 1.91, "author": "lil_thugsta", "desc": "At the local play group for babies and toddlers, I was asking the mothers about the number of teddies each of their children has. The four children are aged 1, 2, 3 and 4. Remarkably, the children have one, two, three and four teddies, although not necessarily respectively. James has more teddies than his age. John is older than Matthew. Curiously only one child has the same number of teddies as his age. Paul has less teddies than John, and the child aged 3 has two teddies. Paul is the youngest. \n\r\nHow old is each child and how many teddies do they have each?", "hint": "No hint available.", "answer": "Matthew is 3 and has two teddies.\r\nPaul is 1 and has one teddy.\r\nJohn is 4 and has three teddies.\r\nJames is 2 and has four teddies.", "category": "Logic", "date": "04/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the local play group for babies and toddlers, I was asking the mothers about the number of teddies each of their children has. The four children are aged 1, 2, 3 and 4. Remarkably, the children have one, two, three and four teddies, although not necessarily respectively. James has more teddies than his age. John is older than Matthew. Curiously only one child has the same number of teddies as his age. Paul has less teddies than John, and the child aged 3 has two teddies. Paul is the youngest. \n\r\nHow old is each child and how many teddies do they have each?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMatthew is 3 and has two teddies.\r\nPaul is 1 and has one teddy.\r\nJohn is 4 and has three teddies.\r\nJames is 2 and has four teddies.\n<|im_start|>answer\nMatthew is 3 and has two teddies.\r\nPaul is 1 and has one teddy.\r\nJohn is 4 and has three teddies.\r\nJames is 2 and has four teddies.\n<|im_end|>" }, { "id": "#50604", "title": "Sums", "fun": 2.72, "difficulty": 1.61, "author": "Genius39", "desc": "7 + 7 = 2\r\n8 + 8 = 4\r\n8 + 5 = 1\r\n6 + 9 = 3\r\n10 + 11 = 9\n\r\nIn this sense, what is the value of 4 + 9?", "hint": "It is about time you have known the answer.", "answer": "1.\r\nThe solution is to add both numbers in the sense of hours, for the first number being the time in AM, and the second number being the number of hours added. The result is the time in PM.\r\nFor the hint, \"It is ABOUT TIME you have known the answer.\"", "category": "Logic", "date": "05/15/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n7 + 7 = 2\r\n8 + 8 = 4\r\n8 + 5 = 1\r\n6 + 9 = 3\r\n10 + 11 = 9\n\r\nIn this sense, what is the value of 4 + 9?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1.\r\nThe solution is to add both numbers in the sense of hours, for the first number being the time in AM, and the second number being the number of hours added. The result is the time in PM.\r\nFor the hint, \"It is ABOUT TIME you have known the answer.\"\n<|im_start|>answer\n1.\r\nThe solution is to add both numbers in the sense of hours, for the first number being the time in AM, and the second number being the number of hours added. The result is the time in PM.\r\nFor the hint, \"It is ABOUT TIME you have known the answer.\"\n<|im_end|>" }, { "id": "#31323", "title": "Backfired Pranks", "fun": 2.72, "difficulty": 1.52, "author": "dishu", "desc": "The naughty four friends once decided to play some practical pranks on four different innocent guys. They learnt 4 different magic spells from the book \"Learn Magic in 2 Days\". Unfortunately, their magic backfired and instead of the intended victims, the girls themselves suffered from 4 different problems. \r\nWith the help of these clues, can you figure out which girl chose which guy as her victim, which spell she threw on him, and what problem did she face as a result of spell backfire.\n\r\nGirls: Dis, Dip, Raj, Rich\r\nBoys: Sur, Rot, Dud, Ank\r\nSpell: Vomiting, Fever, Appetite Loss, Balding\r\nBackfired result: Fainting, Freckles, Obesity, Pimples\n\r\n1. The high fever spell gave pimples to the thrower.\r\n2. The spell intended to make Rot lose appetite, made the thrower obese.\r\n3. It looked like Rich has spent many long hours in the sun after her spell on Dud backfired.\r\n4. The worst sufferer was Sur's torturer, as she remained unconscious for hours after her spell backfired.\r\n5. The vomiting spell was not intended for Dud.\r\n6. Dip was forced to order a new wardrobe for herself, as her existing clothes became useless after her spell backfired.\r\n7. Dis could not show her face to anyone for weeks.", "hint": "No hint available.", "answer": "Dis, Ank, fever, pimples\r\nDip, Rot, appetite loss, obesity\r\nRaj, Sur, vomiting, fainting\r\nRich, Dud, balding, freckles", "category": "Logic-Grid", "date": "06/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe naughty four friends once decided to play some practical pranks on four different innocent guys. They learnt 4 different magic spells from the book \"Learn Magic in 2 Days\". Unfortunately, their magic backfired and instead of the intended victims, the girls themselves suffered from 4 different problems. \r\nWith the help of these clues, can you figure out which girl chose which guy as her victim, which spell she threw on him, and what problem did she face as a result of spell backfire.\n\r\nGirls: Dis, Dip, Raj, Rich\r\nBoys: Sur, Rot, Dud, Ank\r\nSpell: Vomiting, Fever, Appetite Loss, Balding\r\nBackfired result: Fainting, Freckles, Obesity, Pimples\n\r\n1. The high fever spell gave pimples to the thrower.\r\n2. The spell intended to make Rot lose appetite, made the thrower obese.\r\n3. It looked like Rich has spent many long hours in the sun after her spell on Dud backfired.\r\n4. The worst sufferer was Sur's torturer, as she remained unconscious for hours after her spell backfired.\r\n5. The vomiting spell was not intended for Dud.\r\n6. Dip was forced to order a new wardrobe for herself, as her existing clothes became useless after her spell backfired.\r\n7. Dis could not show her face to anyone for weeks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDis, Ank, fever, pimples\r\nDip, Rot, appetite loss, obesity\r\nRaj, Sur, vomiting, fainting\r\nRich, Dud, balding, freckles\n<|im_start|>answer\nDis, Ank, fever, pimples\r\nDip, Rot, appetite loss, obesity\r\nRaj, Sur, vomiting, fainting\r\nRich, Dud, balding, freckles\n<|im_end|>" }, { "id": "#36694", "title": "School Bus Scramble", "fun": 2.72, "difficulty": 1.51, "author": "Smeraldina", "desc": "Help! It's Miss Appleday's first day of school, and she has to make sure all her first graders get on the right buses and go home with the right backpacks. Most of her students are safely on their buses, but she still has four students to send on their way. Can you help Miss Appleday remember the students' first and last names, which backpack to give each child, and which school bus will take each child home? \n\r\nFirst names: Joaquin, Ray, Reiko, Shantel, \r\nLast names: Diamond, Galvez, Johnson, Rivero\r\nThe buses are labelled by color: Green, Grey, Magenta, Red\r\nBackpacks: Hello Kitty, Powerpuff Girls, Power Rangers, Scooby-Doo\n\r\n1. Reiko loves her Hello Kitty backpack which was a birthday gift from her grandma. She remembers which bus color is hers because it starts with the same letter as her last name. \n\r\n2. Two students have alliterative first and last names.\n\r\n3. The boy who loves Power Rangers does not take the Grey Bus. \n\r\n4. Ray moved over the summer and doesn't take the Red Bus anymore. He's grumpy today because he has to use his older sister's \"girly\" backpack (he wrecked his own yesterday playing tug-of-war with the dog). \n\r\n5. Young Mr. Johnson rides the Green Bus to school. \n\r\n6. The Scooby-Doo backpack was left on the Red Bus this morning. Luckily, the bus driver found it and brought it into the school.", "hint": "No hint available.", "answer": "Joaquin Johnson takes the Green Bus and carries a Power Rangers backpack. \r\nRay Rivero rides the Magenta Bus and is grumpy about carrying his sister's hand-me-down Powerpuff Girls backpack.\r\nReiko Galvez remembers that she rides the Grey Bus and loves her Hello Kitty backpack.\r\nShantel Diamond left her Scooby-Doo backpack on the Red Bus this morning.", "category": "Logic-Grid", "date": "05/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHelp! It's Miss Appleday's first day of school, and she has to make sure all her first graders get on the right buses and go home with the right backpacks. Most of her students are safely on their buses, but she still has four students to send on their way. Can you help Miss Appleday remember the students' first and last names, which backpack to give each child, and which school bus will take each child home? \n\r\nFirst names: Joaquin, Ray, Reiko, Shantel, \r\nLast names: Diamond, Galvez, Johnson, Rivero\r\nThe buses are labelled by color: Green, Grey, Magenta, Red\r\nBackpacks: Hello Kitty, Powerpuff Girls, Power Rangers, Scooby-Doo\n\r\n1. Reiko loves her Hello Kitty backpack which was a birthday gift from her grandma. She remembers which bus color is hers because it starts with the same letter as her last name. \n\r\n2. Two students have alliterative first and last names.\n\r\n3. The boy who loves Power Rangers does not take the Grey Bus. \n\r\n4. Ray moved over the summer and doesn't take the Red Bus anymore. He's grumpy today because he has to use his older sister's \"girly\" backpack (he wrecked his own yesterday playing tug-of-war with the dog). \n\r\n5. Young Mr. Johnson rides the Green Bus to school. \n\r\n6. The Scooby-Doo backpack was left on the Red Bus this morning. Luckily, the bus driver found it and brought it into the school.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoaquin Johnson takes the Green Bus and carries a Power Rangers backpack. \r\nRay Rivero rides the Magenta Bus and is grumpy about carrying his sister's hand-me-down Powerpuff Girls backpack.\r\nReiko Galvez remembers that she rides the Grey Bus and loves her Hello Kitty backpack.\r\nShantel Diamond left her Scooby-Doo backpack on the Red Bus this morning.\n<|im_start|>answer\nJoaquin Johnson takes the Green Bus and carries a Power Rangers backpack. \r\nRay Rivero rides the Magenta Bus and is grumpy about carrying his sister's hand-me-down Powerpuff Girls backpack.\r\nReiko Galvez remembers that she rides the Grey Bus and loves her Hello Kitty backpack.\r\nShantel Diamond left her Scooby-Doo backpack on the Red Bus this morning.\n<|im_end|>" }, { "id": "#1338", "title": "Home improvement", "fun": 2.72, "difficulty": 1.95, "author": "Gokaran", "desc": "After a recent spate of home improvements, four couples were having a dinner party to discuss the additions to their houses. Alan had not recently had a new bathroom. Kara had not yet done her kitchen, but perhaps would update it next. Brian, who is married to Maud, had not had new windows. Laura delighted in showing photographs of her new conservatory. Neither Charles nor David had a new kitchen. Julie had not had new windows. Alan, who also had not had windows, is not married to Laura and Charles is not married to Kara. \n\r\nWho is married to whom and what work had they recently undertaken, assuming that each couple had one improvement and no two couples had the same improvement.", "hint": "No hint available.", "answer": "Alan is married to Julie and they had a new kitchen.\r\nBrian is married to Maud and they had a new bathroom.\r\nCharles is married to Laura and they had a new conservatory.\r\nDavid is married to Kara and they had new windows.", "category": "Logic", "date": "11/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter a recent spate of home improvements, four couples were having a dinner party to discuss the additions to their houses. Alan had not recently had a new bathroom. Kara had not yet done her kitchen, but perhaps would update it next. Brian, who is married to Maud, had not had new windows. Laura delighted in showing photographs of her new conservatory. Neither Charles nor David had a new kitchen. Julie had not had new windows. Alan, who also had not had windows, is not married to Laura and Charles is not married to Kara. \n\r\nWho is married to whom and what work had they recently undertaken, assuming that each couple had one improvement and no two couples had the same improvement.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlan is married to Julie and they had a new kitchen.\r\nBrian is married to Maud and they had a new bathroom.\r\nCharles is married to Laura and they had a new conservatory.\r\nDavid is married to Kara and they had new windows.\n<|im_start|>answer\nAlan is married to Julie and they had a new kitchen.\r\nBrian is married to Maud and they had a new bathroom.\r\nCharles is married to Laura and they had a new conservatory.\r\nDavid is married to Kara and they had new windows.\n<|im_end|>" }, { "id": "#48749", "title": "30 Numbers", "fun": 2.72, "difficulty": 1.96, "author": "shenqiang", "desc": "Numbers from 1 to 30 are written on a blackboard.\n\r\nAdd the first two numbers, and append it to the end, then erase the first two numbers.\n\r\nFor example, after the first time, the numbers become 3, 4, 5, ..., 29, 30, and 3.\n\r\nRepeat this process until you get only one number.\n\r\nHow many addition operations are there, and what is the last number on the blackboard?", "hint": "Try to find the pattern.", "answer": "After each operation, the numbers reduce by one, therefore you need 29 times.\n\r\nOf course, the last number remaining on the blackboard is the sum of all the numbers from 1 to 30, which is (1+30)*30/2=465.", "category": "Math", "date": "05/25/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNumbers from 1 to 30 are written on a blackboard.\n\r\nAdd the first two numbers, and append it to the end, then erase the first two numbers.\n\r\nFor example, after the first time, the numbers become 3, 4, 5, ..., 29, 30, and 3.\n\r\nRepeat this process until you get only one number.\n\r\nHow many addition operations are there, and what is the last number on the blackboard?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter each operation, the numbers reduce by one, therefore you need 29 times.\n\r\nOf course, the last number remaining on the blackboard is the sum of all the numbers from 1 to 30, which is (1+30)*30/2=465.\n<|im_start|>answer\nAfter each operation, the numbers reduce by one, therefore you need 29 times.\n\r\nOf course, the last number remaining on the blackboard is the sum of all the numbers from 1 to 30, which is (1+30)*30/2=465.\n<|im_end|>" }, { "id": "#28950", "title": "Local Bus Company", "fun": 2.72, "difficulty": 1.84, "author": "Draw", "desc": "My local bus company has recently expanded and no longer has enough room for all of its buses. Twelve of their buses have to be stored outside. If they decide to increase their garage space by 40%, this will give them enough room for all of their current buses, plus enough room to store another twelve in the future. How many buses does the company currently own?", "hint": "No hint available.", "answer": "72 buses. \n\r\nThey have enough room for 60 of these, expanding the 60 capacity by 40% will give them enough room for 84 - which we know is 12 more than their current count.", "category": "Math", "date": "03/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy local bus company has recently expanded and no longer has enough room for all of its buses. Twelve of their buses have to be stored outside. If they decide to increase their garage space by 40%, this will give them enough room for all of their current buses, plus enough room to store another twelve in the future. How many buses does the company currently own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n72 buses. \n\r\nThey have enough room for 60 of these, expanding the 60 capacity by 40% will give them enough room for 84 - which we know is 12 more than their current count.\n<|im_start|>answer\n72 buses. \n\r\nThey have enough room for 60 of these, expanding the 60 capacity by 40% will give them enough room for 84 - which we know is 12 more than their current count.\n<|im_end|>" }, { "id": "#14553", "title": "Consecutive numbers", "fun": 2.72, "difficulty": 2.71, "author": "Gerd", "desc": "Between 1000 and 2000 you can get each integer as the sum of nonnegative consecutive integers. For example,\n\r\n147+148+149+150+151+152+153 = 1050\n\r\nThere is only one number that you cannot get.\n\r\nWhat is this number?", "hint": "I hope you got the power!", "answer": "1024\n\r\nOnly powers of 2 are not reachable, and the next number is 2048.", "category": "Math", "date": "08/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBetween 1000 and 2000 you can get each integer as the sum of nonnegative consecutive integers. For example,\n\r\n147+148+149+150+151+152+153 = 1050\n\r\nThere is only one number that you cannot get.\n\r\nWhat is this number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1024\n\r\nOnly powers of 2 are not reachable, and the next number is 2048.\n<|im_start|>answer\n1024\n\r\nOnly powers of 2 are not reachable, and the next number is 2048.\n<|im_end|>" }, { "id": "#7120", "title": "Stop the Horse", "fun": 2.72, "difficulty": 1.83, "author": "Cascas", "desc": "Bouncing Bob was riding a particularly frisky horse when suddenly its bridle came off. As they raced down the road, a screaming Bob clung to the horse's ears for dear life. Out of the corner of his eye, Bob saw a car coming, and realizing the horse was completely out of control, he panicked. Flailing his arms about, he accidentally caused the horse to come to an abrupt halt. What could Bouncing Bob have done to make the horse stop?", "hint": "No hint available.", "answer": "Bob accidentally put his hands over the horse's eyes. If a horse can't see he will automatically stop.", "category": "Logic", "date": "09/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBouncing Bob was riding a particularly frisky horse when suddenly its bridle came off. As they raced down the road, a screaming Bob clung to the horse's ears for dear life. Out of the corner of his eye, Bob saw a car coming, and realizing the horse was completely out of control, he panicked. Flailing his arms about, he accidentally caused the horse to come to an abrupt halt. What could Bouncing Bob have done to make the horse stop?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob accidentally put his hands over the horse's eyes. If a horse can't see he will automatically stop.\n<|im_start|>answer\nBob accidentally put his hands over the horse's eyes. If a horse can't see he will automatically stop.\n<|im_end|>" }, { "id": "#25520", "title": "Jack's Used Cars", "fun": 2.72, "difficulty": 1.96, "author": "dddlite", "desc": "Jack Dublovsky, a used car dealer, sold 9 cars last week. However, Jack never writes the dates on his contracts. He can remember the colors of the cars but not what days they sold on. If you can help him, he promises to write the dates on his contracts from now on! The colors of the cars are: green, blue, black, red, yellow, white, gold, purple, and silver. Jack's Used Cars is only open Monday through Saturday. This is what Jack remembers:\n\r\n1. Jack sold 2 more cars on Tuesday than he did on Wednesday - his slowest sales day.\r\n2. The cars with primary colors were sold on Monday, Tuesday, and Saturday.\r\n3. The purple & gold cars weren't sold at the beginning of the week, but they were sold on the same day.\r\n4. The silver & yellow cars were sold 3 days before the white car (2 days between), the white car was sold 2 days before the blue car (1 day between).\r\n5. The cars sold on Tuesday put Jack in a Christmas holiday spirit.\r\n6. The black car was sold the same day as the gold car.\r\n7. Friday was Jack's busiest sales day.\r\n8. Only one car was sold on Thursday and Saturday.", "hint": "Wednesday is Jack's slowest day.\r\nThe Christmas Holiday is usually represented by red & green.", "answer": "Monday - 2 cars - yellow & silver\r\nTuesday - 2 cars - red & green\r\nWednesday - 0 cars\r\nThursday - 1 car - white\r\nFriday - 3 cars - purple, gold & black\r\nSaturday - 1 car - blue", "category": "Logic", "date": "08/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack Dublovsky, a used car dealer, sold 9 cars last week. However, Jack never writes the dates on his contracts. He can remember the colors of the cars but not what days they sold on. If you can help him, he promises to write the dates on his contracts from now on! The colors of the cars are: green, blue, black, red, yellow, white, gold, purple, and silver. Jack's Used Cars is only open Monday through Saturday. This is what Jack remembers:\n\r\n1. Jack sold 2 more cars on Tuesday than he did on Wednesday - his slowest sales day.\r\n2. The cars with primary colors were sold on Monday, Tuesday, and Saturday.\r\n3. The purple & gold cars weren't sold at the beginning of the week, but they were sold on the same day.\r\n4. The silver & yellow cars were sold 3 days before the white car (2 days between), the white car was sold 2 days before the blue car (1 day between).\r\n5. The cars sold on Tuesday put Jack in a Christmas holiday spirit.\r\n6. The black car was sold the same day as the gold car.\r\n7. Friday was Jack's busiest sales day.\r\n8. Only one car was sold on Thursday and Saturday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday - 2 cars - yellow & silver\r\nTuesday - 2 cars - red & green\r\nWednesday - 0 cars\r\nThursday - 1 car - white\r\nFriday - 3 cars - purple, gold & black\r\nSaturday - 1 car - blue\n<|im_start|>answer\nMonday - 2 cars - yellow & silver\r\nTuesday - 2 cars - red & green\r\nWednesday - 0 cars\r\nThursday - 1 car - white\r\nFriday - 3 cars - purple, gold & black\r\nSaturday - 1 car - blue\n<|im_end|>" }, { "id": "#31539", "title": "Coffee Grind", "fun": 2.72, "difficulty": 2.08, "author": "FreddyPharkas", "desc": "Fred had just started work in Hotel Plush and was dealing with a demanding but important guest. \"Pour my coffee, boy! I want exactly 200ml coffee to which you will add enough full cream milk to make it 20% milk. Do it correctly and you may go about your other duties, get it wrong and I will call the manager,\" screeched the darling lady.\n\r\nIt was all Fred could do to stop his hands from trembling as he started to pour the coffee. He poured 200ml into the measuring jug, (he keeps one about his person at all times for such eventualities), then started to think about the milk. 20% of 200ml is 40ml but if he poured 40ml in, the volume would be 240ml, so it wouldn't be 20% milk any more. How much milk should he add?", "hint": "No hint available.", "answer": "The only volume we know is for the coffee, 200ml, so that's the starting point. We also know the final coffee is to be 20% milk, but that also means it is 80% coffee , so 80% = 200ml. That also means 20% = 50ml (80%/4=200ml/4), so he needs to add 50ml milk. Whether he puts anything else in there as well is between Fred and his conscience.", "category": "Math", "date": "07/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred had just started work in Hotel Plush and was dealing with a demanding but important guest. \"Pour my coffee, boy! I want exactly 200ml coffee to which you will add enough full cream milk to make it 20% milk. Do it correctly and you may go about your other duties, get it wrong and I will call the manager,\" screeched the darling lady.\n\r\nIt was all Fred could do to stop his hands from trembling as he started to pour the coffee. He poured 200ml into the measuring jug, (he keeps one about his person at all times for such eventualities), then started to think about the milk. 20% of 200ml is 40ml but if he poured 40ml in, the volume would be 240ml, so it wouldn't be 20% milk any more. How much milk should he add?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe only volume we know is for the coffee, 200ml, so that's the starting point. We also know the final coffee is to be 20% milk, but that also means it is 80% coffee , so 80% = 200ml. That also means 20% = 50ml (80%/4=200ml/4), so he needs to add 50ml milk. Whether he puts anything else in there as well is between Fred and his conscience.\n<|im_start|>answer\nThe only volume we know is for the coffee, 200ml, so that's the starting point. We also know the final coffee is to be 20% milk, but that also means it is 80% coffee , so 80% = 200ml. That also means 20% = 50ml (80%/4=200ml/4), so he needs to add 50ml milk. Whether he puts anything else in there as well is between Fred and his conscience.\n<|im_end|>" }, { "id": "#37011", "title": "Guess That Number I", "fun": 2.72, "difficulty": 1.34, "author": "pokpic", "desc": "\"And welcome back to Guess That Number! Before the break Mr. Pok got to the 1 million dollar question! So, Mr. Pok how are you feeling?\"\r\n\"Very nervous Bill, very nervous,\" replied Mr. Pok. \r\n\"Okay Mr. Pok, you know what to do. We'll put a set of clues on are screen, and you must figure out what number we're talking about! Today, the mystery number is represented by A. Mr. Pok, if you can figure out what number A stands for in 2 minutes or less, we'll give you 1 million dollars! Are you ready?\" asked Bill.\r\n\"I hope so,\" answered Mr. Pok.\r\n\"Okay! The clues are on our screen! On your mark! Get set! GO!\" screamed Bill. \r\nMr. Pok turned around and faced the screen. My challenge to you is can you help Mr. Pok win the million dollar prize? Here are the clues given to Mr. Pok:\r\n1. 100 is larger than A.\r\n2. A is larger than 30.\r\n3. A is a multiple of 6.\r\n4. The sum of A's digits is 9.\r\n5. The number in the tens place is larger than the number in the ones place.\r\n6. The difference between A's digits is 1.\r\nMr. Pok figured out the answer and scribbled it down on the notebook in front of him right when the buzzer sounded. He raised his answer for all to see. \r\n\"Congratulations Mr. Pok! You have won 1 million dollars!\" Bill said into the microphone. \r\nWhat number did Mr. Pok write in the notebook?", "hint": "No hint available.", "answer": "Mr. Pok wrote 54.\n\r\nWe first start with clue number 1. We figure out A is less than 100. Next we look at clue number 2. We figure out that A is bigger than 30. So we now know that A has to be between 31 and 99.\n\r\nThe third clue tells us that it has to be a multiple of 6. So you write down all the multiples of six between 31 and 99. The multiples are 36, 42, 48 54, 60, 66, 72, 78, 84, 90, and 96.\n\r\nNext, we find out that the sum of A's digits is 9, so we can cross out 42, 48, 60, 66, 78, 84, and 96. Next, we find out that the number in the tens place is larger than the number in the ones place so we can cross out 36. The last clue tells us that the difference between A's digits is 1. So therefore the only number that fits all 6 clues is 54.", "category": "Math", "date": "06/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"And welcome back to Guess That Number! Before the break Mr. Pok got to the 1 million dollar question! So, Mr. Pok how are you feeling?\"\r\n\"Very nervous Bill, very nervous,\" replied Mr. Pok. \r\n\"Okay Mr. Pok, you know what to do. We'll put a set of clues on are screen, and you must figure out what number we're talking about! Today, the mystery number is represented by A. Mr. Pok, if you can figure out what number A stands for in 2 minutes or less, we'll give you 1 million dollars! Are you ready?\" asked Bill.\r\n\"I hope so,\" answered Mr. Pok.\r\n\"Okay! The clues are on our screen! On your mark! Get set! GO!\" screamed Bill. \r\nMr. Pok turned around and faced the screen. My challenge to you is can you help Mr. Pok win the million dollar prize? Here are the clues given to Mr. Pok:\r\n1. 100 is larger than A.\r\n2. A is larger than 30.\r\n3. A is a multiple of 6.\r\n4. The sum of A's digits is 9.\r\n5. The number in the tens place is larger than the number in the ones place.\r\n6. The difference between A's digits is 1.\r\nMr. Pok figured out the answer and scribbled it down on the notebook in front of him right when the buzzer sounded. He raised his answer for all to see. \r\n\"Congratulations Mr. Pok! You have won 1 million dollars!\" Bill said into the microphone. \r\nWhat number did Mr. Pok write in the notebook?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Pok wrote 54.\n\r\nWe first start with clue number 1. We figure out A is less than 100. Next we look at clue number 2. We figure out that A is bigger than 30. So we now know that A has to be between 31 and 99.\n\r\nThe third clue tells us that it has to be a multiple of 6. So you write down all the multiples of six between 31 and 99. The multiples are 36, 42, 48 54, 60, 66, 72, 78, 84, 90, and 96.\n\r\nNext, we find out that the sum of A's digits is 9, so we can cross out 42, 48, 60, 66, 78, 84, and 96. Next, we find out that the number in the tens place is larger than the number in the ones place so we can cross out 36. The last clue tells us that the difference between A's digits is 1. So therefore the only number that fits all 6 clues is 54.\n<|im_start|>answer\nMr. Pok wrote 54.\n\r\nWe first start with clue number 1. We figure out A is less than 100. Next we look at clue number 2. We figure out that A is bigger than 30. So we now know that A has to be between 31 and 99.\n\r\nThe third clue tells us that it has to be a multiple of 6. So you write down all the multiples of six between 31 and 99. The multiples are 36, 42, 48 54, 60, 66, 72, 78, 84, 90, and 96.\n\r\nNext, we find out that the sum of A's digits is 9, so we can cross out 42, 48, 60, 66, 78, 84, and 96. Next, we find out that the number in the tens place is larger than the number in the ones place so we can cross out 36. The last clue tells us that the difference between A's digits is 1. So therefore the only number that fits all 6 clues is 54.\n<|im_end|>" }, { "id": "#33197", "title": "American Football", "fun": 2.72, "difficulty": 2.2, "author": "xsagirl", "desc": "Five cousins recently took part in an American football match, playing for charity. Each came along wearing a different colored shirt, and sporting a different number (not necessarily related to the position played, since these were the only football shirts they possess). Each is a fan of a major football team; so find out which color of shirt and number each player wore, as well as the name of the team he supports.\n\r\n1. The cousin who wore the white shirt (which didn't have No. 33 printed on it) doesn't support the Eagles.\n\r\n2. The quarterback's shirt had a number ten higher than that on the blue shirt worn by the wide receiver.\n\r\n3. The running back, who supports the Jetstars, wore a higher number than that on his cousin's orange shirt.\n\r\n4. The Blue Sox supporter wore No. 23 and the linebacker wore No. 43.\n\r\n5. The man in green supports the Dolphins and wore a number lower than that of the offensive linesman.", "hint": "In the grid:\r\nOff linesman = Offensive linesman", "answer": "The linebacker wore No. 43 (clue 4). The cousin in the No. 13 shirt wasn't the running back (clue 3) or offensive linesman (5), so the quarterback's shirt had No. 23 and the wide receiver's blue shirt had No. 13. The quarterback supports the Blue Sox (4). The running back supports the Jetstars (3). The man in green, who supports the Dolphins, isn't the offensive linesman (5), so the offensive linesman's shirt had No. 53. The running back thus wore No. 33, thus his shirt isn't white (1) or orange (3), so yellow. The quarterback's shirt was orange (3). The offensive linesman thus wore white. He doesn't support the Eagles (1), so the Harlequins. The wide receiver supports the Eagles.\n\r\nThus:\n\r\nLinebacker, No. 43, green, Dolphins;\r\nOffensive linesman, No. 53, white, Harlequins;\r\nQuarterback, No. 23, orange, Blue Sox;\r\nRunning back, No. 33, yellow, Jetstars;\r\nWide receiver, No. 13, blue, Eagles.", "category": "Logic-Grid", "date": "09/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive cousins recently took part in an American football match, playing for charity. Each came along wearing a different colored shirt, and sporting a different number (not necessarily related to the position played, since these were the only football shirts they possess). Each is a fan of a major football team; so find out which color of shirt and number each player wore, as well as the name of the team he supports.\n\r\n1. The cousin who wore the white shirt (which didn't have No. 33 printed on it) doesn't support the Eagles.\n\r\n2. The quarterback's shirt had a number ten higher than that on the blue shirt worn by the wide receiver.\n\r\n3. The running back, who supports the Jetstars, wore a higher number than that on his cousin's orange shirt.\n\r\n4. The Blue Sox supporter wore No. 23 and the linebacker wore No. 43.\n\r\n5. The man in green supports the Dolphins and wore a number lower than that of the offensive linesman.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe linebacker wore No. 43 (clue 4). The cousin in the No. 13 shirt wasn't the running back (clue 3) or offensive linesman (5), so the quarterback's shirt had No. 23 and the wide receiver's blue shirt had No. 13. The quarterback supports the Blue Sox (4). The running back supports the Jetstars (3). The man in green, who supports the Dolphins, isn't the offensive linesman (5), so the offensive linesman's shirt had No. 53. The running back thus wore No. 33, thus his shirt isn't white (1) or orange (3), so yellow. The quarterback's shirt was orange (3). The offensive linesman thus wore white. He doesn't support the Eagles (1), so the Harlequins. The wide receiver supports the Eagles.\n\r\nThus:\n\r\nLinebacker, No. 43, green, Dolphins;\r\nOffensive linesman, No. 53, white, Harlequins;\r\nQuarterback, No. 23, orange, Blue Sox;\r\nRunning back, No. 33, yellow, Jetstars;\r\nWide receiver, No. 13, blue, Eagles.\n<|im_start|>answer\nThe linebacker wore No. 43 (clue 4). The cousin in the No. 13 shirt wasn't the running back (clue 3) or offensive linesman (5), so the quarterback's shirt had No. 23 and the wide receiver's blue shirt had No. 13. The quarterback supports the Blue Sox (4). The running back supports the Jetstars (3). The man in green, who supports the Dolphins, isn't the offensive linesman (5), so the offensive linesman's shirt had No. 53. The running back thus wore No. 33, thus his shirt isn't white (1) or orange (3), so yellow. The quarterback's shirt was orange (3). The offensive linesman thus wore white. He doesn't support the Eagles (1), so the Harlequins. The wide receiver supports the Eagles.\n\r\nThus:\n\r\nLinebacker, No. 43, green, Dolphins;\r\nOffensive linesman, No. 53, white, Harlequins;\r\nQuarterback, No. 23, orange, Blue Sox;\r\nRunning back, No. 33, yellow, Jetstars;\r\nWide receiver, No. 13, blue, Eagles.\n<|im_end|>" }, { "id": "#49799", "title": "Twins 2", "fun": 2.71, "difficulty": 0.76, "author": "HABS2933", "desc": "Willy and Wally are twins. Willy will celebrate his fifth birthday tomorrow. Wally will have to wait until next year to turn five. What is today's date?", "hint": "(1) The boys are not what is referred to as \"Irish Twins\" they are identical twins conceived at the same time. \r\n(2) Willy was born 10 minutes before Wally", "answer": "Today is December 30th. Willy was born just before midnight on December 31st. Wally though only 10 minutes younger was born January 1st of the following year.", "category": "Logic", "date": "04/12/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWilly and Wally are twins. Willy will celebrate his fifth birthday tomorrow. Wally will have to wait until next year to turn five. What is today's date?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nToday is December 30th. Willy was born just before midnight on December 31st. Wally though only 10 minutes younger was born January 1st of the following year.\n<|im_start|>answer\nToday is December 30th. Willy was born just before midnight on December 31st. Wally though only 10 minutes younger was born January 1st of the following year.\n<|im_end|>" }, { "id": "#8925", "title": "Lazy Daughter", "fun": 2.71, "difficulty": 1.45, "author": "electronjohn", "desc": "A wealthy wise old woman feared that her daughter was lazy and, as a result, rather stupid. When the old woman died, her will stipulated that her assets were to be liquidated and a check was to be written for the full amount. The check was to be placed in one of three envelopes. The other two envelopes would contain a blank piece of paper. If the daughter could determine from the writing on the envelope which envelope contained the check, she would inherit her mother's fortune. Otherwise, the fortune would go to the old woman's favorite charity for animals. The daughter was not allowed to touch the envelopes. Her decision had to be made based on the writing on the envelopes. The daughter was told that only one envelope had a true statement and that the other two statements were false. \n\r\nThe envelopes had the following writing: \n\r\n1. This envelope does not have the check.\r\n2. This envelope has the check.\r\n3. The second envelope does not have the check.\n\r\nWhich envelope should the daughter pick?", "hint": "No hint available.", "answer": "The daughter should pick envelope 1. Statements 1 and 2 were false, and the only true statement was statement 3. \n\r\nIf the check was in envelope 1, that would make statement 1 false, statement 2 false and statement 3 is the only true statement.\n\r\nIf the check was in envelope 2, statements 1 and 2 would both be true. \n\r\nIf the check was in envelope 3, statements 1 and 3 would both be true.", "category": "Logic", "date": "12/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA wealthy wise old woman feared that her daughter was lazy and, as a result, rather stupid. When the old woman died, her will stipulated that her assets were to be liquidated and a check was to be written for the full amount. The check was to be placed in one of three envelopes. The other two envelopes would contain a blank piece of paper. If the daughter could determine from the writing on the envelope which envelope contained the check, she would inherit her mother's fortune. Otherwise, the fortune would go to the old woman's favorite charity for animals. The daughter was not allowed to touch the envelopes. Her decision had to be made based on the writing on the envelopes. The daughter was told that only one envelope had a true statement and that the other two statements were false. \n\r\nThe envelopes had the following writing: \n\r\n1. This envelope does not have the check.\r\n2. This envelope has the check.\r\n3. The second envelope does not have the check.\n\r\nWhich envelope should the daughter pick?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe daughter should pick envelope 1. Statements 1 and 2 were false, and the only true statement was statement 3. \n\r\nIf the check was in envelope 1, that would make statement 1 false, statement 2 false and statement 3 is the only true statement.\n\r\nIf the check was in envelope 2, statements 1 and 2 would both be true. \n\r\nIf the check was in envelope 3, statements 1 and 3 would both be true.\n<|im_start|>answer\nThe daughter should pick envelope 1. Statements 1 and 2 were false, and the only true statement was statement 3. \n\r\nIf the check was in envelope 1, that would make statement 1 false, statement 2 false and statement 3 is the only true statement.\n\r\nIf the check was in envelope 2, statements 1 and 2 would both be true. \n\r\nIf the check was in envelope 3, statements 1 and 3 would both be true.\n<|im_end|>" }, { "id": "#153", "title": "Apple Cider", "fun": 2.71, "difficulty": 1.76, "author": "Karin", "desc": "A customer arrives at an apple cider farm with a five gallon container and asks the farmer to put four gallons of his finest cider into it. Unfortunately, the only measure the farmer has is a three gallon jug. Can you think of a way that the farmer can measure out exactly four gallons of cider using just these two containers?", "hint": "No hint available.", "answer": "First, fill up the three gallon jug. Pour the three gallons into the five gallon container. Refill the three gallon jug and once again pour it into the five gallon container until it is full. The three gallon jug now contains one gallon. Empty the five gallon container back into the storage tank and then pour the one gallon of cider into it. Now, fill the three gallon jug up again and pour it into the customer`s five gallon container. The container will now contain the desired four gallons.", "category": "Math", "date": "01/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA customer arrives at an apple cider farm with a five gallon container and asks the farmer to put four gallons of his finest cider into it. Unfortunately, the only measure the farmer has is a three gallon jug. Can you think of a way that the farmer can measure out exactly four gallons of cider using just these two containers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, fill up the three gallon jug. Pour the three gallons into the five gallon container. Refill the three gallon jug and once again pour it into the five gallon container until it is full. The three gallon jug now contains one gallon. Empty the five gallon container back into the storage tank and then pour the one gallon of cider into it. Now, fill the three gallon jug up again and pour it into the customer`s five gallon container. The container will now contain the desired four gallons.\n<|im_start|>answer\nFirst, fill up the three gallon jug. Pour the three gallons into the five gallon container. Refill the three gallon jug and once again pour it into the five gallon container until it is full. The three gallon jug now contains one gallon. Empty the five gallon container back into the storage tank and then pour the one gallon of cider into it. Now, fill the three gallon jug up again and pour it into the customer`s five gallon container. The container will now contain the desired four gallons.\n<|im_end|>" }, { "id": "#30778", "title": "Magic Triangle", "fun": 2.71, "difficulty": 2.19, "author": "phrebh", "desc": "Arrange the digits 1 through 9 on a triangle so that there is one digit on each point and two digits on each side between the points. The total of the four digits on any given side must equal 17.", "hint": "Remember that the digits on the points will be included in the totals for both sides that meet at that point.", "answer": "There are two possible solutions.\n\r\nSide One: 1682\r\nSide Two: 2573\r\nSide Three: 3491\n\r\nSide One: 1952\r\nSide Two: 2483\r\nSide Three: 3761\n\r\nVariations of the order of the middle numbers are acceptable.", "category": "Logic", "date": "05/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the digits 1 through 9 on a triangle so that there is one digit on each point and two digits on each side between the points. The total of the four digits on any given side must equal 17.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are two possible solutions.\n\r\nSide One: 1682\r\nSide Two: 2573\r\nSide Three: 3491\n\r\nSide One: 1952\r\nSide Two: 2483\r\nSide Three: 3761\n\r\nVariations of the order of the middle numbers are acceptable.\n<|im_start|>answer\nThere are two possible solutions.\n\r\nSide One: 1682\r\nSide Two: 2573\r\nSide Three: 3491\n\r\nSide One: 1952\r\nSide Two: 2483\r\nSide Three: 3761\n\r\nVariations of the order of the middle numbers are acceptable.\n<|im_end|>" }, { "id": "#38799", "title": "Jockey Races", "fun": 2.71, "difficulty": 2.0, "author": "pokpic", "desc": "In the big race at the Speedy racetrack the top five finishers were Full Sweep, Nightshade, Quatermain, Top Horse, and Whirlaway. In alphabetical order, they were ridden by Alvarez, Hernandez, Perez, Pickman, and Wilson. From the information given, figure out the order of finish of the race and the name of the jockey who rode each of the five horses.\n\r\nHorses: Full Sweep, Nightshade, Quartermain, Top Horse, and Whirlaway\n\r\nJockeys: Alvarez, Hernandez, Perez, Pickman, and Wilson\n\r\nPlaces: first, second, third, fourth, and fifth\n\r\n1. Of Whirlaway and Quartermain, one finished first and one was ridden by Alvarez.\n\r\n2. Pickman finished ahead of Perez but after Whirlaway, who did not win first place.\n\r\n3. Full Sweep did not finish third.\n\r\n4. Top Horse finished ahead of Nightshade but after Wilson, who did not ride the winning horse.", "hint": "No hint available.", "answer": "Full Sweep placed second and was ridden by Wilson.\n\r\nNightshade placed fifth and was ridden by Perez.\n\r\nQuartermain placed first and was ridden by Hernandez.\n\r\nTop Horse placed fourth and was ridden by Pickman.\n\r\nWhirlaway placed third and was ridden by Alvarez.", "category": "Logic-Grid", "date": "10/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the big race at the Speedy racetrack the top five finishers were Full Sweep, Nightshade, Quatermain, Top Horse, and Whirlaway. In alphabetical order, they were ridden by Alvarez, Hernandez, Perez, Pickman, and Wilson. From the information given, figure out the order of finish of the race and the name of the jockey who rode each of the five horses.\n\r\nHorses: Full Sweep, Nightshade, Quartermain, Top Horse, and Whirlaway\n\r\nJockeys: Alvarez, Hernandez, Perez, Pickman, and Wilson\n\r\nPlaces: first, second, third, fourth, and fifth\n\r\n1. Of Whirlaway and Quartermain, one finished first and one was ridden by Alvarez.\n\r\n2. Pickman finished ahead of Perez but after Whirlaway, who did not win first place.\n\r\n3. Full Sweep did not finish third.\n\r\n4. Top Horse finished ahead of Nightshade but after Wilson, who did not ride the winning horse.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFull Sweep placed second and was ridden by Wilson.\n\r\nNightshade placed fifth and was ridden by Perez.\n\r\nQuartermain placed first and was ridden by Hernandez.\n\r\nTop Horse placed fourth and was ridden by Pickman.\n\r\nWhirlaway placed third and was ridden by Alvarez.\n<|im_start|>answer\nFull Sweep placed second and was ridden by Wilson.\n\r\nNightshade placed fifth and was ridden by Perez.\n\r\nQuartermain placed first and was ridden by Hernandez.\n\r\nTop Horse placed fourth and was ridden by Pickman.\n\r\nWhirlaway placed third and was ridden by Alvarez.\n<|im_end|>" }, { "id": "#2299", "title": "Camel Drivers", "fun": 2.71, "difficulty": 2.87, "author": "rayneeday", "desc": "Achmed and Ali were camel-drivers and on one day they decided to quit their job. They wanted to become shepherds. So they went to the market and sold all their camels. The amount of money (dinars) they received for each camel was the same as the total number of camels they owned. With that money they bought as many sheep as possible at 10 dinars a sheep. With the money that was left they bought a goat.\n\r\nOn their way home they got in a fight and decided to split up. When they divided the sheep there was one sheep left. So Ali said to Achmed, \"I take the last sheep and you can get the goat\". \"That's not fair,\" said Achmed, \"a goat costs less than a sheep\". \"OK,\" Ali said, \"then I will give you one of my dogs and then we are even\". And Achmed agreed. \n\r\nWhat's the cost of a dog?", "hint": "No hint available.", "answer": "1 sheep - 1 dog = 1 goat + 1 dog\r\n1 sheep - 1 goat = 2 dogs\r\nA sheep is 10 dinars, but what does a goat cost?\r\nThe money they received for their camels is a square. And the digit in the tens-place of this square is odd (total money / 10 dinars), because they could not divide the sheep equally.\r\nNow the interesting thing is that all squares with an odd tens-place end with a 6. (16^2 = 256, 24^2 = 576). So a goat must cost 6 dinars.\r\n10 - 6 = 2 dogs\r\nSo a dog costs 2 dinars.", "category": "Math", "date": "02/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAchmed and Ali were camel-drivers and on one day they decided to quit their job. They wanted to become shepherds. So they went to the market and sold all their camels. The amount of money (dinars) they received for each camel was the same as the total number of camels they owned. With that money they bought as many sheep as possible at 10 dinars a sheep. With the money that was left they bought a goat.\n\r\nOn their way home they got in a fight and decided to split up. When they divided the sheep there was one sheep left. So Ali said to Achmed, \"I take the last sheep and you can get the goat\". \"That's not fair,\" said Achmed, \"a goat costs less than a sheep\". \"OK,\" Ali said, \"then I will give you one of my dogs and then we are even\". And Achmed agreed. \n\r\nWhat's the cost of a dog?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 sheep - 1 dog = 1 goat + 1 dog\r\n1 sheep - 1 goat = 2 dogs\r\nA sheep is 10 dinars, but what does a goat cost?\r\nThe money they received for their camels is a square. And the digit in the tens-place of this square is odd (total money / 10 dinars), because they could not divide the sheep equally.\r\nNow the interesting thing is that all squares with an odd tens-place end with a 6. (16^2 = 256, 24^2 = 576). So a goat must cost 6 dinars.\r\n10 - 6 = 2 dogs\r\nSo a dog costs 2 dinars.\n<|im_start|>answer\n1 sheep - 1 dog = 1 goat + 1 dog\r\n1 sheep - 1 goat = 2 dogs\r\nA sheep is 10 dinars, but what does a goat cost?\r\nThe money they received for their camels is a square. And the digit in the tens-place of this square is odd (total money / 10 dinars), because they could not divide the sheep equally.\r\nNow the interesting thing is that all squares with an odd tens-place end with a 6. (16^2 = 256, 24^2 = 576). So a goat must cost 6 dinars.\r\n10 - 6 = 2 dogs\r\nSo a dog costs 2 dinars.\n<|im_end|>" }, { "id": "#4730", "title": "The Yosef Family", "fun": 2.71, "difficulty": 2.04, "author": "einat16", "desc": "In the Yosef family there are 11 children. 7 of them are girls named: Ilana, Tikva, Efrat, Ziva, Lilly, Zahava & Ronit. The rest are boys named: Ofer, Rami, Zalman & Ronny. You have to find out in which order they were born, according to the next 12 statements:\n\r\n1) The eldest and the youngest are girls.\r\n2) The second youngest starts with an R.\r\n3) The first starts with a Z.\r\n4) Ronny & Ronit were born one after the other, in that order.\r\n5) Ronit is not the youngest, not the 2nd youngest.\r\n6) The youngest child starts with a vowel.\r\n7) The 4th has an M in his/her name.\r\n8) Zalman & Lilly were born one after the other in that order.\r\n9) The 7th ends with a Y.\r\n10) Tikva, who was born 2nd, is older than Ziva.\r\n11) Ziva is older than Efrat, yet younger than Ilana.\r\n12) Both Ziva and Ilana are older than Ofer.", "hint": "The way to solve it is very similar to the way Einstein's Riddle is solved.", "answer": "The children were born in the following order:\n\r\nZahava, Tikva, Ilana, Zalman, Lilly, Ziva, Ronny, Ronit, Ofer, Rami & Efrat.\r\nMake a table containing numbers 1-11 and work by the way of elimination.", "category": "Logic", "date": "06/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the Yosef family there are 11 children. 7 of them are girls named: Ilana, Tikva, Efrat, Ziva, Lilly, Zahava & Ronit. The rest are boys named: Ofer, Rami, Zalman & Ronny. You have to find out in which order they were born, according to the next 12 statements:\n\r\n1) The eldest and the youngest are girls.\r\n2) The second youngest starts with an R.\r\n3) The first starts with a Z.\r\n4) Ronny & Ronit were born one after the other, in that order.\r\n5) Ronit is not the youngest, not the 2nd youngest.\r\n6) The youngest child starts with a vowel.\r\n7) The 4th has an M in his/her name.\r\n8) Zalman & Lilly were born one after the other in that order.\r\n9) The 7th ends with a Y.\r\n10) Tikva, who was born 2nd, is older than Ziva.\r\n11) Ziva is older than Efrat, yet younger than Ilana.\r\n12) Both Ziva and Ilana are older than Ofer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe children were born in the following order:\n\r\nZahava, Tikva, Ilana, Zalman, Lilly, Ziva, Ronny, Ronit, Ofer, Rami & Efrat.\r\nMake a table containing numbers 1-11 and work by the way of elimination.\n<|im_start|>answer\nThe children were born in the following order:\n\r\nZahava, Tikva, Ilana, Zalman, Lilly, Ziva, Ronny, Ronit, Ofer, Rami & Efrat.\r\nMake a table containing numbers 1-11 and work by the way of elimination.\n<|im_end|>" }, { "id": "#36613", "title": "Mime and Mime Again", "fun": 2.71, "difficulty": 2.15, "author": "camrae27", "desc": "I have always loved pantomime and whenever a show comes to town, I'm there! Over the past month, I have attended five different mime performances in five different theaters (one was the Palace). I also purchased a T-shirt, each of a different size, to give to my family. From the info provided, determine the theater, the mime group, as well as the size of shirt and for whom it was intended.\n\r\n1. I bought an extra-small T-shirt at the performance by Pin Drop (who didn't perform at the Strand Theater). The T-shirt I bought at the Century Theater is exactly one size smaller than the one I bought at the Mime Time show.\n\r\n2. The Eimac Theater is neither the theater where I saw Quiet Please nor the location where I bought a T-shirt for my niece.\n\r\n3. The medium T-shirt isn't the one I bought for my cousin (which I didn't get at the Strand Theater), it is the one I bought for my son. The shirt I bought at the Strand Theater is exactly one size smaller than the one I bought at the Quiet Please show.\n\r\n4. The large shirt (which I bought for my nephew) isn't the one I purchased at the Wind Walkers performance. The extra-large shirt isn't the one I bought at the Clancy Theater for my daughter.\n\r\n5. The T-shirt I bought at the Silent Knight performance is larger than the one I bought at the Eimac Theater (which is neither the shirt I purchased for my cousin nor the one I got for my son).", "hint": "My niece wears a small.", "answer": "Mime Time, Eimac, nephew, large\r\nPin Drop, Clancy, daughter, extra small\r\nQuiet Please, Century, son, medium\r\nWind Walkers, Strand, niece, small\r\nSilent Knight, Palace, cousin, extra large", "category": "Logic-Grid", "date": "05/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have always loved pantomime and whenever a show comes to town, I'm there! Over the past month, I have attended five different mime performances in five different theaters (one was the Palace). I also purchased a T-shirt, each of a different size, to give to my family. From the info provided, determine the theater, the mime group, as well as the size of shirt and for whom it was intended.\n\r\n1. I bought an extra-small T-shirt at the performance by Pin Drop (who didn't perform at the Strand Theater). The T-shirt I bought at the Century Theater is exactly one size smaller than the one I bought at the Mime Time show.\n\r\n2. The Eimac Theater is neither the theater where I saw Quiet Please nor the location where I bought a T-shirt for my niece.\n\r\n3. The medium T-shirt isn't the one I bought for my cousin (which I didn't get at the Strand Theater), it is the one I bought for my son. The shirt I bought at the Strand Theater is exactly one size smaller than the one I bought at the Quiet Please show.\n\r\n4. The large shirt (which I bought for my nephew) isn't the one I purchased at the Wind Walkers performance. The extra-large shirt isn't the one I bought at the Clancy Theater for my daughter.\n\r\n5. The T-shirt I bought at the Silent Knight performance is larger than the one I bought at the Eimac Theater (which is neither the shirt I purchased for my cousin nor the one I got for my son).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMime Time, Eimac, nephew, large\r\nPin Drop, Clancy, daughter, extra small\r\nQuiet Please, Century, son, medium\r\nWind Walkers, Strand, niece, small\r\nSilent Knight, Palace, cousin, extra large\n<|im_start|>answer\nMime Time, Eimac, nephew, large\r\nPin Drop, Clancy, daughter, extra small\r\nQuiet Please, Century, son, medium\r\nWind Walkers, Strand, niece, small\r\nSilent Knight, Palace, cousin, extra large\n<|im_end|>" }, { "id": "#35674", "title": "Eating, Laughing, Thinking, and Yawning", "fun": 2.71, "difficulty": 1.6400000000000001, "author": "NoQuestion", "desc": "Twice the number of people eating equals half of the people who are laughing; if twenty people are thinking, and all of the people thinking are also all of the people laughing... and a quarter of the people laughing are also yawning, then how many people are yawning? How many people are eating?", "hint": "It is a low level of math, nothing too hard. It just takes some thinking.", "answer": "E= eating\r\nL= laughing\r\nT= thinking\r\nY= yawning\n\r\nE= 0.25L\r\n20= T\r\n20= L\n\r\nE= 0.25 x 20\r\nE= 5\n\r\nY= 0.25 x 20\r\nY= 5\n\r\nThere are five people eating and five people yawning.", "category": "Math", "date": "03/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwice the number of people eating equals half of the people who are laughing; if twenty people are thinking, and all of the people thinking are also all of the people laughing... and a quarter of the people laughing are also yawning, then how many people are yawning? How many people are eating?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nE= eating\r\nL= laughing\r\nT= thinking\r\nY= yawning\n\r\nE= 0.25L\r\n20= T\r\n20= L\n\r\nE= 0.25 x 20\r\nE= 5\n\r\nY= 0.25 x 20\r\nY= 5\n\r\nThere are five people eating and five people yawning.\n<|im_start|>answer\nE= eating\r\nL= laughing\r\nT= thinking\r\nY= yawning\n\r\nE= 0.25L\r\n20= T\r\n20= L\n\r\nE= 0.25 x 20\r\nE= 5\n\r\nY= 0.25 x 20\r\nY= 5\n\r\nThere are five people eating and five people yawning.\n<|im_end|>" }, { "id": "#43784", "title": "College Age", "fun": 2.71, "difficulty": 2.08, "author": "whsprec", "desc": "Five college students - Sam, Sean, Seth, Sonny, and Shaw - are in the same dorm. Each is majoring in a different subject: anthropology, chemistry, biology, math or art. Each is taking a different language: French, Spanish, Italian, German, or Russian. And each is in a different class: freshman, sophomore, junior, senior, or graduate. From the clues given, determine the language, class, and major of each of the five students.\n\r\n1. The biology major, the graduate, the student taking Italian, and Shaw harass Sonny about being a freshman.\r\n2. Neither Sean nor Seth is the one who takes Spanish nor the one who is an art major, but one of them is a sophomore.\r\n3. Shaw and the junior had lunch with the math major and later met Sean after his German class.\r\n4. The sophomore, the math major, and Sean all have rooms on the top floor, whereas Sam and the art major have rooms on the ground floor.\r\n5. The anthropology major is taking German.\r\n6. The biology major is not the junior and does not take Russian.", "hint": "No hint available.", "answer": "Sam: Italian, junior, chemistry\r\nSean: German, graduate, anthropology\r\nSeth: French, sophomore, biology\r\nSonny: Spanish, freshman, math\r\nShaw: Russian, senior, art", "category": "Logic-Grid", "date": "12/24/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive college students - Sam, Sean, Seth, Sonny, and Shaw - are in the same dorm. Each is majoring in a different subject: anthropology, chemistry, biology, math or art. Each is taking a different language: French, Spanish, Italian, German, or Russian. And each is in a different class: freshman, sophomore, junior, senior, or graduate. From the clues given, determine the language, class, and major of each of the five students.\n\r\n1. The biology major, the graduate, the student taking Italian, and Shaw harass Sonny about being a freshman.\r\n2. Neither Sean nor Seth is the one who takes Spanish nor the one who is an art major, but one of them is a sophomore.\r\n3. Shaw and the junior had lunch with the math major and later met Sean after his German class.\r\n4. The sophomore, the math major, and Sean all have rooms on the top floor, whereas Sam and the art major have rooms on the ground floor.\r\n5. The anthropology major is taking German.\r\n6. The biology major is not the junior and does not take Russian.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSam: Italian, junior, chemistry\r\nSean: German, graduate, anthropology\r\nSeth: French, sophomore, biology\r\nSonny: Spanish, freshman, math\r\nShaw: Russian, senior, art\n<|im_start|>answer\nSam: Italian, junior, chemistry\r\nSean: German, graduate, anthropology\r\nSeth: French, sophomore, biology\r\nSonny: Spanish, freshman, math\r\nShaw: Russian, senior, art\n<|im_end|>" }, { "id": "#19862", "title": "Prime Ponderings", "fun": 2.71, "difficulty": 2.7, "author": "snaps", "desc": "What are the largest and smallest 5-digit numbers that satisfy the following conditions?\n\r\n1. Each digit of the number is a prime digit.\r\n2. Each successive pair of digits forms a 2-digit number that is NOT a prime number.\r\n3. Each of the prime digits must appear at least once in the 5-digit number.", "hint": "No hint available.", "answer": "Largest - 35772\r\nSmallest - 32257\n\r\nPrime digits are 2, 3, 5 and 7. Taken as pairs, the only combinations that fit criterion 2 are:\r\n22, 25, 27, 32, 33, 35, 52, 55, 57, 72, 75 and 77.\r\nOf that list, 33 is the only number that contains a 3 as the second digit and so for criterion 3 to be satisfied, 3 can only appear at the start of the 5-digit numbers. From there it is simply a matter of choosing the next digits using the list above so that criterion 2 is satisfied, making sure that criterion 3 is also satisfied.", "category": "Math", "date": "12/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat are the largest and smallest 5-digit numbers that satisfy the following conditions?\n\r\n1. Each digit of the number is a prime digit.\r\n2. Each successive pair of digits forms a 2-digit number that is NOT a prime number.\r\n3. Each of the prime digits must appear at least once in the 5-digit number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLargest - 35772\r\nSmallest - 32257\n\r\nPrime digits are 2, 3, 5 and 7. Taken as pairs, the only combinations that fit criterion 2 are:\r\n22, 25, 27, 32, 33, 35, 52, 55, 57, 72, 75 and 77.\r\nOf that list, 33 is the only number that contains a 3 as the second digit and so for criterion 3 to be satisfied, 3 can only appear at the start of the 5-digit numbers. From there it is simply a matter of choosing the next digits using the list above so that criterion 2 is satisfied, making sure that criterion 3 is also satisfied.\n<|im_start|>answer\nLargest - 35772\r\nSmallest - 32257\n\r\nPrime digits are 2, 3, 5 and 7. Taken as pairs, the only combinations that fit criterion 2 are:\r\n22, 25, 27, 32, 33, 35, 52, 55, 57, 72, 75 and 77.\r\nOf that list, 33 is the only number that contains a 3 as the second digit and so for criterion 3 to be satisfied, 3 can only appear at the start of the 5-digit numbers. From there it is simply a matter of choosing the next digits using the list above so that criterion 2 is satisfied, making sure that criterion 3 is also satisfied.\n<|im_end|>" }, { "id": "#37258", "title": "Where Should You Go?", "fun": 2.71, "difficulty": 2.27, "author": "MarcM1098", "desc": "In your last adventure, you left a broken-down supply truck in the middle of a desert, near the equator. You and a Desert Patrol Vehicle (DPV) have been airlifted to the disabled truck so you can repair it and bring it back to camp.\n\r\nBecause of recent attacks, the whole area is under a communications blackout. You must return to camp before sunset so that they can visually identify you. If you return after sunset, they will shoot first and ask questions later.\n\r\nThe repairs take longer than expected, and you realise that driving the truck, you cannot make it to your base camp in time. You will have to return to camp in the DPV (which can travel faster) and leave the truck for another day.\n\r\nYour camp is 500 miles to the south, but there are also two other camps in the area: one is 520 miles west, the other is 480 miles east.\n\r\nWhere should you go to reach a camp before sunset? The DPV can travel 80 mph, and you have plenty of fuel. It is now 12:50 PM and you know that at your base camp, the sun sets at 7:00 PM. One piece of trivia springs to mind: the circumference of earth is about 24900 miles at the equator.", "hint": "The sun doesn't set at the same time everywhere in a timezone. The earth is about 24900 miles around and there are 24 hours a day, so the time of sunset changes by 1 hour for every 1038 miles you travel east or west at the equator.", "answer": "You need to travel west.\n\r\nIt will take 6 hours and 15 minutes (500 miles / 80 mph) to reach the southern camp, so you would arrive at 7:05 PM which is just after sunset, too late!\n\r\nIt will take 6 hours (480/80) to reach the eastern camp, so you would arrive at 6:50 PM, but the sun will set earlier than at your current location. In fact, the sun will set about 28 minutes earlier (6:32 PM), so you would be way too late.\r\n(480 miles * 1 hr / 1038 miles = 0.46 hr = 28 min)\n\r\nIt will take 6 hours and 30 minutes (520/80) to reach the western camp, so you would arrive at 7:20 PM, but the sun will set later than at your current location. In fact, the sun will set about 30 minutes later (7:30 PM), so you arrive in time.\r\n(520 miles * 1 hr / 1038 miles = 0.50 hr = 30 min)", "category": "Math", "date": "07/07/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn your last adventure, you left a broken-down supply truck in the middle of a desert, near the equator. You and a Desert Patrol Vehicle (DPV) have been airlifted to the disabled truck so you can repair it and bring it back to camp.\n\r\nBecause of recent attacks, the whole area is under a communications blackout. You must return to camp before sunset so that they can visually identify you. If you return after sunset, they will shoot first and ask questions later.\n\r\nThe repairs take longer than expected, and you realise that driving the truck, you cannot make it to your base camp in time. You will have to return to camp in the DPV (which can travel faster) and leave the truck for another day.\n\r\nYour camp is 500 miles to the south, but there are also two other camps in the area: one is 520 miles west, the other is 480 miles east.\n\r\nWhere should you go to reach a camp before sunset? The DPV can travel 80 mph, and you have plenty of fuel. It is now 12:50 PM and you know that at your base camp, the sun sets at 7:00 PM. One piece of trivia springs to mind: the circumference of earth is about 24900 miles at the equator.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou need to travel west.\n\r\nIt will take 6 hours and 15 minutes (500 miles / 80 mph) to reach the southern camp, so you would arrive at 7:05 PM which is just after sunset, too late!\n\r\nIt will take 6 hours (480/80) to reach the eastern camp, so you would arrive at 6:50 PM, but the sun will set earlier than at your current location. In fact, the sun will set about 28 minutes earlier (6:32 PM), so you would be way too late.\r\n(480 miles * 1 hr / 1038 miles = 0.46 hr = 28 min)\n\r\nIt will take 6 hours and 30 minutes (520/80) to reach the western camp, so you would arrive at 7:20 PM, but the sun will set later than at your current location. In fact, the sun will set about 30 minutes later (7:30 PM), so you arrive in time.\r\n(520 miles * 1 hr / 1038 miles = 0.50 hr = 30 min)\n<|im_start|>answer\nYou need to travel west.\n\r\nIt will take 6 hours and 15 minutes (500 miles / 80 mph) to reach the southern camp, so you would arrive at 7:05 PM which is just after sunset, too late!\n\r\nIt will take 6 hours (480/80) to reach the eastern camp, so you would arrive at 6:50 PM, but the sun will set earlier than at your current location. In fact, the sun will set about 28 minutes earlier (6:32 PM), so you would be way too late.\r\n(480 miles * 1 hr / 1038 miles = 0.46 hr = 28 min)\n\r\nIt will take 6 hours and 30 minutes (520/80) to reach the western camp, so you would arrive at 7:20 PM, but the sun will set later than at your current location. In fact, the sun will set about 30 minutes later (7:30 PM), so you arrive in time.\r\n(520 miles * 1 hr / 1038 miles = 0.50 hr = 30 min)\n<|im_end|>" }, { "id": "#29188", "title": "How Many Children?", "fun": 2.71, "difficulty": 2.24, "author": "Draw", "desc": "At the local Sunday School meeting, the teacher brought in some puppies. There were 20 more children than puppies. In the corner of the room, within the ant's nest, there were exactly 10 times as many ants as children. In total, including the teacher, the children, the puppies and the ants, there were 1440 legs in the room. How many children attended?", "hint": "No hint available.", "answer": "23 children (46 legs): with 230 ants (1380 legs), 3 puppies (12 legs) and 1 teacher (2 legs). If we call the number of puppies P, then there were (P + 20) children and 10 x (P + 20) ants, and a single teacher. If we now count the legs, we get: \n\r\nPuppies : P x 4 = 4P\r\nChildren: (P + 20) x 2 = 2P + 40\r\nAnts : 10 x (P + 20) x 6 = 60P + 1200\r\nTeacher : 2 = 2\r\n -----------\r\n 66P + 1242 \n\r\nGiving 66P + 1242 = 1440, which means that P = 3, so there were 3 puppies, hence 23 children.", "category": "Math", "date": "03/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the local Sunday School meeting, the teacher brought in some puppies. There were 20 more children than puppies. In the corner of the room, within the ant's nest, there were exactly 10 times as many ants as children. In total, including the teacher, the children, the puppies and the ants, there were 1440 legs in the room. How many children attended?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n23 children (46 legs): with 230 ants (1380 legs), 3 puppies (12 legs) and 1 teacher (2 legs). If we call the number of puppies P, then there were (P + 20) children and 10 x (P + 20) ants, and a single teacher. If we now count the legs, we get: \n\r\nPuppies : P x 4 = 4P\r\nChildren: (P + 20) x 2 = 2P + 40\r\nAnts : 10 x (P + 20) x 6 = 60P + 1200\r\nTeacher : 2 = 2\r\n -----------\r\n 66P + 1242 \n\r\nGiving 66P + 1242 = 1440, which means that P = 3, so there were 3 puppies, hence 23 children.\n<|im_start|>answer\n23 children (46 legs): with 230 ants (1380 legs), 3 puppies (12 legs) and 1 teacher (2 legs). If we call the number of puppies P, then there were (P + 20) children and 10 x (P + 20) ants, and a single teacher. If we now count the legs, we get: \n\r\nPuppies : P x 4 = 4P\r\nChildren: (P + 20) x 2 = 2P + 40\r\nAnts : 10 x (P + 20) x 6 = 60P + 1200\r\nTeacher : 2 = 2\r\n -----------\r\n 66P + 1242 \n\r\nGiving 66P + 1242 = 1440, which means that P = 3, so there were 3 puppies, hence 23 children.\n<|im_end|>" }, { "id": "#33340", "title": "Reversible Exponents", "fun": 2.71, "difficulty": 1.71, "author": "lessthanjake789", "desc": "There is only one pair of numbers that satisfies the equation x^y = y^x, where x does not equal y. Can you figure out which two numbers?", "hint": "^ = to the power of. They are both single digits.", "answer": "2 and 4. 2^4 = 16, and 4^2 = 16.", "category": "Math", "date": "10/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is only one pair of numbers that satisfies the equation x^y = y^x, where x does not equal y. Can you figure out which two numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 and 4. 2^4 = 16, and 4^2 = 16.\n<|im_start|>answer\n2 and 4. 2^4 = 16, and 4^2 = 16.\n<|im_end|>" }, { "id": "#29353", "title": "What's the Correct Time?", "fun": 2.71, "difficulty": 2.24, "author": "Draw", "desc": "I recently gave a new watch to my friend for their birthday. However, as usual with my presents, it was quite useless, as it gains 6 minutes every hour. I set it using my own accurate clock at midnight, and the watch now shows 8:26 am. I know that it stopped 30 minutes ago, so what is the correct time now?", "hint": "No hint available.", "answer": "8:10 am.\n\r\nSince the watch is gaining 6 minutes every hour, for every real hour that has passed, the watch will show 66 minutes. Since the watch shows 8:26 am, we know that 506 watch minutes have passed. This therefore equals 460 real minutes and hence 7 hrs and 40 minutes. The watch stopped 30 minutes ago, therefore the time must now be 8:10 am.", "category": "Math", "date": "03/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI recently gave a new watch to my friend for their birthday. However, as usual with my presents, it was quite useless, as it gains 6 minutes every hour. I set it using my own accurate clock at midnight, and the watch now shows 8:26 am. I know that it stopped 30 minutes ago, so what is the correct time now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8:10 am.\n\r\nSince the watch is gaining 6 minutes every hour, for every real hour that has passed, the watch will show 66 minutes. Since the watch shows 8:26 am, we know that 506 watch minutes have passed. This therefore equals 460 real minutes and hence 7 hrs and 40 minutes. The watch stopped 30 minutes ago, therefore the time must now be 8:10 am.\n<|im_start|>answer\n8:10 am.\n\r\nSince the watch is gaining 6 minutes every hour, for every real hour that has passed, the watch will show 66 minutes. Since the watch shows 8:26 am, we know that 506 watch minutes have passed. This therefore equals 460 real minutes and hence 7 hrs and 40 minutes. The watch stopped 30 minutes ago, therefore the time must now be 8:10 am.\n<|im_end|>" }, { "id": "#27426", "title": "3-digit Numbers", "fun": 2.71, "difficulty": 2.55, "author": "shenqiang", "desc": "There are four 3-digit natural numbers, each of them equals the sum of the cubes of its digits.\n\r\nThree of them are:\n\r\n153=1+125+27\r\n370=27+343+0\r\n407=64+0+343\n\r\nDo you know what the fourth one is? It does not begin with 0, otherwise it isn't a 3-digit number.", "hint": "It's much easier than it seems to be.", "answer": "371.", "category": "Math", "date": "12/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four 3-digit natural numbers, each of them equals the sum of the cubes of its digits.\n\r\nThree of them are:\n\r\n153=1+125+27\r\n370=27+343+0\r\n407=64+0+343\n\r\nDo you know what the fourth one is? It does not begin with 0, otherwise it isn't a 3-digit number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n371.\n<|im_start|>answer\n371.\n<|im_end|>" }, { "id": "#50424", "title": "No New Digits", "fun": 2.71, "difficulty": 2.62, "author": "Ghostology", "desc": "What 6 digit number when multiplied by either 2, 3, 4, 5 or 6 has no new digits which appear?", "hint": "No hint available.", "answer": "142857.\r\n142857 * 2 = 287514\r\n142857 * 3 = 428571\r\n142857 * 4 = 571428\r\n142857 * 5 = 714285\r\n142857 * 6 = 857142", "category": "Math", "date": "09/01/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat 6 digit number when multiplied by either 2, 3, 4, 5 or 6 has no new digits which appear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n142857.\r\n142857 * 2 = 287514\r\n142857 * 3 = 428571\r\n142857 * 4 = 571428\r\n142857 * 5 = 714285\r\n142857 * 6 = 857142\n<|im_start|>answer\n142857.\r\n142857 * 2 = 287514\r\n142857 * 3 = 428571\r\n142857 * 4 = 571428\r\n142857 * 5 = 714285\r\n142857 * 6 = 857142\n<|im_end|>" }, { "id": "#1046", "title": "9 Dishes on the Menu", "fun": 2.71, "difficulty": 2.57, "author": "vivek", "desc": "A particular inn always offers the same nine dishes on its dinner menu: A, B, C, D, E, F, G, H and I. Five foreigners arrive. Nobody tells them which dish corresponds to each letter and so they each select one letter without knowing what they will eat. The innkeeper arrives with the five dishes ordered and puts them in the center of the table so that they can decide who eats what. This goes on for two more nights. The foreigners, who are professors of logic, were able to deduce by the dishes they ordered which letter represents what dish. What could have been the dishes ordered each of the three nights? Note: Each dish was ordered at least once.", "hint": "No hint available.", "answer": "They could have ordered ABCDD their first night (finding out what D is), AEFGG the second night (finding out what G is and what A is, since they had ordered it the previous night too), and BEHII the third night (finding out what I, B and E are). This leaves C, F and H out, and since they had never ordered these dishes twice, and each came out on a different night, they should know what they are.", "category": "Logic", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA particular inn always offers the same nine dishes on its dinner menu: A, B, C, D, E, F, G, H and I. Five foreigners arrive. Nobody tells them which dish corresponds to each letter and so they each select one letter without knowing what they will eat. The innkeeper arrives with the five dishes ordered and puts them in the center of the table so that they can decide who eats what. This goes on for two more nights. The foreigners, who are professors of logic, were able to deduce by the dishes they ordered which letter represents what dish. What could have been the dishes ordered each of the three nights? Note: Each dish was ordered at least once.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey could have ordered ABCDD their first night (finding out what D is), AEFGG the second night (finding out what G is and what A is, since they had ordered it the previous night too), and BEHII the third night (finding out what I, B and E are). This leaves C, F and H out, and since they had never ordered these dishes twice, and each came out on a different night, they should know what they are.\n<|im_start|>answer\nThey could have ordered ABCDD their first night (finding out what D is), AEFGG the second night (finding out what G is and what A is, since they had ordered it the previous night too), and BEHII the third night (finding out what I, B and E are). This leaves C, F and H out, and since they had never ordered these dishes twice, and each came out on a different night, they should know what they are.\n<|im_end|>" }, { "id": "#42504", "title": "The Birthday Party", "fun": 2.71, "difficulty": 1.0, "author": "j279", "desc": "Four friends have been invited to a birthday party. Using the clues below, can you determine which friend brought which present and in what color paper it was wrapped?\n\r\nFriends: Allison, Betty, Christine, Diana\r\nPresents: stationery, a CD, a book, a necklace\r\nColors of wrapping paper: red, yellow, green, blue\n\r\nClues:\n\r\n1. Betty doesn't like to read and therefore doesn't buy books. She knew that the birthday girl's favorite color was red, so she chose that color to wrap her gift.\n\r\n2. When the girl who bought the CD went to the store to buy wrapping paper, the only color they had was green.\n\r\n3. The people invited to the party were Christine, the girl who brought the present that was wrapped in yellow, the girl who bought the necklace, and the girl who used green paper.\n\r\n4. Diana knew that the birthday girl had family who lived out of town. She bought stationery so that her friend could keep in touch with them.", "hint": "No hint available.", "answer": "The present that Allison brought was the CD, and it was wrapped in green paper.\r\nBetty brought the necklace, which was wrapped in red paper.\r\nChristine's present was the book, which was wrapped in blue paper.\r\nDiana brought the stationery, and it was wrapped in yellow paper.", "category": "Logic-Grid", "date": "07/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends have been invited to a birthday party. Using the clues below, can you determine which friend brought which present and in what color paper it was wrapped?\n\r\nFriends: Allison, Betty, Christine, Diana\r\nPresents: stationery, a CD, a book, a necklace\r\nColors of wrapping paper: red, yellow, green, blue\n\r\nClues:\n\r\n1. Betty doesn't like to read and therefore doesn't buy books. She knew that the birthday girl's favorite color was red, so she chose that color to wrap her gift.\n\r\n2. When the girl who bought the CD went to the store to buy wrapping paper, the only color they had was green.\n\r\n3. The people invited to the party were Christine, the girl who brought the present that was wrapped in yellow, the girl who bought the necklace, and the girl who used green paper.\n\r\n4. Diana knew that the birthday girl had family who lived out of town. She bought stationery so that her friend could keep in touch with them.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe present that Allison brought was the CD, and it was wrapped in green paper.\r\nBetty brought the necklace, which was wrapped in red paper.\r\nChristine's present was the book, which was wrapped in blue paper.\r\nDiana brought the stationery, and it was wrapped in yellow paper.\n<|im_start|>answer\nThe present that Allison brought was the CD, and it was wrapped in green paper.\r\nBetty brought the necklace, which was wrapped in red paper.\r\nChristine's present was the book, which was wrapped in blue paper.\r\nDiana brought the stationery, and it was wrapped in yellow paper.\n<|im_end|>" }, { "id": "#17499", "title": "Color the Map", "fun": 2.71, "difficulty": 2.01, "author": "Jake", "desc": "What is the fewest number of colors you can use to color the states of the USA if no states of the same color can touch?", "hint": "No hint available.", "answer": "4 colors. \n\r\nIn fact 4 colors will suffice for any map, real or fabricated. Although, it took over 100 years for mathematicians to prove this fact.", "category": "Logic", "date": "04/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the fewest number of colors you can use to color the states of the USA if no states of the same color can touch?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 colors. \n\r\nIn fact 4 colors will suffice for any map, real or fabricated. Although, it took over 100 years for mathematicians to prove this fact.\n<|im_start|>answer\n4 colors. \n\r\nIn fact 4 colors will suffice for any map, real or fabricated. Although, it took over 100 years for mathematicians to prove this fact.\n<|im_end|>" }, { "id": "#34041", "title": "Little Johnny #3", "fun": 2.71, "difficulty": 2.68, "author": "fishmed", "desc": "Little Johnny was at it again.\n\r\nHis big brother had some small race cars that he wanted to play with, and his brother did not want him to have them. \n\r\nFinally, he made a deal with Little Johnny. If he could figure out the math problem that his teacher had given them that afternoon, he'd let him have the cars for a week.\n\r\nThe problem was to figure out the following.\n\r\nIT + TAKES + A + LITTLE = EFFORT\n\r\nThe numbers 0-9 are used and the teacher had already told them that A = 9 and E = 7. Little Johnny's brother could not figure it out, so he knew that he'd be safe.\n\r\nTen minutes later, Little Johnny's mother was watching while his big brother grudgingly gave up his cars for a week. \n\r\nCan you figure out what the letters represent, like Little Johnny?", "hint": "No hint available.", "answer": "I = 8\r\nT = 1\r\nA = 9\r\nK = 2\r\nE = 7\r\nS = 4\r\nL = 6\r\nF = 0\r\nR = 3\r\nO = 5\n\r\nSo, \n\r\n81 + 19274 + 9 + 681167 = 700531", "category": "Math", "date": "11/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittle Johnny was at it again.\n\r\nHis big brother had some small race cars that he wanted to play with, and his brother did not want him to have them. \n\r\nFinally, he made a deal with Little Johnny. If he could figure out the math problem that his teacher had given them that afternoon, he'd let him have the cars for a week.\n\r\nThe problem was to figure out the following.\n\r\nIT + TAKES + A + LITTLE = EFFORT\n\r\nThe numbers 0-9 are used and the teacher had already told them that A = 9 and E = 7. Little Johnny's brother could not figure it out, so he knew that he'd be safe.\n\r\nTen minutes later, Little Johnny's mother was watching while his big brother grudgingly gave up his cars for a week. \n\r\nCan you figure out what the letters represent, like Little Johnny?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI = 8\r\nT = 1\r\nA = 9\r\nK = 2\r\nE = 7\r\nS = 4\r\nL = 6\r\nF = 0\r\nR = 3\r\nO = 5\n\r\nSo, \n\r\n81 + 19274 + 9 + 681167 = 700531\n<|im_start|>answer\nI = 8\r\nT = 1\r\nA = 9\r\nK = 2\r\nE = 7\r\nS = 4\r\nL = 6\r\nF = 0\r\nR = 3\r\nO = 5\n\r\nSo, \n\r\n81 + 19274 + 9 + 681167 = 700531\n<|im_end|>" }, { "id": "#49405", "title": "Euchre Masquerade", "fun": 2.71, "difficulty": 1.53, "author": "Rhythmic", "desc": "Eight coworkers thought it would be fun to have a euchre tournament. As they were planning, Cameron came up with the idea to dress up in costumes. Samantha thought that was a good idea and suggested that everyone find a partner and dress in similar attire. For this tournament, the players stayed with the same partners for the duration.\n\r\n1) Jack's team and Cameron's team decided to dress up as people.\n\r\n2) The players dressed as presidents did not win, but they placed ahead of the ones dressed as birds.\n\r\n3) Hank got to dress up as broccoli, his favourite food.\n\r\n4) John dressed as Abraham Lincoln.\n\r\n5) Samantha was on the winning team. Cameron was not.\n\r\n6) Daniel's team placed ahead of John's team.", "hint": "Abraham Lincoln was a United States President.", "answer": "Jack and John teamed together and got third place as presidents.\r\nDaniel and Cameron teamed together and got second place as astronauts.\r\nSamantha and Hank teamed together and got first place as vegetables.\r\nGeorge and Elizabeth teamed together and got fourth place as birds.", "category": "Logic-Grid", "date": "03/27/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEight coworkers thought it would be fun to have a euchre tournament. As they were planning, Cameron came up with the idea to dress up in costumes. Samantha thought that was a good idea and suggested that everyone find a partner and dress in similar attire. For this tournament, the players stayed with the same partners for the duration.\n\r\n1) Jack's team and Cameron's team decided to dress up as people.\n\r\n2) The players dressed as presidents did not win, but they placed ahead of the ones dressed as birds.\n\r\n3) Hank got to dress up as broccoli, his favourite food.\n\r\n4) John dressed as Abraham Lincoln.\n\r\n5) Samantha was on the winning team. Cameron was not.\n\r\n6) Daniel's team placed ahead of John's team.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJack and John teamed together and got third place as presidents.\r\nDaniel and Cameron teamed together and got second place as astronauts.\r\nSamantha and Hank teamed together and got first place as vegetables.\r\nGeorge and Elizabeth teamed together and got fourth place as birds.\n<|im_start|>answer\nJack and John teamed together and got third place as presidents.\r\nDaniel and Cameron teamed together and got second place as astronauts.\r\nSamantha and Hank teamed together and got first place as vegetables.\r\nGeorge and Elizabeth teamed together and got fourth place as birds.\n<|im_end|>" }, { "id": "#47167", "title": "Web Hit Videos", "fun": 2.71, "difficulty": 1.75, "author": "whsprec", "desc": "Thanks to the internet, music groups no longer need a recording studio to be noticed. Over a 5 year period, 5 different groups submitted videos onto a music website. It turns out that all 5 videos were among the top 10 most viewed videos of the decade. From the clues below, determine the year the video was released, the group, the song name, and where it was on the top 10 list.\n\r\n1) The \"Mia Momma\" video was no. 3 on the list and was made earlier than Power-up's 2008 hit.\r\n2) \"Marioland\" was a dance craze the year before \"No Pass\" was released.\r\n3) Neither the 2005 video nor the one created by Eden's Gone began with the letter M, and both got higher on the lists than the video of \"Marioland\".\r\n4) No Fishing didn't get as high in the list as the group that made \"No Fruit\".\r\n5) Class Dismissed's movie made it to no. 8.\r\n6) The video in 2007 was no. 1, while the Wet Cement hit was \"Sunk\".", "hint": "No hint available.", "answer": "In 2005, Wet Cement made \"Sunk\", which was no. 5.\r\nIn 2006, No Fishing made \"Mia Momma\", which was no. 3.\r\nIn 2007, Eden's Gone made \"No Fruit\", which was no. 1.\r\nIn 2008, Power-up made \"Marioland\", which was no. 6.\r\nIn 2009, Class Dismissed made \"No Pass\", which was no. 8.", "category": "Logic-Grid", "date": "06/07/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThanks to the internet, music groups no longer need a recording studio to be noticed. Over a 5 year period, 5 different groups submitted videos onto a music website. It turns out that all 5 videos were among the top 10 most viewed videos of the decade. From the clues below, determine the year the video was released, the group, the song name, and where it was on the top 10 list.\n\r\n1) The \"Mia Momma\" video was no. 3 on the list and was made earlier than Power-up's 2008 hit.\r\n2) \"Marioland\" was a dance craze the year before \"No Pass\" was released.\r\n3) Neither the 2005 video nor the one created by Eden's Gone began with the letter M, and both got higher on the lists than the video of \"Marioland\".\r\n4) No Fishing didn't get as high in the list as the group that made \"No Fruit\".\r\n5) Class Dismissed's movie made it to no. 8.\r\n6) The video in 2007 was no. 1, while the Wet Cement hit was \"Sunk\".\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn 2005, Wet Cement made \"Sunk\", which was no. 5.\r\nIn 2006, No Fishing made \"Mia Momma\", which was no. 3.\r\nIn 2007, Eden's Gone made \"No Fruit\", which was no. 1.\r\nIn 2008, Power-up made \"Marioland\", which was no. 6.\r\nIn 2009, Class Dismissed made \"No Pass\", which was no. 8.\n<|im_start|>answer\nIn 2005, Wet Cement made \"Sunk\", which was no. 5.\r\nIn 2006, No Fishing made \"Mia Momma\", which was no. 3.\r\nIn 2007, Eden's Gone made \"No Fruit\", which was no. 1.\r\nIn 2008, Power-up made \"Marioland\", which was no. 6.\r\nIn 2009, Class Dismissed made \"No Pass\", which was no. 8.\n<|im_end|>" }, { "id": "#29492", "title": "A Bird's Eye View", "fun": 2.71, "difficulty": 2.56, "author": "paul726", "desc": "Jack sat in his father's office, atop a bookcase by the wide, floor-to-ceiling window. His father's employer had built this skyscraper right on the shoreline of the lake, directly across which stood the tallest tree in the state. Jack's view was spectacular, and, as he looked across the 866 ft. wide lake, he noticed something which he found interesting. When he gazed at the highest point on the tree, his line of sight was at a 30 degree incline above horizontal. When looking at the base of the tree, where it met the water at the far edge of the lake, he was looking at a 30 degree declination.\n\r\nHow tall is the tree?\n\r\nBonus: Later, after querying his father, he found out that the first floor of the office building was at ground level, and every subsequent floor was exactly 12 ft. above the one below. What floor is his father's office on?", "hint": "Draw a triangle from Jack's eyes, to both the base and the peak of the tree. Make a second triangle from the tree base to the bottom of the building, then up to Jack again.", "answer": "The tree is 1000 ft. tall.\n\r\nStart by picturing a triangle formed by Jack's line of sight to the base of the tree, the lake's surface, and the building. Since the tree and building are at the lake's edge, they're level with each other and the triangle is a right triangle. The angle at the base of the tree is 30 degrees. Using trigonometric functions, we can find the unknown lengths of the triangle. The line of sight is the hypotenuse of the triangle. The height of the building where Jack sits is the side opposite the 30 degree angle. The length across the lake, 866 ft., is the adjacent side.\n\r\nCosine = adjacent/hypotenuse\r\nTangent = opposite/adjacent\n\r\nThus:\n\r\nCos(30)= 0.8660 = 866/hypotenuse Jack's line of sight is 1000 ft.\r\nTan(30)= 0.5774 = opposite/866 -> Jack's height is 500 ft.\n\n\r\nNow, we turn our attention to the triangle formed by the tree and both of Jack's lines of sight. We can see that it's an equilateral triangle, consisting of three 60 degree angles, and therefore all sides are equal. Thus the tree is 1000 ft. high.\n\n\r\nBonus: Jack's height was 500 ft. The largest whole multiples of twelve to divide evenly into that is 492(41x12), placing the office on the 42nd floor (41 above the first floor). Jack's perch atop the bookcase put his eyes eight feet above the floor, rounding out 500 ft.", "category": "Math", "date": "04/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack sat in his father's office, atop a bookcase by the wide, floor-to-ceiling window. His father's employer had built this skyscraper right on the shoreline of the lake, directly across which stood the tallest tree in the state. Jack's view was spectacular, and, as he looked across the 866 ft. wide lake, he noticed something which he found interesting. When he gazed at the highest point on the tree, his line of sight was at a 30 degree incline above horizontal. When looking at the base of the tree, where it met the water at the far edge of the lake, he was looking at a 30 degree declination.\n\r\nHow tall is the tree?\n\r\nBonus: Later, after querying his father, he found out that the first floor of the office building was at ground level, and every subsequent floor was exactly 12 ft. above the one below. What floor is his father's office on?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe tree is 1000 ft. tall.\n\r\nStart by picturing a triangle formed by Jack's line of sight to the base of the tree, the lake's surface, and the building. Since the tree and building are at the lake's edge, they're level with each other and the triangle is a right triangle. The angle at the base of the tree is 30 degrees. Using trigonometric functions, we can find the unknown lengths of the triangle. The line of sight is the hypotenuse of the triangle. The height of the building where Jack sits is the side opposite the 30 degree angle. The length across the lake, 866 ft., is the adjacent side.\n\r\nCosine = adjacent/hypotenuse\r\nTangent = opposite/adjacent\n\r\nThus:\n\r\nCos(30)= 0.8660 = 866/hypotenuse Jack's line of sight is 1000 ft.\r\nTan(30)= 0.5774 = opposite/866 -> Jack's height is 500 ft.\n\n\r\nNow, we turn our attention to the triangle formed by the tree and both of Jack's lines of sight. We can see that it's an equilateral triangle, consisting of three 60 degree angles, and therefore all sides are equal. Thus the tree is 1000 ft. high.\n\n\r\nBonus: Jack's height was 500 ft. The largest whole multiples of twelve to divide evenly into that is 492(41x12), placing the office on the 42nd floor (41 above the first floor). Jack's perch atop the bookcase put his eyes eight feet above the floor, rounding out 500 ft.\n<|im_start|>answer\nThe tree is 1000 ft. tall.\n\r\nStart by picturing a triangle formed by Jack's line of sight to the base of the tree, the lake's surface, and the building. Since the tree and building are at the lake's edge, they're level with each other and the triangle is a right triangle. The angle at the base of the tree is 30 degrees. Using trigonometric functions, we can find the unknown lengths of the triangle. The line of sight is the hypotenuse of the triangle. The height of the building where Jack sits is the side opposite the 30 degree angle. The length across the lake, 866 ft., is the adjacent side.\n\r\nCosine = adjacent/hypotenuse\r\nTangent = opposite/adjacent\n\r\nThus:\n\r\nCos(30)= 0.8660 = 866/hypotenuse Jack's line of sight is 1000 ft.\r\nTan(30)= 0.5774 = opposite/866 -> Jack's height is 500 ft.\n\n\r\nNow, we turn our attention to the triangle formed by the tree and both of Jack's lines of sight. We can see that it's an equilateral triangle, consisting of three 60 degree angles, and therefore all sides are equal. Thus the tree is 1000 ft. high.\n\n\r\nBonus: Jack's height was 500 ft. The largest whole multiples of twelve to divide evenly into that is 492(41x12), placing the office on the 42nd floor (41 above the first floor). Jack's perch atop the bookcase put his eyes eight feet above the floor, rounding out 500 ft.\n<|im_end|>" }, { "id": "#30580", "title": "Three Statements VIII", "fun": 2.71, "difficulty": 1.35, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. If you turn a right-handed glove inside out, it will fit on a left hand.\n\r\n2. An arrow pointing to the left will point to the right when rotated 180 degrees about a vertical axis through its center.\n\r\n3. There are 5 employees - A, B, C, D and E - in the office. Rumors spread through the office according to the following rules: Rumors can be passed in any direction between D and E. Rumors can be passed from A to B, from B to C, and from C to E. A rumor began by B that reaches D would be known by everybody.", "hint": "No hint available.", "answer": "Statements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, a right-handed glove and a left-handed one are mutual mirror images, and if one of them is turned inside out, it will look like the other.\n\r\nIn statement 2, a right-pointing arrow and a left-pointing one are mutual mirror images, and if one of them is rotated 180 degrees, it will look like the other.\n\r\nIn statement 3, a rumor from B can reach C, then reach E, then reach D, but not reach A.", "category": "Logic", "date": "05/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. If you turn a right-handed glove inside out, it will fit on a left hand.\n\r\n2. An arrow pointing to the left will point to the right when rotated 180 degrees about a vertical axis through its center.\n\r\n3. There are 5 employees - A, B, C, D and E - in the office. Rumors spread through the office according to the following rules: Rumors can be passed in any direction between D and E. Rumors can be passed from A to B, from B to C, and from C to E. A rumor began by B that reaches D would be known by everybody.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, a right-handed glove and a left-handed one are mutual mirror images, and if one of them is turned inside out, it will look like the other.\n\r\nIn statement 2, a right-pointing arrow and a left-pointing one are mutual mirror images, and if one of them is rotated 180 degrees, it will look like the other.\n\r\nIn statement 3, a rumor from B can reach C, then reach E, then reach D, but not reach A.\n<|im_start|>answer\nStatements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, a right-handed glove and a left-handed one are mutual mirror images, and if one of them is turned inside out, it will look like the other.\n\r\nIn statement 2, a right-pointing arrow and a left-pointing one are mutual mirror images, and if one of them is rotated 180 degrees, it will look like the other.\n\r\nIn statement 3, a rumor from B can reach C, then reach E, then reach D, but not reach A.\n<|im_end|>" }, { "id": "#26104", "title": "Guess My Age", "fun": 2.71, "difficulty": 1.13, "author": "markmonnin", "desc": "I've had a very peculiar life. For the first quarter of my life, I played no sports at all. After that, I only played one sport at a time. \n\r\nAfter the first quarter, I played only baseball for ten years. I got tired of that so I switched to only playing tennis for nine years. Next, for the past eight years, I've only been running. How old am I?", "hint": "Add up the years after the first quarter to find the last 3 quarters.", "answer": "I am 36 years old.\n\r\n10+9+8=27\r\n27/(3/4)=36", "category": "Math", "date": "09/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI've had a very peculiar life. For the first quarter of my life, I played no sports at all. After that, I only played one sport at a time. \n\r\nAfter the first quarter, I played only baseball for ten years. I got tired of that so I switched to only playing tennis for nine years. Next, for the past eight years, I've only been running. How old am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI am 36 years old.\n\r\n10+9+8=27\r\n27/(3/4)=36\n<|im_start|>answer\nI am 36 years old.\n\r\n10+9+8=27\r\n27/(3/4)=36\n<|im_end|>" }, { "id": "#8809", "title": "Men and Monkeys", "fun": 2.71, "difficulty": 2.22, "author": "lesternoronha1", "desc": "On one side of a river are three humans, one big monkey, two small monkeys, and one boat. Each of the humans and the big monkey are strong enough to row the boat. The boat can fit one or two bodies (regardless of size). If at any time at either side of the river the monkeys outnumber the humans, the monkeys will eat the humans. How do you get everyone on the other side of the river alive?", "hint": "No hint available.", "answer": "Let:\r\nh=human\r\nb=big monkey\r\ns=small monkey \r\n1. Row b and s over ( hhhs / bs )\r\n2. Row b back ( hhhbs / s )\r\n3. Row b and s over ( hhh / bss )\r\n4. Row b back ( hhhb / ss )\r\n5. Row h and h over ( hb / hhss )\r\n6. Row h and s back ( hhbs / hs )\r\n7. Row h and b over ( hs / hhbs ) \r\n8. Row h and s back ( hhss / hb ) \r\n9. Row h and h over ( ss / hhhb )\r\n10. Row b back ( bss / hhh )\r\n11. Row b and s over ( s / hhhbs ) \r\n12. Row b back ( bs / hhhs )\r\n13. Row b and s over ( / hhhbss )", "category": "Logic", "date": "11/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn one side of a river are three humans, one big monkey, two small monkeys, and one boat. Each of the humans and the big monkey are strong enough to row the boat. The boat can fit one or two bodies (regardless of size). If at any time at either side of the river the monkeys outnumber the humans, the monkeys will eat the humans. How do you get everyone on the other side of the river alive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet:\r\nh=human\r\nb=big monkey\r\ns=small monkey \r\n1. Row b and s over ( hhhs / bs )\r\n2. Row b back ( hhhbs / s )\r\n3. Row b and s over ( hhh / bss )\r\n4. Row b back ( hhhb / ss )\r\n5. Row h and h over ( hb / hhss )\r\n6. Row h and s back ( hhbs / hs )\r\n7. Row h and b over ( hs / hhbs ) \r\n8. Row h and s back ( hhss / hb ) \r\n9. Row h and h over ( ss / hhhb )\r\n10. Row b back ( bss / hhh )\r\n11. Row b and s over ( s / hhhbs ) \r\n12. Row b back ( bs / hhhs )\r\n13. Row b and s over ( / hhhbss )\n<|im_start|>answer\nLet:\r\nh=human\r\nb=big monkey\r\ns=small monkey \r\n1. Row b and s over ( hhhs / bs )\r\n2. Row b back ( hhhbs / s )\r\n3. Row b and s over ( hhh / bss )\r\n4. Row b back ( hhhb / ss )\r\n5. Row h and h over ( hb / hhss )\r\n6. Row h and s back ( hhbs / hs )\r\n7. Row h and b over ( hs / hhbs ) \r\n8. Row h and s back ( hhss / hb ) \r\n9. Row h and h over ( ss / hhhb )\r\n10. Row b back ( bss / hhh )\r\n11. Row b and s over ( s / hhhbs ) \r\n12. Row b back ( bs / hhhs )\r\n13. Row b and s over ( / hhhbss )\n<|im_end|>" }, { "id": "#3362", "title": "So Thirsty", "fun": 2.71, "difficulty": 1.51, "author": "Drunky", "desc": "A man goes out drinking every night, returning to his home in the wee hours of every morning. No matter how much he drinks, he never gets a hangover. This drink is very well known, but is rarely consumed, served warm and taken straight from its source. The man is a sucker for a free drink, especially since he can't live without it.\r\nWhat is his favorite drink?", "hint": "Creepy dude you see in movies", "answer": "Blood. He's a vampire", "category": "Logic", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man goes out drinking every night, returning to his home in the wee hours of every morning. No matter how much he drinks, he never gets a hangover. This drink is very well known, but is rarely consumed, served warm and taken straight from its source. The man is a sucker for a free drink, especially since he can't live without it.\r\nWhat is his favorite drink?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlood. He's a vampire\n<|im_start|>answer\nBlood. He's a vampire\n<|im_end|>" }, { "id": "#1439", "title": "Walking Time", "fun": 2.71, "difficulty": 2.14, "author": "Maneesh", "desc": "A man leaves his office daily at 5pm, gets on a local train to his town, and arrives at the station at 6pm. His wife reaches there at exactly 6pm in a car, to pick him up. This is a daily routine.\r\nOn a certain day he left the office at 4pm and forgot to inform his wife. He reached the station of his town at 5pm and started to walk towards his home. He met his wife on the way as she was coming to pick him up at the usual time. They drove back to home. That day they reached home 20 minutes earlier than their usual time.\r\nFor how long, in minutes, did he walk?", "hint": "No hint available.", "answer": "50 Minutes", "category": "Math", "date": "11/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man leaves his office daily at 5pm, gets on a local train to his town, and arrives at the station at 6pm. His wife reaches there at exactly 6pm in a car, to pick him up. This is a daily routine.\r\nOn a certain day he left the office at 4pm and forgot to inform his wife. He reached the station of his town at 5pm and started to walk towards his home. He met his wife on the way as she was coming to pick him up at the usual time. They drove back to home. That day they reached home 20 minutes earlier than their usual time.\r\nFor how long, in minutes, did he walk?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n50 Minutes\n<|im_start|>answer\n50 Minutes\n<|im_end|>" }, { "id": "#22846", "title": "I'm Going on a Picnic...", "fun": 2.71, "difficulty": 2.19, "author": "pawprints62391", "desc": "There were three friends- Jade, Alicia, and Damien, and they were playing a game called \"I'm Going on a Picnic.\" The object of the game is to figure out the pattern of the objects listed.\n\r\n(Jade starts, then Alicia and Damien-Assume that they could all go to the picnic.)\n\r\nJade: I'm going on a picnic. and I'm going to bring Ants.\r\nAlicia: I'm going to bring Dogs.\r\nDamien: I'm bringing some Juice.\r\nJade: Lemons.\r\nAlicia: An Almanac.\r\nDamien: Art.\r\nJade: Iguanas.\r\nAlicia: Money.\r\nDamien: Dirt.\r\nJade: Cats.\r\nAlicia: Igloos.\r\nDamien: Elephants...\n\r\nWhat is the pattern?", "hint": "Look at the first letters of what Damien says, then look at the first letter of what Jade and Alicia say. Think about it, but not too hard!", "answer": "They were spelling out the name of the person who would go after them.\n\r\n(Damien said Juice, Art, Dirt, and Elephants-JADE) :)", "category": "Logic", "date": "05/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were three friends- Jade, Alicia, and Damien, and they were playing a game called \"I'm Going on a Picnic.\" The object of the game is to figure out the pattern of the objects listed.\n\r\n(Jade starts, then Alicia and Damien-Assume that they could all go to the picnic.)\n\r\nJade: I'm going on a picnic. and I'm going to bring Ants.\r\nAlicia: I'm going to bring Dogs.\r\nDamien: I'm bringing some Juice.\r\nJade: Lemons.\r\nAlicia: An Almanac.\r\nDamien: Art.\r\nJade: Iguanas.\r\nAlicia: Money.\r\nDamien: Dirt.\r\nJade: Cats.\r\nAlicia: Igloos.\r\nDamien: Elephants...\n\r\nWhat is the pattern?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey were spelling out the name of the person who would go after them.\n\r\n(Damien said Juice, Art, Dirt, and Elephants-JADE) :)\n<|im_start|>answer\nThey were spelling out the name of the person who would go after them.\n\r\n(Damien said Juice, Art, Dirt, and Elephants-JADE) :)\n<|im_end|>" }, { "id": "#33347", "title": "Potion Problems", "fun": 2.7, "difficulty": 1.34, "author": "grungy49", "desc": "Alex the Wizard was a great and powerful magician in the town of Magikville.\n\r\nHe lived peacefully except for one problem - Barry the Sorcerer, his archenemy. \n\r\nHe decided one day that he had to kill Barry with his most powerful spell, for Barry had killed his friend. \n\r\nThere was one problem though, this spell required potions to be mixed in a certain order, and Alex had forgotten the order!\n\r\nHe could only remember a few things about the order, and if he messed up the order Alex would be killed.\n\r\nCan you determine the order of the five potions (Green, Blue, Red, Yellow, and Death) by using the clues?\n\r\n1. The death potion was not first.\r\n2. The red potion was before the yellow potion.\r\n3. The green potion was not before the death potion but it was before the yellow potion.\r\n4. The blue potion was second to be mixed in.", "hint": "It helps to make a table.", "answer": "Red potion - 1st\r\nBlue potion - 2nd\r\nDeath potion - 3rd\r\nGreen potion - 4th\r\nYellow potion - 5th", "category": "Logic", "date": "10/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlex the Wizard was a great and powerful magician in the town of Magikville.\n\r\nHe lived peacefully except for one problem - Barry the Sorcerer, his archenemy. \n\r\nHe decided one day that he had to kill Barry with his most powerful spell, for Barry had killed his friend. \n\r\nThere was one problem though, this spell required potions to be mixed in a certain order, and Alex had forgotten the order!\n\r\nHe could only remember a few things about the order, and if he messed up the order Alex would be killed.\n\r\nCan you determine the order of the five potions (Green, Blue, Red, Yellow, and Death) by using the clues?\n\r\n1. The death potion was not first.\r\n2. The red potion was before the yellow potion.\r\n3. The green potion was not before the death potion but it was before the yellow potion.\r\n4. The blue potion was second to be mixed in.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRed potion - 1st\r\nBlue potion - 2nd\r\nDeath potion - 3rd\r\nGreen potion - 4th\r\nYellow potion - 5th\n<|im_start|>answer\nRed potion - 1st\r\nBlue potion - 2nd\r\nDeath potion - 3rd\r\nGreen potion - 4th\r\nYellow potion - 5th\n<|im_end|>" }, { "id": "#30344", "title": "Three Statements V", "fun": 2.7, "difficulty": 1.37, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. Out of the following, E is least like the other letters: A Z F N E.\n\r\n2. EVIAN is to NAIVE as 42312 is to 21324.\n\r\n3. Lisa was both the 16th highest and 16th lowest in her mid term exam. Therefore her class had 32 students.", "hint": "No hint available.", "answer": "Statements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, the letters A Z F N all contain 3 straight lines, but the letter E contains 4.\n\r\nIn statement 2, they are just letters or numbers in reverse order.\n\r\nIn statement 3, Lisa can be counted only once, not twice, therefore her class had 31 students.", "category": "Logic", "date": "05/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. Out of the following, E is least like the other letters: A Z F N E.\n\r\n2. EVIAN is to NAIVE as 42312 is to 21324.\n\r\n3. Lisa was both the 16th highest and 16th lowest in her mid term exam. Therefore her class had 32 students.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, the letters A Z F N all contain 3 straight lines, but the letter E contains 4.\n\r\nIn statement 2, they are just letters or numbers in reverse order.\n\r\nIn statement 3, Lisa can be counted only once, not twice, therefore her class had 31 students.\n<|im_start|>answer\nStatements 1 and 2 are true, statement 3 is false.\n\r\nIn statement 1, the letters A Z F N all contain 3 straight lines, but the letter E contains 4.\n\r\nIn statement 2, they are just letters or numbers in reverse order.\n\r\nIn statement 3, Lisa can be counted only once, not twice, therefore her class had 31 students.\n<|im_end|>" }, { "id": "#30519", "title": "No-Fat Frankfurters, Partition Deux", "fun": 2.7, "difficulty": 2.82, "author": "norcekri", "desc": "Kurt & Rod were hanging around the window at school munching the last of their Rnkfurers hoard. They spotted their neighbor lounging in the enclosed courtyard, looking hungry.\r\n\t\"Patty O'Furniture! Good to see you! Want a Rnkfurter?\"\r\n\t\"A what?\"\r\n\tKurt handed her the last he had. She bit in, and her face lit up like a newly-coined metaphor.\r\n\t\"Where can I get more of these?\"\r\n\t\"Rod and I were about to go order some more. But there's a catch: we always order so one of us gets the quantity that the other has for a percentage.\" Patty's blank look bade him explain. \"In our first batch, we got a total of 25 -- 20 for me, and 5 for Rod. I had 20, and he had 20% of the total.\"\r\n\t\"And you think you can do that for three people? You get my percentage, and I get Rod's? I don't think we can do it.\"\r\n\tRod had been thinking about it, and rattled off three numbers to her.\r\n\t\"Those aren't right. The last one isn't the right percentage; there's an added fraction.\"\r\n\t\"So? My mom says they're the same on her old phonograph speeds.\"\r\n\tPatty looked at Kurt, each waiting for the other to give an opinion. Finally, she gestured at the empty wrapper in his hand.\r\n\t\"I'll round off a little for a week's supply of these. Let's go!\"\n\r\n\tSince Rnkfurters come in cases of 25, 50, and 100, they had to leave 10 with the storekeeper to make the numbers work, but they got their munchies.\n\r\n\tHow many did each student get this time?", "hint": "The old phonograph speeds were typically 16, 33-1/3, 45, and 78 RPM.", "answer": "27 for Kurt, 30 for Patty, and 33 for Rod.\r\n\tThat's 30% for Kurt and 33-1/3% for Patty.\n\r\nMethod:\n\r\n\tLet K, P, and R stand for the quantity each of them had. Let T be the total, K+P+R.\r\n \tNow, since Kurt's percentage equals Patty's quantity, we get\r\n100*K/T = P.\r\n\tSimilarly,\r\n100*P/T = R plus a fraction. Now, look at the common factor, 100/T. Let's call this F, the factor relating one quantity to the next.\r\nK*F = P and P*F = R (plus a fraction),\r\nand K*F^2 = R (plus a fraction).\r\nThe clue about the phonograph leaves us looking for a triple with 33 Rnkfurters for Rod, with Patty getting 33-1/3% (one-third) of the total. \r\nP = T/3\r\nP = (K+P+33)/3 -- remember, R=33\r\nNow, combine this with 100*K/T = P, and a bit of algebra gives us the required answer.\r\n-------------\r\nAlternately, there are 11 triples that fit the factor requirement (courtesy of a short computer program), ranging from (19, 25, 32) to (2376, 96, 3). The ones that total 10 less than a multiple of 25 are\r\n27, 30, 33\r\n63, 45, 32\r\n891, 90, 9\n\r\nGiven the phonograph clue, I expect you can recognize that the first triple above is the answer.", "category": "Math", "date": "05/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKurt & Rod were hanging around the window at school munching the last of their Rnkfurers hoard. They spotted their neighbor lounging in the enclosed courtyard, looking hungry.\r\n\t\"Patty O'Furniture! Good to see you! Want a Rnkfurter?\"\r\n\t\"A what?\"\r\n\tKurt handed her the last he had. She bit in, and her face lit up like a newly-coined metaphor.\r\n\t\"Where can I get more of these?\"\r\n\t\"Rod and I were about to go order some more. But there's a catch: we always order so one of us gets the quantity that the other has for a percentage.\" Patty's blank look bade him explain. \"In our first batch, we got a total of 25 -- 20 for me, and 5 for Rod. I had 20, and he had 20% of the total.\"\r\n\t\"And you think you can do that for three people? You get my percentage, and I get Rod's? I don't think we can do it.\"\r\n\tRod had been thinking about it, and rattled off three numbers to her.\r\n\t\"Those aren't right. The last one isn't the right percentage; there's an added fraction.\"\r\n\t\"So? My mom says they're the same on her old phonograph speeds.\"\r\n\tPatty looked at Kurt, each waiting for the other to give an opinion. Finally, she gestured at the empty wrapper in his hand.\r\n\t\"I'll round off a little for a week's supply of these. Let's go!\"\n\r\n\tSince Rnkfurters come in cases of 25, 50, and 100, they had to leave 10 with the storekeeper to make the numbers work, but they got their munchies.\n\r\n\tHow many did each student get this time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n27 for Kurt, 30 for Patty, and 33 for Rod.\r\n\tThat's 30% for Kurt and 33-1/3% for Patty.\n\r\nMethod:\n\r\n\tLet K, P, and R stand for the quantity each of them had. Let T be the total, K+P+R.\r\n \tNow, since Kurt's percentage equals Patty's quantity, we get\r\n100*K/T = P.\r\n\tSimilarly,\r\n100*P/T = R plus a fraction. Now, look at the common factor, 100/T. Let's call this F, the factor relating one quantity to the next.\r\nK*F = P and P*F = R (plus a fraction),\r\nand K*F^2 = R (plus a fraction).\r\nThe clue about the phonograph leaves us looking for a triple with 33 Rnkfurters for Rod, with Patty getting 33-1/3% (one-third) of the total. \r\nP = T/3\r\nP = (K+P+33)/3 -- remember, R=33\r\nNow, combine this with 100*K/T = P, and a bit of algebra gives us the required answer.\r\n-------------\r\nAlternately, there are 11 triples that fit the factor requirement (courtesy of a short computer program), ranging from (19, 25, 32) to (2376, 96, 3). The ones that total 10 less than a multiple of 25 are\r\n27, 30, 33\r\n63, 45, 32\r\n891, 90, 9\n\r\nGiven the phonograph clue, I expect you can recognize that the first triple above is the answer.\n<|im_start|>answer\n27 for Kurt, 30 for Patty, and 33 for Rod.\r\n\tThat's 30% for Kurt and 33-1/3% for Patty.\n\r\nMethod:\n\r\n\tLet K, P, and R stand for the quantity each of them had. Let T be the total, K+P+R.\r\n \tNow, since Kurt's percentage equals Patty's quantity, we get\r\n100*K/T = P.\r\n\tSimilarly,\r\n100*P/T = R plus a fraction. Now, look at the common factor, 100/T. Let's call this F, the factor relating one quantity to the next.\r\nK*F = P and P*F = R (plus a fraction),\r\nand K*F^2 = R (plus a fraction).\r\nThe clue about the phonograph leaves us looking for a triple with 33 Rnkfurters for Rod, with Patty getting 33-1/3% (one-third) of the total. \r\nP = T/3\r\nP = (K+P+33)/3 -- remember, R=33\r\nNow, combine this with 100*K/T = P, and a bit of algebra gives us the required answer.\r\n-------------\r\nAlternately, there are 11 triples that fit the factor requirement (courtesy of a short computer program), ranging from (19, 25, 32) to (2376, 96, 3). The ones that total 10 less than a multiple of 25 are\r\n27, 30, 33\r\n63, 45, 32\r\n891, 90, 9\n\r\nGiven the phonograph clue, I expect you can recognize that the first triple above is the answer.\n<|im_end|>" }, { "id": "#28028", "title": "Opposites 3", "fun": 2.7, "difficulty": 2.05, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n# stands for M, I, D, S, or J\r\n$ stands for A, L, F, O, or I\r\n- stands for U, W, G, N, or C\r\n/ stands for S, R, E, P, or L\n\r\nThe four letter code word, -$/#, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Warm and Cold.", "category": "Logic", "date": "01/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n# stands for M, I, D, S, or J\r\n$ stands for A, L, F, O, or I\r\n- stands for U, W, G, N, or C\r\n/ stands for S, R, E, P, or L\n\r\nThe four letter code word, -$/#, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWarm and Cold.\n<|im_start|>answer\nWarm and Cold.\n<|im_end|>" }, { "id": "#7167", "title": "Leg Travel", "fun": 2.7, "difficulty": 1.84, "author": "Michelle", "desc": "A horse travels a certain distance each day. Strangely enough, two of its legs travel 30 miles each day and the other two legs travel nearly 31 miles. It would seem that two of the horse's legs must be one mile ahead of the other two legs, but of course this can't be true. Since the horse is normal, how is this situation possible?", "hint": "No hint available.", "answer": "The horse operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.", "category": "Logic", "date": "09/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA horse travels a certain distance each day. Strangely enough, two of its legs travel 30 miles each day and the other two legs travel nearly 31 miles. It would seem that two of the horse's legs must be one mile ahead of the other two legs, but of course this can't be true. Since the horse is normal, how is this situation possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe horse operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.\n<|im_start|>answer\nThe horse operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.\n<|im_end|>" }, { "id": "#6744", "title": "15 Pigs", "fun": 2.7, "difficulty": 1.92, "author": "pemalova", "desc": "Your name is Cedrick, you're a Ukrainian farmer with 15 pigs. Being a poor farmer in this country, you are given strange laws to abide by. \n\r\n1. You must have exactly 4 pens.\r\n2. You must have an odd number of pigs in each pen.\n\r\nHow do you do it?", "hint": "You're a peaceful farmer. No killing or adding to your stash of pigs. It may seem like it's impossible, but really, it works.", "answer": "Place 5 pigs in each of three pens. Then put the fourth pen around the other 3. The fourth pen has all 15 pigs.", "category": "Math", "date": "08/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour name is Cedrick, you're a Ukrainian farmer with 15 pigs. Being a poor farmer in this country, you are given strange laws to abide by. \n\r\n1. You must have exactly 4 pens.\r\n2. You must have an odd number of pigs in each pen.\n\r\nHow do you do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPlace 5 pigs in each of three pens. Then put the fourth pen around the other 3. The fourth pen has all 15 pigs.\n<|im_start|>answer\nPlace 5 pigs in each of three pens. Then put the fourth pen around the other 3. The fourth pen has all 15 pigs.\n<|im_end|>" }, { "id": "#3625", "title": "Perfectly Square Island", "fun": 2.7, "difficulty": 1.92, "author": "cathalmccabe", "desc": "There is a perfectly square island, with a very deep moat around it, which is 2m wide all the way around. A man needs to get onto this island and has the use of two planks of wood, 2m wide. They are not long enough to bridge the gap (he obviously needs some overlap each side); he has no means to attach the planks together by nails, glue, screws, etc, or to saw them or change them in any other way. He can't jump, swim, fly or get to the island by any other means than by walking over the planks. How can he do it?", "hint": "TTTThink about the corners", "answer": "You have two squares, really, an outer and inner one. He can place one plank at an angle of 45 degrees over an outer corner (like a triangle, with a right angle at the corner of the outside square). He can place the other plank from the middle of the first plank to the corner of the island!", "category": "Logic", "date": "04/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a perfectly square island, with a very deep moat around it, which is 2m wide all the way around. A man needs to get onto this island and has the use of two planks of wood, 2m wide. They are not long enough to bridge the gap (he obviously needs some overlap each side); he has no means to attach the planks together by nails, glue, screws, etc, or to saw them or change them in any other way. He can't jump, swim, fly or get to the island by any other means than by walking over the planks. How can he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou have two squares, really, an outer and inner one. He can place one plank at an angle of 45 degrees over an outer corner (like a triangle, with a right angle at the corner of the outside square). He can place the other plank from the middle of the first plank to the corner of the island!\n<|im_start|>answer\nYou have two squares, really, an outer and inner one. He can place one plank at an angle of 45 degrees over an outer corner (like a triangle, with a right angle at the corner of the outside square). He can place the other plank from the middle of the first plank to the corner of the island!\n<|im_end|>" }, { "id": "#49260", "title": "Four Houses at an Intersection", "fun": 2.7, "difficulty": 1.75, "author": "Scorefire", "desc": "At a + shaped intersection, four different-coloured houses are at the four corners of the intersection so that each house is separated by a road. All you know about the colours of the houses is:\n\r\n1. The blue house is directly north of the purple house.\n\r\n2. The orange house is directly west of the green house.\n\r\nWhat colours are the two houses that are across the road from the green house?", "hint": "No hint available.", "answer": "Purple and blue.\n\r\nIt is impossible for north to align with the roads, but if north is across the diagonal then it works out. If north went in the direction from the bottom left to the top right of the + intersection, then the blue house would be in the top right corner, the orange in the top left, the purple in the bottom left, and green in the bottom right.", "category": "Logic", "date": "01/20/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a + shaped intersection, four different-coloured houses are at the four corners of the intersection so that each house is separated by a road. All you know about the colours of the houses is:\n\r\n1. The blue house is directly north of the purple house.\n\r\n2. The orange house is directly west of the green house.\n\r\nWhat colours are the two houses that are across the road from the green house?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPurple and blue.\n\r\nIt is impossible for north to align with the roads, but if north is across the diagonal then it works out. If north went in the direction from the bottom left to the top right of the + intersection, then the blue house would be in the top right corner, the orange in the top left, the purple in the bottom left, and green in the bottom right.\n<|im_start|>answer\nPurple and blue.\n\r\nIt is impossible for north to align with the roads, but if north is across the diagonal then it works out. If north went in the direction from the bottom left to the top right of the + intersection, then the blue house would be in the top right corner, the orange in the top left, the purple in the bottom left, and green in the bottom right.\n<|im_end|>" }, { "id": "#33961", "title": "You're the Nanny!", "fun": 2.7, "difficulty": 1.86, "author": "Swordoffury1392", "desc": "You have recently taken on the job of being the nanny for a pair- excuse me, a group- of quints! When you arrived at the job, the babies' parents gave you a piece of paper which told you the colors of the pacifiers of each baby and their crib number. (All the babies have to sleep in their own cribs because that's where their favorite stuffed animals are! Oh, and if you're wondering why they need their pacifiers, try getting a cute little baby to be quiet and sleep without one.)\n\r\nHowever, as you prepared to tuck the babies in for their naps, you found that you misplaced the list! Using the information that you remember, find out what color pacifier each baby has and which crib he/she sleeps in. Good luck! (You're going to need it...)\n\r\nBaby names: Bea, Mae, Rae, Lee, Zoe\r\nPacifier colors: sienna, crimson, lime, hot pink, teal\r\nCrib numbers: 1, 2, 3, 4, 5\n\r\n1. Bea ate dinner (some Gerber apple sauce) with Lee, the baby from crib 3, the baby with the crimson pacifier and the baby with the lime one.\n\r\n2. Zoe's crib number is lower than the baby with a lime pacifier, but higher than Rae's.\n\r\n3. Rae's crib number isn't 1.\n\r\n4. Bea's crib number is higher than Zoe's.\n\r\n5. The baby with a hot pink pacifier has a higher crib number than that of the baby with a sienna pacifier, but has a lower crib number than Mae, whose crib number isn't five. (One of the few things harder than deciphering that is changing a baby's diaper!)", "hint": "A mix of corn starch and baby powder is helpful when changing diapers. Oh wait, you wanted one for the brain teaser. Sorry, there isn't any!", "answer": "Name- Crib number- Pacifier color\n\r\nBea- 5- teal\r\nMae- 4- lime\r\nRae- 2- crimson\r\nLee- 1- sienna\r\nZoe- 3- hot pink", "category": "Logic-Grid", "date": "11/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have recently taken on the job of being the nanny for a pair- excuse me, a group- of quints! When you arrived at the job, the babies' parents gave you a piece of paper which told you the colors of the pacifiers of each baby and their crib number. (All the babies have to sleep in their own cribs because that's where their favorite stuffed animals are! Oh, and if you're wondering why they need their pacifiers, try getting a cute little baby to be quiet and sleep without one.)\n\r\nHowever, as you prepared to tuck the babies in for their naps, you found that you misplaced the list! Using the information that you remember, find out what color pacifier each baby has and which crib he/she sleeps in. Good luck! (You're going to need it...)\n\r\nBaby names: Bea, Mae, Rae, Lee, Zoe\r\nPacifier colors: sienna, crimson, lime, hot pink, teal\r\nCrib numbers: 1, 2, 3, 4, 5\n\r\n1. Bea ate dinner (some Gerber apple sauce) with Lee, the baby from crib 3, the baby with the crimson pacifier and the baby with the lime one.\n\r\n2. Zoe's crib number is lower than the baby with a lime pacifier, but higher than Rae's.\n\r\n3. Rae's crib number isn't 1.\n\r\n4. Bea's crib number is higher than Zoe's.\n\r\n5. The baby with a hot pink pacifier has a higher crib number than that of the baby with a sienna pacifier, but has a lower crib number than Mae, whose crib number isn't five. (One of the few things harder than deciphering that is changing a baby's diaper!)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName- Crib number- Pacifier color\n\r\nBea- 5- teal\r\nMae- 4- lime\r\nRae- 2- crimson\r\nLee- 1- sienna\r\nZoe- 3- hot pink\n<|im_start|>answer\nName- Crib number- Pacifier color\n\r\nBea- 5- teal\r\nMae- 4- lime\r\nRae- 2- crimson\r\nLee- 1- sienna\r\nZoe- 3- hot pink\n<|im_end|>" }, { "id": "#33798", "title": "15 Cents", "fun": 2.7, "difficulty": 1.55, "author": "calmsavior", "desc": "On a piece of paper, make a 3x3 grid with squares that are 1 inch long. Next, get three nickels and three dimes. Can you place the six coins in the squares such that each row, column, and diagonal each have 15 cents? Only one coin is allowed per square.\n\r\nFor those who don't know American currency, a nickel is 5 cents and a dime is 10 cents.", "hint": "The three nickels will be arranged on the same line.", "answer": "[N][E][D]\r\n[D][N][E]\r\n[E][D][N]\n\r\nN = nickel (5 cents)\r\nD = dime (10 cents)\r\nE = empty\n\r\nAll other solutions are reflections or rotations.", "category": "Logic", "date": "11/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a piece of paper, make a 3x3 grid with squares that are 1 inch long. Next, get three nickels and three dimes. Can you place the six coins in the squares such that each row, column, and diagonal each have 15 cents? Only one coin is allowed per square.\n\r\nFor those who don't know American currency, a nickel is 5 cents and a dime is 10 cents.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n[N][E][D]\r\n[D][N][E]\r\n[E][D][N]\n\r\nN = nickel (5 cents)\r\nD = dime (10 cents)\r\nE = empty\n\r\nAll other solutions are reflections or rotations.\n<|im_start|>answer\n[N][E][D]\r\n[D][N][E]\r\n[E][D][N]\n\r\nN = nickel (5 cents)\r\nD = dime (10 cents)\r\nE = empty\n\r\nAll other solutions are reflections or rotations.\n<|im_end|>" }, { "id": "#337", "title": "Weighing Bricks", "fun": 2.7, "difficulty": 1.9000000000000001, "author": "Phyllis", "desc": "A bricklayer has 9 bricks. 8 bricks weigh the same amount, but one brick is slightly heavier than the rest. The bricklayer wants to find the heavy brick. He has a balance scale. How can he find the heavy brick in only two weighings?", "hint": "No hint available.", "answer": "He should divide the bricks into 3 groups of 3. He then weighs 2 sets of 3 bricks against each other. If they balance, the heavy brick is in the group that was set aside. If they do not balance, he then takes the group that was heaviest. He has 3 bricks left. He takes the 2 bricks from the 3 and weighs them against each other. If they balance, the heavy brick is the one which is set aside. If they do not balance, the scale will show which is the heavier brick.", "category": "Math", "date": "03/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bricklayer has 9 bricks. 8 bricks weigh the same amount, but one brick is slightly heavier than the rest. The bricklayer wants to find the heavy brick. He has a balance scale. How can he find the heavy brick in only two weighings?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe should divide the bricks into 3 groups of 3. He then weighs 2 sets of 3 bricks against each other. If they balance, the heavy brick is in the group that was set aside. If they do not balance, he then takes the group that was heaviest. He has 3 bricks left. He takes the 2 bricks from the 3 and weighs them against each other. If they balance, the heavy brick is the one which is set aside. If they do not balance, the scale will show which is the heavier brick.\n<|im_start|>answer\nHe should divide the bricks into 3 groups of 3. He then weighs 2 sets of 3 bricks against each other. If they balance, the heavy brick is in the group that was set aside. If they do not balance, he then takes the group that was heaviest. He has 3 bricks left. He takes the 2 bricks from the 3 and weighs them against each other. If they balance, the heavy brick is the one which is set aside. If they do not balance, the scale will show which is the heavier brick.\n<|im_end|>" }, { "id": "#46171", "title": "Birthday !!!", "fun": 2.7, "difficulty": 1.62, "author": "Kitty_cat_2009", "desc": "Daniel, my son, is exactly one fifth of my age. In 21 years time, I will be exactly twice his age. My wife is exactly seven times older than my daughter, Jessica. In 8 years time, my wife will be three times older than Jessica. How old are Daniel and Jessica now?", "hint": "No hint available.", "answer": "Daniel is 7 years old and Jessica is 4 years old.", "category": "Math", "date": "01/09/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDaniel, my son, is exactly one fifth of my age. In 21 years time, I will be exactly twice his age. My wife is exactly seven times older than my daughter, Jessica. In 8 years time, my wife will be three times older than Jessica. How old are Daniel and Jessica now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDaniel is 7 years old and Jessica is 4 years old.\n<|im_start|>answer\nDaniel is 7 years old and Jessica is 4 years old.\n<|im_end|>" }, { "id": "#39378", "title": "It's a Jungle Out There", "fun": 2.7, "difficulty": 2.72, "author": "cnmne", "desc": "There is a plot of land that is 16 square acres, arranged in a 4 X 4 grid. There are 16 mammals, two each of the following: beaver, cat, dog, goat, horse, lion, tiger, and walrus. There is one mammal in each acre. The acres are labeled A through P, as shown below.\n\r\nA B C D\r\nE F G H\r\nI J K L\r\nM N O P\n\r\nGiven the following clues, determine where each mammal is located. The terms \"next to\" and \"connected together\" mean vertically, horizontally, or diagonally.\n\r\n1) A and D do not contain the same mammal, but one of them has a dog.\r\n2) E and O do not contain the same mammal, but one of them has a horse.\r\n3) B and L contain the same mammal, but not a tiger.\r\n4) C and M contain the same mammal, but not a beaver.\r\n5) F, K, N, and P are four different mammals.\r\n6) The tigers are in different columns.\r\n7) The goats are located in two of the following locations: B, C, K, and O.\r\n8) The lions are located in two of the following locations: A, E, F, and M.\r\n9) Cats don't get along with dogs, so neither cat is next to a dog.\r\n10) Tigers have goats on their menu, so each tiger must be next to at least one goat and each goat must be next to at least one tiger.\r\n11) The beavers and walruses live on the same body of water, so all four must be connected together in some fashion.", "hint": "No hint available.", "answer": "A = lion, B = cat, C = walrus, D = dog\r\nE = horse, F = lion, G = beaver, H = tiger\r\nI = dog, J = beaver, K = goat, L = cat\r\nM = walrus, N = tiger, O = goat, P = horse\n\r\nPer #3, B & L are the same; per #4, C & M are the same; therefore, per #7, K & O are goats; therefore, per #2, E is a horse; therefore, per #8, A & F are lions; therefore, per #1, D is a dog.\r\nPer #4, C & M are not beavers; per #9, C is not a cat; per #10, M is not a tiger; therefore, C & M are walruses; therefore, per #11, G & J are beavers.\r\nPer #3, B & L are not tigers; therefore, B & L are cats. Per #6, N is a tiger; per #9, H & P are not a dog; therefore, I is a dog.\r\nPer #5, P is a horse; therefore, H is a tiger.", "category": "Logic", "date": "11/26/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a plot of land that is 16 square acres, arranged in a 4 X 4 grid. There are 16 mammals, two each of the following: beaver, cat, dog, goat, horse, lion, tiger, and walrus. There is one mammal in each acre. The acres are labeled A through P, as shown below.\n\r\nA B C D\r\nE F G H\r\nI J K L\r\nM N O P\n\r\nGiven the following clues, determine where each mammal is located. The terms \"next to\" and \"connected together\" mean vertically, horizontally, or diagonally.\n\r\n1) A and D do not contain the same mammal, but one of them has a dog.\r\n2) E and O do not contain the same mammal, but one of them has a horse.\r\n3) B and L contain the same mammal, but not a tiger.\r\n4) C and M contain the same mammal, but not a beaver.\r\n5) F, K, N, and P are four different mammals.\r\n6) The tigers are in different columns.\r\n7) The goats are located in two of the following locations: B, C, K, and O.\r\n8) The lions are located in two of the following locations: A, E, F, and M.\r\n9) Cats don't get along with dogs, so neither cat is next to a dog.\r\n10) Tigers have goats on their menu, so each tiger must be next to at least one goat and each goat must be next to at least one tiger.\r\n11) The beavers and walruses live on the same body of water, so all four must be connected together in some fashion.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA = lion, B = cat, C = walrus, D = dog\r\nE = horse, F = lion, G = beaver, H = tiger\r\nI = dog, J = beaver, K = goat, L = cat\r\nM = walrus, N = tiger, O = goat, P = horse\n\r\nPer #3, B & L are the same; per #4, C & M are the same; therefore, per #7, K & O are goats; therefore, per #2, E is a horse; therefore, per #8, A & F are lions; therefore, per #1, D is a dog.\r\nPer #4, C & M are not beavers; per #9, C is not a cat; per #10, M is not a tiger; therefore, C & M are walruses; therefore, per #11, G & J are beavers.\r\nPer #3, B & L are not tigers; therefore, B & L are cats. Per #6, N is a tiger; per #9, H & P are not a dog; therefore, I is a dog.\r\nPer #5, P is a horse; therefore, H is a tiger.\n<|im_start|>answer\nA = lion, B = cat, C = walrus, D = dog\r\nE = horse, F = lion, G = beaver, H = tiger\r\nI = dog, J = beaver, K = goat, L = cat\r\nM = walrus, N = tiger, O = goat, P = horse\n\r\nPer #3, B & L are the same; per #4, C & M are the same; therefore, per #7, K & O are goats; therefore, per #2, E is a horse; therefore, per #8, A & F are lions; therefore, per #1, D is a dog.\r\nPer #4, C & M are not beavers; per #9, C is not a cat; per #10, M is not a tiger; therefore, C & M are walruses; therefore, per #11, G & J are beavers.\r\nPer #3, B & L are not tigers; therefore, B & L are cats. Per #6, N is a tiger; per #9, H & P are not a dog; therefore, I is a dog.\r\nPer #5, P is a horse; therefore, H is a tiger.\n<|im_end|>" }, { "id": "#4766", "title": "Traffic Lights", "fun": 2.7, "difficulty": 2.06, "author": "bobbrt", "desc": "The following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nA procedure is needed to change all the red traffic lights in a small town to green, and vice versa. (Luckily there are no yellow lights in this town, and also no lights that don't work). Assume that you have a street map that shows the locations of all the lights.\n\r\na) If all lights on your map are marked \"done,\" skip the next six statements.\r\nb) If the light is red, skip the next two statements.\r\nc) Turn the light red.\r\nd) Turn the light green.\r\ne) On your map, mark the light you just changed as \"done\" and go back to the first statement.\r\nf) Find a light that is not marked \"done\" on your map, and check whether it is red or green.\r\ng) Skip the next statement.\r\nh) End.", "hint": "No hint available.", "answer": "a) If all lights on your map are marked \"done,\" skip the next six statements.\r\nf) Find a light that is not marked \"done\" on your map, and check whether it is red or green.\r\nb) If the light is red, skip the next two statements.\r\nc) Turn the light red.\r\ng) Skip the next statement.\r\nd) Turn the light green.\r\ne) On your map, mark the light you just changed as \"done\" and go back to the first statement.\r\nh) End.", "category": "Logic", "date": "06/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nA procedure is needed to change all the red traffic lights in a small town to green, and vice versa. (Luckily there are no yellow lights in this town, and also no lights that don't work). Assume that you have a street map that shows the locations of all the lights.\n\r\na) If all lights on your map are marked \"done,\" skip the next six statements.\r\nb) If the light is red, skip the next two statements.\r\nc) Turn the light red.\r\nd) Turn the light green.\r\ne) On your map, mark the light you just changed as \"done\" and go back to the first statement.\r\nf) Find a light that is not marked \"done\" on your map, and check whether it is red or green.\r\ng) Skip the next statement.\r\nh) End.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) If all lights on your map are marked \"done,\" skip the next six statements.\r\nf) Find a light that is not marked \"done\" on your map, and check whether it is red or green.\r\nb) If the light is red, skip the next two statements.\r\nc) Turn the light red.\r\ng) Skip the next statement.\r\nd) Turn the light green.\r\ne) On your map, mark the light you just changed as \"done\" and go back to the first statement.\r\nh) End.\n<|im_start|>answer\na) If all lights on your map are marked \"done,\" skip the next six statements.\r\nf) Find a light that is not marked \"done\" on your map, and check whether it is red or green.\r\nb) If the light is red, skip the next two statements.\r\nc) Turn the light red.\r\ng) Skip the next statement.\r\nd) Turn the light green.\r\ne) On your map, mark the light you just changed as \"done\" and go back to the first statement.\r\nh) End.\n<|im_end|>" }, { "id": "#1086", "title": "Rows of Apple Trees", "fun": 2.7, "difficulty": 2.1, "author": "mephistopheles", "desc": "An apple farmer goes to the nursery to buy 10 apple trees. The owner says that if the farmer can plant the 10 trees in 5 rows of 4, he can have the trees for free. How does the farmer do it?", "hint": "No hint available.", "answer": "He places the trees in the shape of a 5 pointed star.", "category": "Math", "date": "10/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn apple farmer goes to the nursery to buy 10 apple trees. The owner says that if the farmer can plant the 10 trees in 5 rows of 4, he can have the trees for free. How does the farmer do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe places the trees in the shape of a 5 pointed star.\n<|im_start|>answer\nHe places the trees in the shape of a 5 pointed star.\n<|im_end|>" }, { "id": "#23399", "title": "National Hurdles", "fun": 2.7, "difficulty": 2.05, "author": "Philly", "desc": "At a recent Mixed National Hurdle trials, ten contestants competed for the coveted Hurdle Shield. There were numerous judges who made sure that the results were accurate. From their notes can you determine who finished where? \n\r\nIvor Bignose finished before May Eye and Mick Stup whilst Leigh Vamessage was victorious over May Eye and Laura DeLand. \r\nJack Pott was beaten by Jerry Atric, Mick Stup and Al Beback.\r\nLaura DeLand was beaten by Mick Stup, May Eye and Ivor Bignose, whereas Joe King beat Jerry Atric and Jack Pott but lost to Laura DeLand and Inga Hootz. \r\nLeigh Vamessage was beaten by Ivor Bignose and Inga Hootz.\r\nInga Hootz was beaten by Al Beback, who, in turn, lost to Ivor Bignose, but beat Jerry Atric and Jack Pott. \r\nMay Eye finished ahead of Mick Stup and Jerry Atric, who lost to Leigh Vamessage and Inga Hootz.", "hint": "No hint available.", "answer": "Ivor Bignose\r\nAl Beback\r\nInga Hootz\r\nLeigh Vamessage\r\nMay Eye\r\nMick Stup\r\nLaura DeLand\r\nJoe King\r\nJerry Atric\r\nJack Pott", "category": "Logic", "date": "06/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a recent Mixed National Hurdle trials, ten contestants competed for the coveted Hurdle Shield. There were numerous judges who made sure that the results were accurate. From their notes can you determine who finished where? \n\r\nIvor Bignose finished before May Eye and Mick Stup whilst Leigh Vamessage was victorious over May Eye and Laura DeLand. \r\nJack Pott was beaten by Jerry Atric, Mick Stup and Al Beback.\r\nLaura DeLand was beaten by Mick Stup, May Eye and Ivor Bignose, whereas Joe King beat Jerry Atric and Jack Pott but lost to Laura DeLand and Inga Hootz. \r\nLeigh Vamessage was beaten by Ivor Bignose and Inga Hootz.\r\nInga Hootz was beaten by Al Beback, who, in turn, lost to Ivor Bignose, but beat Jerry Atric and Jack Pott. \r\nMay Eye finished ahead of Mick Stup and Jerry Atric, who lost to Leigh Vamessage and Inga Hootz.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIvor Bignose\r\nAl Beback\r\nInga Hootz\r\nLeigh Vamessage\r\nMay Eye\r\nMick Stup\r\nLaura DeLand\r\nJoe King\r\nJerry Atric\r\nJack Pott\n<|im_start|>answer\nIvor Bignose\r\nAl Beback\r\nInga Hootz\r\nLeigh Vamessage\r\nMay Eye\r\nMick Stup\r\nLaura DeLand\r\nJoe King\r\nJerry Atric\r\nJack Pott\n<|im_end|>" }, { "id": "#32639", "title": "Little Women", "fun": 2.7, "difficulty": 1.87, "author": "moonsliver86", "desc": "There are five women having dinner on a circular table. Mrs. Smith is sitting between Miss Cooper and Miss Andrews. Annie is sitting between Connie and Mrs. Grey. Miss Cooper is seated between Annie and Yvette. Elizabeth is seated with Mrs. Summers on her left and Miss Andrews on her right. Teresa paid the bill. \n\r\nWhat are the full names of these five women?", "hint": "Remember that it's a circular table.", "answer": "Annie Summers, Elizabeth Grey, Teresa Andrews, Yvette Smith, Connie Cooper", "category": "Logic", "date": "08/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five women having dinner on a circular table. Mrs. Smith is sitting between Miss Cooper and Miss Andrews. Annie is sitting between Connie and Mrs. Grey. Miss Cooper is seated between Annie and Yvette. Elizabeth is seated with Mrs. Summers on her left and Miss Andrews on her right. Teresa paid the bill. \n\r\nWhat are the full names of these five women?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnnie Summers, Elizabeth Grey, Teresa Andrews, Yvette Smith, Connie Cooper\n<|im_start|>answer\nAnnie Summers, Elizabeth Grey, Teresa Andrews, Yvette Smith, Connie Cooper\n<|im_end|>" }, { "id": "#13063", "title": "Pearls and Girls", "fun": 2.7, "difficulty": 2.7, "author": "willymapo", "desc": "Once an old man died, and in his Will he stated that all the pearls he kept in a little bag were to be distributed among his daughters. To make things fair, the distribution must be done in the following way:\n\r\nThe older girl should receive one pearl, and a seventh of the remaining pearls in the bag.\n\r\nThe second girl should receive two pearls, and a seventh of the remaining pearls in the bag.\n\r\nThe third girl should receive three pearls, and a seventh of the remaining pearls in the bag.\n\r\nAnd so on until all the pearls are exhausted.\r\nNeedless to say, the younger girl grew angry, and went to talk to the Judge because, if distributed that way, she probably would not get a pearl at all.\r\nThe wise Judge looked at her and said: \"Don't worry, my child. Your father was a wise man. He made everything quite right so that, after all the pearls are given, each one of you will have the same quantity of pearls and there will be no pearls left.\"\n\r\nAnd so it was.\r\nHow many pearls were there in the bag?\r\nHow many daughters did the old man have?\r\nHow many pearls did each girl get?", "hint": "If there are no pearls left, how many pearls are in the bag for the last girl? How many pearls did the second-to-last girl get?", "answer": "There were 36 pearls.\r\nThere were 6 daughters.\r\nEach daughter got 6 pearls.\n\r\nThe girl number x will have x pearls and a seventh of the rest. Since the last girl leaves no pearls in the bag, then when she takes her pearls the rest in the bag is zero (a seventh of nothing is nothing).\r\nNow, let's say the last girl was number k. Then she took k pearls and left the bag empty. But as all the girls end up with the same number of pearls, then each girl has k pearls in her hands. That is, the total number of pearls is: k pearls * k girls = square of k.\r\nLet's look at the girl number k-1. She takes k-1 pearls and a seventh of the rest, and leaves exactly k pearls for the last girl (remember the last girl found k pearls in the bag and takes them all). But, since each girl ends up with k pearls, then the \"seventh of the rest\" for the k-1 girl should be 1 pearl (to sum up k pearls at last: k-1+1=k). That means that k pearls of the last girl plus 1 pearl of the k-1 girl divided by 7 results in 1 (a seventh of the rest is 1, (k+1)/7=1 ).\r\nThat is, k+1 = 7 and then k = 6.\r\nSo, the number of pearls is 6*6 = 36, and there were 6 girls.", "category": "Math", "date": "06/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce an old man died, and in his Will he stated that all the pearls he kept in a little bag were to be distributed among his daughters. To make things fair, the distribution must be done in the following way:\n\r\nThe older girl should receive one pearl, and a seventh of the remaining pearls in the bag.\n\r\nThe second girl should receive two pearls, and a seventh of the remaining pearls in the bag.\n\r\nThe third girl should receive three pearls, and a seventh of the remaining pearls in the bag.\n\r\nAnd so on until all the pearls are exhausted.\r\nNeedless to say, the younger girl grew angry, and went to talk to the Judge because, if distributed that way, she probably would not get a pearl at all.\r\nThe wise Judge looked at her and said: \"Don't worry, my child. Your father was a wise man. He made everything quite right so that, after all the pearls are given, each one of you will have the same quantity of pearls and there will be no pearls left.\"\n\r\nAnd so it was.\r\nHow many pearls were there in the bag?\r\nHow many daughters did the old man have?\r\nHow many pearls did each girl get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 36 pearls.\r\nThere were 6 daughters.\r\nEach daughter got 6 pearls.\n\r\nThe girl number x will have x pearls and a seventh of the rest. Since the last girl leaves no pearls in the bag, then when she takes her pearls the rest in the bag is zero (a seventh of nothing is nothing).\r\nNow, let's say the last girl was number k. Then she took k pearls and left the bag empty. But as all the girls end up with the same number of pearls, then each girl has k pearls in her hands. That is, the total number of pearls is: k pearls * k girls = square of k.\r\nLet's look at the girl number k-1. She takes k-1 pearls and a seventh of the rest, and leaves exactly k pearls for the last girl (remember the last girl found k pearls in the bag and takes them all). But, since each girl ends up with k pearls, then the \"seventh of the rest\" for the k-1 girl should be 1 pearl (to sum up k pearls at last: k-1+1=k). That means that k pearls of the last girl plus 1 pearl of the k-1 girl divided by 7 results in 1 (a seventh of the rest is 1, (k+1)/7=1 ).\r\nThat is, k+1 = 7 and then k = 6.\r\nSo, the number of pearls is 6*6 = 36, and there were 6 girls.\n<|im_start|>answer\nThere were 36 pearls.\r\nThere were 6 daughters.\r\nEach daughter got 6 pearls.\n\r\nThe girl number x will have x pearls and a seventh of the rest. Since the last girl leaves no pearls in the bag, then when she takes her pearls the rest in the bag is zero (a seventh of nothing is nothing).\r\nNow, let's say the last girl was number k. Then she took k pearls and left the bag empty. But as all the girls end up with the same number of pearls, then each girl has k pearls in her hands. That is, the total number of pearls is: k pearls * k girls = square of k.\r\nLet's look at the girl number k-1. She takes k-1 pearls and a seventh of the rest, and leaves exactly k pearls for the last girl (remember the last girl found k pearls in the bag and takes them all). But, since each girl ends up with k pearls, then the \"seventh of the rest\" for the k-1 girl should be 1 pearl (to sum up k pearls at last: k-1+1=k). That means that k pearls of the last girl plus 1 pearl of the k-1 girl divided by 7 results in 1 (a seventh of the rest is 1, (k+1)/7=1 ).\r\nThat is, k+1 = 7 and then k = 6.\r\nSo, the number of pearls is 6*6 = 36, and there were 6 girls.\n<|im_end|>" }, { "id": "#219", "title": "Class Cancelled", "fun": 2.7, "difficulty": 1.21, "author": "Phyllis", "desc": "My teacher came into our classroom and said \"Class is cancelled today because I'm not feeling well. We will meet again at 10 A.M., three days after two days before the day before tomorrow.\" \n\r\nWhat day should I go back to class?", "hint": "No hint available.", "answer": "Tomorrow.", "category": "Logic", "date": "02/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy teacher came into our classroom and said \"Class is cancelled today because I'm not feeling well. We will meet again at 10 A.M., three days after two days before the day before tomorrow.\" \n\r\nWhat day should I go back to class?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTomorrow.\n<|im_start|>answer\nTomorrow.\n<|im_end|>" }, { "id": "#39311", "title": "Chess Tournament 2", "fun": 2.7, "difficulty": 1.73, "author": "soccerguy0428", "desc": "8 friends decided to play in a chess tournament. They played a single elimination tournament, with three rounds (the first round, second round, and finals). Using the clues below can you determine who beat whom in each round?\n\r\nBoys: Connor, Mark, Jeremy, Tyler\n\r\nGirls: Kelsey, Megan, Caitlin, Alyssa\n\r\nClues:\n\r\n1. The people whose names start with the same letter played each other in the first round.\n\r\n2. Kelsey got 2nd place, but was the only girl to beat someone in the first round.\n\r\n3. Jeremy never played a girl.\n\r\n4. Connor beat Jeremy.", "hint": "No hint available.", "answer": "First Round:\n\r\nCaitlin vs. Connor, Connor won\r\nJeremy vs. Tyler, Jeremy won\r\nMegan vs. Mark, Mark won\r\nAlyssa vs. Kelsey, Kelsey won\n\r\nSecond Round:\n\r\nConnor vs. Jeremy, Connor won\r\nKelsey vs. Mark, Kelsey won\n\r\nFinals:\n\r\nKelsey vs. Connor, Connor won", "category": "Logic", "date": "11/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n8 friends decided to play in a chess tournament. They played a single elimination tournament, with three rounds (the first round, second round, and finals). Using the clues below can you determine who beat whom in each round?\n\r\nBoys: Connor, Mark, Jeremy, Tyler\n\r\nGirls: Kelsey, Megan, Caitlin, Alyssa\n\r\nClues:\n\r\n1. The people whose names start with the same letter played each other in the first round.\n\r\n2. Kelsey got 2nd place, but was the only girl to beat someone in the first round.\n\r\n3. Jeremy never played a girl.\n\r\n4. Connor beat Jeremy.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst Round:\n\r\nCaitlin vs. Connor, Connor won\r\nJeremy vs. Tyler, Jeremy won\r\nMegan vs. Mark, Mark won\r\nAlyssa vs. Kelsey, Kelsey won\n\r\nSecond Round:\n\r\nConnor vs. Jeremy, Connor won\r\nKelsey vs. Mark, Kelsey won\n\r\nFinals:\n\r\nKelsey vs. Connor, Connor won\n<|im_start|>answer\nFirst Round:\n\r\nCaitlin vs. Connor, Connor won\r\nJeremy vs. Tyler, Jeremy won\r\nMegan vs. Mark, Mark won\r\nAlyssa vs. Kelsey, Kelsey won\n\r\nSecond Round:\n\r\nConnor vs. Jeremy, Connor won\r\nKelsey vs. Mark, Kelsey won\n\r\nFinals:\n\r\nKelsey vs. Connor, Connor won\n<|im_end|>" }, { "id": "#19742", "title": "Logic Problem Puzzle?", "fun": 2.7, "difficulty": 1.85, "author": "lorial", "desc": "Mr. Puzzle has been coming home from the local watering hole a little bit the worse for wear. Mrs. Puzzle is becoming increasingly fed up with his behaviour.\n\r\nWhen Mr. Puzzle arrived home one evening last week, his wife had left him in a bit of a dilemma. They have three bedrooms and they used them all from time to time. On each door Mrs. Puzzle had placed a sign and also another sign stating that only one of the three other statements was true and that was where Mrs. Puzzle was sleeping for that night. Of the other two rooms, one was empty and the other had the neighbours' highly strung Pit Bull Terrier - Bruty inside. Mr. Puzzle was very confused, having consumed a few too many that very evening and he stared blankly at each door.\n\r\nSign on Bedroom 1. Bedroom 3 is empty\r\nSign on Bedroom 2. Bruty is in here\r\nSign on Bedroom 3. Bedroom 2 is empty\n\r\nBehind which door is his wife, where is the dog and which room is empty?", "hint": "No hint available.", "answer": "Bedroom 1. Dog\r\nBedroom 2. Empty\r\nBedroom 3. Wife\n\r\nIf the sign on Bedroom 1 were true this would mean the wife must be in Bedroom 1, but then Bedroom 3 would have to be empty and therefore Bruty would have to be in Bedroom 2. This would mean 2 true signs, so is incorrect.\n\r\nThe sign on Bedroom 2 must be incorrect, as if it were true Bruty would be in here, however, only the Bedroom sign where the wife is sleeping, is true. Therefore, this is incorrect too.\n\r\nTherefore: \n\r\nBedroom 3 sign is true - So Mrs. Puzzle is in here.\r\nBedroom 2 sign is a lie - So Bruty, the dog, must be in Bedroom 1, and this room must be empty.\r\nBedroom 1 sign is a lie - Mrs Puzzle is in Bedroom 3", "category": "Logic", "date": "12/06/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Puzzle has been coming home from the local watering hole a little bit the worse for wear. Mrs. Puzzle is becoming increasingly fed up with his behaviour.\n\r\nWhen Mr. Puzzle arrived home one evening last week, his wife had left him in a bit of a dilemma. They have three bedrooms and they used them all from time to time. On each door Mrs. Puzzle had placed a sign and also another sign stating that only one of the three other statements was true and that was where Mrs. Puzzle was sleeping for that night. Of the other two rooms, one was empty and the other had the neighbours' highly strung Pit Bull Terrier - Bruty inside. Mr. Puzzle was very confused, having consumed a few too many that very evening and he stared blankly at each door.\n\r\nSign on Bedroom 1. Bedroom 3 is empty\r\nSign on Bedroom 2. Bruty is in here\r\nSign on Bedroom 3. Bedroom 2 is empty\n\r\nBehind which door is his wife, where is the dog and which room is empty?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBedroom 1. Dog\r\nBedroom 2. Empty\r\nBedroom 3. Wife\n\r\nIf the sign on Bedroom 1 were true this would mean the wife must be in Bedroom 1, but then Bedroom 3 would have to be empty and therefore Bruty would have to be in Bedroom 2. This would mean 2 true signs, so is incorrect.\n\r\nThe sign on Bedroom 2 must be incorrect, as if it were true Bruty would be in here, however, only the Bedroom sign where the wife is sleeping, is true. Therefore, this is incorrect too.\n\r\nTherefore: \n\r\nBedroom 3 sign is true - So Mrs. Puzzle is in here.\r\nBedroom 2 sign is a lie - So Bruty, the dog, must be in Bedroom 1, and this room must be empty.\r\nBedroom 1 sign is a lie - Mrs Puzzle is in Bedroom 3\n<|im_start|>answer\nBedroom 1. Dog\r\nBedroom 2. Empty\r\nBedroom 3. Wife\n\r\nIf the sign on Bedroom 1 were true this would mean the wife must be in Bedroom 1, but then Bedroom 3 would have to be empty and therefore Bruty would have to be in Bedroom 2. This would mean 2 true signs, so is incorrect.\n\r\nThe sign on Bedroom 2 must be incorrect, as if it were true Bruty would be in here, however, only the Bedroom sign where the wife is sleeping, is true. Therefore, this is incorrect too.\n\r\nTherefore: \n\r\nBedroom 3 sign is true - So Mrs. Puzzle is in here.\r\nBedroom 2 sign is a lie - So Bruty, the dog, must be in Bedroom 1, and this room must be empty.\r\nBedroom 1 sign is a lie - Mrs Puzzle is in Bedroom 3\n<|im_end|>" }, { "id": "#26529", "title": "Bab, Beb, Bib, Bob and Bub Chess Tournament", "fun": 2.7, "difficulty": 1.94, "author": "shenqiang", "desc": "5 men, whose names are Bab, Beb, Bib, Bob and Bub, took part in a chess tournament, and each player was going to play against each other player once. After some days passed, they decided to have a get-together. Bub asked the other men how many matches until then they had played.\n\r\nBab said: \"I have played 1 match.\"\r\nBeb said: \"I have played 2 matches.\"\r\nBib said: \"I have played 3 matches.\"\r\nBob said: \"I have played 4 matches.\"\n\r\nHow many matches had Bub played?", "hint": "If you can't figure it out, draw a diagram.", "answer": "Since Bob had played 4 matches, he must have played against all 4 other players, i.e. Bab, Beb, Bib, and Bub.\n\r\nThe only match that Bab had played must have been against Bob.\n\r\nBib had played 3 matches, and he couldn't have played against Bab. Hence, Bib had played against Beb, Bob and Bub.\n\r\nBeb had played against Bib and Bob, so he couldn't have played against Bab or Bub.\n\r\nTherefore, Bub had played 2 matches, against Bib and Bob.", "category": "Logic", "date": "10/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 men, whose names are Bab, Beb, Bib, Bob and Bub, took part in a chess tournament, and each player was going to play against each other player once. After some days passed, they decided to have a get-together. Bub asked the other men how many matches until then they had played.\n\r\nBab said: \"I have played 1 match.\"\r\nBeb said: \"I have played 2 matches.\"\r\nBib said: \"I have played 3 matches.\"\r\nBob said: \"I have played 4 matches.\"\n\r\nHow many matches had Bub played?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince Bob had played 4 matches, he must have played against all 4 other players, i.e. Bab, Beb, Bib, and Bub.\n\r\nThe only match that Bab had played must have been against Bob.\n\r\nBib had played 3 matches, and he couldn't have played against Bab. Hence, Bib had played against Beb, Bob and Bub.\n\r\nBeb had played against Bib and Bob, so he couldn't have played against Bab or Bub.\n\r\nTherefore, Bub had played 2 matches, against Bib and Bob.\n<|im_start|>answer\nSince Bob had played 4 matches, he must have played against all 4 other players, i.e. Bab, Beb, Bib, and Bub.\n\r\nThe only match that Bab had played must have been against Bob.\n\r\nBib had played 3 matches, and he couldn't have played against Bab. Hence, Bib had played against Beb, Bob and Bub.\n\r\nBeb had played against Bib and Bob, so he couldn't have played against Bab or Bub.\n\r\nTherefore, Bub had played 2 matches, against Bib and Bob.\n<|im_end|>" }, { "id": "#25490", "title": "Peter Rabbit", "fun": 2.7, "difficulty": 1.73, "author": "titanoftheocean", "desc": "Peter Rabbit was starving! He came to a farmer's lettuce garden, but it was surrounded by a picket fence. Peter knew he must eat soon, or he would die. He could barely fit through the fence in his present condition. He knew that if he entered and ate the lettuce, he would be unable to fit back through the fence. If the farmer happened to come by, he could not escape. The lettuce was too large to fit through the fence. How could Peter eat the lettuce and still manage to escape if the need arose?", "hint": "No hint available.", "answer": "Peter crawled through the fence and brought the lettuce back to the edge of the fence. He squeezed back through the fence to the outside and proceeded to feast.", "category": "Logic", "date": "08/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPeter Rabbit was starving! He came to a farmer's lettuce garden, but it was surrounded by a picket fence. Peter knew he must eat soon, or he would die. He could barely fit through the fence in his present condition. He knew that if he entered and ate the lettuce, he would be unable to fit back through the fence. If the farmer happened to come by, he could not escape. The lettuce was too large to fit through the fence. How could Peter eat the lettuce and still manage to escape if the need arose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPeter crawled through the fence and brought the lettuce back to the edge of the fence. He squeezed back through the fence to the outside and proceeded to feast.\n<|im_start|>answer\nPeter crawled through the fence and brought the lettuce back to the edge of the fence. He squeezed back through the fence to the outside and proceeded to feast.\n<|im_end|>" }, { "id": "#20902", "title": "Politicians", "fun": 2.7, "difficulty": 1.8900000000000001, "author": "Kassity", "desc": "You are traveling around the world and you discover a unique island. You learn that the inhabitants of this island possess very unique qualities. First of all, all politicians are liars, and always lie. The inhabitants that are not politicians always tell the truth. When you meet the first inhabitant you ask him if he is a politician, he answers. Upon meeting the second inhabitant, he claims that the first inhabitant denied being a politician. The third inhabitant states that the first inhabitant is, indeed, a politician. \r\nHow many politicians have you encountered?", "hint": "No hint available.", "answer": "1 politician.\r\nThe first inhabitant will deny being a politician if he is a politician or if he is not a politician.\r\nTherefore, the second inhabitant is not a politician because the first inhabitant did in fact deny being a politician.\r\nIf the third inhabitant is not a politician and is truthful, then the first inhabitant is a politician. \r\nIf the third inhabitant is a politician and liar, then the first inhabitant would not be a politician.", "category": "Logic", "date": "02/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are traveling around the world and you discover a unique island. You learn that the inhabitants of this island possess very unique qualities. First of all, all politicians are liars, and always lie. The inhabitants that are not politicians always tell the truth. When you meet the first inhabitant you ask him if he is a politician, he answers. Upon meeting the second inhabitant, he claims that the first inhabitant denied being a politician. The third inhabitant states that the first inhabitant is, indeed, a politician. \r\nHow many politicians have you encountered?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 politician.\r\nThe first inhabitant will deny being a politician if he is a politician or if he is not a politician.\r\nTherefore, the second inhabitant is not a politician because the first inhabitant did in fact deny being a politician.\r\nIf the third inhabitant is not a politician and is truthful, then the first inhabitant is a politician. \r\nIf the third inhabitant is a politician and liar, then the first inhabitant would not be a politician.\n<|im_start|>answer\n1 politician.\r\nThe first inhabitant will deny being a politician if he is a politician or if he is not a politician.\r\nTherefore, the second inhabitant is not a politician because the first inhabitant did in fact deny being a politician.\r\nIf the third inhabitant is not a politician and is truthful, then the first inhabitant is a politician. \r\nIf the third inhabitant is a politician and liar, then the first inhabitant would not be a politician.\n<|im_end|>" }, { "id": "#2073", "title": "Alone in a Cottage", "fun": 2.7, "difficulty": 1.72, "author": "Cascas", "desc": "A wealthy man lives alone in a small cottage. Being partially handicapped he had everything delivered to his cottage. The mailman was delivering a letter one Thursday when he noticed that the front door was ajar. Through the opening he could see the man's body lying in a pool of dried blood. When a police officer arrived he surveyed the scene. On the porch were two bottles of warm milk, Monday's newspaper, a catalog, flyers, and unopened mail. The police officer suspects it was foul play. Who does he suspect and why?", "hint": "No hint available.", "answer": "The police officer suspects the newspaper delivery person. The absence of Tuesday's and Wednesday's newspaper indicates that the delivery person knew there was no one there to read it.", "category": "Logic", "date": "01/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA wealthy man lives alone in a small cottage. Being partially handicapped he had everything delivered to his cottage. The mailman was delivering a letter one Thursday when he noticed that the front door was ajar. Through the opening he could see the man's body lying in a pool of dried blood. When a police officer arrived he surveyed the scene. On the porch were two bottles of warm milk, Monday's newspaper, a catalog, flyers, and unopened mail. The police officer suspects it was foul play. Who does he suspect and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe police officer suspects the newspaper delivery person. The absence of Tuesday's and Wednesday's newspaper indicates that the delivery person knew there was no one there to read it.\n<|im_start|>answer\nThe police officer suspects the newspaper delivery person. The absence of Tuesday's and Wednesday's newspaper indicates that the delivery person knew there was no one there to read it.\n<|im_end|>" }, { "id": "#33499", "title": "Naughts & Crosses", "fun": 2.7, "difficulty": 1.3, "author": "grungy49", "desc": "Sally and Sully are playing a special version of naughts and crosses. They must each draw up a naughts and crosses board with every square filled with either a naught (O) or a cross (X). Then they must each give clues and the other person had to guess the exact placings of the X's and the O's.\n\r\nIt is Sally's turn and Sully is giving clues. Can you figure it out for Sally?\n\r\nNOTE: It is a standard naughts and crosses board, so it will be like this.\n\r\n? ? ?\r\n? ? ?\r\n? ? ?\n\r\nOr a coordinate version: \n\r\n1,1 2,1 3,1\r\n1,2 2,2 3,2\r\n1,3 2,3 3,3\n\r\nOk, let's get started.\r\n_____________________________\n\r\n1. There is an O in the very middle (2,2).\n\r\n2. There are three X's surrounding the middle square (not including diagonals).\n\r\n3. There are 4 X's and 5 O's on the board.\n\r\n4. The bottom right square (3,3) contains an X.\n\r\n5. There is not an X on the bottom row in the middle (2,3).", "hint": "Go ahead - draw up a naughts and crosses board!", "answer": "The board should look like this.\n\r\nO X O\r\nX O X\r\nO O X\n\r\nAfter the first clue, all you know is that O is in the middle.\n\r\n? ? ?\r\n? O ?\r\n? ? ? \n\r\nAt this point, clues 2 and 3 are useless.\n\r\nClue 4 says that the bottom right square contains an X.\n\r\nNow your board should look like this:\n\r\n? ? ?\r\n? O ?\r\n? ? X\n\r\nClue 5 says there is no X at 2,3.\n\r\nThe board should look like this:\n\r\n? ? ?\r\n? O ?\r\n? O X\n\r\nNow you can come back to clue 2.\n\r\nSince there are three X's surrounding the middle square (no diagonals, the X's must go in these three places:\n\r\n? X ?\r\nX O X\r\n? O X\n\r\nClue 3 says that there are only 4 X's on the board - there are 4 X's on the board at that point so the rest must be O's.\n\r\nO X O\r\nX O X\r\nO O X\n\r\nSo - Sally ended up winning, because she found out the placings of Sully's board in lightning quick speed thanks to you! Way to go!", "category": "Logic", "date": "10/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally and Sully are playing a special version of naughts and crosses. They must each draw up a naughts and crosses board with every square filled with either a naught (O) or a cross (X). Then they must each give clues and the other person had to guess the exact placings of the X's and the O's.\n\r\nIt is Sally's turn and Sully is giving clues. Can you figure it out for Sally?\n\r\nNOTE: It is a standard naughts and crosses board, so it will be like this.\n\r\n? ? ?\r\n? ? ?\r\n? ? ?\n\r\nOr a coordinate version: \n\r\n1,1 2,1 3,1\r\n1,2 2,2 3,2\r\n1,3 2,3 3,3\n\r\nOk, let's get started.\r\n_____________________________\n\r\n1. There is an O in the very middle (2,2).\n\r\n2. There are three X's surrounding the middle square (not including diagonals).\n\r\n3. There are 4 X's and 5 O's on the board.\n\r\n4. The bottom right square (3,3) contains an X.\n\r\n5. There is not an X on the bottom row in the middle (2,3).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe board should look like this.\n\r\nO X O\r\nX O X\r\nO O X\n\r\nAfter the first clue, all you know is that O is in the middle.\n\r\n? ? ?\r\n? O ?\r\n? ? ? \n\r\nAt this point, clues 2 and 3 are useless.\n\r\nClue 4 says that the bottom right square contains an X.\n\r\nNow your board should look like this:\n\r\n? ? ?\r\n? O ?\r\n? ? X\n\r\nClue 5 says there is no X at 2,3.\n\r\nThe board should look like this:\n\r\n? ? ?\r\n? O ?\r\n? O X\n\r\nNow you can come back to clue 2.\n\r\nSince there are three X's surrounding the middle square (no diagonals, the X's must go in these three places:\n\r\n? X ?\r\nX O X\r\n? O X\n\r\nClue 3 says that there are only 4 X's on the board - there are 4 X's on the board at that point so the rest must be O's.\n\r\nO X O\r\nX O X\r\nO O X\n\r\nSo - Sally ended up winning, because she found out the placings of Sully's board in lightning quick speed thanks to you! Way to go!\n<|im_start|>answer\nThe board should look like this.\n\r\nO X O\r\nX O X\r\nO O X\n\r\nAfter the first clue, all you know is that O is in the middle.\n\r\n? ? ?\r\n? O ?\r\n? ? ? \n\r\nAt this point, clues 2 and 3 are useless.\n\r\nClue 4 says that the bottom right square contains an X.\n\r\nNow your board should look like this:\n\r\n? ? ?\r\n? O ?\r\n? ? X\n\r\nClue 5 says there is no X at 2,3.\n\r\nThe board should look like this:\n\r\n? ? ?\r\n? O ?\r\n? O X\n\r\nNow you can come back to clue 2.\n\r\nSince there are three X's surrounding the middle square (no diagonals, the X's must go in these three places:\n\r\n? X ?\r\nX O X\r\n? O X\n\r\nClue 3 says that there are only 4 X's on the board - there are 4 X's on the board at that point so the rest must be O's.\n\r\nO X O\r\nX O X\r\nO O X\n\r\nSo - Sally ended up winning, because she found out the placings of Sully's board in lightning quick speed thanks to you! Way to go!\n<|im_end|>" }, { "id": "#10475", "title": "Trip to Boston", "fun": 2.7, "difficulty": 1.71, "author": "Bobbrt", "desc": "Glenn and Steve took turns driving on a trip to Boston and back. Glenn drove the first 40 miles and Steve drove the rest of the way to Boston. On the way back, Glenn started to drive, and then Steve drove the last 50 miles.\n\r\nWhich of the two drove more, and how much more did he drive?", "hint": "No hint available.", "answer": "Steve drove 20 miles more than Glenn, no matter how far the trip to Boston was. It's probably easiest to just try this with numbers:\n\r\nAssume the trip to Boston is 60 miles:\n\r\nGlenn: 40 miles there and 10 miles back for 50 miles total.\r\nSteve: 20 miles there and 50 miles back for 70 miles total.\r\nSteve drives 20 more miles. If you change the number of miles, you'll still get a 20-mile difference.", "category": "Math", "date": "02/15/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGlenn and Steve took turns driving on a trip to Boston and back. Glenn drove the first 40 miles and Steve drove the rest of the way to Boston. On the way back, Glenn started to drive, and then Steve drove the last 50 miles.\n\r\nWhich of the two drove more, and how much more did he drive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSteve drove 20 miles more than Glenn, no matter how far the trip to Boston was. It's probably easiest to just try this with numbers:\n\r\nAssume the trip to Boston is 60 miles:\n\r\nGlenn: 40 miles there and 10 miles back for 50 miles total.\r\nSteve: 20 miles there and 50 miles back for 70 miles total.\r\nSteve drives 20 more miles. If you change the number of miles, you'll still get a 20-mile difference.\n<|im_start|>answer\nSteve drove 20 miles more than Glenn, no matter how far the trip to Boston was. It's probably easiest to just try this with numbers:\n\r\nAssume the trip to Boston is 60 miles:\n\r\nGlenn: 40 miles there and 10 miles back for 50 miles total.\r\nSteve: 20 miles there and 50 miles back for 70 miles total.\r\nSteve drives 20 more miles. If you change the number of miles, you'll still get a 20-mile difference.\n<|im_end|>" }, { "id": "#27797", "title": "Competitive Clowns", "fun": 2.7, "difficulty": 2.33, "author": "peppamintp", "desc": "Many contestants entered the unicycle race, but only the best multi-tasking clown came out on top, considering that each had to juggle clubs while trying to win the race! Most of the pack were soon disqualified after dropping a club or falling off the unicycle. In the end, four of the best clowns crossed the finish line. From this information and the clues below, can you determine each clown's full (real) name, club color (one is silver), and placement?\n\r\nPlaces: 1st, 2nd, 3rd, 4th\r\nFirst Names: Kyle, Matt, Jake, Leon\r\nSurnames: Turner, Pettle, Vertigo, Wheeley\r\nColors: Green, Orange, Silver, Red\n\n\r\n1. Mr. Turner (who isn't Matt) finished one place ahead of the red club juggler.\n\r\n2. The four are Leon, Mr. Vertigo, the one who juggled with orange clubs, and the one who came in third place.\n\r\n3. Kyle finished behind (but not one place behind) Mr. Wheeley.\n\r\n4. Matt and Mr. Pettle finished consecutively, in some order.\n\r\n5. The one who juggled with green clubs finished two places behind Jake.", "hint": "No hint available.", "answer": "1st Place - Leon Wheeley - Silver\r\n2nd Place - Jake Turner - Orange\r\n3rd Place - Kyle Pettle - Red\r\n4th Place - Matt Vertigo - Green\n\r\nThe third place finisher wasn't Vertigo (clue 2) or Wheeley (clue 3), so he is Pettle or Turner.\r\nSince Matt is neither Turner (clue 1) nor Pettle (clue 4), he didn't finish third.\r\nThe one who came in third wasn't Leon (clue 2) or Jake (clue 5), so he is Kyle.\r\nBy clue 3, Wheeley came in first.\r\nSince neither Turner (clue 1) nor Pettle (clue 4) finished fourth, Vertigo did.\r\nVertigo isn't Leon (clue 2) or Jake (clue 5), so he's Matt. \r\nBy clue 4, Kyle is Pettle.\r\nBy elimination, Turner finished second. \r\nBy clue 1, the one with the red clubs finished third. \r\nSince Jake finished two places ahead of the one who had the green clubs (clue 5), Jake finished second and Matt used the green clubs.\r\nBy elimination, Leon came in first. By clue 2, Jake had orange clubs, and Leon had the silver ones.", "category": "Logic", "date": "12/31/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMany contestants entered the unicycle race, but only the best multi-tasking clown came out on top, considering that each had to juggle clubs while trying to win the race! Most of the pack were soon disqualified after dropping a club or falling off the unicycle. In the end, four of the best clowns crossed the finish line. From this information and the clues below, can you determine each clown's full (real) name, club color (one is silver), and placement?\n\r\nPlaces: 1st, 2nd, 3rd, 4th\r\nFirst Names: Kyle, Matt, Jake, Leon\r\nSurnames: Turner, Pettle, Vertigo, Wheeley\r\nColors: Green, Orange, Silver, Red\n\n\r\n1. Mr. Turner (who isn't Matt) finished one place ahead of the red club juggler.\n\r\n2. The four are Leon, Mr. Vertigo, the one who juggled with orange clubs, and the one who came in third place.\n\r\n3. Kyle finished behind (but not one place behind) Mr. Wheeley.\n\r\n4. Matt and Mr. Pettle finished consecutively, in some order.\n\r\n5. The one who juggled with green clubs finished two places behind Jake.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st Place - Leon Wheeley - Silver\r\n2nd Place - Jake Turner - Orange\r\n3rd Place - Kyle Pettle - Red\r\n4th Place - Matt Vertigo - Green\n\r\nThe third place finisher wasn't Vertigo (clue 2) or Wheeley (clue 3), so he is Pettle or Turner.\r\nSince Matt is neither Turner (clue 1) nor Pettle (clue 4), he didn't finish third.\r\nThe one who came in third wasn't Leon (clue 2) or Jake (clue 5), so he is Kyle.\r\nBy clue 3, Wheeley came in first.\r\nSince neither Turner (clue 1) nor Pettle (clue 4) finished fourth, Vertigo did.\r\nVertigo isn't Leon (clue 2) or Jake (clue 5), so he's Matt. \r\nBy clue 4, Kyle is Pettle.\r\nBy elimination, Turner finished second. \r\nBy clue 1, the one with the red clubs finished third. \r\nSince Jake finished two places ahead of the one who had the green clubs (clue 5), Jake finished second and Matt used the green clubs.\r\nBy elimination, Leon came in first. By clue 2, Jake had orange clubs, and Leon had the silver ones.\n<|im_start|>answer\n1st Place - Leon Wheeley - Silver\r\n2nd Place - Jake Turner - Orange\r\n3rd Place - Kyle Pettle - Red\r\n4th Place - Matt Vertigo - Green\n\r\nThe third place finisher wasn't Vertigo (clue 2) or Wheeley (clue 3), so he is Pettle or Turner.\r\nSince Matt is neither Turner (clue 1) nor Pettle (clue 4), he didn't finish third.\r\nThe one who came in third wasn't Leon (clue 2) or Jake (clue 5), so he is Kyle.\r\nBy clue 3, Wheeley came in first.\r\nSince neither Turner (clue 1) nor Pettle (clue 4) finished fourth, Vertigo did.\r\nVertigo isn't Leon (clue 2) or Jake (clue 5), so he's Matt. \r\nBy clue 4, Kyle is Pettle.\r\nBy elimination, Turner finished second. \r\nBy clue 1, the one with the red clubs finished third. \r\nSince Jake finished two places ahead of the one who had the green clubs (clue 5), Jake finished second and Matt used the green clubs.\r\nBy elimination, Leon came in first. By clue 2, Jake had orange clubs, and Leon had the silver ones.\n<|im_end|>" }, { "id": "#14568", "title": "100 Camels", "fun": 2.7, "difficulty": 1.65, "author": "jubjub", "desc": "\"That Sam is one rich man!\" muttered Tom. \"As a matter of fact, he owns 100 or more camels.\"\r\n\"Not a chance,\" replied John, \"I know for a fact he owns fewer than 100 camels.\"\r\nFrank joined in, \"Well, he owns at least one camel.\"\n\r\nIf only one of their statements is true, how many camels does Sam own?", "hint": "No hint available.", "answer": "Sam doesn't own any camels. If the first statement is true then the last is true as well. If the last is true then so is either the first or the second statement. But if the second is true, the first and last aren't necessarily true. Sam can own no camels, making the first and third false, but the second statement true. Since only one can be true, the second is true. He owns zero camels.", "category": "Logic", "date": "08/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"That Sam is one rich man!\" muttered Tom. \"As a matter of fact, he owns 100 or more camels.\"\r\n\"Not a chance,\" replied John, \"I know for a fact he owns fewer than 100 camels.\"\r\nFrank joined in, \"Well, he owns at least one camel.\"\n\r\nIf only one of their statements is true, how many camels does Sam own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSam doesn't own any camels. If the first statement is true then the last is true as well. If the last is true then so is either the first or the second statement. But if the second is true, the first and last aren't necessarily true. Sam can own no camels, making the first and third false, but the second statement true. Since only one can be true, the second is true. He owns zero camels.\n<|im_start|>answer\nSam doesn't own any camels. If the first statement is true then the last is true as well. If the last is true then so is either the first or the second statement. But if the second is true, the first and last aren't necessarily true. Sam can own no camels, making the first and third false, but the second statement true. Since only one can be true, the second is true. He owns zero camels.\n<|im_end|>" }, { "id": "#30010", "title": "The Total is 14, Part III", "fun": 2.7, "difficulty": 2.7, "author": "tsimkin", "desc": "Mr. Simkin, the new math teacher at school, was impressed by his students' ability to solve logic puzzles. He pulled aside three more students, and handed them each a sealed envelope with a number written inside. He told them that they each have a positive integer, and the sum of their numbers was 14.\n\r\nManny, Moe, and Jack each opened their envelopes. Mr. Simkin asks Manny if he knows anything about the numbers the other two are holding, and Manny says, \"I know that Moe and Jack are holding different numbers.\"\n\r\nMoe answers, \"IN THAT CASE, I know that all three of our numbers are different.\"\n\r\nJack thinks for a bit, and then says, \"Now I know all of our numbers.\"\n\r\nMr. Simkin turns to the class and asks if anyone in the class knows the numbers. Gretchen's hand shoots up into the air, and after waiting for a while to see if anyone else will get the answer, Mr. Simkin calls on Gretchen.\n\r\nWhat numbers does she say they each are holding?", "hint": "No hint available.", "answer": "Manny has a 3, Moe has a 2, and Jack has a 9.\n\r\nFrom Manny's statement, we can deduce that his number is odd. Since Moe did not know that they were all different until Manny said that, we know that Moe is not holding a 7, 9, or 11. (Otherwise, he would have already known they were all different.) If he were holding a 1, 3, or 5, he would not be able to be sure his number was different than Manny's. If he were holding a 4, 8, or 12, he could not know that Manny and Jack didn't have the same number, since there are odd pairs that would bring the total to 14. Therefore, Moe must be holding a 2, 6, or 10.\n\r\nThere are 12 triples for (Manny, Moe, Jack) that satisfy all three statements. They are:\r\n(1, 2, 11)\r\n(1, 6, 7)\r\n(1, 10, 3)\r\n(3, 2, 9)\r\n(3, 6, 5)\r\n(3, 10, 1)\r\n(5, 2, 7)\r\n(5, 6, 3)\r\n(7, 2, 5)\r\n(7, 6, 1)\r\n(9, 2, 3)\r\n(11, 2, 1)\n\r\nSince Jack can reason flawlessly, he knows these are the possibilities. In order to make his statement, his number has to be a unique solution. Therefore, he must be holding a 9 or an 11. If he were holding 11, though, he would have known from Manny's statement that Manny had a 1, Moe had a 2, and he had an 11. Since he didn't know them all until after Moe spoke, he must have a 9, leaving Manny a 3 and Moe a 2.\n\r\nMr. Simkin suggests to Gretchen that she may have a career in law enforcement if she can further hone these impressive deductive reasoning skills.", "category": "Logic", "date": "04/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Simkin, the new math teacher at school, was impressed by his students' ability to solve logic puzzles. He pulled aside three more students, and handed them each a sealed envelope with a number written inside. He told them that they each have a positive integer, and the sum of their numbers was 14.\n\r\nManny, Moe, and Jack each opened their envelopes. Mr. Simkin asks Manny if he knows anything about the numbers the other two are holding, and Manny says, \"I know that Moe and Jack are holding different numbers.\"\n\r\nMoe answers, \"IN THAT CASE, I know that all three of our numbers are different.\"\n\r\nJack thinks for a bit, and then says, \"Now I know all of our numbers.\"\n\r\nMr. Simkin turns to the class and asks if anyone in the class knows the numbers. Gretchen's hand shoots up into the air, and after waiting for a while to see if anyone else will get the answer, Mr. Simkin calls on Gretchen.\n\r\nWhat numbers does she say they each are holding?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nManny has a 3, Moe has a 2, and Jack has a 9.\n\r\nFrom Manny's statement, we can deduce that his number is odd. Since Moe did not know that they were all different until Manny said that, we know that Moe is not holding a 7, 9, or 11. (Otherwise, he would have already known they were all different.) If he were holding a 1, 3, or 5, he would not be able to be sure his number was different than Manny's. If he were holding a 4, 8, or 12, he could not know that Manny and Jack didn't have the same number, since there are odd pairs that would bring the total to 14. Therefore, Moe must be holding a 2, 6, or 10.\n\r\nThere are 12 triples for (Manny, Moe, Jack) that satisfy all three statements. They are:\r\n(1, 2, 11)\r\n(1, 6, 7)\r\n(1, 10, 3)\r\n(3, 2, 9)\r\n(3, 6, 5)\r\n(3, 10, 1)\r\n(5, 2, 7)\r\n(5, 6, 3)\r\n(7, 2, 5)\r\n(7, 6, 1)\r\n(9, 2, 3)\r\n(11, 2, 1)\n\r\nSince Jack can reason flawlessly, he knows these are the possibilities. In order to make his statement, his number has to be a unique solution. Therefore, he must be holding a 9 or an 11. If he were holding 11, though, he would have known from Manny's statement that Manny had a 1, Moe had a 2, and he had an 11. Since he didn't know them all until after Moe spoke, he must have a 9, leaving Manny a 3 and Moe a 2.\n\r\nMr. Simkin suggests to Gretchen that she may have a career in law enforcement if she can further hone these impressive deductive reasoning skills.\n<|im_start|>answer\nManny has a 3, Moe has a 2, and Jack has a 9.\n\r\nFrom Manny's statement, we can deduce that his number is odd. Since Moe did not know that they were all different until Manny said that, we know that Moe is not holding a 7, 9, or 11. (Otherwise, he would have already known they were all different.) If he were holding a 1, 3, or 5, he would not be able to be sure his number was different than Manny's. If he were holding a 4, 8, or 12, he could not know that Manny and Jack didn't have the same number, since there are odd pairs that would bring the total to 14. Therefore, Moe must be holding a 2, 6, or 10.\n\r\nThere are 12 triples for (Manny, Moe, Jack) that satisfy all three statements. They are:\r\n(1, 2, 11)\r\n(1, 6, 7)\r\n(1, 10, 3)\r\n(3, 2, 9)\r\n(3, 6, 5)\r\n(3, 10, 1)\r\n(5, 2, 7)\r\n(5, 6, 3)\r\n(7, 2, 5)\r\n(7, 6, 1)\r\n(9, 2, 3)\r\n(11, 2, 1)\n\r\nSince Jack can reason flawlessly, he knows these are the possibilities. In order to make his statement, his number has to be a unique solution. Therefore, he must be holding a 9 or an 11. If he were holding 11, though, he would have known from Manny's statement that Manny had a 1, Moe had a 2, and he had an 11. Since he didn't know them all until after Moe spoke, he must have a 9, leaving Manny a 3 and Moe a 2.\n\r\nMr. Simkin suggests to Gretchen that she may have a career in law enforcement if she can further hone these impressive deductive reasoning skills.\n<|im_end|>" }, { "id": "#19781", "title": "Tracking Time", "fun": 2.7, "difficulty": 2.17, "author": "Zinzey16", "desc": "Ramik was asked how he spends his time during the week, starting from the time he gets home from school at 3:00 P.M., until he goes to bed at 10:00 P.M. He listed his weekly after-school activities as:\n\r\n1. homework, studying, or reading \r\n2. spending time with friends \r\n3. eating \r\n4. chores \r\n5. music lessons \r\n6. soccer \n\r\nHe observed that:\n\r\n1. He spends 50% of his time doing homework, studying, or reading. \r\n2. He spends 1/3 as much time doing chores as he does eating. \r\n3. The amount of time he spends on music lessons equals 50% of the time he devotes to soccer each week. \r\n4. Soccer practices are scheduled twice a week for 2 1/2 hours each time. \r\n5. Each week, the amount of time he spends eating and doing chores combined equals the amount of time he spends on soccer. \r\n6. The rest of his free time is spent with friends. \n\r\nOn average, how much time daily, in hours and minutes, does Ramik spend on each activity? \n\r\nFor next week, if he reduces the amount of time he spends with friends by 50%, will he have enough time to fit in another soccer practice without taking any time from any other activities?", "hint": "No hint available.", "answer": "On average, Ramik spends the following amount of time, daily, on each of these activities:\n\r\n1. homework, studying, or reading: 3 hours, 30 minutes \r\n2. free time with friends: 1 hour \r\n3. eating: 45 minutes \r\n4. chores: 15 minutes \r\n5. music lessons: 30 minutes \r\n6. soccer: 1 hour \n\r\nIf Ramik reduces the amount of time he spends with friends by 50% next week, he will have just enough time (2 1/2 hours) for an additional soccer practice.", "category": "Logic", "date": "12/08/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRamik was asked how he spends his time during the week, starting from the time he gets home from school at 3:00 P.M., until he goes to bed at 10:00 P.M. He listed his weekly after-school activities as:\n\r\n1. homework, studying, or reading \r\n2. spending time with friends \r\n3. eating \r\n4. chores \r\n5. music lessons \r\n6. soccer \n\r\nHe observed that:\n\r\n1. He spends 50% of his time doing homework, studying, or reading. \r\n2. He spends 1/3 as much time doing chores as he does eating. \r\n3. The amount of time he spends on music lessons equals 50% of the time he devotes to soccer each week. \r\n4. Soccer practices are scheduled twice a week for 2 1/2 hours each time. \r\n5. Each week, the amount of time he spends eating and doing chores combined equals the amount of time he spends on soccer. \r\n6. The rest of his free time is spent with friends. \n\r\nOn average, how much time daily, in hours and minutes, does Ramik spend on each activity? \n\r\nFor next week, if he reduces the amount of time he spends with friends by 50%, will he have enough time to fit in another soccer practice without taking any time from any other activities?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn average, Ramik spends the following amount of time, daily, on each of these activities:\n\r\n1. homework, studying, or reading: 3 hours, 30 minutes \r\n2. free time with friends: 1 hour \r\n3. eating: 45 minutes \r\n4. chores: 15 minutes \r\n5. music lessons: 30 minutes \r\n6. soccer: 1 hour \n\r\nIf Ramik reduces the amount of time he spends with friends by 50% next week, he will have just enough time (2 1/2 hours) for an additional soccer practice.\n<|im_start|>answer\nOn average, Ramik spends the following amount of time, daily, on each of these activities:\n\r\n1. homework, studying, or reading: 3 hours, 30 minutes \r\n2. free time with friends: 1 hour \r\n3. eating: 45 minutes \r\n4. chores: 15 minutes \r\n5. music lessons: 30 minutes \r\n6. soccer: 1 hour \n\r\nIf Ramik reduces the amount of time he spends with friends by 50% next week, he will have just enough time (2 1/2 hours) for an additional soccer practice.\n<|im_end|>" }, { "id": "#29985", "title": "192, 384, 576", "fun": 2.7, "difficulty": 2.6, "author": "kiss", "desc": "There are four three-digit numbers that share this property: the number itself, its double and its triple contain each digit from 1 to 9 exactly once. For example, 192 is one of them because 192, 384, 576 contain 1 to 9 each once. 273 is another one of them because 273, 546, 819 contain 1 to 9 each once.\n\r\nCan you find the other two numbers that also have this property?", "hint": "Yes, it's EASIER than you think.", "answer": "219 and 327.\n\r\nJust swap 19 and 2, swap 27 and 3, and you'll get them.", "category": "Math", "date": "04/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four three-digit numbers that share this property: the number itself, its double and its triple contain each digit from 1 to 9 exactly once. For example, 192 is one of them because 192, 384, 576 contain 1 to 9 each once. 273 is another one of them because 273, 546, 819 contain 1 to 9 each once.\n\r\nCan you find the other two numbers that also have this property?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n219 and 327.\n\r\nJust swap 19 and 2, swap 27 and 3, and you'll get them.\n<|im_start|>answer\n219 and 327.\n\r\nJust swap 19 and 2, swap 27 and 3, and you'll get them.\n<|im_end|>" }, { "id": "#52093", "title": "Mama's Best", "fun": 2.7, "difficulty": 1.99, "author": "wimpykidfan37", "desc": "Five recipes were printed in last year's January/February issue of \"Ingestion Weekly\" magazine. Each recipe was submitted by a different person, invented by a different female relative of that person, and each person has a different occupation. The five people are two women named Audrey and Brenda and three men named Carl, Dan, and Edgar. Here are some facts:\n\r\n1. Edgar is the police officer. Brenda isn't the firefighter.\n\r\n2. Dan (whose recipe was invented by his cousin) is neither the electrician nor the surgeon (who submitted the recipe for pancakes).\n\r\n3. Carl isn't the man whose recipe was invented by his sister. The sister isn't the one who invented the turkey scallopine recipe.\n\r\n4. Audrey, who isn't the one whose recipe was invented by his or her grandmother, submitted the sausage casserole recipe.\n\r\n5. The one who submitted his or her mother's quiche recipe, who isn't Carl, isn't the electrician.\n\r\nThe question is:\n\r\nWho submitted the calzones recipe, whose recipe was invented by his or her aunt, and who is the plumber?", "hint": "No hint available.", "answer": "Edgar submitted the calzones recipe, Audrey submitted her aunt's recipe, and Brenda is the plumber. \n\r\nThe only possible scenario is:\n\r\nAudrey the electrician submitted her aunt's recipe for sausage casserole.\r\nBrenda the plumber submitted her mother's recipe for quiche.\r\nCarl the surgeon submitted his grandmother's recipe for pancakes.\r\nDan the firefighter submitted his cousin's recipe for turkey scallopine.\r\nEdgar the police officer submitted his sister's recipe for calzones.", "category": "Logic-Grid", "date": "12/04/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive recipes were printed in last year's January/February issue of \"Ingestion Weekly\" magazine. Each recipe was submitted by a different person, invented by a different female relative of that person, and each person has a different occupation. The five people are two women named Audrey and Brenda and three men named Carl, Dan, and Edgar. Here are some facts:\n\r\n1. Edgar is the police officer. Brenda isn't the firefighter.\n\r\n2. Dan (whose recipe was invented by his cousin) is neither the electrician nor the surgeon (who submitted the recipe for pancakes).\n\r\n3. Carl isn't the man whose recipe was invented by his sister. The sister isn't the one who invented the turkey scallopine recipe.\n\r\n4. Audrey, who isn't the one whose recipe was invented by his or her grandmother, submitted the sausage casserole recipe.\n\r\n5. The one who submitted his or her mother's quiche recipe, who isn't Carl, isn't the electrician.\n\r\nThe question is:\n\r\nWho submitted the calzones recipe, whose recipe was invented by his or her aunt, and who is the plumber?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEdgar submitted the calzones recipe, Audrey submitted her aunt's recipe, and Brenda is the plumber. \n\r\nThe only possible scenario is:\n\r\nAudrey the electrician submitted her aunt's recipe for sausage casserole.\r\nBrenda the plumber submitted her mother's recipe for quiche.\r\nCarl the surgeon submitted his grandmother's recipe for pancakes.\r\nDan the firefighter submitted his cousin's recipe for turkey scallopine.\r\nEdgar the police officer submitted his sister's recipe for calzones.\n<|im_start|>answer\nEdgar submitted the calzones recipe, Audrey submitted her aunt's recipe, and Brenda is the plumber. \n\r\nThe only possible scenario is:\n\r\nAudrey the electrician submitted her aunt's recipe for sausage casserole.\r\nBrenda the plumber submitted her mother's recipe for quiche.\r\nCarl the surgeon submitted his grandmother's recipe for pancakes.\r\nDan the firefighter submitted his cousin's recipe for turkey scallopine.\r\nEdgar the police officer submitted his sister's recipe for calzones.\n<|im_end|>" }, { "id": "#27088", "title": "Teasergle III", "fun": 2.69, "difficulty": 1.71, "author": "phrebh", "desc": "Four online friends, two girls (Blondula and Sassi) and two guys (Swig and Tinman) like to spend time on the same brain teaser oriented site, Teasergle. Each of them likes to play different forum games (Hangman, Mad Gab, Name One Thing About The Person Above You (NOTAPAY), and Picnic) and each of them like to use different smilies in all of their posts (:?, :D, :P, LOL). One day they all were online playing their games and they each kept using the same words in their posts, over and over again (Cake, Diamond, Goat, Speedo). Using the clues below, can you determine who likes to play what forum game, what smilie they use, and what word they kept using?\n\r\n1. The four people are Swig, the girl who likes :P, the person who kept writing Speedo, and the person who used :D.\r\n2. The four games are Picnic, the game that Blondula plays, the game that Tinman plays, and the game that sees a lot of LOLs.\r\n3. The four smilies are :?, the one that Swig uses in NOTAPAY, the one that has been recently been seen with Goat, and the one used by the guy who kept using Diamond.\r\n4. The four words are Cake, the one a girl was using in Picnic, the one being used in Hangman, and Speedo.", "hint": "No hint available.", "answer": "Blondula plays Mad Gab, likes :?, and was hooked on Speedo.\r\nSassi plays Picnic, likes :P, and was hooked on Goat.\r\nSwig plays Notapay, likes LOL, and was hooked on Cake.\r\nTinman plays Hangman, likes :D, and was hooked on Diamond.", "category": "Logic-Grid", "date": "11/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour online friends, two girls (Blondula and Sassi) and two guys (Swig and Tinman) like to spend time on the same brain teaser oriented site, Teasergle. Each of them likes to play different forum games (Hangman, Mad Gab, Name One Thing About The Person Above You (NOTAPAY), and Picnic) and each of them like to use different smilies in all of their posts (:?, :D, :P, LOL). One day they all were online playing their games and they each kept using the same words in their posts, over and over again (Cake, Diamond, Goat, Speedo). Using the clues below, can you determine who likes to play what forum game, what smilie they use, and what word they kept using?\n\r\n1. The four people are Swig, the girl who likes :P, the person who kept writing Speedo, and the person who used :D.\r\n2. The four games are Picnic, the game that Blondula plays, the game that Tinman plays, and the game that sees a lot of LOLs.\r\n3. The four smilies are :?, the one that Swig uses in NOTAPAY, the one that has been recently been seen with Goat, and the one used by the guy who kept using Diamond.\r\n4. The four words are Cake, the one a girl was using in Picnic, the one being used in Hangman, and Speedo.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlondula plays Mad Gab, likes :?, and was hooked on Speedo.\r\nSassi plays Picnic, likes :P, and was hooked on Goat.\r\nSwig plays Notapay, likes LOL, and was hooked on Cake.\r\nTinman plays Hangman, likes :D, and was hooked on Diamond.\n<|im_start|>answer\nBlondula plays Mad Gab, likes :?, and was hooked on Speedo.\r\nSassi plays Picnic, likes :P, and was hooked on Goat.\r\nSwig plays Notapay, likes LOL, and was hooked on Cake.\r\nTinman plays Hangman, likes :D, and was hooked on Diamond.\n<|im_end|>" }, { "id": "#24164", "title": "Cafeteria Capacity", "fun": 2.69, "difficulty": 2.56, "author": "flirtmaster123", "desc": "The Madison School has a new cafeteria with very artistic, new tables for its 375 students. Besides the big round tables, some tables are octagons, pentagons, hexagons or squares. The students eat lunch in 3 shifts, with an equal number of students dining during each lunch period. Because the cafeteria is new, they've allowed extra space in case there are more students in the future. Right now, there are 47 empty seats during each lunch period.\n\n\r\nEach round table seats ten students. Each of the other types of tables can seat one student on each side. \r\nThere are at least 4 tables of each shape. \r\nThe same total number of students can be seated at the square tables as at the pentagons, but there are more square tables than pentagons. \r\nThe total number of students who can be seated at round tables is equal to the total number of students at the square and pentagon shaped tables combined. \r\nThere are more octagonal tables than any other shape. \r\nThere is a total of 4 fewer places at the hexagons than at the round tables. \n\r\nHow many tables are there of each shape?", "hint": "Make a chart, and then guess and check to calculate the total number of places at each type of table.", "answer": "There are 4 round tables, 7 octagonal tables, 6 hexagonal tables, 4 pentagonal tables, and 5 square tables.\n\r\nTable Shape Number of Tables Number of Seats Total Seats \n\r\nsquare 5 4 20 \r\npentagon 4 5 20 \r\nhexagon 6 6 36 \r\noctagon 7 8 56 \r\nround 4 10 40 \r\nTotal places 172", "category": "Math", "date": "06/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Madison School has a new cafeteria with very artistic, new tables for its 375 students. Besides the big round tables, some tables are octagons, pentagons, hexagons or squares. The students eat lunch in 3 shifts, with an equal number of students dining during each lunch period. Because the cafeteria is new, they've allowed extra space in case there are more students in the future. Right now, there are 47 empty seats during each lunch period.\n\n\r\nEach round table seats ten students. Each of the other types of tables can seat one student on each side. \r\nThere are at least 4 tables of each shape. \r\nThe same total number of students can be seated at the square tables as at the pentagons, but there are more square tables than pentagons. \r\nThe total number of students who can be seated at round tables is equal to the total number of students at the square and pentagon shaped tables combined. \r\nThere are more octagonal tables than any other shape. \r\nThere is a total of 4 fewer places at the hexagons than at the round tables. \n\r\nHow many tables are there of each shape?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 4 round tables, 7 octagonal tables, 6 hexagonal tables, 4 pentagonal tables, and 5 square tables.\n\r\nTable Shape Number of Tables Number of Seats Total Seats \n\r\nsquare 5 4 20 \r\npentagon 4 5 20 \r\nhexagon 6 6 36 \r\noctagon 7 8 56 \r\nround 4 10 40 \r\nTotal places 172\n<|im_start|>answer\nThere are 4 round tables, 7 octagonal tables, 6 hexagonal tables, 4 pentagonal tables, and 5 square tables.\n\r\nTable Shape Number of Tables Number of Seats Total Seats \n\r\nsquare 5 4 20 \r\npentagon 4 5 20 \r\nhexagon 6 6 36 \r\noctagon 7 8 56 \r\nround 4 10 40 \r\nTotal places 172\n<|im_end|>" }, { "id": "#2262", "title": "Thief in the Apartment", "fun": 2.69, "difficulty": 1.41, "author": "silverradiance", "desc": "The keeper of an apartment has reasons to believe that a thief is lurking around in his apartment. He decides to invite a detective over to his apartment for further investigation on the thief. The detective then is one day pondering in his room when a knock on the door was heard. A man walked in and said \"Oops, I thought this was my room, sorry,\" and left. The detective immediately arrested the man. Why?", "hint": "No hint available.", "answer": "Why would anyone knock on their own door?", "category": "Logic", "date": "02/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe keeper of an apartment has reasons to believe that a thief is lurking around in his apartment. He decides to invite a detective over to his apartment for further investigation on the thief. The detective then is one day pondering in his room when a knock on the door was heard. A man walked in and said \"Oops, I thought this was my room, sorry,\" and left. The detective immediately arrested the man. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhy would anyone knock on their own door?\n<|im_start|>answer\nWhy would anyone knock on their own door?\n<|im_end|>" }, { "id": "#34273", "title": "Find One Get 2 Free", "fun": 2.69, "difficulty": 0.97, "author": "Sherilyn", "desc": "An explorer found three old sacks. The first one was labeled \"Gold.\" The second sack was labeled \"Silver.\" The third sack was labeled \"Diamonds.\" Each sack has been labeled incorrectly. How could the explorer label each sack correctly if he were only allowed to look into one of the sacks?", "hint": "No hint available.", "answer": "The explorer selected the sack labeled \"Gold.\" Inside, he found diamonds. That left 2 sacks labeled \"Silver\" and \"Diamonds\". If diamonds were in the gold sack, that left silver and gold. Since all of the sacks were labeled incorrectly, he knew the answer. Gold had to be in the silver sack, and silver had to be in the diamond sack.", "category": "Logic", "date": "12/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn explorer found three old sacks. The first one was labeled \"Gold.\" The second sack was labeled \"Silver.\" The third sack was labeled \"Diamonds.\" Each sack has been labeled incorrectly. How could the explorer label each sack correctly if he were only allowed to look into one of the sacks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe explorer selected the sack labeled \"Gold.\" Inside, he found diamonds. That left 2 sacks labeled \"Silver\" and \"Diamonds\". If diamonds were in the gold sack, that left silver and gold. Since all of the sacks were labeled incorrectly, he knew the answer. Gold had to be in the silver sack, and silver had to be in the diamond sack.\n<|im_start|>answer\nThe explorer selected the sack labeled \"Gold.\" Inside, he found diamonds. That left 2 sacks labeled \"Silver\" and \"Diamonds\". If diamonds were in the gold sack, that left silver and gold. Since all of the sacks were labeled incorrectly, he knew the answer. Gold had to be in the silver sack, and silver had to be in the diamond sack.\n<|im_end|>" }, { "id": "#6179", "title": "Tricky Tunnel", "fun": 2.69, "difficulty": 1.4, "author": "im_para_noid", "desc": "You are in a tunnel that branches in two directions, like a T. To your left is a door with the enigmatic words: \"Wide ill you\" and \"Wild lie you.\" On the right are the words \"Evil will you\" and \"Veil will you.\" Which door do you choose?", "hint": "No hint available.", "answer": "Go Right. The words on the right door are an anagram of \"You will live.\" and the words on the left door are an anagram of \"You will die.\"", "category": "Logic", "date": "08/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are in a tunnel that branches in two directions, like a T. To your left is a door with the enigmatic words: \"Wide ill you\" and \"Wild lie you.\" On the right are the words \"Evil will you\" and \"Veil will you.\" Which door do you choose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGo Right. The words on the right door are an anagram of \"You will live.\" and the words on the left door are an anagram of \"You will die.\"\n<|im_start|>answer\nGo Right. The words on the right door are an anagram of \"You will live.\" and the words on the left door are an anagram of \"You will die.\"\n<|im_end|>" }, { "id": "#33998", "title": "Top in Tennis", "fun": 2.69, "difficulty": 2.55, "author": "Winner4600", "desc": "One year, tennis fans all over the world saw four players, Federer, Nadal, Hewitt, and Baghdatis, dominate the sport's four biggest events. These men reached either the quarterfinals, semifinals, finals, or won in each of the four Grand Slams. However, due to a glitch in the computer system, officials have lost the specific results and are depending on you to help them out! They can only provide a few facts that they remember. Can you piece together the information?\n\r\nNadal's poorest showing was in Australia.\n\r\nThe four tennis players are: Nadal, the Australian Open semifinalist, the U.S. Open finalist, and the Australian Open champ, who was runner-up at Wimbledon.\n\r\nThe player who finished in the quarters at Roland Garros (in Paris) had the same result at the U.S. Open.\n\r\nFederer won the most Grand Slams.\n\r\nThe semifinalist in France was the quarterfinalist in England.\n\r\nHewitt didn't win any Grand Slams.\n\r\nThe four men are Hewitt, the French Open quarterfinalist, the French Open champion, and the U.S. Open champion.\n\r\nBaghdatis managed to scrape out a win Down Under, while Nadal followed up with a win on clay.", "hint": "The French Open is played on red clay courts.", "answer": "Federer - Semifinalist at Australian Open - Finalist at French Open - Won Wimbledon - Won US Open\n\r\nNadal - Quarterfinalist at Australian Open - Won French Open - Semifinalist at Wimbledon - Semifinalist at US Open\n\r\nHewitt - Finalist at Australian Open - Semifinalist at French Open - Quarterfinalist at Wimbledon - Finalist at US Open\n\r\nBaghdatis - Won Australian Open - Quarterfinalist at French Open - Finalist at Wimbledon - Quarterfinalist at US Open", "category": "Logic-Grid", "date": "11/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne year, tennis fans all over the world saw four players, Federer, Nadal, Hewitt, and Baghdatis, dominate the sport's four biggest events. These men reached either the quarterfinals, semifinals, finals, or won in each of the four Grand Slams. However, due to a glitch in the computer system, officials have lost the specific results and are depending on you to help them out! They can only provide a few facts that they remember. Can you piece together the information?\n\r\nNadal's poorest showing was in Australia.\n\r\nThe four tennis players are: Nadal, the Australian Open semifinalist, the U.S. Open finalist, and the Australian Open champ, who was runner-up at Wimbledon.\n\r\nThe player who finished in the quarters at Roland Garros (in Paris) had the same result at the U.S. Open.\n\r\nFederer won the most Grand Slams.\n\r\nThe semifinalist in France was the quarterfinalist in England.\n\r\nHewitt didn't win any Grand Slams.\n\r\nThe four men are Hewitt, the French Open quarterfinalist, the French Open champion, and the U.S. Open champion.\n\r\nBaghdatis managed to scrape out a win Down Under, while Nadal followed up with a win on clay.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFederer - Semifinalist at Australian Open - Finalist at French Open - Won Wimbledon - Won US Open\n\r\nNadal - Quarterfinalist at Australian Open - Won French Open - Semifinalist at Wimbledon - Semifinalist at US Open\n\r\nHewitt - Finalist at Australian Open - Semifinalist at French Open - Quarterfinalist at Wimbledon - Finalist at US Open\n\r\nBaghdatis - Won Australian Open - Quarterfinalist at French Open - Finalist at Wimbledon - Quarterfinalist at US Open\n<|im_start|>answer\nFederer - Semifinalist at Australian Open - Finalist at French Open - Won Wimbledon - Won US Open\n\r\nNadal - Quarterfinalist at Australian Open - Won French Open - Semifinalist at Wimbledon - Semifinalist at US Open\n\r\nHewitt - Finalist at Australian Open - Semifinalist at French Open - Quarterfinalist at Wimbledon - Finalist at US Open\n\r\nBaghdatis - Won Australian Open - Quarterfinalist at French Open - Finalist at Wimbledon - Quarterfinalist at US Open\n<|im_end|>" }, { "id": "#38712", "title": "Quintuplets 1", "fun": 2.69, "difficulty": 1.6, "author": "BlackBelt", "desc": "May, Jay, Fay, Ray, and Kay are quintuplets who each like different colors and styles of clothes. From each of the clues, determine the color and style that each likes.\n\r\nThe styles of clothes are: Classic, Western, Punk, Casual, and Preppie.\n\r\nThe colors of the clothes are: Purple, Red, Blue, Orange, and Green.\n\r\n1. The one who wears red western clothes is not May, Ray, or Jay.\r\n2. Kay won't wear blue, orange, or red.\r\n3. Kay and the one who wears purple went shopping with the one who wears casual clothes.\r\n4. May does not like blue.\r\n5. The one who wears punk doesn't like blue or green, and is not Ray.\r\n6. The one who wears preppie clothes went to dinner with Ray and the one who wears blue.\r\n7. Jay does not wear casual clothes.\n\n\r\nHint will reveal Jay's clothes and color.", "hint": "Jay wears blue classic clothes.", "answer": "May wears purple, punk clothes.\r\nJay wears blue, classic clothes.\r\nFay wears red, western clothes.\r\nRay wears orange, casual clothes.\r\nKay wears green, preppie clothes.", "category": "Logic-Grid", "date": "10/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMay, Jay, Fay, Ray, and Kay are quintuplets who each like different colors and styles of clothes. From each of the clues, determine the color and style that each likes.\n\r\nThe styles of clothes are: Classic, Western, Punk, Casual, and Preppie.\n\r\nThe colors of the clothes are: Purple, Red, Blue, Orange, and Green.\n\r\n1. The one who wears red western clothes is not May, Ray, or Jay.\r\n2. Kay won't wear blue, orange, or red.\r\n3. Kay and the one who wears purple went shopping with the one who wears casual clothes.\r\n4. May does not like blue.\r\n5. The one who wears punk doesn't like blue or green, and is not Ray.\r\n6. The one who wears preppie clothes went to dinner with Ray and the one who wears blue.\r\n7. Jay does not wear casual clothes.\n\n\r\nHint will reveal Jay's clothes and color.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMay wears purple, punk clothes.\r\nJay wears blue, classic clothes.\r\nFay wears red, western clothes.\r\nRay wears orange, casual clothes.\r\nKay wears green, preppie clothes.\n<|im_start|>answer\nMay wears purple, punk clothes.\r\nJay wears blue, classic clothes.\r\nFay wears red, western clothes.\r\nRay wears orange, casual clothes.\r\nKay wears green, preppie clothes.\n<|im_end|>" }, { "id": "#34228", "title": "Parade Time", "fun": 2.69, "difficulty": 0.92, "author": "fishmed", "desc": "Eight kids all wanted to be in the class parade. They were all very excited. Using the clues below, please identify what their order was in the parade.\n\r\n1. Alyce is just before Madison, who has nobody behind her.\r\n2. Latoria is just before Juan.\r\n3. Miguel is just after Juan.\r\n4. Only two students are in front of JR.\r\n5. Kim gets to be the leader.\r\n6. Pedro is in front of all but one person.", "hint": "No hint available.", "answer": "The line-up, front to back is: \r\nKim, Pedro, JR, Latoria, Juan, Miguel, Alyce & Madison.", "category": "Logic", "date": "12/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEight kids all wanted to be in the class parade. They were all very excited. Using the clues below, please identify what their order was in the parade.\n\r\n1. Alyce is just before Madison, who has nobody behind her.\r\n2. Latoria is just before Juan.\r\n3. Miguel is just after Juan.\r\n4. Only two students are in front of JR.\r\n5. Kim gets to be the leader.\r\n6. Pedro is in front of all but one person.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe line-up, front to back is: \r\nKim, Pedro, JR, Latoria, Juan, Miguel, Alyce & Madison.\n<|im_start|>answer\nThe line-up, front to back is: \r\nKim, Pedro, JR, Latoria, Juan, Miguel, Alyce & Madison.\n<|im_end|>" }, { "id": "#45342", "title": "New Name, New Location", "fun": 2.69, "difficulty": 1.72, "author": "whsprec", "desc": "Four young men from 4 different cities had the mob after them and needed to be placed in Witness Protection. They then had their names changed and were moved to a different location. From the clues below determine their original names, their new names, which city they left, and where they were relocated.\n\r\n1) The young man previously known as Lamar Moon, was moved to Miami, was not known as Sam Toll, nor did he leave New York.\r\n2) Neither Sam Toll nor the man from New York was relocated to Atlanta.\r\n3) James Kemp, who was formerly known as Omar Peck, isn't from Las Vegas and was not relocated to Denver.\r\n4) The young man from Chicago was moved to Houston, but was neither Fred Gibbs nor Dan Epps.", "hint": "No hint available.", "answer": "Ben Cox was Dan Epps and was relocated from New York to Denver.\r\nSam Toll was Mac Needs and was relocated from Chicago to Houston.\r\nJames Kemp was Omar Peck and was relocated from L.A. to Atlanta.\r\nFred Gibbs was Lamar Moon and was relocated from Las Vegas to Miami.", "category": "Logic-Grid", "date": "09/22/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour young men from 4 different cities had the mob after them and needed to be placed in Witness Protection. They then had their names changed and were moved to a different location. From the clues below determine their original names, their new names, which city they left, and where they were relocated.\n\r\n1) The young man previously known as Lamar Moon, was moved to Miami, was not known as Sam Toll, nor did he leave New York.\r\n2) Neither Sam Toll nor the man from New York was relocated to Atlanta.\r\n3) James Kemp, who was formerly known as Omar Peck, isn't from Las Vegas and was not relocated to Denver.\r\n4) The young man from Chicago was moved to Houston, but was neither Fred Gibbs nor Dan Epps.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBen Cox was Dan Epps and was relocated from New York to Denver.\r\nSam Toll was Mac Needs and was relocated from Chicago to Houston.\r\nJames Kemp was Omar Peck and was relocated from L.A. to Atlanta.\r\nFred Gibbs was Lamar Moon and was relocated from Las Vegas to Miami.\n<|im_start|>answer\nBen Cox was Dan Epps and was relocated from New York to Denver.\r\nSam Toll was Mac Needs and was relocated from Chicago to Houston.\r\nJames Kemp was Omar Peck and was relocated from L.A. to Atlanta.\r\nFred Gibbs was Lamar Moon and was relocated from Las Vegas to Miami.\n<|im_end|>" }, { "id": "#51602", "title": "Movie Messup", "fun": 2.69, "difficulty": 2.66, "author": "Hydra1234", "desc": "At Brothers Movie Studios, the director of a new movie has scheduled five actors-Luis, Oscar, Paul, Randy, and William-to play as a brother, father, senator, soldier, or uncle. Each actor is paid either 85 thousand, 100 thousand, 115 thousand, 130 thousand, or 145 thousand dollars. Finally, each actor is filming on just one of the following dates: September 15, September 22, September 29, October 6, October 13. Unfortunately, the spreadsheet listing all this information has been corrupted. Using clues salvaged from the file and other spreadsheets, recreate the spreadsheet so that the movie will be released on time.\r\nInformation salvaged from the spreadsheet:\n\r\n1. The person who will play the soldier will make 15,000 dollars less than the actor who will play the uncle.\n\r\n2. The man filming on September 29th will make 15,000 dollars more than the person who will play the brother.\n\r\n3. Randy won't be filming on September 29th.\n\r\n4. The person filming on October 13th is either the person making $130,000 or Oscar.\n\r\n5. Of the person making $115,000 and the person filming on October 13th, one will play the soldier and the other is Randy.\n\r\n6. The five people are Luis, the man making $145,000, the actor making $85,000, the person filming on September 15th and the man filming on September 29th.\n\r\n7. Oscar will film on October 6th.\n\r\n8. William won't play the senator.\n\r\n9. Randy will make less than Paul.", "hint": "No hint available.", "answer": "For $85,000, Oscar will be filming on October 6th as the brother.\r\nFor $100,000, William will be filming on September 29th as the father.\r\nFor $115,000, Randy will be filming on September 15th as the senator.\r\nFor $130,000, Luis will be filming on October 13th as the soldier.\r\nFor $145,000, Paul will be filming on September 22nd as the uncle.", "category": "Logic-Grid", "date": "12/29/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt Brothers Movie Studios, the director of a new movie has scheduled five actors-Luis, Oscar, Paul, Randy, and William-to play as a brother, father, senator, soldier, or uncle. Each actor is paid either 85 thousand, 100 thousand, 115 thousand, 130 thousand, or 145 thousand dollars. Finally, each actor is filming on just one of the following dates: September 15, September 22, September 29, October 6, October 13. Unfortunately, the spreadsheet listing all this information has been corrupted. Using clues salvaged from the file and other spreadsheets, recreate the spreadsheet so that the movie will be released on time.\r\nInformation salvaged from the spreadsheet:\n\r\n1. The person who will play the soldier will make 15,000 dollars less than the actor who will play the uncle.\n\r\n2. The man filming on September 29th will make 15,000 dollars more than the person who will play the brother.\n\r\n3. Randy won't be filming on September 29th.\n\r\n4. The person filming on October 13th is either the person making $130,000 or Oscar.\n\r\n5. Of the person making $115,000 and the person filming on October 13th, one will play the soldier and the other is Randy.\n\r\n6. The five people are Luis, the man making $145,000, the actor making $85,000, the person filming on September 15th and the man filming on September 29th.\n\r\n7. Oscar will film on October 6th.\n\r\n8. William won't play the senator.\n\r\n9. Randy will make less than Paul.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor $85,000, Oscar will be filming on October 6th as the brother.\r\nFor $100,000, William will be filming on September 29th as the father.\r\nFor $115,000, Randy will be filming on September 15th as the senator.\r\nFor $130,000, Luis will be filming on October 13th as the soldier.\r\nFor $145,000, Paul will be filming on September 22nd as the uncle.\n<|im_start|>answer\nFor $85,000, Oscar will be filming on October 6th as the brother.\r\nFor $100,000, William will be filming on September 29th as the father.\r\nFor $115,000, Randy will be filming on September 15th as the senator.\r\nFor $130,000, Luis will be filming on October 13th as the soldier.\r\nFor $145,000, Paul will be filming on September 22nd as the uncle.\n<|im_end|>" }, { "id": "#52126", "title": "Alien Anxiety", "fun": 2.69, "difficulty": 2.58, "author": "Hydra1234", "desc": "5 uniquely-shaped UFOs accidentally dropped out of space in 5 different locations over a period of 5 days from the 4th of July to July 8th and were each seen by 1 person. As a government agent, you need to quickly cover up these incidents lest they become a sensation and reveal the existence of aliens. Unfortunately, the aliens do not remember much due to the head trauma inflicted from the severe deceleration into the atmosphere. Using a combination of whatever memories the aliens had and information from the Internet, deduce when did each ship arrive, the ship's shape, who saw them, and which town they were sighted in.\r\n1. The sighting of the horseshoe-shaped UFO was either the July 5 sighting or the report from Walnut Creek.\r\n2. Iva Ingram's sighting was either the sighting of the egg-shaped UFO or the July 6 sighting.\r\n3. A post from Iva Ingram on a conspiracy forum was posted 2 days before a post about a sighting from Upper Lake.\r\n4. A description from the alien who arrived on July 7th reveals that it did not arrive above Tuscon.\r\n5. Iva Ingram's report was submitted sometime before the sighting from Tuscon.\r\n6. Neither the report from San Antonio nor Hal Harrison's sighting was the report of the diamond-shaped UFO.\r\n7. Abe Alvarez's either was living in Tuscon or saw a spaceship on July 8.\r\n8. Of Hal Harrison's sighting and Gil Gates's sighting, one involved the oval-shaped UFO and the other was from Upper Lake.\r\n9. A post describing a teardrop-shaped UFO was posted 2 days before a description of an oval-shaped UFO.\r\n10. The report of the teardrop-shaped UFO was submitted 1 day after the report of the egg-shaped UFO.\r\n11. A blurry photo from Abe Alvarez reveals that he did not photograph a teardrop-shaped spaceship\r\n12. Abe Alvarez, Flora Flynn, Gil Gates, Hal Harrison, and Iva Ingram each saw 1 spaceship over their towns: Tuscon, San Antonio, Upper Lake, Fresno, or Walnut Creek.\r\n13. The 5 spaceships were either diamond, egg, horseshoe, oval, or teardrop-shaped.", "hint": "While digging through the Internet an anonymous post described a cloudy night above Tuscon when the UFO was spotted. Cross-checking old weather forecasts showed that August 7th was a clear night, meaning that the sighting above Long Barn could not have occurred that day.", "answer": "Iva Ingram saw an egg-shaped ship above San Antonio on August 4th. \r\nFlora Fynn saw a teardrop-shaped ship above Tuscon on August 5th.\r\nGil Gates saw a diamond-shaped ship above Upper Lake on the 6th.\r\nHal Harrison saw an oval-shaped ship above Fresno on the 7th.\r\nAbe Alvarez saw a horseshoe-shaped ship above Walnut Creek on the 8th.", "category": "Logic-Grid", "date": "04/06/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 uniquely-shaped UFOs accidentally dropped out of space in 5 different locations over a period of 5 days from the 4th of July to July 8th and were each seen by 1 person. As a government agent, you need to quickly cover up these incidents lest they become a sensation and reveal the existence of aliens. Unfortunately, the aliens do not remember much due to the head trauma inflicted from the severe deceleration into the atmosphere. Using a combination of whatever memories the aliens had and information from the Internet, deduce when did each ship arrive, the ship's shape, who saw them, and which town they were sighted in.\r\n1. The sighting of the horseshoe-shaped UFO was either the July 5 sighting or the report from Walnut Creek.\r\n2. Iva Ingram's sighting was either the sighting of the egg-shaped UFO or the July 6 sighting.\r\n3. A post from Iva Ingram on a conspiracy forum was posted 2 days before a post about a sighting from Upper Lake.\r\n4. A description from the alien who arrived on July 7th reveals that it did not arrive above Tuscon.\r\n5. Iva Ingram's report was submitted sometime before the sighting from Tuscon.\r\n6. Neither the report from San Antonio nor Hal Harrison's sighting was the report of the diamond-shaped UFO.\r\n7. Abe Alvarez's either was living in Tuscon or saw a spaceship on July 8.\r\n8. Of Hal Harrison's sighting and Gil Gates's sighting, one involved the oval-shaped UFO and the other was from Upper Lake.\r\n9. A post describing a teardrop-shaped UFO was posted 2 days before a description of an oval-shaped UFO.\r\n10. The report of the teardrop-shaped UFO was submitted 1 day after the report of the egg-shaped UFO.\r\n11. A blurry photo from Abe Alvarez reveals that he did not photograph a teardrop-shaped spaceship\r\n12. Abe Alvarez, Flora Flynn, Gil Gates, Hal Harrison, and Iva Ingram each saw 1 spaceship over their towns: Tuscon, San Antonio, Upper Lake, Fresno, or Walnut Creek.\r\n13. The 5 spaceships were either diamond, egg, horseshoe, oval, or teardrop-shaped.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIva Ingram saw an egg-shaped ship above San Antonio on August 4th. \r\nFlora Fynn saw a teardrop-shaped ship above Tuscon on August 5th.\r\nGil Gates saw a diamond-shaped ship above Upper Lake on the 6th.\r\nHal Harrison saw an oval-shaped ship above Fresno on the 7th.\r\nAbe Alvarez saw a horseshoe-shaped ship above Walnut Creek on the 8th.\n<|im_start|>answer\nIva Ingram saw an egg-shaped ship above San Antonio on August 4th. \r\nFlora Fynn saw a teardrop-shaped ship above Tuscon on August 5th.\r\nGil Gates saw a diamond-shaped ship above Upper Lake on the 6th.\r\nHal Harrison saw an oval-shaped ship above Fresno on the 7th.\r\nAbe Alvarez saw a horseshoe-shaped ship above Walnut Creek on the 8th.\n<|im_end|>" }, { "id": "#45446", "title": "The Math Department Annual Dinner", "fun": 2.69, "difficulty": 1.68, "author": "dalfamnest", "desc": "My department needs a new Social Coordinator! You see, we were going to have a Chinese New Year dinner but the seating plan proved to be too much for the organizer, who has now resigned. Math teachers can be hard to please!\n\r\nThe restaurant had big round tables for 10 people, (perfect for our department size), with chairs placed evenly around. Everyone was going to attend, and a fun evening seemed assured ... until the problems began.\n\r\n[A] Ding wanted to sit as far as possible away from Dong.\n\r\n[B] Walter wanted to sit opposite Wira, who insisted on sitting closer to Dong than to Ding.\n\r\n[C] Wynn, Dan and Walter always sit together, in that order, anticlockwise (something about feng shui, they claimed.)\n\r\n[D] Wira only wanted to sit between Liza and Fozz, who always sits with Rita!\n\r\nWork out the seating plan and discover which teachers I sat between so everyone's preferences could be satisfied.", "hint": "It's probably easiest to start with Wynn-Dan-Walter - the feng shui trio!", "answer": "Starting with me and going clockwise, there was Walter on my left, Dan, Wynn, Dong, Liza, Wira, Fozz, Rita, and then Ding on my Right.\n\r\nSOLUTION:\r\nIf we number all the seats clockwise starting with Walter = 1, then Dan = 2 and Wynn = 3 [C]. From [B], Wira is at 6. \n\r\nThat leaves only 4 and 9 or 5 and 10 for Dong and Ding [A], and from [B] we find that Dong must be at 4 or 5. Dong can not be at 5 [D] so Dong = 4 and Ding = 9.\n\r\nThat leaves only 7 and 8 for Fozz and Rita respectively [D] so Liza = 5 [D] and I come in at 10.\n\r\nIt's not an easy life teaching, is it? Maybe that's why we decided on an Indian restaurant for next year! I'll report on that later.", "category": "Logic", "date": "10/07/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy department needs a new Social Coordinator! You see, we were going to have a Chinese New Year dinner but the seating plan proved to be too much for the organizer, who has now resigned. Math teachers can be hard to please!\n\r\nThe restaurant had big round tables for 10 people, (perfect for our department size), with chairs placed evenly around. Everyone was going to attend, and a fun evening seemed assured ... until the problems began.\n\r\n[A] Ding wanted to sit as far as possible away from Dong.\n\r\n[B] Walter wanted to sit opposite Wira, who insisted on sitting closer to Dong than to Ding.\n\r\n[C] Wynn, Dan and Walter always sit together, in that order, anticlockwise (something about feng shui, they claimed.)\n\r\n[D] Wira only wanted to sit between Liza and Fozz, who always sits with Rita!\n\r\nWork out the seating plan and discover which teachers I sat between so everyone's preferences could be satisfied.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStarting with me and going clockwise, there was Walter on my left, Dan, Wynn, Dong, Liza, Wira, Fozz, Rita, and then Ding on my Right.\n\r\nSOLUTION:\r\nIf we number all the seats clockwise starting with Walter = 1, then Dan = 2 and Wynn = 3 [C]. From [B], Wira is at 6. \n\r\nThat leaves only 4 and 9 or 5 and 10 for Dong and Ding [A], and from [B] we find that Dong must be at 4 or 5. Dong can not be at 5 [D] so Dong = 4 and Ding = 9.\n\r\nThat leaves only 7 and 8 for Fozz and Rita respectively [D] so Liza = 5 [D] and I come in at 10.\n\r\nIt's not an easy life teaching, is it? Maybe that's why we decided on an Indian restaurant for next year! I'll report on that later.\n<|im_start|>answer\nStarting with me and going clockwise, there was Walter on my left, Dan, Wynn, Dong, Liza, Wira, Fozz, Rita, and then Ding on my Right.\n\r\nSOLUTION:\r\nIf we number all the seats clockwise starting with Walter = 1, then Dan = 2 and Wynn = 3 [C]. From [B], Wira is at 6. \n\r\nThat leaves only 4 and 9 or 5 and 10 for Dong and Ding [A], and from [B] we find that Dong must be at 4 or 5. Dong can not be at 5 [D] so Dong = 4 and Ding = 9.\n\r\nThat leaves only 7 and 8 for Fozz and Rita respectively [D] so Liza = 5 [D] and I come in at 10.\n\r\nIt's not an easy life teaching, is it? Maybe that's why we decided on an Indian restaurant for next year! I'll report on that later.\n<|im_end|>" }, { "id": "#38660", "title": "Murder at Brainteaser Mansion #2", "fun": 2.69, "difficulty": 0.77, "author": "Mystery-King", "desc": "Four guests, Ms. Emerald, Mr. Green, Sir Jade and Mr. Olive, were all invited to an exclusive party at Brainteaser Mansion. However, during the long, dark night, the owner of the spectacular mansion, Mr. Death, was found dead in the study. Since no one apparently knew what happened, rumours were multiplying by the second, because everyone was suspected of killing him with a different weapon. From the following clues, can you work out who killed him?\n\r\n1. The candlestick was \"apparently\" used by a female. \n\r\n2. Mr. Olive's motive was either love or revenge.\n\r\n3. Sir Jade's motive was greed, but he didn't use the sword. \n\r\n4. The motive of the person who used the rope was revenge. \n\r\n5. No male's motive was love.\n\r\nThe person who used the sword is the real killer. Who did it?", "hint": "No hint available.", "answer": "Ms. Emerald, Candlestick, Love.\r\nMr. Green, Sword, Rage.\r\nSir Jade, Revolver , Greed.\r\nMr. Olive, Rope, Revenge.\n\r\nSo, therefore, Mr. Green was the real killer.", "category": "Logic-Grid", "date": "10/07/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour guests, Ms. Emerald, Mr. Green, Sir Jade and Mr. Olive, were all invited to an exclusive party at Brainteaser Mansion. However, during the long, dark night, the owner of the spectacular mansion, Mr. Death, was found dead in the study. Since no one apparently knew what happened, rumours were multiplying by the second, because everyone was suspected of killing him with a different weapon. From the following clues, can you work out who killed him?\n\r\n1. The candlestick was \"apparently\" used by a female. \n\r\n2. Mr. Olive's motive was either love or revenge.\n\r\n3. Sir Jade's motive was greed, but he didn't use the sword. \n\r\n4. The motive of the person who used the rope was revenge. \n\r\n5. No male's motive was love.\n\r\nThe person who used the sword is the real killer. Who did it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMs. Emerald, Candlestick, Love.\r\nMr. Green, Sword, Rage.\r\nSir Jade, Revolver , Greed.\r\nMr. Olive, Rope, Revenge.\n\r\nSo, therefore, Mr. Green was the real killer.\n<|im_start|>answer\nMs. Emerald, Candlestick, Love.\r\nMr. Green, Sword, Rage.\r\nSir Jade, Revolver , Greed.\r\nMr. Olive, Rope, Revenge.\n\r\nSo, therefore, Mr. Green was the real killer.\n<|im_end|>" }, { "id": "#28027", "title": "Opposites 2", "fun": 2.69, "difficulty": 2.42, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n! stands for R, U, O, N, or V\r\n? stands for U, D, L, W, or J\r\n@ stands for A, G, P, E, or Y\r\n; stands for O, M, I, C, or S\n\r\nThe four letter code word, @!;?, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Good and Evil.", "category": "Logic", "date": "01/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n! stands for R, U, O, N, or V\r\n? stands for U, D, L, W, or J\r\n@ stands for A, G, P, E, or Y\r\n; stands for O, M, I, C, or S\n\r\nThe four letter code word, @!;?, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGood and Evil.\n<|im_start|>answer\nGood and Evil.\n<|im_end|>" }, { "id": "#28960", "title": "Something's Fishy", "fun": 2.69, "difficulty": 1.52, "author": "shenqiang", "desc": "The fish market is selling several kinds of fish. But there aren't any prices listed. You ask about the prices, but all the seller will tell you is this:\n\r\n1. A pound of salmon and a pound of bass are $12. \r\n2. A pound of bass and a pound of swordfish are $10. \r\n3. A pound of salmon and a pound of swordfish are $8. \r\n4. A pound of swordfish and a pound of catfish are $5. \n\r\nEach price per pound is a whole-dollar amount. How much is the price per pound for each kind of fish?", "hint": "1. Assign letter names to the different kinds of fish and write equations to decide each combination. For example: salmon = a, bass = b, a + b = $12.\r\n2. If the salmon and the bass together cost $12, and the bass and the swordfish together cost $10, what is the price difference between the salmon and the swordfish?", "answer": "Salmon = $5 per pound\r\nBass = $7 per pound\r\nSwordfish = $3 per pound\r\nCatfish = $2 per pound", "category": "Math", "date": "03/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe fish market is selling several kinds of fish. But there aren't any prices listed. You ask about the prices, but all the seller will tell you is this:\n\r\n1. A pound of salmon and a pound of bass are $12. \r\n2. A pound of bass and a pound of swordfish are $10. \r\n3. A pound of salmon and a pound of swordfish are $8. \r\n4. A pound of swordfish and a pound of catfish are $5. \n\r\nEach price per pound is a whole-dollar amount. How much is the price per pound for each kind of fish?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSalmon = $5 per pound\r\nBass = $7 per pound\r\nSwordfish = $3 per pound\r\nCatfish = $2 per pound\n<|im_start|>answer\nSalmon = $5 per pound\r\nBass = $7 per pound\r\nSwordfish = $3 per pound\r\nCatfish = $2 per pound\n<|im_end|>" }, { "id": "#44946", "title": "Dream Rides", "fun": 2.69, "difficulty": 2.49, "author": "mrsfessler", "desc": "5 American friends were excited about their upcoming 16th birthdays and getting their driver's licenses. What they weren't excited about was the cars their parents owned that they would soon be driving (one was a Ford Focus). Each had a \"dream ride\" (one was a Ford Mustang) that they one day hoped to own. From the clues provided, determine each teen's first and last name, the color and model of their parents' cars and the model of their dream rides.\n\r\n1. The owners of the two blue cars were Mr. Lusk and the Buick Regal's owner. The other cars were owned by Christopher's mom, Mrs. Emery and the owner of the Nissan Sentra.\t\t\t\t\t\t\r\n2. Glenn's dad and the girl who wanted the Chrysler Crossfire's mom owned imported cars. Mrs. Harper, Elizabeth's parent, and the one whose child wanted the Chevy Camaro did not.\t\t\t\t\t\t\t\t\r\n3. The 5 teens were the one who wanted the Dodge Ram, Austin, the ones whose parents drove the Ford Taurus and Nissan Sentra and the daughter of the one who drove the white car. \t\t\t\t\t\t\r\n4. Mr. Lange and Karen's mom owned the white and green cars in some order. The one who wanted the Chevy Corvette called his mom's car \"The Black Bomb.\"\t\t\t\t\t\r\n5. Mr. Wallace's daughter loved pickup trucks! The Toyota Corolla was owned by either Mrs. Emery or Mr. Lusk.", "hint": "Toyota and Nissan are imports\r\nDodge Ram is a pickup truck", "answer": "Karen Emery, white Corolla, Crossfire\r\nGlenn Lange, green Sentra, Mustang\r\nAustin Lusk, blue Focus, Camaro\r\nChristopher Harper, black Taurus, Corvette\r\nElizabeth Wallace, blue Regal, Ram", "category": "Logic-Grid", "date": "07/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 American friends were excited about their upcoming 16th birthdays and getting their driver's licenses. What they weren't excited about was the cars their parents owned that they would soon be driving (one was a Ford Focus). Each had a \"dream ride\" (one was a Ford Mustang) that they one day hoped to own. From the clues provided, determine each teen's first and last name, the color and model of their parents' cars and the model of their dream rides.\n\r\n1. The owners of the two blue cars were Mr. Lusk and the Buick Regal's owner. The other cars were owned by Christopher's mom, Mrs. Emery and the owner of the Nissan Sentra.\t\t\t\t\t\t\r\n2. Glenn's dad and the girl who wanted the Chrysler Crossfire's mom owned imported cars. Mrs. Harper, Elizabeth's parent, and the one whose child wanted the Chevy Camaro did not.\t\t\t\t\t\t\t\t\r\n3. The 5 teens were the one who wanted the Dodge Ram, Austin, the ones whose parents drove the Ford Taurus and Nissan Sentra and the daughter of the one who drove the white car. \t\t\t\t\t\t\r\n4. Mr. Lange and Karen's mom owned the white and green cars in some order. The one who wanted the Chevy Corvette called his mom's car \"The Black Bomb.\"\t\t\t\t\t\r\n5. Mr. Wallace's daughter loved pickup trucks! The Toyota Corolla was owned by either Mrs. Emery or Mr. Lusk.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKaren Emery, white Corolla, Crossfire\r\nGlenn Lange, green Sentra, Mustang\r\nAustin Lusk, blue Focus, Camaro\r\nChristopher Harper, black Taurus, Corvette\r\nElizabeth Wallace, blue Regal, Ram\n<|im_start|>answer\nKaren Emery, white Corolla, Crossfire\r\nGlenn Lange, green Sentra, Mustang\r\nAustin Lusk, blue Focus, Camaro\r\nChristopher Harper, black Taurus, Corvette\r\nElizabeth Wallace, blue Regal, Ram\n<|im_end|>" }, { "id": "#17749", "title": "Santa's Trains", "fun": 2.69, "difficulty": 2.13, "author": "Jake", "desc": "Santa Claus sometimes helps the elves by making some toys. He's not as fast as the elves, but he can still make 30 toys each hour. In order to keep from getting bored he starts each day by building 50 trains and then switches to building 50 airplanes. Then he switches back to trains and keeps switching back and forth until the day is finished. If Santa starts work at 8:00am, when will he finish his 108th train?", "hint": "No hint available.", "answer": "Because Santa started with trains, the 108th train will occur during his 5th batch of toys. Thus he will have built a total of 208 toys. At 2 minutes a toy, his 108th train will happen 416 minutes after he starts work, which is 2:56pm.", "category": "Math", "date": "05/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSanta Claus sometimes helps the elves by making some toys. He's not as fast as the elves, but he can still make 30 toys each hour. In order to keep from getting bored he starts each day by building 50 trains and then switches to building 50 airplanes. Then he switches back to trains and keeps switching back and forth until the day is finished. If Santa starts work at 8:00am, when will he finish his 108th train?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBecause Santa started with trains, the 108th train will occur during his 5th batch of toys. Thus he will have built a total of 208 toys. At 2 minutes a toy, his 108th train will happen 416 minutes after he starts work, which is 2:56pm.\n<|im_start|>answer\nBecause Santa started with trains, the 108th train will occur during his 5th batch of toys. Thus he will have built a total of 208 toys. At 2 minutes a toy, his 108th train will happen 416 minutes after he starts work, which is 2:56pm.\n<|im_end|>" }, { "id": "#30726", "title": "Crab Confusion", "fun": 2.69, "difficulty": 1.43, "author": "JessicaLynn", "desc": "Jessica bought five hermit crabs, along with food and other things her hermit crabs would need. After setting up her crabs' homes, she set them in their tank. A while later, she checked on them, and they had switched shells! Can you help her figure out which ones are which?\n\r\nNames of Crabs: Prince, Camille, BB, Lucky, and Lizzie.\n\r\nOriginal Shell colors: Purple, Blue, Peach, Pink, Lavender.\n\r\nNew Shell colors: Red, Green, Brown, Black, White.\n\r\nSize of Crabs: Extra-Small, Small, Large, Medium, Extra-Large.\n\r\n1. The small one hasn't ever been in a lavender shell.\n\r\n2. Lizzie is the biggest hermit crab.\n\r\n3. The smallest crab had either 6 or 7 letters in its name.\n\r\n4. BB was in a blue shell before she switched, but she moved into the shell that is the color that you have to mix with blue to get purple.\n\r\n5. The one that was in the peach shell is the smallest.\n\r\n6. The one that was in the pink is now in the black shell.\n\r\n7. The one now in the black shell is extra-large.\n\r\n8. Prince was smaller than Lucky, but larger than Camille.\n\r\n9. The one in the green shell now was in the peach shell before.\n\r\n10. Prince was in the purple shell, but now he is in the white one.\n\r\n11. The small one is the one that has a royal name.\n\r\n12. The medium-sized one is now in the brown shell.", "hint": "No hint available.", "answer": "Name/Size/Old Color/New Color\n\r\nPrince/small/purple/white\r\nCamille/extra-small/peach/green\r\nBB/large/blue/red\r\nLucky/medium/lavender/brown\r\nLizzie/extra-large/pink/black", "category": "Logic-Grid", "date": "05/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJessica bought five hermit crabs, along with food and other things her hermit crabs would need. After setting up her crabs' homes, she set them in their tank. A while later, she checked on them, and they had switched shells! Can you help her figure out which ones are which?\n\r\nNames of Crabs: Prince, Camille, BB, Lucky, and Lizzie.\n\r\nOriginal Shell colors: Purple, Blue, Peach, Pink, Lavender.\n\r\nNew Shell colors: Red, Green, Brown, Black, White.\n\r\nSize of Crabs: Extra-Small, Small, Large, Medium, Extra-Large.\n\r\n1. The small one hasn't ever been in a lavender shell.\n\r\n2. Lizzie is the biggest hermit crab.\n\r\n3. The smallest crab had either 6 or 7 letters in its name.\n\r\n4. BB was in a blue shell before she switched, but she moved into the shell that is the color that you have to mix with blue to get purple.\n\r\n5. The one that was in the peach shell is the smallest.\n\r\n6. The one that was in the pink is now in the black shell.\n\r\n7. The one now in the black shell is extra-large.\n\r\n8. Prince was smaller than Lucky, but larger than Camille.\n\r\n9. The one in the green shell now was in the peach shell before.\n\r\n10. Prince was in the purple shell, but now he is in the white one.\n\r\n11. The small one is the one that has a royal name.\n\r\n12. The medium-sized one is now in the brown shell.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName/Size/Old Color/New Color\n\r\nPrince/small/purple/white\r\nCamille/extra-small/peach/green\r\nBB/large/blue/red\r\nLucky/medium/lavender/brown\r\nLizzie/extra-large/pink/black\n<|im_start|>answer\nName/Size/Old Color/New Color\n\r\nPrince/small/purple/white\r\nCamille/extra-small/peach/green\r\nBB/large/blue/red\r\nLucky/medium/lavender/brown\r\nLizzie/extra-large/pink/black\n<|im_end|>" }, { "id": "#29710", "title": "First and Last Names", "fun": 2.69, "difficulty": 1.91, "author": "EnderofGames", "desc": "The first names of five people are Beverly, Charles, Monica, Nelson, and Ruth. Their last names are Atwood, Porter, Stafford, Thompson, and Ward. Match each person first and last names.\n\r\n1) Ruth and Porter went hiking yesterday with Monica and Stafford.\n\r\n2) Beverly enrolled her son, and Atwood enrolled her daughter, at the same nursery school.\n\r\n3) Thompson and Ruth don't have children.\n\r\n4) Charles, who has been in the hospital for the past three days, was visited today by Porter and Nelson.", "hint": "Beverly, Monica and Ruth are female. Charles and Nelson are male.", "answer": "Beverly - Porter\r\nCharles - Thompson\r\nMonica - Atwood\r\nNelson - Stafford\r\nRuth - Ward", "category": "Logic", "date": "04/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe first names of five people are Beverly, Charles, Monica, Nelson, and Ruth. Their last names are Atwood, Porter, Stafford, Thompson, and Ward. Match each person first and last names.\n\r\n1) Ruth and Porter went hiking yesterday with Monica and Stafford.\n\r\n2) Beverly enrolled her son, and Atwood enrolled her daughter, at the same nursery school.\n\r\n3) Thompson and Ruth don't have children.\n\r\n4) Charles, who has been in the hospital for the past three days, was visited today by Porter and Nelson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeverly - Porter\r\nCharles - Thompson\r\nMonica - Atwood\r\nNelson - Stafford\r\nRuth - Ward\n<|im_start|>answer\nBeverly - Porter\r\nCharles - Thompson\r\nMonica - Atwood\r\nNelson - Stafford\r\nRuth - Ward\n<|im_end|>" }, { "id": "#14175", "title": "Al and Cal", "fun": 2.69, "difficulty": 1.76, "author": "mathemagician", "desc": "Two math students, Al and Cal, each picked a number and then performed five arithmetic operations.\n\r\nAl took his number and performed the following operations: \n\r\n(i) subtracted 3\r\n(ii) then multiplied by 4\r\n(iii) then added 5\r\n(iv) then took the square root\r\n(v) then divided by 3\n\r\nCal did just the opposite of his math buddy. He took his number and did the following:\n\r\n(i) added 3\r\n(ii) then divided by 4\r\n(iii) then subtracted 5\r\n(iv) then squared the result\r\n(v) then multiplied by 3\n\r\nAfter performing their arithmetic, BOTH Al and Cal ended up with the same answer of 3 . Also, there were no negative results at any step along the way.\n\r\nWho picked the larger number, Al or Cal ?", "hint": "Work backwards from the final result.", "answer": "Al's number : 22\r\nCal's number: 21\n\r\nWorking backwards from the final result of 3, we have:\n\r\nAl : 3 x 3 = 9 ; 9 ^2 = 81 ; 81 - 5 = 76 ; 76/4 = 19 ; 19 + 3 = 22.\n\r\nCal: 3/3 = 1 ; sqrt(1) = 1 ; 1 + 5= 6;\r\n6 x 4 = 24 ; 24 - 3 = 21.", "category": "Math", "date": "08/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo math students, Al and Cal, each picked a number and then performed five arithmetic operations.\n\r\nAl took his number and performed the following operations: \n\r\n(i) subtracted 3\r\n(ii) then multiplied by 4\r\n(iii) then added 5\r\n(iv) then took the square root\r\n(v) then divided by 3\n\r\nCal did just the opposite of his math buddy. He took his number and did the following:\n\r\n(i) added 3\r\n(ii) then divided by 4\r\n(iii) then subtracted 5\r\n(iv) then squared the result\r\n(v) then multiplied by 3\n\r\nAfter performing their arithmetic, BOTH Al and Cal ended up with the same answer of 3 . Also, there were no negative results at any step along the way.\n\r\nWho picked the larger number, Al or Cal ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAl's number : 22\r\nCal's number: 21\n\r\nWorking backwards from the final result of 3, we have:\n\r\nAl : 3 x 3 = 9 ; 9 ^2 = 81 ; 81 - 5 = 76 ; 76/4 = 19 ; 19 + 3 = 22.\n\r\nCal: 3/3 = 1 ; sqrt(1) = 1 ; 1 + 5= 6;\r\n6 x 4 = 24 ; 24 - 3 = 21.\n<|im_start|>answer\nAl's number : 22\r\nCal's number: 21\n\r\nWorking backwards from the final result of 3, we have:\n\r\nAl : 3 x 3 = 9 ; 9 ^2 = 81 ; 81 - 5 = 76 ; 76/4 = 19 ; 19 + 3 = 22.\n\r\nCal: 3/3 = 1 ; sqrt(1) = 1 ; 1 + 5= 6;\r\n6 x 4 = 24 ; 24 - 3 = 21.\n<|im_end|>" }, { "id": "#679", "title": "My Son and Me", "fun": 2.69, "difficulty": 1.9000000000000001, "author": "vikass", "desc": "If you reverse the digits of my age, you\nhave the age of my son. A year ago, I was\ntwice his age. How old are we both now?", "hint": "No hint available.", "answer": "Father: 73; Son: 37", "category": "Math", "date": "07/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you reverse the digits of my age, you\nhave the age of my son. A year ago, I was\ntwice his age. How old are we both now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFather: 73; Son: 37\n<|im_start|>answer\nFather: 73; Son: 37\n<|im_end|>" }, { "id": "#21408", "title": "Campout", "fun": 2.68, "difficulty": 2.73, "author": "sftbaltwty", "desc": "The wind hit the faces of the four friends with vigor force. \r\nTodd jerked Clea's arm and whispered, \"No, it's this way..\" \r\n\"You're crazy,\" she shot back. \"I know these trails better than you ever will. You wanna win this thing? Follow me.\"\r\nTodd retorted stubbornly, \"No way! I'll manage on my own.\" He walked off down one of the paths and soon disappeared into the dark trees. Clea scoffed and continued on in a different direction.\r\n~\r\nA few hundred yards away, Jake and Bryan were stealthily making their way through the prickly shrub. \"Found anything yet?\" Jake whispered as softly as he could but the silence of the night still made his voice stand out.\r\n\"Keep it down, wouldya?\" Bryan scolded. \"No, I haven't found anything. We don't even know what we're looking for, remember?\"\r\n\"Well, neither do they.\"\r\n\"Yeah but they seem to have the brains..\" Jake rolled his eyes at Bryan's insult. \"That is, if they can manage to get along long enough.\" Both boys chuckled at the thought of their best friends actually getting through one hour, let alone one night, without an argument.\r\n\"Let's just keep walking,\" Jake suggested. \"At least maybe we'll find the campsite. How many different ones are there, anyway?\"\r\n\"Four. Shadybrook, Hillside, Pebblespring and...I can't recall the fourth.\" Bryan shrugged and the two kept walking.\r\n~\r\n\"Found one!\" Clea exclaimed as she picked up the mystery item from its hiding place. She heard someone stumble and fall with an abrupt \"Ah!\" and she quickly spun around to catch Todd face dive a few feet behind her. \"Would you watch where you're going?\" she snapped. \"They'll figure out our location! And besides, weren't you going solo for the rest of the night.\"\r\n\"Well I was,\" Todd mumbled, brushing dirt and leaves from his sweatshirt. He looked up at Clea and smirked, \"'Til I stumbled across you on my path. Thought you knew these trails well.\"\r\n\"You weren't even on a path, Todd. Don't kid yourself. And yeah, you certainly stumbled didn't you?\" Clea's comment caused Todd's smirk to quickly drop from his face.\r\nSuddenly noticing the new object in Clea's hand, Todd tried to snatch it as he said, \"Hey! When'd you get this?\"\r\nClea promptly snatched it back. \"Just now.\"\r\n\"Is it one of the items?\"\r\n\"It certainly fits the clues doesn't it?\" Todd studied the piece for a bit, shuffled through his pockets eventually coming up with some slips of paper, looked at them, back at the piece, back at the papers, and eventually nodded in agreement. \r\nClea groaned and rolled her eyes. \"C'mon. We still have one more to find plus the right campsite.\" She grabbed Todd's hand and they hurried off. \n\r\nFrom the story, you should have been able to decipher that the four friends are involved in a scavenger hunt on a camping trip. Help place them at the right campsite and with the correct objects using the same clues below (some clues are the actual clues given to the children). Also, try to figure out where each object was hidden.\r\nEach team goes with one campsite and two items. \r\n*Make*\r\nClea and Todd- Red Team\r\nJake and Bryan- Blue Team\n\r\nNote that only one campsite per team will be used but each team gets clues for two of the four. It is your job to decipher the clues AND decide which one is the actual site.\n\r\nGood luck! :)\n\r\n1. Blue Team: \r\nYour water is plenty. \r\nThough the sun may be hot, \r\nYou're guarded much better \r\nIn this bug-thriving spot.\r\nOR\r\nThe sunburn's relentless. \r\nYou're thirsting for more. \r\nThe only thing you won't get \r\nIs a sudden downpour.\n\r\nWhich of these will be your home? And which will leave you all alone?\r\n2. The clue for the hairdryer was not given to Clea, but she was given the following hiding spot clue: \r\nI am not hollow, \r\nAm not round, \r\nYou'll find me running \r\nThrough the ground.\r\n3. Jake had clues for none of these three: the frying pan, the object found underneath the leaves, and a campsite containing a double consonant in its spelling pattern.\r\n4. Neither the clues to the log hiding spot nor the frying pan belonged to the Red Team.\r\n5. The belt was found in the leaves but was not found by a member of the Blue Team, whereas the frying pan was found in someplace other than the log.\r\n6. The Red Team's campsite had the following clue: A naturally rounded fragment between 4 and 64 millimeters along with a small stream of water flowing naturally from the earth.", "hint": "No hint available.", "answer": "Answer:\n\r\nRed Team-Pebblespring\r\nClea-toothbrush, stream\r\nTodd-belt, leaves\n\r\nBlue Team-Shadybrook\r\nJake-hairdryer, log\r\nBryan-frying pan, shack\n\r\n~\r\nMr. and Mrs. Thomas (two of the leader) announced to the campers that the Red Team was victorious, having found all of their items and the correct campsite first. Clea and Todd slapped high fives and Jake and Bryan groaned. \"We'll see who comes out a winner in our NEXT game..\" Jake said with a sportsmanlike smile.\r\n~\n\r\n**Please leave a comment.** If you guys like this style, I'll be sure to come up with more like this featuring the four friends. Feel free to use this type of style in your own teaser creations :) Hope you enjoyed it!\n\r\n~Kristyn (sftbaltwty)", "category": "Logic-Grid", "date": "03/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe wind hit the faces of the four friends with vigor force. \r\nTodd jerked Clea's arm and whispered, \"No, it's this way..\" \r\n\"You're crazy,\" she shot back. \"I know these trails better than you ever will. You wanna win this thing? Follow me.\"\r\nTodd retorted stubbornly, \"No way! I'll manage on my own.\" He walked off down one of the paths and soon disappeared into the dark trees. Clea scoffed and continued on in a different direction.\r\n~\r\nA few hundred yards away, Jake and Bryan were stealthily making their way through the prickly shrub. \"Found anything yet?\" Jake whispered as softly as he could but the silence of the night still made his voice stand out.\r\n\"Keep it down, wouldya?\" Bryan scolded. \"No, I haven't found anything. We don't even know what we're looking for, remember?\"\r\n\"Well, neither do they.\"\r\n\"Yeah but they seem to have the brains..\" Jake rolled his eyes at Bryan's insult. \"That is, if they can manage to get along long enough.\" Both boys chuckled at the thought of their best friends actually getting through one hour, let alone one night, without an argument.\r\n\"Let's just keep walking,\" Jake suggested. \"At least maybe we'll find the campsite. How many different ones are there, anyway?\"\r\n\"Four. Shadybrook, Hillside, Pebblespring and...I can't recall the fourth.\" Bryan shrugged and the two kept walking.\r\n~\r\n\"Found one!\" Clea exclaimed as she picked up the mystery item from its hiding place. She heard someone stumble and fall with an abrupt \"Ah!\" and she quickly spun around to catch Todd face dive a few feet behind her. \"Would you watch where you're going?\" she snapped. \"They'll figure out our location! And besides, weren't you going solo for the rest of the night.\"\r\n\"Well I was,\" Todd mumbled, brushing dirt and leaves from his sweatshirt. He looked up at Clea and smirked, \"'Til I stumbled across you on my path. Thought you knew these trails well.\"\r\n\"You weren't even on a path, Todd. Don't kid yourself. And yeah, you certainly stumbled didn't you?\" Clea's comment caused Todd's smirk to quickly drop from his face.\r\nSuddenly noticing the new object in Clea's hand, Todd tried to snatch it as he said, \"Hey! When'd you get this?\"\r\nClea promptly snatched it back. \"Just now.\"\r\n\"Is it one of the items?\"\r\n\"It certainly fits the clues doesn't it?\" Todd studied the piece for a bit, shuffled through his pockets eventually coming up with some slips of paper, looked at them, back at the piece, back at the papers, and eventually nodded in agreement. \r\nClea groaned and rolled her eyes. \"C'mon. We still have one more to find plus the right campsite.\" She grabbed Todd's hand and they hurried off. \n\r\nFrom the story, you should have been able to decipher that the four friends are involved in a scavenger hunt on a camping trip. Help place them at the right campsite and with the correct objects using the same clues below (some clues are the actual clues given to the children). Also, try to figure out where each object was hidden.\r\nEach team goes with one campsite and two items. \r\n*Make*\r\nClea and Todd- Red Team\r\nJake and Bryan- Blue Team\n\r\nNote that only one campsite per team will be used but each team gets clues for two of the four. It is your job to decipher the clues AND decide which one is the actual site.\n\r\nGood luck! :)\n\r\n1. Blue Team: \r\nYour water is plenty. \r\nThough the sun may be hot, \r\nYou're guarded much better \r\nIn this bug-thriving spot.\r\nOR\r\nThe sunburn's relentless. \r\nYou're thirsting for more. \r\nThe only thing you won't get \r\nIs a sudden downpour.\n\r\nWhich of these will be your home? And which will leave you all alone?\r\n2. The clue for the hairdryer was not given to Clea, but she was given the following hiding spot clue: \r\nI am not hollow, \r\nAm not round, \r\nYou'll find me running \r\nThrough the ground.\r\n3. Jake had clues for none of these three: the frying pan, the object found underneath the leaves, and a campsite containing a double consonant in its spelling pattern.\r\n4. Neither the clues to the log hiding spot nor the frying pan belonged to the Red Team.\r\n5. The belt was found in the leaves but was not found by a member of the Blue Team, whereas the frying pan was found in someplace other than the log.\r\n6. The Red Team's campsite had the following clue: A naturally rounded fragment between 4 and 64 millimeters along with a small stream of water flowing naturally from the earth.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer:\n\r\nRed Team-Pebblespring\r\nClea-toothbrush, stream\r\nTodd-belt, leaves\n\r\nBlue Team-Shadybrook\r\nJake-hairdryer, log\r\nBryan-frying pan, shack\n\r\n~\r\nMr. and Mrs. Thomas (two of the leader) announced to the campers that the Red Team was victorious, having found all of their items and the correct campsite first. Clea and Todd slapped high fives and Jake and Bryan groaned. \"We'll see who comes out a winner in our NEXT game..\" Jake said with a sportsmanlike smile.\r\n~\n\r\n**Please leave a comment.** If you guys like this style, I'll be sure to come up with more like this featuring the four friends. Feel free to use this type of style in your own teaser creations :) Hope you enjoyed it!\n\r\n~Kristyn (sftbaltwty)\n<|im_start|>answer\nAnswer:\n\r\nRed Team-Pebblespring\r\nClea-toothbrush, stream\r\nTodd-belt, leaves\n\r\nBlue Team-Shadybrook\r\nJake-hairdryer, log\r\nBryan-frying pan, shack\n\r\n~\r\nMr. and Mrs. Thomas (two of the leader) announced to the campers that the Red Team was victorious, having found all of their items and the correct campsite first. Clea and Todd slapped high fives and Jake and Bryan groaned. \"We'll see who comes out a winner in our NEXT game..\" Jake said with a sportsmanlike smile.\r\n~\n\r\n**Please leave a comment.** If you guys like this style, I'll be sure to come up with more like this featuring the four friends. Feel free to use this type of style in your own teaser creations :) Hope you enjoyed it!\n\r\n~Kristyn (sftbaltwty)\n<|im_end|>" }, { "id": "#29534", "title": "Opposites 18", "fun": 2.68, "difficulty": 2.53, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n! stands for I, S, A, T, or N\r\n# stands for N, F, R, S, or T\r\n& stands for J, E, B, O, or G\r\n* stands for H, E, K, P, or W\r\n^ stands for L, U, D, R, or I\n\r\nThe five letter code word, #&^!*, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "North and South", "category": "Logic", "date": "04/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n! stands for I, S, A, T, or N\r\n# stands for N, F, R, S, or T\r\n& stands for J, E, B, O, or G\r\n* stands for H, E, K, P, or W\r\n^ stands for L, U, D, R, or I\n\r\nThe five letter code word, #&^!*, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNorth and South\n<|im_start|>answer\nNorth and South\n<|im_end|>" }, { "id": "#46839", "title": "Love Island", "fun": 2.68, "difficulty": 2.7, "author": "griphook", "desc": "Four men and four women are in Love Island. Each one falls in love with another and is himself/herself loved by someone else in a complete 8 person loop.\n\r\nPeter falls in love with a girl who is unfortunately in love with Albert. Joseph loves a girl who loves the man who loves Elaine. Liza is loved by the guy who is loved by the girl who is loved by Paolo. Linda hates Paolo and is hated by the man whom Amy loves.\n\r\nNo guy/guy or girl/girl in Love Island.\n\r\nWho loves Joseph and whom does Joseph love?", "hint": "No hint available.", "answer": "Linda loves Joseph, and Joseph loves Amy.\n\r\nAn 8 person loop may be represented as follows:\n\r\nM1 > G1 > M2 > G2 > M3 > G3 > M4 > G4 >\n\r\nFrom second paragraph:\n\r\nLine 1: Peter > G > Albert > G >\r\nLine 2: Joseph > G > M > Elaine >\r\nLine 3: Paolo > G > M > Liza >\r\nLine 4: Linda hates Paolo and is hated by the man Amy loves.\n\r\nStep One: Assume Peter is M1. (Peter can be M2 or M3 or M4 with the same result.)\n\r\nPeter > G1 > Albert > G2 > M3 > G3 > M4 > G4 >\n\r\nStep Two: Elaine is two persons removed from Joseph (from Line 2) so either:\n\r\n#A Peter > G1 > Albert > G2 > Joseph > G3 > M4 > Elaine >\r\n#B Peter > Elaine > Albert > G2 > M3 > G3 > Joseph > G4 >\n\r\nStep Three: In each case, the unknown male must be Paolo.\n\r\n#A Peter > G1 > Albert > G2 > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > G3 > Joseph > G4 >\n\r\nStep Four: Liza is two persons removed from Paolo (from Line 3).\n\r\n#A Peter > Liza > Albert > G2 > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > G3 > Joseph > Liza >\n\r\nStep Five: Linda hates Paolo (from Line 4), so:\r\nIn #A, she can't be G3 and must be G2.\r\nIn #B, she can't be G2 and must be G3.\n\r\n#A Peter > Liza > Albert > Linda > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > Linda > Joseph > Liza >\n\r\nStep Six: In each case, the unknown female must be Amy.\n\r\n#A Peter > Liza > Albert > Linda > Joseph > Amy > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > Amy > Paolo > Linda > Joseph > Liza >\n\r\nStep Seven: Linda is hated by the man whom Amy loves (from line 4).\r\nThus, #B does not work so the solution is #A.\n\r\nPeter > Liza > Albert > Linda > Joseph > Amy > Paolo > Elaine >", "category": "Logic", "date": "04/27/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour men and four women are in Love Island. Each one falls in love with another and is himself/herself loved by someone else in a complete 8 person loop.\n\r\nPeter falls in love with a girl who is unfortunately in love with Albert. Joseph loves a girl who loves the man who loves Elaine. Liza is loved by the guy who is loved by the girl who is loved by Paolo. Linda hates Paolo and is hated by the man whom Amy loves.\n\r\nNo guy/guy or girl/girl in Love Island.\n\r\nWho loves Joseph and whom does Joseph love?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLinda loves Joseph, and Joseph loves Amy.\n\r\nAn 8 person loop may be represented as follows:\n\r\nM1 > G1 > M2 > G2 > M3 > G3 > M4 > G4 >\n\r\nFrom second paragraph:\n\r\nLine 1: Peter > G > Albert > G >\r\nLine 2: Joseph > G > M > Elaine >\r\nLine 3: Paolo > G > M > Liza >\r\nLine 4: Linda hates Paolo and is hated by the man Amy loves.\n\r\nStep One: Assume Peter is M1. (Peter can be M2 or M3 or M4 with the same result.)\n\r\nPeter > G1 > Albert > G2 > M3 > G3 > M4 > G4 >\n\r\nStep Two: Elaine is two persons removed from Joseph (from Line 2) so either:\n\r\n#A Peter > G1 > Albert > G2 > Joseph > G3 > M4 > Elaine >\r\n#B Peter > Elaine > Albert > G2 > M3 > G3 > Joseph > G4 >\n\r\nStep Three: In each case, the unknown male must be Paolo.\n\r\n#A Peter > G1 > Albert > G2 > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > G3 > Joseph > G4 >\n\r\nStep Four: Liza is two persons removed from Paolo (from Line 3).\n\r\n#A Peter > Liza > Albert > G2 > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > G3 > Joseph > Liza >\n\r\nStep Five: Linda hates Paolo (from Line 4), so:\r\nIn #A, she can't be G3 and must be G2.\r\nIn #B, she can't be G2 and must be G3.\n\r\n#A Peter > Liza > Albert > Linda > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > Linda > Joseph > Liza >\n\r\nStep Six: In each case, the unknown female must be Amy.\n\r\n#A Peter > Liza > Albert > Linda > Joseph > Amy > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > Amy > Paolo > Linda > Joseph > Liza >\n\r\nStep Seven: Linda is hated by the man whom Amy loves (from line 4).\r\nThus, #B does not work so the solution is #A.\n\r\nPeter > Liza > Albert > Linda > Joseph > Amy > Paolo > Elaine >\n<|im_start|>answer\nLinda loves Joseph, and Joseph loves Amy.\n\r\nAn 8 person loop may be represented as follows:\n\r\nM1 > G1 > M2 > G2 > M3 > G3 > M4 > G4 >\n\r\nFrom second paragraph:\n\r\nLine 1: Peter > G > Albert > G >\r\nLine 2: Joseph > G > M > Elaine >\r\nLine 3: Paolo > G > M > Liza >\r\nLine 4: Linda hates Paolo and is hated by the man Amy loves.\n\r\nStep One: Assume Peter is M1. (Peter can be M2 or M3 or M4 with the same result.)\n\r\nPeter > G1 > Albert > G2 > M3 > G3 > M4 > G4 >\n\r\nStep Two: Elaine is two persons removed from Joseph (from Line 2) so either:\n\r\n#A Peter > G1 > Albert > G2 > Joseph > G3 > M4 > Elaine >\r\n#B Peter > Elaine > Albert > G2 > M3 > G3 > Joseph > G4 >\n\r\nStep Three: In each case, the unknown male must be Paolo.\n\r\n#A Peter > G1 > Albert > G2 > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > G3 > Joseph > G4 >\n\r\nStep Four: Liza is two persons removed from Paolo (from Line 3).\n\r\n#A Peter > Liza > Albert > G2 > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > G3 > Joseph > Liza >\n\r\nStep Five: Linda hates Paolo (from Line 4), so:\r\nIn #A, she can't be G3 and must be G2.\r\nIn #B, she can't be G2 and must be G3.\n\r\n#A Peter > Liza > Albert > Linda > Joseph > G3 > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > G2 > Paolo > Linda > Joseph > Liza >\n\r\nStep Six: In each case, the unknown female must be Amy.\n\r\n#A Peter > Liza > Albert > Linda > Joseph > Amy > Paolo > Elaine >\r\n#B Peter > Elaine > Albert > Amy > Paolo > Linda > Joseph > Liza >\n\r\nStep Seven: Linda is hated by the man whom Amy loves (from line 4).\r\nThus, #B does not work so the solution is #A.\n\r\nPeter > Liza > Albert > Linda > Joseph > Amy > Paolo > Elaine >\n<|im_end|>" }, { "id": "#13391", "title": "Double the Contrary", "fun": 2.68, "difficulty": 1.72, "author": "willymapo", "desc": "Lucy and Lory are sisters. They are special. They usually tell the truth in all cases, but when recalling something her sister has said, then they twist it a little bit. \n\r\nFor instance, when referring to something Lory had said, Lucy always says quite the contrary: \"Lucy, look, the sky is beautiful.\" \"Did you say the sky is ugly?\". \n\r\nIn Lory's case, when referring so something Lucy said, She always doubles any quantity that appears in the sentence: \" Hey, Lory, I found two flowers.\" \"Mom, Lucy says she found four flowers\". \n\r\nSome day they were talking about a friend of theirs and mom came by. She heard this: \n\r\n- As you say, Jorge is the younger brother. \n\r\n- But you said his brother was 20 years younger.\n\r\n- No, it was you who said that his brother was three times Jorge's age.\n\r\n- Well, that is not important. The important thing is that, as you said, Jorge is 30 years old. \n\r\nWhat are Jorge's and his brother's ages?", "hint": "Looks like Lucy talked first.", "answer": "Jorge is 15 years old, and his brother is 5 years old. \n\r\nLucy is the one that talks first, so Jorge is the older, not the younger. \n\r\nThen Lory talked, so Jorge's brother is 10 years younger, not 20. \n\r\nAgain Lucy, so it was Jorge who was 3 times his brother's age. \n\r\nAnd last, Lory says that Jorge is 30 years, meaning 15 is the actual age. \n\r\nSo, Jorge is 15, his brother 15-10 = 5, and Jorge is 3 times as old as his brother (3*5=15).", "category": "Logic", "date": "06/24/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLucy and Lory are sisters. They are special. They usually tell the truth in all cases, but when recalling something her sister has said, then they twist it a little bit. \n\r\nFor instance, when referring to something Lory had said, Lucy always says quite the contrary: \"Lucy, look, the sky is beautiful.\" \"Did you say the sky is ugly?\". \n\r\nIn Lory's case, when referring so something Lucy said, She always doubles any quantity that appears in the sentence: \" Hey, Lory, I found two flowers.\" \"Mom, Lucy says she found four flowers\". \n\r\nSome day they were talking about a friend of theirs and mom came by. She heard this: \n\r\n- As you say, Jorge is the younger brother. \n\r\n- But you said his brother was 20 years younger.\n\r\n- No, it was you who said that his brother was three times Jorge's age.\n\r\n- Well, that is not important. The important thing is that, as you said, Jorge is 30 years old. \n\r\nWhat are Jorge's and his brother's ages?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJorge is 15 years old, and his brother is 5 years old. \n\r\nLucy is the one that talks first, so Jorge is the older, not the younger. \n\r\nThen Lory talked, so Jorge's brother is 10 years younger, not 20. \n\r\nAgain Lucy, so it was Jorge who was 3 times his brother's age. \n\r\nAnd last, Lory says that Jorge is 30 years, meaning 15 is the actual age. \n\r\nSo, Jorge is 15, his brother 15-10 = 5, and Jorge is 3 times as old as his brother (3*5=15).\n<|im_start|>answer\nJorge is 15 years old, and his brother is 5 years old. \n\r\nLucy is the one that talks first, so Jorge is the older, not the younger. \n\r\nThen Lory talked, so Jorge's brother is 10 years younger, not 20. \n\r\nAgain Lucy, so it was Jorge who was 3 times his brother's age. \n\r\nAnd last, Lory says that Jorge is 30 years, meaning 15 is the actual age. \n\r\nSo, Jorge is 15, his brother 15-10 = 5, and Jorge is 3 times as old as his brother (3*5=15).\n<|im_end|>" }, { "id": "#29750", "title": "MPH", "fun": 2.68, "difficulty": 2.44, "author": "peppamintp", "desc": "Last week, Jude and four friends all went off for a drive to a different place (one went to Bywater). They traveled at speeds of 20, 30, 35, 40, and 45 MPH, and traveled 20, 30, 60, 70, and 80 miles. From the information given, determine each one's speed, the distance each traveled, and each person's destination.\n\r\n1. Jan drove 80 miles to her destination.\r\n2. The driver who covered 60 miles went at 40 mph; it wasn't Jess, who went to Overfield.\r\n3. It took two of the friends 40 minutes each to reach their destinations. Neither Jed nor the driver to Downlea was one of them.\r\n4. Jake took 2 hours to reach Upwood.\r\n5. The drive to Underford is 30 miles.", "hint": "No hint available.", "answer": "Jake, 35 MPH, 70, Upwood\r\nJan 20 MPH, 80, Downlea\r\nJed, 40 MPH, 60, Bywater\r\nJess, 30 MPH, 20, Overfield\r\nJude, 45 MPH, 30, Underford", "category": "Logic-Grid", "date": "04/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast week, Jude and four friends all went off for a drive to a different place (one went to Bywater). They traveled at speeds of 20, 30, 35, 40, and 45 MPH, and traveled 20, 30, 60, 70, and 80 miles. From the information given, determine each one's speed, the distance each traveled, and each person's destination.\n\r\n1. Jan drove 80 miles to her destination.\r\n2. The driver who covered 60 miles went at 40 mph; it wasn't Jess, who went to Overfield.\r\n3. It took two of the friends 40 minutes each to reach their destinations. Neither Jed nor the driver to Downlea was one of them.\r\n4. Jake took 2 hours to reach Upwood.\r\n5. The drive to Underford is 30 miles.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJake, 35 MPH, 70, Upwood\r\nJan 20 MPH, 80, Downlea\r\nJed, 40 MPH, 60, Bywater\r\nJess, 30 MPH, 20, Overfield\r\nJude, 45 MPH, 30, Underford\n<|im_start|>answer\nJake, 35 MPH, 70, Upwood\r\nJan 20 MPH, 80, Downlea\r\nJed, 40 MPH, 60, Bywater\r\nJess, 30 MPH, 20, Overfield\r\nJude, 45 MPH, 30, Underford\n<|im_end|>" }, { "id": "#1048", "title": "Roulette", "fun": 2.68, "difficulty": 1.93, "author": "vivek", "desc": "The famous playboy explained to a beautiful woman his system for playing roulette: \"In each round, I always bet half of the money I have at the time on red. Yesterday, I counted and I had won as many rounds as I had lost.\" Over the course of the night, did the gambler win, lose or break even?", "hint": "No hint available.", "answer": "He lost. Every time he wins, his money increases 1.5 times (with $100, he bets $50 and if he wins, he has $150). When he loses, his money is reduced by half. So a win-loss combination results in a loss of one quarter of his money. The more he plays, the more money he loses, even though he wins the same number of times as he loses.", "category": "Math", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe famous playboy explained to a beautiful woman his system for playing roulette: \"In each round, I always bet half of the money I have at the time on red. Yesterday, I counted and I had won as many rounds as I had lost.\" Over the course of the night, did the gambler win, lose or break even?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe lost. Every time he wins, his money increases 1.5 times (with $100, he bets $50 and if he wins, he has $150). When he loses, his money is reduced by half. So a win-loss combination results in a loss of one quarter of his money. The more he plays, the more money he loses, even though he wins the same number of times as he loses.\n<|im_start|>answer\nHe lost. Every time he wins, his money increases 1.5 times (with $100, he bets $50 and if he wins, he has $150). When he loses, his money is reduced by half. So a win-loss combination results in a loss of one quarter of his money. The more he plays, the more money he loses, even though he wins the same number of times as he loses.\n<|im_end|>" }, { "id": "#1763", "title": "Animal Fair", "fun": 2.68, "difficulty": 1.99, "author": "Nishoo", "desc": "Long long ago, in a village there used to be held an annual animal fair where only elephants, horses and sheep used to be sold. During one year the price-list in the fair was as follows:-\n\r\n One Elephant --- $5\r\n One Horse --- $1\r\n Twenty Sheep --- $1\n\r\nA merchant sent his servant with $100 to the fair and instructed him to buy 100 animals with the money....but the condition was that there had to be at least one animal of each kind in the lot and there must be no money left over.\r\nHow did the servant go about carrying out his task ?", "hint": "No hint available.", "answer": "The servant bought 19 elephants, 1 horse and 80 sheep.\n\r\nTotal number of animals = 19 + 1 + 80 \r\n = 100\n\r\nTotal cost = (19 x 5)+(1x1)+(80 x 1/20) \r\n = 95 + 1 + 4 \r\n = 100", "category": "Math", "date": "12/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLong long ago, in a village there used to be held an annual animal fair where only elephants, horses and sheep used to be sold. During one year the price-list in the fair was as follows:-\n\r\n One Elephant --- $5\r\n One Horse --- $1\r\n Twenty Sheep --- $1\n\r\nA merchant sent his servant with $100 to the fair and instructed him to buy 100 animals with the money....but the condition was that there had to be at least one animal of each kind in the lot and there must be no money left over.\r\nHow did the servant go about carrying out his task ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe servant bought 19 elephants, 1 horse and 80 sheep.\n\r\nTotal number of animals = 19 + 1 + 80 \r\n = 100\n\r\nTotal cost = (19 x 5)+(1x1)+(80 x 1/20) \r\n = 95 + 1 + 4 \r\n = 100\n<|im_start|>answer\nThe servant bought 19 elephants, 1 horse and 80 sheep.\n\r\nTotal number of animals = 19 + 1 + 80 \r\n = 100\n\r\nTotal cost = (19 x 5)+(1x1)+(80 x 1/20) \r\n = 95 + 1 + 4 \r\n = 100\n<|im_end|>" }, { "id": "#21349", "title": "Kitten Ka-boodle", "fun": 2.68, "difficulty": 1.33, "author": "MrBasKetBall", "desc": "Evan and his friends all have kittens. On Presidents' Day (3rd Monday of February), his cat Pumpkin was a year old. Meatloaf is 2 months older than Pumpkin. Cocoa is six months younger than Meatloaf. When Max and Maggie were born in the same litter, Cocoa was 3 months old. Lulu is 6 months older than Max and Maggie. Fluffy is 2 months younger than those two litter mates.\n\r\nIn what month of the year was each kitten born?", "hint": "Make a chart listing all the months of the year in order. Keep track of each kitten's birthday on the chart.", "answer": "Meatloaf was born in December.\r\nPumpkin was born in February.\r\nLulu was born in March.\r\nCocoa was born in June.\r\nMax and Maggie were born in September.\r\nFluffy was born in November.", "category": "Logic", "date": "03/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvan and his friends all have kittens. On Presidents' Day (3rd Monday of February), his cat Pumpkin was a year old. Meatloaf is 2 months older than Pumpkin. Cocoa is six months younger than Meatloaf. When Max and Maggie were born in the same litter, Cocoa was 3 months old. Lulu is 6 months older than Max and Maggie. Fluffy is 2 months younger than those two litter mates.\n\r\nIn what month of the year was each kitten born?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMeatloaf was born in December.\r\nPumpkin was born in February.\r\nLulu was born in March.\r\nCocoa was born in June.\r\nMax and Maggie were born in September.\r\nFluffy was born in November.\n<|im_start|>answer\nMeatloaf was born in December.\r\nPumpkin was born in February.\r\nLulu was born in March.\r\nCocoa was born in June.\r\nMax and Maggie were born in September.\r\nFluffy was born in November.\n<|im_end|>" }, { "id": "#2740", "title": "9:50", "fun": 2.68, "difficulty": 1.77, "author": "Cascas", "desc": "With one line, make it so that it says the time is 9:50.\n\r\n101010", "hint": "How else could it read 9:50", "answer": "10T010\n\r\nTen \"To\" Ten", "category": "Math", "date": "03/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith one line, make it so that it says the time is 9:50.\n\r\n101010\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10T010\n\r\nTen \"To\" Ten\n<|im_start|>answer\n10T010\n\r\nTen \"To\" Ten\n<|im_end|>" }, { "id": "#45158", "title": "Bancroft High School Math Test Scores", "fun": 2.68, "difficulty": 2.35, "author": "caberet", "desc": "Five students compared their most recent math test grades while waiting in the hallway for their art teacher to find his classroom keys. By some fluke, none of the budding artists are in the same math class or received the same grade (from an A+ to a B). Using the following clues, see if you can figure out the first name, last name, math class and grade of each student before the art teacher lets the students into class. Happy solving!\n\r\n1. Only one of the students had the same number of letters in both their first and last names; and only one had the same first letter in both names.\r\n2. Hunter received a higher grade than Mr. Attica, but lower than the geometry student.\r\n3. Even though she had two tests in one day, the algebra I student scored higher than the girl taking algebra II.\r\n4. Both students with a plus sign in their grades are boys.\r\n5. Ms. Ingraam, Ms. Grinde and the Trigonometry student all scored higher than a B+. The Sommer child and the business math student did not have an A in their grade.\r\n6. Hunter, the student with the same initial for both her first and last name, and the Geometry student are on the girls swim team. The trigonometry student and Ian spotted a thick set of keys in their teacher's duffle bag. (All five students are mentioned in this clue.)", "hint": "Hunter can be the name of either a girl or a boy.", "answer": "Andy Heath, A+, Trigonometry\r\nGigi Ingraam, A, Geometry\r\nHunter Grinde, A-, Algebra I\r\nIan Attica, B+ Business Math\r\nSarah Sommer, B, Algebra II", "category": "Logic-Grid", "date": "08/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive students compared their most recent math test grades while waiting in the hallway for their art teacher to find his classroom keys. By some fluke, none of the budding artists are in the same math class or received the same grade (from an A+ to a B). Using the following clues, see if you can figure out the first name, last name, math class and grade of each student before the art teacher lets the students into class. Happy solving!\n\r\n1. Only one of the students had the same number of letters in both their first and last names; and only one had the same first letter in both names.\r\n2. Hunter received a higher grade than Mr. Attica, but lower than the geometry student.\r\n3. Even though she had two tests in one day, the algebra I student scored higher than the girl taking algebra II.\r\n4. Both students with a plus sign in their grades are boys.\r\n5. Ms. Ingraam, Ms. Grinde and the Trigonometry student all scored higher than a B+. The Sommer child and the business math student did not have an A in their grade.\r\n6. Hunter, the student with the same initial for both her first and last name, and the Geometry student are on the girls swim team. The trigonometry student and Ian spotted a thick set of keys in their teacher's duffle bag. (All five students are mentioned in this clue.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndy Heath, A+, Trigonometry\r\nGigi Ingraam, A, Geometry\r\nHunter Grinde, A-, Algebra I\r\nIan Attica, B+ Business Math\r\nSarah Sommer, B, Algebra II\n<|im_start|>answer\nAndy Heath, A+, Trigonometry\r\nGigi Ingraam, A, Geometry\r\nHunter Grinde, A-, Algebra I\r\nIan Attica, B+ Business Math\r\nSarah Sommer, B, Algebra II\n<|im_end|>" }, { "id": "#32391", "title": "Arnold and Carlos: Part 1", "fun": 2.68, "difficulty": 2.03, "author": "HiImDavid", "desc": "Arnold and Carlos love math puzzles. They are constantly making them up for each other to solve. One day, Arnold presents his friend Carlos with a problem. This problem has four clues. Here is the problem Arnold gave:\n\r\n\"I am thinking of a mystery number.\n\r\n1. The mystery number is a 2-digit prime number.\r\n2. When the digits of the mystery number are reversed, another 2-digit prime number is formed.\r\n3. When the original number is added to the next highest prime number, the sum forms a square number.\r\n4. When the mystery number is added to the 2nd prime number after it, the sum is evenly divisible by 4.\n\r\nWhat is the mystery number?\"\n\r\nCan you help Carlos solve Arnold's problem?", "hint": "Make a list and eliminate possibilities due to the clues provided. Eventually, it leads to 1 answer.", "answer": "17.\n\r\nClue #1 - All of the 2-digit numbers are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.\n\r\nAfter Clue #1 we have 21 possibilities.\n\r\nClue #2 - When every number is reversed, the numbers are 11, 31, 71, 91, 32, 92, 13, 73, 14, 34, 74, 35, 95, 16, 76, 17, 37, 97, 38, 98, and 79. Of these, only 31, 71, 13, 73, 17, 37, 97, and 79 are different prime numbers (11 reversed is still 11).\n\r\nAfter Clue #2 we have 8 possibilities: 13, 17, 31, 37, 71, 73, 79, and 97.\n\r\nClue#3 - Add the next prime number to form a perfect square. So, using our list from Clue #2, we know our ten base numbers. We must add 13 and 17, 17 and 19, 31 and 37, 37 and 41, 71 and 73, 73 and 79, 79 and 83, 97 and 101. These sums are 30, 36, 68, 78, 144, 152, 162, and 198 respectively. Of these sums-only 36 (which was formed using 17) and 144 (formed using 71) are perfect squares.\n\r\nAfter Clue #3, we have 2 possibilities: 17 and 71.\n\r\nClue #4 - Add the 2nd prime number after to make a number evenly divisible by 4. This would mean we add 23 to 17, and 79 to 71. These sums are 40 and 150. Only 40 is evenly divisible by 4. So, only 17 fits.\n\r\nAfter Clue #4, we have one possibility: 17.", "category": "Math", "date": "08/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArnold and Carlos love math puzzles. They are constantly making them up for each other to solve. One day, Arnold presents his friend Carlos with a problem. This problem has four clues. Here is the problem Arnold gave:\n\r\n\"I am thinking of a mystery number.\n\r\n1. The mystery number is a 2-digit prime number.\r\n2. When the digits of the mystery number are reversed, another 2-digit prime number is formed.\r\n3. When the original number is added to the next highest prime number, the sum forms a square number.\r\n4. When the mystery number is added to the 2nd prime number after it, the sum is evenly divisible by 4.\n\r\nWhat is the mystery number?\"\n\r\nCan you help Carlos solve Arnold's problem?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n17.\n\r\nClue #1 - All of the 2-digit numbers are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.\n\r\nAfter Clue #1 we have 21 possibilities.\n\r\nClue #2 - When every number is reversed, the numbers are 11, 31, 71, 91, 32, 92, 13, 73, 14, 34, 74, 35, 95, 16, 76, 17, 37, 97, 38, 98, and 79. Of these, only 31, 71, 13, 73, 17, 37, 97, and 79 are different prime numbers (11 reversed is still 11).\n\r\nAfter Clue #2 we have 8 possibilities: 13, 17, 31, 37, 71, 73, 79, and 97.\n\r\nClue#3 - Add the next prime number to form a perfect square. So, using our list from Clue #2, we know our ten base numbers. We must add 13 and 17, 17 and 19, 31 and 37, 37 and 41, 71 and 73, 73 and 79, 79 and 83, 97 and 101. These sums are 30, 36, 68, 78, 144, 152, 162, and 198 respectively. Of these sums-only 36 (which was formed using 17) and 144 (formed using 71) are perfect squares.\n\r\nAfter Clue #3, we have 2 possibilities: 17 and 71.\n\r\nClue #4 - Add the 2nd prime number after to make a number evenly divisible by 4. This would mean we add 23 to 17, and 79 to 71. These sums are 40 and 150. Only 40 is evenly divisible by 4. So, only 17 fits.\n\r\nAfter Clue #4, we have one possibility: 17.\n<|im_start|>answer\n17.\n\r\nClue #1 - All of the 2-digit numbers are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.\n\r\nAfter Clue #1 we have 21 possibilities.\n\r\nClue #2 - When every number is reversed, the numbers are 11, 31, 71, 91, 32, 92, 13, 73, 14, 34, 74, 35, 95, 16, 76, 17, 37, 97, 38, 98, and 79. Of these, only 31, 71, 13, 73, 17, 37, 97, and 79 are different prime numbers (11 reversed is still 11).\n\r\nAfter Clue #2 we have 8 possibilities: 13, 17, 31, 37, 71, 73, 79, and 97.\n\r\nClue#3 - Add the next prime number to form a perfect square. So, using our list from Clue #2, we know our ten base numbers. We must add 13 and 17, 17 and 19, 31 and 37, 37 and 41, 71 and 73, 73 and 79, 79 and 83, 97 and 101. These sums are 30, 36, 68, 78, 144, 152, 162, and 198 respectively. Of these sums-only 36 (which was formed using 17) and 144 (formed using 71) are perfect squares.\n\r\nAfter Clue #3, we have 2 possibilities: 17 and 71.\n\r\nClue #4 - Add the 2nd prime number after to make a number evenly divisible by 4. This would mean we add 23 to 17, and 79 to 71. These sums are 40 and 150. Only 40 is evenly divisible by 4. So, only 17 fits.\n\r\nAfter Clue #4, we have one possibility: 17.\n<|im_end|>" }, { "id": "#36218", "title": "A Five-Letter Charade", "fun": 2.68, "difficulty": 2.74, "author": "aresII", "desc": "I am a word of five letters. Multiply my fifth by two and you have my first. Divide my first by twenty and you have my third. Divide my third by five and you have my second or fourth.", "hint": "No hint available.", "answer": "CIVIL. \r\nL (50) multiplied by 2 equal C (100).\r\nDivide C by 20 and you have V. Divide V by 5 and you have I.", "category": "Logic", "date": "04/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a word of five letters. Multiply my fifth by two and you have my first. Divide my first by twenty and you have my third. Divide my third by five and you have my second or fourth.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCIVIL. \r\nL (50) multiplied by 2 equal C (100).\r\nDivide C by 20 and you have V. Divide V by 5 and you have I.\n<|im_start|>answer\nCIVIL. \r\nL (50) multiplied by 2 equal C (100).\r\nDivide C by 20 and you have V. Divide V by 5 and you have I.\n<|im_end|>" }, { "id": "#31252", "title": "An Unequal Race", "fun": 2.68, "difficulty": 2.01, "author": "spuds", "desc": "Three friends planned to race each other on their bikes. Neil owned a good racing bike and had lots of experience (he belonged to a bike club), while Oscar had just learned to ride. The race seemed unfair, to say the least. After much discussion, they came up with a solution that seemed to allow a more equal race. They agreed on a distance of 50 miles and decided that the excellent biker, Neil, should form a team with the beginner, Oscar. They would bike against the other rider, Patrick, each riding half the distance and combining their time, while Patrick was to bike the full 50 miles by himself.\n\r\nWho would win the race if Oscar could ride only half as fast as Patrick, while Neil rode four times as fast as Oscar?", "hint": "No hint available.", "answer": "If Oscar needs X minutes for the first half of the distance, Neil needs 1/4 times X minutes for the second half. Patrick consequently needs 1/2 times X minutes for half the distance and X minutes for the total.\n\r\nOscar therefore takes exactly the same amount of time for the first half that Patrick takes for the entire distance, so Oscar and Neil lose the race.", "category": "Math", "date": "06/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends planned to race each other on their bikes. Neil owned a good racing bike and had lots of experience (he belonged to a bike club), while Oscar had just learned to ride. The race seemed unfair, to say the least. After much discussion, they came up with a solution that seemed to allow a more equal race. They agreed on a distance of 50 miles and decided that the excellent biker, Neil, should form a team with the beginner, Oscar. They would bike against the other rider, Patrick, each riding half the distance and combining their time, while Patrick was to bike the full 50 miles by himself.\n\r\nWho would win the race if Oscar could ride only half as fast as Patrick, while Neil rode four times as fast as Oscar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Oscar needs X minutes for the first half of the distance, Neil needs 1/4 times X minutes for the second half. Patrick consequently needs 1/2 times X minutes for half the distance and X minutes for the total.\n\r\nOscar therefore takes exactly the same amount of time for the first half that Patrick takes for the entire distance, so Oscar and Neil lose the race.\n<|im_start|>answer\nIf Oscar needs X minutes for the first half of the distance, Neil needs 1/4 times X minutes for the second half. Patrick consequently needs 1/2 times X minutes for half the distance and X minutes for the total.\n\r\nOscar therefore takes exactly the same amount of time for the first half that Patrick takes for the entire distance, so Oscar and Neil lose the race.\n<|im_end|>" }, { "id": "#20844", "title": "Littleton Employment", "fun": 2.68, "difficulty": 1.28, "author": "kellgo", "desc": "Littleton has five major sources of employment: JJ's Food Market, Poppy's Deli, Meat Heads Gym, Barber Bobs, and the Post Office. Each of these places is located on a different street in town: Maple Blvd, Royal Rd, Main St, Fern St, and Apple Ave. Peter, Joe, Alice, Bruce, and Betty all work at different locations on different streets. With the clues below figure out who works where and on what street. ~Good Luck\n\r\nBruce has to pass Fern St. on his way to work.\n\r\nEmployees with names beginning with \"B\" both work on streets with plant names.\n\r\nMeatheads Gym is a men's only gym and only has male employees.\n\r\nNobody's first letter in their name matches the first letters in their employer's name.\n\r\nPoppy's Deli is on Apple Ave.\n\r\nBetty, Joe, and Bruce work at places that do not entail selling food.\n\r\nThe person who works at JJ's Food Market doesn't work on Royal Rd.\n\r\nBetty and Alice met after work to go to the Food Market.", "hint": "No hint available.", "answer": "JJ's Food Market... Main St... Peter\r\nPost Office... Fern St... Betty\r\nBarber Bob's... Royal Rd... Joe\r\nMeatheads Gym... Maple Blvd...Bruce\r\nPoppy's Deli... Apple Ave... Alice", "category": "Logic-Grid", "date": "02/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittleton has five major sources of employment: JJ's Food Market, Poppy's Deli, Meat Heads Gym, Barber Bobs, and the Post Office. Each of these places is located on a different street in town: Maple Blvd, Royal Rd, Main St, Fern St, and Apple Ave. Peter, Joe, Alice, Bruce, and Betty all work at different locations on different streets. With the clues below figure out who works where and on what street. ~Good Luck\n\r\nBruce has to pass Fern St. on his way to work.\n\r\nEmployees with names beginning with \"B\" both work on streets with plant names.\n\r\nMeatheads Gym is a men's only gym and only has male employees.\n\r\nNobody's first letter in their name matches the first letters in their employer's name.\n\r\nPoppy's Deli is on Apple Ave.\n\r\nBetty, Joe, and Bruce work at places that do not entail selling food.\n\r\nThe person who works at JJ's Food Market doesn't work on Royal Rd.\n\r\nBetty and Alice met after work to go to the Food Market.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJJ's Food Market... Main St... Peter\r\nPost Office... Fern St... Betty\r\nBarber Bob's... Royal Rd... Joe\r\nMeatheads Gym... Maple Blvd...Bruce\r\nPoppy's Deli... Apple Ave... Alice\n<|im_start|>answer\nJJ's Food Market... Main St... Peter\r\nPost Office... Fern St... Betty\r\nBarber Bob's... Royal Rd... Joe\r\nMeatheads Gym... Maple Blvd...Bruce\r\nPoppy's Deli... Apple Ave... Alice\n<|im_end|>" }, { "id": "#28134", "title": "Opposites 5", "fun": 2.68, "difficulty": 1.96, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n? stands for M, I, D, S, or A\r\n< stands for D, L, S, J, or Y\r\n> stands for F, P, C, R, or E\r\n! stands for E, H, K, N, or L\n\r\nThe four letter code word, >?system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n? stands for M, I, D, S, or A\r\n< stands for D, L, S, J, or Y\r\n> stands for F, P, C, R, or E\r\n! stands for E, H, K, N, or L\n\r\nThe four letter code word, >?\n<|im_start|>assistant\n<|im_start|>think\nFall and Rise.\n<|im_start|>answer\nFall and Rise.\n<|im_end|>" }, { "id": "#29716", "title": "One to Nine", "fun": 2.68, "difficulty": 2.98, "author": "shenqiang", "desc": "Arrange the digits from 1 to 9 to make a 9-digit number ABCDEFGHI which satisfies the following conditions:\n\r\n1) AB is divisible by 2;\r\n2) ABC is divisible by 3;\r\n3) ABCD is divisible by 4;\r\n4) ABCDE is divisible by 5;\r\n5) ABCDEF is divisible by 6;\r\n6) ABCDEFG is divisible by 7;\r\n7) ABCDEFGH is divisible by 8;\r\n8) ABCDEFGHI is divisible by 9.\n\r\nThere is only one solution.", "hint": "Condition 8 is the easiest to satisfy just because it is automatically satisfied. But condition 6 is the hardest to satisfy, and should be left last.", "answer": "From condition 4, we know that E equals 5.\n\r\nFrom conditions 1, 3, 5 and 7, we know that B, D, F, H are even numbers, therefore A, C, G, I are 1, 3, 7, 9 in some order.\n\r\nFurthermore, from conditions 3 and 7 we know that CD is divisible by 4 and GH is divisible by 8 (because FGH is divisible by 8 and F is even). Because C and G are odd, D and H must be 2 and 6 in some order.\n\r\nFrom conditions 2 and 5, we know that A+B+C, D+E+F, G+H+I are all divisible by 3.\n\r\nIf D=2, then F=8, H=6, B=4. A+4+C is divisible by 3, therefore A and C must be 1 and 7 in some order, G and I must be 3 and 9 in some order. G6 is divisible by 8, therefore G=9. But neither 1472589 nor 7412589 is divisible by 7. \n\r\nTherefore D=6, and F=4, H=2, B=8. G2 is divisible by 8, therefore G=3 or 7. A+8+C is divisible by 3, therefore one of A and C is chosen from 1 and 7, the other is chosen from 3 and 9.\n\r\nIf G=3, then one of A and C is 9, the other is chosen from 1 and 7. But none of 1896543, 7896543, 9816543 and 9876543 is divisible by 7.\n\r\nTherefore G=7, one of A and C is 1, the other is chosen from 3 and 9. From 1836547, 1896547, 3816547 and 9816547, only 3816547 is divisible by 7 (the quotient is 545221).\n\r\nTherefore, the number we are looking for is 381654729.", "category": "Math", "date": "04/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the digits from 1 to 9 to make a 9-digit number ABCDEFGHI which satisfies the following conditions:\n\r\n1) AB is divisible by 2;\r\n2) ABC is divisible by 3;\r\n3) ABCD is divisible by 4;\r\n4) ABCDE is divisible by 5;\r\n5) ABCDEF is divisible by 6;\r\n6) ABCDEFG is divisible by 7;\r\n7) ABCDEFGH is divisible by 8;\r\n8) ABCDEFGHI is divisible by 9.\n\r\nThere is only one solution.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom condition 4, we know that E equals 5.\n\r\nFrom conditions 1, 3, 5 and 7, we know that B, D, F, H are even numbers, therefore A, C, G, I are 1, 3, 7, 9 in some order.\n\r\nFurthermore, from conditions 3 and 7 we know that CD is divisible by 4 and GH is divisible by 8 (because FGH is divisible by 8 and F is even). Because C and G are odd, D and H must be 2 and 6 in some order.\n\r\nFrom conditions 2 and 5, we know that A+B+C, D+E+F, G+H+I are all divisible by 3.\n\r\nIf D=2, then F=8, H=6, B=4. A+4+C is divisible by 3, therefore A and C must be 1 and 7 in some order, G and I must be 3 and 9 in some order. G6 is divisible by 8, therefore G=9. But neither 1472589 nor 7412589 is divisible by 7. \n\r\nTherefore D=6, and F=4, H=2, B=8. G2 is divisible by 8, therefore G=3 or 7. A+8+C is divisible by 3, therefore one of A and C is chosen from 1 and 7, the other is chosen from 3 and 9.\n\r\nIf G=3, then one of A and C is 9, the other is chosen from 1 and 7. But none of 1896543, 7896543, 9816543 and 9876543 is divisible by 7.\n\r\nTherefore G=7, one of A and C is 1, the other is chosen from 3 and 9. From 1836547, 1896547, 3816547 and 9816547, only 3816547 is divisible by 7 (the quotient is 545221).\n\r\nTherefore, the number we are looking for is 381654729.\n<|im_start|>answer\nFrom condition 4, we know that E equals 5.\n\r\nFrom conditions 1, 3, 5 and 7, we know that B, D, F, H are even numbers, therefore A, C, G, I are 1, 3, 7, 9 in some order.\n\r\nFurthermore, from conditions 3 and 7 we know that CD is divisible by 4 and GH is divisible by 8 (because FGH is divisible by 8 and F is even). Because C and G are odd, D and H must be 2 and 6 in some order.\n\r\nFrom conditions 2 and 5, we know that A+B+C, D+E+F, G+H+I are all divisible by 3.\n\r\nIf D=2, then F=8, H=6, B=4. A+4+C is divisible by 3, therefore A and C must be 1 and 7 in some order, G and I must be 3 and 9 in some order. G6 is divisible by 8, therefore G=9. But neither 1472589 nor 7412589 is divisible by 7. \n\r\nTherefore D=6, and F=4, H=2, B=8. G2 is divisible by 8, therefore G=3 or 7. A+8+C is divisible by 3, therefore one of A and C is chosen from 1 and 7, the other is chosen from 3 and 9.\n\r\nIf G=3, then one of A and C is 9, the other is chosen from 1 and 7. But none of 1896543, 7896543, 9816543 and 9876543 is divisible by 7.\n\r\nTherefore G=7, one of A and C is 1, the other is chosen from 3 and 9. From 1836547, 1896547, 3816547 and 9816547, only 3816547 is divisible by 7 (the quotient is 545221).\n\r\nTherefore, the number we are looking for is 381654729.\n<|im_end|>" }, { "id": "#15289", "title": "Daughters and Sons", "fun": 2.68, "difficulty": 1.74, "author": "Smithy", "desc": "A mother and her friend are talking about how many children they have. The friend knows how many daughters the mother has, but doesn't know how many sons she has. The mother says:\r\n\"All of my children have the same amount of brothers and the same amount of sisters as the other children.\"\n\r\nNow the friend knew how many sons she had. How many sons did the mother have?", "hint": "We don't have to know the number of daughters - all that's needed is the mother's statement, and the fact that the friend knows the number of daughters.", "answer": "The mother says that her children all have the same amount of brothers and same amount of sisters as each other. If B is the number of sons and G the number of daughters, then each boy has B-1 brothers and G sisters, and each girl has G-1 sisters and B brothers.\n\r\nFor any combination of brothers and sisters to fit into that rule, there must be either no sons or no daughters, because if there were some of each the sons would have more sisters than the daughters, and vice versa.\n\r\nIf the friend knows the mother has no daughters, the statement does not help her know how many sons there are, as there could be any number.\n\r\nThe friend knows the value of G, and if it was any number other than 0 (which it definitely is), the number of sons would have to be 0.", "category": "Logic", "date": "10/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA mother and her friend are talking about how many children they have. The friend knows how many daughters the mother has, but doesn't know how many sons she has. The mother says:\r\n\"All of my children have the same amount of brothers and the same amount of sisters as the other children.\"\n\r\nNow the friend knew how many sons she had. How many sons did the mother have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe mother says that her children all have the same amount of brothers and same amount of sisters as each other. If B is the number of sons and G the number of daughters, then each boy has B-1 brothers and G sisters, and each girl has G-1 sisters and B brothers.\n\r\nFor any combination of brothers and sisters to fit into that rule, there must be either no sons or no daughters, because if there were some of each the sons would have more sisters than the daughters, and vice versa.\n\r\nIf the friend knows the mother has no daughters, the statement does not help her know how many sons there are, as there could be any number.\n\r\nThe friend knows the value of G, and if it was any number other than 0 (which it definitely is), the number of sons would have to be 0.\n<|im_start|>answer\nThe mother says that her children all have the same amount of brothers and same amount of sisters as each other. If B is the number of sons and G the number of daughters, then each boy has B-1 brothers and G sisters, and each girl has G-1 sisters and B brothers.\n\r\nFor any combination of brothers and sisters to fit into that rule, there must be either no sons or no daughters, because if there were some of each the sons would have more sisters than the daughters, and vice versa.\n\r\nIf the friend knows the mother has no daughters, the statement does not help her know how many sons there are, as there could be any number.\n\r\nThe friend knows the value of G, and if it was any number other than 0 (which it definitely is), the number of sons would have to be 0.\n<|im_end|>" }, { "id": "#3028", "title": "Bad Dream", "fun": 2.68, "difficulty": 1.6300000000000001, "author": "lil_thugsta", "desc": "Two brothers were watching a horror film on video late one night. One brother dozed off and dreamed that he was being chased by the crazy man from the movie, who was trying to kill him. In the dream, he hid in a cupboard. There was no sound except his heart pounding, and he had no idea where his crazed captor was. He was terrified! At that moment, the video finished, and his brother put his hand on the shoulder of his sleeping sibling to wake him. The shock at that tense moment was enough that the sleeping brother suffered a massive heart attack and died instantly.\n\r\nDid this really happen?", "hint": "No hint available.", "answer": "Of course it's not true! If he died instantly, how would anyone know what his dream was about?", "category": "Logic", "date": "03/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo brothers were watching a horror film on video late one night. One brother dozed off and dreamed that he was being chased by the crazy man from the movie, who was trying to kill him. In the dream, he hid in a cupboard. There was no sound except his heart pounding, and he had no idea where his crazed captor was. He was terrified! At that moment, the video finished, and his brother put his hand on the shoulder of his sleeping sibling to wake him. The shock at that tense moment was enough that the sleeping brother suffered a massive heart attack and died instantly.\n\r\nDid this really happen?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOf course it's not true! If he died instantly, how would anyone know what his dream was about?\n<|im_start|>answer\nOf course it's not true! If he died instantly, how would anyone know what his dream was about?\n<|im_end|>" }, { "id": "#36927", "title": "Good Guess", "fun": 2.68, "difficulty": 1.47, "author": "reptile5000", "desc": "In order to win a free laptop computer, students had to guess the exact numbers of gumballs in a jar. The students guessed 45, 41, 55, 50, and 43, but nobody won. The guesses were off by 3, 7, 5, 7, and 2 (given in no particular order). From this information, can you determine the number of gumballs in the jar?", "hint": "No hint available.", "answer": "Forty-Eight gumballs. (48)\r\nSince two guessers were off by seven and no guesses were repeated, these values had to refer to numbers at the opposite sides of the spread The two extremes are 41 and 55. If you add 7 to 41, and subtract 7 from 55, you arrive at the answer, 48.", "category": "Math", "date": "06/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn order to win a free laptop computer, students had to guess the exact numbers of gumballs in a jar. The students guessed 45, 41, 55, 50, and 43, but nobody won. The guesses were off by 3, 7, 5, 7, and 2 (given in no particular order). From this information, can you determine the number of gumballs in the jar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nForty-Eight gumballs. (48)\r\nSince two guessers were off by seven and no guesses were repeated, these values had to refer to numbers at the opposite sides of the spread The two extremes are 41 and 55. If you add 7 to 41, and subtract 7 from 55, you arrive at the answer, 48.\n<|im_start|>answer\nForty-Eight gumballs. (48)\r\nSince two guessers were off by seven and no guesses were repeated, these values had to refer to numbers at the opposite sides of the spread The two extremes are 41 and 55. If you add 7 to 41, and subtract 7 from 55, you arrive at the answer, 48.\n<|im_end|>" }, { "id": "#32344", "title": "Zig and Jodie Hit the Town!", "fun": 2.68, "difficulty": 2.18, "author": "zigthepig", "desc": "Zig went out with her friend Jodie four times last week. From the clues given, can you work out when and where they went, how much it cost, and what genre of music was played?\n\r\n1. Zig and Jodie went to Moo 2 days before they went to Streetwise, which didn't cost £26.\n\r\n2. Sunday's outing was £24; the music that night wasn't rock.\n\r\n3. The metal music, which wasn't on Tuesday, only impressed Zig.\n\r\n4. Kevin's, where the bill came to £20, didn't provide rock music.\n\r\n5. At Blue Ice, Jodie spent £2 less than Zig did at the Thursday outing, where they listened to pop music.", "hint": "No hint available.", "answer": "Sunday, Blue Ice, £24, Metal\r\nTuesday, Kevin's, £20, Classical\r\nThursday, Moo, £26, Pop\r\nSaturday, Streetwise, £22, Rock", "category": "Logic-Grid", "date": "08/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nZig went out with her friend Jodie four times last week. From the clues given, can you work out when and where they went, how much it cost, and what genre of music was played?\n\r\n1. Zig and Jodie went to Moo 2 days before they went to Streetwise, which didn't cost £26.\n\r\n2. Sunday's outing was £24; the music that night wasn't rock.\n\r\n3. The metal music, which wasn't on Tuesday, only impressed Zig.\n\r\n4. Kevin's, where the bill came to £20, didn't provide rock music.\n\r\n5. At Blue Ice, Jodie spent £2 less than Zig did at the Thursday outing, where they listened to pop music.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSunday, Blue Ice, £24, Metal\r\nTuesday, Kevin's, £20, Classical\r\nThursday, Moo, £26, Pop\r\nSaturday, Streetwise, £22, Rock\n<|im_start|>answer\nSunday, Blue Ice, £24, Metal\r\nTuesday, Kevin's, £20, Classical\r\nThursday, Moo, £26, Pop\r\nSaturday, Streetwise, £22, Rock\n<|im_end|>" }, { "id": "#14036", "title": "Multiple Equations", "fun": 2.68, "difficulty": 1.92, "author": "taniapereira99", "desc": "The letters A through H below each represent a number from 1 to 9. Each letter represents the same number throughout and no number is used twice. If C=3 what is H?\n\r\nA - C = D\r\nG x E = F\r\nB + G = H\r\nD/C = E", "hint": "No hint available.", "answer": "H = 5\n\r\nA=9, B=1, C=3,\r\nD=6, E=2, F=8,\r\nG=4", "category": "Math", "date": "07/25/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe letters A through H below each represent a number from 1 to 9. Each letter represents the same number throughout and no number is used twice. If C=3 what is H?\n\r\nA - C = D\r\nG x E = F\r\nB + G = H\r\nD/C = E\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nH = 5\n\r\nA=9, B=1, C=3,\r\nD=6, E=2, F=8,\r\nG=4\n<|im_start|>answer\nH = 5\n\r\nA=9, B=1, C=3,\r\nD=6, E=2, F=8,\r\nG=4\n<|im_end|>" }, { "id": "#35138", "title": "Collecting Food", "fun": 2.68, "difficulty": 1.99, "author": "nick93", "desc": "Two girls (Dawn and Europa) and two boys (Franklin and Gin-tan) worked all day last Saturday collecting canned food for needy families. The last names of the girls and boys are Qualman, Rockland, Sutton, and Talbot, and their ages are 8, 10, 11, and 12. The streets they live on are Marker Avenue, Nesbitt Road, Oddway Road, and Portland Avenue. The numbers of cans of food each collected were 100, 110, 132, 144.\n\r\nRead the clues below and match up everything.\n\r\n1. Rockland and Gin-Tan's ages are each 1/10 the number of cans of food each collected.\n\r\n2. Dawn and Sutton are girl scouts.\n\r\n3. The boy who lives on Marker Avenue collected more cans than Talbot.\n\r\n4. The number of letters in the name of Europa's street is the same as her age. (When counting the letters in the street, the words \"road\", and \"avenue\" are not counted. Example: Marker Road counts as having 6 letters.)\n\r\n5. Europa is 2/3 as old as, and collected more cans of food than, the girl who lives on Oddway road.", "hint": "No hint available.", "answer": "Dawn Qualman, 12 years old, 132 cans, lives on Oddway Road.\n\r\nEuropa Sutton, 8 years old, collected 144 cans, lives on Portland Avenue.\n\r\nFranklin Rockland, 11 years old, collected 110 cans, lives on Marker Avenue.\n\r\nGin-Tan Talbot, 10 years old, collected 100 cans, lives on Nesbitt Road.", "category": "Logic-Grid", "date": "01/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo girls (Dawn and Europa) and two boys (Franklin and Gin-tan) worked all day last Saturday collecting canned food for needy families. The last names of the girls and boys are Qualman, Rockland, Sutton, and Talbot, and their ages are 8, 10, 11, and 12. The streets they live on are Marker Avenue, Nesbitt Road, Oddway Road, and Portland Avenue. The numbers of cans of food each collected were 100, 110, 132, 144.\n\r\nRead the clues below and match up everything.\n\r\n1. Rockland and Gin-Tan's ages are each 1/10 the number of cans of food each collected.\n\r\n2. Dawn and Sutton are girl scouts.\n\r\n3. The boy who lives on Marker Avenue collected more cans than Talbot.\n\r\n4. The number of letters in the name of Europa's street is the same as her age. (When counting the letters in the street, the words \"road\", and \"avenue\" are not counted. Example: Marker Road counts as having 6 letters.)\n\r\n5. Europa is 2/3 as old as, and collected more cans of food than, the girl who lives on Oddway road.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDawn Qualman, 12 years old, 132 cans, lives on Oddway Road.\n\r\nEuropa Sutton, 8 years old, collected 144 cans, lives on Portland Avenue.\n\r\nFranklin Rockland, 11 years old, collected 110 cans, lives on Marker Avenue.\n\r\nGin-Tan Talbot, 10 years old, collected 100 cans, lives on Nesbitt Road.\n<|im_start|>answer\nDawn Qualman, 12 years old, 132 cans, lives on Oddway Road.\n\r\nEuropa Sutton, 8 years old, collected 144 cans, lives on Portland Avenue.\n\r\nFranklin Rockland, 11 years old, collected 110 cans, lives on Marker Avenue.\n\r\nGin-Tan Talbot, 10 years old, collected 100 cans, lives on Nesbitt Road.\n<|im_end|>" }, { "id": "#4579", "title": "Rows and Columns", "fun": 2.68, "difficulty": 2.35, "author": "arij", "desc": "In the sum (shown below), the top row added to the middle row gives the bottom one. Working from top to bottom, remove one digit from each row, from any columns (closing the gaps) to leave three columns of digits, then a second digit from each row to leave two columns, and finally a third to leave one column so that a valid sum remains each time. What are the three sets of digits removed?\n\r\n 3826\r\n +2768\r\n ------\r\n 6594", "hint": "No hint available.", "answer": "Reading from top to bottom, the order of the deletions is : 8,7,6; 3,6,9; 6,8,5.", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the sum (shown below), the top row added to the middle row gives the bottom one. Working from top to bottom, remove one digit from each row, from any columns (closing the gaps) to leave three columns of digits, then a second digit from each row to leave two columns, and finally a third to leave one column so that a valid sum remains each time. What are the three sets of digits removed?\n\r\n 3826\r\n +2768\r\n ------\r\n 6594\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nReading from top to bottom, the order of the deletions is : 8,7,6; 3,6,9; 6,8,5.\n<|im_start|>answer\nReading from top to bottom, the order of the deletions is : 8,7,6; 3,6,9; 6,8,5.\n<|im_end|>" }, { "id": "#15005", "title": "Wacky Wakkey", "fun": 2.68, "difficulty": 2.04, "author": "rose_rox", "desc": "In a land far, far away, called Wakkey, there are 4 rulers who rule 4 different lands, wear 4 different crowns with 4 different populations. \n\r\nRulers: King Ray, King Ross, Queen Rose, Queen Rosa \r\nLands: Bang, Boom, Bam, Buzz \r\nCrowns: Gold, Diamond, Silver, Bronze \r\nPopulations: 1000, 800, 300, 200 \n\r\nFigure out who owns what land, wears which crown and rules what population. \n\r\nClues: \r\n1. The ruler with the lowest population wears the silver crown. \r\n2. Queen Rosa is ruler of Bang. \r\n3. King Ray does not rule and has a hatred towards Buzz. \r\n4. King Ross frequently boasts he rules the highest population. \r\n5. No king, as both dislike bronze, wears that crown. \r\n6. Queen Rose does not rule Bam. \r\n7. Queen Rosa rules a population higher than 300. \r\n8. King Ross owns Buzz.\r\n9. King Ray cannot afford and thus does not wear the diamond crown. \r\n10. Queen Rose is fairly wealthy and wears the gold crown. \r\n11. King Ross does not rule Bam. \r\n12. Boom has a population of 300.", "hint": "No hint available.", "answer": "King Ray is the ruler of Bam, wears the silver crown and rules a population of 200. \n\r\nKing Ross is the ruler of Buzz, wears the diamond crown and rules a population of 1000. \n\r\nQueen Rose is the ruler of Boom, wears the gold crown and rules a population of 300. \n\r\nQueen Rosa is the ruler of Bang, wears the bronze crown and rules a population of 800.\n\n\r\nExplanation (making a chart would be helpful):\r\nClue 1: We know what it states and will keep this in mind.\r\nClue 2: Tells us Queen Rosa owns Bang, so we mark that down.\r\nClue 3: Tells us King Ray does not rule Buzz and neither can Queen Rosa, so King Ross or Queen Rose must own Buzz. \r\nClue 4: Tells us King Ross rules the highest population, 1000, so we mark that down. (This narrows the hint in clue 1 to the three remaining rulers.)\r\nClue 5: Tells us no king wears the bronze crown, so it must be either Queen Rose or Queen Rosa.\r\nClue 6: Tells us Queen Rose does not rule Bam. (Now we know that one of the kings owns Bam, and either King Ross or Queen Rose owns Buzz from the info given in clue 3.)\r\nClue 7: Tells us Queen Rosa rules a population higher than 300 - in other words, rules a population of 800 since 1000 is ruled already.\r\nClue 8: Tells us King Ross owns Buzz, so we mark that down. This also means that Queen Rose MUST own Boom since it is the only land left.\r\nClue 9: Tells us King Ray does not wear the diamond crown, so we mark that down.\r\nClue 10: Tells us Queen Rose wears the gold crown, so we mark that down. This also means that, since Queen Rose wears the gold, Queen Rosa MUST be wearing the bronze because as it states in clue 5, no king wears the bronze. Also tells us that King Ray must wear the silver crown, as he cannot wear the gold, bronze, or diamond crowns (Clues 5, 9, 10). Therefore, King Ross wears the diamond crown.\r\nClue 11: Tells us King Ross does not rule Bam, so King Ray MUST rule Bam because he does not rule Buzz as said in clue 3, and Queen Rose does not rule Bam as said in clue 6 - that is marked down.\r\nClue 12: Tells us Boom has a population of 300, so that is marked down. This means that, since the only population left is 100, and from what it says in clue 1, King Ray rules the 100.", "category": "Logic", "date": "10/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a land far, far away, called Wakkey, there are 4 rulers who rule 4 different lands, wear 4 different crowns with 4 different populations. \n\r\nRulers: King Ray, King Ross, Queen Rose, Queen Rosa \r\nLands: Bang, Boom, Bam, Buzz \r\nCrowns: Gold, Diamond, Silver, Bronze \r\nPopulations: 1000, 800, 300, 200 \n\r\nFigure out who owns what land, wears which crown and rules what population. \n\r\nClues: \r\n1. The ruler with the lowest population wears the silver crown. \r\n2. Queen Rosa is ruler of Bang. \r\n3. King Ray does not rule and has a hatred towards Buzz. \r\n4. King Ross frequently boasts he rules the highest population. \r\n5. No king, as both dislike bronze, wears that crown. \r\n6. Queen Rose does not rule Bam. \r\n7. Queen Rosa rules a population higher than 300. \r\n8. King Ross owns Buzz.\r\n9. King Ray cannot afford and thus does not wear the diamond crown. \r\n10. Queen Rose is fairly wealthy and wears the gold crown. \r\n11. King Ross does not rule Bam. \r\n12. Boom has a population of 300.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKing Ray is the ruler of Bam, wears the silver crown and rules a population of 200. \n\r\nKing Ross is the ruler of Buzz, wears the diamond crown and rules a population of 1000. \n\r\nQueen Rose is the ruler of Boom, wears the gold crown and rules a population of 300. \n\r\nQueen Rosa is the ruler of Bang, wears the bronze crown and rules a population of 800.\n\n\r\nExplanation (making a chart would be helpful):\r\nClue 1: We know what it states and will keep this in mind.\r\nClue 2: Tells us Queen Rosa owns Bang, so we mark that down.\r\nClue 3: Tells us King Ray does not rule Buzz and neither can Queen Rosa, so King Ross or Queen Rose must own Buzz. \r\nClue 4: Tells us King Ross rules the highest population, 1000, so we mark that down. (This narrows the hint in clue 1 to the three remaining rulers.)\r\nClue 5: Tells us no king wears the bronze crown, so it must be either Queen Rose or Queen Rosa.\r\nClue 6: Tells us Queen Rose does not rule Bam. (Now we know that one of the kings owns Bam, and either King Ross or Queen Rose owns Buzz from the info given in clue 3.)\r\nClue 7: Tells us Queen Rosa rules a population higher than 300 - in other words, rules a population of 800 since 1000 is ruled already.\r\nClue 8: Tells us King Ross owns Buzz, so we mark that down. This also means that Queen Rose MUST own Boom since it is the only land left.\r\nClue 9: Tells us King Ray does not wear the diamond crown, so we mark that down.\r\nClue 10: Tells us Queen Rose wears the gold crown, so we mark that down. This also means that, since Queen Rose wears the gold, Queen Rosa MUST be wearing the bronze because as it states in clue 5, no king wears the bronze. Also tells us that King Ray must wear the silver crown, as he cannot wear the gold, bronze, or diamond crowns (Clues 5, 9, 10). Therefore, King Ross wears the diamond crown.\r\nClue 11: Tells us King Ross does not rule Bam, so King Ray MUST rule Bam because he does not rule Buzz as said in clue 3, and Queen Rose does not rule Bam as said in clue 6 - that is marked down.\r\nClue 12: Tells us Boom has a population of 300, so that is marked down. This means that, since the only population left is 100, and from what it says in clue 1, King Ray rules the 100.\n<|im_start|>answer\nKing Ray is the ruler of Bam, wears the silver crown and rules a population of 200. \n\r\nKing Ross is the ruler of Buzz, wears the diamond crown and rules a population of 1000. \n\r\nQueen Rose is the ruler of Boom, wears the gold crown and rules a population of 300. \n\r\nQueen Rosa is the ruler of Bang, wears the bronze crown and rules a population of 800.\n\n\r\nExplanation (making a chart would be helpful):\r\nClue 1: We know what it states and will keep this in mind.\r\nClue 2: Tells us Queen Rosa owns Bang, so we mark that down.\r\nClue 3: Tells us King Ray does not rule Buzz and neither can Queen Rosa, so King Ross or Queen Rose must own Buzz. \r\nClue 4: Tells us King Ross rules the highest population, 1000, so we mark that down. (This narrows the hint in clue 1 to the three remaining rulers.)\r\nClue 5: Tells us no king wears the bronze crown, so it must be either Queen Rose or Queen Rosa.\r\nClue 6: Tells us Queen Rose does not rule Bam. (Now we know that one of the kings owns Bam, and either King Ross or Queen Rose owns Buzz from the info given in clue 3.)\r\nClue 7: Tells us Queen Rosa rules a population higher than 300 - in other words, rules a population of 800 since 1000 is ruled already.\r\nClue 8: Tells us King Ross owns Buzz, so we mark that down. This also means that Queen Rose MUST own Boom since it is the only land left.\r\nClue 9: Tells us King Ray does not wear the diamond crown, so we mark that down.\r\nClue 10: Tells us Queen Rose wears the gold crown, so we mark that down. This also means that, since Queen Rose wears the gold, Queen Rosa MUST be wearing the bronze because as it states in clue 5, no king wears the bronze. Also tells us that King Ray must wear the silver crown, as he cannot wear the gold, bronze, or diamond crowns (Clues 5, 9, 10). Therefore, King Ross wears the diamond crown.\r\nClue 11: Tells us King Ross does not rule Bam, so King Ray MUST rule Bam because he does not rule Buzz as said in clue 3, and Queen Rose does not rule Bam as said in clue 6 - that is marked down.\r\nClue 12: Tells us Boom has a population of 300, so that is marked down. This means that, since the only population left is 100, and from what it says in clue 1, King Ray rules the 100.\n<|im_end|>" }, { "id": "#7827", "title": "Dellzup", "fun": 2.68, "difficulty": 2.21, "author": "hprulz", "desc": "Harry was on holiday last year on the island of Dellzup. Dellzup has a really peculiar shape for an island. It's rectangular, 20 miles long and only 15 feet wide, and is totally covered in trees! It has two tiny villages on it, Start and End. Unfortunately, a fire has begun at Start and is travelling toward End at around 1 mile per hour. There is also a wind which is blowing towards End at around 2 miles per hour. Now Harry, who is at End, has no way of getting off the island: he cannot pass through the fire, he cannot put the fire out, and there is no one to help him. How can he save himself?", "hint": "No hint available.", "answer": "The simplest method is to light a new fire about 1 mile from End. This fire will burn toward End (because of the wind) and when it reaches End, it will go out. Harry can then go to End, knowing that the main fire cannot reach him as his smaller fire has already burned all of the trees down.", "category": "Logic", "date": "10/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHarry was on holiday last year on the island of Dellzup. Dellzup has a really peculiar shape for an island. It's rectangular, 20 miles long and only 15 feet wide, and is totally covered in trees! It has two tiny villages on it, Start and End. Unfortunately, a fire has begun at Start and is travelling toward End at around 1 mile per hour. There is also a wind which is blowing towards End at around 2 miles per hour. Now Harry, who is at End, has no way of getting off the island: he cannot pass through the fire, he cannot put the fire out, and there is no one to help him. How can he save himself?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe simplest method is to light a new fire about 1 mile from End. This fire will burn toward End (because of the wind) and when it reaches End, it will go out. Harry can then go to End, knowing that the main fire cannot reach him as his smaller fire has already burned all of the trees down.\n<|im_start|>answer\nThe simplest method is to light a new fire about 1 mile from End. This fire will burn toward End (because of the wind) and when it reaches End, it will go out. Harry can then go to End, knowing that the main fire cannot reach him as his smaller fire has already burned all of the trees down.\n<|im_end|>" }, { "id": "#8164", "title": "Luke's Ultimate Challenge", "fun": 2.68, "difficulty": 1.39, "author": "bluelightnign", "desc": "Luke issued a challenge to his friend Bob. He asked him a question and gave him 4 simple clues as follows.\n\r\n1. My age is 3 times as large as my brother's.\r\n2. 4 years ago it was 5 times as old as my brother's.\r\n3. Six years ago my age was 9 times that of my brother's.\r\n4. The ages add to give an even numeral.\n\r\nWhat is Luke's age?", "hint": "Luke's age is a multiple of his brother's age.", "answer": "Luke is 24 and his brother is 8.", "category": "Math", "date": "10/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLuke issued a challenge to his friend Bob. He asked him a question and gave him 4 simple clues as follows.\n\r\n1. My age is 3 times as large as my brother's.\r\n2. 4 years ago it was 5 times as old as my brother's.\r\n3. Six years ago my age was 9 times that of my brother's.\r\n4. The ages add to give an even numeral.\n\r\nWhat is Luke's age?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLuke is 24 and his brother is 8.\n<|im_start|>answer\nLuke is 24 and his brother is 8.\n<|im_end|>" }, { "id": "#36366", "title": "The Thief 2", "fun": 2.68, "difficulty": 1.15, "author": "redbunny016", "desc": "A thief stole a diamond from a New York auction house this morning. Detective Dan has the names of three suspects. Mr. Brewer said he spent the morning at the Metropolitan Museum of Art; Mr. Murphy said he took a cab to the Statue of Liberty; and Miss Markum said she was sightseeing from the Empire State Building. Which one does Detective Dan suspect is the thief?", "hint": "No hint available.", "answer": "Mr. Murphy, because the Statue of Liberty is on a small island, accessible by ferry not cab. Mr. Murphy's flawed alibi suggests he may be the thief.", "category": "Logic", "date": "04/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA thief stole a diamond from a New York auction house this morning. Detective Dan has the names of three suspects. Mr. Brewer said he spent the morning at the Metropolitan Museum of Art; Mr. Murphy said he took a cab to the Statue of Liberty; and Miss Markum said she was sightseeing from the Empire State Building. Which one does Detective Dan suspect is the thief?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Murphy, because the Statue of Liberty is on a small island, accessible by ferry not cab. Mr. Murphy's flawed alibi suggests he may be the thief.\n<|im_start|>answer\nMr. Murphy, because the Statue of Liberty is on a small island, accessible by ferry not cab. Mr. Murphy's flawed alibi suggests he may be the thief.\n<|im_end|>" }, { "id": "#3147", "title": "Forgotten Watch", "fun": 2.68, "difficulty": 1.91, "author": "204_blaze_41", "desc": "Mr. Greenwich and his wife were shopping when they decided to go their separate ways to speed things up. They agreed to meet at the bank at 2:00 p.m. Mr. Greenwich realized several minutes later that he had forgotten his watch. He asked a lady walking by for the correct time. Her watch was five minutes fast, but she thought it was ten minutes slow. Mrs. Greenwich had also forgotten her watch so she asked a gentleman passing by for the correct time. The man's watch was ten minutes slow, but he thought it was 15 fast. Taking into account the errors in the watches, who was at the bank first and at what time did they arrive?", "hint": "No hint available.", "answer": "Mr. Greenwich arrived first at quarter to two. He was told a time that was actually 15 minutes faster than the true time. Mrs. Greenwich arrived at 25 after since she was told a time that was 25 minutes slower than the true time.", "category": "Math", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Greenwich and his wife were shopping when they decided to go their separate ways to speed things up. They agreed to meet at the bank at 2:00 p.m. Mr. Greenwich realized several minutes later that he had forgotten his watch. He asked a lady walking by for the correct time. Her watch was five minutes fast, but she thought it was ten minutes slow. Mrs. Greenwich had also forgotten her watch so she asked a gentleman passing by for the correct time. The man's watch was ten minutes slow, but he thought it was 15 fast. Taking into account the errors in the watches, who was at the bank first and at what time did they arrive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Greenwich arrived first at quarter to two. He was told a time that was actually 15 minutes faster than the true time. Mrs. Greenwich arrived at 25 after since she was told a time that was 25 minutes slower than the true time.\n<|im_start|>answer\nMr. Greenwich arrived first at quarter to two. He was told a time that was actually 15 minutes faster than the true time. Mrs. Greenwich arrived at 25 after since she was told a time that was 25 minutes slower than the true time.\n<|im_end|>" }, { "id": "#3053", "title": "Where's the Father?", "fun": 2.68, "difficulty": 2.13, "author": "arij", "desc": "The mother is 21 years older than the child.\r\n6 years from now, the mother will be 5 times as old as the child.\n\r\nQuestion : Where is the father?", "hint": "No hint available.", "answer": "The mum is 21 years older than the child, so...\r\nM = C + 21\n\r\nIn 6 years from now the mum will be 5 times as old as the child.\r\nM + 6 = (C + 6) * 5\n\r\n(C + 21)+ 6 = (C + 6) * 5\r\nC + 27 = 5C + 30\r\n-3 = 4C\r\nC = -3/4\n\r\nThe child is -3/4 years old, i.e. it'll be born in 9 month's time.\r\nSo, the father is probably nearby.", "category": "Math", "date": "03/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe mother is 21 years older than the child.\r\n6 years from now, the mother will be 5 times as old as the child.\n\r\nQuestion : Where is the father?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe mum is 21 years older than the child, so...\r\nM = C + 21\n\r\nIn 6 years from now the mum will be 5 times as old as the child.\r\nM + 6 = (C + 6) * 5\n\r\n(C + 21)+ 6 = (C + 6) * 5\r\nC + 27 = 5C + 30\r\n-3 = 4C\r\nC = -3/4\n\r\nThe child is -3/4 years old, i.e. it'll be born in 9 month's time.\r\nSo, the father is probably nearby.\n<|im_start|>answer\nThe mum is 21 years older than the child, so...\r\nM = C + 21\n\r\nIn 6 years from now the mum will be 5 times as old as the child.\r\nM + 6 = (C + 6) * 5\n\r\n(C + 21)+ 6 = (C + 6) * 5\r\nC + 27 = 5C + 30\r\n-3 = 4C\r\nC = -3/4\n\r\nThe child is -3/4 years old, i.e. it'll be born in 9 month's time.\r\nSo, the father is probably nearby.\n<|im_end|>" }, { "id": "#376", "title": "1 2 3 4 5 6 7 8 9 = 100", "fun": 2.68, "difficulty": 2.18, "author": "Mr. G", "desc": "Can you place + and - signs between the following numerals to make the equation true? You can only use a total of 3 symbols and you cannot rearrange the numerals.\r\n1 2 3 4 5 6 7 8 9 = 100", "hint": "You will use - - +, in that order.", "answer": "123 - 45 - 67 + 89 = 100", "category": "Math", "date": "03/27/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you place + and - signs between the following numerals to make the equation true? You can only use a total of 3 symbols and you cannot rearrange the numerals.\r\n1 2 3 4 5 6 7 8 9 = 100\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n123 - 45 - 67 + 89 = 100\n<|im_start|>answer\n123 - 45 - 67 + 89 = 100\n<|im_end|>" }, { "id": "#3134", "title": "Driving North", "fun": 2.68, "difficulty": 1.57, "author": "204_blaze_41", "desc": "Karl Malloy, the famous magician, claims that when he is in the far north, he can point his car north on a ordinary road, drive it for one mile, and without turning around, end up one mile south from where he started. How does he do it?", "hint": "No hint available.", "answer": "Karl drives his car in reverse.", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKarl Malloy, the famous magician, claims that when he is in the far north, he can point his car north on a ordinary road, drive it for one mile, and without turning around, end up one mile south from where he started. How does he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKarl drives his car in reverse.\n<|im_start|>answer\nKarl drives his car in reverse.\n<|im_end|>" }, { "id": "#917", "title": "Jacks and Aces", "fun": 2.68, "difficulty": 2.49, "author": "slippy0101", "desc": "A man has 3 cards face down on a table. One is a jack and two are aces. He knows the order but you do not. You can ask him one yes or no question, but when you do, you have to point to one of the cards. If you point to an ace, he will tell the truth, if you point to the jack, he will randomly say yes or no. You have to find one of the aces.", "hint": "Yes, there is always a chance you will be pointing to the jack, and that the answer will be meaningless (just a random yes/no) but there is a way to work around it. Don't give up!", "answer": "Point to the middle card and say, \"Is the card to the right an ace?\" If the answer is yes, then the card on the right is an ace. If the answer is no, the card on the left is an ace. This solution works because if you're pointing to an ace then he's obviously telling the truth and if you're pointing to the jack the answer doesn't matter anyway because you will pick one of the other two which are both aces.", "category": "Logic", "date": "09/22/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man has 3 cards face down on a table. One is a jack and two are aces. He knows the order but you do not. You can ask him one yes or no question, but when you do, you have to point to one of the cards. If you point to an ace, he will tell the truth, if you point to the jack, he will randomly say yes or no. You have to find one of the aces.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPoint to the middle card and say, \"Is the card to the right an ace?\" If the answer is yes, then the card on the right is an ace. If the answer is no, the card on the left is an ace. This solution works because if you're pointing to an ace then he's obviously telling the truth and if you're pointing to the jack the answer doesn't matter anyway because you will pick one of the other two which are both aces.\n<|im_start|>answer\nPoint to the middle card and say, \"Is the card to the right an ace?\" If the answer is yes, then the card on the right is an ace. If the answer is no, the card on the left is an ace. This solution works because if you're pointing to an ace then he's obviously telling the truth and if you're pointing to the jack the answer doesn't matter anyway because you will pick one of the other two which are both aces.\n<|im_end|>" }, { "id": "#31980", "title": "Nighty Night", "fun": 2.67, "difficulty": 0.96, "author": "ava199345", "desc": "While her four daughters were at camp, Mrs. Smith decided to clean their rooms for them. She vacuumed their floor, and washed their laundry and their bedclothes. When she took the laundry out of the dryer, she couldn't remember what went on which bed. She did, however, remember certain things about each girl that helped her. Can you figure it out?\n\r\nGirls- Daphne, Rose, Gabi, Chelsea\r\nColor of comforter- orange, pink, purple, blue\r\nNumber of pillows- 1, 2, 3, 4\r\nStuffed animal- dog, bear, rabbit, cat\n\r\n1) The girls are Rose, the girl that likes purple, the one that has a stuffed rabbit, and the person that has two pillows.\r\n2) Chelsea doesn't have the most pillows or the least.\r\n3) The girl with the most pillows also has a stuffed rabbit.\r\n4) Gabi feels snug in the most pillows.\r\n5) Rose has a blue bear to match her comforter.\r\n6) Daphne and Chelsea both have animals that begin with the same letter as their name.\r\n7) Daphne's favorite color is orange and Chelsea has three pillows.", "hint": "No hint available.", "answer": "Daphne- 2 pillows, orange, dog\r\nRose- 1 pillow, blue, bear\r\nGabi- 4 pillows, pink, rabbit\r\nChelsea- 3 pillows, purple, cat", "category": "Logic-Grid", "date": "07/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile her four daughters were at camp, Mrs. Smith decided to clean their rooms for them. She vacuumed their floor, and washed their laundry and their bedclothes. When she took the laundry out of the dryer, she couldn't remember what went on which bed. She did, however, remember certain things about each girl that helped her. Can you figure it out?\n\r\nGirls- Daphne, Rose, Gabi, Chelsea\r\nColor of comforter- orange, pink, purple, blue\r\nNumber of pillows- 1, 2, 3, 4\r\nStuffed animal- dog, bear, rabbit, cat\n\r\n1) The girls are Rose, the girl that likes purple, the one that has a stuffed rabbit, and the person that has two pillows.\r\n2) Chelsea doesn't have the most pillows or the least.\r\n3) The girl with the most pillows also has a stuffed rabbit.\r\n4) Gabi feels snug in the most pillows.\r\n5) Rose has a blue bear to match her comforter.\r\n6) Daphne and Chelsea both have animals that begin with the same letter as their name.\r\n7) Daphne's favorite color is orange and Chelsea has three pillows.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDaphne- 2 pillows, orange, dog\r\nRose- 1 pillow, blue, bear\r\nGabi- 4 pillows, pink, rabbit\r\nChelsea- 3 pillows, purple, cat\n<|im_start|>answer\nDaphne- 2 pillows, orange, dog\r\nRose- 1 pillow, blue, bear\r\nGabi- 4 pillows, pink, rabbit\r\nChelsea- 3 pillows, purple, cat\n<|im_end|>" }, { "id": "#30971", "title": "Slam Dunk", "fun": 2.67, "difficulty": 3.2, "author": "cnmne", "desc": "The hotly-contested basketball game had just ended. Coach Shortfuse, enraged by what he considered poor officiating, grabbed the stat sheets and fed them into a paper shredder. Fortunately, the officials remembered several facts about the scoring. With this information, determine: each starter's first and last name, his position, his jersey number, and points scored.\n\r\nFirst Names: Allen, Jason, Kevin, Shaquille, Tim\r\nLast Names: Duncan, Garnett, Iverson, Kidd, O'Neal\r\nPosition: Center, Power Forward, Small Forward, Shooting Guard, Point Guard\r\nJersey Numbers: #12, #15, #23, #34, #44\r\nPoints Scored: 24, 22, 20, 11, 10\n\r\n1) In addition to the five starters, three bench players also scored. One of the bench players was the fourth-leading scorer; the other two each scored less than 10 points each. All scoring players scored a different amount of points.\r\n2) Kevin scored exactly one-fifth of the total team points.\r\n3) The center scored more points than Allen, who scored more than #34.\r\n4) #15 scored more points than Duncan, who scored more than Shaquille.\r\n5) Garnett scored more points than the power forward, who scored more than #12.\r\n6) Tim scored more points than O'Neal, who scored more than the shooting guard.\r\n7) One of the forwards has \"K\" for an initial.\r\n8) One of the guards has \"K\" for an initial.\r\n9) The players that have a vowel for an initial wear jerseys with an odd number.\r\n10) Iverson scored twice as many points as one of the bench players.\r\n11) Allen scored 18 more points than one of the bench players.\r\n12) Only one starter scored more points than his jersey number.\r\n13) Neither forward wears an odd number.", "hint": "No hint available.", "answer": "Much of the grid can be filled using the normal process of elimination. An explanation for determining the bench scores and team score is provided.\n\r\nThe five starters scored a total of 87 (24 + 22 + 20 + 11 + 10) points. From clue 1, three bench players scored points in the following ranges: 1 through 8, 2 through 9, 12 through 19. This means that the team scored anywhere from 102 (87 + 12 + 2 + 1) to 123 (87 + 19 + 9 + 8) points. From clue 2, the team point total must be a multiple of 5. Kevin scored either 22 (team score = 110) or 24 (team score = 120). From clue 10, Iverson scored either 10 or 24 (11 can not be twice any integer, 20 or 22 would have been twice a starter's score). This means that a bench player scored either 5 or 12. From clue 11, Allen scored 20, 22, or 24 (10 or 11 would have had a bench player scoring negative points). This means that a bench player scored 2, 4, or 6. Since the bench player tied to Allen had a different possible score than the bench player tied to Iverson, Allen can not be Iverson. This leaves the following possible bench scoring combinations: 2, 5, 16; 2, 12, 9; 4, 5, 14; 4, 12, 7; 6, 5, 12; 6, 12, 5. With the 87 points scored by the starters, all combinations produce a team score of 110. The team score could not have been 120, since that would require one of the bench players to score more than 19 points, or require two bench players to score more than 9 points (both violating clue 1).\n\r\nAllen O'Neal, point guard, #23, 20 points\r\nJason Duncan, power forward, #34, 11 points\r\nKevin Garnett, small forward, #44, 22 points\r\nShaquille Kidd, shooting guard, #12, 10 points\r\nTim Iverson, center, #15, 24 points", "category": "Logic-Grid", "date": "06/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe hotly-contested basketball game had just ended. Coach Shortfuse, enraged by what he considered poor officiating, grabbed the stat sheets and fed them into a paper shredder. Fortunately, the officials remembered several facts about the scoring. With this information, determine: each starter's first and last name, his position, his jersey number, and points scored.\n\r\nFirst Names: Allen, Jason, Kevin, Shaquille, Tim\r\nLast Names: Duncan, Garnett, Iverson, Kidd, O'Neal\r\nPosition: Center, Power Forward, Small Forward, Shooting Guard, Point Guard\r\nJersey Numbers: #12, #15, #23, #34, #44\r\nPoints Scored: 24, 22, 20, 11, 10\n\r\n1) In addition to the five starters, three bench players also scored. One of the bench players was the fourth-leading scorer; the other two each scored less than 10 points each. All scoring players scored a different amount of points.\r\n2) Kevin scored exactly one-fifth of the total team points.\r\n3) The center scored more points than Allen, who scored more than #34.\r\n4) #15 scored more points than Duncan, who scored more than Shaquille.\r\n5) Garnett scored more points than the power forward, who scored more than #12.\r\n6) Tim scored more points than O'Neal, who scored more than the shooting guard.\r\n7) One of the forwards has \"K\" for an initial.\r\n8) One of the guards has \"K\" for an initial.\r\n9) The players that have a vowel for an initial wear jerseys with an odd number.\r\n10) Iverson scored twice as many points as one of the bench players.\r\n11) Allen scored 18 more points than one of the bench players.\r\n12) Only one starter scored more points than his jersey number.\r\n13) Neither forward wears an odd number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMuch of the grid can be filled using the normal process of elimination. An explanation for determining the bench scores and team score is provided.\n\r\nThe five starters scored a total of 87 (24 + 22 + 20 + 11 + 10) points. From clue 1, three bench players scored points in the following ranges: 1 through 8, 2 through 9, 12 through 19. This means that the team scored anywhere from 102 (87 + 12 + 2 + 1) to 123 (87 + 19 + 9 + 8) points. From clue 2, the team point total must be a multiple of 5. Kevin scored either 22 (team score = 110) or 24 (team score = 120). From clue 10, Iverson scored either 10 or 24 (11 can not be twice any integer, 20 or 22 would have been twice a starter's score). This means that a bench player scored either 5 or 12. From clue 11, Allen scored 20, 22, or 24 (10 or 11 would have had a bench player scoring negative points). This means that a bench player scored 2, 4, or 6. Since the bench player tied to Allen had a different possible score than the bench player tied to Iverson, Allen can not be Iverson. This leaves the following possible bench scoring combinations: 2, 5, 16; 2, 12, 9; 4, 5, 14; 4, 12, 7; 6, 5, 12; 6, 12, 5. With the 87 points scored by the starters, all combinations produce a team score of 110. The team score could not have been 120, since that would require one of the bench players to score more than 19 points, or require two bench players to score more than 9 points (both violating clue 1).\n\r\nAllen O'Neal, point guard, #23, 20 points\r\nJason Duncan, power forward, #34, 11 points\r\nKevin Garnett, small forward, #44, 22 points\r\nShaquille Kidd, shooting guard, #12, 10 points\r\nTim Iverson, center, #15, 24 points\n<|im_start|>answer\nMuch of the grid can be filled using the normal process of elimination. An explanation for determining the bench scores and team score is provided.\n\r\nThe five starters scored a total of 87 (24 + 22 + 20 + 11 + 10) points. From clue 1, three bench players scored points in the following ranges: 1 through 8, 2 through 9, 12 through 19. This means that the team scored anywhere from 102 (87 + 12 + 2 + 1) to 123 (87 + 19 + 9 + 8) points. From clue 2, the team point total must be a multiple of 5. Kevin scored either 22 (team score = 110) or 24 (team score = 120). From clue 10, Iverson scored either 10 or 24 (11 can not be twice any integer, 20 or 22 would have been twice a starter's score). This means that a bench player scored either 5 or 12. From clue 11, Allen scored 20, 22, or 24 (10 or 11 would have had a bench player scoring negative points). This means that a bench player scored 2, 4, or 6. Since the bench player tied to Allen had a different possible score than the bench player tied to Iverson, Allen can not be Iverson. This leaves the following possible bench scoring combinations: 2, 5, 16; 2, 12, 9; 4, 5, 14; 4, 12, 7; 6, 5, 12; 6, 12, 5. With the 87 points scored by the starters, all combinations produce a team score of 110. The team score could not have been 120, since that would require one of the bench players to score more than 19 points, or require two bench players to score more than 9 points (both violating clue 1).\n\r\nAllen O'Neal, point guard, #23, 20 points\r\nJason Duncan, power forward, #34, 11 points\r\nKevin Garnett, small forward, #44, 22 points\r\nShaquille Kidd, shooting guard, #12, 10 points\r\nTim Iverson, center, #15, 24 points\n<|im_end|>" }, { "id": "#47775", "title": "Breaking Codes", "fun": 2.67, "difficulty": 2.34, "author": "jtolley", "desc": "You are a spy trying to gain access to a high profile building that contains very classified information. The only thing standing between you and those secrets is a keypunch security system containing the digits 1-9 that will open the door to the building. Your spy agency has provided you details about the order of the keys you need to enter:\n\r\n1. Each digit is pressed once and only once.\r\n2. No two consecutive digits are pressed consecutively. \r\n3. The digits 2 and 4 are pressed 2nd and 4th in some order; the digits 6 and 8 are pressed 6th and 8th in some order.\r\n4. The sum of the first 5 digits pressed is 19; the sum of the last 5 digits pressed is 27. \n\r\nAs you wonder why your agency couldn't just write down the sequence for you, you crack the code and enter the building.\n\r\nWhat sequence of keys did you press on the security system to get into the building?", "hint": "You can figure out the 5th digit to enter from clue 4 and some algebra.", "answer": "5, 2, 7, 4, 1, 8, 3, 6, 9\n\r\nFrom clue 4, the sum of the first 4 digits to be pressed, the last 4 digits to be pressed, and two times the 5th digit to be pressed is 19 + 27 = 46. The sum of the first and last 4 digits to be pressed and the 5th digit must be the sum of the digits 1-9, from clue 1. This sum is 45, meaning the 5th digit is 46-45 = 1.\n\r\nFrom clues 2 and 3, 2 must be the 2nd digit and 4 must be the 4th digit. \n\r\nFrom clue 3, 7 must be the 1st or 3rd digit pressed since it can not be pressed before or after the 6 or 8. From clue 4, this means 5 must be pressed 1st or 3rd. But, from clue 2, it can not be the 3rd digit, so it must be the first, meaning 7 is the 3rd digit pressed.\n\r\nThat leaves 3, 6, 8, and 9 as the last 4 digits to be pressed. If 8 were pressed 8th, then the 9 must be pressed 6th, a contradiction with clue 4. So 8 must be pressed 6th meaning 9 is to be pressed last. This leaves 6 to be entered 8th and 3 to be entered 7th.", "category": "Logic", "date": "08/17/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are a spy trying to gain access to a high profile building that contains very classified information. The only thing standing between you and those secrets is a keypunch security system containing the digits 1-9 that will open the door to the building. Your spy agency has provided you details about the order of the keys you need to enter:\n\r\n1. Each digit is pressed once and only once.\r\n2. No two consecutive digits are pressed consecutively. \r\n3. The digits 2 and 4 are pressed 2nd and 4th in some order; the digits 6 and 8 are pressed 6th and 8th in some order.\r\n4. The sum of the first 5 digits pressed is 19; the sum of the last 5 digits pressed is 27. \n\r\nAs you wonder why your agency couldn't just write down the sequence for you, you crack the code and enter the building.\n\r\nWhat sequence of keys did you press on the security system to get into the building?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5, 2, 7, 4, 1, 8, 3, 6, 9\n\r\nFrom clue 4, the sum of the first 4 digits to be pressed, the last 4 digits to be pressed, and two times the 5th digit to be pressed is 19 + 27 = 46. The sum of the first and last 4 digits to be pressed and the 5th digit must be the sum of the digits 1-9, from clue 1. This sum is 45, meaning the 5th digit is 46-45 = 1.\n\r\nFrom clues 2 and 3, 2 must be the 2nd digit and 4 must be the 4th digit. \n\r\nFrom clue 3, 7 must be the 1st or 3rd digit pressed since it can not be pressed before or after the 6 or 8. From clue 4, this means 5 must be pressed 1st or 3rd. But, from clue 2, it can not be the 3rd digit, so it must be the first, meaning 7 is the 3rd digit pressed.\n\r\nThat leaves 3, 6, 8, and 9 as the last 4 digits to be pressed. If 8 were pressed 8th, then the 9 must be pressed 6th, a contradiction with clue 4. So 8 must be pressed 6th meaning 9 is to be pressed last. This leaves 6 to be entered 8th and 3 to be entered 7th.\n<|im_start|>answer\n5, 2, 7, 4, 1, 8, 3, 6, 9\n\r\nFrom clue 4, the sum of the first 4 digits to be pressed, the last 4 digits to be pressed, and two times the 5th digit to be pressed is 19 + 27 = 46. The sum of the first and last 4 digits to be pressed and the 5th digit must be the sum of the digits 1-9, from clue 1. This sum is 45, meaning the 5th digit is 46-45 = 1.\n\r\nFrom clues 2 and 3, 2 must be the 2nd digit and 4 must be the 4th digit. \n\r\nFrom clue 3, 7 must be the 1st or 3rd digit pressed since it can not be pressed before or after the 6 or 8. From clue 4, this means 5 must be pressed 1st or 3rd. But, from clue 2, it can not be the 3rd digit, so it must be the first, meaning 7 is the 3rd digit pressed.\n\r\nThat leaves 3, 6, 8, and 9 as the last 4 digits to be pressed. If 8 were pressed 8th, then the 9 must be pressed 6th, a contradiction with clue 4. So 8 must be pressed 6th meaning 9 is to be pressed last. This leaves 6 to be entered 8th and 3 to be entered 7th.\n<|im_end|>" }, { "id": "#35920", "title": "The Crazy Interior Designer", "fun": 2.67, "difficulty": 1.8800000000000001, "author": "dishu", "desc": "The crazy interior designer Craz had another crazy brainwave last week. He decided to paint his furniture in weird colours and place different furniture items in unusual locations of his house. He displaced one item each day of the week. He was going to write about how his \"genius\" idea worked to his best friend, but unfortunately forgot the details. All he remembered was the following bits of information. Please help him make the whole story for his friend.\n\r\nDays : Monday, Tuesday, Wednesday, Thursday, Friday\r\nFurniture items: Study Table, Clothes Stand, Dining Table, Commode, Bed\r\nLocations: Kitchen, Bathroom, Balcony, Library, Bedroom\r\nColours: Violet, Red, Green, Pink, Blue\n\r\n1. The dining table was painted green on Monday.\r\n2. The kitchen housed a blue furniture piece.\r\n3. The bedroom was filled with foul smell on Wednesday due to the violet coloured item placed there.\r\n4. It was not Friday, when the red coloured piece (not meant for sleeping) was placed in the Library.\r\n5. The pink coloured study table was displaced on Tuesday.\r\n6. The study table location was clearly not meant for serious studies as one could easily get distracted by the ongoings in the neighbourhood.", "hint": "Cloth Stand = Clothes Stand", "answer": "Dear Friend,\n\r\nI had a really brilliant idea last week to break the monotony of everyday life. Each day of the week, I painted one furniture piece of my house in an unusual colour and placed it in a different location rather than its usual place. On Monday, I painted my dining table in a bright parrot green colour and put it in my bathroom. On Tuesday, I placed my bright pink study table in the balcony; the ongoings in the neighbourhood really kept me refreshed and prevented me from falling asleep while studying. On Wednesday however, my experiment was not so successful as the violet coloured commode really filled my bedroom with a stinking foul smell. But the red coloured clothes stand worked like a curtain in the library on Thursday. Finally, on Friday, I prevented myself from making midnight excursions trips to the refrigerator as I placed my blue bed in the kitchen itself.\r\n Love,\r\nCraz\n\r\nNeedless to say, Craz's friend is still laughing after reading this letter.", "category": "Logic-Grid", "date": "03/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe crazy interior designer Craz had another crazy brainwave last week. He decided to paint his furniture in weird colours and place different furniture items in unusual locations of his house. He displaced one item each day of the week. He was going to write about how his \"genius\" idea worked to his best friend, but unfortunately forgot the details. All he remembered was the following bits of information. Please help him make the whole story for his friend.\n\r\nDays : Monday, Tuesday, Wednesday, Thursday, Friday\r\nFurniture items: Study Table, Clothes Stand, Dining Table, Commode, Bed\r\nLocations: Kitchen, Bathroom, Balcony, Library, Bedroom\r\nColours: Violet, Red, Green, Pink, Blue\n\r\n1. The dining table was painted green on Monday.\r\n2. The kitchen housed a blue furniture piece.\r\n3. The bedroom was filled with foul smell on Wednesday due to the violet coloured item placed there.\r\n4. It was not Friday, when the red coloured piece (not meant for sleeping) was placed in the Library.\r\n5. The pink coloured study table was displaced on Tuesday.\r\n6. The study table location was clearly not meant for serious studies as one could easily get distracted by the ongoings in the neighbourhood.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDear Friend,\n\r\nI had a really brilliant idea last week to break the monotony of everyday life. Each day of the week, I painted one furniture piece of my house in an unusual colour and placed it in a different location rather than its usual place. On Monday, I painted my dining table in a bright parrot green colour and put it in my bathroom. On Tuesday, I placed my bright pink study table in the balcony; the ongoings in the neighbourhood really kept me refreshed and prevented me from falling asleep while studying. On Wednesday however, my experiment was not so successful as the violet coloured commode really filled my bedroom with a stinking foul smell. But the red coloured clothes stand worked like a curtain in the library on Thursday. Finally, on Friday, I prevented myself from making midnight excursions trips to the refrigerator as I placed my blue bed in the kitchen itself.\r\n Love,\r\nCraz\n\r\nNeedless to say, Craz's friend is still laughing after reading this letter.\n<|im_start|>answer\nDear Friend,\n\r\nI had a really brilliant idea last week to break the monotony of everyday life. Each day of the week, I painted one furniture piece of my house in an unusual colour and placed it in a different location rather than its usual place. On Monday, I painted my dining table in a bright parrot green colour and put it in my bathroom. On Tuesday, I placed my bright pink study table in the balcony; the ongoings in the neighbourhood really kept me refreshed and prevented me from falling asleep while studying. On Wednesday however, my experiment was not so successful as the violet coloured commode really filled my bedroom with a stinking foul smell. But the red coloured clothes stand worked like a curtain in the library on Thursday. Finally, on Friday, I prevented myself from making midnight excursions trips to the refrigerator as I placed my blue bed in the kitchen itself.\r\n Love,\r\nCraz\n\r\nNeedless to say, Craz's friend is still laughing after reading this letter.\n<|im_end|>" }, { "id": "#49269", "title": "Math Magicians", "fun": 2.67, "difficulty": 1.19, "author": "firefox99", "desc": "An infinite number of mathematicians are standing behind a bar. The first asks the barman for half a pint of beer, the second for a quarter pint, the third an eighth, and so on. How many pints of beer will the barman need to fulfill all mathematicians' wishes?", "hint": "No hint available.", "answer": "Just 1. Add 'em up!", "category": "Math", "date": "01/24/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn infinite number of mathematicians are standing behind a bar. The first asks the barman for half a pint of beer, the second for a quarter pint, the third an eighth, and so on. How many pints of beer will the barman need to fulfill all mathematicians' wishes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJust 1. Add 'em up!\n<|im_start|>answer\nJust 1. Add 'em up!\n<|im_end|>" }, { "id": "#5607", "title": "Neighbours", "fun": 2.67, "difficulty": 2.42, "author": "jon14pople", "desc": "Adam, Ben and Cyril were born in 1309, 1310 and 1311 on the same road in old Jerusalem. They lived their whole life there, and all lived to be over 60. They also had a full active life. However, they never crossed paths with each other. Why should that be so?", "hint": "No hint available.", "answer": "Adam was a Muslim, Ben was a Christian and Cyril was a Jew. Adam was born in 1309 of the Muslim calendar, Ben 1310 in the Christian calendar and Cyril 1311 in the Jewish calendar. Cyril was born over 3000 years before Ben, who in turn was born 619 years before Adam.", "category": "Logic", "date": "07/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdam, Ben and Cyril were born in 1309, 1310 and 1311 on the same road in old Jerusalem. They lived their whole life there, and all lived to be over 60. They also had a full active life. However, they never crossed paths with each other. Why should that be so?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam was a Muslim, Ben was a Christian and Cyril was a Jew. Adam was born in 1309 of the Muslim calendar, Ben 1310 in the Christian calendar and Cyril 1311 in the Jewish calendar. Cyril was born over 3000 years before Ben, who in turn was born 619 years before Adam.\n<|im_start|>answer\nAdam was a Muslim, Ben was a Christian and Cyril was a Jew. Adam was born in 1309 of the Muslim calendar, Ben 1310 in the Christian calendar and Cyril 1311 in the Jewish calendar. Cyril was born over 3000 years before Ben, who in turn was born 619 years before Adam.\n<|im_end|>" }, { "id": "#2141", "title": "The King's Apples", "fun": 2.67, "difficulty": 0.79, "author": "ChemicalBoy08", "desc": "There was once a servant with his own farm. This servant grew a delicious crop of apples. One day he decided to take some to the king. The king's castle is surrounded by 7 layers of walls and each wall has a guard. Each guard stands by a gate.\n\r\nThe servant reached the first gate and said, \"May I go through to show the king my wonderful apples?\"\r\nThe guard replied, \"You may, if you give me half of your apples.\"\r\nThe servant then said, \"Fine, but you have to give me back one apple.\" The guard agreed. The servant did this to the rest of the guards and finally got to the king. \n\r\nThe servant still had the same amount of apples that he had started with. How is this possible?", "hint": "He didn't miss one or steal anything.", "answer": "He had 2 apples.", "category": "Logic", "date": "01/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was once a servant with his own farm. This servant grew a delicious crop of apples. One day he decided to take some to the king. The king's castle is surrounded by 7 layers of walls and each wall has a guard. Each guard stands by a gate.\n\r\nThe servant reached the first gate and said, \"May I go through to show the king my wonderful apples?\"\r\nThe guard replied, \"You may, if you give me half of your apples.\"\r\nThe servant then said, \"Fine, but you have to give me back one apple.\" The guard agreed. The servant did this to the rest of the guards and finally got to the king. \n\r\nThe servant still had the same amount of apples that he had started with. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe had 2 apples.\n<|im_start|>answer\nHe had 2 apples.\n<|im_end|>" }, { "id": "#8397", "title": "Billiards", "fun": 2.67, "difficulty": 2.16, "author": "skaven", "desc": "In the old days of the Raj, the following conversation was heard:\n\r\n'Hello, your name is Smythe isn't it? How about a friendly game of billiards?'\n\r\n'Yes it is Colonel, I'm not very good though, Carstairs gives me a 25 point handicap when we play for 100 points.'\n\r\n'Well, I'll just have to do better than that since I give Carstairs a 20-point handicap when I play him. Shall we play for £100 a game?'\n\r\nHow many points should Smythe be given as a handicap?", "hint": "No hint available.", "answer": "As the Colonel gives Carstairs 20 points in 100, he expects him to make 80 points by the time he reaches 100. Carstairs must shoot at a rate of 4/5 of the Colonel. As Smythe is expected to get 75 for every 100 Carstairs gets, he shoots at a rate of 3/4 of that of Carstairs. \r\nSmythe must shoot at a rate of 3/4 X 4/5 or 3/5 of that of the Colonel.\n\r\nSmythe should be given a handicap of 40 points.", "category": "Math", "date": "11/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the old days of the Raj, the following conversation was heard:\n\r\n'Hello, your name is Smythe isn't it? How about a friendly game of billiards?'\n\r\n'Yes it is Colonel, I'm not very good though, Carstairs gives me a 25 point handicap when we play for 100 points.'\n\r\n'Well, I'll just have to do better than that since I give Carstairs a 20-point handicap when I play him. Shall we play for £100 a game?'\n\r\nHow many points should Smythe be given as a handicap?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAs the Colonel gives Carstairs 20 points in 100, he expects him to make 80 points by the time he reaches 100. Carstairs must shoot at a rate of 4/5 of the Colonel. As Smythe is expected to get 75 for every 100 Carstairs gets, he shoots at a rate of 3/4 of that of Carstairs. \r\nSmythe must shoot at a rate of 3/4 X 4/5 or 3/5 of that of the Colonel.\n\r\nSmythe should be given a handicap of 40 points.\n<|im_start|>answer\nAs the Colonel gives Carstairs 20 points in 100, he expects him to make 80 points by the time he reaches 100. Carstairs must shoot at a rate of 4/5 of the Colonel. As Smythe is expected to get 75 for every 100 Carstairs gets, he shoots at a rate of 3/4 of that of Carstairs. \r\nSmythe must shoot at a rate of 3/4 X 4/5 or 3/5 of that of the Colonel.\n\r\nSmythe should be given a handicap of 40 points.\n<|im_end|>" }, { "id": "#17748", "title": "Dog Circle", "fun": 2.67, "difficulty": 1.9000000000000001, "author": "Jake", "desc": "There is a 10-foot long rope that is tied between a hook on the ceiling and a hook on the floor. There is no slack in the rope. Jake wants to tie up his dog so he can go do a little shopping. He detaches the rope from the floor hook and attaches the free end to the dog's collar, which happens to be 2 feet off the floor because it's a big dog. The dog can now run around in a circle and because the rope goes to the ceiling the dog won't trip or get tangled up in the rope. What a good idea! What is the radius of the circle in which the dog can wander?", "hint": "Draw a picture and remember your trigonometry.", "answer": "The dog can run in a 6-foot radius circle. To get the answer, first draw a right triangle. The long side (hypotenuse) is the length of the rope when fully stretched by the dog, 10ft. The medium side is the distance from the ceiling to the dog's collar, 8ft. The short side of the triangle is the radius of the circle. Using the Pythagorean Theorem (a^2+b^2=c^2) we can solve for this number.", "category": "Math", "date": "05/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a 10-foot long rope that is tied between a hook on the ceiling and a hook on the floor. There is no slack in the rope. Jake wants to tie up his dog so he can go do a little shopping. He detaches the rope from the floor hook and attaches the free end to the dog's collar, which happens to be 2 feet off the floor because it's a big dog. The dog can now run around in a circle and because the rope goes to the ceiling the dog won't trip or get tangled up in the rope. What a good idea! What is the radius of the circle in which the dog can wander?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe dog can run in a 6-foot radius circle. To get the answer, first draw a right triangle. The long side (hypotenuse) is the length of the rope when fully stretched by the dog, 10ft. The medium side is the distance from the ceiling to the dog's collar, 8ft. The short side of the triangle is the radius of the circle. Using the Pythagorean Theorem (a^2+b^2=c^2) we can solve for this number.\n<|im_start|>answer\nThe dog can run in a 6-foot radius circle. To get the answer, first draw a right triangle. The long side (hypotenuse) is the length of the rope when fully stretched by the dog, 10ft. The medium side is the distance from the ceiling to the dog's collar, 8ft. The short side of the triangle is the radius of the circle. Using the Pythagorean Theorem (a^2+b^2=c^2) we can solve for this number.\n<|im_end|>" }, { "id": "#29778", "title": "Coin Collection II", "fun": 2.67, "difficulty": 2.37, "author": "12345678", "desc": "Another numismatist decides to divide his coin collection among his children. The oldest gets 1/2 of the collection, the second gets 1/3, the third gets 1/n, where n is a natural number, and the youngest gets the remaining 50 coins. How many coins at most can there be in the collection?", "hint": "No hint available.", "answer": "There are 2100 coins in the collection and n=7.\n\r\n1050 + 700 + 300 + 50 = 2100", "category": "Math", "date": "04/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnother numismatist decides to divide his coin collection among his children. The oldest gets 1/2 of the collection, the second gets 1/3, the third gets 1/n, where n is a natural number, and the youngest gets the remaining 50 coins. How many coins at most can there be in the collection?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 2100 coins in the collection and n=7.\n\r\n1050 + 700 + 300 + 50 = 2100\n<|im_start|>answer\nThere are 2100 coins in the collection and n=7.\n\r\n1050 + 700 + 300 + 50 = 2100\n<|im_end|>" }, { "id": "#26432", "title": "Ice Cream Quandary", "fun": 2.67, "difficulty": 2.23, "author": "signmeup74", "desc": "Zee's Ice Cream Shop is world renowned for making new and inventive ice cream flavors from scratch. They've made great profits on their Marshmallow Mustang and Cinnebago flavors, but their Purple Pinto is just not turning a profit! \r\nScott, Zee's President, says that customers just don't want to eat purple ice cream. He thinks they should pull the flavor and move on. However Sally, Zee's Marketing Director, disagrees. She has taste tested the flavor with a sampling poll and it got rave reviews.\r\nDaisy, the lowly Flavor Engineer, loves the Purple Pinto and knows that it has profit potential! She thinks the problem might be stemming from the small batch sizes and the fact that Sally takes scoops for sample polls every time they run a batch of the flavor.\r\nDaisy has collected the following information:\r\n1. Currently, there are 30 scoops in a batch.\r\n2. It costs Zee's $12.90 to make each batch, right now.\r\n3. A scoop sells for $0.90.\r\n4. A small profit is not enough! Scott wants $25 per batch to make up for lost time.\r\n5. Sally will not stop taking 17 sample scoops per batch.\r\nFirst of all, is Daisy right? Or is the Purple Pinto just doomed?\r\nIf she is, can you help Daisy determine how large batches should be to ensure that Zee's makes a profit and keeps making her favorite flavor?", "hint": "Daisy may just be a Flavor Engineer, but her intuition is right on!", "answer": "Short answer:\r\nDaisy is right.\r\nShe should up batch size to 86 scoops to give Scott his $25/batch profit.\n\r\nLong answer:\r\nCost to Zee's = $12.90/batch or $0.43/scoop\r\nCost to Customer = $0.90/scoop (WOW! That's more than a 100% mark-up)\r\nBUT:\r\n17 samples cannot be sold.\r\nSo a batch is now only 13 scoops \r\nCost to Customer = $11.70/batch\r\nZee's loses $1.20 per batch. \r\nSo, Daisy is right!\n\r\nNow, to let's help her convince management to increase the batch size.\r\nTo break even: Our cost to make the scoops < Sales dollars from scoops\r\nTo make a $25 profit: Our cost to make the scoops + $25 profit < Sales dollars from scoops\n\r\nLet's make s=the optimal number of scoops in a batch\n\r\nOur cost to make the scoops is:\r\n$0.43 * s + $0.43 * 17 (because we gave 17 away to marketing)\n\r\nSales from the scoops are:\r\n$0.90 *s\n\r\nTherefore:\r\n$0.43 * s+ $0.43*17 + $25 < $0.90 * s\n\r\nA little algebra, please:\r\n0.43s+32.31<0.90s\r\n0.47s>32.31\r\ns > 68.75 scoops to sell\n\r\nAdding in the samples Daisy gave away to Sally:\r\ns = 69 + 17 = 86 scoops/batch\n\r\nDaisy needs to up the batch size to 86 scoops to ensure a $25 profit per batch.\r\nAnd, most importantly, she can use her math to convince Sally and Scott to keep making the Purple Pinto!", "category": "Math", "date": "10/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nZee's Ice Cream Shop is world renowned for making new and inventive ice cream flavors from scratch. They've made great profits on their Marshmallow Mustang and Cinnebago flavors, but their Purple Pinto is just not turning a profit! \r\nScott, Zee's President, says that customers just don't want to eat purple ice cream. He thinks they should pull the flavor and move on. However Sally, Zee's Marketing Director, disagrees. She has taste tested the flavor with a sampling poll and it got rave reviews.\r\nDaisy, the lowly Flavor Engineer, loves the Purple Pinto and knows that it has profit potential! She thinks the problem might be stemming from the small batch sizes and the fact that Sally takes scoops for sample polls every time they run a batch of the flavor.\r\nDaisy has collected the following information:\r\n1. Currently, there are 30 scoops in a batch.\r\n2. It costs Zee's $12.90 to make each batch, right now.\r\n3. A scoop sells for $0.90.\r\n4. A small profit is not enough! Scott wants $25 per batch to make up for lost time.\r\n5. Sally will not stop taking 17 sample scoops per batch.\r\nFirst of all, is Daisy right? Or is the Purple Pinto just doomed?\r\nIf she is, can you help Daisy determine how large batches should be to ensure that Zee's makes a profit and keeps making her favorite flavor?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShort answer:\r\nDaisy is right.\r\nShe should up batch size to 86 scoops to give Scott his $25/batch profit.\n\r\nLong answer:\r\nCost to Zee's = $12.90/batch or $0.43/scoop\r\nCost to Customer = $0.90/scoop (WOW! That's more than a 100% mark-up)\r\nBUT:\r\n17 samples cannot be sold.\r\nSo a batch is now only 13 scoops \r\nCost to Customer = $11.70/batch\r\nZee's loses $1.20 per batch. \r\nSo, Daisy is right!\n\r\nNow, to let's help her convince management to increase the batch size.\r\nTo break even: Our cost to make the scoops < Sales dollars from scoops\r\nTo make a $25 profit: Our cost to make the scoops + $25 profit < Sales dollars from scoops\n\r\nLet's make s=the optimal number of scoops in a batch\n\r\nOur cost to make the scoops is:\r\n$0.43 * s + $0.43 * 17 (because we gave 17 away to marketing)\n\r\nSales from the scoops are:\r\n$0.90 *s\n\r\nTherefore:\r\n$0.43 * s+ $0.43*17 + $25 < $0.90 * s\n\r\nA little algebra, please:\r\n0.43s+32.31<0.90s\r\n0.47s>32.31\r\ns > 68.75 scoops to sell\n\r\nAdding in the samples Daisy gave away to Sally:\r\ns = 69 + 17 = 86 scoops/batch\n\r\nDaisy needs to up the batch size to 86 scoops to ensure a $25 profit per batch.\r\nAnd, most importantly, she can use her math to convince Sally and Scott to keep making the Purple Pinto!\n<|im_start|>answer\nShort answer:\r\nDaisy is right.\r\nShe should up batch size to 86 scoops to give Scott his $25/batch profit.\n\r\nLong answer:\r\nCost to Zee's = $12.90/batch or $0.43/scoop\r\nCost to Customer = $0.90/scoop (WOW! That's more than a 100% mark-up)\r\nBUT:\r\n17 samples cannot be sold.\r\nSo a batch is now only 13 scoops \r\nCost to Customer = $11.70/batch\r\nZee's loses $1.20 per batch. \r\nSo, Daisy is right!\n\r\nNow, to let's help her convince management to increase the batch size.\r\nTo break even: Our cost to make the scoops < Sales dollars from scoops\r\nTo make a $25 profit: Our cost to make the scoops + $25 profit < Sales dollars from scoops\n\r\nLet's make s=the optimal number of scoops in a batch\n\r\nOur cost to make the scoops is:\r\n$0.43 * s + $0.43 * 17 (because we gave 17 away to marketing)\n\r\nSales from the scoops are:\r\n$0.90 *s\n\r\nTherefore:\r\n$0.43 * s+ $0.43*17 + $25 < $0.90 * s\n\r\nA little algebra, please:\r\n0.43s+32.31<0.90s\r\n0.47s>32.31\r\ns > 68.75 scoops to sell\n\r\nAdding in the samples Daisy gave away to Sally:\r\ns = 69 + 17 = 86 scoops/batch\n\r\nDaisy needs to up the batch size to 86 scoops to ensure a $25 profit per batch.\r\nAnd, most importantly, she can use her math to convince Sally and Scott to keep making the Purple Pinto!\n<|im_end|>" }, { "id": "#26116", "title": "Letter Blocks", "fun": 2.67, "difficulty": 2.92, "author": "peanut", "desc": "A child has 4 blocks with a different letter on each side (no letter is repeated on different blocks either). If the list of words below can all be formed using these blocks, figure out which letters belong on which blocks...\n\r\nskid\r\nhoax\r\njoey\r\nglum\r\nrand\r\ngrit\r\nmonk\r\nfair\r\nvane\r\nwide\r\ncafe\r\ndupe\r\njoke\r\nbail\r\nshop", "hint": "No hint available.", "answer": "Block 1: S, E, M, B, R, X\r\nBlock 2: K, W, Y, A, G, P\r\nBlock 3: I, U, N, H, J, C\r\nBlock 4: D, L, O, V, T, F", "category": "Logic", "date": "09/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA child has 4 blocks with a different letter on each side (no letter is repeated on different blocks either). If the list of words below can all be formed using these blocks, figure out which letters belong on which blocks...\n\r\nskid\r\nhoax\r\njoey\r\nglum\r\nrand\r\ngrit\r\nmonk\r\nfair\r\nvane\r\nwide\r\ncafe\r\ndupe\r\njoke\r\nbail\r\nshop\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlock 1: S, E, M, B, R, X\r\nBlock 2: K, W, Y, A, G, P\r\nBlock 3: I, U, N, H, J, C\r\nBlock 4: D, L, O, V, T, F\n<|im_start|>answer\nBlock 1: S, E, M, B, R, X\r\nBlock 2: K, W, Y, A, G, P\r\nBlock 3: I, U, N, H, J, C\r\nBlock 4: D, L, O, V, T, F\n<|im_end|>" }, { "id": "#38950", "title": "Quintuplets 2", "fun": 2.67, "difficulty": 1.37, "author": "BlackBelt", "desc": "Fay, Ray, May, Kay, and Jay are quintuplets who each have a different color and brand of computer. From each of the clues, determine the color and brand that each has.\n\r\nThe brands of computers are: Dell, Gateway, Hewlett-Packard, Sony, and Toshiba.\n\r\nThe colors of the computers are: Black, Silver, Gray, White, and Blue.\n\r\n1. Kay and the one who has a black computer went to the movies with the one who has a Sony computer.\r\n2. The one who owns the Toshiba computer played checkers with Ray and the one who has a gray computer.\r\n3. Jay does not own the Sony computer. \r\n4. The one who has the Hewlett-Packard doesn't have a Gray or Blue computer, and is not Ray.\r\n5. The one who has the silver Gateway is not May, Ray, or Jay.\r\n6. Kay doesn't have the gray, white, or silver computer. \r\n7. May does not have a gray computer.\n\n\r\nHint will reveal Jay's computer type and color.", "hint": "Jay owns a gray Dell.", "answer": "Fay has a silver Gateway.\r\nRay has a white Sony.\r\nKay has a blue Toshiba.\r\nJay has a gray Dell.\r\nMay has a black Hewlett-Packard.", "category": "Logic-Grid", "date": "10/26/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFay, Ray, May, Kay, and Jay are quintuplets who each have a different color and brand of computer. From each of the clues, determine the color and brand that each has.\n\r\nThe brands of computers are: Dell, Gateway, Hewlett-Packard, Sony, and Toshiba.\n\r\nThe colors of the computers are: Black, Silver, Gray, White, and Blue.\n\r\n1. Kay and the one who has a black computer went to the movies with the one who has a Sony computer.\r\n2. The one who owns the Toshiba computer played checkers with Ray and the one who has a gray computer.\r\n3. Jay does not own the Sony computer. \r\n4. The one who has the Hewlett-Packard doesn't have a Gray or Blue computer, and is not Ray.\r\n5. The one who has the silver Gateway is not May, Ray, or Jay.\r\n6. Kay doesn't have the gray, white, or silver computer. \r\n7. May does not have a gray computer.\n\n\r\nHint will reveal Jay's computer type and color.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFay has a silver Gateway.\r\nRay has a white Sony.\r\nKay has a blue Toshiba.\r\nJay has a gray Dell.\r\nMay has a black Hewlett-Packard.\n<|im_start|>answer\nFay has a silver Gateway.\r\nRay has a white Sony.\r\nKay has a blue Toshiba.\r\nJay has a gray Dell.\r\nMay has a black Hewlett-Packard.\n<|im_end|>" }, { "id": "#18194", "title": "World War II Fighter Planes", "fun": 2.67, "difficulty": 1.75, "author": "biztycl", "desc": "You are the Head Researcher working on improving the survival rate* of the WW2 Alliance Force's fighter planes. \n\r\nIn those days, fighter planes are on single propeller engines. Your task is to collect statistics on the number of bullet holes on fighter planes that just returned from their missions, and use this statistics as a basis to recommend improvement to the design of the fighter planes. \n\r\nAfter studying 10,000 planes that returned from the battle field, you discovered that A)60% of the bullet holes are found at the wings of the airplane, B)39% around the cockpit area and only C)1% on the engine area. \n\r\nYour immediate duty is to use this information to recommend which area (A, B or C) to increase armor plating. You could only increase the armor plating on 1 area instead of all because additional armor plating affects the agility of the fighter plane. \n\r\nJustify your rationale for your choice of section (linking to the % of bullet holes found). \n\r\n* Survival rate is determined by whether the plane return safely to ground.", "hint": "This is based on real statistical methodology.", "answer": "Section C - the engine area. \n\r\nOn the surface, the engine area seemingly received the least bullet hits (1%) and should not be warranted additional protection. However, this is not true because majority of planes that suffered engine hits have not survived to return from battleground. So there are very few planes contributing to the count on engine hits. On the other hand, the fact that there are many hits on wings and cockpit area and yet many of these planes still returned safely show that these 2 areas are not the most critical area.\n\r\nSince you could only add armor plate to 1 area - increasing armor plating to the engine area will be most viable in improving the survival rate of the planes.", "category": "Logic", "date": "07/12/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are the Head Researcher working on improving the survival rate* of the WW2 Alliance Force's fighter planes. \n\r\nIn those days, fighter planes are on single propeller engines. Your task is to collect statistics on the number of bullet holes on fighter planes that just returned from their missions, and use this statistics as a basis to recommend improvement to the design of the fighter planes. \n\r\nAfter studying 10,000 planes that returned from the battle field, you discovered that A)60% of the bullet holes are found at the wings of the airplane, B)39% around the cockpit area and only C)1% on the engine area. \n\r\nYour immediate duty is to use this information to recommend which area (A, B or C) to increase armor plating. You could only increase the armor plating on 1 area instead of all because additional armor plating affects the agility of the fighter plane. \n\r\nJustify your rationale for your choice of section (linking to the % of bullet holes found). \n\r\n* Survival rate is determined by whether the plane return safely to ground.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSection C - the engine area. \n\r\nOn the surface, the engine area seemingly received the least bullet hits (1%) and should not be warranted additional protection. However, this is not true because majority of planes that suffered engine hits have not survived to return from battleground. So there are very few planes contributing to the count on engine hits. On the other hand, the fact that there are many hits on wings and cockpit area and yet many of these planes still returned safely show that these 2 areas are not the most critical area.\n\r\nSince you could only add armor plate to 1 area - increasing armor plating to the engine area will be most viable in improving the survival rate of the planes.\n<|im_start|>answer\nSection C - the engine area. \n\r\nOn the surface, the engine area seemingly received the least bullet hits (1%) and should not be warranted additional protection. However, this is not true because majority of planes that suffered engine hits have not survived to return from battleground. So there are very few planes contributing to the count on engine hits. On the other hand, the fact that there are many hits on wings and cockpit area and yet many of these planes still returned safely show that these 2 areas are not the most critical area.\n\r\nSince you could only add armor plate to 1 area - increasing armor plating to the engine area will be most viable in improving the survival rate of the planes.\n<|im_end|>" }, { "id": "#23684", "title": "It's A Summer Birthday", "fun": 2.67, "difficulty": 2.67, "author": "Palsha", "desc": "Most of the students attending Heartwood Middle School have birthdays during the school year. For those who don't, they have a special birthday party on the last day of school. This year there are five. Your job is to figure out the five students' birthdays, their full names, and their ages from the clues presented below. The ages in the grid represent their new ages on their birthday.\n\r\n1) Iris is younger than Elliott, who was born on August 6th.\r\n2) Avery is older than Ken.\r\n3) Amy, older than Scott and Elliott, has a birthday on the 16th.\r\n4) Ken was born on the 6th.\r\n5) The youngest person was born in June.\r\n6) Wyatt and Eli are the two oldest.\r\n7) Ada and Scott have the first and last birthdays in summer.\r\n8) The student who will be 15 has a July 3rd birthday.\r\n9) The 19th is in August.\r\n10) Eli is 14 when school ends on June 8th.\r\n11) Scott is the youngest.\r\n12) Ken is younger than Amy by just 21 days.", "hint": "No hint available.", "answer": "1) Ada Wyatt will be 14 on August 19th.\r\n2) Amy Turner will be 13 on July 16th.\r\n3) Iris Scott will be 12 on June 30th.\r\n4) Eli Avery will be 15 on July 3rd.\r\n5) Ken Elliott will be 13 on August 6th.", "category": "Logic-Grid", "date": "06/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMost of the students attending Heartwood Middle School have birthdays during the school year. For those who don't, they have a special birthday party on the last day of school. This year there are five. Your job is to figure out the five students' birthdays, their full names, and their ages from the clues presented below. The ages in the grid represent their new ages on their birthday.\n\r\n1) Iris is younger than Elliott, who was born on August 6th.\r\n2) Avery is older than Ken.\r\n3) Amy, older than Scott and Elliott, has a birthday on the 16th.\r\n4) Ken was born on the 6th.\r\n5) The youngest person was born in June.\r\n6) Wyatt and Eli are the two oldest.\r\n7) Ada and Scott have the first and last birthdays in summer.\r\n8) The student who will be 15 has a July 3rd birthday.\r\n9) The 19th is in August.\r\n10) Eli is 14 when school ends on June 8th.\r\n11) Scott is the youngest.\r\n12) Ken is younger than Amy by just 21 days.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Ada Wyatt will be 14 on August 19th.\r\n2) Amy Turner will be 13 on July 16th.\r\n3) Iris Scott will be 12 on June 30th.\r\n4) Eli Avery will be 15 on July 3rd.\r\n5) Ken Elliott will be 13 on August 6th.\n<|im_start|>answer\n1) Ada Wyatt will be 14 on August 19th.\r\n2) Amy Turner will be 13 on July 16th.\r\n3) Iris Scott will be 12 on June 30th.\r\n4) Eli Avery will be 15 on July 3rd.\r\n5) Ken Elliott will be 13 on August 6th.\n<|im_end|>" }, { "id": "#4615", "title": "No Big Deal", "fun": 2.67, "difficulty": 1.77, "author": "bobbrt", "desc": "After you have dealt about half of the 52 cards for a bridge game (with four players), the phone rings. You put down the undealt cards to answer the phone. When you return, none of the cards has been touched, and no one can remember where the last card was dealt. Without counting the cards in any hand, or the number of cards yet to be dealt, how can you finish dealing rapidly and accurately, giving each player exactly the same cards they would have received if you hadn't been interrupted?", "hint": "No hint available.", "answer": "Deal from the bottom of the deck, starting with yourself and deal backwards (which should be counterclockwise). Since the only thing you really know is that you would have received the last card, this is what you need for a starting point.", "category": "Logic", "date": "06/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter you have dealt about half of the 52 cards for a bridge game (with four players), the phone rings. You put down the undealt cards to answer the phone. When you return, none of the cards has been touched, and no one can remember where the last card was dealt. Without counting the cards in any hand, or the number of cards yet to be dealt, how can you finish dealing rapidly and accurately, giving each player exactly the same cards they would have received if you hadn't been interrupted?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDeal from the bottom of the deck, starting with yourself and deal backwards (which should be counterclockwise). Since the only thing you really know is that you would have received the last card, this is what you need for a starting point.\n<|im_start|>answer\nDeal from the bottom of the deck, starting with yourself and deal backwards (which should be counterclockwise). Since the only thing you really know is that you would have received the last card, this is what you need for a starting point.\n<|im_end|>" }, { "id": "#34540", "title": "Honest, Hey?", "fun": 2.67, "difficulty": 2.3, "author": "grungy49", "desc": "My name is Grungy. I am an honest person, and I am thinking of one of these numbers: 1, 2, or 3. You may ask me only one yes-no question - I will answer truthfully, and if you choose the right question, you will know which number I am thinking of! If I cannot answer your question, I will simply tell you that I cannot answer it.\n\r\nSo, what question do you need to ask me to determine what number I am thinking of?", "hint": "No hint available.", "answer": "\"I am thinking of either 1.5 or 2.5 - is your number greater than mine?\"\n\r\nIf I answer, \"yes\", then you know it has to be 3 - because I can't tell if you're thinking of 2.5 or 1.5. If I answer, \"no\", it has to be 1. If I answer, \"I cannot answer that question\", then it is two!\n\r\nIf you can think of another answer, good on ya! Feel free to correct this teaser with the new answer. 8-)", "category": "Logic", "date": "12/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy name is Grungy. I am an honest person, and I am thinking of one of these numbers: 1, 2, or 3. You may ask me only one yes-no question - I will answer truthfully, and if you choose the right question, you will know which number I am thinking of! If I cannot answer your question, I will simply tell you that I cannot answer it.\n\r\nSo, what question do you need to ask me to determine what number I am thinking of?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"I am thinking of either 1.5 or 2.5 - is your number greater than mine?\"\n\r\nIf I answer, \"yes\", then you know it has to be 3 - because I can't tell if you're thinking of 2.5 or 1.5. If I answer, \"no\", it has to be 1. If I answer, \"I cannot answer that question\", then it is two!\n\r\nIf you can think of another answer, good on ya! Feel free to correct this teaser with the new answer. 8-)\n<|im_start|>answer\n\"I am thinking of either 1.5 or 2.5 - is your number greater than mine?\"\n\r\nIf I answer, \"yes\", then you know it has to be 3 - because I can't tell if you're thinking of 2.5 or 1.5. If I answer, \"no\", it has to be 1. If I answer, \"I cannot answer that question\", then it is two!\n\r\nIf you can think of another answer, good on ya! Feel free to correct this teaser with the new answer. 8-)\n<|im_end|>" }, { "id": "#42470", "title": "Beaten By the Teacher", "fun": 2.67, "difficulty": 1.14, "author": "whsprec", "desc": "Five high school students did not want to take a test, so they made a deal with their teacher. They would challenge him to five games; if he won all five games, the students would take the test and clean the classroom. If the students won at least one game, they did not have to take the test. Match the student to the game they played and the order in which they played. The next day after school, the teacher had a very clean classroom.\n\r\n1) The students whose names started with \"M\" were the first 3 to lose.\r\n2) Two students challenged the teacher to games which had the same number of letters as their names.\r\n3) The first game played was Scrabble and the last was Monopoly.\r\n4) Mello lost at Chess before Matt lost at UNO.", "hint": "No hint available.", "answer": "1st game Mikami played Scrabble.\r\n2nd game Mello played Chess.\r\n3rd game Matt played UNO.\r\n4th game Nate played Risk.\r\n5th game Takada played Monopoly.", "category": "Logic-Grid", "date": "07/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive high school students did not want to take a test, so they made a deal with their teacher. They would challenge him to five games; if he won all five games, the students would take the test and clean the classroom. If the students won at least one game, they did not have to take the test. Match the student to the game they played and the order in which they played. The next day after school, the teacher had a very clean classroom.\n\r\n1) The students whose names started with \"M\" were the first 3 to lose.\r\n2) Two students challenged the teacher to games which had the same number of letters as their names.\r\n3) The first game played was Scrabble and the last was Monopoly.\r\n4) Mello lost at Chess before Matt lost at UNO.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st game Mikami played Scrabble.\r\n2nd game Mello played Chess.\r\n3rd game Matt played UNO.\r\n4th game Nate played Risk.\r\n5th game Takada played Monopoly.\n<|im_start|>answer\n1st game Mikami played Scrabble.\r\n2nd game Mello played Chess.\r\n3rd game Matt played UNO.\r\n4th game Nate played Risk.\r\n5th game Takada played Monopoly.\n<|im_end|>" }, { "id": "#29643", "title": "It's a Dog's Age", "fun": 2.67, "difficulty": 1.76, "author": "lips", "desc": "Kurt was 1 year old when the family dog Jake was born. When Kurt was 8, he was twice as old as his little sister Katie. Their second dog, Kirby, was born when Katie was 2 years old. Now Katie is 2/3 the age of Kurt, and Kirby is 3 times as old as their cat Hunter.\n\r\nHow old are the kids, dogs, and cat now?", "hint": "Make a table with the known information, then guess and check.", "answer": "Kurt: 12 years old\r\nKatie: 8 years old\r\nJake the dog: 11 years old\r\nKirby the dog: 6 years old\r\nHunter the cat: 2 years old", "category": "Math", "date": "04/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKurt was 1 year old when the family dog Jake was born. When Kurt was 8, he was twice as old as his little sister Katie. Their second dog, Kirby, was born when Katie was 2 years old. Now Katie is 2/3 the age of Kurt, and Kirby is 3 times as old as their cat Hunter.\n\r\nHow old are the kids, dogs, and cat now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKurt: 12 years old\r\nKatie: 8 years old\r\nJake the dog: 11 years old\r\nKirby the dog: 6 years old\r\nHunter the cat: 2 years old\n<|im_start|>answer\nKurt: 12 years old\r\nKatie: 8 years old\r\nJake the dog: 11 years old\r\nKirby the dog: 6 years old\r\nHunter the cat: 2 years old\n<|im_end|>" }, { "id": "#24618", "title": "Sudoku (Mini)", "fun": 2.67, "difficulty": 1.84, "author": "Question_Mark", "desc": "With the numbers given, you must replace every \"~\" with a number (between 1 to 6 and including 1 and 6). Your final outcome should have one of each number in every row, column and box.\n\r\n_ _ _ _ _ _ _ _ _\r\n| 3 1 ~ |~ 5 4 |\r\n| 5 ~ ~ |~ ~ ~|\r\n_ _ _ _ _ _ _ _ _\r\n| 6 2 ~| 3 ~ ~|\r\n| ~ ~ 4| ~ ~ ~|\r\n_ _ _ _ _ _ _ _ _\r\n| ~ ~ ~| ~ ~5 |\r\n| 4 5 ~| ~ 1 2 |\r\n_ _ _ _ _ _ _ _ _", "hint": "No hint available.", "answer": "_ _ _ _ _ _ _ _ _\r\n| 3 1 6 |2 5 4 |\r\n| 5 4 2 |1 6 3 |\r\n_ _ _ _ _ _ _ _ _\r\n| 6 2 5| 3 4 1|\r\n| 1 3 4| 5 2 6|\r\n_ _ _ _ _ _ _ _ _\r\n| 2 6 1| 4 3 5 |\r\n| 4 5 3| 6 1 2 |\r\n_ _ _ _ _ _ _ _ _", "category": "Logic", "date": "07/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith the numbers given, you must replace every \"~\" with a number (between 1 to 6 and including 1 and 6). Your final outcome should have one of each number in every row, column and box.\n\r\n_ _ _ _ _ _ _ _ _\r\n| 3 1 ~ |~ 5 4 |\r\n| 5 ~ ~ |~ ~ ~|\r\n_ _ _ _ _ _ _ _ _\r\n| 6 2 ~| 3 ~ ~|\r\n| ~ ~ 4| ~ ~ ~|\r\n_ _ _ _ _ _ _ _ _\r\n| ~ ~ ~| ~ ~5 |\r\n| 4 5 ~| ~ 1 2 |\r\n_ _ _ _ _ _ _ _ _\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n_ _ _ _ _ _ _ _ _\r\n| 3 1 6 |2 5 4 |\r\n| 5 4 2 |1 6 3 |\r\n_ _ _ _ _ _ _ _ _\r\n| 6 2 5| 3 4 1|\r\n| 1 3 4| 5 2 6|\r\n_ _ _ _ _ _ _ _ _\r\n| 2 6 1| 4 3 5 |\r\n| 4 5 3| 6 1 2 |\r\n_ _ _ _ _ _ _ _ _\n<|im_start|>answer\n_ _ _ _ _ _ _ _ _\r\n| 3 1 6 |2 5 4 |\r\n| 5 4 2 |1 6 3 |\r\n_ _ _ _ _ _ _ _ _\r\n| 6 2 5| 3 4 1|\r\n| 1 3 4| 5 2 6|\r\n_ _ _ _ _ _ _ _ _\r\n| 2 6 1| 4 3 5 |\r\n| 4 5 3| 6 1 2 |\r\n_ _ _ _ _ _ _ _ _\n<|im_end|>" }, { "id": "#24239", "title": "What Time?", "fun": 2.67, "difficulty": 2.77, "author": "aznboi1324", "desc": "In the Art Gallery is a new conceptual art piece. The artist created a huge pile different paintings; periodically he picks up one of the paintings and hangs it on the wall, and adjusts it.\n\r\nAt 11:00, the painting titled \"Number 30\" was hung.\n\r\nAt 4:00, the painting titled \"Number 240\" was hung.\n\r\nAt 7:30, the painting titled \"Number 315\" was hung.\n\r\nWhat painting will the artist hang on the wall at 9:20?", "hint": "No hint available.", "answer": "The answer is \"Number 200\". It is the angle between the hour hand and the minute hand at those respective times.", "category": "Math", "date": "07/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the Art Gallery is a new conceptual art piece. The artist created a huge pile different paintings; periodically he picks up one of the paintings and hangs it on the wall, and adjusts it.\n\r\nAt 11:00, the painting titled \"Number 30\" was hung.\n\r\nAt 4:00, the painting titled \"Number 240\" was hung.\n\r\nAt 7:30, the painting titled \"Number 315\" was hung.\n\r\nWhat painting will the artist hang on the wall at 9:20?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is \"Number 200\". It is the angle between the hour hand and the minute hand at those respective times.\n<|im_start|>answer\nThe answer is \"Number 200\". It is the angle between the hour hand and the minute hand at those respective times.\n<|im_end|>" }, { "id": "#42010", "title": "Tallest to Shortest", "fun": 2.67, "difficulty": 1.78, "author": "brain23", "desc": "Five boys are very close in height, but they want to know how tall they are in order. If the shortest person is lying, and the rest are telling the truth, can you order how tall each boy is from tallest to shortest?\n\r\nAndrew: Keith is taller than me.\r\nDanny: I'm taller than Andrew.\r\nMitch: Andrew is the second tallest.\r\nCarlos: Danny is lying.\r\nKeith: Carlos is the third tallest.", "hint": "No hint available.", "answer": "Keith, Andrew, Carlos, Mitch, Danny\r\nThe way we can determine this is by looking at Andrew's statement. If he's lying, he's the shortest, and Keith is shorter than him. This is impossible because no one can be shorter than the shortest. Andrew and Keith must be telling the truth. That means Carlos is the third tallest, so he isn't lying. That means Danny is lying and is the shortest. Mitch must be telling the truth, so Andrew is the second tallest. Since Keith is taller than Andrew, he must be the tallest and Mitch must be the second shortest.", "category": "Logic", "date": "05/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive boys are very close in height, but they want to know how tall they are in order. If the shortest person is lying, and the rest are telling the truth, can you order how tall each boy is from tallest to shortest?\n\r\nAndrew: Keith is taller than me.\r\nDanny: I'm taller than Andrew.\r\nMitch: Andrew is the second tallest.\r\nCarlos: Danny is lying.\r\nKeith: Carlos is the third tallest.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKeith, Andrew, Carlos, Mitch, Danny\r\nThe way we can determine this is by looking at Andrew's statement. If he's lying, he's the shortest, and Keith is shorter than him. This is impossible because no one can be shorter than the shortest. Andrew and Keith must be telling the truth. That means Carlos is the third tallest, so he isn't lying. That means Danny is lying and is the shortest. Mitch must be telling the truth, so Andrew is the second tallest. Since Keith is taller than Andrew, he must be the tallest and Mitch must be the second shortest.\n<|im_start|>answer\nKeith, Andrew, Carlos, Mitch, Danny\r\nThe way we can determine this is by looking at Andrew's statement. If he's lying, he's the shortest, and Keith is shorter than him. This is impossible because no one can be shorter than the shortest. Andrew and Keith must be telling the truth. That means Carlos is the third tallest, so he isn't lying. That means Danny is lying and is the shortest. Mitch must be telling the truth, so Andrew is the second tallest. Since Keith is taller than Andrew, he must be the tallest and Mitch must be the second shortest.\n<|im_end|>" }, { "id": "#10183", "title": "Hollywood Quest", "fun": 2.67, "difficulty": 2.35, "author": "skaven", "desc": "Five men at a board games club meet once a week to play their favourite board game 'Hollywood Quest'. In this game each space is colour coded one of five colours, each one representing a category of questions. \r\nThe five categories are Books, Celebrities, Films, Music, Television. \r\nThe five colours are blue, green, grey, orange and purple. \r\nCan you name all five men, their favorite categories and the colours represented by those categories? \n\n\r\nCLUES \n\r\n1. Mr Everett prefers the purple coloured squares. \n\r\n2. Mr Harper likes Films category best, which is not the blue nor the orange squares. \n\r\n3. Johns Sanders doesn't like literature-based questions. \n\r\n4. Patrick's favourite colour is the blue (this is not the colour of the TV questions).\n\r\n5. The grey squares indicate a player must answer a question about books, and Mr Erwin won't land on these if he can help it. \n\r\n6. Graham prefers the celebrities category. \n\r\n7. James avoids the green and orange squares. \n\r\n8. Kendal is the fifth surname, and Paul the missing first name.", "hint": "Clues 1,2 and 5 should help you work out the colour Mr Harper likes.\n\r\nWork out Johns Sanders' favourite colour.\n\r\nYou should now be able to work out the colours of all five subjects.", "answer": "Graham Everett, purple, celebrities\r\nJames Kendal, grey, books\r\nJohn Sanders, orange, TV\r\nPatrick Erwin, blue, music\r\nPaul Harper, green, films", "category": "Logic", "date": "02/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive men at a board games club meet once a week to play their favourite board game 'Hollywood Quest'. In this game each space is colour coded one of five colours, each one representing a category of questions. \r\nThe five categories are Books, Celebrities, Films, Music, Television. \r\nThe five colours are blue, green, grey, orange and purple. \r\nCan you name all five men, their favorite categories and the colours represented by those categories? \n\n\r\nCLUES \n\r\n1. Mr Everett prefers the purple coloured squares. \n\r\n2. Mr Harper likes Films category best, which is not the blue nor the orange squares. \n\r\n3. Johns Sanders doesn't like literature-based questions. \n\r\n4. Patrick's favourite colour is the blue (this is not the colour of the TV questions).\n\r\n5. The grey squares indicate a player must answer a question about books, and Mr Erwin won't land on these if he can help it. \n\r\n6. Graham prefers the celebrities category. \n\r\n7. James avoids the green and orange squares. \n\r\n8. Kendal is the fifth surname, and Paul the missing first name.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGraham Everett, purple, celebrities\r\nJames Kendal, grey, books\r\nJohn Sanders, orange, TV\r\nPatrick Erwin, blue, music\r\nPaul Harper, green, films\n<|im_start|>answer\nGraham Everett, purple, celebrities\r\nJames Kendal, grey, books\r\nJohn Sanders, orange, TV\r\nPatrick Erwin, blue, music\r\nPaul Harper, green, films\n<|im_end|>" }, { "id": "#8720", "title": "Who is Taller", "fun": 2.67, "difficulty": 2.06, "author": "lesternoronha1", "desc": "Fifty contestants for the Miss America pageant were arranged in ten rows and five columns on the Boardwalk in Atlantic City. One viewer of this display noticed that of the tallest women in each column that Miss Maryland was the shortest of the five. Another viewer noticed that of the shortest women in each row that Miss Nevada was the tallest of the ten. There are no ties, all fifty women have different heights. Who is taller, Miss Maryland or Miss Nevada?", "hint": "No hint available.", "answer": "Miss Maryland is taller.\n\r\nThere are three possible scenarios:\n\r\n1) If Miss Maryland and Miss Nevada are in the same column then Miss Maryland would be taller, because she is the tallest in that column.\n\r\n2)If Miss Maryland and Miss Nevada are in the same row then Miss Maryland would be taller, because Miss Nevada is the shortest in that row.\n\r\n3)If Miss Maryland and Miss Nevada share neither a row nor column then there must be some other contestant who is both in Miss Maryland's column and Miss Nevada's row. Call this woman Miss Texas. \n\r\nTo illustrate her position consider the following diagram.\r\nxxxxx\r\nxmxxx\r\nxxxxx\r\nxxxxx\r\nxxxxx\r\nxxxxx\r\nxtxxn\r\nxxxxx\r\nxxxxx\r\nxxxxx\n\r\nIn this diagram the m stands for Miss Maryland, the n for Miss Nevada, and the t for Miss Texas. \n\r\nMiss Maryland must be taller than miss Texas, because miss Maryland is the tallest in her column. Miss Texas must be taller than Miss Nevada, because Miss Nevada is the shortest in her row. Thus if M>T>N then M>N, or Miss Maryland is taller than Miss Nevada.", "category": "Logic", "date": "12/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFifty contestants for the Miss America pageant were arranged in ten rows and five columns on the Boardwalk in Atlantic City. One viewer of this display noticed that of the tallest women in each column that Miss Maryland was the shortest of the five. Another viewer noticed that of the shortest women in each row that Miss Nevada was the tallest of the ten. There are no ties, all fifty women have different heights. Who is taller, Miss Maryland or Miss Nevada?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMiss Maryland is taller.\n\r\nThere are three possible scenarios:\n\r\n1) If Miss Maryland and Miss Nevada are in the same column then Miss Maryland would be taller, because she is the tallest in that column.\n\r\n2)If Miss Maryland and Miss Nevada are in the same row then Miss Maryland would be taller, because Miss Nevada is the shortest in that row.\n\r\n3)If Miss Maryland and Miss Nevada share neither a row nor column then there must be some other contestant who is both in Miss Maryland's column and Miss Nevada's row. Call this woman Miss Texas. \n\r\nTo illustrate her position consider the following diagram.\r\nxxxxx\r\nxmxxx\r\nxxxxx\r\nxxxxx\r\nxxxxx\r\nxxxxx\r\nxtxxn\r\nxxxxx\r\nxxxxx\r\nxxxxx\n\r\nIn this diagram the m stands for Miss Maryland, the n for Miss Nevada, and the t for Miss Texas. \n\r\nMiss Maryland must be taller than miss Texas, because miss Maryland is the tallest in her column. Miss Texas must be taller than Miss Nevada, because Miss Nevada is the shortest in her row. Thus if M>T>N then M>N, or Miss Maryland is taller than Miss Nevada.\n<|im_start|>answer\nMiss Maryland is taller.\n\r\nThere are three possible scenarios:\n\r\n1) If Miss Maryland and Miss Nevada are in the same column then Miss Maryland would be taller, because she is the tallest in that column.\n\r\n2)If Miss Maryland and Miss Nevada are in the same row then Miss Maryland would be taller, because Miss Nevada is the shortest in that row.\n\r\n3)If Miss Maryland and Miss Nevada share neither a row nor column then there must be some other contestant who is both in Miss Maryland's column and Miss Nevada's row. Call this woman Miss Texas. \n\r\nTo illustrate her position consider the following diagram.\r\nxxxxx\r\nxmxxx\r\nxxxxx\r\nxxxxx\r\nxxxxx\r\nxxxxx\r\nxtxxn\r\nxxxxx\r\nxxxxx\r\nxxxxx\n\r\nIn this diagram the m stands for Miss Maryland, the n for Miss Nevada, and the t for Miss Texas. \n\r\nMiss Maryland must be taller than miss Texas, because miss Maryland is the tallest in her column. Miss Texas must be taller than Miss Nevada, because Miss Nevada is the shortest in her row. Thus if M>T>N then M>N, or Miss Maryland is taller than Miss Nevada.\n<|im_end|>" }, { "id": "#37976", "title": "The Thanksgiving Pageant", "fun": 2.67, "difficulty": 2.15, "author": "lilrena4ever", "desc": "Allison, Jerry, Bonnie, and Bill are participating in a Thanksgiving Pageant at their school. The students will portray an Indian warrior, a pilgrim, an Indian maiden, and a deer. Their props consist of a pumpkin, a fish, a basket of corn, and colored leaves. During the pageant, they will recite a poem, sing a song, do a dance, and act as the narrator. Their parents, whose lasts names are Lee, Newton, Myers, and Schuler, will be watching in the audience. The ages of the performers are 13, 12, 11, and 10 years old. Use the clues to help you find out who will be doing what for the pageant. \n\r\n1. Mrs. Lee made her daughter's costume and also the costumes of the Indian maiden and the dancer. \r\n2. Mr. Myers helped his son rehearse his poem. \r\n3. The dancer was older than Lee and the pilgrim, but younger than Allison. \r\n4. The 11-year-old ripped her deer outfit, but her mother pinned it.\r\n5. Newton carried his fish during his tribal dance.\r\n6. Jerry's pumpkin was a symbol of the feast for the pilgrims. \r\n7. The Indian maiden carried corn as she sang the song of feasting.", "hint": "No hint available.", "answer": "Allison is the daughter of Mr. Schuler, is 13 years old, has the costume of the Indian maiden, sang a song, and has corn as her prop.\n\r\nJerry is the son of Mr. Myers, is 10 years old, has the costume of the pilgrim, read a poem, and has a pumpkin as a prop.\n\r\nBonnie is the daughter of Mrs. Lee, is 11 years old, has the costume of the deer, is the narrator, and has leaves as her prop.\n\r\nBill is the son of Mr. Newton, is 12 years old, has the costume of the Indian warrior, does the dance, and has a fish as his prop.", "category": "Logic", "date": "08/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAllison, Jerry, Bonnie, and Bill are participating in a Thanksgiving Pageant at their school. The students will portray an Indian warrior, a pilgrim, an Indian maiden, and a deer. Their props consist of a pumpkin, a fish, a basket of corn, and colored leaves. During the pageant, they will recite a poem, sing a song, do a dance, and act as the narrator. Their parents, whose lasts names are Lee, Newton, Myers, and Schuler, will be watching in the audience. The ages of the performers are 13, 12, 11, and 10 years old. Use the clues to help you find out who will be doing what for the pageant. \n\r\n1. Mrs. Lee made her daughter's costume and also the costumes of the Indian maiden and the dancer. \r\n2. Mr. Myers helped his son rehearse his poem. \r\n3. The dancer was older than Lee and the pilgrim, but younger than Allison. \r\n4. The 11-year-old ripped her deer outfit, but her mother pinned it.\r\n5. Newton carried his fish during his tribal dance.\r\n6. Jerry's pumpkin was a symbol of the feast for the pilgrims. \r\n7. The Indian maiden carried corn as she sang the song of feasting.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllison is the daughter of Mr. Schuler, is 13 years old, has the costume of the Indian maiden, sang a song, and has corn as her prop.\n\r\nJerry is the son of Mr. Myers, is 10 years old, has the costume of the pilgrim, read a poem, and has a pumpkin as a prop.\n\r\nBonnie is the daughter of Mrs. Lee, is 11 years old, has the costume of the deer, is the narrator, and has leaves as her prop.\n\r\nBill is the son of Mr. Newton, is 12 years old, has the costume of the Indian warrior, does the dance, and has a fish as his prop.\n<|im_start|>answer\nAllison is the daughter of Mr. Schuler, is 13 years old, has the costume of the Indian maiden, sang a song, and has corn as her prop.\n\r\nJerry is the son of Mr. Myers, is 10 years old, has the costume of the pilgrim, read a poem, and has a pumpkin as a prop.\n\r\nBonnie is the daughter of Mrs. Lee, is 11 years old, has the costume of the deer, is the narrator, and has leaves as her prop.\n\r\nBill is the son of Mr. Newton, is 12 years old, has the costume of the Indian warrior, does the dance, and has a fish as his prop.\n<|im_end|>" }, { "id": "#11863", "title": "Train Spotting", "fun": 2.67, "difficulty": 2.55, "author": "Glenbo", "desc": "During a recent plane and train spotting contest, five eager entrants were lined up ready to be tested on their spotting ability. They had each spotted a number of planes (26, 86, 123, 174, 250) and a number of trains (5, 42, 45, 98, 105). From the clues below, can you determine what colour shirt each was wearing, their position, their age (21, 23, 31, 36, 40) and the number of trains and planes spotted? \n\r\n1. Bob spotted 44 less trains than planes. \r\n2. Tom was 36 years old. \r\n3. The person on the far right was 8 years younger than Bob, and spotted 174 planes. \r\n4. Josh was wearing a yellow shirt and spotted 37 trains fewer than Bob. \r\n5. The person who was wearing a green shirt, was 19 years younger than the person to his left. \r\n6. Steven spotted 105 trains and 250 planes. \r\n7. The person in the centre was 31 years old, was wearing a blue shirt and spotted 42 trains. \r\n8. Doug, who was on the far left, spotted 26 planes, and spotted 72 trains more than planes. \r\n9. The person who was wearing a red shirt was 4 years older than Tom and was not next to the person wearing a blue shirt. \r\n10.The person who was next to the 31 year old, but not next to the person who spotted 26 planes, was wearing a orange shirt, and spotted 45 trains.", "hint": "No hint available.", "answer": "example: \r\n# Name(color shirt)Age, planes spotted, trains spotted \n\r\n1 Doug(red shirt)40,26,98 \r\n2 Steven(green shirt)21,250,105 \r\n3 Bob(blue shirt)31,86,42 \r\n4 Tom(orange shirt)36,123,45 \r\n5 Josh(yellow shirt)23,174,5", "category": "Logic", "date": "04/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a recent plane and train spotting contest, five eager entrants were lined up ready to be tested on their spotting ability. They had each spotted a number of planes (26, 86, 123, 174, 250) and a number of trains (5, 42, 45, 98, 105). From the clues below, can you determine what colour shirt each was wearing, their position, their age (21, 23, 31, 36, 40) and the number of trains and planes spotted? \n\r\n1. Bob spotted 44 less trains than planes. \r\n2. Tom was 36 years old. \r\n3. The person on the far right was 8 years younger than Bob, and spotted 174 planes. \r\n4. Josh was wearing a yellow shirt and spotted 37 trains fewer than Bob. \r\n5. The person who was wearing a green shirt, was 19 years younger than the person to his left. \r\n6. Steven spotted 105 trains and 250 planes. \r\n7. The person in the centre was 31 years old, was wearing a blue shirt and spotted 42 trains. \r\n8. Doug, who was on the far left, spotted 26 planes, and spotted 72 trains more than planes. \r\n9. The person who was wearing a red shirt was 4 years older than Tom and was not next to the person wearing a blue shirt. \r\n10.The person who was next to the 31 year old, but not next to the person who spotted 26 planes, was wearing a orange shirt, and spotted 45 trains.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nexample: \r\n# Name(color shirt)Age, planes spotted, trains spotted \n\r\n1 Doug(red shirt)40,26,98 \r\n2 Steven(green shirt)21,250,105 \r\n3 Bob(blue shirt)31,86,42 \r\n4 Tom(orange shirt)36,123,45 \r\n5 Josh(yellow shirt)23,174,5\n<|im_start|>answer\nexample: \r\n# Name(color shirt)Age, planes spotted, trains spotted \n\r\n1 Doug(red shirt)40,26,98 \r\n2 Steven(green shirt)21,250,105 \r\n3 Bob(blue shirt)31,86,42 \r\n4 Tom(orange shirt)36,123,45 \r\n5 Josh(yellow shirt)23,174,5\n<|im_end|>" }, { "id": "#14066", "title": "Animal Adventures", "fun": 2.67, "difficulty": 2.62, "author": "taniapereira99", "desc": "Five young ladies (Liz, Marge, Sam, Ella and Jenny) went on five different hiking adventures. Each walked a distance of 3, 4, 5, 6, and 7 kilometers (random order). Each were able to take an extraordinary wildlife photograph in different locations (forest, meadow, mountain, river side and bushes) of different animals (rabbit, bird, deer, fox and bear cubs). From the clues below determine where and of what each girl took a photograph of, and the distance each travelled.\n\r\n1. Liz walked twice as far as the girl who saw the deer. The girl who got a shot of the fox travelled one kilometer less than Jenny. The girl in the bushes was not the one who walked 5 kilometers. The girl on the riverside walked either one kilometer more or less than the one who was in the bushes.\n\r\n2. The girl who was quick enough to capture the rabbit on film walked farther than Marge, but not as far as the one who got the bear cubs. The girl who hiked up the mountain walked farther than at least one other girl, but not the farthest. Either Ella or Sam walked more than one kilometer farther than the other. Sam did not get a picture of the bird. The mountain climber walked either one kilometer more or less than Marge.\n\r\n3. The meadow explorer was not the one to take a picture of the bird. The bear cubs and the fox were not captured in the forest. Ella hiked farther than the mountain climber. The girl in the meadow walked one kilometer more or less than the mountain climber.\n\r\n4. The girl on the riverside walked two kilometers more than the one who saw the fox. The deer photographer did not hike as far as Ella, nor as far as the meadow explorer. At least one traveller walked farther than Jenny. The girl in the bushes walked either one kilometer more or less than the rabbit photographer.", "hint": "Set up a grid so you can determine from process of elimination. \n\r\nGo over the clues a number of times to get more information once other things are known.", "answer": "Liz - 6 km, rabbit, riverside\r\nMarge - 4 km, fox, meadow\r\nSam - 3km, deer, forest\r\nElla - 7 km, bear cubs, bushes\r\nJenny - 5 km, bird, mountain", "category": "Logic", "date": "07/29/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive young ladies (Liz, Marge, Sam, Ella and Jenny) went on five different hiking adventures. Each walked a distance of 3, 4, 5, 6, and 7 kilometers (random order). Each were able to take an extraordinary wildlife photograph in different locations (forest, meadow, mountain, river side and bushes) of different animals (rabbit, bird, deer, fox and bear cubs). From the clues below determine where and of what each girl took a photograph of, and the distance each travelled.\n\r\n1. Liz walked twice as far as the girl who saw the deer. The girl who got a shot of the fox travelled one kilometer less than Jenny. The girl in the bushes was not the one who walked 5 kilometers. The girl on the riverside walked either one kilometer more or less than the one who was in the bushes.\n\r\n2. The girl who was quick enough to capture the rabbit on film walked farther than Marge, but not as far as the one who got the bear cubs. The girl who hiked up the mountain walked farther than at least one other girl, but not the farthest. Either Ella or Sam walked more than one kilometer farther than the other. Sam did not get a picture of the bird. The mountain climber walked either one kilometer more or less than Marge.\n\r\n3. The meadow explorer was not the one to take a picture of the bird. The bear cubs and the fox were not captured in the forest. Ella hiked farther than the mountain climber. The girl in the meadow walked one kilometer more or less than the mountain climber.\n\r\n4. The girl on the riverside walked two kilometers more than the one who saw the fox. The deer photographer did not hike as far as Ella, nor as far as the meadow explorer. At least one traveller walked farther than Jenny. The girl in the bushes walked either one kilometer more or less than the rabbit photographer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLiz - 6 km, rabbit, riverside\r\nMarge - 4 km, fox, meadow\r\nSam - 3km, deer, forest\r\nElla - 7 km, bear cubs, bushes\r\nJenny - 5 km, bird, mountain\n<|im_start|>answer\nLiz - 6 km, rabbit, riverside\r\nMarge - 4 km, fox, meadow\r\nSam - 3km, deer, forest\r\nElla - 7 km, bear cubs, bushes\r\nJenny - 5 km, bird, mountain\n<|im_end|>" }, { "id": "#50646", "title": "The E-Z Fix-It Club", "fun": 2.66, "difficulty": 1.54, "author": "theriddler", "desc": "Ellie and Katy passed out screwdrivers and soldering irons to the applicants to join the E-Z Fix-It Club. Applicants could choose from blenders, mixers, fans, electric shavers, and a radio. Applicants had 15 minutes to attempt a repair, and then the results were judged by a panel consisting of Casey, Ian, and Elsie, all founding members of the club. Four applicants passed but only two were eligible to join because of the name rule. The applicants who passed were Opie, Brian, Ellen, and Rosa. Which two got the okay and were asked to join?", "hint": "You don't really need a hint; you'll get it, it's E-Z.", "answer": "Opie and Ellen (OP and LN). All the names of club members sound like alphabet letters, as does the club name, the E-Z Fix-It Club. The other members were LE, KT, KC, EN, and LC.", "category": "Logic", "date": "07/19/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEllie and Katy passed out screwdrivers and soldering irons to the applicants to join the E-Z Fix-It Club. Applicants could choose from blenders, mixers, fans, electric shavers, and a radio. Applicants had 15 minutes to attempt a repair, and then the results were judged by a panel consisting of Casey, Ian, and Elsie, all founding members of the club. Four applicants passed but only two were eligible to join because of the name rule. The applicants who passed were Opie, Brian, Ellen, and Rosa. Which two got the okay and were asked to join?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOpie and Ellen (OP and LN). All the names of club members sound like alphabet letters, as does the club name, the E-Z Fix-It Club. The other members were LE, KT, KC, EN, and LC.\n<|im_start|>answer\nOpie and Ellen (OP and LN). All the names of club members sound like alphabet letters, as does the club name, the E-Z Fix-It Club. The other members were LE, KT, KC, EN, and LC.\n<|im_end|>" }, { "id": "#51662", "title": "One Hundred People at a Party", "fun": 2.66, "difficulty": 2.06, "author": "wimpykidfan37", "desc": "Exactly one hundred people were at a party. Each either always tells the truth or always lies. After the party, one of the one hundred people said, \"I shook hands with exactly one truthteller at the party.\" Another person says, \"I shook hands with two truthtellers,\" and a third says, \"I shook hands with three.\" And so on until someone says, \"I shook hands with 99 truthtellers.\" The hundredth and final person says, \"I shook hands with no truthtellers at all!\" How many truthtellers were at the party?", "hint": "No hint available.", "answer": "There was only one truthteller.\n\r\nLet the person who said he shook hands with one truthteller be Mr. One, the one who said he shook hands with two truthtellers be Mr. Two, and so on. \n\r\nSuppose Mr. Ninety-Nine is a truthteller. This means the others are all truthtellers and he shook hands with them all. But if Mr. Zero and Mr. Ninety-Nine are both truthtellers, Mr. Zero would not have shaken hands with Mr. Ninety-Nine. So Mr. Ninety-Nine must be a liar.\n\r\nSuppose Mr. Ninety-Eight is a truthteller. This means he shook hands with everyone else except Mr. Ninety-Nine. But if Mr. Zero and Mr. Ninety-Eight are both truthtellers, then Mr. Zero would not have shaken hands with Mr. Ninety-Eight. So Mr. Ninety-Eight must also be a liar.\n\r\nUsing similar logic, we can determine that everyone between Mr. Ninety-Seven and Mr. One is a liar.\n\r\nWhat about Mr. Zero? Since everyone else was a liar, he really did not shake hands with any truthtellers. Therefore, Mr. Zero is the only truthteller.", "category": "Logic", "date": "01/21/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nExactly one hundred people were at a party. Each either always tells the truth or always lies. After the party, one of the one hundred people said, \"I shook hands with exactly one truthteller at the party.\" Another person says, \"I shook hands with two truthtellers,\" and a third says, \"I shook hands with three.\" And so on until someone says, \"I shook hands with 99 truthtellers.\" The hundredth and final person says, \"I shook hands with no truthtellers at all!\" How many truthtellers were at the party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere was only one truthteller.\n\r\nLet the person who said he shook hands with one truthteller be Mr. One, the one who said he shook hands with two truthtellers be Mr. Two, and so on. \n\r\nSuppose Mr. Ninety-Nine is a truthteller. This means the others are all truthtellers and he shook hands with them all. But if Mr. Zero and Mr. Ninety-Nine are both truthtellers, Mr. Zero would not have shaken hands with Mr. Ninety-Nine. So Mr. Ninety-Nine must be a liar.\n\r\nSuppose Mr. Ninety-Eight is a truthteller. This means he shook hands with everyone else except Mr. Ninety-Nine. But if Mr. Zero and Mr. Ninety-Eight are both truthtellers, then Mr. Zero would not have shaken hands with Mr. Ninety-Eight. So Mr. Ninety-Eight must also be a liar.\n\r\nUsing similar logic, we can determine that everyone between Mr. Ninety-Seven and Mr. One is a liar.\n\r\nWhat about Mr. Zero? Since everyone else was a liar, he really did not shake hands with any truthtellers. Therefore, Mr. Zero is the only truthteller.\n<|im_start|>answer\nThere was only one truthteller.\n\r\nLet the person who said he shook hands with one truthteller be Mr. One, the one who said he shook hands with two truthtellers be Mr. Two, and so on. \n\r\nSuppose Mr. Ninety-Nine is a truthteller. This means the others are all truthtellers and he shook hands with them all. But if Mr. Zero and Mr. Ninety-Nine are both truthtellers, Mr. Zero would not have shaken hands with Mr. Ninety-Nine. So Mr. Ninety-Nine must be a liar.\n\r\nSuppose Mr. Ninety-Eight is a truthteller. This means he shook hands with everyone else except Mr. Ninety-Nine. But if Mr. Zero and Mr. Ninety-Eight are both truthtellers, then Mr. Zero would not have shaken hands with Mr. Ninety-Eight. So Mr. Ninety-Eight must also be a liar.\n\r\nUsing similar logic, we can determine that everyone between Mr. Ninety-Seven and Mr. One is a liar.\n\r\nWhat about Mr. Zero? Since everyone else was a liar, he really did not shake hands with any truthtellers. Therefore, Mr. Zero is the only truthteller.\n<|im_end|>" }, { "id": "#38520", "title": "Murder at Brainteaser Mansion #1", "fun": 2.66, "difficulty": 0.81, "author": "Mystery-King", "desc": "Four guests, Mrs. Red, Mr. Crimson, Lady Scarlet and Mr. Sienna, were all invited to an exclusive party at Brainteaser Mansion. However, during the long, dark night, the owner of the spectacular mansion, Mr. Death, was found dead in the library. Since no one apparently knew what happened, rumours were multiplying by the second, because everyone was suspected of killing him with a different weapon. From the following clues, can you work out who killed him?\n\r\n1. The person who \"allegedly\" used the poison was a female.\n\r\n2. Mrs. Red's motive was \"supposedly\" money.\n\r\n3. The motive of the person who used the rope was jealousy.\n\r\n4. Mr. Crimson \"apparently\" used the gun but his motive wasn't revenge.\n\r\n5. Lady Scarlet was believed to have used the rope.\n\r\nThe person who used the dagger is the real killer. Who did it?", "hint": "No hint available.", "answer": "Mrs. Red, Poison, Money.\r\nMr. Crimson, Gun, Blackmail.\r\nLady Scarlet, Rope, Jealousy.\r\nMr. Sienna, Dagger, Revenge.\n\r\nSo, therefore, Mr. Sienna was the real killer.", "category": "Logic-Grid", "date": "09/29/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour guests, Mrs. Red, Mr. Crimson, Lady Scarlet and Mr. Sienna, were all invited to an exclusive party at Brainteaser Mansion. However, during the long, dark night, the owner of the spectacular mansion, Mr. Death, was found dead in the library. Since no one apparently knew what happened, rumours were multiplying by the second, because everyone was suspected of killing him with a different weapon. From the following clues, can you work out who killed him?\n\r\n1. The person who \"allegedly\" used the poison was a female.\n\r\n2. Mrs. Red's motive was \"supposedly\" money.\n\r\n3. The motive of the person who used the rope was jealousy.\n\r\n4. Mr. Crimson \"apparently\" used the gun but his motive wasn't revenge.\n\r\n5. Lady Scarlet was believed to have used the rope.\n\r\nThe person who used the dagger is the real killer. Who did it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMrs. Red, Poison, Money.\r\nMr. Crimson, Gun, Blackmail.\r\nLady Scarlet, Rope, Jealousy.\r\nMr. Sienna, Dagger, Revenge.\n\r\nSo, therefore, Mr. Sienna was the real killer.\n<|im_start|>answer\nMrs. Red, Poison, Money.\r\nMr. Crimson, Gun, Blackmail.\r\nLady Scarlet, Rope, Jealousy.\r\nMr. Sienna, Dagger, Revenge.\n\r\nSo, therefore, Mr. Sienna was the real killer.\n<|im_end|>" }, { "id": "#50858", "title": "Cube Corners", "fun": 2.66, "difficulty": 2.23, "author": "cnmne", "desc": "A cube has six faces (sides) and eight vertices (corners). Arrange the numbers 1 through 8, placing one number at each corner, such that the sum of the four corners of each side is the same for all six sides.", "hint": "No hint available.", "answer": "The sum of the four corners of each side is 18. The four numbers on one side are 8 (upper left), 1 (upper right), 6 (lower right), and 3 (lower left). On the opposite side, directly behind those four numbers, are 2, 7, 4, and 5. There are seemingly other arrangements, but they are all due to the orientation of the cube.", "category": "Math", "date": "08/02/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cube has six faces (sides) and eight vertices (corners). Arrange the numbers 1 through 8, placing one number at each corner, such that the sum of the four corners of each side is the same for all six sides.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe sum of the four corners of each side is 18. The four numbers on one side are 8 (upper left), 1 (upper right), 6 (lower right), and 3 (lower left). On the opposite side, directly behind those four numbers, are 2, 7, 4, and 5. There are seemingly other arrangements, but they are all due to the orientation of the cube.\n<|im_start|>answer\nThe sum of the four corners of each side is 18. The four numbers on one side are 8 (upper left), 1 (upper right), 6 (lower right), and 3 (lower left). On the opposite side, directly behind those four numbers, are 2, 7, 4, and 5. There are seemingly other arrangements, but they are all due to the orientation of the cube.\n<|im_end|>" }, { "id": "#51619", "title": "The Four Men's Ages", "fun": 2.66, "difficulty": 0.72, "author": "wimpykidfan37", "desc": "Al, Ben, Carl, and Dan are all different ages. The tens digits of their ages are 2, 3, 4, and 5, though not necessarily in that order. The ones digits of their ages are 2, 3, 4, and 5, also not necessarily in that order. One of them is 42 years old. The tens digit of Al's age is 2, the tens digit of Ben's age is 3, and the ones digit of Carl's age is 4. The ones digit of Al's age is not 5. How old is each man?", "hint": "No hint available.", "answer": "Al is 23, Ben is 35, Carl is 54, and Dan is 42.\n\r\nThe 42-year-old cannot be Al, Ben, or Carl, so it must be Dan.\n\r\nThe ones digit of Al's age isn't 5, nor is it 4 (Carl) or 2 (Dan), so it must be 3. Therefore, Al is 23.\n\r\nThe ones digit of Ben's age isn't 3 (Al), 4 (Carl), or 2 (Dan), so it must be 5. Therefore, Ben is 35.\n\r\nThe tens digit of Carl's age isn't 2 (Al), 3 (Ben), or 4 (Dan), so it must be 5. Therefore, Carl is 54.", "category": "Logic", "date": "12/14/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl, Ben, Carl, and Dan are all different ages. The tens digits of their ages are 2, 3, 4, and 5, though not necessarily in that order. The ones digits of their ages are 2, 3, 4, and 5, also not necessarily in that order. One of them is 42 years old. The tens digit of Al's age is 2, the tens digit of Ben's age is 3, and the ones digit of Carl's age is 4. The ones digit of Al's age is not 5. How old is each man?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAl is 23, Ben is 35, Carl is 54, and Dan is 42.\n\r\nThe 42-year-old cannot be Al, Ben, or Carl, so it must be Dan.\n\r\nThe ones digit of Al's age isn't 5, nor is it 4 (Carl) or 2 (Dan), so it must be 3. Therefore, Al is 23.\n\r\nThe ones digit of Ben's age isn't 3 (Al), 4 (Carl), or 2 (Dan), so it must be 5. Therefore, Ben is 35.\n\r\nThe tens digit of Carl's age isn't 2 (Al), 3 (Ben), or 4 (Dan), so it must be 5. Therefore, Carl is 54.\n<|im_start|>answer\nAl is 23, Ben is 35, Carl is 54, and Dan is 42.\n\r\nThe 42-year-old cannot be Al, Ben, or Carl, so it must be Dan.\n\r\nThe ones digit of Al's age isn't 5, nor is it 4 (Carl) or 2 (Dan), so it must be 3. Therefore, Al is 23.\n\r\nThe ones digit of Ben's age isn't 3 (Al), 4 (Carl), or 2 (Dan), so it must be 5. Therefore, Ben is 35.\n\r\nThe tens digit of Carl's age isn't 2 (Al), 3 (Ben), or 4 (Dan), so it must be 5. Therefore, Carl is 54.\n<|im_end|>" }, { "id": "#52373", "title": "A Misinformed Liar Tells No Lies", "fun": 2.66, "difficulty": 2.08, "author": "Rove_Tarts", "desc": "Three friends, Allie, Kaleb, and Leah have 3 different actions whenever they come across potentially new information. \n\r\nThe first is a Scientist, they are always correct about which statements are true and will always tell the truth.\n\r\nThe second is a Psychologist, they like to test people by lying and seeing their reactions, however they are misinformed. This means that they will receive a false statement, think it is true, and lie about it.\n\r\nThe last is a Lapidary, they will always try to tell the truth, but they are also misinformed.\n\r\nThey receive information (or misinformation) about each other's behaviors and make the following statements:\n\r\nKaleb: Leah is misinformed\r\nAllie: I am not misinformed\r\nLeah: Allie is the Psychologist\n\r\nWho is who?", "hint": "The Psychologist ends up telling the truth and the Lapidary ends up lying.", "answer": "Allie is the Scientist.\r\nKaleb is the Psychologist.\r\nLeah is the Lapidary.\n\r\nAllie cannot be the Psychologist because the Psychologist would say they were misinformed.\n\r\nLeah cannot be the Scientist because Allie isn't the Psychologist.\n\r\nKaleb cannot be the Lapidary because Leah is misinformed and the Lapidary would think Leah isn't misinformed and say that.\n\r\nThis leaves the scenarios:\n\r\nKaleb Scientist\r\nAllie Lapidary\r\nLeah Psychologist\r\nand\r\nKaleb Psychologist\r\nAllie Scientist\r\nLeah Lapidary\n\r\nSince the Psychologist cannot say someone else is the Psychologist (That would mean there's more than 1), the answer must be:\n\r\nAllie is the Scientist.\r\nKaleb is the Psychologist.\r\nLeah is the Lapidary.", "category": "Logic", "date": "04/30/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends, Allie, Kaleb, and Leah have 3 different actions whenever they come across potentially new information. \n\r\nThe first is a Scientist, they are always correct about which statements are true and will always tell the truth.\n\r\nThe second is a Psychologist, they like to test people by lying and seeing their reactions, however they are misinformed. This means that they will receive a false statement, think it is true, and lie about it.\n\r\nThe last is a Lapidary, they will always try to tell the truth, but they are also misinformed.\n\r\nThey receive information (or misinformation) about each other's behaviors and make the following statements:\n\r\nKaleb: Leah is misinformed\r\nAllie: I am not misinformed\r\nLeah: Allie is the Psychologist\n\r\nWho is who?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllie is the Scientist.\r\nKaleb is the Psychologist.\r\nLeah is the Lapidary.\n\r\nAllie cannot be the Psychologist because the Psychologist would say they were misinformed.\n\r\nLeah cannot be the Scientist because Allie isn't the Psychologist.\n\r\nKaleb cannot be the Lapidary because Leah is misinformed and the Lapidary would think Leah isn't misinformed and say that.\n\r\nThis leaves the scenarios:\n\r\nKaleb Scientist\r\nAllie Lapidary\r\nLeah Psychologist\r\nand\r\nKaleb Psychologist\r\nAllie Scientist\r\nLeah Lapidary\n\r\nSince the Psychologist cannot say someone else is the Psychologist (That would mean there's more than 1), the answer must be:\n\r\nAllie is the Scientist.\r\nKaleb is the Psychologist.\r\nLeah is the Lapidary.\n<|im_start|>answer\nAllie is the Scientist.\r\nKaleb is the Psychologist.\r\nLeah is the Lapidary.\n\r\nAllie cannot be the Psychologist because the Psychologist would say they were misinformed.\n\r\nLeah cannot be the Scientist because Allie isn't the Psychologist.\n\r\nKaleb cannot be the Lapidary because Leah is misinformed and the Lapidary would think Leah isn't misinformed and say that.\n\r\nThis leaves the scenarios:\n\r\nKaleb Scientist\r\nAllie Lapidary\r\nLeah Psychologist\r\nand\r\nKaleb Psychologist\r\nAllie Scientist\r\nLeah Lapidary\n\r\nSince the Psychologist cannot say someone else is the Psychologist (That would mean there's more than 1), the answer must be:\n\r\nAllie is the Scientist.\r\nKaleb is the Psychologist.\r\nLeah is the Lapidary.\n<|im_end|>" }, { "id": "#23991", "title": "Squares and Cubes and Squares", "fun": 2.66, "difficulty": 2.01, "author": "Tammy93", "desc": "1) There is only one 2-digit number that is both a square and a cube. What is it?\n\r\n2) There is only one 3-digit number that is both a square and a cube. What is it?\n\r\n3) Which 3-digit number, made of consecutive digits, is 2 less than a cube and 2 more than a square?\n\r\n4) What 2-digit number is 1 more than a square and 1 less than a cube?", "hint": "No hint available.", "answer": "1) 64;8 times 8 and 4 times 4 times 4\n\r\n2) 729; 27 times 27 and 9 times 9 times 9.\n\r\n3) 123 is two more than 121(11 times 11) and two less than 125(5 times 5 times 5)\n\r\n4) 26 is one more than 25(5 times 5) and one less than 27(3 times 3 times 3)", "category": "Math", "date": "06/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n1) There is only one 2-digit number that is both a square and a cube. What is it?\n\r\n2) There is only one 3-digit number that is both a square and a cube. What is it?\n\r\n3) Which 3-digit number, made of consecutive digits, is 2 less than a cube and 2 more than a square?\n\r\n4) What 2-digit number is 1 more than a square and 1 less than a cube?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) 64;8 times 8 and 4 times 4 times 4\n\r\n2) 729; 27 times 27 and 9 times 9 times 9.\n\r\n3) 123 is two more than 121(11 times 11) and two less than 125(5 times 5 times 5)\n\r\n4) 26 is one more than 25(5 times 5) and one less than 27(3 times 3 times 3)\n<|im_start|>answer\n1) 64;8 times 8 and 4 times 4 times 4\n\r\n2) 729; 27 times 27 and 9 times 9 times 9.\n\r\n3) 123 is two more than 121(11 times 11) and two less than 125(5 times 5 times 5)\n\r\n4) 26 is one more than 25(5 times 5) and one less than 27(3 times 3 times 3)\n<|im_end|>" }, { "id": "#3243", "title": "Dog Dilemma", "fun": 2.66, "difficulty": 1.19, "author": "204_blaze_41", "desc": "Shalom had parked his car under a tree and was heading toward the suspect's house when a vicious dog lunged at him. Luckily for Shalom he was just beyond the dog's reach. Since the suspect wasn't home, Shalom decided to leave, but he had a slight problem. The dog, straining at the end of his chain, was following Shalom's every move. With the chain attached to the tree, the dog had access to both car doors. How could Shalom get into his car without the dog being able to reach him?", "hint": "No hint available.", "answer": "Since the dog was following every move he made, Shalom began circling the tree, with the dog right behind him. After several revolutions the chain became shorter, and consequently, the dog no longer had access to both car doors.", "category": "Logic", "date": "04/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nShalom had parked his car under a tree and was heading toward the suspect's house when a vicious dog lunged at him. Luckily for Shalom he was just beyond the dog's reach. Since the suspect wasn't home, Shalom decided to leave, but he had a slight problem. The dog, straining at the end of his chain, was following Shalom's every move. With the chain attached to the tree, the dog had access to both car doors. How could Shalom get into his car without the dog being able to reach him?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince the dog was following every move he made, Shalom began circling the tree, with the dog right behind him. After several revolutions the chain became shorter, and consequently, the dog no longer had access to both car doors.\n<|im_start|>answer\nSince the dog was following every move he made, Shalom began circling the tree, with the dog right behind him. After several revolutions the chain became shorter, and consequently, the dog no longer had access to both car doors.\n<|im_end|>" }, { "id": "#51926", "title": "Divide and Conquer", "fun": 2.66, "difficulty": 1.49, "author": "Musicwritergirl", "desc": "If:\r\n4872+1209= 48\r\n6432+1616=42\r\n5084+2512=27\r\nThen:\r\n9975+9915=?", "hint": "No hint available.", "answer": "15. The first 2 digits of the first number in the equation divided by the first 2 digits of the second number is equal to the first digit of the answer. The last 2 digits of the first number divided by the last 2 digits of the second is equal to the second digit of the answer.\r\nEx. 4872+1209=48\r\n48/12=4\r\n72/09=8", "category": "Math", "date": "06/28/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf:\r\n4872+1209= 48\r\n6432+1616=42\r\n5084+2512=27\r\nThen:\r\n9975+9915=?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15. The first 2 digits of the first number in the equation divided by the first 2 digits of the second number is equal to the first digit of the answer. The last 2 digits of the first number divided by the last 2 digits of the second is equal to the second digit of the answer.\r\nEx. 4872+1209=48\r\n48/12=4\r\n72/09=8\n<|im_start|>answer\n15. The first 2 digits of the first number in the equation divided by the first 2 digits of the second number is equal to the first digit of the answer. The last 2 digits of the first number divided by the last 2 digits of the second is equal to the second digit of the answer.\r\nEx. 4872+1209=48\r\n48/12=4\r\n72/09=8\n<|im_end|>" }, { "id": "#43158", "title": "How Old? How Much? How Tall?", "fun": 2.66, "difficulty": 1.52, "author": "whsprec", "desc": "Four men underwent their yearly physicals. The four men are Toby, Justin, Sam, and Joey. From the clues, determine their ages, heights, and weights.\n\r\n1) Sam is five years older than the tallest man, and he is lighter than the shortest man.\r\n2) Justin is taller than the oldest man and lighter than the youngest.\r\n3) Joey is two inches shorter and ten pounds heavier than Justin, but Joey weighs less than the tallest man.\r\n4) Someone is 6'1\" and 40 years old and someone is 5'11\" and weighs 170 pounds.\r\n5) The lightest man is five years older than the shortest man.\r\n6) The youngest man is 30, one inch shorter than Sam, and five pounds lighter than Toby.\r\n7) The man who is 6' is not Toby, 175-pound Joey, or the oldest man.", "hint": "No hint available.", "answer": "45- Sam- 5'11\"- 170 pounds\r\n40- Toby- 6'1\"-180 pounds\r\n35-Justin-6'-165 pounds\r\n30-Joey-5'10'- 175 pounds", "category": "Logic-Grid", "date": "09/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour men underwent their yearly physicals. The four men are Toby, Justin, Sam, and Joey. From the clues, determine their ages, heights, and weights.\n\r\n1) Sam is five years older than the tallest man, and he is lighter than the shortest man.\r\n2) Justin is taller than the oldest man and lighter than the youngest.\r\n3) Joey is two inches shorter and ten pounds heavier than Justin, but Joey weighs less than the tallest man.\r\n4) Someone is 6'1\" and 40 years old and someone is 5'11\" and weighs 170 pounds.\r\n5) The lightest man is five years older than the shortest man.\r\n6) The youngest man is 30, one inch shorter than Sam, and five pounds lighter than Toby.\r\n7) The man who is 6' is not Toby, 175-pound Joey, or the oldest man.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n45- Sam- 5'11\"- 170 pounds\r\n40- Toby- 6'1\"-180 pounds\r\n35-Justin-6'-165 pounds\r\n30-Joey-5'10'- 175 pounds\n<|im_start|>answer\n45- Sam- 5'11\"- 170 pounds\r\n40- Toby- 6'1\"-180 pounds\r\n35-Justin-6'-165 pounds\r\n30-Joey-5'10'- 175 pounds\n<|im_end|>" }, { "id": "#29669", "title": "Acrobats", "fun": 2.66, "difficulty": 1.77, "author": "EnderofGames", "desc": "Barbara, Corliss, Dexter, and Edward, who are acrobats, use different kinds of equipment (flying rings, horizontal bars, parallel bars, trampoline). Match them up using the clues below:\n\r\n1) The girl who uses the trampoline is younger than Barbara and the person who uses the horizontal bars.\r\n2) Edward is younger than Corliss and the person who uses the flying rings.", "hint": "Barbara and Corliss are girls; Dexter and Edward are boys.", "answer": "Barbara - Flying Rings\r\nCorliss - Trampoline\r\nDexter - Horizontal Bars\r\nEdward - Parallel Bars", "category": "Logic", "date": "04/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBarbara, Corliss, Dexter, and Edward, who are acrobats, use different kinds of equipment (flying rings, horizontal bars, parallel bars, trampoline). Match them up using the clues below:\n\r\n1) The girl who uses the trampoline is younger than Barbara and the person who uses the horizontal bars.\r\n2) Edward is younger than Corliss and the person who uses the flying rings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBarbara - Flying Rings\r\nCorliss - Trampoline\r\nDexter - Horizontal Bars\r\nEdward - Parallel Bars\n<|im_start|>answer\nBarbara - Flying Rings\r\nCorliss - Trampoline\r\nDexter - Horizontal Bars\r\nEdward - Parallel Bars\n<|im_end|>" }, { "id": "#45491", "title": "Lazy Final Saturday", "fun": 2.66, "difficulty": 1.65, "author": "whsprec", "desc": "The Saturday after final's week, five roommates were feeling lazy. So they decided to wake up late, eat breakfast, read a book, and then watch a sport on the TV. From the clues given can you determine who ate what breakfast, the book they read, and the sport they watched. \r\n1) Sam White watched soccer, while the basketball watcher had crepes.\r\n2) Adam Brown read The Shack.\r\n3) Edward Black had toast for breakfast; he didn't read The Host or watch football.\r\n4) Fried eggs and 206 Bones took up most of the morning of one of the roommates, but not Sam White or Russell Green.\r\n5) Football was watched after reading Spartan Gold.\r\n6) The reader of The Host didn't eat pancakes, and the reader of the A Princess of Landover didn't watch baseball.", "hint": "No hint available.", "answer": "Russell Green ate pancakes, read Spartan Gold, then watched football.\r\nSam White ate waffles, read The Host, then watched soccer.\r\nChris Grey ate fried eggs, read 206 Bones, then watched baseball.\r\nAdam Brown ate crepes, read The Shack, then watched basketball.\r\nEdward Black ate toast, read A Princess of Landover, then watched swimming.", "category": "Logic-Grid", "date": "10/13/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Saturday after final's week, five roommates were feeling lazy. So they decided to wake up late, eat breakfast, read a book, and then watch a sport on the TV. From the clues given can you determine who ate what breakfast, the book they read, and the sport they watched. \r\n1) Sam White watched soccer, while the basketball watcher had crepes.\r\n2) Adam Brown read The Shack.\r\n3) Edward Black had toast for breakfast; he didn't read The Host or watch football.\r\n4) Fried eggs and 206 Bones took up most of the morning of one of the roommates, but not Sam White or Russell Green.\r\n5) Football was watched after reading Spartan Gold.\r\n6) The reader of The Host didn't eat pancakes, and the reader of the A Princess of Landover didn't watch baseball.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRussell Green ate pancakes, read Spartan Gold, then watched football.\r\nSam White ate waffles, read The Host, then watched soccer.\r\nChris Grey ate fried eggs, read 206 Bones, then watched baseball.\r\nAdam Brown ate crepes, read The Shack, then watched basketball.\r\nEdward Black ate toast, read A Princess of Landover, then watched swimming.\n<|im_start|>answer\nRussell Green ate pancakes, read Spartan Gold, then watched football.\r\nSam White ate waffles, read The Host, then watched soccer.\r\nChris Grey ate fried eggs, read 206 Bones, then watched baseball.\r\nAdam Brown ate crepes, read The Shack, then watched basketball.\r\nEdward Black ate toast, read A Princess of Landover, then watched swimming.\n<|im_end|>" }, { "id": "#40617", "title": "Steaks", "fun": 2.66, "difficulty": 1.15, "author": "Carlos16", "desc": "If 3 men can eat 3 steaks in 3 days, how many steaks can 6 men eat in 6 days?", "hint": "No hint available.", "answer": "If 3 men can eat 3 steaks in 3 days, then 6 men can eat 6 steaks in 3 days. So in 6 days, the 6 men will be able to eat twice as many steaks as 6, which is 12.", "category": "Logic", "date": "02/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 3 men can eat 3 steaks in 3 days, how many steaks can 6 men eat in 6 days?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf 3 men can eat 3 steaks in 3 days, then 6 men can eat 6 steaks in 3 days. So in 6 days, the 6 men will be able to eat twice as many steaks as 6, which is 12.\n<|im_start|>answer\nIf 3 men can eat 3 steaks in 3 days, then 6 men can eat 6 steaks in 3 days. So in 6 days, the 6 men will be able to eat twice as many steaks as 6, which is 12.\n<|im_end|>" }, { "id": "#24740", "title": "Checker Circle", "fun": 2.66, "difficulty": 1.98, "author": "phrebh", "desc": "Arrange twelve checkers in a circle, like they were the numbers on a clock. Pick up one checker and jump over two other checkers, either clockwise or counterclockwise, and put it on the third checker. Using that same methodology, can you create 6 stacks of 2 checkers each?", "hint": "Remember that a stack of two checkers still contains two checkers.", "answer": "12 onto 9\r\n5 onto 8\r\n2 onto 6\r\n4 onto 11\r\n1 onto 10\r\n3 onto 7\n\r\nThat is one possibility. Rotational and reflective symmetry allow for many others.", "category": "Logic", "date": "07/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange twelve checkers in a circle, like they were the numbers on a clock. Pick up one checker and jump over two other checkers, either clockwise or counterclockwise, and put it on the third checker. Using that same methodology, can you create 6 stacks of 2 checkers each?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12 onto 9\r\n5 onto 8\r\n2 onto 6\r\n4 onto 11\r\n1 onto 10\r\n3 onto 7\n\r\nThat is one possibility. Rotational and reflective symmetry allow for many others.\n<|im_start|>answer\n12 onto 9\r\n5 onto 8\r\n2 onto 6\r\n4 onto 11\r\n1 onto 10\r\n3 onto 7\n\r\nThat is one possibility. Rotational and reflective symmetry allow for many others.\n<|im_end|>" }, { "id": "#14711", "title": "Family Crossing Bridge", "fun": 2.66, "difficulty": 2.09, "author": "xiaobaby", "desc": "It is a dark night and there is a family of 5 that needs to cross a bridge suspended over a deep valley. The only light available was a lamp which could only burn for 30 minutes. Up to two members can cross each time. Different members take different amount of time to cross and the time they take must be at the pace of the slower one. The time taken for each member is as shown:\n\r\n(G)Grandpa - 12 mins\r\n(F)Father - 8 mins\r\n(M)Mother - 6 mins\r\n(S)Sister - 3 mins\r\n(B)Brother - 1 min\n\r\nFor example, if the father and the grandpa were to cross together, it would take 12 minutes, leaving 18 minutes for one of them to return and get the rest moving.\r\nCan you help the family to get across?", "hint": "The brother helps well in bringing the lamp to and fro with his speed.", "answer": "B+S Cross = 27 mins remain\r\nB Back = 26 mins remain\r\nB+M Cross = 20 mins remain\r\nS Back = 17 mins remain\r\nF+G Cross = 5 mins remain\r\nB Back = 4 mins remain\r\nB+S Cross = 1 min remains.\r\nThe family reunites at the other end, leaving 1 minute of light to be happy.", "category": "Logic", "date": "09/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is a dark night and there is a family of 5 that needs to cross a bridge suspended over a deep valley. The only light available was a lamp which could only burn for 30 minutes. Up to two members can cross each time. Different members take different amount of time to cross and the time they take must be at the pace of the slower one. The time taken for each member is as shown:\n\r\n(G)Grandpa - 12 mins\r\n(F)Father - 8 mins\r\n(M)Mother - 6 mins\r\n(S)Sister - 3 mins\r\n(B)Brother - 1 min\n\r\nFor example, if the father and the grandpa were to cross together, it would take 12 minutes, leaving 18 minutes for one of them to return and get the rest moving.\r\nCan you help the family to get across?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nB+S Cross = 27 mins remain\r\nB Back = 26 mins remain\r\nB+M Cross = 20 mins remain\r\nS Back = 17 mins remain\r\nF+G Cross = 5 mins remain\r\nB Back = 4 mins remain\r\nB+S Cross = 1 min remains.\r\nThe family reunites at the other end, leaving 1 minute of light to be happy.\n<|im_start|>answer\nB+S Cross = 27 mins remain\r\nB Back = 26 mins remain\r\nB+M Cross = 20 mins remain\r\nS Back = 17 mins remain\r\nF+G Cross = 5 mins remain\r\nB Back = 4 mins remain\r\nB+S Cross = 1 min remains.\r\nThe family reunites at the other end, leaving 1 minute of light to be happy.\n<|im_end|>" }, { "id": "#29050", "title": "Chaos at the Cat Park?", "fun": 2.66, "difficulty": 1.18, "author": "PineappleMama", "desc": "In Dopeyville, some genius had the idea to make a Cat Park. Similar to a Dog Park, only this is where you take your cat to socialize. Now anyone who has a cat knows this is an insane idea, but look at the name of this town - enough said. \n\r\nNeedless to say, there were problems right from the beginning. There were calicoes having cattywumpuses, tabbies having tantrums, and don't even ask about what the Siameses did to the sandbox. Trust me you don't want to know!\n\r\nSo, one day, Barney, the hired cat-walker of Goober Drive, decided to take his charges to the Cat Park. There were other cat-walkers at the park. The two cats he took were neighbors, and were used to putting up with each other, so they got along fine. However, they didn't get along with the other cats at the park. There was a scuffle and the cats got loose, including three other cats. Turns out, cats are great escape artists. They managed to wiggle out of their leashes, AND their harnesses. So now we have a bit of a disaster. The cat-walkers managed to gather up the frisky felines, but are now stumped as to who's who. Please help Barney and the other Kitty Parents sort out the cats, their leashes, and their harnesses before Barney's customers start to wonder where their beloved cats are.\n\r\nCats: Jewel, Whiskers, Tiger, Mojo, and Bob\r\nHarnesses: Red, Purple, Blue, Green, and White\r\nLeashes: Yellow, Black, Orange, Grey, and Pink\n\r\n1) The five cats are: Whiskers, the cat with the blue harness, the cat with the pink leash, the purple harnessed cat, and Bob. \n\r\n2) Mojo's colors act as a warning of his favorite attack's repercussions. He tends to leave bruises when he decides to head butt people's shins.\n\r\n3) Likewise, Bob's colors remind everyone that he gets easily queasy and suffered from jaundice as a kitten. \n\r\n4) Tiger's colors don't have anything to do with his name. Unless of course his name was old guy with grape juice on half his hair. \n\r\n5) Whisker's accessories reflect his owner's obsession with the Texas Longhorns. \n\r\n6) Jewel's owner is the most girlie person in town. Everything about her is either salmon or scarlet.", "hint": "Queasy is also known as being \"green at the gills\"; jaundice tends to turn your skin/eyes yellow.\r\nBruises are often black and blue.\r\nOlder folks tend to lose the color in their hair, leaving it grey or white.\n\r\nOkay that's enough, this one started off way too easy, now it's just sad.", "answer": "Jewel, red, pink\r\nWhiskers, white, orange\r\nTiger, purple, grey\r\nMojo, blue, black\r\nBob, green, yellow", "category": "Logic-Grid", "date": "03/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Dopeyville, some genius had the idea to make a Cat Park. Similar to a Dog Park, only this is where you take your cat to socialize. Now anyone who has a cat knows this is an insane idea, but look at the name of this town - enough said. \n\r\nNeedless to say, there were problems right from the beginning. There were calicoes having cattywumpuses, tabbies having tantrums, and don't even ask about what the Siameses did to the sandbox. Trust me you don't want to know!\n\r\nSo, one day, Barney, the hired cat-walker of Goober Drive, decided to take his charges to the Cat Park. There were other cat-walkers at the park. The two cats he took were neighbors, and were used to putting up with each other, so they got along fine. However, they didn't get along with the other cats at the park. There was a scuffle and the cats got loose, including three other cats. Turns out, cats are great escape artists. They managed to wiggle out of their leashes, AND their harnesses. So now we have a bit of a disaster. The cat-walkers managed to gather up the frisky felines, but are now stumped as to who's who. Please help Barney and the other Kitty Parents sort out the cats, their leashes, and their harnesses before Barney's customers start to wonder where their beloved cats are.\n\r\nCats: Jewel, Whiskers, Tiger, Mojo, and Bob\r\nHarnesses: Red, Purple, Blue, Green, and White\r\nLeashes: Yellow, Black, Orange, Grey, and Pink\n\r\n1) The five cats are: Whiskers, the cat with the blue harness, the cat with the pink leash, the purple harnessed cat, and Bob. \n\r\n2) Mojo's colors act as a warning of his favorite attack's repercussions. He tends to leave bruises when he decides to head butt people's shins.\n\r\n3) Likewise, Bob's colors remind everyone that he gets easily queasy and suffered from jaundice as a kitten. \n\r\n4) Tiger's colors don't have anything to do with his name. Unless of course his name was old guy with grape juice on half his hair. \n\r\n5) Whisker's accessories reflect his owner's obsession with the Texas Longhorns. \n\r\n6) Jewel's owner is the most girlie person in town. Everything about her is either salmon or scarlet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJewel, red, pink\r\nWhiskers, white, orange\r\nTiger, purple, grey\r\nMojo, blue, black\r\nBob, green, yellow\n<|im_start|>answer\nJewel, red, pink\r\nWhiskers, white, orange\r\nTiger, purple, grey\r\nMojo, blue, black\r\nBob, green, yellow\n<|im_end|>" }, { "id": "#31100", "title": "Pizza Pizza", "fun": 2.66, "difficulty": 1.66, "author": "phrebh", "desc": "Three different people (Aaron, Bertha, and Chuck) with three different last names (Able, Bowman, and Cook) ordered a pizza from their favorite delivery place, Trianimoes. Unfortunately, the person taking the orders messed everything up, as usual. The poor delivery guy had to figure out what pizza (Pepperoni, Sausage, and Supreme) had to go to which address on Travis RD (2313, 2315, and 2317) just using the limited clues that the order taker could remember.\n\r\n1. No one had the same first and last initials.\r\n2. The three pizzas are the pepperoni, the one delivered to 2313, and the one that Bowman ordered.\r\n3. Bertha and Chuck are not next door neighbors.\r\n4. Either Able lives at 2317 or the supreme was delivered to 2317.\r\n5. Chuck loves onions and green peppers and has to have them on his pizza.", "hint": "Remember that one side of the street has odd-numbered houses and the other side has even-numbered houses.", "answer": "Aaron Cook ordered Pepperoni from 2315.\r\nBertha Able ordered Sausage from 2313.\r\nChuck Bowman ordered Supreme from 2317.", "category": "Logic-Grid", "date": "06/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree different people (Aaron, Bertha, and Chuck) with three different last names (Able, Bowman, and Cook) ordered a pizza from their favorite delivery place, Trianimoes. Unfortunately, the person taking the orders messed everything up, as usual. The poor delivery guy had to figure out what pizza (Pepperoni, Sausage, and Supreme) had to go to which address on Travis RD (2313, 2315, and 2317) just using the limited clues that the order taker could remember.\n\r\n1. No one had the same first and last initials.\r\n2. The three pizzas are the pepperoni, the one delivered to 2313, and the one that Bowman ordered.\r\n3. Bertha and Chuck are not next door neighbors.\r\n4. Either Able lives at 2317 or the supreme was delivered to 2317.\r\n5. Chuck loves onions and green peppers and has to have them on his pizza.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAaron Cook ordered Pepperoni from 2315.\r\nBertha Able ordered Sausage from 2313.\r\nChuck Bowman ordered Supreme from 2317.\n<|im_start|>answer\nAaron Cook ordered Pepperoni from 2315.\r\nBertha Able ordered Sausage from 2313.\r\nChuck Bowman ordered Supreme from 2317.\n<|im_end|>" }, { "id": "#30473", "title": "Lost Numbers", "fun": 2.66, "difficulty": 1.72, "author": "fairelamour", "desc": "While walking along the river, you come upon a Countess. The Countess looks very sad, so you ask what is wrong. It seems that the Countess has lost some numbers and needs to find them. She says they are special numbers because:\n\r\n1. They are all between 300 and 600. \r\n2. The middle digit is odd and the other digits are even. \r\n3. The sum of the digits is 13. \n\r\nCan you find the lost numbers for the Countess?", "hint": "1. What digit must each number start with? \r\n2. Numbers ending in zero are even numbers.", "answer": "The lost numbers are 418, 436, 454, 472, and 490.\n\r\nTry 3-digit numbers that begin with 4 and have an odd middle number and an even ones digit. Then add the digits to see if the sum is 13.", "category": "Math", "date": "05/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile walking along the river, you come upon a Countess. The Countess looks very sad, so you ask what is wrong. It seems that the Countess has lost some numbers and needs to find them. She says they are special numbers because:\n\r\n1. They are all between 300 and 600. \r\n2. The middle digit is odd and the other digits are even. \r\n3. The sum of the digits is 13. \n\r\nCan you find the lost numbers for the Countess?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lost numbers are 418, 436, 454, 472, and 490.\n\r\nTry 3-digit numbers that begin with 4 and have an odd middle number and an even ones digit. Then add the digits to see if the sum is 13.\n<|im_start|>answer\nThe lost numbers are 418, 436, 454, 472, and 490.\n\r\nTry 3-digit numbers that begin with 4 and have an odd middle number and an even ones digit. Then add the digits to see if the sum is 13.\n<|im_end|>" }, { "id": "#30472", "title": "Three Statements VII", "fun": 2.66, "difficulty": 1.37, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. Suppose you begin reading a book on page B and end on page E. If you read each page completely and the pages are numbered and read consecutively then you have read (E - B) + 1 pages.\n\r\n2. Christina has 60 apples. Anna has 85 and Dana has 148. Together Christina and Anna have more apples than Dana.\n\r\n3. If you write the words DOS, TAM and MAN with DOS on top, TAM in the middle and MAN at the bottom then the names DAN and SAM can be formed diagonally.", "hint": "No hint available.", "answer": "Statements 1 and 3 are true, statement 2 is false.\n\r\nIn statement 1, the beginning page and the ending page are also included, so you have read (E - B) + 1 pages.\n\r\nIn statement 2, 60+85=145<148.\n\r\nIn statement 3, the grid looks like this:\n\r\nD O S\r\nT A M\r\nM A N\n\r\nThe names DAN and SAM can be formed diagonally.", "category": "Logic", "date": "05/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. Suppose you begin reading a book on page B and end on page E. If you read each page completely and the pages are numbered and read consecutively then you have read (E - B) + 1 pages.\n\r\n2. Christina has 60 apples. Anna has 85 and Dana has 148. Together Christina and Anna have more apples than Dana.\n\r\n3. If you write the words DOS, TAM and MAN with DOS on top, TAM in the middle and MAN at the bottom then the names DAN and SAM can be formed diagonally.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 1 and 3 are true, statement 2 is false.\n\r\nIn statement 1, the beginning page and the ending page are also included, so you have read (E - B) + 1 pages.\n\r\nIn statement 2, 60+85=145<148.\n\r\nIn statement 3, the grid looks like this:\n\r\nD O S\r\nT A M\r\nM A N\n\r\nThe names DAN and SAM can be formed diagonally.\n<|im_start|>answer\nStatements 1 and 3 are true, statement 2 is false.\n\r\nIn statement 1, the beginning page and the ending page are also included, so you have read (E - B) + 1 pages.\n\r\nIn statement 2, 60+85=145<148.\n\r\nIn statement 3, the grid looks like this:\n\r\nD O S\r\nT A M\r\nM A N\n\r\nThe names DAN and SAM can be formed diagonally.\n<|im_end|>" }, { "id": "#35588", "title": "Tom & Jerry", "fun": 2.66, "difficulty": 1.46, "author": "eguee", "desc": "Tom is chasing Jerry again! Jerry can run at 1 meter/sec, but Tom can run at 1.5 meter/sec. \r\nTom, being a stupid cat, runs into a 3 meter long sofa and takes 3 seconds to wriggle out. Jerry's mouse hole is 2 meters away from the other end of the sofa. \r\nIf Jerry runs under the sofa 1 second after Tom gets stuck, and Tom runs over the sofa to catch Jerry, will Tom catch Jerry?", "hint": "Simple Maths", "answer": "Jerry beats Tom (Again!)\r\nJerry needs to run 6 meters, (added the extra second before the sofa), while Tom has to run 9.5 meters (added the seconds taken to wriggle out)\r\n6/1 = 6 seconds\r\n9.5/1.5 = 6 and 1/3 seconds.\r\nJerry will beat Tom by half a meter or 1/3 of a second to Jerry's hole.", "category": "Math", "date": "03/07/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTom is chasing Jerry again! Jerry can run at 1 meter/sec, but Tom can run at 1.5 meter/sec. \r\nTom, being a stupid cat, runs into a 3 meter long sofa and takes 3 seconds to wriggle out. Jerry's mouse hole is 2 meters away from the other end of the sofa. \r\nIf Jerry runs under the sofa 1 second after Tom gets stuck, and Tom runs over the sofa to catch Jerry, will Tom catch Jerry?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJerry beats Tom (Again!)\r\nJerry needs to run 6 meters, (added the extra second before the sofa), while Tom has to run 9.5 meters (added the seconds taken to wriggle out)\r\n6/1 = 6 seconds\r\n9.5/1.5 = 6 and 1/3 seconds.\r\nJerry will beat Tom by half a meter or 1/3 of a second to Jerry's hole.\n<|im_start|>answer\nJerry beats Tom (Again!)\r\nJerry needs to run 6 meters, (added the extra second before the sofa), while Tom has to run 9.5 meters (added the seconds taken to wriggle out)\r\n6/1 = 6 seconds\r\n9.5/1.5 = 6 and 1/3 seconds.\r\nJerry will beat Tom by half a meter or 1/3 of a second to Jerry's hole.\n<|im_end|>" }, { "id": "#22593", "title": "Mini Mine Sweeper", "fun": 2.66, "difficulty": 1.6, "author": "slow_turtle", "desc": "5 total bombs in 3 by 4 grid (3 rows, 4 columns):\n\r\nrow 1: ? ? 2 1\r\nrow 2: 3 ? ? ?\r\nrow 3: ? 1 ? ?\n\r\nFind the bombs.\n\r\nMine Sweeper rules: each number represents the exact total of surrounding mines.", "hint": "There is enough information to figure out the entire grid.", "answer": "* are bombs.\n\r\nrow 1: * * 2 1\r\nrow 2: 3 3 3 *\r\nrow 3: * 1 2 *\n\r\nExplanation:\r\nLet's rewrite the grid with letters:\r\nrow 1: A B 2 1\r\nrow 2: 3 C D E\r\nrow 3: F 1 G H\n\r\nStep 1: we know either D or E is a bomb (but not both).\n\r\nStep 2: From Step 1, we know B or C is a bomb (but not both).\n\r\nStep 3: From Step 2, we know A and F are bombs.\r\nrow 1: * B 2 1\r\nrow 2: 3 C D E\r\nrow 3: * 1 G H\n\r\nStep 4: From Step 3, we know C, D, and G are not bombs.\r\nrow 1: * B 2 1\r\nrow 2: 3 - - E\r\nrow 3: * 1 - H\n\r\nStep 5: From step 4, we know B is a bomb and E is a bomb.\r\nrow 1: * * 2 1\r\nrow 2: 3 - - *\r\nrow 3: * 1 - H\n\r\nStep 6: Since there are exactly 5 bombs H must be a bomb.\r\nrow 1: * * 2 1\r\nrow 2: 3 - - *\r\nrow 3: * 1 - *", "category": "Logic", "date": "05/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 total bombs in 3 by 4 grid (3 rows, 4 columns):\n\r\nrow 1: ? ? 2 1\r\nrow 2: 3 ? ? ?\r\nrow 3: ? 1 ? ?\n\r\nFind the bombs.\n\r\nMine Sweeper rules: each number represents the exact total of surrounding mines.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n* are bombs.\n\r\nrow 1: * * 2 1\r\nrow 2: 3 3 3 *\r\nrow 3: * 1 2 *\n\r\nExplanation:\r\nLet's rewrite the grid with letters:\r\nrow 1: A B 2 1\r\nrow 2: 3 C D E\r\nrow 3: F 1 G H\n\r\nStep 1: we know either D or E is a bomb (but not both).\n\r\nStep 2: From Step 1, we know B or C is a bomb (but not both).\n\r\nStep 3: From Step 2, we know A and F are bombs.\r\nrow 1: * B 2 1\r\nrow 2: 3 C D E\r\nrow 3: * 1 G H\n\r\nStep 4: From Step 3, we know C, D, and G are not bombs.\r\nrow 1: * B 2 1\r\nrow 2: 3 - - E\r\nrow 3: * 1 - H\n\r\nStep 5: From step 4, we know B is a bomb and E is a bomb.\r\nrow 1: * * 2 1\r\nrow 2: 3 - - *\r\nrow 3: * 1 - H\n\r\nStep 6: Since there are exactly 5 bombs H must be a bomb.\r\nrow 1: * * 2 1\r\nrow 2: 3 - - *\r\nrow 3: * 1 - *\n<|im_start|>answer\n* are bombs.\n\r\nrow 1: * * 2 1\r\nrow 2: 3 3 3 *\r\nrow 3: * 1 2 *\n\r\nExplanation:\r\nLet's rewrite the grid with letters:\r\nrow 1: A B 2 1\r\nrow 2: 3 C D E\r\nrow 3: F 1 G H\n\r\nStep 1: we know either D or E is a bomb (but not both).\n\r\nStep 2: From Step 1, we know B or C is a bomb (but not both).\n\r\nStep 3: From Step 2, we know A and F are bombs.\r\nrow 1: * B 2 1\r\nrow 2: 3 C D E\r\nrow 3: * 1 G H\n\r\nStep 4: From Step 3, we know C, D, and G are not bombs.\r\nrow 1: * B 2 1\r\nrow 2: 3 - - E\r\nrow 3: * 1 - H\n\r\nStep 5: From step 4, we know B is a bomb and E is a bomb.\r\nrow 1: * * 2 1\r\nrow 2: 3 - - *\r\nrow 3: * 1 - H\n\r\nStep 6: Since there are exactly 5 bombs H must be a bomb.\r\nrow 1: * * 2 1\r\nrow 2: 3 - - *\r\nrow 3: * 1 - *\n<|im_end|>" }, { "id": "#8500", "title": "Water Juggling", "fun": 2.66, "difficulty": 2.93, "author": "sakirski", "desc": "Here's what you have: \n\r\n-Two 8-liter jugs, filled with water \r\n-One 3-liter jug, empty \r\n-Four infinite size, empty pools \n\r\nHere's what your objective is: \r\nFill each of the four pools with exactly 4 liters of water. \n\r\nHere are your constraints: \n\r\n-You have nothing else at your disposal. \r\n-There is no other water aside from the two 8-liter water filled jugs. \r\n-Once water is poured into any of the 4 pools it cannot be removed from there. \r\n-The jugs are not symmetric so you cannot measure amount by eye or judge based on shape.", "hint": "I am not sure how to help you :). I solved this in 24 steps (you may have more or less). It helps to label the jugs and pools, and then draw. Oh, main key, try to work backwards, from filled pools, and see what final steps are even possible.", "answer": "It's not short but it's right - use a piece of paper and follow the steps using A, B, C and pools. Change the quantities in each as you complete each step - it is worth it to see it come out right. \n\r\nLets label the jugs. \n\r\nJug A - first 8-liter \r\nJug B - second 8-liter \r\nJug C - 3-liter. \n\r\nThe four infinites are pool 1, pool 2, pool 3, and pool 4. \n\r\n1. Jug A to Jug C \r\n2. Jug C to pool 1 \r\n3. Jug A to Jug C \r\n4. Jug A to pool 2 \r\n5. Jug C to Jug A \r\n6. Jug B to Jug C \r\n7. Jug C to Jug A \r\n8. Jug B to Jug C \r\n9. Jug C to Jug A \n\r\nAt this point, we have: \n\r\nJug A - 8 \r\nJug B - 2 \r\nJug C - 1 \r\nPool 1 - 3 \r\nPool 2 - 2 \r\nPools 3&4 - empty \n\r\n10. Jug C to pool 3 \r\n11. Jug B to Jug C \r\n12. Jug A to Jug C \r\n13. Jug C to Jug B \r\n14. Jug A to Jug C \r\n15. Jug C to Jug B \r\n16. Jug A to Jug C \r\n17. Jug A to pool 4 \n\r\nAt this point, we have: \n\r\nJug A - 0 \r\nJug B - 6 \r\nJug C - 3 \r\nPool 1 - 3 \r\nPool 2 - 2 \r\nPool 3 - 1 \r\nPool 4 - 1. \n\r\n18. Jug C to Jug B \r\n19. Jug C to pool 1 \r\n20. Jug B to Jug C \r\n21. Jug C to pool 3 \r\n22. Jug B to Jug C \r\n23. Jug C to pool 4 \r\n24. Jug B to pool 2 \n\r\n... And we end up with the desired result: \n\r\nJug A - 0 \r\nJug B - 0 \r\nJug C - 0 \r\nPool 1 - 4 \r\nPool 2 - 4 \r\nPool 3 - 4 \r\nPool 4 - 4 \n\r\nTough, but workable.", "category": "Logic", "date": "11/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHere's what you have: \n\r\n-Two 8-liter jugs, filled with water \r\n-One 3-liter jug, empty \r\n-Four infinite size, empty pools \n\r\nHere's what your objective is: \r\nFill each of the four pools with exactly 4 liters of water. \n\r\nHere are your constraints: \n\r\n-You have nothing else at your disposal. \r\n-There is no other water aside from the two 8-liter water filled jugs. \r\n-Once water is poured into any of the 4 pools it cannot be removed from there. \r\n-The jugs are not symmetric so you cannot measure amount by eye or judge based on shape.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's not short but it's right - use a piece of paper and follow the steps using A, B, C and pools. Change the quantities in each as you complete each step - it is worth it to see it come out right. \n\r\nLets label the jugs. \n\r\nJug A - first 8-liter \r\nJug B - second 8-liter \r\nJug C - 3-liter. \n\r\nThe four infinites are pool 1, pool 2, pool 3, and pool 4. \n\r\n1. Jug A to Jug C \r\n2. Jug C to pool 1 \r\n3. Jug A to Jug C \r\n4. Jug A to pool 2 \r\n5. Jug C to Jug A \r\n6. Jug B to Jug C \r\n7. Jug C to Jug A \r\n8. Jug B to Jug C \r\n9. Jug C to Jug A \n\r\nAt this point, we have: \n\r\nJug A - 8 \r\nJug B - 2 \r\nJug C - 1 \r\nPool 1 - 3 \r\nPool 2 - 2 \r\nPools 3&4 - empty \n\r\n10. Jug C to pool 3 \r\n11. Jug B to Jug C \r\n12. Jug A to Jug C \r\n13. Jug C to Jug B \r\n14. Jug A to Jug C \r\n15. Jug C to Jug B \r\n16. Jug A to Jug C \r\n17. Jug A to pool 4 \n\r\nAt this point, we have: \n\r\nJug A - 0 \r\nJug B - 6 \r\nJug C - 3 \r\nPool 1 - 3 \r\nPool 2 - 2 \r\nPool 3 - 1 \r\nPool 4 - 1. \n\r\n18. Jug C to Jug B \r\n19. Jug C to pool 1 \r\n20. Jug B to Jug C \r\n21. Jug C to pool 3 \r\n22. Jug B to Jug C \r\n23. Jug C to pool 4 \r\n24. Jug B to pool 2 \n\r\n... And we end up with the desired result: \n\r\nJug A - 0 \r\nJug B - 0 \r\nJug C - 0 \r\nPool 1 - 4 \r\nPool 2 - 4 \r\nPool 3 - 4 \r\nPool 4 - 4 \n\r\nTough, but workable.\n<|im_start|>answer\nIt's not short but it's right - use a piece of paper and follow the steps using A, B, C and pools. Change the quantities in each as you complete each step - it is worth it to see it come out right. \n\r\nLets label the jugs. \n\r\nJug A - first 8-liter \r\nJug B - second 8-liter \r\nJug C - 3-liter. \n\r\nThe four infinites are pool 1, pool 2, pool 3, and pool 4. \n\r\n1. Jug A to Jug C \r\n2. Jug C to pool 1 \r\n3. Jug A to Jug C \r\n4. Jug A to pool 2 \r\n5. Jug C to Jug A \r\n6. Jug B to Jug C \r\n7. Jug C to Jug A \r\n8. Jug B to Jug C \r\n9. Jug C to Jug A \n\r\nAt this point, we have: \n\r\nJug A - 8 \r\nJug B - 2 \r\nJug C - 1 \r\nPool 1 - 3 \r\nPool 2 - 2 \r\nPools 3&4 - empty \n\r\n10. Jug C to pool 3 \r\n11. Jug B to Jug C \r\n12. Jug A to Jug C \r\n13. Jug C to Jug B \r\n14. Jug A to Jug C \r\n15. Jug C to Jug B \r\n16. Jug A to Jug C \r\n17. Jug A to pool 4 \n\r\nAt this point, we have: \n\r\nJug A - 0 \r\nJug B - 6 \r\nJug C - 3 \r\nPool 1 - 3 \r\nPool 2 - 2 \r\nPool 3 - 1 \r\nPool 4 - 1. \n\r\n18. Jug C to Jug B \r\n19. Jug C to pool 1 \r\n20. Jug B to Jug C \r\n21. Jug C to pool 3 \r\n22. Jug B to Jug C \r\n23. Jug C to pool 4 \r\n24. Jug B to pool 2 \n\r\n... And we end up with the desired result: \n\r\nJug A - 0 \r\nJug B - 0 \r\nJug C - 0 \r\nPool 1 - 4 \r\nPool 2 - 4 \r\nPool 3 - 4 \r\nPool 4 - 4 \n\r\nTough, but workable.\n<|im_end|>" }, { "id": "#34492", "title": "What's For Lunch? 2", "fun": 2.66, "difficulty": 1.95, "author": "medster99", "desc": "A man was called forth from his cubicle to perform a time-honored task: get lunch.\n\r\nHis boss, Medster, told him to get a certain number of salads and bagels. A salad costs $1.10, and a bagel costs $1.50. Medster gave him $32.10, the exact amount needed to buy all the items for the 23 people (one item per person). He rushes to The Salad and Bagel Store, and suddenly realizes that he forgot how many bagels and salads to get!\r\nLuckily, the new employee is smart, and successfully figures out how many of each lunch to get.\n\r\nUsing the facts he has, can you figure out how many bagels and salads he needs to get?", "hint": "No hint available.", "answer": "He needs to get 17 bagels, and 6 salads.\r\n17 bagels = $25.50\r\n6 salads = $6.60\n\r\ns = salad\r\nb = bagel\r\ntotal cost = 32.10\r\ntotal people = 23\n\r\n1.1s + 1.5b = 32.10\r\nor\r\ns = (32.10 - 1.5b)/1.1\n\r\ns + b = 23\r\nor\r\ns = 23 - b\n\r\nSince both equations equal s, the both equal each other, and can be solved like so:\n\r\n(32.10 - 1.5b)/1.1 = 23 - b\r\n32.10 - 1.5b = 25.30 - 1.1b\r\n32.10 = 25.30 + 0.4b\r\n6.80 = 0.4b\r\n17 = b\n\n\r\nTherefore:\n\r\ns + 17 = 23\r\ns = 6", "category": "Math", "date": "12/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man was called forth from his cubicle to perform a time-honored task: get lunch.\n\r\nHis boss, Medster, told him to get a certain number of salads and bagels. A salad costs $1.10, and a bagel costs $1.50. Medster gave him $32.10, the exact amount needed to buy all the items for the 23 people (one item per person). He rushes to The Salad and Bagel Store, and suddenly realizes that he forgot how many bagels and salads to get!\r\nLuckily, the new employee is smart, and successfully figures out how many of each lunch to get.\n\r\nUsing the facts he has, can you figure out how many bagels and salads he needs to get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe needs to get 17 bagels, and 6 salads.\r\n17 bagels = $25.50\r\n6 salads = $6.60\n\r\ns = salad\r\nb = bagel\r\ntotal cost = 32.10\r\ntotal people = 23\n\r\n1.1s + 1.5b = 32.10\r\nor\r\ns = (32.10 - 1.5b)/1.1\n\r\ns + b = 23\r\nor\r\ns = 23 - b\n\r\nSince both equations equal s, the both equal each other, and can be solved like so:\n\r\n(32.10 - 1.5b)/1.1 = 23 - b\r\n32.10 - 1.5b = 25.30 - 1.1b\r\n32.10 = 25.30 + 0.4b\r\n6.80 = 0.4b\r\n17 = b\n\n\r\nTherefore:\n\r\ns + 17 = 23\r\ns = 6\n<|im_start|>answer\nHe needs to get 17 bagels, and 6 salads.\r\n17 bagels = $25.50\r\n6 salads = $6.60\n\r\ns = salad\r\nb = bagel\r\ntotal cost = 32.10\r\ntotal people = 23\n\r\n1.1s + 1.5b = 32.10\r\nor\r\ns = (32.10 - 1.5b)/1.1\n\r\ns + b = 23\r\nor\r\ns = 23 - b\n\r\nSince both equations equal s, the both equal each other, and can be solved like so:\n\r\n(32.10 - 1.5b)/1.1 = 23 - b\r\n32.10 - 1.5b = 25.30 - 1.1b\r\n32.10 = 25.30 + 0.4b\r\n6.80 = 0.4b\r\n17 = b\n\n\r\nTherefore:\n\r\ns + 17 = 23\r\ns = 6\n<|im_end|>" }, { "id": "#38447", "title": "Four Students", "fun": 2.66, "difficulty": 1.26, "author": "Draw", "desc": "Four students, Nina, Joy, Annie and Bobby took a mathematics test, and were guessing their grades.\n\r\nNina says: \"If I get an A, so does Joy.\"\r\nJoy says: \"If I get an A, so does Annie.\"\r\nAnnie says: \"If I get an A, so does Bobby.\"\n\r\nThey all guessed correctly, but in fact, only two of them got an A. Who are they?", "hint": "No hint available.", "answer": "If Nina got an A, then all four students got an A, which contradicts the fact that only two got an A.\r\nIf Joy got an A, then so did Annie and Bobby, and also contradicts.\r\nTherefore, only Annie and Bobby got an A.", "category": "Logic", "date": "09/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour students, Nina, Joy, Annie and Bobby took a mathematics test, and were guessing their grades.\n\r\nNina says: \"If I get an A, so does Joy.\"\r\nJoy says: \"If I get an A, so does Annie.\"\r\nAnnie says: \"If I get an A, so does Bobby.\"\n\r\nThey all guessed correctly, but in fact, only two of them got an A. Who are they?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Nina got an A, then all four students got an A, which contradicts the fact that only two got an A.\r\nIf Joy got an A, then so did Annie and Bobby, and also contradicts.\r\nTherefore, only Annie and Bobby got an A.\n<|im_start|>answer\nIf Nina got an A, then all four students got an A, which contradicts the fact that only two got an A.\r\nIf Joy got an A, then so did Annie and Bobby, and also contradicts.\r\nTherefore, only Annie and Bobby got an A.\n<|im_end|>" }, { "id": "#25519", "title": "One Big Mess", "fun": 2.66, "difficulty": 0.98, "author": "metallicman", "desc": "Jacob, Dustin, Brittany, Michelle, and Scott were eating at a restaurant. They each liked one of the following: apples, carrots, Starburst, sandwiches, or Skittles.\n\r\nTheir ages, in no specific order, are: 38, 14, 18, 43, 16.\n\r\nTheir food was under cooked, and they got bad food poisoning. Therefore, no one could remember who was who, but what they could remember was this:\n\r\n1. The one who is 14 likes Skittles.\n\r\n2. The one who is 18 has a name that doesn't start with the letter S or B.\n\r\n3. Michelle is not 14 or 43.\n\r\n4. Dustin likes Starburst.\n\r\n5. Brittany is older than Jacob.\n\r\n6. Scott is older than Dustin and Michelle.\n\r\n7. Jacob is younger than Dustin.\n\r\n8. Scott doesn't like sweets or fruit.\n\r\n9. Michelle likes sandwiches.\n\r\n10. Michelle is five years younger than Scott.\n\r\nCan you straighten out this mess and discover who is who?", "hint": "Skittles and Starburst are sweets (candies).", "answer": "Jacob, 14, likes Skittles.\r\nBrittany, 16, likes apples.\r\nDustin, 18, likes Starburst.\r\nMichelle, 38, likes sandwiches.\r\nScott, 43, likes carrots.", "category": "Logic-Grid", "date": "08/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJacob, Dustin, Brittany, Michelle, and Scott were eating at a restaurant. They each liked one of the following: apples, carrots, Starburst, sandwiches, or Skittles.\n\r\nTheir ages, in no specific order, are: 38, 14, 18, 43, 16.\n\r\nTheir food was under cooked, and they got bad food poisoning. Therefore, no one could remember who was who, but what they could remember was this:\n\r\n1. The one who is 14 likes Skittles.\n\r\n2. The one who is 18 has a name that doesn't start with the letter S or B.\n\r\n3. Michelle is not 14 or 43.\n\r\n4. Dustin likes Starburst.\n\r\n5. Brittany is older than Jacob.\n\r\n6. Scott is older than Dustin and Michelle.\n\r\n7. Jacob is younger than Dustin.\n\r\n8. Scott doesn't like sweets or fruit.\n\r\n9. Michelle likes sandwiches.\n\r\n10. Michelle is five years younger than Scott.\n\r\nCan you straighten out this mess and discover who is who?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJacob, 14, likes Skittles.\r\nBrittany, 16, likes apples.\r\nDustin, 18, likes Starburst.\r\nMichelle, 38, likes sandwiches.\r\nScott, 43, likes carrots.\n<|im_start|>answer\nJacob, 14, likes Skittles.\r\nBrittany, 16, likes apples.\r\nDustin, 18, likes Starburst.\r\nMichelle, 38, likes sandwiches.\r\nScott, 43, likes carrots.\n<|im_end|>" }, { "id": "#25062", "title": "Application Dilemma", "fun": 2.66, "difficulty": 1.83, "author": "dolphingurl12", "desc": "Two men applied for a job. The first man, John Smith, stated in his application that he had 10 years of experience, that he graduated in 1959 from John F. Kennedy High School, and had graduated from a four year college with top grades, and had several references.\n\r\n The second man, Tom Jones stated he had 3 years of experience, and had dropped out of high school. He had only one reference. \n\r\nThe manager shocked everyone, and hired Tom Jones. Why?", "hint": "It had nothing to do with family ties, bribing, or prejudice.", "answer": "John Smith had claimed he had graduated from John F. Kennedy High School in 1959. John F. Kennedy wasn't elected until 1960, and wasn't assassinated until 1963. Before then high schools weren't named for him. His application was fake.", "category": "Logic", "date": "08/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo men applied for a job. The first man, John Smith, stated in his application that he had 10 years of experience, that he graduated in 1959 from John F. Kennedy High School, and had graduated from a four year college with top grades, and had several references.\n\r\n The second man, Tom Jones stated he had 3 years of experience, and had dropped out of high school. He had only one reference. \n\r\nThe manager shocked everyone, and hired Tom Jones. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn Smith had claimed he had graduated from John F. Kennedy High School in 1959. John F. Kennedy wasn't elected until 1960, and wasn't assassinated until 1963. Before then high schools weren't named for him. His application was fake.\n<|im_start|>answer\nJohn Smith had claimed he had graduated from John F. Kennedy High School in 1959. John F. Kennedy wasn't elected until 1960, and wasn't assassinated until 1963. Before then high schools weren't named for him. His application was fake.\n<|im_end|>" }, { "id": "#5081", "title": "Rectangles", "fun": 2.65, "difficulty": 2.33, "author": "Cascas", "desc": "If you were to construct a 7 x 7 checkered square (i.e., a 7 x 7 chess board), how many rectangles would there be in total? You need to include squares too because a square is a special kind of rectangle.", "hint": "All the rectangles on the board can be identified by connecting:\r\n2 points of the 8 in the top edge (to form the length of the rectangle) and\r\n2 points of the 8 in the left edge (to form the breadth of the rectangle).", "answer": "Length of rectangle and number of Possibilities \r\n7 units 1 \r\n6 units 2 \r\n5 units 3 \r\n... ... \r\n1 unit 7 \n\r\nSo, number of possibilities for different lengths of rectangles = 1 + 2 + 3 + ... + 7 = 28.\r\nSimilarly, number of possibilities for different breadths of rectangles = 1 + 2 + 3 + ... + 7 = 28.\r\nHence, number of rectangles = 28 x 28 = 784.", "category": "Math", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you were to construct a 7 x 7 checkered square (i.e., a 7 x 7 chess board), how many rectangles would there be in total? You need to include squares too because a square is a special kind of rectangle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLength of rectangle and number of Possibilities \r\n7 units 1 \r\n6 units 2 \r\n5 units 3 \r\n... ... \r\n1 unit 7 \n\r\nSo, number of possibilities for different lengths of rectangles = 1 + 2 + 3 + ... + 7 = 28.\r\nSimilarly, number of possibilities for different breadths of rectangles = 1 + 2 + 3 + ... + 7 = 28.\r\nHence, number of rectangles = 28 x 28 = 784.\n<|im_start|>answer\nLength of rectangle and number of Possibilities \r\n7 units 1 \r\n6 units 2 \r\n5 units 3 \r\n... ... \r\n1 unit 7 \n\r\nSo, number of possibilities for different lengths of rectangles = 1 + 2 + 3 + ... + 7 = 28.\r\nSimilarly, number of possibilities for different breadths of rectangles = 1 + 2 + 3 + ... + 7 = 28.\r\nHence, number of rectangles = 28 x 28 = 784.\n<|im_end|>" }, { "id": "#30720", "title": "Showtime", "fun": 2.65, "difficulty": 1.6300000000000001, "author": "lips", "desc": "At the Pine Hill School, each grade of students has one turn each year to put on a show for the rest of the school. There is a different grade performing every month beginning in October. The Pine Hill School has a kindergarten and grades 1 through 8.\n\r\nClues:\n\r\n1. The oldest students present the first performance of the school year, while the youngest put on theirs during the last month of the school year. \n\r\n2. The fourth-graders get dressed up as different U.S. Presidents for Presidents' Day, and the seventh-graders' performance is the month after. \n\r\n3. The Thanksgiving play is traditionally done by fifth-graders who are learning about the Pilgrims. \n\r\n4. Second-graders lead the holiday sing-a-long the month after Thanksgiving, followed by sixth-graders the next month with a tribute to Martin Luther King Jr. \n\r\n5. First-graders perform the one month between the third-graders and the kindergarten class. \n\r\nWhich grade is scheduled to put on the performance each month?", "hint": "Make a chart listing the months in order except for July, August, and September. Then use the clues to solve the problem. Check a calendar for holiday dates.", "answer": "October: 8th grade\r\nNovember: 5th grade\r\nDecember: 2nd grade\r\nJanuary: 6th grade\r\nFebruary: 4th grade\r\nMarch: 7th grade\r\nApril: 3rd grade\r\nMay: 1st grade\r\nJune: kindergarten", "category": "Logic", "date": "05/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the Pine Hill School, each grade of students has one turn each year to put on a show for the rest of the school. There is a different grade performing every month beginning in October. The Pine Hill School has a kindergarten and grades 1 through 8.\n\r\nClues:\n\r\n1. The oldest students present the first performance of the school year, while the youngest put on theirs during the last month of the school year. \n\r\n2. The fourth-graders get dressed up as different U.S. Presidents for Presidents' Day, and the seventh-graders' performance is the month after. \n\r\n3. The Thanksgiving play is traditionally done by fifth-graders who are learning about the Pilgrims. \n\r\n4. Second-graders lead the holiday sing-a-long the month after Thanksgiving, followed by sixth-graders the next month with a tribute to Martin Luther King Jr. \n\r\n5. First-graders perform the one month between the third-graders and the kindergarten class. \n\r\nWhich grade is scheduled to put on the performance each month?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOctober: 8th grade\r\nNovember: 5th grade\r\nDecember: 2nd grade\r\nJanuary: 6th grade\r\nFebruary: 4th grade\r\nMarch: 7th grade\r\nApril: 3rd grade\r\nMay: 1st grade\r\nJune: kindergarten\n<|im_start|>answer\nOctober: 8th grade\r\nNovember: 5th grade\r\nDecember: 2nd grade\r\nJanuary: 6th grade\r\nFebruary: 4th grade\r\nMarch: 7th grade\r\nApril: 3rd grade\r\nMay: 1st grade\r\nJune: kindergarten\n<|im_end|>" }, { "id": "#17301", "title": "Discount Coupon Shopper", "fun": 2.65, "difficulty": 2.19, "author": "absy", "desc": "Until last week, Mandy had been putting off the purchase of four major items for her home, waiting for her town's annual bargain days. Each year, the town's four main stores (including Nickels) each send out a coupon for a different percentage discount (10%, 15%, 20%, or 30%) on the purchase of a single item. Can you find the discount that Mandy received on each of her buys, and determine from which store she purchased each item? \n\r\nGiven: \n\r\nDiscounts: 10%, 15%, 20%, 30% \r\nStore Names: Stears, Pal-Mart, Nickels, Dullard's \r\nAppliances: Computer, Dishwasher, Lawnmower, VCR \n\r\nClues: \n\r\n1) The percentage discount Mandy received on her new computer was twice that of the item she bought at Dullard's. \r\n2) The discount on the Stears purchase was ten percentage points lower than the one on the riding lawnmower. \r\n3) The discount on the dishwasher wasn't 15%. \r\n4) Pal-Mart, (which didn't issue the 30% off coupon) isn't the store at which Mandy purchased the VCR.", "hint": "Make a list of one set of givens and list another set of givens that would correspond to them. i.e (Discounts) -- (Store Names)\n\r\n10% -- Stears, Pal-Mart, Nickels, Dullard's\r\n15% -- Stears, Pal-Mart, Nickels, Dullard's, etc.\n\r\nCross off what you know is NOT the correct answer from the clues, and when you find out a discount that fits a store name circle it, or write the information on a piece of paper in a different section to keep track. Do the same with the other correlations that can be surmised by looking at the clues:\n\r\n(Discounts) -- (Appliances)\r\n(Store Names) -- (Appliances)\n\r\nKeep in mind, for example, that if you find a discount for a store, the other discounts can NOT be for the same store, so that gives you more options to mark off to narrow the correct answer down.", "answer": "Stears -- Dishwasher -- 10%\r\nPal-Mart -- Lawnmower -- 20%\r\nNickels -- Computer -- 30%\r\nDullard's -- VCR -- 15%\n\r\n**Clue #1: According to this clue, we know that the computer discount couldn't be 10% or 15%. By the same token, the Dullard's discount can't be 20% or 30%. We also know that the computer wasn't bought at Dullard's. \r\n**Clue #2: Here we know that the discount used on the lawnmower can not be 15% because the Stears discount has to be 10 points lower. Nor can it be 10% for the same reason. Which means that the Stears discount can only be 20% or 10%. The lawnmower was also not purchased at Stears. \r\n**Clue #3: This clue is self explanatory. This leaves the VCR as the 15% discount. Which in turn makes the dishwasher the 10% discount.\r\n**Clue #4: Pal-Mart didn't give out the 30%. Marking this off leaves Nickels as the 30% discount holder. The VCR was not bought at Pal-Mart. \r\n*********We know that the Nickels discount was 30%. The only appliances that could be purchased with the 30% discount coupon are the lawnmower and the computer. So we can mark off the dishwasher and the VCR from Nickels. Since we know that the VCR was purchased with the 15% discount coupon, and Stears can not be the issuer of that coupon, the VCR was not purchased at Stears. Which leaves the VCR purchase at Dullard's, which we now know issued the 15% coupon. Now, from clue #1, we know that the computer discount is twice that of Dullard's. We know Dullard's is 15%, so the computer is 30%, and was purchased at Nickels. Marking these off leaves the dishwasher at Stears and the lawnmower at Pal-Mart. We know that the dishwasher is 10%, so we know that Stears is the 10% coupon issuer. This leaves Pal-Mart as the 20% coupon issuer.", "category": "Logic", "date": "04/09/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUntil last week, Mandy had been putting off the purchase of four major items for her home, waiting for her town's annual bargain days. Each year, the town's four main stores (including Nickels) each send out a coupon for a different percentage discount (10%, 15%, 20%, or 30%) on the purchase of a single item. Can you find the discount that Mandy received on each of her buys, and determine from which store she purchased each item? \n\r\nGiven: \n\r\nDiscounts: 10%, 15%, 20%, 30% \r\nStore Names: Stears, Pal-Mart, Nickels, Dullard's \r\nAppliances: Computer, Dishwasher, Lawnmower, VCR \n\r\nClues: \n\r\n1) The percentage discount Mandy received on her new computer was twice that of the item she bought at Dullard's. \r\n2) The discount on the Stears purchase was ten percentage points lower than the one on the riding lawnmower. \r\n3) The discount on the dishwasher wasn't 15%. \r\n4) Pal-Mart, (which didn't issue the 30% off coupon) isn't the store at which Mandy purchased the VCR.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStears -- Dishwasher -- 10%\r\nPal-Mart -- Lawnmower -- 20%\r\nNickels -- Computer -- 30%\r\nDullard's -- VCR -- 15%\n\r\n**Clue #1: According to this clue, we know that the computer discount couldn't be 10% or 15%. By the same token, the Dullard's discount can't be 20% or 30%. We also know that the computer wasn't bought at Dullard's. \r\n**Clue #2: Here we know that the discount used on the lawnmower can not be 15% because the Stears discount has to be 10 points lower. Nor can it be 10% for the same reason. Which means that the Stears discount can only be 20% or 10%. The lawnmower was also not purchased at Stears. \r\n**Clue #3: This clue is self explanatory. This leaves the VCR as the 15% discount. Which in turn makes the dishwasher the 10% discount.\r\n**Clue #4: Pal-Mart didn't give out the 30%. Marking this off leaves Nickels as the 30% discount holder. The VCR was not bought at Pal-Mart. \r\n*********We know that the Nickels discount was 30%. The only appliances that could be purchased with the 30% discount coupon are the lawnmower and the computer. So we can mark off the dishwasher and the VCR from Nickels. Since we know that the VCR was purchased with the 15% discount coupon, and Stears can not be the issuer of that coupon, the VCR was not purchased at Stears. Which leaves the VCR purchase at Dullard's, which we now know issued the 15% coupon. Now, from clue #1, we know that the computer discount is twice that of Dullard's. We know Dullard's is 15%, so the computer is 30%, and was purchased at Nickels. Marking these off leaves the dishwasher at Stears and the lawnmower at Pal-Mart. We know that the dishwasher is 10%, so we know that Stears is the 10% coupon issuer. This leaves Pal-Mart as the 20% coupon issuer.\n<|im_start|>answer\nStears -- Dishwasher -- 10%\r\nPal-Mart -- Lawnmower -- 20%\r\nNickels -- Computer -- 30%\r\nDullard's -- VCR -- 15%\n\r\n**Clue #1: According to this clue, we know that the computer discount couldn't be 10% or 15%. By the same token, the Dullard's discount can't be 20% or 30%. We also know that the computer wasn't bought at Dullard's. \r\n**Clue #2: Here we know that the discount used on the lawnmower can not be 15% because the Stears discount has to be 10 points lower. Nor can it be 10% for the same reason. Which means that the Stears discount can only be 20% or 10%. The lawnmower was also not purchased at Stears. \r\n**Clue #3: This clue is self explanatory. This leaves the VCR as the 15% discount. Which in turn makes the dishwasher the 10% discount.\r\n**Clue #4: Pal-Mart didn't give out the 30%. Marking this off leaves Nickels as the 30% discount holder. The VCR was not bought at Pal-Mart. \r\n*********We know that the Nickels discount was 30%. The only appliances that could be purchased with the 30% discount coupon are the lawnmower and the computer. So we can mark off the dishwasher and the VCR from Nickels. Since we know that the VCR was purchased with the 15% discount coupon, and Stears can not be the issuer of that coupon, the VCR was not purchased at Stears. Which leaves the VCR purchase at Dullard's, which we now know issued the 15% coupon. Now, from clue #1, we know that the computer discount is twice that of Dullard's. We know Dullard's is 15%, so the computer is 30%, and was purchased at Nickels. Marking these off leaves the dishwasher at Stears and the lawnmower at Pal-Mart. We know that the dishwasher is 10%, so we know that Stears is the 10% coupon issuer. This leaves Pal-Mart as the 20% coupon issuer.\n<|im_end|>" }, { "id": "#49426", "title": "How Old, Again?", "fun": 2.65, "difficulty": 2.14, "author": "fishmed", "desc": "Suppose I am a grandfather. My grandson is about as old in days as my son is in weeks. He is also as many months old as I am in years. Together, the three of us are 140 years old. How old am I?", "hint": "Round is allowed on final answer", "answer": "As noted, all three are 140 years old. Thus, a+b+c=140, where a is grandfather, b is son, and c is grandson. Additionally, grandson being about as many days old as son is in weeks gives 365c=52b. Finally, the grandson being as many months as I am in years gives 12c=a. Thus, the following are known.\n\r\na+b+c=140\r\n365c=52b or b=365c/52\r\n12c=a\n\r\nBy calculation and substitution we have as follows.\n\r\n12c + 365c/52 +c = 140\r\n624c + 365c + 52c = 7280\r\n1041c = 7280\r\nc = 6.99, or 7 (teaser said 'about')\r\nso, as 12c = a, then a = 84.\n\r\nI am 84 years old. \r\nAs an aside, my son is 49.", "category": "Math", "date": "04/02/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose I am a grandfather. My grandson is about as old in days as my son is in weeks. He is also as many months old as I am in years. Together, the three of us are 140 years old. How old am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAs noted, all three are 140 years old. Thus, a+b+c=140, where a is grandfather, b is son, and c is grandson. Additionally, grandson being about as many days old as son is in weeks gives 365c=52b. Finally, the grandson being as many months as I am in years gives 12c=a. Thus, the following are known.\n\r\na+b+c=140\r\n365c=52b or b=365c/52\r\n12c=a\n\r\nBy calculation and substitution we have as follows.\n\r\n12c + 365c/52 +c = 140\r\n624c + 365c + 52c = 7280\r\n1041c = 7280\r\nc = 6.99, or 7 (teaser said 'about')\r\nso, as 12c = a, then a = 84.\n\r\nI am 84 years old. \r\nAs an aside, my son is 49.\n<|im_start|>answer\nAs noted, all three are 140 years old. Thus, a+b+c=140, where a is grandfather, b is son, and c is grandson. Additionally, grandson being about as many days old as son is in weeks gives 365c=52b. Finally, the grandson being as many months as I am in years gives 12c=a. Thus, the following are known.\n\r\na+b+c=140\r\n365c=52b or b=365c/52\r\n12c=a\n\r\nBy calculation and substitution we have as follows.\n\r\n12c + 365c/52 +c = 140\r\n624c + 365c + 52c = 7280\r\n1041c = 7280\r\nc = 6.99, or 7 (teaser said 'about')\r\nso, as 12c = a, then a = 84.\n\r\nI am 84 years old. \r\nAs an aside, my son is 49.\n<|im_end|>" }, { "id": "#4838", "title": "Asparagus", "fun": 2.65, "difficulty": 1.07, "author": "missie", "desc": "A man walked into a family owned store. He asked the clerk if the store carried any asparagus. The clerk replied no. The next day the same man walked in and asked the same clerk if the store carried any asparagus. The clerk again replied, no. The next day, once again, the man walked in and asked the same clerk if the store carried asparagus. The clerk replied, \"If you ask that again I'll staple your lips together.\" Knowing the clerk was serious, the man left. The next day the man came in and asked a question. The clerk replied, no. The man, once again, asked, \"Does this store carry asparagus?\" What did the man ask (where the clerk responded no) that made him brave enough to ask about asparagus?", "hint": "No hint available.", "answer": "The man said, \"Do you have any staples?\"", "category": "Logic", "date": "06/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man walked into a family owned store. He asked the clerk if the store carried any asparagus. The clerk replied no. The next day the same man walked in and asked the same clerk if the store carried any asparagus. The clerk again replied, no. The next day, once again, the man walked in and asked the same clerk if the store carried asparagus. The clerk replied, \"If you ask that again I'll staple your lips together.\" Knowing the clerk was serious, the man left. The next day the man came in and asked a question. The clerk replied, no. The man, once again, asked, \"Does this store carry asparagus?\" What did the man ask (where the clerk responded no) that made him brave enough to ask about asparagus?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man said, \"Do you have any staples?\"\n<|im_start|>answer\nThe man said, \"Do you have any staples?\"\n<|im_end|>" }, { "id": "#11665", "title": "Bike Contest", "fun": 2.65, "difficulty": 1.43, "author": "PeaceJo", "desc": "Sarah, Daniel and Megan had a contest to see who could bike the most miles. Together Sarah and Daniel biked 21 miles. The combined total for Sarah and Megan was 19. Together Megan and Daniel rode 22 miles.\n\r\nWho was the winner?", "hint": "No hint available.", "answer": "Daniel is the winner.\n\r\nSarah = 9 miles\r\nMegan = 10 miles\r\nDaniel = 12 miles\n\r\nSet up three equations:\n\r\nS + D = 21\r\nS + M = 19\r\nM + D = 22\n\r\nand solve for S, M, and D.", "category": "Math", "date": "04/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSarah, Daniel and Megan had a contest to see who could bike the most miles. Together Sarah and Daniel biked 21 miles. The combined total for Sarah and Megan was 19. Together Megan and Daniel rode 22 miles.\n\r\nWho was the winner?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDaniel is the winner.\n\r\nSarah = 9 miles\r\nMegan = 10 miles\r\nDaniel = 12 miles\n\r\nSet up three equations:\n\r\nS + D = 21\r\nS + M = 19\r\nM + D = 22\n\r\nand solve for S, M, and D.\n<|im_start|>answer\nDaniel is the winner.\n\r\nSarah = 9 miles\r\nMegan = 10 miles\r\nDaniel = 12 miles\n\r\nSet up three equations:\n\r\nS + D = 21\r\nS + M = 19\r\nM + D = 22\n\r\nand solve for S, M, and D.\n<|im_end|>" }, { "id": "#26504", "title": "My Maine Man", "fun": 2.65, "difficulty": 1.29, "author": "Rob2003", "desc": "Following the swimsuit round, the number of entrants in the Mr. Maine muscleman contest was whittled down to five finalists: Arnold, Curtis, Kent, Rocky, and Vaughn. Each hails from a different Maine city: Bangor, Lewiston, Old Town, Portland, and Skowhegan. For the final event, the weightlifting competition, each man lifted a different number of pounds: 315, 330, 345, 375, and 390. Only one winner will be treated to the traditional prize: an all-you-can-eat lobster dinner! Determine the city each finalist hails and the number of pounds each finalist lifted during the contest.\n\r\n1. Kent (who isn't the man from Lewiston) lifted the heaviest weight. The man from Bangor lifted the lightest weight.\n\r\n2. Arnold (who didn't lift 330 pounds) lifted exactly 15 pounds more than the man from Old Town. The man from Skowhegan lifted exactly 45 pounds more than Rocky.\n\r\n3. Curtis didn't lift 375 pounds.", "hint": "No hint available.", "answer": "Arnold: Lewiston, 345\r\nCurtis: Bangor, 315\r\nKent: Portland, 390\r\nRocky: Old Town, 330\r\nVaughn: Skowhegan, 375", "category": "Logic-Grid", "date": "10/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFollowing the swimsuit round, the number of entrants in the Mr. Maine muscleman contest was whittled down to five finalists: Arnold, Curtis, Kent, Rocky, and Vaughn. Each hails from a different Maine city: Bangor, Lewiston, Old Town, Portland, and Skowhegan. For the final event, the weightlifting competition, each man lifted a different number of pounds: 315, 330, 345, 375, and 390. Only one winner will be treated to the traditional prize: an all-you-can-eat lobster dinner! Determine the city each finalist hails and the number of pounds each finalist lifted during the contest.\n\r\n1. Kent (who isn't the man from Lewiston) lifted the heaviest weight. The man from Bangor lifted the lightest weight.\n\r\n2. Arnold (who didn't lift 330 pounds) lifted exactly 15 pounds more than the man from Old Town. The man from Skowhegan lifted exactly 45 pounds more than Rocky.\n\r\n3. Curtis didn't lift 375 pounds.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nArnold: Lewiston, 345\r\nCurtis: Bangor, 315\r\nKent: Portland, 390\r\nRocky: Old Town, 330\r\nVaughn: Skowhegan, 375\n<|im_start|>answer\nArnold: Lewiston, 345\r\nCurtis: Bangor, 315\r\nKent: Portland, 390\r\nRocky: Old Town, 330\r\nVaughn: Skowhegan, 375\n<|im_end|>" }, { "id": "#18213", "title": "Word Chain", "fun": 2.65, "difficulty": 2.7, "author": "bintot", "desc": "To solve this puzzle, take the last two letters of the first word described to make the first two letters of the second word, the last two letters of the second word to make the first two letters of the third word, and so on. The last two letters of the tenth word will make the first two letters of the first word and bring you back to where you started. Ready? \n\r\n1. To prevent by fear \r\n2. One of the muses \r\n3. Often on the breakfast table \r\n4. Steps for passing over a fence \r\n5. Lawful \r\n6. Solitary \r\n7. A musical Roman emperor \r\n8. A bird \r\n9. To bury \r\n10. To eat into", "hint": "No hint available.", "answer": "1. Deter\r\n2 Erato\r\n3. Toast\r\n4. Stile\r\n5. Legal\r\n6. Alone\r\n7. Nero\r\n8. Robin\r\n9. Inter\r\n10. Erode", "category": "Logic", "date": "07/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTo solve this puzzle, take the last two letters of the first word described to make the first two letters of the second word, the last two letters of the second word to make the first two letters of the third word, and so on. The last two letters of the tenth word will make the first two letters of the first word and bring you back to where you started. Ready? \n\r\n1. To prevent by fear \r\n2. One of the muses \r\n3. Often on the breakfast table \r\n4. Steps for passing over a fence \r\n5. Lawful \r\n6. Solitary \r\n7. A musical Roman emperor \r\n8. A bird \r\n9. To bury \r\n10. To eat into\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Deter\r\n2 Erato\r\n3. Toast\r\n4. Stile\r\n5. Legal\r\n6. Alone\r\n7. Nero\r\n8. Robin\r\n9. Inter\r\n10. Erode\n<|im_start|>answer\n1. Deter\r\n2 Erato\r\n3. Toast\r\n4. Stile\r\n5. Legal\r\n6. Alone\r\n7. Nero\r\n8. Robin\r\n9. Inter\r\n10. Erode\n<|im_end|>" }, { "id": "#45340", "title": "Paid to Promote", "fun": 2.65, "difficulty": 1.29, "author": "whsprec", "desc": "Five advertising agencies: Better Luck Next Time, Still Trying, Not My Fault, Trust Me, and Second Place recently secured contracts with 5 celebrities, each in a different field, to endorse their products. From the information below determine which agency booked whom, the field in which they are famous in, and the type of product each will be promoting.\n\r\n1) The rapper, who is neither Cameron nor Ashley, will be advertising hair spray; Ashley, who is not an actor, was booked by Trust Me.\r\n2) Not My Fault is not working with Kenny, or the one for shoes; the shoes ad doesn't star the model.\r\n3) Second Place is making the water ad.\r\n4) Better Luck Next Time has secured the services of the talk show host.\r\n5) Lou will be promoting clothes.\r\n6) Jenna is the soccer player.", "hint": "No hint available.", "answer": "Better Luck Next Time booked Cameron the host to promote shoes.\r\nStill Trying booked Kenny the rapper to promote hair spray.\r\nNot My Fault booked Lou the actor to promote clothes.\r\nTrust Me booked Ashley the model to promote perfume.\r\nSecond Place booked Jenna the soccer player to promote water.", "category": "Logic-Grid", "date": "09/22/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive advertising agencies: Better Luck Next Time, Still Trying, Not My Fault, Trust Me, and Second Place recently secured contracts with 5 celebrities, each in a different field, to endorse their products. From the information below determine which agency booked whom, the field in which they are famous in, and the type of product each will be promoting.\n\r\n1) The rapper, who is neither Cameron nor Ashley, will be advertising hair spray; Ashley, who is not an actor, was booked by Trust Me.\r\n2) Not My Fault is not working with Kenny, or the one for shoes; the shoes ad doesn't star the model.\r\n3) Second Place is making the water ad.\r\n4) Better Luck Next Time has secured the services of the talk show host.\r\n5) Lou will be promoting clothes.\r\n6) Jenna is the soccer player.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBetter Luck Next Time booked Cameron the host to promote shoes.\r\nStill Trying booked Kenny the rapper to promote hair spray.\r\nNot My Fault booked Lou the actor to promote clothes.\r\nTrust Me booked Ashley the model to promote perfume.\r\nSecond Place booked Jenna the soccer player to promote water.\n<|im_start|>answer\nBetter Luck Next Time booked Cameron the host to promote shoes.\r\nStill Trying booked Kenny the rapper to promote hair spray.\r\nNot My Fault booked Lou the actor to promote clothes.\r\nTrust Me booked Ashley the model to promote perfume.\r\nSecond Place booked Jenna the soccer player to promote water.\n<|im_end|>" }, { "id": "#28109", "title": "Beethoven's Wig II", "fun": 2.65, "difficulty": 2.36, "author": "beethovenswig", "desc": "Draw a diagram of the Fantasylands to help you with this teaser...\n\r\nBeethoven's Wig has been stolen again! Instead of hiding it in a box, the enemy, who remains anonymous, has hidden it inside one of four castles. Each castle is located in a different fantasyland and has a creature guarding its gates. Use the clues below to put the lands in order (1st,2nd,3rd, and 4th), figure out which castle belongs in which land, which creature belong to which castle, and help Beethoven reclaim his wig!\n\r\nObject: Beethoven's Wig\r\nFantasylands: Lothlorien, Mordor, Narnia, and Malacandra.\r\nCreatures: Dragon, Troll, Giant, and Balrog.\r\nCastles: Stone, Gold, Glass, and Silver.\n\r\n1. Narnia is to the left of Lothlorien, which is to the right of the Balrog.\r\n2. The Stone Castle is to the right of the Wig, and is placed at either Malacandra or Lothlorien.\r\n3. The Giant is not at Lothlorien and is not in the same place as the wig.\r\n4. The Balrog is not in Lothlorien, but he stays at the Stone Castle.\r\n5. The Troll doesn't live at the Golden Castle, which is to the left of where the Balrog stays and to the right of the Silver Castle.\r\n6. Mordor is to the left of the Dragon, who stays at the second place.\r\n7. The Troll is not at the Silver Castle, which is 1 fantasyland to the left of the wig.", "hint": "No hint available.", "answer": "Mordor is the first fantasyland. It contains the Giant and the Silver Castle.\r\nNarnia is the second land. It has the Dragon, the Golden Castle, and the Wig.\r\nMalacandra is the third land. It has the Stone Castle and the Balrog.\r\nLothlorien is the fourth land. It contains the Troll and the Glass Castle.", "category": "Logic", "date": "01/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDraw a diagram of the Fantasylands to help you with this teaser...\n\r\nBeethoven's Wig has been stolen again! Instead of hiding it in a box, the enemy, who remains anonymous, has hidden it inside one of four castles. Each castle is located in a different fantasyland and has a creature guarding its gates. Use the clues below to put the lands in order (1st,2nd,3rd, and 4th), figure out which castle belongs in which land, which creature belong to which castle, and help Beethoven reclaim his wig!\n\r\nObject: Beethoven's Wig\r\nFantasylands: Lothlorien, Mordor, Narnia, and Malacandra.\r\nCreatures: Dragon, Troll, Giant, and Balrog.\r\nCastles: Stone, Gold, Glass, and Silver.\n\r\n1. Narnia is to the left of Lothlorien, which is to the right of the Balrog.\r\n2. The Stone Castle is to the right of the Wig, and is placed at either Malacandra or Lothlorien.\r\n3. The Giant is not at Lothlorien and is not in the same place as the wig.\r\n4. The Balrog is not in Lothlorien, but he stays at the Stone Castle.\r\n5. The Troll doesn't live at the Golden Castle, which is to the left of where the Balrog stays and to the right of the Silver Castle.\r\n6. Mordor is to the left of the Dragon, who stays at the second place.\r\n7. The Troll is not at the Silver Castle, which is 1 fantasyland to the left of the wig.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMordor is the first fantasyland. It contains the Giant and the Silver Castle.\r\nNarnia is the second land. It has the Dragon, the Golden Castle, and the Wig.\r\nMalacandra is the third land. It has the Stone Castle and the Balrog.\r\nLothlorien is the fourth land. It contains the Troll and the Glass Castle.\n<|im_start|>answer\nMordor is the first fantasyland. It contains the Giant and the Silver Castle.\r\nNarnia is the second land. It has the Dragon, the Golden Castle, and the Wig.\r\nMalacandra is the third land. It has the Stone Castle and the Balrog.\r\nLothlorien is the fourth land. It contains the Troll and the Glass Castle.\n<|im_end|>" }, { "id": "#35845", "title": "At the Races", "fun": 2.65, "difficulty": 1.2, "author": "nascarfan19", "desc": "Austin finished 2 places in front of Jerry. Jerry finished 3 places behind Patrick. Patrick finished 1 place behind George. Mary finished 5 places behind George. Hannah finished 2 places in front of Mary. Daniel finished 4 places behind Hannah. Anna finished 1 place in front of Daniel. Jerry finished 5th. Who finished 1st?", "hint": "No hint available.", "answer": "George.\n\r\n1. George\r\n2. Patrick\r\n3. Austin\r\n4. Hannah\r\n5. Jerry\r\n6. Mary\r\n7. Anna\r\n8. Daniel", "category": "Logic", "date": "03/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAustin finished 2 places in front of Jerry. Jerry finished 3 places behind Patrick. Patrick finished 1 place behind George. Mary finished 5 places behind George. Hannah finished 2 places in front of Mary. Daniel finished 4 places behind Hannah. Anna finished 1 place in front of Daniel. Jerry finished 5th. Who finished 1st?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGeorge.\n\r\n1. George\r\n2. Patrick\r\n3. Austin\r\n4. Hannah\r\n5. Jerry\r\n6. Mary\r\n7. Anna\r\n8. Daniel\n<|im_start|>answer\nGeorge.\n\r\n1. George\r\n2. Patrick\r\n3. Austin\r\n4. Hannah\r\n5. Jerry\r\n6. Mary\r\n7. Anna\r\n8. Daniel\n<|im_end|>" }, { "id": "#26627", "title": "World Series 2", "fun": 2.65, "difficulty": 2.35, "author": "cnmne", "desc": "In Major League Baseball, the World Series is a best of seven series. The first team to win four games is the champion. The Series is scheduled so that one team hosts the first two games and the last two games, while the other team hosts the middle three games. The World Series ends as soon as one team wins four games, so the Series could be completed in as few as four games.\n\r\nIn this fantasy Series, the New York Yankees played the Los Angeles Dodgers. Los Angeles hosted the first two games. The final scores of the games were:\r\nGame 1: 4 to 3\r\nGame 2: 6 to 5 (11 innings)\r\nGame 3: 11 to 7\r\nGame 4: 16 to 9\r\nGame 5: 9 to 6 (10 innings)\r\nGame 6: 2 to 1\r\nGame 7: 13 to 8 (13 innings)\n\r\nWhich team won the World Series?", "hint": "No hint available.", "answer": "Seven games were played, which means that the teams split the first six games, each team winning three games. It does not matter who won each of the first six games, since neither team had yet to win four games. The winner of game 7 will have won four games, and therefore, the World Series.\n\r\nThe team that hosts the first two games also hosts the last two games. Since Los Angeles hosted the first two games, game 7 was in Los Angeles. In baseball, the home team bats last. Los Angeles batted last in game 7. Since game 7 went 13 innings, Los Angeles would have batted in the bottom of the inning. In this situation, the home team can never win by more than four runs. When the home team bats in the last inning, the game ends as soon as the winning run is scored. The only way the home team can win by more than one run is via a home run, in which case all runners on base at the time can score. A grand slam home run would only provide a margin of four runs. Therefore, the home team's margin of victory in an extra-inning game can never exceed four runs. The final score was 13 to 8, a margin of five runs. Los Angeles, being the home team, could not have won by that margin. The game was tied 8 to 8 going into the 13th inning. New York scored five runs in the top of the 13th inning.\n\r\nTherefore, the New York Yankees won the World Series, four games to three.", "category": "Logic", "date": "10/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Major League Baseball, the World Series is a best of seven series. The first team to win four games is the champion. The Series is scheduled so that one team hosts the first two games and the last two games, while the other team hosts the middle three games. The World Series ends as soon as one team wins four games, so the Series could be completed in as few as four games.\n\r\nIn this fantasy Series, the New York Yankees played the Los Angeles Dodgers. Los Angeles hosted the first two games. The final scores of the games were:\r\nGame 1: 4 to 3\r\nGame 2: 6 to 5 (11 innings)\r\nGame 3: 11 to 7\r\nGame 4: 16 to 9\r\nGame 5: 9 to 6 (10 innings)\r\nGame 6: 2 to 1\r\nGame 7: 13 to 8 (13 innings)\n\r\nWhich team won the World Series?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSeven games were played, which means that the teams split the first six games, each team winning three games. It does not matter who won each of the first six games, since neither team had yet to win four games. The winner of game 7 will have won four games, and therefore, the World Series.\n\r\nThe team that hosts the first two games also hosts the last two games. Since Los Angeles hosted the first two games, game 7 was in Los Angeles. In baseball, the home team bats last. Los Angeles batted last in game 7. Since game 7 went 13 innings, Los Angeles would have batted in the bottom of the inning. In this situation, the home team can never win by more than four runs. When the home team bats in the last inning, the game ends as soon as the winning run is scored. The only way the home team can win by more than one run is via a home run, in which case all runners on base at the time can score. A grand slam home run would only provide a margin of four runs. Therefore, the home team's margin of victory in an extra-inning game can never exceed four runs. The final score was 13 to 8, a margin of five runs. Los Angeles, being the home team, could not have won by that margin. The game was tied 8 to 8 going into the 13th inning. New York scored five runs in the top of the 13th inning.\n\r\nTherefore, the New York Yankees won the World Series, four games to three.\n<|im_start|>answer\nSeven games were played, which means that the teams split the first six games, each team winning three games. It does not matter who won each of the first six games, since neither team had yet to win four games. The winner of game 7 will have won four games, and therefore, the World Series.\n\r\nThe team that hosts the first two games also hosts the last two games. Since Los Angeles hosted the first two games, game 7 was in Los Angeles. In baseball, the home team bats last. Los Angeles batted last in game 7. Since game 7 went 13 innings, Los Angeles would have batted in the bottom of the inning. In this situation, the home team can never win by more than four runs. When the home team bats in the last inning, the game ends as soon as the winning run is scored. The only way the home team can win by more than one run is via a home run, in which case all runners on base at the time can score. A grand slam home run would only provide a margin of four runs. Therefore, the home team's margin of victory in an extra-inning game can never exceed four runs. The final score was 13 to 8, a margin of five runs. Los Angeles, being the home team, could not have won by that margin. The game was tied 8 to 8 going into the 13th inning. New York scored five runs in the top of the 13th inning.\n\r\nTherefore, the New York Yankees won the World Series, four games to three.\n<|im_end|>" }, { "id": "#44221", "title": "The Math Tutor", "fun": 2.65, "difficulty": 1.78, "author": "whsprec", "desc": "Nicole is a math tutor. Brandon, Lamar, Aaron, Colin, and Justin are the kids she tutors, and she tutors each of them on a different day after school. As it happens, no two children are in the same grade; they range from first to fifth grade. The mothers of the boys are Mrs. Bailey, Mrs. Burch, Mrs. Prescott, Mrs. Foster, and Mrs. Waters. From the clues given, try to determine each child's full name and grade as well as the day of the week on which he receives tutoring.\n\r\n1. Thursday's child is the oldest and Mrs. Burch's child is not the youngest.\r\n2. She tutors Mrs. Foster's son earlier in the week than Justin but later than she tutors the second grader.\r\n3. She doesn't tutor Brandon or Colin on Monday or Friday, but one of them is the first grader and the other is the third grader.\r\n4. She tutors Colin the day before Brandon but the day after the Bailey student.\r\n5. In no particular order, the three youngest students are the Monday student, the Tuesday student, and Mr. Burch's child.\r\n6. Mrs. Prescott's son Aaron is not the oldest nor is he the one tutored on Monday.", "hint": "No hint available.", "answer": "Monday: Lamar Bailey, second grade\r\nTuesday: Colin Foster, first grade\r\nWednesday: Brandon Burch, third grade\r\nThursday: Justin Waters, fifth grade\r\nFriday: Aaron Prescott, fourth grade", "category": "Logic-Grid", "date": "03/08/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNicole is a math tutor. Brandon, Lamar, Aaron, Colin, and Justin are the kids she tutors, and she tutors each of them on a different day after school. As it happens, no two children are in the same grade; they range from first to fifth grade. The mothers of the boys are Mrs. Bailey, Mrs. Burch, Mrs. Prescott, Mrs. Foster, and Mrs. Waters. From the clues given, try to determine each child's full name and grade as well as the day of the week on which he receives tutoring.\n\r\n1. Thursday's child is the oldest and Mrs. Burch's child is not the youngest.\r\n2. She tutors Mrs. Foster's son earlier in the week than Justin but later than she tutors the second grader.\r\n3. She doesn't tutor Brandon or Colin on Monday or Friday, but one of them is the first grader and the other is the third grader.\r\n4. She tutors Colin the day before Brandon but the day after the Bailey student.\r\n5. In no particular order, the three youngest students are the Monday student, the Tuesday student, and Mr. Burch's child.\r\n6. Mrs. Prescott's son Aaron is not the oldest nor is he the one tutored on Monday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday: Lamar Bailey, second grade\r\nTuesday: Colin Foster, first grade\r\nWednesday: Brandon Burch, third grade\r\nThursday: Justin Waters, fifth grade\r\nFriday: Aaron Prescott, fourth grade\n<|im_start|>answer\nMonday: Lamar Bailey, second grade\r\nTuesday: Colin Foster, first grade\r\nWednesday: Brandon Burch, third grade\r\nThursday: Justin Waters, fifth grade\r\nFriday: Aaron Prescott, fourth grade\n<|im_end|>" }, { "id": "#49956", "title": "Pass the Candy!", "fun": 2.65, "difficulty": 2.16, "author": "eighsse", "desc": "A group of 9 friends have a package of 40 W&W's chocolate candies to share. They each, one at a time, take a prime number of W&W's to eat. After that, the bag is empty. Exactly four of the friends took a number of W&W's that had previously been taken by someone else. Of the group, the number of people who took exactly 5 is twice the number of people who wear glasses.\r\nWithout any regard to the order in which they were taken, what individual quantities of W&W's were taken?", "hint": "Even though no information is given about how many people are wearing glasses, the last statement is actually completely relevant, and in fact crucial! What does it tell you about the number of people who took 5 pieces?", "answer": "Answer: 2, 2, 2, 3, 3, 5, 5, 7, 11\n\r\nThere is only one way that any number 13 or greater can be included: {2,2,2,3,3,3,5,7,13}. This would be a valid solution, but... We know that an even number of people must have taken 5 W&W's, because it is twice the number that wear glasses.\n\r\nThis leaves only 5 unique primes (2,3,5,7,11) that can be involved, and we know they all are used, because there must be exactly 5 different primes (from the fourth sentence in the teaser). And we know that 5 must be used an even number of times.\n\r\nSo, that gives us {2,3,5,5,7,11} requiring three more primes whose sum is 7. Obviously, the other three must be {2,2,3}.", "category": "Logic", "date": "09/27/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of 9 friends have a package of 40 W&W's chocolate candies to share. They each, one at a time, take a prime number of W&W's to eat. After that, the bag is empty. Exactly four of the friends took a number of W&W's that had previously been taken by someone else. Of the group, the number of people who took exactly 5 is twice the number of people who wear glasses.\r\nWithout any regard to the order in which they were taken, what individual quantities of W&W's were taken?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: 2, 2, 2, 3, 3, 5, 5, 7, 11\n\r\nThere is only one way that any number 13 or greater can be included: {2,2,2,3,3,3,5,7,13}. This would be a valid solution, but... We know that an even number of people must have taken 5 W&W's, because it is twice the number that wear glasses.\n\r\nThis leaves only 5 unique primes (2,3,5,7,11) that can be involved, and we know they all are used, because there must be exactly 5 different primes (from the fourth sentence in the teaser). And we know that 5 must be used an even number of times.\n\r\nSo, that gives us {2,3,5,5,7,11} requiring three more primes whose sum is 7. Obviously, the other three must be {2,2,3}.\n<|im_start|>answer\nAnswer: 2, 2, 2, 3, 3, 5, 5, 7, 11\n\r\nThere is only one way that any number 13 or greater can be included: {2,2,2,3,3,3,5,7,13}. This would be a valid solution, but... We know that an even number of people must have taken 5 W&W's, because it is twice the number that wear glasses.\n\r\nThis leaves only 5 unique primes (2,3,5,7,11) that can be involved, and we know they all are used, because there must be exactly 5 different primes (from the fourth sentence in the teaser). And we know that 5 must be used an even number of times.\n\r\nSo, that gives us {2,3,5,5,7,11} requiring three more primes whose sum is 7. Obviously, the other three must be {2,2,3}.\n<|im_end|>" }, { "id": "#36062", "title": "Summer Cottages", "fun": 2.65, "difficulty": 1.81, "author": "rubytuesday", "desc": "There are 5 cottages on one section of a beach called Beach View, Captain's Cottage, the Hideaway, the Nook, and Brookside. Can you figure which price and street number go with each house?\n\r\n1. Captain's Cottage is right between Beach View and the cottage that cost $12,500.\n\r\n2. Cottage #2 cost $2,500 more than the Hideaway, which isn't cottage #8.\n\r\n3. The owners of Cottage #10, known as the Nook, paid less for their cottage than their next-door neighbour.\n\r\n4. The cottage that cost $21,000 has a lower number than Brookside.", "hint": "No hint available.", "answer": "Beach View is cottage #2 and cost $15,000.\r\nCaptain's Cottage is #4 and cost $21,000.\r\nThe Hideaway is #6 and cost $12,500.\r\nThe Nook is #10 and cost $16,000.\r\nBrookside is #8 and cost $18,500.", "category": "Logic-Grid", "date": "04/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 5 cottages on one section of a beach called Beach View, Captain's Cottage, the Hideaway, the Nook, and Brookside. Can you figure which price and street number go with each house?\n\r\n1. Captain's Cottage is right between Beach View and the cottage that cost $12,500.\n\r\n2. Cottage #2 cost $2,500 more than the Hideaway, which isn't cottage #8.\n\r\n3. The owners of Cottage #10, known as the Nook, paid less for their cottage than their next-door neighbour.\n\r\n4. The cottage that cost $21,000 has a lower number than Brookside.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeach View is cottage #2 and cost $15,000.\r\nCaptain's Cottage is #4 and cost $21,000.\r\nThe Hideaway is #6 and cost $12,500.\r\nThe Nook is #10 and cost $16,000.\r\nBrookside is #8 and cost $18,500.\n<|im_start|>answer\nBeach View is cottage #2 and cost $15,000.\r\nCaptain's Cottage is #4 and cost $21,000.\r\nThe Hideaway is #6 and cost $12,500.\r\nThe Nook is #10 and cost $16,000.\r\nBrookside is #8 and cost $18,500.\n<|im_end|>" }, { "id": "#5277", "title": "Alphabet Blocks", "fun": 2.65, "difficulty": 2.66, "author": "Bobbrt", "desc": "You have four alphabet blocks. Each block has a different letter of the alphabet on each of its six sides. Using these four blocks, you can spell any of the following words. Can you figure out what six letters appear on each of the four blocks?\n\r\nBODY\r\nCRUX\r\nJACK\r\nJOHN\r\nKNOW\r\nLIFT\r\nMANX\r\nPUGS\r\nQUAD\r\nSHIM\r\nWRIT\r\nYELP", "hint": "No hint available.", "answer": "The first thing that you should notice is that all of the letters except V and Z appear. Therefore each letter appears only on one block. The letters M, A, N, and X must appear on four different blocks (so that you can spell \"MANX\"). Call them blocks 1, 2, 3, and 4, respectively. Block 2 (with the A) must have a letter from CRUX. It can't be C (because then you wouldn't be able to spell JACK) or U (so you can spell QUAD), so it is R. Block 2 must also have a letter from KNOW. It can't be K (JACK) or W (WRIT), so it's O. The letter H can't be on block 1 (SHIM) or block 2 or 3 (JOHN), so H is on block 4. J is on block 1 (JOHN). C can't be on block 1 or 2 (JACK) or block 4 (CRUX), so C is on block 3. U is on block 1 (CRUX), and K is on block 4 (JACK). W, then, is on block 1 (KNOW). I isn't on block 1 or 2 (WRIT), or block 4 (SHIM), so I is on block 3. T is on block 4 (WRIT) and S is on block 2 (SHIM). Block 4, which we already know has H, K, T, and X, can have only two more letters: it must have either D or Q (QUAD), and either G or P (PUGS). But block 4 must also have a letter from YELP, which can only be P, and a letter from BODY, which can only be D. G is on block 3 (PUGS), as is Q(QUAD). Block 3, which already has C, G, I, N, and Q, can only have one more letter: this sixth letter must be in both BODY and YELP, so it must be Y. B is on block 1 (BODY). Block 1, then, contains B, J, M, U, and W, and can have only one more letter: this sixth letter must be in both LIFT and YELP, so it must be L. Finally, block 2 holds E (YELP) and F (LIFT). In summary:\n\r\nBlock 1: B, J, L, M, U, W\r\nBlock 2: A, E, F, O, R, S\r\nBlock 3: C, G, I, N, Q, Y\r\nBlock 4: D, H, K, P, T, X", "category": "Logic", "date": "07/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have four alphabet blocks. Each block has a different letter of the alphabet on each of its six sides. Using these four blocks, you can spell any of the following words. Can you figure out what six letters appear on each of the four blocks?\n\r\nBODY\r\nCRUX\r\nJACK\r\nJOHN\r\nKNOW\r\nLIFT\r\nMANX\r\nPUGS\r\nQUAD\r\nSHIM\r\nWRIT\r\nYELP\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first thing that you should notice is that all of the letters except V and Z appear. Therefore each letter appears only on one block. The letters M, A, N, and X must appear on four different blocks (so that you can spell \"MANX\"). Call them blocks 1, 2, 3, and 4, respectively. Block 2 (with the A) must have a letter from CRUX. It can't be C (because then you wouldn't be able to spell JACK) or U (so you can spell QUAD), so it is R. Block 2 must also have a letter from KNOW. It can't be K (JACK) or W (WRIT), so it's O. The letter H can't be on block 1 (SHIM) or block 2 or 3 (JOHN), so H is on block 4. J is on block 1 (JOHN). C can't be on block 1 or 2 (JACK) or block 4 (CRUX), so C is on block 3. U is on block 1 (CRUX), and K is on block 4 (JACK). W, then, is on block 1 (KNOW). I isn't on block 1 or 2 (WRIT), or block 4 (SHIM), so I is on block 3. T is on block 4 (WRIT) and S is on block 2 (SHIM). Block 4, which we already know has H, K, T, and X, can have only two more letters: it must have either D or Q (QUAD), and either G or P (PUGS). But block 4 must also have a letter from YELP, which can only be P, and a letter from BODY, which can only be D. G is on block 3 (PUGS), as is Q(QUAD). Block 3, which already has C, G, I, N, and Q, can only have one more letter: this sixth letter must be in both BODY and YELP, so it must be Y. B is on block 1 (BODY). Block 1, then, contains B, J, M, U, and W, and can have only one more letter: this sixth letter must be in both LIFT and YELP, so it must be L. Finally, block 2 holds E (YELP) and F (LIFT). In summary:\n\r\nBlock 1: B, J, L, M, U, W\r\nBlock 2: A, E, F, O, R, S\r\nBlock 3: C, G, I, N, Q, Y\r\nBlock 4: D, H, K, P, T, X\n<|im_start|>answer\nThe first thing that you should notice is that all of the letters except V and Z appear. Therefore each letter appears only on one block. The letters M, A, N, and X must appear on four different blocks (so that you can spell \"MANX\"). Call them blocks 1, 2, 3, and 4, respectively. Block 2 (with the A) must have a letter from CRUX. It can't be C (because then you wouldn't be able to spell JACK) or U (so you can spell QUAD), so it is R. Block 2 must also have a letter from KNOW. It can't be K (JACK) or W (WRIT), so it's O. The letter H can't be on block 1 (SHIM) or block 2 or 3 (JOHN), so H is on block 4. J is on block 1 (JOHN). C can't be on block 1 or 2 (JACK) or block 4 (CRUX), so C is on block 3. U is on block 1 (CRUX), and K is on block 4 (JACK). W, then, is on block 1 (KNOW). I isn't on block 1 or 2 (WRIT), or block 4 (SHIM), so I is on block 3. T is on block 4 (WRIT) and S is on block 2 (SHIM). Block 4, which we already know has H, K, T, and X, can have only two more letters: it must have either D or Q (QUAD), and either G or P (PUGS). But block 4 must also have a letter from YELP, which can only be P, and a letter from BODY, which can only be D. G is on block 3 (PUGS), as is Q(QUAD). Block 3, which already has C, G, I, N, and Q, can only have one more letter: this sixth letter must be in both BODY and YELP, so it must be Y. B is on block 1 (BODY). Block 1, then, contains B, J, M, U, and W, and can have only one more letter: this sixth letter must be in both LIFT and YELP, so it must be L. Finally, block 2 holds E (YELP) and F (LIFT). In summary:\n\r\nBlock 1: B, J, L, M, U, W\r\nBlock 2: A, E, F, O, R, S\r\nBlock 3: C, G, I, N, Q, Y\r\nBlock 4: D, H, K, P, T, X\n<|im_end|>" }, { "id": "#29802", "title": "Iccanobif", "fun": 2.65, "difficulty": 2.39, "author": "tsimkin", "desc": "Henry had his head buried deep in his hands, fully frustrated by his math homework for the evening. Gretchen walked in to ask what was wrong, but before she got her question out, Henry launched into a tirade.\n\r\n\"It's completely unfair! How in the world could Mr. Simkin know what Fibonacci would have intended for the rest of his sequence?! Everything I find on-line says that the Fibonacci sequence starts with two 1's. Argh!\"\n\r\nGretchen had usually been able to help in situations like these, so she calmly asked her brother to explain.\n\r\nHe replied, \"Our new math teacher, Mr. Simkin, says that it is only a piece of the Fibonacci sequence we are looking at when it is written as 1, 1, 2, 3, 5, 8... Each number is the sum of the previous two, but he argues that the sequence should read ...1, 1, 2, 3, 5, 8... The only question we have for homework tonight is, what does 'a' equal in the following trail of numbers? ...a, b, c, d, 1, 1, 2, 3, 5, 8...\"\n\r\nA smile spread across Gretchen's face. \"You can do this,\" she reassured her brother, \"and I will be happy to help.\"\n\r\nWhat does 'a' equal in that sequence?", "hint": "Iccanobif is Fibonacci spelled backwards... It might help to work in that same direction...", "answer": "'a' equals 2.\n\r\nSince each number is the sum of the preceding two, d must equal 0, so that the second 1 will equal 0 plus 1. That means c has to equal 1, so that the first 1 would make sense. Therefore, b equals -1, making 0 the sum of the previous two numbers. So a must equal 2, leaving 1 as the sum of -1 and 2.\n\r\nAlternatively, you can look at the sequence as subtractions going from right to left:\r\n3 - 2 = 1\r\n2 - 1 = 1\r\n1 - 1 = 0\r\n1 - 0 = 1\r\n0 - 1 = -1\r\n1 - (-1) = 2", "category": "Math", "date": "04/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHenry had his head buried deep in his hands, fully frustrated by his math homework for the evening. Gretchen walked in to ask what was wrong, but before she got her question out, Henry launched into a tirade.\n\r\n\"It's completely unfair! How in the world could Mr. Simkin know what Fibonacci would have intended for the rest of his sequence?! Everything I find on-line says that the Fibonacci sequence starts with two 1's. Argh!\"\n\r\nGretchen had usually been able to help in situations like these, so she calmly asked her brother to explain.\n\r\nHe replied, \"Our new math teacher, Mr. Simkin, says that it is only a piece of the Fibonacci sequence we are looking at when it is written as 1, 1, 2, 3, 5, 8... Each number is the sum of the previous two, but he argues that the sequence should read ...1, 1, 2, 3, 5, 8... The only question we have for homework tonight is, what does 'a' equal in the following trail of numbers? ...a, b, c, d, 1, 1, 2, 3, 5, 8...\"\n\r\nA smile spread across Gretchen's face. \"You can do this,\" she reassured her brother, \"and I will be happy to help.\"\n\r\nWhat does 'a' equal in that sequence?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n'a' equals 2.\n\r\nSince each number is the sum of the preceding two, d must equal 0, so that the second 1 will equal 0 plus 1. That means c has to equal 1, so that the first 1 would make sense. Therefore, b equals -1, making 0 the sum of the previous two numbers. So a must equal 2, leaving 1 as the sum of -1 and 2.\n\r\nAlternatively, you can look at the sequence as subtractions going from right to left:\r\n3 - 2 = 1\r\n2 - 1 = 1\r\n1 - 1 = 0\r\n1 - 0 = 1\r\n0 - 1 = -1\r\n1 - (-1) = 2\n<|im_start|>answer\n'a' equals 2.\n\r\nSince each number is the sum of the preceding two, d must equal 0, so that the second 1 will equal 0 plus 1. That means c has to equal 1, so that the first 1 would make sense. Therefore, b equals -1, making 0 the sum of the previous two numbers. So a must equal 2, leaving 1 as the sum of -1 and 2.\n\r\nAlternatively, you can look at the sequence as subtractions going from right to left:\r\n3 - 2 = 1\r\n2 - 1 = 1\r\n1 - 1 = 0\r\n1 - 0 = 1\r\n0 - 1 = -1\r\n1 - (-1) = 2\n<|im_end|>" }, { "id": "#33724", "title": "Demise of the Scottish Kings", "fun": 2.65, "difficulty": 1.8, "author": "nick93", "desc": "Throughout the history of Scotland, various men aspired to the crown, only to meet an untimely death a short time later. Since everybody knew that the king wouldn't be around long enough to seek revenge, the kings tended to earn nicknames that were hardly flattering, to say the least.\n\r\nOne year, five different kings (Robert, Edward, James, William, and Thelred) assumed the throne for a period of months before joining their ancestors in the halls of dead royalty. One was attacked by dragons, one was executed by the English for \"political crimes\", one fell prey to a hunting accident, one was poisoned by a political enemy, and one died of the Bubonic Plague. In the short time they reigned, they earned such nicknames as the Unprepared, the Campaigner, the Brute, Pierce-Arrow, and the Inlaw.\n\r\nUsing the 7 clues provided, can you figure out which king held what nickname and how he met his demise?\n\n\r\n 1. The five kings were: Robert, James, the one known as \"the Campaigner\", the one killed in a hunting accident, and the one who died from the plague.\r\n 2. Thelred (who was not known as the Inlaw), Pierce-Arrow, and the king killed by dragons were all 3rd cousins.\r\n 3. Neither dragons nor the English killed Edward nor the Unprepared.\r\n 4. Pierce-Arrow was the only king to share an initial with his means of death.\r\n 5. Thelred was frightened as a youth by a wild boar. Consequently, he avoided the hunt at all costs.\r\n 6. Robert the Brute was not poisoned.\r\n 7. William's death held political reasons.", "hint": "No hint available.", "answer": "*Robert the Brute was killed by dragons\r\n*Edward the Inlaw was killed in a hunting accident\r\n*James Pierce-Arrow was poisoned\r\n*William the Campaigner was killed by the English\r\n*Thelred the Unprepared died of the plague", "category": "Logic-Grid", "date": "10/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThroughout the history of Scotland, various men aspired to the crown, only to meet an untimely death a short time later. Since everybody knew that the king wouldn't be around long enough to seek revenge, the kings tended to earn nicknames that were hardly flattering, to say the least.\n\r\nOne year, five different kings (Robert, Edward, James, William, and Thelred) assumed the throne for a period of months before joining their ancestors in the halls of dead royalty. One was attacked by dragons, one was executed by the English for \"political crimes\", one fell prey to a hunting accident, one was poisoned by a political enemy, and one died of the Bubonic Plague. In the short time they reigned, they earned such nicknames as the Unprepared, the Campaigner, the Brute, Pierce-Arrow, and the Inlaw.\n\r\nUsing the 7 clues provided, can you figure out which king held what nickname and how he met his demise?\n\n\r\n 1. The five kings were: Robert, James, the one known as \"the Campaigner\", the one killed in a hunting accident, and the one who died from the plague.\r\n 2. Thelred (who was not known as the Inlaw), Pierce-Arrow, and the king killed by dragons were all 3rd cousins.\r\n 3. Neither dragons nor the English killed Edward nor the Unprepared.\r\n 4. Pierce-Arrow was the only king to share an initial with his means of death.\r\n 5. Thelred was frightened as a youth by a wild boar. Consequently, he avoided the hunt at all costs.\r\n 6. Robert the Brute was not poisoned.\r\n 7. William's death held political reasons.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n*Robert the Brute was killed by dragons\r\n*Edward the Inlaw was killed in a hunting accident\r\n*James Pierce-Arrow was poisoned\r\n*William the Campaigner was killed by the English\r\n*Thelred the Unprepared died of the plague\n<|im_start|>answer\n*Robert the Brute was killed by dragons\r\n*Edward the Inlaw was killed in a hunting accident\r\n*James Pierce-Arrow was poisoned\r\n*William the Campaigner was killed by the English\r\n*Thelred the Unprepared died of the plague\n<|im_end|>" }, { "id": "#23165", "title": "Mr. Lockety's New Carpet", "fun": 2.65, "difficulty": 2.45, "author": "Palsha", "desc": "Four classrooms in Old Stewball School are getting new carpet, and Mr. Lockety is in charge. But, dashing to class, he lost all his requests. He's even forgotten what he needs in his own room! Which teacher gets which color, and how many square feet of carpet is needed for each? All room dimensions are exact to the foot.\n\r\n1) Room 168 is square.\r\n2) Mrs. Eddy does not like sage.\r\n3) Mr. Lockety's room is 27 feet long.\r\n4) One of the dimensions of the room getting navy is 25 feet.\r\n5) Mrs. Ebuley's room, 22 feet wide, will not have taupe carpet.\r\n6) Just two rooms, the taupe one and room 194, have one foot difference between length and width.\r\n7) Room 186 (not mauve) is 22 feet wide.\r\n8) Ms. Stalk isn't fond of taupe.", "hint": "No hint available.", "answer": "1) Mr. Lockety in Room 186 needs 594 sq. ft. of sage carpet.\r\n2) Mrs. Ebuley in Room 194 needs 506 sq. ft. of mauve carpet.\r\n3) Ms. Stalk in Room 168 needs 625 sq. ft. of navy carpet.\r\n4) Mrs. Eddy in Room 193 needs 552 sq. ft. of taupe carpet.", "category": "Logic-Grid", "date": "05/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour classrooms in Old Stewball School are getting new carpet, and Mr. Lockety is in charge. But, dashing to class, he lost all his requests. He's even forgotten what he needs in his own room! Which teacher gets which color, and how many square feet of carpet is needed for each? All room dimensions are exact to the foot.\n\r\n1) Room 168 is square.\r\n2) Mrs. Eddy does not like sage.\r\n3) Mr. Lockety's room is 27 feet long.\r\n4) One of the dimensions of the room getting navy is 25 feet.\r\n5) Mrs. Ebuley's room, 22 feet wide, will not have taupe carpet.\r\n6) Just two rooms, the taupe one and room 194, have one foot difference between length and width.\r\n7) Room 186 (not mauve) is 22 feet wide.\r\n8) Ms. Stalk isn't fond of taupe.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Mr. Lockety in Room 186 needs 594 sq. ft. of sage carpet.\r\n2) Mrs. Ebuley in Room 194 needs 506 sq. ft. of mauve carpet.\r\n3) Ms. Stalk in Room 168 needs 625 sq. ft. of navy carpet.\r\n4) Mrs. Eddy in Room 193 needs 552 sq. ft. of taupe carpet.\n<|im_start|>answer\n1) Mr. Lockety in Room 186 needs 594 sq. ft. of sage carpet.\r\n2) Mrs. Ebuley in Room 194 needs 506 sq. ft. of mauve carpet.\r\n3) Ms. Stalk in Room 168 needs 625 sq. ft. of navy carpet.\r\n4) Mrs. Eddy in Room 193 needs 552 sq. ft. of taupe carpet.\n<|im_end|>" }, { "id": "#665", "title": "Circular Track", "fun": 2.65, "difficulty": 1.65, "author": "vikass", "desc": "John is riding his bicycle along a circular track. It takes him 2 minutes and 13 seconds to complete one lap. Without any calculations and in less than 15 seconds, you should be able to tell me how long it takes John to complete 60 laps.", "hint": "No hint available.", "answer": "2 hours 13 minutes", "category": "Math", "date": "06/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn is riding his bicycle along a circular track. It takes him 2 minutes and 13 seconds to complete one lap. Without any calculations and in less than 15 seconds, you should be able to tell me how long it takes John to complete 60 laps.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 hours 13 minutes\n<|im_start|>answer\n2 hours 13 minutes\n<|im_end|>" }, { "id": "#4680", "title": "Smart Pawn", "fun": 2.65, "difficulty": 1.52, "author": "bobbrt", "desc": "Bill has only two dollars on him, but needs three dollars for the cab fare to get home. He comes up with an idea. He goes to a pawn shop and pawns his $2 for $1.50. He then finds Steve and sells him his $2 pawn ticket for $1.50. Since Bill ends up with the $3 he needs, who is out the extra dollar and why?", "hint": "No hint available.", "answer": "Steve is out the extra dollar. When he goes to the pawn shop to collect the $2, he will need to return the pawn ticket, plus the $1.50 that the pawn broker gave to Bill. He will then have paid $3 for two dollars.", "category": "Math", "date": "06/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBill has only two dollars on him, but needs three dollars for the cab fare to get home. He comes up with an idea. He goes to a pawn shop and pawns his $2 for $1.50. He then finds Steve and sells him his $2 pawn ticket for $1.50. Since Bill ends up with the $3 he needs, who is out the extra dollar and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSteve is out the extra dollar. When he goes to the pawn shop to collect the $2, he will need to return the pawn ticket, plus the $1.50 that the pawn broker gave to Bill. He will then have paid $3 for two dollars.\n<|im_start|>answer\nSteve is out the extra dollar. When he goes to the pawn shop to collect the $2, he will need to return the pawn ticket, plus the $1.50 that the pawn broker gave to Bill. He will then have paid $3 for two dollars.\n<|im_end|>" }, { "id": "#20152", "title": "I Wonder!", "fun": 2.65, "difficulty": 1.65, "author": "josbuc", "desc": "Find a four letter word that fits with the clues for the following puzzle. Avoid using names, words with repeated letters, or plurals of three letter words. The number in parentheses is the number of letters in the final answer. Use processes of elimination to figure this out. For example the letter T in tune is not one of the letters in the final answer so you should cross out any T's in the entire puzzle. Also (2) means that two of the letters are in the final answer. You will end up with four different letters after completing the upper part of the puzzle.\n\r\nTUNE (0)\n\r\nLAMB (0)\n\r\nDOWN (1)\n\r\nFOUR (1)\n\r\nCOLT (2)\n\r\nPRAY (2)\n\r\nFOIL (1)\r\n__________", "hint": "I suggest you write this down on a piece of paper and not try to solve this while looking at the computer monitor.", "answer": "Copy", "category": "Logic", "date": "12/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind a four letter word that fits with the clues for the following puzzle. Avoid using names, words with repeated letters, or plurals of three letter words. The number in parentheses is the number of letters in the final answer. Use processes of elimination to figure this out. For example the letter T in tune is not one of the letters in the final answer so you should cross out any T's in the entire puzzle. Also (2) means that two of the letters are in the final answer. You will end up with four different letters after completing the upper part of the puzzle.\n\r\nTUNE (0)\n\r\nLAMB (0)\n\r\nDOWN (1)\n\r\nFOUR (1)\n\r\nCOLT (2)\n\r\nPRAY (2)\n\r\nFOIL (1)\r\n__________\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCopy\n<|im_start|>answer\nCopy\n<|im_end|>" }, { "id": "#5080", "title": "Cricket Balls", "fun": 2.65, "difficulty": 1.55, "author": "Cascas", "desc": "Glenn and Jason each have a collection of cricket balls. Glenn said that if Jason would give him 4 of his balls they would have an equal number; but, if Glenn would give Jason 4 of his balls, Jason would have 2 times as many balls as Glenn. How many balls does Jason have?", "hint": "No hint available.", "answer": "Jason has 28 balls and Glenn has 20 balls.\n\r\nIf Jason would give Glenn 4 balls, they would have an equal number.\r\nThis implies that Jason has 8 balls more than Glenn.\n\r\nIf Jason has j balls, then Glenn has (j - 8) balls. \n\r\nIf Glenn would give Jason 4 balls, then Glenn would have (j - 12) balls and Jason would have (j + 4) balls.\r\nNow, Jason would have 2 times as many balls as Glenn.\r\nThis may be written in the form of the following equation.\n\r\nj + 4 = 2 (j - 12) \n\r\nThe equation may be solved as follows.\n\r\n1 j = 4 + 2 x 12 = 28; or\r\nj = 28 / 1 = 28.", "category": "Math", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGlenn and Jason each have a collection of cricket balls. Glenn said that if Jason would give him 4 of his balls they would have an equal number; but, if Glenn would give Jason 4 of his balls, Jason would have 2 times as many balls as Glenn. How many balls does Jason have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJason has 28 balls and Glenn has 20 balls.\n\r\nIf Jason would give Glenn 4 balls, they would have an equal number.\r\nThis implies that Jason has 8 balls more than Glenn.\n\r\nIf Jason has j balls, then Glenn has (j - 8) balls. \n\r\nIf Glenn would give Jason 4 balls, then Glenn would have (j - 12) balls and Jason would have (j + 4) balls.\r\nNow, Jason would have 2 times as many balls as Glenn.\r\nThis may be written in the form of the following equation.\n\r\nj + 4 = 2 (j - 12) \n\r\nThe equation may be solved as follows.\n\r\n1 j = 4 + 2 x 12 = 28; or\r\nj = 28 / 1 = 28.\n<|im_start|>answer\nJason has 28 balls and Glenn has 20 balls.\n\r\nIf Jason would give Glenn 4 balls, they would have an equal number.\r\nThis implies that Jason has 8 balls more than Glenn.\n\r\nIf Jason has j balls, then Glenn has (j - 8) balls. \n\r\nIf Glenn would give Jason 4 balls, then Glenn would have (j - 12) balls and Jason would have (j + 4) balls.\r\nNow, Jason would have 2 times as many balls as Glenn.\r\nThis may be written in the form of the following equation.\n\r\nj + 4 = 2 (j - 12) \n\r\nThe equation may be solved as follows.\n\r\n1 j = 4 + 2 x 12 = 28; or\r\nj = 28 / 1 = 28.\n<|im_end|>" }, { "id": "#4716", "title": "Difficult Order", "fun": 2.65, "difficulty": 1.9000000000000001, "author": "bobbrt", "desc": "Harry went out to dinner with his friends Larry, Barry, and Gary. Harry sat across from Gary. At Gary's right, opposite Barry, sat Larry. When the waiter came for their orders, Larry and Barry ordered steak. Gary chose fish, and Harry (who likes to be difficult) ordered like this: \"Unless the man at the left of the man opposite the man who ordered fish is not having what the man across from the man at the right of the man at my left is having, then I'll have what the man across from the man at the right of the man opposite me ordered. Otherwise, bring me the fettucine alfredo.\" Assuming \"right\" and \"left\" is from the viewpoint of the diners, what did Harry order?", "hint": "No hint available.", "answer": "Harry ordered the fettucine. What he essentially said to the waiter was: \"If Larry ordered the same thing as Gary, I'll have steak.\" Since Larry ordered steak and Gary ordered fish, Harry does not get steak.", "category": "Logic", "date": "06/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHarry went out to dinner with his friends Larry, Barry, and Gary. Harry sat across from Gary. At Gary's right, opposite Barry, sat Larry. When the waiter came for their orders, Larry and Barry ordered steak. Gary chose fish, and Harry (who likes to be difficult) ordered like this: \"Unless the man at the left of the man opposite the man who ordered fish is not having what the man across from the man at the right of the man at my left is having, then I'll have what the man across from the man at the right of the man opposite me ordered. Otherwise, bring me the fettucine alfredo.\" Assuming \"right\" and \"left\" is from the viewpoint of the diners, what did Harry order?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry ordered the fettucine. What he essentially said to the waiter was: \"If Larry ordered the same thing as Gary, I'll have steak.\" Since Larry ordered steak and Gary ordered fish, Harry does not get steak.\n<|im_start|>answer\nHarry ordered the fettucine. What he essentially said to the waiter was: \"If Larry ordered the same thing as Gary, I'll have steak.\" Since Larry ordered steak and Gary ordered fish, Harry does not get steak.\n<|im_end|>" }, { "id": "#24793", "title": "Group Values", "fun": 2.65, "difficulty": 2.67, "author": "WENZY675", "desc": "In each group each of the letters A through H has one of the eight values listed. No two letters have the same value. The simple arithmetic problems are clues for determining the values of each letter. The three groups are independent.\n\r\nGroup 1\r\n2,5,6,8,10,13,15,21\r\nH+D=G\r\nE-C=D\r\nH+G=A\r\nF+H=C\r\nE-F=G\r\nB+E=A\n\r\nGroup 2\r\n3,4,5,9,12,13,17,22\r\nC-A=B\r\nH+D=A\r\nD+F=G\r\nF-A=E\r\nC-D=G\n\r\nGroup 3\r\n4,5,6,10,11,14,15,20\r\nB-G=H\r\nA+E=C\r\nF-C=H\r\nD-B=A\r\nA+H=G\r\nE+F=D", "hint": "No hint available.", "answer": "1. A=21, B=6, C=10, D=5, E=15, F=2, G=13, H=8\r\n2. A=9, B=13, C=22, D=5, E=3, F=12, G=17, H=4\r\n3. A=6, B=14, C=11, D=20, E=5, F=15, G=10, H=4", "category": "Math", "date": "07/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn each group each of the letters A through H has one of the eight values listed. No two letters have the same value. The simple arithmetic problems are clues for determining the values of each letter. The three groups are independent.\n\r\nGroup 1\r\n2,5,6,8,10,13,15,21\r\nH+D=G\r\nE-C=D\r\nH+G=A\r\nF+H=C\r\nE-F=G\r\nB+E=A\n\r\nGroup 2\r\n3,4,5,9,12,13,17,22\r\nC-A=B\r\nH+D=A\r\nD+F=G\r\nF-A=E\r\nC-D=G\n\r\nGroup 3\r\n4,5,6,10,11,14,15,20\r\nB-G=H\r\nA+E=C\r\nF-C=H\r\nD-B=A\r\nA+H=G\r\nE+F=D\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. A=21, B=6, C=10, D=5, E=15, F=2, G=13, H=8\r\n2. A=9, B=13, C=22, D=5, E=3, F=12, G=17, H=4\r\n3. A=6, B=14, C=11, D=20, E=5, F=15, G=10, H=4\n<|im_start|>answer\n1. A=21, B=6, C=10, D=5, E=15, F=2, G=13, H=8\r\n2. A=9, B=13, C=22, D=5, E=3, F=12, G=17, H=4\r\n3. A=6, B=14, C=11, D=20, E=5, F=15, G=10, H=4\n<|im_end|>" }, { "id": "#28636", "title": "Valentines", "fun": 2.65, "difficulty": 1.82, "author": "thepianistalex", "desc": "Every student in a second grade class sends a valentine to each of the other students in the class, for a total of 306 valentines. How many students are in the class?", "hint": "No hint available.", "answer": "18 students", "category": "Math", "date": "02/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery student in a second grade class sends a valentine to each of the other students in the class, for a total of 306 valentines. How many students are in the class?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n18 students\n<|im_start|>answer\n18 students\n<|im_end|>" }, { "id": "#28559", "title": "Cruisin'", "fun": 2.65, "difficulty": 1.92, "author": "Nytwynd", "desc": "On a riverside town, four vacationing families tied their cabin cruisers near various riverside pubs.\n\r\nFrom the clues given, can you give the name of the families, the names of their boats, the pubs their boats are tied to, and the position of the pubs?\n\r\n(Note, the pubs are in a row, and numbered 1-4 from upriver to downriver.)\n\r\nClues:\n\r\n1. The Marches' boat is tied near the Triomph, which is farther downstream than the pub where the Helmsway is tied.\n\r\n2. The cabin cruiser Kestrel is alongside the jetty at the Cat's Eye.\n\r\n3. The 3rd pub is called the Blue Moon; the boat tied up there, which is not the Smithon family's vessel, is not the Rivet.\n\r\n4. The boat farthest downstream belongs to the Byre family.", "hint": "No hint available.", "answer": "1st Pub, Smithon, Helmsway, Hook & Line\r\n2nd Pub, Marches, Rivet, Triomph\r\n3rd Pub, McKay, Vision, Blue Moon\r\n4th Pub, Byre, Kestrel, Cat's Eye", "category": "Logic-Grid", "date": "02/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a riverside town, four vacationing families tied their cabin cruisers near various riverside pubs.\n\r\nFrom the clues given, can you give the name of the families, the names of their boats, the pubs their boats are tied to, and the position of the pubs?\n\r\n(Note, the pubs are in a row, and numbered 1-4 from upriver to downriver.)\n\r\nClues:\n\r\n1. The Marches' boat is tied near the Triomph, which is farther downstream than the pub where the Helmsway is tied.\n\r\n2. The cabin cruiser Kestrel is alongside the jetty at the Cat's Eye.\n\r\n3. The 3rd pub is called the Blue Moon; the boat tied up there, which is not the Smithon family's vessel, is not the Rivet.\n\r\n4. The boat farthest downstream belongs to the Byre family.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st Pub, Smithon, Helmsway, Hook & Line\r\n2nd Pub, Marches, Rivet, Triomph\r\n3rd Pub, McKay, Vision, Blue Moon\r\n4th Pub, Byre, Kestrel, Cat's Eye\n<|im_start|>answer\n1st Pub, Smithon, Helmsway, Hook & Line\r\n2nd Pub, Marches, Rivet, Triomph\r\n3rd Pub, McKay, Vision, Blue Moon\r\n4th Pub, Byre, Kestrel, Cat's Eye\n<|im_end|>" }, { "id": "#30677", "title": "Squared Numbers", "fun": 2.65, "difficulty": 2.23, "author": "cdrock", "desc": "Imagine a 3x3 grid, the rows being 1, 2, 3, and the columns being A, B, and C.\n\r\nUsing the clues below, can you place the numbers 1-9 in the grid?\n\r\nClues:\n\r\n1. Row 1 is made up of odd numbers.\n\r\n2. The sum of Column C, is twice the sum of Row 1.\n\r\n3. Row 2's sum is 24.\n\r\n4. The number in square C3 is not 4.\n\r\n5. The sum of Column A is 11.", "hint": "No hint available.", "answer": "1...3...5\r\n8...9...7\r\n2...4...6", "category": "Logic", "date": "05/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImagine a 3x3 grid, the rows being 1, 2, 3, and the columns being A, B, and C.\n\r\nUsing the clues below, can you place the numbers 1-9 in the grid?\n\r\nClues:\n\r\n1. Row 1 is made up of odd numbers.\n\r\n2. The sum of Column C, is twice the sum of Row 1.\n\r\n3. Row 2's sum is 24.\n\r\n4. The number in square C3 is not 4.\n\r\n5. The sum of Column A is 11.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1...3...5\r\n8...9...7\r\n2...4...6\n<|im_start|>answer\n1...3...5\r\n8...9...7\r\n2...4...6\n<|im_end|>" }, { "id": "#25481", "title": "Babysitting Nightmare", "fun": 2.65, "difficulty": 1.03, "author": "Nighttiger25", "desc": "The parents of 5 boys went out for the night to celebrate their anniversary, and left their kids with a new babysitter. Unfortunately for the babysitter, the boys were feeling particularly restless that night, and decided to pull out their instruments and start playing. However, they all played a different tune and were making horrible noise instead of sweet music. The babysitter asked them to stop and they made a deal with her. If she can figure out the name of each boy, the instrument they are playing, and the color of their shirt, they will sit down and watch television. Can you help the babysitter figure it out before she pulls her hair out?\n\r\nBoys Names: Roger, Ogden, Perry, Brent, Willie\r\nShirt Colors: white, green, purple, red, blue\r\nInstrument: flute, drums, violin, guitar, bass\n\r\nClues:\n\r\n1) The five boys are: Willie, the one playing the drums, the one wearing a blue shirt and playing the flute, the person wearing white, and Roger.\n\r\n2) Ogden and Brent are wearing primary colors.\n\r\n3) Perry has to be careful not to get his bow rosin on his white shirt.\n\r\n4) At one point, Brent gets sick of hearing the boy in purple playing the bass, and throws one of his drumsticks at the boy.\n\r\n5) Although purple wasn't Roger's first choice, it was the only shirt that smelled clean that morning.", "hint": "No hint available.", "answer": "Brent - red - drums\r\nOgden - blue - flute\r\nPerry - white - violin\r\nRoger - purple - bass\r\nWillie - green - guitar", "category": "Logic-Grid", "date": "08/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe parents of 5 boys went out for the night to celebrate their anniversary, and left their kids with a new babysitter. Unfortunately for the babysitter, the boys were feeling particularly restless that night, and decided to pull out their instruments and start playing. However, they all played a different tune and were making horrible noise instead of sweet music. The babysitter asked them to stop and they made a deal with her. If she can figure out the name of each boy, the instrument they are playing, and the color of their shirt, they will sit down and watch television. Can you help the babysitter figure it out before she pulls her hair out?\n\r\nBoys Names: Roger, Ogden, Perry, Brent, Willie\r\nShirt Colors: white, green, purple, red, blue\r\nInstrument: flute, drums, violin, guitar, bass\n\r\nClues:\n\r\n1) The five boys are: Willie, the one playing the drums, the one wearing a blue shirt and playing the flute, the person wearing white, and Roger.\n\r\n2) Ogden and Brent are wearing primary colors.\n\r\n3) Perry has to be careful not to get his bow rosin on his white shirt.\n\r\n4) At one point, Brent gets sick of hearing the boy in purple playing the bass, and throws one of his drumsticks at the boy.\n\r\n5) Although purple wasn't Roger's first choice, it was the only shirt that smelled clean that morning.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrent - red - drums\r\nOgden - blue - flute\r\nPerry - white - violin\r\nRoger - purple - bass\r\nWillie - green - guitar\n<|im_start|>answer\nBrent - red - drums\r\nOgden - blue - flute\r\nPerry - white - violin\r\nRoger - purple - bass\r\nWillie - green - guitar\n<|im_end|>" }, { "id": "#11908", "title": " 5-digit Numbers", "fun": 2.65, "difficulty": 2.65, "author": "Mhalun", "desc": "How many 5-digit numbers are there that do not contain the numbers 3 and 5, and are multiples of 4?\r\n(It cannot start with 0, ie. 01234 is not a 5 digit number)", "hint": "Permutations", "answer": "9408!\r\nThe rule of divisibility says that a number is a multiple of 4 if its last 2 numbers are multiples of 4. So the last 2 numbers can be 21 different options:00, 04, 08, 12, 16, 20, 24, 28, 40, 44, 48, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 because they are multiples of 4 and do not have 3's or 5's.\r\nWe have the last 2 digits we need to know how many can be in the first digit: 1, 2, 4, 6, 7, 8, 9 and the second and third numbers can have these 7 and number 0 too.\n\r\nBy using permutations we give the possible numbers in each digit and the last 2 digits together.\r\n1st*2nd*3rd*(4th and 5th)=?\r\n7x8x8x21=9408", "category": "Math", "date": "Unknown", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many 5-digit numbers are there that do not contain the numbers 3 and 5, and are multiples of 4?\r\n(It cannot start with 0, ie. 01234 is not a 5 digit number)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9408!\r\nThe rule of divisibility says that a number is a multiple of 4 if its last 2 numbers are multiples of 4. So the last 2 numbers can be 21 different options:00, 04, 08, 12, 16, 20, 24, 28, 40, 44, 48, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 because they are multiples of 4 and do not have 3's or 5's.\r\nWe have the last 2 digits we need to know how many can be in the first digit: 1, 2, 4, 6, 7, 8, 9 and the second and third numbers can have these 7 and number 0 too.\n\r\nBy using permutations we give the possible numbers in each digit and the last 2 digits together.\r\n1st*2nd*3rd*(4th and 5th)=?\r\n7x8x8x21=9408\n<|im_start|>answer\n9408!\r\nThe rule of divisibility says that a number is a multiple of 4 if its last 2 numbers are multiples of 4. So the last 2 numbers can be 21 different options:00, 04, 08, 12, 16, 20, 24, 28, 40, 44, 48, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 because they are multiples of 4 and do not have 3's or 5's.\r\nWe have the last 2 digits we need to know how many can be in the first digit: 1, 2, 4, 6, 7, 8, 9 and the second and third numbers can have these 7 and number 0 too.\n\r\nBy using permutations we give the possible numbers in each digit and the last 2 digits together.\r\n1st*2nd*3rd*(4th and 5th)=?\r\n7x8x8x21=9408\n<|im_end|>" }, { "id": "#3673", "title": "Choosing a Builder", "fun": 2.65, "difficulty": 1.87, "author": "PeaceJo", "desc": "A newlywed couple were planning their dream home. They wanted to hire the best contractor, so they solicited tenders from over a hundred contractors. In turn, each presented their qualifications & experience and claimed to be the best. The couple came up with an ingenious idea to figure out who was truly the best. What was it?", "hint": "No hint available.", "answer": "They asked each contractor to nominate an alternate in case they couldn't take on the contract. They then hired the contractor who had received the most nominations.", "category": "Logic", "date": "04/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA newlywed couple were planning their dream home. They wanted to hire the best contractor, so they solicited tenders from over a hundred contractors. In turn, each presented their qualifications & experience and claimed to be the best. The couple came up with an ingenious idea to figure out who was truly the best. What was it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey asked each contractor to nominate an alternate in case they couldn't take on the contract. They then hired the contractor who had received the most nominations.\n<|im_start|>answer\nThey asked each contractor to nominate an alternate in case they couldn't take on the contract. They then hired the contractor who had received the most nominations.\n<|im_end|>" }, { "id": "#30686", "title": "Four Equations", "fun": 2.65, "difficulty": 2.29, "author": "phrebh", "desc": "Checkers, the smartest dog in the world, was doodling in his math diary and come up with three equations:\n\r\nA-B=C\r\nD/E=F\r\nG+H=I\n\r\nHe was about to write a fourth equation using multiplication when an interesting thought occurred to him. Instead of using a new set of numbers (J, K, L) for his fourth equation, he would use the answers of the three existing equations:\n\r\nC*F=I\n\r\nNow the only question in his mind was, \"Can I replace the letters A through I with the digits 1 through 9 in such a way that all four of my equations are correct?\"", "hint": "No hint available.", "answer": "Without too much thought or fanfare, and realizing that slight variations could occur, Checkers wrote the four equations using the digits 1 through 9:\n\r\n9-5=4\r\n6/3=2\r\n1+7=8\r\n4*2=8", "category": "Math", "date": "05/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCheckers, the smartest dog in the world, was doodling in his math diary and come up with three equations:\n\r\nA-B=C\r\nD/E=F\r\nG+H=I\n\r\nHe was about to write a fourth equation using multiplication when an interesting thought occurred to him. Instead of using a new set of numbers (J, K, L) for his fourth equation, he would use the answers of the three existing equations:\n\r\nC*F=I\n\r\nNow the only question in his mind was, \"Can I replace the letters A through I with the digits 1 through 9 in such a way that all four of my equations are correct?\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWithout too much thought or fanfare, and realizing that slight variations could occur, Checkers wrote the four equations using the digits 1 through 9:\n\r\n9-5=4\r\n6/3=2\r\n1+7=8\r\n4*2=8\n<|im_start|>answer\nWithout too much thought or fanfare, and realizing that slight variations could occur, Checkers wrote the four equations using the digits 1 through 9:\n\r\n9-5=4\r\n6/3=2\r\n1+7=8\r\n4*2=8\n<|im_end|>" }, { "id": "#26501", "title": "Knight's Tour", "fun": 2.65, "difficulty": 2.39, "author": "kiss", "desc": "One day, a knight went to the legendary kingdom named Breadland. The Breadlanders love eating bread. They also play chess. What's different from normal chess is that the chessboard they use is 9x7, each player has a queen on each side of the king, one is next to the king and the other is between a bishop and a knight. Also, each side has one more pawn, so that there are totally 4 queens and 18 pawns on the chessboard. In fact, Breadland is a chessboard itself, and is of course 9x7.\n\r\n The knight was on a square of Breadland, he wanted to visit each square of Breadland exactly once, and return to the square he was originally on. Each step, the knight moved to one of the squares nearest to that on which it stands but the queen can't reach.\n\r\n Could the knight achieve his goal?", "hint": "No hint available.", "answer": "Color the chess board alternatively black and white, and suppose the lower left corner is black, as in normal chess. Then each move of the knight brought him from a black square to a white one, or vice versa. If he could achieve his goal, there must have been as many black squares as white ones. However, there were 32 black squares and 31 white squares. Hence, the knight could not achieve his goal, and had to repeat some white square.", "category": "Math", "date": "10/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, a knight went to the legendary kingdom named Breadland. The Breadlanders love eating bread. They also play chess. What's different from normal chess is that the chessboard they use is 9x7, each player has a queen on each side of the king, one is next to the king and the other is between a bishop and a knight. Also, each side has one more pawn, so that there are totally 4 queens and 18 pawns on the chessboard. In fact, Breadland is a chessboard itself, and is of course 9x7.\n\r\n The knight was on a square of Breadland, he wanted to visit each square of Breadland exactly once, and return to the square he was originally on. Each step, the knight moved to one of the squares nearest to that on which it stands but the queen can't reach.\n\r\n Could the knight achieve his goal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nColor the chess board alternatively black and white, and suppose the lower left corner is black, as in normal chess. Then each move of the knight brought him from a black square to a white one, or vice versa. If he could achieve his goal, there must have been as many black squares as white ones. However, there were 32 black squares and 31 white squares. Hence, the knight could not achieve his goal, and had to repeat some white square.\n<|im_start|>answer\nColor the chess board alternatively black and white, and suppose the lower left corner is black, as in normal chess. Then each move of the knight brought him from a black square to a white one, or vice versa. If he could achieve his goal, there must have been as many black squares as white ones. However, there were 32 black squares and 31 white squares. Hence, the knight could not achieve his goal, and had to repeat some white square.\n<|im_end|>" }, { "id": "#45793", "title": "School Fundraiser", "fun": 2.65, "difficulty": 1.7, "author": "whsprec", "desc": "Every year the local high school holds an annual fundraiser. Each school department has one booth to help raise money. The same people, who all happen to be women, have been running the booths for some time now. From the clues below determine who is running what booth, which department they are raising money for, and what year they started.\n\r\n1- The lady who raises money for the band has done so at every fundraiser since 1999.\r\n2- Mrs. Ware, who runs the booth for the math department, began taking part six years later than the lady who runs the knock the pins booth.\r\n3- It was 2002 when Mrs. Staton made her first appearance at the fundraiser.\r\n4- The raffle booth raises money for the History Department.\r\n5- Neither Mrs. Dixon nor the lady who raises funds for Drama runs a booth that involves throwing things.\r\n6-The pie-the-teacher booth has been a constant feature at the fundraiser since 1996, at least three years before Mrs. Blair began helping at the event.", "hint": "No hint available.", "answer": "Mrs. Ware started running the teacher-dunking booth in 2005 to help the Math Department.\r\nMrs. Keyes started running the pie-the-teacher booth in 1996 the help English Department.\r\nMrs. Dixon started running the raffle booth in 1993 to help the History Department.\r\nMrs. Blair started running the knock the pins booth in 1999 to help the band.\r\nMrs. Staton started running the bake sale in 2002 to help Drama.", "category": "Logic-Grid", "date": "11/23/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery year the local high school holds an annual fundraiser. Each school department has one booth to help raise money. The same people, who all happen to be women, have been running the booths for some time now. From the clues below determine who is running what booth, which department they are raising money for, and what year they started.\n\r\n1- The lady who raises money for the band has done so at every fundraiser since 1999.\r\n2- Mrs. Ware, who runs the booth for the math department, began taking part six years later than the lady who runs the knock the pins booth.\r\n3- It was 2002 when Mrs. Staton made her first appearance at the fundraiser.\r\n4- The raffle booth raises money for the History Department.\r\n5- Neither Mrs. Dixon nor the lady who raises funds for Drama runs a booth that involves throwing things.\r\n6-The pie-the-teacher booth has been a constant feature at the fundraiser since 1996, at least three years before Mrs. Blair began helping at the event.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMrs. Ware started running the teacher-dunking booth in 2005 to help the Math Department.\r\nMrs. Keyes started running the pie-the-teacher booth in 1996 the help English Department.\r\nMrs. Dixon started running the raffle booth in 1993 to help the History Department.\r\nMrs. Blair started running the knock the pins booth in 1999 to help the band.\r\nMrs. Staton started running the bake sale in 2002 to help Drama.\n<|im_start|>answer\nMrs. Ware started running the teacher-dunking booth in 2005 to help the Math Department.\r\nMrs. Keyes started running the pie-the-teacher booth in 1996 the help English Department.\r\nMrs. Dixon started running the raffle booth in 1993 to help the History Department.\r\nMrs. Blair started running the knock the pins booth in 1999 to help the band.\r\nMrs. Staton started running the bake sale in 2002 to help Drama.\n<|im_end|>" }, { "id": "#51399", "title": "Commuter Problems", "fun": 2.65, "difficulty": 1.05, "author": "danielj2", "desc": "Five friends (Men: Larry, Harry, and Jerry; Women: Carrie and Mary) each had trouble getting to work one day. Identify which friend used which mode of transport, and the corresponding reason they were late to work.\n\r\nFRIENDS: Larry, Carrie, Harry, Mary, and Jerry. \r\nMODES OF TRANSPORT: Car, Motorcycle, Bus, Bike, Walk\r\nREASONS: Construction, Flat tire, Accident, Storm, Traffic signal\n\r\nCLUES:\r\n1. Neither of the women took public transportation.\r\n2. Mary is still fuming over that faulty traffic signal.\r\n3. The rider on two wheels (who wasn't Carrie) decided to wait out the storm.\r\n4. Harry passed Carrie (who wasn't affected by construction or the storm) on his way to work. She later caught up to him because he forgot to pack his air pump.\r\n5. Jerry hoped to bypass other vehicles on the road by letting someone else drive, but the construction delays were too much.\r\n6. Larry and Mary worked too far away to walk to work and were glad they had full tanks of gas.\r\n7. The walker was an eyewitness to an accident and had to wait around to give a statement to police.", "hint": "No hint available.", "answer": "Larry - Motorcycle - Storm\r\nCarrie - Walk - Accident\r\nHarry - Bike - Flat tire\r\nMary - Car - Traffic signal\r\nJerry - Bus - Construction", "category": "Logic-Grid", "date": "08/17/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends (Men: Larry, Harry, and Jerry; Women: Carrie and Mary) each had trouble getting to work one day. Identify which friend used which mode of transport, and the corresponding reason they were late to work.\n\r\nFRIENDS: Larry, Carrie, Harry, Mary, and Jerry. \r\nMODES OF TRANSPORT: Car, Motorcycle, Bus, Bike, Walk\r\nREASONS: Construction, Flat tire, Accident, Storm, Traffic signal\n\r\nCLUES:\r\n1. Neither of the women took public transportation.\r\n2. Mary is still fuming over that faulty traffic signal.\r\n3. The rider on two wheels (who wasn't Carrie) decided to wait out the storm.\r\n4. Harry passed Carrie (who wasn't affected by construction or the storm) on his way to work. She later caught up to him because he forgot to pack his air pump.\r\n5. Jerry hoped to bypass other vehicles on the road by letting someone else drive, but the construction delays were too much.\r\n6. Larry and Mary worked too far away to walk to work and were glad they had full tanks of gas.\r\n7. The walker was an eyewitness to an accident and had to wait around to give a statement to police.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLarry - Motorcycle - Storm\r\nCarrie - Walk - Accident\r\nHarry - Bike - Flat tire\r\nMary - Car - Traffic signal\r\nJerry - Bus - Construction\n<|im_start|>answer\nLarry - Motorcycle - Storm\r\nCarrie - Walk - Accident\r\nHarry - Bike - Flat tire\r\nMary - Car - Traffic signal\r\nJerry - Bus - Construction\n<|im_end|>" }, { "id": "#44399", "title": "Valentine's Day Anniversaries", "fun": 2.65, "difficulty": 1.47, "author": "whsprec", "desc": "At a church retreat, five couples found out that they all had been married on Valentines Day, but none of them had been married the same number of years. Their last names were Dail, Moore, Doyle, Burton, and Henke. The husbands' names were Todd, Chris, Charles, Peter, and Dale. The wives' names were Elaine, Chelsea, Marcia, Stephanie, and Rebecca. From the clues given, determine the husband and wife that make up each couple and the number of years they have been married.\n\r\n1) Chelsea has not been married as long as Charles and the Moores but longer than Chris and the Dails.\r\n2) Stephanie has been married twice as long as the Doyles but only half as long as Todd.\r\n3) The Henkes have been ten years longer than Peter and ten years less than Marcia.\r\n4) Chris and Rebecca have been married for 25 years less than the Burtons, who have been married the longest.\r\n5) Neither Elaine nor the Dails have been married the shortest amount of time.\r\n6) Dale has been married for 25 years.", "hint": "No hint available.", "answer": "Chris and Rebecca Doyle have been married 5 years.\r\nPeter and Stephanie Dail have been married 10 years.\r\nTodd and Chelsea Henke have been married 20 years.\r\nDale and Elaine Moore have been married 25 years.\r\nCharles and Marcia Burton have been married 30 years.", "category": "Logic-Grid", "date": "04/29/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a church retreat, five couples found out that they all had been married on Valentines Day, but none of them had been married the same number of years. Their last names were Dail, Moore, Doyle, Burton, and Henke. The husbands' names were Todd, Chris, Charles, Peter, and Dale. The wives' names were Elaine, Chelsea, Marcia, Stephanie, and Rebecca. From the clues given, determine the husband and wife that make up each couple and the number of years they have been married.\n\r\n1) Chelsea has not been married as long as Charles and the Moores but longer than Chris and the Dails.\r\n2) Stephanie has been married twice as long as the Doyles but only half as long as Todd.\r\n3) The Henkes have been ten years longer than Peter and ten years less than Marcia.\r\n4) Chris and Rebecca have been married for 25 years less than the Burtons, who have been married the longest.\r\n5) Neither Elaine nor the Dails have been married the shortest amount of time.\r\n6) Dale has been married for 25 years.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChris and Rebecca Doyle have been married 5 years.\r\nPeter and Stephanie Dail have been married 10 years.\r\nTodd and Chelsea Henke have been married 20 years.\r\nDale and Elaine Moore have been married 25 years.\r\nCharles and Marcia Burton have been married 30 years.\n<|im_start|>answer\nChris and Rebecca Doyle have been married 5 years.\r\nPeter and Stephanie Dail have been married 10 years.\r\nTodd and Chelsea Henke have been married 20 years.\r\nDale and Elaine Moore have been married 25 years.\r\nCharles and Marcia Burton have been married 30 years.\n<|im_end|>" }, { "id": "#43220", "title": "Never Ask a Woman Her Age", "fun": 2.65, "difficulty": 1.06, "author": "whsprec", "desc": "Jennifer, Shannon, Jessica, Kate, and Janice, whose last names are Peterson, Smith, Malone, Ware, and Lewis, all go to the same exercise gym. From the clues below, try to determine the first and last name of each woman and her age. Their ages are 80, 60, 50, 40, and 20.\n\r\n1) Jennifer's name is not Malone.\r\n2) Kate is twice as old as Lewis, but only half as old as Shannon.\r\n3) Jessica is 10 years older than Mrs. Smith, but 10 years younger than Mrs. Peterson.\r\n4) Janice is 20 years older than Kate and 20 years younger than Mrs. Ware.\r\n5) Kate is 10 years younger than Jessica but 20 years older than Jennifer.", "hint": "No hint available.", "answer": "Shannon Ware is 80.\r\nJanice Peterson is 60.\r\nJessica Malone is 50.\r\nKate Smith is 40.\r\nJennifer Lewis is 20.", "category": "Logic-Grid", "date": "09/30/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJennifer, Shannon, Jessica, Kate, and Janice, whose last names are Peterson, Smith, Malone, Ware, and Lewis, all go to the same exercise gym. From the clues below, try to determine the first and last name of each woman and her age. Their ages are 80, 60, 50, 40, and 20.\n\r\n1) Jennifer's name is not Malone.\r\n2) Kate is twice as old as Lewis, but only half as old as Shannon.\r\n3) Jessica is 10 years older than Mrs. Smith, but 10 years younger than Mrs. Peterson.\r\n4) Janice is 20 years older than Kate and 20 years younger than Mrs. Ware.\r\n5) Kate is 10 years younger than Jessica but 20 years older than Jennifer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShannon Ware is 80.\r\nJanice Peterson is 60.\r\nJessica Malone is 50.\r\nKate Smith is 40.\r\nJennifer Lewis is 20.\n<|im_start|>answer\nShannon Ware is 80.\r\nJanice Peterson is 60.\r\nJessica Malone is 50.\r\nKate Smith is 40.\r\nJennifer Lewis is 20.\n<|im_end|>" }, { "id": "#400", "title": "One Hundred Dollar Bill", "fun": 2.64, "difficulty": 1.3, "author": "22ACE", "desc": "One day a very rich man was counting his money when he got a very important phone call and he had to leave in a hurry. In his haste he left a one hundred dollar bill on the table. When he came home he noticed the money was missing and he asked the two only other people in the house what happened. The maid said she saw the bill on the table while dusting the library and she hid it under the book. The butler said he got the bill and put it between pages 35 and 36 because he thought it would be safer in the book than under the book. One of them is lying. Who? Why?", "hint": "No hint available.", "answer": "Because odd numbers are always on the right side of the page, pages 35 and 36 are on the same piece of paper so the butler was lying because you can't put anything between one piece of paper.", "category": "Logic", "date": "04/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day a very rich man was counting his money when he got a very important phone call and he had to leave in a hurry. In his haste he left a one hundred dollar bill on the table. When he came home he noticed the money was missing and he asked the two only other people in the house what happened. The maid said she saw the bill on the table while dusting the library and she hid it under the book. The butler said he got the bill and put it between pages 35 and 36 because he thought it would be safer in the book than under the book. One of them is lying. Who? Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBecause odd numbers are always on the right side of the page, pages 35 and 36 are on the same piece of paper so the butler was lying because you can't put anything between one piece of paper.\n<|im_start|>answer\nBecause odd numbers are always on the right side of the page, pages 35 and 36 are on the same piece of paper so the butler was lying because you can't put anything between one piece of paper.\n<|im_end|>" }, { "id": "#42071", "title": "Roman Matches II", "fun": 2.64, "difficulty": 1.84, "author": "MarcM1098", "desc": "The following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it twice: the equation can be corrected in two different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote:\r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: XI = IX - III", "hint": "One solution only affects the left side of the equation; the other solution only affects the right side.", "answer": "First solution: XI = IX + II\r\nTake one matchstick from the III and place it across the minus sign (changing it to a plus sign).\n\r\nSecond solution: VI = IX - III\r\nChange the first X into a V by sliding the matchstick in the X that looks like a backslash (\\) slightly to the left until the bottom touches the matchstick that looks like a forward slash (/).", "category": "Math", "date": "05/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it twice: the equation can be corrected in two different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote:\r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: XI = IX - III\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst solution: XI = IX + II\r\nTake one matchstick from the III and place it across the minus sign (changing it to a plus sign).\n\r\nSecond solution: VI = IX - III\r\nChange the first X into a V by sliding the matchstick in the X that looks like a backslash (\\) slightly to the left until the bottom touches the matchstick that looks like a forward slash (/).\n<|im_start|>answer\nFirst solution: XI = IX + II\r\nTake one matchstick from the III and place it across the minus sign (changing it to a plus sign).\n\r\nSecond solution: VI = IX - III\r\nChange the first X into a V by sliding the matchstick in the X that looks like a backslash (\\) slightly to the left until the bottom touches the matchstick that looks like a forward slash (/).\n<|im_end|>" }, { "id": "#26399", "title": "Whatever Way the Wind Blows", "fun": 2.64, "difficulty": 2.37, "author": "HogwartsGirl05", "desc": "I have five very strange neighbors. Each has a favorite type of weather forecast and a different favorite color. I can never keep them straight on my own so I have a little system. I joined our neighborhood beautification society. On everyone's door my society members and I placed a flag that corresponded to that person's favorites whatever they were. The heavy winds that struck yesterday blew the flags into other yards. Can you figure out who the flags belong to using the facts that I remember?\n\r\n1. No one has a name that corresponds to their weather, starts with the same letter as their weather forecast or starts with the same letter as their last name.\n\r\n2. My five neighbors are: The one who likes rain, the one who likes gray, Mr. Cumulus, the neighbor who likes orange, and Danny.\n\r\n3. Miss Martinez hates rain. The person who likes orange has an \"o\" in their last name.\n\r\n4. Reynolds has fond memories from the US Air Force so that's where he gets his favorite color and because he was a pilot he knows the importance of strong tails.\n\r\n5. The person who loves snow (who isn't Wendy), hates its color. The person who loves white (which isn't Cumulus) is fond of precipitation which helps her gardens. Both Wendy and Cumulus hate the color orange.\n\r\n6. J.C. hates sunshine and in between colors whereas Jones prefers the pleasant, overcast days.\n\r\n7. When the guys on either side of me play football they play in their favorite colors which are orange and blue.", "hint": "Already? Well if you're sure you want me to give it all away, Sunny is female, and the US Air Force wear blue uniforms.", "answer": "Sunny Zephyr, Rain, White\r\nWendy Martinez, Sunshine, Grey\r\nJackson Cumulus, Snow, Black\r\nDanny Reynolds, Wind, Blue\r\nMitch Jones, Clouds, Orange", "category": "Logic-Grid", "date": "10/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have five very strange neighbors. Each has a favorite type of weather forecast and a different favorite color. I can never keep them straight on my own so I have a little system. I joined our neighborhood beautification society. On everyone's door my society members and I placed a flag that corresponded to that person's favorites whatever they were. The heavy winds that struck yesterday blew the flags into other yards. Can you figure out who the flags belong to using the facts that I remember?\n\r\n1. No one has a name that corresponds to their weather, starts with the same letter as their weather forecast or starts with the same letter as their last name.\n\r\n2. My five neighbors are: The one who likes rain, the one who likes gray, Mr. Cumulus, the neighbor who likes orange, and Danny.\n\r\n3. Miss Martinez hates rain. The person who likes orange has an \"o\" in their last name.\n\r\n4. Reynolds has fond memories from the US Air Force so that's where he gets his favorite color and because he was a pilot he knows the importance of strong tails.\n\r\n5. The person who loves snow (who isn't Wendy), hates its color. The person who loves white (which isn't Cumulus) is fond of precipitation which helps her gardens. Both Wendy and Cumulus hate the color orange.\n\r\n6. J.C. hates sunshine and in between colors whereas Jones prefers the pleasant, overcast days.\n\r\n7. When the guys on either side of me play football they play in their favorite colors which are orange and blue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSunny Zephyr, Rain, White\r\nWendy Martinez, Sunshine, Grey\r\nJackson Cumulus, Snow, Black\r\nDanny Reynolds, Wind, Blue\r\nMitch Jones, Clouds, Orange\n<|im_start|>answer\nSunny Zephyr, Rain, White\r\nWendy Martinez, Sunshine, Grey\r\nJackson Cumulus, Snow, Black\r\nDanny Reynolds, Wind, Blue\r\nMitch Jones, Clouds, Orange\n<|im_end|>" }, { "id": "#44017", "title": "Rex and Ralph: Mystery Number", "fun": 2.64, "difficulty": 3.19, "author": "javaguru", "desc": "Two mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Ralph was impressed by the ingenuity of Rex's last attempt using clues involving prime numbers, but he thinks he's got an even better one for Rex. He tells Rex he's thinking of a 6-digit number.\n\r\n\"All of the digits are different. The digital sum matches the number formed by the last two digits in the number. The sum of the first two digits is the same as the sum of the last two digits.\"\n\r\n\"Take the sum of the number, the number rotated one to the left, the number rotated one to the right, the number with the first three and last three digits swapped, the number with the digit pairs rotated to the left, and the number with the digit pairs rotated to the right. The first and last digits of this sum match the last two digits of the number, in some order.\"\n\r\nRalph then asks, \"If each of the three numbers formed by the digit pairs in the number is prime, then what is the number?\"\n\r\nRex looks confused, and for a moment Ralph thinks he's finally gotten him. Then Rex smiles, scribbles a few things down on a pad of paper and then says, \"Very nice, Ralph!\"\n\r\nRex then tells Ralph his number.\n\r\nWhat did Rex say?\n\n\r\n(See the hint for an explanation of the terminology.)", "hint": "The digital sum is the sum of the digits in the number. The digital sum of 247 is 2+4+7 = 13.\n\r\nThe digit pairs in 125690 are 12 56 90. These are also the numbers formed by the digit pairs.\n\r\nRotating 123456 one to the left gives 234561;\r\nRotating 123456 one to the right gives 612345;\r\nRotating the digit pairs in 567890 to the left gives 789056;\r\nRotating the digit pairs in 567890 to the right gives 905678.", "answer": "416723\n\n\r\nHere's how Rex determined Ralph's number:\n\r\nThe insight Rex needed to solve this involves the number produced by the sum of the six numbers created from configurations of the digits in the number. Assign ABCDEF to the digits in Ralph's number. The six numbers Ralph had Rex add together were:\n\r\nABCDEF\r\nBCDEFA\r\nFABCDE\r\nDEFABC\r\nCDEFAB\r\nEFABCD\n\r\nNotice that the six digits in each column in this summation are the six digits in the number. This means that the sum of each column will be the digital sum of the number. If that digital sum is represented by A+B+C+D+E+F = XY, then the problem is equivalent to adding:\n\r\nXXXXXX0\r\n+YYYYYY\n\r\nThe first and last digits will be X and Y only if 10 > X + Y. If X + Y is greater than 9, then the first digit will be X+1. Since both the digital sum of the number (A+B+C+D+E+F) and the first and last digit of the sum of the numbers match the digits XY, you know that 10 > X + Y. When Rex realized this relation he smiled because he knew that he had enough information now.\n\r\nThe digital sum of the number must be between 0+1+2+3+4+5 = 15 and 9+8+7+6+5+4 = 39. Since each of the digit pairs in the number form a prime number, the digital sum must be a prime number in this range. There are only six prime numbers in this range: 17, 19, 23, 29, 31, and 37. 19, 29 and 37 are eliminated since 1+9 > 9, 2+9 > 9 and 3+7 > 9.\n\r\nThe sum of the first two digits must match the sum of the last two digits (X+Y). For 31, 3+1=4, but the only other way to make four without repeating any digits is 0+4. Zero and four can't form a prime number, so the digital sum can't be 31. This leaves 17 and 23.\n\r\nFor the digital sum to be 17, the digits must be either 0+1+2+3+4+7 = 17 or 0+1+2+3+5+6 = 17. Only 0, 1, 2, 3, 4, 7 has both a 1 and 7 to make the last two digits be 17. However, there is no pair of remaining digits with a sum of 1+7 = 8, so the digital sum can't be 17 and therefore must be 23.\n\r\nIf the last two digits are 23, then the first two digits must total 2+3 = 5. The possibilities are 0+5 = 5 and 1+4 = 5. There is one prime number possible with each of these pairs: 05 and 41. The first two digits of the number can't be 05 because then the number would be a 5-digit number and Ralph's number has six digits. So the first two digits are 41 and the last two digits are 23.\n\r\nSince the sum of all the digits is 23, then the sum of the middle two digits must be 23 - (2+3) - (4+1) = 13. There are two pairs of the remaining digits that total 13: 5+8 = 13, and 6+7 = 13. Sixty-seven is the only prime number that can be formed from these pairs, so the middle two digits are 67 and Ralph's number is 416723.", "category": "Math", "date": "02/02/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Ralph was impressed by the ingenuity of Rex's last attempt using clues involving prime numbers, but he thinks he's got an even better one for Rex. He tells Rex he's thinking of a 6-digit number.\n\r\n\"All of the digits are different. The digital sum matches the number formed by the last two digits in the number. The sum of the first two digits is the same as the sum of the last two digits.\"\n\r\n\"Take the sum of the number, the number rotated one to the left, the number rotated one to the right, the number with the first three and last three digits swapped, the number with the digit pairs rotated to the left, and the number with the digit pairs rotated to the right. The first and last digits of this sum match the last two digits of the number, in some order.\"\n\r\nRalph then asks, \"If each of the three numbers formed by the digit pairs in the number is prime, then what is the number?\"\n\r\nRex looks confused, and for a moment Ralph thinks he's finally gotten him. Then Rex smiles, scribbles a few things down on a pad of paper and then says, \"Very nice, Ralph!\"\n\r\nRex then tells Ralph his number.\n\r\nWhat did Rex say?\n\n\r\n(See the hint for an explanation of the terminology.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n416723\n\n\r\nHere's how Rex determined Ralph's number:\n\r\nThe insight Rex needed to solve this involves the number produced by the sum of the six numbers created from configurations of the digits in the number. Assign ABCDEF to the digits in Ralph's number. The six numbers Ralph had Rex add together were:\n\r\nABCDEF\r\nBCDEFA\r\nFABCDE\r\nDEFABC\r\nCDEFAB\r\nEFABCD\n\r\nNotice that the six digits in each column in this summation are the six digits in the number. This means that the sum of each column will be the digital sum of the number. If that digital sum is represented by A+B+C+D+E+F = XY, then the problem is equivalent to adding:\n\r\nXXXXXX0\r\n+YYYYYY\n\r\nThe first and last digits will be X and Y only if 10 > X + Y. If X + Y is greater than 9, then the first digit will be X+1. Since both the digital sum of the number (A+B+C+D+E+F) and the first and last digit of the sum of the numbers match the digits XY, you know that 10 > X + Y. When Rex realized this relation he smiled because he knew that he had enough information now.\n\r\nThe digital sum of the number must be between 0+1+2+3+4+5 = 15 and 9+8+7+6+5+4 = 39. Since each of the digit pairs in the number form a prime number, the digital sum must be a prime number in this range. There are only six prime numbers in this range: 17, 19, 23, 29, 31, and 37. 19, 29 and 37 are eliminated since 1+9 > 9, 2+9 > 9 and 3+7 > 9.\n\r\nThe sum of the first two digits must match the sum of the last two digits (X+Y). For 31, 3+1=4, but the only other way to make four without repeating any digits is 0+4. Zero and four can't form a prime number, so the digital sum can't be 31. This leaves 17 and 23.\n\r\nFor the digital sum to be 17, the digits must be either 0+1+2+3+4+7 = 17 or 0+1+2+3+5+6 = 17. Only 0, 1, 2, 3, 4, 7 has both a 1 and 7 to make the last two digits be 17. However, there is no pair of remaining digits with a sum of 1+7 = 8, so the digital sum can't be 17 and therefore must be 23.\n\r\nIf the last two digits are 23, then the first two digits must total 2+3 = 5. The possibilities are 0+5 = 5 and 1+4 = 5. There is one prime number possible with each of these pairs: 05 and 41. The first two digits of the number can't be 05 because then the number would be a 5-digit number and Ralph's number has six digits. So the first two digits are 41 and the last two digits are 23.\n\r\nSince the sum of all the digits is 23, then the sum of the middle two digits must be 23 - (2+3) - (4+1) = 13. There are two pairs of the remaining digits that total 13: 5+8 = 13, and 6+7 = 13. Sixty-seven is the only prime number that can be formed from these pairs, so the middle two digits are 67 and Ralph's number is 416723.\n<|im_start|>answer\n416723\n\n\r\nHere's how Rex determined Ralph's number:\n\r\nThe insight Rex needed to solve this involves the number produced by the sum of the six numbers created from configurations of the digits in the number. Assign ABCDEF to the digits in Ralph's number. The six numbers Ralph had Rex add together were:\n\r\nABCDEF\r\nBCDEFA\r\nFABCDE\r\nDEFABC\r\nCDEFAB\r\nEFABCD\n\r\nNotice that the six digits in each column in this summation are the six digits in the number. This means that the sum of each column will be the digital sum of the number. If that digital sum is represented by A+B+C+D+E+F = XY, then the problem is equivalent to adding:\n\r\nXXXXXX0\r\n+YYYYYY\n\r\nThe first and last digits will be X and Y only if 10 > X + Y. If X + Y is greater than 9, then the first digit will be X+1. Since both the digital sum of the number (A+B+C+D+E+F) and the first and last digit of the sum of the numbers match the digits XY, you know that 10 > X + Y. When Rex realized this relation he smiled because he knew that he had enough information now.\n\r\nThe digital sum of the number must be between 0+1+2+3+4+5 = 15 and 9+8+7+6+5+4 = 39. Since each of the digit pairs in the number form a prime number, the digital sum must be a prime number in this range. There are only six prime numbers in this range: 17, 19, 23, 29, 31, and 37. 19, 29 and 37 are eliminated since 1+9 > 9, 2+9 > 9 and 3+7 > 9.\n\r\nThe sum of the first two digits must match the sum of the last two digits (X+Y). For 31, 3+1=4, but the only other way to make four without repeating any digits is 0+4. Zero and four can't form a prime number, so the digital sum can't be 31. This leaves 17 and 23.\n\r\nFor the digital sum to be 17, the digits must be either 0+1+2+3+4+7 = 17 or 0+1+2+3+5+6 = 17. Only 0, 1, 2, 3, 4, 7 has both a 1 and 7 to make the last two digits be 17. However, there is no pair of remaining digits with a sum of 1+7 = 8, so the digital sum can't be 17 and therefore must be 23.\n\r\nIf the last two digits are 23, then the first two digits must total 2+3 = 5. The possibilities are 0+5 = 5 and 1+4 = 5. There is one prime number possible with each of these pairs: 05 and 41. The first two digits of the number can't be 05 because then the number would be a 5-digit number and Ralph's number has six digits. So the first two digits are 41 and the last two digits are 23.\n\r\nSince the sum of all the digits is 23, then the sum of the middle two digits must be 23 - (2+3) - (4+1) = 13. There are two pairs of the remaining digits that total 13: 5+8 = 13, and 6+7 = 13. Sixty-seven is the only prime number that can be formed from these pairs, so the middle two digits are 67 and Ralph's number is 416723.\n<|im_end|>" }, { "id": "#48366", "title": "Birthday Gals", "fun": 2.64, "difficulty": 0.89, "author": "Mitty44", "desc": "Five sisters all have their birthday in a different month and each on a different day of the week. Using the clues below, determine the month and day of the week each sister's birthday falls.\n\r\nPaula was born in March but not on Saturday. Abigail's birthday was not on Friday or Wednesday.\r\nThe girl whose birthday was on Monday was born earlier in the year than Brenda and Mary.\r\nTara wasn't born in February but her birthday was on the weekend.\r\nMary was not born in December nor was her birthday on a weekday. The girl whose birthday was in June was born on Sunday.\r\nTara was born earlier in the year than Brenda, whose birthday wasn't on Friday. Mary wasn't born in July.", "hint": "No hint available.", "answer": "Abigail, February, Monday\n\r\nBrenda, December, Wednesday\n\r\nMary, June, Sunday\n\r\nPaula, March, Friday\n\r\nTara, July, Saturday", "category": "Logic-Grid", "date": "01/06/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive sisters all have their birthday in a different month and each on a different day of the week. Using the clues below, determine the month and day of the week each sister's birthday falls.\n\r\nPaula was born in March but not on Saturday. Abigail's birthday was not on Friday or Wednesday.\r\nThe girl whose birthday was on Monday was born earlier in the year than Brenda and Mary.\r\nTara wasn't born in February but her birthday was on the weekend.\r\nMary was not born in December nor was her birthday on a weekday. The girl whose birthday was in June was born on Sunday.\r\nTara was born earlier in the year than Brenda, whose birthday wasn't on Friday. Mary wasn't born in July.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbigail, February, Monday\n\r\nBrenda, December, Wednesday\n\r\nMary, June, Sunday\n\r\nPaula, March, Friday\n\r\nTara, July, Saturday\n<|im_start|>answer\nAbigail, February, Monday\n\r\nBrenda, December, Wednesday\n\r\nMary, June, Sunday\n\r\nPaula, March, Friday\n\r\nTara, July, Saturday\n<|im_end|>" }, { "id": "#44958", "title": "Open Horse Show", "fun": 2.64, "difficulty": 2.28, "author": "mrsfessler", "desc": "At the county fair Open Horse Show, 5 riders competed in different classes. Each won either a blue (1st place), red (2nd place), or white (3rd place) ribbon. From the clues provided, determine each rider's age (one is 25), the name of the horse they rode (one is Miss Liberty), what class they competed in, and what color ribbon they won. The 5 classes were: Hunt Seat - Juvenile rider (age 17 or under), Hunt Seat - Adult rider (over 17), Lead Line - 6 years and under, Arabian Pleasure (no age specifications), and Morgan Pleasure (no age specifications).\n\r\n1. The 5 riders were Michelle, Sahara's rider, the 16 year old, the one who placed 2nd, and the one who competed in Hunt Seat - Adult.\n\r\n2. The 2 blue ribbon winners were Blake and Starheart's rider. Michelle's Morgan horse always performed well in its class.\n\r\n3. Cocoa's rider was younger than the rider in the Arabian Pleasure class, but placed higher than Beth. Beth was younger than the Arabian Pleasure rider.\n\r\n4. From oldest to youngest the riders were the woman who showed in Morgan Pleasure, Fred, the 17 year old, Jasper's rider and the one who was eligible for the last time and showed in the Lead Line - 6 and under class.\n\r\n5. Both Hunt Seat riders placed lower than Isabella and the 49 year old.", "hint": "No hint available.", "answer": "Isabella, 6, Lead Line, Cocoa, Red\n\r\nMichelle, 49, Morgan Pleasure, Starheart, Blue\t\n\r\nBeth, 16, Hunt Seat - Juvenile, Jasper, White\n\r\nFred, 25, Hunt Seat - Adult, Miss Liberty, White\n\r\nBlake, 17, Arabian Pleasure, Sahara, Blue", "category": "Logic-Grid", "date": "07/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the county fair Open Horse Show, 5 riders competed in different classes. Each won either a blue (1st place), red (2nd place), or white (3rd place) ribbon. From the clues provided, determine each rider's age (one is 25), the name of the horse they rode (one is Miss Liberty), what class they competed in, and what color ribbon they won. The 5 classes were: Hunt Seat - Juvenile rider (age 17 or under), Hunt Seat - Adult rider (over 17), Lead Line - 6 years and under, Arabian Pleasure (no age specifications), and Morgan Pleasure (no age specifications).\n\r\n1. The 5 riders were Michelle, Sahara's rider, the 16 year old, the one who placed 2nd, and the one who competed in Hunt Seat - Adult.\n\r\n2. The 2 blue ribbon winners were Blake and Starheart's rider. Michelle's Morgan horse always performed well in its class.\n\r\n3. Cocoa's rider was younger than the rider in the Arabian Pleasure class, but placed higher than Beth. Beth was younger than the Arabian Pleasure rider.\n\r\n4. From oldest to youngest the riders were the woman who showed in Morgan Pleasure, Fred, the 17 year old, Jasper's rider and the one who was eligible for the last time and showed in the Lead Line - 6 and under class.\n\r\n5. Both Hunt Seat riders placed lower than Isabella and the 49 year old.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIsabella, 6, Lead Line, Cocoa, Red\n\r\nMichelle, 49, Morgan Pleasure, Starheart, Blue\t\n\r\nBeth, 16, Hunt Seat - Juvenile, Jasper, White\n\r\nFred, 25, Hunt Seat - Adult, Miss Liberty, White\n\r\nBlake, 17, Arabian Pleasure, Sahara, Blue\n<|im_start|>answer\nIsabella, 6, Lead Line, Cocoa, Red\n\r\nMichelle, 49, Morgan Pleasure, Starheart, Blue\t\n\r\nBeth, 16, Hunt Seat - Juvenile, Jasper, White\n\r\nFred, 25, Hunt Seat - Adult, Miss Liberty, White\n\r\nBlake, 17, Arabian Pleasure, Sahara, Blue\n<|im_end|>" }, { "id": "#26795", "title": "Jungle Gym Hoopla", "fun": 2.64, "difficulty": 0.64, "author": "Kalliann", "desc": "After the sandbox disaster the week before, five fathers were in charge of taking the children to the park. The fathers did not want to have the same mix-up with the sandbox that their wives went through, so this week they kept all their children on the jungle gym. Everything was going good until it was time to leave and the kids had to put their shoes on. It was at that time that the fathers realized that the shoes were all mixed up. Can you help these fathers figure out which shoes belong to which child? \n\r\nThe Fathers: Pete, Sam, Mark, Kaleb, and Zander. \n\r\nThe Children: Zach, Tim, Chris, Laura, and Natalie. \n\r\nThe Shoes: Black, Red, Yellow, Green, and Pink. \n\n\r\nClues: \r\n1) Pete bought his son black shoes, but his son is neither Chris or Tim. \r\n2) Chris hates the colors green and pink, but his friend Laura loves green.\r\n3) Sam, Tim's dad, was searching for shoes the same color as a firetruck. \r\n4) Kaleb and Zander are the only dads with daughters. \r\n5)Natalie's dad is not Kaleb.", "hint": "Laura and Natalie are the only girls", "answer": "Pete is the father of Zach who has Black shoes. \n\r\nSam is the father of Tim who has Red shoes. \n\r\nMark is the father of Chris who has Yellow shoes. \n\r\nKaleb is the father of Laura who has Green shoes. \n\r\nZander is the father of Natalie who has Pink shoes.", "category": "Logic-Grid", "date": "11/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter the sandbox disaster the week before, five fathers were in charge of taking the children to the park. The fathers did not want to have the same mix-up with the sandbox that their wives went through, so this week they kept all their children on the jungle gym. Everything was going good until it was time to leave and the kids had to put their shoes on. It was at that time that the fathers realized that the shoes were all mixed up. Can you help these fathers figure out which shoes belong to which child? \n\r\nThe Fathers: Pete, Sam, Mark, Kaleb, and Zander. \n\r\nThe Children: Zach, Tim, Chris, Laura, and Natalie. \n\r\nThe Shoes: Black, Red, Yellow, Green, and Pink. \n\n\r\nClues: \r\n1) Pete bought his son black shoes, but his son is neither Chris or Tim. \r\n2) Chris hates the colors green and pink, but his friend Laura loves green.\r\n3) Sam, Tim's dad, was searching for shoes the same color as a firetruck. \r\n4) Kaleb and Zander are the only dads with daughters. \r\n5)Natalie's dad is not Kaleb.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPete is the father of Zach who has Black shoes. \n\r\nSam is the father of Tim who has Red shoes. \n\r\nMark is the father of Chris who has Yellow shoes. \n\r\nKaleb is the father of Laura who has Green shoes. \n\r\nZander is the father of Natalie who has Pink shoes.\n<|im_start|>answer\nPete is the father of Zach who has Black shoes. \n\r\nSam is the father of Tim who has Red shoes. \n\r\nMark is the father of Chris who has Yellow shoes. \n\r\nKaleb is the father of Laura who has Green shoes. \n\r\nZander is the father of Natalie who has Pink shoes.\n<|im_end|>" }, { "id": "#1403", "title": "Perfect Eggs", "fun": 2.64, "difficulty": 1.91, "author": "gokaran", "desc": "For his breakfast, Mr Stone likes an egg that has been boiled for exactly 9 minutes. He has two egg timers (those with sand in them), one that runs for 4 minutes and one that runs for 7 minutes. How can he use these timers to boil his egg?", "hint": "No hint available.", "answer": "Start both egg timers. When the 4 minute timer runs out, turn it over. When the 7 minute timer runs out turn it over. When the 4 minute timer runs out again the 7 minute timer has been running for 1 minute. Turn it over once again. When it stops the egg is done.", "category": "Math", "date": "11/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor his breakfast, Mr Stone likes an egg that has been boiled for exactly 9 minutes. He has two egg timers (those with sand in them), one that runs for 4 minutes and one that runs for 7 minutes. How can he use these timers to boil his egg?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStart both egg timers. When the 4 minute timer runs out, turn it over. When the 7 minute timer runs out turn it over. When the 4 minute timer runs out again the 7 minute timer has been running for 1 minute. Turn it over once again. When it stops the egg is done.\n<|im_start|>answer\nStart both egg timers. When the 4 minute timer runs out, turn it over. When the 7 minute timer runs out turn it over. When the 4 minute timer runs out again the 7 minute timer has been running for 1 minute. Turn it over once again. When it stops the egg is done.\n<|im_end|>" }, { "id": "#17117", "title": "A History Lesson", "fun": 2.64, "difficulty": 1.86, "author": "toast9897", "desc": "When Carl Friedrich Gauss was six years old (back in 1783), his schoolteacher asked the students to add up all the numbers from 1 to 100. Unfortunately for the teacher, who was hoping to keep the class occupied, it took young Gauss only a few seconds to work out the answer. Can you figure out what Gauss did to come up with the answer?", "hint": "There is a pattern...", "answer": "Gauss realized that the series 1+2+3+4...+97+98+99+100 could be written as 1+100+2+99+3+98+4+97... or 101 times 50 to get the total 5,050.\n\r\nThis trick works for any sum of sequential integers. The general formula is n(n+1)/2, which is the equation for triangular numbers.", "category": "Math", "date": "03/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Carl Friedrich Gauss was six years old (back in 1783), his schoolteacher asked the students to add up all the numbers from 1 to 100. Unfortunately for the teacher, who was hoping to keep the class occupied, it took young Gauss only a few seconds to work out the answer. Can you figure out what Gauss did to come up with the answer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGauss realized that the series 1+2+3+4...+97+98+99+100 could be written as 1+100+2+99+3+98+4+97... or 101 times 50 to get the total 5,050.\n\r\nThis trick works for any sum of sequential integers. The general formula is n(n+1)/2, which is the equation for triangular numbers.\n<|im_start|>answer\nGauss realized that the series 1+2+3+4...+97+98+99+100 could be written as 1+100+2+99+3+98+4+97... or 101 times 50 to get the total 5,050.\n\r\nThis trick works for any sum of sequential integers. The general formula is n(n+1)/2, which is the equation for triangular numbers.\n<|im_end|>" }, { "id": "#30684", "title": "Race Against Time", "fun": 2.64, "difficulty": 2.36, "author": "fairelamour", "desc": "A child in the remote mountain village of Pliluk has fallen ill. Dotan, his brother Forak, and his sister Loti must get their father, the village healer, who is gathering herbs on the other side of the mountain. To make sure they get him as quickly as possible, they decide to split up. Forak will ride his horse around the mountain's base, Dotan will travel by river raft, and Loti will climb the steep cliff trail.\n\r\nThe raft can travel at 22 miles an hour along the 40 miles of the river, but there are 3 places where Dotan, at each place, will lose 0.4 hours by having to carry the raft around dangerous waterfalls. Forak's horse can travel 15 miles per hour on the flatter part of the 32-mile trail, but only 8 miles per hour on the steep part, which is 30% of the whole trail. Loti's road up and down the cliffs is the shortest, only 14 miles, but her average rate is only 5 miles an hour, and she must take a 10-minute rest at the summit.\n\r\nAssuming Dotan does not hit a rock, Forak is not attacked by an ice panther, and Loti is not bitten by a cliff snake, who will reach their father first? Round all decimals to tenths.", "hint": "Choose your mathematical operations carefully.", "answer": "Forak will reach his father first.\n\r\nAt the rate of 22 miles per hour, Dotan's raft covers the distance of 40 miles in 40/22 = 1.8 hours. Adding the time for three delays, 3*0.4 = 1.2 hours, his total time is 3 hours.\n\r\nThirty percent of Forak's 32-mile trail (or 32*0.3 = 9.6 miles) is steep, and at a rate of 8 miles per hour he covers this steep section in 9.6/8 = 1.2 hours. At a rate of 15 miles per hour on the 22.4-mile flat section, Forak covers this in 22.4/15 = 1.5 hours. His total time is 2.7 hours.\n\r\nAt her average rate of 5 miles per hour, Loti covers her 14-mile mountain trail in 14/5 = 2.8 hours, but her rest time at the summit takes 10/60 or nearly 0.2 hours, so her total time, like Dotan's, is 3 hours.\n\r\nTheir father rides Forak's horse back to the village and treats the child. The child recovers, to everyone's joy.", "category": "Math", "date": "05/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA child in the remote mountain village of Pliluk has fallen ill. Dotan, his brother Forak, and his sister Loti must get their father, the village healer, who is gathering herbs on the other side of the mountain. To make sure they get him as quickly as possible, they decide to split up. Forak will ride his horse around the mountain's base, Dotan will travel by river raft, and Loti will climb the steep cliff trail.\n\r\nThe raft can travel at 22 miles an hour along the 40 miles of the river, but there are 3 places where Dotan, at each place, will lose 0.4 hours by having to carry the raft around dangerous waterfalls. Forak's horse can travel 15 miles per hour on the flatter part of the 32-mile trail, but only 8 miles per hour on the steep part, which is 30% of the whole trail. Loti's road up and down the cliffs is the shortest, only 14 miles, but her average rate is only 5 miles an hour, and she must take a 10-minute rest at the summit.\n\r\nAssuming Dotan does not hit a rock, Forak is not attacked by an ice panther, and Loti is not bitten by a cliff snake, who will reach their father first? Round all decimals to tenths.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nForak will reach his father first.\n\r\nAt the rate of 22 miles per hour, Dotan's raft covers the distance of 40 miles in 40/22 = 1.8 hours. Adding the time for three delays, 3*0.4 = 1.2 hours, his total time is 3 hours.\n\r\nThirty percent of Forak's 32-mile trail (or 32*0.3 = 9.6 miles) is steep, and at a rate of 8 miles per hour he covers this steep section in 9.6/8 = 1.2 hours. At a rate of 15 miles per hour on the 22.4-mile flat section, Forak covers this in 22.4/15 = 1.5 hours. His total time is 2.7 hours.\n\r\nAt her average rate of 5 miles per hour, Loti covers her 14-mile mountain trail in 14/5 = 2.8 hours, but her rest time at the summit takes 10/60 or nearly 0.2 hours, so her total time, like Dotan's, is 3 hours.\n\r\nTheir father rides Forak's horse back to the village and treats the child. The child recovers, to everyone's joy.\n<|im_start|>answer\nForak will reach his father first.\n\r\nAt the rate of 22 miles per hour, Dotan's raft covers the distance of 40 miles in 40/22 = 1.8 hours. Adding the time for three delays, 3*0.4 = 1.2 hours, his total time is 3 hours.\n\r\nThirty percent of Forak's 32-mile trail (or 32*0.3 = 9.6 miles) is steep, and at a rate of 8 miles per hour he covers this steep section in 9.6/8 = 1.2 hours. At a rate of 15 miles per hour on the 22.4-mile flat section, Forak covers this in 22.4/15 = 1.5 hours. His total time is 2.7 hours.\n\r\nAt her average rate of 5 miles per hour, Loti covers her 14-mile mountain trail in 14/5 = 2.8 hours, but her rest time at the summit takes 10/60 or nearly 0.2 hours, so her total time, like Dotan's, is 3 hours.\n\r\nTheir father rides Forak's horse back to the village and treats the child. The child recovers, to everyone's joy.\n<|im_end|>" }, { "id": "#28727", "title": "Jugs", "fun": 2.64, "difficulty": 2.15, "author": "jessjspieks", "desc": "You've got a 4 liter jug and a 9 liter jug. \r\nYou've got a pool of water. \r\nWhat is the fewest number of steps it takes to come up with exactly 6 liters of water? \r\nNo, you cannot pour some water into the 9 liter jug and then guess. Nor can you fill each jug up half way or something. You have to be exact. A step is defined as putting water into a jug (not emptying). For instance, filling the 4 liter jug and then pouring it into the 9 liter jug is 2 steps.", "hint": "It's under 10.", "answer": "The full answer is as follows: \n\r\n1. Fill up the 9 liter jug from the pool. \r\n2. Fill up the 4 liter jug from the 9 liter jug (leaving 5 liters in the 9 liter jug). \r\n3. Empty the 4 liter jug into the pool and fill it again from the 9 liter jug (leaving 1 liter in the 9 liter jug). \r\n4. Empty the 4 liter jug into the pool and put the 1 liter from the 9 liter jug into the 4 liter. \r\n5. Fill the 9 liter jug from the pool. \r\n6. Fill up the 4 liter jug from the 9 liter jug. There was 1 liter in the 4 liter jug, so 3 liters will fill it. This leaves, in the 9 liter jug, exactly 6 liters.", "category": "Logic", "date": "02/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou've got a 4 liter jug and a 9 liter jug. \r\nYou've got a pool of water. \r\nWhat is the fewest number of steps it takes to come up with exactly 6 liters of water? \r\nNo, you cannot pour some water into the 9 liter jug and then guess. Nor can you fill each jug up half way or something. You have to be exact. A step is defined as putting water into a jug (not emptying). For instance, filling the 4 liter jug and then pouring it into the 9 liter jug is 2 steps.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe full answer is as follows: \n\r\n1. Fill up the 9 liter jug from the pool. \r\n2. Fill up the 4 liter jug from the 9 liter jug (leaving 5 liters in the 9 liter jug). \r\n3. Empty the 4 liter jug into the pool and fill it again from the 9 liter jug (leaving 1 liter in the 9 liter jug). \r\n4. Empty the 4 liter jug into the pool and put the 1 liter from the 9 liter jug into the 4 liter. \r\n5. Fill the 9 liter jug from the pool. \r\n6. Fill up the 4 liter jug from the 9 liter jug. There was 1 liter in the 4 liter jug, so 3 liters will fill it. This leaves, in the 9 liter jug, exactly 6 liters.\n<|im_start|>answer\nThe full answer is as follows: \n\r\n1. Fill up the 9 liter jug from the pool. \r\n2. Fill up the 4 liter jug from the 9 liter jug (leaving 5 liters in the 9 liter jug). \r\n3. Empty the 4 liter jug into the pool and fill it again from the 9 liter jug (leaving 1 liter in the 9 liter jug). \r\n4. Empty the 4 liter jug into the pool and put the 1 liter from the 9 liter jug into the 4 liter. \r\n5. Fill the 9 liter jug from the pool. \r\n6. Fill up the 4 liter jug from the 9 liter jug. There was 1 liter in the 4 liter jug, so 3 liters will fill it. This leaves, in the 9 liter jug, exactly 6 liters.\n<|im_end|>" }, { "id": "#29166", "title": "Mystery Number", "fun": 2.64, "difficulty": 1.69, "author": "----", "desc": "Look at the following clues to uncover the mystery number:\n\r\n1. I am a 4-digit even number, and all of my digits are different. \r\n2. The sum of all my digits is 10. \r\n3. Each of my digits is greater than zero. \r\n4. The sum of the digits in my thousands place and hundreds place equals the sum of the digits in my ones place and tens place. \r\n5. My largest digit is in the thousands place. \n\r\nWhat number am I?", "hint": "Make a table with a column for each digit and eliminate the impossibilities.", "answer": "The mystery number is 4132.\n\r\nSince the sum of all four digits is 10, and the sum of the digits in the thousands place and the hundreds place is equal to the sum of the digits in the tens place and the ones place, then you know that each of these sums is equal to 5. Because all of the digits in the mystery number are different and none of them are equal to zero, the four digits must be some combination of 1, 2, 3, and 4.\n\r\nYou also know that the ones digit is an even number, so the ones digit is either 2 or 4. Finally, the last clue says that the largest digit is in the thousands place, so the mystery number must be 4132.", "category": "Math", "date": "03/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLook at the following clues to uncover the mystery number:\n\r\n1. I am a 4-digit even number, and all of my digits are different. \r\n2. The sum of all my digits is 10. \r\n3. Each of my digits is greater than zero. \r\n4. The sum of the digits in my thousands place and hundreds place equals the sum of the digits in my ones place and tens place. \r\n5. My largest digit is in the thousands place. \n\r\nWhat number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe mystery number is 4132.\n\r\nSince the sum of all four digits is 10, and the sum of the digits in the thousands place and the hundreds place is equal to the sum of the digits in the tens place and the ones place, then you know that each of these sums is equal to 5. Because all of the digits in the mystery number are different and none of them are equal to zero, the four digits must be some combination of 1, 2, 3, and 4.\n\r\nYou also know that the ones digit is an even number, so the ones digit is either 2 or 4. Finally, the last clue says that the largest digit is in the thousands place, so the mystery number must be 4132.\n<|im_start|>answer\nThe mystery number is 4132.\n\r\nSince the sum of all four digits is 10, and the sum of the digits in the thousands place and the hundreds place is equal to the sum of the digits in the tens place and the ones place, then you know that each of these sums is equal to 5. Because all of the digits in the mystery number are different and none of them are equal to zero, the four digits must be some combination of 1, 2, 3, and 4.\n\r\nYou also know that the ones digit is an even number, so the ones digit is either 2 or 4. Finally, the last clue says that the largest digit is in the thousands place, so the mystery number must be 4132.\n<|im_end|>" }, { "id": "#534", "title": "Amoebas", "fun": 2.64, "difficulty": 1.21, "author": "kaila912", "desc": "Amoebas reproduce by splitting in two. An amoeba which does so every minute is placed in a jar at exactly ten o`clock in the morning. At 12:00 noon the jar is full. At what time is the jar half full?", "hint": "No hint available.", "answer": "11:59. Since they double every minute, at 11:59 it was half full. One minute later it had doubled and was full.", "category": "Math", "date": "05/31/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAmoebas reproduce by splitting in two. An amoeba which does so every minute is placed in a jar at exactly ten o`clock in the morning. At 12:00 noon the jar is full. At what time is the jar half full?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11:59. Since they double every minute, at 11:59 it was half full. One minute later it had doubled and was full.\n<|im_start|>answer\n11:59. Since they double every minute, at 11:59 it was half full. One minute later it had doubled and was full.\n<|im_end|>" }, { "id": "#38154", "title": "Four Bungalows", "fun": 2.64, "difficulty": 2.09, "author": "holly1447591", "desc": "There are four bungalows in our cul-de-sac. Some of them are made from peculiar materials: straw, wood, brick and glass. Mrs. Scott's bungalow is somewhere to the left of the wooden one and the third one along is brick. Mrs. Umbrella owns a straw bungalow and Mr. Tinsley does not live at either end, but lives somewhere to the right of the glass bungalow. Mr. Wilshaw lives in the fourth bungalow, whilst the first bungalow is not made from straw.\n\r\nBased on these clues, figure out the order of the bungalows, left to right, and who lives in each one.", "hint": "No hint available.", "answer": "From, left to right, Mrs. Scott lives in the glass bungalow. Mrs. Umbrella lives in the straw one. Mr. Tinsley lives in the brick one. Mr. Wilshaw lives in the wooden one.", "category": "Logic", "date": "09/06/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four bungalows in our cul-de-sac. Some of them are made from peculiar materials: straw, wood, brick and glass. Mrs. Scott's bungalow is somewhere to the left of the wooden one and the third one along is brick. Mrs. Umbrella owns a straw bungalow and Mr. Tinsley does not live at either end, but lives somewhere to the right of the glass bungalow. Mr. Wilshaw lives in the fourth bungalow, whilst the first bungalow is not made from straw.\n\r\nBased on these clues, figure out the order of the bungalows, left to right, and who lives in each one.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom, left to right, Mrs. Scott lives in the glass bungalow. Mrs. Umbrella lives in the straw one. Mr. Tinsley lives in the brick one. Mr. Wilshaw lives in the wooden one.\n<|im_start|>answer\nFrom, left to right, Mrs. Scott lives in the glass bungalow. Mrs. Umbrella lives in the straw one. Mr. Tinsley lives in the brick one. Mr. Wilshaw lives in the wooden one.\n<|im_end|>" }, { "id": "#33563", "title": "Speeding Blues", "fun": 2.64, "difficulty": 2.89, "author": "dishu", "desc": "Car 1 started from Point A towards point B. At the same time Car 2 started from point B towards A. They crossed each other at point C. After which, Car 1 reached point B in another 9 hrs, and Car 2 reached point A in another 4 hrs. If both the cars maintained a constant speed throughout the journey, and the speed of Car 1 was 36 miles/hr(mph), then what was the speed of Car 2?", "hint": "No hint available.", "answer": "54 miles/hr.\r\nHere's how to solve:\r\nSpeed of Car 1 = 36 mph\r\nTime taken from point C to B = 9 hrs\r\nthus, distance between C to B = 36 * 9 = 324 miles (Distance = Speed * Time)\n\r\nNow let the distance between point A and C be 'a' miles and let the speed of Car 2 be 'b' mph.\r\nThus time taken by Car 1 to travel from A to C = a/36 (Time = Distance/Speed).\r\nand the time taken by car 2 to travel from B to C = 324/b (Distance between C and B is 324 miles as explained above)\r\nSince both the cars meet at C, then these two times are equal, i.e.\r\na/36 = 324/b\r\nor b = 324 * 36/a =11664/a\n\r\nNow time taken by Car 2 to travel from C to A can be described as a/b or a*a/11664 (writing b in terms of a).\r\nBut it is given that Car 2 takes 4 hrs to travel from C to A. Thus, we get\r\na * a/11664 = 4\r\nor, a * a = 46656\r\nNow taking square root on both sides, we get a = 216. (distance cannot be negative).\r\nThus we get b = 11664/216 = 54.\r\nThus speed of Car 2 = 54 miles/hr", "category": "Math", "date": "10/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCar 1 started from Point A towards point B. At the same time Car 2 started from point B towards A. They crossed each other at point C. After which, Car 1 reached point B in another 9 hrs, and Car 2 reached point A in another 4 hrs. If both the cars maintained a constant speed throughout the journey, and the speed of Car 1 was 36 miles/hr(mph), then what was the speed of Car 2?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n54 miles/hr.\r\nHere's how to solve:\r\nSpeed of Car 1 = 36 mph\r\nTime taken from point C to B = 9 hrs\r\nthus, distance between C to B = 36 * 9 = 324 miles (Distance = Speed * Time)\n\r\nNow let the distance between point A and C be 'a' miles and let the speed of Car 2 be 'b' mph.\r\nThus time taken by Car 1 to travel from A to C = a/36 (Time = Distance/Speed).\r\nand the time taken by car 2 to travel from B to C = 324/b (Distance between C and B is 324 miles as explained above)\r\nSince both the cars meet at C, then these two times are equal, i.e.\r\na/36 = 324/b\r\nor b = 324 * 36/a =11664/a\n\r\nNow time taken by Car 2 to travel from C to A can be described as a/b or a*a/11664 (writing b in terms of a).\r\nBut it is given that Car 2 takes 4 hrs to travel from C to A. Thus, we get\r\na * a/11664 = 4\r\nor, a * a = 46656\r\nNow taking square root on both sides, we get a = 216. (distance cannot be negative).\r\nThus we get b = 11664/216 = 54.\r\nThus speed of Car 2 = 54 miles/hr\n<|im_start|>answer\n54 miles/hr.\r\nHere's how to solve:\r\nSpeed of Car 1 = 36 mph\r\nTime taken from point C to B = 9 hrs\r\nthus, distance between C to B = 36 * 9 = 324 miles (Distance = Speed * Time)\n\r\nNow let the distance between point A and C be 'a' miles and let the speed of Car 2 be 'b' mph.\r\nThus time taken by Car 1 to travel from A to C = a/36 (Time = Distance/Speed).\r\nand the time taken by car 2 to travel from B to C = 324/b (Distance between C and B is 324 miles as explained above)\r\nSince both the cars meet at C, then these two times are equal, i.e.\r\na/36 = 324/b\r\nor b = 324 * 36/a =11664/a\n\r\nNow time taken by Car 2 to travel from C to A can be described as a/b or a*a/11664 (writing b in terms of a).\r\nBut it is given that Car 2 takes 4 hrs to travel from C to A. Thus, we get\r\na * a/11664 = 4\r\nor, a * a = 46656\r\nNow taking square root on both sides, we get a = 216. (distance cannot be negative).\r\nThus we get b = 11664/216 = 54.\r\nThus speed of Car 2 = 54 miles/hr\n<|im_end|>" }, { "id": "#3391", "title": "Jewels", "fun": 2.64, "difficulty": 1.62, "author": "204_BLaZe_41", "desc": "\"I have the only key to the room containing the jewelry of my late aunt, Maggie,\" stated Sid. \"Since her death a week ago, neither I nor anybody else has entered this room. I was quite pleased to hear her will requested that all her jewelry was to be sold and the proceeds to go to charity,\" continued Sid. Shadow removed a large plant whose broad leaves were turned toward the wall, partially covering the safe. While Sid was working the combination lock, Shadow crossed the room to sit on the ledge of the large bay window. Sid opened the safe, and removed the bag of jewels. \"I'm sure these jewels will fetch a fortune for charity,\" said a smiling Sid. \"I'll bet these jewels are either fake or there's a few missing,\" replied Shadow. What aroused Shadow's suspicion?", "hint": "No hint available.", "answer": "Sid, who had the only key, said that neither he nor anyone else had been in the room for the past week. If this were true, the leaves of the plant would have been leaning toward the window instead of the wall.", "category": "Logic", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"I have the only key to the room containing the jewelry of my late aunt, Maggie,\" stated Sid. \"Since her death a week ago, neither I nor anybody else has entered this room. I was quite pleased to hear her will requested that all her jewelry was to be sold and the proceeds to go to charity,\" continued Sid. Shadow removed a large plant whose broad leaves were turned toward the wall, partially covering the safe. While Sid was working the combination lock, Shadow crossed the room to sit on the ledge of the large bay window. Sid opened the safe, and removed the bag of jewels. \"I'm sure these jewels will fetch a fortune for charity,\" said a smiling Sid. \"I'll bet these jewels are either fake or there's a few missing,\" replied Shadow. What aroused Shadow's suspicion?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSid, who had the only key, said that neither he nor anyone else had been in the room for the past week. If this were true, the leaves of the plant would have been leaning toward the window instead of the wall.\n<|im_start|>answer\nSid, who had the only key, said that neither he nor anyone else had been in the room for the past week. If this were true, the leaves of the plant would have been leaning toward the window instead of the wall.\n<|im_end|>" }, { "id": "#1566", "title": "Post Office Burglary", "fun": 2.64, "difficulty": 1.6, "author": "psychodude57", "desc": "After a local Post Office burglary, five suspects were being interviewed. Below is a summary of their statements. Police know that each of them told the truth in one of the statements and lied in the other. From this information can you tell who committed the crime? \n\r\nBrian said:\r\nIt wasn't Charles\r\nIt was Alan\n\r\nDerek said:\r\nIt was Charles\r\nIt wasn't Alan\n\r\nCharles said:\r\nIt was Brian\r\nIt wasn't Eric\n\r\nAlan said:\r\nIt was Eric\r\nIt wasn't Brian\n\r\nEric said:\r\nIt was Derek\r\nIt was Alan", "hint": "No hint available.", "answer": "Derek was the culprit", "category": "Logic", "date": "12/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter a local Post Office burglary, five suspects were being interviewed. Below is a summary of their statements. Police know that each of them told the truth in one of the statements and lied in the other. From this information can you tell who committed the crime? \n\r\nBrian said:\r\nIt wasn't Charles\r\nIt was Alan\n\r\nDerek said:\r\nIt was Charles\r\nIt wasn't Alan\n\r\nCharles said:\r\nIt was Brian\r\nIt wasn't Eric\n\r\nAlan said:\r\nIt was Eric\r\nIt wasn't Brian\n\r\nEric said:\r\nIt was Derek\r\nIt was Alan\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDerek was the culprit\n<|im_start|>answer\nDerek was the culprit\n<|im_end|>" }, { "id": "#14065", "title": "Gamble & Proctor", "fun": 2.64, "difficulty": 2.3, "author": "taniapereira99", "desc": "Two couples, Mr. and Mrs. Gamble and Mr. and Mrs. Proctor, decide to have a friendly game of golf together (The Proctors vs the Gambles). The result was that both teams scored a total of 187 points. Determine from the statements below, each player's first and last name, and individual score.\n\r\n1. Justin's score was not the lowest, but was lower than the average score.\n\r\n2. Cathy's score was three strokes higher than Sue's.\n\r\n3. There was only a one stroke difference between the scores of Mr. and Mrs. Gamble.\n\r\n4. The average score of the men (Justin and Phil) was two strokes higher than of the two women.", "hint": "187/2 = average = 93.5", "answer": "Sue Proctor scored 91\r\nJustin Gamble scored 93\r\nPhil Proctor scored 96\r\nCathy Gamble scored 94\n\r\nFrom 3 it can be determined that the Gambles scored 93 and 94. From 4 the average score of the two men was 94.5 and of the women was 92.5. \r\nFrom 2 Cathy must have had 94 and Sue 91. \r\nFrom 1 the last names can be determined.", "category": "Logic", "date": "07/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo couples, Mr. and Mrs. Gamble and Mr. and Mrs. Proctor, decide to have a friendly game of golf together (The Proctors vs the Gambles). The result was that both teams scored a total of 187 points. Determine from the statements below, each player's first and last name, and individual score.\n\r\n1. Justin's score was not the lowest, but was lower than the average score.\n\r\n2. Cathy's score was three strokes higher than Sue's.\n\r\n3. There was only a one stroke difference between the scores of Mr. and Mrs. Gamble.\n\r\n4. The average score of the men (Justin and Phil) was two strokes higher than of the two women.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSue Proctor scored 91\r\nJustin Gamble scored 93\r\nPhil Proctor scored 96\r\nCathy Gamble scored 94\n\r\nFrom 3 it can be determined that the Gambles scored 93 and 94. From 4 the average score of the two men was 94.5 and of the women was 92.5. \r\nFrom 2 Cathy must have had 94 and Sue 91. \r\nFrom 1 the last names can be determined.\n<|im_start|>answer\nSue Proctor scored 91\r\nJustin Gamble scored 93\r\nPhil Proctor scored 96\r\nCathy Gamble scored 94\n\r\nFrom 3 it can be determined that the Gambles scored 93 and 94. From 4 the average score of the two men was 94.5 and of the women was 92.5. \r\nFrom 2 Cathy must have had 94 and Sue 91. \r\nFrom 1 the last names can be determined.\n<|im_end|>" }, { "id": "#24501", "title": "Scrabble Contest", "fun": 2.64, "difficulty": 1.67, "author": "katey", "desc": "At the local games evening, four lads were competing in the Scrabble and chess competitions. Liam beat Mark in chess, James came third and the 16 year old won. Liam came second in Scrabble, the 15 year old won; James beat the 18 year old and the 19 year old came third. Kevin is 3 years younger than Mark. The person who came last in chess, came third in Scrabble and only one lad got the same position in both games. Can you determine the ages of the lads and the positions in the two games?", "hint": "No hint available.", "answer": "James (15) Scrabble: 1st - Chess: 3rd\r\nKevin(16) Scrabble: 4th - Chess: 1st\r\nLiam (18) Scrabble: 2nd - Chess: 2nd\r\nMark (19) Scrabble: 3rd - Chess: 4th", "category": "Logic", "date": "07/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the local games evening, four lads were competing in the Scrabble and chess competitions. Liam beat Mark in chess, James came third and the 16 year old won. Liam came second in Scrabble, the 15 year old won; James beat the 18 year old and the 19 year old came third. Kevin is 3 years younger than Mark. The person who came last in chess, came third in Scrabble and only one lad got the same position in both games. Can you determine the ages of the lads and the positions in the two games?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJames (15) Scrabble: 1st - Chess: 3rd\r\nKevin(16) Scrabble: 4th - Chess: 1st\r\nLiam (18) Scrabble: 2nd - Chess: 2nd\r\nMark (19) Scrabble: 3rd - Chess: 4th\n<|im_start|>answer\nJames (15) Scrabble: 1st - Chess: 3rd\r\nKevin(16) Scrabble: 4th - Chess: 1st\r\nLiam (18) Scrabble: 2nd - Chess: 2nd\r\nMark (19) Scrabble: 3rd - Chess: 4th\n<|im_end|>" }, { "id": "#41591", "title": "Paintball War", "fun": 2.64, "difficulty": 2.23, "author": "Carlos16", "desc": "There are four people involved in a free for all paintball war. Once someone is shot down, they are out and can no longer shoot. If the last person standing is the only one telling the truth, then who is it?\n\r\nRJ: I was the last person standing.\r\nLori: I was the last to get shot down.\r\nConnor: Glebb shot down RJ.\r\nGlebb: Connor was out before RJ.", "hint": "No hint available.", "answer": "Lori cannot be the last person standing, otherwise she'd be telling the truth that she got shot down. Lori is lying and was therefore either the first or second to get shot down. If Glebb is the last one standing, then Connor got shot down before RJ. Connor and Lori would have to be the first 2 shot down. RJ would be the last to get shot down, but then Connor would be telling the truth since Glebb is the only person left to shoot RJ. Since there is a contradiction, Glebb cannot be the last man standing; it was either RJ or Connor. It can't be RJ because then Glebb would be telling the truth that Connor did worse than RJ. Now we know Connor was the last man standing by process of elimination.\n\r\nAnswer: Connor", "category": "Logic", "date": "04/19/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four people involved in a free for all paintball war. Once someone is shot down, they are out and can no longer shoot. If the last person standing is the only one telling the truth, then who is it?\n\r\nRJ: I was the last person standing.\r\nLori: I was the last to get shot down.\r\nConnor: Glebb shot down RJ.\r\nGlebb: Connor was out before RJ.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLori cannot be the last person standing, otherwise she'd be telling the truth that she got shot down. Lori is lying and was therefore either the first or second to get shot down. If Glebb is the last one standing, then Connor got shot down before RJ. Connor and Lori would have to be the first 2 shot down. RJ would be the last to get shot down, but then Connor would be telling the truth since Glebb is the only person left to shoot RJ. Since there is a contradiction, Glebb cannot be the last man standing; it was either RJ or Connor. It can't be RJ because then Glebb would be telling the truth that Connor did worse than RJ. Now we know Connor was the last man standing by process of elimination.\n\r\nAnswer: Connor\n<|im_start|>answer\nLori cannot be the last person standing, otherwise she'd be telling the truth that she got shot down. Lori is lying and was therefore either the first or second to get shot down. If Glebb is the last one standing, then Connor got shot down before RJ. Connor and Lori would have to be the first 2 shot down. RJ would be the last to get shot down, but then Connor would be telling the truth since Glebb is the only person left to shoot RJ. Since there is a contradiction, Glebb cannot be the last man standing; it was either RJ or Connor. It can't be RJ because then Glebb would be telling the truth that Connor did worse than RJ. Now we know Connor was the last man standing by process of elimination.\n\r\nAnswer: Connor\n<|im_end|>" }, { "id": "#18511", "title": "Liars", "fun": 2.64, "difficulty": 1.44, "author": "AXTON", "desc": "Sally lies on Wednesday, Thursday, Friday, Saturday and Sunday; but tells the truth on all other days. John lies on Sunday, Monday and Tuesday; but tells the truth on all other days.\r\nOne day Sally and John had lunch together. One exclaimed 'I lied yesterday'.\r\nThe other replied 'Me too'.\n\r\nON WHICH DAY DID THEY HAVE LUNCH TOGETHER?", "hint": "A table can be useful...", "answer": "Wednesday\n\r\n- John lied on Tuesday and is telling her the truth, because he tells the truth on Wednesdays.\r\n- Sally is lying to John as she lies on Wednesday, but told the truth on Tuesday.", "category": "Logic", "date": "08/10/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally lies on Wednesday, Thursday, Friday, Saturday and Sunday; but tells the truth on all other days. John lies on Sunday, Monday and Tuesday; but tells the truth on all other days.\r\nOne day Sally and John had lunch together. One exclaimed 'I lied yesterday'.\r\nThe other replied 'Me too'.\n\r\nON WHICH DAY DID THEY HAVE LUNCH TOGETHER?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWednesday\n\r\n- John lied on Tuesday and is telling her the truth, because he tells the truth on Wednesdays.\r\n- Sally is lying to John as she lies on Wednesday, but told the truth on Tuesday.\n<|im_start|>answer\nWednesday\n\r\n- John lied on Tuesday and is telling her the truth, because he tells the truth on Wednesdays.\r\n- Sally is lying to John as she lies on Wednesday, but told the truth on Tuesday.\n<|im_end|>" }, { "id": "#28133", "title": "Opposites 4", "fun": 2.64, "difficulty": 1.97, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n[ stands for A, G, L, N, or I\r\n] stands for E, F, Y, S, or A\r\n/ stands for B, U, C, W, or T\r\n^ stands for M, O, E, P, or S\n\r\nThe four letter code word, ][^/, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Fast and Slow.", "category": "Logic", "date": "01/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n[ stands for A, G, L, N, or I\r\n] stands for E, F, Y, S, or A\r\n/ stands for B, U, C, W, or T\r\n^ stands for M, O, E, P, or S\n\r\nThe four letter code word, ][^/, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFast and Slow.\n<|im_start|>answer\nFast and Slow.\n<|im_end|>" }, { "id": "#14506", "title": "What's the Time?", "fun": 2.63, "difficulty": 1.96, "author": "Smithy", "desc": "At a certain time I looked at a 24-hour digital clock and noticed some things about the time:\n\r\n1) The number in the hours section plus the number in the minutes section makes 60.\n\r\n2) One of the digits in the minutes section is the square root of the other digit in the minutes section.\n\r\n3) The sum of the digits in the minutes section is the number in the hours section reversed. What was the time?", "hint": "No hint available.", "answer": "From clue 2 we know the time has to be : ??:00, ??:11, ??:24, ??:42 or ??:39. \r\nFor clue 1 to work the times would have to be : 60:00, 49:11, 36:24, 18:42 or 21:39. Of these only 18:42 and 21:39 could show up on a 24 hour clock. \n\r\n4+2 does not equal 81 so 18:42 doesn't work for clue 3. 3+9 does equal twelve, so the time was 21:39.", "category": "Math", "date": "08/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a certain time I looked at a 24-hour digital clock and noticed some things about the time:\n\r\n1) The number in the hours section plus the number in the minutes section makes 60.\n\r\n2) One of the digits in the minutes section is the square root of the other digit in the minutes section.\n\r\n3) The sum of the digits in the minutes section is the number in the hours section reversed. What was the time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom clue 2 we know the time has to be : ??:00, ??:11, ??:24, ??:42 or ??:39. \r\nFor clue 1 to work the times would have to be : 60:00, 49:11, 36:24, 18:42 or 21:39. Of these only 18:42 and 21:39 could show up on a 24 hour clock. \n\r\n4+2 does not equal 81 so 18:42 doesn't work for clue 3. 3+9 does equal twelve, so the time was 21:39.\n<|im_start|>answer\nFrom clue 2 we know the time has to be : ??:00, ??:11, ??:24, ??:42 or ??:39. \r\nFor clue 1 to work the times would have to be : 60:00, 49:11, 36:24, 18:42 or 21:39. Of these only 18:42 and 21:39 could show up on a 24 hour clock. \n\r\n4+2 does not equal 81 so 18:42 doesn't work for clue 3. 3+9 does equal twelve, so the time was 21:39.\n<|im_end|>" }, { "id": "#42418", "title": "Neighborly Number", "fun": 2.63, "difficulty": 2.3, "author": "GrayPanther", "desc": "AJ, Celeste, Juan, Kara, Lily, and Randy all live on Redwood Avenue. Each of their house numbers has three digits, but the only digits in their house numbers are 2, 3, 5, and 6. The same digit may appear twice in one of the addresses. \n\r\nAJ's house number is Juan's house number doubled. \r\nJuan lives next to Lily and right across from Randy. \r\nRandy's number is the lowest on the street. \r\nCeleste's number is a higher number than AJ's but has the same three digits as his. They both have the same digit in the hundreds place. \r\nKara's house number is the reverse of Juan's. \r\nWhat is each person's street address?", "hint": "1. Make a chart listing the possible combinations of digits, and then use the clues to eliminate the impossibilities. \r\n2. Remember, street addresses have all the odd numbers on one side, and the even numbers on the other.", "answer": "AJ's street address is 526 Redwood Avenue.\r\nCeleste's street address is 562 Redwood Avenue.\r\nJuan's street address is 263 Redwood Avenue.\r\nKara's street address is 362 Redwood Avenue.\r\nLily's street address is 265 Redwood Avenue.\r\nRandy's street address is 262 Redwood Avenue.", "category": "Logic", "date": "07/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAJ, Celeste, Juan, Kara, Lily, and Randy all live on Redwood Avenue. Each of their house numbers has three digits, but the only digits in their house numbers are 2, 3, 5, and 6. The same digit may appear twice in one of the addresses. \n\r\nAJ's house number is Juan's house number doubled. \r\nJuan lives next to Lily and right across from Randy. \r\nRandy's number is the lowest on the street. \r\nCeleste's number is a higher number than AJ's but has the same three digits as his. They both have the same digit in the hundreds place. \r\nKara's house number is the reverse of Juan's. \r\nWhat is each person's street address?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAJ's street address is 526 Redwood Avenue.\r\nCeleste's street address is 562 Redwood Avenue.\r\nJuan's street address is 263 Redwood Avenue.\r\nKara's street address is 362 Redwood Avenue.\r\nLily's street address is 265 Redwood Avenue.\r\nRandy's street address is 262 Redwood Avenue.\n<|im_start|>answer\nAJ's street address is 526 Redwood Avenue.\r\nCeleste's street address is 562 Redwood Avenue.\r\nJuan's street address is 263 Redwood Avenue.\r\nKara's street address is 362 Redwood Avenue.\r\nLily's street address is 265 Redwood Avenue.\r\nRandy's street address is 262 Redwood Avenue.\n<|im_end|>" }, { "id": "#32640", "title": "Bicycle Lock", "fun": 2.63, "difficulty": 2.07, "author": "moonsliver86", "desc": "Alex, my very mathematical but forgetful friend, made an elaborate code to remember the 10-digit combination to his bicycle lock. He came up with:\n\r\nA - K - B - J - C - H - D - G - E - F \n\r\nwhere each letter stands for a different digit (0-9).\n\r\nSometimes a scatterbrain, he wanted to make sure that he would remember his combination so he wrote down this series of mathematical clues: \n\r\n1) D + D + D = F\r\n2) B / H = K\r\n3) J / D = K\r\n4) H + H = B\r\n5) D x H = CK\r\n6) D / J = H / B\r\n7) G + B + E = F + A + C\r\n8) A x H = KE\t\r\n9) J + A = CC\r\n10) F x D = KG\n\r\nWhat is the 10-digit combination to Alex's bicycle lock?\n\r\n>>>\r\nNote: CK, KE, CC, & KG are two-digit numbers.", "hint": "No hint available.", "answer": "A = 5, B = 8, C = 1, D = 3, E = 0, F = 9, G = 7, H = 4, J = 6, K = 2\n\r\nThe combination is 5-2-8-6-1-4-3-7-0-9.", "category": "Math", "date": "08/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlex, my very mathematical but forgetful friend, made an elaborate code to remember the 10-digit combination to his bicycle lock. He came up with:\n\r\nA - K - B - J - C - H - D - G - E - F \n\r\nwhere each letter stands for a different digit (0-9).\n\r\nSometimes a scatterbrain, he wanted to make sure that he would remember his combination so he wrote down this series of mathematical clues: \n\r\n1) D + D + D = F\r\n2) B / H = K\r\n3) J / D = K\r\n4) H + H = B\r\n5) D x H = CK\r\n6) D / J = H / B\r\n7) G + B + E = F + A + C\r\n8) A x H = KE\t\r\n9) J + A = CC\r\n10) F x D = KG\n\r\nWhat is the 10-digit combination to Alex's bicycle lock?\n\r\n>>>\r\nNote: CK, KE, CC, & KG are two-digit numbers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA = 5, B = 8, C = 1, D = 3, E = 0, F = 9, G = 7, H = 4, J = 6, K = 2\n\r\nThe combination is 5-2-8-6-1-4-3-7-0-9.\n<|im_start|>answer\nA = 5, B = 8, C = 1, D = 3, E = 0, F = 9, G = 7, H = 4, J = 6, K = 2\n\r\nThe combination is 5-2-8-6-1-4-3-7-0-9.\n<|im_end|>" }, { "id": "#30055", "title": "Three Statements III", "fun": 2.63, "difficulty": 1.22, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. If you hold up your right hand in the mirror your image would appear to be holding up its right hand. \n\r\n2. 17 minutes until 9 o'clock is the same as 8:43.\n\r\n3. A group of old ladies meet for an afternoon tea party. They bring all their cats. In all there are 22 heads and 72 feet. This means that there are 7 old ladies and 15 cats in the room.", "hint": "No hint available.", "answer": "Statement 2 is true, and statements 1 and 3 are false.\n\r\nIn statement 1, the mirror image of a right hand is a left hand.\n\r\nIn statement 2, 60-17=43, and it is true.\n\r\nIn statement 3, 7*2+15*4=74, which is 2 more than 72, hence there are, in fact, 8 old ladies and 14 cats in the room.", "category": "Logic", "date": "04/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. If you hold up your right hand in the mirror your image would appear to be holding up its right hand. \n\r\n2. 17 minutes until 9 o'clock is the same as 8:43.\n\r\n3. A group of old ladies meet for an afternoon tea party. They bring all their cats. In all there are 22 heads and 72 feet. This means that there are 7 old ladies and 15 cats in the room.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement 2 is true, and statements 1 and 3 are false.\n\r\nIn statement 1, the mirror image of a right hand is a left hand.\n\r\nIn statement 2, 60-17=43, and it is true.\n\r\nIn statement 3, 7*2+15*4=74, which is 2 more than 72, hence there are, in fact, 8 old ladies and 14 cats in the room.\n<|im_start|>answer\nStatement 2 is true, and statements 1 and 3 are false.\n\r\nIn statement 1, the mirror image of a right hand is a left hand.\n\r\nIn statement 2, 60-17=43, and it is true.\n\r\nIn statement 3, 7*2+15*4=74, which is 2 more than 72, hence there are, in fact, 8 old ladies and 14 cats in the room.\n<|im_end|>" }, { "id": "#26783", "title": "OSTRICHES", "fun": 2.63, "difficulty": 1.95, "author": "dodger", "desc": "Two ostrich breeders, Mandy and Marcia, were talking one day, and noticed that if Mandy sold Marcia seven ostriches, Mandy would have exactly as many ostriches as Marcia. \n\n\n\r\n On the other hand, if Marcia sold Mandy seven ostriches, then Mandy would have exactly twice as many ostriches as Marcia. How many ostriches did each have?", "hint": "No hint available.", "answer": "Mandy had 49 and Marcia had 35", "category": "Math", "date": "11/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo ostrich breeders, Mandy and Marcia, were talking one day, and noticed that if Mandy sold Marcia seven ostriches, Mandy would have exactly as many ostriches as Marcia. \n\n\n\r\n On the other hand, if Marcia sold Mandy seven ostriches, then Mandy would have exactly twice as many ostriches as Marcia. How many ostriches did each have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMandy had 49 and Marcia had 35\n<|im_start|>answer\nMandy had 49 and Marcia had 35\n<|im_end|>" }, { "id": "#23687", "title": "N & G", "fun": 2.63, "difficulty": 2.1, "author": "Palsha", "desc": "The five top readers at the middle school are shown in this puzzle. It's your job to figure out how many books each student read, their initials, and their room numbers from the clues presented below.\n\r\n1) B, who is not L, read 3/4 as many books as S.\r\n2) G is in Room 103.\r\n3) M read four more books than N and two more than P.\r\n4) L's room is between N's and G's.\r\n5) V read more books than N, who read more than L.\r\n6) The student from Room 104 read eight books fewer than the student in Room 101.\r\n7) T's classroom is 102.", "hint": "No hint available.", "answer": "1) NR from Room 105 read 20 books.\r\n2) BT from Room 102 read 12 books.\r\n3) VM from Room 101 read 24 books.\r\n4) SL from Room 104 read 16 books.\r\n5) GP from Room 103 read 22 books.", "category": "Logic-Grid", "date": "06/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe five top readers at the middle school are shown in this puzzle. It's your job to figure out how many books each student read, their initials, and their room numbers from the clues presented below.\n\r\n1) B, who is not L, read 3/4 as many books as S.\r\n2) G is in Room 103.\r\n3) M read four more books than N and two more than P.\r\n4) L's room is between N's and G's.\r\n5) V read more books than N, who read more than L.\r\n6) The student from Room 104 read eight books fewer than the student in Room 101.\r\n7) T's classroom is 102.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) NR from Room 105 read 20 books.\r\n2) BT from Room 102 read 12 books.\r\n3) VM from Room 101 read 24 books.\r\n4) SL from Room 104 read 16 books.\r\n5) GP from Room 103 read 22 books.\n<|im_start|>answer\n1) NR from Room 105 read 20 books.\r\n2) BT from Room 102 read 12 books.\r\n3) VM from Room 101 read 24 books.\r\n4) SL from Room 104 read 16 books.\r\n5) GP from Room 103 read 22 books.\n<|im_end|>" }, { "id": "#49849", "title": "Scrabble Babble", "fun": 2.63, "difficulty": 3.31, "author": "spikethru4", "desc": "Twelve players took part in a Scrabble tournament, where each played seven games against different opponents. From the clues below, can you work out what order the top five finished in, how many games they won, their last opponent, and their highest word (HW) and game (HG) scores for the tournament?\n\r\nTop 5: Chris (m), Dianne (f), Edie (f), Russell (m), Sally (f)\r\nOpponents: Carolyn (f), Judy (f), Mark (m), Russell (m), Sally (f)\r\nGames won: 4, 4.5, 5, 5.5, 6\r\nHigh Game scores: 470, ?, 576, ?, 601\r\nHigh Word scores: 90, ?, 97, ?, 121\n\r\nYou will need to determine the missing high game and high word scores. They are presented in numerical order, and all the scores are different. Note also that a drawn game counts as half a win for both players.\n\r\nClues:\r\n1. The top five players were, in some order: the eventual winner; Carolyn's final opponent; the player with the best game score; the player with the best word score; and Chris.\r\n2. Sally got off to a bad start, losing both her opening games before winning her third.\r\n3. The only tie of the tournament was played between two ladies in game 3.\r\n4. Edie's best game score was a perfect square; the only other player to achieve this came third.\r\n5. The two players whose high game scores were in the 500's had high word scores ending in 5.\r\n6. Only one of the top five played someone of the same gender in the last game; the winner of that match scored 576, their best score for the day.\r\n7. Dianne was delighted to join the '600 Club' in game 5 against Carolyn; this eclipsed Russell's best by 4 points. \r\n8. The champion's highest word score was exactly eight more than that of Mark's last opponent, who finished below Chris.", "hint": "Two of the top five played each other in the final round.\n\r\nIf you haven't worked out the missing High Game scores, check clues 4, 5 & 7.\n\r\nIf you haven't worked out the missing High Word scores, check clues 5 & 8.", "answer": "Pos - Name - Wins - Last Opp - HG - HW\r\n1 - Russell - 6 - Sally - 597 - 105\r\n2 - Edie - 5.5 - Carolyn - 576 - 95\r\n3 - Chris 5 - Judy - 484 - 90\r\n4 - Dianne - 4.5 - Mark - 601 - 97\r\n5. Sally - 4 - Russell - 470 - 121\n\r\nExplanation:\n\r\nSally and Russell must have played each other in the last game. Carolyn didn't play Chris last (Clue 1), and she played Dianne in game 5 (Clue 7), so she must have been Edie's final opponent. Clue 6 tells us the other games were between players of different genders, so Chris played Judy and Dianne played Mark.\n\r\nClue 3 tells us there was only one tied game, between two ladies in round 3. However, Sally could not have been one of them, because she won her third game (Clue 2). So Dianne and Edie must have finished with 4.5 and 5.5, in some order. We know that Mark's opponent (Dianne) finished below Chris (Clue 8) and that Chris did not win overall (Clue 1), so Dianne won 4.5 and Edie 5.5, and Chris therefore won 5. Sally couldn't have won 6 games, as she lost her first two (Clue 2), so Russell must have won 6 and Sally 4. \n\r\nDianne's high game (HG) was 601 and Russell's 597 (Clue 7). Clue 5 tells us that there were only two 500-games, so the other missing score is a perfect square between 471 and 499 (Clue 4), therefore it's 484 (22^2). Clue 4 also says this was scored by the player who came third, i.e. Chris. Clues 4 and 6 tell us Edie scored 576, which leaves Sally with 470.\n\r\nThe missing high word (HW) scores both end in 5 (Clue 5). One must be 95 and the other is either 105 or 115. Clue 8 says there must be a gap of 8 between scores, so 105 is the only possibility. This was Russell's HW and so Dianne scored 97 (also Clue 8). Edie had the other 500-game, so must have the HW of 95 (Clue 5). Chris didn't get the highest word score (Clue 1), so he scored 90 and Sally 121.", "category": "Logic-Grid", "date": "07/01/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwelve players took part in a Scrabble tournament, where each played seven games against different opponents. From the clues below, can you work out what order the top five finished in, how many games they won, their last opponent, and their highest word (HW) and game (HG) scores for the tournament?\n\r\nTop 5: Chris (m), Dianne (f), Edie (f), Russell (m), Sally (f)\r\nOpponents: Carolyn (f), Judy (f), Mark (m), Russell (m), Sally (f)\r\nGames won: 4, 4.5, 5, 5.5, 6\r\nHigh Game scores: 470, ?, 576, ?, 601\r\nHigh Word scores: 90, ?, 97, ?, 121\n\r\nYou will need to determine the missing high game and high word scores. They are presented in numerical order, and all the scores are different. Note also that a drawn game counts as half a win for both players.\n\r\nClues:\r\n1. The top five players were, in some order: the eventual winner; Carolyn's final opponent; the player with the best game score; the player with the best word score; and Chris.\r\n2. Sally got off to a bad start, losing both her opening games before winning her third.\r\n3. The only tie of the tournament was played between two ladies in game 3.\r\n4. Edie's best game score was a perfect square; the only other player to achieve this came third.\r\n5. The two players whose high game scores were in the 500's had high word scores ending in 5.\r\n6. Only one of the top five played someone of the same gender in the last game; the winner of that match scored 576, their best score for the day.\r\n7. Dianne was delighted to join the '600 Club' in game 5 against Carolyn; this eclipsed Russell's best by 4 points. \r\n8. The champion's highest word score was exactly eight more than that of Mark's last opponent, who finished below Chris.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPos - Name - Wins - Last Opp - HG - HW\r\n1 - Russell - 6 - Sally - 597 - 105\r\n2 - Edie - 5.5 - Carolyn - 576 - 95\r\n3 - Chris 5 - Judy - 484 - 90\r\n4 - Dianne - 4.5 - Mark - 601 - 97\r\n5. Sally - 4 - Russell - 470 - 121\n\r\nExplanation:\n\r\nSally and Russell must have played each other in the last game. Carolyn didn't play Chris last (Clue 1), and she played Dianne in game 5 (Clue 7), so she must have been Edie's final opponent. Clue 6 tells us the other games were between players of different genders, so Chris played Judy and Dianne played Mark.\n\r\nClue 3 tells us there was only one tied game, between two ladies in round 3. However, Sally could not have been one of them, because she won her third game (Clue 2). So Dianne and Edie must have finished with 4.5 and 5.5, in some order. We know that Mark's opponent (Dianne) finished below Chris (Clue 8) and that Chris did not win overall (Clue 1), so Dianne won 4.5 and Edie 5.5, and Chris therefore won 5. Sally couldn't have won 6 games, as she lost her first two (Clue 2), so Russell must have won 6 and Sally 4. \n\r\nDianne's high game (HG) was 601 and Russell's 597 (Clue 7). Clue 5 tells us that there were only two 500-games, so the other missing score is a perfect square between 471 and 499 (Clue 4), therefore it's 484 (22^2). Clue 4 also says this was scored by the player who came third, i.e. Chris. Clues 4 and 6 tell us Edie scored 576, which leaves Sally with 470.\n\r\nThe missing high word (HW) scores both end in 5 (Clue 5). One must be 95 and the other is either 105 or 115. Clue 8 says there must be a gap of 8 between scores, so 105 is the only possibility. This was Russell's HW and so Dianne scored 97 (also Clue 8). Edie had the other 500-game, so must have the HW of 95 (Clue 5). Chris didn't get the highest word score (Clue 1), so he scored 90 and Sally 121.\n<|im_start|>answer\nPos - Name - Wins - Last Opp - HG - HW\r\n1 - Russell - 6 - Sally - 597 - 105\r\n2 - Edie - 5.5 - Carolyn - 576 - 95\r\n3 - Chris 5 - Judy - 484 - 90\r\n4 - Dianne - 4.5 - Mark - 601 - 97\r\n5. Sally - 4 - Russell - 470 - 121\n\r\nExplanation:\n\r\nSally and Russell must have played each other in the last game. Carolyn didn't play Chris last (Clue 1), and she played Dianne in game 5 (Clue 7), so she must have been Edie's final opponent. Clue 6 tells us the other games were between players of different genders, so Chris played Judy and Dianne played Mark.\n\r\nClue 3 tells us there was only one tied game, between two ladies in round 3. However, Sally could not have been one of them, because she won her third game (Clue 2). So Dianne and Edie must have finished with 4.5 and 5.5, in some order. We know that Mark's opponent (Dianne) finished below Chris (Clue 8) and that Chris did not win overall (Clue 1), so Dianne won 4.5 and Edie 5.5, and Chris therefore won 5. Sally couldn't have won 6 games, as she lost her first two (Clue 2), so Russell must have won 6 and Sally 4. \n\r\nDianne's high game (HG) was 601 and Russell's 597 (Clue 7). Clue 5 tells us that there were only two 500-games, so the other missing score is a perfect square between 471 and 499 (Clue 4), therefore it's 484 (22^2). Clue 4 also says this was scored by the player who came third, i.e. Chris. Clues 4 and 6 tell us Edie scored 576, which leaves Sally with 470.\n\r\nThe missing high word (HW) scores both end in 5 (Clue 5). One must be 95 and the other is either 105 or 115. Clue 8 says there must be a gap of 8 between scores, so 105 is the only possibility. This was Russell's HW and so Dianne scored 97 (also Clue 8). Edie had the other 500-game, so must have the HW of 95 (Clue 5). Chris didn't get the highest word score (Clue 1), so he scored 90 and Sally 121.\n<|im_end|>" }, { "id": "#42312", "title": "Front Row of Math Class", "fun": 2.63, "difficulty": 1.21, "author": "whsprec", "desc": "In a math class there were 5 students who sat in the front row. Their seats were numbered 1-5 from left to right. There were 3 boys, John, David, and Bob, and 2 girls, Mary and Danielle. Each student wore a different color: green, brown, blue, pink, or red. Match the student to the color they were wearing and the seat in which they sat.\n\r\n1) The girls wore colors which had 5 letters.\r\n2) The person in blue and the person in green had the most distance between them.\r\n3) Neither Danielle nor Bob sat in the 4th seat.\r\n4) Neither Danielle nor Bob sat on the ends, and John did not wear pink.\r\n5) The person in pink sat to the right of the person in blue.\r\n6) David wore red.", "hint": "No hint available.", "answer": "1st seat, John, wearing blue\r\n2nd seat, Bob, wearing pink\r\n3rd seat, Danielle, wearing brown\r\n4th seat, David, wearing red\r\n5th seat, Mary, wearing green", "category": "Logic-Grid", "date": "06/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a math class there were 5 students who sat in the front row. Their seats were numbered 1-5 from left to right. There were 3 boys, John, David, and Bob, and 2 girls, Mary and Danielle. Each student wore a different color: green, brown, blue, pink, or red. Match the student to the color they were wearing and the seat in which they sat.\n\r\n1) The girls wore colors which had 5 letters.\r\n2) The person in blue and the person in green had the most distance between them.\r\n3) Neither Danielle nor Bob sat in the 4th seat.\r\n4) Neither Danielle nor Bob sat on the ends, and John did not wear pink.\r\n5) The person in pink sat to the right of the person in blue.\r\n6) David wore red.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st seat, John, wearing blue\r\n2nd seat, Bob, wearing pink\r\n3rd seat, Danielle, wearing brown\r\n4th seat, David, wearing red\r\n5th seat, Mary, wearing green\n<|im_start|>answer\n1st seat, John, wearing blue\r\n2nd seat, Bob, wearing pink\r\n3rd seat, Danielle, wearing brown\r\n4th seat, David, wearing red\r\n5th seat, Mary, wearing green\n<|im_end|>" }, { "id": "#14507", "title": "Mix 'n' Match", "fun": 2.63, "difficulty": 2.15, "author": "Smithy", "desc": "I have 18 gallons of water shared unequally between three buckets. Then I: \n\r\n1. Pour three quarters of the water in bucket 1 into bucket 2. \n\r\n2. Pour half of the water now in bucket 2 into bucket 3. \n\r\n3.Pour a third of the water now in bucket 3 into bucket 1. \n\r\nNow, all of the buckets contain equal amounts of water. \n\r\nHow much water did each bucket start with?", "hint": "No hint available.", "answer": "We can solve this problem by starting at the end and working backwards.\n\r\nObviously, at the end each bucket will contain 6 gallons of water. Call the buckets B1, B2 and B3.\n\r\nIf pouring a third of the water in B3 at the time into B1 leaves 6 in each, then B3 must have 9 at the time and B1 3.\n\r\nIf pouring half of B2 at the time into B3 at the time leaves 6 in B2 and 9 in B3, then B2 must contain 12 at the time and B3 contain 3. So B3 started with 3 gallons in.\n\r\nIf pouring three quarters of B1 at the time into B2 at the time leaves B1 with 3 and B2 with 12, then B1 had 12 and B2 had 3.\n\r\nSo B1 started with 12 and B2 and B3 both started with 3.", "category": "Math", "date": "08/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have 18 gallons of water shared unequally between three buckets. Then I: \n\r\n1. Pour three quarters of the water in bucket 1 into bucket 2. \n\r\n2. Pour half of the water now in bucket 2 into bucket 3. \n\r\n3.Pour a third of the water now in bucket 3 into bucket 1. \n\r\nNow, all of the buckets contain equal amounts of water. \n\r\nHow much water did each bucket start with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWe can solve this problem by starting at the end and working backwards.\n\r\nObviously, at the end each bucket will contain 6 gallons of water. Call the buckets B1, B2 and B3.\n\r\nIf pouring a third of the water in B3 at the time into B1 leaves 6 in each, then B3 must have 9 at the time and B1 3.\n\r\nIf pouring half of B2 at the time into B3 at the time leaves 6 in B2 and 9 in B3, then B2 must contain 12 at the time and B3 contain 3. So B3 started with 3 gallons in.\n\r\nIf pouring three quarters of B1 at the time into B2 at the time leaves B1 with 3 and B2 with 12, then B1 had 12 and B2 had 3.\n\r\nSo B1 started with 12 and B2 and B3 both started with 3.\n<|im_start|>answer\nWe can solve this problem by starting at the end and working backwards.\n\r\nObviously, at the end each bucket will contain 6 gallons of water. Call the buckets B1, B2 and B3.\n\r\nIf pouring a third of the water in B3 at the time into B1 leaves 6 in each, then B3 must have 9 at the time and B1 3.\n\r\nIf pouring half of B2 at the time into B3 at the time leaves 6 in B2 and 9 in B3, then B2 must contain 12 at the time and B3 contain 3. So B3 started with 3 gallons in.\n\r\nIf pouring three quarters of B1 at the time into B2 at the time leaves B1 with 3 and B2 with 12, then B1 had 12 and B2 had 3.\n\r\nSo B1 started with 12 and B2 and B3 both started with 3.\n<|im_end|>" }, { "id": "#31838", "title": "Teasergle IV", "fun": 2.63, "difficulty": 2.1, "author": "phrebh", "desc": "The incredibly popular brain teaser oriented site Teasergle, has four editors, two female (scotchweed and sourcer) and two male (feenxbum and papsquid) to ensure the quality of brain teasers being submitted. Unfortunately, there are quite a number of duplicate teasers submitted. Of the hundreds of teasers that keep getting submitted, each editor has one they love to see (Born in 1955, Extra Dollar, Light What First?, and Rooster Lays an Egg) and one they hate to see (Barman with Gun, Man in Elevator, Greater Than God, and Plane Crash on Border). They also each wrote a teaser that is constantly being duplicated (Bus Driver's Eyes, Cross the River, Pope Has It, and Riddle of the Sphinx). Using the clues below, can you determine who loves to see what duplicate, wrote which duplicated teaser, and hates to see what duplicate?\n\r\n1. It's strange that the woman who wrote Pope Has It hates to see Greater Than God.\r\n2. Feenxbum either loves to see Rooster Lays an Egg and hates Man in Elevator or wrote Cross the River.\r\n3. The four editors are sourcer, the male who wrote Riddle of the Sphinx, the editor who loves Extra Dollar, and the one who hates to see Barman with Gun.\r\n4. Feenxbum loves any duplicate with an animal in its name.\r\n5. The woman who loves Born in 1955 wrote Cross the River.\r\n6. The four teasers that the editors hate are Plane Crash on Border, the one that feenxbum hates, the one that is hated by the person who loves Light What First?, and the one hated by the person who wrote Pope Has It.", "hint": "No hint available.", "answer": "Feenxbum loves to see Rooster Lays an Egg, hates to see Man in Elevator, and wrote Riddle of the Sphinx.\r\nPapasquid loves to see Light What First?, hates to see Barman with Gun, and wrote Bus Driver's Eyes.\r\nScotchweed loves to see Extra Dollar, hates to see Greater Than God, and wrote Pope Has It.\r\nSourcer loves to see Born in 1955, hates to see Plane Crash on Border, and wrote Cross the River.", "category": "Logic-Grid", "date": "07/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe incredibly popular brain teaser oriented site Teasergle, has four editors, two female (scotchweed and sourcer) and two male (feenxbum and papsquid) to ensure the quality of brain teasers being submitted. Unfortunately, there are quite a number of duplicate teasers submitted. Of the hundreds of teasers that keep getting submitted, each editor has one they love to see (Born in 1955, Extra Dollar, Light What First?, and Rooster Lays an Egg) and one they hate to see (Barman with Gun, Man in Elevator, Greater Than God, and Plane Crash on Border). They also each wrote a teaser that is constantly being duplicated (Bus Driver's Eyes, Cross the River, Pope Has It, and Riddle of the Sphinx). Using the clues below, can you determine who loves to see what duplicate, wrote which duplicated teaser, and hates to see what duplicate?\n\r\n1. It's strange that the woman who wrote Pope Has It hates to see Greater Than God.\r\n2. Feenxbum either loves to see Rooster Lays an Egg and hates Man in Elevator or wrote Cross the River.\r\n3. The four editors are sourcer, the male who wrote Riddle of the Sphinx, the editor who loves Extra Dollar, and the one who hates to see Barman with Gun.\r\n4. Feenxbum loves any duplicate with an animal in its name.\r\n5. The woman who loves Born in 1955 wrote Cross the River.\r\n6. The four teasers that the editors hate are Plane Crash on Border, the one that feenxbum hates, the one that is hated by the person who loves Light What First?, and the one hated by the person who wrote Pope Has It.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFeenxbum loves to see Rooster Lays an Egg, hates to see Man in Elevator, and wrote Riddle of the Sphinx.\r\nPapasquid loves to see Light What First?, hates to see Barman with Gun, and wrote Bus Driver's Eyes.\r\nScotchweed loves to see Extra Dollar, hates to see Greater Than God, and wrote Pope Has It.\r\nSourcer loves to see Born in 1955, hates to see Plane Crash on Border, and wrote Cross the River.\n<|im_start|>answer\nFeenxbum loves to see Rooster Lays an Egg, hates to see Man in Elevator, and wrote Riddle of the Sphinx.\r\nPapasquid loves to see Light What First?, hates to see Barman with Gun, and wrote Bus Driver's Eyes.\r\nScotchweed loves to see Extra Dollar, hates to see Greater Than God, and wrote Pope Has It.\r\nSourcer loves to see Born in 1955, hates to see Plane Crash on Border, and wrote Cross the River.\n<|im_end|>" }, { "id": "#30096", "title": "Sporty Children", "fun": 2.63, "difficulty": 1.35, "author": "Psychic_Master", "desc": "The Cartidas family has several children. 5 of them play football, 4 of them play hockey, and 3 of them play tennis. Each child plays only 2 sports. What is the fewest number of children they could have?", "hint": "No hint available.", "answer": "The answer is six. Let's do a small matching up. Football: F, Hockey: H, Tennis: T\n\r\nHT, FH, FH, TF, FT, FH", "category": "Logic", "date": "04/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Cartidas family has several children. 5 of them play football, 4 of them play hockey, and 3 of them play tennis. Each child plays only 2 sports. What is the fewest number of children they could have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is six. Let's do a small matching up. Football: F, Hockey: H, Tennis: T\n\r\nHT, FH, FH, TF, FT, FH\n<|im_start|>answer\nThe answer is six. Let's do a small matching up. Football: F, Hockey: H, Tennis: T\n\r\nHT, FH, FH, TF, FT, FH\n<|im_end|>" }, { "id": "#522", "title": "Cigars", "fun": 2.63, "difficulty": 1.44, "author": "kaila912", "desc": "Because cigars cannot be entirely smoked, a hobo who collects cigar butts can make 1 cigar out of every 5 butts that he finds. Today, he has collected 25 cigar butts. How many cigars will he be able to smoke?", "hint": "No hint available.", "answer": "6; he makes 5 originals from the 25 butts he found, and after he smokes them he has 5 butts left for another cigar.", "category": "Logic", "date": "05/30/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBecause cigars cannot be entirely smoked, a hobo who collects cigar butts can make 1 cigar out of every 5 butts that he finds. Today, he has collected 25 cigar butts. How many cigars will he be able to smoke?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6; he makes 5 originals from the 25 butts he found, and after he smokes them he has 5 butts left for another cigar.\n<|im_start|>answer\n6; he makes 5 originals from the 25 butts he found, and after he smokes them he has 5 butts left for another cigar.\n<|im_end|>" }, { "id": "#32550", "title": "Condemnation", "fun": 2.63, "difficulty": 1.83, "author": "mufffin09", "desc": "Five people were condemned to a life of worshipping supernatural beings by 5 different deities from either Greek, Egyptian or Norse mythology. They were each condemned to worship a different supernatural being. Also, you'll need to find out how old they are. The people are Sarah, Jessica, Sebastian, Dana and Chandler. The deities are Circe, Odin, Osiris, Artemis, and Isis. The ages are 14, 15,15, 20, and 11. Lastly, the supernatural beings are: vampires, witches, spirits (ghosts), trolls, and werewolves. \n\r\n1. The troll worshipper is younger than the girl who worships witches.\n\r\n2. Jessica and the vampire worshipper are the same age.\n\r\n3. The Scandinavian deity would only condemn someone of Scandinavian descent.\n\r\n4. Sebastian was condemned by an Egyptian deity.\n\r\n5. The spirit worshipper and the boy condemned by Osiris are starting their sophomore year in high school (which you must be 15 to be a sophomore)\n\r\n6. Sarah follows Greek myth\n\r\n7. The 14 year old, Sarah, is friends with the girl condemned by Isis.\n\r\n8. Circe, being a witch, condemned her person to witch worship.\n\r\n9. The oldest worships werewolves.\n\r\n10. Chandler is 11 years old.\n\r\n11. Sarah is best friends with one 15 year old, and is dying to go out with the other 15 year old.\n\r\n12. The 20 year old was condemned by Artemis.\n\r\n13. The 11 year old is of Scandinavian descent.", "hint": "The Greek deities are Circe and Artemis.\n\r\nThe Egyptian deities are Osiris and Isis.\n\r\nThe Scandinavian deity is Odin.", "answer": "Sarah is 14, and was condemned by Circe to worship witches.\n\r\nJessica is 15, and was condemned by Isis to worship spirits. \n\r\nSebastian is 15, and was condemned by Osiris to worship vampires. \n\r\nDana is 20, and was condemned by Artemis to worship werewolves.\n\r\nChandler is 11, and was condemned by Odin to worship trolls.", "category": "Logic-Grid", "date": "08/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people were condemned to a life of worshipping supernatural beings by 5 different deities from either Greek, Egyptian or Norse mythology. They were each condemned to worship a different supernatural being. Also, you'll need to find out how old they are. The people are Sarah, Jessica, Sebastian, Dana and Chandler. The deities are Circe, Odin, Osiris, Artemis, and Isis. The ages are 14, 15,15, 20, and 11. Lastly, the supernatural beings are: vampires, witches, spirits (ghosts), trolls, and werewolves. \n\r\n1. The troll worshipper is younger than the girl who worships witches.\n\r\n2. Jessica and the vampire worshipper are the same age.\n\r\n3. The Scandinavian deity would only condemn someone of Scandinavian descent.\n\r\n4. Sebastian was condemned by an Egyptian deity.\n\r\n5. The spirit worshipper and the boy condemned by Osiris are starting their sophomore year in high school (which you must be 15 to be a sophomore)\n\r\n6. Sarah follows Greek myth\n\r\n7. The 14 year old, Sarah, is friends with the girl condemned by Isis.\n\r\n8. Circe, being a witch, condemned her person to witch worship.\n\r\n9. The oldest worships werewolves.\n\r\n10. Chandler is 11 years old.\n\r\n11. Sarah is best friends with one 15 year old, and is dying to go out with the other 15 year old.\n\r\n12. The 20 year old was condemned by Artemis.\n\r\n13. The 11 year old is of Scandinavian descent.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah is 14, and was condemned by Circe to worship witches.\n\r\nJessica is 15, and was condemned by Isis to worship spirits. \n\r\nSebastian is 15, and was condemned by Osiris to worship vampires. \n\r\nDana is 20, and was condemned by Artemis to worship werewolves.\n\r\nChandler is 11, and was condemned by Odin to worship trolls.\n<|im_start|>answer\nSarah is 14, and was condemned by Circe to worship witches.\n\r\nJessica is 15, and was condemned by Isis to worship spirits. \n\r\nSebastian is 15, and was condemned by Osiris to worship vampires. \n\r\nDana is 20, and was condemned by Artemis to worship werewolves.\n\r\nChandler is 11, and was condemned by Odin to worship trolls.\n<|im_end|>" }, { "id": "#32214", "title": "Harry Potter Characters in Love Stories", "fun": 2.63, "difficulty": 1.47, "author": "dishu", "desc": "After watching the fourth part of the Harry Potter movie series, the four friends went to sleep. In their dreams, they all dreamt that their different favourite characters were the lead actors of different sequels of a famous love story. They also dreamt that they were attending the premiere of these movies at different locales around the world. However, after waking up, they could only remember some parts of their dreams. With the help of the following clues, can you help them reconstruct their whole dreams?\n\r\nFriends: Dis, Dip, Raj, Rich\r\nFavourite Characters: Harry, Ron, Neville, Cedric\r\nMovie Sequel Numbers: 1, 2, 3, 4\r\nPremiere Location: Los Angeles, New York, Paris, Sydney\n\r\n1. The four movie sequels were: Part 1, the one Raj dreamt about, the one that premiered in Los Angeles, and the one starring Ron as the lead actor.\r\n2. Raj dreams about Sydney only, the place where she will eventually have her honeymoon, although that's another teaser.\r\n3. Neville's movie premiered in Paris.\r\n4. Dis always dreams about the different US states where her relatives are settled.\r\n5. Smitten by the Hollywood bug, Dip can't help dreaming about Los Angeles.\r\n6. Neither Cedric nor Harry starred in an odd-numbered sequel.\r\n7. Being very sensitive, Dip just can't get over the death of Cedric (who did not star in the last sequel), and often dreams about him.", "hint": "Assume that there were only four sequels to the famous love story and they were numbered from 1 to 4.", "answer": "Dis dreamt about attending the 3rd sequel, starring Ron, in New York, while Dip dreamt of the sequel 2 premiering in Los Angeles and starring Cedric. Raj was on cloud nine after getting an invitation to the premiere of Harry's movie (the 4th sequel) in Sydney, while Rich attended the first sequel, starring Neville, in Paris.\n\r\nCongratulations! You have solved the puzzle and the four friends thank you for returning their precious moments to them.", "category": "Logic-Grid", "date": "08/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter watching the fourth part of the Harry Potter movie series, the four friends went to sleep. In their dreams, they all dreamt that their different favourite characters were the lead actors of different sequels of a famous love story. They also dreamt that they were attending the premiere of these movies at different locales around the world. However, after waking up, they could only remember some parts of their dreams. With the help of the following clues, can you help them reconstruct their whole dreams?\n\r\nFriends: Dis, Dip, Raj, Rich\r\nFavourite Characters: Harry, Ron, Neville, Cedric\r\nMovie Sequel Numbers: 1, 2, 3, 4\r\nPremiere Location: Los Angeles, New York, Paris, Sydney\n\r\n1. The four movie sequels were: Part 1, the one Raj dreamt about, the one that premiered in Los Angeles, and the one starring Ron as the lead actor.\r\n2. Raj dreams about Sydney only, the place where she will eventually have her honeymoon, although that's another teaser.\r\n3. Neville's movie premiered in Paris.\r\n4. Dis always dreams about the different US states where her relatives are settled.\r\n5. Smitten by the Hollywood bug, Dip can't help dreaming about Los Angeles.\r\n6. Neither Cedric nor Harry starred in an odd-numbered sequel.\r\n7. Being very sensitive, Dip just can't get over the death of Cedric (who did not star in the last sequel), and often dreams about him.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDis dreamt about attending the 3rd sequel, starring Ron, in New York, while Dip dreamt of the sequel 2 premiering in Los Angeles and starring Cedric. Raj was on cloud nine after getting an invitation to the premiere of Harry's movie (the 4th sequel) in Sydney, while Rich attended the first sequel, starring Neville, in Paris.\n\r\nCongratulations! You have solved the puzzle and the four friends thank you for returning their precious moments to them.\n<|im_start|>answer\nDis dreamt about attending the 3rd sequel, starring Ron, in New York, while Dip dreamt of the sequel 2 premiering in Los Angeles and starring Cedric. Raj was on cloud nine after getting an invitation to the premiere of Harry's movie (the 4th sequel) in Sydney, while Rich attended the first sequel, starring Neville, in Paris.\n\r\nCongratulations! You have solved the puzzle and the four friends thank you for returning their precious moments to them.\n<|im_end|>" }, { "id": "#30471", "title": "Three Statements VI", "fun": 2.63, "difficulty": 1.18, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. Emile made some waffles. He ate one and gave half the remainder to his brother Robbie. After eating another one he was left with 2. This means that he made 8 waffles.\n\r\n2. Ian is helping his gym teacher. The teacher asks him to go and get 15 balls from the storage room. If Ian carries 3 balls at a time he will have to make 5 trips to the storage room.\n\r\n3. If you write down all the odd numbers from 1-15 in a row then the sum of any two numbers next to each other is odd.", "hint": "No hint available.", "answer": "Statement 2 is true, statements 1 and 3 are false.\n\r\nIn statement 1, the answer should be (2+1)*2+1=7 waffles.\n\r\nIn statement 2, 15/3=5.\n\r\nIn statement 3, the sum of two odd numbers is even.", "category": "Logic", "date": "05/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. Emile made some waffles. He ate one and gave half the remainder to his brother Robbie. After eating another one he was left with 2. This means that he made 8 waffles.\n\r\n2. Ian is helping his gym teacher. The teacher asks him to go and get 15 balls from the storage room. If Ian carries 3 balls at a time he will have to make 5 trips to the storage room.\n\r\n3. If you write down all the odd numbers from 1-15 in a row then the sum of any two numbers next to each other is odd.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement 2 is true, statements 1 and 3 are false.\n\r\nIn statement 1, the answer should be (2+1)*2+1=7 waffles.\n\r\nIn statement 2, 15/3=5.\n\r\nIn statement 3, the sum of two odd numbers is even.\n<|im_start|>answer\nStatement 2 is true, statements 1 and 3 are false.\n\r\nIn statement 1, the answer should be (2+1)*2+1=7 waffles.\n\r\nIn statement 2, 15/3=5.\n\r\nIn statement 3, the sum of two odd numbers is even.\n<|im_end|>" }, { "id": "#51023", "title": "Caesar Says", "fun": 2.63, "difficulty": 2.05, "author": "Snowdog", "desc": "Caesar says 5 = 4\r\nCaesar says 6 = 9\r\nCaesar says 9 = 1\n\r\nAccording to Caesar, 12 = ?", "hint": "Caesar says FIVE = 4\r\nCaesar says SIX = 9\r\nCaesar says NINE = 1", "answer": "12 = 55\n\r\nSpell the first number and extract the Roman numeral value of the second number.\n\r\nfIVe = 4\r\nsIX = 9\r\nnIne = 1\r\ntweLVe = 55\n\r\nCaesar never told me what 11 is equal to. Is it 55 or 50 and 5? I'll ask next time I see him.", "category": "Logic", "date": "03/26/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCaesar says 5 = 4\r\nCaesar says 6 = 9\r\nCaesar says 9 = 1\n\r\nAccording to Caesar, 12 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12 = 55\n\r\nSpell the first number and extract the Roman numeral value of the second number.\n\r\nfIVe = 4\r\nsIX = 9\r\nnIne = 1\r\ntweLVe = 55\n\r\nCaesar never told me what 11 is equal to. Is it 55 or 50 and 5? I'll ask next time I see him.\n<|im_start|>answer\n12 = 55\n\r\nSpell the first number and extract the Roman numeral value of the second number.\n\r\nfIVe = 4\r\nsIX = 9\r\nnIne = 1\r\ntweLVe = 55\n\r\nCaesar never told me what 11 is equal to. Is it 55 or 50 and 5? I'll ask next time I see him.\n<|im_end|>" }, { "id": "#40931", "title": "Inter-departmental Jam Making Contest", "fun": 2.63, "difficulty": 1.59, "author": "letmeforget9", "desc": "At the recent inter-departmental jam-making contest, four lucky candidates took part in making the juiciest strawberry jam. The ages of the contestants were 14, 17, 20 and 22. As it happens, the person who came last was the oldest, whereas Stuart was three years older than the person who came in second. James was neither the oldest nor the youngest, and Kev finished ahead of the 17 year old but didn't win. John was also unlucky this time and didn't win either. Can you determine who finished where and how old they are?", "hint": "No hint available.", "answer": "Place, Name, Age:\r\n1 James 20\r\n2 Kev 14\r\n3 Stuart 17\r\n4 John 22", "category": "Logic-Grid", "date": "03/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the recent inter-departmental jam-making contest, four lucky candidates took part in making the juiciest strawberry jam. The ages of the contestants were 14, 17, 20 and 22. As it happens, the person who came last was the oldest, whereas Stuart was three years older than the person who came in second. James was neither the oldest nor the youngest, and Kev finished ahead of the 17 year old but didn't win. John was also unlucky this time and didn't win either. Can you determine who finished where and how old they are?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPlace, Name, Age:\r\n1 James 20\r\n2 Kev 14\r\n3 Stuart 17\r\n4 John 22\n<|im_start|>answer\nPlace, Name, Age:\r\n1 James 20\r\n2 Kev 14\r\n3 Stuart 17\r\n4 John 22\n<|im_end|>" }, { "id": "#33094", "title": "I Would Rather Not be an Astronaut", "fun": 2.63, "difficulty": 1.81, "author": "bigSWAFF_69_", "desc": "In the early 1960's, NASA was sending electronic gear into outer space on unmanned missions. They'd already sent somebody into space, but they wanted to make sure that if they were going to send people up for longer flights, that they had a chance of surviving. They were sending electronic gear up to test a variety of things like radiation exposure, and so on.\n\r\nThe equipment kept failing, but they couldn't figure out why.\n\r\nFinally, someone determined that the circuits were overheating, so they installed a fan to cool off the devices.\n\r\nHowever, the problems persisted. Why?", "hint": "No hint available.", "answer": "On those early, unmanned flights they didn't pressurize the cabins. Since there is no air in outer space, and if there is no air to blow around, a fan has no effect. In fact, all it does is add heat. Kind of scary that most of us regular folk could figure this out, but the so called \"rocket scientists\" couldn't. Doesn't make me want to be an astronaut anymore...", "category": "Logic", "date": "09/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the early 1960's, NASA was sending electronic gear into outer space on unmanned missions. They'd already sent somebody into space, but they wanted to make sure that if they were going to send people up for longer flights, that they had a chance of surviving. They were sending electronic gear up to test a variety of things like radiation exposure, and so on.\n\r\nThe equipment kept failing, but they couldn't figure out why.\n\r\nFinally, someone determined that the circuits were overheating, so they installed a fan to cool off the devices.\n\r\nHowever, the problems persisted. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn those early, unmanned flights they didn't pressurize the cabins. Since there is no air in outer space, and if there is no air to blow around, a fan has no effect. In fact, all it does is add heat. Kind of scary that most of us regular folk could figure this out, but the so called \"rocket scientists\" couldn't. Doesn't make me want to be an astronaut anymore...\n<|im_start|>answer\nOn those early, unmanned flights they didn't pressurize the cabins. Since there is no air in outer space, and if there is no air to blow around, a fan has no effect. In fact, all it does is add heat. Kind of scary that most of us regular folk could figure this out, but the so called \"rocket scientists\" couldn't. Doesn't make me want to be an astronaut anymore...\n<|im_end|>" }, { "id": "#7965", "title": "Little Choc", "fun": 2.63, "difficulty": 1.53, "author": "cs526columbia", "desc": "There are two cakes for Little Choc's birthday party. One of them is Chocolate (C), the other Vanilla (V). Little Choc and his 7 other guests will each get one slice of C and one slice of V.\n\r\nSince Little Choc loooves chocolate, and it is his birthday, he proposes a slight change: rather than dividing each cake into 8 slices, divide C into 9 slices, and V into 7. This way Choc can have two C slices, and his guests can still have one slice from each cake. \n\r\nHis guests do not mind eating more of vanilla than chocolate. Being very health-conscious, though, they would mind eating more calories than they would have under the original plan. \n\r\nSo, assuming that both cakes are equal in their total number and distribution of calories, will the guests end up eating more calories under Choc's proposal or not?", "hint": "No hint available.", "answer": "YES, unfortunately for Choc and his guests, his scheme would result in a bit more calories for the guests than the original one. What each would eat now (1/7 + 1/9) is more than what they would have eaten (1/8 + 1/8).", "category": "Math", "date": "10/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two cakes for Little Choc's birthday party. One of them is Chocolate (C), the other Vanilla (V). Little Choc and his 7 other guests will each get one slice of C and one slice of V.\n\r\nSince Little Choc loooves chocolate, and it is his birthday, he proposes a slight change: rather than dividing each cake into 8 slices, divide C into 9 slices, and V into 7. This way Choc can have two C slices, and his guests can still have one slice from each cake. \n\r\nHis guests do not mind eating more of vanilla than chocolate. Being very health-conscious, though, they would mind eating more calories than they would have under the original plan. \n\r\nSo, assuming that both cakes are equal in their total number and distribution of calories, will the guests end up eating more calories under Choc's proposal or not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYES, unfortunately for Choc and his guests, his scheme would result in a bit more calories for the guests than the original one. What each would eat now (1/7 + 1/9) is more than what they would have eaten (1/8 + 1/8).\n<|im_start|>answer\nYES, unfortunately for Choc and his guests, his scheme would result in a bit more calories for the guests than the original one. What each would eat now (1/7 + 1/9) is more than what they would have eaten (1/8 + 1/8).\n<|im_end|>" }, { "id": "#14987", "title": "Insecure", "fun": 2.63, "difficulty": 1.85, "author": "jimbo", "desc": "The security manager for a large company, Mr Hugh Jintellect was giving a presentation to the board regarding the new security arrangements for the building. \"There will be a panel on each doorway with buttons numbered 1 to 5. To gain entry a person will have to enter a code consisting of 5 different digits by pressing the buttons in correct sequence.\" Jimbo spoke up and said, \"To save time why don't you make it just 4 out of the 5 numbers?\"\r\nHugh replied, \"We feel that reducing the number from 5 to only 4 digits will not provide enough combinations to exclude random guesses.\" Why was poor Hugh sacked by the board?", "hint": "How many different combinations are possible?", "answer": "Hugh was sacked because he did not realise that reducing the number of buttons from 5 to 4 leaves exactly the same number of possible combinations of different buttons.\r\nFor 5 buttons the number of combinations is 5x4x3x2x1= 120.\r\nFor 4 buttons it is 5x4x3x2 = 120.\r\nAfter you have chosen 4 different numbers from the 5, there is only one possible fifth number remaining so it adds no extra choices to the number of combinations.", "category": "Math", "date": "10/04/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe security manager for a large company, Mr Hugh Jintellect was giving a presentation to the board regarding the new security arrangements for the building. \"There will be a panel on each doorway with buttons numbered 1 to 5. To gain entry a person will have to enter a code consisting of 5 different digits by pressing the buttons in correct sequence.\" Jimbo spoke up and said, \"To save time why don't you make it just 4 out of the 5 numbers?\"\r\nHugh replied, \"We feel that reducing the number from 5 to only 4 digits will not provide enough combinations to exclude random guesses.\" Why was poor Hugh sacked by the board?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHugh was sacked because he did not realise that reducing the number of buttons from 5 to 4 leaves exactly the same number of possible combinations of different buttons.\r\nFor 5 buttons the number of combinations is 5x4x3x2x1= 120.\r\nFor 4 buttons it is 5x4x3x2 = 120.\r\nAfter you have chosen 4 different numbers from the 5, there is only one possible fifth number remaining so it adds no extra choices to the number of combinations.\n<|im_start|>answer\nHugh was sacked because he did not realise that reducing the number of buttons from 5 to 4 leaves exactly the same number of possible combinations of different buttons.\r\nFor 5 buttons the number of combinations is 5x4x3x2x1= 120.\r\nFor 4 buttons it is 5x4x3x2 = 120.\r\nAfter you have chosen 4 different numbers from the 5, there is only one possible fifth number remaining so it adds no extra choices to the number of combinations.\n<|im_end|>" }, { "id": "#4580", "title": "Making Eleven", "fun": 2.63, "difficulty": 2.21, "author": "mad-ade", "desc": "How would you combine one-third of 12 and four-fifths of 7 to get 11?", "hint": "No hint available.", "answer": "Add EL (one-third of TWELVE) to EVEN (four-fifths of SEVEN) and get ELEVEN.", "category": "Logic", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow would you combine one-third of 12 and four-fifths of 7 to get 11?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdd EL (one-third of TWELVE) to EVEN (four-fifths of SEVEN) and get ELEVEN.\n<|im_start|>answer\nAdd EL (one-third of TWELVE) to EVEN (four-fifths of SEVEN) and get ELEVEN.\n<|im_end|>" }, { "id": "#17141", "title": "All Aboard", "fun": 2.63, "difficulty": 2.25, "author": "slob", "desc": "Courtney and Megan rode the train from the station at the beginning of the line all the way to the terminal at the end of the line. When they got off the train in the city, 70 people got off along with them. Even though it was an express route, the train made 4 stops. People got on the train, but no one got off until they reached the terminal in the city. \n\r\nTwo more passengers boarded the train at the first stop. After making the second stop, the train had three times as many people as it had when it entered the station. Then, just before the doors closed, 3 more people hopped on. \n\r\nAfter the third stop, the number aboard the train was 50% more than it had been when it entered that station. The number of people getting on at the fourth stop doubled the total number of passengers. \n\r\nHow many people boarded the train with Courtney and Megan at the beginning of the line and at each additional stop?", "hint": "No hint available.", "answer": "Courtney and Megan boarded the train along with 3 other people. \n\r\n5 Started on the train \r\nFirst stop: 2 got on. \r\n7 on the train \r\nSecond stop (A): 14 got on \r\n21 = 3 x the amount on the train before 2nd stop \r\nSecond stop (B): 3 more got on before doors closed \r\n24 on the train \r\nThird stop: 12 got on \r\n36 on the train (50% more than 24) \r\nFourth stop: 36 got on to double from 36 therefore doubling the number of passengers. \r\n72 on the train, or 70 not including Courtney and Megan", "category": "Math", "date": "03/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCourtney and Megan rode the train from the station at the beginning of the line all the way to the terminal at the end of the line. When they got off the train in the city, 70 people got off along with them. Even though it was an express route, the train made 4 stops. People got on the train, but no one got off until they reached the terminal in the city. \n\r\nTwo more passengers boarded the train at the first stop. After making the second stop, the train had three times as many people as it had when it entered the station. Then, just before the doors closed, 3 more people hopped on. \n\r\nAfter the third stop, the number aboard the train was 50% more than it had been when it entered that station. The number of people getting on at the fourth stop doubled the total number of passengers. \n\r\nHow many people boarded the train with Courtney and Megan at the beginning of the line and at each additional stop?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCourtney and Megan boarded the train along with 3 other people. \n\r\n5 Started on the train \r\nFirst stop: 2 got on. \r\n7 on the train \r\nSecond stop (A): 14 got on \r\n21 = 3 x the amount on the train before 2nd stop \r\nSecond stop (B): 3 more got on before doors closed \r\n24 on the train \r\nThird stop: 12 got on \r\n36 on the train (50% more than 24) \r\nFourth stop: 36 got on to double from 36 therefore doubling the number of passengers. \r\n72 on the train, or 70 not including Courtney and Megan\n<|im_start|>answer\nCourtney and Megan boarded the train along with 3 other people. \n\r\n5 Started on the train \r\nFirst stop: 2 got on. \r\n7 on the train \r\nSecond stop (A): 14 got on \r\n21 = 3 x the amount on the train before 2nd stop \r\nSecond stop (B): 3 more got on before doors closed \r\n24 on the train \r\nThird stop: 12 got on \r\n36 on the train (50% more than 24) \r\nFourth stop: 36 got on to double from 36 therefore doubling the number of passengers. \r\n72 on the train, or 70 not including Courtney and Megan\n<|im_end|>" }, { "id": "#29856", "title": "Deduction", "fun": 2.63, "difficulty": 1.73, "author": "peppamintp", "desc": "Last Sunday evening, Donna and three other members of her yoga club dined out together. Each woman ordered either salad or soup to start with, and one of the three entrees (cabbage rolls, eggs Benedict, or lasagna). From the clues below, can you determine each woman's name and the two dishes she ordered?\n\r\n1. Every order was different. Each dish mentioned above was ordered at least once.\n\r\n2. Susan and the lady who ordered the salad both ordered lasagna as the main dish.\n\r\n3. Rita and Sarah both ordered soup as the first course.\n\r\n4. Sarah did not order the eggs Benedict.", "hint": "No hint available.", "answer": "1. Donna ordered the salad and lasagna.\r\n2. Rita ordered the soup and eggs Benedict.\r\n3. Sarah ordered the soup and cabbage rolls. \r\n4. Susan ordered the soup and lasagna.", "category": "Logic", "date": "04/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast Sunday evening, Donna and three other members of her yoga club dined out together. Each woman ordered either salad or soup to start with, and one of the three entrees (cabbage rolls, eggs Benedict, or lasagna). From the clues below, can you determine each woman's name and the two dishes she ordered?\n\r\n1. Every order was different. Each dish mentioned above was ordered at least once.\n\r\n2. Susan and the lady who ordered the salad both ordered lasagna as the main dish.\n\r\n3. Rita and Sarah both ordered soup as the first course.\n\r\n4. Sarah did not order the eggs Benedict.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Donna ordered the salad and lasagna.\r\n2. Rita ordered the soup and eggs Benedict.\r\n3. Sarah ordered the soup and cabbage rolls. \r\n4. Susan ordered the soup and lasagna.\n<|im_start|>answer\n1. Donna ordered the salad and lasagna.\r\n2. Rita ordered the soup and eggs Benedict.\r\n3. Sarah ordered the soup and cabbage rolls. \r\n4. Susan ordered the soup and lasagna.\n<|im_end|>" }, { "id": "#7498", "title": "Weirdville", "fun": 2.63, "difficulty": 1.23, "author": "dsquared", "desc": "As I was walking down a hill\r\nOf my home town, it's called \"Weirdville\"\r\nAhead of me, 3 skaters came\r\nAs if their boards, propelled by flame\r\nFor freely they went flying by\r\nNo pushing needed, they barely tried\r\nThen truly did I there behold\r\n4 skooters dashed, with blue and gold\r\nJust as the skaters had before\r\nwhistling past myself they tore.\r\nTo cap it off on this strange day\r\n2 Roller bladers entered the fray\r\nTo match the groups already seen\r\nThey passed quick like they'd never been\r\nI thought how strange, this town of mine\r\nSo many wonders, and strange signs.\n\r\nWhat is so strange about my town of Weirdville?", "hint": "The key is in the first line.", "answer": "The fact that skateboards, skooters, and roller bladers can 'freely' move 'up' hills without need for pushing. The first line mentions the fact that I was walking 'down' a hill and saw all of these groups come ahead of me and fly past me indicating that they were 'free-wheeling' up a hill? Pretty weird if you ask me :P.", "category": "Logic", "date": "09/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAs I was walking down a hill\r\nOf my home town, it's called \"Weirdville\"\r\nAhead of me, 3 skaters came\r\nAs if their boards, propelled by flame\r\nFor freely they went flying by\r\nNo pushing needed, they barely tried\r\nThen truly did I there behold\r\n4 skooters dashed, with blue and gold\r\nJust as the skaters had before\r\nwhistling past myself they tore.\r\nTo cap it off on this strange day\r\n2 Roller bladers entered the fray\r\nTo match the groups already seen\r\nThey passed quick like they'd never been\r\nI thought how strange, this town of mine\r\nSo many wonders, and strange signs.\n\r\nWhat is so strange about my town of Weirdville?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe fact that skateboards, skooters, and roller bladers can 'freely' move 'up' hills without need for pushing. The first line mentions the fact that I was walking 'down' a hill and saw all of these groups come ahead of me and fly past me indicating that they were 'free-wheeling' up a hill? Pretty weird if you ask me :P.\n<|im_start|>answer\nThe fact that skateboards, skooters, and roller bladers can 'freely' move 'up' hills without need for pushing. The first line mentions the fact that I was walking 'down' a hill and saw all of these groups come ahead of me and fly past me indicating that they were 'free-wheeling' up a hill? Pretty weird if you ask me :P.\n<|im_end|>" }, { "id": "#27938", "title": "Granola Bar Boxes", "fun": 2.63, "difficulty": 1.66, "author": "lips", "desc": "Mr. Smith needs snacks for all the students going on a field trip. He bought 9 boxes of granola bars containing a total of 88 bars. He wanted variety, so he purchased 3 different flavors, which happened to come from 3 different companies. The almond chunky granola bars were packaged 8 to a box, the chewy chocolate chip bars came 10 to a box, and the super special raisin nut package contained 12 per box. He bought the most boxes of almond chunky, but had the most raisin nut bars.\n\r\nHow many boxes of each flavor did he buy?", "hint": "Make a chart, and guess and check.", "answer": "Mr. Smith bought 4 boxes of almond chunky, 2 boxes of chewy chocolate chip, and 3 boxes of super special raisin nut granola bars.\n\r\n4*8+2*10+3*12=88.", "category": "Math", "date": "01/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Smith needs snacks for all the students going on a field trip. He bought 9 boxes of granola bars containing a total of 88 bars. He wanted variety, so he purchased 3 different flavors, which happened to come from 3 different companies. The almond chunky granola bars were packaged 8 to a box, the chewy chocolate chip bars came 10 to a box, and the super special raisin nut package contained 12 per box. He bought the most boxes of almond chunky, but had the most raisin nut bars.\n\r\nHow many boxes of each flavor did he buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Smith bought 4 boxes of almond chunky, 2 boxes of chewy chocolate chip, and 3 boxes of super special raisin nut granola bars.\n\r\n4*8+2*10+3*12=88.\n<|im_start|>answer\nMr. Smith bought 4 boxes of almond chunky, 2 boxes of chewy chocolate chip, and 3 boxes of super special raisin nut granola bars.\n\r\n4*8+2*10+3*12=88.\n<|im_end|>" }, { "id": "#30834", "title": "Cornered", "fun": 2.63, "difficulty": 2.66, "author": "norcekri", "desc": "When Nora and Corman stopped by the school to whisk Monette off to lunch, the poor principal was hemmed in by two tall, annoyed math students.\n\r\n\t\"My answer is right, and I want my three points!\" the blond one cried.\r\n\t\"But it's not the answer Mr. Collins left on the key!\"\r\n\t\"He's wrong,\" the other one insisted. \"My answer is right!\"\r\n\tCorman leaned over to whisper in Nora's ear, \"Does she need our help?\"\r\n\t\"Yours, probably. Mr. Collins is at a conference for the weekend, and Monette took his math class. It looks like she handed back an exam.\"\r\n\t\"I teach math. Can I help?\"\r\n\tAll three talked at once; Monette was as frustrated as the two students. While they jabbered, Corman managed to read the problem in question:\n\r\n\t\"My house is built on a strangely-shaped lot, so my back yard is a right triangle with an area of 840 square feet. Each of the three sides measures an integral number of feet. If I want to stake my dog so that he can reach the entire yard, how long must his rope be?\"\n\r\n\tMonette finally pulled rank on the adolescents. \"It's not really your problem, but I'd be glad of some help. Mr. Collins marked their papers wrong; their answers don't match his. The students *sound* right, but math was too long ago for me; I'm not sure. To make matters worse, they don't even agree with each other.\"\r\n\t\"I see,\" said Corman, playing for time while he mentally checked the answer on the key in Monette's trembling hand. \"That's the answer Mr. Collins left you?\"\r\n\t\"Yes,\" she began.\r\n\t\"The right answer is 8 feet shorter,\" the blond claimed.\r\n\t\"No, it's a lot longer,\" insisted the other.\r\n\tCorman held up a hand for peace. \"Actually, you *could* all be correct.\"\r\n\t\"How can there be ... oh, it's one of those problems with an infinite number of right answers, because we're missing a clue?\"\r\n\t\"Well, let me see your work.\" The students handed him their papers; he followed the algebra, nodding for almost a minute.\r\n\t\"Nice work. You've found the only three right answers.\"\r\n\t\"How can there be exactly three? Usually, it's one, two, or infinity?\"\r\n\t\"Usually, you're right. Welcome to discrete math. When you restrict things to whole numbers sometimes they don't work out so simply.\"\n\r\n\tHow much rope did Mr. Collins really need?", "hint": "Mr. Collins's answer key gives the actual dimensions of the yard; he didn't realize there were two other answers from the hints he gave.", "answer": "37 feet.\n\r\n\tThere are three triangles that fit the given hints, having sides\r\n40, 42, 58\r\n24, 70, 74\r\n15, 112, 113\n\r\nFrom the students' comments, we know that the Collins yard has the middle-sized hypotenuse.\n\r\nA right triangle inscribes neatly into a semicircle, with the hypotenuse forming a diameter. The shortest rope needed to reach all points is one staked at the midpoint of the hypotenuse, forming a radius of the circle. 74/2 = 37 feet.\n\r\nThe blond student found the first answer above, and would have used a rope of 29 feet. The other student figured it at 113/2, or 56.5 feet.\n\r\nHistorical note:\r\nLewis Carroll searched for the answer to the basic mathematical problem, sent to him by a reader. He found two right triangles with the same area, but couldn't discover a set of three. Somewhat ironically, Carroll had found 20-21-29 and 12-35-37. Had he doubled their dimensions, he would have had the first two triangles above, and quite likely would have found the third.", "category": "Math", "date": "06/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Nora and Corman stopped by the school to whisk Monette off to lunch, the poor principal was hemmed in by two tall, annoyed math students.\n\r\n\t\"My answer is right, and I want my three points!\" the blond one cried.\r\n\t\"But it's not the answer Mr. Collins left on the key!\"\r\n\t\"He's wrong,\" the other one insisted. \"My answer is right!\"\r\n\tCorman leaned over to whisper in Nora's ear, \"Does she need our help?\"\r\n\t\"Yours, probably. Mr. Collins is at a conference for the weekend, and Monette took his math class. It looks like she handed back an exam.\"\r\n\t\"I teach math. Can I help?\"\r\n\tAll three talked at once; Monette was as frustrated as the two students. While they jabbered, Corman managed to read the problem in question:\n\r\n\t\"My house is built on a strangely-shaped lot, so my back yard is a right triangle with an area of 840 square feet. Each of the three sides measures an integral number of feet. If I want to stake my dog so that he can reach the entire yard, how long must his rope be?\"\n\r\n\tMonette finally pulled rank on the adolescents. \"It's not really your problem, but I'd be glad of some help. Mr. Collins marked their papers wrong; their answers don't match his. The students *sound* right, but math was too long ago for me; I'm not sure. To make matters worse, they don't even agree with each other.\"\r\n\t\"I see,\" said Corman, playing for time while he mentally checked the answer on the key in Monette's trembling hand. \"That's the answer Mr. Collins left you?\"\r\n\t\"Yes,\" she began.\r\n\t\"The right answer is 8 feet shorter,\" the blond claimed.\r\n\t\"No, it's a lot longer,\" insisted the other.\r\n\tCorman held up a hand for peace. \"Actually, you *could* all be correct.\"\r\n\t\"How can there be ... oh, it's one of those problems with an infinite number of right answers, because we're missing a clue?\"\r\n\t\"Well, let me see your work.\" The students handed him their papers; he followed the algebra, nodding for almost a minute.\r\n\t\"Nice work. You've found the only three right answers.\"\r\n\t\"How can there be exactly three? Usually, it's one, two, or infinity?\"\r\n\t\"Usually, you're right. Welcome to discrete math. When you restrict things to whole numbers sometimes they don't work out so simply.\"\n\r\n\tHow much rope did Mr. Collins really need?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n37 feet.\n\r\n\tThere are three triangles that fit the given hints, having sides\r\n40, 42, 58\r\n24, 70, 74\r\n15, 112, 113\n\r\nFrom the students' comments, we know that the Collins yard has the middle-sized hypotenuse.\n\r\nA right triangle inscribes neatly into a semicircle, with the hypotenuse forming a diameter. The shortest rope needed to reach all points is one staked at the midpoint of the hypotenuse, forming a radius of the circle. 74/2 = 37 feet.\n\r\nThe blond student found the first answer above, and would have used a rope of 29 feet. The other student figured it at 113/2, or 56.5 feet.\n\r\nHistorical note:\r\nLewis Carroll searched for the answer to the basic mathematical problem, sent to him by a reader. He found two right triangles with the same area, but couldn't discover a set of three. Somewhat ironically, Carroll had found 20-21-29 and 12-35-37. Had he doubled their dimensions, he would have had the first two triangles above, and quite likely would have found the third.\n<|im_start|>answer\n37 feet.\n\r\n\tThere are three triangles that fit the given hints, having sides\r\n40, 42, 58\r\n24, 70, 74\r\n15, 112, 113\n\r\nFrom the students' comments, we know that the Collins yard has the middle-sized hypotenuse.\n\r\nA right triangle inscribes neatly into a semicircle, with the hypotenuse forming a diameter. The shortest rope needed to reach all points is one staked at the midpoint of the hypotenuse, forming a radius of the circle. 74/2 = 37 feet.\n\r\nThe blond student found the first answer above, and would have used a rope of 29 feet. The other student figured it at 113/2, or 56.5 feet.\n\r\nHistorical note:\r\nLewis Carroll searched for the answer to the basic mathematical problem, sent to him by a reader. He found two right triangles with the same area, but couldn't discover a set of three. Somewhat ironically, Carroll had found 20-21-29 and 12-35-37. Had he doubled their dimensions, he would have had the first two triangles above, and quite likely would have found the third.\n<|im_end|>" }, { "id": "#36010", "title": "Waldo's Peanuts", "fun": 2.63, "difficulty": 1.29, "author": "beepbeeptnm", "desc": "Waldo ate a total of 100 peanuts in 5 days. Each day, he ate 6 more peanuts than he did the day before. So, how many peanuts did Waldo start with on the first day?", "hint": "Example; if Waldo started with 20 peanuts on day 1, he should have eaten 26 peanuts on day 2. By then, he would have eaten a total of 46 peanuts in 2 days. 20 is not the correct answer though, because by day 5, he would have eaten 160 peanuts.", "answer": "Waldo ate 8 peanuts on day 1. He had 14 peanuts on day 2 and added 6 peanuts each day up to day 5. By day 5, Waldo would have eaten a total of 100 peanuts.", "category": "Math", "date": "04/02/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWaldo ate a total of 100 peanuts in 5 days. Each day, he ate 6 more peanuts than he did the day before. So, how many peanuts did Waldo start with on the first day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWaldo ate 8 peanuts on day 1. He had 14 peanuts on day 2 and added 6 peanuts each day up to day 5. By day 5, Waldo would have eaten a total of 100 peanuts.\n<|im_start|>answer\nWaldo ate 8 peanuts on day 1. He had 14 peanuts on day 2 and added 6 peanuts each day up to day 5. By day 5, Waldo would have eaten a total of 100 peanuts.\n<|im_end|>" }, { "id": "#10796", "title": "Kidstuff", "fun": 2.63, "difficulty": 1.8800000000000001, "author": "jimbo", "desc": "Bicycles, tricycles, pedal cars galore\r\nSome have 2 wheels, some 3, some 4\r\nOne each they belong to some girls and boys\r\nEighteen is the number of these toys\r\nIf I change 1 tyre a week I fear\r\nTo change them all will take me a year\r\nThere are half as many cars as trikes\r\nHow many of each are owned by these tykes?", "hint": "How many weeks are there in a year?", "answer": "Suppose there is 1 car. There are 2 tricycles and 15 bikes. This makes 40 wheels - not enough.\r\nSuppose there are 2 cars. There are 4 tricycles and 12 bikes. This makes 44 wheels.\r\nEach time I add 1 car I get 4 extra wheels. I need 52 wheels so I want 2 more cars.\n\r\nAnswer 4 cars, 8 tricycles and 6 bikes.", "category": "Math", "date": "02/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBicycles, tricycles, pedal cars galore\r\nSome have 2 wheels, some 3, some 4\r\nOne each they belong to some girls and boys\r\nEighteen is the number of these toys\r\nIf I change 1 tyre a week I fear\r\nTo change them all will take me a year\r\nThere are half as many cars as trikes\r\nHow many of each are owned by these tykes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSuppose there is 1 car. There are 2 tricycles and 15 bikes. This makes 40 wheels - not enough.\r\nSuppose there are 2 cars. There are 4 tricycles and 12 bikes. This makes 44 wheels.\r\nEach time I add 1 car I get 4 extra wheels. I need 52 wheels so I want 2 more cars.\n\r\nAnswer 4 cars, 8 tricycles and 6 bikes.\n<|im_start|>answer\nSuppose there is 1 car. There are 2 tricycles and 15 bikes. This makes 40 wheels - not enough.\r\nSuppose there are 2 cars. There are 4 tricycles and 12 bikes. This makes 44 wheels.\r\nEach time I add 1 car I get 4 extra wheels. I need 52 wheels so I want 2 more cars.\n\r\nAnswer 4 cars, 8 tricycles and 6 bikes.\n<|im_end|>" }, { "id": "#8803", "title": "Diagony and Allumup", "fun": 2.63, "difficulty": 1.61, "author": "im_para_noid", "desc": "Someone is a diagony if all they say is a lie; likewise, someone is an allumup if all they say is the truth.\n\r\nYou have three friends (Fynudi, Mortimer, and Chloe) and you want to know whether or not Fynudi is a diagony. You ask him and he answers the question, but you are unable to hear him because he mumbled the answer. But the person next to Fynudi (Mortimer) screams, \"He said that he was a diagony!\" and the person next to Mortimer (Chloe) said, \"Mortimer, you are lying.\"\n\r\nNow the question is, what is Chloe?", "hint": "What did Fynudi say?", "answer": "Chloe is an allumup. \n\r\nYou can find this by simple logic. First of all, you know that Fynudi said that he is an allumup (he would never say that he is a diagony, because he would lie about it). So then you know that Mortimer is lying, which shows that Chloe is telling the truth, making her an allumup.", "category": "Logic", "date": "11/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSomeone is a diagony if all they say is a lie; likewise, someone is an allumup if all they say is the truth.\n\r\nYou have three friends (Fynudi, Mortimer, and Chloe) and you want to know whether or not Fynudi is a diagony. You ask him and he answers the question, but you are unable to hear him because he mumbled the answer. But the person next to Fynudi (Mortimer) screams, \"He said that he was a diagony!\" and the person next to Mortimer (Chloe) said, \"Mortimer, you are lying.\"\n\r\nNow the question is, what is Chloe?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChloe is an allumup. \n\r\nYou can find this by simple logic. First of all, you know that Fynudi said that he is an allumup (he would never say that he is a diagony, because he would lie about it). So then you know that Mortimer is lying, which shows that Chloe is telling the truth, making her an allumup.\n<|im_start|>answer\nChloe is an allumup. \n\r\nYou can find this by simple logic. First of all, you know that Fynudi said that he is an allumup (he would never say that he is a diagony, because he would lie about it). So then you know that Mortimer is lying, which shows that Chloe is telling the truth, making her an allumup.\n<|im_end|>" }, { "id": "#9534", "title": "Basketball Blast", "fun": 2.63, "difficulty": 1.17, "author": "IronMaiden980", "desc": "Hoops, Tiny, and Ron are the guard, center, and forward of their three-man basketball team, although not necessarily in that order. In the championship game, the guard, an only child, scored the fewest points. Ron, who dates Hoops' sister, scored more than the center. What position does each player play?", "hint": "No hint available.", "answer": "Tiny is the guard, Ron is the forward, and Hoops is the center.\n\r\nRon can't be the guard because he did not score the least. Likewise, Hoops is not the guard because he is not an only child; thus the guard must be Tiny. Likewise, Ron scored more that the center, which must make him the forward while Hoops fills out the center spot.\n\n\r\nBy the way, they won the game!", "category": "Logic", "date": "01/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHoops, Tiny, and Ron are the guard, center, and forward of their three-man basketball team, although not necessarily in that order. In the championship game, the guard, an only child, scored the fewest points. Ron, who dates Hoops' sister, scored more than the center. What position does each player play?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTiny is the guard, Ron is the forward, and Hoops is the center.\n\r\nRon can't be the guard because he did not score the least. Likewise, Hoops is not the guard because he is not an only child; thus the guard must be Tiny. Likewise, Ron scored more that the center, which must make him the forward while Hoops fills out the center spot.\n\n\r\nBy the way, they won the game!\n<|im_start|>answer\nTiny is the guard, Ron is the forward, and Hoops is the center.\n\r\nRon can't be the guard because he did not score the least. Likewise, Hoops is not the guard because he is not an only child; thus the guard must be Tiny. Likewise, Ron scored more that the center, which must make him the forward while Hoops fills out the center spot.\n\n\r\nBy the way, they won the game!\n<|im_end|>" }, { "id": "#24276", "title": "Be My Valentine", "fun": 2.63, "difficulty": 1.03, "author": "katey", "desc": "Freddie was in love - with three girls from his school! He couldn't decide which one he wanted to give his heart to so he sent all three a Valentine's card. But poor Freddie was out of luck - each girl thought the card came from someone else and Freddie was left on the sideline.\n\r\nFrom the clues below, can you work out the name of each potential sweetheart, the colour of each card Freddie sent and the name of the boy each girl believed the card was sent by?\n\n\r\n1. Unluckily for Freddie, when Miss Jetson received her card, she thought it was from Adam.\n\r\n2. When Molly received her blue coloured card, she told Miss Hanson and together they worked out who the card was from. It didn't occur to either of them that it was from Freddie!\n\r\n3. The girl who received the red card was convinced it came from Ethan.\n\r\n4. Neither Millie nor Miss Motson received a pink card. \n\n\r\nFirst Names: Lily, Millie, Molly\r\nSurnames: Hanson, Jetson, Motson\r\nColours: Blue, pink, red\r\nBoys: Adam, Dylan, Ethan", "hint": "No hint available.", "answer": "Name Colour Boy\r\nLily Jetson Pink Adam\r\nMillie Hanson Red Ethan\r\nMolly Motson Blue Dylan", "category": "Logic-Grid", "date": "07/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFreddie was in love - with three girls from his school! He couldn't decide which one he wanted to give his heart to so he sent all three a Valentine's card. But poor Freddie was out of luck - each girl thought the card came from someone else and Freddie was left on the sideline.\n\r\nFrom the clues below, can you work out the name of each potential sweetheart, the colour of each card Freddie sent and the name of the boy each girl believed the card was sent by?\n\n\r\n1. Unluckily for Freddie, when Miss Jetson received her card, she thought it was from Adam.\n\r\n2. When Molly received her blue coloured card, she told Miss Hanson and together they worked out who the card was from. It didn't occur to either of them that it was from Freddie!\n\r\n3. The girl who received the red card was convinced it came from Ethan.\n\r\n4. Neither Millie nor Miss Motson received a pink card. \n\n\r\nFirst Names: Lily, Millie, Molly\r\nSurnames: Hanson, Jetson, Motson\r\nColours: Blue, pink, red\r\nBoys: Adam, Dylan, Ethan\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName Colour Boy\r\nLily Jetson Pink Adam\r\nMillie Hanson Red Ethan\r\nMolly Motson Blue Dylan\n<|im_start|>answer\nName Colour Boy\r\nLily Jetson Pink Adam\r\nMillie Hanson Red Ethan\r\nMolly Motson Blue Dylan\n<|im_end|>" }, { "id": "#2721", "title": "Buy One Item", "fun": 2.62, "difficulty": 2.23, "author": "lil_thugsta", "desc": "There was once a man who had a very selfish and unkind son. So one day the father sent his son to the market with one coin and said, \"I am sick and tired of your selfish ways. Take this coin and buy with it: something to feed the cows, something to plant in the garden, something for us to eat, and something for us to drink. Don't come back until you do this!\" He is only allowed to buy one item. What did he buy that fulfilled his father's wish?", "hint": "No hint available.", "answer": "He bought a watermelon - the juice to drink, the pulp to eat, the seeds to plant in the garden, and the rind to feed the cows!", "category": "Logic", "date": "03/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was once a man who had a very selfish and unkind son. So one day the father sent his son to the market with one coin and said, \"I am sick and tired of your selfish ways. Take this coin and buy with it: something to feed the cows, something to plant in the garden, something for us to eat, and something for us to drink. Don't come back until you do this!\" He is only allowed to buy one item. What did he buy that fulfilled his father's wish?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe bought a watermelon - the juice to drink, the pulp to eat, the seeds to plant in the garden, and the rind to feed the cows!\n<|im_start|>answer\nHe bought a watermelon - the juice to drink, the pulp to eat, the seeds to plant in the garden, and the rind to feed the cows!\n<|im_end|>" }, { "id": "#38637", "title": "Sporty Kids", "fun": 2.62, "difficulty": 1.36, "author": "cookieruler", "desc": "There are 5 kids in the Smith home. Their names are John, Jill, Jake, Josh, and Shelby. They also each play a different sport. Basketball, Baseball, Soccer, Football and Tennis. Saturday is game day, and they have to get everyone ready for their games. Each kid has a different game time: 10:00, 11:40, 12:20, 1:30, and 4:10. The parents are having trouble remembering everything, but they have some clues. Can you help them?\n\r\n1. The oldest brother will drive his younger sister to her soccer game, then go to his football game at 4:10.\r\n2. Their friend will be driving the youngest brother to his baseball game.\r\n3. Shelby does not play the sport that starts with the same letter as her name.\r\n4. The tennis match starts at 10:00.\r\n5. One of the girls plays Basketball.\r\n6. Jake plays at 12:20.\r\n7. Josh is the middle child.\r\n8. Jill has the second game of the family.", "hint": "No hint available.", "answer": "John plays Football at 4:10.\r\nJill plays Soccer at 11:40.\r\nJake plays Baseball at 12:20.\r\nJosh plays Tennis at 10:00.\r\nShelby plays Basketball at 1:30.", "category": "Logic-Grid", "date": "10/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 5 kids in the Smith home. Their names are John, Jill, Jake, Josh, and Shelby. They also each play a different sport. Basketball, Baseball, Soccer, Football and Tennis. Saturday is game day, and they have to get everyone ready for their games. Each kid has a different game time: 10:00, 11:40, 12:20, 1:30, and 4:10. The parents are having trouble remembering everything, but they have some clues. Can you help them?\n\r\n1. The oldest brother will drive his younger sister to her soccer game, then go to his football game at 4:10.\r\n2. Their friend will be driving the youngest brother to his baseball game.\r\n3. Shelby does not play the sport that starts with the same letter as her name.\r\n4. The tennis match starts at 10:00.\r\n5. One of the girls plays Basketball.\r\n6. Jake plays at 12:20.\r\n7. Josh is the middle child.\r\n8. Jill has the second game of the family.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn plays Football at 4:10.\r\nJill plays Soccer at 11:40.\r\nJake plays Baseball at 12:20.\r\nJosh plays Tennis at 10:00.\r\nShelby plays Basketball at 1:30.\n<|im_start|>answer\nJohn plays Football at 4:10.\r\nJill plays Soccer at 11:40.\r\nJake plays Baseball at 12:20.\r\nJosh plays Tennis at 10:00.\r\nShelby plays Basketball at 1:30.\n<|im_end|>" }, { "id": "#20443", "title": "Five Cards 2", "fun": 2.62, "difficulty": 1.19, "author": "weirdness_-_-", "desc": "Once again it's time to play five cards. Remember to concentrate on the clues and draw a diagram if needed. If you didn't try the first teaser, here's how it works: I have five cards: Square, Circle, Triangle, Diamond and Wavy Lines. Your job is to guess the order of the cards using the clues given. Here are the five clues:\n\r\n1.The triangle and circle are one card apart. (There is 1 card in between them.)\n\r\n2.The circle is next to the square, but not the wavy lines.\n\r\n3.The wavy lines are first in the sequence; the square is not last.\n\r\n4.The triangle is next to the wavy lines.\n\r\n5.The diamond is as far away from the square as the triangle is from the circle.", "hint": "Draw a diagram!", "answer": "Wavy Lines, Triangle, Square, Circle, Diamond\n\r\n1.The triangle and circle are one card apart. This means they cannot be next to each other.\r\n2.The circle is next to the square. It's on one side of the circle.\r\n3.The wavy lines are first. This explains itself.\r\n4.The triangle is next to the wavy lines, making the triangle second and circle fourth.\r\n5.If the diamond is as far away from the wavy lines as possible, it must be last, which means the square is in between the circle and triangle, in the middle.", "category": "Logic", "date": "01/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce again it's time to play five cards. Remember to concentrate on the clues and draw a diagram if needed. If you didn't try the first teaser, here's how it works: I have five cards: Square, Circle, Triangle, Diamond and Wavy Lines. Your job is to guess the order of the cards using the clues given. Here are the five clues:\n\r\n1.The triangle and circle are one card apart. (There is 1 card in between them.)\n\r\n2.The circle is next to the square, but not the wavy lines.\n\r\n3.The wavy lines are first in the sequence; the square is not last.\n\r\n4.The triangle is next to the wavy lines.\n\r\n5.The diamond is as far away from the square as the triangle is from the circle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWavy Lines, Triangle, Square, Circle, Diamond\n\r\n1.The triangle and circle are one card apart. This means they cannot be next to each other.\r\n2.The circle is next to the square. It's on one side of the circle.\r\n3.The wavy lines are first. This explains itself.\r\n4.The triangle is next to the wavy lines, making the triangle second and circle fourth.\r\n5.If the diamond is as far away from the wavy lines as possible, it must be last, which means the square is in between the circle and triangle, in the middle.\n<|im_start|>answer\nWavy Lines, Triangle, Square, Circle, Diamond\n\r\n1.The triangle and circle are one card apart. This means they cannot be next to each other.\r\n2.The circle is next to the square. It's on one side of the circle.\r\n3.The wavy lines are first. This explains itself.\r\n4.The triangle is next to the wavy lines, making the triangle second and circle fourth.\r\n5.If the diamond is as far away from the wavy lines as possible, it must be last, which means the square is in between the circle and triangle, in the middle.\n<|im_end|>" }, { "id": "#673", "title": "Measure 45 Minutes", "fun": 2.62, "difficulty": 2.3, "author": "vikass", "desc": "You have two ropes. Each takes exactly 60 minutes to burn. They are made of different material so even though they take the same amount of time to burn, they burn at separate rates. In addition, each rope burns inconsistently. How do you measure out exactly 45 minutes?", "hint": "No hint available.", "answer": "Take one rope and burn it at both ends.\r\nAt the same time, burn one end of the\r\nother rope. When the first rope finishes\r\nburning (ie. 30 minutes), light the other\r\nend of the remaining rope (half of the\r\nremaining 30 minutes gives you 15 minutes)\r\nWhen it burns out, that`s 45 minutes.", "category": "Logic", "date": "06/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two ropes. Each takes exactly 60 minutes to burn. They are made of different material so even though they take the same amount of time to burn, they burn at separate rates. In addition, each rope burns inconsistently. How do you measure out exactly 45 minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake one rope and burn it at both ends.\r\nAt the same time, burn one end of the\r\nother rope. When the first rope finishes\r\nburning (ie. 30 minutes), light the other\r\nend of the remaining rope (half of the\r\nremaining 30 minutes gives you 15 minutes)\r\nWhen it burns out, that`s 45 minutes.\n<|im_start|>answer\nTake one rope and burn it at both ends.\r\nAt the same time, burn one end of the\r\nother rope. When the first rope finishes\r\nburning (ie. 30 minutes), light the other\r\nend of the remaining rope (half of the\r\nremaining 30 minutes gives you 15 minutes)\r\nWhen it burns out, that`s 45 minutes.\n<|im_end|>" }, { "id": "#39082", "title": "Chess Tournament 1", "fun": 2.62, "difficulty": 1.7, "author": "soccerguy0428", "desc": "Seven friends gather to play in a chess tournament. The players were divided into two sections: Section A has 4 players; and Section B has 3 players. Each player played against every other player in his/her Section. With the information below, can you determine each person's section, and to whom they won and lost.\n\r\nPlayers: Alyssa, Caitlin, Connor, Jeremy, Mark, Megan, and Tyler.\n\r\n1. Megan won every game.\n\r\n2. Caitlin beat Mark who beat Jeremy.\n\r\n3. Everyone in Section A and B had different win and loss records.\n\r\n4. Tyler lost to Alyssa.\n\r\n5. The people whose names begin with a C were in the same section. One of them won all of their games while the other lost all of their games.", "hint": "No hint available.", "answer": "Section A:\n\r\nCaitlin: Beat everyone.\r\nMark: Beat Jeremy and Connor, but lost to Caitlin.\r\nJeremy: Beat Connor, but lost to Caitlin and Mark.\r\nConnor: Lost to everyone.\n\r\nSection B:\n\r\nMegan: Beat everyone.\r\nAlyssa: Beat Tyler, but lost to Megan.\r\nTyler: Lost to everyone.", "category": "Logic", "date": "11/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSeven friends gather to play in a chess tournament. The players were divided into two sections: Section A has 4 players; and Section B has 3 players. Each player played against every other player in his/her Section. With the information below, can you determine each person's section, and to whom they won and lost.\n\r\nPlayers: Alyssa, Caitlin, Connor, Jeremy, Mark, Megan, and Tyler.\n\r\n1. Megan won every game.\n\r\n2. Caitlin beat Mark who beat Jeremy.\n\r\n3. Everyone in Section A and B had different win and loss records.\n\r\n4. Tyler lost to Alyssa.\n\r\n5. The people whose names begin with a C were in the same section. One of them won all of their games while the other lost all of their games.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSection A:\n\r\nCaitlin: Beat everyone.\r\nMark: Beat Jeremy and Connor, but lost to Caitlin.\r\nJeremy: Beat Connor, but lost to Caitlin and Mark.\r\nConnor: Lost to everyone.\n\r\nSection B:\n\r\nMegan: Beat everyone.\r\nAlyssa: Beat Tyler, but lost to Megan.\r\nTyler: Lost to everyone.\n<|im_start|>answer\nSection A:\n\r\nCaitlin: Beat everyone.\r\nMark: Beat Jeremy and Connor, but lost to Caitlin.\r\nJeremy: Beat Connor, but lost to Caitlin and Mark.\r\nConnor: Lost to everyone.\n\r\nSection B:\n\r\nMegan: Beat everyone.\r\nAlyssa: Beat Tyler, but lost to Megan.\r\nTyler: Lost to everyone.\n<|im_end|>" }, { "id": "#1579", "title": "No Change for a Dollar", "fun": 2.62, "difficulty": 1.91, "author": "ichabod clay", "desc": "What is the largest amount of American money you can have in coins without being able to make change for a dollar?", "hint": "No hint available.", "answer": "$1.19 \r\n3 quarters 4 dimes and 4 pennies.", "category": "Math", "date": "12/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the largest amount of American money you can have in coins without being able to make change for a dollar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$1.19 \r\n3 quarters 4 dimes and 4 pennies.\n<|im_start|>answer\n$1.19 \r\n3 quarters 4 dimes and 4 pennies.\n<|im_end|>" }, { "id": "#43208", "title": "How Much Was Stolen?", "fun": 2.62, "difficulty": 1.37, "author": "Thinker1995", "desc": "A burglar had just robbed a bank and was running away with all the money he stole. Suddenly, a guard appeared and refused to let the burglar pass. The burglar had to give up a half of the money he had, as well as an extra $2000, so he could escape. Not too long afterwards, he was stopped again by a second guard, who demanded half of the money the burglar had left, plus a $2000 bonus, in exchange for letting the burglar pass. The burglar gave the guard the amount of money asked and continued running toward his home, until he was stopped again by a third guard. The burglar was so desperate to escape that he was forced to give the third guard half of the money he had left and another $2000. Finally the burglar made it to his house and began to count the money that he still had. He had managed to make off with $9000 dollars and he was a free man, but when he calculated the difference between the amount of money he had originally stolen and the amount of money he actually took home, he was overcome with sadness. How much money did the burglar originally steal?", "hint": "No hint available.", "answer": "The burglar originally stole $100,000.", "category": "Math", "date": "09/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA burglar had just robbed a bank and was running away with all the money he stole. Suddenly, a guard appeared and refused to let the burglar pass. The burglar had to give up a half of the money he had, as well as an extra $2000, so he could escape. Not too long afterwards, he was stopped again by a second guard, who demanded half of the money the burglar had left, plus a $2000 bonus, in exchange for letting the burglar pass. The burglar gave the guard the amount of money asked and continued running toward his home, until he was stopped again by a third guard. The burglar was so desperate to escape that he was forced to give the third guard half of the money he had left and another $2000. Finally the burglar made it to his house and began to count the money that he still had. He had managed to make off with $9000 dollars and he was a free man, but when he calculated the difference between the amount of money he had originally stolen and the amount of money he actually took home, he was overcome with sadness. How much money did the burglar originally steal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe burglar originally stole $100,000.\n<|im_start|>answer\nThe burglar originally stole $100,000.\n<|im_end|>" }, { "id": "#46583", "title": "Tag the Teacher", "fun": 2.62, "difficulty": 1.91, "author": "dalfamnest", "desc": "Sam and three other teachers work in a block of four adjacent classrooms, numbered A6, A7, A8, and A9. Although (perhaps) they don't deserve it, their students have created quite uncomplimentary nicknames for them; one is 'Flabbz'.\n\r\nFrom this information, and the clues below, can you determine which room each teacher uses, and their nicknames?\n\r\n1. When 'Gonzo' teaches, she is so loud that her voice disturbs Jan and 'The Wasp', who work in the rooms adjacent to hers.\n\r\n2. The four teachers are Liz, the teacher in Room A7, 'Crustie' (who does not teach in A8), and the only male teacher, Mike.\n\r\n3. Jan does not teach at either end of the classroom block.", "hint": "Clue #1 holds an indirect clue that is easy to miss.\n\r\nIt is quite tricky to solve this using the grid, so you may prefer to work with a diagram.\n\r\ne.g. || A6 | A7 | A8 | A9 ||\n\r\nIf you are stuck, try placing the teachers in clue #1 first. There are four ways to do that, some of which will be rejected by applying clue #2.", "answer": "A6: 'Crustie' Sam\r\nA7: 'Flabbz' Jan\r\nA8: 'Gonzo' Liz\r\nA9: Mike 'The Wasp'\n\r\nSolution:\r\n'Gonzo' (a woman - #1) is between Jan and 'The Wasp' (#1). Jan is not at either end (#3) so the only possibilities have \"6: 'Wasp', 7: 'Gonzo', 8: Jan\" and \"7: Jan, 8: 'Gonzo', 9: 'Wasp'.\"\n\r\nClue #2 mentions four teachers; hence four different rooms. If we use the option with 'Wasp' in 6, then 'Crustie'=9, leaving 7 and 8 for Liz and Mike. However, this option has Jan in 8, so it is rejected.\n\r\nThe remaining possibility has 'Wasp' in 9, 'Gonzo'=8, so (applying #2) 'Crustie'=6, and 'Flabbz'=7.\n\r\nJan is in 7, so Mike and Liz must be in 8 and 9. Gonzo, in 8, must be female (#1) so Liz=8, Mike=9, leaving Sam=6.", "category": "Logic-Grid", "date": "03/21/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSam and three other teachers work in a block of four adjacent classrooms, numbered A6, A7, A8, and A9. Although (perhaps) they don't deserve it, their students have created quite uncomplimentary nicknames for them; one is 'Flabbz'.\n\r\nFrom this information, and the clues below, can you determine which room each teacher uses, and their nicknames?\n\r\n1. When 'Gonzo' teaches, she is so loud that her voice disturbs Jan and 'The Wasp', who work in the rooms adjacent to hers.\n\r\n2. The four teachers are Liz, the teacher in Room A7, 'Crustie' (who does not teach in A8), and the only male teacher, Mike.\n\r\n3. Jan does not teach at either end of the classroom block.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA6: 'Crustie' Sam\r\nA7: 'Flabbz' Jan\r\nA8: 'Gonzo' Liz\r\nA9: Mike 'The Wasp'\n\r\nSolution:\r\n'Gonzo' (a woman - #1) is between Jan and 'The Wasp' (#1). Jan is not at either end (#3) so the only possibilities have \"6: 'Wasp', 7: 'Gonzo', 8: Jan\" and \"7: Jan, 8: 'Gonzo', 9: 'Wasp'.\"\n\r\nClue #2 mentions four teachers; hence four different rooms. If we use the option with 'Wasp' in 6, then 'Crustie'=9, leaving 7 and 8 for Liz and Mike. However, this option has Jan in 8, so it is rejected.\n\r\nThe remaining possibility has 'Wasp' in 9, 'Gonzo'=8, so (applying #2) 'Crustie'=6, and 'Flabbz'=7.\n\r\nJan is in 7, so Mike and Liz must be in 8 and 9. Gonzo, in 8, must be female (#1) so Liz=8, Mike=9, leaving Sam=6.\n<|im_start|>answer\nA6: 'Crustie' Sam\r\nA7: 'Flabbz' Jan\r\nA8: 'Gonzo' Liz\r\nA9: Mike 'The Wasp'\n\r\nSolution:\r\n'Gonzo' (a woman - #1) is between Jan and 'The Wasp' (#1). Jan is not at either end (#3) so the only possibilities have \"6: 'Wasp', 7: 'Gonzo', 8: Jan\" and \"7: Jan, 8: 'Gonzo', 9: 'Wasp'.\"\n\r\nClue #2 mentions four teachers; hence four different rooms. If we use the option with 'Wasp' in 6, then 'Crustie'=9, leaving 7 and 8 for Liz and Mike. However, this option has Jan in 8, so it is rejected.\n\r\nThe remaining possibility has 'Wasp' in 9, 'Gonzo'=8, so (applying #2) 'Crustie'=6, and 'Flabbz'=7.\n\r\nJan is in 7, so Mike and Liz must be in 8 and 9. Gonzo, in 8, must be female (#1) so Liz=8, Mike=9, leaving Sam=6.\n<|im_end|>" }, { "id": "#22864", "title": "Odd Family", "fun": 2.62, "difficulty": 1.37, "author": "Question_Mark", "desc": "In a room, there is a mother, a father, a son, a daughter, a brother, a sister, an auntie, an uncle, a niece, a nephew, and 2 cousins. However, there are only 4 people in the room. Relations exist only between the people in the room. How can you explain this?", "hint": "No hint available.", "answer": "The 4 people are:\r\nA man, a woman, a boy, and a girl.\r\nHere are the relations.\n\r\nMan:\n\r\nWoman - His sister\r\nBoy - His nephew\r\nGirl - His daughter\n\r\nWoman:\r\nMan - Her brother\r\nBoy - Her son\r\nGirl - Her niece\n\r\nBoy:\r\nMan - His uncle\r\nWoman - His mother\r\nGirl - His cousin\n\r\nGirl:\r\nMan - Her father\r\nWoman - Her auntie\r\nBoy - Her cousin", "category": "Logic", "date": "05/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a room, there is a mother, a father, a son, a daughter, a brother, a sister, an auntie, an uncle, a niece, a nephew, and 2 cousins. However, there are only 4 people in the room. Relations exist only between the people in the room. How can you explain this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 4 people are:\r\nA man, a woman, a boy, and a girl.\r\nHere are the relations.\n\r\nMan:\n\r\nWoman - His sister\r\nBoy - His nephew\r\nGirl - His daughter\n\r\nWoman:\r\nMan - Her brother\r\nBoy - Her son\r\nGirl - Her niece\n\r\nBoy:\r\nMan - His uncle\r\nWoman - His mother\r\nGirl - His cousin\n\r\nGirl:\r\nMan - Her father\r\nWoman - Her auntie\r\nBoy - Her cousin\n<|im_start|>answer\nThe 4 people are:\r\nA man, a woman, a boy, and a girl.\r\nHere are the relations.\n\r\nMan:\n\r\nWoman - His sister\r\nBoy - His nephew\r\nGirl - His daughter\n\r\nWoman:\r\nMan - Her brother\r\nBoy - Her son\r\nGirl - Her niece\n\r\nBoy:\r\nMan - His uncle\r\nWoman - His mother\r\nGirl - His cousin\n\r\nGirl:\r\nMan - Her father\r\nWoman - Her auntie\r\nBoy - Her cousin\n<|im_end|>" }, { "id": "#5572", "title": "Fresh Meat", "fun": 2.62, "difficulty": 1.28, "author": "glennyboy02", "desc": "Several hundred summers ago, a band of explorers were embarking on a sea journey to the far north which would last for three weeks. When they arrived, they planned on having a celebration of roast lamb. The problem they faced was keeping the meat fresh for three weeks. If they tied a rope to the meat and trailed it in the cold water, predator fish would eat it. If they took ice and snow with them to keep the meat cool, the ice and snow would melt and the ship would fill with water. How could they keep the meat fresh until they arrived at their destination?", "hint": "No hint available.", "answer": "Take a live lamb!", "category": "Logic", "date": "07/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSeveral hundred summers ago, a band of explorers were embarking on a sea journey to the far north which would last for three weeks. When they arrived, they planned on having a celebration of roast lamb. The problem they faced was keeping the meat fresh for three weeks. If they tied a rope to the meat and trailed it in the cold water, predator fish would eat it. If they took ice and snow with them to keep the meat cool, the ice and snow would melt and the ship would fill with water. How could they keep the meat fresh until they arrived at their destination?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake a live lamb!\n<|im_start|>answer\nTake a live lamb!\n<|im_end|>" }, { "id": "#31602", "title": "A Few Cards Short of a Pack", "fun": 2.62, "difficulty": 1.48, "author": "Linlou18uk", "desc": "I have a deck of cards from which some are missing. If I deal them equally among nine people, I have two cards to spare. If I deal them equally among four people, I have three cards to spare. If I deal them among seven people, I have five cards to spare. There are normally 52 cards in the deck. \n\r\nHow many cards are missing?", "hint": "No hint available.", "answer": "There are five cards missing, leaving 47 cards in the deck.", "category": "Logic", "date": "07/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have a deck of cards from which some are missing. If I deal them equally among nine people, I have two cards to spare. If I deal them equally among four people, I have three cards to spare. If I deal them among seven people, I have five cards to spare. There are normally 52 cards in the deck. \n\r\nHow many cards are missing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are five cards missing, leaving 47 cards in the deck.\n<|im_start|>answer\nThere are five cards missing, leaving 47 cards in the deck.\n<|im_end|>" }, { "id": "#28093", "title": "Nice Suit", "fun": 2.62, "difficulty": 1.3, "author": "smek", "desc": "At a local bar, three friends, Mr. Green, Mr. Red and Mr. Blue, were having a drink. One man was wearing a red suit; one a green suit; and the other a blue suit. \"Have you noticed,\" said the man in the blue suit, \"that although our suits have colors corresponding to our names, not one of us is wearing a suit that matches our own names?\" Mr. Red looked at the other two and said, \"You're absolutely correct.\"\n\r\nWhat color suit is each man wearing?", "hint": "No hint available.", "answer": "Since none of the men are wearing the color of suit that corresponds to their names, and Mr. Red was replying to the man in the blue suit, it had to be Mr. Green to whom he replied. We then know that Mr.Green is wearing a blue suit. Therefore, Mr. Red is wearing a green suit and Mr. Blue is wearing a red suit.", "category": "Logic", "date": "01/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a local bar, three friends, Mr. Green, Mr. Red and Mr. Blue, were having a drink. One man was wearing a red suit; one a green suit; and the other a blue suit. \"Have you noticed,\" said the man in the blue suit, \"that although our suits have colors corresponding to our names, not one of us is wearing a suit that matches our own names?\" Mr. Red looked at the other two and said, \"You're absolutely correct.\"\n\r\nWhat color suit is each man wearing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince none of the men are wearing the color of suit that corresponds to their names, and Mr. Red was replying to the man in the blue suit, it had to be Mr. Green to whom he replied. We then know that Mr.Green is wearing a blue suit. Therefore, Mr. Red is wearing a green suit and Mr. Blue is wearing a red suit.\n<|im_start|>answer\nSince none of the men are wearing the color of suit that corresponds to their names, and Mr. Red was replying to the man in the blue suit, it had to be Mr. Green to whom he replied. We then know that Mr.Green is wearing a blue suit. Therefore, Mr. Red is wearing a green suit and Mr. Blue is wearing a red suit.\n<|im_end|>" }, { "id": "#6649", "title": "Louisiana Jones", "fun": 2.62, "difficulty": 1.67, "author": "mrbump999", "desc": "It was a typical day for Louisiana Jones, who found himself risking death for a mythical and tasteless artifact. This particular day Louisiana was in the crypts of a previously undiscovered Inca temple. In front of him lay three doors. Above the doors there was writing. Luckily, Louisiana had just read 'Inca for dummies' and could easily translate the inscription. The writing said, 'behind one of the three doors awaits the golden rug, but beware, because behind the other two doors are really nasty monsters.' To aid you in your choice there are signs on each door, but they may be true or false.' Which door hides the golden rug?\n\r\nDoor 1. At least one of the signs is false\n\r\nDoor 2. Door 1 leads to the rug if door 3 does not.\n\r\nDoor 3. The rug is not behind door 2.", "hint": "No hint available.", "answer": "Door 2\n\r\nFirstly, sign 1 must be true. Therefore, one or both of the signs on doors 2 and 3 must be false. If the rug is behind door 1, then the signs on both doors 2 and 3 are true. If door 3 hides the rug, then again, the signs on both doors 2 and 3 are true. However, if door 2 conceals the treasure, then the signs on 2 and 3 would both be false.", "category": "Logic", "date": "08/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was a typical day for Louisiana Jones, who found himself risking death for a mythical and tasteless artifact. This particular day Louisiana was in the crypts of a previously undiscovered Inca temple. In front of him lay three doors. Above the doors there was writing. Luckily, Louisiana had just read 'Inca for dummies' and could easily translate the inscription. The writing said, 'behind one of the three doors awaits the golden rug, but beware, because behind the other two doors are really nasty monsters.' To aid you in your choice there are signs on each door, but they may be true or false.' Which door hides the golden rug?\n\r\nDoor 1. At least one of the signs is false\n\r\nDoor 2. Door 1 leads to the rug if door 3 does not.\n\r\nDoor 3. The rug is not behind door 2.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDoor 2\n\r\nFirstly, sign 1 must be true. Therefore, one or both of the signs on doors 2 and 3 must be false. If the rug is behind door 1, then the signs on both doors 2 and 3 are true. If door 3 hides the rug, then again, the signs on both doors 2 and 3 are true. However, if door 2 conceals the treasure, then the signs on 2 and 3 would both be false.\n<|im_start|>answer\nDoor 2\n\r\nFirstly, sign 1 must be true. Therefore, one or both of the signs on doors 2 and 3 must be false. If the rug is behind door 1, then the signs on both doors 2 and 3 are true. If door 3 hides the rug, then again, the signs on both doors 2 and 3 are true. However, if door 2 conceals the treasure, then the signs on 2 and 3 would both be false.\n<|im_end|>" }, { "id": "#4468", "title": "Coin Story", "fun": 2.62, "difficulty": 1.81, "author": "arij", "desc": "Scatterbrain the Treasurer was a bit of a ... well, scatterbrain, and he had forgotten how many gold, silver and bronze coins were kept in the town vaults. So he decided to ask the three guards, each of whom guarded one type of coin, how many coins were in his charge. However, the guards were uncooperative, and the best that Scatterbrain could get from each was a statement about the numbers of coins in the other two vaults. Dimwit, who was guarding the gold, said there were 3000 silver and 5000 bronze coins; Thickplank, who was in charge of the silver, said there were 3000 gold and 5000 bronze; while Beefbrain, who was protecting the bronze, said there were 4000 gold and 3000 silver. Unfortunately, only one guard was being truthful, each of the other two stating at least one false amount. If there were 12000 coins altogether, how many of each type were there?", "hint": "No hint available.", "answer": "There were 3000 gold coins, 4000 silver and 5000 bronze. Assume each statement to be true in turn and examine the consequences. If Dimwit is telling the truth, there are 3000 silver coins, 5000 bronze coins and hence 4000 gold coins. However, this would make Beefbrain's statement true also. By symmetry if Beefbrain is truthful so is Dimwit. Only if Thickplank is telling the truth are the other statements false.", "category": "Logic", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nScatterbrain the Treasurer was a bit of a ... well, scatterbrain, and he had forgotten how many gold, silver and bronze coins were kept in the town vaults. So he decided to ask the three guards, each of whom guarded one type of coin, how many coins were in his charge. However, the guards were uncooperative, and the best that Scatterbrain could get from each was a statement about the numbers of coins in the other two vaults. Dimwit, who was guarding the gold, said there were 3000 silver and 5000 bronze coins; Thickplank, who was in charge of the silver, said there were 3000 gold and 5000 bronze; while Beefbrain, who was protecting the bronze, said there were 4000 gold and 3000 silver. Unfortunately, only one guard was being truthful, each of the other two stating at least one false amount. If there were 12000 coins altogether, how many of each type were there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 3000 gold coins, 4000 silver and 5000 bronze. Assume each statement to be true in turn and examine the consequences. If Dimwit is telling the truth, there are 3000 silver coins, 5000 bronze coins and hence 4000 gold coins. However, this would make Beefbrain's statement true also. By symmetry if Beefbrain is truthful so is Dimwit. Only if Thickplank is telling the truth are the other statements false.\n<|im_start|>answer\nThere were 3000 gold coins, 4000 silver and 5000 bronze. Assume each statement to be true in turn and examine the consequences. If Dimwit is telling the truth, there are 3000 silver coins, 5000 bronze coins and hence 4000 gold coins. However, this would make Beefbrain's statement true also. By symmetry if Beefbrain is truthful so is Dimwit. Only if Thickplank is telling the truth are the other statements false.\n<|im_end|>" }, { "id": "#30191", "title": "Friendly Firefighters", "fun": 2.62, "difficulty": 1.98, "author": "fairelamour", "desc": "Truck 57-1 pumps 750 gallons of water per minute.\r\nTruck 57-2 pumps 1,000 gallons of water per minute.\r\nTruck 57-3 pumps 1,250 gallons of water per minute.\r\nTruck 57-4 pumps 1,500 gallons of water per minute.\r\nTruck 57-5 pumps 1,750 gallons of water per minute.\n\r\nChief Greg Henry and firefighters Chuck, Darren, Jim, and Vanessa drove the trucks from District 57, responding to a multiple alarm fire. The driver and crew of each truck worked to extinguish the blaze.\n\r\n1. Vanessa and her crew pumped 45,000 gallons of water on the fire in a half-hour. \r\n2. Chief Greg and his crew worked for 45 minutes, pumping more water than Vanessa's crew but less than Jim's crew did in an hour. \r\n3. Chuck and his team pumped the same amount of water as Vanessa's crew in the same amount of time as Jim's crew. \r\n4. Darren's crew worked for 45 minutes and pumped the most water on the flames. \n\r\nWho drove each truck, and how much water did each crew use to douse the fire?", "hint": "Use the grid to determine how much water each truck pumped for the length of time given.", "answer": "Truck 57-1, Chuck, 45,000 gallons;\r\nTruck 57-2, Jim, 60,000 gallons;\r\nTruck 57-3, Chief Greg, 56,250 gallons;\r\nTruck 57-4, Vanessa, 45,000 gallons;\r\nTruck 57-5, Darren, 78,750 gallons.", "category": "Logic-Grid", "date": "04/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTruck 57-1 pumps 750 gallons of water per minute.\r\nTruck 57-2 pumps 1,000 gallons of water per minute.\r\nTruck 57-3 pumps 1,250 gallons of water per minute.\r\nTruck 57-4 pumps 1,500 gallons of water per minute.\r\nTruck 57-5 pumps 1,750 gallons of water per minute.\n\r\nChief Greg Henry and firefighters Chuck, Darren, Jim, and Vanessa drove the trucks from District 57, responding to a multiple alarm fire. The driver and crew of each truck worked to extinguish the blaze.\n\r\n1. Vanessa and her crew pumped 45,000 gallons of water on the fire in a half-hour. \r\n2. Chief Greg and his crew worked for 45 minutes, pumping more water than Vanessa's crew but less than Jim's crew did in an hour. \r\n3. Chuck and his team pumped the same amount of water as Vanessa's crew in the same amount of time as Jim's crew. \r\n4. Darren's crew worked for 45 minutes and pumped the most water on the flames. \n\r\nWho drove each truck, and how much water did each crew use to douse the fire?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTruck 57-1, Chuck, 45,000 gallons;\r\nTruck 57-2, Jim, 60,000 gallons;\r\nTruck 57-3, Chief Greg, 56,250 gallons;\r\nTruck 57-4, Vanessa, 45,000 gallons;\r\nTruck 57-5, Darren, 78,750 gallons.\n<|im_start|>answer\nTruck 57-1, Chuck, 45,000 gallons;\r\nTruck 57-2, Jim, 60,000 gallons;\r\nTruck 57-3, Chief Greg, 56,250 gallons;\r\nTruck 57-4, Vanessa, 45,000 gallons;\r\nTruck 57-5, Darren, 78,750 gallons.\n<|im_end|>" }, { "id": "#41301", "title": "Tell The Truth 2", "fun": 2.62, "difficulty": 1.55, "author": "jsteppergurl", "desc": "A school has 200 students. All of the students are very special. Some of them ALWAYS tell the truth, and the rest of them, NEVER tell the truth. Among the subject areas of math, science, and social studies, each student has one favorite. A survey was conducted, each student was asked three yes-or-no questions. The questions were: \"Do you like math the most?\" \"Do you like science the most?\" \"Do you like social studies the most?\"\n\r\nThe results were as follows:\r\n104 students said \"yes,\" they like math the most.\r\n86 students said \"yes,\" they like science the most.\r\n60 students said \"yes,\" they like social studies the most.\n\r\nHow many students tell the truth, and how many do not?", "hint": "Check how many \"yes\" answers there were in total and how many students are in the school.", "answer": "There are 150 students who tell the truth and 50 students who do not.\n\r\nStudents who tell the truth will answer \"yes\" to one favorite subject, whereas those not telling the truth will answer \"yes\" to two subjects (but not to their real favorite). Since there are 250 answers (104 + 86 + 60), there are 50 extra \"yes\" answers, from the 50 students who do not tell the truth.", "category": "Math", "date": "03/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA school has 200 students. All of the students are very special. Some of them ALWAYS tell the truth, and the rest of them, NEVER tell the truth. Among the subject areas of math, science, and social studies, each student has one favorite. A survey was conducted, each student was asked three yes-or-no questions. The questions were: \"Do you like math the most?\" \"Do you like science the most?\" \"Do you like social studies the most?\"\n\r\nThe results were as follows:\r\n104 students said \"yes,\" they like math the most.\r\n86 students said \"yes,\" they like science the most.\r\n60 students said \"yes,\" they like social studies the most.\n\r\nHow many students tell the truth, and how many do not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 150 students who tell the truth and 50 students who do not.\n\r\nStudents who tell the truth will answer \"yes\" to one favorite subject, whereas those not telling the truth will answer \"yes\" to two subjects (but not to their real favorite). Since there are 250 answers (104 + 86 + 60), there are 50 extra \"yes\" answers, from the 50 students who do not tell the truth.\n<|im_start|>answer\nThere are 150 students who tell the truth and 50 students who do not.\n\r\nStudents who tell the truth will answer \"yes\" to one favorite subject, whereas those not telling the truth will answer \"yes\" to two subjects (but not to their real favorite). Since there are 250 answers (104 + 86 + 60), there are 50 extra \"yes\" answers, from the 50 students who do not tell the truth.\n<|im_end|>" }, { "id": "#30657", "title": "Opposites 21", "fun": 2.62, "difficulty": 2.16, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n$ stands for A, S, D, B, or C\r\n# stands for E, M, K, N, or P\r\n@ stands for E, R, G, H, or N\r\n^ stands for U, V, I, E, or W\n\r\nThe four letter code word, #^$@, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Mean and Nice", "category": "Logic", "date": "05/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n$ stands for A, S, D, B, or C\r\n# stands for E, M, K, N, or P\r\n@ stands for E, R, G, H, or N\r\n^ stands for U, V, I, E, or W\n\r\nThe four letter code word, #^$@, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMean and Nice\n<|im_start|>answer\nMean and Nice\n<|im_end|>" }, { "id": "#40423", "title": "Which is True?", "fun": 2.62, "difficulty": 1.42, "author": "TRILLIONAIRE", "desc": "Which of the following statement(s) is/are true?\n\r\nA: There is only one true statement.\r\nB: \"A\" is telling the truth.\r\nC: \"B\" is lying.\r\nD: This statement is true.", "hint": "No hint available.", "answer": "\"C\" and \"D\"\n\r\n\"A\" cannot be truthful, because that would result in \"B\" being truthful also, which would result in two true statements. \"A\" must be lying, so \"B\" must be lying also. If \"B\" is lying, then \"C\" is telling the truth. So far, there is one true statement, C. \"D\" can be true or false, but if it is false, then there is only one true statement, which results in \"A\" being true, which contradicts everything. \"D\" has to be true, so the two true statements are \"C\" and \"D\".", "category": "Logic", "date": "02/10/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of the following statement(s) is/are true?\n\r\nA: There is only one true statement.\r\nB: \"A\" is telling the truth.\r\nC: \"B\" is lying.\r\nD: This statement is true.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"C\" and \"D\"\n\r\n\"A\" cannot be truthful, because that would result in \"B\" being truthful also, which would result in two true statements. \"A\" must be lying, so \"B\" must be lying also. If \"B\" is lying, then \"C\" is telling the truth. So far, there is one true statement, C. \"D\" can be true or false, but if it is false, then there is only one true statement, which results in \"A\" being true, which contradicts everything. \"D\" has to be true, so the two true statements are \"C\" and \"D\".\n<|im_start|>answer\n\"C\" and \"D\"\n\r\n\"A\" cannot be truthful, because that would result in \"B\" being truthful also, which would result in two true statements. \"A\" must be lying, so \"B\" must be lying also. If \"B\" is lying, then \"C\" is telling the truth. So far, there is one true statement, C. \"D\" can be true or false, but if it is false, then there is only one true statement, which results in \"A\" being true, which contradicts everything. \"D\" has to be true, so the two true statements are \"C\" and \"D\".\n<|im_end|>" }, { "id": "#2134", "title": "How many Parcels", "fun": 2.62, "difficulty": 1.61, "author": "Cascas", "desc": "A husband and wife were walking home from the shopping mall with their purchases when the husband began to complain that his load was too heavy. The wife turned to her husband and said \"I don't know what you're complaining about because if you gave me one of your parcels, I would have twice as many as you, and if I gave you just one of mine, we would have equal loads.\" How many parcels were each carrying?", "hint": "No hint available.", "answer": "The wife was carrying seven parcels and the husband was carrying five.", "category": "Math", "date": "01/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA husband and wife were walking home from the shopping mall with their purchases when the husband began to complain that his load was too heavy. The wife turned to her husband and said \"I don't know what you're complaining about because if you gave me one of your parcels, I would have twice as many as you, and if I gave you just one of mine, we would have equal loads.\" How many parcels were each carrying?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe wife was carrying seven parcels and the husband was carrying five.\n<|im_start|>answer\nThe wife was carrying seven parcels and the husband was carrying five.\n<|im_end|>" }, { "id": "#41503", "title": "iPod Shuffle", "fun": 2.62, "difficulty": 1.45, "author": "sokrchic", "desc": "Karen was playing with her iPod on the way to work one day, when she accidentally erased all the information for five of her favorite songs! Now, with Karen's help, you have to help her remember the title of the song, the artist who sang it, and the album it was published on.\n\r\nSongs: Falling From Grace, Short Bus, New Kid, Apple Juice, and Riding My Dirt Bike\r\nArtists: April Henry, Brooke Smith, John Adams, Chelsey Johnson, and Brent Jones\r\nAlbums: Pencil and Pen, Don't Stop, Never Never, Gave You My Heart, and Cat and Mouse Games\n\r\nClues:\r\n1. The five songs are Falling From Grace, the one sang by Brooke Smith, the song from the album \"Never Never\", New Kid, and the song by John Adams.\r\n2. Brooke Smith was well known for making you thirsty after listening to her songs.\r\n3. Chelsey Johnson and April Henry both had songs with titles longer than two words.\r\n4. John Adams called his friend Brooke Smith to tell her about his new album \"Pencil and Pen\".\r\n5. Brooke was thrilled for John, but she was pretty happy about her new album too. Her album has the same number of words as her song.\r\n6. Chelsey Johnson \"fell from grace\" after she gave someone her heart.", "hint": "F. F. G. = Falling From Grace\r\nRiding Bike = Riding My Dirt Bike\r\nPencil/Pen = Pencil and Pen\r\nC. A. M. G. = Cat and Mouse Games\r\nG. Y. M. H. = Gave You My Heart", "answer": "Brooke Smith sang Apple Juice, which was on the album \"Don't Stop\".\r\nApril Henry sang Riding My Dirt Bike, which was on the album \"Never Never\".\r\nChelsey Johnson sang Falling From Grace, which was on the album \"Gave You My Heart\".\r\nJohn Adams sang Short Bus, which was on the album \"Pencil and Pen\".\r\nBrent Jones sang New Kid, which was on the album \"Cat and Mouse Games\".", "category": "Logic-Grid", "date": "04/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKaren was playing with her iPod on the way to work one day, when she accidentally erased all the information for five of her favorite songs! Now, with Karen's help, you have to help her remember the title of the song, the artist who sang it, and the album it was published on.\n\r\nSongs: Falling From Grace, Short Bus, New Kid, Apple Juice, and Riding My Dirt Bike\r\nArtists: April Henry, Brooke Smith, John Adams, Chelsey Johnson, and Brent Jones\r\nAlbums: Pencil and Pen, Don't Stop, Never Never, Gave You My Heart, and Cat and Mouse Games\n\r\nClues:\r\n1. The five songs are Falling From Grace, the one sang by Brooke Smith, the song from the album \"Never Never\", New Kid, and the song by John Adams.\r\n2. Brooke Smith was well known for making you thirsty after listening to her songs.\r\n3. Chelsey Johnson and April Henry both had songs with titles longer than two words.\r\n4. John Adams called his friend Brooke Smith to tell her about his new album \"Pencil and Pen\".\r\n5. Brooke was thrilled for John, but she was pretty happy about her new album too. Her album has the same number of words as her song.\r\n6. Chelsey Johnson \"fell from grace\" after she gave someone her heart.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrooke Smith sang Apple Juice, which was on the album \"Don't Stop\".\r\nApril Henry sang Riding My Dirt Bike, which was on the album \"Never Never\".\r\nChelsey Johnson sang Falling From Grace, which was on the album \"Gave You My Heart\".\r\nJohn Adams sang Short Bus, which was on the album \"Pencil and Pen\".\r\nBrent Jones sang New Kid, which was on the album \"Cat and Mouse Games\".\n<|im_start|>answer\nBrooke Smith sang Apple Juice, which was on the album \"Don't Stop\".\r\nApril Henry sang Riding My Dirt Bike, which was on the album \"Never Never\".\r\nChelsey Johnson sang Falling From Grace, which was on the album \"Gave You My Heart\".\r\nJohn Adams sang Short Bus, which was on the album \"Pencil and Pen\".\r\nBrent Jones sang New Kid, which was on the album \"Cat and Mouse Games\".\n<|im_end|>" }, { "id": "#44524", "title": "Watson Family Vacation", "fun": 2.62, "difficulty": 1.82, "author": "mrsfessler", "desc": "The Watsons are planning their summer vacation. Each family member wants to visit a different setting in a different state and do two different activities. From the clues, determine the state and setting where each member wants to vacation and the two activities each wants to do.\n\r\n1. The 5 family members are represented by Rose, the boy who wants to visit NC, the one who likes to hike, the boater and the girl who likes to swim.\r\n2. The two sightseers are the sister who wants to go to the lake and the sister who wants to go to PA. Like most men, Bud and Bruce hate shopping.\r\n3. Bud's little sister loves to hike. Both of the activities of the one who wants to visit SC involves water. The mother would love to see some shows in the big city!\r\n4. The oldest sibling, Lisa, loved her last trip to TN and wants to return. The brother loves the mountains and horses. \r\n5. Bruce's youngest daughter loves rural scenery.", "hint": "Rose is the mother. Bruce is the father. Jordan is the youngest daughter. Bud is the middle child.", "answer": "Lisa: Lake, TN, Swimming and Sightseeing\r\nRose: City, NY, Shopping and Shows\r\nBud: Mountains, NC, Horseback Riding and Waterparks\r\nJordan: Rural, PA, Hiking and Sightseeing\r\nBruce: Beach, SC, Fishing and Boating", "category": "Logic-Grid", "date": "05/26/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Watsons are planning their summer vacation. Each family member wants to visit a different setting in a different state and do two different activities. From the clues, determine the state and setting where each member wants to vacation and the two activities each wants to do.\n\r\n1. The 5 family members are represented by Rose, the boy who wants to visit NC, the one who likes to hike, the boater and the girl who likes to swim.\r\n2. The two sightseers are the sister who wants to go to the lake and the sister who wants to go to PA. Like most men, Bud and Bruce hate shopping.\r\n3. Bud's little sister loves to hike. Both of the activities of the one who wants to visit SC involves water. The mother would love to see some shows in the big city!\r\n4. The oldest sibling, Lisa, loved her last trip to TN and wants to return. The brother loves the mountains and horses. \r\n5. Bruce's youngest daughter loves rural scenery.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLisa: Lake, TN, Swimming and Sightseeing\r\nRose: City, NY, Shopping and Shows\r\nBud: Mountains, NC, Horseback Riding and Waterparks\r\nJordan: Rural, PA, Hiking and Sightseeing\r\nBruce: Beach, SC, Fishing and Boating\n<|im_start|>answer\nLisa: Lake, TN, Swimming and Sightseeing\r\nRose: City, NY, Shopping and Shows\r\nBud: Mountains, NC, Horseback Riding and Waterparks\r\nJordan: Rural, PA, Hiking and Sightseeing\r\nBruce: Beach, SC, Fishing and Boating\n<|im_end|>" }, { "id": "#44478", "title": "Flowers on Mother's Day", "fun": 2.62, "difficulty": 2.05, "author": "mrsfessler", "desc": "5 children gave their mothers different types of flowers for Mother's Day. Can you determine each child's first and last name, their mother's name and what type of flower they gave?\n\r\n1. Tanya's daughter gave her either roses or a mixed bouquet.\t\r\n2. The Wolfe boy gave his mother, who was either Tina \t\r\nor Tabby, pansies.\t\r\n3. Mrs. Drake did not receive a mixed bouquet.\t\r\n4. The five moms are represented by Mrs. Fox, Buddy, the girl \t\r\nwho gave the roses, Tammy's son and Tabby.\t\r\n5. Billy's mom loved her azaleas. Mrs. Bird did not receive \t\r\na mixed bouquet or roses from her son.\t\r\n6. Tina doesn't like violets or pansies, they're too much alike. \t\r\nThe violets were given by either Buddy or Barbie\t\r\n7.Barbie's mom was either Mrs. Lyon or Mrs. Drake.\t\r\n8. Mrs. Bird's sister, Tina, loved her roses.\t\r\n9. Barbie's Aunt Terry loved her flowers because they \t\r\nwere her favorite color.\t\r\n10. Buddy and Mrs. Drake's child are cousins.", "hint": "Bobby is a boy.", "answer": "Billy Lyon gave Tammy azaleas.\r\nBobby Wolfe gave Tabby pansies.\r\nBetty Fox gave Tanya a mixed bouquet.\r\nBuddy Bird gave Terry violets.\r\nBarbie Drake gave Tina roses.", "category": "Logic-Grid", "date": "05/18/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 children gave their mothers different types of flowers for Mother's Day. Can you determine each child's first and last name, their mother's name and what type of flower they gave?\n\r\n1. Tanya's daughter gave her either roses or a mixed bouquet.\t\r\n2. The Wolfe boy gave his mother, who was either Tina \t\r\nor Tabby, pansies.\t\r\n3. Mrs. Drake did not receive a mixed bouquet.\t\r\n4. The five moms are represented by Mrs. Fox, Buddy, the girl \t\r\nwho gave the roses, Tammy's son and Tabby.\t\r\n5. Billy's mom loved her azaleas. Mrs. Bird did not receive \t\r\na mixed bouquet or roses from her son.\t\r\n6. Tina doesn't like violets or pansies, they're too much alike. \t\r\nThe violets were given by either Buddy or Barbie\t\r\n7.Barbie's mom was either Mrs. Lyon or Mrs. Drake.\t\r\n8. Mrs. Bird's sister, Tina, loved her roses.\t\r\n9. Barbie's Aunt Terry loved her flowers because they \t\r\nwere her favorite color.\t\r\n10. Buddy and Mrs. Drake's child are cousins.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBilly Lyon gave Tammy azaleas.\r\nBobby Wolfe gave Tabby pansies.\r\nBetty Fox gave Tanya a mixed bouquet.\r\nBuddy Bird gave Terry violets.\r\nBarbie Drake gave Tina roses.\n<|im_start|>answer\nBilly Lyon gave Tammy azaleas.\r\nBobby Wolfe gave Tabby pansies.\r\nBetty Fox gave Tanya a mixed bouquet.\r\nBuddy Bird gave Terry violets.\r\nBarbie Drake gave Tina roses.\n<|im_end|>" }, { "id": "#519", "title": "Liars and Truth Tellers", "fun": 2.62, "difficulty": 1.87, "author": "kaila912", "desc": "You approach two magic talking doors. One door leads to the City of Truth, while the other door leads to the City of Liars. You do not know which door is which. You are able to ask only one question to determine which door is which. The door that leads to the City of Liars always speaks lies, while the door that leads to the City of Truth always speaks the truth. You want to go to the City of Truth. What question do you ask to determine which door leads to the City of Truth?", "hint": "No hint available.", "answer": "Answer #1: You ask a door - \"If I were to ask the other door which door leads to the city of truth, what would he say?\" and then you pick the opposite door of what he tells you.\r\nAnswer #2: Ask the door - \"If I asked you which door leads to the city of truth before, which door would you have told me?\" (negative and negative = positive, positive and positive = positive). and you choose the door that it directs you to.", "category": "Logic", "date": "05/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou approach two magic talking doors. One door leads to the City of Truth, while the other door leads to the City of Liars. You do not know which door is which. You are able to ask only one question to determine which door is which. The door that leads to the City of Liars always speaks lies, while the door that leads to the City of Truth always speaks the truth. You want to go to the City of Truth. What question do you ask to determine which door leads to the City of Truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer #1: You ask a door - \"If I were to ask the other door which door leads to the city of truth, what would he say?\" and then you pick the opposite door of what he tells you.\r\nAnswer #2: Ask the door - \"If I asked you which door leads to the city of truth before, which door would you have told me?\" (negative and negative = positive, positive and positive = positive). and you choose the door that it directs you to.\n<|im_start|>answer\nAnswer #1: You ask a door - \"If I were to ask the other door which door leads to the city of truth, what would he say?\" and then you pick the opposite door of what he tells you.\r\nAnswer #2: Ask the door - \"If I asked you which door leads to the city of truth before, which door would you have told me?\" (negative and negative = positive, positive and positive = positive). and you choose the door that it directs you to.\n<|im_end|>" }, { "id": "#29069", "title": "Party Places", "fun": 2.62, "difficulty": 1.44, "author": "shenqiang", "desc": "There are 6 places set at each table for the big outdoor party. All the tables and chairs have 4 legs each, and altogether the tables and chairs have a total of 196 legs.\n\r\nIf there is one place set for each person who will attend, how many people are expected to come to the big party?", "hint": "Figure out how many chair and table legs are at each table, and then work backwards or guess and check.", "answer": "42 people are expected to come to the big party.\n\r\nEach table has 6 chairs, so there are a total of 7*4=28 legs at each table. \r\nSo, 196/28=7 tables. \r\nTherefore, 7*6=42 guests who are expected to come to the party.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 6 places set at each table for the big outdoor party. All the tables and chairs have 4 legs each, and altogether the tables and chairs have a total of 196 legs.\n\r\nIf there is one place set for each person who will attend, how many people are expected to come to the big party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n42 people are expected to come to the big party.\n\r\nEach table has 6 chairs, so there are a total of 7*4=28 legs at each table. \r\nSo, 196/28=7 tables. \r\nTherefore, 7*6=42 guests who are expected to come to the party.\n<|im_start|>answer\n42 people are expected to come to the big party.\n\r\nEach table has 6 chairs, so there are a total of 7*4=28 legs at each table. \r\nSo, 196/28=7 tables. \r\nTherefore, 7*6=42 guests who are expected to come to the party.\n<|im_end|>" }, { "id": "#31782", "title": "Opposites 22", "fun": 2.62, "difficulty": 2.87, "author": "Winner4600", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n! stands for T, E, O, Z, or Y\r\n? stands for F, G, A, Q, or I\r\n# stands for N, I, W, A, or U\r\n$ stands for T, E, N, I, or H\r\n< stands for R, C, A, S, or B\r\n* stands for I, D, E, U, or S\r\n& stands for J, I, E, P, or K\r\n^ stands for O, L, G, I, or H\r\n> stands for L, S, N, C, or E \n\r\nThe nine letter code word, <$^&?*!#>, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Religious and Atheistic.", "category": "Logic", "date": "07/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n! stands for T, E, O, Z, or Y\r\n? stands for F, G, A, Q, or I\r\n# stands for N, I, W, A, or U\r\n$ stands for T, E, N, I, or H\r\n< stands for R, C, A, S, or B\r\n* stands for I, D, E, U, or S\r\n& stands for J, I, E, P, or K\r\n^ stands for O, L, G, I, or H\r\n> stands for L, S, N, C, or E \n\r\nThe nine letter code word, <$^&?*!#>, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nReligious and Atheistic.\n<|im_start|>answer\nReligious and Atheistic.\n<|im_end|>" }, { "id": "#39845", "title": "Christmas Gifts", "fun": 2.62, "difficulty": 3.0, "author": "mocha613", "desc": "The Smith family was getting very excited for Christmas Eve. Because they have some \"package shakers\" in their family (people who like trying to figure out what they are getting by shaking their gift), the family has decided to hold off on adding gift tags until the giving begins. Unfortunately, they have forgotten what package goes to which family member! There are only 5 packages under their tree, and each person will receive one gift. They are each wrapped in different paper as well as different color ribbon. Help the Smiths sort out their gifts!!!\n\r\nOne of the men gave a gift to their sister and the other gave one to their son. Neither of them used the Snowflake or Bell wrapping paper because they are too \"girly.\"\n\r\nNo gift was wrapped in paper and ribbon of the same color. Else loved the gift she received, which was wrapped in her favorite wrapping paper, the white snowmen, and a ribbon that was not silver or gold.\n\r\nThe girl who received the package with green ribbon did not receive the bracelet or book. The package with red ribbon was not for the man who gave a bowling ball or bicycle.\n\r\nThe five family members were the one who gave to mother, the one who gave a bowling ball, the one who used silver ribbon, the one who used the blue snowflake wrapping paper, and Lauren.\n\r\nElse didn't give a gift to her mother because she lives 3 states away. She also didn't give a gift to her husband, Russ, because they had just recently celebrated their anniversary.\n\r\nNed didn't want a bicycle, so he received something else. Neither daughter received a gift with a green ribbon.\n\r\nSanta lost his shape when one family member tried to wrap a gift that was spherical. The book was wrapped in paper that did not have snow on it.\n\r\nGift givers: Cindy, Ned, Russ, Lauren, Else\r\nGift recipients: Mom, Dad, Son, Daugher, Sister\r\nWrapping Paper: Blue Snowflakes, Red Santas, Green Trees, White Snowmen, Gold Bells\r\nRibbon Color: Blue, Red, Green, Silver, Gold\r\nGift: Bicycle, Book, Building Blocks, Bracelet, Bowling Ball", "hint": "It will be helpful to determine the relationships between people as you go along.", "answer": "Cindy gave her mom, Else, building blocks wrapped in white snowmen paper with green ribbon.\r\nNed gave his sister, Lauren, a bicycle wrapped in green trees paper with silver ribbon.\r\nRuss gave his son, Ned, a bowling ball wrapped in red Santa paper with gold ribbon.\r\nLauren gave her dad, Russ, a book wrapped in gold bells paper with blue ribbon.\r\nElse gave her daughter, Cindy, a bracelet wrapped in blue snowflakes paper with red ribbon.", "category": "Logic-Grid", "date": "12/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Smith family was getting very excited for Christmas Eve. Because they have some \"package shakers\" in their family (people who like trying to figure out what they are getting by shaking their gift), the family has decided to hold off on adding gift tags until the giving begins. Unfortunately, they have forgotten what package goes to which family member! There are only 5 packages under their tree, and each person will receive one gift. They are each wrapped in different paper as well as different color ribbon. Help the Smiths sort out their gifts!!!\n\r\nOne of the men gave a gift to their sister and the other gave one to their son. Neither of them used the Snowflake or Bell wrapping paper because they are too \"girly.\"\n\r\nNo gift was wrapped in paper and ribbon of the same color. Else loved the gift she received, which was wrapped in her favorite wrapping paper, the white snowmen, and a ribbon that was not silver or gold.\n\r\nThe girl who received the package with green ribbon did not receive the bracelet or book. The package with red ribbon was not for the man who gave a bowling ball or bicycle.\n\r\nThe five family members were the one who gave to mother, the one who gave a bowling ball, the one who used silver ribbon, the one who used the blue snowflake wrapping paper, and Lauren.\n\r\nElse didn't give a gift to her mother because she lives 3 states away. She also didn't give a gift to her husband, Russ, because they had just recently celebrated their anniversary.\n\r\nNed didn't want a bicycle, so he received something else. Neither daughter received a gift with a green ribbon.\n\r\nSanta lost his shape when one family member tried to wrap a gift that was spherical. The book was wrapped in paper that did not have snow on it.\n\r\nGift givers: Cindy, Ned, Russ, Lauren, Else\r\nGift recipients: Mom, Dad, Son, Daugher, Sister\r\nWrapping Paper: Blue Snowflakes, Red Santas, Green Trees, White Snowmen, Gold Bells\r\nRibbon Color: Blue, Red, Green, Silver, Gold\r\nGift: Bicycle, Book, Building Blocks, Bracelet, Bowling Ball\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCindy gave her mom, Else, building blocks wrapped in white snowmen paper with green ribbon.\r\nNed gave his sister, Lauren, a bicycle wrapped in green trees paper with silver ribbon.\r\nRuss gave his son, Ned, a bowling ball wrapped in red Santa paper with gold ribbon.\r\nLauren gave her dad, Russ, a book wrapped in gold bells paper with blue ribbon.\r\nElse gave her daughter, Cindy, a bracelet wrapped in blue snowflakes paper with red ribbon.\n<|im_start|>answer\nCindy gave her mom, Else, building blocks wrapped in white snowmen paper with green ribbon.\r\nNed gave his sister, Lauren, a bicycle wrapped in green trees paper with silver ribbon.\r\nRuss gave his son, Ned, a bowling ball wrapped in red Santa paper with gold ribbon.\r\nLauren gave her dad, Russ, a book wrapped in gold bells paper with blue ribbon.\r\nElse gave her daughter, Cindy, a bracelet wrapped in blue snowflakes paper with red ribbon.\n<|im_end|>" }, { "id": "#1762", "title": "Unusual fractions", "fun": 2.62, "difficulty": 2.18, "author": "Nishoo", "desc": "What is so unusual about these fractions ?\n\r\n 19/95 26/65\t 16/64", "hint": "No hint available.", "answer": "Each one can be reduced to its simplest form merely by cancelling the number which is common to both its numerator and its denominator.", "category": "Math", "date": "12/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is so unusual about these fractions ?\n\r\n 19/95 26/65\t 16/64\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach one can be reduced to its simplest form merely by cancelling the number which is common to both its numerator and its denominator.\n<|im_start|>answer\nEach one can be reduced to its simplest form merely by cancelling the number which is common to both its numerator and its denominator.\n<|im_end|>" }, { "id": "#11770", "title": "Breaking Bread", "fun": 2.62, "difficulty": 1.6400000000000001, "author": "jimbo", "desc": "Three travellers met at a lonely oasis. One had 3 loaves of bread, but no money; another had 5 loaves of bread, but no money; while the third had only money. They sat down to a meal and the kind travellers shared their bread equally among all 3. In the morning, the traveller with the money departed leaving 8 silver coins for the other 2 in payment for the bread. How should they share the coins fairly?", "hint": "The one who contributed more should get a larger share.", "answer": "Since they all shared the 8 loaves they ate 2 2/3 loaves each. Thus one gave 1/3 of a loaf while the other gave 2 1/3 loaves to the man with none. The second one gave 7 times as much and should receive 7 times as much back as the other.\r\nThe first should get one coin while the other gets 7 coins.", "category": "Math", "date": "04/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree travellers met at a lonely oasis. One had 3 loaves of bread, but no money; another had 5 loaves of bread, but no money; while the third had only money. They sat down to a meal and the kind travellers shared their bread equally among all 3. In the morning, the traveller with the money departed leaving 8 silver coins for the other 2 in payment for the bread. How should they share the coins fairly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince they all shared the 8 loaves they ate 2 2/3 loaves each. Thus one gave 1/3 of a loaf while the other gave 2 1/3 loaves to the man with none. The second one gave 7 times as much and should receive 7 times as much back as the other.\r\nThe first should get one coin while the other gets 7 coins.\n<|im_start|>answer\nSince they all shared the 8 loaves they ate 2 2/3 loaves each. Thus one gave 1/3 of a loaf while the other gave 2 1/3 loaves to the man with none. The second one gave 7 times as much and should receive 7 times as much back as the other.\r\nThe first should get one coin while the other gets 7 coins.\n<|im_end|>" }, { "id": "#28595", "title": "A Drive Out of Town", "fun": 2.62, "difficulty": 2.18, "author": "RainyMysteria", "desc": "Abe Drivers has to drive 200 km once a week to pick up his deliveries from the post office. He then quickly drives home to open them up.\n\r\nOne week, he left off and, expecting something, drove at 110 km/h. When he reached the post office, there was nothing, so he drove home at the same speed, feeling disappointed.\n\r\nThe next week, he drove at 105 km/h and when he reached the post office, he was able to pick up a big package. When he drove home, he was travelling at 115 km/h.\n\r\nHis daughter, Raine, came down and, being the most curious of girls and the most brilliant of mathematicians, asked her dad how fast he drove for both weeks. When he answered, he said that they took the same time. But Raine disagreed.\n\r\nWho was correct? Raine or Abe? If Abe, how long did it take him to drive there and back? If Raine, how many hours/minutes/seconds was there in the difference?", "hint": "No hint available.", "answer": "Raine was right.\n\r\nDrive A: 200km. 110km/h. 200/110=1.818 [1.818*2= 3.636]\n\r\nDrive B: 200km. 105km/h. 200/105=1.905 115km/h. 200/115=1.739 [1.905+1.739= 3.644]\n\r\nConverting it, A takes 3h 38m 10s and B takes 3h 38m 38s. Therefore, Drive A took 28 fewer seconds than Drive B.", "category": "Math", "date": "02/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbe Drivers has to drive 200 km once a week to pick up his deliveries from the post office. He then quickly drives home to open them up.\n\r\nOne week, he left off and, expecting something, drove at 110 km/h. When he reached the post office, there was nothing, so he drove home at the same speed, feeling disappointed.\n\r\nThe next week, he drove at 105 km/h and when he reached the post office, he was able to pick up a big package. When he drove home, he was travelling at 115 km/h.\n\r\nHis daughter, Raine, came down and, being the most curious of girls and the most brilliant of mathematicians, asked her dad how fast he drove for both weeks. When he answered, he said that they took the same time. But Raine disagreed.\n\r\nWho was correct? Raine or Abe? If Abe, how long did it take him to drive there and back? If Raine, how many hours/minutes/seconds was there in the difference?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRaine was right.\n\r\nDrive A: 200km. 110km/h. 200/110=1.818 [1.818*2= 3.636]\n\r\nDrive B: 200km. 105km/h. 200/105=1.905 115km/h. 200/115=1.739 [1.905+1.739= 3.644]\n\r\nConverting it, A takes 3h 38m 10s and B takes 3h 38m 38s. Therefore, Drive A took 28 fewer seconds than Drive B.\n<|im_start|>answer\nRaine was right.\n\r\nDrive A: 200km. 110km/h. 200/110=1.818 [1.818*2= 3.636]\n\r\nDrive B: 200km. 105km/h. 200/105=1.905 115km/h. 200/115=1.739 [1.905+1.739= 3.644]\n\r\nConverting it, A takes 3h 38m 10s and B takes 3h 38m 38s. Therefore, Drive A took 28 fewer seconds than Drive B.\n<|im_end|>" }, { "id": "#44303", "title": "Produce at the Fair", "fun": 2.62, "difficulty": 1.82, "author": "whsprec", "desc": "The top five prizewinners in the veggie contest at the county fair had the last names of Brown, Wilcox, Byrd, Whittier, and Holden. In no particular order, their first names are Joe, Trevor, Malcolm, Daniel, and Walter. From the clues given, determine the first and last name of each winner, the type of produce that they grew (pumpkin, watermelon, corn, radish, or squash), and the prize, first through fifth, that they won.\n\r\n1. Wilcox's produce finished ahead of the squash, which finished ahead of Walter's veggie, but none of these won first prize.\r\n2. Neither Malcolm nor Holden entered the watermelon or the pumpkin.\r\n3. The Whittier pumpkin placed higher than Daniel's entry, which in turn did better than Mr. Brown's corn.\r\n4. Mr. Wilcox's produce finished behind Whittier's veggie and they both finished behind Trevor's produce.\r\n5. Trevor's last name is not Holden and he did not grow the corn.", "hint": "No hint available.", "answer": "First - Trevor Byrd - Watermelon\r\nSecond - Joe Whittier - Pumpkin\r\nThird - Malcolm Wilcox - Radish\r\nFourth - Daniel Holden - Squash\r\nFifth - Walter Brown - Corn", "category": "Logic-Grid", "date": "03/30/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe top five prizewinners in the veggie contest at the county fair had the last names of Brown, Wilcox, Byrd, Whittier, and Holden. In no particular order, their first names are Joe, Trevor, Malcolm, Daniel, and Walter. From the clues given, determine the first and last name of each winner, the type of produce that they grew (pumpkin, watermelon, corn, radish, or squash), and the prize, first through fifth, that they won.\n\r\n1. Wilcox's produce finished ahead of the squash, which finished ahead of Walter's veggie, but none of these won first prize.\r\n2. Neither Malcolm nor Holden entered the watermelon or the pumpkin.\r\n3. The Whittier pumpkin placed higher than Daniel's entry, which in turn did better than Mr. Brown's corn.\r\n4. Mr. Wilcox's produce finished behind Whittier's veggie and they both finished behind Trevor's produce.\r\n5. Trevor's last name is not Holden and he did not grow the corn.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst - Trevor Byrd - Watermelon\r\nSecond - Joe Whittier - Pumpkin\r\nThird - Malcolm Wilcox - Radish\r\nFourth - Daniel Holden - Squash\r\nFifth - Walter Brown - Corn\n<|im_start|>answer\nFirst - Trevor Byrd - Watermelon\r\nSecond - Joe Whittier - Pumpkin\r\nThird - Malcolm Wilcox - Radish\r\nFourth - Daniel Holden - Squash\r\nFifth - Walter Brown - Corn\n<|im_end|>" }, { "id": "#29808", "title": "Blocks", "fun": 2.62, "difficulty": 2.78, "author": "peppamintp", "desc": "A single letter is on each of the six sides of four toy blocks. No letter is repeated. Any side of a block can be face up, and the blocks can be in any order. The twelve words listed below can be spelled face up using the four blocks.\r\nWhat are the six letters on each block?\n\r\n1. Brim\r\n2. Clip\r\n3. Hank\r\n4. Hoax\r\n5. Home\r\n6. Puny\r\n7. Quit\r\n8. Rude\r\n9. Stow\r\n10. Vein\r\n11. Wife\r\n12. Zeal", "hint": "No hint available.", "answer": "1. ACMUVW\r\n2. BEKPTX\r\n3. DHISYZ\r\n4. FLNOQR", "category": "Logic", "date": "04/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA single letter is on each of the six sides of four toy blocks. No letter is repeated. Any side of a block can be face up, and the blocks can be in any order. The twelve words listed below can be spelled face up using the four blocks.\r\nWhat are the six letters on each block?\n\r\n1. Brim\r\n2. Clip\r\n3. Hank\r\n4. Hoax\r\n5. Home\r\n6. Puny\r\n7. Quit\r\n8. Rude\r\n9. Stow\r\n10. Vein\r\n11. Wife\r\n12. Zeal\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. ACMUVW\r\n2. BEKPTX\r\n3. DHISYZ\r\n4. FLNOQR\n<|im_start|>answer\n1. ACMUVW\r\n2. BEKPTX\r\n3. DHISYZ\r\n4. FLNOQR\n<|im_end|>" }, { "id": "#36488", "title": "Marital Bliss", "fun": 2.62, "difficulty": 1.12, "author": "camrae27", "desc": "Five couples were married last week, each on a different weekday. From the information provided, determine the woman (one is Cathy) and man (one is Paul) who made up each couple, as well as the day on which each couple was married.\n\r\n1. Anne was married on Monday, but not to Wally.\r\n2. Stan's wedding was on Wednesday, Rob was married on Friday, but not to Ida.\r\n3. Vern (who married Fran) was married the day after Eve.", "hint": "No hint available.", "answer": "Anne and Paul- Monday\r\nCathy and Rob- Friday\r\nEve and Stan- Wednesday\r\nFran and Vern- Thursday\r\nIda and Wally- Tuesday", "category": "Logic-Grid", "date": "05/03/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive couples were married last week, each on a different weekday. From the information provided, determine the woman (one is Cathy) and man (one is Paul) who made up each couple, as well as the day on which each couple was married.\n\r\n1. Anne was married on Monday, but not to Wally.\r\n2. Stan's wedding was on Wednesday, Rob was married on Friday, but not to Ida.\r\n3. Vern (who married Fran) was married the day after Eve.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnne and Paul- Monday\r\nCathy and Rob- Friday\r\nEve and Stan- Wednesday\r\nFran and Vern- Thursday\r\nIda and Wally- Tuesday\n<|im_start|>answer\nAnne and Paul- Monday\r\nCathy and Rob- Friday\r\nEve and Stan- Wednesday\r\nFran and Vern- Thursday\r\nIda and Wally- Tuesday\n<|im_end|>" }, { "id": "#3151", "title": "Hunting the Bear", "fun": 2.62, "difficulty": 1.18, "author": "204_blaze_41", "desc": "\"I told you,\" cried Sid Shadier. \"I came up north to track and kill the great brown bear that attacked that family of campers. On my second day I found his tracks, and by nightfall I was hot on his trail. Early the next morning I sighted him heading east. The sun was shining in my eyes so I couldn't see much more than his silhouette. The bear was uncanny. He lost me several minutes later when he cut through a stream. Knowing he might hide and charge me, I got behind a rock and squinted into the sun to search for movement. Suddenly a shadow came up from behind me. Panicked, but certain it was the bear, I whirled around and shot. To my horror I shot and killed Dan Manly.\"\r\n\"That story won't stand,\" said Shadow.\n\r\nWhy not?", "hint": "No hint available.", "answer": "Shadier said he was squinting into the sun hoping to locate movement of the bear. It would be impossible for a shadow to come up from behind him. All shadows would be cast in the opposite direction.", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"I told you,\" cried Sid Shadier. \"I came up north to track and kill the great brown bear that attacked that family of campers. On my second day I found his tracks, and by nightfall I was hot on his trail. Early the next morning I sighted him heading east. The sun was shining in my eyes so I couldn't see much more than his silhouette. The bear was uncanny. He lost me several minutes later when he cut through a stream. Knowing he might hide and charge me, I got behind a rock and squinted into the sun to search for movement. Suddenly a shadow came up from behind me. Panicked, but certain it was the bear, I whirled around and shot. To my horror I shot and killed Dan Manly.\"\r\n\"That story won't stand,\" said Shadow.\n\r\nWhy not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShadier said he was squinting into the sun hoping to locate movement of the bear. It would be impossible for a shadow to come up from behind him. All shadows would be cast in the opposite direction.\n<|im_start|>answer\nShadier said he was squinting into the sun hoping to locate movement of the bear. It would be impossible for a shadow to come up from behind him. All shadows would be cast in the opposite direction.\n<|im_end|>" }, { "id": "#6431", "title": "Reptile House", "fun": 2.62, "difficulty": 1.98, "author": "NuttyPrince", "desc": "At a recent visit to the reptile house at the local zoo, I counted a total of 27 heads and 70 feet. I was counting snakes, lizards, and people. I know that there were exactly twice as many lizards as people. How many snakes did I count?", "hint": "No hint available.", "answer": "6 snakes, 7 people, and 14 lizards.", "category": "Math", "date": "08/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a recent visit to the reptile house at the local zoo, I counted a total of 27 heads and 70 feet. I was counting snakes, lizards, and people. I know that there were exactly twice as many lizards as people. How many snakes did I count?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6 snakes, 7 people, and 14 lizards.\n<|im_start|>answer\n6 snakes, 7 people, and 14 lizards.\n<|im_end|>" }, { "id": "#21274", "title": "More Painters", "fun": 2.62, "difficulty": 0.8300000000000001, "author": "Cocokitty", "desc": "At the Painted House painting company they have 5 painters. The home-owners can choose from 5 paint colors; white, green, blue, yellow and brown. Can you figure out which painter painted which house with which color?\n\r\nClues:\r\n1. Painter 3 painted his house white.\r\n2. House 1 wasn't painted green or yellow.\r\n3. Painters 1 and 4 didn't use green or blue paint.\r\n4. Houses 1, 3 and 5 weren't painted brown.\r\n5. Painters 2, 4 and 5 didn't use brown paint.\r\n6. Houses 1, 3 and 4 weren't painted white.\r\n7. Painter 2 didn't use green or yellow paint.\r\n8. Houses 2 and 5 weren't painted green.\r\n9. Houses 3 and 4 weren't painted yellow.\r\n10. House 2 was not painted white.", "hint": "No hint available.", "answer": "Painter 1. House 4. Brown\r\nPainter 2. House 1. Blue\r\nPainter 3. House 5. White\r\nPainter 4. House 2. Yellow\r\nPainter 5. House 3. Green", "category": "Logic-Grid", "date": "02/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the Painted House painting company they have 5 painters. The home-owners can choose from 5 paint colors; white, green, blue, yellow and brown. Can you figure out which painter painted which house with which color?\n\r\nClues:\r\n1. Painter 3 painted his house white.\r\n2. House 1 wasn't painted green or yellow.\r\n3. Painters 1 and 4 didn't use green or blue paint.\r\n4. Houses 1, 3 and 5 weren't painted brown.\r\n5. Painters 2, 4 and 5 didn't use brown paint.\r\n6. Houses 1, 3 and 4 weren't painted white.\r\n7. Painter 2 didn't use green or yellow paint.\r\n8. Houses 2 and 5 weren't painted green.\r\n9. Houses 3 and 4 weren't painted yellow.\r\n10. House 2 was not painted white.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPainter 1. House 4. Brown\r\nPainter 2. House 1. Blue\r\nPainter 3. House 5. White\r\nPainter 4. House 2. Yellow\r\nPainter 5. House 3. Green\n<|im_start|>answer\nPainter 1. House 4. Brown\r\nPainter 2. House 1. Blue\r\nPainter 3. House 5. White\r\nPainter 4. House 2. Yellow\r\nPainter 5. House 3. Green\n<|im_end|>" }, { "id": "#40083", "title": "Who Broke the Window", "fun": 2.61, "difficulty": 2.39, "author": "shenqiang", "desc": "John, Pete, Tom, George, and Steve are brothers. One day, one of them broke a window. When their father asked them who did it, they gave the following answers:\r\nJohn: \"It was Pete or Tom.\"\r\nPete: \"It was neither George nor me.\"\r\nTom: \"Both of you are lying.\"\r\nSteve: \"No, only one of them is lying.\"\r\nGeorge: \"No, Steve, you are wrong.\"\r\nThen their mother added: \"Three of my sons are telling the truth, but I do not believe what the two others said.\"\n\r\nWho broke the window?", "hint": "If you find it difficult to use logic alone, then use trial and error by assuming each one of the five sons broke the window, and list whether they are telling a lie or the truth.", "answer": "By assuming that each of the five brothers broke the window and seeing how many told the truth, only Tom can be the person who broke the window.", "category": "Logic", "date": "01/16/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn, Pete, Tom, George, and Steve are brothers. One day, one of them broke a window. When their father asked them who did it, they gave the following answers:\r\nJohn: \"It was Pete or Tom.\"\r\nPete: \"It was neither George nor me.\"\r\nTom: \"Both of you are lying.\"\r\nSteve: \"No, only one of them is lying.\"\r\nGeorge: \"No, Steve, you are wrong.\"\r\nThen their mother added: \"Three of my sons are telling the truth, but I do not believe what the two others said.\"\n\r\nWho broke the window?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBy assuming that each of the five brothers broke the window and seeing how many told the truth, only Tom can be the person who broke the window.\n<|im_start|>answer\nBy assuming that each of the five brothers broke the window and seeing how many told the truth, only Tom can be the person who broke the window.\n<|im_end|>" }, { "id": "#48465", "title": "Messy Art Studio", "fun": 2.61, "difficulty": 1.46, "author": "Oxiproxd9", "desc": "Bob, Rich, Craig, George, and Brick were working in the art room with paints. Each boy had two paints, and they picked from red, orange, yellow, green, and blue. By accident, they bumped into each other, and their paint went flying. Luckily, the colors didn't mix, but they forgot whose was whose. They only had the following clues:\n\n\n\r\n-George's first color was a secondary color.\r\n-Only the kids with B's in their names picked the color yellow.\r\n-Brick's first color with George's second color created Rich's first color.\r\n-Those without I's in their name picked warm colors for their first color.\r\n-The second color Craig chose is the same as Rich's first color.\r\n-Both Rich's and George's colors are complementary.\r\n-Brick's colors are both warm.\r\n-No one chose the same color twice.\n\n\r\n(Note: warm colors are red, orange and yellow, whereas cool colors are blue, green and purple. complementary colors are blue and orange, yellow and purple, and green and red.)", "hint": "No hint available.", "answer": "Bob chose red and yellow.\r\nRich chose green and red.\r\nCraig chose blue and green.\r\nGeorge chose orange and blue\r\nBrick chose yellow and orange.", "category": "Logic-Grid", "date": "02/09/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob, Rich, Craig, George, and Brick were working in the art room with paints. Each boy had two paints, and they picked from red, orange, yellow, green, and blue. By accident, they bumped into each other, and their paint went flying. Luckily, the colors didn't mix, but they forgot whose was whose. They only had the following clues:\n\n\n\r\n-George's first color was a secondary color.\r\n-Only the kids with B's in their names picked the color yellow.\r\n-Brick's first color with George's second color created Rich's first color.\r\n-Those without I's in their name picked warm colors for their first color.\r\n-The second color Craig chose is the same as Rich's first color.\r\n-Both Rich's and George's colors are complementary.\r\n-Brick's colors are both warm.\r\n-No one chose the same color twice.\n\n\r\n(Note: warm colors are red, orange and yellow, whereas cool colors are blue, green and purple. complementary colors are blue and orange, yellow and purple, and green and red.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob chose red and yellow.\r\nRich chose green and red.\r\nCraig chose blue and green.\r\nGeorge chose orange and blue\r\nBrick chose yellow and orange.\n<|im_start|>answer\nBob chose red and yellow.\r\nRich chose green and red.\r\nCraig chose blue and green.\r\nGeorge chose orange and blue\r\nBrick chose yellow and orange.\n<|im_end|>" }, { "id": "#31082", "title": "Bragging and Truth", "fun": 2.61, "difficulty": 1.34, "author": "dishu", "desc": "The 4 friends met after a long time. Instead of fighting (their usual pastime), they starting recollecting the good old days. While at it, they could not prevent themselves from bragging about how good they were in their chosen field of study and who their favourite teacher was. It was a different matter though that everybody knew which activity the others really \"excelled\" in. \n\r\nCan you figure out which friend studied which course, who their favourite teacher was, and what activity they really \"excelled in\" with the help of these clues:\n\r\nFriends: Dis, Dip, Raj, Rich\r\nCourses: Marketing, OS, Finance, C++ \r\nTeachers: Mr. M, Mr. V, Ms. P and Ms. S\r\nActivity: Playing Piano, Gambling, Talking on Phone, Reading\n\r\n1. Ms. S has always been the favourite teacher of all marketing students.\n\r\n2. Raj used to spend 20 hrs a day talking to her long distance boyfriend.\n\r\n3. Rich, being true to her name, always thought of money only, as was clear by her choice of study course as well as activity.\n\r\n4. Dis loved reading all sorts of books as long as they had nothing to with her study course which was taught by Mr. M.\n\r\n5. The OS student was a really good Piano Player.\n\r\n6. Ms. P could have won many awards in OS research had she not met an untimely death.", "hint": "No hint available.", "answer": "Friend, Course, Teacher, Activity\r\nDis, C++, Mr. M, Reading\r\nDip, OS, Ms. P, Piano Playing\r\nRaj, Marketing, Ms. S, Talking on Phone\r\nRich, Finance, Mr. V, Gambling", "category": "Logic-Grid", "date": "06/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 4 friends met after a long time. Instead of fighting (their usual pastime), they starting recollecting the good old days. While at it, they could not prevent themselves from bragging about how good they were in their chosen field of study and who their favourite teacher was. It was a different matter though that everybody knew which activity the others really \"excelled\" in. \n\r\nCan you figure out which friend studied which course, who their favourite teacher was, and what activity they really \"excelled in\" with the help of these clues:\n\r\nFriends: Dis, Dip, Raj, Rich\r\nCourses: Marketing, OS, Finance, C++ \r\nTeachers: Mr. M, Mr. V, Ms. P and Ms. S\r\nActivity: Playing Piano, Gambling, Talking on Phone, Reading\n\r\n1. Ms. S has always been the favourite teacher of all marketing students.\n\r\n2. Raj used to spend 20 hrs a day talking to her long distance boyfriend.\n\r\n3. Rich, being true to her name, always thought of money only, as was clear by her choice of study course as well as activity.\n\r\n4. Dis loved reading all sorts of books as long as they had nothing to with her study course which was taught by Mr. M.\n\r\n5. The OS student was a really good Piano Player.\n\r\n6. Ms. P could have won many awards in OS research had she not met an untimely death.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriend, Course, Teacher, Activity\r\nDis, C++, Mr. M, Reading\r\nDip, OS, Ms. P, Piano Playing\r\nRaj, Marketing, Ms. S, Talking on Phone\r\nRich, Finance, Mr. V, Gambling\n<|im_start|>answer\nFriend, Course, Teacher, Activity\r\nDis, C++, Mr. M, Reading\r\nDip, OS, Ms. P, Piano Playing\r\nRaj, Marketing, Ms. S, Talking on Phone\r\nRich, Finance, Mr. V, Gambling\n<|im_end|>" }, { "id": "#28054", "title": "There is a Pattern With These Actors", "fun": 2.61, "difficulty": 2.04, "author": "Question_Mark", "desc": "Five actors, Billy Hunt, Ryan McCrazy, Jimmy Lymmon, Lauren Fender and Rosanna Folia, are shooting a scene in a new movie. Billy managed to do the scene correctly in 5 takes, then in every 7th take afterwards. Ryan managed to do the scene perfectly in the first take, but then he lost his touch and managed to do the scene correctly in every 9th take afterwards. Jimmy took 10 takes to do the scene correctly, but then he managed to do the scene correctly in every 4th take afterwards. Lauren wasn't very sure but she did the scene perfectly on the 4th take, however after that she took 6 takes to do the scene perfectly. Rosanna was perfect on the first and second takes, however after that she managed to do the scene correctly every 5th take.\n\r\nHow many takes did it take to shoot the scene?", "hint": "No hint available.", "answer": "The scene took 82 takes to be filmed perfectly.", "category": "Math", "date": "01/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive actors, Billy Hunt, Ryan McCrazy, Jimmy Lymmon, Lauren Fender and Rosanna Folia, are shooting a scene in a new movie. Billy managed to do the scene correctly in 5 takes, then in every 7th take afterwards. Ryan managed to do the scene perfectly in the first take, but then he lost his touch and managed to do the scene correctly in every 9th take afterwards. Jimmy took 10 takes to do the scene correctly, but then he managed to do the scene correctly in every 4th take afterwards. Lauren wasn't very sure but she did the scene perfectly on the 4th take, however after that she took 6 takes to do the scene perfectly. Rosanna was perfect on the first and second takes, however after that she managed to do the scene correctly every 5th take.\n\r\nHow many takes did it take to shoot the scene?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe scene took 82 takes to be filmed perfectly.\n<|im_start|>answer\nThe scene took 82 takes to be filmed perfectly.\n<|im_end|>" }, { "id": "#41155", "title": "Three Digit Number 2", "fun": 2.61, "difficulty": 1.28, "author": "Carlos16", "desc": "There is a three digit number. The sum of the digits is 17, and two of the digits are the same. The unique digit subtracted from one of the other digits equals a positive even number. What is the digit that is different from the other two digits?", "hint": "No hint available.", "answer": "If two of the numbers in the digit are the same, and the sum equals 17, the possible digits are 449, 557, 665, 773, and 881. Now you must subtract the unique digit from one of the other digits to get a positive even number. 449 and 557 result in negative numbers, so neither of them can be the answer. 665 results in 1, 773 results in 4, and 881 results in 7. 4 is the only one that is even, therefore, the digits have to be 7, 7, and 3.\n\r\nAnswer: 3", "category": "Math", "date": "03/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a three digit number. The sum of the digits is 17, and two of the digits are the same. The unique digit subtracted from one of the other digits equals a positive even number. What is the digit that is different from the other two digits?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf two of the numbers in the digit are the same, and the sum equals 17, the possible digits are 449, 557, 665, 773, and 881. Now you must subtract the unique digit from one of the other digits to get a positive even number. 449 and 557 result in negative numbers, so neither of them can be the answer. 665 results in 1, 773 results in 4, and 881 results in 7. 4 is the only one that is even, therefore, the digits have to be 7, 7, and 3.\n\r\nAnswer: 3\n<|im_start|>answer\nIf two of the numbers in the digit are the same, and the sum equals 17, the possible digits are 449, 557, 665, 773, and 881. Now you must subtract the unique digit from one of the other digits to get a positive even number. 449 and 557 result in negative numbers, so neither of them can be the answer. 665 results in 1, 773 results in 4, and 881 results in 7. 4 is the only one that is even, therefore, the digits have to be 7, 7, and 3.\n\r\nAnswer: 3\n<|im_end|>" }, { "id": "#40341", "title": "Mr. Tim Visits MIT", "fun": 2.61, "difficulty": 1.44, "author": "kratsg", "desc": "Timmie is wearing a T-shirt that says 'MIT' on the front and 'TIM' on the back. He takes it off, turning it inside-out in the process, and puts it on backward. The letters still show. What will he read on the front when he faces a mirror? On the back?", "hint": "The letters can be seen through the shirt, even if it's inside out.\n\r\nNo, Tim didn't go to MIT, he's just visiting (otherwise, he would've answered this for us easily).", "answer": "Front in mirror: TIM\r\nBack in mirror: MIT\n\r\nTimmie takes his shirt and turns it inside out, the front of the shirt (not in mirror) has TIM and the back has MIT.\n\r\nThen, he turns it around so the front has MIT and the back has TIM.\n\r\nWhen you view this in a mirror, it's reversed, again, so we see TIM in the front and MIT in the back (in the mirror).", "category": "Logic", "date": "02/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTimmie is wearing a T-shirt that says 'MIT' on the front and 'TIM' on the back. He takes it off, turning it inside-out in the process, and puts it on backward. The letters still show. What will he read on the front when he faces a mirror? On the back?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFront in mirror: TIM\r\nBack in mirror: MIT\n\r\nTimmie takes his shirt and turns it inside out, the front of the shirt (not in mirror) has TIM and the back has MIT.\n\r\nThen, he turns it around so the front has MIT and the back has TIM.\n\r\nWhen you view this in a mirror, it's reversed, again, so we see TIM in the front and MIT in the back (in the mirror).\n<|im_start|>answer\nFront in mirror: TIM\r\nBack in mirror: MIT\n\r\nTimmie takes his shirt and turns it inside out, the front of the shirt (not in mirror) has TIM and the back has MIT.\n\r\nThen, he turns it around so the front has MIT and the back has TIM.\n\r\nWhen you view this in a mirror, it's reversed, again, so we see TIM in the front and MIT in the back (in the mirror).\n<|im_end|>" }, { "id": "#23017", "title": "Apple Picking", "fun": 2.61, "difficulty": 1.73, "author": "FeaerFactorY666", "desc": "Three people picked 65 apples altogether. At the first tree they each picked the same number of apples. At the second tree they each picked 3 times as many as they picked at the first tree. When they finished at the third tree, the group had 5 times as many apples as they had when they started at that tree. At the fourth tree the group picked just 5 apples.\n\r\nHow many apples did each person pick at the first tree?", "hint": "Work backwards to see how many apples were picked at the last two trees or use algebra.", "answer": "Each person picked 1 apple at the first tree.\n\r\nBegin with 65 apples picked, and work backwards. Subtract the number of apples picked at the fourth tree (5), and then divide the total (60) by 5 to equal the number of apples picked after the first two trees. The total after the first two trees = 12. Since the number of apples picked at the first two trees (12) is equal to the number of apples picked at the first tree plus 3 times the number picked at the first tree (or a total of 4 times the number picked at the first tree), then the number of apples picked at the first tree must be 12 divided by 4 = 3. Therefore, each person picked 1 apple at the first tree.\n\r\nUsing algebra: Suppose they pick y apples at the first tree. Then, they pick 3y apples at the second tree and have 4y apples altogether. After the third tree, they have 5X4y or 20y apples, and after the fourth tree, they have 20y + 5 apples.\n\r\n20y + 5 = 65\r\n20y = 60\r\ny = 3\n\r\nSo each person picks 1 apple at the first tree.", "category": "Math", "date": "05/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people picked 65 apples altogether. At the first tree they each picked the same number of apples. At the second tree they each picked 3 times as many as they picked at the first tree. When they finished at the third tree, the group had 5 times as many apples as they had when they started at that tree. At the fourth tree the group picked just 5 apples.\n\r\nHow many apples did each person pick at the first tree?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach person picked 1 apple at the first tree.\n\r\nBegin with 65 apples picked, and work backwards. Subtract the number of apples picked at the fourth tree (5), and then divide the total (60) by 5 to equal the number of apples picked after the first two trees. The total after the first two trees = 12. Since the number of apples picked at the first two trees (12) is equal to the number of apples picked at the first tree plus 3 times the number picked at the first tree (or a total of 4 times the number picked at the first tree), then the number of apples picked at the first tree must be 12 divided by 4 = 3. Therefore, each person picked 1 apple at the first tree.\n\r\nUsing algebra: Suppose they pick y apples at the first tree. Then, they pick 3y apples at the second tree and have 4y apples altogether. After the third tree, they have 5X4y or 20y apples, and after the fourth tree, they have 20y + 5 apples.\n\r\n20y + 5 = 65\r\n20y = 60\r\ny = 3\n\r\nSo each person picks 1 apple at the first tree.\n<|im_start|>answer\nEach person picked 1 apple at the first tree.\n\r\nBegin with 65 apples picked, and work backwards. Subtract the number of apples picked at the fourth tree (5), and then divide the total (60) by 5 to equal the number of apples picked after the first two trees. The total after the first two trees = 12. Since the number of apples picked at the first two trees (12) is equal to the number of apples picked at the first tree plus 3 times the number picked at the first tree (or a total of 4 times the number picked at the first tree), then the number of apples picked at the first tree must be 12 divided by 4 = 3. Therefore, each person picked 1 apple at the first tree.\n\r\nUsing algebra: Suppose they pick y apples at the first tree. Then, they pick 3y apples at the second tree and have 4y apples altogether. After the third tree, they have 5X4y or 20y apples, and after the fourth tree, they have 20y + 5 apples.\n\r\n20y + 5 = 65\r\n20y = 60\r\ny = 3\n\r\nSo each person picks 1 apple at the first tree.\n<|im_end|>" }, { "id": "#199", "title": "The Land of Zog", "fun": 2.61, "difficulty": 1.78, "author": "Phyllis", "desc": "In the small country of Zog, each person owns one and only one car. Every car's license plate is different and each one contains only one letter and one one-digit number including zero. How many people live in the land of Zog, assuming every license plate is used?", "hint": "No hint available.", "answer": "520\n\r\n26 (letters of the alphabet) X 10 (1-digit numbers 0-9) = 260\n\r\nThat's only if each letter is before the number, but since it can be after, you have to double that.\n\r\n260 X 2 = 520", "category": "Math", "date": "02/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the small country of Zog, each person owns one and only one car. Every car's license plate is different and each one contains only one letter and one one-digit number including zero. How many people live in the land of Zog, assuming every license plate is used?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n520\n\r\n26 (letters of the alphabet) X 10 (1-digit numbers 0-9) = 260\n\r\nThat's only if each letter is before the number, but since it can be after, you have to double that.\n\r\n260 X 2 = 520\n<|im_start|>answer\n520\n\r\n26 (letters of the alphabet) X 10 (1-digit numbers 0-9) = 260\n\r\nThat's only if each letter is before the number, but since it can be after, you have to double that.\n\r\n260 X 2 = 520\n<|im_end|>" }, { "id": "#881", "title": "Locked in a Tower", "fun": 2.61, "difficulty": 2.22, "author": "Michelle", "desc": "A captive queen and her son and daughter were locked in the top room of a very high tower. Outside their window was a pulley with a rope around it, and a basket fastened to each end of the rope. Both baskets weighed the same. One basket is at the top of the tower, the other basket is on the ground. They managed to escape the tower using the pulley and baskets and a weight that they found in the room. It's too dangerous for any of them to come down if they weigh more than 15lbs more than the contents of the other basket, because they would do so too quickly. The one basket coming down would naturally of course draw the other up. The queen weighed 195 lbs. daughter 105, son 90, and the weight 75 lbs. How did they all escape safely?", "hint": "No hint available.", "answer": "This is one method of everyone getting out of the tower.\r\n1) They send the weight down and the empty basket comes up.\r\n2) The son goes down and the weight comes up.\r\n3) They take the weight out; the daughter goes down; the son up.\r\n4) The son gets out; the weight goes down and the empty basket comes up.\r\n5) The daughter puts the weight in the basket and climbs in. The queen goes down while the daughter and weight come up. The daughter gets out.\r\n6) The weight goes down and the empty basket comes up.\r\n7) Son goes down; weight comes up.\r\n8) Daughter removes weight, and goes down while the son comes up.\r\n9) Son sends down weight and the empty basket comes up.\r\n10) The son goes down and the weight comes up.\r\n11) Son gets out and the weight falls to the ground.", "category": "Logic", "date": "09/27/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA captive queen and her son and daughter were locked in the top room of a very high tower. Outside their window was a pulley with a rope around it, and a basket fastened to each end of the rope. Both baskets weighed the same. One basket is at the top of the tower, the other basket is on the ground. They managed to escape the tower using the pulley and baskets and a weight that they found in the room. It's too dangerous for any of them to come down if they weigh more than 15lbs more than the contents of the other basket, because they would do so too quickly. The one basket coming down would naturally of course draw the other up. The queen weighed 195 lbs. daughter 105, son 90, and the weight 75 lbs. How did they all escape safely?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis is one method of everyone getting out of the tower.\r\n1) They send the weight down and the empty basket comes up.\r\n2) The son goes down and the weight comes up.\r\n3) They take the weight out; the daughter goes down; the son up.\r\n4) The son gets out; the weight goes down and the empty basket comes up.\r\n5) The daughter puts the weight in the basket and climbs in. The queen goes down while the daughter and weight come up. The daughter gets out.\r\n6) The weight goes down and the empty basket comes up.\r\n7) Son goes down; weight comes up.\r\n8) Daughter removes weight, and goes down while the son comes up.\r\n9) Son sends down weight and the empty basket comes up.\r\n10) The son goes down and the weight comes up.\r\n11) Son gets out and the weight falls to the ground.\n<|im_start|>answer\nThis is one method of everyone getting out of the tower.\r\n1) They send the weight down and the empty basket comes up.\r\n2) The son goes down and the weight comes up.\r\n3) They take the weight out; the daughter goes down; the son up.\r\n4) The son gets out; the weight goes down and the empty basket comes up.\r\n5) The daughter puts the weight in the basket and climbs in. The queen goes down while the daughter and weight come up. The daughter gets out.\r\n6) The weight goes down and the empty basket comes up.\r\n7) Son goes down; weight comes up.\r\n8) Daughter removes weight, and goes down while the son comes up.\r\n9) Son sends down weight and the empty basket comes up.\r\n10) The son goes down and the weight comes up.\r\n11) Son gets out and the weight falls to the ground.\n<|im_end|>" }, { "id": "#3994", "title": "Eric, Adrian, Cedric, Derek", "fun": 2.61, "difficulty": 1.94, "author": "missie", "desc": "After a local bungled heist, five suspects were being interviewed by the police. Eventually the police managed to get a confession. Below is a summary of their statements and it turns out that exactly 5 of these statements were true. Would you make a good detective, try and work out who committed the crime? \n\r\nAdrian said:\r\nIt wasn't Barry\r\nIt was Cedric\n\r\nBarry said:\r\nIt wasn't Adrian\r\nIt was Derek\n\r\nCedric said:\r\nIt wasn't Derek\r\nIt wasn't Barry\n\r\nDerek said:\r\nIt wasn't Eric\r\nIt was Adrian\n\r\nEric said:\r\nIt wasn't Cedric\r\nIt was Derek", "hint": "No hint available.", "answer": "Eric committed the crime. One method of solving this teaser is to assume that it was Adrian, then work out how many of the statements would then have been true. Once you work out the number of statements for each suspect, you can determine the correct one.", "category": "Logic", "date": "05/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter a local bungled heist, five suspects were being interviewed by the police. Eventually the police managed to get a confession. Below is a summary of their statements and it turns out that exactly 5 of these statements were true. Would you make a good detective, try and work out who committed the crime? \n\r\nAdrian said:\r\nIt wasn't Barry\r\nIt was Cedric\n\r\nBarry said:\r\nIt wasn't Adrian\r\nIt was Derek\n\r\nCedric said:\r\nIt wasn't Derek\r\nIt wasn't Barry\n\r\nDerek said:\r\nIt wasn't Eric\r\nIt was Adrian\n\r\nEric said:\r\nIt wasn't Cedric\r\nIt was Derek\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEric committed the crime. One method of solving this teaser is to assume that it was Adrian, then work out how many of the statements would then have been true. Once you work out the number of statements for each suspect, you can determine the correct one.\n<|im_start|>answer\nEric committed the crime. One method of solving this teaser is to assume that it was Adrian, then work out how many of the statements would then have been true. Once you work out the number of statements for each suspect, you can determine the correct one.\n<|im_end|>" }, { "id": "#43260", "title": "Infiltrator!", "fun": 2.61, "difficulty": 2.73, "author": "TheNinja", "desc": "During one meeting with a clan of ninjas, it has been noticed that more ninjas have turned up to the meeting than usual. The ninjas realised that these infiltrators must be the enemy of the ninjas (the pirates). Each person dressed as a ninja at the meeting made a statement. The cunning ninjas lied about their fellow ninjas in order to remain secret and told the truth about the pirates. The pirates tried to mock the cunningness by lying about the pirates and telling the truth about the ninjas. From the following statements, can you identify the ninjas and pirates?\n\r\nNinja A: Ninja B is a ninja\r\nNinja B: Ninja C belongs to Ninja A's group\r\nNinja C: Ninja C doesn't belong to Ninja F's group\r\nNinja D: Ninja A belongs to Ninja B's group\r\nNinja E: Ninja B belongs to Ninja C's group\r\nNinja F: Ninja E belongs to Ninja A's group\n\r\nRemember, the ninjas and pirates will lie about individual ninjas or pirates, not groups of ninjas or pirates.", "hint": "No hint available.", "answer": "Ninja A is a pirate\r\nNinja B is a ninja\r\nNinja C is a ninja\r\nNinja D is a pirate\r\nNinja E is a pirate\r\nNinja F is a ninja\n\r\nNinja A said that Ninja B is a ninja. This is because Ninja A is a pirate and Ninja B is a ninja, so Ninja A told the truth.\n\r\nNinja B said that Ninja C belongs to Ninja A's group. Ninja B is a ninja and Ninja C is a ninja, so Ninja B lied.\n\r\nNinja C said that Ninja C doesn't belong to Ninja F's group. Ninja C is obviously from the same group as Ninja C, so Ninja C lied.\n\r\nNinja D said that Ninja A belongs to Ninja B's group. Ninja D is a pirate and Ninja A is a pirate so Ninja D lied.\n\r\nNinja E said that Ninja B belongs to Ninja C's group. Ninja E is a pirate and Ninja B is a ninja, so Ninja E told the truth.\n\r\nNinja F said that Ninja E belongs to Ninja A's group. Ninja F is a ninja and Ninja E is a pirate, so Ninja F told the truth.", "category": "Logic", "date": "10/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring one meeting with a clan of ninjas, it has been noticed that more ninjas have turned up to the meeting than usual. The ninjas realised that these infiltrators must be the enemy of the ninjas (the pirates). Each person dressed as a ninja at the meeting made a statement. The cunning ninjas lied about their fellow ninjas in order to remain secret and told the truth about the pirates. The pirates tried to mock the cunningness by lying about the pirates and telling the truth about the ninjas. From the following statements, can you identify the ninjas and pirates?\n\r\nNinja A: Ninja B is a ninja\r\nNinja B: Ninja C belongs to Ninja A's group\r\nNinja C: Ninja C doesn't belong to Ninja F's group\r\nNinja D: Ninja A belongs to Ninja B's group\r\nNinja E: Ninja B belongs to Ninja C's group\r\nNinja F: Ninja E belongs to Ninja A's group\n\r\nRemember, the ninjas and pirates will lie about individual ninjas or pirates, not groups of ninjas or pirates.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNinja A is a pirate\r\nNinja B is a ninja\r\nNinja C is a ninja\r\nNinja D is a pirate\r\nNinja E is a pirate\r\nNinja F is a ninja\n\r\nNinja A said that Ninja B is a ninja. This is because Ninja A is a pirate and Ninja B is a ninja, so Ninja A told the truth.\n\r\nNinja B said that Ninja C belongs to Ninja A's group. Ninja B is a ninja and Ninja C is a ninja, so Ninja B lied.\n\r\nNinja C said that Ninja C doesn't belong to Ninja F's group. Ninja C is obviously from the same group as Ninja C, so Ninja C lied.\n\r\nNinja D said that Ninja A belongs to Ninja B's group. Ninja D is a pirate and Ninja A is a pirate so Ninja D lied.\n\r\nNinja E said that Ninja B belongs to Ninja C's group. Ninja E is a pirate and Ninja B is a ninja, so Ninja E told the truth.\n\r\nNinja F said that Ninja E belongs to Ninja A's group. Ninja F is a ninja and Ninja E is a pirate, so Ninja F told the truth.\n<|im_start|>answer\nNinja A is a pirate\r\nNinja B is a ninja\r\nNinja C is a ninja\r\nNinja D is a pirate\r\nNinja E is a pirate\r\nNinja F is a ninja\n\r\nNinja A said that Ninja B is a ninja. This is because Ninja A is a pirate and Ninja B is a ninja, so Ninja A told the truth.\n\r\nNinja B said that Ninja C belongs to Ninja A's group. Ninja B is a ninja and Ninja C is a ninja, so Ninja B lied.\n\r\nNinja C said that Ninja C doesn't belong to Ninja F's group. Ninja C is obviously from the same group as Ninja C, so Ninja C lied.\n\r\nNinja D said that Ninja A belongs to Ninja B's group. Ninja D is a pirate and Ninja A is a pirate so Ninja D lied.\n\r\nNinja E said that Ninja B belongs to Ninja C's group. Ninja E is a pirate and Ninja B is a ninja, so Ninja E told the truth.\n\r\nNinja F said that Ninja E belongs to Ninja A's group. Ninja F is a ninja and Ninja E is a pirate, so Ninja F told the truth.\n<|im_end|>" }, { "id": "#50421", "title": "Sixes, Sixes, Everywhere!", "fun": 2.61, "difficulty": 2.78, "author": "duhya", "desc": "The following equations are currently incorrect. Using these rules, correct them. \r\nYou can't write any other numbers.\r\nYou cannot use any form of an \"equals\" sign, a \"greater than\" sign, or a \"less than\" sign. Good luck. \n\r\n1 1 1 =6\r\n2 2 2 =6\r\n3 3 3 =6\r\n4 4 4 =6\r\n5 5 5 =6\r\n6 6 6 =6\r\n7 7 7 =6\r\n8 8 8 =6\r\n9 9 9 =6\r\n0 0 0 =6\n\r\nThere can be multiple answers for one equation. I shall be putting only one of each in the answer. Post more answers in the comments.", "hint": "You can use factorials (!) and square roots.\r\nA factorial of a number is defined as:\r\nN*(N-1)*(N-2)*...3*2*1\r\nThe factorial of three is:\r\n3!=3*2*1=6", "answer": "(1+1+1)!\r\n2+2+2\r\n3*3-3\r\n4+4- SqRt (4) SqRt = Square Root\r\n5+5/5\r\n6-6+6\r\n7-7/7\r\n8- SqRt (SqRt (8+8))\r\n((SqRt (9)*SqRt(9))-SqRt (9)\r\n(0!+0!+0!)!", "category": "Math", "date": "10/11/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following equations are currently incorrect. Using these rules, correct them. \r\nYou can't write any other numbers.\r\nYou cannot use any form of an \"equals\" sign, a \"greater than\" sign, or a \"less than\" sign. Good luck. \n\r\n1 1 1 =6\r\n2 2 2 =6\r\n3 3 3 =6\r\n4 4 4 =6\r\n5 5 5 =6\r\n6 6 6 =6\r\n7 7 7 =6\r\n8 8 8 =6\r\n9 9 9 =6\r\n0 0 0 =6\n\r\nThere can be multiple answers for one equation. I shall be putting only one of each in the answer. Post more answers in the comments.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(1+1+1)!\r\n2+2+2\r\n3*3-3\r\n4+4- SqRt (4) SqRt = Square Root\r\n5+5/5\r\n6-6+6\r\n7-7/7\r\n8- SqRt (SqRt (8+8))\r\n((SqRt (9)*SqRt(9))-SqRt (9)\r\n(0!+0!+0!)!\n<|im_start|>answer\n(1+1+1)!\r\n2+2+2\r\n3*3-3\r\n4+4- SqRt (4) SqRt = Square Root\r\n5+5/5\r\n6-6+6\r\n7-7/7\r\n8- SqRt (SqRt (8+8))\r\n((SqRt (9)*SqRt(9))-SqRt (9)\r\n(0!+0!+0!)!\n<|im_end|>" }, { "id": "#46639", "title": "Back in the Tournament", "fun": 2.61, "difficulty": 2.08, "author": "whsprec", "desc": "It is basketball tournament time. For five teams it has been several years since they made the tournament. From the clues below, determine where each school is seeded, what their mascot is, and how long it has been since they last made the tournament. Remember, a higher seed is one with a lower number, with the no. 1 seed being the highest.\n\r\n1) The 7 seeded mascot is the bumblebee, but is not from Chord Uni.\r\n2) It has been twenty years since Stats and Math State made the tournament and they are seeded two places lower than the piano mascot, who isn't seeded 9.\r\n3) The turkey mascot is seeded two places lower than Artist's Paradise and two places higher than the team that have not been in for twenty-one years.\r\n4) It has been over twenty years for Music Melody and their mascot the raindrop.\r\n5) The team that has been waiting for nineteen years is seeded 11.\r\n6) The student who played the mascot of the paintbrush wasn't even born the last time his school made it to the tournament. They have waited the longest to get in.", "hint": "No hint available.", "answer": "The 7 seeded Minor College with mascot the bumblebee have been waiting 18 years.\r\nThe 9 seeded Chord Uni. with mascot the paintbrush have been waiting 22 years.\r\nThe 11 seeded Artist's Paradise with mascot the piano have been waiting 19 years.\r\nThe 13 seeded States and Math State with mascot the turkey have been waiting 20 years.\r\nThe 15 seeded Music Melody with mascot the raindrop have been waiting 21 years.", "category": "Logic-Grid", "date": "03/31/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is basketball tournament time. For five teams it has been several years since they made the tournament. From the clues below, determine where each school is seeded, what their mascot is, and how long it has been since they last made the tournament. Remember, a higher seed is one with a lower number, with the no. 1 seed being the highest.\n\r\n1) The 7 seeded mascot is the bumblebee, but is not from Chord Uni.\r\n2) It has been twenty years since Stats and Math State made the tournament and they are seeded two places lower than the piano mascot, who isn't seeded 9.\r\n3) The turkey mascot is seeded two places lower than Artist's Paradise and two places higher than the team that have not been in for twenty-one years.\r\n4) It has been over twenty years for Music Melody and their mascot the raindrop.\r\n5) The team that has been waiting for nineteen years is seeded 11.\r\n6) The student who played the mascot of the paintbrush wasn't even born the last time his school made it to the tournament. They have waited the longest to get in.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 7 seeded Minor College with mascot the bumblebee have been waiting 18 years.\r\nThe 9 seeded Chord Uni. with mascot the paintbrush have been waiting 22 years.\r\nThe 11 seeded Artist's Paradise with mascot the piano have been waiting 19 years.\r\nThe 13 seeded States and Math State with mascot the turkey have been waiting 20 years.\r\nThe 15 seeded Music Melody with mascot the raindrop have been waiting 21 years.\n<|im_start|>answer\nThe 7 seeded Minor College with mascot the bumblebee have been waiting 18 years.\r\nThe 9 seeded Chord Uni. with mascot the paintbrush have been waiting 22 years.\r\nThe 11 seeded Artist's Paradise with mascot the piano have been waiting 19 years.\r\nThe 13 seeded States and Math State with mascot the turkey have been waiting 20 years.\r\nThe 15 seeded Music Melody with mascot the raindrop have been waiting 21 years.\n<|im_end|>" }, { "id": "#4473", "title": "Where Do I Live", "fun": 2.61, "difficulty": 2.5, "author": "bobbrt", "desc": "My entire family lives on Braingle Street, and for some strange reason I got to choose where everyone lives.\n\r\nMy mother Vera lives at 2005 Braingle St.\r\nMy cousin Lucy lives at 1150 Braingle St.\r\nWhere do I live?", "hint": "If Lucy changed her name to Irene, she'd have to move to 1101 Braingle St.", "answer": "The addresses are based on the first letters of the residents' relations to me, converted to Roman Numerals.\r\nMy Mother Vera = MMV = 2005\r\nMy Cousin Lucy = MCL = 1150\r\nThis leaves \"Me\" living at 1000 Braingle Street.\r\nI could also accept 1 Braingle St. (referring to myself as \"I\") as a valid answer.", "category": "Logic", "date": "06/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy entire family lives on Braingle Street, and for some strange reason I got to choose where everyone lives.\n\r\nMy mother Vera lives at 2005 Braingle St.\r\nMy cousin Lucy lives at 1150 Braingle St.\r\nWhere do I live?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe addresses are based on the first letters of the residents' relations to me, converted to Roman Numerals.\r\nMy Mother Vera = MMV = 2005\r\nMy Cousin Lucy = MCL = 1150\r\nThis leaves \"Me\" living at 1000 Braingle Street.\r\nI could also accept 1 Braingle St. (referring to myself as \"I\") as a valid answer.\n<|im_start|>answer\nThe addresses are based on the first letters of the residents' relations to me, converted to Roman Numerals.\r\nMy Mother Vera = MMV = 2005\r\nMy Cousin Lucy = MCL = 1150\r\nThis leaves \"Me\" living at 1000 Braingle Street.\r\nI could also accept 1 Braingle St. (referring to myself as \"I\") as a valid answer.\n<|im_end|>" }, { "id": "#44394", "title": "In-state Rivalry", "fun": 2.61, "difficulty": 1.45, "author": "whsprec", "desc": "In a small North Carolina town live James, Ryan, Sam, Mark, and Collin. Their last names are Ware, Most, Sullivan, Woolard, and Ruiz. They are graduates of N.C. State, North Carolina, East Carolina, Wake Forest, and Duke. They are in the following professions: anthropologist, teacher, accountant, lawyer, and veterinarian. From the clues below, determine the first and last name of each man, his profession, and his alma mater.\n\r\n1. Ryan was not the one who went to East Carolina or the one who became an accountant; neither was his friend Mr. Woolard.\r\n2. Last week the lawyer, the anthropologist, James, the one who went to North Carolina, and Sam Sullivan had lunch together.\r\n3. Collin is the veterinarian.\r\n4. Neither Mark nor James is named Ruiz or Woolard, and it was not one of these four who became a teacher after going to East Carolina.\r\n5. The anthropologist and the one who went to Duke went to high school with Mark before he was accepted to Wake Forest.\r\n6. James is not Mr. Most.", "hint": "No hint available.", "answer": "James Ware went to Duke to become an accountant.\r\nRyan Ruiz went to N.C. State to become a anthropologist.\r\nSam Sullivan went to East Carolina to become a teacher.\r\nMark Most went to Wake Forest to become a lawyer.\r\nCollin Woolard went to North Carolina to become a veterinarian.", "category": "Logic-Grid", "date": "04/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a small North Carolina town live James, Ryan, Sam, Mark, and Collin. Their last names are Ware, Most, Sullivan, Woolard, and Ruiz. They are graduates of N.C. State, North Carolina, East Carolina, Wake Forest, and Duke. They are in the following professions: anthropologist, teacher, accountant, lawyer, and veterinarian. From the clues below, determine the first and last name of each man, his profession, and his alma mater.\n\r\n1. Ryan was not the one who went to East Carolina or the one who became an accountant; neither was his friend Mr. Woolard.\r\n2. Last week the lawyer, the anthropologist, James, the one who went to North Carolina, and Sam Sullivan had lunch together.\r\n3. Collin is the veterinarian.\r\n4. Neither Mark nor James is named Ruiz or Woolard, and it was not one of these four who became a teacher after going to East Carolina.\r\n5. The anthropologist and the one who went to Duke went to high school with Mark before he was accepted to Wake Forest.\r\n6. James is not Mr. Most.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJames Ware went to Duke to become an accountant.\r\nRyan Ruiz went to N.C. State to become a anthropologist.\r\nSam Sullivan went to East Carolina to become a teacher.\r\nMark Most went to Wake Forest to become a lawyer.\r\nCollin Woolard went to North Carolina to become a veterinarian.\n<|im_start|>answer\nJames Ware went to Duke to become an accountant.\r\nRyan Ruiz went to N.C. State to become a anthropologist.\r\nSam Sullivan went to East Carolina to become a teacher.\r\nMark Most went to Wake Forest to become a lawyer.\r\nCollin Woolard went to North Carolina to become a veterinarian.\n<|im_end|>" }, { "id": "#30714", "title": "A Butcher", "fun": 2.61, "difficulty": 1.62, "author": "npf2005", "desc": "A butcher had a number of legs of lamb to chop up. He chopped each leg into 11 pieces. He chopped at the rate of 45 strokes per minute. How many legs would he chop in 22 minutes?", "hint": "Each leg needs to be chopped ten times, not eleven.", "answer": "99 legs.\n\r\nExplanation: Each leg is chopped 10 times. 22 multiplied by 45 equals 990. 990 divided by 10 equals 99.", "category": "Math", "date": "05/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA butcher had a number of legs of lamb to chop up. He chopped each leg into 11 pieces. He chopped at the rate of 45 strokes per minute. How many legs would he chop in 22 minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n99 legs.\n\r\nExplanation: Each leg is chopped 10 times. 22 multiplied by 45 equals 990. 990 divided by 10 equals 99.\n<|im_start|>answer\n99 legs.\n\r\nExplanation: Each leg is chopped 10 times. 22 multiplied by 45 equals 990. 990 divided by 10 equals 99.\n<|im_end|>" }, { "id": "#30902", "title": "Gauss and an Old Professor", "fun": 2.61, "difficulty": 2.9, "author": "shenqiang", "desc": "There was a famous mathematician named Karl Friedrich Gauss. When he was young, he entered Gotinga University. One day he met an old professor, and spoke to him. They chatted, and the professor asked Gauss about his age.\n\r\nGauss said: \"The cube and the fourth power of my age contain each digit from 0 to 9 exactly once.\"\n\r\nThe professor said: \"Very good. It's good coincidence because the square and the cube of my age contain each digit from 0 to 9 exactly once.\"\n\r\nHow old was Gauss, and how old was the professor?", "hint": "Eliminate the impossibilities, such as their ages can't end with 0.", "answer": "Their ages can't end with 0, 1, 5 or 6, and must be either a multiple of 3 or a multiple of 9 minus 1 because the sum of its square and its cube or its cube and its fourth power is divisible by 9.\n\r\nGauss's age is easy. Since 17^3=4913, 17^4=83521, 22^3=10648, 22^4=234256, Gauss's age is between 18 and 21. The only possibility is 18. 18^3=5832, 18^4=104976.\n\r\nThe professor's age is a little harder. It can be 47 to 99, and the possibilities are: 48, 53, 54, 57, 62, 63, 69, 72, 78, 84, 87, 89, 93, 98, 99. By trial and error, 69 satisfies this condition: 69^2=4761, 69^3=328509.\n\r\nTherefore, Gauss was 18 and the professor was 69.", "category": "Math", "date": "06/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a famous mathematician named Karl Friedrich Gauss. When he was young, he entered Gotinga University. One day he met an old professor, and spoke to him. They chatted, and the professor asked Gauss about his age.\n\r\nGauss said: \"The cube and the fourth power of my age contain each digit from 0 to 9 exactly once.\"\n\r\nThe professor said: \"Very good. It's good coincidence because the square and the cube of my age contain each digit from 0 to 9 exactly once.\"\n\r\nHow old was Gauss, and how old was the professor?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTheir ages can't end with 0, 1, 5 or 6, and must be either a multiple of 3 or a multiple of 9 minus 1 because the sum of its square and its cube or its cube and its fourth power is divisible by 9.\n\r\nGauss's age is easy. Since 17^3=4913, 17^4=83521, 22^3=10648, 22^4=234256, Gauss's age is between 18 and 21. The only possibility is 18. 18^3=5832, 18^4=104976.\n\r\nThe professor's age is a little harder. It can be 47 to 99, and the possibilities are: 48, 53, 54, 57, 62, 63, 69, 72, 78, 84, 87, 89, 93, 98, 99. By trial and error, 69 satisfies this condition: 69^2=4761, 69^3=328509.\n\r\nTherefore, Gauss was 18 and the professor was 69.\n<|im_start|>answer\nTheir ages can't end with 0, 1, 5 or 6, and must be either a multiple of 3 or a multiple of 9 minus 1 because the sum of its square and its cube or its cube and its fourth power is divisible by 9.\n\r\nGauss's age is easy. Since 17^3=4913, 17^4=83521, 22^3=10648, 22^4=234256, Gauss's age is between 18 and 21. The only possibility is 18. 18^3=5832, 18^4=104976.\n\r\nThe professor's age is a little harder. It can be 47 to 99, and the possibilities are: 48, 53, 54, 57, 62, 63, 69, 72, 78, 84, 87, 89, 93, 98, 99. By trial and error, 69 satisfies this condition: 69^2=4761, 69^3=328509.\n\r\nTherefore, Gauss was 18 and the professor was 69.\n<|im_end|>" }, { "id": "#23960", "title": "Which Number?", "fun": 2.61, "difficulty": 1.91, "author": "chidam11", "desc": "In a number of two digits, the digit in the ones place is the square of the digit in tens place and the number formed by reversing the digits exceeds twice the number by 15, what is the number?", "hint": "No hint available.", "answer": "The number is 39.", "category": "Math", "date": "06/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a number of two digits, the digit in the ones place is the square of the digit in tens place and the number formed by reversing the digits exceeds twice the number by 15, what is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 39.\n<|im_start|>answer\nThe number is 39.\n<|im_end|>" }, { "id": "#1725", "title": "Exactly 1,000,000,000.", "fun": 2.61, "difficulty": 2.45, "author": "Nishoo", "desc": "Which two whole numbers, neither containing any zeros, when multiplied together equal exactly 1,000,000,000 ?", "hint": "No hint available.", "answer": "512 and 1,953,125. \n\n\r\nThat is, 2 to the ninth power and 5 to the ninth power.", "category": "Math", "date": "12/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich two whole numbers, neither containing any zeros, when multiplied together equal exactly 1,000,000,000 ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n512 and 1,953,125. \n\n\r\nThat is, 2 to the ninth power and 5 to the ninth power.\n<|im_start|>answer\n512 and 1,953,125. \n\n\r\nThat is, 2 to the ninth power and 5 to the ninth power.\n<|im_end|>" }, { "id": "#39048", "title": "Toothpick Equation", "fun": 2.61, "difficulty": 1.91, "author": "tricky77puzzle", "desc": "This teaser requires 30 toothpicks to do.\n\r\nPlace the toothpicks in a way so that they read \"82 - 41 = 43\" in digital numbers. (To avoid ambiguity, the 4 must be made with perpendicularly placed lines.) You may not modify the equal sign in any way.\n\r\nNow, the challenge: move only one toothpick to make the equation true.", "hint": "Moving two is too easy, just change the 2 to 3 and the 3 to 2. Think outside the box.", "answer": "Move the toothpick in the middle of the 8, and place it crossing and perpendicular to the minus, turning it into a plus sign. The equation should now read \"02 + 41 = 43\" which is correct!", "category": "Logic", "date": "11/02/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser requires 30 toothpicks to do.\n\r\nPlace the toothpicks in a way so that they read \"82 - 41 = 43\" in digital numbers. (To avoid ambiguity, the 4 must be made with perpendicularly placed lines.) You may not modify the equal sign in any way.\n\r\nNow, the challenge: move only one toothpick to make the equation true.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMove the toothpick in the middle of the 8, and place it crossing and perpendicular to the minus, turning it into a plus sign. The equation should now read \"02 + 41 = 43\" which is correct!\n<|im_start|>answer\nMove the toothpick in the middle of the 8, and place it crossing and perpendicular to the minus, turning it into a plus sign. The equation should now read \"02 + 41 = 43\" which is correct!\n<|im_end|>" }, { "id": "#49561", "title": "Shopping Trip 2", "fun": 2.61, "difficulty": 1.49, "author": "fishmed", "desc": "Janet and her husband were out shopping when they decided to split to save time. They agreed to meet back at the bank at 2:00 PM. Janet realized several minutes later that she had forgotten her watch and asked a lady nearby for the correct time. The lady's watch was five minutes fast, but she thought it was ten minutes slow. Janet's husband also forgot his watch so he asked a passing gentleman for the time. The man's watch was ten minutes slow, but he thought it was 15 minutes fast. Taking into account the errors in the watches, who arrived at the bank first, and what time did they arrive?", "hint": "No hint available.", "answer": "Janet got there first at quarter to two. She was told a time that was actually 15 minutes faster than the true time. Her husband, however, arrived at twenty-five after two, as he was told a time that was 25 minutes slower than the true time.", "category": "Logic", "date": "08/23/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJanet and her husband were out shopping when they decided to split to save time. They agreed to meet back at the bank at 2:00 PM. Janet realized several minutes later that she had forgotten her watch and asked a lady nearby for the correct time. The lady's watch was five minutes fast, but she thought it was ten minutes slow. Janet's husband also forgot his watch so he asked a passing gentleman for the time. The man's watch was ten minutes slow, but he thought it was 15 minutes fast. Taking into account the errors in the watches, who arrived at the bank first, and what time did they arrive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJanet got there first at quarter to two. She was told a time that was actually 15 minutes faster than the true time. Her husband, however, arrived at twenty-five after two, as he was told a time that was 25 minutes slower than the true time.\n<|im_start|>answer\nJanet got there first at quarter to two. She was told a time that was actually 15 minutes faster than the true time. Her husband, however, arrived at twenty-five after two, as he was told a time that was 25 minutes slower than the true time.\n<|im_end|>" }, { "id": "#25168", "title": "Class Photo", "fun": 2.61, "difficulty": 2.92, "author": "cnmne", "desc": "Jacob's class picture has 40 photos arranged in a 8 x 5 grid. The photos in the top row are numbered 1 through 8 from left to right, with the photos in the remaining rows similarly numbered (as shown below). Given the following clues (bordering includes horizontal, vertical, and diagonal), where is Jacob's picture?\n\r\nX X X X X X X X (1 - 8)\r\nX X X X X X X X (9 - 16)\r\nX X X X X X X X (17 - 24)\r\nX X X X X X X X (25 - 32)\r\nX X X X X X X X (33 - 40)\n\r\n1) There are 20 boys and 20 girls.\r\n2) Each row and column has at least two girls, but no more than four girls.\r\n3) Every girl borders at least one other girl.\r\n4) Girls are located at positions that are prime numbers.\r\n5) Boys are located at positions that are either squares or cubes.\r\n6) Jacob is the only boy that borders a unique number of girls.", "hint": "The number 1 is not a prime number.", "answer": "Per clue 4: girls are at positions 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, and 37. Per clue 5: boys are at positions 1, 4, 9, 16, 25, 36, 8, and 27.\n\r\nB G G B G _ G B\r\nB _ G _ G _ _ B\r\nG _ G _ _ _ G _\r\nB _ B _ G _ G _\r\n_ _ _ B G _ _ _\n\r\nPer clue 2: make sure each row/column has at least two, but no more than four, girls. This puts boys at positions 6 and 21, and a girl at position 33.\n\r\nB G G B G B G B\r\nB _ G _ G _ _ B\r\nG _ G _ B _ G _\r\nB _ B _ G _ G _\r\nG _ _ B G _ _ _\n\r\nThere are still seven girls to identify, which must be assigned to columns 2, 4, 6, and 8 (clues 1 and 2). This means that boys must fill the open spaces in the other columns (positions 15, 35, and 39).\n\r\nB G G B G B G B\r\nB _ G _ G _ B B\r\nG _ G _ B _ G _\r\nB _ B _ G _ G _\r\nG _ B B G _ B _\n\r\nSince all girls must border at least one other girl (clue 3) and only one more girl can be added to column 2, the next placements can be made (girls at positions 14 and 26).\n\r\nB G G B G B G B\r\nB _ G _ G G B B\r\nG _ G _ B _ G _\r\nB G B _ G _ G _\r\nG _ B B G _ B _\n\r\nThe rest of column 2 must be boys (positions 10, 18, and 34). \n\r\nBecause no row can have more than 4 girls, each row must have exactly 4 girls. Girls must then be at positions 12, 38, and 40. Boys must then be at positions 22 and 30.\n\r\nB G G B G B G B\r\nB B G G G G B B\r\nG B G _ B B G _\r\nB G B _ G B G _\r\nG B B B G G B G\n\r\nThe final two girls must be at either positions 20/32 or 24/28 (clue 2). If the first combination is chosen, then there will be no boy that borders a unique number of girls (clue 6). By placing the girls at the second combination (and boys at the first combination), clue 6 will be satisfied.\n\r\nB G G B G B G B\r\nB B G G G G B B\r\nG B G B B B G G\r\nB G B G G B G B\r\nG B B B G G B G\n\r\nThe boys in the first row border (1, 5, 4, 1) girls.\r\nThe boys in the second row border (2, 5, 4, 3) girls.\r\nThe boys in the third row border (4, 6, 5, 5) girls.\r\nThe boys in the fourth row border (3, 3, 5, 4) girls.\r\nThe boys in the fifth row border (2, 2, 3, 3) girls.\n\r\nThe only boy that borders a unique number of girls is the boy who borders six girls, which is at position 20. Therefore, Jacob is at position 20.", "category": "Logic", "date": "08/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJacob's class picture has 40 photos arranged in a 8 x 5 grid. The photos in the top row are numbered 1 through 8 from left to right, with the photos in the remaining rows similarly numbered (as shown below). Given the following clues (bordering includes horizontal, vertical, and diagonal), where is Jacob's picture?\n\r\nX X X X X X X X (1 - 8)\r\nX X X X X X X X (9 - 16)\r\nX X X X X X X X (17 - 24)\r\nX X X X X X X X (25 - 32)\r\nX X X X X X X X (33 - 40)\n\r\n1) There are 20 boys and 20 girls.\r\n2) Each row and column has at least two girls, but no more than four girls.\r\n3) Every girl borders at least one other girl.\r\n4) Girls are located at positions that are prime numbers.\r\n5) Boys are located at positions that are either squares or cubes.\r\n6) Jacob is the only boy that borders a unique number of girls.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPer clue 4: girls are at positions 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, and 37. Per clue 5: boys are at positions 1, 4, 9, 16, 25, 36, 8, and 27.\n\r\nB G G B G _ G B\r\nB _ G _ G _ _ B\r\nG _ G _ _ _ G _\r\nB _ B _ G _ G _\r\n_ _ _ B G _ _ _\n\r\nPer clue 2: make sure each row/column has at least two, but no more than four, girls. This puts boys at positions 6 and 21, and a girl at position 33.\n\r\nB G G B G B G B\r\nB _ G _ G _ _ B\r\nG _ G _ B _ G _\r\nB _ B _ G _ G _\r\nG _ _ B G _ _ _\n\r\nThere are still seven girls to identify, which must be assigned to columns 2, 4, 6, and 8 (clues 1 and 2). This means that boys must fill the open spaces in the other columns (positions 15, 35, and 39).\n\r\nB G G B G B G B\r\nB _ G _ G _ B B\r\nG _ G _ B _ G _\r\nB _ B _ G _ G _\r\nG _ B B G _ B _\n\r\nSince all girls must border at least one other girl (clue 3) and only one more girl can be added to column 2, the next placements can be made (girls at positions 14 and 26).\n\r\nB G G B G B G B\r\nB _ G _ G G B B\r\nG _ G _ B _ G _\r\nB G B _ G _ G _\r\nG _ B B G _ B _\n\r\nThe rest of column 2 must be boys (positions 10, 18, and 34). \n\r\nBecause no row can have more than 4 girls, each row must have exactly 4 girls. Girls must then be at positions 12, 38, and 40. Boys must then be at positions 22 and 30.\n\r\nB G G B G B G B\r\nB B G G G G B B\r\nG B G _ B B G _\r\nB G B _ G B G _\r\nG B B B G G B G\n\r\nThe final two girls must be at either positions 20/32 or 24/28 (clue 2). If the first combination is chosen, then there will be no boy that borders a unique number of girls (clue 6). By placing the girls at the second combination (and boys at the first combination), clue 6 will be satisfied.\n\r\nB G G B G B G B\r\nB B G G G G B B\r\nG B G B B B G G\r\nB G B G G B G B\r\nG B B B G G B G\n\r\nThe boys in the first row border (1, 5, 4, 1) girls.\r\nThe boys in the second row border (2, 5, 4, 3) girls.\r\nThe boys in the third row border (4, 6, 5, 5) girls.\r\nThe boys in the fourth row border (3, 3, 5, 4) girls.\r\nThe boys in the fifth row border (2, 2, 3, 3) girls.\n\r\nThe only boy that borders a unique number of girls is the boy who borders six girls, which is at position 20. Therefore, Jacob is at position 20.\n<|im_start|>answer\nPer clue 4: girls are at positions 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, and 37. Per clue 5: boys are at positions 1, 4, 9, 16, 25, 36, 8, and 27.\n\r\nB G G B G _ G B\r\nB _ G _ G _ _ B\r\nG _ G _ _ _ G _\r\nB _ B _ G _ G _\r\n_ _ _ B G _ _ _\n\r\nPer clue 2: make sure each row/column has at least two, but no more than four, girls. This puts boys at positions 6 and 21, and a girl at position 33.\n\r\nB G G B G B G B\r\nB _ G _ G _ _ B\r\nG _ G _ B _ G _\r\nB _ B _ G _ G _\r\nG _ _ B G _ _ _\n\r\nThere are still seven girls to identify, which must be assigned to columns 2, 4, 6, and 8 (clues 1 and 2). This means that boys must fill the open spaces in the other columns (positions 15, 35, and 39).\n\r\nB G G B G B G B\r\nB _ G _ G _ B B\r\nG _ G _ B _ G _\r\nB _ B _ G _ G _\r\nG _ B B G _ B _\n\r\nSince all girls must border at least one other girl (clue 3) and only one more girl can be added to column 2, the next placements can be made (girls at positions 14 and 26).\n\r\nB G G B G B G B\r\nB _ G _ G G B B\r\nG _ G _ B _ G _\r\nB G B _ G _ G _\r\nG _ B B G _ B _\n\r\nThe rest of column 2 must be boys (positions 10, 18, and 34). \n\r\nBecause no row can have more than 4 girls, each row must have exactly 4 girls. Girls must then be at positions 12, 38, and 40. Boys must then be at positions 22 and 30.\n\r\nB G G B G B G B\r\nB B G G G G B B\r\nG B G _ B B G _\r\nB G B _ G B G _\r\nG B B B G G B G\n\r\nThe final two girls must be at either positions 20/32 or 24/28 (clue 2). If the first combination is chosen, then there will be no boy that borders a unique number of girls (clue 6). By placing the girls at the second combination (and boys at the first combination), clue 6 will be satisfied.\n\r\nB G G B G B G B\r\nB B G G G G B B\r\nG B G B B B G G\r\nB G B G G B G B\r\nG B B B G G B G\n\r\nThe boys in the first row border (1, 5, 4, 1) girls.\r\nThe boys in the second row border (2, 5, 4, 3) girls.\r\nThe boys in the third row border (4, 6, 5, 5) girls.\r\nThe boys in the fourth row border (3, 3, 5, 4) girls.\r\nThe boys in the fifth row border (2, 2, 3, 3) girls.\n\r\nThe only boy that borders a unique number of girls is the boy who borders six girls, which is at position 20. Therefore, Jacob is at position 20.\n<|im_end|>" }, { "id": "#321", "title": "A Symbol.", "fun": 2.61, "difficulty": 1.39, "author": "Mr. G", "desc": "What common mathematical symbol can you place between the numerals 4 and 5 which results in a number greater than four but less than six?", "hint": "No hint available.", "answer": ".\r\nA decimal point.", "category": "Math", "date": "03/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat common mathematical symbol can you place between the numerals 4 and 5 which results in a number greater than four but less than six?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n.\r\nA decimal point.\n<|im_start|>answer\n.\r\nA decimal point.\n<|im_end|>" }, { "id": "#31756", "title": "Colonial Cafe", "fun": 2.61, "difficulty": 2.25, "author": "fishmed", "desc": "Bob and Jean really like chocolate. When they heard the local cafe come up with a challenge to get a free chocolate sundae with each meal, they jumped at the chance. Their challenge was this. From the following menu, if you choose a complete meal that costs exactly $5.00 before tax, you get a free chocolate sundae. They took a few moments and figured out 11 different menus that allowed this. This is your challenge. Can you find them? \n\r\nEntree:\r\nShrimp, $2.75\r\nChicken, $3.15\r\nRoast Beef, $3.05\r\nHam, $2.05\n\r\nPotato:\r\nMashed, $0.75\r\nFries, $0.85\r\nCheese Fries, $1.05\r\nDouble Baked, $1.10\n\r\nVegetable:\r\nCorn, $0.35\r\nGreen Beans, $0.40\r\nAsparagus, $0.45\r\nMedley, $0.90\n\r\nDrinks:\r\nCoffee, $0.65\r\nMilk, $0.70\r\nChocolate Milk, $0.80\r\nSoda, $1.00", "hint": "A complete meal uses only 1 from each category.", "answer": "Meals are as follows:\n\r\n1: Roast Beef, Fries, Asparagus and Coffee\r\n$3.05 + $0.85 + $0.45 + $0.65 = $5.00\n\r\n2. Shrimp, Double Baked, Corn and Chocolate Milk\r\n$2.75 + $1.10 + $0.35 + $0.80 = $5.00\n\r\n3. Chicken, Mashed Potatoes, Green Beans and Milk\r\n$3.15 + $0.75 + $0.40 + $0.70 = $5.00\n\r\n4. Ham, Cheese Fries, Veg Medley and Soda\r\n$2.05 + $1.05 + $0.90 + $1.00 = $5.00\n\r\n5: Shrimp, Fries, Green Beans and Soda\r\n$2.75 + $0.85 + $0.40 + $1.00 = $5.00\n\r\n6: Shrimp, Cheese Fries, Green Beans and Chocolate Milk\r\n$2.75 + $1.05 + $0.40 + $0.80 = $5.00\n\r\n7: Shrimp, Double Baked, Asparagus and Milk\r\n$2.75 + $1.10 + $0.45 + $0.70 = $5.00\n\r\n8: Chicken, Mashed Potatoes, Asparagus and Coffee\r\n$3.15 + $0.75 + $0.45 + $0.65 = $5.00\n\r\n9: Chicken, Fries, Corn and Coffee\r\n$3.15 + $0.85 + $0.35 + $0.65 = $5.00\n\r\n10: Roast Beef, Mashed Potatoes, Green Beans and Chocolate Milk\r\n$3.05 + $0.75 + $0.40 + $0.80 = $5.00\n\r\n11: Roast Beef, Fries, Green Beans and Milk\r\n$3.05 + $0.85 + $0.40 + $0.70 = $5.00\n\r\nEnjoy the sundae!", "category": "Math", "date": "07/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob and Jean really like chocolate. When they heard the local cafe come up with a challenge to get a free chocolate sundae with each meal, they jumped at the chance. Their challenge was this. From the following menu, if you choose a complete meal that costs exactly $5.00 before tax, you get a free chocolate sundae. They took a few moments and figured out 11 different menus that allowed this. This is your challenge. Can you find them? \n\r\nEntree:\r\nShrimp, $2.75\r\nChicken, $3.15\r\nRoast Beef, $3.05\r\nHam, $2.05\n\r\nPotato:\r\nMashed, $0.75\r\nFries, $0.85\r\nCheese Fries, $1.05\r\nDouble Baked, $1.10\n\r\nVegetable:\r\nCorn, $0.35\r\nGreen Beans, $0.40\r\nAsparagus, $0.45\r\nMedley, $0.90\n\r\nDrinks:\r\nCoffee, $0.65\r\nMilk, $0.70\r\nChocolate Milk, $0.80\r\nSoda, $1.00\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMeals are as follows:\n\r\n1: Roast Beef, Fries, Asparagus and Coffee\r\n$3.05 + $0.85 + $0.45 + $0.65 = $5.00\n\r\n2. Shrimp, Double Baked, Corn and Chocolate Milk\r\n$2.75 + $1.10 + $0.35 + $0.80 = $5.00\n\r\n3. Chicken, Mashed Potatoes, Green Beans and Milk\r\n$3.15 + $0.75 + $0.40 + $0.70 = $5.00\n\r\n4. Ham, Cheese Fries, Veg Medley and Soda\r\n$2.05 + $1.05 + $0.90 + $1.00 = $5.00\n\r\n5: Shrimp, Fries, Green Beans and Soda\r\n$2.75 + $0.85 + $0.40 + $1.00 = $5.00\n\r\n6: Shrimp, Cheese Fries, Green Beans and Chocolate Milk\r\n$2.75 + $1.05 + $0.40 + $0.80 = $5.00\n\r\n7: Shrimp, Double Baked, Asparagus and Milk\r\n$2.75 + $1.10 + $0.45 + $0.70 = $5.00\n\r\n8: Chicken, Mashed Potatoes, Asparagus and Coffee\r\n$3.15 + $0.75 + $0.45 + $0.65 = $5.00\n\r\n9: Chicken, Fries, Corn and Coffee\r\n$3.15 + $0.85 + $0.35 + $0.65 = $5.00\n\r\n10: Roast Beef, Mashed Potatoes, Green Beans and Chocolate Milk\r\n$3.05 + $0.75 + $0.40 + $0.80 = $5.00\n\r\n11: Roast Beef, Fries, Green Beans and Milk\r\n$3.05 + $0.85 + $0.40 + $0.70 = $5.00\n\r\nEnjoy the sundae!\n<|im_start|>answer\nMeals are as follows:\n\r\n1: Roast Beef, Fries, Asparagus and Coffee\r\n$3.05 + $0.85 + $0.45 + $0.65 = $5.00\n\r\n2. Shrimp, Double Baked, Corn and Chocolate Milk\r\n$2.75 + $1.10 + $0.35 + $0.80 = $5.00\n\r\n3. Chicken, Mashed Potatoes, Green Beans and Milk\r\n$3.15 + $0.75 + $0.40 + $0.70 = $5.00\n\r\n4. Ham, Cheese Fries, Veg Medley and Soda\r\n$2.05 + $1.05 + $0.90 + $1.00 = $5.00\n\r\n5: Shrimp, Fries, Green Beans and Soda\r\n$2.75 + $0.85 + $0.40 + $1.00 = $5.00\n\r\n6: Shrimp, Cheese Fries, Green Beans and Chocolate Milk\r\n$2.75 + $1.05 + $0.40 + $0.80 = $5.00\n\r\n7: Shrimp, Double Baked, Asparagus and Milk\r\n$2.75 + $1.10 + $0.45 + $0.70 = $5.00\n\r\n8: Chicken, Mashed Potatoes, Asparagus and Coffee\r\n$3.15 + $0.75 + $0.45 + $0.65 = $5.00\n\r\n9: Chicken, Fries, Corn and Coffee\r\n$3.15 + $0.85 + $0.35 + $0.65 = $5.00\n\r\n10: Roast Beef, Mashed Potatoes, Green Beans and Chocolate Milk\r\n$3.05 + $0.75 + $0.40 + $0.80 = $5.00\n\r\n11: Roast Beef, Fries, Green Beans and Milk\r\n$3.05 + $0.85 + $0.40 + $0.70 = $5.00\n\r\nEnjoy the sundae!\n<|im_end|>" }, { "id": "#49976", "title": "Difficult Danny", "fun": 2.61, "difficulty": 1.95, "author": "eighsse", "desc": "Difficult Danny has acquired his nickname (and some other, less polite nicknames) due to the fact that, whenever he buys anything, he insists upon paying the exact amount, with precisely 100 pieces of currency. Danny walks into McArnold's and orders an iced coffee for $1.99. He pours 100 coins onto the counter, using some number (possibly zero) of each of the following: pennies, nickels, dimes, quarters. There are equal, non-zero quantities of dimes and quarters. What is the breakdown of coins that Difficult Danny used to pay for his iced coffee?\n\r\n(See hint for currency values.)", "hint": "Penny = $0.01\r\nNickel = $0.05\r\nDime = $0.10\r\nQuarter = $0.25", "answer": "94 pennies, 0 nickels, 3 dimes, and 3 quarters.", "category": "Math", "date": "10/20/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDifficult Danny has acquired his nickname (and some other, less polite nicknames) due to the fact that, whenever he buys anything, he insists upon paying the exact amount, with precisely 100 pieces of currency. Danny walks into McArnold's and orders an iced coffee for $1.99. He pours 100 coins onto the counter, using some number (possibly zero) of each of the following: pennies, nickels, dimes, quarters. There are equal, non-zero quantities of dimes and quarters. What is the breakdown of coins that Difficult Danny used to pay for his iced coffee?\n\r\n(See hint for currency values.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n94 pennies, 0 nickels, 3 dimes, and 3 quarters.\n<|im_start|>answer\n94 pennies, 0 nickels, 3 dimes, and 3 quarters.\n<|im_end|>" }, { "id": "#34922", "title": "Little Johnny #4", "fun": 2.61, "difficulty": 2.03, "author": "fishmed", "desc": "You'd think that Little Johnny's brother would learn his lesson, but no, he was at it again. \n\r\nHe wanted some extra money for the movies, so he went to Little Johnny with a bet. \"We got a really hard problem in class today,\" his brother said. \"Even with the hints we were given, we can't figure it out. I'll bet you my week's allowance against yours that you can't figure it out before dinner.\" \n\r\nPINE + TREES + CONES = FOREST\n\r\nLittle Johnny's brother told him that their teacher gave them the letter C=5, T=4, and E=8. He figured he'd get an extra large popcorn with the movie tonight. \n\r\nTwenty minutes later, Little Johnny's mother was giving both allowances to Little Johnny and his brother, sadly, had to stay home. \n\r\nCan you figure out what numbers are represented by each letter? No number stands for more than one letter.", "hint": "No hint available.", "answer": "O = 0\r\nF = 1\r\nI = 2\r\nS = 3\r\nT = 4\r\nC = 5\r\nN = 6\r\nR = 7\r\nE = 8\r\nP = 9\n\r\n9268 + 47883 + 50683 = 107834", "category": "Math", "date": "01/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou'd think that Little Johnny's brother would learn his lesson, but no, he was at it again. \n\r\nHe wanted some extra money for the movies, so he went to Little Johnny with a bet. \"We got a really hard problem in class today,\" his brother said. \"Even with the hints we were given, we can't figure it out. I'll bet you my week's allowance against yours that you can't figure it out before dinner.\" \n\r\nPINE + TREES + CONES = FOREST\n\r\nLittle Johnny's brother told him that their teacher gave them the letter C=5, T=4, and E=8. He figured he'd get an extra large popcorn with the movie tonight. \n\r\nTwenty minutes later, Little Johnny's mother was giving both allowances to Little Johnny and his brother, sadly, had to stay home. \n\r\nCan you figure out what numbers are represented by each letter? No number stands for more than one letter.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nO = 0\r\nF = 1\r\nI = 2\r\nS = 3\r\nT = 4\r\nC = 5\r\nN = 6\r\nR = 7\r\nE = 8\r\nP = 9\n\r\n9268 + 47883 + 50683 = 107834\n<|im_start|>answer\nO = 0\r\nF = 1\r\nI = 2\r\nS = 3\r\nT = 4\r\nC = 5\r\nN = 6\r\nR = 7\r\nE = 8\r\nP = 9\n\r\n9268 + 47883 + 50683 = 107834\n<|im_end|>" }, { "id": "#32664", "title": "Sequential Times", "fun": 2.61, "difficulty": 1.62, "author": "MarcM1098", "desc": "Three-year-old Sam has just learned to count to 30! He especially likes to read the clock when the numbers are in order. For example, he likes 3:45, which he sees not as three forty-five, but as three, four, five. Can you find all the times when the numbers on a clock are in sequential order?\r\nFor an extra challenge, use a 24-hour clock (ignore one leading zero in the hour).", "hint": "Look for both 1-digit and 2-digit numbers.\r\nA 12-hour clock has 9 sequential times, each one occurring twice per day.\r\nA 24-hour clock has an additional 13 (22 in total).", "answer": "A 12-hour clock has these:\r\n1:23 (one, two, three)\r\n2:34\r\n3:45\r\n4:56\r\n9:10 (nine, ten)\r\n10:11\r\n11:12\r\n12:13\r\n12:34 (one, two, three, four)\n\r\nA 24-hour clock has these additional ones:\r\n0:12 (zero, one, two)\r\n13:14 (thirteen, fourteen)\r\n14:15\r\n15:16\r\n16:17\r\n17:18\r\n18:19\r\n19:20\r\n20:21\r\n21:22\r\n22:23\r\n23:24\r\n23:45 (two, three, four, five)", "category": "Logic", "date": "08/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree-year-old Sam has just learned to count to 30! He especially likes to read the clock when the numbers are in order. For example, he likes 3:45, which he sees not as three forty-five, but as three, four, five. Can you find all the times when the numbers on a clock are in sequential order?\r\nFor an extra challenge, use a 24-hour clock (ignore one leading zero in the hour).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA 12-hour clock has these:\r\n1:23 (one, two, three)\r\n2:34\r\n3:45\r\n4:56\r\n9:10 (nine, ten)\r\n10:11\r\n11:12\r\n12:13\r\n12:34 (one, two, three, four)\n\r\nA 24-hour clock has these additional ones:\r\n0:12 (zero, one, two)\r\n13:14 (thirteen, fourteen)\r\n14:15\r\n15:16\r\n16:17\r\n17:18\r\n18:19\r\n19:20\r\n20:21\r\n21:22\r\n22:23\r\n23:24\r\n23:45 (two, three, four, five)\n<|im_start|>answer\nA 12-hour clock has these:\r\n1:23 (one, two, three)\r\n2:34\r\n3:45\r\n4:56\r\n9:10 (nine, ten)\r\n10:11\r\n11:12\r\n12:13\r\n12:34 (one, two, three, four)\n\r\nA 24-hour clock has these additional ones:\r\n0:12 (zero, one, two)\r\n13:14 (thirteen, fourteen)\r\n14:15\r\n15:16\r\n16:17\r\n17:18\r\n18:19\r\n19:20\r\n20:21\r\n21:22\r\n22:23\r\n23:24\r\n23:45 (two, three, four, five)\n<|im_end|>" }, { "id": "#28598", "title": "Half Empty or Half Full", "fun": 2.61, "difficulty": 0.87, "author": "jessjspieks", "desc": "Answer quickly. Filling an empty barrel, which happens first? \n\r\n2/3 full\r\n1/4 empty\r\n1/2 full\r\n3/4 empty", "hint": "Quicker.", "answer": "3/4 empty, since 3/4 empty means 1/4 full.", "category": "Math", "date": "02/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnswer quickly. Filling an empty barrel, which happens first? \n\r\n2/3 full\r\n1/4 empty\r\n1/2 full\r\n3/4 empty\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3/4 empty, since 3/4 empty means 1/4 full.\n<|im_start|>answer\n3/4 empty, since 3/4 empty means 1/4 full.\n<|im_end|>" }, { "id": "#29112", "title": "Shipping Books", "fun": 2.61, "difficulty": 1.8, "author": "Unstumpable", "desc": "The DogHound book company is shipping a load of books to a library in Minnesota. If each student takes 4 books from the load, there will be 20 books left. If 3 students don't take books, and all the other students take 5 books each, then there won't be any books left. How many books are in the load?", "hint": "It's above 100.", "answer": "160. 160 books-20 books=140/4 books for each student=35 students\r\n35 students-3 students that didn't read=32 160/32=5 books for each student", "category": "Math", "date": "03/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe DogHound book company is shipping a load of books to a library in Minnesota. If each student takes 4 books from the load, there will be 20 books left. If 3 students don't take books, and all the other students take 5 books each, then there won't be any books left. How many books are in the load?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n160. 160 books-20 books=140/4 books for each student=35 students\r\n35 students-3 students that didn't read=32 160/32=5 books for each student\n<|im_start|>answer\n160. 160 books-20 books=140/4 books for each student=35 students\r\n35 students-3 students that didn't read=32 160/32=5 books for each student\n<|im_end|>" }, { "id": "#31681", "title": "The Monitors", "fun": 2.6, "difficulty": 1.31, "author": "dishu", "desc": "The 4 friends were made monitors of their hostel during a particular semester. During their tenure, they caught 4 different girls breaking different rules of the hostel. Each of these caught girls was awarded a different punishment by the hostel warden. With the help of these clues, can you figure out which friend caught which girl, breaking which rule, and which girl got which punishment? \n\r\nFriends: Dis, Dip, Raj, Rich\r\nCaught girls: MK, GB, SJ, AK\r\nBroken Rules: Bullying, Eloping, Obscenity, Stealing\r\nPunishments: Monetary Fine, Grade Penalty, Reprimand, Suspension\n\n\r\n1. Miss SJ was suspended for trying to elope with her boyfriend.\r\n2. Miss AK was caught in a highly revealing dress and making objectionable gestures in the waiting hall.\r\n3. Dip caught the girl who was stealing food and clothes from other girls' rooms.\r\n4. Though usually calm, Rich lost her temper when she found that Miss GB was unnecessarily torturing her juniors.\r\n5. The warden severely reprimanded Miss MK for breaking rules.\r\n6. The bully was not fined monetarily.\r\n7. The girl caught by Raj remained broke for the entire semester because of the punishment awarded to her.", "hint": "Grade penalty means that you get lower grades than you deserve.", "answer": "Dis got Miss SJ suspended for trying to elope with her boyfriend.\r\nMiss MK was severely reprimanded for stealing when she was caught red-handed by Dip.\r\nRaj caught Miss AK doing some obscenities which made Miss AK pay a heavy monetary fine.\r\nMiss GB was caught by Rich when she was bullying a junior and so she received a grade penalty.", "category": "Logic-Grid", "date": "07/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 4 friends were made monitors of their hostel during a particular semester. During their tenure, they caught 4 different girls breaking different rules of the hostel. Each of these caught girls was awarded a different punishment by the hostel warden. With the help of these clues, can you figure out which friend caught which girl, breaking which rule, and which girl got which punishment? \n\r\nFriends: Dis, Dip, Raj, Rich\r\nCaught girls: MK, GB, SJ, AK\r\nBroken Rules: Bullying, Eloping, Obscenity, Stealing\r\nPunishments: Monetary Fine, Grade Penalty, Reprimand, Suspension\n\n\r\n1. Miss SJ was suspended for trying to elope with her boyfriend.\r\n2. Miss AK was caught in a highly revealing dress and making objectionable gestures in the waiting hall.\r\n3. Dip caught the girl who was stealing food and clothes from other girls' rooms.\r\n4. Though usually calm, Rich lost her temper when she found that Miss GB was unnecessarily torturing her juniors.\r\n5. The warden severely reprimanded Miss MK for breaking rules.\r\n6. The bully was not fined monetarily.\r\n7. The girl caught by Raj remained broke for the entire semester because of the punishment awarded to her.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDis got Miss SJ suspended for trying to elope with her boyfriend.\r\nMiss MK was severely reprimanded for stealing when she was caught red-handed by Dip.\r\nRaj caught Miss AK doing some obscenities which made Miss AK pay a heavy monetary fine.\r\nMiss GB was caught by Rich when she was bullying a junior and so she received a grade penalty.\n<|im_start|>answer\nDis got Miss SJ suspended for trying to elope with her boyfriend.\r\nMiss MK was severely reprimanded for stealing when she was caught red-handed by Dip.\r\nRaj caught Miss AK doing some obscenities which made Miss AK pay a heavy monetary fine.\r\nMiss GB was caught by Rich when she was bullying a junior and so she received a grade penalty.\n<|im_end|>" }, { "id": "#52407", "title": "Pick A Conclusive Statement", "fun": 2.6, "difficulty": 2.0, "author": "Rove_Tarts", "desc": "Eli and four of his friends either always lie or always tell the truth. His friends made the following statements:\n\r\nAlice: Daniel or Eli is lying\r\nBarry: Eli, Daniel, & Callie are telling the truth\r\nCallie: Daniel is lying\r\nDaniel: Callie and/or Barry is lying\n\r\nEli said one of the following things:\n\r\nAlice & Barry are opposites (one lies and one tells the truth)\r\nAlice & Daniel are opposites\r\nBarry & Callie aren't opposites\r\nCallie & Myself aren't opposites\n\r\nIf you knew which of the four statements was spoken by Eli, then you would know who was lying and who was telling the truth. What did Eli say? Who is lying?", "hint": "No hint available.", "answer": "Barry & Callie aren't opposites; Alice, Barry, & Callie are lying.\n\r\nFirst figure out who you can figure out before you even go to Eli's statements.\n\r\nAssume Barry was telling the truth \r\nDaniel is telling the truth\r\nCallie was telling the truth\r\nTherefore Daniel is lying\r\nWhich is a contradiction\r\nSo Barry is definitely lying\r\nWhich means Daniel is telling the truth\r\nWhich means Callie is lying\n\r\nWe can't know Alice's or Eli's position yet.\n\r\nIf Eli says Alice & Barry are opposites & Eli is honest, then Alice is honest.\r\nIf Alice is honest then Eli is lying because Daniel isn't lying.\r\nThat's a contradiction.\r\nIf Eli is lying then Alice is lying, and Eli is telling the truth.\n\r\nIf Eli says Callie & Myself aren't opposites, then Eli is basically saying that he himself is a liar, which is a contradiction.\n\r\nIf Eli said Alice & Daniel are opposites & is telling the truth, then Alice is lying & Eli is telling the truth.\r\nIf Eli said Alice & Daniel are opposites & is lying, then Alice is telling the truth & Eli is lying.\r\nThere is no way to conclude who is lying, but Eli's statement is conclusive, therefore it can't be this.\n\r\nIf Eli said Callie & Barry aren't opposites, then he would be telling the truth & Alice would be lying.", "category": "Logic", "date": "06/14/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEli and four of his friends either always lie or always tell the truth. His friends made the following statements:\n\r\nAlice: Daniel or Eli is lying\r\nBarry: Eli, Daniel, & Callie are telling the truth\r\nCallie: Daniel is lying\r\nDaniel: Callie and/or Barry is lying\n\r\nEli said one of the following things:\n\r\nAlice & Barry are opposites (one lies and one tells the truth)\r\nAlice & Daniel are opposites\r\nBarry & Callie aren't opposites\r\nCallie & Myself aren't opposites\n\r\nIf you knew which of the four statements was spoken by Eli, then you would know who was lying and who was telling the truth. What did Eli say? Who is lying?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBarry & Callie aren't opposites; Alice, Barry, & Callie are lying.\n\r\nFirst figure out who you can figure out before you even go to Eli's statements.\n\r\nAssume Barry was telling the truth \r\nDaniel is telling the truth\r\nCallie was telling the truth\r\nTherefore Daniel is lying\r\nWhich is a contradiction\r\nSo Barry is definitely lying\r\nWhich means Daniel is telling the truth\r\nWhich means Callie is lying\n\r\nWe can't know Alice's or Eli's position yet.\n\r\nIf Eli says Alice & Barry are opposites & Eli is honest, then Alice is honest.\r\nIf Alice is honest then Eli is lying because Daniel isn't lying.\r\nThat's a contradiction.\r\nIf Eli is lying then Alice is lying, and Eli is telling the truth.\n\r\nIf Eli says Callie & Myself aren't opposites, then Eli is basically saying that he himself is a liar, which is a contradiction.\n\r\nIf Eli said Alice & Daniel are opposites & is telling the truth, then Alice is lying & Eli is telling the truth.\r\nIf Eli said Alice & Daniel are opposites & is lying, then Alice is telling the truth & Eli is lying.\r\nThere is no way to conclude who is lying, but Eli's statement is conclusive, therefore it can't be this.\n\r\nIf Eli said Callie & Barry aren't opposites, then he would be telling the truth & Alice would be lying.\n<|im_start|>answer\nBarry & Callie aren't opposites; Alice, Barry, & Callie are lying.\n\r\nFirst figure out who you can figure out before you even go to Eli's statements.\n\r\nAssume Barry was telling the truth \r\nDaniel is telling the truth\r\nCallie was telling the truth\r\nTherefore Daniel is lying\r\nWhich is a contradiction\r\nSo Barry is definitely lying\r\nWhich means Daniel is telling the truth\r\nWhich means Callie is lying\n\r\nWe can't know Alice's or Eli's position yet.\n\r\nIf Eli says Alice & Barry are opposites & Eli is honest, then Alice is honest.\r\nIf Alice is honest then Eli is lying because Daniel isn't lying.\r\nThat's a contradiction.\r\nIf Eli is lying then Alice is lying, and Eli is telling the truth.\n\r\nIf Eli says Callie & Myself aren't opposites, then Eli is basically saying that he himself is a liar, which is a contradiction.\n\r\nIf Eli said Alice & Daniel are opposites & is telling the truth, then Alice is lying & Eli is telling the truth.\r\nIf Eli said Alice & Daniel are opposites & is lying, then Alice is telling the truth & Eli is lying.\r\nThere is no way to conclude who is lying, but Eli's statement is conclusive, therefore it can't be this.\n\r\nIf Eli said Callie & Barry aren't opposites, then he would be telling the truth & Alice would be lying.\n<|im_end|>" }, { "id": "#29774", "title": "Aliens on Earth", "fun": 2.6, "difficulty": 2.12, "author": "npf2005", "desc": "100 aliens attended an intergalactic meeting on earth.\n\r\n73 had two heads,\r\n28 had three eyes,\r\n21 had four arms,\r\n12 had two heads and three eyes,\r\n9 had three eyes and four arms,\r\n8 had two heads and four arms,\r\n3 had all three unusual features.\n\r\nHow many aliens had none of these unusual features?", "hint": "No hint available.", "answer": "4 aliens.\n\r\nDraw a venn diagram.", "category": "Logic", "date": "04/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n100 aliens attended an intergalactic meeting on earth.\n\r\n73 had two heads,\r\n28 had three eyes,\r\n21 had four arms,\r\n12 had two heads and three eyes,\r\n9 had three eyes and four arms,\r\n8 had two heads and four arms,\r\n3 had all three unusual features.\n\r\nHow many aliens had none of these unusual features?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 aliens.\n\r\nDraw a venn diagram.\n<|im_start|>answer\n4 aliens.\n\r\nDraw a venn diagram.\n<|im_end|>" }, { "id": "#14064", "title": "Belly Beans", "fun": 2.6, "difficulty": 2.31, "author": "taniapereira99", "desc": "Jelly Belly beans were the first jelly beans in outer space when President Reagan sent them on the 1983 flight of the space shuttle Challenger.\n\r\nThree astronauts had four jelly beans left among them one night - a black, a yellow, a green and a red. No astronaut ate more than one jelly bean and the red bean was definitely eaten. According to the following statements, determine which astronaut ate which jelly bean.\n\r\n1. If the second astronaut did not eat the yellow or green jelly bean, then the first astronaut ate the red bean.\n\r\n2. The second astronaut ate the yellow jelly bean, unless the first astronaut ate the red jelly bean.\n\r\n3. If the third astronaut did not eat the black or yellow jelly bean then the second astronaut ate the red bean.\n\r\n4. If the third astronaut ate the yellow jelly bean then the first astronaut did not eat the red jelly bean.", "hint": "If all else fails, use trial and error.", "answer": "First astronaut - red jelly bean\r\nSecond astronaut - green jelly bean\r\nThird astronaut - black jelly bean\n\r\nFrom statement 3, you can deduce that the third astronaut did NOT eat the red jelly bean.\r\nSimilarly, from statement 1, it can be determined that the second astronaut did not eat the red jelly bean. Therefore the first astronaut ate the red jelly bean.\r\nFrom 4, then the third did not eat the yellow bean. Therefore they ate the black jelly bean since from 3, the second did not eat the red bean.\r\nFrom 2, the second ate the green and the yellow bean was uneaten.", "category": "Logic", "date": "07/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJelly Belly beans were the first jelly beans in outer space when President Reagan sent them on the 1983 flight of the space shuttle Challenger.\n\r\nThree astronauts had four jelly beans left among them one night - a black, a yellow, a green and a red. No astronaut ate more than one jelly bean and the red bean was definitely eaten. According to the following statements, determine which astronaut ate which jelly bean.\n\r\n1. If the second astronaut did not eat the yellow or green jelly bean, then the first astronaut ate the red bean.\n\r\n2. The second astronaut ate the yellow jelly bean, unless the first astronaut ate the red jelly bean.\n\r\n3. If the third astronaut did not eat the black or yellow jelly bean then the second astronaut ate the red bean.\n\r\n4. If the third astronaut ate the yellow jelly bean then the first astronaut did not eat the red jelly bean.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst astronaut - red jelly bean\r\nSecond astronaut - green jelly bean\r\nThird astronaut - black jelly bean\n\r\nFrom statement 3, you can deduce that the third astronaut did NOT eat the red jelly bean.\r\nSimilarly, from statement 1, it can be determined that the second astronaut did not eat the red jelly bean. Therefore the first astronaut ate the red jelly bean.\r\nFrom 4, then the third did not eat the yellow bean. Therefore they ate the black jelly bean since from 3, the second did not eat the red bean.\r\nFrom 2, the second ate the green and the yellow bean was uneaten.\n<|im_start|>answer\nFirst astronaut - red jelly bean\r\nSecond astronaut - green jelly bean\r\nThird astronaut - black jelly bean\n\r\nFrom statement 3, you can deduce that the third astronaut did NOT eat the red jelly bean.\r\nSimilarly, from statement 1, it can be determined that the second astronaut did not eat the red jelly bean. Therefore the first astronaut ate the red jelly bean.\r\nFrom 4, then the third did not eat the yellow bean. Therefore they ate the black jelly bean since from 3, the second did not eat the red bean.\r\nFrom 2, the second ate the green and the yellow bean was uneaten.\n<|im_end|>" }, { "id": "#6953", "title": "Cages and Canaries", "fun": 2.6, "difficulty": 1.23, "author": "Cascas", "desc": "I am the owner of a pet store. If I put in one canary per cage, I have one bird too many. If I put in two canaries per cage, I have one cage too many. How many cages and canaries do I have?", "hint": "No hint available.", "answer": "4 birds and 3 cages\n\r\nSolution:\n\r\nlet x = the number of canaries and y = the number of cages. You can set up two equations using the two situations given.\n\r\nFirst, if there is one canary per cage, then there is 1 cage too many (in other words, there is one more bird than cages): x - y = 1\n\r\nSecond, if there are two canaries per cage, then there is 1 cage too many (in other words, there is one more cage than half the number of canaries): y - x/2 = 1\n\r\nSolve the two equations to get x = 4 and y = 3.", "category": "Math", "date": "08/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am the owner of a pet store. If I put in one canary per cage, I have one bird too many. If I put in two canaries per cage, I have one cage too many. How many cages and canaries do I have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 birds and 3 cages\n\r\nSolution:\n\r\nlet x = the number of canaries and y = the number of cages. You can set up two equations using the two situations given.\n\r\nFirst, if there is one canary per cage, then there is 1 cage too many (in other words, there is one more bird than cages): x - y = 1\n\r\nSecond, if there are two canaries per cage, then there is 1 cage too many (in other words, there is one more cage than half the number of canaries): y - x/2 = 1\n\r\nSolve the two equations to get x = 4 and y = 3.\n<|im_start|>answer\n4 birds and 3 cages\n\r\nSolution:\n\r\nlet x = the number of canaries and y = the number of cages. You can set up two equations using the two situations given.\n\r\nFirst, if there is one canary per cage, then there is 1 cage too many (in other words, there is one more bird than cages): x - y = 1\n\r\nSecond, if there are two canaries per cage, then there is 1 cage too many (in other words, there is one more cage than half the number of canaries): y - x/2 = 1\n\r\nSolve the two equations to get x = 4 and y = 3.\n<|im_end|>" }, { "id": "#29539", "title": "Instrumental", "fun": 2.6, "difficulty": 1.6300000000000001, "author": "EnderofGames", "desc": "Anderson, Gerston, Hupper, Jaywin, and Sommers play different musical instruments (one each). The instruments are the baritone horn, the clarinet, the flute, the oboe, and the trumpet. Figure out what instrument each person plays.\n\r\n1) Anderson and Hupper play reed instruments.\n\r\n2) Jaywin and Sommers play brass instruments.\n\r\n3) Hupper and the clarinet player went jogging with Jaywin and the trumpet player.", "hint": "No hint available.", "answer": "Anderson - Clarinet\r\nGerston - Flute\r\nHupper - Oboe\r\nJaywin - Baritone Horn\r\nSommers - Trumpet", "category": "Logic", "date": "04/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnderson, Gerston, Hupper, Jaywin, and Sommers play different musical instruments (one each). The instruments are the baritone horn, the clarinet, the flute, the oboe, and the trumpet. Figure out what instrument each person plays.\n\r\n1) Anderson and Hupper play reed instruments.\n\r\n2) Jaywin and Sommers play brass instruments.\n\r\n3) Hupper and the clarinet player went jogging with Jaywin and the trumpet player.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnderson - Clarinet\r\nGerston - Flute\r\nHupper - Oboe\r\nJaywin - Baritone Horn\r\nSommers - Trumpet\n<|im_start|>answer\nAnderson - Clarinet\r\nGerston - Flute\r\nHupper - Oboe\r\nJaywin - Baritone Horn\r\nSommers - Trumpet\n<|im_end|>" }, { "id": "#36097", "title": "Election In A Small Town", "fun": 2.6, "difficulty": 1.23, "author": "chaskey", "desc": "In the happy town of Minuscule, population 411 or 412, depending on who does the count, four good citizens ran for the office of Mayor. To see who became the Minuscule Mayor, or better, the Mayor of Minuscule, see the clues below.\n\r\nCandidates: Owen, Edith, Nora, George\r\nLocation of major speech: store, school, barbershop, saloon\r\nNumber of people in audience: 8, 12, 20, 40\r\nLength of speech: 15, 20, 30, 60 minutes\r\nNumber of final votes received: 13, 26, 33, 52\n\r\nClues:\r\n 1. It was only coincidental that George's speech was as many minutes long as the number of other people there in the store.\n\r\n 2. Edith's hour-long speech was unplanned--she had gotten in an argument with the bartender. There were twelve people besides Edith there that morning. (None of them were listening, but that doesn't matter).\n\r\n 3. Nora gave her main speech at the school. It came right before the school's Saturday band concert, at which there were 40 people.\n\r\n 4. The candidate who spoke for 20 minutes got 6 more votes than the number of minutes he spoke, which was twice as many votes as the one who spoke for an hour received.\n\r\n 5. Owen's 15-minute speech was to inform his listeners that he was withdrawing his candidacy in favor of his wife, Nora, who was runner-up in the race for votes.", "hint": "No hint available.", "answer": "Owen--barbershop--8 people--15 minutes--52 votes\r\nEdith--saloon--12 people-60 minutes--13 votes\r\nNora--school--40 people--30 minutes--33 votes\r\nGeorge--store--20 people--20 minutes--26 votes", "category": "Logic-Grid", "date": "04/07/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the happy town of Minuscule, population 411 or 412, depending on who does the count, four good citizens ran for the office of Mayor. To see who became the Minuscule Mayor, or better, the Mayor of Minuscule, see the clues below.\n\r\nCandidates: Owen, Edith, Nora, George\r\nLocation of major speech: store, school, barbershop, saloon\r\nNumber of people in audience: 8, 12, 20, 40\r\nLength of speech: 15, 20, 30, 60 minutes\r\nNumber of final votes received: 13, 26, 33, 52\n\r\nClues:\r\n 1. It was only coincidental that George's speech was as many minutes long as the number of other people there in the store.\n\r\n 2. Edith's hour-long speech was unplanned--she had gotten in an argument with the bartender. There were twelve people besides Edith there that morning. (None of them were listening, but that doesn't matter).\n\r\n 3. Nora gave her main speech at the school. It came right before the school's Saturday band concert, at which there were 40 people.\n\r\n 4. The candidate who spoke for 20 minutes got 6 more votes than the number of minutes he spoke, which was twice as many votes as the one who spoke for an hour received.\n\r\n 5. Owen's 15-minute speech was to inform his listeners that he was withdrawing his candidacy in favor of his wife, Nora, who was runner-up in the race for votes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOwen--barbershop--8 people--15 minutes--52 votes\r\nEdith--saloon--12 people-60 minutes--13 votes\r\nNora--school--40 people--30 minutes--33 votes\r\nGeorge--store--20 people--20 minutes--26 votes\n<|im_start|>answer\nOwen--barbershop--8 people--15 minutes--52 votes\r\nEdith--saloon--12 people-60 minutes--13 votes\r\nNora--school--40 people--30 minutes--33 votes\r\nGeorge--store--20 people--20 minutes--26 votes\n<|im_end|>" }, { "id": "#48751", "title": "Clap Your Hands", "fun": 2.6, "difficulty": 2.03, "author": "Mathgeek007", "desc": "There is a special auditorium that holds 100 people. It is not full. Each person claps seven times after a performance. Every time ten claps are heard, the man in the front twitches. Every third twitch, one of the actors hops. Every two hops, a person in the crowd cheers. Every four cheers, the actors bow. If they only bowed once, what is the least amount of people that can be in the auditorium?\n\r\nBONUS! How many bows will the actors do if the auditorium is full?", "hint": "Just try going through the whole process backwards.\n\r\nBONUS! Try doing the process forward. (Remember you can't have a fraction of a twitch or a clap, ect.)", "answer": "One bow = 4 cheers.\r\n4 cheers = 8 hops.\r\n8 hops = 24 twitches.\r\n24 twitches = 240 claps.\r\n240/7 = 34.28\n\r\nSince you can't have a fraction of a person, there must have been at least 35 people.\n\r\nBONUS!\n\r\n100 people = 700 claps.\r\n700 claps = 70 twitches.\r\n70 twitches = 23 hops. (You can't have .3 of a hop)\r\n23 hops = 11 cheers. (You can't have half of a cheer)\r\n11 cheers = 2 bows. (You can't have three-quarters of a bow)\n\r\nAt most, they will bow twice.", "category": "Logic", "date": "05/25/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a special auditorium that holds 100 people. It is not full. Each person claps seven times after a performance. Every time ten claps are heard, the man in the front twitches. Every third twitch, one of the actors hops. Every two hops, a person in the crowd cheers. Every four cheers, the actors bow. If they only bowed once, what is the least amount of people that can be in the auditorium?\n\r\nBONUS! How many bows will the actors do if the auditorium is full?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne bow = 4 cheers.\r\n4 cheers = 8 hops.\r\n8 hops = 24 twitches.\r\n24 twitches = 240 claps.\r\n240/7 = 34.28\n\r\nSince you can't have a fraction of a person, there must have been at least 35 people.\n\r\nBONUS!\n\r\n100 people = 700 claps.\r\n700 claps = 70 twitches.\r\n70 twitches = 23 hops. (You can't have .3 of a hop)\r\n23 hops = 11 cheers. (You can't have half of a cheer)\r\n11 cheers = 2 bows. (You can't have three-quarters of a bow)\n\r\nAt most, they will bow twice.\n<|im_start|>answer\nOne bow = 4 cheers.\r\n4 cheers = 8 hops.\r\n8 hops = 24 twitches.\r\n24 twitches = 240 claps.\r\n240/7 = 34.28\n\r\nSince you can't have a fraction of a person, there must have been at least 35 people.\n\r\nBONUS!\n\r\n100 people = 700 claps.\r\n700 claps = 70 twitches.\r\n70 twitches = 23 hops. (You can't have .3 of a hop)\r\n23 hops = 11 cheers. (You can't have half of a cheer)\r\n11 cheers = 2 bows. (You can't have three-quarters of a bow)\n\r\nAt most, they will bow twice.\n<|im_end|>" }, { "id": "#3237", "title": "Buckle Con", "fun": 2.6, "difficulty": 1.14, "author": "supermew30", "desc": "Bart and Lisa wanted to buy a great birthday present for their dad. They went to the mall and looked for hours. At the end of the second hour, Bart says, \"This is impossible! Let's go home, man!\" \"Let's look at the clothing store,\" says Lisa. They decide to buy a belt buckle from World War 1. On the front it says, \"WW1 Flying Ace.\" They take the belt to the cops and claim it is a fake.\n\r\nHow did they know it was a fake belt buckle?", "hint": "No hint available.", "answer": "The buckle can't be from World War 1. The buckle couldn't have said WW1 on it because they did not know there was going to be a WW2. It should have said \"The Great War\" instead.", "category": "Logic", "date": "04/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBart and Lisa wanted to buy a great birthday present for their dad. They went to the mall and looked for hours. At the end of the second hour, Bart says, \"This is impossible! Let's go home, man!\" \"Let's look at the clothing store,\" says Lisa. They decide to buy a belt buckle from World War 1. On the front it says, \"WW1 Flying Ace.\" They take the belt to the cops and claim it is a fake.\n\r\nHow did they know it was a fake belt buckle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe buckle can't be from World War 1. The buckle couldn't have said WW1 on it because they did not know there was going to be a WW2. It should have said \"The Great War\" instead.\n<|im_start|>answer\nThe buckle can't be from World War 1. The buckle couldn't have said WW1 on it because they did not know there was going to be a WW2. It should have said \"The Great War\" instead.\n<|im_end|>" }, { "id": "#50219", "title": "Minecraft Fans", "fun": 2.6, "difficulty": 1.17, "author": "klsowell", "desc": "Two girls and two boys - Sarah, Kate, Connor, and Jared - were playing the game Minecraft one day. They each had a different username, build, and favorite block. Using the clues, can you figure out which is which?\n\r\nNames: Sarah, Kate, Jared, Connor\r\nBuilds: Castle, Mansion, Skyscraper, Statue\r\nUsernames: puppy23, DragonLord, Blue_Pencil, jtepic\r\nFavorite Blocks: Emerald, Cobblestone, Sponge, Redstone\n\r\nClues:\n\r\n1. The four people are: Blue_Pencil, the one who likes emerald, the one who built the skyscraper, and Jared.\n\r\n2. Neither of the boys like puppies, so they didn't choose their username after them.\n\r\n3. Connor's favorite block is almost electric - it can power machines and prime TNT.\n\r\n4. Jared is into medieval builds, and so made his build in that style.\n\r\n5. puppy23 was very proud of the \"skin\" - or avatar - she'd made, so she built it in huge scale so everyone could see it.\n\r\n6. Even though Sarah offered to help, DragonLord built his skyscraper all by himself. He used redstone for the lights and all the mechanics - his favorite block.\n\r\n7. The girl who liked cobblestone wanted to make a big build, like the others, but she also built something she could live in. She also made her friend, puppy23, her own room.\n\r\n8. Sarah thought emerald was a way overused block, and much preferred her favorite - cobblestone.\n\r\n9. At school, Sarah has had exactly one pencil throughout the entire school year, and it's bright blue.", "hint": "By the way, the medieval era's style includes mansions and castles.", "answer": "Sarah's username is Blue_Pencil, and she built a mansion and likes cobblestone.\r\nKate's username is puppy23, and she built a statue and likes emerald.\r\nConnor's username is DragonLord, and he built a skyscraper and likes redstone.\r\nJared's username is jtepic, and he built a castle and likes sponge.", "category": "Logic-Grid", "date": "04/02/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo girls and two boys - Sarah, Kate, Connor, and Jared - were playing the game Minecraft one day. They each had a different username, build, and favorite block. Using the clues, can you figure out which is which?\n\r\nNames: Sarah, Kate, Jared, Connor\r\nBuilds: Castle, Mansion, Skyscraper, Statue\r\nUsernames: puppy23, DragonLord, Blue_Pencil, jtepic\r\nFavorite Blocks: Emerald, Cobblestone, Sponge, Redstone\n\r\nClues:\n\r\n1. The four people are: Blue_Pencil, the one who likes emerald, the one who built the skyscraper, and Jared.\n\r\n2. Neither of the boys like puppies, so they didn't choose their username after them.\n\r\n3. Connor's favorite block is almost electric - it can power machines and prime TNT.\n\r\n4. Jared is into medieval builds, and so made his build in that style.\n\r\n5. puppy23 was very proud of the \"skin\" - or avatar - she'd made, so she built it in huge scale so everyone could see it.\n\r\n6. Even though Sarah offered to help, DragonLord built his skyscraper all by himself. He used redstone for the lights and all the mechanics - his favorite block.\n\r\n7. The girl who liked cobblestone wanted to make a big build, like the others, but she also built something she could live in. She also made her friend, puppy23, her own room.\n\r\n8. Sarah thought emerald was a way overused block, and much preferred her favorite - cobblestone.\n\r\n9. At school, Sarah has had exactly one pencil throughout the entire school year, and it's bright blue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah's username is Blue_Pencil, and she built a mansion and likes cobblestone.\r\nKate's username is puppy23, and she built a statue and likes emerald.\r\nConnor's username is DragonLord, and he built a skyscraper and likes redstone.\r\nJared's username is jtepic, and he built a castle and likes sponge.\n<|im_start|>answer\nSarah's username is Blue_Pencil, and she built a mansion and likes cobblestone.\r\nKate's username is puppy23, and she built a statue and likes emerald.\r\nConnor's username is DragonLord, and he built a skyscraper and likes redstone.\r\nJared's username is jtepic, and he built a castle and likes sponge.\n<|im_end|>" }, { "id": "#118", "title": "Bushels of Apples", "fun": 2.6, "difficulty": 2.54, "author": "jerry1", "desc": "An unemployed man walks into a shipping warehouse on the wharf. He goes to the foreman and asks for a job. The foreman says he`ll give him a job if he can figure out a problem with 10 bushels of apples. Nine of the bushels are full of apples weighing 1 pound each, but one bushel contains apples weighing 1.1 pounds each. All of the bushels contain the same number of apples. The foreman wants to know which bushel has the heavy apples. There is a scale, but he can only make one measurement on the scale. Making only one weight measurement, how can the man find which bushel contains the heavy apples? He can include any combination of bushels or apples on the scale.", "hint": "You only need to weigh apples, not bushels.", "answer": "The man takes one apple from the first bushel, 2 apples from the second bushel, and so on through the 10 bushels. He then weighs all of these apples. Since each apple in the heavy bushel weighs an extra .1 pound, the weight of the apples would be between 55.1 to 56.0 pounds. The portion over 55 pounds would tell you which bushel has the heavy apples. If the weight is 55.4 pounds, then the bushel with the heavy apples is bushel #4 and so on.", "category": "Math", "date": "01/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn unemployed man walks into a shipping warehouse on the wharf. He goes to the foreman and asks for a job. The foreman says he`ll give him a job if he can figure out a problem with 10 bushels of apples. Nine of the bushels are full of apples weighing 1 pound each, but one bushel contains apples weighing 1.1 pounds each. All of the bushels contain the same number of apples. The foreman wants to know which bushel has the heavy apples. There is a scale, but he can only make one measurement on the scale. Making only one weight measurement, how can the man find which bushel contains the heavy apples? He can include any combination of bushels or apples on the scale.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man takes one apple from the first bushel, 2 apples from the second bushel, and so on through the 10 bushels. He then weighs all of these apples. Since each apple in the heavy bushel weighs an extra .1 pound, the weight of the apples would be between 55.1 to 56.0 pounds. The portion over 55 pounds would tell you which bushel has the heavy apples. If the weight is 55.4 pounds, then the bushel with the heavy apples is bushel #4 and so on.\n<|im_start|>answer\nThe man takes one apple from the first bushel, 2 apples from the second bushel, and so on through the 10 bushels. He then weighs all of these apples. Since each apple in the heavy bushel weighs an extra .1 pound, the weight of the apples would be between 55.1 to 56.0 pounds. The portion over 55 pounds would tell you which bushel has the heavy apples. If the weight is 55.4 pounds, then the bushel with the heavy apples is bushel #4 and so on.\n<|im_end|>" }, { "id": "#8498", "title": "Oranges 2", "fun": 2.6, "difficulty": 2.04, "author": "lesternoronha1", "desc": "Lester has a number of oranges that he has to put into a box. He finds that when he puts them 2 at a time, 1 remains; when he puts them 3 at a time, 2 remain; when he puts them 4 at a time, 3 remain; when he puts them 5 at a time, 4 remain; when he puts them 6 at a time, 5 remain. However when he puts them 7 at a time, none remain. Can you find the number of oranges he has?", "hint": "No hint available.", "answer": "Lester has 119 oranges.\n\r\nThere are probably a few ways to solve this, but one way is to first find multiples of 7 that are not multiples of 2, 3, 4, 5 or 6. This will narrow down your search, and then you can use trial and error to find the answer.", "category": "Math", "date": "11/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester has a number of oranges that he has to put into a box. He finds that when he puts them 2 at a time, 1 remains; when he puts them 3 at a time, 2 remain; when he puts them 4 at a time, 3 remain; when he puts them 5 at a time, 4 remain; when he puts them 6 at a time, 5 remain. However when he puts them 7 at a time, none remain. Can you find the number of oranges he has?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLester has 119 oranges.\n\r\nThere are probably a few ways to solve this, but one way is to first find multiples of 7 that are not multiples of 2, 3, 4, 5 or 6. This will narrow down your search, and then you can use trial and error to find the answer.\n<|im_start|>answer\nLester has 119 oranges.\n\r\nThere are probably a few ways to solve this, but one way is to first find multiples of 7 that are not multiples of 2, 3, 4, 5 or 6. This will narrow down your search, and then you can use trial and error to find the answer.\n<|im_end|>" }, { "id": "#1360", "title": "Find the Fake Coin", "fun": 2.6, "difficulty": 2.56, "author": "Yanivster", "desc": "There are 12 gold coins. One of the coins is fake. It is known that a fake coin weighs either slightly less or slightly more than a real coin. Using a balance scale, how can you find the fake coin, and determine if it weighs less or more than a real coin, in only three weighings?", "hint": "No hint available.", "answer": "Divide the coins into three groups of 4 coins each. First, weigh two of the groups. If they balance, then the fake coin is in the third group, so take three of the coins, and weigh them against three of the coins that we know for sure are real (from the first 8 coins). If they balance, then the remaining coin is the fake one, but we still don't know if it is lighter or heavier, so weigh it against a real coin to determine that. But if it didn't balance, then we know that the fake coin is one of the three, and we also know if it is lighter or heavier, because we know which side had the real coins. So weigh two of the coins against each other, if they balance then the third coin is fake, if they don't balance we know which coin is fake, because we already know if it is lighter or heavier. \r\nNow let's go back to the first weighing; if the two groups didn't balance, we know that the fake coin is in one of the groups, but we don't know which group. Let's mark the group that was heavier as group A, and the group that was lighter group B. For the second weighing, weigh two coins of group A and one coin of group B, against the other two coins of group A and one coin of group B. If they balance, the fake coin must be one of the remaining two, and a weigh between them will tell us which one (they are both from group B so we know that it's lighter). If the second weigh didn't balance, look at the side that is heavier: Either the fake coin is one of the two group A coins, or it can the group B coin on the other side of the scale. Take the two group A coins, and weigh them against each other. If they balance, then it is the group B coin that is fake, and if they don't balance, then the heavier one is the fake coin. \r\nAnd that's that. We have covered all possibilities.", "category": "Logic", "date": "11/11/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 12 gold coins. One of the coins is fake. It is known that a fake coin weighs either slightly less or slightly more than a real coin. Using a balance scale, how can you find the fake coin, and determine if it weighs less or more than a real coin, in only three weighings?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDivide the coins into three groups of 4 coins each. First, weigh two of the groups. If they balance, then the fake coin is in the third group, so take three of the coins, and weigh them against three of the coins that we know for sure are real (from the first 8 coins). If they balance, then the remaining coin is the fake one, but we still don't know if it is lighter or heavier, so weigh it against a real coin to determine that. But if it didn't balance, then we know that the fake coin is one of the three, and we also know if it is lighter or heavier, because we know which side had the real coins. So weigh two of the coins against each other, if they balance then the third coin is fake, if they don't balance we know which coin is fake, because we already know if it is lighter or heavier. \r\nNow let's go back to the first weighing; if the two groups didn't balance, we know that the fake coin is in one of the groups, but we don't know which group. Let's mark the group that was heavier as group A, and the group that was lighter group B. For the second weighing, weigh two coins of group A and one coin of group B, against the other two coins of group A and one coin of group B. If they balance, the fake coin must be one of the remaining two, and a weigh between them will tell us which one (they are both from group B so we know that it's lighter). If the second weigh didn't balance, look at the side that is heavier: Either the fake coin is one of the two group A coins, or it can the group B coin on the other side of the scale. Take the two group A coins, and weigh them against each other. If they balance, then it is the group B coin that is fake, and if they don't balance, then the heavier one is the fake coin. \r\nAnd that's that. We have covered all possibilities.\n<|im_start|>answer\nDivide the coins into three groups of 4 coins each. First, weigh two of the groups. If they balance, then the fake coin is in the third group, so take three of the coins, and weigh them against three of the coins that we know for sure are real (from the first 8 coins). If they balance, then the remaining coin is the fake one, but we still don't know if it is lighter or heavier, so weigh it against a real coin to determine that. But if it didn't balance, then we know that the fake coin is one of the three, and we also know if it is lighter or heavier, because we know which side had the real coins. So weigh two of the coins against each other, if they balance then the third coin is fake, if they don't balance we know which coin is fake, because we already know if it is lighter or heavier. \r\nNow let's go back to the first weighing; if the two groups didn't balance, we know that the fake coin is in one of the groups, but we don't know which group. Let's mark the group that was heavier as group A, and the group that was lighter group B. For the second weighing, weigh two coins of group A and one coin of group B, against the other two coins of group A and one coin of group B. If they balance, the fake coin must be one of the remaining two, and a weigh between them will tell us which one (they are both from group B so we know that it's lighter). If the second weigh didn't balance, look at the side that is heavier: Either the fake coin is one of the two group A coins, or it can the group B coin on the other side of the scale. Take the two group A coins, and weigh them against each other. If they balance, then it is the group B coin that is fake, and if they don't balance, then the heavier one is the fake coin. \r\nAnd that's that. We have covered all possibilities.\n<|im_end|>" }, { "id": "#27663", "title": "Largest Number II", "fun": 2.6, "difficulty": 2.15, "author": "shenqiang", "desc": "What's the largest 6-digit number that satisfies this condition:\n\r\nEach digit from the third on equals the product of its two preceding digits.", "hint": "No hint available.", "answer": "This time, the number of digits is fixed (6), so we should start with the largest digits possible. The first digit is at most 9, and if the second digit is 1 or more, we can't make such a 6-digit number.\n\r\nSo, the largest number we are looking for is 900000.", "category": "Math", "date": "12/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat's the largest 6-digit number that satisfies this condition:\n\r\nEach digit from the third on equals the product of its two preceding digits.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis time, the number of digits is fixed (6), so we should start with the largest digits possible. The first digit is at most 9, and if the second digit is 1 or more, we can't make such a 6-digit number.\n\r\nSo, the largest number we are looking for is 900000.\n<|im_start|>answer\nThis time, the number of digits is fixed (6), so we should start with the largest digits possible. The first digit is at most 9, and if the second digit is 1 or more, we can't make such a 6-digit number.\n\r\nSo, the largest number we are looking for is 900000.\n<|im_end|>" }, { "id": "#16176", "title": "Faithful", "fun": 2.6, "difficulty": 1.3800000000000001, "author": "suchit", "desc": "Presume that you do not know what a rhino looks like. Now the question goes like this: If one day while walking in a forest with two of your close friends, one friend shows you an elephant and tells that this is a rhino, and another friend shows you a hippopotamus and tells you that this is rhino, who would you believe and why?", "hint": "No hint available.", "answer": "I told you that you do not know what a rhino looks like, not that you are unaware of what a hippo and elephant look like. So you shouldn't believe either of them.", "category": "Logic", "date": "01/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPresume that you do not know what a rhino looks like. Now the question goes like this: If one day while walking in a forest with two of your close friends, one friend shows you an elephant and tells that this is a rhino, and another friend shows you a hippopotamus and tells you that this is rhino, who would you believe and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI told you that you do not know what a rhino looks like, not that you are unaware of what a hippo and elephant look like. So you shouldn't believe either of them.\n<|im_start|>answer\nI told you that you do not know what a rhino looks like, not that you are unaware of what a hippo and elephant look like. So you shouldn't believe either of them.\n<|im_end|>" }, { "id": "#41581", "title": "3-2-1 Blast Off!", "fun": 2.6, "difficulty": 1.8, "author": "brain23", "desc": "Somehow Greenlake Elementary School had a field trip to outer space! Unfortunately, the school board can't remember the stats! Each person had a different first and last name, they were all different ages, they all liked a different planet, and they all came at a different time. \n\r\nFirst names: Greg, Kevin, Emily, Carla, Ben\r\nLast names: Waters, Brown, Craig, Samuels, Martin\r\nAges: 6, 7, 8, 9, 10\r\nFavorite planets: Mercury, Mars, Saturn, Neptune, Pluto\r\nTimes: 5, 6, 7, 8, 9\n\r\nClues:\r\n1. Carla had the most colorful last name and loved the smallest planet. She went around 6:00.\r\n2. Mr. Craig's son was startled to see his fifth grade class get to outer space at 9:00.\r\n3. Emily was nervous, for this was the first time in her six-year-old life she had gone away from her hometown.\r\n4. As the kids got nearer and nearer to Saturn, Kevin kept asking to get out of the rocket, for he admired its rings.\r\n5. Miss Waters was very excited to get to the end of the solar system, for she loved Neptune. \r\n6. Ben's class got there at 5:00, so they watched the asteroids zooming for a while.\r\n7.Greg was glad when his fourth-grade class got there at 8:00. He was dying to see Mercury!\r\n8. Ms. Samuels' son (who was in second grade) always got books about Mars at bookstores. He loved Mars.", "hint": "1st grade=6 years old\r\n2nd grade=7 years old\r\n3rd grade=8 years old\r\n4th grade=9 years old\r\n5th grade=10 years old", "answer": "Kevin Craig, age 10, loved Saturn and got to outer space at 9:00.\r\nBen Samuels, age 7, loved Mars and got to outer space at 5:00.\r\nGreg Martin, age 9, loved Mercury and got to outer space at 8:00.\r\nEmily Waters, age 6, loved Neptune and got to outer space at 7:00.\r\nCarla Brown, age 8, loved Pluto and got to outer space at 6:00.", "category": "Logic-Grid", "date": "04/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSomehow Greenlake Elementary School had a field trip to outer space! Unfortunately, the school board can't remember the stats! Each person had a different first and last name, they were all different ages, they all liked a different planet, and they all came at a different time. \n\r\nFirst names: Greg, Kevin, Emily, Carla, Ben\r\nLast names: Waters, Brown, Craig, Samuels, Martin\r\nAges: 6, 7, 8, 9, 10\r\nFavorite planets: Mercury, Mars, Saturn, Neptune, Pluto\r\nTimes: 5, 6, 7, 8, 9\n\r\nClues:\r\n1. Carla had the most colorful last name and loved the smallest planet. She went around 6:00.\r\n2. Mr. Craig's son was startled to see his fifth grade class get to outer space at 9:00.\r\n3. Emily was nervous, for this was the first time in her six-year-old life she had gone away from her hometown.\r\n4. As the kids got nearer and nearer to Saturn, Kevin kept asking to get out of the rocket, for he admired its rings.\r\n5. Miss Waters was very excited to get to the end of the solar system, for she loved Neptune. \r\n6. Ben's class got there at 5:00, so they watched the asteroids zooming for a while.\r\n7.Greg was glad when his fourth-grade class got there at 8:00. He was dying to see Mercury!\r\n8. Ms. Samuels' son (who was in second grade) always got books about Mars at bookstores. He loved Mars.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKevin Craig, age 10, loved Saturn and got to outer space at 9:00.\r\nBen Samuels, age 7, loved Mars and got to outer space at 5:00.\r\nGreg Martin, age 9, loved Mercury and got to outer space at 8:00.\r\nEmily Waters, age 6, loved Neptune and got to outer space at 7:00.\r\nCarla Brown, age 8, loved Pluto and got to outer space at 6:00.\n<|im_start|>answer\nKevin Craig, age 10, loved Saturn and got to outer space at 9:00.\r\nBen Samuels, age 7, loved Mars and got to outer space at 5:00.\r\nGreg Martin, age 9, loved Mercury and got to outer space at 8:00.\r\nEmily Waters, age 6, loved Neptune and got to outer space at 7:00.\r\nCarla Brown, age 8, loved Pluto and got to outer space at 6:00.\n<|im_end|>" }, { "id": "#1815", "title": "Twisted Birthdays", "fun": 2.6, "difficulty": 2.1, "author": "Nishoo", "desc": "One day, Jenny celebrated her birthday. Two days later, her older twin brother, Jerry, celebrated his birthday. How is this possible?", "hint": "No hint available.", "answer": "At the time she went into child labor, the mother of the twins was traveling by boat. The older twin, Jerry, was born first, early on March 1st. The boat then crossed the International Date Line, and therefore, Jenny, the younger twin, was born on February 28th. Therefore, the younger twin celebrates her birthday two days before her older brother every leap year.", "category": "Logic", "date": "12/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, Jenny celebrated her birthday. Two days later, her older twin brother, Jerry, celebrated his birthday. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt the time she went into child labor, the mother of the twins was traveling by boat. The older twin, Jerry, was born first, early on March 1st. The boat then crossed the International Date Line, and therefore, Jenny, the younger twin, was born on February 28th. Therefore, the younger twin celebrates her birthday two days before her older brother every leap year.\n<|im_start|>answer\nAt the time she went into child labor, the mother of the twins was traveling by boat. The older twin, Jerry, was born first, early on March 1st. The boat then crossed the International Date Line, and therefore, Jenny, the younger twin, was born on February 28th. Therefore, the younger twin celebrates her birthday two days before her older brother every leap year.\n<|im_end|>" }, { "id": "#17851", "title": "Petals Around the Rose", "fun": 2.6, "difficulty": 2.99, "author": "hersheykiss8908", "desc": "You roll five dice. The computer calculates the score. Your job is to find out what the computer based the score on. \n\r\nIf you roll 5, 4, 6, 3, and 5, the score is 10. \n\r\nIf you roll 1, 3, 3, 4, and 2, the score is 4. \n\r\nIf you roll 1, 6, 2, 6, and 4,the score is 0. \n\r\nWhat is the method?", "hint": "Think of the title. The score is never odd. Picture the dice in your head.", "answer": "Only the dice that have a centre dot are counted (3 and five). Count the number of dots around the centre dot. These \"petals\" are the score. A five on the die gets a score of 4, and a three on the die gets a score of 2.", "category": "Logic", "date": "06/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou roll five dice. The computer calculates the score. Your job is to find out what the computer based the score on. \n\r\nIf you roll 5, 4, 6, 3, and 5, the score is 10. \n\r\nIf you roll 1, 3, 3, 4, and 2, the score is 4. \n\r\nIf you roll 1, 6, 2, 6, and 4,the score is 0. \n\r\nWhat is the method?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOnly the dice that have a centre dot are counted (3 and five). Count the number of dots around the centre dot. These \"petals\" are the score. A five on the die gets a score of 4, and a three on the die gets a score of 2.\n<|im_start|>answer\nOnly the dice that have a centre dot are counted (3 and five). Count the number of dots around the centre dot. These \"petals\" are the score. A five on the die gets a score of 4, and a three on the die gets a score of 2.\n<|im_end|>" }, { "id": "#14582", "title": "Handy People", "fun": 2.6, "difficulty": 2.71, "author": "taniapereira99", "desc": "Long ago, back before serious illness existed and the new inventions of today, there lived the Handy People. Their height was measured in hands, and they lived long lives. From the statements below identify each of the 5 Handy people's height (12, 13, 14, 15 and 16 hands) and their ages (100, 110, 120, 130 and 140 years).\n\r\nTWIST: One statement is FALSE.\n\r\n1. Har was not the oldest, nor was he the shortest or tallest.\r\n2. Winn was taller than Edvo, who was taller but younger than Frer.\r\n3. Tolo, who was not the second oldest, was older than Har, and shorter than Frer.\r\n4. The one who was 13 hands tall was the oldest.\r\n5. Har was taller and older than Winn and Tolo.\r\n6. The fourth oldest was taller than Tolo, but shorter than Edvo, who was older than Winn.", "hint": "No hint available.", "answer": "Edvo, 15 hands, 130 years\r\nFrer, 13 hands, 140 years\r\nHar, 14 hands, 110 years\r\nTolo, 12 hands, 120 years\r\nWinn, 16 hands, 100 years\n\r\nWhen going through all the statements, it is impossible that both 3 and 5 be true. (3 says Tolo is older than Har while 5 says Har is older than Tolo.) 2 gives the order of height as Winn, Edvo, and Frer. If 5 is true, then Har must be the tallest, but this contradicts 1, therefore 5 is false. \n\r\nFrom 1, 2 and 3 it can be seen that the order of height is Winn, Edvo, Frer, and Tolo - with Har somewhere in between but not the shortest or tallest. Therefore Winn is 16 hands, and Tolo is 12. \n\r\nSince Har is not the oldest, he is not 13 hands, which makes Frer 13 hands and the oldest.\n\r\nFrom 3 and 6, Tolo is not the 2nd or 4th oldest and is not the youngest. Therefore he becomes 120 years. Also from 6, Edvo is not the 4th oldest or youngest. Therefore he is 130 years.\n\r\nSince the 4th oldest is shorter than Edvo, Har must be it at 110 years. And Winn is the youngest. Since the 4th oldest was shorter than Edvo, Har is 14 hands and Edvo is 15 hands.", "category": "Logic", "date": "08/27/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLong ago, back before serious illness existed and the new inventions of today, there lived the Handy People. Their height was measured in hands, and they lived long lives. From the statements below identify each of the 5 Handy people's height (12, 13, 14, 15 and 16 hands) and their ages (100, 110, 120, 130 and 140 years).\n\r\nTWIST: One statement is FALSE.\n\r\n1. Har was not the oldest, nor was he the shortest or tallest.\r\n2. Winn was taller than Edvo, who was taller but younger than Frer.\r\n3. Tolo, who was not the second oldest, was older than Har, and shorter than Frer.\r\n4. The one who was 13 hands tall was the oldest.\r\n5. Har was taller and older than Winn and Tolo.\r\n6. The fourth oldest was taller than Tolo, but shorter than Edvo, who was older than Winn.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEdvo, 15 hands, 130 years\r\nFrer, 13 hands, 140 years\r\nHar, 14 hands, 110 years\r\nTolo, 12 hands, 120 years\r\nWinn, 16 hands, 100 years\n\r\nWhen going through all the statements, it is impossible that both 3 and 5 be true. (3 says Tolo is older than Har while 5 says Har is older than Tolo.) 2 gives the order of height as Winn, Edvo, and Frer. If 5 is true, then Har must be the tallest, but this contradicts 1, therefore 5 is false. \n\r\nFrom 1, 2 and 3 it can be seen that the order of height is Winn, Edvo, Frer, and Tolo - with Har somewhere in between but not the shortest or tallest. Therefore Winn is 16 hands, and Tolo is 12. \n\r\nSince Har is not the oldest, he is not 13 hands, which makes Frer 13 hands and the oldest.\n\r\nFrom 3 and 6, Tolo is not the 2nd or 4th oldest and is not the youngest. Therefore he becomes 120 years. Also from 6, Edvo is not the 4th oldest or youngest. Therefore he is 130 years.\n\r\nSince the 4th oldest is shorter than Edvo, Har must be it at 110 years. And Winn is the youngest. Since the 4th oldest was shorter than Edvo, Har is 14 hands and Edvo is 15 hands.\n<|im_start|>answer\nEdvo, 15 hands, 130 years\r\nFrer, 13 hands, 140 years\r\nHar, 14 hands, 110 years\r\nTolo, 12 hands, 120 years\r\nWinn, 16 hands, 100 years\n\r\nWhen going through all the statements, it is impossible that both 3 and 5 be true. (3 says Tolo is older than Har while 5 says Har is older than Tolo.) 2 gives the order of height as Winn, Edvo, and Frer. If 5 is true, then Har must be the tallest, but this contradicts 1, therefore 5 is false. \n\r\nFrom 1, 2 and 3 it can be seen that the order of height is Winn, Edvo, Frer, and Tolo - with Har somewhere in between but not the shortest or tallest. Therefore Winn is 16 hands, and Tolo is 12. \n\r\nSince Har is not the oldest, he is not 13 hands, which makes Frer 13 hands and the oldest.\n\r\nFrom 3 and 6, Tolo is not the 2nd or 4th oldest and is not the youngest. Therefore he becomes 120 years. Also from 6, Edvo is not the 4th oldest or youngest. Therefore he is 130 years.\n\r\nSince the 4th oldest is shorter than Edvo, Har must be it at 110 years. And Winn is the youngest. Since the 4th oldest was shorter than Edvo, Har is 14 hands and Edvo is 15 hands.\n<|im_end|>" }, { "id": "#22613", "title": "The Fly and the Flea", "fun": 2.6, "difficulty": 1.02, "author": "filetmerlot", "desc": "A fly and a flea are trapped in a flue\r\nsaid the fly to the flea 'to flee is some number times 3'\r\nSaid the flea to the fly 'but 3 squared is too high'\r\nresponds the fly 'but it'll also do to have some number times 2'\r\n'Agreed' said the flea 'Then so it shall be'\r\nSo now it is up to you. \r\nHow far must the fly and the flea fly to flee the flue?", "hint": "No hint available.", "answer": "6 units (pick your own)\n\r\n3 squared is too high, so we know it is less than nine. Since 3 and 2 are factors there is only one number less than 9 with that property.", "category": "Math", "date": "05/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fly and a flea are trapped in a flue\r\nsaid the fly to the flea 'to flee is some number times 3'\r\nSaid the flea to the fly 'but 3 squared is too high'\r\nresponds the fly 'but it'll also do to have some number times 2'\r\n'Agreed' said the flea 'Then so it shall be'\r\nSo now it is up to you. \r\nHow far must the fly and the flea fly to flee the flue?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6 units (pick your own)\n\r\n3 squared is too high, so we know it is less than nine. Since 3 and 2 are factors there is only one number less than 9 with that property.\n<|im_start|>answer\n6 units (pick your own)\n\r\n3 squared is too high, so we know it is less than nine. Since 3 and 2 are factors there is only one number less than 9 with that property.\n<|im_end|>" }, { "id": "#47123", "title": "The Number Sentence", "fun": 2.6, "difficulty": 2.33, "author": "smartlilbit", "desc": "Write a number in each blank to make the following statement true:\n\r\nIn this sentence, the number of occurrences of 1 is____, of 2 is___, of 3 is___, of 4 is___, of 5 is___.", "hint": "The sum of all the answers equals 10.", "answer": "of 1 is 3, of 2 is 2, of 3 is 3, of 4 is 1, of 5 is 1.", "category": "Logic", "date": "05/31/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWrite a number in each blank to make the following statement true:\n\r\nIn this sentence, the number of occurrences of 1 is____, of 2 is___, of 3 is___, of 4 is___, of 5 is___.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nof 1 is 3, of 2 is 2, of 3 is 3, of 4 is 1, of 5 is 1.\n<|im_start|>answer\nof 1 is 3, of 2 is 2, of 3 is 3, of 4 is 1, of 5 is 1.\n<|im_end|>" }, { "id": "#25744", "title": "All Blacks", "fun": 2.6, "difficulty": 2.63, "author": "Gizzer", "desc": "The rugby season may be over, but the wheeling and dealing is just reaching a high point. Recently, each of six teams acquired a different, valuable, player to beef up its roster. Each player specializes in a different position (one is a prop), and, coincidentally enough, each was acquired from a different one of the other teams. Each felt a pang of regret at leaving his former team, but is eagerly awaiting the first scrum of the season with his new mates. From the following clues, can you match each player with his position, new team and former team? \n\r\n1. The one from the Mountaineers didn't sign with the Scarlets. \n\r\n2. The Mountaineers, Troopers and Typhoons signed the fullback, the player who left the Downers and Cowan, in some order. \n\r\n3. The Downers, Scarlets and Jets lost Tuitupou, the center and the player who signed with the Typhoons, in some order. \n\r\n4. Jeeper and the center signed with the Downers and the Typhoons, in some order. \n\r\n5. Rokocoko and McGuyver left the Mountaineers and the Troopers, in some order. \n\r\n6. The player who left the Troopers signed with the Jets. \n\r\n7. The hooker cleared his stuff out of his former Downer locker last week. \n\r\n8. Rokocoko isn't the fullback. \n\r\n9. The wing's wife was delighted that her husband signed with the Scarlets. \n\r\n10. Grippley didn't sign with the Scarlets. \n\r\n11. The fly half, who isn't going to the Mountaineers, isn't Cowan.", "hint": "No hint available.", "answer": "The player who left the Troopers signed with the Jets (clue 6). This player is either Rokocoko or McGuyver (clue 5); the other left the Mountaineers. \n\r\nA third player is the hooker, who left the Downers (clue 7). \n\r\nThe wing signed with the Scarlets. Since the player from the Mountaineers didn't sign with the Scarlets (clue 1), this is a fourth player. \n\r\nCowan is neither the hooker who left the Downers nor the wing who signed with the Scarlets (clue 2), so he is a fifth player. \n\r\nCowan is not the fullback (clue 2) or the fly half (clue 11). \n\r\nThe center cannot have signed with the Typhoons (clue 3), so the center must have signed with the Downers while Jeeper signed with the Typhoons (clue 4). This means that Cowan cannot be the center (clue 2), and must therefore be the prop. \n\r\nThe center didn't leave the Troopers or the Mountaineers (clue 3), so he is the 6th player, leaving Rokocoko and McGuyver as the fullback and the fly half, in some order. \n\r\nAt this point we know the following information about the 6 players: \n\r\n1) Rokocoko/McGuyver, fullback/fly half, left the Troopers for the Jets \r\n2) Rokocoko/McGuyver, fullback/fly half, left the Mountaineers \r\n3) the hooker, left the Downers \r\n4) the wing, signed with the Scarlets \r\n5) Cowan, the prop \r\n6) the center \n\r\nSince Jeeper signed with the Typhoons, he is one of the three people listed in clue 2: he obviously isn't Cowan, so he is either the fullback or the player who left the Downers, ie the hooker (clue 7). We've established that Jeeper cannot be the fullback, so he is the hooker. \n\r\nGrippley didn't sign with the Scarlets (clue 10), so he is the center. This leaves Tuitupou as the wing. \n\r\nAt this point we have the following information: \n\r\n1) Rokocoko/McGuyver, fullback/fly half, left the Troopers for the Jets \r\n2) Rokocoko/McGuyver, fullback/fly half, left the Mountaineers \r\n3) Jeeper, the hooker, left the Downers for the Typhoons \r\n4) Tuitupou, the wing, signed with the Scarlets \r\n5) Cowan, the prop \r\n6) Grippley, the center, signed with the Downers \n\n\r\nThe player that left the Mountaineers couldn't have also signed with the Mountaineers, so Cowan signed with the Mountaineers, and the player that left the Mountaineers signed with the Troopers. \n\r\nThe fullback didn't sign with the Jets (clue 2), so the fullback signed with the Troopers and the fly half signed with the Jets. \n\r\nRokocoko isn't the fullback (clue 8), so McGuyver is the fullback and Rokocoko is the fly half. \n\r\nAt this point we have the following information: \n\r\n1) Rokocoko, the fly half, left the Troopers for the Jets. \r\n2) McGuyver, the fullback, left the Mountaineers for the Troopers. \r\n3) Jeeper, the hooker, left the Downers for the Typhoons. \r\n4) Tuitupou, the wing, signed with the Scarlets. \r\n5) Cowan, the prop, signed with the Mountaineers. \r\n6) Grippley, the center, signed with the Downers. \n\n\r\nTuitupou left the Downers, the Scarlets or the Jets (clue 3). We've established that Jeeper left the Downers, and since Tuitupou signed with the Scarlets, he must have left the Jets. \n\r\nThe Scarlets, therefore, lost the center (clue 3). \n\r\nBy process of elimination, Cowan left the Typhoons. \n\r\nSo these are the 6 players: \n\r\n1) Rokocoko, the fly half, left the Troopers for the Jets. \r\n2) McGuyver, the fullback, left the Mountaineers for the Troopers. \r\n3) Jeeper, the hooker, left the Downers for the Typhoons. \r\n4) Tuitupou, the wing, left the Jets for the Scarlets. \r\n5) Cowan, the prop, left the Typhoons for the Mountaineers. \r\n6) Grippley, the center, left the Scarlets for the Downers.", "category": "Logic", "date": "09/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe rugby season may be over, but the wheeling and dealing is just reaching a high point. Recently, each of six teams acquired a different, valuable, player to beef up its roster. Each player specializes in a different position (one is a prop), and, coincidentally enough, each was acquired from a different one of the other teams. Each felt a pang of regret at leaving his former team, but is eagerly awaiting the first scrum of the season with his new mates. From the following clues, can you match each player with his position, new team and former team? \n\r\n1. The one from the Mountaineers didn't sign with the Scarlets. \n\r\n2. The Mountaineers, Troopers and Typhoons signed the fullback, the player who left the Downers and Cowan, in some order. \n\r\n3. The Downers, Scarlets and Jets lost Tuitupou, the center and the player who signed with the Typhoons, in some order. \n\r\n4. Jeeper and the center signed with the Downers and the Typhoons, in some order. \n\r\n5. Rokocoko and McGuyver left the Mountaineers and the Troopers, in some order. \n\r\n6. The player who left the Troopers signed with the Jets. \n\r\n7. The hooker cleared his stuff out of his former Downer locker last week. \n\r\n8. Rokocoko isn't the fullback. \n\r\n9. The wing's wife was delighted that her husband signed with the Scarlets. \n\r\n10. Grippley didn't sign with the Scarlets. \n\r\n11. The fly half, who isn't going to the Mountaineers, isn't Cowan.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe player who left the Troopers signed with the Jets (clue 6). This player is either Rokocoko or McGuyver (clue 5); the other left the Mountaineers. \n\r\nA third player is the hooker, who left the Downers (clue 7). \n\r\nThe wing signed with the Scarlets. Since the player from the Mountaineers didn't sign with the Scarlets (clue 1), this is a fourth player. \n\r\nCowan is neither the hooker who left the Downers nor the wing who signed with the Scarlets (clue 2), so he is a fifth player. \n\r\nCowan is not the fullback (clue 2) or the fly half (clue 11). \n\r\nThe center cannot have signed with the Typhoons (clue 3), so the center must have signed with the Downers while Jeeper signed with the Typhoons (clue 4). This means that Cowan cannot be the center (clue 2), and must therefore be the prop. \n\r\nThe center didn't leave the Troopers or the Mountaineers (clue 3), so he is the 6th player, leaving Rokocoko and McGuyver as the fullback and the fly half, in some order. \n\r\nAt this point we know the following information about the 6 players: \n\r\n1) Rokocoko/McGuyver, fullback/fly half, left the Troopers for the Jets \r\n2) Rokocoko/McGuyver, fullback/fly half, left the Mountaineers \r\n3) the hooker, left the Downers \r\n4) the wing, signed with the Scarlets \r\n5) Cowan, the prop \r\n6) the center \n\r\nSince Jeeper signed with the Typhoons, he is one of the three people listed in clue 2: he obviously isn't Cowan, so he is either the fullback or the player who left the Downers, ie the hooker (clue 7). We've established that Jeeper cannot be the fullback, so he is the hooker. \n\r\nGrippley didn't sign with the Scarlets (clue 10), so he is the center. This leaves Tuitupou as the wing. \n\r\nAt this point we have the following information: \n\r\n1) Rokocoko/McGuyver, fullback/fly half, left the Troopers for the Jets \r\n2) Rokocoko/McGuyver, fullback/fly half, left the Mountaineers \r\n3) Jeeper, the hooker, left the Downers for the Typhoons \r\n4) Tuitupou, the wing, signed with the Scarlets \r\n5) Cowan, the prop \r\n6) Grippley, the center, signed with the Downers \n\n\r\nThe player that left the Mountaineers couldn't have also signed with the Mountaineers, so Cowan signed with the Mountaineers, and the player that left the Mountaineers signed with the Troopers. \n\r\nThe fullback didn't sign with the Jets (clue 2), so the fullback signed with the Troopers and the fly half signed with the Jets. \n\r\nRokocoko isn't the fullback (clue 8), so McGuyver is the fullback and Rokocoko is the fly half. \n\r\nAt this point we have the following information: \n\r\n1) Rokocoko, the fly half, left the Troopers for the Jets. \r\n2) McGuyver, the fullback, left the Mountaineers for the Troopers. \r\n3) Jeeper, the hooker, left the Downers for the Typhoons. \r\n4) Tuitupou, the wing, signed with the Scarlets. \r\n5) Cowan, the prop, signed with the Mountaineers. \r\n6) Grippley, the center, signed with the Downers. \n\n\r\nTuitupou left the Downers, the Scarlets or the Jets (clue 3). We've established that Jeeper left the Downers, and since Tuitupou signed with the Scarlets, he must have left the Jets. \n\r\nThe Scarlets, therefore, lost the center (clue 3). \n\r\nBy process of elimination, Cowan left the Typhoons. \n\r\nSo these are the 6 players: \n\r\n1) Rokocoko, the fly half, left the Troopers for the Jets. \r\n2) McGuyver, the fullback, left the Mountaineers for the Troopers. \r\n3) Jeeper, the hooker, left the Downers for the Typhoons. \r\n4) Tuitupou, the wing, left the Jets for the Scarlets. \r\n5) Cowan, the prop, left the Typhoons for the Mountaineers. \r\n6) Grippley, the center, left the Scarlets for the Downers.\n<|im_start|>answer\nThe player who left the Troopers signed with the Jets (clue 6). This player is either Rokocoko or McGuyver (clue 5); the other left the Mountaineers. \n\r\nA third player is the hooker, who left the Downers (clue 7). \n\r\nThe wing signed with the Scarlets. Since the player from the Mountaineers didn't sign with the Scarlets (clue 1), this is a fourth player. \n\r\nCowan is neither the hooker who left the Downers nor the wing who signed with the Scarlets (clue 2), so he is a fifth player. \n\r\nCowan is not the fullback (clue 2) or the fly half (clue 11). \n\r\nThe center cannot have signed with the Typhoons (clue 3), so the center must have signed with the Downers while Jeeper signed with the Typhoons (clue 4). This means that Cowan cannot be the center (clue 2), and must therefore be the prop. \n\r\nThe center didn't leave the Troopers or the Mountaineers (clue 3), so he is the 6th player, leaving Rokocoko and McGuyver as the fullback and the fly half, in some order. \n\r\nAt this point we know the following information about the 6 players: \n\r\n1) Rokocoko/McGuyver, fullback/fly half, left the Troopers for the Jets \r\n2) Rokocoko/McGuyver, fullback/fly half, left the Mountaineers \r\n3) the hooker, left the Downers \r\n4) the wing, signed with the Scarlets \r\n5) Cowan, the prop \r\n6) the center \n\r\nSince Jeeper signed with the Typhoons, he is one of the three people listed in clue 2: he obviously isn't Cowan, so he is either the fullback or the player who left the Downers, ie the hooker (clue 7). We've established that Jeeper cannot be the fullback, so he is the hooker. \n\r\nGrippley didn't sign with the Scarlets (clue 10), so he is the center. This leaves Tuitupou as the wing. \n\r\nAt this point we have the following information: \n\r\n1) Rokocoko/McGuyver, fullback/fly half, left the Troopers for the Jets \r\n2) Rokocoko/McGuyver, fullback/fly half, left the Mountaineers \r\n3) Jeeper, the hooker, left the Downers for the Typhoons \r\n4) Tuitupou, the wing, signed with the Scarlets \r\n5) Cowan, the prop \r\n6) Grippley, the center, signed with the Downers \n\n\r\nThe player that left the Mountaineers couldn't have also signed with the Mountaineers, so Cowan signed with the Mountaineers, and the player that left the Mountaineers signed with the Troopers. \n\r\nThe fullback didn't sign with the Jets (clue 2), so the fullback signed with the Troopers and the fly half signed with the Jets. \n\r\nRokocoko isn't the fullback (clue 8), so McGuyver is the fullback and Rokocoko is the fly half. \n\r\nAt this point we have the following information: \n\r\n1) Rokocoko, the fly half, left the Troopers for the Jets. \r\n2) McGuyver, the fullback, left the Mountaineers for the Troopers. \r\n3) Jeeper, the hooker, left the Downers for the Typhoons. \r\n4) Tuitupou, the wing, signed with the Scarlets. \r\n5) Cowan, the prop, signed with the Mountaineers. \r\n6) Grippley, the center, signed with the Downers. \n\n\r\nTuitupou left the Downers, the Scarlets or the Jets (clue 3). We've established that Jeeper left the Downers, and since Tuitupou signed with the Scarlets, he must have left the Jets. \n\r\nThe Scarlets, therefore, lost the center (clue 3). \n\r\nBy process of elimination, Cowan left the Typhoons. \n\r\nSo these are the 6 players: \n\r\n1) Rokocoko, the fly half, left the Troopers for the Jets. \r\n2) McGuyver, the fullback, left the Mountaineers for the Troopers. \r\n3) Jeeper, the hooker, left the Downers for the Typhoons. \r\n4) Tuitupou, the wing, left the Jets for the Scarlets. \r\n5) Cowan, the prop, left the Typhoons for the Mountaineers. \r\n6) Grippley, the center, left the Scarlets for the Downers.\n<|im_end|>" }, { "id": "#9156", "title": "Entrance Exam", "fun": 2.6, "difficulty": 2.25, "author": "doggyxp", "desc": "Below is the curious multiple-choice entrance exam into the exclusive Puzzle Master's puzzle club.\n\r\nQ1. Which is the first question where c) is the correct answer \n\r\na) Q3\r\nb) Q4\r\nc) Q1\r\nd) Q2 \n\r\nQ2. Which is the first question where a) is the correct answer \n\r\na) Q4\r\nb) Q2\r\nc) Q3\r\nd) Q1 \n\r\nQ3. Which is the first question where d) is the correct answer \n\r\na) Q1\r\nb) Q2\r\nc) Q4\r\nd) Q3 \n\r\nQ4. Which is the first question where b) is the correct answer \n\r\na) Q2\r\nb) Q4\r\nc) Q3\r\nd) Q1", "hint": "No hint available.", "answer": "1. d)\r\n2. c)\r\n3. a)\r\n4. b)", "category": "Logic", "date": "12/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBelow is the curious multiple-choice entrance exam into the exclusive Puzzle Master's puzzle club.\n\r\nQ1. Which is the first question where c) is the correct answer \n\r\na) Q3\r\nb) Q4\r\nc) Q1\r\nd) Q2 \n\r\nQ2. Which is the first question where a) is the correct answer \n\r\na) Q4\r\nb) Q2\r\nc) Q3\r\nd) Q1 \n\r\nQ3. Which is the first question where d) is the correct answer \n\r\na) Q1\r\nb) Q2\r\nc) Q4\r\nd) Q3 \n\r\nQ4. Which is the first question where b) is the correct answer \n\r\na) Q2\r\nb) Q4\r\nc) Q3\r\nd) Q1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. d)\r\n2. c)\r\n3. a)\r\n4. b)\n<|im_start|>answer\n1. d)\r\n2. c)\r\n3. a)\r\n4. b)\n<|im_end|>" }, { "id": "#4899", "title": "The Queen's Coin", "fun": 2.6, "difficulty": 2.0, "author": "mad-ade", "desc": "Inspector Mad Ade of Scotland's backyard was a collector of rare and unusual coins. He was visiting a nearby market when he came upon a stall selling collectible coins being run by a well known female villain called May D'upname. Inspector Mad Ade browsed the contents of the stall, looking at several interesting coins celebrating \"100 years of kebabs\". May D'upname saw Inspector Mad Ade's interest and decided to offer him a special coin she had been saving.\r\n\"It's a special one of a kind coin,\" she told Mad Ade, \"It was minted to celebrate the birth of Queen Elizabeth the second.\" Inspector Mad Ade viewed the coin and read the inscription on the reverse side of the coin.\r\n\"In celebration of the birth of princess Elizabeth, daughter to the Duke and Duchess of York, heir to the throne of the United Kingdom and the colonies of the Empire.\" it read.\r\n\"Where did you get this?\" asked Inspector Mad Ade.\r\n\"It was given to my Grandmother in 1926, the year of the queen's birth. It's 100% genuine, honest, I swear on it.\" She replied.\r\n\"Well, in that case you are under arrest for forgery.\" Inspector Mad Ade announced.\n\r\nHow did Mad Ade know the coin was a fake?", "hint": "No hint available.", "answer": "When the Queen was born on the 21st of April 1926, no one could have possibly known she would have been the heir to the throne, because her father wasn't the king until his brother King Edward the eighth abdicated some 10 years later.", "category": "Logic", "date": "06/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nInspector Mad Ade of Scotland's backyard was a collector of rare and unusual coins. He was visiting a nearby market when he came upon a stall selling collectible coins being run by a well known female villain called May D'upname. Inspector Mad Ade browsed the contents of the stall, looking at several interesting coins celebrating \"100 years of kebabs\". May D'upname saw Inspector Mad Ade's interest and decided to offer him a special coin she had been saving.\r\n\"It's a special one of a kind coin,\" she told Mad Ade, \"It was minted to celebrate the birth of Queen Elizabeth the second.\" Inspector Mad Ade viewed the coin and read the inscription on the reverse side of the coin.\r\n\"In celebration of the birth of princess Elizabeth, daughter to the Duke and Duchess of York, heir to the throne of the United Kingdom and the colonies of the Empire.\" it read.\r\n\"Where did you get this?\" asked Inspector Mad Ade.\r\n\"It was given to my Grandmother in 1926, the year of the queen's birth. It's 100% genuine, honest, I swear on it.\" She replied.\r\n\"Well, in that case you are under arrest for forgery.\" Inspector Mad Ade announced.\n\r\nHow did Mad Ade know the coin was a fake?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen the Queen was born on the 21st of April 1926, no one could have possibly known she would have been the heir to the throne, because her father wasn't the king until his brother King Edward the eighth abdicated some 10 years later.\n<|im_start|>answer\nWhen the Queen was born on the 21st of April 1926, no one could have possibly known she would have been the heir to the throne, because her father wasn't the king until his brother King Edward the eighth abdicated some 10 years later.\n<|im_end|>" }, { "id": "#29409", "title": "61, 691, 163", "fun": 2.6, "difficulty": 2.89, "author": "MadDog72", "desc": "What number comes next in the sequence:\r\n61, 691, 163, 487, 4201, ?", "hint": "Reverse the digits of the numbers.", "answer": "9631. The sequence consists of the prime numbers which, when their digits are reversed, are perfect squares.", "category": "Math", "date": "03/29/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number comes next in the sequence:\r\n61, 691, 163, 487, 4201, ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9631. The sequence consists of the prime numbers which, when their digits are reversed, are perfect squares.\n<|im_start|>answer\n9631. The sequence consists of the prime numbers which, when their digits are reversed, are perfect squares.\n<|im_end|>" }, { "id": "#42045", "title": "Which Box Has the Gold?", "fun": 2.6, "difficulty": 1.07, "author": "Carlos16", "desc": "There are four boxes lined up on a desk from left to right. Which box is the gold in if the two truthful boxes are not next to each other, and the two lying boxes are not next to each other?\n\r\nBox A: The gold is not in this box\r\nBox B: The gold is in this box\r\nBox C: The gold is in this box\r\nBox D: The gold is in this box", "hint": "No hint available.", "answer": "If l is lie, and t is truth, the possible patterns for the boxes are: ltlt, and tltl. The gold is in box C because if it wasn't, then box C would be lying. When ever a box is lying, any boxes touching that box would have to be telling the truth. If box B and D were telling the truth, that would be impossible. Therefore, box C is truthful, boxes B & D are lying, and box A is truthful as well.\n\r\nAnswer: Box C", "category": "Logic", "date": "05/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four boxes lined up on a desk from left to right. Which box is the gold in if the two truthful boxes are not next to each other, and the two lying boxes are not next to each other?\n\r\nBox A: The gold is not in this box\r\nBox B: The gold is in this box\r\nBox C: The gold is in this box\r\nBox D: The gold is in this box\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf l is lie, and t is truth, the possible patterns for the boxes are: ltlt, and tltl. The gold is in box C because if it wasn't, then box C would be lying. When ever a box is lying, any boxes touching that box would have to be telling the truth. If box B and D were telling the truth, that would be impossible. Therefore, box C is truthful, boxes B & D are lying, and box A is truthful as well.\n\r\nAnswer: Box C\n<|im_start|>answer\nIf l is lie, and t is truth, the possible patterns for the boxes are: ltlt, and tltl. The gold is in box C because if it wasn't, then box C would be lying. When ever a box is lying, any boxes touching that box would have to be telling the truth. If box B and D were telling the truth, that would be impossible. Therefore, box C is truthful, boxes B & D are lying, and box A is truthful as well.\n\r\nAnswer: Box C\n<|im_end|>" }, { "id": "#32875", "title": "Dinner Time 2", "fun": 2.6, "difficulty": 1.82, "author": "redbunny016", "desc": "Kelly and Felipe had reservations for dinner at Seoul Food for 7:00PM. However, the restaurant mixed up their names and didn't get them seated on time. By analyzing the clues below, you should be able to figure out what time they finally got a table.\n\r\nClues:\r\n1. They sat down within two hours of their reservations.\n\r\n2. All three digits in the time that they were seated are different.\n\r\n3. The second two digits in the time are equal to the first digit plus four.", "hint": "The final answer will also complete this riddle: \n\r\nWhat did Scotty Sweettooth do when he saw the dessert tray loaded with 13 pies?", "answer": "8:12 (ate twelve)", "category": "Logic", "date": "09/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKelly and Felipe had reservations for dinner at Seoul Food for 7:00PM. However, the restaurant mixed up their names and didn't get them seated on time. By analyzing the clues below, you should be able to figure out what time they finally got a table.\n\r\nClues:\r\n1. They sat down within two hours of their reservations.\n\r\n2. All three digits in the time that they were seated are different.\n\r\n3. The second two digits in the time are equal to the first digit plus four.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8:12 (ate twelve)\n<|im_start|>answer\n8:12 (ate twelve)\n<|im_end|>" }, { "id": "#38401", "title": "A Number", "fun": 2.6, "difficulty": 2.05, "author": "maxvu", "desc": "There are 20 players in Maxvu's sports team, numbering from 1 to 20. What is Maxvu's number? Of the choices below, only one is correct.\n\r\nA. an odd number\r\nB. an even number \r\nC. a prime number\r\nD. a composite number", "hint": "No hint available.", "answer": "It's easily seen that one of A and B must be correct, as a number is either odd or even. This means that neither C nor D is correct. If a number is neither prime nor composite, it can only be 1, so choice A is correct.", "category": "Logic", "date": "09/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 20 players in Maxvu's sports team, numbering from 1 to 20. What is Maxvu's number? Of the choices below, only one is correct.\n\r\nA. an odd number\r\nB. an even number \r\nC. a prime number\r\nD. a composite number\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's easily seen that one of A and B must be correct, as a number is either odd or even. This means that neither C nor D is correct. If a number is neither prime nor composite, it can only be 1, so choice A is correct.\n<|im_start|>answer\nIt's easily seen that one of A and B must be correct, as a number is either odd or even. This means that neither C nor D is correct. If a number is neither prime nor composite, it can only be 1, so choice A is correct.\n<|im_end|>" }, { "id": "#10176", "title": "Newspaper Pages", "fun": 2.6, "difficulty": 1.6300000000000001, "author": "dumbell", "desc": "My newspaper has a special 16-page feature in the middle today. Unfortunately my copy is incomplete. The third page of the supplement (page 15 of the newspaper) is missing. What other pages must also be missing?", "hint": "No hint available.", "answer": "Pages 16, 25 and 26. \n\r\nPage 16 must be missing as it is on the back of page 15. The supplement must be numbered from 13 to 28. Since the second sheet from the start of the supplement is missing, then it must be connected to the second sheet from the end of the supplement. This sheet contains pages 25 and 26.", "category": "Logic", "date": "02/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy newspaper has a special 16-page feature in the middle today. Unfortunately my copy is incomplete. The third page of the supplement (page 15 of the newspaper) is missing. What other pages must also be missing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPages 16, 25 and 26. \n\r\nPage 16 must be missing as it is on the back of page 15. The supplement must be numbered from 13 to 28. Since the second sheet from the start of the supplement is missing, then it must be connected to the second sheet from the end of the supplement. This sheet contains pages 25 and 26.\n<|im_start|>answer\nPages 16, 25 and 26. \n\r\nPage 16 must be missing as it is on the back of page 15. The supplement must be numbered from 13 to 28. Since the second sheet from the start of the supplement is missing, then it must be connected to the second sheet from the end of the supplement. This sheet contains pages 25 and 26.\n<|im_end|>" }, { "id": "#50982", "title": "Waring It Well", "fun": 2.6, "difficulty": 2.47, "author": "Snowdog", "desc": "All natural numbers can be written as the sum of cubes of other natural numbers.\n\r\nFor example:\r\n37 = 27 + 8 + 1 + 1 = 3^3 + 2^3 + 1^3 + 1^3\n\r\nAll but two natural numbers can be written as the sum of eight or fewer cubes.\n\r\nTwo numbers require the sum of at least nine cubes.\n\r\na) One such number is 239. Write 239 as the sum of nine cubes.\r\nb) What is the other natural number that requires a sum of at least nine cubes?", "hint": "a) Don't use 4^3 = 64.\r\nb) It is fairly small. Start at 1 and test each number.", "answer": "a) 239 = 125 + 27 + 27 + 27 + 8 + 8 + 8 + 8 + 1\r\nb) 23 = 8 + 8 + 1 + 1 + 1 + 1 + 1 + 1 + 1\n\r\nIn 1770, Edward Waring asked if for every number k, there is a number s such that every natural number can be represented as the sum of at most s powers of k.\n\r\nIt was not until 1909 that a proof of Waring's problem was developed, the Hilbert-Waring Theorem.", "category": "Math", "date": "01/24/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAll natural numbers can be written as the sum of cubes of other natural numbers.\n\r\nFor example:\r\n37 = 27 + 8 + 1 + 1 = 3^3 + 2^3 + 1^3 + 1^3\n\r\nAll but two natural numbers can be written as the sum of eight or fewer cubes.\n\r\nTwo numbers require the sum of at least nine cubes.\n\r\na) One such number is 239. Write 239 as the sum of nine cubes.\r\nb) What is the other natural number that requires a sum of at least nine cubes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) 239 = 125 + 27 + 27 + 27 + 8 + 8 + 8 + 8 + 1\r\nb) 23 = 8 + 8 + 1 + 1 + 1 + 1 + 1 + 1 + 1\n\r\nIn 1770, Edward Waring asked if for every number k, there is a number s such that every natural number can be represented as the sum of at most s powers of k.\n\r\nIt was not until 1909 that a proof of Waring's problem was developed, the Hilbert-Waring Theorem.\n<|im_start|>answer\na) 239 = 125 + 27 + 27 + 27 + 8 + 8 + 8 + 8 + 1\r\nb) 23 = 8 + 8 + 1 + 1 + 1 + 1 + 1 + 1 + 1\n\r\nIn 1770, Edward Waring asked if for every number k, there is a number s such that every natural number can be represented as the sum of at most s powers of k.\n\r\nIt was not until 1909 that a proof of Waring's problem was developed, the Hilbert-Waring Theorem.\n<|im_end|>" }, { "id": "#4184", "title": "The 3 Prophets", "fun": 2.59, "difficulty": 1.26, "author": "einat16", "desc": "Once upon a time there were 3 prophets:\n\r\nOne always tells the truth\r\nOne always lies\r\nAnd one sometimes lies and sometimes tells the truth. \n\r\nIn order to find out who is who, you ask the three if the middle one is the truthteller, liar or \"sometimes\". The first says \"the middle one always lies\". The middle one said \"I sometimes lie and sometimes tell the truth\". The third one says \"he always tells the truth\". You know for a fact that this time the one that sometimes lies and sometimes tells the truth is lying. Which one of them is which?", "hint": "No hint available.", "answer": "The middle one said that he is the \"sometimes\" prophet. If this were true, he could only be the truth teller. since we know that the \"sometimes\" is lying - this situation is impossible, since if he were the truthteller he would have said that he were the truthteller. From this we conclude that the middle one is the lying prophet, which means that whoever said that he was the lying prophet is the truthteller. Since the first prophet said that, he is the truthteller, and the third is the \"sometimes\".", "category": "Logic", "date": "05/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce upon a time there were 3 prophets:\n\r\nOne always tells the truth\r\nOne always lies\r\nAnd one sometimes lies and sometimes tells the truth. \n\r\nIn order to find out who is who, you ask the three if the middle one is the truthteller, liar or \"sometimes\". The first says \"the middle one always lies\". The middle one said \"I sometimes lie and sometimes tell the truth\". The third one says \"he always tells the truth\". You know for a fact that this time the one that sometimes lies and sometimes tells the truth is lying. Which one of them is which?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe middle one said that he is the \"sometimes\" prophet. If this were true, he could only be the truth teller. since we know that the \"sometimes\" is lying - this situation is impossible, since if he were the truthteller he would have said that he were the truthteller. From this we conclude that the middle one is the lying prophet, which means that whoever said that he was the lying prophet is the truthteller. Since the first prophet said that, he is the truthteller, and the third is the \"sometimes\".\n<|im_start|>answer\nThe middle one said that he is the \"sometimes\" prophet. If this were true, he could only be the truth teller. since we know that the \"sometimes\" is lying - this situation is impossible, since if he were the truthteller he would have said that he were the truthteller. From this we conclude that the middle one is the lying prophet, which means that whoever said that he was the lying prophet is the truthteller. Since the first prophet said that, he is the truthteller, and the third is the \"sometimes\".\n<|im_end|>" }, { "id": "#4748", "title": "Shady Ladies", "fun": 2.59, "difficulty": 0.98, "author": "bobbrt", "desc": "Miss White, Miss Black, and Miss Gray are out for a stroll together. One is dressed in white, one in black, and one in gray. \"Isn't it odd,\" says Miss Gray, \"that our dresses match our last names, but no one of us is wearing a dress that matches her own name?\"\n\r\n\"So what?\" said the lady in black.\n\r\nGive the color of each lady's dress.", "hint": "No hint available.", "answer": "Miss Gray's dress cannot match her name, so it must be white or black. Since the lady in black responded to Miss Gray's comment, Miss Gray must be wearing white. This leaves Miss Black wearing gray (since the only choices left for her are black and gray) and therefore Miss White is wearing black.", "category": "Logic", "date": "06/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMiss White, Miss Black, and Miss Gray are out for a stroll together. One is dressed in white, one in black, and one in gray. \"Isn't it odd,\" says Miss Gray, \"that our dresses match our last names, but no one of us is wearing a dress that matches her own name?\"\n\r\n\"So what?\" said the lady in black.\n\r\nGive the color of each lady's dress.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMiss Gray's dress cannot match her name, so it must be white or black. Since the lady in black responded to Miss Gray's comment, Miss Gray must be wearing white. This leaves Miss Black wearing gray (since the only choices left for her are black and gray) and therefore Miss White is wearing black.\n<|im_start|>answer\nMiss Gray's dress cannot match her name, so it must be white or black. Since the lady in black responded to Miss Gray's comment, Miss Gray must be wearing white. This leaves Miss Black wearing gray (since the only choices left for her are black and gray) and therefore Miss White is wearing black.\n<|im_end|>" }, { "id": "#11181", "title": "Lots of Kids", "fun": 2.59, "difficulty": 1.08, "author": "Jake101", "desc": "Once there were 9 children, all of which were in the same family. They were all born 18 months apart. The oldest one (George) was 5 times older than the youngest one (Michael). \n\r\nHow old was Michael?", "hint": "No hint available.", "answer": "3 yrs. old. \r\nIf each child was born 18 months apart, then there has to be a 12 year gap between oldest and youngest. \r\nTherefore George is 15 and Michael 3. \r\nThis is the only 12 year gap that has a difference in ages of 5 times.", "category": "Math", "date": "03/15/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce there were 9 children, all of which were in the same family. They were all born 18 months apart. The oldest one (George) was 5 times older than the youngest one (Michael). \n\r\nHow old was Michael?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 yrs. old. \r\nIf each child was born 18 months apart, then there has to be a 12 year gap between oldest and youngest. \r\nTherefore George is 15 and Michael 3. \r\nThis is the only 12 year gap that has a difference in ages of 5 times.\n<|im_start|>answer\n3 yrs. old. \r\nIf each child was born 18 months apart, then there has to be a 12 year gap between oldest and youngest. \r\nTherefore George is 15 and Michael 3. \r\nThis is the only 12 year gap that has a difference in ages of 5 times.\n<|im_end|>" }, { "id": "#2796", "title": "Largest 2 Digit Number", "fun": 2.59, "difficulty": 1.83, "author": "lil_thugsta", "desc": "What is the largest possible number you can write using only 2 digits?", "hint": "No hint available.", "answer": "9 to the power of 9", "category": "Math", "date": "03/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the largest possible number you can write using only 2 digits?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9 to the power of 9\n<|im_start|>answer\n9 to the power of 9\n<|im_end|>" }, { "id": "#48626", "title": "The Four-digit Number ABCD", "fun": 2.59, "difficulty": 2.45, "author": "shenqiang", "desc": "There is a four-digit number ABCD, where A, B, C, D each represents a different digit from 1 to 9.\n\r\nIf ABCD is divisible by 13, BCDA is divisible by 11, CDAB is divisible by 9, and DABC is divisible by 7, what is the original number ABCD?", "hint": "Try to link the clues together.", "answer": "If BCDA is divisible by 11, then so is ABCD, because both mean that A+C-B-D is divisible by 11.\n\r\nIf CDAB is divisible by 9, then so is ABCD, because both mean that A+B+C+D is divisible by 9.\n\r\nTherefore, ABCD is divisible by 13*11*9=1287, the only possibilities are 1287, 2574, 3861, 5148, 6435, 7722, 9009.\n\r\nAmong them, excluding the two with repeated digits, only 3861 satisfies the last clue - 1386 is divisible by 7.\n\r\nTherefore, ABCD is 3861.", "category": "Math", "date": "04/14/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a four-digit number ABCD, where A, B, C, D each represents a different digit from 1 to 9.\n\r\nIf ABCD is divisible by 13, BCDA is divisible by 11, CDAB is divisible by 9, and DABC is divisible by 7, what is the original number ABCD?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf BCDA is divisible by 11, then so is ABCD, because both mean that A+C-B-D is divisible by 11.\n\r\nIf CDAB is divisible by 9, then so is ABCD, because both mean that A+B+C+D is divisible by 9.\n\r\nTherefore, ABCD is divisible by 13*11*9=1287, the only possibilities are 1287, 2574, 3861, 5148, 6435, 7722, 9009.\n\r\nAmong them, excluding the two with repeated digits, only 3861 satisfies the last clue - 1386 is divisible by 7.\n\r\nTherefore, ABCD is 3861.\n<|im_start|>answer\nIf BCDA is divisible by 11, then so is ABCD, because both mean that A+C-B-D is divisible by 11.\n\r\nIf CDAB is divisible by 9, then so is ABCD, because both mean that A+B+C+D is divisible by 9.\n\r\nTherefore, ABCD is divisible by 13*11*9=1287, the only possibilities are 1287, 2574, 3861, 5148, 6435, 7722, 9009.\n\r\nAmong them, excluding the two with repeated digits, only 3861 satisfies the last clue - 1386 is divisible by 7.\n\r\nTherefore, ABCD is 3861.\n<|im_end|>" }, { "id": "#3652", "title": "School Friend", "fun": 2.59, "difficulty": 1.57, "author": "PeaceJo", "desc": "Joe went back to his hometown and met an old school friend he had not seen for years. His friend said, \"I am married now but not to anyone you know. This is my daughter.\"\n\r\nJoe turned to the little girl and asked her her name. She said, \"I have the same name as my mother.\"\n\r\n\"Then you must be called Louise,\" said Joe. He was right, but how did he know?", "hint": "No hint available.", "answer": "His old school friend was a woman - named Louise.", "category": "Logic", "date": "04/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe went back to his hometown and met an old school friend he had not seen for years. His friend said, \"I am married now but not to anyone you know. This is my daughter.\"\n\r\nJoe turned to the little girl and asked her her name. She said, \"I have the same name as my mother.\"\n\r\n\"Then you must be called Louise,\" said Joe. He was right, but how did he know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHis old school friend was a woman - named Louise.\n<|im_start|>answer\nHis old school friend was a woman - named Louise.\n<|im_end|>" }, { "id": "#8092", "title": "Black Horse", "fun": 2.59, "difficulty": 1.16, "author": "jizzyhuggs", "desc": "A black horse jumps over a castle and lands on a little white man, who disappears. Why does he disappear?", "hint": "No hint available.", "answer": "It's a chess game. The horse is a knight. It jumps over a rook (castle) and lands on a pawn.", "category": "Logic", "date": "10/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA black horse jumps over a castle and lands on a little white man, who disappears. Why does he disappear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's a chess game. The horse is a knight. It jumps over a rook (castle) and lands on a pawn.\n<|im_start|>answer\nIt's a chess game. The horse is a knight. It jumps over a rook (castle) and lands on a pawn.\n<|im_end|>" }, { "id": "#10206", "title": "Snaps Road", "fun": 2.59, "difficulty": 1.67, "author": "snaps", "desc": "The Snapsville Town Council decided to have some fun with numbering the houses in Snaps Road which was in a new residential development in the town. For reasons known only to the Council, they elected not to use house numbers that contained the digit 3 (eg. 13, 32, etc.) or numbers that were multiples of 5 or 7. If there were 30 houses in Snaps Street, what was the number of the last house?", "hint": "No hint available.", "answer": "The last house in Snaps Road was number 62.\n\r\nThe house numbers that were used in Snaps Road were:\r\n1, 2, 4, 6, 8, 9, 11, 12, 16, 17, 18, 19, 22, 24, 26, 27, 29, 41, 44, 46, 47, 48, 51, 52, 54, 57, 58, 59, 61, 62.", "category": "Math", "date": "02/03/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Snapsville Town Council decided to have some fun with numbering the houses in Snaps Road which was in a new residential development in the town. For reasons known only to the Council, they elected not to use house numbers that contained the digit 3 (eg. 13, 32, etc.) or numbers that were multiples of 5 or 7. If there were 30 houses in Snaps Street, what was the number of the last house?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe last house in Snaps Road was number 62.\n\r\nThe house numbers that were used in Snaps Road were:\r\n1, 2, 4, 6, 8, 9, 11, 12, 16, 17, 18, 19, 22, 24, 26, 27, 29, 41, 44, 46, 47, 48, 51, 52, 54, 57, 58, 59, 61, 62.\n<|im_start|>answer\nThe last house in Snaps Road was number 62.\n\r\nThe house numbers that were used in Snaps Road were:\r\n1, 2, 4, 6, 8, 9, 11, 12, 16, 17, 18, 19, 22, 24, 26, 27, 29, 41, 44, 46, 47, 48, 51, 52, 54, 57, 58, 59, 61, 62.\n<|im_end|>" }, { "id": "#1308", "title": "Math in Your Head", "fun": 2.59, "difficulty": 1.27, "author": "gokaran", "desc": "Note: This riddle must be done IN YOUR HEAD ONLY and NOT using paper and a pen.\n\r\nTake 1000 and add 40 to it.\n\r\nNow add another 1000.\n\r\nNow add 30.\n\r\nAnother 1000.\n\r\nNow add 20.\n\r\nNow add another 1000.\n\r\nNow add 10.\n\r\nWhat is the total?", "hint": "No hint available.", "answer": "Did you get 5000?\r\nThe correct answer is actually 4100.\r\nDon't believe it? Check with your calculator!", "category": "Math", "date": "11/07/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNote: This riddle must be done IN YOUR HEAD ONLY and NOT using paper and a pen.\n\r\nTake 1000 and add 40 to it.\n\r\nNow add another 1000.\n\r\nNow add 30.\n\r\nAnother 1000.\n\r\nNow add 20.\n\r\nNow add another 1000.\n\r\nNow add 10.\n\r\nWhat is the total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDid you get 5000?\r\nThe correct answer is actually 4100.\r\nDon't believe it? Check with your calculator!\n<|im_start|>answer\nDid you get 5000?\r\nThe correct answer is actually 4100.\r\nDon't believe it? Check with your calculator!\n<|im_end|>" }, { "id": "#28756", "title": "Time For a Splash", "fun": 2.59, "difficulty": 1.13, "author": "shenqiang", "desc": "Adam, Becky, Carla, Danny, and Elysse are lined up at the diving board. Danny is the only person who dives. The others jump. Carla is standing immediately behind her best friend, who is Adam. Adam is two people in front of Becky. The person who dives is the first in line. Elysse is next to Adam.\n\r\nIn what order are they standing in line at the diving board?", "hint": "No hint available.", "answer": "The people standing in line at the diving board are in the following order: Danny, Elysse, Adam, Carla and Becky.", "category": "Logic", "date": "02/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdam, Becky, Carla, Danny, and Elysse are lined up at the diving board. Danny is the only person who dives. The others jump. Carla is standing immediately behind her best friend, who is Adam. Adam is two people in front of Becky. The person who dives is the first in line. Elysse is next to Adam.\n\r\nIn what order are they standing in line at the diving board?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe people standing in line at the diving board are in the following order: Danny, Elysse, Adam, Carla and Becky.\n<|im_start|>answer\nThe people standing in line at the diving board are in the following order: Danny, Elysse, Adam, Carla and Becky.\n<|im_end|>" }, { "id": "#31858", "title": "Little Johnny", "fun": 2.59, "difficulty": 2.27, "author": "fishmed", "desc": "Little Johnny was trying to work out a Math-Magic problem his teacher had given him at school that day. He was having problems, so he asked his mom to help. \n\r\nThe problem read, MAD + AS + A = BULL\n\r\n\"Mom\", he said, \"I need to use some of the numbers from 0-9 to make this problem work. I have already figured out from Skippy at school that D equals 3 and L equals 7, but I can't get the rest. Each letter stands for only one number.\"\n\r\nHis mother helped him figure out the rest. Can you figure out the answer, given what Little Johnny already knew?", "hint": "No hint available.", "answer": "983 + 86 + 8 = 1077 is the answer, based on what Johnny knew at the beginning.", "category": "Math", "date": "07/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittle Johnny was trying to work out a Math-Magic problem his teacher had given him at school that day. He was having problems, so he asked his mom to help. \n\r\nThe problem read, MAD + AS + A = BULL\n\r\n\"Mom\", he said, \"I need to use some of the numbers from 0-9 to make this problem work. I have already figured out from Skippy at school that D equals 3 and L equals 7, but I can't get the rest. Each letter stands for only one number.\"\n\r\nHis mother helped him figure out the rest. Can you figure out the answer, given what Little Johnny already knew?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n983 + 86 + 8 = 1077 is the answer, based on what Johnny knew at the beginning.\n<|im_start|>answer\n983 + 86 + 8 = 1077 is the answer, based on what Johnny knew at the beginning.\n<|im_end|>" }, { "id": "#25381", "title": "Coloured Balls", "fun": 2.59, "difficulty": 1.02, "author": "DaleGriffin", "desc": "I have a bag containing 24 coloured balls. The colours are red, green and blue. There are twice as many red balls as green balls, and one more red ball than blue balls. How many of each colour ball are there?", "hint": "No hint available.", "answer": "10 red\r\n5 green\r\n9 blue", "category": "Math", "date": "08/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have a bag containing 24 coloured balls. The colours are red, green and blue. There are twice as many red balls as green balls, and one more red ball than blue balls. How many of each colour ball are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10 red\r\n5 green\r\n9 blue\n<|im_start|>answer\n10 red\r\n5 green\r\n9 blue\n<|im_end|>" }, { "id": "#8943", "title": "Five Five Five Five Five", "fun": 2.59, "difficulty": 2.06, "author": "foxer425", "desc": "Fill in the blanks using +, -, *, or / to make this equation valid. You may also add parentheses if necessary.\n\r\n5 _ 5 _ 5 _ 5 _ 5 = 24", "hint": "No hint available.", "answer": "(5 * 5 * 5 - 5 )/ 5 = 24 \r\n5*5=25 \r\n25*5=125 \r\n125-5=120 \r\n120/5=24", "category": "Math", "date": "12/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFill in the blanks using +, -, *, or / to make this equation valid. You may also add parentheses if necessary.\n\r\n5 _ 5 _ 5 _ 5 _ 5 = 24\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(5 * 5 * 5 - 5 )/ 5 = 24 \r\n5*5=25 \r\n25*5=125 \r\n125-5=120 \r\n120/5=24\n<|im_start|>answer\n(5 * 5 * 5 - 5 )/ 5 = 24 \r\n5*5=25 \r\n25*5=125 \r\n125-5=120 \r\n120/5=24\n<|im_end|>" }, { "id": "#41949", "title": "What Four Digit Number?", "fun": 2.59, "difficulty": 1.8900000000000001, "author": "Editor", "desc": "What four digit number has digit 1 three less than digit 4 which is one more than digit 2 which is twice digit 3 which is not a prime number and is one more than 1/3 of digit 4?", "hint": "No hint available.", "answer": "6849.", "category": "Math", "date": "05/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat four digit number has digit 1 three less than digit 4 which is one more than digit 2 which is twice digit 3 which is not a prime number and is one more than 1/3 of digit 4?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6849.\n<|im_start|>answer\n6849.\n<|im_end|>" }, { "id": "#36760", "title": "The Tigers' Grades", "fun": 2.59, "difficulty": 1.0, "author": "pokpic", "desc": "The Timberland Tigers have just gotten their report card. That same day the Tigers got their report card, the coach asked the 4 captains to see him in his office to find out if they qualified for the team. Figure out the first and last name of each player, what his best grade was, and what subject he got it in.\r\nFirst Names: Andrew, Bill, Derrick, Eric\r\nLast Names: Smith, Jones, Williams, Washington\r\nLetter Grades: A+, A, A-, B+\r\nSubjects: Science, Language Arts, Math. Social Studies\r\n1. Derrick and the person who got an A+ in language arts are best friends.\r\n2. Mr. Smith got a B+ in science.\r\n3. Eric was so happy when he got his A+ that he ran into the science classroom where Bill wasn't so happy about his B+.\r\n4. Mr. Williams walked with his best friend Derrick who had just talked to Mr. Jones about Mr. Jones's A- in math.\r\n5. Derrick Washington got an A and talked to Andrew Jones about his grade in math.", "hint": "No hint available.", "answer": "Andrew Jones got an A- in math.\r\nBill Smith got an B+ in science.\r\nDerrick Washington got an A in social studies.\r\nEric Williams got an A+ in language arts.", "category": "Logic-Grid", "date": "05/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Timberland Tigers have just gotten their report card. That same day the Tigers got their report card, the coach asked the 4 captains to see him in his office to find out if they qualified for the team. Figure out the first and last name of each player, what his best grade was, and what subject he got it in.\r\nFirst Names: Andrew, Bill, Derrick, Eric\r\nLast Names: Smith, Jones, Williams, Washington\r\nLetter Grades: A+, A, A-, B+\r\nSubjects: Science, Language Arts, Math. Social Studies\r\n1. Derrick and the person who got an A+ in language arts are best friends.\r\n2. Mr. Smith got a B+ in science.\r\n3. Eric was so happy when he got his A+ that he ran into the science classroom where Bill wasn't so happy about his B+.\r\n4. Mr. Williams walked with his best friend Derrick who had just talked to Mr. Jones about Mr. Jones's A- in math.\r\n5. Derrick Washington got an A and talked to Andrew Jones about his grade in math.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndrew Jones got an A- in math.\r\nBill Smith got an B+ in science.\r\nDerrick Washington got an A in social studies.\r\nEric Williams got an A+ in language arts.\n<|im_start|>answer\nAndrew Jones got an A- in math.\r\nBill Smith got an B+ in science.\r\nDerrick Washington got an A in social studies.\r\nEric Williams got an A+ in language arts.\n<|im_end|>" }, { "id": "#32902", "title": "Monkey Fun!", "fun": 2.59, "difficulty": 1.79, "author": "lorial", "desc": "Three types of monkeys - monkeys of the same type weigh the same - were amusing themselves in the jungle. By chance they found a small wobbly tree, where, by varying the amounts of monkeys on each side they could keep the tree in an upright position.\n\r\nThey found out that:\n\r\n2 howler monkeys and 1 squirrel monkey on one side balanced with 4 spider monkeys on the other side.\n\r\n2 spider monkeys and 1 squirrel monkey on one side balanced with 3 howler monkeys on the other side.\n\r\nCan you determine how many squirrel monkeys on one side it would take to keep the tree upright with 4 howler monkeys on the other side?", "hint": "No hint available.", "answer": "3\n\r\nIn the following explanation assume:\n\r\nspider monkey =sp\r\nsquirrel monkey = sq\r\nhowler monkey = h\n\r\nIf (2h+1sq) = 4sp then divide by 2 giving:\n\r\n(1h+ 0.5sq) = 2sp\n\r\nTherefore:\n\r\n(1sq + 2sp) = (1sq + 1h + 0.5sq) = (1h + 1.5sq)\n\r\nTherefore:\n\r\n3h = (1h + 1.5sq)\n\r\nTherefore: \n\r\n2h = 1.5sq\n\r\nThen multiply this all by 2, giving:\n\r\n4h = 3sq", "category": "Math", "date": "09/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree types of monkeys - monkeys of the same type weigh the same - were amusing themselves in the jungle. By chance they found a small wobbly tree, where, by varying the amounts of monkeys on each side they could keep the tree in an upright position.\n\r\nThey found out that:\n\r\n2 howler monkeys and 1 squirrel monkey on one side balanced with 4 spider monkeys on the other side.\n\r\n2 spider monkeys and 1 squirrel monkey on one side balanced with 3 howler monkeys on the other side.\n\r\nCan you determine how many squirrel monkeys on one side it would take to keep the tree upright with 4 howler monkeys on the other side?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3\n\r\nIn the following explanation assume:\n\r\nspider monkey =sp\r\nsquirrel monkey = sq\r\nhowler monkey = h\n\r\nIf (2h+1sq) = 4sp then divide by 2 giving:\n\r\n(1h+ 0.5sq) = 2sp\n\r\nTherefore:\n\r\n(1sq + 2sp) = (1sq + 1h + 0.5sq) = (1h + 1.5sq)\n\r\nTherefore:\n\r\n3h = (1h + 1.5sq)\n\r\nTherefore: \n\r\n2h = 1.5sq\n\r\nThen multiply this all by 2, giving:\n\r\n4h = 3sq\n<|im_start|>answer\n3\n\r\nIn the following explanation assume:\n\r\nspider monkey =sp\r\nsquirrel monkey = sq\r\nhowler monkey = h\n\r\nIf (2h+1sq) = 4sp then divide by 2 giving:\n\r\n(1h+ 0.5sq) = 2sp\n\r\nTherefore:\n\r\n(1sq + 2sp) = (1sq + 1h + 0.5sq) = (1h + 1.5sq)\n\r\nTherefore:\n\r\n3h = (1h + 1.5sq)\n\r\nTherefore: \n\r\n2h = 1.5sq\n\r\nThen multiply this all by 2, giving:\n\r\n4h = 3sq\n<|im_end|>" }, { "id": "#17788", "title": "The Cycle Race", "fun": 2.59, "difficulty": 2.74, "author": "ansh93", "desc": "In a 14-stage cycle race there were a 100 competitors, among them \"Crazy\" Charles \r\nIn all 14 stages \"Crazy\" Charles finished in the same position: 93rd. However, at the end of the race, \"Crazy\" Charles was declared runner-up in the competition: his accumulated time was less than that of all the other competitors except one, the champion. \r\nBearing in mind the fact that none of the 100 competitors withdrew from the race, how was it possible for \"Crazy\" Charles to finish second if he never even made it into the top 90 competitors?", "hint": "No hint available.", "answer": "\"Crazy\" Charles was runner-up in the race because in each of the 14 stages he beat 7 different competitors, and he beat them all by more time than the accumulated time that they beat him by in all the other stages of the tour. Since 7*14=98, there was only one cyclist that he never beat and that was the champion.", "category": "Math", "date": "05/31/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a 14-stage cycle race there were a 100 competitors, among them \"Crazy\" Charles \r\nIn all 14 stages \"Crazy\" Charles finished in the same position: 93rd. However, at the end of the race, \"Crazy\" Charles was declared runner-up in the competition: his accumulated time was less than that of all the other competitors except one, the champion. \r\nBearing in mind the fact that none of the 100 competitors withdrew from the race, how was it possible for \"Crazy\" Charles to finish second if he never even made it into the top 90 competitors?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"Crazy\" Charles was runner-up in the race because in each of the 14 stages he beat 7 different competitors, and he beat them all by more time than the accumulated time that they beat him by in all the other stages of the tour. Since 7*14=98, there was only one cyclist that he never beat and that was the champion.\n<|im_start|>answer\n\"Crazy\" Charles was runner-up in the race because in each of the 14 stages he beat 7 different competitors, and he beat them all by more time than the accumulated time that they beat him by in all the other stages of the tour. Since 7*14=98, there was only one cyclist that he never beat and that was the champion.\n<|im_end|>" }, { "id": "#17350", "title": "Bird", "fun": 2.59, "difficulty": 2.4, "author": "slob", "desc": "The distance between Station Atena and Station Barcena is 78 miles. A train starts from Atena towards Barcena. A bird starts at the same time from Barcena straight towards the moving train. On reaching the train, it instantaneously turns back and returns to Barcena. The bird makes these journeys from Barcena to the train and back to Barcena continuously till the train reaches Barcena. The bird finally returns to Barcena and rests. Calculate the total distance in miles the bird travels in the following two cases:\n\r\n(a) the bird flies at 70 miles per hour and the speed of the train is 60 miles per hour\n\r\nb) the bird flies at 60 miles per hour and the speed of the train is 70 miles per hour - it is safe to assume that the train does not in fact hit the bird for the sake of the equation.", "hint": "No hint available.", "answer": "Solution:\n\r\nCase (a): Bird flies at a speed greater than that of the train\n\r\nThe train (at a speed of 60 miles per hour) travels 60 miles in 60 minutes.\r\nTherefore, the train travels from Atena to Barcena (78 miles) in 78 minutes.\n\r\nImportantly, the bird makes the journeys continuously back and forth for this same amount of time (namely, 78 minutes).\r\nThus, the total distance traveled by the bird\r\n= 70 miles per hour x 78 minutes = 70 x 78 / 60 miles = 91 miles.\n\r\nCase (b): Bird flies at a speed less than that of the train\n\r\nIn 36 minutes, the bird travels 36 miles, the train travels 42 miles, and the two meet.\r\nNow, the train (which is traveling at a speed greater than that of the bird) will reach Barcena before the bird.\r\nSo, the bird simply returns to Barcena (a return journey of 36 miles).\r\nThus, the total distance traveled by the bird is 72 miles.", "category": "Math", "date": "04/15/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe distance between Station Atena and Station Barcena is 78 miles. A train starts from Atena towards Barcena. A bird starts at the same time from Barcena straight towards the moving train. On reaching the train, it instantaneously turns back and returns to Barcena. The bird makes these journeys from Barcena to the train and back to Barcena continuously till the train reaches Barcena. The bird finally returns to Barcena and rests. Calculate the total distance in miles the bird travels in the following two cases:\n\r\n(a) the bird flies at 70 miles per hour and the speed of the train is 60 miles per hour\n\r\nb) the bird flies at 60 miles per hour and the speed of the train is 70 miles per hour - it is safe to assume that the train does not in fact hit the bird for the sake of the equation.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSolution:\n\r\nCase (a): Bird flies at a speed greater than that of the train\n\r\nThe train (at a speed of 60 miles per hour) travels 60 miles in 60 minutes.\r\nTherefore, the train travels from Atena to Barcena (78 miles) in 78 minutes.\n\r\nImportantly, the bird makes the journeys continuously back and forth for this same amount of time (namely, 78 minutes).\r\nThus, the total distance traveled by the bird\r\n= 70 miles per hour x 78 minutes = 70 x 78 / 60 miles = 91 miles.\n\r\nCase (b): Bird flies at a speed less than that of the train\n\r\nIn 36 minutes, the bird travels 36 miles, the train travels 42 miles, and the two meet.\r\nNow, the train (which is traveling at a speed greater than that of the bird) will reach Barcena before the bird.\r\nSo, the bird simply returns to Barcena (a return journey of 36 miles).\r\nThus, the total distance traveled by the bird is 72 miles.\n<|im_start|>answer\nSolution:\n\r\nCase (a): Bird flies at a speed greater than that of the train\n\r\nThe train (at a speed of 60 miles per hour) travels 60 miles in 60 minutes.\r\nTherefore, the train travels from Atena to Barcena (78 miles) in 78 minutes.\n\r\nImportantly, the bird makes the journeys continuously back and forth for this same amount of time (namely, 78 minutes).\r\nThus, the total distance traveled by the bird\r\n= 70 miles per hour x 78 minutes = 70 x 78 / 60 miles = 91 miles.\n\r\nCase (b): Bird flies at a speed less than that of the train\n\r\nIn 36 minutes, the bird travels 36 miles, the train travels 42 miles, and the two meet.\r\nNow, the train (which is traveling at a speed greater than that of the bird) will reach Barcena before the bird.\r\nSo, the bird simply returns to Barcena (a return journey of 36 miles).\r\nThus, the total distance traveled by the bird is 72 miles.\n<|im_end|>" }, { "id": "#308", "title": "Mary's Dad and Grandfather", "fun": 2.59, "difficulty": 1.56, "author": "Phyllis", "desc": "For Show and Tell at school, Mary told her class that today was the birthday of both her father and her grandfather and that they were exactly the same age. Her teacher said that was impossible, but Mary insisted she was right. Can you explain how she could be right?", "hint": "Mary has two grandfathers.", "answer": "Mary was talking about her father and her maternal grandfather.\n\r\nHer father, for example, could be 50 and her mother`s father, her maternal grandfather, could be 50. Her mother is obviously younger than her father.", "category": "Logic", "date": "02/25/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor Show and Tell at school, Mary told her class that today was the birthday of both her father and her grandfather and that they were exactly the same age. Her teacher said that was impossible, but Mary insisted she was right. Can you explain how she could be right?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary was talking about her father and her maternal grandfather.\n\r\nHer father, for example, could be 50 and her mother`s father, her maternal grandfather, could be 50. Her mother is obviously younger than her father.\n<|im_start|>answer\nMary was talking about her father and her maternal grandfather.\n\r\nHer father, for example, could be 50 and her mother`s father, her maternal grandfather, could be 50. Her mother is obviously younger than her father.\n<|im_end|>" }, { "id": "#1346", "title": "Find the Murderess", "fun": 2.59, "difficulty": 2.29, "author": "Yanivster", "desc": "Three women - Anna, Barbara and Jayne were arrested for the murder of Susan. One of these three was the murderess, one was an accomplice, and one was innocent.\n\r\nThree statements were collected:\r\nA. \"Anna was not the accomplice\"\r\nB. \"Barbara is not the murderess\"\r\nC. \"Jayne is not innocent\"\r\nThe following facts are also known:\r\n1. A statement does not concern the woman who gave it.\r\n2. The innocent woman gave at least one statement.\r\n3. Only the innocent woman tells the truth.\n\r\nWhich woman is the murderess?", "hint": "No hint available.", "answer": "The innocent woman gave one or two statements. If she gave one statement, then the other two must be false, but that situation is not possible, because you always come to a discrepancy. So she must have given two statements. Those statements must be A and B (that's the only way it works out), which means that Anna is the murderess.", "category": "Logic", "date": "11/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree women - Anna, Barbara and Jayne were arrested for the murder of Susan. One of these three was the murderess, one was an accomplice, and one was innocent.\n\r\nThree statements were collected:\r\nA. \"Anna was not the accomplice\"\r\nB. \"Barbara is not the murderess\"\r\nC. \"Jayne is not innocent\"\r\nThe following facts are also known:\r\n1. A statement does not concern the woman who gave it.\r\n2. The innocent woman gave at least one statement.\r\n3. Only the innocent woman tells the truth.\n\r\nWhich woman is the murderess?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe innocent woman gave one or two statements. If she gave one statement, then the other two must be false, but that situation is not possible, because you always come to a discrepancy. So she must have given two statements. Those statements must be A and B (that's the only way it works out), which means that Anna is the murderess.\n<|im_start|>answer\nThe innocent woman gave one or two statements. If she gave one statement, then the other two must be false, but that situation is not possible, because you always come to a discrepancy. So she must have given two statements. Those statements must be A and B (that's the only way it works out), which means that Anna is the murderess.\n<|im_end|>" }, { "id": "#152", "title": "Tennis balls", "fun": 2.59, "difficulty": 1.92, "author": "jerry1", "desc": "There are three boxes of tennis balls in a warehouse. They have all been mislabeled. One box is labeled yellow tennis balls, one is labeled white and yellow tennis balls and one is labeled white tennis balls. Take one can of tennis balls out of one box without looking into the box or into any other box. By just looking at the color of this one can of balls, can you correctly label each of the boxes?", "hint": "Every box is mislabeled.", "answer": "Take a can of tennis balls from the box labeled `White and Yellow Tennis Balls`. Say that the ball is yellow. Take the `Yellow Tennis Balls` label and put it on that box. Remove the `White and Yellow Tennis Balls` label and put it on the box marked `White Tennis Balls`. It couldn't go on the box that had previously had the `Yellow Tennis Balls` label, because that would mean that the `White Tennis Balls` label couldn't be changed, and we have been told that all the boxes are mislabeled. Move the `White Tennis Balls` label to the unlabeled box. (The same logic would prevail if you started with any of the boxes.)", "category": "Logic", "date": "01/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three boxes of tennis balls in a warehouse. They have all been mislabeled. One box is labeled yellow tennis balls, one is labeled white and yellow tennis balls and one is labeled white tennis balls. Take one can of tennis balls out of one box without looking into the box or into any other box. By just looking at the color of this one can of balls, can you correctly label each of the boxes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake a can of tennis balls from the box labeled `White and Yellow Tennis Balls`. Say that the ball is yellow. Take the `Yellow Tennis Balls` label and put it on that box. Remove the `White and Yellow Tennis Balls` label and put it on the box marked `White Tennis Balls`. It couldn't go on the box that had previously had the `Yellow Tennis Balls` label, because that would mean that the `White Tennis Balls` label couldn't be changed, and we have been told that all the boxes are mislabeled. Move the `White Tennis Balls` label to the unlabeled box. (The same logic would prevail if you started with any of the boxes.)\n<|im_start|>answer\nTake a can of tennis balls from the box labeled `White and Yellow Tennis Balls`. Say that the ball is yellow. Take the `Yellow Tennis Balls` label and put it on that box. Remove the `White and Yellow Tennis Balls` label and put it on the box marked `White Tennis Balls`. It couldn't go on the box that had previously had the `Yellow Tennis Balls` label, because that would mean that the `White Tennis Balls` label couldn't be changed, and we have been told that all the boxes are mislabeled. Move the `White Tennis Balls` label to the unlabeled box. (The same logic would prevail if you started with any of the boxes.)\n<|im_end|>" }, { "id": "#21666", "title": "Elevator Rides", "fun": 2.59, "difficulty": 2.75, "author": "chidam11", "desc": "Kevin and Smith are in charge of counting people who get on and off the lift. They take turns riding to the top floor and back down, counting as they go. After three such trips each morning noon and evening, there is an average taken.\r\n The hotel manager wants to know the days average.\r\n1.On Smith's noon trip there were 32 fewer people than in his morning count.\r\n2.Kevin counted a total of 122 in the morning and noon counts, just one higher than his evening count, but 24 more than Smith's Evening count.\r\n3.Kevin's morning count is the same as Smith's average.\r\n4.Kevin's evening count was 37 more than Smith's morning count.", "hint": "Clue 2 gives most of the information needed to get started.", "answer": "Morning Noon Evening Total Ave\r\nKevin 78 44 121 243 81\r\nSmith 84 52 98 234 78", "category": "Math", "date": "03/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKevin and Smith are in charge of counting people who get on and off the lift. They take turns riding to the top floor and back down, counting as they go. After three such trips each morning noon and evening, there is an average taken.\r\n The hotel manager wants to know the days average.\r\n1.On Smith's noon trip there were 32 fewer people than in his morning count.\r\n2.Kevin counted a total of 122 in the morning and noon counts, just one higher than his evening count, but 24 more than Smith's Evening count.\r\n3.Kevin's morning count is the same as Smith's average.\r\n4.Kevin's evening count was 37 more than Smith's morning count.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMorning Noon Evening Total Ave\r\nKevin 78 44 121 243 81\r\nSmith 84 52 98 234 78\n<|im_start|>answer\nMorning Noon Evening Total Ave\r\nKevin 78 44 121 243 81\r\nSmith 84 52 98 234 78\n<|im_end|>" }, { "id": "#622", "title": "Find the 3 letter word...", "fun": 2.59, "difficulty": 1.27, "author": "Phyllis", "desc": "Find a common 3 letter word given the following:\r\nLEG has no common letter with it.\r\nERG has one common letter, not at the correct place.\r\nSIR has one common letter, at the correct place.\r\nSIC has one common letter, not at the correct place.\r\nAIL has one common letter, not at the correct place.", "hint": "No hint available.", "answer": "The word is CAR. \r\nSince the word contains no E or G as in LEG, the only good letter in ERG is R. Then the good letter in SIR is R and it is the third letter of the word. I and L are not in the word, so the good letter of AIL is A. The A is not the first letter of the word, so it must the be second. The good letter of SIC is C,which must begin the word.", "category": "Logic", "date": "06/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind a common 3 letter word given the following:\r\nLEG has no common letter with it.\r\nERG has one common letter, not at the correct place.\r\nSIR has one common letter, at the correct place.\r\nSIC has one common letter, not at the correct place.\r\nAIL has one common letter, not at the correct place.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe word is CAR. \r\nSince the word contains no E or G as in LEG, the only good letter in ERG is R. Then the good letter in SIR is R and it is the third letter of the word. I and L are not in the word, so the good letter of AIL is A. The A is not the first letter of the word, so it must the be second. The good letter of SIC is C,which must begin the word.\n<|im_start|>answer\nThe word is CAR. \r\nSince the word contains no E or G as in LEG, the only good letter in ERG is R. Then the good letter in SIR is R and it is the third letter of the word. I and L are not in the word, so the good letter of AIL is A. The A is not the first letter of the word, so it must the be second. The good letter of SIC is C,which must begin the word.\n<|im_end|>" }, { "id": "#10701", "title": "Half a Hole", "fun": 2.59, "difficulty": 2.21, "author": "jimbo", "desc": "While digging a hole his back he did bend. \r\nWhen asked how deep it would be in the end, \r\nHe replied \"I'm halfway, and this I will vow, \r\nYou can see how far above the top my head is now\". \r\n\"But when it is finished, as sure as my name is Ken,\" \r\n\"My head will be twice as far below the top then.\" \r\n\"Pray tell me dear Kenneth, what is your height?\" \r\n\"I'm one metre sixty!\" Can you get the depth right?", "hint": "No hint available.", "answer": "The final depth will be 2.4 metres. \n\r\nLet x = the hole's final depth, and y = the height above ground level that Ken's head is now. \n\r\nFrom the first statement you can set up the equation: \n\r\nx/2 + y = 1.6 \r\n(Half the final hole depth + the height Ken's head is above ground level = Ken's height) \n\r\nFrom the second statement you can set up the equation: \n\r\nx - 2y = 1.6 \n\r\n(The final depth of the hole - twice the height that Ken's head is currently above ground level = Ken's height). \n\r\nSolve these for x to get the answer of 2.4 metres.", "category": "Math", "date": "02/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile digging a hole his back he did bend. \r\nWhen asked how deep it would be in the end, \r\nHe replied \"I'm halfway, and this I will vow, \r\nYou can see how far above the top my head is now\". \r\n\"But when it is finished, as sure as my name is Ken,\" \r\n\"My head will be twice as far below the top then.\" \r\n\"Pray tell me dear Kenneth, what is your height?\" \r\n\"I'm one metre sixty!\" Can you get the depth right?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe final depth will be 2.4 metres. \n\r\nLet x = the hole's final depth, and y = the height above ground level that Ken's head is now. \n\r\nFrom the first statement you can set up the equation: \n\r\nx/2 + y = 1.6 \r\n(Half the final hole depth + the height Ken's head is above ground level = Ken's height) \n\r\nFrom the second statement you can set up the equation: \n\r\nx - 2y = 1.6 \n\r\n(The final depth of the hole - twice the height that Ken's head is currently above ground level = Ken's height). \n\r\nSolve these for x to get the answer of 2.4 metres.\n<|im_start|>answer\nThe final depth will be 2.4 metres. \n\r\nLet x = the hole's final depth, and y = the height above ground level that Ken's head is now. \n\r\nFrom the first statement you can set up the equation: \n\r\nx/2 + y = 1.6 \r\n(Half the final hole depth + the height Ken's head is above ground level = Ken's height) \n\r\nFrom the second statement you can set up the equation: \n\r\nx - 2y = 1.6 \n\r\n(The final depth of the hole - twice the height that Ken's head is currently above ground level = Ken's height). \n\r\nSolve these for x to get the answer of 2.4 metres.\n<|im_end|>" }, { "id": "#36669", "title": "Opposites 33", "fun": 2.59, "difficulty": 2.42, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n* stands for L, T, K, C, or N\r\n) stands for D, O, E, H, or S\r\n+ stands for N, G, I, O, or X\r\n( stands for Y, T, E, P, or F\r\n_ stands for R, B, M, A, or S\n\r\nThe five letter code word, (+_*), can be translated into two English words that are opposites. What are the two words?", "hint": "In music...", "answer": "Forte and Piano.", "category": "Logic", "date": "05/19/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n* stands for L, T, K, C, or N\r\n) stands for D, O, E, H, or S\r\n+ stands for N, G, I, O, or X\r\n( stands for Y, T, E, P, or F\r\n_ stands for R, B, M, A, or S\n\r\nThe five letter code word, (+_*), can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nForte and Piano.\n<|im_start|>answer\nForte and Piano.\n<|im_end|>" }, { "id": "#44857", "title": "Puzzling Pets", "fun": 2.59, "difficulty": 1.24, "author": "Shelilah", "desc": "There are four friends: Anna, Bobby, Fred, and Gina. They each have a different pet, and they all adopted their pets in different ways. The pets include a cat, a dog, a fish, and a parrot. Their names are Cookie, Freddie, Millie, and Zuzi. One was a birthday present, one was found in the park, one was bought in the pet store, and one was a newborn in the family. Can you figure out which pet is which?\n\r\nClues:\r\nAnna named her pet after the friend she had a crush on.\r\nBobby is allergic to anything furry.\r\nFred's family had a pregnant pet before he got his.\r\nThese are all of the different pets: Zuzi, Gina's pet, the cat, and the pet from the pet store.\r\nBefore he had a home, this pet entertained customers by talking to them.\r\nGina loves to cuddle with her pet.\r\nBobby's friends always ask him if he won his pet at a carnival.\r\nSomeday, Cookie's real owner might find him and want him back.", "hint": "The pet that entertained the customers talked in English to them.\r\nPeople normally cuddle with pets that are furry.\r\nThere is a game at carnivals where you throw a ball into bowls of water and you might get a pet as a prize.", "answer": "Anna owns Freddie the parrot, whom she bought at the pet store.\r\nBobby owns Zuzi the fish, whom he received as a birthday present.\r\nFred owns Millie the cat, who was born to his family's cat.\r\nGina owns Cookie the dog, whom she found in the park.", "category": "Logic-Grid", "date": "07/14/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four friends: Anna, Bobby, Fred, and Gina. They each have a different pet, and they all adopted their pets in different ways. The pets include a cat, a dog, a fish, and a parrot. Their names are Cookie, Freddie, Millie, and Zuzi. One was a birthday present, one was found in the park, one was bought in the pet store, and one was a newborn in the family. Can you figure out which pet is which?\n\r\nClues:\r\nAnna named her pet after the friend she had a crush on.\r\nBobby is allergic to anything furry.\r\nFred's family had a pregnant pet before he got his.\r\nThese are all of the different pets: Zuzi, Gina's pet, the cat, and the pet from the pet store.\r\nBefore he had a home, this pet entertained customers by talking to them.\r\nGina loves to cuddle with her pet.\r\nBobby's friends always ask him if he won his pet at a carnival.\r\nSomeday, Cookie's real owner might find him and want him back.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnna owns Freddie the parrot, whom she bought at the pet store.\r\nBobby owns Zuzi the fish, whom he received as a birthday present.\r\nFred owns Millie the cat, who was born to his family's cat.\r\nGina owns Cookie the dog, whom she found in the park.\n<|im_start|>answer\nAnna owns Freddie the parrot, whom she bought at the pet store.\r\nBobby owns Zuzi the fish, whom he received as a birthday present.\r\nFred owns Millie the cat, who was born to his family's cat.\r\nGina owns Cookie the dog, whom she found in the park.\n<|im_end|>" }, { "id": "#25762", "title": "Morning Melange", "fun": 2.59, "difficulty": 2.72, "author": "cinnamon30", "desc": "This morning, the popular Bay area cable access TV show, \"Morning Melange\", featured six guests (including Francine and Evan). Each guest lives in a different town in the region (including Corte Madera), and each has a different talent or interest that was the focus of his or her segment. The segments began at 6:45, 7:00, 7:15, 7:30, 7:45 and 8:00. Discover, for each time, the full name of the featured guest, where he or she lives and his or her special interest.\n\r\n1. The first three guests were, in some order: the person surnamed Ivens, the person from Berkeley and the antique car collector.\r\n2. Damien's segment was sometime before Lautremont's segment.\r\n3. Krieger's segment began at 7:45.\r\n4. Alice appeared after the person from Oakland and before the person surnamed Morley.\r\n5. The people from Berkeley and Daly City aren't of the same sex.\r\n6. The six guests were: Cathy, the person whose first name is Damien, the person whose last name is Novak, the person from Daly City, the person from Palo Alto and the bungee jumper.\r\n7. The last name of the financial adviser is either Lautremont or Novak.\r\n8. Jaspersen's segment began exactly 45 minutes after the beekeeper's segment.\r\n9. The crepe chef went on sometime before the person from Sausalito and sometime after Brandon.\r\n10. The hypnotherapist's segment began at 7:15.", "hint": "Females are Alice, Cathy and Francine; males are Brandon, Damien and Evan.", "answer": "6:45, Damien Ivens, Oakland, Beekeeper\r\n7:00, Alice Lautremont, Palo Alto, Antique car collector\r\n7:15, Cathy Morley, Berkeley, Hypnotherapist\r\n7:30, Brandon Jaspersen, Corte Madera, Bungee jumper\r\n7:45, Evan Krieger, Daly City, Crepe Chef\r\n8:00 Francine Novak, Sausalito, Financial Adviser\n\r\nThe hypnotherapist's segment began at 7:15 (10). Jaspersen's segment was in the second half (8). The beekeeper was in the first half, and was either 6:45 or 7:00 (8). Since Krieger was at 7:45 (3), then Jaspersen was at 7:30. This leaves the beekeeper at 6:45 (8). The antique car collector has to be at 7:00 (1). \n\r\nThe financial adviser isn't Jaspersen or Kreiger (7), and is therefore on during the 8:00 segment. Likewise, Morley can't be at 8:00 (7), or in the first two segments (4); thus Morley has to be at 7:15. This puts Alice at 7:00 and Oakland at 6:45 (4). This also puts Ivens at 6:45 and Berkeley at 7:15 (1). \n\r\nThe two guests in the 6:45 and 7:15 segments are neither Novak, from Daly City or Palo Alto, or interested in bungee jumping. Therefore, these guests must be Cathy and Damien (6). Therefore, Brandon is at 7:30, the chef at 7:45, and the guest from Sausalito at 8:00 (9). The bungee jumper, who must be at 7:30, cannot be from Daly City or Palo Alto, and so is from Corte Madera (6). Alice must be from either Daly City or Palo Alto, so cannot have a last name of Novak (6). \n\r\nTherefore, Lautremont is in the 7:00 time slot and Novak is the 8:00 time slot. Damien was at 6:45 (2), leaving Cathy at 7:15. \n\r\nSince Cathy is from Berkeley, Alice cannot be from Daly City (5), and is therefore from Palo Alto. Likewise, Kreiger, who must be from Daly City, cannot be Francine, and must be named Evan. This leaves Francine at 8:00.", "category": "Logic", "date": "09/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis morning, the popular Bay area cable access TV show, \"Morning Melange\", featured six guests (including Francine and Evan). Each guest lives in a different town in the region (including Corte Madera), and each has a different talent or interest that was the focus of his or her segment. The segments began at 6:45, 7:00, 7:15, 7:30, 7:45 and 8:00. Discover, for each time, the full name of the featured guest, where he or she lives and his or her special interest.\n\r\n1. The first three guests were, in some order: the person surnamed Ivens, the person from Berkeley and the antique car collector.\r\n2. Damien's segment was sometime before Lautremont's segment.\r\n3. Krieger's segment began at 7:45.\r\n4. Alice appeared after the person from Oakland and before the person surnamed Morley.\r\n5. The people from Berkeley and Daly City aren't of the same sex.\r\n6. The six guests were: Cathy, the person whose first name is Damien, the person whose last name is Novak, the person from Daly City, the person from Palo Alto and the bungee jumper.\r\n7. The last name of the financial adviser is either Lautremont or Novak.\r\n8. Jaspersen's segment began exactly 45 minutes after the beekeeper's segment.\r\n9. The crepe chef went on sometime before the person from Sausalito and sometime after Brandon.\r\n10. The hypnotherapist's segment began at 7:15.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6:45, Damien Ivens, Oakland, Beekeeper\r\n7:00, Alice Lautremont, Palo Alto, Antique car collector\r\n7:15, Cathy Morley, Berkeley, Hypnotherapist\r\n7:30, Brandon Jaspersen, Corte Madera, Bungee jumper\r\n7:45, Evan Krieger, Daly City, Crepe Chef\r\n8:00 Francine Novak, Sausalito, Financial Adviser\n\r\nThe hypnotherapist's segment began at 7:15 (10). Jaspersen's segment was in the second half (8). The beekeeper was in the first half, and was either 6:45 or 7:00 (8). Since Krieger was at 7:45 (3), then Jaspersen was at 7:30. This leaves the beekeeper at 6:45 (8). The antique car collector has to be at 7:00 (1). \n\r\nThe financial adviser isn't Jaspersen or Kreiger (7), and is therefore on during the 8:00 segment. Likewise, Morley can't be at 8:00 (7), or in the first two segments (4); thus Morley has to be at 7:15. This puts Alice at 7:00 and Oakland at 6:45 (4). This also puts Ivens at 6:45 and Berkeley at 7:15 (1). \n\r\nThe two guests in the 6:45 and 7:15 segments are neither Novak, from Daly City or Palo Alto, or interested in bungee jumping. Therefore, these guests must be Cathy and Damien (6). Therefore, Brandon is at 7:30, the chef at 7:45, and the guest from Sausalito at 8:00 (9). The bungee jumper, who must be at 7:30, cannot be from Daly City or Palo Alto, and so is from Corte Madera (6). Alice must be from either Daly City or Palo Alto, so cannot have a last name of Novak (6). \n\r\nTherefore, Lautremont is in the 7:00 time slot and Novak is the 8:00 time slot. Damien was at 6:45 (2), leaving Cathy at 7:15. \n\r\nSince Cathy is from Berkeley, Alice cannot be from Daly City (5), and is therefore from Palo Alto. Likewise, Kreiger, who must be from Daly City, cannot be Francine, and must be named Evan. This leaves Francine at 8:00.\n<|im_start|>answer\n6:45, Damien Ivens, Oakland, Beekeeper\r\n7:00, Alice Lautremont, Palo Alto, Antique car collector\r\n7:15, Cathy Morley, Berkeley, Hypnotherapist\r\n7:30, Brandon Jaspersen, Corte Madera, Bungee jumper\r\n7:45, Evan Krieger, Daly City, Crepe Chef\r\n8:00 Francine Novak, Sausalito, Financial Adviser\n\r\nThe hypnotherapist's segment began at 7:15 (10). Jaspersen's segment was in the second half (8). The beekeeper was in the first half, and was either 6:45 or 7:00 (8). Since Krieger was at 7:45 (3), then Jaspersen was at 7:30. This leaves the beekeeper at 6:45 (8). The antique car collector has to be at 7:00 (1). \n\r\nThe financial adviser isn't Jaspersen or Kreiger (7), and is therefore on during the 8:00 segment. Likewise, Morley can't be at 8:00 (7), or in the first two segments (4); thus Morley has to be at 7:15. This puts Alice at 7:00 and Oakland at 6:45 (4). This also puts Ivens at 6:45 and Berkeley at 7:15 (1). \n\r\nThe two guests in the 6:45 and 7:15 segments are neither Novak, from Daly City or Palo Alto, or interested in bungee jumping. Therefore, these guests must be Cathy and Damien (6). Therefore, Brandon is at 7:30, the chef at 7:45, and the guest from Sausalito at 8:00 (9). The bungee jumper, who must be at 7:30, cannot be from Daly City or Palo Alto, and so is from Corte Madera (6). Alice must be from either Daly City or Palo Alto, so cannot have a last name of Novak (6). \n\r\nTherefore, Lautremont is in the 7:00 time slot and Novak is the 8:00 time slot. Damien was at 6:45 (2), leaving Cathy at 7:15. \n\r\nSince Cathy is from Berkeley, Alice cannot be from Daly City (5), and is therefore from Palo Alto. Likewise, Kreiger, who must be from Daly City, cannot be Francine, and must be named Evan. This leaves Francine at 8:00.\n<|im_end|>" }, { "id": "#14152", "title": "4+4+4+4=1?", "fun": 2.59, "difficulty": 2.23, "author": "cool_star", "desc": "Just using addition, subtraction, multiplication, and division, can you form all the numbers from 1 to 10 using exactly four 4's? \n\r\nYou may use parentheses and you can also combine fours to make other numbers (like 44 or 444).", "hint": "It may be helpful to know that you can make 0 with 4-4 and 1 with 4/4.", "answer": "(4+4)/(4+4) = 1\r\n(4x4)/(4+4) = 2\r\n(4+4+4)/4 = 3\r\n4+(4-4)/4 = 4\r\n(4x4+4)/4 = 5\r\n4+(4+4)/4 = 6\r\n44/4-4 = 7\r\n4+4+4-4 = 8\r\n4+4+4/4 = 9\r\n(44-4)/4 = 10", "category": "Math", "date": "08/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJust using addition, subtraction, multiplication, and division, can you form all the numbers from 1 to 10 using exactly four 4's? \n\r\nYou may use parentheses and you can also combine fours to make other numbers (like 44 or 444).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(4+4)/(4+4) = 1\r\n(4x4)/(4+4) = 2\r\n(4+4+4)/4 = 3\r\n4+(4-4)/4 = 4\r\n(4x4+4)/4 = 5\r\n4+(4+4)/4 = 6\r\n44/4-4 = 7\r\n4+4+4-4 = 8\r\n4+4+4/4 = 9\r\n(44-4)/4 = 10\n<|im_start|>answer\n(4+4)/(4+4) = 1\r\n(4x4)/(4+4) = 2\r\n(4+4+4)/4 = 3\r\n4+(4-4)/4 = 4\r\n(4x4+4)/4 = 5\r\n4+(4+4)/4 = 6\r\n44/4-4 = 7\r\n4+4+4-4 = 8\r\n4+4+4/4 = 9\r\n(44-4)/4 = 10\n<|im_end|>" }, { "id": "#41335", "title": "The \"Easy Way Out\"", "fun": 2.59, "difficulty": 1.54, "author": "ubp22", "desc": "Claudia, Ben, Mary and I all attended Humber College together. We got together for coffee last week to catch up. Reminiscing our college days, we laughed about how the other students said we were taking \"the easy way out\" because we all took business programs. \n\r\nAfter we all left, I was trying to remember everyone's last names, programs they were enrolled in, favourite courses, and the length of their programs. Based on what I remembered, can you help me figure out all the details?\n\r\nFirst Names: Ben, Caterina, Mary\n\r\nLast Names: Delco, Thompson, Adecco \n\r\nPrograms: Business Admin, Business Management, Marketing\n\r\nFavourite Subjects: Business Law, Accounting, Microeconomics\n\r\nProgram Lengths (Yrs): 2, 3, 4\n\r\nClues: \r\n1. Caterina felt that her accounting skills would help her run her own business after graduation.\r\n2. The student who liked Law was in school longer than the student who likes Accounting.\r\n3. The Marketing student was not Mary.\r\n4. Mr. Delco's favourite subject was not Accounting.\r\n5. The three graduates were (in increasing order of program length) the Business Management graduate, the student who liked law, and Thompson.", "hint": "No hint available.", "answer": "Ben Delco, Marketing, Law, 3\r\nCaterina Adecco, Business Management, Accounting, 2\r\nMary Thompson, Business Admin, Microeconomics, 4", "category": "Logic-Grid", "date": "04/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nClaudia, Ben, Mary and I all attended Humber College together. We got together for coffee last week to catch up. Reminiscing our college days, we laughed about how the other students said we were taking \"the easy way out\" because we all took business programs. \n\r\nAfter we all left, I was trying to remember everyone's last names, programs they were enrolled in, favourite courses, and the length of their programs. Based on what I remembered, can you help me figure out all the details?\n\r\nFirst Names: Ben, Caterina, Mary\n\r\nLast Names: Delco, Thompson, Adecco \n\r\nPrograms: Business Admin, Business Management, Marketing\n\r\nFavourite Subjects: Business Law, Accounting, Microeconomics\n\r\nProgram Lengths (Yrs): 2, 3, 4\n\r\nClues: \r\n1. Caterina felt that her accounting skills would help her run her own business after graduation.\r\n2. The student who liked Law was in school longer than the student who likes Accounting.\r\n3. The Marketing student was not Mary.\r\n4. Mr. Delco's favourite subject was not Accounting.\r\n5. The three graduates were (in increasing order of program length) the Business Management graduate, the student who liked law, and Thompson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBen Delco, Marketing, Law, 3\r\nCaterina Adecco, Business Management, Accounting, 2\r\nMary Thompson, Business Admin, Microeconomics, 4\n<|im_start|>answer\nBen Delco, Marketing, Law, 3\r\nCaterina Adecco, Business Management, Accounting, 2\r\nMary Thompson, Business Admin, Microeconomics, 4\n<|im_end|>" }, { "id": "#3956", "title": "Aye or Nay", "fun": 2.59, "difficulty": 2.69, "author": "PeaceJo", "desc": "The five-person city council of Noyes Heights met recently to vote on five proposals. Each of the five council members cast an aye or a nay vote for each of the five proposals, with no abstentions. Use the clues below to discover how each council member voted on each of the proposals.\n\r\n1. Each proposal got a different number of aye votes (possibly zero).\n\r\n2. All in all, there was one more aye vote than nay vote cast.\n\r\n3. At no time did Quincy vote nay on two consecutive proposals.\n\r\n4. Orlando, Penny and Sven voted the same way on the second proposal.\n\r\n5. Rosina voted aye on the fourth proposal.\n\r\n6. Quincy and Sven voted differently from each other on each of the first three proposals.\n\r\n7. The third proposal received one more aye vote than the second proposal did.", "hint": "No hint available.", "answer": "Orlando - nay, aye, aye, aye, nay\r\nPenny - nay, aye, aye, aye, nay\r\nQuincy - aye, nay, aye, aye, nay\r\nRosina - nay, nay, aye, aye, nay \r\nSven - nay, aye, nay, aye, nay", "category": "Logic", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe five-person city council of Noyes Heights met recently to vote on five proposals. Each of the five council members cast an aye or a nay vote for each of the five proposals, with no abstentions. Use the clues below to discover how each council member voted on each of the proposals.\n\r\n1. Each proposal got a different number of aye votes (possibly zero).\n\r\n2. All in all, there was one more aye vote than nay vote cast.\n\r\n3. At no time did Quincy vote nay on two consecutive proposals.\n\r\n4. Orlando, Penny and Sven voted the same way on the second proposal.\n\r\n5. Rosina voted aye on the fourth proposal.\n\r\n6. Quincy and Sven voted differently from each other on each of the first three proposals.\n\r\n7. The third proposal received one more aye vote than the second proposal did.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOrlando - nay, aye, aye, aye, nay\r\nPenny - nay, aye, aye, aye, nay\r\nQuincy - aye, nay, aye, aye, nay\r\nRosina - nay, nay, aye, aye, nay \r\nSven - nay, aye, nay, aye, nay\n<|im_start|>answer\nOrlando - nay, aye, aye, aye, nay\r\nPenny - nay, aye, aye, aye, nay\r\nQuincy - aye, nay, aye, aye, nay\r\nRosina - nay, nay, aye, aye, nay \r\nSven - nay, aye, nay, aye, nay\n<|im_end|>" }, { "id": "#42208", "title": "Roman Matches III", "fun": 2.59, "difficulty": 2.0, "author": "MarcM1098", "desc": "The following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it three times; the equation can be corrected in three different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote:\r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: IV = XII - VI", "hint": "One solution only affects the right side of the equation; another only affects the left side, the other affects both sides.", "answer": "First solution: IV = XI - VII\r\nTake the matchstick from the right of the XII and add it to the right of the VI.\n\r\nSecond solution: VI = XII - VI\r\nTake the matchstick from the left of the IV and put it on the right of the same numeral, changing it to VI.\n\r\nThird solution: V = XII - VII\r\nTake the matchstick from the left of the IV and add it to the right of the VI.", "category": "Math", "date": "06/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it three times; the equation can be corrected in three different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote:\r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: IV = XII - VI\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst solution: IV = XI - VII\r\nTake the matchstick from the right of the XII and add it to the right of the VI.\n\r\nSecond solution: VI = XII - VI\r\nTake the matchstick from the left of the IV and put it on the right of the same numeral, changing it to VI.\n\r\nThird solution: V = XII - VII\r\nTake the matchstick from the left of the IV and add it to the right of the VI.\n<|im_start|>answer\nFirst solution: IV = XI - VII\r\nTake the matchstick from the right of the XII and add it to the right of the VI.\n\r\nSecond solution: VI = XII - VI\r\nTake the matchstick from the left of the IV and put it on the right of the same numeral, changing it to VI.\n\r\nThird solution: V = XII - VII\r\nTake the matchstick from the left of the IV and add it to the right of the VI.\n<|im_end|>" }, { "id": "#24319", "title": "Who's Who?", "fun": 2.59, "difficulty": 1.1, "author": "Cheerleader_09", "desc": "Try to find each person's full name and her age.\n\r\nFirst names- Hannah, Tonnie, Abbey, and Kayla\n\r\nMiddle names- Ann, Elizabeth, Ranae, and Nicole\n\r\nLast names- Clark, Linn, Marino, and Kimble\n\r\nAges-13, 14, 15, and 16\n\n\r\n1. Abbey's last name comes before Tonnie's alphabetically.\n\r\n2. The 14 year old doesn't have the names Hannah, Ann, or Marino.\n\r\n3. No one's first name starts with the same letter as her middle name.\n\r\n4. Hannah is the oldest and has the shortest last name.\n\r\n5. Kayla's last name starts with the same letter as her first.\n\r\n6. Tonnie's middle name has the same number of letters as her first.\n\r\n7. Kayla's and Abbey's middle names both start with vowels.\n\r\n8. Tonnie isn't the youngest.", "hint": "No hint available.", "answer": "Abbey Elizabeth Clark-14\r\nHannah Ranae Linn- 16\r\nTonnie Nicole Marino- 15\r\nKayla Ann Kimble-13", "category": "Logic-Grid", "date": "07/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTry to find each person's full name and her age.\n\r\nFirst names- Hannah, Tonnie, Abbey, and Kayla\n\r\nMiddle names- Ann, Elizabeth, Ranae, and Nicole\n\r\nLast names- Clark, Linn, Marino, and Kimble\n\r\nAges-13, 14, 15, and 16\n\n\r\n1. Abbey's last name comes before Tonnie's alphabetically.\n\r\n2. The 14 year old doesn't have the names Hannah, Ann, or Marino.\n\r\n3. No one's first name starts with the same letter as her middle name.\n\r\n4. Hannah is the oldest and has the shortest last name.\n\r\n5. Kayla's last name starts with the same letter as her first.\n\r\n6. Tonnie's middle name has the same number of letters as her first.\n\r\n7. Kayla's and Abbey's middle names both start with vowels.\n\r\n8. Tonnie isn't the youngest.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbbey Elizabeth Clark-14\r\nHannah Ranae Linn- 16\r\nTonnie Nicole Marino- 15\r\nKayla Ann Kimble-13\n<|im_start|>answer\nAbbey Elizabeth Clark-14\r\nHannah Ranae Linn- 16\r\nTonnie Nicole Marino- 15\r\nKayla Ann Kimble-13\n<|im_end|>" }, { "id": "#29196", "title": "Lost and Found", "fun": 2.59, "difficulty": 1.3800000000000001, "author": "____", "desc": "Doria, Libby, Robb, TJ, and Vinny searched the lost and found table. By the time they finished, two gloves (one red, one blue), a blue hat, a striped sweater, and one pair of black sneakers had all made it back to their original owners. Each of the students found one of these missing items.\n\r\nClues:\n\r\n1. Libby and TJ both found something with red in it. \r\n2. TJ and Doria each found a glove. \r\n3. Vinny was the only one to walk off with something in each hand. \n\r\nWhat items did each person find at the lost and found table?", "hint": "Make a chart and eliminate the impossibilities.", "answer": "Doria found her blue glove.\r\nLibby found her striped sweater.\r\nRobb found his blue hat.\r\nTJ found his red glove.\r\nVinny found his black sneakers.", "category": "Logic", "date": "03/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDoria, Libby, Robb, TJ, and Vinny searched the lost and found table. By the time they finished, two gloves (one red, one blue), a blue hat, a striped sweater, and one pair of black sneakers had all made it back to their original owners. Each of the students found one of these missing items.\n\r\nClues:\n\r\n1. Libby and TJ both found something with red in it. \r\n2. TJ and Doria each found a glove. \r\n3. Vinny was the only one to walk off with something in each hand. \n\r\nWhat items did each person find at the lost and found table?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDoria found her blue glove.\r\nLibby found her striped sweater.\r\nRobb found his blue hat.\r\nTJ found his red glove.\r\nVinny found his black sneakers.\n<|im_start|>answer\nDoria found her blue glove.\r\nLibby found her striped sweater.\r\nRobb found his blue hat.\r\nTJ found his red glove.\r\nVinny found his black sneakers.\n<|im_end|>" }, { "id": "#22386", "title": "Unlucky Car Thief", "fun": 2.58, "difficulty": 2.96, "author": "i_am_hated", "desc": "A car thief, who had managed to evade the authorities in the past, unknowingly took the automobile that belonged to Inspector Detweiler. The sleuth wasted no time and spared no effort in discovering and carefully examining the available clues. He was able to identify four suspects with certainty that one of them was the culprit.\n\r\n The four make the statements below. In total, six statements are true and six false.\n\r\nSuspect A:\r\n1. C and I have met many times before today.\r\n2. B is guilty. \r\n3. The car thief did not know it was the Inspector's car.\n\r\nSuspect B:\r\n1. D did not do it.\r\n2. D's third statement is false.\r\n3. I am innocent.\n\r\nSuspect C:\r\n1. I have never met A before today.\r\n2. B is not guilty.\r\n3. D knows how to drive.\n\r\nSuspect D:\r\n1. B's first statement is false.\r\n2. I do not know how to drive.\r\n3. A did it.\n\r\nWhich one is the car thief?", "hint": "No hint available.", "answer": "Consider that six statements are false. A's first statement and C's first statement contradict each other. One of them is false. C's and D's contradict each other. One of them is false. Therefore, there are four additional false statements.\n\r\nAssume A is guilty. If so, A's second statement, B's second statement, and D's first statement are the additional false statements. \n\r\nAssume D is guilty. If so, A's second statement, B's first statement, and D's third statement are false. This also only makes five false statements. D did not do it.\n\r\nAssume C did it. If so, A's second statement, D's first and third statements are false. This again, makes only five false statements.\n\r\nAfter ruling out suspects A, C and D, B is the culprit. B's third statement, C's second statement, and D's first and third statements are the additional false statements. This adds up to six.", "category": "Logic", "date": "04/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA car thief, who had managed to evade the authorities in the past, unknowingly took the automobile that belonged to Inspector Detweiler. The sleuth wasted no time and spared no effort in discovering and carefully examining the available clues. He was able to identify four suspects with certainty that one of them was the culprit.\n\r\n The four make the statements below. In total, six statements are true and six false.\n\r\nSuspect A:\r\n1. C and I have met many times before today.\r\n2. B is guilty. \r\n3. The car thief did not know it was the Inspector's car.\n\r\nSuspect B:\r\n1. D did not do it.\r\n2. D's third statement is false.\r\n3. I am innocent.\n\r\nSuspect C:\r\n1. I have never met A before today.\r\n2. B is not guilty.\r\n3. D knows how to drive.\n\r\nSuspect D:\r\n1. B's first statement is false.\r\n2. I do not know how to drive.\r\n3. A did it.\n\r\nWhich one is the car thief?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nConsider that six statements are false. A's first statement and C's first statement contradict each other. One of them is false. C's and D's contradict each other. One of them is false. Therefore, there are four additional false statements.\n\r\nAssume A is guilty. If so, A's second statement, B's second statement, and D's first statement are the additional false statements. \n\r\nAssume D is guilty. If so, A's second statement, B's first statement, and D's third statement are false. This also only makes five false statements. D did not do it.\n\r\nAssume C did it. If so, A's second statement, D's first and third statements are false. This again, makes only five false statements.\n\r\nAfter ruling out suspects A, C and D, B is the culprit. B's third statement, C's second statement, and D's first and third statements are the additional false statements. This adds up to six.\n<|im_start|>answer\nConsider that six statements are false. A's first statement and C's first statement contradict each other. One of them is false. C's and D's contradict each other. One of them is false. Therefore, there are four additional false statements.\n\r\nAssume A is guilty. If so, A's second statement, B's second statement, and D's first statement are the additional false statements. \n\r\nAssume D is guilty. If so, A's second statement, B's first statement, and D's third statement are false. This also only makes five false statements. D did not do it.\n\r\nAssume C did it. If so, A's second statement, D's first and third statements are false. This again, makes only five false statements.\n\r\nAfter ruling out suspects A, C and D, B is the culprit. B's third statement, C's second statement, and D's first and third statements are the additional false statements. This adds up to six.\n<|im_end|>" }, { "id": "#27574", "title": "Largest Number", "fun": 2.58, "difficulty": 2.42, "author": "shenqiang", "desc": "What's the largest natural number that satisfies this condition:\n\r\nEach digit from the third on equals the sum of its two preceding digits.", "hint": "No hint available.", "answer": "To make a largest number, we need the most number of digits. So we should start with the smallest digits possible. The first digit is at least 1, and the second digit can be 0.\n\r\nSo, the largest number we are looking for is 10112358.", "category": "Math", "date": "12/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat's the largest natural number that satisfies this condition:\n\r\nEach digit from the third on equals the sum of its two preceding digits.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo make a largest number, we need the most number of digits. So we should start with the smallest digits possible. The first digit is at least 1, and the second digit can be 0.\n\r\nSo, the largest number we are looking for is 10112358.\n<|im_start|>answer\nTo make a largest number, we need the most number of digits. So we should start with the smallest digits possible. The first digit is at least 1, and the second digit can be 0.\n\r\nSo, the largest number we are looking for is 10112358.\n<|im_end|>" }, { "id": "#20294", "title": "24 Games II", "fun": 2.58, "difficulty": 1.94, "author": "doggyxp", "desc": "Can you take the numbers 23, 23, 23, and 23, and make the total equal 24 using basic arithmetic signs (*, /, +, -)? Each number may only be used once, and every number must be used.\n\r\nFor example, if given 2, 2, 4, and 6, the answer would be\n\r\n6/2 = 3\r\n3*2 = 6\r\n6*4 = 24\n\r\n2, 2, 4, and 6 were all used once.", "hint": "No hint available.", "answer": "For 23, 23, 23, and 23, the answer is\n\r\n23*23 = 529\r\n529+23 = 552\r\n552/23 = 24", "category": "Math", "date": "01/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you take the numbers 23, 23, 23, and 23, and make the total equal 24 using basic arithmetic signs (*, /, +, -)? Each number may only be used once, and every number must be used.\n\r\nFor example, if given 2, 2, 4, and 6, the answer would be\n\r\n6/2 = 3\r\n3*2 = 6\r\n6*4 = 24\n\r\n2, 2, 4, and 6 were all used once.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor 23, 23, 23, and 23, the answer is\n\r\n23*23 = 529\r\n529+23 = 552\r\n552/23 = 24\n<|im_start|>answer\nFor 23, 23, 23, and 23, the answer is\n\r\n23*23 = 529\r\n529+23 = 552\r\n552/23 = 24\n<|im_end|>" }, { "id": "#29187", "title": "Largest Sum", "fun": 2.58, "difficulty": 1.95, "author": "Draw", "desc": "Starting in the bottom left corner and moving either up or right, adding up the numbers along the way, what is the largest sum which can be made?\n\r\n5 2 5 4 1\r\n7 6 1 7 3\r\n5 9 4 1 5\r\n2 3 8 3 2\r\n3 1 4 9 6", "hint": "No hint available.", "answer": "38.\n\r\n3+2+5+9+6+1+7+4+1=38.", "category": "Math", "date": "03/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStarting in the bottom left corner and moving either up or right, adding up the numbers along the way, what is the largest sum which can be made?\n\r\n5 2 5 4 1\r\n7 6 1 7 3\r\n5 9 4 1 5\r\n2 3 8 3 2\r\n3 1 4 9 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n38.\n\r\n3+2+5+9+6+1+7+4+1=38.\n<|im_start|>answer\n38.\n\r\n3+2+5+9+6+1+7+4+1=38.\n<|im_end|>" }, { "id": "#41173", "title": "What's Right and What's Wrong", "fun": 2.58, "difficulty": 1.91, "author": "brain23", "desc": "Mrs. Richards was grading papers one day when she came across some old tests. They were about states. But Mrs. Richards could only remember that one person got all five right. One person got three right. One person got one right. And one person got them all wrong.\n\r\nHere are the test answers:\r\nJason\r\n1. New York\r\n2. Louisiana\r\n3. Oregon\r\n4. Texas\r\n5. Michigan\n\r\nStephan\r\n1. Oregon\r\n2. Texas\r\n3. New York\r\n4. Louisiana\r\n5. Michigan\n\r\nNancy\r\n1. Oregon\r\n2. New York\r\n3. Louisiana\r\n4. Michigan\r\n5. Texas\n\r\nBridget\r\n1. New York\r\n2. Louisiana\r\n3. Oregon\r\n4. Michigan\r\n5. Texas\n\r\nWhat were the correct answers? Who got them all right? Who got three right? Who got one right? And who got them all wrong?", "hint": "No hint available.", "answer": "The correct answers were: 1. New York 2. Louisiana 3. Oregon 4. Texas 5. Michigan. Jason got them all right. Bridget got three right. Stephan got one right. And Nancy got them all wrong.", "category": "Logic", "date": "03/23/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Richards was grading papers one day when she came across some old tests. They were about states. But Mrs. Richards could only remember that one person got all five right. One person got three right. One person got one right. And one person got them all wrong.\n\r\nHere are the test answers:\r\nJason\r\n1. New York\r\n2. Louisiana\r\n3. Oregon\r\n4. Texas\r\n5. Michigan\n\r\nStephan\r\n1. Oregon\r\n2. Texas\r\n3. New York\r\n4. Louisiana\r\n5. Michigan\n\r\nNancy\r\n1. Oregon\r\n2. New York\r\n3. Louisiana\r\n4. Michigan\r\n5. Texas\n\r\nBridget\r\n1. New York\r\n2. Louisiana\r\n3. Oregon\r\n4. Michigan\r\n5. Texas\n\r\nWhat were the correct answers? Who got them all right? Who got three right? Who got one right? And who got them all wrong?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe correct answers were: 1. New York 2. Louisiana 3. Oregon 4. Texas 5. Michigan. Jason got them all right. Bridget got three right. Stephan got one right. And Nancy got them all wrong.\n<|im_start|>answer\nThe correct answers were: 1. New York 2. Louisiana 3. Oregon 4. Texas 5. Michigan. Jason got them all right. Bridget got three right. Stephan got one right. And Nancy got them all wrong.\n<|im_end|>" }, { "id": "#36199", "title": "Opposites 32", "fun": 2.58, "difficulty": 2.23, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of four letters.\n\r\n8 stands for T, D, F, or E\r\n@ stands for A, N, I, or Z\r\n! stands for W, O, E, or M\r\n# stands for V, I, L, or U\r\n9 stands for S, K, T, or G\r\n0 stands for A, N, D, or P\r\n$ stands for L, I, B, or E\r\n7 stands for P, Q, V, or F\n\r\nThe eight letter code word, 0!9@8#7$, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Positive and Negative.", "category": "Logic", "date": "04/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of four letters.\n\r\n8 stands for T, D, F, or E\r\n@ stands for A, N, I, or Z\r\n! stands for W, O, E, or M\r\n# stands for V, I, L, or U\r\n9 stands for S, K, T, or G\r\n0 stands for A, N, D, or P\r\n$ stands for L, I, B, or E\r\n7 stands for P, Q, V, or F\n\r\nThe eight letter code word, 0!9@8#7$, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPositive and Negative.\n<|im_start|>answer\nPositive and Negative.\n<|im_end|>" }, { "id": "#41963", "title": "4 Classes, 4 A's", "fun": 2.58, "difficulty": 1.54, "author": "whsprec", "desc": "Adam, Billy, Caroline, and David each have an A in their favorite subject. Each student has only one A and it is in either Calculus, Biology, Physics, or English. Each student's favorite class is taken during a different time from first to fourth period, and there is only one A per period. Match the student to their favorite class and the period in which the class is taken.\n\r\n1) Adam's class is after Physics and before Biology.\r\n2) Caroline has an A in Biology, so she tutors Billy during their free 4th period.\r\n3) David is grounded for failing Physics 1st period.\r\n4) The student with the A in English has the class 4th period.", "hint": "No hint available.", "answer": "Adam - Calculus, 2nd period\r\nBilly - Physics, 1st period\r\nCaroline - Biology, 3rd period\r\nDavid - English, 4th period", "category": "Logic", "date": "05/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdam, Billy, Caroline, and David each have an A in their favorite subject. Each student has only one A and it is in either Calculus, Biology, Physics, or English. Each student's favorite class is taken during a different time from first to fourth period, and there is only one A per period. Match the student to their favorite class and the period in which the class is taken.\n\r\n1) Adam's class is after Physics and before Biology.\r\n2) Caroline has an A in Biology, so she tutors Billy during their free 4th period.\r\n3) David is grounded for failing Physics 1st period.\r\n4) The student with the A in English has the class 4th period.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam - Calculus, 2nd period\r\nBilly - Physics, 1st period\r\nCaroline - Biology, 3rd period\r\nDavid - English, 4th period\n<|im_start|>answer\nAdam - Calculus, 2nd period\r\nBilly - Physics, 1st period\r\nCaroline - Biology, 3rd period\r\nDavid - English, 4th period\n<|im_end|>" }, { "id": "#1345", "title": "The Bet", "fun": 2.58, "difficulty": 1.27, "author": "Yanivster", "desc": "Fred told Jack: \"I'll bet you a dollar, that if you give me two dollars, I'll give you back three dollars.\"\n\r\nWho ended up winning money?", "hint": "No hint available.", "answer": "Fred did. Jack gave him two dollars, but he did not give him back three dollars, so he lost the bet and gave Jack one dollar, still holding one of Jack's dollars.", "category": "Logic", "date": "11/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred told Jack: \"I'll bet you a dollar, that if you give me two dollars, I'll give you back three dollars.\"\n\r\nWho ended up winning money?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFred did. Jack gave him two dollars, but he did not give him back three dollars, so he lost the bet and gave Jack one dollar, still holding one of Jack's dollars.\n<|im_start|>answer\nFred did. Jack gave him two dollars, but he did not give him back three dollars, so he lost the bet and gave Jack one dollar, still holding one of Jack's dollars.\n<|im_end|>" }, { "id": "#1997", "title": "Bog Snorkelling", "fun": 2.58, "difficulty": 1.97, "author": "Majeen", "desc": "Four friends were competing in the internationally renowned Bog Snorkelling competition. As usual, the judges were a little careless and once again, they managed to lose the results. Luckily, a number of spectators were able to remember the following snippets of information: \n\r\nOnly one person wore the same number as the position they finished. Gary, who didn't wear green, beat Barry. Larry beat the person who wore yellow. The person who wore number 3, wore green. The person who wore number 2 finished first whereas Harry came last. The person who finished second wore green, Barry wore yellow and the person wearing red beat the person wearing blue. \n\r\nCan you work out who finished where, the number and color they wore?", "hint": "No hint available.", "answer": "Gary won, wore number 2 and red.\r\nLarry came second, wore number 3 and green.\r\nBarry came third, wore number 1 and yellow.\r\nHarry came last and wore number 4 and blue.", "category": "Logic", "date": "01/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends were competing in the internationally renowned Bog Snorkelling competition. As usual, the judges were a little careless and once again, they managed to lose the results. Luckily, a number of spectators were able to remember the following snippets of information: \n\r\nOnly one person wore the same number as the position they finished. Gary, who didn't wear green, beat Barry. Larry beat the person who wore yellow. The person who wore number 3, wore green. The person who wore number 2 finished first whereas Harry came last. The person who finished second wore green, Barry wore yellow and the person wearing red beat the person wearing blue. \n\r\nCan you work out who finished where, the number and color they wore?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGary won, wore number 2 and red.\r\nLarry came second, wore number 3 and green.\r\nBarry came third, wore number 1 and yellow.\r\nHarry came last and wore number 4 and blue.\n<|im_start|>answer\nGary won, wore number 2 and red.\r\nLarry came second, wore number 3 and green.\r\nBarry came third, wore number 1 and yellow.\r\nHarry came last and wore number 4 and blue.\n<|im_end|>" }, { "id": "#48515", "title": "Calendar (Alternate Version)", "fun": 2.58, "difficulty": 1.95, "author": "shenqiang", "desc": "Tom's birthday is exactly 4 weeks later, and today is his birthday with month and day reversed.\n\r\nWhat is Tom's birthday?", "hint": "Consider all possibilities.", "answer": "It's easy to say that the month and day must differ by 1.\n\r\nFurthermore, if their difference is 1, then the previous month must have 1 day more than 28, which is February in a leap year.\n\r\nTherefore, Tom's birthday is March 2nd.", "category": "Math", "date": "02/27/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTom's birthday is exactly 4 weeks later, and today is his birthday with month and day reversed.\n\r\nWhat is Tom's birthday?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's easy to say that the month and day must differ by 1.\n\r\nFurthermore, if their difference is 1, then the previous month must have 1 day more than 28, which is February in a leap year.\n\r\nTherefore, Tom's birthday is March 2nd.\n<|im_start|>answer\nIt's easy to say that the month and day must differ by 1.\n\r\nFurthermore, if their difference is 1, then the previous month must have 1 day more than 28, which is February in a leap year.\n\r\nTherefore, Tom's birthday is March 2nd.\n<|im_end|>" }, { "id": "#31262", "title": "4139 Main Street", "fun": 2.58, "difficulty": 2.03, "author": "horse_luver", "desc": "There is an apartment building on 4139 Main Street. There is a strange thing about floor 7 of this building ... everyone is a prime age! From the clues provided, can you decipher how old these residents are?\n\r\nIn Suzy's age, the digits have a sum of four. Seven years from now, Suzy's age, when you add the digits together, will be 20 less than her current age. She is under 100 years old. How old is Suzy?\n\r\nJason is younger than Suzy by at least 5 years. Four years ago Jason was prime, and in 4 years Jason will be prime again. How old is Jason?", "hint": "Make a list of all the possible numbers it could be, as per the clues. Then, cross them off when they don't pertain to other clues. There is only one possible answer!", "answer": "To solve for Suzy's age, we must first list all the numbers under 100 with a sum of 4:\n\r\n4, 13, 22, 31, 40\n\r\nOf these, the only prime numbers are 13 and 31. If we try the second clue on each number, we get:\n\r\n13+7=20, 2+0=2, 13-2=11 \r\n31+7=38, 3+8=11, 31-11=20 \n\r\nTherefore, Suzy must be 31. \n\n\r\nTo find Jason's age, we should first take Suzy's age (31) and subtract 5, leaving us with 26. This is the maximum possible age Jason could be. Again, listing out all the prime numbers under 26:\n\r\n2, 3, 5, 7, 11, 13, 17, 19, 23 \n\r\nIf we add four to each of these, only 3, 7, 13, and 19 stay prime. Taking these remaining 4 and subtracting four, the only one that remains prime is 7.\n\r\nTherefore, Jason must be 7.\n\n\r\nAs an interesting side note, 4139 (the street number) is prime! If you don't believe me, check for yourself!", "category": "Math", "date": "06/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is an apartment building on 4139 Main Street. There is a strange thing about floor 7 of this building ... everyone is a prime age! From the clues provided, can you decipher how old these residents are?\n\r\nIn Suzy's age, the digits have a sum of four. Seven years from now, Suzy's age, when you add the digits together, will be 20 less than her current age. She is under 100 years old. How old is Suzy?\n\r\nJason is younger than Suzy by at least 5 years. Four years ago Jason was prime, and in 4 years Jason will be prime again. How old is Jason?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo solve for Suzy's age, we must first list all the numbers under 100 with a sum of 4:\n\r\n4, 13, 22, 31, 40\n\r\nOf these, the only prime numbers are 13 and 31. If we try the second clue on each number, we get:\n\r\n13+7=20, 2+0=2, 13-2=11 \r\n31+7=38, 3+8=11, 31-11=20 \n\r\nTherefore, Suzy must be 31. \n\n\r\nTo find Jason's age, we should first take Suzy's age (31) and subtract 5, leaving us with 26. This is the maximum possible age Jason could be. Again, listing out all the prime numbers under 26:\n\r\n2, 3, 5, 7, 11, 13, 17, 19, 23 \n\r\nIf we add four to each of these, only 3, 7, 13, and 19 stay prime. Taking these remaining 4 and subtracting four, the only one that remains prime is 7.\n\r\nTherefore, Jason must be 7.\n\n\r\nAs an interesting side note, 4139 (the street number) is prime! If you don't believe me, check for yourself!\n<|im_start|>answer\nTo solve for Suzy's age, we must first list all the numbers under 100 with a sum of 4:\n\r\n4, 13, 22, 31, 40\n\r\nOf these, the only prime numbers are 13 and 31. If we try the second clue on each number, we get:\n\r\n13+7=20, 2+0=2, 13-2=11 \r\n31+7=38, 3+8=11, 31-11=20 \n\r\nTherefore, Suzy must be 31. \n\n\r\nTo find Jason's age, we should first take Suzy's age (31) and subtract 5, leaving us with 26. This is the maximum possible age Jason could be. Again, listing out all the prime numbers under 26:\n\r\n2, 3, 5, 7, 11, 13, 17, 19, 23 \n\r\nIf we add four to each of these, only 3, 7, 13, and 19 stay prime. Taking these remaining 4 and subtracting four, the only one that remains prime is 7.\n\r\nTherefore, Jason must be 7.\n\n\r\nAs an interesting side note, 4139 (the street number) is prime! If you don't believe me, check for yourself!\n<|im_end|>" }, { "id": "#4819", "title": "King's Path", "fun": 2.58, "difficulty": 2.53, "author": "arij", "desc": "A medieval king needed to work out how he could recruit fighting men for the battle ahead. However, there were so many distractions around the castle, his thinking became confused. So in order to change his daze into knights, he asked for a secluded walk to be made so he could ponder in peace. The head gardener was given the job of planting lines of high bushes. First, he planted a line running 100 paces east. Then from the end of that line he planted a line 100 paces north, then 100 west, 98 south, 98 east, 96 north, 96 west, and so on. This made a square spiral path 2 paces wide. If the king intended to walk down the middle of the path, how long was the path?", "hint": "No hint available.", "answer": "The path was 5000 paces long. If the path is straightened out into a line, its area is that of the square, 100x100 square paces. Dividing by the path width 2 gives the solution.", "category": "Math", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA medieval king needed to work out how he could recruit fighting men for the battle ahead. However, there were so many distractions around the castle, his thinking became confused. So in order to change his daze into knights, he asked for a secluded walk to be made so he could ponder in peace. The head gardener was given the job of planting lines of high bushes. First, he planted a line running 100 paces east. Then from the end of that line he planted a line 100 paces north, then 100 west, 98 south, 98 east, 96 north, 96 west, and so on. This made a square spiral path 2 paces wide. If the king intended to walk down the middle of the path, how long was the path?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe path was 5000 paces long. If the path is straightened out into a line, its area is that of the square, 100x100 square paces. Dividing by the path width 2 gives the solution.\n<|im_start|>answer\nThe path was 5000 paces long. If the path is straightened out into a line, its area is that of the square, 100x100 square paces. Dividing by the path width 2 gives the solution.\n<|im_end|>" }, { "id": "#29695", "title": "Twos and Fives", "fun": 2.58, "difficulty": 2.18, "author": "fairelamour", "desc": "We have 10 2's and 10 5's. Pick some of them, and add them together. If we pick them all, we get the sum 70. Which sums between 1 and 70 are impossible?", "hint": "1 and 3 are impossible.", "answer": "By symmetry, 67 and 69 are also impossible. Other sums can be constructed easily.\n\r\nTherefore, four sums 1, 3, 67 and 69 are impossible.", "category": "Math", "date": "04/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWe have 10 2's and 10 5's. Pick some of them, and add them together. If we pick them all, we get the sum 70. Which sums between 1 and 70 are impossible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBy symmetry, 67 and 69 are also impossible. Other sums can be constructed easily.\n\r\nTherefore, four sums 1, 3, 67 and 69 are impossible.\n<|im_start|>answer\nBy symmetry, 67 and 69 are also impossible. Other sums can be constructed easily.\n\r\nTherefore, four sums 1, 3, 67 and 69 are impossible.\n<|im_end|>" }, { "id": "#9152", "title": "Who is...", "fun": 2.58, "difficulty": 1.21, "author": "speedyg1000", "desc": "Who is your father's mother's great-grandson's aunt's brother? \n\r\nAssume that your grandmother had one child, you have one sister and one brother, and you have a son but none of your siblings do.", "hint": "No hint available.", "answer": "It can be you (if you are a boy) or your brother.", "category": "Logic", "date": "12/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWho is your father's mother's great-grandson's aunt's brother? \n\r\nAssume that your grandmother had one child, you have one sister and one brother, and you have a son but none of your siblings do.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt can be you (if you are a boy) or your brother.\n<|im_start|>answer\nIt can be you (if you are a boy) or your brother.\n<|im_end|>" }, { "id": "#2082", "title": "Pencil Problem", "fun": 2.58, "difficulty": 1.43, "author": "Mogmatt16", "desc": "A man is stuck inside of the average classroom with nothing to write with except his pencil. He is not allowed out until he has written his name on his pencil and can still write with it. How does he do this?", "hint": "He couldn't do this in a bathroom or a closet.", "answer": "He breaks it in half and writes his name on it. He then sharpens his pencil so he can write with it.", "category": "Logic", "date": "01/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is stuck inside of the average classroom with nothing to write with except his pencil. He is not allowed out until he has written his name on his pencil and can still write with it. How does he do this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe breaks it in half and writes his name on it. He then sharpens his pencil so he can write with it.\n<|im_start|>answer\nHe breaks it in half and writes his name on it. He then sharpens his pencil so he can write with it.\n<|im_end|>" }, { "id": "#28923", "title": "Big Bill's Balloon Barn", "fun": 2.58, "difficulty": 2.84, "author": "PineappleMama", "desc": "Bill, of Big Bill's Balloon Barn, is having a bad week. Not only did a multi-symptom flu bug blow through the office, but a computer bug as well. Here it is Friday morning, and he's having to make out the payroll without the use of his computer. This, of course, is harder since all five of his employees missed some work this week. Can you use the clues to figure out each employee's name, symptom, what day they left early, when they left, and then their total hours for the week?\n\r\nNames: Jerry Jones, Vanessa Williams, Jessica James, Robert Marley, Jenny Number\r\nSymptoms: Earache, Dizziness, Headache, Sneezing, Nausea\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\r\nTimes Left: 12 pm, 1 pm, 2 pm, 3 pm, 4 pm\r\nHours: 13, 14, 35, 36, 39\n\r\nUseful Information:\r\nFull Time = 40 hrs/wk, Part Time=16hrs/wk.\n\r\n1) The five employees are: \"Sneezy\", Bob, the woman who had 39 hours, the man who earned $210.00, and the employee who goes by J.J.\n\r\n2) The two part time employees are students at the local college. One has classes on Tuesday and Thursday; the other has classes on Monday, Wednesday and Friday. Bill likes seeing his employee's educating themselves, so he pays all his employees the same $6.00 per hour whether they are full time or part time.\n\r\n3) Jessica's glad that no one at work knows about the annoying Cher song her mom named her after. That would have made her headache much worse! \"Just further proof that Mondays are evil.\"\n\r\n4) Vanessa doesn't think she's as cute as the beauty queen who shares her name, but she could only handle being called a dwarf until 1pm. Of course, when the others finally caught the bug, they didn't think their symptoms were funny either.\n\r\n5) Jessica and Robert both spend Wednesday morning studying in the library. Vanessa left early 3 days before Jessica had to.\n\r\n6) Marley got nauseous, so he didn't last as long as Jenny, but he did manage to hold out one hour longer than his study buddy.\n\r\n7) Thursday's dizzy victim, who left at noon, thinks his name is ironic, since he never liked Troy Aikman, or his team.", "hint": "Bill is making out checks on Friday MORNING...which means that the PAYROLL week runs Friday through Thursday...not Monday through Friday.", "answer": "Jerry was dizzy on Thursday; he left at 12 pm, giving him 35 hours for the week.\n\r\nVanessa was \"Sneezy\" on Friday; she left at 1 pm, giving her 36 hours for the week.\n\r\nJessica had a headache on Monday; she left at 2 pm, giving her 13 hours for the week.\n\r\nRobert was nauseated on Tuesday; he left at 3 pm, giving him 14 hours for the week.\n\r\nJenny had an earache on Wednesday; she left at 4 pm, giving her 39 hours for the week.", "category": "Logic-Grid", "date": "03/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBill, of Big Bill's Balloon Barn, is having a bad week. Not only did a multi-symptom flu bug blow through the office, but a computer bug as well. Here it is Friday morning, and he's having to make out the payroll without the use of his computer. This, of course, is harder since all five of his employees missed some work this week. Can you use the clues to figure out each employee's name, symptom, what day they left early, when they left, and then their total hours for the week?\n\r\nNames: Jerry Jones, Vanessa Williams, Jessica James, Robert Marley, Jenny Number\r\nSymptoms: Earache, Dizziness, Headache, Sneezing, Nausea\r\nDays: Monday, Tuesday, Wednesday, Thursday, Friday\r\nTimes Left: 12 pm, 1 pm, 2 pm, 3 pm, 4 pm\r\nHours: 13, 14, 35, 36, 39\n\r\nUseful Information:\r\nFull Time = 40 hrs/wk, Part Time=16hrs/wk.\n\r\n1) The five employees are: \"Sneezy\", Bob, the woman who had 39 hours, the man who earned $210.00, and the employee who goes by J.J.\n\r\n2) The two part time employees are students at the local college. One has classes on Tuesday and Thursday; the other has classes on Monday, Wednesday and Friday. Bill likes seeing his employee's educating themselves, so he pays all his employees the same $6.00 per hour whether they are full time or part time.\n\r\n3) Jessica's glad that no one at work knows about the annoying Cher song her mom named her after. That would have made her headache much worse! \"Just further proof that Mondays are evil.\"\n\r\n4) Vanessa doesn't think she's as cute as the beauty queen who shares her name, but she could only handle being called a dwarf until 1pm. Of course, when the others finally caught the bug, they didn't think their symptoms were funny either.\n\r\n5) Jessica and Robert both spend Wednesday morning studying in the library. Vanessa left early 3 days before Jessica had to.\n\r\n6) Marley got nauseous, so he didn't last as long as Jenny, but he did manage to hold out one hour longer than his study buddy.\n\r\n7) Thursday's dizzy victim, who left at noon, thinks his name is ironic, since he never liked Troy Aikman, or his team.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJerry was dizzy on Thursday; he left at 12 pm, giving him 35 hours for the week.\n\r\nVanessa was \"Sneezy\" on Friday; she left at 1 pm, giving her 36 hours for the week.\n\r\nJessica had a headache on Monday; she left at 2 pm, giving her 13 hours for the week.\n\r\nRobert was nauseated on Tuesday; he left at 3 pm, giving him 14 hours for the week.\n\r\nJenny had an earache on Wednesday; she left at 4 pm, giving her 39 hours for the week.\n<|im_start|>answer\nJerry was dizzy on Thursday; he left at 12 pm, giving him 35 hours for the week.\n\r\nVanessa was \"Sneezy\" on Friday; she left at 1 pm, giving her 36 hours for the week.\n\r\nJessica had a headache on Monday; she left at 2 pm, giving her 13 hours for the week.\n\r\nRobert was nauseated on Tuesday; he left at 3 pm, giving him 14 hours for the week.\n\r\nJenny had an earache on Wednesday; she left at 4 pm, giving her 39 hours for the week.\n<|im_end|>" }, { "id": "#30218", "title": "What Number Am I?", "fun": 2.58, "difficulty": 1.58, "author": "Hana_Kimi", "desc": "I am a 4-digit number that is the same when my digits are written backwards. The sum of my outside digits is 6 times the sum of my two middle digits. What number am I?", "hint": "No hint available.", "answer": "6116. Written the same forward and backwards. 6+6=12. 1+1=2x6=12.", "category": "Math", "date": "05/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a 4-digit number that is the same when my digits are written backwards. The sum of my outside digits is 6 times the sum of my two middle digits. What number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6116. Written the same forward and backwards. 6+6=12. 1+1=2x6=12.\n<|im_start|>answer\n6116. Written the same forward and backwards. 6+6=12. 1+1=2x6=12.\n<|im_end|>" }, { "id": "#47525", "title": "The Three Children of Mr. and Mrs. Jones", "fun": 2.58, "difficulty": 2.1, "author": "RomanG417", "desc": "Mr. and Mrs. Jones have three children, all under the age of 20, but none with the same age.\r\nLast year, the product of the three ages was 224.\r\nThis year the product of the three ages is 360\r\nWhat are the children's ages now?", "hint": "Don't waste your time trying to set up an equation. All the ages are integers, go from there.", "answer": "5, 8, and 9\n\r\nThe prime factorization of 224 is 2^5*7.\n\r\nUsing this, the possible sets of three ages of which the product is 224 are:\r\n2, 7, 16\r\n4, 7, 8\r\n2, 8, 14\n\r\nNow to find out which one of these sets was their ages a year ago, add 1 to each number and multiply:\r\n3*8*17\r\n5*8*9\r\n3*9*15\n\r\nThe only set which multiplies to 360 is the 5, 8, and 9 set, meaning that these are the children's current ages.", "category": "Math", "date": "07/18/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. and Mrs. Jones have three children, all under the age of 20, but none with the same age.\r\nLast year, the product of the three ages was 224.\r\nThis year the product of the three ages is 360\r\nWhat are the children's ages now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5, 8, and 9\n\r\nThe prime factorization of 224 is 2^5*7.\n\r\nUsing this, the possible sets of three ages of which the product is 224 are:\r\n2, 7, 16\r\n4, 7, 8\r\n2, 8, 14\n\r\nNow to find out which one of these sets was their ages a year ago, add 1 to each number and multiply:\r\n3*8*17\r\n5*8*9\r\n3*9*15\n\r\nThe only set which multiplies to 360 is the 5, 8, and 9 set, meaning that these are the children's current ages.\n<|im_start|>answer\n5, 8, and 9\n\r\nThe prime factorization of 224 is 2^5*7.\n\r\nUsing this, the possible sets of three ages of which the product is 224 are:\r\n2, 7, 16\r\n4, 7, 8\r\n2, 8, 14\n\r\nNow to find out which one of these sets was their ages a year ago, add 1 to each number and multiply:\r\n3*8*17\r\n5*8*9\r\n3*9*15\n\r\nThe only set which multiplies to 360 is the 5, 8, and 9 set, meaning that these are the children's current ages.\n<|im_end|>" }, { "id": "#3549", "title": "Medical Mixup", "fun": 2.58, "difficulty": 2.23, "author": "od-1", "desc": "There are 4 doctors who all work out of one medical building.\r\nDr. Adam, Dr. Bob, Dr. Chuck and Dr. Dannielle. They must all share space in the facility. Each gets one day of the week from Monday to Thursday. But as luck would have it the facility's schedule got mixed. \n\r\nThey are a cosmetic surgeon, a podiatrist, a vet and a dentist. Their patients are Spot, Joe, Kate and Sid. Their bookings where for nasal hair removal, neutering, tooth filling and foot fungus removal.\n\r\nDr. Adam works only on Mondays and never on animals as they give him hives. \n\r\nKate requires a filling because she's a Krispy cream addict. \n\r\nFortunately, Joe was not neutered.\n\r\nDr. Bob had scheduled surgery, but not on Thursday or Wednesday; that's when he had nasal hair transplant classes. \n\r\nDr. Dannielle never took patients named Sid or ones with mushrooms protruding from their toes, and she liked pets but felt her husband was enough. \n\r\nSid was booked for cosmetic surgery on Tuesday because Wednesday he had to take his dog to be neutered. \n\r\nDr. Chuck didn't mind nasal hair, but preferred his patients to have hair all over. He also played golf Thursday-Sunday.\n\r\nSo can you reschedule everyone?", "hint": "spot is a dog", "answer": "Monday Dr. Adam podiatrist Joe foot fungus\r\nTuesday Dr. Bob cosmetic surgeon Sid nasal hair removal\r\nWednesday Dr. Chuck vet spot neutering\r\nThursday Dr. Dannielle dentist Kate tooth filling.", "category": "Logic", "date": "04/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 4 doctors who all work out of one medical building.\r\nDr. Adam, Dr. Bob, Dr. Chuck and Dr. Dannielle. They must all share space in the facility. Each gets one day of the week from Monday to Thursday. But as luck would have it the facility's schedule got mixed. \n\r\nThey are a cosmetic surgeon, a podiatrist, a vet and a dentist. Their patients are Spot, Joe, Kate and Sid. Their bookings where for nasal hair removal, neutering, tooth filling and foot fungus removal.\n\r\nDr. Adam works only on Mondays and never on animals as they give him hives. \n\r\nKate requires a filling because she's a Krispy cream addict. \n\r\nFortunately, Joe was not neutered.\n\r\nDr. Bob had scheduled surgery, but not on Thursday or Wednesday; that's when he had nasal hair transplant classes. \n\r\nDr. Dannielle never took patients named Sid or ones with mushrooms protruding from their toes, and she liked pets but felt her husband was enough. \n\r\nSid was booked for cosmetic surgery on Tuesday because Wednesday he had to take his dog to be neutered. \n\r\nDr. Chuck didn't mind nasal hair, but preferred his patients to have hair all over. He also played golf Thursday-Sunday.\n\r\nSo can you reschedule everyone?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday Dr. Adam podiatrist Joe foot fungus\r\nTuesday Dr. Bob cosmetic surgeon Sid nasal hair removal\r\nWednesday Dr. Chuck vet spot neutering\r\nThursday Dr. Dannielle dentist Kate tooth filling.\n<|im_start|>answer\nMonday Dr. Adam podiatrist Joe foot fungus\r\nTuesday Dr. Bob cosmetic surgeon Sid nasal hair removal\r\nWednesday Dr. Chuck vet spot neutering\r\nThursday Dr. Dannielle dentist Kate tooth filling.\n<|im_end|>" }, { "id": "#36643", "title": "New Releases", "fun": 2.58, "difficulty": 2.17, "author": "phrebh", "desc": "Three people (Arnold, Meathead, and Stabem) were on their way to three different record stores (Sam Goody, Tower, and Virgin) to buy the new releases, in three different formats (CD, LP, and Tape), from three different bands (Slipknot, Static X, and Testament). Using the clues below, can you determine who bought what band's album, in what format, from where?\n\r\n1. Either Arnold or Stabem bought the LP of either Slipknot or Testament.\n\r\n2. Either the CD or Tape of either Slipknot or Static X was purchased at Tower.\n\r\n3. Arnold either bought the CD or LP version of either Static X or Testament.\n\r\n4. Either the Slipknot album was purchased by Meathead or Stabem went to Sam Goody and bought a CD.\n\r\n5. Sam Goody sold either an LP or a Tape to either Meathead or Stabem.\n\r\n6. Testament's new release was either on LP or Tape and was sold at either Tower or Virgin.\n\r\n7. Tower sold either Static X or Testament to either Arnold or Stabem.\n\r\n8. Either the LP or tape was bought by Stabem at either Sam Goody or Virgin.", "hint": "No hint available.", "answer": "Arnold bought the Static X CD from Tower.\r\nMeathead bought the Slipknot Tape from Sam Goody.\r\nStabem bought the Testament LP from Virgin.", "category": "Logic-Grid", "date": "05/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people (Arnold, Meathead, and Stabem) were on their way to three different record stores (Sam Goody, Tower, and Virgin) to buy the new releases, in three different formats (CD, LP, and Tape), from three different bands (Slipknot, Static X, and Testament). Using the clues below, can you determine who bought what band's album, in what format, from where?\n\r\n1. Either Arnold or Stabem bought the LP of either Slipknot or Testament.\n\r\n2. Either the CD or Tape of either Slipknot or Static X was purchased at Tower.\n\r\n3. Arnold either bought the CD or LP version of either Static X or Testament.\n\r\n4. Either the Slipknot album was purchased by Meathead or Stabem went to Sam Goody and bought a CD.\n\r\n5. Sam Goody sold either an LP or a Tape to either Meathead or Stabem.\n\r\n6. Testament's new release was either on LP or Tape and was sold at either Tower or Virgin.\n\r\n7. Tower sold either Static X or Testament to either Arnold or Stabem.\n\r\n8. Either the LP or tape was bought by Stabem at either Sam Goody or Virgin.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nArnold bought the Static X CD from Tower.\r\nMeathead bought the Slipknot Tape from Sam Goody.\r\nStabem bought the Testament LP from Virgin.\n<|im_start|>answer\nArnold bought the Static X CD from Tower.\r\nMeathead bought the Slipknot Tape from Sam Goody.\r\nStabem bought the Testament LP from Virgin.\n<|im_end|>" }, { "id": "#26436", "title": "Greg the Golfer", "fun": 2.58, "difficulty": 2.37, "author": "lifeisgood812", "desc": "Greg the Golfer is the most talked-about golfer at his Country Club. After years of smashing windows with his slices and scooping divots, he finally got his game figured out. No matter what club he uses, the ball he hits always travels one of two distances. Greg has it worked it out so that by combining these two shots, sometimes hitting two long shots and one short shot, for example, he can play the front nine of the course in 26 strokes. He always plays in a straight line from tee to cup, since his hooks and slices are in the past. Sometimes he hits the ball past the green but he always makes up for it with his short shot. It doesn't matter to him because he always hits it one of two distances. The question is this: What are the two distances that Greg uses in hitting into history? Remember this: Greg's yardage for the first nine holes is 150 yards, 300 yards, 250 yards, 325 yards, 275 yards, 350 yards, 225 yards, 400 yards, and 425 yards.", "hint": "No hint available.", "answer": "Greg's two shots are a 150 yard drive and a 125 yard approach shot. The holes are made in the following way: 150 yards: 1 drive. 300 yards: 2 drives. 250 yards: 2 approaches. 325 yards: 3 drives, 1 approach back. 275 yards: 1 drive, 1 approach. 350 yards: 4 approaches, 1 drive back. 225 yards: 3 approaches, 1 drive back. 400 yards: 1 drive, 2 approaches. 425 yards: 2 drives, 1 approach.", "category": "Math", "date": "10/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGreg the Golfer is the most talked-about golfer at his Country Club. After years of smashing windows with his slices and scooping divots, he finally got his game figured out. No matter what club he uses, the ball he hits always travels one of two distances. Greg has it worked it out so that by combining these two shots, sometimes hitting two long shots and one short shot, for example, he can play the front nine of the course in 26 strokes. He always plays in a straight line from tee to cup, since his hooks and slices are in the past. Sometimes he hits the ball past the green but he always makes up for it with his short shot. It doesn't matter to him because he always hits it one of two distances. The question is this: What are the two distances that Greg uses in hitting into history? Remember this: Greg's yardage for the first nine holes is 150 yards, 300 yards, 250 yards, 325 yards, 275 yards, 350 yards, 225 yards, 400 yards, and 425 yards.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGreg's two shots are a 150 yard drive and a 125 yard approach shot. The holes are made in the following way: 150 yards: 1 drive. 300 yards: 2 drives. 250 yards: 2 approaches. 325 yards: 3 drives, 1 approach back. 275 yards: 1 drive, 1 approach. 350 yards: 4 approaches, 1 drive back. 225 yards: 3 approaches, 1 drive back. 400 yards: 1 drive, 2 approaches. 425 yards: 2 drives, 1 approach.\n<|im_start|>answer\nGreg's two shots are a 150 yard drive and a 125 yard approach shot. The holes are made in the following way: 150 yards: 1 drive. 300 yards: 2 drives. 250 yards: 2 approaches. 325 yards: 3 drives, 1 approach back. 275 yards: 1 drive, 1 approach. 350 yards: 4 approaches, 1 drive back. 225 yards: 3 approaches, 1 drive back. 400 yards: 1 drive, 2 approaches. 425 yards: 2 drives, 1 approach.\n<|im_end|>" }, { "id": "#17711", "title": "Quarter Lineup", "fun": 2.58, "difficulty": 2.47, "author": "jholman", "desc": "120 quarters are lined up on a table. Every second coin is replaced with a dime. Then, every third coin is replaced with a nickel. Finally, every fourth coin is replaced with a penny.\n\r\nHow much are the coins remaining on the table worth?", "hint": "Consider the value of twelve coins after the replacements.", "answer": "The value of the remaining coins is $13.80.\n\r\nSince the least common multiple of 2, 3, and 4 is 12, the value of each consecutive set of 12 coins will have the same value as the other sets after the replacements.\n\r\nHere is a diagram of the replacements for 12 coins:\r\nQQQQQQQQQQQQ\r\nQDQDQDQDQDQD\r\nQDNDQNQDNDQN\r\nQDNPQNQPNDQP\n\r\n4 quarters = $1\r\n2 dimes = $.20\r\n3 nickels = $.15\r\n3 pennies = $.03\n\r\n12 coins = $1.38\r\n120 coins = $13.80", "category": "Math", "date": "05/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n120 quarters are lined up on a table. Every second coin is replaced with a dime. Then, every third coin is replaced with a nickel. Finally, every fourth coin is replaced with a penny.\n\r\nHow much are the coins remaining on the table worth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe value of the remaining coins is $13.80.\n\r\nSince the least common multiple of 2, 3, and 4 is 12, the value of each consecutive set of 12 coins will have the same value as the other sets after the replacements.\n\r\nHere is a diagram of the replacements for 12 coins:\r\nQQQQQQQQQQQQ\r\nQDQDQDQDQDQD\r\nQDNDQNQDNDQN\r\nQDNPQNQPNDQP\n\r\n4 quarters = $1\r\n2 dimes = $.20\r\n3 nickels = $.15\r\n3 pennies = $.03\n\r\n12 coins = $1.38\r\n120 coins = $13.80\n<|im_start|>answer\nThe value of the remaining coins is $13.80.\n\r\nSince the least common multiple of 2, 3, and 4 is 12, the value of each consecutive set of 12 coins will have the same value as the other sets after the replacements.\n\r\nHere is a diagram of the replacements for 12 coins:\r\nQQQQQQQQQQQQ\r\nQDQDQDQDQDQD\r\nQDNDQNQDNDQN\r\nQDNPQNQPNDQP\n\r\n4 quarters = $1\r\n2 dimes = $.20\r\n3 nickels = $.15\r\n3 pennies = $.03\n\r\n12 coins = $1.38\r\n120 coins = $13.80\n<|im_end|>" }, { "id": "#3083", "title": "Family Photo", "fun": 2.58, "difficulty": 1.55, "author": "comet16", "desc": "A family photo has:\n\r\none grandfather, one grandmother;\r\ntwo fathers, two mothers;\r\nsix children, four grandchildren;\r\ntwo brothers, two sisters;\r\nthree sons, three daughters;\r\none father-in-law, one mother-in-law, one daughter-in-law\n\r\nWhat is the least number of people here?", "hint": "No hint available.", "answer": "8: \r\nfour children- two boys, two girls\r\ntheir mother and father\r\none set of grandparents", "category": "Logic", "date": "04/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA family photo has:\n\r\none grandfather, one grandmother;\r\ntwo fathers, two mothers;\r\nsix children, four grandchildren;\r\ntwo brothers, two sisters;\r\nthree sons, three daughters;\r\none father-in-law, one mother-in-law, one daughter-in-law\n\r\nWhat is the least number of people here?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8: \r\nfour children- two boys, two girls\r\ntheir mother and father\r\none set of grandparents\n<|im_start|>answer\n8: \r\nfour children- two boys, two girls\r\ntheir mother and father\r\none set of grandparents\n<|im_end|>" }, { "id": "#21062", "title": "Girls and Their Dates", "fun": 2.58, "difficulty": 1.92, "author": "sftbaltwty", "desc": "It was girls' night out and 6 friends decided to have a little fun by double dating with each other. Each couple spent the night at a different type of shopping store, a different type of restaurant, and a different type of movie, respectively. Using the following clues, try to piece together which girl went out with whom and where they went. Good luck!\n\r\n1. Reed and Rebecca are sisters; they did not date or go to the electronics store.\r\n2. The girls who went to the Mexican restaurant and Tawny did not see a romantic comedy. \r\n3. Rebecca wasn't in the mood for horror after buying her new dress, and neither was Jackie or Jade.\r\n4. Alix, a girl who went to the books & art store, and a girl who went to the steakhouse all live on the same street.\r\n5. There was no action that took place at the clothing store or the place where Tawny was.\r\n6. Jackie, a girl who ate Italian, and a girl who saw the romantic comedy are all 17 years old.", "hint": "No hint available.", "answer": "-Jackie, Alix, electronics, Mexican, action\r\n-Reed, Tawny, books & art, Italian, horror\r\n-Jade, Rebecca, clothing, steakhouse, romantic comedy", "category": "Logic-Grid", "date": "02/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was girls' night out and 6 friends decided to have a little fun by double dating with each other. Each couple spent the night at a different type of shopping store, a different type of restaurant, and a different type of movie, respectively. Using the following clues, try to piece together which girl went out with whom and where they went. Good luck!\n\r\n1. Reed and Rebecca are sisters; they did not date or go to the electronics store.\r\n2. The girls who went to the Mexican restaurant and Tawny did not see a romantic comedy. \r\n3. Rebecca wasn't in the mood for horror after buying her new dress, and neither was Jackie or Jade.\r\n4. Alix, a girl who went to the books & art store, and a girl who went to the steakhouse all live on the same street.\r\n5. There was no action that took place at the clothing store or the place where Tawny was.\r\n6. Jackie, a girl who ate Italian, and a girl who saw the romantic comedy are all 17 years old.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-Jackie, Alix, electronics, Mexican, action\r\n-Reed, Tawny, books & art, Italian, horror\r\n-Jade, Rebecca, clothing, steakhouse, romantic comedy\n<|im_start|>answer\n-Jackie, Alix, electronics, Mexican, action\r\n-Reed, Tawny, books & art, Italian, horror\r\n-Jade, Rebecca, clothing, steakhouse, romantic comedy\n<|im_end|>" }, { "id": "#28217", "title": "Opposites 6", "fun": 2.58, "difficulty": 2.12, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n: stands for W, E, I, G, or H\r\n< stands for G, A, C, I, or P\r\n> stands for I, Y, R, P, or S\r\n[ stands for F, S, E, D, or J\r\n] stands for E, L, J, I, or T\r\n$ stands for N, M, F, R, or U\n\r\nThe six letter code word, [<$:]>, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Safety and Danger.", "category": "Logic", "date": "01/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n: stands for W, E, I, G, or H\r\n< stands for G, A, C, I, or P\r\n> stands for I, Y, R, P, or S\r\n[ stands for F, S, E, D, or J\r\n] stands for E, L, J, I, or T\r\n$ stands for N, M, F, R, or U\n\r\nThe six letter code word, [<$:]>, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSafety and Danger.\n<|im_start|>answer\nSafety and Danger.\n<|im_end|>" }, { "id": "#28778", "title": "Taking a Test", "fun": 2.58, "difficulty": 1.56, "author": "fishmed", "desc": "Robert took a test of 20 questions. The test was graded by giving 10 points for each correct answer and deducting 5 points for each incorrect answer. Robert answered all 20 questions and received a score of 125. How many wrong answers did he have?", "hint": "No hint available.", "answer": "He had 5 wrong answers. If he had answered all 20 questions correctly, he would have scored 200. Since he scored 125, this means he lost 75 points. We must deduct 15 points for each wrong answer; 10 points that he did not earn for getting it right, plus the 5 points that are deducted for the answer being wrong. 75 lost points divided by 15 equals 5 wrong answers.", "category": "Math", "date": "02/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRobert took a test of 20 questions. The test was graded by giving 10 points for each correct answer and deducting 5 points for each incorrect answer. Robert answered all 20 questions and received a score of 125. How many wrong answers did he have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe had 5 wrong answers. If he had answered all 20 questions correctly, he would have scored 200. Since he scored 125, this means he lost 75 points. We must deduct 15 points for each wrong answer; 10 points that he did not earn for getting it right, plus the 5 points that are deducted for the answer being wrong. 75 lost points divided by 15 equals 5 wrong answers.\n<|im_start|>answer\nHe had 5 wrong answers. If he had answered all 20 questions correctly, he would have scored 200. Since he scored 125, this means he lost 75 points. We must deduct 15 points for each wrong answer; 10 points that he did not earn for getting it right, plus the 5 points that are deducted for the answer being wrong. 75 lost points divided by 15 equals 5 wrong answers.\n<|im_end|>" }, { "id": "#4717", "title": "Candy Sale", "fun": 2.58, "difficulty": 1.85, "author": "bobbrt", "desc": "The following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nChocolate truffles cost $5 per pound for the first 5 pounds, and only $3 per pound for any amount beyond the first 5 pounds. How would you compute the cost of any given amount of truffles?\n\r\na) Multiply by 5.\r\nb) Multiply by 3.\r\nc) If the amount is over 5 pounds, skip the next two statements.\r\nd) Write the result, which is the price in dollars.\r\ne) Subtract 5 from the weight in pounds.\r\nf) Skip the next three statements.\r\ng) Add 25.", "hint": "No hint available.", "answer": "c) If the amount is over 5 pounds, skip the next two statements.\r\na) Multiply by 5.\r\nf) Skip the next three statements.\r\ne) Subtract 5 from the weight in pounds.\r\nb) Multiply by 3.\r\ng) Add 25.\r\nd) Write the result, which is the price in dollars.", "category": "Logic", "date": "06/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nChocolate truffles cost $5 per pound for the first 5 pounds, and only $3 per pound for any amount beyond the first 5 pounds. How would you compute the cost of any given amount of truffles?\n\r\na) Multiply by 5.\r\nb) Multiply by 3.\r\nc) If the amount is over 5 pounds, skip the next two statements.\r\nd) Write the result, which is the price in dollars.\r\ne) Subtract 5 from the weight in pounds.\r\nf) Skip the next three statements.\r\ng) Add 25.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nc) If the amount is over 5 pounds, skip the next two statements.\r\na) Multiply by 5.\r\nf) Skip the next three statements.\r\ne) Subtract 5 from the weight in pounds.\r\nb) Multiply by 3.\r\ng) Add 25.\r\nd) Write the result, which is the price in dollars.\n<|im_start|>answer\nc) If the amount is over 5 pounds, skip the next two statements.\r\na) Multiply by 5.\r\nf) Skip the next three statements.\r\ne) Subtract 5 from the weight in pounds.\r\nb) Multiply by 3.\r\ng) Add 25.\r\nd) Write the result, which is the price in dollars.\n<|im_end|>" }, { "id": "#3139", "title": "Dead or Alive", "fun": 2.58, "difficulty": 1.14, "author": "204_blaze_41", "desc": "A wise man lived on a hill above a small town. The townspeople often approached him to solve their difficult problems and riddles. One day, two lads decided to fool him. They took a dove and set off up the hill. Standing before him, one of the lads said \"Tell me, wise man, is the dove I hold behind my back dead or alive?\" The man smiled and said \"I cannot answer your question correctly\". Even though the wise man knew the condition of the dove, why wouldn't he state whether it was dead or alive?", "hint": "No hint available.", "answer": "The man told the two lads, \"If I say the dove is alive, you will kill the bird and show me that it is dead. If I say that it is dead, you will release the dove and it will fly away. So you see I cannot answer your question\".", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA wise man lived on a hill above a small town. The townspeople often approached him to solve their difficult problems and riddles. One day, two lads decided to fool him. They took a dove and set off up the hill. Standing before him, one of the lads said \"Tell me, wise man, is the dove I hold behind my back dead or alive?\" The man smiled and said \"I cannot answer your question correctly\". Even though the wise man knew the condition of the dove, why wouldn't he state whether it was dead or alive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man told the two lads, \"If I say the dove is alive, you will kill the bird and show me that it is dead. If I say that it is dead, you will release the dove and it will fly away. So you see I cannot answer your question\".\n<|im_start|>answer\nThe man told the two lads, \"If I say the dove is alive, you will kill the bird and show me that it is dead. If I say that it is dead, you will release the dove and it will fly away. So you see I cannot answer your question\".\n<|im_end|>" }, { "id": "#29793", "title": "Three Statements", "fun": 2.58, "difficulty": 1.97, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. All humans are mortal. Socrates is human. This implies that Socrates is mortal.\n\r\n2. The next number in the series 3968, 63, 8, 3... is 2.\n\r\n3. The next number in the series 1, 3, 6, 10... is 16.", "hint": "No hint available.", "answer": "Statements 1 and 2 are true; statement 3 is false.\n\r\nStatement 1 is the simplest form of syllogism, and it's true.\n\r\nIn statement 2, each number is the square root of its preceding number increased by 1, and it's true.\n\r\nIn statement 3, the differences of neighboring terms are 2, 3, 4... and the next number should be 15, so it's false.", "category": "Logic", "date": "04/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. All humans are mortal. Socrates is human. This implies that Socrates is mortal.\n\r\n2. The next number in the series 3968, 63, 8, 3... is 2.\n\r\n3. The next number in the series 1, 3, 6, 10... is 16.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 1 and 2 are true; statement 3 is false.\n\r\nStatement 1 is the simplest form of syllogism, and it's true.\n\r\nIn statement 2, each number is the square root of its preceding number increased by 1, and it's true.\n\r\nIn statement 3, the differences of neighboring terms are 2, 3, 4... and the next number should be 15, so it's false.\n<|im_start|>answer\nStatements 1 and 2 are true; statement 3 is false.\n\r\nStatement 1 is the simplest form of syllogism, and it's true.\n\r\nIn statement 2, each number is the square root of its preceding number increased by 1, and it's true.\n\r\nIn statement 3, the differences of neighboring terms are 2, 3, 4... and the next number should be 15, so it's false.\n<|im_end|>" }, { "id": "#521", "title": "Empty and Full Glasses", "fun": 2.58, "difficulty": 1.23, "author": "kaila912", "desc": "There are 6 glasses. The 3 on the left are filled, the 3 on the right are empty. How can you make a pattern of full-empty-full-empty-full-empty with only moving or touching 1 glass?", "hint": "No hint available.", "answer": "Take the second glass to the left (it is full) and pour it in the 5th glass, then set the second glass back down.", "category": "Logic", "date": "05/30/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 6 glasses. The 3 on the left are filled, the 3 on the right are empty. How can you make a pattern of full-empty-full-empty-full-empty with only moving or touching 1 glass?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake the second glass to the left (it is full) and pour it in the 5th glass, then set the second glass back down.\n<|im_start|>answer\nTake the second glass to the left (it is full) and pour it in the 5th glass, then set the second glass back down.\n<|im_end|>" }, { "id": "#20989", "title": "The Great Heist", "fun": 2.58, "difficulty": 1.1, "author": "Sane", "desc": "4 Men stole 4 Cars during 4 different times in the same day. We know who committed the crimes. For everything else we have only uncovered 3 clues, so we are stumped to who is responsible for what. We need your help.\n\r\nThis is what we know:\n\r\n1. Carleton did not steal the Ferarri Enzo.\r\n2. Carleton stole his car immediately before Pierson did, who stole his immediately before the Pagini Zonda was stolen.\r\n3. Reynold stole the Dodge Viper, but he was not first.\n\r\nWho stole what, and when?", "hint": "No hint available.", "answer": "Reynold Stole the Dodge Viper (3). \r\nCarleton did not steal the Ferarri Enzo (1) or the Pagini Zonda (2), so it was the Shelby Cobra. \r\nPierson did not steal the Pagini Zonda (2). By elimination, Wilson stole the Pagini Zonda and Pierson stole the Ferarri Enzo. \r\nThe car that was stolen first was not the Ferrari Enzo (2), Pagini Zonda (2), Dodge Viper (3). By elimination it is the Shelby Cobra. \r\nThe car immediately after Carleton, the Ferrari Enzo, was stolen next (2), then the Pagini Zonda (2). \r\nBy elimination, the Dodge Viper was stolen last. \n\r\nIn summary: \n\r\nWilson - Pagini Zonda - 5:00 PM\r\nReynold - Dodge Viper - 11:00 PM\r\nCarleton - Sheby Cobra - 6:00 AM\r\nPierson - Ferarri Enzo - NOON", "category": "Logic-Grid", "date": "02/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 Men stole 4 Cars during 4 different times in the same day. We know who committed the crimes. For everything else we have only uncovered 3 clues, so we are stumped to who is responsible for what. We need your help.\n\r\nThis is what we know:\n\r\n1. Carleton did not steal the Ferarri Enzo.\r\n2. Carleton stole his car immediately before Pierson did, who stole his immediately before the Pagini Zonda was stolen.\r\n3. Reynold stole the Dodge Viper, but he was not first.\n\r\nWho stole what, and when?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nReynold Stole the Dodge Viper (3). \r\nCarleton did not steal the Ferarri Enzo (1) or the Pagini Zonda (2), so it was the Shelby Cobra. \r\nPierson did not steal the Pagini Zonda (2). By elimination, Wilson stole the Pagini Zonda and Pierson stole the Ferarri Enzo. \r\nThe car that was stolen first was not the Ferrari Enzo (2), Pagini Zonda (2), Dodge Viper (3). By elimination it is the Shelby Cobra. \r\nThe car immediately after Carleton, the Ferrari Enzo, was stolen next (2), then the Pagini Zonda (2). \r\nBy elimination, the Dodge Viper was stolen last. \n\r\nIn summary: \n\r\nWilson - Pagini Zonda - 5:00 PM\r\nReynold - Dodge Viper - 11:00 PM\r\nCarleton - Sheby Cobra - 6:00 AM\r\nPierson - Ferarri Enzo - NOON\n<|im_start|>answer\nReynold Stole the Dodge Viper (3). \r\nCarleton did not steal the Ferarri Enzo (1) or the Pagini Zonda (2), so it was the Shelby Cobra. \r\nPierson did not steal the Pagini Zonda (2). By elimination, Wilson stole the Pagini Zonda and Pierson stole the Ferarri Enzo. \r\nThe car that was stolen first was not the Ferrari Enzo (2), Pagini Zonda (2), Dodge Viper (3). By elimination it is the Shelby Cobra. \r\nThe car immediately after Carleton, the Ferrari Enzo, was stolen next (2), then the Pagini Zonda (2). \r\nBy elimination, the Dodge Viper was stolen last. \n\r\nIn summary: \n\r\nWilson - Pagini Zonda - 5:00 PM\r\nReynold - Dodge Viper - 11:00 PM\r\nCarleton - Sheby Cobra - 6:00 AM\r\nPierson - Ferarri Enzo - NOON\n<|im_end|>" }, { "id": "#20187", "title": "Number Grid", "fun": 2.58, "difficulty": 1.97, "author": "rose_rox", "desc": "Below is a square of numbers. What number is X?\n\r\n1 4 0 3\r\n5 8 4 7\r\n2 x 1 4\r\n6 9 5 8", "hint": "No hint available.", "answer": "X = 5. \n\r\nAlong each row, the numbers follow a +3, -4, +3 pattern.\r\nDown each column, the numbers follow a +4, -3, +4 pattern", "category": "Math", "date": "01/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBelow is a square of numbers. What number is X?\n\r\n1 4 0 3\r\n5 8 4 7\r\n2 x 1 4\r\n6 9 5 8\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nX = 5. \n\r\nAlong each row, the numbers follow a +3, -4, +3 pattern.\r\nDown each column, the numbers follow a +4, -3, +4 pattern\n<|im_start|>answer\nX = 5. \n\r\nAlong each row, the numbers follow a +3, -4, +3 pattern.\r\nDown each column, the numbers follow a +4, -3, +4 pattern\n<|im_end|>" }, { "id": "#244", "title": "What`s the product?", "fun": 2.58, "difficulty": 1.85, "author": "cruiser", "desc": "(a-x)(b-x)(c-x) ... (z-x) = ?", "hint": "No hint available.", "answer": "0\n\nOne of the terms is (x-x) which equals 0. Anything times 0 is 0.", "category": "Math", "date": "02/04/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n(a-x)(b-x)(c-x) ... (z-x) = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0\n\nOne of the terms is (x-x) which equals 0. Anything times 0 is 0.\n<|im_start|>answer\n0\n\nOne of the terms is (x-x) which equals 0. Anything times 0 is 0.\n<|im_end|>" }, { "id": "#27960", "title": "Eleven Up", "fun": 2.58, "difficulty": 2.31, "author": "shenqiang", "desc": "Four players, Goenitz, Yashiro, Shermie, and Chris, are playing a game called \"Eleven Up\". The goal of this game is to get as many pairs of cards as possible that add to 11. The game deck has 24 cards, including 2 sets numbered 0 to 11. The cards have been dealt evenly among the 4 players. \n\r\nAfter dealing, the four players have discovered that the game is a tie, because they each have the same number of pairs totaling 11.\n\r\nHere are the clues:\n\r\n1. Goenitz's 6 cards are consecutive.\r\n2. Yashiro and Shermie together have 3 of the 4 highest single cards.\r\n3. The sum of Yashiro's 2 lowest cards equals the difference between his two highest ones.\r\n4. Chris's 3 highest cards are all even, but Shermie's 3 highest ones are all odd. \r\n5. Yashiro and Shermie have 2 pairs of cards that are the same. \n\r\nWhich cards does each player have?", "hint": "Find the possible combinations of 11. Then make a chart and eliminate the impossibilities.", "answer": "Goenitz's cards are 3, 4, 5, 6, 7, and 8.\r\nYashiro's cards are 0, 1, 2, 9, 10, and 11.\r\nShermie's cards are 0, 2, 4, 7, 9, and 11.\r\nChris's cards are 1, 3, 5, 6, 8, and 10.", "category": "Logic", "date": "01/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour players, Goenitz, Yashiro, Shermie, and Chris, are playing a game called \"Eleven Up\". The goal of this game is to get as many pairs of cards as possible that add to 11. The game deck has 24 cards, including 2 sets numbered 0 to 11. The cards have been dealt evenly among the 4 players. \n\r\nAfter dealing, the four players have discovered that the game is a tie, because they each have the same number of pairs totaling 11.\n\r\nHere are the clues:\n\r\n1. Goenitz's 6 cards are consecutive.\r\n2. Yashiro and Shermie together have 3 of the 4 highest single cards.\r\n3. The sum of Yashiro's 2 lowest cards equals the difference between his two highest ones.\r\n4. Chris's 3 highest cards are all even, but Shermie's 3 highest ones are all odd. \r\n5. Yashiro and Shermie have 2 pairs of cards that are the same. \n\r\nWhich cards does each player have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGoenitz's cards are 3, 4, 5, 6, 7, and 8.\r\nYashiro's cards are 0, 1, 2, 9, 10, and 11.\r\nShermie's cards are 0, 2, 4, 7, 9, and 11.\r\nChris's cards are 1, 3, 5, 6, 8, and 10.\n<|im_start|>answer\nGoenitz's cards are 3, 4, 5, 6, 7, and 8.\r\nYashiro's cards are 0, 1, 2, 9, 10, and 11.\r\nShermie's cards are 0, 2, 4, 7, 9, and 11.\r\nChris's cards are 1, 3, 5, 6, 8, and 10.\n<|im_end|>" }, { "id": "#44033", "title": "Which President?", "fun": 2.58, "difficulty": 1.76, "author": "perrygf", "desc": "Grover Cleveland was the 22nd president of the United States. He was succeeded by Benjamin Harrison. Cleveland was then elected the 24th president, succeeding Harrison. Therefore, Cleveland, on his second election, succeeded his own successor. Which was the only other United States president to succeed his own successor?", "hint": "This is in Logic, not Trivia!", "answer": "Benjamin Harrison. He succeeded Cleveland, who was his successor.", "category": "Logic", "date": "01/31/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrover Cleveland was the 22nd president of the United States. He was succeeded by Benjamin Harrison. Cleveland was then elected the 24th president, succeeding Harrison. Therefore, Cleveland, on his second election, succeeded his own successor. Which was the only other United States president to succeed his own successor?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBenjamin Harrison. He succeeded Cleveland, who was his successor.\n<|im_start|>answer\nBenjamin Harrison. He succeeded Cleveland, who was his successor.\n<|im_end|>" }, { "id": "#24338", "title": "Frank's Fast Food Eatery", "fun": 2.58, "difficulty": 2.18, "author": "adamplovette", "desc": "FRANK'S FAST FOOD EATERY \r\nHamburger with toppings $2.25 \r\nFries $0.95 \r\nCola $0.50 \r\nCoffee $0.75 \n\r\nFrank's Fast Food Eatery offers a Saturday Soccer Team Special. When student sports teams come in wearing their uniforms and accompanied by their coaches, they can get 1 hamburger free for every 5 they purchase.\n\r\nThe entire Meadowland team wore their uniforms and went to Frank's Eatery for lunch with their 2 coaches. Each person, including the players and coaches, had 1 hamburger with toppings. Each player had a cola and shared a bag of fries with 1 other teammate. The 2 coaches each had his own order of fries and a coffee. The total bill (no tax) for the students and coaches came to $42.10.\n\r\nHow many players are on the team?", "hint": "Using the prices on the menu, estimate the possible number of players on the team.\n\r\nMake a chart, work backwards, and then guess and check.", "answer": "There were 12 players on the team.\n\r\nItems: Cost\r\n10 Hamburgers (part of special): $22.50\r\n2 Free hamburgers: $0.00\r\n2 Additional hamburgers: $4.50\r\n6 Fries for players: $5.70\r\n2 Fries for coaches: $1.90\r\n12 Colas: $6.00\r\n2 Coffees: $1.50\r\nTOTAL BILL: $42.10", "category": "Math", "date": "07/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFRANK'S FAST FOOD EATERY \r\nHamburger with toppings $2.25 \r\nFries $0.95 \r\nCola $0.50 \r\nCoffee $0.75 \n\r\nFrank's Fast Food Eatery offers a Saturday Soccer Team Special. When student sports teams come in wearing their uniforms and accompanied by their coaches, they can get 1 hamburger free for every 5 they purchase.\n\r\nThe entire Meadowland team wore their uniforms and went to Frank's Eatery for lunch with their 2 coaches. Each person, including the players and coaches, had 1 hamburger with toppings. Each player had a cola and shared a bag of fries with 1 other teammate. The 2 coaches each had his own order of fries and a coffee. The total bill (no tax) for the students and coaches came to $42.10.\n\r\nHow many players are on the team?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 12 players on the team.\n\r\nItems: Cost\r\n10 Hamburgers (part of special): $22.50\r\n2 Free hamburgers: $0.00\r\n2 Additional hamburgers: $4.50\r\n6 Fries for players: $5.70\r\n2 Fries for coaches: $1.90\r\n12 Colas: $6.00\r\n2 Coffees: $1.50\r\nTOTAL BILL: $42.10\n<|im_start|>answer\nThere were 12 players on the team.\n\r\nItems: Cost\r\n10 Hamburgers (part of special): $22.50\r\n2 Free hamburgers: $0.00\r\n2 Additional hamburgers: $4.50\r\n6 Fries for players: $5.70\r\n2 Fries for coaches: $1.90\r\n12 Colas: $6.00\r\n2 Coffees: $1.50\r\nTOTAL BILL: $42.10\n<|im_end|>" }, { "id": "#29172", "title": "Coin Collection", "fun": 2.58, "difficulty": 1.57, "author": "12345678", "desc": "A numismatist decides to divide his coin collection among his children. The oldest gets 1/2 of the collection, the next gets 1/4, the next gets 1/5, and the youngest gets the remaining 49 coins. How many coins are in the collection?", "hint": "No hint available.", "answer": "There are 980 coins in the collection.\n\r\n490 + 245 + 196 + 49 = 980", "category": "Math", "date": "03/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA numismatist decides to divide his coin collection among his children. The oldest gets 1/2 of the collection, the next gets 1/4, the next gets 1/5, and the youngest gets the remaining 49 coins. How many coins are in the collection?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 980 coins in the collection.\n\r\n490 + 245 + 196 + 49 = 980\n<|im_start|>answer\nThere are 980 coins in the collection.\n\r\n490 + 245 + 196 + 49 = 980\n<|im_end|>" }, { "id": "#36981", "title": "Military Fun 2", "fun": 2.57, "difficulty": 2.16, "author": "soccerguy0428", "desc": "Please do Military Fun first before doing this teaser. This teaser continues on from the first time the friends got together, and will give away the answer to Military Fun. So, please do that teaser first.\n\r\nThe same 7 friends are back, Stephen, Felicia, Brad, Abby, Clark, Anna, and Jessica. This time they want to go into a pretend battle. So, they invited 3 of their other friends over to make the team 5 on 5. The new friends are, Paul, Kelsey, and Luke. Those 3 will start out as Privates like everyone else did. The other 7 friends will take their rank from the last time.\n\r\nThe teams were split.\n\r\nBlue Team:\n\r\nLieutenant General Stephen\t\r\nMajor Felicia\t\t\t\r\nSergeant Abby\r\nPrivate Paul\r\nPrivate Kelsey\n\r\nRed Team:\n\r\nColonel Anna\r\nCaptain Clark\r\nSergeant Brad\r\nCorporal Jessica\r\nPrivate Luke\n\r\nThis is a list of the ranks again, just in case anyone forgot it.\r\nRanks\r\n1. Lieutenant General\r\n2. Brigadier General\r\n3. Colonel\r\n4. Lieutenant Colonel\r\n5. Major\r\n6. Captain\r\n7. First Lieutenant\r\n8. Second Lieutenant\r\n9. First Sergeant\r\n10. Sergeant\r\n11. Corporal\r\n12. Private\n\r\nEach team was given a very small base, and 15 balls (pretending to be cannon balls) to throw at each other.\n\r\nIf anyone is a Second Lieutenant or lower, and is hit by a ball, they are out. If anyone is between a First Lieutenant and a Lieutenant Colonel, they get two total hits before they are out. And if anyone is a Colonel or higher, they get three hits before they are out.\n\r\nStart:\r\nThe Red team throws 5 balls, and hits everyone once except for the General and Sergeant.\r\nThe Blue team fires 6 balls, hitting the Red team leader twice and everyone else once.\n\r\nThe Red team fires 3 balls and hits the General and the Major once each. The other one ends up missing.\r\nThe Blue team fires 2 balls and hits the lowest ranked man left, the other one misses.\n\r\nThe Red team is up again and fires 2 balls, and hits the General twice.\r\nThe Blue team throws their remaining 7 balls and hits the Red team's last player.\r\nWho was left on the blue team?", "hint": "No hint available.", "answer": "First of all, both teams could take the same number of hits. Stephen and Anna could both take 3 hits, Felicia and Clark could both take 2 hits and the other 6 members could each take 1 hit.\n\r\nSo, when the Red team throws balls and hit, it hits everyone but Abby and Stephen. That takes out Paul and Kelsey, and leaves Felicia with 1 hit left.\n\r\nWhen the Blue team fires and hits everybody once and Anna twice, that leaves Clark and Anna both with only 1 hit left.\n\r\nBack to the Red team firing their 3 balls. It hits Stephen and Felicia once, taking Felicia out of the game, and leaving Stephen with 2 hits.\n\r\nWhen the Blue team fires again, they hit the lowest ranked man, and that's Clark. So, that takes him out and just leaves Anna with one hit left.\n\r\nThe last time that the Red team fires, it hits Stephen twice taking Stephen out of the game.\n\r\nThen the blue team fires back hitting Anna, knocking out everybody on the Red team, making the people on the Blue team the winners of the battle.\n\r\nThe only person left on the Blue team is Sergeant Abby.", "category": "Logic", "date": "06/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlease do Military Fun first before doing this teaser. This teaser continues on from the first time the friends got together, and will give away the answer to Military Fun. So, please do that teaser first.\n\r\nThe same 7 friends are back, Stephen, Felicia, Brad, Abby, Clark, Anna, and Jessica. This time they want to go into a pretend battle. So, they invited 3 of their other friends over to make the team 5 on 5. The new friends are, Paul, Kelsey, and Luke. Those 3 will start out as Privates like everyone else did. The other 7 friends will take their rank from the last time.\n\r\nThe teams were split.\n\r\nBlue Team:\n\r\nLieutenant General Stephen\t\r\nMajor Felicia\t\t\t\r\nSergeant Abby\r\nPrivate Paul\r\nPrivate Kelsey\n\r\nRed Team:\n\r\nColonel Anna\r\nCaptain Clark\r\nSergeant Brad\r\nCorporal Jessica\r\nPrivate Luke\n\r\nThis is a list of the ranks again, just in case anyone forgot it.\r\nRanks\r\n1. Lieutenant General\r\n2. Brigadier General\r\n3. Colonel\r\n4. Lieutenant Colonel\r\n5. Major\r\n6. Captain\r\n7. First Lieutenant\r\n8. Second Lieutenant\r\n9. First Sergeant\r\n10. Sergeant\r\n11. Corporal\r\n12. Private\n\r\nEach team was given a very small base, and 15 balls (pretending to be cannon balls) to throw at each other.\n\r\nIf anyone is a Second Lieutenant or lower, and is hit by a ball, they are out. If anyone is between a First Lieutenant and a Lieutenant Colonel, they get two total hits before they are out. And if anyone is a Colonel or higher, they get three hits before they are out.\n\r\nStart:\r\nThe Red team throws 5 balls, and hits everyone once except for the General and Sergeant.\r\nThe Blue team fires 6 balls, hitting the Red team leader twice and everyone else once.\n\r\nThe Red team fires 3 balls and hits the General and the Major once each. The other one ends up missing.\r\nThe Blue team fires 2 balls and hits the lowest ranked man left, the other one misses.\n\r\nThe Red team is up again and fires 2 balls, and hits the General twice.\r\nThe Blue team throws their remaining 7 balls and hits the Red team's last player.\r\nWho was left on the blue team?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst of all, both teams could take the same number of hits. Stephen and Anna could both take 3 hits, Felicia and Clark could both take 2 hits and the other 6 members could each take 1 hit.\n\r\nSo, when the Red team throws balls and hit, it hits everyone but Abby and Stephen. That takes out Paul and Kelsey, and leaves Felicia with 1 hit left.\n\r\nWhen the Blue team fires and hits everybody once and Anna twice, that leaves Clark and Anna both with only 1 hit left.\n\r\nBack to the Red team firing their 3 balls. It hits Stephen and Felicia once, taking Felicia out of the game, and leaving Stephen with 2 hits.\n\r\nWhen the Blue team fires again, they hit the lowest ranked man, and that's Clark. So, that takes him out and just leaves Anna with one hit left.\n\r\nThe last time that the Red team fires, it hits Stephen twice taking Stephen out of the game.\n\r\nThen the blue team fires back hitting Anna, knocking out everybody on the Red team, making the people on the Blue team the winners of the battle.\n\r\nThe only person left on the Blue team is Sergeant Abby.\n<|im_start|>answer\nFirst of all, both teams could take the same number of hits. Stephen and Anna could both take 3 hits, Felicia and Clark could both take 2 hits and the other 6 members could each take 1 hit.\n\r\nSo, when the Red team throws balls and hit, it hits everyone but Abby and Stephen. That takes out Paul and Kelsey, and leaves Felicia with 1 hit left.\n\r\nWhen the Blue team fires and hits everybody once and Anna twice, that leaves Clark and Anna both with only 1 hit left.\n\r\nBack to the Red team firing their 3 balls. It hits Stephen and Felicia once, taking Felicia out of the game, and leaving Stephen with 2 hits.\n\r\nWhen the Blue team fires again, they hit the lowest ranked man, and that's Clark. So, that takes him out and just leaves Anna with one hit left.\n\r\nThe last time that the Red team fires, it hits Stephen twice taking Stephen out of the game.\n\r\nThen the blue team fires back hitting Anna, knocking out everybody on the Red team, making the people on the Blue team the winners of the battle.\n\r\nThe only person left on the Blue team is Sergeant Abby.\n<|im_end|>" }, { "id": "#41925", "title": "Easy Peasy", "fun": 2.57, "difficulty": 0.97, "author": "TRILLIONAIRE", "desc": "If EELS + MARK + BEST + WARY = EASY,\r\nWhat does HELP + BARK + WARD + LEAD equal?", "hint": "No hint available.", "answer": "HARD\n\r\n1st + 2nd + 3rd + 4th letter of advancing words = Answer", "category": "Logic", "date": "05/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf EELS + MARK + BEST + WARY = EASY,\r\nWhat does HELP + BARK + WARD + LEAD equal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHARD\n\r\n1st + 2nd + 3rd + 4th letter of advancing words = Answer\n<|im_start|>answer\nHARD\n\r\n1st + 2nd + 3rd + 4th letter of advancing words = Answer\n<|im_end|>" }, { "id": "#28728", "title": "Can I Borrow?", "fun": 2.57, "difficulty": 2.28, "author": "jessjspieks", "desc": "This is a teaser for people who know the US coins. My apologies to any out-of-country visitors.\n\r\nYou and a friend pass by a standard coin-operated vending machine and you decide to get a candy bar. The price is US$0.95, but after checking your pockets, you only have a dollar (US$1), and the machine only takes coins. \n\r\nYou turn to your friend and have this conversation. \n\r\nYou: Hey, do you have change for a dollar? \r\nFriend: Let's see... I have 6 US coins but, although they add up to US$1.15, I can't break a dollar. \r\nYou: Huh? Can you make change for half a dollar? \r\nFriend: No. \r\nYou: How about a quarter? \r\nFriend: Nope. And before you ask I can't make change for a dime or nickel either. \r\nYou: Really? And these 6 coins are all US government coins currently in production? \r\nFriend: Yes. \r\nYou: Well, can you just put your coins into the vending machine and buy me the candy bar, and I'll pay you back? \r\nFriend: Sorry, I'd like to, but I can't with the coins I have.\n\r\nWhat coins does your friend have?", "hint": "As the Jeopardy theme song plays and time is passing...", "answer": "Your friend has 4 dimes, a quarter, and a 50 cent piece. They all add up to US$1.15 and he doesn't have change for a dollar, US$0.50, US$0.25, US$0.10, or US$0.05. Also, and here's the trick, he can't buy the candy bar for US$0.95 because a typical US vending machine doesn't take 50 cent coins -- only quarters and below.", "category": "Math", "date": "02/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis is a teaser for people who know the US coins. My apologies to any out-of-country visitors.\n\r\nYou and a friend pass by a standard coin-operated vending machine and you decide to get a candy bar. The price is US$0.95, but after checking your pockets, you only have a dollar (US$1), and the machine only takes coins. \n\r\nYou turn to your friend and have this conversation. \n\r\nYou: Hey, do you have change for a dollar? \r\nFriend: Let's see... I have 6 US coins but, although they add up to US$1.15, I can't break a dollar. \r\nYou: Huh? Can you make change for half a dollar? \r\nFriend: No. \r\nYou: How about a quarter? \r\nFriend: Nope. And before you ask I can't make change for a dime or nickel either. \r\nYou: Really? And these 6 coins are all US government coins currently in production? \r\nFriend: Yes. \r\nYou: Well, can you just put your coins into the vending machine and buy me the candy bar, and I'll pay you back? \r\nFriend: Sorry, I'd like to, but I can't with the coins I have.\n\r\nWhat coins does your friend have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYour friend has 4 dimes, a quarter, and a 50 cent piece. They all add up to US$1.15 and he doesn't have change for a dollar, US$0.50, US$0.25, US$0.10, or US$0.05. Also, and here's the trick, he can't buy the candy bar for US$0.95 because a typical US vending machine doesn't take 50 cent coins -- only quarters and below.\n<|im_start|>answer\nYour friend has 4 dimes, a quarter, and a 50 cent piece. They all add up to US$1.15 and he doesn't have change for a dollar, US$0.50, US$0.25, US$0.10, or US$0.05. Also, and here's the trick, he can't buy the candy bar for US$0.95 because a typical US vending machine doesn't take 50 cent coins -- only quarters and below.\n<|im_end|>" }, { "id": "#14441", "title": "861 Candles", "fun": 2.57, "difficulty": 2.11, "author": "mathemagician", "desc": "I have always had the correct number of candles on each of my birthday cakes. I have had exactly one birthday cake for each year of my life. If I have blown out a total of 861 candles thus far, how old am I?\n\r\nCan you find the answer without just adding up numbers until you reach 861?", "hint": "1+ 2+ 3 + ... + n = 861 .\n\r\nTo sum up the first n positive integers, the following formula is helpful: \r\nSum = n*(n+1)/2 \r\nThink of it this way: find the smaller of two consecutive positive integers such that half the product of the integers is 861.", "answer": "41\n\r\nIf n = 41 , we see that:\n\r\nS = 41(41+1)/2 = 41(42)/2 = 861.\n\r\nThus, if you add up the integers from 1 to 41, you will get a total of 861.", "category": "Math", "date": "08/20/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have always had the correct number of candles on each of my birthday cakes. I have had exactly one birthday cake for each year of my life. If I have blown out a total of 861 candles thus far, how old am I?\n\r\nCan you find the answer without just adding up numbers until you reach 861?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n41\n\r\nIf n = 41 , we see that:\n\r\nS = 41(41+1)/2 = 41(42)/2 = 861.\n\r\nThus, if you add up the integers from 1 to 41, you will get a total of 861.\n<|im_start|>answer\n41\n\r\nIf n = 41 , we see that:\n\r\nS = 41(41+1)/2 = 41(42)/2 = 861.\n\r\nThus, if you add up the integers from 1 to 41, you will get a total of 861.\n<|im_end|>" }, { "id": "#331", "title": "How Many Students Got an A?", "fun": 2.57, "difficulty": 1.61, "author": "Phyllis", "desc": "The teacher has finished grading the math papers at West High School. The class size is under 30. One third of the class got a `B`, one fourth got a `B-` and one sixth got a `C`. One eighth of the class flunked and the remainder of the class received an `A`.\n\r\nHow many students in the class received an `A`?", "hint": "No hint available.", "answer": "Find a common denominator for 3, 4, 6 and 8. The only common denominator smaller than 30 is 24. Therefore, the class size was 24 and the grades were:\r\nB: 8\r\nB-: 6\r\nC: 4\r\nD/F: 3\r\nThe number of students who received A`s was 3 (24 - 21)", "category": "Math", "date": "03/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe teacher has finished grading the math papers at West High School. The class size is under 30. One third of the class got a `B`, one fourth got a `B-` and one sixth got a `C`. One eighth of the class flunked and the remainder of the class received an `A`.\n\r\nHow many students in the class received an `A`?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFind a common denominator for 3, 4, 6 and 8. The only common denominator smaller than 30 is 24. Therefore, the class size was 24 and the grades were:\r\nB: 8\r\nB-: 6\r\nC: 4\r\nD/F: 3\r\nThe number of students who received A`s was 3 (24 - 21)\n<|im_start|>answer\nFind a common denominator for 3, 4, 6 and 8. The only common denominator smaller than 30 is 24. Therefore, the class size was 24 and the grades were:\r\nB: 8\r\nB-: 6\r\nC: 4\r\nD/F: 3\r\nThe number of students who received A`s was 3 (24 - 21)\n<|im_end|>" }, { "id": "#23931", "title": "Cluedo Weekend", "fun": 2.57, "difficulty": 0.72, "author": "katey", "desc": "During a recent Cluedo weekend, four games were played. \r\nIn one game Miss Scarlet used the spanner, but not in the library. \r\nIn another game the rope was used in the study, but not by Colonel Mustard. \r\nDuring one game the gun was used in the conservatory, whilst in another game Professor Plum was not to be found in the library. Colonel Mustard was never in the conservatory and Mrs White never used the rope.\r\nThe lead piping may or may not have been used in the kitchen. \r\nCan you determine who used what and where?", "hint": "No hint available.", "answer": "Culprit Weapon Location\r\nMiss Scarlet spanner kitchen\r\nProfessor Plum rope study\r\nColonel Mustard lead piping library\r\nMrs White gun conservatory", "category": "Logic-Grid", "date": "06/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a recent Cluedo weekend, four games were played. \r\nIn one game Miss Scarlet used the spanner, but not in the library. \r\nIn another game the rope was used in the study, but not by Colonel Mustard. \r\nDuring one game the gun was used in the conservatory, whilst in another game Professor Plum was not to be found in the library. Colonel Mustard was never in the conservatory and Mrs White never used the rope.\r\nThe lead piping may or may not have been used in the kitchen. \r\nCan you determine who used what and where?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCulprit Weapon Location\r\nMiss Scarlet spanner kitchen\r\nProfessor Plum rope study\r\nColonel Mustard lead piping library\r\nMrs White gun conservatory\n<|im_start|>answer\nCulprit Weapon Location\r\nMiss Scarlet spanner kitchen\r\nProfessor Plum rope study\r\nColonel Mustard lead piping library\r\nMrs White gun conservatory\n<|im_end|>" }, { "id": "#36466", "title": "Knights & Knaves", "fun": 2.57, "difficulty": 1.05, "author": "ChRmD1", "desc": "A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet two inhabitants: Amy and Brittany. \n\r\nAmy tells you that Brittany is a knave. Brittany says, 'Neither Amy nor I are knaves.'\n\r\nWhat are Amy and Brittany?", "hint": "Guess and Check", "answer": "Take Amy's statement and assume it's true. If Brittany is a knave, that means that she is lying. That would mean that one of them is a knave, which would still be true. If Amy was lying, then Brittany would be telling the truth that neither of them were knaves, which would contradict Amy's lie. Therefore, Amy is a knight, and Brittany is a knave.", "category": "Logic", "date": "04/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet two inhabitants: Amy and Brittany. \n\r\nAmy tells you that Brittany is a knave. Brittany says, 'Neither Amy nor I are knaves.'\n\r\nWhat are Amy and Brittany?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake Amy's statement and assume it's true. If Brittany is a knave, that means that she is lying. That would mean that one of them is a knave, which would still be true. If Amy was lying, then Brittany would be telling the truth that neither of them were knaves, which would contradict Amy's lie. Therefore, Amy is a knight, and Brittany is a knave.\n<|im_start|>answer\nTake Amy's statement and assume it's true. If Brittany is a knave, that means that she is lying. That would mean that one of them is a knave, which would still be true. If Amy was lying, then Brittany would be telling the truth that neither of them were knaves, which would contradict Amy's lie. Therefore, Amy is a knight, and Brittany is a knave.\n<|im_end|>" }, { "id": "#26108", "title": "Housewarming Gifts", "fun": 2.57, "difficulty": 0.63, "author": "dcf525", "desc": "After I moved into my new apartment, four friends stopped by to see the place. Knowing my love of plants, each brought me a different type as a housewarming gift. The new plants now occupy different spots in the apartment. Can you determine who gave me which plant and where it now resides?\n\r\nFriends: Natasha, David, Carmen, Chris\n\r\nPlants: Cactus, Pothos, Spider plant, Zebra plant\n\r\nLocations: Bathroom, Coffee table, Kitchen, Stereo\n\r\n1. My brother David brought me the zebra plant, which I didn't hang in the bathroom.\n\r\n2. A woman brought the plant that I placed next to the kitchen window.\n\r\n3. Natasha (who didn't bring the cactus) didn't bring the plant that now hangs in the bathroom.\n\r\n4. Chris brought the plant that is now on the coffee table.\n\r\n5. Carmen didn't bring the cactus or the pothos.", "hint": "Carmen is female.", "answer": "Natasha, pothos, kitchen window\r\nDavid, zebra plant, stereo\r\nCarmen, spider plant, bathroom\r\nChris, cactus, coffee table", "category": "Logic-Grid", "date": "09/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter I moved into my new apartment, four friends stopped by to see the place. Knowing my love of plants, each brought me a different type as a housewarming gift. The new plants now occupy different spots in the apartment. Can you determine who gave me which plant and where it now resides?\n\r\nFriends: Natasha, David, Carmen, Chris\n\r\nPlants: Cactus, Pothos, Spider plant, Zebra plant\n\r\nLocations: Bathroom, Coffee table, Kitchen, Stereo\n\r\n1. My brother David brought me the zebra plant, which I didn't hang in the bathroom.\n\r\n2. A woman brought the plant that I placed next to the kitchen window.\n\r\n3. Natasha (who didn't bring the cactus) didn't bring the plant that now hangs in the bathroom.\n\r\n4. Chris brought the plant that is now on the coffee table.\n\r\n5. Carmen didn't bring the cactus or the pothos.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNatasha, pothos, kitchen window\r\nDavid, zebra plant, stereo\r\nCarmen, spider plant, bathroom\r\nChris, cactus, coffee table\n<|im_start|>answer\nNatasha, pothos, kitchen window\r\nDavid, zebra plant, stereo\r\nCarmen, spider plant, bathroom\r\nChris, cactus, coffee table\n<|im_end|>" }, { "id": "#18457", "title": "Battleship Tournament", "fun": 2.57, "difficulty": 3.04, "author": "Poker", "desc": "The first round of the Children's Battleship Tournament has just been concluded. Our ten contenders (including Roger and Lila) have just concluded their first five exciting matches. Each match consisted of two players facing off against each other trying to guess the locations of the other player's ships. (The Carrier covers 5 squares, the Battleship covers 4 squares, the Destroyer and Submarine each cover 3 squares, and the Patrol Boat covers 2 squares.) In the end of each match, only one of the winner's ships remained - and it was a different one in each match! From the information given, can you determine the full name of the winner and loser of each match, as well as the remaining ship of the winner?\n\r\n1. Alexis Chartel, although managing to sink her opponent's Carrier and Patrol Boat, still lost; her opponent was not surnamed Roon.\r\n2. The surviving ship of the kid whose last name is Azzuro (who is not Jason) is shorter than the surviving ship of the player that beat the kid surnamed Yeller.\r\n3. The kid who defeated Charlie won because of his or her surviving Submarine.\r\n4. Fred (who is not surnamed Blanc) lost to the kid who's last name is Black (who is not Bart).\r\n5. One of the matches was between the players surnamed Lavender and Tanger.\r\n6. Three - and only three - of the matches were between one boy and one girl.\r\n7. The five games were the one Stacie won (but the loser was not surnamed Chartel), the one Patty lost, the one won by the boy who's last name is Brown, the one lost by the kid who's last name is Blanc, and the one where the only surviving ship was a Patrol Boat (who's last name is not Black).\r\n8. Bart managed to have his Carrier survive the entire game, thus winning his game.\r\n9. The kids surnamed Peach and Lavender had the same result in their matches.\r\n10. Georgia Roon won her match, but not against Patty or Charlie.", "hint": "In case you need all the kid's names:\r\nThe boys are Bart, Charlie, Fred, Jason, and Roger.\r\nThe girls are Alexis, Georgia, Lila, Patty, and Stacie.\r\nThe last names are Azzuro, Black, Blanc, Brown, Chartrel, Lavender, Peach, Roon, Tanger, and Yeller.", "answer": "From clue 1, Alexis' last name is Chartel, and she lost. From clue 3. Charlie lost the game where the surviving ship was the Submarine. From clue 4, Fred lost to Black. From clue 8, Bart won the game where the surviving ship was the Carrier; from clue 4, he is not Black, and from clue 1, he did not defeat Alexis, so he was in a fourth game. From clue 10, Georgia's last name is Roon, and she won, but not against Charlie, and from clue 1, not against Alexis, so she was in a fifth match. So five matches are:\r\n_____ _____ beat Alexis Chartel by a _____.\r\nBart _____ beat _____ _____ by a Carrier.\r\n_____ _____ beat Charlie _____ by a Submarine.\r\n_____ Black beat Fred _____ by a _____.\r\nGeorgia Roon beat _____ _____ by a _____.\r\nPatty did not lose to Georgia (clue 10); she lost to Bart. Alexis Charlet was not defeated by Stacie (clue 7), nor was the surviving ship the Patrol Boat (clue 1); she was defeated by Brown (only one left in clue 7). Fred is not Blanc (clue 4), nor was the surviving ship the Patrol Boat (clue 7); he was defeated by Stacie (only one left in clue 7). Charlie is Blanc (only one left in clue 7), so Georgia Roon won with her Patrol Boat (only one left in clue 7). Meaning:\r\nStacie Black beat Fred _____ by a _____\r\nBart _____ beat Patty _____ by a Carrier.\r\n_____ Brown beat Alexis Chartel by a _____.\r\n_____ _____ beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat _____ _____ by a Patrol Boat.\r\nThe only match in which Lavender and Tanger could face each other is the one where Bart beat Patty - but we don't know which last name goes with which kid. The only remaining winner that Azzuro could be is the one that beat Charlie. Yeller cannot have lost to Georgia (Patrol Boat is shorter than Submarine - clue 2); he is Fred, and his opponent won with a Battleship (only remaining ship longer than a Submarine - clue 2), so Brown beat Alexis with a Destroyer (only ship left). Meaning:\r\nStacie Black beat Fred Yeller by a Battleship.\r\nBart _____ beat Patty _____ by a Carrier.\r\n_____ Brown beat Alexis Chartrel by a Destroyer.\r\n_____ Azzuro beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat _____ _____ by a Patrol Boat.\r\nThe only place for the last name Peach is as the kid who lost to Georgia. Since Peach lost, Lavender must have lost (clue 9) and Tanger must have won. Two of the matches are known to be between a boy and a girl. The other three must be one between a boy and a girl (clue 6), one between two boys (two of the unplaced kids are boys, and only one of them could be in the third boy/girl match), and one between two girls (two of the placed kids with unplaced opponents are girls, and only one of them could be in the third boy/girl match). Charlie must be facing a boy who's last name is Azzuro, but it's not Jason (clue 2); it's Roger. Brown cannot be Lila (clue 7); he's Jason, so Lila is Peach (only possibility).\n\r\nIn summary:\r\nBart Tanger beat Patty Lavender by a Carrier.\r\nStacie Black beat Fred Yeller by a Battleship.\r\nJason Brown beat Alexis Chartel by a Destroyer.\r\nRoger Azzuro beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat Lila Peach by a Patrol Boat.", "category": "Logic", "date": "08/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe first round of the Children's Battleship Tournament has just been concluded. Our ten contenders (including Roger and Lila) have just concluded their first five exciting matches. Each match consisted of two players facing off against each other trying to guess the locations of the other player's ships. (The Carrier covers 5 squares, the Battleship covers 4 squares, the Destroyer and Submarine each cover 3 squares, and the Patrol Boat covers 2 squares.) In the end of each match, only one of the winner's ships remained - and it was a different one in each match! From the information given, can you determine the full name of the winner and loser of each match, as well as the remaining ship of the winner?\n\r\n1. Alexis Chartel, although managing to sink her opponent's Carrier and Patrol Boat, still lost; her opponent was not surnamed Roon.\r\n2. The surviving ship of the kid whose last name is Azzuro (who is not Jason) is shorter than the surviving ship of the player that beat the kid surnamed Yeller.\r\n3. The kid who defeated Charlie won because of his or her surviving Submarine.\r\n4. Fred (who is not surnamed Blanc) lost to the kid who's last name is Black (who is not Bart).\r\n5. One of the matches was between the players surnamed Lavender and Tanger.\r\n6. Three - and only three - of the matches were between one boy and one girl.\r\n7. The five games were the one Stacie won (but the loser was not surnamed Chartel), the one Patty lost, the one won by the boy who's last name is Brown, the one lost by the kid who's last name is Blanc, and the one where the only surviving ship was a Patrol Boat (who's last name is not Black).\r\n8. Bart managed to have his Carrier survive the entire game, thus winning his game.\r\n9. The kids surnamed Peach and Lavender had the same result in their matches.\r\n10. Georgia Roon won her match, but not against Patty or Charlie.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom clue 1, Alexis' last name is Chartel, and she lost. From clue 3. Charlie lost the game where the surviving ship was the Submarine. From clue 4, Fred lost to Black. From clue 8, Bart won the game where the surviving ship was the Carrier; from clue 4, he is not Black, and from clue 1, he did not defeat Alexis, so he was in a fourth game. From clue 10, Georgia's last name is Roon, and she won, but not against Charlie, and from clue 1, not against Alexis, so she was in a fifth match. So five matches are:\r\n_____ _____ beat Alexis Chartel by a _____.\r\nBart _____ beat _____ _____ by a Carrier.\r\n_____ _____ beat Charlie _____ by a Submarine.\r\n_____ Black beat Fred _____ by a _____.\r\nGeorgia Roon beat _____ _____ by a _____.\r\nPatty did not lose to Georgia (clue 10); she lost to Bart. Alexis Charlet was not defeated by Stacie (clue 7), nor was the surviving ship the Patrol Boat (clue 1); she was defeated by Brown (only one left in clue 7). Fred is not Blanc (clue 4), nor was the surviving ship the Patrol Boat (clue 7); he was defeated by Stacie (only one left in clue 7). Charlie is Blanc (only one left in clue 7), so Georgia Roon won with her Patrol Boat (only one left in clue 7). Meaning:\r\nStacie Black beat Fred _____ by a _____\r\nBart _____ beat Patty _____ by a Carrier.\r\n_____ Brown beat Alexis Chartel by a _____.\r\n_____ _____ beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat _____ _____ by a Patrol Boat.\r\nThe only match in which Lavender and Tanger could face each other is the one where Bart beat Patty - but we don't know which last name goes with which kid. The only remaining winner that Azzuro could be is the one that beat Charlie. Yeller cannot have lost to Georgia (Patrol Boat is shorter than Submarine - clue 2); he is Fred, and his opponent won with a Battleship (only remaining ship longer than a Submarine - clue 2), so Brown beat Alexis with a Destroyer (only ship left). Meaning:\r\nStacie Black beat Fred Yeller by a Battleship.\r\nBart _____ beat Patty _____ by a Carrier.\r\n_____ Brown beat Alexis Chartrel by a Destroyer.\r\n_____ Azzuro beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat _____ _____ by a Patrol Boat.\r\nThe only place for the last name Peach is as the kid who lost to Georgia. Since Peach lost, Lavender must have lost (clue 9) and Tanger must have won. Two of the matches are known to be between a boy and a girl. The other three must be one between a boy and a girl (clue 6), one between two boys (two of the unplaced kids are boys, and only one of them could be in the third boy/girl match), and one between two girls (two of the placed kids with unplaced opponents are girls, and only one of them could be in the third boy/girl match). Charlie must be facing a boy who's last name is Azzuro, but it's not Jason (clue 2); it's Roger. Brown cannot be Lila (clue 7); he's Jason, so Lila is Peach (only possibility).\n\r\nIn summary:\r\nBart Tanger beat Patty Lavender by a Carrier.\r\nStacie Black beat Fred Yeller by a Battleship.\r\nJason Brown beat Alexis Chartel by a Destroyer.\r\nRoger Azzuro beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat Lila Peach by a Patrol Boat.\n<|im_start|>answer\nFrom clue 1, Alexis' last name is Chartel, and she lost. From clue 3. Charlie lost the game where the surviving ship was the Submarine. From clue 4, Fred lost to Black. From clue 8, Bart won the game where the surviving ship was the Carrier; from clue 4, he is not Black, and from clue 1, he did not defeat Alexis, so he was in a fourth game. From clue 10, Georgia's last name is Roon, and she won, but not against Charlie, and from clue 1, not against Alexis, so she was in a fifth match. So five matches are:\r\n_____ _____ beat Alexis Chartel by a _____.\r\nBart _____ beat _____ _____ by a Carrier.\r\n_____ _____ beat Charlie _____ by a Submarine.\r\n_____ Black beat Fred _____ by a _____.\r\nGeorgia Roon beat _____ _____ by a _____.\r\nPatty did not lose to Georgia (clue 10); she lost to Bart. Alexis Charlet was not defeated by Stacie (clue 7), nor was the surviving ship the Patrol Boat (clue 1); she was defeated by Brown (only one left in clue 7). Fred is not Blanc (clue 4), nor was the surviving ship the Patrol Boat (clue 7); he was defeated by Stacie (only one left in clue 7). Charlie is Blanc (only one left in clue 7), so Georgia Roon won with her Patrol Boat (only one left in clue 7). Meaning:\r\nStacie Black beat Fred _____ by a _____\r\nBart _____ beat Patty _____ by a Carrier.\r\n_____ Brown beat Alexis Chartel by a _____.\r\n_____ _____ beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat _____ _____ by a Patrol Boat.\r\nThe only match in which Lavender and Tanger could face each other is the one where Bart beat Patty - but we don't know which last name goes with which kid. The only remaining winner that Azzuro could be is the one that beat Charlie. Yeller cannot have lost to Georgia (Patrol Boat is shorter than Submarine - clue 2); he is Fred, and his opponent won with a Battleship (only remaining ship longer than a Submarine - clue 2), so Brown beat Alexis with a Destroyer (only ship left). Meaning:\r\nStacie Black beat Fred Yeller by a Battleship.\r\nBart _____ beat Patty _____ by a Carrier.\r\n_____ Brown beat Alexis Chartrel by a Destroyer.\r\n_____ Azzuro beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat _____ _____ by a Patrol Boat.\r\nThe only place for the last name Peach is as the kid who lost to Georgia. Since Peach lost, Lavender must have lost (clue 9) and Tanger must have won. Two of the matches are known to be between a boy and a girl. The other three must be one between a boy and a girl (clue 6), one between two boys (two of the unplaced kids are boys, and only one of them could be in the third boy/girl match), and one between two girls (two of the placed kids with unplaced opponents are girls, and only one of them could be in the third boy/girl match). Charlie must be facing a boy who's last name is Azzuro, but it's not Jason (clue 2); it's Roger. Brown cannot be Lila (clue 7); he's Jason, so Lila is Peach (only possibility).\n\r\nIn summary:\r\nBart Tanger beat Patty Lavender by a Carrier.\r\nStacie Black beat Fred Yeller by a Battleship.\r\nJason Brown beat Alexis Chartel by a Destroyer.\r\nRoger Azzuro beat Charlie Blanc by a Submarine.\r\nGeorgia Roon beat Lila Peach by a Patrol Boat.\n<|im_end|>" }, { "id": "#21516", "title": "How Old is the House?", "fun": 2.57, "difficulty": 0.76, "author": "tsimkin", "desc": "Gretchen and Henry were looking to buy a house together, and finally found one with a beautifully landscaped yard, plenty of bedrooms, and a beautiful tree out front. They asked the owner how old the house was, and this was his reply:\n\r\n\"I planted that tree when the house was built. It was 7 feet tall at the time. It has grown 3 feet each year, and at the end of this past full year, it was four times its original height.\"\n\r\n\"But how old is the house?\" asked Henry.\n\r\nGretchen said, \"Don't be so dense. He just told us.\"\n\r\nSo, how old is the house?", "hint": "No hint available.", "answer": "The house is 7 years old.\n\r\nThe tree height is 28 feet, since it is four times its original height.\n\r\nTo figure out the age of the tree, let x = age of the tree in years. The height of the tree is then 7 + 3x. Since we know that the tree is now 28 feet, we can say:\r\n28 = 7 + 3x\r\n21 = 3x\r\n7 = x\n\r\nSo the tree must be 7 years old, making the house just as old.", "category": "Math", "date": "03/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGretchen and Henry were looking to buy a house together, and finally found one with a beautifully landscaped yard, plenty of bedrooms, and a beautiful tree out front. They asked the owner how old the house was, and this was his reply:\n\r\n\"I planted that tree when the house was built. It was 7 feet tall at the time. It has grown 3 feet each year, and at the end of this past full year, it was four times its original height.\"\n\r\n\"But how old is the house?\" asked Henry.\n\r\nGretchen said, \"Don't be so dense. He just told us.\"\n\r\nSo, how old is the house?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe house is 7 years old.\n\r\nThe tree height is 28 feet, since it is four times its original height.\n\r\nTo figure out the age of the tree, let x = age of the tree in years. The height of the tree is then 7 + 3x. Since we know that the tree is now 28 feet, we can say:\r\n28 = 7 + 3x\r\n21 = 3x\r\n7 = x\n\r\nSo the tree must be 7 years old, making the house just as old.\n<|im_start|>answer\nThe house is 7 years old.\n\r\nThe tree height is 28 feet, since it is four times its original height.\n\r\nTo figure out the age of the tree, let x = age of the tree in years. The height of the tree is then 7 + 3x. Since we know that the tree is now 28 feet, we can say:\r\n28 = 7 + 3x\r\n21 = 3x\r\n7 = x\n\r\nSo the tree must be 7 years old, making the house just as old.\n<|im_end|>" }, { "id": "#11602", "title": "Kidnapped!", "fun": 2.57, "difficulty": 1.73, "author": "horse_luver", "desc": "Four strong men kidnap a man. They tie him up tightly and lock all the doors. One of the men says \"We will each make 2 statements. If you can tell who always lies and who always tells the truth, we will release you.\"\n\r\n#1 said: \r\n3 people are lying.\r\nI tell the truth.\n\r\n#2 said: \r\n#1 is a liar.\r\n#3 tells the truth.\n\r\n# 3 said: \r\n#2 tells the truth.\r\n#1 tells lies.\n\r\n#4 said: \r\n#1 tells the truth.\r\n#3 lies.\n\r\nWho lies and who tells the truth?", "hint": "No hint available.", "answer": "Let us assume #1 tells the truth.\r\nIn saying that 3 people lie and he tells the truth, he is saying everyone but himself lies. If we look at #4s first statement, that #1 tells the truth, everyone cannot lie. Therefore, both #1 and #4 lie. #2, therefore, must tell the truth, because he said that #1 lies. #2, in saying that #3 tells the truth in his second statement, must be telling the truth, so #3 also tells the truth.\n\r\nSummary:\r\n#1 lies.\r\n#2 tells the truth.\r\n#3 tells the truth.\r\n#4 lies.", "category": "Logic", "date": "04/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour strong men kidnap a man. They tie him up tightly and lock all the doors. One of the men says \"We will each make 2 statements. If you can tell who always lies and who always tells the truth, we will release you.\"\n\r\n#1 said: \r\n3 people are lying.\r\nI tell the truth.\n\r\n#2 said: \r\n#1 is a liar.\r\n#3 tells the truth.\n\r\n# 3 said: \r\n#2 tells the truth.\r\n#1 tells lies.\n\r\n#4 said: \r\n#1 tells the truth.\r\n#3 lies.\n\r\nWho lies and who tells the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet us assume #1 tells the truth.\r\nIn saying that 3 people lie and he tells the truth, he is saying everyone but himself lies. If we look at #4s first statement, that #1 tells the truth, everyone cannot lie. Therefore, both #1 and #4 lie. #2, therefore, must tell the truth, because he said that #1 lies. #2, in saying that #3 tells the truth in his second statement, must be telling the truth, so #3 also tells the truth.\n\r\nSummary:\r\n#1 lies.\r\n#2 tells the truth.\r\n#3 tells the truth.\r\n#4 lies.\n<|im_start|>answer\nLet us assume #1 tells the truth.\r\nIn saying that 3 people lie and he tells the truth, he is saying everyone but himself lies. If we look at #4s first statement, that #1 tells the truth, everyone cannot lie. Therefore, both #1 and #4 lie. #2, therefore, must tell the truth, because he said that #1 lies. #2, in saying that #3 tells the truth in his second statement, must be telling the truth, so #3 also tells the truth.\n\r\nSummary:\r\n#1 lies.\r\n#2 tells the truth.\r\n#3 tells the truth.\r\n#4 lies.\n<|im_end|>" }, { "id": "#26387", "title": "Confusing Math", "fun": 2.57, "difficulty": 2.31, "author": "stormtrooper", "desc": "A9543B represents a six-digit number in which A and B are digits different from each other. The number is divisible by 11 and also by 8.\n\r\nWhat digit does A represent?", "hint": "The six-digit number is divisible by 8 and 11. Find B first.", "answer": "This might be a little confusing:\n\r\nSince the number is divisible by 8, the number 43B formed by the last three digits of the given number is divisible by 8. Digit B must be 2.\n\r\nSince A95432 is divisible by 11, the difference between the sum of its odd-place digits and the sum of its even-place digits is 0 or a multiple of 11. In this case, the difference is 0. Then (A+5+3)-(9+4+2)=0 is equivalent to A+8=15 or A=7.\n\r\nB=2\r\nA=7", "category": "Math", "date": "10/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA9543B represents a six-digit number in which A and B are digits different from each other. The number is divisible by 11 and also by 8.\n\r\nWhat digit does A represent?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis might be a little confusing:\n\r\nSince the number is divisible by 8, the number 43B formed by the last three digits of the given number is divisible by 8. Digit B must be 2.\n\r\nSince A95432 is divisible by 11, the difference between the sum of its odd-place digits and the sum of its even-place digits is 0 or a multiple of 11. In this case, the difference is 0. Then (A+5+3)-(9+4+2)=0 is equivalent to A+8=15 or A=7.\n\r\nB=2\r\nA=7\n<|im_start|>answer\nThis might be a little confusing:\n\r\nSince the number is divisible by 8, the number 43B formed by the last three digits of the given number is divisible by 8. Digit B must be 2.\n\r\nSince A95432 is divisible by 11, the difference between the sum of its odd-place digits and the sum of its even-place digits is 0 or a multiple of 11. In this case, the difference is 0. Then (A+5+3)-(9+4+2)=0 is equivalent to A+8=15 or A=7.\n\r\nB=2\r\nA=7\n<|im_end|>" }, { "id": "#27979", "title": "The Tourist Group", "fun": 2.57, "difficulty": 2.35, "author": "brules370", "desc": "A tourist group of 86 people broke up into two groups. The smaller group went to the beach, and the bigger group went to see a water mill. The following statements are all true. How many people were in each group?\r\na) A quarter of the people in one of the groups is more than the number of people in the other group.\r\nb) One of the groups contains 6 times as many women as men.\r\nc) One of the groups contains only married couples.\r\nd) The number of people in one of the groups is divisible by 4.\r\ne) One of the groups contains 8 times as many people who are younger than 50 as those who are at least 50 years old.", "hint": "No hint available.", "answer": "The first thing is to make this question an equation. The equation is x+y=86. x is the larger group and y is the smaller group. So, y=86-x. So, x+86-x=86. If the first statement is true then ¼(x)>y. Since y=86-x, then ¼(x)>86-x. Now find out the greatest possible number that will satisfy the equation ¼(x)>86-x. The largest number y could be is 17. The smallest number x could be is 69.\r\nIf c) is true, then one of the groups must be even since \"couples\" are the multiples of 2 (1 couple consists of 2 people, 2 couples consists of 4 people). Then, you figure out that 1 group affects the other group. If there is 1 more person in group x, then there is one less person in group y. So, that means that both group must be even or else both groups are odd and no group will satisfy c). So x must consist of 70, 72, 74, 76, 78, 80, 82, 84, or 86 people and y must consist of 16, 14, 12, 10, 8, 6, 4, 2, or 0 people. Now try to make the groups satisfy e). Substitute c for young people and o for old people. The equation is 8o=c. So, o+c equals the number of people in one of the groups. If c=8o, then that will mean o+8o equals the number of people in one of the groups. Then, simplified the equation.\r\no+8o=9o.\r\nSo 9o equal the number of people in one of the groups. So one of the groups has to be a multiple of 9. Since y consists of a group that has 16 people or under, then the only multiple of 9 is 9. But the groups have to consist of an even number of people, so group x must satisfy e). The only multiples of 9 above 70 and under 86 are 72 and 81. But, the number has to be even. So, group x consists of 72 people and y consists of 14 people. \r\nSo, the answer is that there are 72 people that went to see the water mill and 14 people went to the beach.", "category": "Logic", "date": "01/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA tourist group of 86 people broke up into two groups. The smaller group went to the beach, and the bigger group went to see a water mill. The following statements are all true. How many people were in each group?\r\na) A quarter of the people in one of the groups is more than the number of people in the other group.\r\nb) One of the groups contains 6 times as many women as men.\r\nc) One of the groups contains only married couples.\r\nd) The number of people in one of the groups is divisible by 4.\r\ne) One of the groups contains 8 times as many people who are younger than 50 as those who are at least 50 years old.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first thing is to make this question an equation. The equation is x+y=86. x is the larger group and y is the smaller group. So, y=86-x. So, x+86-x=86. If the first statement is true then ¼(x)>y. Since y=86-x, then ¼(x)>86-x. Now find out the greatest possible number that will satisfy the equation ¼(x)>86-x. The largest number y could be is 17. The smallest number x could be is 69.\r\nIf c) is true, then one of the groups must be even since \"couples\" are the multiples of 2 (1 couple consists of 2 people, 2 couples consists of 4 people). Then, you figure out that 1 group affects the other group. If there is 1 more person in group x, then there is one less person in group y. So, that means that both group must be even or else both groups are odd and no group will satisfy c). So x must consist of 70, 72, 74, 76, 78, 80, 82, 84, or 86 people and y must consist of 16, 14, 12, 10, 8, 6, 4, 2, or 0 people. Now try to make the groups satisfy e). Substitute c for young people and o for old people. The equation is 8o=c. So, o+c equals the number of people in one of the groups. If c=8o, then that will mean o+8o equals the number of people in one of the groups. Then, simplified the equation.\r\no+8o=9o.\r\nSo 9o equal the number of people in one of the groups. So one of the groups has to be a multiple of 9. Since y consists of a group that has 16 people or under, then the only multiple of 9 is 9. But the groups have to consist of an even number of people, so group x must satisfy e). The only multiples of 9 above 70 and under 86 are 72 and 81. But, the number has to be even. So, group x consists of 72 people and y consists of 14 people. \r\nSo, the answer is that there are 72 people that went to see the water mill and 14 people went to the beach.\n<|im_start|>answer\nThe first thing is to make this question an equation. The equation is x+y=86. x is the larger group and y is the smaller group. So, y=86-x. So, x+86-x=86. If the first statement is true then ¼(x)>y. Since y=86-x, then ¼(x)>86-x. Now find out the greatest possible number that will satisfy the equation ¼(x)>86-x. The largest number y could be is 17. The smallest number x could be is 69.\r\nIf c) is true, then one of the groups must be even since \"couples\" are the multiples of 2 (1 couple consists of 2 people, 2 couples consists of 4 people). Then, you figure out that 1 group affects the other group. If there is 1 more person in group x, then there is one less person in group y. So, that means that both group must be even or else both groups are odd and no group will satisfy c). So x must consist of 70, 72, 74, 76, 78, 80, 82, 84, or 86 people and y must consist of 16, 14, 12, 10, 8, 6, 4, 2, or 0 people. Now try to make the groups satisfy e). Substitute c for young people and o for old people. The equation is 8o=c. So, o+c equals the number of people in one of the groups. If c=8o, then that will mean o+8o equals the number of people in one of the groups. Then, simplified the equation.\r\no+8o=9o.\r\nSo 9o equal the number of people in one of the groups. So one of the groups has to be a multiple of 9. Since y consists of a group that has 16 people or under, then the only multiple of 9 is 9. But the groups have to consist of an even number of people, so group x must satisfy e). The only multiples of 9 above 70 and under 86 are 72 and 81. But, the number has to be even. So, group x consists of 72 people and y consists of 14 people. \r\nSo, the answer is that there are 72 people that went to see the water mill and 14 people went to the beach.\n<|im_end|>" }, { "id": "#38430", "title": "Seven Sportsmen", "fun": 2.57, "difficulty": 3.02, "author": "shenqiang", "desc": "Seven sportsmen are standing in a row. Each sportsman has a different 1-digit number. The product of the first three, the product of the middle three, and the product of the last three are all equal.\n\r\nWhat's the middle sportsman's number?", "hint": "Figure out what the numbers are, and then eliminate the impossibilities.", "answer": "Let their numbers be a through g, we have abc=cde=efg.\n\r\n5 or 7 cannot occur, because they are prime and no other 1-digit number contains them. Therefore, the numbers are 1, 2, 3, 4, 6, 8, 9.\n\r\nSince abc=efg, abcdefg/d is a perfect square. 1*2*3*4*6*8*9=2^7*3^4, and d can be only 2 or 8.\n\r\nIf d=2, the numbers 1, 3, 4, 6, 8, 9 can be made into 1*8*9=3*4*6=72, and we can have c=9, e=4: 9*2*4=72.\n\r\nIf d=8, the numbers 1, 2, 3, 4, 6, 9 can be made into 1*4*9=2*3*6=36, but 36 is not divisible by 8.\n\r\nTherefore, the middle sportsman's number is 2.", "category": "Logic", "date": "09/23/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSeven sportsmen are standing in a row. Each sportsman has a different 1-digit number. The product of the first three, the product of the middle three, and the product of the last three are all equal.\n\r\nWhat's the middle sportsman's number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet their numbers be a through g, we have abc=cde=efg.\n\r\n5 or 7 cannot occur, because they are prime and no other 1-digit number contains them. Therefore, the numbers are 1, 2, 3, 4, 6, 8, 9.\n\r\nSince abc=efg, abcdefg/d is a perfect square. 1*2*3*4*6*8*9=2^7*3^4, and d can be only 2 or 8.\n\r\nIf d=2, the numbers 1, 3, 4, 6, 8, 9 can be made into 1*8*9=3*4*6=72, and we can have c=9, e=4: 9*2*4=72.\n\r\nIf d=8, the numbers 1, 2, 3, 4, 6, 9 can be made into 1*4*9=2*3*6=36, but 36 is not divisible by 8.\n\r\nTherefore, the middle sportsman's number is 2.\n<|im_start|>answer\nLet their numbers be a through g, we have abc=cde=efg.\n\r\n5 or 7 cannot occur, because they are prime and no other 1-digit number contains them. Therefore, the numbers are 1, 2, 3, 4, 6, 8, 9.\n\r\nSince abc=efg, abcdefg/d is a perfect square. 1*2*3*4*6*8*9=2^7*3^4, and d can be only 2 or 8.\n\r\nIf d=2, the numbers 1, 3, 4, 6, 8, 9 can be made into 1*8*9=3*4*6=72, and we can have c=9, e=4: 9*2*4=72.\n\r\nIf d=8, the numbers 1, 2, 3, 4, 6, 9 can be made into 1*4*9=2*3*6=36, but 36 is not divisible by 8.\n\r\nTherefore, the middle sportsman's number is 2.\n<|im_end|>" }, { "id": "#44845", "title": "The Culprit", "fun": 2.57, "difficulty": 1.74, "author": "nogoodnames", "desc": "Five suspects have been interrogated.\n\r\nAlan said, \"Dan is the culprit.\"\r\nBob said, \"I am not guilty.\"\r\nCharles said, \"It was not Eddie.\"\r\nDan said, \"Alan lies when he says that I did it.\"\r\nEddie says, \"Bob is telling the truth.\"\n\r\nWho is the culprit if two of the statements are false?", "hint": "No hint available.", "answer": "Eddie is the culprit.\n\r\nAlan:False, Bob:True, Charles:False, Dan:True, Eddie:True.", "category": "Logic", "date": "07/14/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive suspects have been interrogated.\n\r\nAlan said, \"Dan is the culprit.\"\r\nBob said, \"I am not guilty.\"\r\nCharles said, \"It was not Eddie.\"\r\nDan said, \"Alan lies when he says that I did it.\"\r\nEddie says, \"Bob is telling the truth.\"\n\r\nWho is the culprit if two of the statements are false?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEddie is the culprit.\n\r\nAlan:False, Bob:True, Charles:False, Dan:True, Eddie:True.\n<|im_start|>answer\nEddie is the culprit.\n\r\nAlan:False, Bob:True, Charles:False, Dan:True, Eddie:True.\n<|im_end|>" }, { "id": "#286", "title": "Time does fly!", "fun": 2.57, "difficulty": 1.35, "author": "Mr. G", "desc": "Five years ago, Anthony was three times as old as his sister. Now he is only twice as old. How old are Anthony and his sister?", "hint": "No hint available.", "answer": "Anthony is 20 and his sister is 10. Five years ago he was 15 and she was 5.", "category": "Math", "date": "02/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive years ago, Anthony was three times as old as his sister. Now he is only twice as old. How old are Anthony and his sister?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnthony is 20 and his sister is 10. Five years ago he was 15 and she was 5.\n<|im_start|>answer\nAnthony is 20 and his sister is 10. Five years ago he was 15 and she was 5.\n<|im_end|>" }, { "id": "#21304", "title": "Hell's Attack", "fun": 2.57, "difficulty": 1.23, "author": "iconofsin", "desc": "There are five monsters: A demon, a dragon, a gargoyle, a satyr, and a ghoul.\n\r\nThere were five victims: John, Michael, Samuel, Paul, and George.\n\r\nThere were five methods of death: hellfire, spikes, hanged, eaten, and beaten.\n\n\r\nClues:\n\r\n(1) George was not beaten.\r\n(2) The person that was burned to death by the hellfire was killed by the dragon.\r\n(3) Sam was killed by the ghoul.\r\n(4) Satyrs are known to beat their victims (and they enjoy it)\r\n(5) Neither John nor George were killed by the spikes.\r\n(6) Paul was eaten, but not by a gargoyle.\r\n(7) The gargoyle threw his victim in the spike pits.\r\n(8) John was not hanged.", "hint": "Uh, think carefully.", "answer": "Michael was thrown into the spike pits by the gargoyle.\r\nGeorge was burned by the dragon's hellfire.\r\nJohn was beaten by the satyr.\r\nSam was hanged by the ghoul.\r\nPaul was eaten by the demon.", "category": "Logic-Grid", "date": "03/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five monsters: A demon, a dragon, a gargoyle, a satyr, and a ghoul.\n\r\nThere were five victims: John, Michael, Samuel, Paul, and George.\n\r\nThere were five methods of death: hellfire, spikes, hanged, eaten, and beaten.\n\n\r\nClues:\n\r\n(1) George was not beaten.\r\n(2) The person that was burned to death by the hellfire was killed by the dragon.\r\n(3) Sam was killed by the ghoul.\r\n(4) Satyrs are known to beat their victims (and they enjoy it)\r\n(5) Neither John nor George were killed by the spikes.\r\n(6) Paul was eaten, but not by a gargoyle.\r\n(7) The gargoyle threw his victim in the spike pits.\r\n(8) John was not hanged.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMichael was thrown into the spike pits by the gargoyle.\r\nGeorge was burned by the dragon's hellfire.\r\nJohn was beaten by the satyr.\r\nSam was hanged by the ghoul.\r\nPaul was eaten by the demon.\n<|im_start|>answer\nMichael was thrown into the spike pits by the gargoyle.\r\nGeorge was burned by the dragon's hellfire.\r\nJohn was beaten by the satyr.\r\nSam was hanged by the ghoul.\r\nPaul was eaten by the demon.\n<|im_end|>" }, { "id": "#21348", "title": "Birds and Reptiles", "fun": 2.57, "difficulty": 0.91, "author": "ballaup35", "desc": "Abbie, Betty and Cindy each love animals; they especially love birds and reptiles. They each have a favorite bird: one loves albatrosses, another loves bald eagles, another loves cardinals. They each have a favorite reptile, too: one loves alligators, another loves boa constrictors, and one loves crocodiles. None of them have the same favorites. None of their favorites start with the same letter as their name. Each girl's favorite bird and reptile begin with a different letter.\n\r\nIf Abbie's favorite bird is a cardinal, what are each girl's favorite bird and reptile?", "hint": "No hint available.", "answer": "Abbie's favorites are cardinal and boa constrictor. Betty's favorites are albatross and crocodile. Cindy's favorites are bald eagle and alligator.", "category": "Logic", "date": "03/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbbie, Betty and Cindy each love animals; they especially love birds and reptiles. They each have a favorite bird: one loves albatrosses, another loves bald eagles, another loves cardinals. They each have a favorite reptile, too: one loves alligators, another loves boa constrictors, and one loves crocodiles. None of them have the same favorites. None of their favorites start with the same letter as their name. Each girl's favorite bird and reptile begin with a different letter.\n\r\nIf Abbie's favorite bird is a cardinal, what are each girl's favorite bird and reptile?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbbie's favorites are cardinal and boa constrictor. Betty's favorites are albatross and crocodile. Cindy's favorites are bald eagle and alligator.\n<|im_start|>answer\nAbbie's favorites are cardinal and boa constrictor. Betty's favorites are albatross and crocodile. Cindy's favorites are bald eagle and alligator.\n<|im_end|>" }, { "id": "#27920", "title": "New Year Bash!", "fun": 2.57, "difficulty": 0.92, "author": "brainster", "desc": "Five friends, Jenna, Brad, Anna, Chris, and Ronald, decided to get together and throw a new year party. They each had to organize one part of the entertainment, as well as arrange food items for each course of the new year bash meal. Can you figure out who handled what?\n\r\n1. No one organized any part of the entertainment or food, the first letter of which coincided with the first letter of their name.\n\r\n2. Neither Anna nor Ronald handled the organization of the quiz, but one of them handled the starters.\n\r\n3. Anna knew of some great places where they could have the party, so she agreed to find a suitable venue.\n\r\n4. Ronald did not organize the music for the party.\n\r\n5. Jenna worked for a music store and had the perfect list of head bangers set up for a wild night.\n\r\n6. Chris did not feel brainy enough to do the quiz. However, he had a sweet tooth, so he handled one of the sweets.\n\r\n7. Brad's food item included beef, onions, and peas.\n\r\n8. Jenna's Dad owned a bakery and made the perfect new year cake for the party.\n\r\n9. Anna's food item did not include chicken wings and french fingers.", "hint": "Sweets refer to either cake or dessert.", "answer": "Jenna - Music, Cake\r\nBrad - Quiz, Main Course\r\nAnna - Venue, Beverages\r\nRonald - Bingo, Starters\r\nChris - Return Gifts, Dessert", "category": "Logic-Grid", "date": "01/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends, Jenna, Brad, Anna, Chris, and Ronald, decided to get together and throw a new year party. They each had to organize one part of the entertainment, as well as arrange food items for each course of the new year bash meal. Can you figure out who handled what?\n\r\n1. No one organized any part of the entertainment or food, the first letter of which coincided with the first letter of their name.\n\r\n2. Neither Anna nor Ronald handled the organization of the quiz, but one of them handled the starters.\n\r\n3. Anna knew of some great places where they could have the party, so she agreed to find a suitable venue.\n\r\n4. Ronald did not organize the music for the party.\n\r\n5. Jenna worked for a music store and had the perfect list of head bangers set up for a wild night.\n\r\n6. Chris did not feel brainy enough to do the quiz. However, he had a sweet tooth, so he handled one of the sweets.\n\r\n7. Brad's food item included beef, onions, and peas.\n\r\n8. Jenna's Dad owned a bakery and made the perfect new year cake for the party.\n\r\n9. Anna's food item did not include chicken wings and french fingers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJenna - Music, Cake\r\nBrad - Quiz, Main Course\r\nAnna - Venue, Beverages\r\nRonald - Bingo, Starters\r\nChris - Return Gifts, Dessert\n<|im_start|>answer\nJenna - Music, Cake\r\nBrad - Quiz, Main Course\r\nAnna - Venue, Beverages\r\nRonald - Bingo, Starters\r\nChris - Return Gifts, Dessert\n<|im_end|>" }, { "id": "#42816", "title": "All Aboard the Hogwarts Express", "fun": 2.57, "difficulty": 2.65, "author": "PotionsMaster", "desc": "On the Hogwarts Express, the conductor completely screwed up and lost his seating notes! However, he has managed to get his hands on the following clues. Can you help him solve the clues and seat everyone in their proper place?\n\r\nThe Hogwarts Express has two different rows. Each row has two compartments. Each compartment has two rows of seats, and each row in the compartment can hold three people. In this case, there is a left compartment and a right compartment, like the following:\n\r\nLeft (corridor) Right\n\r\nClues:\n\r\n1) Harry is sitting across from Neville.\r\n2) Neville is in the left compartment.\r\n3) Ginny is sitting next to Neville, Luna, or both.\r\n4) Hermione, who is sitting completely diagonal from Neville, is next to either Harry, Ron, or both.\r\n5) Malfoy cannot be in the left compartment.\r\n6) Ron is sitting between Harry and Hermione.\r\n7) Luna is sitting diagonally from Harry.\r\n8) Malfoy is sitting next to Parkinson or Crabbe.\r\n9) Zabini is sitting opposite Nott.\r\n10) Crabbe and Goyle are sitting together next to one other person.\r\n11) Nott is diagonal from Parkinson.\r\n12) Harry must get a window seat.\r\n13) Hermione is in the aisle across the row from Malfoy.\r\n14) Crabbe is in the aisle across the row from Luna.\r\n15) Harry is closer to the front of the train.\n\r\nNote about the clues: Diagonal can mean completely diagonal (across, over 2) or it can mean slightly diagonal (across, over 1).", "hint": "No hint available.", "answer": "Harry, Ron, Hermione | Malfoy, Parkinson, Zabini\n\r\nNeville, Ginny, Luna | Crabbe, Goyle, Nott", "category": "Logic", "date": "08/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn the Hogwarts Express, the conductor completely screwed up and lost his seating notes! However, he has managed to get his hands on the following clues. Can you help him solve the clues and seat everyone in their proper place?\n\r\nThe Hogwarts Express has two different rows. Each row has two compartments. Each compartment has two rows of seats, and each row in the compartment can hold three people. In this case, there is a left compartment and a right compartment, like the following:\n\r\nLeft (corridor) Right\n\r\nClues:\n\r\n1) Harry is sitting across from Neville.\r\n2) Neville is in the left compartment.\r\n3) Ginny is sitting next to Neville, Luna, or both.\r\n4) Hermione, who is sitting completely diagonal from Neville, is next to either Harry, Ron, or both.\r\n5) Malfoy cannot be in the left compartment.\r\n6) Ron is sitting between Harry and Hermione.\r\n7) Luna is sitting diagonally from Harry.\r\n8) Malfoy is sitting next to Parkinson or Crabbe.\r\n9) Zabini is sitting opposite Nott.\r\n10) Crabbe and Goyle are sitting together next to one other person.\r\n11) Nott is diagonal from Parkinson.\r\n12) Harry must get a window seat.\r\n13) Hermione is in the aisle across the row from Malfoy.\r\n14) Crabbe is in the aisle across the row from Luna.\r\n15) Harry is closer to the front of the train.\n\r\nNote about the clues: Diagonal can mean completely diagonal (across, over 2) or it can mean slightly diagonal (across, over 1).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry, Ron, Hermione | Malfoy, Parkinson, Zabini\n\r\nNeville, Ginny, Luna | Crabbe, Goyle, Nott\n<|im_start|>answer\nHarry, Ron, Hermione | Malfoy, Parkinson, Zabini\n\r\nNeville, Ginny, Luna | Crabbe, Goyle, Nott\n<|im_end|>" }, { "id": "#31195", "title": "An Old Riddle", "fun": 2.57, "difficulty": 1.16, "author": "youdumbsavage", "desc": "In medieval England, a king's jester was imprisoned (the king didn't like the jester's jokes). The jester was locked in a room at the top of a high tower. The room had only one tiny window. The jester found a piece of rope. It wasn't long enough to reach the ground. So, he divided it in half and tied the two halves together. This made the rope long enough and he escaped. How?", "hint": "No hint available.", "answer": "He divided the rope vertically, not horizontally.", "category": "Logic", "date": "06/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn medieval England, a king's jester was imprisoned (the king didn't like the jester's jokes). The jester was locked in a room at the top of a high tower. The room had only one tiny window. The jester found a piece of rope. It wasn't long enough to reach the ground. So, he divided it in half and tied the two halves together. This made the rope long enough and he escaped. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe divided the rope vertically, not horizontally.\n<|im_start|>answer\nHe divided the rope vertically, not horizontally.\n<|im_end|>" }, { "id": "#6131", "title": "Five Men and Five Dogs", "fun": 2.57, "difficulty": 2.24, "author": "SkEwL_gUrl", "desc": "Five men and five dogs (each man owned a dog) went hiking. They encountered a river that was swift and deep. The only way to cross it was an abandoned boat, left ashore on their side. But it would only hold three living things. Unfortunately, the dogs were edgy and could not be near another person (not even momentarily) unless its owner was present. One of the dogs attended a highly advanced, highly specialized obedience school and therefore knew how to operate the boat (as the men did) -- the other dogs lack this skill. How did the five men and the five dogs cross the river?", "hint": "No hint available.", "answer": "Let the five men be represented by A, B, C, D, and E. Let the five dogs be represented by a, b, c, d, and e. Let the dog that can operate the boat be dog a. a, b, and c cross the river. a comes back alone and takes back d. a goes back and stays behind while B, C, and D cross the river. Now A, a, E, and e are on the starting shore, and B, b, C, c, D, and d are on the destination shore. D and d return; A and a cross. C and c go back, and C, D, and E cross. Now dogs c, d, and e are on the starting shore, and everyone else is on the destination shore. a goes back and returns with c and d, then goes back and returns with e.", "category": "Logic", "date": "07/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive men and five dogs (each man owned a dog) went hiking. They encountered a river that was swift and deep. The only way to cross it was an abandoned boat, left ashore on their side. But it would only hold three living things. Unfortunately, the dogs were edgy and could not be near another person (not even momentarily) unless its owner was present. One of the dogs attended a highly advanced, highly specialized obedience school and therefore knew how to operate the boat (as the men did) -- the other dogs lack this skill. How did the five men and the five dogs cross the river?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet the five men be represented by A, B, C, D, and E. Let the five dogs be represented by a, b, c, d, and e. Let the dog that can operate the boat be dog a. a, b, and c cross the river. a comes back alone and takes back d. a goes back and stays behind while B, C, and D cross the river. Now A, a, E, and e are on the starting shore, and B, b, C, c, D, and d are on the destination shore. D and d return; A and a cross. C and c go back, and C, D, and E cross. Now dogs c, d, and e are on the starting shore, and everyone else is on the destination shore. a goes back and returns with c and d, then goes back and returns with e.\n<|im_start|>answer\nLet the five men be represented by A, B, C, D, and E. Let the five dogs be represented by a, b, c, d, and e. Let the dog that can operate the boat be dog a. a, b, and c cross the river. a comes back alone and takes back d. a goes back and stays behind while B, C, and D cross the river. Now A, a, E, and e are on the starting shore, and B, b, C, c, D, and d are on the destination shore. D and d return; A and a cross. C and c go back, and C, D, and E cross. Now dogs c, d, and e are on the starting shore, and everyone else is on the destination shore. a goes back and returns with c and d, then goes back and returns with e.\n<|im_end|>" }, { "id": "#51800", "title": "Exoplanet Entropy", "fun": 2.57, "difficulty": 2.54, "author": "Hydra1234", "desc": "The Hubble Telescope has discovered five new solar systems with exoplanets in the Goldilocks Zones of each system. Unfortunately, a solar flare corrupted the transmission and severely damaged the telescope. Can you determine the size of the exoplanets, their distance from the Earth, their solar system, and the expplanet's name?\r\nThe transmission revealed several clues:\r\n1. Hinveng is 4 light years closer to us than Rodul.\r\n2. Vestor orbits star PLC 120.\r\n3. Hinveng is 6 light years closer to us than the exoplanet with a diameter of 714,000 mi..\r\n4. Of the exoplanet orbiting star HV 491 and the exoplanet orbiting star MKP 427, one has a diameter of 310,000 mi. and the other is 41 light years from Earth.\r\n5. Ereph is farther away from us than the exoplanet with a diameter of 650,000 mi..\r\n6. The exoplanet orbiting star HV 491 is 4 light years closer to us than the exoplanet orbiting star PLC 120.\r\n7. The exoplanet with a diameter of 295,000 mi. doesn't orbit star EX 53.\r\n8. Cheelia doesn't orbit star ZQ 75.\r\n9. Ereph is either the exoplanet orbiting star HV 491 or the exoplanet 45 light years from Earth.\r\n10. All planets are further than 40 light years away from Earth and closer than 50 light years away from Earth.\r\n11. All planets are 281,000, 295,000, 310,000, 650,000, or 714,000 miles in diameter.", "hint": "No hint available.", "answer": "Hinveng is 41 light years away orbiting MKP 427 with a diameter of 650,000 miles.\r\nEreph is 43 light years away orbiting HV 491 with a diameter of 310,000 miles.\r\nRodul is 45 light years away orbiting ZQ 75 with a diameter of 295,000 miles.\r\nVestor is 47 light years away orbiting PLC 120 with a diameter of 714,000 miles.\r\nCheelia is 49 light years away orbiting EX 53 with a diameter of 281,000 miles.", "category": "Logic-Grid", "date": "03/30/18", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Hubble Telescope has discovered five new solar systems with exoplanets in the Goldilocks Zones of each system. Unfortunately, a solar flare corrupted the transmission and severely damaged the telescope. Can you determine the size of the exoplanets, their distance from the Earth, their solar system, and the expplanet's name?\r\nThe transmission revealed several clues:\r\n1. Hinveng is 4 light years closer to us than Rodul.\r\n2. Vestor orbits star PLC 120.\r\n3. Hinveng is 6 light years closer to us than the exoplanet with a diameter of 714,000 mi..\r\n4. Of the exoplanet orbiting star HV 491 and the exoplanet orbiting star MKP 427, one has a diameter of 310,000 mi. and the other is 41 light years from Earth.\r\n5. Ereph is farther away from us than the exoplanet with a diameter of 650,000 mi..\r\n6. The exoplanet orbiting star HV 491 is 4 light years closer to us than the exoplanet orbiting star PLC 120.\r\n7. The exoplanet with a diameter of 295,000 mi. doesn't orbit star EX 53.\r\n8. Cheelia doesn't orbit star ZQ 75.\r\n9. Ereph is either the exoplanet orbiting star HV 491 or the exoplanet 45 light years from Earth.\r\n10. All planets are further than 40 light years away from Earth and closer than 50 light years away from Earth.\r\n11. All planets are 281,000, 295,000, 310,000, 650,000, or 714,000 miles in diameter.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHinveng is 41 light years away orbiting MKP 427 with a diameter of 650,000 miles.\r\nEreph is 43 light years away orbiting HV 491 with a diameter of 310,000 miles.\r\nRodul is 45 light years away orbiting ZQ 75 with a diameter of 295,000 miles.\r\nVestor is 47 light years away orbiting PLC 120 with a diameter of 714,000 miles.\r\nCheelia is 49 light years away orbiting EX 53 with a diameter of 281,000 miles.\n<|im_start|>answer\nHinveng is 41 light years away orbiting MKP 427 with a diameter of 650,000 miles.\r\nEreph is 43 light years away orbiting HV 491 with a diameter of 310,000 miles.\r\nRodul is 45 light years away orbiting ZQ 75 with a diameter of 295,000 miles.\r\nVestor is 47 light years away orbiting PLC 120 with a diameter of 714,000 miles.\r\nCheelia is 49 light years away orbiting EX 53 with a diameter of 281,000 miles.\n<|im_end|>" }, { "id": "#30894", "title": "Horse Crazy", "fun": 2.57, "difficulty": 2.01, "author": "fairelamour", "desc": "Elisa has always wanted a horse, and now she has fallen in love with a buckskin quarter horse gelding named Canyon Sunshine. The horse is priced at $3,000. Elisa's stepfather decides to give her an interest-free loan for the total price of Canyon Sunshine. While paying off this loan, Elisa will also be responsible for the $90 per month upkeep of the horse.\n\r\nElisa has $875 in a savings account. She has a steady baby-sitting job, which pays her $5 an hour. She baby-sits 4 nights monthly, 6 hours each night. She also earns $6 an hour working 16 hours each month cleaning the horse stalls at a local stable. Elisa decides to pay back her stepfather's loan as soon as possible with her savings and with every bit she earns monthly.\n\r\nIf Elisa's job situation remains unchanged, how many months will it take her to repay the loan?", "hint": "Divide the problem into parts.", "answer": "It will take Elisa 17 months to repay the loan.\n\r\nAfter closing her savings account to make the first payment, Elisa has a debt of $3,000 - $875 = $2,125.\n\r\nHer monthly income from baby-sitting is 4 * 6 * $5 = $120. Her monthly income from cleaning the stable is 16 * $6 = $96. So her total monthly income is $216.\n\r\nBut she must also pay $90 a month for the upkeep of Canyon Sunshine. So she can make monthly payments of $216 - $90 = $126.\n\r\nShe will have repaid the loan after 17 months: $2,125 / $126/month = 16.8.", "category": "Math", "date": "06/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nElisa has always wanted a horse, and now she has fallen in love with a buckskin quarter horse gelding named Canyon Sunshine. The horse is priced at $3,000. Elisa's stepfather decides to give her an interest-free loan for the total price of Canyon Sunshine. While paying off this loan, Elisa will also be responsible for the $90 per month upkeep of the horse.\n\r\nElisa has $875 in a savings account. She has a steady baby-sitting job, which pays her $5 an hour. She baby-sits 4 nights monthly, 6 hours each night. She also earns $6 an hour working 16 hours each month cleaning the horse stalls at a local stable. Elisa decides to pay back her stepfather's loan as soon as possible with her savings and with every bit she earns monthly.\n\r\nIf Elisa's job situation remains unchanged, how many months will it take her to repay the loan?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will take Elisa 17 months to repay the loan.\n\r\nAfter closing her savings account to make the first payment, Elisa has a debt of $3,000 - $875 = $2,125.\n\r\nHer monthly income from baby-sitting is 4 * 6 * $5 = $120. Her monthly income from cleaning the stable is 16 * $6 = $96. So her total monthly income is $216.\n\r\nBut she must also pay $90 a month for the upkeep of Canyon Sunshine. So she can make monthly payments of $216 - $90 = $126.\n\r\nShe will have repaid the loan after 17 months: $2,125 / $126/month = 16.8.\n<|im_start|>answer\nIt will take Elisa 17 months to repay the loan.\n\r\nAfter closing her savings account to make the first payment, Elisa has a debt of $3,000 - $875 = $2,125.\n\r\nHer monthly income from baby-sitting is 4 * 6 * $5 = $120. Her monthly income from cleaning the stable is 16 * $6 = $96. So her total monthly income is $216.\n\r\nBut she must also pay $90 a month for the upkeep of Canyon Sunshine. So she can make monthly payments of $216 - $90 = $126.\n\r\nShe will have repaid the loan after 17 months: $2,125 / $126/month = 16.8.\n<|im_end|>" }, { "id": "#40750", "title": "Cake Theft", "fun": 2.57, "difficulty": 1.76, "author": "lab123", "desc": "During a recent police investigation, Chief Inspector Stone was interviewing five local villains to try and identify who stole Mrs. Archer's cake from the mid-summer's fair. Below is a summary of their statements: \n\r\nArnold: \"It wasn't Edward.\"\r\n \"It was Brian.\"\n\r\nBrian: \"It wasn't Charlie.\"\r\n \"It wasn't Edward.\"\n\r\nCharlie: \"It was Edward.\"\r\n \"It wasn't Arnold.\"\n\r\nDerek: \"It was Charlie.\"\r\n \"It was Brian.\"\n\r\nEdward: \"It was Derek.\"\r\n \"It wasn't Arnold.\"\n\r\nIt was well known that each suspect told exactly one lie. Can you determine who stole the cake?", "hint": "No hint available.", "answer": "Charlie committed the terrible crime. The way to solve this puzzle is to look at each clue. We know that exactly one of each person's statements is true. Looking at Arnold's statements, let's check to see if 'it was Brian' is true. If 'it was Brian' is true, then we know the other statement is false, therefore it was Edward. This is a contradiction. Hence we now know it wasn't Brian, nor Edward (as 'it wasn't Edward' must be the true statement). Looking at Charlie's statement, we can similarly determine that it wasn't Arnold either. Edward's statement gives us that it wasn't Derek, which leaves only Charlie as the culprit. It is always wise to check this against the other clues.", "category": "Logic", "date": "02/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a recent police investigation, Chief Inspector Stone was interviewing five local villains to try and identify who stole Mrs. Archer's cake from the mid-summer's fair. Below is a summary of their statements: \n\r\nArnold: \"It wasn't Edward.\"\r\n \"It was Brian.\"\n\r\nBrian: \"It wasn't Charlie.\"\r\n \"It wasn't Edward.\"\n\r\nCharlie: \"It was Edward.\"\r\n \"It wasn't Arnold.\"\n\r\nDerek: \"It was Charlie.\"\r\n \"It was Brian.\"\n\r\nEdward: \"It was Derek.\"\r\n \"It wasn't Arnold.\"\n\r\nIt was well known that each suspect told exactly one lie. Can you determine who stole the cake?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCharlie committed the terrible crime. The way to solve this puzzle is to look at each clue. We know that exactly one of each person's statements is true. Looking at Arnold's statements, let's check to see if 'it was Brian' is true. If 'it was Brian' is true, then we know the other statement is false, therefore it was Edward. This is a contradiction. Hence we now know it wasn't Brian, nor Edward (as 'it wasn't Edward' must be the true statement). Looking at Charlie's statement, we can similarly determine that it wasn't Arnold either. Edward's statement gives us that it wasn't Derek, which leaves only Charlie as the culprit. It is always wise to check this against the other clues.\n<|im_start|>answer\nCharlie committed the terrible crime. The way to solve this puzzle is to look at each clue. We know that exactly one of each person's statements is true. Looking at Arnold's statements, let's check to see if 'it was Brian' is true. If 'it was Brian' is true, then we know the other statement is false, therefore it was Edward. This is a contradiction. Hence we now know it wasn't Brian, nor Edward (as 'it wasn't Edward' must be the true statement). Looking at Charlie's statement, we can similarly determine that it wasn't Arnold either. Edward's statement gives us that it wasn't Derek, which leaves only Charlie as the culprit. It is always wise to check this against the other clues.\n<|im_end|>" }, { "id": "#16522", "title": "Bowling League", "fun": 2.57, "difficulty": 2.12, "author": "absy", "desc": "Joyce and her four best friends bowl together on a team named the Alley Cats. The team played a great game last Friday as each woman's score was higher than her average. Can you find each bowler's full name and her Friday night score?\n\r\nGiven:\n\r\nScores -- \t170, 175, 195, 210, 230\r\nFirst Names -- \tAmy, Evelyn, Hillary, Joyce, Opal\r\nLast Names -- \tMarin, Peterson, Rielly, Shapiro, Webster\n\r\nClues:\n\r\n#1) Hillary, whose average is 197, isn't Ms. Webster\r\n#2) Opal scored exactly 20 more points than Ms. Shapiro\r\n#3) Ms. Rielly (who isn't Evelyn), scored lower than Opal's average\r\n#4) Amy's score was higher than Ms. Peterson's\r\n#5) Opal is NOT Ms. Marin and neither woman scored 230 points.", "hint": "Make a list of one set of givens and list another set of givens that would correspond to them... i.e. (first names) -- (last names)\n\r\nAmy -- Marin, Peterson, Rielly, Shapiro, Webster\r\nEvelyn -- Marin, Peterson, Rielly, Shapiro, Webster, etc.\n\r\nCross off what you know is NOT the correct answer from the clues, and when you find out a last name that fits a first name circle it, or write the full name on the piece of paper in a different section to keep track. Do the same with the other correlations that can be surmised by looking at the clues: \n\r\n(last names) -- (bowling scores)\r\n(first names) -- (bowling scores) \n\r\nKeep in mind that for example, if you find a last name for a first name, the other first names can NOT have that last name, so that gives you another answer to mark off to narrow the correct answer down.", "answer": "Joyce Rielly -- 170\r\nEvelyn Shapiro -- 175\r\nAmy Webster -- 230\r\nHillary Marin -- 210\r\nOpal Peterson -- 195\n\r\n**Clue #1: We know Hillary isn't Ms. Webster, so you can cross that off immediately. We also know that Hillary's bowling average is 197. The problem states that it was a good night because each lady scored higher than her average. We know then, that Hillary's average must be either 210 or 230. Cross off the others for Hillary. \r\n**Clue #2: Opal scored 20 more points than Ms. Shapiro. Looking at the scores, there are 2 sets of the numbers that have differences of 20. 175 ; 195 and 210 ; 230. So for Opal and Ms. Shapiro, you can immediately mark off the 170 score. Also, Opal can NOT be Ms. Shapiro.\r\n**Clue #3: Ms. Rielly is NOT Evelyn, so cross off Rielly on Evelyn's list. Rielly scored lower than Opal. This means that Opal cannot have the lowest score, which was crossed off in the last clue, and Rielly can NOT have the highest score. So cross off the 230 on Rielly's list. Also, if it says Rielly scored lower than Opal, we can assume Opal is NOT Ms. Rielly...mark it off.\r\n**Clue #4: If Amy's score was higher than Ms. Peterson's, then Amy cannot have the lowest score (170) and Ms. Peterson cannot have the highest score (230). Cross them off. Here as well, we can assume that if they have different scores, Amy can NOT be Ms. Peterson. \r\n**Clue #5: Opal is NOT Ms. Marin, neither scored 230 points. Cross them off. If Opal did not score 230 points, then the 20 point difference is not the 210 ; 230. So we know that Opal and Ms. Shapiro's scores are 195 and 175, respectively. Since we know Shapiro has a 175, any of the first names that have 175 crossed off can NOT be Shapiro, therefore Hillary can NOT be Ms. Shapiro...mark it off. Also note that Ms. Webster scored 230.\r\n*********Once we know that Opal's score is 195, we know that Rielly scored lower than that. So Rielly's score is either 170 or 175. Shapiro's score is 175, so we know that Rielly's score is 170. First names with 170 marked off already can NOT have a last name of Rielly. SO mark off Rielly on Amy's, Hillary's, and Opal's list. We now see that the full name is Joyce Rielly with a score of 170. Now you have the first complete section of the answer. Also, we know Opal is NOT Ms. Marin, so you can cross off 195 from Ms. Marin's score list. Now we know Marin scored 210. That leaves Peterson with 195. Opal is Ms. Peterson. We know that Amy scored higher than Ms. Peterson, who scored 195. So Amy could only have scored a 210 or 230. Marking 175 off Amy's list shows you Evelyn has 175. which makes her Ms. Shapiro. Marking Webster off of Opal's list, leaves Amy as Webster which in turn leaves Hillary as Marin.", "category": "Logic", "date": "02/10/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoyce and her four best friends bowl together on a team named the Alley Cats. The team played a great game last Friday as each woman's score was higher than her average. Can you find each bowler's full name and her Friday night score?\n\r\nGiven:\n\r\nScores -- \t170, 175, 195, 210, 230\r\nFirst Names -- \tAmy, Evelyn, Hillary, Joyce, Opal\r\nLast Names -- \tMarin, Peterson, Rielly, Shapiro, Webster\n\r\nClues:\n\r\n#1) Hillary, whose average is 197, isn't Ms. Webster\r\n#2) Opal scored exactly 20 more points than Ms. Shapiro\r\n#3) Ms. Rielly (who isn't Evelyn), scored lower than Opal's average\r\n#4) Amy's score was higher than Ms. Peterson's\r\n#5) Opal is NOT Ms. Marin and neither woman scored 230 points.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoyce Rielly -- 170\r\nEvelyn Shapiro -- 175\r\nAmy Webster -- 230\r\nHillary Marin -- 210\r\nOpal Peterson -- 195\n\r\n**Clue #1: We know Hillary isn't Ms. Webster, so you can cross that off immediately. We also know that Hillary's bowling average is 197. The problem states that it was a good night because each lady scored higher than her average. We know then, that Hillary's average must be either 210 or 230. Cross off the others for Hillary. \r\n**Clue #2: Opal scored 20 more points than Ms. Shapiro. Looking at the scores, there are 2 sets of the numbers that have differences of 20. 175 ; 195 and 210 ; 230. So for Opal and Ms. Shapiro, you can immediately mark off the 170 score. Also, Opal can NOT be Ms. Shapiro.\r\n**Clue #3: Ms. Rielly is NOT Evelyn, so cross off Rielly on Evelyn's list. Rielly scored lower than Opal. This means that Opal cannot have the lowest score, which was crossed off in the last clue, and Rielly can NOT have the highest score. So cross off the 230 on Rielly's list. Also, if it says Rielly scored lower than Opal, we can assume Opal is NOT Ms. Rielly...mark it off.\r\n**Clue #4: If Amy's score was higher than Ms. Peterson's, then Amy cannot have the lowest score (170) and Ms. Peterson cannot have the highest score (230). Cross them off. Here as well, we can assume that if they have different scores, Amy can NOT be Ms. Peterson. \r\n**Clue #5: Opal is NOT Ms. Marin, neither scored 230 points. Cross them off. If Opal did not score 230 points, then the 20 point difference is not the 210 ; 230. So we know that Opal and Ms. Shapiro's scores are 195 and 175, respectively. Since we know Shapiro has a 175, any of the first names that have 175 crossed off can NOT be Shapiro, therefore Hillary can NOT be Ms. Shapiro...mark it off. Also note that Ms. Webster scored 230.\r\n*********Once we know that Opal's score is 195, we know that Rielly scored lower than that. So Rielly's score is either 170 or 175. Shapiro's score is 175, so we know that Rielly's score is 170. First names with 170 marked off already can NOT have a last name of Rielly. SO mark off Rielly on Amy's, Hillary's, and Opal's list. We now see that the full name is Joyce Rielly with a score of 170. Now you have the first complete section of the answer. Also, we know Opal is NOT Ms. Marin, so you can cross off 195 from Ms. Marin's score list. Now we know Marin scored 210. That leaves Peterson with 195. Opal is Ms. Peterson. We know that Amy scored higher than Ms. Peterson, who scored 195. So Amy could only have scored a 210 or 230. Marking 175 off Amy's list shows you Evelyn has 175. which makes her Ms. Shapiro. Marking Webster off of Opal's list, leaves Amy as Webster which in turn leaves Hillary as Marin.\n<|im_start|>answer\nJoyce Rielly -- 170\r\nEvelyn Shapiro -- 175\r\nAmy Webster -- 230\r\nHillary Marin -- 210\r\nOpal Peterson -- 195\n\r\n**Clue #1: We know Hillary isn't Ms. Webster, so you can cross that off immediately. We also know that Hillary's bowling average is 197. The problem states that it was a good night because each lady scored higher than her average. We know then, that Hillary's average must be either 210 or 230. Cross off the others for Hillary. \r\n**Clue #2: Opal scored 20 more points than Ms. Shapiro. Looking at the scores, there are 2 sets of the numbers that have differences of 20. 175 ; 195 and 210 ; 230. So for Opal and Ms. Shapiro, you can immediately mark off the 170 score. Also, Opal can NOT be Ms. Shapiro.\r\n**Clue #3: Ms. Rielly is NOT Evelyn, so cross off Rielly on Evelyn's list. Rielly scored lower than Opal. This means that Opal cannot have the lowest score, which was crossed off in the last clue, and Rielly can NOT have the highest score. So cross off the 230 on Rielly's list. Also, if it says Rielly scored lower than Opal, we can assume Opal is NOT Ms. Rielly...mark it off.\r\n**Clue #4: If Amy's score was higher than Ms. Peterson's, then Amy cannot have the lowest score (170) and Ms. Peterson cannot have the highest score (230). Cross them off. Here as well, we can assume that if they have different scores, Amy can NOT be Ms. Peterson. \r\n**Clue #5: Opal is NOT Ms. Marin, neither scored 230 points. Cross them off. If Opal did not score 230 points, then the 20 point difference is not the 210 ; 230. So we know that Opal and Ms. Shapiro's scores are 195 and 175, respectively. Since we know Shapiro has a 175, any of the first names that have 175 crossed off can NOT be Shapiro, therefore Hillary can NOT be Ms. Shapiro...mark it off. Also note that Ms. Webster scored 230.\r\n*********Once we know that Opal's score is 195, we know that Rielly scored lower than that. So Rielly's score is either 170 or 175. Shapiro's score is 175, so we know that Rielly's score is 170. First names with 170 marked off already can NOT have a last name of Rielly. SO mark off Rielly on Amy's, Hillary's, and Opal's list. We now see that the full name is Joyce Rielly with a score of 170. Now you have the first complete section of the answer. Also, we know Opal is NOT Ms. Marin, so you can cross off 195 from Ms. Marin's score list. Now we know Marin scored 210. That leaves Peterson with 195. Opal is Ms. Peterson. We know that Amy scored higher than Ms. Peterson, who scored 195. So Amy could only have scored a 210 or 230. Marking 175 off Amy's list shows you Evelyn has 175. which makes her Ms. Shapiro. Marking Webster off of Opal's list, leaves Amy as Webster which in turn leaves Hillary as Marin.\n<|im_end|>" }, { "id": "#27200", "title": "Zeros", "fun": 2.57, "difficulty": 2.74, "author": "cdrock", "desc": "Use the numbers 1 to 4 in each column and row, and then add 0, 1, or 2 zeros after each number that needs it so that the numbers add up to the numbers listed below the grid.\n\r\nX A B C D\r\n1. _ _ _ _\r\n2. _ _ _ _\r\n3. _ _ _ _\r\n4. _ _ _ _\n\r\nRows:\r\n1. 640\r\n2. 442\r\n3. 55\r\n4. 442\n\r\nColumns:\r\nA. 316\r\nB. 433\r\nC. 280\r\nD. 550", "hint": "No hint available.", "answer": "010 400 200 030\r\n300 002 040 100\r\n004 001 030 020\r\n002 030 010 400", "category": "Logic", "date": "11/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUse the numbers 1 to 4 in each column and row, and then add 0, 1, or 2 zeros after each number that needs it so that the numbers add up to the numbers listed below the grid.\n\r\nX A B C D\r\n1. _ _ _ _\r\n2. _ _ _ _\r\n3. _ _ _ _\r\n4. _ _ _ _\n\r\nRows:\r\n1. 640\r\n2. 442\r\n3. 55\r\n4. 442\n\r\nColumns:\r\nA. 316\r\nB. 433\r\nC. 280\r\nD. 550\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n010 400 200 030\r\n300 002 040 100\r\n004 001 030 020\r\n002 030 010 400\n<|im_start|>answer\n010 400 200 030\r\n300 002 040 100\r\n004 001 030 020\r\n002 030 010 400\n<|im_end|>" }, { "id": "#15982", "title": "The Peculiar Number", "fun": 2.57, "difficulty": 1.65, "author": "apr2001", "desc": "There is a number which is very peculiar. This number is three times the sum of its digits. What number is it?", "hint": "No hint available.", "answer": "The number is 27:\r\n2 + 7 = 9\r\n9 times 3 = 27", "category": "Math", "date": "12/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a number which is very peculiar. This number is three times the sum of its digits. What number is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 27:\r\n2 + 7 = 9\r\n9 times 3 = 27\n<|im_start|>answer\nThe number is 27:\r\n2 + 7 = 9\r\n9 times 3 = 27\n<|im_end|>" }, { "id": "#1494", "title": "Stealing Apples", "fun": 2.56, "difficulty": 1.66, "author": "Night", "desc": "Three boys went to their neighbor's tree to steal apples. Only one of them could climb, so that boy started to pick apples. \n\r\nThe neighbor woke up and he came outside to investigate. The other two boys who couldn't climb got scared and ran away. \n\r\nThe boy up in the tree waited patiently until the neighbor left, and then got down with the apples he picked. He divided them into three equal parts and left with his share. \n\r\nThe next day the second boy came and he saw the apples lying around. He divided them into three sections and took the share with the most apples. \n\r\nA few hours later the third boy arrived and took all the apples that were left. \n\r\nThe next day when they met again, they found out they all had the same number of apples.\n\r\nHow could this be? How many apples were there if the boy picked fewer than 9 apples?", "hint": "No hint available.", "answer": "There were 6 apples.\n\r\nThe first boy divided it into 3 sections (2, 2, 2). Then took two.\n\r\nThe second boy divided the remaining 4 into 3 sections (2, 1, 1). Then took the share with the most apples (2). \n\r\nThe third boy took the remainder (2).\n\r\nThey each had 2 to make a total of 6.", "category": "Math", "date": "11/22/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree boys went to their neighbor's tree to steal apples. Only one of them could climb, so that boy started to pick apples. \n\r\nThe neighbor woke up and he came outside to investigate. The other two boys who couldn't climb got scared and ran away. \n\r\nThe boy up in the tree waited patiently until the neighbor left, and then got down with the apples he picked. He divided them into three equal parts and left with his share. \n\r\nThe next day the second boy came and he saw the apples lying around. He divided them into three sections and took the share with the most apples. \n\r\nA few hours later the third boy arrived and took all the apples that were left. \n\r\nThe next day when they met again, they found out they all had the same number of apples.\n\r\nHow could this be? How many apples were there if the boy picked fewer than 9 apples?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 6 apples.\n\r\nThe first boy divided it into 3 sections (2, 2, 2). Then took two.\n\r\nThe second boy divided the remaining 4 into 3 sections (2, 1, 1). Then took the share with the most apples (2). \n\r\nThe third boy took the remainder (2).\n\r\nThey each had 2 to make a total of 6.\n<|im_start|>answer\nThere were 6 apples.\n\r\nThe first boy divided it into 3 sections (2, 2, 2). Then took two.\n\r\nThe second boy divided the remaining 4 into 3 sections (2, 1, 1). Then took the share with the most apples (2). \n\r\nThe third boy took the remainder (2).\n\r\nThey each had 2 to make a total of 6.\n<|im_end|>" }, { "id": "#47589", "title": "Flowers", "fun": 2.56, "difficulty": 0.97, "author": "cutieluck", "desc": "How many flowers do I have if all of them are roses except two, all of them are tulips except two, and all of them are daisies except two?", "hint": "No hint available.", "answer": "Two solutions: \n\r\nThree flowers : rose, tulip, daisy\n\r\nTwo flowers : carnation, geranium", "category": "Logic", "date": "07/24/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many flowers do I have if all of them are roses except two, all of them are tulips except two, and all of them are daisies except two?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwo solutions: \n\r\nThree flowers : rose, tulip, daisy\n\r\nTwo flowers : carnation, geranium\n<|im_start|>answer\nTwo solutions: \n\r\nThree flowers : rose, tulip, daisy\n\r\nTwo flowers : carnation, geranium\n<|im_end|>" }, { "id": "#403", "title": "Farmers market", "fun": 2.56, "difficulty": 2.26, "author": "Andy", "desc": "A farmer must spend exactly $100 to buy exactly 100 animals, and must buy at least one of each animal. Cows are $10 each, Goats are $1 each and Chickens are 8 for a $1. What does he buy?", "hint": "No hint available.", "answer": "7 Cows, 21 Goats, and 72 Chickens.", "category": "Math", "date": "04/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA farmer must spend exactly $100 to buy exactly 100 animals, and must buy at least one of each animal. Cows are $10 each, Goats are $1 each and Chickens are 8 for a $1. What does he buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 Cows, 21 Goats, and 72 Chickens.\n<|im_start|>answer\n7 Cows, 21 Goats, and 72 Chickens.\n<|im_end|>" }, { "id": "#13441", "title": "2+2=5", "fun": 2.56, "difficulty": 2.96, "author": "ChemicalBoy08", "desc": "Using only two 2's and any combination of mathematical signs, symbols and functions can you make 5?", "hint": "No hint available.", "answer": "SQRT(.2 ^ -2) \n\r\nTake .2 and raise it to the power of -2 and then take the square root.", "category": "Math", "date": "06/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing only two 2's and any combination of mathematical signs, symbols and functions can you make 5?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSQRT(.2 ^ -2) \n\r\nTake .2 and raise it to the power of -2 and then take the square root.\n<|im_start|>answer\nSQRT(.2 ^ -2) \n\r\nTake .2 and raise it to the power of -2 and then take the square root.\n<|im_end|>" }, { "id": "#37792", "title": "Company Move", "fun": 2.56, "difficulty": 1.56, "author": "bigSWAFF_69_", "desc": "I once worked at a company which employed 50 people, all of whom worked at the corporate headquarters in the same 4,000 square foot office building in the United States. We all lived in different directions: north, south, northwest, southeast from work, none more than 30 miles away. There were no housing complexes where we lived and no physical obstructions in the way (mountains, lakes, oceans, etc.). \n\r\nThe company's president made an economic decision in relocating all 50 employees to a new office location. In doing so, he didn't take into account how the move might affect the distance employees had to travel to work.\n\r\nAfter the move, the president found that the new headquarters was closer to his home. It worked out great for him because he also got a fancy new office with more room. Once the move was finally completed, every single employee, myself included, was closer to home than before the move.\n\r\nIf we all still work in the same office together, as before, how can this be?", "hint": "No hint available.", "answer": "We moved from the 25th floor of a large building to the 15th floor. We were all closer to our homes, albeit by a small distance.", "category": "Logic", "date": "08/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI once worked at a company which employed 50 people, all of whom worked at the corporate headquarters in the same 4,000 square foot office building in the United States. We all lived in different directions: north, south, northwest, southeast from work, none more than 30 miles away. There were no housing complexes where we lived and no physical obstructions in the way (mountains, lakes, oceans, etc.). \n\r\nThe company's president made an economic decision in relocating all 50 employees to a new office location. In doing so, he didn't take into account how the move might affect the distance employees had to travel to work.\n\r\nAfter the move, the president found that the new headquarters was closer to his home. It worked out great for him because he also got a fancy new office with more room. Once the move was finally completed, every single employee, myself included, was closer to home than before the move.\n\r\nIf we all still work in the same office together, as before, how can this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWe moved from the 25th floor of a large building to the 15th floor. We were all closer to our homes, albeit by a small distance.\n<|im_start|>answer\nWe moved from the 25th floor of a large building to the 15th floor. We were all closer to our homes, albeit by a small distance.\n<|im_end|>" }, { "id": "#29003", "title": "Tests", "fun": 2.56, "difficulty": 1.13, "author": "thompson1", "desc": "4 kids had tests in 4 different classes today. Each one studied a different amount of time for their test. Figure out which kids had which tests and how long they each spent studying.\n\r\nKids - Jim, Sara, Ted, and Kaitlyn\r\nSubjects - English, Math, Science, and History\r\nTimes - 5, 20, 35, and 40 minutes\n\r\n1. The girl that had a math test did not study for the longest amount of time.\n\r\n2. Jim, who had an English test, studied 15 minutes longer than Kaitlyn.\n\r\n3. Ted did not take a science class.\n\r\n4. The kid taking the science class studied for 20 minutes.", "hint": "Jim and Ted are boys; Sara and Kaitlyn are girls.", "answer": "Jim studied 35 minutes for his English test.\r\nSara studied 5 minutes for her math test.\r\nTed studied 40 minutes for his history test.\r\nKaitlyn studied 20 minutes for her science test.", "category": "Logic-Grid", "date": "03/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 kids had tests in 4 different classes today. Each one studied a different amount of time for their test. Figure out which kids had which tests and how long they each spent studying.\n\r\nKids - Jim, Sara, Ted, and Kaitlyn\r\nSubjects - English, Math, Science, and History\r\nTimes - 5, 20, 35, and 40 minutes\n\r\n1. The girl that had a math test did not study for the longest amount of time.\n\r\n2. Jim, who had an English test, studied 15 minutes longer than Kaitlyn.\n\r\n3. Ted did not take a science class.\n\r\n4. The kid taking the science class studied for 20 minutes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJim studied 35 minutes for his English test.\r\nSara studied 5 minutes for her math test.\r\nTed studied 40 minutes for his history test.\r\nKaitlyn studied 20 minutes for her science test.\n<|im_start|>answer\nJim studied 35 minutes for his English test.\r\nSara studied 5 minutes for her math test.\r\nTed studied 40 minutes for his history test.\r\nKaitlyn studied 20 minutes for her science test.\n<|im_end|>" }, { "id": "#20911", "title": "A number is missing. What is it?", "fun": 2.56, "difficulty": 2.07, "author": "fishmed", "desc": "2820\r\n1199\r\n3345\r\n736?\n\r\nWhat is the missing number?", "hint": "No hint available.", "answer": "The missing number is 4.\r\nIf you put a line under 3345 and a plus sign to the side, this is really a math problem:\n\r\n 2820\r\n 1199\r\n+3345\r\n -----\r\n 7364", "category": "Logic", "date": "02/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n2820\r\n1199\r\n3345\r\n736?\n\r\nWhat is the missing number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe missing number is 4.\r\nIf you put a line under 3345 and a plus sign to the side, this is really a math problem:\n\r\n 2820\r\n 1199\r\n+3345\r\n -----\r\n 7364\n<|im_start|>answer\nThe missing number is 4.\r\nIf you put a line under 3345 and a plus sign to the side, this is really a math problem:\n\r\n 2820\r\n 1199\r\n+3345\r\n -----\r\n 7364\n<|im_end|>" }, { "id": "#49988", "title": "Slush Shack", "fun": 2.56, "difficulty": 2.84, "author": "eighsse", "desc": "You have a small shack in a parking lot, out of which you sell slushes for a few hours a day. You sell them in 4 sizes: small (12 oz), medium (20 oz), large (32 oz), and x-large (40 oz), and you charge $1.50, $2.25, $3.75, and $4.50 for each size, respectively. The cups cost you 3 cents for small, 5 cents for medium, 8 cents for large, and 10 cents for x-large, and the slush ingredients cost you 6 cents per ounce. Today, you are having a special: with every slush purchased, the customer receives a coupon for a free small slush. You figure that this special will increase sales for the day, but that the losses (due to giving out free slushes in the future) will cut the profit down to a much-below-average day. Your hope, though, is that it will help by drawing more regular customers in the long run. Your goal is to profit $20 even after the coupon losses. Through the day, medium was the best-selling size -- they sold exactly 4 times as many as smalls! -- followed by large, then x-large, and finally small. At the end of the day, the profit (not accounting for the coupons) from your sales was $46.50. Did you make the $20 net profit goal?\r\n(This is strictly profit of sale over purchase, not involving paying employees, bills, etc. Also, assume that the customers who use the coupons would not have returned if they didn't have the coupon. Therefore, the loss from a coupon is the cost for you to make the slush, not the price you would normally receive for it.)", "hint": "Here is the profit made on each size (found using the information in the first few sentences):\r\nSmall: $0.75\r\nMedium: $1.00\r\nLarge: $1.75\r\nX-large: $2.00", "answer": "(1): m=4s\r\n(2): m > l > x > s\r\n(3): 75s + 100m + 175l + 200x = 4650, divided by 25 gives...\r\n(4): 3s + 4m + 7l + 8x = 186\r\n(1) subbed into (4) gives (5): 19s + 7l + 8x = 186\n\r\nCan s=2? m would be 8, the maximum for l would be 7, and the maximum for x would be 6. For these maximum values, (5) says 135 = 186. The left side, which is at its maximum, is less than the right side, so s must be at least 3.\n\r\nCan s=5? The least x can be is 6, and the minimum for l is 7. This minimum substituted into (5) gives 192 = 186. So 5 is too high to be s.\n\r\nNow we know that s must be either 3 or 4. Let's set s equal to 3 for now, and see what happens.\n\r\nSubstituting into (5) gives: 7l + 8x = 129, solved for l gives (6): l = (129 - 8x) / 7\r\nWe know x is at least 4, because s is 3. So let's try different values for x, starting at 4, and substitute into (6).\r\nIf x=4, then l=13 6/7, which is not a whole number, proving impossible.\r\nIf x=5, then l=12 5/7, also not a whole number. As x increases by 1, the remainder decreases by 1. So we have to increase x by 5 to get to a whole number l-value.\r\nIf x=10, then l = 7. Now we have a whole number for l...however, x is greater than l, so (2) is now false. We can also see that if we increase x further, l will be decreasing, so (2) will only continue farther and farther from truth.\r\nThis proves that s cannot be 3, and is now narrowed down to s=4.\n\r\nSubstituting s=4 into (5) gives: 7l + 8x = 110, solved for l gives (7): l = (110 - 8x) / 7.\r\nNow we again test x-values (minimum of x=5) for valid results: If x=5, l=10. Because l is a whole number greater than x, this is a valid solution! Increasing x by 7 to find the next possibility gives x=12, l=2. x > l, so any greater x-value is impossible.\n\r\nThe solution is s=4, m=16, x=5, l=10. This is a total of 35 slushes, and therefore 35 coupons given out. 35 * $0.75 = $26.25 in losses from the coupons. $46.50 - $26.25 = $20.25 net profit when accounting for the coupons. You made your goal!", "category": "Math", "date": "11/01/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a small shack in a parking lot, out of which you sell slushes for a few hours a day. You sell them in 4 sizes: small (12 oz), medium (20 oz), large (32 oz), and x-large (40 oz), and you charge $1.50, $2.25, $3.75, and $4.50 for each size, respectively. The cups cost you 3 cents for small, 5 cents for medium, 8 cents for large, and 10 cents for x-large, and the slush ingredients cost you 6 cents per ounce. Today, you are having a special: with every slush purchased, the customer receives a coupon for a free small slush. You figure that this special will increase sales for the day, but that the losses (due to giving out free slushes in the future) will cut the profit down to a much-below-average day. Your hope, though, is that it will help by drawing more regular customers in the long run. Your goal is to profit $20 even after the coupon losses. Through the day, medium was the best-selling size -- they sold exactly 4 times as many as smalls! -- followed by large, then x-large, and finally small. At the end of the day, the profit (not accounting for the coupons) from your sales was $46.50. Did you make the $20 net profit goal?\r\n(This is strictly profit of sale over purchase, not involving paying employees, bills, etc. Also, assume that the customers who use the coupons would not have returned if they didn't have the coupon. Therefore, the loss from a coupon is the cost for you to make the slush, not the price you would normally receive for it.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(1): m=4s\r\n(2): m > l > x > s\r\n(3): 75s + 100m + 175l + 200x = 4650, divided by 25 gives...\r\n(4): 3s + 4m + 7l + 8x = 186\r\n(1) subbed into (4) gives (5): 19s + 7l + 8x = 186\n\r\nCan s=2? m would be 8, the maximum for l would be 7, and the maximum for x would be 6. For these maximum values, (5) says 135 = 186. The left side, which is at its maximum, is less than the right side, so s must be at least 3.\n\r\nCan s=5? The least x can be is 6, and the minimum for l is 7. This minimum substituted into (5) gives 192 = 186. So 5 is too high to be s.\n\r\nNow we know that s must be either 3 or 4. Let's set s equal to 3 for now, and see what happens.\n\r\nSubstituting into (5) gives: 7l + 8x = 129, solved for l gives (6): l = (129 - 8x) / 7\r\nWe know x is at least 4, because s is 3. So let's try different values for x, starting at 4, and substitute into (6).\r\nIf x=4, then l=13 6/7, which is not a whole number, proving impossible.\r\nIf x=5, then l=12 5/7, also not a whole number. As x increases by 1, the remainder decreases by 1. So we have to increase x by 5 to get to a whole number l-value.\r\nIf x=10, then l = 7. Now we have a whole number for l...however, x is greater than l, so (2) is now false. We can also see that if we increase x further, l will be decreasing, so (2) will only continue farther and farther from truth.\r\nThis proves that s cannot be 3, and is now narrowed down to s=4.\n\r\nSubstituting s=4 into (5) gives: 7l + 8x = 110, solved for l gives (7): l = (110 - 8x) / 7.\r\nNow we again test x-values (minimum of x=5) for valid results: If x=5, l=10. Because l is a whole number greater than x, this is a valid solution! Increasing x by 7 to find the next possibility gives x=12, l=2. x > l, so any greater x-value is impossible.\n\r\nThe solution is s=4, m=16, x=5, l=10. This is a total of 35 slushes, and therefore 35 coupons given out. 35 * $0.75 = $26.25 in losses from the coupons. $46.50 - $26.25 = $20.25 net profit when accounting for the coupons. You made your goal!\n<|im_start|>answer\n(1): m=4s\r\n(2): m > l > x > s\r\n(3): 75s + 100m + 175l + 200x = 4650, divided by 25 gives...\r\n(4): 3s + 4m + 7l + 8x = 186\r\n(1) subbed into (4) gives (5): 19s + 7l + 8x = 186\n\r\nCan s=2? m would be 8, the maximum for l would be 7, and the maximum for x would be 6. For these maximum values, (5) says 135 = 186. The left side, which is at its maximum, is less than the right side, so s must be at least 3.\n\r\nCan s=5? The least x can be is 6, and the minimum for l is 7. This minimum substituted into (5) gives 192 = 186. So 5 is too high to be s.\n\r\nNow we know that s must be either 3 or 4. Let's set s equal to 3 for now, and see what happens.\n\r\nSubstituting into (5) gives: 7l + 8x = 129, solved for l gives (6): l = (129 - 8x) / 7\r\nWe know x is at least 4, because s is 3. So let's try different values for x, starting at 4, and substitute into (6).\r\nIf x=4, then l=13 6/7, which is not a whole number, proving impossible.\r\nIf x=5, then l=12 5/7, also not a whole number. As x increases by 1, the remainder decreases by 1. So we have to increase x by 5 to get to a whole number l-value.\r\nIf x=10, then l = 7. Now we have a whole number for l...however, x is greater than l, so (2) is now false. We can also see that if we increase x further, l will be decreasing, so (2) will only continue farther and farther from truth.\r\nThis proves that s cannot be 3, and is now narrowed down to s=4.\n\r\nSubstituting s=4 into (5) gives: 7l + 8x = 110, solved for l gives (7): l = (110 - 8x) / 7.\r\nNow we again test x-values (minimum of x=5) for valid results: If x=5, l=10. Because l is a whole number greater than x, this is a valid solution! Increasing x by 7 to find the next possibility gives x=12, l=2. x > l, so any greater x-value is impossible.\n\r\nThe solution is s=4, m=16, x=5, l=10. This is a total of 35 slushes, and therefore 35 coupons given out. 35 * $0.75 = $26.25 in losses from the coupons. $46.50 - $26.25 = $20.25 net profit when accounting for the coupons. You made your goal!\n<|im_end|>" }, { "id": "#9405", "title": "Snapoker Championships", "fun": 2.56, "difficulty": 2.36, "author": "snaps", "desc": "The card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frenetic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nAt the 2002 International Snapoker Championships, the final was very hotly contested. Despite the high level of competitiveness in the final, no fights broke out. It was also a day for the history books as it had often been speculated in \"Here Piggy!\", the official Snapoker magazine, that the longest official Snapoker game, which was played in 1979 and lasted for 186 hands, would never be surpassed (incidentally, this 186-hand game was concluded when the fourth placed player lost his marbles and started the biggest Snapoker fight ever seen). Not only did the 2002 ISC final surpass the 186-hand record, it guaranteed that this new record could never be beaten again, only equalled. How many hands were played in the 2002 ISC final?", "hint": "In each hand there are a total of 10 points on offer, so after any given hand the total of all four players' scores must be a multiple of 10.", "answer": "There were 207 hands dealt in all.\n\r\nIn each hand of Snapoker there are a total of 10 points on offer, so after any given hand the total of all four players' scores must be a multiple of 10.\n\r\nThe highest total of all four players' scores such that the individual scores are still all less than the 518-point winning mark is 2060 (eg. 517, 516, 514, 513 or some other similar combination), which corresponds to 206 hands. This would mean that on the 207th hand one of the players would finally and inevitably win the game.", "category": "Math", "date": "12/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frenetic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nAt the 2002 International Snapoker Championships, the final was very hotly contested. Despite the high level of competitiveness in the final, no fights broke out. It was also a day for the history books as it had often been speculated in \"Here Piggy!\", the official Snapoker magazine, that the longest official Snapoker game, which was played in 1979 and lasted for 186 hands, would never be surpassed (incidentally, this 186-hand game was concluded when the fourth placed player lost his marbles and started the biggest Snapoker fight ever seen). Not only did the 2002 ISC final surpass the 186-hand record, it guaranteed that this new record could never be beaten again, only equalled. How many hands were played in the 2002 ISC final?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 207 hands dealt in all.\n\r\nIn each hand of Snapoker there are a total of 10 points on offer, so after any given hand the total of all four players' scores must be a multiple of 10.\n\r\nThe highest total of all four players' scores such that the individual scores are still all less than the 518-point winning mark is 2060 (eg. 517, 516, 514, 513 or some other similar combination), which corresponds to 206 hands. This would mean that on the 207th hand one of the players would finally and inevitably win the game.\n<|im_start|>answer\nThere were 207 hands dealt in all.\n\r\nIn each hand of Snapoker there are a total of 10 points on offer, so after any given hand the total of all four players' scores must be a multiple of 10.\n\r\nThe highest total of all four players' scores such that the individual scores are still all less than the 518-point winning mark is 2060 (eg. 517, 516, 514, 513 or some other similar combination), which corresponds to 206 hands. This would mean that on the 207th hand one of the players would finally and inevitably win the game.\n<|im_end|>" }, { "id": "#32059", "title": "Popcorn Problems", "fun": 2.56, "difficulty": 2.72, "author": "TheRiddler1024", "desc": "When the circus's popcorn vendor went on vacation, Charlie the Chimp saw it as the perfect opportunity to start a new act, so he volunteered to man the stand. Everything was going great until the very end of the day, when a set of twins showed up. There was just 1 large box of popcorn left to sell, and it was too late to pop another batch, so the twins asked Charlie if he could split the popcorn into two equal portions.Charlie knew that the large box held exactly 12 cups of popcorn. He also had 2 empty boxes on hand: a medium box that held exactly 8 cups and a small box that held exactly 5 cups. But none of the boxes had any measurement markings on them. There must be a way to divide the 12 cups of popcorn so that the two boxes contain exactly 6 cups each, thought the chimp. \r\nHow did he give out an equal amount of popcorn to the twins?", "hint": "No hint available.", "answer": "Fill the 8-cup box from the 12-cup box, leaving 4 cups. Fill the 5-cup box from the 8-cup box, leaving 3 cups. Empty the 5-cup box into the 12-cup box. Now there are 9 cups in the 12-cup box and 3 cups in the 8-cup box. Pour the 3 cups into the 5-cup box. Fill the 8-cup box from the 12-cup box, leaving 1 cup in the 12-cup box. Fill the 5-cup box (it already has 3 cups in it) from the 8-cup box, leaving 6 cups in the 8-cup box. Finally, empty the 5-cup box into the 12-cup box. This results in 6 cups in the 12-cup box, 6 cups in the 8-cup box, and nothing in the 5-cup box.", "category": "Math", "date": "07/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen the circus's popcorn vendor went on vacation, Charlie the Chimp saw it as the perfect opportunity to start a new act, so he volunteered to man the stand. Everything was going great until the very end of the day, when a set of twins showed up. There was just 1 large box of popcorn left to sell, and it was too late to pop another batch, so the twins asked Charlie if he could split the popcorn into two equal portions.Charlie knew that the large box held exactly 12 cups of popcorn. He also had 2 empty boxes on hand: a medium box that held exactly 8 cups and a small box that held exactly 5 cups. But none of the boxes had any measurement markings on them. There must be a way to divide the 12 cups of popcorn so that the two boxes contain exactly 6 cups each, thought the chimp. \r\nHow did he give out an equal amount of popcorn to the twins?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFill the 8-cup box from the 12-cup box, leaving 4 cups. Fill the 5-cup box from the 8-cup box, leaving 3 cups. Empty the 5-cup box into the 12-cup box. Now there are 9 cups in the 12-cup box and 3 cups in the 8-cup box. Pour the 3 cups into the 5-cup box. Fill the 8-cup box from the 12-cup box, leaving 1 cup in the 12-cup box. Fill the 5-cup box (it already has 3 cups in it) from the 8-cup box, leaving 6 cups in the 8-cup box. Finally, empty the 5-cup box into the 12-cup box. This results in 6 cups in the 12-cup box, 6 cups in the 8-cup box, and nothing in the 5-cup box.\n<|im_start|>answer\nFill the 8-cup box from the 12-cup box, leaving 4 cups. Fill the 5-cup box from the 8-cup box, leaving 3 cups. Empty the 5-cup box into the 12-cup box. Now there are 9 cups in the 12-cup box and 3 cups in the 8-cup box. Pour the 3 cups into the 5-cup box. Fill the 8-cup box from the 12-cup box, leaving 1 cup in the 12-cup box. Fill the 5-cup box (it already has 3 cups in it) from the 8-cup box, leaving 6 cups in the 8-cup box. Finally, empty the 5-cup box into the 12-cup box. This results in 6 cups in the 12-cup box, 6 cups in the 8-cup box, and nothing in the 5-cup box.\n<|im_end|>" }, { "id": "#5023", "title": "Chess Tournament", "fun": 2.56, "difficulty": 2.77, "author": "Beelzebub", "desc": "During the final round of a chess tournament, the eventual top 4 finishers in the tournament played their final game against 4 different opponents. The tournament boards were numbered from 1 to 50 to facilitate location and identification of games. Each of the top 4 finishers played a different opening in this last game. Use the clues below to determine the first and last names of the first through fourth place winners of the tournament, the chess opening each used in his last game, and the number of the chess board on which he played his final game. \n\r\n1. Mr. Hart played the King's Indian Defence.\n\r\n2. Steve placed ahead of the one who used the Ruy Lopez opening.\n\r\n3. The top 4 players were Larry, Mr. Korn, the contestant who opened with Queen's Gambit, and a player who played on an even-numbered board.\n\r\n4. Mr. Rose finished exactly 2 places ahead of the player on board 31.\n\r\n5. The number of the 3rd place winner's board is at least 10 higher or at least 10 lower than that of Mr. Baird.\n\r\n6. The number of the board of the contestant who placed immediately after Bert is exactly 15 higher than the number of the board played by the one who placed immediately before Tom.\n\r\n7. The lowest board number of the top 4 finishers was exactly half the number of the board played by the one who placed immediately after the one who played the Giuoco Piano opening.\n\r\n8. The highest board number was exactly 8 higher than the board number of the man who finished exactly two places after Bert.", "hint": "All other information (First name, Surname, Moves, Positions) are given in the puzzle, apart from the board numbers. The key to this puzzle is figuring them out, and then everything falls into place. Try different combinations, there is only one that works.", "answer": "Firstly, work out the board numbers. We know that Bert finished in the first 2 (Clue 8) and board 31 finished in the last 2 (Clue 4). Using all combinations of these, we can eliminate all but the correct numbers, ie 16, 31, 32 and 40.\n\r\nAfter we know the numbers, the rest falls into place.\n\r\nFirst: Steve Rose, Queen's Gambit, board 40\r\nSecond: Bert Baird, Ruy Lopez, board 16\r\nThird: Tom Korn, Giuoco Piano, board 31\r\nFourth: Larry Hart, King's Indian, board 32", "category": "Logic", "date": "06/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring the final round of a chess tournament, the eventual top 4 finishers in the tournament played their final game against 4 different opponents. The tournament boards were numbered from 1 to 50 to facilitate location and identification of games. Each of the top 4 finishers played a different opening in this last game. Use the clues below to determine the first and last names of the first through fourth place winners of the tournament, the chess opening each used in his last game, and the number of the chess board on which he played his final game. \n\r\n1. Mr. Hart played the King's Indian Defence.\n\r\n2. Steve placed ahead of the one who used the Ruy Lopez opening.\n\r\n3. The top 4 players were Larry, Mr. Korn, the contestant who opened with Queen's Gambit, and a player who played on an even-numbered board.\n\r\n4. Mr. Rose finished exactly 2 places ahead of the player on board 31.\n\r\n5. The number of the 3rd place winner's board is at least 10 higher or at least 10 lower than that of Mr. Baird.\n\r\n6. The number of the board of the contestant who placed immediately after Bert is exactly 15 higher than the number of the board played by the one who placed immediately before Tom.\n\r\n7. The lowest board number of the top 4 finishers was exactly half the number of the board played by the one who placed immediately after the one who played the Giuoco Piano opening.\n\r\n8. The highest board number was exactly 8 higher than the board number of the man who finished exactly two places after Bert.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirstly, work out the board numbers. We know that Bert finished in the first 2 (Clue 8) and board 31 finished in the last 2 (Clue 4). Using all combinations of these, we can eliminate all but the correct numbers, ie 16, 31, 32 and 40.\n\r\nAfter we know the numbers, the rest falls into place.\n\r\nFirst: Steve Rose, Queen's Gambit, board 40\r\nSecond: Bert Baird, Ruy Lopez, board 16\r\nThird: Tom Korn, Giuoco Piano, board 31\r\nFourth: Larry Hart, King's Indian, board 32\n<|im_start|>answer\nFirstly, work out the board numbers. We know that Bert finished in the first 2 (Clue 8) and board 31 finished in the last 2 (Clue 4). Using all combinations of these, we can eliminate all but the correct numbers, ie 16, 31, 32 and 40.\n\r\nAfter we know the numbers, the rest falls into place.\n\r\nFirst: Steve Rose, Queen's Gambit, board 40\r\nSecond: Bert Baird, Ruy Lopez, board 16\r\nThird: Tom Korn, Giuoco Piano, board 31\r\nFourth: Larry Hart, King's Indian, board 32\n<|im_end|>" }, { "id": "#21305", "title": "Cell Phones", "fun": 2.56, "difficulty": 0.85, "author": "JessicaLynn", "desc": "These five people are always on their new cell phones; Lora, Jessica, Jennifer, Karen, and Barbara. They each try to think of as many reasons as they can to use their cell phones. They each use their cell phones 32, 12, 13, 9, or 4 times a day. They also have cell phones of their favorite animal; Elephants, Monkeys, Bears, Cats, and Dogs. Figure out which type of cell phones they have and how many times a day they use their cell phone with these clues.\n\r\n1) Jessica, who hates monkeys, (especially since she is always called one), doesn't use her cell phone more than ten times a day.\n\r\n2) Karen doesn't use her cell phone more than the one who has cats on her cell phone, but does use it more than Jessica.\n\r\n3) Jessica's favorite animal is not the bear, but the one who does have the bear uses it 13 times a day.\n\r\n4) Barbara doesn't use her cell phone 9 or 4 times a day. \n\r\n5) Jennifer uses her cell phone 12 times a day.\n\r\n6) Lora uses her cell phone more than Jennifer, but less than Barbara.\n\r\n7) Jessica uses her phone less than Karen, who doesn't have elephants or monkeys on her cell phone.\n\r\n8) Barbara has either dogs or cats on her phone.", "hint": "No hint available.", "answer": "Jessica Elephants 4\r\nJennifer Monkeys 12\r\nLora Bears 13 \r\nKaren Dogs 9\r\nBarbara Cats 32", "category": "Logic-Grid", "date": "03/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThese five people are always on their new cell phones; Lora, Jessica, Jennifer, Karen, and Barbara. They each try to think of as many reasons as they can to use their cell phones. They each use their cell phones 32, 12, 13, 9, or 4 times a day. They also have cell phones of their favorite animal; Elephants, Monkeys, Bears, Cats, and Dogs. Figure out which type of cell phones they have and how many times a day they use their cell phone with these clues.\n\r\n1) Jessica, who hates monkeys, (especially since she is always called one), doesn't use her cell phone more than ten times a day.\n\r\n2) Karen doesn't use her cell phone more than the one who has cats on her cell phone, but does use it more than Jessica.\n\r\n3) Jessica's favorite animal is not the bear, but the one who does have the bear uses it 13 times a day.\n\r\n4) Barbara doesn't use her cell phone 9 or 4 times a day. \n\r\n5) Jennifer uses her cell phone 12 times a day.\n\r\n6) Lora uses her cell phone more than Jennifer, but less than Barbara.\n\r\n7) Jessica uses her phone less than Karen, who doesn't have elephants or monkeys on her cell phone.\n\r\n8) Barbara has either dogs or cats on her phone.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJessica Elephants 4\r\nJennifer Monkeys 12\r\nLora Bears 13 \r\nKaren Dogs 9\r\nBarbara Cats 32\n<|im_start|>answer\nJessica Elephants 4\r\nJennifer Monkeys 12\r\nLora Bears 13 \r\nKaren Dogs 9\r\nBarbara Cats 32\n<|im_end|>" }, { "id": "#3522", "title": "Mother-in-Law Relationships", "fun": 2.56, "difficulty": 1.98, "author": "arij", "desc": "A man and a lady were walking out of the airport when a person asked them their relationship. The man replied, \"Her mother-in-law and my mother-in-law are mother and daughter to each other\"\n\r\nWhat's the man's relationship with the lady?", "hint": "No hint available.", "answer": "The lady is the man's daughter-in-law.", "category": "Logic", "date": "04/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man and a lady were walking out of the airport when a person asked them their relationship. The man replied, \"Her mother-in-law and my mother-in-law are mother and daughter to each other\"\n\r\nWhat's the man's relationship with the lady?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lady is the man's daughter-in-law.\n<|im_start|>answer\nThe lady is the man's daughter-in-law.\n<|im_end|>" }, { "id": "#44170", "title": "Bingo Card 2", "fun": 2.56, "difficulty": 2.65, "author": "cnmne", "desc": "You are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) Row 1: the tens digits are all different.\r\n2) Row 2: the numbers are even.\r\n3) Row 4: the sum of the five numbers is 178.\r\n4) Row 5: the numbers are prime.\r\n5) Column B: the sum of the five numbers is 60.\r\n6) Column I: two of the numbers are greater than 19.\r\n7) Column O: the numbers are in increasing equally-spaced order, from top to bottom.\r\n8) The product of B3 and O3 is between 600 and 700.\r\n9) The sum of I1 and G5 equals the sum of G1 and I5.\r\n10) N1 is midway between I4 and G4.\r\n11) N5 is midway between I2 and G2.\r\n12) I3 is midway between B1 and N1, and G3 is midway between N1 and O1.\r\n13) There are five numbers that are divisible by 11; only one per row and one per column.\r\n14) There is one triangle number in each column.", "hint": "No hint available.", "answer": "13 21 31 55 63\r\n12 18 44 56 64\r\n10 22 -- 47 65\r\n14 16 36 46 66\r\n11 19 37 53 67\n\r\n1) Per clue 2, eliminate the odd numbers in row 2.\r\n2) Per clue 4, eliminate the non-prime numbers in row 5.\r\n3) Per clue 14, 55 must be in column G and 66 must be in column O.\r\n4) Per clue 7, column O must contain 63 through 67, in order, from top to bottom.\r\n5) Per clue 8, B3 must be 10 (a triangle number).\r\n6) Per clue 14, eliminate the following numbers from column B: 1, 3, 6, and 15.\r\n7) Per clue 5, eliminate numbers less than 10.\r\n8) Per clue 12, eliminate impossible combinations.\r\n9) Per clue 13, G1 must be 55. B1 can not be 11, therefore B1 must be 13 and B5 must be 11.\r\n10) Per clue 1, I1 must be greater than 19. Per clue 9, I1 must be 21 or 25 or 27. Per clue 13, 22 must be in column I. Per clue 14, 21 or 28 must be in column I. Per clue 6, only two numbers in column I can be greater than 19. I1 must be 21 and I3 must be 22.\r\n11) Per clue 12, N1 must be 31 and G3 must be 47.\r\n12) Per clue 13, N2 must be 44.\r\n13) Per clue 9, I5 must be 19 and G5 must be 53.\r\n14) Per clue 10, I4 must be 16 and N4 must be 46. This leaves I2 as 18.\r\n15) Per clue 11, N5 must be 37 and G2 must be 56.\r\n16) Per clue 14, N4 must be 36 or 45. Per clue 3, since the sum is even, N4 must be 36. B4 must be 14. This leaves B2 as 12.", "category": "Logic", "date": "03/02/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) Row 1: the tens digits are all different.\r\n2) Row 2: the numbers are even.\r\n3) Row 4: the sum of the five numbers is 178.\r\n4) Row 5: the numbers are prime.\r\n5) Column B: the sum of the five numbers is 60.\r\n6) Column I: two of the numbers are greater than 19.\r\n7) Column O: the numbers are in increasing equally-spaced order, from top to bottom.\r\n8) The product of B3 and O3 is between 600 and 700.\r\n9) The sum of I1 and G5 equals the sum of G1 and I5.\r\n10) N1 is midway between I4 and G4.\r\n11) N5 is midway between I2 and G2.\r\n12) I3 is midway between B1 and N1, and G3 is midway between N1 and O1.\r\n13) There are five numbers that are divisible by 11; only one per row and one per column.\r\n14) There is one triangle number in each column.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n13 21 31 55 63\r\n12 18 44 56 64\r\n10 22 -- 47 65\r\n14 16 36 46 66\r\n11 19 37 53 67\n\r\n1) Per clue 2, eliminate the odd numbers in row 2.\r\n2) Per clue 4, eliminate the non-prime numbers in row 5.\r\n3) Per clue 14, 55 must be in column G and 66 must be in column O.\r\n4) Per clue 7, column O must contain 63 through 67, in order, from top to bottom.\r\n5) Per clue 8, B3 must be 10 (a triangle number).\r\n6) Per clue 14, eliminate the following numbers from column B: 1, 3, 6, and 15.\r\n7) Per clue 5, eliminate numbers less than 10.\r\n8) Per clue 12, eliminate impossible combinations.\r\n9) Per clue 13, G1 must be 55. B1 can not be 11, therefore B1 must be 13 and B5 must be 11.\r\n10) Per clue 1, I1 must be greater than 19. Per clue 9, I1 must be 21 or 25 or 27. Per clue 13, 22 must be in column I. Per clue 14, 21 or 28 must be in column I. Per clue 6, only two numbers in column I can be greater than 19. I1 must be 21 and I3 must be 22.\r\n11) Per clue 12, N1 must be 31 and G3 must be 47.\r\n12) Per clue 13, N2 must be 44.\r\n13) Per clue 9, I5 must be 19 and G5 must be 53.\r\n14) Per clue 10, I4 must be 16 and N4 must be 46. This leaves I2 as 18.\r\n15) Per clue 11, N5 must be 37 and G2 must be 56.\r\n16) Per clue 14, N4 must be 36 or 45. Per clue 3, since the sum is even, N4 must be 36. B4 must be 14. This leaves B2 as 12.\n<|im_start|>answer\n13 21 31 55 63\r\n12 18 44 56 64\r\n10 22 -- 47 65\r\n14 16 36 46 66\r\n11 19 37 53 67\n\r\n1) Per clue 2, eliminate the odd numbers in row 2.\r\n2) Per clue 4, eliminate the non-prime numbers in row 5.\r\n3) Per clue 14, 55 must be in column G and 66 must be in column O.\r\n4) Per clue 7, column O must contain 63 through 67, in order, from top to bottom.\r\n5) Per clue 8, B3 must be 10 (a triangle number).\r\n6) Per clue 14, eliminate the following numbers from column B: 1, 3, 6, and 15.\r\n7) Per clue 5, eliminate numbers less than 10.\r\n8) Per clue 12, eliminate impossible combinations.\r\n9) Per clue 13, G1 must be 55. B1 can not be 11, therefore B1 must be 13 and B5 must be 11.\r\n10) Per clue 1, I1 must be greater than 19. Per clue 9, I1 must be 21 or 25 or 27. Per clue 13, 22 must be in column I. Per clue 14, 21 or 28 must be in column I. Per clue 6, only two numbers in column I can be greater than 19. I1 must be 21 and I3 must be 22.\r\n11) Per clue 12, N1 must be 31 and G3 must be 47.\r\n12) Per clue 13, N2 must be 44.\r\n13) Per clue 9, I5 must be 19 and G5 must be 53.\r\n14) Per clue 10, I4 must be 16 and N4 must be 46. This leaves I2 as 18.\r\n15) Per clue 11, N5 must be 37 and G2 must be 56.\r\n16) Per clue 14, N4 must be 36 or 45. Per clue 3, since the sum is even, N4 must be 36. B4 must be 14. This leaves B2 as 12.\n<|im_end|>" }, { "id": "#8904", "title": "Sweets", "fun": 2.56, "difficulty": 1.81, "author": "master123", "desc": "For being good at the garden fete, four children were each given two sweets. Jack had an orange sweet. The child who had a red one also had a blue one. No child had two sweets of the same colour. The child who had a green sweet also had a red one. Jim didn't have a red sweet and Joe had a green one. James didn't have an orange one and Jack had no blue sweets. Knowing that there were two sweets of each colour, can you tell the colours of the sweets each child had?", "hint": "No hint available.", "answer": "Jack had an orange and a green sweet.\r\nJim had an orange and a blue one.\r\nJames had a red and a blue sweet.\r\nJoe had a green and a red one.", "category": "Logic", "date": "12/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor being good at the garden fete, four children were each given two sweets. Jack had an orange sweet. The child who had a red one also had a blue one. No child had two sweets of the same colour. The child who had a green sweet also had a red one. Jim didn't have a red sweet and Joe had a green one. James didn't have an orange one and Jack had no blue sweets. Knowing that there were two sweets of each colour, can you tell the colours of the sweets each child had?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJack had an orange and a green sweet.\r\nJim had an orange and a blue one.\r\nJames had a red and a blue sweet.\r\nJoe had a green and a red one.\n<|im_start|>answer\nJack had an orange and a green sweet.\r\nJim had an orange and a blue one.\r\nJames had a red and a blue sweet.\r\nJoe had a green and a red one.\n<|im_end|>" }, { "id": "#31502", "title": "Counting Wrappers", "fun": 2.56, "difficulty": 2.1, "author": "MarcM1098", "desc": "Your favourite chocolate bar is having a special promotion, buy 10 get 1 free! To get a free bar, simply collect 10 wrappers and turn them in for 1 free bar. What fraction of a bar is each wrapper worth?", "hint": "Remember that the free bar has a wrapper.", "answer": "Each wrapper is worth 1/9 of a bar.\n\r\n10 wrappers are worth 1 free bar, so it appears each wrapper is worth 1/10 of a bar, except that the free bar comes with a wrapper.\n\r\n10 wrappers are worth 1 free bar (with 1 free wrapper), so each wrapper is worth 1/10 of a bar plus 1/10 of a wrapper. The 1/10 of a wrapper is worth 1/100 of a bar plus 1/100 of a wrapper, and so on. 1/10 + 1/100 + 1/1000 + ... = 0.111... = 1/9.\n\r\nThe answer can be shown with the following algebra, where w is the value of a wrapper, and b is the value of a bar.\r\n10w = b + w (10 wrappers are worth 1 bar with 1 wrapper)\r\n9w = b (subtract w from each side)\r\nw = b/9 (divide both sides by 9)\r\nEach wrapper (w) is worth 1/9 of a bar (b).", "category": "Math", "date": "07/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour favourite chocolate bar is having a special promotion, buy 10 get 1 free! To get a free bar, simply collect 10 wrappers and turn them in for 1 free bar. What fraction of a bar is each wrapper worth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach wrapper is worth 1/9 of a bar.\n\r\n10 wrappers are worth 1 free bar, so it appears each wrapper is worth 1/10 of a bar, except that the free bar comes with a wrapper.\n\r\n10 wrappers are worth 1 free bar (with 1 free wrapper), so each wrapper is worth 1/10 of a bar plus 1/10 of a wrapper. The 1/10 of a wrapper is worth 1/100 of a bar plus 1/100 of a wrapper, and so on. 1/10 + 1/100 + 1/1000 + ... = 0.111... = 1/9.\n\r\nThe answer can be shown with the following algebra, where w is the value of a wrapper, and b is the value of a bar.\r\n10w = b + w (10 wrappers are worth 1 bar with 1 wrapper)\r\n9w = b (subtract w from each side)\r\nw = b/9 (divide both sides by 9)\r\nEach wrapper (w) is worth 1/9 of a bar (b).\n<|im_start|>answer\nEach wrapper is worth 1/9 of a bar.\n\r\n10 wrappers are worth 1 free bar, so it appears each wrapper is worth 1/10 of a bar, except that the free bar comes with a wrapper.\n\r\n10 wrappers are worth 1 free bar (with 1 free wrapper), so each wrapper is worth 1/10 of a bar plus 1/10 of a wrapper. The 1/10 of a wrapper is worth 1/100 of a bar plus 1/100 of a wrapper, and so on. 1/10 + 1/100 + 1/1000 + ... = 0.111... = 1/9.\n\r\nThe answer can be shown with the following algebra, where w is the value of a wrapper, and b is the value of a bar.\r\n10w = b + w (10 wrappers are worth 1 bar with 1 wrapper)\r\n9w = b (subtract w from each side)\r\nw = b/9 (divide both sides by 9)\r\nEach wrapper (w) is worth 1/9 of a bar (b).\n<|im_end|>" }, { "id": "#1180", "title": "Threes and Sevens", "fun": 2.56, "difficulty": 2.58, "author": "thephirm", "desc": "Using the four digits 3,3,7,7 and the mathematical operators +,-,*,/ write an expression equal to 24. You must use each digit exactly once, but may use each operator multiple times, or not at all. Parentheses are allowed. The following would be a valid expression: \n\r\n\t(7 + 3)/(7 + 3) = 1", "hint": "Think fractions.", "answer": "(3 + 3/7) * 7 = 24", "category": "Math", "date": "10/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the four digits 3,3,7,7 and the mathematical operators +,-,*,/ write an expression equal to 24. You must use each digit exactly once, but may use each operator multiple times, or not at all. Parentheses are allowed. The following would be a valid expression: \n\r\n\t(7 + 3)/(7 + 3) = 1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(3 + 3/7) * 7 = 24\n<|im_start|>answer\n(3 + 3/7) * 7 = 24\n<|im_end|>" }, { "id": "#436", "title": "How Many In The Family?", "fun": 2.56, "difficulty": 1.61, "author": "Spikejw1", "desc": "Each son in the Hubbard family has just as many brothers as sisters, but each daughter has twice as many brothers as sisters.\n\nHow many boys and girls are there in the family?", "hint": "Do your math and remember one is not one`s own sibling.", "answer": "There are 4 boys and 3 girls in the family.\n\n(Each boy has 3 brothers and 3 sisters, but each girl has 4 brothers and 2 sisters.)", "category": "Math", "date": "05/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach son in the Hubbard family has just as many brothers as sisters, but each daughter has twice as many brothers as sisters.\n\nHow many boys and girls are there in the family?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 4 boys and 3 girls in the family.\n\n(Each boy has 3 brothers and 3 sisters, but each girl has 4 brothers and 2 sisters.)\n<|im_start|>answer\nThere are 4 boys and 3 girls in the family.\n\n(Each boy has 3 brothers and 3 sisters, but each girl has 4 brothers and 2 sisters.)\n<|im_end|>" }, { "id": "#37124", "title": "Birthday Buddies", "fun": 2.56, "difficulty": 1.67, "author": "beepbeeptnm", "desc": "Al, Betty, Charlie, Derrick, and Emily are good friends, and they all have consecutive birthdays.\n\r\n1) Al's birthday is as many days before Charlie's as Betty's is after Emily's.\n\r\n2) Derrick is 3 days older than Emily.\n\r\n3) Charlie's birthday this year is on Wednesday.\n\r\nOn which day of the week is each person's birthday?", "hint": "No hint available.", "answer": "Derrick's birthday is on Monday.\r\nAl's birthday is on Tuesday.\r\nCharlie's birthday is on Wednesday.\r\nEmily's birthday is on Thursday.\r\nBetty's birthday is on Friday.", "category": "Logic", "date": "06/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl, Betty, Charlie, Derrick, and Emily are good friends, and they all have consecutive birthdays.\n\r\n1) Al's birthday is as many days before Charlie's as Betty's is after Emily's.\n\r\n2) Derrick is 3 days older than Emily.\n\r\n3) Charlie's birthday this year is on Wednesday.\n\r\nOn which day of the week is each person's birthday?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDerrick's birthday is on Monday.\r\nAl's birthday is on Tuesday.\r\nCharlie's birthday is on Wednesday.\r\nEmily's birthday is on Thursday.\r\nBetty's birthday is on Friday.\n<|im_start|>answer\nDerrick's birthday is on Monday.\r\nAl's birthday is on Tuesday.\r\nCharlie's birthday is on Wednesday.\r\nEmily's birthday is on Thursday.\r\nBetty's birthday is on Friday.\n<|im_end|>" }, { "id": "#3475", "title": "Meeting Three People", "fun": 2.56, "difficulty": 1.27, "author": "missie", "desc": "I had to meet an Australian, an American and a South African at the airport. One of them was called Bruce, and I identified him immediately, despite never having met any of them before. How?", "hint": "No hint available.", "answer": "The other two were women.", "category": "Logic", "date": "04/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI had to meet an Australian, an American and a South African at the airport. One of them was called Bruce, and I identified him immediately, despite never having met any of them before. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe other two were women.\n<|im_start|>answer\nThe other two were women.\n<|im_end|>" }, { "id": "#39630", "title": "Opposites 35", "fun": 2.56, "difficulty": 1.98, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\nr stands for L, A, K, S, or T\r\nA stands for S, X, F, E, or A\r\nK stands for Y, P, M, G, or N\r\np stands for V, D, L, Q, or E\r\nS stands for U, B, I, M, or C\n\n\r\nThe five letter code word, SpArK, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Clean and Messy.", "category": "Logic", "date": "12/15/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\nr stands for L, A, K, S, or T\r\nA stands for S, X, F, E, or A\r\nK stands for Y, P, M, G, or N\r\np stands for V, D, L, Q, or E\r\nS stands for U, B, I, M, or C\n\n\r\nThe five letter code word, SpArK, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nClean and Messy.\n<|im_start|>answer\nClean and Messy.\n<|im_end|>" }, { "id": "#10946", "title": "Aeiea", "fun": 2.56, "difficulty": 1.45, "author": "Christina0213", "desc": "You are a traveler and stop in an inn to rest. While you sit by the fire, you meet another traveler, who introduces herself as Aeiea. You begin a pleasant conversation, and exchange information about why you are travelling. She says that she is travelling in search of gold that her ancestors buried, and if you come with her she will share it. You become excited until she adds one more comment about herself. \"Oh, I do need to tell you one thing. I always lie.\" \n\r\nNow you need to figure out two things: \r\n1) Is Aeiea telling the truth or lying when she says she always lies? \r\n2) Can you trust her story?", "hint": "It's not as hard as it might seem at first. Think CAREFULLY about what would be the case if she lied or told the truth with her final statement. Try not to make assumptions.", "answer": "1) Aeiea is lying. \n\r\nIt's really fairly simple. If Aeiea is telling the truth, that means that she does not ALWAYS lie, because then the statement would be false. It leaves that Aeiea must be lying when she says that she always lies. A common misconception is that if she is lying about always lying, that means she must always tell the truth, and if that were the case then neither case would be possible. However, she doesn't have to ALWAYS tell the truth if she's lying about always lying, she simply has to tell the truth SOME of the time. \n\r\n2) Taking into account the answer to number one, you cannot trust her story, as she does lie some of the time, not to mention the fact that she is obviously willing to lie to YOU.", "category": "Logic", "date": "03/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are a traveler and stop in an inn to rest. While you sit by the fire, you meet another traveler, who introduces herself as Aeiea. You begin a pleasant conversation, and exchange information about why you are travelling. She says that she is travelling in search of gold that her ancestors buried, and if you come with her she will share it. You become excited until she adds one more comment about herself. \"Oh, I do need to tell you one thing. I always lie.\" \n\r\nNow you need to figure out two things: \r\n1) Is Aeiea telling the truth or lying when she says she always lies? \r\n2) Can you trust her story?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Aeiea is lying. \n\r\nIt's really fairly simple. If Aeiea is telling the truth, that means that she does not ALWAYS lie, because then the statement would be false. It leaves that Aeiea must be lying when she says that she always lies. A common misconception is that if she is lying about always lying, that means she must always tell the truth, and if that were the case then neither case would be possible. However, she doesn't have to ALWAYS tell the truth if she's lying about always lying, she simply has to tell the truth SOME of the time. \n\r\n2) Taking into account the answer to number one, you cannot trust her story, as she does lie some of the time, not to mention the fact that she is obviously willing to lie to YOU.\n<|im_start|>answer\n1) Aeiea is lying. \n\r\nIt's really fairly simple. If Aeiea is telling the truth, that means that she does not ALWAYS lie, because then the statement would be false. It leaves that Aeiea must be lying when she says that she always lies. A common misconception is that if she is lying about always lying, that means she must always tell the truth, and if that were the case then neither case would be possible. However, she doesn't have to ALWAYS tell the truth if she's lying about always lying, she simply has to tell the truth SOME of the time. \n\r\n2) Taking into account the answer to number one, you cannot trust her story, as she does lie some of the time, not to mention the fact that she is obviously willing to lie to YOU.\n<|im_end|>" }, { "id": "#4634", "title": "Three Coins 2", "fun": 2.56, "difficulty": 1.44, "author": "bobbrt", "desc": "You are travelling to an exotic country which has three types of coins. Each coin has a different value (5, 10, or 15 units), a different color (red, green, or blue), and a different shape (round, square, and triangular). You have one of each coin in your pocket. \n\r\na) If you randomly select one coin, it will either be red, a circle, or the 5 unit coin. \r\nb) If you randomly select another coin, it will either be blue, a triangle, or the 10 unit coin. \r\nc) The triangular coin is worth more than the square coin.\r\nWhat is the color, shape, and value of each coin?", "hint": "No hint available.", "answer": "1) The 5 unit coin is blue and square.\r\n2) The 10 unit coin is green and round.\r\n3) The 15 unit coin is red and triangular.\n\r\nHere's how to solve it:\n\r\nStatement \"a\" will tell you that the round coin is not red or the 5 unit coin. Statement \"b\" indicates that the triangular coin is not blue or the 10 unit coin. Statement \"c\" then tells you that the triangular coin has to be the 15 unit coin (since it can't be the 5 unit coin, either).\r\nNow going back to statement \"a\", the round coin must be the 10 unit coin which makes the square coin the 5 unit coin. Also from statement \"a\" you can determine that the square coin is not red (since the 5 unit coin is not red), leaving the triangular coin to be red. From statement \"b\" you can determine that the square coin is blue, since the 10 unit coin (the round one) cannot be blue. This leaves the round coin to be green.", "category": "Logic", "date": "06/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are travelling to an exotic country which has three types of coins. Each coin has a different value (5, 10, or 15 units), a different color (red, green, or blue), and a different shape (round, square, and triangular). You have one of each coin in your pocket. \n\r\na) If you randomly select one coin, it will either be red, a circle, or the 5 unit coin. \r\nb) If you randomly select another coin, it will either be blue, a triangle, or the 10 unit coin. \r\nc) The triangular coin is worth more than the square coin.\r\nWhat is the color, shape, and value of each coin?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) The 5 unit coin is blue and square.\r\n2) The 10 unit coin is green and round.\r\n3) The 15 unit coin is red and triangular.\n\r\nHere's how to solve it:\n\r\nStatement \"a\" will tell you that the round coin is not red or the 5 unit coin. Statement \"b\" indicates that the triangular coin is not blue or the 10 unit coin. Statement \"c\" then tells you that the triangular coin has to be the 15 unit coin (since it can't be the 5 unit coin, either).\r\nNow going back to statement \"a\", the round coin must be the 10 unit coin which makes the square coin the 5 unit coin. Also from statement \"a\" you can determine that the square coin is not red (since the 5 unit coin is not red), leaving the triangular coin to be red. From statement \"b\" you can determine that the square coin is blue, since the 10 unit coin (the round one) cannot be blue. This leaves the round coin to be green.\n<|im_start|>answer\n1) The 5 unit coin is blue and square.\r\n2) The 10 unit coin is green and round.\r\n3) The 15 unit coin is red and triangular.\n\r\nHere's how to solve it:\n\r\nStatement \"a\" will tell you that the round coin is not red or the 5 unit coin. Statement \"b\" indicates that the triangular coin is not blue or the 10 unit coin. Statement \"c\" then tells you that the triangular coin has to be the 15 unit coin (since it can't be the 5 unit coin, either).\r\nNow going back to statement \"a\", the round coin must be the 10 unit coin which makes the square coin the 5 unit coin. Also from statement \"a\" you can determine that the square coin is not red (since the 5 unit coin is not red), leaving the triangular coin to be red. From statement \"b\" you can determine that the square coin is blue, since the 10 unit coin (the round one) cannot be blue. This leaves the round coin to be green.\n<|im_end|>" }, { "id": "#43910", "title": "The Truth Teller, The Liar, and The Unreliable Man", "fun": 2.56, "difficulty": 2.78, "author": "javaguru", "desc": "There are three men, Alex, Bob and Chuck. One of the men always tells the truth and one always lies. The third man always tells a lie after telling the truth and always tells the truth after telling a lie. The third man can answer the first question truthfully or can lie.\n\r\nCan you tell who is the truth teller, the liar and the unreliable man by asking just three questions? Each question is directed to a single person.", "hint": "No hint available.", "answer": "First ask Alex, \"Does Bob sometimes tell the truth and sometimes lie?\"\n\r\nA \"yes\" answer means one of the following must be true:\r\n1) Alex is the truth teller and Bob is unreliable;\r\n2) Alex is the liar and Bob is the truth teller;\r\n3) Alex is unreliable and is lying and Bob is the truth teller; or\r\n4) Alex is unreliable and is lying and Bob is the liar.\n\r\nA \"no\" answer means one of these must be true:\r\n1) Alex is the truth teller and Bob is the liar;\r\n2) Alex is the liar and Bob is unreliable;\r\n3) Alex is unreliable and is telling the truth and Bob is the truth teller; or\r\n4) Alex is unreliable and is telling the truth and Bob is the liar.\n\r\nIf the answer is \"yes\", you ask Alex \"Is Bob the liar?\"; if the answer is \"no\", you ask Alex \"Is Bob the truth teller?\"\n\r\nDepending on the answers to the first two questions, you know one of the following:\n\r\nA) If the answer to both questions was \"yes\" then either\r\n1) Alex is the liar and Bob is the truth teller; or\r\n2) Alex is unreliable and lied on the first question and Bob is the liar.\n\r\nB) If the answer to both questions is \"no\" then either\r\n1) Alex is the truth teller and Bob is the liar; or\r\n2) Alex is unreliable and Bob is the truth teller.\n\r\nC) If the answer to the first question was \"yes\" and the second question was \"no\" then either\r\n1) Alex is the truth teller and Bob is unreliable; or\r\n2) Alex is unreliable and lied on the first question and Bob is the truth teller.\r\nIn either case, Chuck is the liar.\n\r\nD) If the answer to the first question was \"no\" and the second question was \"yes\" then either\r\n1) Alex is the liar and Bob is unreliable; or\r\n2) Alex is unreliable and Bob is the liar.\r\nIn either case, Chuck is the truth teller.\n\r\nIn cases A & B you've identified one person as either the liar or the truth teller and you've identified another person as either not the liar or not the truth teller. In these cases you ask the person who is neither the liar or the truth teller a question you know the answer to. In cases C & D you've identified Chuck as either the liar or truth teller. At this point you simply ask Chuck a question to identify either Alex or Bob.\n\r\nSo the final question and results for each case are:\n\r\nA) You ask Bob \"Is Alex the truth teller?\"\r\n\"yes\" means that\r\nAlex is unreliable, Bob is the liar and Chuck is the truth teller;\r\n\"no\" means that\r\nAlex is the liar, Bob is the truth teller and Chuck is unreliable.\n\r\nB) You ask Bob \"Is Alex the liar?\"\r\n\"yes\" means that\r\nAlex is the truth teller, Bob is the liar and Chuck is unreliable;\r\n\"no\" means that\r\nAlex is unreliable, Bob is the truth teller and Chuck is the liar.\n\r\nC) You ask Chuck \"Is Alex the truth teller?\"\r\n\"yes\" means that\r\nAlex is unreliable, Bob is the truth teller and Chuck is the liar;\r\n\"no\" means that\r\nAlex is the truth teller, Bob is unreliable and Chuck is the liar.\n\r\nD) You ask Chuck \"Is Alex the liar?\"\r\n\"yes\" means that\r\nAlex is the liar, Bob is unreliable and Chuck is the truth teller;\r\n\"no\" means that\r\nAlex is unreliable, Bob is the liar and Chuck is the truth teller.", "category": "Logic", "date": "01/16/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three men, Alex, Bob and Chuck. One of the men always tells the truth and one always lies. The third man always tells a lie after telling the truth and always tells the truth after telling a lie. The third man can answer the first question truthfully or can lie.\n\r\nCan you tell who is the truth teller, the liar and the unreliable man by asking just three questions? Each question is directed to a single person.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst ask Alex, \"Does Bob sometimes tell the truth and sometimes lie?\"\n\r\nA \"yes\" answer means one of the following must be true:\r\n1) Alex is the truth teller and Bob is unreliable;\r\n2) Alex is the liar and Bob is the truth teller;\r\n3) Alex is unreliable and is lying and Bob is the truth teller; or\r\n4) Alex is unreliable and is lying and Bob is the liar.\n\r\nA \"no\" answer means one of these must be true:\r\n1) Alex is the truth teller and Bob is the liar;\r\n2) Alex is the liar and Bob is unreliable;\r\n3) Alex is unreliable and is telling the truth and Bob is the truth teller; or\r\n4) Alex is unreliable and is telling the truth and Bob is the liar.\n\r\nIf the answer is \"yes\", you ask Alex \"Is Bob the liar?\"; if the answer is \"no\", you ask Alex \"Is Bob the truth teller?\"\n\r\nDepending on the answers to the first two questions, you know one of the following:\n\r\nA) If the answer to both questions was \"yes\" then either\r\n1) Alex is the liar and Bob is the truth teller; or\r\n2) Alex is unreliable and lied on the first question and Bob is the liar.\n\r\nB) If the answer to both questions is \"no\" then either\r\n1) Alex is the truth teller and Bob is the liar; or\r\n2) Alex is unreliable and Bob is the truth teller.\n\r\nC) If the answer to the first question was \"yes\" and the second question was \"no\" then either\r\n1) Alex is the truth teller and Bob is unreliable; or\r\n2) Alex is unreliable and lied on the first question and Bob is the truth teller.\r\nIn either case, Chuck is the liar.\n\r\nD) If the answer to the first question was \"no\" and the second question was \"yes\" then either\r\n1) Alex is the liar and Bob is unreliable; or\r\n2) Alex is unreliable and Bob is the liar.\r\nIn either case, Chuck is the truth teller.\n\r\nIn cases A & B you've identified one person as either the liar or the truth teller and you've identified another person as either not the liar or not the truth teller. In these cases you ask the person who is neither the liar or the truth teller a question you know the answer to. In cases C & D you've identified Chuck as either the liar or truth teller. At this point you simply ask Chuck a question to identify either Alex or Bob.\n\r\nSo the final question and results for each case are:\n\r\nA) You ask Bob \"Is Alex the truth teller?\"\r\n\"yes\" means that\r\nAlex is unreliable, Bob is the liar and Chuck is the truth teller;\r\n\"no\" means that\r\nAlex is the liar, Bob is the truth teller and Chuck is unreliable.\n\r\nB) You ask Bob \"Is Alex the liar?\"\r\n\"yes\" means that\r\nAlex is the truth teller, Bob is the liar and Chuck is unreliable;\r\n\"no\" means that\r\nAlex is unreliable, Bob is the truth teller and Chuck is the liar.\n\r\nC) You ask Chuck \"Is Alex the truth teller?\"\r\n\"yes\" means that\r\nAlex is unreliable, Bob is the truth teller and Chuck is the liar;\r\n\"no\" means that\r\nAlex is the truth teller, Bob is unreliable and Chuck is the liar.\n\r\nD) You ask Chuck \"Is Alex the liar?\"\r\n\"yes\" means that\r\nAlex is the liar, Bob is unreliable and Chuck is the truth teller;\r\n\"no\" means that\r\nAlex is unreliable, Bob is the liar and Chuck is the truth teller.\n<|im_start|>answer\nFirst ask Alex, \"Does Bob sometimes tell the truth and sometimes lie?\"\n\r\nA \"yes\" answer means one of the following must be true:\r\n1) Alex is the truth teller and Bob is unreliable;\r\n2) Alex is the liar and Bob is the truth teller;\r\n3) Alex is unreliable and is lying and Bob is the truth teller; or\r\n4) Alex is unreliable and is lying and Bob is the liar.\n\r\nA \"no\" answer means one of these must be true:\r\n1) Alex is the truth teller and Bob is the liar;\r\n2) Alex is the liar and Bob is unreliable;\r\n3) Alex is unreliable and is telling the truth and Bob is the truth teller; or\r\n4) Alex is unreliable and is telling the truth and Bob is the liar.\n\r\nIf the answer is \"yes\", you ask Alex \"Is Bob the liar?\"; if the answer is \"no\", you ask Alex \"Is Bob the truth teller?\"\n\r\nDepending on the answers to the first two questions, you know one of the following:\n\r\nA) If the answer to both questions was \"yes\" then either\r\n1) Alex is the liar and Bob is the truth teller; or\r\n2) Alex is unreliable and lied on the first question and Bob is the liar.\n\r\nB) If the answer to both questions is \"no\" then either\r\n1) Alex is the truth teller and Bob is the liar; or\r\n2) Alex is unreliable and Bob is the truth teller.\n\r\nC) If the answer to the first question was \"yes\" and the second question was \"no\" then either\r\n1) Alex is the truth teller and Bob is unreliable; or\r\n2) Alex is unreliable and lied on the first question and Bob is the truth teller.\r\nIn either case, Chuck is the liar.\n\r\nD) If the answer to the first question was \"no\" and the second question was \"yes\" then either\r\n1) Alex is the liar and Bob is unreliable; or\r\n2) Alex is unreliable and Bob is the liar.\r\nIn either case, Chuck is the truth teller.\n\r\nIn cases A & B you've identified one person as either the liar or the truth teller and you've identified another person as either not the liar or not the truth teller. In these cases you ask the person who is neither the liar or the truth teller a question you know the answer to. In cases C & D you've identified Chuck as either the liar or truth teller. At this point you simply ask Chuck a question to identify either Alex or Bob.\n\r\nSo the final question and results for each case are:\n\r\nA) You ask Bob \"Is Alex the truth teller?\"\r\n\"yes\" means that\r\nAlex is unreliable, Bob is the liar and Chuck is the truth teller;\r\n\"no\" means that\r\nAlex is the liar, Bob is the truth teller and Chuck is unreliable.\n\r\nB) You ask Bob \"Is Alex the liar?\"\r\n\"yes\" means that\r\nAlex is the truth teller, Bob is the liar and Chuck is unreliable;\r\n\"no\" means that\r\nAlex is unreliable, Bob is the truth teller and Chuck is the liar.\n\r\nC) You ask Chuck \"Is Alex the truth teller?\"\r\n\"yes\" means that\r\nAlex is unreliable, Bob is the truth teller and Chuck is the liar;\r\n\"no\" means that\r\nAlex is the truth teller, Bob is unreliable and Chuck is the liar.\n\r\nD) You ask Chuck \"Is Alex the liar?\"\r\n\"yes\" means that\r\nAlex is the liar, Bob is unreliable and Chuck is the truth teller;\r\n\"no\" means that\r\nAlex is unreliable, Bob is the liar and Chuck is the truth teller.\n<|im_end|>" }, { "id": "#23522", "title": "It Adds Up", "fun": 2.56, "difficulty": 1.67, "author": "dbs241", "desc": "Figure out the pattern in the first three examples and use it to figure out the last.\r\n1, 2, 3 (s)\r\n4, 5, 6 (f)\r\n7, 7, 1 (f)\r\n3, 9, 7 (?)", "hint": "The title is the hint.", "answer": "The answer is (n). Add the numbers and take the first letter of the sum.", "category": "Math", "date": "06/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFigure out the pattern in the first three examples and use it to figure out the last.\r\n1, 2, 3 (s)\r\n4, 5, 6 (f)\r\n7, 7, 1 (f)\r\n3, 9, 7 (?)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is (n). Add the numbers and take the first letter of the sum.\n<|im_start|>answer\nThe answer is (n). Add the numbers and take the first letter of the sum.\n<|im_end|>" }, { "id": "#52196", "title": "4 Numbers", "fun": 2.56, "difficulty": 1.84, "author": "Rove_Tarts", "desc": "There is a combination lock with four inputs 0-9. Can you figure it out?\n\n\r\nThe second isn't a 6.\n\r\nOnly one digit starts with a vowel.\n\r\nThe fourth is greater than the first, is greater than or equal to the third, and is greater than the second.\n\r\nEither the first two numbers are even & the last two numbers are odd or vice versa.\n\r\nThe difference between the 1st & 2nd is the same as the difference between the 4th & 3rd (order matters).\n\r\nOne of the numbers is prime; three are composite.", "hint": "1 & 0 are neither prime nor composite & there is no 2.", "answer": "8, 4, 5, 9", "category": "Logic", "date": "06/01/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a combination lock with four inputs 0-9. Can you figure it out?\n\n\r\nThe second isn't a 6.\n\r\nOnly one digit starts with a vowel.\n\r\nThe fourth is greater than the first, is greater than or equal to the third, and is greater than the second.\n\r\nEither the first two numbers are even & the last two numbers are odd or vice versa.\n\r\nThe difference between the 1st & 2nd is the same as the difference between the 4th & 3rd (order matters).\n\r\nOne of the numbers is prime; three are composite.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8, 4, 5, 9\n<|im_start|>answer\n8, 4, 5, 9\n<|im_end|>" }, { "id": "#13639", "title": "Truckload of Chickens", "fun": 2.56, "difficulty": 2.16, "author": "Pialojo", "desc": "A man took a truckload of chickens to market. In the first hour, he sold one-half of his birds, plus one-half of a chicken. The next hour, he sold one-third of his remaining chickens plus one-third of a chicken. In the third hour, he sold one-fourth of what he had left, plus three-fourths of a chicken. The last hour, he sold one-fifth of the chickens, plus one-fifth of a chicken. He did not cut up any chickens to make these sales. He returned home with 19 chickens. How many did he take to market?", "hint": "No hint available.", "answer": "101\n\r\nSo at each hour he has: \r\n101 \r\n50 \r\n33 \r\n24 \r\n19\n\r\nThe equations is 4/5*(3/4*(2/3*(.5X-.5)-1/3)-.75)-.2=19", "category": "Math", "date": "07/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man took a truckload of chickens to market. In the first hour, he sold one-half of his birds, plus one-half of a chicken. The next hour, he sold one-third of his remaining chickens plus one-third of a chicken. In the third hour, he sold one-fourth of what he had left, plus three-fourths of a chicken. The last hour, he sold one-fifth of the chickens, plus one-fifth of a chicken. He did not cut up any chickens to make these sales. He returned home with 19 chickens. How many did he take to market?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n101\n\r\nSo at each hour he has: \r\n101 \r\n50 \r\n33 \r\n24 \r\n19\n\r\nThe equations is 4/5*(3/4*(2/3*(.5X-.5)-1/3)-.75)-.2=19\n<|im_start|>answer\n101\n\r\nSo at each hour he has: \r\n101 \r\n50 \r\n33 \r\n24 \r\n19\n\r\nThe equations is 4/5*(3/4*(2/3*(.5X-.5)-1/3)-.75)-.2=19\n<|im_end|>" }, { "id": "#41592", "title": "Who Won the Race?", "fun": 2.56, "difficulty": 2.07, "author": "Carlos16", "desc": "Four people finished a race, but only the runners know the results. If the top two placing runners are truthful, while the bottom 2 placing runners are lying, then who really won the race?\n\r\nDelvon: Jevon got 1st.\r\nTrevon: Delvon did worse than Jevon.\r\nKevion: Trevon is lying.\r\nJevon: I did better than Kevion.", "hint": "No hint available.", "answer": "Jevon couldn't have gotten 1st because then Delvon would be the other truth teller and would have to be 2nd. Trevon would have to be lying that Delvon did worse than Jevon, which isn't a lie. Since there is a contradiction, Jevon was definitely not 1st and Delvon is lying. If Trevon is the other liar, then Jevon and Kevion must be the truth tellers. That means Delvon had to have done worse than Jevon, resulting in Trevon telling the truth. Since there is a contradiction, Trevon isn't the other liar. Kevion has to be lying about Trevon lying, so Kevion and Delvon are in the liars in the bottom 2. Jevon has to be in the top 2, but since Delvon is lying about Jevon being 1st, Jevon is 2nd and Trevon is 1st. Kevion and Delvon are still somewhere in the bottom 2.\n\r\nAnswer: Trevon", "category": "Logic", "date": "04/19/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people finished a race, but only the runners know the results. If the top two placing runners are truthful, while the bottom 2 placing runners are lying, then who really won the race?\n\r\nDelvon: Jevon got 1st.\r\nTrevon: Delvon did worse than Jevon.\r\nKevion: Trevon is lying.\r\nJevon: I did better than Kevion.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJevon couldn't have gotten 1st because then Delvon would be the other truth teller and would have to be 2nd. Trevon would have to be lying that Delvon did worse than Jevon, which isn't a lie. Since there is a contradiction, Jevon was definitely not 1st and Delvon is lying. If Trevon is the other liar, then Jevon and Kevion must be the truth tellers. That means Delvon had to have done worse than Jevon, resulting in Trevon telling the truth. Since there is a contradiction, Trevon isn't the other liar. Kevion has to be lying about Trevon lying, so Kevion and Delvon are in the liars in the bottom 2. Jevon has to be in the top 2, but since Delvon is lying about Jevon being 1st, Jevon is 2nd and Trevon is 1st. Kevion and Delvon are still somewhere in the bottom 2.\n\r\nAnswer: Trevon\n<|im_start|>answer\nJevon couldn't have gotten 1st because then Delvon would be the other truth teller and would have to be 2nd. Trevon would have to be lying that Delvon did worse than Jevon, which isn't a lie. Since there is a contradiction, Jevon was definitely not 1st and Delvon is lying. If Trevon is the other liar, then Jevon and Kevion must be the truth tellers. That means Delvon had to have done worse than Jevon, resulting in Trevon telling the truth. Since there is a contradiction, Trevon isn't the other liar. Kevion has to be lying about Trevon lying, so Kevion and Delvon are in the liars in the bottom 2. Jevon has to be in the top 2, but since Delvon is lying about Jevon being 1st, Jevon is 2nd and Trevon is 1st. Kevion and Delvon are still somewhere in the bottom 2.\n\r\nAnswer: Trevon\n<|im_end|>" }, { "id": "#2264", "title": "Colored Squares", "fun": 2.56, "difficulty": 2.44, "author": "RayneeDay", "desc": "Consider a grid of size 4 x 4 (i.e. sixteen squares), where all squares should get a color. The colored grid should meet the following conditions:\n\r\n4 squares should be colored blue, \r\n3 squares should be colored red, \r\n3 squares should be colored white, \r\n3 squares should be colored green, \r\n3 squares should be colored yellow, and \n\r\nHow can these squares be arranged so that no color appears more than once in any horizontal, vertical, or diagonal line?", "hint": "No hint available.", "answer": "W B G R\r\nR Y W B \r\nB G R Y\r\nY W B G", "category": "Logic", "date": "02/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nConsider a grid of size 4 x 4 (i.e. sixteen squares), where all squares should get a color. The colored grid should meet the following conditions:\n\r\n4 squares should be colored blue, \r\n3 squares should be colored red, \r\n3 squares should be colored white, \r\n3 squares should be colored green, \r\n3 squares should be colored yellow, and \n\r\nHow can these squares be arranged so that no color appears more than once in any horizontal, vertical, or diagonal line?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nW B G R\r\nR Y W B \r\nB G R Y\r\nY W B G\n<|im_start|>answer\nW B G R\r\nR Y W B \r\nB G R Y\r\nY W B G\n<|im_end|>" }, { "id": "#9487", "title": "A Suspension Bridge", "fun": 2.55, "difficulty": 1.9000000000000001, "author": "lesternoronha1", "desc": "Before airplanes were invented, a suspension bridge was being planned to span a violent river. There was no way a boat could carry the suspension cables across the violent water, and the bridge could not be built until the cables were in place. The builders decided to hold a contest to solve the problem. The contest was won by a young boy. Shortly thereafter the cables spanned the water. \n\r\nWhat contest could have been used to solve this problem?", "hint": "No hint available.", "answer": "The builders offered a prize to the first person to fly a kite from one side to the other. Once the kite string made the crossing, a heavier cord was tied to the string and it was pulled across. This process was repeated until the first cable crossed the river.", "category": "Logic", "date": "12/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBefore airplanes were invented, a suspension bridge was being planned to span a violent river. There was no way a boat could carry the suspension cables across the violent water, and the bridge could not be built until the cables were in place. The builders decided to hold a contest to solve the problem. The contest was won by a young boy. Shortly thereafter the cables spanned the water. \n\r\nWhat contest could have been used to solve this problem?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe builders offered a prize to the first person to fly a kite from one side to the other. Once the kite string made the crossing, a heavier cord was tied to the string and it was pulled across. This process was repeated until the first cable crossed the river.\n<|im_start|>answer\nThe builders offered a prize to the first person to fly a kite from one side to the other. Once the kite string made the crossing, a heavier cord was tied to the string and it was pulled across. This process was repeated until the first cable crossed the river.\n<|im_end|>" }, { "id": "#41462", "title": "Two are Guilty", "fun": 2.55, "difficulty": 1.65, "author": "Carlos16", "desc": "Five people are suspects in a hit-and-run, but only two are guilty. This time the guilty people are telling the truth, while the innocent people are lying.\n\r\nConnor: It wasn't Jay\r\nJay: It was Kate and Connor\r\nKate: It was Toparnis\r\nToparnis: It was I\r\nRJ: It wasn't Kate\n\r\nWhich two are guilty?", "hint": "No hint available.", "answer": "If Jay is telling the truth, then Kate and Connor are guilty. Jay would also have to be guilty if he's telling the truth, but there can only be 2 guilty people. This means Jay must be lying and is innocent. Connor has to be telling the truth and is guilty. Since Jay is lying, it can't be Kate because that would result in Jay telling the truth. Since Kate is innocent, RJ must be telling the truth and is the other guilty one.\n\r\nAnswer: Connor and RJ", "category": "Logic", "date": "04/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive people are suspects in a hit-and-run, but only two are guilty. This time the guilty people are telling the truth, while the innocent people are lying.\n\r\nConnor: It wasn't Jay\r\nJay: It was Kate and Connor\r\nKate: It was Toparnis\r\nToparnis: It was I\r\nRJ: It wasn't Kate\n\r\nWhich two are guilty?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Jay is telling the truth, then Kate and Connor are guilty. Jay would also have to be guilty if he's telling the truth, but there can only be 2 guilty people. This means Jay must be lying and is innocent. Connor has to be telling the truth and is guilty. Since Jay is lying, it can't be Kate because that would result in Jay telling the truth. Since Kate is innocent, RJ must be telling the truth and is the other guilty one.\n\r\nAnswer: Connor and RJ\n<|im_start|>answer\nIf Jay is telling the truth, then Kate and Connor are guilty. Jay would also have to be guilty if he's telling the truth, but there can only be 2 guilty people. This means Jay must be lying and is innocent. Connor has to be telling the truth and is guilty. Since Jay is lying, it can't be Kate because that would result in Jay telling the truth. Since Kate is innocent, RJ must be telling the truth and is the other guilty one.\n\r\nAnswer: Connor and RJ\n<|im_end|>" }, { "id": "#50481", "title": "1+1=2", "fun": 2.55, "difficulty": 2.08, "author": "duhya", "desc": "ONE + ONE = TWO\n\r\nUsing neither of the numbers 1 or 2, replace each letter of the equation to make it true. Also, no letter is equal to zero. \n\r\nIf so, what is WETTEN?", "hint": "No hint available.", "answer": "467+467=934\n\r\nWETTEN = 379976\n\r\nO has to be less than five but greater than two, because TWO has three digits, not four. It has to be even, so it must be 4.\n\r\nE can't be two, so it is 7.\n\r\nN can't be one, or two, or five. It can't be three or eight, as this would make W equal E. It can't be nine, since this would make N equal W.\n\r\nFrom there on out, the equation is easily solved. \n\r\nE-7\r\nN-6\r\nO-4\r\nT-9\r\nW-3", "category": "Logic", "date": "12/21/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nONE + ONE = TWO\n\r\nUsing neither of the numbers 1 or 2, replace each letter of the equation to make it true. Also, no letter is equal to zero. \n\r\nIf so, what is WETTEN?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n467+467=934\n\r\nWETTEN = 379976\n\r\nO has to be less than five but greater than two, because TWO has three digits, not four. It has to be even, so it must be 4.\n\r\nE can't be two, so it is 7.\n\r\nN can't be one, or two, or five. It can't be three or eight, as this would make W equal E. It can't be nine, since this would make N equal W.\n\r\nFrom there on out, the equation is easily solved. \n\r\nE-7\r\nN-6\r\nO-4\r\nT-9\r\nW-3\n<|im_start|>answer\n467+467=934\n\r\nWETTEN = 379976\n\r\nO has to be less than five but greater than two, because TWO has three digits, not four. It has to be even, so it must be 4.\n\r\nE can't be two, so it is 7.\n\r\nN can't be one, or two, or five. It can't be three or eight, as this would make W equal E. It can't be nine, since this would make N equal W.\n\r\nFrom there on out, the equation is easily solved. \n\r\nE-7\r\nN-6\r\nO-4\r\nT-9\r\nW-3\n<|im_end|>" }, { "id": "#6102", "title": "Ages", "fun": 2.55, "difficulty": 1.98, "author": "k2w2man", "desc": "If Susan is 10, Arabella is 20, and Jim and Neil are both 5, how old is Jennifer by the same system?", "hint": "No hint available.", "answer": "Jennifer is 15, in the system that awards 5 for each syllable.", "category": "Math", "date": "07/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf Susan is 10, Arabella is 20, and Jim and Neil are both 5, how old is Jennifer by the same system?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJennifer is 15, in the system that awards 5 for each syllable.\n<|im_start|>answer\nJennifer is 15, in the system that awards 5 for each syllable.\n<|im_end|>" }, { "id": "#8910", "title": "Marbles in Squares", "fun": 2.55, "difficulty": 2.02, "author": "lesternoronha1", "desc": "Lester and Terance each have marble collections. The number in Lester's collection is a square number (1,4,9,16, etc). Lester says to Terance, \"If you give me all of your marbles I'll still have a square number.\" Terance replies, \"If you gave me the number in my collection you would still be left with a square.\" What is the least number of marbles Lester has?", "hint": "No hint available.", "answer": "Lester has 25 marbles and Terance has 24 marbles.", "category": "Math", "date": "12/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester and Terance each have marble collections. The number in Lester's collection is a square number (1,4,9,16, etc). Lester says to Terance, \"If you give me all of your marbles I'll still have a square number.\" Terance replies, \"If you gave me the number in my collection you would still be left with a square.\" What is the least number of marbles Lester has?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLester has 25 marbles and Terance has 24 marbles.\n<|im_start|>answer\nLester has 25 marbles and Terance has 24 marbles.\n<|im_end|>" }, { "id": "#8133", "title": "Algebraic Sugar Cane", "fun": 2.55, "difficulty": 2.09, "author": "bluelightnign", "desc": "10 factories produce sugar cane. The second produced twice as much as the first. The third and fourth each produced 80 more than the first. The fifth produced twice as much as the second. The sixth produced 40 more than the fifth. The seventh and eighth each produced 40 less than the fifth. The ninth produced 80 more than the second. The tenth produced nothing due to drought in Australia. If the sum of the production equaled 11,700, what did the first factory produce?", "hint": "Use algebra. Eg / The first factory is X and the second is 2X.", "answer": "500. First write down what each factory produced in relation to the first factory (whose production is X):\n\r\n1: X\r\n2: 2X\r\n3: X+80\r\n4: X+80\r\n5: 4X\r\n6: 4X+40\r\n7: 4X-40\r\n8: 4X-40\r\n9: 2X+80\r\n10: 0X\n\r\nAdd them all up and set equal to 11,700 to get the equation:\r\n23X + 200 = 11,700\n\r\nSolution is: X = 500", "category": "Math", "date": "10/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n10 factories produce sugar cane. The second produced twice as much as the first. The third and fourth each produced 80 more than the first. The fifth produced twice as much as the second. The sixth produced 40 more than the fifth. The seventh and eighth each produced 40 less than the fifth. The ninth produced 80 more than the second. The tenth produced nothing due to drought in Australia. If the sum of the production equaled 11,700, what did the first factory produce?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n500. First write down what each factory produced in relation to the first factory (whose production is X):\n\r\n1: X\r\n2: 2X\r\n3: X+80\r\n4: X+80\r\n5: 4X\r\n6: 4X+40\r\n7: 4X-40\r\n8: 4X-40\r\n9: 2X+80\r\n10: 0X\n\r\nAdd them all up and set equal to 11,700 to get the equation:\r\n23X + 200 = 11,700\n\r\nSolution is: X = 500\n<|im_start|>answer\n500. First write down what each factory produced in relation to the first factory (whose production is X):\n\r\n1: X\r\n2: 2X\r\n3: X+80\r\n4: X+80\r\n5: 4X\r\n6: 4X+40\r\n7: 4X-40\r\n8: 4X-40\r\n9: 2X+80\r\n10: 0X\n\r\nAdd them all up and set equal to 11,700 to get the equation:\r\n23X + 200 = 11,700\n\r\nSolution is: X = 500\n<|im_end|>" }, { "id": "#42070", "title": "Roman Matches I", "fun": 2.55, "difficulty": 1.6, "author": "MarcM1098", "desc": "The following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it twice: the equation can be corrected in two different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote: \r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: III = II - I", "hint": "One solution changes the Roman numerals; the other solution doesn't.", "answer": "First solution: II = III - I\r\nTake one matchstick from the III on the left side of the equation and add it to the II on the right side.\n\r\nSecond solution: III - II = I\r\nTake one matchstick from the equals sign (changing it to a minus sign) and place it above the minus sign (changing it to an equals sign).", "category": "Math", "date": "05/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it twice: the equation can be corrected in two different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote: \r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: III = II - I\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst solution: II = III - I\r\nTake one matchstick from the III on the left side of the equation and add it to the II on the right side.\n\r\nSecond solution: III - II = I\r\nTake one matchstick from the equals sign (changing it to a minus sign) and place it above the minus sign (changing it to an equals sign).\n<|im_start|>answer\nFirst solution: II = III - I\r\nTake one matchstick from the III on the left side of the equation and add it to the II on the right side.\n\r\nSecond solution: III - II = I\r\nTake one matchstick from the equals sign (changing it to a minus sign) and place it above the minus sign (changing it to an equals sign).\n<|im_end|>" }, { "id": "#40574", "title": "The Zoo 2", "fun": 2.55, "difficulty": 1.07, "author": "TRILLIONAIRE", "desc": "Zookeeper Robin has the job of feeding all of the zoo's animals in the morning. She has a schedule that she follows each day. Use the clues below to figure out her schedule. \t\n\r\nBears are fed fifteen minutes after the zebras. \r\nLions are fed after the monkeys.\r\nGiraffes are fed before the monkeys but after the zebras. \n\r\nThe different times she feeds the animals are: 6:30, 6:45, 7:00, 7:15, 7:30 am.", "hint": "No hint available.", "answer": "6:30 AM - Zebras \r\n6:45 AM - Bears \r\n7:00 AM - Giraffes \r\n7:15 AM - Monkeys \r\n7:30 AM - Lions", "category": "Logic", "date": "02/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nZookeeper Robin has the job of feeding all of the zoo's animals in the morning. She has a schedule that she follows each day. Use the clues below to figure out her schedule. \t\n\r\nBears are fed fifteen minutes after the zebras. \r\nLions are fed after the monkeys.\r\nGiraffes are fed before the monkeys but after the zebras. \n\r\nThe different times she feeds the animals are: 6:30, 6:45, 7:00, 7:15, 7:30 am.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6:30 AM - Zebras \r\n6:45 AM - Bears \r\n7:00 AM - Giraffes \r\n7:15 AM - Monkeys \r\n7:30 AM - Lions\n<|im_start|>answer\n6:30 AM - Zebras \r\n6:45 AM - Bears \r\n7:00 AM - Giraffes \r\n7:15 AM - Monkeys \r\n7:30 AM - Lions\n<|im_end|>" }, { "id": "#1404", "title": "How Old is Grandpa", "fun": 2.55, "difficulty": 2.49, "author": "gokaran", "desc": "Grandpa says, \"My grandson is about as many days as my son is weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 100 years. Can you tell me my age in years?\"", "hint": "No hint available.", "answer": "This problem is conveniently solved by writing down the necessary equations. \n\r\nLet m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus, \n\r\n365g = 52s. \n\r\nSince my grandson is 12g months old, \n\r\n12g = m. \n\r\nSince my grandson, my son and I together are 100 years, \n\r\ng + s + m = 100. \n\r\nThe above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows. \n\r\nm / 12 + 365 m / (52 x 12) + m = 100 or \n\n\r\n52 m + 365 m + 624 m = 624 x 100 or \n\n\r\nm = 624 x 100 / 1041 = 60. \n\r\nSo, I am 60 years old.\" \n\r\nFood for thought: \n\r\nWhy is the word \"about\" used in the Problem Statement in the sentence \"My grandson is about as many days as my son is weeks\"? Calculate the son's age and the grandson's age. Then, verify whether the first equation (i.e., 365g = 52s) is exactly satisfied. \n\r\nAn elegant solution is possible on realizing the significance of the word \"about\" in the Problem Statement. \n\r\nElegant Solution: \n\r\nThe first equation (365g = 52s) can be approximated by \n\r\n7g = s. \n\r\nAs before, the other two equations are \n\r\n12g = m \n\r\ng + s + m = 100. \n\r\nThe above system of 3 equations in 3 unknowns (g, s and m) can be simply solved as follows. \n\r\ng + 7g + 12g = 100 or 20g = 100. \n\r\nm = 12g = 12 x 100 / 20 = 60. \n\r\nSo, Grandpa is 60 years old.", "category": "Math", "date": "11/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrandpa says, \"My grandson is about as many days as my son is weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 100 years. Can you tell me my age in years?\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis problem is conveniently solved by writing down the necessary equations. \n\r\nLet m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus, \n\r\n365g = 52s. \n\r\nSince my grandson is 12g months old, \n\r\n12g = m. \n\r\nSince my grandson, my son and I together are 100 years, \n\r\ng + s + m = 100. \n\r\nThe above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows. \n\r\nm / 12 + 365 m / (52 x 12) + m = 100 or \n\n\r\n52 m + 365 m + 624 m = 624 x 100 or \n\n\r\nm = 624 x 100 / 1041 = 60. \n\r\nSo, I am 60 years old.\" \n\r\nFood for thought: \n\r\nWhy is the word \"about\" used in the Problem Statement in the sentence \"My grandson is about as many days as my son is weeks\"? Calculate the son's age and the grandson's age. Then, verify whether the first equation (i.e., 365g = 52s) is exactly satisfied. \n\r\nAn elegant solution is possible on realizing the significance of the word \"about\" in the Problem Statement. \n\r\nElegant Solution: \n\r\nThe first equation (365g = 52s) can be approximated by \n\r\n7g = s. \n\r\nAs before, the other two equations are \n\r\n12g = m \n\r\ng + s + m = 100. \n\r\nThe above system of 3 equations in 3 unknowns (g, s and m) can be simply solved as follows. \n\r\ng + 7g + 12g = 100 or 20g = 100. \n\r\nm = 12g = 12 x 100 / 20 = 60. \n\r\nSo, Grandpa is 60 years old.\n<|im_start|>answer\nThis problem is conveniently solved by writing down the necessary equations. \n\r\nLet m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus, \n\r\n365g = 52s. \n\r\nSince my grandson is 12g months old, \n\r\n12g = m. \n\r\nSince my grandson, my son and I together are 100 years, \n\r\ng + s + m = 100. \n\r\nThe above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows. \n\r\nm / 12 + 365 m / (52 x 12) + m = 100 or \n\n\r\n52 m + 365 m + 624 m = 624 x 100 or \n\n\r\nm = 624 x 100 / 1041 = 60. \n\r\nSo, I am 60 years old.\" \n\r\nFood for thought: \n\r\nWhy is the word \"about\" used in the Problem Statement in the sentence \"My grandson is about as many days as my son is weeks\"? Calculate the son's age and the grandson's age. Then, verify whether the first equation (i.e., 365g = 52s) is exactly satisfied. \n\r\nAn elegant solution is possible on realizing the significance of the word \"about\" in the Problem Statement. \n\r\nElegant Solution: \n\r\nThe first equation (365g = 52s) can be approximated by \n\r\n7g = s. \n\r\nAs before, the other two equations are \n\r\n12g = m \n\r\ng + s + m = 100. \n\r\nThe above system of 3 equations in 3 unknowns (g, s and m) can be simply solved as follows. \n\r\ng + 7g + 12g = 100 or 20g = 100. \n\r\nm = 12g = 12 x 100 / 20 = 60. \n\r\nSo, Grandpa is 60 years old.\n<|im_end|>" }, { "id": "#6263", "title": "Dogs and Fleas", "fun": 2.55, "difficulty": 1.4, "author": "Delport", "desc": "There are two dogs. Both have fleas.\n\r\nIf one flea jumps from the 1st dog to the 2nd, then both will have \r\nthe same amount.\n\r\nOr if one flea jumps from the 2nd dog to the 1st, then the 1st will \r\nhave 5 times the amount of the 2nd.\n\r\nHow many fleas do each dog have before any jumping takes place?", "hint": "No hint available.", "answer": "1st dog as 4 fleas\r\n2nd dog as 2 fleas", "category": "Math", "date": "08/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two dogs. Both have fleas.\n\r\nIf one flea jumps from the 1st dog to the 2nd, then both will have \r\nthe same amount.\n\r\nOr if one flea jumps from the 2nd dog to the 1st, then the 1st will \r\nhave 5 times the amount of the 2nd.\n\r\nHow many fleas do each dog have before any jumping takes place?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st dog as 4 fleas\r\n2nd dog as 2 fleas\n<|im_start|>answer\n1st dog as 4 fleas\r\n2nd dog as 2 fleas\n<|im_end|>" }, { "id": "#33503", "title": "Tribal Truth", "fun": 2.55, "difficulty": 1.67, "author": "jamesbond", "desc": "There are two tribes, X and Y, in a jungle such that people belonging to tribe X always speak the truth while those in tribe Y always lie.\n\r\nSuppose you come across 4 such people A, B, C, D:\n\r\nA B C D\n\r\nA says: \"B is in tribe Y.\"\r\nB says: \"C is in tribe Y.\"\r\nC says: \"D is in tribe Y.\"\r\nD says: \"A will say that C is in tribe Y.\"\n\r\nIf there are two people from each tribe, can you deduce who is from which tribe?", "hint": "Try using the \"Trial and Error\" Method.", "answer": "LOGIC:\r\nSuppose there are any 2 tribal people of the same tribe standing adjacent to each other.\r\nThen, if one of them is asked about the tribe of the other, he'll say \"TRIBE X\".\n\r\nIf both are in tribe X, then he'll tell the truth, that is \"TRIBE X\".\n\r\nX X - TRIBE X\n\r\nIf both are in tribe Y, then he'll lie, that is \"TRIBE X\".\n\r\nY Y - TRIBE X\n\r\nSimilarly, if their tribes are different, then the answer will always be \"TRIBE Y\".\n\r\nX Y - TRIBE Y\n\r\nY X - TRIBE Y\n\r\nSo from the question, A and B are in different tribes, so are B and C and so are C and D.\r\nSince there are two types of tribes only, A and C are in the same tribe while B and D are in the same tribe.\r\nNow, since according to D, A will call C a liar (TRIBE Y), in spite of both of them being in the same tribe, D is lying.\r\nHence B and D are liars (TRIBE Y), while A and C are honest (TRIBE X).\n\r\nA - TRIBE X\r\nB - TRIBE Y\r\nC - TRIBE X\r\nD - TRIBE Y", "category": "Logic", "date": "10/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two tribes, X and Y, in a jungle such that people belonging to tribe X always speak the truth while those in tribe Y always lie.\n\r\nSuppose you come across 4 such people A, B, C, D:\n\r\nA B C D\n\r\nA says: \"B is in tribe Y.\"\r\nB says: \"C is in tribe Y.\"\r\nC says: \"D is in tribe Y.\"\r\nD says: \"A will say that C is in tribe Y.\"\n\r\nIf there are two people from each tribe, can you deduce who is from which tribe?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLOGIC:\r\nSuppose there are any 2 tribal people of the same tribe standing adjacent to each other.\r\nThen, if one of them is asked about the tribe of the other, he'll say \"TRIBE X\".\n\r\nIf both are in tribe X, then he'll tell the truth, that is \"TRIBE X\".\n\r\nX X - TRIBE X\n\r\nIf both are in tribe Y, then he'll lie, that is \"TRIBE X\".\n\r\nY Y - TRIBE X\n\r\nSimilarly, if their tribes are different, then the answer will always be \"TRIBE Y\".\n\r\nX Y - TRIBE Y\n\r\nY X - TRIBE Y\n\r\nSo from the question, A and B are in different tribes, so are B and C and so are C and D.\r\nSince there are two types of tribes only, A and C are in the same tribe while B and D are in the same tribe.\r\nNow, since according to D, A will call C a liar (TRIBE Y), in spite of both of them being in the same tribe, D is lying.\r\nHence B and D are liars (TRIBE Y), while A and C are honest (TRIBE X).\n\r\nA - TRIBE X\r\nB - TRIBE Y\r\nC - TRIBE X\r\nD - TRIBE Y\n<|im_start|>answer\nLOGIC:\r\nSuppose there are any 2 tribal people of the same tribe standing adjacent to each other.\r\nThen, if one of them is asked about the tribe of the other, he'll say \"TRIBE X\".\n\r\nIf both are in tribe X, then he'll tell the truth, that is \"TRIBE X\".\n\r\nX X - TRIBE X\n\r\nIf both are in tribe Y, then he'll lie, that is \"TRIBE X\".\n\r\nY Y - TRIBE X\n\r\nSimilarly, if their tribes are different, then the answer will always be \"TRIBE Y\".\n\r\nX Y - TRIBE Y\n\r\nY X - TRIBE Y\n\r\nSo from the question, A and B are in different tribes, so are B and C and so are C and D.\r\nSince there are two types of tribes only, A and C are in the same tribe while B and D are in the same tribe.\r\nNow, since according to D, A will call C a liar (TRIBE Y), in spite of both of them being in the same tribe, D is lying.\r\nHence B and D are liars (TRIBE Y), while A and C are honest (TRIBE X).\n\r\nA - TRIBE X\r\nB - TRIBE Y\r\nC - TRIBE X\r\nD - TRIBE Y\n<|im_end|>" }, { "id": "#20915", "title": "10,000 - 9,999...", "fun": 2.55, "difficulty": 1.42, "author": "fishmed", "desc": "Can you solve this?\n\n\r\n10,000 - 9,999 + 9,998 - 9,997...\r\n...5 + 4 - 3 + 2 - 1 = ?", "hint": "No hint available.", "answer": "The answer is 5,000. If you noticed, each consecutive pair, starting with the 1st two equals one and it happens in the progression, 5,000 times.", "category": "Math", "date": "02/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you solve this?\n\n\r\n10,000 - 9,999 + 9,998 - 9,997...\r\n...5 + 4 - 3 + 2 - 1 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 5,000. If you noticed, each consecutive pair, starting with the 1st two equals one and it happens in the progression, 5,000 times.\n<|im_start|>answer\nThe answer is 5,000. If you noticed, each consecutive pair, starting with the 1st two equals one and it happens in the progression, 5,000 times.\n<|im_end|>" }, { "id": "#5431", "title": "Family Reunions", "fun": 2.55, "difficulty": 2.42, "author": "Bobbrt", "desc": "The following statements were made by each of eight people at a family reunion. They are each referring to one of the other seven people (in other words the person being referred to in the first statement, Maria, is making one of the other statements). Can you determine who made each statement? Assume that all parents are married and that all married couples are heterosexual, married only once, still married, and attending together. \n\r\n1. \"I am Maria's niece.\"\r\n2. \"Christopher is my only cousin.\"\r\n3. \"Clarissa is my brother's wife.\"\r\n4. \"I am Donna's sister.\"\r\n5. \"Jonathan is my uncle.\"\r\n6. \"Theodore is my brother.\"\r\n7. \"Ben is my nephew.\"\r\n8. \"Judy is my daughter.\"", "hint": "No hint available.", "answer": "1. Donna\r\n2. Ben\r\n3. Theodore\r\n4. Judy\r\n5. Christopher\r\n6. Jonathan\r\n7. Maria\r\n8. Clarissa\n\r\nI had trouble coming up with a nice, straightforward logical solution for this problem so I had to use a little trial and error. Since no grandchildren are mentioned, I assumed that there were only two generations present. I started with the women: I used statements 1 and 3 to put Maria and Clarissa in the older generation, respectively. Then I used statements 4 and 8 to put Donna and Judy in the younger generation, as sisters. Statement 7 puts Ben in the younger generation. If Christopher is also in the younger generation, then Ben must be Donna and Judy's brother and either Ben or Donna says statement 2. If Theodore and Jonathan are in the older generation, then Jonathan must be Clarissa's husband and Theodore must be Jonathan's brother (Statement 3). Statement 1 has to be said by Donna, since she is the only girl left in the younger generation who could say that. This leaves Ben saying statement 2. By elimination, Clarissa must give statement 8 and Maria statement 7. The only thing left is for Christopher to make statement 5.", "category": "Logic", "date": "07/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following statements were made by each of eight people at a family reunion. They are each referring to one of the other seven people (in other words the person being referred to in the first statement, Maria, is making one of the other statements). Can you determine who made each statement? Assume that all parents are married and that all married couples are heterosexual, married only once, still married, and attending together. \n\r\n1. \"I am Maria's niece.\"\r\n2. \"Christopher is my only cousin.\"\r\n3. \"Clarissa is my brother's wife.\"\r\n4. \"I am Donna's sister.\"\r\n5. \"Jonathan is my uncle.\"\r\n6. \"Theodore is my brother.\"\r\n7. \"Ben is my nephew.\"\r\n8. \"Judy is my daughter.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Donna\r\n2. Ben\r\n3. Theodore\r\n4. Judy\r\n5. Christopher\r\n6. Jonathan\r\n7. Maria\r\n8. Clarissa\n\r\nI had trouble coming up with a nice, straightforward logical solution for this problem so I had to use a little trial and error. Since no grandchildren are mentioned, I assumed that there were only two generations present. I started with the women: I used statements 1 and 3 to put Maria and Clarissa in the older generation, respectively. Then I used statements 4 and 8 to put Donna and Judy in the younger generation, as sisters. Statement 7 puts Ben in the younger generation. If Christopher is also in the younger generation, then Ben must be Donna and Judy's brother and either Ben or Donna says statement 2. If Theodore and Jonathan are in the older generation, then Jonathan must be Clarissa's husband and Theodore must be Jonathan's brother (Statement 3). Statement 1 has to be said by Donna, since she is the only girl left in the younger generation who could say that. This leaves Ben saying statement 2. By elimination, Clarissa must give statement 8 and Maria statement 7. The only thing left is for Christopher to make statement 5.\n<|im_start|>answer\n1. Donna\r\n2. Ben\r\n3. Theodore\r\n4. Judy\r\n5. Christopher\r\n6. Jonathan\r\n7. Maria\r\n8. Clarissa\n\r\nI had trouble coming up with a nice, straightforward logical solution for this problem so I had to use a little trial and error. Since no grandchildren are mentioned, I assumed that there were only two generations present. I started with the women: I used statements 1 and 3 to put Maria and Clarissa in the older generation, respectively. Then I used statements 4 and 8 to put Donna and Judy in the younger generation, as sisters. Statement 7 puts Ben in the younger generation. If Christopher is also in the younger generation, then Ben must be Donna and Judy's brother and either Ben or Donna says statement 2. If Theodore and Jonathan are in the older generation, then Jonathan must be Clarissa's husband and Theodore must be Jonathan's brother (Statement 3). Statement 1 has to be said by Donna, since she is the only girl left in the younger generation who could say that. This leaves Ben saying statement 2. By elimination, Clarissa must give statement 8 and Maria statement 7. The only thing left is for Christopher to make statement 5.\n<|im_end|>" }, { "id": "#3602", "title": "Losing Petrol", "fun": 2.55, "difficulty": 1.75, "author": "lil_thugsta", "desc": "After visiting my Great Aunt Bernie, I travelled home in my old jalopy. The car was so old and battered, I was stuck in second gear. This meant that I could only travel along at a steady 30 miles per hour and managed a paltry 20 miles per gallon of petrol. At the start of the journey I had placed exactly 10 gallons of petrol into the tank. I knew though, that the petrol tank had a leak and lost petrol at the rate of half a gallon per hour. As I arrived home, the car stopped because it had run out of petrol and I only just made it. How far was it from my Great Aunt's to my home?", "hint": "No hint available.", "answer": "150 miles; as I was travelling at 30 mph, I was using 1.5 gallons of petrol and losing 0.5 gallon of petrol for each hour I travelled. Therefore, I was getting through the petrol at a total rate 2 gallons per hour. Since I had 10 gallons of petrol at the start, I could travel for 5 hours before running out. 5 hours at 30 mph is 150 miles.", "category": "Math", "date": "04/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter visiting my Great Aunt Bernie, I travelled home in my old jalopy. The car was so old and battered, I was stuck in second gear. This meant that I could only travel along at a steady 30 miles per hour and managed a paltry 20 miles per gallon of petrol. At the start of the journey I had placed exactly 10 gallons of petrol into the tank. I knew though, that the petrol tank had a leak and lost petrol at the rate of half a gallon per hour. As I arrived home, the car stopped because it had run out of petrol and I only just made it. How far was it from my Great Aunt's to my home?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n150 miles; as I was travelling at 30 mph, I was using 1.5 gallons of petrol and losing 0.5 gallon of petrol for each hour I travelled. Therefore, I was getting through the petrol at a total rate 2 gallons per hour. Since I had 10 gallons of petrol at the start, I could travel for 5 hours before running out. 5 hours at 30 mph is 150 miles.\n<|im_start|>answer\n150 miles; as I was travelling at 30 mph, I was using 1.5 gallons of petrol and losing 0.5 gallon of petrol for each hour I travelled. Therefore, I was getting through the petrol at a total rate 2 gallons per hour. Since I had 10 gallons of petrol at the start, I could travel for 5 hours before running out. 5 hours at 30 mph is 150 miles.\n<|im_end|>" }, { "id": "#17740", "title": "Hungry Termites", "fun": 2.55, "difficulty": 2.96, "author": "Jake", "desc": "You have two very hungry termites and two sticks of wood. One stick of wood is 12 inches long and the other is 16 inches long. One termite can eat sticks at the rate of 1 inch every 3 minutes. The other termite can eat 1 inch in 4 minutes. How would you use the termites and sticks to measure 61 minutes?", "hint": "No hint available.", "answer": "Start the slow termite eating the longer stick. It will take the slow termite 16 minutes to eat the 4 inches that will make the sticks the same size. When the sticks are the same size, start the fast termite on the other stick. This termite will finish his 12 inch stick in 36 minutes. That's 52 minutes elapsed so far and the slow termite still has 3 inches left on his stick. Remove the slow termite and let the fast termite finish off the 3 inches in 9 minutes for a total of 61 minutes.", "category": "Math", "date": "05/25/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two very hungry termites and two sticks of wood. One stick of wood is 12 inches long and the other is 16 inches long. One termite can eat sticks at the rate of 1 inch every 3 minutes. The other termite can eat 1 inch in 4 minutes. How would you use the termites and sticks to measure 61 minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStart the slow termite eating the longer stick. It will take the slow termite 16 minutes to eat the 4 inches that will make the sticks the same size. When the sticks are the same size, start the fast termite on the other stick. This termite will finish his 12 inch stick in 36 minutes. That's 52 minutes elapsed so far and the slow termite still has 3 inches left on his stick. Remove the slow termite and let the fast termite finish off the 3 inches in 9 minutes for a total of 61 minutes.\n<|im_start|>answer\nStart the slow termite eating the longer stick. It will take the slow termite 16 minutes to eat the 4 inches that will make the sticks the same size. When the sticks are the same size, start the fast termite on the other stick. This termite will finish his 12 inch stick in 36 minutes. That's 52 minutes elapsed so far and the slow termite still has 3 inches left on his stick. Remove the slow termite and let the fast termite finish off the 3 inches in 9 minutes for a total of 61 minutes.\n<|im_end|>" }, { "id": "#46205", "title": "Four 0's", "fun": 2.55, "difficulty": 2.53, "author": "wicked_one", "desc": "Using only four ZERO'S (0) and any Mathematical Operations/Symbols, obtain the number 24.", "hint": "No hint available.", "answer": "0! = 1\n\r\n(0! + 0! + 0! + 0!)! = 24", "category": "Math", "date": "01/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing only four ZERO'S (0) and any Mathematical Operations/Symbols, obtain the number 24.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0! = 1\n\r\n(0! + 0! + 0! + 0!)! = 24\n<|im_start|>answer\n0! = 1\n\r\n(0! + 0! + 0! + 0!)! = 24\n<|im_end|>" }, { "id": "#3955", "title": "Invisible Cat", "fun": 2.55, "difficulty": 2.24, "author": "PeaceJo", "desc": "Ms. Smith insists that she owns an invisible cat named Sam. She's always mentioning to one friend or another what mischief Sam has most recently gotten into. \n\r\nUse the following clues to determine which weekday (Monday to Friday) last week Sam committed each 'faux paw' and which friend Ms. Smith saw that she complained about it to (including Mr. Beck and Ms. Dove).\n\r\n1. Sam began the week by clawing the drapes.\n\r\n2. On Thursday, Ms. Smith apologized to her male dinner guest for Sam's shameless begging under the table.\n\r\n3. Friday wasn't the day that Ms. Smith told Mr. Astor about Sam's shedding invisible cat hair all over her red velvet sofa.\n\r\n4. Ms. Edge was sleeping soundly in Ms. Smith's guest room only to be awakened suddenly at dawn by Ms. Smith's attempts to silence Sam's imperceptible cries to be let out the front door.\n\r\n5. Neither Tuesday nor Friday was the day one visitor heard the story of how Sam knocked over and broke a priceless invisible vase.\n\r\n6. Ms. Case didn't see Ms. Smith on Monday.", "hint": "No hint available.", "answer": "Monday - Clawing drapes - Ms. Dove\r\nTuesday - Shedding on sofa - Mr. Astor\r\nWednesday - Breaking vase - Ms. Case\r\nThursday - Begging at table- Mr. Beck\r\nFriday - Crying at dawn- Ms. Edge", "category": "Logic", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Smith insists that she owns an invisible cat named Sam. She's always mentioning to one friend or another what mischief Sam has most recently gotten into. \n\r\nUse the following clues to determine which weekday (Monday to Friday) last week Sam committed each 'faux paw' and which friend Ms. Smith saw that she complained about it to (including Mr. Beck and Ms. Dove).\n\r\n1. Sam began the week by clawing the drapes.\n\r\n2. On Thursday, Ms. Smith apologized to her male dinner guest for Sam's shameless begging under the table.\n\r\n3. Friday wasn't the day that Ms. Smith told Mr. Astor about Sam's shedding invisible cat hair all over her red velvet sofa.\n\r\n4. Ms. Edge was sleeping soundly in Ms. Smith's guest room only to be awakened suddenly at dawn by Ms. Smith's attempts to silence Sam's imperceptible cries to be let out the front door.\n\r\n5. Neither Tuesday nor Friday was the day one visitor heard the story of how Sam knocked over and broke a priceless invisible vase.\n\r\n6. Ms. Case didn't see Ms. Smith on Monday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday - Clawing drapes - Ms. Dove\r\nTuesday - Shedding on sofa - Mr. Astor\r\nWednesday - Breaking vase - Ms. Case\r\nThursday - Begging at table- Mr. Beck\r\nFriday - Crying at dawn- Ms. Edge\n<|im_start|>answer\nMonday - Clawing drapes - Ms. Dove\r\nTuesday - Shedding on sofa - Mr. Astor\r\nWednesday - Breaking vase - Ms. Case\r\nThursday - Begging at table- Mr. Beck\r\nFriday - Crying at dawn- Ms. Edge\n<|im_end|>" }, { "id": "#25334", "title": "The Four Jays", "fun": 2.55, "difficulty": 2.4, "author": "katie56", "desc": "Four friends named Jane, June, Jean and Jenny discovered that, if a different non-zero integer was assigned to each letter of their names and added together, it produced their ages.\n\r\nJune is 17, Jenny is two years older, while Jane and Jean are both sweet 16. All the girls agree that June is in her prime. Can you find the numbers the girls assigned to each letter of their names?\n\n\r\n(There are two possible answers.)", "hint": "prime...", "answer": "J=2; U=7; N=5; E=3; A=6; Y=4\n\r\nor\n\r\nJ=3; U=7; N=5; E=2; A=6; Y=4\n\n\r\nThe little clue 'June is in her prime' should have helped, as it suggests that all the numbers in her name are prime numbers. As the total is 17 all the numbers must be less than 10, so:\n\r\nJ=2; U=7; N=5; E=3 (or J=3; U=7; N=5; E=2)\n\r\nSetting these numbers in the word Jane or Jean we can conclude that\n\r\n16=2+A+5+3, so A=6.\n\r\nPutting these numbers in the word Jenny in the same way we find Y=4.", "category": "Logic", "date": "08/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends named Jane, June, Jean and Jenny discovered that, if a different non-zero integer was assigned to each letter of their names and added together, it produced their ages.\n\r\nJune is 17, Jenny is two years older, while Jane and Jean are both sweet 16. All the girls agree that June is in her prime. Can you find the numbers the girls assigned to each letter of their names?\n\n\r\n(There are two possible answers.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJ=2; U=7; N=5; E=3; A=6; Y=4\n\r\nor\n\r\nJ=3; U=7; N=5; E=2; A=6; Y=4\n\n\r\nThe little clue 'June is in her prime' should have helped, as it suggests that all the numbers in her name are prime numbers. As the total is 17 all the numbers must be less than 10, so:\n\r\nJ=2; U=7; N=5; E=3 (or J=3; U=7; N=5; E=2)\n\r\nSetting these numbers in the word Jane or Jean we can conclude that\n\r\n16=2+A+5+3, so A=6.\n\r\nPutting these numbers in the word Jenny in the same way we find Y=4.\n<|im_start|>answer\nJ=2; U=7; N=5; E=3; A=6; Y=4\n\r\nor\n\r\nJ=3; U=7; N=5; E=2; A=6; Y=4\n\n\r\nThe little clue 'June is in her prime' should have helped, as it suggests that all the numbers in her name are prime numbers. As the total is 17 all the numbers must be less than 10, so:\n\r\nJ=2; U=7; N=5; E=3 (or J=3; U=7; N=5; E=2)\n\r\nSetting these numbers in the word Jane or Jean we can conclude that\n\r\n16=2+A+5+3, so A=6.\n\r\nPutting these numbers in the word Jenny in the same way we find Y=4.\n<|im_end|>" }, { "id": "#43795", "title": "The Runner's Race", "fun": 2.55, "difficulty": 1.96, "author": "whsprec", "desc": "Five runners competed in a race; they were Dae, DaeShawn, Daemon, Daelen, and Daegel. They represented different teams: Turbo, I'm Tired, Eat Dust, How Far Left, and Shin Splits. They each wore a different color uniform: red, yellow, blue, green, and orange. Determine, from the clues given, the runner, the color of the uniform, the team, and the order in which they finished.\n\r\n1. Daemon won, but was not wearing the yellow uniform.\r\n2. Dae finished ahead of How Far Left but behind the blue uniform; however, none of them finished first.\r\n3. Neither Daemon, DaeShawn nor Daegel was wearing red, but one was team I'm Tired, another team Shin Splits, and the other finished fourth.\r\n4. Daelen finished ahead of the one in red, who beat How Far Left, who was ahead of the orange uniform.\r\n5. Neither DaeShawn nor Daemon represented Shin Splits or Turbo and neither of the teams or runners finished second.", "hint": "No hint available.", "answer": "1st: Daemon, I'm Tired, Green\r\n2nd: Daelen, Eat Dust, Blue\r\n3rd: Dae, Turbo, Red\r\n4th: DaeShawn, How Far Left, Yellow\r\n5th: Daegel, Shin Splits, Orange", "category": "Logic-Grid", "date": "12/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive runners competed in a race; they were Dae, DaeShawn, Daemon, Daelen, and Daegel. They represented different teams: Turbo, I'm Tired, Eat Dust, How Far Left, and Shin Splits. They each wore a different color uniform: red, yellow, blue, green, and orange. Determine, from the clues given, the runner, the color of the uniform, the team, and the order in which they finished.\n\r\n1. Daemon won, but was not wearing the yellow uniform.\r\n2. Dae finished ahead of How Far Left but behind the blue uniform; however, none of them finished first.\r\n3. Neither Daemon, DaeShawn nor Daegel was wearing red, but one was team I'm Tired, another team Shin Splits, and the other finished fourth.\r\n4. Daelen finished ahead of the one in red, who beat How Far Left, who was ahead of the orange uniform.\r\n5. Neither DaeShawn nor Daemon represented Shin Splits or Turbo and neither of the teams or runners finished second.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st: Daemon, I'm Tired, Green\r\n2nd: Daelen, Eat Dust, Blue\r\n3rd: Dae, Turbo, Red\r\n4th: DaeShawn, How Far Left, Yellow\r\n5th: Daegel, Shin Splits, Orange\n<|im_start|>answer\n1st: Daemon, I'm Tired, Green\r\n2nd: Daelen, Eat Dust, Blue\r\n3rd: Dae, Turbo, Red\r\n4th: DaeShawn, How Far Left, Yellow\r\n5th: Daegel, Shin Splits, Orange\n<|im_end|>" }, { "id": "#36722", "title": "Team Picture", "fun": 2.55, "difficulty": 1.43, "author": "pokpic", "desc": "The Timberland Tigers 11 players were taking their team picture. Figure out who sat where for the picture. Remember that each player has a jersey on, numbered 0 to 10.\r\n1. Number 9 is exactly in the middle.\r\n2. Number 8 is right before 2 but after 10.\r\n3. Number 4 is the one before number 9 but right after number 2.\r\n4. Number 1 is behind 3 and 7 in that order.\r\n5. Number 6 is right behind 9 but right in front of 0.\r\n6. Number 10 is first and Number 1 is last.\r\n7. Number 5 is right before 8 and right after Number 10.\r\n8. Number 3 is right after 0.", "hint": "No hint available.", "answer": "The order is \r\n#10 #5 # 8 # 2 # 4 # 9 #6 #0 #3 #7 #1", "category": "Logic", "date": "05/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Timberland Tigers 11 players were taking their team picture. Figure out who sat where for the picture. Remember that each player has a jersey on, numbered 0 to 10.\r\n1. Number 9 is exactly in the middle.\r\n2. Number 8 is right before 2 but after 10.\r\n3. Number 4 is the one before number 9 but right after number 2.\r\n4. Number 1 is behind 3 and 7 in that order.\r\n5. Number 6 is right behind 9 but right in front of 0.\r\n6. Number 10 is first and Number 1 is last.\r\n7. Number 5 is right before 8 and right after Number 10.\r\n8. Number 3 is right after 0.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe order is \r\n#10 #5 # 8 # 2 # 4 # 9 #6 #0 #3 #7 #1\n<|im_start|>answer\nThe order is \r\n#10 #5 # 8 # 2 # 4 # 9 #6 #0 #3 #7 #1\n<|im_end|>" }, { "id": "#20985", "title": "I Will Spend $10", "fun": 2.55, "difficulty": 1.98, "author": "Jessica", "desc": "A man goes into a store one day, and says to the cashier, \"If you can match and give me what I have in my pocket, I will spend $10 in your store.\"\n\r\nThe cashier matched and gave the man the money, and the man spent $10. The man then went to another store, said the same thing, and did the same. He then went to a third store, said the same thing, and did the same. After leaving the third store, he had no money left. How much money did he start out with?", "hint": "No hint available.", "answer": "He started out with $8.75.\r\n8.75+8.75=17.50-10.00=$7.50\r\n7.50+7.50=15.00-10.00=$5.00\r\n5.00+5.00=10.00-10.00=$0", "category": "Math", "date": "02/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man goes into a store one day, and says to the cashier, \"If you can match and give me what I have in my pocket, I will spend $10 in your store.\"\n\r\nThe cashier matched and gave the man the money, and the man spent $10. The man then went to another store, said the same thing, and did the same. He then went to a third store, said the same thing, and did the same. After leaving the third store, he had no money left. How much money did he start out with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe started out with $8.75.\r\n8.75+8.75=17.50-10.00=$7.50\r\n7.50+7.50=15.00-10.00=$5.00\r\n5.00+5.00=10.00-10.00=$0\n<|im_start|>answer\nHe started out with $8.75.\r\n8.75+8.75=17.50-10.00=$7.50\r\n7.50+7.50=15.00-10.00=$5.00\r\n5.00+5.00=10.00-10.00=$0\n<|im_end|>" }, { "id": "#21486", "title": "Dice Tournament", "fun": 2.55, "difficulty": 1.74, "author": "cdrock", "desc": "I was gambling against some of my best friends at a dice tournament (a game we made up). In the game you get to roll 6 dice and the person across from you gives you clues to figure out the numbers of the dice and the order you rolled them (left to right). One of the most unknown rules is that if you role a straight (1, 2, 3, 4, 5,and 6), then you triple your money but you only get five clues. Believe it or not, on my first roll I rolled a straight. My friend thought a while and finally figured out the clues and immediately told me them. \n\r\nClues:\n\r\n1. The die that was rolled 4 was on one of the ends.\n\r\n2. The die that was rolled 1 is two dice away from both the die that was rolled 2 and the die that was rolled 5.\n\r\n3. The die that was rolled 3 is somewhere to the left of the die that was rolled 6.\n\r\n4. The die that was rolled 2 is next to the die that was rolled 4.\n\r\n5. The die that was rolled 5 is somewhere to the right of the die that was rolled 4.", "hint": "No hint available.", "answer": "4, 2, 3, 1, 6, and 5 reading from left to right", "category": "Logic", "date": "03/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was gambling against some of my best friends at a dice tournament (a game we made up). In the game you get to roll 6 dice and the person across from you gives you clues to figure out the numbers of the dice and the order you rolled them (left to right). One of the most unknown rules is that if you role a straight (1, 2, 3, 4, 5,and 6), then you triple your money but you only get five clues. Believe it or not, on my first roll I rolled a straight. My friend thought a while and finally figured out the clues and immediately told me them. \n\r\nClues:\n\r\n1. The die that was rolled 4 was on one of the ends.\n\r\n2. The die that was rolled 1 is two dice away from both the die that was rolled 2 and the die that was rolled 5.\n\r\n3. The die that was rolled 3 is somewhere to the left of the die that was rolled 6.\n\r\n4. The die that was rolled 2 is next to the die that was rolled 4.\n\r\n5. The die that was rolled 5 is somewhere to the right of the die that was rolled 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4, 2, 3, 1, 6, and 5 reading from left to right\n<|im_start|>answer\n4, 2, 3, 1, 6, and 5 reading from left to right\n<|im_end|>" }, { "id": "#5798", "title": "6 ? 6 ? 6 ? 6", "fun": 2.55, "difficulty": 2.0, "author": "Bobbrt", "desc": "Insert the symbols +, -, *, and / between the 6's to make each equation below valid. The only catch is that the equations must read from left to right, ignoring normal arithmetic order. For example, 3 + 3 * 3 would equal 18, not 12 (3+3=6; 6*3=18).\n\r\n1. 42 = 6 ? 6 ? 6 ? 6\r\n2. 48 = 6 ? 6 ? 6 ? 6\r\n3. 66 = 6 ? 6 ? 6 ? 6\r\n4. 108 = 6 ? 6 ? 6 ? 6\r\n5. 180 = 6 ? 6 ? 6 ? 6", "hint": "No hint available.", "answer": "1. 42 = 6 / 6 + 6 * 6\r\n2. 48 = 6 * 6 + 6 + 6\r\n3. 66 = 6 + 6 * 6 - 6\r\n4. 108 = 6 + 6 + 6 * 6\r\n5. 180 = 6 * 6 - 6 * 6", "category": "Math", "date": "07/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nInsert the symbols +, -, *, and / between the 6's to make each equation below valid. The only catch is that the equations must read from left to right, ignoring normal arithmetic order. For example, 3 + 3 * 3 would equal 18, not 12 (3+3=6; 6*3=18).\n\r\n1. 42 = 6 ? 6 ? 6 ? 6\r\n2. 48 = 6 ? 6 ? 6 ? 6\r\n3. 66 = 6 ? 6 ? 6 ? 6\r\n4. 108 = 6 ? 6 ? 6 ? 6\r\n5. 180 = 6 ? 6 ? 6 ? 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. 42 = 6 / 6 + 6 * 6\r\n2. 48 = 6 * 6 + 6 + 6\r\n3. 66 = 6 + 6 * 6 - 6\r\n4. 108 = 6 + 6 + 6 * 6\r\n5. 180 = 6 * 6 - 6 * 6\n<|im_start|>answer\n1. 42 = 6 / 6 + 6 * 6\r\n2. 48 = 6 * 6 + 6 + 6\r\n3. 66 = 6 + 6 * 6 - 6\r\n4. 108 = 6 + 6 + 6 * 6\r\n5. 180 = 6 * 6 - 6 * 6\n<|im_end|>" }, { "id": "#5079", "title": "Escalator", "fun": 2.55, "difficulty": 2.47, "author": "Cascas", "desc": "Justin takes the underground train to work and uses an escalator at the railway station. If Justin runs up 7 steps of the escalator, then it takes him 30.0 seconds to reach the top of the escalator. If he runs up 13 steps of the escalator, then it takes him only 21.0 seconds to reach the top. \n\r\nHow many seconds would it take Justin to reach the top if he did not run up any steps of the escalator at all?", "hint": "No hint available.", "answer": "Solution: \n\r\nIf he runs up 7 steps, then he needs 30.0 seconds to reach the top.\r\nIf he runs up 13 steps, then he needs 21.0 seconds to reach the top. \n\r\nThe 6 additional steps take 9.0 seconds.\r\nTherefore, each step takes 1.5 seconds. \n\r\nTotal steps in escalator = 7 + 30.0 / 1.5 = 27 or Total steps in escalator = 13 + 21.0 / 1.5 = 27. \n\r\nIf Justin did not run up any steps at all,\r\nhe would reach the top of the escalator in 40.5 seconds", "category": "Math", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJustin takes the underground train to work and uses an escalator at the railway station. If Justin runs up 7 steps of the escalator, then it takes him 30.0 seconds to reach the top of the escalator. If he runs up 13 steps of the escalator, then it takes him only 21.0 seconds to reach the top. \n\r\nHow many seconds would it take Justin to reach the top if he did not run up any steps of the escalator at all?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSolution: \n\r\nIf he runs up 7 steps, then he needs 30.0 seconds to reach the top.\r\nIf he runs up 13 steps, then he needs 21.0 seconds to reach the top. \n\r\nThe 6 additional steps take 9.0 seconds.\r\nTherefore, each step takes 1.5 seconds. \n\r\nTotal steps in escalator = 7 + 30.0 / 1.5 = 27 or Total steps in escalator = 13 + 21.0 / 1.5 = 27. \n\r\nIf Justin did not run up any steps at all,\r\nhe would reach the top of the escalator in 40.5 seconds\n<|im_start|>answer\nSolution: \n\r\nIf he runs up 7 steps, then he needs 30.0 seconds to reach the top.\r\nIf he runs up 13 steps, then he needs 21.0 seconds to reach the top. \n\r\nThe 6 additional steps take 9.0 seconds.\r\nTherefore, each step takes 1.5 seconds. \n\r\nTotal steps in escalator = 7 + 30.0 / 1.5 = 27 or Total steps in escalator = 13 + 21.0 / 1.5 = 27. \n\r\nIf Justin did not run up any steps at all,\r\nhe would reach the top of the escalator in 40.5 seconds\n<|im_end|>" }, { "id": "#25740", "title": "It wasn't who I am, but what I am?", "fun": 2.55, "difficulty": 0.76, "author": "bigbadmike", "desc": "I came into the class room, and then suddenly someone stuck me on the wall. Next, the teacher walked in and adjusted me like a lousy picture frame! Then I asked myself, \"Why did she leave me hanging?\" I just don't understand.\n\r\n\tThe kids keep staring at me and then the teacher. Back and forth, back and forth. Why do they stare? Is it because of my face? Is it the fact that I can't stop waving my arms around and around?\n\r\n\tWhatever it was, they left me hanging there all day and night; even on vacations.\n\r\n\tEvery time it was the same. DAY AFTER DAY! WEEK AFTER WEEK!! MONTH AFTER MONTH!!!!!!!!!\n\r\n\tThen, at the end of the school year, I realized the reason I was treated the way I was. It wasn't who I am, but what I am.\n\r\n\tBut, WHAT AM I?", "hint": "You can tell I am good with numbers by the look on my face.", "answer": "I am a clock.", "category": "Logic", "date": "09/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI came into the class room, and then suddenly someone stuck me on the wall. Next, the teacher walked in and adjusted me like a lousy picture frame! Then I asked myself, \"Why did she leave me hanging?\" I just don't understand.\n\r\n\tThe kids keep staring at me and then the teacher. Back and forth, back and forth. Why do they stare? Is it because of my face? Is it the fact that I can't stop waving my arms around and around?\n\r\n\tWhatever it was, they left me hanging there all day and night; even on vacations.\n\r\n\tEvery time it was the same. DAY AFTER DAY! WEEK AFTER WEEK!! MONTH AFTER MONTH!!!!!!!!!\n\r\n\tThen, at the end of the school year, I realized the reason I was treated the way I was. It wasn't who I am, but what I am.\n\r\n\tBut, WHAT AM I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI am a clock.\n<|im_start|>answer\nI am a clock.\n<|im_end|>" }, { "id": "#23675", "title": "Dogged Again", "fun": 2.55, "difficulty": 0.81, "author": "Ill-Logic-Al", "desc": "Al, Mary, JJ, and Eric all have dogs of different breeds. The dogs' breeds are Beagle, German Shepherd, Springer, and mixed (mutt). The dogs' ages are 12 years, 10 years, 3 years and 6 months. \n\r\nFrom the facts below figure out who has which dog and how old is each.\n\r\nMary's dog is older than the mutt and the German Shepherd combined.\n\r\nEric has a Beagle, named Buster, who is not the oldest, and his hound is older than two other dogs combined.\n\r\nAl's dog is older than the mutt.", "hint": "No hint available.", "answer": "Al - German Shepherd - 3y\r\nMary - Springer - 12y\r\nJJ - Mutt - 6 months\r\nEric - Beagle - 10y \n\r\nEric's dog cannot be the youngest nor the second youngest, because two dogs ages have to combine to make that dog's age. It can't be the oldest, so it must be 10 years. \n\r\nMary's dog is not the German Shepherd nor the mutt because their ages combined are younger than her dog's age. Her dog must be the oldest and the Springer.\n\r\nAl's dog is older than the mutt. So his dog must be the German Shepherd and 3 years.\n\r\nJJ has what's left. Mutt at 6 months.", "category": "Logic-Grid", "date": "06/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl, Mary, JJ, and Eric all have dogs of different breeds. The dogs' breeds are Beagle, German Shepherd, Springer, and mixed (mutt). The dogs' ages are 12 years, 10 years, 3 years and 6 months. \n\r\nFrom the facts below figure out who has which dog and how old is each.\n\r\nMary's dog is older than the mutt and the German Shepherd combined.\n\r\nEric has a Beagle, named Buster, who is not the oldest, and his hound is older than two other dogs combined.\n\r\nAl's dog is older than the mutt.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAl - German Shepherd - 3y\r\nMary - Springer - 12y\r\nJJ - Mutt - 6 months\r\nEric - Beagle - 10y \n\r\nEric's dog cannot be the youngest nor the second youngest, because two dogs ages have to combine to make that dog's age. It can't be the oldest, so it must be 10 years. \n\r\nMary's dog is not the German Shepherd nor the mutt because their ages combined are younger than her dog's age. Her dog must be the oldest and the Springer.\n\r\nAl's dog is older than the mutt. So his dog must be the German Shepherd and 3 years.\n\r\nJJ has what's left. Mutt at 6 months.\n<|im_start|>answer\nAl - German Shepherd - 3y\r\nMary - Springer - 12y\r\nJJ - Mutt - 6 months\r\nEric - Beagle - 10y \n\r\nEric's dog cannot be the youngest nor the second youngest, because two dogs ages have to combine to make that dog's age. It can't be the oldest, so it must be 10 years. \n\r\nMary's dog is not the German Shepherd nor the mutt because their ages combined are younger than her dog's age. Her dog must be the oldest and the Springer.\n\r\nAl's dog is older than the mutt. So his dog must be the German Shepherd and 3 years.\n\r\nJJ has what's left. Mutt at 6 months.\n<|im_end|>" }, { "id": "#22789", "title": "7777", "fun": 2.55, "difficulty": 2.62, "author": "fishmed", "desc": "Can you take 4 7's and arrange them with any math symbols needed to make the total be 100?", "hint": "Division is needed", "answer": "77/.77=100", "category": "Math", "date": "05/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you take 4 7's and arrange them with any math symbols needed to make the total be 100?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n77/.77=100\n<|im_start|>answer\n77/.77=100\n<|im_end|>" }, { "id": "#40101", "title": "Triathlon Competition", "fun": 2.55, "difficulty": 3.33, "author": "cnmne", "desc": "A triathlon consists of three events: swimming, cycling, and running. The contestants are: Adam, Bert, Carl, Doug, and Eric. From the following clues, you must determine: the order of finish in swimming, the order of finish in cycling, the order of finish in running, and the overall rankings.\n\r\nPoints are awarded for each event: 1st place earns 4 points, 2nd earns 3, 3rd earns 2, 4th earns 1, and 5th earns 0. Each contestant's three event scores are added together to obtain that person's total score. The total score determines the order of the overall rankings.\n\r\n1) Adam did not finish 5th in any individual event.\r\n2) Bert finished 2nd in only one individual event.\r\n3) Carl finished one position better in swimming than in cycling.\r\n4) Doug finished 4th in only one individual event.\r\n5) Eric did not finish 3rd in any individual event.\r\n6) No contestant who won an individual event had the best overall ranking.\r\n7) The contestant who finished 3rd in cycling finished better in swimming than the contestant who finished 3rd in running.\r\n8) The contestant who finished 4th in running finished better in cycling than the contestant who finished 4th in swimming.\r\n9) The contestant who finished 5th in swimming finished better in running than the contestant who finished 5th in cycling.\r\n10) Only one contestant finished each event in a different position, and that contestant finished 4th overall.", "hint": "You must first determine the five unique point totals necessary to determine the overall standings.\n\r\nThen you must determine what combination of individual finishes are necessary to achieve those overall point totals.", "answer": "The scoring system provides 10 points per event, or a total of 30 overall points. Since the overall winner did not win any individual event (clue 6) and Bert finished 2nd in one event (clue 2), that means that the best total score could only be 8 points (two 2nd place and one 3rd place). The only way to achieve 30 points with five unique scores, 8 being best, is 8 + 7 + 6 + 5 + 4 = 30.\n\r\nOnly the contestant who finished 4th overall had three different finishes, (clue 10), so the only way to achieve the proper overall point totals is as follows:\r\n1st place (8 points) - 2nd, 2nd, 3rd (no 1st, 4th, or 5th individual finishes)\r\n2nd place (7 points) - 2nd, 3rd, 3rd (no 1st, 4th, or 5th individual finishes)\r\n3rd place (6 points) - 1st, 4th, 4th (no 2nd, 3rd, or 5th individual finishes)\r\n4th place (5 points) - 1st, 4th, 5th (no 2nd or 3rd individual finishes)\r\n5th place (4 points) - 1st, 5th, 5th (no 2nd, 3rd, or 4th individual finishes)\n\r\nAdam did not finish 4th or 5th overall (clue 1). Bert finished 2nd overall (clue 2). Doug finished 4th overall (clue 4). Eric did not finish 1st or 2nd overall (clue 5). The contestant who finished 3rd in cycling is not the same as the one who finished 3rd in running (clue 7), so the contestant who finished 2nd overall had to finish 3rd in swimming. Carl finished one position better in swimming than in cycling, and the only combination that works is 2nd in swimming and 3rd in cycling.\n\r\nSwimming: Eric, Carl, Bert, Adam, Doug\r\nCycling: Doug, Bert, Carl, Adam, Eric\r\nRunning: Adam, Carl, Bert, Doug, Eric\r\nOverall: Carl, Bert, Adam, Doug, Eric", "category": "Logic-Grid", "date": "01/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA triathlon consists of three events: swimming, cycling, and running. The contestants are: Adam, Bert, Carl, Doug, and Eric. From the following clues, you must determine: the order of finish in swimming, the order of finish in cycling, the order of finish in running, and the overall rankings.\n\r\nPoints are awarded for each event: 1st place earns 4 points, 2nd earns 3, 3rd earns 2, 4th earns 1, and 5th earns 0. Each contestant's three event scores are added together to obtain that person's total score. The total score determines the order of the overall rankings.\n\r\n1) Adam did not finish 5th in any individual event.\r\n2) Bert finished 2nd in only one individual event.\r\n3) Carl finished one position better in swimming than in cycling.\r\n4) Doug finished 4th in only one individual event.\r\n5) Eric did not finish 3rd in any individual event.\r\n6) No contestant who won an individual event had the best overall ranking.\r\n7) The contestant who finished 3rd in cycling finished better in swimming than the contestant who finished 3rd in running.\r\n8) The contestant who finished 4th in running finished better in cycling than the contestant who finished 4th in swimming.\r\n9) The contestant who finished 5th in swimming finished better in running than the contestant who finished 5th in cycling.\r\n10) Only one contestant finished each event in a different position, and that contestant finished 4th overall.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe scoring system provides 10 points per event, or a total of 30 overall points. Since the overall winner did not win any individual event (clue 6) and Bert finished 2nd in one event (clue 2), that means that the best total score could only be 8 points (two 2nd place and one 3rd place). The only way to achieve 30 points with five unique scores, 8 being best, is 8 + 7 + 6 + 5 + 4 = 30.\n\r\nOnly the contestant who finished 4th overall had three different finishes, (clue 10), so the only way to achieve the proper overall point totals is as follows:\r\n1st place (8 points) - 2nd, 2nd, 3rd (no 1st, 4th, or 5th individual finishes)\r\n2nd place (7 points) - 2nd, 3rd, 3rd (no 1st, 4th, or 5th individual finishes)\r\n3rd place (6 points) - 1st, 4th, 4th (no 2nd, 3rd, or 5th individual finishes)\r\n4th place (5 points) - 1st, 4th, 5th (no 2nd or 3rd individual finishes)\r\n5th place (4 points) - 1st, 5th, 5th (no 2nd, 3rd, or 4th individual finishes)\n\r\nAdam did not finish 4th or 5th overall (clue 1). Bert finished 2nd overall (clue 2). Doug finished 4th overall (clue 4). Eric did not finish 1st or 2nd overall (clue 5). The contestant who finished 3rd in cycling is not the same as the one who finished 3rd in running (clue 7), so the contestant who finished 2nd overall had to finish 3rd in swimming. Carl finished one position better in swimming than in cycling, and the only combination that works is 2nd in swimming and 3rd in cycling.\n\r\nSwimming: Eric, Carl, Bert, Adam, Doug\r\nCycling: Doug, Bert, Carl, Adam, Eric\r\nRunning: Adam, Carl, Bert, Doug, Eric\r\nOverall: Carl, Bert, Adam, Doug, Eric\n<|im_start|>answer\nThe scoring system provides 10 points per event, or a total of 30 overall points. Since the overall winner did not win any individual event (clue 6) and Bert finished 2nd in one event (clue 2), that means that the best total score could only be 8 points (two 2nd place and one 3rd place). The only way to achieve 30 points with five unique scores, 8 being best, is 8 + 7 + 6 + 5 + 4 = 30.\n\r\nOnly the contestant who finished 4th overall had three different finishes, (clue 10), so the only way to achieve the proper overall point totals is as follows:\r\n1st place (8 points) - 2nd, 2nd, 3rd (no 1st, 4th, or 5th individual finishes)\r\n2nd place (7 points) - 2nd, 3rd, 3rd (no 1st, 4th, or 5th individual finishes)\r\n3rd place (6 points) - 1st, 4th, 4th (no 2nd, 3rd, or 5th individual finishes)\r\n4th place (5 points) - 1st, 4th, 5th (no 2nd or 3rd individual finishes)\r\n5th place (4 points) - 1st, 5th, 5th (no 2nd, 3rd, or 4th individual finishes)\n\r\nAdam did not finish 4th or 5th overall (clue 1). Bert finished 2nd overall (clue 2). Doug finished 4th overall (clue 4). Eric did not finish 1st or 2nd overall (clue 5). The contestant who finished 3rd in cycling is not the same as the one who finished 3rd in running (clue 7), so the contestant who finished 2nd overall had to finish 3rd in swimming. Carl finished one position better in swimming than in cycling, and the only combination that works is 2nd in swimming and 3rd in cycling.\n\r\nSwimming: Eric, Carl, Bert, Adam, Doug\r\nCycling: Doug, Bert, Carl, Adam, Eric\r\nRunning: Adam, Carl, Bert, Doug, Eric\r\nOverall: Carl, Bert, Adam, Doug, Eric\n<|im_end|>" }, { "id": "#7173", "title": "Sabrina and Samantha", "fun": 2.55, "difficulty": 1.83, "author": "Michelle", "desc": "Sabrina gave Samantha as many dollars as Samantha started out with. Samantha then gave Sabrina back as much as Sabrina had left. Sabrina then gave Samantha back as many dollars as Samantha had left, which left Sabrina broke and gave Samantha a total of $80.00. How much did Sabrina and Samantha have at the beginning of their exchange?", "hint": "No hint available.", "answer": "Sabrina had $50 and Samantha had $30.\n\r\nThis can be solved by setting up two simultaneous equations, but it's easier just to work backwards:\n\r\nAt each step, the person who is receiving the money gets the amount that they were already holding. In other words, they double their money. \r\nTherefore, just before the last exchange, Samantha must have had $40 and was given another $40 to get to her total of $80.\r\nJust before the second exchange, Sabrina must have had half of her $40. Therefore, Sabrina had $20 and Samantha had $60. \r\nAfter the first exchange Samantha doubled her money, so she must have had $30 before the exchange, leaving Sabrina with $50 at the start.", "category": "Math", "date": "09/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSabrina gave Samantha as many dollars as Samantha started out with. Samantha then gave Sabrina back as much as Sabrina had left. Sabrina then gave Samantha back as many dollars as Samantha had left, which left Sabrina broke and gave Samantha a total of $80.00. How much did Sabrina and Samantha have at the beginning of their exchange?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSabrina had $50 and Samantha had $30.\n\r\nThis can be solved by setting up two simultaneous equations, but it's easier just to work backwards:\n\r\nAt each step, the person who is receiving the money gets the amount that they were already holding. In other words, they double their money. \r\nTherefore, just before the last exchange, Samantha must have had $40 and was given another $40 to get to her total of $80.\r\nJust before the second exchange, Sabrina must have had half of her $40. Therefore, Sabrina had $20 and Samantha had $60. \r\nAfter the first exchange Samantha doubled her money, so she must have had $30 before the exchange, leaving Sabrina with $50 at the start.\n<|im_start|>answer\nSabrina had $50 and Samantha had $30.\n\r\nThis can be solved by setting up two simultaneous equations, but it's easier just to work backwards:\n\r\nAt each step, the person who is receiving the money gets the amount that they were already holding. In other words, they double their money. \r\nTherefore, just before the last exchange, Samantha must have had $40 and was given another $40 to get to her total of $80.\r\nJust before the second exchange, Sabrina must have had half of her $40. Therefore, Sabrina had $20 and Samantha had $60. \r\nAfter the first exchange Samantha doubled her money, so she must have had $30 before the exchange, leaving Sabrina with $50 at the start.\n<|im_end|>" }, { "id": "#39874", "title": "Homecoming Parade", "fun": 2.55, "difficulty": 1.29, "author": "allan512", "desc": "Martin, Peg, Frank, and Yvonne are in the homecoming parade. They are in the BMX brigade, the Queen's Court float, the marching band, and the football float. They are in the 9th, 10th, 11th, and 12th grades, and they are either the second, fifth, sixth, or twelfth entry in the parade. March through these clues to determine what each student is doing in the parade.\n\r\nClues:\n\r\n1. Martin is nearer the beginning of the parade than the girl riding on the Queen's Court float and the boy on the football float, but he comes after Yvonne.\n\r\n2. Frank is in a higher grade than the girl with the marching band and Peg, but he is in a lower grade than the boy who is with the fifth entry.\n\r\n3. The person with the Queen's float is in a higher grade than the girl with the marching band.\n\r\n4. The Queen's float is the final parade feature.", "hint": "No hint available.", "answer": "Martin = BMX brigade, 12th grade, and 5th entry\n\r\nPeg = Queen's court, 10th grade, and 12th entry\n\r\nFrank = football float, 11th grade, and 6th entry\n\r\nYvonne = marching band, 9th grade, and 2nd entry", "category": "Logic-Grid", "date": "01/01/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMartin, Peg, Frank, and Yvonne are in the homecoming parade. They are in the BMX brigade, the Queen's Court float, the marching band, and the football float. They are in the 9th, 10th, 11th, and 12th grades, and they are either the second, fifth, sixth, or twelfth entry in the parade. March through these clues to determine what each student is doing in the parade.\n\r\nClues:\n\r\n1. Martin is nearer the beginning of the parade than the girl riding on the Queen's Court float and the boy on the football float, but he comes after Yvonne.\n\r\n2. Frank is in a higher grade than the girl with the marching band and Peg, but he is in a lower grade than the boy who is with the fifth entry.\n\r\n3. The person with the Queen's float is in a higher grade than the girl with the marching band.\n\r\n4. The Queen's float is the final parade feature.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMartin = BMX brigade, 12th grade, and 5th entry\n\r\nPeg = Queen's court, 10th grade, and 12th entry\n\r\nFrank = football float, 11th grade, and 6th entry\n\r\nYvonne = marching band, 9th grade, and 2nd entry\n<|im_start|>answer\nMartin = BMX brigade, 12th grade, and 5th entry\n\r\nPeg = Queen's court, 10th grade, and 12th entry\n\r\nFrank = football float, 11th grade, and 6th entry\n\r\nYvonne = marching band, 9th grade, and 2nd entry\n<|im_end|>" }, { "id": "#5128", "title": "My Age", "fun": 2.55, "difficulty": 1.61, "author": "Cascas", "desc": "When I add 6 times my age 6 years from now to 7 times my age 7 years from now, I get 14 times my current age. How old will I be 3 years from now?", "hint": "No hint available.", "answer": "88", "category": "Math", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen I add 6 times my age 6 years from now to 7 times my age 7 years from now, I get 14 times my current age. How old will I be 3 years from now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n88\n<|im_start|>answer\n88\n<|im_end|>" }, { "id": "#31944", "title": "Opposites 24", "fun": 2.55, "difficulty": 1.91, "author": "Winner4600", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n# stands for N, L, H, E, or T\r\n* stands for Y, G, H, P, or D\r\n7 stands for S, I, O, A, or U\r\n1 stands for C, U, F, E, or B\n\r\nThe four letter code word, 7*1#, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Open and Shut.", "category": "Logic", "date": "07/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n# stands for N, L, H, E, or T\r\n* stands for Y, G, H, P, or D\r\n7 stands for S, I, O, A, or U\r\n1 stands for C, U, F, E, or B\n\r\nThe four letter code word, 7*1#, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOpen and Shut.\n<|im_start|>answer\nOpen and Shut.\n<|im_end|>" }, { "id": "#28007", "title": "Men, Women and Children", "fun": 2.55, "difficulty": 1.04, "author": "npf2005", "desc": "In a party of 35 people there are twice as many women as children and twice as many children as men. How many of each are there?", "hint": "No hint available.", "answer": "5 men, 10 children and 20 women.", "category": "Math", "date": "01/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a party of 35 people there are twice as many women as children and twice as many children as men. How many of each are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 men, 10 children and 20 women.\n<|im_start|>answer\n5 men, 10 children and 20 women.\n<|im_end|>" }, { "id": "#2174", "title": "Step in Step", "fun": 2.55, "difficulty": 1.95, "author": "Cascas", "desc": "A man and a boy who are walking together step out with their right feet. The boy walks three paces while the man walks two. When will they both put their left feet forward together?", "hint": "No hint available.", "answer": "Never. Every second cycle their right feet will go forward together, but never their left.", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man and a boy who are walking together step out with their right feet. The boy walks three paces while the man walks two. When will they both put their left feet forward together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNever. Every second cycle their right feet will go forward together, but never their left.\n<|im_start|>answer\nNever. Every second cycle their right feet will go forward together, but never their left.\n<|im_end|>" }, { "id": "#3638", "title": "I Can't Say It", "fun": 2.55, "difficulty": 1.23, "author": "Bobbrt", "desc": "I either always lie or always tell the truth. Regardless of which it is, there is one statement that I can never make. What is it?", "hint": "No hint available.", "answer": "The statement is \"I always lie\" (or variations of it).\r\nIf I always lie, then that statement would be the truth, so I couldn't say it. If I always tell the truth, then I obviously couldn't say it because it would be a lie.", "category": "Logic", "date": "04/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI either always lie or always tell the truth. Regardless of which it is, there is one statement that I can never make. What is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe statement is \"I always lie\" (or variations of it).\r\nIf I always lie, then that statement would be the truth, so I couldn't say it. If I always tell the truth, then I obviously couldn't say it because it would be a lie.\n<|im_start|>answer\nThe statement is \"I always lie\" (or variations of it).\r\nIf I always lie, then that statement would be the truth, so I couldn't say it. If I always tell the truth, then I obviously couldn't say it because it would be a lie.\n<|im_end|>" }, { "id": "#45063", "title": "Mafia Wars", "fun": 2.55, "difficulty": 2.13, "author": "goatroper605", "desc": "Trooper Thorn has found that he really enjoys playing the online game Mafia Wars. He's also met a bunch of people who enjoy playing the game, as well. They've all decided to start a new mafia family called the Lost Souls. After having fully equipped everyone in the family, they've decided to attack their arch nemesis mafia family called the Boston Irish Mob. Trooper Thorn has been placed in charge of devising a schedule of attacks. After several hours of working on it, he has finally come up with this schedule. However, exhausted from his labors, he falls asleep at his desk & winds up drooling all over his notes; rendering them all but useless. From the information he can remember, can you figure out who the teams are, who they're supposed to attack & the day/time of the attack?\n\r\n1. Lucky wasn't attacked on Monday, but he was attacked two hours later than Scathach's target.\n\r\n2. Tommy, who wasn't teamed up with Mojo, attacked at 2pm, but not on Friday. Godfather was attacked the day after Mangler attacked her target but two days before the person attacked at 6:00pm.\n\r\n3. Porkchop attacked the day before Whisper was attacked but four hours later than Mojo attacked.\n\r\n4. Angel & her partner Fightin' Irish attacked either Whisper or Godfather. Monday's attack was done at 4 pm.\n\r\n5. Porkchop wasn't partnered with Lizzie. Meathook attacked Scarface. Mojo didn't attack on Wednesday.\n\r\n6. Froglegz was attacked two hours earlier than Mangler attacked but three days after Meathook attacked. Shoco's partner, who wasn't Lizzie, didn't attack Whisper or Godfather but they did attack on Tuesday.", "hint": "No hint available.", "answer": "1. Fightin' Irish / Angel / Whisper / 6pm / Friday\n\r\n2. Tommy / Lizzie / Godfather / 2pm / Wednesday\n\r\n3. Porkchop / Scathach / Froglegz / 8pm / Thursday\n\r\n4. Shoco / Mangler / Lucky / 10pm / Tuesday\n\r\n5. Meathook / Mojo / Scarface / 4pm / Monday", "category": "Logic-Grid", "date": "08/16/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTrooper Thorn has found that he really enjoys playing the online game Mafia Wars. He's also met a bunch of people who enjoy playing the game, as well. They've all decided to start a new mafia family called the Lost Souls. After having fully equipped everyone in the family, they've decided to attack their arch nemesis mafia family called the Boston Irish Mob. Trooper Thorn has been placed in charge of devising a schedule of attacks. After several hours of working on it, he has finally come up with this schedule. However, exhausted from his labors, he falls asleep at his desk & winds up drooling all over his notes; rendering them all but useless. From the information he can remember, can you figure out who the teams are, who they're supposed to attack & the day/time of the attack?\n\r\n1. Lucky wasn't attacked on Monday, but he was attacked two hours later than Scathach's target.\n\r\n2. Tommy, who wasn't teamed up with Mojo, attacked at 2pm, but not on Friday. Godfather was attacked the day after Mangler attacked her target but two days before the person attacked at 6:00pm.\n\r\n3. Porkchop attacked the day before Whisper was attacked but four hours later than Mojo attacked.\n\r\n4. Angel & her partner Fightin' Irish attacked either Whisper or Godfather. Monday's attack was done at 4 pm.\n\r\n5. Porkchop wasn't partnered with Lizzie. Meathook attacked Scarface. Mojo didn't attack on Wednesday.\n\r\n6. Froglegz was attacked two hours earlier than Mangler attacked but three days after Meathook attacked. Shoco's partner, who wasn't Lizzie, didn't attack Whisper or Godfather but they did attack on Tuesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Fightin' Irish / Angel / Whisper / 6pm / Friday\n\r\n2. Tommy / Lizzie / Godfather / 2pm / Wednesday\n\r\n3. Porkchop / Scathach / Froglegz / 8pm / Thursday\n\r\n4. Shoco / Mangler / Lucky / 10pm / Tuesday\n\r\n5. Meathook / Mojo / Scarface / 4pm / Monday\n<|im_start|>answer\n1. Fightin' Irish / Angel / Whisper / 6pm / Friday\n\r\n2. Tommy / Lizzie / Godfather / 2pm / Wednesday\n\r\n3. Porkchop / Scathach / Froglegz / 8pm / Thursday\n\r\n4. Shoco / Mangler / Lucky / 10pm / Tuesday\n\r\n5. Meathook / Mojo / Scarface / 4pm / Monday\n<|im_end|>" }, { "id": "#14652", "title": "Googlebunnies I", "fun": 2.55, "difficulty": 2.06, "author": "taiya2003", "desc": "Googlebunnies are creatures that come in two types (spooky and flitty) and two genders (male and female). The spooky males and flitty females always tell the truth; flitty males and spooky females always lie. \n\r\nYou come across 3 Googlebunnies. Determine the type and gender of each based on their statements: \n\r\nA: Ask B what my type is - he will give a truthful answer. C is flitty. \n\r\nB: A and I are both males. C is a female. \n\r\nC: A and B are both females. B is spooky.", "hint": "No hint available.", "answer": "A. Spooky Female \r\nB. Spooky Female \r\nC. Spooky Male \n\r\nIf A is truthful, B must be truthful which would make C a Flitty Female. Since that would mean C speaks the truth then A and B are both predators which would make B's statement false. Therefore A must be lying. \n\r\nTherefore if A lies then B must lie (from A's statement). \n\r\nFrom A's false statement then, C is spooky and from B's false statement. C is male. Therefore C is truthful and A and B are both Spooky Females.", "category": "Logic", "date": "09/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGooglebunnies are creatures that come in two types (spooky and flitty) and two genders (male and female). The spooky males and flitty females always tell the truth; flitty males and spooky females always lie. \n\r\nYou come across 3 Googlebunnies. Determine the type and gender of each based on their statements: \n\r\nA: Ask B what my type is - he will give a truthful answer. C is flitty. \n\r\nB: A and I are both males. C is a female. \n\r\nC: A and B are both females. B is spooky.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA. Spooky Female \r\nB. Spooky Female \r\nC. Spooky Male \n\r\nIf A is truthful, B must be truthful which would make C a Flitty Female. Since that would mean C speaks the truth then A and B are both predators which would make B's statement false. Therefore A must be lying. \n\r\nTherefore if A lies then B must lie (from A's statement). \n\r\nFrom A's false statement then, C is spooky and from B's false statement. C is male. Therefore C is truthful and A and B are both Spooky Females.\n<|im_start|>answer\nA. Spooky Female \r\nB. Spooky Female \r\nC. Spooky Male \n\r\nIf A is truthful, B must be truthful which would make C a Flitty Female. Since that would mean C speaks the truth then A and B are both predators which would make B's statement false. Therefore A must be lying. \n\r\nTherefore if A lies then B must lie (from A's statement). \n\r\nFrom A's false statement then, C is spooky and from B's false statement. C is male. Therefore C is truthful and A and B are both Spooky Females.\n<|im_end|>" }, { "id": "#42044", "title": "Who Will He Like?", "fun": 2.55, "difficulty": 1.55, "author": "Carlos16", "desc": "Peter likes Susan but not Shawna. He likes Nancy but not Edith, and he likes William but not Charles. Following this same logic, will he like Roger or Chris?", "hint": "No hint available.", "answer": "Peter has a fondness for names that have two of the same consonant or, alternatively, names with a vowel as the second letter.\n\r\nAnswer: Roger", "category": "Logic", "date": "05/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPeter likes Susan but not Shawna. He likes Nancy but not Edith, and he likes William but not Charles. Following this same logic, will he like Roger or Chris?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPeter has a fondness for names that have two of the same consonant or, alternatively, names with a vowel as the second letter.\n\r\nAnswer: Roger\n<|im_start|>answer\nPeter has a fondness for names that have two of the same consonant or, alternatively, names with a vowel as the second letter.\n\r\nAnswer: Roger\n<|im_end|>" }, { "id": "#44076", "title": "Book Group Lunch", "fun": 2.55, "difficulty": 1.6300000000000001, "author": "dswilborn", "desc": "The Daly City Book Group meets every Wednesday for lunch. One week, Paul, Kate, Mike, and Tina all sat at the same table and talked about their favorite book genres, favorite authors, and, of course, their favorite books (one of which was \"To Kill a Mockingbird\"). Interestingly enough, each person liked books and authors that didn't always match their favorite genre style. Can you determine from the clues below each person's reading preferences?\n\r\n1. Kate enjoys Charles Dickens, but does not like reading biographies. Paul, on the other hand, prefers an American author.\n\r\n2. \"The Color Purple\" fan has never read a romance novel, nor has he read anything by Ernest Hemingway.\n\r\n3. During lunch, Mike sat between the biography fan and the person who likes science fiction. He noticed that the science fiction fan was holding a copy of her favorite book, \"Little Women\".\n\r\n4. Although some of Shakespeare's plays could be considered romantic, the person who reads romance novels can't stand his writing!\n\r\n5. The four people who shared a table were: Paul, the woman who loves John Steinbeck books, the mystery fan, and the person who reads \"Lord of the Rings\" every year.", "hint": "Steinbeck and Hemingway are American authors.", "answer": "Kate: romance books, Charles Dickens, \"Lord of the Rings\"\r\nMike: mystery books, William Shakespeare, \"The Color Purple\"\r\nPaul: biographies, Ernest Hemingway, \"To Kill a Mockingbird\"\r\nTina: science fiction books, John Steinbeck, \"Little Women\"", "category": "Logic-Grid", "date": "02/08/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Daly City Book Group meets every Wednesday for lunch. One week, Paul, Kate, Mike, and Tina all sat at the same table and talked about their favorite book genres, favorite authors, and, of course, their favorite books (one of which was \"To Kill a Mockingbird\"). Interestingly enough, each person liked books and authors that didn't always match their favorite genre style. Can you determine from the clues below each person's reading preferences?\n\r\n1. Kate enjoys Charles Dickens, but does not like reading biographies. Paul, on the other hand, prefers an American author.\n\r\n2. \"The Color Purple\" fan has never read a romance novel, nor has he read anything by Ernest Hemingway.\n\r\n3. During lunch, Mike sat between the biography fan and the person who likes science fiction. He noticed that the science fiction fan was holding a copy of her favorite book, \"Little Women\".\n\r\n4. Although some of Shakespeare's plays could be considered romantic, the person who reads romance novels can't stand his writing!\n\r\n5. The four people who shared a table were: Paul, the woman who loves John Steinbeck books, the mystery fan, and the person who reads \"Lord of the Rings\" every year.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKate: romance books, Charles Dickens, \"Lord of the Rings\"\r\nMike: mystery books, William Shakespeare, \"The Color Purple\"\r\nPaul: biographies, Ernest Hemingway, \"To Kill a Mockingbird\"\r\nTina: science fiction books, John Steinbeck, \"Little Women\"\n<|im_start|>answer\nKate: romance books, Charles Dickens, \"Lord of the Rings\"\r\nMike: mystery books, William Shakespeare, \"The Color Purple\"\r\nPaul: biographies, Ernest Hemingway, \"To Kill a Mockingbird\"\r\nTina: science fiction books, John Steinbeck, \"Little Women\"\n<|im_end|>" }, { "id": "#36735", "title": "Cornered In Choresville", "fun": 2.55, "difficulty": 1.85, "author": "chaskey", "desc": "On a spring day in Choresville, five acquaintances, all relatively new in town, had specific objectives in mind concerning particular objects. Temporarily useful knowledge of these errands and chores in various parts of town may be acquired by carefully following the following carefully-formed clues.\n\r\nPEOPLE: men: Sal Vaged, Tim Id, Ben A. Brink\r\n women: Ona Verge, Atta Edge\r\nOBJECTS: money, lunch, coat, water pipe, ring\r\nBUSINESSES: Big Piggy Bank, May Bee Beauty Salon, Flat Facets Diamonds, Genuine Hardware, Sole Shoe Repair\r\nBUILDINGS: Bent Brick, Vertical Towers, Stacked Stories, Cloud Tickler, Lofty Lights\r\nSTREETS: Pothole Parkway, Famed Feet Walkway, Stoned Street, New Avenue, Noble Bull Boulevard\n\r\nCLUES:\r\n1. As he was walking down Stoned Street, on his way around the corner to Big Piggy Bank to secure his newly-purchased engagement ring into his safety-deposit box, Sal Vaged met Atta Edge just coming out of Genuine Hardware, where she had delivered a box lunch to her husband.\n\r\n2. Sal asked Atta if she had seen his fiancee, and she said that, yes, Ona Verge had been called to replace a broken water pipe at the May Bee Beauty Salon in the Stacked Stories Building.\n\r\n3. Ben A. Brink wanted to watch an air show from the Cloud Tickler Building on Pothole Parkway, which would have afforded a good view, but he had to go instead to Flat Facets Diamonds, a block over on Famed Feet Walkway, to pick up his coat that he had left at an office party.\n\r\n4. In the meantime, Ona finally remembered that the Stacked Stories Building is on Noble Bull Boulevard, and it's the Bent Brick Building that's on Famed Feet Walkway.\n\r\n5. Tim Id's memory was not so clear; he had to go collect the money for the air show tickets from the owner of the Sole Shoe Repair; and he couldn't remember whether it is the Bent Brick Building or the Vertical Towers Building, but he knew that it is on New Avenue.", "hint": "No hint available.", "answer": "Sal Vaged -- ring -- Big Piggy Bank -- Cloud Tickler Bldg. -- Pothole Parkway\n\r\nTim Id -- money -- Sole Shoe Repair-- Vertical Towers Bldg. -- New Avenue\n\r\nBen A. Brink -- coat -- Flat Facets Diamonds -- Bent Brick Bldg. -- Famed Feet Walkway\n\r\nOna Verge -- water pipe -- May Bee Beauty Salon -- Stacked Stories Bldg. -- Noble Bull Blvd.\n\r\nAtta Edge -- lunch -- Genuine Hardware -- Lofty Lights Bldg. -- Stoned Street", "category": "Logic-Grid", "date": "05/26/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a spring day in Choresville, five acquaintances, all relatively new in town, had specific objectives in mind concerning particular objects. Temporarily useful knowledge of these errands and chores in various parts of town may be acquired by carefully following the following carefully-formed clues.\n\r\nPEOPLE: men: Sal Vaged, Tim Id, Ben A. Brink\r\n women: Ona Verge, Atta Edge\r\nOBJECTS: money, lunch, coat, water pipe, ring\r\nBUSINESSES: Big Piggy Bank, May Bee Beauty Salon, Flat Facets Diamonds, Genuine Hardware, Sole Shoe Repair\r\nBUILDINGS: Bent Brick, Vertical Towers, Stacked Stories, Cloud Tickler, Lofty Lights\r\nSTREETS: Pothole Parkway, Famed Feet Walkway, Stoned Street, New Avenue, Noble Bull Boulevard\n\r\nCLUES:\r\n1. As he was walking down Stoned Street, on his way around the corner to Big Piggy Bank to secure his newly-purchased engagement ring into his safety-deposit box, Sal Vaged met Atta Edge just coming out of Genuine Hardware, where she had delivered a box lunch to her husband.\n\r\n2. Sal asked Atta if she had seen his fiancee, and she said that, yes, Ona Verge had been called to replace a broken water pipe at the May Bee Beauty Salon in the Stacked Stories Building.\n\r\n3. Ben A. Brink wanted to watch an air show from the Cloud Tickler Building on Pothole Parkway, which would have afforded a good view, but he had to go instead to Flat Facets Diamonds, a block over on Famed Feet Walkway, to pick up his coat that he had left at an office party.\n\r\n4. In the meantime, Ona finally remembered that the Stacked Stories Building is on Noble Bull Boulevard, and it's the Bent Brick Building that's on Famed Feet Walkway.\n\r\n5. Tim Id's memory was not so clear; he had to go collect the money for the air show tickets from the owner of the Sole Shoe Repair; and he couldn't remember whether it is the Bent Brick Building or the Vertical Towers Building, but he knew that it is on New Avenue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSal Vaged -- ring -- Big Piggy Bank -- Cloud Tickler Bldg. -- Pothole Parkway\n\r\nTim Id -- money -- Sole Shoe Repair-- Vertical Towers Bldg. -- New Avenue\n\r\nBen A. Brink -- coat -- Flat Facets Diamonds -- Bent Brick Bldg. -- Famed Feet Walkway\n\r\nOna Verge -- water pipe -- May Bee Beauty Salon -- Stacked Stories Bldg. -- Noble Bull Blvd.\n\r\nAtta Edge -- lunch -- Genuine Hardware -- Lofty Lights Bldg. -- Stoned Street\n<|im_start|>answer\nSal Vaged -- ring -- Big Piggy Bank -- Cloud Tickler Bldg. -- Pothole Parkway\n\r\nTim Id -- money -- Sole Shoe Repair-- Vertical Towers Bldg. -- New Avenue\n\r\nBen A. Brink -- coat -- Flat Facets Diamonds -- Bent Brick Bldg. -- Famed Feet Walkway\n\r\nOna Verge -- water pipe -- May Bee Beauty Salon -- Stacked Stories Bldg. -- Noble Bull Blvd.\n\r\nAtta Edge -- lunch -- Genuine Hardware -- Lofty Lights Bldg. -- Stoned Street\n<|im_end|>" }, { "id": "#3365", "title": "Smart Suitor", "fun": 2.55, "difficulty": 1.35, "author": "Drunky", "desc": "A wise king devised a contest to see who would receive the princess' hand in marriage. The princess was put in a 50x50 foot carpeted room. Each of her four suitors was put in one corner of the room with a small box to stand on. The first one to touch the princess' hand would be the winner and become the new king. The rules of the test were that the contestants could not walk over the carpet, cross the carpet, or hang from anything; nor could they use anything but their body and wits. One suitor figured out a way and married the princess and became the new king.\n\r\nHow did he figure it out?", "hint": "No hint available.", "answer": "He asked the princess, \"Would you please come over here and touch my hand?\"", "category": "Logic", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA wise king devised a contest to see who would receive the princess' hand in marriage. The princess was put in a 50x50 foot carpeted room. Each of her four suitors was put in one corner of the room with a small box to stand on. The first one to touch the princess' hand would be the winner and become the new king. The rules of the test were that the contestants could not walk over the carpet, cross the carpet, or hang from anything; nor could they use anything but their body and wits. One suitor figured out a way and married the princess and became the new king.\n\r\nHow did he figure it out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe asked the princess, \"Would you please come over here and touch my hand?\"\n<|im_start|>answer\nHe asked the princess, \"Would you please come over here and touch my hand?\"\n<|im_end|>" }, { "id": "#28244", "title": "What's \"Purrfect\"?", "fun": 2.54, "difficulty": 2.16, "author": "Draw", "desc": "\"I'm 'purrfect'\", purred Six, digging her claws into the top of the fence. \"They call me Six because 6 is a 'purrfectly' perfect number.\"\n\r\n\"What's so perfect about it?\" meowed the long-hair from the next yard.\n\r\n\"There's something special about 6 that makes it just perfect. Only a good thinker can figure it out!\"\n\r\nSix is right. 6 is called a perfect number. Figure out why. Then find the next greater perfect number!", "hint": "Think about the factors of 6. See what happens when you add or multiply all of them (except for 6 itself) together.", "answer": "A perfect number is equal to the sum of all its whole number factors, except itself. So, 6 is a perfect number because the sum of its whole number factors, except itself, is 6 (1 + 2 + 3 = 6). The next greater perfect number is 28 because the sum of its whole number factors, except itself, 1, 2, 4, 7, and 14 add up to 28.", "category": "Math", "date": "01/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"I'm 'purrfect'\", purred Six, digging her claws into the top of the fence. \"They call me Six because 6 is a 'purrfectly' perfect number.\"\n\r\n\"What's so perfect about it?\" meowed the long-hair from the next yard.\n\r\n\"There's something special about 6 that makes it just perfect. Only a good thinker can figure it out!\"\n\r\nSix is right. 6 is called a perfect number. Figure out why. Then find the next greater perfect number!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA perfect number is equal to the sum of all its whole number factors, except itself. So, 6 is a perfect number because the sum of its whole number factors, except itself, is 6 (1 + 2 + 3 = 6). The next greater perfect number is 28 because the sum of its whole number factors, except itself, 1, 2, 4, 7, and 14 add up to 28.\n<|im_start|>answer\nA perfect number is equal to the sum of all its whole number factors, except itself. So, 6 is a perfect number because the sum of its whole number factors, except itself, is 6 (1 + 2 + 3 = 6). The next greater perfect number is 28 because the sum of its whole number factors, except itself, 1, 2, 4, 7, and 14 add up to 28.\n<|im_end|>" }, { "id": "#26460", "title": "Will He Make It?", "fun": 2.54, "difficulty": 1.82, "author": "Yoyobug02", "desc": "Gino's mom has told him he needs to take a bucket of water over to their neighbor since she is experiencing problems with her water supply. He doesn't want to waste much time since he has a soccer game to play later in the afternoon. From past experience he knows if he uses the small hose it takes 45 minutes to fill the bucket with water. He also knows that the larger hose can do the same in 30 minutes. If he uses both hoses, how long will it take him to fill the bucket?", "hint": "No hint available.", "answer": "The small hose can fill 1/45 of the bucket every minute. The larger hose can fill 1/30 of the bucket every minute. To add the two speeds, we need to first find a common denominator.\n\r\n1/45 = 2/90 and 1/30 = 3/90\r\nAdding the two speeds:\r\n2/90 + 3/90 = 5/90 = 1/18\r\nSince both hoses together can fill 1/18 of the bucket every minute, it will take 18 minutes. By doing this Gino will save at a minimum 12 minutes. This will get him to his soccer game just in time.", "category": "Math", "date": "10/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGino's mom has told him he needs to take a bucket of water over to their neighbor since she is experiencing problems with her water supply. He doesn't want to waste much time since he has a soccer game to play later in the afternoon. From past experience he knows if he uses the small hose it takes 45 minutes to fill the bucket with water. He also knows that the larger hose can do the same in 30 minutes. If he uses both hoses, how long will it take him to fill the bucket?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe small hose can fill 1/45 of the bucket every minute. The larger hose can fill 1/30 of the bucket every minute. To add the two speeds, we need to first find a common denominator.\n\r\n1/45 = 2/90 and 1/30 = 3/90\r\nAdding the two speeds:\r\n2/90 + 3/90 = 5/90 = 1/18\r\nSince both hoses together can fill 1/18 of the bucket every minute, it will take 18 minutes. By doing this Gino will save at a minimum 12 minutes. This will get him to his soccer game just in time.\n<|im_start|>answer\nThe small hose can fill 1/45 of the bucket every minute. The larger hose can fill 1/30 of the bucket every minute. To add the two speeds, we need to first find a common denominator.\n\r\n1/45 = 2/90 and 1/30 = 3/90\r\nAdding the two speeds:\r\n2/90 + 3/90 = 5/90 = 1/18\r\nSince both hoses together can fill 1/18 of the bucket every minute, it will take 18 minutes. By doing this Gino will save at a minimum 12 minutes. This will get him to his soccer game just in time.\n<|im_end|>" }, { "id": "#28896", "title": "Opposites 13", "fun": 2.54, "difficulty": 2.11, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n; stands for N, O, L, U, or T\r\n( stands for K, B, M, E, or Y\r\n3 stands for H, E, P, C, or W\r\n* stands for F, A, J, E, or R\n\n\r\nThe four letter code word, 3;*(, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Work and Play.", "category": "Logic", "date": "03/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n; stands for N, O, L, U, or T\r\n( stands for K, B, M, E, or Y\r\n3 stands for H, E, P, C, or W\r\n* stands for F, A, J, E, or R\n\n\r\nThe four letter code word, 3;*(, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWork and Play.\n<|im_start|>answer\nWork and Play.\n<|im_end|>" }, { "id": "#10729", "title": "You are the Greatest", "fun": 2.54, "difficulty": 1.45, "author": "jimbo", "desc": "On a blank piece of paper, draw a large rectangle and inside the rectangle write these three statements [A] [B] and [C] exactly as they appear.\n\r\nA: In this box are 3 statements\r\nB: Only 1 of these statements is true.\r\nC: I am the greatest.\n\r\nNow your task is to find out which if any of these three statements are true!", "hint": "No hint available.", "answer": "Since there are three statements it is possible that none, 1 ,2 or all 3 are true. \r\nSince [A] is clearly true it cannot be none.\r\n[B] cannot be true because then [B] would be the only true statement and we already know [A] is true.\r\nThus it cannot be only 1 that is true.\n\r\nIt clearly is not all 3 since we just found [B] is false.\r\nThat only leaves 2 true statements, namely [A] and [C].\n\r\nCongratulations, you have just proven that you are the greatest!", "category": "Logic", "date": "02/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a blank piece of paper, draw a large rectangle and inside the rectangle write these three statements [A] [B] and [C] exactly as they appear.\n\r\nA: In this box are 3 statements\r\nB: Only 1 of these statements is true.\r\nC: I am the greatest.\n\r\nNow your task is to find out which if any of these three statements are true!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince there are three statements it is possible that none, 1 ,2 or all 3 are true. \r\nSince [A] is clearly true it cannot be none.\r\n[B] cannot be true because then [B] would be the only true statement and we already know [A] is true.\r\nThus it cannot be only 1 that is true.\n\r\nIt clearly is not all 3 since we just found [B] is false.\r\nThat only leaves 2 true statements, namely [A] and [C].\n\r\nCongratulations, you have just proven that you are the greatest!\n<|im_start|>answer\nSince there are three statements it is possible that none, 1 ,2 or all 3 are true. \r\nSince [A] is clearly true it cannot be none.\r\n[B] cannot be true because then [B] would be the only true statement and we already know [A] is true.\r\nThus it cannot be only 1 that is true.\n\r\nIt clearly is not all 3 since we just found [B] is false.\r\nThat only leaves 2 true statements, namely [A] and [C].\n\r\nCongratulations, you have just proven that you are the greatest!\n<|im_end|>" }, { "id": "#17119", "title": "The Racehorse", "fun": 2.54, "difficulty": 1.86, "author": "horse_luver", "desc": "There is a racehorse that has won so many prestigious races, many fans come to admire him each day. One day, the owners of the horse were interviewed by a newscaster. The interviewer asked how many people were there today to admire the horse. The owner's reply was as follows:\n\r\n\"Twelve times the amount of yesterday's. Yesterday there was twelve times the amount of the day before. The day before, 155,000 people less came, than how many came during these last two days.\"\n\r\nThe quick thinking interviewer promptly replied with the number of viewers who attended today. Can you do the same?", "hint": "No hint available.", "answer": "144,000 people came today, 12,000 the day before, and 1,000 two days ago.", "category": "Math", "date": "03/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a racehorse that has won so many prestigious races, many fans come to admire him each day. One day, the owners of the horse were interviewed by a newscaster. The interviewer asked how many people were there today to admire the horse. The owner's reply was as follows:\n\r\n\"Twelve times the amount of yesterday's. Yesterday there was twelve times the amount of the day before. The day before, 155,000 people less came, than how many came during these last two days.\"\n\r\nThe quick thinking interviewer promptly replied with the number of viewers who attended today. Can you do the same?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n144,000 people came today, 12,000 the day before, and 1,000 two days ago.\n<|im_start|>answer\n144,000 people came today, 12,000 the day before, and 1,000 two days ago.\n<|im_end|>" }, { "id": "#13476", "title": "Snail Racing Contest", "fun": 2.54, "difficulty": 1.82, "author": "braingle44", "desc": "After a snail racing contest, the four contestants were congratulating each other. Only one snail wore the same number as the position it finished in. Alfred's snail wasn't painted yellow or blue, and the snail who wore 3, which was painted red, beat the snail who came in third. Arthur's snail beat Anne's snail, whereas Alice's snail beat the snail who wore 1. The snail painted green, Alice's, came second and the snail painted blue wore number 4. Anne's snail wore number 1. \r\nCan you work out whose snail finished where, its number and the colour it was painted?", "hint": "No hint available.", "answer": "First: Alfred wore 3 and was red.\r\nSecond: Alice wore 2 and was green.\r\nThird: Arthur wore 4 and was blue.\r\nFourth: Anne wore 1 and was yellow.", "category": "Logic", "date": "06/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter a snail racing contest, the four contestants were congratulating each other. Only one snail wore the same number as the position it finished in. Alfred's snail wasn't painted yellow or blue, and the snail who wore 3, which was painted red, beat the snail who came in third. Arthur's snail beat Anne's snail, whereas Alice's snail beat the snail who wore 1. The snail painted green, Alice's, came second and the snail painted blue wore number 4. Anne's snail wore number 1. \r\nCan you work out whose snail finished where, its number and the colour it was painted?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst: Alfred wore 3 and was red.\r\nSecond: Alice wore 2 and was green.\r\nThird: Arthur wore 4 and was blue.\r\nFourth: Anne wore 1 and was yellow.\n<|im_start|>answer\nFirst: Alfred wore 3 and was red.\r\nSecond: Alice wore 2 and was green.\r\nThird: Arthur wore 4 and was blue.\r\nFourth: Anne wore 1 and was yellow.\n<|im_end|>" }, { "id": "#29941", "title": "Three Statements II", "fun": 2.54, "difficulty": 1.26, "author": "lips", "desc": "Which of these three statements are true?\n\r\n1. Lisa is faster than Jane, and Nora is slower than Lisa. It is impossible to tell whether Nora is faster than Jane based on these facts alone.\n\r\n2. Jack owes $64 to John. Jack has only $28 but Bill gives him another $28. Therefore Jack can repay John in full.\n\r\n3. A rancher is building an open-ended fence by stringing wire between posts 20 feet apart. If the fence is 100 feet long the rancher should use 5 posts.", "hint": "No hint available.", "answer": "Statement 1 is true, and statements 2 and 3 are false.\n\r\nIn statement 1, we only know that Lisa is the fastest of the three, and we know nothing else.\n\r\nIn statement 2, 28+28=56<64.\n\r\nIn statement 3, since the fence is open-ended, you need 6 posts.", "category": "Logic", "date": "04/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these three statements are true?\n\r\n1. Lisa is faster than Jane, and Nora is slower than Lisa. It is impossible to tell whether Nora is faster than Jane based on these facts alone.\n\r\n2. Jack owes $64 to John. Jack has only $28 but Bill gives him another $28. Therefore Jack can repay John in full.\n\r\n3. A rancher is building an open-ended fence by stringing wire between posts 20 feet apart. If the fence is 100 feet long the rancher should use 5 posts.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement 1 is true, and statements 2 and 3 are false.\n\r\nIn statement 1, we only know that Lisa is the fastest of the three, and we know nothing else.\n\r\nIn statement 2, 28+28=56<64.\n\r\nIn statement 3, since the fence is open-ended, you need 6 posts.\n<|im_start|>answer\nStatement 1 is true, and statements 2 and 3 are false.\n\r\nIn statement 1, we only know that Lisa is the fastest of the three, and we know nothing else.\n\r\nIn statement 2, 28+28=56<64.\n\r\nIn statement 3, since the fence is open-ended, you need 6 posts.\n<|im_end|>" }, { "id": "#26620", "title": "Chess Tournament II", "fun": 2.54, "difficulty": 2.47, "author": "shenqiang", "desc": "The first chess tournament ended. Bab, Beb, Bib, Bob and Bub became good friends, and returned to their houses. \n\r\nThey told their wives about the tournament. Their wives were also chess players, and they decided to hold another tournament.\n\r\nThis time, each of the 10 players was going to play against each other player once, with an exception that no games were played between the couples. So a total of 40 games would be played.\n\r\nAfter some days passed, they decided to have a get-together. Bub asked the other people how many matches until then they had played.\n\r\nSomething fun was that Bub heard 9 different answers.\n\r\nHow many matches until then had Mrs. Bub played?", "hint": "If you can't figure it out, draw a diagram.", "answer": "Each player could play at most 8 matches, so the answers Bub heard was 0, 1, 2, 3, 4, 5, 6, 7, 8 in some order.\n\r\nAssume without loss of generality that it was Bab that had played 8 matches. Then all players except Mrs. Bab must have played against Bab, and it must have been Mrs. Bab who had played no matches.\n\r\nThen, assume without loss of generality that Beb had played 7 matches, and then all players except Mrs. Bab and Mrs. Beb must have played against Beb, and it must have been Mrs. Beb who had played 1 match.\n\r\nRepeat this and we know that Mrs. Bub had played 4 matches.", "category": "Logic", "date": "10/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe first chess tournament ended. Bab, Beb, Bib, Bob and Bub became good friends, and returned to their houses. \n\r\nThey told their wives about the tournament. Their wives were also chess players, and they decided to hold another tournament.\n\r\nThis time, each of the 10 players was going to play against each other player once, with an exception that no games were played between the couples. So a total of 40 games would be played.\n\r\nAfter some days passed, they decided to have a get-together. Bub asked the other people how many matches until then they had played.\n\r\nSomething fun was that Bub heard 9 different answers.\n\r\nHow many matches until then had Mrs. Bub played?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach player could play at most 8 matches, so the answers Bub heard was 0, 1, 2, 3, 4, 5, 6, 7, 8 in some order.\n\r\nAssume without loss of generality that it was Bab that had played 8 matches. Then all players except Mrs. Bab must have played against Bab, and it must have been Mrs. Bab who had played no matches.\n\r\nThen, assume without loss of generality that Beb had played 7 matches, and then all players except Mrs. Bab and Mrs. Beb must have played against Beb, and it must have been Mrs. Beb who had played 1 match.\n\r\nRepeat this and we know that Mrs. Bub had played 4 matches.\n<|im_start|>answer\nEach player could play at most 8 matches, so the answers Bub heard was 0, 1, 2, 3, 4, 5, 6, 7, 8 in some order.\n\r\nAssume without loss of generality that it was Bab that had played 8 matches. Then all players except Mrs. Bab must have played against Bab, and it must have been Mrs. Bab who had played no matches.\n\r\nThen, assume without loss of generality that Beb had played 7 matches, and then all players except Mrs. Bab and Mrs. Beb must have played against Beb, and it must have been Mrs. Beb who had played 1 match.\n\r\nRepeat this and we know that Mrs. Bub had played 4 matches.\n<|im_end|>" }, { "id": "#28052", "title": "Sweet Shop Treats", "fun": 2.54, "difficulty": 1.71, "author": "Draw", "desc": "Annabel, Cara, Graham, Jordy, and Maddy went to Sally's Sweet Shop for a treat. \n\r\nMenu:\n\r\nIce-cream Sundae $2.65 \r\nDouble-scoop Cone $2.10 \r\nChocolate Fudge Cake $2.40 \r\nJuice Float $1.00 \r\nChocolate Candy Animal $1.25 \r\nIce-cream Soda $2.25 \n\r\nEach person got something different and each gave the cashier $3.00. Every item on the menu was purchased by someone in the group.\n\r\nAnnabel got back 3 quarters, 1 dime, and 1 nickel in change. \r\nGraham got back the least amount of change. \r\nCara got back 40¢ more than Graham. \r\nJordy is the only one who bought 2 items. He still got back 3 quarters in change. \r\nWhich sweet treats did each person buy?\n\r\n(Note: a quarter is worth $0.25, a dime is worth $0.10, and a nickel is worth $0.05.)", "hint": "Find the correct change from $3.00 for each of the items. Then make a chart to eliminate the impossibilities.", "answer": "Annabel bought the double-scoop cone.\r\nCara bought the ice-cream soda.\r\nGraham bought the ice-cream sundae.\r\nJordy bought the juice float and chocolate candy animal.\r\nMaddy bought the chocolate fudge cake.", "category": "Math", "date": "01/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnnabel, Cara, Graham, Jordy, and Maddy went to Sally's Sweet Shop for a treat. \n\r\nMenu:\n\r\nIce-cream Sundae $2.65 \r\nDouble-scoop Cone $2.10 \r\nChocolate Fudge Cake $2.40 \r\nJuice Float $1.00 \r\nChocolate Candy Animal $1.25 \r\nIce-cream Soda $2.25 \n\r\nEach person got something different and each gave the cashier $3.00. Every item on the menu was purchased by someone in the group.\n\r\nAnnabel got back 3 quarters, 1 dime, and 1 nickel in change. \r\nGraham got back the least amount of change. \r\nCara got back 40¢ more than Graham. \r\nJordy is the only one who bought 2 items. He still got back 3 quarters in change. \r\nWhich sweet treats did each person buy?\n\r\n(Note: a quarter is worth $0.25, a dime is worth $0.10, and a nickel is worth $0.05.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnnabel bought the double-scoop cone.\r\nCara bought the ice-cream soda.\r\nGraham bought the ice-cream sundae.\r\nJordy bought the juice float and chocolate candy animal.\r\nMaddy bought the chocolate fudge cake.\n<|im_start|>answer\nAnnabel bought the double-scoop cone.\r\nCara bought the ice-cream soda.\r\nGraham bought the ice-cream sundae.\r\nJordy bought the juice float and chocolate candy animal.\r\nMaddy bought the chocolate fudge cake.\n<|im_end|>" }, { "id": "#29770", "title": "101", "fun": 2.54, "difficulty": 2.44, "author": "Draw", "desc": "Add plus and minus signs among the digits 1 2 3 4 5 6 7 8 9 to make the total 101. For example, 1+2+3+45+67-8-9=101. There are ten ways to do it.", "hint": "Try all possible combinations of two-digit numbers and the three-digit number 123. Since there are only plus and minus signs, be aware of parity.", "answer": "(1)1+2+3+45+67-8-9=101\r\n(2)1+2+34+56+7-8+9=101\r\n(3)1+2-3+4-5+6+7+89=101\r\n(4)1+23+4+5+67-8+9=101\r\n(5)1+23-4+5-6-7+89=101\r\n(6)1-2+3+4+5-6+7+89=101\r\n(7)1-2+34+5-6+78-9=101\r\n(8)12+34+5+67-8-9=101\r\n(9)12-3+4-5+6+78+9=101\r\n(10)123+4+56+7-89=101", "category": "Math", "date": "04/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdd plus and minus signs among the digits 1 2 3 4 5 6 7 8 9 to make the total 101. For example, 1+2+3+45+67-8-9=101. There are ten ways to do it.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(1)1+2+3+45+67-8-9=101\r\n(2)1+2+34+56+7-8+9=101\r\n(3)1+2-3+4-5+6+7+89=101\r\n(4)1+23+4+5+67-8+9=101\r\n(5)1+23-4+5-6-7+89=101\r\n(6)1-2+3+4+5-6+7+89=101\r\n(7)1-2+34+5-6+78-9=101\r\n(8)12+34+5+67-8-9=101\r\n(9)12-3+4-5+6+78+9=101\r\n(10)123+4+56+7-89=101\n<|im_start|>answer\n(1)1+2+3+45+67-8-9=101\r\n(2)1+2+34+56+7-8+9=101\r\n(3)1+2-3+4-5+6+7+89=101\r\n(4)1+23+4+5+67-8+9=101\r\n(5)1+23-4+5-6-7+89=101\r\n(6)1-2+3+4+5-6+7+89=101\r\n(7)1-2+34+5-6+78-9=101\r\n(8)12+34+5+67-8-9=101\r\n(9)12-3+4-5+6+78+9=101\r\n(10)123+4+56+7-89=101\n<|im_end|>" }, { "id": "#7684", "title": "Unloading the Dice", "fun": 2.54, "difficulty": 2.25, "author": "dewtell", "desc": "The Sharks and the Jets have decided to settle their differences with a game of Snakes and Ladders, in which movement is determined by the roll of a single die. The problem is, neither group trusts the other not to gain an advantage by swapping in a loaded die at a crucial moment. Officer Krupke, who wants to keep the peace, comes up with a novel proposal. Instead of rolling one die, each side will roll a die of its own choosing each time a die roll is required. Then the two die rolls will be combined by a simple formula that produces a number from one to six. This formula has the property that if either one of the two dice is fair, the results will be evenly distributed among the six numbers. Thus either side can guarantee a fair result just by making sure that its own die is fair. What formula might Officer Krupke have suggested?", "hint": "No hint available.", "answer": "One simple formula is: add the two dice together, and subtract 6 if the total is greater than 6. With this formula, any number the other side rolls establishes a simple mapping from the faces of your own die to the final total. For example, if the other side rolls a three, then your 1 maps to 4, 2 maps to 5, 3 maps to 6, 4 maps to 1, 5 maps to 2, and 6 maps to 3. As long as your own die is fair, the six numbers will all be equally\r\nlikely to be rolled, no matter how badly biased the other side's die may be.", "category": "Logic", "date": "09/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Sharks and the Jets have decided to settle their differences with a game of Snakes and Ladders, in which movement is determined by the roll of a single die. The problem is, neither group trusts the other not to gain an advantage by swapping in a loaded die at a crucial moment. Officer Krupke, who wants to keep the peace, comes up with a novel proposal. Instead of rolling one die, each side will roll a die of its own choosing each time a die roll is required. Then the two die rolls will be combined by a simple formula that produces a number from one to six. This formula has the property that if either one of the two dice is fair, the results will be evenly distributed among the six numbers. Thus either side can guarantee a fair result just by making sure that its own die is fair. What formula might Officer Krupke have suggested?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne simple formula is: add the two dice together, and subtract 6 if the total is greater than 6. With this formula, any number the other side rolls establishes a simple mapping from the faces of your own die to the final total. For example, if the other side rolls a three, then your 1 maps to 4, 2 maps to 5, 3 maps to 6, 4 maps to 1, 5 maps to 2, and 6 maps to 3. As long as your own die is fair, the six numbers will all be equally\r\nlikely to be rolled, no matter how badly biased the other side's die may be.\n<|im_start|>answer\nOne simple formula is: add the two dice together, and subtract 6 if the total is greater than 6. With this formula, any number the other side rolls establishes a simple mapping from the faces of your own die to the final total. For example, if the other side rolls a three, then your 1 maps to 4, 2 maps to 5, 3 maps to 6, 4 maps to 1, 5 maps to 2, and 6 maps to 3. As long as your own die is fair, the six numbers will all be equally\r\nlikely to be rolled, no matter how badly biased the other side's die may be.\n<|im_end|>" }, { "id": "#41266", "title": "Car Wash Cycle", "fun": 2.54, "difficulty": 1.36, "author": "rockstar1234567", "desc": "Three cars go to the car wash. For each car to complete the cycle, they must go through all three stages in the right order, and each stage takes 1 minute to complete:\n\r\n1.Pre-soak\n\r\n2.Rinse/polish\n\r\n3.Dry\n\r\nHow long does it take for all three of the cars to complete the cycles?", "hint": "Continuously going.", "answer": "5 minutes. Here's why:\n\r\n1st minute:\n\r\nPre-soak: Car 1\r\nRinse/polish: empty\r\nDry: empty\n\n\r\n2nd minute:\n\r\nPre-soak: Car 2\r\nRinse/polish: Car 1\r\nDry: empty\n\n\r\n3rd minute:\n\r\nPre-soak: Car 3\r\nRinse/polish: Car 2\r\nDry: Car 1\n\n\r\n4th minute:\n\r\nPre-soak: empty\r\nRinse/polish: Car 3\r\nDry: Car 2\n\n\r\n5th minute:\n\r\nPre-soak: empty\r\nRinse/polish: empty\r\nDry: Car 3\n\n\r\n6th minute:\n\r\nPre-soak: empty\r\nRinse/polish: empty\r\nDry: empty", "category": "Logic", "date": "03/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree cars go to the car wash. For each car to complete the cycle, they must go through all three stages in the right order, and each stage takes 1 minute to complete:\n\r\n1.Pre-soak\n\r\n2.Rinse/polish\n\r\n3.Dry\n\r\nHow long does it take for all three of the cars to complete the cycles?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 minutes. Here's why:\n\r\n1st minute:\n\r\nPre-soak: Car 1\r\nRinse/polish: empty\r\nDry: empty\n\n\r\n2nd minute:\n\r\nPre-soak: Car 2\r\nRinse/polish: Car 1\r\nDry: empty\n\n\r\n3rd minute:\n\r\nPre-soak: Car 3\r\nRinse/polish: Car 2\r\nDry: Car 1\n\n\r\n4th minute:\n\r\nPre-soak: empty\r\nRinse/polish: Car 3\r\nDry: Car 2\n\n\r\n5th minute:\n\r\nPre-soak: empty\r\nRinse/polish: empty\r\nDry: Car 3\n\n\r\n6th minute:\n\r\nPre-soak: empty\r\nRinse/polish: empty\r\nDry: empty\n<|im_start|>answer\n5 minutes. Here's why:\n\r\n1st minute:\n\r\nPre-soak: Car 1\r\nRinse/polish: empty\r\nDry: empty\n\n\r\n2nd minute:\n\r\nPre-soak: Car 2\r\nRinse/polish: Car 1\r\nDry: empty\n\n\r\n3rd minute:\n\r\nPre-soak: Car 3\r\nRinse/polish: Car 2\r\nDry: Car 1\n\n\r\n4th minute:\n\r\nPre-soak: empty\r\nRinse/polish: Car 3\r\nDry: Car 2\n\n\r\n5th minute:\n\r\nPre-soak: empty\r\nRinse/polish: empty\r\nDry: Car 3\n\n\r\n6th minute:\n\r\nPre-soak: empty\r\nRinse/polish: empty\r\nDry: empty\n<|im_end|>" }, { "id": "#41368", "title": "Peanuts For Peter", "fun": 2.54, "difficulty": 1.72, "author": "Carlos16", "desc": "Three children, Peter, Jane and Eric, shared a bag of peanuts. There were 770 peanuts in the bag. For every 4 peanuts Peter took, Jane took 3, and for every 6 peanuts Peter took, Eric took 7. How many peanuts did Peter get?", "hint": "No hint available.", "answer": "For every 12 peanuts Peter took, Jane had 9 and Eric 14. This is a total of 35 in one round. 770 divided by 35 is 22, so they had 22 rounds. 12 times 22 are 264.\n\r\nAnswer: 264", "category": "Math", "date": "04/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree children, Peter, Jane and Eric, shared a bag of peanuts. There were 770 peanuts in the bag. For every 4 peanuts Peter took, Jane took 3, and for every 6 peanuts Peter took, Eric took 7. How many peanuts did Peter get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor every 12 peanuts Peter took, Jane had 9 and Eric 14. This is a total of 35 in one round. 770 divided by 35 is 22, so they had 22 rounds. 12 times 22 are 264.\n\r\nAnswer: 264\n<|im_start|>answer\nFor every 12 peanuts Peter took, Jane had 9 and Eric 14. This is a total of 35 in one round. 770 divided by 35 is 22, so they had 22 rounds. 12 times 22 are 264.\n\r\nAnswer: 264\n<|im_end|>" }, { "id": "#38893", "title": "What's the Number?", "fun": 2.54, "difficulty": 1.36, "author": "grilledcheese", "desc": "Find the four digit number in which the first digit is one fourth of the last digit, the second digit is 6 times the first digit, and the third digit is the second digit plus 3.", "hint": "No hint available.", "answer": "1694", "category": "Math", "date": "10/23/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the four digit number in which the first digit is one fourth of the last digit, the second digit is 6 times the first digit, and the third digit is the second digit plus 3.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1694\n<|im_start|>answer\n1694\n<|im_end|>" }, { "id": "#9254", "title": "Smith - Jones - Robinson", "fun": 2.54, "difficulty": 2.08, "author": "bluetwo", "desc": "On a train, Smith, Robinson, and Jones are the fireman, brakeman, and the engineer, but NOT respectively. Also aboard the train are three businessmen who have the same names: a Mr. Smith, a Mr. Robinson, and a Mr. Jones. Using the clues below, can you determine the identity of the Engineer?\n\r\n1. Mr. Robinson lives in Detroit. \r\n2. The brakeman lives exactly halfway between Chicago and Detroit \r\n3. Mr. Jones earns exactly $20,000 per year. \r\n4. The brakeman's nearest neighbor, one of the passengers, earns exactly three times as much as the brakeman. \r\n5. Smith beats the fireman in billiards. \r\n6. The passenger whose name is the same as the brakeman's lives in Chicago.", "hint": "No hint available.", "answer": "1. Mr. Robinson lives in Detroit and the brakeman's nearest neighbor earns exactly 3 times as much as the brakeman. Therefore, neither Mr. Robinson nor Mr. Jones are the brakeman's nearest neighbor, so it must be Mr. Smith.\r\n2. Smith beats the fireman at billiards and the passenger whose name is the same as the brakeman's lives in Chicago. Mr. Robinson lives in Detroit and Mr. Smith lives between Chicago and Detroit. Therefore, it must be Mr. Jones who lives in Chicago and Jones is the brakeman.\r\n3. Smith is not the brakeman and he is not the fireman. He must be the engineer.", "category": "Logic", "date": "12/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a train, Smith, Robinson, and Jones are the fireman, brakeman, and the engineer, but NOT respectively. Also aboard the train are three businessmen who have the same names: a Mr. Smith, a Mr. Robinson, and a Mr. Jones. Using the clues below, can you determine the identity of the Engineer?\n\r\n1. Mr. Robinson lives in Detroit. \r\n2. The brakeman lives exactly halfway between Chicago and Detroit \r\n3. Mr. Jones earns exactly $20,000 per year. \r\n4. The brakeman's nearest neighbor, one of the passengers, earns exactly three times as much as the brakeman. \r\n5. Smith beats the fireman in billiards. \r\n6. The passenger whose name is the same as the brakeman's lives in Chicago.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Mr. Robinson lives in Detroit and the brakeman's nearest neighbor earns exactly 3 times as much as the brakeman. Therefore, neither Mr. Robinson nor Mr. Jones are the brakeman's nearest neighbor, so it must be Mr. Smith.\r\n2. Smith beats the fireman at billiards and the passenger whose name is the same as the brakeman's lives in Chicago. Mr. Robinson lives in Detroit and Mr. Smith lives between Chicago and Detroit. Therefore, it must be Mr. Jones who lives in Chicago and Jones is the brakeman.\r\n3. Smith is not the brakeman and he is not the fireman. He must be the engineer.\n<|im_start|>answer\n1. Mr. Robinson lives in Detroit and the brakeman's nearest neighbor earns exactly 3 times as much as the brakeman. Therefore, neither Mr. Robinson nor Mr. Jones are the brakeman's nearest neighbor, so it must be Mr. Smith.\r\n2. Smith beats the fireman at billiards and the passenger whose name is the same as the brakeman's lives in Chicago. Mr. Robinson lives in Detroit and Mr. Smith lives between Chicago and Detroit. Therefore, it must be Mr. Jones who lives in Chicago and Jones is the brakeman.\r\n3. Smith is not the brakeman and he is not the fireman. He must be the engineer.\n<|im_end|>" }, { "id": "#43298", "title": "What Did Each Rent?", "fun": 2.54, "difficulty": 1.6300000000000001, "author": "Thinker1995", "desc": "A family was vacationing at a lake. The family members were a sister, a brother, a mom, a dad, and a grandpa. The family each rented something to keep them busy during the trip. However though, everyone forgot what they each rented. Can you help them figure out what they each rented using these clues?\n\r\nThe vehicles were: a green bicycle, a red tandem, a blue motorbike, a red rowboat, and a yellow skateboard.\n\r\n1. Dad wanted to do something by himself.\r\n2. The rowboat can seat either two children, or one adult.\r\n3. Sister rented something red.\r\n4. Brother wanted to have his hands free.\r\n5. Children are not allowed in the water unless an adult is with them. \r\n6. Grandpa is tired, and won't do anything that involves moving his legs.\r\n7. Mom is afraid of the water.\r\n8. Mom and sister were planning to do something together.\r\n9. None of the adults want to ride the blue motorbike.", "hint": "Two people ride the tandem, so there is one vehicle that nobody rented.", "answer": "Green bicycle: dad\r\nRed tandem: mom and sister\r\nRed rowboat: grandpa\r\nYellow skateboard: brother\n\r\nNobody rented the blue motorbike.", "category": "Logic", "date": "10/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA family was vacationing at a lake. The family members were a sister, a brother, a mom, a dad, and a grandpa. The family each rented something to keep them busy during the trip. However though, everyone forgot what they each rented. Can you help them figure out what they each rented using these clues?\n\r\nThe vehicles were: a green bicycle, a red tandem, a blue motorbike, a red rowboat, and a yellow skateboard.\n\r\n1. Dad wanted to do something by himself.\r\n2. The rowboat can seat either two children, or one adult.\r\n3. Sister rented something red.\r\n4. Brother wanted to have his hands free.\r\n5. Children are not allowed in the water unless an adult is with them. \r\n6. Grandpa is tired, and won't do anything that involves moving his legs.\r\n7. Mom is afraid of the water.\r\n8. Mom and sister were planning to do something together.\r\n9. None of the adults want to ride the blue motorbike.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGreen bicycle: dad\r\nRed tandem: mom and sister\r\nRed rowboat: grandpa\r\nYellow skateboard: brother\n\r\nNobody rented the blue motorbike.\n<|im_start|>answer\nGreen bicycle: dad\r\nRed tandem: mom and sister\r\nRed rowboat: grandpa\r\nYellow skateboard: brother\n\r\nNobody rented the blue motorbike.\n<|im_end|>" }, { "id": "#42147", "title": "Roman Matches IV", "fun": 2.54, "difficulty": 1.98, "author": "MarcM1098", "desc": "The following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it twice: the equation can be corrected in two different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote:\r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: L = L + L", "hint": "One solution involves an I, the other involves a C.", "answer": "First solution: LI = L + I or LI = I + L\r\nTake one matchstick from the bottom of either L on the right side of the equation, turn it to form a I, and add it after the L on the left side of the equation.\n\r\nSecond solution: L = C - L\r\nTake the vertical match from the plus sign (changing it to a minus sign), turn it horizontally, and add it to the top of the first L on the right side of the equation, changing it to a C.", "category": "Math", "date": "06/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following equation involving Roman numerals is formed using matchsticks. The given equation is wrong. Can you correct it by moving just one matchstick? See if you can do it twice: the equation can be corrected in two different ways. Each solution must be an equation (i.e., it must contain one equals sign).\n\r\nNote:\r\nI(1) and -(minus) are each formed from one matchstick.\r\nV(5), X(10), L(50), +(plus), and =(equals) are each two matchsticks.\r\nC(100) is three matchsticks.\n\r\nThe incorrect equation is: L = L + L\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst solution: LI = L + I or LI = I + L\r\nTake one matchstick from the bottom of either L on the right side of the equation, turn it to form a I, and add it after the L on the left side of the equation.\n\r\nSecond solution: L = C - L\r\nTake the vertical match from the plus sign (changing it to a minus sign), turn it horizontally, and add it to the top of the first L on the right side of the equation, changing it to a C.\n<|im_start|>answer\nFirst solution: LI = L + I or LI = I + L\r\nTake one matchstick from the bottom of either L on the right side of the equation, turn it to form a I, and add it after the L on the left side of the equation.\n\r\nSecond solution: L = C - L\r\nTake the vertical match from the plus sign (changing it to a minus sign), turn it horizontally, and add it to the top of the first L on the right side of the equation, changing it to a C.\n<|im_end|>" }, { "id": "#40084", "title": "Bed of Bricks", "fun": 2.54, "difficulty": 2.09, "author": "icestar12", "desc": "Five stacks of bricks are piled outside the Winter Street School waiting to be used to create a path. They are in their shipping stacks, which are 9 bricks high, 9 bricks across, and 4 bricks deep. Twelve bricks will cover an area of 16 inches x 24 inches.\n\r\nIf the path is to be 4 feet wide, how long will it be (in feet and inches) if all but 1 dozen bricks are used?", "hint": "No hint available.", "answer": "The path will be 89 feet, 4 inches long. (Remember, .3333 of a foot = 4 inches.)\n\r\nNumber of bricks in stacks = 5 x 9 x 9 x 4 = 1,620 \r\nNumber of bricks used = 1,620 - 12 = 1,608 \r\nArea covered by 12 bricks = 16 x 24 = 384 square inches \r\nArea covered by 1 brick = 384 / 12 = 32 square inches \r\nArea covered by 1,608 bricks = 32 x 1,608 = 51,456 square inches \r\nLength of path covered = (area of path) / (width of path) inches \r\n = 51,456 / 48 inches \r\n = 1,072 inches or 89 1/3 feet", "category": "Math", "date": "01/16/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive stacks of bricks are piled outside the Winter Street School waiting to be used to create a path. They are in their shipping stacks, which are 9 bricks high, 9 bricks across, and 4 bricks deep. Twelve bricks will cover an area of 16 inches x 24 inches.\n\r\nIf the path is to be 4 feet wide, how long will it be (in feet and inches) if all but 1 dozen bricks are used?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe path will be 89 feet, 4 inches long. (Remember, .3333 of a foot = 4 inches.)\n\r\nNumber of bricks in stacks = 5 x 9 x 9 x 4 = 1,620 \r\nNumber of bricks used = 1,620 - 12 = 1,608 \r\nArea covered by 12 bricks = 16 x 24 = 384 square inches \r\nArea covered by 1 brick = 384 / 12 = 32 square inches \r\nArea covered by 1,608 bricks = 32 x 1,608 = 51,456 square inches \r\nLength of path covered = (area of path) / (width of path) inches \r\n = 51,456 / 48 inches \r\n = 1,072 inches or 89 1/3 feet\n<|im_start|>answer\nThe path will be 89 feet, 4 inches long. (Remember, .3333 of a foot = 4 inches.)\n\r\nNumber of bricks in stacks = 5 x 9 x 9 x 4 = 1,620 \r\nNumber of bricks used = 1,620 - 12 = 1,608 \r\nArea covered by 12 bricks = 16 x 24 = 384 square inches \r\nArea covered by 1 brick = 384 / 12 = 32 square inches \r\nArea covered by 1,608 bricks = 32 x 1,608 = 51,456 square inches \r\nLength of path covered = (area of path) / (width of path) inches \r\n = 51,456 / 48 inches \r\n = 1,072 inches or 89 1/3 feet\n<|im_end|>" }, { "id": "#28739", "title": "Candy Sales", "fun": 2.54, "difficulty": 2.66, "author": "paul726", "desc": "Mary Jane, the confectioner with two first names, looked up her fellow candy maker in the phone book. \"Cracker, Jack\" was the listing, and during the ensuing phone conversation they decided to jointly market their products in a single multi-pack. They quickly discovered that the normal rules of economics applied, as when they reduced their price, they were able to sell more of their product, and vice versa.\n\r\nWhen they priced a box of candy at $5.95, they realized a profit of $1.75 per box and sold on average 100 boxes per week.\r\nFor each $0.20 reduction in price, their sales increased by 25 boxes per week.\n\r\nWhat did they finally determine was the optimum price at which to sell their wares to produce the maximum weekly profit?\n\r\n(Assume that changes in price have no effect on the cost of producing or marketing the candy.)", "hint": "Form an equation which calculates profit and reflects the effects of changes in price.", "answer": "This can be solved in a few different ways. Trial and error is one, and perhaps the simplest. Deriving an equation for the profit produces:\n\n\r\nP(Profit) = ($1.75-0.20x)(100+25x)\r\n ........ = -5x²-20x+43.75x+175\r\n ........ = -5x² +23.75x +175\n\r\nHere, the 'x' represents the number of $0.20 reductions in price (and per-box profit), and thereby the number of 25 box sales increases that will be performed.\n\r\nThis produces an inverted parabola when graphed, and the point of maximum profit can be fairly accurately determined by observation. Finally, using basic calculus, the first derivative can be obtained:\n\n\r\nP` = -10x +23.75\n\r\nTo maximize Profit, find the point where the first derivative is equal to zero.\n\r\n 0 = -10x +23.75\r\n10x = 23.75\r\n x = 2.375\n\r\nTherefore, the price should be reduced by 2.375 x $0.20, or $0.47 per box for an optimum price of $5.48 per box.\r\nThis yields sales of approximately 159 boxes per week, at a profit per box of $1.28 for a total weekly profit of $203.52.", "category": "Math", "date": "02/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMary Jane, the confectioner with two first names, looked up her fellow candy maker in the phone book. \"Cracker, Jack\" was the listing, and during the ensuing phone conversation they decided to jointly market their products in a single multi-pack. They quickly discovered that the normal rules of economics applied, as when they reduced their price, they were able to sell more of their product, and vice versa.\n\r\nWhen they priced a box of candy at $5.95, they realized a profit of $1.75 per box and sold on average 100 boxes per week.\r\nFor each $0.20 reduction in price, their sales increased by 25 boxes per week.\n\r\nWhat did they finally determine was the optimum price at which to sell their wares to produce the maximum weekly profit?\n\r\n(Assume that changes in price have no effect on the cost of producing or marketing the candy.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis can be solved in a few different ways. Trial and error is one, and perhaps the simplest. Deriving an equation for the profit produces:\n\n\r\nP(Profit) = ($1.75-0.20x)(100+25x)\r\n ........ = -5x²-20x+43.75x+175\r\n ........ = -5x² +23.75x +175\n\r\nHere, the 'x' represents the number of $0.20 reductions in price (and per-box profit), and thereby the number of 25 box sales increases that will be performed.\n\r\nThis produces an inverted parabola when graphed, and the point of maximum profit can be fairly accurately determined by observation. Finally, using basic calculus, the first derivative can be obtained:\n\n\r\nP` = -10x +23.75\n\r\nTo maximize Profit, find the point where the first derivative is equal to zero.\n\r\n 0 = -10x +23.75\r\n10x = 23.75\r\n x = 2.375\n\r\nTherefore, the price should be reduced by 2.375 x $0.20, or $0.47 per box for an optimum price of $5.48 per box.\r\nThis yields sales of approximately 159 boxes per week, at a profit per box of $1.28 for a total weekly profit of $203.52.\n<|im_start|>answer\nThis can be solved in a few different ways. Trial and error is one, and perhaps the simplest. Deriving an equation for the profit produces:\n\n\r\nP(Profit) = ($1.75-0.20x)(100+25x)\r\n ........ = -5x²-20x+43.75x+175\r\n ........ = -5x² +23.75x +175\n\r\nHere, the 'x' represents the number of $0.20 reductions in price (and per-box profit), and thereby the number of 25 box sales increases that will be performed.\n\r\nThis produces an inverted parabola when graphed, and the point of maximum profit can be fairly accurately determined by observation. Finally, using basic calculus, the first derivative can be obtained:\n\n\r\nP` = -10x +23.75\n\r\nTo maximize Profit, find the point where the first derivative is equal to zero.\n\r\n 0 = -10x +23.75\r\n10x = 23.75\r\n x = 2.375\n\r\nTherefore, the price should be reduced by 2.375 x $0.20, or $0.47 per box for an optimum price of $5.48 per box.\r\nThis yields sales of approximately 159 boxes per week, at a profit per box of $1.28 for a total weekly profit of $203.52.\n<|im_end|>" }, { "id": "#38530", "title": "Brothers and Sisters", "fun": 2.54, "difficulty": 1.52, "author": "----", "desc": "Three men, whose names are Taro, Kenzi and Takasi, each have a sister whose names are Megu, Yuri and Kayo. They say:\n\r\nTaro:\"Megu and I are siblings.\"\r\nMegu:\"Takasi and I are siblings.\"\r\nTakasi:\"Kayo and I are siblings.\"\n\r\nHowever, none of them is telling the truth.\r\nWho is Yuri's brother?", "hint": "Eliminate the impossibilities.", "answer": "Takasi's sister can't be Megu or Kayo, and can be only Yuri.\n\r\nTherefore, Yuri's brother is Takasi.", "category": "Logic", "date": "09/29/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree men, whose names are Taro, Kenzi and Takasi, each have a sister whose names are Megu, Yuri and Kayo. They say:\n\r\nTaro:\"Megu and I are siblings.\"\r\nMegu:\"Takasi and I are siblings.\"\r\nTakasi:\"Kayo and I are siblings.\"\n\r\nHowever, none of them is telling the truth.\r\nWho is Yuri's brother?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTakasi's sister can't be Megu or Kayo, and can be only Yuri.\n\r\nTherefore, Yuri's brother is Takasi.\n<|im_start|>answer\nTakasi's sister can't be Megu or Kayo, and can be only Yuri.\n\r\nTherefore, Yuri's brother is Takasi.\n<|im_end|>" }, { "id": "#23012", "title": "Doggies!!!", "fun": 2.54, "difficulty": 1.87, "author": "bigSWAFF_69_", "desc": "Two friends, Billy and Jimmy, both have dogs. During a Presidents Day parade, they took them with them when they went to see it. They wanted to figure out which dog was the oldest. This is what they came up with. Patches was born 12 months ago. Meatball was 8 months old when Patches was born. Maggie and Max were born in the same litter. Spot was 5 months old when the \"twins\" were born. Zoe is 3 months older than the two litter mates. Meatball is 4 months older than Zoe. How old are the dogs? And what month were they born in? (exclude \"day-by-day\" just go by months)", "hint": "You must need to know what month Presidents Day is in. Patches will have to be the first doggie that you get.", "answer": "Patches- 12 months- February\r\nMeatball- 20 months- June\r\nZoe- 16 months- October\r\nMaggie and Max- 13 months- January\r\nSpot- 18 months- August", "category": "Logic", "date": "05/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo friends, Billy and Jimmy, both have dogs. During a Presidents Day parade, they took them with them when they went to see it. They wanted to figure out which dog was the oldest. This is what they came up with. Patches was born 12 months ago. Meatball was 8 months old when Patches was born. Maggie and Max were born in the same litter. Spot was 5 months old when the \"twins\" were born. Zoe is 3 months older than the two litter mates. Meatball is 4 months older than Zoe. How old are the dogs? And what month were they born in? (exclude \"day-by-day\" just go by months)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPatches- 12 months- February\r\nMeatball- 20 months- June\r\nZoe- 16 months- October\r\nMaggie and Max- 13 months- January\r\nSpot- 18 months- August\n<|im_start|>answer\nPatches- 12 months- February\r\nMeatball- 20 months- June\r\nZoe- 16 months- October\r\nMaggie and Max- 13 months- January\r\nSpot- 18 months- August\n<|im_end|>" }, { "id": "#2820", "title": "Fell Off a Cliff", "fun": 2.54, "difficulty": 1.34, "author": "204_BlaZe_41", "desc": "The dead body of Adrian was found at the bottom of the cliff. He was clothed in heavy hiking boots, mitts, several light jackets, and thick woolen trousers. James G recounted. \"I returned to camp early to make dinner for the hunting party when I saw Adrian and Lulo arguing. They had been dating for several years and frequently held heated discussions. I didn't want to intrude, so I hid behind a tree. Suddenly Adrian picked up a rock and delivered a fatal blow to Lulo's head. Just then Adrian saw me. He was so startled he turned and ran. He obviously forgot about the cliff and fell to his death.\" When the lab checked the rock that supposedly killed Lulo, it found Adrian's fingerprints on it. They immediately ordered the arrest of James G. Why?", "hint": "No hint available.", "answer": "Adrian's body was found wearing mitts, so it would not have been possible for his fingerprints to be on the rock that killed Lulo unless James arranged for them to be there.", "category": "Logic", "date": "03/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe dead body of Adrian was found at the bottom of the cliff. He was clothed in heavy hiking boots, mitts, several light jackets, and thick woolen trousers. James G recounted. \"I returned to camp early to make dinner for the hunting party when I saw Adrian and Lulo arguing. They had been dating for several years and frequently held heated discussions. I didn't want to intrude, so I hid behind a tree. Suddenly Adrian picked up a rock and delivered a fatal blow to Lulo's head. Just then Adrian saw me. He was so startled he turned and ran. He obviously forgot about the cliff and fell to his death.\" When the lab checked the rock that supposedly killed Lulo, it found Adrian's fingerprints on it. They immediately ordered the arrest of James G. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdrian's body was found wearing mitts, so it would not have been possible for his fingerprints to be on the rock that killed Lulo unless James arranged for them to be there.\n<|im_start|>answer\nAdrian's body was found wearing mitts, so it would not have been possible for his fingerprints to be on the rock that killed Lulo unless James arranged for them to be there.\n<|im_end|>" }, { "id": "#4818", "title": "Mugs and Balls", "fun": 2.54, "difficulty": 1.31, "author": "arij", "desc": "The fair had arrived in town. \"A prize for guessing the number of balls under the mugs,\" shouted one stall owner, as he placed four upturned mugs on the counter in front of him. Each concealed the same number of balls and on each mug was a statement about the number of balls underneath : One or four; Two or four; Two or three; One or two. Only one of the statements was correct. How many balls were under a mug and which statement is true?", "hint": "No hint available.", "answer": "Three balls under each mug and the third statement was true. The number three appears in only the third statement so that must be the correct one.", "category": "Logic", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe fair had arrived in town. \"A prize for guessing the number of balls under the mugs,\" shouted one stall owner, as he placed four upturned mugs on the counter in front of him. Each concealed the same number of balls and on each mug was a statement about the number of balls underneath : One or four; Two or four; Two or three; One or two. Only one of the statements was correct. How many balls were under a mug and which statement is true?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree balls under each mug and the third statement was true. The number three appears in only the third statement so that must be the correct one.\n<|im_start|>answer\nThree balls under each mug and the third statement was true. The number three appears in only the third statement so that must be the correct one.\n<|im_end|>" }, { "id": "#52268", "title": "The Landlord", "fun": 2.54, "difficulty": 2.47, "author": "wimpykidfan37", "desc": "Al, Ben, Carl, and Dan live in four adjacent apartments. The apartments are set up like this:\n\r\n|1|2|3|4|\n\r\nwith apartment 1 being the westernmost apartment and apartment 4 being the easternmost. One of the four is the landlord. Here are some facts:\n\r\n1. If Carl does not live next to Ben, then Al is the landlord and he lives in apartment 1.\n\r\n2. If Al lives east of Carl, then Dan is the landlord and he lives in apartment 4.\n\r\n3. If Ben does not live next to Dan, then Carl is the landlord and he lives in apartment 3.\n\r\n4. If Dan lives east of Al, then Ben is the landlord and he lives in apartment 2.\n\r\nWho is the landlord?", "hint": "All four facts are in the form of \"hypothesis and conclusion\" statements. If the hypothesis of such a statement is false, the whole statement is true. If the conclusion is true, the whole statement is true. However, if the hypothesis is true and the conclusion is false, the statement is false. This means that each statement has either a false hypothesis or a true conclusion.", "answer": "Carl is the landlord.\n\r\nObviously only one conclusion is true at most. Let us suppose that all conclusions are false. This would mean that each hypothesis is also false. From facts 1 and 3, Ben lives next to both Carl and Dan, and therefore between Carl and Dan. Then either Al lives east of both Carl and Dan (contradicting fact 4) or Carl and Dan both live east of Al (contradicting fact 2.) So there must be exactly one true hypothesis, which will be paired with the one true conclusion. Obviously each of the three false conclusions is paired with a false hypothesis.\n\r\nIf conclusion 1 is true, then Al lives in apartment 1. But since hypothesis 4 is false, Al has to live east of Dan. So this cannot be right.\n\r\nIf conclusion 2 is true, then Dan lives in apartment 4. But since hypothesis 4 is false, Al must live east of Dan. So this cannot be right, either.\n\r\nIf conclusion 4 is true, Ben lives in apartment 2. Then, since hypotheses 1 and 3 are false, Ben lives between Carl and Dan, putting Al in apartment 4. But since hypothesis 2 is false, Carl must live east of Al. Therefore, conclusion 3 is true.", "category": "Logic", "date": "09/12/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl, Ben, Carl, and Dan live in four adjacent apartments. The apartments are set up like this:\n\r\n|1|2|3|4|\n\r\nwith apartment 1 being the westernmost apartment and apartment 4 being the easternmost. One of the four is the landlord. Here are some facts:\n\r\n1. If Carl does not live next to Ben, then Al is the landlord and he lives in apartment 1.\n\r\n2. If Al lives east of Carl, then Dan is the landlord and he lives in apartment 4.\n\r\n3. If Ben does not live next to Dan, then Carl is the landlord and he lives in apartment 3.\n\r\n4. If Dan lives east of Al, then Ben is the landlord and he lives in apartment 2.\n\r\nWho is the landlord?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarl is the landlord.\n\r\nObviously only one conclusion is true at most. Let us suppose that all conclusions are false. This would mean that each hypothesis is also false. From facts 1 and 3, Ben lives next to both Carl and Dan, and therefore between Carl and Dan. Then either Al lives east of both Carl and Dan (contradicting fact 4) or Carl and Dan both live east of Al (contradicting fact 2.) So there must be exactly one true hypothesis, which will be paired with the one true conclusion. Obviously each of the three false conclusions is paired with a false hypothesis.\n\r\nIf conclusion 1 is true, then Al lives in apartment 1. But since hypothesis 4 is false, Al has to live east of Dan. So this cannot be right.\n\r\nIf conclusion 2 is true, then Dan lives in apartment 4. But since hypothesis 4 is false, Al must live east of Dan. So this cannot be right, either.\n\r\nIf conclusion 4 is true, Ben lives in apartment 2. Then, since hypotheses 1 and 3 are false, Ben lives between Carl and Dan, putting Al in apartment 4. But since hypothesis 2 is false, Carl must live east of Al. Therefore, conclusion 3 is true.\n<|im_start|>answer\nCarl is the landlord.\n\r\nObviously only one conclusion is true at most. Let us suppose that all conclusions are false. This would mean that each hypothesis is also false. From facts 1 and 3, Ben lives next to both Carl and Dan, and therefore between Carl and Dan. Then either Al lives east of both Carl and Dan (contradicting fact 4) or Carl and Dan both live east of Al (contradicting fact 2.) So there must be exactly one true hypothesis, which will be paired with the one true conclusion. Obviously each of the three false conclusions is paired with a false hypothesis.\n\r\nIf conclusion 1 is true, then Al lives in apartment 1. But since hypothesis 4 is false, Al has to live east of Dan. So this cannot be right.\n\r\nIf conclusion 2 is true, then Dan lives in apartment 4. But since hypothesis 4 is false, Al must live east of Dan. So this cannot be right, either.\n\r\nIf conclusion 4 is true, Ben lives in apartment 2. Then, since hypotheses 1 and 3 are false, Ben lives between Carl and Dan, putting Al in apartment 4. But since hypothesis 2 is false, Carl must live east of Al. Therefore, conclusion 3 is true.\n<|im_end|>" }, { "id": "#4089", "title": "Frying Pan", "fun": 2.54, "difficulty": 0.96, "author": "valeriy", "desc": "There is a frying pan that's big enough to hold 2 pieces of meat. It takes one minute to fry the piece of meat on one side. You have 3 pieces of the meat and you have to cook them in 3 minutes. \n\r\nIs it possible? And how?", "hint": "No hint available.", "answer": "Fry pieces 1 and 2 on one side. Then fry the 1st piece on the second side and the 3rd on the first side. And in the last minute fry the 2nd and 3rd on the second side.", "category": "Logic", "date": "05/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a frying pan that's big enough to hold 2 pieces of meat. It takes one minute to fry the piece of meat on one side. You have 3 pieces of the meat and you have to cook them in 3 minutes. \n\r\nIs it possible? And how?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFry pieces 1 and 2 on one side. Then fry the 1st piece on the second side and the 3rd on the first side. And in the last minute fry the 2nd and 3rd on the second side.\n<|im_start|>answer\nFry pieces 1 and 2 on one side. Then fry the 1st piece on the second side and the 3rd on the first side. And in the last minute fry the 2nd and 3rd on the second side.\n<|im_end|>" }, { "id": "#38124", "title": "Who Plays What?", "fun": 2.54, "difficulty": 2.22, "author": "Rocky_B", "desc": "Four students are seated around a square table. They each play a different school sport: basketball, baseball, lacrosse, soccer. Based on the following clues, figure out what sport each person plays.\n\r\nThe baseball player sits to the left of Deanna. Julie and Jake sit next to each other. The lacrosse player sits across from William. A girl sits to the left of the soccer player.", "hint": "No hint available.", "answer": "Deanna plays basketball.\r\nJulie plays lacrosse.\r\nWilliam plays baseball.\r\nJake plays soccer.", "category": "Logic", "date": "09/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour students are seated around a square table. They each play a different school sport: basketball, baseball, lacrosse, soccer. Based on the following clues, figure out what sport each person plays.\n\r\nThe baseball player sits to the left of Deanna. Julie and Jake sit next to each other. The lacrosse player sits across from William. A girl sits to the left of the soccer player.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDeanna plays basketball.\r\nJulie plays lacrosse.\r\nWilliam plays baseball.\r\nJake plays soccer.\n<|im_start|>answer\nDeanna plays basketball.\r\nJulie plays lacrosse.\r\nWilliam plays baseball.\r\nJake plays soccer.\n<|im_end|>" }, { "id": "#35740", "title": "The Rose Show", "fun": 2.54, "difficulty": 2.5100000000000002, "author": "locomom", "desc": "At the annual Pottstown Rose Show, Mr. Tom Thorne, an avid rose grower, entered his six best new hybrid roses. He did extremely well, taking home 28 ribbons. From the following clues, can you figure out how many blue ribbons and how many red ribbons each rose received?\n\r\nNames of Roses are: Pretty in Pink, Ravishing Red, Simply Silver, Mrs. Thelma Thorne, Very Violet and Yummy Yellow.\n\r\n1. No two roses won the same total number of ribbons.\n\r\n2. \"Pretty in Pink\" won one-quarter of the total amount, which was the same amount as the number that \"Ravishing Red\", \"Yummy Yellow\" and \"Simply Silver\" won together.\n\r\n3. \"Very Violet\" won the same number of ribbons as both \"Mrs.Thelma Thorne\" and \"Simply Silver\" together.\n\r\n4. Three-quarters of \"Ravishing Red's\" ribbons were red.\n\r\n5. One-third of \"Mrs. Thelma Thorne's\" ribbons were blue; \"Yummy Yellow\" won just one blue ribbon.\n\r\n6. \"Simply Silver\" won an equal number of blue and red ribbons.\n\r\n7. \"Very Violet\" won the same number of blue ribbons as \"Pretty in Pink\".\n\r\n8. \"Very Violet\" won as many red ribbons as were won by \"Mrs. Thelma Thorne\" and \"Ravishing Red\" together.", "hint": "No hint available.", "answer": "Pretty in Pink - 1 Blue - 6 Red\r\nRavishing Red - 1 Blue - 3 Red\r\nSimply Silver - 1 Blue - 1 Red\r\nMrs. Thelma Thorne - 2 Blue - 4 Red\r\nVery Violet - 1 Blue - 7 red\r\nYummy Yellow - 1 Blue only", "category": "Logic", "date": "03/17/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the annual Pottstown Rose Show, Mr. Tom Thorne, an avid rose grower, entered his six best new hybrid roses. He did extremely well, taking home 28 ribbons. From the following clues, can you figure out how many blue ribbons and how many red ribbons each rose received?\n\r\nNames of Roses are: Pretty in Pink, Ravishing Red, Simply Silver, Mrs. Thelma Thorne, Very Violet and Yummy Yellow.\n\r\n1. No two roses won the same total number of ribbons.\n\r\n2. \"Pretty in Pink\" won one-quarter of the total amount, which was the same amount as the number that \"Ravishing Red\", \"Yummy Yellow\" and \"Simply Silver\" won together.\n\r\n3. \"Very Violet\" won the same number of ribbons as both \"Mrs.Thelma Thorne\" and \"Simply Silver\" together.\n\r\n4. Three-quarters of \"Ravishing Red's\" ribbons were red.\n\r\n5. One-third of \"Mrs. Thelma Thorne's\" ribbons were blue; \"Yummy Yellow\" won just one blue ribbon.\n\r\n6. \"Simply Silver\" won an equal number of blue and red ribbons.\n\r\n7. \"Very Violet\" won the same number of blue ribbons as \"Pretty in Pink\".\n\r\n8. \"Very Violet\" won as many red ribbons as were won by \"Mrs. Thelma Thorne\" and \"Ravishing Red\" together.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPretty in Pink - 1 Blue - 6 Red\r\nRavishing Red - 1 Blue - 3 Red\r\nSimply Silver - 1 Blue - 1 Red\r\nMrs. Thelma Thorne - 2 Blue - 4 Red\r\nVery Violet - 1 Blue - 7 red\r\nYummy Yellow - 1 Blue only\n<|im_start|>answer\nPretty in Pink - 1 Blue - 6 Red\r\nRavishing Red - 1 Blue - 3 Red\r\nSimply Silver - 1 Blue - 1 Red\r\nMrs. Thelma Thorne - 2 Blue - 4 Red\r\nVery Violet - 1 Blue - 7 red\r\nYummy Yellow - 1 Blue only\n<|im_end|>" }, { "id": "#34885", "title": "The Curious License Plate", "fun": 2.54, "difficulty": 2.57, "author": "chidam11", "desc": "When Chidam got his first car, the first thing he had to do was to get a license plate. When he got his plate, he noticed that the plate had a peculiar number with five digits on it. He also noticed that the numbers could be read upside down, but the value of the number had increased by 78633.\n\n\r\nCan you help Chidam find the number of his license plate number?", "hint": "There are only 5 digits from 0 to 9 which can be read upside down. The numbers are - 0, 1, 6, 8 and 9.", "answer": "The number of Chidam's license plate is 10968, which is 89601 when inverted. That is 78633 more than the original number.", "category": "Logic", "date": "01/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Chidam got his first car, the first thing he had to do was to get a license plate. When he got his plate, he noticed that the plate had a peculiar number with five digits on it. He also noticed that the numbers could be read upside down, but the value of the number had increased by 78633.\n\n\r\nCan you help Chidam find the number of his license plate number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number of Chidam's license plate is 10968, which is 89601 when inverted. That is 78633 more than the original number.\n<|im_start|>answer\nThe number of Chidam's license plate is 10968, which is 89601 when inverted. That is 78633 more than the original number.\n<|im_end|>" }, { "id": "#5473", "title": "Three Vacations", "fun": 2.54, "difficulty": 1.6300000000000001, "author": "Bobbrt", "desc": "Miss English, Mrs. French, and Ms. Lapp all went on vacation recently, one to England, one to France, and one to Lapland. If only one of the following four statements is true, who went where?\n\r\n1. Ms. Lapp went to England.\r\n2. Ms. Lapp did not go to France.\r\n3. Miss English did not go to France.\r\n4. Miss English did not go to Lapland.", "hint": "No hint available.", "answer": "The third statement is the only one that can be true and satisfy the conditions of the puzzle. Therefore, Ms. Lapp went to France, Miss English went to Lapland, and Mrs. French went to England.", "category": "Logic", "date": "07/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMiss English, Mrs. French, and Ms. Lapp all went on vacation recently, one to England, one to France, and one to Lapland. If only one of the following four statements is true, who went where?\n\r\n1. Ms. Lapp went to England.\r\n2. Ms. Lapp did not go to France.\r\n3. Miss English did not go to France.\r\n4. Miss English did not go to Lapland.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe third statement is the only one that can be true and satisfy the conditions of the puzzle. Therefore, Ms. Lapp went to France, Miss English went to Lapland, and Mrs. French went to England.\n<|im_start|>answer\nThe third statement is the only one that can be true and satisfy the conditions of the puzzle. Therefore, Ms. Lapp went to France, Miss English went to Lapland, and Mrs. French went to England.\n<|im_end|>" }, { "id": "#3953", "title": "Making Beds", "fun": 2.54, "difficulty": 1.34, "author": "PeaceJo", "desc": "On Saturday morning, Millicent took four sets of sheets out of the linen closet to make the four beds in her house (one was her daughter's bed). Each set of sheets was of a different solid colour (one was green). Combine this information with the clues below to put the four beds in the order in which Millicent made them and match each with the colour of its sheets.\n\r\n1. Millicent made the beds in this order: first the bed with the tan sheets, then her son's bed, then the guest bed and finally the bed with white sheets.\n\r\n2. The white sheets didn't go on the master bed.\n\r\n3. The blue sheets didn't go on her son's bed.", "hint": "No hint available.", "answer": "First - master bed - tan sheets\r\nSecond - son's bed - green sheets\r\nThird - guest bed - blue sheets\r\nFourth - daughter's bed - white sheets", "category": "Logic", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Saturday morning, Millicent took four sets of sheets out of the linen closet to make the four beds in her house (one was her daughter's bed). Each set of sheets was of a different solid colour (one was green). Combine this information with the clues below to put the four beds in the order in which Millicent made them and match each with the colour of its sheets.\n\r\n1. Millicent made the beds in this order: first the bed with the tan sheets, then her son's bed, then the guest bed and finally the bed with white sheets.\n\r\n2. The white sheets didn't go on the master bed.\n\r\n3. The blue sheets didn't go on her son's bed.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst - master bed - tan sheets\r\nSecond - son's bed - green sheets\r\nThird - guest bed - blue sheets\r\nFourth - daughter's bed - white sheets\n<|im_start|>answer\nFirst - master bed - tan sheets\r\nSecond - son's bed - green sheets\r\nThird - guest bed - blue sheets\r\nFourth - daughter's bed - white sheets\n<|im_end|>" }, { "id": "#31896", "title": "Hoosier Hysteria", "fun": 2.54, "difficulty": 2.69, "author": "GebbieRose", "desc": "It was an excellent basketball game, according to Coach Pasquale; the team set a record high. In the 4th quarter, they scored 1/4 of the total points which they scored in the game, less 3. In the 3rd, they scored 1/3 of their score at the end of the 3rd, less 2. In the 2nd, they scored 1/2 of their score at the end of the 2nd, less 1. Their score at the end of the 1st was 27. What was their final score?", "hint": "Start at the beginning...", "answer": "96 Points\n\r\nEXPLANATION: You know the score at the end of the first quarter is 27, so to figure the score at the end of the second, let X=score after the second quarter & (X/2 - 1) = points scored in the second quarter:\r\n\tX=(X/2 - 1) + 27 (points scored in first quarter)\r\n\tX=52\n\r\nLet Y = score at end of third quarter & (Y/3 - 2) = point scored in third quarter:\r\n\tY=(Y/3 - 2) + 52 (score at end of second quarter)\r\n\tY=75\n\r\nLet Z = score at end of fourth quarter & (Z/4 - 3) = points scored in the fourth quarter:\t\r\n\tZ= (Z/4 - 3) + 75 (score at end of third quarter)\r\n\tZ=96", "category": "Math", "date": "07/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was an excellent basketball game, according to Coach Pasquale; the team set a record high. In the 4th quarter, they scored 1/4 of the total points which they scored in the game, less 3. In the 3rd, they scored 1/3 of their score at the end of the 3rd, less 2. In the 2nd, they scored 1/2 of their score at the end of the 2nd, less 1. Their score at the end of the 1st was 27. What was their final score?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n96 Points\n\r\nEXPLANATION: You know the score at the end of the first quarter is 27, so to figure the score at the end of the second, let X=score after the second quarter & (X/2 - 1) = points scored in the second quarter:\r\n\tX=(X/2 - 1) + 27 (points scored in first quarter)\r\n\tX=52\n\r\nLet Y = score at end of third quarter & (Y/3 - 2) = point scored in third quarter:\r\n\tY=(Y/3 - 2) + 52 (score at end of second quarter)\r\n\tY=75\n\r\nLet Z = score at end of fourth quarter & (Z/4 - 3) = points scored in the fourth quarter:\t\r\n\tZ= (Z/4 - 3) + 75 (score at end of third quarter)\r\n\tZ=96\n<|im_start|>answer\n96 Points\n\r\nEXPLANATION: You know the score at the end of the first quarter is 27, so to figure the score at the end of the second, let X=score after the second quarter & (X/2 - 1) = points scored in the second quarter:\r\n\tX=(X/2 - 1) + 27 (points scored in first quarter)\r\n\tX=52\n\r\nLet Y = score at end of third quarter & (Y/3 - 2) = point scored in third quarter:\r\n\tY=(Y/3 - 2) + 52 (score at end of second quarter)\r\n\tY=75\n\r\nLet Z = score at end of fourth quarter & (Z/4 - 3) = points scored in the fourth quarter:\t\r\n\tZ= (Z/4 - 3) + 75 (score at end of third quarter)\r\n\tZ=96\n<|im_end|>" }, { "id": "#30069", "title": "Table Tennis Challenge", "fun": 2.54, "difficulty": 2.93, "author": "cinnamon30", "desc": "Patrice and seven of her friends organized the Ultimate Table Tennis Challenge to determine who the best Ping-Pong player among them was. The challenge consisted of three rounds of singles matches (two players competing per match). In each round, the first player to win FIVE games won the match and eliminated the opponent from the competition. The winners of the four first round matches advanced to the second round and the two second round winners advanced to the championship match. Each match was played at a different location, including the Beachcomber Swim Club. All first round matches were played on outdoor tables, both second round locations were indoor tables and the final round was played in the table tennis stadium at the New York Athletic Club. No two people won the same number of games, so players eliminated in the same round were ranked by the total number of games won. Identify each competitor's final ranking (first through eighth), full name (one last name is Chang), and the total number of games he or she won. In addition, figure out each location of each match, the competitors and their scores.\n\r\n1. The winner of the match at the Southville YMCA lost at least three games on the indoor table in Uncle Phil's basement before meeting McNeilly in the finals.\n\r\n2. The first round opponent of the eventual champion was neither Fitzroy (who lost in the first round) nor the person who lost at the Brooklyn Table Tennis Academy.\n\r\n3. The championship round took the maximum possible number of games in a match.\n\r\n4. The seven matches, in some order, were: Jamie's first round victory, the match in which White won exactly 2 games, the match at Eastlake Municipal Park, the match that Lottie lost, the only match Diaz played, the match Toskhaya lost and the match in which somebody won exactly one game.\n\r\n5. Bill never played Dave.\n\r\n6. Averson didn't play Jamie in the first round.\n\r\n7. A total of 55 games were played in the whole challenge, 30 of which were the first round matches.\n\r\n8. McNeilly, who isn't Lottie or Kristin, never played Samuel or Gianelli.\n\r\n9. The four who advanced to the second round were: White, Lottie, the person who played Regina in the first round and someone whose indoor match was at the Islip Town Hall.\n\r\n10. McNeilly's opponent in the first round won more games than Diaz.\n\r\n11. Kristin never played at the Southville YMCA.\n\r\n12. Regina won more games than the person eliminated at Eastlake Municipal Park.\n\r\n13. Kristin won more games than Bill, who won at least five.\n\r\n14. In the first round, Dave didn't play the eventual champion", "hint": "Last names: Averson, Chang, Diaz, Fitzroy, Gianelli, McNeilly, Toskhaya and White", "answer": "RANKING/ PLAYER/ GAMES \n\r\n1st - Jamie McNeilly, 15 games\r\n2nd - Lottie Averson, 14 games\r\n3rd - Kristin Toskhaya, 9 games \r\n4th - Bill White, 7 games\r\n5th - Patrice Chang, 4 games\r\n6th - Regina Diaz, 3 games\r\n7th - Samuel Fitzroy, 2 games\r\n8th - Dave Gianelli, 1 game\n\r\n1st Round \r\nBeachcomber, Jamie, 5, Patrice, 4\r\nBrooklyn, Kristin, 5, Regina, 3\r\nEastlake, Bill, 5, Samuel, 2\r\nSouthville, Lottie, 5, Dave, 1\n\r\n2nd Round\r\nIslip, Jamie, 5, Bill, 2\r\nUncle Phil's, Lottie, 5, Kristin, 4\n\r\n3rd Round\r\nN. Y. Athletic, Jamie, 5, Lottie, 4\n\r\nThe final match was played at the New York Athletic Club (intro). The loser in the championship round lost 4 games (3) for a total of 9 games in the final round (intro and 3). \r\nThere were 30 matches in the first round (7); with 20 of them being wins (intro) therefore the total of lost games in the first round are 10. From clue 4, we know that somebody won exactly 1 game. From the intro we know no one won the same number of games, therefore the number of games lost in the first round is 1, 2, 3, and 4, can't have 5 because that means they would have advanced to the next round.\r\nThis leaves 55 (total games played (clue 7)) - 30 (1st round - clue 7) - 9 (Final round - clue 3) = 16 games in 2nd round. 10 of these 16 games are the winner's games, which leaves 6 games for the losers in round 2. The 2 loser's games can't be 3 & 3, because this would mean both players would have a total of 8 games each. No two players won the same number of games (intro). They can't be 5 & 1 because that would leave a tie and only 1 can advance. They can't be 6 & 0 because 5 wins advances someone, so no one can win 6. This leaves 2 & 4 as the games won by the losers in the second round.\r\nThis means the total numbers of matches won from 1st ranked to 8th ranked are: 15, 14, 9, 7, 4, 3, 2 and 1 for a total off 55 games (7).\r\nFrom clue 1 we know that the Southville YMCA was used in round 1, Uncle Phil's Basement is used in round 2 and McNeilly is in the final game, which means McNeilly won a match in round 1 and in round 2 for a total of either 14 (if he loses the finals) or 15 (if he wins the finals) games.\r\nIslip Town Hall is used in the 2nd round (9), which leaves Eastlake Municipal Park, The Beachcomber Swim Club and Brooklyn Table Tennis Academy being used for the other 3 matches in the first round.\r\nFrom clue 9, we know the four first round winners are: White, Lottie, the one who played Regina in the first round and The Islip Town Hall match. McNeilly has to be 1 of these four (1). McNeilly isn't Lottie (8), can't be White since both are last names, so is either the one who played Regina or the one who played at Islip Town Hall. Regina lost the first round match (9).\r\nWhite is in the second round (9) and is the player who won only two games (4), which means White doesn't go to the finals and won a total of 7 games.\r\nFrom clue 4, four of the 1st round matches are: Jamie's 1st round victory, Eastlake Municipal Park (see above), the only match Diaz played and someone who won exactly one game. We know White won exactly two games (4) and the final round took the maximum number of games (3), therefore White's 2 game win has to be in the 2nd round. Since we now know the four 1st round matches, Toskhaya had to win in the 1st round and moves on to round 2.\r\nFrom clue 13, Bill won at least 5 games and Kristin won more than Bill. This means that both Bill and Kristin won their first round matches and moves on to the second round. The four players in round 2 are: Jamie, Lottie, Bill and Kristin. One of these four was the eventual winner, but it wasn't Bill (13) or Lottie (4), so Jamie or Kristin is the winner. Kristin isn't McNeilly (8) and never played at Southville (11), so she didn't play in the finals (1). This makes Jamie the winner.\r\nSince Bill didn't finish second overall (13 and above), he wasn't Jamie's opponent in the finals. Kristin wasn't in the finals (see above); therefore Lottie lost in the final match with a total of 14 games overall. Jamie and Lottie were the 2nd round winners. Lottie isn't McNeilly (8), therefore Jamie is, who won the final round.\r\nLottie isn't Toskhaya (4) or White (9), therefore Lottie played against Toskhaya in round two.\r\nIn the 1st round, Jamie McNeilly didn't play Fitzroy (2), Averson (6), Diaz (4) or Gianelli (8); thus he played Chang. Jamie didn't play at the Southville YMCA (1), Eastlake Park (4), Brooklyn Academy (2), thus he played on the Beachcomber Swim Club table in round one. Jamie didn't play Lottie, Kristin or Bill in round one, since they are winners in round one. Jamie didn't play Samuel (8) or Dave (14). From clue 9 Regina was the one who played Toskhaya in round one, therefore Jamie had to play Patrice in round 1.\r\nFrom clue 1 and above, we know Lottie played at the Southville YMCA in round one.\r\nFrom clue 13, Kristin won more games than Bill, so Kristin is Toskhaya and Bill is White.\r\nRegina didn't play at Eastlake (12) and she won more than one game, therefore she is Diaz.\r\nRegina Diaz didn't win overall 1 game (4); she won more than the Eastlake player (12) but less than McNeilly's first round opponent (10) -who is Patrice Chang. Thus, she won 3 games overall, the Eastlake opponent won 2 games overall and Patrice Chang won 4 games overall.\r\nKristin didn't play at the Southville YMCA; therefore she played at the Brooklyn Academy.\r\nLottie played Jamie in the final round, therefore her last name isn't Fitzroy (2) or Gianelli (8), therefore she is Averson.\r\nLottie Averson played at Southville YMCA (1 and above).\r\nBills 1st round opponent wasn't Dave (5), thus Lottie played Dave and Bill played Samuel in the 1st round. Samuel isn't Gianelli (8), thus he is Fitzroy and Dave is Gianelli.", "category": "Logic", "date": "04/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPatrice and seven of her friends organized the Ultimate Table Tennis Challenge to determine who the best Ping-Pong player among them was. The challenge consisted of three rounds of singles matches (two players competing per match). In each round, the first player to win FIVE games won the match and eliminated the opponent from the competition. The winners of the four first round matches advanced to the second round and the two second round winners advanced to the championship match. Each match was played at a different location, including the Beachcomber Swim Club. All first round matches were played on outdoor tables, both second round locations were indoor tables and the final round was played in the table tennis stadium at the New York Athletic Club. No two people won the same number of games, so players eliminated in the same round were ranked by the total number of games won. Identify each competitor's final ranking (first through eighth), full name (one last name is Chang), and the total number of games he or she won. In addition, figure out each location of each match, the competitors and their scores.\n\r\n1. The winner of the match at the Southville YMCA lost at least three games on the indoor table in Uncle Phil's basement before meeting McNeilly in the finals.\n\r\n2. The first round opponent of the eventual champion was neither Fitzroy (who lost in the first round) nor the person who lost at the Brooklyn Table Tennis Academy.\n\r\n3. The championship round took the maximum possible number of games in a match.\n\r\n4. The seven matches, in some order, were: Jamie's first round victory, the match in which White won exactly 2 games, the match at Eastlake Municipal Park, the match that Lottie lost, the only match Diaz played, the match Toskhaya lost and the match in which somebody won exactly one game.\n\r\n5. Bill never played Dave.\n\r\n6. Averson didn't play Jamie in the first round.\n\r\n7. A total of 55 games were played in the whole challenge, 30 of which were the first round matches.\n\r\n8. McNeilly, who isn't Lottie or Kristin, never played Samuel or Gianelli.\n\r\n9. The four who advanced to the second round were: White, Lottie, the person who played Regina in the first round and someone whose indoor match was at the Islip Town Hall.\n\r\n10. McNeilly's opponent in the first round won more games than Diaz.\n\r\n11. Kristin never played at the Southville YMCA.\n\r\n12. Regina won more games than the person eliminated at Eastlake Municipal Park.\n\r\n13. Kristin won more games than Bill, who won at least five.\n\r\n14. In the first round, Dave didn't play the eventual champion\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRANKING/ PLAYER/ GAMES \n\r\n1st - Jamie McNeilly, 15 games\r\n2nd - Lottie Averson, 14 games\r\n3rd - Kristin Toskhaya, 9 games \r\n4th - Bill White, 7 games\r\n5th - Patrice Chang, 4 games\r\n6th - Regina Diaz, 3 games\r\n7th - Samuel Fitzroy, 2 games\r\n8th - Dave Gianelli, 1 game\n\r\n1st Round \r\nBeachcomber, Jamie, 5, Patrice, 4\r\nBrooklyn, Kristin, 5, Regina, 3\r\nEastlake, Bill, 5, Samuel, 2\r\nSouthville, Lottie, 5, Dave, 1\n\r\n2nd Round\r\nIslip, Jamie, 5, Bill, 2\r\nUncle Phil's, Lottie, 5, Kristin, 4\n\r\n3rd Round\r\nN. Y. Athletic, Jamie, 5, Lottie, 4\n\r\nThe final match was played at the New York Athletic Club (intro). The loser in the championship round lost 4 games (3) for a total of 9 games in the final round (intro and 3). \r\nThere were 30 matches in the first round (7); with 20 of them being wins (intro) therefore the total of lost games in the first round are 10. From clue 4, we know that somebody won exactly 1 game. From the intro we know no one won the same number of games, therefore the number of games lost in the first round is 1, 2, 3, and 4, can't have 5 because that means they would have advanced to the next round.\r\nThis leaves 55 (total games played (clue 7)) - 30 (1st round - clue 7) - 9 (Final round - clue 3) = 16 games in 2nd round. 10 of these 16 games are the winner's games, which leaves 6 games for the losers in round 2. The 2 loser's games can't be 3 & 3, because this would mean both players would have a total of 8 games each. No two players won the same number of games (intro). They can't be 5 & 1 because that would leave a tie and only 1 can advance. They can't be 6 & 0 because 5 wins advances someone, so no one can win 6. This leaves 2 & 4 as the games won by the losers in the second round.\r\nThis means the total numbers of matches won from 1st ranked to 8th ranked are: 15, 14, 9, 7, 4, 3, 2 and 1 for a total off 55 games (7).\r\nFrom clue 1 we know that the Southville YMCA was used in round 1, Uncle Phil's Basement is used in round 2 and McNeilly is in the final game, which means McNeilly won a match in round 1 and in round 2 for a total of either 14 (if he loses the finals) or 15 (if he wins the finals) games.\r\nIslip Town Hall is used in the 2nd round (9), which leaves Eastlake Municipal Park, The Beachcomber Swim Club and Brooklyn Table Tennis Academy being used for the other 3 matches in the first round.\r\nFrom clue 9, we know the four first round winners are: White, Lottie, the one who played Regina in the first round and The Islip Town Hall match. McNeilly has to be 1 of these four (1). McNeilly isn't Lottie (8), can't be White since both are last names, so is either the one who played Regina or the one who played at Islip Town Hall. Regina lost the first round match (9).\r\nWhite is in the second round (9) and is the player who won only two games (4), which means White doesn't go to the finals and won a total of 7 games.\r\nFrom clue 4, four of the 1st round matches are: Jamie's 1st round victory, Eastlake Municipal Park (see above), the only match Diaz played and someone who won exactly one game. We know White won exactly two games (4) and the final round took the maximum number of games (3), therefore White's 2 game win has to be in the 2nd round. Since we now know the four 1st round matches, Toskhaya had to win in the 1st round and moves on to round 2.\r\nFrom clue 13, Bill won at least 5 games and Kristin won more than Bill. This means that both Bill and Kristin won their first round matches and moves on to the second round. The four players in round 2 are: Jamie, Lottie, Bill and Kristin. One of these four was the eventual winner, but it wasn't Bill (13) or Lottie (4), so Jamie or Kristin is the winner. Kristin isn't McNeilly (8) and never played at Southville (11), so she didn't play in the finals (1). This makes Jamie the winner.\r\nSince Bill didn't finish second overall (13 and above), he wasn't Jamie's opponent in the finals. Kristin wasn't in the finals (see above); therefore Lottie lost in the final match with a total of 14 games overall. Jamie and Lottie were the 2nd round winners. Lottie isn't McNeilly (8), therefore Jamie is, who won the final round.\r\nLottie isn't Toskhaya (4) or White (9), therefore Lottie played against Toskhaya in round two.\r\nIn the 1st round, Jamie McNeilly didn't play Fitzroy (2), Averson (6), Diaz (4) or Gianelli (8); thus he played Chang. Jamie didn't play at the Southville YMCA (1), Eastlake Park (4), Brooklyn Academy (2), thus he played on the Beachcomber Swim Club table in round one. Jamie didn't play Lottie, Kristin or Bill in round one, since they are winners in round one. Jamie didn't play Samuel (8) or Dave (14). From clue 9 Regina was the one who played Toskhaya in round one, therefore Jamie had to play Patrice in round 1.\r\nFrom clue 1 and above, we know Lottie played at the Southville YMCA in round one.\r\nFrom clue 13, Kristin won more games than Bill, so Kristin is Toskhaya and Bill is White.\r\nRegina didn't play at Eastlake (12) and she won more than one game, therefore she is Diaz.\r\nRegina Diaz didn't win overall 1 game (4); she won more than the Eastlake player (12) but less than McNeilly's first round opponent (10) -who is Patrice Chang. Thus, she won 3 games overall, the Eastlake opponent won 2 games overall and Patrice Chang won 4 games overall.\r\nKristin didn't play at the Southville YMCA; therefore she played at the Brooklyn Academy.\r\nLottie played Jamie in the final round, therefore her last name isn't Fitzroy (2) or Gianelli (8), therefore she is Averson.\r\nLottie Averson played at Southville YMCA (1 and above).\r\nBills 1st round opponent wasn't Dave (5), thus Lottie played Dave and Bill played Samuel in the 1st round. Samuel isn't Gianelli (8), thus he is Fitzroy and Dave is Gianelli.\n<|im_start|>answer\nRANKING/ PLAYER/ GAMES \n\r\n1st - Jamie McNeilly, 15 games\r\n2nd - Lottie Averson, 14 games\r\n3rd - Kristin Toskhaya, 9 games \r\n4th - Bill White, 7 games\r\n5th - Patrice Chang, 4 games\r\n6th - Regina Diaz, 3 games\r\n7th - Samuel Fitzroy, 2 games\r\n8th - Dave Gianelli, 1 game\n\r\n1st Round \r\nBeachcomber, Jamie, 5, Patrice, 4\r\nBrooklyn, Kristin, 5, Regina, 3\r\nEastlake, Bill, 5, Samuel, 2\r\nSouthville, Lottie, 5, Dave, 1\n\r\n2nd Round\r\nIslip, Jamie, 5, Bill, 2\r\nUncle Phil's, Lottie, 5, Kristin, 4\n\r\n3rd Round\r\nN. Y. Athletic, Jamie, 5, Lottie, 4\n\r\nThe final match was played at the New York Athletic Club (intro). The loser in the championship round lost 4 games (3) for a total of 9 games in the final round (intro and 3). \r\nThere were 30 matches in the first round (7); with 20 of them being wins (intro) therefore the total of lost games in the first round are 10. From clue 4, we know that somebody won exactly 1 game. From the intro we know no one won the same number of games, therefore the number of games lost in the first round is 1, 2, 3, and 4, can't have 5 because that means they would have advanced to the next round.\r\nThis leaves 55 (total games played (clue 7)) - 30 (1st round - clue 7) - 9 (Final round - clue 3) = 16 games in 2nd round. 10 of these 16 games are the winner's games, which leaves 6 games for the losers in round 2. The 2 loser's games can't be 3 & 3, because this would mean both players would have a total of 8 games each. No two players won the same number of games (intro). They can't be 5 & 1 because that would leave a tie and only 1 can advance. They can't be 6 & 0 because 5 wins advances someone, so no one can win 6. This leaves 2 & 4 as the games won by the losers in the second round.\r\nThis means the total numbers of matches won from 1st ranked to 8th ranked are: 15, 14, 9, 7, 4, 3, 2 and 1 for a total off 55 games (7).\r\nFrom clue 1 we know that the Southville YMCA was used in round 1, Uncle Phil's Basement is used in round 2 and McNeilly is in the final game, which means McNeilly won a match in round 1 and in round 2 for a total of either 14 (if he loses the finals) or 15 (if he wins the finals) games.\r\nIslip Town Hall is used in the 2nd round (9), which leaves Eastlake Municipal Park, The Beachcomber Swim Club and Brooklyn Table Tennis Academy being used for the other 3 matches in the first round.\r\nFrom clue 9, we know the four first round winners are: White, Lottie, the one who played Regina in the first round and The Islip Town Hall match. McNeilly has to be 1 of these four (1). McNeilly isn't Lottie (8), can't be White since both are last names, so is either the one who played Regina or the one who played at Islip Town Hall. Regina lost the first round match (9).\r\nWhite is in the second round (9) and is the player who won only two games (4), which means White doesn't go to the finals and won a total of 7 games.\r\nFrom clue 4, four of the 1st round matches are: Jamie's 1st round victory, Eastlake Municipal Park (see above), the only match Diaz played and someone who won exactly one game. We know White won exactly two games (4) and the final round took the maximum number of games (3), therefore White's 2 game win has to be in the 2nd round. Since we now know the four 1st round matches, Toskhaya had to win in the 1st round and moves on to round 2.\r\nFrom clue 13, Bill won at least 5 games and Kristin won more than Bill. This means that both Bill and Kristin won their first round matches and moves on to the second round. The four players in round 2 are: Jamie, Lottie, Bill and Kristin. One of these four was the eventual winner, but it wasn't Bill (13) or Lottie (4), so Jamie or Kristin is the winner. Kristin isn't McNeilly (8) and never played at Southville (11), so she didn't play in the finals (1). This makes Jamie the winner.\r\nSince Bill didn't finish second overall (13 and above), he wasn't Jamie's opponent in the finals. Kristin wasn't in the finals (see above); therefore Lottie lost in the final match with a total of 14 games overall. Jamie and Lottie were the 2nd round winners. Lottie isn't McNeilly (8), therefore Jamie is, who won the final round.\r\nLottie isn't Toskhaya (4) or White (9), therefore Lottie played against Toskhaya in round two.\r\nIn the 1st round, Jamie McNeilly didn't play Fitzroy (2), Averson (6), Diaz (4) or Gianelli (8); thus he played Chang. Jamie didn't play at the Southville YMCA (1), Eastlake Park (4), Brooklyn Academy (2), thus he played on the Beachcomber Swim Club table in round one. Jamie didn't play Lottie, Kristin or Bill in round one, since they are winners in round one. Jamie didn't play Samuel (8) or Dave (14). From clue 9 Regina was the one who played Toskhaya in round one, therefore Jamie had to play Patrice in round 1.\r\nFrom clue 1 and above, we know Lottie played at the Southville YMCA in round one.\r\nFrom clue 13, Kristin won more games than Bill, so Kristin is Toskhaya and Bill is White.\r\nRegina didn't play at Eastlake (12) and she won more than one game, therefore she is Diaz.\r\nRegina Diaz didn't win overall 1 game (4); she won more than the Eastlake player (12) but less than McNeilly's first round opponent (10) -who is Patrice Chang. Thus, she won 3 games overall, the Eastlake opponent won 2 games overall and Patrice Chang won 4 games overall.\r\nKristin didn't play at the Southville YMCA; therefore she played at the Brooklyn Academy.\r\nLottie played Jamie in the final round, therefore her last name isn't Fitzroy (2) or Gianelli (8), therefore she is Averson.\r\nLottie Averson played at Southville YMCA (1 and above).\r\nBills 1st round opponent wasn't Dave (5), thus Lottie played Dave and Bill played Samuel in the 1st round. Samuel isn't Gianelli (8), thus he is Fitzroy and Dave is Gianelli.\n<|im_end|>" }, { "id": "#1263", "title": "Lies, Lies, Lies", "fun": 2.54, "difficulty": 1.12, "author": "Yanivster", "desc": "Here are ten statements:\n\r\n1. Exactly one of these statements is not true.\r\n2. Exactly two of these statements are not true.\r\n3. Exactly three of these statements are not true.\r\n4. Exactly four of these statements are not true.\r\n5. Exactly five of these statements are not true.\r\n6. Exactly six of these statements are not true.\r\n7. Exactly seven of these statements are not true.\r\n8. Exactly eight of these statements are not true.\r\n9. Exactly nine of these statements are not true.\r\n10. Exactly ten of these statements are not true.\n\r\nHow many and which of the above statements is true?", "hint": "No hint available.", "answer": "Only one of these statements can be true, and it has to be number 9.", "category": "Logic", "date": "11/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHere are ten statements:\n\r\n1. Exactly one of these statements is not true.\r\n2. Exactly two of these statements are not true.\r\n3. Exactly three of these statements are not true.\r\n4. Exactly four of these statements are not true.\r\n5. Exactly five of these statements are not true.\r\n6. Exactly six of these statements are not true.\r\n7. Exactly seven of these statements are not true.\r\n8. Exactly eight of these statements are not true.\r\n9. Exactly nine of these statements are not true.\r\n10. Exactly ten of these statements are not true.\n\r\nHow many and which of the above statements is true?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOnly one of these statements can be true, and it has to be number 9.\n<|im_start|>answer\nOnly one of these statements can be true, and it has to be number 9.\n<|im_end|>" }, { "id": "#10700", "title": "Operators and Symbols", "fun": 2.54, "difficulty": 2.64, "author": "nettlett", "desc": "Add the appropriate mathematical operators or symbols to make the following correct: \n\r\n3 4 5 = 90\n\r\nParentheses may be used freely.", "hint": "The answer is not 3^4 + 4 + 5, as this introduces an extra 4.", "answer": "(3/4)x5! = 90\n\r\n5! is 1x2x3x4x5 = 120", "category": "Math", "date": "02/24/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdd the appropriate mathematical operators or symbols to make the following correct: \n\r\n3 4 5 = 90\n\r\nParentheses may be used freely.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(3/4)x5! = 90\n\r\n5! is 1x2x3x4x5 = 120\n<|im_start|>answer\n(3/4)x5! = 90\n\r\n5! is 1x2x3x4x5 = 120\n<|im_end|>" }, { "id": "#45973", "title": "Ministerial Mutterings", "fun": 2.54, "difficulty": 2.43, "author": "dalfamnest", "desc": "In the purely fictitious land of Fiddledeboox, the Minister of Finance emerged from a top-level meeting. Reporters had gathered to hear his announcement about either an increase or a decrease in either wages, subsidies or tax levels.\n\r\nIt was widely known that this Minister [M] told the truth to reporters [R] only once in every three statements.\n\r\nM: Well, I can tell you that it's about subsidies.\r\nR: Are they going down again?\r\nM: Nothing is going down.\r\nR: So it's good news for the people?\r\nM: Of course. Either subsidies are going down or there will be a wage increase.\n\r\nWhile others jostled to ask the next question, one logically minded newshound was already leaving with the hot headline news.\n\r\nFrom the Minister's three statements above, can you also deduce the truth?", "hint": "Assume each statement, in turn, to be true. Then examine the truth or otherwise of the others.\n\r\nOr check the statements in the light of each of the six possibilities.", "answer": "It was a tax increase.\n\r\nSolution:\r\nRemember that only one statement can be true.\n\r\nIf (1) is true then either (2) or (3) will be true as well. So (1) is a lie.\n\r\nIf (3) is true, either (1) or (2) would be also true. So (3) is a lie.\n\r\nIf (2) is true, it must be either wages or taxes going up or (1) would be true. It cannot be wages, making (3) true, so taxes are increasing.\n\r\nThere are other ways of deducing this gloomy news.", "category": "Logic", "date": "12/11/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the purely fictitious land of Fiddledeboox, the Minister of Finance emerged from a top-level meeting. Reporters had gathered to hear his announcement about either an increase or a decrease in either wages, subsidies or tax levels.\n\r\nIt was widely known that this Minister [M] told the truth to reporters [R] only once in every three statements.\n\r\nM: Well, I can tell you that it's about subsidies.\r\nR: Are they going down again?\r\nM: Nothing is going down.\r\nR: So it's good news for the people?\r\nM: Of course. Either subsidies are going down or there will be a wage increase.\n\r\nWhile others jostled to ask the next question, one logically minded newshound was already leaving with the hot headline news.\n\r\nFrom the Minister's three statements above, can you also deduce the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt was a tax increase.\n\r\nSolution:\r\nRemember that only one statement can be true.\n\r\nIf (1) is true then either (2) or (3) will be true as well. So (1) is a lie.\n\r\nIf (3) is true, either (1) or (2) would be also true. So (3) is a lie.\n\r\nIf (2) is true, it must be either wages or taxes going up or (1) would be true. It cannot be wages, making (3) true, so taxes are increasing.\n\r\nThere are other ways of deducing this gloomy news.\n<|im_start|>answer\nIt was a tax increase.\n\r\nSolution:\r\nRemember that only one statement can be true.\n\r\nIf (1) is true then either (2) or (3) will be true as well. So (1) is a lie.\n\r\nIf (3) is true, either (1) or (2) would be also true. So (3) is a lie.\n\r\nIf (2) is true, it must be either wages or taxes going up or (1) would be true. It cannot be wages, making (3) true, so taxes are increasing.\n\r\nThere are other ways of deducing this gloomy news.\n<|im_end|>" }, { "id": "#5219", "title": "Painters", "fun": 2.54, "difficulty": 1.71, "author": "Cascas", "desc": "A painting job can be completed by 7 painters in 17 days. If 7 more painters join the team 7 days after starting work on the job, then how many more days are required to complete the job?", "hint": "No hint available.", "answer": "Total effort required by 7 painters for 17 days = 7 x 17 = 119 man-days. \n\r\nInitial effort by 7 painters for 7 days = 7 x 7 = 49 man-days. \n\r\nJob still requires 119 - 49 = 70 man-days, and there are 14 painters available to do it. \n\r\nAdditional effort required by 14 painters for 70 man-days = 70 / 14 = 5 days. \n\r\nThus, 5 more days are required to complete the painting job.", "category": "Math", "date": "07/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA painting job can be completed by 7 painters in 17 days. If 7 more painters join the team 7 days after starting work on the job, then how many more days are required to complete the job?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTotal effort required by 7 painters for 17 days = 7 x 17 = 119 man-days. \n\r\nInitial effort by 7 painters for 7 days = 7 x 7 = 49 man-days. \n\r\nJob still requires 119 - 49 = 70 man-days, and there are 14 painters available to do it. \n\r\nAdditional effort required by 14 painters for 70 man-days = 70 / 14 = 5 days. \n\r\nThus, 5 more days are required to complete the painting job.\n<|im_start|>answer\nTotal effort required by 7 painters for 17 days = 7 x 17 = 119 man-days. \n\r\nInitial effort by 7 painters for 7 days = 7 x 7 = 49 man-days. \n\r\nJob still requires 119 - 49 = 70 man-days, and there are 14 painters available to do it. \n\r\nAdditional effort required by 14 painters for 70 man-days = 70 / 14 = 5 days. \n\r\nThus, 5 more days are required to complete the painting job.\n<|im_end|>" }, { "id": "#377", "title": "How Old Am I?", "fun": 2.54, "difficulty": 1.45, "author": "Mr. G", "desc": "I was born on August 1, 25 B.C. I died on August 1, 25 A.D. How old was I when I died?", "hint": "The answer definitely isn't 50.", "answer": "49. There was no year zero.", "category": "Logic", "date": "03/27/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was born on August 1, 25 B.C. I died on August 1, 25 A.D. How old was I when I died?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n49. There was no year zero.\n<|im_start|>answer\n49. There was no year zero.\n<|im_end|>" }, { "id": "#320", "title": "A Weedy Garden.", "fun": 2.54, "difficulty": 1.33, "author": "Mr. G", "desc": "Let's say you have a garden. On day one, there is only one weed. If the number of weeds doubles every day, and the garden is full of weeds on the 30th day, how many days will it take to fill the garden if we start with two weeds?", "hint": "No hint available.", "answer": "29 days. It's just like you started on day two.", "category": "Logic", "date": "03/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLet's say you have a garden. On day one, there is only one weed. If the number of weeds doubles every day, and the garden is full of weeds on the 30th day, how many days will it take to fill the garden if we start with two weeds?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n29 days. It's just like you started on day two.\n<|im_start|>answer\n29 days. It's just like you started on day two.\n<|im_end|>" }, { "id": "#4372", "title": "Lock and Key", "fun": 2.54, "difficulty": 1.82, "author": "gokaran", "desc": "You want to send a valuable object to a friend. You have a box which is more than large enough to contain the object. You have several locks with keys. The box has a locking ring which is more than large enough to have a lock attached. But your friend does not have the key to any lock that you have. Note that you cannot send a key in an unlocked box, since it might be copied. How do you do it?", "hint": "No hint available.", "answer": "Attach a lock to the ring. Send it to her. She attaches her own lock and sends it back. You remove your lock and send it back to her. She removes her lock.", "category": "Logic", "date": "05/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou want to send a valuable object to a friend. You have a box which is more than large enough to contain the object. You have several locks with keys. The box has a locking ring which is more than large enough to have a lock attached. But your friend does not have the key to any lock that you have. Note that you cannot send a key in an unlocked box, since it might be copied. How do you do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAttach a lock to the ring. Send it to her. She attaches her own lock and sends it back. You remove your lock and send it back to her. She removes her lock.\n<|im_start|>answer\nAttach a lock to the ring. Send it to her. She attaches her own lock and sends it back. You remove your lock and send it back to her. She removes her lock.\n<|im_end|>" }, { "id": "#41926", "title": "Flower Power 2", "fun": 2.54, "difficulty": 1.05, "author": "TRILLIONAIRE", "desc": "My first is in three and also in tray\r\nMy second in burn but not in bray\r\nMy third in lamp and also loop\r\nMt fourth in pile but not in coop\r\nMy last in part and also pink\r\nMy whole a flower you will think...", "hint": "T____", "answer": "Tulip", "category": "Logic", "date": "05/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy first is in three and also in tray\r\nMy second in burn but not in bray\r\nMy third in lamp and also loop\r\nMt fourth in pile but not in coop\r\nMy last in part and also pink\r\nMy whole a flower you will think...\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTulip\n<|im_start|>answer\nTulip\n<|im_end|>" }, { "id": "#28652", "title": "How Long Has He Got Left?", "fun": 2.54, "difficulty": 1.65, "author": "Question_Mark", "desc": "Quentin is a man who writes puzzle books. His editor gives him a task for his next book. He must produce 500 puzzles in the space of 80 days. He has created 300 puzzles already. However he has been working slower than normal, producing an average of 15 puzzles for every 4 days. How fast will Quentin have to work now to get the book finished on time?", "hint": "No hint available.", "answer": "Quentin will never get the book in on time. He is on his 80th day. If he has been producing 15 puzzles for 4 days then, 15*(80/4)=300.", "category": "Math", "date": "02/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuentin is a man who writes puzzle books. His editor gives him a task for his next book. He must produce 500 puzzles in the space of 80 days. He has created 300 puzzles already. However he has been working slower than normal, producing an average of 15 puzzles for every 4 days. How fast will Quentin have to work now to get the book finished on time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nQuentin will never get the book in on time. He is on his 80th day. If he has been producing 15 puzzles for 4 days then, 15*(80/4)=300.\n<|im_start|>answer\nQuentin will never get the book in on time. He is on his 80th day. If he has been producing 15 puzzles for 4 days then, 15*(80/4)=300.\n<|im_end|>" }, { "id": "#44313", "title": "Alpha-Grid", "fun": 2.54, "difficulty": 2.61, "author": "cnmne", "desc": "20 cells are arranged in a 5x4 grid. The cells are occupied by 20 birds (10 different birds, a pair (2) of each).\n\r\nThe cells are labeled as follows:\r\nABCDE\r\nFGHIK\r\nLMNOP\r\nRSTUW\n\r\nThe birds are: albatross, bunting, cardinal, chickadee, finch, flamingo, hawk, magpie, penguin, and swan.\n\r\nA bird can only occupy a cell if the cell is labeled with a letter that is in the bird's name. For example, a hawk can only be in cell: H, A, W, or K.\n\r\nEach pair of birds must be in the same row or the same column.\n\r\nWhere are the birds located?", "hint": "No hint available.", "answer": "1) Determine the locations of the swans. The only cells that are in the same row/column are in row 4.\r\n2) Determine the locations of the hawks. One of the cells is eliminated because it is occupied by a swan. The only remaining cells that are in the same row/column are in row 2.\r\n3) Determine the bird that is in row 1 column 2. Placing the bunting in that cell will lead to a dead end. Therefore, an albatross must be in that cell.\r\n4) The remaining cells can be easily filled with the remaining birds.\n\r\nRow 1: albatross, albatross, chickadee, chickadee, penguin\r\nRow 2: finch, magpie, hawk, finch, hawk\r\nRow 3: cardinal, magpie, flamingo, flamingo, penguin\r\nRow 4: cardinal, swan, bunting, bunting, swan", "category": "Logic", "date": "04/01/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n20 cells are arranged in a 5x4 grid. The cells are occupied by 20 birds (10 different birds, a pair (2) of each).\n\r\nThe cells are labeled as follows:\r\nABCDE\r\nFGHIK\r\nLMNOP\r\nRSTUW\n\r\nThe birds are: albatross, bunting, cardinal, chickadee, finch, flamingo, hawk, magpie, penguin, and swan.\n\r\nA bird can only occupy a cell if the cell is labeled with a letter that is in the bird's name. For example, a hawk can only be in cell: H, A, W, or K.\n\r\nEach pair of birds must be in the same row or the same column.\n\r\nWhere are the birds located?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Determine the locations of the swans. The only cells that are in the same row/column are in row 4.\r\n2) Determine the locations of the hawks. One of the cells is eliminated because it is occupied by a swan. The only remaining cells that are in the same row/column are in row 2.\r\n3) Determine the bird that is in row 1 column 2. Placing the bunting in that cell will lead to a dead end. Therefore, an albatross must be in that cell.\r\n4) The remaining cells can be easily filled with the remaining birds.\n\r\nRow 1: albatross, albatross, chickadee, chickadee, penguin\r\nRow 2: finch, magpie, hawk, finch, hawk\r\nRow 3: cardinal, magpie, flamingo, flamingo, penguin\r\nRow 4: cardinal, swan, bunting, bunting, swan\n<|im_start|>answer\n1) Determine the locations of the swans. The only cells that are in the same row/column are in row 4.\r\n2) Determine the locations of the hawks. One of the cells is eliminated because it is occupied by a swan. The only remaining cells that are in the same row/column are in row 2.\r\n3) Determine the bird that is in row 1 column 2. Placing the bunting in that cell will lead to a dead end. Therefore, an albatross must be in that cell.\r\n4) The remaining cells can be easily filled with the remaining birds.\n\r\nRow 1: albatross, albatross, chickadee, chickadee, penguin\r\nRow 2: finch, magpie, hawk, finch, hawk\r\nRow 3: cardinal, magpie, flamingo, flamingo, penguin\r\nRow 4: cardinal, swan, bunting, bunting, swan\n<|im_end|>" }, { "id": "#40940", "title": "Carnival Booth", "fun": 2.54, "difficulty": 1.21, "author": "Carlos16", "desc": "You are at a carnival booth where you need to figure out which door the money is behind.\n\r\nDoor 1 says: The money is behind door 2.\r\nDoor 2 says: The money is not behind door 3.\r\nDoor 3 says: Door 1 is lying.\n\r\nWhich door is the money behind if only one door is telling the truth?", "hint": "No hint available.", "answer": "If door 1 is telling the truth, then the money is behind door 2. That means door 2 is lying, and if door 2 is lying, then the money is behind door 3. The money is only behind one door, so door 1 is lying.\r\nIf door 1 is lying, then door 3 has to be telling the truth. Since only one door is telling the truth, door 2 is lying, which means the money is behind door 3.\n\r\nAnswer: Door 3.", "category": "Logic", "date": "03/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are at a carnival booth where you need to figure out which door the money is behind.\n\r\nDoor 1 says: The money is behind door 2.\r\nDoor 2 says: The money is not behind door 3.\r\nDoor 3 says: Door 1 is lying.\n\r\nWhich door is the money behind if only one door is telling the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf door 1 is telling the truth, then the money is behind door 2. That means door 2 is lying, and if door 2 is lying, then the money is behind door 3. The money is only behind one door, so door 1 is lying.\r\nIf door 1 is lying, then door 3 has to be telling the truth. Since only one door is telling the truth, door 2 is lying, which means the money is behind door 3.\n\r\nAnswer: Door 3.\n<|im_start|>answer\nIf door 1 is telling the truth, then the money is behind door 2. That means door 2 is lying, and if door 2 is lying, then the money is behind door 3. The money is only behind one door, so door 1 is lying.\r\nIf door 1 is lying, then door 3 has to be telling the truth. Since only one door is telling the truth, door 2 is lying, which means the money is behind door 3.\n\r\nAnswer: Door 3.\n<|im_end|>" }, { "id": "#23294", "title": "Exchanged Students", "fun": 2.54, "difficulty": 0.91, "author": "sissy245", "desc": "Five American students are in a foreign exchange program. There are three boys (James, Jacob, and Alex) and two girls (Liz and Melissa). Each student went to a different country (Mexico, Canada, Brazil, China, and Italy) and brought a different musical instrument (Guitar, Harmonica, Sax, Piano, and Flute) with them. Find who went where and who brought what from these facts:\n\r\n1) Liz has been studying Italian and she loves it.\n\r\n2) James loves Chinese food.\n\r\n3) Alex loves Jazz and cannot go long without his instrument.\n\r\n4) Jacob didn't need an extra bag or case for his instrument, as it fit in his pocket.\n\r\n5) Melissa wanted to see the Amazon.\n\r\n6) James had a hard time getting his '64 Strat through security.\n\r\n7) Melissa's case for her instrument lined one side of her suitcase.\n\r\n8) Alex wanted a Spanish feel.\n\r\n9) Liz's family had a baby grand piano.\n\r\n10) Jacob wanted to go back to his French roots, but he didn't want to leave the continent.", "hint": "Where is the Amazon?\r\nWhere is Quebec?", "answer": "James - China - Guitar\n\r\nMelissa - Brazil - Flute\n\r\nAlex - Mexico - Sax\n\r\nLiz - Italy - Piano\n\r\nJacob - Canada - Harmonica", "category": "Logic-Grid", "date": "05/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive American students are in a foreign exchange program. There are three boys (James, Jacob, and Alex) and two girls (Liz and Melissa). Each student went to a different country (Mexico, Canada, Brazil, China, and Italy) and brought a different musical instrument (Guitar, Harmonica, Sax, Piano, and Flute) with them. Find who went where and who brought what from these facts:\n\r\n1) Liz has been studying Italian and she loves it.\n\r\n2) James loves Chinese food.\n\r\n3) Alex loves Jazz and cannot go long without his instrument.\n\r\n4) Jacob didn't need an extra bag or case for his instrument, as it fit in his pocket.\n\r\n5) Melissa wanted to see the Amazon.\n\r\n6) James had a hard time getting his '64 Strat through security.\n\r\n7) Melissa's case for her instrument lined one side of her suitcase.\n\r\n8) Alex wanted a Spanish feel.\n\r\n9) Liz's family had a baby grand piano.\n\r\n10) Jacob wanted to go back to his French roots, but he didn't want to leave the continent.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJames - China - Guitar\n\r\nMelissa - Brazil - Flute\n\r\nAlex - Mexico - Sax\n\r\nLiz - Italy - Piano\n\r\nJacob - Canada - Harmonica\n<|im_start|>answer\nJames - China - Guitar\n\r\nMelissa - Brazil - Flute\n\r\nAlex - Mexico - Sax\n\r\nLiz - Italy - Piano\n\r\nJacob - Canada - Harmonica\n<|im_end|>" }, { "id": "#3600", "title": "Braingle Triathlon", "fun": 2.54, "difficulty": 1.84, "author": "lil_thugsta", "desc": "During the latest round of the Braingle triathlon, Parker was fourth. Adrian is not the oldest, but is older than Duncan, who was not second. The child who was next in age to the youngest, finished second. The child who finished in third place is older than the child who finished first. Antonio is younger than the child who finished in third place. Can you determine who finished where and place the children in order of age?", "hint": "No hint available.", "answer": "Parker, the oldest, finished in last place. Adrian finished in third. Antonio finished in second. Duncan, the youngest finished in first place.", "category": "Logic", "date": "04/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring the latest round of the Braingle triathlon, Parker was fourth. Adrian is not the oldest, but is older than Duncan, who was not second. The child who was next in age to the youngest, finished second. The child who finished in third place is older than the child who finished first. Antonio is younger than the child who finished in third place. Can you determine who finished where and place the children in order of age?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nParker, the oldest, finished in last place. Adrian finished in third. Antonio finished in second. Duncan, the youngest finished in first place.\n<|im_start|>answer\nParker, the oldest, finished in last place. Adrian finished in third. Antonio finished in second. Duncan, the youngest finished in first place.\n<|im_end|>" }, { "id": "#5691", "title": "One Dollar Notes", "fun": 2.54, "difficulty": 1.47, "author": "glennyboy02", "desc": "A popular attraction at an exhibition was a sealed glass box containing 500,000 dollar notes. This was a fundraiser where for $10 a ticket a person could guess how many notes the box contained. At the end of the exhibition, when the seal was broken and the notes counted, there was only $470,000. Mr Koorc was responsible for enclosing the money. When questioned by Mr Ecilop, he said that he had personally counted every note by hand and to be sure, he had counted every note twice by hand during the five day exhibition. He insisted he may have been off by 80 or 90 dollars, but not 30,000! Mr Ecilop insists he is lying and arrests him immediately, but how can he be so sure?", "hint": "No hint available.", "answer": "It wouldn't have been possible to count the notes. Even once by hand and averaging one note per second, it would have taken over a week of nonstop counting.", "category": "Logic", "date": "07/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA popular attraction at an exhibition was a sealed glass box containing 500,000 dollar notes. This was a fundraiser where for $10 a ticket a person could guess how many notes the box contained. At the end of the exhibition, when the seal was broken and the notes counted, there was only $470,000. Mr Koorc was responsible for enclosing the money. When questioned by Mr Ecilop, he said that he had personally counted every note by hand and to be sure, he had counted every note twice by hand during the five day exhibition. He insisted he may have been off by 80 or 90 dollars, but not 30,000! Mr Ecilop insists he is lying and arrests him immediately, but how can he be so sure?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt wouldn't have been possible to count the notes. Even once by hand and averaging one note per second, it would have taken over a week of nonstop counting.\n<|im_start|>answer\nIt wouldn't have been possible to count the notes. Even once by hand and averaging one note per second, it would have taken over a week of nonstop counting.\n<|im_end|>" }, { "id": "#12710", "title": "The Sick Dog and the Flower", "fun": 2.53, "difficulty": 2.67, "author": "kvakk", "desc": "Hi, my name is mister Kvakk. I live in a very big house in the country. Outside my house I have a lot of very big gardens, and it is in one of these gardens my dog (which is also my best friend) lives. But although my dog is just a dog, it has also got the ability to think. And not just that, my dog is a really smart and rational dog too. \n\r\nUnfortunately, the dog is not happy. It is infected by a virus. It feels ill. The doctor says it's a 50% chance that it will die, and a 50% chance that it will be fresh again. \r\nBut in this garden where my dog lives, I have also a lot of plants. Some days ago, I put a new seed in my garden. The seed will grow up to a beautiful, red flower. So delicious will the flower be, that my dog really will want to eat it when it has grown up (yes, my dog eats flowers). But the flower is even more wonderful. If my dog eats this flower, this will kill every virus in it, and the dog will survive. \n\r\nBut this flower is also a very special kind of plant, because it has the ability to think too. And it is completely rational. It knows that my dog will want to eat it one day later. Therefore, the flower has the option to develop a weapon: At any time it may start to develop poison. If my dog is so unlucky to eat a flower full of poison, it will surely die, which, of course, it doesn't want to. So if the flower decides to develop poison, it's best for the dog not to eat it. \r\nBut the poison development is not an easy task to do for the flower. It doesn't want to make poison just to make poison. If it could avoid developing poison, it wouldn't do it. But, of course, the flower would like to live too, and it's better for it to develop poison than to be eaten by the dog. \n\r\nUnfortunately, there is no way for the dog to see or know whether the flower has decided to develop poison or not. Both the dog and the flower know this. The dog knows, however, that the flower is just as rational as itself. The dog knows that the flower has the option to make poison, and the dog knows that the creation of poison is a hard task to do for the flower, and that it will only do it if it can save its life. In the same way, the flower knows that my dog is completely rational. My dog also knows that the flower cares only about itself. Whether the dog dies or not is irrelevant to the flower. No other red flowers will ever grow in this garden. \n\r\nLet's sum up the assumptions: \n\r\n1. The flower is rational and wants to make its own life as good as possible.\r\n2. The flower knows that the dog is rational.\r\n3. The flower doesn't want to die.\r\n4. The flower doesn't care about what will happen to the dog.\r\n5. The flower doesn't want to make poison. It's a hard task to do.\r\n6. But the flower will make poison if that could prevent the dog from eating it.\r\n7. The dog is rational.\r\n8. The dog knows that the flower doesn't care about whether the dog dies or not.\r\n9. The dog doesn't want to die.\r\n10. The dog knows that the flower is rational (there is no uncertainty at this point, it knows it for sure).\r\n11. The dog knows that the flower will make poison if that could prevent the dog from eating it.\r\n12. The dog cannot see or know whether the flower actually makes poison or not.\r\n13. The dog knows that the flower knows that the dog cannot see or know this.\r\n14. If the dog eats a flower without poison it will survive. If it is poisonous it will die.\r\n15. If the dog doesn't eat the flower, it is a 50 % chance that it will die.\n\r\nSo now, the question is: Will the dog eat the flower? Why or why not?", "hint": "Hint 1: \r\nWe know from assumption 5 and 6 that the flower will only develop poison if that could prevent it from being eaten. And we know that the dog knows this (assumptions 10 and 11). It therefore knows how the flower thinks, but it's impossible for the dog to actually see if the flower has produced poison or not. And the flower knows this. \n\r\nHint 2: \r\nSince the dog cannot see whether the flower has developed poison or not, its action must be independent of what the flower actually has done. Should the flower make poison? Remember that the dog knows for sure that the flower is rational. So, the dog should try to think what it would have done if it had been the case that it were the flower.", "answer": "The dog will eat the flower, and because the flower does not develop poison, the dog will survive. (As you can see, the flower was my medicine to the dog!) \n\r\nBut why will the dog eat the flower? \n\r\n1. If the dog does not eat the flower, it's a 50 % chance that it will die \r\n2. Remember further, that the dog cannot see or know whether the flower has actually produced poison or not. So what the dog decides to do is therefore independent of what the flower decides to do. If the dog has decided to eat, the flowers action cannot prevent it, and if the dog has decided not to eat, the flower cannot do any thing about this either. It has only some control over whether the dog will die or not, but it doesn't care about this. \r\n3. The flower knows that the dog cannot know whether it has produced poison or not. Consequently, the flowers choice of action is unimportant for what the dog will do. Poison creation cannot change the action of the dog. \r\n4. We know that the flower will only make poison if it could prevent it from being eaten. But it can't. The only reason the flower could have to make poison was to get revenge over the dog. But we know from assumption 4 that the flower doesn't want revenge. \r\n5. That's why the flower has no reason to make poison. What the dog will do is INDEPENDENT of whether it will create poison or not. \r\n6. The flower has no reason to make poison. Because what the dog decides to do is not dependent of whether it makes poison or not. If the dog should eat it, it will die no matter what it has done. And in that case it is best for it to not make poison, because that will make its life better. In the same way; if the dog will not eat the flower, it will be best for the flower to live a life without poison. \r\n7. It doesn't matter what the dog will do: In any case, the flower will not produce poison \n\r\nOK, this is half of the solution. We now know that the flower will not make poison. And from assumptions 7, 8, 10 and 11 we now that the dog will know this too. The dog can be fairly sure about that the flower will not make poison. This is because the dog knows that the flower is rational, and it knows how the flowers preferences are (assumptions 8 and 11). We know that the flower will not be poisonous if it is rational, and the dog will know this too. Therefore, the dog can eat the flower (and save its life!). \n\r\n8. Because the dog knows that the flower is rational, it can guess how the flower might think. Therefore, it will know that the flower will not be poisonous \r\n9. It can eat the flower. The probability of death will certainly be much higher if it doesn't.", "category": "Logic", "date": "05/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHi, my name is mister Kvakk. I live in a very big house in the country. Outside my house I have a lot of very big gardens, and it is in one of these gardens my dog (which is also my best friend) lives. But although my dog is just a dog, it has also got the ability to think. And not just that, my dog is a really smart and rational dog too. \n\r\nUnfortunately, the dog is not happy. It is infected by a virus. It feels ill. The doctor says it's a 50% chance that it will die, and a 50% chance that it will be fresh again. \r\nBut in this garden where my dog lives, I have also a lot of plants. Some days ago, I put a new seed in my garden. The seed will grow up to a beautiful, red flower. So delicious will the flower be, that my dog really will want to eat it when it has grown up (yes, my dog eats flowers). But the flower is even more wonderful. If my dog eats this flower, this will kill every virus in it, and the dog will survive. \n\r\nBut this flower is also a very special kind of plant, because it has the ability to think too. And it is completely rational. It knows that my dog will want to eat it one day later. Therefore, the flower has the option to develop a weapon: At any time it may start to develop poison. If my dog is so unlucky to eat a flower full of poison, it will surely die, which, of course, it doesn't want to. So if the flower decides to develop poison, it's best for the dog not to eat it. \r\nBut the poison development is not an easy task to do for the flower. It doesn't want to make poison just to make poison. If it could avoid developing poison, it wouldn't do it. But, of course, the flower would like to live too, and it's better for it to develop poison than to be eaten by the dog. \n\r\nUnfortunately, there is no way for the dog to see or know whether the flower has decided to develop poison or not. Both the dog and the flower know this. The dog knows, however, that the flower is just as rational as itself. The dog knows that the flower has the option to make poison, and the dog knows that the creation of poison is a hard task to do for the flower, and that it will only do it if it can save its life. In the same way, the flower knows that my dog is completely rational. My dog also knows that the flower cares only about itself. Whether the dog dies or not is irrelevant to the flower. No other red flowers will ever grow in this garden. \n\r\nLet's sum up the assumptions: \n\r\n1. The flower is rational and wants to make its own life as good as possible.\r\n2. The flower knows that the dog is rational.\r\n3. The flower doesn't want to die.\r\n4. The flower doesn't care about what will happen to the dog.\r\n5. The flower doesn't want to make poison. It's a hard task to do.\r\n6. But the flower will make poison if that could prevent the dog from eating it.\r\n7. The dog is rational.\r\n8. The dog knows that the flower doesn't care about whether the dog dies or not.\r\n9. The dog doesn't want to die.\r\n10. The dog knows that the flower is rational (there is no uncertainty at this point, it knows it for sure).\r\n11. The dog knows that the flower will make poison if that could prevent the dog from eating it.\r\n12. The dog cannot see or know whether the flower actually makes poison or not.\r\n13. The dog knows that the flower knows that the dog cannot see or know this.\r\n14. If the dog eats a flower without poison it will survive. If it is poisonous it will die.\r\n15. If the dog doesn't eat the flower, it is a 50 % chance that it will die.\n\r\nSo now, the question is: Will the dog eat the flower? Why or why not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe dog will eat the flower, and because the flower does not develop poison, the dog will survive. (As you can see, the flower was my medicine to the dog!) \n\r\nBut why will the dog eat the flower? \n\r\n1. If the dog does not eat the flower, it's a 50 % chance that it will die \r\n2. Remember further, that the dog cannot see or know whether the flower has actually produced poison or not. So what the dog decides to do is therefore independent of what the flower decides to do. If the dog has decided to eat, the flowers action cannot prevent it, and if the dog has decided not to eat, the flower cannot do any thing about this either. It has only some control over whether the dog will die or not, but it doesn't care about this. \r\n3. The flower knows that the dog cannot know whether it has produced poison or not. Consequently, the flowers choice of action is unimportant for what the dog will do. Poison creation cannot change the action of the dog. \r\n4. We know that the flower will only make poison if it could prevent it from being eaten. But it can't. The only reason the flower could have to make poison was to get revenge over the dog. But we know from assumption 4 that the flower doesn't want revenge. \r\n5. That's why the flower has no reason to make poison. What the dog will do is INDEPENDENT of whether it will create poison or not. \r\n6. The flower has no reason to make poison. Because what the dog decides to do is not dependent of whether it makes poison or not. If the dog should eat it, it will die no matter what it has done. And in that case it is best for it to not make poison, because that will make its life better. In the same way; if the dog will not eat the flower, it will be best for the flower to live a life without poison. \r\n7. It doesn't matter what the dog will do: In any case, the flower will not produce poison \n\r\nOK, this is half of the solution. We now know that the flower will not make poison. And from assumptions 7, 8, 10 and 11 we now that the dog will know this too. The dog can be fairly sure about that the flower will not make poison. This is because the dog knows that the flower is rational, and it knows how the flowers preferences are (assumptions 8 and 11). We know that the flower will not be poisonous if it is rational, and the dog will know this too. Therefore, the dog can eat the flower (and save its life!). \n\r\n8. Because the dog knows that the flower is rational, it can guess how the flower might think. Therefore, it will know that the flower will not be poisonous \r\n9. It can eat the flower. The probability of death will certainly be much higher if it doesn't.\n<|im_start|>answer\nThe dog will eat the flower, and because the flower does not develop poison, the dog will survive. (As you can see, the flower was my medicine to the dog!) \n\r\nBut why will the dog eat the flower? \n\r\n1. If the dog does not eat the flower, it's a 50 % chance that it will die \r\n2. Remember further, that the dog cannot see or know whether the flower has actually produced poison or not. So what the dog decides to do is therefore independent of what the flower decides to do. If the dog has decided to eat, the flowers action cannot prevent it, and if the dog has decided not to eat, the flower cannot do any thing about this either. It has only some control over whether the dog will die or not, but it doesn't care about this. \r\n3. The flower knows that the dog cannot know whether it has produced poison or not. Consequently, the flowers choice of action is unimportant for what the dog will do. Poison creation cannot change the action of the dog. \r\n4. We know that the flower will only make poison if it could prevent it from being eaten. But it can't. The only reason the flower could have to make poison was to get revenge over the dog. But we know from assumption 4 that the flower doesn't want revenge. \r\n5. That's why the flower has no reason to make poison. What the dog will do is INDEPENDENT of whether it will create poison or not. \r\n6. The flower has no reason to make poison. Because what the dog decides to do is not dependent of whether it makes poison or not. If the dog should eat it, it will die no matter what it has done. And in that case it is best for it to not make poison, because that will make its life better. In the same way; if the dog will not eat the flower, it will be best for the flower to live a life without poison. \r\n7. It doesn't matter what the dog will do: In any case, the flower will not produce poison \n\r\nOK, this is half of the solution. We now know that the flower will not make poison. And from assumptions 7, 8, 10 and 11 we now that the dog will know this too. The dog can be fairly sure about that the flower will not make poison. This is because the dog knows that the flower is rational, and it knows how the flowers preferences are (assumptions 8 and 11). We know that the flower will not be poisonous if it is rational, and the dog will know this too. Therefore, the dog can eat the flower (and save its life!). \n\r\n8. Because the dog knows that the flower is rational, it can guess how the flower might think. Therefore, it will know that the flower will not be poisonous \r\n9. It can eat the flower. The probability of death will certainly be much higher if it doesn't.\n<|im_end|>" }, { "id": "#46513", "title": "Semi-liar", "fun": 2.53, "difficulty": 1.03, "author": "Stack1607", "desc": "There was a criminal mastermind named Dr. Rey. Dr. Rey was very smart and witty to the point of arrogance. He defied everyone by publicly expressing that when he would talk, he would state a true fact and a false statement together.\r\nOne time there was a party. Many criminal masterminds were there, and the talk turned to a very recent case that was very mysterious and popular at that time. It was the case of the very clean murder of John Smith, a highly-ranked agent of the CIA. One of the criminal masterminds present asked Dr. Rey whether he had anything to do with that murder - he said it in a humorous way, of course. Dr. Rey, smiling lightly, said: \"I had nothing to do with that murder. Oh! How time passes, I was 50 on my previous birthday and I'll be 52 on my next\". An undercover agent smiled on hearing that, and a few hours later, Dr. Rey was in prison.\n\r\nWhat was the occasion of the party?", "hint": "No hint available.", "answer": "It was Dr. Rey's birthday.", "category": "Logic", "date": "03/13/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a criminal mastermind named Dr. Rey. Dr. Rey was very smart and witty to the point of arrogance. He defied everyone by publicly expressing that when he would talk, he would state a true fact and a false statement together.\r\nOne time there was a party. Many criminal masterminds were there, and the talk turned to a very recent case that was very mysterious and popular at that time. It was the case of the very clean murder of John Smith, a highly-ranked agent of the CIA. One of the criminal masterminds present asked Dr. Rey whether he had anything to do with that murder - he said it in a humorous way, of course. Dr. Rey, smiling lightly, said: \"I had nothing to do with that murder. Oh! How time passes, I was 50 on my previous birthday and I'll be 52 on my next\". An undercover agent smiled on hearing that, and a few hours later, Dr. Rey was in prison.\n\r\nWhat was the occasion of the party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt was Dr. Rey's birthday.\n<|im_start|>answer\nIt was Dr. Rey's birthday.\n<|im_end|>" }, { "id": "#35982", "title": "Opposites 29", "fun": 2.53, "difficulty": 2.55, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n$ stands for O, W, G, S, or U\r\n& stands for H, L, A, N, or D\r\n# stands for E, F, M, P, or V\r\n* stands for I, O, K, J, or Y\n\r\nThe four letter code word, #$&*, can be translated into two English prefixes that are opposites. What are the two prefixes?", "hint": "It's not a game...", "answer": "Mono and Poly, meaning one and many, not as in the game.", "category": "Logic", "date": "03/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n$ stands for O, W, G, S, or U\r\n& stands for H, L, A, N, or D\r\n# stands for E, F, M, P, or V\r\n* stands for I, O, K, J, or Y\n\r\nThe four letter code word, #$&*, can be translated into two English prefixes that are opposites. What are the two prefixes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMono and Poly, meaning one and many, not as in the game.\n<|im_start|>answer\nMono and Poly, meaning one and many, not as in the game.\n<|im_end|>" }, { "id": "#1334", "title": "Meeting of Four", "fun": 2.53, "difficulty": 2.09, "author": "mrice", "desc": "Every Tuesday at BizCo, Joe, Abby, Bob and Pam get together for a meeting, and each sits on a separate side of a square table.\r\nThere is one employee present from each department of the company.\n\r\n1. Three of the people always drink coffee, and each owns a different color cup, the other person never drinks coffee.\r\n2. The person with the red cup sits across from the person who owns the blue cup.\r\n3. Abby sits to Joe's right, but Pam sits to the left of the marketer.\r\n4. Joe drinks from a yellow cup, and the engineer's cup is blue.\r\n5. The accountant's wife is the sister of the marketer's wife.\r\n6. Sometimes Bob forgets his cup and has to borrow a spare one from Joe.\n\r\nSo, who doesn't drink coffee?", "hint": "No hint available.", "answer": "Pam does not drink coffee!\n\r\nProceeding clockwise around the table are Pam, then Abby the Engineer with her blue cup, then Joe the Accountant with his yellow cup, and then Bob from Marketing with his red cup.", "category": "Logic", "date": "11/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery Tuesday at BizCo, Joe, Abby, Bob and Pam get together for a meeting, and each sits on a separate side of a square table.\r\nThere is one employee present from each department of the company.\n\r\n1. Three of the people always drink coffee, and each owns a different color cup, the other person never drinks coffee.\r\n2. The person with the red cup sits across from the person who owns the blue cup.\r\n3. Abby sits to Joe's right, but Pam sits to the left of the marketer.\r\n4. Joe drinks from a yellow cup, and the engineer's cup is blue.\r\n5. The accountant's wife is the sister of the marketer's wife.\r\n6. Sometimes Bob forgets his cup and has to borrow a spare one from Joe.\n\r\nSo, who doesn't drink coffee?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPam does not drink coffee!\n\r\nProceeding clockwise around the table are Pam, then Abby the Engineer with her blue cup, then Joe the Accountant with his yellow cup, and then Bob from Marketing with his red cup.\n<|im_start|>answer\nPam does not drink coffee!\n\r\nProceeding clockwise around the table are Pam, then Abby the Engineer with her blue cup, then Joe the Accountant with his yellow cup, and then Bob from Marketing with his red cup.\n<|im_end|>" }, { "id": "#3954", "title": "Tightwad on Elm Street", "fun": 2.53, "difficulty": 2.0, "author": "PeaceJo", "desc": "Penny Pyncher is known throughout her Elm Street neighbourhood for her habit of 'borrowing' things from her neighbors and then neglecting to return them. In fact, every weekday last week she appeared at a different neighbour's doorstep to borrow something different (including detergent). Use this info and the clues below to determine what Penny borrowed from each neighbour and on which day she borrowed it.\n\r\n1. Penny asked to borrow the eggs the day before she went to the Avery house, but sometime after she asked for the trash bags.\n\r\n2. Her Friday visit to the Wolceks wasn't for the purpose of borrowing cheese.\n\r\n3. Penny was at the Norris house sometime before Mrs. Simon lent her a loaf of bread.\n\r\n4. She visited the Harkin house on Wednesday.", "hint": "No hint available.", "answer": "Monday - Norris - Trash Bags\r\nTuesday - Simon - Bread\r\nWednesday - Harkin - Eggs\r\nThursday - Avery - Cheese\r\nFriday - Wolcek - Detergent", "category": "Logic", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPenny Pyncher is known throughout her Elm Street neighbourhood for her habit of 'borrowing' things from her neighbors and then neglecting to return them. In fact, every weekday last week she appeared at a different neighbour's doorstep to borrow something different (including detergent). Use this info and the clues below to determine what Penny borrowed from each neighbour and on which day she borrowed it.\n\r\n1. Penny asked to borrow the eggs the day before she went to the Avery house, but sometime after she asked for the trash bags.\n\r\n2. Her Friday visit to the Wolceks wasn't for the purpose of borrowing cheese.\n\r\n3. Penny was at the Norris house sometime before Mrs. Simon lent her a loaf of bread.\n\r\n4. She visited the Harkin house on Wednesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday - Norris - Trash Bags\r\nTuesday - Simon - Bread\r\nWednesday - Harkin - Eggs\r\nThursday - Avery - Cheese\r\nFriday - Wolcek - Detergent\n<|im_start|>answer\nMonday - Norris - Trash Bags\r\nTuesday - Simon - Bread\r\nWednesday - Harkin - Eggs\r\nThursday - Avery - Cheese\r\nFriday - Wolcek - Detergent\n<|im_end|>" }, { "id": "#24091", "title": "The Perfunctory Professor", "fun": 2.53, "difficulty": 1.17, "author": "buttons03", "desc": "The band teacher at the Perspicacious School for the Magnanimous Musicians has misplaced her lesson schedule! Help Professor Perfunctory figure out what each student plays and what day they are coming for a lesson, based on the information that she can remember.\n\r\nElla has gymnastics practice on Tuesdays and Thursdays.\n\r\nThe Oboe player has lessons on Wednesdays.\n\r\nRobyn plays an instrument with a reed.\n\r\nGail plays the only brass instrument.\n\r\nElecia does not have lessons on Mondays.\n\r\nStudents who play a reeded instrument come on Tuesdays and Wednesdays.\n\r\nElla's instrument is held sideways.\n\r\nElecia's instrument is a double reed.", "hint": "No hint available.", "answer": "Ella plays the Flute and comes on Mondays.\n\r\nElecia plays the Oboe and comes on Wednesdays.\n\r\nRobyn plays the Saxophone and comes on Tuesdays.\n\r\nGail plays the Trumpet and comes on Thursdays.", "category": "Logic-Grid", "date": "06/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe band teacher at the Perspicacious School for the Magnanimous Musicians has misplaced her lesson schedule! Help Professor Perfunctory figure out what each student plays and what day they are coming for a lesson, based on the information that she can remember.\n\r\nElla has gymnastics practice on Tuesdays and Thursdays.\n\r\nThe Oboe player has lessons on Wednesdays.\n\r\nRobyn plays an instrument with a reed.\n\r\nGail plays the only brass instrument.\n\r\nElecia does not have lessons on Mondays.\n\r\nStudents who play a reeded instrument come on Tuesdays and Wednesdays.\n\r\nElla's instrument is held sideways.\n\r\nElecia's instrument is a double reed.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nElla plays the Flute and comes on Mondays.\n\r\nElecia plays the Oboe and comes on Wednesdays.\n\r\nRobyn plays the Saxophone and comes on Tuesdays.\n\r\nGail plays the Trumpet and comes on Thursdays.\n<|im_start|>answer\nElla plays the Flute and comes on Mondays.\n\r\nElecia plays the Oboe and comes on Wednesdays.\n\r\nRobyn plays the Saxophone and comes on Tuesdays.\n\r\nGail plays the Trumpet and comes on Thursdays.\n<|im_end|>" }, { "id": "#36852", "title": "Twin Trouble 2", "fun": 2.53, "difficulty": 1.74, "author": "reptile5000", "desc": "Mo and Joe are twins. They were born on January 1st in New York, at noon.Their births were normal, with no problems. Mo was born in 2006 and Joe was born in 2007. How?", "hint": "No hint available.", "answer": "Mo and Joe were both twins, but not siblings. They didn't have the same mother.", "category": "Logic", "date": "06/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMo and Joe are twins. They were born on January 1st in New York, at noon.Their births were normal, with no problems. Mo was born in 2006 and Joe was born in 2007. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMo and Joe were both twins, but not siblings. They didn't have the same mother.\n<|im_start|>answer\nMo and Joe were both twins, but not siblings. They didn't have the same mother.\n<|im_end|>" }, { "id": "#24738", "title": "Rubber Band Walking", "fun": 2.53, "difficulty": 2.77, "author": "phrebh", "desc": "There is a rubber band that is looped around an immovable steel rod. It is three inches long. At the fixed end is a spider. He starts walking along the rubber band at the rate of one inch per minute. \n\r\nA minute after he started, the rubber band is stretched by three inches. The spider continues walking on it at the same rate. \n\r\nIn another minute, the rubber band is stretched another three inches. \n\r\nThis keeps going on until the spider reaches the end of the rubber band. How long did it take the spider to reach the end?", "hint": "The spider's position is not changed when the rubber band is stretched, but the total distance of travel does change.", "answer": "10.781355 minutes.\n\r\nThe following shows the lengths of the rubber band, the time in minutes, and the distance traveled by the spider.\n\r\n3, 0, 0\r\n6, 1, 2\r\n9, 2, 4.5\r\n12, 3, 7.333333\r\n15, 4, 10.41667\r\n18, 5, 13.7\r\n21, 6, 17.15\r\n24, 7, 20.74286\r\n27, 8, 24.46071\r\n30, 9, 28.28968\r\n33, 10, 32.21865\r\n36, 10.781355, 36", "category": "Math", "date": "07/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a rubber band that is looped around an immovable steel rod. It is three inches long. At the fixed end is a spider. He starts walking along the rubber band at the rate of one inch per minute. \n\r\nA minute after he started, the rubber band is stretched by three inches. The spider continues walking on it at the same rate. \n\r\nIn another minute, the rubber band is stretched another three inches. \n\r\nThis keeps going on until the spider reaches the end of the rubber band. How long did it take the spider to reach the end?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10.781355 minutes.\n\r\nThe following shows the lengths of the rubber band, the time in minutes, and the distance traveled by the spider.\n\r\n3, 0, 0\r\n6, 1, 2\r\n9, 2, 4.5\r\n12, 3, 7.333333\r\n15, 4, 10.41667\r\n18, 5, 13.7\r\n21, 6, 17.15\r\n24, 7, 20.74286\r\n27, 8, 24.46071\r\n30, 9, 28.28968\r\n33, 10, 32.21865\r\n36, 10.781355, 36\n<|im_start|>answer\n10.781355 minutes.\n\r\nThe following shows the lengths of the rubber band, the time in minutes, and the distance traveled by the spider.\n\r\n3, 0, 0\r\n6, 1, 2\r\n9, 2, 4.5\r\n12, 3, 7.333333\r\n15, 4, 10.41667\r\n18, 5, 13.7\r\n21, 6, 17.15\r\n24, 7, 20.74286\r\n27, 8, 24.46071\r\n30, 9, 28.28968\r\n33, 10, 32.21865\r\n36, 10.781355, 36\n<|im_end|>" }, { "id": "#33301", "title": "CAB+BAT=CAT?", "fun": 2.53, "difficulty": 2.24, "author": "koma", "desc": "When does CAB + BAT = CAT?", "hint": "Think geometry.", "answer": "When CAB, BAT, and CAT are angles. \n\r\nIf angle CAB and angle BAT are adjacent, with A as the vertex, then the outer rays will form angle CAT.", "category": "Math", "date": "10/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen does CAB + BAT = CAT?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen CAB, BAT, and CAT are angles. \n\r\nIf angle CAB and angle BAT are adjacent, with A as the vertex, then the outer rays will form angle CAT.\n<|im_start|>answer\nWhen CAB, BAT, and CAT are angles. \n\r\nIf angle CAB and angle BAT are adjacent, with A as the vertex, then the outer rays will form angle CAT.\n<|im_end|>" }, { "id": "#36721", "title": "1 = 10?", "fun": 2.53, "difficulty": 1.23, "author": "tedger", "desc": "What can you add to both 1 and 10 to make them equal?", "hint": "No hint available.", "answer": "A decimal point.\n\r\nAdding a \".\" makes each a decimal (.1 and .10 which are equal).", "category": "Logic", "date": "05/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat can you add to both 1 and 10 to make them equal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA decimal point.\n\r\nAdding a \".\" makes each a decimal (.1 and .10 which are equal).\n<|im_start|>answer\nA decimal point.\n\r\nAdding a \".\" makes each a decimal (.1 and .10 which are equal).\n<|im_end|>" }, { "id": "#36367", "title": "Pet Names and Owners", "fun": 2.53, "difficulty": 0.84, "author": "merrypippin246", "desc": "People: Mary, John, and Luke\r\nPets: Cat, Dog, and Bird\r\nPet Names: Jake, Buffy, Brownie\n\r\nUse these clues to decide who owns which pet, and what the pet's name is.\n\r\n1) John's pet's name is Jake.\r\n2) Brownie is the name of a bird.\r\n3) Mary has a dog.\r\n4) Jake is the name of a cat.", "hint": "No hint available.", "answer": "Mary has a dog named Buffy.\r\nLuke has a bird named Brownie.\r\nJohn has a cat named Jake.", "category": "Logic", "date": "04/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPeople: Mary, John, and Luke\r\nPets: Cat, Dog, and Bird\r\nPet Names: Jake, Buffy, Brownie\n\r\nUse these clues to decide who owns which pet, and what the pet's name is.\n\r\n1) John's pet's name is Jake.\r\n2) Brownie is the name of a bird.\r\n3) Mary has a dog.\r\n4) Jake is the name of a cat.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary has a dog named Buffy.\r\nLuke has a bird named Brownie.\r\nJohn has a cat named Jake.\n<|im_start|>answer\nMary has a dog named Buffy.\r\nLuke has a bird named Brownie.\r\nJohn has a cat named Jake.\n<|im_end|>" }, { "id": "#27358", "title": "Postman", "fun": 2.53, "difficulty": 2.77, "author": "shenqiang", "desc": "A postman delivered letters every day. On the first day he delivered one letter, on the second day he delivered three letters, on the third day he delivered five letters, and so on. Each day from the second on he delivered two letters more than the preceding day.\n\r\nThe day he retired, he noticed that he had delivered a total of more than 100,000 letters. \n\r\nSomething fun is that the total number of letters he had delivered has its digits arranged in ascending order.\n\r\nHow many days had he worked, and how many letters had he delivered in total?", "hint": "The number of days he had worked also has its digits arranged in ascending order.", "answer": "It's easy to see that the number of letters he had delivered is the square of the number of days he had worked.\n\r\nSquare numbers can't end in 7 or 8, and 123456 is not a square because it is divisible by 3 but not by 9. Hence the number of letters must end with 9.\n\r\nSince odd squares have remainder 1 upon division by 8, the number formed by its fourth and fifth digits must be divisible by 4, which can be 48, 56 or 68.\n\r\nNumbers that have remainder 2 upon division by 3, and those that are divisible by 3 but not by 9 are not squares. By trial and error, we know that the only square number satisfying these conditions is 134689=367^2.\n\r\nHence, he had worked for 367 days, and had delivered 134689 letters.", "category": "Math", "date": "12/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA postman delivered letters every day. On the first day he delivered one letter, on the second day he delivered three letters, on the third day he delivered five letters, and so on. Each day from the second on he delivered two letters more than the preceding day.\n\r\nThe day he retired, he noticed that he had delivered a total of more than 100,000 letters. \n\r\nSomething fun is that the total number of letters he had delivered has its digits arranged in ascending order.\n\r\nHow many days had he worked, and how many letters had he delivered in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's easy to see that the number of letters he had delivered is the square of the number of days he had worked.\n\r\nSquare numbers can't end in 7 or 8, and 123456 is not a square because it is divisible by 3 but not by 9. Hence the number of letters must end with 9.\n\r\nSince odd squares have remainder 1 upon division by 8, the number formed by its fourth and fifth digits must be divisible by 4, which can be 48, 56 or 68.\n\r\nNumbers that have remainder 2 upon division by 3, and those that are divisible by 3 but not by 9 are not squares. By trial and error, we know that the only square number satisfying these conditions is 134689=367^2.\n\r\nHence, he had worked for 367 days, and had delivered 134689 letters.\n<|im_start|>answer\nIt's easy to see that the number of letters he had delivered is the square of the number of days he had worked.\n\r\nSquare numbers can't end in 7 or 8, and 123456 is not a square because it is divisible by 3 but not by 9. Hence the number of letters must end with 9.\n\r\nSince odd squares have remainder 1 upon division by 8, the number formed by its fourth and fifth digits must be divisible by 4, which can be 48, 56 or 68.\n\r\nNumbers that have remainder 2 upon division by 3, and those that are divisible by 3 but not by 9 are not squares. By trial and error, we know that the only square number satisfying these conditions is 134689=367^2.\n\r\nHence, he had worked for 367 days, and had delivered 134689 letters.\n<|im_end|>" }, { "id": "#29167", "title": "Snog Challenge", "fun": 2.53, "difficulty": 2.61, "author": "----", "desc": "These numbers are snogs:\n\r\n 25 73\r\n 81 9 33\r\n 41 65\n\r\nThese numbers are NOT snogs:\n\r\n 5 70 16\r\n 3 29 44\r\n 59 60 64\n\r\nWhich of these numbers are snogs?\n\r\n 48 57 37 17\r\n 53 49 62\r\n 8 4 18", "hint": "Snogs are one more than...", "answer": "The numbers 17, 49, and 57 are snogs.\n\r\nSnogs are each one more than a multiple of 8.", "category": "Math", "date": "03/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThese numbers are snogs:\n\r\n 25 73\r\n 81 9 33\r\n 41 65\n\r\nThese numbers are NOT snogs:\n\r\n 5 70 16\r\n 3 29 44\r\n 59 60 64\n\r\nWhich of these numbers are snogs?\n\r\n 48 57 37 17\r\n 53 49 62\r\n 8 4 18\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers 17, 49, and 57 are snogs.\n\r\nSnogs are each one more than a multiple of 8.\n<|im_start|>answer\nThe numbers 17, 49, and 57 are snogs.\n\r\nSnogs are each one more than a multiple of 8.\n<|im_end|>" }, { "id": "#29459", "title": "Winning Record", "fun": 2.53, "difficulty": 2.11, "author": "____", "desc": "Chanelle has won 429 games and lost 431 games of her favorite computer card game.\n\r\nIf she wins 3 out of every 4 games she plays from now on, how many more games must she play to bring her total winning percentage up to 55%?", "hint": "Guess and check and keep track of the number of games won, games lost, and total games played. Better still, use a variable to represent the number of extra games Chanelle must play.", "answer": "Chanelle must play 220 more games. In these 220 games she wins 3 out of every 4 games, bringing her total of games won to 594 out of 1,080 played (or, 55%).", "category": "Math", "date": "03/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChanelle has won 429 games and lost 431 games of her favorite computer card game.\n\r\nIf she wins 3 out of every 4 games she plays from now on, how many more games must she play to bring her total winning percentage up to 55%?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChanelle must play 220 more games. In these 220 games she wins 3 out of every 4 games, bringing her total of games won to 594 out of 1,080 played (or, 55%).\n<|im_start|>answer\nChanelle must play 220 more games. In these 220 games she wins 3 out of every 4 games, bringing her total of games won to 594 out of 1,080 played (or, 55%).\n<|im_end|>" }, { "id": "#38138", "title": "Eat a Sheep", "fun": 2.53, "difficulty": 2.34, "author": "lips", "desc": "A lion takes 4 hours to eat one sheep, a leopard takes 5 hours and a bear takes 6. If a single sheep was thrown to them, how long would they take to devour it?", "hint": "No hint available.", "answer": "60/37 hours (about 1.6 hours). In one hour a lion eats 1/4 of a sheep, a leopard eats 1/5 and a bear 1/6. So in one hour combined they eat 1/4 + 1/5 + 1/6 sheep. Therefore one sheep will take 1 / (1/4 + 1/5 + 1/6) hours = 60/37.", "category": "Math", "date": "09/06/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA lion takes 4 hours to eat one sheep, a leopard takes 5 hours and a bear takes 6. If a single sheep was thrown to them, how long would they take to devour it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n60/37 hours (about 1.6 hours). In one hour a lion eats 1/4 of a sheep, a leopard eats 1/5 and a bear 1/6. So in one hour combined they eat 1/4 + 1/5 + 1/6 sheep. Therefore one sheep will take 1 / (1/4 + 1/5 + 1/6) hours = 60/37.\n<|im_start|>answer\n60/37 hours (about 1.6 hours). In one hour a lion eats 1/4 of a sheep, a leopard eats 1/5 and a bear 1/6. So in one hour combined they eat 1/4 + 1/5 + 1/6 sheep. Therefore one sheep will take 1 / (1/4 + 1/5 + 1/6) hours = 60/37.\n<|im_end|>" }, { "id": "#3449", "title": "Water in the Desert", "fun": 2.53, "difficulty": 1.14, "author": "Mogmatt16", "desc": "Two men have planned a trip across the desert and back. The day before, they tie a barrel with all the water they'll need to their donkey. They go to sleep. At 11:30 p.m. the first wife gets up and puts a small hole in the bottom of the barrel, calculating that at its rate of coming out, the men will have no water left on the way back. At 1:30 a.m. the second of the men's wife gets up. She sneaks out and poisons the water in the barrel to kill the men and goes back to sleep. Sure enough, along the trip they die. Who is guilty of murder?", "hint": "No hint available.", "answer": "Although they are both guilty of attempted murder, the wife who poisoned the water is guilty because they drank that first and died of it before all the tainted water leaked out.", "category": "Logic", "date": "04/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo men have planned a trip across the desert and back. The day before, they tie a barrel with all the water they'll need to their donkey. They go to sleep. At 11:30 p.m. the first wife gets up and puts a small hole in the bottom of the barrel, calculating that at its rate of coming out, the men will have no water left on the way back. At 1:30 a.m. the second of the men's wife gets up. She sneaks out and poisons the water in the barrel to kill the men and goes back to sleep. Sure enough, along the trip they die. Who is guilty of murder?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlthough they are both guilty of attempted murder, the wife who poisoned the water is guilty because they drank that first and died of it before all the tainted water leaked out.\n<|im_start|>answer\nAlthough they are both guilty of attempted murder, the wife who poisoned the water is guilty because they drank that first and died of it before all the tainted water leaked out.\n<|im_end|>" }, { "id": "#45100", "title": "Tina's Pets", "fun": 2.53, "difficulty": 0.98, "author": "nogoodnames", "desc": "Tina has a large collection of pets. 1/3 of them are cats, 1/4 of them are dogs, 1/5 are hamsters and the rest are goldfish. If Tina has 39 goldfish, how many pets in total does she have?", "hint": "No hint available.", "answer": "She has 180 pets in total.\n\r\nCats + Dogs + Hamsters = 1/3 + 1/4 + 1/5 = 47/60.\r\nRemainder = 13/60 = Number of Goldfish.\r\nIf 13/60 = 39, total number of animals = (39x60)/13 = 180.\n\r\nIn other words, 13/60 of Tina's pets are goldfish and because she has 39 goldfish, 39/13 = 3, so 1/60 = 3, 3x60 = 180, so 180 pets in total and the equation will look like, 20/60 + 15/60 + 12/60 + 13/60 = 60/60, or 1.", "category": "Math", "date": "08/19/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTina has a large collection of pets. 1/3 of them are cats, 1/4 of them are dogs, 1/5 are hamsters and the rest are goldfish. If Tina has 39 goldfish, how many pets in total does she have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe has 180 pets in total.\n\r\nCats + Dogs + Hamsters = 1/3 + 1/4 + 1/5 = 47/60.\r\nRemainder = 13/60 = Number of Goldfish.\r\nIf 13/60 = 39, total number of animals = (39x60)/13 = 180.\n\r\nIn other words, 13/60 of Tina's pets are goldfish and because she has 39 goldfish, 39/13 = 3, so 1/60 = 3, 3x60 = 180, so 180 pets in total and the equation will look like, 20/60 + 15/60 + 12/60 + 13/60 = 60/60, or 1.\n<|im_start|>answer\nShe has 180 pets in total.\n\r\nCats + Dogs + Hamsters = 1/3 + 1/4 + 1/5 = 47/60.\r\nRemainder = 13/60 = Number of Goldfish.\r\nIf 13/60 = 39, total number of animals = (39x60)/13 = 180.\n\r\nIn other words, 13/60 of Tina's pets are goldfish and because she has 39 goldfish, 39/13 = 3, so 1/60 = 3, 3x60 = 180, so 180 pets in total and the equation will look like, 20/60 + 15/60 + 12/60 + 13/60 = 60/60, or 1.\n<|im_end|>" }, { "id": "#7604", "title": "Penultimate Frisbee", "fun": 2.53, "difficulty": 2.92, "author": "dewtell", "desc": "The game of penultimate frisbee has two scoring moves: the bungee and the wedgie.\r\nEach type of score is worth an odd prime number of points, with a bungee being worth more than a wedgie. If the largest score that can never be achieved in a game is 95 points (no matter how long the game lasts), how many points is each move worth?", "hint": "If the two moves are worth p and q, the largest score that can not be\r\nachieved by some combination of bungees and wedgies is p*q-p-q.", "answer": "The bungee is worth 17 points, and the wedgie is worth 7.\n\r\nThe largest score that can not be achieved by some combination of p and q points, with p relatively prime to q, is p*q-p-q = (p-1)*(q-1)-1. \r\nSo 96 must be factorable as (p-1)*(q-1), for odd primes p and q.\r\nSince the prime factorization of 96 = 2^5*3, and each of the two\r\nfactors must be even, the possible factorizations are:\r\n2*48\r\n4*24\r\n8*12\r\n16*6\n\r\nOnly the last factorization yields two factors each of which is one less\r\nthan an odd prime, so 17 and 7 must be the two primes we seek.", "category": "Math", "date": "09/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe game of penultimate frisbee has two scoring moves: the bungee and the wedgie.\r\nEach type of score is worth an odd prime number of points, with a bungee being worth more than a wedgie. If the largest score that can never be achieved in a game is 95 points (no matter how long the game lasts), how many points is each move worth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe bungee is worth 17 points, and the wedgie is worth 7.\n\r\nThe largest score that can not be achieved by some combination of p and q points, with p relatively prime to q, is p*q-p-q = (p-1)*(q-1)-1. \r\nSo 96 must be factorable as (p-1)*(q-1), for odd primes p and q.\r\nSince the prime factorization of 96 = 2^5*3, and each of the two\r\nfactors must be even, the possible factorizations are:\r\n2*48\r\n4*24\r\n8*12\r\n16*6\n\r\nOnly the last factorization yields two factors each of which is one less\r\nthan an odd prime, so 17 and 7 must be the two primes we seek.\n<|im_start|>answer\nThe bungee is worth 17 points, and the wedgie is worth 7.\n\r\nThe largest score that can not be achieved by some combination of p and q points, with p relatively prime to q, is p*q-p-q = (p-1)*(q-1)-1. \r\nSo 96 must be factorable as (p-1)*(q-1), for odd primes p and q.\r\nSince the prime factorization of 96 = 2^5*3, and each of the two\r\nfactors must be even, the possible factorizations are:\r\n2*48\r\n4*24\r\n8*12\r\n16*6\n\r\nOnly the last factorization yields two factors each of which is one less\r\nthan an odd prime, so 17 and 7 must be the two primes we seek.\n<|im_end|>" }, { "id": "#7189", "title": "One Half", "fun": 2.53, "difficulty": 2.78, "author": "im_para_noid", "desc": "Arrange the digits 0, 1, 2, 2, 3, 4, 4, 5, 6, and 9, to form a single fraction that equals 1/2. (Here is one example that, alas, turns out not to be true: 32145/24690=1/2)", "hint": "No hint available.", "answer": "One solution: 12345/24690=1/2", "category": "Math", "date": "09/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the digits 0, 1, 2, 2, 3, 4, 4, 5, 6, and 9, to form a single fraction that equals 1/2. (Here is one example that, alas, turns out not to be true: 32145/24690=1/2)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne solution: 12345/24690=1/2\n<|im_start|>answer\nOne solution: 12345/24690=1/2\n<|im_end|>" }, { "id": "#5895", "title": "4 Grades", "fun": 2.53, "difficulty": 2.36, "author": "Bintot", "desc": "Just before the end of the term four high school students were discussing their chances for certain grades. The following remarks contain the gist of their hopes and fears.\n\r\nJack: We'll all get different grades. If I get an A, then Lucy will get a D.\r\nJean: If Lucy gets a C, then Jack will get a D. Jack will get a better grade than Paul.\r\nLucy: If Jean doesn't get an A, then Jack will get a C. If I get a B, then Paul won't get a D.\r\nPaul: If Lucy gets an A, then I'll get a B. if Jean doesn't get a B, I won't either.\r\nWhen the final examinations were graded and the term marks made out each of the four passed, and strange as it may seem, each received a grade that checked exactly with all the ideas they had previously expressed.\n\r\nWhat grade did each receive?", "hint": "No hint available.", "answer": "Jack, Jean, Lucy, and Paul received B, A, D, and C, respectively.", "category": "Logic", "date": "07/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJust before the end of the term four high school students were discussing their chances for certain grades. The following remarks contain the gist of their hopes and fears.\n\r\nJack: We'll all get different grades. If I get an A, then Lucy will get a D.\r\nJean: If Lucy gets a C, then Jack will get a D. Jack will get a better grade than Paul.\r\nLucy: If Jean doesn't get an A, then Jack will get a C. If I get a B, then Paul won't get a D.\r\nPaul: If Lucy gets an A, then I'll get a B. if Jean doesn't get a B, I won't either.\r\nWhen the final examinations were graded and the term marks made out each of the four passed, and strange as it may seem, each received a grade that checked exactly with all the ideas they had previously expressed.\n\r\nWhat grade did each receive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJack, Jean, Lucy, and Paul received B, A, D, and C, respectively.\n<|im_start|>answer\nJack, Jean, Lucy, and Paul received B, A, D, and C, respectively.\n<|im_end|>" }, { "id": "#5152", "title": "The Electricity Shop", "fun": 2.53, "difficulty": 1.8, "author": "GAZZA30", "desc": "Gazza went to the electricity shop to get stuff for his new house. He needed 5 items - a stereo, a cooker, a TV, a washing machine and a tumble dryer. Each item was priced exactly to the pound and no two items cost the same. If Gazza had only 349 pounds to spend what is the maximum price of the cheapest item?", "hint": "No hint available.", "answer": "67 pounds - items were priced at 67/68/69/70/71 total 345 pounds as if it were 68/69/70/71/72 the total price would be 350 pounds and Gazza could not afford it!", "category": "Math", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGazza went to the electricity shop to get stuff for his new house. He needed 5 items - a stereo, a cooker, a TV, a washing machine and a tumble dryer. Each item was priced exactly to the pound and no two items cost the same. If Gazza had only 349 pounds to spend what is the maximum price of the cheapest item?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n67 pounds - items were priced at 67/68/69/70/71 total 345 pounds as if it were 68/69/70/71/72 the total price would be 350 pounds and Gazza could not afford it!\n<|im_start|>answer\n67 pounds - items were priced at 67/68/69/70/71 total 345 pounds as if it were 68/69/70/71/72 the total price would be 350 pounds and Gazza could not afford it!\n<|im_end|>" }, { "id": "#36278", "title": "Placings", "fun": 2.53, "difficulty": 2.48, "author": "flowers2234", "desc": "List the order in which each person finished.\n\r\nTommy Tombstone finished after Lance Lamers and Brett Brown but before Mitch Monday. \r\nPeter Poultry finished before Daniel Dusk and Lance Lamers. \r\nSam Sunny finished after Peter Poultry and before Jack Jill and Harry Hills. \r\nKeri Kernel finished after Peter Poultry, Mitch Monday and Tommy Tombstone. \r\nLance Lamers finished after Brett Brown and Daniel Dusk, but before Jack Jill and Mitch Monday. \r\nMitch Monday finished after Sam Sunny and Brett Brown. \r\nBrett Brown finished before Jack Jill, Mitch Monday and Peter Poultry. \r\nDaniel Dusk finished before Keri Kernel and Tommy Tombstone, but after Sam Sunny. \r\nJack Jill finished before Keri Kernel, Tommy Tombstone and Mitch Monday, but after Peter Poultry and Daniel Dusk. \r\nHarry Hills finished before Mitch Monday but after Lance Lamers, Jack Jill and Tommy Tombstone.", "hint": "No hint available.", "answer": "1.Brett Brown\r\n2.Peter Poultry\r\n3.Sam Sunny\r\n4.Daniel Dusk\r\n5.Lance Lamers\r\n6.Jack Jill\r\n7.Tommy Tombstone \r\n8.Harry Hills\r\n9.Mitch Monday\r\n10.Keri Kernel", "category": "Logic", "date": "04/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nList the order in which each person finished.\n\r\nTommy Tombstone finished after Lance Lamers and Brett Brown but before Mitch Monday. \r\nPeter Poultry finished before Daniel Dusk and Lance Lamers. \r\nSam Sunny finished after Peter Poultry and before Jack Jill and Harry Hills. \r\nKeri Kernel finished after Peter Poultry, Mitch Monday and Tommy Tombstone. \r\nLance Lamers finished after Brett Brown and Daniel Dusk, but before Jack Jill and Mitch Monday. \r\nMitch Monday finished after Sam Sunny and Brett Brown. \r\nBrett Brown finished before Jack Jill, Mitch Monday and Peter Poultry. \r\nDaniel Dusk finished before Keri Kernel and Tommy Tombstone, but after Sam Sunny. \r\nJack Jill finished before Keri Kernel, Tommy Tombstone and Mitch Monday, but after Peter Poultry and Daniel Dusk. \r\nHarry Hills finished before Mitch Monday but after Lance Lamers, Jack Jill and Tommy Tombstone.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1.Brett Brown\r\n2.Peter Poultry\r\n3.Sam Sunny\r\n4.Daniel Dusk\r\n5.Lance Lamers\r\n6.Jack Jill\r\n7.Tommy Tombstone \r\n8.Harry Hills\r\n9.Mitch Monday\r\n10.Keri Kernel\n<|im_start|>answer\n1.Brett Brown\r\n2.Peter Poultry\r\n3.Sam Sunny\r\n4.Daniel Dusk\r\n5.Lance Lamers\r\n6.Jack Jill\r\n7.Tommy Tombstone \r\n8.Harry Hills\r\n9.Mitch Monday\r\n10.Keri Kernel\n<|im_end|>" }, { "id": "#7031", "title": "Dinner party", "fun": 2.53, "difficulty": 1.48, "author": "Galadriel", "desc": "Yesterday I sat at the table with the butcher, the baker and the grocer.\r\nI sat to the left of Frank.\r\nPeter sat to the right of the butcher.\r\nIf Steve, who sat across from Frank, isn't the baker, then who sells groceries?", "hint": "No hint available.", "answer": "Steve\n\r\nFrom the second statement, we know that \"I\" (you) sat to the left of Frank.\r\nThe fourth statement states that Steve sat across from Frank. This leaves Peter sitting across from you, and therefore to the right of Frank. Frank is therefore the butcher, from statement three.\r\nIf Steve isn't the baker (statement four), then Peter must be the baker, leaving Steve to be the grocer.", "category": "Logic", "date": "08/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYesterday I sat at the table with the butcher, the baker and the grocer.\r\nI sat to the left of Frank.\r\nPeter sat to the right of the butcher.\r\nIf Steve, who sat across from Frank, isn't the baker, then who sells groceries?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSteve\n\r\nFrom the second statement, we know that \"I\" (you) sat to the left of Frank.\r\nThe fourth statement states that Steve sat across from Frank. This leaves Peter sitting across from you, and therefore to the right of Frank. Frank is therefore the butcher, from statement three.\r\nIf Steve isn't the baker (statement four), then Peter must be the baker, leaving Steve to be the grocer.\n<|im_start|>answer\nSteve\n\r\nFrom the second statement, we know that \"I\" (you) sat to the left of Frank.\r\nThe fourth statement states that Steve sat across from Frank. This leaves Peter sitting across from you, and therefore to the right of Frank. Frank is therefore the butcher, from statement three.\r\nIf Steve isn't the baker (statement four), then Peter must be the baker, leaving Steve to be the grocer.\n<|im_end|>" }, { "id": "#4037", "title": "Boy and Girl", "fun": 2.53, "difficulty": 1.01, "author": "librashorty", "desc": "There is a girl behind each boy, and a boy behind each girl. How many children are needed to do this?", "hint": "No hint available.", "answer": "It can be done with just two children: only one boy and one girl are needed if they stand back to back!", "category": "Logic", "date": "05/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a girl behind each boy, and a boy behind each girl. How many children are needed to do this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt can be done with just two children: only one boy and one girl are needed if they stand back to back!\n<|im_start|>answer\nIt can be done with just two children: only one boy and one girl are needed if they stand back to back!\n<|im_end|>" }, { "id": "#42973", "title": "The Card Collector", "fun": 2.53, "difficulty": 2.13, "author": "donquixote235", "desc": "Philpot Nerdling collects baseball cards and keeps them in a three-ring binder. Rather than regular pages made of paper, the binder contains plastic sleeves that are large enough to hold nine cards per page, arranged in a 3x3 grid. Cards numbered 1 through 9 are on the first page, 10 through 18 on the second page, and so forth.\n\r\nPhilpot has just started collecting for this season, and the first card he finds is numbered \"258\". Philpot managed to locate the proper page, but couldn't remember which of the nine spaces should contain the card.\n\r\nWithout using division or subtraction, can you help him locate the right space?", "hint": "No hint available.", "answer": "The card should go in the sixth spot. Adding all the digits of a 10-base number together will give you a number from 1 to 9, which corresponds to the lowest digit in the 9-base system to which you're converting.\n\r\nIn other words, 2+5+8 = 15, and 1+5 = 6. The card goes in the sixth spot.", "category": "Math", "date": "09/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPhilpot Nerdling collects baseball cards and keeps them in a three-ring binder. Rather than regular pages made of paper, the binder contains plastic sleeves that are large enough to hold nine cards per page, arranged in a 3x3 grid. Cards numbered 1 through 9 are on the first page, 10 through 18 on the second page, and so forth.\n\r\nPhilpot has just started collecting for this season, and the first card he finds is numbered \"258\". Philpot managed to locate the proper page, but couldn't remember which of the nine spaces should contain the card.\n\r\nWithout using division or subtraction, can you help him locate the right space?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe card should go in the sixth spot. Adding all the digits of a 10-base number together will give you a number from 1 to 9, which corresponds to the lowest digit in the 9-base system to which you're converting.\n\r\nIn other words, 2+5+8 = 15, and 1+5 = 6. The card goes in the sixth spot.\n<|im_start|>answer\nThe card should go in the sixth spot. Adding all the digits of a 10-base number together will give you a number from 1 to 9, which corresponds to the lowest digit in the 9-base system to which you're converting.\n\r\nIn other words, 2+5+8 = 15, and 1+5 = 6. The card goes in the sixth spot.\n<|im_end|>" }, { "id": "#9253", "title": "Going Shopping", "fun": 2.53, "difficulty": 1.72, "author": "bluetwo", "desc": "Three ladies (Ann, Julie, and Karen) managed to persuade their respective husbands (Lee, Ian, and David) to go shopping with them one Saturday morning. Between them, they purchased a watch, a kettle, and records and spent $10, $11, and $12. \n\r\nUsing the clues below, can you work out who is married to whom and say which item each couple bought and how much they paid for it? \n\r\n-The item purchased by Ann and David was more expensive than the watch. \r\n-Karen and her husband did not buy the cheapest item of the three. \r\n-Lee spent 11$ for the item chosen by his wife. \r\n-Ian and his wife bought the Records.", "hint": "No hint available.", "answer": "Ann and her husband did not buy the $10 item because their purchased item was more expensive than the watch. Neither did Karen and her husband. Therefore it must have been Julie and her husband who bought the 10$ item, and since Lee spent $11 then he is not her husband and her husband must be Ian, while Lee must be married to Karen.\n\r\nIan and Julie bought the records and Ann and David did not buy the watch therefore it must have been Lee and Karen who bought the watch for $11. Ann and David must have bought the kettle that must have been for $12, while the records must be for $10.", "category": "Logic", "date": "12/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree ladies (Ann, Julie, and Karen) managed to persuade their respective husbands (Lee, Ian, and David) to go shopping with them one Saturday morning. Between them, they purchased a watch, a kettle, and records and spent $10, $11, and $12. \n\r\nUsing the clues below, can you work out who is married to whom and say which item each couple bought and how much they paid for it? \n\r\n-The item purchased by Ann and David was more expensive than the watch. \r\n-Karen and her husband did not buy the cheapest item of the three. \r\n-Lee spent 11$ for the item chosen by his wife. \r\n-Ian and his wife bought the Records.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnn and her husband did not buy the $10 item because their purchased item was more expensive than the watch. Neither did Karen and her husband. Therefore it must have been Julie and her husband who bought the 10$ item, and since Lee spent $11 then he is not her husband and her husband must be Ian, while Lee must be married to Karen.\n\r\nIan and Julie bought the records and Ann and David did not buy the watch therefore it must have been Lee and Karen who bought the watch for $11. Ann and David must have bought the kettle that must have been for $12, while the records must be for $10.\n<|im_start|>answer\nAnn and her husband did not buy the $10 item because their purchased item was more expensive than the watch. Neither did Karen and her husband. Therefore it must have been Julie and her husband who bought the 10$ item, and since Lee spent $11 then he is not her husband and her husband must be Ian, while Lee must be married to Karen.\n\r\nIan and Julie bought the records and Ann and David did not buy the watch therefore it must have been Lee and Karen who bought the watch for $11. Ann and David must have bought the kettle that must have been for $12, while the records must be for $10.\n<|im_end|>" }, { "id": "#28378", "title": "Three Consecutive Evens", "fun": 2.53, "difficulty": 2.37, "author": "kiss", "desc": "Which three consecutive even numbers, when multiplied together, give the product 8xxxx2?\n\r\nEach x here represents a digit, not necessarily the same.", "hint": "No hint available.", "answer": "94, 96 and 98.\n\r\nIt's easy to get: since 90^3=729000, they must all begin with 9. Because the last digit of 2*4*6 is 8, and the last digit of 4*6*8 is 2, it must be 94*96*98, which equals 884352.", "category": "Math", "date": "01/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich three consecutive even numbers, when multiplied together, give the product 8xxxx2?\n\r\nEach x here represents a digit, not necessarily the same.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n94, 96 and 98.\n\r\nIt's easy to get: since 90^3=729000, they must all begin with 9. Because the last digit of 2*4*6 is 8, and the last digit of 4*6*8 is 2, it must be 94*96*98, which equals 884352.\n<|im_start|>answer\n94, 96 and 98.\n\r\nIt's easy to get: since 90^3=729000, they must all begin with 9. Because the last digit of 2*4*6 is 8, and the last digit of 4*6*8 is 2, it must be 94*96*98, which equals 884352.\n<|im_end|>" }, { "id": "#29998", "title": "Cryptic Time", "fun": 2.53, "difficulty": 2.47, "author": "RainyMysteria", "desc": "Raine was trying to reset her watch clock one afternoon, after it had stopped running the day before. Even though she didn't know what the real time was, her father had given her a clue. \"The right time is calculated by adding 1/4 of the time since noon today to 1/2 of the time till midnight tonight.\"\r\nWhen her father told her this clue, she thanked him and set her watch correctly. What time was it?", "hint": "x = time since noon\r\n(12-x)= ?", "answer": "4:48 pm. \n\r\nThe time is divided up so x = the time in hours.\n\r\nx = From noon till now\r\n(12-x) = Time till midnight\n\r\nTherefore, putting the clue into what we know, we get the equation:\n\r\nx = 1/4 x + 1/2 (12-x)\n\r\nExpand: \n\r\nx = 1/4 x + 6 - 1/2 x\r\n5/4 x = 6\r\nx =24/5 = 4.8 hours or 4 hours 48 minutes.\n\r\nTherefore, the time is 4:48 pm.", "category": "Math", "date": "04/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRaine was trying to reset her watch clock one afternoon, after it had stopped running the day before. Even though she didn't know what the real time was, her father had given her a clue. \"The right time is calculated by adding 1/4 of the time since noon today to 1/2 of the time till midnight tonight.\"\r\nWhen her father told her this clue, she thanked him and set her watch correctly. What time was it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4:48 pm. \n\r\nThe time is divided up so x = the time in hours.\n\r\nx = From noon till now\r\n(12-x) = Time till midnight\n\r\nTherefore, putting the clue into what we know, we get the equation:\n\r\nx = 1/4 x + 1/2 (12-x)\n\r\nExpand: \n\r\nx = 1/4 x + 6 - 1/2 x\r\n5/4 x = 6\r\nx =24/5 = 4.8 hours or 4 hours 48 minutes.\n\r\nTherefore, the time is 4:48 pm.\n<|im_start|>answer\n4:48 pm. \n\r\nThe time is divided up so x = the time in hours.\n\r\nx = From noon till now\r\n(12-x) = Time till midnight\n\r\nTherefore, putting the clue into what we know, we get the equation:\n\r\nx = 1/4 x + 1/2 (12-x)\n\r\nExpand: \n\r\nx = 1/4 x + 6 - 1/2 x\r\n5/4 x = 6\r\nx =24/5 = 4.8 hours or 4 hours 48 minutes.\n\r\nTherefore, the time is 4:48 pm.\n<|im_end|>" }, { "id": "#16042", "title": "What Can We Do?", "fun": 2.53, "difficulty": 1.84, "author": "eiennikirei", "desc": "The Mitchells want to do something interesting as a family this weekend. Here is an idea from each person of what they'd like to do for fun: \n\r\n1) go fishing in a lake \r\n2) play card/board/arcade games \r\n3) explore a rain forest \r\n4) visit a petting zoo \n\r\nIf mom has Zoophobia, dad has Dendrophobia, Allen has Pogonophobia, and Jasmine has Limnophobia, what can this family do together for fun?", "hint": "No hint available.", "answer": "The Mitchells would have to play board games, card games, and arcade games. \r\nThey cannot go fishing in a lake because Jasmine has Limnophobia (fear of lakes). \r\nThey cannot explore a rain forest because dad has Dendrophobia (fear of trees).\r\nThey cannot visit a petting zoo because mom has Zoophobia (fear of animals).\r\nAllen has Pogonophobia (fear of beards) but that doesn't effect the choices.", "category": "Logic", "date": "01/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Mitchells want to do something interesting as a family this weekend. Here is an idea from each person of what they'd like to do for fun: \n\r\n1) go fishing in a lake \r\n2) play card/board/arcade games \r\n3) explore a rain forest \r\n4) visit a petting zoo \n\r\nIf mom has Zoophobia, dad has Dendrophobia, Allen has Pogonophobia, and Jasmine has Limnophobia, what can this family do together for fun?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Mitchells would have to play board games, card games, and arcade games. \r\nThey cannot go fishing in a lake because Jasmine has Limnophobia (fear of lakes). \r\nThey cannot explore a rain forest because dad has Dendrophobia (fear of trees).\r\nThey cannot visit a petting zoo because mom has Zoophobia (fear of animals).\r\nAllen has Pogonophobia (fear of beards) but that doesn't effect the choices.\n<|im_start|>answer\nThe Mitchells would have to play board games, card games, and arcade games. \r\nThey cannot go fishing in a lake because Jasmine has Limnophobia (fear of lakes). \r\nThey cannot explore a rain forest because dad has Dendrophobia (fear of trees).\r\nThey cannot visit a petting zoo because mom has Zoophobia (fear of animals).\r\nAllen has Pogonophobia (fear of beards) but that doesn't effect the choices.\n<|im_end|>" }, { "id": "#30685", "title": "Calendar Fun", "fun": 2.53, "difficulty": 1.44, "author": "fairelamour", "desc": "Jason said: \"Pick any three dates that are next to each other in a week on the calendar. Give me only the sum and I'll tell you your dates.\"\n\r\nNoriko secretly chose 14, 15, and 16, and gave the sum 45 to Jason. In a couple of seconds Jason said, \"The dates are 14, 15, and 16.\"\n\r\nDavid secretly chose 22, 23, and 24, and gave the sum 69. Again, in a couple of seconds, Jason said, \"The dates are 22, 23, and 24.\"\n\r\nCan you figure out Jason's trick?", "hint": "Try some easier numbers, such as 1, 2, and 3 or 3, 4, and 5, to see if you can find a pattern. How is the sum related to the dates?", "answer": "Jason's trick is to divide the sum by 3, in order to find the middle number of the three dates.\n\r\nIf you have a sum of 6, the middle date is 6/3, or 2, and the dates are 1, 2, and 3. If you have a sum of 45, the middle date is 45/3, or 15, and the dates are 14, 15, and 16. If you have a sum of 69, the middle date is 69/3, or 23, and the dates are 22, 23, and 24.", "category": "Logic", "date": "05/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJason said: \"Pick any three dates that are next to each other in a week on the calendar. Give me only the sum and I'll tell you your dates.\"\n\r\nNoriko secretly chose 14, 15, and 16, and gave the sum 45 to Jason. In a couple of seconds Jason said, \"The dates are 14, 15, and 16.\"\n\r\nDavid secretly chose 22, 23, and 24, and gave the sum 69. Again, in a couple of seconds, Jason said, \"The dates are 22, 23, and 24.\"\n\r\nCan you figure out Jason's trick?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJason's trick is to divide the sum by 3, in order to find the middle number of the three dates.\n\r\nIf you have a sum of 6, the middle date is 6/3, or 2, and the dates are 1, 2, and 3. If you have a sum of 45, the middle date is 45/3, or 15, and the dates are 14, 15, and 16. If you have a sum of 69, the middle date is 69/3, or 23, and the dates are 22, 23, and 24.\n<|im_start|>answer\nJason's trick is to divide the sum by 3, in order to find the middle number of the three dates.\n\r\nIf you have a sum of 6, the middle date is 6/3, or 2, and the dates are 1, 2, and 3. If you have a sum of 45, the middle date is 45/3, or 15, and the dates are 14, 15, and 16. If you have a sum of 69, the middle date is 69/3, or 23, and the dates are 22, 23, and 24.\n<|im_end|>" }, { "id": "#4577", "title": "Grandma's Age", "fun": 2.53, "difficulty": 1.35, "author": "arij", "desc": "\"I've always been 45 years older than your Dad\", said Grandma to young Trickle. \"But now the two digits in my age, both prime, are the reverse of the two in your Dad's age\". How old is Grandma?", "hint": "No hint available.", "answer": "Grandma was 72 years old. Let the two digits be A and B. Then 10A+B-10B-A=45 so 9(A-B)=45. This gives A-B=5. Of the pairs 5,0; 6,1; 7,2; 8,3; 9,4 only 7,2 are both prime numbers.", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"I've always been 45 years older than your Dad\", said Grandma to young Trickle. \"But now the two digits in my age, both prime, are the reverse of the two in your Dad's age\". How old is Grandma?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGrandma was 72 years old. Let the two digits be A and B. Then 10A+B-10B-A=45 so 9(A-B)=45. This gives A-B=5. Of the pairs 5,0; 6,1; 7,2; 8,3; 9,4 only 7,2 are both prime numbers.\n<|im_start|>answer\nGrandma was 72 years old. Let the two digits be A and B. Then 10A+B-10B-A=45 so 9(A-B)=45. This gives A-B=5. Of the pairs 5,0; 6,1; 7,2; 8,3; 9,4 only 7,2 are both prime numbers.\n<|im_end|>" }, { "id": "#47439", "title": "9 = 4", "fun": 2.53, "difficulty": 2.02, "author": "wwestar1000", "desc": "Complete the series. 9 = 4, 21 = 9, 22 = 9, 24 = 10, 8 = 5, 7 = 5, 99 = 10, 100 = 10, 16 = ?, 17 = ?", "hint": "Count carefully.", "answer": "16 = 7 and 17 = 9. The number of letters in the spelling of 16 (sixteen) is 7 and that of 17 (seventeen) is 9.", "category": "Logic", "date": "07/08/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nComplete the series. 9 = 4, 21 = 9, 22 = 9, 24 = 10, 8 = 5, 7 = 5, 99 = 10, 100 = 10, 16 = ?, 17 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16 = 7 and 17 = 9. The number of letters in the spelling of 16 (sixteen) is 7 and that of 17 (seventeen) is 9.\n<|im_start|>answer\n16 = 7 and 17 = 9. The number of letters in the spelling of 16 (sixteen) is 7 and that of 17 (seventeen) is 9.\n<|im_end|>" }, { "id": "#30235", "title": "Non-Fat Frankfurters", "fun": 2.53, "difficulty": 2.69, "author": "norcekri", "desc": "\"I'm telling you, Kurt,\" Rod said to his best friend, \"these Rnkfurers are the greatest thing since whatever was before sliced bread! They're low-calorie, high-protein, fortified with vitamins B-1, B-36, and F-22, and come with three months of basic cable!\"\n\r\nKurt finally gave in, and agreed to go in with Rod on a minimum special order of the multi-colored treats. When the box arrived, they divided the bounty as originally planned.\n\r\n\"Interesting,\" Kurt noted, \"that the number of Rnkfurers you got is the same integer as my percentage.\"\n\r\nRod did a little mental math. \"You're right,\" he noted, \"and I think that's the lowest pair of integers we could do that with.\"\n\r\n\"Maybe; the next largest set is trivial. 50 Rnkfurers each, and then we'd each have the percentage the other guy got: 50% and 50 Rnkfurers each.\"\n\r\nKurt unwrapped a Rnkfurer and took his first bite. He glowed with pleasure for half a minute, and then spoke quietly.\n\r\n\"Rod, how many of these in a case?\"\n\r\n\"Fifty.\"\n\r\n\"I think we'd better order a few. And this time, it's my turn to get more than you do.\"\n\r\n\"Well, we can still arrange it so the number I get is your percentage of the total.\"\n\r\nKurt did a little mental math this time. \"Yeah, that's right. I can't fit more than 100 in my desk at school, so this will do the trick.\"\n\r\nHow many did each boy get each time?", "hint": "Although there are a dozen pairs of numbers that satisfy the percentage condition, the three used in the story are the only ones in which each boy gets fewer than 100 Rnkfurers.", "answer": "1st order: Rod 20, Kurt 5. Kurt has 20% of the total.\r\n2nd order: Rod 60, Kurt 90. Kurt has 60% of the total.\n\r\nThe equation to satisfy is\r\nR = 100*K / (R+K)\r\nwhere R and K are both integers.\n\r\nAnother way to look at this is\r\nK = R*R/(100-R)", "category": "Math", "date": "05/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"I'm telling you, Kurt,\" Rod said to his best friend, \"these Rnkfurers are the greatest thing since whatever was before sliced bread! They're low-calorie, high-protein, fortified with vitamins B-1, B-36, and F-22, and come with three months of basic cable!\"\n\r\nKurt finally gave in, and agreed to go in with Rod on a minimum special order of the multi-colored treats. When the box arrived, they divided the bounty as originally planned.\n\r\n\"Interesting,\" Kurt noted, \"that the number of Rnkfurers you got is the same integer as my percentage.\"\n\r\nRod did a little mental math. \"You're right,\" he noted, \"and I think that's the lowest pair of integers we could do that with.\"\n\r\n\"Maybe; the next largest set is trivial. 50 Rnkfurers each, and then we'd each have the percentage the other guy got: 50% and 50 Rnkfurers each.\"\n\r\nKurt unwrapped a Rnkfurer and took his first bite. He glowed with pleasure for half a minute, and then spoke quietly.\n\r\n\"Rod, how many of these in a case?\"\n\r\n\"Fifty.\"\n\r\n\"I think we'd better order a few. And this time, it's my turn to get more than you do.\"\n\r\n\"Well, we can still arrange it so the number I get is your percentage of the total.\"\n\r\nKurt did a little mental math this time. \"Yeah, that's right. I can't fit more than 100 in my desk at school, so this will do the trick.\"\n\r\nHow many did each boy get each time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st order: Rod 20, Kurt 5. Kurt has 20% of the total.\r\n2nd order: Rod 60, Kurt 90. Kurt has 60% of the total.\n\r\nThe equation to satisfy is\r\nR = 100*K / (R+K)\r\nwhere R and K are both integers.\n\r\nAnother way to look at this is\r\nK = R*R/(100-R)\n<|im_start|>answer\n1st order: Rod 20, Kurt 5. Kurt has 20% of the total.\r\n2nd order: Rod 60, Kurt 90. Kurt has 60% of the total.\n\r\nThe equation to satisfy is\r\nR = 100*K / (R+K)\r\nwhere R and K are both integers.\n\r\nAnother way to look at this is\r\nK = R*R/(100-R)\n<|im_end|>" }, { "id": "#27632", "title": "Arrogant Arnold and Witty Will", "fun": 2.53, "difficulty": 2.81, "author": "Swordoffury1392", "desc": "Arrogant Arnold and Witty Will are brothers. One day, they were going from New Jersey to Florida. Bored, they decided to ask each other brain teasers. After a while, they got bored with this, so Arnold decided to place a bet. He would ask Will one teaser, which he thought was very hard. If Will got it right, Arnold would clean his room for the rest of the year. However, if Will got it WRONG, he would have to clean Arnold's room for a year and do his dishes for a month. After thinking for a while, Will agreed to this. This was Arnold's teaser:\r\nUse each digit 1-9 only once each, so that one number multiplied by another equals the third. One example is 12*483=5796. Name at least one more!!!\r\nBeing witty as his name suggests, Will easily answered this. The question is, can you find one?", "hint": "1) They can't be -12*483=-5796, 1.2*48.3=57.96, etc.\r\n2) The third number in another possibility is also 5796.", "answer": "The other possibilities are [drum roll please :)]...\r\n18 , 297 , 5346\r\n27 , 198 , 5346\r\n28 , 157 , 4396\r\n39 , 186 , 7254\r\n42 , 138 , 5796\r\n48 , 159 , 7632", "category": "Math", "date": "12/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrogant Arnold and Witty Will are brothers. One day, they were going from New Jersey to Florida. Bored, they decided to ask each other brain teasers. After a while, they got bored with this, so Arnold decided to place a bet. He would ask Will one teaser, which he thought was very hard. If Will got it right, Arnold would clean his room for the rest of the year. However, if Will got it WRONG, he would have to clean Arnold's room for a year and do his dishes for a month. After thinking for a while, Will agreed to this. This was Arnold's teaser:\r\nUse each digit 1-9 only once each, so that one number multiplied by another equals the third. One example is 12*483=5796. Name at least one more!!!\r\nBeing witty as his name suggests, Will easily answered this. The question is, can you find one?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe other possibilities are [drum roll please :)]...\r\n18 , 297 , 5346\r\n27 , 198 , 5346\r\n28 , 157 , 4396\r\n39 , 186 , 7254\r\n42 , 138 , 5796\r\n48 , 159 , 7632\n<|im_start|>answer\nThe other possibilities are [drum roll please :)]...\r\n18 , 297 , 5346\r\n27 , 198 , 5346\r\n28 , 157 , 4396\r\n39 , 186 , 7254\r\n42 , 138 , 5796\r\n48 , 159 , 7632\n<|im_end|>" }, { "id": "#4174", "title": "No Zeros", "fun": 2.53, "difficulty": 2.18, "author": "librashorty", "desc": "Can you find a five digit number which has no zeros and no digit is repeated, and where: \n\r\nThe first digit is a prime number.\r\nThe second digit is the fifth digit minus the first digit.\r\nThe third digit is twice the first digit.\r\nThe fourth digit is the third digit plus three.\r\nThe fifth digit is the difference between the first digit and the fourth digit.", "hint": "No hint available.", "answer": "23,475", "category": "Math", "date": "05/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you find a five digit number which has no zeros and no digit is repeated, and where: \n\r\nThe first digit is a prime number.\r\nThe second digit is the fifth digit minus the first digit.\r\nThe third digit is twice the first digit.\r\nThe fourth digit is the third digit plus three.\r\nThe fifth digit is the difference between the first digit and the fourth digit.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n23,475\n<|im_start|>answer\n23,475\n<|im_end|>" }, { "id": "#47695", "title": "Three Gunmen", "fun": 2.53, "difficulty": 1.2, "author": "Mathgeek007", "desc": "There are three gunmen on horses. Ab has a 100% chance of hitting his target when he shoots, but has a weak gun. He never misses. Bob also has a 100% chance of hitting, but he has a tremendous strong gun. However, Cam only has a 50% chance of hitting with his musket. Simultaneously, they all take a shot. One man is left alive. Who?", "hint": "If you know you and another person shoot their target perfectly, who would you go for first?", "answer": "Cam is. The two other men, knowing they each shoot perfectly, would shoot each other knowing they still have a chance of surviving if Cam shoots at them. Nobody was shooting at Cam, therefore, he stays alive.", "category": "Logic", "date": "08/08/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three gunmen on horses. Ab has a 100% chance of hitting his target when he shoots, but has a weak gun. He never misses. Bob also has a 100% chance of hitting, but he has a tremendous strong gun. However, Cam only has a 50% chance of hitting with his musket. Simultaneously, they all take a shot. One man is left alive. Who?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCam is. The two other men, knowing they each shoot perfectly, would shoot each other knowing they still have a chance of surviving if Cam shoots at them. Nobody was shooting at Cam, therefore, he stays alive.\n<|im_start|>answer\nCam is. The two other men, knowing they each shoot perfectly, would shoot each other knowing they still have a chance of surviving if Cam shoots at them. Nobody was shooting at Cam, therefore, he stays alive.\n<|im_end|>" }, { "id": "#14649", "title": "Bridge Players", "fun": 2.53, "difficulty": 2.49, "author": "taniapereira99", "desc": "At a family get-together, four married couples played bridge at two different tables (4 people at each table). From the statements below determine which players were at which table and who their partner was.\n\r\n1. Mrs. Johnson was partnered with her son-in-law.\r\n2. Mr. Jones' partner was his wife's brother-in-law.\r\n3. Mrs. Jones played against her sister.\r\n4. Mr. Johnson played against his father-in-law.\r\n5. Mrs. Smith's partner was her daughter.\r\n6. Mrs. Williams partner was her grandfather.\r\n7. Mr. Johnson's partner was a man.", "hint": "No hint available.", "answer": "From statements 3, 5 and 6 the four couples consist of 3 generations since there is a set of sisters involved and there are grandparents present.\r\nFrom 2 and 3, the Jones are definitely one of the sisters, and from 6, the Williams are definitely on the 3rd generation. Looking at 1 and 4, the Johnson's are on the 2nd generation and since the Smiths have a daughter, they are on the 1st or 2nd generation. But since the Jones must be one of the sisters, the Smiths cannot fall in the 2nd generation with the Johnson's. Therefore the Smiths are the grandparents.\n\r\nFrom 6, Mrs. Williams' partner is Mr. Smith. From 1 and 6, Mrs. Johnston and Mrs. Williams both have male partners, therefore from 5, Mrs. Smith's partner could have only been Mrs. Jones. Which also means that Jones and Johnson are the pair of sisters.\n\r\nThus from 2, Mr. Jones is then partnered with Mr. Johnson, and from 3, Mrs Jones (who is partnered with Mrs. Smith) is playing against Mrs. Johnson (whose partner is Mr. Williams from 1).\n\r\nIn summation, Mr. Jones and Mr. Johnson play against Mrs. Williams and Mr Smith, while Mrs Jones and Mrs. Smith play against Mrs. Johnson and Mr. Williams.", "category": "Logic", "date": "09/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a family get-together, four married couples played bridge at two different tables (4 people at each table). From the statements below determine which players were at which table and who their partner was.\n\r\n1. Mrs. Johnson was partnered with her son-in-law.\r\n2. Mr. Jones' partner was his wife's brother-in-law.\r\n3. Mrs. Jones played against her sister.\r\n4. Mr. Johnson played against his father-in-law.\r\n5. Mrs. Smith's partner was her daughter.\r\n6. Mrs. Williams partner was her grandfather.\r\n7. Mr. Johnson's partner was a man.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom statements 3, 5 and 6 the four couples consist of 3 generations since there is a set of sisters involved and there are grandparents present.\r\nFrom 2 and 3, the Jones are definitely one of the sisters, and from 6, the Williams are definitely on the 3rd generation. Looking at 1 and 4, the Johnson's are on the 2nd generation and since the Smiths have a daughter, they are on the 1st or 2nd generation. But since the Jones must be one of the sisters, the Smiths cannot fall in the 2nd generation with the Johnson's. Therefore the Smiths are the grandparents.\n\r\nFrom 6, Mrs. Williams' partner is Mr. Smith. From 1 and 6, Mrs. Johnston and Mrs. Williams both have male partners, therefore from 5, Mrs. Smith's partner could have only been Mrs. Jones. Which also means that Jones and Johnson are the pair of sisters.\n\r\nThus from 2, Mr. Jones is then partnered with Mr. Johnson, and from 3, Mrs Jones (who is partnered with Mrs. Smith) is playing against Mrs. Johnson (whose partner is Mr. Williams from 1).\n\r\nIn summation, Mr. Jones and Mr. Johnson play against Mrs. Williams and Mr Smith, while Mrs Jones and Mrs. Smith play against Mrs. Johnson and Mr. Williams.\n<|im_start|>answer\nFrom statements 3, 5 and 6 the four couples consist of 3 generations since there is a set of sisters involved and there are grandparents present.\r\nFrom 2 and 3, the Jones are definitely one of the sisters, and from 6, the Williams are definitely on the 3rd generation. Looking at 1 and 4, the Johnson's are on the 2nd generation and since the Smiths have a daughter, they are on the 1st or 2nd generation. But since the Jones must be one of the sisters, the Smiths cannot fall in the 2nd generation with the Johnson's. Therefore the Smiths are the grandparents.\n\r\nFrom 6, Mrs. Williams' partner is Mr. Smith. From 1 and 6, Mrs. Johnston and Mrs. Williams both have male partners, therefore from 5, Mrs. Smith's partner could have only been Mrs. Jones. Which also means that Jones and Johnson are the pair of sisters.\n\r\nThus from 2, Mr. Jones is then partnered with Mr. Johnson, and from 3, Mrs Jones (who is partnered with Mrs. Smith) is playing against Mrs. Johnson (whose partner is Mr. Williams from 1).\n\r\nIn summation, Mr. Jones and Mr. Johnson play against Mrs. Williams and Mr Smith, while Mrs Jones and Mrs. Smith play against Mrs. Johnson and Mr. Williams.\n<|im_end|>" }, { "id": "#28218", "title": "Opposites 7", "fun": 2.53, "difficulty": 1.96, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n: stands for M, R, F, U, or Y\r\n# stands for R, H, L, Y, or S\r\n* stands for A, O, G, R, or E\r\n_ stands for T, D, L, J, or C\n\r\nThe four letter code word, #*:_, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Soft and Loud or Soft and Hard.", "category": "Logic", "date": "01/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n: stands for M, R, F, U, or Y\r\n# stands for R, H, L, Y, or S\r\n* stands for A, O, G, R, or E\r\n_ stands for T, D, L, J, or C\n\r\nThe four letter code word, #*:_, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSoft and Loud or Soft and Hard.\n<|im_start|>answer\nSoft and Loud or Soft and Hard.\n<|im_end|>" }, { "id": "#2333", "title": "Rope", "fun": 2.53, "difficulty": 2.16, "author": "missie", "desc": "A man ordered a length of rope by telephone from his nearest hardware shop. But when he went to collect the rope, he found that the assistant had miswritten the order by interchanging feet and inches. As a result of this, the rope was only 30 percent of the length that the man wanted. So, what length did he want and what length did he get?", "hint": "No hint available.", "answer": "Ordered: 9 feet and 2 inches\r\nReceived: 2 feet and 9 inches", "category": "Math", "date": "02/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man ordered a length of rope by telephone from his nearest hardware shop. But when he went to collect the rope, he found that the assistant had miswritten the order by interchanging feet and inches. As a result of this, the rope was only 30 percent of the length that the man wanted. So, what length did he want and what length did he get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOrdered: 9 feet and 2 inches\r\nReceived: 2 feet and 9 inches\n<|im_start|>answer\nOrdered: 9 feet and 2 inches\r\nReceived: 2 feet and 9 inches\n<|im_end|>" }, { "id": "#31384", "title": "Flip a Coin", "fun": 2.53, "difficulty": 1.68, "author": "holly1447591", "desc": "A man makes the following proposition to his friend:\n\r\n\"I will let you flip a coin 20 times. Each time the coin lands on heads, I will give you $2.00. However, each time the coin lands on tails, you must give me $3.00.\"\n\r\nHis friend flips the coin 20 times and the end result is that no money is to change hands.\n\r\nHow many times did the coin land on heads?", "hint": "No hint available.", "answer": "Since each won and lost an equal amount, the following equation can be used to find the solution: 2x = 3(20-x), where x = number of times heads came up.\r\nSolving this results in 5x = 60. Thus, x = 12.\n\r\nThe coin must have landed on heads a total of 12 times in order for no money to exchange hands.", "category": "Math", "date": "06/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man makes the following proposition to his friend:\n\r\n\"I will let you flip a coin 20 times. Each time the coin lands on heads, I will give you $2.00. However, each time the coin lands on tails, you must give me $3.00.\"\n\r\nHis friend flips the coin 20 times and the end result is that no money is to change hands.\n\r\nHow many times did the coin land on heads?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince each won and lost an equal amount, the following equation can be used to find the solution: 2x = 3(20-x), where x = number of times heads came up.\r\nSolving this results in 5x = 60. Thus, x = 12.\n\r\nThe coin must have landed on heads a total of 12 times in order for no money to exchange hands.\n<|im_start|>answer\nSince each won and lost an equal amount, the following equation can be used to find the solution: 2x = 3(20-x), where x = number of times heads came up.\r\nSolving this results in 5x = 60. Thus, x = 12.\n\r\nThe coin must have landed on heads a total of 12 times in order for no money to exchange hands.\n<|im_end|>" }, { "id": "#22226", "title": "Bridge Falling.......", "fun": 2.53, "difficulty": 1.92, "author": "tikiwop9", "desc": "A bridge, 2 miles long, is rated for 12,000 lbs. Even one ounce more will cause it to collapse. A truck weighing precisely 12,000 lbs begins to cross. At the halfway point, a sparrow weighing 5 ounces lands on the truck. The bridge does not collapse. Why?", "hint": "No hint available.", "answer": "By the time the sparrow lands on the truck, it has already consumed more than 5 ounces of fuel.", "category": "Logic", "date": "04/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bridge, 2 miles long, is rated for 12,000 lbs. Even one ounce more will cause it to collapse. A truck weighing precisely 12,000 lbs begins to cross. At the halfway point, a sparrow weighing 5 ounces lands on the truck. The bridge does not collapse. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBy the time the sparrow lands on the truck, it has already consumed more than 5 ounces of fuel.\n<|im_start|>answer\nBy the time the sparrow lands on the truck, it has already consumed more than 5 ounces of fuel.\n<|im_end|>" }, { "id": "#39733", "title": "Vine Leaves", "fun": 2.53, "difficulty": 1.13, "author": "icestar12", "desc": "Juanita was helping her mom and dad weed their garden. She noticed an interesting thing about the pea vines. No matter how tall they were, their leaves started one foot from the ground. Above that point, there was one leaf every four inches. The three vines in the garden were five, seven, and eight feet tall.\n\r\nHow many leaves are there altogether?", "hint": "No hint available.", "answer": "The five-foot vine has 13 leaves; the seven-foot vine has 19 leaves; and the eight-foot vine has 22 leaves. The total number of leaves on the three vines is 54.", "category": "Math", "date": "12/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJuanita was helping her mom and dad weed their garden. She noticed an interesting thing about the pea vines. No matter how tall they were, their leaves started one foot from the ground. Above that point, there was one leaf every four inches. The three vines in the garden were five, seven, and eight feet tall.\n\r\nHow many leaves are there altogether?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe five-foot vine has 13 leaves; the seven-foot vine has 19 leaves; and the eight-foot vine has 22 leaves. The total number of leaves on the three vines is 54.\n<|im_start|>answer\nThe five-foot vine has 13 leaves; the seven-foot vine has 19 leaves; and the eight-foot vine has 22 leaves. The total number of leaves on the three vines is 54.\n<|im_end|>" }, { "id": "#33547", "title": "Little Johnny #2", "fun": 2.53, "difficulty": 2.4, "author": "fishmed", "desc": "Little Johnny was pestering his big brother for some candy. He knew that his brother had several pieces and wanted some. \n\r\nHis brother had Quick Quackers, Tangy Toffees, Fizzy Booms, Apple Chewies, Purple Plops, Zounds!, Sour Screams, and Buzzy Bites.\n\r\nLittle Johnny's favorites were Tangy Toffee and Quick Quackers. His brother said he'd give him all of those that he had if he could figure out how many Tangy Toffees and Quick Quackers he had in his room.\n\r\nHe told Little Johnny the following clues.\n\r\n1. If he added all the Buzzy Bites, the Purple Plops and Fizzy Booms that he had, the total was 48.\n\r\n2. If he added the number of Apple Chewies and Buzzy Bites, it was the same as the number of Zounds! he had.\n\r\n3. If he added the number of Zounds! and the Purple Plops, it was the same as the number of Tangy Toffees he had.\n\r\n4. If he added the number of Tangy Toffees and the Apple Chewies, it was the same as the number of Fizzy Booms he had.\n\r\n5. If he added the number of Fizzy Booms and the Sour Screams, it was the same as the number of Quick Quackers he had.\n\r\n6. Finally, he told him that if you subtracted the number of Tangy Toffees from the Quick Quackers, he would have the number 14.\n\r\nLittle Johnny took a few minutes, but walked away with all the Tangy Toffees and Quick Quackers, even though his mother had to make his brother honor his promise. Can you figure out how many Quick Quackers and Tangy Toffees that Little Johnny got?", "hint": "No hint available.", "answer": "Apple Chewies = A\r\nBuzzy Bites = B\r\nFizzy Booms = F\r\nPurple Plops = P\r\nQuick Quackers = Q\r\nSour Screams = S\r\nTangy Toffees = T\r\nZounds! = Z\n\r\nThe givens are as follows:\n\r\n1. B + P + F = 48\r\n2. A + B = Z\r\n3. Z + P = T\r\n4. T + A = F\r\n5. F + S = Q\r\n6. Q - T = 14\n\r\nNow, moving a few things around we find the following: \n\r\nB = Z - A (from given #2)\r\nP = T - Z (from given #3)\r\nF = T + A (from given #4)\n\r\nThen B + P + F = (Z - A) + (T - Z) + (T + A) = 2T once you add and subtract it all. \n\r\nSince B + P + F = 48 = 2T.\n\r\nAs such, T = 24.\r\nAnd from given #6, Q = 14 + T = 38\n\r\nSo, Q = 38 and T = 24", "category": "Math", "date": "10/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittle Johnny was pestering his big brother for some candy. He knew that his brother had several pieces and wanted some. \n\r\nHis brother had Quick Quackers, Tangy Toffees, Fizzy Booms, Apple Chewies, Purple Plops, Zounds!, Sour Screams, and Buzzy Bites.\n\r\nLittle Johnny's favorites were Tangy Toffee and Quick Quackers. His brother said he'd give him all of those that he had if he could figure out how many Tangy Toffees and Quick Quackers he had in his room.\n\r\nHe told Little Johnny the following clues.\n\r\n1. If he added all the Buzzy Bites, the Purple Plops and Fizzy Booms that he had, the total was 48.\n\r\n2. If he added the number of Apple Chewies and Buzzy Bites, it was the same as the number of Zounds! he had.\n\r\n3. If he added the number of Zounds! and the Purple Plops, it was the same as the number of Tangy Toffees he had.\n\r\n4. If he added the number of Tangy Toffees and the Apple Chewies, it was the same as the number of Fizzy Booms he had.\n\r\n5. If he added the number of Fizzy Booms and the Sour Screams, it was the same as the number of Quick Quackers he had.\n\r\n6. Finally, he told him that if you subtracted the number of Tangy Toffees from the Quick Quackers, he would have the number 14.\n\r\nLittle Johnny took a few minutes, but walked away with all the Tangy Toffees and Quick Quackers, even though his mother had to make his brother honor his promise. Can you figure out how many Quick Quackers and Tangy Toffees that Little Johnny got?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nApple Chewies = A\r\nBuzzy Bites = B\r\nFizzy Booms = F\r\nPurple Plops = P\r\nQuick Quackers = Q\r\nSour Screams = S\r\nTangy Toffees = T\r\nZounds! = Z\n\r\nThe givens are as follows:\n\r\n1. B + P + F = 48\r\n2. A + B = Z\r\n3. Z + P = T\r\n4. T + A = F\r\n5. F + S = Q\r\n6. Q - T = 14\n\r\nNow, moving a few things around we find the following: \n\r\nB = Z - A (from given #2)\r\nP = T - Z (from given #3)\r\nF = T + A (from given #4)\n\r\nThen B + P + F = (Z - A) + (T - Z) + (T + A) = 2T once you add and subtract it all. \n\r\nSince B + P + F = 48 = 2T.\n\r\nAs such, T = 24.\r\nAnd from given #6, Q = 14 + T = 38\n\r\nSo, Q = 38 and T = 24\n<|im_start|>answer\nApple Chewies = A\r\nBuzzy Bites = B\r\nFizzy Booms = F\r\nPurple Plops = P\r\nQuick Quackers = Q\r\nSour Screams = S\r\nTangy Toffees = T\r\nZounds! = Z\n\r\nThe givens are as follows:\n\r\n1. B + P + F = 48\r\n2. A + B = Z\r\n3. Z + P = T\r\n4. T + A = F\r\n5. F + S = Q\r\n6. Q - T = 14\n\r\nNow, moving a few things around we find the following: \n\r\nB = Z - A (from given #2)\r\nP = T - Z (from given #3)\r\nF = T + A (from given #4)\n\r\nThen B + P + F = (Z - A) + (T - Z) + (T + A) = 2T once you add and subtract it all. \n\r\nSince B + P + F = 48 = 2T.\n\r\nAs such, T = 24.\r\nAnd from given #6, Q = 14 + T = 38\n\r\nSo, Q = 38 and T = 24\n<|im_end|>" }, { "id": "#11754", "title": "Bird Brains", "fun": 2.53, "difficulty": 2.0, "author": "jimbo", "desc": "If 3 thistled thrushes eat 3 packs of birdseed in 3 weeks and 4 feathery finches eat 4 packs of birdseed in 4 weeks and 6 coloured cockatoos eat 6 packs of birdseed in 6 weeks then how much birdseed will feed 12 thistled thrushes, 12 feathery finches and 12 coloured cockatoos for 12 weeks?", "hint": "It must be dozens and dozens!", "answer": "3 thrushes eat 3 packs in 3 weeks\r\n3 thrushes eat 12 packs in 12 weeks\r\n12 thrushes eat 48 packs in 12 weeks.\r\n4 finches eat 4 packs in 4 weeks\r\n4 finches eat 12 packs in 12 weeks,\r\n12 finches eat 36 packs in 12 weeks.\r\n6 cockatoos eat 6 packs in 6 weeks,\r\n6 cockatoos eat 12 packs in 12 weeks,\r\n12 cockatoos eat 24 packs in 12 weeks\r\nSo 48+36+24 = 108 packs.\n\r\nAnswer: 108 packs.", "category": "Math", "date": "04/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 3 thistled thrushes eat 3 packs of birdseed in 3 weeks and 4 feathery finches eat 4 packs of birdseed in 4 weeks and 6 coloured cockatoos eat 6 packs of birdseed in 6 weeks then how much birdseed will feed 12 thistled thrushes, 12 feathery finches and 12 coloured cockatoos for 12 weeks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 thrushes eat 3 packs in 3 weeks\r\n3 thrushes eat 12 packs in 12 weeks\r\n12 thrushes eat 48 packs in 12 weeks.\r\n4 finches eat 4 packs in 4 weeks\r\n4 finches eat 12 packs in 12 weeks,\r\n12 finches eat 36 packs in 12 weeks.\r\n6 cockatoos eat 6 packs in 6 weeks,\r\n6 cockatoos eat 12 packs in 12 weeks,\r\n12 cockatoos eat 24 packs in 12 weeks\r\nSo 48+36+24 = 108 packs.\n\r\nAnswer: 108 packs.\n<|im_start|>answer\n3 thrushes eat 3 packs in 3 weeks\r\n3 thrushes eat 12 packs in 12 weeks\r\n12 thrushes eat 48 packs in 12 weeks.\r\n4 finches eat 4 packs in 4 weeks\r\n4 finches eat 12 packs in 12 weeks,\r\n12 finches eat 36 packs in 12 weeks.\r\n6 cockatoos eat 6 packs in 6 weeks,\r\n6 cockatoos eat 12 packs in 12 weeks,\r\n12 cockatoos eat 24 packs in 12 weeks\r\nSo 48+36+24 = 108 packs.\n\r\nAnswer: 108 packs.\n<|im_end|>" }, { "id": "#44952", "title": "Confusing Ferris Wheel", "fun": 2.53, "difficulty": 2.12, "author": "grilledcheese", "desc": "There are 10 two-seater cars attached to a Ferris wheel. The Ferris wheel turns so that one car rotates through the exit platform every minute. The wheel began operation at 10 in the morning and shut down 30 minutes later. What's the maximum number of people that could have taken a ride on the wheel in that time period?", "hint": "If the wheel has to stop promptly at 10:30, then the operator won't allow anyone on who can't get off the Ferris wheel by 10:30.", "answer": "42\n\r\nFor the first nine minutes it's moving, the cars are arriving at the unloading zone are unoccupied. For the last nine minutes, of operation, no one will be able to get on the ride.\r\nFrom the time the Ferris wheel fills up at 10 minutes past the hour until the last passenger steps off at 10:30, a total of 21 sets of passengers will have taken a ride.", "category": "Logic", "date": "07/26/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 10 two-seater cars attached to a Ferris wheel. The Ferris wheel turns so that one car rotates through the exit platform every minute. The wheel began operation at 10 in the morning and shut down 30 minutes later. What's the maximum number of people that could have taken a ride on the wheel in that time period?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n42\n\r\nFor the first nine minutes it's moving, the cars are arriving at the unloading zone are unoccupied. For the last nine minutes, of operation, no one will be able to get on the ride.\r\nFrom the time the Ferris wheel fills up at 10 minutes past the hour until the last passenger steps off at 10:30, a total of 21 sets of passengers will have taken a ride.\n<|im_start|>answer\n42\n\r\nFor the first nine minutes it's moving, the cars are arriving at the unloading zone are unoccupied. For the last nine minutes, of operation, no one will be able to get on the ride.\r\nFrom the time the Ferris wheel fills up at 10 minutes past the hour until the last passenger steps off at 10:30, a total of 21 sets of passengers will have taken a ride.\n<|im_end|>" }, { "id": "#8264", "title": "The String Around the Cylinder", "fun": 2.53, "difficulty": 2.3, "author": "higgo", "desc": "A cylinder 48cm high has a circumference of 16cm. A string makes exactly 4 complete turns around the cylinder, while its two ends touch the cylinder's top and bottom (forming a spiral around the cylinder). \n\r\nHow long is the string in cm?", "hint": "Pythagoras' theorem may help.", "answer": "80cm.\n\r\nFinding the length of the string is the same as finding the length of the hypotenuse of a triangle with a height of 48 cm and a base of 64 cm (16 x 4). Using Pythagoras' theorem, you get:\n\r\nh^2 = 48^2 + 64^2\r\nSolving, h = 80 cm.", "category": "Math", "date": "10/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cylinder 48cm high has a circumference of 16cm. A string makes exactly 4 complete turns around the cylinder, while its two ends touch the cylinder's top and bottom (forming a spiral around the cylinder). \n\r\nHow long is the string in cm?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n80cm.\n\r\nFinding the length of the string is the same as finding the length of the hypotenuse of a triangle with a height of 48 cm and a base of 64 cm (16 x 4). Using Pythagoras' theorem, you get:\n\r\nh^2 = 48^2 + 64^2\r\nSolving, h = 80 cm.\n<|im_start|>answer\n80cm.\n\r\nFinding the length of the string is the same as finding the length of the hypotenuse of a triangle with a height of 48 cm and a base of 64 cm (16 x 4). Using Pythagoras' theorem, you get:\n\r\nh^2 = 48^2 + 64^2\r\nSolving, h = 80 cm.\n<|im_end|>" }, { "id": "#270", "title": "Three generations", "fun": 2.53, "difficulty": 1.81, "author": "Phyllis", "desc": "Grandpa Jones says:\n`My son Adam is 24 years younger than me and 35 years older than my grandson, Joey. Together our total ages add up to 100.` Can you figure out the age of each one of them?", "hint": "No hint available.", "answer": "Grandpa Jones was 24 when Adam was born and Joey was born 35 years later, so Grandpa has to be at least 59 years old. Add this to Adam`s age at Joey`s birth to get a total age of 94. If Joey was 1 year old, the total combined ages would be 97 (adding 1 year to every age.) But, if Joey is 2 years old then Grandpa would be 61 and Adam would be 37 and their combined ages would be 100.", "category": "Math", "date": "02/13/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrandpa Jones says:\n`My son Adam is 24 years younger than me and 35 years older than my grandson, Joey. Together our total ages add up to 100.` Can you figure out the age of each one of them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGrandpa Jones was 24 when Adam was born and Joey was born 35 years later, so Grandpa has to be at least 59 years old. Add this to Adam`s age at Joey`s birth to get a total age of 94. If Joey was 1 year old, the total combined ages would be 97 (adding 1 year to every age.) But, if Joey is 2 years old then Grandpa would be 61 and Adam would be 37 and their combined ages would be 100.\n<|im_start|>answer\nGrandpa Jones was 24 when Adam was born and Joey was born 35 years later, so Grandpa has to be at least 59 years old. Add this to Adam`s age at Joey`s birth to get a total age of 94. If Joey was 1 year old, the total combined ages would be 97 (adding 1 year to every age.) But, if Joey is 2 years old then Grandpa would be 61 and Adam would be 37 and their combined ages would be 100.\n<|im_end|>" }, { "id": "#29461", "title": "Campers' Caps", "fun": 2.53, "difficulty": 2.1, "author": "shenqiang", "desc": "At Camp Brainy, all the campers get a camp logo baseball cap that is the color of their choice. There are red, blue, yellow, black, and green caps. The caps have just arrived in 3 cartons of 50 each. Two volunteers are unpacking them now.\n\r\n1. The first carton had just black caps. All but 15 were ordered by campers. \r\n2. The second carton had 10 more green caps than blue caps. After the campers picked their hats, there were 5 each of these 2 colors left over. \r\n3. The last box had an equal number of red and yellow caps. Five more campers wanted red caps than wanted blue caps. Only half as many campers wanted yellow as wanted red. \n\r\nHow many campers ordered each color cap, and how many of each color were left over?", "hint": "Make a chart to track the number of caps of each color ordered and left over.", "answer": "50 black caps, 35 ordered, 15 left;\r\n30 green caps, 25 ordered, 5 left;\r\n20 blue caps, 15 ordered, 5 left;\r\n25 red caps, 20 ordered, 5 left;\r\n25 yellow caps, 10 ordered, 15 left.", "category": "Math", "date": "03/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt Camp Brainy, all the campers get a camp logo baseball cap that is the color of their choice. There are red, blue, yellow, black, and green caps. The caps have just arrived in 3 cartons of 50 each. Two volunteers are unpacking them now.\n\r\n1. The first carton had just black caps. All but 15 were ordered by campers. \r\n2. The second carton had 10 more green caps than blue caps. After the campers picked their hats, there were 5 each of these 2 colors left over. \r\n3. The last box had an equal number of red and yellow caps. Five more campers wanted red caps than wanted blue caps. Only half as many campers wanted yellow as wanted red. \n\r\nHow many campers ordered each color cap, and how many of each color were left over?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n50 black caps, 35 ordered, 15 left;\r\n30 green caps, 25 ordered, 5 left;\r\n20 blue caps, 15 ordered, 5 left;\r\n25 red caps, 20 ordered, 5 left;\r\n25 yellow caps, 10 ordered, 15 left.\n<|im_start|>answer\n50 black caps, 35 ordered, 15 left;\r\n30 green caps, 25 ordered, 5 left;\r\n20 blue caps, 15 ordered, 5 left;\r\n25 red caps, 20 ordered, 5 left;\r\n25 yellow caps, 10 ordered, 15 left.\n<|im_end|>" }, { "id": "#5098", "title": "Grandfather's Will", "fun": 2.53, "difficulty": 1.43, "author": "peppermintwist", "desc": "Grandfather thinks it is time to prepare his will. He has three daughters: Anne, Beatrice, and Caroline. Each of his daughters has at least one child. The six grandchildren are: Frederic, Gregory, Henry, John, Laura, and Mary. Grandfather wishes each of his grandchildren to receive an equal share, but he can't remember how many children each of his daughters has. However, he does remember that:\n\r\nBeatrice has the largest family.\r\nAnne doesn't have a daughter.\r\nMary has two brothers.\r\nHenry's brother is six months younger than Gregory.\r\nLaura has neither a brother nor a sister.\n\r\nHow many children does each child have?", "hint": "Use a piece of paper to work it out!", "answer": "Beatrice has three children, Anne has two, and Caroline has one.", "category": "Logic", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrandfather thinks it is time to prepare his will. He has three daughters: Anne, Beatrice, and Caroline. Each of his daughters has at least one child. The six grandchildren are: Frederic, Gregory, Henry, John, Laura, and Mary. Grandfather wishes each of his grandchildren to receive an equal share, but he can't remember how many children each of his daughters has. However, he does remember that:\n\r\nBeatrice has the largest family.\r\nAnne doesn't have a daughter.\r\nMary has two brothers.\r\nHenry's brother is six months younger than Gregory.\r\nLaura has neither a brother nor a sister.\n\r\nHow many children does each child have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeatrice has three children, Anne has two, and Caroline has one.\n<|im_start|>answer\nBeatrice has three children, Anne has two, and Caroline has one.\n<|im_end|>" }, { "id": "#2298", "title": "Tennis Balls & Planets", "fun": 2.53, "difficulty": 2.08, "author": "rayneeday", "desc": "A fool wants to tie a rope around the earth. So he buys a rope of 40,000 KM and ties it around the world. His neighbour, also a fool, wants to do the same only he wants the rope on sticks 1 meter above the ground.\n\n\r\nHow much more rope does he need?\r\nAnd how much more rope do you need when you use a tennis ball instead of the earth?", "hint": "No hint available.", "answer": "6 meters 28 centimeters.\n\r\nx=2*PI*(r+1)-2*PI*r\r\nx=2*PI*r+2*PI-2*PI*r\r\nx=2*PI\r\nx=6.28\n\r\nIt does not matter what the radius of the circle is. You always need 2*pi meters more of rope for each additional meter of radius added.", "category": "Math", "date": "02/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fool wants to tie a rope around the earth. So he buys a rope of 40,000 KM and ties it around the world. His neighbour, also a fool, wants to do the same only he wants the rope on sticks 1 meter above the ground.\n\n\r\nHow much more rope does he need?\r\nAnd how much more rope do you need when you use a tennis ball instead of the earth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6 meters 28 centimeters.\n\r\nx=2*PI*(r+1)-2*PI*r\r\nx=2*PI*r+2*PI-2*PI*r\r\nx=2*PI\r\nx=6.28\n\r\nIt does not matter what the radius of the circle is. You always need 2*pi meters more of rope for each additional meter of radius added.\n<|im_start|>answer\n6 meters 28 centimeters.\n\r\nx=2*PI*(r+1)-2*PI*r\r\nx=2*PI*r+2*PI-2*PI*r\r\nx=2*PI\r\nx=6.28\n\r\nIt does not matter what the radius of the circle is. You always need 2*pi meters more of rope for each additional meter of radius added.\n<|im_end|>" }, { "id": "#37121", "title": "Grab a Cab", "fun": 2.53, "difficulty": 1.27, "author": "pating", "desc": "Pating and his wife are at the entrance of their subdivision. Their subdivision is actually just a long straight road with no side streets. Their house is 1 kilometer away from the entrance. While waiting for a cab to take them home, Pating decides to just walk his way to their house (he needs the exercise) leaving his wife in the entrance. He walks at a steady pace of 3km/hr. After 18 minutes, his wife finally manages to hail a cab and orders the driver to take her home. The cab goes at a constant speed of 40km/hr. Who will reach their house first?", "hint": "No hint available.", "answer": "Using the formula of D = RT, where D is distance, R = rate or speed, T = time:\r\nFor Pating, he will reach the house if he continues on walking in (1km)/(3km/hr) = .33333hr or 20 minutes.\r\nFor his wife, she will reach the house in (1km)/(40km/hr) = .025hr or 1.5 minutes. Counting the 18 minutes lead time of Pating, 19.5 minutes.\r\nSo Pating's wife will reach their home first.\n\r\nBut if this is a combination of a math and trick question, they will arrive at their house together. \n\r\nIf his wife really loves him, she'll let him inside the cab as soon as the cab overtakes Pating.", "category": "Math", "date": "06/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPating and his wife are at the entrance of their subdivision. Their subdivision is actually just a long straight road with no side streets. Their house is 1 kilometer away from the entrance. While waiting for a cab to take them home, Pating decides to just walk his way to their house (he needs the exercise) leaving his wife in the entrance. He walks at a steady pace of 3km/hr. After 18 minutes, his wife finally manages to hail a cab and orders the driver to take her home. The cab goes at a constant speed of 40km/hr. Who will reach their house first?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUsing the formula of D = RT, where D is distance, R = rate or speed, T = time:\r\nFor Pating, he will reach the house if he continues on walking in (1km)/(3km/hr) = .33333hr or 20 minutes.\r\nFor his wife, she will reach the house in (1km)/(40km/hr) = .025hr or 1.5 minutes. Counting the 18 minutes lead time of Pating, 19.5 minutes.\r\nSo Pating's wife will reach their home first.\n\r\nBut if this is a combination of a math and trick question, they will arrive at their house together. \n\r\nIf his wife really loves him, she'll let him inside the cab as soon as the cab overtakes Pating.\n<|im_start|>answer\nUsing the formula of D = RT, where D is distance, R = rate or speed, T = time:\r\nFor Pating, he will reach the house if he continues on walking in (1km)/(3km/hr) = .33333hr or 20 minutes.\r\nFor his wife, she will reach the house in (1km)/(40km/hr) = .025hr or 1.5 minutes. Counting the 18 minutes lead time of Pating, 19.5 minutes.\r\nSo Pating's wife will reach their home first.\n\r\nBut if this is a combination of a math and trick question, they will arrive at their house together. \n\r\nIf his wife really loves him, she'll let him inside the cab as soon as the cab overtakes Pating.\n<|im_end|>" }, { "id": "#33963", "title": "Doing The Math On The Ever-Slowing Drive", "fun": 2.52, "difficulty": 2.08, "author": "shane91592", "desc": "You're driving your car on the highway at 75 mph, and you notice a sign that says you are 75 miles from your destination. So if you continue driving at that speed, you'd be there in an hour.\n\r\nWhen you have driven one mile and you are now 74 miles from your destination, you drop your speed down to 74 mph.\n\r\nSo, you drive that first mile at 75 mph; when you are 74 miles from your destination, you drop your speed down to 74 mph; and then 73 mph, 72 mph... and so on. Until, finally, you get down to 1 mile from your destination and you're driving at one mile per hour.\n\r\nIf you do this, how long is it going to take you to travel the entire 75 miles, rounding it to the nearest hour?", "hint": "No hint available.", "answer": "It will take approximately 5 hours. The way to figure this one out is to divide 60 by 1, 60 by 2, 60 by 3....60 by 74, 60 by 75. Once you have found the answer to each of those equations, add them all up, and this will give you your answer in minutes. To get the answer in hours,just divide the number of minutes by sixty, round it to the nearest hour, and you will have your answer.", "category": "Math", "date": "11/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou're driving your car on the highway at 75 mph, and you notice a sign that says you are 75 miles from your destination. So if you continue driving at that speed, you'd be there in an hour.\n\r\nWhen you have driven one mile and you are now 74 miles from your destination, you drop your speed down to 74 mph.\n\r\nSo, you drive that first mile at 75 mph; when you are 74 miles from your destination, you drop your speed down to 74 mph; and then 73 mph, 72 mph... and so on. Until, finally, you get down to 1 mile from your destination and you're driving at one mile per hour.\n\r\nIf you do this, how long is it going to take you to travel the entire 75 miles, rounding it to the nearest hour?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will take approximately 5 hours. The way to figure this one out is to divide 60 by 1, 60 by 2, 60 by 3....60 by 74, 60 by 75. Once you have found the answer to each of those equations, add them all up, and this will give you your answer in minutes. To get the answer in hours,just divide the number of minutes by sixty, round it to the nearest hour, and you will have your answer.\n<|im_start|>answer\nIt will take approximately 5 hours. The way to figure this one out is to divide 60 by 1, 60 by 2, 60 by 3....60 by 74, 60 by 75. Once you have found the answer to each of those equations, add them all up, and this will give you your answer in minutes. To get the answer in hours,just divide the number of minutes by sixty, round it to the nearest hour, and you will have your answer.\n<|im_end|>" }, { "id": "#11999", "title": "Math Madness", "fun": 2.52, "difficulty": 1.87, "author": "jcjcisdabomb", "desc": "Draw a 3 x 3 grid so it has 9 boxes. You have to write the numbers 0 to 8 in each box so that going side to side, up and down, and diagonally the sum is 12. Each number can be used only once.", "hint": "No hint available.", "answer": "5 0 7\r\n6 4 2 \r\n1 8 3", "category": "Math", "date": "04/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDraw a 3 x 3 grid so it has 9 boxes. You have to write the numbers 0 to 8 in each box so that going side to side, up and down, and diagonally the sum is 12. Each number can be used only once.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 0 7\r\n6 4 2 \r\n1 8 3\n<|im_start|>answer\n5 0 7\r\n6 4 2 \r\n1 8 3\n<|im_end|>" }, { "id": "#14086", "title": "Number Trick...", "fun": 2.52, "difficulty": 2.08, "author": "wxscooter", "desc": "Professor X has managed to create a simple program that can multiply any two whole numbers and calculate the answer correctly.\n\r\nBut, a problem has arisen....it seems the program will NOT correctly multiply a number by itself (such as 4 X 4).\n\r\nFortunately, the professor knows a way to get around this glitch.\n\r\nKeeping in mind that the program must accept ANY whole integer, do you know a way to have the program multiply the numbers in a different way to get the correct result? \r\nThis method only has to work when multiplying a number by itself.", "hint": "No hint available.", "answer": "Here's a neat trick to calculate any given number multiplied by itself:\n\r\nTake one less than the given number and multiply it by one greater than the given number and add 1.\n\r\nFor example:\r\n25 X 25 = 625\r\n24 X 26 = 624 + 1 = 625\n\r\nIt also works for negative numbers:\r\n-1 X -1 = 1\r\n-2 X 0 + 1 = 1\n\r\nThe mathematical formula that the professor should use would be:\n\r\n(n = given integer)\r\n(n + 1) X (n - 1) + 1\n\r\nThis would be equivalent to n X n.", "category": "Math", "date": "07/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nProfessor X has managed to create a simple program that can multiply any two whole numbers and calculate the answer correctly.\n\r\nBut, a problem has arisen....it seems the program will NOT correctly multiply a number by itself (such as 4 X 4).\n\r\nFortunately, the professor knows a way to get around this glitch.\n\r\nKeeping in mind that the program must accept ANY whole integer, do you know a way to have the program multiply the numbers in a different way to get the correct result? \r\nThis method only has to work when multiplying a number by itself.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHere's a neat trick to calculate any given number multiplied by itself:\n\r\nTake one less than the given number and multiply it by one greater than the given number and add 1.\n\r\nFor example:\r\n25 X 25 = 625\r\n24 X 26 = 624 + 1 = 625\n\r\nIt also works for negative numbers:\r\n-1 X -1 = 1\r\n-2 X 0 + 1 = 1\n\r\nThe mathematical formula that the professor should use would be:\n\r\n(n = given integer)\r\n(n + 1) X (n - 1) + 1\n\r\nThis would be equivalent to n X n.\n<|im_start|>answer\nHere's a neat trick to calculate any given number multiplied by itself:\n\r\nTake one less than the given number and multiply it by one greater than the given number and add 1.\n\r\nFor example:\r\n25 X 25 = 625\r\n24 X 26 = 624 + 1 = 625\n\r\nIt also works for negative numbers:\r\n-1 X -1 = 1\r\n-2 X 0 + 1 = 1\n\r\nThe mathematical formula that the professor should use would be:\n\r\n(n = given integer)\r\n(n + 1) X (n - 1) + 1\n\r\nThis would be equivalent to n X n.\n<|im_end|>" }, { "id": "#19696", "title": "The Five Cards", "fun": 2.52, "difficulty": 1.13, "author": "weirdness_-_-", "desc": "Five cards sit on the table. Each has a different design or shape on it. The five cards are: Diamond, Wavy Lines, Square, Triangle, and Circle. Given the following 5 clues, can you decide the order of the five cards?\r\n1.The Square and the Diamond have 2 cards between them.\r\n2.The Wavy Lines are to the right of the Diamond.\r\n3.The Square and Wavy Lines are as far apart as possible.\r\n4.The Circle is not to the side of the Diamond.\r\n5.The Triangle is not first in the sequence.", "hint": "This teaser is very easy if you draw a diagram.", "answer": "The order was Square, Circle, Triangle, Diamond, Wavy Lines.\r\nClue 1: We know now that the Square and Diamond are 3 cards apart, so the Square must fall 1st or 2nd and the Diamond 4th or last.\r\n2.The Wavy Lines are to the Diamond's right, so the Diamond falls 4th leaving the Square at 1st.\r\n3.This is just a hint to let you know the Square was 1st.\r\n4.The Circle wasn't to the side of the Diamond, so it had to fall 2nd, next to the Square.\r\n5. The Triangle wasn't 1st, so it had to fit in the last place not taken, 3rd, or to the left of the Diamond.", "category": "Logic", "date": "12/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive cards sit on the table. Each has a different design or shape on it. The five cards are: Diamond, Wavy Lines, Square, Triangle, and Circle. Given the following 5 clues, can you decide the order of the five cards?\r\n1.The Square and the Diamond have 2 cards between them.\r\n2.The Wavy Lines are to the right of the Diamond.\r\n3.The Square and Wavy Lines are as far apart as possible.\r\n4.The Circle is not to the side of the Diamond.\r\n5.The Triangle is not first in the sequence.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe order was Square, Circle, Triangle, Diamond, Wavy Lines.\r\nClue 1: We know now that the Square and Diamond are 3 cards apart, so the Square must fall 1st or 2nd and the Diamond 4th or last.\r\n2.The Wavy Lines are to the Diamond's right, so the Diamond falls 4th leaving the Square at 1st.\r\n3.This is just a hint to let you know the Square was 1st.\r\n4.The Circle wasn't to the side of the Diamond, so it had to fall 2nd, next to the Square.\r\n5. The Triangle wasn't 1st, so it had to fit in the last place not taken, 3rd, or to the left of the Diamond.\n<|im_start|>answer\nThe order was Square, Circle, Triangle, Diamond, Wavy Lines.\r\nClue 1: We know now that the Square and Diamond are 3 cards apart, so the Square must fall 1st or 2nd and the Diamond 4th or last.\r\n2.The Wavy Lines are to the Diamond's right, so the Diamond falls 4th leaving the Square at 1st.\r\n3.This is just a hint to let you know the Square was 1st.\r\n4.The Circle wasn't to the side of the Diamond, so it had to fall 2nd, next to the Square.\r\n5. The Triangle wasn't 1st, so it had to fit in the last place not taken, 3rd, or to the left of the Diamond.\n<|im_end|>" }, { "id": "#1456", "title": "Four Clowns", "fun": 2.52, "difficulty": 1.96, "author": "psychodude57", "desc": "Four clowns were getting ready for the evening's performance. From the clothes trunk each clown had to get their socks and shoes. There was one pair of each shoes and socks in each color. The red socks went with the blue shoes. Baba had yellow shoes but not yellow socks. The clown with green shoes did not have blue socks. Boba had neither red shoes nor red socks. Bilbo's shoes were the same colour as Babil's socks. The clown with red shoes had green socks. Can you tell who had which color shoes and socks?", "hint": "No hint available.", "answer": "Baba had yellow shoes and blue socks.\r\nBoba had green shoes and yellow socks.\r\nBilbo had red shoes and green socks.\r\nBabil had blue shoes and red socks.", "category": "Logic", "date": "11/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour clowns were getting ready for the evening's performance. From the clothes trunk each clown had to get their socks and shoes. There was one pair of each shoes and socks in each color. The red socks went with the blue shoes. Baba had yellow shoes but not yellow socks. The clown with green shoes did not have blue socks. Boba had neither red shoes nor red socks. Bilbo's shoes were the same colour as Babil's socks. The clown with red shoes had green socks. Can you tell who had which color shoes and socks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBaba had yellow shoes and blue socks.\r\nBoba had green shoes and yellow socks.\r\nBilbo had red shoes and green socks.\r\nBabil had blue shoes and red socks.\n<|im_start|>answer\nBaba had yellow shoes and blue socks.\r\nBoba had green shoes and yellow socks.\r\nBilbo had red shoes and green socks.\r\nBabil had blue shoes and red socks.\n<|im_end|>" }, { "id": "#6710", "title": "Doesn't Add Up 2", "fun": 2.52, "difficulty": 1.96, "author": "dumbell", "desc": "How can you take one away from twenty nine and be left with thirty?", "hint": "No hint available.", "answer": "Use roman numerals. XXIX take out (i.e. take away) the I leaves XXX.", "category": "Math", "date": "08/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can you take one away from twenty nine and be left with thirty?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUse roman numerals. XXIX take out (i.e. take away) the I leaves XXX.\n<|im_start|>answer\nUse roman numerals. XXIX take out (i.e. take away) the I leaves XXX.\n<|im_end|>" }, { "id": "#20078", "title": "Divisorama", "fun": 2.52, "difficulty": 2.79, "author": "cnmne", "desc": "Arrange the numerals \"123456789\" to form a 9-digit number (referred to as \"ABCDEFGHI\") whose 2-digit subsets meet the following criteria:\n\r\n1) AB is divisible by 2\r\n2) BC is divisible by 3\r\n3) CD is divisible by 4\r\n4) DE is divisible by 5\r\n5) EF is divisible by 6\r\n6) FG is divisible by 7\r\n7) GH is divisible by 8\r\n8) HI is divisible by 9\n\r\nThere are two solutions.", "hint": "No hint available.", "answer": "781254963 and 187254963\n\r\nAB, CD, EF, and GH must be divisible by even divisors. Therefore B, D, F, and H must be even numerals. This means that A, C, E, G, and I are odd numerals. DE must be divisible by 5, therefore E is 5. EF must be divisible by 6, therefore EF is 54. FG must be divisible by 7, therefore FG is 49. GH must be divisible by 8, therefore GH is 96. GH must be divisible by 9, therefore GH is 63. The last five digits have now been determined to be 54963. To be divisible by 4, CD must end in 2. This makes B equal 8. The digits are now ?8?254963. The remaining digits, 1 and 7, can be placed into either remaining location.", "category": "Math", "date": "12/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numerals \"123456789\" to form a 9-digit number (referred to as \"ABCDEFGHI\") whose 2-digit subsets meet the following criteria:\n\r\n1) AB is divisible by 2\r\n2) BC is divisible by 3\r\n3) CD is divisible by 4\r\n4) DE is divisible by 5\r\n5) EF is divisible by 6\r\n6) FG is divisible by 7\r\n7) GH is divisible by 8\r\n8) HI is divisible by 9\n\r\nThere are two solutions.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n781254963 and 187254963\n\r\nAB, CD, EF, and GH must be divisible by even divisors. Therefore B, D, F, and H must be even numerals. This means that A, C, E, G, and I are odd numerals. DE must be divisible by 5, therefore E is 5. EF must be divisible by 6, therefore EF is 54. FG must be divisible by 7, therefore FG is 49. GH must be divisible by 8, therefore GH is 96. GH must be divisible by 9, therefore GH is 63. The last five digits have now been determined to be 54963. To be divisible by 4, CD must end in 2. This makes B equal 8. The digits are now ?8?254963. The remaining digits, 1 and 7, can be placed into either remaining location.\n<|im_start|>answer\n781254963 and 187254963\n\r\nAB, CD, EF, and GH must be divisible by even divisors. Therefore B, D, F, and H must be even numerals. This means that A, C, E, G, and I are odd numerals. DE must be divisible by 5, therefore E is 5. EF must be divisible by 6, therefore EF is 54. FG must be divisible by 7, therefore FG is 49. GH must be divisible by 8, therefore GH is 96. GH must be divisible by 9, therefore GH is 63. The last five digits have now been determined to be 54963. To be divisible by 4, CD must end in 2. This makes B equal 8. The digits are now ?8?254963. The remaining digits, 1 and 7, can be placed into either remaining location.\n<|im_end|>" }, { "id": "#36198", "title": "Opposites 31", "fun": 2.52, "difficulty": 1.93, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n= stands for H, B, E, V, or O\r\n4 stands for J, D, L, M, or U\r\n8 stands for O, S, G, K, or E\r\n9 stands for R, N, T, F, or S\n\r\nThe four letter code word, 4=98, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "More and Less.", "category": "Logic", "date": "04/12/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n= stands for H, B, E, V, or O\r\n4 stands for J, D, L, M, or U\r\n8 stands for O, S, G, K, or E\r\n9 stands for R, N, T, F, or S\n\r\nThe four letter code word, 4=98, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMore and Less.\n<|im_start|>answer\nMore and Less.\n<|im_end|>" }, { "id": "#8890", "title": "Swimming to Shore", "fun": 2.52, "difficulty": 2.82, "author": "lesternoronha1", "desc": "A man is standing on a rock in the middle of a circular lake of radius 1. There is a tiger on the shore of the lake that can run four times as fast you can swim, however the tiger cannot swim. The tiger is hungry and always attempts to keep the distance between the two of you at a minimum. How can you safely swim to shore?\n\r\nAssume that as long as you can get to the shore before the tiger gets to you (even if it is only a split-second before), you will be safe.", "hint": "No hint available.", "answer": "Until you are more than 1/4 of the radius away from the rock you can swim fast enough so that you can keep the tiger the furthest distance possible from you. Regardless of which direction the tiger moves around the circle, you swim the other way, always keeping the rock between you and the tiger. While you are doing this you will be able to move outward, since you will have some energy to spare.\r\nBefore long you will be 1/4 of the radius away from the center and the tiger will be 180 degrees away. At this point swim straight to the point on the shore furthest from the tiger. You will be able to get there in 3/4 units of time, while it will take the tiger pi/4 =~ 0.7854 units of time.", "category": "Math", "date": "12/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is standing on a rock in the middle of a circular lake of radius 1. There is a tiger on the shore of the lake that can run four times as fast you can swim, however the tiger cannot swim. The tiger is hungry and always attempts to keep the distance between the two of you at a minimum. How can you safely swim to shore?\n\r\nAssume that as long as you can get to the shore before the tiger gets to you (even if it is only a split-second before), you will be safe.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUntil you are more than 1/4 of the radius away from the rock you can swim fast enough so that you can keep the tiger the furthest distance possible from you. Regardless of which direction the tiger moves around the circle, you swim the other way, always keeping the rock between you and the tiger. While you are doing this you will be able to move outward, since you will have some energy to spare.\r\nBefore long you will be 1/4 of the radius away from the center and the tiger will be 180 degrees away. At this point swim straight to the point on the shore furthest from the tiger. You will be able to get there in 3/4 units of time, while it will take the tiger pi/4 =~ 0.7854 units of time.\n<|im_start|>answer\nUntil you are more than 1/4 of the radius away from the rock you can swim fast enough so that you can keep the tiger the furthest distance possible from you. Regardless of which direction the tiger moves around the circle, you swim the other way, always keeping the rock between you and the tiger. While you are doing this you will be able to move outward, since you will have some energy to spare.\r\nBefore long you will be 1/4 of the radius away from the center and the tiger will be 180 degrees away. At this point swim straight to the point on the shore furthest from the tiger. You will be able to get there in 3/4 units of time, while it will take the tiger pi/4 =~ 0.7854 units of time.\n<|im_end|>" }, { "id": "#119", "title": "A Democrat and a Republican", "fun": 2.52, "difficulty": 1.6, "author": "Phyllis", "desc": "A Democrat and a Republican are being interviewed. \n\r\n\"I am a Republican\", says the man. \n\r\n\"I am a Democrat\", says the woman. Assume that at least one of them is lying. Which one is it?", "hint": "No hint available.", "answer": "Both of them are liars! If the woman was lying, then there would be two Republicans. If the man was lying, there would be two Democrats. We are told that one is a Democrat and one a Republican and that at least one of them is lying. Therefore, both are lying.", "category": "Logic", "date": "01/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA Democrat and a Republican are being interviewed. \n\r\n\"I am a Republican\", says the man. \n\r\n\"I am a Democrat\", says the woman. Assume that at least one of them is lying. Which one is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoth of them are liars! If the woman was lying, then there would be two Republicans. If the man was lying, there would be two Democrats. We are told that one is a Democrat and one a Republican and that at least one of them is lying. Therefore, both are lying.\n<|im_start|>answer\nBoth of them are liars! If the woman was lying, then there would be two Republicans. If the man was lying, there would be two Democrats. We are told that one is a Democrat and one a Republican and that at least one of them is lying. Therefore, both are lying.\n<|im_end|>" }, { "id": "#31795", "title": "Liars, Liars #2", "fun": 2.52, "difficulty": 1.69, "author": "teen_wiz", "desc": "In the land of Brainopia, there are three races of people: Mikkos, who tell the truth all the time, Kikkos, who always tell lies, and Zikkos who tell alternate false and true statements, in which the order is not known (i.e. true/false/true or false/true/false).\n\r\nA foreigner visiting Brainopia approached three Brainopians, hoping to get a straight answer as to which of them was of what race. He only asked one Brainopian to tell the races of himself and his companions. This was the reply the foreigner received:\n\r\nPerson 1:\r\na. I am not the Mikko.\r\nb. Person 2 is not the Kikko.\r\nc. Person 3 is not the Zikko.\n\r\nCan you help the foreigner determine who is who, assuming each person represents a different race?", "hint": "No hint available.", "answer": "Person 1 is a Zikko.\r\nPerson 2 is a Kikko.\r\nPerson 3 is a Mikko.", "category": "Logic", "date": "07/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of Brainopia, there are three races of people: Mikkos, who tell the truth all the time, Kikkos, who always tell lies, and Zikkos who tell alternate false and true statements, in which the order is not known (i.e. true/false/true or false/true/false).\n\r\nA foreigner visiting Brainopia approached three Brainopians, hoping to get a straight answer as to which of them was of what race. He only asked one Brainopian to tell the races of himself and his companions. This was the reply the foreigner received:\n\r\nPerson 1:\r\na. I am not the Mikko.\r\nb. Person 2 is not the Kikko.\r\nc. Person 3 is not the Zikko.\n\r\nCan you help the foreigner determine who is who, assuming each person represents a different race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPerson 1 is a Zikko.\r\nPerson 2 is a Kikko.\r\nPerson 3 is a Mikko.\n<|im_start|>answer\nPerson 1 is a Zikko.\r\nPerson 2 is a Kikko.\r\nPerson 3 is a Mikko.\n<|im_end|>" }, { "id": "#2340", "title": "Flipping Pages", "fun": 2.52, "difficulty": 2.06, "author": "ChuckieChen", "desc": "Yesterday I went through a book, which I had already read, in a peculiar manner. After I had finished a page, I flipped to the next page, then rotated the book 180 degrees. After that page, I rotated it 180 degrees and then flipped through the next page, rotated the book 180 degrees again, and continued in this fashion until I was done with the whole book. What was I doing?", "hint": "No hint available.", "answer": "I was photocopying the book.", "category": "Logic", "date": "02/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYesterday I went through a book, which I had already read, in a peculiar manner. After I had finished a page, I flipped to the next page, then rotated the book 180 degrees. After that page, I rotated it 180 degrees and then flipped through the next page, rotated the book 180 degrees again, and continued in this fashion until I was done with the whole book. What was I doing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI was photocopying the book.\n<|im_start|>answer\nI was photocopying the book.\n<|im_end|>" }, { "id": "#9416", "title": "Five Sisters, Three Bedrooms", "fun": 2.52, "difficulty": 1.13, "author": "queenlila", "desc": "Lise, Meg, Jeanne, Ally, and Sadie are sisters. Their family has just moved into a new house. There are three bedrooms available for the five girls:\r\nOne large bedroom with a bathroom\r\nOne medium-sized bedroom\r\nOne small bedroom with a bathroom\n\r\nThe family plans to put two girls each into the large and medium-sized rooms and one girl into the small room. Each girl makes the following demands:\n\r\n-Sadie is afraid of the dark and wants to share a room.\r\n-Lise wants a bathroom in her room.\r\n-Meg likes the view from the medium-sized room.\r\n-Ally wants to share a room, but not with Sadie or Meg.\r\n-Jeanne wants her own room unless she can share with Meg.\n\r\nBased on these requests, who should get each room?", "hint": "Try making a chart.", "answer": "Large room: Ally and Lise.\r\nMedium-sized room: Meg and Sadie.\r\nSmall room: Jeanne.\n\r\nThe logic:\r\nSadie wants to share, so she can't be in the small room.\r\nLise wants a bathroom, so she can't be in the medium-sized room.\r\nMeg has to be in the medium-sized room.\r\nAlly wants to share, but not with Meg, so she has to be in the large room. She won't share with Sadie either, so Sadie must be with Meg in the medium-sized room.\r\nJeanne can't share with Meg because Sadie is sharing with Meg, so she has to have her own room.\r\nThis leaves Lise in the large room with Ally.", "category": "Logic", "date": "12/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLise, Meg, Jeanne, Ally, and Sadie are sisters. Their family has just moved into a new house. There are three bedrooms available for the five girls:\r\nOne large bedroom with a bathroom\r\nOne medium-sized bedroom\r\nOne small bedroom with a bathroom\n\r\nThe family plans to put two girls each into the large and medium-sized rooms and one girl into the small room. Each girl makes the following demands:\n\r\n-Sadie is afraid of the dark and wants to share a room.\r\n-Lise wants a bathroom in her room.\r\n-Meg likes the view from the medium-sized room.\r\n-Ally wants to share a room, but not with Sadie or Meg.\r\n-Jeanne wants her own room unless she can share with Meg.\n\r\nBased on these requests, who should get each room?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLarge room: Ally and Lise.\r\nMedium-sized room: Meg and Sadie.\r\nSmall room: Jeanne.\n\r\nThe logic:\r\nSadie wants to share, so she can't be in the small room.\r\nLise wants a bathroom, so she can't be in the medium-sized room.\r\nMeg has to be in the medium-sized room.\r\nAlly wants to share, but not with Meg, so she has to be in the large room. She won't share with Sadie either, so Sadie must be with Meg in the medium-sized room.\r\nJeanne can't share with Meg because Sadie is sharing with Meg, so she has to have her own room.\r\nThis leaves Lise in the large room with Ally.\n<|im_start|>answer\nLarge room: Ally and Lise.\r\nMedium-sized room: Meg and Sadie.\r\nSmall room: Jeanne.\n\r\nThe logic:\r\nSadie wants to share, so she can't be in the small room.\r\nLise wants a bathroom, so she can't be in the medium-sized room.\r\nMeg has to be in the medium-sized room.\r\nAlly wants to share, but not with Meg, so she has to be in the large room. She won't share with Sadie either, so Sadie must be with Meg in the medium-sized room.\r\nJeanne can't share with Meg because Sadie is sharing with Meg, so she has to have her own room.\r\nThis leaves Lise in the large room with Ally.\n<|im_end|>" }, { "id": "#26055", "title": "Talent Show", "fun": 2.52, "difficulty": 0.8, "author": "upper90xox", "desc": "Gavin, Danny, Zander, and Stan teamed up with Galinda, Allyson, Sarah, and Deanna to sing songs at their school talent show. Determine which duo (boy-girl teams) sang which song, and who the partners were, using the clues below.\n\r\n1. Zander was half of the duo that had a hit with the hip-hop song: \"Dirty Pop\".\n\r\n2. The male half of the duo that had a hit with the rock beat \"Welcome to the Jungle\" wasn't Stan or Gavin.\n\r\n3. Stan (whose partner wasn't Allyson or Deanna) wasn't the male half of the duo who had a hit with the reggae tune \"Jamming\".\n\r\n4. Danny did not perform with Galinda or Deanna.\n\r\n5. Galinda (whose partner wasn't Gavin) wasn't the female half of the duo who sang the country song \"Man! I Feel Like a Woman!\"", "hint": "No hint available.", "answer": "Danny and Allyson sang \"Welcome to the Jungle\".\n\r\nGavin and Deanna sang \"Jamming\".\n\r\nStan and Sarah sang \"Man! I Feel Like a Woman!\"\n\r\nZander and Galinda sang \"Dirty Pop\".", "category": "Logic-Grid", "date": "09/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGavin, Danny, Zander, and Stan teamed up with Galinda, Allyson, Sarah, and Deanna to sing songs at their school talent show. Determine which duo (boy-girl teams) sang which song, and who the partners were, using the clues below.\n\r\n1. Zander was half of the duo that had a hit with the hip-hop song: \"Dirty Pop\".\n\r\n2. The male half of the duo that had a hit with the rock beat \"Welcome to the Jungle\" wasn't Stan or Gavin.\n\r\n3. Stan (whose partner wasn't Allyson or Deanna) wasn't the male half of the duo who had a hit with the reggae tune \"Jamming\".\n\r\n4. Danny did not perform with Galinda or Deanna.\n\r\n5. Galinda (whose partner wasn't Gavin) wasn't the female half of the duo who sang the country song \"Man! I Feel Like a Woman!\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDanny and Allyson sang \"Welcome to the Jungle\".\n\r\nGavin and Deanna sang \"Jamming\".\n\r\nStan and Sarah sang \"Man! I Feel Like a Woman!\"\n\r\nZander and Galinda sang \"Dirty Pop\".\n<|im_start|>answer\nDanny and Allyson sang \"Welcome to the Jungle\".\n\r\nGavin and Deanna sang \"Jamming\".\n\r\nStan and Sarah sang \"Man! I Feel Like a Woman!\"\n\r\nZander and Galinda sang \"Dirty Pop\".\n<|im_end|>" }, { "id": "#24285", "title": "Melvin the Wizard", "fun": 2.52, "difficulty": 2.26, "author": "Riddlerman", "desc": "Melvin the Wizard has some magic blue orbs.\n\r\nEvery day 1 disappears.\r\nEvery 2 days 1 goes green.\r\nEvery 4 days 1 green orb disappears instead of another blue one.\n\r\nFrom these facts, determine what the ratio of blue to green (or vice versa) orbs remaining is from the beginning to the end of February in the Year 2292. He has 50 orbs at the start of February.", "hint": "It is easier to work it out in a 10 x 5 grid.", "answer": "The ratio is 1 : 2 (green : blue).\n\r\nIf you draw a 10 x 5 grid, cross out a square for each orb that disappears. Put a circle in each box for each green orb. The year 2292 is a leap year, so there are 29 days in the month (February). Mark each 'day' you work out. You will find on each row, you get 4 disappeared orbs and 1 green orb. This pattern continues, so when you have counted 29 days, there are 14 blue orbs remaining and 7 green ones. This gives you the ratio of 1 : 2 (green : blue)", "category": "Math", "date": "07/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMelvin the Wizard has some magic blue orbs.\n\r\nEvery day 1 disappears.\r\nEvery 2 days 1 goes green.\r\nEvery 4 days 1 green orb disappears instead of another blue one.\n\r\nFrom these facts, determine what the ratio of blue to green (or vice versa) orbs remaining is from the beginning to the end of February in the Year 2292. He has 50 orbs at the start of February.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ratio is 1 : 2 (green : blue).\n\r\nIf you draw a 10 x 5 grid, cross out a square for each orb that disappears. Put a circle in each box for each green orb. The year 2292 is a leap year, so there are 29 days in the month (February). Mark each 'day' you work out. You will find on each row, you get 4 disappeared orbs and 1 green orb. This pattern continues, so when you have counted 29 days, there are 14 blue orbs remaining and 7 green ones. This gives you the ratio of 1 : 2 (green : blue)\n<|im_start|>answer\nThe ratio is 1 : 2 (green : blue).\n\r\nIf you draw a 10 x 5 grid, cross out a square for each orb that disappears. Put a circle in each box for each green orb. The year 2292 is a leap year, so there are 29 days in the month (February). Mark each 'day' you work out. You will find on each row, you get 4 disappeared orbs and 1 green orb. This pattern continues, so when you have counted 29 days, there are 14 blue orbs remaining and 7 green ones. This gives you the ratio of 1 : 2 (green : blue)\n<|im_end|>" }, { "id": "#12258", "title": "A Trip Around the World", "fun": 2.52, "difficulty": 1.87, "author": "PebblesExtreme", "desc": "Albert, who was just back from his trip around the world in a sailboat, asked me, \"What part of my boat has travelled the longest distance?\"", "hint": "No hint available.", "answer": "The mast, in other words the top of the highest mast (top of the sail).\n\r\nThe earth is round(ish), therefore the mast would form a concentric circle with the hull (for example). The mast, being the furthest away from the centre of the earth, would form a circle whose circumference would be bigger, therefore it would have travelled the longest distance.", "category": "Logic", "date": "05/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlbert, who was just back from his trip around the world in a sailboat, asked me, \"What part of my boat has travelled the longest distance?\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe mast, in other words the top of the highest mast (top of the sail).\n\r\nThe earth is round(ish), therefore the mast would form a concentric circle with the hull (for example). The mast, being the furthest away from the centre of the earth, would form a circle whose circumference would be bigger, therefore it would have travelled the longest distance.\n<|im_start|>answer\nThe mast, in other words the top of the highest mast (top of the sail).\n\r\nThe earth is round(ish), therefore the mast would form a concentric circle with the hull (for example). The mast, being the furthest away from the centre of the earth, would form a circle whose circumference would be bigger, therefore it would have travelled the longest distance.\n<|im_end|>" }, { "id": "#12781", "title": "Long Distance Runner", "fun": 2.52, "difficulty": 1.84, "author": "adoontourious", "desc": "Adoontourious wanted to run the shore-to-shore marathon next month, a 26-mile race from one side of the island where he lived to the other. He decided to work up the 26 miles by running five days a week for the next five weeks. Each day he'd run one mile longer than he did the day before, except for the first day of each week, when he'd run the same number of miles he ran on the last day of the previous week. He wanted his last two practice runs to be 26 and 27 miles long. \n\r\nHow many miles would he have to run on his first practice run?", "hint": "No hint available.", "answer": "Adoontourious will have to run 7 miles on his first run in order to run 27 miles on his last run. \n\r\nSince he will run the same amount of miles on the first day of each week as on the last day of the previous week, and he will run one more mile than the previous day on the other four days of each week, then he will add four miles to the length of his daily practice run by the end of each week. In five weeks he will have added 20 miles to his daily run, so he will have to start at seven miles to reach is goal (27-20=7).", "category": "Math", "date": "05/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdoontourious wanted to run the shore-to-shore marathon next month, a 26-mile race from one side of the island where he lived to the other. He decided to work up the 26 miles by running five days a week for the next five weeks. Each day he'd run one mile longer than he did the day before, except for the first day of each week, when he'd run the same number of miles he ran on the last day of the previous week. He wanted his last two practice runs to be 26 and 27 miles long. \n\r\nHow many miles would he have to run on his first practice run?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdoontourious will have to run 7 miles on his first run in order to run 27 miles on his last run. \n\r\nSince he will run the same amount of miles on the first day of each week as on the last day of the previous week, and he will run one more mile than the previous day on the other four days of each week, then he will add four miles to the length of his daily practice run by the end of each week. In five weeks he will have added 20 miles to his daily run, so he will have to start at seven miles to reach is goal (27-20=7).\n<|im_start|>answer\nAdoontourious will have to run 7 miles on his first run in order to run 27 miles on his last run. \n\r\nSince he will run the same amount of miles on the first day of each week as on the last day of the previous week, and he will run one more mile than the previous day on the other four days of each week, then he will add four miles to the length of his daily practice run by the end of each week. In five weeks he will have added 20 miles to his daily run, so he will have to start at seven miles to reach is goal (27-20=7).\n<|im_end|>" }, { "id": "#44409", "title": "Grandpa Dan's Bad Memory", "fun": 2.52, "difficulty": 0.8300000000000001, "author": "MegRen", "desc": "Grandpa Dan has 5 grandchildren, all of different ages. Each grandchild has a different pet as well. As he gets older, Grandpa's memory isn't what it used to be, so he can't remember the ages and pets of his grandchildren. Using the clues below, can you figure out each child's age and pet?\n\r\n1. No child has a pet with the same first letter as their name.\r\n2. Cats and dogs require a lot of work and responsibility, so only the oldest children have one of these pets.\r\n3. The youngest child has loved reptiles and amphibians since he saw Finding Nemo.\r\n4. Davey hopes to get his pet to sing \"Happy Birthday\" to him on his tenth birthday.\r\n5. Carmen loves taking her pet for a walk on his new leash every day.\r\n6. Howie keeps his pet in a box.\r\n7. Traci hates cleaning her pet's cage. Her pet always hides in its exercise wheel.\r\n8. Patrick hopes he can get a dog when he turns thirteen, just like his cousin did.", "hint": "No hint available.", "answer": "Carmen, 13, has a dog.\r\nDavey, 9, has a parrot.\r\nHowie, 4, has a turtle.\r\nPatrick, 11, has a cat.\r\nTraci, 5, has a hamster.", "category": "Logic-Grid", "date": "05/03/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrandpa Dan has 5 grandchildren, all of different ages. Each grandchild has a different pet as well. As he gets older, Grandpa's memory isn't what it used to be, so he can't remember the ages and pets of his grandchildren. Using the clues below, can you figure out each child's age and pet?\n\r\n1. No child has a pet with the same first letter as their name.\r\n2. Cats and dogs require a lot of work and responsibility, so only the oldest children have one of these pets.\r\n3. The youngest child has loved reptiles and amphibians since he saw Finding Nemo.\r\n4. Davey hopes to get his pet to sing \"Happy Birthday\" to him on his tenth birthday.\r\n5. Carmen loves taking her pet for a walk on his new leash every day.\r\n6. Howie keeps his pet in a box.\r\n7. Traci hates cleaning her pet's cage. Her pet always hides in its exercise wheel.\r\n8. Patrick hopes he can get a dog when he turns thirteen, just like his cousin did.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarmen, 13, has a dog.\r\nDavey, 9, has a parrot.\r\nHowie, 4, has a turtle.\r\nPatrick, 11, has a cat.\r\nTraci, 5, has a hamster.\n<|im_start|>answer\nCarmen, 13, has a dog.\r\nDavey, 9, has a parrot.\r\nHowie, 4, has a turtle.\r\nPatrick, 11, has a cat.\r\nTraci, 5, has a hamster.\n<|im_end|>" }, { "id": "#36287", "title": "Special Sunday Activity", "fun": 2.52, "difficulty": 1.71, "author": "FatHead", "desc": "Every 5th Sunday of the month (when the month even has five Sundays), the local church has a special coeducational activity planned, in place of Sunday School. How often, or on how many Sundays, does this happen each year?\n\r\nAssume that if ever there's a 53rd Sunday in the year, the activity is cancelled due to the church's really tight budget, so that there's always 52 Sundays to deal with.", "hint": "At least how many Sundays does each month have? What does that tell you about its 1st, 2nd, 3rd and 4th Sundays?", "answer": "This takes place on four Sundays a year. \n\r\nThe year has 52 Sundays, and each month has a 1st, 2nd, 3rd and 4th Sunday. That totals 48, leaving 4 unaccounted for. These four must be the 5th Sundays.", "category": "Math", "date": "04/17/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery 5th Sunday of the month (when the month even has five Sundays), the local church has a special coeducational activity planned, in place of Sunday School. How often, or on how many Sundays, does this happen each year?\n\r\nAssume that if ever there's a 53rd Sunday in the year, the activity is cancelled due to the church's really tight budget, so that there's always 52 Sundays to deal with.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis takes place on four Sundays a year. \n\r\nThe year has 52 Sundays, and each month has a 1st, 2nd, 3rd and 4th Sunday. That totals 48, leaving 4 unaccounted for. These four must be the 5th Sundays.\n<|im_start|>answer\nThis takes place on four Sundays a year. \n\r\nThe year has 52 Sundays, and each month has a 1st, 2nd, 3rd and 4th Sunday. That totals 48, leaving 4 unaccounted for. These four must be the 5th Sundays.\n<|im_end|>" }, { "id": "#3351", "title": "Bike Trip", "fun": 2.52, "difficulty": 1.9000000000000001, "author": "204_BLaZe_41", "desc": "Justin Time was on a gruelling trip from his hometown of Neutron to the town of Proton. Justin and his bicycle were able to hitch a ride to the town of Electron, which was exactly halfway to Proton. The ride lasted one hour, and was ten times faster than if Justin had cycled the same distance. When Justin got out of the car at Electron he noticed his tire was flat, which meant walking the rest of the way to Proton. Walking took him twice as long as cycling. When Justin finally reached Proton, he repaired his bicycle tire and rode the entire distance home to Neutron. How much time did each trip take and which of the two was faster?", "hint": "No hint available.", "answer": "The return trip was faster. Since it was one hour to Electron by car, which was ten times faster than cycling, the time from Electron to Proton took an additional 20 hours since he walked, and walking took twice as long as cycling. Therefore, the first half of the trip took a total of 21 hours. The return trip took Justin 20 hours, since he cycled the entire distance and cycling is twice as fast as walking.", "category": "Math", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJustin Time was on a gruelling trip from his hometown of Neutron to the town of Proton. Justin and his bicycle were able to hitch a ride to the town of Electron, which was exactly halfway to Proton. The ride lasted one hour, and was ten times faster than if Justin had cycled the same distance. When Justin got out of the car at Electron he noticed his tire was flat, which meant walking the rest of the way to Proton. Walking took him twice as long as cycling. When Justin finally reached Proton, he repaired his bicycle tire and rode the entire distance home to Neutron. How much time did each trip take and which of the two was faster?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe return trip was faster. Since it was one hour to Electron by car, which was ten times faster than cycling, the time from Electron to Proton took an additional 20 hours since he walked, and walking took twice as long as cycling. Therefore, the first half of the trip took a total of 21 hours. The return trip took Justin 20 hours, since he cycled the entire distance and cycling is twice as fast as walking.\n<|im_start|>answer\nThe return trip was faster. Since it was one hour to Electron by car, which was ten times faster than cycling, the time from Electron to Proton took an additional 20 hours since he walked, and walking took twice as long as cycling. Therefore, the first half of the trip took a total of 21 hours. The return trip took Justin 20 hours, since he cycled the entire distance and cycling is twice as fast as walking.\n<|im_end|>" }, { "id": "#13934", "title": "Powers of Four", "fun": 2.52, "difficulty": 1.16, "author": "cool_star", "desc": "Sally and Anna took turns multiplying numbers. Sally picked the number four. Anna multiplied that by 4 to get 16. Sally multiplied that by 4 to get 64. Anna multiplied that by 4 to get 256.\n\r\nAfter going back and forth several times, one of them got the number 1,048,576. Who came up with that number, Sally or Anna?", "hint": "You may be able to find a pattern!", "answer": "Anna came up with that number. Note that all of Anna's numbers end in 6 and all of Sally's numbers end in 4. That's all you need to know!", "category": "Math", "date": "07/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally and Anna took turns multiplying numbers. Sally picked the number four. Anna multiplied that by 4 to get 16. Sally multiplied that by 4 to get 64. Anna multiplied that by 4 to get 256.\n\r\nAfter going back and forth several times, one of them got the number 1,048,576. Who came up with that number, Sally or Anna?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnna came up with that number. Note that all of Anna's numbers end in 6 and all of Sally's numbers end in 4. That's all you need to know!\n<|im_start|>answer\nAnna came up with that number. Note that all of Anna's numbers end in 6 and all of Sally's numbers end in 4. That's all you need to know!\n<|im_end|>" }, { "id": "#50181", "title": "The Dracoria Trainers", "fun": 2.52, "difficulty": 0.58, "author": "klsowell", "desc": "Once, in a faraway land called Dracoria, four girls - Lillie, Harley, Crystal, and Geneva - were becoming dragon trainers. They each got a different-colored dragon and named it something different. Using the clues, can you figure out who had which dragon and what she named it?\n\r\n1. The four people are: the one who owns the Red Dragon, the one who owns Brookzhay, the one who owns the Gold Dragon, and Crystal.\n\r\n2. Lillie thinks Aero and Brookzhay are nice-looking dragons, but prefers her own, the Gold Dragon.\n\r\n3. Harley's dragon is the fastest, but Aero is right behind.\n\r\n4. Even though Skae's name sounds like \"Sky\", she is not the color of the sky, day or night.\n\r\n5. Reikke, the Gold Dragon, wishes she belonged to Crystal because she gives her dragon more treats.\n\r\n6. Harley thinks she's cool because her dragon is the color of the night, but Geneva thinks her dragon, Skae, is much cooler.", "hint": "The day sky is blue and the night sky is black.", "answer": "Lillie has the Gold Dragon and calls it Reikke.\r\nHarley has the Black Dragon and calls it Brookzhay.\r\nCrystal has the Blue Dragon and calls it Aero.\r\nGeneva has the Red Dragon and calls it Skae.", "category": "Logic-Grid", "date": "03/11/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce, in a faraway land called Dracoria, four girls - Lillie, Harley, Crystal, and Geneva - were becoming dragon trainers. They each got a different-colored dragon and named it something different. Using the clues, can you figure out who had which dragon and what she named it?\n\r\n1. The four people are: the one who owns the Red Dragon, the one who owns Brookzhay, the one who owns the Gold Dragon, and Crystal.\n\r\n2. Lillie thinks Aero and Brookzhay are nice-looking dragons, but prefers her own, the Gold Dragon.\n\r\n3. Harley's dragon is the fastest, but Aero is right behind.\n\r\n4. Even though Skae's name sounds like \"Sky\", she is not the color of the sky, day or night.\n\r\n5. Reikke, the Gold Dragon, wishes she belonged to Crystal because she gives her dragon more treats.\n\r\n6. Harley thinks she's cool because her dragon is the color of the night, but Geneva thinks her dragon, Skae, is much cooler.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLillie has the Gold Dragon and calls it Reikke.\r\nHarley has the Black Dragon and calls it Brookzhay.\r\nCrystal has the Blue Dragon and calls it Aero.\r\nGeneva has the Red Dragon and calls it Skae.\n<|im_start|>answer\nLillie has the Gold Dragon and calls it Reikke.\r\nHarley has the Black Dragon and calls it Brookzhay.\r\nCrystal has the Blue Dragon and calls it Aero.\r\nGeneva has the Red Dragon and calls it Skae.\n<|im_end|>" }, { "id": "#47947", "title": "Making Change", "fun": 2.52, "difficulty": 2.22, "author": "MarcM1098", "desc": "Canada and The United States have a quarter, dime, nickel, and penny (25, 10, 5, and 1 cent coins).\n\r\n1. The minimum number of coins needed to make change for a dollar (i.e. to make any amount less than 100) is nine coins. For example, nine coins are required to make 99 cents: 3 quarters, 2 dimes, and 4 pennies. What is the only smaller amount that also requires nine coins?\n\r\n2. Having a 20 cent coin instead of a dime would be more efficient; at most eight coins would be needed to make change for a dollar. See if you can make 89 cents with only eight coins (using 25, 20, 5, and 1 cent coins).\n\r\n3. There are other coin values that are still more efficient, such as 25, 18, 5, and 1 cent coins. What is the fewest number of these coins needed to make 89 cents?", "hint": "1. Take the answer for 99 cents and just replace one coin with a smaller one.\n\r\n2. Don't use as many quarters as possible (don't be \"greedy\").\n\r\n3. You don't need any pennies.", "answer": "1. 94 cents also requires nine coins: 3 quarters, 1 dime, 1 nickel, and 4 pennies.\n\r\n2. 89 cents can be made using 1 quarter, 3 twenty-cent coins, and 4 pennies. If you try to use as many quarters as possible (called a \"greedy\" algorithm), it actually takes more coins: 3 quarters, 2 nickels, and 4 pennies is nine coins. One advantage of the existing coin values is that the \"greedy\" algorithm always works: use as many coins of highest value first, then the next highest, and so on.\n\r\n3. 89 cents can be made using only six coins: 1 quarter, 3 eighteen-cent coins, and 2 nickels. In fact, any amount under 100 can be made with just six coins. There are several other coin values (such as 24, 19, 4, and 1; or 28, 13, 6, and 1) that are just as efficient, but none is better. The problem with these \"efficient\" amounts is trying to figure out the best way to make change in your head.", "category": "Math", "date": "09/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCanada and The United States have a quarter, dime, nickel, and penny (25, 10, 5, and 1 cent coins).\n\r\n1. The minimum number of coins needed to make change for a dollar (i.e. to make any amount less than 100) is nine coins. For example, nine coins are required to make 99 cents: 3 quarters, 2 dimes, and 4 pennies. What is the only smaller amount that also requires nine coins?\n\r\n2. Having a 20 cent coin instead of a dime would be more efficient; at most eight coins would be needed to make change for a dollar. See if you can make 89 cents with only eight coins (using 25, 20, 5, and 1 cent coins).\n\r\n3. There are other coin values that are still more efficient, such as 25, 18, 5, and 1 cent coins. What is the fewest number of these coins needed to make 89 cents?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. 94 cents also requires nine coins: 3 quarters, 1 dime, 1 nickel, and 4 pennies.\n\r\n2. 89 cents can be made using 1 quarter, 3 twenty-cent coins, and 4 pennies. If you try to use as many quarters as possible (called a \"greedy\" algorithm), it actually takes more coins: 3 quarters, 2 nickels, and 4 pennies is nine coins. One advantage of the existing coin values is that the \"greedy\" algorithm always works: use as many coins of highest value first, then the next highest, and so on.\n\r\n3. 89 cents can be made using only six coins: 1 quarter, 3 eighteen-cent coins, and 2 nickels. In fact, any amount under 100 can be made with just six coins. There are several other coin values (such as 24, 19, 4, and 1; or 28, 13, 6, and 1) that are just as efficient, but none is better. The problem with these \"efficient\" amounts is trying to figure out the best way to make change in your head.\n<|im_start|>answer\n1. 94 cents also requires nine coins: 3 quarters, 1 dime, 1 nickel, and 4 pennies.\n\r\n2. 89 cents can be made using 1 quarter, 3 twenty-cent coins, and 4 pennies. If you try to use as many quarters as possible (called a \"greedy\" algorithm), it actually takes more coins: 3 quarters, 2 nickels, and 4 pennies is nine coins. One advantage of the existing coin values is that the \"greedy\" algorithm always works: use as many coins of highest value first, then the next highest, and so on.\n\r\n3. 89 cents can be made using only six coins: 1 quarter, 3 eighteen-cent coins, and 2 nickels. In fact, any amount under 100 can be made with just six coins. There are several other coin values (such as 24, 19, 4, and 1; or 28, 13, 6, and 1) that are just as efficient, but none is better. The problem with these \"efficient\" amounts is trying to figure out the best way to make change in your head.\n<|im_end|>" }, { "id": "#40855", "title": "Spanish Class", "fun": 2.52, "difficulty": 1.36, "author": "chocolatecake", "desc": "Mrs. McGuire, the Spanish teacher at Hillsview High, had her students take a Spanish test. Later that night, she was taking them home to grade them when she noticed that some of the student's tests didn't have names on them. She narrowed her search down to five students: Brooke, Max, Austin, Jake, and Susie. Help Mrs. McGuire figure out whose test is whose and what grade each of them had received.\n\r\nClues: \n\r\n1. Brooke got a 91% on her test.\n\r\n2. The student with the last name Smith did not get an 86%.\n\r\n3. Susie got a lower grade than Jake.\n\r\n4. Max's last name is not Reiner.\n\r\n5. The student who got an 80% is not Austin.\n\r\n6. The student who got a 62% was Max.\n\r\n7. The student who got a 75% has the last name of Smith.\n\r\n8. The student with the last name Tomten did not get an 80% or 62%.\n\r\n9. Susie's last name does not end or start with a 'T'.\n\r\n10. Austin's last name is Johnson.", "hint": "No hint available.", "answer": "Brooke - Tomten - 91%\r\nJake - Reiner - 80%\r\nSusie - Smith - 75%\r\nMax - Ernst - 62%\r\nAustin - Johnson - 86%", "category": "Logic-Grid", "date": "03/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. McGuire, the Spanish teacher at Hillsview High, had her students take a Spanish test. Later that night, she was taking them home to grade them when she noticed that some of the student's tests didn't have names on them. She narrowed her search down to five students: Brooke, Max, Austin, Jake, and Susie. Help Mrs. McGuire figure out whose test is whose and what grade each of them had received.\n\r\nClues: \n\r\n1. Brooke got a 91% on her test.\n\r\n2. The student with the last name Smith did not get an 86%.\n\r\n3. Susie got a lower grade than Jake.\n\r\n4. Max's last name is not Reiner.\n\r\n5. The student who got an 80% is not Austin.\n\r\n6. The student who got a 62% was Max.\n\r\n7. The student who got a 75% has the last name of Smith.\n\r\n8. The student with the last name Tomten did not get an 80% or 62%.\n\r\n9. Susie's last name does not end or start with a 'T'.\n\r\n10. Austin's last name is Johnson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBrooke - Tomten - 91%\r\nJake - Reiner - 80%\r\nSusie - Smith - 75%\r\nMax - Ernst - 62%\r\nAustin - Johnson - 86%\n<|im_start|>answer\nBrooke - Tomten - 91%\r\nJake - Reiner - 80%\r\nSusie - Smith - 75%\r\nMax - Ernst - 62%\r\nAustin - Johnson - 86%\n<|im_end|>" }, { "id": "#7132", "title": "X Likes Cars", "fun": 2.52, "difficulty": 1.76, "author": "mozven", "desc": "X likes to buy and sell cars. For two weeks he bought 5 cars every 12 hours. Then, on June 2nd, he decided to start selling. Every day he would sell 6 cars, then buy 2. But every third day, he would sell 5 cars, and buy 3. X decided that he'll shut down his business when he has no more cars. At this rate, what day will X shut down his business?", "hint": "No hint available.", "answer": "July 12th, 41 days after he started selling.\n\r\n5 cars every 12 hours = 10 cars per day = 140 cars bought in the two weeks. This is the starting point.\n\r\nEvery two out of three days, he nets 4 cars sold (2 bought - 6 sold). The third day, he nets 2 cars sold (3 bought - 5 sold). This means that he nets 4 + 4 + 2 = 10 cars sold every three days.\n\r\nSince he needs to sell 140 cars, it will take him 14 3-day cycles to do this. 14 * 3 = 42 days. But on day 41 he sells his 6 cars and runs out. He would normally buy two more later that day, but he is already out.", "category": "Math", "date": "09/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nX likes to buy and sell cars. For two weeks he bought 5 cars every 12 hours. Then, on June 2nd, he decided to start selling. Every day he would sell 6 cars, then buy 2. But every third day, he would sell 5 cars, and buy 3. X decided that he'll shut down his business when he has no more cars. At this rate, what day will X shut down his business?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJuly 12th, 41 days after he started selling.\n\r\n5 cars every 12 hours = 10 cars per day = 140 cars bought in the two weeks. This is the starting point.\n\r\nEvery two out of three days, he nets 4 cars sold (2 bought - 6 sold). The third day, he nets 2 cars sold (3 bought - 5 sold). This means that he nets 4 + 4 + 2 = 10 cars sold every three days.\n\r\nSince he needs to sell 140 cars, it will take him 14 3-day cycles to do this. 14 * 3 = 42 days. But on day 41 he sells his 6 cars and runs out. He would normally buy two more later that day, but he is already out.\n<|im_start|>answer\nJuly 12th, 41 days after he started selling.\n\r\n5 cars every 12 hours = 10 cars per day = 140 cars bought in the two weeks. This is the starting point.\n\r\nEvery two out of three days, he nets 4 cars sold (2 bought - 6 sold). The third day, he nets 2 cars sold (3 bought - 5 sold). This means that he nets 4 + 4 + 2 = 10 cars sold every three days.\n\r\nSince he needs to sell 140 cars, it will take him 14 3-day cycles to do this. 14 * 3 = 42 days. But on day 41 he sells his 6 cars and runs out. He would normally buy two more later that day, but he is already out.\n<|im_end|>" }, { "id": "#24534", "title": "Game Specialties", "fun": 2.52, "difficulty": 1.29, "author": "dolphingurl12", "desc": "Two girls (Maggie, Lucy) and two boys (Greg, Zack) specialize in different games (rummy, chess, Monopoly, Scrabble). Their last names are McCormick, Dixion, Lowe, and Jones. Find each person's full name and game specialty.\n\r\n1. Dixion, who does not play Monopoly, and Lowe think they are better at their games than the girls are at their own games. \n\r\n2. The rummy player said she'd teach Jones to play Clue. \n\r\n3. Lucy and McCormick had dinner with the Monopoly player. \n\r\n4. Greg and the chess player have the same locker in their gym class at school.", "hint": "No hint available.", "answer": "Maggie McCormick- Rummy\r\nLucy Jones- Scrabble\r\nGreg Lowe- Monopoly\r\nZack Dixion- Chess", "category": "Logic-Grid", "date": "07/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo girls (Maggie, Lucy) and two boys (Greg, Zack) specialize in different games (rummy, chess, Monopoly, Scrabble). Their last names are McCormick, Dixion, Lowe, and Jones. Find each person's full name and game specialty.\n\r\n1. Dixion, who does not play Monopoly, and Lowe think they are better at their games than the girls are at their own games. \n\r\n2. The rummy player said she'd teach Jones to play Clue. \n\r\n3. Lucy and McCormick had dinner with the Monopoly player. \n\r\n4. Greg and the chess player have the same locker in their gym class at school.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMaggie McCormick- Rummy\r\nLucy Jones- Scrabble\r\nGreg Lowe- Monopoly\r\nZack Dixion- Chess\n<|im_start|>answer\nMaggie McCormick- Rummy\r\nLucy Jones- Scrabble\r\nGreg Lowe- Monopoly\r\nZack Dixion- Chess\n<|im_end|>" }, { "id": "#4318", "title": "Symbols", "fun": 2.52, "difficulty": 2.69, "author": "cathalmccabe", "desc": "Each letter ABCDEFGH represents the numbers 1 to 8 inclusive:\n\r\nFA*A=CF\r\nDG*A=BA \r\nH*E=DH \r\nF*A = C \n\r\nCan you match the letter to the number?", "hint": "G = 1", "answer": "1 = G\r\n2 = A\r\n3 = D\r\n4 = F\r\n5 = H\r\n6 = B\r\n7 = E\r\n8 = C\n\r\n42*2=84\r\n31*2=62 \r\n5*7=35 \r\n4*2 = 8 \n\r\nSolution: (From 2: means 2nd line etc:)\r\nFrom 2: G=1 because A*G = A (A is not 5, because then from 1, F should also be 5)\n\r\nFrom 4: F*A has to be a single number so it can only be 2*3 or 2*4 (or vice versa) and C can only be 6 or 8\r\nThere are four possibilities here, \r\n4*2 = 8 \r\n2*4 = 8 \r\n3*2 = 6 or \r\n3*2 = 6\n\r\nThey would give from 1: \r\n42*2 (=84) \r\n24*4 (=92) \r\n32*2 (=64) or \r\n23*3 (=69) \r\nCan't be 2*4 or 3*2 (because 92 and 69 are not possible), so \r\nA=2\r\nFrom 2: B is twice something, so it can only be 4 6 or 8 (not 2 because it's already known)\r\nD is half 4 6 or 8, so it can only be 2, 3, or 4\n\r\nFrom 3: All the possible combinations of numbers multiplied that would give a two digit number: (Eliminate any with 1 or 2 in the product eg 3*7=21 or 3*8=24 etc)\n\n\r\n4*8 =32\r\n5*6 =30\r\n5*7 =35\r\n5*8 =40\r\n6*7 =42\r\n6*8 =48\n\r\nThe second term of the product must be one of the numbers multiplied by each other, so eliminate any that don't fit in here leaving:\n\r\n5*7 =35\r\n6*8 =48\n\r\nSo, filling in what's known so far:\n\r\nF2*2=CF\r\nD1*2=B2 \r\nH*E=DH \r\nF*2 = C \n\r\nFrom 1: F=4, then C = 8\r\nFrom 2: B = 6\r\nFrom 3: H*E = 5*7 or 5*7 = 35 D=3 H= 5, so E = 7", "category": "Math", "date": "05/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach letter ABCDEFGH represents the numbers 1 to 8 inclusive:\n\r\nFA*A=CF\r\nDG*A=BA \r\nH*E=DH \r\nF*A = C \n\r\nCan you match the letter to the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 = G\r\n2 = A\r\n3 = D\r\n4 = F\r\n5 = H\r\n6 = B\r\n7 = E\r\n8 = C\n\r\n42*2=84\r\n31*2=62 \r\n5*7=35 \r\n4*2 = 8 \n\r\nSolution: (From 2: means 2nd line etc:)\r\nFrom 2: G=1 because A*G = A (A is not 5, because then from 1, F should also be 5)\n\r\nFrom 4: F*A has to be a single number so it can only be 2*3 or 2*4 (or vice versa) and C can only be 6 or 8\r\nThere are four possibilities here, \r\n4*2 = 8 \r\n2*4 = 8 \r\n3*2 = 6 or \r\n3*2 = 6\n\r\nThey would give from 1: \r\n42*2 (=84) \r\n24*4 (=92) \r\n32*2 (=64) or \r\n23*3 (=69) \r\nCan't be 2*4 or 3*2 (because 92 and 69 are not possible), so \r\nA=2\r\nFrom 2: B is twice something, so it can only be 4 6 or 8 (not 2 because it's already known)\r\nD is half 4 6 or 8, so it can only be 2, 3, or 4\n\r\nFrom 3: All the possible combinations of numbers multiplied that would give a two digit number: (Eliminate any with 1 or 2 in the product eg 3*7=21 or 3*8=24 etc)\n\n\r\n4*8 =32\r\n5*6 =30\r\n5*7 =35\r\n5*8 =40\r\n6*7 =42\r\n6*8 =48\n\r\nThe second term of the product must be one of the numbers multiplied by each other, so eliminate any that don't fit in here leaving:\n\r\n5*7 =35\r\n6*8 =48\n\r\nSo, filling in what's known so far:\n\r\nF2*2=CF\r\nD1*2=B2 \r\nH*E=DH \r\nF*2 = C \n\r\nFrom 1: F=4, then C = 8\r\nFrom 2: B = 6\r\nFrom 3: H*E = 5*7 or 5*7 = 35 D=3 H= 5, so E = 7\n<|im_start|>answer\n1 = G\r\n2 = A\r\n3 = D\r\n4 = F\r\n5 = H\r\n6 = B\r\n7 = E\r\n8 = C\n\r\n42*2=84\r\n31*2=62 \r\n5*7=35 \r\n4*2 = 8 \n\r\nSolution: (From 2: means 2nd line etc:)\r\nFrom 2: G=1 because A*G = A (A is not 5, because then from 1, F should also be 5)\n\r\nFrom 4: F*A has to be a single number so it can only be 2*3 or 2*4 (or vice versa) and C can only be 6 or 8\r\nThere are four possibilities here, \r\n4*2 = 8 \r\n2*4 = 8 \r\n3*2 = 6 or \r\n3*2 = 6\n\r\nThey would give from 1: \r\n42*2 (=84) \r\n24*4 (=92) \r\n32*2 (=64) or \r\n23*3 (=69) \r\nCan't be 2*4 or 3*2 (because 92 and 69 are not possible), so \r\nA=2\r\nFrom 2: B is twice something, so it can only be 4 6 or 8 (not 2 because it's already known)\r\nD is half 4 6 or 8, so it can only be 2, 3, or 4\n\r\nFrom 3: All the possible combinations of numbers multiplied that would give a two digit number: (Eliminate any with 1 or 2 in the product eg 3*7=21 or 3*8=24 etc)\n\n\r\n4*8 =32\r\n5*6 =30\r\n5*7 =35\r\n5*8 =40\r\n6*7 =42\r\n6*8 =48\n\r\nThe second term of the product must be one of the numbers multiplied by each other, so eliminate any that don't fit in here leaving:\n\r\n5*7 =35\r\n6*8 =48\n\r\nSo, filling in what's known so far:\n\r\nF2*2=CF\r\nD1*2=B2 \r\nH*E=DH \r\nF*2 = C \n\r\nFrom 1: F=4, then C = 8\r\nFrom 2: B = 6\r\nFrom 3: H*E = 5*7 or 5*7 = 35 D=3 H= 5, so E = 7\n<|im_end|>" }, { "id": "#7414", "title": "703 Sweets", "fun": 2.52, "difficulty": 1.74, "author": "warrior", "desc": "A local school teacher wanted to share 703 sweets equally among the pupils, if there were more than 20 pupils, how many sweets did each receive?", "hint": "Try to figure out how many pupils in the class first.", "answer": "19 sweets for the 37 pupils. \r\nBesides 1 and 703, 19 and 37 are the only factors of 703.", "category": "Math", "date": "09/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA local school teacher wanted to share 703 sweets equally among the pupils, if there were more than 20 pupils, how many sweets did each receive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19 sweets for the 37 pupils. \r\nBesides 1 and 703, 19 and 37 are the only factors of 703.\n<|im_start|>answer\n19 sweets for the 37 pupils. \r\nBesides 1 and 703, 19 and 37 are the only factors of 703.\n<|im_end|>" }, { "id": "#28253", "title": "Collection of Leaves", "fun": 2.52, "difficulty": 1.5, "author": "shenqiang", "desc": "As Mr. Smith's birthday approaches, he starts to collect leaves. On the first day of the month he collects one leaf, on the second day he collects two, and so on. So by his birthday he'll have collected 276 leaves altogether. On which day of the month is Mr. Smith's birthday?", "hint": "No hint available.", "answer": "On the 23rd.", "category": "Math", "date": "01/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAs Mr. Smith's birthday approaches, he starts to collect leaves. On the first day of the month he collects one leaf, on the second day he collects two, and so on. So by his birthday he'll have collected 276 leaves altogether. On which day of the month is Mr. Smith's birthday?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn the 23rd.\n<|im_start|>answer\nOn the 23rd.\n<|im_end|>" }, { "id": "#20275", "title": "3 Different Things", "fun": 2.52, "difficulty": 1.21, "author": "knbrain", "desc": "3 painters from 3 different companies were painting a billboard. The men had 3 different last names: Red, Blue and Green. The 3 companies they came from had the same names as the workers. As they were painting, they started talking. \"It is funny that all of our last names are different from our companies' names.\" said Mr. Red. \"Yes, very strange.\" replied the man from Blue & Co.\n\r\nWho worked for which company?", "hint": "Read the teaser carefully.", "answer": "Mr. Red worked for Green & Co.\r\nMr. Green worked for Blue & Co.\r\nMr. Blue worked for Red & Co.\n\r\nAlthough at first it seems impossible, we know Mr. Red couldn't work for the red company. He also couldn't work for Blue & Co. because he was talking to the man from Blue & Co. Since we now know that Mr. Red is from Green & Co. it is easy.", "category": "Logic", "date": "01/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n3 painters from 3 different companies were painting a billboard. The men had 3 different last names: Red, Blue and Green. The 3 companies they came from had the same names as the workers. As they were painting, they started talking. \"It is funny that all of our last names are different from our companies' names.\" said Mr. Red. \"Yes, very strange.\" replied the man from Blue & Co.\n\r\nWho worked for which company?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Red worked for Green & Co.\r\nMr. Green worked for Blue & Co.\r\nMr. Blue worked for Red & Co.\n\r\nAlthough at first it seems impossible, we know Mr. Red couldn't work for the red company. He also couldn't work for Blue & Co. because he was talking to the man from Blue & Co. Since we now know that Mr. Red is from Green & Co. it is easy.\n<|im_start|>answer\nMr. Red worked for Green & Co.\r\nMr. Green worked for Blue & Co.\r\nMr. Blue worked for Red & Co.\n\r\nAlthough at first it seems impossible, we know Mr. Red couldn't work for the red company. He also couldn't work for Blue & Co. because he was talking to the man from Blue & Co. Since we now know that Mr. Red is from Green & Co. it is easy.\n<|im_end|>" }, { "id": "#42471", "title": "Town Soccer Logic Grid", "fun": 2.52, "difficulty": 1.18, "author": "beatlesman12", "desc": "Ralph, Chris, Sam, Russel, and Hugo all play town soccer. They play for Hamilton, Revere, Beverly, Salem, and Marblehead. The teams wear orange, white, red, blue, and green. They all came in different places in the league. They came in 1st, 2nd, 3rd, 4th, and 5th. Determine who played for what team, what colors they wore, and what places they came in.\n\r\n1. Hugo and Russel play for teams whose names have the same number of syllables as their names.\r\n2. The five people are the person who plays on the 1st place orange team, Hugo, Chris (who is from Marblehead), Russel, and the person who plays for Hamilton.\r\n3. Hamilton wears blue.\r\n4. Ralph plays for Beverly.\r\n5. Hugo plays for Revere, and they came in 4th place.\r\n6. Salem did not come in any place below 3rd place.\r\n7. Marblehead wears red, and they came in 3rd place.\r\n8. Russel wears white.", "hint": "No hint available.", "answer": "Ralph, Beverly, Orange, 1st\r\nChris, Marblehead, Red, 3rd\r\nSam, Hamilton, Blue, 5th\r\nRussel, Salem, White, 2nd\r\nHugo, Revere, Green, 4th", "category": "Logic-Grid", "date": "07/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRalph, Chris, Sam, Russel, and Hugo all play town soccer. They play for Hamilton, Revere, Beverly, Salem, and Marblehead. The teams wear orange, white, red, blue, and green. They all came in different places in the league. They came in 1st, 2nd, 3rd, 4th, and 5th. Determine who played for what team, what colors they wore, and what places they came in.\n\r\n1. Hugo and Russel play for teams whose names have the same number of syllables as their names.\r\n2. The five people are the person who plays on the 1st place orange team, Hugo, Chris (who is from Marblehead), Russel, and the person who plays for Hamilton.\r\n3. Hamilton wears blue.\r\n4. Ralph plays for Beverly.\r\n5. Hugo plays for Revere, and they came in 4th place.\r\n6. Salem did not come in any place below 3rd place.\r\n7. Marblehead wears red, and they came in 3rd place.\r\n8. Russel wears white.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRalph, Beverly, Orange, 1st\r\nChris, Marblehead, Red, 3rd\r\nSam, Hamilton, Blue, 5th\r\nRussel, Salem, White, 2nd\r\nHugo, Revere, Green, 4th\n<|im_start|>answer\nRalph, Beverly, Orange, 1st\r\nChris, Marblehead, Red, 3rd\r\nSam, Hamilton, Blue, 5th\r\nRussel, Salem, White, 2nd\r\nHugo, Revere, Green, 4th\n<|im_end|>" }, { "id": "#27112", "title": "2001", "fun": 2.52, "difficulty": 2.97, "author": "lips", "desc": "Use addition, subtraction, multiplication, division, and parentheses to make the following equation hold.\n\r\n9 8 7 6 5 4 3 2 1=2001\n\r\nYou can't use two or more of the digits to make multiple-digit numbers (i.e. solutions like (987+6-5+4*3)*2+1=2001 are not allowed.)", "hint": "No hint available.", "answer": "9*8*(7+6*5)/4*3+2+1=2001.", "category": "Math", "date": "11/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUse addition, subtraction, multiplication, division, and parentheses to make the following equation hold.\n\r\n9 8 7 6 5 4 3 2 1=2001\n\r\nYou can't use two or more of the digits to make multiple-digit numbers (i.e. solutions like (987+6-5+4*3)*2+1=2001 are not allowed.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9*8*(7+6*5)/4*3+2+1=2001.\n<|im_start|>answer\n9*8*(7+6*5)/4*3+2+1=2001.\n<|im_end|>" }, { "id": "#2615", "title": "Run vs Walk", "fun": 2.52, "difficulty": 1.07, "author": "204_BLaZe_41", "desc": "Since a person uses about the same amount of energy walking for ten kilometers as running for ten kilometers, would a person use more energy running for ten minutes, walking for ten minutes, or is the same amount of energy spent? Why?", "hint": "No hint available.", "answer": "In the first situation, the measurement was distance so the runner would finish much earlier than the person walking; therefore, the amount of energy spent would be approximately the same. In the second situation, the measurement is time, and a person who runs for ten minutes will cover a much greater distance and therefore burn more energy than a person walking for ten minutes.", "category": "Logic", "date": "03/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSince a person uses about the same amount of energy walking for ten kilometers as running for ten kilometers, would a person use more energy running for ten minutes, walking for ten minutes, or is the same amount of energy spent? Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn the first situation, the measurement was distance so the runner would finish much earlier than the person walking; therefore, the amount of energy spent would be approximately the same. In the second situation, the measurement is time, and a person who runs for ten minutes will cover a much greater distance and therefore burn more energy than a person walking for ten minutes.\n<|im_start|>answer\nIn the first situation, the measurement was distance so the runner would finish much earlier than the person walking; therefore, the amount of energy spent would be approximately the same. In the second situation, the measurement is time, and a person who runs for ten minutes will cover a much greater distance and therefore burn more energy than a person walking for ten minutes.\n<|im_end|>" }, { "id": "#35916", "title": "What a Marriage!", "fun": 2.5100000000000002, "difficulty": 1.41, "author": "reptile5000", "desc": "Chris and Jill were married. On their marriage day, Chris was three times as old as Jill. 21 years later, Chris was only 2 times as old as Jill. What was their age when they were married?", "hint": "c= Chris' age at marriage\r\nj= Jill's age at marriage\n\r\nc = 3j at marriage\r\nc + 21 = 2j + 42\r\n...you take it from here", "answer": "Chris was 63.\r\nJill was 21.\n\r\nc = 3j at marriage\r\nc + 21 = 2j + 42\r\nc = 2j + 21\r\n(3j) = 2j + 21\r\nj = 21", "category": "Math", "date": "03/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChris and Jill were married. On their marriage day, Chris was three times as old as Jill. 21 years later, Chris was only 2 times as old as Jill. What was their age when they were married?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChris was 63.\r\nJill was 21.\n\r\nc = 3j at marriage\r\nc + 21 = 2j + 42\r\nc = 2j + 21\r\n(3j) = 2j + 21\r\nj = 21\n<|im_start|>answer\nChris was 63.\r\nJill was 21.\n\r\nc = 3j at marriage\r\nc + 21 = 2j + 42\r\nc = 2j + 21\r\n(3j) = 2j + 21\r\nj = 21\n<|im_end|>" }, { "id": "#28666", "title": "The Locket", "fun": 2.5100000000000002, "difficulty": 1.06, "author": "jodocroco", "desc": "It was Jodie's birthday, and she received a gorgeous golden locket from her mum. She couldn't wait to show all her friends, but she couldn't decide whose picture to put in it. She knew that if she put one friend's picture in it, the others would be upset. So she made a way that whichever of her friends looked at it would see a picture of themselves, so no one would get upset. How did she do it when the locket could only hold one picture?", "hint": "No hint available.", "answer": "Instead of putting a picture in it, she put a mirror in, so whichever of her friends looked at it, they would see their reflection.", "category": "Logic", "date": "02/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was Jodie's birthday, and she received a gorgeous golden locket from her mum. She couldn't wait to show all her friends, but she couldn't decide whose picture to put in it. She knew that if she put one friend's picture in it, the others would be upset. So she made a way that whichever of her friends looked at it would see a picture of themselves, so no one would get upset. How did she do it when the locket could only hold one picture?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nInstead of putting a picture in it, she put a mirror in, so whichever of her friends looked at it, they would see their reflection.\n<|im_start|>answer\nInstead of putting a picture in it, she put a mirror in, so whichever of her friends looked at it, they would see their reflection.\n<|im_end|>" }, { "id": "#5199", "title": "Vacation Activities", "fun": 2.5100000000000002, "difficulty": 1.83, "author": "Cascas", "desc": "It was vacation time, and so I decided to visit my cousin's home. What a grand time we had! In the mornings, we both would go for a jog. The evenings were spent on the tennis court. Tiring as these activities were, we could manage only one per day, i.e., either we went for a jog or played tennis each day. There were days when we felt lazy and stayed home all day long. \n\r\nNow, there were 14 mornings when we did nothing, 15 evenings when we stayed at home, and a total of 9 days when we jogged or played tennis. For how many days did I stay at my cousin's place?", "hint": "No hint available.", "answer": "19", "category": "Math", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was vacation time, and so I decided to visit my cousin's home. What a grand time we had! In the mornings, we both would go for a jog. The evenings were spent on the tennis court. Tiring as these activities were, we could manage only one per day, i.e., either we went for a jog or played tennis each day. There were days when we felt lazy and stayed home all day long. \n\r\nNow, there were 14 mornings when we did nothing, 15 evenings when we stayed at home, and a total of 9 days when we jogged or played tennis. For how many days did I stay at my cousin's place?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19\n<|im_start|>answer\n19\n<|im_end|>" }, { "id": "#45273", "title": "The Booker Poet", "fun": 2.5100000000000002, "difficulty": 1.74, "author": "nidhikaila", "desc": "Beird Waker, the celebrated poet, finally won a Booker for his thirteenth anthology of poems. In the post event party, you are in the circle surrounding the poet when Miss Gee, another guest, asks him innocently, \"Do you actually remember the order in which your books were published?\" This one liner sends the poet into a monologue:\n\r\n\"Aah, let's see.. I got the Booker for \"Figments\", which, as you know, is my thirteenth book.. but the first was a book called \"Candy Floss\", which, if I may say so, appears rather puerile when I read it now.. \"Bubbles\" was right after \"Silence\", but way before \"Kingdom\" . \"Horsecarts\" was after \"Durian\" but before \"Kingdom\" again. \"Echo\" and \"Reverberations\" were next to each other. \"Mindreading\" came just after \"Reverberations\" and just before \"Glenfiddich\", but even Glenfiddich was before \"Kingdom\" for sure.\n\r\n\"Oppression\" was my bestseller, but sadly it wasn't the first book. I wish it was, it came a close second, but by then the market already had a perception about me.\n\r\n\"Elephant Song\" and \"Echo\" had 2 books between them. \"Silence\" and \"Elephant Song\" had as many books between them as did \"Bubbles\" and \"Durian\". But, \"Bubbles\" was definitely published before \"Elephant Song\".\"\n\r\nCan you help the much bewildered Miss Gee with the correct order of the books?", "hint": "No hint available.", "answer": "1\tCandy Floss\r\n2\tOppression\r\n3\tSilence \r\n4\tBubbles\r\n5\tElephant Song\r\n6\tDurian \r\n7\tHorsecarts\r\n8\tEcho\r\n9\tReverberations\r\n10\tMindreading\r\n11\tGlenfiddich\r\n12\tKingdom\r\n13\tFigments", "category": "Logic", "date": "09/11/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBeird Waker, the celebrated poet, finally won a Booker for his thirteenth anthology of poems. In the post event party, you are in the circle surrounding the poet when Miss Gee, another guest, asks him innocently, \"Do you actually remember the order in which your books were published?\" This one liner sends the poet into a monologue:\n\r\n\"Aah, let's see.. I got the Booker for \"Figments\", which, as you know, is my thirteenth book.. but the first was a book called \"Candy Floss\", which, if I may say so, appears rather puerile when I read it now.. \"Bubbles\" was right after \"Silence\", but way before \"Kingdom\" . \"Horsecarts\" was after \"Durian\" but before \"Kingdom\" again. \"Echo\" and \"Reverberations\" were next to each other. \"Mindreading\" came just after \"Reverberations\" and just before \"Glenfiddich\", but even Glenfiddich was before \"Kingdom\" for sure.\n\r\n\"Oppression\" was my bestseller, but sadly it wasn't the first book. I wish it was, it came a close second, but by then the market already had a perception about me.\n\r\n\"Elephant Song\" and \"Echo\" had 2 books between them. \"Silence\" and \"Elephant Song\" had as many books between them as did \"Bubbles\" and \"Durian\". But, \"Bubbles\" was definitely published before \"Elephant Song\".\"\n\r\nCan you help the much bewildered Miss Gee with the correct order of the books?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1\tCandy Floss\r\n2\tOppression\r\n3\tSilence \r\n4\tBubbles\r\n5\tElephant Song\r\n6\tDurian \r\n7\tHorsecarts\r\n8\tEcho\r\n9\tReverberations\r\n10\tMindreading\r\n11\tGlenfiddich\r\n12\tKingdom\r\n13\tFigments\n<|im_start|>answer\n1\tCandy Floss\r\n2\tOppression\r\n3\tSilence \r\n4\tBubbles\r\n5\tElephant Song\r\n6\tDurian \r\n7\tHorsecarts\r\n8\tEcho\r\n9\tReverberations\r\n10\tMindreading\r\n11\tGlenfiddich\r\n12\tKingdom\r\n13\tFigments\n<|im_end|>" }, { "id": "#27580", "title": "Basketball Standings", "fun": 2.5100000000000002, "difficulty": 1.52, "author": "ttviper", "desc": "The Flames, the Soul, the Engines, the Vipers, and the Tigers are basketball teams in a basketball league. The Vipers are in first place leading the Tigers by three games. The Engines are ahead of the Flames. The Flames are behind the Soul by one game. The Soul are behind the Tigers by seven games while still behind the Engines by three. What are the standings? (Including games behind)", "hint": "Make a chart", "answer": "Leaders in order: Games Back\r\n1. Vipers -\r\n2. Tigers 3\r\n3. Engines 7\r\n4. Soul 10\r\n5. Flames 11", "category": "Logic", "date": "12/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Flames, the Soul, the Engines, the Vipers, and the Tigers are basketball teams in a basketball league. The Vipers are in first place leading the Tigers by three games. The Engines are ahead of the Flames. The Flames are behind the Soul by one game. The Soul are behind the Tigers by seven games while still behind the Engines by three. What are the standings? (Including games behind)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeaders in order: Games Back\r\n1. Vipers -\r\n2. Tigers 3\r\n3. Engines 7\r\n4. Soul 10\r\n5. Flames 11\n<|im_start|>answer\nLeaders in order: Games Back\r\n1. Vipers -\r\n2. Tigers 3\r\n3. Engines 7\r\n4. Soul 10\r\n5. Flames 11\n<|im_end|>" }, { "id": "#29034", "title": "Forumgle", "fun": 2.5100000000000002, "difficulty": 1.29, "author": "EnderofGames", "desc": "Four people, each with a different nickname, job, and nationality, met on a forum site called Forumgle. With the clues below, you are to figure out who's who.\n\r\nNicknames: Sorcerer, Champion, Dorothy, Demosthenes.\r\nJobs: Nurse, Mechanic, Writer, Mathematician.\r\nNationalities: Australia, Canada, U.S., Cayman Islands.\n\r\n1) The four people are the writer, Champion, the Canadian, and the Cayman Islander.\n\r\n2) Sorcerer is the mathematician.\n\r\n3) Dorothy is from the Cayman Islands.\n\r\n4) The writer and the Australian were friends before the other two had accounts, but the mechanic and the Australian never became buddies.", "hint": "Math = Mathematician", "answer": "Champion, nurse, Australia.\r\nDemosthenes, writer, U.S.\r\nDorothy, mechanic, Cayman Islands.\r\nSorcerer, mathematician, Canada.", "category": "Logic-Grid", "date": "03/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people, each with a different nickname, job, and nationality, met on a forum site called Forumgle. With the clues below, you are to figure out who's who.\n\r\nNicknames: Sorcerer, Champion, Dorothy, Demosthenes.\r\nJobs: Nurse, Mechanic, Writer, Mathematician.\r\nNationalities: Australia, Canada, U.S., Cayman Islands.\n\r\n1) The four people are the writer, Champion, the Canadian, and the Cayman Islander.\n\r\n2) Sorcerer is the mathematician.\n\r\n3) Dorothy is from the Cayman Islands.\n\r\n4) The writer and the Australian were friends before the other two had accounts, but the mechanic and the Australian never became buddies.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChampion, nurse, Australia.\r\nDemosthenes, writer, U.S.\r\nDorothy, mechanic, Cayman Islands.\r\nSorcerer, mathematician, Canada.\n<|im_start|>answer\nChampion, nurse, Australia.\r\nDemosthenes, writer, U.S.\r\nDorothy, mechanic, Cayman Islands.\r\nSorcerer, mathematician, Canada.\n<|im_end|>" }, { "id": "#1517", "title": "River Crossing", "fun": 2.5100000000000002, "difficulty": 1.78, "author": "mcse", "desc": "A family of six is crossing a river with a 2-passenger boat. The family includes the following members: Dad, Mom, Maid, Boy, Girl & Dog. Only the 3 adults can row the boat and the dog counts as a passenger. \n\r\nThe dog will bite if the maid is not present. \r\nMom will fight with the boy if Dad is not present. \r\nDad will fight with the girl if Mom is not present. \n\r\nHow can they all get across safely?", "hint": "No hint available.", "answer": "Dad & Boy go and Dad comes back.\r\nDad & Mom go and Mom comes back.\r\nMaid & Dog go and Dad comes back.\r\nDad & Mom go and Mom comes back.\r\nMom & Girl go and everyone is over.", "category": "Logic", "date": "11/25/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA family of six is crossing a river with a 2-passenger boat. The family includes the following members: Dad, Mom, Maid, Boy, Girl & Dog. Only the 3 adults can row the boat and the dog counts as a passenger. \n\r\nThe dog will bite if the maid is not present. \r\nMom will fight with the boy if Dad is not present. \r\nDad will fight with the girl if Mom is not present. \n\r\nHow can they all get across safely?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDad & Boy go and Dad comes back.\r\nDad & Mom go and Mom comes back.\r\nMaid & Dog go and Dad comes back.\r\nDad & Mom go and Mom comes back.\r\nMom & Girl go and everyone is over.\n<|im_start|>answer\nDad & Boy go and Dad comes back.\r\nDad & Mom go and Mom comes back.\r\nMaid & Dog go and Dad comes back.\r\nDad & Mom go and Mom comes back.\r\nMom & Girl go and everyone is over.\n<|im_end|>" }, { "id": "#11668", "title": "Summer Saturday", "fun": 2.5100000000000002, "difficulty": 1.62, "author": "PeaceJo", "desc": "Sarah, Daniel, Megan and Shawn each did something different on Saturday morning and then met for lunch at McDonald's. One of them took Toby for a walk, one of them looked after Baby James, one of them visited Auntie PeaceJo and one of them took flowers to Grandma. At lunch one had a Big Mac, one had a Filet-o-fish, one had a McChicken and one had only french fries.\n\r\nWhat did each friend do and what did they have for lunch? Use the following clues to sort it out.\n\r\n1. Sarah used scissors to cut tulips.\r\n2. The friend that took Toby for a walk is the only one who likes fish.\r\n3. Shawn is allergic to Toby and to wheat.\r\n4. Daniel spend the day with his mom's sister and he doesn't eat red meat.", "hint": "No hint available.", "answer": "Sarah - Took flowers to Grandma & ate the Big Mac\r\nDaniel - Visited Auntie PeaceJo and ate the McChicken\r\nMegan - Took Toby for a walk and ate Filet-o-Fish\r\nShawn - Looked after Baby James and ate French fries (all the others have wheat in the buns)", "category": "Logic", "date": "04/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSarah, Daniel, Megan and Shawn each did something different on Saturday morning and then met for lunch at McDonald's. One of them took Toby for a walk, one of them looked after Baby James, one of them visited Auntie PeaceJo and one of them took flowers to Grandma. At lunch one had a Big Mac, one had a Filet-o-fish, one had a McChicken and one had only french fries.\n\r\nWhat did each friend do and what did they have for lunch? Use the following clues to sort it out.\n\r\n1. Sarah used scissors to cut tulips.\r\n2. The friend that took Toby for a walk is the only one who likes fish.\r\n3. Shawn is allergic to Toby and to wheat.\r\n4. Daniel spend the day with his mom's sister and he doesn't eat red meat.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah - Took flowers to Grandma & ate the Big Mac\r\nDaniel - Visited Auntie PeaceJo and ate the McChicken\r\nMegan - Took Toby for a walk and ate Filet-o-Fish\r\nShawn - Looked after Baby James and ate French fries (all the others have wheat in the buns)\n<|im_start|>answer\nSarah - Took flowers to Grandma & ate the Big Mac\r\nDaniel - Visited Auntie PeaceJo and ate the McChicken\r\nMegan - Took Toby for a walk and ate Filet-o-Fish\r\nShawn - Looked after Baby James and ate French fries (all the others have wheat in the buns)\n<|im_end|>" }, { "id": "#23260", "title": "The Funeral", "fun": 2.5100000000000002, "difficulty": 1.72, "author": "Question_Mark", "desc": "A sad event has just taken place. Four people have died. They each had a funeral. Their names were Scott, Hill, Miles and Paul. They were each related to someone. They were called Raven, Simon, Michael and Richard. The ways they were related are father & son, brothers, cousins and uncle & nephew. Their funerals each took place on different days. They were Monday, Wednesday, Friday and Sunday. You must say whose funeral took place on what day, who they were related to and in what way. Unfortunately, you cannot remember very much, but you do remember the following things:\n\r\n1) Nobody went to someone's funeral whose first name began with the same letter as their own name.\n\r\n2) Hill's funeral was not on Monday or Friday.\n\r\n3) Richard's cousin's funeral did not take place on Friday or Sunday.\n\r\n4) Simon doesn't have any brothers.\n\r\n5) Raven went to his father's funeral on Sunday.\n\r\n6) Scott's funeral was 2 days before Hill's.\n\r\n7) Michael and Scott are brothers.\n\r\n8) One person's funeral was on a day which begins with the same letter as their own name.\n\r\n9) Miles doesn't have children.\n\r\n10) The uncle's funeral was 2 days before the brother's funeral.\n\r\nGood luck.", "hint": "Use the logic-grid solver.", "answer": "Scott's funeral took place on Friday. He was related to Michael and they were brothers.\n\r\nHill's funeral took place on Sunday. He was related to Raven and they were father & son.\n\r\nMiles's funeral took place on Monday. He was related to Richard and they were cousins.\n\r\nPaul's funeral took place on Wednesday. He was related to Simon and they were uncle & nephew.", "category": "Logic-Grid", "date": "05/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA sad event has just taken place. Four people have died. They each had a funeral. Their names were Scott, Hill, Miles and Paul. They were each related to someone. They were called Raven, Simon, Michael and Richard. The ways they were related are father & son, brothers, cousins and uncle & nephew. Their funerals each took place on different days. They were Monday, Wednesday, Friday and Sunday. You must say whose funeral took place on what day, who they were related to and in what way. Unfortunately, you cannot remember very much, but you do remember the following things:\n\r\n1) Nobody went to someone's funeral whose first name began with the same letter as their own name.\n\r\n2) Hill's funeral was not on Monday or Friday.\n\r\n3) Richard's cousin's funeral did not take place on Friday or Sunday.\n\r\n4) Simon doesn't have any brothers.\n\r\n5) Raven went to his father's funeral on Sunday.\n\r\n6) Scott's funeral was 2 days before Hill's.\n\r\n7) Michael and Scott are brothers.\n\r\n8) One person's funeral was on a day which begins with the same letter as their own name.\n\r\n9) Miles doesn't have children.\n\r\n10) The uncle's funeral was 2 days before the brother's funeral.\n\r\nGood luck.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nScott's funeral took place on Friday. He was related to Michael and they were brothers.\n\r\nHill's funeral took place on Sunday. He was related to Raven and they were father & son.\n\r\nMiles's funeral took place on Monday. He was related to Richard and they were cousins.\n\r\nPaul's funeral took place on Wednesday. He was related to Simon and they were uncle & nephew.\n<|im_start|>answer\nScott's funeral took place on Friday. He was related to Michael and they were brothers.\n\r\nHill's funeral took place on Sunday. He was related to Raven and they were father & son.\n\r\nMiles's funeral took place on Monday. He was related to Richard and they were cousins.\n\r\nPaul's funeral took place on Wednesday. He was related to Simon and they were uncle & nephew.\n<|im_end|>" }, { "id": "#30044", "title": "More Values", "fun": 2.5100000000000002, "difficulty": 2.37, "author": "peppamintp", "desc": "Each of the letters A - H has one of the eight values listed. No two letters have the same value. The simple arithmetic problems are clues for determining the value of each letter.\n\r\n2 6 10 12 16 18 20 26\n\r\n1. H + A = F\r\n2. D - F = G\r\n3. C + H = B\r\n4. E - D = H\r\n5. B + C = E\r\n6. G + C = A", "hint": "No hint available.", "answer": "A=12\r\nB=16\r\nC=10\r\nD=20\r\nE=26\r\nF=18\r\nG=2\r\nH=6\n\r\n1) 18, 2) 2, 3) 16 4) 6 5) 26 6) 12", "category": "Math", "date": "04/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach of the letters A - H has one of the eight values listed. No two letters have the same value. The simple arithmetic problems are clues for determining the value of each letter.\n\r\n2 6 10 12 16 18 20 26\n\r\n1. H + A = F\r\n2. D - F = G\r\n3. C + H = B\r\n4. E - D = H\r\n5. B + C = E\r\n6. G + C = A\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA=12\r\nB=16\r\nC=10\r\nD=20\r\nE=26\r\nF=18\r\nG=2\r\nH=6\n\r\n1) 18, 2) 2, 3) 16 4) 6 5) 26 6) 12\n<|im_start|>answer\nA=12\r\nB=16\r\nC=10\r\nD=20\r\nE=26\r\nF=18\r\nG=2\r\nH=6\n\r\n1) 18, 2) 2, 3) 16 4) 6 5) 26 6) 12\n<|im_end|>" }, { "id": "#1993", "title": "Reindeer", "fun": 2.5100000000000002, "difficulty": 2.16, "author": "Majeen", "desc": "Santa always leaves plans for his elves to determine the order in which the reindeer will pull his sleigh. This year, for the European leg of his journey, his elves are working to the following schedule, which will form a single line of nine reindeer: \n\r\nComet behind Rudolph, Prancer and Cupid. Blitzen behind Cupid and in front of Donder, Vixen and Dancer. Cupid in front of Comet, Blitzen and Vixen. Donder behind Vixen, Dasher and Prancer. Rudolph behind Prancer and in front of Donder, Dancer and Dasher. Vixen in front of Dancer and Comet. Dancer behind Donder, Rudolph and Blitzen. Prancer in front of Cupid, Donder and Blitzen. Dasher behind Prancer and in front of Vixen, Dancer and Blitzen. Donder behind Comet and Cupid. Cupid in front of Rudolph and Dancer. Vixen behind Rudolph, Prancer and Dasher. \n\r\nCan you help the elves work out the order of the reindeer?", "hint": "No hint available.", "answer": "From front to back: Prancer, Cupid, Rudolph, Dasher, Blitzen, Vixen, Comet, Donder then Dancer.", "category": "Logic", "date": "01/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSanta always leaves plans for his elves to determine the order in which the reindeer will pull his sleigh. This year, for the European leg of his journey, his elves are working to the following schedule, which will form a single line of nine reindeer: \n\r\nComet behind Rudolph, Prancer and Cupid. Blitzen behind Cupid and in front of Donder, Vixen and Dancer. Cupid in front of Comet, Blitzen and Vixen. Donder behind Vixen, Dasher and Prancer. Rudolph behind Prancer and in front of Donder, Dancer and Dasher. Vixen in front of Dancer and Comet. Dancer behind Donder, Rudolph and Blitzen. Prancer in front of Cupid, Donder and Blitzen. Dasher behind Prancer and in front of Vixen, Dancer and Blitzen. Donder behind Comet and Cupid. Cupid in front of Rudolph and Dancer. Vixen behind Rudolph, Prancer and Dasher. \n\r\nCan you help the elves work out the order of the reindeer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom front to back: Prancer, Cupid, Rudolph, Dasher, Blitzen, Vixen, Comet, Donder then Dancer.\n<|im_start|>answer\nFrom front to back: Prancer, Cupid, Rudolph, Dasher, Blitzen, Vixen, Comet, Donder then Dancer.\n<|im_end|>" }, { "id": "#22219", "title": "Fix the Town", "fun": 2.5100000000000002, "difficulty": 1.82, "author": "DJNic", "desc": "One day an earthquake jumbled 8 of the buildings on Main Street up. \n\r\nThey were the following buildings: the school, the bank, the church, the theater, the jail, the mall, the thrift store, and the Town Hall.\n\r\nPlease fix the town to the order it is is supposed to be in.\n\r\n1) The jail is directly in between the theater and Town Hall buildings.\n\r\n2) The store is two away from the bank.\n\r\n3) The school is three away from the theater.\n\r\n4) The bank is somewhere at the left of the church.\n\r\n5) The store is next to the school.\n\r\n6) The church is next to the theater.\n\r\n7) The theater is 4 away from the store.\n\r\n8) The bank is next to the church.\n\r\n9) The mall is at the far left.", "hint": "No hint available.", "answer": "Left to Right:\n\r\nMall, Store, School, Bank, Church, Theater, Jail, Town Hall.", "category": "Logic", "date": "04/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day an earthquake jumbled 8 of the buildings on Main Street up. \n\r\nThey were the following buildings: the school, the bank, the church, the theater, the jail, the mall, the thrift store, and the Town Hall.\n\r\nPlease fix the town to the order it is is supposed to be in.\n\r\n1) The jail is directly in between the theater and Town Hall buildings.\n\r\n2) The store is two away from the bank.\n\r\n3) The school is three away from the theater.\n\r\n4) The bank is somewhere at the left of the church.\n\r\n5) The store is next to the school.\n\r\n6) The church is next to the theater.\n\r\n7) The theater is 4 away from the store.\n\r\n8) The bank is next to the church.\n\r\n9) The mall is at the far left.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeft to Right:\n\r\nMall, Store, School, Bank, Church, Theater, Jail, Town Hall.\n<|im_start|>answer\nLeft to Right:\n\r\nMall, Store, School, Bank, Church, Theater, Jail, Town Hall.\n<|im_end|>" }, { "id": "#3377", "title": "Chain E-Mail", "fun": 2.5100000000000002, "difficulty": 2.05, "author": "Mogmatt16", "desc": "Maybe you've gotten this e-mail before. It reads:\n\r\n\"I just got the coolest thing! This is endorsed by AOL and is great! Just forward this e-mail to ten people and you'll get an entirely new buddy list! I can see alternate screen names, who they're talking to, when they were last on and every thing! Remember, all you have to do is forward this to ten people and the buddylist 2000 is yours!\"\n\r\nUsing logic, how can you easily prove this wrong?", "hint": "This applies to any chain mail telling you about what will happen depending on how many people you send it to.", "answer": "They must send the e-mail to get the list. Whoever wrote this is bragging about it and claims to be looking at it. They can't change an e-mail they have already sent. How can they be telling you about it if they haven't gotten it yet due to not sending the e-mail?", "category": "Logic", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMaybe you've gotten this e-mail before. It reads:\n\r\n\"I just got the coolest thing! This is endorsed by AOL and is great! Just forward this e-mail to ten people and you'll get an entirely new buddy list! I can see alternate screen names, who they're talking to, when they were last on and every thing! Remember, all you have to do is forward this to ten people and the buddylist 2000 is yours!\"\n\r\nUsing logic, how can you easily prove this wrong?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey must send the e-mail to get the list. Whoever wrote this is bragging about it and claims to be looking at it. They can't change an e-mail they have already sent. How can they be telling you about it if they haven't gotten it yet due to not sending the e-mail?\n<|im_start|>answer\nThey must send the e-mail to get the list. Whoever wrote this is bragging about it and claims to be looking at it. They can't change an e-mail they have already sent. How can they be telling you about it if they haven't gotten it yet due to not sending the e-mail?\n<|im_end|>" }, { "id": "#50386", "title": "\"Simple\" Addition #1", "fun": 2.5100000000000002, "difficulty": 1.84, "author": "Ghostology", "desc": "Add in any required number of mathematical symbols to make this equation work.\n\r\n 0 0 0 = 6", "hint": "You need to use factorials to solve this sum.\n\r\nn! = n * (n-1) * (n-2) * .... * 2 * 1\n\r\nE.g. 2! = 2 * 1\r\n 3! = 3 * 2 * 1\r\n 0! = 1\n\r\nBrackets are also required. No other symbols are required.", "answer": "(0! + 0! + 0!)!", "category": "Math", "date": "06/30/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdd in any required number of mathematical symbols to make this equation work.\n\r\n 0 0 0 = 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(0! + 0! + 0!)!\n<|im_start|>answer\n(0! + 0! + 0!)!\n<|im_end|>" }, { "id": "#2206", "title": "Bags of Candies", "fun": 2.5100000000000002, "difficulty": 1.91, "author": "Cascas", "desc": "Michael has five bags of candies to give out. Four of the bags have a total of 84 candies. The fifth contains four candies less than the average of the five bags. How many candies are in the fifth bag?", "hint": "No hint available.", "answer": "Sixteen", "category": "Math", "date": "01/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMichael has five bags of candies to give out. Four of the bags have a total of 84 candies. The fifth contains four candies less than the average of the five bags. How many candies are in the fifth bag?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSixteen\n<|im_start|>answer\nSixteen\n<|im_end|>" }, { "id": "#48841", "title": "Favorite Snack", "fun": 2.5100000000000002, "difficulty": 0.98, "author": "Faith511", "desc": "Jenny, Carl, Benny, Mady, and Freddie are going to the candy store to buy a chocolate bar, a white chocolate bar, a lollipop, cotton candy, and a pack of gum. What is each kids favorite candy? Use these hints to find out.\n\r\n1.Both of the girls have chocolate treats.\n\r\n2.Mady, Carl, and the boy with cotton candy, are all in the same grade.\n\r\n3.Jenny, the girl with the white chocolate, the boy with gum, and Freddie, all play soccer.\n\r\n4.Carl has braces, so no gum for him.", "hint": "No hint available.", "answer": "Jenny - Chocolate bar\r\nCarl - Lollipop\r\nBenny - Gum\r\nMady - White chocolate\r\nFreddie - Cotton candy", "category": "Logic", "date": "06/26/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJenny, Carl, Benny, Mady, and Freddie are going to the candy store to buy a chocolate bar, a white chocolate bar, a lollipop, cotton candy, and a pack of gum. What is each kids favorite candy? Use these hints to find out.\n\r\n1.Both of the girls have chocolate treats.\n\r\n2.Mady, Carl, and the boy with cotton candy, are all in the same grade.\n\r\n3.Jenny, the girl with the white chocolate, the boy with gum, and Freddie, all play soccer.\n\r\n4.Carl has braces, so no gum for him.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJenny - Chocolate bar\r\nCarl - Lollipop\r\nBenny - Gum\r\nMady - White chocolate\r\nFreddie - Cotton candy\n<|im_start|>answer\nJenny - Chocolate bar\r\nCarl - Lollipop\r\nBenny - Gum\r\nMady - White chocolate\r\nFreddie - Cotton candy\n<|im_end|>" }, { "id": "#5773", "title": "River Trip", "fun": 2.5100000000000002, "difficulty": 2.02, "author": "Bobbrt", "desc": "Suppose there is a river that has no current. A man gets into a canoe and paddles upstream from his dock to the river's bend 5 kilometers away, and then turns around and returns to the dock. The entire trip takes 40 minutes. Now suppose that the river has a current of 2 kilometers per hour. If the man makes exactly the same trip, will it take longer than 40 minutes, shorter than 40 minutes, or the same amount of time?", "hint": "No hint available.", "answer": "The trip will take longer than 40 minutes. The man will travel two kph slower on the upstream trip and two kph faster on the downstream trip. However, the trip will take longer than 40 minutes because the canoe will be slowed down for a longer period of time going upstream than the time it gains going downstream.", "category": "Math", "date": "07/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose there is a river that has no current. A man gets into a canoe and paddles upstream from his dock to the river's bend 5 kilometers away, and then turns around and returns to the dock. The entire trip takes 40 minutes. Now suppose that the river has a current of 2 kilometers per hour. If the man makes exactly the same trip, will it take longer than 40 minutes, shorter than 40 minutes, or the same amount of time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe trip will take longer than 40 minutes. The man will travel two kph slower on the upstream trip and two kph faster on the downstream trip. However, the trip will take longer than 40 minutes because the canoe will be slowed down for a longer period of time going upstream than the time it gains going downstream.\n<|im_start|>answer\nThe trip will take longer than 40 minutes. The man will travel two kph slower on the upstream trip and two kph faster on the downstream trip. However, the trip will take longer than 40 minutes because the canoe will be slowed down for a longer period of time going upstream than the time it gains going downstream.\n<|im_end|>" }, { "id": "#29506", "title": "Question Mark's Function Machine", "fun": 2.5100000000000002, "difficulty": 2.84, "author": "Question_Mark", "desc": "Question Mark is very proud with himself. He has just designed his very own function machine. When a number goes into this machine, a different number comes out. A basic formula is used to determine what comes out. If:\n\r\n3 -> 90\r\n4 -> 272\r\n5 -> 650\r\n6 -> 1332\r\n7 -> 2450\n\r\nWhat will come out if 10 goes in?", "hint": "No hint available.", "answer": "10100. The formula is n^4 + n^2. In other words:\n\r\n3^4 (81) + 3^2 (9) = 90\r\n4^4 (256) + 4^2 (16) = 272\r\n5^4 (625) + 5^2 (25) = 650\r\n6^4 (1296) + 6^2 (36) = 1332\r\n7^4 (2401) + 7^2 (49) = 2450\n\r\nAnd therefore:\r\n10^4 (10000) + 10^2 (100) = 10100", "category": "Math", "date": "04/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuestion Mark is very proud with himself. He has just designed his very own function machine. When a number goes into this machine, a different number comes out. A basic formula is used to determine what comes out. If:\n\r\n3 -> 90\r\n4 -> 272\r\n5 -> 650\r\n6 -> 1332\r\n7 -> 2450\n\r\nWhat will come out if 10 goes in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10100. The formula is n^4 + n^2. In other words:\n\r\n3^4 (81) + 3^2 (9) = 90\r\n4^4 (256) + 4^2 (16) = 272\r\n5^4 (625) + 5^2 (25) = 650\r\n6^4 (1296) + 6^2 (36) = 1332\r\n7^4 (2401) + 7^2 (49) = 2450\n\r\nAnd therefore:\r\n10^4 (10000) + 10^2 (100) = 10100\n<|im_start|>answer\n10100. The formula is n^4 + n^2. In other words:\n\r\n3^4 (81) + 3^2 (9) = 90\r\n4^4 (256) + 4^2 (16) = 272\r\n5^4 (625) + 5^2 (25) = 650\r\n6^4 (1296) + 6^2 (36) = 1332\r\n7^4 (2401) + 7^2 (49) = 2450\n\r\nAnd therefore:\r\n10^4 (10000) + 10^2 (100) = 10100\n<|im_end|>" }, { "id": "#31843", "title": "Fingers and Toes", "fun": 2.5100000000000002, "difficulty": 1.49, "author": "bigSWAFF_69_", "desc": "Two of the world's best mathematicians were given the following problem:\n\r\nIf you take all the fingers on one hand and multiply it with all the fingers on your other hand, then subtract the number of toes on both of your feet, what number would you get?\n\r\nIf both mathematicians had all of their digits, and were 100% sure that they did all of their math correctly, how come one of them came up with an answer that was nearly 3 times that of the other?", "hint": "No hint available.", "answer": "One of the mathematicians counted each of the digits on his hand as a finger. 5 times 5 equals 25. 25 - 10 (the number of toes he has) = 15.\n\r\nThe other mathematician counted each of his fingers; 4. 4 times 4 equals 16. 16 - 10 = 6.\n\n\r\nSome people mistakenly count the thumb as a finger, which is what the first mathematician did.", "category": "Logic", "date": "07/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo of the world's best mathematicians were given the following problem:\n\r\nIf you take all the fingers on one hand and multiply it with all the fingers on your other hand, then subtract the number of toes on both of your feet, what number would you get?\n\r\nIf both mathematicians had all of their digits, and were 100% sure that they did all of their math correctly, how come one of them came up with an answer that was nearly 3 times that of the other?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne of the mathematicians counted each of the digits on his hand as a finger. 5 times 5 equals 25. 25 - 10 (the number of toes he has) = 15.\n\r\nThe other mathematician counted each of his fingers; 4. 4 times 4 equals 16. 16 - 10 = 6.\n\n\r\nSome people mistakenly count the thumb as a finger, which is what the first mathematician did.\n<|im_start|>answer\nOne of the mathematicians counted each of the digits on his hand as a finger. 5 times 5 equals 25. 25 - 10 (the number of toes he has) = 15.\n\r\nThe other mathematician counted each of his fingers; 4. 4 times 4 equals 16. 16 - 10 = 6.\n\n\r\nSome people mistakenly count the thumb as a finger, which is what the first mathematician did.\n<|im_end|>" }, { "id": "#14420", "title": "One Ice Cream for Two?", "fun": 2.5100000000000002, "difficulty": 1.54, "author": "Gerd", "desc": "Tom and Tina both have some money. Because it is a hot day, they decide to buy an ice cream for each of them. But then they realize they both don't have enough money. Tom needs 24 cents more for his ice cream, and Tina needs two cents more to buy one. Now they decide to buy one ice cream together, but still they don't have enough money to do so. \n\r\nWhat does one ice cream cost?", "hint": "No hint available.", "answer": "25 cents. \n\r\nBoth possess some money. Tina needs two more cents, and because it is still not enough with Tom's money to buy one ice cream, Tom only has one cent. Therefore one ice cream costs 25 cents.", "category": "Math", "date": "08/19/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTom and Tina both have some money. Because it is a hot day, they decide to buy an ice cream for each of them. But then they realize they both don't have enough money. Tom needs 24 cents more for his ice cream, and Tina needs two cents more to buy one. Now they decide to buy one ice cream together, but still they don't have enough money to do so. \n\r\nWhat does one ice cream cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n25 cents. \n\r\nBoth possess some money. Tina needs two more cents, and because it is still not enough with Tom's money to buy one ice cream, Tom only has one cent. Therefore one ice cream costs 25 cents.\n<|im_start|>answer\n25 cents. \n\r\nBoth possess some money. Tina needs two more cents, and because it is still not enough with Tom's money to buy one ice cream, Tom only has one cent. Therefore one ice cream costs 25 cents.\n<|im_end|>" }, { "id": "#36064", "title": "Some Squares", "fun": 2.5100000000000002, "difficulty": 1.8800000000000001, "author": "rzhao", "desc": "You are a 3rd grader. You have been victorious during the food fight today in school. As you walk home, a 5th grader suddenly jumps up behind you, with some moldy food from last week in his hand. He threatens to splat you unless you answer the following question correctly in 10 seconds:\n\r\nWhat is the square of 11,111,111?", "hint": "The 5th grader looks down at you, and says, \"I'll give you one hint: The square of 111 is 12,321.\"", "answer": "123,456,787,654,321\n\r\nUsing the hint, and the fact that the squares of 1 and 11 are 1 and 121, respectively, we can see a pattern in the series. When all the digits of a number are 1, and there are under 10 digits, the square of the number is 123...n...321, where n is the number of digits in the original number. Note however that this pattern only works for numbers with less that 10 digits, and all the digits must be 1.", "category": "Math", "date": "04/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are a 3rd grader. You have been victorious during the food fight today in school. As you walk home, a 5th grader suddenly jumps up behind you, with some moldy food from last week in his hand. He threatens to splat you unless you answer the following question correctly in 10 seconds:\n\r\nWhat is the square of 11,111,111?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n123,456,787,654,321\n\r\nUsing the hint, and the fact that the squares of 1 and 11 are 1 and 121, respectively, we can see a pattern in the series. When all the digits of a number are 1, and there are under 10 digits, the square of the number is 123...n...321, where n is the number of digits in the original number. Note however that this pattern only works for numbers with less that 10 digits, and all the digits must be 1.\n<|im_start|>answer\n123,456,787,654,321\n\r\nUsing the hint, and the fact that the squares of 1 and 11 are 1 and 121, respectively, we can see a pattern in the series. When all the digits of a number are 1, and there are under 10 digits, the square of the number is 123...n...321, where n is the number of digits in the original number. Note however that this pattern only works for numbers with less that 10 digits, and all the digits must be 1.\n<|im_end|>" }, { "id": "#49079", "title": "Cupcakes", "fun": 2.5100000000000002, "difficulty": 0.8200000000000001, "author": "bubbubfilt", "desc": "In the small town of Iyzzilen, there are many bakeries. The bakeries of Rokkal, Numinny, and Saldra each make a certain treat--cupcakes, croissants, and cookies. Each has a different hostess--Jessei, Laxa, and Glapra. And each is on a different street--1st, 2nd, and 3rd.\n\r\nRashiir is a tourist wishing to sample the food. She has been given these facts by locals to direct her to each shop:\r\n1. Jessei works next to Rokkal.\r\n2. The shop on 3rd doesn't make cookies.\r\n3. Laxa would never work on 1st; the traffic is dreadful.\r\n4. Numinny workers like to sprinkle chocolate dustings on their croissants.\r\n5. Laxa serves chocolate chip cookies hot from the oven, all gooey and melting.\r\n6. Saldra is famous for its strategic location on the street with many cupcake lovers, which isn't 3rd.\r\n7. Glapra is well-known as the founder and hostess of the shop on 1st.\n\r\nRashiir appreciates your being such a big help!", "hint": "No hint available.", "answer": "On 1st Street, Glapra, hostess of Saldra, serves the best cupcakes Rashiir ever had!\r\nJessei, hostess of Numinny, started the chocolate croissant tradition on 3rd Street--for which Rashiir is eternally grateful!\r\nLaxa, hostess of Rokkal, which is on 2nd Street, serves the best cookies in Iyzzilen, which Rashiir loved!\r\nRashiir gave each hostess a hefty tip and hopes you will come along for when she takes her next trip!", "category": "Logic-Grid", "date": "10/14/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the small town of Iyzzilen, there are many bakeries. The bakeries of Rokkal, Numinny, and Saldra each make a certain treat--cupcakes, croissants, and cookies. Each has a different hostess--Jessei, Laxa, and Glapra. And each is on a different street--1st, 2nd, and 3rd.\n\r\nRashiir is a tourist wishing to sample the food. She has been given these facts by locals to direct her to each shop:\r\n1. Jessei works next to Rokkal.\r\n2. The shop on 3rd doesn't make cookies.\r\n3. Laxa would never work on 1st; the traffic is dreadful.\r\n4. Numinny workers like to sprinkle chocolate dustings on their croissants.\r\n5. Laxa serves chocolate chip cookies hot from the oven, all gooey and melting.\r\n6. Saldra is famous for its strategic location on the street with many cupcake lovers, which isn't 3rd.\r\n7. Glapra is well-known as the founder and hostess of the shop on 1st.\n\r\nRashiir appreciates your being such a big help!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn 1st Street, Glapra, hostess of Saldra, serves the best cupcakes Rashiir ever had!\r\nJessei, hostess of Numinny, started the chocolate croissant tradition on 3rd Street--for which Rashiir is eternally grateful!\r\nLaxa, hostess of Rokkal, which is on 2nd Street, serves the best cookies in Iyzzilen, which Rashiir loved!\r\nRashiir gave each hostess a hefty tip and hopes you will come along for when she takes her next trip!\n<|im_start|>answer\nOn 1st Street, Glapra, hostess of Saldra, serves the best cupcakes Rashiir ever had!\r\nJessei, hostess of Numinny, started the chocolate croissant tradition on 3rd Street--for which Rashiir is eternally grateful!\r\nLaxa, hostess of Rokkal, which is on 2nd Street, serves the best cookies in Iyzzilen, which Rashiir loved!\r\nRashiir gave each hostess a hefty tip and hopes you will come along for when she takes her next trip!\n<|im_end|>" }, { "id": "#32881", "title": "Two Weights?", "fun": 2.5100000000000002, "difficulty": 2.88, "author": "moonsliver86", "desc": "Martin rushed into the room bearing good news.\n\r\n\"Joseph, your idea worked! The company liked the idea of using only two types of weights to measure heavy objects!\" announced Martin, giving the letter to Joseph.\n\r\n\"I told you so. Given any two types of weights, you can measure objects that are above a certain weight,\" explained Joseph, reading the letter, \"Well, as long as the two weights are not both even.\"\n\r\nMartin thought for a moment and then realized that he had no clue what Joseph meant by that, so he asked, \"Huh? What? Isn't the new weight system designed to measure all types of objects?\"\n\r\nJoseph smiled and replied, \"Technically, yes. However, this system can't measure objects that weigh 1 pound, 2 pounds and other lighter objects. Besides, both weights are heavier than 10 pounds.\"\n\r\n\"Really? But then why did the company like it?\" wondered Martin, \"What use does it have then? Can it measure 300 pounds? 90 pounds? 69 pounds?!\"\n\r\n\"Yes, yes, and no.\" Joseph laughed, \"You're not getting the point. The company only weighs things 120 pounds or heavier. This weighing system can't measure 119 pounds but any object above 119 pounds can be expressed as a sum of combinations of these two weights.\"\n\r\nAfter hearing that, Martin was even more confused. Finally, Joseph said, \"Look, 17 (5+5+7) can be expressed as a sum of only 5s and 7s. 18, on the other hand, can't. It works on the same principles. Think about it. You'll get it eventually.\"\n\r\nAssuming everything has integer weights, what were the two types of weights that Joseph suggested?", "hint": "Try it out with small numbers. What is the largest number that can not be expressed as a sum of 3s and 4s? The answer is 5. Try it out with other numbers. You'll find a pattern eventually.", "answer": "The two weights are 11 and 13.\n\r\nIf you played around with the hint, you'll realize that the largest number that cannot be expressed as a sum of Xs and Ys is equal to (X-1)(Y-1) - 1.\n\r\nWe are told that the largest number that can not be expressed as a sum of a combination of the two weights is 119.\n\r\nThus,\r\n119 = (x-1)(y-1) - 1\r\n120 = (x-1)(y-1)\n\r\nFrom here, we only have to list 120's factors: (1,120), (2,60), (3,40), (4,30), (5,24), (6,20), (8,15), (10,12). There are 8 possible combinations.\n\r\nHowever, we were told that both weights were above 10 pounds. Thus, only one pair remains (10,12). So, x=11 and y=13.\n\r\nTry it out. You can't make 119 using only 11s and 13s but you can make 120 and above using only 11s and 13s.", "category": "Math", "date": "09/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMartin rushed into the room bearing good news.\n\r\n\"Joseph, your idea worked! The company liked the idea of using only two types of weights to measure heavy objects!\" announced Martin, giving the letter to Joseph.\n\r\n\"I told you so. Given any two types of weights, you can measure objects that are above a certain weight,\" explained Joseph, reading the letter, \"Well, as long as the two weights are not both even.\"\n\r\nMartin thought for a moment and then realized that he had no clue what Joseph meant by that, so he asked, \"Huh? What? Isn't the new weight system designed to measure all types of objects?\"\n\r\nJoseph smiled and replied, \"Technically, yes. However, this system can't measure objects that weigh 1 pound, 2 pounds and other lighter objects. Besides, both weights are heavier than 10 pounds.\"\n\r\n\"Really? But then why did the company like it?\" wondered Martin, \"What use does it have then? Can it measure 300 pounds? 90 pounds? 69 pounds?!\"\n\r\n\"Yes, yes, and no.\" Joseph laughed, \"You're not getting the point. The company only weighs things 120 pounds or heavier. This weighing system can't measure 119 pounds but any object above 119 pounds can be expressed as a sum of combinations of these two weights.\"\n\r\nAfter hearing that, Martin was even more confused. Finally, Joseph said, \"Look, 17 (5+5+7) can be expressed as a sum of only 5s and 7s. 18, on the other hand, can't. It works on the same principles. Think about it. You'll get it eventually.\"\n\r\nAssuming everything has integer weights, what were the two types of weights that Joseph suggested?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two weights are 11 and 13.\n\r\nIf you played around with the hint, you'll realize that the largest number that cannot be expressed as a sum of Xs and Ys is equal to (X-1)(Y-1) - 1.\n\r\nWe are told that the largest number that can not be expressed as a sum of a combination of the two weights is 119.\n\r\nThus,\r\n119 = (x-1)(y-1) - 1\r\n120 = (x-1)(y-1)\n\r\nFrom here, we only have to list 120's factors: (1,120), (2,60), (3,40), (4,30), (5,24), (6,20), (8,15), (10,12). There are 8 possible combinations.\n\r\nHowever, we were told that both weights were above 10 pounds. Thus, only one pair remains (10,12). So, x=11 and y=13.\n\r\nTry it out. You can't make 119 using only 11s and 13s but you can make 120 and above using only 11s and 13s.\n<|im_start|>answer\nThe two weights are 11 and 13.\n\r\nIf you played around with the hint, you'll realize that the largest number that cannot be expressed as a sum of Xs and Ys is equal to (X-1)(Y-1) - 1.\n\r\nWe are told that the largest number that can not be expressed as a sum of a combination of the two weights is 119.\n\r\nThus,\r\n119 = (x-1)(y-1) - 1\r\n120 = (x-1)(y-1)\n\r\nFrom here, we only have to list 120's factors: (1,120), (2,60), (3,40), (4,30), (5,24), (6,20), (8,15), (10,12). There are 8 possible combinations.\n\r\nHowever, we were told that both weights were above 10 pounds. Thus, only one pair remains (10,12). So, x=11 and y=13.\n\r\nTry it out. You can't make 119 using only 11s and 13s but you can make 120 and above using only 11s and 13s.\n<|im_end|>" }, { "id": "#2091", "title": "The Dog Walk", "fun": 2.5100000000000002, "difficulty": 1.96, "author": "Cascas", "desc": "Matthew walks up and down a hill which is three kilometers each way. His dog, being slower, walks at half the speed. When Matthew reaches the top of the hill he turns around and walks down to meet his dog part way. Matthew continues walking to the bottom of the hill maintaining his speed. The dog follows him, also maintaining his speed. How far does the dog walk?", "hint": "No hint available.", "answer": "Four kilometers. When Matthew reaches the top of the hill, he will have walked three kilometers, and his dog will be half-way, or 1.5 kilometers. Matthew then turns around and walks back, but his dog continues walking up the hill until they meet. They will meet at the two kilometer point. The dog will turn around at this point and follow Matthew down the hill completing a 4 kilometer walk.", "category": "Math", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMatthew walks up and down a hill which is three kilometers each way. His dog, being slower, walks at half the speed. When Matthew reaches the top of the hill he turns around and walks down to meet his dog part way. Matthew continues walking to the bottom of the hill maintaining his speed. The dog follows him, also maintaining his speed. How far does the dog walk?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFour kilometers. When Matthew reaches the top of the hill, he will have walked three kilometers, and his dog will be half-way, or 1.5 kilometers. Matthew then turns around and walks back, but his dog continues walking up the hill until they meet. They will meet at the two kilometer point. The dog will turn around at this point and follow Matthew down the hill completing a 4 kilometer walk.\n<|im_start|>answer\nFour kilometers. When Matthew reaches the top of the hill, he will have walked three kilometers, and his dog will be half-way, or 1.5 kilometers. Matthew then turns around and walks back, but his dog continues walking up the hill until they meet. They will meet at the two kilometer point. The dog will turn around at this point and follow Matthew down the hill completing a 4 kilometer walk.\n<|im_end|>" }, { "id": "#26012", "title": "Double Trouble Math Equation", "fun": 2.5100000000000002, "difficulty": 2.44, "author": "qsceszxdwa", "desc": "Put the numbers 1 through 9 in the blanks, using each one only one time, to make this all true:\n\r\n_ _ x _ = _ _ _ = _ _ x _", "hint": "No hint available.", "answer": "58 x 3 = 174 = 29 x 6", "category": "Math", "date": "09/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPut the numbers 1 through 9 in the blanks, using each one only one time, to make this all true:\n\r\n_ _ x _ = _ _ _ = _ _ x _\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n58 x 3 = 174 = 29 x 6\n<|im_start|>answer\n58 x 3 = 174 = 29 x 6\n<|im_end|>" }, { "id": "#1379", "title": "Missing Symbols", "fun": 2.5100000000000002, "difficulty": 1.71, "author": "psychodude57", "desc": "Can you replace the question marks with maths symbols and make the equation correct: \n\r\n(6 ? 2) ? (3 ? 4) ? (6 ? 2) = 25", "hint": "No hint available.", "answer": "(6 - 2) * (3 + 4) - (6 / 2) = 25", "category": "Math", "date": "11/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you replace the question marks with maths symbols and make the equation correct: \n\r\n(6 ? 2) ? (3 ? 4) ? (6 ? 2) = 25\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(6 - 2) * (3 + 4) - (6 / 2) = 25\n<|im_start|>answer\n(6 - 2) * (3 + 4) - (6 / 2) = 25\n<|im_end|>" }, { "id": "#1565", "title": "Strawberry Jam", "fun": 2.5100000000000002, "difficulty": 1.78, "author": "psychodude57", "desc": "At the recent inter-departmental jam making contest, four lucky candidates took part to make the juiciest strawberry jam. The ages of the contestants were 14, 17, 20 and 22. As it happens the person who came last was the oldest, whereas Stuart was three years older than the person who came second. James was neither the oldest nor the youngest and Kev finished ahead of the 17 year old, but didn't win. John was also unlucky this time and didn't win either. Can you determine who finished where and how old they are?", "hint": "No hint available.", "answer": "James is 20 and came first.\r\nKev is 14 and came second.\r\nStuart is 17 and came third.\r\nJohn is 22 and came last.", "category": "Logic", "date": "12/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the recent inter-departmental jam making contest, four lucky candidates took part to make the juiciest strawberry jam. The ages of the contestants were 14, 17, 20 and 22. As it happens the person who came last was the oldest, whereas Stuart was three years older than the person who came second. James was neither the oldest nor the youngest and Kev finished ahead of the 17 year old, but didn't win. John was also unlucky this time and didn't win either. Can you determine who finished where and how old they are?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJames is 20 and came first.\r\nKev is 14 and came second.\r\nStuart is 17 and came third.\r\nJohn is 22 and came last.\n<|im_start|>answer\nJames is 20 and came first.\r\nKev is 14 and came second.\r\nStuart is 17 and came third.\r\nJohn is 22 and came last.\n<|im_end|>" }, { "id": "#25268", "title": "Students", "fun": 2.5100000000000002, "difficulty": 1.15, "author": "ErIn_RuLeS", "desc": "There are five students that moved around to other desks. Their names are Rick, Jane, Sara, Erin, and Henry.\n\r\nHelp the teacher figure out the new seating plan:\n\r\nErin likes Henry, so she now sits immediately to his left.\n\r\nJane hates Erin, so she now sits 3 seats away from her. (2 in between)\n\r\nRick hates to sit near the door, so he now sits at the end.\n\r\nSara likes to be at the center of attention, so she now sits in the middle.", "hint": "No hint available.", "answer": "Erin\r\nHenry\r\nSara\r\nJane\r\nRick", "category": "Logic", "date": "08/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are five students that moved around to other desks. Their names are Rick, Jane, Sara, Erin, and Henry.\n\r\nHelp the teacher figure out the new seating plan:\n\r\nErin likes Henry, so she now sits immediately to his left.\n\r\nJane hates Erin, so she now sits 3 seats away from her. (2 in between)\n\r\nRick hates to sit near the door, so he now sits at the end.\n\r\nSara likes to be at the center of attention, so she now sits in the middle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nErin\r\nHenry\r\nSara\r\nJane\r\nRick\n<|im_start|>answer\nErin\r\nHenry\r\nSara\r\nJane\r\nRick\n<|im_end|>" }, { "id": "#20147", "title": "The Hardware Store", "fun": 2.5100000000000002, "difficulty": 2.36, "author": "deathinator0", "desc": "A man goes into a hardware store to purchase some knobs. To purchase one knob you must pay a minimum of 4 U.S. coins. Two knobs can be purchased with a minimum of 6 U.S. coins. 3 knobs require a minimum of 2 U.S. coins. How much does one knob cost?\n\r\nU.S Coins include: a penny ($.01), a nickel ($.05), a dime ($.10), a quarter ($.25), a half-dollar ($.50), and a silver dollar ($1.00).", "hint": "Three knobs cannot be purchased with $0.50.", "answer": "One knob costs $0.17", "category": "Math", "date": "12/27/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man goes into a hardware store to purchase some knobs. To purchase one knob you must pay a minimum of 4 U.S. coins. Two knobs can be purchased with a minimum of 6 U.S. coins. 3 knobs require a minimum of 2 U.S. coins. How much does one knob cost?\n\r\nU.S Coins include: a penny ($.01), a nickel ($.05), a dime ($.10), a quarter ($.25), a half-dollar ($.50), and a silver dollar ($1.00).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne knob costs $0.17\n<|im_start|>answer\nOne knob costs $0.17\n<|im_end|>" }, { "id": "#28339", "title": "Opposites 8", "fun": 2.5100000000000002, "difficulty": 2.2, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n% stands for W, E, L, T, or O\r\n* stands for E, U, P, M, or N\r\n_ stands for E, J, S, A, or Y\r\n+ stands for I, R, A, S, or G\r\n/ stands for D, K, E, P, or H\n\r\nThe five letter code word, +%_/*, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Sleep and Awake.", "category": "Logic", "date": "01/29/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n% stands for W, E, L, T, or O\r\n* stands for E, U, P, M, or N\r\n_ stands for E, J, S, A, or Y\r\n+ stands for I, R, A, S, or G\r\n/ stands for D, K, E, P, or H\n\r\nThe five letter code word, +%_/*, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSleep and Awake.\n<|im_start|>answer\nSleep and Awake.\n<|im_end|>" }, { "id": "#4173", "title": "Marathon", "fun": 2.5, "difficulty": 1.44, "author": "librashorty", "desc": "After a recent marathon, the following was noted. \n\r\nAlan finished after Simon. \r\nIan finished after Kevin. \r\nSimon finished after Brian.\r\nKevin finished before Alan. \r\nBrian finished after Kevin. \r\nBrian finished before Alan. \r\nSimon finished before Ian. \r\nAlan finished before Ian. \n\r\nWho finished where?", "hint": "No hint available.", "answer": "The result was Kevin, Brian, Simon, Alan then Ian.", "category": "Logic", "date": "05/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter a recent marathon, the following was noted. \n\r\nAlan finished after Simon. \r\nIan finished after Kevin. \r\nSimon finished after Brian.\r\nKevin finished before Alan. \r\nBrian finished after Kevin. \r\nBrian finished before Alan. \r\nSimon finished before Ian. \r\nAlan finished before Ian. \n\r\nWho finished where?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe result was Kevin, Brian, Simon, Alan then Ian.\n<|im_start|>answer\nThe result was Kevin, Brian, Simon, Alan then Ian.\n<|im_end|>" }, { "id": "#16972", "title": "Make 120", "fun": 2.5, "difficulty": 2.63, "author": "slob", "desc": "Given five zeroes, using any mathematical operations, can you make a total of 120?", "hint": "No hint available.", "answer": "(0!+0!+0!+0!+0!)! = 120 \n\r\n0! is defined to equal 1. \n\r\n(1+1+1+1+1)! = 5! = 120", "category": "Math", "date": "03/10/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGiven five zeroes, using any mathematical operations, can you make a total of 120?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(0!+0!+0!+0!+0!)! = 120 \n\r\n0! is defined to equal 1. \n\r\n(1+1+1+1+1)! = 5! = 120\n<|im_start|>answer\n(0!+0!+0!+0!+0!)! = 120 \n\r\n0! is defined to equal 1. \n\r\n(1+1+1+1+1)! = 5! = 120\n<|im_end|>" }, { "id": "#14165", "title": "Five Digits", "fun": 2.5, "difficulty": 2.08, "author": "mathemagician", "desc": "I am thinking of a five-digit number in which no two of the digits are the same.\n\r\nThe fourth digit is three times the second; the last digit is two more than the sum of the first and second; the first digit is one less than the fourth; and the third digit is the difference between the last digit and the first.\n\r\nWhat's my number?", "hint": "The smallest digit is 2.", "answer": "52,469", "category": "Math", "date": "08/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am thinking of a five-digit number in which no two of the digits are the same.\n\r\nThe fourth digit is three times the second; the last digit is two more than the sum of the first and second; the first digit is one less than the fourth; and the third digit is the difference between the last digit and the first.\n\r\nWhat's my number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n52,469\n<|im_start|>answer\n52,469\n<|im_end|>" }, { "id": "#18942", "title": "Getting to Know the Band", "fun": 2.5, "difficulty": 2.24, "author": "Poker", "desc": "Thad is part of the little known band known as 'The Royal Flush.' He and his seven buddies each play a different instrument (guitar, bass, drums, keyboard, harmonica, saxophone, trumpet, or miscellaneous percussion). In addition to each playing an instrument, one member is the lead singer, and two others do backup singing. From the information given, can you determine who plays what, and who sings lead and who sings backup?\n\r\n1. Curt absolutely cannot use his voice or breath in any way to contribute to the music of the band - he can't sing, and he can't play the harmonica, saxophone, or trumpet.\r\n2. Only one of the guitar and bass players is singing.\r\n3. The three singers are Ollie (who can't play the keyboard), the drummer (I know drummers aren't renowned for singing, but this one's an exception), and the lead singer.\r\n4. The only reason that Ralph's in the band is because the drummer can't handle all of the percussion; Ralph does misc. percussion, and he doesn't even sing!\r\n5. Neither Eddie nor Pat (who can't sing a note) plays the harmonica.\r\n6. The guitarist isn't a backup singer, nor is the bass player the lead singer.\r\n7. Harry is a fine drummer, and he also plays the trumpet. But aside from his voice, that's all he can do.\r\n8. Mike has a very good singing voice, but someone had a better one, as Mike is only a backup singer.\r\n9. In case it isn't obvious, nobody who plays the harmonica, saxophone, or trumpet also sings.", "hint": "Figure out which instruments the singers play first.", "answer": "Ralph does misc. percussion and doesn't sing (clue 4). The other non-singers play the harmonica, saxophone, trumpet, and one of the guitar or the bass (clues 2 and 9). The drummer and keyboard player are singers, but neither of them is Ollie (also a singer, clue 3), so Ollie is the third singer, so the keyboard player is the lead singer (clue 3, only spot left). Mike sings backup, so he plays the drums (only spot on clue 3), and Ollie sings backup, so he plays the bass (clue 6). Curt does not sing (clue 1), but does not play the harmonica, saxophone, or trumpet (clue 1); he plays guitar. Harry plays the trumpet (clue 7, he cannot play the drums). Neither Eddie nor Pat plays harmonica (clue 5), that is Thad. Pat cannot sing (clue 5), so he does not play keyboard (lead singer); he plays saxophone, so Eddie sings lead and plays keyboard. In summary:\n\r\nEddie plays the keyboard and sings lead.\r\nCurt plays the guitar.\r\nOllie plays the bass and sings backup.\r\nMike plays the drums and sings backup.\r\nThad plays the harmonica.\r\nPat plays the saxophone.\r\nHarry plays the trumpet.\r\nRalph plays miscellaneous percussion.", "category": "Logic", "date": "09/25/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThad is part of the little known band known as 'The Royal Flush.' He and his seven buddies each play a different instrument (guitar, bass, drums, keyboard, harmonica, saxophone, trumpet, or miscellaneous percussion). In addition to each playing an instrument, one member is the lead singer, and two others do backup singing. From the information given, can you determine who plays what, and who sings lead and who sings backup?\n\r\n1. Curt absolutely cannot use his voice or breath in any way to contribute to the music of the band - he can't sing, and he can't play the harmonica, saxophone, or trumpet.\r\n2. Only one of the guitar and bass players is singing.\r\n3. The three singers are Ollie (who can't play the keyboard), the drummer (I know drummers aren't renowned for singing, but this one's an exception), and the lead singer.\r\n4. The only reason that Ralph's in the band is because the drummer can't handle all of the percussion; Ralph does misc. percussion, and he doesn't even sing!\r\n5. Neither Eddie nor Pat (who can't sing a note) plays the harmonica.\r\n6. The guitarist isn't a backup singer, nor is the bass player the lead singer.\r\n7. Harry is a fine drummer, and he also plays the trumpet. But aside from his voice, that's all he can do.\r\n8. Mike has a very good singing voice, but someone had a better one, as Mike is only a backup singer.\r\n9. In case it isn't obvious, nobody who plays the harmonica, saxophone, or trumpet also sings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRalph does misc. percussion and doesn't sing (clue 4). The other non-singers play the harmonica, saxophone, trumpet, and one of the guitar or the bass (clues 2 and 9). The drummer and keyboard player are singers, but neither of them is Ollie (also a singer, clue 3), so Ollie is the third singer, so the keyboard player is the lead singer (clue 3, only spot left). Mike sings backup, so he plays the drums (only spot on clue 3), and Ollie sings backup, so he plays the bass (clue 6). Curt does not sing (clue 1), but does not play the harmonica, saxophone, or trumpet (clue 1); he plays guitar. Harry plays the trumpet (clue 7, he cannot play the drums). Neither Eddie nor Pat plays harmonica (clue 5), that is Thad. Pat cannot sing (clue 5), so he does not play keyboard (lead singer); he plays saxophone, so Eddie sings lead and plays keyboard. In summary:\n\r\nEddie plays the keyboard and sings lead.\r\nCurt plays the guitar.\r\nOllie plays the bass and sings backup.\r\nMike plays the drums and sings backup.\r\nThad plays the harmonica.\r\nPat plays the saxophone.\r\nHarry plays the trumpet.\r\nRalph plays miscellaneous percussion.\n<|im_start|>answer\nRalph does misc. percussion and doesn't sing (clue 4). The other non-singers play the harmonica, saxophone, trumpet, and one of the guitar or the bass (clues 2 and 9). The drummer and keyboard player are singers, but neither of them is Ollie (also a singer, clue 3), so Ollie is the third singer, so the keyboard player is the lead singer (clue 3, only spot left). Mike sings backup, so he plays the drums (only spot on clue 3), and Ollie sings backup, so he plays the bass (clue 6). Curt does not sing (clue 1), but does not play the harmonica, saxophone, or trumpet (clue 1); he plays guitar. Harry plays the trumpet (clue 7, he cannot play the drums). Neither Eddie nor Pat plays harmonica (clue 5), that is Thad. Pat cannot sing (clue 5), so he does not play keyboard (lead singer); he plays saxophone, so Eddie sings lead and plays keyboard. In summary:\n\r\nEddie plays the keyboard and sings lead.\r\nCurt plays the guitar.\r\nOllie plays the bass and sings backup.\r\nMike plays the drums and sings backup.\r\nThad plays the harmonica.\r\nPat plays the saxophone.\r\nHarry plays the trumpet.\r\nRalph plays miscellaneous percussion.\n<|im_end|>" }, { "id": "#2734", "title": "Water Temps", "fun": 2.5, "difficulty": 2.8, "author": "gakuka", "desc": "Pretend you have two faucets for your shower, one that releases hot water and one that releases cold water, but at varying pressures. If the hot water is 105 degrees Fahrenheit and the cold water is 45 degrees Fahrenheit, and you could rotate the faucet at most 360 degrees, how much would you have to rotate the cold water faucet to get the temperature to be 98.6 degrees Fahrenheit, if the hot water is turned on all the way, and could not be turned down?", "hint": "Add how much you've rotated each and divide by the total rotation to get the average temperature.", "answer": "the equation for finding the answer, explained by the hint, is (105(360)+(45)(x))/(360+x)=98.6\r\nSolving for x:\r\nx= 42.985 degrees", "category": "Math", "date": "03/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPretend you have two faucets for your shower, one that releases hot water and one that releases cold water, but at varying pressures. If the hot water is 105 degrees Fahrenheit and the cold water is 45 degrees Fahrenheit, and you could rotate the faucet at most 360 degrees, how much would you have to rotate the cold water faucet to get the temperature to be 98.6 degrees Fahrenheit, if the hot water is turned on all the way, and could not be turned down?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nthe equation for finding the answer, explained by the hint, is (105(360)+(45)(x))/(360+x)=98.6\r\nSolving for x:\r\nx= 42.985 degrees\n<|im_start|>answer\nthe equation for finding the answer, explained by the hint, is (105(360)+(45)(x))/(360+x)=98.6\r\nSolving for x:\r\nx= 42.985 degrees\n<|im_end|>" }, { "id": "#14728", "title": "Club Logic", "fun": 2.5, "difficulty": 1.76, "author": "jimbo", "desc": "At Jimbo's school there are 3 clubs: the snooker club, the chess club and the table tennis club.\r\n1. All of the chess players also belong to one or more of the other clubs.\r\n2. No snooker players play chess except for those who also play table tennis.\r\n3. Some table tennis players who don't play chess also play snooker.\n\r\nNow determine if the following statements are true or false:\n\r\nA. Some non table tennis players that play snooker also play chess (T or F?)\r\nB. No chess players that also play table tennis play snooker (T or F?)\r\nC. Some non-snooker players who play chess also play table-tennis (T or F?)", "hint": "Model this with a deck of cards such that the snooker players are the Hearts, the Chess players are the Kings and the table tennis players are court cards. Thus all Kings are Hearts and/or court cards. No hearts are Kings except for KH which is also a court card. Some court cards that are not Kings are also hearts. Now reinterpret the questions.", "answer": "A. The answer is FALSE. In terms of the hint given, some non court cards that are hearts are also Kings would be false. \r\nB. The answer is FALSE. In terms of the hint given, no King that is also a court card is a heart would be false. \r\nC. The answer is TRUE. In terms of the hint given, some non-hearts that are Kings are also court cards would be true.", "category": "Logic", "date": "09/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt Jimbo's school there are 3 clubs: the snooker club, the chess club and the table tennis club.\r\n1. All of the chess players also belong to one or more of the other clubs.\r\n2. No snooker players play chess except for those who also play table tennis.\r\n3. Some table tennis players who don't play chess also play snooker.\n\r\nNow determine if the following statements are true or false:\n\r\nA. Some non table tennis players that play snooker also play chess (T or F?)\r\nB. No chess players that also play table tennis play snooker (T or F?)\r\nC. Some non-snooker players who play chess also play table-tennis (T or F?)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA. The answer is FALSE. In terms of the hint given, some non court cards that are hearts are also Kings would be false. \r\nB. The answer is FALSE. In terms of the hint given, no King that is also a court card is a heart would be false. \r\nC. The answer is TRUE. In terms of the hint given, some non-hearts that are Kings are also court cards would be true.\n<|im_start|>answer\nA. The answer is FALSE. In terms of the hint given, some non court cards that are hearts are also Kings would be false. \r\nB. The answer is FALSE. In terms of the hint given, no King that is also a court card is a heart would be false. \r\nC. The answer is TRUE. In terms of the hint given, some non-hearts that are Kings are also court cards would be true.\n<|im_end|>" }, { "id": "#33325", "title": "Number 25", "fun": 2.5, "difficulty": 2.34, "author": "spookboy0", "desc": "Five digits, I have five digits in all\r\nThe sum of my whole is nineteen\r\nTwo digits are alike in every way\r\nYet two other digits are in between\n\r\nI'm number twenty-five in a famous succession\r\nThe middle number has no value to size\r\nThe first two digits and the last two digits\r\nAre both very much divisible by five\n\r\nWhat number am I?", "hint": "No hint available.", "answer": "75,025\n\r\n7 + 5 + 0 + 2 + 5 = 19\n\r\nThe 0 and the 2 are the two digits in between the 5's.\n\r\n75,025 is the 25th number in the Fibonacci sequence.\n\r\nThe middle number, 0, has no value.\n\r\n75 and 25 are both divisible by 5.", "category": "Math", "date": "10/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive digits, I have five digits in all\r\nThe sum of my whole is nineteen\r\nTwo digits are alike in every way\r\nYet two other digits are in between\n\r\nI'm number twenty-five in a famous succession\r\nThe middle number has no value to size\r\nThe first two digits and the last two digits\r\nAre both very much divisible by five\n\r\nWhat number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n75,025\n\r\n7 + 5 + 0 + 2 + 5 = 19\n\r\nThe 0 and the 2 are the two digits in between the 5's.\n\r\n75,025 is the 25th number in the Fibonacci sequence.\n\r\nThe middle number, 0, has no value.\n\r\n75 and 25 are both divisible by 5.\n<|im_start|>answer\n75,025\n\r\n7 + 5 + 0 + 2 + 5 = 19\n\r\nThe 0 and the 2 are the two digits in between the 5's.\n\r\n75,025 is the 25th number in the Fibonacci sequence.\n\r\nThe middle number, 0, has no value.\n\r\n75 and 25 are both divisible by 5.\n<|im_end|>" }, { "id": "#22965", "title": "Inspector Beethoven", "fun": 2.5, "difficulty": 1.8, "author": "beethovenswig", "desc": "Beethoven needs your help! Mozart has been killed at a party in a mansion and Beethoven has been called to the case. The rooms in the mansion are: The Library, The Dining Room, The Music Room, and The Study. Mozart was killed in the Music room. Schubert, Joplin, Hayden, and Gershwin are the suspects. Beethoven has figured out that the suspect that was in the Music Room at the time of the murder is the one who killed Mozart. Find out which suspect was in which room at the time of the murder to figure out the person who killed Mozart!\n\r\n1. Schubert hated books.\r\n2. Joplin was either eating or practicing piano.\r\n3. Gershwin liked books, but wasn't in the Library.\r\n4. There were two people in the Music Room.\r\n5. Schubert was sick of being called \"Sherbet\" by Joplin, so he left the room Joplin was in.", "hint": "No hint available.", "answer": "Schubert murdered Mozart.\r\nHayden was in the Library.\r\nJoplin was in the Dining Room.\r\nGershwin was in the Study.\r\nSchubert was in the Music Room. \r\nThe second person in the music room was Mozart's dead body!", "category": "Logic", "date": "05/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBeethoven needs your help! Mozart has been killed at a party in a mansion and Beethoven has been called to the case. The rooms in the mansion are: The Library, The Dining Room, The Music Room, and The Study. Mozart was killed in the Music room. Schubert, Joplin, Hayden, and Gershwin are the suspects. Beethoven has figured out that the suspect that was in the Music Room at the time of the murder is the one who killed Mozart. Find out which suspect was in which room at the time of the murder to figure out the person who killed Mozart!\n\r\n1. Schubert hated books.\r\n2. Joplin was either eating or practicing piano.\r\n3. Gershwin liked books, but wasn't in the Library.\r\n4. There were two people in the Music Room.\r\n5. Schubert was sick of being called \"Sherbet\" by Joplin, so he left the room Joplin was in.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSchubert murdered Mozart.\r\nHayden was in the Library.\r\nJoplin was in the Dining Room.\r\nGershwin was in the Study.\r\nSchubert was in the Music Room. \r\nThe second person in the music room was Mozart's dead body!\n<|im_start|>answer\nSchubert murdered Mozart.\r\nHayden was in the Library.\r\nJoplin was in the Dining Room.\r\nGershwin was in the Study.\r\nSchubert was in the Music Room. \r\nThe second person in the music room was Mozart's dead body!\n<|im_end|>" }, { "id": "#12497", "title": "It is May 2003", "fun": 2.5, "difficulty": 2.09, "author": "ejasami", "desc": "It is May 2003 and today three planets and a central star are in a straight line (this isn't necessarily our solar system). The farthest planet takes 18 years to complete an orbit around the central star, the second farthest takes 9 years to orbit around the star, and the nearest takes 4 years 6 months. What month and year will it be when the planets and star are once again in a straight line? Assume they have the same axis of orbit and their calendar measurement is the same as ours.", "hint": "No hint available.", "answer": "May 2012. Given the assumption that they have the same axis of orbit, in 9 years they will be aligned in a straight line ... even though they are not all on the same side of the star. The furthest planet with the 18 year orbit is on the far side of the central star, but still in line with the others.", "category": "Math", "date": "05/20/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is May 2003 and today three planets and a central star are in a straight line (this isn't necessarily our solar system). The farthest planet takes 18 years to complete an orbit around the central star, the second farthest takes 9 years to orbit around the star, and the nearest takes 4 years 6 months. What month and year will it be when the planets and star are once again in a straight line? Assume they have the same axis of orbit and their calendar measurement is the same as ours.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMay 2012. Given the assumption that they have the same axis of orbit, in 9 years they will be aligned in a straight line ... even though they are not all on the same side of the star. The furthest planet with the 18 year orbit is on the far side of the central star, but still in line with the others.\n<|im_start|>answer\nMay 2012. Given the assumption that they have the same axis of orbit, in 9 years they will be aligned in a straight line ... even though they are not all on the same side of the star. The furthest planet with the 18 year orbit is on the far side of the central star, but still in line with the others.\n<|im_end|>" }, { "id": "#1551", "title": "Maria's Age", "fun": 2.5, "difficulty": 1.71, "author": "gokaran", "desc": "Maria doesn't like to tell people her real age. When somebody asks her how old she is, she says that she is twenty-one. (Maria mentally omits all Sundays because on Sundays she doesn't work, so she claims she doesn't get any older.) \n\r\nHow old is Maria really?", "hint": "No hint available.", "answer": "Maria could be either 24 or 25. She subtracted one-seventh of her real age.\n\r\nIf she were actually 24.5 years old, she could claim that she was 21 (24.5 * 6/7 = 21).\n\r\nIf she were actually 25.6 years old, she could also claim that she was 21 (25.6 * 6/7 = 21.9 (rounded)).", "category": "Math", "date": "11/30/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMaria doesn't like to tell people her real age. When somebody asks her how old she is, she says that she is twenty-one. (Maria mentally omits all Sundays because on Sundays she doesn't work, so she claims she doesn't get any older.) \n\r\nHow old is Maria really?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMaria could be either 24 or 25. She subtracted one-seventh of her real age.\n\r\nIf she were actually 24.5 years old, she could claim that she was 21 (24.5 * 6/7 = 21).\n\r\nIf she were actually 25.6 years old, she could also claim that she was 21 (25.6 * 6/7 = 21.9 (rounded)).\n<|im_start|>answer\nMaria could be either 24 or 25. She subtracted one-seventh of her real age.\n\r\nIf she were actually 24.5 years old, she could claim that she was 21 (24.5 * 6/7 = 21).\n\r\nIf she were actually 25.6 years old, she could also claim that she was 21 (25.6 * 6/7 = 21.9 (rounded)).\n<|im_end|>" }, { "id": "#24718", "title": "Rob and Bob", "fun": 2.5, "difficulty": 1.57, "author": "luckyseven", "desc": "Rob and Bob played a challenging game several times, betting one pebble on the outcome every time. Rob won seven pebbles, while Bob won seven times. There were no ties. \n\r\nHow many times did they play?", "hint": "No hint available.", "answer": "If Rob is up seven pebbles, that means he has won seven more times that he has lost. He lost seven times. Therefore Rob won 7+7=14 times.\n\r\ngames played\r\n= Rob's wins + Bob's wins\r\n= 14 + 7=21", "category": "Math", "date": "07/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRob and Bob played a challenging game several times, betting one pebble on the outcome every time. Rob won seven pebbles, while Bob won seven times. There were no ties. \n\r\nHow many times did they play?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Rob is up seven pebbles, that means he has won seven more times that he has lost. He lost seven times. Therefore Rob won 7+7=14 times.\n\r\ngames played\r\n= Rob's wins + Bob's wins\r\n= 14 + 7=21\n<|im_start|>answer\nIf Rob is up seven pebbles, that means he has won seven more times that he has lost. He lost seven times. Therefore Rob won 7+7=14 times.\n\r\ngames played\r\n= Rob's wins + Bob's wins\r\n= 14 + 7=21\n<|im_end|>" }, { "id": "#28722", "title": "Opposites 9", "fun": 2.5, "difficulty": 2.3, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n3 stands for P, L, U, Y, or R\r\n\\ stands for E, D, H, M, or G\r\n/ stands for O, W, C, E, or K\r\n1 stands for A, N, I, B, or S\n\r\nThe four letter code word, /13\\, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Wild and Calm", "category": "Logic", "date": "02/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n3 stands for P, L, U, Y, or R\r\n\\ stands for E, D, H, M, or G\r\n/ stands for O, W, C, E, or K\r\n1 stands for A, N, I, B, or S\n\r\nThe four letter code word, /13\\, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWild and Calm\n<|im_start|>answer\nWild and Calm\n<|im_end|>" }, { "id": "#29131", "title": "Opposites 16", "fun": 2.5, "difficulty": 2.07, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n} stands for C, N, T, E, or M\r\n] stands for O, B, R, M, or K\r\n> stands for I, H, R, E, or C\r\n) stands for A, S, P, D, or Y\n\r\nThe four letter code word, >)]}, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Harm and Care", "category": "Logic", "date": "03/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n} stands for C, N, T, E, or M\r\n] stands for O, B, R, M, or K\r\n> stands for I, H, R, E, or C\r\n) stands for A, S, P, D, or Y\n\r\nThe four letter code word, >)]}, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarm and Care\n<|im_start|>answer\nHarm and Care\n<|im_end|>" }, { "id": "#33412", "title": "One Less Than...", "fun": 2.5, "difficulty": 2.47, "author": "lessthanjake789", "desc": "What is the smallest number, besides 1, that is one less than twice its digits reversed?", "hint": "So, 2 digit number AB = 2BA-1.", "answer": "73. 37*2 - 1 = 73.", "category": "Math", "date": "10/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest number, besides 1, that is one less than twice its digits reversed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n73. 37*2 - 1 = 73.\n<|im_start|>answer\n73. 37*2 - 1 = 73.\n<|im_end|>" }, { "id": "#23374", "title": "Ice Cream", "fun": 2.5, "difficulty": 1.13, "author": "dbs241", "desc": "Ten ice cream bars and 6 ice cream cones cost $13. But if you buy 6 ice cream bars and 10 ice cream cones, the bill will be $11. How much does an ice cream bar cost?", "hint": "No hint available.", "answer": "Ice cream bars cost $1. (Ice cream cones cost 50 cents.)", "category": "Math", "date": "06/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTen ice cream bars and 6 ice cream cones cost $13. But if you buy 6 ice cream bars and 10 ice cream cones, the bill will be $11. How much does an ice cream bar cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIce cream bars cost $1. (Ice cream cones cost 50 cents.)\n<|im_start|>answer\nIce cream bars cost $1. (Ice cream cones cost 50 cents.)\n<|im_end|>" }, { "id": "#19786", "title": "The Toy Store", "fun": 2.5, "difficulty": 1.25, "author": "horse_luver", "desc": "Abby, Bob, Cindy and Don went to the toy store to get a new toy. They each bought a different toy. They paid a different price for their items. Work out who bought what toy for what price. \n\r\nKids: Abby, Bob, Cindy, Don \r\nToys: Ball, Skipping rope, Paper doll, Book \r\nPrices: $1, $1.50, $2, $2.50 \n\r\n1) A boy bought the ball. \r\n2) Cindy paid with a bill and got less than $3 back. \r\n3) The $1 item was made from paper. \r\n4) The boys only brought $1.75 each. \r\n5) The skipping rope was exactly $1 more than the ball. \r\n6) The book was not $2. \r\n7) Someone with an \"n\" in their name bought the ball.", "hint": "If (not that) Abby bought something for $1, and Abby bought the rope, then we know the $1 item is the rope. (Note: These facts may or may not be true.)", "answer": "Abby bought the $2 paper doll.\r\nBob bought the $1 book.\r\nCindy bought the $2.50 skipping rope.\r\nDon bought the $1.50 ball.", "category": "Logic-Grid", "date": "12/08/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbby, Bob, Cindy and Don went to the toy store to get a new toy. They each bought a different toy. They paid a different price for their items. Work out who bought what toy for what price. \n\r\nKids: Abby, Bob, Cindy, Don \r\nToys: Ball, Skipping rope, Paper doll, Book \r\nPrices: $1, $1.50, $2, $2.50 \n\r\n1) A boy bought the ball. \r\n2) Cindy paid with a bill and got less than $3 back. \r\n3) The $1 item was made from paper. \r\n4) The boys only brought $1.75 each. \r\n5) The skipping rope was exactly $1 more than the ball. \r\n6) The book was not $2. \r\n7) Someone with an \"n\" in their name bought the ball.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbby bought the $2 paper doll.\r\nBob bought the $1 book.\r\nCindy bought the $2.50 skipping rope.\r\nDon bought the $1.50 ball.\n<|im_start|>answer\nAbby bought the $2 paper doll.\r\nBob bought the $1 book.\r\nCindy bought the $2.50 skipping rope.\r\nDon bought the $1.50 ball.\n<|im_end|>" }, { "id": "#19024", "title": "Higher Card", "fun": 2.5, "difficulty": 2.08, "author": "stcaeyg449", "desc": "You find yourself at the Greenjack table. Greenjack is similar to Blackjack, except that it is completely different. It is played with a deck of only 16 cards, divided into 4 suits: Red, Blue, Orange and Green. There are four cards in each suit: Ace, King, Queen and Jack. Ace outranks King, which outranks Queen, which outranks Jack - except for the Green Jack, which outranks every other card. If two cards have the same face value, then Red outranks Blue, which outranks Orange, which outranks Green, again except for the Green Jack, which outranks everything.\n\r\nHere's how the game is played: you are dealt one card face up, and the dealer is dealt one card face down. The dealer then makes some true statements, and you have to work out who has the higher card, you or the dealer. It's that simple!\n\r\nRound 1:\r\nYou are dealt the Green Ace and the dealer makes three statements: \n\r\n1. My card would beat any Queen.\r\n2. Knowing this, if my card is more likely to beat yours, then my card is Blue. Otherwise it isn't.\r\n3. Given all of the information you now know, if your card is more likely to beat mine, then my card is a King. Otherwise it isn't. \n\r\nWho has the higher card, you or the dealer?", "hint": "No hint available.", "answer": "The dealer's card is higher: after #1 you know that you have a Green Ace (GA) and the dealer's card can beat any Queen, therefore the dealer must have one of the following cards: RA, BA, OA, RK, BK, OK, GK, GJ. Of these 8 cards, 4 can beat yours, therefore by #2 the dealer can't have a blue card, which means that his card must be one of: RA, OA, RK, OK, GK, GJ. Of these 6 cards your card can beat 3, therefore by #3 the dealer can't have a King, which means he has one of: RA, OA, GJ - all of which can beat your card. Therefore the dealer's card is higher.", "category": "Logic", "date": "10/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou find yourself at the Greenjack table. Greenjack is similar to Blackjack, except that it is completely different. It is played with a deck of only 16 cards, divided into 4 suits: Red, Blue, Orange and Green. There are four cards in each suit: Ace, King, Queen and Jack. Ace outranks King, which outranks Queen, which outranks Jack - except for the Green Jack, which outranks every other card. If two cards have the same face value, then Red outranks Blue, which outranks Orange, which outranks Green, again except for the Green Jack, which outranks everything.\n\r\nHere's how the game is played: you are dealt one card face up, and the dealer is dealt one card face down. The dealer then makes some true statements, and you have to work out who has the higher card, you or the dealer. It's that simple!\n\r\nRound 1:\r\nYou are dealt the Green Ace and the dealer makes three statements: \n\r\n1. My card would beat any Queen.\r\n2. Knowing this, if my card is more likely to beat yours, then my card is Blue. Otherwise it isn't.\r\n3. Given all of the information you now know, if your card is more likely to beat mine, then my card is a King. Otherwise it isn't. \n\r\nWho has the higher card, you or the dealer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe dealer's card is higher: after #1 you know that you have a Green Ace (GA) and the dealer's card can beat any Queen, therefore the dealer must have one of the following cards: RA, BA, OA, RK, BK, OK, GK, GJ. Of these 8 cards, 4 can beat yours, therefore by #2 the dealer can't have a blue card, which means that his card must be one of: RA, OA, RK, OK, GK, GJ. Of these 6 cards your card can beat 3, therefore by #3 the dealer can't have a King, which means he has one of: RA, OA, GJ - all of which can beat your card. Therefore the dealer's card is higher.\n<|im_start|>answer\nThe dealer's card is higher: after #1 you know that you have a Green Ace (GA) and the dealer's card can beat any Queen, therefore the dealer must have one of the following cards: RA, BA, OA, RK, BK, OK, GK, GJ. Of these 8 cards, 4 can beat yours, therefore by #2 the dealer can't have a blue card, which means that his card must be one of: RA, OA, RK, OK, GK, GJ. Of these 6 cards your card can beat 3, therefore by #3 the dealer can't have a King, which means he has one of: RA, OA, GJ - all of which can beat your card. Therefore the dealer's card is higher.\n<|im_end|>" }, { "id": "#1488", "title": "Barrel of Wine", "fun": 2.5, "difficulty": 1.83, "author": "gokaran", "desc": "There is a barrel with no lid and some wine in it. \"This barrel of wine is more than half full,\" said Curly. Moe says, \"No it's not. It's less than half full.\" \n\r\nWithout any measuring implements and without removing any wine from the barrel, how can they easily determine who is correct?", "hint": "No hint available.", "answer": "Solution: Tilt the barrel until the wine barely touches the lip of the barrel. If the bottom of the barrel is visible then it is less than half full. If the barrel bottom is still covered by the wine, then it is more than half full.", "category": "Logic", "date": "11/22/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a barrel with no lid and some wine in it. \"This barrel of wine is more than half full,\" said Curly. Moe says, \"No it's not. It's less than half full.\" \n\r\nWithout any measuring implements and without removing any wine from the barrel, how can they easily determine who is correct?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSolution: Tilt the barrel until the wine barely touches the lip of the barrel. If the bottom of the barrel is visible then it is less than half full. If the barrel bottom is still covered by the wine, then it is more than half full.\n<|im_start|>answer\nSolution: Tilt the barrel until the wine barely touches the lip of the barrel. If the bottom of the barrel is visible then it is less than half full. If the barrel bottom is still covered by the wine, then it is more than half full.\n<|im_end|>" }, { "id": "#5095", "title": "Fish Market", "fun": 2.5, "difficulty": 1.03, "author": "peppermintwist", "desc": "Using the listed items, devise a system that will logically determine the missing price.\n\r\nTrout.................................20\r\nSalmon................................19\r\nPlaice................................16\r\nMackerel..............................?", "hint": "Think about the first letter", "answer": "13- The numerical value of the first letter!", "category": "Logic", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the listed items, devise a system that will logically determine the missing price.\n\r\nTrout.................................20\r\nSalmon................................19\r\nPlaice................................16\r\nMackerel..............................?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n13- The numerical value of the first letter!\n<|im_start|>answer\n13- The numerical value of the first letter!\n<|im_end|>" }, { "id": "#3420", "title": "Fast Food Folly", "fun": 2.5, "difficulty": 1.78, "author": "OD-1", "desc": "Bob, Sid, Mary, and Kate went out to lunch and, as it happens with fast food, they messed up the order, and put everything in one bag. There are 2 burgers, 2 fries, 3 salads, and 3 drinks. Now Bob, being a 130 lb runt, ate one of everything. Bob also had 2 more items than Mary. Sid did not eat salad as it gave him gas so the others wouldn't let him have any, but he did drink something and had 1 more item than Mary. Mary was a potato rights advocate and would not eat fries, but had one more item than Kate. Kate, believing that the aspartame in the pop would cause her memory loss, didn't drink anything, and fearing ecoli for poorly processed meat, didn't eat a burger. Nobody ate 2 of anything.\n\r\nSo who ate what?", "hint": "Kate had salad only", "answer": "Bob \r\n1 burger\r\n1 fry\r\n1 salad\r\n1 drink\n\r\nSid \r\n1 burger\r\n1 fry\r\n1 drink\n\r\nMary \r\n1 salad\r\n1 drink\n\r\nKate \r\n1 salad", "category": "Logic", "date": "04/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob, Sid, Mary, and Kate went out to lunch and, as it happens with fast food, they messed up the order, and put everything in one bag. There are 2 burgers, 2 fries, 3 salads, and 3 drinks. Now Bob, being a 130 lb runt, ate one of everything. Bob also had 2 more items than Mary. Sid did not eat salad as it gave him gas so the others wouldn't let him have any, but he did drink something and had 1 more item than Mary. Mary was a potato rights advocate and would not eat fries, but had one more item than Kate. Kate, believing that the aspartame in the pop would cause her memory loss, didn't drink anything, and fearing ecoli for poorly processed meat, didn't eat a burger. Nobody ate 2 of anything.\n\r\nSo who ate what?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob \r\n1 burger\r\n1 fry\r\n1 salad\r\n1 drink\n\r\nSid \r\n1 burger\r\n1 fry\r\n1 drink\n\r\nMary \r\n1 salad\r\n1 drink\n\r\nKate \r\n1 salad\n<|im_start|>answer\nBob \r\n1 burger\r\n1 fry\r\n1 salad\r\n1 drink\n\r\nSid \r\n1 burger\r\n1 fry\r\n1 drink\n\r\nMary \r\n1 salad\r\n1 drink\n\r\nKate \r\n1 salad\n<|im_end|>" }, { "id": "#31601", "title": "The Car Park", "fun": 2.5, "difficulty": 1.09, "author": "Linlou18uk", "desc": "Six people go into a store through the underground car park going to floors 1, 2, 3, 4, 5 and 6. Each person goes to a different floor in the same elevator, which goes up stopping at each floor. Eddie's ride is the longest. Angie gets out before Frankie but after Debbie. Charlie gets out first. Barbie leaves before Debbie, who leaves at the third floor.\n\r\nAt what floor does each person leave?", "hint": "No hint available.", "answer": "Charlie leaves at the 1st floor.\r\nBarbie leaves at the 2nd floor.\r\nDebbie leaves at the 3rd floor.\r\nAngie leaves at the 4th floor.\r\nFrankie leaves at the 5th floor.\r\nEddie leaves at the 6th floor.", "category": "Logic", "date": "07/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix people go into a store through the underground car park going to floors 1, 2, 3, 4, 5 and 6. Each person goes to a different floor in the same elevator, which goes up stopping at each floor. Eddie's ride is the longest. Angie gets out before Frankie but after Debbie. Charlie gets out first. Barbie leaves before Debbie, who leaves at the third floor.\n\r\nAt what floor does each person leave?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCharlie leaves at the 1st floor.\r\nBarbie leaves at the 2nd floor.\r\nDebbie leaves at the 3rd floor.\r\nAngie leaves at the 4th floor.\r\nFrankie leaves at the 5th floor.\r\nEddie leaves at the 6th floor.\n<|im_start|>answer\nCharlie leaves at the 1st floor.\r\nBarbie leaves at the 2nd floor.\r\nDebbie leaves at the 3rd floor.\r\nAngie leaves at the 4th floor.\r\nFrankie leaves at the 5th floor.\r\nEddie leaves at the 6th floor.\n<|im_end|>" }, { "id": "#28723", "title": "Opposites 10", "fun": 2.5, "difficulty": 2.2, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n* stands for K, U, O, G, or V\r\n$ stands for E, G, M, T, or J\r\n) stands for W, H, P, E, or Y\r\n- stands for A, N, I, C, or B\n\r\nThe four letter code word, $-*), can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Give and Take.", "category": "Logic", "date": "02/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n* stands for K, U, O, G, or V\r\n$ stands for E, G, M, T, or J\r\n) stands for W, H, P, E, or Y\r\n- stands for A, N, I, C, or B\n\r\nThe four letter code word, $-*), can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGive and Take.\n<|im_start|>answer\nGive and Take.\n<|im_end|>" }, { "id": "#17475", "title": "Shoe Factory", "fun": 2.5, "difficulty": 1.45, "author": "VaLeRiY", "desc": "One company had two factories, in different parts of the country, that were making the same style of shoes. In both factories, workers were stealing shoes. \r\nHow, without using any security, could that company stop the stealing?", "hint": "No hint available.", "answer": "Make one factory make the left shoe, and the other make the right shoe.", "category": "Logic", "date": "04/25/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne company had two factories, in different parts of the country, that were making the same style of shoes. In both factories, workers were stealing shoes. \r\nHow, without using any security, could that company stop the stealing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMake one factory make the left shoe, and the other make the right shoe.\n<|im_start|>answer\nMake one factory make the left shoe, and the other make the right shoe.\n<|im_end|>" }, { "id": "#27468", "title": "How Many Pages?", "fun": 2.5, "difficulty": 1.74, "author": "Tammy93", "desc": "Josh is writing a book. He starts on page 1. When he finished, he used a total of 228 digits. How many pages does he have?", "hint": "No hint available.", "answer": "112 pages.", "category": "Math", "date": "12/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJosh is writing a book. He starts on page 1. When he finished, he used a total of 228 digits. How many pages does he have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n112 pages.\n<|im_start|>answer\n112 pages.\n<|im_end|>" }, { "id": "#44421", "title": "Book Club", "fun": 2.5, "difficulty": 1.44, "author": "whsprec", "desc": "Five ladies - Lopez, Moore, Ruiz, Sullivan, and Gardner - took turns hosting book club. They each hosted once during the first five months of the year and once the last 5 months of the year. They took June and July off. From the clues below, determine the two months each lady hosted book club.\n\r\n1- Mrs. Moore hosted the first time before Mrs. Gardner, who was before Mrs. Sullivan; for the second hosting, the order was reversed.\r\n2- The lady who hosted in March also hosted in September.\r\n3- Mrs. Lopez did not host in April or March.\r\n4- Neither Mrs. Lopez nor the lady who hosted in January hosted again in August or December.\r\n5- Mrs. Ruiz hosted the second time before Mrs. Moore but after Mrs. Lopez.", "hint": "No hint available.", "answer": "Ruiz hosted in January and November.\r\nMoore hosted in February and December.\r\nGardner hosted in March and September.\r\nSullivan hosed in April and August.\r\nLopez hosted in May and October.", "category": "Logic-Grid", "date": "05/06/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive ladies - Lopez, Moore, Ruiz, Sullivan, and Gardner - took turns hosting book club. They each hosted once during the first five months of the year and once the last 5 months of the year. They took June and July off. From the clues below, determine the two months each lady hosted book club.\n\r\n1- Mrs. Moore hosted the first time before Mrs. Gardner, who was before Mrs. Sullivan; for the second hosting, the order was reversed.\r\n2- The lady who hosted in March also hosted in September.\r\n3- Mrs. Lopez did not host in April or March.\r\n4- Neither Mrs. Lopez nor the lady who hosted in January hosted again in August or December.\r\n5- Mrs. Ruiz hosted the second time before Mrs. Moore but after Mrs. Lopez.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRuiz hosted in January and November.\r\nMoore hosted in February and December.\r\nGardner hosted in March and September.\r\nSullivan hosed in April and August.\r\nLopez hosted in May and October.\n<|im_start|>answer\nRuiz hosted in January and November.\r\nMoore hosted in February and December.\r\nGardner hosted in March and September.\r\nSullivan hosed in April and August.\r\nLopez hosted in May and October.\n<|im_end|>" }, { "id": "#9060", "title": "Getting Across", "fun": 2.5, "difficulty": 0.92, "author": "justin", "desc": "Three people were trying to cross a river. One of them weighs 100 pounds and the other two weigh 50 pounds each. The only way to get across the river is to take a boat, but the boat can only carry 100 pounds at a time. How did all 3 of them get across the river using the boat?", "hint": "No hint available.", "answer": "First the two 50-pound men got on the boat and went across. Then one of the 50-pound men got off the boat and the other man went back. He got off and the 100-pound man got on and went across. He then went ashore and let the 50-pound man onto the boat. He went back to get the last man and all ended up safely on the opposite bank.", "category": "Logic", "date": "12/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people were trying to cross a river. One of them weighs 100 pounds and the other two weigh 50 pounds each. The only way to get across the river is to take a boat, but the boat can only carry 100 pounds at a time. How did all 3 of them get across the river using the boat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst the two 50-pound men got on the boat and went across. Then one of the 50-pound men got off the boat and the other man went back. He got off and the 100-pound man got on and went across. He then went ashore and let the 50-pound man onto the boat. He went back to get the last man and all ended up safely on the opposite bank.\n<|im_start|>answer\nFirst the two 50-pound men got on the boat and went across. Then one of the 50-pound men got off the boat and the other man went back. He got off and the 100-pound man got on and went across. He then went ashore and let the 50-pound man onto the boat. He went back to get the last man and all ended up safely on the opposite bank.\n<|im_end|>" }, { "id": "#32497", "title": "Arnold and Carlos: Part 2", "fun": 2.5, "difficulty": 2.7600000000000002, "author": "HiImDavid", "desc": "Arnold and Carlos love math puzzles. They are constantly making them up for each other to solve. One day, Carlos presents his friend Arnold with a problem. This problem has six clues. Here is the problem Carlos gave:\n\r\n--------------------------------------------\r\nI am thinking of a mystery number.\n\r\n1. The mystery number is a 3-digit prime number with digits ABC.\r\n2. Two 2-digit prime numbers occur in the mystery number (AB and BC).\r\n3. A, B, and C are all distinct digits.\r\n4. The mystery number does not contain a 9.\r\n5. If A, B, and C are re-arranged from greatest to least, a 3-digit prime number is formed.\r\n6. If A, B, and C are re-arranged from least to greatest, a 3-digit prime number is formed.\n\r\nWhat is the mystery number?\"\r\n----------------------------------------\n\r\nCan you help Arnold solve Carlos's problem?", "hint": "Make a list and organize your possibilities. It will lead down to one answer.\n\r\nThe 3-digit prime numbers are:\r\n101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, and 997.", "answer": "Answer: 617.\n\r\nClue #1- \"The mystery number is a 3-digit prime number with digits ABC.\" The 3-digit prime numbers are: 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, and 997\n\r\nAfter Clue #1- we have 143 possibilities.\n\r\nClue #2- \"Two 2-digit prime numbers occur in the mystery number (AB and BC).\" The two digit prime numbers are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97. Since the two prime numbers are AB and BC, they share one digit- B. The only combinations for ABC such that AB and BC are prime numbers is: 113, 117, 119, 131, 137, 171, 173, 179, 197, 231, 237, 297, 311, 313, 317, 319, 371, 373, 379, 411, 413, 417, 419, 431, 437, 471, 473, 479, 531, 537, 597, 611, 613, 617, 619, 671, 673, 679, 711, 713, 717, 719, 731, 737, 797, 831, 837, 897, 971, 973, and 979.Out of these 51 numbers, only 113, 131, 137, 173, 179, 197, 311, 313, 317, 373, 379, 419, 431, 479, 613, 617, 619, 673, 719, 797, and 971 are prime.\n\r\nAfter Clue #2 we have 21 possibilities: 113, 131, 137, 173, 179, 197, 311, 313, 317, 373, 379, 419, 431, 479, 613, 617, 619, 673, 719, 797, and 971.\n\r\nClue #3- \"A, B, and C are all distinct digits.\" Out of our 21 possibilities, 113, 131, 311, 313, 373, and 797 do not have distinct digits.\n\r\nAfter Clue #3, we have 15 possibilities: 137, 173, 179, 197, 317, 379, 419, 431, 479, 613, 617, 619, 673, 719, and 971.\n\r\nClue #4- \"The mystery number does not contain a 9.\"179, 197, 379, 419, 479, 619, 719, and 971 all contain a 9.\n\r\nAfter Clue #4, we have 7 possibilities: 137, 173, 317, 431, 613, 617, and 673.\n\r\nClue #5- \"If A, B, and C are re-arranged from greatest to least, a 3-digit prime number is formed.\" With our 7 possibilities (137, 173, 317, 431, 613, 617, and 673) we arrange their digits from greatest to least getting 731, 731, 731, 431, 631, 761, and 763 respectively. Of these new 7 numbers, only 431 (from 431), 631 (from 613), and 761 (from 617) are prime.\n\r\nAfter Clue #5, we have 3 possibilities: 431, 613, and 617.\n\r\nClue #6- \"If A, B, and C are re-arranged from least to greatest, a 3-digit prime number is formed.\" With our 3 possibilities (431, 613, and 617), we arrange their digits from least to greatest to get 134, 136, and 167 respectively. 134 (from 431) and 136 (from 631) are non-prime. 167 (from 617) is prime.\n\r\nAfter Clue #6, we have one possibility: 617.\n\r\n617 is the mystery number.", "category": "Math", "date": "08/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArnold and Carlos love math puzzles. They are constantly making them up for each other to solve. One day, Carlos presents his friend Arnold with a problem. This problem has six clues. Here is the problem Carlos gave:\n\r\n--------------------------------------------\r\nI am thinking of a mystery number.\n\r\n1. The mystery number is a 3-digit prime number with digits ABC.\r\n2. Two 2-digit prime numbers occur in the mystery number (AB and BC).\r\n3. A, B, and C are all distinct digits.\r\n4. The mystery number does not contain a 9.\r\n5. If A, B, and C are re-arranged from greatest to least, a 3-digit prime number is formed.\r\n6. If A, B, and C are re-arranged from least to greatest, a 3-digit prime number is formed.\n\r\nWhat is the mystery number?\"\r\n----------------------------------------\n\r\nCan you help Arnold solve Carlos's problem?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: 617.\n\r\nClue #1- \"The mystery number is a 3-digit prime number with digits ABC.\" The 3-digit prime numbers are: 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, and 997\n\r\nAfter Clue #1- we have 143 possibilities.\n\r\nClue #2- \"Two 2-digit prime numbers occur in the mystery number (AB and BC).\" The two digit prime numbers are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97. Since the two prime numbers are AB and BC, they share one digit- B. The only combinations for ABC such that AB and BC are prime numbers is: 113, 117, 119, 131, 137, 171, 173, 179, 197, 231, 237, 297, 311, 313, 317, 319, 371, 373, 379, 411, 413, 417, 419, 431, 437, 471, 473, 479, 531, 537, 597, 611, 613, 617, 619, 671, 673, 679, 711, 713, 717, 719, 731, 737, 797, 831, 837, 897, 971, 973, and 979.Out of these 51 numbers, only 113, 131, 137, 173, 179, 197, 311, 313, 317, 373, 379, 419, 431, 479, 613, 617, 619, 673, 719, 797, and 971 are prime.\n\r\nAfter Clue #2 we have 21 possibilities: 113, 131, 137, 173, 179, 197, 311, 313, 317, 373, 379, 419, 431, 479, 613, 617, 619, 673, 719, 797, and 971.\n\r\nClue #3- \"A, B, and C are all distinct digits.\" Out of our 21 possibilities, 113, 131, 311, 313, 373, and 797 do not have distinct digits.\n\r\nAfter Clue #3, we have 15 possibilities: 137, 173, 179, 197, 317, 379, 419, 431, 479, 613, 617, 619, 673, 719, and 971.\n\r\nClue #4- \"The mystery number does not contain a 9.\"179, 197, 379, 419, 479, 619, 719, and 971 all contain a 9.\n\r\nAfter Clue #4, we have 7 possibilities: 137, 173, 317, 431, 613, 617, and 673.\n\r\nClue #5- \"If A, B, and C are re-arranged from greatest to least, a 3-digit prime number is formed.\" With our 7 possibilities (137, 173, 317, 431, 613, 617, and 673) we arrange their digits from greatest to least getting 731, 731, 731, 431, 631, 761, and 763 respectively. Of these new 7 numbers, only 431 (from 431), 631 (from 613), and 761 (from 617) are prime.\n\r\nAfter Clue #5, we have 3 possibilities: 431, 613, and 617.\n\r\nClue #6- \"If A, B, and C are re-arranged from least to greatest, a 3-digit prime number is formed.\" With our 3 possibilities (431, 613, and 617), we arrange their digits from least to greatest to get 134, 136, and 167 respectively. 134 (from 431) and 136 (from 631) are non-prime. 167 (from 617) is prime.\n\r\nAfter Clue #6, we have one possibility: 617.\n\r\n617 is the mystery number.\n<|im_start|>answer\nAnswer: 617.\n\r\nClue #1- \"The mystery number is a 3-digit prime number with digits ABC.\" The 3-digit prime numbers are: 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, and 997\n\r\nAfter Clue #1- we have 143 possibilities.\n\r\nClue #2- \"Two 2-digit prime numbers occur in the mystery number (AB and BC).\" The two digit prime numbers are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97. Since the two prime numbers are AB and BC, they share one digit- B. The only combinations for ABC such that AB and BC are prime numbers is: 113, 117, 119, 131, 137, 171, 173, 179, 197, 231, 237, 297, 311, 313, 317, 319, 371, 373, 379, 411, 413, 417, 419, 431, 437, 471, 473, 479, 531, 537, 597, 611, 613, 617, 619, 671, 673, 679, 711, 713, 717, 719, 731, 737, 797, 831, 837, 897, 971, 973, and 979.Out of these 51 numbers, only 113, 131, 137, 173, 179, 197, 311, 313, 317, 373, 379, 419, 431, 479, 613, 617, 619, 673, 719, 797, and 971 are prime.\n\r\nAfter Clue #2 we have 21 possibilities: 113, 131, 137, 173, 179, 197, 311, 313, 317, 373, 379, 419, 431, 479, 613, 617, 619, 673, 719, 797, and 971.\n\r\nClue #3- \"A, B, and C are all distinct digits.\" Out of our 21 possibilities, 113, 131, 311, 313, 373, and 797 do not have distinct digits.\n\r\nAfter Clue #3, we have 15 possibilities: 137, 173, 179, 197, 317, 379, 419, 431, 479, 613, 617, 619, 673, 719, and 971.\n\r\nClue #4- \"The mystery number does not contain a 9.\"179, 197, 379, 419, 479, 619, 719, and 971 all contain a 9.\n\r\nAfter Clue #4, we have 7 possibilities: 137, 173, 317, 431, 613, 617, and 673.\n\r\nClue #5- \"If A, B, and C are re-arranged from greatest to least, a 3-digit prime number is formed.\" With our 7 possibilities (137, 173, 317, 431, 613, 617, and 673) we arrange their digits from greatest to least getting 731, 731, 731, 431, 631, 761, and 763 respectively. Of these new 7 numbers, only 431 (from 431), 631 (from 613), and 761 (from 617) are prime.\n\r\nAfter Clue #5, we have 3 possibilities: 431, 613, and 617.\n\r\nClue #6- \"If A, B, and C are re-arranged from least to greatest, a 3-digit prime number is formed.\" With our 3 possibilities (431, 613, and 617), we arrange their digits from least to greatest to get 134, 136, and 167 respectively. 134 (from 431) and 136 (from 631) are non-prime. 167 (from 617) is prime.\n\r\nAfter Clue #6, we have one possibility: 617.\n\r\n617 is the mystery number.\n<|im_end|>" }, { "id": "#9643", "title": "A Flowery Fiasco", "fun": 2.5, "difficulty": 1.81, "author": "saxophonechick13", "desc": "There was a very young princess who was very beautiful. Her father thought it was time for her to marry. He held a series of competitions. All of the men dropped out, but one, a peasant. The King was very unhappy about this and he wanted to make sure the peasant could not marry his daughter. He placed 100 roses in a room. Only one rose was from their garden. The rest were fakes. They all looked and smelled the same. It was impossible to tell them apart. The peasant was very wise though, and picked out the correct rose. How did he do it?", "hint": "He didn't do it he had help from an animal.", "answer": "He let a bee fly in through the window and the bee went to the only flower with pollen.", "category": "Logic", "date": "01/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a very young princess who was very beautiful. Her father thought it was time for her to marry. He held a series of competitions. All of the men dropped out, but one, a peasant. The King was very unhappy about this and he wanted to make sure the peasant could not marry his daughter. He placed 100 roses in a room. Only one rose was from their garden. The rest were fakes. They all looked and smelled the same. It was impossible to tell them apart. The peasant was very wise though, and picked out the correct rose. How did he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe let a bee fly in through the window and the bee went to the only flower with pollen.\n<|im_start|>answer\nHe let a bee fly in through the window and the bee went to the only flower with pollen.\n<|im_end|>" }, { "id": "#42117", "title": "Ahmes's Papyrus", "fun": 2.5, "difficulty": 2.59, "author": "rush2", "desc": "About 2000 B.C. there lived Ahmes, a royal secretary and mathematician of the Pharaoh Amenemhat III. In 1853 an Englishman Rhind found one of Ahmes's papyruses near the temple of Ramses II in Thebes. The papyrus is a rectangle 33 cm wide and about 5 m long. There is the following math brain teaser on it (besides others).\n\r\n100 measures of corn must be divided among 5 workers, so that the second worker gets as many measures more than the first worker, as the third gets more than the second, the fourth more than the third and the fifth more than the fourth. The first two workers shall get seven times less measures of corn than the three others.\r\nHow many measures of corn shall each worker get?", "hint": "No hint available.", "answer": "2 equations give a clear answer to the given question:\r\n5w + 10d = 100\r\n7*(2w + d) = 3w + 9d\r\nWhere w is amount of corn for the first worker, d is the difference (amount of corn) between two consecutive workers. So this is the solution:\r\n1st worker = 10/6 measures of corn\r\n2nd worker = 65/6 measures of corn\r\n3rd worker = 120/6 (20) measures of corn\r\n4th worker = 175/6 measures of corn\r\n5th worker = 230/6 measures of corn", "category": "Math", "date": "06/01/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbout 2000 B.C. there lived Ahmes, a royal secretary and mathematician of the Pharaoh Amenemhat III. In 1853 an Englishman Rhind found one of Ahmes's papyruses near the temple of Ramses II in Thebes. The papyrus is a rectangle 33 cm wide and about 5 m long. There is the following math brain teaser on it (besides others).\n\r\n100 measures of corn must be divided among 5 workers, so that the second worker gets as many measures more than the first worker, as the third gets more than the second, the fourth more than the third and the fifth more than the fourth. The first two workers shall get seven times less measures of corn than the three others.\r\nHow many measures of corn shall each worker get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 equations give a clear answer to the given question:\r\n5w + 10d = 100\r\n7*(2w + d) = 3w + 9d\r\nWhere w is amount of corn for the first worker, d is the difference (amount of corn) between two consecutive workers. So this is the solution:\r\n1st worker = 10/6 measures of corn\r\n2nd worker = 65/6 measures of corn\r\n3rd worker = 120/6 (20) measures of corn\r\n4th worker = 175/6 measures of corn\r\n5th worker = 230/6 measures of corn\n<|im_start|>answer\n2 equations give a clear answer to the given question:\r\n5w + 10d = 100\r\n7*(2w + d) = 3w + 9d\r\nWhere w is amount of corn for the first worker, d is the difference (amount of corn) between two consecutive workers. So this is the solution:\r\n1st worker = 10/6 measures of corn\r\n2nd worker = 65/6 measures of corn\r\n3rd worker = 120/6 (20) measures of corn\r\n4th worker = 175/6 measures of corn\r\n5th worker = 230/6 measures of corn\n<|im_end|>" }, { "id": "#7476", "title": "Yummie Gummies", "fun": 2.5, "difficulty": 2.42, "author": "hprulz", "desc": "Mikey was looking through his drawer where he was saving all of his packages of gummy fruit candy. He found a dozen packages of candy altogether. He kept a chart listing how many pieces of candy there were in each package and figured out that he had 81 pieces of candy in all. His chart listed the color of each package, but not the names of the candy. Each kind of candy comes in only one color. The chart looked like this: \n\n\r\nGreen packages 2 pieces per package \r\nYellow packages 5 pieces per package \r\nBrown packages 9 pieces per package \r\nGray packages 12 pieces per package \n\r\nEach Zing Zong is so big that these packages contain the fewest candies. There are an equal number of Zing Zong packages as Gummy Ape packages. There are 2 dozen pieces of Egg Smasher candies, and a dozen more pieces of Power Busters than Egg Smashers. \n\r\nWhich candy is in each color package, and how many packages of each kind does Mikey have?", "hint": "No hint available.", "answer": "Looking at the column that shows the number of pieces per package, you can see that 12 is the only number left in this column that is a factor of 24, so Egg Smashers belong in the gray packages, and there must be 24 ÷ 12 = 2 gray packages. \n\r\nLooking at the same column, you can see that 9 is a factor of 36 but 5 is not, so Power Busters come in the brown packages, and there must be 36 ÷ 9 = 4 brown packages. \n\r\nYou now know that Gummy Apes come in the yellow packages. You also know that there are 12 - 4 - 2 = 6 packages to be accounted for, of which 3 are green and 3 are yellow. So, there must be a total of 3 x 2 = 6 pieces of Zing Zong and 3 x 5 = 15 Gummy Ape candies. \n\r\nCheck the total pieces of candy: 24 + 36 + 6 + 15 = 81.", "category": "Math", "date": "09/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMikey was looking through his drawer where he was saving all of his packages of gummy fruit candy. He found a dozen packages of candy altogether. He kept a chart listing how many pieces of candy there were in each package and figured out that he had 81 pieces of candy in all. His chart listed the color of each package, but not the names of the candy. Each kind of candy comes in only one color. The chart looked like this: \n\n\r\nGreen packages 2 pieces per package \r\nYellow packages 5 pieces per package \r\nBrown packages 9 pieces per package \r\nGray packages 12 pieces per package \n\r\nEach Zing Zong is so big that these packages contain the fewest candies. There are an equal number of Zing Zong packages as Gummy Ape packages. There are 2 dozen pieces of Egg Smasher candies, and a dozen more pieces of Power Busters than Egg Smashers. \n\r\nWhich candy is in each color package, and how many packages of each kind does Mikey have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLooking at the column that shows the number of pieces per package, you can see that 12 is the only number left in this column that is a factor of 24, so Egg Smashers belong in the gray packages, and there must be 24 ÷ 12 = 2 gray packages. \n\r\nLooking at the same column, you can see that 9 is a factor of 36 but 5 is not, so Power Busters come in the brown packages, and there must be 36 ÷ 9 = 4 brown packages. \n\r\nYou now know that Gummy Apes come in the yellow packages. You also know that there are 12 - 4 - 2 = 6 packages to be accounted for, of which 3 are green and 3 are yellow. So, there must be a total of 3 x 2 = 6 pieces of Zing Zong and 3 x 5 = 15 Gummy Ape candies. \n\r\nCheck the total pieces of candy: 24 + 36 + 6 + 15 = 81.\n<|im_start|>answer\nLooking at the column that shows the number of pieces per package, you can see that 12 is the only number left in this column that is a factor of 24, so Egg Smashers belong in the gray packages, and there must be 24 ÷ 12 = 2 gray packages. \n\r\nLooking at the same column, you can see that 9 is a factor of 36 but 5 is not, so Power Busters come in the brown packages, and there must be 36 ÷ 9 = 4 brown packages. \n\r\nYou now know that Gummy Apes come in the yellow packages. You also know that there are 12 - 4 - 2 = 6 packages to be accounted for, of which 3 are green and 3 are yellow. So, there must be a total of 3 x 2 = 6 pieces of Zing Zong and 3 x 5 = 15 Gummy Ape candies. \n\r\nCheck the total pieces of candy: 24 + 36 + 6 + 15 = 81.\n<|im_end|>" }, { "id": "#43689", "title": "Eliza Pseudonym and the Quintuple Feature", "fun": 2.5, "difficulty": 2.31, "author": "mathgrant", "desc": "Eliza Pseudonym and four of her friends recently went to the local movie theatre to watch five new movies together. After each movie, the five friends discussed what they thought, and rated each movie on a scale of one to five stars (with one star being the worst, and five being the best). To their astonishment, not only did no two movies get the same rating from the same moviegoer, but no two of the moviegoers gave the same movie the same rating! From the clues below, determine what rating each friend gave each movie. (Note: There were no fractional star ratings.)\n\r\n1. Delilah's least favorite film was \"Nanos: The MP3 Players of Fate\", which wasn't Barbra's favorite film.\r\n2. The woman who liked \"Maybe Geniuses\" the least didn't give \"Nanos: The MP3 Players of Fate\" a two-star rating.\r\n3. \"You Got Curved\" was poorly received by Anna (who gave it a one-star rating) and Carla (who gave it a two-star rating).\r\n4. Anna gave \"Maybe Geniuses\" precisely one more star in its rating than she did for \"Nanos: The MP3 Players of Fate\".\r\n5. Barbra gave \"Giggly\" exactly twice as many stars as did the viewer whose least favorite film was \"Shoegirls\".\r\n6. Carla didn't give \"Maybe Geniuses\" a four-star rating.", "hint": "No hint available.", "answer": "Each woman's ratings, from least favorite (*) to favorite (*****):\n\r\nAnna: You Got Curved (*), Nanos: The MP3 Players of Fate (**), Maybe Geniuses (***), Shoegirls (****), Giggly (*****)\r\nBarbra: Maybe Geniuses (*), Shoegirls (**), Nanos: The MP3 Players of Fate (***), Giggly (****), You Got Curved (*****)\r\nCarla: Giggly (*), You Got Curved (**), Shoegirls (***), Nanos: The MP3 Players of Fate (****), Maybe Geniuses (*****)\r\nDelilah: Nanos: The MP3 Players of Fate (*), Maybe Geniuses (**), Giggly (***), You Got Curved (****), Shoegirls (*****)\r\nEliza: Shoegirls (*), Giggly (**), You Got Curved (***), Maybe Geniuses (****), Nanos: The MP3 Players of Fate (*****)", "category": "Logic", "date": "12/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEliza Pseudonym and four of her friends recently went to the local movie theatre to watch five new movies together. After each movie, the five friends discussed what they thought, and rated each movie on a scale of one to five stars (with one star being the worst, and five being the best). To their astonishment, not only did no two movies get the same rating from the same moviegoer, but no two of the moviegoers gave the same movie the same rating! From the clues below, determine what rating each friend gave each movie. (Note: There were no fractional star ratings.)\n\r\n1. Delilah's least favorite film was \"Nanos: The MP3 Players of Fate\", which wasn't Barbra's favorite film.\r\n2. The woman who liked \"Maybe Geniuses\" the least didn't give \"Nanos: The MP3 Players of Fate\" a two-star rating.\r\n3. \"You Got Curved\" was poorly received by Anna (who gave it a one-star rating) and Carla (who gave it a two-star rating).\r\n4. Anna gave \"Maybe Geniuses\" precisely one more star in its rating than she did for \"Nanos: The MP3 Players of Fate\".\r\n5. Barbra gave \"Giggly\" exactly twice as many stars as did the viewer whose least favorite film was \"Shoegirls\".\r\n6. Carla didn't give \"Maybe Geniuses\" a four-star rating.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach woman's ratings, from least favorite (*) to favorite (*****):\n\r\nAnna: You Got Curved (*), Nanos: The MP3 Players of Fate (**), Maybe Geniuses (***), Shoegirls (****), Giggly (*****)\r\nBarbra: Maybe Geniuses (*), Shoegirls (**), Nanos: The MP3 Players of Fate (***), Giggly (****), You Got Curved (*****)\r\nCarla: Giggly (*), You Got Curved (**), Shoegirls (***), Nanos: The MP3 Players of Fate (****), Maybe Geniuses (*****)\r\nDelilah: Nanos: The MP3 Players of Fate (*), Maybe Geniuses (**), Giggly (***), You Got Curved (****), Shoegirls (*****)\r\nEliza: Shoegirls (*), Giggly (**), You Got Curved (***), Maybe Geniuses (****), Nanos: The MP3 Players of Fate (*****)\n<|im_start|>answer\nEach woman's ratings, from least favorite (*) to favorite (*****):\n\r\nAnna: You Got Curved (*), Nanos: The MP3 Players of Fate (**), Maybe Geniuses (***), Shoegirls (****), Giggly (*****)\r\nBarbra: Maybe Geniuses (*), Shoegirls (**), Nanos: The MP3 Players of Fate (***), Giggly (****), You Got Curved (*****)\r\nCarla: Giggly (*), You Got Curved (**), Shoegirls (***), Nanos: The MP3 Players of Fate (****), Maybe Geniuses (*****)\r\nDelilah: Nanos: The MP3 Players of Fate (*), Maybe Geniuses (**), Giggly (***), You Got Curved (****), Shoegirls (*****)\r\nEliza: Shoegirls (*), Giggly (**), You Got Curved (***), Maybe Geniuses (****), Nanos: The MP3 Players of Fate (*****)\n<|im_end|>" }, { "id": "#26692", "title": "Test Scores", "fun": 2.5, "difficulty": 1.18, "author": "hamburger", "desc": "Bob shows his test score to John, Marty, and Shana, but they keep theirs hidden. John thinks, \"At least two of us have the same score.\" Marty thinks, \"I didn't get the lowest score.\" Shana thinks, \"I didn't get the highest score.\" In what order did John, Marty, and Shana score from lowest to highest?", "hint": "No hint available.", "answer": "Lowest: Shana\r\nMiddle: John\r\nHighest: Marty", "category": "Logic", "date": "11/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob shows his test score to John, Marty, and Shana, but they keep theirs hidden. John thinks, \"At least two of us have the same score.\" Marty thinks, \"I didn't get the lowest score.\" Shana thinks, \"I didn't get the highest score.\" In what order did John, Marty, and Shana score from lowest to highest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLowest: Shana\r\nMiddle: John\r\nHighest: Marty\n<|im_start|>answer\nLowest: Shana\r\nMiddle: John\r\nHighest: Marty\n<|im_end|>" }, { "id": "#1073", "title": "No One Dollar Bills", "fun": 2.5, "difficulty": 1.53, "author": "Michelle", "desc": "How could you give someone $63 using six bills without using one dollar bills?", "hint": "No hint available.", "answer": "1- $50 bill\r\n1- $5 bill\r\n4- $2 bills", "category": "Math", "date": "10/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow could you give someone $63 using six bills without using one dollar bills?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1- $50 bill\r\n1- $5 bill\r\n4- $2 bills\n<|im_start|>answer\n1- $50 bill\r\n1- $5 bill\r\n4- $2 bills\n<|im_end|>" }, { "id": "#4722", "title": "Father's Son", "fun": 2.5, "difficulty": 1.18, "author": "librashorty", "desc": "Who is your father's only son's brother's uncle's wife's daughter's brother's father's son?", "hint": "No hint available.", "answer": "No-one, an only son cannot have a brother, although they may have a sister.", "category": "Logic", "date": "06/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWho is your father's only son's brother's uncle's wife's daughter's brother's father's son?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo-one, an only son cannot have a brother, although they may have a sister.\n<|im_start|>answer\nNo-one, an only son cannot have a brother, although they may have a sister.\n<|im_end|>" }, { "id": "#27422", "title": "Captain John's Journey (part 3)", "fun": 2.5, "difficulty": 2.28, "author": "cdrock", "desc": "After finding a lost map, escaping a city, and navigating around rocks, Captain John has ended up on the distant island that holds a sacred treasure.\n\r\nNoticing there are mountains in certain places of the island, Captain John is once again in a situation. He must find a path to the X that marks the spot where the treasure is without passing over a mountain, as he can't get over one.\n\r\nWith what Captain John knows about the island, can you figure out where the nine things in a 3-by-3 grid go,(Crew, X (treasure), 3 mountains, and 4 trails) and go in the right path to the X without passing over a mountain?\n\r\n1. The second column is the only column or row in which two mountains are next to each other.\n\r\n2. The crew only walks diagonally one time on the trail.\n\r\n3. The X does not have any part of the trail in its row.\n\r\n4. The crew is above the mountain in their column.\n\r\n5. At least one of the mountains are only next to a path immediately vertical and horizontal to it.", "hint": "No hint available.", "answer": "The items on the island go as followed:\n\r\nCrew l Moun. l X\r\nTrail l Moun. l Trail\r\nMoun. l Trail l Trail\n\r\nThe trail that Captain John and his crew should follow, is as followed starting at 1 and ending at 6.\n\r\n1 l X l 6\r\n2 l X l 5\r\nX l 3 l 4", "category": "Logic", "date": "12/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter finding a lost map, escaping a city, and navigating around rocks, Captain John has ended up on the distant island that holds a sacred treasure.\n\r\nNoticing there are mountains in certain places of the island, Captain John is once again in a situation. He must find a path to the X that marks the spot where the treasure is without passing over a mountain, as he can't get over one.\n\r\nWith what Captain John knows about the island, can you figure out where the nine things in a 3-by-3 grid go,(Crew, X (treasure), 3 mountains, and 4 trails) and go in the right path to the X without passing over a mountain?\n\r\n1. The second column is the only column or row in which two mountains are next to each other.\n\r\n2. The crew only walks diagonally one time on the trail.\n\r\n3. The X does not have any part of the trail in its row.\n\r\n4. The crew is above the mountain in their column.\n\r\n5. At least one of the mountains are only next to a path immediately vertical and horizontal to it.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe items on the island go as followed:\n\r\nCrew l Moun. l X\r\nTrail l Moun. l Trail\r\nMoun. l Trail l Trail\n\r\nThe trail that Captain John and his crew should follow, is as followed starting at 1 and ending at 6.\n\r\n1 l X l 6\r\n2 l X l 5\r\nX l 3 l 4\n<|im_start|>answer\nThe items on the island go as followed:\n\r\nCrew l Moun. l X\r\nTrail l Moun. l Trail\r\nMoun. l Trail l Trail\n\r\nThe trail that Captain John and his crew should follow, is as followed starting at 1 and ending at 6.\n\r\n1 l X l 6\r\n2 l X l 5\r\nX l 3 l 4\n<|im_end|>" }, { "id": "#21156", "title": "Continents", "fun": 2.49, "difficulty": 0.98, "author": "Braingirl", "desc": "What's similar about the names of these continents?\n\r\nAsia\r\nAfrica\r\nAustralia\r\nAntarctica\r\nEurope", "hint": "No hint available.", "answer": "They all start with the same letter that they end with.", "category": "Logic", "date": "02/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat's similar about the names of these continents?\n\r\nAsia\r\nAfrica\r\nAustralia\r\nAntarctica\r\nEurope\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey all start with the same letter that they end with.\n<|im_start|>answer\nThey all start with the same letter that they end with.\n<|im_end|>" }, { "id": "#7266", "title": "Couriers", "fun": 2.49, "difficulty": 2.09, "author": "warrior", "desc": "A priest sent a courier from Rome to Venice to reach Venice in 7 days. At the same time, the Mayor of Venice sent a courier to Rome to reach Rome in 9 days. The distance was 250 miles. In how many days will they meet?", "hint": "The speed of the couriers are 250/7 and 250/9", "answer": "The speed of the couriers are 250/7 and 250/9, so their approach speed was \r\n250(1/7 + 1/9) = 250 * 16/63 and they will meet in \r\n63/16 = 3.94 days.", "category": "Math", "date": "09/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA priest sent a courier from Rome to Venice to reach Venice in 7 days. At the same time, the Mayor of Venice sent a courier to Rome to reach Rome in 9 days. The distance was 250 miles. In how many days will they meet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe speed of the couriers are 250/7 and 250/9, so their approach speed was \r\n250(1/7 + 1/9) = 250 * 16/63 and they will meet in \r\n63/16 = 3.94 days.\n<|im_start|>answer\nThe speed of the couriers are 250/7 and 250/9, so their approach speed was \r\n250(1/7 + 1/9) = 250 * 16/63 and they will meet in \r\n63/16 = 3.94 days.\n<|im_end|>" }, { "id": "#40085", "title": "Pencil Patterns", "fun": 2.49, "difficulty": 2.0, "author": "icestar12", "desc": "Cathy, Deena, Jeff, Pete, and Sara are collecting and trading pencils. When they began, each person had 5 pencils of the same pattern. Each person's pencils were a different pattern from everyone else's pattern. Anyone who got a pencil in a trade kept that pencil. This is what happened:\n\r\nJeff began with 5 cartoon pencils and traded pencils with Pete, Cathy, and Deena. \r\nSara began with 5 solid colored pencils, including 3 solid orange and 2 solid green. She traded 1 orange pencil with each other girl and 1 green pencil with Pete. \r\nCathy had 5 pencils illustrated with horses. They were her favorite, so she only traded with Jeff and Sara, and kept the rest of her pencils. \r\nPete exchanged 1 of his striped pencils for a polka-dot pencil. \r\nWhat combination of pencils does each person have at the end of the trades? Include the color if the information is given.", "hint": "No hint available.", "answer": "After trading, each person has the following pencils:\n\r\nJeff: 2 cartoon character, 1 striped, 1 horse, and 1 polka dot \r\nPete: 1 cartoon character, 1 solid green, 1 polka-dot, and 2 striped \r\nCathy: 1 cartoon character, 1 solid orange, and 3 horse \r\nDeena: 1 cartoon character, 1 solid orange, 1 striped, and 2 polka-dot \r\nSara: 1 solid orange, 1 solid green, 1 striped, 1 polka-dot, and 1 horse", "category": "Logic", "date": "01/16/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCathy, Deena, Jeff, Pete, and Sara are collecting and trading pencils. When they began, each person had 5 pencils of the same pattern. Each person's pencils were a different pattern from everyone else's pattern. Anyone who got a pencil in a trade kept that pencil. This is what happened:\n\r\nJeff began with 5 cartoon pencils and traded pencils with Pete, Cathy, and Deena. \r\nSara began with 5 solid colored pencils, including 3 solid orange and 2 solid green. She traded 1 orange pencil with each other girl and 1 green pencil with Pete. \r\nCathy had 5 pencils illustrated with horses. They were her favorite, so she only traded with Jeff and Sara, and kept the rest of her pencils. \r\nPete exchanged 1 of his striped pencils for a polka-dot pencil. \r\nWhat combination of pencils does each person have at the end of the trades? Include the color if the information is given.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter trading, each person has the following pencils:\n\r\nJeff: 2 cartoon character, 1 striped, 1 horse, and 1 polka dot \r\nPete: 1 cartoon character, 1 solid green, 1 polka-dot, and 2 striped \r\nCathy: 1 cartoon character, 1 solid orange, and 3 horse \r\nDeena: 1 cartoon character, 1 solid orange, 1 striped, and 2 polka-dot \r\nSara: 1 solid orange, 1 solid green, 1 striped, 1 polka-dot, and 1 horse\n<|im_start|>answer\nAfter trading, each person has the following pencils:\n\r\nJeff: 2 cartoon character, 1 striped, 1 horse, and 1 polka dot \r\nPete: 1 cartoon character, 1 solid green, 1 polka-dot, and 2 striped \r\nCathy: 1 cartoon character, 1 solid orange, and 3 horse \r\nDeena: 1 cartoon character, 1 solid orange, 1 striped, and 2 polka-dot \r\nSara: 1 solid orange, 1 solid green, 1 striped, 1 polka-dot, and 1 horse\n<|im_end|>" }, { "id": "#29521", "title": "Birthday Present", "fun": 2.49, "difficulty": 1.78, "author": "Freaks", "desc": "It's a simple little game, in which one of your friends is having a birthday party, and other students will have to give a birthday present. If your friend accepts the gift, the student will then be allowed to come to the birthday party.\n\r\nYour Friend: \"What will you give to me?\"\r\nKimberly: \"I'll give you a necklace.\"\r\nYour Friend: \"Nope. You're not invited. Next?\"\r\nRyan: \"I'll give you a roasted chicken as an addition for the dinner.\"\r\nYour Friend: \"Okay then, you're invited. Next?\"\r\nLizz: \"I'll give you a lighter.\"\r\nYour Friend: \"I don't smoke, but you're invited anyway. Next?\"\n\r\nNow it's your turn. So what should you give to your friend so he/she will invite you?", "hint": "Remember what each person gives, and what gifts get them invited.", "answer": "Any gift is fine, as long as the first letter of the thing you're going to give to your friend is the same with your name. So if your name starts with A, give him/her something that starts with the letter A.", "category": "Logic", "date": "04/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's a simple little game, in which one of your friends is having a birthday party, and other students will have to give a birthday present. If your friend accepts the gift, the student will then be allowed to come to the birthday party.\n\r\nYour Friend: \"What will you give to me?\"\r\nKimberly: \"I'll give you a necklace.\"\r\nYour Friend: \"Nope. You're not invited. Next?\"\r\nRyan: \"I'll give you a roasted chicken as an addition for the dinner.\"\r\nYour Friend: \"Okay then, you're invited. Next?\"\r\nLizz: \"I'll give you a lighter.\"\r\nYour Friend: \"I don't smoke, but you're invited anyway. Next?\"\n\r\nNow it's your turn. So what should you give to your friend so he/she will invite you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAny gift is fine, as long as the first letter of the thing you're going to give to your friend is the same with your name. So if your name starts with A, give him/her something that starts with the letter A.\n<|im_start|>answer\nAny gift is fine, as long as the first letter of the thing you're going to give to your friend is the same with your name. So if your name starts with A, give him/her something that starts with the letter A.\n<|im_end|>" }, { "id": "#16797", "title": "Twice As Old", "fun": 2.49, "difficulty": 1.53, "author": "Nite_Owl", "desc": "A girl is twice as old as her brother and half as old as her father. In 22 years, her brother will be half as old as his father. How old is the daughter now?", "hint": "No hint available.", "answer": "She is 22. Her brother is 11 and her father is 44. In 22 years, her brother would be 33 and their father would 66.", "category": "Math", "date": "02/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA girl is twice as old as her brother and half as old as her father. In 22 years, her brother will be half as old as his father. How old is the daughter now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe is 22. Her brother is 11 and her father is 44. In 22 years, her brother would be 33 and their father would 66.\n<|im_start|>answer\nShe is 22. Her brother is 11 and her father is 44. In 22 years, her brother would be 33 and their father would 66.\n<|im_end|>" }, { "id": "#1479", "title": "1 to 1,000,000", "fun": 2.49, "difficulty": 1.6400000000000001, "author": "tallpaul5k", "desc": "How many perfect squares (numbers that are results of squaring an integer) are there from 1 to 1,000,000?\n\r\nExamples: \r\n16=4*4\r\n121=11*11", "hint": "There are more than 100 and less than 10,000", "answer": "1,000\r\n1^2=1,2^2=4...999^2=998,001, 1000^2=1,000,000", "category": "Math", "date": "11/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many perfect squares (numbers that are results of squaring an integer) are there from 1 to 1,000,000?\n\r\nExamples: \r\n16=4*4\r\n121=11*11\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1,000\r\n1^2=1,2^2=4...999^2=998,001, 1000^2=1,000,000\n<|im_start|>answer\n1,000\r\n1^2=1,2^2=4...999^2=998,001, 1000^2=1,000,000\n<|im_end|>" }, { "id": "#43545", "title": "Super - Crazy Math Squares", "fun": 2.49, "difficulty": 2.96, "author": "beepbeeptnm", "desc": "Place 16 different 2-digit numbers in a 4x4 square grid so that they add up to the same number horizontally, vertically, and diagonally, and horizontally, vertically, and diagonally when turned UPSIDE - DOWN.", "hint": "This is not a trick question.\n\r\nThe magic sum is 264.", "answer": "The numbers should be like this:\n\r\n 96 11 89 68\r\n 88 69 91 16\r\n 61 86 18 99\r\n 19 98 66 81\n\r\n*Note that the only numbers used are 1, 6, 8, and 9, because these numbers can be read as either the same or a different number when turned upside down.\n\r\nExample: 1 and 8 look the same upside down, but 6 turns into 9 and 9 turns into 6.\n\r\nSo 89 becomes 68, 99 becomes 66, etc., and the numbers in the box still add up to 264 (vertically, horizontally, and diagonally) upside down!!", "category": "Math", "date": "11/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlace 16 different 2-digit numbers in a 4x4 square grid so that they add up to the same number horizontally, vertically, and diagonally, and horizontally, vertically, and diagonally when turned UPSIDE - DOWN.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers should be like this:\n\r\n 96 11 89 68\r\n 88 69 91 16\r\n 61 86 18 99\r\n 19 98 66 81\n\r\n*Note that the only numbers used are 1, 6, 8, and 9, because these numbers can be read as either the same or a different number when turned upside down.\n\r\nExample: 1 and 8 look the same upside down, but 6 turns into 9 and 9 turns into 6.\n\r\nSo 89 becomes 68, 99 becomes 66, etc., and the numbers in the box still add up to 264 (vertically, horizontally, and diagonally) upside down!!\n<|im_start|>answer\nThe numbers should be like this:\n\r\n 96 11 89 68\r\n 88 69 91 16\r\n 61 86 18 99\r\n 19 98 66 81\n\r\n*Note that the only numbers used are 1, 6, 8, and 9, because these numbers can be read as either the same or a different number when turned upside down.\n\r\nExample: 1 and 8 look the same upside down, but 6 turns into 9 and 9 turns into 6.\n\r\nSo 89 becomes 68, 99 becomes 66, etc., and the numbers in the box still add up to 264 (vertically, horizontally, and diagonally) upside down!!\n<|im_end|>" }, { "id": "#3154", "title": "Dig a Hole", "fun": 2.49, "difficulty": 1.54, "author": "204_blaze_41", "desc": "If it takes a man one hour to dig a hole two meters long, two meters wide, and two meters deep, how long would it take the same man to dig a hole four meters long, four meters wide, and four meters deep, assuming he digs at the same rate of speed?", "hint": "No hint available.", "answer": "Eight hours. It takes twice as long to double the length, twice as long to double the width, and twice as long to double the depth. To find cubic measurement you multiply length x width x height; therefore, on the first hole, one hour equals 2m x 2m x 2m = 8 cubic meters. On the second hole, the formula is 4m x 4m x 4m=64 cubic meters.", "category": "Math", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf it takes a man one hour to dig a hole two meters long, two meters wide, and two meters deep, how long would it take the same man to dig a hole four meters long, four meters wide, and four meters deep, assuming he digs at the same rate of speed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEight hours. It takes twice as long to double the length, twice as long to double the width, and twice as long to double the depth. To find cubic measurement you multiply length x width x height; therefore, on the first hole, one hour equals 2m x 2m x 2m = 8 cubic meters. On the second hole, the formula is 4m x 4m x 4m=64 cubic meters.\n<|im_start|>answer\nEight hours. It takes twice as long to double the length, twice as long to double the width, and twice as long to double the depth. To find cubic measurement you multiply length x width x height; therefore, on the first hole, one hour equals 2m x 2m x 2m = 8 cubic meters. On the second hole, the formula is 4m x 4m x 4m=64 cubic meters.\n<|im_end|>" }, { "id": "#4820", "title": "Wood-cutting Machines", "fun": 2.49, "difficulty": 2.64, "author": "arij", "desc": "In a wood-cutting factory, four large sawing machines stand in a windowless room. Each machine has an on/off switch attached, there being no doubt as to which switch controls which machine. Outside the door to the room are four back-up on/off switches, one for each machine inside. The power for each machine must first pass through the back-up switch, and then the machine switch before reaching the saw. The problem is, the new manager cannot decide how these back-up switches match with the machines inside the room. One day, the manager's brother visits. The manager takes him inside the sawing room where all four machines are at work and explains the problem. The brother announces that he intends to leave the room and that when he returns he will be able to match correctly the four switches outside the room to the four machines inside. The brother works alone, cannot see the machines from outside the room and solves the problem purely by operating switches. How is it possible?", "hint": "No hint available.", "answer": "Turn two machine switches off, go outside the room and, by listening, test all six combinations of two back-up switches to find which two match the two \"machine-on\" switches inside the room. Only one of the six combinations of two back-ups gives complete silence when switched off and these \"machine-on\" back-ups match the two \"on\" in the room. Now, before returning to the room, leave one \"on\" off and one \"off\" on leaving the other \"on\" on and \"off\" off, that is, only two switches are activated. Back inside the room, we can now match the switches by seeing which \"on\" machine is now off and which \"off\" is now on (when we activate its switch).", "category": "Logic", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a wood-cutting factory, four large sawing machines stand in a windowless room. Each machine has an on/off switch attached, there being no doubt as to which switch controls which machine. Outside the door to the room are four back-up on/off switches, one for each machine inside. The power for each machine must first pass through the back-up switch, and then the machine switch before reaching the saw. The problem is, the new manager cannot decide how these back-up switches match with the machines inside the room. One day, the manager's brother visits. The manager takes him inside the sawing room where all four machines are at work and explains the problem. The brother announces that he intends to leave the room and that when he returns he will be able to match correctly the four switches outside the room to the four machines inside. The brother works alone, cannot see the machines from outside the room and solves the problem purely by operating switches. How is it possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTurn two machine switches off, go outside the room and, by listening, test all six combinations of two back-up switches to find which two match the two \"machine-on\" switches inside the room. Only one of the six combinations of two back-ups gives complete silence when switched off and these \"machine-on\" back-ups match the two \"on\" in the room. Now, before returning to the room, leave one \"on\" off and one \"off\" on leaving the other \"on\" on and \"off\" off, that is, only two switches are activated. Back inside the room, we can now match the switches by seeing which \"on\" machine is now off and which \"off\" is now on (when we activate its switch).\n<|im_start|>answer\nTurn two machine switches off, go outside the room and, by listening, test all six combinations of two back-up switches to find which two match the two \"machine-on\" switches inside the room. Only one of the six combinations of two back-ups gives complete silence when switched off and these \"machine-on\" back-ups match the two \"on\" in the room. Now, before returning to the room, leave one \"on\" off and one \"off\" on leaving the other \"on\" on and \"off\" off, that is, only two switches are activated. Back inside the room, we can now match the switches by seeing which \"on\" machine is now off and which \"off\" is now on (when we activate its switch).\n<|im_end|>" }, { "id": "#26406", "title": "What Year Am I?", "fun": 2.49, "difficulty": 1.6, "author": "Blaque1", "desc": "In the month of May, mathematician Maria Gaerana was born in Italy. Maria was a gifted child who spoke more than a dozen languages by age nine. Her love however was mathematics, and even in a time when women were not educated, she became famous for her published books on mathematics. Solve the following to find out what year she was born.\n\r\nThe two digit number formed by my tens and units is one greater than the two digit number formed by my thousands and hundreds digits; their sum is 35.\n\r\nWhat year am I? __ __ __ __", "hint": "You don't have to find the remainder.", "answer": "To find the digits you have to first divide then subtract.\n\r\n1) 35/2 = 17\r\n2) 35-17 =18 \n\r\nTherefore, the year is 1718.", "category": "Math", "date": "10/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the month of May, mathematician Maria Gaerana was born in Italy. Maria was a gifted child who spoke more than a dozen languages by age nine. Her love however was mathematics, and even in a time when women were not educated, she became famous for her published books on mathematics. Solve the following to find out what year she was born.\n\r\nThe two digit number formed by my tens and units is one greater than the two digit number formed by my thousands and hundreds digits; their sum is 35.\n\r\nWhat year am I? __ __ __ __\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo find the digits you have to first divide then subtract.\n\r\n1) 35/2 = 17\r\n2) 35-17 =18 \n\r\nTherefore, the year is 1718.\n<|im_start|>answer\nTo find the digits you have to first divide then subtract.\n\r\n1) 35/2 = 17\r\n2) 35-17 =18 \n\r\nTherefore, the year is 1718.\n<|im_end|>" }, { "id": "#1146", "title": "Eight Eights", "fun": 2.49, "difficulty": 1.87, "author": "Ramlion", "desc": "Arrange eight eights so they add up to one thousand.", "hint": "No hint available.", "answer": "888 + 88 + 8 + 8 + 8 = 1000", "category": "Math", "date": "10/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange eight eights so they add up to one thousand.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n888 + 88 + 8 + 8 + 8 = 1000\n<|im_start|>answer\n888 + 88 + 8 + 8 + 8 = 1000\n<|im_end|>" }, { "id": "#444", "title": "I Like Oranges, But Not Peanuts....", "fun": 2.49, "difficulty": 1.39, "author": "Phyllis", "desc": "I like oranges, but I do not like peanuts. I like apples, but I do not like pineapples. I like pears, but I do not like grapes. Will I like cherries or strawberries?", "hint": "Consider where each of the foods grow.", "answer": "I only like foods that are grown in trees, so I will like cherries and not strawberries.", "category": "Logic", "date": "05/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI like oranges, but I do not like peanuts. I like apples, but I do not like pineapples. I like pears, but I do not like grapes. Will I like cherries or strawberries?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI only like foods that are grown in trees, so I will like cherries and not strawberries.\n<|im_start|>answer\nI only like foods that are grown in trees, so I will like cherries and not strawberries.\n<|im_end|>" }, { "id": "#9066", "title": "Where's the Gold?", "fun": 2.49, "difficulty": 2.0, "author": "lesternoronha1", "desc": "Two boxes are labeled \"A\" and \"B\". The sign on box A says, \"The sign on box B is true and the gold is in box A\". The sign on box B says, \"The sign on box A is false and the gold is in box A\". Assuming there is gold in one of the boxes, which box contains the gold?\n\r\n1) Box A\r\n2) Box B\r\n3) You can't determine from the information given.", "hint": "No hint available.", "answer": "3) You can't determine from the information given.\n\r\nThe sign on box A says, \"The sign on box B is true and the gold is in box A\". The sign on box B says, \"The sign on box A is false and the gold is in box A\". The following argument can be made: If the statement on box A is true, then the statement on box B is true, since that is what the statement on box A says. However, the statement on box B states that the statement on box A is false, which contradicts the original assumption. Therefore, the statement on box A must be false. This implies that either the statement on box B is false or that the gold is in box B. If the statement on box B is false, then either the statement on box A is true (which it cannot be) or the gold is in box B. Either way, the gold is in box B. \n\r\nHowever, there is a hidden assumption in this argument, namely, that each statement must be either true or false. This assumption leads to paradoxes; for example, consider the statement: \"This statement is false.\" If it is true, it is false; if it is false, it is true. The only way out of the paradox is to deny that the statement is either true or false and label it meaningless instead. Both of the statements on the boxes are therefore meaningless and nothing can be concluded from them.", "category": "Logic", "date": "12/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo boxes are labeled \"A\" and \"B\". The sign on box A says, \"The sign on box B is true and the gold is in box A\". The sign on box B says, \"The sign on box A is false and the gold is in box A\". Assuming there is gold in one of the boxes, which box contains the gold?\n\r\n1) Box A\r\n2) Box B\r\n3) You can't determine from the information given.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3) You can't determine from the information given.\n\r\nThe sign on box A says, \"The sign on box B is true and the gold is in box A\". The sign on box B says, \"The sign on box A is false and the gold is in box A\". The following argument can be made: If the statement on box A is true, then the statement on box B is true, since that is what the statement on box A says. However, the statement on box B states that the statement on box A is false, which contradicts the original assumption. Therefore, the statement on box A must be false. This implies that either the statement on box B is false or that the gold is in box B. If the statement on box B is false, then either the statement on box A is true (which it cannot be) or the gold is in box B. Either way, the gold is in box B. \n\r\nHowever, there is a hidden assumption in this argument, namely, that each statement must be either true or false. This assumption leads to paradoxes; for example, consider the statement: \"This statement is false.\" If it is true, it is false; if it is false, it is true. The only way out of the paradox is to deny that the statement is either true or false and label it meaningless instead. Both of the statements on the boxes are therefore meaningless and nothing can be concluded from them.\n<|im_start|>answer\n3) You can't determine from the information given.\n\r\nThe sign on box A says, \"The sign on box B is true and the gold is in box A\". The sign on box B says, \"The sign on box A is false and the gold is in box A\". The following argument can be made: If the statement on box A is true, then the statement on box B is true, since that is what the statement on box A says. However, the statement on box B states that the statement on box A is false, which contradicts the original assumption. Therefore, the statement on box A must be false. This implies that either the statement on box B is false or that the gold is in box B. If the statement on box B is false, then either the statement on box A is true (which it cannot be) or the gold is in box B. Either way, the gold is in box B. \n\r\nHowever, there is a hidden assumption in this argument, namely, that each statement must be either true or false. This assumption leads to paradoxes; for example, consider the statement: \"This statement is false.\" If it is true, it is false; if it is false, it is true. The only way out of the paradox is to deny that the statement is either true or false and label it meaningless instead. Both of the statements on the boxes are therefore meaningless and nothing can be concluded from them.\n<|im_end|>" }, { "id": "#29363", "title": "Play Ball 2", "fun": 2.49, "difficulty": 3.2, "author": "thompson1", "desc": "In a Little League Baseball game between the Braves and the Yankees, there were only 5 kids who had RBIs (Runs Batted In); two of them were on the Braves and three of them were on the Yankees. Each person had a different number of at-bats, of hits, and of RBIs. The scorekeeper was sick, so he couldn't come to the game, and had his brother go instead. Unfortunately, his brother forgot to write down the stats. This is all that he remembers. Help the scorekeeper figure out who is on which team, and how many hits, at-bats, and RBIs they had.\n\r\nNicknames \"Slammer,\" \"The Rocket,\" \"Flash,\" \"The Hammer,\" and \"Ace\"\r\nRBIs - 2, 3, 5, 6, 8\r\nHits - 1, 2, 3, 4, 5\r\nAt-bats - 1, 3, 4, 5, 7\r\nTeam - 2 Braves, 3 Yankees\n\r\n1. The Braves won.\r\n2. The five kids are: \"Slammer,\" the one with a 1.000 batting average, the one with 2 hits, the one with 7 at-bats, and the one with the least RBIs.\r\n3. \"Flash,\" who plays on the same team as his best friend, \"Ace,\" had 3 plate appearances, 5 RBIs, and got out at least once.\r\n4. \"The Rocket\" had either 1 or 2 hits.\r\n5. The players that had 2 more RBIs than at-bats did not have 3 hits.\r\n6. Only one player had one less RBI than hits.\r\n7. \"Flash\" only had RBIs off hits.\r\n8. \"Ace\" has half as many letters in his nickname as there are in the name of the team he plays for.\n\r\n You will be able to use the hint to find some answers before you even look at the clues.", "hint": "Batting Average is equal to hits/at bats.\r\n Plate Appearances and at-bats are not the same thing. A plate appearance is any time the batter goes up to the plate. It is only an at-bat if they get a hit or get out (as opposed to a walk or a hit-by-pitch). You cannot have more hits than at-bats.\r\n RBIs don't have to come off hits. If a player is walked or hit-by-pitch and a runner scores because of it, the batter gets an RBI. You can get more than one RBI on one hit, but only up to four.\r\n To figure out who wins, just add up the RBIs for each team.", "answer": "\"Slammer\" had 6 RBIs, 4 hits, and 5 at-bats for the Yankees.\r\n\"The Rocket\" had 3 RBIs, 1 hit, and 1 at-bat for the Yankees.\r\n\"Flash\" had 5 RBIs, 2 hits, and 3 at-bats for the Braves.\r\n\"The Hammer\" had 2 RBIs, 3 hits, and 4 at-bats for the Yankees.\r\n\"Ace\" had 8 RBIs, 5 hits, and 7 at-bats for the Braves.", "category": "Logic-Grid", "date": "03/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a Little League Baseball game between the Braves and the Yankees, there were only 5 kids who had RBIs (Runs Batted In); two of them were on the Braves and three of them were on the Yankees. Each person had a different number of at-bats, of hits, and of RBIs. The scorekeeper was sick, so he couldn't come to the game, and had his brother go instead. Unfortunately, his brother forgot to write down the stats. This is all that he remembers. Help the scorekeeper figure out who is on which team, and how many hits, at-bats, and RBIs they had.\n\r\nNicknames \"Slammer,\" \"The Rocket,\" \"Flash,\" \"The Hammer,\" and \"Ace\"\r\nRBIs - 2, 3, 5, 6, 8\r\nHits - 1, 2, 3, 4, 5\r\nAt-bats - 1, 3, 4, 5, 7\r\nTeam - 2 Braves, 3 Yankees\n\r\n1. The Braves won.\r\n2. The five kids are: \"Slammer,\" the one with a 1.000 batting average, the one with 2 hits, the one with 7 at-bats, and the one with the least RBIs.\r\n3. \"Flash,\" who plays on the same team as his best friend, \"Ace,\" had 3 plate appearances, 5 RBIs, and got out at least once.\r\n4. \"The Rocket\" had either 1 or 2 hits.\r\n5. The players that had 2 more RBIs than at-bats did not have 3 hits.\r\n6. Only one player had one less RBI than hits.\r\n7. \"Flash\" only had RBIs off hits.\r\n8. \"Ace\" has half as many letters in his nickname as there are in the name of the team he plays for.\n\r\n You will be able to use the hint to find some answers before you even look at the clues.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"Slammer\" had 6 RBIs, 4 hits, and 5 at-bats for the Yankees.\r\n\"The Rocket\" had 3 RBIs, 1 hit, and 1 at-bat for the Yankees.\r\n\"Flash\" had 5 RBIs, 2 hits, and 3 at-bats for the Braves.\r\n\"The Hammer\" had 2 RBIs, 3 hits, and 4 at-bats for the Yankees.\r\n\"Ace\" had 8 RBIs, 5 hits, and 7 at-bats for the Braves.\n<|im_start|>answer\n\"Slammer\" had 6 RBIs, 4 hits, and 5 at-bats for the Yankees.\r\n\"The Rocket\" had 3 RBIs, 1 hit, and 1 at-bat for the Yankees.\r\n\"Flash\" had 5 RBIs, 2 hits, and 3 at-bats for the Braves.\r\n\"The Hammer\" had 2 RBIs, 3 hits, and 4 at-bats for the Yankees.\r\n\"Ace\" had 8 RBIs, 5 hits, and 7 at-bats for the Braves.\n<|im_end|>" }, { "id": "#42979", "title": "Pet Accessories", "fun": 2.49, "difficulty": 1.01, "author": "whsprec", "desc": "Four friends - Mary, Ruth, Susie, and Betty - each own a pet. Their pets are a Chihuahua, a Yorkshire, a Chinese cat, and a box turtle. Each friend carries her pet in either a purple, pink, polka dot, or striped bag. Match the owner to the pet and the bag.\n\r\n1) Mary thinks her pet looks good in stripes.\r\n2) Betty and Susie are the dog owners, one of which has a pink bag.\r\n3) The turtle, the Chihuahua, and the pet in purple are all smaller than Ruth's pet.\r\n4) Susie took her pet to dinner with the pets in purple and stripes.", "hint": "No hint available.", "answer": "Mary - box turtle in striped bag\r\nRuth - Chinese cat in polka dot bag\r\nSusie - Chihuahua in pink bag\r\nBetty - Yorkshire in purple bag", "category": "Logic-Grid", "date": "09/03/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends - Mary, Ruth, Susie, and Betty - each own a pet. Their pets are a Chihuahua, a Yorkshire, a Chinese cat, and a box turtle. Each friend carries her pet in either a purple, pink, polka dot, or striped bag. Match the owner to the pet and the bag.\n\r\n1) Mary thinks her pet looks good in stripes.\r\n2) Betty and Susie are the dog owners, one of which has a pink bag.\r\n3) The turtle, the Chihuahua, and the pet in purple are all smaller than Ruth's pet.\r\n4) Susie took her pet to dinner with the pets in purple and stripes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary - box turtle in striped bag\r\nRuth - Chinese cat in polka dot bag\r\nSusie - Chihuahua in pink bag\r\nBetty - Yorkshire in purple bag\n<|im_start|>answer\nMary - box turtle in striped bag\r\nRuth - Chinese cat in polka dot bag\r\nSusie - Chihuahua in pink bag\r\nBetty - Yorkshire in purple bag\n<|im_end|>" }, { "id": "#28025", "title": "Three Strikes", "fun": 2.49, "difficulty": 1.17, "author": "12345678", "desc": "I was having trouble sleeping last night and I tossed and turned well into the night. Our local town hall has a clock which strikes on the hour and also strikes just once on the half hour. During one of my more awake moments I heard the clock strike once, but I could not tell what time it was. Half an hour later it struck once again, but I still could not tell what time it was. Finally, half an hour later it struck once again and I knew what the time was. What time was it?", "hint": "No hint available.", "answer": "1.30 in the morning. The first single strike was at 12.30.", "category": "Logic", "date": "01/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was having trouble sleeping last night and I tossed and turned well into the night. Our local town hall has a clock which strikes on the hour and also strikes just once on the half hour. During one of my more awake moments I heard the clock strike once, but I could not tell what time it was. Half an hour later it struck once again, but I still could not tell what time it was. Finally, half an hour later it struck once again and I knew what the time was. What time was it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1.30 in the morning. The first single strike was at 12.30.\n<|im_start|>answer\n1.30 in the morning. The first single strike was at 12.30.\n<|im_end|>" }, { "id": "#9305", "title": "Odometer Reading", "fun": 2.49, "difficulty": 1.03, "author": "lesternoronha1", "desc": "A car's odometer shows 72927 miles, a palindromic number. What is the minimum number of miles you would need to travel to form another?", "hint": "A palindrome can be read both forwards and backwards, like \"Kayak\".", "answer": "110 miles. (73037)", "category": "Math", "date": "12/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA car's odometer shows 72927 miles, a palindromic number. What is the minimum number of miles you would need to travel to form another?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n110 miles. (73037)\n<|im_start|>answer\n110 miles. (73037)\n<|im_end|>" }, { "id": "#10940", "title": "Untouchables", "fun": 2.49, "difficulty": 2.66, "author": "codammanus", "desc": "One day, 4 groups of people meet together to hold a meeting. There are 3 representatives from each group. \r\nThe groups are: KINGS, QUEENS, RELIGIOUS FIGURES and STOOGES. \n\r\nAmong the KINGS are: James, Saul and Henry. \r\nAmong the QUEENS are Victoria, Elizabeth and Candace. \r\nThe RELIGIOUS FIGURES consist of the Pope, Mother Teresa and Gandhi.\r\nThe STOOGES, of course, are none other than Moe, Larry and Curly. \n\r\nThe Stooges decide to play a game with the rest of the group. The game is called Untouchable. The Stooges start the game by tapping certain ones on the shoulder a specific number of times. The object of the game is for the other groups to figure out the pattern the Stooges set (that is, why they tap certain individuals a certain number of times), and to follow the pattern they set. \n\r\nThe only stipulation to the game is that people belonging to the RELIGIOUS FIGURES group do not tap anyone; however, they can be tapped. \n\r\nThe shoulder taps occur this way, starting with the Stooges (who originated the pattern): \n\r\nMoe taps James, Gandhi, the Pope and Saul twice each.\r\nLarry taps Henry, and Curly once each.\r\nCurly taps Henry and Larry once each. \n\r\n(The KINGS catch on and do the following): \n\r\nJames taps the Pope, Saul, Gandhi and Moe twice each. \r\nSaul taps Gandhi, Moe and James and the Pope twice each. \r\nHenry taps Larry and Curly once each. \n\r\n(The QUEENS catch on and do the following): \n\r\nElizabeth and Victoria tap each other four times each. \n\r\nQuestion: \n\r\nWho are the untouchables?", "hint": "No hint available.", "answer": "The pattern set by the Stooges is that each one taps the person with the same number of vowels in their name, one tap for every vowel. \n\r\nQueen Candace only has 3 Vowels, and Mother Teresa has 5. Neither of them have a counterpart with the same number of vowels. They would, therefore be the untouchables.", "category": "Logic", "date": "03/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, 4 groups of people meet together to hold a meeting. There are 3 representatives from each group. \r\nThe groups are: KINGS, QUEENS, RELIGIOUS FIGURES and STOOGES. \n\r\nAmong the KINGS are: James, Saul and Henry. \r\nAmong the QUEENS are Victoria, Elizabeth and Candace. \r\nThe RELIGIOUS FIGURES consist of the Pope, Mother Teresa and Gandhi.\r\nThe STOOGES, of course, are none other than Moe, Larry and Curly. \n\r\nThe Stooges decide to play a game with the rest of the group. The game is called Untouchable. The Stooges start the game by tapping certain ones on the shoulder a specific number of times. The object of the game is for the other groups to figure out the pattern the Stooges set (that is, why they tap certain individuals a certain number of times), and to follow the pattern they set. \n\r\nThe only stipulation to the game is that people belonging to the RELIGIOUS FIGURES group do not tap anyone; however, they can be tapped. \n\r\nThe shoulder taps occur this way, starting with the Stooges (who originated the pattern): \n\r\nMoe taps James, Gandhi, the Pope and Saul twice each.\r\nLarry taps Henry, and Curly once each.\r\nCurly taps Henry and Larry once each. \n\r\n(The KINGS catch on and do the following): \n\r\nJames taps the Pope, Saul, Gandhi and Moe twice each. \r\nSaul taps Gandhi, Moe and James and the Pope twice each. \r\nHenry taps Larry and Curly once each. \n\r\n(The QUEENS catch on and do the following): \n\r\nElizabeth and Victoria tap each other four times each. \n\r\nQuestion: \n\r\nWho are the untouchables?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pattern set by the Stooges is that each one taps the person with the same number of vowels in their name, one tap for every vowel. \n\r\nQueen Candace only has 3 Vowels, and Mother Teresa has 5. Neither of them have a counterpart with the same number of vowels. They would, therefore be the untouchables.\n<|im_start|>answer\nThe pattern set by the Stooges is that each one taps the person with the same number of vowels in their name, one tap for every vowel. \n\r\nQueen Candace only has 3 Vowels, and Mother Teresa has 5. Neither of them have a counterpart with the same number of vowels. They would, therefore be the untouchables.\n<|im_end|>" }, { "id": "#3262", "title": "Clever Thief", "fun": 2.49, "difficulty": 1.19, "author": "PeaceJo", "desc": "In olden days you are a clever thief charged with treason against the king and sentenced to death. But the king decides to be a little lenient and lets you choose your own way to die. What way should you choose?", "hint": "No hint available.", "answer": "Old age. (Natural causes would work as well.)", "category": "Logic", "date": "04/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn olden days you are a clever thief charged with treason against the king and sentenced to death. But the king decides to be a little lenient and lets you choose your own way to die. What way should you choose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOld age. (Natural causes would work as well.)\n<|im_start|>answer\nOld age. (Natural causes would work as well.)\n<|im_end|>" }, { "id": "#10515", "title": "If There's a Camel", "fun": 2.49, "difficulty": 2.91, "author": "griphook", "desc": "Every year during his birthday, the Sultan sponsors 3 camel races with the following prizes (listed in order 1st, 2nd, 3rd): \n\r\nRACE A \r\n$500 \r\n300 \r\n100 \n\r\nRACE B \r\n$250 \r\n150 \r\n75 \n\r\nRACE C \r\n$150 \r\n100 \r\n50 \n\r\n$500 bonus for winning all 3 Races. (SLAM) \r\n$200 bonus for winning 1st, 2nd, and 3rd in any one Race (SWEEP). \n\r\nALI BOBO tells you that he owns the 3rd (\"Aluminum\"), 6th(\"Boron\"), and 9th(\"Copper\") fastest camels. He concedes that KAREEM owns the 1st, 4th, and 7th fastest camels, while SHARIF has the 2nd, 5th, and 8th fastest entries. There are other owners but with far inferior camels. \n\r\nThe Rules \n\r\na. Maximum 3 camels per owner. \r\nb. A camel can run only in one race. \r\nc. An owner may enter his camels all in one race or distribute them as he desires. \n\r\nLast year ALI BOBO's camels won third place in each of the 3 Races. His gross winnings amounted to $225. \n\r\nALI BOBO wants a risk-free strategy to increase his total winnings. \n\r\nQUESTION: What should be ALI BOBO's strategy?", "hint": "Sometimes we must sacrifice some battles to win the war.", "answer": "Ali Bobo must enter Copper in Race A, Aluminum in Race B, and Boron in Race C.\n\r\nSCENARIOS\n\r\n1. Kareem defends his Slam and fields his camels in RACES A,B, and C according to their speed. Shariff follows that same strategy.\n\r\nALI's Aluminum will win in Race B over the K(4th) and S(5th). Boron will win in Race C over K(7th) and S(8th). Copper will still place 3rd in Race A. Total Winnings $500.\n\r\n2. Kareem defends his SLAM. Shariff follows Ali's strategy. \n\r\nAluminum will place second to S(2nd) in Race B. Boron will place second to S(5th) in Race C. Copper will place third to K(1st) and S(8th). Total winnings: $350.\n\r\n3. Kareem loses his mind and does not go for the grand slam. He enters his 3 camels in Race A. Shariff follows his strategy in Scenario 1.\n\r\nCopper will not win anything in Race A. Aluminum will win in Race B. Boron will win in Race C. Winnings: $400.\n\r\n4. Same as Scenario 3 but Shariff has same strategy as Ali.\n\r\nCopper loses in Race A. Aluminum places second in Race B. Boron places second in Race C. Winnings $250.\n\r\n5. Kareem camels all in Race A. Shariff's all in race B. \n\r\nCopper loses in Race A. Aluminum still places second in Race B. Boron wins in Race C. Winnings $300.\n\r\n6. Kareem defends his slam. Shariff camels all in race B.\r\nCopper will place second in Race A. Aluminum will still be second in Race B. Boron will win over K(7th) Winnings:$600.\n\r\n7. Kareem and Shariff has same strategy as Ali. \n\r\nCopper will be third, Aluminum will be third. Boron will be third. Winnings:$225. Same as last year.\n\r\nThere are other scenarios but with the strategy with the worst case scenario for Ali is $225.", "category": "Logic", "date": "02/17/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery year during his birthday, the Sultan sponsors 3 camel races with the following prizes (listed in order 1st, 2nd, 3rd): \n\r\nRACE A \r\n$500 \r\n300 \r\n100 \n\r\nRACE B \r\n$250 \r\n150 \r\n75 \n\r\nRACE C \r\n$150 \r\n100 \r\n50 \n\r\n$500 bonus for winning all 3 Races. (SLAM) \r\n$200 bonus for winning 1st, 2nd, and 3rd in any one Race (SWEEP). \n\r\nALI BOBO tells you that he owns the 3rd (\"Aluminum\"), 6th(\"Boron\"), and 9th(\"Copper\") fastest camels. He concedes that KAREEM owns the 1st, 4th, and 7th fastest camels, while SHARIF has the 2nd, 5th, and 8th fastest entries. There are other owners but with far inferior camels. \n\r\nThe Rules \n\r\na. Maximum 3 camels per owner. \r\nb. A camel can run only in one race. \r\nc. An owner may enter his camels all in one race or distribute them as he desires. \n\r\nLast year ALI BOBO's camels won third place in each of the 3 Races. His gross winnings amounted to $225. \n\r\nALI BOBO wants a risk-free strategy to increase his total winnings. \n\r\nQUESTION: What should be ALI BOBO's strategy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAli Bobo must enter Copper in Race A, Aluminum in Race B, and Boron in Race C.\n\r\nSCENARIOS\n\r\n1. Kareem defends his Slam and fields his camels in RACES A,B, and C according to their speed. Shariff follows that same strategy.\n\r\nALI's Aluminum will win in Race B over the K(4th) and S(5th). Boron will win in Race C over K(7th) and S(8th). Copper will still place 3rd in Race A. Total Winnings $500.\n\r\n2. Kareem defends his SLAM. Shariff follows Ali's strategy. \n\r\nAluminum will place second to S(2nd) in Race B. Boron will place second to S(5th) in Race C. Copper will place third to K(1st) and S(8th). Total winnings: $350.\n\r\n3. Kareem loses his mind and does not go for the grand slam. He enters his 3 camels in Race A. Shariff follows his strategy in Scenario 1.\n\r\nCopper will not win anything in Race A. Aluminum will win in Race B. Boron will win in Race C. Winnings: $400.\n\r\n4. Same as Scenario 3 but Shariff has same strategy as Ali.\n\r\nCopper loses in Race A. Aluminum places second in Race B. Boron places second in Race C. Winnings $250.\n\r\n5. Kareem camels all in Race A. Shariff's all in race B. \n\r\nCopper loses in Race A. Aluminum still places second in Race B. Boron wins in Race C. Winnings $300.\n\r\n6. Kareem defends his slam. Shariff camels all in race B.\r\nCopper will place second in Race A. Aluminum will still be second in Race B. Boron will win over K(7th) Winnings:$600.\n\r\n7. Kareem and Shariff has same strategy as Ali. \n\r\nCopper will be third, Aluminum will be third. Boron will be third. Winnings:$225. Same as last year.\n\r\nThere are other scenarios but with the strategy with the worst case scenario for Ali is $225.\n<|im_start|>answer\nAli Bobo must enter Copper in Race A, Aluminum in Race B, and Boron in Race C.\n\r\nSCENARIOS\n\r\n1. Kareem defends his Slam and fields his camels in RACES A,B, and C according to their speed. Shariff follows that same strategy.\n\r\nALI's Aluminum will win in Race B over the K(4th) and S(5th). Boron will win in Race C over K(7th) and S(8th). Copper will still place 3rd in Race A. Total Winnings $500.\n\r\n2. Kareem defends his SLAM. Shariff follows Ali's strategy. \n\r\nAluminum will place second to S(2nd) in Race B. Boron will place second to S(5th) in Race C. Copper will place third to K(1st) and S(8th). Total winnings: $350.\n\r\n3. Kareem loses his mind and does not go for the grand slam. He enters his 3 camels in Race A. Shariff follows his strategy in Scenario 1.\n\r\nCopper will not win anything in Race A. Aluminum will win in Race B. Boron will win in Race C. Winnings: $400.\n\r\n4. Same as Scenario 3 but Shariff has same strategy as Ali.\n\r\nCopper loses in Race A. Aluminum places second in Race B. Boron places second in Race C. Winnings $250.\n\r\n5. Kareem camels all in Race A. Shariff's all in race B. \n\r\nCopper loses in Race A. Aluminum still places second in Race B. Boron wins in Race C. Winnings $300.\n\r\n6. Kareem defends his slam. Shariff camels all in race B.\r\nCopper will place second in Race A. Aluminum will still be second in Race B. Boron will win over K(7th) Winnings:$600.\n\r\n7. Kareem and Shariff has same strategy as Ali. \n\r\nCopper will be third, Aluminum will be third. Boron will be third. Winnings:$225. Same as last year.\n\r\nThere are other scenarios but with the strategy with the worst case scenario for Ali is $225.\n<|im_end|>" }, { "id": "#2724", "title": "Clothing Store", "fun": 2.49, "difficulty": 1.45, "author": "lil_thugsta", "desc": "There is a clothing store in Winnipeg. The owner has devised his own method of pricing items. A vest costs $20, socks cost $25, a tie costs $15 and a blouse costs $30. Using the method, how much would a pair of underwear cost?", "hint": "No hint available.", "answer": "At $5 a letter you'd be charged $45 for underwear.", "category": "Logic", "date": "03/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a clothing store in Winnipeg. The owner has devised his own method of pricing items. A vest costs $20, socks cost $25, a tie costs $15 and a blouse costs $30. Using the method, how much would a pair of underwear cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt $5 a letter you'd be charged $45 for underwear.\n<|im_start|>answer\nAt $5 a letter you'd be charged $45 for underwear.\n<|im_end|>" }, { "id": "#24507", "title": "Red Dwarf", "fun": 2.49, "difficulty": 1.27, "author": "phrebh", "desc": "Cat (Felinis Sapien), Kryten (Mechanoid), Lister (Homo Sapien), and Rimmer (Hologrammatic Homo Sapien) have collected souvenirs for their eventual return to Earth, a stuffed GELF (Genetically Engineered Life Form) doll, a jigsaw puzzle of the Jupiter Mining Corporation vessel Red Dwarf, a CD of Rastabilly Skank music, and a poster from Srehtorb Drawkcab Gnizama Eht show. Each souvenir cost a different amount of dollarpounds: 12, 18, 24, and 30. Using the clues below, can you figure out who bought what souvenir and how much they paid for it?\n\r\n1. An organic life form bought the doll. \r\n2. The CD was exactly 12DP less than the puzzle. \r\n3. Rimmer paid with two 20DP notes and got less than 15DP back in change. \r\n4. The nonhumans each only had a 20DP note to spend on souvenirs.\r\n5. Rimmer and Kryten were on the poster, so they wouldn't want to buy it.\r\n6. The doll was the least expensive souvenir.", "hint": "Although a hologram, Rimmer is still considered human. Even though Kryten does have some organic material in some of his chips, he is not considered organic.", "answer": "Lister bought the poster for 24 dollarpounds.\r\nCat bought the doll for 12 dollarpounds.\r\nRimmer bought the puzzle for 30 dollarpounds.\r\nKryten bought the CD for 18 dollarpounds.", "category": "Logic-Grid", "date": "07/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCat (Felinis Sapien), Kryten (Mechanoid), Lister (Homo Sapien), and Rimmer (Hologrammatic Homo Sapien) have collected souvenirs for their eventual return to Earth, a stuffed GELF (Genetically Engineered Life Form) doll, a jigsaw puzzle of the Jupiter Mining Corporation vessel Red Dwarf, a CD of Rastabilly Skank music, and a poster from Srehtorb Drawkcab Gnizama Eht show. Each souvenir cost a different amount of dollarpounds: 12, 18, 24, and 30. Using the clues below, can you figure out who bought what souvenir and how much they paid for it?\n\r\n1. An organic life form bought the doll. \r\n2. The CD was exactly 12DP less than the puzzle. \r\n3. Rimmer paid with two 20DP notes and got less than 15DP back in change. \r\n4. The nonhumans each only had a 20DP note to spend on souvenirs.\r\n5. Rimmer and Kryten were on the poster, so they wouldn't want to buy it.\r\n6. The doll was the least expensive souvenir.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLister bought the poster for 24 dollarpounds.\r\nCat bought the doll for 12 dollarpounds.\r\nRimmer bought the puzzle for 30 dollarpounds.\r\nKryten bought the CD for 18 dollarpounds.\n<|im_start|>answer\nLister bought the poster for 24 dollarpounds.\r\nCat bought the doll for 12 dollarpounds.\r\nRimmer bought the puzzle for 30 dollarpounds.\r\nKryten bought the CD for 18 dollarpounds.\n<|im_end|>" }, { "id": "#39601", "title": "Opposites 34", "fun": 2.49, "difficulty": 2.22, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\nL stands for E, F, O, B, or X\r\nF stands for K, N, V, D, or A\r\nR stands for C, W, Y, O, or E\r\n! stands for S, A, J, T, or R\r\nO stands for H, L, M, R, or S\n\r\nThe five letter code word, ROFL!, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Chaos and Order.", "category": "Logic", "date": "12/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\nL stands for E, F, O, B, or X\r\nF stands for K, N, V, D, or A\r\nR stands for C, W, Y, O, or E\r\n! stands for S, A, J, T, or R\r\nO stands for H, L, M, R, or S\n\r\nThe five letter code word, ROFL!, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChaos and Order.\n<|im_start|>answer\nChaos and Order.\n<|im_end|>" }, { "id": "#47101", "title": "Class Photo 3", "fun": 2.49, "difficulty": 2.96, "author": "cnmne", "desc": "Stacey's class picture has 35 photos arranged in a 7 x 5 grid. The photos in the top row are numbered 1 through 7 from left to right, with the photos in the remaining rows similarly numbered. Given the following clues (bordering includes horizontal, vertical, and diagonal), where is Stacey's picture?\n\r\nX X X X X X X (1 - 7)\r\nX X X X X X X (8 - 14)\r\nX X X X X X X (15 - 21)\r\nX X X X X X X (22 - 28)\r\nX X X X X X X (29 - 35)\n\r\n1) Stacey and her two best friends, Rhonda and Teresa, are located along a straight line (horizontally, vertically, or diagonally). However, Stacey does not border either Rhonda or Teresa.\r\n2) The sum of the three positions (Stacey, Rhonda, and Teresa) is a prime number.\r\n3) There are 18 boys and 17 girls.\r\n4) Boys are not located at positions that are square numbers or cube numbers.\r\n5) Girls are not located at positions that are prime numbers.\r\n6) The sum of the positions where boys are located is less than the sum of the positions where girls are located.\r\n7) There are no more than four girls in any row.\r\n8) There are at least two girls in each column.\r\n9) There are no more than three girls in any diagonal.", "hint": "No hint available.", "answer": "A) Boys are located at the following positions (clue 5): 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, and 31. Girls are located at the following positions (clue 4): 1, 4, 8, 9, 16, 25, and 27.\r\nB) A boy must be at position 33 (clue 9). Girls must be at positions 10, 24, 12, and 26 (clue 8).\r\nC) Boys must be at positions 14, 22, and 28 (clue 7). A boy must be at position 32 (clue 9).\r\nD) Two boys still need to be placed. To satisfy clue 9, they must be among the following three positions: 6, 18, and 30. The summation of all positions (1 through 35) is 630. To satisfy clue 6, the sum of the positions for boys must be less than one-half of 630, or less than 315. The 15 boys already placed have a position sum of 289. To satisfy clue 6, the remaining two boys must add no more than 25. This means that the last two boys must be placed at positions 6 and 18, producing a total of 313. Girls occupy the remaining positions (15, 20, 21, 30, 34, and 35).\n\r\nStep A Step B Step C Step D\r\nGBBGBxB GBBGBxB GBBGBxB GBBGBBB\r\nGGxBxBx GGGBGBx GGGBGBB GGGBGBB\r\nxGBxBxx xGBxBxx xGBxBxx GGBBBGG\r\nxBxGxGx xBGGGGx BBGGGGB BBGGGGB\r\nBxBxxxx BxBxBxx BxBBBxx BGBBBGG\n\r\nStacey, Rhonda, and Teresa occupy positions that sum to a prime number (clue 1). The only sets of three positions that sum to a prime number are:\r\n8, 9, 12 (sum 29)\r\n9, 10, 12 (sum 31)\n\r\nPer clue 1, Stacey does not border either Rhonda or Teresa. With either set, Stacey is at position 12.", "category": "Logic", "date": "05/27/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStacey's class picture has 35 photos arranged in a 7 x 5 grid. The photos in the top row are numbered 1 through 7 from left to right, with the photos in the remaining rows similarly numbered. Given the following clues (bordering includes horizontal, vertical, and diagonal), where is Stacey's picture?\n\r\nX X X X X X X (1 - 7)\r\nX X X X X X X (8 - 14)\r\nX X X X X X X (15 - 21)\r\nX X X X X X X (22 - 28)\r\nX X X X X X X (29 - 35)\n\r\n1) Stacey and her two best friends, Rhonda and Teresa, are located along a straight line (horizontally, vertically, or diagonally). However, Stacey does not border either Rhonda or Teresa.\r\n2) The sum of the three positions (Stacey, Rhonda, and Teresa) is a prime number.\r\n3) There are 18 boys and 17 girls.\r\n4) Boys are not located at positions that are square numbers or cube numbers.\r\n5) Girls are not located at positions that are prime numbers.\r\n6) The sum of the positions where boys are located is less than the sum of the positions where girls are located.\r\n7) There are no more than four girls in any row.\r\n8) There are at least two girls in each column.\r\n9) There are no more than three girls in any diagonal.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA) Boys are located at the following positions (clue 5): 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, and 31. Girls are located at the following positions (clue 4): 1, 4, 8, 9, 16, 25, and 27.\r\nB) A boy must be at position 33 (clue 9). Girls must be at positions 10, 24, 12, and 26 (clue 8).\r\nC) Boys must be at positions 14, 22, and 28 (clue 7). A boy must be at position 32 (clue 9).\r\nD) Two boys still need to be placed. To satisfy clue 9, they must be among the following three positions: 6, 18, and 30. The summation of all positions (1 through 35) is 630. To satisfy clue 6, the sum of the positions for boys must be less than one-half of 630, or less than 315. The 15 boys already placed have a position sum of 289. To satisfy clue 6, the remaining two boys must add no more than 25. This means that the last two boys must be placed at positions 6 and 18, producing a total of 313. Girls occupy the remaining positions (15, 20, 21, 30, 34, and 35).\n\r\nStep A Step B Step C Step D\r\nGBBGBxB GBBGBxB GBBGBxB GBBGBBB\r\nGGxBxBx GGGBGBx GGGBGBB GGGBGBB\r\nxGBxBxx xGBxBxx xGBxBxx GGBBBGG\r\nxBxGxGx xBGGGGx BBGGGGB BBGGGGB\r\nBxBxxxx BxBxBxx BxBBBxx BGBBBGG\n\r\nStacey, Rhonda, and Teresa occupy positions that sum to a prime number (clue 1). The only sets of three positions that sum to a prime number are:\r\n8, 9, 12 (sum 29)\r\n9, 10, 12 (sum 31)\n\r\nPer clue 1, Stacey does not border either Rhonda or Teresa. With either set, Stacey is at position 12.\n<|im_start|>answer\nA) Boys are located at the following positions (clue 5): 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, and 31. Girls are located at the following positions (clue 4): 1, 4, 8, 9, 16, 25, and 27.\r\nB) A boy must be at position 33 (clue 9). Girls must be at positions 10, 24, 12, and 26 (clue 8).\r\nC) Boys must be at positions 14, 22, and 28 (clue 7). A boy must be at position 32 (clue 9).\r\nD) Two boys still need to be placed. To satisfy clue 9, they must be among the following three positions: 6, 18, and 30. The summation of all positions (1 through 35) is 630. To satisfy clue 6, the sum of the positions for boys must be less than one-half of 630, or less than 315. The 15 boys already placed have a position sum of 289. To satisfy clue 6, the remaining two boys must add no more than 25. This means that the last two boys must be placed at positions 6 and 18, producing a total of 313. Girls occupy the remaining positions (15, 20, 21, 30, 34, and 35).\n\r\nStep A Step B Step C Step D\r\nGBBGBxB GBBGBxB GBBGBxB GBBGBBB\r\nGGxBxBx GGGBGBx GGGBGBB GGGBGBB\r\nxGBxBxx xGBxBxx xGBxBxx GGBBBGG\r\nxBxGxGx xBGGGGx BBGGGGB BBGGGGB\r\nBxBxxxx BxBxBxx BxBBBxx BGBBBGG\n\r\nStacey, Rhonda, and Teresa occupy positions that sum to a prime number (clue 1). The only sets of three positions that sum to a prime number are:\r\n8, 9, 12 (sum 29)\r\n9, 10, 12 (sum 31)\n\r\nPer clue 1, Stacey does not border either Rhonda or Teresa. With either set, Stacey is at position 12.\n<|im_end|>" }, { "id": "#13736", "title": "Three Suspects", "fun": 2.49, "difficulty": 2.19, "author": "cccc", "desc": "There were 3 suspects for a crime. One is the robber, who only tells lies, one is the accomplice, who tells both truth and lie. Finally there is the innocent who tells only truths. Here is their statements about their jobs: \n\r\nA: I'm a clerk, B is a taxi driver, C is a barber. \n\r\nB: I'm a doctor, A, ah, you must ask him. For sure he'll say he's a clerk. C is an employee of Bai Huo Company.\n\r\nC: I'm an employee of Bai Huo Company, A is the barber, and B is a taxi driver. \n\r\nWho is the robber?", "hint": "The part where B says \"for sure\" has nothing to do with the answer. But the part where he says \"for sure he would say\" has.", "answer": "A is the robber. All of his statements are lies. \r\nB is the innocent man. He meant that A would SAY he's a clerk, not he IS.\r\nC is the accomplice. His first statement is the truth, his second statement could be the truth or a lie (it doesn't matter), and his third statement is a lie.", "category": "Logic", "date": "07/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 3 suspects for a crime. One is the robber, who only tells lies, one is the accomplice, who tells both truth and lie. Finally there is the innocent who tells only truths. Here is their statements about their jobs: \n\r\nA: I'm a clerk, B is a taxi driver, C is a barber. \n\r\nB: I'm a doctor, A, ah, you must ask him. For sure he'll say he's a clerk. C is an employee of Bai Huo Company.\n\r\nC: I'm an employee of Bai Huo Company, A is the barber, and B is a taxi driver. \n\r\nWho is the robber?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA is the robber. All of his statements are lies. \r\nB is the innocent man. He meant that A would SAY he's a clerk, not he IS.\r\nC is the accomplice. His first statement is the truth, his second statement could be the truth or a lie (it doesn't matter), and his third statement is a lie.\n<|im_start|>answer\nA is the robber. All of his statements are lies. \r\nB is the innocent man. He meant that A would SAY he's a clerk, not he IS.\r\nC is the accomplice. His first statement is the truth, his second statement could be the truth or a lie (it doesn't matter), and his third statement is a lie.\n<|im_end|>" }, { "id": "#30319", "title": "Mystery Circles", "fun": 2.49, "difficulty": 2.19, "author": "fairelamour", "desc": "Outside the lost city of Xaitec, archaeologists have noticed three rings of large stones, each with a straight line of stones beside it. Twins Sari and Devon have been asked by the chief archaeologist to see whether there may be a connection between the rings and the lines.\n\r\nThe twins decide to determine the diameters of the circles by stretching measuring tape across the widest part of each circle. They find the diameters to be 4.68 m, 9.36 m, and 14.04 m. They measure each of the corresponding straight lines of stones, finding them to be 14.7 m, 29.4 m, and 44.1 m, respectively.\n\r\nThey show the numbers to Jody, who is in charge of mapping. Jody looks at the numbers and says, \"Fascinating. Have you seen the connection?\" Sari says, \"Well, the second circle is twice as wide as the first, and the third is three times as wide as the first.\" Devon adds, \"And the same ratios apply to the straight lines!\"\n\r\n\"Fine!\" says Jody. \"But how is each circle related to the straight line next to it?\"\n\r\nWhat is the answer to Jody's question?", "hint": "Use a calculator to explore the ratios.", "answer": "The measure of each straight line represents the circumference of the corresponding circle.\n\r\nIf the twins were to divide the measure of each straight line by the diameter of the corresponding circle, they would get a quotient of 3.14 in all three cases. This quantity is the famous number pi, and the circumference of any circle is pi times the diameter. So what Jody noticed was that each straight line represented the circumference of the corresponding circle.", "category": "Math", "date": "05/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOutside the lost city of Xaitec, archaeologists have noticed three rings of large stones, each with a straight line of stones beside it. Twins Sari and Devon have been asked by the chief archaeologist to see whether there may be a connection between the rings and the lines.\n\r\nThe twins decide to determine the diameters of the circles by stretching measuring tape across the widest part of each circle. They find the diameters to be 4.68 m, 9.36 m, and 14.04 m. They measure each of the corresponding straight lines of stones, finding them to be 14.7 m, 29.4 m, and 44.1 m, respectively.\n\r\nThey show the numbers to Jody, who is in charge of mapping. Jody looks at the numbers and says, \"Fascinating. Have you seen the connection?\" Sari says, \"Well, the second circle is twice as wide as the first, and the third is three times as wide as the first.\" Devon adds, \"And the same ratios apply to the straight lines!\"\n\r\n\"Fine!\" says Jody. \"But how is each circle related to the straight line next to it?\"\n\r\nWhat is the answer to Jody's question?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe measure of each straight line represents the circumference of the corresponding circle.\n\r\nIf the twins were to divide the measure of each straight line by the diameter of the corresponding circle, they would get a quotient of 3.14 in all three cases. This quantity is the famous number pi, and the circumference of any circle is pi times the diameter. So what Jody noticed was that each straight line represented the circumference of the corresponding circle.\n<|im_start|>answer\nThe measure of each straight line represents the circumference of the corresponding circle.\n\r\nIf the twins were to divide the measure of each straight line by the diameter of the corresponding circle, they would get a quotient of 3.14 in all three cases. This quantity is the famous number pi, and the circumference of any circle is pi times the diameter. So what Jody noticed was that each straight line represented the circumference of the corresponding circle.\n<|im_end|>" }, { "id": "#29728", "title": "The Value of Two is Nine", "fun": 2.49, "difficulty": 2.42, "author": "peppamintp", "desc": "Each of the letters A - H has one of the eight values listed. No two letters have the same value. The simple arithmetic problems are clues for determining the value of each letter.\n\r\n2 6 7 9 12 13 14 15\n\r\n1. B + A = D\r\n2. E - H = C\r\n3. B + G = F\r\n4. F + C = D\r\n5. G + G = E\r\n6. C + G = A", "hint": "No hint available.", "answer": "A = 9\r\nB = 6\r\nC = 2\r\nD = 15\r\nE = 14 \r\nF = 13\r\nG = 7\r\nH = 12\n\r\n1. 6 + 9 = 15\r\n2. 14 - 12 = 2\r\n3. 6 + 7 = 13\r\n4. 13 + 2 = 15\r\n5. 7 + 7 = 14\r\n6. 2 + 7 = 9", "category": "Math", "date": "04/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach of the letters A - H has one of the eight values listed. No two letters have the same value. The simple arithmetic problems are clues for determining the value of each letter.\n\r\n2 6 7 9 12 13 14 15\n\r\n1. B + A = D\r\n2. E - H = C\r\n3. B + G = F\r\n4. F + C = D\r\n5. G + G = E\r\n6. C + G = A\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA = 9\r\nB = 6\r\nC = 2\r\nD = 15\r\nE = 14 \r\nF = 13\r\nG = 7\r\nH = 12\n\r\n1. 6 + 9 = 15\r\n2. 14 - 12 = 2\r\n3. 6 + 7 = 13\r\n4. 13 + 2 = 15\r\n5. 7 + 7 = 14\r\n6. 2 + 7 = 9\n<|im_start|>answer\nA = 9\r\nB = 6\r\nC = 2\r\nD = 15\r\nE = 14 \r\nF = 13\r\nG = 7\r\nH = 12\n\r\n1. 6 + 9 = 15\r\n2. 14 - 12 = 2\r\n3. 6 + 7 = 13\r\n4. 13 + 2 = 15\r\n5. 7 + 7 = 14\r\n6. 2 + 7 = 9\n<|im_end|>" }, { "id": "#4339", "title": "Insurance Salesman", "fun": 2.49, "difficulty": 2.11, "author": "Beelzebub", "desc": "An insurance salesman calls to the door of a house. He asks the lady about her family and wishes to know the ages of her children. She informs him that she has 3 children but does not wish to disclose information about them to a complete stranger. So he asks for a clue.\n\r\nShe tells him that: The product of their ages is 36 eg 2x3x6\n\r\nBut there are several possibilities, so he asks for another clue. She then tells him that the number of the house next door is the sum of their ages eg 2+3+6=11 But he still can't tell what their ages are so he asks for a final clue.\n\r\nThe lady then tells him that her eldest child plays the piano.\n\r\nStraightaway he knows their ages and attempts to sell the woman insurance.\n\r\nWhat are the ages of the woman's children and how did the salesman know?", "hint": "No hint available.", "answer": "Clue 1 - all possible solution:\r\n1,1,36\r\n1,2,18\r\n1,3,12\r\n1,4,9\r\n1,6,6\r\n2,2,9\r\n2,3,6\r\n3,3,4\n\r\nclue 2:\r\n1+1+36=38\r\n1+2+18=21\r\n1+3+12=16\r\n1+4+9=14\r\n1+6+6=13\r\n2+2+9=13\r\n2+3+6=11\r\n3+3+4=10\r\nSince he knows what number next door is, he must ask for a third clue only if the number is in 2 of the above ie\r\n1+6+6=13\r\n2+2+9=13\n\r\nClue 3:\r\nHer eldest child plays the piano, therefore the eldest cannot be a twin, so her children are aged 2, 2 and 9.", "category": "Math", "date": "05/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn insurance salesman calls to the door of a house. He asks the lady about her family and wishes to know the ages of her children. She informs him that she has 3 children but does not wish to disclose information about them to a complete stranger. So he asks for a clue.\n\r\nShe tells him that: The product of their ages is 36 eg 2x3x6\n\r\nBut there are several possibilities, so he asks for another clue. She then tells him that the number of the house next door is the sum of their ages eg 2+3+6=11 But he still can't tell what their ages are so he asks for a final clue.\n\r\nThe lady then tells him that her eldest child plays the piano.\n\r\nStraightaway he knows their ages and attempts to sell the woman insurance.\n\r\nWhat are the ages of the woman's children and how did the salesman know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nClue 1 - all possible solution:\r\n1,1,36\r\n1,2,18\r\n1,3,12\r\n1,4,9\r\n1,6,6\r\n2,2,9\r\n2,3,6\r\n3,3,4\n\r\nclue 2:\r\n1+1+36=38\r\n1+2+18=21\r\n1+3+12=16\r\n1+4+9=14\r\n1+6+6=13\r\n2+2+9=13\r\n2+3+6=11\r\n3+3+4=10\r\nSince he knows what number next door is, he must ask for a third clue only if the number is in 2 of the above ie\r\n1+6+6=13\r\n2+2+9=13\n\r\nClue 3:\r\nHer eldest child plays the piano, therefore the eldest cannot be a twin, so her children are aged 2, 2 and 9.\n<|im_start|>answer\nClue 1 - all possible solution:\r\n1,1,36\r\n1,2,18\r\n1,3,12\r\n1,4,9\r\n1,6,6\r\n2,2,9\r\n2,3,6\r\n3,3,4\n\r\nclue 2:\r\n1+1+36=38\r\n1+2+18=21\r\n1+3+12=16\r\n1+4+9=14\r\n1+6+6=13\r\n2+2+9=13\r\n2+3+6=11\r\n3+3+4=10\r\nSince he knows what number next door is, he must ask for a third clue only if the number is in 2 of the above ie\r\n1+6+6=13\r\n2+2+9=13\n\r\nClue 3:\r\nHer eldest child plays the piano, therefore the eldest cannot be a twin, so her children are aged 2, 2 and 9.\n<|im_end|>" }, { "id": "#867", "title": "Three Women", "fun": 2.49, "difficulty": 1.7, "author": "Michelle", "desc": "Of the three women lunching together, Melanie is older than the woman with black hair, but younger than the bookkeeper. The computer operator is the doctor's younger sister. Rebecca is younger than the brunette, and Debbie is older than the blonde. What color is each woman's hair, how old is she compared to the others, and what is her profession?", "hint": "No hint available.", "answer": "Melanie is the blonde doctor. Rebecca is the black-haired computer operator and is the youngest. Debbie is the brunette bookkeeper and the oldest.", "category": "Logic", "date": "09/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOf the three women lunching together, Melanie is older than the woman with black hair, but younger than the bookkeeper. The computer operator is the doctor's younger sister. Rebecca is younger than the brunette, and Debbie is older than the blonde. What color is each woman's hair, how old is she compared to the others, and what is her profession?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMelanie is the blonde doctor. Rebecca is the black-haired computer operator and is the youngest. Debbie is the brunette bookkeeper and the oldest.\n<|im_start|>answer\nMelanie is the blonde doctor. Rebecca is the black-haired computer operator and is the youngest. Debbie is the brunette bookkeeper and the oldest.\n<|im_end|>" }, { "id": "#35626", "title": "Opposites 27", "fun": 2.49, "difficulty": 2.42, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n- stands for E, O, L, C, or W\r\n= stands for J, K, U, R, or S\r\n* stands for B, O, P, F, or C\r\n+ stands for D, G, I, M, or A\r\n/ stands for F, N, H, E, or R\n\r\nThe five letter code word, */+-=, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Order and Chaos.", "category": "Logic", "date": "03/09/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n- stands for E, O, L, C, or W\r\n= stands for J, K, U, R, or S\r\n* stands for B, O, P, F, or C\r\n+ stands for D, G, I, M, or A\r\n/ stands for F, N, H, E, or R\n\r\nThe five letter code word, */+-=, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOrder and Chaos.\n<|im_start|>answer\nOrder and Chaos.\n<|im_end|>" }, { "id": "#39716", "title": "Winter Break", "fun": 2.49, "difficulty": 1.91, "author": "nerdyiscool", "desc": "Over Winter Break, five best friends each did different activities in different cities. Can you find out each friend's full name, what they did, and where they went?\n\r\nFirst names: Julie, Megan, David, Fred, Sam\r\nLast names: Wallace, Thompson, Mallard, Shields, Drake\r\nActivities: Ski Trip, Moving, Cruise, Cooking Classes, Visiting Relatives\r\nPlaces: Houston, Paris, Cleveland, Vancouver, Miami\n\r\n1) Julie and Ms. Wallace, in particular, were sad that David wasn't coming back.\r\n2) Neither Sam nor Julie have ever left the U.S. before this winter break. \r\n3) All first names that have two syllables belong with last names that have two syllables. Nobody's last name starts with the same letter as their first name.\r\n4) Ms. Mallard is excited to learn about French cuisine.\r\n5) Mr. Thompson doesn't want to move.\r\n6) The friends, in no particular order, are as follows: the girl who is going on a ski trip, Mr. Shields, Megan, the boy headed to Houston, and Julie.\r\n7) Cruises can only be taken in warm coastal cities. Ski trips can only be taken in cold, mountainous places. Remember this is winter.\r\n8) The cruise ship Fred is traveling on does not dock in Houston.", "hint": "Sam can be a boy's or a girl's name. In this case it is short for Samantha.", "answer": "Full Name- Activity- City\n\r\nJulie Mallard- Cooking Classes- Paris\r\nMegan Wallace- Moving- Cleveland\r\nDavid Thompson- Visiting Relatives- Houston\r\nFred Shields- Cruise- Miami\r\nSam Drake- Ski Trip- Vancouver", "category": "Logic-Grid", "date": "12/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOver Winter Break, five best friends each did different activities in different cities. Can you find out each friend's full name, what they did, and where they went?\n\r\nFirst names: Julie, Megan, David, Fred, Sam\r\nLast names: Wallace, Thompson, Mallard, Shields, Drake\r\nActivities: Ski Trip, Moving, Cruise, Cooking Classes, Visiting Relatives\r\nPlaces: Houston, Paris, Cleveland, Vancouver, Miami\n\r\n1) Julie and Ms. Wallace, in particular, were sad that David wasn't coming back.\r\n2) Neither Sam nor Julie have ever left the U.S. before this winter break. \r\n3) All first names that have two syllables belong with last names that have two syllables. Nobody's last name starts with the same letter as their first name.\r\n4) Ms. Mallard is excited to learn about French cuisine.\r\n5) Mr. Thompson doesn't want to move.\r\n6) The friends, in no particular order, are as follows: the girl who is going on a ski trip, Mr. Shields, Megan, the boy headed to Houston, and Julie.\r\n7) Cruises can only be taken in warm coastal cities. Ski trips can only be taken in cold, mountainous places. Remember this is winter.\r\n8) The cruise ship Fred is traveling on does not dock in Houston.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFull Name- Activity- City\n\r\nJulie Mallard- Cooking Classes- Paris\r\nMegan Wallace- Moving- Cleveland\r\nDavid Thompson- Visiting Relatives- Houston\r\nFred Shields- Cruise- Miami\r\nSam Drake- Ski Trip- Vancouver\n<|im_start|>answer\nFull Name- Activity- City\n\r\nJulie Mallard- Cooking Classes- Paris\r\nMegan Wallace- Moving- Cleveland\r\nDavid Thompson- Visiting Relatives- Houston\r\nFred Shields- Cruise- Miami\r\nSam Drake- Ski Trip- Vancouver\n<|im_end|>" }, { "id": "#32512", "title": "Circular System?", "fun": 2.49, "difficulty": 1.8800000000000001, "author": "moonsliver86", "desc": "Given that:\n\r\na + b = 12\r\nc + d = 7\r\nb-c = 2\r\na-d = 3\n\r\nFind (a-b) + (c - d).", "hint": "It doesn't hurt to \"regroup\".", "answer": "The answer is 1. If you tried to get each letter individually, you'd probably go in circles. Instead, notice that (a-b) + (c-d) = (a+c) - (b+d).\r\nAlso, (a+c) = [(a+b) - (b-c)], and (b+d) = [(a+b) - (a-d)], so:\n\r\n(a+c) - (b+d)\r\n= [(a+b) - (b-c)] - [(a+b) - (a-d)]\r\n= [(12 - 2)] - [(12 - 3)]\r\n= 10 - 9\r\n= 1\n\r\nor\n\r\n(a-b) + (c-d) \r\n= (a-d) - (b-c)\r\n= 3 - 2\r\n= 1", "category": "Math", "date": "08/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGiven that:\n\r\na + b = 12\r\nc + d = 7\r\nb-c = 2\r\na-d = 3\n\r\nFind (a-b) + (c - d).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 1. If you tried to get each letter individually, you'd probably go in circles. Instead, notice that (a-b) + (c-d) = (a+c) - (b+d).\r\nAlso, (a+c) = [(a+b) - (b-c)], and (b+d) = [(a+b) - (a-d)], so:\n\r\n(a+c) - (b+d)\r\n= [(a+b) - (b-c)] - [(a+b) - (a-d)]\r\n= [(12 - 2)] - [(12 - 3)]\r\n= 10 - 9\r\n= 1\n\r\nor\n\r\n(a-b) + (c-d) \r\n= (a-d) - (b-c)\r\n= 3 - 2\r\n= 1\n<|im_start|>answer\nThe answer is 1. If you tried to get each letter individually, you'd probably go in circles. Instead, notice that (a-b) + (c-d) = (a+c) - (b+d).\r\nAlso, (a+c) = [(a+b) - (b-c)], and (b+d) = [(a+b) - (a-d)], so:\n\r\n(a+c) - (b+d)\r\n= [(a+b) - (b-c)] - [(a+b) - (a-d)]\r\n= [(12 - 2)] - [(12 - 3)]\r\n= 10 - 9\r\n= 1\n\r\nor\n\r\n(a-b) + (c-d) \r\n= (a-d) - (b-c)\r\n= 3 - 2\r\n= 1\n<|im_end|>" }, { "id": "#35351", "title": "Little Johnny #5", "fun": 2.49, "difficulty": 2.0, "author": "fishmed", "desc": "Little Johnny's brother was at it again. He felt he really had Johnny this time. \"You know how mother always says, 'Two wrongs don't make a right?' Well, our teacher said, as a math problem it was possible for two wrongs to make a right. I bet you washing the dinner dishes for a week that you can't get this before dinner.\"\n\r\nWRONG + WRONG = RIGHT\n\r\n\"And the teacher gave us the hint that T = 8, H = 6 and I = 1\"\n\r\nWell, after dinner, Little Johnny's brother was sadly doing the dishes while Little Johnny was off watching TV with his parents. \n\r\nCan you figure out the answer as well? Each letter stands for the same number 0-9 throughout the problem.", "hint": "The number 0 and 9 are not used.", "answer": "I = 1\r\nW = 2\r\nN = 3\r\nG = 4\r\nR = 5\r\nH = 6\r\nO = 7\r\nT = 8\n\r\n25734 + 25734 = 51468", "category": "Math", "date": "02/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittle Johnny's brother was at it again. He felt he really had Johnny this time. \"You know how mother always says, 'Two wrongs don't make a right?' Well, our teacher said, as a math problem it was possible for two wrongs to make a right. I bet you washing the dinner dishes for a week that you can't get this before dinner.\"\n\r\nWRONG + WRONG = RIGHT\n\r\n\"And the teacher gave us the hint that T = 8, H = 6 and I = 1\"\n\r\nWell, after dinner, Little Johnny's brother was sadly doing the dishes while Little Johnny was off watching TV with his parents. \n\r\nCan you figure out the answer as well? Each letter stands for the same number 0-9 throughout the problem.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI = 1\r\nW = 2\r\nN = 3\r\nG = 4\r\nR = 5\r\nH = 6\r\nO = 7\r\nT = 8\n\r\n25734 + 25734 = 51468\n<|im_start|>answer\nI = 1\r\nW = 2\r\nN = 3\r\nG = 4\r\nR = 5\r\nH = 6\r\nO = 7\r\nT = 8\n\r\n25734 + 25734 = 51468\n<|im_end|>" }, { "id": "#41509", "title": "Soda Bottles", "fun": 2.49, "difficulty": 1.71, "author": "GrayPanther", "desc": "Sally likes soda very much. At the local convenience store, for 5 empty soda bottles she receives a full bottle. As part of the Girl Guide's recycling initiative, she manages to collect 77 empty bottles. How many bottles of soda will she be able to drink in total?", "hint": "No hint available.", "answer": "19 bottles\n\r\nFrom the initial 77 bottles, she receives 15 full bottles (with 2 spare empties). From the 17 empties, she receives 3 more full bottles (with 2 spare empties). From the 5 empties she receives one final full bottle.", "category": "Math", "date": "04/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally likes soda very much. At the local convenience store, for 5 empty soda bottles she receives a full bottle. As part of the Girl Guide's recycling initiative, she manages to collect 77 empty bottles. How many bottles of soda will she be able to drink in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19 bottles\n\r\nFrom the initial 77 bottles, she receives 15 full bottles (with 2 spare empties). From the 17 empties, she receives 3 more full bottles (with 2 spare empties). From the 5 empties she receives one final full bottle.\n<|im_start|>answer\n19 bottles\n\r\nFrom the initial 77 bottles, she receives 15 full bottles (with 2 spare empties). From the 17 empties, she receives 3 more full bottles (with 2 spare empties). From the 5 empties she receives one final full bottle.\n<|im_end|>" }, { "id": "#13954", "title": "A + B + C + D", "fun": 2.48, "difficulty": 2.15, "author": "mathemagician", "desc": "A, B, C, and D are all positive whole numbers. If A is to 2 as B is to 3; B is to 6 as C is to 8; and C is to 9 as D is to 12, what is the SMALLEST possible value for the sum: A + B + C + D ?", "hint": "A/2 = B/3 or 3A = 2B\n\r\nB/6 = C/8 or 8B = 6C ;\n\r\nC/9 = D/12 or 12C = 9D .\n\r\nWhat's the smallest positive whole numbers that satisfies all three of the above equations?", "answer": "43 \r\nA = 6 , B = 9 , C = 12 , and D = 16 . \n\r\nSo, A + B+ C + D = 43.", "category": "Math", "date": "07/22/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA, B, C, and D are all positive whole numbers. If A is to 2 as B is to 3; B is to 6 as C is to 8; and C is to 9 as D is to 12, what is the SMALLEST possible value for the sum: A + B + C + D ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n43 \r\nA = 6 , B = 9 , C = 12 , and D = 16 . \n\r\nSo, A + B+ C + D = 43.\n<|im_start|>answer\n43 \r\nA = 6 , B = 9 , C = 12 , and D = 16 . \n\r\nSo, A + B+ C + D = 43.\n<|im_end|>" }, { "id": "#3353", "title": "Canadian and US Dollars", "fun": 2.48, "difficulty": 2.07, "author": "lil_thugsta", "desc": "At one time, the Canadian and US dollars were discounted by 10 cents on each side of the border (i.e., a Canadian dollar was worth 90 US cents in the US, and a US dollar was worth 90 Canadian cents in Canada). A man walks into a bar on the US side of the border, orders 10 US cents worth of beer, pays with a US dollar and receives a Canadian dollar in change. He then walks across the border to Canada, orders 10 Canadian cents worth of beer, pays with a Canadian dollar and receives a US dollar in change. He continues this throughout the day, and ends up dead drunk with the original dollar in his pocket.\r\nWho pays for the drinks?", "hint": "No hint available.", "answer": "The man paid for all the drinks. But, you say, he ended up with the same amount of money that he started with! However, as he transported Canadian dollars into Canada and US dollars into the US, he performed \"economic work\" by moving the currency to a location where it was in greater demand (and thus valued higher). The earnings from this work were spent on the drinks.", "category": "Math", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt one time, the Canadian and US dollars were discounted by 10 cents on each side of the border (i.e., a Canadian dollar was worth 90 US cents in the US, and a US dollar was worth 90 Canadian cents in Canada). A man walks into a bar on the US side of the border, orders 10 US cents worth of beer, pays with a US dollar and receives a Canadian dollar in change. He then walks across the border to Canada, orders 10 Canadian cents worth of beer, pays with a Canadian dollar and receives a US dollar in change. He continues this throughout the day, and ends up dead drunk with the original dollar in his pocket.\r\nWho pays for the drinks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man paid for all the drinks. But, you say, he ended up with the same amount of money that he started with! However, as he transported Canadian dollars into Canada and US dollars into the US, he performed \"economic work\" by moving the currency to a location where it was in greater demand (and thus valued higher). The earnings from this work were spent on the drinks.\n<|im_start|>answer\nThe man paid for all the drinks. But, you say, he ended up with the same amount of money that he started with! However, as he transported Canadian dollars into Canada and US dollars into the US, he performed \"economic work\" by moving the currency to a location where it was in greater demand (and thus valued higher). The earnings from this work were spent on the drinks.\n<|im_end|>" }, { "id": "#2566", "title": "Men with Earrings", "fun": 2.48, "difficulty": 1.35, "author": "204_blaze_41", "desc": "There is a certain club which is for men only. There are 600 men who belong to this club and 5% of these men wear one earring. Of the other 95% membership, half wear two earrings and the other half wear none. How many earrings are being worn in this club?", "hint": "No hint available.", "answer": "Six hundred. We know that 5%, or 30 people of the men are wearing one earring. Of the other 95%, 570, we know that half are wearing two earrings and the other half none. This is the same as if they all wore one.", "category": "Math", "date": "03/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a certain club which is for men only. There are 600 men who belong to this club and 5% of these men wear one earring. Of the other 95% membership, half wear two earrings and the other half wear none. How many earrings are being worn in this club?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSix hundred. We know that 5%, or 30 people of the men are wearing one earring. Of the other 95%, 570, we know that half are wearing two earrings and the other half none. This is the same as if they all wore one.\n<|im_start|>answer\nSix hundred. We know that 5%, or 30 people of the men are wearing one earring. Of the other 95%, 570, we know that half are wearing two earrings and the other half none. This is the same as if they all wore one.\n<|im_end|>" }, { "id": "#13528", "title": "The See-Saw", "fun": 2.48, "difficulty": 1.28, "author": "cool_star", "desc": "On one side of a balanced see-saw is an ice cube, on the other side is a basketball. The ice cube and the basketball have the same weight. \n\r\nQuestions: \n\r\n1. Which side will the see-saw tilt toward first? \n\r\n2. Which side will the see-saw tilt toward at the end?", "hint": "No hint available.", "answer": "1. The see-saw will tilt toward the basketball first after the ice has melted a bit. The water won't be able to stay on the see-saw, so that side's lighter. \n\r\n2. The see-saw will balance out in the end, because the basketball will roll off after it tilts towards it, and the ice will melt entirely and the water will run off and/or evaporate. So there will be nothing on the see-saw at the end.", "category": "Logic", "date": "06/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn one side of a balanced see-saw is an ice cube, on the other side is a basketball. The ice cube and the basketball have the same weight. \n\r\nQuestions: \n\r\n1. Which side will the see-saw tilt toward first? \n\r\n2. Which side will the see-saw tilt toward at the end?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. The see-saw will tilt toward the basketball first after the ice has melted a bit. The water won't be able to stay on the see-saw, so that side's lighter. \n\r\n2. The see-saw will balance out in the end, because the basketball will roll off after it tilts towards it, and the ice will melt entirely and the water will run off and/or evaporate. So there will be nothing on the see-saw at the end.\n<|im_start|>answer\n1. The see-saw will tilt toward the basketball first after the ice has melted a bit. The water won't be able to stay on the see-saw, so that side's lighter. \n\r\n2. The see-saw will balance out in the end, because the basketball will roll off after it tilts towards it, and the ice will melt entirely and the water will run off and/or evaporate. So there will be nothing on the see-saw at the end.\n<|im_end|>" }, { "id": "#234", "title": "55 Cents", "fun": 2.48, "difficulty": 1.1, "author": "Phyllis", "desc": "A man holds out his closed fist and says: \"I am holding two coins in my hand. The sum of these coins comes to exactly 55 cents. One of the coins is not a nickel. Can you tell me the value of each of the coins?\"", "hint": "A nickel is worth 5 cents.", "answer": "The coin that is not a nickel is a half dollar. The other coin is a nickel.", "category": "Logic", "date": "02/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man holds out his closed fist and says: \"I am holding two coins in my hand. The sum of these coins comes to exactly 55 cents. One of the coins is not a nickel. Can you tell me the value of each of the coins?\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe coin that is not a nickel is a half dollar. The other coin is a nickel.\n<|im_start|>answer\nThe coin that is not a nickel is a half dollar. The other coin is a nickel.\n<|im_end|>" }, { "id": "#47469", "title": "The Liars' Rail", "fun": 2.48, "difficulty": 2.79, "author": "dalfamnest", "desc": "The people of Olde Mathville had unique ways of punishing wayward citizens. For example, those convicted of crimes of dishonesty were chained to the Liars' Rail until they solved a number of puzzles.\n\r\nOne such puzzle has been recently discovered! \n\r\nIn the multiplication below, each letter - L, I, A, R, and S - takes the place of a different digit. Find the digits to make the multiplication true. \n\r\nL I A R\r\n x S\r\n--------\r\nR A I L\n\r\nor: L I A R x S = R A I L", "hint": "The product of S x L must be less than 10. Combining that with the need for S x R to end in L limits the possibilities quickly.", "answer": "L=2, I=1, A=7, R=8, and S=4\n\r\n2178 x 4 = 8712\n\n\r\nOne possible solution guide:\r\n* SxL<10, as the product is a 4-digit number; S can not = 1\r\n... so S,L can be 2,3; 2,4; 3,1; 3,2; 4,1; 4,2\n\r\n* but SxR ends in L - and if S or R is even, so is L\r\n... so S,L,R can be 2,4,7; 3,1,7; 3,2,4; 4,2,8\n\r\n* the first three are quickly rejected by checking the multiplication\r\n... S=4, L=2, R=8\n\r\n* Since 2000 x 4 = 8000, nothing has been carried from multiplying the hundreds digit\r\n... so I=1 or 0 \n\r\n* I=0 is rejected as '3' tens have been carried forward from multiplying 4x8; the 3 must be added to 7 to give 0 in the bottom line, and we cannot have 4 x __ = 7.\r\n... so I=1\r\n... so A=7 (the only way to get a 1 in the tens column of the product)", "category": "Math", "date": "07/12/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe people of Olde Mathville had unique ways of punishing wayward citizens. For example, those convicted of crimes of dishonesty were chained to the Liars' Rail until they solved a number of puzzles.\n\r\nOne such puzzle has been recently discovered! \n\r\nIn the multiplication below, each letter - L, I, A, R, and S - takes the place of a different digit. Find the digits to make the multiplication true. \n\r\nL I A R\r\n x S\r\n--------\r\nR A I L\n\r\nor: L I A R x S = R A I L\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nL=2, I=1, A=7, R=8, and S=4\n\r\n2178 x 4 = 8712\n\n\r\nOne possible solution guide:\r\n* SxL<10, as the product is a 4-digit number; S can not = 1\r\n... so S,L can be 2,3; 2,4; 3,1; 3,2; 4,1; 4,2\n\r\n* but SxR ends in L - and if S or R is even, so is L\r\n... so S,L,R can be 2,4,7; 3,1,7; 3,2,4; 4,2,8\n\r\n* the first three are quickly rejected by checking the multiplication\r\n... S=4, L=2, R=8\n\r\n* Since 2000 x 4 = 8000, nothing has been carried from multiplying the hundreds digit\r\n... so I=1 or 0 \n\r\n* I=0 is rejected as '3' tens have been carried forward from multiplying 4x8; the 3 must be added to 7 to give 0 in the bottom line, and we cannot have 4 x __ = 7.\r\n... so I=1\r\n... so A=7 (the only way to get a 1 in the tens column of the product)\n<|im_start|>answer\nL=2, I=1, A=7, R=8, and S=4\n\r\n2178 x 4 = 8712\n\n\r\nOne possible solution guide:\r\n* SxL<10, as the product is a 4-digit number; S can not = 1\r\n... so S,L can be 2,3; 2,4; 3,1; 3,2; 4,1; 4,2\n\r\n* but SxR ends in L - and if S or R is even, so is L\r\n... so S,L,R can be 2,4,7; 3,1,7; 3,2,4; 4,2,8\n\r\n* the first three are quickly rejected by checking the multiplication\r\n... S=4, L=2, R=8\n\r\n* Since 2000 x 4 = 8000, nothing has been carried from multiplying the hundreds digit\r\n... so I=1 or 0 \n\r\n* I=0 is rejected as '3' tens have been carried forward from multiplying 4x8; the 3 must be added to 7 to give 0 in the bottom line, and we cannot have 4 x __ = 7.\r\n... so I=1\r\n... so A=7 (the only way to get a 1 in the tens column of the product)\n<|im_end|>" }, { "id": "#10608", "title": "Yesterday?", "fun": 2.48, "difficulty": 1.59, "author": "niki", "desc": "A certain day was yesterday when the day before yesterday was yesterday . On that certain day Kim's parents said \"we'll go on a picnic the day after tomorrow if it doesn't rain\". It rained the day before yesterday but not since. \n\r\nDid the family go on the picnic?", "hint": "No hint available.", "answer": "Yes. \n\r\nAssume today is Friday. The first sentence simply says that the \"certain day\" was the day before yesterday, or Wednesday. On Wednesday, the parents said that they would go on a picnic on Friday (today) if it doesn't rain. Since it hasn't rained since the day before yesterday (Wednesday), then the family did go on a picnic today.", "category": "Logic", "date": "02/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA certain day was yesterday when the day before yesterday was yesterday . On that certain day Kim's parents said \"we'll go on a picnic the day after tomorrow if it doesn't rain\". It rained the day before yesterday but not since. \n\r\nDid the family go on the picnic?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes. \n\r\nAssume today is Friday. The first sentence simply says that the \"certain day\" was the day before yesterday, or Wednesday. On Wednesday, the parents said that they would go on a picnic on Friday (today) if it doesn't rain. Since it hasn't rained since the day before yesterday (Wednesday), then the family did go on a picnic today.\n<|im_start|>answer\nYes. \n\r\nAssume today is Friday. The first sentence simply says that the \"certain day\" was the day before yesterday, or Wednesday. On Wednesday, the parents said that they would go on a picnic on Friday (today) if it doesn't rain. Since it hasn't rained since the day before yesterday (Wednesday), then the family did go on a picnic today.\n<|im_end|>" }, { "id": "#44837", "title": "A Whole New Season", "fun": 2.48, "difficulty": 1.95, "author": "mrsfessler", "desc": "Five friends were discussing their favorite shows of the new television season. From the clues provided, determine each friend's favorite new show, the star of each show, and what time it aired (one was at 9:00pm).\n\r\nShows: CSI Podunk, Desolate Husbands, Wheel of Fate, Dr. Cure, Cuddles in the Country\n\r\nStars: \r\nMale- Justin Time, Chance Ripley\r\nFemale- Chiquita Jalapeno, Lily Gardens, Rosie McDougal \n\r\n1. Isaac's favorite show aired 1/2 hour after the one starring Justin Time but before Dr. Cure. Desolate Husbands aired either at 8:00pm or 10:00pm.\n\r\n2. The five shows are the one at 8:30pm, Melinda's favorite, the one starring Chance Ripley, CSI Podunk and Wheel of Fate. \n\r\n3. Charles really enjoyed the work of the male starring in his favorite show, which was on after Chiquita Jalapeno's show. Ruth's favorite show was the last one on.\n\r\n4. The show starring Chiquita Jalapeno aired before CSI Podunk. Rosie McDougal's show and Cuddles in the Country aired one after the other in some order.\n\r\n5. The two shows airing at 8:00pm are the one starring Lily Gardens and Michael's favorite.", "hint": "No hint available.", "answer": "Isaac: CSI Podunk, 9:00pm, Rosie McDougal\r\nMelinda: Desolate Husbands, 8:00pm, Lily Gardens\r\nCharles: Cuddles in the Country, 8:30pm, Justin Time\r\nMichael: Wheel of Fate, 8:00pm, Chiquita Jalapeno\r\nRuth: Dr. Cure, 10:00pm, Chance Ripley", "category": "Logic-Grid", "date": "07/12/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends were discussing their favorite shows of the new television season. From the clues provided, determine each friend's favorite new show, the star of each show, and what time it aired (one was at 9:00pm).\n\r\nShows: CSI Podunk, Desolate Husbands, Wheel of Fate, Dr. Cure, Cuddles in the Country\n\r\nStars: \r\nMale- Justin Time, Chance Ripley\r\nFemale- Chiquita Jalapeno, Lily Gardens, Rosie McDougal \n\r\n1. Isaac's favorite show aired 1/2 hour after the one starring Justin Time but before Dr. Cure. Desolate Husbands aired either at 8:00pm or 10:00pm.\n\r\n2. The five shows are the one at 8:30pm, Melinda's favorite, the one starring Chance Ripley, CSI Podunk and Wheel of Fate. \n\r\n3. Charles really enjoyed the work of the male starring in his favorite show, which was on after Chiquita Jalapeno's show. Ruth's favorite show was the last one on.\n\r\n4. The show starring Chiquita Jalapeno aired before CSI Podunk. Rosie McDougal's show and Cuddles in the Country aired one after the other in some order.\n\r\n5. The two shows airing at 8:00pm are the one starring Lily Gardens and Michael's favorite.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIsaac: CSI Podunk, 9:00pm, Rosie McDougal\r\nMelinda: Desolate Husbands, 8:00pm, Lily Gardens\r\nCharles: Cuddles in the Country, 8:30pm, Justin Time\r\nMichael: Wheel of Fate, 8:00pm, Chiquita Jalapeno\r\nRuth: Dr. Cure, 10:00pm, Chance Ripley\n<|im_start|>answer\nIsaac: CSI Podunk, 9:00pm, Rosie McDougal\r\nMelinda: Desolate Husbands, 8:00pm, Lily Gardens\r\nCharles: Cuddles in the Country, 8:30pm, Justin Time\r\nMichael: Wheel of Fate, 8:00pm, Chiquita Jalapeno\r\nRuth: Dr. Cure, 10:00pm, Chance Ripley\n<|im_end|>" }, { "id": "#10917", "title": "A Prisoner", "fun": 2.48, "difficulty": 2.48, "author": "AllsatrASH08", "desc": "A prisoner sat alone in his cell staring through the bars at the six doors to the guardroom beyond them. Suddenly, there was the sound of footsteps. One guard came in through door A and a second entered through door F. They unlocked the cell door. \"We shall set you free,\" said one of the guards, \"but first you must pass through all six doors, each door once only, in the correct order. Three are entrances only and three are exits only. Door A must be followed by door B or E; B by C or E; C by D or F; D by A or F; E by B or D; and F by C or D.\" With that the guards left through door B. In what order must the prisoner pass through the doors?", "hint": "The prisoner must alternate exits and entrances. List the six possible orders then study the conditions to eliminate possibilities.", "answer": "The order is CFDABE. The guards entered through doors A and F and exited at door B. The prisoner must alternate exits and entrances. Let the unknown entrance be X. With a \"_\" denoting an exit door the possible orders are: \n\r\n(a) _A_F_X ; (b) _F_A_X ; (c) _X_A_F ; (d) _X_F_A ; (e) _A_X_F ; (f) _F_X_A \n\r\nNeither (a) nor (c) are possible since A is followed by B or E and neither leads to F. Since A can only be preceded by D, (e) and (f) are possible as DA_X_F and _F_XDA, respectively. With D used, door F can only be preceded by C to give DA_XCF and CF_XDA, respectively. Door B must occupy the remaining space in each possibility (third door is exit) so X=E but C cannot follow E in the former and for the latter, B cannot follow F. This eliminates (e) and (f). Since only D precedes A, (b) is possible as _FDA_X and (d) as _X_FDA. For (d), the exit B must occupy a \"_\" but cannot be followed by F, and if it is the first door, neither the C or E that must follow as X can be followed by the remaining E or C, respectively. This only leaves (b) and only C (of the possible B,C,E) can precede F as CFDA_X and B must occupy the final \"_\" as an exit leaving E=X. Notice that the condition that E is followed by B or D cannot be satisfied until the prisoner has completed his task and finally wins his freedom through B or D!", "category": "Logic", "date": "03/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA prisoner sat alone in his cell staring through the bars at the six doors to the guardroom beyond them. Suddenly, there was the sound of footsteps. One guard came in through door A and a second entered through door F. They unlocked the cell door. \"We shall set you free,\" said one of the guards, \"but first you must pass through all six doors, each door once only, in the correct order. Three are entrances only and three are exits only. Door A must be followed by door B or E; B by C or E; C by D or F; D by A or F; E by B or D; and F by C or D.\" With that the guards left through door B. In what order must the prisoner pass through the doors?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe order is CFDABE. The guards entered through doors A and F and exited at door B. The prisoner must alternate exits and entrances. Let the unknown entrance be X. With a \"_\" denoting an exit door the possible orders are: \n\r\n(a) _A_F_X ; (b) _F_A_X ; (c) _X_A_F ; (d) _X_F_A ; (e) _A_X_F ; (f) _F_X_A \n\r\nNeither (a) nor (c) are possible since A is followed by B or E and neither leads to F. Since A can only be preceded by D, (e) and (f) are possible as DA_X_F and _F_XDA, respectively. With D used, door F can only be preceded by C to give DA_XCF and CF_XDA, respectively. Door B must occupy the remaining space in each possibility (third door is exit) so X=E but C cannot follow E in the former and for the latter, B cannot follow F. This eliminates (e) and (f). Since only D precedes A, (b) is possible as _FDA_X and (d) as _X_FDA. For (d), the exit B must occupy a \"_\" but cannot be followed by F, and if it is the first door, neither the C or E that must follow as X can be followed by the remaining E or C, respectively. This only leaves (b) and only C (of the possible B,C,E) can precede F as CFDA_X and B must occupy the final \"_\" as an exit leaving E=X. Notice that the condition that E is followed by B or D cannot be satisfied until the prisoner has completed his task and finally wins his freedom through B or D!\n<|im_start|>answer\nThe order is CFDABE. The guards entered through doors A and F and exited at door B. The prisoner must alternate exits and entrances. Let the unknown entrance be X. With a \"_\" denoting an exit door the possible orders are: \n\r\n(a) _A_F_X ; (b) _F_A_X ; (c) _X_A_F ; (d) _X_F_A ; (e) _A_X_F ; (f) _F_X_A \n\r\nNeither (a) nor (c) are possible since A is followed by B or E and neither leads to F. Since A can only be preceded by D, (e) and (f) are possible as DA_X_F and _F_XDA, respectively. With D used, door F can only be preceded by C to give DA_XCF and CF_XDA, respectively. Door B must occupy the remaining space in each possibility (third door is exit) so X=E but C cannot follow E in the former and for the latter, B cannot follow F. This eliminates (e) and (f). Since only D precedes A, (b) is possible as _FDA_X and (d) as _X_FDA. For (d), the exit B must occupy a \"_\" but cannot be followed by F, and if it is the first door, neither the C or E that must follow as X can be followed by the remaining E or C, respectively. This only leaves (b) and only C (of the possible B,C,E) can precede F as CFDA_X and B must occupy the final \"_\" as an exit leaving E=X. Notice that the condition that E is followed by B or D cannot be satisfied until the prisoner has completed his task and finally wins his freedom through B or D!\n<|im_end|>" }, { "id": "#10001", "title": "MMMMM! Mosquitos!", "fun": 2.48, "difficulty": 1.51, "author": "Dave_13", "desc": "A bat ate 1050 mosquitos in four nights. Each night she ate 25 more than the night before. \n\r\nHow many mosquitos did the bat eat each night?", "hint": "No hint available.", "answer": "The bat ate 225 mosquitoes on the first night, 250 on the second night, 275 on the third night, and 300 on the fourth night. \r\nLet x represent the number of mosquitoes the bat ate on the first night. You know that the bat ate 25 more than this on the second night, or x + 25. On the third night, the bat ate 25 more mosquitoes, or x + 50. On the fourth night, the bat ate 25 more mosquitoes, or x + 75. You also know the total for all four nights was 1050. So, you can write this equation: \r\nx + (x + 25) + (x + 50) + (x + 75) = 1050 \n\r\nThis equation simplifies to: \n\r\n4x + 150 = 1050 \n\r\nSolving for x, \n\r\n4x = 900\r\nx = 225", "category": "Math", "date": "01/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bat ate 1050 mosquitos in four nights. Each night she ate 25 more than the night before. \n\r\nHow many mosquitos did the bat eat each night?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe bat ate 225 mosquitoes on the first night, 250 on the second night, 275 on the third night, and 300 on the fourth night. \r\nLet x represent the number of mosquitoes the bat ate on the first night. You know that the bat ate 25 more than this on the second night, or x + 25. On the third night, the bat ate 25 more mosquitoes, or x + 50. On the fourth night, the bat ate 25 more mosquitoes, or x + 75. You also know the total for all four nights was 1050. So, you can write this equation: \r\nx + (x + 25) + (x + 50) + (x + 75) = 1050 \n\r\nThis equation simplifies to: \n\r\n4x + 150 = 1050 \n\r\nSolving for x, \n\r\n4x = 900\r\nx = 225\n<|im_start|>answer\nThe bat ate 225 mosquitoes on the first night, 250 on the second night, 275 on the third night, and 300 on the fourth night. \r\nLet x represent the number of mosquitoes the bat ate on the first night. You know that the bat ate 25 more than this on the second night, or x + 25. On the third night, the bat ate 25 more mosquitoes, or x + 50. On the fourth night, the bat ate 25 more mosquitoes, or x + 75. You also know the total for all four nights was 1050. So, you can write this equation: \r\nx + (x + 25) + (x + 50) + (x + 75) = 1050 \n\r\nThis equation simplifies to: \n\r\n4x + 150 = 1050 \n\r\nSolving for x, \n\r\n4x = 900\r\nx = 225\n<|im_end|>" }, { "id": "#25583", "title": "Wood 2", "fun": 2.48, "difficulty": 2.24, "author": "ndnumber1fan", "desc": "A block of wood, in the form of a cuboid 4\" x 7\" x 14\", has all its six faces painted pink. If the wooden block is cut into 392 cubes of 1\" x 1\" x 1\", how many of these would have pink paint on them?", "hint": "No hint available.", "answer": "The 1\" x 1\" x 1\" cubes that do not have any pink paint on them will be at the core of the wooden block. This core will be 2\" x 5\" x 12\", and will contain 120 cubes. \n\r\nOut of a total of 392 cubes, there are 120 cubes without any pink paint on them. Therefore, the remaining 272 cubes will have one, two or three sides with pink paint on them, depending on whether they were at the face, edge or corner of the wooden block.", "category": "Math", "date": "08/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA block of wood, in the form of a cuboid 4\" x 7\" x 14\", has all its six faces painted pink. If the wooden block is cut into 392 cubes of 1\" x 1\" x 1\", how many of these would have pink paint on them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 1\" x 1\" x 1\" cubes that do not have any pink paint on them will be at the core of the wooden block. This core will be 2\" x 5\" x 12\", and will contain 120 cubes. \n\r\nOut of a total of 392 cubes, there are 120 cubes without any pink paint on them. Therefore, the remaining 272 cubes will have one, two or three sides with pink paint on them, depending on whether they were at the face, edge or corner of the wooden block.\n<|im_start|>answer\nThe 1\" x 1\" x 1\" cubes that do not have any pink paint on them will be at the core of the wooden block. This core will be 2\" x 5\" x 12\", and will contain 120 cubes. \n\r\nOut of a total of 392 cubes, there are 120 cubes without any pink paint on them. Therefore, the remaining 272 cubes will have one, two or three sides with pink paint on them, depending on whether they were at the face, edge or corner of the wooden block.\n<|im_end|>" }, { "id": "#2135", "title": "Native or Visitor", "fun": 2.48, "difficulty": 1.58, "author": "Cascas", "desc": "Natives lie and visitors tell the truth. I was having lunch with a salesman and I needed to know if he was a native or a visitor. Instead of asking him, I saw a woman beside us. I said \"Go ask the woman if she's a native or a visitor\". When he came back he said that she was a visitor. From the answer I knew if he was a visitor or a native. Which is he?", "hint": "No hint available.", "answer": "He is a visitor.\n\r\nIf she's a visitor, she would be honest and say so. If she's a native, she'd lie and say she's a visitor. So no matter what, we know that she'll say that she's a visitor. NOW for the man. We know that he says that she's a visitor, therefore he MUST be telling the truth and be a visitor. If he were lying, his response (regardless of what the woman is) would be that she is a native. Make sense?", "category": "Logic", "date": "01/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNatives lie and visitors tell the truth. I was having lunch with a salesman and I needed to know if he was a native or a visitor. Instead of asking him, I saw a woman beside us. I said \"Go ask the woman if she's a native or a visitor\". When he came back he said that she was a visitor. From the answer I knew if he was a visitor or a native. Which is he?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe is a visitor.\n\r\nIf she's a visitor, she would be honest and say so. If she's a native, she'd lie and say she's a visitor. So no matter what, we know that she'll say that she's a visitor. NOW for the man. We know that he says that she's a visitor, therefore he MUST be telling the truth and be a visitor. If he were lying, his response (regardless of what the woman is) would be that she is a native. Make sense?\n<|im_start|>answer\nHe is a visitor.\n\r\nIf she's a visitor, she would be honest and say so. If she's a native, she'd lie and say she's a visitor. So no matter what, we know that she'll say that she's a visitor. NOW for the man. We know that he says that she's a visitor, therefore he MUST be telling the truth and be a visitor. If he were lying, his response (regardless of what the woman is) would be that she is a native. Make sense?\n<|im_end|>" }, { "id": "#2859", "title": "Grooves", "fun": 2.48, "difficulty": 1.36, "author": "204_BLaZe_41", "desc": "How many grooves are there on each side of a standard 33 1/3 record album that has six songs on each side?", "hint": "No hint available.", "answer": "There is one groove on each side. When you put the needle on the album it follows one groove from the beginning to end. If there was more than one groove, the needle would stop at the end of each groove, which happens to be the situation when a needle finds a good scratch.", "category": "Logic", "date": "03/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many grooves are there on each side of a standard 33 1/3 record album that has six songs on each side?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere is one groove on each side. When you put the needle on the album it follows one groove from the beginning to end. If there was more than one groove, the needle would stop at the end of each groove, which happens to be the situation when a needle finds a good scratch.\n<|im_start|>answer\nThere is one groove on each side. When you put the needle on the album it follows one groove from the beginning to end. If there was more than one groove, the needle would stop at the end of each groove, which happens to be the situation when a needle finds a good scratch.\n<|im_end|>" }, { "id": "#14900", "title": "1000 Prime Numbers", "fun": 2.48, "difficulty": 1.82, "author": "jess1118", "desc": "Determine the ones place value of the product of the first 1000 prime numbers. (What number would be in the ones position if you multiplied all of the first 1000 prime numbers together?)", "hint": "All you need to know the first three prime numbers.", "answer": "ZERO. Any numbers multiplied by 2 and 5 (which are prime) result in a zero in the ones place.", "category": "Math", "date": "09/24/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDetermine the ones place value of the product of the first 1000 prime numbers. (What number would be in the ones position if you multiplied all of the first 1000 prime numbers together?)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZERO. Any numbers multiplied by 2 and 5 (which are prime) result in a zero in the ones place.\n<|im_start|>answer\nZERO. Any numbers multiplied by 2 and 5 (which are prime) result in a zero in the ones place.\n<|im_end|>" }, { "id": "#16949", "title": "Two Clocks 2", "fun": 2.48, "difficulty": 2.6, "author": "kalliann", "desc": "At midnight on Sunday, December 31st, Professor Lawrence set two of her analog clocks to the correct time. One of her clocks gains one minute every hour and the other loses two minutes every hour. \n\r\n1. When will the clocks next show the same time as each other? \n\r\n2. When will the clocks both show the correct time?", "hint": "No hint available.", "answer": "1. Midnight after 10 days, which is 240 hours later. They both show 4 o'clock, one clock has gained 240 minutes (4 hours) and the other has lost 480 minutes (8 hours).\n\r\n2. Midnight after 30 days, which is 720 hours later. They both now show 12 o'clock.", "category": "Math", "date": "03/09/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt midnight on Sunday, December 31st, Professor Lawrence set two of her analog clocks to the correct time. One of her clocks gains one minute every hour and the other loses two minutes every hour. \n\r\n1. When will the clocks next show the same time as each other? \n\r\n2. When will the clocks both show the correct time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Midnight after 10 days, which is 240 hours later. They both show 4 o'clock, one clock has gained 240 minutes (4 hours) and the other has lost 480 minutes (8 hours).\n\r\n2. Midnight after 30 days, which is 720 hours later. They both now show 12 o'clock.\n<|im_start|>answer\n1. Midnight after 10 days, which is 240 hours later. They both show 4 o'clock, one clock has gained 240 minutes (4 hours) and the other has lost 480 minutes (8 hours).\n\r\n2. Midnight after 30 days, which is 720 hours later. They both now show 12 o'clock.\n<|im_end|>" }, { "id": "#17943", "title": "Five Cards", "fun": 2.48, "difficulty": 3.18, "author": "Poker", "desc": "I was playing a game of five card draw poker with a bunch of logicians. By the time we had finished bidding and were just about to reveal our cards, I was pretty confident I would win of the four of us remaining. I had three nines, some face card (I can't remember what suit or even whether it was a jack, queen, or king) and a four. (Or was it a five? I can't remember.)\n\r\nI was even more sure when two of my opponents laid down their cards. One had a pair of fours and a pair of sevens, the other had a pair of twos and a pair of eights. My third opponent, however, laid down his five cards face down in a row. He said, \"I have a straight, and the cards are, from lowest to highest: a ten, a jack, a queen, a king, and an ace. I have at least one card of each of the four suits: clubs, spades, hearts, and diamonds. I am fairly certain that this is the winning hand, but I'm feeling generous today, and I will give a third of the pot to whoever can determine which suit I have two cards of.\n\r\nNow I know you can't figure it out without some clues. Here they are:\n\r\n1. The king is next to at least one diamond.\r\n2. The queen is next to exactly one heart.\r\n3. The jack is next to at least one spade, but is not next to any hearts.\r\n4. The ten is next to at least one club.\r\n5. The ace does not border any black cards, nor does it border any diamonds.\r\n6. My two cards of the same suit are not next to each other.\r\n7. Of the ten possible pairings of cards, only one pair, when removed, leaves three cards in ascending order from left to right.\r\n8. My ace is not the card on the far left.\"\n\r\nThere was a minute's silence. One of the other logicians said, \"I give up! There's no way to figure that out!\"\r\nThe other agreed. But I didn't. I had just figured out which suit he had two of.\n\r\nWhich suit is it?", "hint": "The first step is to determine where the ace goes.\n\r\nAlso, consider this: How could I have figured it out when two expert logicians couldn't?", "answer": "The two cards on the ends and the card in the middle border a combined number of two suits. So at least one pair of them should be listed as bordering a card of the same suit in clues 1-5. Of the five, only the ace and the queen meet this criterion, so they must be two cards apart. One of them must be in the center, but it can't be the ace (the two cards on the ends would only border hearts - and one of them has to be bordering something else from clues 1-4), so it must be the queen. The ace is not on the left end from clue 8, so it must be on the right end, and the card next to it must be a heart. So far we have this(X represents unknown):\r\nX X Q X A\r\nX X X H X\r\nAt least one of the two cards to the left of the queen is lower than the queen (two of the remaining cards are lower, and only one can be right of the queen), so the triplet that is in ascending order is the queen, the ace, and the single card to the left of the queen that is lower than the queen. That means the king is left of the queen, and is also left of both the jack and the ten (otherwise, jack king ace or ten king ace would be a second triplet), so it must be on the far left. The jack must be left of the ten (or else ten jack ace would be a second triplet), so it must be second from the left, and the ten must be second from the right. The only card next to the king is the jack of diamonds (it's a diamond from clue 1). So far we have(T is ten):\r\nK J Q T A\r\nX D X H X\r\nNow we seem to be stuck. We don't have any more clues that can be used. So how did I figure it out?\r\nI held a face card (I said so myself in the intro). I must have known it cannot be that card and deduced the correct answer from there.\r\nBut which card did I have? We already know the suit of the jack, so my holding a jack would not help. Could I have held a queen? No, because I know the queen to either be a spade or club (clue 6), so one of the cards next to the queen would have its clue satisfied (see clues 3 and 4), and I could not determine the suit of the card on the other side of it.\r\nTherefore, I must have held a king. But which king? I know the king is not a diamond (clue 6) or a heart (clue 3). If I held the king of clubs, then the king next to the jack would have satisfied the jack's clue, and I could not have determine the suit of either card next to the ten.\r\nTherefore, I held the king of spades. The king of clubs must have been on the far left (only suit available), so the only card next to the jack that could be a spade is the queen, so the only card next to the ten that could be a club is the ace. In summary:\r\nK J Q T A\r\nC D S H C\r\nTherefore there are two CLUBS.", "category": "Logic", "date": "06/17/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was playing a game of five card draw poker with a bunch of logicians. By the time we had finished bidding and were just about to reveal our cards, I was pretty confident I would win of the four of us remaining. I had three nines, some face card (I can't remember what suit or even whether it was a jack, queen, or king) and a four. (Or was it a five? I can't remember.)\n\r\nI was even more sure when two of my opponents laid down their cards. One had a pair of fours and a pair of sevens, the other had a pair of twos and a pair of eights. My third opponent, however, laid down his five cards face down in a row. He said, \"I have a straight, and the cards are, from lowest to highest: a ten, a jack, a queen, a king, and an ace. I have at least one card of each of the four suits: clubs, spades, hearts, and diamonds. I am fairly certain that this is the winning hand, but I'm feeling generous today, and I will give a third of the pot to whoever can determine which suit I have two cards of.\n\r\nNow I know you can't figure it out without some clues. Here they are:\n\r\n1. The king is next to at least one diamond.\r\n2. The queen is next to exactly one heart.\r\n3. The jack is next to at least one spade, but is not next to any hearts.\r\n4. The ten is next to at least one club.\r\n5. The ace does not border any black cards, nor does it border any diamonds.\r\n6. My two cards of the same suit are not next to each other.\r\n7. Of the ten possible pairings of cards, only one pair, when removed, leaves three cards in ascending order from left to right.\r\n8. My ace is not the card on the far left.\"\n\r\nThere was a minute's silence. One of the other logicians said, \"I give up! There's no way to figure that out!\"\r\nThe other agreed. But I didn't. I had just figured out which suit he had two of.\n\r\nWhich suit is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two cards on the ends and the card in the middle border a combined number of two suits. So at least one pair of them should be listed as bordering a card of the same suit in clues 1-5. Of the five, only the ace and the queen meet this criterion, so they must be two cards apart. One of them must be in the center, but it can't be the ace (the two cards on the ends would only border hearts - and one of them has to be bordering something else from clues 1-4), so it must be the queen. The ace is not on the left end from clue 8, so it must be on the right end, and the card next to it must be a heart. So far we have this(X represents unknown):\r\nX X Q X A\r\nX X X H X\r\nAt least one of the two cards to the left of the queen is lower than the queen (two of the remaining cards are lower, and only one can be right of the queen), so the triplet that is in ascending order is the queen, the ace, and the single card to the left of the queen that is lower than the queen. That means the king is left of the queen, and is also left of both the jack and the ten (otherwise, jack king ace or ten king ace would be a second triplet), so it must be on the far left. The jack must be left of the ten (or else ten jack ace would be a second triplet), so it must be second from the left, and the ten must be second from the right. The only card next to the king is the jack of diamonds (it's a diamond from clue 1). So far we have(T is ten):\r\nK J Q T A\r\nX D X H X\r\nNow we seem to be stuck. We don't have any more clues that can be used. So how did I figure it out?\r\nI held a face card (I said so myself in the intro). I must have known it cannot be that card and deduced the correct answer from there.\r\nBut which card did I have? We already know the suit of the jack, so my holding a jack would not help. Could I have held a queen? No, because I know the queen to either be a spade or club (clue 6), so one of the cards next to the queen would have its clue satisfied (see clues 3 and 4), and I could not determine the suit of the card on the other side of it.\r\nTherefore, I must have held a king. But which king? I know the king is not a diamond (clue 6) or a heart (clue 3). If I held the king of clubs, then the king next to the jack would have satisfied the jack's clue, and I could not have determine the suit of either card next to the ten.\r\nTherefore, I held the king of spades. The king of clubs must have been on the far left (only suit available), so the only card next to the jack that could be a spade is the queen, so the only card next to the ten that could be a club is the ace. In summary:\r\nK J Q T A\r\nC D S H C\r\nTherefore there are two CLUBS.\n<|im_start|>answer\nThe two cards on the ends and the card in the middle border a combined number of two suits. So at least one pair of them should be listed as bordering a card of the same suit in clues 1-5. Of the five, only the ace and the queen meet this criterion, so they must be two cards apart. One of them must be in the center, but it can't be the ace (the two cards on the ends would only border hearts - and one of them has to be bordering something else from clues 1-4), so it must be the queen. The ace is not on the left end from clue 8, so it must be on the right end, and the card next to it must be a heart. So far we have this(X represents unknown):\r\nX X Q X A\r\nX X X H X\r\nAt least one of the two cards to the left of the queen is lower than the queen (two of the remaining cards are lower, and only one can be right of the queen), so the triplet that is in ascending order is the queen, the ace, and the single card to the left of the queen that is lower than the queen. That means the king is left of the queen, and is also left of both the jack and the ten (otherwise, jack king ace or ten king ace would be a second triplet), so it must be on the far left. The jack must be left of the ten (or else ten jack ace would be a second triplet), so it must be second from the left, and the ten must be second from the right. The only card next to the king is the jack of diamonds (it's a diamond from clue 1). So far we have(T is ten):\r\nK J Q T A\r\nX D X H X\r\nNow we seem to be stuck. We don't have any more clues that can be used. So how did I figure it out?\r\nI held a face card (I said so myself in the intro). I must have known it cannot be that card and deduced the correct answer from there.\r\nBut which card did I have? We already know the suit of the jack, so my holding a jack would not help. Could I have held a queen? No, because I know the queen to either be a spade or club (clue 6), so one of the cards next to the queen would have its clue satisfied (see clues 3 and 4), and I could not determine the suit of the card on the other side of it.\r\nTherefore, I must have held a king. But which king? I know the king is not a diamond (clue 6) or a heart (clue 3). If I held the king of clubs, then the king next to the jack would have satisfied the jack's clue, and I could not have determine the suit of either card next to the ten.\r\nTherefore, I held the king of spades. The king of clubs must have been on the far left (only suit available), so the only card next to the jack that could be a spade is the queen, so the only card next to the ten that could be a club is the ace. In summary:\r\nK J Q T A\r\nC D S H C\r\nTherefore there are two CLUBS.\n<|im_end|>" }, { "id": "#14682", "title": "Cleverest in the Land", "fun": 2.48, "difficulty": 2.54, "author": "Smithy", "desc": "In the village of Einstown, every villager thought they were the cleverest. They used to argue about it all the time, so eventually the leader devised a clever plan. He pretended to hold a vote for who was the cleverest person, where people had to nominate other villagers to go up to the vote. Everyone in the village would know of everyone nominated except themselves, and they all knew that at least one person got nominated.\n\r\nOnce the nominations were over the leader announced his plan. He said that the first person to come forward and say that they were nominated with proof would be the cleverest person in the village. He told them to go to the village hall at exactly 7:00 pm once they had worked it out. None of the people told each other if they got nominated, as they all wanted to win.\n\r\nAfter the first night nobody had come forward. Nobody came forward on the second night either. Nor the third, fourth fifth etc. Eventually on the 30th night a certain number of people came forward claiming to have been nominated. They were all right.\n\r\nHow many people came forward on the 30th night and why? (Assume that they all were clever enough to work the method out).", "hint": "No hint available.", "answer": "Call the number of people nominated N.\n\r\nAny person nominated would know of N-1 people nominated, as they would not know that they themselves were nominated. If there was 1 person nominated, the nominee would know of nobody who was nominated, and therefore would know that they were nominated. Because nobody came forward on the first night there was more than one person nominated.\n\r\nUsing the same logic, anyone on the second night who knew of one person nominated would then be able to work out that they were nominated as there was at least two people. Because nobody came forward on the second night there was at least three.\n\r\nThis carries on all the way up. Nobody came forward on the 29th night, meaning there was at least thirty. People now came forward the next night, so everyone who came forward knew of 29 nominees, meaning 30 people came forward on the 30th night.", "category": "Logic", "date": "09/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the village of Einstown, every villager thought they were the cleverest. They used to argue about it all the time, so eventually the leader devised a clever plan. He pretended to hold a vote for who was the cleverest person, where people had to nominate other villagers to go up to the vote. Everyone in the village would know of everyone nominated except themselves, and they all knew that at least one person got nominated.\n\r\nOnce the nominations were over the leader announced his plan. He said that the first person to come forward and say that they were nominated with proof would be the cleverest person in the village. He told them to go to the village hall at exactly 7:00 pm once they had worked it out. None of the people told each other if they got nominated, as they all wanted to win.\n\r\nAfter the first night nobody had come forward. Nobody came forward on the second night either. Nor the third, fourth fifth etc. Eventually on the 30th night a certain number of people came forward claiming to have been nominated. They were all right.\n\r\nHow many people came forward on the 30th night and why? (Assume that they all were clever enough to work the method out).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCall the number of people nominated N.\n\r\nAny person nominated would know of N-1 people nominated, as they would not know that they themselves were nominated. If there was 1 person nominated, the nominee would know of nobody who was nominated, and therefore would know that they were nominated. Because nobody came forward on the first night there was more than one person nominated.\n\r\nUsing the same logic, anyone on the second night who knew of one person nominated would then be able to work out that they were nominated as there was at least two people. Because nobody came forward on the second night there was at least three.\n\r\nThis carries on all the way up. Nobody came forward on the 29th night, meaning there was at least thirty. People now came forward the next night, so everyone who came forward knew of 29 nominees, meaning 30 people came forward on the 30th night.\n<|im_start|>answer\nCall the number of people nominated N.\n\r\nAny person nominated would know of N-1 people nominated, as they would not know that they themselves were nominated. If there was 1 person nominated, the nominee would know of nobody who was nominated, and therefore would know that they were nominated. Because nobody came forward on the first night there was more than one person nominated.\n\r\nUsing the same logic, anyone on the second night who knew of one person nominated would then be able to work out that they were nominated as there was at least two people. Because nobody came forward on the second night there was at least three.\n\r\nThis carries on all the way up. Nobody came forward on the 29th night, meaning there was at least thirty. People now came forward the next night, so everyone who came forward knew of 29 nominees, meaning 30 people came forward on the 30th night.\n<|im_end|>" }, { "id": "#39963", "title": "Number Hang-up", "fun": 2.48, "difficulty": 1.56, "author": "icestar12", "desc": "The owner of a motel with 100 rooms wants the room doors numbered in order from 1 to 100. She asks you to buy numbers and hang them on the doors. Now you must go to the store and buy all the digits you need to make the numbers.\n\r\nHow many of each digit, 0 to 9, must you buy?", "hint": "No hint available.", "answer": "You will need twenty-one 1s, twenty each of 2 through 9, and eleven 0s.", "category": "Math", "date": "01/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe owner of a motel with 100 rooms wants the room doors numbered in order from 1 to 100. She asks you to buy numbers and hang them on the doors. Now you must go to the store and buy all the digits you need to make the numbers.\n\r\nHow many of each digit, 0 to 9, must you buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou will need twenty-one 1s, twenty each of 2 through 9, and eleven 0s.\n<|im_start|>answer\nYou will need twenty-one 1s, twenty each of 2 through 9, and eleven 0s.\n<|im_end|>" }, { "id": "#4837", "title": "Fred, Ed & Ned", "fun": 2.48, "difficulty": 1.08, "author": "Charliesangel", "desc": "Fred, Ed & Ned head off into town to do their weekly chores.\n\r\nFred has to get a pair of shoes re-soled.\r\nEd has to get duplicates for three keys.\r\nNed needs two pairs of shoes to be resoled.\n\r\nThey find a shop that cuts keys and resoles shoes and had two members of staff that were not busy.\n\r\nThe shop advertises:\n\r\nKeys cut for $2 only takes five minutes\r\nShoes resoled $10 per pair only takes fifteen minutes.\n\r\nHow long do Fred, Ed and Ned have to wait to get their items back finished?", "hint": "No hint available.", "answer": "30 Minutes (one assistant does Fred's shoes and Ed's keys and the other does Ned's two pairs of shoes.", "category": "Logic", "date": "06/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred, Ed & Ned head off into town to do their weekly chores.\n\r\nFred has to get a pair of shoes re-soled.\r\nEd has to get duplicates for three keys.\r\nNed needs two pairs of shoes to be resoled.\n\r\nThey find a shop that cuts keys and resoles shoes and had two members of staff that were not busy.\n\r\nThe shop advertises:\n\r\nKeys cut for $2 only takes five minutes\r\nShoes resoled $10 per pair only takes fifteen minutes.\n\r\nHow long do Fred, Ed and Ned have to wait to get their items back finished?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n30 Minutes (one assistant does Fred's shoes and Ed's keys and the other does Ned's two pairs of shoes.\n<|im_start|>answer\n30 Minutes (one assistant does Fred's shoes and Ed's keys and the other does Ned's two pairs of shoes.\n<|im_end|>" }, { "id": "#4619", "title": "Shipwrecked", "fun": 2.48, "difficulty": 1.4, "author": "mad-ade", "desc": "There was a shipwreck at sea and Mad Ade, Smelly O'Riley and Elvis impersonator Tavish McPresley were washed ashore on a small island. Reaching the shore, exhausted, they all fell asleep.\n\r\nMad Ade woke first (whilst having a glorious dream about living in a land where Kebabs were served every meal, and twice for breakfast), and saw that a box of bananas had been washed ashore. Being greedy as he is, he ate one third of the bananas and went back to sleep to continue his Kebab related dreams. \n\r\nNext, Smelly O'Riley woke up, and seeing the box of bananas, ate one third of what was left and went back to sleep. \n\r\nTavish McPresley woke up next and assumed that the other two hadn't eaten any bananas, so he ate one third of what remained. \n\r\nWhen Tavish McPresley had finished, there were eight bananas left over. How many bananas were in the box originally?", "hint": "No hint available.", "answer": "27\n\r\nSolution:\r\nWhen Tavish finished, the remaining 8 bananas represented 2/3 of the amount that had existed when he started (so each 1/3 = 4). Therefore there were 12 bananas (4 + 4 + 4)when he started, and when Smelly O'Riley finished. \n\r\nFollowing the same logic, the remaining 12 bananas represented 2/3 of the amount that had existed when Smelly O'Riley started (and each 1/3 = 6). Therefore there were 18 bananas (6 + 6 + 6) when he started, and when Mad Ade finished.\n\r\nAgain, following the same logic, the remaining 18 bananas represented 2/3 of the amount that had existed when Mad Ade started (and each 1/3 = 9). So, there must have been 27 (9 + 9 + 9) bananas originally.", "category": "Logic", "date": "06/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a shipwreck at sea and Mad Ade, Smelly O'Riley and Elvis impersonator Tavish McPresley were washed ashore on a small island. Reaching the shore, exhausted, they all fell asleep.\n\r\nMad Ade woke first (whilst having a glorious dream about living in a land where Kebabs were served every meal, and twice for breakfast), and saw that a box of bananas had been washed ashore. Being greedy as he is, he ate one third of the bananas and went back to sleep to continue his Kebab related dreams. \n\r\nNext, Smelly O'Riley woke up, and seeing the box of bananas, ate one third of what was left and went back to sleep. \n\r\nTavish McPresley woke up next and assumed that the other two hadn't eaten any bananas, so he ate one third of what remained. \n\r\nWhen Tavish McPresley had finished, there were eight bananas left over. How many bananas were in the box originally?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n27\n\r\nSolution:\r\nWhen Tavish finished, the remaining 8 bananas represented 2/3 of the amount that had existed when he started (so each 1/3 = 4). Therefore there were 12 bananas (4 + 4 + 4)when he started, and when Smelly O'Riley finished. \n\r\nFollowing the same logic, the remaining 12 bananas represented 2/3 of the amount that had existed when Smelly O'Riley started (and each 1/3 = 6). Therefore there were 18 bananas (6 + 6 + 6) when he started, and when Mad Ade finished.\n\r\nAgain, following the same logic, the remaining 18 bananas represented 2/3 of the amount that had existed when Mad Ade started (and each 1/3 = 9). So, there must have been 27 (9 + 9 + 9) bananas originally.\n<|im_start|>answer\n27\n\r\nSolution:\r\nWhen Tavish finished, the remaining 8 bananas represented 2/3 of the amount that had existed when he started (so each 1/3 = 4). Therefore there were 12 bananas (4 + 4 + 4)when he started, and when Smelly O'Riley finished. \n\r\nFollowing the same logic, the remaining 12 bananas represented 2/3 of the amount that had existed when Smelly O'Riley started (and each 1/3 = 6). Therefore there were 18 bananas (6 + 6 + 6) when he started, and when Mad Ade finished.\n\r\nAgain, following the same logic, the remaining 18 bananas represented 2/3 of the amount that had existed when Mad Ade started (and each 1/3 = 9). So, there must have been 27 (9 + 9 + 9) bananas originally.\n<|im_end|>" }, { "id": "#23795", "title": "Avg Salary ??", "fun": 2.48, "difficulty": 2.31, "author": "vetriselvan", "desc": "Three coworkers would like to know their average salary. \r\nHowever, they are self-conscious and don't want to tell each other their own salaries, for fear of either being ridiculed or getting their houses robbed. How can they find their average salary, without disclosing their own salaries?", "hint": "No hint available.", "answer": "Guy 1 adds a constant to his salary and tells guy 2. Guy 2 adds his salary and tells Guy 3. Guy 3 adds his salary and tells Guy 1. Guy 1 subtracts the original constant and then divides by 3 to get the average.", "category": "Math", "date": "06/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree coworkers would like to know their average salary. \r\nHowever, they are self-conscious and don't want to tell each other their own salaries, for fear of either being ridiculed or getting their houses robbed. How can they find their average salary, without disclosing their own salaries?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGuy 1 adds a constant to his salary and tells guy 2. Guy 2 adds his salary and tells Guy 3. Guy 3 adds his salary and tells Guy 1. Guy 1 subtracts the original constant and then divides by 3 to get the average.\n<|im_start|>answer\nGuy 1 adds a constant to his salary and tells guy 2. Guy 2 adds his salary and tells Guy 3. Guy 3 adds his salary and tells Guy 1. Guy 1 subtracts the original constant and then divides by 3 to get the average.\n<|im_end|>" }, { "id": "#4749", "title": "Balancing Beams", "fun": 2.48, "difficulty": 2.49, "author": "bobbrt", "desc": "The following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nYou have three heavy beams marked A, B, and C, and want to find out which one is the heaviest. You also have a scale that tells you which of any two beams is heavier, but it does not give the specific weight of any beam. In what order must you perform the following steps to determine which beam is the heaviest, and to mark it accordingly? Assume that all three have different weights.\n\r\na) Weigh A against B.\r\nb) Weigh B against C.\r\nc) Weigh A against C.\r\nd) If A is heavier, skip the next three statements.\r\ne) If A is heavier, skip the next four statements.\r\nf) If B is heavier, skip the next five statements.\r\ng) Mark A \"heaviest.\"\r\nh) Mark B \"heaviest.\"\r\ni) Mark C \"heaviest.\"\r\nj) Skip the next statement.\r\nk) Skip the next two statements.\r\nl) Skip the next three statements.\r\nm) End.", "hint": "The first two steps are \"a\" and \"d\", in that order.", "answer": "a) Weigh A against B.\r\nd) If A is heavier, skip the next three statements.\r\nb) Weigh B against C.\r\nf) If B is heavier, skip the next five statements.\r\nk) Skip the next two statements.\r\nc) Weigh A against C.\r\ne) If A is heavier, skip the next four statements.\r\ni) Mark C \"heaviest.\"\r\nl) Skip the next three statements.\r\nh) Mark B \"heaviest.\"\r\nj) Skip the next statement.\r\ng) Mark A \"heaviest.\"\r\nm) End.", "category": "Logic", "date": "06/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nYou have three heavy beams marked A, B, and C, and want to find out which one is the heaviest. You also have a scale that tells you which of any two beams is heavier, but it does not give the specific weight of any beam. In what order must you perform the following steps to determine which beam is the heaviest, and to mark it accordingly? Assume that all three have different weights.\n\r\na) Weigh A against B.\r\nb) Weigh B against C.\r\nc) Weigh A against C.\r\nd) If A is heavier, skip the next three statements.\r\ne) If A is heavier, skip the next four statements.\r\nf) If B is heavier, skip the next five statements.\r\ng) Mark A \"heaviest.\"\r\nh) Mark B \"heaviest.\"\r\ni) Mark C \"heaviest.\"\r\nj) Skip the next statement.\r\nk) Skip the next two statements.\r\nl) Skip the next three statements.\r\nm) End.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) Weigh A against B.\r\nd) If A is heavier, skip the next three statements.\r\nb) Weigh B against C.\r\nf) If B is heavier, skip the next five statements.\r\nk) Skip the next two statements.\r\nc) Weigh A against C.\r\ne) If A is heavier, skip the next four statements.\r\ni) Mark C \"heaviest.\"\r\nl) Skip the next three statements.\r\nh) Mark B \"heaviest.\"\r\nj) Skip the next statement.\r\ng) Mark A \"heaviest.\"\r\nm) End.\n<|im_start|>answer\na) Weigh A against B.\r\nd) If A is heavier, skip the next three statements.\r\nb) Weigh B against C.\r\nf) If B is heavier, skip the next five statements.\r\nk) Skip the next two statements.\r\nc) Weigh A against C.\r\ne) If A is heavier, skip the next four statements.\r\ni) Mark C \"heaviest.\"\r\nl) Skip the next three statements.\r\nh) Mark B \"heaviest.\"\r\nj) Skip the next statement.\r\ng) Mark A \"heaviest.\"\r\nm) End.\n<|im_end|>" }, { "id": "#48739", "title": "Marathon Race", "fun": 2.48, "difficulty": 1.21, "author": "shenqiang", "desc": "Takashi took part in a marathon race.\n\r\nAt half-time, he is 6th last. After that, he is overtaken by three more contestants, but then he struggled and overtook 10 in a row, getting himself the bronze prize (3rd place).\n\r\nHow many contestants were there in total?", "hint": "Try to work backwards.", "answer": "15.", "category": "Math", "date": "05/26/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTakashi took part in a marathon race.\n\r\nAt half-time, he is 6th last. After that, he is overtaken by three more contestants, but then he struggled and overtook 10 in a row, getting himself the bronze prize (3rd place).\n\r\nHow many contestants were there in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15.\n<|im_start|>answer\n15.\n<|im_end|>" }, { "id": "#26911", "title": "The Examination", "fun": 2.48, "difficulty": 2.15, "author": "shenqiang", "desc": "Bab, Beb, Bib, Bob and Bub took part in an examination. There were five subjects: biology, history, maths, physics, and geography. Use the clues below to find who got how many points in which subject.\n\r\n1. Every subject awarded each pupil with a different score between 1 - 5.\r\n2. Bab got the highest total score, which was 24 points. Beb got second, Bib third, Bob fourth, and Bub last. No two of them got the same total score.\r\n3. Bib got the same number of points in 4 subjects.\r\n4. Bob got 4 points in history.\r\n5. Bub got 3 points in biology and 5 points in physics.", "hint": "There's only one answer to this teaser, but neither maths nor geography was mentioned in the clues. What would that mean?", "answer": "Bab got 4 points in physics, and 5 points in the other four subjects.\r\nBeb got 2 points in history, 1 point in physics, and 4 points in the other three subjects.\r\nBib got 1 point in biology and 3 points in the other four subjects.\r\nBob got 4 points in history and 2 points in the other four subjects.\r\nBub got 3 points in biology, 5 points in physics, and 1 point in the other three subjects.", "category": "Logic", "date": "11/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBab, Beb, Bib, Bob and Bub took part in an examination. There were five subjects: biology, history, maths, physics, and geography. Use the clues below to find who got how many points in which subject.\n\r\n1. Every subject awarded each pupil with a different score between 1 - 5.\r\n2. Bab got the highest total score, which was 24 points. Beb got second, Bib third, Bob fourth, and Bub last. No two of them got the same total score.\r\n3. Bib got the same number of points in 4 subjects.\r\n4. Bob got 4 points in history.\r\n5. Bub got 3 points in biology and 5 points in physics.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBab got 4 points in physics, and 5 points in the other four subjects.\r\nBeb got 2 points in history, 1 point in physics, and 4 points in the other three subjects.\r\nBib got 1 point in biology and 3 points in the other four subjects.\r\nBob got 4 points in history and 2 points in the other four subjects.\r\nBub got 3 points in biology, 5 points in physics, and 1 point in the other three subjects.\n<|im_start|>answer\nBab got 4 points in physics, and 5 points in the other four subjects.\r\nBeb got 2 points in history, 1 point in physics, and 4 points in the other three subjects.\r\nBib got 1 point in biology and 3 points in the other four subjects.\r\nBob got 4 points in history and 2 points in the other four subjects.\r\nBub got 3 points in biology, 5 points in physics, and 1 point in the other three subjects.\n<|im_end|>" }, { "id": "#42930", "title": "Katie's Arcade Party", "fun": 2.48, "difficulty": 1.41, "author": "TRILLIONAIRE", "desc": "For Katie's birthday, her dad took her and three friends to the arcade for an evening of fun and games. The kids spent the evening competing with each other for the highest scores on their favorite arcade games. Determine the full name of each friend, each friend's favorite arcade game, and the game on which each friend achieved the highest score.\n\r\n1. Smithy's favorite game is not Ultimate Checkers. The kid whose last name is Harmie scored highest in Tetris. Katie's last name isn't Moose.\n\r\n2. The favorite game of the kid who scored highest in Ultimate Chess was Battleship.\n\r\n3. Demi's favorite wasn't RoboZapper. Katie's last name isn't Cratic.\n\r\n4. Smithy scored highest in Twiddle. Billybob's favorite was Ultimate Checkers.\n\r\n5. The kid who scored highest in Ultimate Chess wasn't Katie. The kid whose favorite game was Disco doesn't have a last name of Thorton.\n\r\n6. RoboZapper was the favorite game of the kid whose last name is Moose. The kid whose last name is Cratic didn't get the high score in Pac-Man.", "hint": "The one whose favorite game is Battleship got the high score with Ultimate Chess.", "answer": "Full Name ~~ Fav. Game ~~ High Score\n\r\nKatie Harmie ~~ Disco ~~ Tetris\r\nBillybob Thorton ~~ Ultimate Checkers ~~ Pac-Man\r\nSmithy Moose ~~ RoboZapper ~~ Twiddle\r\nDemi Cratic ~~ Battleship ~~ Ultimate Chess", "category": "Logic-Grid", "date": "08/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor Katie's birthday, her dad took her and three friends to the arcade for an evening of fun and games. The kids spent the evening competing with each other for the highest scores on their favorite arcade games. Determine the full name of each friend, each friend's favorite arcade game, and the game on which each friend achieved the highest score.\n\r\n1. Smithy's favorite game is not Ultimate Checkers. The kid whose last name is Harmie scored highest in Tetris. Katie's last name isn't Moose.\n\r\n2. The favorite game of the kid who scored highest in Ultimate Chess was Battleship.\n\r\n3. Demi's favorite wasn't RoboZapper. Katie's last name isn't Cratic.\n\r\n4. Smithy scored highest in Twiddle. Billybob's favorite was Ultimate Checkers.\n\r\n5. The kid who scored highest in Ultimate Chess wasn't Katie. The kid whose favorite game was Disco doesn't have a last name of Thorton.\n\r\n6. RoboZapper was the favorite game of the kid whose last name is Moose. The kid whose last name is Cratic didn't get the high score in Pac-Man.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFull Name ~~ Fav. Game ~~ High Score\n\r\nKatie Harmie ~~ Disco ~~ Tetris\r\nBillybob Thorton ~~ Ultimate Checkers ~~ Pac-Man\r\nSmithy Moose ~~ RoboZapper ~~ Twiddle\r\nDemi Cratic ~~ Battleship ~~ Ultimate Chess\n<|im_start|>answer\nFull Name ~~ Fav. Game ~~ High Score\n\r\nKatie Harmie ~~ Disco ~~ Tetris\r\nBillybob Thorton ~~ Ultimate Checkers ~~ Pac-Man\r\nSmithy Moose ~~ RoboZapper ~~ Twiddle\r\nDemi Cratic ~~ Battleship ~~ Ultimate Chess\n<|im_end|>" }, { "id": "#44572", "title": "Memorial Day Parade", "fun": 2.48, "difficulty": 1.42, "author": "mrsfessler", "desc": "Jessie, Amanda, Rudolph, Ben, and Lindsey participated in their city's annual Memorial Day parade. From the clues provided, determine each person's full name (one last name is Adams), what unit they were with (one is the Air Force), and what order they were in.\n\r\n1. The clowns marched after the band but before the antique cars. Jessie and Lindsey were in the 3rd and 4th units in some order. \r\n2. Rudolph and Mr. Delaney both wore their uniforms with pride. Ms. Carver's Model T wasn't the 3rd unit. \r\n3. The 5 participants were Rudolph, the trumpet player, Senator Estepp, the last unit, and Ms. Baker. \r\n4. Jessie was glad he was between the band and the clowns. \r\n5. The band, the politician, and Ms. Baker did not march 1st or last.", "hint": "No hint available.", "answer": "Jessie Estepp, politicians, 3rd\r\nAmanda Carver, antique cars, 5th\r\nRudolph Adams, Air Force, 1st\r\nBen Delaney, band, 2nd\r\nLindsey Baker, clowns, 4th", "category": "Logic-Grid", "date": "06/03/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJessie, Amanda, Rudolph, Ben, and Lindsey participated in their city's annual Memorial Day parade. From the clues provided, determine each person's full name (one last name is Adams), what unit they were with (one is the Air Force), and what order they were in.\n\r\n1. The clowns marched after the band but before the antique cars. Jessie and Lindsey were in the 3rd and 4th units in some order. \r\n2. Rudolph and Mr. Delaney both wore their uniforms with pride. Ms. Carver's Model T wasn't the 3rd unit. \r\n3. The 5 participants were Rudolph, the trumpet player, Senator Estepp, the last unit, and Ms. Baker. \r\n4. Jessie was glad he was between the band and the clowns. \r\n5. The band, the politician, and Ms. Baker did not march 1st or last.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJessie Estepp, politicians, 3rd\r\nAmanda Carver, antique cars, 5th\r\nRudolph Adams, Air Force, 1st\r\nBen Delaney, band, 2nd\r\nLindsey Baker, clowns, 4th\n<|im_start|>answer\nJessie Estepp, politicians, 3rd\r\nAmanda Carver, antique cars, 5th\r\nRudolph Adams, Air Force, 1st\r\nBen Delaney, band, 2nd\r\nLindsey Baker, clowns, 4th\n<|im_end|>" }, { "id": "#14902", "title": "The Rabbit and Kangaroo Race", "fun": 2.48, "difficulty": 1.81, "author": "jess1118", "desc": "A rabbit and a kangaroo decide to have a race. Their course was 100 feet up and back (200 feet total). The rabbit only jumps in sets of three jumps of 2 feet each in the same time that the kangaroo only makes two jumps of a yard each. Who won the race?", "hint": "It was NOT a tie.", "answer": "The rabbit won the race by four feet. Even though they were jumping in increments of six, the Kangaroo was mid jump on the 100 yard mark. In order for the Kangaroo to turn around he had to go past the halfway mark 2 feet and back 2 feet.", "category": "Math", "date": "09/25/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA rabbit and a kangaroo decide to have a race. Their course was 100 feet up and back (200 feet total). The rabbit only jumps in sets of three jumps of 2 feet each in the same time that the kangaroo only makes two jumps of a yard each. Who won the race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe rabbit won the race by four feet. Even though they were jumping in increments of six, the Kangaroo was mid jump on the 100 yard mark. In order for the Kangaroo to turn around he had to go past the halfway mark 2 feet and back 2 feet.\n<|im_start|>answer\nThe rabbit won the race by four feet. Even though they were jumping in increments of six, the Kangaroo was mid jump on the 100 yard mark. In order for the Kangaroo to turn around he had to go past the halfway mark 2 feet and back 2 feet.\n<|im_end|>" }, { "id": "#7963", "title": "Tammy's Age", "fun": 2.48, "difficulty": 3.0, "author": "snaps", "desc": "I was talking to a friend Tammy, the middle child of five. She has a younger sister Tracey, and three brothers Tommy (oldest child), Timmy and Tony (youngest child). I asked her how old she was, but she hardly ever gives a straight answer. The following is the conversation we had.\r\n\"How old are you Tammy?\"\r\n\"I am three times as old as Timmy was when Tony was born. Actually, it's funny, but Timmy's, Tracey's, Tommy's and my ages were all factors of Mum's age when Tony was born. The only other year where the ages of more than two of us were factors of Mum's age was when Tracey was half as old as I am now.\"\r\n\"How old is your Mum now?\"\r\n\"There's another funny thing. When Mum turns 50, Tony will be the same age Mum was when she gave birth to Tommy.\"\n\r\nAssuming Tammy was talking in terms of whole years, and with my mathematical and reasoning abilities I was able to quickly deduce not just Tammy's age, but all of their ages. So how old are Tommy, Timmy, Tammy, Tracey, Tony and Mum now?", "hint": "No hint available.", "answer": "Tommy is 23, Timmy is 19, Tammy is 18, Tracey is 16, Tony is 13 and Mum is 43.\n\r\nSolution:\r\nx = Mum's age when she gave birth to Tommy = Tony's age when Mum turns 50;\r\ny = Tommy's age when Tony was born\r\nz = Mum's age when Tony was born\n\r\nFrom Tammy's last statement, 2x + y = 50 and it can be deduced that x = z - y, where y is a factor of z. By combining the two equations you get 2z = 50 + y The only possible solutions for that equation so that y is also a factor of z are (z = 26, y = 2) and (z = 30, y = 10). Only 30 has four or more factors, so Mum was 30 and Tommy was 10 when Tony was born.\n\r\nThis means that of the remaining factors of 30, Timmy was 6, 5 or 3, Tammy was 5, 3 or 2 and Tracey was 3, 2 or 1. This makes Tammy 18, 15 or 9 now. The only other time where the ages of more than two of the children were factors of Mum's age was when Tracey was half what Tammy is now, so Tammy must be 18 now.\n\r\nIn the second multiple-factors-of-Mum's-age year, Tracey was therefore 9. When Tony was born, Tracey was either 3, 2 or 1, giving possible time differences of 6, 7 or 8 years, which correspond to Tony's age in the second multiple-factors-of-Mum's-age year. It also means Mum was 36, 37 or 38 that year. 37 is prime and 38 has factors of 1, 2 and 19, and as Tony was at least 6, it means that Mum must have been 36 that year.\n\r\nGoing back to when Tony was born we have that Mum was 30, Tommy was 10, Timmy was 6, Tracey was 3, and as the middle child Tammy must have been 5. If Tammy is 18 now then Tony is 13, Tracey is 16, Timmy is 19, Tommy is 23 and Mum is 43.", "category": "Math", "date": "10/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was talking to a friend Tammy, the middle child of five. She has a younger sister Tracey, and three brothers Tommy (oldest child), Timmy and Tony (youngest child). I asked her how old she was, but she hardly ever gives a straight answer. The following is the conversation we had.\r\n\"How old are you Tammy?\"\r\n\"I am three times as old as Timmy was when Tony was born. Actually, it's funny, but Timmy's, Tracey's, Tommy's and my ages were all factors of Mum's age when Tony was born. The only other year where the ages of more than two of us were factors of Mum's age was when Tracey was half as old as I am now.\"\r\n\"How old is your Mum now?\"\r\n\"There's another funny thing. When Mum turns 50, Tony will be the same age Mum was when she gave birth to Tommy.\"\n\r\nAssuming Tammy was talking in terms of whole years, and with my mathematical and reasoning abilities I was able to quickly deduce not just Tammy's age, but all of their ages. So how old are Tommy, Timmy, Tammy, Tracey, Tony and Mum now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTommy is 23, Timmy is 19, Tammy is 18, Tracey is 16, Tony is 13 and Mum is 43.\n\r\nSolution:\r\nx = Mum's age when she gave birth to Tommy = Tony's age when Mum turns 50;\r\ny = Tommy's age when Tony was born\r\nz = Mum's age when Tony was born\n\r\nFrom Tammy's last statement, 2x + y = 50 and it can be deduced that x = z - y, where y is a factor of z. By combining the two equations you get 2z = 50 + y The only possible solutions for that equation so that y is also a factor of z are (z = 26, y = 2) and (z = 30, y = 10). Only 30 has four or more factors, so Mum was 30 and Tommy was 10 when Tony was born.\n\r\nThis means that of the remaining factors of 30, Timmy was 6, 5 or 3, Tammy was 5, 3 or 2 and Tracey was 3, 2 or 1. This makes Tammy 18, 15 or 9 now. The only other time where the ages of more than two of the children were factors of Mum's age was when Tracey was half what Tammy is now, so Tammy must be 18 now.\n\r\nIn the second multiple-factors-of-Mum's-age year, Tracey was therefore 9. When Tony was born, Tracey was either 3, 2 or 1, giving possible time differences of 6, 7 or 8 years, which correspond to Tony's age in the second multiple-factors-of-Mum's-age year. It also means Mum was 36, 37 or 38 that year. 37 is prime and 38 has factors of 1, 2 and 19, and as Tony was at least 6, it means that Mum must have been 36 that year.\n\r\nGoing back to when Tony was born we have that Mum was 30, Tommy was 10, Timmy was 6, Tracey was 3, and as the middle child Tammy must have been 5. If Tammy is 18 now then Tony is 13, Tracey is 16, Timmy is 19, Tommy is 23 and Mum is 43.\n<|im_start|>answer\nTommy is 23, Timmy is 19, Tammy is 18, Tracey is 16, Tony is 13 and Mum is 43.\n\r\nSolution:\r\nx = Mum's age when she gave birth to Tommy = Tony's age when Mum turns 50;\r\ny = Tommy's age when Tony was born\r\nz = Mum's age when Tony was born\n\r\nFrom Tammy's last statement, 2x + y = 50 and it can be deduced that x = z - y, where y is a factor of z. By combining the two equations you get 2z = 50 + y The only possible solutions for that equation so that y is also a factor of z are (z = 26, y = 2) and (z = 30, y = 10). Only 30 has four or more factors, so Mum was 30 and Tommy was 10 when Tony was born.\n\r\nThis means that of the remaining factors of 30, Timmy was 6, 5 or 3, Tammy was 5, 3 or 2 and Tracey was 3, 2 or 1. This makes Tammy 18, 15 or 9 now. The only other time where the ages of more than two of the children were factors of Mum's age was when Tracey was half what Tammy is now, so Tammy must be 18 now.\n\r\nIn the second multiple-factors-of-Mum's-age year, Tracey was therefore 9. When Tony was born, Tracey was either 3, 2 or 1, giving possible time differences of 6, 7 or 8 years, which correspond to Tony's age in the second multiple-factors-of-Mum's-age year. It also means Mum was 36, 37 or 38 that year. 37 is prime and 38 has factors of 1, 2 and 19, and as Tony was at least 6, it means that Mum must have been 36 that year.\n\r\nGoing back to when Tony was born we have that Mum was 30, Tommy was 10, Timmy was 6, Tracey was 3, and as the middle child Tammy must have been 5. If Tammy is 18 now then Tony is 13, Tracey is 16, Timmy is 19, Tommy is 23 and Mum is 43.\n<|im_end|>" }, { "id": "#39890", "title": "Running Racers", "fun": 2.47, "difficulty": 1.16, "author": "icestar12", "desc": "Mandy, Yasheika, Nikki, Deanna, and Katrina were in a 100-yard race. When the newspaper photographer took photos of the race, Mandy had just passed the midway mark, Yasheika was 15 yards away from the finish, and Deanna had run 40 yards. Katrina had run twice as far as Deanna. Nikki was at the 70-yard mark. Help the photographer identify the runners.\n\r\nList the runners in order, starting with the runner closest to the finish line.", "hint": "No hint available.", "answer": "Yasheika is closest to the finish, followed by Katrina, Nikki, Mandy, and Deanna.", "category": "Logic", "date": "01/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMandy, Yasheika, Nikki, Deanna, and Katrina were in a 100-yard race. When the newspaper photographer took photos of the race, Mandy had just passed the midway mark, Yasheika was 15 yards away from the finish, and Deanna had run 40 yards. Katrina had run twice as far as Deanna. Nikki was at the 70-yard mark. Help the photographer identify the runners.\n\r\nList the runners in order, starting with the runner closest to the finish line.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYasheika is closest to the finish, followed by Katrina, Nikki, Mandy, and Deanna.\n<|im_start|>answer\nYasheika is closest to the finish, followed by Katrina, Nikki, Mandy, and Deanna.\n<|im_end|>" }, { "id": "#15685", "title": "Get Smart", "fun": 2.47, "difficulty": 1.55, "author": "jimbo", "desc": "Maxwell Smart (Agent 86) was trying to get a coded message to his girlfriend (Agent 99). He had to type into his shoe phone, her agent number 99 as the sum of two prime numbers. How many different ways could Max do this?", "hint": "Don't spend TOO long searching!", "answer": "Just one way. As all prime numbers except 2 are odd, and the sum of any two odd numbers is even, then the sum must contain 2 as one of the numbers since 99 is odd. Therefore, 2 + 97 is the only way.", "category": "Math", "date": "12/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMaxwell Smart (Agent 86) was trying to get a coded message to his girlfriend (Agent 99). He had to type into his shoe phone, her agent number 99 as the sum of two prime numbers. How many different ways could Max do this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJust one way. As all prime numbers except 2 are odd, and the sum of any two odd numbers is even, then the sum must contain 2 as one of the numbers since 99 is odd. Therefore, 2 + 97 is the only way.\n<|im_start|>answer\nJust one way. As all prime numbers except 2 are odd, and the sum of any two odd numbers is even, then the sum must contain 2 as one of the numbers since 99 is odd. Therefore, 2 + 97 is the only way.\n<|im_end|>" }, { "id": "#11679", "title": "3 by 3 Logic", "fun": 2.47, "difficulty": 1.53, "author": "jimbo", "desc": "Just take the first two statements in each set as being correct and deduce whether the implication is true or false. (It doesn't matter whether you think the statements are actually true or not, just apply the logic.)\n\r\n[1] Some chess players are left handed.\r\nAll left-handed people play the piano.\r\nTrue or False? \"Some piano players play chess.\"\n\r\n[2] Some guitar players eat quiche.\r\nAll quiche eaters are surfers.\r\nTrue or False? \"All guitar players are surfers.\"\n\r\n[3] No athletes who like probability play scrabble.\r\nAll athletes who use deodorant play scrabble.\r\nTrue or False? \"No athletes who use deodorant like probability.\"", "hint": "Try replacing the zany descriptions with something more familiar, like some dogs have white tails, etc.", "answer": "[1] True\r\n[2] False\r\n[3] True", "category": "Logic", "date": "04/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJust take the first two statements in each set as being correct and deduce whether the implication is true or false. (It doesn't matter whether you think the statements are actually true or not, just apply the logic.)\n\r\n[1] Some chess players are left handed.\r\nAll left-handed people play the piano.\r\nTrue or False? \"Some piano players play chess.\"\n\r\n[2] Some guitar players eat quiche.\r\nAll quiche eaters are surfers.\r\nTrue or False? \"All guitar players are surfers.\"\n\r\n[3] No athletes who like probability play scrabble.\r\nAll athletes who use deodorant play scrabble.\r\nTrue or False? \"No athletes who use deodorant like probability.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n[1] True\r\n[2] False\r\n[3] True\n<|im_start|>answer\n[1] True\r\n[2] False\r\n[3] True\n<|im_end|>" }, { "id": "#26514", "title": "Threes and Eights", "fun": 2.47, "difficulty": 2.38, "author": "lips", "desc": "Using the four digits 3,3,8,8 and the mathematical operators +,-,*,/ write an expression equal to 24. You must use each digit exactly once, but may use each operator multiple times, or not at all. Parentheses are allowed. The following would be a valid expression: \n\r\n(8 + 3)/(8 + 3) = 1", "hint": "Think fractions.", "answer": "8 / (3 - 8/3) = 24", "category": "Math", "date": "10/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the four digits 3,3,8,8 and the mathematical operators +,-,*,/ write an expression equal to 24. You must use each digit exactly once, but may use each operator multiple times, or not at all. Parentheses are allowed. The following would be a valid expression: \n\r\n(8 + 3)/(8 + 3) = 1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8 / (3 - 8/3) = 24\n<|im_start|>answer\n8 / (3 - 8/3) = 24\n<|im_end|>" }, { "id": "#29719", "title": "Math Competition 2", "fun": 2.47, "difficulty": 2.56, "author": "bigSWAFF_69_", "desc": "It is the day of the Math Competition, Felipe got off to a bad start, but now has a chance to be in the top 10 of all 5 schools, and get in the finals. He once again found himself tied for the last spot, this time with a girl named Rico. Same as last time, the two get one question to answer the fastest, the winner getting to go on to the finals the next day.\n\r\nSuppose that each distinct letter in the equation MATH = COU + NTS is replaced by a different digit chosen from 1 through 9 in such a way that the resulting equation is true. If H=4, how many working options are there?", "hint": "No hint available.", "answer": "4\n\n\r\n798 + 526 = 1324\r\n796 + 528 = 1324\r\n598 + 726 = 1324\r\n596 + 728 = 1324\n\r\nRico choked on her pencil, giving Felipe the win by default.", "category": "Math", "date": "04/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is the day of the Math Competition, Felipe got off to a bad start, but now has a chance to be in the top 10 of all 5 schools, and get in the finals. He once again found himself tied for the last spot, this time with a girl named Rico. Same as last time, the two get one question to answer the fastest, the winner getting to go on to the finals the next day.\n\r\nSuppose that each distinct letter in the equation MATH = COU + NTS is replaced by a different digit chosen from 1 through 9 in such a way that the resulting equation is true. If H=4, how many working options are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4\n\n\r\n798 + 526 = 1324\r\n796 + 528 = 1324\r\n598 + 726 = 1324\r\n596 + 728 = 1324\n\r\nRico choked on her pencil, giving Felipe the win by default.\n<|im_start|>answer\n4\n\n\r\n798 + 526 = 1324\r\n796 + 528 = 1324\r\n598 + 726 = 1324\r\n596 + 728 = 1324\n\r\nRico choked on her pencil, giving Felipe the win by default.\n<|im_end|>" }, { "id": "#36380", "title": "Antonyms on a Chart", "fun": 2.47, "difficulty": 2.73, "author": "t4mt", "desc": "T4 has a chart in his possession. On it says:\r\n1 stands for O, U, D, or B\r\n2 stands for S, K, Q, or T\r\n3 stands for I, H, E, or N\r\n4 stands for O, I, F, or W\r\n5 stands for Z, U, Y, or S\r\n6 stands for I, L, E, or C \n\r\nBelow that, he wrote the number \"123456.\" This number, using the decryption method above, can mean two words that are antonyms. What are the two words?", "hint": "One is the word \"useful\".", "answer": "Otiose and useful.", "category": "Logic", "date": "04/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nT4 has a chart in his possession. On it says:\r\n1 stands for O, U, D, or B\r\n2 stands for S, K, Q, or T\r\n3 stands for I, H, E, or N\r\n4 stands for O, I, F, or W\r\n5 stands for Z, U, Y, or S\r\n6 stands for I, L, E, or C \n\r\nBelow that, he wrote the number \"123456.\" This number, using the decryption method above, can mean two words that are antonyms. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOtiose and useful.\n<|im_start|>answer\nOtiose and useful.\n<|im_end|>" }, { "id": "#50393", "title": "Simple Addition #2", "fun": 2.47, "difficulty": 2.19, "author": "Ghostology", "desc": "Add in any required number of mathematical symbols to make this equation work.\n\r\n8 8 8 = 6", "hint": "You need to use square roots, division, brackets, factorial and addition.\n\r\nFactorial = !\r\nn! = n * (n-1) * (n-2) * .... * 2 * 1\n\r\nE.g. 2! = 2 * 1\r\n3! = 3 * 2 * 1\r\n0! = 1", "answer": "Take note: Square roots are defined as SqRt( ) because the square root sign does not show up.\n\r\nSqRt(8 / 8 + 8)! = 6\n\r\n8/8 + 8 = 9\r\nSqRt( 9 ) = Square root 9 = 3\r\n3! = 3 * 2 * 1 = 6", "category": "Math", "date": "07/11/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdd in any required number of mathematical symbols to make this equation work.\n\r\n8 8 8 = 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake note: Square roots are defined as SqRt( ) because the square root sign does not show up.\n\r\nSqRt(8 / 8 + 8)! = 6\n\r\n8/8 + 8 = 9\r\nSqRt( 9 ) = Square root 9 = 3\r\n3! = 3 * 2 * 1 = 6\n<|im_start|>answer\nTake note: Square roots are defined as SqRt( ) because the square root sign does not show up.\n\r\nSqRt(8 / 8 + 8)! = 6\n\r\n8/8 + 8 = 9\r\nSqRt( 9 ) = Square root 9 = 3\r\n3! = 3 * 2 * 1 = 6\n<|im_end|>" }, { "id": "#30337", "title": "Expressions", "fun": 2.47, "difficulty": 1.47, "author": "Hana_Kimi", "desc": "Kyle said that he can use each of the numbers 1, 2, 3, and 4 exactly once and the operations of addition and multiplication to write an expression with a value of 15. What expression did Kyle write?", "hint": "No hint available.", "answer": "(4x3)+2+1=15, or 2(4+3)+1=15.", "category": "Math", "date": "05/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKyle said that he can use each of the numbers 1, 2, 3, and 4 exactly once and the operations of addition and multiplication to write an expression with a value of 15. What expression did Kyle write?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(4x3)+2+1=15, or 2(4+3)+1=15.\n<|im_start|>answer\n(4x3)+2+1=15, or 2(4+3)+1=15.\n<|im_end|>" }, { "id": "#43234", "title": "Who Took the Cookies?", "fun": 2.47, "difficulty": 0.91, "author": "dswilborn", "desc": "Mr. Johnson, a fourth grade teacher at Skyline School, brought four of his favorite cookies to school for his after-school snack. He laid them out on a plate, but before he could eat them he was summoned to the office.\n\r\nWhen he returned, the cookies were gone! He went across the hall to Mrs. Tamer's room and asked her if she had seen anyone enter his room. She said she had seen four students, including Bill, but couldn't remember what order they had entered.\n\r\nMr. Johnson questioned the students, but the stories were so mixed up he wasn't sure exactly who took what cookie and when. Can you figure it out?\n\r\n1. Bryan took a cookie sometime after Lewis had been in the room, but before the person who took the oatmeal cookie.\n\r\n2. A boy was the last person to enter the room, but he did not take the sugar cookie.\n\r\n3. The peanut butter cookie was taken third.\n\r\n4. The chocolate chip cookie was taken first, but not by Lewis.\n\r\n5. Anna is allergic to peanut butter and left it untouched.", "hint": "No hint available.", "answer": "1st - Anna took the chocolate chip cookie.\r\n2nd - Lewis took the sugar cookie.\r\n3rd - Bryan took the peanut butter cookie.\r\n4th - Bill took the oatmeal cookie.", "category": "Logic-Grid", "date": "10/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Johnson, a fourth grade teacher at Skyline School, brought four of his favorite cookies to school for his after-school snack. He laid them out on a plate, but before he could eat them he was summoned to the office.\n\r\nWhen he returned, the cookies were gone! He went across the hall to Mrs. Tamer's room and asked her if she had seen anyone enter his room. She said she had seen four students, including Bill, but couldn't remember what order they had entered.\n\r\nMr. Johnson questioned the students, but the stories were so mixed up he wasn't sure exactly who took what cookie and when. Can you figure it out?\n\r\n1. Bryan took a cookie sometime after Lewis had been in the room, but before the person who took the oatmeal cookie.\n\r\n2. A boy was the last person to enter the room, but he did not take the sugar cookie.\n\r\n3. The peanut butter cookie was taken third.\n\r\n4. The chocolate chip cookie was taken first, but not by Lewis.\n\r\n5. Anna is allergic to peanut butter and left it untouched.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st - Anna took the chocolate chip cookie.\r\n2nd - Lewis took the sugar cookie.\r\n3rd - Bryan took the peanut butter cookie.\r\n4th - Bill took the oatmeal cookie.\n<|im_start|>answer\n1st - Anna took the chocolate chip cookie.\r\n2nd - Lewis took the sugar cookie.\r\n3rd - Bryan took the peanut butter cookie.\r\n4th - Bill took the oatmeal cookie.\n<|im_end|>" }, { "id": "#24431", "title": "Pride Middle School", "fun": 2.47, "difficulty": 0.88, "author": "sassy_101", "desc": "The secretary at Pride Middle School got all the grades, teachers, and subjects mixed up for one student attending PMS. This is what she knows:\n\r\nTeachers: Mrs. Harland, Mrs. Bride, Mrs. Kean, Mr. Ley, and Mr. Bikly.\r\nSubjects: Math, Science, Social Studies, Reading, and Language Arts.\r\nGrades: A, A-, B+, B, and B-.\n\r\n1. None of the teachers gave out a grade that begins with the first letter of their name. \r\n2. Mrs. Kean, who does not teach math or science, gave the lowest grade.\r\n3. Mrs. Harland gave a lower grade than the reading teacher, Mr. Ley.\r\n4. Mr. Bikly gave a lower grade than the math teacher.\r\n5. Neither Mr. Bikly nor Mrs. Bride is the science teacher.\r\n6. The language arts teacher gave a B-.", "hint": "No hint available.", "answer": "Mrs. Bride- Math- A\r\nMr. Bikly- Social studies- A-\r\nMr. Ley- Reading- B+\r\nMrs. Harland- science- B\r\nMrs. Kean- Language Arts- B-", "category": "Logic-Grid", "date": "07/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe secretary at Pride Middle School got all the grades, teachers, and subjects mixed up for one student attending PMS. This is what she knows:\n\r\nTeachers: Mrs. Harland, Mrs. Bride, Mrs. Kean, Mr. Ley, and Mr. Bikly.\r\nSubjects: Math, Science, Social Studies, Reading, and Language Arts.\r\nGrades: A, A-, B+, B, and B-.\n\r\n1. None of the teachers gave out a grade that begins with the first letter of their name. \r\n2. Mrs. Kean, who does not teach math or science, gave the lowest grade.\r\n3. Mrs. Harland gave a lower grade than the reading teacher, Mr. Ley.\r\n4. Mr. Bikly gave a lower grade than the math teacher.\r\n5. Neither Mr. Bikly nor Mrs. Bride is the science teacher.\r\n6. The language arts teacher gave a B-.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMrs. Bride- Math- A\r\nMr. Bikly- Social studies- A-\r\nMr. Ley- Reading- B+\r\nMrs. Harland- science- B\r\nMrs. Kean- Language Arts- B-\n<|im_start|>answer\nMrs. Bride- Math- A\r\nMr. Bikly- Social studies- A-\r\nMr. Ley- Reading- B+\r\nMrs. Harland- science- B\r\nMrs. Kean- Language Arts- B-\n<|im_end|>" }, { "id": "#27778", "title": "Wages", "fun": 2.47, "difficulty": 1.27, "author": "jajajaja", "desc": "Jen, Paula and Sarah had spent the week decorating an elderly neighbour's house, for which they earned £500 between them. When it came to dividing up the money Paula claimed she had worked three times harder than Jen, and Sarah had worked twice as hard as Paula. If the money was divided fairly, how much money did they each receive?", "hint": "No hint available.", "answer": "Jen =£50\r\nPaula =£150\r\nSarah =£300", "category": "Math", "date": "12/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJen, Paula and Sarah had spent the week decorating an elderly neighbour's house, for which they earned £500 between them. When it came to dividing up the money Paula claimed she had worked three times harder than Jen, and Sarah had worked twice as hard as Paula. If the money was divided fairly, how much money did they each receive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJen =£50\r\nPaula =£150\r\nSarah =£300\n<|im_start|>answer\nJen =£50\r\nPaula =£150\r\nSarah =£300\n<|im_end|>" }, { "id": "#31768", "title": "Twins and Their Mistakes", "fun": 2.47, "difficulty": 2.91, "author": "stang99", "desc": "Six sets of twins ( a boy and a girl in every case) made several errors in their history and geography examinations; and it was noted that every girl made precisely the same number of errors as her brother in the two subjects. Name each pair of siblings and their surname and work out how many mistakes each made in their history and geography examination papers.\n\r\n1. The boy (not Luke) whose sister is Louella made more history errors than Sammy.\r\n2. George did better in history than the boy surnamed O'Connell, who made either one more or one less geography error than the twins surnamed Dean.\r\n3. Anne made either one more or one less geography error than Louella.\r\n4. The twins who made 11 geography errors didn't make exactly 11 history errors.\r\n5. David and his sister made either one more or one less mistake in the history exam than the twins who made 14 geography errors.\r\n6. Edward and his sister did worse at history than the pair who made 15 geography errors. Edward made one more error in the geography exam than Luke.\r\n7. The McCall twins didn't make one less history mistake than the Vole twins.\r\n8. Susan (who made seven history errors) made one less geography error than the girl who made one less history error than Anne.\r\n9. The twins surnamed Waters made one more history mistake than the twins surnamed Seal, who made more geography errors than the McCall twins.\r\n10. Gail made one more geography error than the girl who made one more history error than Louella.\r\n11. Martin made either one more or one less geography error than his best friend and his sister, who made more history mistakes than Diane.\r\n12. Wendy and her brother (who didn't make eight history mistakes) didn't make as many errors in geography as George and his sister.\n\r\nBrothers are David, Edward, George, Luke, Martin & Sammy.\r\nSisters are Anne, Diane, Gail, Louella, Susan & Wendy.\r\nSurnames are Dean, McCall, O'Connell, Seal, Vole & Waters.\r\nGeography errors are 10, 11, 12, 14, 15 & 16.\r\nHistory errors are 6, 7, 8, 10, 11 & 12.", "hint": "No hint available.", "answer": "Susan made seven history errors (clue 8) and no one made nine, so Anne made either 11 or 12. Louella didn't make six history errors (1), so (10) must have made either 10 or 11. If Louella made 11 and Anne made 12, then Susan made one less geography error than Louella (8) and Gail made one more than Anne (10). But then, since no one made 13 geography errors, clue 3 doesn't work. So Louella made 10 history errors. If Anne made 11 history errors, then Gail made one more geography error than Anne (10) and Susan made one less geography error than Louella (8). But again, since no one made 13 geography errors, clue 3 still doesn't work. So Anne made 12 history errors.\n\r\nThe twins with 11 errors made one more geography error than Susan (8) and one less than Gail (10), so Gail made 12 or 16 geography errors and Susan made 10 or 14 : while twins with 11 history errors made 11 or 15 geography errors. Thus those with 11 history errors made 15 geography errors (4), Gail made 16 geography errors and Susan made 14. Edward made 12 history errors (6) so is Anne's brother; Anne and her brother made either 10, 11 or 12 geography errors, so (6) made 11 or 12 and Luke and his sister made 10 or 11, ie one of them made 11. Luke's sister isn't Louella (1), so Luke made either six or eight history errors, as did David (5). Thus David's sister is Gail.\n\r\nAnne made 11 geography errors (3), so Luke made 10 and Louella made 12. Sammy's sister is Susan (1). Wendy made 10 geography errors (12), so Diane made 15. Luke (who is Wendy's brother) made six history errors (12), so David made eight. By elimination, Sammy made seven and so is Susan's brother. Martin's sister is Louella (11). Diane's brother is George. Edwards is surnamed O'Connell (2) and the Dean girl is either Louella or Wendy (10 or 12 geography errors). The Waters and Seal twins (9) made either eight and seven history errors or else 11 and 10; so the Seal twins made 14 or 12 geography errors and the McCall twins made 10 or 12. If the Seal twins made 12 geography errors and the McCall twins made 10, then (above) the Dean twins are excluded. Thus Sammy's surname is Seal and David's is Waters. Diane's surname is Vole. Martin's isn't McCall (7), so must be Dean. Luke's is McCall.\n\r\nThus ( geography-history );\r\nDavid - Gail - Waters - 16 -8;\r\nEdward - Anne - O'Connell - 11- 12;\r\nGeorge - Diane - Vole - 15 - 11;\r\nLuke - Wendy - McCall - 10 - 6;\r\nMartin - Louella - Dean - 12 - 10;\r\nSammy - Susan - Seal - 14 - 7;", "category": "Logic", "date": "07/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix sets of twins ( a boy and a girl in every case) made several errors in their history and geography examinations; and it was noted that every girl made precisely the same number of errors as her brother in the two subjects. Name each pair of siblings and their surname and work out how many mistakes each made in their history and geography examination papers.\n\r\n1. The boy (not Luke) whose sister is Louella made more history errors than Sammy.\r\n2. George did better in history than the boy surnamed O'Connell, who made either one more or one less geography error than the twins surnamed Dean.\r\n3. Anne made either one more or one less geography error than Louella.\r\n4. The twins who made 11 geography errors didn't make exactly 11 history errors.\r\n5. David and his sister made either one more or one less mistake in the history exam than the twins who made 14 geography errors.\r\n6. Edward and his sister did worse at history than the pair who made 15 geography errors. Edward made one more error in the geography exam than Luke.\r\n7. The McCall twins didn't make one less history mistake than the Vole twins.\r\n8. Susan (who made seven history errors) made one less geography error than the girl who made one less history error than Anne.\r\n9. The twins surnamed Waters made one more history mistake than the twins surnamed Seal, who made more geography errors than the McCall twins.\r\n10. Gail made one more geography error than the girl who made one more history error than Louella.\r\n11. Martin made either one more or one less geography error than his best friend and his sister, who made more history mistakes than Diane.\r\n12. Wendy and her brother (who didn't make eight history mistakes) didn't make as many errors in geography as George and his sister.\n\r\nBrothers are David, Edward, George, Luke, Martin & Sammy.\r\nSisters are Anne, Diane, Gail, Louella, Susan & Wendy.\r\nSurnames are Dean, McCall, O'Connell, Seal, Vole & Waters.\r\nGeography errors are 10, 11, 12, 14, 15 & 16.\r\nHistory errors are 6, 7, 8, 10, 11 & 12.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSusan made seven history errors (clue 8) and no one made nine, so Anne made either 11 or 12. Louella didn't make six history errors (1), so (10) must have made either 10 or 11. If Louella made 11 and Anne made 12, then Susan made one less geography error than Louella (8) and Gail made one more than Anne (10). But then, since no one made 13 geography errors, clue 3 doesn't work. So Louella made 10 history errors. If Anne made 11 history errors, then Gail made one more geography error than Anne (10) and Susan made one less geography error than Louella (8). But again, since no one made 13 geography errors, clue 3 still doesn't work. So Anne made 12 history errors.\n\r\nThe twins with 11 errors made one more geography error than Susan (8) and one less than Gail (10), so Gail made 12 or 16 geography errors and Susan made 10 or 14 : while twins with 11 history errors made 11 or 15 geography errors. Thus those with 11 history errors made 15 geography errors (4), Gail made 16 geography errors and Susan made 14. Edward made 12 history errors (6) so is Anne's brother; Anne and her brother made either 10, 11 or 12 geography errors, so (6) made 11 or 12 and Luke and his sister made 10 or 11, ie one of them made 11. Luke's sister isn't Louella (1), so Luke made either six or eight history errors, as did David (5). Thus David's sister is Gail.\n\r\nAnne made 11 geography errors (3), so Luke made 10 and Louella made 12. Sammy's sister is Susan (1). Wendy made 10 geography errors (12), so Diane made 15. Luke (who is Wendy's brother) made six history errors (12), so David made eight. By elimination, Sammy made seven and so is Susan's brother. Martin's sister is Louella (11). Diane's brother is George. Edwards is surnamed O'Connell (2) and the Dean girl is either Louella or Wendy (10 or 12 geography errors). The Waters and Seal twins (9) made either eight and seven history errors or else 11 and 10; so the Seal twins made 14 or 12 geography errors and the McCall twins made 10 or 12. If the Seal twins made 12 geography errors and the McCall twins made 10, then (above) the Dean twins are excluded. Thus Sammy's surname is Seal and David's is Waters. Diane's surname is Vole. Martin's isn't McCall (7), so must be Dean. Luke's is McCall.\n\r\nThus ( geography-history );\r\nDavid - Gail - Waters - 16 -8;\r\nEdward - Anne - O'Connell - 11- 12;\r\nGeorge - Diane - Vole - 15 - 11;\r\nLuke - Wendy - McCall - 10 - 6;\r\nMartin - Louella - Dean - 12 - 10;\r\nSammy - Susan - Seal - 14 - 7;\n<|im_start|>answer\nSusan made seven history errors (clue 8) and no one made nine, so Anne made either 11 or 12. Louella didn't make six history errors (1), so (10) must have made either 10 or 11. If Louella made 11 and Anne made 12, then Susan made one less geography error than Louella (8) and Gail made one more than Anne (10). But then, since no one made 13 geography errors, clue 3 doesn't work. So Louella made 10 history errors. If Anne made 11 history errors, then Gail made one more geography error than Anne (10) and Susan made one less geography error than Louella (8). But again, since no one made 13 geography errors, clue 3 still doesn't work. So Anne made 12 history errors.\n\r\nThe twins with 11 errors made one more geography error than Susan (8) and one less than Gail (10), so Gail made 12 or 16 geography errors and Susan made 10 or 14 : while twins with 11 history errors made 11 or 15 geography errors. Thus those with 11 history errors made 15 geography errors (4), Gail made 16 geography errors and Susan made 14. Edward made 12 history errors (6) so is Anne's brother; Anne and her brother made either 10, 11 or 12 geography errors, so (6) made 11 or 12 and Luke and his sister made 10 or 11, ie one of them made 11. Luke's sister isn't Louella (1), so Luke made either six or eight history errors, as did David (5). Thus David's sister is Gail.\n\r\nAnne made 11 geography errors (3), so Luke made 10 and Louella made 12. Sammy's sister is Susan (1). Wendy made 10 geography errors (12), so Diane made 15. Luke (who is Wendy's brother) made six history errors (12), so David made eight. By elimination, Sammy made seven and so is Susan's brother. Martin's sister is Louella (11). Diane's brother is George. Edwards is surnamed O'Connell (2) and the Dean girl is either Louella or Wendy (10 or 12 geography errors). The Waters and Seal twins (9) made either eight and seven history errors or else 11 and 10; so the Seal twins made 14 or 12 geography errors and the McCall twins made 10 or 12. If the Seal twins made 12 geography errors and the McCall twins made 10, then (above) the Dean twins are excluded. Thus Sammy's surname is Seal and David's is Waters. Diane's surname is Vole. Martin's isn't McCall (7), so must be Dean. Luke's is McCall.\n\r\nThus ( geography-history );\r\nDavid - Gail - Waters - 16 -8;\r\nEdward - Anne - O'Connell - 11- 12;\r\nGeorge - Diane - Vole - 15 - 11;\r\nLuke - Wendy - McCall - 10 - 6;\r\nMartin - Louella - Dean - 12 - 10;\r\nSammy - Susan - Seal - 14 - 7;\n<|im_end|>" }, { "id": "#16580", "title": "Cleaning the House", "fun": 2.47, "difficulty": 2.6, "author": "absy", "desc": "Ever since Emily began her new job, the last thing she wants to do when she gets home is clean her apartment. She decided to make a schedule so that she would clean a different room (including the living room) each day (Monday through Friday). Last week she procrastinated by talking on the phone, so this week, Emily decided to let the answering machine handle her calls, and she received a different number of messages each day. Can you determine the which rooms she cleaned each day and the number of messages she received?\n\r\nGiven:\n\r\nCleaning Days -- \tMonday, Tuesday, Wednesday, Thursday, Friday\r\nNumber of Messages -- \t1, 2, 3, 4, 5\r\nRooms Cleaned -- \tBedroom, Living Room, Bathroom, Den, Kitchen\n\r\nClues:\n\r\n#1) Emily received more messages on Thursday than on the day she cleaned her bedroom, but fewer than on Tuesday.\r\n#2) Emily cleaned the bathroom on the day after receiving just one message and one day before she cleaned the den.\r\n#3) She received more messages when she cleaned her bedroom than when she cleaned the den.\r\n#4) Emily cleaned the kitchen on Wednesday.", "hint": "Hints:\n\r\nMake a list of one set of givens and list another set of givens that would correspond to them... i.e. (Days) -- (Messages)\n\r\nMonday -- 1 2 3 4 5\r\nTuesday -- 1 2 3 4 5, etc.\n\r\nCross off what you know is NOT the correct answer from the clues, and when you find out a number of messages that fits a day circle it, or write it on the piece of paper in a different section to keep track. Do the same with the other correlations that can be surmised by looking at the clues: \n\r\n(Days) -- (Rooms)\r\n(Rooms) -- (Messages)\n\r\nKeep in mind that for example, if you find a number of messages for a day, the other days can NOT have that amount of messages, so that gives you another answer to mark off to narrow the correct answer down.", "answer": "Answers:\n\r\nMonday -- Bedroom -- 3\r\nTuesday -- Living Room -- 5\r\nWednesday -- Kitchen -- 1\r\nThursday -- Bathroom -- 4\r\nFriday -- Den -- 2\n\r\n**Clue #1: If she received more messages on Thursday than on the day she cleaned her bedroom, she could not have received 1 message on Thursday as the day she cleaned her room would have to be 0, which is not an option. She could not have received 5 messages on the day she cleaned her bedroom because Thursday would then have to be at least 6 messages which is not an option. Assume also that she did NOT clean her bedroom on Thursday or Tuesday, as they are mentioned in the same clue. Since she had fewer messages on Thursday than Tuesday, she could not have received 1 message on Tuesday for the same reasons mentioned above. Also by the same token, she could not have received 5 on Thursday because Tuesday would have to be 6. \r\n**Clue #2: 1 message -- bathroom -- den....the order of the happenings in clue 2. therefore, she could not have cleaned the bathroom on Monday, nor the den. Also assume she did not receive 1 message on the bathroom or den cleanings. She could not have cleaned the bathroom on Friday. As that would leave no day for the den, which is the day after. She could not have received 1 message on Thursday or Friday because there would not be enough days to clean the bathroom and den.\r\n**Clue #3: If she received more messages when she cleaned her bedroom than when she cleaned the den, she could not have received 5 messages when she cleaned the den, nor 1 message when she cleaned her bedroom. \r\n**Clue #4: She cleaned the Kitchen on Wednesday..self explanatory.\r\n*********Now look back using all the clues instead of 1 at a time. In Clue 1 and Clue 3. More messages when she cleaned her bedroom than the den (#3). In Clue 1, it says she got more messages on Thursday than when she cleaned her room. So she could NOT have cleaned her den on Thursday. That leaves Tuesday and Friday for the den. But remember the order given in Clue 2. The den could not have been cleaned on Tuesday. Den was on Friday, which leaves only one day for the bedroom, which is Monday. Now add in the order in Clue 2, and you know that Thursday she cleaned the bathroom, and Wednesday, when she cleaned the kitchen, she received 1 message. When you know the bathroom was cleaned on Thursday, that leaves one room and one day. The living room was cleaned on Tuesday. That leaves the messages for each day. We know that the bedroom was cleaned on Monday. You should have marked off 1 and 5 messages for the bedroom. So that means that 1 and 5 should be marked off the day the bedroom was cleaned as well. They have to match. Another that doesn't match, is that Friday the den was cleaned. We know that 1 and 5 messages were not received while the den was being cleaned, so 1 and 5 could not have been received on Friday. After marking that 5 off, there is only one day with a five left -- Tuesday. You know that she received more messages on Thursday than when she cleaned her bedroom (Monday). The highest that she could have received on Thursday is 4. So we know that 4 could not have been received on Monday. By the same token, we know that she received more messages when cleaning the bathroom (Thursday) than when cleaning the den (Friday). The highest she could have received on Thursday is 4. So we know that for Friday to be less, she could not receive 4 messages on Friday. This means she received 4 messages on Thursday when she cleaned the bathroom. Looking back at clue 2 gives you the answer for the last section. She received more messages when cleaning her bedroom than when cleaning the den. So she received 3 in the bedroom, and 2 in the den.", "category": "Logic", "date": "02/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEver since Emily began her new job, the last thing she wants to do when she gets home is clean her apartment. She decided to make a schedule so that she would clean a different room (including the living room) each day (Monday through Friday). Last week she procrastinated by talking on the phone, so this week, Emily decided to let the answering machine handle her calls, and she received a different number of messages each day. Can you determine the which rooms she cleaned each day and the number of messages she received?\n\r\nGiven:\n\r\nCleaning Days -- \tMonday, Tuesday, Wednesday, Thursday, Friday\r\nNumber of Messages -- \t1, 2, 3, 4, 5\r\nRooms Cleaned -- \tBedroom, Living Room, Bathroom, Den, Kitchen\n\r\nClues:\n\r\n#1) Emily received more messages on Thursday than on the day she cleaned her bedroom, but fewer than on Tuesday.\r\n#2) Emily cleaned the bathroom on the day after receiving just one message and one day before she cleaned the den.\r\n#3) She received more messages when she cleaned her bedroom than when she cleaned the den.\r\n#4) Emily cleaned the kitchen on Wednesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswers:\n\r\nMonday -- Bedroom -- 3\r\nTuesday -- Living Room -- 5\r\nWednesday -- Kitchen -- 1\r\nThursday -- Bathroom -- 4\r\nFriday -- Den -- 2\n\r\n**Clue #1: If she received more messages on Thursday than on the day she cleaned her bedroom, she could not have received 1 message on Thursday as the day she cleaned her room would have to be 0, which is not an option. She could not have received 5 messages on the day she cleaned her bedroom because Thursday would then have to be at least 6 messages which is not an option. Assume also that she did NOT clean her bedroom on Thursday or Tuesday, as they are mentioned in the same clue. Since she had fewer messages on Thursday than Tuesday, she could not have received 1 message on Tuesday for the same reasons mentioned above. Also by the same token, she could not have received 5 on Thursday because Tuesday would have to be 6. \r\n**Clue #2: 1 message -- bathroom -- den....the order of the happenings in clue 2. therefore, she could not have cleaned the bathroom on Monday, nor the den. Also assume she did not receive 1 message on the bathroom or den cleanings. She could not have cleaned the bathroom on Friday. As that would leave no day for the den, which is the day after. She could not have received 1 message on Thursday or Friday because there would not be enough days to clean the bathroom and den.\r\n**Clue #3: If she received more messages when she cleaned her bedroom than when she cleaned the den, she could not have received 5 messages when she cleaned the den, nor 1 message when she cleaned her bedroom. \r\n**Clue #4: She cleaned the Kitchen on Wednesday..self explanatory.\r\n*********Now look back using all the clues instead of 1 at a time. In Clue 1 and Clue 3. More messages when she cleaned her bedroom than the den (#3). In Clue 1, it says she got more messages on Thursday than when she cleaned her room. So she could NOT have cleaned her den on Thursday. That leaves Tuesday and Friday for the den. But remember the order given in Clue 2. The den could not have been cleaned on Tuesday. Den was on Friday, which leaves only one day for the bedroom, which is Monday. Now add in the order in Clue 2, and you know that Thursday she cleaned the bathroom, and Wednesday, when she cleaned the kitchen, she received 1 message. When you know the bathroom was cleaned on Thursday, that leaves one room and one day. The living room was cleaned on Tuesday. That leaves the messages for each day. We know that the bedroom was cleaned on Monday. You should have marked off 1 and 5 messages for the bedroom. So that means that 1 and 5 should be marked off the day the bedroom was cleaned as well. They have to match. Another that doesn't match, is that Friday the den was cleaned. We know that 1 and 5 messages were not received while the den was being cleaned, so 1 and 5 could not have been received on Friday. After marking that 5 off, there is only one day with a five left -- Tuesday. You know that she received more messages on Thursday than when she cleaned her bedroom (Monday). The highest that she could have received on Thursday is 4. So we know that 4 could not have been received on Monday. By the same token, we know that she received more messages when cleaning the bathroom (Thursday) than when cleaning the den (Friday). The highest she could have received on Thursday is 4. So we know that for Friday to be less, she could not receive 4 messages on Friday. This means she received 4 messages on Thursday when she cleaned the bathroom. Looking back at clue 2 gives you the answer for the last section. She received more messages when cleaning her bedroom than when cleaning the den. So she received 3 in the bedroom, and 2 in the den.\n<|im_start|>answer\nAnswers:\n\r\nMonday -- Bedroom -- 3\r\nTuesday -- Living Room -- 5\r\nWednesday -- Kitchen -- 1\r\nThursday -- Bathroom -- 4\r\nFriday -- Den -- 2\n\r\n**Clue #1: If she received more messages on Thursday than on the day she cleaned her bedroom, she could not have received 1 message on Thursday as the day she cleaned her room would have to be 0, which is not an option. She could not have received 5 messages on the day she cleaned her bedroom because Thursday would then have to be at least 6 messages which is not an option. Assume also that she did NOT clean her bedroom on Thursday or Tuesday, as they are mentioned in the same clue. Since she had fewer messages on Thursday than Tuesday, she could not have received 1 message on Tuesday for the same reasons mentioned above. Also by the same token, she could not have received 5 on Thursday because Tuesday would have to be 6. \r\n**Clue #2: 1 message -- bathroom -- den....the order of the happenings in clue 2. therefore, she could not have cleaned the bathroom on Monday, nor the den. Also assume she did not receive 1 message on the bathroom or den cleanings. She could not have cleaned the bathroom on Friday. As that would leave no day for the den, which is the day after. She could not have received 1 message on Thursday or Friday because there would not be enough days to clean the bathroom and den.\r\n**Clue #3: If she received more messages when she cleaned her bedroom than when she cleaned the den, she could not have received 5 messages when she cleaned the den, nor 1 message when she cleaned her bedroom. \r\n**Clue #4: She cleaned the Kitchen on Wednesday..self explanatory.\r\n*********Now look back using all the clues instead of 1 at a time. In Clue 1 and Clue 3. More messages when she cleaned her bedroom than the den (#3). In Clue 1, it says she got more messages on Thursday than when she cleaned her room. So she could NOT have cleaned her den on Thursday. That leaves Tuesday and Friday for the den. But remember the order given in Clue 2. The den could not have been cleaned on Tuesday. Den was on Friday, which leaves only one day for the bedroom, which is Monday. Now add in the order in Clue 2, and you know that Thursday she cleaned the bathroom, and Wednesday, when she cleaned the kitchen, she received 1 message. When you know the bathroom was cleaned on Thursday, that leaves one room and one day. The living room was cleaned on Tuesday. That leaves the messages for each day. We know that the bedroom was cleaned on Monday. You should have marked off 1 and 5 messages for the bedroom. So that means that 1 and 5 should be marked off the day the bedroom was cleaned as well. They have to match. Another that doesn't match, is that Friday the den was cleaned. We know that 1 and 5 messages were not received while the den was being cleaned, so 1 and 5 could not have been received on Friday. After marking that 5 off, there is only one day with a five left -- Tuesday. You know that she received more messages on Thursday than when she cleaned her bedroom (Monday). The highest that she could have received on Thursday is 4. So we know that 4 could not have been received on Monday. By the same token, we know that she received more messages when cleaning the bathroom (Thursday) than when cleaning the den (Friday). The highest she could have received on Thursday is 4. So we know that for Friday to be less, she could not receive 4 messages on Friday. This means she received 4 messages on Thursday when she cleaned the bathroom. Looking back at clue 2 gives you the answer for the last section. She received more messages when cleaning her bedroom than when cleaning the den. So she received 3 in the bedroom, and 2 in the den.\n<|im_end|>" }, { "id": "#4725", "title": "Basket of Oranges", "fun": 2.47, "difficulty": 1.35, "author": "bluetwo", "desc": "A fruit vendor had a basket of oranges. A customer approached him and purchased one half of the oranges plus half an orange. A second customer came and purchased one half of what he had left plus half an orange. A third customer bought one half of what was left plus half an orange, leaving the vendor's basket empty.\n\r\nHe did not cut or break any orange.\n\r\nHow many did he have when he started?", "hint": "No hint available.", "answer": "He started with 7 oranges. Half of 7 + 1/2 an orange = 4, leaving the man with 3 oranges. Half of 3 + 1/2 an orange = 2, leaving the man with one orange. Half of 1 + 1/2 an orange = 1, leaving the man with no more oranges.", "category": "Math", "date": "06/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fruit vendor had a basket of oranges. A customer approached him and purchased one half of the oranges plus half an orange. A second customer came and purchased one half of what he had left plus half an orange. A third customer bought one half of what was left plus half an orange, leaving the vendor's basket empty.\n\r\nHe did not cut or break any orange.\n\r\nHow many did he have when he started?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe started with 7 oranges. Half of 7 + 1/2 an orange = 4, leaving the man with 3 oranges. Half of 3 + 1/2 an orange = 2, leaving the man with one orange. Half of 1 + 1/2 an orange = 1, leaving the man with no more oranges.\n<|im_start|>answer\nHe started with 7 oranges. Half of 7 + 1/2 an orange = 4, leaving the man with 3 oranges. Half of 3 + 1/2 an orange = 2, leaving the man with one orange. Half of 1 + 1/2 an orange = 1, leaving the man with no more oranges.\n<|im_end|>" }, { "id": "#10385", "title": "Good Scientist, Bad Scientist", "fun": 2.47, "difficulty": 1.84, "author": "Codammanus", "desc": "One day, a great scientist gone bad decides to wreak havoc on others in his profession. He has another scientist kidnapped, uses an evil formula that disables 4 of the good scientist's five senses: his sight, his smell, his taste, and his sense of touch. He then has him strapped to a bed very securely. He then says, 'I am going to place a single object in the center of this room with you. If you want to live, you will have something to tell me about the object when I return. Please do not insult my intelligence by telling me that it is an object, or an object that I placed in the room, or anything having to do with me, or the object's location for that matter. We both know it is an object, that I put it here, and that it is in the center of the room. You must therefore state a SCIENTIFIC FACT about the object.'\n\r\nBefore leaving though, he says: 'Silly me, I almost forgot...' (He then disables the good scientists hearing. Now he has none of his senses to work with). He returns after one hour, restores all of the scientist's senses, and says: 'So tell me something about the object professor.' The good scientist saves his own life with his answer, to the chagrin of the evil scientist. \n\r\nWhat, though, could he have possibly said, being that he had no senses?", "hint": "No hint available.", "answer": "The good scientist simply said: 'It is a SCIENTIFIC FACT that the object you placed in the center of the room with me has MASS.'\n\r\nAll OBJECTS have mass.", "category": "Logic", "date": "02/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, a great scientist gone bad decides to wreak havoc on others in his profession. He has another scientist kidnapped, uses an evil formula that disables 4 of the good scientist's five senses: his sight, his smell, his taste, and his sense of touch. He then has him strapped to a bed very securely. He then says, 'I am going to place a single object in the center of this room with you. If you want to live, you will have something to tell me about the object when I return. Please do not insult my intelligence by telling me that it is an object, or an object that I placed in the room, or anything having to do with me, or the object's location for that matter. We both know it is an object, that I put it here, and that it is in the center of the room. You must therefore state a SCIENTIFIC FACT about the object.'\n\r\nBefore leaving though, he says: 'Silly me, I almost forgot...' (He then disables the good scientists hearing. Now he has none of his senses to work with). He returns after one hour, restores all of the scientist's senses, and says: 'So tell me something about the object professor.' The good scientist saves his own life with his answer, to the chagrin of the evil scientist. \n\r\nWhat, though, could he have possibly said, being that he had no senses?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe good scientist simply said: 'It is a SCIENTIFIC FACT that the object you placed in the center of the room with me has MASS.'\n\r\nAll OBJECTS have mass.\n<|im_start|>answer\nThe good scientist simply said: 'It is a SCIENTIFIC FACT that the object you placed in the center of the room with me has MASS.'\n\r\nAll OBJECTS have mass.\n<|im_end|>" }, { "id": "#52177", "title": "The Troll Bridge 6", "fun": 2.47, "difficulty": 2.66, "author": "wimpykidfan37", "desc": "A bridge was guarded by an evil troll. The troll was very intelligent, but he was also a coward. He was afraid of anyone smarter than him. So every time anyone tried to cross the bridge, the troll would set up a test. If the traveler passed the test, he would be allowed to cross. Otherwise, the troll would eat him.\n\r\nA traveler came across the bridge. The troll said, \"You may only cross my bridge if you know the password.\" He then wrote an equation on a rock:\n\r\nSLIDE\r\n-DEAN\r\n______\r\n 3651\n\r\n\"Each letter in the equation represents a different digit,\" said the troll. \"The letters in the password represent 3651.\"\n\r\nSo, what is the password?", "hint": "No hint available.", "answer": "The password is LENS.\n\r\nSince SL-D=3 or (SL-1)-D=3 (meaning SL-D=4), and since the highest possible sum of two different one-digit numbers is 17, S must equal 1.\n\r\nSince SL=1L=10+L, D must be 6 or greater, since 6 is the lowest number that can be added to 4 to get a two-digit number. \n\r\nSuppose D=6. Then L must equal 0. Since D-A (or 1D-A, but this is impossible because 16 or greater minus 5 or 6 is a two-digit number) is 5 or 6, A must equal 0 or 1. But since L=0 and S=1, this cannot work.\n\r\nSuppose D=7. Then L is 0 or 1, and since S=1, L=0. A must be 1 or 2, but since S=1, A=2.\n\r\nSuppose D=8. Then L is 1 or 2, and since S=1, L=2. A must be 2 or 3, but since L=2, A=3.\n\r\nSuppose D=9. Then L is 2 or 3, and A is 3 or 4. Therefore, either L=2 and A=3, L=2 and A=4, or L=3 and A=4.\n\r\nThe only possibility for D-A=6 is D=9 and A=3. Since 1 is carried from D to E, N must equal 9, since that's the only one-digit number that can be added to 1 to get a two-digit number. But since D=9, this cannot work.\n\r\nTherefore, D-A=5, and E-N=1. Since 1 could not have been carried from D to E, E cannot be 0. Since S=1, E cannot be 1. If E=2, then N=1, which cannot work because S=1. If E=3, then N=2. But if D=7, A=2. If D=8, then L=2 and A=3. If D=9, then L is either 2 or 3. So E cannot be 3.\n\r\nTherefore, E is 4 or greater. Since 4+6 is a two-digit number, 1 must have been carried over from L to I, and 1L-D=4.\n\r\nIf D=7, then L=0. But since 10-7=3, D cannot be 7.\n\r\nIf D=9, then L=3 and A=4.\n\r\nIf E=4, then N=3. But if D=8, A=3, and if D=9, L=3 and A=4. So this cannot work.\n\r\nIf E=5, then since 1I-E=6, I=1. But since S=1, this cannot work.\n\r\nIf E=7, then I=3. But if D=8, then A=3, and if D=9, then L=3. So this cannot work.\n\r\nIf E=8, then I=4, and D cannot be 8. But if D=9, then A=4. So this cannot work.\n\r\nIf E=9, then N=8, and D cannot be 8 or 9. So this cannot work.\n\r\nTherefore, E=6, N=5, and I=2. If D=8, then L=2, so D must equal 9. This means:\n\r\nS=1, I=2, L=3, A=4, N=5, E=6, and D=9.\n\r\nTherefore, 3651=LENS.", "category": "Math", "date": "06/01/19", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bridge was guarded by an evil troll. The troll was very intelligent, but he was also a coward. He was afraid of anyone smarter than him. So every time anyone tried to cross the bridge, the troll would set up a test. If the traveler passed the test, he would be allowed to cross. Otherwise, the troll would eat him.\n\r\nA traveler came across the bridge. The troll said, \"You may only cross my bridge if you know the password.\" He then wrote an equation on a rock:\n\r\nSLIDE\r\n-DEAN\r\n______\r\n 3651\n\r\n\"Each letter in the equation represents a different digit,\" said the troll. \"The letters in the password represent 3651.\"\n\r\nSo, what is the password?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe password is LENS.\n\r\nSince SL-D=3 or (SL-1)-D=3 (meaning SL-D=4), and since the highest possible sum of two different one-digit numbers is 17, S must equal 1.\n\r\nSince SL=1L=10+L, D must be 6 or greater, since 6 is the lowest number that can be added to 4 to get a two-digit number. \n\r\nSuppose D=6. Then L must equal 0. Since D-A (or 1D-A, but this is impossible because 16 or greater minus 5 or 6 is a two-digit number) is 5 or 6, A must equal 0 or 1. But since L=0 and S=1, this cannot work.\n\r\nSuppose D=7. Then L is 0 or 1, and since S=1, L=0. A must be 1 or 2, but since S=1, A=2.\n\r\nSuppose D=8. Then L is 1 or 2, and since S=1, L=2. A must be 2 or 3, but since L=2, A=3.\n\r\nSuppose D=9. Then L is 2 or 3, and A is 3 or 4. Therefore, either L=2 and A=3, L=2 and A=4, or L=3 and A=4.\n\r\nThe only possibility for D-A=6 is D=9 and A=3. Since 1 is carried from D to E, N must equal 9, since that's the only one-digit number that can be added to 1 to get a two-digit number. But since D=9, this cannot work.\n\r\nTherefore, D-A=5, and E-N=1. Since 1 could not have been carried from D to E, E cannot be 0. Since S=1, E cannot be 1. If E=2, then N=1, which cannot work because S=1. If E=3, then N=2. But if D=7, A=2. If D=8, then L=2 and A=3. If D=9, then L is either 2 or 3. So E cannot be 3.\n\r\nTherefore, E is 4 or greater. Since 4+6 is a two-digit number, 1 must have been carried over from L to I, and 1L-D=4.\n\r\nIf D=7, then L=0. But since 10-7=3, D cannot be 7.\n\r\nIf D=9, then L=3 and A=4.\n\r\nIf E=4, then N=3. But if D=8, A=3, and if D=9, L=3 and A=4. So this cannot work.\n\r\nIf E=5, then since 1I-E=6, I=1. But since S=1, this cannot work.\n\r\nIf E=7, then I=3. But if D=8, then A=3, and if D=9, then L=3. So this cannot work.\n\r\nIf E=8, then I=4, and D cannot be 8. But if D=9, then A=4. So this cannot work.\n\r\nIf E=9, then N=8, and D cannot be 8 or 9. So this cannot work.\n\r\nTherefore, E=6, N=5, and I=2. If D=8, then L=2, so D must equal 9. This means:\n\r\nS=1, I=2, L=3, A=4, N=5, E=6, and D=9.\n\r\nTherefore, 3651=LENS.\n<|im_start|>answer\nThe password is LENS.\n\r\nSince SL-D=3 or (SL-1)-D=3 (meaning SL-D=4), and since the highest possible sum of two different one-digit numbers is 17, S must equal 1.\n\r\nSince SL=1L=10+L, D must be 6 or greater, since 6 is the lowest number that can be added to 4 to get a two-digit number. \n\r\nSuppose D=6. Then L must equal 0. Since D-A (or 1D-A, but this is impossible because 16 or greater minus 5 or 6 is a two-digit number) is 5 or 6, A must equal 0 or 1. But since L=0 and S=1, this cannot work.\n\r\nSuppose D=7. Then L is 0 or 1, and since S=1, L=0. A must be 1 or 2, but since S=1, A=2.\n\r\nSuppose D=8. Then L is 1 or 2, and since S=1, L=2. A must be 2 or 3, but since L=2, A=3.\n\r\nSuppose D=9. Then L is 2 or 3, and A is 3 or 4. Therefore, either L=2 and A=3, L=2 and A=4, or L=3 and A=4.\n\r\nThe only possibility for D-A=6 is D=9 and A=3. Since 1 is carried from D to E, N must equal 9, since that's the only one-digit number that can be added to 1 to get a two-digit number. But since D=9, this cannot work.\n\r\nTherefore, D-A=5, and E-N=1. Since 1 could not have been carried from D to E, E cannot be 0. Since S=1, E cannot be 1. If E=2, then N=1, which cannot work because S=1. If E=3, then N=2. But if D=7, A=2. If D=8, then L=2 and A=3. If D=9, then L is either 2 or 3. So E cannot be 3.\n\r\nTherefore, E is 4 or greater. Since 4+6 is a two-digit number, 1 must have been carried over from L to I, and 1L-D=4.\n\r\nIf D=7, then L=0. But since 10-7=3, D cannot be 7.\n\r\nIf D=9, then L=3 and A=4.\n\r\nIf E=4, then N=3. But if D=8, A=3, and if D=9, L=3 and A=4. So this cannot work.\n\r\nIf E=5, then since 1I-E=6, I=1. But since S=1, this cannot work.\n\r\nIf E=7, then I=3. But if D=8, then A=3, and if D=9, then L=3. So this cannot work.\n\r\nIf E=8, then I=4, and D cannot be 8. But if D=9, then A=4. So this cannot work.\n\r\nIf E=9, then N=8, and D cannot be 8 or 9. So this cannot work.\n\r\nTherefore, E=6, N=5, and I=2. If D=8, then L=2, so D must equal 9. This means:\n\r\nS=1, I=2, L=3, A=4, N=5, E=6, and D=9.\n\r\nTherefore, 3651=LENS.\n<|im_end|>" }, { "id": "#51014", "title": "Gold Breakout", "fun": 2.47, "difficulty": 1.56, "author": "ultimatecub", "desc": "Someone has broken into one of the city's most secure bank vaults and stolen some gold bullion. Six suspects have been rounded up. Use the clues to try and narrow down the list of suspects.\n\r\nThe suspects are Alex, Beth, Charlotte, Dave, Emily, and Frank.\n\n\r\nClues:\r\n1. A suspicious-looking masked person dressed in a black hoodie and thick trousers was seen with a bank certified tool kit labelled VAULT MAINTENANCE near the vault.\r\n2. 200 lbs of gold was stolen; 100 lbs carried by each thief.\r\n3. Emily and Dave are workers at the bank.\r\n4. All the suspects are health and fitness fanatics except Dave and Beth.\r\n5. The passages between the vault and the bank entrance are long, narrow, and it is easy to get lost in them.\r\n6. Two people were seen from a distance running to the bank entrance carrying sacks.\r\n7. All the suspects were informed that the theft happened on Saturday night.\r\n8. Alex claimed to have been eating at the fast food place with his friends each evening from last Sunday to Saturday so he couldn't have done it.\r\n9. Frank broke his arm a few days before the theft.\r\n10. Charlotte works as a medical consultant and claimed that she was at home on Saturday night.\r\n11. The bank is very secure.\r\n12. Beth works as a receptionist.\n\n\r\nUse the clues. Which of the suspects should be questioned further?", "hint": "No hint available.", "answer": "Alex and Emily should be investigated further.\r\nFrank is unlikely to have done it since he broke his arm (clue 9) and the criminals were running carrying heavy amounts of gold (clues 2 and 6).\n\n\r\nBeth is unlikely to have done it since she does not work out much (clue 4) and it might be difficult to carry a heavy amount of gold (clue 2) a long way (clue 5).\n\n\r\nIf Alex is one of the health and fitness fanatics (clue 4), what is the probability of him being at the fast food place for six consecutive evenings in a row? This statement is slightly suspicious and further investigation is required.\n\n\r\nSince the bank is very secure (clue 11), and the passages between the vault and bank entrance are long and narrow (clue 5), Emily is a potential suspect. As the bank is secure, it would probably take an employee of the bank to get hold of the gold (Emily or Dave). Since Dave doesn't work out much (clue 4), it would be difficult for him to carry a heavy load of gold a long way while running (clue 6). That leaves Emily.", "category": "Logic", "date": "03/23/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSomeone has broken into one of the city's most secure bank vaults and stolen some gold bullion. Six suspects have been rounded up. Use the clues to try and narrow down the list of suspects.\n\r\nThe suspects are Alex, Beth, Charlotte, Dave, Emily, and Frank.\n\n\r\nClues:\r\n1. A suspicious-looking masked person dressed in a black hoodie and thick trousers was seen with a bank certified tool kit labelled VAULT MAINTENANCE near the vault.\r\n2. 200 lbs of gold was stolen; 100 lbs carried by each thief.\r\n3. Emily and Dave are workers at the bank.\r\n4. All the suspects are health and fitness fanatics except Dave and Beth.\r\n5. The passages between the vault and the bank entrance are long, narrow, and it is easy to get lost in them.\r\n6. Two people were seen from a distance running to the bank entrance carrying sacks.\r\n7. All the suspects were informed that the theft happened on Saturday night.\r\n8. Alex claimed to have been eating at the fast food place with his friends each evening from last Sunday to Saturday so he couldn't have done it.\r\n9. Frank broke his arm a few days before the theft.\r\n10. Charlotte works as a medical consultant and claimed that she was at home on Saturday night.\r\n11. The bank is very secure.\r\n12. Beth works as a receptionist.\n\n\r\nUse the clues. Which of the suspects should be questioned further?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlex and Emily should be investigated further.\r\nFrank is unlikely to have done it since he broke his arm (clue 9) and the criminals were running carrying heavy amounts of gold (clues 2 and 6).\n\n\r\nBeth is unlikely to have done it since she does not work out much (clue 4) and it might be difficult to carry a heavy amount of gold (clue 2) a long way (clue 5).\n\n\r\nIf Alex is one of the health and fitness fanatics (clue 4), what is the probability of him being at the fast food place for six consecutive evenings in a row? This statement is slightly suspicious and further investigation is required.\n\n\r\nSince the bank is very secure (clue 11), and the passages between the vault and bank entrance are long and narrow (clue 5), Emily is a potential suspect. As the bank is secure, it would probably take an employee of the bank to get hold of the gold (Emily or Dave). Since Dave doesn't work out much (clue 4), it would be difficult for him to carry a heavy load of gold a long way while running (clue 6). That leaves Emily.\n<|im_start|>answer\nAlex and Emily should be investigated further.\r\nFrank is unlikely to have done it since he broke his arm (clue 9) and the criminals were running carrying heavy amounts of gold (clues 2 and 6).\n\n\r\nBeth is unlikely to have done it since she does not work out much (clue 4) and it might be difficult to carry a heavy amount of gold (clue 2) a long way (clue 5).\n\n\r\nIf Alex is one of the health and fitness fanatics (clue 4), what is the probability of him being at the fast food place for six consecutive evenings in a row? This statement is slightly suspicious and further investigation is required.\n\n\r\nSince the bank is very secure (clue 11), and the passages between the vault and bank entrance are long and narrow (clue 5), Emily is a potential suspect. As the bank is secure, it would probably take an employee of the bank to get hold of the gold (Emily or Dave). Since Dave doesn't work out much (clue 4), it would be difficult for him to carry a heavy load of gold a long way while running (clue 6). That leaves Emily.\n<|im_end|>" }, { "id": "#1872", "title": "Math and Money", "fun": 2.47, "difficulty": 1.47, "author": "missie", "desc": "In order to encourage his son to study math, a father agrees to pay his boy 8 cents for every problem correctly solved and to fine him 5 cents for each incorrect solution. At the end of 26 problems, neither owes anything to the other.\n\r\nHow many problems did the boy solve correctly?", "hint": "No hint available.", "answer": "Ten Problems\n\r\nlet x represent the number of problems answered correctly, then 26-x represent the number of problems answered incorrectly:\n\r\n8x - 5(26-x) = 0\r\n8x - 130+5x = 0\r\n13x = 130\r\nx = 10\r\n26-x = 16\n\r\nTherefore, 10 answers were correct and 16 were incorrect.", "category": "Math", "date": "12/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn order to encourage his son to study math, a father agrees to pay his boy 8 cents for every problem correctly solved and to fine him 5 cents for each incorrect solution. At the end of 26 problems, neither owes anything to the other.\n\r\nHow many problems did the boy solve correctly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTen Problems\n\r\nlet x represent the number of problems answered correctly, then 26-x represent the number of problems answered incorrectly:\n\r\n8x - 5(26-x) = 0\r\n8x - 130+5x = 0\r\n13x = 130\r\nx = 10\r\n26-x = 16\n\r\nTherefore, 10 answers were correct and 16 were incorrect.\n<|im_start|>answer\nTen Problems\n\r\nlet x represent the number of problems answered correctly, then 26-x represent the number of problems answered incorrectly:\n\r\n8x - 5(26-x) = 0\r\n8x - 130+5x = 0\r\n13x = 130\r\nx = 10\r\n26-x = 16\n\r\nTherefore, 10 answers were correct and 16 were incorrect.\n<|im_end|>" }, { "id": "#45521", "title": "How Old is Hannah?", "fun": 2.47, "difficulty": 0.85, "author": "dowinka", "desc": "Fiona is 4 years old. Hannah is 4 times as old as Sasha. Sasha is 5 years older than Fiona's cousin Andrew, who is 1 year older than Nick, Fiona's twin brother. How old is Hannah?", "hint": "No hint available.", "answer": "Hannah is 40 years old.", "category": "Math", "date": "10/21/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFiona is 4 years old. Hannah is 4 times as old as Sasha. Sasha is 5 years older than Fiona's cousin Andrew, who is 1 year older than Nick, Fiona's twin brother. How old is Hannah?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHannah is 40 years old.\n<|im_start|>answer\nHannah is 40 years old.\n<|im_end|>" }, { "id": "#37844", "title": "Apartment Building 20234", "fun": 2.47, "difficulty": 1.18, "author": "ava199345", "desc": "In apartment building 20234, there live six best friends. Each of them lives on a different floor of the building. Can you figure out who lives on which floor?\n\r\n1) Andrea lives below Ben, yet above Jade.\r\n2) Ben lives below Kim, yet above Mike.\r\n3) Mike lives below Andrea, yet above Jade.\r\n4) John lives on the first floor.", "hint": "No hint available.", "answer": "6th floor-Kim\r\n5th floor-Ben\r\n4th floor-Andrea\r\n3rd floor-Mike\r\n2nd floor-Jade\r\n1st floor-John", "category": "Logic", "date": "08/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn apartment building 20234, there live six best friends. Each of them lives on a different floor of the building. Can you figure out who lives on which floor?\n\r\n1) Andrea lives below Ben, yet above Jade.\r\n2) Ben lives below Kim, yet above Mike.\r\n3) Mike lives below Andrea, yet above Jade.\r\n4) John lives on the first floor.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6th floor-Kim\r\n5th floor-Ben\r\n4th floor-Andrea\r\n3rd floor-Mike\r\n2nd floor-Jade\r\n1st floor-John\n<|im_start|>answer\n6th floor-Kim\r\n5th floor-Ben\r\n4th floor-Andrea\r\n3rd floor-Mike\r\n2nd floor-Jade\r\n1st floor-John\n<|im_end|>" }, { "id": "#35877", "title": "Crack the Code III", "fun": 2.47, "difficulty": 2.82, "author": "peanut", "desc": "Your sister has jetted off to Europe on holiday and has left you to watch over her house and feed the cats. She is very protective over her precious cats and, hence, has a high-tech alarm system which requires a 10-digit code to deactivate it. Unfortunately, you have forgotten the code to disarm the alarm! Oddly however, you remember some mathematical facts about them...\n\r\nCan you figure it out in time to feed the hungry cats?!?\n\r\n* Each digit from 0 to 9 is used once only in the code.\n\r\n* The sum of the numbers in the 3rd and 4th positions is equal to the product of the numbers in the 6th and 9th positions.\n\r\n* The product of the numbers in the 5th and 10th positions is odd.\n\r\n* The 2nd number (i.e. the number in the 2nd position) is larger than the 5th, which is larger than the 7th.\n\r\n* The 8th number is larger than the 6th, which is larger than the 2nd.\n\r\n* The sum of the 2nd, 6th, and 9th numbers is a perfect square.\n\r\n* The sum of the 4th and 9th numbers is equal to the 10th number.\n\r\n* The sum of the 1st and 5th numbers is equal to the sum of the 7th and 10th numbers.\n\r\n* The number in the 9th position is even.", "hint": "The number in the 9th position is 4.", "answer": "8 2 7 5 1 3 0 6 4 9", "category": "Logic", "date": "03/25/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour sister has jetted off to Europe on holiday and has left you to watch over her house and feed the cats. She is very protective over her precious cats and, hence, has a high-tech alarm system which requires a 10-digit code to deactivate it. Unfortunately, you have forgotten the code to disarm the alarm! Oddly however, you remember some mathematical facts about them...\n\r\nCan you figure it out in time to feed the hungry cats?!?\n\r\n* Each digit from 0 to 9 is used once only in the code.\n\r\n* The sum of the numbers in the 3rd and 4th positions is equal to the product of the numbers in the 6th and 9th positions.\n\r\n* The product of the numbers in the 5th and 10th positions is odd.\n\r\n* The 2nd number (i.e. the number in the 2nd position) is larger than the 5th, which is larger than the 7th.\n\r\n* The 8th number is larger than the 6th, which is larger than the 2nd.\n\r\n* The sum of the 2nd, 6th, and 9th numbers is a perfect square.\n\r\n* The sum of the 4th and 9th numbers is equal to the 10th number.\n\r\n* The sum of the 1st and 5th numbers is equal to the sum of the 7th and 10th numbers.\n\r\n* The number in the 9th position is even.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8 2 7 5 1 3 0 6 4 9\n<|im_start|>answer\n8 2 7 5 1 3 0 6 4 9\n<|im_end|>" }, { "id": "#2356", "title": "Poles and Strings", "fun": 2.47, "difficulty": 2.29, "author": "KevThaDrinkKilla", "desc": "You have two vertical poles. One stands at 6ft. 6in, the other at 7ft. 7in. From the top of each pole tie a string to the bottom of the other pole. \n\r\nAt what height do the two strings cross?", "hint": "It doesn't matter how far apart they are", "answer": "42 inches.\n\r\nYou multiply the height of the two poles and then divide that by the sum of the two heights.. \n\r\n(78 x 91) divided by (78 + 91) = 42", "category": "Math", "date": "02/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two vertical poles. One stands at 6ft. 6in, the other at 7ft. 7in. From the top of each pole tie a string to the bottom of the other pole. \n\r\nAt what height do the two strings cross?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n42 inches.\n\r\nYou multiply the height of the two poles and then divide that by the sum of the two heights.. \n\r\n(78 x 91) divided by (78 + 91) = 42\n<|im_start|>answer\n42 inches.\n\r\nYou multiply the height of the two poles and then divide that by the sum of the two heights.. \n\r\n(78 x 91) divided by (78 + 91) = 42\n<|im_end|>" }, { "id": "#4993", "title": "Two Frogs and The Well", "fun": 2.47, "difficulty": 1.41, "author": "missie", "desc": "During a long, hot summer, the pond where two frogs lived dried up. When the rain failed to come, the frogs left their home in search of water. Sometime later they passed a deep well. On seeing the water below, one frog said, \"Why not make this our new home? Look at all the water down there!\"\r\nThe second frog responded and the first frog immediately felt foolish for suggesting such a thing. What'd the second frog say?", "hint": "What happened to the lake?", "answer": "He said, \"There may be more water down there now, but if it dries up, how will we get back out?\"", "category": "Logic", "date": "06/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a long, hot summer, the pond where two frogs lived dried up. When the rain failed to come, the frogs left their home in search of water. Sometime later they passed a deep well. On seeing the water below, one frog said, \"Why not make this our new home? Look at all the water down there!\"\r\nThe second frog responded and the first frog immediately felt foolish for suggesting such a thing. What'd the second frog say?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe said, \"There may be more water down there now, but if it dries up, how will we get back out?\"\n<|im_start|>answer\nHe said, \"There may be more water down there now, but if it dries up, how will we get back out?\"\n<|im_end|>" }, { "id": "#31761", "title": "Original Number", "fun": 2.47, "difficulty": 2.75, "author": "kiss", "desc": "Take a five-digit number and reverse it. Subtract the original number from the reversed number and you are left with 33957.\n\r\nHow many different possibilities does the original number have?", "hint": "Work from the first and last digits.", "answer": "Suppose that the original number is abcde. Then edcba-abcde=33957.\n\r\nSince e>a, we must have e=a+3 and therefore d=b+4, and c can be any digit.\n\r\na can be 1 to 6 and e 4 to 9, b can be 0 to 5 and d 4 to 9, each pair has 6 possibilities, and c has 10 possibilities.\n\r\nTherefore, the original number has 6*6*10=360 different possibilities.", "category": "Math", "date": "07/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTake a five-digit number and reverse it. Subtract the original number from the reversed number and you are left with 33957.\n\r\nHow many different possibilities does the original number have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSuppose that the original number is abcde. Then edcba-abcde=33957.\n\r\nSince e>a, we must have e=a+3 and therefore d=b+4, and c can be any digit.\n\r\na can be 1 to 6 and e 4 to 9, b can be 0 to 5 and d 4 to 9, each pair has 6 possibilities, and c has 10 possibilities.\n\r\nTherefore, the original number has 6*6*10=360 different possibilities.\n<|im_start|>answer\nSuppose that the original number is abcde. Then edcba-abcde=33957.\n\r\nSince e>a, we must have e=a+3 and therefore d=b+4, and c can be any digit.\n\r\na can be 1 to 6 and e 4 to 9, b can be 0 to 5 and d 4 to 9, each pair has 6 possibilities, and c has 10 possibilities.\n\r\nTherefore, the original number has 6*6*10=360 different possibilities.\n<|im_end|>" }, { "id": "#3459", "title": "Pitches", "fun": 2.47, "difficulty": 1.87, "author": "pusandave", "desc": "What is the minimum number of pitches that could be thrown in a professional baseball game?", "hint": "No hint available.", "answer": "52. \n\r\nThe minimum number of pitches per batter is one. If each batter hit a ball in play and flies out or is thrown out then there would be 6 pitches per inning. Since someone must win in order to finish the game without extra innings, one player could hit a home run on the first pitch. If the home team is the team that hits the home run, and all of the other batters were out in one pitch, then the game would end at the middle of the 9th inning. This would be 6 pitches per inning for eight innings, plus one for the home run, plus 3 for the top of the ninth. Grand total 52 minimum pitches to win a baseball game.", "category": "Logic", "date": "04/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the minimum number of pitches that could be thrown in a professional baseball game?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n52. \n\r\nThe minimum number of pitches per batter is one. If each batter hit a ball in play and flies out or is thrown out then there would be 6 pitches per inning. Since someone must win in order to finish the game without extra innings, one player could hit a home run on the first pitch. If the home team is the team that hits the home run, and all of the other batters were out in one pitch, then the game would end at the middle of the 9th inning. This would be 6 pitches per inning for eight innings, plus one for the home run, plus 3 for the top of the ninth. Grand total 52 minimum pitches to win a baseball game.\n<|im_start|>answer\n52. \n\r\nThe minimum number of pitches per batter is one. If each batter hit a ball in play and flies out or is thrown out then there would be 6 pitches per inning. Since someone must win in order to finish the game without extra innings, one player could hit a home run on the first pitch. If the home team is the team that hits the home run, and all of the other batters were out in one pitch, then the game would end at the middle of the 9th inning. This would be 6 pitches per inning for eight innings, plus one for the home run, plus 3 for the top of the ninth. Grand total 52 minimum pitches to win a baseball game.\n<|im_end|>" }, { "id": "#3626", "title": "Wine Tasting", "fun": 2.47, "difficulty": 1.8800000000000001, "author": "valeriy", "desc": "One company was making two different kinds of wine, which had very similar taste. One sunny day 3 friends were sitting outside and drinking one of the wines. Kostya walked up to them and bet that he could tell which wine is which. They made a deal. The friends tied his eyes, brought a bottle of the other wine, and let him drink a cup of each wine. Kostya guessed which wine was which. And the three friends would have paid Kostya if an old man had not passed by. He said that the bet wasn't fair.\n\r\nWhat was unfair about the bet?", "hint": "No hint available.", "answer": "The second bottle that the friends brought was cold.", "category": "Logic", "date": "04/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne company was making two different kinds of wine, which had very similar taste. One sunny day 3 friends were sitting outside and drinking one of the wines. Kostya walked up to them and bet that he could tell which wine is which. They made a deal. The friends tied his eyes, brought a bottle of the other wine, and let him drink a cup of each wine. Kostya guessed which wine was which. And the three friends would have paid Kostya if an old man had not passed by. He said that the bet wasn't fair.\n\r\nWhat was unfair about the bet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe second bottle that the friends brought was cold.\n<|im_start|>answer\nThe second bottle that the friends brought was cold.\n<|im_end|>" }, { "id": "#16579", "title": "Study Time", "fun": 2.47, "difficulty": 2.6, "author": "absy", "desc": "In order to best use his study time, Caleb has enlisted the help of four other students in his philosophy class by forming a study group. Each of the five students is assigned to read one of the first 5 chapters of their text Great Minds Don't Necessarily Think Alike, and prepare a summary of the chapter to present to the group. Can you determine the title of each of the five chapters, as well as the student responsible for reading it?\n\r\nGiven:\n\r\nChapters -- \t\t1, 2, 3, 4, 5\r\nChapter Titles --\t\tDescartes Before DesHorse, Freudian Slippers, I Kant Understand It, Jung At Heart, Sense of Hume-or\r\nStudent Names -- \tAlex, Caleb, Joan, Kiera, Toby\n\r\nClues:\n\r\n#1) Alex's chapter immediately follows \"Sense of Hume-or\" and immediately precedes \"Descartes Before DesHorse.\"\r\n#2) \"Jung At Heart\" is the name of a chapter that comes somewhere before the chapter assigned to Toby.\r\n#3) Kiera's chapter is three chapters after \"Freudian Slippers.\"\r\n#4) Two consecutive chapters, in one order or the another, are \"I Kant Understand It\" and Joan's chapter (which isn't chapter four)", "hint": "Hints:\n\r\nMake a list of one set of givens and list another set of givens that would correspond to them... i.e. (Chapter Numbers) -- (Titles)\n\r\nChap 1 -- Des, Freud, I Kant, Jung, Sense\r\nChap 2 -- Des, Freud, I Kant, Jung, Sense, etc.\n\r\nCross off what you know is NOT the correct answer from the clues, and when you find a chapter number that fits a title, circle it, or write the information on the piece of paper in a different section to keep track. Do the same with the other correlations that can be surmised by looking at the clues: \n\r\n(Chapter Names) -- (Students Names)\r\n(Student Names) -- (Chapter Numbers)\n\r\nKeep in mind that for example, if you find a chapter number for a title, the other chapter numbers can NOT have that title, so that gives you another answer to mark off to narrow the correct answer down.", "answer": "Answers:\n\r\nChapter 1 -- \"Jung At Heart\" -- Caleb\r\nChapter 2 -- \"Freudian Slippers\" -- Toby\r\nChapter 3 -- \"Sense of Hume-or\" -- Joan\r\nChapter 4 -- \"I Kant Understand It\" -- Alex\r\nChapter 5 -- \"Descartes Before DesHorse\" -- Kiera \n\r\n**Clue #1: This gives us an order. We know that three of the chapters are, in this order, (Sense, Alex's, Descartes). Therefore, Alex's chapter can not be the first chapter, or the last. \"Sense\" can not be the last chapter, and \"Descartes\" can not be the first. We can also assume that \"Sense\" nor \"Descartes\" is Alex's chapter. \r\n**Clue #2: This lets us know that Toby's chapter can not be the first chapter, and that \"Jung\" can not be the last chapter. We assume \"Jung\" is not Toby's chapter. \r\n**Clue #3: If Kiera's chapter is three AFTER \"Freud\", then \"Freud\" can NOT be the 3rd, 4th or 5th chapter. This also means that Kiera's chapter can not be the 1st, 2nd, or 3rd chapters.\r\n**Clue #4: Joan's chapter is not 4th. If \"Kant\" is 5th, Joan's would be 4th. So we know that \"Kant\" is not the 5th chapter. That leaves \"Descartes\" as the 5th chapter. Assume Joan's chapter is not \"Kant.\" \r\n*********Recall the order given in Clue 1. This means Alex's chapter is 4th, and \"Sense\" is 3rd. This also leaves Kiera's as the 5th chapter, which is \"Descartes\". For hers to be 3 after \"Freud\", \"Freud\" has the be the 2nd chapter. We know that \"Jung\" comes before Toby's chapter. This leaves chapters 1 and 4. If \"Jung\" is chapter 4, Toby's would be 5, but we know that 5 is Kiera's, so \"Jung\" has to be chapter 1. This makes \"Kant\" chapter 4, and Alex's chapter. This means that Joans has to be the 3rd or the 5th because of the order between Joan's chapter and \"Kant\" that we were already given, and we already know that Kiera has the 5th chapter. So we know that Joan has chapter 3, \"Sense.\" After marking off the chapter numbers by the names, you see that Toby's is chapter 2, \"Freud\" and that leaves Caleb with chapter 1, \"Jung.\"", "category": "Logic", "date": "02/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn order to best use his study time, Caleb has enlisted the help of four other students in his philosophy class by forming a study group. Each of the five students is assigned to read one of the first 5 chapters of their text Great Minds Don't Necessarily Think Alike, and prepare a summary of the chapter to present to the group. Can you determine the title of each of the five chapters, as well as the student responsible for reading it?\n\r\nGiven:\n\r\nChapters -- \t\t1, 2, 3, 4, 5\r\nChapter Titles --\t\tDescartes Before DesHorse, Freudian Slippers, I Kant Understand It, Jung At Heart, Sense of Hume-or\r\nStudent Names -- \tAlex, Caleb, Joan, Kiera, Toby\n\r\nClues:\n\r\n#1) Alex's chapter immediately follows \"Sense of Hume-or\" and immediately precedes \"Descartes Before DesHorse.\"\r\n#2) \"Jung At Heart\" is the name of a chapter that comes somewhere before the chapter assigned to Toby.\r\n#3) Kiera's chapter is three chapters after \"Freudian Slippers.\"\r\n#4) Two consecutive chapters, in one order or the another, are \"I Kant Understand It\" and Joan's chapter (which isn't chapter four)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswers:\n\r\nChapter 1 -- \"Jung At Heart\" -- Caleb\r\nChapter 2 -- \"Freudian Slippers\" -- Toby\r\nChapter 3 -- \"Sense of Hume-or\" -- Joan\r\nChapter 4 -- \"I Kant Understand It\" -- Alex\r\nChapter 5 -- \"Descartes Before DesHorse\" -- Kiera \n\r\n**Clue #1: This gives us an order. We know that three of the chapters are, in this order, (Sense, Alex's, Descartes). Therefore, Alex's chapter can not be the first chapter, or the last. \"Sense\" can not be the last chapter, and \"Descartes\" can not be the first. We can also assume that \"Sense\" nor \"Descartes\" is Alex's chapter. \r\n**Clue #2: This lets us know that Toby's chapter can not be the first chapter, and that \"Jung\" can not be the last chapter. We assume \"Jung\" is not Toby's chapter. \r\n**Clue #3: If Kiera's chapter is three AFTER \"Freud\", then \"Freud\" can NOT be the 3rd, 4th or 5th chapter. This also means that Kiera's chapter can not be the 1st, 2nd, or 3rd chapters.\r\n**Clue #4: Joan's chapter is not 4th. If \"Kant\" is 5th, Joan's would be 4th. So we know that \"Kant\" is not the 5th chapter. That leaves \"Descartes\" as the 5th chapter. Assume Joan's chapter is not \"Kant.\" \r\n*********Recall the order given in Clue 1. This means Alex's chapter is 4th, and \"Sense\" is 3rd. This also leaves Kiera's as the 5th chapter, which is \"Descartes\". For hers to be 3 after \"Freud\", \"Freud\" has the be the 2nd chapter. We know that \"Jung\" comes before Toby's chapter. This leaves chapters 1 and 4. If \"Jung\" is chapter 4, Toby's would be 5, but we know that 5 is Kiera's, so \"Jung\" has to be chapter 1. This makes \"Kant\" chapter 4, and Alex's chapter. This means that Joans has to be the 3rd or the 5th because of the order between Joan's chapter and \"Kant\" that we were already given, and we already know that Kiera has the 5th chapter. So we know that Joan has chapter 3, \"Sense.\" After marking off the chapter numbers by the names, you see that Toby's is chapter 2, \"Freud\" and that leaves Caleb with chapter 1, \"Jung.\"\n<|im_start|>answer\nAnswers:\n\r\nChapter 1 -- \"Jung At Heart\" -- Caleb\r\nChapter 2 -- \"Freudian Slippers\" -- Toby\r\nChapter 3 -- \"Sense of Hume-or\" -- Joan\r\nChapter 4 -- \"I Kant Understand It\" -- Alex\r\nChapter 5 -- \"Descartes Before DesHorse\" -- Kiera \n\r\n**Clue #1: This gives us an order. We know that three of the chapters are, in this order, (Sense, Alex's, Descartes). Therefore, Alex's chapter can not be the first chapter, or the last. \"Sense\" can not be the last chapter, and \"Descartes\" can not be the first. We can also assume that \"Sense\" nor \"Descartes\" is Alex's chapter. \r\n**Clue #2: This lets us know that Toby's chapter can not be the first chapter, and that \"Jung\" can not be the last chapter. We assume \"Jung\" is not Toby's chapter. \r\n**Clue #3: If Kiera's chapter is three AFTER \"Freud\", then \"Freud\" can NOT be the 3rd, 4th or 5th chapter. This also means that Kiera's chapter can not be the 1st, 2nd, or 3rd chapters.\r\n**Clue #4: Joan's chapter is not 4th. If \"Kant\" is 5th, Joan's would be 4th. So we know that \"Kant\" is not the 5th chapter. That leaves \"Descartes\" as the 5th chapter. Assume Joan's chapter is not \"Kant.\" \r\n*********Recall the order given in Clue 1. This means Alex's chapter is 4th, and \"Sense\" is 3rd. This also leaves Kiera's as the 5th chapter, which is \"Descartes\". For hers to be 3 after \"Freud\", \"Freud\" has the be the 2nd chapter. We know that \"Jung\" comes before Toby's chapter. This leaves chapters 1 and 4. If \"Jung\" is chapter 4, Toby's would be 5, but we know that 5 is Kiera's, so \"Jung\" has to be chapter 1. This makes \"Kant\" chapter 4, and Alex's chapter. This means that Joans has to be the 3rd or the 5th because of the order between Joan's chapter and \"Kant\" that we were already given, and we already know that Kiera has the 5th chapter. So we know that Joan has chapter 3, \"Sense.\" After marking off the chapter numbers by the names, you see that Toby's is chapter 2, \"Freud\" and that leaves Caleb with chapter 1, \"Jung.\"\n<|im_end|>" }, { "id": "#27302", "title": "Books", "fun": 2.47, "difficulty": 1.68, "author": "smarty008", "desc": "Andrew has a random number of books. Only one of the following statements is true.\n\r\n1. Andrew has at least 72 books.\n\r\n2. Andrew has at least 62 books.\n\r\n3. Andrew has at least 42 books.\n\r\nWhat is the biggest amount of books Andrew can have?", "hint": "No hint available.", "answer": "61.\n\r\nFrom 72 to infinity, 3 statements would be true.\n\r\nFrom 62 to 71, 2 statements would be true.\n\r\nFrom 42 to 61, 1 statement would be true.\n\r\nFrom 0 to 41, 0 statements would be true.\r\nBetween 42 and 61, 61 would be the biggest.", "category": "Logic", "date": "12/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAndrew has a random number of books. Only one of the following statements is true.\n\r\n1. Andrew has at least 72 books.\n\r\n2. Andrew has at least 62 books.\n\r\n3. Andrew has at least 42 books.\n\r\nWhat is the biggest amount of books Andrew can have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n61.\n\r\nFrom 72 to infinity, 3 statements would be true.\n\r\nFrom 62 to 71, 2 statements would be true.\n\r\nFrom 42 to 61, 1 statement would be true.\n\r\nFrom 0 to 41, 0 statements would be true.\r\nBetween 42 and 61, 61 would be the biggest.\n<|im_start|>answer\n61.\n\r\nFrom 72 to infinity, 3 statements would be true.\n\r\nFrom 62 to 71, 2 statements would be true.\n\r\nFrom 42 to 61, 1 statement would be true.\n\r\nFrom 0 to 41, 0 statements would be true.\r\nBetween 42 and 61, 61 would be the biggest.\n<|im_end|>" }, { "id": "#13629", "title": "Homer and Horace 1", "fun": 2.47, "difficulty": 0.9400000000000001, "author": "Timothy", "desc": "Homer and Horace are twins that look exactly alike. \r\nThey each have two personalities, State 1 and State 2. \r\nHomer tells the truth in State 1 and lies in State 2 while Horace lies in State 1 and tells the truth in State 2. \n\r\nOne of them said, \"I am in State 1.\" \n\r\nWho said this?", "hint": "No hint available.", "answer": "He is either telling the truth or lying. \n\r\nIf he is telling the truth, then he is in State 1, but only Homer tells the truth in State 1. \r\nIf he is lying, then he is in State 2, but only Homer lies in State 2. \n\r\nIn either case, he is Homer.", "category": "Logic", "date": "07/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHomer and Horace are twins that look exactly alike. \r\nThey each have two personalities, State 1 and State 2. \r\nHomer tells the truth in State 1 and lies in State 2 while Horace lies in State 1 and tells the truth in State 2. \n\r\nOne of them said, \"I am in State 1.\" \n\r\nWho said this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe is either telling the truth or lying. \n\r\nIf he is telling the truth, then he is in State 1, but only Homer tells the truth in State 1. \r\nIf he is lying, then he is in State 2, but only Homer lies in State 2. \n\r\nIn either case, he is Homer.\n<|im_start|>answer\nHe is either telling the truth or lying. \n\r\nIf he is telling the truth, then he is in State 1, but only Homer tells the truth in State 1. \r\nIf he is lying, then he is in State 2, but only Homer lies in State 2. \n\r\nIn either case, he is Homer.\n<|im_end|>" }, { "id": "#8760", "title": "Truth or Lies", "fun": 2.47, "difficulty": 1.6300000000000001, "author": "lesternoronha1", "desc": "You are traveling down a path and come to a fork in the road. A sign lays fallen at the path indicating that one path leads to a village where everyone tells the truth and the other to a village where everyone tells lies. The sign has been knocked down so you do not know which path leads to which village. Then someone from one of the villages (you don't know which one) comes down the path from which you came. You may ask him one question to determine which path goes to which village. What question do you ask?", "hint": "No hint available.", "answer": "You point to either path and say, \"Are you from this village?\" If the person answers 'yes' then you are pointing to the truthful village, if they answer 'no' then you are pointing to the lying village.\r\n1)If you point to the truthful village what will a truthful person say in answer to your question? \r\n2)If you point to the truthful village what will a untruthful person say in answer to your question? \r\n3)If you point to the untruthful village what will a truthful person say in answer to your question? \r\n4)If you point to the untruthful village what will a untruthful person say in answer to your question? \r\nThe answers to these questions are: 1. \"yes\", 2. \"yes\", 3. \"no\", 4. \"no\".\r\nNote that in the two cases where the answer is \"yes\" you are pointing to the truthful village and in the two cases where the answer is \"no\" you are pointing to the untruthful village. Thus you can tell from the reply to which village you are pointing. You do not have to know to whom you are speaking.", "category": "Logic", "date": "11/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are traveling down a path and come to a fork in the road. A sign lays fallen at the path indicating that one path leads to a village where everyone tells the truth and the other to a village where everyone tells lies. The sign has been knocked down so you do not know which path leads to which village. Then someone from one of the villages (you don't know which one) comes down the path from which you came. You may ask him one question to determine which path goes to which village. What question do you ask?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou point to either path and say, \"Are you from this village?\" If the person answers 'yes' then you are pointing to the truthful village, if they answer 'no' then you are pointing to the lying village.\r\n1)If you point to the truthful village what will a truthful person say in answer to your question? \r\n2)If you point to the truthful village what will a untruthful person say in answer to your question? \r\n3)If you point to the untruthful village what will a truthful person say in answer to your question? \r\n4)If you point to the untruthful village what will a untruthful person say in answer to your question? \r\nThe answers to these questions are: 1. \"yes\", 2. \"yes\", 3. \"no\", 4. \"no\".\r\nNote that in the two cases where the answer is \"yes\" you are pointing to the truthful village and in the two cases where the answer is \"no\" you are pointing to the untruthful village. Thus you can tell from the reply to which village you are pointing. You do not have to know to whom you are speaking.\n<|im_start|>answer\nYou point to either path and say, \"Are you from this village?\" If the person answers 'yes' then you are pointing to the truthful village, if they answer 'no' then you are pointing to the lying village.\r\n1)If you point to the truthful village what will a truthful person say in answer to your question? \r\n2)If you point to the truthful village what will a untruthful person say in answer to your question? \r\n3)If you point to the untruthful village what will a truthful person say in answer to your question? \r\n4)If you point to the untruthful village what will a untruthful person say in answer to your question? \r\nThe answers to these questions are: 1. \"yes\", 2. \"yes\", 3. \"no\", 4. \"no\".\r\nNote that in the two cases where the answer is \"yes\" you are pointing to the truthful village and in the two cases where the answer is \"no\" you are pointing to the untruthful village. Thus you can tell from the reply to which village you are pointing. You do not have to know to whom you are speaking.\n<|im_end|>" }, { "id": "#30180", "title": "Five Fives", "fun": 2.47, "difficulty": 2.86, "author": "kodhrawara", "desc": "5 5 5 5 5 = 37\n\r\nCan you make a target number 37 by using five 5s?\r\nYou can use any math operator or group the 5s (as in 555)\r\nThere are at least two different ways.", "hint": "No hint available.", "answer": "Since the total of five 5s is 25, we have to choose an operator which can make a large number. \n\r\nObviously, the multiplication operator is not good enough. We chose the factorial operator!\r\n((5!+5!)-55)/5 = (120+120-55)/5 = 185/5 = 37\r\n5!/(5+5)+5*5 = 120/10 + 25 = 12 + 25 = 37\n\r\nA third solution uses \"raising to the 5th power\"\r\n((5+5)/5)**5 + 5 = 37", "category": "Math", "date": "04/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 5 5 5 5 = 37\n\r\nCan you make a target number 37 by using five 5s?\r\nYou can use any math operator or group the 5s (as in 555)\r\nThere are at least two different ways.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince the total of five 5s is 25, we have to choose an operator which can make a large number. \n\r\nObviously, the multiplication operator is not good enough. We chose the factorial operator!\r\n((5!+5!)-55)/5 = (120+120-55)/5 = 185/5 = 37\r\n5!/(5+5)+5*5 = 120/10 + 25 = 12 + 25 = 37\n\r\nA third solution uses \"raising to the 5th power\"\r\n((5+5)/5)**5 + 5 = 37\n<|im_start|>answer\nSince the total of five 5s is 25, we have to choose an operator which can make a large number. \n\r\nObviously, the multiplication operator is not good enough. We chose the factorial operator!\r\n((5!+5!)-55)/5 = (120+120-55)/5 = 185/5 = 37\r\n5!/(5+5)+5*5 = 120/10 + 25 = 12 + 25 = 37\n\r\nA third solution uses \"raising to the 5th power\"\r\n((5+5)/5)**5 + 5 = 37\n<|im_end|>" }, { "id": "#20815", "title": "How Old Are They?", "fun": 2.47, "difficulty": 2.21, "author": "NewYork_101", "desc": "A husband and wife have a combined age of 91. The husband is now twice as old as his wife was when he was as old as she is now. How old are they?", "hint": "No hint available.", "answer": "Husband = 52, Wife = 39.\n\r\nIf we call the husband's age h, and the wife's w, we know:\n\r\nh + w = 91 (a)\n\r\nTheir age difference is h - w. We know the husband is 2 * (how old his wife was when he was her age), so we need to take their age difference off his current wife's age, as follows:\n\r\n2 * (w - (h - w)) = h\n\r\nSimplifying this we get:\n\r\n4w = 3h\n\r\nplugging this back into (a) gives the required answer.", "category": "Math", "date": "02/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA husband and wife have a combined age of 91. The husband is now twice as old as his wife was when he was as old as she is now. How old are they?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHusband = 52, Wife = 39.\n\r\nIf we call the husband's age h, and the wife's w, we know:\n\r\nh + w = 91 (a)\n\r\nTheir age difference is h - w. We know the husband is 2 * (how old his wife was when he was her age), so we need to take their age difference off his current wife's age, as follows:\n\r\n2 * (w - (h - w)) = h\n\r\nSimplifying this we get:\n\r\n4w = 3h\n\r\nplugging this back into (a) gives the required answer.\n<|im_start|>answer\nHusband = 52, Wife = 39.\n\r\nIf we call the husband's age h, and the wife's w, we know:\n\r\nh + w = 91 (a)\n\r\nTheir age difference is h - w. We know the husband is 2 * (how old his wife was when he was her age), so we need to take their age difference off his current wife's age, as follows:\n\r\n2 * (w - (h - w)) = h\n\r\nSimplifying this we get:\n\r\n4w = 3h\n\r\nplugging this back into (a) gives the required answer.\n<|im_end|>" }, { "id": "#11468", "title": "5 Businessmen", "fun": 2.47, "difficulty": 2.95, "author": "inudbz", "desc": "These five businessmen represented different companies at a recent trade fair. Unfortunately, the hotel they were all due to stay in had accidentally double booked their rooms. They tried other hotels in the area, but all were fully booked. Consequently, they all agreed to share the only two rooms available in the hotel - one twin and one triple. \n\r\nFrom the clues, can you work out each man's name, company and official title? \n\r\n1. When the five men realized their dilemma, they drew straws to see who would share with whom. The outcome for four of them was that the CEO shared with the businessman from ABM Inc. and Edgar shared with the Developer. \r\n2. Alan does not work for Reed Right and is not the Director. The Director does not work for Lantel or Blue Teeth. \r\n3. Neither Clarkson nor Grimaldi works for Reed Right. Grimaldi is either the IT Analyst or the CEO. \r\n4. The businessman from Reed Right did not share a room with Thomas. \r\n5. Clarkson, who does not work for Lantel, shared with either Thomas or Grimaldi but not both. \r\n6. Edgar's surname is either Casson or Graves. Edgar did not share with Carl. \r\n7. The businessman from Chiptech shared with the businessman from Lantel. \r\n8. The CEO shared with the IT Analyst. \r\n9. Casson works for either Blue Teeth or Chiptech. \r\n10. Neither Joshua nor Alan works for ABM Inc. \r\n11. Fielder shared with the Director. \r\n12. The Accountant from Blue Teeth shared with the Developer. \n\r\nFirst names: Alan, Carl, Edgar, Joshua, Thomas. \r\nLast names: Casson, Clarkson, Fielder, Graves, Grimaldi. \r\nCompany: ABM Inc., Blue Teeth, Chiptech, Lantel, Reed", "hint": "No hint available.", "answer": "First Name, Last Name, Company, Position:\n\r\nCarl Grimaldi, ABM Inc., IT Analyst \r\nEdgar Casson, Chiptech, Director \r\nJoshua Graves, Reed Right, CEO \r\nAlan Clarkson, Blue Teeth, Accountant \r\nThomas Fielder, Lantel, Developer \n\r\nTo solve this teaser, you first need to determine who shared which room with whom. Three delegates shared the triple and two shared the twin. The CEO shared with the businessman from ABM in one room and Edgar shared with the Developer in the other (1). Since Grimaldi is either the IT Analyst or the CEO (3) and the CEO shared with the IT Analyst, Grimaldi is in the same room as whoever is the CEO, IT Analyst and ABM delegate although Grimaldi could have been one of these people. Edgar did not share with Carl (6) so Carl is in the same bedroom as, and possibly is, the CEO, IT Analyst, Grimaldi and/or the ABM delegate. Grimaldi and Thomas were in different rooms so Thomas shared a room with Clarkson (5) and the Reed Right delegate was in a different room to Thomas. At this stage we know: \n\r\nRoom 1 \r\nCEO \r\nIT Analyst \r\nABM delegate \r\nGrimaldi \r\nCarl \r\nReed Right delegate \n\r\nRoom 2 \r\nEdgar \r\nDeveloper \r\nThomas \r\nClarkson \n\r\nSince the Chiptech delegate shared with the Lantel delegate (7), both of these must have been in room 2 otherwise there would be four delegates in room 1 which is not possible. \n\r\nNow this has been ascertained, the puzzle can be solved: \n\r\nThe CEO shared with the IT Analyst so the IT Analyst must work for ABM (Clues 1 and 8) so the CEO must work for Reed Right. Since Grimaldi does not work for Reed Right, he must be the IT Analyst. Clarkson, Fielder and Casson are in room 2 so the CEO must be Graves. Graves is not Edgar (1), Thomas (4), Carl (IT Analyst) or Alan (2) so must be Joshua. Clarkson is not Thomas (5), Edgar (6), Carl or Joshua (in room 1) so must be Alan. The Director does not work for Lantel or Blue Teeth (2), Reed Right or ABM (room 1) so must work for Chiptech. This is not Graves or Grimaldi (room 1), Clarkson (2) or Fielder (11) so must be Casson. Since Graves; first name is Joshua, Casson must be Edgar (6). Alan Clarkson does not work for Reed Right or ABM (room 1); Lantel (5) or Chiptech so must work for Blue Teeth. Since he is not the Developer (12) he must be the Accountant. This leaves Thomas Fielder who is the Developer for Lantel.", "category": "Logic", "date": "03/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThese five businessmen represented different companies at a recent trade fair. Unfortunately, the hotel they were all due to stay in had accidentally double booked their rooms. They tried other hotels in the area, but all were fully booked. Consequently, they all agreed to share the only two rooms available in the hotel - one twin and one triple. \n\r\nFrom the clues, can you work out each man's name, company and official title? \n\r\n1. When the five men realized their dilemma, they drew straws to see who would share with whom. The outcome for four of them was that the CEO shared with the businessman from ABM Inc. and Edgar shared with the Developer. \r\n2. Alan does not work for Reed Right and is not the Director. The Director does not work for Lantel or Blue Teeth. \r\n3. Neither Clarkson nor Grimaldi works for Reed Right. Grimaldi is either the IT Analyst or the CEO. \r\n4. The businessman from Reed Right did not share a room with Thomas. \r\n5. Clarkson, who does not work for Lantel, shared with either Thomas or Grimaldi but not both. \r\n6. Edgar's surname is either Casson or Graves. Edgar did not share with Carl. \r\n7. The businessman from Chiptech shared with the businessman from Lantel. \r\n8. The CEO shared with the IT Analyst. \r\n9. Casson works for either Blue Teeth or Chiptech. \r\n10. Neither Joshua nor Alan works for ABM Inc. \r\n11. Fielder shared with the Director. \r\n12. The Accountant from Blue Teeth shared with the Developer. \n\r\nFirst names: Alan, Carl, Edgar, Joshua, Thomas. \r\nLast names: Casson, Clarkson, Fielder, Graves, Grimaldi. \r\nCompany: ABM Inc., Blue Teeth, Chiptech, Lantel, Reed\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst Name, Last Name, Company, Position:\n\r\nCarl Grimaldi, ABM Inc., IT Analyst \r\nEdgar Casson, Chiptech, Director \r\nJoshua Graves, Reed Right, CEO \r\nAlan Clarkson, Blue Teeth, Accountant \r\nThomas Fielder, Lantel, Developer \n\r\nTo solve this teaser, you first need to determine who shared which room with whom. Three delegates shared the triple and two shared the twin. The CEO shared with the businessman from ABM in one room and Edgar shared with the Developer in the other (1). Since Grimaldi is either the IT Analyst or the CEO (3) and the CEO shared with the IT Analyst, Grimaldi is in the same room as whoever is the CEO, IT Analyst and ABM delegate although Grimaldi could have been one of these people. Edgar did not share with Carl (6) so Carl is in the same bedroom as, and possibly is, the CEO, IT Analyst, Grimaldi and/or the ABM delegate. Grimaldi and Thomas were in different rooms so Thomas shared a room with Clarkson (5) and the Reed Right delegate was in a different room to Thomas. At this stage we know: \n\r\nRoom 1 \r\nCEO \r\nIT Analyst \r\nABM delegate \r\nGrimaldi \r\nCarl \r\nReed Right delegate \n\r\nRoom 2 \r\nEdgar \r\nDeveloper \r\nThomas \r\nClarkson \n\r\nSince the Chiptech delegate shared with the Lantel delegate (7), both of these must have been in room 2 otherwise there would be four delegates in room 1 which is not possible. \n\r\nNow this has been ascertained, the puzzle can be solved: \n\r\nThe CEO shared with the IT Analyst so the IT Analyst must work for ABM (Clues 1 and 8) so the CEO must work for Reed Right. Since Grimaldi does not work for Reed Right, he must be the IT Analyst. Clarkson, Fielder and Casson are in room 2 so the CEO must be Graves. Graves is not Edgar (1), Thomas (4), Carl (IT Analyst) or Alan (2) so must be Joshua. Clarkson is not Thomas (5), Edgar (6), Carl or Joshua (in room 1) so must be Alan. The Director does not work for Lantel or Blue Teeth (2), Reed Right or ABM (room 1) so must work for Chiptech. This is not Graves or Grimaldi (room 1), Clarkson (2) or Fielder (11) so must be Casson. Since Graves; first name is Joshua, Casson must be Edgar (6). Alan Clarkson does not work for Reed Right or ABM (room 1); Lantel (5) or Chiptech so must work for Blue Teeth. Since he is not the Developer (12) he must be the Accountant. This leaves Thomas Fielder who is the Developer for Lantel.\n<|im_start|>answer\nFirst Name, Last Name, Company, Position:\n\r\nCarl Grimaldi, ABM Inc., IT Analyst \r\nEdgar Casson, Chiptech, Director \r\nJoshua Graves, Reed Right, CEO \r\nAlan Clarkson, Blue Teeth, Accountant \r\nThomas Fielder, Lantel, Developer \n\r\nTo solve this teaser, you first need to determine who shared which room with whom. Three delegates shared the triple and two shared the twin. The CEO shared with the businessman from ABM in one room and Edgar shared with the Developer in the other (1). Since Grimaldi is either the IT Analyst or the CEO (3) and the CEO shared with the IT Analyst, Grimaldi is in the same room as whoever is the CEO, IT Analyst and ABM delegate although Grimaldi could have been one of these people. Edgar did not share with Carl (6) so Carl is in the same bedroom as, and possibly is, the CEO, IT Analyst, Grimaldi and/or the ABM delegate. Grimaldi and Thomas were in different rooms so Thomas shared a room with Clarkson (5) and the Reed Right delegate was in a different room to Thomas. At this stage we know: \n\r\nRoom 1 \r\nCEO \r\nIT Analyst \r\nABM delegate \r\nGrimaldi \r\nCarl \r\nReed Right delegate \n\r\nRoom 2 \r\nEdgar \r\nDeveloper \r\nThomas \r\nClarkson \n\r\nSince the Chiptech delegate shared with the Lantel delegate (7), both of these must have been in room 2 otherwise there would be four delegates in room 1 which is not possible. \n\r\nNow this has been ascertained, the puzzle can be solved: \n\r\nThe CEO shared with the IT Analyst so the IT Analyst must work for ABM (Clues 1 and 8) so the CEO must work for Reed Right. Since Grimaldi does not work for Reed Right, he must be the IT Analyst. Clarkson, Fielder and Casson are in room 2 so the CEO must be Graves. Graves is not Edgar (1), Thomas (4), Carl (IT Analyst) or Alan (2) so must be Joshua. Clarkson is not Thomas (5), Edgar (6), Carl or Joshua (in room 1) so must be Alan. The Director does not work for Lantel or Blue Teeth (2), Reed Right or ABM (room 1) so must work for Chiptech. This is not Graves or Grimaldi (room 1), Clarkson (2) or Fielder (11) so must be Casson. Since Graves; first name is Joshua, Casson must be Edgar (6). Alan Clarkson does not work for Reed Right or ABM (room 1); Lantel (5) or Chiptech so must work for Blue Teeth. Since he is not the Developer (12) he must be the Accountant. This leaves Thomas Fielder who is the Developer for Lantel.\n<|im_end|>" }, { "id": "#7246", "title": "Math Reunion", "fun": 2.47, "difficulty": 2.84, "author": "dewtell", "desc": "Dear Jim:\n\r\nOur twenty-fifth reunion went wonderfully last week. The Math Department put on a great spread. I'm sorry you couldn't make it. I ran into Ralph Jones there - remember him? It turns out he married Susie Jacobsen a couple of years after graduation - imagine that! They have three kids, all boys, and their ages make a nice puzzle. No two of them are the same age. Right now, Albert's age is the same as the sum of the digits of the ages of his two brothers. A year ago, Bill was in the same situation. Finally, six years from now it will be Charles' turn to have an age equal to the sum of the digits of his brothers' ages. I trust that's enough information to let you figure out their ages.\n\r\nGive my regards to Sharon, and I hope I'll see you at our next reunion.\n\r\nJerry", "hint": "Any non-negative integer is congruent to the sum of its digits, mod 9. (They have the same remainder when divided by 9.)", "answer": "Albert is 11, Bill is 6, and Charles is 5, 11 = 6+5. A year ago, they were 10, 5, and 4, 1+0+4 = 5. In six years, they will be 17, 12, and 11, 1+7+1+2=11.\n\r\nYou can solve this one by trial and error, but you can also solve simultaneous congruences mod 9. Let a, b, and c represent the present ages of the three boys. Since any non-negative integer is congruent to the sum of its digits, mod 9, we have three congruences:\r\na = b + c (mod 9)\r\nb-1 = (a-1) + (c-1) (mod 9)\r\nc+6 = (a+6) + (b+6) (mod 9)\n\r\nSubstituting the value of a from the first congruence into the other two and simplifying, we get:\r\n2c = 1 = 10 (mod 9), so c = 5 (mod 9), and\r\n2b = -6 = 12 (mod 9), so b = 6 (mod 9),\r\nso a = b + c = 2 (mod 9). \n\r\nAge 2 is too young for Albert to be equal to the sum of digits of his brother's ages, and 20 is too old (it would require that both brothers be 19, contrary to the required congruences), so Albert must be 11, and the rest follows quickly.", "category": "Math", "date": "09/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDear Jim:\n\r\nOur twenty-fifth reunion went wonderfully last week. The Math Department put on a great spread. I'm sorry you couldn't make it. I ran into Ralph Jones there - remember him? It turns out he married Susie Jacobsen a couple of years after graduation - imagine that! They have three kids, all boys, and their ages make a nice puzzle. No two of them are the same age. Right now, Albert's age is the same as the sum of the digits of the ages of his two brothers. A year ago, Bill was in the same situation. Finally, six years from now it will be Charles' turn to have an age equal to the sum of the digits of his brothers' ages. I trust that's enough information to let you figure out their ages.\n\r\nGive my regards to Sharon, and I hope I'll see you at our next reunion.\n\r\nJerry\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlbert is 11, Bill is 6, and Charles is 5, 11 = 6+5. A year ago, they were 10, 5, and 4, 1+0+4 = 5. In six years, they will be 17, 12, and 11, 1+7+1+2=11.\n\r\nYou can solve this one by trial and error, but you can also solve simultaneous congruences mod 9. Let a, b, and c represent the present ages of the three boys. Since any non-negative integer is congruent to the sum of its digits, mod 9, we have three congruences:\r\na = b + c (mod 9)\r\nb-1 = (a-1) + (c-1) (mod 9)\r\nc+6 = (a+6) + (b+6) (mod 9)\n\r\nSubstituting the value of a from the first congruence into the other two and simplifying, we get:\r\n2c = 1 = 10 (mod 9), so c = 5 (mod 9), and\r\n2b = -6 = 12 (mod 9), so b = 6 (mod 9),\r\nso a = b + c = 2 (mod 9). \n\r\nAge 2 is too young for Albert to be equal to the sum of digits of his brother's ages, and 20 is too old (it would require that both brothers be 19, contrary to the required congruences), so Albert must be 11, and the rest follows quickly.\n<|im_start|>answer\nAlbert is 11, Bill is 6, and Charles is 5, 11 = 6+5. A year ago, they were 10, 5, and 4, 1+0+4 = 5. In six years, they will be 17, 12, and 11, 1+7+1+2=11.\n\r\nYou can solve this one by trial and error, but you can also solve simultaneous congruences mod 9. Let a, b, and c represent the present ages of the three boys. Since any non-negative integer is congruent to the sum of its digits, mod 9, we have three congruences:\r\na = b + c (mod 9)\r\nb-1 = (a-1) + (c-1) (mod 9)\r\nc+6 = (a+6) + (b+6) (mod 9)\n\r\nSubstituting the value of a from the first congruence into the other two and simplifying, we get:\r\n2c = 1 = 10 (mod 9), so c = 5 (mod 9), and\r\n2b = -6 = 12 (mod 9), so b = 6 (mod 9),\r\nso a = b + c = 2 (mod 9). \n\r\nAge 2 is too young for Albert to be equal to the sum of digits of his brother's ages, and 20 is too old (it would require that both brothers be 19, contrary to the required congruences), so Albert must be 11, and the rest follows quickly.\n<|im_end|>" }, { "id": "#317", "title": "Two Pencils", "fun": 2.47, "difficulty": 1.27, "author": "Phyllis", "desc": "Karin has two pencils. One is a good one, and one is a cheap one. The good pencil cost $1.00 more than the cheap one. Karin spent $1.10 for both pencils. How much did her cheap pencil cost?", "hint": "No hint available.", "answer": "Five cents. The expensive pencil cost $1.05. You may have thought the answer was 10 cents, but that does not meet the requirement of the expensive pencil costing $1.00 MORE than the cheap pencil. If the cheap pencil cost 10 cents, the expensive pencil would only cost 90 cents more.", "category": "Math", "date": "02/28/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKarin has two pencils. One is a good one, and one is a cheap one. The good pencil cost $1.00 more than the cheap one. Karin spent $1.10 for both pencils. How much did her cheap pencil cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFive cents. The expensive pencil cost $1.05. You may have thought the answer was 10 cents, but that does not meet the requirement of the expensive pencil costing $1.00 MORE than the cheap pencil. If the cheap pencil cost 10 cents, the expensive pencil would only cost 90 cents more.\n<|im_start|>answer\nFive cents. The expensive pencil cost $1.05. You may have thought the answer was 10 cents, but that does not meet the requirement of the expensive pencil costing $1.00 MORE than the cheap pencil. If the cheap pencil cost 10 cents, the expensive pencil would only cost 90 cents more.\n<|im_end|>" }, { "id": "#11006", "title": "Who Said That?", "fun": 2.47, "difficulty": 1.1, "author": "jimbo", "desc": "Suzie just could not tell the truth while her friend Samantha (the nice one) just could not tell a lie. The lady on the left wagged her finger at her friend and announced \"She said she is Suzie!\" \n\r\nWho is the lady on the left?", "hint": "No hint available.", "answer": "Since Suzie always lies and Samantha always tells the truth, neither lady would ever say that her own name is Suzie. Therefore the woman on the left must be lying about what the other lady said. The lady on the left is therefore Suzie.", "category": "Logic", "date": "03/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuzie just could not tell the truth while her friend Samantha (the nice one) just could not tell a lie. The lady on the left wagged her finger at her friend and announced \"She said she is Suzie!\" \n\r\nWho is the lady on the left?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince Suzie always lies and Samantha always tells the truth, neither lady would ever say that her own name is Suzie. Therefore the woman on the left must be lying about what the other lady said. The lady on the left is therefore Suzie.\n<|im_start|>answer\nSince Suzie always lies and Samantha always tells the truth, neither lady would ever say that her own name is Suzie. Therefore the woman on the left must be lying about what the other lady said. The lady on the left is therefore Suzie.\n<|im_end|>" }, { "id": "#981", "title": "Jean Jane Joan", "fun": 2.47, "difficulty": 1.8800000000000001, "author": "Michelle", "desc": "Joan and Jane are sisters. Jean is Joan's daughter and 12 years younger than her aunt. Joan is twice as old as Jean. Four years ago, Joan was the same age as Jane is now, and Jane was twice as old as her niece. How old is Jean?", "hint": "No hint available.", "answer": "Joan is 32, Jane is 28, and Jean is 16.", "category": "Math", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoan and Jane are sisters. Jean is Joan's daughter and 12 years younger than her aunt. Joan is twice as old as Jean. Four years ago, Joan was the same age as Jane is now, and Jane was twice as old as her niece. How old is Jean?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoan is 32, Jane is 28, and Jean is 16.\n<|im_start|>answer\nJoan is 32, Jane is 28, and Jean is 16.\n<|im_end|>" }, { "id": "#5214", "title": "Nail the Square", "fun": 2.47, "difficulty": 1.12, "author": "michelle", "desc": "A 27\" x 27\" square metal plate needs to be fixed by a carpenter on to a wooden board. The carpenter uses nails all along the edges of the square such that there are 28 nails on each side of the square. Each nail is at the same distance from the neighboring nails. How many nails does the carpenter use?", "hint": "No hint available.", "answer": "The four corners of the square have one nail each. \n\r\nEach side of the square now requires 26 nails (excluding the four corners). \n\r\nThus, Total number of nails used = 4 + (4 x 26) = 108.", "category": "Math", "date": "07/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 27\" x 27\" square metal plate needs to be fixed by a carpenter on to a wooden board. The carpenter uses nails all along the edges of the square such that there are 28 nails on each side of the square. Each nail is at the same distance from the neighboring nails. How many nails does the carpenter use?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe four corners of the square have one nail each. \n\r\nEach side of the square now requires 26 nails (excluding the four corners). \n\r\nThus, Total number of nails used = 4 + (4 x 26) = 108.\n<|im_start|>answer\nThe four corners of the square have one nail each. \n\r\nEach side of the square now requires 26 nails (excluding the four corners). \n\r\nThus, Total number of nails used = 4 + (4 x 26) = 108.\n<|im_end|>" }, { "id": "#14752", "title": "A Prime Example", "fun": 2.47, "difficulty": 2.91, "author": "mathemagician", "desc": "Can you think of three different two-digit prime numbers in which: \n\r\n(i) the average of ANY TWO of the numbers is a prime, and \n\r\n(ii) the average of all three of the numbers is a prime?", "hint": "The average of two of the numbers is 59.", "answer": "The numbers are 11, 47, and 71.\n\r\nThe average of 11 and 47 is 29,\r\nthe average of 11 and 71 is 41,\r\nthe average of 47 and 71 is 59,\r\nand the average of all three numbers is 43 .", "category": "Math", "date": "09/12/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you think of three different two-digit prime numbers in which: \n\r\n(i) the average of ANY TWO of the numbers is a prime, and \n\r\n(ii) the average of all three of the numbers is a prime?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers are 11, 47, and 71.\n\r\nThe average of 11 and 47 is 29,\r\nthe average of 11 and 71 is 41,\r\nthe average of 47 and 71 is 59,\r\nand the average of all three numbers is 43 .\n<|im_start|>answer\nThe numbers are 11, 47, and 71.\n\r\nThe average of 11 and 47 is 29,\r\nthe average of 11 and 71 is 41,\r\nthe average of 47 and 71 is 59,\r\nand the average of all three numbers is 43 .\n<|im_end|>" }, { "id": "#14725", "title": "Waterloo Street", "fun": 2.47, "difficulty": 2.06, "author": "taniapereira99", "desc": "On Waterloo Street, there are five neighbours: the Chaes, the D'Costas, the Lams, the Mazumdars and the O'Neils. All neighbours live either adjacent to, or directly across the street from one another. Two of their houses are white, one is grey, one is green and one is blue. \n\r\nFrom the clues below, determine which side of the street each neighbour lives (north or south) and the colour of their house.\n\r\n1. The two white houses are directly across from one another on the west end of the street.\n\r\n2. The Chaes do not live adjacent to either of the white houses.\n\r\n3. The D'Costas live on the same side of the street that the Chaes live.\n\r\n4. The blue house is immediately east of the D'Costa house, on the same side of the street.\n\r\n5. The Lams house is not grey or white, and is next door to the O'Neils (which is on the south side of the street).\n\r\n6. The Mazumdar house is directly across the street from the Lams.", "hint": "No hint available.", "answer": "From 1, a white house is on either side of the west end of the street. Since from 2, the Chaes cannot live next to the white houses, it on the east end of the street (north or south, unknown).\n\r\nFrom 3, the D'Costas are in a white house or in the middle between one of the white houses and the Chaes. (Assuming of course that there is a maximum of 3 on either side of the street). From 4, the blue house therefore is either the in between house (if the D'Costa's are in the white house) or the Chae house.\n\r\nSince from 5, the Lam and the O'Neil houses are on the south side, the Chaes, D'Costas and Mazumdars(from 6) are on the north side. That would make The O'Neils be owners of the white house on the south side, and the Lams the owners of the house beside it. That would make the Mazumdars live in the center house (therefore blue on the north side) and the D'Costas live in the white house. Since the Lams do not have a grey house, the Chaes do. This leaves the Lams with the green house.", "category": "Logic", "date": "09/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Waterloo Street, there are five neighbours: the Chaes, the D'Costas, the Lams, the Mazumdars and the O'Neils. All neighbours live either adjacent to, or directly across the street from one another. Two of their houses are white, one is grey, one is green and one is blue. \n\r\nFrom the clues below, determine which side of the street each neighbour lives (north or south) and the colour of their house.\n\r\n1. The two white houses are directly across from one another on the west end of the street.\n\r\n2. The Chaes do not live adjacent to either of the white houses.\n\r\n3. The D'Costas live on the same side of the street that the Chaes live.\n\r\n4. The blue house is immediately east of the D'Costa house, on the same side of the street.\n\r\n5. The Lams house is not grey or white, and is next door to the O'Neils (which is on the south side of the street).\n\r\n6. The Mazumdar house is directly across the street from the Lams.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom 1, a white house is on either side of the west end of the street. Since from 2, the Chaes cannot live next to the white houses, it on the east end of the street (north or south, unknown).\n\r\nFrom 3, the D'Costas are in a white house or in the middle between one of the white houses and the Chaes. (Assuming of course that there is a maximum of 3 on either side of the street). From 4, the blue house therefore is either the in between house (if the D'Costa's are in the white house) or the Chae house.\n\r\nSince from 5, the Lam and the O'Neil houses are on the south side, the Chaes, D'Costas and Mazumdars(from 6) are on the north side. That would make The O'Neils be owners of the white house on the south side, and the Lams the owners of the house beside it. That would make the Mazumdars live in the center house (therefore blue on the north side) and the D'Costas live in the white house. Since the Lams do not have a grey house, the Chaes do. This leaves the Lams with the green house.\n<|im_start|>answer\nFrom 1, a white house is on either side of the west end of the street. Since from 2, the Chaes cannot live next to the white houses, it on the east end of the street (north or south, unknown).\n\r\nFrom 3, the D'Costas are in a white house or in the middle between one of the white houses and the Chaes. (Assuming of course that there is a maximum of 3 on either side of the street). From 4, the blue house therefore is either the in between house (if the D'Costa's are in the white house) or the Chae house.\n\r\nSince from 5, the Lam and the O'Neil houses are on the south side, the Chaes, D'Costas and Mazumdars(from 6) are on the north side. That would make The O'Neils be owners of the white house on the south side, and the Lams the owners of the house beside it. That would make the Mazumdars live in the center house (therefore blue on the north side) and the D'Costas live in the white house. Since the Lams do not have a grey house, the Chaes do. This leaves the Lams with the green house.\n<|im_end|>" }, { "id": "#43854", "title": "12-digit Oddities", "fun": 2.46, "difficulty": 3.24, "author": "javaguru", "desc": "What characteristic do these three 12-digit numbers share with each other, but with no other 12-digit number?\n\r\n100307124369\r\n111824028801\r\n433800063225", "hint": "316713\r\n334401\r\n656635", "answer": "They are all square numbers:\n\r\n100307124369 = 316713^2\r\n111824028801 = 334401^2\r\n433800063225 = 656635^2\n\r\nThe sum of their digits are square numbers:\n\r\n1+0+0+3+0+7+1+2+4+3+6+9 = 36 = 6^2\r\n1+1+1+8+2+4+0+2+8+8+0+1 = 36 = 6^2\r\n4+3+3+8+0+0+0+6+3+2+2+5 = 36 = 6^2\n\r\nThe sum of their digit pairs are square numbers:\n\r\n10+03+07+12+43+69 = 144 = 12^2\r\n11+18+24+02+88+01 = 144 = 12^2\r\n43+38+00+06+32+25 = 144 = 12^2\n\r\nThe sum of their digit triplets are square numbers:\n\r\n100+307+124+369 = 900 = 30^2\r\n111+824+028+801 = 1764 = 42^2\r\n433+800+063+225 = 1521 = 39^2\n\r\nThe sum of their digit quadruplets are square numbers:\n\r\n1003+0712+4369 = 6084 = 78^2\r\n1118+2402+8801 = 12321 = 111^2\r\n4338+0006+3225 = 7569 = 87^2\n\r\nThe sum of their digit sextuplets are square numbers:\n\r\n100307+124369 = 224676 = 474^2\r\n111824+028801 = 140625 = 375^2\r\n433800+063225 = 497025 = 705^2", "category": "Math", "date": "01/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat characteristic do these three 12-digit numbers share with each other, but with no other 12-digit number?\n\r\n100307124369\r\n111824028801\r\n433800063225\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are all square numbers:\n\r\n100307124369 = 316713^2\r\n111824028801 = 334401^2\r\n433800063225 = 656635^2\n\r\nThe sum of their digits are square numbers:\n\r\n1+0+0+3+0+7+1+2+4+3+6+9 = 36 = 6^2\r\n1+1+1+8+2+4+0+2+8+8+0+1 = 36 = 6^2\r\n4+3+3+8+0+0+0+6+3+2+2+5 = 36 = 6^2\n\r\nThe sum of their digit pairs are square numbers:\n\r\n10+03+07+12+43+69 = 144 = 12^2\r\n11+18+24+02+88+01 = 144 = 12^2\r\n43+38+00+06+32+25 = 144 = 12^2\n\r\nThe sum of their digit triplets are square numbers:\n\r\n100+307+124+369 = 900 = 30^2\r\n111+824+028+801 = 1764 = 42^2\r\n433+800+063+225 = 1521 = 39^2\n\r\nThe sum of their digit quadruplets are square numbers:\n\r\n1003+0712+4369 = 6084 = 78^2\r\n1118+2402+8801 = 12321 = 111^2\r\n4338+0006+3225 = 7569 = 87^2\n\r\nThe sum of their digit sextuplets are square numbers:\n\r\n100307+124369 = 224676 = 474^2\r\n111824+028801 = 140625 = 375^2\r\n433800+063225 = 497025 = 705^2\n<|im_start|>answer\nThey are all square numbers:\n\r\n100307124369 = 316713^2\r\n111824028801 = 334401^2\r\n433800063225 = 656635^2\n\r\nThe sum of their digits are square numbers:\n\r\n1+0+0+3+0+7+1+2+4+3+6+9 = 36 = 6^2\r\n1+1+1+8+2+4+0+2+8+8+0+1 = 36 = 6^2\r\n4+3+3+8+0+0+0+6+3+2+2+5 = 36 = 6^2\n\r\nThe sum of their digit pairs are square numbers:\n\r\n10+03+07+12+43+69 = 144 = 12^2\r\n11+18+24+02+88+01 = 144 = 12^2\r\n43+38+00+06+32+25 = 144 = 12^2\n\r\nThe sum of their digit triplets are square numbers:\n\r\n100+307+124+369 = 900 = 30^2\r\n111+824+028+801 = 1764 = 42^2\r\n433+800+063+225 = 1521 = 39^2\n\r\nThe sum of their digit quadruplets are square numbers:\n\r\n1003+0712+4369 = 6084 = 78^2\r\n1118+2402+8801 = 12321 = 111^2\r\n4338+0006+3225 = 7569 = 87^2\n\r\nThe sum of their digit sextuplets are square numbers:\n\r\n100307+124369 = 224676 = 474^2\r\n111824+028801 = 140625 = 375^2\r\n433800+063225 = 497025 = 705^2\n<|im_end|>" }, { "id": "#21080", "title": "The Candles On The Cake", "fun": 2.46, "difficulty": 1.45, "author": "MrBasKetBall", "desc": "You are at a birthday party and the cake is brought in. The birthday candles on the cake are in a pattern: red, yellow, red, yellow, blue, red, yellow, blue, green. The pattern continues, adding pink, orange, purple, and white candles.\n\r\nHow many candles are on the cake in all?", "hint": "Illustrate the pattern with colors or letters, adding each new color in its turn.", "answer": "The pattern:\n\n\r\nred, yellow,\r\nred, yellow, blue,\r\nred, yellow, blue, green,\r\nred, yellow, blue, green, pink,\r\nred, yellow, blue, green, pink, orange,\r\nred, yellow, blue, green, pink, orange, purple,\r\nred, yellow, blue, green, pink, orange, purple, white\n\n\r\nTotal Candles:\n\n\r\n2 + 3 + 4 + 5 + 6 + 7 + 8 = 35", "category": "Math", "date": "02/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are at a birthday party and the cake is brought in. The birthday candles on the cake are in a pattern: red, yellow, red, yellow, blue, red, yellow, blue, green. The pattern continues, adding pink, orange, purple, and white candles.\n\r\nHow many candles are on the cake in all?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pattern:\n\n\r\nred, yellow,\r\nred, yellow, blue,\r\nred, yellow, blue, green,\r\nred, yellow, blue, green, pink,\r\nred, yellow, blue, green, pink, orange,\r\nred, yellow, blue, green, pink, orange, purple,\r\nred, yellow, blue, green, pink, orange, purple, white\n\n\r\nTotal Candles:\n\n\r\n2 + 3 + 4 + 5 + 6 + 7 + 8 = 35\n<|im_start|>answer\nThe pattern:\n\n\r\nred, yellow,\r\nred, yellow, blue,\r\nred, yellow, blue, green,\r\nred, yellow, blue, green, pink,\r\nred, yellow, blue, green, pink, orange,\r\nred, yellow, blue, green, pink, orange, purple,\r\nred, yellow, blue, green, pink, orange, purple, white\n\n\r\nTotal Candles:\n\n\r\n2 + 3 + 4 + 5 + 6 + 7 + 8 = 35\n<|im_end|>" }, { "id": "#39732", "title": "Handy Candy", "fun": 2.46, "difficulty": 0.87, "author": "icestar12", "desc": "The kids on Abracadabra Street counted all of their Halloween candy. They had 18 pieces of candy in all.\n\r\nAbby had fewer than 4 pieces of candy. \r\nBilly had twice as much as Abby. \r\nCharlie had twice as much as Billy. \r\nDavid had 2 pieces more than Abby. \n\r\nHow many pieces of candy did each kid have?", "hint": "No hint available.", "answer": "Abby had 2 pieces, Billy had 4 pieces, Charlie had 8 pieces, and David had 4 pieces.", "category": "Logic", "date": "12/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe kids on Abracadabra Street counted all of their Halloween candy. They had 18 pieces of candy in all.\n\r\nAbby had fewer than 4 pieces of candy. \r\nBilly had twice as much as Abby. \r\nCharlie had twice as much as Billy. \r\nDavid had 2 pieces more than Abby. \n\r\nHow many pieces of candy did each kid have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbby had 2 pieces, Billy had 4 pieces, Charlie had 8 pieces, and David had 4 pieces.\n<|im_start|>answer\nAbby had 2 pieces, Billy had 4 pieces, Charlie had 8 pieces, and David had 4 pieces.\n<|im_end|>" }, { "id": "#23511", "title": "The Three Sisters", "fun": 2.46, "difficulty": 0.92, "author": "goosh", "desc": "Names: Mary, Sarah, and Cindy\r\nAges: 16, 17, and 18\r\nFavorite animals: cat, snake, and turtle.\n\r\n1. Cindy is either the youngest or the oldest.\r\n2. No one has the same first initial as their animal.\r\n3. Mary is not the oldest or the youngest.\r\n4. Cindy's pet is the turtle.\r\n5. Sarah is not the oldest.", "hint": "No hint available.", "answer": "Cindy: 18, turtle\r\nMary: 17,snake\r\nSarah: 16, cat", "category": "Logic", "date": "06/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNames: Mary, Sarah, and Cindy\r\nAges: 16, 17, and 18\r\nFavorite animals: cat, snake, and turtle.\n\r\n1. Cindy is either the youngest or the oldest.\r\n2. No one has the same first initial as their animal.\r\n3. Mary is not the oldest or the youngest.\r\n4. Cindy's pet is the turtle.\r\n5. Sarah is not the oldest.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCindy: 18, turtle\r\nMary: 17,snake\r\nSarah: 16, cat\n<|im_start|>answer\nCindy: 18, turtle\r\nMary: 17,snake\r\nSarah: 16, cat\n<|im_end|>" }, { "id": "#8532", "title": "Lest Outta Tera", "fun": 2.46, "difficulty": 1.45, "author": "lesternoronha1", "desc": "Lester owns a factory adept at making a substance called Lest. It is made by using a substance called Tera. \r\nMaking 1 unit of Lest involves using 11 grams of Tera and during it's processing 2 grams of Tera are given out which are reusable.\r\nNow Lester has ordered for 128 grams of Tera.\r\nHow many units of Lest can be made out of that?", "hint": "The 2 grams of Tera can be reused with another 9 grams to make a unit of Lest.", "answer": "Lester can make 14 units of Lest.\n\r\n128 grams of Tera gives 11 units of Lest and 22 grams of Tera are given out with 7 grams already left from 128 thus leading to 29 grams.\n\r\nThese 29 grams can make 2 units of Lest and 11 grams are left out ( 7 left behind and 4 given out during processing).\n\r\nThese 11 grams are used to make 1 unit of Lest.\n\r\nThus the number of units of Lest = 11+2+1=14.", "category": "Math", "date": "11/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester owns a factory adept at making a substance called Lest. It is made by using a substance called Tera. \r\nMaking 1 unit of Lest involves using 11 grams of Tera and during it's processing 2 grams of Tera are given out which are reusable.\r\nNow Lester has ordered for 128 grams of Tera.\r\nHow many units of Lest can be made out of that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLester can make 14 units of Lest.\n\r\n128 grams of Tera gives 11 units of Lest and 22 grams of Tera are given out with 7 grams already left from 128 thus leading to 29 grams.\n\r\nThese 29 grams can make 2 units of Lest and 11 grams are left out ( 7 left behind and 4 given out during processing).\n\r\nThese 11 grams are used to make 1 unit of Lest.\n\r\nThus the number of units of Lest = 11+2+1=14.\n<|im_start|>answer\nLester can make 14 units of Lest.\n\r\n128 grams of Tera gives 11 units of Lest and 22 grams of Tera are given out with 7 grams already left from 128 thus leading to 29 grams.\n\r\nThese 29 grams can make 2 units of Lest and 11 grams are left out ( 7 left behind and 4 given out during processing).\n\r\nThese 11 grams are used to make 1 unit of Lest.\n\r\nThus the number of units of Lest = 11+2+1=14.\n<|im_end|>" }, { "id": "#38464", "title": "Four Consecutive Natural Numbers", "fun": 2.46, "difficulty": 2.46, "author": "lips", "desc": "The product of four consecutive natural numbers is 9???4, and we don't know what the ?s are. Find the largest number of the four.", "hint": "No hint available.", "answer": "The product of four consecutive natural numbers end with a 4, therefore none of them can end with 5 or 0, and their unit digits can be only 1, 2, 3, 4 or 6, 7, 8, 9.\n\r\nSince 20^4=160000 and 15^4=50625, they can only be 16 through 19, and we check that 16*17*18*19=93024.\n\r\nTherefore, the largest number of the four is 19.", "category": "Math", "date": "09/26/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe product of four consecutive natural numbers is 9???4, and we don't know what the ?s are. Find the largest number of the four.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe product of four consecutive natural numbers end with a 4, therefore none of them can end with 5 or 0, and their unit digits can be only 1, 2, 3, 4 or 6, 7, 8, 9.\n\r\nSince 20^4=160000 and 15^4=50625, they can only be 16 through 19, and we check that 16*17*18*19=93024.\n\r\nTherefore, the largest number of the four is 19.\n<|im_start|>answer\nThe product of four consecutive natural numbers end with a 4, therefore none of them can end with 5 or 0, and their unit digits can be only 1, 2, 3, 4 or 6, 7, 8, 9.\n\r\nSince 20^4=160000 and 15^4=50625, they can only be 16 through 19, and we check that 16*17*18*19=93024.\n\r\nTherefore, the largest number of the four is 19.\n<|im_end|>" }, { "id": "#39343", "title": "Office Order", "fun": 2.46, "difficulty": 0.73, "author": "lesliep72875", "desc": "Monica's boss asked her to order some supplies for an important project. While organizing her desk, she spilled her coffee all over her ordering list. The list was soaked and partially unreadable. Please help Monica determine the ordering information.\n\r\nItems: 24 Binders, 1 Overhead Projector, 24 Pens, and 2 Cartons of Paper\n\r\nSuppliers: Office Chain, Presentation Co., Recycling Co., and Reporting Corp.\n\r\nCost of Items: $480, $250, $20, $110\n\r\n1) The projector is not the most expensive item; however, it's not cheapest either.\n\r\n2) The paper costs $55 per carton through Recycling Co.\n\r\n3) The binders are the most expensive and are not ordered from Office Chain; however, the cheapest item is.\n\r\n4) The most expensive item is not ordered from Presentation Co.", "hint": "No hint available.", "answer": "Item - Cost - Suppliers\n\r\n24 Pens - $20 - Office Chain\r\n24 Binders - $480 - Reporting Corp.\r\n1 Overhead Projector - $250 - Presentation Co.\r\n2 Cartons of Paper - $110 - Recycling Co.", "category": "Logic-Grid", "date": "11/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMonica's boss asked her to order some supplies for an important project. While organizing her desk, she spilled her coffee all over her ordering list. The list was soaked and partially unreadable. Please help Monica determine the ordering information.\n\r\nItems: 24 Binders, 1 Overhead Projector, 24 Pens, and 2 Cartons of Paper\n\r\nSuppliers: Office Chain, Presentation Co., Recycling Co., and Reporting Corp.\n\r\nCost of Items: $480, $250, $20, $110\n\r\n1) The projector is not the most expensive item; however, it's not cheapest either.\n\r\n2) The paper costs $55 per carton through Recycling Co.\n\r\n3) The binders are the most expensive and are not ordered from Office Chain; however, the cheapest item is.\n\r\n4) The most expensive item is not ordered from Presentation Co.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nItem - Cost - Suppliers\n\r\n24 Pens - $20 - Office Chain\r\n24 Binders - $480 - Reporting Corp.\r\n1 Overhead Projector - $250 - Presentation Co.\r\n2 Cartons of Paper - $110 - Recycling Co.\n<|im_start|>answer\nItem - Cost - Suppliers\n\r\n24 Pens - $20 - Office Chain\r\n24 Binders - $480 - Reporting Corp.\r\n1 Overhead Projector - $250 - Presentation Co.\r\n2 Cartons of Paper - $110 - Recycling Co.\n<|im_end|>" }, { "id": "#26605", "title": "Knight's Trouble", "fun": 2.46, "difficulty": 2.32, "author": "kiss", "desc": "Having failed to achieve his previous goal, the knight wanted to leave Breadland. However, he was captured by the king of Breadland for stepping all around in his kingdom.\n\r\nThe king decided to sentence the knight to death, but before that he wanted to test the knight's intelligence. The king said:\n\r\n\"Play a game of chess with me. You know, in my kingdom, the chessboard is 9x7. Each player has a queen on each side of the king, one is next to the king and the other is between a bishop and a knight. Also, each player has an additional pawn. \n\r\nBut this time the rule is changed. Each player in turn must make TWO legal moves. He can't put his king in check either after his first move or after his second move. \n\r\nIf you win or the game ties, I'll set you free. If I win, I'll sentence you to death immediately.\n\r\nYou move first.\"\n\r\nCould the knight avoid being sentenced to death?", "hint": "I only asked whether or not the knight could avoid being sentenced. I didn't ask which moves must the knight make to avoid being sentenced.", "answer": "The answer is affirmative.\n\r\nAssume that the knight couldn't avoid being sentenced. This means that no matter what moves the knight made, the king could always win.\n\r\nThen the knight could move one of his knights and then move back. \r\nBut then every piece would be on its original position, and it would be the king's turn to move, and the knight could win the game, which contradicts our assumption.\n\r\nHence, the knight had a strategy to guarantee at least a tie.\n\r\nNote that I didn't point out what the strategy is. I only showed its existence.", "category": "Logic", "date": "10/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHaving failed to achieve his previous goal, the knight wanted to leave Breadland. However, he was captured by the king of Breadland for stepping all around in his kingdom.\n\r\nThe king decided to sentence the knight to death, but before that he wanted to test the knight's intelligence. The king said:\n\r\n\"Play a game of chess with me. You know, in my kingdom, the chessboard is 9x7. Each player has a queen on each side of the king, one is next to the king and the other is between a bishop and a knight. Also, each player has an additional pawn. \n\r\nBut this time the rule is changed. Each player in turn must make TWO legal moves. He can't put his king in check either after his first move or after his second move. \n\r\nIf you win or the game ties, I'll set you free. If I win, I'll sentence you to death immediately.\n\r\nYou move first.\"\n\r\nCould the knight avoid being sentenced to death?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is affirmative.\n\r\nAssume that the knight couldn't avoid being sentenced. This means that no matter what moves the knight made, the king could always win.\n\r\nThen the knight could move one of his knights and then move back. \r\nBut then every piece would be on its original position, and it would be the king's turn to move, and the knight could win the game, which contradicts our assumption.\n\r\nHence, the knight had a strategy to guarantee at least a tie.\n\r\nNote that I didn't point out what the strategy is. I only showed its existence.\n<|im_start|>answer\nThe answer is affirmative.\n\r\nAssume that the knight couldn't avoid being sentenced. This means that no matter what moves the knight made, the king could always win.\n\r\nThen the knight could move one of his knights and then move back. \r\nBut then every piece would be on its original position, and it would be the king's turn to move, and the knight could win the game, which contradicts our assumption.\n\r\nHence, the knight had a strategy to guarantee at least a tie.\n\r\nNote that I didn't point out what the strategy is. I only showed its existence.\n<|im_end|>" }, { "id": "#14200", "title": "Water in Jugs", "fun": 2.46, "difficulty": 2.16, "author": "riddler81", "desc": "You have three jugs:\n\r\nA 10-liter jug, filled with water\r\nA 7-liter jug, empty\r\nA 3-liter jug, empty\n\r\nYour objective is to end up having 5 liters of water in the 10-liter jug, and 5 liters of water in the 7-liter jug.\r\nNote that you have nothing else at your disposal other than these three jugs and that you cannot perform measurements by eye or based on the shape of the jugs.", "hint": "No hint available.", "answer": "It is not that difficult. Let us label the 10-liter jug as X, the 7-liters jug as Y, and the 3-liters jug as Z. Here are the steps:\r\n1.Pour Jug X into Jug Z.\r\n2.Pour Jug Z into Jug Y.\r\n3.Pour Jug X into Jug Z.\r\n4.Pour Jug Z into Jug Y.\r\n5.Pour Jug X into Jug Z.\n\r\nNow you have 1 liter of water in the 10-liter Jug (X), 6 liters of water in the 7-liters jug (Y), and 3 liters of water in the 3-liters jug (Z). Now pour water from jug Z into jug Y, until jug Y becomes full. You will now have 1 liter of water in X, 7 liters in Y, and 2 liters in Z. Then perform the following steps:\n\r\n1.Pour Jug Y into Jug X.\r\n2.Pour Jug Z into Jug Y.\r\n3.Pour Jug X into Jug Z.\r\n4.Pour Jug Z into Jug Y.\n\r\nAt this point, you will have 5 liters of water in X and 5 liters in Y just as desired.", "category": "Logic", "date": "08/07/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have three jugs:\n\r\nA 10-liter jug, filled with water\r\nA 7-liter jug, empty\r\nA 3-liter jug, empty\n\r\nYour objective is to end up having 5 liters of water in the 10-liter jug, and 5 liters of water in the 7-liter jug.\r\nNote that you have nothing else at your disposal other than these three jugs and that you cannot perform measurements by eye or based on the shape of the jugs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is not that difficult. Let us label the 10-liter jug as X, the 7-liters jug as Y, and the 3-liters jug as Z. Here are the steps:\r\n1.Pour Jug X into Jug Z.\r\n2.Pour Jug Z into Jug Y.\r\n3.Pour Jug X into Jug Z.\r\n4.Pour Jug Z into Jug Y.\r\n5.Pour Jug X into Jug Z.\n\r\nNow you have 1 liter of water in the 10-liter Jug (X), 6 liters of water in the 7-liters jug (Y), and 3 liters of water in the 3-liters jug (Z). Now pour water from jug Z into jug Y, until jug Y becomes full. You will now have 1 liter of water in X, 7 liters in Y, and 2 liters in Z. Then perform the following steps:\n\r\n1.Pour Jug Y into Jug X.\r\n2.Pour Jug Z into Jug Y.\r\n3.Pour Jug X into Jug Z.\r\n4.Pour Jug Z into Jug Y.\n\r\nAt this point, you will have 5 liters of water in X and 5 liters in Y just as desired.\n<|im_start|>answer\nIt is not that difficult. Let us label the 10-liter jug as X, the 7-liters jug as Y, and the 3-liters jug as Z. Here are the steps:\r\n1.Pour Jug X into Jug Z.\r\n2.Pour Jug Z into Jug Y.\r\n3.Pour Jug X into Jug Z.\r\n4.Pour Jug Z into Jug Y.\r\n5.Pour Jug X into Jug Z.\n\r\nNow you have 1 liter of water in the 10-liter Jug (X), 6 liters of water in the 7-liters jug (Y), and 3 liters of water in the 3-liters jug (Z). Now pour water from jug Z into jug Y, until jug Y becomes full. You will now have 1 liter of water in X, 7 liters in Y, and 2 liters in Z. Then perform the following steps:\n\r\n1.Pour Jug Y into Jug X.\r\n2.Pour Jug Z into Jug Y.\r\n3.Pour Jug X into Jug Z.\r\n4.Pour Jug Z into Jug Y.\n\r\nAt this point, you will have 5 liters of water in X and 5 liters in Y just as desired.\n<|im_end|>" }, { "id": "#12064", "title": "Creative Slicing", "fun": 2.46, "difficulty": 1.2, "author": "just_moi", "desc": "How can you divide a pizza into 8 equal slices using only 3 straight cuts?", "hint": "The solution is likely to be messy!", "answer": "Cut #1: Cut the pizza straight down the middle into two halves\n\r\nCut #2: Keeping the two halves in place, cut the pizza straight down the middle at right angles to the first cut (you will be left with 4 equal quarters\n\r\nCut #3: Pile the 4 quarters on top of each other and cut through the middle of the pile. You will be left with 8 equal slices.", "category": "Logic", "date": "04/27/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can you divide a pizza into 8 equal slices using only 3 straight cuts?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCut #1: Cut the pizza straight down the middle into two halves\n\r\nCut #2: Keeping the two halves in place, cut the pizza straight down the middle at right angles to the first cut (you will be left with 4 equal quarters\n\r\nCut #3: Pile the 4 quarters on top of each other and cut through the middle of the pile. You will be left with 8 equal slices.\n<|im_start|>answer\nCut #1: Cut the pizza straight down the middle into two halves\n\r\nCut #2: Keeping the two halves in place, cut the pizza straight down the middle at right angles to the first cut (you will be left with 4 equal quarters\n\r\nCut #3: Pile the 4 quarters on top of each other and cut through the middle of the pile. You will be left with 8 equal slices.\n<|im_end|>" }, { "id": "#46133", "title": "Pizza Puzzle", "fun": 2.46, "difficulty": 1.7, "author": "Scorefire", "desc": "Amy was eating a pizza, and the pizza is cut into 8 pieces. Because this is mathematics, and mathematics is exact, we will say that eating a 1/8 of a pizza takes exactly 2 minutes.\n\r\nNow, Amy starts eating, but 2 minutes later, Barney comes, and he wants pizza too. So they both eat some more pizza, until, 2 minutes later, Chris arrives and he wants some pizza too! So they all eat pizza, until, 2 minutes later, Dean arrives, and he wants pizza as well! Now, there is not enough pizza for all of them to share with the way it is cut, so they'll have to cut the pizza into 4 pieces. Now, cutting 1 straight line (No matter how long or short) takes 1 minute, and (because there are 4 people) it takes them 4 times less of the amount of time to cut one straight line. What is the shortest amount of time they can achieve this? (Cutting the pizza, not eating the pizza)", "hint": "How many 1/8s of a pizza are left?Think about the way they can place what is left of the pizza.", "answer": "15 seconds.\n\r\nIf Amy starts eating one slice, and two minutes later, Barney comes, that means that she ate 1 slice (1/8 of the pizza). Then when Barney and Amy continue eating until Chris comes, they would've eaten 2 slices together, making 3 slices eaten altogether. And when Amy, Barney, and Chris continue eating until Dean comes, they eat 3 slices combined, and altogether, 6 slices, leaving 2 slices uneaten. If they place the 2 slices opposite each other, then they can cut 1 straight line to cut both of the two pieces in half, and then they have 4/16 or 4 halves of a slice.", "category": "Math", "date": "01/03/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAmy was eating a pizza, and the pizza is cut into 8 pieces. Because this is mathematics, and mathematics is exact, we will say that eating a 1/8 of a pizza takes exactly 2 minutes.\n\r\nNow, Amy starts eating, but 2 minutes later, Barney comes, and he wants pizza too. So they both eat some more pizza, until, 2 minutes later, Chris arrives and he wants some pizza too! So they all eat pizza, until, 2 minutes later, Dean arrives, and he wants pizza as well! Now, there is not enough pizza for all of them to share with the way it is cut, so they'll have to cut the pizza into 4 pieces. Now, cutting 1 straight line (No matter how long or short) takes 1 minute, and (because there are 4 people) it takes them 4 times less of the amount of time to cut one straight line. What is the shortest amount of time they can achieve this? (Cutting the pizza, not eating the pizza)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15 seconds.\n\r\nIf Amy starts eating one slice, and two minutes later, Barney comes, that means that she ate 1 slice (1/8 of the pizza). Then when Barney and Amy continue eating until Chris comes, they would've eaten 2 slices together, making 3 slices eaten altogether. And when Amy, Barney, and Chris continue eating until Dean comes, they eat 3 slices combined, and altogether, 6 slices, leaving 2 slices uneaten. If they place the 2 slices opposite each other, then they can cut 1 straight line to cut both of the two pieces in half, and then they have 4/16 or 4 halves of a slice.\n<|im_start|>answer\n15 seconds.\n\r\nIf Amy starts eating one slice, and two minutes later, Barney comes, that means that she ate 1 slice (1/8 of the pizza). Then when Barney and Amy continue eating until Chris comes, they would've eaten 2 slices together, making 3 slices eaten altogether. And when Amy, Barney, and Chris continue eating until Dean comes, they eat 3 slices combined, and altogether, 6 slices, leaving 2 slices uneaten. If they place the 2 slices opposite each other, then they can cut 1 straight line to cut both of the two pieces in half, and then they have 4/16 or 4 halves of a slice.\n<|im_end|>" }, { "id": "#9403", "title": "Snapoker Scoring", "fun": 2.46, "difficulty": 2.56, "author": "snaps", "desc": "The card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frantic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nThe other day, I was having a lively game of Snapoker with three friends when, after three hands, my good friend Kasy commented that my score was the only score that was not a prime number. What was my score?", "hint": "In each hand there are a total of 10 points on offer, so after three hands the total of all four players' points must be 30.", "answer": "I was on 9 points.\n\r\nAfter one round of Snapoker a total of 10 points have been awarded to the four players, so after three rounds a total of 30 points have been awarded, meaning players' scores must add up to 30.\n\r\nThe lowest score after three hands is 3 (receiving 1 point every hand) and the greatest score is 12 (receiving 4 points every hand). Note also that if one player has a score of 3, the next lowest possible score is 6 (receiving 2 points on every hand). Similarly, if one player has a score of 12, the next highest possible is 9 (receiving 3 points every hand). If however a player has a score of 4 (1, 1 and 2 points) the next lowest possible score is 5 (2, 2 and 1 points). A similar approach can be applied for lowest scores of 5, 6 and 7 and for highest scores of 11, 10 and 9.\n\r\nNow while there are many possible combinations of points that add up to 30, there are only three combinations where one player's score is not a prime number. These combinations of points are:\r\n3, 7, 9, 11;\r\n5, 5, 9, 11;\r\n7, 7, 7, 9.\n\r\nIn each of the cases above, 9 is the only non-prime and thus must be my score.", "category": "Math", "date": "12/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frantic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nThe other day, I was having a lively game of Snapoker with three friends when, after three hands, my good friend Kasy commented that my score was the only score that was not a prime number. What was my score?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI was on 9 points.\n\r\nAfter one round of Snapoker a total of 10 points have been awarded to the four players, so after three rounds a total of 30 points have been awarded, meaning players' scores must add up to 30.\n\r\nThe lowest score after three hands is 3 (receiving 1 point every hand) and the greatest score is 12 (receiving 4 points every hand). Note also that if one player has a score of 3, the next lowest possible score is 6 (receiving 2 points on every hand). Similarly, if one player has a score of 12, the next highest possible is 9 (receiving 3 points every hand). If however a player has a score of 4 (1, 1 and 2 points) the next lowest possible score is 5 (2, 2 and 1 points). A similar approach can be applied for lowest scores of 5, 6 and 7 and for highest scores of 11, 10 and 9.\n\r\nNow while there are many possible combinations of points that add up to 30, there are only three combinations where one player's score is not a prime number. These combinations of points are:\r\n3, 7, 9, 11;\r\n5, 5, 9, 11;\r\n7, 7, 7, 9.\n\r\nIn each of the cases above, 9 is the only non-prime and thus must be my score.\n<|im_start|>answer\nI was on 9 points.\n\r\nAfter one round of Snapoker a total of 10 points have been awarded to the four players, so after three rounds a total of 30 points have been awarded, meaning players' scores must add up to 30.\n\r\nThe lowest score after three hands is 3 (receiving 1 point every hand) and the greatest score is 12 (receiving 4 points every hand). Note also that if one player has a score of 3, the next lowest possible score is 6 (receiving 2 points on every hand). Similarly, if one player has a score of 12, the next highest possible is 9 (receiving 3 points every hand). If however a player has a score of 4 (1, 1 and 2 points) the next lowest possible score is 5 (2, 2 and 1 points). A similar approach can be applied for lowest scores of 5, 6 and 7 and for highest scores of 11, 10 and 9.\n\r\nNow while there are many possible combinations of points that add up to 30, there are only three combinations where one player's score is not a prime number. These combinations of points are:\r\n3, 7, 9, 11;\r\n5, 5, 9, 11;\r\n7, 7, 7, 9.\n\r\nIn each of the cases above, 9 is the only non-prime and thus must be my score.\n<|im_end|>" }, { "id": "#36498", "title": "Knights & Knaves II", "fun": 2.46, "difficulty": 1.7, "author": "ChRmD1", "desc": "A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie.\n\r\nThere, you meet three inhabitants: Abe, Bess, and Carol. Abe says, 'At least one of the following is true: that Carol is a knave or that I am a knight.' Bess says, 'Abe could claim that I am a knave.' Carol claims, 'Neither Abe nor Bess are knights.'\n\r\nSo who is a knight and who is a knave?", "hint": "Guess and Check", "answer": "Take Carol's statement and assume that it is true, and that she is a knight. This would mean that both Abe and Bess are knaves. This would mean that Abe couldn't claim that Bess is a knave, which works since, if he did, he would be telling the truth, which we have already said was not true. This means that Abe's statement is also false, so none of the following would be true, and Carol would be a knight and Abe would be a knave, which fits the previous information. Therefore, Abe and Bess are knaves, and Carol is a knight.", "category": "Logic", "date": "05/04/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie.\n\r\nThere, you meet three inhabitants: Abe, Bess, and Carol. Abe says, 'At least one of the following is true: that Carol is a knave or that I am a knight.' Bess says, 'Abe could claim that I am a knave.' Carol claims, 'Neither Abe nor Bess are knights.'\n\r\nSo who is a knight and who is a knave?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake Carol's statement and assume that it is true, and that she is a knight. This would mean that both Abe and Bess are knaves. This would mean that Abe couldn't claim that Bess is a knave, which works since, if he did, he would be telling the truth, which we have already said was not true. This means that Abe's statement is also false, so none of the following would be true, and Carol would be a knight and Abe would be a knave, which fits the previous information. Therefore, Abe and Bess are knaves, and Carol is a knight.\n<|im_start|>answer\nTake Carol's statement and assume that it is true, and that she is a knight. This would mean that both Abe and Bess are knaves. This would mean that Abe couldn't claim that Bess is a knave, which works since, if he did, he would be telling the truth, which we have already said was not true. This means that Abe's statement is also false, so none of the following would be true, and Carol would be a knight and Abe would be a knave, which fits the previous information. Therefore, Abe and Bess are knaves, and Carol is a knight.\n<|im_end|>" }, { "id": "#31244", "title": "25-9=2?", "fun": 2.46, "difficulty": 1.74, "author": "bballer21", "desc": "Can you make this statement true by adding two mathematic symbols?\r\n25-9=2", "hint": "No hint available.", "answer": "Take the square roots.\r\nSquare root of 25 is 5.\r\nSquare root of 9 is 3.\r\n5-3 is 2.", "category": "Math", "date": "06/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you make this statement true by adding two mathematic symbols?\r\n25-9=2\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake the square roots.\r\nSquare root of 25 is 5.\r\nSquare root of 9 is 3.\r\n5-3 is 2.\n<|im_start|>answer\nTake the square roots.\r\nSquare root of 25 is 5.\r\nSquare root of 9 is 3.\r\n5-3 is 2.\n<|im_end|>" }, { "id": "#4528", "title": "Fishing Rod", "fun": 2.46, "difficulty": 1.83, "author": "mad-ade", "desc": "Mad Ade rides the bus to the local Hardware Store. While there he buys a fishing pole that's 5 feet long. As Mad Ade goes to get on the bus to go home, he is stopped by the bus driver. The bus driver tells him he can't board the bus with anything over 4 feet long. \n\r\nMad Ade goes back to the Hardware store and buys one thing then returns and boards the bus. \n\r\nThe pole can not be cut, bent, broken, or taken apart. What did the Mad Ade buy to allow him to board the bus with the fishing pole?", "hint": "No hint available.", "answer": "A box 4' X 3'. He then puts the pole in diagonally.", "category": "Math", "date": "06/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade rides the bus to the local Hardware Store. While there he buys a fishing pole that's 5 feet long. As Mad Ade goes to get on the bus to go home, he is stopped by the bus driver. The bus driver tells him he can't board the bus with anything over 4 feet long. \n\r\nMad Ade goes back to the Hardware store and buys one thing then returns and boards the bus. \n\r\nThe pole can not be cut, bent, broken, or taken apart. What did the Mad Ade buy to allow him to board the bus with the fishing pole?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA box 4' X 3'. He then puts the pole in diagonally.\n<|im_start|>answer\nA box 4' X 3'. He then puts the pole in diagonally.\n<|im_end|>" }, { "id": "#34851", "title": "In Da Zone Pop Group", "fun": 2.46, "difficulty": 1.14, "author": "scallio", "desc": "The newest teen group to hit the pop scene is \"In Da Zone\". The group has 4 members. Can you sort out which girl wears what color clothes and shoes and the color of her hair?\n\r\nNames: Jayray, Cici, Rhen, Chloe\r\nOutfits: yellow, blue, red, green\r\nShoes: brown, yellow, white, black\r\nHair: brown, purple, black, blonde\n\n\r\nJayray has purple hair.\n\r\nThe girl with the black hair always wears a green outfit with brown go-go boots.\n\r\nCici is not a blonde.\n\r\nRhen does not have brown hair.\n\r\nChloe wears the blue themed clothes, but does not wear black or yellow shoes.\n\r\nThe blonde does not wear red.\n\r\nRhen does not wear green clothes, nor white or black shoes.\n\r\nThe girl that wears the yellow shirt and skirt always wears matching yellow platform pumps and hair.", "hint": "Cici wears the brown go-go boots.", "answer": "Jayray, with her purple hair, wears red outfits with black shoes.\n\r\nCici has black hair and wears green clothes with brown go-go boots.\n\r\nRhen, the blonde, wears yellow clothes with matching yellow platform pumps.\n\r\nChloe has the brown hair, blue outfit and white shoes.", "category": "Logic-Grid", "date": "01/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe newest teen group to hit the pop scene is \"In Da Zone\". The group has 4 members. Can you sort out which girl wears what color clothes and shoes and the color of her hair?\n\r\nNames: Jayray, Cici, Rhen, Chloe\r\nOutfits: yellow, blue, red, green\r\nShoes: brown, yellow, white, black\r\nHair: brown, purple, black, blonde\n\n\r\nJayray has purple hair.\n\r\nThe girl with the black hair always wears a green outfit with brown go-go boots.\n\r\nCici is not a blonde.\n\r\nRhen does not have brown hair.\n\r\nChloe wears the blue themed clothes, but does not wear black or yellow shoes.\n\r\nThe blonde does not wear red.\n\r\nRhen does not wear green clothes, nor white or black shoes.\n\r\nThe girl that wears the yellow shirt and skirt always wears matching yellow platform pumps and hair.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJayray, with her purple hair, wears red outfits with black shoes.\n\r\nCici has black hair and wears green clothes with brown go-go boots.\n\r\nRhen, the blonde, wears yellow clothes with matching yellow platform pumps.\n\r\nChloe has the brown hair, blue outfit and white shoes.\n<|im_start|>answer\nJayray, with her purple hair, wears red outfits with black shoes.\n\r\nCici has black hair and wears green clothes with brown go-go boots.\n\r\nRhen, the blonde, wears yellow clothes with matching yellow platform pumps.\n\r\nChloe has the brown hair, blue outfit and white shoes.\n<|im_end|>" }, { "id": "#43903", "title": "Sporty People", "fun": 2.46, "difficulty": 1.04, "author": "kaipolani114", "desc": "Brandon, Britney, Brianna and Bronson each play a sport that has a competition on a different day of the week. Also, each person is in a different grade. Can you figure out each person's grade, the sport they're in and what day they compete?\n\r\nThe sports are basketball, track and field, soccer, and swimming.\r\nThe competitions are either on Thursday, Friday, Saturday, or Sunday.\r\nEach person is either a high school freshman, sophomore, junior, or senior.\n\r\n1. Neither of the girls plays basketball or swims, and neither has competitions on Fridays or Sundays.\r\n2. The person who plays basketball is a senior. The basketball game is on Fridays.\r\n3. Bronson is one grade higher than Brianna.\r\n4. In the sport Britney is in, she gets kicked a lot.\r\n5. Bronson is in a sport that doesn't require running during the competitions.\r\n6. Britney is a freshman.\r\n7. The soccer games are on Thursdays.", "hint": "No hint available.", "answer": "Britney is a freshman who plays soccer. Her games are on Thursdays.\r\nBrianna is a sophomore who is in track and field. Her meets are on Saturdays.\r\nBronson is a junior who is on the swim team. His meets are on Sundays.\r\nBrandon is a senior who plays basketball. His games are on Fridays.", "category": "Logic-Grid", "date": "01/12/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBrandon, Britney, Brianna and Bronson each play a sport that has a competition on a different day of the week. Also, each person is in a different grade. Can you figure out each person's grade, the sport they're in and what day they compete?\n\r\nThe sports are basketball, track and field, soccer, and swimming.\r\nThe competitions are either on Thursday, Friday, Saturday, or Sunday.\r\nEach person is either a high school freshman, sophomore, junior, or senior.\n\r\n1. Neither of the girls plays basketball or swims, and neither has competitions on Fridays or Sundays.\r\n2. The person who plays basketball is a senior. The basketball game is on Fridays.\r\n3. Bronson is one grade higher than Brianna.\r\n4. In the sport Britney is in, she gets kicked a lot.\r\n5. Bronson is in a sport that doesn't require running during the competitions.\r\n6. Britney is a freshman.\r\n7. The soccer games are on Thursdays.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBritney is a freshman who plays soccer. Her games are on Thursdays.\r\nBrianna is a sophomore who is in track and field. Her meets are on Saturdays.\r\nBronson is a junior who is on the swim team. His meets are on Sundays.\r\nBrandon is a senior who plays basketball. His games are on Fridays.\n<|im_start|>answer\nBritney is a freshman who plays soccer. Her games are on Thursdays.\r\nBrianna is a sophomore who is in track and field. Her meets are on Saturdays.\r\nBronson is a junior who is on the swim team. His meets are on Sundays.\r\nBrandon is a senior who plays basketball. His games are on Fridays.\n<|im_end|>" }, { "id": "#28678", "title": "1999", "fun": 2.46, "difficulty": 1.43, "author": "lips", "desc": "The year 1999 is special. Using the numbers 1, 9, 9 and 9, in that order, make the number 89. You may use brackets and any standard maths operation such as the square root, +, -, * and /. For example, 26 = -1 + 9 + 9 + 9.", "hint": "No hint available.", "answer": "89 = -1 + 9 + (9 * 9).", "category": "Math", "date": "02/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe year 1999 is special. Using the numbers 1, 9, 9 and 9, in that order, make the number 89. You may use brackets and any standard maths operation such as the square root, +, -, * and /. For example, 26 = -1 + 9 + 9 + 9.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n89 = -1 + 9 + (9 * 9).\n<|im_start|>answer\n89 = -1 + 9 + (9 * 9).\n<|im_end|>" }, { "id": "#13433", "title": "Buckets of Water", "fun": 2.46, "difficulty": 1.02, "author": "mind-twister_75", "desc": "There is a fire in a building. They need exactly 7 quarts of water to put it out (don't worry about why). A man goes out to the river with the only two buckets they have: a 5 quart bucket and a 3 quart bucket. The buckets are not see-through and they have no level indicator markings. How does the man get exactly 7 quarts of water?", "hint": "No hint available.", "answer": "The man takes the 5 quart bucket and fills it up. Then he dumps the water into the 3 quart bucket. Then he dumps the 3 quart bucket back in the river. He then dumps what's left in the 5 quart bucket (2 quarts) into the 3 quart bucket. Then he fills up the 5 quart bucket. Both buckets together now total 7 quarts: 5 quarts in the 5 quart bucket and 2 quarts in the 3 quart bucket.", "category": "Logic", "date": "06/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a fire in a building. They need exactly 7 quarts of water to put it out (don't worry about why). A man goes out to the river with the only two buckets they have: a 5 quart bucket and a 3 quart bucket. The buckets are not see-through and they have no level indicator markings. How does the man get exactly 7 quarts of water?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man takes the 5 quart bucket and fills it up. Then he dumps the water into the 3 quart bucket. Then he dumps the 3 quart bucket back in the river. He then dumps what's left in the 5 quart bucket (2 quarts) into the 3 quart bucket. Then he fills up the 5 quart bucket. Both buckets together now total 7 quarts: 5 quarts in the 5 quart bucket and 2 quarts in the 3 quart bucket.\n<|im_start|>answer\nThe man takes the 5 quart bucket and fills it up. Then he dumps the water into the 3 quart bucket. Then he dumps the 3 quart bucket back in the river. He then dumps what's left in the 5 quart bucket (2 quarts) into the 3 quart bucket. Then he fills up the 5 quart bucket. Both buckets together now total 7 quarts: 5 quarts in the 5 quart bucket and 2 quarts in the 3 quart bucket.\n<|im_end|>" }, { "id": "#41156", "title": "Which Statement is True?", "fun": 2.46, "difficulty": 1.74, "author": "Carlos16", "desc": "Which one of these statements is true?\n\r\nStatement 1: The sum of the false statements is 8\r\nStatement 2: This statement is true\r\nStatement 3: Statement 1 is true\r\nStatement 4: Statement 2 is false", "hint": "No hint available.", "answer": "Statement 1 cannot be true because then the sum of the false statements would equal 9, not 8. Statement 3 cannot be true since that would make Statement 1 true. Statement 2 cannot be true because the sum of the false statements would equal 8, and that would result in Statements 1 and 3 being true also. Since we know Statement 2 is false, we know Statement 4 is true, because it says that Statement 2 is false.\n\r\nAnswer: Statement 4", "category": "Logic", "date": "03/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich one of these statements is true?\n\r\nStatement 1: The sum of the false statements is 8\r\nStatement 2: This statement is true\r\nStatement 3: Statement 1 is true\r\nStatement 4: Statement 2 is false\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement 1 cannot be true because then the sum of the false statements would equal 9, not 8. Statement 3 cannot be true since that would make Statement 1 true. Statement 2 cannot be true because the sum of the false statements would equal 8, and that would result in Statements 1 and 3 being true also. Since we know Statement 2 is false, we know Statement 4 is true, because it says that Statement 2 is false.\n\r\nAnswer: Statement 4\n<|im_start|>answer\nStatement 1 cannot be true because then the sum of the false statements would equal 9, not 8. Statement 3 cannot be true since that would make Statement 1 true. Statement 2 cannot be true because the sum of the false statements would equal 8, and that would result in Statements 1 and 3 being true also. Since we know Statement 2 is false, we know Statement 4 is true, because it says that Statement 2 is false.\n\r\nAnswer: Statement 4\n<|im_end|>" }, { "id": "#11687", "title": "Pick-up Sticks", "fun": 2.46, "difficulty": 1.8900000000000001, "author": "Pheonix_down", "desc": "You and your friend, who is always tricking you, are playing a game of pick-up sticks when he/she decides to change the rules. \n\r\nThe object of the game is to make the other player pick up the last stick. You can only pick up either 1,2,or 3 sticks on your turn. One player chooses how many sticks will be in the pile and the other goes first. \n\r\nThis time you go first and your friend chooses 29 sticks. Are you going to win? What is the strategy your friend uses?", "hint": "Your friend is very smart.", "answer": "No, you are not going to win if your friend knows the correct strategy. Whatever number of sticks that you pick on each turn, your friend will subtract that number from four and pick that many sticks:\n\r\nYou pick 1, he picks 3\r\nYou pick 2, he picks 2\r\nYou pick 3, he picks 1\n\r\nThen the total number of sticks will have to be one more than a number divisible by four. This will guarantee that there is one stick left after his last turn.", "category": "Logic", "date": "04/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou and your friend, who is always tricking you, are playing a game of pick-up sticks when he/she decides to change the rules. \n\r\nThe object of the game is to make the other player pick up the last stick. You can only pick up either 1,2,or 3 sticks on your turn. One player chooses how many sticks will be in the pile and the other goes first. \n\r\nThis time you go first and your friend chooses 29 sticks. Are you going to win? What is the strategy your friend uses?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo, you are not going to win if your friend knows the correct strategy. Whatever number of sticks that you pick on each turn, your friend will subtract that number from four and pick that many sticks:\n\r\nYou pick 1, he picks 3\r\nYou pick 2, he picks 2\r\nYou pick 3, he picks 1\n\r\nThen the total number of sticks will have to be one more than a number divisible by four. This will guarantee that there is one stick left after his last turn.\n<|im_start|>answer\nNo, you are not going to win if your friend knows the correct strategy. Whatever number of sticks that you pick on each turn, your friend will subtract that number from four and pick that many sticks:\n\r\nYou pick 1, he picks 3\r\nYou pick 2, he picks 2\r\nYou pick 3, he picks 1\n\r\nThen the total number of sticks will have to be one more than a number divisible by four. This will guarantee that there is one stick left after his last turn.\n<|im_end|>" }, { "id": "#40570", "title": "Lunch Break Troubles . . .", "fun": 2.46, "difficulty": 1.4, "author": "snowmonster", "desc": "James was supposed to buy 4 Hamburgers and 3 Pops for $14.50. Instead, he bought 3 Hamburgers and 4 Pops for $13.50. What was the price of a single Hamburger? A single Pop?", "hint": "No hint available.", "answer": "One Hamburger cost $2.50 and one Pop cost $1.50.", "category": "Math", "date": "02/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJames was supposed to buy 4 Hamburgers and 3 Pops for $14.50. Instead, he bought 3 Hamburgers and 4 Pops for $13.50. What was the price of a single Hamburger? A single Pop?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne Hamburger cost $2.50 and one Pop cost $1.50.\n<|im_start|>answer\nOne Hamburger cost $2.50 and one Pop cost $1.50.\n<|im_end|>" }, { "id": "#2674", "title": "United Manager", "fun": 2.46, "difficulty": 1.8, "author": "missie", "desc": "The United manager was talking to his team after the match, when he pointed at Byran Johnson, who was one of the laziest, most inept players on the pitch, and said,\"If only we had five players like him.\" Has he gone mad?", "hint": "No hint available.", "answer": "The trouble was, the whole team played like him. Having only five players like him would not have been as bad.", "category": "Logic", "date": "03/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe United manager was talking to his team after the match, when he pointed at Byran Johnson, who was one of the laziest, most inept players on the pitch, and said,\"If only we had five players like him.\" Has he gone mad?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe trouble was, the whole team played like him. Having only five players like him would not have been as bad.\n<|im_start|>answer\nThe trouble was, the whole team played like him. Having only five players like him would not have been as bad.\n<|im_end|>" }, { "id": "#48663", "title": "The Four Integers", "fun": 2.46, "difficulty": 1.49, "author": "Mathgeek007", "desc": "There are four different integers. Here are eight clues to help you find out what they are.\n\r\nThe sum of the three lowest numbers is 0.\n\r\nThe two lowest numbers are negative, and consecutive.\n\r\nThe highest number is the second-lowest number squared.\n\r\nThe difference of all the numbers (in order from greatest to least) is 9.\n\r\nThe difference of all the numbers (in order from least to greatest) is -17.\n\r\nThe difference of the two highest numbers is 2.\n\r\nThe sum of the two lowest numbers is -7.\n\r\nThe second-lowest number plus 10 is the second-highest.\n\r\nWhat are the four integers?", "hint": "You didn't forget about negative numbers, did you?", "answer": "9, 7, (-3), (-4)\n\r\n7 + (-3) + (-4) = 0\n\r\n(-3) and (-4) are negative and consecutive.\n\r\n(-3sqrd) is (-3)*(-3), which is 9.\n\r\n9 - 7 - (-3) - (-4) = 9\n\r\n(-4) - (-3) - 7 - 9 = -17\n\r\n9 - 7 = 2\n\r\n(-3) + (-4) = -7\n\r\n(-3) + 10 = 7", "category": "Math", "date": "04/23/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four different integers. Here are eight clues to help you find out what they are.\n\r\nThe sum of the three lowest numbers is 0.\n\r\nThe two lowest numbers are negative, and consecutive.\n\r\nThe highest number is the second-lowest number squared.\n\r\nThe difference of all the numbers (in order from greatest to least) is 9.\n\r\nThe difference of all the numbers (in order from least to greatest) is -17.\n\r\nThe difference of the two highest numbers is 2.\n\r\nThe sum of the two lowest numbers is -7.\n\r\nThe second-lowest number plus 10 is the second-highest.\n\r\nWhat are the four integers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9, 7, (-3), (-4)\n\r\n7 + (-3) + (-4) = 0\n\r\n(-3) and (-4) are negative and consecutive.\n\r\n(-3sqrd) is (-3)*(-3), which is 9.\n\r\n9 - 7 - (-3) - (-4) = 9\n\r\n(-4) - (-3) - 7 - 9 = -17\n\r\n9 - 7 = 2\n\r\n(-3) + (-4) = -7\n\r\n(-3) + 10 = 7\n<|im_start|>answer\n9, 7, (-3), (-4)\n\r\n7 + (-3) + (-4) = 0\n\r\n(-3) and (-4) are negative and consecutive.\n\r\n(-3sqrd) is (-3)*(-3), which is 9.\n\r\n9 - 7 - (-3) - (-4) = 9\n\r\n(-4) - (-3) - 7 - 9 = -17\n\r\n9 - 7 = 2\n\r\n(-3) + (-4) = -7\n\r\n(-3) + 10 = 7\n<|im_end|>" }, { "id": "#5758", "title": "Messed-Up Survey", "fun": 2.46, "difficulty": 0.9500000000000001, "author": "mollynoodl", "desc": "A survey agency recently reported their results of a recent survey in the local newspaper. The report clearly states that exactly 100 lawyers were interviewed. Of the one hundred, 75 own BMWs, 95 own Volvos, and 50 lawyers own both a BMW and a Volvo. \n\r\nWithin a short time, several lawyers argue that the results are incorrect. How can they tell?", "hint": "No hint available.", "answer": "The numbers do not add up correctly. The report stated that only 100 people were interviewed, but they received 120 responses. You can see this by making a Venn Diagram of the data. (BMW only-25, BMW and Volvo-50, Volvo only-45)\r\n 25\r\n 50\r\n+45\r\n----\r\n120", "category": "Logic", "date": "07/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA survey agency recently reported their results of a recent survey in the local newspaper. The report clearly states that exactly 100 lawyers were interviewed. Of the one hundred, 75 own BMWs, 95 own Volvos, and 50 lawyers own both a BMW and a Volvo. \n\r\nWithin a short time, several lawyers argue that the results are incorrect. How can they tell?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers do not add up correctly. The report stated that only 100 people were interviewed, but they received 120 responses. You can see this by making a Venn Diagram of the data. (BMW only-25, BMW and Volvo-50, Volvo only-45)\r\n 25\r\n 50\r\n+45\r\n----\r\n120\n<|im_start|>answer\nThe numbers do not add up correctly. The report stated that only 100 people were interviewed, but they received 120 responses. You can see this by making a Venn Diagram of the data. (BMW only-25, BMW and Volvo-50, Volvo only-45)\r\n 25\r\n 50\r\n+45\r\n----\r\n120\n<|im_end|>" }, { "id": "#7475", "title": "Read-a-thon", "fun": 2.46, "difficulty": 1.79, "author": "hprulz", "desc": "This year there has been a 10% increase in participation at the Summit School Annual Read-A-Thon. The school population has remained the same. Last year, 80% of the school's 550 students were involved in the event. Of the students who participated this year, 38 read just 1 or 2 books, 83 read 3 to 5 books, 172 read 6 to 9 books, and the rest read 10 or more books. \r\nWhat percentage (to the nearest whole percent) of the participating students this year read more than 5 books for the Read-A-Thon?", "hint": "No hint available.", "answer": "If 80% of the school participated in last year's Read-A-Thon, this 80% represents 550 x 0.8 = 440 students. If this year's participation shows a 10% increase on last year's, this means that 440 x 1.1 = 484 students took part. Of these, the number who read more than 5 books was 484 - (38 + 83) = 363. So, these readers were 100 x 363/484 = 75% of the participants.", "category": "Math", "date": "09/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis year there has been a 10% increase in participation at the Summit School Annual Read-A-Thon. The school population has remained the same. Last year, 80% of the school's 550 students were involved in the event. Of the students who participated this year, 38 read just 1 or 2 books, 83 read 3 to 5 books, 172 read 6 to 9 books, and the rest read 10 or more books. \r\nWhat percentage (to the nearest whole percent) of the participating students this year read more than 5 books for the Read-A-Thon?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf 80% of the school participated in last year's Read-A-Thon, this 80% represents 550 x 0.8 = 440 students. If this year's participation shows a 10% increase on last year's, this means that 440 x 1.1 = 484 students took part. Of these, the number who read more than 5 books was 484 - (38 + 83) = 363. So, these readers were 100 x 363/484 = 75% of the participants.\n<|im_start|>answer\nIf 80% of the school participated in last year's Read-A-Thon, this 80% represents 550 x 0.8 = 440 students. If this year's participation shows a 10% increase on last year's, this means that 440 x 1.1 = 484 students took part. Of these, the number who read more than 5 books was 484 - (38 + 83) = 363. So, these readers were 100 x 363/484 = 75% of the participants.\n<|im_end|>" }, { "id": "#17096", "title": "Sharks 2", "fun": 2.46, "difficulty": 2.74, "author": "cnmne", "desc": "The Boldavian navy has a rigorous training program. In order to graduate from the naval academy, cadets must enter a pool and fight sharks. Today, a group of cadets was tested. Each cadet put on his mask, snorkel, and two flippers; and armed himself with a knife. Then the cadets jumped into the pool. The sharks were then released from their pens. After 10 minutes of gruelling hand-to-fin combat, all of the sharks were killed. Miraculously, none of the cadets were killed. Exiting the pool, the cadets began to haul the shark bodies out of the water. The dead sharks were soon lying in a row. One of the cadets noted that during the fight, there were 4 times as many cadets in the water as there were sharks. A second cadet then stated that the number of legs they now had was equal to the square of the number of sharks. A third said that the number of cadet legs was 14 more than the total number of cadet and shark heads. How many sharks were killed?", "hint": "No hint available.", "answer": "7 sharks were killed.\n\r\nSince there were 4 times as many cadets, there were 28 cadets. The number of cadet legs is equal to the square of the number of sharks, which would be 49 legs. 49 legs is 14 more than the number of cadet and shark heads: 7 sharks plus 28 cadets equals 35 heads.\n\r\nNote that although all of the cadets survived, nothing was said about possible injuries. In fact, each shark had bitten off one leg from each of 7 cadets. This explains the shortage of legs, since 28 cadets should have had 56 legs, not 49. Also note the statement of the second cadet, who said 'the number of legs they NOW had ...'.", "category": "Math", "date": "03/20/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Boldavian navy has a rigorous training program. In order to graduate from the naval academy, cadets must enter a pool and fight sharks. Today, a group of cadets was tested. Each cadet put on his mask, snorkel, and two flippers; and armed himself with a knife. Then the cadets jumped into the pool. The sharks were then released from their pens. After 10 minutes of gruelling hand-to-fin combat, all of the sharks were killed. Miraculously, none of the cadets were killed. Exiting the pool, the cadets began to haul the shark bodies out of the water. The dead sharks were soon lying in a row. One of the cadets noted that during the fight, there were 4 times as many cadets in the water as there were sharks. A second cadet then stated that the number of legs they now had was equal to the square of the number of sharks. A third said that the number of cadet legs was 14 more than the total number of cadet and shark heads. How many sharks were killed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 sharks were killed.\n\r\nSince there were 4 times as many cadets, there were 28 cadets. The number of cadet legs is equal to the square of the number of sharks, which would be 49 legs. 49 legs is 14 more than the number of cadet and shark heads: 7 sharks plus 28 cadets equals 35 heads.\n\r\nNote that although all of the cadets survived, nothing was said about possible injuries. In fact, each shark had bitten off one leg from each of 7 cadets. This explains the shortage of legs, since 28 cadets should have had 56 legs, not 49. Also note the statement of the second cadet, who said 'the number of legs they NOW had ...'.\n<|im_start|>answer\n7 sharks were killed.\n\r\nSince there were 4 times as many cadets, there were 28 cadets. The number of cadet legs is equal to the square of the number of sharks, which would be 49 legs. 49 legs is 14 more than the number of cadet and shark heads: 7 sharks plus 28 cadets equals 35 heads.\n\r\nNote that although all of the cadets survived, nothing was said about possible injuries. In fact, each shark had bitten off one leg from each of 7 cadets. This explains the shortage of legs, since 28 cadets should have had 56 legs, not 49. Also note the statement of the second cadet, who said 'the number of legs they NOW had ...'.\n<|im_end|>" }, { "id": "#50300", "title": "Balance Beams 1", "fun": 2.46, "difficulty": 2.05, "author": "MarcM1098", "desc": "Two beams (rows of numbers) are given below. The first beam has a sum of 17; the second beam has a sum of 22. Your challenge is to balance the beams, so that the two rows have the same sum. You are only allowed to move two numbers; all of the numbers must be used in the answer.\n\r\n1 3 5 8\r\n2 4 7 9", "hint": "The sum of all the numbers is odd.\r\nOne of the numbers must be moved in a tricky way to make a smaller number.", "answer": "Move the 9 to the top row, but as you do, turn it upside down, making it into a 6.\r\nMove the 5 to the bottom row. Both beams now have a sum of 18.\n\r\n1 3 6 8\r\n2 4 7 5", "category": "Math", "date": "05/09/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo beams (rows of numbers) are given below. The first beam has a sum of 17; the second beam has a sum of 22. Your challenge is to balance the beams, so that the two rows have the same sum. You are only allowed to move two numbers; all of the numbers must be used in the answer.\n\r\n1 3 5 8\r\n2 4 7 9\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMove the 9 to the top row, but as you do, turn it upside down, making it into a 6.\r\nMove the 5 to the bottom row. Both beams now have a sum of 18.\n\r\n1 3 6 8\r\n2 4 7 5\n<|im_start|>answer\nMove the 9 to the top row, but as you do, turn it upside down, making it into a 6.\r\nMove the 5 to the bottom row. Both beams now have a sum of 18.\n\r\n1 3 6 8\r\n2 4 7 5\n<|im_end|>" }, { "id": "#40307", "title": "Oldest and Youngest", "fun": 2.46, "difficulty": 1.33, "author": "TRILLIONAIRE", "desc": "1. Kevin is older than Trevor but younger than Mike. Trevor is younger than Sam who is younger than Mike. Kevin is younger than Sam. Who is the oldest? \n\r\n2. Alyssa is younger than Ed but older than Harold. Bea is younger than Harold. Who is the second oldest? \n\r\n3. Malcolm is younger than John and Tina. Tina is older than Mike who is older than John. Who is the second youngest?", "hint": "No hint available.", "answer": "1. Mike\r\n2. Alyssa\r\n3. John", "category": "Logic", "date": "02/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n1. Kevin is older than Trevor but younger than Mike. Trevor is younger than Sam who is younger than Mike. Kevin is younger than Sam. Who is the oldest? \n\r\n2. Alyssa is younger than Ed but older than Harold. Bea is younger than Harold. Who is the second oldest? \n\r\n3. Malcolm is younger than John and Tina. Tina is older than Mike who is older than John. Who is the second youngest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Mike\r\n2. Alyssa\r\n3. John\n<|im_start|>answer\n1. Mike\r\n2. Alyssa\r\n3. John\n<|im_end|>" }, { "id": "#24725", "title": "Can You Find the Number?", "fun": 2.46, "difficulty": 2.79, "author": "Yoyobug02", "desc": "Can you find a five digit number that, if you place a 9 at the beginning to make a new number, is four times larger than if you place the 9 at the end instead?", "hint": "No hint available.", "answer": "23076: 923076 / 230769 = 4.", "category": "Math", "date": "07/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you find a five digit number that, if you place a 9 at the beginning to make a new number, is four times larger than if you place the 9 at the end instead?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n23076: 923076 / 230769 = 4.\n<|im_start|>answer\n23076: 923076 / 230769 = 4.\n<|im_end|>" }, { "id": "#2148", "title": "Four-Digit Number", "fun": 2.46, "difficulty": 1.31, "author": "missie", "desc": "What is the four-digit number in which the first digit is 1/3 the second, the third is the sum of the first and second, and the last is three times the second?", "hint": "No hint available.", "answer": "1349", "category": "Math", "date": "01/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the four-digit number in which the first digit is 1/3 the second, the third is the sum of the first and second, and the last is three times the second?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1349\n<|im_start|>answer\n1349\n<|im_end|>" }, { "id": "#15965", "title": "Candy Murder", "fun": 2.46, "difficulty": 2.67, "author": "doggyxp", "desc": "Detective Grant was inspecting the scene of the crime. The 50-year-old victim, Joe, had been poisoned by a candy containing cyanide. On the table surrounding him were 9 other candies, but none of them contained cyanide. This murder was highly suspicious, because Joe had just gotten off a 2-yr jail sentence. \r\nGrant was very puzzled, because he had recently come across three similar murders, none of which had been solved. Jeff, 30, had gotten off a 10-yr sentence a few weeks ago. The next day, he had been found murdered in the same fashion as Joe, but in his case only 3 candies were left on the table. John, 46, was found with 5 candies the day after a 4-yr sentence had been turned over a week ago. Jim, 35, had gotten off a 5-yr sentence a few days ago, only to be found dead with 6 candies yesterday. \r\nGrant puzzled over these cases for days, and then -boom- it hit him. There was a pattern in these murders! What pattern did Grant spot? \n\r\nEach suspect ate a candy before they died. \r\nLife expectancy when the murders were committed was 70 years. \n\r\n(It was also curious that many criminals had been let off their sentences too, but had not been killed. 23, in fact, had gotten off.)", "hint": "SUSPECT--AGE--SENTENCE--CANDIES\r\nJoe--------50----2 years-------9\r\nJeff--------30----10 yrs--------3\r\nJohn-------46----4 yrs---------5\r\nJim--------35----5 yrs----------6", "answer": "The killer was a prosecutor (George) who thought that the criminal deserved a chance to live outside of jail. When the case came before him, he dismissed it. He then went to the criminal's house, and offered him a chance to gamble his life, or go to jail. George offered him a certain number of candies, one of which was poisoned. If the criminal chose a poisoned candy, he died. If he chose a pure candy, he lived.\n\r\nThe criminal's remaining life expectancy divided by his prison sentence would be the number of candies George would bring him, one of which might kill him. In the case of Joe:\r\nHis remaining life expectancy at age 50 was 20. 20 divided by 2(his sentence) is 10. George brought him 10 candies, one of which was poisoned. Joe ate the poisoned one, and left nine on the table.\n\r\nThe 23 criminals who got off their sentences, but did not die, chose pure candies.", "category": "Math", "date": "12/29/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDetective Grant was inspecting the scene of the crime. The 50-year-old victim, Joe, had been poisoned by a candy containing cyanide. On the table surrounding him were 9 other candies, but none of them contained cyanide. This murder was highly suspicious, because Joe had just gotten off a 2-yr jail sentence. \r\nGrant was very puzzled, because he had recently come across three similar murders, none of which had been solved. Jeff, 30, had gotten off a 10-yr sentence a few weeks ago. The next day, he had been found murdered in the same fashion as Joe, but in his case only 3 candies were left on the table. John, 46, was found with 5 candies the day after a 4-yr sentence had been turned over a week ago. Jim, 35, had gotten off a 5-yr sentence a few days ago, only to be found dead with 6 candies yesterday. \r\nGrant puzzled over these cases for days, and then -boom- it hit him. There was a pattern in these murders! What pattern did Grant spot? \n\r\nEach suspect ate a candy before they died. \r\nLife expectancy when the murders were committed was 70 years. \n\r\n(It was also curious that many criminals had been let off their sentences too, but had not been killed. 23, in fact, had gotten off.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe killer was a prosecutor (George) who thought that the criminal deserved a chance to live outside of jail. When the case came before him, he dismissed it. He then went to the criminal's house, and offered him a chance to gamble his life, or go to jail. George offered him a certain number of candies, one of which was poisoned. If the criminal chose a poisoned candy, he died. If he chose a pure candy, he lived.\n\r\nThe criminal's remaining life expectancy divided by his prison sentence would be the number of candies George would bring him, one of which might kill him. In the case of Joe:\r\nHis remaining life expectancy at age 50 was 20. 20 divided by 2(his sentence) is 10. George brought him 10 candies, one of which was poisoned. Joe ate the poisoned one, and left nine on the table.\n\r\nThe 23 criminals who got off their sentences, but did not die, chose pure candies.\n<|im_start|>answer\nThe killer was a prosecutor (George) who thought that the criminal deserved a chance to live outside of jail. When the case came before him, he dismissed it. He then went to the criminal's house, and offered him a chance to gamble his life, or go to jail. George offered him a certain number of candies, one of which was poisoned. If the criminal chose a poisoned candy, he died. If he chose a pure candy, he lived.\n\r\nThe criminal's remaining life expectancy divided by his prison sentence would be the number of candies George would bring him, one of which might kill him. In the case of Joe:\r\nHis remaining life expectancy at age 50 was 20. 20 divided by 2(his sentence) is 10. George brought him 10 candies, one of which was poisoned. Joe ate the poisoned one, and left nine on the table.\n\r\nThe 23 criminals who got off their sentences, but did not die, chose pure candies.\n<|im_end|>" }, { "id": "#46899", "title": "Pizza Discount", "fun": 2.46, "difficulty": 1.8900000000000001, "author": "Yazmeen", "desc": "The 10\" pizza sells for $3.99 at my favorite pizza store. The store claims they have a great deal on the large 12\" pizza, which is specially priced at $ 4.31. What is the per cent discount the store is offering?", "hint": "No hint available.", "answer": "25\n\r\nThe small pizza has a diameter of 10\" and therefore an area proportional to 10^2 = 100. \n\r\nThe large pizza has a diameter of 12\" and therefore an area proportional to 12^2 = 144. \n\r\nIf the pizzas are priced according to their areas, then,\n\r\nPrice of large pizza / Price of small \r\npizza = (12 / 10)^2 = 1.44 \n\r\nNormal price of large pizza = 1.44 x $3.99 = $5.75. \n\r\nThus, discount on large pizza = [1 - ($4.31 / $5.75)] x 100 = 25%.", "category": "Math", "date": "05/02/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 10\" pizza sells for $3.99 at my favorite pizza store. The store claims they have a great deal on the large 12\" pizza, which is specially priced at $ 4.31. What is the per cent discount the store is offering?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n25\n\r\nThe small pizza has a diameter of 10\" and therefore an area proportional to 10^2 = 100. \n\r\nThe large pizza has a diameter of 12\" and therefore an area proportional to 12^2 = 144. \n\r\nIf the pizzas are priced according to their areas, then,\n\r\nPrice of large pizza / Price of small \r\npizza = (12 / 10)^2 = 1.44 \n\r\nNormal price of large pizza = 1.44 x $3.99 = $5.75. \n\r\nThus, discount on large pizza = [1 - ($4.31 / $5.75)] x 100 = 25%.\n<|im_start|>answer\n25\n\r\nThe small pizza has a diameter of 10\" and therefore an area proportional to 10^2 = 100. \n\r\nThe large pizza has a diameter of 12\" and therefore an area proportional to 12^2 = 144. \n\r\nIf the pizzas are priced according to their areas, then,\n\r\nPrice of large pizza / Price of small \r\npizza = (12 / 10)^2 = 1.44 \n\r\nNormal price of large pizza = 1.44 x $3.99 = $5.75. \n\r\nThus, discount on large pizza = [1 - ($4.31 / $5.75)] x 100 = 25%.\n<|im_end|>" }, { "id": "#35514", "title": "Opposites 26", "fun": 2.46, "difficulty": 2.47, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n@ stands for M, O, F, L, or V\r\n$ stands for B, N, R, E, or J\r\n% stands for T, F, B, L, or A\r\n! stands for W, T, S, E, or I \r\n# stands for F, O, A, T, or L \n\r\nThe five letter code word, %$#@!, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Above and Below", "category": "Logic", "date": "03/03/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n@ stands for M, O, F, L, or V\r\n$ stands for B, N, R, E, or J\r\n% stands for T, F, B, L, or A\r\n! stands for W, T, S, E, or I \r\n# stands for F, O, A, T, or L \n\r\nThe five letter code word, %$#@!, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbove and Below\n<|im_start|>answer\nAbove and Below\n<|im_end|>" }, { "id": "#5361", "title": "Obscure Oblong", "fun": 2.46, "difficulty": 1.81, "author": "Sir_Col", "desc": "A 4 by 4 square is unusual in that it is the only square, with integral (whole number) length sides, for which the area and perimeter are equal in value.\n\r\nFind the dimensions of the only oblong (non-square rectangle) with integral length sides, such that the area is equal to the perimeter in value.", "hint": "No hint available.", "answer": "3 by 6 (area=3x6=18, perimeter=3+6+3+6=18)", "category": "Math", "date": "07/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 4 by 4 square is unusual in that it is the only square, with integral (whole number) length sides, for which the area and perimeter are equal in value.\n\r\nFind the dimensions of the only oblong (non-square rectangle) with integral length sides, such that the area is equal to the perimeter in value.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 by 6 (area=3x6=18, perimeter=3+6+3+6=18)\n<|im_start|>answer\n3 by 6 (area=3x6=18, perimeter=3+6+3+6=18)\n<|im_end|>" }, { "id": "#1071", "title": "Peacocks and Pigs", "fun": 2.46, "difficulty": 1.48, "author": "Michelle", "desc": "There is a cage at the zoo that contains both peacocks and pigs. If there is a total of 30 eyes and 44 feet, how many of each are there in the cage?", "hint": "No hint available.", "answer": "7 pigs\r\n8 peacocks", "category": "Math", "date": "10/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a cage at the zoo that contains both peacocks and pigs. If there is a total of 30 eyes and 44 feet, how many of each are there in the cage?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 pigs\r\n8 peacocks\n<|im_start|>answer\n7 pigs\r\n8 peacocks\n<|im_end|>" }, { "id": "#31924", "title": "Opposites 23", "fun": 2.46, "difficulty": 2.62, "author": "Winner4600", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n@ stands for E, C, O, N, or A\r\n6 stands for L, E, P, W, or T\r\n& stands for E, S, B, R, or G\r\n^ stands for N, H, A, T, or K\n\r\nThe four letter code word, 6@&^, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "East and West.", "category": "Logic", "date": "07/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n@ stands for E, C, O, N, or A\r\n6 stands for L, E, P, W, or T\r\n& stands for E, S, B, R, or G\r\n^ stands for N, H, A, T, or K\n\r\nThe four letter code word, 6@&^, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEast and West.\n<|im_start|>answer\nEast and West.\n<|im_end|>" }, { "id": "#28107", "title": "Marbles", "fun": 2.46, "difficulty": 2.14, "author": "kiss", "desc": "You are filling various lengths of tubes with marbles. A yellow marble is 19 mm wide and a green marble is 21 mm wide. How many marbles of each color will exactly fill a tube that is 562 mm long?", "hint": "No hint available.", "answer": "13 yellow and 15 green marbles.\n\r\n13*19=247\r\n15*21=315\r\n247+315=562", "category": "Math", "date": "01/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are filling various lengths of tubes with marbles. A yellow marble is 19 mm wide and a green marble is 21 mm wide. How many marbles of each color will exactly fill a tube that is 562 mm long?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n13 yellow and 15 green marbles.\n\r\n13*19=247\r\n15*21=315\r\n247+315=562\n<|im_start|>answer\n13 yellow and 15 green marbles.\n\r\n13*19=247\r\n15*21=315\r\n247+315=562\n<|im_end|>" }, { "id": "#9355", "title": "Logic at the Movies", "fun": 2.46, "difficulty": 1.28, "author": "something", "desc": "In the Land of Sometana, there are two types of inhabitants, Goodies and Baddies. Baddies always lie and Goodies always tell the truth. Something was at a movie with Someone but wasn't sure whether she was a Baddie or Goodie. Something decided to test Someone by asking her to ask the usher whether he (the usher) was a Baddie or a Goodie. Someone said that the usher had said that he (the usher) was a Goodie. Can you work out if Someone is a Baddie or a Goodie?", "hint": "No hint available.", "answer": "Someone is a Goodie. The usher would always say that he was a Goodie, since a Goodie tells the truth, but the Baddie would lie and still say that they were a Goodie. It doesn't really matter what the usher said. Just that Someone correctly repeated what the usher said. Since Someone correctly said that the usher indicated that he (the usher) was a Goodie, Someone must be telling the truth and therefore is a Goodie.", "category": "Logic", "date": "12/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the Land of Sometana, there are two types of inhabitants, Goodies and Baddies. Baddies always lie and Goodies always tell the truth. Something was at a movie with Someone but wasn't sure whether she was a Baddie or Goodie. Something decided to test Someone by asking her to ask the usher whether he (the usher) was a Baddie or a Goodie. Someone said that the usher had said that he (the usher) was a Goodie. Can you work out if Someone is a Baddie or a Goodie?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSomeone is a Goodie. The usher would always say that he was a Goodie, since a Goodie tells the truth, but the Baddie would lie and still say that they were a Goodie. It doesn't really matter what the usher said. Just that Someone correctly repeated what the usher said. Since Someone correctly said that the usher indicated that he (the usher) was a Goodie, Someone must be telling the truth and therefore is a Goodie.\n<|im_start|>answer\nSomeone is a Goodie. The usher would always say that he was a Goodie, since a Goodie tells the truth, but the Baddie would lie and still say that they were a Goodie. It doesn't really matter what the usher said. Just that Someone correctly repeated what the usher said. Since Someone correctly said that the usher indicated that he (the usher) was a Goodie, Someone must be telling the truth and therefore is a Goodie.\n<|im_end|>" }, { "id": "#4603", "title": "0 1 2 3 4.......", "fun": 2.46, "difficulty": 1.65, "author": "rose_rox", "desc": "Put the appropriate + or - signs between the numbers, in the correct places, to make this equation true:\n\r\n0123456789=1", "hint": "0+1+2.........", "answer": "0+1+2+3+4-5+6+7-8-9=1", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPut the appropriate + or - signs between the numbers, in the correct places, to make this equation true:\n\r\n0123456789=1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0+1+2+3+4-5+6+7-8-9=1\n<|im_start|>answer\n0+1+2+3+4-5+6+7-8-9=1\n<|im_end|>" }, { "id": "#41495", "title": "Mystery Number 2", "fun": 2.46, "difficulty": 2.7, "author": "cnmne", "desc": "There is a ten-digit mystery number, represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) A * F = CE\r\n2) B * H = JI\r\n3) D * G = BH\r\n4) G * I = CF", "hint": "No hint available.", "answer": "5738069241\n\r\nA = 5, B = 7, C = 3, D = 8, E = 0, F = 6, G = 9, H = 2, I = 4, J = 1\n\r\n1) A * F = CE, 5 * 6 = 30\r\n2) B * H = JI, 7 * 2 = 14\r\n3) D * G = BH, 8 * 9 = 72\r\n4) G * I = CF, 9 * 4 = 36\n\r\nA) If a number has 5 as a units digit, then one of its factors must also have 5 as a units digit. Therefore, the following can not be 5: E, F, H, I.\r\nB) If any multiplier is 0, then the product is also 0. Therefore, the following can not be 0: A, B, D, F, G, H, I.\r\nC) If any multiplier is 1, then the product equals the other multiplier. Therefore, the following can not be 1: A, B, D, F, G, H, I.\r\nD) Through trial and error, it can be found that C and J can not be 0. Therefore, E = 0.\r\nE) To satisfy equation #1, A = 5 and F must be an even number and C must be 1 through 4.\r\nF) Through trial and error, it can be found that C can not be 1. Therefore, J = 1.\r\nG) Through trial and error, it can be found that C can not be 2 or 4. Therefore, C = 3, which results in F = 6, G = 9, and I = 4.\r\nH) To satisfy equation #2, B and H must 2 and 7 or 7 and 2. This results in D = 8.\r\nI) To satisfy equation #3, B = 7 and H = 2.", "category": "Logic", "date": "04/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten-digit mystery number, represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) A * F = CE\r\n2) B * H = JI\r\n3) D * G = BH\r\n4) G * I = CF\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5738069241\n\r\nA = 5, B = 7, C = 3, D = 8, E = 0, F = 6, G = 9, H = 2, I = 4, J = 1\n\r\n1) A * F = CE, 5 * 6 = 30\r\n2) B * H = JI, 7 * 2 = 14\r\n3) D * G = BH, 8 * 9 = 72\r\n4) G * I = CF, 9 * 4 = 36\n\r\nA) If a number has 5 as a units digit, then one of its factors must also have 5 as a units digit. Therefore, the following can not be 5: E, F, H, I.\r\nB) If any multiplier is 0, then the product is also 0. Therefore, the following can not be 0: A, B, D, F, G, H, I.\r\nC) If any multiplier is 1, then the product equals the other multiplier. Therefore, the following can not be 1: A, B, D, F, G, H, I.\r\nD) Through trial and error, it can be found that C and J can not be 0. Therefore, E = 0.\r\nE) To satisfy equation #1, A = 5 and F must be an even number and C must be 1 through 4.\r\nF) Through trial and error, it can be found that C can not be 1. Therefore, J = 1.\r\nG) Through trial and error, it can be found that C can not be 2 or 4. Therefore, C = 3, which results in F = 6, G = 9, and I = 4.\r\nH) To satisfy equation #2, B and H must 2 and 7 or 7 and 2. This results in D = 8.\r\nI) To satisfy equation #3, B = 7 and H = 2.\n<|im_start|>answer\n5738069241\n\r\nA = 5, B = 7, C = 3, D = 8, E = 0, F = 6, G = 9, H = 2, I = 4, J = 1\n\r\n1) A * F = CE, 5 * 6 = 30\r\n2) B * H = JI, 7 * 2 = 14\r\n3) D * G = BH, 8 * 9 = 72\r\n4) G * I = CF, 9 * 4 = 36\n\r\nA) If a number has 5 as a units digit, then one of its factors must also have 5 as a units digit. Therefore, the following can not be 5: E, F, H, I.\r\nB) If any multiplier is 0, then the product is also 0. Therefore, the following can not be 0: A, B, D, F, G, H, I.\r\nC) If any multiplier is 1, then the product equals the other multiplier. Therefore, the following can not be 1: A, B, D, F, G, H, I.\r\nD) Through trial and error, it can be found that C and J can not be 0. Therefore, E = 0.\r\nE) To satisfy equation #1, A = 5 and F must be an even number and C must be 1 through 4.\r\nF) Through trial and error, it can be found that C can not be 1. Therefore, J = 1.\r\nG) Through trial and error, it can be found that C can not be 2 or 4. Therefore, C = 3, which results in F = 6, G = 9, and I = 4.\r\nH) To satisfy equation #2, B and H must 2 and 7 or 7 and 2. This results in D = 8.\r\nI) To satisfy equation #3, B = 7 and H = 2.\n<|im_end|>" }, { "id": "#22735", "title": "Is it Fair", "fun": 2.46, "difficulty": 1.85, "author": "Tammy93", "desc": "At the fairground, Ben was watching a cup and balls trick. The stall owner had labeled the cups A-D. There was a total of four balls under the cups. The owner made the following claims:\n\r\n\"There is 1 ball under cup A, zero or 1 ball under B, 2 balls under C, and zero or 2 balls under D.\"\n\r\nIn reality, no cup had more than 2 balls underneath and exactly three of his four claims were lies. If we know that cup A had no balls underneath, how many balls did each cup have?", "hint": "No hint available.", "answer": "A=0\r\nB=2\r\nC=0\r\nD=2\n\r\nWe know that claim 1 is a lie because A has no balls under it.\n\r\nIf claim 3 is true, then C has 2 balls under it, which would mean that either B or D would have to have 2 balls under them, or they would each have 1 ball. This means that if claim 3 is true, then either claim 2 or claim 4 would also be true. Also, if C had 1 ball, then B has 1 and D has 2 which makes claims 1 and 4 true, or B has 2 and D has 1 which makes all claims lies. As only one claim is true, then this means that claim 3 must be false and C must have 0 balls.\n\r\nThis means that both B and D must have 2 balls, which means that claim 2 is a lie and claim 4 is true.", "category": "Logic", "date": "05/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the fairground, Ben was watching a cup and balls trick. The stall owner had labeled the cups A-D. There was a total of four balls under the cups. The owner made the following claims:\n\r\n\"There is 1 ball under cup A, zero or 1 ball under B, 2 balls under C, and zero or 2 balls under D.\"\n\r\nIn reality, no cup had more than 2 balls underneath and exactly three of his four claims were lies. If we know that cup A had no balls underneath, how many balls did each cup have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA=0\r\nB=2\r\nC=0\r\nD=2\n\r\nWe know that claim 1 is a lie because A has no balls under it.\n\r\nIf claim 3 is true, then C has 2 balls under it, which would mean that either B or D would have to have 2 balls under them, or they would each have 1 ball. This means that if claim 3 is true, then either claim 2 or claim 4 would also be true. Also, if C had 1 ball, then B has 1 and D has 2 which makes claims 1 and 4 true, or B has 2 and D has 1 which makes all claims lies. As only one claim is true, then this means that claim 3 must be false and C must have 0 balls.\n\r\nThis means that both B and D must have 2 balls, which means that claim 2 is a lie and claim 4 is true.\n<|im_start|>answer\nA=0\r\nB=2\r\nC=0\r\nD=2\n\r\nWe know that claim 1 is a lie because A has no balls under it.\n\r\nIf claim 3 is true, then C has 2 balls under it, which would mean that either B or D would have to have 2 balls under them, or they would each have 1 ball. This means that if claim 3 is true, then either claim 2 or claim 4 would also be true. Also, if C had 1 ball, then B has 1 and D has 2 which makes claims 1 and 4 true, or B has 2 and D has 1 which makes all claims lies. As only one claim is true, then this means that claim 3 must be false and C must have 0 balls.\n\r\nThis means that both B and D must have 2 balls, which means that claim 2 is a lie and claim 4 is true.\n<|im_end|>" }, { "id": "#41928", "title": "Second Youngest", "fun": 2.46, "difficulty": 1.0, "author": "Carlos16", "desc": "Ted is younger than Shelby, who is older than Sebastian.\r\nRoy is older than Diego.\r\nTed is older than Roy.\r\nSebastian is younger than Diego.\r\nWho is the second youngest?", "hint": "No hint available.", "answer": "The order from eldest to youngest is Shelby, Ted, Roy, Diego, and Sebastian.\n\r\nAnswer: Diego", "category": "Logic", "date": "05/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTed is younger than Shelby, who is older than Sebastian.\r\nRoy is older than Diego.\r\nTed is older than Roy.\r\nSebastian is younger than Diego.\r\nWho is the second youngest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe order from eldest to youngest is Shelby, Ted, Roy, Diego, and Sebastian.\n\r\nAnswer: Diego\n<|im_start|>answer\nThe order from eldest to youngest is Shelby, Ted, Roy, Diego, and Sebastian.\n\r\nAnswer: Diego\n<|im_end|>" }, { "id": "#11969", "title": "Dominoes", "fun": 2.45, "difficulty": 1.98, "author": "Mhalun", "desc": "Two diagonally opposite corner squares are removed from a chess board (in other words, the upper left-most square and the lower right-most square are cut out).\n\r\nCan the board still be completely covered by dominoes that measure 2 squares by 1 square (each domino covers two adjacent squares on the board)?\n\r\nNo domino is allowed to hang over the edge of the board, and dominoes aren't allowed to cover each other.", "hint": "Colors give it away!", "answer": "No it can't. Each domino covers a black square in the board and a white one (colors vary), if you take the corners you'll eliminate either 2 whites or 2 blacks so there will be 32 of one color and 30 of the other, hence you'll have 2 squares of the same color left. Try it!", "category": "Logic", "date": "04/22/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo diagonally opposite corner squares are removed from a chess board (in other words, the upper left-most square and the lower right-most square are cut out).\n\r\nCan the board still be completely covered by dominoes that measure 2 squares by 1 square (each domino covers two adjacent squares on the board)?\n\r\nNo domino is allowed to hang over the edge of the board, and dominoes aren't allowed to cover each other.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo it can't. Each domino covers a black square in the board and a white one (colors vary), if you take the corners you'll eliminate either 2 whites or 2 blacks so there will be 32 of one color and 30 of the other, hence you'll have 2 squares of the same color left. Try it!\n<|im_start|>answer\nNo it can't. Each domino covers a black square in the board and a white one (colors vary), if you take the corners you'll eliminate either 2 whites or 2 blacks so there will be 32 of one color and 30 of the other, hence you'll have 2 squares of the same color left. Try it!\n<|im_end|>" }, { "id": "#45418", "title": "Mr. and Mrs. Crazy: Concert Income", "fun": 2.45, "difficulty": 2.0, "author": "CaIceDevil", "desc": "Mr. and Mrs. Crazy recently had their concert, and they want to know how much their total income was. After calculating that they earned $95, they figured out that 100 people attended their concert. If each child paid 50 cents, each pensioner paid $2.50, and adults paid $10 each, how many children, pensioners, and adults went to the concert?", "hint": "No hint available.", "answer": "There were 85 children, 13 pensioners, and 2 adults.", "category": "Math", "date": "10/03/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. and Mrs. Crazy recently had their concert, and they want to know how much their total income was. After calculating that they earned $95, they figured out that 100 people attended their concert. If each child paid 50 cents, each pensioner paid $2.50, and adults paid $10 each, how many children, pensioners, and adults went to the concert?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 85 children, 13 pensioners, and 2 adults.\n<|im_start|>answer\nThere were 85 children, 13 pensioners, and 2 adults.\n<|im_end|>" }, { "id": "#3090", "title": "Something in His Pocket", "fun": 2.45, "difficulty": 1.15, "author": "204_blaze_41", "desc": "While on safari in the wild jungles of Africa, Professor Noki woke up one morning and felt something in the pocket of his shorts. It had a head and tail, but no legs. When Noki got up he could feel it move inside his pocket. Noki, however, showed little concern and went about his morning rituals. Why such a casual attitude?", "hint": "No hint available.", "answer": "It was only a coin in his pocket.", "category": "Logic", "date": "04/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile on safari in the wild jungles of Africa, Professor Noki woke up one morning and felt something in the pocket of his shorts. It had a head and tail, but no legs. When Noki got up he could feel it move inside his pocket. Noki, however, showed little concern and went about his morning rituals. Why such a casual attitude?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt was only a coin in his pocket.\n<|im_start|>answer\nIt was only a coin in his pocket.\n<|im_end|>" }, { "id": "#4418", "title": "Scotland to Dover", "fun": 2.45, "difficulty": 1.07, "author": "mad-ade", "desc": "A train was leaving Scotland and heading for Dover at the same time as a Mercedes. Mad Ade, who is the owner of the Mercedes, was unaware that both of the front tires had slow punctures, and by the time the car arrived in London those tires were already completely flat. Although Mad Ade did not change or have the tires repaired, the Mercedes reached Dover at the same time as the train. \n\r\nHow could this be?", "hint": "No hint available.", "answer": "Mad Ade's Mercedes was loaded on the train, as freight.", "category": "Logic", "date": "06/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA train was leaving Scotland and heading for Dover at the same time as a Mercedes. Mad Ade, who is the owner of the Mercedes, was unaware that both of the front tires had slow punctures, and by the time the car arrived in London those tires were already completely flat. Although Mad Ade did not change or have the tires repaired, the Mercedes reached Dover at the same time as the train. \n\r\nHow could this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade's Mercedes was loaded on the train, as freight.\n<|im_start|>answer\nMad Ade's Mercedes was loaded on the train, as freight.\n<|im_end|>" }, { "id": "#2460", "title": "Cake Eating", "fun": 2.45, "difficulty": 1.11, "author": "missie", "desc": "Samantha and Suzy were squabbling over a small cake. Their mother solved the question of which one should cut it, as well as the problem of how to make sure the pieces were even, in a very simple manner. No one could complain. What was her solution?", "hint": "No hint available.", "answer": "One child got to cut the cake in half and the other got first pick.", "category": "Logic", "date": "02/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSamantha and Suzy were squabbling over a small cake. Their mother solved the question of which one should cut it, as well as the problem of how to make sure the pieces were even, in a very simple manner. No one could complain. What was her solution?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne child got to cut the cake in half and the other got first pick.\n<|im_start|>answer\nOne child got to cut the cake in half and the other got first pick.\n<|im_end|>" }, { "id": "#29067", "title": "Seconds in a Week", "fun": 2.45, "difficulty": 1.45, "author": "lips", "desc": "Which is larger, the number of seconds in a week or the number of minutes in a year?", "hint": "No hint available.", "answer": "The number of seconds in a week is larger.\n\r\nThere are 604,800 seconds in a week, and 525,600 minutes in a calendar year. \n\r\nNote: There are 525,960 minutes in a leap year, which is still less than the number of seconds in a week.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is larger, the number of seconds in a week or the number of minutes in a year?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number of seconds in a week is larger.\n\r\nThere are 604,800 seconds in a week, and 525,600 minutes in a calendar year. \n\r\nNote: There are 525,960 minutes in a leap year, which is still less than the number of seconds in a week.\n<|im_start|>answer\nThe number of seconds in a week is larger.\n\r\nThere are 604,800 seconds in a week, and 525,600 minutes in a calendar year. \n\r\nNote: There are 525,960 minutes in a leap year, which is still less than the number of seconds in a week.\n<|im_end|>" }, { "id": "#12554", "title": "Empty Pet Store", "fun": 2.45, "difficulty": 1.18, "author": "NEWF", "desc": "Last week seven gerbils, four budgies, three iguanas, a parrot and five goldfish escaped from the pet store.\r\nOn each of the two following days, half of the loose pets were recaptured.\r\nHow many animals were still free at the end of the second day?", "hint": "No hint available.", "answer": "Five animals were still free at the end of the second day. Twenty animals escaped. On the first day ten were captured. On the second day half of these (five) were captured, leaving five free.", "category": "Math", "date": "05/22/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast week seven gerbils, four budgies, three iguanas, a parrot and five goldfish escaped from the pet store.\r\nOn each of the two following days, half of the loose pets were recaptured.\r\nHow many animals were still free at the end of the second day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFive animals were still free at the end of the second day. Twenty animals escaped. On the first day ten were captured. On the second day half of these (five) were captured, leaving five free.\n<|im_start|>answer\nFive animals were still free at the end of the second day. Twenty animals escaped. On the first day ten were captured. On the second day half of these (five) were captured, leaving five free.\n<|im_end|>" }, { "id": "#23143", "title": "Classes For The Ages", "fun": 2.45, "difficulty": 0.65, "author": "DennysGirl", "desc": "Four teachers teach four different classes. Can you figure out which teachers teach which class, and how long they've been teaching that class?\n\r\nClues:\n\r\n1. Mr. Bein collects art, but doesn't teach the class.\r\n2. Ms. Burger has been teaching for more than 5 years.\r\n3. The teachers are: Mr. Stein, the Art teacher, the English teacher, and Mr. Bein.\r\n4. Mr. Stein confuses his students everyday with his long explanations and calculations.\r\n5. The English teacher has been teaching for 2 years.\r\n6. Mr. Stein and Ms. Nova started working one year apart from each other.", "hint": "No hint available.", "answer": "1. Mr. Bein collects art, but doesn't teach the class. (Therefore, Mr. Bein is not the Art teacher.)\r\n2. Ms. Burger has been teaching for more than 5 years. (Which means she had been working for 8 years, the only choice higher than 5.)\r\n3. The teachers are: Mr. Stein, the Art teacher, the English teacher, and Mr. Bein. (Neither Mr. Stein nor Mr. Bein is the Art teacher or the English teacher.)\r\n4. Mr. Stein confuses his students everyday with his long explanations and calculations. (Which Math teachers usually do. So Mr Stein is the Math teacher and Mr. Bein is the History teacher.)\r\n5. The English teacher has been teaching for 2 years. (Ms. Burger is not the English teacher, but the Art teacher. Ms. Nova is the English teacher.)\r\n6. Mr. Stein and Ms. Nova started working one year apart from each other. (Ms. Nova, the English teacher, has been teaching for 2 years, so Mr. Stein has been working for 1 year, and Mr. Bein for 5.)\n\r\nMr. Stein/Math/1 year\r\nMs. Nova/English/2 years\r\nMr. Bein/History/5 years\r\nMs. Burger/Art/8 years", "category": "Logic-Grid", "date": "05/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour teachers teach four different classes. Can you figure out which teachers teach which class, and how long they've been teaching that class?\n\r\nClues:\n\r\n1. Mr. Bein collects art, but doesn't teach the class.\r\n2. Ms. Burger has been teaching for more than 5 years.\r\n3. The teachers are: Mr. Stein, the Art teacher, the English teacher, and Mr. Bein.\r\n4. Mr. Stein confuses his students everyday with his long explanations and calculations.\r\n5. The English teacher has been teaching for 2 years.\r\n6. Mr. Stein and Ms. Nova started working one year apart from each other.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Mr. Bein collects art, but doesn't teach the class. (Therefore, Mr. Bein is not the Art teacher.)\r\n2. Ms. Burger has been teaching for more than 5 years. (Which means she had been working for 8 years, the only choice higher than 5.)\r\n3. The teachers are: Mr. Stein, the Art teacher, the English teacher, and Mr. Bein. (Neither Mr. Stein nor Mr. Bein is the Art teacher or the English teacher.)\r\n4. Mr. Stein confuses his students everyday with his long explanations and calculations. (Which Math teachers usually do. So Mr Stein is the Math teacher and Mr. Bein is the History teacher.)\r\n5. The English teacher has been teaching for 2 years. (Ms. Burger is not the English teacher, but the Art teacher. Ms. Nova is the English teacher.)\r\n6. Mr. Stein and Ms. Nova started working one year apart from each other. (Ms. Nova, the English teacher, has been teaching for 2 years, so Mr. Stein has been working for 1 year, and Mr. Bein for 5.)\n\r\nMr. Stein/Math/1 year\r\nMs. Nova/English/2 years\r\nMr. Bein/History/5 years\r\nMs. Burger/Art/8 years\n<|im_start|>answer\n1. Mr. Bein collects art, but doesn't teach the class. (Therefore, Mr. Bein is not the Art teacher.)\r\n2. Ms. Burger has been teaching for more than 5 years. (Which means she had been working for 8 years, the only choice higher than 5.)\r\n3. The teachers are: Mr. Stein, the Art teacher, the English teacher, and Mr. Bein. (Neither Mr. Stein nor Mr. Bein is the Art teacher or the English teacher.)\r\n4. Mr. Stein confuses his students everyday with his long explanations and calculations. (Which Math teachers usually do. So Mr Stein is the Math teacher and Mr. Bein is the History teacher.)\r\n5. The English teacher has been teaching for 2 years. (Ms. Burger is not the English teacher, but the Art teacher. Ms. Nova is the English teacher.)\r\n6. Mr. Stein and Ms. Nova started working one year apart from each other. (Ms. Nova, the English teacher, has been teaching for 2 years, so Mr. Stein has been working for 1 year, and Mr. Bein for 5.)\n\r\nMr. Stein/Math/1 year\r\nMs. Nova/English/2 years\r\nMr. Bein/History/5 years\r\nMs. Burger/Art/8 years\n<|im_end|>" }, { "id": "#22918", "title": "Picture Mishap", "fun": 2.45, "difficulty": 1.29, "author": "andrewcs", "desc": "After several people had their picture taken at a photography studio, the photographer then realized that all the pictures were coming out inverted horizontally. What was on the left was now on the right. The customers said that the pictures looked fine, and bought them anyway.\n\r\nWhy could the customers not see the mistake?", "hint": "It made a mirror image.", "answer": "Most people only see themselves when looking in a mirror, and a mirror also inverts horizontally. So, people will recognize the opposite of their face.", "category": "Logic", "date": "05/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter several people had their picture taken at a photography studio, the photographer then realized that all the pictures were coming out inverted horizontally. What was on the left was now on the right. The customers said that the pictures looked fine, and bought them anyway.\n\r\nWhy could the customers not see the mistake?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMost people only see themselves when looking in a mirror, and a mirror also inverts horizontally. So, people will recognize the opposite of their face.\n<|im_start|>answer\nMost people only see themselves when looking in a mirror, and a mirror also inverts horizontally. So, people will recognize the opposite of their face.\n<|im_end|>" }, { "id": "#7558", "title": "Squares", "fun": 2.45, "difficulty": 2.57, "author": "rickey", "desc": "The square of one whole number minus the square of another whole number equals 73.\r\nWhat are the two numbers? This can be done by trial and error but a little mathematical knowledge and maybe some algebra will get the answer fast.", "hint": "73 is similar 41,29,19 etc.", "answer": "The two numbers are 37 & 36. Therefore (37x37)1369 minus (36x36)1296 = 73. The number 73 is a \"prime\" number i.e. the only two multiples for it are \"73\" & \"1\". By algebra, x2-y2 = 73 which is (x+y)(x-y)=73. One of those two numbers must be \"1\". It can't be x+y (that would be more than \"1\") so it must be x-y=1. By simple substitution the answer is revealed.", "category": "Math", "date": "09/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe square of one whole number minus the square of another whole number equals 73.\r\nWhat are the two numbers? This can be done by trial and error but a little mathematical knowledge and maybe some algebra will get the answer fast.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two numbers are 37 & 36. Therefore (37x37)1369 minus (36x36)1296 = 73. The number 73 is a \"prime\" number i.e. the only two multiples for it are \"73\" & \"1\". By algebra, x2-y2 = 73 which is (x+y)(x-y)=73. One of those two numbers must be \"1\". It can't be x+y (that would be more than \"1\") so it must be x-y=1. By simple substitution the answer is revealed.\n<|im_start|>answer\nThe two numbers are 37 & 36. Therefore (37x37)1369 minus (36x36)1296 = 73. The number 73 is a \"prime\" number i.e. the only two multiples for it are \"73\" & \"1\". By algebra, x2-y2 = 73 which is (x+y)(x-y)=73. One of those two numbers must be \"1\". It can't be x+y (that would be more than \"1\") so it must be x-y=1. By simple substitution the answer is revealed.\n<|im_end|>" }, { "id": "#30547", "title": "Opposites 19", "fun": 2.45, "difficulty": 2.23, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n% stands for E, H, M, I, or N\r\n* stands for W, Q, P, D, or R\r\n@ stands for N, U, D, P, or T\r\n! stands for O, E, I, W, or R\r\n# stands for Y, B, S, T, or N\n\r\nThe five letter code word, !@#%*, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Inner and Outer", "category": "Logic", "date": "05/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n% stands for E, H, M, I, or N\r\n* stands for W, Q, P, D, or R\r\n@ stands for N, U, D, P, or T\r\n! stands for O, E, I, W, or R\r\n# stands for Y, B, S, T, or N\n\r\nThe five letter code word, !@#%*, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nInner and Outer\n<|im_start|>answer\nInner and Outer\n<|im_end|>" }, { "id": "#22719", "title": "Star of David", "fun": 2.45, "difficulty": 2.58, "author": "cnmne", "desc": "The Star of David (the star on the flag of Israel) has two superimposed equilateral triangles which produce six line segments and twelve segment intersections. Using this star as a template, arrange the numbers 1 through 12, placing them at the twelve intersections, such that the four numbers on each line segment produce a sum of 26. There is more than one solution.", "hint": "No hint available.", "answer": "One possible solution (starting at the top point and going clockwise around the perimeter): 2, 6, 5, 11, 7, 1, 9, 10, 8, 4, 3, 12. This produces segments of: 2 + 6 + 11 + 7, 5 + 11 + 1 + 9, 7 + 1 + 10 + 8, 9 + 10 + 4 + 3, 8 + 4 + 12 + 2, 3 + 12 + 6 + 5.", "category": "Math", "date": "05/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Star of David (the star on the flag of Israel) has two superimposed equilateral triangles which produce six line segments and twelve segment intersections. Using this star as a template, arrange the numbers 1 through 12, placing them at the twelve intersections, such that the four numbers on each line segment produce a sum of 26. There is more than one solution.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne possible solution (starting at the top point and going clockwise around the perimeter): 2, 6, 5, 11, 7, 1, 9, 10, 8, 4, 3, 12. This produces segments of: 2 + 6 + 11 + 7, 5 + 11 + 1 + 9, 7 + 1 + 10 + 8, 9 + 10 + 4 + 3, 8 + 4 + 12 + 2, 3 + 12 + 6 + 5.\n<|im_start|>answer\nOne possible solution (starting at the top point and going clockwise around the perimeter): 2, 6, 5, 11, 7, 1, 9, 10, 8, 4, 3, 12. This produces segments of: 2 + 6 + 11 + 7, 5 + 11 + 1 + 9, 7 + 1 + 10 + 8, 9 + 10 + 4 + 3, 8 + 4 + 12 + 2, 3 + 12 + 6 + 5.\n<|im_end|>" }, { "id": "#31531", "title": "Least Positive Difference", "fun": 2.45, "difficulty": 2.3, "author": "holly1447591", "desc": "Use the numbers 7, 3, 5, 0, 8, 1, 4, and 6 to fill in the expression xxxx-xxxx. You may use each number only once.\n\r\nHow can you arrange the numbers to get the least positive difference?", "hint": "The way you choose digits for the thousands place may be different from the way you choose the other digits.", "answer": "5013 - 4876 = 137", "category": "Math", "date": "07/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUse the numbers 7, 3, 5, 0, 8, 1, 4, and 6 to fill in the expression xxxx-xxxx. You may use each number only once.\n\r\nHow can you arrange the numbers to get the least positive difference?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5013 - 4876 = 137\n<|im_start|>answer\n5013 - 4876 = 137\n<|im_end|>" }, { "id": "#3142", "title": "Uncle's Fortune", "fun": 2.45, "difficulty": 1.39, "author": "204_blaze_41", "desc": "Shadow slipped on the wet grass as he crossed the lawn to meet Anton Smith on the front porch. When Anton unlocked the front door, Shadow went to the kitchen to wash the grass and mud from his hands. He turned on the hot water tap and immediately received a stream of hot water. After washing he met Anton in the study. Anton crossed the room and excitedly opened the sealed envelope containing the safe's combination. He opened the safe and read the will. It read that as long as his deceased uncle's wishes were complied with, Anton would be entitled to the fortune. \"As you know\", said Shadow, \"your uncle requested that nobody be allowed to enter this house until they do so with me three days after his death. Since you have the only key, I'm afraid you just lost your uncle's fortune\". Why?", "hint": "No hint available.", "answer": "Anton had been in the house. When Shadow turned on the hot water tap, he immediately received a jet of hot water. It would take a short time for the water from the water heater to reach the faucet if the tap has not been recently used.", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nShadow slipped on the wet grass as he crossed the lawn to meet Anton Smith on the front porch. When Anton unlocked the front door, Shadow went to the kitchen to wash the grass and mud from his hands. He turned on the hot water tap and immediately received a stream of hot water. After washing he met Anton in the study. Anton crossed the room and excitedly opened the sealed envelope containing the safe's combination. He opened the safe and read the will. It read that as long as his deceased uncle's wishes were complied with, Anton would be entitled to the fortune. \"As you know\", said Shadow, \"your uncle requested that nobody be allowed to enter this house until they do so with me three days after his death. Since you have the only key, I'm afraid you just lost your uncle's fortune\". Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnton had been in the house. When Shadow turned on the hot water tap, he immediately received a jet of hot water. It would take a short time for the water from the water heater to reach the faucet if the tap has not been recently used.\n<|im_start|>answer\nAnton had been in the house. When Shadow turned on the hot water tap, he immediately received a jet of hot water. It would take a short time for the water from the water heater to reach the faucet if the tap has not been recently used.\n<|im_end|>" }, { "id": "#25631", "title": "Number?", "fun": 2.45, "difficulty": 1.32, "author": "Kerchiebod", "desc": "Find a number whose double exceeds its half by exactly 99.", "hint": "No hint available.", "answer": "66.", "category": "Math", "date": "08/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind a number whose double exceeds its half by exactly 99.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n66.\n<|im_start|>answer\n66.\n<|im_end|>" }, { "id": "#45394", "title": "I am a Seven Digit Number", "fun": 2.45, "difficulty": 2.11, "author": "Lord_Hawk", "desc": "I am a seven digit number. All of my digits are distinct and non-zero. The sum of all my digits is 29. My first digit is 2, and my last is 6. No two consecutive digits are even, no two consecutive digits are odd, and no two consecutive digits are prime.\r\nThe number also follows another interesting pattern - starting from the first digit, if the second digit is higher, then the third will be lower than the second, and the fourth higher than the third, and so on alternately. This pattern can also be inverted.\n\r\nWhat am I?", "hint": "Which digits can add up to 29? Then consider the rules and work from digit to digit.\r\nRemember that 1 is not a prime - it is a cardinal number.", "answer": "2143856", "category": "Math", "date": "09/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a seven digit number. All of my digits are distinct and non-zero. The sum of all my digits is 29. My first digit is 2, and my last is 6. No two consecutive digits are even, no two consecutive digits are odd, and no two consecutive digits are prime.\r\nThe number also follows another interesting pattern - starting from the first digit, if the second digit is higher, then the third will be lower than the second, and the fourth higher than the third, and so on alternately. This pattern can also be inverted.\n\r\nWhat am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2143856\n<|im_start|>answer\n2143856\n<|im_end|>" }, { "id": "#29280", "title": "The Five Digit Number", "fun": 2.45, "difficulty": 2.09, "author": "Desired", "desc": "Can you find a five digit number which has no zeros and no repeated digits, where: \n\r\nThe first digit is a prime number.\r\nThe second digit is the fifth digit minus the first digit.\r\nThe third digit is twice the first digit.\r\nThe fourth digit is the third digit plus three.\r\nThe fifth digit is the difference between the first digit and the fourth digit.", "hint": "No hint available.", "answer": "23475", "category": "Math", "date": "03/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you find a five digit number which has no zeros and no repeated digits, where: \n\r\nThe first digit is a prime number.\r\nThe second digit is the fifth digit minus the first digit.\r\nThe third digit is twice the first digit.\r\nThe fourth digit is the third digit plus three.\r\nThe fifth digit is the difference between the first digit and the fourth digit.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n23475\n<|im_start|>answer\n23475\n<|im_end|>" }, { "id": "#40513", "title": "Four People", "fun": 2.45, "difficulty": 1.24, "author": "Carlos16", "desc": "Four people are suspected of stealing a diamond from a museum. If one of each person's statements is true and one is false, who is the thief?\n\r\nBo said: It was Bo. It wasn't Roman. \r\nRoman said: It was Kate. It wasn't Bo. \r\nJohn said: It was Roman. It wasn't Kate. \r\nKate said: It was John. It was Bo.", "hint": "No hint available.", "answer": "Since one of each person's statements are true, the thief was either John or Bo, since Kate accused both of them. If Roman was lying when he said it wasn't Bo, he must have been telling the truth when he said it was Kate. Since it can't be Bo and Kate, it can only be John.\n\r\nAnswer: John", "category": "Logic", "date": "02/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people are suspected of stealing a diamond from a museum. If one of each person's statements is true and one is false, who is the thief?\n\r\nBo said: It was Bo. It wasn't Roman. \r\nRoman said: It was Kate. It wasn't Bo. \r\nJohn said: It was Roman. It wasn't Kate. \r\nKate said: It was John. It was Bo.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince one of each person's statements are true, the thief was either John or Bo, since Kate accused both of them. If Roman was lying when he said it wasn't Bo, he must have been telling the truth when he said it was Kate. Since it can't be Bo and Kate, it can only be John.\n\r\nAnswer: John\n<|im_start|>answer\nSince one of each person's statements are true, the thief was either John or Bo, since Kate accused both of them. If Roman was lying when he said it wasn't Bo, he must have been telling the truth when he said it was Kate. Since it can't be Bo and Kate, it can only be John.\n\r\nAnswer: John\n<|im_end|>" }, { "id": "#5014", "title": "Joe Schmo in Kalamazoo", "fun": 2.45, "difficulty": 1.82, "author": "im_para_noid", "desc": "Joe Schmo has an appointment in Kalamazoo at 2:00 pm. If he leaves home and travels at 15 miles per hour, he will arrive at 1:00 pm; if he travels at 10 miles per hour, he will not arrive until 3:00 pm. How far is it from his home to his appointment in Kalamazoo?", "hint": "No hint available.", "answer": "60 miles. This requires some basic algebra and use of the formula distance = rate x time. Let the distance in question be d, and let t be the time it takes to travel distance d at 15 mph. Then the time it takes to travel distance d at 10 mph will be t + 2 hours. So we have the two equations:\r\nd=15t and d=10(t+2)\r\nSo therefore 15t = 10(t+2)\r\nwhich with a little manipulation gives t = 4.\r\nSince d=15t we get distance d = 60 miles.", "category": "Math", "date": "06/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe Schmo has an appointment in Kalamazoo at 2:00 pm. If he leaves home and travels at 15 miles per hour, he will arrive at 1:00 pm; if he travels at 10 miles per hour, he will not arrive until 3:00 pm. How far is it from his home to his appointment in Kalamazoo?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n60 miles. This requires some basic algebra and use of the formula distance = rate x time. Let the distance in question be d, and let t be the time it takes to travel distance d at 15 mph. Then the time it takes to travel distance d at 10 mph will be t + 2 hours. So we have the two equations:\r\nd=15t and d=10(t+2)\r\nSo therefore 15t = 10(t+2)\r\nwhich with a little manipulation gives t = 4.\r\nSince d=15t we get distance d = 60 miles.\n<|im_start|>answer\n60 miles. This requires some basic algebra and use of the formula distance = rate x time. Let the distance in question be d, and let t be the time it takes to travel distance d at 15 mph. Then the time it takes to travel distance d at 10 mph will be t + 2 hours. So we have the two equations:\r\nd=15t and d=10(t+2)\r\nSo therefore 15t = 10(t+2)\r\nwhich with a little manipulation gives t = 4.\r\nSince d=15t we get distance d = 60 miles.\n<|im_end|>" }, { "id": "#47033", "title": "Prison Break", "fun": 2.45, "difficulty": 1.18, "author": "seanthema", "desc": "Joe is trying to run away from the police. He runs at an average of 5 miles per hour. But, sadly, the police cars go at 15 miles an hour. The sewer, which will lead him to freedom, is 20 miles away.\n\r\nHow far is Joe from the police, assuming that when he reaches the sewer, they will have just caught up with him?", "hint": "Think of the sewer as point 0 on a number line.", "answer": "He is 40 miles away. Assuming that the sewer is 0, when he is 5 miles away, the police are 15 miles, keep doing this until he gets to the distance he is from the sewer now, which is 20 miles away. You should see that the police are 60 miles away from the sewer.", "category": "Math", "date": "05/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe is trying to run away from the police. He runs at an average of 5 miles per hour. But, sadly, the police cars go at 15 miles an hour. The sewer, which will lead him to freedom, is 20 miles away.\n\r\nHow far is Joe from the police, assuming that when he reaches the sewer, they will have just caught up with him?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe is 40 miles away. Assuming that the sewer is 0, when he is 5 miles away, the police are 15 miles, keep doing this until he gets to the distance he is from the sewer now, which is 20 miles away. You should see that the police are 60 miles away from the sewer.\n<|im_start|>answer\nHe is 40 miles away. Assuming that the sewer is 0, when he is 5 miles away, the police are 15 miles, keep doing this until he gets to the distance he is from the sewer now, which is 20 miles away. You should see that the police are 60 miles away from the sewer.\n<|im_end|>" }, { "id": "#39852", "title": "Walter and Grandmother", "fun": 2.45, "difficulty": 2.02, "author": "shenqiang", "desc": "At the end of 2005 Walter was half as old as his grandmother. The sum of the years in which they were born is 3860. How old will Walter be at the end of 2006?", "hint": "No hint available.", "answer": "The sum of the ages of Walter and his grandmother at the end of 2005 is 2*2005-3860=150. Since Walter was half as old as his grandmother, Walter was 50 and his grandmother was 100. Therefore, Walter will be 51 at the end of 2006.", "category": "Math", "date": "12/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the end of 2005 Walter was half as old as his grandmother. The sum of the years in which they were born is 3860. How old will Walter be at the end of 2006?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe sum of the ages of Walter and his grandmother at the end of 2005 is 2*2005-3860=150. Since Walter was half as old as his grandmother, Walter was 50 and his grandmother was 100. Therefore, Walter will be 51 at the end of 2006.\n<|im_start|>answer\nThe sum of the ages of Walter and his grandmother at the end of 2005 is 2*2005-3860=150. Since Walter was half as old as his grandmother, Walter was 50 and his grandmother was 100. Therefore, Walter will be 51 at the end of 2006.\n<|im_end|>" }, { "id": "#28471", "title": "Swaffs, Cools, Swells, and Dudes", "fun": 2.45, "difficulty": 1.26, "author": "bigSWAFF_69_", "desc": "If all Swaffs are Cools, all Cools are Swells, and all Swells are Dudes, then is it safe to say all Dudes are Swaffs?", "hint": "No hint available.", "answer": "No.\n\r\nAll Swaffs would be Dudes, but not necessarily the other way around.", "category": "Logic", "date": "02/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf all Swaffs are Cools, all Cools are Swells, and all Swells are Dudes, then is it safe to say all Dudes are Swaffs?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo.\n\r\nAll Swaffs would be Dudes, but not necessarily the other way around.\n<|im_start|>answer\nNo.\n\r\nAll Swaffs would be Dudes, but not necessarily the other way around.\n<|im_end|>" }, { "id": "#14684", "title": "What Day?", "fun": 2.45, "difficulty": 1.8900000000000001, "author": "mathemagician", "desc": "If today is four days before the day immediately before two days after Wednesday, WHAT DAY comes immediately before the day that is two days after the day immediately after the day which comes two days before the day which comes three days after the day before yesterday?", "hint": "Determine what \"Today\" is, then work backwards until you determine the day in question.", "answer": "MONDAY. \n\r\n\"Today\" is Sunday . \n\r\nNow, starting at Sunday and working backwards (from \"the day before yesterday\"), we have the following: \n\r\n- 2 + 3 -2 + 1 + 2 - 1 \n\r\nSo, we go from Sunday to Fri. to Mon. to Sat. to Sun. to Tues. to MONDAY.", "category": "Logic", "date": "09/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf today is four days before the day immediately before two days after Wednesday, WHAT DAY comes immediately before the day that is two days after the day immediately after the day which comes two days before the day which comes three days after the day before yesterday?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMONDAY. \n\r\n\"Today\" is Sunday . \n\r\nNow, starting at Sunday and working backwards (from \"the day before yesterday\"), we have the following: \n\r\n- 2 + 3 -2 + 1 + 2 - 1 \n\r\nSo, we go from Sunday to Fri. to Mon. to Sat. to Sun. to Tues. to MONDAY.\n<|im_start|>answer\nMONDAY. \n\r\n\"Today\" is Sunday . \n\r\nNow, starting at Sunday and working backwards (from \"the day before yesterday\"), we have the following: \n\r\n- 2 + 3 -2 + 1 + 2 - 1 \n\r\nSo, we go from Sunday to Fri. to Mon. to Sat. to Sun. to Tues. to MONDAY.\n<|im_end|>" }, { "id": "#2077", "title": "12 Days of Christmas", "fun": 2.45, "difficulty": 1.86, "author": "ChemicalBoy08", "desc": "How many gifts, in total, did I receive during the Twelve Days of Christmas - according to the song?", "hint": "No hint available.", "answer": "364; for example, on the fifth day of Christmas, my true love gave to me: five gold rings + four calling birds + three French hens + two turtle doves + a partridge in a pear tree.", "category": "Math", "date": "01/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many gifts, in total, did I receive during the Twelve Days of Christmas - according to the song?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n364; for example, on the fifth day of Christmas, my true love gave to me: five gold rings + four calling birds + three French hens + two turtle doves + a partridge in a pear tree.\n<|im_start|>answer\n364; for example, on the fifth day of Christmas, my true love gave to me: five gold rings + four calling birds + three French hens + two turtle doves + a partridge in a pear tree.\n<|im_end|>" }, { "id": "#2673", "title": "The Browns", "fun": 2.45, "difficulty": 1.07, "author": "missie", "desc": "Mr. and Mrs. Brown have four daughters, who each have a husband, two brothers, and two sons. Can all the Browns fit into a 4 seater car?", "hint": "No hint available.", "answer": "Yes. The married daughters are no longer Browns.", "category": "Logic", "date": "03/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. and Mrs. Brown have four daughters, who each have a husband, two brothers, and two sons. Can all the Browns fit into a 4 seater car?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes. The married daughters are no longer Browns.\n<|im_start|>answer\nYes. The married daughters are no longer Browns.\n<|im_end|>" }, { "id": "#48154", "title": "Mystery Number 7", "fun": 2.45, "difficulty": 3.21, "author": "cnmne", "desc": "There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) Either A = B / 3 or A = G + 3.\r\n2) Either B = I - 4 or B = E + 4.\r\n3) Either C = J + 2 or C = F * 3.\r\n4) Either D = G * 4 or D = E / 3.\r\n5) Either E = J - 1 or E = D / 4.\r\n6) Either F = B * 2 or F = A - 4.\r\n7) Either G = F + 1 or G = I - 3.\r\n8) Either H = A / 2 or H = C * 3.\r\n9) Either I = H + 3 or I = D / 2.\r\n10) Either J = H - 2 or J = C * 2.", "hint": "No hint available.", "answer": "5038612947\n\r\nA = 5, B = 0, C = 3, D = 8, E = 6, F = 1, G = 2, H = 9, I = 4, J = 7\n\r\n1) A = G + 3 = 2 + 3 = 5.\r\n2) B = I - 4 = 4 - 4 = 0.\r\n3) C = F * 3 = 1 * 3 = 3.\r\n4) D = G * 4 = 2 * 4 = 8.\r\n5) E = J - 1 = 7 - 1 = 6.\r\n6) F = A - 4 = 5 - 4 = 1.\r\n7) G = F + 1 = 1 + 1 = 2.\r\n8) H = C * 3 = 3 * 3 = 9.\r\n9) I = D / 2 = 8 / 2 = 4.\r\n10) J = H - 2 = 9 - 2 = 7.\n\r\nA) Check each letter for any value that it can not be on the left side of an equation. For example, A can not be 0, as B would also have to be 0 or G would have to be negative. On the first pass through the letters, the following can be determined: A not 0, C not 0, C not 1, D not 0, D not 5, D not 6, D not 7, D not 9, E not 9, F not 7, F not 9, G not 8 (because F not 7), H not 0, H not 5, H not 7, H not 8, I not 0, I not 3 (because H not 0 and D not 6), I not 8 (because H not 5), J not 3 (because H not 5), J not 5 (because H not 7), and J not 9.\r\nB) Make a second pass through the letters. The following can be determined: C not 5, C not 7, D not 3, E not 4, E not 8, and G not 0.\r\nC) Make a third pass. The following can be determined: B not 8.\r\nD) For D, only four numbers are still valid: 1, 2, 4, and 8. Plug each of these numbers into D and check the resulting flow of equations. If D = 1, then the resulting flow will lead to J having to be both 4 and 0. If D = 2, then the resulting flow will lead to 2 also being assigned to G. If D = 4, then the resulting flow will lead to 4 also being assigned to either A or I. If D = 8, then G = 2, F = 1, and A = 5.\r\nE) For E, four numbers are still valid: 0, 3, 6, and 7. Plug each number into E and check the resulting flow. If E = 0, then the flow will lead to J being assigned 1, which has already been assigned to F. If E = 3, then the flow will lead to C being assigned 2, which has already been assigned to G. If E = 7, then the flow will lead to J being assigned 8, which has already been assigned to D. If E = 6, then J = 7, H = 9, and C = 3.\r\nF) The only remaining value for I is 4, which leaves 0 being assigned to B.", "category": "Logic", "date": "10/26/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) Either A = B / 3 or A = G + 3.\r\n2) Either B = I - 4 or B = E + 4.\r\n3) Either C = J + 2 or C = F * 3.\r\n4) Either D = G * 4 or D = E / 3.\r\n5) Either E = J - 1 or E = D / 4.\r\n6) Either F = B * 2 or F = A - 4.\r\n7) Either G = F + 1 or G = I - 3.\r\n8) Either H = A / 2 or H = C * 3.\r\n9) Either I = H + 3 or I = D / 2.\r\n10) Either J = H - 2 or J = C * 2.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5038612947\n\r\nA = 5, B = 0, C = 3, D = 8, E = 6, F = 1, G = 2, H = 9, I = 4, J = 7\n\r\n1) A = G + 3 = 2 + 3 = 5.\r\n2) B = I - 4 = 4 - 4 = 0.\r\n3) C = F * 3 = 1 * 3 = 3.\r\n4) D = G * 4 = 2 * 4 = 8.\r\n5) E = J - 1 = 7 - 1 = 6.\r\n6) F = A - 4 = 5 - 4 = 1.\r\n7) G = F + 1 = 1 + 1 = 2.\r\n8) H = C * 3 = 3 * 3 = 9.\r\n9) I = D / 2 = 8 / 2 = 4.\r\n10) J = H - 2 = 9 - 2 = 7.\n\r\nA) Check each letter for any value that it can not be on the left side of an equation. For example, A can not be 0, as B would also have to be 0 or G would have to be negative. On the first pass through the letters, the following can be determined: A not 0, C not 0, C not 1, D not 0, D not 5, D not 6, D not 7, D not 9, E not 9, F not 7, F not 9, G not 8 (because F not 7), H not 0, H not 5, H not 7, H not 8, I not 0, I not 3 (because H not 0 and D not 6), I not 8 (because H not 5), J not 3 (because H not 5), J not 5 (because H not 7), and J not 9.\r\nB) Make a second pass through the letters. The following can be determined: C not 5, C not 7, D not 3, E not 4, E not 8, and G not 0.\r\nC) Make a third pass. The following can be determined: B not 8.\r\nD) For D, only four numbers are still valid: 1, 2, 4, and 8. Plug each of these numbers into D and check the resulting flow of equations. If D = 1, then the resulting flow will lead to J having to be both 4 and 0. If D = 2, then the resulting flow will lead to 2 also being assigned to G. If D = 4, then the resulting flow will lead to 4 also being assigned to either A or I. If D = 8, then G = 2, F = 1, and A = 5.\r\nE) For E, four numbers are still valid: 0, 3, 6, and 7. Plug each number into E and check the resulting flow. If E = 0, then the flow will lead to J being assigned 1, which has already been assigned to F. If E = 3, then the flow will lead to C being assigned 2, which has already been assigned to G. If E = 7, then the flow will lead to J being assigned 8, which has already been assigned to D. If E = 6, then J = 7, H = 9, and C = 3.\r\nF) The only remaining value for I is 4, which leaves 0 being assigned to B.\n<|im_start|>answer\n5038612947\n\r\nA = 5, B = 0, C = 3, D = 8, E = 6, F = 1, G = 2, H = 9, I = 4, J = 7\n\r\n1) A = G + 3 = 2 + 3 = 5.\r\n2) B = I - 4 = 4 - 4 = 0.\r\n3) C = F * 3 = 1 * 3 = 3.\r\n4) D = G * 4 = 2 * 4 = 8.\r\n5) E = J - 1 = 7 - 1 = 6.\r\n6) F = A - 4 = 5 - 4 = 1.\r\n7) G = F + 1 = 1 + 1 = 2.\r\n8) H = C * 3 = 3 * 3 = 9.\r\n9) I = D / 2 = 8 / 2 = 4.\r\n10) J = H - 2 = 9 - 2 = 7.\n\r\nA) Check each letter for any value that it can not be on the left side of an equation. For example, A can not be 0, as B would also have to be 0 or G would have to be negative. On the first pass through the letters, the following can be determined: A not 0, C not 0, C not 1, D not 0, D not 5, D not 6, D not 7, D not 9, E not 9, F not 7, F not 9, G not 8 (because F not 7), H not 0, H not 5, H not 7, H not 8, I not 0, I not 3 (because H not 0 and D not 6), I not 8 (because H not 5), J not 3 (because H not 5), J not 5 (because H not 7), and J not 9.\r\nB) Make a second pass through the letters. The following can be determined: C not 5, C not 7, D not 3, E not 4, E not 8, and G not 0.\r\nC) Make a third pass. The following can be determined: B not 8.\r\nD) For D, only four numbers are still valid: 1, 2, 4, and 8. Plug each of these numbers into D and check the resulting flow of equations. If D = 1, then the resulting flow will lead to J having to be both 4 and 0. If D = 2, then the resulting flow will lead to 2 also being assigned to G. If D = 4, then the resulting flow will lead to 4 also being assigned to either A or I. If D = 8, then G = 2, F = 1, and A = 5.\r\nE) For E, four numbers are still valid: 0, 3, 6, and 7. Plug each number into E and check the resulting flow. If E = 0, then the flow will lead to J being assigned 1, which has already been assigned to F. If E = 3, then the flow will lead to C being assigned 2, which has already been assigned to G. If E = 7, then the flow will lead to J being assigned 8, which has already been assigned to D. If E = 6, then J = 7, H = 9, and C = 3.\r\nF) The only remaining value for I is 4, which leaves 0 being assigned to B.\n<|im_end|>" }, { "id": "#1455", "title": "Triathlon", "fun": 2.45, "difficulty": 1.87, "author": "psychodude57", "desc": "The final of the triathlon was a close run thing. The whole tournament was decided on the last two sections, swimming and cycling. Adrian didn't win either section. The person who won the swimming came third in the cycling. Adrian beat Keith in swimming, but was beaten by Keith in the cycling. Keith was last in neither section. Duncan won the cycling, but was beaten by Billy in the swimming. Can you work out who came where in each section?", "hint": "No hint available.", "answer": "Swimming; Billy, Adrian, Keith, Duncan.\r\nCycling; Duncan, Keith, Billy, Adrian.", "category": "Logic", "date": "11/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe final of the triathlon was a close run thing. The whole tournament was decided on the last two sections, swimming and cycling. Adrian didn't win either section. The person who won the swimming came third in the cycling. Adrian beat Keith in swimming, but was beaten by Keith in the cycling. Keith was last in neither section. Duncan won the cycling, but was beaten by Billy in the swimming. Can you work out who came where in each section?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSwimming; Billy, Adrian, Keith, Duncan.\r\nCycling; Duncan, Keith, Billy, Adrian.\n<|im_start|>answer\nSwimming; Billy, Adrian, Keith, Duncan.\r\nCycling; Duncan, Keith, Billy, Adrian.\n<|im_end|>" }, { "id": "#42097", "title": "Whose Submarine?", "fun": 2.45, "difficulty": 0.88, "author": "beatlesman12", "desc": "John, George, Paul, and Ringo have four submarines that are each a different color. The colors are: yellow, red, blue, and green. The submarines are in very different conditions as well. The conditions are: New, Like New, Good, and Needs Work. Decide who owns what color submarine and what condition it's in.\n\r\n1. John and George do not own a blue submarine.\r\n2. Paul's submarine is in better condition than the red submarine, but in worse condition than George's.\r\n3. The person with the submarine that needs work has a yellow submarine.\r\n4. John does not own the submarine that needs work.\r\n5. George owns the green submarine.", "hint": "No hint available.", "answer": "Paul, Like New, Blue\n\r\nJohn, Good, Red\n\r\nGeorge, New, Green\n\r\nRingo, Needs Work, Yellow", "category": "Logic-Grid", "date": "05/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn, George, Paul, and Ringo have four submarines that are each a different color. The colors are: yellow, red, blue, and green. The submarines are in very different conditions as well. The conditions are: New, Like New, Good, and Needs Work. Decide who owns what color submarine and what condition it's in.\n\r\n1. John and George do not own a blue submarine.\r\n2. Paul's submarine is in better condition than the red submarine, but in worse condition than George's.\r\n3. The person with the submarine that needs work has a yellow submarine.\r\n4. John does not own the submarine that needs work.\r\n5. George owns the green submarine.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPaul, Like New, Blue\n\r\nJohn, Good, Red\n\r\nGeorge, New, Green\n\r\nRingo, Needs Work, Yellow\n<|im_start|>answer\nPaul, Like New, Blue\n\r\nJohn, Good, Red\n\r\nGeorge, New, Green\n\r\nRingo, Needs Work, Yellow\n<|im_end|>" }, { "id": "#280", "title": "My busy schedule!", "fun": 2.45, "difficulty": 0.91, "author": "Karin", "desc": "Next week I want to have lunch with my friend, visit a new art gallery, meet with my professor and have my teeth cleaned. My friend cannot meet me on Wednesday, my professor does not keep week-end office hours, the art gallery is closed on Tuesday, Thursday, and weekends, and my dentist has office hours only on Tuesday, Friday and Saturday. On what day can I do everything that I have planned?", "hint": "No hint available.", "answer": "Friday. Just cross out the days that can`t be used.", "category": "Logic", "date": "02/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNext week I want to have lunch with my friend, visit a new art gallery, meet with my professor and have my teeth cleaned. My friend cannot meet me on Wednesday, my professor does not keep week-end office hours, the art gallery is closed on Tuesday, Thursday, and weekends, and my dentist has office hours only on Tuesday, Friday and Saturday. On what day can I do everything that I have planned?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriday. Just cross out the days that can`t be used.\n<|im_start|>answer\nFriday. Just cross out the days that can`t be used.\n<|im_end|>" }, { "id": "#30828", "title": "Harry Potter and the Jobs", "fun": 2.45, "difficulty": 0.86, "author": "GoHarryPotterCS", "desc": "Harry Potter, Hermione Granger, and Ron Weasley all graduated from their School: Hogwarts School of Witchcraft and Wizardry and were heading out to get a job. One person became an Auror, one trained and later became a teacher at Hogwarts, and one got a job at the Ministry of Magic. Find out who got which job, and what age they got it at. (19, 20, or 21.)\n\r\nNote that Harry Potter fans will know more about these things BUT the knowledge of the books will NOT help you in any way to solve this. In fact, you may be surprised at the answers.....\n\r\nClues:\n\r\n1. Hermione was not interested in becoming an Auror.\n\r\n2. Harry and the person who is in the Ministry both loved the color blue.\n\r\n3. The teaching job came at the latest age.\n\r\n4. The boys got the jobs at the youngest and oldest age.\n\r\n5. Hermione wanted a place of power and Ron did not wish to return to Hogwarts.", "hint": "No hint available.", "answer": "Ron: Auror, 19\r\nHermione: Ministry, 20\r\nHarry: Teacher, 21", "category": "Logic-Grid", "date": "06/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHarry Potter, Hermione Granger, and Ron Weasley all graduated from their School: Hogwarts School of Witchcraft and Wizardry and were heading out to get a job. One person became an Auror, one trained and later became a teacher at Hogwarts, and one got a job at the Ministry of Magic. Find out who got which job, and what age they got it at. (19, 20, or 21.)\n\r\nNote that Harry Potter fans will know more about these things BUT the knowledge of the books will NOT help you in any way to solve this. In fact, you may be surprised at the answers.....\n\r\nClues:\n\r\n1. Hermione was not interested in becoming an Auror.\n\r\n2. Harry and the person who is in the Ministry both loved the color blue.\n\r\n3. The teaching job came at the latest age.\n\r\n4. The boys got the jobs at the youngest and oldest age.\n\r\n5. Hermione wanted a place of power and Ron did not wish to return to Hogwarts.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRon: Auror, 19\r\nHermione: Ministry, 20\r\nHarry: Teacher, 21\n<|im_start|>answer\nRon: Auror, 19\r\nHermione: Ministry, 20\r\nHarry: Teacher, 21\n<|im_end|>" }, { "id": "#43945", "title": "4+4+4+4=2!", "fun": 2.45, "difficulty": 3.04, "author": "javaguru", "desc": "In \"4+4+4+4=1!\" it was shown that just using addition, subtraction, multiplication, and division, you can form all the numbers from 0 to 9 using exactly four 4's.\n\r\nFor example: 7 = 4 + 4 - 4/4\n\r\nNow if you add the operations square root, factorial, and exponent, what is the first number counting up from zero that can't be formed? How can each number be formed?\n\r\nYou may use parentheses, but you may not combine fours to make 44 or 444.\n\r\n(An exponent is raising a number to the power of another number such as 4^4 = 256; a factorial is the product of all the integers from 1 to the integer such as 4! = 1x2x3x4 = 24.)", "hint": "The first number that can't be formed is 39.", "answer": "The first number that can't be formed is 39. This isn't proved, so maybe you can figure out how to form 39.\n\r\nThere are several ways to form most of the numbers, here are some for the numbers 0 to 9 using just addition, subtract, multiplication and division:\n\r\n0 = 4+4-4-4 = (4-4)*4+4\r\n1 = (4/4)*(4/4) = (4*4)/(4*4) = (4+4)/(4+4) = (4/4)/(4/4)\r\n2 = (4/4)+(4/4) = (4*4)/(4+4) = 4/((4+4)/4)\r\n3 = (4+4+4)/4 = (4*4-4)/4\r\n4 = (4-4)*4+4\r\n5 = (4*4+4)/4\r\n6 = 4+((4+4)/4)\r\n7 = (4+4)-4/4\r\n8 = 4+4+4-4 = (4/4)*4+4 = ((4+4)/4)*4 = 4*4-4-4\r\n9 = 4+4+4/4\n\r\nHere are some ways to form the numbers from 10 to 38 using the additional operators:\n\r\n10 = 4+4+4-SQRT(4)\r\n11 = 4!/SQRT(4)-4/4\r\n12 = 4*(4-4/4)\r\n13 = 4!/SQRT(4)+4/4\r\n14 = 4+4+4+SQRT(4)\r\n15 = 4*4-4/4\r\n16 = 4*4-4+4 = 4+4+4+4 = 4*4*4/4\r\n17 = 4*4+4/4\r\n18 = 4*4+4/SQRT(4)\r\n19 = 4!-4-4/4\r\n20 = (4+(4/4))*4\r\n21 = 4!-4+4/4\r\n22 = 4!-(4+4)/4\r\n23 = 4!-4^(4-4)\r\n24 = 4*4+4+4\r\n25 = (4+4/4)^SQRT(4) = 4!+4^(4-4) = (4!*4!+4!)/4!\r\n26 = 4!+(4+4)/4\r\n27 = 4!+4-4/4\r\n28 = 4*(4+4)-4 = 4!+4+4-4\r\n29 = 4!+4+4/4\r\n30 = (4+4)*4-SQRT(4) = (4+4/4)!/4 = 4!+SQRT(4)+SQRT(4)+SQRT(4)\r\n31 = ((4+SQRT(4))!+4!)/4! = (SQRT(SQRT(SQRT(4)))^4!-SQRT(4))/SQRT(4)\r\n32 = 4*4+4*4 = SQRT(4)^(4+4/4) = 4^4/(4/SQRT(4)) = 4*4*4/SQRT(4) = (4+SQRT(4))^SQRT(4)-4\r\n33 = (SQRT(SQRT(SQRT(4)))^4!+SQRT(4))/SQRT(4)\r\n34 = 4*(4+4)+SQRT(4) = (4+SQRT(2))!/4!+4 = 4!+4+4+SQRT(4)\r\n35 = 4! + (4! - SQRT(4)) / SQRT(4)\r\n36 = 4! + 4 + 4 + 4\r\n37 = 4! + (4! + SQRT(4)) / SQRT(4)\r\n38 = 4! + (4 * 4) - SQRT(4)", "category": "Math", "date": "01/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn \"4+4+4+4=1!\" it was shown that just using addition, subtraction, multiplication, and division, you can form all the numbers from 0 to 9 using exactly four 4's.\n\r\nFor example: 7 = 4 + 4 - 4/4\n\r\nNow if you add the operations square root, factorial, and exponent, what is the first number counting up from zero that can't be formed? How can each number be formed?\n\r\nYou may use parentheses, but you may not combine fours to make 44 or 444.\n\r\n(An exponent is raising a number to the power of another number such as 4^4 = 256; a factorial is the product of all the integers from 1 to the integer such as 4! = 1x2x3x4 = 24.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first number that can't be formed is 39. This isn't proved, so maybe you can figure out how to form 39.\n\r\nThere are several ways to form most of the numbers, here are some for the numbers 0 to 9 using just addition, subtract, multiplication and division:\n\r\n0 = 4+4-4-4 = (4-4)*4+4\r\n1 = (4/4)*(4/4) = (4*4)/(4*4) = (4+4)/(4+4) = (4/4)/(4/4)\r\n2 = (4/4)+(4/4) = (4*4)/(4+4) = 4/((4+4)/4)\r\n3 = (4+4+4)/4 = (4*4-4)/4\r\n4 = (4-4)*4+4\r\n5 = (4*4+4)/4\r\n6 = 4+((4+4)/4)\r\n7 = (4+4)-4/4\r\n8 = 4+4+4-4 = (4/4)*4+4 = ((4+4)/4)*4 = 4*4-4-4\r\n9 = 4+4+4/4\n\r\nHere are some ways to form the numbers from 10 to 38 using the additional operators:\n\r\n10 = 4+4+4-SQRT(4)\r\n11 = 4!/SQRT(4)-4/4\r\n12 = 4*(4-4/4)\r\n13 = 4!/SQRT(4)+4/4\r\n14 = 4+4+4+SQRT(4)\r\n15 = 4*4-4/4\r\n16 = 4*4-4+4 = 4+4+4+4 = 4*4*4/4\r\n17 = 4*4+4/4\r\n18 = 4*4+4/SQRT(4)\r\n19 = 4!-4-4/4\r\n20 = (4+(4/4))*4\r\n21 = 4!-4+4/4\r\n22 = 4!-(4+4)/4\r\n23 = 4!-4^(4-4)\r\n24 = 4*4+4+4\r\n25 = (4+4/4)^SQRT(4) = 4!+4^(4-4) = (4!*4!+4!)/4!\r\n26 = 4!+(4+4)/4\r\n27 = 4!+4-4/4\r\n28 = 4*(4+4)-4 = 4!+4+4-4\r\n29 = 4!+4+4/4\r\n30 = (4+4)*4-SQRT(4) = (4+4/4)!/4 = 4!+SQRT(4)+SQRT(4)+SQRT(4)\r\n31 = ((4+SQRT(4))!+4!)/4! = (SQRT(SQRT(SQRT(4)))^4!-SQRT(4))/SQRT(4)\r\n32 = 4*4+4*4 = SQRT(4)^(4+4/4) = 4^4/(4/SQRT(4)) = 4*4*4/SQRT(4) = (4+SQRT(4))^SQRT(4)-4\r\n33 = (SQRT(SQRT(SQRT(4)))^4!+SQRT(4))/SQRT(4)\r\n34 = 4*(4+4)+SQRT(4) = (4+SQRT(2))!/4!+4 = 4!+4+4+SQRT(4)\r\n35 = 4! + (4! - SQRT(4)) / SQRT(4)\r\n36 = 4! + 4 + 4 + 4\r\n37 = 4! + (4! + SQRT(4)) / SQRT(4)\r\n38 = 4! + (4 * 4) - SQRT(4)\n<|im_start|>answer\nThe first number that can't be formed is 39. This isn't proved, so maybe you can figure out how to form 39.\n\r\nThere are several ways to form most of the numbers, here are some for the numbers 0 to 9 using just addition, subtract, multiplication and division:\n\r\n0 = 4+4-4-4 = (4-4)*4+4\r\n1 = (4/4)*(4/4) = (4*4)/(4*4) = (4+4)/(4+4) = (4/4)/(4/4)\r\n2 = (4/4)+(4/4) = (4*4)/(4+4) = 4/((4+4)/4)\r\n3 = (4+4+4)/4 = (4*4-4)/4\r\n4 = (4-4)*4+4\r\n5 = (4*4+4)/4\r\n6 = 4+((4+4)/4)\r\n7 = (4+4)-4/4\r\n8 = 4+4+4-4 = (4/4)*4+4 = ((4+4)/4)*4 = 4*4-4-4\r\n9 = 4+4+4/4\n\r\nHere are some ways to form the numbers from 10 to 38 using the additional operators:\n\r\n10 = 4+4+4-SQRT(4)\r\n11 = 4!/SQRT(4)-4/4\r\n12 = 4*(4-4/4)\r\n13 = 4!/SQRT(4)+4/4\r\n14 = 4+4+4+SQRT(4)\r\n15 = 4*4-4/4\r\n16 = 4*4-4+4 = 4+4+4+4 = 4*4*4/4\r\n17 = 4*4+4/4\r\n18 = 4*4+4/SQRT(4)\r\n19 = 4!-4-4/4\r\n20 = (4+(4/4))*4\r\n21 = 4!-4+4/4\r\n22 = 4!-(4+4)/4\r\n23 = 4!-4^(4-4)\r\n24 = 4*4+4+4\r\n25 = (4+4/4)^SQRT(4) = 4!+4^(4-4) = (4!*4!+4!)/4!\r\n26 = 4!+(4+4)/4\r\n27 = 4!+4-4/4\r\n28 = 4*(4+4)-4 = 4!+4+4-4\r\n29 = 4!+4+4/4\r\n30 = (4+4)*4-SQRT(4) = (4+4/4)!/4 = 4!+SQRT(4)+SQRT(4)+SQRT(4)\r\n31 = ((4+SQRT(4))!+4!)/4! = (SQRT(SQRT(SQRT(4)))^4!-SQRT(4))/SQRT(4)\r\n32 = 4*4+4*4 = SQRT(4)^(4+4/4) = 4^4/(4/SQRT(4)) = 4*4*4/SQRT(4) = (4+SQRT(4))^SQRT(4)-4\r\n33 = (SQRT(SQRT(SQRT(4)))^4!+SQRT(4))/SQRT(4)\r\n34 = 4*(4+4)+SQRT(4) = (4+SQRT(2))!/4!+4 = 4!+4+4+SQRT(4)\r\n35 = 4! + (4! - SQRT(4)) / SQRT(4)\r\n36 = 4! + 4 + 4 + 4\r\n37 = 4! + (4! + SQRT(4)) / SQRT(4)\r\n38 = 4! + (4 * 4) - SQRT(4)\n<|im_end|>" }, { "id": "#31259", "title": "Triangle", "fun": 2.45, "difficulty": 1.84, "author": "Tammy93", "desc": "A scalene triangle has integer lengths. What is the least possible integer perimeter of this triangle?", "hint": "No hint available.", "answer": "9 units; 2, 3, and 4. In any triangle, the sum of any two sides must be greater than the 3rd side. Scalene means that each side of the triangle has a different length. Knowing that, a triangle with sides 1, 2, and 3 is impossible because 1+2=3, which pretty much makes it a straight line. Moving on, a triangle with sides 2, 3, and 4 is possible, because 2+3>4. Therefore, the perimeter is 9.", "category": "Math", "date": "06/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA scalene triangle has integer lengths. What is the least possible integer perimeter of this triangle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9 units; 2, 3, and 4. In any triangle, the sum of any two sides must be greater than the 3rd side. Scalene means that each side of the triangle has a different length. Knowing that, a triangle with sides 1, 2, and 3 is impossible because 1+2=3, which pretty much makes it a straight line. Moving on, a triangle with sides 2, 3, and 4 is possible, because 2+3>4. Therefore, the perimeter is 9.\n<|im_start|>answer\n9 units; 2, 3, and 4. In any triangle, the sum of any two sides must be greater than the 3rd side. Scalene means that each side of the triangle has a different length. Knowing that, a triangle with sides 1, 2, and 3 is impossible because 1+2=3, which pretty much makes it a straight line. Moving on, a triangle with sides 2, 3, and 4 is possible, because 2+3>4. Therefore, the perimeter is 9.\n<|im_end|>" }, { "id": "#26107", "title": "Family Trips", "fun": 2.44, "difficulty": 0.64, "author": "dcf525", "desc": "The Fennings encourage their four children to take the lead in planning family events. In each of the last four years, a different child has planned a different place he or she wanted to go. Can you determine the year each child came up with a vacation plan and what destination he or she chose?\n\r\nYears: 2001, 2002, 2003, 2004\r\nChildren: Alexandra, Cliff, Ezekiel, Hazel\r\nLocations: Busch Gardens, Niagara Falls, Philadelphia, Williamsburg\n\n\r\n1. Neither Alexandra nor Cliff planned the 2003 trip.\n\r\n2. Ezekiel didn't plan a trip to Niagara Falls.\n\r\n3. Hazel picked the 2002 destination.\n\r\n4. Alexandra planned a trip to Busch Gardens.\n\r\n5. Neither Ezekiel nor Hazel planned the trip to Williamsburg.\n\r\n6. A boy planned the 2004 vacation trip.", "hint": "Alexandra and Hazel are girls. Cliff and Ezekiel are boys.", "answer": "2001, Alexandra, Busch Gardens\r\n2002, Hazel, Niagara Falls\r\n2003, Ezekiel, Philadelphia\r\n2004, Cliff, Williamsburg", "category": "Logic-Grid", "date": "09/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Fennings encourage their four children to take the lead in planning family events. In each of the last four years, a different child has planned a different place he or she wanted to go. Can you determine the year each child came up with a vacation plan and what destination he or she chose?\n\r\nYears: 2001, 2002, 2003, 2004\r\nChildren: Alexandra, Cliff, Ezekiel, Hazel\r\nLocations: Busch Gardens, Niagara Falls, Philadelphia, Williamsburg\n\n\r\n1. Neither Alexandra nor Cliff planned the 2003 trip.\n\r\n2. Ezekiel didn't plan a trip to Niagara Falls.\n\r\n3. Hazel picked the 2002 destination.\n\r\n4. Alexandra planned a trip to Busch Gardens.\n\r\n5. Neither Ezekiel nor Hazel planned the trip to Williamsburg.\n\r\n6. A boy planned the 2004 vacation trip.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2001, Alexandra, Busch Gardens\r\n2002, Hazel, Niagara Falls\r\n2003, Ezekiel, Philadelphia\r\n2004, Cliff, Williamsburg\n<|im_start|>answer\n2001, Alexandra, Busch Gardens\r\n2002, Hazel, Niagara Falls\r\n2003, Ezekiel, Philadelphia\r\n2004, Cliff, Williamsburg\n<|im_end|>" }, { "id": "#1055", "title": "Two Ropes", "fun": 2.44, "difficulty": 2.3, "author": "vivek", "desc": "Two fifty foot ropes are suspended from a forty foot ceiling, about twenty feet apart. Armed with only a knife, how much of the rope can you steal?", "hint": "No hint available.", "answer": "Almost all of it. Tie the ropes together. Climb up one of them. Tie a loop in it as close as possible to the ceiling. Cut it below the loop. Run the rope through the loop and tie it to your waist. Climb the other rope (this may involve some swinging action). Pull the rope going through the loop tight and cut the other rope as close as possible to the ceiling. You will swing down on the rope through the loop. Lower yourself to the ground by letting out rope. Pull the rope through the loop. You will have nearly all the rope.", "category": "Logic", "date": "10/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo fifty foot ropes are suspended from a forty foot ceiling, about twenty feet apart. Armed with only a knife, how much of the rope can you steal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlmost all of it. Tie the ropes together. Climb up one of them. Tie a loop in it as close as possible to the ceiling. Cut it below the loop. Run the rope through the loop and tie it to your waist. Climb the other rope (this may involve some swinging action). Pull the rope going through the loop tight and cut the other rope as close as possible to the ceiling. You will swing down on the rope through the loop. Lower yourself to the ground by letting out rope. Pull the rope through the loop. You will have nearly all the rope.\n<|im_start|>answer\nAlmost all of it. Tie the ropes together. Climb up one of them. Tie a loop in it as close as possible to the ceiling. Cut it below the loop. Run the rope through the loop and tie it to your waist. Climb the other rope (this may involve some swinging action). Pull the rope going through the loop tight and cut the other rope as close as possible to the ceiling. You will swing down on the rope through the loop. Lower yourself to the ground by letting out rope. Pull the rope through the loop. You will have nearly all the rope.\n<|im_end|>" }, { "id": "#44101", "title": "Six Villages", "fun": 2.44, "difficulty": 3.47, "author": "javaguru", "desc": "There are six villages along the coast of the only perfectly round island in the known universe. The villages are evenly distributed along the coastline so that the distance between any two neighboring coastal villages is always the same. There is an absolutely straight path through the jungle connecting every pair of villages. These paths create thirteen crossings in the interior of the island, one of which is in the middle of the island where paths from every village meet.\n\r\nThe island has a strange courtship custom. Before a father will give permission for his daughter to marry, her suitor must bring the father a fish each day until he has traveled by every route from his village to the father's village. The young man only travels along routes where he is always getting closer to his destination. The young man may visit other villages along the way.\n\r\nOn April first a father's three sons come to tell him of their intent to woe a bride, each from a different village. The brides' villages are the first three villages encountered when traveling clockwise around the island.\n\r\nIf the sons begin their courtship today and the couples are married on the day following each son's last trip, what are the three wedding dates?\n\r\nBonus Question: If the coastline of the island is ten miles long, how long is the longest route that any of the sons takes to reach their betrothed's village?", "hint": "To find the number of routes, start from the son's village and move to the farthest away village or crossing from the bride's village he could travel to that hasn't been visited. Record the number of routes to this village or crossing. Keep repeating this, marking the number of routes to each village or crossing along the path until reaching his destination.", "answer": "The wedding dates are April 6th, May 12th, and August 1st.\r\nBonus question: ~ 6.86 miles.\n\n\r\nAll villages are crossings. Here are the steps to determine the number of routes to reach any point:\n\r\n1) First set the starting point to one.\r\n2) Select the unvisited crossing that is adjacent to a visited crossing and is closer to the destination, but which is the farthest such unvisited crossing from the destination.\r\n3) Set this crossing to the sum of the values for all of the adjacent visited crossings. (If you do this in the correct order, all the adjacent visited crossings are farther from the destination.)\r\n4) If the last selected crossing is not the destination then continue with step two.\n\r\nWhich points are closer or farther from the destination can be determined using the right triangles formed by the intersecting paths. The shortest path from a point to a line is perpendicular to the line. Moving toward the right angle formed by the path and the line is moving closer to the point; moving away from this right angle is moving farther from the point.\n\r\nNote that when moving from a village to the opposite village that all of the crossings to the left of the direct path between the villages are symmetrical with the corresponding crossing to the right.\n\n\r\nThe routes:\n\r\nThis is a little hard to follow without a diagram, so you might want to create one. The diagram is a regular hexagon with lines connecting each pair of vertices. There are three intersections created along each of these connecting lines, with the three lines connecting opposite vertices meeting in the middle. Label one vertex A and moving clockwise, label the remaining vertices B-F. Label the middle intersection M. Label the intersection along the path from A to M (path AM) as Ai; label the similar intersections for the remaining vertices as Bi to Fi. Label the intersection of paths AC and BF as ABi. Label the similar intersections BCi, CDi, DEi, EFi and FAi.\n\n\r\nRoutes to an adjacent village (A to B):\n\r\nTo determine the routes from A to B first set A to 1.\r\nThe farthest point from B that is closer than A and adjacent to A is Ai. Ai can only be reached from A, so set Ai to 1.\r\nThe next farthest point is ABi. ABi can be reached from A and Ai so set ABi to 1+1=2.\r\nThe next farthest point is Bi. Bi can only be reached from ABi, so set Bi to 2.\r\nThe next farthest point is the destination B. B can be reached from A, ABi and Bi, so set B to 1+2+2=5.\n\r\nThere are five routes to an adjacent village, so that son will make his last trip on April 5th and the wedding will be the next day on April 6th.\n\n\r\nRoutes to the second village along the coast (A to C):\n\r\nA = 1\r\nAFi = A = 1\r\nFi = AFi = 1\r\nAi = A + AFi = 2\r\nABi = Ai + A = 3\r\nM and B are equidistant from C, so in either order:\r\nM = Ai + Fi = 3\r\nB = A + ABi = 4\r\nBi and Di are equidistant from C, so in either order:\r\nBi = B + ABi + M = 10\r\nDi = M = 3\r\nBCi and CDi are equidistant from C, so in either order:\r\nBCi = B + Bi = 14\r\nCDi = Di = 3\r\nCi = BCi + CDi + M = 20\r\nC = B + BCi + CDi + Ci = 41\n\r\nThere are 41 routes from A to C, so that son will make his last trip on May 11th and the wedding will be the next day on May 12th.\n\n\r\nRoutes to the opposite village (A to D):\n\r\nSince the intersections to the left and right of the direct path are mirrors, the left-side calculation is assigned to both.\r\nA = 1\r\nF, B = A = 1\r\nFAi, ABi = A + B = 2\r\nAi = A + ABi + FAi = 5\r\nFi, Bi = ABi + B = 3\r\nEFi, BCi = B + Bi = 4\r\nM, C and E are equidistant from D, so in any order:\r\nM = Ai + Fi + Bi = 11\r\nE, C = B + BCi = 5\r\nEi, Ci = BCi + M + C = 20\r\nDEi, CDi = C + Ci = 25\r\nDi = M + CDi + DEi = 61\r\nD = C + E + CDi + DEi + Di = 121\n\r\nThere are 121 routes from A to D, so that son will make his last trip on July 31st and the wedding will be the next day on August 1st.\n\n\r\nBonus Question:\n\r\nThe longest route is a route to the opposite village. Given the above diagram, the longest routes the son will have to travel from A to D is:\n\r\nA-B-ABi-C-Ci-CDi-Di-D\n\r\nand the mirror route\n\r\nA-F-FAi-E-Ei-DEi-Di-D\n\r\n(ABi-C is the same as ABi-Bi-BCi-C)\n\r\nIf the circumference is 10 miles then the diameter is 10/Pi miles and the radius is 5/Pi miles. Since a regular hexagon is formed from six equilateral triangles, the length of a side of the hexagon is equal to its radius.\n\r\nThe path A-B is then 5/Pi miles. The path B-D bisects the path C-M, so both C-Ci and Di-D are half the radius. A-B + C-Ci + Di-D is then equal to the diameter 10/Pi.\n\r\nThe paths B-ABi, ABi-BCi, and BCi-C are all sides of equilateral triangles with a height of one half of the radius. The paths Ci-CDi and CDi-Di are each half of the side of one of these same triangles. The side of one of these equilateral triangles is\n\r\n5/(sqrt(3)*Pi)\n\r\nSo the total distance traveled is\n\r\n10/Pi + 4*(5/(sqrt(3)*Pi)) = 10/Pi + 20/(sqrt(3)*Pi) ~ 6.86 miles", "category": "Math", "date": "02/14/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are six villages along the coast of the only perfectly round island in the known universe. The villages are evenly distributed along the coastline so that the distance between any two neighboring coastal villages is always the same. There is an absolutely straight path through the jungle connecting every pair of villages. These paths create thirteen crossings in the interior of the island, one of which is in the middle of the island where paths from every village meet.\n\r\nThe island has a strange courtship custom. Before a father will give permission for his daughter to marry, her suitor must bring the father a fish each day until he has traveled by every route from his village to the father's village. The young man only travels along routes where he is always getting closer to his destination. The young man may visit other villages along the way.\n\r\nOn April first a father's three sons come to tell him of their intent to woe a bride, each from a different village. The brides' villages are the first three villages encountered when traveling clockwise around the island.\n\r\nIf the sons begin their courtship today and the couples are married on the day following each son's last trip, what are the three wedding dates?\n\r\nBonus Question: If the coastline of the island is ten miles long, how long is the longest route that any of the sons takes to reach their betrothed's village?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe wedding dates are April 6th, May 12th, and August 1st.\r\nBonus question: ~ 6.86 miles.\n\n\r\nAll villages are crossings. Here are the steps to determine the number of routes to reach any point:\n\r\n1) First set the starting point to one.\r\n2) Select the unvisited crossing that is adjacent to a visited crossing and is closer to the destination, but which is the farthest such unvisited crossing from the destination.\r\n3) Set this crossing to the sum of the values for all of the adjacent visited crossings. (If you do this in the correct order, all the adjacent visited crossings are farther from the destination.)\r\n4) If the last selected crossing is not the destination then continue with step two.\n\r\nWhich points are closer or farther from the destination can be determined using the right triangles formed by the intersecting paths. The shortest path from a point to a line is perpendicular to the line. Moving toward the right angle formed by the path and the line is moving closer to the point; moving away from this right angle is moving farther from the point.\n\r\nNote that when moving from a village to the opposite village that all of the crossings to the left of the direct path between the villages are symmetrical with the corresponding crossing to the right.\n\n\r\nThe routes:\n\r\nThis is a little hard to follow without a diagram, so you might want to create one. The diagram is a regular hexagon with lines connecting each pair of vertices. There are three intersections created along each of these connecting lines, with the three lines connecting opposite vertices meeting in the middle. Label one vertex A and moving clockwise, label the remaining vertices B-F. Label the middle intersection M. Label the intersection along the path from A to M (path AM) as Ai; label the similar intersections for the remaining vertices as Bi to Fi. Label the intersection of paths AC and BF as ABi. Label the similar intersections BCi, CDi, DEi, EFi and FAi.\n\n\r\nRoutes to an adjacent village (A to B):\n\r\nTo determine the routes from A to B first set A to 1.\r\nThe farthest point from B that is closer than A and adjacent to A is Ai. Ai can only be reached from A, so set Ai to 1.\r\nThe next farthest point is ABi. ABi can be reached from A and Ai so set ABi to 1+1=2.\r\nThe next farthest point is Bi. Bi can only be reached from ABi, so set Bi to 2.\r\nThe next farthest point is the destination B. B can be reached from A, ABi and Bi, so set B to 1+2+2=5.\n\r\nThere are five routes to an adjacent village, so that son will make his last trip on April 5th and the wedding will be the next day on April 6th.\n\n\r\nRoutes to the second village along the coast (A to C):\n\r\nA = 1\r\nAFi = A = 1\r\nFi = AFi = 1\r\nAi = A + AFi = 2\r\nABi = Ai + A = 3\r\nM and B are equidistant from C, so in either order:\r\nM = Ai + Fi = 3\r\nB = A + ABi = 4\r\nBi and Di are equidistant from C, so in either order:\r\nBi = B + ABi + M = 10\r\nDi = M = 3\r\nBCi and CDi are equidistant from C, so in either order:\r\nBCi = B + Bi = 14\r\nCDi = Di = 3\r\nCi = BCi + CDi + M = 20\r\nC = B + BCi + CDi + Ci = 41\n\r\nThere are 41 routes from A to C, so that son will make his last trip on May 11th and the wedding will be the next day on May 12th.\n\n\r\nRoutes to the opposite village (A to D):\n\r\nSince the intersections to the left and right of the direct path are mirrors, the left-side calculation is assigned to both.\r\nA = 1\r\nF, B = A = 1\r\nFAi, ABi = A + B = 2\r\nAi = A + ABi + FAi = 5\r\nFi, Bi = ABi + B = 3\r\nEFi, BCi = B + Bi = 4\r\nM, C and E are equidistant from D, so in any order:\r\nM = Ai + Fi + Bi = 11\r\nE, C = B + BCi = 5\r\nEi, Ci = BCi + M + C = 20\r\nDEi, CDi = C + Ci = 25\r\nDi = M + CDi + DEi = 61\r\nD = C + E + CDi + DEi + Di = 121\n\r\nThere are 121 routes from A to D, so that son will make his last trip on July 31st and the wedding will be the next day on August 1st.\n\n\r\nBonus Question:\n\r\nThe longest route is a route to the opposite village. Given the above diagram, the longest routes the son will have to travel from A to D is:\n\r\nA-B-ABi-C-Ci-CDi-Di-D\n\r\nand the mirror route\n\r\nA-F-FAi-E-Ei-DEi-Di-D\n\r\n(ABi-C is the same as ABi-Bi-BCi-C)\n\r\nIf the circumference is 10 miles then the diameter is 10/Pi miles and the radius is 5/Pi miles. Since a regular hexagon is formed from six equilateral triangles, the length of a side of the hexagon is equal to its radius.\n\r\nThe path A-B is then 5/Pi miles. The path B-D bisects the path C-M, so both C-Ci and Di-D are half the radius. A-B + C-Ci + Di-D is then equal to the diameter 10/Pi.\n\r\nThe paths B-ABi, ABi-BCi, and BCi-C are all sides of equilateral triangles with a height of one half of the radius. The paths Ci-CDi and CDi-Di are each half of the side of one of these same triangles. The side of one of these equilateral triangles is\n\r\n5/(sqrt(3)*Pi)\n\r\nSo the total distance traveled is\n\r\n10/Pi + 4*(5/(sqrt(3)*Pi)) = 10/Pi + 20/(sqrt(3)*Pi) ~ 6.86 miles\n<|im_start|>answer\nThe wedding dates are April 6th, May 12th, and August 1st.\r\nBonus question: ~ 6.86 miles.\n\n\r\nAll villages are crossings. Here are the steps to determine the number of routes to reach any point:\n\r\n1) First set the starting point to one.\r\n2) Select the unvisited crossing that is adjacent to a visited crossing and is closer to the destination, but which is the farthest such unvisited crossing from the destination.\r\n3) Set this crossing to the sum of the values for all of the adjacent visited crossings. (If you do this in the correct order, all the adjacent visited crossings are farther from the destination.)\r\n4) If the last selected crossing is not the destination then continue with step two.\n\r\nWhich points are closer or farther from the destination can be determined using the right triangles formed by the intersecting paths. The shortest path from a point to a line is perpendicular to the line. Moving toward the right angle formed by the path and the line is moving closer to the point; moving away from this right angle is moving farther from the point.\n\r\nNote that when moving from a village to the opposite village that all of the crossings to the left of the direct path between the villages are symmetrical with the corresponding crossing to the right.\n\n\r\nThe routes:\n\r\nThis is a little hard to follow without a diagram, so you might want to create one. The diagram is a regular hexagon with lines connecting each pair of vertices. There are three intersections created along each of these connecting lines, with the three lines connecting opposite vertices meeting in the middle. Label one vertex A and moving clockwise, label the remaining vertices B-F. Label the middle intersection M. Label the intersection along the path from A to M (path AM) as Ai; label the similar intersections for the remaining vertices as Bi to Fi. Label the intersection of paths AC and BF as ABi. Label the similar intersections BCi, CDi, DEi, EFi and FAi.\n\n\r\nRoutes to an adjacent village (A to B):\n\r\nTo determine the routes from A to B first set A to 1.\r\nThe farthest point from B that is closer than A and adjacent to A is Ai. Ai can only be reached from A, so set Ai to 1.\r\nThe next farthest point is ABi. ABi can be reached from A and Ai so set ABi to 1+1=2.\r\nThe next farthest point is Bi. Bi can only be reached from ABi, so set Bi to 2.\r\nThe next farthest point is the destination B. B can be reached from A, ABi and Bi, so set B to 1+2+2=5.\n\r\nThere are five routes to an adjacent village, so that son will make his last trip on April 5th and the wedding will be the next day on April 6th.\n\n\r\nRoutes to the second village along the coast (A to C):\n\r\nA = 1\r\nAFi = A = 1\r\nFi = AFi = 1\r\nAi = A + AFi = 2\r\nABi = Ai + A = 3\r\nM and B are equidistant from C, so in either order:\r\nM = Ai + Fi = 3\r\nB = A + ABi = 4\r\nBi and Di are equidistant from C, so in either order:\r\nBi = B + ABi + M = 10\r\nDi = M = 3\r\nBCi and CDi are equidistant from C, so in either order:\r\nBCi = B + Bi = 14\r\nCDi = Di = 3\r\nCi = BCi + CDi + M = 20\r\nC = B + BCi + CDi + Ci = 41\n\r\nThere are 41 routes from A to C, so that son will make his last trip on May 11th and the wedding will be the next day on May 12th.\n\n\r\nRoutes to the opposite village (A to D):\n\r\nSince the intersections to the left and right of the direct path are mirrors, the left-side calculation is assigned to both.\r\nA = 1\r\nF, B = A = 1\r\nFAi, ABi = A + B = 2\r\nAi = A + ABi + FAi = 5\r\nFi, Bi = ABi + B = 3\r\nEFi, BCi = B + Bi = 4\r\nM, C and E are equidistant from D, so in any order:\r\nM = Ai + Fi + Bi = 11\r\nE, C = B + BCi = 5\r\nEi, Ci = BCi + M + C = 20\r\nDEi, CDi = C + Ci = 25\r\nDi = M + CDi + DEi = 61\r\nD = C + E + CDi + DEi + Di = 121\n\r\nThere are 121 routes from A to D, so that son will make his last trip on July 31st and the wedding will be the next day on August 1st.\n\n\r\nBonus Question:\n\r\nThe longest route is a route to the opposite village. Given the above diagram, the longest routes the son will have to travel from A to D is:\n\r\nA-B-ABi-C-Ci-CDi-Di-D\n\r\nand the mirror route\n\r\nA-F-FAi-E-Ei-DEi-Di-D\n\r\n(ABi-C is the same as ABi-Bi-BCi-C)\n\r\nIf the circumference is 10 miles then the diameter is 10/Pi miles and the radius is 5/Pi miles. Since a regular hexagon is formed from six equilateral triangles, the length of a side of the hexagon is equal to its radius.\n\r\nThe path A-B is then 5/Pi miles. The path B-D bisects the path C-M, so both C-Ci and Di-D are half the radius. A-B + C-Ci + Di-D is then equal to the diameter 10/Pi.\n\r\nThe paths B-ABi, ABi-BCi, and BCi-C are all sides of equilateral triangles with a height of one half of the radius. The paths Ci-CDi and CDi-Di are each half of the side of one of these same triangles. The side of one of these equilateral triangles is\n\r\n5/(sqrt(3)*Pi)\n\r\nSo the total distance traveled is\n\r\n10/Pi + 4*(5/(sqrt(3)*Pi)) = 10/Pi + 20/(sqrt(3)*Pi) ~ 6.86 miles\n<|im_end|>" }, { "id": "#2035", "title": "Soft Drink Dilemma", "fun": 2.44, "difficulty": 1.91, "author": "Mogmatt16", "desc": "You have two 8 oz. cups in front of you. One is filled with Root Beer and one is full of Club Soda. You take one tablespoon of Root Beer and pour it into the Club Soda. Stir well. Now, you take a tablespoon of the mixture you just stirred, and pour it into the Root Beer. Now, does the Root Beer have more Club Soda in it or vice versa? Don't account for spilling.", "hint": "No hint available.", "answer": "They are equal. For every drop of club soda in the root beer, there is a drop of root beer in the club soda.", "category": "Math", "date": "01/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two 8 oz. cups in front of you. One is filled with Root Beer and one is full of Club Soda. You take one tablespoon of Root Beer and pour it into the Club Soda. Stir well. Now, you take a tablespoon of the mixture you just stirred, and pour it into the Root Beer. Now, does the Root Beer have more Club Soda in it or vice versa? Don't account for spilling.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are equal. For every drop of club soda in the root beer, there is a drop of root beer in the club soda.\n<|im_start|>answer\nThey are equal. For every drop of club soda in the root beer, there is a drop of root beer in the club soda.\n<|im_end|>" }, { "id": "#8703", "title": "The Science Fair", "fun": 2.44, "difficulty": 1.31, "author": "something", "desc": "Isaac and Albert were excitedly describing the result of the Third Annual International Science Fair Extravaganza in Sweden. There were three contestants, Louis, Rene, and Johannes. Isaac reported that Louis won the fair, while Rene came in second. Albert, on the other hand, reported that Johannes won the fair, while Louis came in second.\r\nIn fact, neither Isaac nor Albert had given a correct report of the results of the science fair. Each of them had given one correct statement and one false statement. What was the actual placing of the three contestants?", "hint": "No hint available.", "answer": "Johannes won; Rene came in second; Louis came in third.\n\r\nAll you have to do to solve this is look at Isaac's first statement: \"Louis won the fair\". If this were true then neither of Albert's statements could be true. Therefore this must be Isaac's false statement.\n\r\nThis means that Isaac's second statement, \"Rene came in second\" must be true, which in turn means that Albert's first statement, \"John came in first\" must also be true. This leaves Louis in third place.", "category": "Logic", "date": "11/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIsaac and Albert were excitedly describing the result of the Third Annual International Science Fair Extravaganza in Sweden. There were three contestants, Louis, Rene, and Johannes. Isaac reported that Louis won the fair, while Rene came in second. Albert, on the other hand, reported that Johannes won the fair, while Louis came in second.\r\nIn fact, neither Isaac nor Albert had given a correct report of the results of the science fair. Each of them had given one correct statement and one false statement. What was the actual placing of the three contestants?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohannes won; Rene came in second; Louis came in third.\n\r\nAll you have to do to solve this is look at Isaac's first statement: \"Louis won the fair\". If this were true then neither of Albert's statements could be true. Therefore this must be Isaac's false statement.\n\r\nThis means that Isaac's second statement, \"Rene came in second\" must be true, which in turn means that Albert's first statement, \"John came in first\" must also be true. This leaves Louis in third place.\n<|im_start|>answer\nJohannes won; Rene came in second; Louis came in third.\n\r\nAll you have to do to solve this is look at Isaac's first statement: \"Louis won the fair\". If this were true then neither of Albert's statements could be true. Therefore this must be Isaac's false statement.\n\r\nThis means that Isaac's second statement, \"Rene came in second\" must be true, which in turn means that Albert's first statement, \"John came in first\" must also be true. This leaves Louis in third place.\n<|im_end|>" }, { "id": "#14862", "title": "Numbers and Their Reversion", "fun": 2.44, "difficulty": 2.8, "author": "Gerd", "desc": "If you add 9 and 9 you get 18, and if you multiply 9 by 9 you get 81 (the reverse of 18). There are 2 more pairs of numbers with the same characteristics and where the result is two-digit:\r\n24 + 3 = 27 and 24 * 3 = 72\r\nand\r\n47 + 2 = 49 and 47 * 2 = 94\n\r\nBut there is only one pair of numbers with a triple-digit result and its reversion.\n\r\nWhat are the 2 numbers?", "hint": "One number has 1 digit and the other has 3.", "answer": "The numbers are 497 and 2:\n\r\n497 + 2 = 499\r\nand\r\n497 * 2 = 994", "category": "Math", "date": "09/20/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you add 9 and 9 you get 18, and if you multiply 9 by 9 you get 81 (the reverse of 18). There are 2 more pairs of numbers with the same characteristics and where the result is two-digit:\r\n24 + 3 = 27 and 24 * 3 = 72\r\nand\r\n47 + 2 = 49 and 47 * 2 = 94\n\r\nBut there is only one pair of numbers with a triple-digit result and its reversion.\n\r\nWhat are the 2 numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers are 497 and 2:\n\r\n497 + 2 = 499\r\nand\r\n497 * 2 = 994\n<|im_start|>answer\nThe numbers are 497 and 2:\n\r\n497 + 2 = 499\r\nand\r\n497 * 2 = 994\n<|im_end|>" }, { "id": "#662", "title": "Birthday Cake", "fun": 2.44, "difficulty": 1.56, "author": "vikass", "desc": "Suppose you are given a birthday cake which is round in shape (like a perfect circle) and you are asked to make eight equal pieces out of it by using a knife only three times. How would you proceed?", "hint": "No hint available.", "answer": "Use the knife a first time to cut it across one of its diameters. Then use the knife a second time to cut across another diameter and you will have four equal parts. Use the knife a third time to cut the cake horizontally, half way across its thickness, and you have the eight equal pieces!!!", "category": "Math", "date": "08/25/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose you are given a birthday cake which is round in shape (like a perfect circle) and you are asked to make eight equal pieces out of it by using a knife only three times. How would you proceed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUse the knife a first time to cut it across one of its diameters. Then use the knife a second time to cut across another diameter and you will have four equal parts. Use the knife a third time to cut the cake horizontally, half way across its thickness, and you have the eight equal pieces!!!\n<|im_start|>answer\nUse the knife a first time to cut it across one of its diameters. Then use the knife a second time to cut across another diameter and you will have four equal parts. Use the knife a third time to cut the cake horizontally, half way across its thickness, and you have the eight equal pieces!!!\n<|im_end|>" }, { "id": "#16027", "title": "Mail Delivery", "fun": 2.44, "difficulty": 1.69, "author": "doggyxp", "desc": "Aly lives in a street with 12 houses. Every day she gets more letters than are delivered to any other house. Today 57 letters were delivered to her street. What is the smallest number of letters that Aly could have received today?", "hint": "No hint available.", "answer": "6 letters. \n\r\nFor Aly to receive the least amount of letters, the deliveries had to be spread out as evenly as possible amongst the 12 houses. The nearest multiple of 12 below 57 is 48 (4 letters per house). This leaves 9 letters. If seven people each receive one more letter and Aly receives two more letters, then this is the minimum that she could receive: six letters.", "category": "Math", "date": "01/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAly lives in a street with 12 houses. Every day she gets more letters than are delivered to any other house. Today 57 letters were delivered to her street. What is the smallest number of letters that Aly could have received today?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6 letters. \n\r\nFor Aly to receive the least amount of letters, the deliveries had to be spread out as evenly as possible amongst the 12 houses. The nearest multiple of 12 below 57 is 48 (4 letters per house). This leaves 9 letters. If seven people each receive one more letter and Aly receives two more letters, then this is the minimum that she could receive: six letters.\n<|im_start|>answer\n6 letters. \n\r\nFor Aly to receive the least amount of letters, the deliveries had to be spread out as evenly as possible amongst the 12 houses. The nearest multiple of 12 below 57 is 48 (4 letters per house). This leaves 9 letters. If seven people each receive one more letter and Aly receives two more letters, then this is the minimum that she could receive: six letters.\n<|im_end|>" }, { "id": "#13842", "title": "Four Score and Four Minutes Ago", "fun": 2.44, "difficulty": 2.32, "author": "mathemagician", "desc": "Four score and four minutes ago, the time was precisely half past four plus forty and four minutes more. Now, in order to score, you must work your way through these fours galore and tell me more:\n\r\nWhat is the angle between the hour hand and minute hand of a clock at the present time?", "hint": "The time is presently 6:38 .\n\r\nThe minute hand moves 6 degrees per minute; the hour hand moves 30 degrees each hour or 0.5 degree per minute.", "answer": "29 degrees.\n\r\nFrom the \"12 O'Clock\" position:\r\nin 38 minutes, the minute hand has moved 228 degrees; in 6 hours, 38 min., the hour hand has moved 199 degrees.\n\r\n228-199 = 29 degrees .", "category": "Math", "date": "07/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour score and four minutes ago, the time was precisely half past four plus forty and four minutes more. Now, in order to score, you must work your way through these fours galore and tell me more:\n\r\nWhat is the angle between the hour hand and minute hand of a clock at the present time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n29 degrees.\n\r\nFrom the \"12 O'Clock\" position:\r\nin 38 minutes, the minute hand has moved 228 degrees; in 6 hours, 38 min., the hour hand has moved 199 degrees.\n\r\n228-199 = 29 degrees .\n<|im_start|>answer\n29 degrees.\n\r\nFrom the \"12 O'Clock\" position:\r\nin 38 minutes, the minute hand has moved 228 degrees; in 6 hours, 38 min., the hour hand has moved 199 degrees.\n\r\n228-199 = 29 degrees .\n<|im_end|>" }, { "id": "#1382", "title": "Beethoven", "fun": 2.44, "difficulty": 2.04, "author": "psychodude57", "desc": "In my collection of classical music I have a range of pieces which last 6, 7, 8 and 9 minutes. The piece by Bach lasts 8 minutes and the CD lasts longer than the piece by Holst. The piece on DAT tape is longer than the piece by Beethoven. The single lasts for 7 minutes and the album does not contain any Holst. The piece by Butler is on the DAT tape. Can you determine which piece of music is on which format and how long each lasts?", "hint": "No hint available.", "answer": "Beethoven is on the album and lasts 6 minutes.\r\nHolst is on the single and lasts 7 minutes.\r\nBach is on CD and lasts 8 minutes.\r\nButler is on DAT tape and lasts 9 minutes.", "category": "Logic", "date": "11/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn my collection of classical music I have a range of pieces which last 6, 7, 8 and 9 minutes. The piece by Bach lasts 8 minutes and the CD lasts longer than the piece by Holst. The piece on DAT tape is longer than the piece by Beethoven. The single lasts for 7 minutes and the album does not contain any Holst. The piece by Butler is on the DAT tape. Can you determine which piece of music is on which format and how long each lasts?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeethoven is on the album and lasts 6 minutes.\r\nHolst is on the single and lasts 7 minutes.\r\nBach is on CD and lasts 8 minutes.\r\nButler is on DAT tape and lasts 9 minutes.\n<|im_start|>answer\nBeethoven is on the album and lasts 6 minutes.\r\nHolst is on the single and lasts 7 minutes.\r\nBach is on CD and lasts 8 minutes.\r\nButler is on DAT tape and lasts 9 minutes.\n<|im_end|>" }, { "id": "#41622", "title": "Three CDs", "fun": 2.44, "difficulty": 1.12, "author": "phrebh", "desc": "A set of 25-year-old triplets (two boys, Donovan and Gerry, and one girl, Dusty) were talking about a British Invasion CD they all own. They thought it was weird that they each got it for a different birthday (13th, 16th, and 21st) from a different person (their mom, their dad, and a friend). They didn't think it was weird that they each had different favorites (Come Dancing, Gloria, and Winchester Cathedral), though, since they had very different personalities.\n\r\nUsing the clues below, can you figure out who got the CD for which birthday, from whom, and what their favorite song is?\n\r\n1. The person whose favorite song is \"Winchester Cathedral\" did not get the CD from a parent.\n\r\n2. Donovan always liked \"Come Dancing\" even though it made him cry the first time he heard it, on the way to DMV to get his first driver's license.\n\r\n3. Dad didn't give his son the CD 12 years ago.\n\r\n4. Dusty got her copy of the CD after Donovan got his.\n\r\n5. The friend who got one of the triplets the CD met that triplet in college.", "hint": "In their state, the triplets could not get a driver's license before the age of 16.\n\r\nThe triplets all started college when they were 18.", "answer": "Donovan's favorite song on the CD is \"Come Dancing\" and his dad gave him the CD for his 16th birthday.\n\r\nDusty's favorite song on the CD is \"Winchester Cathedral\" and her friend gave her the CD for her 21st birthday.\n\r\nGerry's favorite song on the CD is \"Gloria\" and his mom gave him the CD for his 13th birthday.", "category": "Logic-Grid", "date": "04/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA set of 25-year-old triplets (two boys, Donovan and Gerry, and one girl, Dusty) were talking about a British Invasion CD they all own. They thought it was weird that they each got it for a different birthday (13th, 16th, and 21st) from a different person (their mom, their dad, and a friend). They didn't think it was weird that they each had different favorites (Come Dancing, Gloria, and Winchester Cathedral), though, since they had very different personalities.\n\r\nUsing the clues below, can you figure out who got the CD for which birthday, from whom, and what their favorite song is?\n\r\n1. The person whose favorite song is \"Winchester Cathedral\" did not get the CD from a parent.\n\r\n2. Donovan always liked \"Come Dancing\" even though it made him cry the first time he heard it, on the way to DMV to get his first driver's license.\n\r\n3. Dad didn't give his son the CD 12 years ago.\n\r\n4. Dusty got her copy of the CD after Donovan got his.\n\r\n5. The friend who got one of the triplets the CD met that triplet in college.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDonovan's favorite song on the CD is \"Come Dancing\" and his dad gave him the CD for his 16th birthday.\n\r\nDusty's favorite song on the CD is \"Winchester Cathedral\" and her friend gave her the CD for her 21st birthday.\n\r\nGerry's favorite song on the CD is \"Gloria\" and his mom gave him the CD for his 13th birthday.\n<|im_start|>answer\nDonovan's favorite song on the CD is \"Come Dancing\" and his dad gave him the CD for his 16th birthday.\n\r\nDusty's favorite song on the CD is \"Winchester Cathedral\" and her friend gave her the CD for her 21st birthday.\n\r\nGerry's favorite song on the CD is \"Gloria\" and his mom gave him the CD for his 13th birthday.\n<|im_end|>" }, { "id": "#3135", "title": "Half Plus One", "fun": 2.44, "difficulty": 1.98, "author": "204_blaze_41", "desc": "Pete Wheels is a used car salesman. He sold half his cars plus one more to his first customer of the day. To the second customer, he sold half of the remaining plus one more. To the third customer, he sold half the remainder plus one more; and to the fourth customer, he sold half the remainder plus one more. Pete was now the proud salesman of an empty car lot. How many cars did Pete have for sale at the start of the day?", "hint": "No hint available.", "answer": "Thirty. The trick is to work backwards. On his fourth and final sale he sells half of his remainder plus one more, leaving him with zero. Therefore we know that he sold one plus one more on the fourth sale. On the third sale he sold half of six, plus one more which left him with two for the fourth sale. On the second sale he sold half of 14 plus one more which left him with six for the third sale. Therefore, on the first sale he sold half of 30 plus one more which left him with 14 for the second sale.", "category": "Math", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPete Wheels is a used car salesman. He sold half his cars plus one more to his first customer of the day. To the second customer, he sold half of the remaining plus one more. To the third customer, he sold half the remainder plus one more; and to the fourth customer, he sold half the remainder plus one more. Pete was now the proud salesman of an empty car lot. How many cars did Pete have for sale at the start of the day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThirty. The trick is to work backwards. On his fourth and final sale he sells half of his remainder plus one more, leaving him with zero. Therefore we know that he sold one plus one more on the fourth sale. On the third sale he sold half of six, plus one more which left him with two for the fourth sale. On the second sale he sold half of 14 plus one more which left him with six for the third sale. Therefore, on the first sale he sold half of 30 plus one more which left him with 14 for the second sale.\n<|im_start|>answer\nThirty. The trick is to work backwards. On his fourth and final sale he sells half of his remainder plus one more, leaving him with zero. Therefore we know that he sold one plus one more on the fourth sale. On the third sale he sold half of six, plus one more which left him with two for the fourth sale. On the second sale he sold half of 14 plus one more which left him with six for the third sale. Therefore, on the first sale he sold half of 30 plus one more which left him with 14 for the second sale.\n<|im_end|>" }, { "id": "#38545", "title": "What's the Job?", "fun": 2.44, "difficulty": 1.43, "author": "wannamarryharry", "desc": "Brown, Jones, and Smith are a doctor, a lawyer, and a teacher. The teacher, who is an only child, earns the least money. Smith, who married Brown's sister, earns more than the lawyer. What is each man's job?", "hint": "No hint available.", "answer": "Jones is the teacher, Brown is the lawyer, and Smith is the doctor.", "category": "Logic", "date": "09/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBrown, Jones, and Smith are a doctor, a lawyer, and a teacher. The teacher, who is an only child, earns the least money. Smith, who married Brown's sister, earns more than the lawyer. What is each man's job?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJones is the teacher, Brown is the lawyer, and Smith is the doctor.\n<|im_start|>answer\nJones is the teacher, Brown is the lawyer, and Smith is the doctor.\n<|im_end|>" }, { "id": "#29878", "title": "3608528850368400786036725", "fun": 2.44, "difficulty": 2.98, "author": "shenqiang", "desc": "What is so unusual about this number?\n\r\n3608528850368400786036725", "hint": "It's the greatest natural number with this property. If you can't figure it out, check out teaser 29716.", "answer": "The number formed by its first n digits is divisible by n, e.g. 36 is divisible by 2, 360 is divisible by 3, 3608 is divisible by 4, etc.", "category": "Math", "date": "04/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is so unusual about this number?\n\r\n3608528850368400786036725\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number formed by its first n digits is divisible by n, e.g. 36 is divisible by 2, 360 is divisible by 3, 3608 is divisible by 4, etc.\n<|im_start|>answer\nThe number formed by its first n digits is divisible by n, e.g. 36 is divisible by 2, 360 is divisible by 3, 3608 is divisible by 4, etc.\n<|im_end|>" }, { "id": "#22604", "title": "Girl Scouts", "fun": 2.44, "difficulty": 0.71, "author": "wordwizz", "desc": "Girl Scout Troop #123 is going on a field trip. Each girl going on the trip has a partner (the troop leader is using the buddy system), a sack lunch and a type of girl scout badge. Your job is to find Janie, Anna and Lauren's buddy, lunch and badge while using the clues. Good Luck!\n\r\n* Partners: Zoey, Amelia, Jade\r\nLunches: PB&J, tuna sandwich, Lunchables\r\nBadges: Cooking, community service, 1000 cookie boxes sold\n\r\nClues:\r\n-Jade's partner has the 1000 cookies sold badge.\r\n-Anna doesn't like fish.\r\n-Lauren messed up her lunch because she wasn't a good cook, so she got the Lunchables.\r\n-Amelia is surprised about her partner because she thought her partner would be nice considering the community service badge she has.\r\n-None of the girls share initials with their partners.\r\n-Zoey and Janie are best friends so they were thrilled when the troop leader made them partners.", "hint": "No hint available.", "answer": "Janie-Zoey - Tuna - Cooking\n\r\nAnna-Jade - PB&J - 1000 cookies sold\n\r\nLauren-Amelia - Lunchables - community service", "category": "Logic-Grid", "date": "05/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGirl Scout Troop #123 is going on a field trip. Each girl going on the trip has a partner (the troop leader is using the buddy system), a sack lunch and a type of girl scout badge. Your job is to find Janie, Anna and Lauren's buddy, lunch and badge while using the clues. Good Luck!\n\r\n* Partners: Zoey, Amelia, Jade\r\nLunches: PB&J, tuna sandwich, Lunchables\r\nBadges: Cooking, community service, 1000 cookie boxes sold\n\r\nClues:\r\n-Jade's partner has the 1000 cookies sold badge.\r\n-Anna doesn't like fish.\r\n-Lauren messed up her lunch because she wasn't a good cook, so she got the Lunchables.\r\n-Amelia is surprised about her partner because she thought her partner would be nice considering the community service badge she has.\r\n-None of the girls share initials with their partners.\r\n-Zoey and Janie are best friends so they were thrilled when the troop leader made them partners.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJanie-Zoey - Tuna - Cooking\n\r\nAnna-Jade - PB&J - 1000 cookies sold\n\r\nLauren-Amelia - Lunchables - community service\n<|im_start|>answer\nJanie-Zoey - Tuna - Cooking\n\r\nAnna-Jade - PB&J - 1000 cookies sold\n\r\nLauren-Amelia - Lunchables - community service\n<|im_end|>" }, { "id": "#32906", "title": "Age of Father and Son", "fun": 2.44, "difficulty": 1.29, "author": "love_____xoxo", "desc": "The ages of a father and son add up to 66. The digits of the father's age are those of son's age reversed.\n\r\nHow old could they be? (3 possible solutions.)", "hint": "No hint available.", "answer": "42 and 24, 51 and 15, or 60 and 06.", "category": "Math", "date": "09/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe ages of a father and son add up to 66. The digits of the father's age are those of son's age reversed.\n\r\nHow old could they be? (3 possible solutions.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n42 and 24, 51 and 15, or 60 and 06.\n<|im_start|>answer\n42 and 24, 51 and 15, or 60 and 06.\n<|im_end|>" }, { "id": "#36650", "title": "Passes", "fun": 2.44, "difficulty": 1.81, "author": "pokpic", "desc": "The Timberland Tigers coach gave his 14 players jerseys numbered 0 to 13. He then told them to stand in numerical order from 0 to 13 in a circle, and he gave the ball to the player wearing the number 0. He told them to pass it to the person 3 numbers ahead of them. For example, if I was number 6 and I got the ball, I would pass it to number 9. After 120 passes the coach told them to take a rest. Who had the ball when they stopped?", "hint": "No hint available.", "answer": "Number 10 had the ball when they stopped because every 14 passes it get backs to zero. If you divide 120 by 14 you get 8 remainder 8. Then you use that extra remainder as 8 passes to get #10.", "category": "Math", "date": "05/17/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Timberland Tigers coach gave his 14 players jerseys numbered 0 to 13. He then told them to stand in numerical order from 0 to 13 in a circle, and he gave the ball to the player wearing the number 0. He told them to pass it to the person 3 numbers ahead of them. For example, if I was number 6 and I got the ball, I would pass it to number 9. After 120 passes the coach told them to take a rest. Who had the ball when they stopped?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNumber 10 had the ball when they stopped because every 14 passes it get backs to zero. If you divide 120 by 14 you get 8 remainder 8. Then you use that extra remainder as 8 passes to get #10.\n<|im_start|>answer\nNumber 10 had the ball when they stopped because every 14 passes it get backs to zero. If you divide 120 by 14 you get 8 remainder 8. Then you use that extra remainder as 8 passes to get #10.\n<|im_end|>" }, { "id": "#35457", "title": "Opposites 25", "fun": 2.44, "difficulty": 2.26, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n@ stands for E, M, J, O, or A\r\n% stands for R, L, A, C, or Y\r\n$ stands for G, W, F, A, or R\r\n) stands for R, Q, U, S, or E\n\r\nThe four letter code word, $@%), can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Fore and Rear.", "category": "Logic", "date": "02/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n@ stands for E, M, J, O, or A\r\n% stands for R, L, A, C, or Y\r\n$ stands for G, W, F, A, or R\r\n) stands for R, Q, U, S, or E\n\r\nThe four letter code word, $@%), can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFore and Rear.\n<|im_start|>answer\nFore and Rear.\n<|im_end|>" }, { "id": "#40727", "title": "Vandals", "fun": 2.44, "difficulty": 1.27, "author": "Carlos16", "desc": "Three people are accused of vandalizing a police car, but possibly they aren't all guilty.\r\nGuilty people are lying, while innocent people tell the truth. Who was/were the vandal(s)?\n\r\nLarry says: \"More than one of us vandalized the car.\"\r\nGary says: \"Larry and Jerry did it.\"\r\nJerry says: \"All three of us are guilty.\"", "hint": "No hint available.", "answer": "If Larry is lying, then the vandal has to be Larry alone. That means Jerry and Gary are telling the truth, but that would create contradictions. That means Larry must be telling the truth for there to be no contradictions. Since Larry is telling the truth, more than one person vandalized the car. Since it can't be Larry, it has to be Gary and Jerry.\n\r\nAnswer: Gary and Jerry", "category": "Logic", "date": "02/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people are accused of vandalizing a police car, but possibly they aren't all guilty.\r\nGuilty people are lying, while innocent people tell the truth. Who was/were the vandal(s)?\n\r\nLarry says: \"More than one of us vandalized the car.\"\r\nGary says: \"Larry and Jerry did it.\"\r\nJerry says: \"All three of us are guilty.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Larry is lying, then the vandal has to be Larry alone. That means Jerry and Gary are telling the truth, but that would create contradictions. That means Larry must be telling the truth for there to be no contradictions. Since Larry is telling the truth, more than one person vandalized the car. Since it can't be Larry, it has to be Gary and Jerry.\n\r\nAnswer: Gary and Jerry\n<|im_start|>answer\nIf Larry is lying, then the vandal has to be Larry alone. That means Jerry and Gary are telling the truth, but that would create contradictions. That means Larry must be telling the truth for there to be no contradictions. Since Larry is telling the truth, more than one person vandalized the car. Since it can't be Larry, it has to be Gary and Jerry.\n\r\nAnswer: Gary and Jerry\n<|im_end|>" }, { "id": "#42709", "title": "How to Cross the River", "fun": 2.44, "difficulty": 2.15, "author": "GrayPanther", "desc": "A father, a mother, 2 sons, 2 daughters, a guard and a prisoner want to cross the river.\n\r\n1. The raft can carry only 2 people.\n\r\n2. The father can not be left with any of the daughters unless the mother is present\n\r\n3. The mother can not be left with any of the sons unless the father is present.\n\r\n4. The criminal can not stay with any family member unless the guard is present.\n\r\n5. Only the father, mother, and guard know how to use the raft.", "hint": "No hint available.", "answer": "cross. Guard + Prisoner\r\nback. Guard\r\ncross. Guard + Girl\r\nback. Guard + Prisoner\r\ncross. Mother + Girl\r\nback. Mother\r\ncross. Mother + Father\r\nback. Father\r\ncross. Guard + Prisoner\r\nback. Mother\r\ncross. Father + Mother\r\nback. Father\r\ncross. Father + Boy\r\nback. Guard + Prisoner\r\ncross. Guard + Boy\r\nback. Guard\r\ncross. Guard + Prisoner", "category": "Logic", "date": "08/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA father, a mother, 2 sons, 2 daughters, a guard and a prisoner want to cross the river.\n\r\n1. The raft can carry only 2 people.\n\r\n2. The father can not be left with any of the daughters unless the mother is present\n\r\n3. The mother can not be left with any of the sons unless the father is present.\n\r\n4. The criminal can not stay with any family member unless the guard is present.\n\r\n5. Only the father, mother, and guard know how to use the raft.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\ncross. Guard + Prisoner\r\nback. Guard\r\ncross. Guard + Girl\r\nback. Guard + Prisoner\r\ncross. Mother + Girl\r\nback. Mother\r\ncross. Mother + Father\r\nback. Father\r\ncross. Guard + Prisoner\r\nback. Mother\r\ncross. Father + Mother\r\nback. Father\r\ncross. Father + Boy\r\nback. Guard + Prisoner\r\ncross. Guard + Boy\r\nback. Guard\r\ncross. Guard + Prisoner\n<|im_start|>answer\ncross. Guard + Prisoner\r\nback. Guard\r\ncross. Guard + Girl\r\nback. Guard + Prisoner\r\ncross. Mother + Girl\r\nback. Mother\r\ncross. Mother + Father\r\nback. Father\r\ncross. Guard + Prisoner\r\nback. Mother\r\ncross. Father + Mother\r\nback. Father\r\ncross. Father + Boy\r\nback. Guard + Prisoner\r\ncross. Guard + Boy\r\nback. Guard\r\ncross. Guard + Prisoner\n<|im_end|>" }, { "id": "#3579", "title": "Tricky Maths Symbols", "fun": 2.44, "difficulty": 2.85, "author": "cathalmccabe", "desc": "Each symbol represents one and only one of the numbers from 1-9 inclusive.\r\nAll the terms are added except the last one, which is a multiplication # * $ = &$.\n\r\n&$ is a double digit number.\r\nSolve :\n\n\r\n\\ + > = &$\r\n^ + % = &$\r\n? + > + @ =&$\r\n\\ + ^ + & = &$\r\n# + ? + ^ = &$\r\n# MULTIPLIED by $ = &$", "hint": "Need to use a lot of logical thinking and deduction: For a start: if \\ + > are the biggest numbers possible, 9 and 8, the &$ = 17\r\n& is non zero so it must be 1\r\n& = 1", "answer": "To check your answer:\n\r\n1 = &\r\n2 = @\r\n3 = #\r\n4 = ?\r\n5 = $\r\n6 = \\\r\n7 = %\r\n8= ^\r\n9 = >\n\n\n\r\n6 + 9 = 15\r\n8 + 7 = 15\r\n4 + 9 + 2 = 15\r\n6 + 8 + 1 = 15\r\n3 + 4 + 8 = 15\r\n3*5 = 15\n\r\nFor a complete solution:\n\r\n\t\\ + > = &$\r\n\t^ + % = &$\r\nStarting with the sums with only two terms; because two terms added together can only have a maximum of (9+8)= 17 and the first digit of &$ is non-zero, so the minimum is 12\r\nTherefore & is 1\n\r\n\t# MULTIPLIED by $ = &$\r\nsomething multiplied by something else must be between 17 and 11 (from above)\r\nThere are only a few combinations, but only one possibility here\r\n2 * 6 = 12\r\n2 * 7 = 14\r\n2 * 8 = 16\n\r\n3 * 4 = 12\r\n3 * 5 = 15\r\nThe second multiplying term is equal to the second digit of the answer = 5\n\r\nTherefore # is 3 and $ is 5\n\r\nFilling in what's known:\r\n\\ + > = 15\r\n^ + % = 15\r\n? + > + @ = 15\r\n\\ + ^ + 1 = 15\r\n3 + ? + ^ = 15\n\r\n\t\\ + > = 15\r\n\t^ + % = 15\n\r\nThese symbols must be 6, 7, 8, 9 because otherwise a result of 15 can't be got.\r\nThey must be either 9 + 6 or 7 + 8 in some order.\n\r\n\t\\ + ^ + 1 = 15\r\n\\ + ^ = 14 they can't be 9 (because 5 is already known.)\r\nSo they must be 8 and 6 in some order.\r\nThat also means > and % must be 7 and 9 in some order.\n\r\n? and @ must be 2 and 4 in some order (They are the only symbols left for the only two numbers), and ? + @ = 6\n\r\n\t? + > + @ = 15\r\nThat means > must be 9\n\r\n\t\\ + > = 15\r\nThat means \\ = 6\r\n\t\\ + ^ = 14\r\n^ is equal to 8\r\nand % = 7\n\r\nFilling in what's known again:\r\n6+ 9 = 15\r\n8 + 7 = 15\r\n? + 9 + @ = 15\r\n6 + 8 + 1 = 15\r\n3 + ? + 8 = 15\n\r\n? must be 4\r\nand therfore @ = 2\n\n\r\n1 = &\r\n2 = @\r\n3 = #\r\n4 = ?\r\n5 = $\r\n6 = \\\r\n7 = %\r\n8= ^\r\n9 = >\n\n\n\r\n6 + 9 = 15\r\n8 + 7 = 15\r\n4 + 9 + 2 = 15\r\n6 + 8 + 1 = 15\r\n3 + 4 + 8 = 15\r\n3*5 = 15", "category": "Math", "date": "04/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach symbol represents one and only one of the numbers from 1-9 inclusive.\r\nAll the terms are added except the last one, which is a multiplication # * $ = &$.\n\r\n&$ is a double digit number.\r\nSolve :\n\n\r\n\\ + > = &$\r\n^ + % = &$\r\n? + > + @ =&$\r\n\\ + ^ + & = &$\r\n# + ? + ^ = &$\r\n# MULTIPLIED by $ = &$\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo check your answer:\n\r\n1 = &\r\n2 = @\r\n3 = #\r\n4 = ?\r\n5 = $\r\n6 = \\\r\n7 = %\r\n8= ^\r\n9 = >\n\n\n\r\n6 + 9 = 15\r\n8 + 7 = 15\r\n4 + 9 + 2 = 15\r\n6 + 8 + 1 = 15\r\n3 + 4 + 8 = 15\r\n3*5 = 15\n\r\nFor a complete solution:\n\r\n\t\\ + > = &$\r\n\t^ + % = &$\r\nStarting with the sums with only two terms; because two terms added together can only have a maximum of (9+8)= 17 and the first digit of &$ is non-zero, so the minimum is 12\r\nTherefore & is 1\n\r\n\t# MULTIPLIED by $ = &$\r\nsomething multiplied by something else must be between 17 and 11 (from above)\r\nThere are only a few combinations, but only one possibility here\r\n2 * 6 = 12\r\n2 * 7 = 14\r\n2 * 8 = 16\n\r\n3 * 4 = 12\r\n3 * 5 = 15\r\nThe second multiplying term is equal to the second digit of the answer = 5\n\r\nTherefore # is 3 and $ is 5\n\r\nFilling in what's known:\r\n\\ + > = 15\r\n^ + % = 15\r\n? + > + @ = 15\r\n\\ + ^ + 1 = 15\r\n3 + ? + ^ = 15\n\r\n\t\\ + > = 15\r\n\t^ + % = 15\n\r\nThese symbols must be 6, 7, 8, 9 because otherwise a result of 15 can't be got.\r\nThey must be either 9 + 6 or 7 + 8 in some order.\n\r\n\t\\ + ^ + 1 = 15\r\n\\ + ^ = 14 they can't be 9 (because 5 is already known.)\r\nSo they must be 8 and 6 in some order.\r\nThat also means > and % must be 7 and 9 in some order.\n\r\n? and @ must be 2 and 4 in some order (They are the only symbols left for the only two numbers), and ? + @ = 6\n\r\n\t? + > + @ = 15\r\nThat means > must be 9\n\r\n\t\\ + > = 15\r\nThat means \\ = 6\r\n\t\\ + ^ = 14\r\n^ is equal to 8\r\nand % = 7\n\r\nFilling in what's known again:\r\n6+ 9 = 15\r\n8 + 7 = 15\r\n? + 9 + @ = 15\r\n6 + 8 + 1 = 15\r\n3 + ? + 8 = 15\n\r\n? must be 4\r\nand therfore @ = 2\n\n\r\n1 = &\r\n2 = @\r\n3 = #\r\n4 = ?\r\n5 = $\r\n6 = \\\r\n7 = %\r\n8= ^\r\n9 = >\n\n\n\r\n6 + 9 = 15\r\n8 + 7 = 15\r\n4 + 9 + 2 = 15\r\n6 + 8 + 1 = 15\r\n3 + 4 + 8 = 15\r\n3*5 = 15\n<|im_start|>answer\nTo check your answer:\n\r\n1 = &\r\n2 = @\r\n3 = #\r\n4 = ?\r\n5 = $\r\n6 = \\\r\n7 = %\r\n8= ^\r\n9 = >\n\n\n\r\n6 + 9 = 15\r\n8 + 7 = 15\r\n4 + 9 + 2 = 15\r\n6 + 8 + 1 = 15\r\n3 + 4 + 8 = 15\r\n3*5 = 15\n\r\nFor a complete solution:\n\r\n\t\\ + > = &$\r\n\t^ + % = &$\r\nStarting with the sums with only two terms; because two terms added together can only have a maximum of (9+8)= 17 and the first digit of &$ is non-zero, so the minimum is 12\r\nTherefore & is 1\n\r\n\t# MULTIPLIED by $ = &$\r\nsomething multiplied by something else must be between 17 and 11 (from above)\r\nThere are only a few combinations, but only one possibility here\r\n2 * 6 = 12\r\n2 * 7 = 14\r\n2 * 8 = 16\n\r\n3 * 4 = 12\r\n3 * 5 = 15\r\nThe second multiplying term is equal to the second digit of the answer = 5\n\r\nTherefore # is 3 and $ is 5\n\r\nFilling in what's known:\r\n\\ + > = 15\r\n^ + % = 15\r\n? + > + @ = 15\r\n\\ + ^ + 1 = 15\r\n3 + ? + ^ = 15\n\r\n\t\\ + > = 15\r\n\t^ + % = 15\n\r\nThese symbols must be 6, 7, 8, 9 because otherwise a result of 15 can't be got.\r\nThey must be either 9 + 6 or 7 + 8 in some order.\n\r\n\t\\ + ^ + 1 = 15\r\n\\ + ^ = 14 they can't be 9 (because 5 is already known.)\r\nSo they must be 8 and 6 in some order.\r\nThat also means > and % must be 7 and 9 in some order.\n\r\n? and @ must be 2 and 4 in some order (They are the only symbols left for the only two numbers), and ? + @ = 6\n\r\n\t? + > + @ = 15\r\nThat means > must be 9\n\r\n\t\\ + > = 15\r\nThat means \\ = 6\r\n\t\\ + ^ = 14\r\n^ is equal to 8\r\nand % = 7\n\r\nFilling in what's known again:\r\n6+ 9 = 15\r\n8 + 7 = 15\r\n? + 9 + @ = 15\r\n6 + 8 + 1 = 15\r\n3 + ? + 8 = 15\n\r\n? must be 4\r\nand therfore @ = 2\n\n\r\n1 = &\r\n2 = @\r\n3 = #\r\n4 = ?\r\n5 = $\r\n6 = \\\r\n7 = %\r\n8= ^\r\n9 = >\n\n\n\r\n6 + 9 = 15\r\n8 + 7 = 15\r\n4 + 9 + 2 = 15\r\n6 + 8 + 1 = 15\r\n3 + 4 + 8 = 15\r\n3*5 = 15\n<|im_end|>" }, { "id": "#7257", "title": "A clock", "fun": 2.44, "difficulty": 1.86, "author": "warrior", "desc": "How many times do all the hands on a clock go around in an hour?", "hint": "No hint available.", "answer": "Second hand=60\r\nMinute hand=1\r\nHour hand=1/12\n\r\ntotal: 61.083333", "category": "Math", "date": "09/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many times do all the hands on a clock go around in an hour?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSecond hand=60\r\nMinute hand=1\r\nHour hand=1/12\n\r\ntotal: 61.083333\n<|im_start|>answer\nSecond hand=60\r\nMinute hand=1\r\nHour hand=1/12\n\r\ntotal: 61.083333\n<|im_end|>" }, { "id": "#448", "title": "How Far can a Dog Run", "fun": 2.44, "difficulty": 1.18, "author": "Sydgal47", "desc": "How far can a dog run into the woods?", "hint": "No hint available.", "answer": "Only halfway. If it runs more, then it would be running out of the woods.", "category": "Logic", "date": "05/07/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow far can a dog run into the woods?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOnly halfway. If it runs more, then it would be running out of the woods.\n<|im_start|>answer\nOnly halfway. If it runs more, then it would be running out of the woods.\n<|im_end|>" }, { "id": "#5096", "title": "A Day at the Beach", "fun": 2.44, "difficulty": 1.66, "author": "peppermintwist", "desc": "During summer vacation, four children, Alex, Belinda, Eric, and the eldest child, spend their days at the beach. One day at lunch their mother asks: 'Did anyone go surfing this morning?'\n\r\nThe eldest child answers:\n\r\nI wasn't paying very close attention to the others, but I think Alex and Belinda weren't together.\n\r\nHowever, if Alex did go surfing, it wasn't alone.\n\r\nIf Eric surfed, Alex and Belinda were with him.\n\r\nWho went surfing?", "hint": "No hint available.", "answer": "The eldest child", "category": "Logic", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring summer vacation, four children, Alex, Belinda, Eric, and the eldest child, spend their days at the beach. One day at lunch their mother asks: 'Did anyone go surfing this morning?'\n\r\nThe eldest child answers:\n\r\nI wasn't paying very close attention to the others, but I think Alex and Belinda weren't together.\n\r\nHowever, if Alex did go surfing, it wasn't alone.\n\r\nIf Eric surfed, Alex and Belinda were with him.\n\r\nWho went surfing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe eldest child\n<|im_start|>answer\nThe eldest child\n<|im_end|>" }, { "id": "#5979", "title": "Circular Socket", "fun": 2.44, "difficulty": 2.25, "author": "mad-ade", "desc": "Mad Ade has just purchased himself a second hand Automatic kebab rolling machine (made in Madadia, at the world famous \"Botulism Bros.\" factory). At the back of the machine is an electrical cable with a quite strange plug. The plug has 7 prongs arranged in a circle, which matches the socket on the wall, thus allowing the plug to be rotated and inserted in 7 different ways. Each prong of the plug is numbered from 1 to 7. The holes in the socket are also numbered, but can be switched around. To make the Kebab machine work only one plug prong has to fit in the corresponding hole of the socket. How can Mad Ade Number the socket holes in such a manner that no matter how the plug is inserted, at least one prong will fit into the correctly numbered hole in the socket?", "hint": "No hint available.", "answer": "The prongs on the plug are already marked with consecutive numbers: 1, 2, 3, 4, 5, 6, 7. Number the holes in the socket clockwise, with every other number, then wrapping back around: 1, 3, 5, 7, 2, 4, 6. This ensures at least one correct connection no matter how the plug is inserted.", "category": "Logic", "date": "07/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has just purchased himself a second hand Automatic kebab rolling machine (made in Madadia, at the world famous \"Botulism Bros.\" factory). At the back of the machine is an electrical cable with a quite strange plug. The plug has 7 prongs arranged in a circle, which matches the socket on the wall, thus allowing the plug to be rotated and inserted in 7 different ways. Each prong of the plug is numbered from 1 to 7. The holes in the socket are also numbered, but can be switched around. To make the Kebab machine work only one plug prong has to fit in the corresponding hole of the socket. How can Mad Ade Number the socket holes in such a manner that no matter how the plug is inserted, at least one prong will fit into the correctly numbered hole in the socket?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe prongs on the plug are already marked with consecutive numbers: 1, 2, 3, 4, 5, 6, 7. Number the holes in the socket clockwise, with every other number, then wrapping back around: 1, 3, 5, 7, 2, 4, 6. This ensures at least one correct connection no matter how the plug is inserted.\n<|im_start|>answer\nThe prongs on the plug are already marked with consecutive numbers: 1, 2, 3, 4, 5, 6, 7. Number the holes in the socket clockwise, with every other number, then wrapping back around: 1, 3, 5, 7, 2, 4, 6. This ensures at least one correct connection no matter how the plug is inserted.\n<|im_end|>" }, { "id": "#38062", "title": "How Much Money 2", "fun": 2.44, "difficulty": 1.98, "author": "maxvu", "desc": "How much money would I have had if, in spending 1/5 and then 1/5 of the remaining, I had altogether spent $36.00?", "hint": "No hint available.", "answer": "$100.", "category": "Math", "date": "09/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow much money would I have had if, in spending 1/5 and then 1/5 of the remaining, I had altogether spent $36.00?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$100.\n<|im_start|>answer\n$100.\n<|im_end|>" }, { "id": "#34465", "title": "Segments in a Circle", "fun": 2.44, "difficulty": 2.52, "author": "t4mt", "desc": "3 lines can divide a circle into a maximum of 7 regions. What is the greatest number of regions that 100 lines can divide a circle into?", "hint": "Try to notice a pattern:\n\r\nIf there are 4 lines, there can be at most 11 regions.\r\nIf there are 5 lines, there can be at most 16 regions.\r\nIf there are 6 lines, there can be at most 22 regions.", "answer": "5051.\n\r\nNotice that 100+99+98...+3+2+1=5050, one less from 5051, and 3+2+1=6, one less from the maximum number of regions when there are 3 lines.", "category": "Math", "date": "12/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n3 lines can divide a circle into a maximum of 7 regions. What is the greatest number of regions that 100 lines can divide a circle into?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5051.\n\r\nNotice that 100+99+98...+3+2+1=5050, one less from 5051, and 3+2+1=6, one less from the maximum number of regions when there are 3 lines.\n<|im_start|>answer\n5051.\n\r\nNotice that 100+99+98...+3+2+1=5050, one less from 5051, and 3+2+1=6, one less from the maximum number of regions when there are 3 lines.\n<|im_end|>" }, { "id": "#17551", "title": "Playing Ball", "fun": 2.44, "difficulty": 1.84, "author": "Jake", "desc": "Five friends (Bobby, Isaac, Isabel, Mimi and Shane) are participating in a baseball game with some other people. Each friend plays a different position (First base, Pitcher, Shortstop, Catcher, Right field) and makes a different number of hits (1,2,3,4 or 5). From the clues can you figure out who did what?\n\r\nClues:\r\n1) Bobby, the furthest from home base, had exactly twice as many hits as the pitcher.\r\n2) The shortstop was tired after getting her fifth hit.\r\n3) Shane had more hits than all the other infielders except for Isabel.\r\n4) Isaac wears a mask.", "hint": "No hint available.", "answer": "From clue 1 we know that Bobby is the right fielder and that he got 4 hits and the pitcher got 2 hits.\n\r\nFrom clue 2 we know that the shortstop is a woman (Mimi or Isabel) and that she got 5 hits.\n\r\nFrom clue 3 we know that Shane had 3 hits and Isabel had 5. This means that Isabel is the shortstop (see clue 2).\n\r\nFrom clue 4 we know that Isaac is the catcher.\n\r\nSince we already know that Shane had 3 hits and the pitcher had 2, Shane cannot be the pitcher. The only position left for him is first base, which leaves Mimi as the pitcher. \n\r\nNow we know everything:\n\n\r\nBobby is the right fielder and he got 4 hits.\r\nIsaac is the catcher and he got 1 hit.\r\nIsabel is the shortstop and she got 5 hits.\r\nMimi is the pitcher and she got 2 hits.\r\nShane is the first baseman and he got 3 hits.", "category": "Logic", "date": "05/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends (Bobby, Isaac, Isabel, Mimi and Shane) are participating in a baseball game with some other people. Each friend plays a different position (First base, Pitcher, Shortstop, Catcher, Right field) and makes a different number of hits (1,2,3,4 or 5). From the clues can you figure out who did what?\n\r\nClues:\r\n1) Bobby, the furthest from home base, had exactly twice as many hits as the pitcher.\r\n2) The shortstop was tired after getting her fifth hit.\r\n3) Shane had more hits than all the other infielders except for Isabel.\r\n4) Isaac wears a mask.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom clue 1 we know that Bobby is the right fielder and that he got 4 hits and the pitcher got 2 hits.\n\r\nFrom clue 2 we know that the shortstop is a woman (Mimi or Isabel) and that she got 5 hits.\n\r\nFrom clue 3 we know that Shane had 3 hits and Isabel had 5. This means that Isabel is the shortstop (see clue 2).\n\r\nFrom clue 4 we know that Isaac is the catcher.\n\r\nSince we already know that Shane had 3 hits and the pitcher had 2, Shane cannot be the pitcher. The only position left for him is first base, which leaves Mimi as the pitcher. \n\r\nNow we know everything:\n\n\r\nBobby is the right fielder and he got 4 hits.\r\nIsaac is the catcher and he got 1 hit.\r\nIsabel is the shortstop and she got 5 hits.\r\nMimi is the pitcher and she got 2 hits.\r\nShane is the first baseman and he got 3 hits.\n<|im_start|>answer\nFrom clue 1 we know that Bobby is the right fielder and that he got 4 hits and the pitcher got 2 hits.\n\r\nFrom clue 2 we know that the shortstop is a woman (Mimi or Isabel) and that she got 5 hits.\n\r\nFrom clue 3 we know that Shane had 3 hits and Isabel had 5. This means that Isabel is the shortstop (see clue 2).\n\r\nFrom clue 4 we know that Isaac is the catcher.\n\r\nSince we already know that Shane had 3 hits and the pitcher had 2, Shane cannot be the pitcher. The only position left for him is first base, which leaves Mimi as the pitcher. \n\r\nNow we know everything:\n\n\r\nBobby is the right fielder and he got 4 hits.\r\nIsaac is the catcher and he got 1 hit.\r\nIsabel is the shortstop and she got 5 hits.\r\nMimi is the pitcher and she got 2 hits.\r\nShane is the first baseman and he got 3 hits.\n<|im_end|>" }, { "id": "#23930", "title": "Golf House Mischief", "fun": 2.44, "difficulty": 1.33, "author": "katey", "desc": "Five men, whose names are Bob Edison, Tom Stevenson, Marty Brown, Jim Davis, and John Alberts were being questioned by the police for a crime committed in their local golf house.\n\r\nOther detectives have already investigated, they have questioned the suspects, the witnesses, and people who know the suspects and they have collected physical evidence from the crime scene. They have collected the following 14 clues, but have not been able to solve the crime. Therefore, they have called in the world's greatest detective: YOU, who must now examine the clues and solve the crime for them and find the culprit. \n\r\nNo two suspects have the same hair colour, weight, height, wife's first name, or colour shoes.\r\nThe suspect who has red hair weighs 140 pounds.\r\nBob Edison is 5 feet 3 inches tall.\r\nThe culprit has a wife named Mary.\r\nThe suspect who weighs 150 pounds is not the one who is 5 feet 9 inches tall.\r\nThe suspect who has a wife named Pam is not the one who has blonde hair.\r\nJim Davis was wearing orange shoes.\r\nJohn Alberts has black hair.\r\nThe suspect who has a wife named Betty weighs 200 pounds.\r\nTom Stevenson weighs 210 pounds.\r\nThe suspect who weighs 200 pounds has no hair.\r\nThe suspect who has a wife named Cathy weighs 140 pounds.\r\nMarty Brown has brown hair.\r\nThe suspect who has black hair has a wife named Mary.\r\nThe suspect who has no hair is not the one who was wearing orange shoes.", "hint": "No hint available.", "answer": "John Alberts: John Alberts has black hair and the suspect who has black hair has a wife named Mary. Therefore, John Alberts has a wife named Mary. The culprit has a wife named Mary, so John Alberts is the culprit.", "category": "Logic", "date": "06/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive men, whose names are Bob Edison, Tom Stevenson, Marty Brown, Jim Davis, and John Alberts were being questioned by the police for a crime committed in their local golf house.\n\r\nOther detectives have already investigated, they have questioned the suspects, the witnesses, and people who know the suspects and they have collected physical evidence from the crime scene. They have collected the following 14 clues, but have not been able to solve the crime. Therefore, they have called in the world's greatest detective: YOU, who must now examine the clues and solve the crime for them and find the culprit. \n\r\nNo two suspects have the same hair colour, weight, height, wife's first name, or colour shoes.\r\nThe suspect who has red hair weighs 140 pounds.\r\nBob Edison is 5 feet 3 inches tall.\r\nThe culprit has a wife named Mary.\r\nThe suspect who weighs 150 pounds is not the one who is 5 feet 9 inches tall.\r\nThe suspect who has a wife named Pam is not the one who has blonde hair.\r\nJim Davis was wearing orange shoes.\r\nJohn Alberts has black hair.\r\nThe suspect who has a wife named Betty weighs 200 pounds.\r\nTom Stevenson weighs 210 pounds.\r\nThe suspect who weighs 200 pounds has no hair.\r\nThe suspect who has a wife named Cathy weighs 140 pounds.\r\nMarty Brown has brown hair.\r\nThe suspect who has black hair has a wife named Mary.\r\nThe suspect who has no hair is not the one who was wearing orange shoes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn Alberts: John Alberts has black hair and the suspect who has black hair has a wife named Mary. Therefore, John Alberts has a wife named Mary. The culprit has a wife named Mary, so John Alberts is the culprit.\n<|im_start|>answer\nJohn Alberts: John Alberts has black hair and the suspect who has black hair has a wife named Mary. Therefore, John Alberts has a wife named Mary. The culprit has a wife named Mary, so John Alberts is the culprit.\n<|im_end|>" }, { "id": "#43235", "title": "Alien Feet", "fun": 2.43, "difficulty": 1.26, "author": "getoffursausage", "desc": "BREAKING NEWS!\n\r\nA Mars probe sent from Earth has disturbed a colony of Martians. They have come to Earth and have taken over our planet. The Martian leader has decided to change the unit of length used in the United States from 12 inches in a foot to 10 inches in a foot because the Martian's foot is only 10 inches long. \n\r\nThe Martians are allowing the United States to keep the mile the same length as before so that no new road signs and mile markers have to be created. Now that the Martians have taken over our planet, how many feet are in one mile?", "hint": "In the original mile there are 5,280 feet.", "answer": "6,336 feet.\n\r\nIn the original mile there are 5,280 feet. That means that there were 63,360 inches in a mile (5,280x12).\n\r\nThere are still 63,360 inches in a mile because the inches and overall length of the mile are unchanged. Because there are 10 inches in a foot, divide 63,360 by 10. This will give you the new amount of feet in a mile--6,336!", "category": "Math", "date": "10/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBREAKING NEWS!\n\r\nA Mars probe sent from Earth has disturbed a colony of Martians. They have come to Earth and have taken over our planet. The Martian leader has decided to change the unit of length used in the United States from 12 inches in a foot to 10 inches in a foot because the Martian's foot is only 10 inches long. \n\r\nThe Martians are allowing the United States to keep the mile the same length as before so that no new road signs and mile markers have to be created. Now that the Martians have taken over our planet, how many feet are in one mile?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6,336 feet.\n\r\nIn the original mile there are 5,280 feet. That means that there were 63,360 inches in a mile (5,280x12).\n\r\nThere are still 63,360 inches in a mile because the inches and overall length of the mile are unchanged. Because there are 10 inches in a foot, divide 63,360 by 10. This will give you the new amount of feet in a mile--6,336!\n<|im_start|>answer\n6,336 feet.\n\r\nIn the original mile there are 5,280 feet. That means that there were 63,360 inches in a mile (5,280x12).\n\r\nThere are still 63,360 inches in a mile because the inches and overall length of the mile are unchanged. Because there are 10 inches in a foot, divide 63,360 by 10. This will give you the new amount of feet in a mile--6,336!\n<|im_end|>" }, { "id": "#43804", "title": "Rex and Ralph: Daughter Multiplication", "fun": 2.43, "difficulty": 2.94, "author": "javaguru", "desc": "Two mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Rex thinks he may finally get Ralph with his latest. Rex tells Ralph that he has four daughters, ages seven to twenty-three.\n\r\n\"Multiply each of my daughter's age by each of her three sisters' ages. For each daughter, take the product of the three resulting numbers. Then take the product of these four results. Divide this total by the product of the four daughter's ages and discard the fractional portion. Next subtract the product of the four daughter's ages. Now divide this value by 10.\"\n\r\n\"What is the remainder?\" Rex asks.\n\r\nRalph thinks about this for about a minute before answering.\n\r\nRex is disappointed that he has once again failed to stump Ralph.\n\r\nWhat was Ralph's answer?", "hint": "There will be no fractional portion to discard.\n\r\nOh, and the ages of Rex's daughters are irrelevant.", "answer": "Zero.\n\r\nChoose four positive integers, A, B, C and D.\n\r\nStep 1 yields:\r\nA: AB, AC, AD\r\nB: BA, BC, BD\r\nC: CA, CB, CD\r\nD: DA, DB, DC\n\r\nStep 2 yields:\r\nA: (A^3)BCD\r\nB: (B^3)ACD\r\nC: (C^3)ABD\r\nD: (D^3)ABC\n\r\nStep 3 yields:\r\n(ABCD)^6\n\r\nStep 4 yields:\r\n((ABCD)^6)/(ABCD) = (ABCD)^5\n\r\nFor any positive integer x, x mod 10 = (x^5) mod 10. Therefore,\n\r\n(ABCD)^5 mod 10 = (ABCD) mod 10\n\r\nand \n\r\n((ABCD)^5 - (ABCD)) mod 10 = 0", "category": "Math", "date": "12/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Rex thinks he may finally get Ralph with his latest. Rex tells Ralph that he has four daughters, ages seven to twenty-three.\n\r\n\"Multiply each of my daughter's age by each of her three sisters' ages. For each daughter, take the product of the three resulting numbers. Then take the product of these four results. Divide this total by the product of the four daughter's ages and discard the fractional portion. Next subtract the product of the four daughter's ages. Now divide this value by 10.\"\n\r\n\"What is the remainder?\" Rex asks.\n\r\nRalph thinks about this for about a minute before answering.\n\r\nRex is disappointed that he has once again failed to stump Ralph.\n\r\nWhat was Ralph's answer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZero.\n\r\nChoose four positive integers, A, B, C and D.\n\r\nStep 1 yields:\r\nA: AB, AC, AD\r\nB: BA, BC, BD\r\nC: CA, CB, CD\r\nD: DA, DB, DC\n\r\nStep 2 yields:\r\nA: (A^3)BCD\r\nB: (B^3)ACD\r\nC: (C^3)ABD\r\nD: (D^3)ABC\n\r\nStep 3 yields:\r\n(ABCD)^6\n\r\nStep 4 yields:\r\n((ABCD)^6)/(ABCD) = (ABCD)^5\n\r\nFor any positive integer x, x mod 10 = (x^5) mod 10. Therefore,\n\r\n(ABCD)^5 mod 10 = (ABCD) mod 10\n\r\nand \n\r\n((ABCD)^5 - (ABCD)) mod 10 = 0\n<|im_start|>answer\nZero.\n\r\nChoose four positive integers, A, B, C and D.\n\r\nStep 1 yields:\r\nA: AB, AC, AD\r\nB: BA, BC, BD\r\nC: CA, CB, CD\r\nD: DA, DB, DC\n\r\nStep 2 yields:\r\nA: (A^3)BCD\r\nB: (B^3)ACD\r\nC: (C^3)ABD\r\nD: (D^3)ABC\n\r\nStep 3 yields:\r\n(ABCD)^6\n\r\nStep 4 yields:\r\n((ABCD)^6)/(ABCD) = (ABCD)^5\n\r\nFor any positive integer x, x mod 10 = (x^5) mod 10. Therefore,\n\r\n(ABCD)^5 mod 10 = (ABCD) mod 10\n\r\nand \n\r\n((ABCD)^5 - (ABCD)) mod 10 = 0\n<|im_end|>" }, { "id": "#48266", "title": "The Music Recital", "fun": 2.43, "difficulty": 1.78, "author": "legotboy", "desc": "At a musical recital five students (Zak, Rachel, Jeremy, Jessi, and Michael) performed five musical pieces. Two by Bach, two by Mozart and one by Vivaldi. There were three violinists and two pianists. Each student performed only one piece, and played only one instrument. Find the order of the students, their respective instruments and the composer, with the following conditions:\n\r\n1.The composers were not played consecutively.\n\r\n2. Vivaldi was played last and Mozart was played first.\n\r\n3. There was one piano piece that was played between two violin pieces, and two violin pieces between the first and last piano piece.\n\r\n4. There were no piano pieces by Mozart.\n\r\n5. Rachel played third.\n\r\n6. Michael played the piano, and immediately followed Zak, who played a piece by Mozart.: \n\r\n7. Jessi did not play a piece by Vivaldi", "hint": "No hint available.", "answer": "First, Zak played a piece by Mozart on the violin.\n\r\nSecond, Michael played a piece by Bach on the piano.\n\r\nThird, Rachel played a piece by Mozart on the violin.\n\r\nFourth, Jessi played a piece by Bach on the violin.\n\r\nFifth, Jeremy played a piece by Vivaldi on the piano.", "category": "Logic-Grid", "date": "12/05/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a musical recital five students (Zak, Rachel, Jeremy, Jessi, and Michael) performed five musical pieces. Two by Bach, two by Mozart and one by Vivaldi. There were three violinists and two pianists. Each student performed only one piece, and played only one instrument. Find the order of the students, their respective instruments and the composer, with the following conditions:\n\r\n1.The composers were not played consecutively.\n\r\n2. Vivaldi was played last and Mozart was played first.\n\r\n3. There was one piano piece that was played between two violin pieces, and two violin pieces between the first and last piano piece.\n\r\n4. There were no piano pieces by Mozart.\n\r\n5. Rachel played third.\n\r\n6. Michael played the piano, and immediately followed Zak, who played a piece by Mozart.: \n\r\n7. Jessi did not play a piece by Vivaldi\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, Zak played a piece by Mozart on the violin.\n\r\nSecond, Michael played a piece by Bach on the piano.\n\r\nThird, Rachel played a piece by Mozart on the violin.\n\r\nFourth, Jessi played a piece by Bach on the violin.\n\r\nFifth, Jeremy played a piece by Vivaldi on the piano.\n<|im_start|>answer\nFirst, Zak played a piece by Mozart on the violin.\n\r\nSecond, Michael played a piece by Bach on the piano.\n\r\nThird, Rachel played a piece by Mozart on the violin.\n\r\nFourth, Jessi played a piece by Bach on the violin.\n\r\nFifth, Jeremy played a piece by Vivaldi on the piano.\n<|im_end|>" }, { "id": "#27822", "title": "40+10+10=60", "fun": 2.43, "difficulty": 2.81, "author": "shenqiang", "desc": "In the equation FORTY+TEN+TEN=SIXTY, each letter represents a different digit. Can you figure out which letter is which digit?", "hint": "Start from the last digits.", "answer": "First, there are ten different letters in this equation: E, F, I, N, O, R, S, T, X, Y. Therefore, every digit from 0 to 9 is used.\n\r\nBecause the last two digits of TY+EN*2 is TY, EN*2 is divisible by 100, EN must equal 50.\n\r\nWe get FOR+T*2+1=SIX.\n\r\nSince T*2+1<20, SI is at most FO+2. We must have S=F+1, and since the digit 0 is occupied by N, O must equal 9 and I must equal 1. Hence SI=FO+2.\n\r\nWe get R+T*2+1=20+X, or R=X+(19-T*2). The remaining digits are 2, 3, 4, 6, 7, 8. \n\r\nIf T=6, Then R=X+7, which is impossible for these numbers. And T can't be lower.\n\r\nIf T=7, then R=X+5, and we can only have R=8, X=3. This leaves 2, 4, 6, from which we can't choose S=F+1.\n\r\nIf T=8, then R=X+3, we can have R=6, X=3, or R=7, X=4.\n\r\nIf R=6, X=3, the remaining digits are 2, 4, 7, and again we can't choose S=F+1.\n\r\nIf R=7, X=4, the remaining digits are 2, 3, 6, where 3=2+1. Hence S=3, F=2.\n\r\nFinally, the remaining digit 6 is for Y.\n\r\nTherefore, the equation is 29786+850+850=31486.", "category": "Math", "date": "01/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the equation FORTY+TEN+TEN=SIXTY, each letter represents a different digit. Can you figure out which letter is which digit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, there are ten different letters in this equation: E, F, I, N, O, R, S, T, X, Y. Therefore, every digit from 0 to 9 is used.\n\r\nBecause the last two digits of TY+EN*2 is TY, EN*2 is divisible by 100, EN must equal 50.\n\r\nWe get FOR+T*2+1=SIX.\n\r\nSince T*2+1<20, SI is at most FO+2. We must have S=F+1, and since the digit 0 is occupied by N, O must equal 9 and I must equal 1. Hence SI=FO+2.\n\r\nWe get R+T*2+1=20+X, or R=X+(19-T*2). The remaining digits are 2, 3, 4, 6, 7, 8. \n\r\nIf T=6, Then R=X+7, which is impossible for these numbers. And T can't be lower.\n\r\nIf T=7, then R=X+5, and we can only have R=8, X=3. This leaves 2, 4, 6, from which we can't choose S=F+1.\n\r\nIf T=8, then R=X+3, we can have R=6, X=3, or R=7, X=4.\n\r\nIf R=6, X=3, the remaining digits are 2, 4, 7, and again we can't choose S=F+1.\n\r\nIf R=7, X=4, the remaining digits are 2, 3, 6, where 3=2+1. Hence S=3, F=2.\n\r\nFinally, the remaining digit 6 is for Y.\n\r\nTherefore, the equation is 29786+850+850=31486.\n<|im_start|>answer\nFirst, there are ten different letters in this equation: E, F, I, N, O, R, S, T, X, Y. Therefore, every digit from 0 to 9 is used.\n\r\nBecause the last two digits of TY+EN*2 is TY, EN*2 is divisible by 100, EN must equal 50.\n\r\nWe get FOR+T*2+1=SIX.\n\r\nSince T*2+1<20, SI is at most FO+2. We must have S=F+1, and since the digit 0 is occupied by N, O must equal 9 and I must equal 1. Hence SI=FO+2.\n\r\nWe get R+T*2+1=20+X, or R=X+(19-T*2). The remaining digits are 2, 3, 4, 6, 7, 8. \n\r\nIf T=6, Then R=X+7, which is impossible for these numbers. And T can't be lower.\n\r\nIf T=7, then R=X+5, and we can only have R=8, X=3. This leaves 2, 4, 6, from which we can't choose S=F+1.\n\r\nIf T=8, then R=X+3, we can have R=6, X=3, or R=7, X=4.\n\r\nIf R=6, X=3, the remaining digits are 2, 4, 7, and again we can't choose S=F+1.\n\r\nIf R=7, X=4, the remaining digits are 2, 3, 6, where 3=2+1. Hence S=3, F=2.\n\r\nFinally, the remaining digit 6 is for Y.\n\r\nTherefore, the equation is 29786+850+850=31486.\n<|im_end|>" }, { "id": "#6366", "title": "Math Symbols", "fun": 2.43, "difficulty": 2.04, "author": "cathalmccabe", "desc": "You have the numbers 2 3 4 6 7 8 represented by the symbols # $ & % ? ! Each symbol represents one and only only number. From the following can you figure out which number matches which symbol? (X means multiplied by)\n\r\n?# = # X !\r\n?# = $ X %\r\n#? = ! X &\r\n$? = % X #", "hint": "No hint available.", "answer": "? 2\r\n$ 3\r\n# 4\r\n! 6\r\n& 7\r\n% 8\n\r\nFrom the first two equations:\r\n?# = # X !\r\n?# = $ X %\n\r\nYou need to find the same product from four different numbers. And the second digit of the product (#) must be a factor\n\r\n2 * 6 = 12 (2)\r\nor\r\n3 * 4 = 12\n\r\nor 6*4 = 24 (4)\r\nor\r\n8*3 = 24\n\r\nThe 3rd equation is the opposite so its either 21 or 42\n\r\nWhich can only be made from 7*6 or 7*3\n\r\nWe could have \r\n2 * 6 = 12 \r\n3 * 4 = 12\r\n3 * 7 = 21\r\nBut then we have fail to use 8!\r\nso we must have \n\r\n24 = 6*4\r\n24 = 8*3\r\n42 = 7*6\n\r\nso we know \n\r\n? 2\r\n# 4 \r\nso\r\n! is 6\r\n& is 7\n\n\r\n3 and 8 can be got from:\r\n$? = % X #", "category": "Math", "date": "08/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have the numbers 2 3 4 6 7 8 represented by the symbols # $ & % ? ! Each symbol represents one and only only number. From the following can you figure out which number matches which symbol? (X means multiplied by)\n\r\n?# = # X !\r\n?# = $ X %\r\n#? = ! X &\r\n$? = % X #\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n? 2\r\n$ 3\r\n# 4\r\n! 6\r\n& 7\r\n% 8\n\r\nFrom the first two equations:\r\n?# = # X !\r\n?# = $ X %\n\r\nYou need to find the same product from four different numbers. And the second digit of the product (#) must be a factor\n\r\n2 * 6 = 12 (2)\r\nor\r\n3 * 4 = 12\n\r\nor 6*4 = 24 (4)\r\nor\r\n8*3 = 24\n\r\nThe 3rd equation is the opposite so its either 21 or 42\n\r\nWhich can only be made from 7*6 or 7*3\n\r\nWe could have \r\n2 * 6 = 12 \r\n3 * 4 = 12\r\n3 * 7 = 21\r\nBut then we have fail to use 8!\r\nso we must have \n\r\n24 = 6*4\r\n24 = 8*3\r\n42 = 7*6\n\r\nso we know \n\r\n? 2\r\n# 4 \r\nso\r\n! is 6\r\n& is 7\n\n\r\n3 and 8 can be got from:\r\n$? = % X #\n<|im_start|>answer\n? 2\r\n$ 3\r\n# 4\r\n! 6\r\n& 7\r\n% 8\n\r\nFrom the first two equations:\r\n?# = # X !\r\n?# = $ X %\n\r\nYou need to find the same product from four different numbers. And the second digit of the product (#) must be a factor\n\r\n2 * 6 = 12 (2)\r\nor\r\n3 * 4 = 12\n\r\nor 6*4 = 24 (4)\r\nor\r\n8*3 = 24\n\r\nThe 3rd equation is the opposite so its either 21 or 42\n\r\nWhich can only be made from 7*6 or 7*3\n\r\nWe could have \r\n2 * 6 = 12 \r\n3 * 4 = 12\r\n3 * 7 = 21\r\nBut then we have fail to use 8!\r\nso we must have \n\r\n24 = 6*4\r\n24 = 8*3\r\n42 = 7*6\n\r\nso we know \n\r\n? 2\r\n# 4 \r\nso\r\n! is 6\r\n& is 7\n\n\r\n3 and 8 can be got from:\r\n$? = % X #\n<|im_end|>" }, { "id": "#15128", "title": "How Many Ounces?", "fun": 2.43, "difficulty": 1.8900000000000001, "author": "adoontourious", "desc": "Joey has 8 drinking glasses, all of different sizes. He has lined them up from smallest to largest and numbered them 1 (smallest) to 8 (largest). He knows that glass #4 holds 10 ounces and that glass #7 holds a pint, or 16 ounces. Now he wants to figure out how much all the others hold! \r\nHe experiments by filling up different glasses with water and pouring the water back and forth into other glasses. Here are his results: \n\r\n-Pouring water from glasses #1 and #2 filled glass #4. \n\r\n-Pouring water from glasses #1 and #3 filled glass #5. \n\r\n-Pouring water from glasses #2 and #3 filled glass #6. \n\r\n-Pouring water from glasses #1 and #5 filled glass #7. \n\r\n-Pouring water from glasses #1 and #7 filled glass #8. \n\r\n-Pouring water twice from glass #3 filled glass #7. \n\r\n-Pouring water twice from glass #4 filled glass #8. \n\r\nHow much water does each glass hold?", "hint": "No hint available.", "answer": "The glasses hold this much water: \n\r\n-Glass #1 holds 4 ounces. \n\r\n-Glass #2 holds 6 ounces. \n\r\n-Glass #3 holds 8 ounces. \n\r\n-Glass #4 holds 10 ounces. \n\r\n-Glass #5 holds 12 ounces. \n\r\n-Glass #6 holds 14 ounces. \n\r\n-Glass #7 holds 16 ounces. \n\r\n-Glass #8 holds 20 ounces. \n\r\nSince (2) #4s = #8 and #4 holds 10 ounces, #8 must hold 20 ounces (10 +10 = 20).\r\nSince (2) #3s = #7 and #7 holds 16 ounces, #3 must hold 8 ounces (16 ÷ 2 = 8).\r\nSince #7 holds 16 ounces and #7 + #1 = #8, then #1 must hold 4 ounces (20 - 16 = 4).\r\nSince #1 + #2 = #4, #2 must hold 6 ounces (10 - 4 = 6).\r\nSince #1 + #5 = #7, #5 must hold 12 ounces (16 - 4 = 12).\r\nSince #2 + #3 = #6, #6 must hold 14 ounces (6 + 8 = 14).", "category": "Logic", "date": "10/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoey has 8 drinking glasses, all of different sizes. He has lined them up from smallest to largest and numbered them 1 (smallest) to 8 (largest). He knows that glass #4 holds 10 ounces and that glass #7 holds a pint, or 16 ounces. Now he wants to figure out how much all the others hold! \r\nHe experiments by filling up different glasses with water and pouring the water back and forth into other glasses. Here are his results: \n\r\n-Pouring water from glasses #1 and #2 filled glass #4. \n\r\n-Pouring water from glasses #1 and #3 filled glass #5. \n\r\n-Pouring water from glasses #2 and #3 filled glass #6. \n\r\n-Pouring water from glasses #1 and #5 filled glass #7. \n\r\n-Pouring water from glasses #1 and #7 filled glass #8. \n\r\n-Pouring water twice from glass #3 filled glass #7. \n\r\n-Pouring water twice from glass #4 filled glass #8. \n\r\nHow much water does each glass hold?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe glasses hold this much water: \n\r\n-Glass #1 holds 4 ounces. \n\r\n-Glass #2 holds 6 ounces. \n\r\n-Glass #3 holds 8 ounces. \n\r\n-Glass #4 holds 10 ounces. \n\r\n-Glass #5 holds 12 ounces. \n\r\n-Glass #6 holds 14 ounces. \n\r\n-Glass #7 holds 16 ounces. \n\r\n-Glass #8 holds 20 ounces. \n\r\nSince (2) #4s = #8 and #4 holds 10 ounces, #8 must hold 20 ounces (10 +10 = 20).\r\nSince (2) #3s = #7 and #7 holds 16 ounces, #3 must hold 8 ounces (16 ÷ 2 = 8).\r\nSince #7 holds 16 ounces and #7 + #1 = #8, then #1 must hold 4 ounces (20 - 16 = 4).\r\nSince #1 + #2 = #4, #2 must hold 6 ounces (10 - 4 = 6).\r\nSince #1 + #5 = #7, #5 must hold 12 ounces (16 - 4 = 12).\r\nSince #2 + #3 = #6, #6 must hold 14 ounces (6 + 8 = 14).\n<|im_start|>answer\nThe glasses hold this much water: \n\r\n-Glass #1 holds 4 ounces. \n\r\n-Glass #2 holds 6 ounces. \n\r\n-Glass #3 holds 8 ounces. \n\r\n-Glass #4 holds 10 ounces. \n\r\n-Glass #5 holds 12 ounces. \n\r\n-Glass #6 holds 14 ounces. \n\r\n-Glass #7 holds 16 ounces. \n\r\n-Glass #8 holds 20 ounces. \n\r\nSince (2) #4s = #8 and #4 holds 10 ounces, #8 must hold 20 ounces (10 +10 = 20).\r\nSince (2) #3s = #7 and #7 holds 16 ounces, #3 must hold 8 ounces (16 ÷ 2 = 8).\r\nSince #7 holds 16 ounces and #7 + #1 = #8, then #1 must hold 4 ounces (20 - 16 = 4).\r\nSince #1 + #2 = #4, #2 must hold 6 ounces (10 - 4 = 6).\r\nSince #1 + #5 = #7, #5 must hold 12 ounces (16 - 4 = 12).\r\nSince #2 + #3 = #6, #6 must hold 14 ounces (6 + 8 = 14).\n<|im_end|>" }, { "id": "#12821", "title": "Physical Math", "fun": 2.43, "difficulty": 2.65, "author": "Gizzer", "desc": "Due to cutbacks at the local high school, physical education and mathematics were combined into one class. This made for some interesting \"exercises\". One of the questions on this term's final exam stated:\n\r\nFrom a starting position walk to the right a distance (in feet) represented by the first prime number. Then turn right 90 degrees and walk a distance represented by the 2nd prime number, and so on, until all prime numbers less than 100 have been accounted for. Then answer the following questions.\n\r\na) How far have you walked?\r\nb) How far (to the nearest inch) do you have to walk to return to your starting position?", "hint": "Do it on paper, unless you need the exercise!", "answer": "a) You have walked 1060 feet.\r\nb) You have to walk 73 feet, 9 inches\n\r\nExplanation\n\r\nThere are 25 prime numbers between 1 and 100, neither of which is prime. (No, 1 is not prime.) So you will walk in an expanding square with sides of length 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 feet. This is a total of 1060 feet.\n\r\nThe net result of your turns will be that you are 56 feet ahead of your starting position.\n\r\n (2+11+23+41+59+73+97)\r\n- (5+17+31+47+67+83)\n\r\nYou will also be 48 feet to the left of your starting position.\n\r\n (7+19+37+53+71+89)\r\n- (3+13+29+43+61+79)\n\r\nTo calculate the distance back to the starting position, calculate the length of the hypotenuse of the right angle triangle with legs that are 56 and 48 feet long. This is 73.756 feet, or 73 feet, 9 inches.", "category": "Math", "date": "05/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDue to cutbacks at the local high school, physical education and mathematics were combined into one class. This made for some interesting \"exercises\". One of the questions on this term's final exam stated:\n\r\nFrom a starting position walk to the right a distance (in feet) represented by the first prime number. Then turn right 90 degrees and walk a distance represented by the 2nd prime number, and so on, until all prime numbers less than 100 have been accounted for. Then answer the following questions.\n\r\na) How far have you walked?\r\nb) How far (to the nearest inch) do you have to walk to return to your starting position?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) You have walked 1060 feet.\r\nb) You have to walk 73 feet, 9 inches\n\r\nExplanation\n\r\nThere are 25 prime numbers between 1 and 100, neither of which is prime. (No, 1 is not prime.) So you will walk in an expanding square with sides of length 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 feet. This is a total of 1060 feet.\n\r\nThe net result of your turns will be that you are 56 feet ahead of your starting position.\n\r\n (2+11+23+41+59+73+97)\r\n- (5+17+31+47+67+83)\n\r\nYou will also be 48 feet to the left of your starting position.\n\r\n (7+19+37+53+71+89)\r\n- (3+13+29+43+61+79)\n\r\nTo calculate the distance back to the starting position, calculate the length of the hypotenuse of the right angle triangle with legs that are 56 and 48 feet long. This is 73.756 feet, or 73 feet, 9 inches.\n<|im_start|>answer\na) You have walked 1060 feet.\r\nb) You have to walk 73 feet, 9 inches\n\r\nExplanation\n\r\nThere are 25 prime numbers between 1 and 100, neither of which is prime. (No, 1 is not prime.) So you will walk in an expanding square with sides of length 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 feet. This is a total of 1060 feet.\n\r\nThe net result of your turns will be that you are 56 feet ahead of your starting position.\n\r\n (2+11+23+41+59+73+97)\r\n- (5+17+31+47+67+83)\n\r\nYou will also be 48 feet to the left of your starting position.\n\r\n (7+19+37+53+71+89)\r\n- (3+13+29+43+61+79)\n\r\nTo calculate the distance back to the starting position, calculate the length of the hypotenuse of the right angle triangle with legs that are 56 and 48 feet long. This is 73.756 feet, or 73 feet, 9 inches.\n<|im_end|>" }, { "id": "#276", "title": "An Unusual Clothing Store", "fun": 2.43, "difficulty": 1.39, "author": "Phyllis", "desc": "A young boy goes into an unusual clothing store. The owner tells him that he charges $3 for a tie, $3 for a hat and $5 for a shirt. How much would he charge for a jacket?", "hint": "Count it up!", "answer": "He would charge $6 because he charges $1 for each letter in the name of the item.", "category": "Logic", "date": "02/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA young boy goes into an unusual clothing store. The owner tells him that he charges $3 for a tie, $3 for a hat and $5 for a shirt. How much would he charge for a jacket?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe would charge $6 because he charges $1 for each letter in the name of the item.\n<|im_start|>answer\nHe would charge $6 because he charges $1 for each letter in the name of the item.\n<|im_end|>" }, { "id": "#32982", "title": "Letter Blocks II", "fun": 2.43, "difficulty": 2.71, "author": "peanut", "desc": "You have four kiddies' building blocks with a different letter on each side. You notice that by rearranging the blocks several times, the following list of words can be formed:\n\r\npink\r\njest\r\nrope\r\nquip\r\ngoal\r\ncony\r\nfrog\r\ndark\r\nsite\r\nglum\r\nwack\r\nhave\r\ntiny\r\nwish\r\nbins\n\r\nWhat letters appear on each block?", "hint": "The letters n and e are on the same block.", "answer": "Block 1: p, a, f, m, y, s\r\nBlock 2: i, r, l, c, v, j\r\nBlock 3: n, e, d, g, q, w\r\nBlock 4: k, o, u, t, h, b", "category": "Logic", "date": "09/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have four kiddies' building blocks with a different letter on each side. You notice that by rearranging the blocks several times, the following list of words can be formed:\n\r\npink\r\njest\r\nrope\r\nquip\r\ngoal\r\ncony\r\nfrog\r\ndark\r\nsite\r\nglum\r\nwack\r\nhave\r\ntiny\r\nwish\r\nbins\n\r\nWhat letters appear on each block?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlock 1: p, a, f, m, y, s\r\nBlock 2: i, r, l, c, v, j\r\nBlock 3: n, e, d, g, q, w\r\nBlock 4: k, o, u, t, h, b\n<|im_start|>answer\nBlock 1: p, a, f, m, y, s\r\nBlock 2: i, r, l, c, v, j\r\nBlock 3: n, e, d, g, q, w\r\nBlock 4: k, o, u, t, h, b\n<|im_end|>" }, { "id": "#697", "title": "Light a fuse", "fun": 2.43, "difficulty": 2.57, "author": "link2440", "desc": "You have 2 fuses. One fuse burns for 1 hour, the other burns for 2 hours. The problem is that the fuses burn irregular. The last few inches may burn longer than first few inches. Using the 2 fuses how can you create a fuse that burns for exactly 45 minutes. Remember, cutting them does no good since you don't know how long the cut fuse lasts.", "hint": "No hint available.", "answer": "You burn both sides of the 1 hour fuse and 1 side of the 2 hour fuse at the same time. Regardless of the varying speeds of the one hour fuse, when it goes out it has been 30 minutes. At that point there would be 1 hour and 30 minutes left on the 2 hour fuse. You then light the other end of the 2 hour fuse and since the burning time would be cut in half the fuse would be 45 minutes long.", "category": "Logic", "date": "07/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have 2 fuses. One fuse burns for 1 hour, the other burns for 2 hours. The problem is that the fuses burn irregular. The last few inches may burn longer than first few inches. Using the 2 fuses how can you create a fuse that burns for exactly 45 minutes. Remember, cutting them does no good since you don't know how long the cut fuse lasts.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou burn both sides of the 1 hour fuse and 1 side of the 2 hour fuse at the same time. Regardless of the varying speeds of the one hour fuse, when it goes out it has been 30 minutes. At that point there would be 1 hour and 30 minutes left on the 2 hour fuse. You then light the other end of the 2 hour fuse and since the burning time would be cut in half the fuse would be 45 minutes long.\n<|im_start|>answer\nYou burn both sides of the 1 hour fuse and 1 side of the 2 hour fuse at the same time. Regardless of the varying speeds of the one hour fuse, when it goes out it has been 30 minutes. At that point there would be 1 hour and 30 minutes left on the 2 hour fuse. You then light the other end of the 2 hour fuse and since the burning time would be cut in half the fuse would be 45 minutes long.\n<|im_end|>" }, { "id": "#31269", "title": "Counting on Fingers", "fun": 2.43, "difficulty": 2.17, "author": "irar1792", "desc": "A mathematician walks in on his daughter counting on her fingers. He has no problem with this, but finds it odd that after counting to five (thumb to pinky finger), she doubles back and counts her ring finger as six, middle finger as seven, etc.\r\nWhen the girl gets to twenty, on her ring finger, her father asks her what she is doing. \r\n\"I want to see what finger the number 1972 lands on,\" the young girl replies. The father chuckles, does some quick arithmetic and tells the girl the finger on which she will land. How does he do it, and on what finger will his daughter finish?", "hint": "No hint available.", "answer": "The girl will land on her ring finger.\n\r\nThe number of the thumb minus one is always divisible by eight.\n\r\nDivide with remainder: 1972/8=246R4\n\r\nCount the thumb as one. The ring finger is four.", "category": "Math", "date": "06/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA mathematician walks in on his daughter counting on her fingers. He has no problem with this, but finds it odd that after counting to five (thumb to pinky finger), she doubles back and counts her ring finger as six, middle finger as seven, etc.\r\nWhen the girl gets to twenty, on her ring finger, her father asks her what she is doing. \r\n\"I want to see what finger the number 1972 lands on,\" the young girl replies. The father chuckles, does some quick arithmetic and tells the girl the finger on which she will land. How does he do it, and on what finger will his daughter finish?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe girl will land on her ring finger.\n\r\nThe number of the thumb minus one is always divisible by eight.\n\r\nDivide with remainder: 1972/8=246R4\n\r\nCount the thumb as one. The ring finger is four.\n<|im_start|>answer\nThe girl will land on her ring finger.\n\r\nThe number of the thumb minus one is always divisible by eight.\n\r\nDivide with remainder: 1972/8=246R4\n\r\nCount the thumb as one. The ring finger is four.\n<|im_end|>" }, { "id": "#8346", "title": "Joe and Smoe", "fun": 2.43, "difficulty": 2.47, "author": "tissue", "desc": "Two friends, Joe and Smoe, were born in May, one in 1932, the other a year later. Each had an antique grandfather clock of which he was extremely proud. Both of the clocks worked fairly well considering their age, but one clock gained ten seconds per hour while the other one lost ten seconds per hour. On a day in January, the two friends set both clocks correctly at 12:00 noon. \"Do you realize,\" asked Joe, \"that the next time both of our clocks will show exactly the same time will be on your 47th birthday?\" Smoe agreed. Who is older, Joe or Smoe?", "hint": "No hint available.", "answer": "To find the answer, we have to find how long it will be before the clocks show the same time again. This is when the slow clock loses six hours, and the fast one gains six hours. This will take 90 days. In 90 days they will come together at 6:00. On a calendar, there are 90 days between noon January 31, and noon May 1 in years with no leap year. If Smoe had been born in 1933, his 47th birthday would have been in 1980, a leap year. This means that Smoe must be older, born in 1932, and the time of this problem is 1979.", "category": "Logic", "date": "11/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo friends, Joe and Smoe, were born in May, one in 1932, the other a year later. Each had an antique grandfather clock of which he was extremely proud. Both of the clocks worked fairly well considering their age, but one clock gained ten seconds per hour while the other one lost ten seconds per hour. On a day in January, the two friends set both clocks correctly at 12:00 noon. \"Do you realize,\" asked Joe, \"that the next time both of our clocks will show exactly the same time will be on your 47th birthday?\" Smoe agreed. Who is older, Joe or Smoe?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo find the answer, we have to find how long it will be before the clocks show the same time again. This is when the slow clock loses six hours, and the fast one gains six hours. This will take 90 days. In 90 days they will come together at 6:00. On a calendar, there are 90 days between noon January 31, and noon May 1 in years with no leap year. If Smoe had been born in 1933, his 47th birthday would have been in 1980, a leap year. This means that Smoe must be older, born in 1932, and the time of this problem is 1979.\n<|im_start|>answer\nTo find the answer, we have to find how long it will be before the clocks show the same time again. This is when the slow clock loses six hours, and the fast one gains six hours. This will take 90 days. In 90 days they will come together at 6:00. On a calendar, there are 90 days between noon January 31, and noon May 1 in years with no leap year. If Smoe had been born in 1933, his 47th birthday would have been in 1980, a leap year. This means that Smoe must be older, born in 1932, and the time of this problem is 1979.\n<|im_end|>" }, { "id": "#30284", "title": "Powerful Weights and Measures", "fun": 2.43, "difficulty": 2.87, "author": "CyberPhunk", "desc": "Long ago, in a land far away, there lived a primitive culture whose founding chief had eleven fingers. This chief had a strong affinity for the number eleven because of his special circumstances and thus founded a numbering system based on the number eleven. The number 121 had very special meaning, as it was eleven times eleven.\n\r\nThe system of weight measures that he devised were also based on the number eleven. The base unit was called a stone, for a convenient rock that was handy. The next unit was the lump, being eleven stone in weight. Eleven lumps were called a mass.\n\r\nSo: 11 stone = a lump and 11 lumps = a mass.\n\r\nThe problem was, using 10 lump and 11 stone weights to measure out any weight from 1 stone to 1 mass required carrying around quite a lot of weight! The chief, being aware that this was beyond his math skills, asked his advisors for help. The request was to come up with a minimum number of weights that would allow for the weighing of any measure between one stone and one mass using a set of scales. What was their solution?", "hint": "The title has a slight hint.\n\r\nThe number eleven has nothing to do with the set of weights.", "answer": "The minimum number of weights is 5.\n\r\nweight 1 = 1 stone = 3^0\r\nweight 2 = 3 stone = 3^1\r\nweight 3 = 9 stone = 3^2\r\nweight 4 = 2 lump 5 stone = 27 stone = 3^3\r\nweight 5 = 7 lump 4 stone = 81 stone = 3^4\n\r\nAll five added together weigh one mass, and allow the weighing of any measure down to one stone.\n\r\nThe progression from one stone to one mass would be:\n\r\n1, 3-1, 3, 3 +1, 9-3-1, 9-3, 9-3 + 1, 9-1, 9, 27-9-3-1, 27-9-3, ....", "category": "Math", "date": "05/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLong ago, in a land far away, there lived a primitive culture whose founding chief had eleven fingers. This chief had a strong affinity for the number eleven because of his special circumstances and thus founded a numbering system based on the number eleven. The number 121 had very special meaning, as it was eleven times eleven.\n\r\nThe system of weight measures that he devised were also based on the number eleven. The base unit was called a stone, for a convenient rock that was handy. The next unit was the lump, being eleven stone in weight. Eleven lumps were called a mass.\n\r\nSo: 11 stone = a lump and 11 lumps = a mass.\n\r\nThe problem was, using 10 lump and 11 stone weights to measure out any weight from 1 stone to 1 mass required carrying around quite a lot of weight! The chief, being aware that this was beyond his math skills, asked his advisors for help. The request was to come up with a minimum number of weights that would allow for the weighing of any measure between one stone and one mass using a set of scales. What was their solution?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe minimum number of weights is 5.\n\r\nweight 1 = 1 stone = 3^0\r\nweight 2 = 3 stone = 3^1\r\nweight 3 = 9 stone = 3^2\r\nweight 4 = 2 lump 5 stone = 27 stone = 3^3\r\nweight 5 = 7 lump 4 stone = 81 stone = 3^4\n\r\nAll five added together weigh one mass, and allow the weighing of any measure down to one stone.\n\r\nThe progression from one stone to one mass would be:\n\r\n1, 3-1, 3, 3 +1, 9-3-1, 9-3, 9-3 + 1, 9-1, 9, 27-9-3-1, 27-9-3, ....\n<|im_start|>answer\nThe minimum number of weights is 5.\n\r\nweight 1 = 1 stone = 3^0\r\nweight 2 = 3 stone = 3^1\r\nweight 3 = 9 stone = 3^2\r\nweight 4 = 2 lump 5 stone = 27 stone = 3^3\r\nweight 5 = 7 lump 4 stone = 81 stone = 3^4\n\r\nAll five added together weigh one mass, and allow the weighing of any measure down to one stone.\n\r\nThe progression from one stone to one mass would be:\n\r\n1, 3-1, 3, 3 +1, 9-3-1, 9-3, 9-3 + 1, 9-1, 9, 27-9-3-1, 27-9-3, ....\n<|im_end|>" }, { "id": "#506", "title": "Five 5`s", "fun": 2.43, "difficulty": 1.6, "author": "Squidgy", "desc": "How can five 5`s equal 31?", "hint": "No hint available.", "answer": "5x5+5+5/5 (or five times five plus five plus five-fifths)=31", "category": "Math", "date": "05/28/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can five 5`s equal 31?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5x5+5+5/5 (or five times five plus five plus five-fifths)=31\n<|im_start|>answer\n5x5+5+5/5 (or five times five plus five plus five-fifths)=31\n<|im_end|>" }, { "id": "#29309", "title": "Wheel Machine", "fun": 2.43, "difficulty": 2.79, "author": "kiss", "desc": "I have a machine which has four cog wheels in constant mesh. The largest cog has 242 teeth and the others have 160, 64 and 22 respectively. How many revolutions must the largest cog make before each of the cogs is back in its starting position?", "hint": "No hint available.", "answer": "160 revolutions.\n\r\nThe least common multiple of 242=2*11^2, 160=2^5*5, 64=2^6 and 22=2*11 is 2^6*5*11^2=38720.\n\r\n38720/242=160.", "category": "Math", "date": "03/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have a machine which has four cog wheels in constant mesh. The largest cog has 242 teeth and the others have 160, 64 and 22 respectively. How many revolutions must the largest cog make before each of the cogs is back in its starting position?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n160 revolutions.\n\r\nThe least common multiple of 242=2*11^2, 160=2^5*5, 64=2^6 and 22=2*11 is 2^6*5*11^2=38720.\n\r\n38720/242=160.\n<|im_start|>answer\n160 revolutions.\n\r\nThe least common multiple of 242=2*11^2, 160=2^5*5, 64=2^6 and 22=2*11 is 2^6*5*11^2=38720.\n\r\n38720/242=160.\n<|im_end|>" }, { "id": "#29070", "title": "Wrapping It Up", "fun": 2.43, "difficulty": 1.8800000000000001, "author": "shenqiang", "desc": "I need to wrap eight cube-shaped boxes that are four inches on each side. I may wrap them separately, or I may wrap them together in a variety of different shapes and configurations.\n\r\nIn what way should I wrap all the boxes to use the least amount of wrapping paper?", "hint": "Think of different ways to arrange the boxes for wrapping. The number of box sides to be covered by the wrapping paper determines how much paper is needed.", "answer": "To use the smallest amount of wrapping paper, I need to arrange the boxes as a cube.\n\r\nI can wrap the boxes separately; in a long line of eight; as a rectangle made up of two rows of four boxes each; or together as a cube.\n\r\nWrapping separately:\r\n48 box sides x 16 square inches per box side = 768 square inches;\n\r\nWrapping as a line of eight:\r\n34 box sides x 16 square inches per box side = 544 square inches;\n\r\nWrapping as a rectangle:\r\n28 box sides x 16 square inches per box side = 448 square inches;\n\r\nWrapping as a cube:\r\n24 box sides x 16 square inches per box side = 384 square inches.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI need to wrap eight cube-shaped boxes that are four inches on each side. I may wrap them separately, or I may wrap them together in a variety of different shapes and configurations.\n\r\nIn what way should I wrap all the boxes to use the least amount of wrapping paper?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo use the smallest amount of wrapping paper, I need to arrange the boxes as a cube.\n\r\nI can wrap the boxes separately; in a long line of eight; as a rectangle made up of two rows of four boxes each; or together as a cube.\n\r\nWrapping separately:\r\n48 box sides x 16 square inches per box side = 768 square inches;\n\r\nWrapping as a line of eight:\r\n34 box sides x 16 square inches per box side = 544 square inches;\n\r\nWrapping as a rectangle:\r\n28 box sides x 16 square inches per box side = 448 square inches;\n\r\nWrapping as a cube:\r\n24 box sides x 16 square inches per box side = 384 square inches.\n<|im_start|>answer\nTo use the smallest amount of wrapping paper, I need to arrange the boxes as a cube.\n\r\nI can wrap the boxes separately; in a long line of eight; as a rectangle made up of two rows of four boxes each; or together as a cube.\n\r\nWrapping separately:\r\n48 box sides x 16 square inches per box side = 768 square inches;\n\r\nWrapping as a line of eight:\r\n34 box sides x 16 square inches per box side = 544 square inches;\n\r\nWrapping as a rectangle:\r\n28 box sides x 16 square inches per box side = 448 square inches;\n\r\nWrapping as a cube:\r\n24 box sides x 16 square inches per box side = 384 square inches.\n<|im_end|>" }, { "id": "#509", "title": "Three Coins", "fun": 2.43, "difficulty": 0.8200000000000001, "author": "Phyllis", "desc": "Two fathers and two sons were walking along a road. They happened to find three silver coins lying in their path. They picked up the coins and divided them evenly--each of them receiving one coin. How is this possible?", "hint": "No hint available.", "answer": "There were only three people walking along the road--a grandfather, his son and his grandson. Thus, there were two fathers and two sons. Each one took 1 coin.", "category": "Logic", "date": "05/28/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo fathers and two sons were walking along a road. They happened to find three silver coins lying in their path. They picked up the coins and divided them evenly--each of them receiving one coin. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were only three people walking along the road--a grandfather, his son and his grandson. Thus, there were two fathers and two sons. Each one took 1 coin.\n<|im_start|>answer\nThere were only three people walking along the road--a grandfather, his son and his grandson. Thus, there were two fathers and two sons. Each one took 1 coin.\n<|im_end|>" }, { "id": "#29320", "title": "Sand Buckets", "fun": 2.43, "difficulty": 2.06, "author": "____", "desc": "Jemal, Lara, and Oren were making a giant sandcastle on the beach. They had 4 buckets: 2 red buckets that carry 3 lbs of sand each, 1 blue bucket that carries 5 lbs of sand, and 1 orange bucket that carries 7 lbs of sand.\n\r\nThey took turns carrying full buckets of damp sand back to their sandcastle spot. Altogether, they made 12 trips to the water's edge to get the damp sand.\n\r\nJemal made 4 trips, carrying 2 buckets each time. He used every possible combination of colored buckets. \r\nOren made 1 less trip than Jemal, using the blue and orange buckets each trip. \r\nLara used the 2 red buckets for each of her trips. \r\nHow many pounds of sand did they haul from the water's edge to their sandcastle spot?", "hint": "Make a chart, then work backwards.", "answer": "They carried 102 pounds of sand from the water's edge to their sandcastle spot, and they made a beautiful castle!\n\r\nJemal: (3+3)+(3+5)+(3+7)+(5+7)=36\r\nOren: (5+7)*3=36\r\nLara: (3+3)*(12-4-3)=30\r\nTotal: 36+36+30=102", "category": "Math", "date": "03/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJemal, Lara, and Oren were making a giant sandcastle on the beach. They had 4 buckets: 2 red buckets that carry 3 lbs of sand each, 1 blue bucket that carries 5 lbs of sand, and 1 orange bucket that carries 7 lbs of sand.\n\r\nThey took turns carrying full buckets of damp sand back to their sandcastle spot. Altogether, they made 12 trips to the water's edge to get the damp sand.\n\r\nJemal made 4 trips, carrying 2 buckets each time. He used every possible combination of colored buckets. \r\nOren made 1 less trip than Jemal, using the blue and orange buckets each trip. \r\nLara used the 2 red buckets for each of her trips. \r\nHow many pounds of sand did they haul from the water's edge to their sandcastle spot?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey carried 102 pounds of sand from the water's edge to their sandcastle spot, and they made a beautiful castle!\n\r\nJemal: (3+3)+(3+5)+(3+7)+(5+7)=36\r\nOren: (5+7)*3=36\r\nLara: (3+3)*(12-4-3)=30\r\nTotal: 36+36+30=102\n<|im_start|>answer\nThey carried 102 pounds of sand from the water's edge to their sandcastle spot, and they made a beautiful castle!\n\r\nJemal: (3+3)+(3+5)+(3+7)+(5+7)=36\r\nOren: (5+7)*3=36\r\nLara: (3+3)*(12-4-3)=30\r\nTotal: 36+36+30=102\n<|im_end|>" }, { "id": "#7941", "title": "Around the World", "fun": 2.43, "difficulty": 2.32, "author": "bluetwo", "desc": "Two cars circumnavigate the world. Time is kept as they pass each other, travelling in opposite directions at the same speed of 70 miles per hour. The only difference is that one car is travelling on the surface of the planet, while the other is on a roadway 15 feet above ground. \n\r\nAssuming the world is a perfect sphere and exactly 25,000 miles around, how much faster does the car travelling on the surface reach the original starting point? \n\r\nAssume, for the sake of the puzzle, that there are 2 continuous, unobstructed, flat roadways around the earth and that the cars don't need gas, the drivers don't need 'pit stops', etc.", "hint": "Circumference = 2*pi*r", "answer": "The answer is only about 1 second!!!\n\r\nThe circumference of the Earth is 2*pi*r. The circumference of the road 15 feet above the Earth is 2*pi*(r+15). The difference between these two distances is 2*pi*15 = 94 feet. This is how much further the car on the elevated roadway has to travel.\r\n70 miles per hour is equal to 103 feet per second. At 103 feet per second, it will take the car on the elevated roadway just under one second to travel the extra 94 feet.", "category": "Math", "date": "10/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo cars circumnavigate the world. Time is kept as they pass each other, travelling in opposite directions at the same speed of 70 miles per hour. The only difference is that one car is travelling on the surface of the planet, while the other is on a roadway 15 feet above ground. \n\r\nAssuming the world is a perfect sphere and exactly 25,000 miles around, how much faster does the car travelling on the surface reach the original starting point? \n\r\nAssume, for the sake of the puzzle, that there are 2 continuous, unobstructed, flat roadways around the earth and that the cars don't need gas, the drivers don't need 'pit stops', etc.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is only about 1 second!!!\n\r\nThe circumference of the Earth is 2*pi*r. The circumference of the road 15 feet above the Earth is 2*pi*(r+15). The difference between these two distances is 2*pi*15 = 94 feet. This is how much further the car on the elevated roadway has to travel.\r\n70 miles per hour is equal to 103 feet per second. At 103 feet per second, it will take the car on the elevated roadway just under one second to travel the extra 94 feet.\n<|im_start|>answer\nThe answer is only about 1 second!!!\n\r\nThe circumference of the Earth is 2*pi*r. The circumference of the road 15 feet above the Earth is 2*pi*(r+15). The difference between these two distances is 2*pi*15 = 94 feet. This is how much further the car on the elevated roadway has to travel.\r\n70 miles per hour is equal to 103 feet per second. At 103 feet per second, it will take the car on the elevated roadway just under one second to travel the extra 94 feet.\n<|im_end|>" }, { "id": "#18703", "title": "Pay My Bill", "fun": 2.43, "difficulty": 2.7, "author": "gooseash", "desc": "At a certain fast food restaurant, Brain can buy 3 burgers, 7 shakes and one order of Fries for $120 exactly. At the same place it would cost $164.50 for 4 burgers, 10 shakes, and one order of fries. How much would it cost for an ordinary meal of one burger, one shake, and one order of fries?", "hint": "No hint available.", "answer": "If b stands for burgers, S for shakes and f for fries\r\n3b + 7s + f = 120\r\n4b + 10s + f = 164.50\n\r\nsolving these two we get \r\nb + 3s = 44.50\r\nrewriting 3b +7s + f as\r\n2b + b + 7s + f = 120\r\n2(44.50 - 3s)+ b + 7s + f = 120\r\n89 -6s + b + 7s + f = 120\r\nb + s + f = 120 - 89 = 31", "category": "Math", "date": "09/01/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a certain fast food restaurant, Brain can buy 3 burgers, 7 shakes and one order of Fries for $120 exactly. At the same place it would cost $164.50 for 4 burgers, 10 shakes, and one order of fries. How much would it cost for an ordinary meal of one burger, one shake, and one order of fries?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf b stands for burgers, S for shakes and f for fries\r\n3b + 7s + f = 120\r\n4b + 10s + f = 164.50\n\r\nsolving these two we get \r\nb + 3s = 44.50\r\nrewriting 3b +7s + f as\r\n2b + b + 7s + f = 120\r\n2(44.50 - 3s)+ b + 7s + f = 120\r\n89 -6s + b + 7s + f = 120\r\nb + s + f = 120 - 89 = 31\n<|im_start|>answer\nIf b stands for burgers, S for shakes and f for fries\r\n3b + 7s + f = 120\r\n4b + 10s + f = 164.50\n\r\nsolving these two we get \r\nb + 3s = 44.50\r\nrewriting 3b +7s + f as\r\n2b + b + 7s + f = 120\r\n2(44.50 - 3s)+ b + 7s + f = 120\r\n89 -6s + b + 7s + f = 120\r\nb + s + f = 120 - 89 = 31\n<|im_end|>" }, { "id": "#30638", "title": "License Plate", "fun": 2.43, "difficulty": 1.6400000000000001, "author": "Hana_Kimi", "desc": "The last three digits of Allison's license plate have a product of 360. The sum of the digits is 22 and the digits are in order from the least to greatest. What are the three digits of her license plate?", "hint": "No hint available.", "answer": "Last Digits=5, 8, and 9. (5x8)x9= 360. 5+8+9= 22.", "category": "Math", "date": "05/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe last three digits of Allison's license plate have a product of 360. The sum of the digits is 22 and the digits are in order from the least to greatest. What are the three digits of her license plate?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLast Digits=5, 8, and 9. (5x8)x9= 360. 5+8+9= 22.\n<|im_start|>answer\nLast Digits=5, 8, and 9. (5x8)x9= 360. 5+8+9= 22.\n<|im_end|>" }, { "id": "#333", "title": "Antique lamps", "fun": 2.43, "difficulty": 1.87, "author": "Phyllis", "desc": "A collector of antique lamps bought two lamps, and then, discovering she was short of money, immediately had to sell them again. She sold each lamp for $600. On one of the lamps she made 20% and on the other one she lost 20%. Did she make or lose money on the whole deal? How much?", "hint": "No hint available.", "answer": "She lost money. You can calculate that the one lamp cost $500 and the other one cost $750. That means she paid $1250 for them together and then sold them for $1200 losing $50.", "category": "Math", "date": "03/10/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA collector of antique lamps bought two lamps, and then, discovering she was short of money, immediately had to sell them again. She sold each lamp for $600. On one of the lamps she made 20% and on the other one she lost 20%. Did she make or lose money on the whole deal? How much?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe lost money. You can calculate that the one lamp cost $500 and the other one cost $750. That means she paid $1250 for them together and then sold them for $1200 losing $50.\n<|im_start|>answer\nShe lost money. You can calculate that the one lamp cost $500 and the other one cost $750. That means she paid $1250 for them together and then sold them for $1200 losing $50.\n<|im_end|>" }, { "id": "#49415", "title": "The Million", "fun": 2.43, "difficulty": 2.32, "author": "Faith511", "desc": "It's greater than one million but less than ten million. \r\nIt's an even number. \r\nNone of the digits are less than three. \r\nNo digit is used more than once.\r\nThe sum of the digits in the ones period is twelve. \r\nThe digit in the ten thousands place is equal to the sum of the digits in the tens and hundreds places. \r\nThe digit in the millions place is two more than the digit in the thousands place. \r\nThe digit in the hundred thousands place is twice the digit in the tens place. \r\nWhat is the mystery number?", "hint": "No hint available.", "answer": "The \"million mystery\" number is 9,687,534.", "category": "Math", "date": "04/15/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's greater than one million but less than ten million. \r\nIt's an even number. \r\nNone of the digits are less than three. \r\nNo digit is used more than once.\r\nThe sum of the digits in the ones period is twelve. \r\nThe digit in the ten thousands place is equal to the sum of the digits in the tens and hundreds places. \r\nThe digit in the millions place is two more than the digit in the thousands place. \r\nThe digit in the hundred thousands place is twice the digit in the tens place. \r\nWhat is the mystery number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe \"million mystery\" number is 9,687,534.\n<|im_start|>answer\nThe \"million mystery\" number is 9,687,534.\n<|im_end|>" }, { "id": "#14583", "title": "Palindromes", "fun": 2.43, "difficulty": 1.98, "author": "Monique114", "desc": "What do these numbers have in common, other than all being palindromes?\n\r\n484, 676, 10201, 12321", "hint": "No hint available.", "answer": "They are all perfect squares.", "category": "Math", "date": "08/27/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat do these numbers have in common, other than all being palindromes?\n\r\n484, 676, 10201, 12321\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are all perfect squares.\n<|im_start|>answer\nThey are all perfect squares.\n<|im_end|>" }, { "id": "#34423", "title": "You Could Go Infinite", "fun": 2.43, "difficulty": 2.84, "author": "stil", "desc": "What three-digit number when doubled is, by value, one more than the value of the same three digits when reversed?\r\nIf this is too easy, go for extra points included with hint.", "hint": "A wrongheaded guess would say 123, because 123 * 2 = 321 + 1. The title hints you can easily go on to find for a ten-digit number that otherwise has same characteristics.", "answer": "Answer-\r\n397.\r\n397 * 2 = 794 = 793 + 1.\n\r\nSolution-\r\nWith lowercase letters standing for unknown digits, the problem is formulized as:\r\n(100a + 10b + c) * 2 = (100c + 10b + a) + 1.\r\n200a + 20b + 2c = a + 10b + 100c + 1.\r\n199a + 10b - 98c - 1 = 0.\r\n[The negative values achieve their negative extreme when c = 9. - 98c - 1 = -883. This caps the value of a as the integral portion of 883/199, i.e., 4. This is in brackets, because there are stronger forces which make this unimportant.]\r\nRule 1) No number starts with a 0. [a is not 0. c is not 0.]\r\nRule 2) Because doubling a number starting with 5, 6, 7, 8, or 9 will result in a product with an additional position/digit, a must be less than 5. [a is 1, 2, 3, or 4.]\r\nRule 3) When a digit is doubled, the most that can be \"carried\" to the next position is 1. This happens when and only when the digit doubled is 5, 6, 7, 8, or 9.\r\nRule 4) Any multiple of 2 will be an even number. To differ from the doubled number by just 1, the reversed number must be odd and its last digit must be odd. a must be an odd digit. [a is 1 or 3.]\r\nRule 5) Doubling a three-digit number results in a number determined by the leading digit and limited to two hundred possibilities. (Doubling a number in the 100's has a result in the 200's or 300's. Doubling a number in the 400's has a result in the 800's or 900's.)[If a is 1, c is 2 or 3. If a is 3, c is 6 or 7.] \n\r\nWhen the digits are reversed, b replaces b so it must either be b * 2 = b or, if Rule 3 comes into play, b * 2 = 10 + (b - 1). [b could only be 0 when c < 5 and only 9 when c >4.]\r\n With just four possibilities, there is no point in rendering additional rules! Just test them.\r\n102? Is 204 = 201 + 1? No.\r\n103? Is 206 = 301 + 1? No. [Wrong hundreds even.]\r\n396? Is 792 = 693 + 1? No. [Wrong hundreds again.]\r\nThe answer given is the only one that passes.\n\r\nAs for extra points, an infinite number of 9's can be added between the 3 and the 7 without spoiling the major characteristics.\r\n3999999997 * 2 = 7999999994 = 7999999993 + 1.", "category": "Math", "date": "12/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat three-digit number when doubled is, by value, one more than the value of the same three digits when reversed?\r\nIf this is too easy, go for extra points included with hint.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer-\r\n397.\r\n397 * 2 = 794 = 793 + 1.\n\r\nSolution-\r\nWith lowercase letters standing for unknown digits, the problem is formulized as:\r\n(100a + 10b + c) * 2 = (100c + 10b + a) + 1.\r\n200a + 20b + 2c = a + 10b + 100c + 1.\r\n199a + 10b - 98c - 1 = 0.\r\n[The negative values achieve their negative extreme when c = 9. - 98c - 1 = -883. This caps the value of a as the integral portion of 883/199, i.e., 4. This is in brackets, because there are stronger forces which make this unimportant.]\r\nRule 1) No number starts with a 0. [a is not 0. c is not 0.]\r\nRule 2) Because doubling a number starting with 5, 6, 7, 8, or 9 will result in a product with an additional position/digit, a must be less than 5. [a is 1, 2, 3, or 4.]\r\nRule 3) When a digit is doubled, the most that can be \"carried\" to the next position is 1. This happens when and only when the digit doubled is 5, 6, 7, 8, or 9.\r\nRule 4) Any multiple of 2 will be an even number. To differ from the doubled number by just 1, the reversed number must be odd and its last digit must be odd. a must be an odd digit. [a is 1 or 3.]\r\nRule 5) Doubling a three-digit number results in a number determined by the leading digit and limited to two hundred possibilities. (Doubling a number in the 100's has a result in the 200's or 300's. Doubling a number in the 400's has a result in the 800's or 900's.)[If a is 1, c is 2 or 3. If a is 3, c is 6 or 7.] \n\r\nWhen the digits are reversed, b replaces b so it must either be b * 2 = b or, if Rule 3 comes into play, b * 2 = 10 + (b - 1). [b could only be 0 when c < 5 and only 9 when c >4.]\r\n With just four possibilities, there is no point in rendering additional rules! Just test them.\r\n102? Is 204 = 201 + 1? No.\r\n103? Is 206 = 301 + 1? No. [Wrong hundreds even.]\r\n396? Is 792 = 693 + 1? No. [Wrong hundreds again.]\r\nThe answer given is the only one that passes.\n\r\nAs for extra points, an infinite number of 9's can be added between the 3 and the 7 without spoiling the major characteristics.\r\n3999999997 * 2 = 7999999994 = 7999999993 + 1.\n<|im_start|>answer\nAnswer-\r\n397.\r\n397 * 2 = 794 = 793 + 1.\n\r\nSolution-\r\nWith lowercase letters standing for unknown digits, the problem is formulized as:\r\n(100a + 10b + c) * 2 = (100c + 10b + a) + 1.\r\n200a + 20b + 2c = a + 10b + 100c + 1.\r\n199a + 10b - 98c - 1 = 0.\r\n[The negative values achieve their negative extreme when c = 9. - 98c - 1 = -883. This caps the value of a as the integral portion of 883/199, i.e., 4. This is in brackets, because there are stronger forces which make this unimportant.]\r\nRule 1) No number starts with a 0. [a is not 0. c is not 0.]\r\nRule 2) Because doubling a number starting with 5, 6, 7, 8, or 9 will result in a product with an additional position/digit, a must be less than 5. [a is 1, 2, 3, or 4.]\r\nRule 3) When a digit is doubled, the most that can be \"carried\" to the next position is 1. This happens when and only when the digit doubled is 5, 6, 7, 8, or 9.\r\nRule 4) Any multiple of 2 will be an even number. To differ from the doubled number by just 1, the reversed number must be odd and its last digit must be odd. a must be an odd digit. [a is 1 or 3.]\r\nRule 5) Doubling a three-digit number results in a number determined by the leading digit and limited to two hundred possibilities. (Doubling a number in the 100's has a result in the 200's or 300's. Doubling a number in the 400's has a result in the 800's or 900's.)[If a is 1, c is 2 or 3. If a is 3, c is 6 or 7.] \n\r\nWhen the digits are reversed, b replaces b so it must either be b * 2 = b or, if Rule 3 comes into play, b * 2 = 10 + (b - 1). [b could only be 0 when c < 5 and only 9 when c >4.]\r\n With just four possibilities, there is no point in rendering additional rules! Just test them.\r\n102? Is 204 = 201 + 1? No.\r\n103? Is 206 = 301 + 1? No. [Wrong hundreds even.]\r\n396? Is 792 = 693 + 1? No. [Wrong hundreds again.]\r\nThe answer given is the only one that passes.\n\r\nAs for extra points, an infinite number of 9's can be added between the 3 and the 7 without spoiling the major characteristics.\r\n3999999997 * 2 = 7999999994 = 7999999993 + 1.\n<|im_end|>" }, { "id": "#26920", "title": "How Many Dollars", "fun": 2.43, "difficulty": 2.98, "author": "kiss", "desc": "Sandy and Sue each has a whole number of dollars. I ask them how many dollars they have.\n\r\nSandy says: \"If Sue gives me some dollars, we'll have the same amount of money. But if I give Sue the same number of dollars, she'll have twice as much money as I have.\"\n\r\nSue says: \"And if you remove the first digit of my wealth and place it to the end, you'll get Sandy's wealth.\"\n\r\nIf neither of them has more than 1 million dollars, how many dollars do they each have?", "hint": "First get the ratio, then get their amount.", "answer": "Let X and Y be Sandy's and Sue's amounts of money, respectively. Let Z be the number of dollars in Sandy's statement.\n\r\nThen X+Z=Y-Z and 2(X-Z)=Y+Z. Solving this we get X=5Z and Y=7Z.\n\r\nAccording to Sue's statement, let A be the first digit of Sue's wealth, B be the remaining digits, and n be the number of digits, then Y=A*10^(n-1)+B and X=10B+A.\n\r\n7X=5Y\r\n7*(10B+A)=5*(A*10^(n-1)+B)\r\n(5*10^(n-1)-7)A=65B\n\r\nSince 65B is divisible by 5 and 5*10^(n-1)-7 is not, A must equal 5. We get:\n\r\n5*10^(n-1)-7=13B\n\r\nThe least value of n such that 5*10^(n-1)-7 is a multiple of 13 is 6:\n\r\n499993=38461*13\n\r\nThe next is 12, which makes them have more than 1 million dollars. Hence n=6 and B=38461.\n\r\nTherefore, Sandy has 384615 dollars and Sue has 538461 dollars.", "category": "Math", "date": "11/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSandy and Sue each has a whole number of dollars. I ask them how many dollars they have.\n\r\nSandy says: \"If Sue gives me some dollars, we'll have the same amount of money. But if I give Sue the same number of dollars, she'll have twice as much money as I have.\"\n\r\nSue says: \"And if you remove the first digit of my wealth and place it to the end, you'll get Sandy's wealth.\"\n\r\nIf neither of them has more than 1 million dollars, how many dollars do they each have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet X and Y be Sandy's and Sue's amounts of money, respectively. Let Z be the number of dollars in Sandy's statement.\n\r\nThen X+Z=Y-Z and 2(X-Z)=Y+Z. Solving this we get X=5Z and Y=7Z.\n\r\nAccording to Sue's statement, let A be the first digit of Sue's wealth, B be the remaining digits, and n be the number of digits, then Y=A*10^(n-1)+B and X=10B+A.\n\r\n7X=5Y\r\n7*(10B+A)=5*(A*10^(n-1)+B)\r\n(5*10^(n-1)-7)A=65B\n\r\nSince 65B is divisible by 5 and 5*10^(n-1)-7 is not, A must equal 5. We get:\n\r\n5*10^(n-1)-7=13B\n\r\nThe least value of n such that 5*10^(n-1)-7 is a multiple of 13 is 6:\n\r\n499993=38461*13\n\r\nThe next is 12, which makes them have more than 1 million dollars. Hence n=6 and B=38461.\n\r\nTherefore, Sandy has 384615 dollars and Sue has 538461 dollars.\n<|im_start|>answer\nLet X and Y be Sandy's and Sue's amounts of money, respectively. Let Z be the number of dollars in Sandy's statement.\n\r\nThen X+Z=Y-Z and 2(X-Z)=Y+Z. Solving this we get X=5Z and Y=7Z.\n\r\nAccording to Sue's statement, let A be the first digit of Sue's wealth, B be the remaining digits, and n be the number of digits, then Y=A*10^(n-1)+B and X=10B+A.\n\r\n7X=5Y\r\n7*(10B+A)=5*(A*10^(n-1)+B)\r\n(5*10^(n-1)-7)A=65B\n\r\nSince 65B is divisible by 5 and 5*10^(n-1)-7 is not, A must equal 5. We get:\n\r\n5*10^(n-1)-7=13B\n\r\nThe least value of n such that 5*10^(n-1)-7 is a multiple of 13 is 6:\n\r\n499993=38461*13\n\r\nThe next is 12, which makes them have more than 1 million dollars. Hence n=6 and B=38461.\n\r\nTherefore, Sandy has 384615 dollars and Sue has 538461 dollars.\n<|im_end|>" }, { "id": "#17361", "title": "The Case of the Dead Boxer", "fun": 2.43, "difficulty": 2.16, "author": "doggyxp", "desc": "Tony Jack's worldly possessions were laid out on a small table in police headquarters. They consisted of a T-shirt, sneakers, and white cotton trousers. In a pocket of the trousers was a card, which read:\r\n\"July 28. Your weight, 173 lbs. Your fortune, You will enjoy a long life.\"\n\r\n\"His life lasted 22 years,\" Inspector Hobbs told Dr. Hall. \"Late last night,\" he continued, \"we got a call to come to the carnival. Somebody had started up a Ferris wheel. We found a male corpse jack-knifed over a strut. Glancing at the man's battered face, I thought he had been beaten. Then I recognized Tony.\r\n\"Last night Tony fought 'Killer Malone' for the state middleweight title,\" he continued. \"Tony took a pounding. We know he left the arena still pretty dazed. He must have come out to the carnival. He used to be a roustabout, and he knew his way around.\r\n\"It looks like he got here after closing,\" said the inspector, \"used the scale, and then started up the big wheel. He took a ride and fell out. The medical examiner says he died instantly.\"\n\r\nDr Hall, the famed criminologist, contemplated Tony's possessions.\n\r\n\"He might have been killed elsewhere and hung on the strut,\" said Hall. \"I heard rumors of a fix in the Malone fight.\r\n\"It looks to me like Tony refused to take a dive and the mob made him pay the full price. The killers apparently did a clumsy job. To avoid giving themselves away, they changed his clothes and staged the scene out at the Ferris wheel.\"\n\r\nHow did Hall know?", "hint": "Reread the first paragraph.", "answer": "Tony fought on the night of his death for the middleweight, one hundred and sixty pounds. When found, he had on someone else's clothing, for the card in his pocket gave his body weight as an impossible \"173 lbs.\" Tony could not have gained 13 pounds in just a few hours.", "category": "Logic", "date": "04/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTony Jack's worldly possessions were laid out on a small table in police headquarters. They consisted of a T-shirt, sneakers, and white cotton trousers. In a pocket of the trousers was a card, which read:\r\n\"July 28. Your weight, 173 lbs. Your fortune, You will enjoy a long life.\"\n\r\n\"His life lasted 22 years,\" Inspector Hobbs told Dr. Hall. \"Late last night,\" he continued, \"we got a call to come to the carnival. Somebody had started up a Ferris wheel. We found a male corpse jack-knifed over a strut. Glancing at the man's battered face, I thought he had been beaten. Then I recognized Tony.\r\n\"Last night Tony fought 'Killer Malone' for the state middleweight title,\" he continued. \"Tony took a pounding. We know he left the arena still pretty dazed. He must have come out to the carnival. He used to be a roustabout, and he knew his way around.\r\n\"It looks like he got here after closing,\" said the inspector, \"used the scale, and then started up the big wheel. He took a ride and fell out. The medical examiner says he died instantly.\"\n\r\nDr Hall, the famed criminologist, contemplated Tony's possessions.\n\r\n\"He might have been killed elsewhere and hung on the strut,\" said Hall. \"I heard rumors of a fix in the Malone fight.\r\n\"It looks to me like Tony refused to take a dive and the mob made him pay the full price. The killers apparently did a clumsy job. To avoid giving themselves away, they changed his clothes and staged the scene out at the Ferris wheel.\"\n\r\nHow did Hall know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTony fought on the night of his death for the middleweight, one hundred and sixty pounds. When found, he had on someone else's clothing, for the card in his pocket gave his body weight as an impossible \"173 lbs.\" Tony could not have gained 13 pounds in just a few hours.\n<|im_start|>answer\nTony fought on the night of his death for the middleweight, one hundred and sixty pounds. When found, he had on someone else's clothing, for the card in his pocket gave his body weight as an impossible \"173 lbs.\" Tony could not have gained 13 pounds in just a few hours.\n<|im_end|>" }, { "id": "#980", "title": "Oranges", "fun": 2.43, "difficulty": 1.2, "author": "Michelle", "desc": "Joe bought a bag of oranges on Monday, and ate a third of them. On Tuesday he ate half of the remaining oranges. On Wednesday he looked in the bag to find he only had two oranges left. How many oranges were originally in the bag?", "hint": "No hint available.", "answer": "He had 6 oranges to start with, and ate 2 the first day and 2 the second day.", "category": "Math", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe bought a bag of oranges on Monday, and ate a third of them. On Tuesday he ate half of the remaining oranges. On Wednesday he looked in the bag to find he only had two oranges left. How many oranges were originally in the bag?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe had 6 oranges to start with, and ate 2 the first day and 2 the second day.\n<|im_start|>answer\nHe had 6 oranges to start with, and ate 2 the first day and 2 the second day.\n<|im_end|>" }, { "id": "#19639", "title": "Nonsense", "fun": 2.43, "difficulty": 2.52, "author": "icepenguin13", "desc": "What inference can you draw from the following statements:\n\r\n1. Some alligators carry umbrellas in the shower.\r\n2. Only those that know that flying fish live in trees prefer caramel candy to chocolate.\r\n3. Certain days are set aside for alligators to watch rabbits play hockey.\r\n4. Some large reptiles are steeplechasers.\r\n5. Only steeplechasers can watch hockey games.\r\n6.Those alligators that carry umbrellas in the shower know that flying fish live in the trees.\r\n7. Those that prefer chocolate to caramel candy cannot be steeplechasers.\r\n8. Steeplechasers are vegetarians.", "hint": "No hint available.", "answer": "Only alligators that are vegetarians are allowed to watch rabbits play hockey.", "category": "Logic", "date": "11/30/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat inference can you draw from the following statements:\n\r\n1. Some alligators carry umbrellas in the shower.\r\n2. Only those that know that flying fish live in trees prefer caramel candy to chocolate.\r\n3. Certain days are set aside for alligators to watch rabbits play hockey.\r\n4. Some large reptiles are steeplechasers.\r\n5. Only steeplechasers can watch hockey games.\r\n6.Those alligators that carry umbrellas in the shower know that flying fish live in the trees.\r\n7. Those that prefer chocolate to caramel candy cannot be steeplechasers.\r\n8. Steeplechasers are vegetarians.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOnly alligators that are vegetarians are allowed to watch rabbits play hockey.\n<|im_start|>answer\nOnly alligators that are vegetarians are allowed to watch rabbits play hockey.\n<|im_end|>" }, { "id": "#24331", "title": "Pets Reunion", "fun": 2.43, "difficulty": 1.37, "author": "Philly", "desc": "At a recent Pets Anonymous reunion, the attendees were discussing which pets they had recently owned. James used to have a dog. The person who used to own a mouse now owns a cat, but the person who used to have a cat does not have a mouse. Kevin has now or used to have a dog, I can't remember which. Becky has never owned a mouse. Only one person now owns the pet they previously had. Rebecca kept quiet throughout the meeting and nobody mentioned the hamster. Can you determine who owns which pet and what they used to own?", "hint": "No hint available.", "answer": "Name Current pet Previous pet\n\r\nBecky hamster hamster\r\nKevin dog cat\r\nJames mouse dog\r\nRebecca cat mouse", "category": "Logic-Grid", "date": "07/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a recent Pets Anonymous reunion, the attendees were discussing which pets they had recently owned. James used to have a dog. The person who used to own a mouse now owns a cat, but the person who used to have a cat does not have a mouse. Kevin has now or used to have a dog, I can't remember which. Becky has never owned a mouse. Only one person now owns the pet they previously had. Rebecca kept quiet throughout the meeting and nobody mentioned the hamster. Can you determine who owns which pet and what they used to own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName Current pet Previous pet\n\r\nBecky hamster hamster\r\nKevin dog cat\r\nJames mouse dog\r\nRebecca cat mouse\n<|im_start|>answer\nName Current pet Previous pet\n\r\nBecky hamster hamster\r\nKevin dog cat\r\nJames mouse dog\r\nRebecca cat mouse\n<|im_end|>" }, { "id": "#43849", "title": "Happy Families", "fun": 2.43, "difficulty": 0.88, "author": "eggface", "desc": "There are four friends: Ella, Sarah, Mary, and Anne.\r\nEach has a husband whose names are: Fred, James, John, and George.\r\nTheir surnames are: Jones, Smith, Chambers, and Howard.\r\nOne of the women has one child, one has two, one has three, and one has four children.\n\r\nCan you match the women to their husbands, surnames, and number of children using the clues below?\n\r\n1. Ella's surname is neither Smith nor Jones.\r\n2. Sarah has three children.\r\n3. George has had two children with his wife, Mary.\r\n4. Sarah and Ella's surnames are Chambers and Smith.\r\n5. The couple with one child has the surname Jones.\r\n6. James' surname is neither Chambers nor Jones.\r\n7. Fred and Anne have less than three children.", "hint": "No hint available.", "answer": "Ella Chambers is married to John and has four children.\r\nSarah Smith is married to James and has three children.\r\nMary Howard is married to George and has two children.\r\nAnne Jones is married to Fred and has one child.", "category": "Logic-Grid", "date": "01/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four friends: Ella, Sarah, Mary, and Anne.\r\nEach has a husband whose names are: Fred, James, John, and George.\r\nTheir surnames are: Jones, Smith, Chambers, and Howard.\r\nOne of the women has one child, one has two, one has three, and one has four children.\n\r\nCan you match the women to their husbands, surnames, and number of children using the clues below?\n\r\n1. Ella's surname is neither Smith nor Jones.\r\n2. Sarah has three children.\r\n3. George has had two children with his wife, Mary.\r\n4. Sarah and Ella's surnames are Chambers and Smith.\r\n5. The couple with one child has the surname Jones.\r\n6. James' surname is neither Chambers nor Jones.\r\n7. Fred and Anne have less than three children.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nElla Chambers is married to John and has four children.\r\nSarah Smith is married to James and has three children.\r\nMary Howard is married to George and has two children.\r\nAnne Jones is married to Fred and has one child.\n<|im_start|>answer\nElla Chambers is married to John and has four children.\r\nSarah Smith is married to James and has three children.\r\nMary Howard is married to George and has two children.\r\nAnne Jones is married to Fred and has one child.\n<|im_end|>" }, { "id": "#758", "title": "Poor Frog", "fun": 2.43, "difficulty": 1.33, "author": "beans", "desc": "A frog fell into a well that was 12 feet deep. He could jump three feet, but every time he did, he would fall back two feet. How many times did the frog have to jump before he got out of the well?", "hint": "No hint available.", "answer": "10... on the 10th jump he reached 12 feet and was out.", "category": "Math", "date": "08/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA frog fell into a well that was 12 feet deep. He could jump three feet, but every time he did, he would fall back two feet. How many times did the frog have to jump before he got out of the well?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10... on the 10th jump he reached 12 feet and was out.\n<|im_start|>answer\n10... on the 10th jump he reached 12 feet and was out.\n<|im_end|>" }, { "id": "#27852", "title": "Touch Down", "fun": 2.43, "difficulty": 2.09, "author": "peppamintp", "desc": "This past fall's homecoming football game at Albany High School was a joyous occasion. The home team scored five touchdowns while holding its rivals to a score of zero. In addition, five of the top senior players (including the boy whose last name is Hurd) each scored one of the five touchdowns. From this information and the clues below, can you determine each player's full name and the order in which they scored?\n\r\n1. The second one to run the ball past the goal posts and Hixson are Marc and Murphy, in some order; the other three players are the third one to score, Haynes, and Holmes.\n\r\n2. The first player to score a touchdown is either Morris or Murphy.\n\r\n3. The fifth player to get a touchdown and Haynes are Marc and Matt, in some order.\n\r\n4. Mike isn't Hudson.", "hint": "No hint available.", "answer": "1. Marc Hixson, fifth\r\n2. Matt Haynes, fourth\r\n3. Mike Hurd, third\r\n4. Murphy Hudson, second\r\n5. Morris Holmes, first\n\r\nBy clue 1, Marc isn't Haynes. \r\nSince the fifth player to score and Haynes are Marc and Matt, in some order (clue 3), Marc is the fifth player and Matt is Haynes. \r\nBy clue 1, then, Marc is Hixson and Murphy scored second. \r\nMorris scored first (clue 2). \r\nSince Matt Haynes didn't score third (clue 1), he scored fourth. \r\nBy elimination, Mike scored third. \r\nBy clue 1, Holmes didn't score second or third; he scored first. Since Mike isn't Hudson (clue 4), he's Hurd, and Murphy is Hudson.", "category": "Logic", "date": "01/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis past fall's homecoming football game at Albany High School was a joyous occasion. The home team scored five touchdowns while holding its rivals to a score of zero. In addition, five of the top senior players (including the boy whose last name is Hurd) each scored one of the five touchdowns. From this information and the clues below, can you determine each player's full name and the order in which they scored?\n\r\n1. The second one to run the ball past the goal posts and Hixson are Marc and Murphy, in some order; the other three players are the third one to score, Haynes, and Holmes.\n\r\n2. The first player to score a touchdown is either Morris or Murphy.\n\r\n3. The fifth player to get a touchdown and Haynes are Marc and Matt, in some order.\n\r\n4. Mike isn't Hudson.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Marc Hixson, fifth\r\n2. Matt Haynes, fourth\r\n3. Mike Hurd, third\r\n4. Murphy Hudson, second\r\n5. Morris Holmes, first\n\r\nBy clue 1, Marc isn't Haynes. \r\nSince the fifth player to score and Haynes are Marc and Matt, in some order (clue 3), Marc is the fifth player and Matt is Haynes. \r\nBy clue 1, then, Marc is Hixson and Murphy scored second. \r\nMorris scored first (clue 2). \r\nSince Matt Haynes didn't score third (clue 1), he scored fourth. \r\nBy elimination, Mike scored third. \r\nBy clue 1, Holmes didn't score second or third; he scored first. Since Mike isn't Hudson (clue 4), he's Hurd, and Murphy is Hudson.\n<|im_start|>answer\n1. Marc Hixson, fifth\r\n2. Matt Haynes, fourth\r\n3. Mike Hurd, third\r\n4. Murphy Hudson, second\r\n5. Morris Holmes, first\n\r\nBy clue 1, Marc isn't Haynes. \r\nSince the fifth player to score and Haynes are Marc and Matt, in some order (clue 3), Marc is the fifth player and Matt is Haynes. \r\nBy clue 1, then, Marc is Hixson and Murphy scored second. \r\nMorris scored first (clue 2). \r\nSince Matt Haynes didn't score third (clue 1), he scored fourth. \r\nBy elimination, Mike scored third. \r\nBy clue 1, Holmes didn't score second or third; he scored first. Since Mike isn't Hudson (clue 4), he's Hurd, and Murphy is Hudson.\n<|im_end|>" }, { "id": "#4189", "title": "Imprisonment", "fun": 2.43, "difficulty": 1.72, "author": "O_wise_one", "desc": "There once was a man, who was innocent, who was sent to prison, and was to die the next day by beheading. His cell was stone with a dirt floor, and a heavy wooden door that couldn't be opened from the inside. There was a window 15 feet high, but he could not climb the wall. He tried to tunnel out, but the wall went too far underground, so he abandoned that idea. How did he escape?", "hint": "No hint available.", "answer": "He dug a hole, and piled the dirt that he dug out by the window. He climbed up the pile, and out the window.", "category": "Logic", "date": "05/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere once was a man, who was innocent, who was sent to prison, and was to die the next day by beheading. His cell was stone with a dirt floor, and a heavy wooden door that couldn't be opened from the inside. There was a window 15 feet high, but he could not climb the wall. He tried to tunnel out, but the wall went too far underground, so he abandoned that idea. How did he escape?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe dug a hole, and piled the dirt that he dug out by the window. He climbed up the pile, and out the window.\n<|im_start|>answer\nHe dug a hole, and piled the dirt that he dug out by the window. He climbed up the pile, and out the window.\n<|im_end|>" }, { "id": "#44586", "title": "Central Casting", "fun": 2.43, "difficulty": 1.77, "author": "dswilborn", "desc": "A new situation comedy with five main characters is being cast in Hollywood. One of the show's ongoing plots involves the complicated love story between the main characters. From the information below, can you determine the name of the character, their profession, who their love interest is, and what personality 'quirk' that character has?\n\r\nCharacters: Aimee, Bert, Kate, Tom, Lewis\r\nProfession: accountant, banker, fashion consultant, journalist, real estate agent\r\nPersonality Quirk: compulsive, funny, insecure, tough, unreliable\n\r\n1. Two of the male characters are in love with the same woman, but Lewis is not one of those men.\n\r\n2. The real estate agent is good on the job, but is seen as insecure in relationships.\n\r\n3. The five characters are: Tom, the fashion consultant, the compulsive woman in love with Bert, the funny guy, and the real estate agent.\n\r\n4. The accountant and the banker are in love with each other, but the journalist's love for Kate complicates that relationship.\n\r\n5. Though seen as unreliable, Lewis knows he can someday make Aimee love him.\n\r\n6. Tom acts tough, but the real estate agent loves him anyway.\n\r\n7. Kate is in love with the banker.", "hint": "All characters are straight. No one is in love with Lewis.", "answer": "The characters are:\r\nAimee, real estate agent, insecure, loves Tom\r\nBert, banker, funny, loves Kate\r\nKate, accountant, compulsive, loves Bert\r\nLewis, fashion consultant, unreliable, loves Aimee\r\nTom, journalist, tough, loves Kate", "category": "Logic-Grid", "date": "06/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA new situation comedy with five main characters is being cast in Hollywood. One of the show's ongoing plots involves the complicated love story between the main characters. From the information below, can you determine the name of the character, their profession, who their love interest is, and what personality 'quirk' that character has?\n\r\nCharacters: Aimee, Bert, Kate, Tom, Lewis\r\nProfession: accountant, banker, fashion consultant, journalist, real estate agent\r\nPersonality Quirk: compulsive, funny, insecure, tough, unreliable\n\r\n1. Two of the male characters are in love with the same woman, but Lewis is not one of those men.\n\r\n2. The real estate agent is good on the job, but is seen as insecure in relationships.\n\r\n3. The five characters are: Tom, the fashion consultant, the compulsive woman in love with Bert, the funny guy, and the real estate agent.\n\r\n4. The accountant and the banker are in love with each other, but the journalist's love for Kate complicates that relationship.\n\r\n5. Though seen as unreliable, Lewis knows he can someday make Aimee love him.\n\r\n6. Tom acts tough, but the real estate agent loves him anyway.\n\r\n7. Kate is in love with the banker.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe characters are:\r\nAimee, real estate agent, insecure, loves Tom\r\nBert, banker, funny, loves Kate\r\nKate, accountant, compulsive, loves Bert\r\nLewis, fashion consultant, unreliable, loves Aimee\r\nTom, journalist, tough, loves Kate\n<|im_start|>answer\nThe characters are:\r\nAimee, real estate agent, insecure, loves Tom\r\nBert, banker, funny, loves Kate\r\nKate, accountant, compulsive, loves Bert\r\nLewis, fashion consultant, unreliable, loves Aimee\r\nTom, journalist, tough, loves Kate\n<|im_end|>" }, { "id": "#897", "title": "Divide the Will", "fun": 2.43, "difficulty": 2.11, "author": "Michelle", "desc": "An old woman died leaving an estate of $1,000,000. Her estate was divided up among her surviving relatives. Her relatives: Jennie, Bobbie, Ellie, Ginnie, Candie, Dannie, Frannie, Annie, Hollie and Kathie were each given an amount of money. The eccentric woman's will stated that each of her relatives was to be given an amount based on the alphabetic order of their first name. The heirs were listed in the order of their names and thus the order of their gift. Annie received the most and Kathie received the least amount. The difference in the amounts given to each person was to be constant. (i.e. The difference between the amount given to the first and second person on the list was the same as the difference in the amount given to the next-to-last and the last person on the list.)\n\r\nIf Ellie received 108,000, how much did each other person receive?", "hint": "No hint available.", "answer": "Annie - 172,000 \r\nBobbie - 156,000 \r\nCandie - 140,000 \r\nDannie - 124,000 \r\nEllie - 108,000 \r\nFrannie - 92,000 \r\nGinnie - 76,000\r\nHollie - 60,000 \r\nJennie - 44,000 \r\nKathie - 28,000", "category": "Math", "date": "09/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn old woman died leaving an estate of $1,000,000. Her estate was divided up among her surviving relatives. Her relatives: Jennie, Bobbie, Ellie, Ginnie, Candie, Dannie, Frannie, Annie, Hollie and Kathie were each given an amount of money. The eccentric woman's will stated that each of her relatives was to be given an amount based on the alphabetic order of their first name. The heirs were listed in the order of their names and thus the order of their gift. Annie received the most and Kathie received the least amount. The difference in the amounts given to each person was to be constant. (i.e. The difference between the amount given to the first and second person on the list was the same as the difference in the amount given to the next-to-last and the last person on the list.)\n\r\nIf Ellie received 108,000, how much did each other person receive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnnie - 172,000 \r\nBobbie - 156,000 \r\nCandie - 140,000 \r\nDannie - 124,000 \r\nEllie - 108,000 \r\nFrannie - 92,000 \r\nGinnie - 76,000\r\nHollie - 60,000 \r\nJennie - 44,000 \r\nKathie - 28,000\n<|im_start|>answer\nAnnie - 172,000 \r\nBobbie - 156,000 \r\nCandie - 140,000 \r\nDannie - 124,000 \r\nEllie - 108,000 \r\nFrannie - 92,000 \r\nGinnie - 76,000\r\nHollie - 60,000 \r\nJennie - 44,000 \r\nKathie - 28,000\n<|im_end|>" }, { "id": "#42925", "title": "Plain, Plaid, Stripes or Dots", "fun": 2.43, "difficulty": 0.88, "author": "whsprec", "desc": "There are 5 people in a room: Jimmy, Chad, Toby, Keith and Chelsey. Each person has a different color shirt: red, black, green, blue or yellow. Each shirt has a different pattern: plain, plaid, vertical stripes, horizontal stripes or polka dots. Match the person to the shirt and the pattern.\n\r\n1) The polka dot shirt is not black.\r\n2) The plain shirt is not yellow or blue.\r\n3) Keith is wearing a striped red shirt.\r\n4) Toby's name has the same number of letters as either his pattern or color.\r\n5) Chelsey is in polka dots.\r\n6) The horizontal stripes are on Jimmy's green shirt.", "hint": "No hint available.", "answer": "Jimmy is wearing green horizontal stripes.\r\nChad is wearing plain black.\r\nToby is wearing blue plaid.\r\nKeith is wearing red vertical stripes.\r\nChelsey is wearing yellow polka dots.", "category": "Logic-Grid", "date": "08/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 5 people in a room: Jimmy, Chad, Toby, Keith and Chelsey. Each person has a different color shirt: red, black, green, blue or yellow. Each shirt has a different pattern: plain, plaid, vertical stripes, horizontal stripes or polka dots. Match the person to the shirt and the pattern.\n\r\n1) The polka dot shirt is not black.\r\n2) The plain shirt is not yellow or blue.\r\n3) Keith is wearing a striped red shirt.\r\n4) Toby's name has the same number of letters as either his pattern or color.\r\n5) Chelsey is in polka dots.\r\n6) The horizontal stripes are on Jimmy's green shirt.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJimmy is wearing green horizontal stripes.\r\nChad is wearing plain black.\r\nToby is wearing blue plaid.\r\nKeith is wearing red vertical stripes.\r\nChelsey is wearing yellow polka dots.\n<|im_start|>answer\nJimmy is wearing green horizontal stripes.\r\nChad is wearing plain black.\r\nToby is wearing blue plaid.\r\nKeith is wearing red vertical stripes.\r\nChelsey is wearing yellow polka dots.\n<|im_end|>" }, { "id": "#13861", "title": "Trick or Treat", "fun": 2.43, "difficulty": 1.1, "author": "cool_star", "desc": "Halloween was almost over, and Mr. Green had less than 20 candies left. When the doorbell rang, he thought he would give all the candies away. \n\r\nWhen he opened the door, there were two trick or treaters. He wanted to give away the candies evenly, but he noticed that when he divided the candies in two, there was one left over. \n\r\nAt that point, he saw another trick or treater behind the first two. He tried to divide the candies evenly among the three of them, but again one was left over. \n\r\nFinally, another trick or treater came to his door, making it four trick or treaters altogether. Mr. Green still had one candy left over after dividing the left over candies in fours. \n\r\nHow many candies did Mr. Green have left when the doorbell rang?", "hint": "No hint available.", "answer": "Mr. Green had 13 candies left over. 13 is the only number under 20 that fits the description (it is one more than 12, which is evenly divisible by 2, 3, and 4).", "category": "Math", "date": "07/17/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHalloween was almost over, and Mr. Green had less than 20 candies left. When the doorbell rang, he thought he would give all the candies away. \n\r\nWhen he opened the door, there were two trick or treaters. He wanted to give away the candies evenly, but he noticed that when he divided the candies in two, there was one left over. \n\r\nAt that point, he saw another trick or treater behind the first two. He tried to divide the candies evenly among the three of them, but again one was left over. \n\r\nFinally, another trick or treater came to his door, making it four trick or treaters altogether. Mr. Green still had one candy left over after dividing the left over candies in fours. \n\r\nHow many candies did Mr. Green have left when the doorbell rang?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Green had 13 candies left over. 13 is the only number under 20 that fits the description (it is one more than 12, which is evenly divisible by 2, 3, and 4).\n<|im_start|>answer\nMr. Green had 13 candies left over. 13 is the only number under 20 that fits the description (it is one more than 12, which is evenly divisible by 2, 3, and 4).\n<|im_end|>" }, { "id": "#48181", "title": "Crossed Crocodiles", "fun": 2.42, "difficulty": 1.07, "author": "dalfamnest", "desc": "On a recent visit to the local Crocodile Rehabilitation Unit I took a photo of the rectangular area where several were kept to recover from injuries.\n\r\nThere was at least one very large crocodile in each of the four corners of the area. Opposite each crocodile were three crocodiles, and at each crocodile's tail lay at least one crocodile.\n\r\nWhat is the smallest number of crocodiles that would make this photo description possible?", "hint": "It was not a very large area.", "answer": "Four crocodiles were in my photo. Each one was in a corner of the floor, facing the corner.\n\r\nThus, each crocodile was opposite three others (either across or diagonally). The area was small enough so that their tails were almost touching as they pondered their escape!\n\r\nThe diagram below illustrates this solution.\n\r\n\\ /\r\n/ \\", "category": "Logic", "date": "11/07/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a recent visit to the local Crocodile Rehabilitation Unit I took a photo of the rectangular area where several were kept to recover from injuries.\n\r\nThere was at least one very large crocodile in each of the four corners of the area. Opposite each crocodile were three crocodiles, and at each crocodile's tail lay at least one crocodile.\n\r\nWhat is the smallest number of crocodiles that would make this photo description possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFour crocodiles were in my photo. Each one was in a corner of the floor, facing the corner.\n\r\nThus, each crocodile was opposite three others (either across or diagonally). The area was small enough so that their tails were almost touching as they pondered their escape!\n\r\nThe diagram below illustrates this solution.\n\r\n\\ /\r\n/ \\\n<|im_start|>answer\nFour crocodiles were in my photo. Each one was in a corner of the floor, facing the corner.\n\r\nThus, each crocodile was opposite three others (either across or diagonally). The area was small enough so that their tails were almost touching as they pondered their escape!\n\r\nThe diagram below illustrates this solution.\n\r\n\\ /\r\n/ \\\n<|im_end|>" }, { "id": "#28959", "title": "Rapid Readers", "fun": 2.42, "difficulty": 1.31, "author": "shenqiang", "desc": "Heather, Ankit, Margaret, Kareem and Roger are each reading the same book for a school book report. The book's 12 chapters are each 11 pages long.\n\r\nClues:\n\r\n1. Heather planned to read half the book in 2 days. Now she's halfway toward that goal. \r\n2. Ankit has read 4 chapters so far. \r\n3. Margaret has read 20 pages past the halfway mark. \r\n4. Kareem is 25 pages past the halfway mark. \r\n5. Roger has only 2 chapters to go. \n\r\nHow many pages has each person read?", "hint": "There are several ways to solve this problem. One is to find the total number of pages in the book and take it from there.", "answer": "Heather has read 33 pages.\r\nAnkit has read 44 pages.\r\nMargaret has read 86 pages.\r\nKareem has read 91 pages.\r\nRoger has read 110 pages.", "category": "Math", "date": "03/07/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHeather, Ankit, Margaret, Kareem and Roger are each reading the same book for a school book report. The book's 12 chapters are each 11 pages long.\n\r\nClues:\n\r\n1. Heather planned to read half the book in 2 days. Now she's halfway toward that goal. \r\n2. Ankit has read 4 chapters so far. \r\n3. Margaret has read 20 pages past the halfway mark. \r\n4. Kareem is 25 pages past the halfway mark. \r\n5. Roger has only 2 chapters to go. \n\r\nHow many pages has each person read?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHeather has read 33 pages.\r\nAnkit has read 44 pages.\r\nMargaret has read 86 pages.\r\nKareem has read 91 pages.\r\nRoger has read 110 pages.\n<|im_start|>answer\nHeather has read 33 pages.\r\nAnkit has read 44 pages.\r\nMargaret has read 86 pages.\r\nKareem has read 91 pages.\r\nRoger has read 110 pages.\n<|im_end|>" }, { "id": "#1043", "title": "World Cup", "fun": 2.42, "difficulty": 1.71, "author": "vivek", "desc": "An alien spaceship landed on Earth. They knew that earthlings are divided into three groups: those who always tell the truth, those who always lie, and those who do both, alternating between true and false statements, starting with either.\n\r\n\"Let's go!\" said the alien captain.\n\r\nThe aliens approached three earthlings, who each were from a different group, and asked, \"Who won the last World Cup? Who came in second? Who came in third?\"\r\nOne of them responded, \"Zaire first. Uruguay second. Spain third.\"\n\r\nAnother one said, \"Zaire first. Spain second. Uruguay third.\"\n\r\nThe third one said, \"Uruguay first. Spain second. Zaire third.\"\n\r\nThe aliens returned to their spaceship and flew back to where they came from. Do you know which response was the true ranking in the World Cup?", "hint": "No hint available.", "answer": "Uruguay came in first, Spain second, Zaire third.", "category": "Logic", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn alien spaceship landed on Earth. They knew that earthlings are divided into three groups: those who always tell the truth, those who always lie, and those who do both, alternating between true and false statements, starting with either.\n\r\n\"Let's go!\" said the alien captain.\n\r\nThe aliens approached three earthlings, who each were from a different group, and asked, \"Who won the last World Cup? Who came in second? Who came in third?\"\r\nOne of them responded, \"Zaire first. Uruguay second. Spain third.\"\n\r\nAnother one said, \"Zaire first. Spain second. Uruguay third.\"\n\r\nThe third one said, \"Uruguay first. Spain second. Zaire third.\"\n\r\nThe aliens returned to their spaceship and flew back to where they came from. Do you know which response was the true ranking in the World Cup?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUruguay came in first, Spain second, Zaire third.\n<|im_start|>answer\nUruguay came in first, Spain second, Zaire third.\n<|im_end|>" }, { "id": "#1261", "title": "Sheep Selling Trip", "fun": 2.42, "difficulty": 1.87, "author": "Rado", "desc": "A farmer wants to sell sheep at a fair which lies on the other side of the hill under which he lives. In order to get there in time, he needs to travel at an average speed of 60km/h. The road is 10km up the hill and 10km down the hill. However, his car can go up the hill at maximum of 30km/h. How fast does he need to go down the hill to meet the average speed he has set?", "hint": "It is not 90km/h and it is not 120km/h either.", "answer": "He would need an infinite speed which means he cannot make it. (Explanation: if he needs to travel 20km at 60km/h it will take him 20min; and the up-the-hill part of the trip is 10km at 30km/h which takes 20min so he has no time left for the down-the-hill part of the trip)", "category": "Math", "date": "11/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA farmer wants to sell sheep at a fair which lies on the other side of the hill under which he lives. In order to get there in time, he needs to travel at an average speed of 60km/h. The road is 10km up the hill and 10km down the hill. However, his car can go up the hill at maximum of 30km/h. How fast does he need to go down the hill to meet the average speed he has set?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe would need an infinite speed which means he cannot make it. (Explanation: if he needs to travel 20km at 60km/h it will take him 20min; and the up-the-hill part of the trip is 10km at 30km/h which takes 20min so he has no time left for the down-the-hill part of the trip)\n<|im_start|>answer\nHe would need an infinite speed which means he cannot make it. (Explanation: if he needs to travel 20km at 60km/h it will take him 20min; and the up-the-hill part of the trip is 10km at 30km/h which takes 20min so he has no time left for the down-the-hill part of the trip)\n<|im_end|>" }, { "id": "#22796", "title": "Can You Figure", "fun": 2.42, "difficulty": 1.77, "author": "fishmed", "desc": "Using the digits 0-9, only once each time, can you solve the below equation? \n\r\nAB8C\r\n+ D4\r\n------\r\n6EF1", "hint": "No hint available.", "answer": "5987\r\n+ 34\r\n------\r\n6021", "category": "Math", "date": "05/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the digits 0-9, only once each time, can you solve the below equation? \n\r\nAB8C\r\n+ D4\r\n------\r\n6EF1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5987\r\n+ 34\r\n------\r\n6021\n<|im_start|>answer\n5987\r\n+ 34\r\n------\r\n6021\n<|im_end|>" }, { "id": "#29450", "title": "A Van", "fun": 2.42, "difficulty": 1.91, "author": "BobbyKat", "desc": "A van travels a maximum of 100 km/h. Its speed decreases in proportion with the number of passengers. The van can carry a maximum of seven people. Given that the van can travel 88 km/h with 3 people in the van, what will be the speed of the van when 6 people are on board?", "hint": "(100-88)/3=4 km/hr/person", "answer": "100 - 3t = 88 \r\n100 - 88 = 3t \r\nt = 12/3 \r\nt = 4 km/h reduction in speed per person \r\nWhen six persons are on board, the van travels at \r\n100 - 6t = 100 - 6(4) = 76 km/h.", "category": "Math", "date": "03/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA van travels a maximum of 100 km/h. Its speed decreases in proportion with the number of passengers. The van can carry a maximum of seven people. Given that the van can travel 88 km/h with 3 people in the van, what will be the speed of the van when 6 people are on board?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n100 - 3t = 88 \r\n100 - 88 = 3t \r\nt = 12/3 \r\nt = 4 km/h reduction in speed per person \r\nWhen six persons are on board, the van travels at \r\n100 - 6t = 100 - 6(4) = 76 km/h.\n<|im_start|>answer\n100 - 3t = 88 \r\n100 - 88 = 3t \r\nt = 12/3 \r\nt = 4 km/h reduction in speed per person \r\nWhen six persons are on board, the van travels at \r\n100 - 6t = 100 - 6(4) = 76 km/h.\n<|im_end|>" }, { "id": "#1088", "title": "King Tut", "fun": 2.42, "difficulty": 2.16, "author": "Michelle", "desc": "King Tut died 120 years after King Eros was born. Their combined ages when they died was 100 years. King Eros died in the year 40B.C. In what year was King Tut born?", "hint": "No hint available.", "answer": "He was born 20 B.C. There were 120 years between the birth of King Eros and the death of King Tut, but since their ages amounted to 100 years, there must have been 20 years when neither existed. This would be the period between the death of King Eros, 40 B.C and the birth of King Tut, 20 B.C.", "category": "Math", "date": "10/10/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKing Tut died 120 years after King Eros was born. Their combined ages when they died was 100 years. King Eros died in the year 40B.C. In what year was King Tut born?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe was born 20 B.C. There were 120 years between the birth of King Eros and the death of King Tut, but since their ages amounted to 100 years, there must have been 20 years when neither existed. This would be the period between the death of King Eros, 40 B.C and the birth of King Tut, 20 B.C.\n<|im_start|>answer\nHe was born 20 B.C. There were 120 years between the birth of King Eros and the death of King Tut, but since their ages amounted to 100 years, there must have been 20 years when neither existed. This would be the period between the death of King Eros, 40 B.C and the birth of King Tut, 20 B.C.\n<|im_end|>" }, { "id": "#20043", "title": "The Cunning Farmer", "fun": 2.42, "difficulty": 1.87, "author": "joegro01", "desc": "A cunning farmer, when asked how many sheep he has, replied, \"One third of my sheep are in the barn, and one fifth are in the pasture. Three times the difference between these two numbers equals the amount of newborns. My daughter has one as a pet.\"\n\r\nHow many sheep does the farmer have?", "hint": "No hint available.", "answer": "15.\n\r\n5 in the barn, 3 in the pasture, 3*(5-3) or 6 newborns, and one pet.", "category": "Math", "date": "12/21/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cunning farmer, when asked how many sheep he has, replied, \"One third of my sheep are in the barn, and one fifth are in the pasture. Three times the difference between these two numbers equals the amount of newborns. My daughter has one as a pet.\"\n\r\nHow many sheep does the farmer have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15.\n\r\n5 in the barn, 3 in the pasture, 3*(5-3) or 6 newborns, and one pet.\n<|im_start|>answer\n15.\n\r\n5 in the barn, 3 in the pasture, 3*(5-3) or 6 newborns, and one pet.\n<|im_end|>" }, { "id": "#27804", "title": "Paper Rolls", "fun": 2.42, "difficulty": 2.0, "author": "achnid", "desc": "Can you roll a rectangular piece of paper one way and make it change which way it is rolled without unrolling it?\n\r\nFor example, roll it the long way and change it to be rolled the short way.", "hint": "It's easier with a larger piece of paper.", "answer": "Yes, this is possible. \n\r\n1: Take a piece of paper and roll it up. \r\n2: Push one side of the roll out so it makes a cone shape.\r\n3: Continue in the same general direction with slight rolling.\n\r\nEventually, it will change to being closer to the other type of roll and you just have to coax it a little bit to finish the roll.\n\r\nThis can be done either way you roll the paper and you can make it go back and forth doing this.", "category": "Logic", "date": "01/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you roll a rectangular piece of paper one way and make it change which way it is rolled without unrolling it?\n\r\nFor example, roll it the long way and change it to be rolled the short way.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes, this is possible. \n\r\n1: Take a piece of paper and roll it up. \r\n2: Push one side of the roll out so it makes a cone shape.\r\n3: Continue in the same general direction with slight rolling.\n\r\nEventually, it will change to being closer to the other type of roll and you just have to coax it a little bit to finish the roll.\n\r\nThis can be done either way you roll the paper and you can make it go back and forth doing this.\n<|im_start|>answer\nYes, this is possible. \n\r\n1: Take a piece of paper and roll it up. \r\n2: Push one side of the roll out so it makes a cone shape.\r\n3: Continue in the same general direction with slight rolling.\n\r\nEventually, it will change to being closer to the other type of roll and you just have to coax it a little bit to finish the roll.\n\r\nThis can be done either way you roll the paper and you can make it go back and forth doing this.\n<|im_end|>" }, { "id": "#24910", "title": "Class Pets", "fun": 2.42, "difficulty": 0.63, "author": "teaserboy", "desc": "At Glendale Elementary school there are five classes (1st, 2nd, 3rd, 4th, and 5th grade), and each class has a different amount of students (25, 30, 35, 40, and 45). Plus each class has a different pet (turtle, frog, fish, bunny, and snake). Using the clues below, determine how many students are in each class and what pet they have.\n\r\n2nd grade has the least amount of students.\n\r\n5th grade wanted the snake, but got the bunny.\n\r\n1st grade, which is stuck in the middle student-wise, thought that its pet snake was scary.\n\r\n4th grade , which isn't the largest class, has a fish.\n\r\nThe turtle is in the largest class.\n\r\nThe second biggest class got the bunny.", "hint": "No hint available.", "answer": "1st: 35, snake\r\n2nd: 25, frog\r\n3rd: 45, turtle\r\n4th: 30, fish\r\n5th: 40, bunny", "category": "Logic-Grid", "date": "07/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt Glendale Elementary school there are five classes (1st, 2nd, 3rd, 4th, and 5th grade), and each class has a different amount of students (25, 30, 35, 40, and 45). Plus each class has a different pet (turtle, frog, fish, bunny, and snake). Using the clues below, determine how many students are in each class and what pet they have.\n\r\n2nd grade has the least amount of students.\n\r\n5th grade wanted the snake, but got the bunny.\n\r\n1st grade, which is stuck in the middle student-wise, thought that its pet snake was scary.\n\r\n4th grade , which isn't the largest class, has a fish.\n\r\nThe turtle is in the largest class.\n\r\nThe second biggest class got the bunny.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st: 35, snake\r\n2nd: 25, frog\r\n3rd: 45, turtle\r\n4th: 30, fish\r\n5th: 40, bunny\n<|im_start|>answer\n1st: 35, snake\r\n2nd: 25, frog\r\n3rd: 45, turtle\r\n4th: 30, fish\r\n5th: 40, bunny\n<|im_end|>" }, { "id": "#10080", "title": "Logical Light-up", "fun": 2.42, "difficulty": 1.96, "author": "Melly", "desc": "As Miss Earwig entered the interview room, her four inquisitors sat behind the oak table watching her. Earwig mentally ordered them from left to right and noted the following facts:\n\r\n1. The pipe smoker sat immediately to the right of Mr. Blowtorch. \r\n2. Mr. Crumpet did not smoke cigarettes. \r\n3. Neither Mr. Crumpet nor Mr. Drivel were third. \r\n4. The cigarette smoker sat immediately to the left of Mr. Amoeba. \r\n5. Mr. Crumpet was not the cigar smoker. \r\n6. The cigar smoker sat immediately to the left of the cigarette smoker. \r\n7. The cigar smoker was neither second nor third. \n\r\nAssuming no interrogator smoked two different items, can you find the name and smoking habit for each position?", "hint": "No hint available.", "answer": "1 \r\nDrivel \r\nCigar \n\r\n2 \r\nBlowtorch \r\nCigarette \n\r\n3 \r\nAmoeba \r\nPipe \n\r\n4 \r\nCrumpet \r\nNonsmoker", "category": "Logic", "date": "01/27/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAs Miss Earwig entered the interview room, her four inquisitors sat behind the oak table watching her. Earwig mentally ordered them from left to right and noted the following facts:\n\r\n1. The pipe smoker sat immediately to the right of Mr. Blowtorch. \r\n2. Mr. Crumpet did not smoke cigarettes. \r\n3. Neither Mr. Crumpet nor Mr. Drivel were third. \r\n4. The cigarette smoker sat immediately to the left of Mr. Amoeba. \r\n5. Mr. Crumpet was not the cigar smoker. \r\n6. The cigar smoker sat immediately to the left of the cigarette smoker. \r\n7. The cigar smoker was neither second nor third. \n\r\nAssuming no interrogator smoked two different items, can you find the name and smoking habit for each position?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 \r\nDrivel \r\nCigar \n\r\n2 \r\nBlowtorch \r\nCigarette \n\r\n3 \r\nAmoeba \r\nPipe \n\r\n4 \r\nCrumpet \r\nNonsmoker\n<|im_start|>answer\n1 \r\nDrivel \r\nCigar \n\r\n2 \r\nBlowtorch \r\nCigarette \n\r\n3 \r\nAmoeba \r\nPipe \n\r\n4 \r\nCrumpet \r\nNonsmoker\n<|im_end|>" }, { "id": "#29673", "title": "Bales of Hay", "fun": 2.42, "difficulty": 2.6, "author": "medster99", "desc": "A farmer was weighing five bales of hay, and each bale was a different weight. Because he was an odd farmer, he weighed the hay bales in groups of two, in every possible combination (but 2-3 and 3-2 are the same). The farmer wrote down the total weights, but forgot to match them to the groups of hay bales (1&2, 1&3 etc.) that they went with. The weights were 80, 82, 83, 84, 85, 86, 87, 88, 90, and 91 kilograms. \r\nThe task is to find out how much each bale of hay weighs and what combinations of bales made each total weight.", "hint": "No hint available.", "answer": "Hay bale #1- 39 kg\r\nHay bale #2- 41 kg\r\nHay bale #3- 43 kg\r\nHay bale #4- 44 kg\r\nHay bale #5- 47 kg\n\r\n Total\r\nWeight....Bale....Bale Weights\r\n...80....| 1 + 2 |....39 + 41\r\n...82....| 1 + 3 |....39 + 43\r\n...83....| 1 + 4 |....39 + 44\r\n...84....| 2 + 3 |....41 + 43\r\n...85....| 2 + 4 |....41 + 44\r\n...86....| 1 + 5 |....39 + 47\r\n...87....| 3 + 4 |....43 + 44\r\n...88....| 2 + 5 |....41 + 47\r\n...90....| 3 + 5 |....43 + 47\r\n...91....| 4 + 5 |....44 + 47", "category": "Math", "date": "04/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA farmer was weighing five bales of hay, and each bale was a different weight. Because he was an odd farmer, he weighed the hay bales in groups of two, in every possible combination (but 2-3 and 3-2 are the same). The farmer wrote down the total weights, but forgot to match them to the groups of hay bales (1&2, 1&3 etc.) that they went with. The weights were 80, 82, 83, 84, 85, 86, 87, 88, 90, and 91 kilograms. \r\nThe task is to find out how much each bale of hay weighs and what combinations of bales made each total weight.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHay bale #1- 39 kg\r\nHay bale #2- 41 kg\r\nHay bale #3- 43 kg\r\nHay bale #4- 44 kg\r\nHay bale #5- 47 kg\n\r\n Total\r\nWeight....Bale....Bale Weights\r\n...80....| 1 + 2 |....39 + 41\r\n...82....| 1 + 3 |....39 + 43\r\n...83....| 1 + 4 |....39 + 44\r\n...84....| 2 + 3 |....41 + 43\r\n...85....| 2 + 4 |....41 + 44\r\n...86....| 1 + 5 |....39 + 47\r\n...87....| 3 + 4 |....43 + 44\r\n...88....| 2 + 5 |....41 + 47\r\n...90....| 3 + 5 |....43 + 47\r\n...91....| 4 + 5 |....44 + 47\n<|im_start|>answer\nHay bale #1- 39 kg\r\nHay bale #2- 41 kg\r\nHay bale #3- 43 kg\r\nHay bale #4- 44 kg\r\nHay bale #5- 47 kg\n\r\n Total\r\nWeight....Bale....Bale Weights\r\n...80....| 1 + 2 |....39 + 41\r\n...82....| 1 + 3 |....39 + 43\r\n...83....| 1 + 4 |....39 + 44\r\n...84....| 2 + 3 |....41 + 43\r\n...85....| 2 + 4 |....41 + 44\r\n...86....| 1 + 5 |....39 + 47\r\n...87....| 3 + 4 |....43 + 44\r\n...88....| 2 + 5 |....41 + 47\r\n...90....| 3 + 5 |....43 + 47\r\n...91....| 4 + 5 |....44 + 47\n<|im_end|>" }, { "id": "#29508", "title": "Question Mark's Function Machine MKII", "fun": 2.42, "difficulty": 2.68, "author": "Question_Mark", "desc": "Question Mark has re-written the formula of his function machine. If a number goes in, a different number comes out. If:\n\r\n7 -> 315\r\n8 -> 480\r\n9 -> 693\r\n10 -> 960\r\n11 -> 1287\n\r\nWhat will come out if 20 goes in?", "hint": "No hint available.", "answer": "7920. The formula is n^3 - n*4. In other words:\n\r\n7^3 (343) - 7*4 (28) = 315\r\n8^3 (512) - 8*4 (32) = 480\r\n9^3 (729) - 9*4 (36) = 693\r\n10^3 (1000) - 10*4 (40) = 960\r\n11^3 (1331) - 11*4 (44) = 1287\n\r\nAnd therefore:\r\n20^3 (8000) - 20*4 (80) = 7920.", "category": "Math", "date": "04/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuestion Mark has re-written the formula of his function machine. If a number goes in, a different number comes out. If:\n\r\n7 -> 315\r\n8 -> 480\r\n9 -> 693\r\n10 -> 960\r\n11 -> 1287\n\r\nWhat will come out if 20 goes in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7920. The formula is n^3 - n*4. In other words:\n\r\n7^3 (343) - 7*4 (28) = 315\r\n8^3 (512) - 8*4 (32) = 480\r\n9^3 (729) - 9*4 (36) = 693\r\n10^3 (1000) - 10*4 (40) = 960\r\n11^3 (1331) - 11*4 (44) = 1287\n\r\nAnd therefore:\r\n20^3 (8000) - 20*4 (80) = 7920.\n<|im_start|>answer\n7920. The formula is n^3 - n*4. In other words:\n\r\n7^3 (343) - 7*4 (28) = 315\r\n8^3 (512) - 8*4 (32) = 480\r\n9^3 (729) - 9*4 (36) = 693\r\n10^3 (1000) - 10*4 (40) = 960\r\n11^3 (1331) - 11*4 (44) = 1287\n\r\nAnd therefore:\r\n20^3 (8000) - 20*4 (80) = 7920.\n<|im_end|>" }, { "id": "#35647", "title": "Opposites 28", "fun": 2.42, "difficulty": 2.15, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n@ stands for J, O, N, K, or E\r\n/ stands for E, Y, M, L, or F\r\n) stands for G, J, O, L, or B\r\n\\ stands for U, P, D, B, or R \r\n( stands for S, I, G, T, or A \n\r\nThe five letter code word, /(@)\\, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Major and Minor.", "category": "Logic", "date": "03/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n@ stands for J, O, N, K, or E\r\n/ stands for E, Y, M, L, or F\r\n) stands for G, J, O, L, or B\r\n\\ stands for U, P, D, B, or R \r\n( stands for S, I, G, T, or A \n\r\nThe five letter code word, /(@)\\, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMajor and Minor.\n<|im_start|>answer\nMajor and Minor.\n<|im_end|>" }, { "id": "#24115", "title": "School Reunion", "fun": 2.42, "difficulty": 1.22, "author": "katey", "desc": "During a recent school reunion, four men were discussing their starting salaries back in 1962. The salaries in question were, 8, 10, 12 and 14 thousand pounds per year.\n\r\nOf course the MP earned the most.\r\nAlan earned more than Brian and the doctor earned more than Derek, the vet. \r\nCharles could not remember what he started on. \r\nBrian, the lawyer, did not start on £10,000 nor did Derek. \n\r\nCan you determine who has which job and their starting salaries?", "hint": "No hint available.", "answer": "Name, Profession, Salary\r\nAlan, MP, £14,000\r\nBrian, lawyer, £12,000\r\nCharles, doctor, £10,000\r\nDerek, vet, £ 8,000", "category": "Logic-Grid", "date": "06/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a recent school reunion, four men were discussing their starting salaries back in 1962. The salaries in question were, 8, 10, 12 and 14 thousand pounds per year.\n\r\nOf course the MP earned the most.\r\nAlan earned more than Brian and the doctor earned more than Derek, the vet. \r\nCharles could not remember what he started on. \r\nBrian, the lawyer, did not start on £10,000 nor did Derek. \n\r\nCan you determine who has which job and their starting salaries?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName, Profession, Salary\r\nAlan, MP, £14,000\r\nBrian, lawyer, £12,000\r\nCharles, doctor, £10,000\r\nDerek, vet, £ 8,000\n<|im_start|>answer\nName, Profession, Salary\r\nAlan, MP, £14,000\r\nBrian, lawyer, £12,000\r\nCharles, doctor, £10,000\r\nDerek, vet, £ 8,000\n<|im_end|>" }, { "id": "#29323", "title": "Arriving at the Area", "fun": 2.42, "difficulty": 2.08, "author": "shenqiang", "desc": "Ramona's parents have promised her a beautiful new blue carpet for her room. All she has to do is figure out how many square feet her room is.\n\r\nRamona measures her room with a tape measure. It is 9 ft 6 in. long and 7 ft 3 in. wide. In one of the longer sides is an alcove, 4 ft wide and 2 ft deep, where Ramona keeps her horse collection on shelves. On the opposite side, the radiator stands in front of the wall. It is 15 in. deep and 27 in. wide. The carpet can't go under it. As long as she is carpeting the room, Ramona has decided to put a piece of carpet on top of her built-in dresser. The dresser covers the floor and sticks out 18 in. from one of the short walls and is 32 in. wide.\n\r\nHow many square feet of carpet does Ramona need for her room, to the nearest whole square foot?", "hint": "Rewrite the inches as decimal fractions of a foot.", "answer": "Room's area: 9.5ft*7.25ft=68.88sqft\r\nAlcove's area: 4.0ft*2.0ft=8.00sqft\r\nradiator's area: 1.25ft*2.25ft=2.81sqft\n\r\n68.88+8.00-2.81=74.07\n\r\nRounding up to the nearest whole number, Ramona needs 75 square feet of carpet. There is no carpet underneath the built-in dresser, so carpeting its top doesn't add to or subtract from the room's area.", "category": "Math", "date": "03/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRamona's parents have promised her a beautiful new blue carpet for her room. All she has to do is figure out how many square feet her room is.\n\r\nRamona measures her room with a tape measure. It is 9 ft 6 in. long and 7 ft 3 in. wide. In one of the longer sides is an alcove, 4 ft wide and 2 ft deep, where Ramona keeps her horse collection on shelves. On the opposite side, the radiator stands in front of the wall. It is 15 in. deep and 27 in. wide. The carpet can't go under it. As long as she is carpeting the room, Ramona has decided to put a piece of carpet on top of her built-in dresser. The dresser covers the floor and sticks out 18 in. from one of the short walls and is 32 in. wide.\n\r\nHow many square feet of carpet does Ramona need for her room, to the nearest whole square foot?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRoom's area: 9.5ft*7.25ft=68.88sqft\r\nAlcove's area: 4.0ft*2.0ft=8.00sqft\r\nradiator's area: 1.25ft*2.25ft=2.81sqft\n\r\n68.88+8.00-2.81=74.07\n\r\nRounding up to the nearest whole number, Ramona needs 75 square feet of carpet. There is no carpet underneath the built-in dresser, so carpeting its top doesn't add to or subtract from the room's area.\n<|im_start|>answer\nRoom's area: 9.5ft*7.25ft=68.88sqft\r\nAlcove's area: 4.0ft*2.0ft=8.00sqft\r\nradiator's area: 1.25ft*2.25ft=2.81sqft\n\r\n68.88+8.00-2.81=74.07\n\r\nRounding up to the nearest whole number, Ramona needs 75 square feet of carpet. There is no carpet underneath the built-in dresser, so carpeting its top doesn't add to or subtract from the room's area.\n<|im_end|>" }, { "id": "#40124", "title": "3-digit Number", "fun": 2.42, "difficulty": 1.53, "author": "shenqiang", "desc": "There's a 3-digit number. The sum of its digits is 10, the product of its digits is 20, and it is divisible by 7. What is the 3-digit number?", "hint": "No hint available.", "answer": "The 1-digit factors of 20 are 1, 2, 4 and 5, therefore, the number is made up of 1, 4 and 5.\n\r\nOut of the six numbers formed by the 3 digits, 145, 154, 415, 451, 514 and 541, only 154 is divisible by 7.", "category": "Math", "date": "01/19/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere's a 3-digit number. The sum of its digits is 10, the product of its digits is 20, and it is divisible by 7. What is the 3-digit number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 1-digit factors of 20 are 1, 2, 4 and 5, therefore, the number is made up of 1, 4 and 5.\n\r\nOut of the six numbers formed by the 3 digits, 145, 154, 415, 451, 514 and 541, only 154 is divisible by 7.\n<|im_start|>answer\nThe 1-digit factors of 20 are 1, 2, 4 and 5, therefore, the number is made up of 1, 4 and 5.\n\r\nOut of the six numbers formed by the 3 digits, 145, 154, 415, 451, 514 and 541, only 154 is divisible by 7.\n<|im_end|>" }, { "id": "#8363", "title": "The Bookworm", "fun": 2.42, "difficulty": 2.08, "author": "something", "desc": "A bookworm eats from the first page of encyclopedia number 1 to the last page of encyclopaedia number 5. The bookworm eats in a straight line. Each encyclopedia consists of 400 pages. Each leaf is 0.01 inches thick and each cover is 0.25 inches thick. What distance does the bookworm eat through?", "hint": "No hint available.", "answer": "The bookworm nibbles his way through approximately eight inches. The first page of the first volume is the rightmost page of the first volume. The last page of the last volume is the leftmost page of the last volume. So the only part of the first volume he eats is the front cover, and the only part of the last volume he eats is the back cover. \r\nThe reason the answer is not fourteen inches is that while each leaf is .01 inches thick, each leaf is two pages. So 400 pages is only two inches thick. \r\nFinally, we say approximately eight inches because it is a matter of semantics whether the bookworm ate the first page of the first volume.", "category": "Math", "date": "11/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bookworm eats from the first page of encyclopedia number 1 to the last page of encyclopaedia number 5. The bookworm eats in a straight line. Each encyclopedia consists of 400 pages. Each leaf is 0.01 inches thick and each cover is 0.25 inches thick. What distance does the bookworm eat through?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe bookworm nibbles his way through approximately eight inches. The first page of the first volume is the rightmost page of the first volume. The last page of the last volume is the leftmost page of the last volume. So the only part of the first volume he eats is the front cover, and the only part of the last volume he eats is the back cover. \r\nThe reason the answer is not fourteen inches is that while each leaf is .01 inches thick, each leaf is two pages. So 400 pages is only two inches thick. \r\nFinally, we say approximately eight inches because it is a matter of semantics whether the bookworm ate the first page of the first volume.\n<|im_start|>answer\nThe bookworm nibbles his way through approximately eight inches. The first page of the first volume is the rightmost page of the first volume. The last page of the last volume is the leftmost page of the last volume. So the only part of the first volume he eats is the front cover, and the only part of the last volume he eats is the back cover. \r\nThe reason the answer is not fourteen inches is that while each leaf is .01 inches thick, each leaf is two pages. So 400 pages is only two inches thick. \r\nFinally, we say approximately eight inches because it is a matter of semantics whether the bookworm ate the first page of the first volume.\n<|im_end|>" }, { "id": "#40835", "title": "More or Less Money", "fun": 2.42, "difficulty": 1.14, "author": "Carlos16", "desc": "After each day, you get one less than twice as many dollars as you got the day before. You get one dollar on March 26, so how many dollars did you get on March 21?", "hint": "No hint available.", "answer": "The number 1 is one less than 2, so if 2 is twice as many dollars as you got the day before, then you got 1 dollar the day before since 2 is twice as much as 1. That means you got 1 dollar on the 26th and the 25th. You can do the same thing with March 25, until you get to March 21. You will get 1 dollar every day, and the pattern will never change.\n\r\nAnswer: 1 dollar", "category": "Logic", "date": "03/03/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter each day, you get one less than twice as many dollars as you got the day before. You get one dollar on March 26, so how many dollars did you get on March 21?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number 1 is one less than 2, so if 2 is twice as many dollars as you got the day before, then you got 1 dollar the day before since 2 is twice as much as 1. That means you got 1 dollar on the 26th and the 25th. You can do the same thing with March 25, until you get to March 21. You will get 1 dollar every day, and the pattern will never change.\n\r\nAnswer: 1 dollar\n<|im_start|>answer\nThe number 1 is one less than 2, so if 2 is twice as many dollars as you got the day before, then you got 1 dollar the day before since 2 is twice as much as 1. That means you got 1 dollar on the 26th and the 25th. You can do the same thing with March 25, until you get to March 21. You will get 1 dollar every day, and the pattern will never change.\n\r\nAnswer: 1 dollar\n<|im_end|>" }, { "id": "#30898", "title": "Video Visions", "fun": 2.42, "difficulty": 2.28, "author": "maxvu", "desc": "Tobin is thinking of joining a video club. He received this offer in the mail:\n\r\n\"Buy 7 videos for just 1 penny apiece! (You must follow either Plan A or Plan B.) \n\r\nPlan A: Buy 2 more videos for $6.95 each with your initial order. Then buy only 3 more videos over the next 3 years at regular club prices.\n\r\nPlan B: Buy only the 7 videos for 1 penny apiece. Then buy 5 videos over the next 3 years at regular club prices. \n\r\nRegular club prices: Each video normally costs between $19.95 and $39.95.\n\r\nSend no money now. We'll bill you later.\"\n\r\nTobin has $23.00 in an empty peanut-butter jar in his room, so he estimates he can afford to send for the 9 movies because they will cost around $14.00. Tobin tells his Uncle Ben about the video deal, and his uncle says, \"Tobe, do yourself a favor and look through the fine print to find out how much they're actually going to bill you for those videos.\" Tobin finds this information:\n\r\nShipping and Handling\n\r\nFor the first 7 movies ... $1.60 each\r\nFor additional movies ... $1.70 each\n\r\nState sales tax on all purchases is 3%. \n\r\nHow many videos can Tobin afford to order right now? Then, how much would it cost Tobin for his total of 12 videos over the next 3 years, using an average of the regular club prices?", "hint": "1. Break down the problem into smaller problems. \r\n2. Shipping and handling charges should not be taxed.", "answer": "Tobin can afford to order only 7 videos right now. The total cost for all 12 videos will be $174.01.\n\r\nPlan A: Tobin will pay $ .07 + (2 * $6.95) = $13.97 for the first 9 videos. With a 3% sales tax, the videos will cost $14.39. However, Tobin must also pay for the shipping costs: (7 * $1.60) + (2 * $1.70) = $14.60, boosting the total price of the first 9 videos to $28.99. He cannot afford this right now, so he must consider Plan B.\n\r\nPlan B: Tobin's initial order will cost $ .07 (including sales tax) + (7 * $1.60) for shipping and handling = $11.27. The average club price is ($19.95 + $39.95) / 2 = $29.95. So the remaining 5 videos will cost 5 * $29.95 = $149.75. With a 3% sales tax, the videos will cost $154.24 + (5 * $1.70) for shipping and handling = $162.74. Adding the cost of the first 7 videos to the cost of the other 5 gives a total cost of $174.01.", "category": "Math", "date": "06/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTobin is thinking of joining a video club. He received this offer in the mail:\n\r\n\"Buy 7 videos for just 1 penny apiece! (You must follow either Plan A or Plan B.) \n\r\nPlan A: Buy 2 more videos for $6.95 each with your initial order. Then buy only 3 more videos over the next 3 years at regular club prices.\n\r\nPlan B: Buy only the 7 videos for 1 penny apiece. Then buy 5 videos over the next 3 years at regular club prices. \n\r\nRegular club prices: Each video normally costs between $19.95 and $39.95.\n\r\nSend no money now. We'll bill you later.\"\n\r\nTobin has $23.00 in an empty peanut-butter jar in his room, so he estimates he can afford to send for the 9 movies because they will cost around $14.00. Tobin tells his Uncle Ben about the video deal, and his uncle says, \"Tobe, do yourself a favor and look through the fine print to find out how much they're actually going to bill you for those videos.\" Tobin finds this information:\n\r\nShipping and Handling\n\r\nFor the first 7 movies ... $1.60 each\r\nFor additional movies ... $1.70 each\n\r\nState sales tax on all purchases is 3%. \n\r\nHow many videos can Tobin afford to order right now? Then, how much would it cost Tobin for his total of 12 videos over the next 3 years, using an average of the regular club prices?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTobin can afford to order only 7 videos right now. The total cost for all 12 videos will be $174.01.\n\r\nPlan A: Tobin will pay $ .07 + (2 * $6.95) = $13.97 for the first 9 videos. With a 3% sales tax, the videos will cost $14.39. However, Tobin must also pay for the shipping costs: (7 * $1.60) + (2 * $1.70) = $14.60, boosting the total price of the first 9 videos to $28.99. He cannot afford this right now, so he must consider Plan B.\n\r\nPlan B: Tobin's initial order will cost $ .07 (including sales tax) + (7 * $1.60) for shipping and handling = $11.27. The average club price is ($19.95 + $39.95) / 2 = $29.95. So the remaining 5 videos will cost 5 * $29.95 = $149.75. With a 3% sales tax, the videos will cost $154.24 + (5 * $1.70) for shipping and handling = $162.74. Adding the cost of the first 7 videos to the cost of the other 5 gives a total cost of $174.01.\n<|im_start|>answer\nTobin can afford to order only 7 videos right now. The total cost for all 12 videos will be $174.01.\n\r\nPlan A: Tobin will pay $ .07 + (2 * $6.95) = $13.97 for the first 9 videos. With a 3% sales tax, the videos will cost $14.39. However, Tobin must also pay for the shipping costs: (7 * $1.60) + (2 * $1.70) = $14.60, boosting the total price of the first 9 videos to $28.99. He cannot afford this right now, so he must consider Plan B.\n\r\nPlan B: Tobin's initial order will cost $ .07 (including sales tax) + (7 * $1.60) for shipping and handling = $11.27. The average club price is ($19.95 + $39.95) / 2 = $29.95. So the remaining 5 videos will cost 5 * $29.95 = $149.75. With a 3% sales tax, the videos will cost $154.24 + (5 * $1.70) for shipping and handling = $162.74. Adding the cost of the first 7 videos to the cost of the other 5 gives a total cost of $174.01.\n<|im_end|>" }, { "id": "#32492", "title": "Soccer Project", "fun": 2.42, "difficulty": 1.36, "author": "grungy49", "desc": "Daniel is a keen soccer fan in the soccer-mad town of Tammell. He barracks for four different local clubs! He picked one player from each team to do his school project on. He was sure he had remembered everything perfectly until he was asked to present his project. He was about to talk about his favourite players but he found he couldn't remember which was in which team and where each one played! He found he couldn't even remember their last names! Now it's your turn to save him from a certain F. \n\r\nUsing the clues your job is to find out what each player's first and last name is, what position they play, and what club they play for. \n\r\nGood luck, and hurry - the class is waiting! \n\r\nClues\r\n1. Sam plays in the midfield and his last name rhymes with Frank's.\r\n2. Mr Bracken plays for the Strikers, but isn't a striker in the game.\r\n3. Norsewick were proud to recruit Thomas, their newest defender.\r\n4. Mr Mayne is a goalie in Castleton.\r\n5. Frank is a striker.\r\n6. Mr Miller, who plays for Redland, isn't a midfielder.", "hint": "No hint available.", "answer": "Frank Miller is a striker in Redland.\r\nJoseph Mayne is a goalie in Castleton.\r\nThomas Bracken is a defender in Norsewick.\r\nSam Tillah is a midfielder in Greenham.", "category": "Logic-Grid", "date": "08/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDaniel is a keen soccer fan in the soccer-mad town of Tammell. He barracks for four different local clubs! He picked one player from each team to do his school project on. He was sure he had remembered everything perfectly until he was asked to present his project. He was about to talk about his favourite players but he found he couldn't remember which was in which team and where each one played! He found he couldn't even remember their last names! Now it's your turn to save him from a certain F. \n\r\nUsing the clues your job is to find out what each player's first and last name is, what position they play, and what club they play for. \n\r\nGood luck, and hurry - the class is waiting! \n\r\nClues\r\n1. Sam plays in the midfield and his last name rhymes with Frank's.\r\n2. Mr Bracken plays for the Strikers, but isn't a striker in the game.\r\n3. Norsewick were proud to recruit Thomas, their newest defender.\r\n4. Mr Mayne is a goalie in Castleton.\r\n5. Frank is a striker.\r\n6. Mr Miller, who plays for Redland, isn't a midfielder.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrank Miller is a striker in Redland.\r\nJoseph Mayne is a goalie in Castleton.\r\nThomas Bracken is a defender in Norsewick.\r\nSam Tillah is a midfielder in Greenham.\n<|im_start|>answer\nFrank Miller is a striker in Redland.\r\nJoseph Mayne is a goalie in Castleton.\r\nThomas Bracken is a defender in Norsewick.\r\nSam Tillah is a midfielder in Greenham.\n<|im_end|>" }, { "id": "#23538", "title": "The 5 Friends", "fun": 2.42, "difficulty": 0.84, "author": "Hatedsgurl", "desc": "There are 5 friends going to a movie (Chris, Joey, Andy, Kelsey, & Tina). How are they standing in line for a ticket?\n\r\nChris is in front of Andy.\r\nKelsey is behind Andy.\r\nTina is behind Joey.\r\nJoey is in front of Chris.\r\nTina is in front of Andy.\r\nTina is behind Chris.", "hint": "No hint available.", "answer": "Joey, Chris, Tina, Andy, Kelsey", "category": "Logic", "date": "06/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 5 friends going to a movie (Chris, Joey, Andy, Kelsey, & Tina). How are they standing in line for a ticket?\n\r\nChris is in front of Andy.\r\nKelsey is behind Andy.\r\nTina is behind Joey.\r\nJoey is in front of Chris.\r\nTina is in front of Andy.\r\nTina is behind Chris.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoey, Chris, Tina, Andy, Kelsey\n<|im_start|>answer\nJoey, Chris, Tina, Andy, Kelsey\n<|im_end|>" }, { "id": "#32308", "title": "Pizza Pizza Pie", "fun": 2.42, "difficulty": 1.65, "author": "bigSWAFF_69_", "desc": "Jeremy loves to order pizza from the same local joint every Friday. He has ordered so many pizzas there, they have set up a special account for him. The account earns him $1 for every purchase of $20 or more.\n\r\nJeremy orders the exact same thing every week, two large pizzas with anchovies and bacon. The total is always $22.95. Because he is always hungry, he never messes around with change. He pays the delivery guy $25 every time, and asks for the change to be put into his ever-growing account.\n\n\r\nSince Jeremy orders pizza every week, how many days would it take before he will have enough money in his account to order his regular two pizzas without having to spend any extra money?", "hint": "No hint available.", "answer": "56 days.\n\r\nJeremy spends over $20 every week, which earns him $1 in his account.\n\r\nWhen he pays for his pizza, he is always $2.05 over. This means that every week $3.05 is added to his account.\n\n\r\nHis regular order costs $22.95. $22.95 divided by $3.05 is just over 7.5 (orders). Since he only orders once a week, that equals 7.5 weeks. We must round 7.5 up to 8. It takes him 8 weeks to accumulate enough money (at least $22.95) in his account. 8 times 7 (days in a week) is 56 - the number of days it will take for his account to have enough money in it, for him to purchase his regular order.", "category": "Math", "date": "08/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeremy loves to order pizza from the same local joint every Friday. He has ordered so many pizzas there, they have set up a special account for him. The account earns him $1 for every purchase of $20 or more.\n\r\nJeremy orders the exact same thing every week, two large pizzas with anchovies and bacon. The total is always $22.95. Because he is always hungry, he never messes around with change. He pays the delivery guy $25 every time, and asks for the change to be put into his ever-growing account.\n\n\r\nSince Jeremy orders pizza every week, how many days would it take before he will have enough money in his account to order his regular two pizzas without having to spend any extra money?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n56 days.\n\r\nJeremy spends over $20 every week, which earns him $1 in his account.\n\r\nWhen he pays for his pizza, he is always $2.05 over. This means that every week $3.05 is added to his account.\n\n\r\nHis regular order costs $22.95. $22.95 divided by $3.05 is just over 7.5 (orders). Since he only orders once a week, that equals 7.5 weeks. We must round 7.5 up to 8. It takes him 8 weeks to accumulate enough money (at least $22.95) in his account. 8 times 7 (days in a week) is 56 - the number of days it will take for his account to have enough money in it, for him to purchase his regular order.\n<|im_start|>answer\n56 days.\n\r\nJeremy spends over $20 every week, which earns him $1 in his account.\n\r\nWhen he pays for his pizza, he is always $2.05 over. This means that every week $3.05 is added to his account.\n\n\r\nHis regular order costs $22.95. $22.95 divided by $3.05 is just over 7.5 (orders). Since he only orders once a week, that equals 7.5 weeks. We must round 7.5 up to 8. It takes him 8 weeks to accumulate enough money (at least $22.95) in his account. 8 times 7 (days in a week) is 56 - the number of days it will take for his account to have enough money in it, for him to purchase his regular order.\n<|im_end|>" }, { "id": "#11655", "title": "Principal Witnesses", "fun": 2.42, "difficulty": 2.22, "author": "jimbo", "desc": "The Principal of Jimbo's school interviewed 30% of the 8th graders at recess about the food fight yesterday. The Assistant Principal grabbed 40% of 8th graders at lunchtime to investigate the disappearance of all of the blackboard erasers. Fortunately for Jimbo, he was in the 50% of 8th graders that escaped without an interview. If twenty-five 8th graders had to front only the Principal, how many students are in 8th grade at Jimbo's school?", "hint": "No hint available.", "answer": "Since 50% had no interview, then 50% did have an interview. But the Principal and the Assistant P together interviewed 40% + 30% = 70%. That means 20% of the 8th graders were interviewed twice. That leaves 10% who fronted only the Principal. Thus there are 250 students in 8th grade at Jimbo's school.", "category": "Math", "date": "04/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Principal of Jimbo's school interviewed 30% of the 8th graders at recess about the food fight yesterday. The Assistant Principal grabbed 40% of 8th graders at lunchtime to investigate the disappearance of all of the blackboard erasers. Fortunately for Jimbo, he was in the 50% of 8th graders that escaped without an interview. If twenty-five 8th graders had to front only the Principal, how many students are in 8th grade at Jimbo's school?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince 50% had no interview, then 50% did have an interview. But the Principal and the Assistant P together interviewed 40% + 30% = 70%. That means 20% of the 8th graders were interviewed twice. That leaves 10% who fronted only the Principal. Thus there are 250 students in 8th grade at Jimbo's school.\n<|im_start|>answer\nSince 50% had no interview, then 50% did have an interview. But the Principal and the Assistant P together interviewed 40% + 30% = 70%. That means 20% of the 8th graders were interviewed twice. That leaves 10% who fronted only the Principal. Thus there are 250 students in 8th grade at Jimbo's school.\n<|im_end|>" }, { "id": "#6954", "title": "Men with Mustaches", "fun": 2.42, "difficulty": 2.29, "author": "majd", "desc": "You have a group of eighty two men, some of the men are tall, the number of the medium height men is double that of the tall men and the number of the short men is triple that of the medium height men and one man is very tall.\n\r\nYou know that all tall men are bald but not all of the short men are bald, and that some of the medium height men are bald but the number of the medium height men with hair is double of that of the bald medium height men. You also know that none of the tall men does not have mustache while none of the short men with hair have mustache, but half of the bald medium height men have mustaches and nine of the medium height men with hair have mustaches too. If the number of the bald short men with mustache is less by three than the rest of other men that have mustaches and the percentage of total men with mustaches is 50% then the question is: does the very tall man have mustache or not (do not guess) and how can you prove that?", "hint": "No hint available.", "answer": "Yes, the very tall man has a mustache.\n\r\nLet number of tall men = X then number of medium height men is 2X and number of short men is 6X (3*2X).\r\nTotal number of men = X+2X+6X+1(very tall man) = 82\r\nSolving 9X = 81 gives:\r\nNumber of tall men is 9\r\nNumber of medium height men is 18\r\nNumber of short men is 54\r\nAnd 1 very tall man\n\r\nGrouping facts:\r\n1. All tall men are bald and none of the tall men does not have mustache (in other words all of them have mustaches) that means you have 9 tall bald people with mustache.\n\r\n2. The number of medium height men with hair is double of the number of bald medium height men (assume it Y) gives: Y+2Y = 18, and so Y = 6 which is the number of bald medium height men and the number of medium height men with hair = 12. \r\n9 medium height men with hair have mustaches and 3 bald medium height men (half of them) have mustaches too.\n\r\n3. Adding up the number of men that have mustaches up till this point from 1 & 2 above:\r\nNumber of men with mustaches = 9(tall) + 9(medium height men with hair) + 3(bald medium height men = 21\r\nIf the very tall man does not have a mustache, then the number of bald short men mustache = 18 (less by 3 than the above number.) If the very tall man does have a mustache then the number of bald short men is 19 (less by 3 than the above number plus one for the very tall man.)\n\r\nPercentage of total number of men with mustaches = 0.5 \r\n= 0.5 * 82 = 41 men\r\nThere must be 21 + (21 + W) - 3 + W = 41 men with mustaches (where W is the one very tall man if having a mustache, and either equals 1 if he has a mustache or = 0 if he does not have one.) \r\nSolving the equation: 42 + 2W - 3 = 41 gives that W = 1 and thus the very tall man has a mustache.", "category": "Math", "date": "08/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a group of eighty two men, some of the men are tall, the number of the medium height men is double that of the tall men and the number of the short men is triple that of the medium height men and one man is very tall.\n\r\nYou know that all tall men are bald but not all of the short men are bald, and that some of the medium height men are bald but the number of the medium height men with hair is double of that of the bald medium height men. You also know that none of the tall men does not have mustache while none of the short men with hair have mustache, but half of the bald medium height men have mustaches and nine of the medium height men with hair have mustaches too. If the number of the bald short men with mustache is less by three than the rest of other men that have mustaches and the percentage of total men with mustaches is 50% then the question is: does the very tall man have mustache or not (do not guess) and how can you prove that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes, the very tall man has a mustache.\n\r\nLet number of tall men = X then number of medium height men is 2X and number of short men is 6X (3*2X).\r\nTotal number of men = X+2X+6X+1(very tall man) = 82\r\nSolving 9X = 81 gives:\r\nNumber of tall men is 9\r\nNumber of medium height men is 18\r\nNumber of short men is 54\r\nAnd 1 very tall man\n\r\nGrouping facts:\r\n1. All tall men are bald and none of the tall men does not have mustache (in other words all of them have mustaches) that means you have 9 tall bald people with mustache.\n\r\n2. The number of medium height men with hair is double of the number of bald medium height men (assume it Y) gives: Y+2Y = 18, and so Y = 6 which is the number of bald medium height men and the number of medium height men with hair = 12. \r\n9 medium height men with hair have mustaches and 3 bald medium height men (half of them) have mustaches too.\n\r\n3. Adding up the number of men that have mustaches up till this point from 1 & 2 above:\r\nNumber of men with mustaches = 9(tall) + 9(medium height men with hair) + 3(bald medium height men = 21\r\nIf the very tall man does not have a mustache, then the number of bald short men mustache = 18 (less by 3 than the above number.) If the very tall man does have a mustache then the number of bald short men is 19 (less by 3 than the above number plus one for the very tall man.)\n\r\nPercentage of total number of men with mustaches = 0.5 \r\n= 0.5 * 82 = 41 men\r\nThere must be 21 + (21 + W) - 3 + W = 41 men with mustaches (where W is the one very tall man if having a mustache, and either equals 1 if he has a mustache or = 0 if he does not have one.) \r\nSolving the equation: 42 + 2W - 3 = 41 gives that W = 1 and thus the very tall man has a mustache.\n<|im_start|>answer\nYes, the very tall man has a mustache.\n\r\nLet number of tall men = X then number of medium height men is 2X and number of short men is 6X (3*2X).\r\nTotal number of men = X+2X+6X+1(very tall man) = 82\r\nSolving 9X = 81 gives:\r\nNumber of tall men is 9\r\nNumber of medium height men is 18\r\nNumber of short men is 54\r\nAnd 1 very tall man\n\r\nGrouping facts:\r\n1. All tall men are bald and none of the tall men does not have mustache (in other words all of them have mustaches) that means you have 9 tall bald people with mustache.\n\r\n2. The number of medium height men with hair is double of the number of bald medium height men (assume it Y) gives: Y+2Y = 18, and so Y = 6 which is the number of bald medium height men and the number of medium height men with hair = 12. \r\n9 medium height men with hair have mustaches and 3 bald medium height men (half of them) have mustaches too.\n\r\n3. Adding up the number of men that have mustaches up till this point from 1 & 2 above:\r\nNumber of men with mustaches = 9(tall) + 9(medium height men with hair) + 3(bald medium height men = 21\r\nIf the very tall man does not have a mustache, then the number of bald short men mustache = 18 (less by 3 than the above number.) If the very tall man does have a mustache then the number of bald short men is 19 (less by 3 than the above number plus one for the very tall man.)\n\r\nPercentage of total number of men with mustaches = 0.5 \r\n= 0.5 * 82 = 41 men\r\nThere must be 21 + (21 + W) - 3 + W = 41 men with mustaches (where W is the one very tall man if having a mustache, and either equals 1 if he has a mustache or = 0 if he does not have one.) \r\nSolving the equation: 42 + 2W - 3 = 41 gives that W = 1 and thus the very tall man has a mustache.\n<|im_end|>" }, { "id": "#36815", "title": "The Winning Combination 3", "fun": 2.42, "difficulty": 2.5100000000000002, "author": "grungy49", "desc": "Well... The Winning Combination is back.. but with a twist! You are a millionaire... but you have now become very greedy and a cheater. You spend lots of money on selfish things, and are finding yourself very short of money. The show has refused to let you back on after you meanly insulted the host. \n\r\nBut you are sneakier than that. Now, your son has applied to be a contestant and has successfully made it on. He, however, has nowhere near the brain power as you, so you have figured out another device, being the greedy person you are, to help your son out and claim half a million more.\n\r\nHe is secretly wearing a very cleverly disguised earpiece which you will talk to him through. Whilst you sit at home, with a pen and paper, he will recite the clues into your ear and you must solve them for him!\n\r\nYou grip your pen... with headphones and microphone in place, and wait for him to start reciting.\n\r\nThe combination is spaced out like this... ??-??-??-??. A 'set' refers to a set of two numbers.\n\r\n\"OK, Dad...\n\r\n1. The sum of the digits in the third set is less than 14 but greater than 10.\n\r\n2. The third set of numbers is 13 smaller than the fourth set.\n\r\n3. If you multiply the second set of numbers by 2 and add 7, then you will get the first set of numbers.\n\r\n4. The sum of the digits in the fourth set is greater than the sum of the digits in the first set.\n\r\n5. There are no 0's, 3's or 6's in the combination. Every other number is in the combination.\n\r\n6. The first set of two digits is a square number (for example 81 is a square number... 9x9).\n\r\nHurry, Dad, hurry!\"", "hint": "The numbers in the first set are not higher than 60.", "answer": "The solution is 49-21-75-88.\n\r\nFirst of all, we know that there are no 0's, 3's or 6's in the combination and that every other digit appears at least once (clue 5).\n\r\nOK, we'll start on the first set.\n\r\nWe know it's a square number (clue 6).\n\r\nThe only available square numbers that don't have a 0, 3 or 6 in them are:\n\r\n25\r\n49\r\n81\n\r\nNow, read clue 3. This tells us that multiplying the second set of numbers by 2 and then adding 7 will give us the first set.\n\r\nSo you must work backwards from the three numbers we know are the possibilities.\n\r\n81 - 7 = 74 / 2 = 37. However, we know there are no 3's in the combination so this can't be right.\n\r\n25 - 7 = 18 / 2 = 9. This can't be right, because written down it would be 09 and we know there are no 0's.\n\r\nSo that leaves with 49.\n\r\n49 - 7 = 42 / 2 = 21.\n\r\nNow we know this much:\n\r\n49-21-??-??\n\r\nNow we must work on the last two sets.\n\r\nClue 2 tells us that the third set is 13 smaller than the fourth set.\n\r\nHere are the possible combinations:\n\r\n11-24\r\n12-25\r\n14-27\r\n15-28\r\n28-41\r\n29-42\r\n41-54\r\n42-55\r\n44-57\r\n45-58\r\n58-71\r\n59-72\r\n71-84\r\n72-85\r\n74-87\r\n75-88\r\n78-91\r\n79-92\r\n81-94\r\n82-95\r\n84-97\r\n85-98\n\r\nNow, we must remember clue 5 - this tells us that every number will appear in the combination at least once, apart from 0, 3 and 6.\n\r\nCurrently, we have 1, 2, 4 and 9 in... so that leaves out 5, 7 and 8.\n\r\nSo now we review the list... there are only three possible combinations that include 5, 7 and 8:\n\r\n58-71\r\n75-88\r\n72-85\n\r\nNow, we read clue 4. This tells us the sum of the digits in the fourth set is greater than the sum of the digits in the first set. The sum of the digits in the first set is 13 (4 + 9), and so the only one greater than that is the 75-88 combination (8 + 8 = 16).\n\r\nSo there we have it.\n\r\n49-21-75-88.\n\r\n(P.S. Sorry if this offended anybody, not that I think it would, but in my other teaser people were complaining so I'm just putting this in here for warning).", "category": "Logic", "date": "06/02/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWell... The Winning Combination is back.. but with a twist! You are a millionaire... but you have now become very greedy and a cheater. You spend lots of money on selfish things, and are finding yourself very short of money. The show has refused to let you back on after you meanly insulted the host. \n\r\nBut you are sneakier than that. Now, your son has applied to be a contestant and has successfully made it on. He, however, has nowhere near the brain power as you, so you have figured out another device, being the greedy person you are, to help your son out and claim half a million more.\n\r\nHe is secretly wearing a very cleverly disguised earpiece which you will talk to him through. Whilst you sit at home, with a pen and paper, he will recite the clues into your ear and you must solve them for him!\n\r\nYou grip your pen... with headphones and microphone in place, and wait for him to start reciting.\n\r\nThe combination is spaced out like this... ??-??-??-??. A 'set' refers to a set of two numbers.\n\r\n\"OK, Dad...\n\r\n1. The sum of the digits in the third set is less than 14 but greater than 10.\n\r\n2. The third set of numbers is 13 smaller than the fourth set.\n\r\n3. If you multiply the second set of numbers by 2 and add 7, then you will get the first set of numbers.\n\r\n4. The sum of the digits in the fourth set is greater than the sum of the digits in the first set.\n\r\n5. There are no 0's, 3's or 6's in the combination. Every other number is in the combination.\n\r\n6. The first set of two digits is a square number (for example 81 is a square number... 9x9).\n\r\nHurry, Dad, hurry!\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe solution is 49-21-75-88.\n\r\nFirst of all, we know that there are no 0's, 3's or 6's in the combination and that every other digit appears at least once (clue 5).\n\r\nOK, we'll start on the first set.\n\r\nWe know it's a square number (clue 6).\n\r\nThe only available square numbers that don't have a 0, 3 or 6 in them are:\n\r\n25\r\n49\r\n81\n\r\nNow, read clue 3. This tells us that multiplying the second set of numbers by 2 and then adding 7 will give us the first set.\n\r\nSo you must work backwards from the three numbers we know are the possibilities.\n\r\n81 - 7 = 74 / 2 = 37. However, we know there are no 3's in the combination so this can't be right.\n\r\n25 - 7 = 18 / 2 = 9. This can't be right, because written down it would be 09 and we know there are no 0's.\n\r\nSo that leaves with 49.\n\r\n49 - 7 = 42 / 2 = 21.\n\r\nNow we know this much:\n\r\n49-21-??-??\n\r\nNow we must work on the last two sets.\n\r\nClue 2 tells us that the third set is 13 smaller than the fourth set.\n\r\nHere are the possible combinations:\n\r\n11-24\r\n12-25\r\n14-27\r\n15-28\r\n28-41\r\n29-42\r\n41-54\r\n42-55\r\n44-57\r\n45-58\r\n58-71\r\n59-72\r\n71-84\r\n72-85\r\n74-87\r\n75-88\r\n78-91\r\n79-92\r\n81-94\r\n82-95\r\n84-97\r\n85-98\n\r\nNow, we must remember clue 5 - this tells us that every number will appear in the combination at least once, apart from 0, 3 and 6.\n\r\nCurrently, we have 1, 2, 4 and 9 in... so that leaves out 5, 7 and 8.\n\r\nSo now we review the list... there are only three possible combinations that include 5, 7 and 8:\n\r\n58-71\r\n75-88\r\n72-85\n\r\nNow, we read clue 4. This tells us the sum of the digits in the fourth set is greater than the sum of the digits in the first set. The sum of the digits in the first set is 13 (4 + 9), and so the only one greater than that is the 75-88 combination (8 + 8 = 16).\n\r\nSo there we have it.\n\r\n49-21-75-88.\n\r\n(P.S. Sorry if this offended anybody, not that I think it would, but in my other teaser people were complaining so I'm just putting this in here for warning).\n<|im_start|>answer\nThe solution is 49-21-75-88.\n\r\nFirst of all, we know that there are no 0's, 3's or 6's in the combination and that every other digit appears at least once (clue 5).\n\r\nOK, we'll start on the first set.\n\r\nWe know it's a square number (clue 6).\n\r\nThe only available square numbers that don't have a 0, 3 or 6 in them are:\n\r\n25\r\n49\r\n81\n\r\nNow, read clue 3. This tells us that multiplying the second set of numbers by 2 and then adding 7 will give us the first set.\n\r\nSo you must work backwards from the three numbers we know are the possibilities.\n\r\n81 - 7 = 74 / 2 = 37. However, we know there are no 3's in the combination so this can't be right.\n\r\n25 - 7 = 18 / 2 = 9. This can't be right, because written down it would be 09 and we know there are no 0's.\n\r\nSo that leaves with 49.\n\r\n49 - 7 = 42 / 2 = 21.\n\r\nNow we know this much:\n\r\n49-21-??-??\n\r\nNow we must work on the last two sets.\n\r\nClue 2 tells us that the third set is 13 smaller than the fourth set.\n\r\nHere are the possible combinations:\n\r\n11-24\r\n12-25\r\n14-27\r\n15-28\r\n28-41\r\n29-42\r\n41-54\r\n42-55\r\n44-57\r\n45-58\r\n58-71\r\n59-72\r\n71-84\r\n72-85\r\n74-87\r\n75-88\r\n78-91\r\n79-92\r\n81-94\r\n82-95\r\n84-97\r\n85-98\n\r\nNow, we must remember clue 5 - this tells us that every number will appear in the combination at least once, apart from 0, 3 and 6.\n\r\nCurrently, we have 1, 2, 4 and 9 in... so that leaves out 5, 7 and 8.\n\r\nSo now we review the list... there are only three possible combinations that include 5, 7 and 8:\n\r\n58-71\r\n75-88\r\n72-85\n\r\nNow, we read clue 4. This tells us the sum of the digits in the fourth set is greater than the sum of the digits in the first set. The sum of the digits in the first set is 13 (4 + 9), and so the only one greater than that is the 75-88 combination (8 + 8 = 16).\n\r\nSo there we have it.\n\r\n49-21-75-88.\n\r\n(P.S. Sorry if this offended anybody, not that I think it would, but in my other teaser people were complaining so I'm just putting this in here for warning).\n<|im_end|>" }, { "id": "#15011", "title": "Cuckoo Clock", "fun": 2.42, "difficulty": 2.08, "author": "adoontourious", "desc": "Adoontourious has an antique cuckoo clock. It's a lovely clock, but it runs too slowly; it loses 9 minutes of time every hour. Mike visits his friend Adoontourious one day, and notices that the cuckoo clock is exactly on time at noon on Tuesday. \r\nWhen is the next time Adoontourious' clock will be exactly on time?", "hint": "No hint available.", "answer": "The clock will have to lose 12 hours (or 720 minutes) until it seems to be back \"on time.\" Losing 9 minutes every hour, the clock will take 80 hours (720 ÷ 9) to lose 12 hours. Eighty hours from noon on Tuesday will be 8:00 pm on Friday.", "category": "Math", "date": "10/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdoontourious has an antique cuckoo clock. It's a lovely clock, but it runs too slowly; it loses 9 minutes of time every hour. Mike visits his friend Adoontourious one day, and notices that the cuckoo clock is exactly on time at noon on Tuesday. \r\nWhen is the next time Adoontourious' clock will be exactly on time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe clock will have to lose 12 hours (or 720 minutes) until it seems to be back \"on time.\" Losing 9 minutes every hour, the clock will take 80 hours (720 ÷ 9) to lose 12 hours. Eighty hours from noon on Tuesday will be 8:00 pm on Friday.\n<|im_start|>answer\nThe clock will have to lose 12 hours (or 720 minutes) until it seems to be back \"on time.\" Losing 9 minutes every hour, the clock will take 80 hours (720 ÷ 9) to lose 12 hours. Eighty hours from noon on Tuesday will be 8:00 pm on Friday.\n<|im_end|>" }, { "id": "#43955", "title": "Greatest Product", "fun": 2.42, "difficulty": 2.69, "author": "javaguru", "desc": "What is the largest product of positive integers whose sum is 20?", "hint": "No hint available.", "answer": "1458 = 3^6 x 2\n\r\nThree is the smallest number whose product is greater than its sum. Therefore you want to include as many 3's in the answer as possible. Then make 2's (or 4's) out of the remainder.\n\r\n20 / 3 = 6, remainder 2 so 3^6 x 2", "category": "Math", "date": "01/20/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the largest product of positive integers whose sum is 20?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1458 = 3^6 x 2\n\r\nThree is the smallest number whose product is greater than its sum. Therefore you want to include as many 3's in the answer as possible. Then make 2's (or 4's) out of the remainder.\n\r\n20 / 3 = 6, remainder 2 so 3^6 x 2\n<|im_start|>answer\n1458 = 3^6 x 2\n\r\nThree is the smallest number whose product is greater than its sum. Therefore you want to include as many 3's in the answer as possible. Then make 2's (or 4's) out of the remainder.\n\r\n20 / 3 = 6, remainder 2 so 3^6 x 2\n<|im_end|>" }, { "id": "#8578", "title": "Squared or Cubed?", "fun": 2.42, "difficulty": 2.37, "author": "lesternoronha1", "desc": "Find the smallest two whole numbers that satisfy the following:\n\r\nThe difference of their squares is a cube and the difference of their cubes is a square.", "hint": "No hint available.", "answer": "The numbers are 10 and 6. The difference between their squares gives 64 (4 cubed) whereas the difference between their cubes is 784 (28 squared).", "category": "Math", "date": "11/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the smallest two whole numbers that satisfy the following:\n\r\nThe difference of their squares is a cube and the difference of their cubes is a square.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers are 10 and 6. The difference between their squares gives 64 (4 cubed) whereas the difference between their cubes is 784 (28 squared).\n<|im_start|>answer\nThe numbers are 10 and 6. The difference between their squares gives 64 (4 cubed) whereas the difference between their cubes is 784 (28 squared).\n<|im_end|>" }, { "id": "#22708", "title": "Foiled Again", "fun": 2.42, "difficulty": 1.68, "author": "exterminator", "desc": "Brock and his brothers bought their mom a 3 pound box of candy. Each candy was wrapped in colored foil and weighed 2 ounces.\r\nThere were at least 3 wrappers of each color. \r\nThere were twice as many blue wrappers as green wrappers. \r\nThe number of gold wrappers equaled the number of silver wrappers. \r\nThere was one more candy wrapped in green than in silver. \r\nThe total number of gold and silver wrappers was equal to the number of red wrappers. \r\nHow many candies were wrapped in each color?\n\r\nRemember, there are 16 ounces to a pound", "hint": "Work with the first information to find the total number of candies, and then guess and check or use algebra.", "answer": "Color\tNumber\r\nSilver\t3\r\nGold\t3\r\nRed\t6\r\nBlue\t8\r\nGreen\t4\r\nTotal\t24", "category": "Math", "date": "05/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBrock and his brothers bought their mom a 3 pound box of candy. Each candy was wrapped in colored foil and weighed 2 ounces.\r\nThere were at least 3 wrappers of each color. \r\nThere were twice as many blue wrappers as green wrappers. \r\nThe number of gold wrappers equaled the number of silver wrappers. \r\nThere was one more candy wrapped in green than in silver. \r\nThe total number of gold and silver wrappers was equal to the number of red wrappers. \r\nHow many candies were wrapped in each color?\n\r\nRemember, there are 16 ounces to a pound\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nColor\tNumber\r\nSilver\t3\r\nGold\t3\r\nRed\t6\r\nBlue\t8\r\nGreen\t4\r\nTotal\t24\n<|im_start|>answer\nColor\tNumber\r\nSilver\t3\r\nGold\t3\r\nRed\t6\r\nBlue\t8\r\nGreen\t4\r\nTotal\t24\n<|im_end|>" }, { "id": "#21206", "title": "Pocket Full of Change.", "fun": 2.42, "difficulty": 2.37, "author": "ti-jayz6", "desc": "You have 55 coins totaling $10.00. There are more nickels than pennies, more dimes than nickels, and more quarters than dimes. How many of each coin do you have?", "hint": "No hint available.", "answer": "35 quarters $8.75\r\n 9 dimes .90\r\n 6 nickels .30\r\n 5 pennies .05\r\n $10.00", "category": "Math", "date": "02/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have 55 coins totaling $10.00. There are more nickels than pennies, more dimes than nickels, and more quarters than dimes. How many of each coin do you have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n35 quarters $8.75\r\n 9 dimes .90\r\n 6 nickels .30\r\n 5 pennies .05\r\n $10.00\n<|im_start|>answer\n35 quarters $8.75\r\n 9 dimes .90\r\n 6 nickels .30\r\n 5 pennies .05\r\n $10.00\n<|im_end|>" }, { "id": "#1454", "title": "New Watch", "fun": 2.42, "difficulty": 2.0, "author": "psychodude57", "desc": "I need to get a new watch. The one I have loses exactly 20 minutes every hour. It now shows 4:00am and I know that it was correct at midnight, when I last set it. I happen to know that the watch stopped 4 hours ago, so what is the correct time now?", "hint": "No hint available.", "answer": "10:00am.", "category": "Math", "date": "11/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI need to get a new watch. The one I have loses exactly 20 minutes every hour. It now shows 4:00am and I know that it was correct at midnight, when I last set it. I happen to know that the watch stopped 4 hours ago, so what is the correct time now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10:00am.\n<|im_start|>answer\n10:00am.\n<|im_end|>" }, { "id": "#26535", "title": "One Third?", "fun": 2.42, "difficulty": 2.43, "author": "lifeisgood812", "desc": "Can you use all nine digits (1, 2, 3, 4, 5, 6, 7, 8, and 9) in any order to make a fraction equal to one-third?", "hint": "No hint available.", "answer": "5832/17496 = 1/3\n\r\nor\n\r\n5823/17469 = 1/3", "category": "Math", "date": "10/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you use all nine digits (1, 2, 3, 4, 5, 6, 7, 8, and 9) in any order to make a fraction equal to one-third?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5832/17496 = 1/3\n\r\nor\n\r\n5823/17469 = 1/3\n<|im_start|>answer\n5832/17496 = 1/3\n\r\nor\n\r\n5823/17469 = 1/3\n<|im_end|>" }, { "id": "#25616", "title": "Sequencing the Stone...", "fun": 2.42, "difficulty": 2.61, "author": "BWMyers51", "desc": "A group of stones are all lined up. Upon closer inspection, you realize there are numbers on the stones, as follows:\n\r\n1 - 2 - 3 - 5 - 9 - 12 \n\r\nThe last stone has had its number worn off by wind and time, what should the number on the stone read?", "hint": "This is a logical sequence, not necessarily a mathematical one.", "answer": "21\n\r\none - two - three - five - nine - twelve - twenty-one \n\r\nThe words for the numbers end in vowels.", "category": "Logic", "date": "08/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of stones are all lined up. Upon closer inspection, you realize there are numbers on the stones, as follows:\n\r\n1 - 2 - 3 - 5 - 9 - 12 \n\r\nThe last stone has had its number worn off by wind and time, what should the number on the stone read?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21\n\r\none - two - three - five - nine - twelve - twenty-one \n\r\nThe words for the numbers end in vowels.\n<|im_start|>answer\n21\n\r\none - two - three - five - nine - twelve - twenty-one \n\r\nThe words for the numbers end in vowels.\n<|im_end|>" }, { "id": "#42863", "title": "Quadruplets!!", "fun": 2.42, "difficulty": 0.85, "author": "eggface", "desc": "Identical quadruplets - Oliver, Charles, Dominic and Fred - have lost their teddies and their sets of matching clothing, and their mother doesn't know who is who! Help her to solve which boy has which teddy and which set of clothing.\n\r\nAll Mother can remember are the following:\n\r\nOliver's teddy isn't complete.\r\nThe boy with the green clothes has the brand new teddy.\r\nDominic has blue clothes.\r\nThe ancient teddy is often dressed to match its owner, who often wears yellow.\r\nCharles doesn't like red or yellow.\r\nFred doesn't have an incomplete teddy.\r\nThe one-eared teddy belongs to a boy in red clothes.", "hint": "No hint available.", "answer": "Oliver has the one-eared teddy and the red clothes.\r\nCharles has the brand new teddy and the green clothes.\r\nDominic has the one-footed teddy and the blue clothes.\r\nFred has the ancient teddy and yellow clothes.", "category": "Logic-Grid", "date": "08/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIdentical quadruplets - Oliver, Charles, Dominic and Fred - have lost their teddies and their sets of matching clothing, and their mother doesn't know who is who! Help her to solve which boy has which teddy and which set of clothing.\n\r\nAll Mother can remember are the following:\n\r\nOliver's teddy isn't complete.\r\nThe boy with the green clothes has the brand new teddy.\r\nDominic has blue clothes.\r\nThe ancient teddy is often dressed to match its owner, who often wears yellow.\r\nCharles doesn't like red or yellow.\r\nFred doesn't have an incomplete teddy.\r\nThe one-eared teddy belongs to a boy in red clothes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOliver has the one-eared teddy and the red clothes.\r\nCharles has the brand new teddy and the green clothes.\r\nDominic has the one-footed teddy and the blue clothes.\r\nFred has the ancient teddy and yellow clothes.\n<|im_start|>answer\nOliver has the one-eared teddy and the red clothes.\r\nCharles has the brand new teddy and the green clothes.\r\nDominic has the one-footed teddy and the blue clothes.\r\nFred has the ancient teddy and yellow clothes.\n<|im_end|>" }, { "id": "#8497", "title": "Legs & Legs & Legs !!!", "fun": 2.41, "difficulty": 1.75, "author": "lesternoronha1", "desc": "Lester saw a number of men, dogs and spiders in a group. When he counted the number of legs of all of them in the group he found them to be 420. He knows that the number of dogs in the group are double the number of men and the number of spiders are double the number of dogs.\r\nCan you help him find the number of men, dogs and spiders in the group?", "hint": "Men have 2 legs,\r\nDogs have 4 legs and\r\nSpiders have 8 legs.", "answer": "Lester found that there were 10 men, 20 dogs and 40 spiders in the group.\n\r\nIf you consider the group to consist of 1 man, 2 dogs and 4 spiders, the number of legs will be 42 (This is the least value possible with the given ratio). Since 420 is ten times 42, you must multiply this ratio of men to dogs to spiders by 10 to get the answer.", "category": "Math", "date": "11/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester saw a number of men, dogs and spiders in a group. When he counted the number of legs of all of them in the group he found them to be 420. He knows that the number of dogs in the group are double the number of men and the number of spiders are double the number of dogs.\r\nCan you help him find the number of men, dogs and spiders in the group?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLester found that there were 10 men, 20 dogs and 40 spiders in the group.\n\r\nIf you consider the group to consist of 1 man, 2 dogs and 4 spiders, the number of legs will be 42 (This is the least value possible with the given ratio). Since 420 is ten times 42, you must multiply this ratio of men to dogs to spiders by 10 to get the answer.\n<|im_start|>answer\nLester found that there were 10 men, 20 dogs and 40 spiders in the group.\n\r\nIf you consider the group to consist of 1 man, 2 dogs and 4 spiders, the number of legs will be 42 (This is the least value possible with the given ratio). Since 420 is ten times 42, you must multiply this ratio of men to dogs to spiders by 10 to get the answer.\n<|im_end|>" }, { "id": "#24823", "title": "Hole in One", "fun": 2.41, "difficulty": 2.37, "author": "phrebh", "desc": "Fred took a ball that has a 13 inch diameter and drilled a circular hole through the center of it. The hole was 5 inches wide, but how deep is it?", "hint": "No hint available.", "answer": "12 inches.\n\r\nTo solve this one, we can use the work of Pythagoras. If we draw the ball and hole from the side, they look like a circle with a rectangle in it, with all four points of the rectangle touching the circle. \n\r\nWe know the length of the short side and we need the length of the long side. To get it, we'll need the length of the diagonal of the rectangle to create a triangle. By looking back at our drawing, we can see that the diagonal of the rectangle is equal to the diameter of the ball.\n\r\nFrom that we have a triangle where hypotenuse, c, is 13 inches, leg a is 5 inches, and we want to solve for leg b. Using c^2=a^2 + b^2, we solve for b and find that the depth of the hole is 12 inches.", "category": "Math", "date": "07/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred took a ball that has a 13 inch diameter and drilled a circular hole through the center of it. The hole was 5 inches wide, but how deep is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12 inches.\n\r\nTo solve this one, we can use the work of Pythagoras. If we draw the ball and hole from the side, they look like a circle with a rectangle in it, with all four points of the rectangle touching the circle. \n\r\nWe know the length of the short side and we need the length of the long side. To get it, we'll need the length of the diagonal of the rectangle to create a triangle. By looking back at our drawing, we can see that the diagonal of the rectangle is equal to the diameter of the ball.\n\r\nFrom that we have a triangle where hypotenuse, c, is 13 inches, leg a is 5 inches, and we want to solve for leg b. Using c^2=a^2 + b^2, we solve for b and find that the depth of the hole is 12 inches.\n<|im_start|>answer\n12 inches.\n\r\nTo solve this one, we can use the work of Pythagoras. If we draw the ball and hole from the side, they look like a circle with a rectangle in it, with all four points of the rectangle touching the circle. \n\r\nWe know the length of the short side and we need the length of the long side. To get it, we'll need the length of the diagonal of the rectangle to create a triangle. By looking back at our drawing, we can see that the diagonal of the rectangle is equal to the diameter of the ball.\n\r\nFrom that we have a triangle where hypotenuse, c, is 13 inches, leg a is 5 inches, and we want to solve for leg b. Using c^2=a^2 + b^2, we solve for b and find that the depth of the hole is 12 inches.\n<|im_end|>" }, { "id": "#2916", "title": "Pyramid Construction", "fun": 2.41, "difficulty": 2.21, "author": "204_BLaZe_41", "desc": "In the course of constructing a pyramid, a large stone cube was being transported across the desert on logs. All of the logs were two meters in circumference. How far did the stone cube move in relation to the ground, with each complete revolution of the logs?", "hint": "No hint available.", "answer": "Four meters. The logs move ahead two meters on the ground and the stone cube moves ahead two meters on the logs.", "category": "Math", "date": "03/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the course of constructing a pyramid, a large stone cube was being transported across the desert on logs. All of the logs were two meters in circumference. How far did the stone cube move in relation to the ground, with each complete revolution of the logs?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFour meters. The logs move ahead two meters on the ground and the stone cube moves ahead two meters on the logs.\n<|im_start|>answer\nFour meters. The logs move ahead two meters on the ground and the stone cube moves ahead two meters on the logs.\n<|im_end|>" }, { "id": "#5641", "title": "Psychic Card Guess", "fun": 2.41, "difficulty": 1.81, "author": "Bobbrt", "desc": "Abe, Bea, and Cal deal three aces face down on a table and guess at the suit of each card in turn. Each of the three aces is correctly identified by at least one person. Nobody gets exactly one right answer, however, and no two persons finish with the same number of correct answers. What are the three cards?\n\r\nGuesses:\r\nAbe: 1. Heart 2. Spade 3. Club\r\nBea: 1. Heart 2. Diamond 3. Club\r\nCal: 1. Diamond 2. Spade 3. Heart", "hint": "No hint available.", "answer": "The cards are:\r\n1. Heart 2. Diamond 3. Club\n\r\nSince nobody guesses just one card correctly and no two people guess the same number of cards correctly, then the number guessed correctly by the three people must be zero, two, and three cards. Since Abe and Bea have two similar guesses, card 1 must be Hearts and card 3 must be clubs. This means that Cal must be wrong on all counts, which means that card 2 must be a Diamond.", "category": "Logic", "date": "07/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbe, Bea, and Cal deal three aces face down on a table and guess at the suit of each card in turn. Each of the three aces is correctly identified by at least one person. Nobody gets exactly one right answer, however, and no two persons finish with the same number of correct answers. What are the three cards?\n\r\nGuesses:\r\nAbe: 1. Heart 2. Spade 3. Club\r\nBea: 1. Heart 2. Diamond 3. Club\r\nCal: 1. Diamond 2. Spade 3. Heart\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cards are:\r\n1. Heart 2. Diamond 3. Club\n\r\nSince nobody guesses just one card correctly and no two people guess the same number of cards correctly, then the number guessed correctly by the three people must be zero, two, and three cards. Since Abe and Bea have two similar guesses, card 1 must be Hearts and card 3 must be clubs. This means that Cal must be wrong on all counts, which means that card 2 must be a Diamond.\n<|im_start|>answer\nThe cards are:\r\n1. Heart 2. Diamond 3. Club\n\r\nSince nobody guesses just one card correctly and no two people guess the same number of cards correctly, then the number guessed correctly by the three people must be zero, two, and three cards. Since Abe and Bea have two similar guesses, card 1 must be Hearts and card 3 must be clubs. This means that Cal must be wrong on all counts, which means that card 2 must be a Diamond.\n<|im_end|>" }, { "id": "#11497", "title": "Duffus's Tea Goes Green", "fun": 2.41, "difficulty": 1.69, "author": "od-1", "desc": "Duffus Mcclutski drank a lot of tea and enjoyed collecting teas from all around the world. But Duffus, not wanting to waste any tea, collected the bags after he used them, which posed a little problem as soggy tea bags don't keep well, so he placed them in his basement to dry. But when he went to organize them he forgot what was what, and, wanting to show off his famous Chinese green tea, needed to figure it out before his guests arrived. He had 6 piles, each from a different country: Canada, England, China, Jamaica, India, and the U.S. \r\nPile A had 2 round and 2 square bags. \r\nPile B had 4 double folded bags with fuzzy green mould string and tags. \r\nPile C had 1155 double folded bags with tags string and enough mould to supply a large hospital with penicillin. \r\nPile D had 2 double folded bags. \r\nPile E had 1 new unused double folded bag. \r\nPile F had 10 round and 20 double folded bags with blue slime mould. \n\r\n- Most of the tea Duffus drank came from England thus leaving the most used bags. \r\n- Canadian tea came in two shapes. \r\n- The tea from India tasted so bad that Duffus burned it as incense rather than drink it. He kept only 1 bag for his collection. \r\n- The Jamaican tea had tags so Duffus knew which they were. \r\n- Duffus remembered that the green tea came in double folded bags \r\n- Duffus also recalled being told that Canadian tea would not go mouldy because the igloos in which the tea was bagged was too cold for mould spores to exist. (Remember he's named Duffus) \r\n- The U.S tea, however, did go mouldy. \n\r\nSo which pile is the Chinese green tea in?", "hint": "No hint available.", "answer": "Pile D had the green tea bags. \n\r\nA= Canada / had 2 round and 2 square bags no mould / Canadian tea came in two shapes / Canadian tea would not go mouldy.\r\nB= Jamaica / had 4 double folded bags with fuzzy green mould string and tags / tea had tags so Duffus knew which they were/ this is the only other tea with tags other than England. \r\nC= England / had 1155 double folded bags/ Most of the tea Duffus drank came from England thus leaving the most used bags. \r\nD= China / had 2 double folded bags (no mould) / green tea came in double folded bags/ \r\nE= India / had 1 new unused double folded bag / tea from India tasted so bad that Duffus burned it as incense rather than drink it. He kept only 1 bag for his collection. \r\nF= U.S / had 10 round and 20 double folded bags with blue slime mould. / U.S tea, however, did go mouldy. \n\r\nSo the only tea in double folded bags that didn't go mouldy was in pile D", "category": "Logic", "date": "03/31/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuffus Mcclutski drank a lot of tea and enjoyed collecting teas from all around the world. But Duffus, not wanting to waste any tea, collected the bags after he used them, which posed a little problem as soggy tea bags don't keep well, so he placed them in his basement to dry. But when he went to organize them he forgot what was what, and, wanting to show off his famous Chinese green tea, needed to figure it out before his guests arrived. He had 6 piles, each from a different country: Canada, England, China, Jamaica, India, and the U.S. \r\nPile A had 2 round and 2 square bags. \r\nPile B had 4 double folded bags with fuzzy green mould string and tags. \r\nPile C had 1155 double folded bags with tags string and enough mould to supply a large hospital with penicillin. \r\nPile D had 2 double folded bags. \r\nPile E had 1 new unused double folded bag. \r\nPile F had 10 round and 20 double folded bags with blue slime mould. \n\r\n- Most of the tea Duffus drank came from England thus leaving the most used bags. \r\n- Canadian tea came in two shapes. \r\n- The tea from India tasted so bad that Duffus burned it as incense rather than drink it. He kept only 1 bag for his collection. \r\n- The Jamaican tea had tags so Duffus knew which they were. \r\n- Duffus remembered that the green tea came in double folded bags \r\n- Duffus also recalled being told that Canadian tea would not go mouldy because the igloos in which the tea was bagged was too cold for mould spores to exist. (Remember he's named Duffus) \r\n- The U.S tea, however, did go mouldy. \n\r\nSo which pile is the Chinese green tea in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPile D had the green tea bags. \n\r\nA= Canada / had 2 round and 2 square bags no mould / Canadian tea came in two shapes / Canadian tea would not go mouldy.\r\nB= Jamaica / had 4 double folded bags with fuzzy green mould string and tags / tea had tags so Duffus knew which they were/ this is the only other tea with tags other than England. \r\nC= England / had 1155 double folded bags/ Most of the tea Duffus drank came from England thus leaving the most used bags. \r\nD= China / had 2 double folded bags (no mould) / green tea came in double folded bags/ \r\nE= India / had 1 new unused double folded bag / tea from India tasted so bad that Duffus burned it as incense rather than drink it. He kept only 1 bag for his collection. \r\nF= U.S / had 10 round and 20 double folded bags with blue slime mould. / U.S tea, however, did go mouldy. \n\r\nSo the only tea in double folded bags that didn't go mouldy was in pile D\n<|im_start|>answer\nPile D had the green tea bags. \n\r\nA= Canada / had 2 round and 2 square bags no mould / Canadian tea came in two shapes / Canadian tea would not go mouldy.\r\nB= Jamaica / had 4 double folded bags with fuzzy green mould string and tags / tea had tags so Duffus knew which they were/ this is the only other tea with tags other than England. \r\nC= England / had 1155 double folded bags/ Most of the tea Duffus drank came from England thus leaving the most used bags. \r\nD= China / had 2 double folded bags (no mould) / green tea came in double folded bags/ \r\nE= India / had 1 new unused double folded bag / tea from India tasted so bad that Duffus burned it as incense rather than drink it. He kept only 1 bag for his collection. \r\nF= U.S / had 10 round and 20 double folded bags with blue slime mould. / U.S tea, however, did go mouldy. \n\r\nSo the only tea in double folded bags that didn't go mouldy was in pile D\n<|im_end|>" }, { "id": "#19614", "title": "Madadian Mail", "fun": 2.41, "difficulty": 2.62, "author": "Mad-Ade", "desc": "Madadia is split, like other countries, into cities, towns and villages. Some are large and some are small. Postman Patel delivers the mail in the village of \"Lardville\".\n\r\nNow Lardville is so small there is only one street with only ten houses, numbered from 1 to 10.\n\r\nIn a certain week, Patel did not deliver any mail at two houses in the village; at the other houses he delivered mail three times each. Each working day he delivered mail at exactly four houses. \n\r\nThe sums of the house numbers where he delivered mail were:\r\non Monday: 18\r\non Tuesday: 12\r\non Wednesday: 23\r\non Thursday: 19\r\non Friday: 32\r\non Saturday: 25\r\non Sunday: he never works just in case any murder suspects try to use this as an excuse.\n\r\nCan you work out which two houses received no mail this week?", "hint": "No hint available.", "answer": "If postman Patel would have delivered mail three times at each house, then the total sum of the house numbers per day would be (1+2+3+4+5+6+7+8+9+10)x3=165. Now that sum is 18+12+23+19+32+25=129. The difference is 165-129=36; divided by 3 this is 12. The sum of the house numbers where no mail was delivered is therefore 12. The following combinations are possible:\r\n2+10\r\n3+9\r\n4+8\r\n5+7\n\r\nEach day at four houses the mail was delivered. On Tuesday the sum was 12. 12 can only be made from four house numbers in 2 ways:\n\r\n1+2+3+6\r\n1+2+4+5\n\r\nThe same holds for Friday with the sum of 32:\n\r\n5+8+9+10\r\n6+7+9+10\n\r\nFrom this we can conclude that the house numbers 1, 2, 9 and 10 for sure have received mail, which means that the combinations 2+10 and 3+9 are not possible. Also the combination 5+7 is not possible, because mail was delivered either at house 5 or at house 7.\n\r\nThus the only remaining solution is: houses 4 and 8.", "category": "Logic", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMadadia is split, like other countries, into cities, towns and villages. Some are large and some are small. Postman Patel delivers the mail in the village of \"Lardville\".\n\r\nNow Lardville is so small there is only one street with only ten houses, numbered from 1 to 10.\n\r\nIn a certain week, Patel did not deliver any mail at two houses in the village; at the other houses he delivered mail three times each. Each working day he delivered mail at exactly four houses. \n\r\nThe sums of the house numbers where he delivered mail were:\r\non Monday: 18\r\non Tuesday: 12\r\non Wednesday: 23\r\non Thursday: 19\r\non Friday: 32\r\non Saturday: 25\r\non Sunday: he never works just in case any murder suspects try to use this as an excuse.\n\r\nCan you work out which two houses received no mail this week?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf postman Patel would have delivered mail three times at each house, then the total sum of the house numbers per day would be (1+2+3+4+5+6+7+8+9+10)x3=165. Now that sum is 18+12+23+19+32+25=129. The difference is 165-129=36; divided by 3 this is 12. The sum of the house numbers where no mail was delivered is therefore 12. The following combinations are possible:\r\n2+10\r\n3+9\r\n4+8\r\n5+7\n\r\nEach day at four houses the mail was delivered. On Tuesday the sum was 12. 12 can only be made from four house numbers in 2 ways:\n\r\n1+2+3+6\r\n1+2+4+5\n\r\nThe same holds for Friday with the sum of 32:\n\r\n5+8+9+10\r\n6+7+9+10\n\r\nFrom this we can conclude that the house numbers 1, 2, 9 and 10 for sure have received mail, which means that the combinations 2+10 and 3+9 are not possible. Also the combination 5+7 is not possible, because mail was delivered either at house 5 or at house 7.\n\r\nThus the only remaining solution is: houses 4 and 8.\n<|im_start|>answer\nIf postman Patel would have delivered mail three times at each house, then the total sum of the house numbers per day would be (1+2+3+4+5+6+7+8+9+10)x3=165. Now that sum is 18+12+23+19+32+25=129. The difference is 165-129=36; divided by 3 this is 12. The sum of the house numbers where no mail was delivered is therefore 12. The following combinations are possible:\r\n2+10\r\n3+9\r\n4+8\r\n5+7\n\r\nEach day at four houses the mail was delivered. On Tuesday the sum was 12. 12 can only be made from four house numbers in 2 ways:\n\r\n1+2+3+6\r\n1+2+4+5\n\r\nThe same holds for Friday with the sum of 32:\n\r\n5+8+9+10\r\n6+7+9+10\n\r\nFrom this we can conclude that the house numbers 1, 2, 9 and 10 for sure have received mail, which means that the combinations 2+10 and 3+9 are not possible. Also the combination 5+7 is not possible, because mail was delivered either at house 5 or at house 7.\n\r\nThus the only remaining solution is: houses 4 and 8.\n<|im_end|>" }, { "id": "#43203", "title": "It Just Doesn't Add Up!", "fun": 2.41, "difficulty": 1.68, "author": "getoffursausage", "desc": "What is the only number in which you can add up all its digits, and then multiply that number by three and get your original number?", "hint": "Example: 11. 1+1=2. 2x3=6. If it was the number, 2x3 would equal 11 (the original number).", "answer": "27.\n\r\n2+7=9. 9x3=27. 27=27", "category": "Math", "date": "09/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the only number in which you can add up all its digits, and then multiply that number by three and get your original number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n27.\n\r\n2+7=9. 9x3=27. 27=27\n<|im_start|>answer\n27.\n\r\n2+7=9. 9x3=27. 27=27\n<|im_end|>" }, { "id": "#869", "title": "How old is Sarah?", "fun": 2.41, "difficulty": 1.76, "author": "Michelle", "desc": "Sarah went to get her drivers license. When asked her age, she replied: \"My age today is three times what it will be three years from now minus three times what my age was three years ago.\" How old is Sarah?", "hint": "No hint available.", "answer": "Sarah is 18. \n\r\nIf she is 18, then three times her age three years from now would be 21*3 (63). Three times her age three years ago would be 15*3 (45). Subtract 45 from 63 and she is 18.", "category": "Math", "date": "09/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSarah went to get her drivers license. When asked her age, she replied: \"My age today is three times what it will be three years from now minus three times what my age was three years ago.\" How old is Sarah?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah is 18. \n\r\nIf she is 18, then three times her age three years from now would be 21*3 (63). Three times her age three years ago would be 15*3 (45). Subtract 45 from 63 and she is 18.\n<|im_start|>answer\nSarah is 18. \n\r\nIf she is 18, then three times her age three years from now would be 21*3 (63). Three times her age three years ago would be 15*3 (45). Subtract 45 from 63 and she is 18.\n<|im_end|>" }, { "id": "#20249", "title": "24 Games", "fun": 2.41, "difficulty": 2.31, "author": "doggyxp", "desc": "Can you take the numbers 21, 10, 5, and 3, and make the total equal 24 using basic arithmetic signs (*, /, +, -)? Each number may only be used once, and every number must be used.\n\r\nFor example, if given 2, 2, 4, and 6, the answer would be\n\r\n6/2 = 3\r\n3*2 = 6\r\n6*4 = 24\n\r\n2, 2, 4, and 6 were all used once.", "hint": "No hint available.", "answer": "For 21, 10, 5, and 3, the answer is\n\r\n10+5 = 15\r\n15*3 = 45\r\n45-21 = 24", "category": "Math", "date": "01/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you take the numbers 21, 10, 5, and 3, and make the total equal 24 using basic arithmetic signs (*, /, +, -)? Each number may only be used once, and every number must be used.\n\r\nFor example, if given 2, 2, 4, and 6, the answer would be\n\r\n6/2 = 3\r\n3*2 = 6\r\n6*4 = 24\n\r\n2, 2, 4, and 6 were all used once.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor 21, 10, 5, and 3, the answer is\n\r\n10+5 = 15\r\n15*3 = 45\r\n45-21 = 24\n<|im_start|>answer\nFor 21, 10, 5, and 3, the answer is\n\r\n10+5 = 15\r\n15*3 = 45\r\n45-21 = 24\n<|im_end|>" }, { "id": "#9161", "title": "How Much Money?", "fun": 2.41, "difficulty": 1.46, "author": "cooperdude", "desc": "Jeff has a bunch of coins. Figure out how many coins he has using only these facts:\n\r\nHe puts an equal amount in each of 9 bags and has none left over. \r\nHe puts an equal amount in each of 6 bags and has none left over.\r\nHe puts an equal amount in each of 5 bags and has 2 left over.\n\r\nWhat is the least amount of coins Jeff could have?", "hint": "Think about the multiples.", "answer": "72. \n\r\nIt's the lowest multiple of 6 and 9 that when divided by 5 will give a remainder of 2.", "category": "Math", "date": "12/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeff has a bunch of coins. Figure out how many coins he has using only these facts:\n\r\nHe puts an equal amount in each of 9 bags and has none left over. \r\nHe puts an equal amount in each of 6 bags and has none left over.\r\nHe puts an equal amount in each of 5 bags and has 2 left over.\n\r\nWhat is the least amount of coins Jeff could have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n72. \n\r\nIt's the lowest multiple of 6 and 9 that when divided by 5 will give a remainder of 2.\n<|im_start|>answer\n72. \n\r\nIt's the lowest multiple of 6 and 9 that when divided by 5 will give a remainder of 2.\n<|im_end|>" }, { "id": "#43071", "title": "Bingo Card", "fun": 2.41, "difficulty": 3.03, "author": "cnmne", "desc": "You are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) All numbers in row 2 are divisible by 2; all numbers in row 3 are divisible by 3; all numbers in row 4 are divisible by 4; all numbers in row 5 are divisible by 5.\r\n2) Row 2: the units digits are the same.\r\n3) Row 4: the units digits are all different.\r\n4) Row 5: the sum of the numbers is divisible by 7.\r\n5) Column B: contains five consecutive numbers (in any order).\r\n6) Column I: three of the numbers are odd.\r\n7) Column G: three numbers are divisible by 3; three numbers are divisible by 4; one number is divisible by 12.\r\n8) Column O: the sum of the five numbers is an odd number.\r\n9) The product of I3 and G3 is between 1300 and 1400.\r\n10) The sum of B1 and O1 is 82.\r\n11) The difference between N1 and N5 is 1.\r\n12) N2 is midway between B4 and O4.\r\n13) N4 is midway between I1 and G1.", "hint": "No hint available.", "answer": "7 23 44 57 75\r\n 6 26 36 56 66\r\n 9 27 -- 51 72\r\n 8 16 40 52 64\r\n10 25 45 60 70\n\r\n1) Per clue 1, eliminate the appropriate numbers in the various rows.\r\n2) Per clue 6, since rows 2 and 4 must contain even numbers, the other three rows in column I must contain odd numbers. I5 must be 25.\r\n3) Per clue 7, G5 must be 60.\r\n4) Per clue 9, I3 must be 27 and G3 must be 51.\r\n5) Per clue 13, since I1 is odd, then G1 must be odd. G1 must be 57. I1 must be 23. N4 must be 40.\r\n6) Per clue 10, B1 can not be less than 7 and O1 can not be less than 67.\r\n7) Per clue 2, based on G2, no number in row 2 can end in 0 or 4 or 8.\r\n8) Per clue 5, eliminate impossible combinations in column B.\r\n9) Per clue 12, eliminate numbers that can not work. N2 must be 36. O4 must be either 64 or 68.\r\n10) Per clue 2, the units digits is 6. B2 must be 6. G2 must be 56. O2 must be 66. This leaves G4 as 52.\r\n11) Per clue 5, eliminate impossible combinations in column B. B1 must be 7.\r\n12) Per clue 10, O1 must be 75.\r\n13) Per clue 3, I4 must be 16. This leaves I2 as 26.\r\n14) Per clue 4, in order for the sum of row 5 to be divisible by 7, the sum must be either 175 or 210. Since I5 must be 25 and G5 must be 60, then the sum must be 210. B5 must be 10. N5 must be 45. O5 must be 70.\r\n15) Per clue 5, B3 must be 9 and B4 must be 8.\r\n16) Per clue 3, O4 must be 64.\r\n17) Per clue 8, O3 must be 72.\r\n18) Per clue 11, N1 must be 44.", "category": "Logic", "date": "09/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) All numbers in row 2 are divisible by 2; all numbers in row 3 are divisible by 3; all numbers in row 4 are divisible by 4; all numbers in row 5 are divisible by 5.\r\n2) Row 2: the units digits are the same.\r\n3) Row 4: the units digits are all different.\r\n4) Row 5: the sum of the numbers is divisible by 7.\r\n5) Column B: contains five consecutive numbers (in any order).\r\n6) Column I: three of the numbers are odd.\r\n7) Column G: three numbers are divisible by 3; three numbers are divisible by 4; one number is divisible by 12.\r\n8) Column O: the sum of the five numbers is an odd number.\r\n9) The product of I3 and G3 is between 1300 and 1400.\r\n10) The sum of B1 and O1 is 82.\r\n11) The difference between N1 and N5 is 1.\r\n12) N2 is midway between B4 and O4.\r\n13) N4 is midway between I1 and G1.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 23 44 57 75\r\n 6 26 36 56 66\r\n 9 27 -- 51 72\r\n 8 16 40 52 64\r\n10 25 45 60 70\n\r\n1) Per clue 1, eliminate the appropriate numbers in the various rows.\r\n2) Per clue 6, since rows 2 and 4 must contain even numbers, the other three rows in column I must contain odd numbers. I5 must be 25.\r\n3) Per clue 7, G5 must be 60.\r\n4) Per clue 9, I3 must be 27 and G3 must be 51.\r\n5) Per clue 13, since I1 is odd, then G1 must be odd. G1 must be 57. I1 must be 23. N4 must be 40.\r\n6) Per clue 10, B1 can not be less than 7 and O1 can not be less than 67.\r\n7) Per clue 2, based on G2, no number in row 2 can end in 0 or 4 or 8.\r\n8) Per clue 5, eliminate impossible combinations in column B.\r\n9) Per clue 12, eliminate numbers that can not work. N2 must be 36. O4 must be either 64 or 68.\r\n10) Per clue 2, the units digits is 6. B2 must be 6. G2 must be 56. O2 must be 66. This leaves G4 as 52.\r\n11) Per clue 5, eliminate impossible combinations in column B. B1 must be 7.\r\n12) Per clue 10, O1 must be 75.\r\n13) Per clue 3, I4 must be 16. This leaves I2 as 26.\r\n14) Per clue 4, in order for the sum of row 5 to be divisible by 7, the sum must be either 175 or 210. Since I5 must be 25 and G5 must be 60, then the sum must be 210. B5 must be 10. N5 must be 45. O5 must be 70.\r\n15) Per clue 5, B3 must be 9 and B4 must be 8.\r\n16) Per clue 3, O4 must be 64.\r\n17) Per clue 8, O3 must be 72.\r\n18) Per clue 11, N1 must be 44.\n<|im_start|>answer\n7 23 44 57 75\r\n 6 26 36 56 66\r\n 9 27 -- 51 72\r\n 8 16 40 52 64\r\n10 25 45 60 70\n\r\n1) Per clue 1, eliminate the appropriate numbers in the various rows.\r\n2) Per clue 6, since rows 2 and 4 must contain even numbers, the other three rows in column I must contain odd numbers. I5 must be 25.\r\n3) Per clue 7, G5 must be 60.\r\n4) Per clue 9, I3 must be 27 and G3 must be 51.\r\n5) Per clue 13, since I1 is odd, then G1 must be odd. G1 must be 57. I1 must be 23. N4 must be 40.\r\n6) Per clue 10, B1 can not be less than 7 and O1 can not be less than 67.\r\n7) Per clue 2, based on G2, no number in row 2 can end in 0 or 4 or 8.\r\n8) Per clue 5, eliminate impossible combinations in column B.\r\n9) Per clue 12, eliminate numbers that can not work. N2 must be 36. O4 must be either 64 or 68.\r\n10) Per clue 2, the units digits is 6. B2 must be 6. G2 must be 56. O2 must be 66. This leaves G4 as 52.\r\n11) Per clue 5, eliminate impossible combinations in column B. B1 must be 7.\r\n12) Per clue 10, O1 must be 75.\r\n13) Per clue 3, I4 must be 16. This leaves I2 as 26.\r\n14) Per clue 4, in order for the sum of row 5 to be divisible by 7, the sum must be either 175 or 210. Since I5 must be 25 and G5 must be 60, then the sum must be 210. B5 must be 10. N5 must be 45. O5 must be 70.\r\n15) Per clue 5, B3 must be 9 and B4 must be 8.\r\n16) Per clue 3, O4 must be 64.\r\n17) Per clue 8, O3 must be 72.\r\n18) Per clue 11, N1 must be 44.\n<|im_end|>" }, { "id": "#29509", "title": "Question Mark's Function Machine MKIII", "fun": 2.41, "difficulty": 2.71, "author": "Question_Mark", "desc": "Question Mark cannot get enough of changing the formula to his function machine. This time, one number goes in, but TWO numbers come out. If:\n\r\n9 -> 576 & 72\r\n10 -> 810 & 90\r\n11 -> 1100 & 110\r\n12 -> 1452 & 132\r\n13 -> 1872 & 156\n\r\nWhat will come out if 25 goes in?", "hint": "No hint available.", "answer": "14400 & 600. The formula is n^3 - n^2. The numbers are then split by the formula of (n-1)/n & 1/n. In other words:\n\r\n9^3 (729) - 9^2 (81) = 648\r\n>8/9*648 = 576, 1/9*648 = 72\r\n10^3 (1000) - 10^2 (100) = 900\r\n>9/10*900 = 810, 1/10*900 = 90\r\n11^3 (1331) - 11^2 (121) = 1210\r\n>10/11*1210 = 1100, 1/11*1210 = 110\r\n12^3 (1728) - 12^2 (144) = 1584\r\n>11/12*1584 = 1452, 1/12*1584 = 132\r\n13^3 (2197) - 13^2 (169) = 2028\r\n>12/13*2028 = 1872, 1/13*2028 = 156\n\r\nAnd therefore:\r\n25^3 (15625) - 25^2 (625) = 15000\r\n>24/25*15000 = 14400, 1/25*15000 = 600", "category": "Math", "date": "04/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuestion Mark cannot get enough of changing the formula to his function machine. This time, one number goes in, but TWO numbers come out. If:\n\r\n9 -> 576 & 72\r\n10 -> 810 & 90\r\n11 -> 1100 & 110\r\n12 -> 1452 & 132\r\n13 -> 1872 & 156\n\r\nWhat will come out if 25 goes in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n14400 & 600. The formula is n^3 - n^2. The numbers are then split by the formula of (n-1)/n & 1/n. In other words:\n\r\n9^3 (729) - 9^2 (81) = 648\r\n>8/9*648 = 576, 1/9*648 = 72\r\n10^3 (1000) - 10^2 (100) = 900\r\n>9/10*900 = 810, 1/10*900 = 90\r\n11^3 (1331) - 11^2 (121) = 1210\r\n>10/11*1210 = 1100, 1/11*1210 = 110\r\n12^3 (1728) - 12^2 (144) = 1584\r\n>11/12*1584 = 1452, 1/12*1584 = 132\r\n13^3 (2197) - 13^2 (169) = 2028\r\n>12/13*2028 = 1872, 1/13*2028 = 156\n\r\nAnd therefore:\r\n25^3 (15625) - 25^2 (625) = 15000\r\n>24/25*15000 = 14400, 1/25*15000 = 600\n<|im_start|>answer\n14400 & 600. The formula is n^3 - n^2. The numbers are then split by the formula of (n-1)/n & 1/n. In other words:\n\r\n9^3 (729) - 9^2 (81) = 648\r\n>8/9*648 = 576, 1/9*648 = 72\r\n10^3 (1000) - 10^2 (100) = 900\r\n>9/10*900 = 810, 1/10*900 = 90\r\n11^3 (1331) - 11^2 (121) = 1210\r\n>10/11*1210 = 1100, 1/11*1210 = 110\r\n12^3 (1728) - 12^2 (144) = 1584\r\n>11/12*1584 = 1452, 1/12*1584 = 132\r\n13^3 (2197) - 13^2 (169) = 2028\r\n>12/13*2028 = 1872, 1/13*2028 = 156\n\r\nAnd therefore:\r\n25^3 (15625) - 25^2 (625) = 15000\r\n>24/25*15000 = 14400, 1/25*15000 = 600\n<|im_end|>" }, { "id": "#49482", "title": "Watch My Horse, Please", "fun": 2.41, "difficulty": 1.11, "author": "fishmed", "desc": "Two posts, 1 foot to a side, are seated in the ground exactly 2 feet apart. My horse is tied to an anchor on the outside of one post with a rope that is 30 feet long. He likes to walk, but can only go in circles due to the rope and posts. How many times can he go around the posts before he runs out of rope?", "hint": "No hint available.", "answer": "3 times.\n\r\nOne trip around the posts consists of 3 feet on each post, as he does not waste rope on the sides facing each other, plus 4 feet for the two gaps between the posts, making one trip around the posts 10 feet in total. 30 divided by 10 equals 3 laps around the posts.", "category": "Math", "date": "05/13/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo posts, 1 foot to a side, are seated in the ground exactly 2 feet apart. My horse is tied to an anchor on the outside of one post with a rope that is 30 feet long. He likes to walk, but can only go in circles due to the rope and posts. How many times can he go around the posts before he runs out of rope?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 times.\n\r\nOne trip around the posts consists of 3 feet on each post, as he does not waste rope on the sides facing each other, plus 4 feet for the two gaps between the posts, making one trip around the posts 10 feet in total. 30 divided by 10 equals 3 laps around the posts.\n<|im_start|>answer\n3 times.\n\r\nOne trip around the posts consists of 3 feet on each post, as he does not waste rope on the sides facing each other, plus 4 feet for the two gaps between the posts, making one trip around the posts 10 feet in total. 30 divided by 10 equals 3 laps around the posts.\n<|im_end|>" }, { "id": "#41303", "title": "The Egg Game", "fun": 2.41, "difficulty": 2.43, "author": "kratsg", "desc": "There are 2008 eggs lying in front of you. I am also with you waiting to start the game. The goal of the game is to be the person to take that very last egg (or eggs) to win. You and I can each only take between 1 and 100 eggs at a time. You go first. How many eggs must you take initially in order to always win (assuming we both play perfectly)?", "hint": "By a perfect game, that means over any two turns, the sum of the number of eggs you and I take is the same (except of course, excluding the initial move you make).", "answer": "89 eggs.\n\r\nIn order to see this, look at the smallest way possible to guarantee a win; you leave me with 101 eggs. If I take 1 egg, you take all 100; if I take 100 eggs, you take the last one. Therefore you would always win.\n\r\nIf you try with 202, I can take from 1 to 100, so there is 201 to 102 left. Then you would take 100 or 1 egg(s) in order to leave me with 101 again. By simple analysis, you must take 101 eggs over two rounds in order to get down to 101.\n\r\n19*101 = 1919, so we must take 2008-1919 = 89 eggs to start off with a multiple of 101.", "category": "Logic", "date": "03/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 2008 eggs lying in front of you. I am also with you waiting to start the game. The goal of the game is to be the person to take that very last egg (or eggs) to win. You and I can each only take between 1 and 100 eggs at a time. You go first. How many eggs must you take initially in order to always win (assuming we both play perfectly)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n89 eggs.\n\r\nIn order to see this, look at the smallest way possible to guarantee a win; you leave me with 101 eggs. If I take 1 egg, you take all 100; if I take 100 eggs, you take the last one. Therefore you would always win.\n\r\nIf you try with 202, I can take from 1 to 100, so there is 201 to 102 left. Then you would take 100 or 1 egg(s) in order to leave me with 101 again. By simple analysis, you must take 101 eggs over two rounds in order to get down to 101.\n\r\n19*101 = 1919, so we must take 2008-1919 = 89 eggs to start off with a multiple of 101.\n<|im_start|>answer\n89 eggs.\n\r\nIn order to see this, look at the smallest way possible to guarantee a win; you leave me with 101 eggs. If I take 1 egg, you take all 100; if I take 100 eggs, you take the last one. Therefore you would always win.\n\r\nIf you try with 202, I can take from 1 to 100, so there is 201 to 102 left. Then you would take 100 or 1 egg(s) in order to leave me with 101 again. By simple analysis, you must take 101 eggs over two rounds in order to get down to 101.\n\r\n19*101 = 1919, so we must take 2008-1919 = 89 eggs to start off with a multiple of 101.\n<|im_end|>" }, { "id": "#14640", "title": "13 cm Ruler", "fun": 2.41, "difficulty": 2.59, "author": "Gerd", "desc": "With a blank ruler (without marks) of exactly 13 cm you can only measure 13 cm. Now you are allowed to set 4 marks so that you can read off all full centimeter values from 1 to 13 cm directly from the ruler.\n\r\nWhere must these 4 marks be?\n\n\r\nMuch harder question:\r\nThe blank ruler has a length of 36 cm and you need 8 marks.\r\nSet the marks.", "hint": "No hint available.", "answer": "Marks on the 13 cm-ruler:\r\n1 - 2 - 6 and 10 cm. \n\r\nYou could then use these marks together to measure any length of 13 cm or less. For example, you could measure 8 cm by using the distance between the 2 and 10 cm marks. \n\n\r\nMarks on the ruler with 36 cm: \r\n1 - 3 - 6 - 13 - 20 - 27 - 31 - 35 cm", "category": "Math", "date": "09/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith a blank ruler (without marks) of exactly 13 cm you can only measure 13 cm. Now you are allowed to set 4 marks so that you can read off all full centimeter values from 1 to 13 cm directly from the ruler.\n\r\nWhere must these 4 marks be?\n\n\r\nMuch harder question:\r\nThe blank ruler has a length of 36 cm and you need 8 marks.\r\nSet the marks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMarks on the 13 cm-ruler:\r\n1 - 2 - 6 and 10 cm. \n\r\nYou could then use these marks together to measure any length of 13 cm or less. For example, you could measure 8 cm by using the distance between the 2 and 10 cm marks. \n\n\r\nMarks on the ruler with 36 cm: \r\n1 - 3 - 6 - 13 - 20 - 27 - 31 - 35 cm\n<|im_start|>answer\nMarks on the 13 cm-ruler:\r\n1 - 2 - 6 and 10 cm. \n\r\nYou could then use these marks together to measure any length of 13 cm or less. For example, you could measure 8 cm by using the distance between the 2 and 10 cm marks. \n\n\r\nMarks on the ruler with 36 cm: \r\n1 - 3 - 6 - 13 - 20 - 27 - 31 - 35 cm\n<|im_end|>" }, { "id": "#42176", "title": "Prom Date", "fun": 2.41, "difficulty": 0.78, "author": "whsprec", "desc": "Five couples went to the prom as a group. The boys' names were Mark, Quintin, Jim, Bob, and James. The girls' names were Amanda, Betty, Susan, Jessica, and Jasmin. Each couple wore matching colors of either blue, yellow, red, green, or pink. Match the dates and the color they are wearing.\r\n1) Two couples have the same first letter in their name. One of those letters is \"B\".\r\n2) Susan wore red and Jessica wore blue.\r\n3) Susan has more letters in her name than her date does.\r\n4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.\r\n5) Amanda went with Jim and they did not wear green.", "hint": "No hint available.", "answer": "Mark and Susan wore red.\r\nQuintin and Jessica wore blue.\r\nJim and Amanda wore pink.\r\nBob and Betty wore green.\r\nJames and Jasmin wore yellow.", "category": "Logic-Grid", "date": "06/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive couples went to the prom as a group. The boys' names were Mark, Quintin, Jim, Bob, and James. The girls' names were Amanda, Betty, Susan, Jessica, and Jasmin. Each couple wore matching colors of either blue, yellow, red, green, or pink. Match the dates and the color they are wearing.\r\n1) Two couples have the same first letter in their name. One of those letters is \"B\".\r\n2) Susan wore red and Jessica wore blue.\r\n3) Susan has more letters in her name than her date does.\r\n4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.\r\n5) Amanda went with Jim and they did not wear green.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMark and Susan wore red.\r\nQuintin and Jessica wore blue.\r\nJim and Amanda wore pink.\r\nBob and Betty wore green.\r\nJames and Jasmin wore yellow.\n<|im_start|>answer\nMark and Susan wore red.\r\nQuintin and Jessica wore blue.\r\nJim and Amanda wore pink.\r\nBob and Betty wore green.\r\nJames and Jasmin wore yellow.\n<|im_end|>" }, { "id": "#2179", "title": "Presidents", "fun": 2.41, "difficulty": 1.01, "author": "Cascas", "desc": "The 22nd and the 24th presidents of the U.S had the same mother and father, but they weren't brothers. How could this be?", "hint": "No hint available.", "answer": "They were the same man. He was Grover Cleveland.", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 22nd and the 24th presidents of the U.S had the same mother and father, but they weren't brothers. How could this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey were the same man. He was Grover Cleveland.\n<|im_start|>answer\nThey were the same man. He was Grover Cleveland.\n<|im_end|>" }, { "id": "#34345", "title": "Temperature Tally", "fun": 2.41, "difficulty": 1.4, "author": "nick93", "desc": "This past February, Ms. Curley's class kept track of the temperature every day for one week. They made a chart to post the outdoor temperatures for each day of the school week at 9:00 a.m. and at noon.\n\r\n * On Monday, the temperature was 31 degrees Fahrenheit at noon. It had been 10 degrees colder that morning at 9:00 a.m.\r\n * Thursday's 9:00 a.m. temperature was double the temperature for the same time on Monday.\r\n * On Wednesday and Thursday, the temperature rose 6 degrees from nine o'clock until noon.\r\n * Tuesday morning at 9:00 a.m., the temperature was 10 degrees warmer than on Monday at the same time. At noon on Tuesday, it was exactly at the freezing mark.\r\n * Wednesday noon was 3 degrees colder than Thursday noon.\r\n * The first reading on Friday was 5 degrees colder than the day before at the same time. It warmed up 5 degrees each hour until noon.\n\r\nWhat was the temperature each day at 9:00 a.m. and at noon?", "hint": "No hint available.", "answer": "Temp.at 9:00 a.m. (on the left) and the Temp. at noon (on the right):\r\nMonday \t21°F \t 31°F\r\nTuesday \t31°F \t 32°F\r\nWednesday 39°F 45°F\r\nThursday \t42°F \t 48°F\r\nFriday 37°F 52°F", "category": "Logic", "date": "12/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis past February, Ms. Curley's class kept track of the temperature every day for one week. They made a chart to post the outdoor temperatures for each day of the school week at 9:00 a.m. and at noon.\n\r\n * On Monday, the temperature was 31 degrees Fahrenheit at noon. It had been 10 degrees colder that morning at 9:00 a.m.\r\n * Thursday's 9:00 a.m. temperature was double the temperature for the same time on Monday.\r\n * On Wednesday and Thursday, the temperature rose 6 degrees from nine o'clock until noon.\r\n * Tuesday morning at 9:00 a.m., the temperature was 10 degrees warmer than on Monday at the same time. At noon on Tuesday, it was exactly at the freezing mark.\r\n * Wednesday noon was 3 degrees colder than Thursday noon.\r\n * The first reading on Friday was 5 degrees colder than the day before at the same time. It warmed up 5 degrees each hour until noon.\n\r\nWhat was the temperature each day at 9:00 a.m. and at noon?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTemp.at 9:00 a.m. (on the left) and the Temp. at noon (on the right):\r\nMonday \t21°F \t 31°F\r\nTuesday \t31°F \t 32°F\r\nWednesday 39°F 45°F\r\nThursday \t42°F \t 48°F\r\nFriday 37°F 52°F\n<|im_start|>answer\nTemp.at 9:00 a.m. (on the left) and the Temp. at noon (on the right):\r\nMonday \t21°F \t 31°F\r\nTuesday \t31°F \t 32°F\r\nWednesday 39°F 45°F\r\nThursday \t42°F \t 48°F\r\nFriday 37°F 52°F\n<|im_end|>" }, { "id": "#27913", "title": "Hogwarts", "fun": 2.41, "difficulty": 0.65, "author": "GoHarryPotterCS", "desc": "A group of soon-to-be-first-years at Hogwarts School of Witchcraft and Wizardry just walked into the Great Hall. Everybody has been sorted into a house of either Slytherin, Hufflepuff, Gryffindor, or Ravenclaw. Hufflepuff = Loyal and Trustworthy; Ravenclaw = cunning and intelligent; Gryffindor = brave and noble; Slytherin = keen and ambitious.\r\n There are still 4 kids to be sorted. Their names are Billy, Shelby, Anthony, and Kristen. The sorting hat takes some time for each kid. Find out the amount of time the hat took and which house each kid ended up in.\n\r\nClue 1. Shelby is VERY smart.\n\r\nClue 2. Billy is a scaredy cat.\n\r\nClue 3. Billy and the boy in Slytherin took under a minute to be sorted.\n\r\nClue 4. Billy always keeps promises and is not very bright.\n\r\nClue 5. The person in Gryffindor took the longest.\n\r\nClue 6. Anthony was the fastest to be sorted.\n\r\nClue 7. Billy was sorted 30 seconds faster than the Ravenclaw.", "hint": "Kristen = Gryffindor, 2 minutes\r\n(Shelby is a girl)", "answer": "Shelby = Ravenclaw, 1 minute\r\nBilly = Hufflepuff, 30 seconds\r\nKristen = Gryffindor, 2 minutes\r\nAnthony = Slytherin, 20 seconds", "category": "Logic-Grid", "date": "01/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of soon-to-be-first-years at Hogwarts School of Witchcraft and Wizardry just walked into the Great Hall. Everybody has been sorted into a house of either Slytherin, Hufflepuff, Gryffindor, or Ravenclaw. Hufflepuff = Loyal and Trustworthy; Ravenclaw = cunning and intelligent; Gryffindor = brave and noble; Slytherin = keen and ambitious.\r\n There are still 4 kids to be sorted. Their names are Billy, Shelby, Anthony, and Kristen. The sorting hat takes some time for each kid. Find out the amount of time the hat took and which house each kid ended up in.\n\r\nClue 1. Shelby is VERY smart.\n\r\nClue 2. Billy is a scaredy cat.\n\r\nClue 3. Billy and the boy in Slytherin took under a minute to be sorted.\n\r\nClue 4. Billy always keeps promises and is not very bright.\n\r\nClue 5. The person in Gryffindor took the longest.\n\r\nClue 6. Anthony was the fastest to be sorted.\n\r\nClue 7. Billy was sorted 30 seconds faster than the Ravenclaw.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShelby = Ravenclaw, 1 minute\r\nBilly = Hufflepuff, 30 seconds\r\nKristen = Gryffindor, 2 minutes\r\nAnthony = Slytherin, 20 seconds\n<|im_start|>answer\nShelby = Ravenclaw, 1 minute\r\nBilly = Hufflepuff, 30 seconds\r\nKristen = Gryffindor, 2 minutes\r\nAnthony = Slytherin, 20 seconds\n<|im_end|>" }, { "id": "#50188", "title": "Logic", "fun": 2.41, "difficulty": 1.25, "author": "Ezhilsaha", "desc": "What demands an answer, but asks no question?", "hint": "No hint available.", "answer": "Telephone Call", "category": "Logic", "date": "03/22/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat demands an answer, but asks no question?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTelephone Call\n<|im_start|>answer\nTelephone Call\n<|im_end|>" }, { "id": "#35397", "title": "Near Orange Bags?", "fun": 2.41, "difficulty": 3.11, "author": "calmsavior", "desc": "\"What's the password?\" asked The Entity, with a weasel-like demeanor. Spy IQ was confused, until he realized he had received a strange postcard weeks before. The crafty spy still needed to enter the underground cellar leading to a new set of gadgets to be used on the next mission, but he was halted by The Entity's presence. What the postcard said might help Spy IQ find the password The Entity needs to allow the spy into the secret lair. The postcard says this:\n\n\r\nA relative of mine was expelled.\r\nIt was my niece.\r\nWouldn't you agree?\r\nIt was because she joined a band of bikers.\r\nShe's doing lots of things wrong.\r\nShe always shows a lot of toughness.\n\r\nP.S. \r\nIsaac Newton:\r\nNear orange bags lying east.\r\nGets as strange equally slowly.\n\n\r\nThat P.S. looks like it could be the catalyst to solve for the encrypted password. But, what could it be?", "hint": "Look closely at the P.S.\r\nA secret message lies within the P.S. that will assist you in searching for the password.\n\r\nHere, I'll change it up a bit:\r\nP.S. \r\nIsaac Newton:\r\nNear Orange Bags Lying East.\r\nGets As Strange Equally Slowly.", "answer": "The password is PIGEON.\n\r\nIf you look carefully at the P.S., you will notice that the first letter of each word spells IN NOBLE GASES:\n\r\nP.S. \r\n[I]saac [N]ewton:\r\n[N]ear [O]range [B]ags [L]ying [E]ast.\r\n[G]ets [A]s [S]trange [E]qually [S]lowly.\n\r\nNow, look in the first six lines of the postcard. The symbols for noble gases can be found in the last word of each line, with a letter lying in between:\n\r\na relative of mine was eXpElled.\r\nit was my NiEce.\r\nwouldn't you AgRee? etc.\n\r\nIf you take each letter that is within the symbols of the noble gases, you will spell the word PIGEON:\n\r\na relative of mine was eX[p]Elled.\r\nit was my N[i]Ece.\r\nwouldn't you A[g]Ree?\r\nit was because she joined a band of biK[e]Rs.\r\nshe's doing lots of things wR[o]Ng.\r\nshe always shows a lot of tougH[n]Ess.\n\r\nAfter saying the password, Spy IQ entered the secret lair and found useful gadgets, including Instant Tile Camouflage.", "category": "Logic", "date": "02/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"What's the password?\" asked The Entity, with a weasel-like demeanor. Spy IQ was confused, until he realized he had received a strange postcard weeks before. The crafty spy still needed to enter the underground cellar leading to a new set of gadgets to be used on the next mission, but he was halted by The Entity's presence. What the postcard said might help Spy IQ find the password The Entity needs to allow the spy into the secret lair. The postcard says this:\n\n\r\nA relative of mine was expelled.\r\nIt was my niece.\r\nWouldn't you agree?\r\nIt was because she joined a band of bikers.\r\nShe's doing lots of things wrong.\r\nShe always shows a lot of toughness.\n\r\nP.S. \r\nIsaac Newton:\r\nNear orange bags lying east.\r\nGets as strange equally slowly.\n\n\r\nThat P.S. looks like it could be the catalyst to solve for the encrypted password. But, what could it be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe password is PIGEON.\n\r\nIf you look carefully at the P.S., you will notice that the first letter of each word spells IN NOBLE GASES:\n\r\nP.S. \r\n[I]saac [N]ewton:\r\n[N]ear [O]range [B]ags [L]ying [E]ast.\r\n[G]ets [A]s [S]trange [E]qually [S]lowly.\n\r\nNow, look in the first six lines of the postcard. The symbols for noble gases can be found in the last word of each line, with a letter lying in between:\n\r\na relative of mine was eXpElled.\r\nit was my NiEce.\r\nwouldn't you AgRee? etc.\n\r\nIf you take each letter that is within the symbols of the noble gases, you will spell the word PIGEON:\n\r\na relative of mine was eX[p]Elled.\r\nit was my N[i]Ece.\r\nwouldn't you A[g]Ree?\r\nit was because she joined a band of biK[e]Rs.\r\nshe's doing lots of things wR[o]Ng.\r\nshe always shows a lot of tougH[n]Ess.\n\r\nAfter saying the password, Spy IQ entered the secret lair and found useful gadgets, including Instant Tile Camouflage.\n<|im_start|>answer\nThe password is PIGEON.\n\r\nIf you look carefully at the P.S., you will notice that the first letter of each word spells IN NOBLE GASES:\n\r\nP.S. \r\n[I]saac [N]ewton:\r\n[N]ear [O]range [B]ags [L]ying [E]ast.\r\n[G]ets [A]s [S]trange [E]qually [S]lowly.\n\r\nNow, look in the first six lines of the postcard. The symbols for noble gases can be found in the last word of each line, with a letter lying in between:\n\r\na relative of mine was eXpElled.\r\nit was my NiEce.\r\nwouldn't you AgRee? etc.\n\r\nIf you take each letter that is within the symbols of the noble gases, you will spell the word PIGEON:\n\r\na relative of mine was eX[p]Elled.\r\nit was my N[i]Ece.\r\nwouldn't you A[g]Ree?\r\nit was because she joined a band of biK[e]Rs.\r\nshe's doing lots of things wR[o]Ng.\r\nshe always shows a lot of tougH[n]Ess.\n\r\nAfter saying the password, Spy IQ entered the secret lair and found useful gadgets, including Instant Tile Camouflage.\n<|im_end|>" }, { "id": "#4795", "title": "Footprints 2", "fun": 2.41, "difficulty": 1.59, "author": "leenie_122", "desc": "There was a man that was walking along. It was raining heavily, and it was very muddy. As he was walking along he turned around, but he couldn't see his footprints. Why?", "hint": "No hint available.", "answer": "Because he was walking backwards.", "category": "Logic", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a man that was walking along. It was raining heavily, and it was very muddy. As he was walking along he turned around, but he couldn't see his footprints. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBecause he was walking backwards.\n<|im_start|>answer\nBecause he was walking backwards.\n<|im_end|>" }, { "id": "#41860", "title": "Monkey Island", "fun": 2.41, "difficulty": 1.8, "author": "Dishhead5", "desc": "There are people and strange monkeys on this island, and you can not tell who is who. They speak either only the truth or only lies.\r\nWho are the following two guys?\r\nA: B is a lying monkey. I am human.\r\nB: A is telling the truth.", "hint": "No hint available.", "answer": "Assume B is not lying. Then, A would be telling the truth, however, A says B lies. Therefore A would be lying, and hence B cannot be telling the truth. This means A is not telling the truth. Hence B is not a lying monkey, rather, he is a lying human. And A is a lying monkey.", "category": "Logic", "date": "05/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are people and strange monkeys on this island, and you can not tell who is who. They speak either only the truth or only lies.\r\nWho are the following two guys?\r\nA: B is a lying monkey. I am human.\r\nB: A is telling the truth.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAssume B is not lying. Then, A would be telling the truth, however, A says B lies. Therefore A would be lying, and hence B cannot be telling the truth. This means A is not telling the truth. Hence B is not a lying monkey, rather, he is a lying human. And A is a lying monkey.\n<|im_start|>answer\nAssume B is not lying. Then, A would be telling the truth, however, A says B lies. Therefore A would be lying, and hence B cannot be telling the truth. This means A is not telling the truth. Hence B is not a lying monkey, rather, he is a lying human. And A is a lying monkey.\n<|im_end|>" }, { "id": "#265", "title": "A Money Matter", "fun": 2.41, "difficulty": 2.08, "author": "Mr. G", "desc": "What is the fewest number of American coins you need to have the exact change for every situation, in one cent increments, between one cent and one dollar?", "hint": "No hint available.", "answer": "A total of nine coins.\r\nFour pennies, one nickel, two dimes, one quarter, and one half-dollar.", "category": "Math", "date": "02/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the fewest number of American coins you need to have the exact change for every situation, in one cent increments, between one cent and one dollar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA total of nine coins.\r\nFour pennies, one nickel, two dimes, one quarter, and one half-dollar.\n<|im_start|>answer\nA total of nine coins.\r\nFour pennies, one nickel, two dimes, one quarter, and one half-dollar.\n<|im_end|>" }, { "id": "#23891", "title": "Money Mayhem", "fun": 2.41, "difficulty": 1.57, "author": "Tori592", "desc": "In Shmithalithaophogous the currency is marbles. A yellow one is equal to about 87 American dollars. A green one is twice that. A red one is a third of a green one. A blue one is 4x a red one. A purple one is 10% of a blue marble.\n\r\nWhat would be the simplest combination to make $1856?", "hint": "No hint available.", "answer": "First, you must establish what the values are.\r\nYellow-87\r\nGreen-174\r\nRed-58\r\nBlue-232\r\nPurple-23.2\r\nThen, you divide 1856 by 232 to see how many blue marbles are needed. The answer is 8 blue marbles.", "category": "Math", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Shmithalithaophogous the currency is marbles. A yellow one is equal to about 87 American dollars. A green one is twice that. A red one is a third of a green one. A blue one is 4x a red one. A purple one is 10% of a blue marble.\n\r\nWhat would be the simplest combination to make $1856?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, you must establish what the values are.\r\nYellow-87\r\nGreen-174\r\nRed-58\r\nBlue-232\r\nPurple-23.2\r\nThen, you divide 1856 by 232 to see how many blue marbles are needed. The answer is 8 blue marbles.\n<|im_start|>answer\nFirst, you must establish what the values are.\r\nYellow-87\r\nGreen-174\r\nRed-58\r\nBlue-232\r\nPurple-23.2\r\nThen, you divide 1856 by 232 to see how many blue marbles are needed. The answer is 8 blue marbles.\n<|im_end|>" }, { "id": "#26319", "title": "More Twin Trouble", "fun": 2.41, "difficulty": 1.42, "author": "deepsea", "desc": "James, a lovable 5 year-old, was happily sitting at home with his babysitter, playing with his blocks. The phone rang, and when she came back, she looked excited and told him that his parents were coming home. She also said that they adopted Siamese twins. She explained that they were born in America even though they were \"Siamese\". When James' parents came home, they introduced the twins to their son. One of the twins, Mandy, was very tired, so she immediately went to sleep on the parents' bed. However, the other twin, Susie, was very anxious to meet James and they played together. The babysitter was very embarrassed after seeing them, but she had never said anything untruthful to James.\n\r\nWhat happened?", "hint": "*sings* That's why the LADY is a TRAMP.", "answer": "They were Siamese cats from the same litter.", "category": "Logic", "date": "10/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJames, a lovable 5 year-old, was happily sitting at home with his babysitter, playing with his blocks. The phone rang, and when she came back, she looked excited and told him that his parents were coming home. She also said that they adopted Siamese twins. She explained that they were born in America even though they were \"Siamese\". When James' parents came home, they introduced the twins to their son. One of the twins, Mandy, was very tired, so she immediately went to sleep on the parents' bed. However, the other twin, Susie, was very anxious to meet James and they played together. The babysitter was very embarrassed after seeing them, but she had never said anything untruthful to James.\n\r\nWhat happened?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey were Siamese cats from the same litter.\n<|im_start|>answer\nThey were Siamese cats from the same litter.\n<|im_end|>" }, { "id": "#21058", "title": "Who Ate Which Fruit?", "fun": 2.41, "difficulty": 0.55, "author": "Unicorns", "desc": "There are 4 people - Jenny, Bob, Kate and Joseph\n\r\nThey each had a piece of fruit - Orange, Apple, Grapes and Banana\n\r\nOn a certain day - Monday, Friday, Saturday, Tuesday\n\r\nCan you work out who has which fruit on which day?\n\r\nClues - \n\r\n1. The person that had the orange ate it on Saturday.\n\r\n2. The woman who had the apple did not eat it on Tuesday.\n\r\n3. Joseph did not eat the bananas and did not eat on Friday.\n\r\n4. People with O in their name did not eat the orange.\n\r\n5. Bob ate his fruit on Tuesday.\n\r\n6. Jenny loved eating her orange.", "hint": "No hint available.", "answer": "Jenny - Orange - Saturday\r\nBob - Banana - Tuesday\r\nKate - Apple - Friday\r\nJoseph - Grapes - Monday", "category": "Logic-Grid", "date": "02/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 4 people - Jenny, Bob, Kate and Joseph\n\r\nThey each had a piece of fruit - Orange, Apple, Grapes and Banana\n\r\nOn a certain day - Monday, Friday, Saturday, Tuesday\n\r\nCan you work out who has which fruit on which day?\n\r\nClues - \n\r\n1. The person that had the orange ate it on Saturday.\n\r\n2. The woman who had the apple did not eat it on Tuesday.\n\r\n3. Joseph did not eat the bananas and did not eat on Friday.\n\r\n4. People with O in their name did not eat the orange.\n\r\n5. Bob ate his fruit on Tuesday.\n\r\n6. Jenny loved eating her orange.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJenny - Orange - Saturday\r\nBob - Banana - Tuesday\r\nKate - Apple - Friday\r\nJoseph - Grapes - Monday\n<|im_start|>answer\nJenny - Orange - Saturday\r\nBob - Banana - Tuesday\r\nKate - Apple - Friday\r\nJoseph - Grapes - Monday\n<|im_end|>" }, { "id": "#8290", "title": "Frogger's Pond", "fun": 2.41, "difficulty": 1.42, "author": "quinnomatic", "desc": "Frogger the magic frog can jump 10 feet using his magical magic jump, but his magic loses its power by a half each time, so his next jump only goes as far as 5 feet. The next jump will take him 2.5 feet, and so on. How many jumps does it take to make it all the way across a 100 foot long pond?", "hint": "No hint available.", "answer": "He can't make it to the other side. No matter how much he jumps, he will only travel about 20 feet at the most.", "category": "Math", "date": "10/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFrogger the magic frog can jump 10 feet using his magical magic jump, but his magic loses its power by a half each time, so his next jump only goes as far as 5 feet. The next jump will take him 2.5 feet, and so on. How many jumps does it take to make it all the way across a 100 foot long pond?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe can't make it to the other side. No matter how much he jumps, he will only travel about 20 feet at the most.\n<|im_start|>answer\nHe can't make it to the other side. No matter how much he jumps, he will only travel about 20 feet at the most.\n<|im_end|>" }, { "id": "#19249", "title": "One is Three...", "fun": 2.41, "difficulty": 1.42, "author": "DSdude", "desc": "One is three. Three is five. Five is four. And four is the magic number. \n\r\nWhat is the pattern?", "hint": "No hint available.", "answer": "ONE is spelled with three letters. \r\nTHREE is spelled with five letters. \r\nFIVE is spelled with four letters. \r\nAnd four is the magic number, because FOUR has four letters in its name.", "category": "Logic", "date": "10/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne is three. Three is five. Five is four. And four is the magic number. \n\r\nWhat is the pattern?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nONE is spelled with three letters. \r\nTHREE is spelled with five letters. \r\nFIVE is spelled with four letters. \r\nAnd four is the magic number, because FOUR has four letters in its name.\n<|im_start|>answer\nONE is spelled with three letters. \r\nTHREE is spelled with five letters. \r\nFIVE is spelled with four letters. \r\nAnd four is the magic number, because FOUR has four letters in its name.\n<|im_end|>" }, { "id": "#8630", "title": "Cats and Mice", "fun": 2.41, "difficulty": 2.28, "author": "lesternoronha1", "desc": "A number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number of mice. How many cats do you think there were? \n\r\nThere are two conditions:\n\r\na) It is not one cat that killed the lot because I have used the word 'Cats'\r\nb) It is not 999919 cats because I have used the word 'mice'.", "hint": "No hint available.", "answer": "The number 999919 cannot be a prime number at first glance. If the problem has only one solution, then this number should have only 2 factors. The factors are 991 and 1009 which are both prime. Since each cat killed more mice than there were cats the answer is clearly that 991 cats killed 1009 mice.", "category": "Math", "date": "11/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number of mice. How many cats do you think there were? \n\r\nThere are two conditions:\n\r\na) It is not one cat that killed the lot because I have used the word 'Cats'\r\nb) It is not 999919 cats because I have used the word 'mice'.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number 999919 cannot be a prime number at first glance. If the problem has only one solution, then this number should have only 2 factors. The factors are 991 and 1009 which are both prime. Since each cat killed more mice than there were cats the answer is clearly that 991 cats killed 1009 mice.\n<|im_start|>answer\nThe number 999919 cannot be a prime number at first glance. If the problem has only one solution, then this number should have only 2 factors. The factors are 991 and 1009 which are both prime. Since each cat killed more mice than there were cats the answer is clearly that 991 cats killed 1009 mice.\n<|im_end|>" }, { "id": "#43762", "title": "Friends' Day Off", "fun": 2.41, "difficulty": 0.84, "author": "clevercoffee", "desc": "Four friends with crazy work schedules all got a different day off this week. Each did something fun on their day off. Can you determine who took what day off from what job as well as what each person did? \n\r\nThe Bartender either went to a movie or went shopping on her day off. \n\r\nThe person who took Sunday off was a woman. \n\r\nWednesday was a great day for a person to go hunting. \n\r\nLeigha did not take Friday off nor did she go fishing. \n\r\nThe four friends are.....Mark, the one who took Friday off, the Stylist, and the one who went fishing. \n\r\nStarr is a Bartender but did not go fishing. \n\r\nMark enjoyed Wednesday but did not go shopping. \n\r\nJessica enjoyed Sunday off from her Barista job, and Leigha bought a new purse on her day off.", "hint": "No hint available.", "answer": "Leigha - Stylist - Tuesday - Shopping\r\nStarr - Bartender - Friday - Movie\r\nMark - Jeweler - Wednesday - Hunting\r\nJessica - Barista - Sunday - Fishing", "category": "Logic-Grid", "date": "12/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends with crazy work schedules all got a different day off this week. Each did something fun on their day off. Can you determine who took what day off from what job as well as what each person did? \n\r\nThe Bartender either went to a movie or went shopping on her day off. \n\r\nThe person who took Sunday off was a woman. \n\r\nWednesday was a great day for a person to go hunting. \n\r\nLeigha did not take Friday off nor did she go fishing. \n\r\nThe four friends are.....Mark, the one who took Friday off, the Stylist, and the one who went fishing. \n\r\nStarr is a Bartender but did not go fishing. \n\r\nMark enjoyed Wednesday but did not go shopping. \n\r\nJessica enjoyed Sunday off from her Barista job, and Leigha bought a new purse on her day off.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeigha - Stylist - Tuesday - Shopping\r\nStarr - Bartender - Friday - Movie\r\nMark - Jeweler - Wednesday - Hunting\r\nJessica - Barista - Sunday - Fishing\n<|im_start|>answer\nLeigha - Stylist - Tuesday - Shopping\r\nStarr - Bartender - Friday - Movie\r\nMark - Jeweler - Wednesday - Hunting\r\nJessica - Barista - Sunday - Fishing\n<|im_end|>" }, { "id": "#1471", "title": "Hare and Tortoise", "fun": 2.41, "difficulty": 1.15, "author": "Jbody33", "desc": "Haretown and Tortoiseville are 27 miles apart. A hare travels at 7 miles per hour from Haretown to Tortoiseville, while a tortoise travels at 2 miles per hour from Tortoiseville to Haretown. \n\r\nIf both set out at the same time, how many miles will the hare have to travel before meeting the tortoise en route?", "hint": "No hint available.", "answer": "The hare and the tortoise are together covering the distance at 9 miles per hour (i.e., on adding their speeds). \r\nSo, they will cover the distance of 27 miles in 3 hours. \r\nThus, in 3 hours, they will meet and the hare will have traveled 21 miles.", "category": "Math", "date": "11/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHaretown and Tortoiseville are 27 miles apart. A hare travels at 7 miles per hour from Haretown to Tortoiseville, while a tortoise travels at 2 miles per hour from Tortoiseville to Haretown. \n\r\nIf both set out at the same time, how many miles will the hare have to travel before meeting the tortoise en route?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe hare and the tortoise are together covering the distance at 9 miles per hour (i.e., on adding their speeds). \r\nSo, they will cover the distance of 27 miles in 3 hours. \r\nThus, in 3 hours, they will meet and the hare will have traveled 21 miles.\n<|im_start|>answer\nThe hare and the tortoise are together covering the distance at 9 miles per hour (i.e., on adding their speeds). \r\nSo, they will cover the distance of 27 miles in 3 hours. \r\nThus, in 3 hours, they will meet and the hare will have traveled 21 miles.\n<|im_end|>" }, { "id": "#29087", "title": "Knotty Notation", "fun": 2.41, "difficulty": 2.46, "author": "kiss", "desc": "A single drop of water contains 1.70 quintillion molecules. In the chemistry lab, I'm following a procedure that calls for me to add 30 drops of water to a solution. I must report how many hydrogen atoms I have added to the solution. I must write the answer in scientific notation.\n\r\nWhat should I report?", "hint": "Consult a dictionary or a chemistry text.", "answer": "I should report that I have added 1.02*10^20 hydrogen atoms to the solution.\n\r\nI have added 30 drops of water. Each drop of water contains 1.7 quintillion molecules. So, I have added 51 quintillion molecules (1.7*30=51). Since each molecule of water has 2 hydrogen atoms, you can determine that I have added 102 quintillion hydrogen atoms to the solution (2*51 = 102).\n\r\nAlso, 1 quintillion is equal to 1 followed by 18 zeros. In scientific notation, it's written as 1*10^18. In scientific notation, a number is expressed as a decimal number between 1 and 10 multiplied by a power of 10. So, in scientific notation, 102 quintillion = 1.02*10^20.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA single drop of water contains 1.70 quintillion molecules. In the chemistry lab, I'm following a procedure that calls for me to add 30 drops of water to a solution. I must report how many hydrogen atoms I have added to the solution. I must write the answer in scientific notation.\n\r\nWhat should I report?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI should report that I have added 1.02*10^20 hydrogen atoms to the solution.\n\r\nI have added 30 drops of water. Each drop of water contains 1.7 quintillion molecules. So, I have added 51 quintillion molecules (1.7*30=51). Since each molecule of water has 2 hydrogen atoms, you can determine that I have added 102 quintillion hydrogen atoms to the solution (2*51 = 102).\n\r\nAlso, 1 quintillion is equal to 1 followed by 18 zeros. In scientific notation, it's written as 1*10^18. In scientific notation, a number is expressed as a decimal number between 1 and 10 multiplied by a power of 10. So, in scientific notation, 102 quintillion = 1.02*10^20.\n<|im_start|>answer\nI should report that I have added 1.02*10^20 hydrogen atoms to the solution.\n\r\nI have added 30 drops of water. Each drop of water contains 1.7 quintillion molecules. So, I have added 51 quintillion molecules (1.7*30=51). Since each molecule of water has 2 hydrogen atoms, you can determine that I have added 102 quintillion hydrogen atoms to the solution (2*51 = 102).\n\r\nAlso, 1 quintillion is equal to 1 followed by 18 zeros. In scientific notation, it's written as 1*10^18. In scientific notation, a number is expressed as a decimal number between 1 and 10 multiplied by a power of 10. So, in scientific notation, 102 quintillion = 1.02*10^20.\n<|im_end|>" }, { "id": "#4322", "title": "Whose House", "fun": 2.41, "difficulty": 1.24, "author": "mad-ade", "desc": "Mad Ade is looking at a picture, in his mother's, only sibling's, nephew's house. \n\r\nSomeone walks by Mad Ade and asks \"Who are you looking at?\" Mad Ade answered \"I am looking at my daughter's, only brother's, mother's, father's son-in-law's, son's, father's picture. Also, neither I nor my wife have brothers or sisters.\" \n\r\nWhose house is Mad Ade in and who is he looking at?", "hint": "No hint available.", "answer": "Mad Ade's mother's only brother's nephew is the Mad Ade himself as Mad Ade does not have any brothers or sisters. Thus, he is in his own house. \n\r\nMad Ade's daughter's only brother = his son \r\nSon's mother = his wife \r\nWife's father's son-in-law = Mad Ade himself (as his wife does not have any brothers or sisters) \r\nAgain, Mad Ade's son's father is himself. \n\r\nHence, Mad Ade is in his own house and looking at his own picture!", "category": "Logic", "date": "05/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is looking at a picture, in his mother's, only sibling's, nephew's house. \n\r\nSomeone walks by Mad Ade and asks \"Who are you looking at?\" Mad Ade answered \"I am looking at my daughter's, only brother's, mother's, father's son-in-law's, son's, father's picture. Also, neither I nor my wife have brothers or sisters.\" \n\r\nWhose house is Mad Ade in and who is he looking at?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade's mother's only brother's nephew is the Mad Ade himself as Mad Ade does not have any brothers or sisters. Thus, he is in his own house. \n\r\nMad Ade's daughter's only brother = his son \r\nSon's mother = his wife \r\nWife's father's son-in-law = Mad Ade himself (as his wife does not have any brothers or sisters) \r\nAgain, Mad Ade's son's father is himself. \n\r\nHence, Mad Ade is in his own house and looking at his own picture!\n<|im_start|>answer\nMad Ade's mother's only brother's nephew is the Mad Ade himself as Mad Ade does not have any brothers or sisters. Thus, he is in his own house. \n\r\nMad Ade's daughter's only brother = his son \r\nSon's mother = his wife \r\nWife's father's son-in-law = Mad Ade himself (as his wife does not have any brothers or sisters) \r\nAgain, Mad Ade's son's father is himself. \n\r\nHence, Mad Ade is in his own house and looking at his own picture!\n<|im_end|>" }, { "id": "#36894", "title": "Cornered At #10 Plaza", "fun": 2.41, "difficulty": 2.26, "author": "chaskey", "desc": "On the same day last year, four good citizens chose to go on errands that coincidently took them to the four corners of #10 Plaza (called that because that is where 10th Avenue intersects 10th Street). Who the people were, the objects of their objectives, and where they went may be determined by following the clues below.\n\r\nPEOPLE: Al Ive, Ben Efits, Lon Ely, Sal Ary\r\nOBJECTS: speech, mural, water, coffee\r\nCORNERS: northeast (NE), southeast (SE), northwest (NW), southwest (SW)\r\nPLACES: Gastric Grocery, Late Newspaper, Todaze Drugs Pharmacy, Mold Memorial Fountain\n\r\nCLUES:\r\n1. That was the day he came to fill the watercoolers in the Late Newspaper building.\n\r\n2. On the corner in front of Gastric Grocery, Sal Ary talked for a little while with Ben Efits about the mural Lon Ely was painting in the building across 10th Street, and then he, Sal, went inside to buy coffee.\n\r\n3. Ben Efits waited until the southbound 10th Street bus passed close by in the right lane, then he crossed 10th St., turned left, and crossed 10th Avenue to that corner where he intended to deliver a speech about the benefits of public speaking.\n\r\n4. As Lon Ely was coming from working on his deepsea mural in the Todaze Drugs Pharmacy, he could hear Ben Efits yelling something about speaking. The decibels were coming from the Mold Memorial Fountain directly across 10th Avenue.", "hint": "No hint available.", "answer": "Al Ive--water--NW--Late Newspaper\r\nBen Efits--speech--NE--Mold Memoria Fountain\r\nLon Ely--mural--SE--Todaze Drugs Pharmacy\r\nSal Ary--coffee--SW--Gastric Grocery", "category": "Logic-Grid", "date": "06/08/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn the same day last year, four good citizens chose to go on errands that coincidently took them to the four corners of #10 Plaza (called that because that is where 10th Avenue intersects 10th Street). Who the people were, the objects of their objectives, and where they went may be determined by following the clues below.\n\r\nPEOPLE: Al Ive, Ben Efits, Lon Ely, Sal Ary\r\nOBJECTS: speech, mural, water, coffee\r\nCORNERS: northeast (NE), southeast (SE), northwest (NW), southwest (SW)\r\nPLACES: Gastric Grocery, Late Newspaper, Todaze Drugs Pharmacy, Mold Memorial Fountain\n\r\nCLUES:\r\n1. That was the day he came to fill the watercoolers in the Late Newspaper building.\n\r\n2. On the corner in front of Gastric Grocery, Sal Ary talked for a little while with Ben Efits about the mural Lon Ely was painting in the building across 10th Street, and then he, Sal, went inside to buy coffee.\n\r\n3. Ben Efits waited until the southbound 10th Street bus passed close by in the right lane, then he crossed 10th St., turned left, and crossed 10th Avenue to that corner where he intended to deliver a speech about the benefits of public speaking.\n\r\n4. As Lon Ely was coming from working on his deepsea mural in the Todaze Drugs Pharmacy, he could hear Ben Efits yelling something about speaking. The decibels were coming from the Mold Memorial Fountain directly across 10th Avenue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAl Ive--water--NW--Late Newspaper\r\nBen Efits--speech--NE--Mold Memoria Fountain\r\nLon Ely--mural--SE--Todaze Drugs Pharmacy\r\nSal Ary--coffee--SW--Gastric Grocery\n<|im_start|>answer\nAl Ive--water--NW--Late Newspaper\r\nBen Efits--speech--NE--Mold Memoria Fountain\r\nLon Ely--mural--SE--Todaze Drugs Pharmacy\r\nSal Ary--coffee--SW--Gastric Grocery\n<|im_end|>" }, { "id": "#2253", "title": "Meet the Boss", "fun": 2.41, "difficulty": 1.45, "author": "PyroTekniks", "desc": "Your boss has gone out of town. Her secretary is angry at you for some reason, so he tells you, \"She wants to see you in her office at 8:30 A.M. two days after the day before the day after tomorrow.\" What day will you show up half an hour early to see your boss? Today is Tuesday.", "hint": "No hint available.", "answer": "Friday", "category": "Logic", "date": "02/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour boss has gone out of town. Her secretary is angry at you for some reason, so he tells you, \"She wants to see you in her office at 8:30 A.M. two days after the day before the day after tomorrow.\" What day will you show up half an hour early to see your boss? Today is Tuesday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriday\n<|im_start|>answer\nFriday\n<|im_end|>" }, { "id": "#25242", "title": "Which is the Original?", "fun": 2.41, "difficulty": 1.12, "author": "dolphingurl12", "desc": "A teacher was making copies of a class assignment, when he remembered he forgot to add a problem to the end. He wanted to use the original copy to write on. By only touching them, how did he know which was the original copy?", "hint": "The copies and the original were exactly alike, the paper was the same color, and he made no markings to any of them.", "answer": "The new copies were warm as they had just been printed, while the original copy was room temperature.", "category": "Logic", "date": "08/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA teacher was making copies of a class assignment, when he remembered he forgot to add a problem to the end. He wanted to use the original copy to write on. By only touching them, how did he know which was the original copy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe new copies were warm as they had just been printed, while the original copy was room temperature.\n<|im_start|>answer\nThe new copies were warm as they had just been printed, while the original copy was room temperature.\n<|im_end|>" }, { "id": "#1868", "title": "The Cloak", "fun": 2.41, "difficulty": 1.79, "author": "missie", "desc": "A butler is promised $100 and a cloak as his wages for a year. After 7 months he leaves this job, and receives the cloak and $20 as his payment. How much is the cloak worth?", "hint": "No hint available.", "answer": "$92", "category": "Math", "date": "12/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA butler is promised $100 and a cloak as his wages for a year. After 7 months he leaves this job, and receives the cloak and $20 as his payment. How much is the cloak worth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$92\n<|im_start|>answer\n$92\n<|im_end|>" }, { "id": "#32045", "title": "Scrambled Eggs", "fun": 2.4, "difficulty": 1.97, "author": "Sir_CombusTable", "desc": "If 4 frogs lay 4 eggs in 4 days, and 3 ducks lay 3 eggs in 3 days, and 2 hens lay 2 eggs twice in two days, how many eggs will 1 frog, 1 duck, and 1 hen lay in total from the beginning of February to the end of March in a leap year?", "hint": "No hint available.", "answer": "95\n\r\nIf 4 frogs lay 4 eggs in 4 days, then 1 frog would lay 1 egg every 4 days. Using the same logic, we can say that 1 duck would lay 1 egg every three days.\n\r\nIf 2 hens lay 2 eggs TWICE in 2 days, then that means 2 hens would lay 4 eggs in 2 days. Using the same logic as before we can say 1 hen lays 2 eggs every 2 days, therefore it lays 1 egg per day.\n\r\nIn a leap year February has 29 days and March has 31, which is a total of 60 days.\n\r\nAt a rate of 1 egg per day, the hen would lay 60 eggs. At 1 egg every 3 days, the duck would lay 20 eggs. And at 1 egg every 4 days the frog would lay 15 eggs.\n\r\n60 + 20 + 15 = 95", "category": "Math", "date": "07/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 4 frogs lay 4 eggs in 4 days, and 3 ducks lay 3 eggs in 3 days, and 2 hens lay 2 eggs twice in two days, how many eggs will 1 frog, 1 duck, and 1 hen lay in total from the beginning of February to the end of March in a leap year?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n95\n\r\nIf 4 frogs lay 4 eggs in 4 days, then 1 frog would lay 1 egg every 4 days. Using the same logic, we can say that 1 duck would lay 1 egg every three days.\n\r\nIf 2 hens lay 2 eggs TWICE in 2 days, then that means 2 hens would lay 4 eggs in 2 days. Using the same logic as before we can say 1 hen lays 2 eggs every 2 days, therefore it lays 1 egg per day.\n\r\nIn a leap year February has 29 days and March has 31, which is a total of 60 days.\n\r\nAt a rate of 1 egg per day, the hen would lay 60 eggs. At 1 egg every 3 days, the duck would lay 20 eggs. And at 1 egg every 4 days the frog would lay 15 eggs.\n\r\n60 + 20 + 15 = 95\n<|im_start|>answer\n95\n\r\nIf 4 frogs lay 4 eggs in 4 days, then 1 frog would lay 1 egg every 4 days. Using the same logic, we can say that 1 duck would lay 1 egg every three days.\n\r\nIf 2 hens lay 2 eggs TWICE in 2 days, then that means 2 hens would lay 4 eggs in 2 days. Using the same logic as before we can say 1 hen lays 2 eggs every 2 days, therefore it lays 1 egg per day.\n\r\nIn a leap year February has 29 days and March has 31, which is a total of 60 days.\n\r\nAt a rate of 1 egg per day, the hen would lay 60 eggs. At 1 egg every 3 days, the duck would lay 20 eggs. And at 1 egg every 4 days the frog would lay 15 eggs.\n\r\n60 + 20 + 15 = 95\n<|im_end|>" }, { "id": "#18358", "title": "Minefield", "fun": 2.4, "difficulty": 2.79, "author": "jmcleod", "desc": "A road leading to a secret military base is 20 feet wide. Private Roberts was ordered to plant 20 land mines on the road in a 20-foot by 20-foot area. He laid out the area in a grid, with 100 2-foot squares arranged in 10 columns (running parallel with the road) and 10 rows (running perpendicular with the road). He planted each land mine within a square on the grid so that there were exactly two mines in each row and two in each column. When he was finished, he found himself on the wrong side of the minefield, and he couldn't get back to the base without crossing the minefield. \n\r\nHe labeled the columns A-J from left to right, and numbered the rows 1-10 starting with the row closest to the base. \n\r\n-- A B C D E F G H I J\r\n01X X X X X X X X X X\r\n02X X X X X X X X X X\r\n03X X X X X X X X X X\r\n04X X X X X X X X X X\r\n05X X X X X X X X X X\r\n06X X X X X X X X X X\r\n07X X X X X X X X X X\r\n08X X X X X X X X X X\r\n09X X X X X X X X X X\r\n10X X X X X X X X X X\n\r\nHe could remember the following facts about where the mines were planted:\n\r\n1. There was no mine in any of the four corners.\r\n2. Row 10 was the only row where the two mines were next to each other.\r\n3. The two mines in column C were in the same rows as the two mines in column H.\r\n4. One of the mines in column B was in row 7.\r\n5. In row 9, there were 3 empty squares between the two mines.\r\n6. Both mines in column E were in row 5 or higher.\r\n7. One of the mines in column I was in row 9 or 10.\r\n8. Both mines in column H were in odd number rows.\r\n9. The two mines in column D were in the same rows as the two mines in column J.\r\n10. One of the mines in column A was in row 5.\n\r\nCan you find a safe path to the other side of the mine field moving one square at a time (either horizontally, vertically, or diagonally), starting in row 10 and moving through row one?", "hint": "Try to map the safe squares, not the mines. Diagonal movements are allowed.", "answer": "The shortest safe path: start at C:10 and walk straight to C:5, turn right to D:5, then move diagonal to E:4, and walk straight out through E:1. Following is a map of the safe squares.\n\r\n-- A B C D E F G H I J\r\n01S X X S S X X X X S\r\n02X X S X S X X S X X\r\n03X X X X S X X X X X\r\n04X X S X S X X S X X\r\n05X S S S X X X S X S\r\n06X X S X X X X S X X\r\n07S X S S X X X S X S\r\n08X X S X X X X S X X\r\n09S S S S X S S S X S\r\n10S X S X X X X S X S\n\r\nRow 10: A, C, H and J are safe (clue 1, 3, 8).\r\nRow 9: Clue 1, 2, 5, 7 place mines in I:9 and E:9.\r\nRow 8: C and H are safe (clue 3 and 8).\r\nRow 7: There is a mine in B (clue 4), which makes A,C,D, H, and J safe (clue 2,3, and 9).\r\nRow 6: C and H are safe (clue 3 and 8).\r\nRow 5: There is a mine in A (clue 10), which makes B,C,D, H, and J safe (clue 2,3, and 9).\r\nRow 1 through 4: E is safe (clue 6).", "category": "Logic", "date": "07/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA road leading to a secret military base is 20 feet wide. Private Roberts was ordered to plant 20 land mines on the road in a 20-foot by 20-foot area. He laid out the area in a grid, with 100 2-foot squares arranged in 10 columns (running parallel with the road) and 10 rows (running perpendicular with the road). He planted each land mine within a square on the grid so that there were exactly two mines in each row and two in each column. When he was finished, he found himself on the wrong side of the minefield, and he couldn't get back to the base without crossing the minefield. \n\r\nHe labeled the columns A-J from left to right, and numbered the rows 1-10 starting with the row closest to the base. \n\r\n-- A B C D E F G H I J\r\n01X X X X X X X X X X\r\n02X X X X X X X X X X\r\n03X X X X X X X X X X\r\n04X X X X X X X X X X\r\n05X X X X X X X X X X\r\n06X X X X X X X X X X\r\n07X X X X X X X X X X\r\n08X X X X X X X X X X\r\n09X X X X X X X X X X\r\n10X X X X X X X X X X\n\r\nHe could remember the following facts about where the mines were planted:\n\r\n1. There was no mine in any of the four corners.\r\n2. Row 10 was the only row where the two mines were next to each other.\r\n3. The two mines in column C were in the same rows as the two mines in column H.\r\n4. One of the mines in column B was in row 7.\r\n5. In row 9, there were 3 empty squares between the two mines.\r\n6. Both mines in column E were in row 5 or higher.\r\n7. One of the mines in column I was in row 9 or 10.\r\n8. Both mines in column H were in odd number rows.\r\n9. The two mines in column D were in the same rows as the two mines in column J.\r\n10. One of the mines in column A was in row 5.\n\r\nCan you find a safe path to the other side of the mine field moving one square at a time (either horizontally, vertically, or diagonally), starting in row 10 and moving through row one?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe shortest safe path: start at C:10 and walk straight to C:5, turn right to D:5, then move diagonal to E:4, and walk straight out through E:1. Following is a map of the safe squares.\n\r\n-- A B C D E F G H I J\r\n01S X X S S X X X X S\r\n02X X S X S X X S X X\r\n03X X X X S X X X X X\r\n04X X S X S X X S X X\r\n05X S S S X X X S X S\r\n06X X S X X X X S X X\r\n07S X S S X X X S X S\r\n08X X S X X X X S X X\r\n09S S S S X S S S X S\r\n10S X S X X X X S X S\n\r\nRow 10: A, C, H and J are safe (clue 1, 3, 8).\r\nRow 9: Clue 1, 2, 5, 7 place mines in I:9 and E:9.\r\nRow 8: C and H are safe (clue 3 and 8).\r\nRow 7: There is a mine in B (clue 4), which makes A,C,D, H, and J safe (clue 2,3, and 9).\r\nRow 6: C and H are safe (clue 3 and 8).\r\nRow 5: There is a mine in A (clue 10), which makes B,C,D, H, and J safe (clue 2,3, and 9).\r\nRow 1 through 4: E is safe (clue 6).\n<|im_start|>answer\nThe shortest safe path: start at C:10 and walk straight to C:5, turn right to D:5, then move diagonal to E:4, and walk straight out through E:1. Following is a map of the safe squares.\n\r\n-- A B C D E F G H I J\r\n01S X X S S X X X X S\r\n02X X S X S X X S X X\r\n03X X X X S X X X X X\r\n04X X S X S X X S X X\r\n05X S S S X X X S X S\r\n06X X S X X X X S X X\r\n07S X S S X X X S X S\r\n08X X S X X X X S X X\r\n09S S S S X S S S X S\r\n10S X S X X X X S X S\n\r\nRow 10: A, C, H and J are safe (clue 1, 3, 8).\r\nRow 9: Clue 1, 2, 5, 7 place mines in I:9 and E:9.\r\nRow 8: C and H are safe (clue 3 and 8).\r\nRow 7: There is a mine in B (clue 4), which makes A,C,D, H, and J safe (clue 2,3, and 9).\r\nRow 6: C and H are safe (clue 3 and 8).\r\nRow 5: There is a mine in A (clue 10), which makes B,C,D, H, and J safe (clue 2,3, and 9).\r\nRow 1 through 4: E is safe (clue 6).\n<|im_end|>" }, { "id": "#4496", "title": "Nobby, Bobby and Rover", "fun": 2.4, "difficulty": 2.02, "author": "mad-ade", "desc": "In the legendary land of MADADIA, there lived a king, King Mad Ade of the Kebab people. King Mad Ade had three sons called Nobby, Bobby and Rover. They were triplets, but unfortunately due to a mix up at birth no one knew which was the oldest, the heir to the kingdom. The king decided to set a challenge for his three sons, to determine who should inherit the kingdom. He called his sons and spoke to them all. \"Nobby, Bobby, Rover\" he said \"Behind the castle you will each find an identical plot of land marked with your names.\" At this he held out 3 packets of seeds, one for each son. \"take these and grow me some flowers. I will look at them this time next year.\" At that he dismissed his sons and marked the date on the calendar.\n\r\nOne year later he visited the three plots of land he had given his sons. He noted that Nobby's plot was full of beautiful flowers.\r\nHe walked on to Bobby's plot which was also packed with beautiful flowers. He ambled around to Rover's only to find nothing more than a patch of muddy ground and some grass.\r\nLater that day he called his sons together. \"Boys, I have made my choice as to who shall inherit the Kingdom of MADADIA!\" he announced. The three brothers waited with bated breath.\r\n\" I shall be leaving it to .......Rover!\"\n\r\nWhat made King Mad Ade choose his son Rover?", "hint": "No hint available.", "answer": "Because he had given them all dud seeds that he knew wouldn't grow. Nobby and Bobby saw that the seeds were not growing so brought in flowers to impress the King, whereas Rover decided to let the king see the true result. Therefore the King knew that despite Nobby and Bobby's efforts to please him, only Rover could be trusted.", "category": "Logic", "date": "06/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary land of MADADIA, there lived a king, King Mad Ade of the Kebab people. King Mad Ade had three sons called Nobby, Bobby and Rover. They were triplets, but unfortunately due to a mix up at birth no one knew which was the oldest, the heir to the kingdom. The king decided to set a challenge for his three sons, to determine who should inherit the kingdom. He called his sons and spoke to them all. \"Nobby, Bobby, Rover\" he said \"Behind the castle you will each find an identical plot of land marked with your names.\" At this he held out 3 packets of seeds, one for each son. \"take these and grow me some flowers. I will look at them this time next year.\" At that he dismissed his sons and marked the date on the calendar.\n\r\nOne year later he visited the three plots of land he had given his sons. He noted that Nobby's plot was full of beautiful flowers.\r\nHe walked on to Bobby's plot which was also packed with beautiful flowers. He ambled around to Rover's only to find nothing more than a patch of muddy ground and some grass.\r\nLater that day he called his sons together. \"Boys, I have made my choice as to who shall inherit the Kingdom of MADADIA!\" he announced. The three brothers waited with bated breath.\r\n\" I shall be leaving it to .......Rover!\"\n\r\nWhat made King Mad Ade choose his son Rover?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBecause he had given them all dud seeds that he knew wouldn't grow. Nobby and Bobby saw that the seeds were not growing so brought in flowers to impress the King, whereas Rover decided to let the king see the true result. Therefore the King knew that despite Nobby and Bobby's efforts to please him, only Rover could be trusted.\n<|im_start|>answer\nBecause he had given them all dud seeds that he knew wouldn't grow. Nobby and Bobby saw that the seeds were not growing so brought in flowers to impress the King, whereas Rover decided to let the king see the true result. Therefore the King knew that despite Nobby and Bobby's efforts to please him, only Rover could be trusted.\n<|im_end|>" }, { "id": "#40062", "title": "144 Books", "fun": 2.4, "difficulty": 2.43, "author": "shenqiang", "desc": "Peter had 144 books and donated them to four schools. When Peter checked the number of books given to each school, he found out that the difference of the number of books between School A and School B was 4; between School B and School C was 3; between School C and School D was 2. School A had the most number of books, but received less than 40 books. How many books did School D get?", "hint": "No hint available.", "answer": "Denote the number of books received by the four schools a, b, c and d, respectively.\r\nSince a is the largest, b must equal a-4.\r\nc differs 3 from b, and can be either a-1 or a-7.\r\nIf c=a-1, then d must be a-3, which implies a+(a-4)+(a-1)+(a-3)=144, a=38, and a-3=35.\r\nIf c=a-7, then d can be either a-5 or a-9. However, it can be checked that in either case, a>=40.\r\nTherefore, School D got 35 books.", "category": "Math", "date": "01/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPeter had 144 books and donated them to four schools. When Peter checked the number of books given to each school, he found out that the difference of the number of books between School A and School B was 4; between School B and School C was 3; between School C and School D was 2. School A had the most number of books, but received less than 40 books. How many books did School D get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDenote the number of books received by the four schools a, b, c and d, respectively.\r\nSince a is the largest, b must equal a-4.\r\nc differs 3 from b, and can be either a-1 or a-7.\r\nIf c=a-1, then d must be a-3, which implies a+(a-4)+(a-1)+(a-3)=144, a=38, and a-3=35.\r\nIf c=a-7, then d can be either a-5 or a-9. However, it can be checked that in either case, a>=40.\r\nTherefore, School D got 35 books.\n<|im_start|>answer\nDenote the number of books received by the four schools a, b, c and d, respectively.\r\nSince a is the largest, b must equal a-4.\r\nc differs 3 from b, and can be either a-1 or a-7.\r\nIf c=a-1, then d must be a-3, which implies a+(a-4)+(a-1)+(a-3)=144, a=38, and a-3=35.\r\nIf c=a-7, then d can be either a-5 or a-9. However, it can be checked that in either case, a>=40.\r\nTherefore, School D got 35 books.\n<|im_end|>" }, { "id": "#39833", "title": "Why? 2", "fun": 2.4, "difficulty": 0.72, "author": "Cammi_27", "desc": "Three people were killed in one night, in the same mansion, in three different rooms, and for three different reasons. The killers were Aviva, Kaleb, and Liz. They killed Camille, Tyler, and Kaylee. Based on the following clues, help Detective Miff find who killed whom and for what reason.\n\r\n1. Camille was killed by another girl because of a silly bet made earlier that day.\r\n2. Kaleb killed his victim by accident.\r\n3. Liz killed Kaylee in a lime green room out of a sudden burst of rage from the wall hangings she noticed in the kitchen.\r\n4. Aviva killed her victim in the garden and won five hundred dollars.\r\n5. Tyler was killed by a flying book that struck him in the back of his head. Later his killer was upset by the news of Tyler's death. \r\n6. Kaylee was found dead on the toilet.", "hint": "Kaleb and Tyler are boys and Kaylee, Camille, Aviva, and Liz are girls. The mansion they are in belongs to Kaylee. They are having this get together to discuss the break in that just happened at Liz's mansion next door.", "answer": "Aviva killed Camille in the garden because of a silly bet with her friends. She was in need of some money after she bought the upgrade on her house.\r\nKaleb killed Tyler in the library because he carelessly threw a dictionary behind his head after moving it aside to look at something on the shelf.\r\nLiz killed Kaylee in the bathroom after she was talking to Kaylee in the kitchen and noticed a lot of the missing paintings from her living room and dining room hanging on the kitchen walls. She had an outburst of rage and struck Kaylee hard with a butcher knife.", "category": "Logic-Grid", "date": "12/29/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people were killed in one night, in the same mansion, in three different rooms, and for three different reasons. The killers were Aviva, Kaleb, and Liz. They killed Camille, Tyler, and Kaylee. Based on the following clues, help Detective Miff find who killed whom and for what reason.\n\r\n1. Camille was killed by another girl because of a silly bet made earlier that day.\r\n2. Kaleb killed his victim by accident.\r\n3. Liz killed Kaylee in a lime green room out of a sudden burst of rage from the wall hangings she noticed in the kitchen.\r\n4. Aviva killed her victim in the garden and won five hundred dollars.\r\n5. Tyler was killed by a flying book that struck him in the back of his head. Later his killer was upset by the news of Tyler's death. \r\n6. Kaylee was found dead on the toilet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAviva killed Camille in the garden because of a silly bet with her friends. She was in need of some money after she bought the upgrade on her house.\r\nKaleb killed Tyler in the library because he carelessly threw a dictionary behind his head after moving it aside to look at something on the shelf.\r\nLiz killed Kaylee in the bathroom after she was talking to Kaylee in the kitchen and noticed a lot of the missing paintings from her living room and dining room hanging on the kitchen walls. She had an outburst of rage and struck Kaylee hard with a butcher knife.\n<|im_start|>answer\nAviva killed Camille in the garden because of a silly bet with her friends. She was in need of some money after she bought the upgrade on her house.\r\nKaleb killed Tyler in the library because he carelessly threw a dictionary behind his head after moving it aside to look at something on the shelf.\r\nLiz killed Kaylee in the bathroom after she was talking to Kaylee in the kitchen and noticed a lot of the missing paintings from her living room and dining room hanging on the kitchen walls. She had an outburst of rage and struck Kaylee hard with a butcher knife.\n<|im_end|>" }, { "id": "#3893", "title": "Playing Cards", "fun": 2.4, "difficulty": 1.65, "author": "mad-ade", "desc": "You are holding some playing cards, you have 1 queen, 2 diamonds, 3 aces and 4 spades. What is the minimum amount of cards you could have if no card is repeated?", "hint": "No hint available.", "answer": "Seven. You have 2 diamonds and 4 spades, giving you at least 6 altogether. The queen can be either of those 2 suits, but as there are 3 aces, 1 has to come from a different suit, giving you a 7th card.", "category": "Logic", "date": "05/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are holding some playing cards, you have 1 queen, 2 diamonds, 3 aces and 4 spades. What is the minimum amount of cards you could have if no card is repeated?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSeven. You have 2 diamonds and 4 spades, giving you at least 6 altogether. The queen can be either of those 2 suits, but as there are 3 aces, 1 has to come from a different suit, giving you a 7th card.\n<|im_start|>answer\nSeven. You have 2 diamonds and 4 spades, giving you at least 6 altogether. The queen can be either of those 2 suits, but as there are 3 aces, 1 has to come from a different suit, giving you a 7th card.\n<|im_end|>" }, { "id": "#11111", "title": "Where's Duffus?", "fun": 2.4, "difficulty": 1.77, "author": "OD-1", "desc": "Duffus Mcclutski loved his tea and often had friends over who shared his passion. On one particular occasion Duffus had Mr. & Mrs. Blue, their 2 boys and 2 girls, Mr.& Mrs. Redneck, their 4 boys and his 3 nieces were over. As the kids didn't drink tea and quickly got bored they convinced the adults to play hide and seek with them. As the clutter in his house could hide a small army it was perfect. There were 2 bedrooms; a kitchen; bathroom; living room; dining room and basement to hide in. Though no one hid in the basement for fear of finding Duffus's used tea bag collection (but that's another teaser). All Duffus's nieces were in one bedroom and two boys in the other. The other girls hid in the dining room. One of the adults was in the bathroom for she had drank too much tea. There were adults hiding in the bathroom; living room; kitchen and dining room. Mrs. Blue wasn't hiding, as she was the one who was to find everyone. One adult and four boys were in the kitchen, so that if the game dragged on they could get a snack. The man with no daughters was fighting with Mr.B's girls for the same hiding spot. There were no kids in the living room, and the man in the dining room had four children. When the game was over, everyone was found except Duffus who had fallen asleep from too much herbal tea. \n\r\nWhere did Duffus hide?", "hint": "Just figure out where the adults are.", "answer": "Yes, Duffus was in the living room asleep behind the couch. If he had been the man in the kitchen the four boys would have known his whereabouts and wouldn't have eaten all his snacks. Well, maybe they would have, but that too is another teaser.", "category": "Logic", "date": "03/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuffus Mcclutski loved his tea and often had friends over who shared his passion. On one particular occasion Duffus had Mr. & Mrs. Blue, their 2 boys and 2 girls, Mr.& Mrs. Redneck, their 4 boys and his 3 nieces were over. As the kids didn't drink tea and quickly got bored they convinced the adults to play hide and seek with them. As the clutter in his house could hide a small army it was perfect. There were 2 bedrooms; a kitchen; bathroom; living room; dining room and basement to hide in. Though no one hid in the basement for fear of finding Duffus's used tea bag collection (but that's another teaser). All Duffus's nieces were in one bedroom and two boys in the other. The other girls hid in the dining room. One of the adults was in the bathroom for she had drank too much tea. There were adults hiding in the bathroom; living room; kitchen and dining room. Mrs. Blue wasn't hiding, as she was the one who was to find everyone. One adult and four boys were in the kitchen, so that if the game dragged on they could get a snack. The man with no daughters was fighting with Mr.B's girls for the same hiding spot. There were no kids in the living room, and the man in the dining room had four children. When the game was over, everyone was found except Duffus who had fallen asleep from too much herbal tea. \n\r\nWhere did Duffus hide?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes, Duffus was in the living room asleep behind the couch. If he had been the man in the kitchen the four boys would have known his whereabouts and wouldn't have eaten all his snacks. Well, maybe they would have, but that too is another teaser.\n<|im_start|>answer\nYes, Duffus was in the living room asleep behind the couch. If he had been the man in the kitchen the four boys would have known his whereabouts and wouldn't have eaten all his snacks. Well, maybe they would have, but that too is another teaser.\n<|im_end|>" }, { "id": "#29460", "title": "Big Six Stop", "fun": 2.4, "difficulty": 1.7, "author": "____", "desc": "Anders and Gabby went to the Big Six convenience store to shop. Anders had twice as much money as Gabby. He spent all but $ .05. He got two pieces of gum and one of each other item listed in the table. Gabby got two different things from the list.\n\r\nIce Pop: $ .50 \r\nGum: $ .15 \r\nApple Drink: $ .65 \n\r\nHow much money did they each have when they started, and what things did each person buy?", "hint": "Make a chart and work backwards.", "answer": "Anders started with $1.50 and bought two pieces of gum, one ice pop, and one apple drink. Gabby began with $ .75 and spent $ .65 on an ice pop and a piece of gum.\n\r\nThe clues tell you what items Anders bought, so you know that he spent (2 x $ .15) + $ .50 + $ .65 = $1.45. He had $ .05 left over, so Anders started with $1.50.\n\r\nGabby began with half Anders' total, $1.50 / 2 = $ .75. She bought two different items in one of three possible combinations: ice pop and gum ($ .50 + $ .15 = $ .65), ice pop and apple drink ($ .50 + $ .65 = $1.15), or gum and apple drink ($ .15 + $ .65 = $ .80). Because she had only $ .75, she must have bought an ice pop and a piece of gum.", "category": "Math", "date": "03/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnders and Gabby went to the Big Six convenience store to shop. Anders had twice as much money as Gabby. He spent all but $ .05. He got two pieces of gum and one of each other item listed in the table. Gabby got two different things from the list.\n\r\nIce Pop: $ .50 \r\nGum: $ .15 \r\nApple Drink: $ .65 \n\r\nHow much money did they each have when they started, and what things did each person buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnders started with $1.50 and bought two pieces of gum, one ice pop, and one apple drink. Gabby began with $ .75 and spent $ .65 on an ice pop and a piece of gum.\n\r\nThe clues tell you what items Anders bought, so you know that he spent (2 x $ .15) + $ .50 + $ .65 = $1.45. He had $ .05 left over, so Anders started with $1.50.\n\r\nGabby began with half Anders' total, $1.50 / 2 = $ .75. She bought two different items in one of three possible combinations: ice pop and gum ($ .50 + $ .15 = $ .65), ice pop and apple drink ($ .50 + $ .65 = $1.15), or gum and apple drink ($ .15 + $ .65 = $ .80). Because she had only $ .75, she must have bought an ice pop and a piece of gum.\n<|im_start|>answer\nAnders started with $1.50 and bought two pieces of gum, one ice pop, and one apple drink. Gabby began with $ .75 and spent $ .65 on an ice pop and a piece of gum.\n\r\nThe clues tell you what items Anders bought, so you know that he spent (2 x $ .15) + $ .50 + $ .65 = $1.45. He had $ .05 left over, so Anders started with $1.50.\n\r\nGabby began with half Anders' total, $1.50 / 2 = $ .75. She bought two different items in one of three possible combinations: ice pop and gum ($ .50 + $ .15 = $ .65), ice pop and apple drink ($ .50 + $ .65 = $1.15), or gum and apple drink ($ .15 + $ .65 = $ .80). Because she had only $ .75, she must have bought an ice pop and a piece of gum.\n<|im_end|>" }, { "id": "#1260", "title": "Typists", "fun": 2.4, "difficulty": 1.42, "author": "gokaran", "desc": "If two typists can type two pages in two minutes, how many typists will it take to type 18 pages in six minutes?", "hint": "No hint available.", "answer": "6. \r\nOne typist types one page in two minutes.", "category": "Math", "date": "11/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf two typists can type two pages in two minutes, how many typists will it take to type 18 pages in six minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6. \r\nOne typist types one page in two minutes.\n<|im_start|>answer\n6. \r\nOne typist types one page in two minutes.\n<|im_end|>" }, { "id": "#31725", "title": "Opposites 20", "fun": 2.4, "difficulty": 2.77, "author": "Winner4600", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n^ stands for N, F, D, R, or E\r\n{ stands for A, W, L, T, or O\r\n@ stands for M, E, C, A, or B\r\n] stands for L, P, O, A, or T\n\r\nThe four letter code word, {@^], can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Warp and Weft.", "category": "Logic", "date": "07/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n^ stands for N, F, D, R, or E\r\n{ stands for A, W, L, T, or O\r\n@ stands for M, E, C, A, or B\r\n] stands for L, P, O, A, or T\n\r\nThe four letter code word, {@^], can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWarp and Weft.\n<|im_start|>answer\nWarp and Weft.\n<|im_end|>" }, { "id": "#21567", "title": "Cookie Sheets", "fun": 2.4, "difficulty": 1.46, "author": "CheerGoalBasket", "desc": "Ms. Gold's class is baking Valentine goodies for the entire grade. They want to be sure they have enough for the 96 children and 4 teachers to be able to have one each of each type of cookie. They decided they would fit the different size cookies on each cookie sheet by following this plan:\n\r\nSmall heart butter cookies: 6 rows of 6 cookies per sheet\r\nMedium heart sugar cookies: 5 rows of 5 cookies per sheet\r\nGiant heart frosted cookies: 3 rows of 4 cookies per sheet\n\r\nIf they use each cookie sheet only once, how many cookie sheets will they need?", "hint": "No hint available.", "answer": "Step 1: \n\r\nThey need at least 100 of each kind of cookie. \n\r\nStep 2: \n\r\nSmall heart butter cookies will take 3 cookie sheets, giving them 108 cookies\r\nMedium heart sugar cookies will take 4 cookie sheets, giving them 100 cookies\r\nGiant heart frosted cookies will take 9 cookie sheets, giving them 108 cookies \n\r\nAnswer: \n\r\nThey need 16 cookie sheets in all.", "category": "Math", "date": "03/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Gold's class is baking Valentine goodies for the entire grade. They want to be sure they have enough for the 96 children and 4 teachers to be able to have one each of each type of cookie. They decided they would fit the different size cookies on each cookie sheet by following this plan:\n\r\nSmall heart butter cookies: 6 rows of 6 cookies per sheet\r\nMedium heart sugar cookies: 5 rows of 5 cookies per sheet\r\nGiant heart frosted cookies: 3 rows of 4 cookies per sheet\n\r\nIf they use each cookie sheet only once, how many cookie sheets will they need?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStep 1: \n\r\nThey need at least 100 of each kind of cookie. \n\r\nStep 2: \n\r\nSmall heart butter cookies will take 3 cookie sheets, giving them 108 cookies\r\nMedium heart sugar cookies will take 4 cookie sheets, giving them 100 cookies\r\nGiant heart frosted cookies will take 9 cookie sheets, giving them 108 cookies \n\r\nAnswer: \n\r\nThey need 16 cookie sheets in all.\n<|im_start|>answer\nStep 1: \n\r\nThey need at least 100 of each kind of cookie. \n\r\nStep 2: \n\r\nSmall heart butter cookies will take 3 cookie sheets, giving them 108 cookies\r\nMedium heart sugar cookies will take 4 cookie sheets, giving them 100 cookies\r\nGiant heart frosted cookies will take 9 cookie sheets, giving them 108 cookies \n\r\nAnswer: \n\r\nThey need 16 cookie sheets in all.\n<|im_end|>" }, { "id": "#22284", "title": "A Phony Problem", "fun": 2.4, "difficulty": 0.64, "author": "Leviathan", "desc": "What is the product of all the numbers on a phone?", "hint": "ALL the numbers", "answer": "0. There is a 0 on phones too.", "category": "Math", "date": "04/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the product of all the numbers on a phone?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0. There is a 0 on phones too.\n<|im_start|>answer\n0. There is a 0 on phones too.\n<|im_end|>" }, { "id": "#2354", "title": "Schubert's Steamroller", "fun": 2.4, "difficulty": 2.16, "author": "KevThaDrinkKilla", "desc": "Wolves, foxes, birds, caterpillars, and snails are animals, and there are some of each. Also there are some grains, and grains are plants. \n\r\nEvery animal either likes to eat all plants, or, all animals much smaller than itself that like to eat some plants. \n\r\nCaterpillars and snails are much smaller than birds, which are much smaller than foxes, which in turn are much smaller than wolves. Wolves do not like to eat foxes or grains, while birds like to eat caterpillars but not snails. Caterpillars and snails like to eat some plants. \n\r\nTherefore there is an animal that likes to eat a grain-eating animal. What is it?", "hint": "No hint available.", "answer": "The fox likes to eat the bird which likes to eat the grain.\n\r\nReason:\r\nThe bird is a plant eating animal because it does not like to eat snails, which like to eat some plant, so it does not like to eat ALL such animals. \n\r\nTherefore it must like to eat all plants. \n\r\nThe fox is not a plant eating animal, because the wolf does not like to eat all plants (specifically grain), and therefore must like eating all animals which like to eat some plants. \n\r\nBut it does not like to eat foxes. \n\r\nTherefore foxes cannot be animals which like to eat some plant.", "category": "Logic", "date": "02/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWolves, foxes, birds, caterpillars, and snails are animals, and there are some of each. Also there are some grains, and grains are plants. \n\r\nEvery animal either likes to eat all plants, or, all animals much smaller than itself that like to eat some plants. \n\r\nCaterpillars and snails are much smaller than birds, which are much smaller than foxes, which in turn are much smaller than wolves. Wolves do not like to eat foxes or grains, while birds like to eat caterpillars but not snails. Caterpillars and snails like to eat some plants. \n\r\nTherefore there is an animal that likes to eat a grain-eating animal. What is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe fox likes to eat the bird which likes to eat the grain.\n\r\nReason:\r\nThe bird is a plant eating animal because it does not like to eat snails, which like to eat some plant, so it does not like to eat ALL such animals. \n\r\nTherefore it must like to eat all plants. \n\r\nThe fox is not a plant eating animal, because the wolf does not like to eat all plants (specifically grain), and therefore must like eating all animals which like to eat some plants. \n\r\nBut it does not like to eat foxes. \n\r\nTherefore foxes cannot be animals which like to eat some plant.\n<|im_start|>answer\nThe fox likes to eat the bird which likes to eat the grain.\n\r\nReason:\r\nThe bird is a plant eating animal because it does not like to eat snails, which like to eat some plant, so it does not like to eat ALL such animals. \n\r\nTherefore it must like to eat all plants. \n\r\nThe fox is not a plant eating animal, because the wolf does not like to eat all plants (specifically grain), and therefore must like eating all animals which like to eat some plants. \n\r\nBut it does not like to eat foxes. \n\r\nTherefore foxes cannot be animals which like to eat some plant.\n<|im_end|>" }, { "id": "#18060", "title": "Alphabet Math", "fun": 2.4, "difficulty": 2.62, "author": "crystalstar", "desc": "Find what all the letters stand for to make the equation correct.\n\r\nABCD x 4 = DCBA", "hint": "If ABCD is being multiplied by 4, the answer must be even. Therefore, A, which is the last digit of the answer, must be even.", "answer": "A = 2, B = 1, C = 7, D = 8", "category": "Math", "date": "06/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind what all the letters stand for to make the equation correct.\n\r\nABCD x 4 = DCBA\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA = 2, B = 1, C = 7, D = 8\n<|im_start|>answer\nA = 2, B = 1, C = 7, D = 8\n<|im_end|>" }, { "id": "#44417", "title": "3 Friends in College", "fun": 2.4, "difficulty": 1.47, "author": "MegRen", "desc": "Three best friends from high school (Livia, Maggie, Nicole) decided to go to different colleges (A&M, Rice, UT) and major in different scientific fields (Biology, Chemistry, Zoology). Each girl also participated in a different extracurricular activity (Band, Cheerleading, Choir) and had a different GPA (3.4, 3.8, 4.0) after her first college semester. Can you figure out where each girl went, what she chose to major in, what activity she participated in and her GPA after her first semester?\n\r\n1. The friend who went to A&M did not have the highest GPA nor was she the friend who majored in Biology.\r\n2. The friend who was a cheerleader did not let her practices affect her studying: she had the highest GPA of her friends.\r\n3. Though she played in band in high school, Maggie was not part of her college band program.\r\n4. The chemistry major did not go to UT nor did she have a 3.4 GPA.\r\n5. Livia, who can't carry a tune to save her life, was not studying animal life.\r\n6. The girl attending Rice had the highest GPA.\r\n7. Nicole hates working with chemicals and compounds, so she chose a different branch of science to major in.\r\n8. Maggie and the biology major both played the flute in high school.\r\n9. The friend with a 3.4 GPA has loved animals her entire life, so of course she chose to study animals in college.\r\n10. Maggie loves singing so much that she started her own band.", "hint": "No hint available.", "answer": "Livia - Rice - Chemistry - 4.0 - Cheerleading\r\nMaggie - A&M - Zoology - 3.4 - Choir\r\nNicole - UT - Biology - 3.8 - Band", "category": "Logic-Grid", "date": "05/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree best friends from high school (Livia, Maggie, Nicole) decided to go to different colleges (A&M, Rice, UT) and major in different scientific fields (Biology, Chemistry, Zoology). Each girl also participated in a different extracurricular activity (Band, Cheerleading, Choir) and had a different GPA (3.4, 3.8, 4.0) after her first college semester. Can you figure out where each girl went, what she chose to major in, what activity she participated in and her GPA after her first semester?\n\r\n1. The friend who went to A&M did not have the highest GPA nor was she the friend who majored in Biology.\r\n2. The friend who was a cheerleader did not let her practices affect her studying: she had the highest GPA of her friends.\r\n3. Though she played in band in high school, Maggie was not part of her college band program.\r\n4. The chemistry major did not go to UT nor did she have a 3.4 GPA.\r\n5. Livia, who can't carry a tune to save her life, was not studying animal life.\r\n6. The girl attending Rice had the highest GPA.\r\n7. Nicole hates working with chemicals and compounds, so she chose a different branch of science to major in.\r\n8. Maggie and the biology major both played the flute in high school.\r\n9. The friend with a 3.4 GPA has loved animals her entire life, so of course she chose to study animals in college.\r\n10. Maggie loves singing so much that she started her own band.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLivia - Rice - Chemistry - 4.0 - Cheerleading\r\nMaggie - A&M - Zoology - 3.4 - Choir\r\nNicole - UT - Biology - 3.8 - Band\n<|im_start|>answer\nLivia - Rice - Chemistry - 4.0 - Cheerleading\r\nMaggie - A&M - Zoology - 3.4 - Choir\r\nNicole - UT - Biology - 3.8 - Band\n<|im_end|>" }, { "id": "#8488", "title": "Number Square", "fun": 2.4, "difficulty": 2.25, "author": "datra16", "desc": "Arrange the numbers 1 through 16 in a square of 4 by 4 numbers so that each row, column, and diagonal adds up to 34.", "hint": "The 4 corners will also add up to 34.", "answer": "01 15 14 04 \r\n12 06 07 09 \r\n08 10 11 05 \r\n13 03 02 16", "category": "Math", "date": "11/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numbers 1 through 16 in a square of 4 by 4 numbers so that each row, column, and diagonal adds up to 34.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n01 15 14 04 \r\n12 06 07 09 \r\n08 10 11 05 \r\n13 03 02 16\n<|im_start|>answer\n01 15 14 04 \r\n12 06 07 09 \r\n08 10 11 05 \r\n13 03 02 16\n<|im_end|>" }, { "id": "#2658", "title": "Ship and Boiler", "fun": 2.4, "difficulty": 2.07, "author": "cathalmccabe", "desc": "A ship is twice as old as its boiler was when the ship was as old as the boiler is now.\r\nThe sum of their ages is 21. \r\nHow old is the boiler, and how old is the ship?", "hint": "Once you get your head around the wording, I think it's easy enough. Try and write down the equations for everything you know.", "answer": "There is an age difference between the ship and the boiler, lets call it D. It will always be the same\n\r\nSHIP = BOILER + D (1)\r\nThe SHIP = 2 * (what the BOILER was) (2)\r\nBOILER NOW = BOILER's age then + D (3)\r\nSHIP NOW + BOILER NOW = 21 (4)\n\r\nThere are now 4 equations with 4 unknowns which can be solved simultaneously To give :\r\nShip is 12\r\nBoiler is 9", "category": "Math", "date": "03/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA ship is twice as old as its boiler was when the ship was as old as the boiler is now.\r\nThe sum of their ages is 21. \r\nHow old is the boiler, and how old is the ship?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere is an age difference between the ship and the boiler, lets call it D. It will always be the same\n\r\nSHIP = BOILER + D (1)\r\nThe SHIP = 2 * (what the BOILER was) (2)\r\nBOILER NOW = BOILER's age then + D (3)\r\nSHIP NOW + BOILER NOW = 21 (4)\n\r\nThere are now 4 equations with 4 unknowns which can be solved simultaneously To give :\r\nShip is 12\r\nBoiler is 9\n<|im_start|>answer\nThere is an age difference between the ship and the boiler, lets call it D. It will always be the same\n\r\nSHIP = BOILER + D (1)\r\nThe SHIP = 2 * (what the BOILER was) (2)\r\nBOILER NOW = BOILER's age then + D (3)\r\nSHIP NOW + BOILER NOW = 21 (4)\n\r\nThere are now 4 equations with 4 unknowns which can be solved simultaneously To give :\r\nShip is 12\r\nBoiler is 9\n<|im_end|>" }, { "id": "#655", "title": "Birds and Branches", "fun": 2.4, "difficulty": 1.4, "author": "vikass", "desc": "Some birds have been flying non-stop for two hours. Suddenly, the leader of the group decided that they should all have a rest and it pointed out a tree with bare branches nearby. At first the leader of the birds said that they should be perched on one branch each. By doing so, one of the birds did not have a branch for his own. So, the birds' leader did not like it and said that on each branch there should be two birds perched. In doing so, there was one branch which didn't have any birds on it. How many birds and branches were there?", "hint": "No hint available.", "answer": "4 birds and 3 branches", "category": "Logic", "date": "06/27/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome birds have been flying non-stop for two hours. Suddenly, the leader of the group decided that they should all have a rest and it pointed out a tree with bare branches nearby. At first the leader of the birds said that they should be perched on one branch each. By doing so, one of the birds did not have a branch for his own. So, the birds' leader did not like it and said that on each branch there should be two birds perched. In doing so, there was one branch which didn't have any birds on it. How many birds and branches were there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 birds and 3 branches\n<|im_start|>answer\n4 birds and 3 branches\n<|im_end|>" }, { "id": "#1564", "title": "Taps and Plugs", "fun": 2.4, "difficulty": 2.22, "author": "psychodude57", "desc": "My bath has two taps and a plug hole. The cold tap on its own fills the bath in 15 minutes, the hot one in 6 minutes. The plug hole can drain the bath in 30 minutes with the taps off. How long will the bath take to fill if I leave both taps on with the plug left out?", "hint": "No hint available.", "answer": "5 minutes\n\r\n1/15(Cold) + 1/6(Hot) = 1/x + 1/30\r\nsolve for x. \r\n1/5 = 1/x =======> 5 minutes", "category": "Math", "date": "12/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy bath has two taps and a plug hole. The cold tap on its own fills the bath in 15 minutes, the hot one in 6 minutes. The plug hole can drain the bath in 30 minutes with the taps off. How long will the bath take to fill if I leave both taps on with the plug left out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 minutes\n\r\n1/15(Cold) + 1/6(Hot) = 1/x + 1/30\r\nsolve for x. \r\n1/5 = 1/x =======> 5 minutes\n<|im_start|>answer\n5 minutes\n\r\n1/15(Cold) + 1/6(Hot) = 1/x + 1/30\r\nsolve for x. \r\n1/5 = 1/x =======> 5 minutes\n<|im_end|>" }, { "id": "#24890", "title": "Odd Swimmer", "fun": 2.4, "difficulty": 1.76, "author": "spookyb", "desc": "\"Swimmers, take your mark. Beeep!\" yelled the announcer. Samantha jumped into the water and took off, she dog-paddled, swam a little butterfly, swam a little breaststroke, and even swam some backstroke. When she got out the timer told her she was supposed to be doing a specific stroke, but the DQ judge didn't disqualify her. Why?", "hint": "Think about each individual stroke and their rules.", "answer": "Samantha was supposed to be doing freestyle. The coaches show you one way to do this stroke because it is the fastest way, but you can do whatever you like on freestyle except touch the bottom of the pool, so Samantha didn't get disqualified.", "category": "Logic", "date": "07/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"Swimmers, take your mark. Beeep!\" yelled the announcer. Samantha jumped into the water and took off, she dog-paddled, swam a little butterfly, swam a little breaststroke, and even swam some backstroke. When she got out the timer told her she was supposed to be doing a specific stroke, but the DQ judge didn't disqualify her. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSamantha was supposed to be doing freestyle. The coaches show you one way to do this stroke because it is the fastest way, but you can do whatever you like on freestyle except touch the bottom of the pool, so Samantha didn't get disqualified.\n<|im_start|>answer\nSamantha was supposed to be doing freestyle. The coaches show you one way to do this stroke because it is the fastest way, but you can do whatever you like on freestyle except touch the bottom of the pool, so Samantha didn't get disqualified.\n<|im_end|>" }, { "id": "#3336", "title": "Diamond Theft", "fun": 2.4, "difficulty": 2.37, "author": "204_blaze_41", "desc": "There is a famous diamond displayed in a room that measures 15 meters by 15 meters by 15 meters. The room is made entirely of concrete blocks and the floor is covered with a thick carpet. The only thing in the room is the diamond that is housed under a glass cube. The glass cube stands on a one-meter pedestal in the centre of the room. Alarm wires spaced eight centimetres apart and running parallel to each other lie under the carpet. The alarm will trigger if more than four kilograms of pressure is applied to any individual wire. Will Carlo who weighs 74 kilograms was able to steal the famous diamond using the following equipment: a five meter 2 x 4 board, four leather straps (each two meters long and five cm wide), a hammer, and a saw. How could he do it without triggering the alarm?", "hint": "No hint available.", "answer": "Will Carlo stole the diamond in the following manner: First, he cut five meter 2 x 4 boards in half. Then using the available straps, he fastened the two boards to his feet like skies. With the boards strapped to his feet, his weight was displacing enough so that he did not exceed the wire's weight tolerance and triggers the alarm. Carlo then slowly and carefully walked to the centre of the room, smashed the glass cube with the hammer, took the diamond and returned the same way he came in.", "category": "Logic", "date": "04/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a famous diamond displayed in a room that measures 15 meters by 15 meters by 15 meters. The room is made entirely of concrete blocks and the floor is covered with a thick carpet. The only thing in the room is the diamond that is housed under a glass cube. The glass cube stands on a one-meter pedestal in the centre of the room. Alarm wires spaced eight centimetres apart and running parallel to each other lie under the carpet. The alarm will trigger if more than four kilograms of pressure is applied to any individual wire. Will Carlo who weighs 74 kilograms was able to steal the famous diamond using the following equipment: a five meter 2 x 4 board, four leather straps (each two meters long and five cm wide), a hammer, and a saw. How could he do it without triggering the alarm?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWill Carlo stole the diamond in the following manner: First, he cut five meter 2 x 4 boards in half. Then using the available straps, he fastened the two boards to his feet like skies. With the boards strapped to his feet, his weight was displacing enough so that he did not exceed the wire's weight tolerance and triggers the alarm. Carlo then slowly and carefully walked to the centre of the room, smashed the glass cube with the hammer, took the diamond and returned the same way he came in.\n<|im_start|>answer\nWill Carlo stole the diamond in the following manner: First, he cut five meter 2 x 4 boards in half. Then using the available straps, he fastened the two boards to his feet like skies. With the boards strapped to his feet, his weight was displacing enough so that he did not exceed the wire's weight tolerance and triggers the alarm. Carlo then slowly and carefully walked to the centre of the room, smashed the glass cube with the hammer, took the diamond and returned the same way he came in.\n<|im_end|>" }, { "id": "#3732", "title": "Bags of Kittens", "fun": 2.4, "difficulty": 1.65, "author": "watupchicks", "desc": "Six men have 6 bags each. In every bag there are 6 cats, each cat has 6 kittens. How many legs in all?", "hint": "No hint available.", "answer": "6,060 \r\nHere is how you get the answer:\r\nYou go 6*2 for the mens legs, so that is 12. Put that number off to the side.\n\r\nThen you go 6*6 for the bags so that is 36. You go 36*6 for the number of cats and that is 216. You then take 216*4 for the legs, and then you should get 864 (now put that number off to the side).\n\r\nYou now take 216*6 (1296) for the number of kittens and then 1296*4 and you should get 5,184 for the kittens legs (keep that number) because you already multiplied the legs together you don't have to do it again.\n\r\nNow here is how you get 6,060:\r\n5,184 + 864 + 12 = 6,060\n\r\nDid you get it yet?", "category": "Math", "date": "04/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix men have 6 bags each. In every bag there are 6 cats, each cat has 6 kittens. How many legs in all?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6,060 \r\nHere is how you get the answer:\r\nYou go 6*2 for the mens legs, so that is 12. Put that number off to the side.\n\r\nThen you go 6*6 for the bags so that is 36. You go 36*6 for the number of cats and that is 216. You then take 216*4 for the legs, and then you should get 864 (now put that number off to the side).\n\r\nYou now take 216*6 (1296) for the number of kittens and then 1296*4 and you should get 5,184 for the kittens legs (keep that number) because you already multiplied the legs together you don't have to do it again.\n\r\nNow here is how you get 6,060:\r\n5,184 + 864 + 12 = 6,060\n\r\nDid you get it yet?\n<|im_start|>answer\n6,060 \r\nHere is how you get the answer:\r\nYou go 6*2 for the mens legs, so that is 12. Put that number off to the side.\n\r\nThen you go 6*6 for the bags so that is 36. You go 36*6 for the number of cats and that is 216. You then take 216*4 for the legs, and then you should get 864 (now put that number off to the side).\n\r\nYou now take 216*6 (1296) for the number of kittens and then 1296*4 and you should get 5,184 for the kittens legs (keep that number) because you already multiplied the legs together you don't have to do it again.\n\r\nNow here is how you get 6,060:\r\n5,184 + 864 + 12 = 6,060\n\r\nDid you get it yet?\n<|im_end|>" }, { "id": "#24116", "title": "Paintballing Weekend", "fun": 2.4, "difficulty": 0.71, "author": "katey", "desc": "During a crazy weekend of paintball, four friends were having great fun. The paint came in blue, green, yellow and red. Coincidentally, the four friends had T-shirts in those same colours. \n\r\nBrenda used blue paint balls. \r\nThe person in the green T-shirt used yellow paint balls. \r\nJames was not wearing a red T-shirt. \r\nDiane used green paint balls and wore a blue T-shirt. \r\nSimon was the only person who used paint which was the same colour as his T-shirt. \n\r\nCan you tell which colour paint they each used and the colour of their respective T-shirts?", "hint": "No hint available.", "answer": "Name, Wore, Paint\r\nSimon, red, red\r\nBrenda, yellow, blue\r\nJames, green, yellow\r\nDiane, blue, green", "category": "Logic-Grid", "date": "06/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a crazy weekend of paintball, four friends were having great fun. The paint came in blue, green, yellow and red. Coincidentally, the four friends had T-shirts in those same colours. \n\r\nBrenda used blue paint balls. \r\nThe person in the green T-shirt used yellow paint balls. \r\nJames was not wearing a red T-shirt. \r\nDiane used green paint balls and wore a blue T-shirt. \r\nSimon was the only person who used paint which was the same colour as his T-shirt. \n\r\nCan you tell which colour paint they each used and the colour of their respective T-shirts?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName, Wore, Paint\r\nSimon, red, red\r\nBrenda, yellow, blue\r\nJames, green, yellow\r\nDiane, blue, green\n<|im_start|>answer\nName, Wore, Paint\r\nSimon, red, red\r\nBrenda, yellow, blue\r\nJames, green, yellow\r\nDiane, blue, green\n<|im_end|>" }, { "id": "#5320", "title": "Steps", "fun": 2.4, "difficulty": 2.16, "author": "glennyboy02", "desc": "Glenn's step is 4 fifths of that of his father's and he walks 30 steps in a minute.\r\nGlenn's sister, Melanie has a step which is 3 quarters of Glenn's and walks 25 steps in a minute. \r\nGlenn's mother has a step which is twice the size of Melanie's and walks 20 steps in a minute, but gets tired very quickly and every 200 steps stops for a 3 minute rest.\r\nGlenn's Grandma and Grandpa have a step which is one eighth shorter than Glenn's step but walk 40 steps in a minute! While Glenn's Auntie and Uncle have a step that is one fifth larger than Glenn's father but only walk 15 steps in a minute.\r\nGlenn's father's step is exactly 1 metre and he walks 27 steps in a minute.\n\r\nGlenn's whole family go on a scenic bushwalk through Wakiri National Park, the walk is exactly 3 kilometres long. Who will finish the walk first and how long will it take? Who will finish the walk last and how long will it take them?", "hint": "100 cm in a metre.\r\n1000 metres in a km.", "answer": "Glenn's Grandma and Grandpa will finish the walk first and it will take them 107 minutes. Glenn's sister Melanie, will finish the walk last and it will take her 200 minutes.\n\r\nHow to do it:\n\r\nFind the length of everyone's step by using the length of Glenn's father's step multiply this number by the amount of steps they do in a minute and divide by 300000. Convert everything to cm.\n\r\nGlenn = 80 x 30 divided by 300000cm = 125 min\r\nMelanie = 60 x 25 divided by 300000cm = 200 min\r\nGrandparents = 70 x 40 divided by 300000cm = 107 min\r\nAunt & Uncle = 120 x 15 divided by 300000cm = 167 min\r\nMother = 120 x 20 divided by 300000cm = 125 min + 12 x 3 = 161 min\r\nFather = 100x 27 divided by 300000cm = 111 min.", "category": "Math", "date": "07/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGlenn's step is 4 fifths of that of his father's and he walks 30 steps in a minute.\r\nGlenn's sister, Melanie has a step which is 3 quarters of Glenn's and walks 25 steps in a minute. \r\nGlenn's mother has a step which is twice the size of Melanie's and walks 20 steps in a minute, but gets tired very quickly and every 200 steps stops for a 3 minute rest.\r\nGlenn's Grandma and Grandpa have a step which is one eighth shorter than Glenn's step but walk 40 steps in a minute! While Glenn's Auntie and Uncle have a step that is one fifth larger than Glenn's father but only walk 15 steps in a minute.\r\nGlenn's father's step is exactly 1 metre and he walks 27 steps in a minute.\n\r\nGlenn's whole family go on a scenic bushwalk through Wakiri National Park, the walk is exactly 3 kilometres long. Who will finish the walk first and how long will it take? Who will finish the walk last and how long will it take them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGlenn's Grandma and Grandpa will finish the walk first and it will take them 107 minutes. Glenn's sister Melanie, will finish the walk last and it will take her 200 minutes.\n\r\nHow to do it:\n\r\nFind the length of everyone's step by using the length of Glenn's father's step multiply this number by the amount of steps they do in a minute and divide by 300000. Convert everything to cm.\n\r\nGlenn = 80 x 30 divided by 300000cm = 125 min\r\nMelanie = 60 x 25 divided by 300000cm = 200 min\r\nGrandparents = 70 x 40 divided by 300000cm = 107 min\r\nAunt & Uncle = 120 x 15 divided by 300000cm = 167 min\r\nMother = 120 x 20 divided by 300000cm = 125 min + 12 x 3 = 161 min\r\nFather = 100x 27 divided by 300000cm = 111 min.\n<|im_start|>answer\nGlenn's Grandma and Grandpa will finish the walk first and it will take them 107 minutes. Glenn's sister Melanie, will finish the walk last and it will take her 200 minutes.\n\r\nHow to do it:\n\r\nFind the length of everyone's step by using the length of Glenn's father's step multiply this number by the amount of steps they do in a minute and divide by 300000. Convert everything to cm.\n\r\nGlenn = 80 x 30 divided by 300000cm = 125 min\r\nMelanie = 60 x 25 divided by 300000cm = 200 min\r\nGrandparents = 70 x 40 divided by 300000cm = 107 min\r\nAunt & Uncle = 120 x 15 divided by 300000cm = 167 min\r\nMother = 120 x 20 divided by 300000cm = 125 min + 12 x 3 = 161 min\r\nFather = 100x 27 divided by 300000cm = 111 min.\n<|im_end|>" }, { "id": "#34013", "title": "Stone Bridge Crossing", "fun": 2.4, "difficulty": 2.05, "author": "dishu", "desc": "Three people, Ann, Ben and Jen want to cross a river from left bank to right bank. Another three people, Tim, Jim and Kim want to cross the same river from right bank to left bank.\n\r\nHowever, there is no boat but only 1 stone bridge consisting of just 7 big stones(not tied to each other), each of which can hold only 1 person at a time. All these people have a limited jumping capacity, so that they can only jump to the stone immediately next to them if it is empty. \n\r\nNow, all of these people are quite arrogant and so will never turn back once they have begun their journey. That is, they can only move forward in the direction of their destination. They are also quite selfish and will not help anybody travelling in the same direction as themselves. \n\r\nBut they are also practical and know that they will not be able to cross without helping each other. Each of them is willing to help a person coming from opposite direction so that they can get a path for their own journey ahead. With this help, a person can jump two stones at a time, such that if, say, Ann and Tim are occupying two adjacent stones and the stone next to Tim on the other side is empty, then Tim will help Ann in directly jumping to that stone, and vice versa. \n\r\nNow initially the 6 people are lined up on the 7 stones from left to right as follows:\n\r\nAnn Ben Jen emp Tim Jim Kim\r\n(where emp stands for empty stone). \n\r\nYour job is to find how they will cross over the stones such that they are finally lined up as follows:\n\r\nTim Jim Kim emp Ann Ben Jen\n\r\nNow, find out the shortest step-wise procedure, assuming that Tim moves first.", "hint": "15 steps", "answer": "Step 1: Tim jumps to occupy the empty stone.\r\nStep 2: Tim helps Jen in occupying the newly emptied stone between him and Jim.\r\nStep 3: Ben occupies the stone emptied by Jen.\r\nStep 4: Ben helps Tim in occupying the newly emptied stone.\r\nRight now they are lined up like this:\r\nAnn Tim Ben emp Jen Jim Kim\n\r\nStep 5: Jen helps Jim in occupying the empty stone.\r\nStep 6: Kim occupies the stone emptied by Jim.\r\nStep 7: Kim helps Jen in occupying the stone vacated by her.\r\nStep 8: Jim helps Ben in occupying the stone vacated by Jen.\r\nNow the people are lined up as follows:\r\nAnn Tim emp Jim Ben Kim Jen\n\r\nStep 9: Tim helps Ann in occupying the empty stone.\r\nStep 10: Tim jumps to the stone emptied by Ann.\r\nStep 11: Ann helps Jim in occupying the stone vacated by Tim.\r\nStep 12: Ben helps Kim in occupying the stone vacated by Jim.\r\nSo now the people are lined up as follows:\r\nTim Jim Ann Kim Ben emp Jen\n\r\nStep 13: Ben occupies the empty stone.\r\nStep 14: Kim helps Ann in occupying the stone emptied by Ben.\r\nStep 15: Kim jumps to the stone emptied by Ann.\r\nSo finally the people are lined up as:\r\nTim Jim Kim emp Ann Ben Jen\n\r\nJust as we wanted.\n\r\nThere are other possible answers which are permutations of the above procedure by altering certain movements, but this is one of the shortest ways.", "category": "Logic", "date": "11/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people, Ann, Ben and Jen want to cross a river from left bank to right bank. Another three people, Tim, Jim and Kim want to cross the same river from right bank to left bank.\n\r\nHowever, there is no boat but only 1 stone bridge consisting of just 7 big stones(not tied to each other), each of which can hold only 1 person at a time. All these people have a limited jumping capacity, so that they can only jump to the stone immediately next to them if it is empty. \n\r\nNow, all of these people are quite arrogant and so will never turn back once they have begun their journey. That is, they can only move forward in the direction of their destination. They are also quite selfish and will not help anybody travelling in the same direction as themselves. \n\r\nBut they are also practical and know that they will not be able to cross without helping each other. Each of them is willing to help a person coming from opposite direction so that they can get a path for their own journey ahead. With this help, a person can jump two stones at a time, such that if, say, Ann and Tim are occupying two adjacent stones and the stone next to Tim on the other side is empty, then Tim will help Ann in directly jumping to that stone, and vice versa. \n\r\nNow initially the 6 people are lined up on the 7 stones from left to right as follows:\n\r\nAnn Ben Jen emp Tim Jim Kim\r\n(where emp stands for empty stone). \n\r\nYour job is to find how they will cross over the stones such that they are finally lined up as follows:\n\r\nTim Jim Kim emp Ann Ben Jen\n\r\nNow, find out the shortest step-wise procedure, assuming that Tim moves first.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStep 1: Tim jumps to occupy the empty stone.\r\nStep 2: Tim helps Jen in occupying the newly emptied stone between him and Jim.\r\nStep 3: Ben occupies the stone emptied by Jen.\r\nStep 4: Ben helps Tim in occupying the newly emptied stone.\r\nRight now they are lined up like this:\r\nAnn Tim Ben emp Jen Jim Kim\n\r\nStep 5: Jen helps Jim in occupying the empty stone.\r\nStep 6: Kim occupies the stone emptied by Jim.\r\nStep 7: Kim helps Jen in occupying the stone vacated by her.\r\nStep 8: Jim helps Ben in occupying the stone vacated by Jen.\r\nNow the people are lined up as follows:\r\nAnn Tim emp Jim Ben Kim Jen\n\r\nStep 9: Tim helps Ann in occupying the empty stone.\r\nStep 10: Tim jumps to the stone emptied by Ann.\r\nStep 11: Ann helps Jim in occupying the stone vacated by Tim.\r\nStep 12: Ben helps Kim in occupying the stone vacated by Jim.\r\nSo now the people are lined up as follows:\r\nTim Jim Ann Kim Ben emp Jen\n\r\nStep 13: Ben occupies the empty stone.\r\nStep 14: Kim helps Ann in occupying the stone emptied by Ben.\r\nStep 15: Kim jumps to the stone emptied by Ann.\r\nSo finally the people are lined up as:\r\nTim Jim Kim emp Ann Ben Jen\n\r\nJust as we wanted.\n\r\nThere are other possible answers which are permutations of the above procedure by altering certain movements, but this is one of the shortest ways.\n<|im_start|>answer\nStep 1: Tim jumps to occupy the empty stone.\r\nStep 2: Tim helps Jen in occupying the newly emptied stone between him and Jim.\r\nStep 3: Ben occupies the stone emptied by Jen.\r\nStep 4: Ben helps Tim in occupying the newly emptied stone.\r\nRight now they are lined up like this:\r\nAnn Tim Ben emp Jen Jim Kim\n\r\nStep 5: Jen helps Jim in occupying the empty stone.\r\nStep 6: Kim occupies the stone emptied by Jim.\r\nStep 7: Kim helps Jen in occupying the stone vacated by her.\r\nStep 8: Jim helps Ben in occupying the stone vacated by Jen.\r\nNow the people are lined up as follows:\r\nAnn Tim emp Jim Ben Kim Jen\n\r\nStep 9: Tim helps Ann in occupying the empty stone.\r\nStep 10: Tim jumps to the stone emptied by Ann.\r\nStep 11: Ann helps Jim in occupying the stone vacated by Tim.\r\nStep 12: Ben helps Kim in occupying the stone vacated by Jim.\r\nSo now the people are lined up as follows:\r\nTim Jim Ann Kim Ben emp Jen\n\r\nStep 13: Ben occupies the empty stone.\r\nStep 14: Kim helps Ann in occupying the stone emptied by Ben.\r\nStep 15: Kim jumps to the stone emptied by Ann.\r\nSo finally the people are lined up as:\r\nTim Jim Kim emp Ann Ben Jen\n\r\nJust as we wanted.\n\r\nThere are other possible answers which are permutations of the above procedure by altering certain movements, but this is one of the shortest ways.\n<|im_end|>" }, { "id": "#38494", "title": "How Many Students", "fun": 2.4, "difficulty": 1.8800000000000001, "author": "Draw", "desc": "There are several students in the classroom. Some of them have 28 oranges, some have 30, and others have 31. Altogether they have 365 oranges.\n\r\nHow many students are there?", "hint": "If this teaser reminds you of something, please post it in the comments.", "answer": "365=31*11+24=28*13+1, therefore there are 12 or 13 students.\n\r\nBut if there are 13 students, they have at least 28*11+30+31=369 oranges.\n\r\nTherefore, there are 12 students.", "category": "Math", "date": "09/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are several students in the classroom. Some of them have 28 oranges, some have 30, and others have 31. Altogether they have 365 oranges.\n\r\nHow many students are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n365=31*11+24=28*13+1, therefore there are 12 or 13 students.\n\r\nBut if there are 13 students, they have at least 28*11+30+31=369 oranges.\n\r\nTherefore, there are 12 students.\n<|im_start|>answer\n365=31*11+24=28*13+1, therefore there are 12 or 13 students.\n\r\nBut if there are 13 students, they have at least 28*11+30+31=369 oranges.\n\r\nTherefore, there are 12 students.\n<|im_end|>" }, { "id": "#23962", "title": "Pots", "fun": 2.4, "difficulty": 2.29, "author": "horse_luver", "desc": "You have two pots which fit the same lid. The large pot is 12 ounces without the lid. With the lid it weighs twice as much as the small pot on its own. The small pot with the lid is one-third more than the large pot on its own.\n\r\n(1) How much does the lid weigh?\r\n(2) How much does the small pot weigh?", "hint": "No hint available.", "answer": "The lid weighs 6 2/3 ounces and the small pot weighs 9 1/3 ounces.\n\r\nLet us call the large pot P, the small pot p, and the lid L. The equations we are given then translate to:\n\r\n1) P=12\r\n2) P+L=2p\r\n3) p+L=P+P/3\n\r\nCombining the first two equations, we get:\r\n4) 12+L=2p\n\r\nCombining the second two, we get:\r\n5)p+L=12+12/3\r\np+L=16\n\r\nSimplifying equation two, we get:\r\n6) p=P/2 +L/2\r\nAdding L to each side gets:\r\nP/2+L/2+L=p+L\n\r\nCombining this with equation five gets:\r\n7) P/2+L/2+L=P+P 1/3\r\nP/2+L/2+L=16\n\r\nGoing back and adding in equation 1 gets:\r\n8) 12/2+L/2+L=16\r\n6+ L/2+L=16\n\r\nSubtracting 6 from each side gets:\r\n9) L/2+L=10\r\n1.5L=10\n\r\nTo simplify this:\r\n10) L=10/1.5\r\nL=6 2/3\n\r\nTo figure out p is a simpler matter. Combining equations 4 and 10 gets:\r\n11) 12+6 2/3=2p\r\n18 2/3=2p\n\r\nSimplifying this gets:\r\n12) p=18 2/3 / 2\r\np=9 1/3", "category": "Math", "date": "06/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two pots which fit the same lid. The large pot is 12 ounces without the lid. With the lid it weighs twice as much as the small pot on its own. The small pot with the lid is one-third more than the large pot on its own.\n\r\n(1) How much does the lid weigh?\r\n(2) How much does the small pot weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lid weighs 6 2/3 ounces and the small pot weighs 9 1/3 ounces.\n\r\nLet us call the large pot P, the small pot p, and the lid L. The equations we are given then translate to:\n\r\n1) P=12\r\n2) P+L=2p\r\n3) p+L=P+P/3\n\r\nCombining the first two equations, we get:\r\n4) 12+L=2p\n\r\nCombining the second two, we get:\r\n5)p+L=12+12/3\r\np+L=16\n\r\nSimplifying equation two, we get:\r\n6) p=P/2 +L/2\r\nAdding L to each side gets:\r\nP/2+L/2+L=p+L\n\r\nCombining this with equation five gets:\r\n7) P/2+L/2+L=P+P 1/3\r\nP/2+L/2+L=16\n\r\nGoing back and adding in equation 1 gets:\r\n8) 12/2+L/2+L=16\r\n6+ L/2+L=16\n\r\nSubtracting 6 from each side gets:\r\n9) L/2+L=10\r\n1.5L=10\n\r\nTo simplify this:\r\n10) L=10/1.5\r\nL=6 2/3\n\r\nTo figure out p is a simpler matter. Combining equations 4 and 10 gets:\r\n11) 12+6 2/3=2p\r\n18 2/3=2p\n\r\nSimplifying this gets:\r\n12) p=18 2/3 / 2\r\np=9 1/3\n<|im_start|>answer\nThe lid weighs 6 2/3 ounces and the small pot weighs 9 1/3 ounces.\n\r\nLet us call the large pot P, the small pot p, and the lid L. The equations we are given then translate to:\n\r\n1) P=12\r\n2) P+L=2p\r\n3) p+L=P+P/3\n\r\nCombining the first two equations, we get:\r\n4) 12+L=2p\n\r\nCombining the second two, we get:\r\n5)p+L=12+12/3\r\np+L=16\n\r\nSimplifying equation two, we get:\r\n6) p=P/2 +L/2\r\nAdding L to each side gets:\r\nP/2+L/2+L=p+L\n\r\nCombining this with equation five gets:\r\n7) P/2+L/2+L=P+P 1/3\r\nP/2+L/2+L=16\n\r\nGoing back and adding in equation 1 gets:\r\n8) 12/2+L/2+L=16\r\n6+ L/2+L=16\n\r\nSubtracting 6 from each side gets:\r\n9) L/2+L=10\r\n1.5L=10\n\r\nTo simplify this:\r\n10) L=10/1.5\r\nL=6 2/3\n\r\nTo figure out p is a simpler matter. Combining equations 4 and 10 gets:\r\n11) 12+6 2/3=2p\r\n18 2/3=2p\n\r\nSimplifying this gets:\r\n12) p=18 2/3 / 2\r\np=9 1/3\n<|im_end|>" }, { "id": "#47489", "title": "THE GAME OF CHOCOLATES", "fun": 2.4, "difficulty": 0.85, "author": "cutieluck", "desc": "Last vacation, my cousin came over to stay at my home. We made the most of her stay at my place... and I even earned a few chocolates.\n\r\nEvery day, we would play a game of chess. Whoever lost the game owed a chocolate to the other. After the last game we played (that was the day she was to leave), we counted the number of games each of us had won and lost. Wow! I had won more than her. So, she handed me 7 chocolates... though she herself was the winner in 12 games.\n\r\nHow many days did my cousin spend at my place?", "hint": "No hint available.", "answer": "31\n\n\r\nMy cousin won 12 games. Since I got 7 chocolates, I must have won 7 games more than my cousin did. So, I won a total of 19 games. \r\nThus, the total number of games that we played was 31. Since we played a game each day, that was the number of days my cousin stayed at my house!", "category": "Math", "date": "07/13/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast vacation, my cousin came over to stay at my home. We made the most of her stay at my place... and I even earned a few chocolates.\n\r\nEvery day, we would play a game of chess. Whoever lost the game owed a chocolate to the other. After the last game we played (that was the day she was to leave), we counted the number of games each of us had won and lost. Wow! I had won more than her. So, she handed me 7 chocolates... though she herself was the winner in 12 games.\n\r\nHow many days did my cousin spend at my place?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n31\n\n\r\nMy cousin won 12 games. Since I got 7 chocolates, I must have won 7 games more than my cousin did. So, I won a total of 19 games. \r\nThus, the total number of games that we played was 31. Since we played a game each day, that was the number of days my cousin stayed at my house!\n<|im_start|>answer\n31\n\n\r\nMy cousin won 12 games. Since I got 7 chocolates, I must have won 7 games more than my cousin did. So, I won a total of 19 games. \r\nThus, the total number of games that we played was 31. Since we played a game each day, that was the number of days my cousin stayed at my house!\n<|im_end|>" }, { "id": "#37241", "title": "Mixed Awards", "fun": 2.39, "difficulty": 0.7000000000000001, "author": "cookieruler", "desc": "One of the teachers, Mrs. Pillywag, of Gaithersburg High School, is in charge of giving out awards for student accomplishment. The problem is that she doesn't know who is getting what award or what grade they're in. \n\r\nShe knows the names of the students, the possible grades, and what awards there are. The student names are John Smith, Peter Lauer, Lauren Knight, and Kaitlynn Taylor. At the school, the grades are 9th, 10th, 11th, and 12th. Only one student receives an award per grade. The possible awards are Science Excellence, Athlete-Scholar, Artist of the Year, and Principal's Choice Award.\n\r\nShe also knows:\r\n1. Only a 12th Grader can get the Principal's Choice Award.\r\n2. Lauren has won the Artist Award every year she was in high school.\r\n3. The winners in 9th and 12th grade are both boys.\r\n4. The person who won the Athlete-Scholar Award is in 10th Grade.\r\n5. The winner of the Science Excellence award has only been in the school for 1 year.\r\n6. Lauren is in 11th Grade.\r\n7. Kaitlynn is the Athlete-Scholar.\r\n8. Peter won the award that starts with the same letter as his name.", "hint": "No hint available.", "answer": "Peter is in 12th Grade and won the Principal's Choice Award.\n\r\nLauren is in 11th Grade and won the Artist of the Year Award.\n\r\nKaitlynn is in 10th Grade and won the Athlete-Scholar Award.\n\r\nJohn is in 9th Grade and won the Science Excellence Award.", "category": "Logic-Grid", "date": "07/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne of the teachers, Mrs. Pillywag, of Gaithersburg High School, is in charge of giving out awards for student accomplishment. The problem is that she doesn't know who is getting what award or what grade they're in. \n\r\nShe knows the names of the students, the possible grades, and what awards there are. The student names are John Smith, Peter Lauer, Lauren Knight, and Kaitlynn Taylor. At the school, the grades are 9th, 10th, 11th, and 12th. Only one student receives an award per grade. The possible awards are Science Excellence, Athlete-Scholar, Artist of the Year, and Principal's Choice Award.\n\r\nShe also knows:\r\n1. Only a 12th Grader can get the Principal's Choice Award.\r\n2. Lauren has won the Artist Award every year she was in high school.\r\n3. The winners in 9th and 12th grade are both boys.\r\n4. The person who won the Athlete-Scholar Award is in 10th Grade.\r\n5. The winner of the Science Excellence award has only been in the school for 1 year.\r\n6. Lauren is in 11th Grade.\r\n7. Kaitlynn is the Athlete-Scholar.\r\n8. Peter won the award that starts with the same letter as his name.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPeter is in 12th Grade and won the Principal's Choice Award.\n\r\nLauren is in 11th Grade and won the Artist of the Year Award.\n\r\nKaitlynn is in 10th Grade and won the Athlete-Scholar Award.\n\r\nJohn is in 9th Grade and won the Science Excellence Award.\n<|im_start|>answer\nPeter is in 12th Grade and won the Principal's Choice Award.\n\r\nLauren is in 11th Grade and won the Artist of the Year Award.\n\r\nKaitlynn is in 10th Grade and won the Athlete-Scholar Award.\n\r\nJohn is in 9th Grade and won the Science Excellence Award.\n<|im_end|>" }, { "id": "#8960", "title": "Stamps", "fun": 2.39, "difficulty": 1.98, "author": "lesternoronha1", "desc": "\"Dad wants one-cent, two-cent, three-cent, five-cent, and ten-cent stamps. He said to get four each of two sorts and three each of the others, but I've forgotten which. He gave me exactly enough to buy them; just these dimes.\" How many stamps of each type does Dad want? A dime is worth ten cents.", "hint": "No hint available.", "answer": "The easy way to solve this is to sell her three each, for 3x(1+2+3+5+10) = 63 cents. Two more stamps must be bought, and they must make seven cents (since 17 is too much), so the fourth stamps are a two and a five.", "category": "Math", "date": "12/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"Dad wants one-cent, two-cent, three-cent, five-cent, and ten-cent stamps. He said to get four each of two sorts and three each of the others, but I've forgotten which. He gave me exactly enough to buy them; just these dimes.\" How many stamps of each type does Dad want? A dime is worth ten cents.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe easy way to solve this is to sell her three each, for 3x(1+2+3+5+10) = 63 cents. Two more stamps must be bought, and they must make seven cents (since 17 is too much), so the fourth stamps are a two and a five.\n<|im_start|>answer\nThe easy way to solve this is to sell her three each, for 3x(1+2+3+5+10) = 63 cents. Two more stamps must be bought, and they must make seven cents (since 17 is too much), so the fourth stamps are a two and a five.\n<|im_end|>" }, { "id": "#44653", "title": "Whats for Breakfast?", "fun": 2.39, "difficulty": 1.22, "author": "whsprec", "desc": "One week a family decided to serve each other breakfast in bed. So Monday through Thursday each member was treated to his or her choice of breakfast. From the clues below match the family member to the breakfast and the day they were served.\n\r\n1-The sister ate on either Wednesday or Thursday.\r\n2-One of the children ate cornflakes, but they did not eat on Tuesday.\r\n3-The member that ate on Monday had neither toast nor pancakes.\r\n4-The mother did not eat the pancakes.\r\n5-A female ate on Wednesday, but she did not eat toast.\r\n6-The person that ate pancakes is not the brother and did not eat on Thursday.\r\n7-The father did not eat on Tuesday and did not have porridge.\r\n8-The brother did not eat on Thursday.", "hint": "No hint available.", "answer": "The brother had cornflakes on Monday\r\nThe mother had porridge on Tuesday\r\nThe sister had pancakes on Wednesday\r\nThe father had toast on Thursday", "category": "Logic-Grid", "date": "06/14/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne week a family decided to serve each other breakfast in bed. So Monday through Thursday each member was treated to his or her choice of breakfast. From the clues below match the family member to the breakfast and the day they were served.\n\r\n1-The sister ate on either Wednesday or Thursday.\r\n2-One of the children ate cornflakes, but they did not eat on Tuesday.\r\n3-The member that ate on Monday had neither toast nor pancakes.\r\n4-The mother did not eat the pancakes.\r\n5-A female ate on Wednesday, but she did not eat toast.\r\n6-The person that ate pancakes is not the brother and did not eat on Thursday.\r\n7-The father did not eat on Tuesday and did not have porridge.\r\n8-The brother did not eat on Thursday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe brother had cornflakes on Monday\r\nThe mother had porridge on Tuesday\r\nThe sister had pancakes on Wednesday\r\nThe father had toast on Thursday\n<|im_start|>answer\nThe brother had cornflakes on Monday\r\nThe mother had porridge on Tuesday\r\nThe sister had pancakes on Wednesday\r\nThe father had toast on Thursday\n<|im_end|>" }, { "id": "#29576", "title": "Red or Blue", "fun": 2.39, "difficulty": 1.23, "author": "jntrcs", "desc": "Was the robber's car red or blue? Read the story to see if you can figure it out: \r\nThe police already knew the getaway car was red or blue. Luckily, Charlie saw the robbery and was able to tell them. Charlie's brother later told some friends what had happened. \"Charlie said the car was blue,\" he said. The problem is that one brother always tells the truth, but we don't know which. The other always tells lies.", "hint": "No hint available.", "answer": "The car was red. If Charlie lied then the brother told the truth it would be red. But if Charlie told the truth and his brother lied it would be red.", "category": "Logic", "date": "04/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWas the robber's car red or blue? Read the story to see if you can figure it out: \r\nThe police already knew the getaway car was red or blue. Luckily, Charlie saw the robbery and was able to tell them. Charlie's brother later told some friends what had happened. \"Charlie said the car was blue,\" he said. The problem is that one brother always tells the truth, but we don't know which. The other always tells lies.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe car was red. If Charlie lied then the brother told the truth it would be red. But if Charlie told the truth and his brother lied it would be red.\n<|im_start|>answer\nThe car was red. If Charlie lied then the brother told the truth it would be red. But if Charlie told the truth and his brother lied it would be red.\n<|im_end|>" }, { "id": "#44108", "title": "Less Than a Google", "fun": 2.39, "difficulty": 2.85, "author": "javaguru", "desc": "Before Google was a company, it was a number. A googol is 10^100: a one followed by a hundred zeros.\n\r\nHow many natural numbers less than a googol are both the square of a square and the cube of a cube?\n\n\r\n(If N is an integer then N^2 is a square and N^3 is a cube.)", "hint": "No hint available.", "answer": "599\n\n\r\nThe square of a square is (N^2)^2 = N^(2*2) = N^4. The cube of a cube is (N^3)^3 = N^(3*3) = N^9. The least common multiple between 4 and 9 is 36, so a number that is a square of a square and a cube of a cube is a number of the form N^36.\n\r\nThe 36th root of a googol is\n\r\n(10^100)^(1/36) = 10^(100/36) = 10^(2.77777...) ~ 599.48\n\r\nso 599 is the largest integer N such that N^36 < 10^100.\n\r\nChecking this finds that\n\r\n599^36 ~ 9.7 x 10^99\r\n600^36 ~ 1.03 x 10^100\n\r\nSince zero is not a natural number, 1^36 = 1 is the first such number and 599^36 is the last, giving 599 numbers.", "category": "Math", "date": "02/16/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBefore Google was a company, it was a number. A googol is 10^100: a one followed by a hundred zeros.\n\r\nHow many natural numbers less than a googol are both the square of a square and the cube of a cube?\n\n\r\n(If N is an integer then N^2 is a square and N^3 is a cube.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n599\n\n\r\nThe square of a square is (N^2)^2 = N^(2*2) = N^4. The cube of a cube is (N^3)^3 = N^(3*3) = N^9. The least common multiple between 4 and 9 is 36, so a number that is a square of a square and a cube of a cube is a number of the form N^36.\n\r\nThe 36th root of a googol is\n\r\n(10^100)^(1/36) = 10^(100/36) = 10^(2.77777...) ~ 599.48\n\r\nso 599 is the largest integer N such that N^36 < 10^100.\n\r\nChecking this finds that\n\r\n599^36 ~ 9.7 x 10^99\r\n600^36 ~ 1.03 x 10^100\n\r\nSince zero is not a natural number, 1^36 = 1 is the first such number and 599^36 is the last, giving 599 numbers.\n<|im_start|>answer\n599\n\n\r\nThe square of a square is (N^2)^2 = N^(2*2) = N^4. The cube of a cube is (N^3)^3 = N^(3*3) = N^9. The least common multiple between 4 and 9 is 36, so a number that is a square of a square and a cube of a cube is a number of the form N^36.\n\r\nThe 36th root of a googol is\n\r\n(10^100)^(1/36) = 10^(100/36) = 10^(2.77777...) ~ 599.48\n\r\nso 599 is the largest integer N such that N^36 < 10^100.\n\r\nChecking this finds that\n\r\n599^36 ~ 9.7 x 10^99\r\n600^36 ~ 1.03 x 10^100\n\r\nSince zero is not a natural number, 1^36 = 1 is the first such number and 599^36 is the last, giving 599 numbers.\n<|im_end|>" }, { "id": "#48280", "title": "Half a Cup", "fun": 2.39, "difficulty": 0.96, "author": "Scorefire", "desc": "You are making a certain type of cake that requires half a cup of water. Unfortunately, you only have one that fills up to 1 cup, and another that fills up to 3 quarters of a cup. How can you measure half a cup?", "hint": "If you fill 1 cup of water and you pour 3 quarters of a cup to fill the other cup, how much water remains in the larger cup?", "answer": "Fill 1 cup of water, then pour it into the other cup so that a quarter of water remains in the larger cup. Then, empty the 3 quarter cup and pour the 1 quarter that is in the other cup into the 3 quarter cup. Fill 1 cup of water again, and pour the water into the 3 quarter cup until full, and you should have half a cup of water in the larger cup.", "category": "Logic", "date": "12/10/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are making a certain type of cake that requires half a cup of water. Unfortunately, you only have one that fills up to 1 cup, and another that fills up to 3 quarters of a cup. How can you measure half a cup?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFill 1 cup of water, then pour it into the other cup so that a quarter of water remains in the larger cup. Then, empty the 3 quarter cup and pour the 1 quarter that is in the other cup into the 3 quarter cup. Fill 1 cup of water again, and pour the water into the 3 quarter cup until full, and you should have half a cup of water in the larger cup.\n<|im_start|>answer\nFill 1 cup of water, then pour it into the other cup so that a quarter of water remains in the larger cup. Then, empty the 3 quarter cup and pour the 1 quarter that is in the other cup into the 3 quarter cup. Fill 1 cup of water again, and pour the water into the 3 quarter cup until full, and you should have half a cup of water in the larger cup.\n<|im_end|>" }, { "id": "#23345", "title": "Happy Birthday Jenny", "fun": 2.39, "difficulty": 3.07, "author": "cinnamon30", "desc": "Jenny was four years old last week, and her parents threw her an extravagant birthday party. They hired five people to entertain, each in a different way and each for a different price ($50, $75, $100, $125, or $150). Determine the order in which the five entertainers performed, what each person did and his or her charge.\n\r\n1. The entertainer who charged $125 and the entertainer who performed just after Kelly are, in some order, the puppeteer and a person who charged less than the person who sang the children's song.\r\n2. The clown performed sometime after Wyatt and sometime before the person who charged $75.\r\n3. Louis didn't charge $150.\r\n4. The five entertainers were: Wyatt, the acrobat, the second entertainer, the person who performed just before Kelly, and the person who charged $25 more than the magician.\r\n5. Noreen performed either just before or just after a person who charged less than Louis.\r\n6. Kelly charged $25 more than the acrobat.\r\n7. Alicia isn't the children's singer.", "hint": "No hint available.", "answer": "1st - Noreen, singer, $150\r\n2nd - Kelly, magician, $100\r\n3rd - Wyatt, puppeteer, $50\r\n4th - Louis, clown, $125\r\n5th - Alicia, acrobat, $75\n\r\nKelly didn't perform fifth - clue 1, or perform first - clue 4. If she performed 3rd, the 2nd performer would be listed twice in clue 4. Thus , Kelly was second or fourth. Suppose she was fourth. She isn't the acrobat, clue 6, so of the people listed in clue 4, Kelly would be the one who was paid $25 more than the magician. However, Kelly was paid $25 more than the acrobat - clue 6, so the acrobat and the magician would have charged the same amount. Therefore, Kelly was the second performer. Wyatt didn't perform 4th or 5th - clue 2. He wasn't before Kelly - clue 4, so he wasn't first; he performed 3rd. The clown came on fourth, and the person who charged $75 was 5th - clue 2. By elimination, the 5th person was 1st to perform. Of the people mentioned in clue 4, the clown is the one who charged $25 more than the magician. By elimination in clue 4, the acrobat performed 5th. Kelly charged $100 - clue 6. Wyatt performed just after Kelly (see above), so he is either the puppeteer or charged less than the singer - clue 1; in neither case is he the singer. He didn't charge $125 - clue 1. The clown didn't charge $50 (see above), so he charged either $125 or $150. Thus the magician charged $100 or $125 (see above). In neither case is Wyatt the magician (see above), so he's the puppeteer. The singer charged more than $125 - clue 1, so he or she charged $150. Therefore, Kelly isn't the singer, she's the magician. By elimination, the singer performed 1st and charged $150 (see above). The singer is neither Alicia - clue 7, nor Louis - clue 3, she's Noreen. The clown charged $125 (clue 4 and above). By elimination, Wyatt charged $50. Kelly charged less than Louis - clue 5, so Louis charged $125. By elimination, Alicia is the acrobat.", "category": "Logic-Grid", "date": "06/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJenny was four years old last week, and her parents threw her an extravagant birthday party. They hired five people to entertain, each in a different way and each for a different price ($50, $75, $100, $125, or $150). Determine the order in which the five entertainers performed, what each person did and his or her charge.\n\r\n1. The entertainer who charged $125 and the entertainer who performed just after Kelly are, in some order, the puppeteer and a person who charged less than the person who sang the children's song.\r\n2. The clown performed sometime after Wyatt and sometime before the person who charged $75.\r\n3. Louis didn't charge $150.\r\n4. The five entertainers were: Wyatt, the acrobat, the second entertainer, the person who performed just before Kelly, and the person who charged $25 more than the magician.\r\n5. Noreen performed either just before or just after a person who charged less than Louis.\r\n6. Kelly charged $25 more than the acrobat.\r\n7. Alicia isn't the children's singer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st - Noreen, singer, $150\r\n2nd - Kelly, magician, $100\r\n3rd - Wyatt, puppeteer, $50\r\n4th - Louis, clown, $125\r\n5th - Alicia, acrobat, $75\n\r\nKelly didn't perform fifth - clue 1, or perform first - clue 4. If she performed 3rd, the 2nd performer would be listed twice in clue 4. Thus , Kelly was second or fourth. Suppose she was fourth. She isn't the acrobat, clue 6, so of the people listed in clue 4, Kelly would be the one who was paid $25 more than the magician. However, Kelly was paid $25 more than the acrobat - clue 6, so the acrobat and the magician would have charged the same amount. Therefore, Kelly was the second performer. Wyatt didn't perform 4th or 5th - clue 2. He wasn't before Kelly - clue 4, so he wasn't first; he performed 3rd. The clown came on fourth, and the person who charged $75 was 5th - clue 2. By elimination, the 5th person was 1st to perform. Of the people mentioned in clue 4, the clown is the one who charged $25 more than the magician. By elimination in clue 4, the acrobat performed 5th. Kelly charged $100 - clue 6. Wyatt performed just after Kelly (see above), so he is either the puppeteer or charged less than the singer - clue 1; in neither case is he the singer. He didn't charge $125 - clue 1. The clown didn't charge $50 (see above), so he charged either $125 or $150. Thus the magician charged $100 or $125 (see above). In neither case is Wyatt the magician (see above), so he's the puppeteer. The singer charged more than $125 - clue 1, so he or she charged $150. Therefore, Kelly isn't the singer, she's the magician. By elimination, the singer performed 1st and charged $150 (see above). The singer is neither Alicia - clue 7, nor Louis - clue 3, she's Noreen. The clown charged $125 (clue 4 and above). By elimination, Wyatt charged $50. Kelly charged less than Louis - clue 5, so Louis charged $125. By elimination, Alicia is the acrobat.\n<|im_start|>answer\n1st - Noreen, singer, $150\r\n2nd - Kelly, magician, $100\r\n3rd - Wyatt, puppeteer, $50\r\n4th - Louis, clown, $125\r\n5th - Alicia, acrobat, $75\n\r\nKelly didn't perform fifth - clue 1, or perform first - clue 4. If she performed 3rd, the 2nd performer would be listed twice in clue 4. Thus , Kelly was second or fourth. Suppose she was fourth. She isn't the acrobat, clue 6, so of the people listed in clue 4, Kelly would be the one who was paid $25 more than the magician. However, Kelly was paid $25 more than the acrobat - clue 6, so the acrobat and the magician would have charged the same amount. Therefore, Kelly was the second performer. Wyatt didn't perform 4th or 5th - clue 2. He wasn't before Kelly - clue 4, so he wasn't first; he performed 3rd. The clown came on fourth, and the person who charged $75 was 5th - clue 2. By elimination, the 5th person was 1st to perform. Of the people mentioned in clue 4, the clown is the one who charged $25 more than the magician. By elimination in clue 4, the acrobat performed 5th. Kelly charged $100 - clue 6. Wyatt performed just after Kelly (see above), so he is either the puppeteer or charged less than the singer - clue 1; in neither case is he the singer. He didn't charge $125 - clue 1. The clown didn't charge $50 (see above), so he charged either $125 or $150. Thus the magician charged $100 or $125 (see above). In neither case is Wyatt the magician (see above), so he's the puppeteer. The singer charged more than $125 - clue 1, so he or she charged $150. Therefore, Kelly isn't the singer, she's the magician. By elimination, the singer performed 1st and charged $150 (see above). The singer is neither Alicia - clue 7, nor Louis - clue 3, she's Noreen. The clown charged $125 (clue 4 and above). By elimination, Wyatt charged $50. Kelly charged less than Louis - clue 5, so Louis charged $125. By elimination, Alicia is the acrobat.\n<|im_end|>" }, { "id": "#49137", "title": "Wine Money", "fun": 2.39, "difficulty": 2.11, "author": "rob77", "desc": "A French couple celebrates their 50th anniversary with a trip to Florida. One night they buy a bottle of wine that, even by French standards, is premium. They buy it with 130 Euros, and the exchange rate that day is 1.35 dollars per Euro. The restaurant charges a 3 percentage-point premium to exchange currencies. The wine was priced at $171.22 American, and the couple got five American coins back as change. Which five coins did they get?", "hint": "There are three types of coins.", "answer": "They got one quarter, one dime, and three pennies. With a 1.35 exchange rate, after the three percentage-point premium they get 1.32 dollars per Euro. Paying 130 Euros*1.32 is $171.60 American dollars. The price is $171.22, for a difference of 38 cents. The only way to give that change with five coins is one quarter, one dime, and three pennies.", "category": "Math", "date": "11/20/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA French couple celebrates their 50th anniversary with a trip to Florida. One night they buy a bottle of wine that, even by French standards, is premium. They buy it with 130 Euros, and the exchange rate that day is 1.35 dollars per Euro. The restaurant charges a 3 percentage-point premium to exchange currencies. The wine was priced at $171.22 American, and the couple got five American coins back as change. Which five coins did they get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey got one quarter, one dime, and three pennies. With a 1.35 exchange rate, after the three percentage-point premium they get 1.32 dollars per Euro. Paying 130 Euros*1.32 is $171.60 American dollars. The price is $171.22, for a difference of 38 cents. The only way to give that change with five coins is one quarter, one dime, and three pennies.\n<|im_start|>answer\nThey got one quarter, one dime, and three pennies. With a 1.35 exchange rate, after the three percentage-point premium they get 1.32 dollars per Euro. Paying 130 Euros*1.32 is $171.60 American dollars. The price is $171.22, for a difference of 38 cents. The only way to give that change with five coins is one quarter, one dime, and three pennies.\n<|im_end|>" }, { "id": "#24286", "title": "Grandma?", "fun": 2.39, "difficulty": 1.73, "author": "drift15", "desc": "There was a rich man who was in love with a greedy lady who only wanted his money. \r\nOne day, the lady said to the rich man, \"Let's live happily till we're old. I'll be the grandmother of your grandchildren!\" \r\nThe rich man promised a great amount of money if she was true to her word just to make sure. \r\nFifty years later, the greedy lady received the promised great amount of money from the man. \r\nHowever, they were not married, nor did the lady ever bear him any children. \r\nHow is this possible?", "hint": "No hint available.", "answer": "Everyone has two grandmothers. The lady married another man whose child married the child of the rich man. Thus, they shared grandchildren.", "category": "Logic", "date": "07/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a rich man who was in love with a greedy lady who only wanted his money. \r\nOne day, the lady said to the rich man, \"Let's live happily till we're old. I'll be the grandmother of your grandchildren!\" \r\nThe rich man promised a great amount of money if she was true to her word just to make sure. \r\nFifty years later, the greedy lady received the promised great amount of money from the man. \r\nHowever, they were not married, nor did the lady ever bear him any children. \r\nHow is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEveryone has two grandmothers. The lady married another man whose child married the child of the rich man. Thus, they shared grandchildren.\n<|im_start|>answer\nEveryone has two grandmothers. The lady married another man whose child married the child of the rich man. Thus, they shared grandchildren.\n<|im_end|>" }, { "id": "#37066", "title": "Bridge Builders", "fun": 2.39, "difficulty": 2.82, "author": "dunchen22", "desc": "There was a new and very popular Emperor in a small country in the Pacific Ocean. The country consisted of two small islands 3 miles apart. The only way to get to the other island was an old, small ferry boat. The new Emperor was very progressive and wanted to shape up the community to attract tourists and hopefully new residents to stop the population from shrinking. \n\r\nHe decided to connect the islands by a new bridge. Everyone knew the job would be difficult and dangerous, and when he put out the word only two companies were even willing to attempt it.\n\r\nCompany A was the first to offer and said they could do it for $800,000. When the Emperor told the contractor of Company B what Company A offered, the contractor of Company B said they could not do it for less than $1,000,000. The Emperor took a while to think it over. Contractor B, being very smart and confident, came back to the Emperor and said, \"Sir, I will give you an offer you cannot refuse. The decision is completely up to you in the end, but you can pay me $200,000, $750,000, or $1,000,000 for the job.\" Contractor B proceeded with his details and the Emperor immediately accepted his offer. Company B ended up being paid $1,000,000 for the job. Contractor B did not lie, cheat, or swindle the Emperor in any way. He is a very honest businessman.\n\r\nWhy did Company B's offer sound so good to the Emperor, and more importantly, how did Company B end up with the highest amount?", "hint": "2 Hints: \r\n1. Company A is part of Company B's idea.\n\n\n\n\n\n\n\r\n2. Use your math and accounting skills", "answer": "Contractor B was very confident in his company's excellent work. It was high quality work so could not lower the full price to under $1,000,000. He suggested to the Emperor that each company start building from opposite ends and each complete a quarter of the bridge. The emperor could then examine the 2 quarters and make his decision on which company would complete the job, based off of quality. \n\r\nEach company would be paid $200,000 for their quarter, that way if Company A won, the emperor would still only be paying $800,000 ($400,000 more to Company A for the rest of the bridge). If Company B won, Contractor B argued, it would be because they were obviously superior in bridge building and thus worthy of the extra money. The Emperor would still only be paying $950,000 that way anyway, which is still cheaper than Company B's full offer, while Company B would still get paid their full ¾ pay for ¾ of a bridge ($750,000).\n\r\nWhen Company A heard this offer, they knew they were beat because they knew their bridge-building skills were far inferior. They figured it was not worth the $200,000 to start even building since it was so dangerous and immediately backed out, forcing the Emperor to pay Company B their full asking price of $1,000,000.", "category": "Logic", "date": "06/25/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a new and very popular Emperor in a small country in the Pacific Ocean. The country consisted of two small islands 3 miles apart. The only way to get to the other island was an old, small ferry boat. The new Emperor was very progressive and wanted to shape up the community to attract tourists and hopefully new residents to stop the population from shrinking. \n\r\nHe decided to connect the islands by a new bridge. Everyone knew the job would be difficult and dangerous, and when he put out the word only two companies were even willing to attempt it.\n\r\nCompany A was the first to offer and said they could do it for $800,000. When the Emperor told the contractor of Company B what Company A offered, the contractor of Company B said they could not do it for less than $1,000,000. The Emperor took a while to think it over. Contractor B, being very smart and confident, came back to the Emperor and said, \"Sir, I will give you an offer you cannot refuse. The decision is completely up to you in the end, but you can pay me $200,000, $750,000, or $1,000,000 for the job.\" Contractor B proceeded with his details and the Emperor immediately accepted his offer. Company B ended up being paid $1,000,000 for the job. Contractor B did not lie, cheat, or swindle the Emperor in any way. He is a very honest businessman.\n\r\nWhy did Company B's offer sound so good to the Emperor, and more importantly, how did Company B end up with the highest amount?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nContractor B was very confident in his company's excellent work. It was high quality work so could not lower the full price to under $1,000,000. He suggested to the Emperor that each company start building from opposite ends and each complete a quarter of the bridge. The emperor could then examine the 2 quarters and make his decision on which company would complete the job, based off of quality. \n\r\nEach company would be paid $200,000 for their quarter, that way if Company A won, the emperor would still only be paying $800,000 ($400,000 more to Company A for the rest of the bridge). If Company B won, Contractor B argued, it would be because they were obviously superior in bridge building and thus worthy of the extra money. The Emperor would still only be paying $950,000 that way anyway, which is still cheaper than Company B's full offer, while Company B would still get paid their full ¾ pay for ¾ of a bridge ($750,000).\n\r\nWhen Company A heard this offer, they knew they were beat because they knew their bridge-building skills were far inferior. They figured it was not worth the $200,000 to start even building since it was so dangerous and immediately backed out, forcing the Emperor to pay Company B their full asking price of $1,000,000.\n<|im_start|>answer\nContractor B was very confident in his company's excellent work. It was high quality work so could not lower the full price to under $1,000,000. He suggested to the Emperor that each company start building from opposite ends and each complete a quarter of the bridge. The emperor could then examine the 2 quarters and make his decision on which company would complete the job, based off of quality. \n\r\nEach company would be paid $200,000 for their quarter, that way if Company A won, the emperor would still only be paying $800,000 ($400,000 more to Company A for the rest of the bridge). If Company B won, Contractor B argued, it would be because they were obviously superior in bridge building and thus worthy of the extra money. The Emperor would still only be paying $950,000 that way anyway, which is still cheaper than Company B's full offer, while Company B would still get paid their full ¾ pay for ¾ of a bridge ($750,000).\n\r\nWhen Company A heard this offer, they knew they were beat because they knew their bridge-building skills were far inferior. They figured it was not worth the $200,000 to start even building since it was so dangerous and immediately backed out, forcing the Emperor to pay Company B their full asking price of $1,000,000.\n<|im_end|>" }, { "id": "#29062", "title": "Total 85008", "fun": 2.39, "difficulty": 2.13, "author": "kiss", "desc": "Can you find three consecutive even numbers that total 85008 when multiplied together?", "hint": "No hint available.", "answer": "42, 44 and 46.\n\r\nSince 4^3=64<85<125=5^3, they must lie between 40 and 50.\n\r\nSince 2*4*6 ends in 8 and 4*6*8 ends in 2, they must be 42, 44 and 46.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you find three consecutive even numbers that total 85008 when multiplied together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n42, 44 and 46.\n\r\nSince 4^3=64<85<125=5^3, they must lie between 40 and 50.\n\r\nSince 2*4*6 ends in 8 and 4*6*8 ends in 2, they must be 42, 44 and 46.\n<|im_start|>answer\n42, 44 and 46.\n\r\nSince 4^3=64<85<125=5^3, they must lie between 40 and 50.\n\r\nSince 2*4*6 ends in 8 and 4*6*8 ends in 2, they must be 42, 44 and 46.\n<|im_end|>" }, { "id": "#41671", "title": "Basketball Game", "fun": 2.39, "difficulty": 1.6, "author": "TRILLIONAIRE", "desc": "At the end of the first half of the basketball game, the Magnets and the Scouts were tied at 24 points. Each team had scored 12 baskets, including at least one each of 1-, 2-, and 3-point baskets. However, the Scouts had made more 3-point baskets than the Magnets. The Magnets had scored an equal number of 1-, 2-, and 3-point baskets.\n\r\nHow many 1-, 2-, and 3-point baskets did each team score?", "hint": "No hint available.", "answer": "The Magnets scored four 1-point baskets, four 2-pointers, and four 3-pointers.\n\r\nThe Scouts scored five 1-point baskets, two 2-pointers, and five 3-pointers.", "category": "Math", "date": "04/24/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the end of the first half of the basketball game, the Magnets and the Scouts were tied at 24 points. Each team had scored 12 baskets, including at least one each of 1-, 2-, and 3-point baskets. However, the Scouts had made more 3-point baskets than the Magnets. The Magnets had scored an equal number of 1-, 2-, and 3-point baskets.\n\r\nHow many 1-, 2-, and 3-point baskets did each team score?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Magnets scored four 1-point baskets, four 2-pointers, and four 3-pointers.\n\r\nThe Scouts scored five 1-point baskets, two 2-pointers, and five 3-pointers.\n<|im_start|>answer\nThe Magnets scored four 1-point baskets, four 2-pointers, and four 3-pointers.\n\r\nThe Scouts scored five 1-point baskets, two 2-pointers, and five 3-pointers.\n<|im_end|>" }, { "id": "#27679", "title": "Divide By 2", "fun": 2.39, "difficulty": 1.97, "author": "smarty008", "desc": "Which number doesn't belong?\n\r\na) 32768\r\nb) 2048\r\nc) 524288\r\nd) 3145728\r\ne) 8192", "hint": "No hint available.", "answer": "d) 3145728\n\r\nAll of the other numbers you can divide by 2 until you get 1.", "category": "Math", "date": "12/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich number doesn't belong?\n\r\na) 32768\r\nb) 2048\r\nc) 524288\r\nd) 3145728\r\ne) 8192\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nd) 3145728\n\r\nAll of the other numbers you can divide by 2 until you get 1.\n<|im_start|>answer\nd) 3145728\n\r\nAll of the other numbers you can divide by 2 until you get 1.\n<|im_end|>" }, { "id": "#8674", "title": "The Married Man", "fun": 2.39, "difficulty": 2.09, "author": "lesternoronha1", "desc": "Lee, Dale and Terry are related to each other.\n\r\n(a) Among the three are Lee's legal spouse, Dale's sibling and Terry's sister-in-law. \r\n(b) Lee's legal spouse and Dale's sibling are of the same sex. \n\r\nWhich one is the married man?", "hint": "No hint available.", "answer": "Dale is the married man.\n\r\nFrom statement (a) there are two possibilities:\n\r\n1) Lee is married to Dale and Terry is Dale's sibling.\r\n2) Lee is married to Terry and Dale is Lee's sibling.\n\r\nStatement (b) rules out (2) above since Lee and Terry (the married couple) would have to be the same sex.\n\r\nSince (1) is true then statement (a) says that Lee is Terry's sister-in-law, making Lee's spouse Dale the married man.", "category": "Logic", "date": "11/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLee, Dale and Terry are related to each other.\n\r\n(a) Among the three are Lee's legal spouse, Dale's sibling and Terry's sister-in-law. \r\n(b) Lee's legal spouse and Dale's sibling are of the same sex. \n\r\nWhich one is the married man?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDale is the married man.\n\r\nFrom statement (a) there are two possibilities:\n\r\n1) Lee is married to Dale and Terry is Dale's sibling.\r\n2) Lee is married to Terry and Dale is Lee's sibling.\n\r\nStatement (b) rules out (2) above since Lee and Terry (the married couple) would have to be the same sex.\n\r\nSince (1) is true then statement (a) says that Lee is Terry's sister-in-law, making Lee's spouse Dale the married man.\n<|im_start|>answer\nDale is the married man.\n\r\nFrom statement (a) there are two possibilities:\n\r\n1) Lee is married to Dale and Terry is Dale's sibling.\r\n2) Lee is married to Terry and Dale is Lee's sibling.\n\r\nStatement (b) rules out (2) above since Lee and Terry (the married couple) would have to be the same sex.\n\r\nSince (1) is true then statement (a) says that Lee is Terry's sister-in-law, making Lee's spouse Dale the married man.\n<|im_end|>" }, { "id": "#42118", "title": "Who's Who at School", "fun": 2.39, "difficulty": 0.9400000000000001, "author": "whsprec", "desc": "At a school, there are students between 1st grade and 12th grade. Tom, Josh, Liza, Bill and Mary all go to the school. In no particular order, they are either in 1st, 2nd, 3rd, 8th, or 10th grade. Each of them is in a different grade level and has a different 1st period class. The 1st period classes offered are Math, German, Science, P.E. and English. Match the student to their 1st period class and their grade.\n\r\n1) Liza and Mary are the oldest.\r\n2) Tom, Josh, and Bill are not taking a language class.\r\n3) Mary is older than the German student, who is older than the P.E. student.\r\n4) The 2nd grader took Tom, who is older than the 2nd grader, his math homework when he was sick.\r\n5) Bill asked the 2nd grader to come to the lab to help finish a project for Bill's science class.", "hint": "No hint available.", "answer": "Tom- Math, 3rd grade\r\nJosh- P.E., 2nd grade\r\nLiza- German, 8th grade\r\nBill- Science, 1st grade\r\nMary- English, 10th grade", "category": "Logic-Grid", "date": "06/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a school, there are students between 1st grade and 12th grade. Tom, Josh, Liza, Bill and Mary all go to the school. In no particular order, they are either in 1st, 2nd, 3rd, 8th, or 10th grade. Each of them is in a different grade level and has a different 1st period class. The 1st period classes offered are Math, German, Science, P.E. and English. Match the student to their 1st period class and their grade.\n\r\n1) Liza and Mary are the oldest.\r\n2) Tom, Josh, and Bill are not taking a language class.\r\n3) Mary is older than the German student, who is older than the P.E. student.\r\n4) The 2nd grader took Tom, who is older than the 2nd grader, his math homework when he was sick.\r\n5) Bill asked the 2nd grader to come to the lab to help finish a project for Bill's science class.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTom- Math, 3rd grade\r\nJosh- P.E., 2nd grade\r\nLiza- German, 8th grade\r\nBill- Science, 1st grade\r\nMary- English, 10th grade\n<|im_start|>answer\nTom- Math, 3rd grade\r\nJosh- P.E., 2nd grade\r\nLiza- German, 8th grade\r\nBill- Science, 1st grade\r\nMary- English, 10th grade\n<|im_end|>" }, { "id": "#33282", "title": "1/29th", "fun": 2.39, "difficulty": 2.31, "author": "lessthanjake789", "desc": "What three digit number is 29 times as large as its last two digits? There is only one answer.", "hint": "Some number ending in X, times 29, equals some number ending in X again.", "answer": "725. 725/25 = 29.", "category": "Math", "date": "10/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat three digit number is 29 times as large as its last two digits? There is only one answer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n725. 725/25 = 29.\n<|im_start|>answer\n725. 725/25 = 29.\n<|im_end|>" }, { "id": "#29317", "title": "Two Cars", "fun": 2.39, "difficulty": 2.81, "author": "BobbyKat", "desc": "Two cars race around a circular track, in opposite directions, at constant rates. They start at the same point and meet every 30 seconds. If they move in the same direction, they meet every 120 seconds. If the track is 1800 meters long, what is the speed of each car?", "hint": "1) \n\r\n Let x = rate of car 1 (m/s)\r\n Let y = rate of car 2 (m/s)\n\r\n 1800m = 30x+30y\r\n 1800-30x = 30y\n\r\n2) Use method of substitution or elimination.", "answer": "Let x = rate of car 1 (m/s)\r\nLet y = rate of car 2 (m/s)\n\r\n(1) 1800m = 30x+30y\r\n1800-30x = 30y\r\n7200-120x = 120y\n\r\n(2) 1800 + 120x = 120y\n\r\nSolve for Car 1: (1)=(2)\r\n7200-120x = 1800+120x\r\n5400 = 240x\r\nx = 22.5 m/s\n\r\nConvert to km/hr\r\nx = 22.5m/sec *60sec/min*60min/hr = 81 km/hr\r\n1000 m/km\n\r\nSolve for Car 2:\r\nSubstitute x = 22.5 m/s\n\r\n1800+120x = 120y\r\ny = 1800+120x\r\n120\n\r\ny = 1800+120(22.5)\r\n120\n\r\ny = 37.5 m/s\n\r\nConvert to km/hr\r\nx =37.5m/sec *60sec/min*60min/hr = 135 km/hr\r\n1000 m/km", "category": "Math", "date": "03/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo cars race around a circular track, in opposite directions, at constant rates. They start at the same point and meet every 30 seconds. If they move in the same direction, they meet every 120 seconds. If the track is 1800 meters long, what is the speed of each car?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet x = rate of car 1 (m/s)\r\nLet y = rate of car 2 (m/s)\n\r\n(1) 1800m = 30x+30y\r\n1800-30x = 30y\r\n7200-120x = 120y\n\r\n(2) 1800 + 120x = 120y\n\r\nSolve for Car 1: (1)=(2)\r\n7200-120x = 1800+120x\r\n5400 = 240x\r\nx = 22.5 m/s\n\r\nConvert to km/hr\r\nx = 22.5m/sec *60sec/min*60min/hr = 81 km/hr\r\n1000 m/km\n\r\nSolve for Car 2:\r\nSubstitute x = 22.5 m/s\n\r\n1800+120x = 120y\r\ny = 1800+120x\r\n120\n\r\ny = 1800+120(22.5)\r\n120\n\r\ny = 37.5 m/s\n\r\nConvert to km/hr\r\nx =37.5m/sec *60sec/min*60min/hr = 135 km/hr\r\n1000 m/km\n<|im_start|>answer\nLet x = rate of car 1 (m/s)\r\nLet y = rate of car 2 (m/s)\n\r\n(1) 1800m = 30x+30y\r\n1800-30x = 30y\r\n7200-120x = 120y\n\r\n(2) 1800 + 120x = 120y\n\r\nSolve for Car 1: (1)=(2)\r\n7200-120x = 1800+120x\r\n5400 = 240x\r\nx = 22.5 m/s\n\r\nConvert to km/hr\r\nx = 22.5m/sec *60sec/min*60min/hr = 81 km/hr\r\n1000 m/km\n\r\nSolve for Car 2:\r\nSubstitute x = 22.5 m/s\n\r\n1800+120x = 120y\r\ny = 1800+120x\r\n120\n\r\ny = 1800+120(22.5)\r\n120\n\r\ny = 37.5 m/s\n\r\nConvert to km/hr\r\nx =37.5m/sec *60sec/min*60min/hr = 135 km/hr\r\n1000 m/km\n<|im_end|>" }, { "id": "#1044", "title": "Teacher's Age", "fun": 2.39, "difficulty": 2.24, "author": "vivek", "desc": "A young man asks his beautiful mathematics teacher her age. She responds, \"Today's date is my age, although before this week is over there will be another day with a date one fifth of the new age that I will be.\" What is the teacher's sign of the zodiac?", "hint": "No hint available.", "answer": "The teacher is a Pisces. This conversation could have only taken place on February 29. She was 29 then. Six days later (March 6), having turned 30, it becomes true that the date is one fifth of her age. This means her birthday occurs during the six first days of March.", "category": "Math", "date": "10/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA young man asks his beautiful mathematics teacher her age. She responds, \"Today's date is my age, although before this week is over there will be another day with a date one fifth of the new age that I will be.\" What is the teacher's sign of the zodiac?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe teacher is a Pisces. This conversation could have only taken place on February 29. She was 29 then. Six days later (March 6), having turned 30, it becomes true that the date is one fifth of her age. This means her birthday occurs during the six first days of March.\n<|im_start|>answer\nThe teacher is a Pisces. This conversation could have only taken place on February 29. She was 29 then. Six days later (March 6), having turned 30, it becomes true that the date is one fifth of her age. This means her birthday occurs during the six first days of March.\n<|im_end|>" }, { "id": "#8843", "title": "Three Surgeons", "fun": 2.39, "difficulty": 2.12, "author": "lesternoronha1", "desc": "How can three surgeons, with open wounds on their hands, operate on a patient with only two surgical gloves so that nobody is directly exposed to anybody else's blood?\n\r\nThey can operate one at a time and can all operate one-handed.", "hint": "No hint available.", "answer": "Call the gloves A and B, and the surgeons 1, 2, and 3. \r\nFirst, surgeon 1 operates with glove A inside glove B. \r\nSecond, take glove A out of glove B. \r\nThird, surgeon 2 operates using glove B. \r\nFourth, turn glove A inside out. \r\nFifth, surgeon 3 operates with glove A inside glove B.", "category": "Logic", "date": "12/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can three surgeons, with open wounds on their hands, operate on a patient with only two surgical gloves so that nobody is directly exposed to anybody else's blood?\n\r\nThey can operate one at a time and can all operate one-handed.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCall the gloves A and B, and the surgeons 1, 2, and 3. \r\nFirst, surgeon 1 operates with glove A inside glove B. \r\nSecond, take glove A out of glove B. \r\nThird, surgeon 2 operates using glove B. \r\nFourth, turn glove A inside out. \r\nFifth, surgeon 3 operates with glove A inside glove B.\n<|im_start|>answer\nCall the gloves A and B, and the surgeons 1, 2, and 3. \r\nFirst, surgeon 1 operates with glove A inside glove B. \r\nSecond, take glove A out of glove B. \r\nThird, surgeon 2 operates using glove B. \r\nFourth, turn glove A inside out. \r\nFifth, surgeon 3 operates with glove A inside glove B.\n<|im_end|>" }, { "id": "#44009", "title": "Rex and Ralph: Polygonal House", "fun": 2.39, "difficulty": 3.18, "author": "javaguru", "desc": "Two mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Ralph has just finished building a custom house and invites Rex to dinner.\n\r\nHe tells Rex, \"The lot my house sits on is a regular polygon. My house is a matching regular polygon sitting on a circular foundation in the middle of the yard. The closest part of the foundation to the edge of my property is exactly the same as the diameter of the foundation. The house is two stories, built around a central circular atrium with a diameter that is exactly one tenth the longest measurement of my property.\"\n\r\n\"Sounds like quite the house!\" remarked Rex.\n\r\n\"Yes, I've been building it for almost two years. When I was excavating the foundation I found a section of an old irrigation pipe. The pipe exactly bisected the area of the house, with each end of the pipe at an edge of the house. After the house was completed while I was preparing to put up a fence around the edge of the property, I discovered that the length of the pipe I found was exactly the length of one side of the property. I used the pipe as a gate across the side of the property with the driveway and built the fence around the other sides. I built a total of 400 feet of fence.\"\n\r\n\"So what's the square footage of my house?\" Ralph asked.\n\r\n\"Are you counting the space occupied by the walls in the square footage?\" asked Rex.\n\r\n\"Yes of course,\" Ralph replied. \"It also includes the stairways, hallways, and basically all of the space inside of the exterior walls.\"\n\r\nRex smiles and says, \"Nice try, Ralph! Assuming the information you gave me is correct, it'll take just a minute or two to calculate it.\"\n\r\nHow did Rex know the square footage, and what was his answer?", "hint": "A regular polygon has the length of all sides and arc of all interior angles equal.\n\r\nThe first thing you need to determine is the number of sides for Ralph's house. The rest solves in a fairly straight-forward manner once this is determined.", "answer": "2,730 sq. feet\n\r\nRex realized that he would need to know the number of sides on Ralph's house in order to make use of the only measurement Ralph gave him, which was the perimeter minus the length of one side for the property. The length of a side of the property needed to be the length of the pipe that bisected the area of the house. The length of the pipe is the key to figuring out how many sides the house has.\n\r\nThe house is a regular polygon inscribed in the circle that is the foundation. Since the closest edge of the property is equal to the diameter of the foundation, then the property must be a similar polygon circumscribed around a circle with a diameter three times the size of the foundation.\n\r\nThe minimum and maximum length line segments that can bisect the area of a regular polygon are calculated differently for even- and odd-sided polygons.\n\r\nFor an even-sided polygon inscribed in a circle of radius r, the maximum line segment has its ends at two opposite vertices and the length is 2r. The minimum line segment goes from the middle of one edge to the middle of the opposite edge. The distance from the edge to the center of a polygon is the apothem, so the minimum line segment is two times the apothem a.\n\r\nFor an odd-sided polygon the maximum bisector goes from a vertex to the middle of the opposite side, so the maximum is r + a. As with an even-sided polygon, the minimum bisector for an odd-sided polygon extends through the center of the polygon and at an angle halfway between two adjacent maximum bisectors.\n\r\n2Pi radians = 360 degrees. The central angle between any two adjacent vertices on a polygon with n sides is then 2Pi/n and the angle between a vertex radius and the apothem is half that or Pi/n. The apothem and the radius form two sides of a right triangle, with the third side formed by one half of the side bisected by the apothem. For a regular polygon with n sides of length s this gives the following relationships:\n\r\na = r*Cos(Pi/n)\r\nr = a/Cos(Pi/n)\r\ns = 2*a*Tan(Pi/n)\n\r\nRex assigns one as the radius of the foundation. This makes the apothem of the property three and the side of the property is:\n\r\n2*3*Tan(Pi/n) = 6*Tan(Pi/n)\n\r\nSo where Min(n) and Max(n) are the minimum and maximum length of a bisector for an n-sided polygon inscribed in a unit circle, Rex needs to find an integer value for n that satisfies the inequality:\n\r\nMax(n) >= 6*Tan(Pi/n) >= Min(n)\n\r\nSince Rex is pretty sure there's only one solution, he figures first he'll just use the minimum and maximum functions for even-sided polygons. The minimum and maximum for odd-sided polygons will be within this range, so he might find an odd-sided polygon that doesn't satisfy the equation, but he won't miss any that do. This gives:\n\r\n2 >= 6*Tan(Pi/n) >= 2*Cos(Pi/n)\n\r\nTaking just the first part of the inequality gives:\n\r\n2 >= 6*Tan(Pi/n)\r\n1/3 >= Tan(Pi/n)\r\natan(1/3) >= Pi/n\r\natan(1/3) / Pi >= 1/n\r\nn >= Pi/atan(1/3)\r\nn >= 9.8\n\r\nHe tries 10 and finds that:\n\r\nMax(10) = 2 >\r\n6*Tan(Pi/10) = 1.95 >\r\nMin(10) = Cos(Pi/10) = 1.90\n\r\nNow Rex knows that Ralph's house has ten sides and is a regular decagon. That makes the length of the pipe and of a side of the larger decagon 400/9 = 44 4/9 = 44.444.. feet. From the equation above:\n\r\n44.444 = 2*a*Tan(Pi/10)\r\na = 44.444 / Tan(Pi/10) ~ 68.393\n\r\nSo the radius of the larger circle is 68.393 feet and the radius of the foundation is 68.393/3 = 22.798, which is also the radius of the house decagon. The apothem and length of a side for the house are:\n\r\na = 22.798 * Cos(Pi/10) = 21.682\r\ns = 2 * 21.682 * Tan(Pi/10) = 14.090\n\r\nThe side and apothem are the base and height of one of the ten triangles formed by two vertex radii and a side. The area of one of these triangles is then\n\r\n14.090 * 21.682 / 2 = 152.75\n\r\nand the area of the decagon is 10 * 152.75 = 1527.5. Now Rex just needs to know the size of the atrium to calculate the square footage of the house. The radius of the atrium is one-tenth the radius of the large decagon, which is\n\r\nr = 68.393 / Cos(Pi/10) = 71.913\n\r\nso the area of the atrium is\n\r\n(71.913 / 10)^2 * Pi = 162.47\n\r\nand the area of the two floors in Ralph's house is\n\r\n(1527.5 - 162.47) * 2 = 2730.0 square feet.", "category": "Math", "date": "01/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Ralph has just finished building a custom house and invites Rex to dinner.\n\r\nHe tells Rex, \"The lot my house sits on is a regular polygon. My house is a matching regular polygon sitting on a circular foundation in the middle of the yard. The closest part of the foundation to the edge of my property is exactly the same as the diameter of the foundation. The house is two stories, built around a central circular atrium with a diameter that is exactly one tenth the longest measurement of my property.\"\n\r\n\"Sounds like quite the house!\" remarked Rex.\n\r\n\"Yes, I've been building it for almost two years. When I was excavating the foundation I found a section of an old irrigation pipe. The pipe exactly bisected the area of the house, with each end of the pipe at an edge of the house. After the house was completed while I was preparing to put up a fence around the edge of the property, I discovered that the length of the pipe I found was exactly the length of one side of the property. I used the pipe as a gate across the side of the property with the driveway and built the fence around the other sides. I built a total of 400 feet of fence.\"\n\r\n\"So what's the square footage of my house?\" Ralph asked.\n\r\n\"Are you counting the space occupied by the walls in the square footage?\" asked Rex.\n\r\n\"Yes of course,\" Ralph replied. \"It also includes the stairways, hallways, and basically all of the space inside of the exterior walls.\"\n\r\nRex smiles and says, \"Nice try, Ralph! Assuming the information you gave me is correct, it'll take just a minute or two to calculate it.\"\n\r\nHow did Rex know the square footage, and what was his answer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2,730 sq. feet\n\r\nRex realized that he would need to know the number of sides on Ralph's house in order to make use of the only measurement Ralph gave him, which was the perimeter minus the length of one side for the property. The length of a side of the property needed to be the length of the pipe that bisected the area of the house. The length of the pipe is the key to figuring out how many sides the house has.\n\r\nThe house is a regular polygon inscribed in the circle that is the foundation. Since the closest edge of the property is equal to the diameter of the foundation, then the property must be a similar polygon circumscribed around a circle with a diameter three times the size of the foundation.\n\r\nThe minimum and maximum length line segments that can bisect the area of a regular polygon are calculated differently for even- and odd-sided polygons.\n\r\nFor an even-sided polygon inscribed in a circle of radius r, the maximum line segment has its ends at two opposite vertices and the length is 2r. The minimum line segment goes from the middle of one edge to the middle of the opposite edge. The distance from the edge to the center of a polygon is the apothem, so the minimum line segment is two times the apothem a.\n\r\nFor an odd-sided polygon the maximum bisector goes from a vertex to the middle of the opposite side, so the maximum is r + a. As with an even-sided polygon, the minimum bisector for an odd-sided polygon extends through the center of the polygon and at an angle halfway between two adjacent maximum bisectors.\n\r\n2Pi radians = 360 degrees. The central angle between any two adjacent vertices on a polygon with n sides is then 2Pi/n and the angle between a vertex radius and the apothem is half that or Pi/n. The apothem and the radius form two sides of a right triangle, with the third side formed by one half of the side bisected by the apothem. For a regular polygon with n sides of length s this gives the following relationships:\n\r\na = r*Cos(Pi/n)\r\nr = a/Cos(Pi/n)\r\ns = 2*a*Tan(Pi/n)\n\r\nRex assigns one as the radius of the foundation. This makes the apothem of the property three and the side of the property is:\n\r\n2*3*Tan(Pi/n) = 6*Tan(Pi/n)\n\r\nSo where Min(n) and Max(n) are the minimum and maximum length of a bisector for an n-sided polygon inscribed in a unit circle, Rex needs to find an integer value for n that satisfies the inequality:\n\r\nMax(n) >= 6*Tan(Pi/n) >= Min(n)\n\r\nSince Rex is pretty sure there's only one solution, he figures first he'll just use the minimum and maximum functions for even-sided polygons. The minimum and maximum for odd-sided polygons will be within this range, so he might find an odd-sided polygon that doesn't satisfy the equation, but he won't miss any that do. This gives:\n\r\n2 >= 6*Tan(Pi/n) >= 2*Cos(Pi/n)\n\r\nTaking just the first part of the inequality gives:\n\r\n2 >= 6*Tan(Pi/n)\r\n1/3 >= Tan(Pi/n)\r\natan(1/3) >= Pi/n\r\natan(1/3) / Pi >= 1/n\r\nn >= Pi/atan(1/3)\r\nn >= 9.8\n\r\nHe tries 10 and finds that:\n\r\nMax(10) = 2 >\r\n6*Tan(Pi/10) = 1.95 >\r\nMin(10) = Cos(Pi/10) = 1.90\n\r\nNow Rex knows that Ralph's house has ten sides and is a regular decagon. That makes the length of the pipe and of a side of the larger decagon 400/9 = 44 4/9 = 44.444.. feet. From the equation above:\n\r\n44.444 = 2*a*Tan(Pi/10)\r\na = 44.444 / Tan(Pi/10) ~ 68.393\n\r\nSo the radius of the larger circle is 68.393 feet and the radius of the foundation is 68.393/3 = 22.798, which is also the radius of the house decagon. The apothem and length of a side for the house are:\n\r\na = 22.798 * Cos(Pi/10) = 21.682\r\ns = 2 * 21.682 * Tan(Pi/10) = 14.090\n\r\nThe side and apothem are the base and height of one of the ten triangles formed by two vertex radii and a side. The area of one of these triangles is then\n\r\n14.090 * 21.682 / 2 = 152.75\n\r\nand the area of the decagon is 10 * 152.75 = 1527.5. Now Rex just needs to know the size of the atrium to calculate the square footage of the house. The radius of the atrium is one-tenth the radius of the large decagon, which is\n\r\nr = 68.393 / Cos(Pi/10) = 71.913\n\r\nso the area of the atrium is\n\r\n(71.913 / 10)^2 * Pi = 162.47\n\r\nand the area of the two floors in Ralph's house is\n\r\n(1527.5 - 162.47) * 2 = 2730.0 square feet.\n<|im_start|>answer\n2,730 sq. feet\n\r\nRex realized that he would need to know the number of sides on Ralph's house in order to make use of the only measurement Ralph gave him, which was the perimeter minus the length of one side for the property. The length of a side of the property needed to be the length of the pipe that bisected the area of the house. The length of the pipe is the key to figuring out how many sides the house has.\n\r\nThe house is a regular polygon inscribed in the circle that is the foundation. Since the closest edge of the property is equal to the diameter of the foundation, then the property must be a similar polygon circumscribed around a circle with a diameter three times the size of the foundation.\n\r\nThe minimum and maximum length line segments that can bisect the area of a regular polygon are calculated differently for even- and odd-sided polygons.\n\r\nFor an even-sided polygon inscribed in a circle of radius r, the maximum line segment has its ends at two opposite vertices and the length is 2r. The minimum line segment goes from the middle of one edge to the middle of the opposite edge. The distance from the edge to the center of a polygon is the apothem, so the minimum line segment is two times the apothem a.\n\r\nFor an odd-sided polygon the maximum bisector goes from a vertex to the middle of the opposite side, so the maximum is r + a. As with an even-sided polygon, the minimum bisector for an odd-sided polygon extends through the center of the polygon and at an angle halfway between two adjacent maximum bisectors.\n\r\n2Pi radians = 360 degrees. The central angle between any two adjacent vertices on a polygon with n sides is then 2Pi/n and the angle between a vertex radius and the apothem is half that or Pi/n. The apothem and the radius form two sides of a right triangle, with the third side formed by one half of the side bisected by the apothem. For a regular polygon with n sides of length s this gives the following relationships:\n\r\na = r*Cos(Pi/n)\r\nr = a/Cos(Pi/n)\r\ns = 2*a*Tan(Pi/n)\n\r\nRex assigns one as the radius of the foundation. This makes the apothem of the property three and the side of the property is:\n\r\n2*3*Tan(Pi/n) = 6*Tan(Pi/n)\n\r\nSo where Min(n) and Max(n) are the minimum and maximum length of a bisector for an n-sided polygon inscribed in a unit circle, Rex needs to find an integer value for n that satisfies the inequality:\n\r\nMax(n) >= 6*Tan(Pi/n) >= Min(n)\n\r\nSince Rex is pretty sure there's only one solution, he figures first he'll just use the minimum and maximum functions for even-sided polygons. The minimum and maximum for odd-sided polygons will be within this range, so he might find an odd-sided polygon that doesn't satisfy the equation, but he won't miss any that do. This gives:\n\r\n2 >= 6*Tan(Pi/n) >= 2*Cos(Pi/n)\n\r\nTaking just the first part of the inequality gives:\n\r\n2 >= 6*Tan(Pi/n)\r\n1/3 >= Tan(Pi/n)\r\natan(1/3) >= Pi/n\r\natan(1/3) / Pi >= 1/n\r\nn >= Pi/atan(1/3)\r\nn >= 9.8\n\r\nHe tries 10 and finds that:\n\r\nMax(10) = 2 >\r\n6*Tan(Pi/10) = 1.95 >\r\nMin(10) = Cos(Pi/10) = 1.90\n\r\nNow Rex knows that Ralph's house has ten sides and is a regular decagon. That makes the length of the pipe and of a side of the larger decagon 400/9 = 44 4/9 = 44.444.. feet. From the equation above:\n\r\n44.444 = 2*a*Tan(Pi/10)\r\na = 44.444 / Tan(Pi/10) ~ 68.393\n\r\nSo the radius of the larger circle is 68.393 feet and the radius of the foundation is 68.393/3 = 22.798, which is also the radius of the house decagon. The apothem and length of a side for the house are:\n\r\na = 22.798 * Cos(Pi/10) = 21.682\r\ns = 2 * 21.682 * Tan(Pi/10) = 14.090\n\r\nThe side and apothem are the base and height of one of the ten triangles formed by two vertex radii and a side. The area of one of these triangles is then\n\r\n14.090 * 21.682 / 2 = 152.75\n\r\nand the area of the decagon is 10 * 152.75 = 1527.5. Now Rex just needs to know the size of the atrium to calculate the square footage of the house. The radius of the atrium is one-tenth the radius of the large decagon, which is\n\r\nr = 68.393 / Cos(Pi/10) = 71.913\n\r\nso the area of the atrium is\n\r\n(71.913 / 10)^2 * Pi = 162.47\n\r\nand the area of the two floors in Ralph's house is\n\r\n(1527.5 - 162.47) * 2 = 2730.0 square feet.\n<|im_end|>" }, { "id": "#33150", "title": "CrossDigit 5", "fun": 2.39, "difficulty": 2.27, "author": "dishu", "desc": "This teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digit. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A3, A4, B4, C1, D1 and D2.\r\n2. The sum of digits in row A equal 10.\r\n3. The sum of digits in row B equal 19.\r\n4. The sum of digits in row C equal 18.\r\n5. The sum of digits in row D equal 3.\r\n6. The sum of digits in column 1 equal 4.\r\n7. The sum of digits in column 2 equal 24.\r\n8. The sum of digits in column 3 equal 18.\r\n9. The sum of digits in column 4 equal 4.\n\r\nNow figure out which box contains which digit and do not forget the rules.", "hint": "A number can be present more than once in the grid, but not the same row or column.", "answer": "The solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 9, A3: Blank, A4: Blank\r\nB1: 3, B2: 7, B3: 9, B4: Blank,\r\nC1: Blank, C2: 8, C3: 7, C4: 3\r\nD1: Blank, D2: Blank, D3: 2, D4: 1", "category": "Math", "date": "09/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digit. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A3, A4, B4, C1, D1 and D2.\r\n2. The sum of digits in row A equal 10.\r\n3. The sum of digits in row B equal 19.\r\n4. The sum of digits in row C equal 18.\r\n5. The sum of digits in row D equal 3.\r\n6. The sum of digits in column 1 equal 4.\r\n7. The sum of digits in column 2 equal 24.\r\n8. The sum of digits in column 3 equal 18.\r\n9. The sum of digits in column 4 equal 4.\n\r\nNow figure out which box contains which digit and do not forget the rules.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 9, A3: Blank, A4: Blank\r\nB1: 3, B2: 7, B3: 9, B4: Blank,\r\nC1: Blank, C2: 8, C3: 7, C4: 3\r\nD1: Blank, D2: Blank, D3: 2, D4: 1\n<|im_start|>answer\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 9, A3: Blank, A4: Blank\r\nB1: 3, B2: 7, B3: 9, B4: Blank,\r\nC1: Blank, C2: 8, C3: 7, C4: 3\r\nD1: Blank, D2: Blank, D3: 2, D4: 1\n<|im_end|>" }, { "id": "#22551", "title": "Dazzling Dorm Heights", "fun": 2.39, "difficulty": 1.59, "author": "FeaerFactorY666", "desc": "Brittany, Cody, Erin, Marcus, and Roger visited their sisters and brothers at the high-rise dormitory on the State University campus. The kids had fun running up and down the stairs and playing in the elevators. The top 9 floors of the dorm are for male students, and floors 2 through 8 are for female students. (The first floor is the lobby and the cafeteria.)\n\r\nCody's brother lives on the top floor. \r\nMarcus, Roger, and Cody took the elevator to visit Cody's brother's room. Then they ran down 5 flights of stairs. They realized they'd overshot their destination, so they took an elevator up 1 floor to get to Roger's brother's room. \r\nFrom Roger's brother's room the three boys went down 6 flights of stairs to visit Marcus's sister. From her room they took the elevator up 4 floors, where they met Brittany and her brother getting on at his floor. \r\nErin and her sister walked up 2 flights from the lobby to get to Erin's sister's room. \r\nOn what floor does each of the college students live?", "hint": "Draw a diagram and label the floors. Then count the floors and trace the path followed by each of the visitors.", "answer": "Listed from top to bottom:\n\r\nCody's brother is on the 17th floor.\r\nRoger's brother is on the 13th floor.\r\nBrittany's brother is on the 11th floor.\r\nMarcus's sister is on the 7th floor.\r\nErin's sister is on the 3rd floor.", "category": "Logic", "date": "04/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBrittany, Cody, Erin, Marcus, and Roger visited their sisters and brothers at the high-rise dormitory on the State University campus. The kids had fun running up and down the stairs and playing in the elevators. The top 9 floors of the dorm are for male students, and floors 2 through 8 are for female students. (The first floor is the lobby and the cafeteria.)\n\r\nCody's brother lives on the top floor. \r\nMarcus, Roger, and Cody took the elevator to visit Cody's brother's room. Then they ran down 5 flights of stairs. They realized they'd overshot their destination, so they took an elevator up 1 floor to get to Roger's brother's room. \r\nFrom Roger's brother's room the three boys went down 6 flights of stairs to visit Marcus's sister. From her room they took the elevator up 4 floors, where they met Brittany and her brother getting on at his floor. \r\nErin and her sister walked up 2 flights from the lobby to get to Erin's sister's room. \r\nOn what floor does each of the college students live?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nListed from top to bottom:\n\r\nCody's brother is on the 17th floor.\r\nRoger's brother is on the 13th floor.\r\nBrittany's brother is on the 11th floor.\r\nMarcus's sister is on the 7th floor.\r\nErin's sister is on the 3rd floor.\n<|im_start|>answer\nListed from top to bottom:\n\r\nCody's brother is on the 17th floor.\r\nRoger's brother is on the 13th floor.\r\nBrittany's brother is on the 11th floor.\r\nMarcus's sister is on the 7th floor.\r\nErin's sister is on the 3rd floor.\n<|im_end|>" }, { "id": "#40133", "title": "30's a Good Number!", "fun": 2.39, "difficulty": 1.98, "author": "snowmonster", "desc": "See if you can come up with the number 30 four different ways by using four sets of three identical digits.", "hint": "No hint available.", "answer": "1) 33-3=30\r\n2) 5x5+5=30\r\n3) 6x6-6=30\r\n4) XXX=30 (Roman numerals)", "category": "Math", "date": "01/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSee if you can come up with the number 30 four different ways by using four sets of three identical digits.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) 33-3=30\r\n2) 5x5+5=30\r\n3) 6x6-6=30\r\n4) XXX=30 (Roman numerals)\n<|im_start|>answer\n1) 33-3=30\r\n2) 5x5+5=30\r\n3) 6x6-6=30\r\n4) XXX=30 (Roman numerals)\n<|im_end|>" }, { "id": "#38197", "title": "Three Sportsmen", "fun": 2.39, "difficulty": 2.72, "author": "shenqiang", "desc": "Three sportsmen, Tom, Jim and Sam, are standing in a row, and we can see their backs. Each of them wears a suit, which are red, yellow and blue in no particular order. Each suit has a different number, between 2 and 9, inclusive. Clues are:\n\r\n1. In the order they stand, the three numbers form a perfect square.\r\n2. Tom's number is smaller than the rightmost sportsman's number.\r\n3. The yellow suit's number is odd.\r\n4. The factorial of Sam's number, plus one, is divisible by the red suit's number.", "hint": "One of the clues is very important.", "answer": "Left: Tom, yellow, 5;\r\nMiddle: Jim, red, 7;\r\nRight: Sam, blue, 6.\n\r\nFrom clue 4, the red suit's number must be greater than Sam's number, and must be odd. By trial and error, the possible combinations are (3,2), (5,4), (7,3), (7,6).\r\nFrom clue 1, the square can only be 324 or 576, where 3 or 7 is the red suit's number.\r\nFrom clue 3, the square must be 576, and 5 is the yellow suit's number and 6 the blue one.\r\nFrom clue 2, Tom must be the 5 and Jim the 7.", "category": "Logic", "date": "09/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree sportsmen, Tom, Jim and Sam, are standing in a row, and we can see their backs. Each of them wears a suit, which are red, yellow and blue in no particular order. Each suit has a different number, between 2 and 9, inclusive. Clues are:\n\r\n1. In the order they stand, the three numbers form a perfect square.\r\n2. Tom's number is smaller than the rightmost sportsman's number.\r\n3. The yellow suit's number is odd.\r\n4. The factorial of Sam's number, plus one, is divisible by the red suit's number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeft: Tom, yellow, 5;\r\nMiddle: Jim, red, 7;\r\nRight: Sam, blue, 6.\n\r\nFrom clue 4, the red suit's number must be greater than Sam's number, and must be odd. By trial and error, the possible combinations are (3,2), (5,4), (7,3), (7,6).\r\nFrom clue 1, the square can only be 324 or 576, where 3 or 7 is the red suit's number.\r\nFrom clue 3, the square must be 576, and 5 is the yellow suit's number and 6 the blue one.\r\nFrom clue 2, Tom must be the 5 and Jim the 7.\n<|im_start|>answer\nLeft: Tom, yellow, 5;\r\nMiddle: Jim, red, 7;\r\nRight: Sam, blue, 6.\n\r\nFrom clue 4, the red suit's number must be greater than Sam's number, and must be odd. By trial and error, the possible combinations are (3,2), (5,4), (7,3), (7,6).\r\nFrom clue 1, the square can only be 324 or 576, where 3 or 7 is the red suit's number.\r\nFrom clue 3, the square must be 576, and 5 is the yellow suit's number and 6 the blue one.\r\nFrom clue 2, Tom must be the 5 and Jim the 7.\n<|im_end|>" }, { "id": "#17223", "title": "Pyramids of Egypt", "fun": 2.39, "difficulty": 2.32, "author": "slob", "desc": "My Dad has a miniature Pyramid of Egypt. It is 5 inches in height. Dad was invited to display it at an exhibition. Dad felt it was too small and decided to build a scaled-up model of the Pyramid out of material whose density is (1/ 5) times the density of the material used for the miniature. He did a \"back-of-the-envelope\" calculation to check whether the model would be big enough. \r\nIf the mass (or weight) of the miniature and the scaled-up model are to be the same, how many inches in height will be the scaled-up Pyramid? Give your answer to two places of decimal.", "hint": "No hint available.", "answer": "Mass = Density * volume and \r\nVolume of model/Volume of miniature = (H of model / H of miniature)^3\n\r\nIn the above equation, H is the characteristic dimension (say, height). \r\nIf the mass is to be the same, then density is inversely proportional to volume. Also, the volumes are directly proportional to the cubes of the heights for objects that are geometrically similar. Therefore, the heights are seen to be inversely proportional to the cube roots of the densities. Thus, \r\nHeight of model = Height of miniature x (Density of miniature / Density of model)^1/3 or \r\nHeight of model = 5 x [ 5^1/3 ] = 8.55 inches.", "category": "Math", "date": "04/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy Dad has a miniature Pyramid of Egypt. It is 5 inches in height. Dad was invited to display it at an exhibition. Dad felt it was too small and decided to build a scaled-up model of the Pyramid out of material whose density is (1/ 5) times the density of the material used for the miniature. He did a \"back-of-the-envelope\" calculation to check whether the model would be big enough. \r\nIf the mass (or weight) of the miniature and the scaled-up model are to be the same, how many inches in height will be the scaled-up Pyramid? Give your answer to two places of decimal.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMass = Density * volume and \r\nVolume of model/Volume of miniature = (H of model / H of miniature)^3\n\r\nIn the above equation, H is the characteristic dimension (say, height). \r\nIf the mass is to be the same, then density is inversely proportional to volume. Also, the volumes are directly proportional to the cubes of the heights for objects that are geometrically similar. Therefore, the heights are seen to be inversely proportional to the cube roots of the densities. Thus, \r\nHeight of model = Height of miniature x (Density of miniature / Density of model)^1/3 or \r\nHeight of model = 5 x [ 5^1/3 ] = 8.55 inches.\n<|im_start|>answer\nMass = Density * volume and \r\nVolume of model/Volume of miniature = (H of model / H of miniature)^3\n\r\nIn the above equation, H is the characteristic dimension (say, height). \r\nIf the mass is to be the same, then density is inversely proportional to volume. Also, the volumes are directly proportional to the cubes of the heights for objects that are geometrically similar. Therefore, the heights are seen to be inversely proportional to the cube roots of the densities. Thus, \r\nHeight of model = Height of miniature x (Density of miniature / Density of model)^1/3 or \r\nHeight of model = 5 x [ 5^1/3 ] = 8.55 inches.\n<|im_end|>" }, { "id": "#15297", "title": "Exact Postage With Three Stamps", "fun": 2.39, "difficulty": 2.93, "author": "Gerd", "desc": "In each of the problems below, you need to determine what stamp denominations you need to provide postage from 1 cent up to the given amount, using no more than three stamps per letter. \n\r\nFor example: Which two different stamps are needed to provide postage from 1 to 7 cents using no more than three stamps at a time? \n\r\nAnswer: you need some 1-cent and some 3-cent stamps: \r\n1 = 1; 1 + 1 = 2; 3 = 3; 1 + 3 = 4; \r\n1 + 1 + 3 = 5; 3 + 3 = 6; 1 + 3 + 3 = 7\r\n(note that you can't make 8 cents without using four stamps)\n\r\nRemember, for each problem below you can only use one, two, or three stamps per letter, even though you have several different types of stamps to choose from and an unlimited number of each.\n\r\nFirst problem: With three different denominations you should be able to reach a postage of 15 cents without an interruption. What different stamps do you need? \n\r\nSecond problem: With four different denominations you should be able to reach a postage of 24 cents without an interruption. What stamps do you need? \n\r\nThird problem: With five different denominations you should be able to reach a postage of 36 cents without an interruption. Name the stamps. \n\r\nFourth problem: With six different denominations you should be able to reach a postage of 52 cents without an interruption. (There are two sets of stamps) \n\r\nLast problem (very hard and time consuming!): With seven different denominations you should be able to reach a postage of 70 cents without an interruption.", "hint": "No hint available.", "answer": "First: Three stamps: 1 - 4 - 5 go up to 15 \r\nSecond: Four stamps: 1 - 4 - 7 - 8 up to 24 \r\nThird: Five stamps: 1 - 4 - 6 - 14 - 15 up to 36 \r\nFourth: Six stamps: 1 - 3 - 7 - 9 - 19 - 24 (and the other set is: 1 - 4 - 6 - 14 - 17 - 29) up to 52 \r\nLast problem: Seven stamps: 1 - 4 - 5 - 15 - 18 - 27 - 34 up to 70.", "category": "Math", "date": "11/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn each of the problems below, you need to determine what stamp denominations you need to provide postage from 1 cent up to the given amount, using no more than three stamps per letter. \n\r\nFor example: Which two different stamps are needed to provide postage from 1 to 7 cents using no more than three stamps at a time? \n\r\nAnswer: you need some 1-cent and some 3-cent stamps: \r\n1 = 1; 1 + 1 = 2; 3 = 3; 1 + 3 = 4; \r\n1 + 1 + 3 = 5; 3 + 3 = 6; 1 + 3 + 3 = 7\r\n(note that you can't make 8 cents without using four stamps)\n\r\nRemember, for each problem below you can only use one, two, or three stamps per letter, even though you have several different types of stamps to choose from and an unlimited number of each.\n\r\nFirst problem: With three different denominations you should be able to reach a postage of 15 cents without an interruption. What different stamps do you need? \n\r\nSecond problem: With four different denominations you should be able to reach a postage of 24 cents without an interruption. What stamps do you need? \n\r\nThird problem: With five different denominations you should be able to reach a postage of 36 cents without an interruption. Name the stamps. \n\r\nFourth problem: With six different denominations you should be able to reach a postage of 52 cents without an interruption. (There are two sets of stamps) \n\r\nLast problem (very hard and time consuming!): With seven different denominations you should be able to reach a postage of 70 cents without an interruption.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst: Three stamps: 1 - 4 - 5 go up to 15 \r\nSecond: Four stamps: 1 - 4 - 7 - 8 up to 24 \r\nThird: Five stamps: 1 - 4 - 6 - 14 - 15 up to 36 \r\nFourth: Six stamps: 1 - 3 - 7 - 9 - 19 - 24 (and the other set is: 1 - 4 - 6 - 14 - 17 - 29) up to 52 \r\nLast problem: Seven stamps: 1 - 4 - 5 - 15 - 18 - 27 - 34 up to 70.\n<|im_start|>answer\nFirst: Three stamps: 1 - 4 - 5 go up to 15 \r\nSecond: Four stamps: 1 - 4 - 7 - 8 up to 24 \r\nThird: Five stamps: 1 - 4 - 6 - 14 - 15 up to 36 \r\nFourth: Six stamps: 1 - 3 - 7 - 9 - 19 - 24 (and the other set is: 1 - 4 - 6 - 14 - 17 - 29) up to 52 \r\nLast problem: Seven stamps: 1 - 4 - 5 - 15 - 18 - 27 - 34 up to 70.\n<|im_end|>" }, { "id": "#898", "title": "Father's Sister's Sister-in-law", "fun": 2.39, "difficulty": 1.02, "author": "Michelle", "desc": "What is the closest relation that your father's sister's sister-in-law could be to you?", "hint": "No hint available.", "answer": "Your Mother", "category": "Logic", "date": "09/28/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the closest relation that your father's sister's sister-in-law could be to you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYour Mother\n<|im_start|>answer\nYour Mother\n<|im_end|>" }, { "id": "#18872", "title": "Three Digit Employee Id!!!", "fun": 2.39, "difficulty": 2.71, "author": "lesternoronha1", "desc": "Two years ago, a problem surfaced at the Romankachi Pharmaceuticals Ltd. - one of the many companies belonging to the huge Romankachi conglomerate.\n\r\nWe were devising a three digit id (nonzero first digit) for the employees such that no two employees can have id's that are identical when written in the reverse order. For example, 123 and 321 are identical and hence only one of them can exist. Also a 3 digit id starting with a 0 was invalid since the machine used for swiping does not recognize a 3 digit id starting with a 0.\n\r\nAfter a lot of careful analysis and discussion, we were able to figure out the maximum number of employees that could use this system. Can you repeat the feat?", "hint": "No hint available.", "answer": "It has been mentioned that a 3 digit code starting with a 0 is invalid. Hence we cannot use codes from 001 to 099. \n\r\nHence the total number of valid 3 digit id's is 900. \n\r\nOut of these, three digit numbers that are symmetrical will have the same first and the last digit. The first and the last digit in this case can be selected in 9 ways(any number from 1 to 9). The second digit can be selected in 10 ways(any number from 0 to 9). Therefore number of symmetrical three digit numbers = 9*10 = 90. These 90 id's will not have a corresponding number when written in reverse order. \n\r\nSecondly numbers ending with a zero will also not have a corresponding 3 digit number when written in reverse order. For example, reverse of 910 is 019 which is not a valid three digit code due to the condition given that 3 digit codes starting with 0 are invalid. Number of such three digit numbers = 9*10 = 90. \n\r\nRest of the (900-180) = 720 numbers can be classified into two groups of 360 numbers each, where corresponding pairs of numbers will be identical when written in reverse order. Hence consider only 360 of these numbers. \n\r\nTherefore total number of valid employee id's possible = 90 + 90 + 360 = 540.", "category": "Math", "date": "09/20/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo years ago, a problem surfaced at the Romankachi Pharmaceuticals Ltd. - one of the many companies belonging to the huge Romankachi conglomerate.\n\r\nWe were devising a three digit id (nonzero first digit) for the employees such that no two employees can have id's that are identical when written in the reverse order. For example, 123 and 321 are identical and hence only one of them can exist. Also a 3 digit id starting with a 0 was invalid since the machine used for swiping does not recognize a 3 digit id starting with a 0.\n\r\nAfter a lot of careful analysis and discussion, we were able to figure out the maximum number of employees that could use this system. Can you repeat the feat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt has been mentioned that a 3 digit code starting with a 0 is invalid. Hence we cannot use codes from 001 to 099. \n\r\nHence the total number of valid 3 digit id's is 900. \n\r\nOut of these, three digit numbers that are symmetrical will have the same first and the last digit. The first and the last digit in this case can be selected in 9 ways(any number from 1 to 9). The second digit can be selected in 10 ways(any number from 0 to 9). Therefore number of symmetrical three digit numbers = 9*10 = 90. These 90 id's will not have a corresponding number when written in reverse order. \n\r\nSecondly numbers ending with a zero will also not have a corresponding 3 digit number when written in reverse order. For example, reverse of 910 is 019 which is not a valid three digit code due to the condition given that 3 digit codes starting with 0 are invalid. Number of such three digit numbers = 9*10 = 90. \n\r\nRest of the (900-180) = 720 numbers can be classified into two groups of 360 numbers each, where corresponding pairs of numbers will be identical when written in reverse order. Hence consider only 360 of these numbers. \n\r\nTherefore total number of valid employee id's possible = 90 + 90 + 360 = 540.\n<|im_start|>answer\nIt has been mentioned that a 3 digit code starting with a 0 is invalid. Hence we cannot use codes from 001 to 099. \n\r\nHence the total number of valid 3 digit id's is 900. \n\r\nOut of these, three digit numbers that are symmetrical will have the same first and the last digit. The first and the last digit in this case can be selected in 9 ways(any number from 1 to 9). The second digit can be selected in 10 ways(any number from 0 to 9). Therefore number of symmetrical three digit numbers = 9*10 = 90. These 90 id's will not have a corresponding number when written in reverse order. \n\r\nSecondly numbers ending with a zero will also not have a corresponding 3 digit number when written in reverse order. For example, reverse of 910 is 019 which is not a valid three digit code due to the condition given that 3 digit codes starting with 0 are invalid. Number of such three digit numbers = 9*10 = 90. \n\r\nRest of the (900-180) = 720 numbers can be classified into two groups of 360 numbers each, where corresponding pairs of numbers will be identical when written in reverse order. Hence consider only 360 of these numbers. \n\r\nTherefore total number of valid employee id's possible = 90 + 90 + 360 = 540.\n<|im_end|>" }, { "id": "#2193", "title": "Movie Money", "fun": 2.39, "difficulty": 1.09, "author": "Cascas", "desc": "If you're paying, is it cheaper to take one friend to the movies twice, or two friends to the movies at once?", "hint": "No hint available.", "answer": "Two friends to a movie at once. You're only paying for three tickets but if you were to take one friend to a movie twice you would be paying for 4 tickets - don't forget about your ticket.", "category": "Math", "date": "01/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you're paying, is it cheaper to take one friend to the movies twice, or two friends to the movies at once?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwo friends to a movie at once. You're only paying for three tickets but if you were to take one friend to a movie twice you would be paying for 4 tickets - don't forget about your ticket.\n<|im_start|>answer\nTwo friends to a movie at once. You're only paying for three tickets but if you were to take one friend to a movie twice you would be paying for 4 tickets - don't forget about your ticket.\n<|im_end|>" }, { "id": "#18055", "title": "Madadian Race Horses", "fun": 2.39, "difficulty": 2.84, "author": "mad-ade", "desc": "Mad Ade's rich uncle \"Uncle Rich\" owned the famous Madadian Race horse breeding stables \"The Gluepot\".\r\nIt has a private race track that has five lanes.\r\nUncle Rich has 25 horses and wishes to know which are the three fastest.\r\nWhat is the least number of races needed to be run to find the answer?\r\nNote that it is only the ranking of the horses being found not the actual timings.", "hint": "No hint available.", "answer": "Answer: 7 races \n\r\nRace #1 to Race #5 - Divide the horses into 5 groups of 5. Race each group to rank the first 3 in each - that's 5 races. \n\r\nRace #6 - Race the winner from each group. The winner in this race is the fastest horse. \n\r\nRace #7 - Race the second and third horses from the race in which the fastest horse raced initially, \r\nthe first and second horses from the group of the second horse in Race #6, and the third horse in Race #6 (that's a total of 5 horses). \n\r\nThe first and second horses in Race #7 are the second and third horses of the entire stable.", "category": "Logic", "date": "06/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's rich uncle \"Uncle Rich\" owned the famous Madadian Race horse breeding stables \"The Gluepot\".\r\nIt has a private race track that has five lanes.\r\nUncle Rich has 25 horses and wishes to know which are the three fastest.\r\nWhat is the least number of races needed to be run to find the answer?\r\nNote that it is only the ranking of the horses being found not the actual timings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: 7 races \n\r\nRace #1 to Race #5 - Divide the horses into 5 groups of 5. Race each group to rank the first 3 in each - that's 5 races. \n\r\nRace #6 - Race the winner from each group. The winner in this race is the fastest horse. \n\r\nRace #7 - Race the second and third horses from the race in which the fastest horse raced initially, \r\nthe first and second horses from the group of the second horse in Race #6, and the third horse in Race #6 (that's a total of 5 horses). \n\r\nThe first and second horses in Race #7 are the second and third horses of the entire stable.\n<|im_start|>answer\nAnswer: 7 races \n\r\nRace #1 to Race #5 - Divide the horses into 5 groups of 5. Race each group to rank the first 3 in each - that's 5 races. \n\r\nRace #6 - Race the winner from each group. The winner in this race is the fastest horse. \n\r\nRace #7 - Race the second and third horses from the race in which the fastest horse raced initially, \r\nthe first and second horses from the group of the second horse in Race #6, and the third horse in Race #6 (that's a total of 5 horses). \n\r\nThe first and second horses in Race #7 are the second and third horses of the entire stable.\n<|im_end|>" }, { "id": "#3386", "title": "Jelly Beans", "fun": 2.39, "difficulty": 0.9, "author": "Drunky", "desc": "Alice, Ben, Charlie, David, and Ed entered a contest to guess how many jelly beans are in a jar. Alice guessed 30, Ben guessed 28, Charlie guessed 29, David guessed 25, and Ed guessed 26. Two were off the mark by 1, one was wrong by 4, and one by 3. But one was correct. \n\r\nHow many jelly beans are in the jar at the store?", "hint": "No hint available.", "answer": "29", "category": "Math", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlice, Ben, Charlie, David, and Ed entered a contest to guess how many jelly beans are in a jar. Alice guessed 30, Ben guessed 28, Charlie guessed 29, David guessed 25, and Ed guessed 26. Two were off the mark by 1, one was wrong by 4, and one by 3. But one was correct. \n\r\nHow many jelly beans are in the jar at the store?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n29\n<|im_start|>answer\n29\n<|im_end|>" }, { "id": "#23106", "title": "Who's Where?", "fun": 2.38, "difficulty": 1.28, "author": "sk8ter", "desc": "There were 5 people standing in a line. These were their names: Trey, Kim, Errin, Crystal,and Tierra.\n\r\nNeither Trey nor Kim is next to Tierra.\r\nNeither Kim nor Tierra is next to Errin.\r\nCrystal is just to the right of Errin.\n\r\nName the people, from left to right in the line.", "hint": "No hint available.", "answer": "Kim, Trey, Errin, Crystal, Tierra", "category": "Logic", "date": "05/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 5 people standing in a line. These were their names: Trey, Kim, Errin, Crystal,and Tierra.\n\r\nNeither Trey nor Kim is next to Tierra.\r\nNeither Kim nor Tierra is next to Errin.\r\nCrystal is just to the right of Errin.\n\r\nName the people, from left to right in the line.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKim, Trey, Errin, Crystal, Tierra\n<|im_start|>answer\nKim, Trey, Errin, Crystal, Tierra\n<|im_end|>" }, { "id": "#2196", "title": "Hand Shakes", "fun": 2.38, "difficulty": 1.34, "author": "Cascas", "desc": "If seven people meet each other and each shakes hands only once with each of the others, how many handshakes will there have been?", "hint": "No hint available.", "answer": "21.", "category": "Math", "date": "01/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf seven people meet each other and each shakes hands only once with each of the others, how many handshakes will there have been?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21.\n<|im_start|>answer\n21.\n<|im_end|>" }, { "id": "#38412", "title": "A Square", "fun": 2.38, "difficulty": 2.0, "author": "Victor", "desc": "Some students are standing in a square. Counting from any of the eight directions, Victor is the fifth. How many students are there?", "hint": "It is not 100.", "answer": "Since Victor is the fifth counting from any direction, there are 5+5-1=9 students on each row and each column, and there are 9*9=81 students.\n\r\nThe students stand like this, V is where Victor stands:\n\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S V S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S", "category": "Math", "date": "09/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome students are standing in a square. Counting from any of the eight directions, Victor is the fifth. How many students are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince Victor is the fifth counting from any direction, there are 5+5-1=9 students on each row and each column, and there are 9*9=81 students.\n\r\nThe students stand like this, V is where Victor stands:\n\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S V S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\n<|im_start|>answer\nSince Victor is the fifth counting from any direction, there are 5+5-1=9 students on each row and each column, and there are 9*9=81 students.\n\r\nThe students stand like this, V is where Victor stands:\n\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S V S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\r\nS S S S S S S S S\n<|im_end|>" }, { "id": "#38764", "title": "A Five Digit Palindromic Square", "fun": 2.38, "difficulty": 2.74, "author": "shenqiang", "desc": "There is a five digit square number that is palindromic, and each digit is also a nonzero square number.\n\r\nWhat is it?", "hint": "Of course, it must be the square of a palindromic number. Therefore, when you multiply its square root by itself, there's no carrying, because carrying will break the palindrome. And therefore...", "answer": "44944=212^2.", "category": "Math", "date": "10/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a five digit square number that is palindromic, and each digit is also a nonzero square number.\n\r\nWhat is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n44944=212^2.\n<|im_start|>answer\n44944=212^2.\n<|im_end|>" }, { "id": "#885", "title": "Five Men Stood in a Line", "fun": 2.38, "difficulty": 1.8900000000000001, "author": "Michelle", "desc": "Five men stood in line (single file) at the grocery store. Their occupations are: programmer, salesman, accountant, IRS agent and a radio announcer.\n\r\n- Mark, who is nearest to the cashier, called the radio announcer this morning. \r\n- The salesman is not Mark. \r\n- Darryl is in the middle of the line between the programmer and the IRS agent. \r\n- Don is shopping for a dinner party. \r\n- Matthew is the IRS agent's cousin. \r\n- There is nobody behind Alex. \r\n- Matthew is standing in front of Alex. \r\n- The radio announcer is at one end of the line.\n\r\nIdentify each of the men with their chosen career.", "hint": "No hint available.", "answer": "Don - IRS agent\n\r\nMark - accountant\n\r\nAlex - radio announcer\n\r\nMatthew - programmer\n\r\nDarryl - salesman", "category": "Logic", "date": "09/28/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive men stood in line (single file) at the grocery store. Their occupations are: programmer, salesman, accountant, IRS agent and a radio announcer.\n\r\n- Mark, who is nearest to the cashier, called the radio announcer this morning. \r\n- The salesman is not Mark. \r\n- Darryl is in the middle of the line between the programmer and the IRS agent. \r\n- Don is shopping for a dinner party. \r\n- Matthew is the IRS agent's cousin. \r\n- There is nobody behind Alex. \r\n- Matthew is standing in front of Alex. \r\n- The radio announcer is at one end of the line.\n\r\nIdentify each of the men with their chosen career.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDon - IRS agent\n\r\nMark - accountant\n\r\nAlex - radio announcer\n\r\nMatthew - programmer\n\r\nDarryl - salesman\n<|im_start|>answer\nDon - IRS agent\n\r\nMark - accountant\n\r\nAlex - radio announcer\n\r\nMatthew - programmer\n\r\nDarryl - salesman\n<|im_end|>" }, { "id": "#8562", "title": "Lost City of Kebabylon", "fun": 2.38, "difficulty": 2.25, "author": "mad-ade", "desc": "Once again, Madadia's insipid explorer, Wigan Smith, is on the trail of lost treasure. He has come across a map showing that somewhere in the middle of the Chillivalley desert, there is the lost city of \"Kebabylon\". \r\nTo reach it, he will have to travel overland by foot from the coast. On a trek like this, each person who goes on the journey can only carry enough rations for one person for five days, and the farthest Wigan Smith and his group can travel in one day is 30 miles. Also, \"Kebabylon\" is 120 miles from the starting point. \n\r\nWhat Wigan Smith is trying to figure out is the fewest number of persons, including himself, that he will need in his group so that he can reach the \"Kebabylon\", stay overnight, and then return to the coast without running out of supplies. \n\r\nHow many persons (including himself) will Wigan Smith need to accomplish this mission?\n\r\nBear in mind that Wigan Smith has no moral character when it comes to money and wealth.", "hint": "Only Wigan needs to make the whole journey!", "answer": "3 people (Wigan Smith and 2 others) \n\r\nThis solution only applies because Wigan Smith has no moral character.\n\r\nAs each person can carry five days rations for 1 person , and that the total journey will require 8 days (4 days there, overnight stay, then 4 days back), then the journey would seem impossible. However, Smith and 2 companions could travel 2 days and have 3 rations each. If one companion \"Mysteriously died\" that night, Smith and his other companion would have 4.5 rations each. At the end of the fourth day they would have 2.5 ration each. If Smith's last companion \"Mysteriously died\" that night, he would have 5 rations, which would be more than enough to stay an extra day and return to the coast.", "category": "Logic", "date": "11/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce again, Madadia's insipid explorer, Wigan Smith, is on the trail of lost treasure. He has come across a map showing that somewhere in the middle of the Chillivalley desert, there is the lost city of \"Kebabylon\". \r\nTo reach it, he will have to travel overland by foot from the coast. On a trek like this, each person who goes on the journey can only carry enough rations for one person for five days, and the farthest Wigan Smith and his group can travel in one day is 30 miles. Also, \"Kebabylon\" is 120 miles from the starting point. \n\r\nWhat Wigan Smith is trying to figure out is the fewest number of persons, including himself, that he will need in his group so that he can reach the \"Kebabylon\", stay overnight, and then return to the coast without running out of supplies. \n\r\nHow many persons (including himself) will Wigan Smith need to accomplish this mission?\n\r\nBear in mind that Wigan Smith has no moral character when it comes to money and wealth.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 people (Wigan Smith and 2 others) \n\r\nThis solution only applies because Wigan Smith has no moral character.\n\r\nAs each person can carry five days rations for 1 person , and that the total journey will require 8 days (4 days there, overnight stay, then 4 days back), then the journey would seem impossible. However, Smith and 2 companions could travel 2 days and have 3 rations each. If one companion \"Mysteriously died\" that night, Smith and his other companion would have 4.5 rations each. At the end of the fourth day they would have 2.5 ration each. If Smith's last companion \"Mysteriously died\" that night, he would have 5 rations, which would be more than enough to stay an extra day and return to the coast.\n<|im_start|>answer\n3 people (Wigan Smith and 2 others) \n\r\nThis solution only applies because Wigan Smith has no moral character.\n\r\nAs each person can carry five days rations for 1 person , and that the total journey will require 8 days (4 days there, overnight stay, then 4 days back), then the journey would seem impossible. However, Smith and 2 companions could travel 2 days and have 3 rations each. If one companion \"Mysteriously died\" that night, Smith and his other companion would have 4.5 rations each. At the end of the fourth day they would have 2.5 ration each. If Smith's last companion \"Mysteriously died\" that night, he would have 5 rations, which would be more than enough to stay an extra day and return to the coast.\n<|im_end|>" }, { "id": "#38427", "title": "Division", "fun": 2.38, "difficulty": 2.36, "author": "Victor", "desc": "When A is divided by B, the quotient is C and the remainder is D. B, C, D are 1-digit numbers. What are the maximal and minimal values of A?", "hint": "No hint available.", "answer": "A=BC+D.\r\nFor the maximal value of A, B and C have to be 9, and D is at most 8, A=9*9+8=89.\r\nFor the minimal value of A, B is at least 2(otherwise there's no remainder), and C and D have to be 1, A=2*1+1=3.", "category": "Math", "date": "09/23/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen A is divided by B, the quotient is C and the remainder is D. B, C, D are 1-digit numbers. What are the maximal and minimal values of A?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA=BC+D.\r\nFor the maximal value of A, B and C have to be 9, and D is at most 8, A=9*9+8=89.\r\nFor the minimal value of A, B is at least 2(otherwise there's no remainder), and C and D have to be 1, A=2*1+1=3.\n<|im_start|>answer\nA=BC+D.\r\nFor the maximal value of A, B and C have to be 9, and D is at most 8, A=9*9+8=89.\r\nFor the minimal value of A, B is at least 2(otherwise there's no remainder), and C and D have to be 1, A=2*1+1=3.\n<|im_end|>" }, { "id": "#4532", "title": "Poorly Paid Workers", "fun": 2.38, "difficulty": 1.58, "author": "mad-ade", "desc": "In the legendary country of MADADIA there was an unscrupulous factory owner called \"Nastee O'Baskit\". He paid his workers only £2 a day, but would fine them £3 a day if he caught them sitting down. After 30 working days (not including weekends) one of his workers received his wage packet, which was empty. When he asked his boss why he had no pay, the boss said that with days worked, minus fines for being caught sitting, the worker had just broken even.\n\r\nHow many days did the worker get paid £2, and how many did he get fined £3?", "hint": "No hint available.", "answer": "Out of 30 working days, the worker was paid 18 days at £2 and fined 12 days at £3.\n\r\n18*2 = 36\r\n12*3 = 36 \r\n36 - 36 = 0", "category": "Math", "date": "06/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary country of MADADIA there was an unscrupulous factory owner called \"Nastee O'Baskit\". He paid his workers only £2 a day, but would fine them £3 a day if he caught them sitting down. After 30 working days (not including weekends) one of his workers received his wage packet, which was empty. When he asked his boss why he had no pay, the boss said that with days worked, minus fines for being caught sitting, the worker had just broken even.\n\r\nHow many days did the worker get paid £2, and how many did he get fined £3?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOut of 30 working days, the worker was paid 18 days at £2 and fined 12 days at £3.\n\r\n18*2 = 36\r\n12*3 = 36 \r\n36 - 36 = 0\n<|im_start|>answer\nOut of 30 working days, the worker was paid 18 days at £2 and fined 12 days at £3.\n\r\n18*2 = 36\r\n12*3 = 36 \r\n36 - 36 = 0\n<|im_end|>" }, { "id": "#8759", "title": "The Brother's Check", "fun": 2.38, "difficulty": 2.04, "author": "lesternoronha1", "desc": "Two brothers share a flock of x sheep. They take the sheep to the market and sell each sheep for $x. At the end of the day they put the money from the sales on the table to divide it equally. All money is in $10 bills, except for a few $1 bills (less than 10 of them). One at a time they take out $10 bills. The brother who draws first also draws last. The second brother complains about getting one less $10 bill so the first brother offers him all the $1 bills. The second brother still received a total less than the first brother so he asks the first brother to write him a check to balance the things out. How much was the check for?", "hint": "No hint available.", "answer": "Since they sell x sheep for $x apiece, the total amount of money they will make is $x^2. In other words, the total is a perfect square.\r\nSince the first brother to draw a $10 bill is also the last one to draw, there must be an odd number of $10 bills. In other words the number in the 10's place of the total amount earned must be odd.\r\nAny perfect square with an odd number in the 10's place always has a 6 in the unit's place (check it out - it's true). Therefore the brothers must have $6 in one-dollar bills.\r\nIf the first brother has an extra $10 and the second brother has the $6, then the difference is $4, and the first brother has to write a check for $2 to even things out.", "category": "Math", "date": "11/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo brothers share a flock of x sheep. They take the sheep to the market and sell each sheep for $x. At the end of the day they put the money from the sales on the table to divide it equally. All money is in $10 bills, except for a few $1 bills (less than 10 of them). One at a time they take out $10 bills. The brother who draws first also draws last. The second brother complains about getting one less $10 bill so the first brother offers him all the $1 bills. The second brother still received a total less than the first brother so he asks the first brother to write him a check to balance the things out. How much was the check for?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince they sell x sheep for $x apiece, the total amount of money they will make is $x^2. In other words, the total is a perfect square.\r\nSince the first brother to draw a $10 bill is also the last one to draw, there must be an odd number of $10 bills. In other words the number in the 10's place of the total amount earned must be odd.\r\nAny perfect square with an odd number in the 10's place always has a 6 in the unit's place (check it out - it's true). Therefore the brothers must have $6 in one-dollar bills.\r\nIf the first brother has an extra $10 and the second brother has the $6, then the difference is $4, and the first brother has to write a check for $2 to even things out.\n<|im_start|>answer\nSince they sell x sheep for $x apiece, the total amount of money they will make is $x^2. In other words, the total is a perfect square.\r\nSince the first brother to draw a $10 bill is also the last one to draw, there must be an odd number of $10 bills. In other words the number in the 10's place of the total amount earned must be odd.\r\nAny perfect square with an odd number in the 10's place always has a 6 in the unit's place (check it out - it's true). Therefore the brothers must have $6 in one-dollar bills.\r\nIf the first brother has an extra $10 and the second brother has the $6, then the difference is $4, and the first brother has to write a check for $2 to even things out.\n<|im_end|>" }, { "id": "#4234", "title": "Days Gone By", "fun": 2.38, "difficulty": 1.34, "author": "LungTungBeng", "desc": "A man told his friend, \"The day before yesterday was the 26th, while the day after tomorrow will be the 3rd.\" The friend frowned but then he realized that the other was right. How come?", "hint": "Review the title.", "answer": "He spoke the first half of the sentence right before midnight of the 28th of February, and the other half past midnight (that is, on the eve of the 1st of March). You can figure out that he was right unless this was a leap year.", "category": "Logic", "date": "05/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man told his friend, \"The day before yesterday was the 26th, while the day after tomorrow will be the 3rd.\" The friend frowned but then he realized that the other was right. How come?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe spoke the first half of the sentence right before midnight of the 28th of February, and the other half past midnight (that is, on the eve of the 1st of March). You can figure out that he was right unless this was a leap year.\n<|im_start|>answer\nHe spoke the first half of the sentence right before midnight of the 28th of February, and the other half past midnight (that is, on the eve of the 1st of March). You can figure out that he was right unless this was a leap year.\n<|im_end|>" }, { "id": "#26505", "title": "How Do Ya Like Them Apples?", "fun": 2.38, "difficulty": 0.58, "author": "Rob2003", "desc": "Since the fall air was crisp and clear, five friends (Francis, Norman, Oscar, Rachel, and Sarah) journeyed to Adam's Apple Orchard for an afternoon of apple picking. After gathering their bushels of apples, they retired to the orchard's visitor's center, where each person bought a different delicious apple treat: apple cider, apple doughnut, apple pie, apple turnover, and candied apple made with a different type of apple: Cortland, Golden Delicious, Granny Smith, Jonathan, and Rome Beauty. To complete the perfect afternoon, the five friends enjoyed a dusk hayride through the nearby woods, making this day the apples of their eyes! From the information provided, can you determine the apple treat purchased by each person and type of apple from which it was made? \n\r\n1. Francis bought the apple pie baked with Golden Delicious apples. Rachel purchased a scrumptious apple donut (which wasn't the treat made with Cortland apples).\n\r\n2. Sarah bought the apple turnover. Oscar isn't the one who purchased the jug of apple cider.\n\r\n3. Norman purchased the treat made from Rome Beauty apple. The candied apple was made with Jonathan apple.", "hint": "No hint available.", "answer": "Francis: apple pie, Golden Delicious\r\nNorman: apple cider, Rome Beauty\r\nOscar: candied apple, Jonathan\r\nRachel: apple doughnut,Granny Smith\r\nSarah: apple turnover, Cortland", "category": "Logic-Grid", "date": "10/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSince the fall air was crisp and clear, five friends (Francis, Norman, Oscar, Rachel, and Sarah) journeyed to Adam's Apple Orchard for an afternoon of apple picking. After gathering their bushels of apples, they retired to the orchard's visitor's center, where each person bought a different delicious apple treat: apple cider, apple doughnut, apple pie, apple turnover, and candied apple made with a different type of apple: Cortland, Golden Delicious, Granny Smith, Jonathan, and Rome Beauty. To complete the perfect afternoon, the five friends enjoyed a dusk hayride through the nearby woods, making this day the apples of their eyes! From the information provided, can you determine the apple treat purchased by each person and type of apple from which it was made? \n\r\n1. Francis bought the apple pie baked with Golden Delicious apples. Rachel purchased a scrumptious apple donut (which wasn't the treat made with Cortland apples).\n\r\n2. Sarah bought the apple turnover. Oscar isn't the one who purchased the jug of apple cider.\n\r\n3. Norman purchased the treat made from Rome Beauty apple. The candied apple was made with Jonathan apple.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrancis: apple pie, Golden Delicious\r\nNorman: apple cider, Rome Beauty\r\nOscar: candied apple, Jonathan\r\nRachel: apple doughnut,Granny Smith\r\nSarah: apple turnover, Cortland\n<|im_start|>answer\nFrancis: apple pie, Golden Delicious\r\nNorman: apple cider, Rome Beauty\r\nOscar: candied apple, Jonathan\r\nRachel: apple doughnut,Granny Smith\r\nSarah: apple turnover, Cortland\n<|im_end|>" }, { "id": "#9148", "title": "Discount Policy", "fun": 2.38, "difficulty": 2.5, "author": "doggyxp", "desc": "The local CD shop operates an unusual discount policy. The discount on the next purchase is worked out on the current purchase in the following way: for every whole dollar spent you get 0.5% discount on the next purchase. For example, if you purchased $8.99 on the first purchase, you would then get a 4% discount on the next purchase and so on. You can make as many purchases as necessary.\n\r\nYou need to buy 7 CDs, costing, $11.50, $12.00, $12.00, $12.50, $13.00, $13.00 and $14.50 - what is the cheapest method of buying them?", "hint": "Make 2 purchases.", "answer": "Purchase 1: $11.50, $12.00, $12.00, $12.50 = $48.00 (which gives a 24% discount on the next purchase). \r\nPurchase 2: $13.00, $13.00, $14.50 = $40.50 minus 24% discount = $30.78. For a total cost of $78.78 dollars.", "category": "Math", "date": "12/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe local CD shop operates an unusual discount policy. The discount on the next purchase is worked out on the current purchase in the following way: for every whole dollar spent you get 0.5% discount on the next purchase. For example, if you purchased $8.99 on the first purchase, you would then get a 4% discount on the next purchase and so on. You can make as many purchases as necessary.\n\r\nYou need to buy 7 CDs, costing, $11.50, $12.00, $12.00, $12.50, $13.00, $13.00 and $14.50 - what is the cheapest method of buying them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPurchase 1: $11.50, $12.00, $12.00, $12.50 = $48.00 (which gives a 24% discount on the next purchase). \r\nPurchase 2: $13.00, $13.00, $14.50 = $40.50 minus 24% discount = $30.78. For a total cost of $78.78 dollars.\n<|im_start|>answer\nPurchase 1: $11.50, $12.00, $12.00, $12.50 = $48.00 (which gives a 24% discount on the next purchase). \r\nPurchase 2: $13.00, $13.00, $14.50 = $40.50 minus 24% discount = $30.78. For a total cost of $78.78 dollars.\n<|im_end|>" }, { "id": "#41890", "title": "Fur, Scales, and Tails", "fun": 2.38, "difficulty": 1.55, "author": "whsprec", "desc": "Four men live in the same neighborhood: Jeff, Bill, Fred, and Andy. They each own a different pet: dog, cat, fish, and lizard, and live in a different color house: brown, red, green, and blue. Match the owner with the pet and color of the house.\r\n1- Jeff's and Andy's pets do not have fur.\r\n2- The dog and the fish do not live in the brown house.\r\n3- Andy's and Fred's pets have 4 legs, but neither one owns a dog nor lives in the red house.\r\n4- Bill's house color has 5 letters.\r\n5- The lizard lives in the blue house.", "hint": "No hint available.", "answer": "Jeff- Fish, Red\r\nBill- Dog, Green\r\nFred- Cat, Brown\r\nAndy- Lizard, Blue", "category": "Logic", "date": "05/11/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour men live in the same neighborhood: Jeff, Bill, Fred, and Andy. They each own a different pet: dog, cat, fish, and lizard, and live in a different color house: brown, red, green, and blue. Match the owner with the pet and color of the house.\r\n1- Jeff's and Andy's pets do not have fur.\r\n2- The dog and the fish do not live in the brown house.\r\n3- Andy's and Fred's pets have 4 legs, but neither one owns a dog nor lives in the red house.\r\n4- Bill's house color has 5 letters.\r\n5- The lizard lives in the blue house.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJeff- Fish, Red\r\nBill- Dog, Green\r\nFred- Cat, Brown\r\nAndy- Lizard, Blue\n<|im_start|>answer\nJeff- Fish, Red\r\nBill- Dog, Green\r\nFred- Cat, Brown\r\nAndy- Lizard, Blue\n<|im_end|>" }, { "id": "#19015", "title": "Romankachi Friends !!!", "fun": 2.38, "difficulty": 1.93, "author": "lesternoronha1", "desc": "Four of my friends Ashwath, Charan, Karthik and Srinivas are nicknamed Essi, KK, Kit and Maha, not necessarily in the same order. \n\r\nMy observations about them are as follows :-\n\r\n1) Karthik is stronger than Essi but can't run as fast as Kit.\r\n2) Essi is stronger than Ashwath but weaker than KK.\r\n3) Srinivas is faster than Karthik and slower than Maha but weaker than Essi.\n\r\nCan you recognize the nickname of each of my friends?", "hint": "No hint available.", "answer": "Ashwath is nicknamed Maha, Charan is nicknamed Essi, Karthik is nicknamed KK and Srinivas is nicknamed Kit.\n\r\nThe observations given about the four friends are as follows :-\n\r\n1) Karthik is stronger than Essi but can't run as fast as Kit.\r\n2) Essi is stronger than Ashwath but weaker than KK.\r\n3) Srinivas is faster than Karthik and slower than Maha but weaker than Essi.\n\r\nFrom observation 1, Karthik is different from Essi and Kit. Hence Karthik may be any one of KK or Maha.\n\r\nFrom observation 2, Ashwath is different from Essi and KK. Hence Ashwath may be any one of Kit or Maha.\n\r\nFrom observation 3, Srinivas and Karthik are different from Maha and Essi. Hence they may be either KK or Kit.\n\r\nCombining observations 2 and 3, Ashwath must be Maha, because Srinivas and Karthik are different from Maha and Essi and Ashwath is different from Essi, hence the only left out nickname for Ashwath being Maha. \n\r\nSince Ashwath is Maha and using observation 3 (wherein Srinivas and Karthik are different from Maha and Essi), Charan is left with the nickname Essi.\n\r\nFrom observation 3 we have, Srinivas and Karthik may be one of KK or Kit. However from observation 1, Karthik is different from Essi and Kit. Hence Karthik must be nicknamed KK and hence Srinivas is left with the nickname Kit.\n\r\nHence Ashwath, Charan, Karthik and Srinivas are nicknamed Maha, Essi, KK and Kit respectively.", "category": "Logic", "date": "10/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour of my friends Ashwath, Charan, Karthik and Srinivas are nicknamed Essi, KK, Kit and Maha, not necessarily in the same order. \n\r\nMy observations about them are as follows :-\n\r\n1) Karthik is stronger than Essi but can't run as fast as Kit.\r\n2) Essi is stronger than Ashwath but weaker than KK.\r\n3) Srinivas is faster than Karthik and slower than Maha but weaker than Essi.\n\r\nCan you recognize the nickname of each of my friends?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAshwath is nicknamed Maha, Charan is nicknamed Essi, Karthik is nicknamed KK and Srinivas is nicknamed Kit.\n\r\nThe observations given about the four friends are as follows :-\n\r\n1) Karthik is stronger than Essi but can't run as fast as Kit.\r\n2) Essi is stronger than Ashwath but weaker than KK.\r\n3) Srinivas is faster than Karthik and slower than Maha but weaker than Essi.\n\r\nFrom observation 1, Karthik is different from Essi and Kit. Hence Karthik may be any one of KK or Maha.\n\r\nFrom observation 2, Ashwath is different from Essi and KK. Hence Ashwath may be any one of Kit or Maha.\n\r\nFrom observation 3, Srinivas and Karthik are different from Maha and Essi. Hence they may be either KK or Kit.\n\r\nCombining observations 2 and 3, Ashwath must be Maha, because Srinivas and Karthik are different from Maha and Essi and Ashwath is different from Essi, hence the only left out nickname for Ashwath being Maha. \n\r\nSince Ashwath is Maha and using observation 3 (wherein Srinivas and Karthik are different from Maha and Essi), Charan is left with the nickname Essi.\n\r\nFrom observation 3 we have, Srinivas and Karthik may be one of KK or Kit. However from observation 1, Karthik is different from Essi and Kit. Hence Karthik must be nicknamed KK and hence Srinivas is left with the nickname Kit.\n\r\nHence Ashwath, Charan, Karthik and Srinivas are nicknamed Maha, Essi, KK and Kit respectively.\n<|im_start|>answer\nAshwath is nicknamed Maha, Charan is nicknamed Essi, Karthik is nicknamed KK and Srinivas is nicknamed Kit.\n\r\nThe observations given about the four friends are as follows :-\n\r\n1) Karthik is stronger than Essi but can't run as fast as Kit.\r\n2) Essi is stronger than Ashwath but weaker than KK.\r\n3) Srinivas is faster than Karthik and slower than Maha but weaker than Essi.\n\r\nFrom observation 1, Karthik is different from Essi and Kit. Hence Karthik may be any one of KK or Maha.\n\r\nFrom observation 2, Ashwath is different from Essi and KK. Hence Ashwath may be any one of Kit or Maha.\n\r\nFrom observation 3, Srinivas and Karthik are different from Maha and Essi. Hence they may be either KK or Kit.\n\r\nCombining observations 2 and 3, Ashwath must be Maha, because Srinivas and Karthik are different from Maha and Essi and Ashwath is different from Essi, hence the only left out nickname for Ashwath being Maha. \n\r\nSince Ashwath is Maha and using observation 3 (wherein Srinivas and Karthik are different from Maha and Essi), Charan is left with the nickname Essi.\n\r\nFrom observation 3 we have, Srinivas and Karthik may be one of KK or Kit. However from observation 1, Karthik is different from Essi and Kit. Hence Karthik must be nicknamed KK and hence Srinivas is left with the nickname Kit.\n\r\nHence Ashwath, Charan, Karthik and Srinivas are nicknamed Maha, Essi, KK and Kit respectively.\n<|im_end|>" }, { "id": "#48389", "title": "Building a Birdhouse", "fun": 2.38, "difficulty": 1.23, "author": "Mathgeek007", "desc": "Each of four people (Cadence, Drew, Giovanni, Yasmin) built a birdhouse. Each person used a different kind of wood (Boxwood, Cherrywood, Mahogany, Ebony), each birdhouse was made specifically for a different type of bird (Condor, Oriole, Titmouse, Vulture), and they all built their houses at different times of the day (10:00AM, 1:30 PM, 8:30 PM, 10:00 PM). Using these 10 clues, can you find which person used what kind of wood, what kind of bird they made it for, and what time they made it?\n\r\nThe one who built it for the condor arrived earlier than the one who built it for the oriole.\n\r\nThe one who built the house for the condor is not Drew.\n\r\nEither the one who built the vulture's house or the one who built the condor's birdhouse is Drew.\n\r\nThe person whose house is made of mahogany made it for the titmouse.\n\r\nThe one who built the house for the oriole made it earlier than Cadence.\n\r\nThe person whose house is made of ebony did not built the condor's house.\n\r\nThe person who made a house at 1:30pm made it of cherrywood.\n\r\nThe person whose house is made of cherrywood didn't make it for the vulture.\n\r\nThe one who built a house for the oriole is not Yasmin.\n\r\nOf Cadence and the one who built a house for the condor, one built at 10:00pm and the other built at 10:00am.", "hint": "The titmouse's house was made at 10:00 PM.", "answer": "10:00am Yasmin condor boxwood \n\r\n1:30pm Giovanni oriole cherrywood \n\r\n8:30pm Drew vulture ebony \n\r\n10:00pm Cadence titmouse mahogany", "category": "Logic-Grid", "date": "01/15/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach of four people (Cadence, Drew, Giovanni, Yasmin) built a birdhouse. Each person used a different kind of wood (Boxwood, Cherrywood, Mahogany, Ebony), each birdhouse was made specifically for a different type of bird (Condor, Oriole, Titmouse, Vulture), and they all built their houses at different times of the day (10:00AM, 1:30 PM, 8:30 PM, 10:00 PM). Using these 10 clues, can you find which person used what kind of wood, what kind of bird they made it for, and what time they made it?\n\r\nThe one who built it for the condor arrived earlier than the one who built it for the oriole.\n\r\nThe one who built the house for the condor is not Drew.\n\r\nEither the one who built the vulture's house or the one who built the condor's birdhouse is Drew.\n\r\nThe person whose house is made of mahogany made it for the titmouse.\n\r\nThe one who built the house for the oriole made it earlier than Cadence.\n\r\nThe person whose house is made of ebony did not built the condor's house.\n\r\nThe person who made a house at 1:30pm made it of cherrywood.\n\r\nThe person whose house is made of cherrywood didn't make it for the vulture.\n\r\nThe one who built a house for the oriole is not Yasmin.\n\r\nOf Cadence and the one who built a house for the condor, one built at 10:00pm and the other built at 10:00am.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10:00am Yasmin condor boxwood \n\r\n1:30pm Giovanni oriole cherrywood \n\r\n8:30pm Drew vulture ebony \n\r\n10:00pm Cadence titmouse mahogany\n<|im_start|>answer\n10:00am Yasmin condor boxwood \n\r\n1:30pm Giovanni oriole cherrywood \n\r\n8:30pm Drew vulture ebony \n\r\n10:00pm Cadence titmouse mahogany\n<|im_end|>" }, { "id": "#4382", "title": "Missing Cakes", "fun": 2.38, "difficulty": 1.9000000000000001, "author": "mad-ade", "desc": "As a youngster Mad Ade had a job working as an errand boy. One day he was given the task of collecting boxes of cakes for the Summer Fair. He collected boxes from various people in his local village and each box was labelled in Roman Numerals with the number of cakes in the box. By the time Mad Ade had collected the last box, he was quite hungry, and really needed to eat at least one cake. Luckily the last box was marked with an XI, meaning there were 11 cakes in it. He had the brain wave of turning the box around and underlining the number to give the impression there were IX, that is 9 cakes. However, after eating the 2 cakes, (predictably) Mad Ade was still hungry. How did the young Mad Ade change the number shown on the box again and eat even more cakes, without any one knowing?", "hint": "No hint available.", "answer": "He could add an S to the IX to give the impression there were supposed to be 6 cakes in the box, thus eating 5 cakes in total.", "category": "Logic", "date": "05/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAs a youngster Mad Ade had a job working as an errand boy. One day he was given the task of collecting boxes of cakes for the Summer Fair. He collected boxes from various people in his local village and each box was labelled in Roman Numerals with the number of cakes in the box. By the time Mad Ade had collected the last box, he was quite hungry, and really needed to eat at least one cake. Luckily the last box was marked with an XI, meaning there were 11 cakes in it. He had the brain wave of turning the box around and underlining the number to give the impression there were IX, that is 9 cakes. However, after eating the 2 cakes, (predictably) Mad Ade was still hungry. How did the young Mad Ade change the number shown on the box again and eat even more cakes, without any one knowing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe could add an S to the IX to give the impression there were supposed to be 6 cakes in the box, thus eating 5 cakes in total.\n<|im_start|>answer\nHe could add an S to the IX to give the impression there were supposed to be 6 cakes in the box, thus eating 5 cakes in total.\n<|im_end|>" }, { "id": "#31591", "title": "Two Coasts", "fun": 2.38, "difficulty": 1.76, "author": "Crazycriely", "desc": "There were 3 men. One was on the east coast, one was on the west coast, and one was in Montana. The man in Montana called his 2 friends, but when they answered they both said that they were awakened by his call. The man in Montana said it was only 8pm but forgot about the time zones. The man on the west coast said it was 10pm. The man on the east coast said it was 10pm as well. How is this possible?", "hint": "They are in the US, and not on an island.", "answer": "The east coast and west coast were the coasts of Florida.", "category": "Logic", "date": "07/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 3 men. One was on the east coast, one was on the west coast, and one was in Montana. The man in Montana called his 2 friends, but when they answered they both said that they were awakened by his call. The man in Montana said it was only 8pm but forgot about the time zones. The man on the west coast said it was 10pm. The man on the east coast said it was 10pm as well. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe east coast and west coast were the coasts of Florida.\n<|im_start|>answer\nThe east coast and west coast were the coasts of Florida.\n<|im_end|>" }, { "id": "#44608", "title": "Friends and Books", "fun": 2.38, "difficulty": 1.92, "author": "mrsfessler", "desc": "5 friends are discussing their favorite book, \"Little Women\". Determine from the clues each girl's age, her favorite character and her favorite scene in the book.\n\r\n1. The 14 year old is a tomboy, so she really relates to Jo. The youngest and oldest, in some order, like Meg's wedding scene and Amy the best.\n\r\n2. The one who likes Beth is older than Bree who is older than the one who likes the Christmas scene. Marie gets so emotional at Mr. March's homecoming, but that's not her favorite scene.\n\r\n3. The two 13 year olds are Anna and the one who loves the book's happy ending. The girl who likes the homecoming scene is older than Lisa.\n\r\n4. The 5 girls are represented by the 12 year old, Laurie, Jill, Laurie's proposal to Amy, and Meg. The girl who likes Meg is older than Lisa.\n\r\n5. The 17 year old is a romantic so she likes either Meg's wedding or the proposal the best. Although the book is about 4 women, Bree likes the male character best.", "hint": "Laurie is a boy.", "answer": "Marie, Jo, proposal, 14\r\nJill, Beth, wedding, 17\r\nBree, Laurie, ending, 13\r\nAnna, Meg, homecoming, 13\r\nLisa, Amy, Christmas, 12", "category": "Logic-Grid", "date": "06/09/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 friends are discussing their favorite book, \"Little Women\". Determine from the clues each girl's age, her favorite character and her favorite scene in the book.\n\r\n1. The 14 year old is a tomboy, so she really relates to Jo. The youngest and oldest, in some order, like Meg's wedding scene and Amy the best.\n\r\n2. The one who likes Beth is older than Bree who is older than the one who likes the Christmas scene. Marie gets so emotional at Mr. March's homecoming, but that's not her favorite scene.\n\r\n3. The two 13 year olds are Anna and the one who loves the book's happy ending. The girl who likes the homecoming scene is older than Lisa.\n\r\n4. The 5 girls are represented by the 12 year old, Laurie, Jill, Laurie's proposal to Amy, and Meg. The girl who likes Meg is older than Lisa.\n\r\n5. The 17 year old is a romantic so she likes either Meg's wedding or the proposal the best. Although the book is about 4 women, Bree likes the male character best.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMarie, Jo, proposal, 14\r\nJill, Beth, wedding, 17\r\nBree, Laurie, ending, 13\r\nAnna, Meg, homecoming, 13\r\nLisa, Amy, Christmas, 12\n<|im_start|>answer\nMarie, Jo, proposal, 14\r\nJill, Beth, wedding, 17\r\nBree, Laurie, ending, 13\r\nAnna, Meg, homecoming, 13\r\nLisa, Amy, Christmas, 12\n<|im_end|>" }, { "id": "#43678", "title": "Eliza Pseudonym and the Daily Word", "fun": 2.38, "difficulty": 2.29, "author": "mathgrant", "desc": "During a six-day period from Monday through Saturday, Eliza Pseudonym and her friends Anna, Barbra, Carla, Delilah, and Fiona have subscribed to an internet mailing list that features a new word every day. No two women subscribed on the same day. On each day during the six-day period, a different word has been featured (abulia, betise, caryatid, dehisce, euhemerism, and floruit, in some order). From the clues below, determine the day on which each woman subscribed, and the day on which each word was featured.\n\r\n1. Exactly one of the women has a name beginning with the same letter of the alphabet as the word featured on the day that she subscribed to the mailing list.\r\n2. The word \"caryatid\" was featured precisely two days prior to Fiona joining the mailing list.\r\n3. Carla joined the mailing list on Friday.\r\n4. Anna signed up for the mailing list precisely one day after the word \"euhemerism\" was highlighted.\r\n5. Wednesday's word did not end with the letter \"e\".\r\n6. Barbra subscribed precisely three days after the word \"dehisce\" was featured.", "hint": "No hint available.", "answer": "Monday: Eliza, dehisce\r\nTuesday: Delilah\t, euhemerism\r\nWednesday: Anna, abulia\r\nThursday: Barbra, caryatid\r\nFriday: Carla, floruit\r\nSaturday: Fiona, betise", "category": "Logic", "date": "12/06/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a six-day period from Monday through Saturday, Eliza Pseudonym and her friends Anna, Barbra, Carla, Delilah, and Fiona have subscribed to an internet mailing list that features a new word every day. No two women subscribed on the same day. On each day during the six-day period, a different word has been featured (abulia, betise, caryatid, dehisce, euhemerism, and floruit, in some order). From the clues below, determine the day on which each woman subscribed, and the day on which each word was featured.\n\r\n1. Exactly one of the women has a name beginning with the same letter of the alphabet as the word featured on the day that she subscribed to the mailing list.\r\n2. The word \"caryatid\" was featured precisely two days prior to Fiona joining the mailing list.\r\n3. Carla joined the mailing list on Friday.\r\n4. Anna signed up for the mailing list precisely one day after the word \"euhemerism\" was highlighted.\r\n5. Wednesday's word did not end with the letter \"e\".\r\n6. Barbra subscribed precisely three days after the word \"dehisce\" was featured.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMonday: Eliza, dehisce\r\nTuesday: Delilah\t, euhemerism\r\nWednesday: Anna, abulia\r\nThursday: Barbra, caryatid\r\nFriday: Carla, floruit\r\nSaturday: Fiona, betise\n<|im_start|>answer\nMonday: Eliza, dehisce\r\nTuesday: Delilah\t, euhemerism\r\nWednesday: Anna, abulia\r\nThursday: Barbra, caryatid\r\nFriday: Carla, floruit\r\nSaturday: Fiona, betise\n<|im_end|>" }, { "id": "#3481", "title": "Right of Way", "fun": 2.38, "difficulty": 1.16, "author": "Drunky", "desc": "Four cars come to a four way stop, all coming from a different direction. They can't decide who got there first, so they all entered the intersection at the same time. They do not crash into each other. How is this possible?", "hint": "No hint available.", "answer": "They all made right hand turns.", "category": "Logic", "date": "04/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour cars come to a four way stop, all coming from a different direction. They can't decide who got there first, so they all entered the intersection at the same time. They do not crash into each other. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey all made right hand turns.\n<|im_start|>answer\nThey all made right hand turns.\n<|im_end|>" }, { "id": "#3289", "title": "Rope Escape", "fun": 2.38, "difficulty": 1.8, "author": "204_blaze_41", "desc": "Sid Shady is in jail and is planning his escape. His cell, which is on the third floor, is 30 meters above ground level. Shady managed to remove one of the bars from the window, enabling him to squeeze through. He has a rope, but it is only 15 meters in length and a fall of 15 meters would be too dangerous. Aside from the bars on his cell window, there is nothing else, above or below, where he could fasten the rope. However, using just the rope, Shady was able to escape safely. How?", "hint": "No hint available.", "answer": "The ever-crafty Shady untwisted the strands of rope, which left him with two ropes, half the original rope's thickness, but twice the length. With the new rope he was able to lower himself to safety.", "category": "Logic", "date": "04/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSid Shady is in jail and is planning his escape. His cell, which is on the third floor, is 30 meters above ground level. Shady managed to remove one of the bars from the window, enabling him to squeeze through. He has a rope, but it is only 15 meters in length and a fall of 15 meters would be too dangerous. Aside from the bars on his cell window, there is nothing else, above or below, where he could fasten the rope. However, using just the rope, Shady was able to escape safely. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ever-crafty Shady untwisted the strands of rope, which left him with two ropes, half the original rope's thickness, but twice the length. With the new rope he was able to lower himself to safety.\n<|im_start|>answer\nThe ever-crafty Shady untwisted the strands of rope, which left him with two ropes, half the original rope's thickness, but twice the length. With the new rope he was able to lower himself to safety.\n<|im_end|>" }, { "id": "#17453", "title": "Tennis Championship", "fun": 2.38, "difficulty": 1.68, "author": "slob", "desc": "A tennis championship is played on a knock-out basis (ie. a player is out of the tournament when he loses a match). \n\r\n(a) How many players participate in the tournament if 63 matches in total are played? \n\r\n(b) How many matches are played in the tournament if 28 players in total participate?", "hint": "Is it true that all players except the champion have to lose one match?", "answer": "The final: total matches = 1 (2 players) \r\nSemi-finals: 2 matches (4 players) and total matches = 1 + 2 = 3 matches \r\nQuarter finals: 4 matches (8 players) and total matches = 1 + 2 + 4 = 7 matches \r\nPre-Quarter finals: 8 matches (16 players) and total matches = 1 + 2 + 4 + 8 = 15 \n\r\nNote that half the players lose their matches at each stage and are out of the tournament. \n\r\nMore importantly, the above explanation shows that the total number of matches played is always one less than the number of players participating in the tournament. This is basically because all players except the champion have to lose a match. One can now easily answer the two questions posed. \n\r\n(a) If 63 matches are totally played, then 64 players participate in the tournament. \n\r\n(b) If 28 players participate in the tournament, then 27 matches are played in total.", "category": "Math", "date": "04/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA tennis championship is played on a knock-out basis (ie. a player is out of the tournament when he loses a match). \n\r\n(a) How many players participate in the tournament if 63 matches in total are played? \n\r\n(b) How many matches are played in the tournament if 28 players in total participate?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe final: total matches = 1 (2 players) \r\nSemi-finals: 2 matches (4 players) and total matches = 1 + 2 = 3 matches \r\nQuarter finals: 4 matches (8 players) and total matches = 1 + 2 + 4 = 7 matches \r\nPre-Quarter finals: 8 matches (16 players) and total matches = 1 + 2 + 4 + 8 = 15 \n\r\nNote that half the players lose their matches at each stage and are out of the tournament. \n\r\nMore importantly, the above explanation shows that the total number of matches played is always one less than the number of players participating in the tournament. This is basically because all players except the champion have to lose a match. One can now easily answer the two questions posed. \n\r\n(a) If 63 matches are totally played, then 64 players participate in the tournament. \n\r\n(b) If 28 players participate in the tournament, then 27 matches are played in total.\n<|im_start|>answer\nThe final: total matches = 1 (2 players) \r\nSemi-finals: 2 matches (4 players) and total matches = 1 + 2 = 3 matches \r\nQuarter finals: 4 matches (8 players) and total matches = 1 + 2 + 4 = 7 matches \r\nPre-Quarter finals: 8 matches (16 players) and total matches = 1 + 2 + 4 + 8 = 15 \n\r\nNote that half the players lose their matches at each stage and are out of the tournament. \n\r\nMore importantly, the above explanation shows that the total number of matches played is always one less than the number of players participating in the tournament. This is basically because all players except the champion have to lose a match. One can now easily answer the two questions posed. \n\r\n(a) If 63 matches are totally played, then 64 players participate in the tournament. \n\r\n(b) If 28 players participate in the tournament, then 27 matches are played in total.\n<|im_end|>" }, { "id": "#11667", "title": "Comic Collecting", "fun": 2.38, "difficulty": 1.66, "author": "PeaceJo", "desc": "Sarah, Daniel, Megan and Shawn are each collecting Terrible Toby, Jumping James and Super Scout comic books. Together they have 100 comic books and everyone has at least one. Daniel has 3 times as many as Megan. Sarah has twice as many as Daniel and Shawn has fewer than 40.\n\r\nWho has the most comics?", "hint": "No hint available.", "answer": "Sarah does.\n\r\nThere are 3 possible answers but in each one, Sarah has the most.\n\r\n1. Sarah 42/Daniel 21/Megan 7/Shawn 30\r\n2. Sarah 48/Daniel 24/Megan 8/Shawn 20\r\n3. Sarah 54/Daniel 27/Megan 9/Shawn 10", "category": "Math", "date": "04/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSarah, Daniel, Megan and Shawn are each collecting Terrible Toby, Jumping James and Super Scout comic books. Together they have 100 comic books and everyone has at least one. Daniel has 3 times as many as Megan. Sarah has twice as many as Daniel and Shawn has fewer than 40.\n\r\nWho has the most comics?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah does.\n\r\nThere are 3 possible answers but in each one, Sarah has the most.\n\r\n1. Sarah 42/Daniel 21/Megan 7/Shawn 30\r\n2. Sarah 48/Daniel 24/Megan 8/Shawn 20\r\n3. Sarah 54/Daniel 27/Megan 9/Shawn 10\n<|im_start|>answer\nSarah does.\n\r\nThere are 3 possible answers but in each one, Sarah has the most.\n\r\n1. Sarah 42/Daniel 21/Megan 7/Shawn 30\r\n2. Sarah 48/Daniel 24/Megan 8/Shawn 20\r\n3. Sarah 54/Daniel 27/Megan 9/Shawn 10\n<|im_end|>" }, { "id": "#41286", "title": "Breakfast Cookers", "fun": 2.38, "difficulty": 1.87, "author": "brain23", "desc": "Five boys had to cook breakfast for each other. Nobody cooked for the same person. Using the clues below, can you determine who cooked breakfast for whom?\n\r\n1. Mark does not have to make Steve breakfast.\r\n2. Bob's breakfast is not cooked by Tom.\r\n3. Tom doesn't have to cook breakfast for Mark.\r\n4. Steve doesn't have to cook for anyone with an O in their name.\r\n5. Bob is allergic to what Tom ordered.\r\n6. Joe can't cook anything hot. Tom's food is hot.\r\n7. Steve will never eat anything cooked by Bob.", "hint": "No hint available.", "answer": "Mark cooked breakfast for Tom.\r\nJoe cooked breakfast for Bob.\r\nSteve cooked breakfast for Mark.\r\nBob cooked breakfast for Joe.\r\nTom cooked breakfast for Steve.", "category": "Logic", "date": "03/30/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive boys had to cook breakfast for each other. Nobody cooked for the same person. Using the clues below, can you determine who cooked breakfast for whom?\n\r\n1. Mark does not have to make Steve breakfast.\r\n2. Bob's breakfast is not cooked by Tom.\r\n3. Tom doesn't have to cook breakfast for Mark.\r\n4. Steve doesn't have to cook for anyone with an O in their name.\r\n5. Bob is allergic to what Tom ordered.\r\n6. Joe can't cook anything hot. Tom's food is hot.\r\n7. Steve will never eat anything cooked by Bob.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMark cooked breakfast for Tom.\r\nJoe cooked breakfast for Bob.\r\nSteve cooked breakfast for Mark.\r\nBob cooked breakfast for Joe.\r\nTom cooked breakfast for Steve.\n<|im_start|>answer\nMark cooked breakfast for Tom.\r\nJoe cooked breakfast for Bob.\r\nSteve cooked breakfast for Mark.\r\nBob cooked breakfast for Joe.\r\nTom cooked breakfast for Steve.\n<|im_end|>" }, { "id": "#4753", "title": "Half a Clock", "fun": 2.38, "difficulty": 1.48, "author": "mad-ade", "desc": "One evening Mad Ade sat at home waiting for his favourite Kebab shop, \"The Sweaty Chef\", to open. He kept glancing as his clock (a regular analog clock face with the numerals 1 to 12 correctly positioned), waiting for opening time. Mad Ade noticed that he could draw a straight line to split the clock face in half in such a way that the sum of the numbers on one side of the line would equal the sum of the numbers on the other side of the line?\n\r\nWhere could Mad Ade draw the line, and what is the total of numbers on either side?", "hint": "No hint available.", "answer": "If Mad Ade was to draw a straight line that begins on the left side of the clock face between 9 and 10 and cuts across the clock face to the right side between 3 and 4.\n\r\n The sum of the numbers above the line equals 39, and the sum of the numbers below the line equals 39.", "category": "Logic", "date": "06/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne evening Mad Ade sat at home waiting for his favourite Kebab shop, \"The Sweaty Chef\", to open. He kept glancing as his clock (a regular analog clock face with the numerals 1 to 12 correctly positioned), waiting for opening time. Mad Ade noticed that he could draw a straight line to split the clock face in half in such a way that the sum of the numbers on one side of the line would equal the sum of the numbers on the other side of the line?\n\r\nWhere could Mad Ade draw the line, and what is the total of numbers on either side?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Mad Ade was to draw a straight line that begins on the left side of the clock face between 9 and 10 and cuts across the clock face to the right side between 3 and 4.\n\r\n The sum of the numbers above the line equals 39, and the sum of the numbers below the line equals 39.\n<|im_start|>answer\nIf Mad Ade was to draw a straight line that begins on the left side of the clock face between 9 and 10 and cuts across the clock face to the right side between 3 and 4.\n\r\n The sum of the numbers above the line equals 39, and the sum of the numbers below the line equals 39.\n<|im_end|>" }, { "id": "#4794", "title": "The Gold Chain", "fun": 2.38, "difficulty": 2.48, "author": "missie", "desc": "A rich man left his home, with only a gold chain with 123 links. He decides to stay at an inn. The owner of the inn wants one link for the first week, two links for the second week, three links for the third week, etc. What is the minimum amount of cuts?", "hint": "No hint available.", "answer": "The minimum number of cuts needed to be made is 4. If the links are numbered from 1 to 123, then the cuts would be made on the following links:\r\n6, 17, 38, and 79. \n\r\nThis would result in four 1-link pieces, one 5 link piece, one 10-link piece, one 20-link piece, one 40-link piece, and one 44 piece.", "category": "Math", "date": "06/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA rich man left his home, with only a gold chain with 123 links. He decides to stay at an inn. The owner of the inn wants one link for the first week, two links for the second week, three links for the third week, etc. What is the minimum amount of cuts?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe minimum number of cuts needed to be made is 4. If the links are numbered from 1 to 123, then the cuts would be made on the following links:\r\n6, 17, 38, and 79. \n\r\nThis would result in four 1-link pieces, one 5 link piece, one 10-link piece, one 20-link piece, one 40-link piece, and one 44 piece.\n<|im_start|>answer\nThe minimum number of cuts needed to be made is 4. If the links are numbered from 1 to 123, then the cuts would be made on the following links:\r\n6, 17, 38, and 79. \n\r\nThis would result in four 1-link pieces, one 5 link piece, one 10-link piece, one 20-link piece, one 40-link piece, and one 44 piece.\n<|im_end|>" }, { "id": "#10434", "title": "Building a house", "fun": 2.38, "difficulty": 1.7, "author": "ka-boom", "desc": "Joe and Bob can build a house together in 45 days. Bob works exactly half the speed that Joe does. How many days can Joe and Bob each build a house on their own?", "hint": "No hint available.", "answer": "Since it takes them 45 days together to build one house, they can build 1/45 of a house in one day. Therefore you can set up an equation to add up each person's contribution to this 1/45 of a house:\n\r\n1/x + 1/2x = 1/45\n\r\nSince the fractions on the left side of the equation represent each person's contribution, solving for x and then inverting each fraction will give their output in days/house:\n\r\nJoe takes 67.5 days and Bob takes 135 days.", "category": "Math", "date": "02/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe and Bob can build a house together in 45 days. Bob works exactly half the speed that Joe does. How many days can Joe and Bob each build a house on their own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince it takes them 45 days together to build one house, they can build 1/45 of a house in one day. Therefore you can set up an equation to add up each person's contribution to this 1/45 of a house:\n\r\n1/x + 1/2x = 1/45\n\r\nSince the fractions on the left side of the equation represent each person's contribution, solving for x and then inverting each fraction will give their output in days/house:\n\r\nJoe takes 67.5 days and Bob takes 135 days.\n<|im_start|>answer\nSince it takes them 45 days together to build one house, they can build 1/45 of a house in one day. Therefore you can set up an equation to add up each person's contribution to this 1/45 of a house:\n\r\n1/x + 1/2x = 1/45\n\r\nSince the fractions on the left side of the equation represent each person's contribution, solving for x and then inverting each fraction will give their output in days/house:\n\r\nJoe takes 67.5 days and Bob takes 135 days.\n<|im_end|>" }, { "id": "#38410", "title": "Shoes Galore", "fun": 2.38, "difficulty": 1.77, "author": "Alyssawu", "desc": "Bobby, Jake, Hannah, Mark, and Alyssa have $71.97 altogether. What could each of them buy at Shoes Galore from the list below?\n\r\nBrown Earth Shoes: $30.00\r\nBlack Canvas Deck Shoes: $15.00\r\nTan Moccasins: $10.99\r\nPink and White Converse All-Stars: $9.99\r\nLight Blue Flip-Flops: $5.99\n\r\nClue #1: Hannah has less money than Jake.\r\nClue #2: Mark has more money than Jake.\r\nClue #3: Alyssa has less money than Mark and Jake but more money than Hannah.\r\nClue #4: Bobby has more money than Mark.", "hint": "No hint available.", "answer": "1. Bobby: Brown Earth Shoes, $30.00.\r\n2. Mark: Black Canvas Deck Shoes, $15.00.\r\n3. Jake: Tan Moccasins, $10.99.\r\n4. Alyssa: Pink and White Converse All-Stars, $9.99.\r\n5. Hannah: Light Blue Flip-Flops, $5.99.", "category": "Logic", "date": "09/22/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBobby, Jake, Hannah, Mark, and Alyssa have $71.97 altogether. What could each of them buy at Shoes Galore from the list below?\n\r\nBrown Earth Shoes: $30.00\r\nBlack Canvas Deck Shoes: $15.00\r\nTan Moccasins: $10.99\r\nPink and White Converse All-Stars: $9.99\r\nLight Blue Flip-Flops: $5.99\n\r\nClue #1: Hannah has less money than Jake.\r\nClue #2: Mark has more money than Jake.\r\nClue #3: Alyssa has less money than Mark and Jake but more money than Hannah.\r\nClue #4: Bobby has more money than Mark.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Bobby: Brown Earth Shoes, $30.00.\r\n2. Mark: Black Canvas Deck Shoes, $15.00.\r\n3. Jake: Tan Moccasins, $10.99.\r\n4. Alyssa: Pink and White Converse All-Stars, $9.99.\r\n5. Hannah: Light Blue Flip-Flops, $5.99.\n<|im_start|>answer\n1. Bobby: Brown Earth Shoes, $30.00.\r\n2. Mark: Black Canvas Deck Shoes, $15.00.\r\n3. Jake: Tan Moccasins, $10.99.\r\n4. Alyssa: Pink and White Converse All-Stars, $9.99.\r\n5. Hannah: Light Blue Flip-Flops, $5.99.\n<|im_end|>" }, { "id": "#40271", "title": "Mr. Jones", "fun": 2.38, "difficulty": 1.42, "author": "Dontrelle", "desc": "Mr. Jones is 28 years older than his son. In 11 years, he will be 3 times as old as his son. How old is each person now?", "hint": "Using algebra will be the easiest way to solve this.", "answer": "3(x + 11) = x + 28 + 11\r\nMr. Jones: 31; son: 3", "category": "Math", "date": "01/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Jones is 28 years older than his son. In 11 years, he will be 3 times as old as his son. How old is each person now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3(x + 11) = x + 28 + 11\r\nMr. Jones: 31; son: 3\n<|im_start|>answer\n3(x + 11) = x + 28 + 11\r\nMr. Jones: 31; son: 3\n<|im_end|>" }, { "id": "#8508", "title": "x^2 - y^2", "fun": 2.38, "difficulty": 2.45, "author": "lesternoronha1", "desc": "Lester is very intent on finding a formula to calculate the difference between two squares but doesn't have any squared terms in it. \r\nEg: If x and y are two numbers with y>x then he wants to find a formula to calculate (y^2)-(x^2) which does not contain any x^2 or y^2 terms in it. \n\r\nHe finds that there are two cases:\r\na) when x and y are consecutive.\r\nb) when x and y are not consecutive.\n\r\nCan you help him find the formula?", "hint": "Take some consecutive and nonconsecutive examples and try for yourself.", "answer": "a) when x and y are consecutive, the difference between their squares is given by : \r\ndifference = x + y.\n\r\nb) when x and y are not consecutive, the difference between their squares is given by : \r\ndifference = x + y + 2 * (sum of numbers between x and y) \n\r\nYou should note that part (a) is just a simplified version of (b), in which there are no numbers between x and y.", "category": "Math", "date": "11/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester is very intent on finding a formula to calculate the difference between two squares but doesn't have any squared terms in it. \r\nEg: If x and y are two numbers with y>x then he wants to find a formula to calculate (y^2)-(x^2) which does not contain any x^2 or y^2 terms in it. \n\r\nHe finds that there are two cases:\r\na) when x and y are consecutive.\r\nb) when x and y are not consecutive.\n\r\nCan you help him find the formula?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) when x and y are consecutive, the difference between their squares is given by : \r\ndifference = x + y.\n\r\nb) when x and y are not consecutive, the difference between their squares is given by : \r\ndifference = x + y + 2 * (sum of numbers between x and y) \n\r\nYou should note that part (a) is just a simplified version of (b), in which there are no numbers between x and y.\n<|im_start|>answer\na) when x and y are consecutive, the difference between their squares is given by : \r\ndifference = x + y.\n\r\nb) when x and y are not consecutive, the difference between their squares is given by : \r\ndifference = x + y + 2 * (sum of numbers between x and y) \n\r\nYou should note that part (a) is just a simplified version of (b), in which there are no numbers between x and y.\n<|im_end|>" }, { "id": "#23856", "title": "How Many?", "fun": 2.38, "difficulty": 1.27, "author": "shdwhawk", "desc": "Mr and Mrs Tan have three sons. Each of their sons has two sisters. Each sister has three cousins. Each cousin has a great-grandparent. \n\r\nHow many people are there?", "hint": "Read VERY carefully. Then do some mental sums.", "answer": "11 people. \r\nMr Tan, Mrs Tan, 1st son, 2nd son, 3rd son, 1st daughter, 2nd daughter. 1st cousin, 2nd cousin, 3rd cousin, and finally, the great-grandparent.", "category": "Math", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr and Mrs Tan have three sons. Each of their sons has two sisters. Each sister has three cousins. Each cousin has a great-grandparent. \n\r\nHow many people are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11 people. \r\nMr Tan, Mrs Tan, 1st son, 2nd son, 3rd son, 1st daughter, 2nd daughter. 1st cousin, 2nd cousin, 3rd cousin, and finally, the great-grandparent.\n<|im_start|>answer\n11 people. \r\nMr Tan, Mrs Tan, 1st son, 2nd son, 3rd son, 1st daughter, 2nd daughter. 1st cousin, 2nd cousin, 3rd cousin, and finally, the great-grandparent.\n<|im_end|>" }, { "id": "#36916", "title": "Pepperland Kennel", "fun": 2.38, "difficulty": 0.88, "author": "beatlesgirl", "desc": "Lucy works at Pepperland Kennel where she watches dogs while their owners are away. One day, Lucy went out for lunch, but when she returned, she saw that someone had taken the collars off of four of the dogs. She suddenly remembered that the owners of these four dogs were supposed to pick them up within the hour. Help Lucy match each dog with their collar and owner.\n\r\n1. The Shih Tzu's collar is blue.\n\r\n2. Mr. Lennon's dog has a red collar.\n\r\n3. The Chihuahua belongs to Mr. Starr.\n\r\n4. The dog that belongs to Mr. Harrison does not have a blue or orange collar.\n\r\n5. The Maltese is not wearing a purple collar.", "hint": "No hint available.", "answer": "1. The Maltese belongs to Mr. Lennon and is wearing a red collar.\n\r\n2. The Shih Tzu belongs to Mr. McCart and is wearing a blue collar.\n\r\n3. The Pomeranian belongs to Mr. Harrison and is wearing a purple collar.\n\r\n4. The Chihuahua belongs to Mr. Starr and is wearing an orange collar.", "category": "Logic-Grid", "date": "06/12/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLucy works at Pepperland Kennel where she watches dogs while their owners are away. One day, Lucy went out for lunch, but when she returned, she saw that someone had taken the collars off of four of the dogs. She suddenly remembered that the owners of these four dogs were supposed to pick them up within the hour. Help Lucy match each dog with their collar and owner.\n\r\n1. The Shih Tzu's collar is blue.\n\r\n2. Mr. Lennon's dog has a red collar.\n\r\n3. The Chihuahua belongs to Mr. Starr.\n\r\n4. The dog that belongs to Mr. Harrison does not have a blue or orange collar.\n\r\n5. The Maltese is not wearing a purple collar.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. The Maltese belongs to Mr. Lennon and is wearing a red collar.\n\r\n2. The Shih Tzu belongs to Mr. McCart and is wearing a blue collar.\n\r\n3. The Pomeranian belongs to Mr. Harrison and is wearing a purple collar.\n\r\n4. The Chihuahua belongs to Mr. Starr and is wearing an orange collar.\n<|im_start|>answer\n1. The Maltese belongs to Mr. Lennon and is wearing a red collar.\n\r\n2. The Shih Tzu belongs to Mr. McCart and is wearing a blue collar.\n\r\n3. The Pomeranian belongs to Mr. Harrison and is wearing a purple collar.\n\r\n4. The Chihuahua belongs to Mr. Starr and is wearing an orange collar.\n<|im_end|>" }, { "id": "#19904", "title": "Not So Good Habits", "fun": 2.38, "difficulty": 2.95, "author": "follydog", "desc": "A man smokes and drinks coffee lightened with cream. He is absolutely consistent in his habits. Every day, except every four years when he abstains on Leap Day, he smokes the same number of cigarettes, brews the same amount of coffee grinds, and uses the same amount of cream in his coffee. Every day he buys the daily newspaper, which he purchases more often than a pack of 20 cigarettes. The pack of cigarettes is purchased more often than a half-pint of cream, which in turn is purchased more often than a one pound can of coffee. On Flag Day (USA) he purchased all four items. The next time he purchased all four items on the same day was the Fourth of July of the following year. How many cigarettes does he smoke each day?", "hint": "Flag Day (USA) is June 14", "answer": "4 cigarettes a day.\n\r\nThe purchases are made according to 4 different cycles. There are 385 days from Flag Day until July Fourth of the following year excluding Leap Day. These purchasing cycles intersect every 385 days and are thus in the set of factors for 385 (1, 5, 7, 11, and 385). Since the newspaper is purchased every day, and the coffee and cream are purchased more often then the pack of cigarettes, then the pack is purchased either every 5 days or every 7 days. The pack contains 20 cigarettes which only has the factor 5 in common with the possible cycle for the cigarettes. Therefore a pack of 20 is purchased every 5 days.", "category": "Math", "date": "12/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man smokes and drinks coffee lightened with cream. He is absolutely consistent in his habits. Every day, except every four years when he abstains on Leap Day, he smokes the same number of cigarettes, brews the same amount of coffee grinds, and uses the same amount of cream in his coffee. Every day he buys the daily newspaper, which he purchases more often than a pack of 20 cigarettes. The pack of cigarettes is purchased more often than a half-pint of cream, which in turn is purchased more often than a one pound can of coffee. On Flag Day (USA) he purchased all four items. The next time he purchased all four items on the same day was the Fourth of July of the following year. How many cigarettes does he smoke each day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 cigarettes a day.\n\r\nThe purchases are made according to 4 different cycles. There are 385 days from Flag Day until July Fourth of the following year excluding Leap Day. These purchasing cycles intersect every 385 days and are thus in the set of factors for 385 (1, 5, 7, 11, and 385). Since the newspaper is purchased every day, and the coffee and cream are purchased more often then the pack of cigarettes, then the pack is purchased either every 5 days or every 7 days. The pack contains 20 cigarettes which only has the factor 5 in common with the possible cycle for the cigarettes. Therefore a pack of 20 is purchased every 5 days.\n<|im_start|>answer\n4 cigarettes a day.\n\r\nThe purchases are made according to 4 different cycles. There are 385 days from Flag Day until July Fourth of the following year excluding Leap Day. These purchasing cycles intersect every 385 days and are thus in the set of factors for 385 (1, 5, 7, 11, and 385). Since the newspaper is purchased every day, and the coffee and cream are purchased more often then the pack of cigarettes, then the pack is purchased either every 5 days or every 7 days. The pack contains 20 cigarettes which only has the factor 5 in common with the possible cycle for the cigarettes. Therefore a pack of 20 is purchased every 5 days.\n<|im_end|>" }, { "id": "#30298", "title": "Dice and Counter", "fun": 2.38, "difficulty": 1.48, "author": "npf2005", "desc": "Here are instructions for a die and counter:\n\r\nWhen the die shows an even number on top, the counter moves two places forward in addition to the number on the die. When the die shows an odd number on top, the counter moves one place back in addition to the number on the die.\n\r\nAssuming the counter starts on zero, on what number will the counter be after seven throws of the die, producing the following numbers on top: 6, 4, 3, 1, 2, 6, 5.", "hint": "No hint available.", "answer": "14.\r\nThe results are as follows:\r\n1st throw (6) = 8\r\n2nd throw (4) = 14\r\n3rd throw (3) = 10\r\n4th throw (1) = 8\r\n5th throw (2) = 12\r\n6th throw (6) = 20\r\n7th throw (5) = 14", "category": "Logic", "date": "05/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHere are instructions for a die and counter:\n\r\nWhen the die shows an even number on top, the counter moves two places forward in addition to the number on the die. When the die shows an odd number on top, the counter moves one place back in addition to the number on the die.\n\r\nAssuming the counter starts on zero, on what number will the counter be after seven throws of the die, producing the following numbers on top: 6, 4, 3, 1, 2, 6, 5.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n14.\r\nThe results are as follows:\r\n1st throw (6) = 8\r\n2nd throw (4) = 14\r\n3rd throw (3) = 10\r\n4th throw (1) = 8\r\n5th throw (2) = 12\r\n6th throw (6) = 20\r\n7th throw (5) = 14\n<|im_start|>answer\n14.\r\nThe results are as follows:\r\n1st throw (6) = 8\r\n2nd throw (4) = 14\r\n3rd throw (3) = 10\r\n4th throw (1) = 8\r\n5th throw (2) = 12\r\n6th throw (6) = 20\r\n7th throw (5) = 14\n<|im_end|>" }, { "id": "#1394", "title": "Four Digits", "fun": 2.38, "difficulty": 1.79, "author": "psychodude57", "desc": "What four digit number has digit 2 less than digit 4 which is two thirds of digit 1 which is two thirds of digit 3 which is three times digit 2?", "hint": "No hint available.", "answer": "6394.", "category": "Math", "date": "11/13/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat four digit number has digit 2 less than digit 4 which is two thirds of digit 1 which is two thirds of digit 3 which is three times digit 2?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6394.\n<|im_start|>answer\n6394.\n<|im_end|>" }, { "id": "#32199", "title": "A Day Out", "fun": 2.38, "difficulty": 1.56, "author": "grungy49", "desc": "Keith opened the door, hopped into the car and revved his engine. He was going to the small town exhibition. \n\r\nHe arrived at the exhibition not long after, and began wandering over to look at the different things.\n\r\nAt the gift shop he spent 50% of his overall money.\n\r\nHe then went on the Dodgems and spent 20% of the remaining money.\n\r\nHe entered a raffle which cost 50% of the remaining money.\n\r\nHe finally bought one hot dog which cost 10% of the remaining money.\n\r\nHe ended up with $22.50.\n\r\nHow much money did Keith start with, and how much did each thing cost?", "hint": "No hint available.", "answer": "You have to work backwards to get this right. All you know at this point is that Keith ended up with $22.50. \n\r\nThe hot dog costs $2.50.\n\r\nThat would bring us up to $25.00. 10% of $25.00 equals $2.50 so if he spends $2.50 on the hot dog that brings us to $22.50, which is the starting point.\n\r\nThe raffle ticket was $25.00.\n\r\nBefore he buys the raffle ticket he has $50.00. He spends 50% of this, so then all you have to do is double $25.00 which makes $50.00.\n\r\nThe Dodgems were $12.50. \n\r\nThis means that before he went on the Dodgems he had $62.50. The Dodgems would have cost 20% of this, which is $12.50. That takes us to $50.00, which is where he was after the Dodgems. \n\r\nThe gifts cost $62.50.\n\r\nOnce again, you just have to multiply the money before the Dodgems by 2. \n\r\nThis means that he started with $125.\n\r\nHot Dog - $2.50\r\nRaffle Ticket - $25.00\r\nDodgems - $12.50\r\nGifts - $62.50\n\r\nTotal - $125", "category": "Math", "date": "07/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKeith opened the door, hopped into the car and revved his engine. He was going to the small town exhibition. \n\r\nHe arrived at the exhibition not long after, and began wandering over to look at the different things.\n\r\nAt the gift shop he spent 50% of his overall money.\n\r\nHe then went on the Dodgems and spent 20% of the remaining money.\n\r\nHe entered a raffle which cost 50% of the remaining money.\n\r\nHe finally bought one hot dog which cost 10% of the remaining money.\n\r\nHe ended up with $22.50.\n\r\nHow much money did Keith start with, and how much did each thing cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou have to work backwards to get this right. All you know at this point is that Keith ended up with $22.50. \n\r\nThe hot dog costs $2.50.\n\r\nThat would bring us up to $25.00. 10% of $25.00 equals $2.50 so if he spends $2.50 on the hot dog that brings us to $22.50, which is the starting point.\n\r\nThe raffle ticket was $25.00.\n\r\nBefore he buys the raffle ticket he has $50.00. He spends 50% of this, so then all you have to do is double $25.00 which makes $50.00.\n\r\nThe Dodgems were $12.50. \n\r\nThis means that before he went on the Dodgems he had $62.50. The Dodgems would have cost 20% of this, which is $12.50. That takes us to $50.00, which is where he was after the Dodgems. \n\r\nThe gifts cost $62.50.\n\r\nOnce again, you just have to multiply the money before the Dodgems by 2. \n\r\nThis means that he started with $125.\n\r\nHot Dog - $2.50\r\nRaffle Ticket - $25.00\r\nDodgems - $12.50\r\nGifts - $62.50\n\r\nTotal - $125\n<|im_start|>answer\nYou have to work backwards to get this right. All you know at this point is that Keith ended up with $22.50. \n\r\nThe hot dog costs $2.50.\n\r\nThat would bring us up to $25.00. 10% of $25.00 equals $2.50 so if he spends $2.50 on the hot dog that brings us to $22.50, which is the starting point.\n\r\nThe raffle ticket was $25.00.\n\r\nBefore he buys the raffle ticket he has $50.00. He spends 50% of this, so then all you have to do is double $25.00 which makes $50.00.\n\r\nThe Dodgems were $12.50. \n\r\nThis means that before he went on the Dodgems he had $62.50. The Dodgems would have cost 20% of this, which is $12.50. That takes us to $50.00, which is where he was after the Dodgems. \n\r\nThe gifts cost $62.50.\n\r\nOnce again, you just have to multiply the money before the Dodgems by 2. \n\r\nThis means that he started with $125.\n\r\nHot Dog - $2.50\r\nRaffle Ticket - $25.00\r\nDodgems - $12.50\r\nGifts - $62.50\n\r\nTotal - $125\n<|im_end|>" }, { "id": "#4651", "title": "Potatoes", "fun": 2.38, "difficulty": 1.18, "author": "librashorty", "desc": "Using five potatoes, how can you feed six children an equal amount of potatoes, without resorting to fractions?", "hint": "No hint available.", "answer": "Make mash potatoes, french fries, or anything else!!!", "category": "Logic", "date": "06/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing five potatoes, how can you feed six children an equal amount of potatoes, without resorting to fractions?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMake mash potatoes, french fries, or anything else!!!\n<|im_start|>answer\nMake mash potatoes, french fries, or anything else!!!\n<|im_end|>" }, { "id": "#38449", "title": "Four Numbers", "fun": 2.38, "difficulty": 2.18, "author": "lips", "desc": "In the equation A234+1B34+12C4+123D=12345, each letter represents a digit. Can you get them?", "hint": "No hint available.", "answer": "The ones digits read 4+4+4+D=5 (or 15), so D=3 to make 15. Carry 1 to the tens digits.\r\nThe tens digits read 3+3+C+3+1=4 (or 14), so C=4 to make 14. Carry 1 to the hundreds digits.\r\nThe hundreds digits read 2+B+2+2+1=3 (or 13), so B=6 to make 13. Carry 1 to the thousands digits.\r\nThe thousands digits read A+1+1+1+1=12, so A=8 to make 12.", "category": "Math", "date": "09/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the equation A234+1B34+12C4+123D=12345, each letter represents a digit. Can you get them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ones digits read 4+4+4+D=5 (or 15), so D=3 to make 15. Carry 1 to the tens digits.\r\nThe tens digits read 3+3+C+3+1=4 (or 14), so C=4 to make 14. Carry 1 to the hundreds digits.\r\nThe hundreds digits read 2+B+2+2+1=3 (or 13), so B=6 to make 13. Carry 1 to the thousands digits.\r\nThe thousands digits read A+1+1+1+1=12, so A=8 to make 12.\n<|im_start|>answer\nThe ones digits read 4+4+4+D=5 (or 15), so D=3 to make 15. Carry 1 to the tens digits.\r\nThe tens digits read 3+3+C+3+1=4 (or 14), so C=4 to make 14. Carry 1 to the hundreds digits.\r\nThe hundreds digits read 2+B+2+2+1=3 (or 13), so B=6 to make 13. Carry 1 to the thousands digits.\r\nThe thousands digits read A+1+1+1+1=12, so A=8 to make 12.\n<|im_end|>" }, { "id": "#14990", "title": "Greater But Lesser", "fun": 2.38, "difficulty": 1.37, "author": "rose_rox", "desc": "What two-digit number is both: \n\r\na) one more than a square, and \r\nb) one less than a cube?", "hint": "No hint available.", "answer": "26\n\r\nOne more than 25 (5*5) and one less than 27 (3*3*3).", "category": "Math", "date": "10/04/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat two-digit number is both: \n\r\na) one more than a square, and \r\nb) one less than a cube?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n26\n\r\nOne more than 25 (5*5) and one less than 27 (3*3*3).\n<|im_start|>answer\n26\n\r\nOne more than 25 (5*5) and one less than 27 (3*3*3).\n<|im_end|>" }, { "id": "#50925", "title": "Cube Edges", "fun": 2.38, "difficulty": 2.19, "author": "cnmne", "desc": "A cube has six faces and twelve edges. Arrange the numbers 1 through 12, placing one number at each edge, such that the sum of the four edges of each face is the same for all six faces. There are many possible solutions (80, to be exact). Find one of them.", "hint": "No hint available.", "answer": "Each of the numbers 1 through 12 is used one time. The summation of those numbers is 78. Each of the numbers appears on two faces, meaning that the sum of all faces is 78*2, or 156. There are six faces, so each face has a sum of 156/6, or 26. The sum of the four edges of each face is 26. One solution: the four numbers on one face are 1 (top), 8 (right), 6 (bottom), and 11 (left); on the opposite side, directly behind those four numbers, are 10, 2, 9, and 5; the remaining four numbers, located on the edges that connect the front and back faces, are 3 (upper left), 12 (upper right), 4 (lower right), and 7 (lower left).", "category": "Math", "date": "12/04/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cube has six faces and twelve edges. Arrange the numbers 1 through 12, placing one number at each edge, such that the sum of the four edges of each face is the same for all six faces. There are many possible solutions (80, to be exact). Find one of them.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach of the numbers 1 through 12 is used one time. The summation of those numbers is 78. Each of the numbers appears on two faces, meaning that the sum of all faces is 78*2, or 156. There are six faces, so each face has a sum of 156/6, or 26. The sum of the four edges of each face is 26. One solution: the four numbers on one face are 1 (top), 8 (right), 6 (bottom), and 11 (left); on the opposite side, directly behind those four numbers, are 10, 2, 9, and 5; the remaining four numbers, located on the edges that connect the front and back faces, are 3 (upper left), 12 (upper right), 4 (lower right), and 7 (lower left).\n<|im_start|>answer\nEach of the numbers 1 through 12 is used one time. The summation of those numbers is 78. Each of the numbers appears on two faces, meaning that the sum of all faces is 78*2, or 156. There are six faces, so each face has a sum of 156/6, or 26. The sum of the four edges of each face is 26. One solution: the four numbers on one face are 1 (top), 8 (right), 6 (bottom), and 11 (left); on the opposite side, directly behind those four numbers, are 10, 2, 9, and 5; the remaining four numbers, located on the edges that connect the front and back faces, are 3 (upper left), 12 (upper right), 4 (lower right), and 7 (lower left).\n<|im_end|>" }, { "id": "#43932", "title": "Rex and Ralph: Prime Clues", "fun": 2.38, "difficulty": 3.14, "author": "javaguru", "desc": "Two mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Frustrated that Ralph was able to so easily figure out his last question, Rex is certain this one won't be so easy. He tells Ralph he's thinking of a number.\n\r\n\"The numbers one less and one more than the number are both the product of five prime numbers. The three numbers together have thirteen prime factors, all different. The sum of the prime factors of the number is 1400.\"\n\r\n\"OK,\" says Ralph after a moment. \"That's probably enough information to find the number with a brute-force search, is that what you expect me to do?\"\n\r\n\"No, no, no,\" replies Rex. \"I don't want you to do anything as inelegant as that. Here's some more information.\"\n\r\n\"The digital sum of each of the number's prime factors is prime, as is digital sum of the product of these sums. In fact, if you the reverse the digits in the product's digital sum you get a different prime number that is the digital sum of the number I'm thinking of.\"\n\r\nRalph takes out a pad of paper and starts jotting down some notes.\n\r\n\"The middle two digits in the number are its only prime digits and the number formed by the middle two digits is also prime. The number formed by the first three digits in the number is prime and its digital sum is also prime. In fact, the digital sum of the digital sum, and the digital sum of the digital sum of the digital sum of the first three numbers are also both prime.\"\n\r\n\"What number am I thinking of?\" asks Rex.\n\r\nRalph jots down a few more notes and then does a couple of calculations on his calculator. He says, \"OK, I know it's one of two numbers, but I don't want to factor these to figure out which one.\"\n\r\nRex frowns and says, \"One of those numbers is divisible by 13.\"\n\r\nRalph smiles and tells Rex the number.\n\r\nWhat were the two numbers and which one was the one Rex was thinking of?\n\n\r\nNote: The \"digital sum\" is the sum of the digits in a number. For example, the digital sum of 247 = 2 + 4 + 7 = 13.", "hint": "You don't have to factor any numbers to find the answer, nor do you need to determine the primality of any numbers larger than 1000.\n\r\nThe problem is as much about logic as it is about math.", "answer": "The two numbers Ralph finds are 443,794 and 887,314. Rex's number is 887,314.\n\r\n887313 = 3 x 7 x 29 x 31 x 47\r\n887314 = 2 x 487 x 911\r\n887315 = 5 x 11 x 13 x 17 x 73\n\n\r\nHere's how Ralph did it:\n\r\nFirst, since the three adjacent numbers don't share any prime numbers, the middle number must be even, otherwise both the other numbers would have to be divisible by 2. If one of the factors in Rex's number is two, then the other two factors must add up to 1400 - 2 = 1398.\n\r\nThe maximum product of two numbers that add up to 1398 is 699 x 699, so the upper bound for Rex's number is 2 x 699 x 699 = 977,202.\n\r\nThe product of the first ten odd prime numbers is\n\r\n3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 = 100,280,245,065\n\r\nThis is the minimum value for the product of Rex's number minus one times Rex's number plus one. Therefore the square root of this number is the lower bound for Rex's number. The square root of 100,280,245,065 ~ 316,670. So now Ralph knows that Rex's number is an even number between 316,670 and 977,202. He figures this could be found by brute force given the other clues. (In fact, 887,314 is the only number in this range that is between two numbers with five or more unique prime factors, but Ralph doesn't know that.)\n\r\nThe digital sum of the prime factors of the number are prime numbers, one of which is 2. The other two must be prime numbers between 316,670 / 1,398 ~ 227 and 1,398. The maximum digital sum for numbers in this range is 3 x 9 = 27, so the maximum value for the product of the three prime digital sums is 2 x 23 x 23 = 1,058. The digital sum of this number is also prime. The maximum digital sum in this range is 27, so the digital sum of this product is a prime number less than 27.\n\r\nThe largest digital sum for a number in the range 316,670 to 977,202 is 6 x 9 = 54. This means that the digital sum of the number must be a prime number less than 54 that is a different prime number less than 27 when reversed. There are four prime numbers less than 54 that are a different prime number when reversed: 13, 17, 31 and 37. The digital sum of Rex's number must be 31.\n\r\nThe middle two digits are prime. For there to be a middle two digits, the number of digits in the number must be even. So now the upper bound for the number is 977,202. The number formed by the middle two digits must also be prime. There are only four two-digit prime numbers composed of prime digits: 23, 37, 53 and 73. The number formed by the first three digits is prime, so the third digit can't be 2 or 5. The middle two digits must be either 37 or 73.\n\r\nSince the sum of the first three digits is a prime number, the sum must be one of 5, 7, 11, 13, 17, 19 or 23. Since the number must start with a 4, 6, 8 or 9, the minimum value for the first three digits is 403, which eliminates 5 as a digital sum. The digital sum of the digital sum of the first three digits must be prime, so it can't be 13, 17 or 19. This leaves 7, 11 or 23 as the digital sum of the first three digits.\n\r\nSince the only possibility for the first three digits totaling 7 is 403, Ralph did a couple of quick calculations to determine that 403 = 13 x 31, so it isn't prime. So the digital sum of the first three digits must be either 11 or 23 and the digital sum of the last three digits must be 20 or 8.\n\r\nThere are only four ways to make a digital sum of 11 for the first three digits that ends in a three or seven and starts with 4, 6, 8 or 9: 407, 443, 623 and 803. Ralph does a couple more quick calculations and determines that 407 = 11 x 37, 623 = 7 x 89 and 803 = 11 x 73, but that 443 is prime. If 443 are the first three digits, then the last three digits must total 20, start with a 7 and end with a 4, 6 or 8. There is only three ways to do this: 758, 776 and 794. The fifth digit can't be prime, so only 794 is possible. This gives the first number 443,794.\n\r\nIf the first three digits total 23, start with a 4, 6, 8 or 9, and end with a 3 or 7, then the choices are 887 and 977. The second digit in 977 is prime, so the only choice is 887. Ralph checks and finds that 887 is prime. If the first three numbers are 887 then the last three must start with a 3, end with a 4, 6 or 8 and total 8. Only 314 is possible, giving the second number 887,314.\n\r\nWhen Rex tells Ralph one of the numbers is divisible by 13, Ralph finds that 443,794 = 13 x 34,138. Since 13 can't be one of the prime factors of the number, the number must be 887,314.", "category": "Math", "date": "01/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo mathematicians, Rex and Ralph, have an ongoing competition to stump each other. Frustrated that Ralph was able to so easily figure out his last question, Rex is certain this one won't be so easy. He tells Ralph he's thinking of a number.\n\r\n\"The numbers one less and one more than the number are both the product of five prime numbers. The three numbers together have thirteen prime factors, all different. The sum of the prime factors of the number is 1400.\"\n\r\n\"OK,\" says Ralph after a moment. \"That's probably enough information to find the number with a brute-force search, is that what you expect me to do?\"\n\r\n\"No, no, no,\" replies Rex. \"I don't want you to do anything as inelegant as that. Here's some more information.\"\n\r\n\"The digital sum of each of the number's prime factors is prime, as is digital sum of the product of these sums. In fact, if you the reverse the digits in the product's digital sum you get a different prime number that is the digital sum of the number I'm thinking of.\"\n\r\nRalph takes out a pad of paper and starts jotting down some notes.\n\r\n\"The middle two digits in the number are its only prime digits and the number formed by the middle two digits is also prime. The number formed by the first three digits in the number is prime and its digital sum is also prime. In fact, the digital sum of the digital sum, and the digital sum of the digital sum of the digital sum of the first three numbers are also both prime.\"\n\r\n\"What number am I thinking of?\" asks Rex.\n\r\nRalph jots down a few more notes and then does a couple of calculations on his calculator. He says, \"OK, I know it's one of two numbers, but I don't want to factor these to figure out which one.\"\n\r\nRex frowns and says, \"One of those numbers is divisible by 13.\"\n\r\nRalph smiles and tells Rex the number.\n\r\nWhat were the two numbers and which one was the one Rex was thinking of?\n\n\r\nNote: The \"digital sum\" is the sum of the digits in a number. For example, the digital sum of 247 = 2 + 4 + 7 = 13.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two numbers Ralph finds are 443,794 and 887,314. Rex's number is 887,314.\n\r\n887313 = 3 x 7 x 29 x 31 x 47\r\n887314 = 2 x 487 x 911\r\n887315 = 5 x 11 x 13 x 17 x 73\n\n\r\nHere's how Ralph did it:\n\r\nFirst, since the three adjacent numbers don't share any prime numbers, the middle number must be even, otherwise both the other numbers would have to be divisible by 2. If one of the factors in Rex's number is two, then the other two factors must add up to 1400 - 2 = 1398.\n\r\nThe maximum product of two numbers that add up to 1398 is 699 x 699, so the upper bound for Rex's number is 2 x 699 x 699 = 977,202.\n\r\nThe product of the first ten odd prime numbers is\n\r\n3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 = 100,280,245,065\n\r\nThis is the minimum value for the product of Rex's number minus one times Rex's number plus one. Therefore the square root of this number is the lower bound for Rex's number. The square root of 100,280,245,065 ~ 316,670. So now Ralph knows that Rex's number is an even number between 316,670 and 977,202. He figures this could be found by brute force given the other clues. (In fact, 887,314 is the only number in this range that is between two numbers with five or more unique prime factors, but Ralph doesn't know that.)\n\r\nThe digital sum of the prime factors of the number are prime numbers, one of which is 2. The other two must be prime numbers between 316,670 / 1,398 ~ 227 and 1,398. The maximum digital sum for numbers in this range is 3 x 9 = 27, so the maximum value for the product of the three prime digital sums is 2 x 23 x 23 = 1,058. The digital sum of this number is also prime. The maximum digital sum in this range is 27, so the digital sum of this product is a prime number less than 27.\n\r\nThe largest digital sum for a number in the range 316,670 to 977,202 is 6 x 9 = 54. This means that the digital sum of the number must be a prime number less than 54 that is a different prime number less than 27 when reversed. There are four prime numbers less than 54 that are a different prime number when reversed: 13, 17, 31 and 37. The digital sum of Rex's number must be 31.\n\r\nThe middle two digits are prime. For there to be a middle two digits, the number of digits in the number must be even. So now the upper bound for the number is 977,202. The number formed by the middle two digits must also be prime. There are only four two-digit prime numbers composed of prime digits: 23, 37, 53 and 73. The number formed by the first three digits is prime, so the third digit can't be 2 or 5. The middle two digits must be either 37 or 73.\n\r\nSince the sum of the first three digits is a prime number, the sum must be one of 5, 7, 11, 13, 17, 19 or 23. Since the number must start with a 4, 6, 8 or 9, the minimum value for the first three digits is 403, which eliminates 5 as a digital sum. The digital sum of the digital sum of the first three digits must be prime, so it can't be 13, 17 or 19. This leaves 7, 11 or 23 as the digital sum of the first three digits.\n\r\nSince the only possibility for the first three digits totaling 7 is 403, Ralph did a couple of quick calculations to determine that 403 = 13 x 31, so it isn't prime. So the digital sum of the first three digits must be either 11 or 23 and the digital sum of the last three digits must be 20 or 8.\n\r\nThere are only four ways to make a digital sum of 11 for the first three digits that ends in a three or seven and starts with 4, 6, 8 or 9: 407, 443, 623 and 803. Ralph does a couple more quick calculations and determines that 407 = 11 x 37, 623 = 7 x 89 and 803 = 11 x 73, but that 443 is prime. If 443 are the first three digits, then the last three digits must total 20, start with a 7 and end with a 4, 6 or 8. There is only three ways to do this: 758, 776 and 794. The fifth digit can't be prime, so only 794 is possible. This gives the first number 443,794.\n\r\nIf the first three digits total 23, start with a 4, 6, 8 or 9, and end with a 3 or 7, then the choices are 887 and 977. The second digit in 977 is prime, so the only choice is 887. Ralph checks and finds that 887 is prime. If the first three numbers are 887 then the last three must start with a 3, end with a 4, 6 or 8 and total 8. Only 314 is possible, giving the second number 887,314.\n\r\nWhen Rex tells Ralph one of the numbers is divisible by 13, Ralph finds that 443,794 = 13 x 34,138. Since 13 can't be one of the prime factors of the number, the number must be 887,314.\n<|im_start|>answer\nThe two numbers Ralph finds are 443,794 and 887,314. Rex's number is 887,314.\n\r\n887313 = 3 x 7 x 29 x 31 x 47\r\n887314 = 2 x 487 x 911\r\n887315 = 5 x 11 x 13 x 17 x 73\n\n\r\nHere's how Ralph did it:\n\r\nFirst, since the three adjacent numbers don't share any prime numbers, the middle number must be even, otherwise both the other numbers would have to be divisible by 2. If one of the factors in Rex's number is two, then the other two factors must add up to 1400 - 2 = 1398.\n\r\nThe maximum product of two numbers that add up to 1398 is 699 x 699, so the upper bound for Rex's number is 2 x 699 x 699 = 977,202.\n\r\nThe product of the first ten odd prime numbers is\n\r\n3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 = 100,280,245,065\n\r\nThis is the minimum value for the product of Rex's number minus one times Rex's number plus one. Therefore the square root of this number is the lower bound for Rex's number. The square root of 100,280,245,065 ~ 316,670. So now Ralph knows that Rex's number is an even number between 316,670 and 977,202. He figures this could be found by brute force given the other clues. (In fact, 887,314 is the only number in this range that is between two numbers with five or more unique prime factors, but Ralph doesn't know that.)\n\r\nThe digital sum of the prime factors of the number are prime numbers, one of which is 2. The other two must be prime numbers between 316,670 / 1,398 ~ 227 and 1,398. The maximum digital sum for numbers in this range is 3 x 9 = 27, so the maximum value for the product of the three prime digital sums is 2 x 23 x 23 = 1,058. The digital sum of this number is also prime. The maximum digital sum in this range is 27, so the digital sum of this product is a prime number less than 27.\n\r\nThe largest digital sum for a number in the range 316,670 to 977,202 is 6 x 9 = 54. This means that the digital sum of the number must be a prime number less than 54 that is a different prime number less than 27 when reversed. There are four prime numbers less than 54 that are a different prime number when reversed: 13, 17, 31 and 37. The digital sum of Rex's number must be 31.\n\r\nThe middle two digits are prime. For there to be a middle two digits, the number of digits in the number must be even. So now the upper bound for the number is 977,202. The number formed by the middle two digits must also be prime. There are only four two-digit prime numbers composed of prime digits: 23, 37, 53 and 73. The number formed by the first three digits is prime, so the third digit can't be 2 or 5. The middle two digits must be either 37 or 73.\n\r\nSince the sum of the first three digits is a prime number, the sum must be one of 5, 7, 11, 13, 17, 19 or 23. Since the number must start with a 4, 6, 8 or 9, the minimum value for the first three digits is 403, which eliminates 5 as a digital sum. The digital sum of the digital sum of the first three digits must be prime, so it can't be 13, 17 or 19. This leaves 7, 11 or 23 as the digital sum of the first three digits.\n\r\nSince the only possibility for the first three digits totaling 7 is 403, Ralph did a couple of quick calculations to determine that 403 = 13 x 31, so it isn't prime. So the digital sum of the first three digits must be either 11 or 23 and the digital sum of the last three digits must be 20 or 8.\n\r\nThere are only four ways to make a digital sum of 11 for the first three digits that ends in a three or seven and starts with 4, 6, 8 or 9: 407, 443, 623 and 803. Ralph does a couple more quick calculations and determines that 407 = 11 x 37, 623 = 7 x 89 and 803 = 11 x 73, but that 443 is prime. If 443 are the first three digits, then the last three digits must total 20, start with a 7 and end with a 4, 6 or 8. There is only three ways to do this: 758, 776 and 794. The fifth digit can't be prime, so only 794 is possible. This gives the first number 443,794.\n\r\nIf the first three digits total 23, start with a 4, 6, 8 or 9, and end with a 3 or 7, then the choices are 887 and 977. The second digit in 977 is prime, so the only choice is 887. Ralph checks and finds that 887 is prime. If the first three numbers are 887 then the last three must start with a 3, end with a 4, 6 or 8 and total 8. Only 314 is possible, giving the second number 887,314.\n\r\nWhen Rex tells Ralph one of the numbers is divisible by 13, Ralph finds that 443,794 = 13 x 34,138. Since 13 can't be one of the prime factors of the number, the number must be 887,314.\n<|im_end|>" }, { "id": "#39157", "title": "101 Percent Surprise", "fun": 2.38, "difficulty": 2.07, "author": "MarcM1098", "desc": "The other day, I took an online survey in which there were two choices: \"True\" and \"False\". I made my selection and was surprised to see the results:\r\n33% of people had selected \"True\"\r\n68% of people had selected \"False\".\n\r\nMy biggest surprise was that most people didn't agree with me. The answer was obviously \"True\", how could anyone think otherwise?\n\r\nI was also slightly surprised to see that the responses totaled 101 percent. Obviously the percentages were rounded to whole numbers. What is the minimum number of people that had completed the survey?", "hint": "Before rounding, the two percentages must total 100.", "answer": "The exact results must be 32.5% and 67.5%. These values total 100% and both numbers would be rounded up to match the observed results of 33% and 68%.\n\r\nThe percents can be written as fractions: 32.5/100 and 67.5/100. \r\nMultiply top and bottom by two to avoid the decimals: 65/200 and 135/200.\r\nFinally, reduce the fractions (both are divisible by 5): 13/40 and 27/40.\n\r\nThus there were a total of 40 votes; 13 voted \"True\" and 27 voted \"False\".", "category": "Math", "date": "11/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe other day, I took an online survey in which there were two choices: \"True\" and \"False\". I made my selection and was surprised to see the results:\r\n33% of people had selected \"True\"\r\n68% of people had selected \"False\".\n\r\nMy biggest surprise was that most people didn't agree with me. The answer was obviously \"True\", how could anyone think otherwise?\n\r\nI was also slightly surprised to see that the responses totaled 101 percent. Obviously the percentages were rounded to whole numbers. What is the minimum number of people that had completed the survey?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe exact results must be 32.5% and 67.5%. These values total 100% and both numbers would be rounded up to match the observed results of 33% and 68%.\n\r\nThe percents can be written as fractions: 32.5/100 and 67.5/100. \r\nMultiply top and bottom by two to avoid the decimals: 65/200 and 135/200.\r\nFinally, reduce the fractions (both are divisible by 5): 13/40 and 27/40.\n\r\nThus there were a total of 40 votes; 13 voted \"True\" and 27 voted \"False\".\n<|im_start|>answer\nThe exact results must be 32.5% and 67.5%. These values total 100% and both numbers would be rounded up to match the observed results of 33% and 68%.\n\r\nThe percents can be written as fractions: 32.5/100 and 67.5/100. \r\nMultiply top and bottom by two to avoid the decimals: 65/200 and 135/200.\r\nFinally, reduce the fractions (both are divisible by 5): 13/40 and 27/40.\n\r\nThus there were a total of 40 votes; 13 voted \"True\" and 27 voted \"False\".\n<|im_end|>" }, { "id": "#447", "title": "Jay and Mary", "fun": 2.38, "difficulty": 1.31, "author": "Spikejw1", "desc": "Jay and Mary are playing cards for a stake of a dollar a game. At the end of the evening, Jay has won 3 games and Mary has won $3.\n\r\nHow many games did they play?", "hint": "No hint available.", "answer": "They played 9 games.\n\r\n(Jay won 3 games, and Mary won 6 games.)", "category": "Math", "date": "05/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJay and Mary are playing cards for a stake of a dollar a game. At the end of the evening, Jay has won 3 games and Mary has won $3.\n\r\nHow many games did they play?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey played 9 games.\n\r\n(Jay won 3 games, and Mary won 6 games.)\n<|im_start|>answer\nThey played 9 games.\n\r\n(Jay won 3 games, and Mary won 6 games.)\n<|im_end|>" }, { "id": "#2247", "title": "Fill the Blanks", "fun": 2.38, "difficulty": 2.66, "author": "jokester8000", "desc": "With the common mathematical operators +, -, *, / try to fill in the blanks in the equation below to make it work.\n\r\n2 5 2 2 6 4 10 10 7=10 \n\r\nFor an extra challenge, whatever operators you use in the first 4 spaces, you must use in the same order in the last 4 spaces.", "hint": "No hint available.", "answer": "(((2*5-2)/2+6)*4-10)/10+7=10", "category": "Math", "date": "02/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith the common mathematical operators +, -, *, / try to fill in the blanks in the equation below to make it work.\n\r\n2 5 2 2 6 4 10 10 7=10 \n\r\nFor an extra challenge, whatever operators you use in the first 4 spaces, you must use in the same order in the last 4 spaces.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(((2*5-2)/2+6)*4-10)/10+7=10\n<|im_start|>answer\n(((2*5-2)/2+6)*4-10)/10+7=10\n<|im_end|>" }, { "id": "#16357", "title": "Top of the List", "fun": 2.37, "difficulty": 1.05, "author": "fishmed", "desc": "William Abbott was the least intelligent and laziest boy in a class of 30 students who took an examination. Yet when the results were posted, William's name was at the top of the list. How come?", "hint": "No hint available.", "answer": "The results were posted in alphabetical order.", "category": "Logic", "date": "01/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWilliam Abbott was the least intelligent and laziest boy in a class of 30 students who took an examination. Yet when the results were posted, William's name was at the top of the list. How come?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe results were posted in alphabetical order.\n<|im_start|>answer\nThe results were posted in alphabetical order.\n<|im_end|>" }, { "id": "#29145", "title": "Opposites 17", "fun": 2.37, "difficulty": 2.22, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n8 stands for N, L, O, Y, or A\r\n7 stands for E, H, L, C, or G\r\n9 stands for E, K, P, M, or T\r\n^ stands for U, T, I, B, or V\n\r\nThe four letter code word, 78^9, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Love and Hate.", "category": "Logic", "date": "03/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n8 stands for N, L, O, Y, or A\r\n7 stands for E, H, L, C, or G\r\n9 stands for E, K, P, M, or T\r\n^ stands for U, T, I, B, or V\n\r\nThe four letter code word, 78^9, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLove and Hate.\n<|im_start|>answer\nLove and Hate.\n<|im_end|>" }, { "id": "#1955", "title": "Gus and Joe", "fun": 2.37, "difficulty": 1.6, "author": "missie", "desc": "Gus and Joe are raising pigs. Gus said that if Joe would give him two pigs they would have an equal number, but if Gus gave Joe two of his, Joe would have twice as many as Gus. How many pigs did they each have?", "hint": "No hint available.", "answer": "Gus had 10\r\nJoe had 14", "category": "Math", "date": "01/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGus and Joe are raising pigs. Gus said that if Joe would give him two pigs they would have an equal number, but if Gus gave Joe two of his, Joe would have twice as many as Gus. How many pigs did they each have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGus had 10\r\nJoe had 14\n<|im_start|>answer\nGus had 10\r\nJoe had 14\n<|im_end|>" }, { "id": "#36623", "title": "3 Cats", "fun": 2.37, "difficulty": 1.5, "author": "tedger", "desc": "It takes three cats three minutes to catch three mice. (Each cat can catch a mouse in three minutes.)\n\r\nAssuming they continue catching mice at the same pace, how long will it take the three cats to catch 100 mice?", "hint": "100 divided by 3 equals ______.", "answer": "102 minutes\n\r\nEach cat catches a mouse in three minutes. It would take them six minutes to catch six, nine to catch nine, and 99 to catch 99; but what about the 100th mouse? It would still take a cat three minutes to catch him, making the total 102 minutes.", "category": "Logic", "date": "05/13/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt takes three cats three minutes to catch three mice. (Each cat can catch a mouse in three minutes.)\n\r\nAssuming they continue catching mice at the same pace, how long will it take the three cats to catch 100 mice?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n102 minutes\n\r\nEach cat catches a mouse in three minutes. It would take them six minutes to catch six, nine to catch nine, and 99 to catch 99; but what about the 100th mouse? It would still take a cat three minutes to catch him, making the total 102 minutes.\n<|im_start|>answer\n102 minutes\n\r\nEach cat catches a mouse in three minutes. It would take them six minutes to catch six, nine to catch nine, and 99 to catch 99; but what about the 100th mouse? It would still take a cat three minutes to catch him, making the total 102 minutes.\n<|im_end|>" }, { "id": "#16800", "title": "Mr. Brown's Pictures", "fun": 2.37, "difficulty": 1.91, "author": "brains5000", "desc": "Mr. Brown looks at five pictures. One of them is a picture of Miss Peaches. One is a picture of a dog named Spot. One is a picture of a female angel. One is a picture of a pizza pie, and one was a picture of a car. The first one is related to something you eat. The second one is to the left of the car. The fourth and fifth one have one thing in common. The fifth one has two things in common with the first one as well. In what order were the pictures?", "hint": "The third one is obvious. Think about how #4 and 5 could be alike. Take two of the pictures and think of their similarities. After that, how could 1 and 5 be alike? And the only one not talked about is the second one.", "answer": "The 1st one is the pizza, because it is related to something you eat. The second one is Spot, the third one is the car, the fourth one is the angel and the fifth one is Miss Peaches. 4 and 5 are alike because they are both female. 1 and 5 are alike because pizza and peaches are both foods, and both start with the letter P.", "category": "Logic", "date": "02/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Brown looks at five pictures. One of them is a picture of Miss Peaches. One is a picture of a dog named Spot. One is a picture of a female angel. One is a picture of a pizza pie, and one was a picture of a car. The first one is related to something you eat. The second one is to the left of the car. The fourth and fifth one have one thing in common. The fifth one has two things in common with the first one as well. In what order were the pictures?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 1st one is the pizza, because it is related to something you eat. The second one is Spot, the third one is the car, the fourth one is the angel and the fifth one is Miss Peaches. 4 and 5 are alike because they are both female. 1 and 5 are alike because pizza and peaches are both foods, and both start with the letter P.\n<|im_start|>answer\nThe 1st one is the pizza, because it is related to something you eat. The second one is Spot, the third one is the car, the fourth one is the angel and the fifth one is Miss Peaches. 4 and 5 are alike because they are both female. 1 and 5 are alike because pizza and peaches are both foods, and both start with the letter P.\n<|im_end|>" }, { "id": "#30843", "title": "No-Fat Frankfurters, A Last Hope", "fun": 2.37, "difficulty": 2.93, "author": "norcekri", "desc": "Patty O'Furniture, Kurt, & Rod were walking downtown when they spotted a forlorn friend staring at a small object in her hand. She was propped against a wall, one foot off the ground.\r\n\t\"I know her,\" Patty said. \"She looks like she could use some help. I think she broke a heel off her shoe.\"\r\n\tPatty was right; the small object was a 3-inch heel.\r\n\t\"This is my sole sister,\" the girl groaned, \"with the obvious name.\"\r\n\tKurt looked blank. After a few seconds, Rod's face lit up.\r\n\t\"Pleased to meet you, Eileen,\" he smirked.\r\n\t\"I wish it could be under better circumstances. You wouldn't have any superglue on you? Maybe an extra pair of size-5 sneakers?\"\r\n\tThey searched their pockets -- no spare shoes, no modern adhesives. Kurt fell back on his usual solution for all depressing problems: a Rnkfurer.\r\n\t\"Is that a spare heel?\" Eileen asked.\r\n\t\"No, it's the world's best snack. Non-fat, low-calorie, high-fiber, made of recycled materials, fortified with five vitamins, and contains 100% of your recommended daily allowance of Public Broadcasting.\"\r\n\t\"Right,\" she grumbled, \"and it tastes like recycled history essays?\"\r\n\tThe three grinned broadly at her. \"Try one,\" Kurt said, proffering one of the shrink-wrapped torpedoes.\r\n\tEileen shifted some of her weight back to the toe of the damaged right shoe and tentatively accepted the Rnkfurer. She unwrapped it, took one bite, and saw her ecstatic grin reflected on the faces of the other three.\n\r\n\t\"Where can I get more of these?\"\r\n\t\"We were about to go order more tomorrow. But there's a catch: we always order so one of us gets the quantity that the other has for a percentage.\"\r\n\tEileen got it right away. \"So we each get 25 of them, and have 25% of the total.\"\r\n\tRod grinned. \"That's cheating. We use different numbers.\"\r\n\t\"Oh, all right.\" She thought for a few seconds. \"So you can do it a few ways for two people, round off for three, but we couldn't do it for four.\"\r\n\t\"Really?\" Rod wasn't as quick with the enlarged problem. \"I'm not surprised, but that means we'll just have to buy in pairs.\"\r\n\t\"Or change the rules a little,\" Eileen added.\r\n\t\"How so?\" Kurt was ready to do almost anything that would get a Rnkfurer refill.\r\n\t\"Well, how about if Kurt buys twice as many as Rod's percentage, Patty gets twice as many as Kurt's percentage ...\"\r\n\tKurt looked hopeful, Patty was expectant, and Rod's analytical gears were grinding.\r\n\t\"It's a big order, but we could do it,\" he finally declared.\n\r\n\tThe grocer now orders Rnkfurers only in cases 100, but that didn't disturb anything. How many did each student get this time?", "hint": "They got a total of 600 Rnkfurers.", "answer": "Rod\t405, 67.5% ... 67.5 * 2 = 135\r\nKurt\t135, 22.5% ... 22.5 * 2 = 45\r\nPatti\t45, 7.5% ... 7.5 * 2 = 15\r\nEileen\t15\r\nTOTAL 600\n\r\nMethod:\n\r\n\tLet E, P, K, and R stand for the quantity each of them had. Let T be the total, R+K+P+E. The math works much like last time, but with four-hundredths instead of percentages.\r\n \tSince four times Rod's percentage equals Kurt's quantity, and so on for the other three students, we get\r\n2 * 100 * R/T = K. Rearranging ...\r\nR = K * T/200. Now, for the other students ...\r\nK = P * T/200\r\nP = E * T/200\r\nNow, look at the common factor, T/200. Let's call this F, the factor relating one quantity to the next.\r\nP = E * F\r\nK = P * F = E * F^2\r\nR = K* F = E * F^3\r\nand T = E*(1+F+F^2+F^3)\r\n-------------\r\nSince E, P, and K are each four times a percentage, and those percentages are less than the whole order, E+P+K<200. All the order amounts are integers; an exhaustive search shows that there are no solutions for F<1. Since F=1 is \"cheating\", F>1, which means K>P>E, and E<200/3.\n\r\nE+P+K=E*(1+F+F^2)<200, so\r\nF cannot be more than 13;\r\nK is a multiple of a perfect square (numerator of F^2);\r\nE is a multiple of a perfect cube (denominator of F^3); the cube cannot be more than 4 (4*4*4).\n\r\nNow, a brute-force search of the finite possibilities for F (numerator 1-13, denominator 1-4) and possible multiples that leave E+P+K<200, we end with only one option where the total is a multiple of 100: F=3 and E=15.", "category": "Math", "date": "06/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPatty O'Furniture, Kurt, & Rod were walking downtown when they spotted a forlorn friend staring at a small object in her hand. She was propped against a wall, one foot off the ground.\r\n\t\"I know her,\" Patty said. \"She looks like she could use some help. I think she broke a heel off her shoe.\"\r\n\tPatty was right; the small object was a 3-inch heel.\r\n\t\"This is my sole sister,\" the girl groaned, \"with the obvious name.\"\r\n\tKurt looked blank. After a few seconds, Rod's face lit up.\r\n\t\"Pleased to meet you, Eileen,\" he smirked.\r\n\t\"I wish it could be under better circumstances. You wouldn't have any superglue on you? Maybe an extra pair of size-5 sneakers?\"\r\n\tThey searched their pockets -- no spare shoes, no modern adhesives. Kurt fell back on his usual solution for all depressing problems: a Rnkfurer.\r\n\t\"Is that a spare heel?\" Eileen asked.\r\n\t\"No, it's the world's best snack. Non-fat, low-calorie, high-fiber, made of recycled materials, fortified with five vitamins, and contains 100% of your recommended daily allowance of Public Broadcasting.\"\r\n\t\"Right,\" she grumbled, \"and it tastes like recycled history essays?\"\r\n\tThe three grinned broadly at her. \"Try one,\" Kurt said, proffering one of the shrink-wrapped torpedoes.\r\n\tEileen shifted some of her weight back to the toe of the damaged right shoe and tentatively accepted the Rnkfurer. She unwrapped it, took one bite, and saw her ecstatic grin reflected on the faces of the other three.\n\r\n\t\"Where can I get more of these?\"\r\n\t\"We were about to go order more tomorrow. But there's a catch: we always order so one of us gets the quantity that the other has for a percentage.\"\r\n\tEileen got it right away. \"So we each get 25 of them, and have 25% of the total.\"\r\n\tRod grinned. \"That's cheating. We use different numbers.\"\r\n\t\"Oh, all right.\" She thought for a few seconds. \"So you can do it a few ways for two people, round off for three, but we couldn't do it for four.\"\r\n\t\"Really?\" Rod wasn't as quick with the enlarged problem. \"I'm not surprised, but that means we'll just have to buy in pairs.\"\r\n\t\"Or change the rules a little,\" Eileen added.\r\n\t\"How so?\" Kurt was ready to do almost anything that would get a Rnkfurer refill.\r\n\t\"Well, how about if Kurt buys twice as many as Rod's percentage, Patty gets twice as many as Kurt's percentage ...\"\r\n\tKurt looked hopeful, Patty was expectant, and Rod's analytical gears were grinding.\r\n\t\"It's a big order, but we could do it,\" he finally declared.\n\r\n\tThe grocer now orders Rnkfurers only in cases 100, but that didn't disturb anything. How many did each student get this time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRod\t405, 67.5% ... 67.5 * 2 = 135\r\nKurt\t135, 22.5% ... 22.5 * 2 = 45\r\nPatti\t45, 7.5% ... 7.5 * 2 = 15\r\nEileen\t15\r\nTOTAL 600\n\r\nMethod:\n\r\n\tLet E, P, K, and R stand for the quantity each of them had. Let T be the total, R+K+P+E. The math works much like last time, but with four-hundredths instead of percentages.\r\n \tSince four times Rod's percentage equals Kurt's quantity, and so on for the other three students, we get\r\n2 * 100 * R/T = K. Rearranging ...\r\nR = K * T/200. Now, for the other students ...\r\nK = P * T/200\r\nP = E * T/200\r\nNow, look at the common factor, T/200. Let's call this F, the factor relating one quantity to the next.\r\nP = E * F\r\nK = P * F = E * F^2\r\nR = K* F = E * F^3\r\nand T = E*(1+F+F^2+F^3)\r\n-------------\r\nSince E, P, and K are each four times a percentage, and those percentages are less than the whole order, E+P+K<200. All the order amounts are integers; an exhaustive search shows that there are no solutions for F<1. Since F=1 is \"cheating\", F>1, which means K>P>E, and E<200/3.\n\r\nE+P+K=E*(1+F+F^2)<200, so\r\nF cannot be more than 13;\r\nK is a multiple of a perfect square (numerator of F^2);\r\nE is a multiple of a perfect cube (denominator of F^3); the cube cannot be more than 4 (4*4*4).\n\r\nNow, a brute-force search of the finite possibilities for F (numerator 1-13, denominator 1-4) and possible multiples that leave E+P+K<200, we end with only one option where the total is a multiple of 100: F=3 and E=15.\n<|im_start|>answer\nRod\t405, 67.5% ... 67.5 * 2 = 135\r\nKurt\t135, 22.5% ... 22.5 * 2 = 45\r\nPatti\t45, 7.5% ... 7.5 * 2 = 15\r\nEileen\t15\r\nTOTAL 600\n\r\nMethod:\n\r\n\tLet E, P, K, and R stand for the quantity each of them had. Let T be the total, R+K+P+E. The math works much like last time, but with four-hundredths instead of percentages.\r\n \tSince four times Rod's percentage equals Kurt's quantity, and so on for the other three students, we get\r\n2 * 100 * R/T = K. Rearranging ...\r\nR = K * T/200. Now, for the other students ...\r\nK = P * T/200\r\nP = E * T/200\r\nNow, look at the common factor, T/200. Let's call this F, the factor relating one quantity to the next.\r\nP = E * F\r\nK = P * F = E * F^2\r\nR = K* F = E * F^3\r\nand T = E*(1+F+F^2+F^3)\r\n-------------\r\nSince E, P, and K are each four times a percentage, and those percentages are less than the whole order, E+P+K<200. All the order amounts are integers; an exhaustive search shows that there are no solutions for F<1. Since F=1 is \"cheating\", F>1, which means K>P>E, and E<200/3.\n\r\nE+P+K=E*(1+F+F^2)<200, so\r\nF cannot be more than 13;\r\nK is a multiple of a perfect square (numerator of F^2);\r\nE is a multiple of a perfect cube (denominator of F^3); the cube cannot be more than 4 (4*4*4).\n\r\nNow, a brute-force search of the finite possibilities for F (numerator 1-13, denominator 1-4) and possible multiples that leave E+P+K<200, we end with only one option where the total is a multiple of 100: F=3 and E=15.\n<|im_end|>" }, { "id": "#2624", "title": "Tennis Tournament", "fun": 2.37, "difficulty": 1.41, "author": "lthang", "desc": "In a singles tennis tournament, 111 players participated. They used a new ball for each new match. When a player lost one match, he was eliminated from the tournament. How many balls did they need?", "hint": "No hint available.", "answer": "There was only one winner, so the remaining 110 players were defeated in 110 matches. Therefore, they used 110 balls.", "category": "Math", "date": "03/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a singles tennis tournament, 111 players participated. They used a new ball for each new match. When a player lost one match, he was eliminated from the tournament. How many balls did they need?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere was only one winner, so the remaining 110 players were defeated in 110 matches. Therefore, they used 110 balls.\n<|im_start|>answer\nThere was only one winner, so the remaining 110 players were defeated in 110 matches. Therefore, they used 110 balls.\n<|im_end|>" }, { "id": "#10214", "title": "Reversing Numbers", "fun": 2.37, "difficulty": 2.3, "author": "melly", "desc": "If a number consisting of three different digits is subtracted from its reverse, the answer is the same three digits in yet another order. What is the number?", "hint": "No hint available.", "answer": "The only possibility is: 954 - 459 = 495.", "category": "Math", "date": "02/03/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a number consisting of three different digits is subtracted from its reverse, the answer is the same three digits in yet another order. What is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe only possibility is: 954 - 459 = 495.\n<|im_start|>answer\nThe only possibility is: 954 - 459 = 495.\n<|im_end|>" }, { "id": "#49084", "title": "Allison's Birthday", "fun": 2.37, "difficulty": 1.67, "author": "Gwendalla", "desc": "My dear friend Allison walked up to me and asked me what her birthday was.\n\r\n\"You forgot your own birthday?\" I questioned her, with a puzzled look on my face.\n\r\n\"No,\" she said, \"I mean I want you to remember it. You don't remember anything!\"\n\r\n\"At least give me a hint,\" I pleaded. \n\r\nEventually she gave in. \"First week of November.\"\n\r\nNow, she and I are masters at logic. I myself knew it near instantly. Do you know what it is?", "hint": "What is in the first week of every year? \n\r\nGo from there.", "answer": "November 1, is her birthday. The only possible answer is 1. It is the only day guaranteed to be in the first week.", "category": "Logic", "date": "10/15/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy dear friend Allison walked up to me and asked me what her birthday was.\n\r\n\"You forgot your own birthday?\" I questioned her, with a puzzled look on my face.\n\r\n\"No,\" she said, \"I mean I want you to remember it. You don't remember anything!\"\n\r\n\"At least give me a hint,\" I pleaded. \n\r\nEventually she gave in. \"First week of November.\"\n\r\nNow, she and I are masters at logic. I myself knew it near instantly. Do you know what it is?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNovember 1, is her birthday. The only possible answer is 1. It is the only day guaranteed to be in the first week.\n<|im_start|>answer\nNovember 1, is her birthday. The only possible answer is 1. It is the only day guaranteed to be in the first week.\n<|im_end|>" }, { "id": "#38125", "title": "How Many Dots?", "fun": 2.37, "difficulty": 1.5, "author": "Rocky_B", "desc": "A 1-6 number cube is sitting on a table. Lenore counts 17 dots on all the sides she can see.\n\r\nWhich face of the number cube is resting on the table?", "hint": "Count the total number of dots on a 1-6 number cube.", "answer": "The side resting on the table is the one with 4 dots.\n\r\n21 total dots - 17 visible dots = 4 hidden dots", "category": "Math", "date": "09/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 1-6 number cube is sitting on a table. Lenore counts 17 dots on all the sides she can see.\n\r\nWhich face of the number cube is resting on the table?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe side resting on the table is the one with 4 dots.\n\r\n21 total dots - 17 visible dots = 4 hidden dots\n<|im_start|>answer\nThe side resting on the table is the one with 4 dots.\n\r\n21 total dots - 17 visible dots = 4 hidden dots\n<|im_end|>" }, { "id": "#31978", "title": "A Wallet Full of Bills", "fun": 2.37, "difficulty": 1.55, "author": "IrIsHcHiCk_1128", "desc": "Jane has twenty bills in her wallet. She has a total of $80. If she has two more $5 bills than $10 bills, and four more $1 bills than $5 bills, how many bills of each does she have?", "hint": "No hint available.", "answer": "She has:\r\nten $1 bills\r\nsix $5 bills\r\nand four $10 bills", "category": "Math", "date": "07/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJane has twenty bills in her wallet. She has a total of $80. If she has two more $5 bills than $10 bills, and four more $1 bills than $5 bills, how many bills of each does she have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe has:\r\nten $1 bills\r\nsix $5 bills\r\nand four $10 bills\n<|im_start|>answer\nShe has:\r\nten $1 bills\r\nsix $5 bills\r\nand four $10 bills\n<|im_end|>" }, { "id": "#7500", "title": "Baseball team", "fun": 2.37, "difficulty": 2.38, "author": "ossa", "desc": "Andy dislikes the catcher. Ed's sister is engaged to the second baseman. The center fielder is taller than the right fielder. Harry and the third baseman live in the same building. Paul and Allen each won $20 from the pitcher at pinochle. Ed and the outfielders play poker during their free time. The pitcher's wife is the third baseman's sister. The pitcher, catcher, and infielders except Allen, Harry, and Andy, are shorter than Sam. Paul, Andy, and the shortstop lost $50 each at the racetrack. Paul, Harry, Bill, and the catcher took a trouncing from the second baseman at pool. Sam is involved in a divorce suit. The catcher and the third baseman each have two children. Ed, Paul, Jerry, the right fielder, and the center fielder are bachelors. The others are married. The shortstop, the third baseman, and Bill each cleaned up $100 betting on the fight. One of the outfielders is either Mike or Andy. Jerry is taller than Bill. Mike is shorter than Bill. Each of them is heavier than the third baseman.\n\r\nUsing these facts, determine the names of the men playing the various positions on the baseball team.", "hint": "No hint available.", "answer": "Harry is the pitcher, Allen the catcher, Paul the first baseman, Jerry the second baseman, Andy the third baseman, Ed the shortstop, Sam the left fielder, Mike the right fielder, and Bill the center fielder.", "category": "Logic", "date": "09/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAndy dislikes the catcher. Ed's sister is engaged to the second baseman. The center fielder is taller than the right fielder. Harry and the third baseman live in the same building. Paul and Allen each won $20 from the pitcher at pinochle. Ed and the outfielders play poker during their free time. The pitcher's wife is the third baseman's sister. The pitcher, catcher, and infielders except Allen, Harry, and Andy, are shorter than Sam. Paul, Andy, and the shortstop lost $50 each at the racetrack. Paul, Harry, Bill, and the catcher took a trouncing from the second baseman at pool. Sam is involved in a divorce suit. The catcher and the third baseman each have two children. Ed, Paul, Jerry, the right fielder, and the center fielder are bachelors. The others are married. The shortstop, the third baseman, and Bill each cleaned up $100 betting on the fight. One of the outfielders is either Mike or Andy. Jerry is taller than Bill. Mike is shorter than Bill. Each of them is heavier than the third baseman.\n\r\nUsing these facts, determine the names of the men playing the various positions on the baseball team.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry is the pitcher, Allen the catcher, Paul the first baseman, Jerry the second baseman, Andy the third baseman, Ed the shortstop, Sam the left fielder, Mike the right fielder, and Bill the center fielder.\n<|im_start|>answer\nHarry is the pitcher, Allen the catcher, Paul the first baseman, Jerry the second baseman, Andy the third baseman, Ed the shortstop, Sam the left fielder, Mike the right fielder, and Bill the center fielder.\n<|im_end|>" }, { "id": "#13373", "title": "Much Ado About Me", "fun": 2.37, "difficulty": 2.13, "author": "Bobbrt", "desc": "Below is a short, 3-question quiz about...ME. There is one correct answer for each question. How much do you know about me? It may be more than you think.\n\r\n1. The outline of my family crest is in the shape of a:\r\n(a) square\r\n(b) parallelogram\r\n(c) quadrilateral\r\n(d) rectangle\n\r\n2. My favorite number is:\r\n(a) 5\r\n(b) 12\r\n(c) 7\r\n(d) one of the above\r\n(e) none of the above\r\n(f) 6\n\r\n3. My street number is:\r\n(a) 25\r\n(b) greater than 6\r\n(c) greater than 9\r\n(d) 7", "hint": "If you think that you can't possibly get the answers, then you didn't read the introduction carefully enough.", "answer": "The key point of this teaser is that there is ONLY ONE correct answer to each question.\n\r\n1. Since a square is a type of rectangle, which is a type of parallelogram, which is a type of quadrilateral, then the only possible unique answer is (c), quadrilateral.\n\r\n2. Since answers of (a), (b), or (c) would also result in (d) being correct, and an answer of (f) would result in (e) also being correct, the only possible answer is (e). \r\n(in case you're wondering, my favorite number is 13)\n\r\n(3) Since 7, 25, and anything greater than 9 are also greater than 6, neither (a), (c), or (d) can be the answer because (b) would also be an answer. Therefore the answer must be (b), and assuming that only integers are used for numbering streets, my street number must be 8.", "category": "Logic", "date": "06/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBelow is a short, 3-question quiz about...ME. There is one correct answer for each question. How much do you know about me? It may be more than you think.\n\r\n1. The outline of my family crest is in the shape of a:\r\n(a) square\r\n(b) parallelogram\r\n(c) quadrilateral\r\n(d) rectangle\n\r\n2. My favorite number is:\r\n(a) 5\r\n(b) 12\r\n(c) 7\r\n(d) one of the above\r\n(e) none of the above\r\n(f) 6\n\r\n3. My street number is:\r\n(a) 25\r\n(b) greater than 6\r\n(c) greater than 9\r\n(d) 7\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe key point of this teaser is that there is ONLY ONE correct answer to each question.\n\r\n1. Since a square is a type of rectangle, which is a type of parallelogram, which is a type of quadrilateral, then the only possible unique answer is (c), quadrilateral.\n\r\n2. Since answers of (a), (b), or (c) would also result in (d) being correct, and an answer of (f) would result in (e) also being correct, the only possible answer is (e). \r\n(in case you're wondering, my favorite number is 13)\n\r\n(3) Since 7, 25, and anything greater than 9 are also greater than 6, neither (a), (c), or (d) can be the answer because (b) would also be an answer. Therefore the answer must be (b), and assuming that only integers are used for numbering streets, my street number must be 8.\n<|im_start|>answer\nThe key point of this teaser is that there is ONLY ONE correct answer to each question.\n\r\n1. Since a square is a type of rectangle, which is a type of parallelogram, which is a type of quadrilateral, then the only possible unique answer is (c), quadrilateral.\n\r\n2. Since answers of (a), (b), or (c) would also result in (d) being correct, and an answer of (f) would result in (e) also being correct, the only possible answer is (e). \r\n(in case you're wondering, my favorite number is 13)\n\r\n(3) Since 7, 25, and anything greater than 9 are also greater than 6, neither (a), (c), or (d) can be the answer because (b) would also be an answer. Therefore the answer must be (b), and assuming that only integers are used for numbering streets, my street number must be 8.\n<|im_end|>" }, { "id": "#319", "title": "Philosophy, math and poets", "fun": 2.37, "difficulty": 2.0, "author": "Phyllis", "desc": "Are these 4 statements logically compatible?\r\n#1-Some mathematicians are philosophers.\r\n#2-Immortals are ignorant of philosophy\r\n#3-No poet practices mathematics.\r\n#4-All mortals are poets.", "hint": "No hint available.", "answer": "Start with the statement #2. If immortals are ignorant of philosophy, philosophers must be mortals, otherwise they would be ignorant of philosophy. Since statement #4 says all mortals are poets, philosophers must be poets. Since statement #3 says no poet practices mathematics, no philosopher does either. So, a mathematician cannot be a philosopher, which makes statement #1 inconsistent with the other 3 statements.", "category": "Logic", "date": "02/28/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAre these 4 statements logically compatible?\r\n#1-Some mathematicians are philosophers.\r\n#2-Immortals are ignorant of philosophy\r\n#3-No poet practices mathematics.\r\n#4-All mortals are poets.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStart with the statement #2. If immortals are ignorant of philosophy, philosophers must be mortals, otherwise they would be ignorant of philosophy. Since statement #4 says all mortals are poets, philosophers must be poets. Since statement #3 says no poet practices mathematics, no philosopher does either. So, a mathematician cannot be a philosopher, which makes statement #1 inconsistent with the other 3 statements.\n<|im_start|>answer\nStart with the statement #2. If immortals are ignorant of philosophy, philosophers must be mortals, otherwise they would be ignorant of philosophy. Since statement #4 says all mortals are poets, philosophers must be poets. Since statement #3 says no poet practices mathematics, no philosopher does either. So, a mathematician cannot be a philosopher, which makes statement #1 inconsistent with the other 3 statements.\n<|im_end|>" }, { "id": "#40026", "title": "Six Trees", "fun": 2.37, "difficulty": 1.36, "author": "shenqiang", "desc": "Six trees stand equally spaced along one side of a straight road. The distance from the first tree to the fourth is 60 feet. What is the distance in feet between the first and last trees?\n\r\nThe widths of the trees can be omitted.", "hint": "It is NOT 40 feet.\n\r\nHow many gaps exist between the first and the fourth trees?", "answer": "There are 3 gaps between the first and the fourth trees; therefore, each gap is 20 feet.\r\nThere are 5 gaps between the first and the last (i.e. sixth) trees, which is 100 feet.", "category": "Math", "date": "01/12/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix trees stand equally spaced along one side of a straight road. The distance from the first tree to the fourth is 60 feet. What is the distance in feet between the first and last trees?\n\r\nThe widths of the trees can be omitted.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 3 gaps between the first and the fourth trees; therefore, each gap is 20 feet.\r\nThere are 5 gaps between the first and the last (i.e. sixth) trees, which is 100 feet.\n<|im_start|>answer\nThere are 3 gaps between the first and the fourth trees; therefore, each gap is 20 feet.\r\nThere are 5 gaps between the first and the last (i.e. sixth) trees, which is 100 feet.\n<|im_end|>" }, { "id": "#9159", "title": "Shipwreck", "fun": 2.37, "difficulty": 1.46, "author": "glennyboy02", "desc": "Victims of a shipwreck were lost at sea. Due to strong waves they were all soon separated. Search parties quickly went out to find them. On the first day 1/6 of the survivors were found. The next day 1/5 of those still lost were found. On the third day 1/4 of those still lost were found. On the fourth day 1/3 of those still lost were found. 1/2 of those still lost were found on the fifth day, and on the sixth and last day the 3 remaining boatmen and boatwomen were found. \n\r\nHow many people were originally lost at sea?", "hint": "No hint available.", "answer": "There were 18 people originally lost at sea.\n\r\nThe amount of people remaining lost after each day is as follows:\n\r\nDAY 1 = 15\r\nDAY 2 = 12\r\nDAY 3 = 9\r\nDAY 4 = 6\r\nDAY 5 = 3\r\nDAY 6 = 0", "category": "Math", "date": "12/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nVictims of a shipwreck were lost at sea. Due to strong waves they were all soon separated. Search parties quickly went out to find them. On the first day 1/6 of the survivors were found. The next day 1/5 of those still lost were found. On the third day 1/4 of those still lost were found. On the fourth day 1/3 of those still lost were found. 1/2 of those still lost were found on the fifth day, and on the sixth and last day the 3 remaining boatmen and boatwomen were found. \n\r\nHow many people were originally lost at sea?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were 18 people originally lost at sea.\n\r\nThe amount of people remaining lost after each day is as follows:\n\r\nDAY 1 = 15\r\nDAY 2 = 12\r\nDAY 3 = 9\r\nDAY 4 = 6\r\nDAY 5 = 3\r\nDAY 6 = 0\n<|im_start|>answer\nThere were 18 people originally lost at sea.\n\r\nThe amount of people remaining lost after each day is as follows:\n\r\nDAY 1 = 15\r\nDAY 2 = 12\r\nDAY 3 = 9\r\nDAY 4 = 6\r\nDAY 5 = 3\r\nDAY 6 = 0\n<|im_end|>" }, { "id": "#29538", "title": "Simple Addition 2", "fun": 2.37, "difficulty": 1.93, "author": "Cogmatic", "desc": "What is in the one's digits place in the number that is the sum of 1+2+3+...+999,998+999,999+1,000,000?", "hint": "No hint available.", "answer": "Zero.\n\r\nBecause the sum contains the addition of the following sum in the one's digits place 100,000 times:\n\r\n0+1+2+3+4+5+6+7+8+9=45\n\r\nWe can deduce that:\n\r\n100,000 x 45 = 4,500,000\n\r\nand since 0 is in the one's digits place in this number, we can deduce that 0 is also in the one's digits place in the total sum since only the digits in the one's place can affect the number in the one's digits place.", "category": "Math", "date": "04/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is in the one's digits place in the number that is the sum of 1+2+3+...+999,998+999,999+1,000,000?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZero.\n\r\nBecause the sum contains the addition of the following sum in the one's digits place 100,000 times:\n\r\n0+1+2+3+4+5+6+7+8+9=45\n\r\nWe can deduce that:\n\r\n100,000 x 45 = 4,500,000\n\r\nand since 0 is in the one's digits place in this number, we can deduce that 0 is also in the one's digits place in the total sum since only the digits in the one's place can affect the number in the one's digits place.\n<|im_start|>answer\nZero.\n\r\nBecause the sum contains the addition of the following sum in the one's digits place 100,000 times:\n\r\n0+1+2+3+4+5+6+7+8+9=45\n\r\nWe can deduce that:\n\r\n100,000 x 45 = 4,500,000\n\r\nand since 0 is in the one's digits place in this number, we can deduce that 0 is also in the one's digits place in the total sum since only the digits in the one's place can affect the number in the one's digits place.\n<|im_end|>" }, { "id": "#42408", "title": "The NASCAR Race", "fun": 2.37, "difficulty": 1.31, "author": "nascarfan19", "desc": "5 drivers are in the Daytona 500. Each has made a late pit stop, and all finished the race.\n\r\nDrivers:\r\nJeff Gordon\r\nDale Earnhardt Jr.\r\nTony Stewart\r\nJimmie Johnson\r\nRyan Newman\n\r\nPit Stops:\r\n4 Tires\r\n2 Tires\r\nGas Only\r\nChassis Adjustment\r\nEngine Fix\n\r\n1. Jeff Gordon did not take a 2 tire change.\r\n2. Jimmie Johnson did not finish lower than 3rd.\r\n3. Tony Stewart had an engine problem before pit stops.\r\n4. Dale Jr. did not win the race.\r\n5. Jimmie Johnson already took tires earlier, so he did not need them.\r\n6. Ryan Newman needed a chassis adjustment.\r\n7. Ryan Newman's stop was short, so he did not finish lower than 3rd.\r\n8. Jimmie Johnson nearly spun on the last lap, costing him a position.\r\n9. Tony Stewart's engine problems continued and he ended up in 5th.\r\n10. Dale Jr. edged out Jeff Gordon at the finish line.", "hint": "Edged out means to come immediately before the other.", "answer": "Jeff Gordon: 4 Tires, 4th Place\r\nJimmie Johnson: Gas Only, 2nd Place\r\nDale Jr.: 2 Tires, 3rd Place\r\nRyan Newman: Chassis Adjustment, 1st Place\r\nTony Stewart: Engine Fix, 5th Place", "category": "Logic-Grid", "date": "07/03/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 drivers are in the Daytona 500. Each has made a late pit stop, and all finished the race.\n\r\nDrivers:\r\nJeff Gordon\r\nDale Earnhardt Jr.\r\nTony Stewart\r\nJimmie Johnson\r\nRyan Newman\n\r\nPit Stops:\r\n4 Tires\r\n2 Tires\r\nGas Only\r\nChassis Adjustment\r\nEngine Fix\n\r\n1. Jeff Gordon did not take a 2 tire change.\r\n2. Jimmie Johnson did not finish lower than 3rd.\r\n3. Tony Stewart had an engine problem before pit stops.\r\n4. Dale Jr. did not win the race.\r\n5. Jimmie Johnson already took tires earlier, so he did not need them.\r\n6. Ryan Newman needed a chassis adjustment.\r\n7. Ryan Newman's stop was short, so he did not finish lower than 3rd.\r\n8. Jimmie Johnson nearly spun on the last lap, costing him a position.\r\n9. Tony Stewart's engine problems continued and he ended up in 5th.\r\n10. Dale Jr. edged out Jeff Gordon at the finish line.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJeff Gordon: 4 Tires, 4th Place\r\nJimmie Johnson: Gas Only, 2nd Place\r\nDale Jr.: 2 Tires, 3rd Place\r\nRyan Newman: Chassis Adjustment, 1st Place\r\nTony Stewart: Engine Fix, 5th Place\n<|im_start|>answer\nJeff Gordon: 4 Tires, 4th Place\r\nJimmie Johnson: Gas Only, 2nd Place\r\nDale Jr.: 2 Tires, 3rd Place\r\nRyan Newman: Chassis Adjustment, 1st Place\r\nTony Stewart: Engine Fix, 5th Place\n<|im_end|>" }, { "id": "#32832", "title": "CrossDigit 3", "fun": 2.37, "difficulty": 2.22, "author": "dishu", "desc": "This teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digits. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are B4, C2, C3 and D3.\r\n2. The sum of digits in row A equal 10.\r\n3. The sum of digits in row B equal 21.\r\n4. The sum of digits in row C equal 12.\r\n5. The sum of digits in row D equal 19.\r\n6. The sum of digits in column 1 equal 10.\r\n7. The sum of digits in column 2 equal 19.\r\n8. The sum of digits in column 3 equal 13.\r\n9. The sum of digits in column 4 equal 20.\n\r\nNow figure out which box contains which digit and do not forget the rules.", "hint": "A number can be present more than once in the grid, but not the same row or column.", "answer": "The solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 2, A3: 4, A4: 3\r\nB1: 4, B2: 8, B3: 9, B4: Blank\r\nC1: 3, C2: Blank, C3: Blank, C4: 9\r\nD1: 2, D2:9, D3: Blank, D4: 8", "category": "Math", "date": "09/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digits. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are B4, C2, C3 and D3.\r\n2. The sum of digits in row A equal 10.\r\n3. The sum of digits in row B equal 21.\r\n4. The sum of digits in row C equal 12.\r\n5. The sum of digits in row D equal 19.\r\n6. The sum of digits in column 1 equal 10.\r\n7. The sum of digits in column 2 equal 19.\r\n8. The sum of digits in column 3 equal 13.\r\n9. The sum of digits in column 4 equal 20.\n\r\nNow figure out which box contains which digit and do not forget the rules.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 2, A3: 4, A4: 3\r\nB1: 4, B2: 8, B3: 9, B4: Blank\r\nC1: 3, C2: Blank, C3: Blank, C4: 9\r\nD1: 2, D2:9, D3: Blank, D4: 8\n<|im_start|>answer\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 2, A3: 4, A4: 3\r\nB1: 4, B2: 8, B3: 9, B4: Blank\r\nC1: 3, C2: Blank, C3: Blank, C4: 9\r\nD1: 2, D2:9, D3: Blank, D4: 8\n<|im_end|>" }, { "id": "#42120", "title": "Strange Connection", "fun": 2.37, "difficulty": 2.86, "author": "V_Bapat", "desc": "What is the connection between 567 and 854?", "hint": "Think about the magic of 9.", "answer": "SQUARE(567) = 321489\r\nSQUARE(854) = 729316\n\r\nBoth the equations use each of the digits 1 to 9 once each. These are the only two numbers with this property.", "category": "Math", "date": "06/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the connection between 567 and 854?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSQUARE(567) = 321489\r\nSQUARE(854) = 729316\n\r\nBoth the equations use each of the digits 1 to 9 once each. These are the only two numbers with this property.\n<|im_start|>answer\nSQUARE(567) = 321489\r\nSQUARE(854) = 729316\n\r\nBoth the equations use each of the digits 1 to 9 once each. These are the only two numbers with this property.\n<|im_end|>" }, { "id": "#48907", "title": "Mates + Dates - Easy", "fun": 2.37, "difficulty": 0.27, "author": "coolcat101202", "desc": "Three girls all got dates on the same day. From their texts, can you figure out which girl went with which guy and where they went on their dates.\n\r\nNames - Sarah, Natalie, Charlotte\r\nDates - Nick, Matt, Ben\r\nPlaces - park, movie, dinner\n\r\n5:45\r\nCan't believe how cold it is and the grass is all wet, yuck. It's okay though, Matt gave me his coat, I think he really likes me.\n\r\n8:34\r\nHey guys, hope you're having a better time than I am. Ben is such a bore, I don't think I'll be doing this again. xoxoxo love, Sarah oxoxox\n\r\n9:24\r\nWow, this movie is fantastic and he's just as into it as I am. I don't think it'd ever be as fun with a geek like Matt (no offence). I don't ever want this to end. Good luck on your dates, love Natalie", "hint": "I wouldn't want to go to the park on a date, it'd be cold and it might be wet.", "answer": "Charlotte had a fabulous time on her date with Matt, even if she did get a bit wet sitting on the grass at the park.\n\r\nSarah and Ben didn't really get on, but the dinner was good none the less.\n\r\nNatalie loved the movie and it was even better having Nick to hold on to at the scary parts.", "category": "Logic-Grid", "date": "08/01/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree girls all got dates on the same day. From their texts, can you figure out which girl went with which guy and where they went on their dates.\n\r\nNames - Sarah, Natalie, Charlotte\r\nDates - Nick, Matt, Ben\r\nPlaces - park, movie, dinner\n\r\n5:45\r\nCan't believe how cold it is and the grass is all wet, yuck. It's okay though, Matt gave me his coat, I think he really likes me.\n\r\n8:34\r\nHey guys, hope you're having a better time than I am. Ben is such a bore, I don't think I'll be doing this again. xoxoxo love, Sarah oxoxox\n\r\n9:24\r\nWow, this movie is fantastic and he's just as into it as I am. I don't think it'd ever be as fun with a geek like Matt (no offence). I don't ever want this to end. Good luck on your dates, love Natalie\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCharlotte had a fabulous time on her date with Matt, even if she did get a bit wet sitting on the grass at the park.\n\r\nSarah and Ben didn't really get on, but the dinner was good none the less.\n\r\nNatalie loved the movie and it was even better having Nick to hold on to at the scary parts.\n<|im_start|>answer\nCharlotte had a fabulous time on her date with Matt, even if she did get a bit wet sitting on the grass at the park.\n\r\nSarah and Ben didn't really get on, but the dinner was good none the less.\n\r\nNatalie loved the movie and it was even better having Nick to hold on to at the scary parts.\n<|im_end|>" }, { "id": "#4778", "title": "Leap Year", "fun": 2.37, "difficulty": 2.16, "author": "bobbrt", "desc": "The following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nYou want to be able to write \"leap year\" or \"not a leap year\" for any given year from 1801 to 2101, according to whether or not the given year had or will have 366 days in it. You must remember to take into account that years ending in 00 are leap years only if they are evenly divisible by 400 (thus, 1900 was not a leap year but 2000 was). Years ending in any other digits, of course, are leap years if and only if they are divisible by 4.\n\r\na) Divide the year by 100.\r\nb) Divide the year by 4.\r\nc) Read the year chosen (from 1801 to 2101).\r\nd) Divide the year by 400.\r\ne) Skip the next statement.\r\nf) If there is a remainder, skip the next two statements.\r\ng) If there is a remainder, skip the next two statements.\r\nh) If there is a remainder, skip the next six statements.\r\ni) Write \"leap year.\"\r\nj) Write \"not a leap year.\"\r\nk) End.", "hint": "No hint available.", "answer": "c) Read the year chosen (from 1801 to 2101).\r\nb) Divide the year by 4.\r\nh) If there is a remainder, skip the next six statements.\r\na) Divide the year by 100.\r\nf or g) If there is a remainder, skip the next two statements.\r\nd) Divide the year by 400.\r\nf or g) If there is a remainder, skip the next two statements.\r\ni) Write \"leap year.\"\r\ne) Skip the next statement.\r\nj) Write \"not a leap year.\"\r\nk) End.", "category": "Logic", "date": "06/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following task involves several steps, but they are out of order. Arrange them so that a person who follows the steps exactly can perform the task:\n\r\nYou want to be able to write \"leap year\" or \"not a leap year\" for any given year from 1801 to 2101, according to whether or not the given year had or will have 366 days in it. You must remember to take into account that years ending in 00 are leap years only if they are evenly divisible by 400 (thus, 1900 was not a leap year but 2000 was). Years ending in any other digits, of course, are leap years if and only if they are divisible by 4.\n\r\na) Divide the year by 100.\r\nb) Divide the year by 4.\r\nc) Read the year chosen (from 1801 to 2101).\r\nd) Divide the year by 400.\r\ne) Skip the next statement.\r\nf) If there is a remainder, skip the next two statements.\r\ng) If there is a remainder, skip the next two statements.\r\nh) If there is a remainder, skip the next six statements.\r\ni) Write \"leap year.\"\r\nj) Write \"not a leap year.\"\r\nk) End.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nc) Read the year chosen (from 1801 to 2101).\r\nb) Divide the year by 4.\r\nh) If there is a remainder, skip the next six statements.\r\na) Divide the year by 100.\r\nf or g) If there is a remainder, skip the next two statements.\r\nd) Divide the year by 400.\r\nf or g) If there is a remainder, skip the next two statements.\r\ni) Write \"leap year.\"\r\ne) Skip the next statement.\r\nj) Write \"not a leap year.\"\r\nk) End.\n<|im_start|>answer\nc) Read the year chosen (from 1801 to 2101).\r\nb) Divide the year by 4.\r\nh) If there is a remainder, skip the next six statements.\r\na) Divide the year by 100.\r\nf or g) If there is a remainder, skip the next two statements.\r\nd) Divide the year by 400.\r\nf or g) If there is a remainder, skip the next two statements.\r\ni) Write \"leap year.\"\r\ne) Skip the next statement.\r\nj) Write \"not a leap year.\"\r\nk) End.\n<|im_end|>" }, { "id": "#6294", "title": "Elevator stops", "fun": 2.37, "difficulty": 1.15, "author": "pilp07", "desc": "Katie went to visit her friends in their apartment building. \r\nShe took the elevator to the 4th floor to Randy's apartment. \r\nShe met Randy and they walked down 2 flights of stairs to Chrissy's apartment. \r\nThen Chrissy, Randy and Katie got in the elevator. They went up and passed 2 floors to meet Scott at his apartment. \r\nScott lives 1 floor below the top floor. \r\nWhat floor is on the top of the building?", "hint": "No hint available.", "answer": "There are 6 floors in the building. \r\nExplanation \n\r\nKatie took the elevator to the 4th floor to Randy's apartment. Now she is on the 4th floor. \r\nShe met Randy and they walked down 2 flights of stairs to Chrissy's apartment. Now they are on the 2nd floor. \r\nThen Chrissy, Randy and Katie got in the elevator. They went up and passed 2 floors to meet Scott at his apartment. They passed 2 floors. That means they went past floors 3 and 4, so now they are on the 5th floor. That means Scott lives on the 5th floor. \r\nScott lives 1 floor below the top floor. If Scott lives on the 5th floor, 1 floor above that is the 6th floor. \r\nThere are 6 floors in the building.", "category": "Math", "date": "08/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKatie went to visit her friends in their apartment building. \r\nShe took the elevator to the 4th floor to Randy's apartment. \r\nShe met Randy and they walked down 2 flights of stairs to Chrissy's apartment. \r\nThen Chrissy, Randy and Katie got in the elevator. They went up and passed 2 floors to meet Scott at his apartment. \r\nScott lives 1 floor below the top floor. \r\nWhat floor is on the top of the building?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 6 floors in the building. \r\nExplanation \n\r\nKatie took the elevator to the 4th floor to Randy's apartment. Now she is on the 4th floor. \r\nShe met Randy and they walked down 2 flights of stairs to Chrissy's apartment. Now they are on the 2nd floor. \r\nThen Chrissy, Randy and Katie got in the elevator. They went up and passed 2 floors to meet Scott at his apartment. They passed 2 floors. That means they went past floors 3 and 4, so now they are on the 5th floor. That means Scott lives on the 5th floor. \r\nScott lives 1 floor below the top floor. If Scott lives on the 5th floor, 1 floor above that is the 6th floor. \r\nThere are 6 floors in the building.\n<|im_start|>answer\nThere are 6 floors in the building. \r\nExplanation \n\r\nKatie took the elevator to the 4th floor to Randy's apartment. Now she is on the 4th floor. \r\nShe met Randy and they walked down 2 flights of stairs to Chrissy's apartment. Now they are on the 2nd floor. \r\nThen Chrissy, Randy and Katie got in the elevator. They went up and passed 2 floors to meet Scott at his apartment. They passed 2 floors. That means they went past floors 3 and 4, so now they are on the 5th floor. That means Scott lives on the 5th floor. \r\nScott lives 1 floor below the top floor. If Scott lives on the 5th floor, 1 floor above that is the 6th floor. \r\nThere are 6 floors in the building.\n<|im_end|>" }, { "id": "#4924", "title": "Can Can", "fun": 2.37, "difficulty": 2.18, "author": "mad-ade", "desc": "Mad Ade is hungry as usual, but unfortunately the Kebab shop is not open yet. As a result he decides to make himself an instant meal, the type where you just add boiling water. He needs to measure out a quarter litre of water.\r\nAfter a quick search Mad Ade finds that he doesn't possess any type of measuring jug. All he can find is an old baked bean tin that has a 1 litre capacity. Using only the old tin and a pen how can Mad Ade measure out the much needed quarter of litre of water?", "hint": "No hint available.", "answer": "Fill the can to over half full, and tip it so that the water runs out until it reaches just from the lip of the can to the edge of the base. Now the can is one half full. Tilt the can upright and mark it inside to show how far the water comes. Finally, tip out the water a bit at a time, until when tilted, the water goes from the mark you scratched to the edge of the bottom. This will give you a quarter of a litre.", "category": "Logic", "date": "06/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is hungry as usual, but unfortunately the Kebab shop is not open yet. As a result he decides to make himself an instant meal, the type where you just add boiling water. He needs to measure out a quarter litre of water.\r\nAfter a quick search Mad Ade finds that he doesn't possess any type of measuring jug. All he can find is an old baked bean tin that has a 1 litre capacity. Using only the old tin and a pen how can Mad Ade measure out the much needed quarter of litre of water?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFill the can to over half full, and tip it so that the water runs out until it reaches just from the lip of the can to the edge of the base. Now the can is one half full. Tilt the can upright and mark it inside to show how far the water comes. Finally, tip out the water a bit at a time, until when tilted, the water goes from the mark you scratched to the edge of the bottom. This will give you a quarter of a litre.\n<|im_start|>answer\nFill the can to over half full, and tip it so that the water runs out until it reaches just from the lip of the can to the edge of the base. Now the can is one half full. Tilt the can upright and mark it inside to show how far the water comes. Finally, tip out the water a bit at a time, until when tilted, the water goes from the mark you scratched to the edge of the bottom. This will give you a quarter of a litre.\n<|im_end|>" }, { "id": "#25807", "title": "Secret Word I", "fun": 2.37, "difficulty": 2.58, "author": "lisha_kc", "desc": "Find the secret 5 letter word (_ _ _ _ _) that shares:\n\r\n2 letters with MAGIC\r\n2 letters with YEARN\r\n2 letters with BLAME\r\n2 letters with GRABS\r\n2 letters with KARMA\r\n3 letters with BREAK\n\n\r\neg. strESSEs shares four letters with the word ESSEnce.", "hint": "The second letter of the first word is in the secret word.", "answer": "The secret word is CAKES.", "category": "Logic", "date": "09/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the secret 5 letter word (_ _ _ _ _) that shares:\n\r\n2 letters with MAGIC\r\n2 letters with YEARN\r\n2 letters with BLAME\r\n2 letters with GRABS\r\n2 letters with KARMA\r\n3 letters with BREAK\n\n\r\neg. strESSEs shares four letters with the word ESSEnce.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe secret word is CAKES.\n<|im_start|>answer\nThe secret word is CAKES.\n<|im_end|>" }, { "id": "#8345", "title": "Deck", "fun": 2.37, "difficulty": 0.86, "author": "tissue", "desc": "Three playing cards are laying face up, side by side. A King is just to the right of a Queen. A King is directly to the left of a King. A Diamond is to the left of a Heart, and a Diamond is just to the right of a Diamond. What are the three cards?", "hint": "No hint available.", "answer": "Queen of Diamonds, King of Diamonds, King of Hearts.", "category": "Logic", "date": "11/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree playing cards are laying face up, side by side. A King is just to the right of a Queen. A King is directly to the left of a King. A Diamond is to the left of a Heart, and a Diamond is just to the right of a Diamond. What are the three cards?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nQueen of Diamonds, King of Diamonds, King of Hearts.\n<|im_start|>answer\nQueen of Diamonds, King of Diamonds, King of Hearts.\n<|im_end|>" }, { "id": "#7646", "title": "Liar Liar", "fun": 2.37, "difficulty": 2.5, "author": "mad-ade", "desc": "Mad Ade's cousin Steve lies a lot. He tells the truth on only one day in a week. \n\r\nOne day he said: \"I lie on Mondays and Tuesdays.\" \r\nThe next day he said: \"Today is either Sunday, Saturday, or Thursday.\" \r\nThe next day he said: \"I lie on Fridays and Wednesdays.\" \n\r\nOn which day of the week does Steve tell the truth?", "hint": "No hint available.", "answer": "Mad Ade's cousin Steve tells the truth on Tuesdays\r\nThe first and third statements are incompatible; they cannot of course both be true, and they can only be lies if on one of the days mentioned Steve tells the truth. But, they have no such day in common. Therefore one of them must be true, and the other must refer to that day. Looking at the second statement (which must be a lie, as there can at most be one true statement and we have one), the first day cannot be Wednesday, Friday or Saturday. Therefore, the first statement cannot be true, since the third cannot refer to it by day. Therefore, the third statement is true, and must (from the first statement) be a Monday or Tuesday. Statement two, however, rules out Monday, leaving only Tuesday as the 'day of truth'. Thus: 'one day' is a Sunday; on the third day (Tuesday) Steve is truthful.", "category": "Logic", "date": "09/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's cousin Steve lies a lot. He tells the truth on only one day in a week. \n\r\nOne day he said: \"I lie on Mondays and Tuesdays.\" \r\nThe next day he said: \"Today is either Sunday, Saturday, or Thursday.\" \r\nThe next day he said: \"I lie on Fridays and Wednesdays.\" \n\r\nOn which day of the week does Steve tell the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade's cousin Steve tells the truth on Tuesdays\r\nThe first and third statements are incompatible; they cannot of course both be true, and they can only be lies if on one of the days mentioned Steve tells the truth. But, they have no such day in common. Therefore one of them must be true, and the other must refer to that day. Looking at the second statement (which must be a lie, as there can at most be one true statement and we have one), the first day cannot be Wednesday, Friday or Saturday. Therefore, the first statement cannot be true, since the third cannot refer to it by day. Therefore, the third statement is true, and must (from the first statement) be a Monday or Tuesday. Statement two, however, rules out Monday, leaving only Tuesday as the 'day of truth'. Thus: 'one day' is a Sunday; on the third day (Tuesday) Steve is truthful.\n<|im_start|>answer\nMad Ade's cousin Steve tells the truth on Tuesdays\r\nThe first and third statements are incompatible; they cannot of course both be true, and they can only be lies if on one of the days mentioned Steve tells the truth. But, they have no such day in common. Therefore one of them must be true, and the other must refer to that day. Looking at the second statement (which must be a lie, as there can at most be one true statement and we have one), the first day cannot be Wednesday, Friday or Saturday. Therefore, the first statement cannot be true, since the third cannot refer to it by day. Therefore, the third statement is true, and must (from the first statement) be a Monday or Tuesday. Statement two, however, rules out Monday, leaving only Tuesday as the 'day of truth'. Thus: 'one day' is a Sunday; on the third day (Tuesday) Steve is truthful.\n<|im_end|>" }, { "id": "#32833", "title": "CrossDigit 4", "fun": 2.37, "difficulty": 2.22, "author": "dishu", "desc": "This teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digits. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are B3, C2, C4 and D4.\r\n2. The sum of digits in row A equal 11.\r\n3. The sum of digits in row B equal 22.\r\n4. The sum of digits in row C equal 12.\r\n5. The sum of digits in row D equal 17.\r\n6. The sum of digits in column 1 equal 11.\r\n7. The sum of digits in column 2 equal 18.\r\n8. The sum of digits in column 3 equal 20.\r\n9. The sum of digits in column 4 equal 13.\n\r\nNow figure out which box contains which digit and do not forget the rules.", "hint": "A number can be present more than once in the grid, but not the same row or column.", "answer": "The solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 2, A3: 3, A4: 5\r\nB1: 5, B2: 9, B3: Blank, B4: 8\r\nC1: 3, C2: Blank, C3: 9, C4: Blank\r\nD1: 2, D2:7, D3: 8, D4: Blank", "category": "Math", "date": "09/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digits. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are B3, C2, C4 and D4.\r\n2. The sum of digits in row A equal 11.\r\n3. The sum of digits in row B equal 22.\r\n4. The sum of digits in row C equal 12.\r\n5. The sum of digits in row D equal 17.\r\n6. The sum of digits in column 1 equal 11.\r\n7. The sum of digits in column 2 equal 18.\r\n8. The sum of digits in column 3 equal 20.\r\n9. The sum of digits in column 4 equal 13.\n\r\nNow figure out which box contains which digit and do not forget the rules.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 2, A3: 3, A4: 5\r\nB1: 5, B2: 9, B3: Blank, B4: 8\r\nC1: 3, C2: Blank, C3: 9, C4: Blank\r\nD1: 2, D2:7, D3: 8, D4: Blank\n<|im_start|>answer\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 2, A3: 3, A4: 5\r\nB1: 5, B2: 9, B3: Blank, B4: 8\r\nC1: 3, C2: Blank, C3: 9, C4: Blank\r\nD1: 2, D2:7, D3: 8, D4: Blank\n<|im_end|>" }, { "id": "#5495", "title": "Crazy Shoe Store", "fun": 2.37, "difficulty": 1.96, "author": "speedymcg", "desc": "The following were the prices of items in a store:\r\nSHOES..........$6\r\nBOOTS..........$4\r\nSANDALS........$6\r\nSLIPPERS.......$6\r\nWhat is the pattern and how much would SOCKS cost?", "hint": "to find out PART of the pattern, note the letter that appears a lot.", "answer": "The pattern...\r\nS = 2$\r\nany vowel= 1$\n\r\nSOCKS would cost 5$", "category": "Math", "date": "07/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following were the prices of items in a store:\r\nSHOES..........$6\r\nBOOTS..........$4\r\nSANDALS........$6\r\nSLIPPERS.......$6\r\nWhat is the pattern and how much would SOCKS cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pattern...\r\nS = 2$\r\nany vowel= 1$\n\r\nSOCKS would cost 5$\n<|im_start|>answer\nThe pattern...\r\nS = 2$\r\nany vowel= 1$\n\r\nSOCKS would cost 5$\n<|im_end|>" }, { "id": "#48574", "title": "The Number X", "fun": 2.37, "difficulty": 1.24, "author": "shenqiang", "desc": "What is the number X?\n\r\nXXXX+XX+X+X+X=9000", "hint": "No hint available.", "answer": "X is 8.", "category": "Math", "date": "03/20/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the number X?\n\r\nXXXX+XX+X+X+X=9000\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nX is 8.\n<|im_start|>answer\nX is 8.\n<|im_end|>" }, { "id": "#2855", "title": "Escape", "fun": 2.36, "difficulty": 1.76, "author": "204_BLaZe_41", "desc": "Jay escaped from jail and headed to the country. While walking along a rural road, he saw a police car speeding towards him. Jay ran toward it for a short time and then fled into the woods. Why did he run toward the car?", "hint": "No hint available.", "answer": "Jay was just starting to cross a bridge when he saw a police car. He ran toward the car to get off the bridge before running into the woods.", "category": "Logic", "date": "03/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJay escaped from jail and headed to the country. While walking along a rural road, he saw a police car speeding towards him. Jay ran toward it for a short time and then fled into the woods. Why did he run toward the car?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJay was just starting to cross a bridge when he saw a police car. He ran toward the car to get off the bridge before running into the woods.\n<|im_start|>answer\nJay was just starting to cross a bridge when he saw a police car. He ran toward the car to get off the bridge before running into the woods.\n<|im_end|>" }, { "id": "#40647", "title": "Simple Sums", "fun": 2.36, "difficulty": 2.39, "author": "psychoserenity", "desc": "If 527 - 142 = 345\r\nAnd 901 + 522 = 223\r\nThen 148 - 253 = ?", "hint": "Time for a little smackerel of something!", "answer": "In the first sum the answer is 40 less than it should be suggesting that the ten's digit rolled over at 60 instead of 100.\r\nThe second sum shows that the numbers reset at 1200 and that the numbers are based on a twelve hour clock.\r\nSo the answer for the final sum is 1055 or five minutes to eleven.\r\nExtra points to anyone who got the Winnie-the-Pooh reference in the hint.", "category": "Math", "date": "02/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 527 - 142 = 345\r\nAnd 901 + 522 = 223\r\nThen 148 - 253 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn the first sum the answer is 40 less than it should be suggesting that the ten's digit rolled over at 60 instead of 100.\r\nThe second sum shows that the numbers reset at 1200 and that the numbers are based on a twelve hour clock.\r\nSo the answer for the final sum is 1055 or five minutes to eleven.\r\nExtra points to anyone who got the Winnie-the-Pooh reference in the hint.\n<|im_start|>answer\nIn the first sum the answer is 40 less than it should be suggesting that the ten's digit rolled over at 60 instead of 100.\r\nThe second sum shows that the numbers reset at 1200 and that the numbers are based on a twelve hour clock.\r\nSo the answer for the final sum is 1055 or five minutes to eleven.\r\nExtra points to anyone who got the Winnie-the-Pooh reference in the hint.\n<|im_end|>" }, { "id": "#26203", "title": "Antique Jewelry", "fun": 2.36, "difficulty": 2.32, "author": "dogboy", "desc": "Three pieces of antique jewelry - a locket, a pin, and a ring - have ages whose sum is 310 years. The sum of 2 times the age of the locket 5 years ago and the age of the pin 10 years ago is 240 years. The difference between 3 times the locket's age in 3 years and 2 times the ring's age 4 years ago is 0. Find the ages of the locket, the pin, and the ring.", "hint": "The equation system is one of three open sentences each having three placeholders.", "answer": "Locket=L\r\nPin=P\r\nRing=R\n\r\nL+P+R=310 (equation 1)\r\n2L+P=260 (equation 2)\r\n3L-2R=-17 (equation 3)\n\r\nCombine equations 1 and 2, and multiply equation 2 by -1.\r\nL+P+R=310\r\n-2L-P=-260\r\n____________\r\n-L+R=50\n\n\r\nNow multiply the new equation by 2 and combine it with equation 3.\r\n3L-2R=-17\r\n-2L+2R=100\r\n____________\r\nL=83 \n\r\nSo the locket is 83 years old.\n\r\nNow substitute the value for \"L\" into the original equation 2.\r\n2L+P=260\r\n2(83)+P=260\r\n166+P=260\r\nP=94\n\r\nSo the pin is 94 years old.\n\r\nFor the final step substitute the locket's age into the original equation 3 to get the ring's age.\n\r\n3L-2R=-17\r\n3(83)-2R=-17\r\n249-2R=-17\r\nR=133\n\r\nSo the ring is 133 years old.\n\r\nAdd the three values to verify:\n\r\n83+94+133=310", "category": "Math", "date": "10/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree pieces of antique jewelry - a locket, a pin, and a ring - have ages whose sum is 310 years. The sum of 2 times the age of the locket 5 years ago and the age of the pin 10 years ago is 240 years. The difference between 3 times the locket's age in 3 years and 2 times the ring's age 4 years ago is 0. Find the ages of the locket, the pin, and the ring.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLocket=L\r\nPin=P\r\nRing=R\n\r\nL+P+R=310 (equation 1)\r\n2L+P=260 (equation 2)\r\n3L-2R=-17 (equation 3)\n\r\nCombine equations 1 and 2, and multiply equation 2 by -1.\r\nL+P+R=310\r\n-2L-P=-260\r\n____________\r\n-L+R=50\n\n\r\nNow multiply the new equation by 2 and combine it with equation 3.\r\n3L-2R=-17\r\n-2L+2R=100\r\n____________\r\nL=83 \n\r\nSo the locket is 83 years old.\n\r\nNow substitute the value for \"L\" into the original equation 2.\r\n2L+P=260\r\n2(83)+P=260\r\n166+P=260\r\nP=94\n\r\nSo the pin is 94 years old.\n\r\nFor the final step substitute the locket's age into the original equation 3 to get the ring's age.\n\r\n3L-2R=-17\r\n3(83)-2R=-17\r\n249-2R=-17\r\nR=133\n\r\nSo the ring is 133 years old.\n\r\nAdd the three values to verify:\n\r\n83+94+133=310\n<|im_start|>answer\nLocket=L\r\nPin=P\r\nRing=R\n\r\nL+P+R=310 (equation 1)\r\n2L+P=260 (equation 2)\r\n3L-2R=-17 (equation 3)\n\r\nCombine equations 1 and 2, and multiply equation 2 by -1.\r\nL+P+R=310\r\n-2L-P=-260\r\n____________\r\n-L+R=50\n\n\r\nNow multiply the new equation by 2 and combine it with equation 3.\r\n3L-2R=-17\r\n-2L+2R=100\r\n____________\r\nL=83 \n\r\nSo the locket is 83 years old.\n\r\nNow substitute the value for \"L\" into the original equation 2.\r\n2L+P=260\r\n2(83)+P=260\r\n166+P=260\r\nP=94\n\r\nSo the pin is 94 years old.\n\r\nFor the final step substitute the locket's age into the original equation 3 to get the ring's age.\n\r\n3L-2R=-17\r\n3(83)-2R=-17\r\n249-2R=-17\r\nR=133\n\r\nSo the ring is 133 years old.\n\r\nAdd the three values to verify:\n\r\n83+94+133=310\n<|im_end|>" }, { "id": "#44548", "title": "Vampire Novels", "fun": 2.36, "difficulty": 1.44, "author": "braintwister95", "desc": "Five friends had vampire obsessions. They were talking about their favorite vampire series when they started fighting about which was the best. One of their other friends was listening and soon got very confused. He doesn't know who wrote which series, who was the main character, or who liked which book. Help him match them up before he gets hurt.\n\r\nGirls: Lisa, Jen, Allison, Dalice, Whitley\r\nSeries: Twilight, House of Night, Vampire Kisses, Vampire Diaries, Vampire Academy\r\nAuthor: L.J. Smith, Ellen Schreiber, Stephenie Meyer, Richelle Mead, P.C. & Kristin Cast\r\nFirst Names: Rose, Isabella, Zoey, Elena, Raven\r\nLast Names: Redbird, Madison, Swan, Gilbert, Hathaway\n\r\n1. Whitley's favorite series does not have vampire in the title.\n\r\n2. The girls are: Dalice, the one who likes L.J. Smith, the one who likes Zoey Redbird, the one who likes Vampire Academy, and Whitley.\n\r\n3. Allison, who loves the House of Night series, dislikes Ellen Schreiber, Dalice's favorite.\n\r\n4.The series are: Jen's favorite, Vampire Kisses, the one Stephenie Meyer wrote, the one starring Zoey Redbird, and Vampire Academy.\n\r\n5. Lisa's first name starts with the same letter as Jen's favorite author, whose character is Elena, whose last name is not Swan or Madison.\n\r\n6. The characters are: Isabella Swan, the one created by the Casts, Lisa's favorite, the one in Vampire Diaries, and Dalice's favorite, whose last name is Madison.\n\r\n7. Allison loves the series that was authored by two people, but Lisa prefers Rose Hathaway.", "hint": "Allison, House of Night, P.C. & Kristin Cast, Zoey Redbird.", "answer": "Girl, series, author, main character\r\nLisa, Vampire Academy, Richelle Mead, Rose Hathaway.\r\nJen, Vampire Diaries, L.J. Smith, Elena Gilbert\r\nAllison, House of Night, P.C. & Kristin Cast, Zoey Redbird.\r\nDalice, Vampire Kisses, Ellen Schreiber, Raven Madison.\r\nWhitley, Twilight, Stephenie Meyer, Isabella Swan.", "category": "Logic-Grid", "date": "05/29/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive friends had vampire obsessions. They were talking about their favorite vampire series when they started fighting about which was the best. One of their other friends was listening and soon got very confused. He doesn't know who wrote which series, who was the main character, or who liked which book. Help him match them up before he gets hurt.\n\r\nGirls: Lisa, Jen, Allison, Dalice, Whitley\r\nSeries: Twilight, House of Night, Vampire Kisses, Vampire Diaries, Vampire Academy\r\nAuthor: L.J. Smith, Ellen Schreiber, Stephenie Meyer, Richelle Mead, P.C. & Kristin Cast\r\nFirst Names: Rose, Isabella, Zoey, Elena, Raven\r\nLast Names: Redbird, Madison, Swan, Gilbert, Hathaway\n\r\n1. Whitley's favorite series does not have vampire in the title.\n\r\n2. The girls are: Dalice, the one who likes L.J. Smith, the one who likes Zoey Redbird, the one who likes Vampire Academy, and Whitley.\n\r\n3. Allison, who loves the House of Night series, dislikes Ellen Schreiber, Dalice's favorite.\n\r\n4.The series are: Jen's favorite, Vampire Kisses, the one Stephenie Meyer wrote, the one starring Zoey Redbird, and Vampire Academy.\n\r\n5. Lisa's first name starts with the same letter as Jen's favorite author, whose character is Elena, whose last name is not Swan or Madison.\n\r\n6. The characters are: Isabella Swan, the one created by the Casts, Lisa's favorite, the one in Vampire Diaries, and Dalice's favorite, whose last name is Madison.\n\r\n7. Allison loves the series that was authored by two people, but Lisa prefers Rose Hathaway.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGirl, series, author, main character\r\nLisa, Vampire Academy, Richelle Mead, Rose Hathaway.\r\nJen, Vampire Diaries, L.J. Smith, Elena Gilbert\r\nAllison, House of Night, P.C. & Kristin Cast, Zoey Redbird.\r\nDalice, Vampire Kisses, Ellen Schreiber, Raven Madison.\r\nWhitley, Twilight, Stephenie Meyer, Isabella Swan.\n<|im_start|>answer\nGirl, series, author, main character\r\nLisa, Vampire Academy, Richelle Mead, Rose Hathaway.\r\nJen, Vampire Diaries, L.J. Smith, Elena Gilbert\r\nAllison, House of Night, P.C. & Kristin Cast, Zoey Redbird.\r\nDalice, Vampire Kisses, Ellen Schreiber, Raven Madison.\r\nWhitley, Twilight, Stephenie Meyer, Isabella Swan.\n<|im_end|>" }, { "id": "#5093", "title": "Common Cents", "fun": 2.36, "difficulty": 2.27, "author": "peppermintwist", "desc": "Eric, Rebecca, Jenny, and Mitch each have $1.00 in coins.\n\r\nNobody has pennies\r\nEveryone has at least one quarter\r\nEach person has a different number of quarters\r\nMitch has six times as many nickels as Rebecca\r\nRebecca has twice as many dimes as Eric\r\nEric has fewer nickels than Rebecca\n\r\nHow many, and which, coins do each have?", "hint": "No hint available.", "answer": "Jenny- four quarters\r\nEric- three quarters, two dimes, one nickel\r\nRebecca- two quarters, four dimes, two nickels\r\nMitch- one quarter, eleven nickels, two dimes", "category": "Logic", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEric, Rebecca, Jenny, and Mitch each have $1.00 in coins.\n\r\nNobody has pennies\r\nEveryone has at least one quarter\r\nEach person has a different number of quarters\r\nMitch has six times as many nickels as Rebecca\r\nRebecca has twice as many dimes as Eric\r\nEric has fewer nickels than Rebecca\n\r\nHow many, and which, coins do each have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJenny- four quarters\r\nEric- three quarters, two dimes, one nickel\r\nRebecca- two quarters, four dimes, two nickels\r\nMitch- one quarter, eleven nickels, two dimes\n<|im_start|>answer\nJenny- four quarters\r\nEric- three quarters, two dimes, one nickel\r\nRebecca- two quarters, four dimes, two nickels\r\nMitch- one quarter, eleven nickels, two dimes\n<|im_end|>" }, { "id": "#4445", "title": "Damaged Art", "fun": 2.36, "difficulty": 2.12, "author": "mad-ade", "desc": "Mad Ade's Uncle, Phil Space, who doesn't like what passes for art these days, ran into the National Gallery and caused millions of pounds of damage to several masterpieces. Later that day, Uncle Phil was invited to meet the manager and was warmly thanked for his actions.\n\r\nHow come?", "hint": "No hint available.", "answer": "Uncle Phil is a fireman. The water from his hose damaged the paintings as he put out a fire in the Gallery, but in the process rescuing hundreds of millions of pounds worth.", "category": "Logic", "date": "06/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Uncle, Phil Space, who doesn't like what passes for art these days, ran into the National Gallery and caused millions of pounds of damage to several masterpieces. Later that day, Uncle Phil was invited to meet the manager and was warmly thanked for his actions.\n\r\nHow come?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUncle Phil is a fireman. The water from his hose damaged the paintings as he put out a fire in the Gallery, but in the process rescuing hundreds of millions of pounds worth.\n<|im_start|>answer\nUncle Phil is a fireman. The water from his hose damaged the paintings as he put out a fire in the Gallery, but in the process rescuing hundreds of millions of pounds worth.\n<|im_end|>" }, { "id": "#29016", "title": "Opposites 15", "fun": 2.36, "difficulty": 2.21, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n^ stands for M, O, I, U, or W\r\nV stands for Y, U, F, E, or L\r\n< stands for H, E, B, K, or T\r\n> stands for J, A, G, N, or P\n\n\r\nThe four letter code word, <^>V, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Huge and Tiny", "category": "Logic", "date": "03/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n^ stands for M, O, I, U, or W\r\nV stands for Y, U, F, E, or L\r\n< stands for H, E, B, K, or T\r\n> stands for J, A, G, N, or P\n\n\r\nThe four letter code word, <^>V, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHuge and Tiny\n<|im_start|>answer\nHuge and Tiny\n<|im_end|>" }, { "id": "#27932", "title": "Are You Ready For Some Football?", "fun": 2.36, "difficulty": 2.3, "author": "bigSWAFF_69_", "desc": "Swaff finished up watching a game of American Football when his older brother Abjar walked in. Abjar asked what the score was:\n\r\nSwaff replied: \"It was 20 to 0\"\n\r\nAbjar was excited, because his team had won in a shut-out. Being the curious dude that he was, Abjar asked Swaff how they amassed 20 points.\n\r\nSwaff wanted to have some fun, and told Abjar to guess.\n\r\nAbjar decided he must first list ALL the possibilities of scoring 20 points, then pick the one that seems the most reasonable.\n\r\nHow many different possibilities could Abjar come up with? (Assuming that anything at all can happen, within the rules of American Football)", "hint": "In American Football, you can score a few ways:\n\r\n6 points for a touchdown\r\n-after a touchdown you have the option to go for 1 or 2 extra points.\n\r\n3 points for a field goal\n\r\n2 points for a safety", "answer": "Abjar could come up with 24 different ways.\n\r\nThe 24 Options for Scoring are:\n\r\nThree touchdowns(18), one safety(2) =20\n\r\nThree touchdowns(18), one 2 point extra point(2) =20\n\r\nThree touchdowns(18), two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), four safeties(8) =20\n\r\nTwo touchdowns(12), three safeties(6), one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), three safeties(6), two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), two safeties(4), two 2 point extra points(4) =20\n\r\nTwo touchdowns(12), one safety(2), two field goals(6) =20\n\r\nTwo touchdowns(12), one safety(2), one field goal(3), one 1 point extra point(1), one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), two field goals(6) two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), two field goals(6) one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), two safeties(4), one field goal(3), one 1 point extra point(1) =20\n\r\nOne touchdown(6), seven safeties(14) =20\n\r\nOne touchdown(6), six safeties(12), one 2 point extra point(2) =20\n\r\nOne touchdown(6), five safeties(10), one field goal(3), one 1 point extra point(1) =20\n\r\nOne touchdown(6), four safeties(8), two field goals(6) =20\n\r\nOne touchdown(6), three safeties(6), one 2 point extra point(2), two field goals(6) =20\n\r\nOne touchdown(6), two safeties(4), one 1 point extra point(1), three field goals(9) =20\n\r\nOne touchdown(6), one safety(2), 4 field goals(12) =20\n\r\nOne touchdown(6), one 2 point extra point(2), 4 field goals(12) =20\n\r\nTen safeties =20\n\r\nSeven safeties(14), two field goals(6) =20\n\r\nFour safeties(8), four field goals(12) = 20\n\r\nOne safety(2), six field goals(18) =20", "category": "Math", "date": "01/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSwaff finished up watching a game of American Football when his older brother Abjar walked in. Abjar asked what the score was:\n\r\nSwaff replied: \"It was 20 to 0\"\n\r\nAbjar was excited, because his team had won in a shut-out. Being the curious dude that he was, Abjar asked Swaff how they amassed 20 points.\n\r\nSwaff wanted to have some fun, and told Abjar to guess.\n\r\nAbjar decided he must first list ALL the possibilities of scoring 20 points, then pick the one that seems the most reasonable.\n\r\nHow many different possibilities could Abjar come up with? (Assuming that anything at all can happen, within the rules of American Football)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbjar could come up with 24 different ways.\n\r\nThe 24 Options for Scoring are:\n\r\nThree touchdowns(18), one safety(2) =20\n\r\nThree touchdowns(18), one 2 point extra point(2) =20\n\r\nThree touchdowns(18), two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), four safeties(8) =20\n\r\nTwo touchdowns(12), three safeties(6), one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), three safeties(6), two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), two safeties(4), two 2 point extra points(4) =20\n\r\nTwo touchdowns(12), one safety(2), two field goals(6) =20\n\r\nTwo touchdowns(12), one safety(2), one field goal(3), one 1 point extra point(1), one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), two field goals(6) two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), two field goals(6) one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), two safeties(4), one field goal(3), one 1 point extra point(1) =20\n\r\nOne touchdown(6), seven safeties(14) =20\n\r\nOne touchdown(6), six safeties(12), one 2 point extra point(2) =20\n\r\nOne touchdown(6), five safeties(10), one field goal(3), one 1 point extra point(1) =20\n\r\nOne touchdown(6), four safeties(8), two field goals(6) =20\n\r\nOne touchdown(6), three safeties(6), one 2 point extra point(2), two field goals(6) =20\n\r\nOne touchdown(6), two safeties(4), one 1 point extra point(1), three field goals(9) =20\n\r\nOne touchdown(6), one safety(2), 4 field goals(12) =20\n\r\nOne touchdown(6), one 2 point extra point(2), 4 field goals(12) =20\n\r\nTen safeties =20\n\r\nSeven safeties(14), two field goals(6) =20\n\r\nFour safeties(8), four field goals(12) = 20\n\r\nOne safety(2), six field goals(18) =20\n<|im_start|>answer\nAbjar could come up with 24 different ways.\n\r\nThe 24 Options for Scoring are:\n\r\nThree touchdowns(18), one safety(2) =20\n\r\nThree touchdowns(18), one 2 point extra point(2) =20\n\r\nThree touchdowns(18), two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), four safeties(8) =20\n\r\nTwo touchdowns(12), three safeties(6), one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), three safeties(6), two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), two safeties(4), two 2 point extra points(4) =20\n\r\nTwo touchdowns(12), one safety(2), two field goals(6) =20\n\r\nTwo touchdowns(12), one safety(2), one field goal(3), one 1 point extra point(1), one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), two field goals(6) two 1 point extra points(2) =20\n\r\nTwo touchdowns(12), two field goals(6) one 2 point extra point(2) =20\n\r\nTwo touchdowns(12), two safeties(4), one field goal(3), one 1 point extra point(1) =20\n\r\nOne touchdown(6), seven safeties(14) =20\n\r\nOne touchdown(6), six safeties(12), one 2 point extra point(2) =20\n\r\nOne touchdown(6), five safeties(10), one field goal(3), one 1 point extra point(1) =20\n\r\nOne touchdown(6), four safeties(8), two field goals(6) =20\n\r\nOne touchdown(6), three safeties(6), one 2 point extra point(2), two field goals(6) =20\n\r\nOne touchdown(6), two safeties(4), one 1 point extra point(1), three field goals(9) =20\n\r\nOne touchdown(6), one safety(2), 4 field goals(12) =20\n\r\nOne touchdown(6), one 2 point extra point(2), 4 field goals(12) =20\n\r\nTen safeties =20\n\r\nSeven safeties(14), two field goals(6) =20\n\r\nFour safeties(8), four field goals(12) = 20\n\r\nOne safety(2), six field goals(18) =20\n<|im_end|>" }, { "id": "#28608", "title": "Population of Tibet", "fun": 2.36, "difficulty": 2.66, "author": "Draw", "desc": "My computer has been up to its usual tricks again. I wanted to know the population of some major countries and here are the results: \n\r\nUSA 130,000\r\nEngland 410,000\r\nFrance 340,000\r\nPeru 200,000\r\nBrazil 340,000\r\nGreece 300,000\r\nJapan 270,000 \n\r\nHow many people were listed as living in Tibet?", "hint": "No hint available.", "answer": "270,000 people.\n\r\nEach vowel is worth 3 and each consonant is worth 7, these are added together and then multiplied by 10000. Therefore, Tibet has 2v + 3c = 2 * 3 + 3 * 7 = 27, therefore 270,000 people.", "category": "Math", "date": "02/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy computer has been up to its usual tricks again. I wanted to know the population of some major countries and here are the results: \n\r\nUSA 130,000\r\nEngland 410,000\r\nFrance 340,000\r\nPeru 200,000\r\nBrazil 340,000\r\nGreece 300,000\r\nJapan 270,000 \n\r\nHow many people were listed as living in Tibet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n270,000 people.\n\r\nEach vowel is worth 3 and each consonant is worth 7, these are added together and then multiplied by 10000. Therefore, Tibet has 2v + 3c = 2 * 3 + 3 * 7 = 27, therefore 270,000 people.\n<|im_start|>answer\n270,000 people.\n\r\nEach vowel is worth 3 and each consonant is worth 7, these are added together and then multiplied by 10000. Therefore, Tibet has 2v + 3c = 2 * 3 + 3 * 7 = 27, therefore 270,000 people.\n<|im_end|>" }, { "id": "#5502", "title": "One Fifth", "fun": 2.36, "difficulty": 2.5, "author": "im_para_noid", "desc": "Arrange the digits 0, 1, 1, 2, 3, 4, 6, and 7 to form a single fraction that equals 1/5\r\n(Here is one expression, which, alas, is not true: 101/23467 = 1/5)", "hint": "No hint available.", "answer": "1234/6170=1/5\n\r\nwith others that also work", "category": "Math", "date": "07/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the digits 0, 1, 1, 2, 3, 4, 6, and 7 to form a single fraction that equals 1/5\r\n(Here is one expression, which, alas, is not true: 101/23467 = 1/5)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1234/6170=1/5\n\r\nwith others that also work\n<|im_start|>answer\n1234/6170=1/5\n\r\nwith others that also work\n<|im_end|>" }, { "id": "#1859", "title": "Lots of Fives", "fun": 2.36, "difficulty": 2.17, "author": "jokester8000", "desc": "Fill in the blanks to make the equation work:\n\r\n5 55 55 5 555=599", "hint": "No hint available.", "answer": "(5*55-55)/5+555=599", "category": "Math", "date": "12/24/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFill in the blanks to make the equation work:\n\r\n5 55 55 5 555=599\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(5*55-55)/5+555=599\n<|im_start|>answer\n(5*55-55)/5+555=599\n<|im_end|>" }, { "id": "#2469", "title": "Basketball Bet", "fun": 2.36, "difficulty": 1.3800000000000001, "author": "lil_thugsta", "desc": "James bets Paul $1.00 that he could guess the score of the basketball game before it starts. Paul agrees, but loses the bet. Why did Paul lose the bet?", "hint": "No hint available.", "answer": "James said the score would be 0-0 and he was right. \"Before\" any basketball game starts, the score is always 0-0.", "category": "Logic", "date": "03/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJames bets Paul $1.00 that he could guess the score of the basketball game before it starts. Paul agrees, but loses the bet. Why did Paul lose the bet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJames said the score would be 0-0 and he was right. \"Before\" any basketball game starts, the score is always 0-0.\n<|im_start|>answer\nJames said the score would be 0-0 and he was right. \"Before\" any basketball game starts, the score is always 0-0.\n<|im_end|>" }, { "id": "#12925", "title": "How Hard is it to Get an Apple?", "fun": 2.36, "difficulty": 1.62, "author": "willymapo", "desc": "The legend tells of a young boy that entered a celestial garden. In the entrance, a sign said, \"who enters, will receive what he or she gives\".\n\r\nThere were beautiful flowers, which the boy touched softly because the petals seemed so delicate as if about to fall. There where also magical rocks and trees. Even the roughest stone was soft to the delicate touch of the boy. \r\nSuddenly, he found a great tree full with delicious apples. They were big and seemed made of silk. The boy felt hunger, so he took a stick and threw it to an apple to get it down. But what a surprise! The stick broke apart as if thrown against a rock. The boy then took a bigger stick and tried to hit the branch with all his strength. The bigger stick also broke. Now a little concerned, the boy then looked for a rock that felt hard in his furious grip, and then threw it with all his might to the soft looking apple. The rock was torn into pieces. The boy looked down disappointedly, realizing that surely there was no way to eat the fruit, when before his eyes a little mouse passed carrying an apple. \r\nSo, there was a way. Could you tell the boy how to get the apple?", "hint": "The harder you hit the tree, the harder it becomes...", "answer": "The tree was giving what it was receiving. If you hit it hard, it will be hard. Just as the delicate flowers to the delicate touch, the apple has to be taken softly, not by force.\r\nSo, the boy should try delicately to PUT (not take) the apple on the branch, and it will fall into his fingers.", "category": "Logic", "date": "06/04/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe legend tells of a young boy that entered a celestial garden. In the entrance, a sign said, \"who enters, will receive what he or she gives\".\n\r\nThere were beautiful flowers, which the boy touched softly because the petals seemed so delicate as if about to fall. There where also magical rocks and trees. Even the roughest stone was soft to the delicate touch of the boy. \r\nSuddenly, he found a great tree full with delicious apples. They were big and seemed made of silk. The boy felt hunger, so he took a stick and threw it to an apple to get it down. But what a surprise! The stick broke apart as if thrown against a rock. The boy then took a bigger stick and tried to hit the branch with all his strength. The bigger stick also broke. Now a little concerned, the boy then looked for a rock that felt hard in his furious grip, and then threw it with all his might to the soft looking apple. The rock was torn into pieces. The boy looked down disappointedly, realizing that surely there was no way to eat the fruit, when before his eyes a little mouse passed carrying an apple. \r\nSo, there was a way. Could you tell the boy how to get the apple?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe tree was giving what it was receiving. If you hit it hard, it will be hard. Just as the delicate flowers to the delicate touch, the apple has to be taken softly, not by force.\r\nSo, the boy should try delicately to PUT (not take) the apple on the branch, and it will fall into his fingers.\n<|im_start|>answer\nThe tree was giving what it was receiving. If you hit it hard, it will be hard. Just as the delicate flowers to the delicate touch, the apple has to be taken softly, not by force.\r\nSo, the boy should try delicately to PUT (not take) the apple on the branch, and it will fall into his fingers.\n<|im_end|>" }, { "id": "#2506", "title": "Creatures in a Cage", "fun": 2.36, "difficulty": 1.92, "author": "Cascas", "desc": "There's a cage with jungle animals and creatures. There are 11 heads and 20 feet. There are twice as many jungle creatures with four feet as there are jungle creatures with two feet. How many creatures of each are in the cage?", "hint": "No hint available.", "answer": "4 four legged animals\r\n2 two legged animals\r\n5 snakes", "category": "Math", "date": "03/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere's a cage with jungle animals and creatures. There are 11 heads and 20 feet. There are twice as many jungle creatures with four feet as there are jungle creatures with two feet. How many creatures of each are in the cage?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 four legged animals\r\n2 two legged animals\r\n5 snakes\n<|im_start|>answer\n4 four legged animals\r\n2 two legged animals\r\n5 snakes\n<|im_end|>" }, { "id": "#4494", "title": "McBrownpants", "fun": 2.36, "difficulty": 1.54, "author": "mad-ade", "desc": "Mad Ade's great great granddad was a Cowboy in the wild west.\r\n He was known either by the Indian name \"Dances with Alcohol\" or his nickname \"Mad Cow McBrownpants\". One day, he saw his face on a poster nailed to a tree. As he approached, he saw \"Wanted, Dead or Alive\". Under his picture, it read: \"Reward ___ \r\nDollars.\"\n\r\nThere was a three-digit figure on the poster. Mad Cow McBrownpants drew his Colt and shot at the first number (in the hundreds column). He had just reduced the price on his head four fifths. \n\r\n\"Good shot,\" said his Indian sidekick, \"Talks without Sense\", who stood on the other side of the tree, polishing his arrow. McBrownpants nodded, and shot again at another number (in the tens column). He had just reduced the price on his head by another four fifths.\n\r\n\"Nice shooting!\" said his sidekick again, hoping for a wage rise.\n\r\n\"Stop groveling,\" said McBrownpants. \n\r\nWhat was the initial reward offered on Mad Cow McBrownpants head?", "hint": "No hint available.", "answer": "$125.00", "category": "Math", "date": "06/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's great great granddad was a Cowboy in the wild west.\r\n He was known either by the Indian name \"Dances with Alcohol\" or his nickname \"Mad Cow McBrownpants\". One day, he saw his face on a poster nailed to a tree. As he approached, he saw \"Wanted, Dead or Alive\". Under his picture, it read: \"Reward ___ \r\nDollars.\"\n\r\nThere was a three-digit figure on the poster. Mad Cow McBrownpants drew his Colt and shot at the first number (in the hundreds column). He had just reduced the price on his head four fifths. \n\r\n\"Good shot,\" said his Indian sidekick, \"Talks without Sense\", who stood on the other side of the tree, polishing his arrow. McBrownpants nodded, and shot again at another number (in the tens column). He had just reduced the price on his head by another four fifths.\n\r\n\"Nice shooting!\" said his sidekick again, hoping for a wage rise.\n\r\n\"Stop groveling,\" said McBrownpants. \n\r\nWhat was the initial reward offered on Mad Cow McBrownpants head?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$125.00\n<|im_start|>answer\n$125.00\n<|im_end|>" }, { "id": "#23021", "title": "Picnic 2", "fun": 2.36, "difficulty": 1.6300000000000001, "author": "didida", "desc": "There are two girls and one boy. Their names are June, Kate, and John. They decided to go on a picnic and they each brought three things. They ended up with a blanket, a cooler, a soccer ball, a basketball, a skateboard, cherries, strawberries, sandwiches, and napkins.\n\r\nWho brought what, based on the following clues?\n\r\n1. Kate hates soccer so she would never bring a soccer ball.\r\n2. Whoever brought the cooler brought the napkins.\r\n3. The boy did not bring the skateboard.\r\n4. Neither girl plays soccer or basketball.\r\n5. June did not bring stuff to do.\r\n6. John does not own a cooler.\r\n7. Kate brought both kinds of fruit.\r\n8. June brought the blanket.", "hint": "No hint available.", "answer": "Kate-skateboard-strawberries-cherries\r\nJune-cooler-napkins-blanket\r\nJohn-soccerball-basketball-sandwiches", "category": "Logic", "date": "05/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two girls and one boy. Their names are June, Kate, and John. They decided to go on a picnic and they each brought three things. They ended up with a blanket, a cooler, a soccer ball, a basketball, a skateboard, cherries, strawberries, sandwiches, and napkins.\n\r\nWho brought what, based on the following clues?\n\r\n1. Kate hates soccer so she would never bring a soccer ball.\r\n2. Whoever brought the cooler brought the napkins.\r\n3. The boy did not bring the skateboard.\r\n4. Neither girl plays soccer or basketball.\r\n5. June did not bring stuff to do.\r\n6. John does not own a cooler.\r\n7. Kate brought both kinds of fruit.\r\n8. June brought the blanket.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKate-skateboard-strawberries-cherries\r\nJune-cooler-napkins-blanket\r\nJohn-soccerball-basketball-sandwiches\n<|im_start|>answer\nKate-skateboard-strawberries-cherries\r\nJune-cooler-napkins-blanket\r\nJohn-soccerball-basketball-sandwiches\n<|im_end|>" }, { "id": "#4784", "title": "Chocolate Profit", "fun": 2.36, "difficulty": 1.71, "author": "mad-ade", "desc": "Mad Ade went into his local corner shop to buy a chocolate bar. He paid 50 pence for the bar, and to his delight and astonishment, got back four times the change to which he was entitled. He noted that this was equivalent to twice the amount he had given the shop keeper. What was Mad Ade's total profit?", "hint": "No hint available.", "answer": "Mad Ade's profit was £1.50\n\r\nHe gave the shop keeper £1.00 and got back £2.00 in change.\n\r\nHis profit so far is £1.00. But he also got a chocolate bar valued at 50p. \r\nSo his total profit is £1.50", "category": "Math", "date": "06/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade went into his local corner shop to buy a chocolate bar. He paid 50 pence for the bar, and to his delight and astonishment, got back four times the change to which he was entitled. He noted that this was equivalent to twice the amount he had given the shop keeper. What was Mad Ade's total profit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade's profit was £1.50\n\r\nHe gave the shop keeper £1.00 and got back £2.00 in change.\n\r\nHis profit so far is £1.00. But he also got a chocolate bar valued at 50p. \r\nSo his total profit is £1.50\n<|im_start|>answer\nMad Ade's profit was £1.50\n\r\nHe gave the shop keeper £1.00 and got back £2.00 in change.\n\r\nHis profit so far is £1.00. But he also got a chocolate bar valued at 50p. \r\nSo his total profit is £1.50\n<|im_end|>" }, { "id": "#28823", "title": "Opposites 12", "fun": 2.36, "difficulty": 2.77, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n! stands for Y, E, G, P, or T\r\n@ stands for F, B, A, Q, or T\r\n# stands for R, E, A, N, or Z\r\n$ stands for F, E, N, S, or H\r\n% stands for S, T, Y, M, or W\r\n^ stands for P, D, E, H, or C\r\n& stands for U, K, H, T, or B\r\n* stands for O, J, G, I, or Z\r\n? stands for E, L, D, N, or C\n\r\nThe nine letter code word, ^*$%@#&?!, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Construct and Dismantle.", "category": "Logic", "date": "02/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n! stands for Y, E, G, P, or T\r\n@ stands for F, B, A, Q, or T\r\n# stands for R, E, A, N, or Z\r\n$ stands for F, E, N, S, or H\r\n% stands for S, T, Y, M, or W\r\n^ stands for P, D, E, H, or C\r\n& stands for U, K, H, T, or B\r\n* stands for O, J, G, I, or Z\r\n? stands for E, L, D, N, or C\n\r\nThe nine letter code word, ^*$%@#&?!, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nConstruct and Dismantle.\n<|im_start|>answer\nConstruct and Dismantle.\n<|im_end|>" }, { "id": "#2929", "title": "Soda, Hot Dog, Popcorn", "fun": 2.36, "difficulty": 1.7, "author": "pusandave", "desc": "Your are selling concessions for the local school. You know that you sold 4 sodas for every 3 boxes of popcorn. You also know that you sold 1 hot dog for every two sodas. If you didn't sell anything else, and you sold 45 items, how many sodas, popcorns and hot dogs did you sell?", "hint": "If \"S\" is the number of sodas, then the number of popcorns is 3/4(S).", "answer": "20 sodas, 15 popcorns and 10 hot dogs.\n\r\nIf \"S\" is the number of sodas, than 3/4(S) is the number of popcorns and 1/2(S) is the number of hot dogs.", "category": "Math", "date": "03/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour are selling concessions for the local school. You know that you sold 4 sodas for every 3 boxes of popcorn. You also know that you sold 1 hot dog for every two sodas. If you didn't sell anything else, and you sold 45 items, how many sodas, popcorns and hot dogs did you sell?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20 sodas, 15 popcorns and 10 hot dogs.\n\r\nIf \"S\" is the number of sodas, than 3/4(S) is the number of popcorns and 1/2(S) is the number of hot dogs.\n<|im_start|>answer\n20 sodas, 15 popcorns and 10 hot dogs.\n\r\nIf \"S\" is the number of sodas, than 3/4(S) is the number of popcorns and 1/2(S) is the number of hot dogs.\n<|im_end|>" }, { "id": "#30312", "title": "I Read You 5x5", "fun": 2.36, "difficulty": 3.01, "author": "norcekri", "desc": "\"Congratulations, Great-Aunt Nora!\" The voice of Victor Summ, her eldest nephew, was tired, but exultant. Her older sister was the first grandparent among the five Shekrie siblings.\r\n\t\"Let me put you on speaker-phone, Vic. Corman is here.\" Nora had little doubt that her romance with a math teacher was the reason Victor, a research statistician, called personally, instead of letting his mother handle the news.\r\n\tNora beamed at Corman as she hit the button. \"You're on, 'Daddy'. Mother and children are doing fine?\"\r\n\t\"Cogita's doing great, although we had a bit of a shuffle in the maternity ward. Hi, Professor diNoni -- you'll love this one.\"\r\n\t\"Hi, Victor. I've heard more about you than ... no, you've known your aunt longer. You probably know how much she's talked about you.\"\r\n\t\"It runs in the family,\" he smiled across two time zones. \"Doc Matter, our OB, said it was the strangest coincidence she's seen in a decade. The kids were born 10, 20, 30, minutes apart, up to an interval of an hour-fifty ...\" Vic's voice trailed off.\r\n\t\"Except for one interval?\" Corman filled in.\r\n\t\"Right. She said it was really weird, watching the time. She said Adele was born at six sharp, Brand at 6:10, and they just kept hitting 10-minute multiples, until Elana came out at 7:50.\"\r\n\tNora yelped. \"You had *eleven*,\" then her left brain caught up, \"no, just the quintuplets. Sorry.\"\r\n\t\"De nada, Aunt Nora. But that's where the problems started: they had the birth order mixed up. Someone had assumed we'd named them in order, with Brand, Caleb, and Derec in between. I pointed out that they'd managed to get all five wrong, and then Cogita wanted me.\"\r\n\t\"So they got it sorted out?\"\r\n\t\"Not quite. The OB saw to the post-delivery stuff while we beamed at each other. Then a nurse came in and said they figured it out: we'd named them in alphabetical order, but by the last letter of their names. They had all five wrong again! Heck, even if we'd done it in reverse alphabetical order, either way, they would have had all five wrong!\"\r\n\t\"So what did they do?\"\r\n\t\"Doc Matter said she may be getting gray, but she wasn't going to sign the certificates until they were all correct. She dictated the birth times and told them to match them with the weight and length stats to sort things out -- and if they couldn't, they shouldn't bother reporting for work after tonight.\"\r\n\tHe took a cleansing breath. \"On a happier note, we'd like the blood aunts and uncles to serve as godparents, since there are five of you. Would you stand for Caleb, Aunt Nora, since the two of you have the same birth position in the family?\"\r\n\t\"I'd love to. And if anyone in this family declines, I'll have Corman make them figure out the birth order. Do you have it yet, dear?\"\r\n\tVic broke in, \"He doesn't have enough information yet, and I can hear you smirking at him.\"\r\n\tCorman held up a hand to keep her quiet. \"Since I don't know much about Nora's birth order, I'll have to make this a bigger question. How far apart were Brand and Elena born?\"\r\n\t\"Fifty minutes, on their cute little noses.\"\r\n\t\"Got it.\" Corman recited the birth order, complete with times. Can you do the same?", "hint": "There is only one way (plus a mirror-image reflection) to arrange ten different intervals in a span of 11 ten-minute units. If you need help, search for \"Optimal Rulers\".", "answer": "6:00\tDerec\r\n6:10\tAdele\t0:10 later\r\n6:40\tBrand\t0:30 later, 0:40 after Derec\r\n7:30\tElena\t0:50 later, 1:30 after Derec, 1:20 after Adele\r\n7:50\tCaleb\t0:20 later, 1:50 after Derek, 1:40 after Adele, 1:10 after Brand.\n\r\n\tThe missing interval is one hour.\n\r\nMethod:\r\n\tNumber the ten time points from 0 to 11 (6:00 to 7:50). The only ways to arrange them to get ten different intervals for the births are events at points 0, 1, 4, 9, and 11 and the reverse: 11, 10, 7, 2, and 0. The clue gives three birth times at 6:00, 6:10, and 7:50, so we have the first arrangement.\r\n\tThe clues about alphabetic and reverse-alphabetic order giving five wrong placements mean that Caleb and Derek were not born 2nd, 3rd, or 4th; Adele and Elena were not born first or last, and Brand was not born 2nd or 4th.\r\n\tThe 50-minute interval given at the end means puts Brand and Elena into the 3rd & 4th spots, which leaves 2nd as the place for Adele.\r\n\tFinally, we have Caleb and Derec to fill the first and last spots. Caleb and Nora share a birth position. The first paragraph mentions that Cogita is Nora's older sister, so Caleb cannot be the firstborn.", "category": "Logic", "date": "05/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"Congratulations, Great-Aunt Nora!\" The voice of Victor Summ, her eldest nephew, was tired, but exultant. Her older sister was the first grandparent among the five Shekrie siblings.\r\n\t\"Let me put you on speaker-phone, Vic. Corman is here.\" Nora had little doubt that her romance with a math teacher was the reason Victor, a research statistician, called personally, instead of letting his mother handle the news.\r\n\tNora beamed at Corman as she hit the button. \"You're on, 'Daddy'. Mother and children are doing fine?\"\r\n\t\"Cogita's doing great, although we had a bit of a shuffle in the maternity ward. Hi, Professor diNoni -- you'll love this one.\"\r\n\t\"Hi, Victor. I've heard more about you than ... no, you've known your aunt longer. You probably know how much she's talked about you.\"\r\n\t\"It runs in the family,\" he smiled across two time zones. \"Doc Matter, our OB, said it was the strangest coincidence she's seen in a decade. The kids were born 10, 20, 30, minutes apart, up to an interval of an hour-fifty ...\" Vic's voice trailed off.\r\n\t\"Except for one interval?\" Corman filled in.\r\n\t\"Right. She said it was really weird, watching the time. She said Adele was born at six sharp, Brand at 6:10, and they just kept hitting 10-minute multiples, until Elana came out at 7:50.\"\r\n\tNora yelped. \"You had *eleven*,\" then her left brain caught up, \"no, just the quintuplets. Sorry.\"\r\n\t\"De nada, Aunt Nora. But that's where the problems started: they had the birth order mixed up. Someone had assumed we'd named them in order, with Brand, Caleb, and Derec in between. I pointed out that they'd managed to get all five wrong, and then Cogita wanted me.\"\r\n\t\"So they got it sorted out?\"\r\n\t\"Not quite. The OB saw to the post-delivery stuff while we beamed at each other. Then a nurse came in and said they figured it out: we'd named them in alphabetical order, but by the last letter of their names. They had all five wrong again! Heck, even if we'd done it in reverse alphabetical order, either way, they would have had all five wrong!\"\r\n\t\"So what did they do?\"\r\n\t\"Doc Matter said she may be getting gray, but she wasn't going to sign the certificates until they were all correct. She dictated the birth times and told them to match them with the weight and length stats to sort things out -- and if they couldn't, they shouldn't bother reporting for work after tonight.\"\r\n\tHe took a cleansing breath. \"On a happier note, we'd like the blood aunts and uncles to serve as godparents, since there are five of you. Would you stand for Caleb, Aunt Nora, since the two of you have the same birth position in the family?\"\r\n\t\"I'd love to. And if anyone in this family declines, I'll have Corman make them figure out the birth order. Do you have it yet, dear?\"\r\n\tVic broke in, \"He doesn't have enough information yet, and I can hear you smirking at him.\"\r\n\tCorman held up a hand to keep her quiet. \"Since I don't know much about Nora's birth order, I'll have to make this a bigger question. How far apart were Brand and Elena born?\"\r\n\t\"Fifty minutes, on their cute little noses.\"\r\n\t\"Got it.\" Corman recited the birth order, complete with times. Can you do the same?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6:00\tDerec\r\n6:10\tAdele\t0:10 later\r\n6:40\tBrand\t0:30 later, 0:40 after Derec\r\n7:30\tElena\t0:50 later, 1:30 after Derec, 1:20 after Adele\r\n7:50\tCaleb\t0:20 later, 1:50 after Derek, 1:40 after Adele, 1:10 after Brand.\n\r\n\tThe missing interval is one hour.\n\r\nMethod:\r\n\tNumber the ten time points from 0 to 11 (6:00 to 7:50). The only ways to arrange them to get ten different intervals for the births are events at points 0, 1, 4, 9, and 11 and the reverse: 11, 10, 7, 2, and 0. The clue gives three birth times at 6:00, 6:10, and 7:50, so we have the first arrangement.\r\n\tThe clues about alphabetic and reverse-alphabetic order giving five wrong placements mean that Caleb and Derek were not born 2nd, 3rd, or 4th; Adele and Elena were not born first or last, and Brand was not born 2nd or 4th.\r\n\tThe 50-minute interval given at the end means puts Brand and Elena into the 3rd & 4th spots, which leaves 2nd as the place for Adele.\r\n\tFinally, we have Caleb and Derec to fill the first and last spots. Caleb and Nora share a birth position. The first paragraph mentions that Cogita is Nora's older sister, so Caleb cannot be the firstborn.\n<|im_start|>answer\n6:00\tDerec\r\n6:10\tAdele\t0:10 later\r\n6:40\tBrand\t0:30 later, 0:40 after Derec\r\n7:30\tElena\t0:50 later, 1:30 after Derec, 1:20 after Adele\r\n7:50\tCaleb\t0:20 later, 1:50 after Derek, 1:40 after Adele, 1:10 after Brand.\n\r\n\tThe missing interval is one hour.\n\r\nMethod:\r\n\tNumber the ten time points from 0 to 11 (6:00 to 7:50). The only ways to arrange them to get ten different intervals for the births are events at points 0, 1, 4, 9, and 11 and the reverse: 11, 10, 7, 2, and 0. The clue gives three birth times at 6:00, 6:10, and 7:50, so we have the first arrangement.\r\n\tThe clues about alphabetic and reverse-alphabetic order giving five wrong placements mean that Caleb and Derek were not born 2nd, 3rd, or 4th; Adele and Elena were not born first or last, and Brand was not born 2nd or 4th.\r\n\tThe 50-minute interval given at the end means puts Brand and Elena into the 3rd & 4th spots, which leaves 2nd as the place for Adele.\r\n\tFinally, we have Caleb and Derec to fill the first and last spots. Caleb and Nora share a birth position. The first paragraph mentions that Cogita is Nora's older sister, so Caleb cannot be the firstborn.\n<|im_end|>" }, { "id": "#10758", "title": "Unlucky Horse", "fun": 2.36, "difficulty": 3.01, "author": "griphook", "desc": "Seven horses in a farm in Kentucky,\r\nOf three blacks, the oldest is a daddy;\r\nOf two browns, the 3 year old male is called BILLY,\r\nAnd the horse SNOWY is white as a lily.\n\r\nOf two half-sister mares, the black won in the Derby,\r\nShe's a shade lighter than her daughter, BEAUTY;\r\nBEAUTY and her cousin LUCKY, both half the age of their auntie,\r\nBut faster than either ROCKY or SUNNY.\n\r\nThree of the horses are ready for the Derby,\r\nA horse must be three years to be an entry;\r\nMaybe this year the farm gets lucky, \r\nTheir stallion's loss last year was a pity.\n\n\r\nCHALLENGE: Describe the horse that lost in last year's Derby.", "hint": "For purposes of this riddle the following terms are defined as:\n\r\nMare- female horse\r\nStallion- mature male horse\r\nDerby- a race for three year old horses.", "answer": "SNOWY, a 4 year old male white horse lost last year.\n\r\nThe Derby is for three year old horses. Therefore only a current four year old horse could have lost last year.\n\r\nSNOWY is the only horse which could have been three last year (four this year).\n\r\nThe farm is preparing three of the seven horses for this years Derby. There must therefore be at least three 3-year old horses among the seven. BILLY is 3-years old. Necessarily, BEAUTY and her cousin LUCKY must be 3 years old both. (They are of the same age).\r\nBeauty's mom could not be three because she won in the Derby before. The oldest black is even older than BEAUTY's mom. \r\nBEAUTY's aunt could not be three. If she were, then SNOWY must also be three to complete the three entries this year. This would mean that no horse would be four years old as BEAUTY and LUCKY would be one and a half years old. BEAUTY's mom won in the DERBY as a three year old, she could not win and lose at the same time. (The riddle suggests that the farm did not win last year so the mom must be over 5 years old).\n\r\nIn sum, if BILLY, BEAUTY, and LUCKY are three years old, their aunt must be six. BEAUTY's mom must be five or more. The oldest black must be older than the black mom. Only SNOWY could be four this year.\n\r\nSNOWY is white (given), 4 years as deduced, and male from the fact that it was a stallion which lost last year. \n\r\nThe names of BEAUTY's mom and aunt and that of the oldest black are immaterial. The same is true with the color of lucky.", "category": "Logic", "date": "02/27/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSeven horses in a farm in Kentucky,\r\nOf three blacks, the oldest is a daddy;\r\nOf two browns, the 3 year old male is called BILLY,\r\nAnd the horse SNOWY is white as a lily.\n\r\nOf two half-sister mares, the black won in the Derby,\r\nShe's a shade lighter than her daughter, BEAUTY;\r\nBEAUTY and her cousin LUCKY, both half the age of their auntie,\r\nBut faster than either ROCKY or SUNNY.\n\r\nThree of the horses are ready for the Derby,\r\nA horse must be three years to be an entry;\r\nMaybe this year the farm gets lucky, \r\nTheir stallion's loss last year was a pity.\n\n\r\nCHALLENGE: Describe the horse that lost in last year's Derby.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSNOWY, a 4 year old male white horse lost last year.\n\r\nThe Derby is for three year old horses. Therefore only a current four year old horse could have lost last year.\n\r\nSNOWY is the only horse which could have been three last year (four this year).\n\r\nThe farm is preparing three of the seven horses for this years Derby. There must therefore be at least three 3-year old horses among the seven. BILLY is 3-years old. Necessarily, BEAUTY and her cousin LUCKY must be 3 years old both. (They are of the same age).\r\nBeauty's mom could not be three because she won in the Derby before. The oldest black is even older than BEAUTY's mom. \r\nBEAUTY's aunt could not be three. If she were, then SNOWY must also be three to complete the three entries this year. This would mean that no horse would be four years old as BEAUTY and LUCKY would be one and a half years old. BEAUTY's mom won in the DERBY as a three year old, she could not win and lose at the same time. (The riddle suggests that the farm did not win last year so the mom must be over 5 years old).\n\r\nIn sum, if BILLY, BEAUTY, and LUCKY are three years old, their aunt must be six. BEAUTY's mom must be five or more. The oldest black must be older than the black mom. Only SNOWY could be four this year.\n\r\nSNOWY is white (given), 4 years as deduced, and male from the fact that it was a stallion which lost last year. \n\r\nThe names of BEAUTY's mom and aunt and that of the oldest black are immaterial. The same is true with the color of lucky.\n<|im_start|>answer\nSNOWY, a 4 year old male white horse lost last year.\n\r\nThe Derby is for three year old horses. Therefore only a current four year old horse could have lost last year.\n\r\nSNOWY is the only horse which could have been three last year (four this year).\n\r\nThe farm is preparing three of the seven horses for this years Derby. There must therefore be at least three 3-year old horses among the seven. BILLY is 3-years old. Necessarily, BEAUTY and her cousin LUCKY must be 3 years old both. (They are of the same age).\r\nBeauty's mom could not be three because she won in the Derby before. The oldest black is even older than BEAUTY's mom. \r\nBEAUTY's aunt could not be three. If she were, then SNOWY must also be three to complete the three entries this year. This would mean that no horse would be four years old as BEAUTY and LUCKY would be one and a half years old. BEAUTY's mom won in the DERBY as a three year old, she could not win and lose at the same time. (The riddle suggests that the farm did not win last year so the mom must be over 5 years old).\n\r\nIn sum, if BILLY, BEAUTY, and LUCKY are three years old, their aunt must be six. BEAUTY's mom must be five or more. The oldest black must be older than the black mom. Only SNOWY could be four this year.\n\r\nSNOWY is white (given), 4 years as deduced, and male from the fact that it was a stallion which lost last year. \n\r\nThe names of BEAUTY's mom and aunt and that of the oldest black are immaterial. The same is true with the color of lucky.\n<|im_end|>" }, { "id": "#50939", "title": "Base Instinct", "fun": 2.36, "difficulty": 2.08, "author": "Snowdog", "desc": "What is the missing value in the following list?\n\r\n17 18 21 23 25 ? 101 122 10001", "hint": "This list ends at 10001. It does not continue to the right.\n\r\nCheck the teaser's title.", "answer": "The missing value is 32.\n\r\nThese are the representations of the decimal value 17 in decreasing number bases, down to binary.\n\r\nBase 10: 1x10 + 7x1 = 17\r\nBase 9: 1x9 + 8x1 = 17\r\nBase 8: 2x8 + 1x1 = 17\r\nBase 7: 2x7 + 3x1 = 17\r\nBase 6: 2x6 + 5x1 = 17\r\nBase 5: 3x5 + 2x1 = 17 <- Missing value 32\r\nBase 4: 1x16 + 0x4 + 1x1 = 17\r\nBase 3: 1x9 + 2x3 + 2x1 = 17\r\nBase 2: 1x16 + 0x8 + 0x4 + 0x2 +1x1 = 17", "category": "Math", "date": "12/24/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the missing value in the following list?\n\r\n17 18 21 23 25 ? 101 122 10001\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe missing value is 32.\n\r\nThese are the representations of the decimal value 17 in decreasing number bases, down to binary.\n\r\nBase 10: 1x10 + 7x1 = 17\r\nBase 9: 1x9 + 8x1 = 17\r\nBase 8: 2x8 + 1x1 = 17\r\nBase 7: 2x7 + 3x1 = 17\r\nBase 6: 2x6 + 5x1 = 17\r\nBase 5: 3x5 + 2x1 = 17 <- Missing value 32\r\nBase 4: 1x16 + 0x4 + 1x1 = 17\r\nBase 3: 1x9 + 2x3 + 2x1 = 17\r\nBase 2: 1x16 + 0x8 + 0x4 + 0x2 +1x1 = 17\n<|im_start|>answer\nThe missing value is 32.\n\r\nThese are the representations of the decimal value 17 in decreasing number bases, down to binary.\n\r\nBase 10: 1x10 + 7x1 = 17\r\nBase 9: 1x9 + 8x1 = 17\r\nBase 8: 2x8 + 1x1 = 17\r\nBase 7: 2x7 + 3x1 = 17\r\nBase 6: 2x6 + 5x1 = 17\r\nBase 5: 3x5 + 2x1 = 17 <- Missing value 32\r\nBase 4: 1x16 + 0x4 + 1x1 = 17\r\nBase 3: 1x9 + 2x3 + 2x1 = 17\r\nBase 2: 1x16 + 0x8 + 0x4 + 0x2 +1x1 = 17\n<|im_end|>" }, { "id": "#31441", "title": "Friends and Their Jobs", "fun": 2.36, "difficulty": 0.84, "author": "kistin14", "desc": "4 friends all worked in an office building, but with different jobs. Their first names were Ace, Bob, Cathy, and Denise. Their last names were Adams, Bina, Christian, and Dak. The jobs were President, Vice President, Secretary, and Intern.\n\r\n1.) No one had the same initials. Like AA or BB.\n\r\n2.) Ace wasn't the Secretary.\n\r\n3.) Bob told the Secretary that the Vice President and President were going to work late.\n\r\n4.) Mrs. Christian dated Mr. Dak for a while, but broke up.\n\r\n5.) Mr. Adams was the Intern and Mrs. Bina was the President.\n\r\n6.) Ace wanted to be promoted to President in a few years when Cathy retired.\n\r\n7.) Denise loved her job typing for the higher positions.", "hint": "No hint available.", "answer": "Ace Dak was the Vice President.\r\nBob Adams was the Intern.\r\nCathy Bina was the President.\r\nDenise Christian was the Secretary.", "category": "Logic-Grid", "date": "06/29/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 friends all worked in an office building, but with different jobs. Their first names were Ace, Bob, Cathy, and Denise. Their last names were Adams, Bina, Christian, and Dak. The jobs were President, Vice President, Secretary, and Intern.\n\r\n1.) No one had the same initials. Like AA or BB.\n\r\n2.) Ace wasn't the Secretary.\n\r\n3.) Bob told the Secretary that the Vice President and President were going to work late.\n\r\n4.) Mrs. Christian dated Mr. Dak for a while, but broke up.\n\r\n5.) Mr. Adams was the Intern and Mrs. Bina was the President.\n\r\n6.) Ace wanted to be promoted to President in a few years when Cathy retired.\n\r\n7.) Denise loved her job typing for the higher positions.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAce Dak was the Vice President.\r\nBob Adams was the Intern.\r\nCathy Bina was the President.\r\nDenise Christian was the Secretary.\n<|im_start|>answer\nAce Dak was the Vice President.\r\nBob Adams was the Intern.\r\nCathy Bina was the President.\r\nDenise Christian was the Secretary.\n<|im_end|>" }, { "id": "#6298", "title": "Five Digit Number", "fun": 2.36, "difficulty": 1.33, "author": "Bintot", "desc": "What is the five-digit number, no zeroes, in which the second digit is three times the first, the third is one more than the second, the fourth is four times the first, and the last is one-half more than the second?", "hint": "No hint available.", "answer": "26789", "category": "Math", "date": "08/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the five-digit number, no zeroes, in which the second digit is three times the first, the third is one more than the second, the fourth is four times the first, and the last is one-half more than the second?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n26789\n<|im_start|>answer\n26789\n<|im_end|>" }, { "id": "#14346", "title": "Fathers and Sons", "fun": 2.36, "difficulty": 2.28, "author": "Smithy", "desc": "Father A is twice the difference in years of the ages of Father B and Son A, who is one and a half times the age of Son B. \r\nFather B is currently twice the age Son A is going to be when Son B will be double the age he is now. \n\r\nAll of the ages are multiples of five, and they are all under 100. \n\r\nHow old are all four people?", "hint": "No hint available.", "answer": "Son A = 15 years old. \r\nSon B = 10 years old. \r\nFather B = 50 years old. \r\nFather A = 70 years old.\n\r\nYou know that Son A is 1.5 times older than Son B. Therefore: \n\r\nSa = 1.5*Sb, or \n\r\nSb = 2/3 * Sa (call this equation 1)\n\r\nYou also know that Father B is twice the age Son A will be when Son B's age doubles. You can set up the equation:\n\r\nFb = 2*(Sa + Sb) (call this equation 2)\n\r\nPlugging equation (1) into equation (2) and reducing, you get:\n\r\nFb = 10/3*Sa\n\r\nBecause of the fraction, Fa must be evenly divisible by 3. The only multiple of 5 that satisfies this and keeps Father B's age below 100 is 15, which is Son A's age. Once this is known, the other ages are pretty straightforward to figure out.", "category": "Math", "date": "08/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFather A is twice the difference in years of the ages of Father B and Son A, who is one and a half times the age of Son B. \r\nFather B is currently twice the age Son A is going to be when Son B will be double the age he is now. \n\r\nAll of the ages are multiples of five, and they are all under 100. \n\r\nHow old are all four people?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSon A = 15 years old. \r\nSon B = 10 years old. \r\nFather B = 50 years old. \r\nFather A = 70 years old.\n\r\nYou know that Son A is 1.5 times older than Son B. Therefore: \n\r\nSa = 1.5*Sb, or \n\r\nSb = 2/3 * Sa (call this equation 1)\n\r\nYou also know that Father B is twice the age Son A will be when Son B's age doubles. You can set up the equation:\n\r\nFb = 2*(Sa + Sb) (call this equation 2)\n\r\nPlugging equation (1) into equation (2) and reducing, you get:\n\r\nFb = 10/3*Sa\n\r\nBecause of the fraction, Fa must be evenly divisible by 3. The only multiple of 5 that satisfies this and keeps Father B's age below 100 is 15, which is Son A's age. Once this is known, the other ages are pretty straightforward to figure out.\n<|im_start|>answer\nSon A = 15 years old. \r\nSon B = 10 years old. \r\nFather B = 50 years old. \r\nFather A = 70 years old.\n\r\nYou know that Son A is 1.5 times older than Son B. Therefore: \n\r\nSa = 1.5*Sb, or \n\r\nSb = 2/3 * Sa (call this equation 1)\n\r\nYou also know that Father B is twice the age Son A will be when Son B's age doubles. You can set up the equation:\n\r\nFb = 2*(Sa + Sb) (call this equation 2)\n\r\nPlugging equation (1) into equation (2) and reducing, you get:\n\r\nFb = 10/3*Sa\n\r\nBecause of the fraction, Fa must be evenly divisible by 3. The only multiple of 5 that satisfies this and keeps Father B's age below 100 is 15, which is Son A's age. Once this is known, the other ages are pretty straightforward to figure out.\n<|im_end|>" }, { "id": "#16347", "title": "A Plane Trip", "fun": 2.36, "difficulty": 1.72, "author": "airhead3", "desc": "Two identical airplanes (Plane A and Plane B) make the round-trip flight from Miami to Las Vegas on different days. They both use the exact same route, have the same layover time in Las Vegas and flight conditions are the same, save one: Plane A experiences no winds on the flight, and Plane B experiences a constant wind that gives it a headwind (flying against the wind) going to Las Vegas, and a tailwind (flying with the wind) back to Miami. If both airplanes maintain the same airspeed (speed relative to the wind) the entire flight, which airplane will take longer to complete the round-trip? Why?", "hint": "You don't need math to solve it.", "answer": "Plane B will take longer. The headwind decreases Plane B's speed over the ground the same amount as the tailwind increases it. However, the headwind is acting on the airplane for a longer period of time, consequently slowing the plane down longer than the period it was sped up for.", "category": "Logic", "date": "01/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo identical airplanes (Plane A and Plane B) make the round-trip flight from Miami to Las Vegas on different days. They both use the exact same route, have the same layover time in Las Vegas and flight conditions are the same, save one: Plane A experiences no winds on the flight, and Plane B experiences a constant wind that gives it a headwind (flying against the wind) going to Las Vegas, and a tailwind (flying with the wind) back to Miami. If both airplanes maintain the same airspeed (speed relative to the wind) the entire flight, which airplane will take longer to complete the round-trip? Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPlane B will take longer. The headwind decreases Plane B's speed over the ground the same amount as the tailwind increases it. However, the headwind is acting on the airplane for a longer period of time, consequently slowing the plane down longer than the period it was sped up for.\n<|im_start|>answer\nPlane B will take longer. The headwind decreases Plane B's speed over the ground the same amount as the tailwind increases it. However, the headwind is acting on the airplane for a longer period of time, consequently slowing the plane down longer than the period it was sped up for.\n<|im_end|>" }, { "id": "#2013", "title": "2=1?", "fun": 2.36, "difficulty": 1.85, "author": "Mogmatt16", "desc": "Read this following proof carefully.\n\r\nX=Y Given\r\nX^2=XY Multiply both sides by X\r\nX^2-Y^2=XY-Y^2 Subtract Y^2 from both sides\r\n(X+Y)(X-Y)=Y(X-Y) Factor both sides\r\n(X+Y)=Y Cancel out common factors\r\nY+Y = Y Substitute in from line (1)\r\n2Y = Y Collect the Y's\r\n2 = 1 Divide both sides by Y\n\r\nNow obviously, 2 doesn't equal 1. So what's wrong with this proof?", "hint": "It's in lines 4 and 5.", "answer": "'Cancelling' the common factors from line (4) to (5) means dividing by the factor (X-Y). Since X=Y, this is a division by 0, the results of which are undefined.", "category": "Math", "date": "01/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRead this following proof carefully.\n\r\nX=Y Given\r\nX^2=XY Multiply both sides by X\r\nX^2-Y^2=XY-Y^2 Subtract Y^2 from both sides\r\n(X+Y)(X-Y)=Y(X-Y) Factor both sides\r\n(X+Y)=Y Cancel out common factors\r\nY+Y = Y Substitute in from line (1)\r\n2Y = Y Collect the Y's\r\n2 = 1 Divide both sides by Y\n\r\nNow obviously, 2 doesn't equal 1. So what's wrong with this proof?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n'Cancelling' the common factors from line (4) to (5) means dividing by the factor (X-Y). Since X=Y, this is a division by 0, the results of which are undefined.\n<|im_start|>answer\n'Cancelling' the common factors from line (4) to (5) means dividing by the factor (X-Y). Since X=Y, this is a division by 0, the results of which are undefined.\n<|im_end|>" }, { "id": "#48514", "title": "Calendar", "fun": 2.36, "difficulty": 2.31, "author": "shenqiang", "desc": "Tom's birthday is exactly 6 weeks later, and today is his birthday with month and day reversed.\n\r\nWhat is Tom's birthday?", "hint": "Consider all possibilities.", "answer": "Tom's birthday must be in the next year; otherwise, if you reverse the month and day, it will be a few days less than one or two months, and not 42 days. (For example, 2.1 is 30 days after 1.2, and 5.3 is 59 days after 3.5.)\n\r\nIf Tom's birthday is in the next year, it's easy to see that it must be on January 12, and today is December 1st.", "category": "Math", "date": "02/27/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTom's birthday is exactly 6 weeks later, and today is his birthday with month and day reversed.\n\r\nWhat is Tom's birthday?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTom's birthday must be in the next year; otherwise, if you reverse the month and day, it will be a few days less than one or two months, and not 42 days. (For example, 2.1 is 30 days after 1.2, and 5.3 is 59 days after 3.5.)\n\r\nIf Tom's birthday is in the next year, it's easy to see that it must be on January 12, and today is December 1st.\n<|im_start|>answer\nTom's birthday must be in the next year; otherwise, if you reverse the month and day, it will be a few days less than one or two months, and not 42 days. (For example, 2.1 is 30 days after 1.2, and 5.3 is 59 days after 3.5.)\n\r\nIf Tom's birthday is in the next year, it's easy to see that it must be on January 12, and today is December 1st.\n<|im_end|>" }, { "id": "#8315", "title": "Valentine's Day Mascara", "fun": 2.36, "difficulty": 1.98, "author": "mad-ade", "desc": "Annie Warthogg, Bunnie Bentknows, Candy Potboiler and Dina Noteef, Madiadia's least desirable and ugliest ladies, visited Mad Ade on February 14th.\n\r\nThe time of each visit was as follows: \r\n- Annie at 8:00 \r\n- Bunnie at 9:00 \r\n- Candy at 10:00 \r\n- Dina at 11:00 \n\r\n(1) Each time mentioned above may be either AM or PM. \n\r\n(2) Candy did not visit Mad Ade between Bunnie and Dina. \n\r\n(3) At least one female visited Mad Ade between Annie and Bunnie. \n\r\n(4) Annie did not visit Mad Ade before both Candy and Dina.\n\r\nCan you tell at what time and in what order they each visited Mad Ade?", "hint": "No hint available.", "answer": "Bunnie (9:00AM) - Dina (11:00AM) - Annie (8:00PM) - Candy (10:00PM) \n\r\nFrom the given data, it is clear that at least one female visited Mad Ade in the morning and at least one female visited Mad Ade in the evening.\r\nAlso, from (4), Annie did not visit Mad Ade first. It means that Annie visited Mad Ade at 8:00 PM. \n\r\nFrom (3), Bunnie must have visited Mad Ade at 9:00 AM. Also, either Candy or Dina, or both, visited Mad Ade in the morning. \n\r\nBut from (2), only Dina could have visited Mad Ade in the morning, at 11:00 AM, and hence, Candy visited Mad Ade at 10:00 PM.", "category": "Logic", "date": "11/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnnie Warthogg, Bunnie Bentknows, Candy Potboiler and Dina Noteef, Madiadia's least desirable and ugliest ladies, visited Mad Ade on February 14th.\n\r\nThe time of each visit was as follows: \r\n- Annie at 8:00 \r\n- Bunnie at 9:00 \r\n- Candy at 10:00 \r\n- Dina at 11:00 \n\r\n(1) Each time mentioned above may be either AM or PM. \n\r\n(2) Candy did not visit Mad Ade between Bunnie and Dina. \n\r\n(3) At least one female visited Mad Ade between Annie and Bunnie. \n\r\n(4) Annie did not visit Mad Ade before both Candy and Dina.\n\r\nCan you tell at what time and in what order they each visited Mad Ade?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBunnie (9:00AM) - Dina (11:00AM) - Annie (8:00PM) - Candy (10:00PM) \n\r\nFrom the given data, it is clear that at least one female visited Mad Ade in the morning and at least one female visited Mad Ade in the evening.\r\nAlso, from (4), Annie did not visit Mad Ade first. It means that Annie visited Mad Ade at 8:00 PM. \n\r\nFrom (3), Bunnie must have visited Mad Ade at 9:00 AM. Also, either Candy or Dina, or both, visited Mad Ade in the morning. \n\r\nBut from (2), only Dina could have visited Mad Ade in the morning, at 11:00 AM, and hence, Candy visited Mad Ade at 10:00 PM.\n<|im_start|>answer\nBunnie (9:00AM) - Dina (11:00AM) - Annie (8:00PM) - Candy (10:00PM) \n\r\nFrom the given data, it is clear that at least one female visited Mad Ade in the morning and at least one female visited Mad Ade in the evening.\r\nAlso, from (4), Annie did not visit Mad Ade first. It means that Annie visited Mad Ade at 8:00 PM. \n\r\nFrom (3), Bunnie must have visited Mad Ade at 9:00 AM. Also, either Candy or Dina, or both, visited Mad Ade in the morning. \n\r\nBut from (2), only Dina could have visited Mad Ade in the morning, at 11:00 AM, and hence, Candy visited Mad Ade at 10:00 PM.\n<|im_end|>" }, { "id": "#31823", "title": "Cattatackya", "fun": 2.36, "difficulty": 2.03, "author": "npf2005", "desc": "In the fictional, rat infested village of Cattatackya (where cats live) last month, each cat killed the same number of rats as every other cat. The total number of rat fatalities (deaths) during the month came to a total of 2117.\n\r\nLess than 50 cats achieved this remarkable number of rat killings. How many cats were living in Cattatackya that month, and how many rats did each kill?", "hint": "No hint available.", "answer": "29 cats each killed 73 rats.", "category": "Math", "date": "07/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the fictional, rat infested village of Cattatackya (where cats live) last month, each cat killed the same number of rats as every other cat. The total number of rat fatalities (deaths) during the month came to a total of 2117.\n\r\nLess than 50 cats achieved this remarkable number of rat killings. How many cats were living in Cattatackya that month, and how many rats did each kill?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n29 cats each killed 73 rats.\n<|im_start|>answer\n29 cats each killed 73 rats.\n<|im_end|>" }, { "id": "#14477", "title": "Find the Number", "fun": 2.36, "difficulty": 1.83, "author": "Gerd", "desc": "The number has 5 digits.\n\r\na: the first and the third digit are the same, all others are different.\r\nb: the highest digit is 7 and the lowest is 1.\r\nc: the third digit is twice as much as the fourth.\r\nd: the second digit is higher than the fifth.\r\ne: the sum of the five digits is 23.\n\r\nWhat is the number?", "hint": "No hint available.", "answer": "67631 \n\r\nBecause of 'a' and 'c' there are three possibilities: \n\r\n2-21- (with 7 and 6 we only get 18) \r\n4-42- (with 7 and 1 (b) we get 18) \r\n6-63- (b says we need a 7 and a 1, and d shows the position.)", "category": "Math", "date": "08/22/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe number has 5 digits.\n\r\na: the first and the third digit are the same, all others are different.\r\nb: the highest digit is 7 and the lowest is 1.\r\nc: the third digit is twice as much as the fourth.\r\nd: the second digit is higher than the fifth.\r\ne: the sum of the five digits is 23.\n\r\nWhat is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n67631 \n\r\nBecause of 'a' and 'c' there are three possibilities: \n\r\n2-21- (with 7 and 6 we only get 18) \r\n4-42- (with 7 and 1 (b) we get 18) \r\n6-63- (b says we need a 7 and a 1, and d shows the position.)\n<|im_start|>answer\n67631 \n\r\nBecause of 'a' and 'c' there are three possibilities: \n\r\n2-21- (with 7 and 6 we only get 18) \r\n4-42- (with 7 and 1 (b) we get 18) \r\n6-63- (b says we need a 7 and a 1, and d shows the position.)\n<|im_end|>" }, { "id": "#32614", "title": "Tinman's Pick", "fun": 2.36, "difficulty": 1.23, "author": "metallicman", "desc": "Tinman was in quite a pickle. He was choosing a vehicle that he had to drive for the next 7 years, and he had to make the best decision possible. He had only five choices to choose from, and the choices each had different qualities that made them better or worse.\n\r\nIf the third choice was worse than the first choice and the second choice as good as the fifth, but the fifth choice was only as good as the worst choice leaving the fourth choice a little better than the third but not as good as the first, and the second was the worst choice to go with, which choice should Tinman go with if he wanted the best vehicle?", "hint": "No hint available.", "answer": "Tinman should go with the first choice. In order from worst to best, the choices are:\n\r\n5th/2nd, 3rd, 4th, 1st.", "category": "Logic", "date": "08/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTinman was in quite a pickle. He was choosing a vehicle that he had to drive for the next 7 years, and he had to make the best decision possible. He had only five choices to choose from, and the choices each had different qualities that made them better or worse.\n\r\nIf the third choice was worse than the first choice and the second choice as good as the fifth, but the fifth choice was only as good as the worst choice leaving the fourth choice a little better than the third but not as good as the first, and the second was the worst choice to go with, which choice should Tinman go with if he wanted the best vehicle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTinman should go with the first choice. In order from worst to best, the choices are:\n\r\n5th/2nd, 3rd, 4th, 1st.\n<|im_start|>answer\nTinman should go with the first choice. In order from worst to best, the choices are:\n\r\n5th/2nd, 3rd, 4th, 1st.\n<|im_end|>" }, { "id": "#26091", "title": "Teasergle", "fun": 2.36, "difficulty": 0.71, "author": "phrebh", "desc": "Three online friends, one female (Sara) and two males (Frederick and Tim), like to spend time on the same brain teaser oriented site, Teasergle. Each of them like all aspects of Teasergle, but they each gravitate to different sections (Forums, Games, and Teasers). One day, they all visited Teasergle for different lengths of time (4 hours, 8 hours, and 12 hours). Using the clue below, can you find out which friend went to what section for how long?\n\r\nThe three friends are the one who played for the least amount of time, the person whose name shares an initial with his section, and the one who boasted in the Forums that she had been on the longest.", "hint": "No hint available.", "answer": "Frederick was in the Games section for 4 hours.\r\nSara was in the Forums section for 12 hours.\r\nTim was in the Teasers section for 8 hours.", "category": "Logic-Grid", "date": "09/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree online friends, one female (Sara) and two males (Frederick and Tim), like to spend time on the same brain teaser oriented site, Teasergle. Each of them like all aspects of Teasergle, but they each gravitate to different sections (Forums, Games, and Teasers). One day, they all visited Teasergle for different lengths of time (4 hours, 8 hours, and 12 hours). Using the clue below, can you find out which friend went to what section for how long?\n\r\nThe three friends are the one who played for the least amount of time, the person whose name shares an initial with his section, and the one who boasted in the Forums that she had been on the longest.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrederick was in the Games section for 4 hours.\r\nSara was in the Forums section for 12 hours.\r\nTim was in the Teasers section for 8 hours.\n<|im_start|>answer\nFrederick was in the Games section for 4 hours.\r\nSara was in the Forums section for 12 hours.\r\nTim was in the Teasers section for 8 hours.\n<|im_end|>" }, { "id": "#26284", "title": "4 Trucks", "fun": 2.36, "difficulty": 2.16, "author": "dutchymonster", "desc": "There were four truckers, each with a different colour truck: red, green, white and blue.\r\nThey each had a different number of drops on their run.\r\nHow long was each run, and how many drops did they have?\n\r\n1) The red truck had the least number of drops.\n\r\n2) The blue truck spent 20 minutes at each drop, and only drove in exactly 1 hour stints.\n\r\n3) The white truck traveled 2 hours to his first drop, spent 30 minutes at each drop, then drove 2 hours home. All of his drops were one hour apart.\n\r\n4) The green truck left the depot before the red truck and, after completing both of his drops, returned to find the red truck was already back.", "hint": "No hint available.", "answer": "Red truck - 1 drop - 6 hours\r\nBlue truck - 3 drops - 5 hours\r\nWhite truck - 4 drops - 9 hours\r\nGreen truck - 2 drops - 8 hours", "category": "Logic-Grid", "date": "10/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were four truckers, each with a different colour truck: red, green, white and blue.\r\nThey each had a different number of drops on their run.\r\nHow long was each run, and how many drops did they have?\n\r\n1) The red truck had the least number of drops.\n\r\n2) The blue truck spent 20 minutes at each drop, and only drove in exactly 1 hour stints.\n\r\n3) The white truck traveled 2 hours to his first drop, spent 30 minutes at each drop, then drove 2 hours home. All of his drops were one hour apart.\n\r\n4) The green truck left the depot before the red truck and, after completing both of his drops, returned to find the red truck was already back.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRed truck - 1 drop - 6 hours\r\nBlue truck - 3 drops - 5 hours\r\nWhite truck - 4 drops - 9 hours\r\nGreen truck - 2 drops - 8 hours\n<|im_start|>answer\nRed truck - 1 drop - 6 hours\r\nBlue truck - 3 drops - 5 hours\r\nWhite truck - 4 drops - 9 hours\r\nGreen truck - 2 drops - 8 hours\n<|im_end|>" }, { "id": "#4441", "title": "Which Bus Stop", "fun": 2.36, "difficulty": 1.8800000000000001, "author": "mad-ade", "desc": "Every day Mad Ade takes the bus to work. He can get off at one of two stops. The first stop is 100 metres from the Spam recycling factory in which he works. The second stop is 200 metres past the Factory. Mad Ade always rides past the first stop, and gets off at the second. Why?", "hint": "No hint available.", "answer": "The factory is on a hill. When Mad Ade gets off at the stop farthest from the building he is walking downhill, and Mad Ade is quite lazy...", "category": "Logic", "date": "06/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery day Mad Ade takes the bus to work. He can get off at one of two stops. The first stop is 100 metres from the Spam recycling factory in which he works. The second stop is 200 metres past the Factory. Mad Ade always rides past the first stop, and gets off at the second. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe factory is on a hill. When Mad Ade gets off at the stop farthest from the building he is walking downhill, and Mad Ade is quite lazy...\n<|im_start|>answer\nThe factory is on a hill. When Mad Ade gets off at the stop farthest from the building he is walking downhill, and Mad Ade is quite lazy...\n<|im_end|>" }, { "id": "#2903", "title": "Jugs of Water", "fun": 2.36, "difficulty": 1.76, "author": "204_BLaZe_41", "desc": "There are two plastic jugs filled with water. How could you put all of this water into a barrel, without using the jugs or any dividers, and still tell which water came from which jug?", "hint": "No hint available.", "answer": "First, you would freeze the water in one or both jugs. Then, cut the plastic away, leaving only the ice. You could now put them into a barrel and see which water came from which jug.", "category": "Logic", "date": "03/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two plastic jugs filled with water. How could you put all of this water into a barrel, without using the jugs or any dividers, and still tell which water came from which jug?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, you would freeze the water in one or both jugs. Then, cut the plastic away, leaving only the ice. You could now put them into a barrel and see which water came from which jug.\n<|im_start|>answer\nFirst, you would freeze the water in one or both jugs. Then, cut the plastic away, leaving only the ice. You could now put them into a barrel and see which water came from which jug.\n<|im_end|>" }, { "id": "#9927", "title": "Snaps Street", "fun": 2.36, "difficulty": 1.76, "author": "snaps", "desc": "The Snapsville Town Council decided to have some fun with numbering the houses in Snaps Street which was in a new residential development in the town. For reasons known only to the Council, they elected not to use house numbers that were multiples of 3 or 4. If the last house on Snaps Street is 67, how many houses are in the street?", "hint": "No hint available.", "answer": "There are 34 houses in Snaps Street.\n\r\nThe house numbers that were used in Snaps Street were:\r\n1, 2, 5, 7, 10, 11, 13, 14, 17, 19, 22, 23, 25, 26, 29, 31, 34, 35, 37, 38, 41, 43, 46, 47, 49, 50, 53, 55, 58, 59, 61, 62, 65, 67.", "category": "Math", "date": "01/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Snapsville Town Council decided to have some fun with numbering the houses in Snaps Street which was in a new residential development in the town. For reasons known only to the Council, they elected not to use house numbers that were multiples of 3 or 4. If the last house on Snaps Street is 67, how many houses are in the street?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 34 houses in Snaps Street.\n\r\nThe house numbers that were used in Snaps Street were:\r\n1, 2, 5, 7, 10, 11, 13, 14, 17, 19, 22, 23, 25, 26, 29, 31, 34, 35, 37, 38, 41, 43, 46, 47, 49, 50, 53, 55, 58, 59, 61, 62, 65, 67.\n<|im_start|>answer\nThere are 34 houses in Snaps Street.\n\r\nThe house numbers that were used in Snaps Street were:\r\n1, 2, 5, 7, 10, 11, 13, 14, 17, 19, 22, 23, 25, 26, 29, 31, 34, 35, 37, 38, 41, 43, 46, 47, 49, 50, 53, 55, 58, 59, 61, 62, 65, 67.\n<|im_end|>" }, { "id": "#8719", "title": "Fractional Operations", "fun": 2.36, "difficulty": 1.68, "author": "lesternoronha1", "desc": "A fraction becomes 2/3 when 1 is added to both its numerator and denominator and it becomes 1/2 when 1 is subtracted from both the numerator and denominator. \n\r\nFind the fraction.", "hint": "No hint available.", "answer": "The original fraction = 3/5.\n\r\nYou can solve this fairly quickly by trial-and-error, or you can set up two equations using the information given:\n\r\n1) (x+1)/(y+1) = 2/3\r\n2) (x-1)/(y-1) = 1/2\n\r\nwhere x is the original numerator and y is the original denominator.\n\r\nFirst isolate x in equation 1:\n\r\nx+1 = 2/3*(y+1)\r\nx = 2/3*y-1/3\n\r\nPlug this value for x into equation 2:\n\r\n2/3*y - 4/3 = 1/2*(y-1)\n\r\nSolve this for y to get y = 5.\r\nPlug this value for y into equation 2 to get x = 3.\r\nTherefore the original fraction is 3/5.", "category": "Math", "date": "11/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fraction becomes 2/3 when 1 is added to both its numerator and denominator and it becomes 1/2 when 1 is subtracted from both the numerator and denominator. \n\r\nFind the fraction.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe original fraction = 3/5.\n\r\nYou can solve this fairly quickly by trial-and-error, or you can set up two equations using the information given:\n\r\n1) (x+1)/(y+1) = 2/3\r\n2) (x-1)/(y-1) = 1/2\n\r\nwhere x is the original numerator and y is the original denominator.\n\r\nFirst isolate x in equation 1:\n\r\nx+1 = 2/3*(y+1)\r\nx = 2/3*y-1/3\n\r\nPlug this value for x into equation 2:\n\r\n2/3*y - 4/3 = 1/2*(y-1)\n\r\nSolve this for y to get y = 5.\r\nPlug this value for y into equation 2 to get x = 3.\r\nTherefore the original fraction is 3/5.\n<|im_start|>answer\nThe original fraction = 3/5.\n\r\nYou can solve this fairly quickly by trial-and-error, or you can set up two equations using the information given:\n\r\n1) (x+1)/(y+1) = 2/3\r\n2) (x-1)/(y-1) = 1/2\n\r\nwhere x is the original numerator and y is the original denominator.\n\r\nFirst isolate x in equation 1:\n\r\nx+1 = 2/3*(y+1)\r\nx = 2/3*y-1/3\n\r\nPlug this value for x into equation 2:\n\r\n2/3*y - 4/3 = 1/2*(y-1)\n\r\nSolve this for y to get y = 5.\r\nPlug this value for y into equation 2 to get x = 3.\r\nTherefore the original fraction is 3/5.\n<|im_end|>" }, { "id": "#8783", "title": "Two Ladders", "fun": 2.36, "difficulty": 2.42, "author": "lesternoronha1", "desc": "There is a 6 foot wide alley. Both walls of the alley are perpendicular to the ground. Two ladders, one 10 feet long, the other 12 feet, are propped up from opposite corners to the adjacent wall, forming an X shape. All four feet of each ladder are firmly touching either the corner or the wall. The two ladders are also touching each other at the intersection of the X shape. What is the distance from the point of intersection to the ground?", "hint": "No hint available.", "answer": "The answer is sqrt(108)/(1+(sqrt(108)/8)) =~ 4.52 feet.\n\r\nConsider the two ladders two lines on a graph. Let the shorter ladder extend from (0,0) to (6,8). Let the longer ladder extend from (6,0) to (0,sqrt(108)). The square root of 108 can be found using the Pythagorean formula. Then solve for the slope and y intercept to find the equations of the two lines: \r\nThe shorter ladder has the equation y=(4/3)*x. \r\nThe longer ladder has the equation y=(-sqrt(108)/6)*x + sqrt(108). \r\nThe lines meet where the ladders cross. \r\nUse substitution to solve for y.", "category": "Math", "date": "11/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a 6 foot wide alley. Both walls of the alley are perpendicular to the ground. Two ladders, one 10 feet long, the other 12 feet, are propped up from opposite corners to the adjacent wall, forming an X shape. All four feet of each ladder are firmly touching either the corner or the wall. The two ladders are also touching each other at the intersection of the X shape. What is the distance from the point of intersection to the ground?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is sqrt(108)/(1+(sqrt(108)/8)) =~ 4.52 feet.\n\r\nConsider the two ladders two lines on a graph. Let the shorter ladder extend from (0,0) to (6,8). Let the longer ladder extend from (6,0) to (0,sqrt(108)). The square root of 108 can be found using the Pythagorean formula. Then solve for the slope and y intercept to find the equations of the two lines: \r\nThe shorter ladder has the equation y=(4/3)*x. \r\nThe longer ladder has the equation y=(-sqrt(108)/6)*x + sqrt(108). \r\nThe lines meet where the ladders cross. \r\nUse substitution to solve for y.\n<|im_start|>answer\nThe answer is sqrt(108)/(1+(sqrt(108)/8)) =~ 4.52 feet.\n\r\nConsider the two ladders two lines on a graph. Let the shorter ladder extend from (0,0) to (6,8). Let the longer ladder extend from (6,0) to (0,sqrt(108)). The square root of 108 can be found using the Pythagorean formula. Then solve for the slope and y intercept to find the equations of the two lines: \r\nThe shorter ladder has the equation y=(4/3)*x. \r\nThe longer ladder has the equation y=(-sqrt(108)/6)*x + sqrt(108). \r\nThe lines meet where the ladders cross. \r\nUse substitution to solve for y.\n<|im_end|>" }, { "id": "#19621", "title": "Mad Ade's Blocks #2", "fun": 2.35, "difficulty": 2.78, "author": "Mad-Ade", "desc": "Mad Ade is once again babysitting for family. The devil's spawn...er...three year old nephew he is watching is playing with some painted wooden blocks that have letters on the side, much like they did in teaser #15201.\r\nOnce again there are four blocks, each with a different letter on each side, making a total of 24 letters altogether.\r\nMad Ade noticed that the devil's...er...his nephew managed to make the following words from the four blocks.\r\nBOXY, \r\nBUCK, \r\nCHAW, \r\nDIGS, \r\nEXAM, \r\nFLIT,\r\nGIRL, \r\nJUMP, \r\nOGRE, \r\nOKAY, \r\nPAWN, \r\nZEST \n\r\nNow Mad Ade is relatively simple and once more missed the potential teaser in the situation, his mind firmly fixed on Kebabs.\r\nCan you figure out how the letters are arranged on the 4 blocks?", "hint": "No hint available.", "answer": "Block 1: A, B, F, J, R, and S.\r\nBlock 2: D, E, L, U, W, and Y.\r\nBlock 3: C, I, M, N, O, and Z.\r\nBlock 4: G, H, K, P, T, and X.\n\r\nFrom the word EXAM, we conclude that E and A are not on the same block.\r\nFrom the word OGRE, we conclude that E and O are not on the same block.\r\nFrom the word OKAY, we conclude that A and O are not on the same block.\r\nCombining these, we conclude that A, E, and O are on different blocks. Assume that A is on block 1, E is on block 2, and O is on block 3. \r\nFrom the words BOXY and EXAM, we conclude that X is not on the same block as A (block 1), E (block 2), and O (block 3), so X is on block 4.\r\nFrom the words BOXY and OKAY, we conclude that Y is not on the same block as A (block 1), O (block 3), and X (block 4), so Y is on block 2.\r\nFrom the word EXAM, we conclude that M is not on the same block as A (block 1), E (block 2), and X (block 4), so M is on block 3.\r\nFrom the word OKAY, we conclude that K is not on the same block as A (block 1), Y (block 2), and O (block 3), so K is on block 4.\r\nFrom the word BOXY, we conclude that B is not on the same block as Y (block 2), O (block 3), and X (block 4), so B is on block 1.\r\nFrom the words BUCK and JUMP, we conclude that U is not on the same block as B (block 1), M (block 3), and K (block 4), so U is on block 2.\r\nFrom the words PAWN and JUMP, we conclude that P is not on the same block as A (block 1), U (block 2), and M (block 3), so P is on block 4.\r\nFrom the word JUMP, we conclude that J is not on the same block as U (block 2), M (block 3), and P (block 4), so J is on block 1.\r\nFrom the words CHAW and BUCK, we conclude that C is not on the same block as A (block 1), U (block 2), and K (block 4), so C is on block 3.\r\nFrom the words CHAW and PAWN, we conclude that W is not on the same block as A (block 1), C (block 3), and P (block 4), so W is on block 2.\r\nFrom the word CHAW, we conclude that H is not on the same block as A (block 1), W (block 2), and C (block 3), so H is on block 4.\r\nFrom the word PAWN, we conclude that N is not on the same block as A (block 1), W (block 2), and P (block 4), so N is on block 3.\n\n\r\nNow, we must still have three letters for block 1, and two letters for each of the blocks 2, 3, and 4. We have the following letters left: \n\n\r\nD, F, G, I, L, R, S, T, Z \r\nFrom the words DIGS, FLIT and GIRL, we conclude that I is not on the same block as D, F, G, L, R, S, and T, so I is on the same block as Z. Furthermore, I and Z are on block 2, 3, or 4.\r\nFrom the word ZEST, we conclude that Z is not on the same block as E (block 2), so Z is on block 3 or 4.\r\nFrom the word OGRE, we conclude that G and R are not on the same block as E (block 2), and O (block 3), so G and R are on block 1 or 4, but not on the same block.\r\nFrom the word GIRL, we conclude that I is not on the same block as G and R (block 1 or 4), so I is on block 2 or 3. Since Z is on block 3 or 4, I and Z must be on block 3. Now we have all six letters of block 3: C, I, M, N, O, and Z.\n\n\r\nFrom the word GIRL, we conclude that L is not on the same block as G and R (block 1 and 4), so L is on block 2.\r\nFrom the words FLIT and GIRL, we conclude that F, G, L, R, and T are not on the same block as L (block 2), and from the word ZEST, we conclude that S is not on the same block as E (block 2). So D must be on block 2.\r\nNow we have all six letters of block 2: D, E, L, U, W, and Y.\n\n\r\nFrom the words GIRL and DIGS, we conclude that G is not on the same block as R and S.\r\nFrom the words FLIT and ZEST, we conclude that T is not on the same block as F and S.\r\nCombining this, F, R, and S must be on the same block (block 1), and G and T must be on the same block (block 4).", "category": "Logic", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is once again babysitting for family. The devil's spawn...er...three year old nephew he is watching is playing with some painted wooden blocks that have letters on the side, much like they did in teaser #15201.\r\nOnce again there are four blocks, each with a different letter on each side, making a total of 24 letters altogether.\r\nMad Ade noticed that the devil's...er...his nephew managed to make the following words from the four blocks.\r\nBOXY, \r\nBUCK, \r\nCHAW, \r\nDIGS, \r\nEXAM, \r\nFLIT,\r\nGIRL, \r\nJUMP, \r\nOGRE, \r\nOKAY, \r\nPAWN, \r\nZEST \n\r\nNow Mad Ade is relatively simple and once more missed the potential teaser in the situation, his mind firmly fixed on Kebabs.\r\nCan you figure out how the letters are arranged on the 4 blocks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlock 1: A, B, F, J, R, and S.\r\nBlock 2: D, E, L, U, W, and Y.\r\nBlock 3: C, I, M, N, O, and Z.\r\nBlock 4: G, H, K, P, T, and X.\n\r\nFrom the word EXAM, we conclude that E and A are not on the same block.\r\nFrom the word OGRE, we conclude that E and O are not on the same block.\r\nFrom the word OKAY, we conclude that A and O are not on the same block.\r\nCombining these, we conclude that A, E, and O are on different blocks. Assume that A is on block 1, E is on block 2, and O is on block 3. \r\nFrom the words BOXY and EXAM, we conclude that X is not on the same block as A (block 1), E (block 2), and O (block 3), so X is on block 4.\r\nFrom the words BOXY and OKAY, we conclude that Y is not on the same block as A (block 1), O (block 3), and X (block 4), so Y is on block 2.\r\nFrom the word EXAM, we conclude that M is not on the same block as A (block 1), E (block 2), and X (block 4), so M is on block 3.\r\nFrom the word OKAY, we conclude that K is not on the same block as A (block 1), Y (block 2), and O (block 3), so K is on block 4.\r\nFrom the word BOXY, we conclude that B is not on the same block as Y (block 2), O (block 3), and X (block 4), so B is on block 1.\r\nFrom the words BUCK and JUMP, we conclude that U is not on the same block as B (block 1), M (block 3), and K (block 4), so U is on block 2.\r\nFrom the words PAWN and JUMP, we conclude that P is not on the same block as A (block 1), U (block 2), and M (block 3), so P is on block 4.\r\nFrom the word JUMP, we conclude that J is not on the same block as U (block 2), M (block 3), and P (block 4), so J is on block 1.\r\nFrom the words CHAW and BUCK, we conclude that C is not on the same block as A (block 1), U (block 2), and K (block 4), so C is on block 3.\r\nFrom the words CHAW and PAWN, we conclude that W is not on the same block as A (block 1), C (block 3), and P (block 4), so W is on block 2.\r\nFrom the word CHAW, we conclude that H is not on the same block as A (block 1), W (block 2), and C (block 3), so H is on block 4.\r\nFrom the word PAWN, we conclude that N is not on the same block as A (block 1), W (block 2), and P (block 4), so N is on block 3.\n\n\r\nNow, we must still have three letters for block 1, and two letters for each of the blocks 2, 3, and 4. We have the following letters left: \n\n\r\nD, F, G, I, L, R, S, T, Z \r\nFrom the words DIGS, FLIT and GIRL, we conclude that I is not on the same block as D, F, G, L, R, S, and T, so I is on the same block as Z. Furthermore, I and Z are on block 2, 3, or 4.\r\nFrom the word ZEST, we conclude that Z is not on the same block as E (block 2), so Z is on block 3 or 4.\r\nFrom the word OGRE, we conclude that G and R are not on the same block as E (block 2), and O (block 3), so G and R are on block 1 or 4, but not on the same block.\r\nFrom the word GIRL, we conclude that I is not on the same block as G and R (block 1 or 4), so I is on block 2 or 3. Since Z is on block 3 or 4, I and Z must be on block 3. Now we have all six letters of block 3: C, I, M, N, O, and Z.\n\n\r\nFrom the word GIRL, we conclude that L is not on the same block as G and R (block 1 and 4), so L is on block 2.\r\nFrom the words FLIT and GIRL, we conclude that F, G, L, R, and T are not on the same block as L (block 2), and from the word ZEST, we conclude that S is not on the same block as E (block 2). So D must be on block 2.\r\nNow we have all six letters of block 2: D, E, L, U, W, and Y.\n\n\r\nFrom the words GIRL and DIGS, we conclude that G is not on the same block as R and S.\r\nFrom the words FLIT and ZEST, we conclude that T is not on the same block as F and S.\r\nCombining this, F, R, and S must be on the same block (block 1), and G and T must be on the same block (block 4).\n<|im_start|>answer\nBlock 1: A, B, F, J, R, and S.\r\nBlock 2: D, E, L, U, W, and Y.\r\nBlock 3: C, I, M, N, O, and Z.\r\nBlock 4: G, H, K, P, T, and X.\n\r\nFrom the word EXAM, we conclude that E and A are not on the same block.\r\nFrom the word OGRE, we conclude that E and O are not on the same block.\r\nFrom the word OKAY, we conclude that A and O are not on the same block.\r\nCombining these, we conclude that A, E, and O are on different blocks. Assume that A is on block 1, E is on block 2, and O is on block 3. \r\nFrom the words BOXY and EXAM, we conclude that X is not on the same block as A (block 1), E (block 2), and O (block 3), so X is on block 4.\r\nFrom the words BOXY and OKAY, we conclude that Y is not on the same block as A (block 1), O (block 3), and X (block 4), so Y is on block 2.\r\nFrom the word EXAM, we conclude that M is not on the same block as A (block 1), E (block 2), and X (block 4), so M is on block 3.\r\nFrom the word OKAY, we conclude that K is not on the same block as A (block 1), Y (block 2), and O (block 3), so K is on block 4.\r\nFrom the word BOXY, we conclude that B is not on the same block as Y (block 2), O (block 3), and X (block 4), so B is on block 1.\r\nFrom the words BUCK and JUMP, we conclude that U is not on the same block as B (block 1), M (block 3), and K (block 4), so U is on block 2.\r\nFrom the words PAWN and JUMP, we conclude that P is not on the same block as A (block 1), U (block 2), and M (block 3), so P is on block 4.\r\nFrom the word JUMP, we conclude that J is not on the same block as U (block 2), M (block 3), and P (block 4), so J is on block 1.\r\nFrom the words CHAW and BUCK, we conclude that C is not on the same block as A (block 1), U (block 2), and K (block 4), so C is on block 3.\r\nFrom the words CHAW and PAWN, we conclude that W is not on the same block as A (block 1), C (block 3), and P (block 4), so W is on block 2.\r\nFrom the word CHAW, we conclude that H is not on the same block as A (block 1), W (block 2), and C (block 3), so H is on block 4.\r\nFrom the word PAWN, we conclude that N is not on the same block as A (block 1), W (block 2), and P (block 4), so N is on block 3.\n\n\r\nNow, we must still have three letters for block 1, and two letters for each of the blocks 2, 3, and 4. We have the following letters left: \n\n\r\nD, F, G, I, L, R, S, T, Z \r\nFrom the words DIGS, FLIT and GIRL, we conclude that I is not on the same block as D, F, G, L, R, S, and T, so I is on the same block as Z. Furthermore, I and Z are on block 2, 3, or 4.\r\nFrom the word ZEST, we conclude that Z is not on the same block as E (block 2), so Z is on block 3 or 4.\r\nFrom the word OGRE, we conclude that G and R are not on the same block as E (block 2), and O (block 3), so G and R are on block 1 or 4, but not on the same block.\r\nFrom the word GIRL, we conclude that I is not on the same block as G and R (block 1 or 4), so I is on block 2 or 3. Since Z is on block 3 or 4, I and Z must be on block 3. Now we have all six letters of block 3: C, I, M, N, O, and Z.\n\n\r\nFrom the word GIRL, we conclude that L is not on the same block as G and R (block 1 and 4), so L is on block 2.\r\nFrom the words FLIT and GIRL, we conclude that F, G, L, R, and T are not on the same block as L (block 2), and from the word ZEST, we conclude that S is not on the same block as E (block 2). So D must be on block 2.\r\nNow we have all six letters of block 2: D, E, L, U, W, and Y.\n\n\r\nFrom the words GIRL and DIGS, we conclude that G is not on the same block as R and S.\r\nFrom the words FLIT and ZEST, we conclude that T is not on the same block as F and S.\r\nCombining this, F, R, and S must be on the same block (block 1), and G and T must be on the same block (block 4).\n<|im_end|>" }, { "id": "#4466", "title": "The Chompem Cannibals", "fun": 2.35, "difficulty": 1.52, "author": "arij", "desc": "The Chompem Cannibals of Drybone Island have the annoying habit of eating each other. In fact, Grandpa Chompem went missing only last week, and it was thought he'd lost his way home until his bits and pieces were found on the beach. One evening, the Chompems threw a dinner party, one of those bring-a-friend get-togethers. Six cannibals turned up and they decided to eat each other in turn. So someone was selected for everyone to eat (except the victim!), and when he had been eaten, someone else was selected, and so on. If it took one cannibal two hours on his own to devour one person, how long was it before just one consumer remained?", "hint": "No hint available.", "answer": "It took 4 hours 34 minutes for one cannibal to remain. It took 5 cannibals, 2/5 hours to eat the first victim, four cannibals 2/4 hours to devour the second, three cannibals 2/3 hours for the third, two cannibals 2/2 hours for the fourth and one cannibal 2/1 hours for the fifth.", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Chompem Cannibals of Drybone Island have the annoying habit of eating each other. In fact, Grandpa Chompem went missing only last week, and it was thought he'd lost his way home until his bits and pieces were found on the beach. One evening, the Chompems threw a dinner party, one of those bring-a-friend get-togethers. Six cannibals turned up and they decided to eat each other in turn. So someone was selected for everyone to eat (except the victim!), and when he had been eaten, someone else was selected, and so on. If it took one cannibal two hours on his own to devour one person, how long was it before just one consumer remained?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt took 4 hours 34 minutes for one cannibal to remain. It took 5 cannibals, 2/5 hours to eat the first victim, four cannibals 2/4 hours to devour the second, three cannibals 2/3 hours for the third, two cannibals 2/2 hours for the fourth and one cannibal 2/1 hours for the fifth.\n<|im_start|>answer\nIt took 4 hours 34 minutes for one cannibal to remain. It took 5 cannibals, 2/5 hours to eat the first victim, four cannibals 2/4 hours to devour the second, three cannibals 2/3 hours for the third, two cannibals 2/2 hours for the fourth and one cannibal 2/1 hours for the fifth.\n<|im_end|>" }, { "id": "#4472", "title": "Kebab Kidnap", "fun": 2.35, "difficulty": 1.67, "author": "mad-ade", "desc": "Mad Ade was kidnapped by the K.L.F (Kebab Liberation Federation), and taken to a hideout. From overheard conversation, he knew he was either in London, England or in Sydney, Australia. He was drugged by using a decoy Kebab and transported, and when he came to, he had been locked in a room with no windows or other way to see outside. There was a table, a bed, a chair, and a sink in the room, but nothing else. However, Mad Ade was able to easily figure out which city he was in. How did Mad Ade do it?", "hint": "No hint available.", "answer": "Since water drains counter-clockwise in the northern hemisphere (London), and clockwise in the southern hemisphere (Sidney), Mad Ade simply put some water in the sink and watched which way it drained.", "category": "Logic", "date": "06/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was kidnapped by the K.L.F (Kebab Liberation Federation), and taken to a hideout. From overheard conversation, he knew he was either in London, England or in Sydney, Australia. He was drugged by using a decoy Kebab and transported, and when he came to, he had been locked in a room with no windows or other way to see outside. There was a table, a bed, a chair, and a sink in the room, but nothing else. However, Mad Ade was able to easily figure out which city he was in. How did Mad Ade do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince water drains counter-clockwise in the northern hemisphere (London), and clockwise in the southern hemisphere (Sidney), Mad Ade simply put some water in the sink and watched which way it drained.\n<|im_start|>answer\nSince water drains counter-clockwise in the northern hemisphere (London), and clockwise in the southern hemisphere (Sidney), Mad Ade simply put some water in the sink and watched which way it drained.\n<|im_end|>" }, { "id": "#3730", "title": "Light Bulb Flipping", "fun": 2.35, "difficulty": 1.72, "author": "Mogmatt16", "desc": "Assume you have a switch to a light bulb. It starts out off. After half a minute, you flip the switch. After a quarter of a minute you flip the switch again. And do so after an eighth, a sixteenth, and a thirty-second, and so on. At the end of the minute, is the bulb on or off?", "hint": "There could be three answers here.", "answer": "There are three answers depending on how you think about it.\n\r\n1) I never said the switch was flipped again, so it would be on.\n\r\n2) No Light bulb could go that fast so most likely it would be burned out.\n\r\n3) You can't answer this because the light switch would be flipped infinitely many times before the minute was over. And infinity isn't odd or even.", "category": "Logic", "date": "04/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAssume you have a switch to a light bulb. It starts out off. After half a minute, you flip the switch. After a quarter of a minute you flip the switch again. And do so after an eighth, a sixteenth, and a thirty-second, and so on. At the end of the minute, is the bulb on or off?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are three answers depending on how you think about it.\n\r\n1) I never said the switch was flipped again, so it would be on.\n\r\n2) No Light bulb could go that fast so most likely it would be burned out.\n\r\n3) You can't answer this because the light switch would be flipped infinitely many times before the minute was over. And infinity isn't odd or even.\n<|im_start|>answer\nThere are three answers depending on how you think about it.\n\r\n1) I never said the switch was flipped again, so it would be on.\n\r\n2) No Light bulb could go that fast so most likely it would be burned out.\n\r\n3) You can't answer this because the light switch would be flipped infinitely many times before the minute was over. And infinity isn't odd or even.\n<|im_end|>" }, { "id": "#4568", "title": "Jack's Eyes", "fun": 2.35, "difficulty": 1.22, "author": "mad-ade", "desc": "At a card game Mad Ade asked a question. \"In an ordinary deck of playing cards, two of the Jacks have two eyes and two of the Jacks have one eye. How many eyes are on all four Jack cards?\"", "hint": "No hint available.", "answer": "12 (Remember, each card has 2 faces)", "category": "Logic", "date": "06/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a card game Mad Ade asked a question. \"In an ordinary deck of playing cards, two of the Jacks have two eyes and two of the Jacks have one eye. How many eyes are on all four Jack cards?\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12 (Remember, each card has 2 faces)\n<|im_start|>answer\n12 (Remember, each card has 2 faces)\n<|im_end|>" }, { "id": "#966", "title": "Pigeon", "fun": 2.35, "difficulty": 1.69, "author": "Michelle", "desc": "Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 18 MPH between the 2 friends until the friends meet. How far does the pigeon travel?", "hint": "No hint available.", "answer": "It takes 3 hours for the friends to meet; so the pigeon flies for 3 hours at 18 MPH=54 miles.", "category": "Math", "date": "10/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 18 MPH between the 2 friends until the friends meet. How far does the pigeon travel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt takes 3 hours for the friends to meet; so the pigeon flies for 3 hours at 18 MPH=54 miles.\n<|im_start|>answer\nIt takes 3 hours for the friends to meet; so the pigeon flies for 3 hours at 18 MPH=54 miles.\n<|im_end|>" }, { "id": "#25846", "title": "The Chocolate Catastrophe", "fun": 2.35, "difficulty": 0.73, "author": "twixy", "desc": "Four girls (Nikki, Tara, Clarissa, and Cindy) all wanted to buy their friend Cleo gifts for her birthday. However, when they got to her house, they realized they had all given her chocolates and an extra gift.\n\r\nChocolates: cherry cordials, chocolate truffles, Hershey's chocolate, or Reese's Pieces. \n\r\nExtra Gift: a movie, a CD, a board game, or makeup. \n\r\nWho gave what?\n\r\nThe person who bought the cherry cordials also bought a CD.\n\r\nOne person bought chocolates and an extra gift that both started with the same letter as her first name.\n\r\nTara did not give makeup.\n\r\nNikki was about to buy a board game for Cleo, but in the end decided that she should buy something else.\n\r\nClarissa did not buy a CD.\n\r\nTara bought Cleo's favorite chocolate.\n\r\nNikki was about to buy Cleo's favorite chocolate, but decided not to in the end.\n\r\nCleo's favorite chocolates are chocolate truffles.\n\r\nClarissa knew that Cleo wanted new mascara, so she decided to buy that for her.\n\r\nNikki bought Reese's Pieces.\n\r\nTara bought the board game Clue.", "hint": "No hint available.", "answer": "Nikki gave Reese's Pieces and a movie.\r\nTara gave chocolate truffles and a board game.\r\nClarissa gave Hershey's Chocolate and makeup.\r\nCindy gave cherry cordials and a CD.", "category": "Logic-Grid", "date": "09/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour girls (Nikki, Tara, Clarissa, and Cindy) all wanted to buy their friend Cleo gifts for her birthday. However, when they got to her house, they realized they had all given her chocolates and an extra gift.\n\r\nChocolates: cherry cordials, chocolate truffles, Hershey's chocolate, or Reese's Pieces. \n\r\nExtra Gift: a movie, a CD, a board game, or makeup. \n\r\nWho gave what?\n\r\nThe person who bought the cherry cordials also bought a CD.\n\r\nOne person bought chocolates and an extra gift that both started with the same letter as her first name.\n\r\nTara did not give makeup.\n\r\nNikki was about to buy a board game for Cleo, but in the end decided that she should buy something else.\n\r\nClarissa did not buy a CD.\n\r\nTara bought Cleo's favorite chocolate.\n\r\nNikki was about to buy Cleo's favorite chocolate, but decided not to in the end.\n\r\nCleo's favorite chocolates are chocolate truffles.\n\r\nClarissa knew that Cleo wanted new mascara, so she decided to buy that for her.\n\r\nNikki bought Reese's Pieces.\n\r\nTara bought the board game Clue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNikki gave Reese's Pieces and a movie.\r\nTara gave chocolate truffles and a board game.\r\nClarissa gave Hershey's Chocolate and makeup.\r\nCindy gave cherry cordials and a CD.\n<|im_start|>answer\nNikki gave Reese's Pieces and a movie.\r\nTara gave chocolate truffles and a board game.\r\nClarissa gave Hershey's Chocolate and makeup.\r\nCindy gave cherry cordials and a CD.\n<|im_end|>" }, { "id": "#38364", "title": "Flip 100 Coins", "fun": 2.35, "difficulty": 2.83, "author": "smarty__blondy", "desc": "Tom has 100 coins on the table with their heads up. Each time he flips 93 coins, turning heads to tails or vice versa. \n\r\nWhat is the least number of times he must do this in order to get all of them tails up?", "hint": "Maybe you have seen the \"flip 7 in 10\" problem and think this one is also 4, but it isn't, because the logic is a little different.", "answer": "If you have seen the \"flip 9 in 10\" problem, you know that you have to leave one coin unflipped each time, and it will require 10 times.\n\r\nIn this problem, the first time leaves 7 coins heads up, the second time leaves at most 14 coins TAILS up, the third time leaves at most 21 coins HEADS up, the fourth time leaves at most 28 coins TAILS up, ..., and the fourteenth time leaves at most 98 coins tails up.\n\r\nThe fifteenth time, he flips 1 of the 2 coins that is heads up, and 92 of the coins that are tails up, leaving 93 coins heads up.\n\r\nThe sixteenth and last time he can get all of them tails up.", "category": "Math", "date": "09/19/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTom has 100 coins on the table with their heads up. Each time he flips 93 coins, turning heads to tails or vice versa. \n\r\nWhat is the least number of times he must do this in order to get all of them tails up?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you have seen the \"flip 9 in 10\" problem, you know that you have to leave one coin unflipped each time, and it will require 10 times.\n\r\nIn this problem, the first time leaves 7 coins heads up, the second time leaves at most 14 coins TAILS up, the third time leaves at most 21 coins HEADS up, the fourth time leaves at most 28 coins TAILS up, ..., and the fourteenth time leaves at most 98 coins tails up.\n\r\nThe fifteenth time, he flips 1 of the 2 coins that is heads up, and 92 of the coins that are tails up, leaving 93 coins heads up.\n\r\nThe sixteenth and last time he can get all of them tails up.\n<|im_start|>answer\nIf you have seen the \"flip 9 in 10\" problem, you know that you have to leave one coin unflipped each time, and it will require 10 times.\n\r\nIn this problem, the first time leaves 7 coins heads up, the second time leaves at most 14 coins TAILS up, the third time leaves at most 21 coins HEADS up, the fourth time leaves at most 28 coins TAILS up, ..., and the fourteenth time leaves at most 98 coins tails up.\n\r\nThe fifteenth time, he flips 1 of the 2 coins that is heads up, and 92 of the coins that are tails up, leaving 93 coins heads up.\n\r\nThe sixteenth and last time he can get all of them tails up.\n<|im_end|>" }, { "id": "#35422", "title": "T4 and D4", "fun": 2.35, "difficulty": 1.97, "author": "t4mt", "desc": "D4 was trying to impress everyone at T4's birthday party by giving T4 a math problem. Celebrating 1994, T4's birth year, what is the 1994th digit in the decimal expansion of 1/7 to the right of the decimal point?", "hint": "Actually do the math for a bit...", "answer": "4.\n\r\nAny number not a multiple of 7 will divide out with the pattern 1,4,2,8,5, and 7. 1/7 is simply 0.1428571428571428571428757... Divide 1994 by 6 and get 332 with remainder 2. 4 is the second digit of the six-digit pattern, so it is also the 1994th digit.", "category": "Math", "date": "02/24/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nD4 was trying to impress everyone at T4's birthday party by giving T4 a math problem. Celebrating 1994, T4's birth year, what is the 1994th digit in the decimal expansion of 1/7 to the right of the decimal point?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4.\n\r\nAny number not a multiple of 7 will divide out with the pattern 1,4,2,8,5, and 7. 1/7 is simply 0.1428571428571428571428757... Divide 1994 by 6 and get 332 with remainder 2. 4 is the second digit of the six-digit pattern, so it is also the 1994th digit.\n<|im_start|>answer\n4.\n\r\nAny number not a multiple of 7 will divide out with the pattern 1,4,2,8,5, and 7. 1/7 is simply 0.1428571428571428571428757... Divide 1994 by 6 and get 332 with remainder 2. 4 is the second digit of the six-digit pattern, so it is also the 1994th digit.\n<|im_end|>" }, { "id": "#19517", "title": "Mad Ade's Special Number", "fun": 2.35, "difficulty": 1.92, "author": "Mad-Ade", "desc": "Whilst looking in the phone book for the new phone number of the \"Sweaty Chef Kebab Shop\" Mad Ade came across the six digit number 312132 . He noticed that this number has a very interesting attribute: 1 digit exists between the two 1s, 2 digits exist between the two 2's and 3 digits exist between the two 3s. \r\nMad Ade wondered if he could add two more 4s with 4 digits between the two 4s to make an eight digit number that still holds the above attributes? \r\nObviously Mad Ade never found the answer because he found the phone number he was after. Can you find a possible answer?", "hint": "No hint available.", "answer": "41312432 or 23421314. Of course these 2 numbers are actually the same, just reverse one to become another one.", "category": "Logic", "date": "11/23/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhilst looking in the phone book for the new phone number of the \"Sweaty Chef Kebab Shop\" Mad Ade came across the six digit number 312132 . He noticed that this number has a very interesting attribute: 1 digit exists between the two 1s, 2 digits exist between the two 2's and 3 digits exist between the two 3s. \r\nMad Ade wondered if he could add two more 4s with 4 digits between the two 4s to make an eight digit number that still holds the above attributes? \r\nObviously Mad Ade never found the answer because he found the phone number he was after. Can you find a possible answer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n41312432 or 23421314. Of course these 2 numbers are actually the same, just reverse one to become another one.\n<|im_start|>answer\n41312432 or 23421314. Of course these 2 numbers are actually the same, just reverse one to become another one.\n<|im_end|>" }, { "id": "#4913", "title": "Dots on a Die", "fun": 2.35, "difficulty": 2.31, "author": "Mogmatt16", "desc": "What is the greatest number of dots you can see on a six-sided die if you don't use mirrors? Assume you have 20/20 vision.", "hint": "Don't say 15.", "answer": "20. Hold the die so you can see the 6 side dead on. Then, turn it to put the 6 side on its corner. Then, put it between your eyes, and cross your eyes. You should be able to see the 5,4,3, and 2 side.", "category": "Logic", "date": "06/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the greatest number of dots you can see on a six-sided die if you don't use mirrors? Assume you have 20/20 vision.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20. Hold the die so you can see the 6 side dead on. Then, turn it to put the 6 side on its corner. Then, put it between your eyes, and cross your eyes. You should be able to see the 5,4,3, and 2 side.\n<|im_start|>answer\n20. Hold the die so you can see the 6 side dead on. Then, turn it to put the 6 side on its corner. Then, put it between your eyes, and cross your eyes. You should be able to see the 5,4,3, and 2 side.\n<|im_end|>" }, { "id": "#10376", "title": "Day at the Beach", "fun": 2.35, "difficulty": 1.37, "author": "IronMaiden980", "desc": "Lenny, Lance, Lulu, and Laura enjoy a good game of tug-of-war every time they visit the beach. Lance can outpull Lenny and Lulu together. Lance and Lenny together match up evenly against Laura and Lulu, but if Lulu and Lenny switch places, then Laura and Lenny can win easily. Name the four beachgoers in order of how strong they are.", "hint": "No hint available.", "answer": "From strongest to weakest: Laura, Lance, Lenny, Lulu", "category": "Logic", "date": "02/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLenny, Lance, Lulu, and Laura enjoy a good game of tug-of-war every time they visit the beach. Lance can outpull Lenny and Lulu together. Lance and Lenny together match up evenly against Laura and Lulu, but if Lulu and Lenny switch places, then Laura and Lenny can win easily. Name the four beachgoers in order of how strong they are.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom strongest to weakest: Laura, Lance, Lenny, Lulu\n<|im_start|>answer\nFrom strongest to weakest: Laura, Lance, Lenny, Lulu\n<|im_end|>" }, { "id": "#34321", "title": "Easy As Cake, Junior", "fun": 2.35, "difficulty": 2.73, "author": "stil", "desc": "In our business, my two partners and I usually cut a lot of cake. However, when we get a last minute cancellation, we sometimes look for new and unusual ways to cut small amounts of cake.\r\nOn one such occasion, we tried to find a cake with an unusual set of attributes.\r\nFirst, it had to be a regular polygon, i.e. all sides equal in length and all angles equal in size.\r\nSecond, using only standard cuts (straight and perpendicular to the plate) from some corner to another, we would be able to exactly divide that polygon into equal portions.\r\nThird, except for the last cut, each cut would create one, and only one, such portion. The last cut would create two such portions.\r\nFourth, there must be more than two portions. (Otherwise, a square or any regular polygon with an even number of sides would do. A cut from one corner to its opposing corner would carve out two pieces of 50% each.)\r\nFor discussion purposes, we decided to label the points of our polygons alphabetically. A pentagon can only produce three pieces. Triangles ABC and CDE are equals, but triangle ACE is larger. A hexagon yields three or four pieces, but they will be of two different sizes. Triangles ABC = CDE = EFA <> ACE, or triangles ABC = DEF <> CDF = FAC. Etc.\r\nAbout this time, Junior, our partner-in-waiting, said, \"Cousins, I can do this, and I'll get to take a share of the cake.\"\r\nKnowing Junior, we asked, \"How big a headache is your math gonna give us?\"\r\nShe answered, \"I can prove it without using trig, powers, roots, or the Pythagorean Theorem.\" \r\nName the polygon she chose, tell how to divide it, and if you can, give proof the portions are equal.", "hint": "Junior's proof uses fact that all dimensions of an isosceles right triangle are determined by its name and the length of its hypotenuse.", "answer": "Junior knew an octagon would sequentially yield four quarters.\r\nAfter labeling the points of a perfect octagon, Junior told us, \"Before I cut the cake, I'll give the proof. First, I mark a line from A to D. This creates a trapezoid (trapezium in Britain) ABCD. Next, I mark the lines EH, BG, and CF. These four lines crosshatch the area dividing it into 1 square surrounded by 4 equal triangles and 4 equal rectangles.\"\r\nThe partners (me included) chimed in with the rest of these observations: The sides of the square are the same length as those of the octagon. Dividing the central square into isosceles right triangles (by marking both of its diagonals) would yield 4 triangles equivalent to the first 4. The total area of the octagon can be accounted for by 8 equal triangles and 4 equal rectangles. Because it is made of 2 triangles and 1 rectangle, trapezoid ABCD is 1/4 of the octagon. A second trapezoid taken from the irregular hexagon ADEFGH will equal 1/4 of the octagon and leave 1/2 of the original octagon in the shape of a rectangle or a kite, either of which is easily split to provide the last two 1/4's. (The second and third cuts can be made in reverse order.)\r\n...\r\nThe pieces from two arrangements follow:\r\n1) ABCD, DEFG, ADH, and DGH.\r\n2) ABCD, EFGH, ADH, and DEH.", "category": "Math", "date": "12/09/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn our business, my two partners and I usually cut a lot of cake. However, when we get a last minute cancellation, we sometimes look for new and unusual ways to cut small amounts of cake.\r\nOn one such occasion, we tried to find a cake with an unusual set of attributes.\r\nFirst, it had to be a regular polygon, i.e. all sides equal in length and all angles equal in size.\r\nSecond, using only standard cuts (straight and perpendicular to the plate) from some corner to another, we would be able to exactly divide that polygon into equal portions.\r\nThird, except for the last cut, each cut would create one, and only one, such portion. The last cut would create two such portions.\r\nFourth, there must be more than two portions. (Otherwise, a square or any regular polygon with an even number of sides would do. A cut from one corner to its opposing corner would carve out two pieces of 50% each.)\r\nFor discussion purposes, we decided to label the points of our polygons alphabetically. A pentagon can only produce three pieces. Triangles ABC and CDE are equals, but triangle ACE is larger. A hexagon yields three or four pieces, but they will be of two different sizes. Triangles ABC = CDE = EFA <> ACE, or triangles ABC = DEF <> CDF = FAC. Etc.\r\nAbout this time, Junior, our partner-in-waiting, said, \"Cousins, I can do this, and I'll get to take a share of the cake.\"\r\nKnowing Junior, we asked, \"How big a headache is your math gonna give us?\"\r\nShe answered, \"I can prove it without using trig, powers, roots, or the Pythagorean Theorem.\" \r\nName the polygon she chose, tell how to divide it, and if you can, give proof the portions are equal.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJunior knew an octagon would sequentially yield four quarters.\r\nAfter labeling the points of a perfect octagon, Junior told us, \"Before I cut the cake, I'll give the proof. First, I mark a line from A to D. This creates a trapezoid (trapezium in Britain) ABCD. Next, I mark the lines EH, BG, and CF. These four lines crosshatch the area dividing it into 1 square surrounded by 4 equal triangles and 4 equal rectangles.\"\r\nThe partners (me included) chimed in with the rest of these observations: The sides of the square are the same length as those of the octagon. Dividing the central square into isosceles right triangles (by marking both of its diagonals) would yield 4 triangles equivalent to the first 4. The total area of the octagon can be accounted for by 8 equal triangles and 4 equal rectangles. Because it is made of 2 triangles and 1 rectangle, trapezoid ABCD is 1/4 of the octagon. A second trapezoid taken from the irregular hexagon ADEFGH will equal 1/4 of the octagon and leave 1/2 of the original octagon in the shape of a rectangle or a kite, either of which is easily split to provide the last two 1/4's. (The second and third cuts can be made in reverse order.)\r\n...\r\nThe pieces from two arrangements follow:\r\n1) ABCD, DEFG, ADH, and DGH.\r\n2) ABCD, EFGH, ADH, and DEH.\n<|im_start|>answer\nJunior knew an octagon would sequentially yield four quarters.\r\nAfter labeling the points of a perfect octagon, Junior told us, \"Before I cut the cake, I'll give the proof. First, I mark a line from A to D. This creates a trapezoid (trapezium in Britain) ABCD. Next, I mark the lines EH, BG, and CF. These four lines crosshatch the area dividing it into 1 square surrounded by 4 equal triangles and 4 equal rectangles.\"\r\nThe partners (me included) chimed in with the rest of these observations: The sides of the square are the same length as those of the octagon. Dividing the central square into isosceles right triangles (by marking both of its diagonals) would yield 4 triangles equivalent to the first 4. The total area of the octagon can be accounted for by 8 equal triangles and 4 equal rectangles. Because it is made of 2 triangles and 1 rectangle, trapezoid ABCD is 1/4 of the octagon. A second trapezoid taken from the irregular hexagon ADEFGH will equal 1/4 of the octagon and leave 1/2 of the original octagon in the shape of a rectangle or a kite, either of which is easily split to provide the last two 1/4's. (The second and third cuts can be made in reverse order.)\r\n...\r\nThe pieces from two arrangements follow:\r\n1) ABCD, DEFG, ADH, and DGH.\r\n2) ABCD, EFGH, ADH, and DEH.\n<|im_end|>" }, { "id": "#40902", "title": "Biggest Number", "fun": 2.35, "difficulty": 2.55, "author": "Jim1029", "desc": "Using the digits 1 to 9, create two numbers which when multiplied together give you the highest number. For example, 12345678 x 9 = 111111102. Clearly there are higher products. What is the highest?", "hint": "One number has 5 digits.", "answer": "9642 x 87531 makes 843,973,902.", "category": "Math", "date": "03/06/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the digits 1 to 9, create two numbers which when multiplied together give you the highest number. For example, 12345678 x 9 = 111111102. Clearly there are higher products. What is the highest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9642 x 87531 makes 843,973,902.\n<|im_start|>answer\n9642 x 87531 makes 843,973,902.\n<|im_end|>" }, { "id": "#31784", "title": "Frienemies", "fun": 2.35, "difficulty": 1.18, "author": "irar1792", "desc": "A couple of high schoolers, Kate and Claire, were looking at Kate's elementary school yearbook. They were looking for one page in particular- the BFF (Best Friends Forever) page, of course. Unfortunately, Kate's cat had gotten there before them, and the page was torn to a point where only names were recognizable.\n\r\nCan you figure out who was Best Friends with whom, what their relationship is currently like, and what they looked like in the now-torn picture?\n\r\nThe friends: Kate, Claire, Max, John, Samantha, and Rob\n\r\nThe current relationships: BFF's, \"enemies\", dating\n\r\nThe pics: hugging, laughing, playing\n\r\n1) Samantha thought boys had cooties, but always hugged her friends\r\n2) The couple that are now boyfriend/girlfriend were very giggly as children.\r\n3) Max, always a sweet guy, could never hate someone he grew up with.\r\n4) \"John and Claire, sitting in a tree. K-I-S-S-I-N-G!\" was a popular song on the playground.", "hint": "The two who remain best friends prefer to be called buds.", "answer": "Friend1-Friend2-current relationship-in picture\n\r\nKate-Samantha-enemies-hugging\r\nMax-Rob-BFF-playing\r\nJohn-Claire-dating-laughing", "category": "Logic-Grid", "date": "07/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA couple of high schoolers, Kate and Claire, were looking at Kate's elementary school yearbook. They were looking for one page in particular- the BFF (Best Friends Forever) page, of course. Unfortunately, Kate's cat had gotten there before them, and the page was torn to a point where only names were recognizable.\n\r\nCan you figure out who was Best Friends with whom, what their relationship is currently like, and what they looked like in the now-torn picture?\n\r\nThe friends: Kate, Claire, Max, John, Samantha, and Rob\n\r\nThe current relationships: BFF's, \"enemies\", dating\n\r\nThe pics: hugging, laughing, playing\n\r\n1) Samantha thought boys had cooties, but always hugged her friends\r\n2) The couple that are now boyfriend/girlfriend were very giggly as children.\r\n3) Max, always a sweet guy, could never hate someone he grew up with.\r\n4) \"John and Claire, sitting in a tree. K-I-S-S-I-N-G!\" was a popular song on the playground.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriend1-Friend2-current relationship-in picture\n\r\nKate-Samantha-enemies-hugging\r\nMax-Rob-BFF-playing\r\nJohn-Claire-dating-laughing\n<|im_start|>answer\nFriend1-Friend2-current relationship-in picture\n\r\nKate-Samantha-enemies-hugging\r\nMax-Rob-BFF-playing\r\nJohn-Claire-dating-laughing\n<|im_end|>" }, { "id": "#960", "title": "Average Speed", "fun": 2.35, "difficulty": 1.81, "author": "Michelle", "desc": "A car travels at a speed of 30 mph over a certain distance, and then returns over the same distance at a speed of 20 mph. What is the average speed for the total trip?", "hint": "No hint available.", "answer": "24 mph. Most people are quick to answer 25 mph, but this is not correct, as we will see. Let the distance traveled be 60 miles each way. Then, the trip out = 60/30 = 2 hours, and the trip back = 60/20 = 3 hours. Therefore: the 120 mile trip = 120/5 = 24 mph.", "category": "Math", "date": "10/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA car travels at a speed of 30 mph over a certain distance, and then returns over the same distance at a speed of 20 mph. What is the average speed for the total trip?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n24 mph. Most people are quick to answer 25 mph, but this is not correct, as we will see. Let the distance traveled be 60 miles each way. Then, the trip out = 60/30 = 2 hours, and the trip back = 60/20 = 3 hours. Therefore: the 120 mile trip = 120/5 = 24 mph.\n<|im_start|>answer\n24 mph. Most people are quick to answer 25 mph, but this is not correct, as we will see. Let the distance traveled be 60 miles each way. Then, the trip out = 60/30 = 2 hours, and the trip back = 60/20 = 3 hours. Therefore: the 120 mile trip = 120/5 = 24 mph.\n<|im_end|>" }, { "id": "#36842", "title": "Derrick's Theory", "fun": 2.35, "difficulty": 2.13, "author": "pokpic", "desc": "Captain Derrick Washington is one of the four captains of the Timberland Tigers basketball team. Derrick has this theory: If he drinks water every 8 minutes, milk every 12 minutes, and coffee every 14 minutes, he will do better in that day's game. If Derrick woke up at 9:30am and drank all three drinks at 9:35am, what is the latest time he would have drank all three drinks at the same time if his game starts at 7:30pm?", "hint": "No hint available.", "answer": "5:59pm\n\r\nIt took 168 minutes, or 2 hours and 48 minutes, for Derrick to drink all of them at the same time again. If you repeatedly add 2 hours and 48 minutes to 9:35am, you'll find the last time prior to the game that all drinks were had at the same time was at 5:59pm.", "category": "Math", "date": "06/04/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCaptain Derrick Washington is one of the four captains of the Timberland Tigers basketball team. Derrick has this theory: If he drinks water every 8 minutes, milk every 12 minutes, and coffee every 14 minutes, he will do better in that day's game. If Derrick woke up at 9:30am and drank all three drinks at 9:35am, what is the latest time he would have drank all three drinks at the same time if his game starts at 7:30pm?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5:59pm\n\r\nIt took 168 minutes, or 2 hours and 48 minutes, for Derrick to drink all of them at the same time again. If you repeatedly add 2 hours and 48 minutes to 9:35am, you'll find the last time prior to the game that all drinks were had at the same time was at 5:59pm.\n<|im_start|>answer\n5:59pm\n\r\nIt took 168 minutes, or 2 hours and 48 minutes, for Derrick to drink all of them at the same time again. If you repeatedly add 2 hours and 48 minutes to 9:35am, you'll find the last time prior to the game that all drinks were had at the same time was at 5:59pm.\n<|im_end|>" }, { "id": "#1267", "title": "Who's in the middle?", "fun": 2.35, "difficulty": 1.75, "author": "Yanivster", "desc": "Five kids are standing in a line holding hands: George, Kelly, Michael, Jennifer and Roy.\r\nIt is known that:\r\nIf Michael isn't at the right end of the line, then there are more than two kids between Kelly and George.\r\nIf Jennifer and Roy are standing next to each other, than George doesn't stand at the end of the line.\r\nKelly is standing at the right end of the line.\n\r\nWho is standing in the middle?", "hint": "No hint available.", "answer": "Michael is standing in the middle.", "category": "Logic", "date": "11/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive kids are standing in a line holding hands: George, Kelly, Michael, Jennifer and Roy.\r\nIt is known that:\r\nIf Michael isn't at the right end of the line, then there are more than two kids between Kelly and George.\r\nIf Jennifer and Roy are standing next to each other, than George doesn't stand at the end of the line.\r\nKelly is standing at the right end of the line.\n\r\nWho is standing in the middle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMichael is standing in the middle.\n<|im_start|>answer\nMichael is standing in the middle.\n<|im_end|>" }, { "id": "#7135", "title": "Orchard", "fun": 2.35, "difficulty": 2.08, "author": "Gouranga", "desc": "Last year, the average number of apples on each tree equalled the number of trees in the orchard. However this year there were 640 less apples than last year's harvest. If the average number of apples per tree this year was 72, how many trees are there in my orchard?\n\r\nPlease Note: No extra trees have been planted or any removed! There are no tricks to this question.", "hint": "No hint available.", "answer": "There are 80 trees in my lovely little orchard.\n\r\nLet T = the number of trees and N = the total number of apples. Set up two equations, one for each year:\n\r\nLast year: N/T = T or N = T^2\r\nThis year: (N-640)/T = 72\n\r\nSubstitute N = T^2 into the second equation to get: (T^2 - 640)/T = 72.\n\r\nMultiplying both sides by T and rearranging gives you the polynomial: T^2 - 72*T - 640 = 0. Solving this gives roots of -8 and 80. Obviously, there can't be -8 trees in the orchard, so there must be 80.", "category": "Math", "date": "09/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast year, the average number of apples on each tree equalled the number of trees in the orchard. However this year there were 640 less apples than last year's harvest. If the average number of apples per tree this year was 72, how many trees are there in my orchard?\n\r\nPlease Note: No extra trees have been planted or any removed! There are no tricks to this question.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 80 trees in my lovely little orchard.\n\r\nLet T = the number of trees and N = the total number of apples. Set up two equations, one for each year:\n\r\nLast year: N/T = T or N = T^2\r\nThis year: (N-640)/T = 72\n\r\nSubstitute N = T^2 into the second equation to get: (T^2 - 640)/T = 72.\n\r\nMultiplying both sides by T and rearranging gives you the polynomial: T^2 - 72*T - 640 = 0. Solving this gives roots of -8 and 80. Obviously, there can't be -8 trees in the orchard, so there must be 80.\n<|im_start|>answer\nThere are 80 trees in my lovely little orchard.\n\r\nLet T = the number of trees and N = the total number of apples. Set up two equations, one for each year:\n\r\nLast year: N/T = T or N = T^2\r\nThis year: (N-640)/T = 72\n\r\nSubstitute N = T^2 into the second equation to get: (T^2 - 640)/T = 72.\n\r\nMultiplying both sides by T and rearranging gives you the polynomial: T^2 - 72*T - 640 = 0. Solving this gives roots of -8 and 80. Obviously, there can't be -8 trees in the orchard, so there must be 80.\n<|im_end|>" }, { "id": "#24509", "title": "Cow Cash", "fun": 2.35, "difficulty": 2.46, "author": "ndnumber1fan", "desc": "A farmer with seven daughters is budgeting the food and medical expenses they will incur to care for their herd of cows over a two-week period. The herd consists of adult mother cows and their calves.\n\r\nEach of the farmer's daughters has seven plows, each plow is pulled by seven mother cows, and each mother cow has seven calves.\n\r\nThe farmer and his daughters know the following:\n\n\r\nOut of all those mother cows, two-sevenths are still nursing their calves, while five-sevenths of the mothers have weaned their calves. \n\r\nNursing mothers eat more, so they each need 8 ounces of solid cow food a day. The other mothers need only 6 ounces a day. \n\r\nThe weaned calves each need 2 ounces of food a day, while the calves still being nursed don't eat any solid food. \n\r\nThe family pays $1.02 per pound of solid cow food. \n\r\nDuring this two-week period, each calf has to be vaccinated. The cost of the vaccination is $14 per calf. \n\r\nWhat will be the total amount paid to feed and vaccinate the cows during this two-week period?", "hint": "No hint available.", "answer": "It costs $38,686.97 to care for the cows for 2 weeks.\n\r\nExplanation\n\n\r\nDetermine the number of cows and calves. \r\n7 daughters x 7 plows for each daughter = 49 plows altogether \r\n7 mother cows per plow x 49 plows = 343 mother cows \r\n7 calves per mother cow x 343 mother cows = 2,401 calves \n\n\r\nDetermine the number of types of cows and calves. \r\nThe nursing mothers = 2/7 x 343 = 98. \r\nThe mothers with weaned calves = 5/7 x 343 = 245. \r\nFive-sevenths of the calves are weaned and do need solid food: 5/7 x 2,401 = 1,715 weaned calves. \r\nTwo-sevenths of the calves are still nursing and don't need solid food: 2/7 x 2,401 = 686 nursing calves. \n\n\r\nDetermine the amount of food each type of cow or calf requires. \r\nEach nursing mother needs 8 ounces of food per day; the total number of ounces of food per day for all nursing cows is: 8 x 98 = 784 oz per day. \r\nEach mother with weaned calves needs 6 ounces of food per day; the total number of ounces of food per day for all mother cows with weaned calves is: 6 x 245 = 1,470 oz of food per day. \r\nWeaned calves eat 2 ounces of food per day: 1,715 x 2 = 3,430 oz of food per day. \n\n\r\nDetermine the amount of food the entire herd needs. \r\nThe whole herd of cows needs:\n\r\n784 + 1,470 + 3,430 = 5,684 oz\n\r\n5,684 oz of food per day /16 oz per lb = 355.25 lbs of cow food per day.\n\n\n\r\nDetermine how much money the food will cost. \r\nThere are 14 days in 2 weeks. Multiply 355.25 lbs by 14 days to find the number of pounds of food needed for 2 weeks, 4,973.5 lbs. \n\r\nSince the food costs $1.02 per pound, multiply 4,973.5 lbs. by $1.02 to find the total amount needed for food, $5.072.97. \n\n\r\nDetermine how much the vaccinations will cost. \r\nAll 2,401 calves need vaccinations. Multiply 2,401 calves by $14 per shot to find the total amount needed for shots, $33,614. \n\n\r\nAdd the cost of the food to the cost of the vaccinations to find the total cost of caring for the cows for 2 weeks. \r\n$5,072.97 + $33,614 = $38,686.97.", "category": "Math", "date": "07/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA farmer with seven daughters is budgeting the food and medical expenses they will incur to care for their herd of cows over a two-week period. The herd consists of adult mother cows and their calves.\n\r\nEach of the farmer's daughters has seven plows, each plow is pulled by seven mother cows, and each mother cow has seven calves.\n\r\nThe farmer and his daughters know the following:\n\n\r\nOut of all those mother cows, two-sevenths are still nursing their calves, while five-sevenths of the mothers have weaned their calves. \n\r\nNursing mothers eat more, so they each need 8 ounces of solid cow food a day. The other mothers need only 6 ounces a day. \n\r\nThe weaned calves each need 2 ounces of food a day, while the calves still being nursed don't eat any solid food. \n\r\nThe family pays $1.02 per pound of solid cow food. \n\r\nDuring this two-week period, each calf has to be vaccinated. The cost of the vaccination is $14 per calf. \n\r\nWhat will be the total amount paid to feed and vaccinate the cows during this two-week period?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt costs $38,686.97 to care for the cows for 2 weeks.\n\r\nExplanation\n\n\r\nDetermine the number of cows and calves. \r\n7 daughters x 7 plows for each daughter = 49 plows altogether \r\n7 mother cows per plow x 49 plows = 343 mother cows \r\n7 calves per mother cow x 343 mother cows = 2,401 calves \n\n\r\nDetermine the number of types of cows and calves. \r\nThe nursing mothers = 2/7 x 343 = 98. \r\nThe mothers with weaned calves = 5/7 x 343 = 245. \r\nFive-sevenths of the calves are weaned and do need solid food: 5/7 x 2,401 = 1,715 weaned calves. \r\nTwo-sevenths of the calves are still nursing and don't need solid food: 2/7 x 2,401 = 686 nursing calves. \n\n\r\nDetermine the amount of food each type of cow or calf requires. \r\nEach nursing mother needs 8 ounces of food per day; the total number of ounces of food per day for all nursing cows is: 8 x 98 = 784 oz per day. \r\nEach mother with weaned calves needs 6 ounces of food per day; the total number of ounces of food per day for all mother cows with weaned calves is: 6 x 245 = 1,470 oz of food per day. \r\nWeaned calves eat 2 ounces of food per day: 1,715 x 2 = 3,430 oz of food per day. \n\n\r\nDetermine the amount of food the entire herd needs. \r\nThe whole herd of cows needs:\n\r\n784 + 1,470 + 3,430 = 5,684 oz\n\r\n5,684 oz of food per day /16 oz per lb = 355.25 lbs of cow food per day.\n\n\n\r\nDetermine how much money the food will cost. \r\nThere are 14 days in 2 weeks. Multiply 355.25 lbs by 14 days to find the number of pounds of food needed for 2 weeks, 4,973.5 lbs. \n\r\nSince the food costs $1.02 per pound, multiply 4,973.5 lbs. by $1.02 to find the total amount needed for food, $5.072.97. \n\n\r\nDetermine how much the vaccinations will cost. \r\nAll 2,401 calves need vaccinations. Multiply 2,401 calves by $14 per shot to find the total amount needed for shots, $33,614. \n\n\r\nAdd the cost of the food to the cost of the vaccinations to find the total cost of caring for the cows for 2 weeks. \r\n$5,072.97 + $33,614 = $38,686.97.\n<|im_start|>answer\nIt costs $38,686.97 to care for the cows for 2 weeks.\n\r\nExplanation\n\n\r\nDetermine the number of cows and calves. \r\n7 daughters x 7 plows for each daughter = 49 plows altogether \r\n7 mother cows per plow x 49 plows = 343 mother cows \r\n7 calves per mother cow x 343 mother cows = 2,401 calves \n\n\r\nDetermine the number of types of cows and calves. \r\nThe nursing mothers = 2/7 x 343 = 98. \r\nThe mothers with weaned calves = 5/7 x 343 = 245. \r\nFive-sevenths of the calves are weaned and do need solid food: 5/7 x 2,401 = 1,715 weaned calves. \r\nTwo-sevenths of the calves are still nursing and don't need solid food: 2/7 x 2,401 = 686 nursing calves. \n\n\r\nDetermine the amount of food each type of cow or calf requires. \r\nEach nursing mother needs 8 ounces of food per day; the total number of ounces of food per day for all nursing cows is: 8 x 98 = 784 oz per day. \r\nEach mother with weaned calves needs 6 ounces of food per day; the total number of ounces of food per day for all mother cows with weaned calves is: 6 x 245 = 1,470 oz of food per day. \r\nWeaned calves eat 2 ounces of food per day: 1,715 x 2 = 3,430 oz of food per day. \n\n\r\nDetermine the amount of food the entire herd needs. \r\nThe whole herd of cows needs:\n\r\n784 + 1,470 + 3,430 = 5,684 oz\n\r\n5,684 oz of food per day /16 oz per lb = 355.25 lbs of cow food per day.\n\n\n\r\nDetermine how much money the food will cost. \r\nThere are 14 days in 2 weeks. Multiply 355.25 lbs by 14 days to find the number of pounds of food needed for 2 weeks, 4,973.5 lbs. \n\r\nSince the food costs $1.02 per pound, multiply 4,973.5 lbs. by $1.02 to find the total amount needed for food, $5.072.97. \n\n\r\nDetermine how much the vaccinations will cost. \r\nAll 2,401 calves need vaccinations. Multiply 2,401 calves by $14 per shot to find the total amount needed for shots, $33,614. \n\n\r\nAdd the cost of the food to the cost of the vaccinations to find the total cost of caring for the cows for 2 weeks. \r\n$5,072.97 + $33,614 = $38,686.97.\n<|im_end|>" }, { "id": "#18418", "title": "Degrees of Time", "fun": 2.35, "difficulty": 1.61, "author": "eelliott2", "desc": "How many degrees are between the hour and minute hand on a clock if the time is 3:40?", "hint": "Try sketching it out on paper.", "answer": "130 Degrees\n\r\nThe easiest way to solve this is to think that the clock is a circle and that there are 360 degrees in a circle. Draw a clock and set the hands at 3:40. From the 3 to the 8 equals 150 degrees; which might have been your answer if you didn't account for the movement of the hour hand. Since the minute hand is at the eight, it has moved 2/3 around the clock. Therefore, the hour hand has moved 2/3 the distance in between the 3 and the 4. Since there are 30 degrees in between each number, this means that the hour hand has moved 20 degrees towards the 4, or 150 degrees - 20 degrees = 130 degrees.", "category": "Math", "date": "08/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many degrees are between the hour and minute hand on a clock if the time is 3:40?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n130 Degrees\n\r\nThe easiest way to solve this is to think that the clock is a circle and that there are 360 degrees in a circle. Draw a clock and set the hands at 3:40. From the 3 to the 8 equals 150 degrees; which might have been your answer if you didn't account for the movement of the hour hand. Since the minute hand is at the eight, it has moved 2/3 around the clock. Therefore, the hour hand has moved 2/3 the distance in between the 3 and the 4. Since there are 30 degrees in between each number, this means that the hour hand has moved 20 degrees towards the 4, or 150 degrees - 20 degrees = 130 degrees.\n<|im_start|>answer\n130 Degrees\n\r\nThe easiest way to solve this is to think that the clock is a circle and that there are 360 degrees in a circle. Draw a clock and set the hands at 3:40. From the 3 to the 8 equals 150 degrees; which might have been your answer if you didn't account for the movement of the hour hand. Since the minute hand is at the eight, it has moved 2/3 around the clock. Therefore, the hour hand has moved 2/3 the distance in between the 3 and the 4. Since there are 30 degrees in between each number, this means that the hour hand has moved 20 degrees towards the 4, or 150 degrees - 20 degrees = 130 degrees.\n<|im_end|>" }, { "id": "#1869", "title": "Deducting Motorcycles", "fun": 2.35, "difficulty": 1.7, "author": "missie", "desc": "Two years ago, a man was offered a motorcycle for $1024, but he declined to buy it. A year later, he was offered the same motorcycle for $640, but again decided not to buy it. A little while after that, he was again offered the motorcycle, this time at $400. Again, he refused to buy it. Last week, he turned the motorcycle down even though the price had now fallen to $250. If the owner offers it for sale yet again, and he makes a consistent reduction, how much will it be for sale for the next time?", "hint": "No hint available.", "answer": "$156.25. Because each price was always 5/8 of the previous price.", "category": "Math", "date": "12/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo years ago, a man was offered a motorcycle for $1024, but he declined to buy it. A year later, he was offered the same motorcycle for $640, but again decided not to buy it. A little while after that, he was again offered the motorcycle, this time at $400. Again, he refused to buy it. Last week, he turned the motorcycle down even though the price had now fallen to $250. If the owner offers it for sale yet again, and he makes a consistent reduction, how much will it be for sale for the next time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$156.25. Because each price was always 5/8 of the previous price.\n<|im_start|>answer\n$156.25. Because each price was always 5/8 of the previous price.\n<|im_end|>" }, { "id": "#5710", "title": "A Cricket Match", "fun": 2.35, "difficulty": 1.58, "author": "arij", "desc": "The cricket match between India and Pakistan was over.\r\nHarbhajan scored more runs than Ganguly. \r\nSachin scored more runs than Laxman but less than Dravid \r\nBadani scored as many runs as Agarkar but less than Dravid and more than Sachin. \r\nGanguly scored more runs than either Agarkar or Dravid. \r\nEach batsman scored 10 runs more than his immediate batsman. The lowest score was 10 runs. How much did each one of them score?", "hint": "No hint available.", "answer": "60-Harbhajan \r\n50-Ganguly \r\n40-Dravid \r\n30-Badani \r\n30-Agarkar \r\n20-Sachin \r\n10-Laxman", "category": "Logic", "date": "07/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe cricket match between India and Pakistan was over.\r\nHarbhajan scored more runs than Ganguly. \r\nSachin scored more runs than Laxman but less than Dravid \r\nBadani scored as many runs as Agarkar but less than Dravid and more than Sachin. \r\nGanguly scored more runs than either Agarkar or Dravid. \r\nEach batsman scored 10 runs more than his immediate batsman. The lowest score was 10 runs. How much did each one of them score?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n60-Harbhajan \r\n50-Ganguly \r\n40-Dravid \r\n30-Badani \r\n30-Agarkar \r\n20-Sachin \r\n10-Laxman\n<|im_start|>answer\n60-Harbhajan \r\n50-Ganguly \r\n40-Dravid \r\n30-Badani \r\n30-Agarkar \r\n20-Sachin \r\n10-Laxman\n<|im_end|>" }, { "id": "#6919", "title": "Mice & Ropes", "fun": 2.35, "difficulty": 2.75, "author": "majd", "desc": "You have two identical ropes and three mice. Each mouse bites off the rope at a different biting speed. All three biting speeds are constant.\n\r\nMouse(A) bites off one rope in 60 minutes.\r\nMouse(B) bites off one rope in 90 minutes.\r\nMouse(C) bites off one rope in 180 minutes.\n\r\nYou do not have any time or distance measuring tools and the length of the rope is unknown. How can you measure 75 minutes?", "hint": "No hint available.", "answer": "Mark the two ropes as Rope(A) and Rope(B). \n\r\n1. Let Mouse(A) and Mouse(C) start biting off Rope(A) at the same time, starting each from one end (moving in opposite directions). At the same time, let Mouse(B) start biting off Rope(B).\n\r\nFinding relative speeds between Mouse(A) and Mouse(C):\r\nDistance = Speed * Time \r\nX = S(A) * 60, where S(A) is biting speed for Mouse(A) and X is Rope(A) length\r\nX = S(C) * 180, where S(C) is biting speed for Mouse(C) and X is Rope(A) length\n\r\nSolving the two above equations gives:\r\nS(A)/S(C) = 3:1, which means that for each 3 units Mouse(A) will move, Mouse (C) will move 1 unit.\n\r\nMoving in opposite directions (assume Mouse(A) from left to right and Mouse(C) from right to left), the two mice will meet after Mouse(A) bites off three times what Mouse(C) bit off, which divides Rope(A) length in to 4 units.\n\r\nMouse(A) bitten off portion = 3/4 X (where X is Rope(A) length)\r\nMouse(C) bitten off portion = 1/4 X\n\r\nFinding the time spent before Rope(A) is completely bitten off by the two mice:\r\nIf Mouse(A) needs 60 minutes to bite off X, How many minutes are needed to bite off 3/4 X?\n\r\nMinutes needed = 3/4 * 60 = 45 minutes are needed to fully bite off Rope(A) by Mouse(A) and Mouse(C). At that point in time, Mouse(B) would have bitten off exactly half the length of Rope(B) (needing 90 minutes to bite off the full rope), and needs an additional 45 minutes to bite off the remaining rope half.\n\r\n2. Let Mouse(B) continue biting off Rope(B) and make Mouse(C) start biting off the other end of Rope(B).\n\r\nFinding relative speeds between Mouse(B) and Mouse(C):\r\nDistance = Speed * Time \r\nX/2 = S(B) * 90, where S(B) is biting speed for Mouse(B) and X/2 is the remaining half of Rope(B) length\r\nX/2 = S(C) * 180, where S(C) is biting speed for Mouse(C) and X/2 is the remaining half of Rope(B) length\n\r\nSolving the two above equations gives:\r\nS(B)/S(C) = 2:1, which means that for each 2 units Mouse(B) will move, Mouse(C) will move 1 unit.\n\r\nMoving in opposite directions (assume Mouse(B) from left to right and Mouse(C) from right to left), the two mice will meet after Mouse(B) bites off two times what Mouse(C) bit off, which divides the remaining half of Rope(B) length to 3 units.\n\r\nMouse(B) bitten off portion = 2/3 * X/2 = X/3\r\nMouse(C) bitten off portion = 1/3 * X/2 = X/6\n\r\nFinding the time spent before the remaining half of Rope(B) is completely bitten off by the two mice:\r\nIf Mouse(B) needs 90 minutes to bite off X, how many minutes are needed to bite off X/3?\n\r\nMinutes needed = 1/3 * 90 = 30 minutes are needed to fully bite off the remaining half of Rope(B) by Mouse(B) and Mouse(C). \n\r\nAt that point in time, 75 minutes would have passed (45 minutes consumed from biting off Rope(A) and another 30 minutes consumed from biting off Rope(B)).", "category": "Math", "date": "08/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two identical ropes and three mice. Each mouse bites off the rope at a different biting speed. All three biting speeds are constant.\n\r\nMouse(A) bites off one rope in 60 minutes.\r\nMouse(B) bites off one rope in 90 minutes.\r\nMouse(C) bites off one rope in 180 minutes.\n\r\nYou do not have any time or distance measuring tools and the length of the rope is unknown. How can you measure 75 minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMark the two ropes as Rope(A) and Rope(B). \n\r\n1. Let Mouse(A) and Mouse(C) start biting off Rope(A) at the same time, starting each from one end (moving in opposite directions). At the same time, let Mouse(B) start biting off Rope(B).\n\r\nFinding relative speeds between Mouse(A) and Mouse(C):\r\nDistance = Speed * Time \r\nX = S(A) * 60, where S(A) is biting speed for Mouse(A) and X is Rope(A) length\r\nX = S(C) * 180, where S(C) is biting speed for Mouse(C) and X is Rope(A) length\n\r\nSolving the two above equations gives:\r\nS(A)/S(C) = 3:1, which means that for each 3 units Mouse(A) will move, Mouse (C) will move 1 unit.\n\r\nMoving in opposite directions (assume Mouse(A) from left to right and Mouse(C) from right to left), the two mice will meet after Mouse(A) bites off three times what Mouse(C) bit off, which divides Rope(A) length in to 4 units.\n\r\nMouse(A) bitten off portion = 3/4 X (where X is Rope(A) length)\r\nMouse(C) bitten off portion = 1/4 X\n\r\nFinding the time spent before Rope(A) is completely bitten off by the two mice:\r\nIf Mouse(A) needs 60 minutes to bite off X, How many minutes are needed to bite off 3/4 X?\n\r\nMinutes needed = 3/4 * 60 = 45 minutes are needed to fully bite off Rope(A) by Mouse(A) and Mouse(C). At that point in time, Mouse(B) would have bitten off exactly half the length of Rope(B) (needing 90 minutes to bite off the full rope), and needs an additional 45 minutes to bite off the remaining rope half.\n\r\n2. Let Mouse(B) continue biting off Rope(B) and make Mouse(C) start biting off the other end of Rope(B).\n\r\nFinding relative speeds between Mouse(B) and Mouse(C):\r\nDistance = Speed * Time \r\nX/2 = S(B) * 90, where S(B) is biting speed for Mouse(B) and X/2 is the remaining half of Rope(B) length\r\nX/2 = S(C) * 180, where S(C) is biting speed for Mouse(C) and X/2 is the remaining half of Rope(B) length\n\r\nSolving the two above equations gives:\r\nS(B)/S(C) = 2:1, which means that for each 2 units Mouse(B) will move, Mouse(C) will move 1 unit.\n\r\nMoving in opposite directions (assume Mouse(B) from left to right and Mouse(C) from right to left), the two mice will meet after Mouse(B) bites off two times what Mouse(C) bit off, which divides the remaining half of Rope(B) length to 3 units.\n\r\nMouse(B) bitten off portion = 2/3 * X/2 = X/3\r\nMouse(C) bitten off portion = 1/3 * X/2 = X/6\n\r\nFinding the time spent before the remaining half of Rope(B) is completely bitten off by the two mice:\r\nIf Mouse(B) needs 90 minutes to bite off X, how many minutes are needed to bite off X/3?\n\r\nMinutes needed = 1/3 * 90 = 30 minutes are needed to fully bite off the remaining half of Rope(B) by Mouse(B) and Mouse(C). \n\r\nAt that point in time, 75 minutes would have passed (45 minutes consumed from biting off Rope(A) and another 30 minutes consumed from biting off Rope(B)).\n<|im_start|>answer\nMark the two ropes as Rope(A) and Rope(B). \n\r\n1. Let Mouse(A) and Mouse(C) start biting off Rope(A) at the same time, starting each from one end (moving in opposite directions). At the same time, let Mouse(B) start biting off Rope(B).\n\r\nFinding relative speeds between Mouse(A) and Mouse(C):\r\nDistance = Speed * Time \r\nX = S(A) * 60, where S(A) is biting speed for Mouse(A) and X is Rope(A) length\r\nX = S(C) * 180, where S(C) is biting speed for Mouse(C) and X is Rope(A) length\n\r\nSolving the two above equations gives:\r\nS(A)/S(C) = 3:1, which means that for each 3 units Mouse(A) will move, Mouse (C) will move 1 unit.\n\r\nMoving in opposite directions (assume Mouse(A) from left to right and Mouse(C) from right to left), the two mice will meet after Mouse(A) bites off three times what Mouse(C) bit off, which divides Rope(A) length in to 4 units.\n\r\nMouse(A) bitten off portion = 3/4 X (where X is Rope(A) length)\r\nMouse(C) bitten off portion = 1/4 X\n\r\nFinding the time spent before Rope(A) is completely bitten off by the two mice:\r\nIf Mouse(A) needs 60 minutes to bite off X, How many minutes are needed to bite off 3/4 X?\n\r\nMinutes needed = 3/4 * 60 = 45 minutes are needed to fully bite off Rope(A) by Mouse(A) and Mouse(C). At that point in time, Mouse(B) would have bitten off exactly half the length of Rope(B) (needing 90 minutes to bite off the full rope), and needs an additional 45 minutes to bite off the remaining rope half.\n\r\n2. Let Mouse(B) continue biting off Rope(B) and make Mouse(C) start biting off the other end of Rope(B).\n\r\nFinding relative speeds between Mouse(B) and Mouse(C):\r\nDistance = Speed * Time \r\nX/2 = S(B) * 90, where S(B) is biting speed for Mouse(B) and X/2 is the remaining half of Rope(B) length\r\nX/2 = S(C) * 180, where S(C) is biting speed for Mouse(C) and X/2 is the remaining half of Rope(B) length\n\r\nSolving the two above equations gives:\r\nS(B)/S(C) = 2:1, which means that for each 2 units Mouse(B) will move, Mouse(C) will move 1 unit.\n\r\nMoving in opposite directions (assume Mouse(B) from left to right and Mouse(C) from right to left), the two mice will meet after Mouse(B) bites off two times what Mouse(C) bit off, which divides the remaining half of Rope(B) length to 3 units.\n\r\nMouse(B) bitten off portion = 2/3 * X/2 = X/3\r\nMouse(C) bitten off portion = 1/3 * X/2 = X/6\n\r\nFinding the time spent before the remaining half of Rope(B) is completely bitten off by the two mice:\r\nIf Mouse(B) needs 90 minutes to bite off X, how many minutes are needed to bite off X/3?\n\r\nMinutes needed = 1/3 * 90 = 30 minutes are needed to fully bite off the remaining half of Rope(B) by Mouse(B) and Mouse(C). \n\r\nAt that point in time, 75 minutes would have passed (45 minutes consumed from biting off Rope(A) and another 30 minutes consumed from biting off Rope(B)).\n<|im_end|>" }, { "id": "#784", "title": "Rabbit, Wolf, and Lettuce", "fun": 2.35, "difficulty": 1.08, "author": "Nike01", "desc": "A man comes to a river with a boat. He has with him a wolf, a rabbit and a head of lettuce. The man can only carry one single passenger besides himself in the boat. How can he get them all to the other side without the rabbit eating the lettuce, or the wolf eating the rabbit?", "hint": "There are more than three steps involved", "answer": "First take the rabbit over. \r\nThen take the lettuce over and bring back the rabbit. \r\nThen take the wolf over and finally the rabbit.", "category": "Logic", "date": "08/24/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man comes to a river with a boat. He has with him a wolf, a rabbit and a head of lettuce. The man can only carry one single passenger besides himself in the boat. How can he get them all to the other side without the rabbit eating the lettuce, or the wolf eating the rabbit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst take the rabbit over. \r\nThen take the lettuce over and bring back the rabbit. \r\nThen take the wolf over and finally the rabbit.\n<|im_start|>answer\nFirst take the rabbit over. \r\nThen take the lettuce over and bring back the rabbit. \r\nThen take the wolf over and finally the rabbit.\n<|im_end|>" }, { "id": "#6059", "title": "Exam Scores", "fun": 2.35, "difficulty": 1.31, "author": "glennyboy02", "desc": "Ten students sit for an exam which has a maximum score of 100. The average of the 10 scores was 92. What is the mininum mark a student could have scored?", "hint": "No hint available.", "answer": "20 (20+9x100=920 divided by 10=92)", "category": "Math", "date": "07/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTen students sit for an exam which has a maximum score of 100. The average of the 10 scores was 92. What is the mininum mark a student could have scored?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20 (20+9x100=920 divided by 10=92)\n<|im_start|>answer\n20 (20+9x100=920 divided by 10=92)\n<|im_end|>" }, { "id": "#5397", "title": "Spare Stair", "fun": 2.35, "difficulty": 1.96, "author": "mad-ade", "desc": "Mad Ade's office is on the 3rd floor of the \"Multinational Kebab and Lard Insurance Company\" building and, though there is a lift, he likes using the big circular staircase. He goes up the stairs 2 at a time (to get more exercise) but is annoyed that there is always just 1 stair left over when he gets to his landing.\r\nOne day, in a burst of energy he went up the stairs 3 at a time, and still had 1 stair left over!\r\nBy counting (certainly not by doing it!) Mad Ade established that even if he could go up 4, 5 or 6 stairs at a time there would still be 1 left over.\r\nWorse yet, no matter how many stairs Mad Ade did at a time (except for 1 or the lot) there would always be some left over.\r\nHow many stairs are there to Mad Ade's office?", "hint": "No hint available.", "answer": "61 stairs", "category": "Math", "date": "07/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's office is on the 3rd floor of the \"Multinational Kebab and Lard Insurance Company\" building and, though there is a lift, he likes using the big circular staircase. He goes up the stairs 2 at a time (to get more exercise) but is annoyed that there is always just 1 stair left over when he gets to his landing.\r\nOne day, in a burst of energy he went up the stairs 3 at a time, and still had 1 stair left over!\r\nBy counting (certainly not by doing it!) Mad Ade established that even if he could go up 4, 5 or 6 stairs at a time there would still be 1 left over.\r\nWorse yet, no matter how many stairs Mad Ade did at a time (except for 1 or the lot) there would always be some left over.\r\nHow many stairs are there to Mad Ade's office?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n61 stairs\n<|im_start|>answer\n61 stairs\n<|im_end|>" }, { "id": "#31153", "title": "Rnkfurers In Philos", "fun": 2.35, "difficulty": 2.89, "author": "norcekri", "desc": "Patty O'Furniture and her lopsided friend, Eileen, were down to their last dozen Rnkfurers. Rnkfurers are a little-known snack: a non-fat frankfurter whose natural flavorants include antivitriolic acids, sesquipedalian hydrocarbons, and golden bail powder. They're as nutritious as they are delicious, and the only advertising they need is word of mouth ... if you can get your friend to stop eating them long enough to tell you what they are.\r\n\tEileen was contemplating how many to buy; the 15 she'd bought hadn't lasted long, and only Patty's generosity had kept her from exorcising her craving by writing an acrostic sonnet about the treats during English class.\r\n\tNow, after school, they were on their way to the local grocery store for their next order, strolling along in iambic pentameter. Patty plodded as Eileen's step provided the stresses. Gradually, they realized they could hear singing of a sort coming from up the street. The voices matched their pace -- one high and lilting in C-major, the other percussive and in the key of \"off\". As the two girls advanced, they tracked the sound to a large elm in Desire Creek's front yard. Patty spotted a red sneaker on one branch and grinned.\r\n\t\"I know that voice! C'mon down.\"\r\n\t\"Who is it?\" Eileen prodded.\r\n\t\"Well, what do you call a guy making annoying noises in a tree?\"\r\n\tEileen shrugged. \"C'mon down, Jay,\" Patty called into the leaves.\r\n\t\"Why should I?\"\r\n\t\"I'll give you each a Rnkfurer.\"\r\n\t\"Is that the new Sinatra CD?\"\r\n\t\"No, it's the world's greatest snack.\"\r\n\t\"I'm hungry, too!\" the other voice whined.\r\n\t\"Who's up there with you?\" Patty asked.\r\n\t\"I'll bet I know!\" Eileen called. \"It's obvious!\"\r\n\tPatty's face lit up in realization. \"Robin!\" they laughed together.\n\r\n\tA pair of hard landings and two bites later, Jay and Robin were negotiating to join the next bulk order of Rnkfurers. Patty explained how they'd always ordered such that one person got a number of Rnkfurers equal to the next person's percentage.\r\n\t\"But that doesn't work out very well with three people, and only with multiples of percentages for four,\" Eileen added.\r\n\t\"That's okay,\" Robin said. \"Does it have to be percentages?\"\r\n\t\"There's no law; just tradition. What do you have in mind?\"\r\n\t\"We've just studied amicable numbers in algebra.\"\r\n\t\"What are those?\"\r\n\t\"You know what a perfect number is?\"\r\n\t\"Sure,\" Patty interjected, \"a number equal to the sum of its divisors.\"\r\n\t\"Great,\" Jay continued. \"Amicable numbers are a pair where each is equal to the sum of the other one's divisors.\"\r\n\tPatty and Eileen digested that for a moment, then nodded.\r\n\t\"So, what do you have for four people?\" Patty encouraged.\r\n\t\"I don't know. The smallest pair of amicable numbers is 220 and 284. Maybe we could order two sets of that?\"\r\n\t\"I don't know; traditionally, it's been a dependent sequence. What's the next pair?\"\r\n\t\"1184 and 1210.\"\r\n\t\"That's a lot, even for us. Besides, they come in cases of 25, 50, and 100, and we get a price break on the larger cases.\"\r\n\t\"Well, how about an aliquot sequence?\"\r\n\t\"Okay. How does it taste?\" Patty asked.\r\n\t\"Can you hum a few bars?\" Eileen offered at the same time.\r\n\tRobin laughed. \"No, it's a series of numbers, each one being the sum of the previous number's divisors. For instance, start with 12. Its divisors add up to 16. 16's divisors add up to 15, then 9, and it's downhill from there.\"\r\n\tEileen and Patty understood. \"So, you just don't have to get back to your starting point?\"\r\n\t\"Right. Some of the sequences seem to go on for a long time, but a few stick in the same neighborhood for a few terms.\"\r\n\t\"Well, do you have any of those handy?\"\r\n\t\"It depends; how many of these do we want to order? You two know what makes a week's supply, I hope?\"\r\n\t\"Sure.\" Patty spoke as the veteran Rnkfurerphile. \"At least 100 each, but probably not much more over the long haul.\"\r\n\tJay and Robin shared a glance. \"Robin, is your homework still in your pack?\"\r\n\t\"It sure is. One aliquot sequence coming up, the first four terms between 100 and 200, and the sum is divisible by 25.\"\n\r\n\tTen minutes later, the four friends were in the grocery store, ordering their Rnkfurers. What are the four quantities in the sequence?", "hint": "You can leave out numbers that are primes (sum of proper divisors is 1) or the product of two primes (sum of divisors will be less than 100). This will shorten your search somewhat.", "answer": "108, 172, 136, and 134.\n\r\nMethod:\r\n\tThis one really requires a brute-force approach. The sigma function (sum of a number's divisors) does not lend itself to 3rd-order analysis (3 numbers past the first one). Most of the remaining numbers will leave the 100-200 range on the first or second iteration. I used a small computer program. The only sequence that stays in bounds for 4 terms is the one given.\n\r\nSide notes:\r\n\tThe name \"Desire Creek\" is a nod to \"Desire Under the Elms\" and the \"Elm Creek Quilt\" books.\n\n\r\n\tThere are 4-cycles of amicable numbers. However, the least quadruple is a little large, even for Patty's appetite: 1264460, 1547860, 1727636, 1305184.", "category": "Math", "date": "06/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPatty O'Furniture and her lopsided friend, Eileen, were down to their last dozen Rnkfurers. Rnkfurers are a little-known snack: a non-fat frankfurter whose natural flavorants include antivitriolic acids, sesquipedalian hydrocarbons, and golden bail powder. They're as nutritious as they are delicious, and the only advertising they need is word of mouth ... if you can get your friend to stop eating them long enough to tell you what they are.\r\n\tEileen was contemplating how many to buy; the 15 she'd bought hadn't lasted long, and only Patty's generosity had kept her from exorcising her craving by writing an acrostic sonnet about the treats during English class.\r\n\tNow, after school, they were on their way to the local grocery store for their next order, strolling along in iambic pentameter. Patty plodded as Eileen's step provided the stresses. Gradually, they realized they could hear singing of a sort coming from up the street. The voices matched their pace -- one high and lilting in C-major, the other percussive and in the key of \"off\". As the two girls advanced, they tracked the sound to a large elm in Desire Creek's front yard. Patty spotted a red sneaker on one branch and grinned.\r\n\t\"I know that voice! C'mon down.\"\r\n\t\"Who is it?\" Eileen prodded.\r\n\t\"Well, what do you call a guy making annoying noises in a tree?\"\r\n\tEileen shrugged. \"C'mon down, Jay,\" Patty called into the leaves.\r\n\t\"Why should I?\"\r\n\t\"I'll give you each a Rnkfurer.\"\r\n\t\"Is that the new Sinatra CD?\"\r\n\t\"No, it's the world's greatest snack.\"\r\n\t\"I'm hungry, too!\" the other voice whined.\r\n\t\"Who's up there with you?\" Patty asked.\r\n\t\"I'll bet I know!\" Eileen called. \"It's obvious!\"\r\n\tPatty's face lit up in realization. \"Robin!\" they laughed together.\n\r\n\tA pair of hard landings and two bites later, Jay and Robin were negotiating to join the next bulk order of Rnkfurers. Patty explained how they'd always ordered such that one person got a number of Rnkfurers equal to the next person's percentage.\r\n\t\"But that doesn't work out very well with three people, and only with multiples of percentages for four,\" Eileen added.\r\n\t\"That's okay,\" Robin said. \"Does it have to be percentages?\"\r\n\t\"There's no law; just tradition. What do you have in mind?\"\r\n\t\"We've just studied amicable numbers in algebra.\"\r\n\t\"What are those?\"\r\n\t\"You know what a perfect number is?\"\r\n\t\"Sure,\" Patty interjected, \"a number equal to the sum of its divisors.\"\r\n\t\"Great,\" Jay continued. \"Amicable numbers are a pair where each is equal to the sum of the other one's divisors.\"\r\n\tPatty and Eileen digested that for a moment, then nodded.\r\n\t\"So, what do you have for four people?\" Patty encouraged.\r\n\t\"I don't know. The smallest pair of amicable numbers is 220 and 284. Maybe we could order two sets of that?\"\r\n\t\"I don't know; traditionally, it's been a dependent sequence. What's the next pair?\"\r\n\t\"1184 and 1210.\"\r\n\t\"That's a lot, even for us. Besides, they come in cases of 25, 50, and 100, and we get a price break on the larger cases.\"\r\n\t\"Well, how about an aliquot sequence?\"\r\n\t\"Okay. How does it taste?\" Patty asked.\r\n\t\"Can you hum a few bars?\" Eileen offered at the same time.\r\n\tRobin laughed. \"No, it's a series of numbers, each one being the sum of the previous number's divisors. For instance, start with 12. Its divisors add up to 16. 16's divisors add up to 15, then 9, and it's downhill from there.\"\r\n\tEileen and Patty understood. \"So, you just don't have to get back to your starting point?\"\r\n\t\"Right. Some of the sequences seem to go on for a long time, but a few stick in the same neighborhood for a few terms.\"\r\n\t\"Well, do you have any of those handy?\"\r\n\t\"It depends; how many of these do we want to order? You two know what makes a week's supply, I hope?\"\r\n\t\"Sure.\" Patty spoke as the veteran Rnkfurerphile. \"At least 100 each, but probably not much more over the long haul.\"\r\n\tJay and Robin shared a glance. \"Robin, is your homework still in your pack?\"\r\n\t\"It sure is. One aliquot sequence coming up, the first four terms between 100 and 200, and the sum is divisible by 25.\"\n\r\n\tTen minutes later, the four friends were in the grocery store, ordering their Rnkfurers. What are the four quantities in the sequence?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n108, 172, 136, and 134.\n\r\nMethod:\r\n\tThis one really requires a brute-force approach. The sigma function (sum of a number's divisors) does not lend itself to 3rd-order analysis (3 numbers past the first one). Most of the remaining numbers will leave the 100-200 range on the first or second iteration. I used a small computer program. The only sequence that stays in bounds for 4 terms is the one given.\n\r\nSide notes:\r\n\tThe name \"Desire Creek\" is a nod to \"Desire Under the Elms\" and the \"Elm Creek Quilt\" books.\n\n\r\n\tThere are 4-cycles of amicable numbers. However, the least quadruple is a little large, even for Patty's appetite: 1264460, 1547860, 1727636, 1305184.\n<|im_start|>answer\n108, 172, 136, and 134.\n\r\nMethod:\r\n\tThis one really requires a brute-force approach. The sigma function (sum of a number's divisors) does not lend itself to 3rd-order analysis (3 numbers past the first one). Most of the remaining numbers will leave the 100-200 range on the first or second iteration. I used a small computer program. The only sequence that stays in bounds for 4 terms is the one given.\n\r\nSide notes:\r\n\tThe name \"Desire Creek\" is a nod to \"Desire Under the Elms\" and the \"Elm Creek Quilt\" books.\n\n\r\n\tThere are 4-cycles of amicable numbers. However, the least quadruple is a little large, even for Patty's appetite: 1264460, 1547860, 1727636, 1305184.\n<|im_end|>" }, { "id": "#2102", "title": "$99", "fun": 2.35, "difficulty": 1.66, "author": "ChemicalBoy08", "desc": "A bank customer had $100 in his account. He then made 6 withdrawals, totaling $100. He kept a record of these withdrawals, and the balance remaining in the account, as follows: \n\n\r\nWithdrawals........Balance Left\r\n$50...................$50\r\n$25...................$25\r\n$10...................$15\r\n$8.....................$7\r\n$5.....................$2 \r\n$2.....................$0\r\n___________________\r\n$100..................$99 \n\r\nWhen he added up the columns as above, he assumed that he must owe $1 to the bank. Was he right?", "hint": "No hint available.", "answer": "There is no reason whatever why the customer's original deposit of $100 should equal the total of the balances left after each withdrawal. The total of withdrawals in the left-hand column must always equal $100, but is purely coincidence that the total of the right-hand column is close to $100.", "category": "Math", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bank customer had $100 in his account. He then made 6 withdrawals, totaling $100. He kept a record of these withdrawals, and the balance remaining in the account, as follows: \n\n\r\nWithdrawals........Balance Left\r\n$50...................$50\r\n$25...................$25\r\n$10...................$15\r\n$8.....................$7\r\n$5.....................$2 \r\n$2.....................$0\r\n___________________\r\n$100..................$99 \n\r\nWhen he added up the columns as above, he assumed that he must owe $1 to the bank. Was he right?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere is no reason whatever why the customer's original deposit of $100 should equal the total of the balances left after each withdrawal. The total of withdrawals in the left-hand column must always equal $100, but is purely coincidence that the total of the right-hand column is close to $100.\n<|im_start|>answer\nThere is no reason whatever why the customer's original deposit of $100 should equal the total of the balances left after each withdrawal. The total of withdrawals in the left-hand column must always equal $100, but is purely coincidence that the total of the right-hand column is close to $100.\n<|im_end|>" }, { "id": "#28929", "title": "Opposites 14", "fun": 2.35, "difficulty": 2.73, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n) stands for T, E, S, A, or L\r\n< stands for F, E, C, R, or P\r\n> stands for E, R, L, K, or S\r\n[ stands for F, S, E, D, or R\r\n] stands for W, M, J, U, or Y\r\n( stands for N, A, H, O, or B\n\r\nThe six letter code word, <([])>, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Casual and Formal", "category": "Logic", "date": "03/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n) stands for T, E, S, A, or L\r\n< stands for F, E, C, R, or P\r\n> stands for E, R, L, K, or S\r\n[ stands for F, S, E, D, or R\r\n] stands for W, M, J, U, or Y\r\n( stands for N, A, H, O, or B\n\r\nThe six letter code word, <([])>, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCasual and Formal\n<|im_start|>answer\nCasual and Formal\n<|im_end|>" }, { "id": "#28448", "title": "Threes and Fours", "fun": 2.35, "difficulty": 2.45, "author": "shenqiang", "desc": "Which is the smallest natural number that satisfies the following conditions:\n\r\n(1) Its digits consist of, and only of 3's and 4's.\r\n(2) Its digital sum is divisible by 3 and 4.\r\n(3) The number itself is divisible by 3 and 4.", "hint": "It's very easy.", "answer": "From conditions 1 and 2, we know that we need at least 3 4's and 4 3's.\n\r\nThe smallest number they make is 3333444, which is divisible by 3 and 4.\n\r\nTherefore, the number we're looking for is 3333444.", "category": "Math", "date": "02/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is the smallest natural number that satisfies the following conditions:\n\r\n(1) Its digits consist of, and only of 3's and 4's.\r\n(2) Its digital sum is divisible by 3 and 4.\r\n(3) The number itself is divisible by 3 and 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom conditions 1 and 2, we know that we need at least 3 4's and 4 3's.\n\r\nThe smallest number they make is 3333444, which is divisible by 3 and 4.\n\r\nTherefore, the number we're looking for is 3333444.\n<|im_start|>answer\nFrom conditions 1 and 2, we know that we need at least 3 4's and 4 3's.\n\r\nThe smallest number they make is 3333444, which is divisible by 3 and 4.\n\r\nTherefore, the number we're looking for is 3333444.\n<|im_end|>" }, { "id": "#49023", "title": "Word Ratio", "fun": 2.35, "difficulty": 2.42, "author": "Gizzer", "desc": "runway : cinema\r\nanswer : ?\n\r\nDirections: Ratios usually involve numbers. This word ratio is a little different in that all four words in the ratio are somehow related. Can you find a word that completes the ratio? \n\r\n(Note: there is more than one possible answer.)", "hint": "No hint available.", "answer": "Any 6-letter word with the letters \"se\" in the middle will complete the word ratio. Possible answers include the words absent, assert, bisect, desert, insect, itself, losers, misery, museum, resent, unseen, wisely, etc.\n\r\nThe middle two letters of each of the words in the ratio represents a direction. The embedded directions relate to the position of the word within the ratio.\n\r\nruNWay: ciNEma\r\nanSWer: abSEnt", "category": "Logic", "date": "09/13/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nrunway : cinema\r\nanswer : ?\n\r\nDirections: Ratios usually involve numbers. This word ratio is a little different in that all four words in the ratio are somehow related. Can you find a word that completes the ratio? \n\r\n(Note: there is more than one possible answer.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAny 6-letter word with the letters \"se\" in the middle will complete the word ratio. Possible answers include the words absent, assert, bisect, desert, insect, itself, losers, misery, museum, resent, unseen, wisely, etc.\n\r\nThe middle two letters of each of the words in the ratio represents a direction. The embedded directions relate to the position of the word within the ratio.\n\r\nruNWay: ciNEma\r\nanSWer: abSEnt\n<|im_start|>answer\nAny 6-letter word with the letters \"se\" in the middle will complete the word ratio. Possible answers include the words absent, assert, bisect, desert, insect, itself, losers, misery, museum, resent, unseen, wisely, etc.\n\r\nThe middle two letters of each of the words in the ratio represents a direction. The embedded directions relate to the position of the word within the ratio.\n\r\nruNWay: ciNEma\r\nanSWer: abSEnt\n<|im_end|>" }, { "id": "#38548", "title": "Keys and Locks", "fun": 2.35, "difficulty": 1.66, "author": "Draw", "desc": "Each key fits only one lock. There are ten locks and their keys in some order. How many times, in the worst case, do you have to try to match each lock with each key?", "hint": "It's not 55.", "answer": "To determine the first lock you need 9 tries, if none of them fits, then the last key fits.\r\nTo determine the second lock you need 8 tries, and so on.\r\n9+8+7+6+5+4+3+2+1=45.", "category": "Math", "date": "09/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach key fits only one lock. There are ten locks and their keys in some order. How many times, in the worst case, do you have to try to match each lock with each key?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo determine the first lock you need 9 tries, if none of them fits, then the last key fits.\r\nTo determine the second lock you need 8 tries, and so on.\r\n9+8+7+6+5+4+3+2+1=45.\n<|im_start|>answer\nTo determine the first lock you need 9 tries, if none of them fits, then the last key fits.\r\nTo determine the second lock you need 8 tries, and so on.\r\n9+8+7+6+5+4+3+2+1=45.\n<|im_end|>" }, { "id": "#9460", "title": "Rattlesnake Jake", "fun": 2.35, "difficulty": 1.7, "author": "k2w2man", "desc": "It's time to paint the Big Barn, and Paul has enlisted the help of \"Rattlesnake\" Jake, his rancher neighbor from across the Snake River. Jake is feelin' a mite achy, having spent the previous day bustin' some broncs, so it takes him six hours to paint one wall. Paul plans to spend some time with Miss Rosy Boa later in the afternoon, so he gets his wall done in three hours. Assuming all the walls are the same size, how much time would it take Paul and Jake to complete another wall while working together at their previous pace?", "hint": "No hint available.", "answer": "2 hours. \r\nBreaking down the job on an hourly basis, Paul can finish 1/3 of the job in an hour, while Jake completes 1/6 of the wall in the same hour. Working together, they will complete 1/3 plus 1/6 (or 1/2) of the wall in one hour, and finish the job in two.", "category": "Math", "date": "12/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's time to paint the Big Barn, and Paul has enlisted the help of \"Rattlesnake\" Jake, his rancher neighbor from across the Snake River. Jake is feelin' a mite achy, having spent the previous day bustin' some broncs, so it takes him six hours to paint one wall. Paul plans to spend some time with Miss Rosy Boa later in the afternoon, so he gets his wall done in three hours. Assuming all the walls are the same size, how much time would it take Paul and Jake to complete another wall while working together at their previous pace?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 hours. \r\nBreaking down the job on an hourly basis, Paul can finish 1/3 of the job in an hour, while Jake completes 1/6 of the wall in the same hour. Working together, they will complete 1/3 plus 1/6 (or 1/2) of the wall in one hour, and finish the job in two.\n<|im_start|>answer\n2 hours. \r\nBreaking down the job on an hourly basis, Paul can finish 1/3 of the job in an hour, while Jake completes 1/6 of the wall in the same hour. Working together, they will complete 1/3 plus 1/6 (or 1/2) of the wall in one hour, and finish the job in two.\n<|im_end|>" }, { "id": "#20945", "title": "Community Garden", "fun": 2.35, "difficulty": 2.11, "author": "MrBasKetBall", "desc": "Bryce, Duane, Julianna, and Sonya share a 40 feet by 48 feet rectangular portion of the community garden in their neighborhood. Within this space, each has their own rectangular garden plot.\n\r\nBryce is the only one with a square plot. Its area is 1/2 the area of Duane's. \r\nThe area of Bryce's plot is 2/3 the area of Julianna's garden. Their plots have one side in common. \r\nSonya's garden has an area twice that of Julianna's garden. \n\r\nWhat are the dimensions (length and width) of each person's garden plot?", "hint": "No hint available.", "answer": "Bryce's garden is 16 ft by 16 ft (with an area of 256 square feet).\r\nDuane's garden is 32 ft by 16 ft (with an area of 512 square feet).\r\nJulianna's garden is 24 ft by 16 ft (with an area of 384 square feet).\r\nSonya's garden is 24 ft by 32 ft (with an area of 768 square feet).", "category": "Math", "date": "02/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBryce, Duane, Julianna, and Sonya share a 40 feet by 48 feet rectangular portion of the community garden in their neighborhood. Within this space, each has their own rectangular garden plot.\n\r\nBryce is the only one with a square plot. Its area is 1/2 the area of Duane's. \r\nThe area of Bryce's plot is 2/3 the area of Julianna's garden. Their plots have one side in common. \r\nSonya's garden has an area twice that of Julianna's garden. \n\r\nWhat are the dimensions (length and width) of each person's garden plot?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBryce's garden is 16 ft by 16 ft (with an area of 256 square feet).\r\nDuane's garden is 32 ft by 16 ft (with an area of 512 square feet).\r\nJulianna's garden is 24 ft by 16 ft (with an area of 384 square feet).\r\nSonya's garden is 24 ft by 32 ft (with an area of 768 square feet).\n<|im_start|>answer\nBryce's garden is 16 ft by 16 ft (with an area of 256 square feet).\r\nDuane's garden is 32 ft by 16 ft (with an area of 512 square feet).\r\nJulianna's garden is 24 ft by 16 ft (with an area of 384 square feet).\r\nSonya's garden is 24 ft by 32 ft (with an area of 768 square feet).\n<|im_end|>" }, { "id": "#8868", "title": "Father of the Brides", "fun": 2.35, "difficulty": 3.0, "author": "dewtell", "desc": "The wedding reception was winding down as Bill Johnson, the father of the bride, held forth to anyone who was left to hear his report on the fiscal damages.\n\r\n\"That's the last one married off - thank goodness! That's been one wedding a year for the last four years I've had to pay for. Alice got married three years ago, then Barbara, Cheryl, and now Denise. They've all gotten married on the same day, June 30th, for some reason, and each girl had to have her three sisters as the bridesmaids, but could they share a color scheme? No - each one had to have her own colors. God forbid they should be able to reuse the bridesmaids' dresses, let alone share a wedding dress. Alice tried to persuade Denise to reuse her color scheme, but Denise said she had lived with her older sister's hand-me-downs long enough.\n\r\nFunny thing, though - each bride managed to get married when her age was just the same as the sum of the digits of the ages of her three sisters. You don't see that every day, I bet. But why couldn't they share something that costs money instead of this trivia?\"\n\r\nBill didn't mention how old his daughters are, but he's given us enough information to work out all four ages. How old are they?", "hint": "1. Any non-negative integer is congruent to the sum of its digits, mod 9. (They have the same remainder when divided by 9.)\n\r\n2. Each daughter was between 17 and 33 at the time of her wedding.", "answer": "Alice is 27, Barbara is 28, Cheryl is 20, and Denise is 21, 21 = 2+7+2+8+2+0.\r\nA year ago, they were 26, 27, 19, and 20, 19 = 2+6+2+7+2+0.\r\nTwo years ago, they were 25, 26, 18, and 19, 26 = 2+5+1+8+1+9.\r\nThree years ago, they were 24, 25, 17, and 18, 24 = 2+5+1+7+1+8.\n\r\nYou can solve this one by trial and error (particularly with the hint), but you can also use the fact that any non-negative integer is congruent to the sum of its digits, mod 9. If a, b, c, and d are the present ages of the four women, that gives us four linear congruences:\r\nd = a + b + c (mod 9)\r\nc-1 = (a-1)+(b-1)+(d-1) (mod 9)\r\nb-2 = (a-2)+(c-2)+(d-2) (mod 9)\r\na-3 = (b-3)+(c-3)+(d-3) (mod 9).\n\r\nSolving for the four variables, we get: a=0, b=1, c=2, d=3 (all mod 9). It remains to find four integers congruent to these numbers that will satisfy the digit addition property. If you use the age restriction in the hint, you can omit some of the following analysis, but I present it here in full to show that the solution is truly unique even without the hint.\n\r\nIf we go back 3 years to Alice's wedding, we have: a-3=6, b-3=7, c-3=8, and d-3=9 (mod 9). Now all numbers less than 79 that are congruent to 7 also have a digit sum of 7, and likewise numbers congruent to 8 less than 89 have a digit sum of 8, and numbers congruent to 9 (except 0) less than 99 have a digit sum of 9. We can rule out such high ages, because each woman must have a turn being the sum of her sister's ages' digits, and the maximum sum of digits for three ages less than 199 is 54 (for 99, 99, and 99). Likewise, we can rule out zero as a valid age for Denise three years ago, because she needs to have an age now that can be the sum of the digits of three other valid ages. So Alice three years ago must have been 7+8+9=24, making her 27 now.\n\r\nNow go back 2 years to Barbara's wedding. Alice we now know was 25. Cheryl's age was congruent to 9 (mod 9), so she must have had a digit sum of 9. Denise's age was congruent to 1 (mod 9), so she must have had a digit sum of 10 unless she was 10 years old herself (we have previously ruled out 1 as a valid age). But if Denise was 10, then Barbara would have been 17 two years ago, and this year Alice and Barbara together would be contributing 2+7+1+9 = 19 years to Denise's age, contradicting the assumption that she was 10 two years ago. So Denise had a digit sum of 10 two years ago, and Barbara was therefore 2+5+9+10=26 at the time of her wedding, hence 28 now.\n\r\nNow consider Cheryl's wedding last year. Alice was 26 and Barbara was 27. Denise's age was congruent to 2 (mod 9), so she must have had a digit sum of either 2 or 11. If it was 11, then Cheryl would have been 11+2+6+2+7=28 then, making her 29 now. But then Denise would have to be 2+7+2+8+2+9=30 now to Alice's 27, contradicting the information that Alice was her older sister. So Denise's digit sum must have been 2 last year, making Cheryl 19 then, and Denise 21 now.", "category": "Math", "date": "12/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe wedding reception was winding down as Bill Johnson, the father of the bride, held forth to anyone who was left to hear his report on the fiscal damages.\n\r\n\"That's the last one married off - thank goodness! That's been one wedding a year for the last four years I've had to pay for. Alice got married three years ago, then Barbara, Cheryl, and now Denise. They've all gotten married on the same day, June 30th, for some reason, and each girl had to have her three sisters as the bridesmaids, but could they share a color scheme? No - each one had to have her own colors. God forbid they should be able to reuse the bridesmaids' dresses, let alone share a wedding dress. Alice tried to persuade Denise to reuse her color scheme, but Denise said she had lived with her older sister's hand-me-downs long enough.\n\r\nFunny thing, though - each bride managed to get married when her age was just the same as the sum of the digits of the ages of her three sisters. You don't see that every day, I bet. But why couldn't they share something that costs money instead of this trivia?\"\n\r\nBill didn't mention how old his daughters are, but he's given us enough information to work out all four ages. How old are they?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlice is 27, Barbara is 28, Cheryl is 20, and Denise is 21, 21 = 2+7+2+8+2+0.\r\nA year ago, they were 26, 27, 19, and 20, 19 = 2+6+2+7+2+0.\r\nTwo years ago, they were 25, 26, 18, and 19, 26 = 2+5+1+8+1+9.\r\nThree years ago, they were 24, 25, 17, and 18, 24 = 2+5+1+7+1+8.\n\r\nYou can solve this one by trial and error (particularly with the hint), but you can also use the fact that any non-negative integer is congruent to the sum of its digits, mod 9. If a, b, c, and d are the present ages of the four women, that gives us four linear congruences:\r\nd = a + b + c (mod 9)\r\nc-1 = (a-1)+(b-1)+(d-1) (mod 9)\r\nb-2 = (a-2)+(c-2)+(d-2) (mod 9)\r\na-3 = (b-3)+(c-3)+(d-3) (mod 9).\n\r\nSolving for the four variables, we get: a=0, b=1, c=2, d=3 (all mod 9). It remains to find four integers congruent to these numbers that will satisfy the digit addition property. If you use the age restriction in the hint, you can omit some of the following analysis, but I present it here in full to show that the solution is truly unique even without the hint.\n\r\nIf we go back 3 years to Alice's wedding, we have: a-3=6, b-3=7, c-3=8, and d-3=9 (mod 9). Now all numbers less than 79 that are congruent to 7 also have a digit sum of 7, and likewise numbers congruent to 8 less than 89 have a digit sum of 8, and numbers congruent to 9 (except 0) less than 99 have a digit sum of 9. We can rule out such high ages, because each woman must have a turn being the sum of her sister's ages' digits, and the maximum sum of digits for three ages less than 199 is 54 (for 99, 99, and 99). Likewise, we can rule out zero as a valid age for Denise three years ago, because she needs to have an age now that can be the sum of the digits of three other valid ages. So Alice three years ago must have been 7+8+9=24, making her 27 now.\n\r\nNow go back 2 years to Barbara's wedding. Alice we now know was 25. Cheryl's age was congruent to 9 (mod 9), so she must have had a digit sum of 9. Denise's age was congruent to 1 (mod 9), so she must have had a digit sum of 10 unless she was 10 years old herself (we have previously ruled out 1 as a valid age). But if Denise was 10, then Barbara would have been 17 two years ago, and this year Alice and Barbara together would be contributing 2+7+1+9 = 19 years to Denise's age, contradicting the assumption that she was 10 two years ago. So Denise had a digit sum of 10 two years ago, and Barbara was therefore 2+5+9+10=26 at the time of her wedding, hence 28 now.\n\r\nNow consider Cheryl's wedding last year. Alice was 26 and Barbara was 27. Denise's age was congruent to 2 (mod 9), so she must have had a digit sum of either 2 or 11. If it was 11, then Cheryl would have been 11+2+6+2+7=28 then, making her 29 now. But then Denise would have to be 2+7+2+8+2+9=30 now to Alice's 27, contradicting the information that Alice was her older sister. So Denise's digit sum must have been 2 last year, making Cheryl 19 then, and Denise 21 now.\n<|im_start|>answer\nAlice is 27, Barbara is 28, Cheryl is 20, and Denise is 21, 21 = 2+7+2+8+2+0.\r\nA year ago, they were 26, 27, 19, and 20, 19 = 2+6+2+7+2+0.\r\nTwo years ago, they were 25, 26, 18, and 19, 26 = 2+5+1+8+1+9.\r\nThree years ago, they were 24, 25, 17, and 18, 24 = 2+5+1+7+1+8.\n\r\nYou can solve this one by trial and error (particularly with the hint), but you can also use the fact that any non-negative integer is congruent to the sum of its digits, mod 9. If a, b, c, and d are the present ages of the four women, that gives us four linear congruences:\r\nd = a + b + c (mod 9)\r\nc-1 = (a-1)+(b-1)+(d-1) (mod 9)\r\nb-2 = (a-2)+(c-2)+(d-2) (mod 9)\r\na-3 = (b-3)+(c-3)+(d-3) (mod 9).\n\r\nSolving for the four variables, we get: a=0, b=1, c=2, d=3 (all mod 9). It remains to find four integers congruent to these numbers that will satisfy the digit addition property. If you use the age restriction in the hint, you can omit some of the following analysis, but I present it here in full to show that the solution is truly unique even without the hint.\n\r\nIf we go back 3 years to Alice's wedding, we have: a-3=6, b-3=7, c-3=8, and d-3=9 (mod 9). Now all numbers less than 79 that are congruent to 7 also have a digit sum of 7, and likewise numbers congruent to 8 less than 89 have a digit sum of 8, and numbers congruent to 9 (except 0) less than 99 have a digit sum of 9. We can rule out such high ages, because each woman must have a turn being the sum of her sister's ages' digits, and the maximum sum of digits for three ages less than 199 is 54 (for 99, 99, and 99). Likewise, we can rule out zero as a valid age for Denise three years ago, because she needs to have an age now that can be the sum of the digits of three other valid ages. So Alice three years ago must have been 7+8+9=24, making her 27 now.\n\r\nNow go back 2 years to Barbara's wedding. Alice we now know was 25. Cheryl's age was congruent to 9 (mod 9), so she must have had a digit sum of 9. Denise's age was congruent to 1 (mod 9), so she must have had a digit sum of 10 unless she was 10 years old herself (we have previously ruled out 1 as a valid age). But if Denise was 10, then Barbara would have been 17 two years ago, and this year Alice and Barbara together would be contributing 2+7+1+9 = 19 years to Denise's age, contradicting the assumption that she was 10 two years ago. So Denise had a digit sum of 10 two years ago, and Barbara was therefore 2+5+9+10=26 at the time of her wedding, hence 28 now.\n\r\nNow consider Cheryl's wedding last year. Alice was 26 and Barbara was 27. Denise's age was congruent to 2 (mod 9), so she must have had a digit sum of either 2 or 11. If it was 11, then Cheryl would have been 11+2+6+2+7=28 then, making her 29 now. But then Denise would have to be 2+7+2+8+2+9=30 now to Alice's 27, contradicting the information that Alice was her older sister. So Denise's digit sum must have been 2 last year, making Cheryl 19 then, and Denise 21 now.\n<|im_end|>" }, { "id": "#31709", "title": "Holiday Symbols", "fun": 2.35, "difficulty": 1.71, "author": "lips", "desc": "Students at Riverside School are learning about December holidays. Brian, David, Josh, Kevin, Michelle, and Stephanie each volunteered to bring in items to represent a different holiday. The holidays included are Boxing Day, Christmas, Hanukkah, Hogmanay, Kwanzaa, and New Year's Eve.\n\r\n1. Michelle learned about several holidays from her research. She found out that a Kinara is a candleholder used for Kwanzaa. She also learned that children celebrating Hogmanay in Scotland go house to house collecting special cakes. She brought in Hogmanay cakes. \r\n2. Kevin helped the boy who brought Christmas stockings and lights hang them up. \r\n3. David brought in candles and a candleholder. \r\n4. Josh shared a dreidel and his family's Hanukkah menorah and candles with the class. \r\n5. One of the girls brought in confetti for the New Year's celebration. \n\r\nMake a list to show who is responsible for each holiday.", "hint": "Make a chart and use the clues to eliminate the impossible combinations.", "answer": "David brought the Kinara and candles for Kwanzaa. \r\nBrian brought the lights and stockings for Christmas. \r\nJosh brought the menorah, candles, and dreidel for Hannukah. \r\nMichelle brought the cakes for Hogmanay. \r\nStephanie brought confetti for New Year's Eve. \r\nKevin brought used clothing to donate for Boxing Day.", "category": "Logic", "date": "07/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStudents at Riverside School are learning about December holidays. Brian, David, Josh, Kevin, Michelle, and Stephanie each volunteered to bring in items to represent a different holiday. The holidays included are Boxing Day, Christmas, Hanukkah, Hogmanay, Kwanzaa, and New Year's Eve.\n\r\n1. Michelle learned about several holidays from her research. She found out that a Kinara is a candleholder used for Kwanzaa. She also learned that children celebrating Hogmanay in Scotland go house to house collecting special cakes. She brought in Hogmanay cakes. \r\n2. Kevin helped the boy who brought Christmas stockings and lights hang them up. \r\n3. David brought in candles and a candleholder. \r\n4. Josh shared a dreidel and his family's Hanukkah menorah and candles with the class. \r\n5. One of the girls brought in confetti for the New Year's celebration. \n\r\nMake a list to show who is responsible for each holiday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDavid brought the Kinara and candles for Kwanzaa. \r\nBrian brought the lights and stockings for Christmas. \r\nJosh brought the menorah, candles, and dreidel for Hannukah. \r\nMichelle brought the cakes for Hogmanay. \r\nStephanie brought confetti for New Year's Eve. \r\nKevin brought used clothing to donate for Boxing Day.\n<|im_start|>answer\nDavid brought the Kinara and candles for Kwanzaa. \r\nBrian brought the lights and stockings for Christmas. \r\nJosh brought the menorah, candles, and dreidel for Hannukah. \r\nMichelle brought the cakes for Hogmanay. \r\nStephanie brought confetti for New Year's Eve. \r\nKevin brought used clothing to donate for Boxing Day.\n<|im_end|>" }, { "id": "#677", "title": "Generous Grandpa", "fun": 2.34, "difficulty": 1.28, "author": "vikass", "desc": "Grandpa was feeling generous, so he gave\n$100 to his five grandchildren. Starting \nwith the youngest, each got $2.00 more than the next younger one. In other words, the youngest got one sum, the next got $2.00 more, and so on.\n\nHow much did the youngest grandchild get?", "hint": "No hint available.", "answer": "$16", "category": "Math", "date": "07/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrandpa was feeling generous, so he gave\n$100 to his five grandchildren. Starting \nwith the youngest, each got $2.00 more than the next younger one. In other words, the youngest got one sum, the next got $2.00 more, and so on.\n\nHow much did the youngest grandchild get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$16\n<|im_start|>answer\n$16\n<|im_end|>" }, { "id": "#44422", "title": "Home Is Where?", "fun": 2.34, "difficulty": 1.29, "author": "whsprec", "desc": "In Greenville there are 4 stadiums but 5 teams, so two teams share a stadium. The stadiums are Thunderdome, Home Stretch, Sandlot, and All-Night. The teams are the Chockers, the Ringers, the JVs, the Burnouts, and the Overrateds. The sports played are rugby, soccer, hockey, football, and basketball. From the clues given, determine the name of each sports team and the stadium at which they play.\n\r\n1- Neither the Overrateds nor the team that plays at Sandlot must share its stadium, but the Burnouts must.\r\n2- The rugby team doesn't play at Sandlot and it shares its stadium with the JVs.\r\n3- The basketball team, the hockey team, and the Ringers do not share their stadiums.\r\n4- The soccer team is not called the Ringers and doesn't play at All-Night.\r\n5- The football team plays at Thunderdome stadium, but the hockey team does not play at All-Night.", "hint": "The shared stadium is Home Stretch.", "answer": "The Burnouts play rugby at Home Stretch.\r\nThe JVs play soccer at Home Stretch.\r\nThe Chockers play hockey at Sandlot.\r\nThe Ringers play football at Thunderdome.\r\nThe Overrateds play basketball at All-Night.", "category": "Logic-Grid", "date": "05/06/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Greenville there are 4 stadiums but 5 teams, so two teams share a stadium. The stadiums are Thunderdome, Home Stretch, Sandlot, and All-Night. The teams are the Chockers, the Ringers, the JVs, the Burnouts, and the Overrateds. The sports played are rugby, soccer, hockey, football, and basketball. From the clues given, determine the name of each sports team and the stadium at which they play.\n\r\n1- Neither the Overrateds nor the team that plays at Sandlot must share its stadium, but the Burnouts must.\r\n2- The rugby team doesn't play at Sandlot and it shares its stadium with the JVs.\r\n3- The basketball team, the hockey team, and the Ringers do not share their stadiums.\r\n4- The soccer team is not called the Ringers and doesn't play at All-Night.\r\n5- The football team plays at Thunderdome stadium, but the hockey team does not play at All-Night.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Burnouts play rugby at Home Stretch.\r\nThe JVs play soccer at Home Stretch.\r\nThe Chockers play hockey at Sandlot.\r\nThe Ringers play football at Thunderdome.\r\nThe Overrateds play basketball at All-Night.\n<|im_start|>answer\nThe Burnouts play rugby at Home Stretch.\r\nThe JVs play soccer at Home Stretch.\r\nThe Chockers play hockey at Sandlot.\r\nThe Ringers play football at Thunderdome.\r\nThe Overrateds play basketball at All-Night.\n<|im_end|>" }, { "id": "#12078", "title": "Old Man Justice and the Rotten Rascals", "fun": 2.34, "difficulty": 2.54, "author": "Codammanus", "desc": "One day three kids decide to wreak havoc in town-again (this is the third time this month). This time they run into an old man's grocery store and steal quite a few items. They hit the wrong spot this time, because this was Old Man Justice's place (he's notorious for meting out his own brand of 'justice'). Old Man Justice chases the kids through town, and during the chase, they drop the goods, turn around, and start chasing him. Unfortunately, the old man falls into a ditch and is badly hurt. A month later after he recovers he is able to identify the culprits, and Old Man Justice calls in his 'support team,' (2 of which were also victims of the thieves), and has the perpetrators rounded up for justice. At a dinner later that evening, dubbed the 'Repast of Right' the old man begins with these words: \n\r\n'To do what we've done took moxie and nerve,\r\nBut alas! As we eat, our justice is served.\r\nAs we've judged these few, let's render to each their due,\r\nNot an 'eye for an eye,' but rather 'one for two.' \r\n(What we see as JUST, is JUST what we do.)\r\nNeither trial, nor jury, should these ones receive,\r\nNo more to trouble us, for no more shall they breathe!\r\nSo drink wine of success, and not of defeat,\r\nJustice is waiting, so friends let us eat.'\n\r\nQuestion:\r\nProvided that Old Man Justice and those in his group are not cannibals, how are these three guilty kids punished by the people at the dinner?", "hint": "No hint available.", "answer": "The Old man and his group certainly did EAT THE KIDS, (as implied by the words of Old Man Justice), but they were of course young goats, and not young delinquent children.\n\r\nNotice that justice is going to be 'served' along with this meal. Also, this extreme justice is also going to result in the kids not-breathing, (meaning they will die), and thus won't be any more trouble. It is not an 'eye for eye' but more like 'one for two' because Old Man Justice was only injured, not killed, therefore the 'justice' is not proportionate to the crime. It also took guts and nerve for these seniors to hunt down someone's livestock and kill it, without the benefit of due process, or discussion w/ the owner in the least.\n\r\nAs they were good for a meal, I suppose the kids weren't so rotten after all!", "category": "Logic", "date": "04/27/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day three kids decide to wreak havoc in town-again (this is the third time this month). This time they run into an old man's grocery store and steal quite a few items. They hit the wrong spot this time, because this was Old Man Justice's place (he's notorious for meting out his own brand of 'justice'). Old Man Justice chases the kids through town, and during the chase, they drop the goods, turn around, and start chasing him. Unfortunately, the old man falls into a ditch and is badly hurt. A month later after he recovers he is able to identify the culprits, and Old Man Justice calls in his 'support team,' (2 of which were also victims of the thieves), and has the perpetrators rounded up for justice. At a dinner later that evening, dubbed the 'Repast of Right' the old man begins with these words: \n\r\n'To do what we've done took moxie and nerve,\r\nBut alas! As we eat, our justice is served.\r\nAs we've judged these few, let's render to each their due,\r\nNot an 'eye for an eye,' but rather 'one for two.' \r\n(What we see as JUST, is JUST what we do.)\r\nNeither trial, nor jury, should these ones receive,\r\nNo more to trouble us, for no more shall they breathe!\r\nSo drink wine of success, and not of defeat,\r\nJustice is waiting, so friends let us eat.'\n\r\nQuestion:\r\nProvided that Old Man Justice and those in his group are not cannibals, how are these three guilty kids punished by the people at the dinner?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Old man and his group certainly did EAT THE KIDS, (as implied by the words of Old Man Justice), but they were of course young goats, and not young delinquent children.\n\r\nNotice that justice is going to be 'served' along with this meal. Also, this extreme justice is also going to result in the kids not-breathing, (meaning they will die), and thus won't be any more trouble. It is not an 'eye for eye' but more like 'one for two' because Old Man Justice was only injured, not killed, therefore the 'justice' is not proportionate to the crime. It also took guts and nerve for these seniors to hunt down someone's livestock and kill it, without the benefit of due process, or discussion w/ the owner in the least.\n\r\nAs they were good for a meal, I suppose the kids weren't so rotten after all!\n<|im_start|>answer\nThe Old man and his group certainly did EAT THE KIDS, (as implied by the words of Old Man Justice), but they were of course young goats, and not young delinquent children.\n\r\nNotice that justice is going to be 'served' along with this meal. Also, this extreme justice is also going to result in the kids not-breathing, (meaning they will die), and thus won't be any more trouble. It is not an 'eye for eye' but more like 'one for two' because Old Man Justice was only injured, not killed, therefore the 'justice' is not proportionate to the crime. It also took guts and nerve for these seniors to hunt down someone's livestock and kill it, without the benefit of due process, or discussion w/ the owner in the least.\n\r\nAs they were good for a meal, I suppose the kids weren't so rotten after all!\n<|im_end|>" }, { "id": "#41300", "title": "Poster Kingdom", "fun": 2.34, "difficulty": 1.97, "author": "jsteppergurl", "desc": "POSTER PRICES:\r\n12\" x 18\" posters cost $7 \r\n24\" x 36\" posters cost $9 \r\n41\" x 20\" posters cost $11 \n\r\nThe Poster Kingdom is offering a special sale on their posters: \"Buy two posters, and take a dollar off one of the posters.\" Kathy, Lauren, Joe, Travis, and Shirley each bought two posters and spent a total of $85.\n\r\nShirley bought two different-size posters, but they were not the same combination as those Travis or Kathy bought. \r\nKathy spent $17 on two different-size posters. \r\nThe two posters Travis bought cover 1,080 square inches. \r\nLauren spent the most, purchasing two posters of the same size. \r\nHow much money did each person spend, and what size posters did they buy?", "hint": "Try working backwards.", "answer": "Kathy's posters were 12\" x 18\" and 41\" x 20\". She spent a total of $17.\r\nLauren's posters were both 41\" x 20\". She spent a total of $21.\r\nJoe's two posters were 12\" x 18\". She spent a total of $13.\r\nTravis' posters were 12\" x 18\" and 24\" x 36\". He spent a total of $15.\r\nShirley's posters were 24\" x 36\" and 41\" x 20\". She spent a total of $19.", "category": "Math", "date": "03/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPOSTER PRICES:\r\n12\" x 18\" posters cost $7 \r\n24\" x 36\" posters cost $9 \r\n41\" x 20\" posters cost $11 \n\r\nThe Poster Kingdom is offering a special sale on their posters: \"Buy two posters, and take a dollar off one of the posters.\" Kathy, Lauren, Joe, Travis, and Shirley each bought two posters and spent a total of $85.\n\r\nShirley bought two different-size posters, but they were not the same combination as those Travis or Kathy bought. \r\nKathy spent $17 on two different-size posters. \r\nThe two posters Travis bought cover 1,080 square inches. \r\nLauren spent the most, purchasing two posters of the same size. \r\nHow much money did each person spend, and what size posters did they buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKathy's posters were 12\" x 18\" and 41\" x 20\". She spent a total of $17.\r\nLauren's posters were both 41\" x 20\". She spent a total of $21.\r\nJoe's two posters were 12\" x 18\". She spent a total of $13.\r\nTravis' posters were 12\" x 18\" and 24\" x 36\". He spent a total of $15.\r\nShirley's posters were 24\" x 36\" and 41\" x 20\". She spent a total of $19.\n<|im_start|>answer\nKathy's posters were 12\" x 18\" and 41\" x 20\". She spent a total of $17.\r\nLauren's posters were both 41\" x 20\". She spent a total of $21.\r\nJoe's two posters were 12\" x 18\". She spent a total of $13.\r\nTravis' posters were 12\" x 18\" and 24\" x 36\". He spent a total of $15.\r\nShirley's posters were 24\" x 36\" and 41\" x 20\". She spent a total of $19.\n<|im_end|>" }, { "id": "#32823", "title": "Menagerie", "fun": 2.34, "difficulty": 3.03, "author": "cnmne", "desc": "Zachary has a private zoo. He has five groups of animals in his zoo: snakes, birds, mammals, insects, and spiders. Assume that, typically: animals have 1 head, snakes have 0 legs, birds have 2 legs, mammals have 4 legs, insects have 6 legs, and spiders have 8 legs. Zachary has some unusual animals in his zoo. He has: a snake with 3 heads, a bird with 2 heads, a mammal with 3 legs, an insect with 4 legs, and a spider with 7 legs. From the following information, determine how many of each group of animals that Zachary has in his menagerie.\n\r\n1) There are a total of 100 heads and 376 legs.\r\n2) Each group has a different quantity of animals.\r\n3) The most populous group has 10 more members than the least populous group.\r\n4) There are twice as many insect legs as there are bird legs.\r\n5) There are as many snake heads as there are spider heads.", "hint": "No hint available.", "answer": "A) Since there are 3 extra heads (2 snake and 1 bird), there are only 97 animals (clue 1). Find a set of five different numbers whose sum is 97 (clue 2) and whose size difference between the least populous and most populous group is 10 (clue 3). There are 17 sets that meet these requirements.\r\n13, 18, 21, 22, 23\r\n13, 19, 20, 22, 23\r\n14, 15, 21, 23, 24\r\n14, 16, 20, 23, 24\r\n14, 16, 21, 22, 24\r\n14, 17, 19, 23, 24\r\n14, 17, 20, 22, 24\r\n14, 18, 19, 22, 24\r\n14, 18, 20, 21, 24\r\n15, 16, 17, 24, 25\r\n15, 16, 18, 23, 25\r\n15, 16, 19, 22, 25\r\n15, 16, 20, 21, 25\r\n15, 17, 18, 22, 25\r\n15, 17, 19, 21, 25\r\n15, 18, 19, 20, 25\r\n16, 17, 18, 20, 26\r\nB) There are twice as many insect legs as there are bird legs (clue 4). To find the possible bird and insect group sizes, multiply the quantity of insects by 6 (legs per insect). Subtract 2 (an insect is missing 2 legs). Divide by 2 (twice as many insect legs as bird legs). Divide by 2 (legs per bird) to get the quantity of birds. The formula is: B = ((I * 6) - 2) / 4. There are three combinations that work: 13 and 19, 15 and 22, 17 and 25.\r\n((13 insects * 6 legs/insect) - 2 missing legs) / 4 = 19 birds\r\n((15 insects * 6 legs/insect) - 2 missing legs) / 4 = 22 birds\r\n((17 insects * 6 legs/insect) - 2 missing legs) / 4 = 25 birds\r\nOf the 17 sets (from step A), only 5 contain these sizes.\r\n13, 19, 20, 22, 23 (13 insects & 19 birds)\r\n15, 16, 17, 24, 25 (17 insects & 25 birds)\r\n15, 16, 19, 22, 25 (15 insects & 22 birds)\r\n15, 17, 18, 22, 25 (15 insects & 22 birds or 17 insects & 25 birds)\r\n15, 17, 19, 21, 25 (17 insects & 25 birds)\r\nC) There are as many snake heads as spider heads (clue 5). Since there is a snake with two extra heads, there are actually 2 fewer snakes compared to spiders. Only 2 combinations (from step B) yield the required head count.\r\n13 insects, 19 birds, 20 snakes, 22 spiders, 23 mammals\r\n15 mammals, 17 insects, 19 snakes, 21 spiders, 25 birds\r\nD) The only group combination (from step C) that produces 376 legs (clue 1) is: 15, 17, 19, 21, 25. The other combination yields 380 legs.\r\n(15 mammals * 4 legs/mammal) - 1 missing leg = 59 legs\r\n(17 insects * 6 legs/insect) - 2 missing legs = 100 legs\r\n19 snakes * 0 legs/snake = 0 legs\r\n(21 spiders * 8 legs/spider) - 1 missing leg = 167 legs\r\n25 birds * 2 legs/birds = 50 legs\n\r\nThus, there are: 19 snakes (21 heads and 0 legs), 25 birds (26 heads and 50 legs), 15 mammals (15 heads and 59 legs), 17 insects (17 heads and 100 legs), and 21 spiders (21 heads and 167 legs). This produces 97 animals with 100 heads and 376 legs.", "category": "Logic", "date": "09/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nZachary has a private zoo. He has five groups of animals in his zoo: snakes, birds, mammals, insects, and spiders. Assume that, typically: animals have 1 head, snakes have 0 legs, birds have 2 legs, mammals have 4 legs, insects have 6 legs, and spiders have 8 legs. Zachary has some unusual animals in his zoo. He has: a snake with 3 heads, a bird with 2 heads, a mammal with 3 legs, an insect with 4 legs, and a spider with 7 legs. From the following information, determine how many of each group of animals that Zachary has in his menagerie.\n\r\n1) There are a total of 100 heads and 376 legs.\r\n2) Each group has a different quantity of animals.\r\n3) The most populous group has 10 more members than the least populous group.\r\n4) There are twice as many insect legs as there are bird legs.\r\n5) There are as many snake heads as there are spider heads.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA) Since there are 3 extra heads (2 snake and 1 bird), there are only 97 animals (clue 1). Find a set of five different numbers whose sum is 97 (clue 2) and whose size difference between the least populous and most populous group is 10 (clue 3). There are 17 sets that meet these requirements.\r\n13, 18, 21, 22, 23\r\n13, 19, 20, 22, 23\r\n14, 15, 21, 23, 24\r\n14, 16, 20, 23, 24\r\n14, 16, 21, 22, 24\r\n14, 17, 19, 23, 24\r\n14, 17, 20, 22, 24\r\n14, 18, 19, 22, 24\r\n14, 18, 20, 21, 24\r\n15, 16, 17, 24, 25\r\n15, 16, 18, 23, 25\r\n15, 16, 19, 22, 25\r\n15, 16, 20, 21, 25\r\n15, 17, 18, 22, 25\r\n15, 17, 19, 21, 25\r\n15, 18, 19, 20, 25\r\n16, 17, 18, 20, 26\r\nB) There are twice as many insect legs as there are bird legs (clue 4). To find the possible bird and insect group sizes, multiply the quantity of insects by 6 (legs per insect). Subtract 2 (an insect is missing 2 legs). Divide by 2 (twice as many insect legs as bird legs). Divide by 2 (legs per bird) to get the quantity of birds. The formula is: B = ((I * 6) - 2) / 4. There are three combinations that work: 13 and 19, 15 and 22, 17 and 25.\r\n((13 insects * 6 legs/insect) - 2 missing legs) / 4 = 19 birds\r\n((15 insects * 6 legs/insect) - 2 missing legs) / 4 = 22 birds\r\n((17 insects * 6 legs/insect) - 2 missing legs) / 4 = 25 birds\r\nOf the 17 sets (from step A), only 5 contain these sizes.\r\n13, 19, 20, 22, 23 (13 insects & 19 birds)\r\n15, 16, 17, 24, 25 (17 insects & 25 birds)\r\n15, 16, 19, 22, 25 (15 insects & 22 birds)\r\n15, 17, 18, 22, 25 (15 insects & 22 birds or 17 insects & 25 birds)\r\n15, 17, 19, 21, 25 (17 insects & 25 birds)\r\nC) There are as many snake heads as spider heads (clue 5). Since there is a snake with two extra heads, there are actually 2 fewer snakes compared to spiders. Only 2 combinations (from step B) yield the required head count.\r\n13 insects, 19 birds, 20 snakes, 22 spiders, 23 mammals\r\n15 mammals, 17 insects, 19 snakes, 21 spiders, 25 birds\r\nD) The only group combination (from step C) that produces 376 legs (clue 1) is: 15, 17, 19, 21, 25. The other combination yields 380 legs.\r\n(15 mammals * 4 legs/mammal) - 1 missing leg = 59 legs\r\n(17 insects * 6 legs/insect) - 2 missing legs = 100 legs\r\n19 snakes * 0 legs/snake = 0 legs\r\n(21 spiders * 8 legs/spider) - 1 missing leg = 167 legs\r\n25 birds * 2 legs/birds = 50 legs\n\r\nThus, there are: 19 snakes (21 heads and 0 legs), 25 birds (26 heads and 50 legs), 15 mammals (15 heads and 59 legs), 17 insects (17 heads and 100 legs), and 21 spiders (21 heads and 167 legs). This produces 97 animals with 100 heads and 376 legs.\n<|im_start|>answer\nA) Since there are 3 extra heads (2 snake and 1 bird), there are only 97 animals (clue 1). Find a set of five different numbers whose sum is 97 (clue 2) and whose size difference between the least populous and most populous group is 10 (clue 3). There are 17 sets that meet these requirements.\r\n13, 18, 21, 22, 23\r\n13, 19, 20, 22, 23\r\n14, 15, 21, 23, 24\r\n14, 16, 20, 23, 24\r\n14, 16, 21, 22, 24\r\n14, 17, 19, 23, 24\r\n14, 17, 20, 22, 24\r\n14, 18, 19, 22, 24\r\n14, 18, 20, 21, 24\r\n15, 16, 17, 24, 25\r\n15, 16, 18, 23, 25\r\n15, 16, 19, 22, 25\r\n15, 16, 20, 21, 25\r\n15, 17, 18, 22, 25\r\n15, 17, 19, 21, 25\r\n15, 18, 19, 20, 25\r\n16, 17, 18, 20, 26\r\nB) There are twice as many insect legs as there are bird legs (clue 4). To find the possible bird and insect group sizes, multiply the quantity of insects by 6 (legs per insect). Subtract 2 (an insect is missing 2 legs). Divide by 2 (twice as many insect legs as bird legs). Divide by 2 (legs per bird) to get the quantity of birds. The formula is: B = ((I * 6) - 2) / 4. There are three combinations that work: 13 and 19, 15 and 22, 17 and 25.\r\n((13 insects * 6 legs/insect) - 2 missing legs) / 4 = 19 birds\r\n((15 insects * 6 legs/insect) - 2 missing legs) / 4 = 22 birds\r\n((17 insects * 6 legs/insect) - 2 missing legs) / 4 = 25 birds\r\nOf the 17 sets (from step A), only 5 contain these sizes.\r\n13, 19, 20, 22, 23 (13 insects & 19 birds)\r\n15, 16, 17, 24, 25 (17 insects & 25 birds)\r\n15, 16, 19, 22, 25 (15 insects & 22 birds)\r\n15, 17, 18, 22, 25 (15 insects & 22 birds or 17 insects & 25 birds)\r\n15, 17, 19, 21, 25 (17 insects & 25 birds)\r\nC) There are as many snake heads as spider heads (clue 5). Since there is a snake with two extra heads, there are actually 2 fewer snakes compared to spiders. Only 2 combinations (from step B) yield the required head count.\r\n13 insects, 19 birds, 20 snakes, 22 spiders, 23 mammals\r\n15 mammals, 17 insects, 19 snakes, 21 spiders, 25 birds\r\nD) The only group combination (from step C) that produces 376 legs (clue 1) is: 15, 17, 19, 21, 25. The other combination yields 380 legs.\r\n(15 mammals * 4 legs/mammal) - 1 missing leg = 59 legs\r\n(17 insects * 6 legs/insect) - 2 missing legs = 100 legs\r\n19 snakes * 0 legs/snake = 0 legs\r\n(21 spiders * 8 legs/spider) - 1 missing leg = 167 legs\r\n25 birds * 2 legs/birds = 50 legs\n\r\nThus, there are: 19 snakes (21 heads and 0 legs), 25 birds (26 heads and 50 legs), 15 mammals (15 heads and 59 legs), 17 insects (17 heads and 100 legs), and 21 spiders (21 heads and 167 legs). This produces 97 animals with 100 heads and 376 legs.\n<|im_end|>" }, { "id": "#6243", "title": "Kebab Farmer", "fun": 2.34, "difficulty": 2.13, "author": "mad-ade", "desc": "In the legendary country of MADADIA, there once lived a kebab farmer. One day, he had 1000 freshly grown Kebabs to package and 10 empty boxes into which to put them.\r\n He asks his assistant Norris O'Cabbage to place all the one thousand Kebabs in all the 10 boxes in such a manner that if a customer asks for any number of Kebabs from 1 to 1000, Norris should be able to pick them in terms of boxes. \n\r\nHow did Norris O'Cabbage place all the Kebabs among the ten boxes, given that any number of freshly harvested Kebabs can be put in one box.", "hint": "No hint available.", "answer": "1, 2, 4, 8, 16, 32, 64, 128, 256, 489 \n\r\nLet's start from scratch. \r\nThe Kebab farmer can ask for only 1 Kebab, so one box must contain 1 Kebab.\r\nHe can ask for 2 Kebabs, so one box must contain 2 Kebabs. \r\nHe can ask for 3 Kebabs, in which case box one and box two will add up to 3 Kebabs.\r\nHe can ask for 4 Kebabs, so one box, i.e. a third box, must contain 4 Kebabs. \r\nNow using box number one, two and three containing 1, 2 and 4 Kebabs respectively, Norris can give up to 7 Kebabs. Hence, the fourth box must contain 8 Kebabs. \r\nSimilarly, using first four boxes containing 1, 2, 4 and 8 Kebabs, Norris can give up to 15 Kebabs. Hence, the fifth box must contain 16 Kebabs.\r\nYou must have noticed one thing: that each box till now contains power of 2 Kebabs. Hence the answer is 1, 2, 4, 8, 16, 32, 64, 128, 256, 489. This is true for any number of Kebabs.", "category": "Math", "date": "08/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary country of MADADIA, there once lived a kebab farmer. One day, he had 1000 freshly grown Kebabs to package and 10 empty boxes into which to put them.\r\n He asks his assistant Norris O'Cabbage to place all the one thousand Kebabs in all the 10 boxes in such a manner that if a customer asks for any number of Kebabs from 1 to 1000, Norris should be able to pick them in terms of boxes. \n\r\nHow did Norris O'Cabbage place all the Kebabs among the ten boxes, given that any number of freshly harvested Kebabs can be put in one box.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1, 2, 4, 8, 16, 32, 64, 128, 256, 489 \n\r\nLet's start from scratch. \r\nThe Kebab farmer can ask for only 1 Kebab, so one box must contain 1 Kebab.\r\nHe can ask for 2 Kebabs, so one box must contain 2 Kebabs. \r\nHe can ask for 3 Kebabs, in which case box one and box two will add up to 3 Kebabs.\r\nHe can ask for 4 Kebabs, so one box, i.e. a third box, must contain 4 Kebabs. \r\nNow using box number one, two and three containing 1, 2 and 4 Kebabs respectively, Norris can give up to 7 Kebabs. Hence, the fourth box must contain 8 Kebabs. \r\nSimilarly, using first four boxes containing 1, 2, 4 and 8 Kebabs, Norris can give up to 15 Kebabs. Hence, the fifth box must contain 16 Kebabs.\r\nYou must have noticed one thing: that each box till now contains power of 2 Kebabs. Hence the answer is 1, 2, 4, 8, 16, 32, 64, 128, 256, 489. This is true for any number of Kebabs.\n<|im_start|>answer\n1, 2, 4, 8, 16, 32, 64, 128, 256, 489 \n\r\nLet's start from scratch. \r\nThe Kebab farmer can ask for only 1 Kebab, so one box must contain 1 Kebab.\r\nHe can ask for 2 Kebabs, so one box must contain 2 Kebabs. \r\nHe can ask for 3 Kebabs, in which case box one and box two will add up to 3 Kebabs.\r\nHe can ask for 4 Kebabs, so one box, i.e. a third box, must contain 4 Kebabs. \r\nNow using box number one, two and three containing 1, 2 and 4 Kebabs respectively, Norris can give up to 7 Kebabs. Hence, the fourth box must contain 8 Kebabs. \r\nSimilarly, using first four boxes containing 1, 2, 4 and 8 Kebabs, Norris can give up to 15 Kebabs. Hence, the fifth box must contain 16 Kebabs.\r\nYou must have noticed one thing: that each box till now contains power of 2 Kebabs. Hence the answer is 1, 2, 4, 8, 16, 32, 64, 128, 256, 489. This is true for any number of Kebabs.\n<|im_end|>" }, { "id": "#5125", "title": "Spiders and Flies", "fun": 2.34, "difficulty": 1.46, "author": "Cascas", "desc": "There was a big web with 13 spiders and flies on it. There were a total of 94 legs on the web. How many spiders are there?", "hint": "No hint available.", "answer": "8", "category": "Math", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a big web with 13 spiders and flies on it. There were a total of 94 legs on the web. How many spiders are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8\n<|im_start|>answer\n8\n<|im_end|>" }, { "id": "#669", "title": "Copying Tapes", "fun": 2.34, "difficulty": 1.22, "author": "vikass", "desc": "Marty and Jill want to copy three 60 minute tapes. They have two tape recorders that will dub the tapes for them, so they can do two at a time.\r\nIt takes 30 minutes for each side to complete; therefore in one hour two tapes will be done, and in another hour the third will be done. Jill says all three tapes can be made in 90 minutes. How?", "hint": "No hint available.", "answer": "Jill will rotate the three tapes. Let's call them tapes 1,2, and 3 with sides A and B. In the first 30 minutes they will tape 1A and 2A, in the second 30 minutes they will tape 1B and 3A (Tape 1 is now done). Finally, in the last 30 minutes, they will tape 2B and 3B.", "category": "Logic", "date": "06/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMarty and Jill want to copy three 60 minute tapes. They have two tape recorders that will dub the tapes for them, so they can do two at a time.\r\nIt takes 30 minutes for each side to complete; therefore in one hour two tapes will be done, and in another hour the third will be done. Jill says all three tapes can be made in 90 minutes. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJill will rotate the three tapes. Let's call them tapes 1,2, and 3 with sides A and B. In the first 30 minutes they will tape 1A and 2A, in the second 30 minutes they will tape 1B and 3A (Tape 1 is now done). Finally, in the last 30 minutes, they will tape 2B and 3B.\n<|im_start|>answer\nJill will rotate the three tapes. Let's call them tapes 1,2, and 3 with sides A and B. In the first 30 minutes they will tape 1A and 2A, in the second 30 minutes they will tape 1B and 3A (Tape 1 is now done). Finally, in the last 30 minutes, they will tape 2B and 3B.\n<|im_end|>" }, { "id": "#2823", "title": "Airplanes", "fun": 2.34, "difficulty": 1.37, "author": "204_BlaZe_41", "desc": "There are two airplanes heading straight toward each other. One plane is travelling at 15km per minute, and the other is travelling at 10km per minute. Assuming that the planes are exactly 1000 km apart, what distance will be between them one minute before they meet?", "hint": "No hint available.", "answer": "25 kilometers. Since they are travelling at a combined speed of 25 kilometers per minute toward each other, they will be 25 km apart one minute before they meet.", "category": "Math", "date": "03/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two airplanes heading straight toward each other. One plane is travelling at 15km per minute, and the other is travelling at 10km per minute. Assuming that the planes are exactly 1000 km apart, what distance will be between them one minute before they meet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n25 kilometers. Since they are travelling at a combined speed of 25 kilometers per minute toward each other, they will be 25 km apart one minute before they meet.\n<|im_start|>answer\n25 kilometers. Since they are travelling at a combined speed of 25 kilometers per minute toward each other, they will be 25 km apart one minute before they meet.\n<|im_end|>" }, { "id": "#23557", "title": "Food", "fun": 2.34, "difficulty": 1.68, "author": "Yoyobug02", "desc": "Two great white sharks were boasting about how much they ate. Jaws said to Teeth, \"I ate 98 pounds of codfish and half as much shrimp. Then I ate 44 bluefish that weighed 3 pounds each, and for dessert I had a 100-pound boat anchor.\"\n\r\n\"That's nothing,\" said Teeth. \"I gulped down an entire tuna that weighed 52 kg. Then I ate three tentacles from a giant octopus. They weighed 28 kg each. And for dessert I had a floating life preserver, about 4 and one half kg, I would say.\"\n\r\nSo, who ate more?", "hint": "No hint available.", "answer": "Jaws ate more than Teeth.\n\r\nJaws ate:\n\r\n98.0 lbs of codfish\r\n49.0 lbs of shrimp (98/2)\r\n132.0 lbs of bluefish (3x44)\r\n100.0 lbs of boat anchor\n\r\n379.0 lbs TOTAL \n\r\nTeeth ate:\n\r\n52.0 kg of tuna\r\n84.0 kg of octopus tentacle (3x28)\r\n4.5 kg of life preserver\n\r\n140.5 kg TOTAL\n\r\nTo convert pounds to kilograms, multiply by 0.45.\r\nJaws ate 379 lbs, or 170.55 kg, of food.\n\r\nOr, to convert kilograms to pounds, multiply by 2.2.\r\nTeeth ate 140.5 kg, or 309.1 lbs, of food.\n\r\nEither way, Teeth loses.", "category": "Math", "date": "06/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo great white sharks were boasting about how much they ate. Jaws said to Teeth, \"I ate 98 pounds of codfish and half as much shrimp. Then I ate 44 bluefish that weighed 3 pounds each, and for dessert I had a 100-pound boat anchor.\"\n\r\n\"That's nothing,\" said Teeth. \"I gulped down an entire tuna that weighed 52 kg. Then I ate three tentacles from a giant octopus. They weighed 28 kg each. And for dessert I had a floating life preserver, about 4 and one half kg, I would say.\"\n\r\nSo, who ate more?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJaws ate more than Teeth.\n\r\nJaws ate:\n\r\n98.0 lbs of codfish\r\n49.0 lbs of shrimp (98/2)\r\n132.0 lbs of bluefish (3x44)\r\n100.0 lbs of boat anchor\n\r\n379.0 lbs TOTAL \n\r\nTeeth ate:\n\r\n52.0 kg of tuna\r\n84.0 kg of octopus tentacle (3x28)\r\n4.5 kg of life preserver\n\r\n140.5 kg TOTAL\n\r\nTo convert pounds to kilograms, multiply by 0.45.\r\nJaws ate 379 lbs, or 170.55 kg, of food.\n\r\nOr, to convert kilograms to pounds, multiply by 2.2.\r\nTeeth ate 140.5 kg, or 309.1 lbs, of food.\n\r\nEither way, Teeth loses.\n<|im_start|>answer\nJaws ate more than Teeth.\n\r\nJaws ate:\n\r\n98.0 lbs of codfish\r\n49.0 lbs of shrimp (98/2)\r\n132.0 lbs of bluefish (3x44)\r\n100.0 lbs of boat anchor\n\r\n379.0 lbs TOTAL \n\r\nTeeth ate:\n\r\n52.0 kg of tuna\r\n84.0 kg of octopus tentacle (3x28)\r\n4.5 kg of life preserver\n\r\n140.5 kg TOTAL\n\r\nTo convert pounds to kilograms, multiply by 0.45.\r\nJaws ate 379 lbs, or 170.55 kg, of food.\n\r\nOr, to convert kilograms to pounds, multiply by 2.2.\r\nTeeth ate 140.5 kg, or 309.1 lbs, of food.\n\r\nEither way, Teeth loses.\n<|im_end|>" }, { "id": "#19461", "title": "Kitchen Cups", "fun": 2.34, "difficulty": 1.12, "author": "kagome", "desc": "All you have in the kitchen are 2 containers. The smaller holds 3 cups and the larger holds 5 cups. How can you use these two containers to measure exactly 1 cup of water?", "hint": "No hint available.", "answer": "Fill the 3 cup container with water. Pour it into the 5 cup container. Then repeat until the 5 cup container is full and you will have 1 cup of water left in the 3 cup container.", "category": "Logic", "date": "11/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAll you have in the kitchen are 2 containers. The smaller holds 3 cups and the larger holds 5 cups. How can you use these two containers to measure exactly 1 cup of water?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFill the 3 cup container with water. Pour it into the 5 cup container. Then repeat until the 5 cup container is full and you will have 1 cup of water left in the 3 cup container.\n<|im_start|>answer\nFill the 3 cup container with water. Pour it into the 5 cup container. Then repeat until the 5 cup container is full and you will have 1 cup of water left in the 3 cup container.\n<|im_end|>" }, { "id": "#2172", "title": "Six Daughters", "fun": 2.34, "difficulty": 0.72, "author": "Cascas", "desc": "A husband and wife have six daughters and each daughter has one brother. How many people are in the family?", "hint": "No hint available.", "answer": "Nine. Each daughter shares the same brother.", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA husband and wife have six daughters and each daughter has one brother. How many people are in the family?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNine. Each daughter shares the same brother.\n<|im_start|>answer\nNine. Each daughter shares the same brother.\n<|im_end|>" }, { "id": "#8440", "title": "A Boy and His Ducks", "fun": 2.34, "difficulty": 0.79, "author": "electronjohn", "desc": "A boy, walking home some ducks, was asked how many he had. He replied, \r\n\"When in line, there are two ducks ahead of a duck, two ducks behind a duck, and one duck in the middle.\" How many ducks had he?", "hint": "Ducks like to swim. Not a good hint you say? Well I guess you are right about that. OK, pay attention to the commas. Each statement between commas should be considered separately. And do not read it as \"at least\" two ducks ahead of \"at least\" one duck, etc. It has all the words it needs already in it.", "answer": "There are three ducks. Two in front of the last duck. Two behind the first duck. And one duck in the middle with a duck in front and behind it.", "category": "Logic", "date": "11/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA boy, walking home some ducks, was asked how many he had. He replied, \r\n\"When in line, there are two ducks ahead of a duck, two ducks behind a duck, and one duck in the middle.\" How many ducks had he?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are three ducks. Two in front of the last duck. Two behind the first duck. And one duck in the middle with a duck in front and behind it.\n<|im_start|>answer\nThere are three ducks. Two in front of the last duck. Two behind the first duck. And one duck in the middle with a duck in front and behind it.\n<|im_end|>" }, { "id": "#27914", "title": "Sally, George, and Frank", "fun": 2.34, "difficulty": 0.7000000000000001, "author": "EnderofGames", "desc": "Sally, George, and Frank were picking up their fast-food orders: a burger, a plate of fries, and a slice of pizza. \n\r\n \"Who ordered what?\" asked the man at the counter.\n\r\n George didn't order the pizza, but the boy who ordered the fries thought he did. This was all the waiter needed to know.\n\r\nWho ordered what?", "hint": "No hint available.", "answer": "Sally ordered the pizza, George ordered the burger, and Frank ordered the fries.", "category": "Logic", "date": "01/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally, George, and Frank were picking up their fast-food orders: a burger, a plate of fries, and a slice of pizza. \n\r\n \"Who ordered what?\" asked the man at the counter.\n\r\n George didn't order the pizza, but the boy who ordered the fries thought he did. This was all the waiter needed to know.\n\r\nWho ordered what?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSally ordered the pizza, George ordered the burger, and Frank ordered the fries.\n<|im_start|>answer\nSally ordered the pizza, George ordered the burger, and Frank ordered the fries.\n<|im_end|>" }, { "id": "#49982", "title": "A Series of Headaches", "fun": 2.34, "difficulty": 2.8, "author": "eighsse", "desc": "The Detroit Tigers played the Cincinnati Reds in the World Series (Major League Baseball). In this particular series (which went the full seven games), there was only one shutout, and no team scored more than 12 runs in any game. Following are some facts that apply to BOTH teams, individually, pertaining to the number of runs scored in each of the 7 games (no information is given about the order in which these games occured). For each team, there were:\n\r\n[1] 4 games with a prime number of runs.\r\n[2] A multiple of 3 games with an even number of runs.\r\n[3] No two games, the product of whose runs was a prime number.\r\n[4] 2 games with a perfect square of runs.\r\n[5] No game with exactly 5 runs.\n\r\nThe Tigers scored 30 runs in the entire series, and [6] scored 7 or 8 runs in at least one game. The Reds scored 36 runs, and [7] of all seven games, there are exactly two pairs of games, the sum of whose runs was exactly 9 (a game can be used in multiple pairs).\n\r\nBased on this information, which of these statements is accurate?\r\n1. The Detroit Tigers won the World Series.\r\n2. The Cincinnati Reds won the World Series.\r\n3. The World Series winner is uncertain.\n\r\nThe bracketed clue numbers [1]-[7] are used for reference in the answer explanation.", "hint": "Hint: In baseball, the points are called \"runs,\" and there are no tie games in Major League Baseball. The World Series is a best-of-seven series of games. A shutout is a game in which a team is held to 0 runs. Of course, this entire scenario is hypothetical, and not based upon any actual World Series.", "answer": "The Detroit Tigers won the World Series.\n\r\n[2]: Since there were seven games, this must be 0, 3, or 6 games. We know both teams scored an even number of runs in the whole series. This narrows it down from {0, 3, or 6} to 3. So each team had 3 even-run games, and 4 odd-run games.\n\r\n[3]: The only case in which two whole numbers may be multiplied together to produce a prime number is that one number is 1 and the other is prime. Since one clue mentions that both teams had some prime-number-run games, the statement is shown to be merely an obfuscated way of saying \"there were no games with exactly 1 run for either team.\"\n\r\n[1] and [4]: These clues become very useful when combined, for no number exists that is both a perfect square and a prime number. So for each team, these make up 6 of the 7 games, leaving only one game for each team in which neither a prime number nor a perfect square of runs was scored. Here is the breakdown of the numbers 0 to 12, aside from the eliminated numbers 1 and 5:\r\nPrime - 2,3,7,11 [4 games for each team]\r\nSquare - 0,4,9 [2 games each]\r\nNeither prime nor square - 6,8,10,12 [1 game each]\n\r\nSince all of the \"neither prime nor square\" numbers are even, this leaves 2 even and 4 odd games to make up the 6 \"prime or square\" games for each team. Since we know there was exactly one shutout, one team's square games were either {0,4} or {0,9}, and the other team's square games were either {4,4}, {4,9}, or {9,9}.\n\r\n[7]: It can be found that the Reds must have one of the following subsets: {3,6,0,9}, {3,3,6}, {2,2,7}, {2,7,7}, {3,6,2,7}, {2,7,0,9}. {2,7,0,9} is the only one that can be completed legally: {2,7,0,9,3,3,12}.\n\r\nWe now know the Tigers' square games are either {4,4}, {4,9}, or {9,9}. {4,4} is the only one that can be continued legally, which forces their 4 primes to be odd. So Detroit did not score less than 3 in any game, which means the Reds could have won a maximum of just three games: those in which they scored 7, 9, 12.", "category": "Logic", "date": "10/27/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Detroit Tigers played the Cincinnati Reds in the World Series (Major League Baseball). In this particular series (which went the full seven games), there was only one shutout, and no team scored more than 12 runs in any game. Following are some facts that apply to BOTH teams, individually, pertaining to the number of runs scored in each of the 7 games (no information is given about the order in which these games occured). For each team, there were:\n\r\n[1] 4 games with a prime number of runs.\r\n[2] A multiple of 3 games with an even number of runs.\r\n[3] No two games, the product of whose runs was a prime number.\r\n[4] 2 games with a perfect square of runs.\r\n[5] No game with exactly 5 runs.\n\r\nThe Tigers scored 30 runs in the entire series, and [6] scored 7 or 8 runs in at least one game. The Reds scored 36 runs, and [7] of all seven games, there are exactly two pairs of games, the sum of whose runs was exactly 9 (a game can be used in multiple pairs).\n\r\nBased on this information, which of these statements is accurate?\r\n1. The Detroit Tigers won the World Series.\r\n2. The Cincinnati Reds won the World Series.\r\n3. The World Series winner is uncertain.\n\r\nThe bracketed clue numbers [1]-[7] are used for reference in the answer explanation.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Detroit Tigers won the World Series.\n\r\n[2]: Since there were seven games, this must be 0, 3, or 6 games. We know both teams scored an even number of runs in the whole series. This narrows it down from {0, 3, or 6} to 3. So each team had 3 even-run games, and 4 odd-run games.\n\r\n[3]: The only case in which two whole numbers may be multiplied together to produce a prime number is that one number is 1 and the other is prime. Since one clue mentions that both teams had some prime-number-run games, the statement is shown to be merely an obfuscated way of saying \"there were no games with exactly 1 run for either team.\"\n\r\n[1] and [4]: These clues become very useful when combined, for no number exists that is both a perfect square and a prime number. So for each team, these make up 6 of the 7 games, leaving only one game for each team in which neither a prime number nor a perfect square of runs was scored. Here is the breakdown of the numbers 0 to 12, aside from the eliminated numbers 1 and 5:\r\nPrime - 2,3,7,11 [4 games for each team]\r\nSquare - 0,4,9 [2 games each]\r\nNeither prime nor square - 6,8,10,12 [1 game each]\n\r\nSince all of the \"neither prime nor square\" numbers are even, this leaves 2 even and 4 odd games to make up the 6 \"prime or square\" games for each team. Since we know there was exactly one shutout, one team's square games were either {0,4} or {0,9}, and the other team's square games were either {4,4}, {4,9}, or {9,9}.\n\r\n[7]: It can be found that the Reds must have one of the following subsets: {3,6,0,9}, {3,3,6}, {2,2,7}, {2,7,7}, {3,6,2,7}, {2,7,0,9}. {2,7,0,9} is the only one that can be completed legally: {2,7,0,9,3,3,12}.\n\r\nWe now know the Tigers' square games are either {4,4}, {4,9}, or {9,9}. {4,4} is the only one that can be continued legally, which forces their 4 primes to be odd. So Detroit did not score less than 3 in any game, which means the Reds could have won a maximum of just three games: those in which they scored 7, 9, 12.\n<|im_start|>answer\nThe Detroit Tigers won the World Series.\n\r\n[2]: Since there were seven games, this must be 0, 3, or 6 games. We know both teams scored an even number of runs in the whole series. This narrows it down from {0, 3, or 6} to 3. So each team had 3 even-run games, and 4 odd-run games.\n\r\n[3]: The only case in which two whole numbers may be multiplied together to produce a prime number is that one number is 1 and the other is prime. Since one clue mentions that both teams had some prime-number-run games, the statement is shown to be merely an obfuscated way of saying \"there were no games with exactly 1 run for either team.\"\n\r\n[1] and [4]: These clues become very useful when combined, for no number exists that is both a perfect square and a prime number. So for each team, these make up 6 of the 7 games, leaving only one game for each team in which neither a prime number nor a perfect square of runs was scored. Here is the breakdown of the numbers 0 to 12, aside from the eliminated numbers 1 and 5:\r\nPrime - 2,3,7,11 [4 games for each team]\r\nSquare - 0,4,9 [2 games each]\r\nNeither prime nor square - 6,8,10,12 [1 game each]\n\r\nSince all of the \"neither prime nor square\" numbers are even, this leaves 2 even and 4 odd games to make up the 6 \"prime or square\" games for each team. Since we know there was exactly one shutout, one team's square games were either {0,4} or {0,9}, and the other team's square games were either {4,4}, {4,9}, or {9,9}.\n\r\n[7]: It can be found that the Reds must have one of the following subsets: {3,6,0,9}, {3,3,6}, {2,2,7}, {2,7,7}, {3,6,2,7}, {2,7,0,9}. {2,7,0,9} is the only one that can be completed legally: {2,7,0,9,3,3,12}.\n\r\nWe now know the Tigers' square games are either {4,4}, {4,9}, or {9,9}. {4,4} is the only one that can be continued legally, which forces their 4 primes to be odd. So Detroit did not score less than 3 in any game, which means the Reds could have won a maximum of just three games: those in which they scored 7, 9, 12.\n<|im_end|>" }, { "id": "#22434", "title": "Averages Aren't So Easy", "fun": 2.34, "difficulty": 1.6300000000000001, "author": "Leviathan", "desc": "A man is biking on a 40 mile trip. He travels the first half of the trip at a speed of 15 miles per hour. If he wants his average speed to be 20 miles per hour, at what speed should he travel during the second half?", "hint": "No hint available.", "answer": "30 miles per hour.\n\r\nStep 1: If he wants an average speed of 20 miles per hour on a 40 mile trip, then he needs to travel for a total time of 2 hours.\n\r\nStep 2: Since he travels at a speed of 15 miles per hour during the first half of the trip, it takes him 80 minutes for the first half, so he has 40 minutes left to travel 20 miles.\n\r\nStep 3: Since he needs to travel 20 miles in 40, simply add one half of 40 (20), to make 60 (an hour), and do the same to the 20 miles he needs to travel to find out how many miles per hour he needs to travel.\n\r\nComplicated, eh?", "category": "Math", "date": "04/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is biking on a 40 mile trip. He travels the first half of the trip at a speed of 15 miles per hour. If he wants his average speed to be 20 miles per hour, at what speed should he travel during the second half?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n30 miles per hour.\n\r\nStep 1: If he wants an average speed of 20 miles per hour on a 40 mile trip, then he needs to travel for a total time of 2 hours.\n\r\nStep 2: Since he travels at a speed of 15 miles per hour during the first half of the trip, it takes him 80 minutes for the first half, so he has 40 minutes left to travel 20 miles.\n\r\nStep 3: Since he needs to travel 20 miles in 40, simply add one half of 40 (20), to make 60 (an hour), and do the same to the 20 miles he needs to travel to find out how many miles per hour he needs to travel.\n\r\nComplicated, eh?\n<|im_start|>answer\n30 miles per hour.\n\r\nStep 1: If he wants an average speed of 20 miles per hour on a 40 mile trip, then he needs to travel for a total time of 2 hours.\n\r\nStep 2: Since he travels at a speed of 15 miles per hour during the first half of the trip, it takes him 80 minutes for the first half, so he has 40 minutes left to travel 20 miles.\n\r\nStep 3: Since he needs to travel 20 miles in 40, simply add one half of 40 (20), to make 60 (an hour), and do the same to the 20 miles he needs to travel to find out how many miles per hour he needs to travel.\n\r\nComplicated, eh?\n<|im_end|>" }, { "id": "#1401", "title": "Empty the Reservoir", "fun": 2.34, "difficulty": 1.94, "author": "psychodude57", "desc": "A large fresh water reservoir has two types of drainage systems, small pipes and large pipes. 6 large pipes, on their own, can drain the reservoir in 12 hours. 3 large pipes and 9 small pipes, at the same time, can drain the reservoir in 8 hours. How long will 5 small pipes, on their own, take to drain the reservoir?", "hint": "The exact sizes of the pipes and reservoir do not matter.", "answer": "21 hours and 36 minutes.", "category": "Math", "date": "11/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA large fresh water reservoir has two types of drainage systems, small pipes and large pipes. 6 large pipes, on their own, can drain the reservoir in 12 hours. 3 large pipes and 9 small pipes, at the same time, can drain the reservoir in 8 hours. How long will 5 small pipes, on their own, take to drain the reservoir?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21 hours and 36 minutes.\n<|im_start|>answer\n21 hours and 36 minutes.\n<|im_end|>" }, { "id": "#29110", "title": "The Concert", "fun": 2.34, "difficulty": 0.93, "author": "thompson1", "desc": "There were 3 boys that needed some money to go to a concert. They decided to get different jobs that paid different amounts of money. Figure out each boy's first name, last name, what job they got, and how much money they got.\n\r\nFirst names - John, Jacob, and Jordan\r\nLast names - Nathanson, Jones, and Smith\r\nJobs - Raking leaves, Mowing the Lawn, and Doing the Laundry\r\nMoney Earned per Week - $40, $25, and $10\n\r\n1. The boys are: John, the one who does the laundry, and the one who gets $40 per week.\n\r\n2. Jacob Nathanson doesn't rake leaves or get $40 per week.\n\r\n3. John, who gets $25 per week, does not have the last name of Jones.\n\r\n4. Raking leaves doesn't get you $40 per week.", "hint": "No hint available.", "answer": "John Smith makes $25 per week for raking leaves.\r\nJacob Nathanson makes $10 per week for doing the laundry.\r\nJordan Jones makes $40 per week for mowing the lawn.", "category": "Logic-Grid", "date": "03/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 3 boys that needed some money to go to a concert. They decided to get different jobs that paid different amounts of money. Figure out each boy's first name, last name, what job they got, and how much money they got.\n\r\nFirst names - John, Jacob, and Jordan\r\nLast names - Nathanson, Jones, and Smith\r\nJobs - Raking leaves, Mowing the Lawn, and Doing the Laundry\r\nMoney Earned per Week - $40, $25, and $10\n\r\n1. The boys are: John, the one who does the laundry, and the one who gets $40 per week.\n\r\n2. Jacob Nathanson doesn't rake leaves or get $40 per week.\n\r\n3. John, who gets $25 per week, does not have the last name of Jones.\n\r\n4. Raking leaves doesn't get you $40 per week.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn Smith makes $25 per week for raking leaves.\r\nJacob Nathanson makes $10 per week for doing the laundry.\r\nJordan Jones makes $40 per week for mowing the lawn.\n<|im_start|>answer\nJohn Smith makes $25 per week for raking leaves.\r\nJacob Nathanson makes $10 per week for doing the laundry.\r\nJordan Jones makes $40 per week for mowing the lawn.\n<|im_end|>" }, { "id": "#4757", "title": "Dream World", "fun": 2.34, "difficulty": 1.47, "author": "mad-ade", "desc": "Mad Ade is dreaming of a strange world in which the colours of things have changed from what we consider normal. Assume the following changes: \n\r\nSnow is now red.\r\nGrass is now black.\r\nThe sky is now brown.\r\nBlood is now white.\r\nSoot is now green.\n\r\nIn such a world, what is the colour of wood?", "hint": "No hint available.", "answer": "Wood is now blue. The puzzle consists of pairs that exchange colours. \r\nSince the sky is now brown, brown things become blue.", "category": "Logic", "date": "06/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is dreaming of a strange world in which the colours of things have changed from what we consider normal. Assume the following changes: \n\r\nSnow is now red.\r\nGrass is now black.\r\nThe sky is now brown.\r\nBlood is now white.\r\nSoot is now green.\n\r\nIn such a world, what is the colour of wood?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWood is now blue. The puzzle consists of pairs that exchange colours. \r\nSince the sky is now brown, brown things become blue.\n<|im_start|>answer\nWood is now blue. The puzzle consists of pairs that exchange colours. \r\nSince the sky is now brown, brown things become blue.\n<|im_end|>" }, { "id": "#10942", "title": "Runaway Train", "fun": 2.34, "difficulty": 1.98, "author": "codammanus", "desc": "A train moving at a speed of less than 1 mile per hour passes 200 people in less than 5 minutes. When the train finally stops, it doesn't pick up any passengers. The person that stops the train is not even on the train. In fact, no one is on the train. Most likely, where is this train?", "hint": "No hint available.", "answer": "This train is most likely at a wedding. (The train of the bride's gown)", "category": "Logic", "date": "03/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA train moving at a speed of less than 1 mile per hour passes 200 people in less than 5 minutes. When the train finally stops, it doesn't pick up any passengers. The person that stops the train is not even on the train. In fact, no one is on the train. Most likely, where is this train?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis train is most likely at a wedding. (The train of the bride's gown)\n<|im_start|>answer\nThis train is most likely at a wedding. (The train of the bride's gown)\n<|im_end|>" }, { "id": "#34564", "title": "Park It Ranger", "fun": 2.34, "difficulty": 2.7600000000000002, "author": "stil", "desc": "Ranger Cadet Bu Star has just been given the task of moving the five cases of Park Pop soda at the Weiss Pavilion to the Wirth Pavilion, which is 5 miles away. For transportation, Bu must use a MoJoPed, a moped which runs on Park Pop. It can carry, at most, its rider and 25 bottles of soda, i.e., one case in its cargo carrier and one bottle in its fuel tank. It gets one mile to the bottle and is currently empty; it will only move under Pop power. How many unopened bottles can Bu deliver to the second pavilion?\r\nComments to triflers:\r\nThe bottles and cases are hi-tech, so there are no concerns about theft or littering. They can stay parked or be discarded anywhere. Yes, the constant rate of fuel use is unreal, and yes, of course, I am asking for the maximum number of bottles!", "hint": "There are hints in the comments to triflers and in the title.", "answer": "80\r\nTo achieve this surprising result, Bu must first take the five cases, one at a time, and park them at a point along the route 2 5/18 miles from the Weiss Pavilion. This takes 9 trips of 2 5/18 miles (5 advancing trips interspersed with 4 return trips) for a total of 20.5 miles traveled (9 * 2 5/18 = 20.5) and 20.5 bottles of soda used. Cadet Star now has 99.5 bottles of soda. (5 * 24 - 20.5 = 120 - 20.5 = 99.5) He puts 3.5 of these aside and redistributes the other 96 to completely fill four cases. With one less case to move, Bu will now make 2 fewer trips. The 3.5 bottles set aside are used to move the four cases the next 1/2 mile toward the Wirth Pavilion. After this, the Wirth Pavilion is just 2 2/9 miles away ( 5 - 2 5/18 - 9/18 = 2 4/18 ). Next, he travels 15 5/9 miles (7 * 2 2/9) using 15 5/9 bottles of soda to complete his trip. The ranger cadet delivers 80 bottles to the pavilion and has 4/9 of a Park Pop to spare. (96 - 15 5/9 = 80 4/9)", "category": "Math", "date": "12/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRanger Cadet Bu Star has just been given the task of moving the five cases of Park Pop soda at the Weiss Pavilion to the Wirth Pavilion, which is 5 miles away. For transportation, Bu must use a MoJoPed, a moped which runs on Park Pop. It can carry, at most, its rider and 25 bottles of soda, i.e., one case in its cargo carrier and one bottle in its fuel tank. It gets one mile to the bottle and is currently empty; it will only move under Pop power. How many unopened bottles can Bu deliver to the second pavilion?\r\nComments to triflers:\r\nThe bottles and cases are hi-tech, so there are no concerns about theft or littering. They can stay parked or be discarded anywhere. Yes, the constant rate of fuel use is unreal, and yes, of course, I am asking for the maximum number of bottles!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n80\r\nTo achieve this surprising result, Bu must first take the five cases, one at a time, and park them at a point along the route 2 5/18 miles from the Weiss Pavilion. This takes 9 trips of 2 5/18 miles (5 advancing trips interspersed with 4 return trips) for a total of 20.5 miles traveled (9 * 2 5/18 = 20.5) and 20.5 bottles of soda used. Cadet Star now has 99.5 bottles of soda. (5 * 24 - 20.5 = 120 - 20.5 = 99.5) He puts 3.5 of these aside and redistributes the other 96 to completely fill four cases. With one less case to move, Bu will now make 2 fewer trips. The 3.5 bottles set aside are used to move the four cases the next 1/2 mile toward the Wirth Pavilion. After this, the Wirth Pavilion is just 2 2/9 miles away ( 5 - 2 5/18 - 9/18 = 2 4/18 ). Next, he travels 15 5/9 miles (7 * 2 2/9) using 15 5/9 bottles of soda to complete his trip. The ranger cadet delivers 80 bottles to the pavilion and has 4/9 of a Park Pop to spare. (96 - 15 5/9 = 80 4/9)\n<|im_start|>answer\n80\r\nTo achieve this surprising result, Bu must first take the five cases, one at a time, and park them at a point along the route 2 5/18 miles from the Weiss Pavilion. This takes 9 trips of 2 5/18 miles (5 advancing trips interspersed with 4 return trips) for a total of 20.5 miles traveled (9 * 2 5/18 = 20.5) and 20.5 bottles of soda used. Cadet Star now has 99.5 bottles of soda. (5 * 24 - 20.5 = 120 - 20.5 = 99.5) He puts 3.5 of these aside and redistributes the other 96 to completely fill four cases. With one less case to move, Bu will now make 2 fewer trips. The 3.5 bottles set aside are used to move the four cases the next 1/2 mile toward the Wirth Pavilion. After this, the Wirth Pavilion is just 2 2/9 miles away ( 5 - 2 5/18 - 9/18 = 2 4/18 ). Next, he travels 15 5/9 miles (7 * 2 2/9) using 15 5/9 bottles of soda to complete his trip. The ranger cadet delivers 80 bottles to the pavilion and has 4/9 of a Park Pop to spare. (96 - 15 5/9 = 80 4/9)\n<|im_end|>" }, { "id": "#29066", "title": "Number 9", "fun": 2.34, "difficulty": 1.84, "author": "Victor", "desc": "I am compiling a world almanac, and it now contains lots of pages. I know that it takes 121 digits to print the page numbers in sequence. How many numbered pages does the book have, and how many times does the number 9 appear?", "hint": "No hint available.", "answer": "There are 65 pages and the number 9 appears 6 times.\n\r\n9+56*2=121\r\n9 appears in 9, 19, 29, 39, 49 and 59.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am compiling a world almanac, and it now contains lots of pages. I know that it takes 121 digits to print the page numbers in sequence. How many numbered pages does the book have, and how many times does the number 9 appear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 65 pages and the number 9 appears 6 times.\n\r\n9+56*2=121\r\n9 appears in 9, 19, 29, 39, 49 and 59.\n<|im_start|>answer\nThere are 65 pages and the number 9 appears 6 times.\n\r\n9+56*2=121\r\n9 appears in 9, 19, 29, 39, 49 and 59.\n<|im_end|>" }, { "id": "#24741", "title": "Kristie's Birthday Party", "fun": 2.34, "difficulty": 0.73, "author": "brain_dead", "desc": "Kristie is throwing a birthday party for her 13th birthday. She has invited five people: Nolan, Trina, Sarah, Lisa, and Cody. Each guest had to bring some kind of drink, food, and a present. Who brought what?\n\r\nNote: If a person doesn't like something then they didn't bring it.\n\r\nDRINKS: Pepsi, fruit punch, Coke, root beer, and Dr Pepper\n\r\nFOODS: ham, cake, shrimp, fish, and potatoes\n\r\nPRESENTS: CD, toothbrush, DVD, basketball, and a football\n\r\n1. Sarah was a vegetarian and won't even touch any kind of meat, including seafood.\r\n2. Trina brought ham but not fruit punch.\r\n3. Lisa believed everyone should have clean teeth, so she brought the toothbrush.\r\n4. Nolan brought the basketball.\r\n5. Sarah was obsessed with music but didn't care for DVDs at all.\r\n6. Sarah hates any kind of pop.\r\n7. Lisa brought Coke but not fish, although she did bring a type of seafood.\r\n8. Cody likes football and knew Kristie did too, so that was his gift.\r\n9. Nolan brought potatoes.\r\n10. Trina brought the soda with two o's in the name of it.\r\n11. Cody does not like Dr Pepper at all.", "hint": "No hint available.", "answer": "NOLAN, Dr Pepper, potatoes, basketball\r\nTRINA, root beer, ham, DVD\r\nSARAH, fruit punch, cake, CD\r\nLISA, Coke, shrimp, toothbrush\r\nCODY, Pepsi, fish, football", "category": "Logic-Grid", "date": "07/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKristie is throwing a birthday party for her 13th birthday. She has invited five people: Nolan, Trina, Sarah, Lisa, and Cody. Each guest had to bring some kind of drink, food, and a present. Who brought what?\n\r\nNote: If a person doesn't like something then they didn't bring it.\n\r\nDRINKS: Pepsi, fruit punch, Coke, root beer, and Dr Pepper\n\r\nFOODS: ham, cake, shrimp, fish, and potatoes\n\r\nPRESENTS: CD, toothbrush, DVD, basketball, and a football\n\r\n1. Sarah was a vegetarian and won't even touch any kind of meat, including seafood.\r\n2. Trina brought ham but not fruit punch.\r\n3. Lisa believed everyone should have clean teeth, so she brought the toothbrush.\r\n4. Nolan brought the basketball.\r\n5. Sarah was obsessed with music but didn't care for DVDs at all.\r\n6. Sarah hates any kind of pop.\r\n7. Lisa brought Coke but not fish, although she did bring a type of seafood.\r\n8. Cody likes football and knew Kristie did too, so that was his gift.\r\n9. Nolan brought potatoes.\r\n10. Trina brought the soda with two o's in the name of it.\r\n11. Cody does not like Dr Pepper at all.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNOLAN, Dr Pepper, potatoes, basketball\r\nTRINA, root beer, ham, DVD\r\nSARAH, fruit punch, cake, CD\r\nLISA, Coke, shrimp, toothbrush\r\nCODY, Pepsi, fish, football\n<|im_start|>answer\nNOLAN, Dr Pepper, potatoes, basketball\r\nTRINA, root beer, ham, DVD\r\nSARAH, fruit punch, cake, CD\r\nLISA, Coke, shrimp, toothbrush\r\nCODY, Pepsi, fish, football\n<|im_end|>" }, { "id": "#23064", "title": "Can You Guess the Number", "fun": 2.34, "difficulty": 2.13, "author": "phrebh", "desc": "Fred and Bob are sitting around, shooting the mathematical breeze, when they decide to play a game of \"Guess the Number\".\n\r\nFred tells Bob that he is thinking of a number between 13 and 1313. \n\r\nBob asks Fred if the number is below 500. Fred says, \"Yes.\"\n\r\nBob asks Fred if the number is a perfect square. Fred says, \"Yes.\"\n\r\nBob asks Fred if the number is a perfect cube. Fred says, \"Yes.\"\n\r\nFred then tells Bob that one of his answers was incorrect and the number he is thinking of starts with an odd digit greater than 3.\n\r\nWhat is the number that Fred is thinking of?", "hint": "No hint available.", "answer": "729\n\r\nTo work it out, first separate the numbers at the 500 hundred point and find all of the perfect squares and perfect cubes.\n\r\n13-499:\r\nPerfect squares - 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484\r\nPerfect cubes - 27, 64, 125, 216, 343\r\nBoth - 64\n\r\n500-1313:\r\nPerfect squares - 529, 576, 625, 676, 729, 784, 841, 900, 961, 1024, 1089, 1156, 1225, 1296\r\nPerfect cubes - 512, 729, 1000\r\nBoth - 729\n\r\nIn the lists of squares and cubes less than 500, there are no numbers that begin with an odd number greater than 3. Therefore, we can conclude that the first answer Fred gave was the incorrect one, and that 729 must be the answer.", "category": "Math", "date": "05/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred and Bob are sitting around, shooting the mathematical breeze, when they decide to play a game of \"Guess the Number\".\n\r\nFred tells Bob that he is thinking of a number between 13 and 1313. \n\r\nBob asks Fred if the number is below 500. Fred says, \"Yes.\"\n\r\nBob asks Fred if the number is a perfect square. Fred says, \"Yes.\"\n\r\nBob asks Fred if the number is a perfect cube. Fred says, \"Yes.\"\n\r\nFred then tells Bob that one of his answers was incorrect and the number he is thinking of starts with an odd digit greater than 3.\n\r\nWhat is the number that Fred is thinking of?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n729\n\r\nTo work it out, first separate the numbers at the 500 hundred point and find all of the perfect squares and perfect cubes.\n\r\n13-499:\r\nPerfect squares - 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484\r\nPerfect cubes - 27, 64, 125, 216, 343\r\nBoth - 64\n\r\n500-1313:\r\nPerfect squares - 529, 576, 625, 676, 729, 784, 841, 900, 961, 1024, 1089, 1156, 1225, 1296\r\nPerfect cubes - 512, 729, 1000\r\nBoth - 729\n\r\nIn the lists of squares and cubes less than 500, there are no numbers that begin with an odd number greater than 3. Therefore, we can conclude that the first answer Fred gave was the incorrect one, and that 729 must be the answer.\n<|im_start|>answer\n729\n\r\nTo work it out, first separate the numbers at the 500 hundred point and find all of the perfect squares and perfect cubes.\n\r\n13-499:\r\nPerfect squares - 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484\r\nPerfect cubes - 27, 64, 125, 216, 343\r\nBoth - 64\n\r\n500-1313:\r\nPerfect squares - 529, 576, 625, 676, 729, 784, 841, 900, 961, 1024, 1089, 1156, 1225, 1296\r\nPerfect cubes - 512, 729, 1000\r\nBoth - 729\n\r\nIn the lists of squares and cubes less than 500, there are no numbers that begin with an odd number greater than 3. Therefore, we can conclude that the first answer Fred gave was the incorrect one, and that 729 must be the answer.\n<|im_end|>" }, { "id": "#9547", "title": "On The Stand", "fun": 2.34, "difficulty": 1.85, "author": "Palsha", "desc": "A suspect was questioned in a case he was being accused of. He was asked by the court if his statements were true, and he replied...\n\r\n\"I guarantee that it is untenable to deny the opposite of the veracity of my affirmations.\"\n\r\nQ)Is the suspect telling the court the truth or is he lying?", "hint": "No hint available.", "answer": "A)He's lying\n\r\n\"To deny the opposite of the veracity\"=to deny falsehood=to affirm the truth\n\r\n\"I guarantee that it is untenable\"=it cannot be maintained", "category": "Logic", "date": "01/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA suspect was questioned in a case he was being accused of. He was asked by the court if his statements were true, and he replied...\n\r\n\"I guarantee that it is untenable to deny the opposite of the veracity of my affirmations.\"\n\r\nQ)Is the suspect telling the court the truth or is he lying?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA)He's lying\n\r\n\"To deny the opposite of the veracity\"=to deny falsehood=to affirm the truth\n\r\n\"I guarantee that it is untenable\"=it cannot be maintained\n<|im_start|>answer\nA)He's lying\n\r\n\"To deny the opposite of the veracity\"=to deny falsehood=to affirm the truth\n\r\n\"I guarantee that it is untenable\"=it cannot be maintained\n<|im_end|>" }, { "id": "#38609", "title": "Stamps Please!", "fun": 2.34, "difficulty": 1.54, "author": "snowmonster", "desc": "James handed the postal person a one-dollar bill and said, \"I'll have some 2-cent stamps, 10 times as many 1-cent stamps, and the balance in 5-cent stamps, please!\" How many of each was he given?", "hint": "No hint available.", "answer": "5 2-cent stamps, 50 1-cent stamps and 8 5-cent stamps!", "category": "Logic", "date": "10/04/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJames handed the postal person a one-dollar bill and said, \"I'll have some 2-cent stamps, 10 times as many 1-cent stamps, and the balance in 5-cent stamps, please!\" How many of each was he given?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 2-cent stamps, 50 1-cent stamps and 8 5-cent stamps!\n<|im_start|>answer\n5 2-cent stamps, 50 1-cent stamps and 8 5-cent stamps!\n<|im_end|>" }, { "id": "#5629", "title": "Planes Apart", "fun": 2.34, "difficulty": 2.16, "author": "mad-ade", "desc": "Two planes fly once around the world together.\r\nThey both fly at a constant distance above the\r\nsurface of the Earth, one above the other.\r\nOn completion, one of the planes has travelled \r\ntwo kilometres further than the other.\r\n(Assume the Earth is a perfect sphere.)\n\r\nHow far apart (in metres) were the two planes?", "hint": "No hint available.", "answer": "1000/pi [or 318.3 metres]", "category": "Math", "date": "07/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo planes fly once around the world together.\r\nThey both fly at a constant distance above the\r\nsurface of the Earth, one above the other.\r\nOn completion, one of the planes has travelled \r\ntwo kilometres further than the other.\r\n(Assume the Earth is a perfect sphere.)\n\r\nHow far apart (in metres) were the two planes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1000/pi [or 318.3 metres]\n<|im_start|>answer\n1000/pi [or 318.3 metres]\n<|im_end|>" }, { "id": "#12644", "title": "Volleyball Tournament", "fun": 2.34, "difficulty": 2.04, "author": "ejasami", "desc": "During the recent volleyball tournament, 5 schools were competing. Each school played each other once (single round robin format), with 4 points for a win, 2 points for a draw, 0 points if they lost. Here are the final points after all of the matches: \n\r\nUC Davis--12 \r\nSonoma St--10 \r\nSac St--8 \r\nChico St--4 \n\r\nCal Poly ==?== \n\r\nHow many points did Cal Poly end the season with?", "hint": "No hint available.", "answer": "6 points; in a single round robin format five teams will play a total of 10 matches. With ten matches 40 points were possible. The other team points add up to 34; Cal Poly must have 6 points to take the total to 40", "category": "Math", "date": "05/24/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring the recent volleyball tournament, 5 schools were competing. Each school played each other once (single round robin format), with 4 points for a win, 2 points for a draw, 0 points if they lost. Here are the final points after all of the matches: \n\r\nUC Davis--12 \r\nSonoma St--10 \r\nSac St--8 \r\nChico St--4 \n\r\nCal Poly ==?== \n\r\nHow many points did Cal Poly end the season with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6 points; in a single round robin format five teams will play a total of 10 matches. With ten matches 40 points were possible. The other team points add up to 34; Cal Poly must have 6 points to take the total to 40\n<|im_start|>answer\n6 points; in a single round robin format five teams will play a total of 10 matches. With ten matches 40 points were possible. The other team points add up to 34; Cal Poly must have 6 points to take the total to 40\n<|im_end|>" }, { "id": "#245", "title": "Area of a Triangle", "fun": 2.34, "difficulty": 1.6, "author": "cruiser", "desc": "What is the area of a triangle with sides 1, 3, and 4 inches?", "hint": "You don`t need a formula to figure this out.", "answer": "It`s impossible to have a triangle with those sides. The sum of two of the sides is equal to the third side. The result would be a straight line, and the area would be zero.", "category": "Math", "date": "02/04/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the area of a triangle with sides 1, 3, and 4 inches?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt`s impossible to have a triangle with those sides. The sum of two of the sides is equal to the third side. The result would be a straight line, and the area would be zero.\n<|im_start|>answer\nIt`s impossible to have a triangle with those sides. The sum of two of the sides is equal to the third side. The result would be a straight line, and the area would be zero.\n<|im_end|>" }, { "id": "#16331", "title": "Perfect Pyramid", "fun": 2.34, "difficulty": 2.48, "author": "cnmne", "desc": "Arrange the numbers 1 through 10 in the shape of a pyramid (1 number at the peak, 2 numbers in the next row down, 3 in the next row, and 4 in the bottom row). The numbers must be arranged such that each number is equal to the difference of the two numbers directly below it. For example, if 5 and 1 are next to each other in the same row, then 4 must be placed on top of them.\n\r\nTo demonstrate, a three-level pyramid using the numbers 1 through 6 could be arranged as follows:\r\ntop row: 2\r\nsecond row: 5 3\r\nbottom row: 6 1 4", "hint": "No hint available.", "answer": "top row: 3\r\nsecond row: 7 4\r\nthird row: 2 9 5\r\nbottom row: 8 10 1 6", "category": "Math", "date": "01/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numbers 1 through 10 in the shape of a pyramid (1 number at the peak, 2 numbers in the next row down, 3 in the next row, and 4 in the bottom row). The numbers must be arranged such that each number is equal to the difference of the two numbers directly below it. For example, if 5 and 1 are next to each other in the same row, then 4 must be placed on top of them.\n\r\nTo demonstrate, a three-level pyramid using the numbers 1 through 6 could be arranged as follows:\r\ntop row: 2\r\nsecond row: 5 3\r\nbottom row: 6 1 4\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\ntop row: 3\r\nsecond row: 7 4\r\nthird row: 2 9 5\r\nbottom row: 8 10 1 6\n<|im_start|>answer\ntop row: 3\r\nsecond row: 7 4\r\nthird row: 2 9 5\r\nbottom row: 8 10 1 6\n<|im_end|>" }, { "id": "#1296", "title": "Columns", "fun": 2.34, "difficulty": 1.82, "author": "Rado", "desc": "There are two columns, both 100m high (both heading straight up from the ground). A rope is tied to the tops of both columns. The rope is hanging freely and its length is 160m. The lowest point of the rope is exactly 20m from the ground. What is the distance between the two columns?", "hint": "Draw a picture... and remember no difficult math calculation is needed.", "answer": "The distance is zero. The lowest point of the rope divides the rope in half, i.e. 80m each. If you add 80m plus the distance from the ground which is 20m, you get 100m, so the rope must be going straight down...", "category": "Math", "date": "11/05/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two columns, both 100m high (both heading straight up from the ground). A rope is tied to the tops of both columns. The rope is hanging freely and its length is 160m. The lowest point of the rope is exactly 20m from the ground. What is the distance between the two columns?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe distance is zero. The lowest point of the rope divides the rope in half, i.e. 80m each. If you add 80m plus the distance from the ground which is 20m, you get 100m, so the rope must be going straight down...\n<|im_start|>answer\nThe distance is zero. The lowest point of the rope divides the rope in half, i.e. 80m each. If you add 80m plus the distance from the ground which is 20m, you get 100m, so the rope must be going straight down...\n<|im_end|>" }, { "id": "#41846", "title": "Hamburger Cook-Off", "fun": 2.34, "difficulty": 1.55, "author": "brain23", "desc": "In the hamburger cook-off, the finals had just begun. However, one person in the contest had a store-bought hamburger. If the one who has the store-bought hamburger is lying and the innocent people are telling the truth, who is lying?\n\r\nJohn: It wasn't Steven.\r\nNick: It wasn't Greg.\r\nSteven: It wasn't Nick.\r\nKevin: It was John.\r\nGreg: It was Kevin.", "hint": "No hint available.", "answer": "Kevin had the store-bought hamburger. The way to determine this is by looking first at Steven's statement. If \"it wasn't Nick\" is false, Steven must be lying, which means he's guilty, and Nick is also guilty. Since only one person is guilty, Nick and Steven made their hamburgers and are innocent. Because of this, John is also innocent. Kevin says it was John, which is false, since John has been cleared. Greg must also be telling the truth and is innocent.", "category": "Logic", "date": "05/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the hamburger cook-off, the finals had just begun. However, one person in the contest had a store-bought hamburger. If the one who has the store-bought hamburger is lying and the innocent people are telling the truth, who is lying?\n\r\nJohn: It wasn't Steven.\r\nNick: It wasn't Greg.\r\nSteven: It wasn't Nick.\r\nKevin: It was John.\r\nGreg: It was Kevin.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKevin had the store-bought hamburger. The way to determine this is by looking first at Steven's statement. If \"it wasn't Nick\" is false, Steven must be lying, which means he's guilty, and Nick is also guilty. Since only one person is guilty, Nick and Steven made their hamburgers and are innocent. Because of this, John is also innocent. Kevin says it was John, which is false, since John has been cleared. Greg must also be telling the truth and is innocent.\n<|im_start|>answer\nKevin had the store-bought hamburger. The way to determine this is by looking first at Steven's statement. If \"it wasn't Nick\" is false, Steven must be lying, which means he's guilty, and Nick is also guilty. Since only one person is guilty, Nick and Steven made their hamburgers and are innocent. Because of this, John is also innocent. Kevin says it was John, which is false, since John has been cleared. Greg must also be telling the truth and is innocent.\n<|im_end|>" }, { "id": "#41685", "title": "Two Attackers", "fun": 2.34, "difficulty": 1.25, "author": "Carlos16", "desc": "Four people are found in an alley after reported fighting. Two people are victims, while the other two are the attackers. The attackers are lying and the victims are telling the truth. Based on that information, who were the two attackers?\n\r\nTJ: Drake beat me up.\r\nJake: I saw RJ getting attacked.\r\nDrake: TJ beat me up.\r\nRJ: I saw Jake getting attacked.", "hint": "No hint available.", "answer": "Since TJ and Drake are accusing each other, then one or both of them is an attacker. If Jake was an attacker, then he's lying that RJ was attacked, which means RJ is also an attacker. That's impossible since there would be more than two attackers. Jake must be telling the truth. Since Jake is truthful, then RJ is also truthful and innocent, which only leaves TJ and Drake as attackers.\n\r\nAnswer: TJ and Drake", "category": "Logic", "date": "04/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people are found in an alley after reported fighting. Two people are victims, while the other two are the attackers. The attackers are lying and the victims are telling the truth. Based on that information, who were the two attackers?\n\r\nTJ: Drake beat me up.\r\nJake: I saw RJ getting attacked.\r\nDrake: TJ beat me up.\r\nRJ: I saw Jake getting attacked.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince TJ and Drake are accusing each other, then one or both of them is an attacker. If Jake was an attacker, then he's lying that RJ was attacked, which means RJ is also an attacker. That's impossible since there would be more than two attackers. Jake must be telling the truth. Since Jake is truthful, then RJ is also truthful and innocent, which only leaves TJ and Drake as attackers.\n\r\nAnswer: TJ and Drake\n<|im_start|>answer\nSince TJ and Drake are accusing each other, then one or both of them is an attacker. If Jake was an attacker, then he's lying that RJ was attacked, which means RJ is also an attacker. That's impossible since there would be more than two attackers. Jake must be telling the truth. Since Jake is truthful, then RJ is also truthful and innocent, which only leaves TJ and Drake as attackers.\n\r\nAnswer: TJ and Drake\n<|im_end|>" }, { "id": "#11695", "title": "Alternate Sports Titles", "fun": 2.34, "difficulty": 1.03, "author": "od-1", "desc": "I often tease my buddies who are sports freaks. I do so by referring to their favorite sports in unusual ways.\n\r\nGrown men acting like children running on water covered concrete with plastic and steel tied to their feet, chasing after a piece of vulcanized rubber with twigs.\n\r\nWhat sport is this?", "hint": "No hint available.", "answer": "Ice Hockey.", "category": "Logic", "date": "04/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI often tease my buddies who are sports freaks. I do so by referring to their favorite sports in unusual ways.\n\r\nGrown men acting like children running on water covered concrete with plastic and steel tied to their feet, chasing after a piece of vulcanized rubber with twigs.\n\r\nWhat sport is this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIce Hockey.\n<|im_start|>answer\nIce Hockey.\n<|im_end|>" }, { "id": "#28822", "title": "Opposites 11", "fun": 2.34, "difficulty": 2.0, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n% stands for L, K, G, A, or T\r\n^ stands for M, C, Y, I, or R\r\n= stands for G, E, B, O, or K\r\n& stands for H, W, J, E, or R\r\n$ stands for O, H, F, N, or P\n\r\nThe five letter code word, &^=$%, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Right and Wrong.", "category": "Logic", "date": "02/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n% stands for L, K, G, A, or T\r\n^ stands for M, C, Y, I, or R\r\n= stands for G, E, B, O, or K\r\n& stands for H, W, J, E, or R\r\n$ stands for O, H, F, N, or P\n\r\nThe five letter code word, &^=$%, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRight and Wrong.\n<|im_start|>answer\nRight and Wrong.\n<|im_end|>" }, { "id": "#29357", "title": "Which is More?", "fun": 2.34, "difficulty": 1.66, "author": "lips", "desc": "Are there more square inches in a piece of carpet 15 yards by 5 yards or feet in a 20 mile walk?", "hint": "No hint available.", "answer": "Feet in a 20 mile walk.\n\r\nThere are 105,600 feet in a 20 mile walk, but only 97,200 square inches in a piece of carpet 15 yards by 5 yards.", "category": "Math", "date": "03/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAre there more square inches in a piece of carpet 15 yards by 5 yards or feet in a 20 mile walk?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFeet in a 20 mile walk.\n\r\nThere are 105,600 feet in a 20 mile walk, but only 97,200 square inches in a piece of carpet 15 yards by 5 yards.\n<|im_start|>answer\nFeet in a 20 mile walk.\n\r\nThere are 105,600 feet in a 20 mile walk, but only 97,200 square inches in a piece of carpet 15 yards by 5 yards.\n<|im_end|>" }, { "id": "#44477", "title": "Musical Statues", "fun": 2.34, "difficulty": 1.17, "author": "whsprec", "desc": "A music shop sells statues of different composers: Mozart, Bach, Chopin, Strauss, and Beethoven. The statues cost 5 dollars, 10 dollars, 15 dollars, 20 dollars, or 25 dollars. The base of each statue is red, blue, green, gray, or yellow. What color is each statue and how much does it cost?\n\r\n1) The Mozart statue is worth more than the yellow one, which cost more than the Bach.\r\n2) The Chopin statue cost twice as much as the green one.\r\n3) The blue statue cost less than the Strauss, but more than the 15 dollar red one.\r\n4) The Mozart statue does not cost 20 dollars.", "hint": "No hint available.", "answer": "The Bach statue is green and costs 5 dollars.\r\nThe Chopin statue is yellow and costs 10 dollars.\r\nThe Mozart statue is red and costs 15 dollars.\r\nThe Beethoven statue is blue and costs 20 dollars.\r\nThe Strauss statue is gray and costs 25 dollars.", "category": "Logic-Grid", "date": "05/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA music shop sells statues of different composers: Mozart, Bach, Chopin, Strauss, and Beethoven. The statues cost 5 dollars, 10 dollars, 15 dollars, 20 dollars, or 25 dollars. The base of each statue is red, blue, green, gray, or yellow. What color is each statue and how much does it cost?\n\r\n1) The Mozart statue is worth more than the yellow one, which cost more than the Bach.\r\n2) The Chopin statue cost twice as much as the green one.\r\n3) The blue statue cost less than the Strauss, but more than the 15 dollar red one.\r\n4) The Mozart statue does not cost 20 dollars.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Bach statue is green and costs 5 dollars.\r\nThe Chopin statue is yellow and costs 10 dollars.\r\nThe Mozart statue is red and costs 15 dollars.\r\nThe Beethoven statue is blue and costs 20 dollars.\r\nThe Strauss statue is gray and costs 25 dollars.\n<|im_start|>answer\nThe Bach statue is green and costs 5 dollars.\r\nThe Chopin statue is yellow and costs 10 dollars.\r\nThe Mozart statue is red and costs 15 dollars.\r\nThe Beethoven statue is blue and costs 20 dollars.\r\nThe Strauss statue is gray and costs 25 dollars.\n<|im_end|>" }, { "id": "#2170", "title": "Electrician and Plumber", "fun": 2.33, "difficulty": 1.1, "author": "Cascas", "desc": "There was an electrician and a plumber waiting in line for the movies. One of them was the father of the other one's son. How could this be?", "hint": "No hint available.", "answer": "They were husband and wife.", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was an electrician and a plumber waiting in line for the movies. One of them was the father of the other one's son. How could this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey were husband and wife.\n<|im_start|>answer\nThey were husband and wife.\n<|im_end|>" }, { "id": "#4692", "title": "Ruined Night", "fun": 2.33, "difficulty": 2.12, "author": "mad-ade", "desc": "A tourist in London took a ride in Mad Ade's taxi cab. When he reached his destination, the tourist paid Mad Ade the fare, but did not include a tip. At this Mad Ade was displeased and said something to the tourist that ruined his whole evening. The two men were strangers and had never met previously. What did Mad Ade say?", "hint": "No hint available.", "answer": "The tourist was going to a performance of the famous Agatha Christie play The Mousetrap. Mad Ade dropped him outside the theater. When the tourist didn't give a tip, Mad Ade revealed how the play ended, thus spoiling the tourist's night.", "category": "Logic", "date": "06/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA tourist in London took a ride in Mad Ade's taxi cab. When he reached his destination, the tourist paid Mad Ade the fare, but did not include a tip. At this Mad Ade was displeased and said something to the tourist that ruined his whole evening. The two men were strangers and had never met previously. What did Mad Ade say?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe tourist was going to a performance of the famous Agatha Christie play The Mousetrap. Mad Ade dropped him outside the theater. When the tourist didn't give a tip, Mad Ade revealed how the play ended, thus spoiling the tourist's night.\n<|im_start|>answer\nThe tourist was going to a performance of the famous Agatha Christie play The Mousetrap. Mad Ade dropped him outside the theater. When the tourist didn't give a tip, Mad Ade revealed how the play ended, thus spoiling the tourist's night.\n<|im_end|>" }, { "id": "#5074", "title": "Winning Kebabs", "fun": 2.33, "difficulty": 2.44, "author": "mad-ade", "desc": "Mad Ade and three friends at the back of the classroom were comparing the numbers of Kebabs they had won at the local Kebab gala. \"I've got one more than you\", said Mad-Ade. \"I've got two more than you\", said one friend to another. \"I've got three more than you\" said one to another. \"I've got four more than you\" , \"I've got five more than you\", \"I've got six more than you\", rang their excited voices, but we don't know who was talking to whom. \n\r\nIf they had won a total of 27 kebabs between them, how many did Mad Ade win?", "hint": "No hint available.", "answer": "Mad Ade won five kebabs\r\nThere were only four friends, and six differences between them which were given. Therefore every possible difference between the four friends was named and we are looking for four numbers whose six differences are 1, 2, 3, 4, 5 and 6.\r\nThe differences between numbers don't change if all the numbers are increased or decreased by the same amount, so we can start by assuming that the first number is one, in which case the largest number (to give a maximum difference of six), must be seven.\r\nWe have to fill in the two middle numbers so that the six differences are the numbers 1 to 6. There are just two ways to do this:\r\n1 2 5 7 or 1 3 6 7\r\nThe total number of kebabs won in the first case is 1+2+5+7=15, which can be raised to 27 if we add three kebabs to each friends total, making their totals 4, 5, 8 and 10. The total of the second set is, however, 17, which cannot be raised to 27 by increasing each number by the same amount. \r\nTherefore the number of kebabs won by each friend is 4, 5, 8, 10 and Mad Ade, who won one more than one of the other friends, won five kebabs.", "category": "Math", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade and three friends at the back of the classroom were comparing the numbers of Kebabs they had won at the local Kebab gala. \"I've got one more than you\", said Mad-Ade. \"I've got two more than you\", said one friend to another. \"I've got three more than you\" said one to another. \"I've got four more than you\" , \"I've got five more than you\", \"I've got six more than you\", rang their excited voices, but we don't know who was talking to whom. \n\r\nIf they had won a total of 27 kebabs between them, how many did Mad Ade win?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade won five kebabs\r\nThere were only four friends, and six differences between them which were given. Therefore every possible difference between the four friends was named and we are looking for four numbers whose six differences are 1, 2, 3, 4, 5 and 6.\r\nThe differences between numbers don't change if all the numbers are increased or decreased by the same amount, so we can start by assuming that the first number is one, in which case the largest number (to give a maximum difference of six), must be seven.\r\nWe have to fill in the two middle numbers so that the six differences are the numbers 1 to 6. There are just two ways to do this:\r\n1 2 5 7 or 1 3 6 7\r\nThe total number of kebabs won in the first case is 1+2+5+7=15, which can be raised to 27 if we add three kebabs to each friends total, making their totals 4, 5, 8 and 10. The total of the second set is, however, 17, which cannot be raised to 27 by increasing each number by the same amount. \r\nTherefore the number of kebabs won by each friend is 4, 5, 8, 10 and Mad Ade, who won one more than one of the other friends, won five kebabs.\n<|im_start|>answer\nMad Ade won five kebabs\r\nThere were only four friends, and six differences between them which were given. Therefore every possible difference between the four friends was named and we are looking for four numbers whose six differences are 1, 2, 3, 4, 5 and 6.\r\nThe differences between numbers don't change if all the numbers are increased or decreased by the same amount, so we can start by assuming that the first number is one, in which case the largest number (to give a maximum difference of six), must be seven.\r\nWe have to fill in the two middle numbers so that the six differences are the numbers 1 to 6. There are just two ways to do this:\r\n1 2 5 7 or 1 3 6 7\r\nThe total number of kebabs won in the first case is 1+2+5+7=15, which can be raised to 27 if we add three kebabs to each friends total, making their totals 4, 5, 8 and 10. The total of the second set is, however, 17, which cannot be raised to 27 by increasing each number by the same amount. \r\nTherefore the number of kebabs won by each friend is 4, 5, 8, 10 and Mad Ade, who won one more than one of the other friends, won five kebabs.\n<|im_end|>" }, { "id": "#4470", "title": "Trapped Bird", "fun": 2.33, "difficulty": 1.73, "author": "mad-ade", "desc": "Whilst out walking one day, Mad Ade comes across a sparrow that had fallen into a hole in a rock. The hole measures three inches in diameter and is three feet deep. Due to the depth of the hole, the sparrow cannot be reached by hand. Mad Ade cannot use sticks or canes, because he could hurt the bird. How can Mad Ade free the bird without causing it any harm?", "hint": "No hint available.", "answer": "By gradually pouring sand into the hole. The bird will keep moving so that it is not buried in the sand, forcing it higher until it comes out.", "category": "Logic", "date": "06/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhilst out walking one day, Mad Ade comes across a sparrow that had fallen into a hole in a rock. The hole measures three inches in diameter and is three feet deep. Due to the depth of the hole, the sparrow cannot be reached by hand. Mad Ade cannot use sticks or canes, because he could hurt the bird. How can Mad Ade free the bird without causing it any harm?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBy gradually pouring sand into the hole. The bird will keep moving so that it is not buried in the sand, forcing it higher until it comes out.\n<|im_start|>answer\nBy gradually pouring sand into the hole. The bird will keep moving so that it is not buried in the sand, forcing it higher until it comes out.\n<|im_end|>" }, { "id": "#6487", "title": "Candle Light Kebab", "fun": 2.33, "difficulty": 1.98, "author": "mad-ade", "desc": "Mad Ade was studying for his Kebabology examinations at the University of MADADIA. He was doing some final revision before his morning exam, but alas there was a power cut. This was around 1:00 AM. Mad Ade managed to find two candles in the dark and lit them. The two candles were of equal length but one was much thicker than the other. \r\nAccording to the box the candles were in the thick candle is supposed to last six hours and the thin one two hours less. When Mad Ade finally went to sleep, dreaming of kebabs, the thick candle was twice as long as the thin one. \n\r\nFor how long did Mad Ade study by candle light?", "hint": "No hint available.", "answer": "3hrs. \r\nSay the length of the candle is 1 unit. After 1 hr the thick candle will be 5/6 of one unit, the thin candle 3/4. After two hrs the thick candle will be 2/3 (4/6) the size and then thin 1/2 (2/4). After 3hrs the thick candle will be 1/2 (3/6) and the thin 1/4. As 2* 1/4 = 1/2. The answer is 3hrs.", "category": "Math", "date": "08/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was studying for his Kebabology examinations at the University of MADADIA. He was doing some final revision before his morning exam, but alas there was a power cut. This was around 1:00 AM. Mad Ade managed to find two candles in the dark and lit them. The two candles were of equal length but one was much thicker than the other. \r\nAccording to the box the candles were in the thick candle is supposed to last six hours and the thin one two hours less. When Mad Ade finally went to sleep, dreaming of kebabs, the thick candle was twice as long as the thin one. \n\r\nFor how long did Mad Ade study by candle light?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3hrs. \r\nSay the length of the candle is 1 unit. After 1 hr the thick candle will be 5/6 of one unit, the thin candle 3/4. After two hrs the thick candle will be 2/3 (4/6) the size and then thin 1/2 (2/4). After 3hrs the thick candle will be 1/2 (3/6) and the thin 1/4. As 2* 1/4 = 1/2. The answer is 3hrs.\n<|im_start|>answer\n3hrs. \r\nSay the length of the candle is 1 unit. After 1 hr the thick candle will be 5/6 of one unit, the thin candle 3/4. After two hrs the thick candle will be 2/3 (4/6) the size and then thin 1/2 (2/4). After 3hrs the thick candle will be 1/2 (3/6) and the thin 1/4. As 2* 1/4 = 1/2. The answer is 3hrs.\n<|im_end|>" }, { "id": "#42454", "title": "The Track Meet", "fun": 2.33, "difficulty": 1.47, "author": "nascarfan19", "desc": "5 friends, Mark, Joe, Jimmy, Freddy, and Craig, are all running in their district track meet. They each run different events in different places.\n\r\nEvents: 100 Meter Dash, 200 Meter Dash, 400 Meter Dash, 4x800 Meter Run, and the 1600 Meter Run.\n\r\n1. Craig is an endurance runner, so he only runs 4x800 or 1600 meter runs.\r\n2. Joe was the only one to drop out in his event.\r\n3. Jimmy is a sprinter, which means he runs 100, 200, or 400 meter dashes.\r\n4. Mark is the fastest in his school, so he finished either 1st or 3rd.\r\n5. Freddy ran the 400 meter dash.\r\n6. Craig's teammate handed the baton to Craig in first place, but went down to 4th by the time he handed it off again, so he didn't finish 3rd or better.\r\n7. Freddy stumbled at the start of his event, so he did not finish 6th or better.\r\n8. Jimmy ran the 200 meter dash.\r\n9. Joe is not a sprinter.\r\n10. Mark isn't just the fastest in his school, he's the fastest in the district.", "hint": "No hint available.", "answer": "Mark: 100 Meter Dash, 1st Place\r\nJoe: 1600 Meter Run, 12th Place\r\nJimmy: 200 Meter Dash, 3rd Place\r\nFreddy: 400 Meter Dash, 9th Place\r\nCraig: 4x800 Meter Run, 6th Place", "category": "Logic-Grid", "date": "07/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n5 friends, Mark, Joe, Jimmy, Freddy, and Craig, are all running in their district track meet. They each run different events in different places.\n\r\nEvents: 100 Meter Dash, 200 Meter Dash, 400 Meter Dash, 4x800 Meter Run, and the 1600 Meter Run.\n\r\n1. Craig is an endurance runner, so he only runs 4x800 or 1600 meter runs.\r\n2. Joe was the only one to drop out in his event.\r\n3. Jimmy is a sprinter, which means he runs 100, 200, or 400 meter dashes.\r\n4. Mark is the fastest in his school, so he finished either 1st or 3rd.\r\n5. Freddy ran the 400 meter dash.\r\n6. Craig's teammate handed the baton to Craig in first place, but went down to 4th by the time he handed it off again, so he didn't finish 3rd or better.\r\n7. Freddy stumbled at the start of his event, so he did not finish 6th or better.\r\n8. Jimmy ran the 200 meter dash.\r\n9. Joe is not a sprinter.\r\n10. Mark isn't just the fastest in his school, he's the fastest in the district.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMark: 100 Meter Dash, 1st Place\r\nJoe: 1600 Meter Run, 12th Place\r\nJimmy: 200 Meter Dash, 3rd Place\r\nFreddy: 400 Meter Dash, 9th Place\r\nCraig: 4x800 Meter Run, 6th Place\n<|im_start|>answer\nMark: 100 Meter Dash, 1st Place\r\nJoe: 1600 Meter Run, 12th Place\r\nJimmy: 200 Meter Dash, 3rd Place\r\nFreddy: 400 Meter Dash, 9th Place\r\nCraig: 4x800 Meter Run, 6th Place\n<|im_end|>" }, { "id": "#28671", "title": "The Dice Game", "fun": 2.33, "difficulty": 2.78, "author": "Question_Mark", "desc": "Xavier and Rex were playing a game that involved 5 dice. In each turn, they would roll the 5 dice. Each face of the die is worth a different amount of points. On their first 2 shots, they rolled this:\n\r\nXavier 1: 1, 3, 3, 4, 6 = 177 points\r\nRex 1: 2, 4, 4, 5, 6 = 268 points\r\nXavier 2: 1, 1, 1, 4, 4 = 203 points\r\nRex 2: 1, 2, 3, 4, 6 = 216 points\n\r\nUsing this information, can you work out how many points Xavier and Rex each got on their third turn and how many points each face is worth?\n\r\nXavier 3: 1, 2, 2, 3, 4 = ?\r\nRex 3: 1, 3, 4, 6, 6 = ?", "hint": "Xavier scored more than Rex and the difference between the two total scores is 26 points.", "answer": "Xavier: 281 (Total: 661)\r\nRex: 151 (Total: 635)\n\r\n1 = 25 points\r\n2 = 77 points\r\n3 = 38 points\r\n4 = 64 points\r\n5 = 51 points\r\n6 = 12 points\n\r\nFrom Xavier's first shot and Rex's second shot, we can deduce that a 2 is worth more than a 3. From Xavier's second shot, we can deduce that a 1 is worth an odd number. By trial and error we can work out the value of each face.", "category": "Math", "date": "02/17/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nXavier and Rex were playing a game that involved 5 dice. In each turn, they would roll the 5 dice. Each face of the die is worth a different amount of points. On their first 2 shots, they rolled this:\n\r\nXavier 1: 1, 3, 3, 4, 6 = 177 points\r\nRex 1: 2, 4, 4, 5, 6 = 268 points\r\nXavier 2: 1, 1, 1, 4, 4 = 203 points\r\nRex 2: 1, 2, 3, 4, 6 = 216 points\n\r\nUsing this information, can you work out how many points Xavier and Rex each got on their third turn and how many points each face is worth?\n\r\nXavier 3: 1, 2, 2, 3, 4 = ?\r\nRex 3: 1, 3, 4, 6, 6 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nXavier: 281 (Total: 661)\r\nRex: 151 (Total: 635)\n\r\n1 = 25 points\r\n2 = 77 points\r\n3 = 38 points\r\n4 = 64 points\r\n5 = 51 points\r\n6 = 12 points\n\r\nFrom Xavier's first shot and Rex's second shot, we can deduce that a 2 is worth more than a 3. From Xavier's second shot, we can deduce that a 1 is worth an odd number. By trial and error we can work out the value of each face.\n<|im_start|>answer\nXavier: 281 (Total: 661)\r\nRex: 151 (Total: 635)\n\r\n1 = 25 points\r\n2 = 77 points\r\n3 = 38 points\r\n4 = 64 points\r\n5 = 51 points\r\n6 = 12 points\n\r\nFrom Xavier's first shot and Rex's second shot, we can deduce that a 2 is worth more than a 3. From Xavier's second shot, we can deduce that a 1 is worth an odd number. By trial and error we can work out the value of each face.\n<|im_end|>" }, { "id": "#41383", "title": "False Statement", "fun": 2.33, "difficulty": 1.16, "author": "Carlos16", "desc": "Which statement is false if only one is false?\n\r\nStatement A: Statement D is true\r\nStatement B: Statement A is false\r\nStatement C: Statement B is false\r\nStatement D: Statement C is true", "hint": "No hint available.", "answer": "When statement B is true, it results in statement A being false, which results in statement D being false also. This results in more than one false statement, so statement B is the false one.\n\r\nAnswer: B", "category": "Logic", "date": "04/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich statement is false if only one is false?\n\r\nStatement A: Statement D is true\r\nStatement B: Statement A is false\r\nStatement C: Statement B is false\r\nStatement D: Statement C is true\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen statement B is true, it results in statement A being false, which results in statement D being false also. This results in more than one false statement, so statement B is the false one.\n\r\nAnswer: B\n<|im_start|>answer\nWhen statement B is true, it results in statement A being false, which results in statement D being false also. This results in more than one false statement, so statement B is the false one.\n\r\nAnswer: B\n<|im_end|>" }, { "id": "#8581", "title": "Madadian Multiplex Two", "fun": 2.33, "difficulty": 1.9000000000000001, "author": "mad-ade", "desc": "Four couples are going to the movies to see the brand new Sci-Fi adventure film, by Madadian director Steven Squealburger, entitled \"The Empire Strikes For More Money\". Each row in the cinema holds eight seats. Sweaty Betty and Dim Jim don't want to sit next to Alice Malice and Tom Wrong . Alice and Tom don't want to sit next to Gertrude Gutrott and Bill Ovrites. On the other hand, Sally Forth and Bob Foraples don't want to sit next to Betty and Jim. \n\r\nHow can the couples arrange themselves in a row so that they all sit where they would like?", "hint": "No hint available.", "answer": "From the given data, it can be inferred that: \r\n(Sally & Bob) NOT (Betty & Jim) NOT (Alice & Tom) NOT (Gertrude & Bill) \n\r\n(A) NOT (B) means A and B can not sit next to each other. \n\r\nNow, it is obvious that (Betty & Jim) and (Alice & Tom) will occupy the corner seats as both of them can have only one neighbour. Therefore, \r\n(Gertrude & Bill) will sit next to (Betty & Jim) \r\n(Sally & Bob) will sit next to (Gertrude & Bill)\r\n(Alice & Tom) will sit next to (Sally & Bob) \n\r\nThus, there are two possible arrangements - mirror images of each other. \n\r\n1. (Betty & Jim) - (Gertrude & Bill) - (Sally & Bob) - (Alice & Tom) \r\n2. (Alice & Tom) - (Sally & Bob) - (Gertrude & Bill) - (Betty & Jim)", "category": "Logic", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour couples are going to the movies to see the brand new Sci-Fi adventure film, by Madadian director Steven Squealburger, entitled \"The Empire Strikes For More Money\". Each row in the cinema holds eight seats. Sweaty Betty and Dim Jim don't want to sit next to Alice Malice and Tom Wrong . Alice and Tom don't want to sit next to Gertrude Gutrott and Bill Ovrites. On the other hand, Sally Forth and Bob Foraples don't want to sit next to Betty and Jim. \n\r\nHow can the couples arrange themselves in a row so that they all sit where they would like?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom the given data, it can be inferred that: \r\n(Sally & Bob) NOT (Betty & Jim) NOT (Alice & Tom) NOT (Gertrude & Bill) \n\r\n(A) NOT (B) means A and B can not sit next to each other. \n\r\nNow, it is obvious that (Betty & Jim) and (Alice & Tom) will occupy the corner seats as both of them can have only one neighbour. Therefore, \r\n(Gertrude & Bill) will sit next to (Betty & Jim) \r\n(Sally & Bob) will sit next to (Gertrude & Bill)\r\n(Alice & Tom) will sit next to (Sally & Bob) \n\r\nThus, there are two possible arrangements - mirror images of each other. \n\r\n1. (Betty & Jim) - (Gertrude & Bill) - (Sally & Bob) - (Alice & Tom) \r\n2. (Alice & Tom) - (Sally & Bob) - (Gertrude & Bill) - (Betty & Jim)\n<|im_start|>answer\nFrom the given data, it can be inferred that: \r\n(Sally & Bob) NOT (Betty & Jim) NOT (Alice & Tom) NOT (Gertrude & Bill) \n\r\n(A) NOT (B) means A and B can not sit next to each other. \n\r\nNow, it is obvious that (Betty & Jim) and (Alice & Tom) will occupy the corner seats as both of them can have only one neighbour. Therefore, \r\n(Gertrude & Bill) will sit next to (Betty & Jim) \r\n(Sally & Bob) will sit next to (Gertrude & Bill)\r\n(Alice & Tom) will sit next to (Sally & Bob) \n\r\nThus, there are two possible arrangements - mirror images of each other. \n\r\n1. (Betty & Jim) - (Gertrude & Bill) - (Sally & Bob) - (Alice & Tom) \r\n2. (Alice & Tom) - (Sally & Bob) - (Gertrude & Bill) - (Betty & Jim)\n<|im_end|>" }, { "id": "#13516", "title": "How Many Candies?", "fun": 2.33, "difficulty": 2.75, "author": "badolina", "desc": "Rob the robot went to the candy-store to buy some candies. He found his favorite gums in front of him, in packages of 225 gums in each.\r\nThough extremely intelligent, he is still a robot, thus capable of using only 1's and 0's.\r\nWhat is the minimum number of gums that Rob ate that day if he finished all of his packages, and the number of gums contained nothing but 1's and 0's?\n\r\nOh yes, and you can't cheat and use binary notation. The answer is in base 10, but still only uses 1's and 0's.", "hint": "Think of the factors of 225, and kids, don't try this at home (or you would suffer from a severe stomach ache).", "answer": "11,111,111,100\n\r\nThis contains nine ones, so it is divisible by 9, and two 0's at the end, so it is divisible by 25.", "category": "Math", "date": "06/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRob the robot went to the candy-store to buy some candies. He found his favorite gums in front of him, in packages of 225 gums in each.\r\nThough extremely intelligent, he is still a robot, thus capable of using only 1's and 0's.\r\nWhat is the minimum number of gums that Rob ate that day if he finished all of his packages, and the number of gums contained nothing but 1's and 0's?\n\r\nOh yes, and you can't cheat and use binary notation. The answer is in base 10, but still only uses 1's and 0's.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11,111,111,100\n\r\nThis contains nine ones, so it is divisible by 9, and two 0's at the end, so it is divisible by 25.\n<|im_start|>answer\n11,111,111,100\n\r\nThis contains nine ones, so it is divisible by 9, and two 0's at the end, so it is divisible by 25.\n<|im_end|>" }, { "id": "#49214", "title": "What Four Numbers?", "fun": 2.33, "difficulty": 1.3800000000000001, "author": "CrazyPineapple", "desc": "Using the clues below, what four numbers am I thinking of?\n\r\nThe sum of all the numbers is 31.\r\nOne number is odd.\r\nThe highest number minus the lowest number is 7.\r\nIf you subtract the middle two numbers, it equals two.\r\nThere are no duplicate numbers.", "hint": "No hint available.", "answer": "The digits are 12, 5, 6, and 8.", "category": "Math", "date": "01/03/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the clues below, what four numbers am I thinking of?\n\r\nThe sum of all the numbers is 31.\r\nOne number is odd.\r\nThe highest number minus the lowest number is 7.\r\nIf you subtract the middle two numbers, it equals two.\r\nThere are no duplicate numbers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe digits are 12, 5, 6, and 8.\n<|im_start|>answer\nThe digits are 12, 5, 6, and 8.\n<|im_end|>" }, { "id": "#45841", "title": "Math Matches", "fun": 2.33, "difficulty": 2.29, "author": "wicked_one", "desc": "Suppose these lines were some matches. Move just one match to make the following equation correct.\n\r\nI + II + III = IIII\n\r\na) What's after \" = \" cannot be changed.\r\nb) Move only ONE match.", "hint": "No hint available.", "answer": "Take a match from \"II\", put it on the middle of \"III\" and you'll have I + I + I + I = IIII.", "category": "Math", "date": "11/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose these lines were some matches. Move just one match to make the following equation correct.\n\r\nI + II + III = IIII\n\r\na) What's after \" = \" cannot be changed.\r\nb) Move only ONE match.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTake a match from \"II\", put it on the middle of \"III\" and you'll have I + I + I + I = IIII.\n<|im_start|>answer\nTake a match from \"II\", put it on the middle of \"III\" and you'll have I + I + I + I = IIII.\n<|im_end|>" }, { "id": "#18035", "title": "The Order", "fun": 2.33, "difficulty": 2.61, "author": "collie07652", "desc": "There is a five-digit number having digits 1-9, no two digits being identical. Two are prime numbers, two are square numbers, and one is neither. The third digit is twice the fifth, the fourth is six greater than the second and the last is three less than the first.", "hint": "No hint available.", "answer": "73894", "category": "Math", "date": "06/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a five-digit number having digits 1-9, no two digits being identical. Two are prime numbers, two are square numbers, and one is neither. The third digit is twice the fifth, the fourth is six greater than the second and the last is three less than the first.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n73894\n<|im_start|>answer\n73894\n<|im_end|>" }, { "id": "#19049", "title": "Calendar Troubles !!!", "fun": 2.33, "difficulty": 1.71, "author": "lesternoronha1", "desc": "The other day, I was going through the calendar looking for the next holiday that comes on a weekday because I just love holidays. Just then I observed that this calendar year had started with a Sunday and ended with a Sunday too. If I had delved into further observations about this calendar year, I would have observed that one of the statements given below about this year was false. Which one?\n\r\n1) This calendar year is not a leap year.\r\n2) In this calendar year, the 15th of January and 15th of October fall on the same day of the week.\r\n3) In this calendar year, the 10th of July and 10th of October fall on the same day of the week.\r\n4) There will be 53 Sundays in this calendar year.", "hint": "No hint available.", "answer": "Statement 3 is false\n\r\nThe statements given about the calendar year are\n\r\n1) This calendar year is not a leap year.\r\n2) In this calendar year, the 15th of January and 15th of October fall on the same day of the week.\r\n3) In this calendar year, the 10th of July and 10th of October fall on the same day of the week.\r\n4) There will be 53 Sundays in this calendar year.\n\n\r\nSince the calendar year started with a Sunday and ends with a Sunday too, the year must not be a leap year, since only non leap years start and end on the same day of the week. Hence statement 1 is definitely true.\n\r\nAlso in a non leap year, the calendar of January matches with that of October. Hence the 15th of January and 15th of October must fall on the same day of the week. Hence statement 2 is also true.\n\r\nLastly if a year starts on a Sunday and ends on a Sunday too, that calendar year has 53 Sundays. Hence statement 4 is also true.\n\r\nThus statement 3 which states that the 10th of July and 10th of October fall on the same day of the week should be false.", "category": "Logic", "date": "10/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe other day, I was going through the calendar looking for the next holiday that comes on a weekday because I just love holidays. Just then I observed that this calendar year had started with a Sunday and ended with a Sunday too. If I had delved into further observations about this calendar year, I would have observed that one of the statements given below about this year was false. Which one?\n\r\n1) This calendar year is not a leap year.\r\n2) In this calendar year, the 15th of January and 15th of October fall on the same day of the week.\r\n3) In this calendar year, the 10th of July and 10th of October fall on the same day of the week.\r\n4) There will be 53 Sundays in this calendar year.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement 3 is false\n\r\nThe statements given about the calendar year are\n\r\n1) This calendar year is not a leap year.\r\n2) In this calendar year, the 15th of January and 15th of October fall on the same day of the week.\r\n3) In this calendar year, the 10th of July and 10th of October fall on the same day of the week.\r\n4) There will be 53 Sundays in this calendar year.\n\n\r\nSince the calendar year started with a Sunday and ends with a Sunday too, the year must not be a leap year, since only non leap years start and end on the same day of the week. Hence statement 1 is definitely true.\n\r\nAlso in a non leap year, the calendar of January matches with that of October. Hence the 15th of January and 15th of October must fall on the same day of the week. Hence statement 2 is also true.\n\r\nLastly if a year starts on a Sunday and ends on a Sunday too, that calendar year has 53 Sundays. Hence statement 4 is also true.\n\r\nThus statement 3 which states that the 10th of July and 10th of October fall on the same day of the week should be false.\n<|im_start|>answer\nStatement 3 is false\n\r\nThe statements given about the calendar year are\n\r\n1) This calendar year is not a leap year.\r\n2) In this calendar year, the 15th of January and 15th of October fall on the same day of the week.\r\n3) In this calendar year, the 10th of July and 10th of October fall on the same day of the week.\r\n4) There will be 53 Sundays in this calendar year.\n\n\r\nSince the calendar year started with a Sunday and ends with a Sunday too, the year must not be a leap year, since only non leap years start and end on the same day of the week. Hence statement 1 is definitely true.\n\r\nAlso in a non leap year, the calendar of January matches with that of October. Hence the 15th of January and 15th of October must fall on the same day of the week. Hence statement 2 is also true.\n\r\nLastly if a year starts on a Sunday and ends on a Sunday too, that calendar year has 53 Sundays. Hence statement 4 is also true.\n\r\nThus statement 3 which states that the 10th of July and 10th of October fall on the same day of the week should be false.\n<|im_end|>" }, { "id": "#2178", "title": "Stand Behind", "fun": 2.33, "difficulty": 1.1, "author": "Cascas", "desc": "How can you stand behind someone when they are standing behind you?", "hint": "No hint available.", "answer": "Stand back to back with them.", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can you stand behind someone when they are standing behind you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStand back to back with them.\n<|im_start|>answer\nStand back to back with them.\n<|im_end|>" }, { "id": "#1839", "title": "Book Reading Club", "fun": 2.33, "difficulty": 1.53, "author": "missie", "desc": "The six students in the Nutmeg Library Mystery Book Reading Club read a total of 20 books during the summer. The girls read the same number of books as the boys. \n\r\n-Abby and Stefanie read the same books. \r\n-Shaun read one more book than Nate. \r\n-Luis read the same number of books as Shaun and Nate read combined. \r\n-Pam read one more book than Luis.\n\r\nHow many books did each person read?", "hint": "No hint available.", "answer": "Each person read the following number of books: \r\nAbby: 2\r\nPam: 6\r\nStefanie: 2\r\nLuis: 5\r\nNate: 2\r\nShaun: 3", "category": "Logic", "date": "12/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe six students in the Nutmeg Library Mystery Book Reading Club read a total of 20 books during the summer. The girls read the same number of books as the boys. \n\r\n-Abby and Stefanie read the same books. \r\n-Shaun read one more book than Nate. \r\n-Luis read the same number of books as Shaun and Nate read combined. \r\n-Pam read one more book than Luis.\n\r\nHow many books did each person read?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach person read the following number of books: \r\nAbby: 2\r\nPam: 6\r\nStefanie: 2\r\nLuis: 5\r\nNate: 2\r\nShaun: 3\n<|im_start|>answer\nEach person read the following number of books: \r\nAbby: 2\r\nPam: 6\r\nStefanie: 2\r\nLuis: 5\r\nNate: 2\r\nShaun: 3\n<|im_end|>" }, { "id": "#2430", "title": "Coffee or Soda", "fun": 2.33, "difficulty": 1.51, "author": "Mr. Enigma", "desc": "George, Helen, and Steve are drinking coffee. \r\nBert, Karen, and Dave are drinking soda. \r\nUsing logic, is Elizabeth drinking coffee or soda?", "hint": "No hint available.", "answer": "Elizabeth is drinking coffee. The letter E appears twice in her name, as it does in the names of the others that are drinking coffee.", "category": "Logic", "date": "02/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGeorge, Helen, and Steve are drinking coffee. \r\nBert, Karen, and Dave are drinking soda. \r\nUsing logic, is Elizabeth drinking coffee or soda?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nElizabeth is drinking coffee. The letter E appears twice in her name, as it does in the names of the others that are drinking coffee.\n<|im_start|>answer\nElizabeth is drinking coffee. The letter E appears twice in her name, as it does in the names of the others that are drinking coffee.\n<|im_end|>" }, { "id": "#4221", "title": "Mad Ade's Cows", "fun": 2.33, "difficulty": 2.24, "author": "mad-ade", "desc": "Mad Ade has a field of grass that grows equally thick and in a uniform rate. It would take 70 cows 24 days to eat all the grass, or it would take 30 cows 60 days to eat the grass. Unfortunately Mad Ade has only got enough cows to clear the field in 96 days.\n\r\nHow many cows has Mad Ade got?", "hint": "No hint available.", "answer": "Mad Ade has 20 cows.\n\r\nAssume one cow does one unit of work in one day. In the first case with 70 cows, total units of work done = 70x24 = 1680.\r\nIn the second case with 30 cows, total units of work done = 30x60 = 1800.\r\nSo, in 36 days, the grass has grown = 1800-1680 = 120 units of work.\r\nSo, in 36 more days, i.e. 96 days, total units of work required = 1800 + 120 = 1920.\r\nNo. of cows required = 1920/96 = 20.", "category": "Math", "date": "05/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has a field of grass that grows equally thick and in a uniform rate. It would take 70 cows 24 days to eat all the grass, or it would take 30 cows 60 days to eat the grass. Unfortunately Mad Ade has only got enough cows to clear the field in 96 days.\n\r\nHow many cows has Mad Ade got?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade has 20 cows.\n\r\nAssume one cow does one unit of work in one day. In the first case with 70 cows, total units of work done = 70x24 = 1680.\r\nIn the second case with 30 cows, total units of work done = 30x60 = 1800.\r\nSo, in 36 days, the grass has grown = 1800-1680 = 120 units of work.\r\nSo, in 36 more days, i.e. 96 days, total units of work required = 1800 + 120 = 1920.\r\nNo. of cows required = 1920/96 = 20.\n<|im_start|>answer\nMad Ade has 20 cows.\n\r\nAssume one cow does one unit of work in one day. In the first case with 70 cows, total units of work done = 70x24 = 1680.\r\nIn the second case with 30 cows, total units of work done = 30x60 = 1800.\r\nSo, in 36 days, the grass has grown = 1800-1680 = 120 units of work.\r\nSo, in 36 more days, i.e. 96 days, total units of work required = 1800 + 120 = 1920.\r\nNo. of cows required = 1920/96 = 20.\n<|im_end|>" }, { "id": "#30345", "title": "Pets and Players", "fun": 2.33, "difficulty": 1.72, "author": "fairelamour", "desc": "Imelda's class of 36 has taken a survey of students. Among other survey results were the following statistics:\n\r\n1. The ratio of those who play sports to the total surveyed is 7:12.\n\r\n2. Among the sports players, the ratio of sports players who are pet owners to the total number of sports players is 3:7.\n\r\nHow many of the sports players are not pet owners?", "hint": "Make use of equivalent fractions.", "answer": "There are 12 sports players who are not pet owners.\n\r\nTo find the number of sports players, write an equivalent fraction for with a denominator of 36: 7/12=21/36. So there are 21 sports players.\n\r\nNow, to find how many of the 21 sports players are pet owners, write an equivalent fraction for with a denominator of 21: 3/7=9/21. So 9 sports players are pet owners, and 21 - 9 = 12 sports players who are not pet owners.", "category": "Math", "date": "05/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImelda's class of 36 has taken a survey of students. Among other survey results were the following statistics:\n\r\n1. The ratio of those who play sports to the total surveyed is 7:12.\n\r\n2. Among the sports players, the ratio of sports players who are pet owners to the total number of sports players is 3:7.\n\r\nHow many of the sports players are not pet owners?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 12 sports players who are not pet owners.\n\r\nTo find the number of sports players, write an equivalent fraction for with a denominator of 36: 7/12=21/36. So there are 21 sports players.\n\r\nNow, to find how many of the 21 sports players are pet owners, write an equivalent fraction for with a denominator of 21: 3/7=9/21. So 9 sports players are pet owners, and 21 - 9 = 12 sports players who are not pet owners.\n<|im_start|>answer\nThere are 12 sports players who are not pet owners.\n\r\nTo find the number of sports players, write an equivalent fraction for with a denominator of 36: 7/12=21/36. So there are 21 sports players.\n\r\nNow, to find how many of the 21 sports players are pet owners, write an equivalent fraction for with a denominator of 21: 3/7=9/21. So 9 sports players are pet owners, and 21 - 9 = 12 sports players who are not pet owners.\n<|im_end|>" }, { "id": "#35732", "title": "Opposites 30", "fun": 2.33, "difficulty": 2.5100000000000002, "author": "EnderofGames", "desc": "In the following code, each symbol stands for one of five letters.\n\r\n* stands for T, L, M, V, or Y\r\n# stands for S, H, C, M, or B\r\n^ stands for F, S, K, I, or O\r\n$ stands for O, W, G, U, or P\n\r\nThe four letter code word, #$^*, can be translated into two English words that are opposites. What are the two words?", "hint": "No hint available.", "answer": "Boom and Bust.", "category": "Logic", "date": "03/17/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following code, each symbol stands for one of five letters.\n\r\n* stands for T, L, M, V, or Y\r\n# stands for S, H, C, M, or B\r\n^ stands for F, S, K, I, or O\r\n$ stands for O, W, G, U, or P\n\r\nThe four letter code word, #$^*, can be translated into two English words that are opposites. What are the two words?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoom and Bust.\n<|im_start|>answer\nBoom and Bust.\n<|im_end|>" }, { "id": "#14997", "title": "The Sweaty Chef's Opening Days", "fun": 2.33, "difficulty": 2.14, "author": "mad-ade", "desc": "In order to conduct the work at Mad Ade's Favourite Take-away The Sweaty Chef KebabShop it is necessary to have a minimum of three workers each day. The staff consists of five persons who work on part time basis. Lily Livard can work on Mondays, Wednesdays and Fridays. Bea Sting cannot report for work on Wednesdays. Minnie Skurt can report for work on Tuesdays and Wednesdays only. Dinah Sore cannot work on Fridays. Eve Ning is available anytime except on the first Monday and Thursday of the month. \n\r\nDuring which day of the week might it be impossible to conduct the work at The Sweaty Chef KebabShop? \r\nNote that The Sweaty Chef KebabShop remains closed on Sundays, much to Mad Ade's dismay.", "hint": "No hint available.", "answer": "One Thursday each month. \n\r\nSince Eve Ning cannot work during one of the Thursdays of the month, that will be the one day per month that the The Sweaty Chef KebabShop cannot be run. Otherwise, the days could look like this: \n\r\nMonday: Lily Livard, Bea Sting, Dinah Sore \r\nTuesday: Bea Sting, Minnie Skurt, Eve Ning (or Dinah Sore) \r\nWednesday: Lily Livard, Minnie Skurt, Dinah Sore (or Eve Ning \r\nThursday: Bea Sting, Dinah Sore \r\nFriday: Lily Livard, Bea Sting, \r\nSaturday: Bea Sting, Dinah Sore, Eve Ning", "category": "Logic", "date": "10/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn order to conduct the work at Mad Ade's Favourite Take-away The Sweaty Chef KebabShop it is necessary to have a minimum of three workers each day. The staff consists of five persons who work on part time basis. Lily Livard can work on Mondays, Wednesdays and Fridays. Bea Sting cannot report for work on Wednesdays. Minnie Skurt can report for work on Tuesdays and Wednesdays only. Dinah Sore cannot work on Fridays. Eve Ning is available anytime except on the first Monday and Thursday of the month. \n\r\nDuring which day of the week might it be impossible to conduct the work at The Sweaty Chef KebabShop? \r\nNote that The Sweaty Chef KebabShop remains closed on Sundays, much to Mad Ade's dismay.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne Thursday each month. \n\r\nSince Eve Ning cannot work during one of the Thursdays of the month, that will be the one day per month that the The Sweaty Chef KebabShop cannot be run. Otherwise, the days could look like this: \n\r\nMonday: Lily Livard, Bea Sting, Dinah Sore \r\nTuesday: Bea Sting, Minnie Skurt, Eve Ning (or Dinah Sore) \r\nWednesday: Lily Livard, Minnie Skurt, Dinah Sore (or Eve Ning \r\nThursday: Bea Sting, Dinah Sore \r\nFriday: Lily Livard, Bea Sting, \r\nSaturday: Bea Sting, Dinah Sore, Eve Ning\n<|im_start|>answer\nOne Thursday each month. \n\r\nSince Eve Ning cannot work during one of the Thursdays of the month, that will be the one day per month that the The Sweaty Chef KebabShop cannot be run. Otherwise, the days could look like this: \n\r\nMonday: Lily Livard, Bea Sting, Dinah Sore \r\nTuesday: Bea Sting, Minnie Skurt, Eve Ning (or Dinah Sore) \r\nWednesday: Lily Livard, Minnie Skurt, Dinah Sore (or Eve Ning \r\nThursday: Bea Sting, Dinah Sore \r\nFriday: Lily Livard, Bea Sting, \r\nSaturday: Bea Sting, Dinah Sore, Eve Ning\n<|im_end|>" }, { "id": "#19096", "title": "Height vs Weight !!!", "fun": 2.33, "difficulty": 2.06, "author": "lesternoronha1", "desc": "Among four boys - Prashant, Vineet, Tarun and Kiran - the following comparisons of height and weight are made. The shorter of Tarun and Kiran is the heaviest of all four. The lighter of Prashant and Vineet is the tallest of all four. The shorter of Vineet and Tarun is the heavier of the two. The taller of Prashant and Kiran is the lightest of all the four. Tarun is not lighter than Vineet and not heavier than Kiran. No two boys are equal in either height or weight. Can you determine the shortest boy and the lightest boy among the four boys?", "hint": "No hint available.", "answer": "Let us list the observations about the four boys Prashant, Vineet, Tarun and Kiran.\n\r\n1) The shorter of Tarun and Kiran is the heaviest of all four.\r\n2) The lighter of Prashant and Vineet is the tallest of all four. \r\n3) The shorter of Vineet and Tarun is the heavier of the two. \r\n4) The taller of Prashant and Kiran is the lightest of all the four. \r\n5) Tarun is not lighter than Vineet and not heavier than Kiran. \r\n6) No two boys are equal in either height or weight.\n\r\nFrom observation 5, Tarun must be heavier than Vineet and lighter than Kiran using observation 6 which states that no two boys are equal in weight.\n\r\nSince Tarun is heavier than Vineet, from observation 3 Tarun must be the shorter of the two. Also since Tarun is lighter than Kiran, from observation 1 Tarun must be taller than Kiran, resulting in Kiran being the heaviest of all the four (from observation 1).\n\r\nSince Kiran is the heaviest of all the four, from observation 4, Prashant must be lighter than Kiran resulting in Prashant being the lightest of all the four (from observation 4).\n\r\nNow we know that Tarun is shorter than Vineet. From observation 2, Prashant is the tallest of all the four since he is the lightest in the group. Also we have Tarun must be taller than Kiran, thus making Kiran the shortest in the group. (Kiran is shorter than Tarun who is shorter than Vineet with Prashant as the tallest in the group).\n\r\nThus ranking them according to height and weight, we get the following table\n\r\nRank\tHeight\t Weight\r\n 1\tPrashant Kiran\r\n 2\tVineet\t Tarun\r\n 3 \t Tarun\t Vineet\r\n 4 Kiran Prashant\n\r\nHence Kiran is the shortest and Prashant the lightest of the four boys.", "category": "Logic", "date": "10/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAmong four boys - Prashant, Vineet, Tarun and Kiran - the following comparisons of height and weight are made. The shorter of Tarun and Kiran is the heaviest of all four. The lighter of Prashant and Vineet is the tallest of all four. The shorter of Vineet and Tarun is the heavier of the two. The taller of Prashant and Kiran is the lightest of all the four. Tarun is not lighter than Vineet and not heavier than Kiran. No two boys are equal in either height or weight. Can you determine the shortest boy and the lightest boy among the four boys?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet us list the observations about the four boys Prashant, Vineet, Tarun and Kiran.\n\r\n1) The shorter of Tarun and Kiran is the heaviest of all four.\r\n2) The lighter of Prashant and Vineet is the tallest of all four. \r\n3) The shorter of Vineet and Tarun is the heavier of the two. \r\n4) The taller of Prashant and Kiran is the lightest of all the four. \r\n5) Tarun is not lighter than Vineet and not heavier than Kiran. \r\n6) No two boys are equal in either height or weight.\n\r\nFrom observation 5, Tarun must be heavier than Vineet and lighter than Kiran using observation 6 which states that no two boys are equal in weight.\n\r\nSince Tarun is heavier than Vineet, from observation 3 Tarun must be the shorter of the two. Also since Tarun is lighter than Kiran, from observation 1 Tarun must be taller than Kiran, resulting in Kiran being the heaviest of all the four (from observation 1).\n\r\nSince Kiran is the heaviest of all the four, from observation 4, Prashant must be lighter than Kiran resulting in Prashant being the lightest of all the four (from observation 4).\n\r\nNow we know that Tarun is shorter than Vineet. From observation 2, Prashant is the tallest of all the four since he is the lightest in the group. Also we have Tarun must be taller than Kiran, thus making Kiran the shortest in the group. (Kiran is shorter than Tarun who is shorter than Vineet with Prashant as the tallest in the group).\n\r\nThus ranking them according to height and weight, we get the following table\n\r\nRank\tHeight\t Weight\r\n 1\tPrashant Kiran\r\n 2\tVineet\t Tarun\r\n 3 \t Tarun\t Vineet\r\n 4 Kiran Prashant\n\r\nHence Kiran is the shortest and Prashant the lightest of the four boys.\n<|im_start|>answer\nLet us list the observations about the four boys Prashant, Vineet, Tarun and Kiran.\n\r\n1) The shorter of Tarun and Kiran is the heaviest of all four.\r\n2) The lighter of Prashant and Vineet is the tallest of all four. \r\n3) The shorter of Vineet and Tarun is the heavier of the two. \r\n4) The taller of Prashant and Kiran is the lightest of all the four. \r\n5) Tarun is not lighter than Vineet and not heavier than Kiran. \r\n6) No two boys are equal in either height or weight.\n\r\nFrom observation 5, Tarun must be heavier than Vineet and lighter than Kiran using observation 6 which states that no two boys are equal in weight.\n\r\nSince Tarun is heavier than Vineet, from observation 3 Tarun must be the shorter of the two. Also since Tarun is lighter than Kiran, from observation 1 Tarun must be taller than Kiran, resulting in Kiran being the heaviest of all the four (from observation 1).\n\r\nSince Kiran is the heaviest of all the four, from observation 4, Prashant must be lighter than Kiran resulting in Prashant being the lightest of all the four (from observation 4).\n\r\nNow we know that Tarun is shorter than Vineet. From observation 2, Prashant is the tallest of all the four since he is the lightest in the group. Also we have Tarun must be taller than Kiran, thus making Kiran the shortest in the group. (Kiran is shorter than Tarun who is shorter than Vineet with Prashant as the tallest in the group).\n\r\nThus ranking them according to height and weight, we get the following table\n\r\nRank\tHeight\t Weight\r\n 1\tPrashant Kiran\r\n 2\tVineet\t Tarun\r\n 3 \t Tarun\t Vineet\r\n 4 Kiran Prashant\n\r\nHence Kiran is the shortest and Prashant the lightest of the four boys.\n<|im_end|>" }, { "id": "#8288", "title": "Familiar Stranger", "fun": 2.33, "difficulty": 1.31, "author": "quinnomatic", "desc": "Mike was watching T.V. and all of a sudden he leaps to his feet and says, \"That's Simon\", pointing at someone who was at the screen. Then his brother Mark comes in, looks at his brother, then looks back at the T.V. and says, \"So it is.\"\n\r\nHow do they know Simon if they hadn't seen him before, no pictures, nothing?", "hint": "Take note of the fact that Mark looks at his brother Mike then looks back.", "answer": "He is their long lost, separated triplet brother.", "category": "Logic", "date": "11/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMike was watching T.V. and all of a sudden he leaps to his feet and says, \"That's Simon\", pointing at someone who was at the screen. Then his brother Mark comes in, looks at his brother, then looks back at the T.V. and says, \"So it is.\"\n\r\nHow do they know Simon if they hadn't seen him before, no pictures, nothing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe is their long lost, separated triplet brother.\n<|im_start|>answer\nHe is their long lost, separated triplet brother.\n<|im_end|>" }, { "id": "#43459", "title": "Eight People", "fun": 2.33, "difficulty": 2.34, "author": "shenqiang", "desc": "In a mathematics contest, A, B, C, D, E, F, G and H got the top eight places. The teacher asked them to guess who got first.\n\r\nA said: \"Either F or H is first.\"\r\nB said: \"I'm first.\"\r\nC said: \"G is first.\"\r\nD said: \"B is not first.\"\r\nE said: \"A is wrong.\"\r\nF said: \"Neither I nor H is the first.\"\r\nG said: \"C is not first.\"\r\nH said: \"I agree with A.\"\n\r\nThe teacher told them that exactly three of them guessed correctly. Then, who got first?", "hint": "It's OK to use trial and error, however, there might be better methods.", "answer": "Since B and D contradict each other, exactly one of them must be true.\r\nSince A and H agree with each other while E and F are against them, exactly two of these four must be true.\n\r\nTherefore, neither C nor G guessed correctly. Since G guessed that C is not first, C must be first.", "category": "Logic", "date": "10/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a mathematics contest, A, B, C, D, E, F, G and H got the top eight places. The teacher asked them to guess who got first.\n\r\nA said: \"Either F or H is first.\"\r\nB said: \"I'm first.\"\r\nC said: \"G is first.\"\r\nD said: \"B is not first.\"\r\nE said: \"A is wrong.\"\r\nF said: \"Neither I nor H is the first.\"\r\nG said: \"C is not first.\"\r\nH said: \"I agree with A.\"\n\r\nThe teacher told them that exactly three of them guessed correctly. Then, who got first?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince B and D contradict each other, exactly one of them must be true.\r\nSince A and H agree with each other while E and F are against them, exactly two of these four must be true.\n\r\nTherefore, neither C nor G guessed correctly. Since G guessed that C is not first, C must be first.\n<|im_start|>answer\nSince B and D contradict each other, exactly one of them must be true.\r\nSince A and H agree with each other while E and F are against them, exactly two of these four must be true.\n\r\nTherefore, neither C nor G guessed correctly. Since G guessed that C is not first, C must be first.\n<|im_end|>" }, { "id": "#9435", "title": "Crime Calls", "fun": 2.33, "difficulty": 2.31, "author": "SPRITEBABE44", "desc": "There has been a murder on a street of bungalows. There are 10 bungalows. Each person who lives in a bungalow knows one unique piece of information. To solve the crime everybody needs to know everything. They decide to share their information by phone.\n\r\nWhat is the minimum number of calls that need to be made to solve the crime?", "hint": "No hint available.", "answer": "16\n\r\nName the 10 people with letters: A, B, C, ... and so on. A through F each call any one of G, H, I, or J (it doesn't matter which one). That makes six calls so far. Then G calls H and I calls J, after which G calls I and H calls J. Now we've used 10 calls, and G, H, I, and J all know everything. Finally, each of A through F is called by someone in G through J - 6 more calls to get everyone knowing everything. 16 calls in all.", "category": "Logic", "date": "12/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere has been a murder on a street of bungalows. There are 10 bungalows. Each person who lives in a bungalow knows one unique piece of information. To solve the crime everybody needs to know everything. They decide to share their information by phone.\n\r\nWhat is the minimum number of calls that need to be made to solve the crime?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16\n\r\nName the 10 people with letters: A, B, C, ... and so on. A through F each call any one of G, H, I, or J (it doesn't matter which one). That makes six calls so far. Then G calls H and I calls J, after which G calls I and H calls J. Now we've used 10 calls, and G, H, I, and J all know everything. Finally, each of A through F is called by someone in G through J - 6 more calls to get everyone knowing everything. 16 calls in all.\n<|im_start|>answer\n16\n\r\nName the 10 people with letters: A, B, C, ... and so on. A through F each call any one of G, H, I, or J (it doesn't matter which one). That makes six calls so far. Then G calls H and I calls J, after which G calls I and H calls J. Now we've used 10 calls, and G, H, I, and J all know everything. Finally, each of A through F is called by someone in G through J - 6 more calls to get everyone knowing everything. 16 calls in all.\n<|im_end|>" }, { "id": "#2675", "title": "Picking Apples", "fun": 2.33, "difficulty": 1.95, "author": "Chrissy---", "desc": "There once was a man who liked to pick apples from his big old apple tree. On the first day he picked 1 apple, on the second he picked 2 apples, on the third he picked 4 apples. On the fourth he picked 8 apples. If this pattern continues, then how many days will it take him to pick 67,108,864 apples???", "hint": "The operation I'd use:\n\r\n1X1 = 1\r\n1X2 = 2\r\n2X2 = 4\r\n4X2 = 8", "answer": "It will take 27 days", "category": "Math", "date": "03/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere once was a man who liked to pick apples from his big old apple tree. On the first day he picked 1 apple, on the second he picked 2 apples, on the third he picked 4 apples. On the fourth he picked 8 apples. If this pattern continues, then how many days will it take him to pick 67,108,864 apples???\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will take 27 days\n<|im_start|>answer\nIt will take 27 days\n<|im_end|>" }, { "id": "#5573", "title": "Three Digits", "fun": 2.33, "difficulty": 2.08, "author": "mad-ade", "desc": "Using the same digit three times, the number 24 can be made in different ways. One of the ways is 8 + 8 + 8.\n\r\nFind three other ways of using three digits (all the same) to make 24.", "hint": "No hint available.", "answer": "22 + 2\n\r\n3^3 - 3\n\r\n9 x sqrt(9) - sqrt(9)", "category": "Math", "date": "07/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the same digit three times, the number 24 can be made in different ways. One of the ways is 8 + 8 + 8.\n\r\nFind three other ways of using three digits (all the same) to make 24.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n22 + 2\n\r\n3^3 - 3\n\r\n9 x sqrt(9) - sqrt(9)\n<|im_start|>answer\n22 + 2\n\r\n3^3 - 3\n\r\n9 x sqrt(9) - sqrt(9)\n<|im_end|>" }, { "id": "#16714", "title": "Possible", "fun": 2.33, "difficulty": 1.15, "author": "birdie007bklyn", "desc": "In a world where everything is possible, what is impossible?", "hint": "No hint available.", "answer": "For something to be impossible.", "category": "Logic", "date": "02/23/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a world where everything is possible, what is impossible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor something to be impossible.\n<|im_start|>answer\nFor something to be impossible.\n<|im_end|>" }, { "id": "#9872", "title": "Two Sentries", "fun": 2.33, "difficulty": 0.86, "author": "lesternoronha1", "desc": "Two sentries were on duty outside a barracks. One faced up the road to watch for anyone approaching from the North. The other looked down the road to see if anyone was approached from the South. Suddenly one of them said to the other, \"Why are you smiling?\" \n\r\nHow did he know that his companion was smiling?", "hint": "No hint available.", "answer": "Although the guards were looking in opposite directions, they were not back to back. They were facing each other.", "category": "Logic", "date": "01/17/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo sentries were on duty outside a barracks. One faced up the road to watch for anyone approaching from the North. The other looked down the road to see if anyone was approached from the South. Suddenly one of them said to the other, \"Why are you smiling?\" \n\r\nHow did he know that his companion was smiling?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlthough the guards were looking in opposite directions, they were not back to back. They were facing each other.\n<|im_start|>answer\nAlthough the guards were looking in opposite directions, they were not back to back. They were facing each other.\n<|im_end|>" }, { "id": "#11283", "title": "Constant Value", "fun": 2.33, "difficulty": 1.6400000000000001, "author": "wxman", "desc": "Despite years of inflation this collection of 51 common American items was valued at $5 in 1900, 1950, 2000 as well as today. \n\r\nWhat is it?", "hint": "You can bank on it.", "answer": "A roll of US dimes (10-cent pieces): 50 dimes and the paper roller.", "category": "Logic", "date": "03/19/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDespite years of inflation this collection of 51 common American items was valued at $5 in 1900, 1950, 2000 as well as today. \n\r\nWhat is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA roll of US dimes (10-cent pieces): 50 dimes and the paper roller.\n<|im_start|>answer\nA roll of US dimes (10-cent pieces): 50 dimes and the paper roller.\n<|im_end|>" }, { "id": "#44953", "title": "Too Many Pills", "fun": 2.33, "difficulty": 1.25, "author": "grilledcheese", "desc": "A man has been prescribed 10 pills. Starting today, he must take one pill a day, but because the concentration of the medicine is different in each pill, he must take them in a specific order. Since the pills look the same, the man decided to write numbers on each pill to help him remember the order he needs to take them in.\n\r\nWhat is the least amount of pills he has to number if he wants to keep track of the order?", "hint": "No hint available.", "answer": "8\n\r\nSince he has to start the medicine today, the first thing for him to do is take the first pill.\r\nNext, he labels 2-9. He doesn't need to label pill number 10 because it will be the only one without a label.", "category": "Logic", "date": "07/26/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man has been prescribed 10 pills. Starting today, he must take one pill a day, but because the concentration of the medicine is different in each pill, he must take them in a specific order. Since the pills look the same, the man decided to write numbers on each pill to help him remember the order he needs to take them in.\n\r\nWhat is the least amount of pills he has to number if he wants to keep track of the order?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8\n\r\nSince he has to start the medicine today, the first thing for him to do is take the first pill.\r\nNext, he labels 2-9. He doesn't need to label pill number 10 because it will be the only one without a label.\n<|im_start|>answer\n8\n\r\nSince he has to start the medicine today, the first thing for him to do is take the first pill.\r\nNext, he labels 2-9. He doesn't need to label pill number 10 because it will be the only one without a label.\n<|im_end|>" }, { "id": "#20884", "title": "2 Brothers and 2 Sisters", "fun": 2.33, "difficulty": 0.93, "author": "Weezy105", "desc": "Each child in a family has at least 2 brothers and 2 sisters. What is the smallest number of children the family might have?", "hint": "No hint available.", "answer": "6. If each boy in the family has at least 2 brothers, then the smallest number of boys is 3. Similarly, if each girl in the family has at least 2 sisters, then the smallest number of girls is 3. Thus, the smallest number of children the family might have is 6.", "category": "Math", "date": "02/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach child in a family has at least 2 brothers and 2 sisters. What is the smallest number of children the family might have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6. If each boy in the family has at least 2 brothers, then the smallest number of boys is 3. Similarly, if each girl in the family has at least 2 sisters, then the smallest number of girls is 3. Thus, the smallest number of children the family might have is 6.\n<|im_start|>answer\n6. If each boy in the family has at least 2 brothers, then the smallest number of boys is 3. Similarly, if each girl in the family has at least 2 sisters, then the smallest number of girls is 3. Thus, the smallest number of children the family might have is 6.\n<|im_end|>" }, { "id": "#3976", "title": "Poor Robot", "fun": 2.33, "difficulty": 1.96, "author": "GoldieLuvNeopets", "desc": "Jilbert is delighted at her new purchase of a Wheelie Bot (robot). She looks at the box it came in, and reads that it is 'guaranteed to travel 10km on a single battery'. Wow, what a long way! Jilbert puts her Wheelie Bot on a specially designed 1-meter radius circular track, for exercise, and then leaves for the night. The Wheelie Bot starts moving, completing one lap every twenty seconds! \n\r\nThree hours after Jilbert leaves, her little sister Harriet arrives and sees the new toy. Shrieking with excitement Harriet shouts 'faster, go on, faster'. The Wheelie Bot complies and starts going five times its original speed, zooming around the track again and again - poor Wheelie Bot :( When Jilbert got back and saw her poor Wheelie Bot exhausted she was not a happy sister! \n\r\nThe question is : \r\nHow many minutes in total did it take for the Wheelie Bot to run out of batteries?? (please round your answer down to the nearest minute)", "hint": "No hint available.", "answer": "250 minutes", "category": "Math", "date": "05/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJilbert is delighted at her new purchase of a Wheelie Bot (robot). She looks at the box it came in, and reads that it is 'guaranteed to travel 10km on a single battery'. Wow, what a long way! Jilbert puts her Wheelie Bot on a specially designed 1-meter radius circular track, for exercise, and then leaves for the night. The Wheelie Bot starts moving, completing one lap every twenty seconds! \n\r\nThree hours after Jilbert leaves, her little sister Harriet arrives and sees the new toy. Shrieking with excitement Harriet shouts 'faster, go on, faster'. The Wheelie Bot complies and starts going five times its original speed, zooming around the track again and again - poor Wheelie Bot :( When Jilbert got back and saw her poor Wheelie Bot exhausted she was not a happy sister! \n\r\nThe question is : \r\nHow many minutes in total did it take for the Wheelie Bot to run out of batteries?? (please round your answer down to the nearest minute)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n250 minutes\n<|im_start|>answer\n250 minutes\n<|im_end|>" }, { "id": "#13609", "title": "The Dwarvish Feast", "fun": 2.33, "difficulty": 2.89, "author": "bobdole", "desc": "In a forest somewhere in Scotland lives a group of 100 dwarves. Each night they meet in the middle of the forest for a grand feast. When morning comes, they all go home. Each dwarf is wearing either a red hat or a blue hat. Curiously, there are no mirrors in the forest, so no dwarf knows the color of his own hat. A dwarf would never take off his hat to see its color, and a major dwarf faux pas is to comment on the color of another dwarf's hat. The dwarves know, however, that there is at least one red hatted dwarf and one blue hatted dwarf. One day, the master dwarf announces that the nightly feast will only be intended for blue hatted dwarves, and as soon as a dwarf knows that he is wearing a red hat, he should not come back the next day, and he should never return. \r\nHow many days does it take before there are no dwarves left with red hats at the party? (Assume all the dwarves are equally capable of figuring it out, in other words, there are no smart dwarves, and no stupid dwarves...)", "hint": "The number of days depends on the number of red hats.", "answer": "It will take one more day than the number of dwarves with red hats.\r\nHow this works is: assume that there is only one red-hatted dwarf. He would go to the party only to see 99 blue hats. He knows that there is at least one red hat. Since all he sees is blue, he knows it must be him, so he knows not to come back the next day. Meanwhile, the blue hatted dwarves can only see one red hat, so they think that if he comes back tomorrow, then he must have seen another red hat. Since each blue hatted dwarf only sees one red hat, he would assume that if the red hatted dwarf came back tomorrow, then he must be the other red hat that the first red hatted dwarf saw. So the second day, all the blue hatted dwarves would come expecting to see if the red hatted dwarf came back. Which he wouldn't, because he knows he has a red hat. So the first day there are no dwarves with red hats is day 2, or one day more than the number of dwarves with red hats. \r\nIf there were two dwarves with red hats, each red hatted dwarf would realize on the second day that he was wearing a red hat, because he would see that the other red hat had come back, and that means that he must have seen another red hat. Since the red hats would see 98 blue hats, they would know on the second day, and the third day would be the first day that no red hatted dwarves came to the feast. This same system works for any number of red hats, because each time a blue hatted dwarf is thinking that if the red hats come back tomorrow, then he must have a red hat, the red hatted dwarves already know, and so they don't come the next day.", "category": "Logic", "date": "07/03/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a forest somewhere in Scotland lives a group of 100 dwarves. Each night they meet in the middle of the forest for a grand feast. When morning comes, they all go home. Each dwarf is wearing either a red hat or a blue hat. Curiously, there are no mirrors in the forest, so no dwarf knows the color of his own hat. A dwarf would never take off his hat to see its color, and a major dwarf faux pas is to comment on the color of another dwarf's hat. The dwarves know, however, that there is at least one red hatted dwarf and one blue hatted dwarf. One day, the master dwarf announces that the nightly feast will only be intended for blue hatted dwarves, and as soon as a dwarf knows that he is wearing a red hat, he should not come back the next day, and he should never return. \r\nHow many days does it take before there are no dwarves left with red hats at the party? (Assume all the dwarves are equally capable of figuring it out, in other words, there are no smart dwarves, and no stupid dwarves...)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will take one more day than the number of dwarves with red hats.\r\nHow this works is: assume that there is only one red-hatted dwarf. He would go to the party only to see 99 blue hats. He knows that there is at least one red hat. Since all he sees is blue, he knows it must be him, so he knows not to come back the next day. Meanwhile, the blue hatted dwarves can only see one red hat, so they think that if he comes back tomorrow, then he must have seen another red hat. Since each blue hatted dwarf only sees one red hat, he would assume that if the red hatted dwarf came back tomorrow, then he must be the other red hat that the first red hatted dwarf saw. So the second day, all the blue hatted dwarves would come expecting to see if the red hatted dwarf came back. Which he wouldn't, because he knows he has a red hat. So the first day there are no dwarves with red hats is day 2, or one day more than the number of dwarves with red hats. \r\nIf there were two dwarves with red hats, each red hatted dwarf would realize on the second day that he was wearing a red hat, because he would see that the other red hat had come back, and that means that he must have seen another red hat. Since the red hats would see 98 blue hats, they would know on the second day, and the third day would be the first day that no red hatted dwarves came to the feast. This same system works for any number of red hats, because each time a blue hatted dwarf is thinking that if the red hats come back tomorrow, then he must have a red hat, the red hatted dwarves already know, and so they don't come the next day.\n<|im_start|>answer\nIt will take one more day than the number of dwarves with red hats.\r\nHow this works is: assume that there is only one red-hatted dwarf. He would go to the party only to see 99 blue hats. He knows that there is at least one red hat. Since all he sees is blue, he knows it must be him, so he knows not to come back the next day. Meanwhile, the blue hatted dwarves can only see one red hat, so they think that if he comes back tomorrow, then he must have seen another red hat. Since each blue hatted dwarf only sees one red hat, he would assume that if the red hatted dwarf came back tomorrow, then he must be the other red hat that the first red hatted dwarf saw. So the second day, all the blue hatted dwarves would come expecting to see if the red hatted dwarf came back. Which he wouldn't, because he knows he has a red hat. So the first day there are no dwarves with red hats is day 2, or one day more than the number of dwarves with red hats. \r\nIf there were two dwarves with red hats, each red hatted dwarf would realize on the second day that he was wearing a red hat, because he would see that the other red hat had come back, and that means that he must have seen another red hat. Since the red hats would see 98 blue hats, they would know on the second day, and the third day would be the first day that no red hatted dwarves came to the feast. This same system works for any number of red hats, because each time a blue hatted dwarf is thinking that if the red hats come back tomorrow, then he must have a red hat, the red hatted dwarves already know, and so they don't come the next day.\n<|im_end|>" }, { "id": "#5127", "title": "Trip to Pinewood", "fun": 2.33, "difficulty": 1.42, "author": "Cascas", "desc": "The drive from Oakland to Pinewood was a tricky one. I covered the uphill distance of 70 miles at 42 miles per hour. The return journey from Pinewood to Oakland was downhill, and I managed to drive at 56 miles per hour. What was my average speed for the entire journey?", "hint": "No hint available.", "answer": "My average speed was 48 miles per hour.\r\nTotal distance = 2 x 70 miles. \r\nTime for uphill journey (from Oakland to Pinewood) = 70 / 42 hours.\r\nTime for downhill journey (from Pinewood to Oakland) = 70 / 56 hours.\r\nTotal time = (70 / 42) + (70 / 56) = 2 x 70 / 48 hours. \r\nAverage speed = Total distance / Total time = 48 miles per hour.", "category": "Math", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe drive from Oakland to Pinewood was a tricky one. I covered the uphill distance of 70 miles at 42 miles per hour. The return journey from Pinewood to Oakland was downhill, and I managed to drive at 56 miles per hour. What was my average speed for the entire journey?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMy average speed was 48 miles per hour.\r\nTotal distance = 2 x 70 miles. \r\nTime for uphill journey (from Oakland to Pinewood) = 70 / 42 hours.\r\nTime for downhill journey (from Pinewood to Oakland) = 70 / 56 hours.\r\nTotal time = (70 / 42) + (70 / 56) = 2 x 70 / 48 hours. \r\nAverage speed = Total distance / Total time = 48 miles per hour.\n<|im_start|>answer\nMy average speed was 48 miles per hour.\r\nTotal distance = 2 x 70 miles. \r\nTime for uphill journey (from Oakland to Pinewood) = 70 / 42 hours.\r\nTime for downhill journey (from Pinewood to Oakland) = 70 / 56 hours.\r\nTotal time = (70 / 42) + (70 / 56) = 2 x 70 / 48 hours. \r\nAverage speed = Total distance / Total time = 48 miles per hour.\n<|im_end|>" }, { "id": "#6749", "title": "Two 3's", "fun": 2.33, "difficulty": 2.9, "author": "pemalova", "desc": "Your mission is to come up with an equation that will equal twenty. The catch is that you can only use two 3's (example: 3+3=6). You can use any function you want but the total must be 20.", "hint": "No hint available.", "answer": "The first three, is 3(factorial). That means 3x2x1. That equals 6. Divide that by .3, and you have your answer.", "category": "Math", "date": "08/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour mission is to come up with an equation that will equal twenty. The catch is that you can only use two 3's (example: 3+3=6). You can use any function you want but the total must be 20.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first three, is 3(factorial). That means 3x2x1. That equals 6. Divide that by .3, and you have your answer.\n<|im_start|>answer\nThe first three, is 3(factorial). That means 3x2x1. That equals 6. Divide that by .3, and you have your answer.\n<|im_end|>" }, { "id": "#1999", "title": "Dozens and Dozens", "fun": 2.33, "difficulty": 1.26, "author": "Majeen", "desc": "Which is more: \r\nBuns in a dozen baker's dozens or hours in a week?", "hint": "No hint available.", "answer": "Hours in a week; there are 156 buns in a dozen baker's dozens and 168 hours in a week.", "category": "Math", "date": "01/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is more: \r\nBuns in a dozen baker's dozens or hours in a week?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHours in a week; there are 156 buns in a dozen baker's dozens and 168 hours in a week.\n<|im_start|>answer\nHours in a week; there are 156 buns in a dozen baker's dozens and 168 hours in a week.\n<|im_end|>" }, { "id": "#16148", "title": "Sir Mad and The Dragon", "fun": 2.33, "difficulty": 2.24, "author": "mad-ade", "desc": "During the Medieval period of Madadian history the land was terrorised with strange creatures, like the legendary Georgian Dragon that roamed the hills of the lower Madadian Forest.\r\nYoung Sir Mad Ade, knight of the periodic table, was dispatched by the King to dispense with the infamous Dragon.\r\nThe task was not as straight forward as in may seem, as the Georgian Dragon had three heads and three tails. If this was not bad enough there was even more of a problem, the dragon had certain regenerative powers, so if one head is chopped off, a new head grows, also if Sir Mad Ade is to chop off one tail, two new tails grow.\r\nIf Sir Mad hacks off two tails, one new head grows. But if two heads are chopped off, nothing grows. \r\nYoung Sir Mad has with him a magical sword, blessed by the lady of the boating lake. The sword is capable of removing with a single blow either one head or two heads, or one tail or two tails, but never a combination of a head or a tail in one blow.\r\nWhat is the smallest number of strokes required by Sir Mad Ade to chop off all heads and tails of the dragon, thus killing it?", "hint": "No hint available.", "answer": "Sir Mad Ade managed it in nine strokes. \r\nThe best way to achieve this is that all of the tails must be converted to heads in such a way that the dragon is left with an even number of heads. \n\r\nThe way Sir Mad did this in the smallest number of strokes was to first convert the three tails to six tails by using three one-tail strokes, then converting the six tails to three heads via three two-tail strokes. Finally, the now six-headed dragon can be killed with three two-head strokes. \n\r\nThus, total of nine strokes to chop off all heads and tails of the dragon.", "category": "Math", "date": "01/12/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring the Medieval period of Madadian history the land was terrorised with strange creatures, like the legendary Georgian Dragon that roamed the hills of the lower Madadian Forest.\r\nYoung Sir Mad Ade, knight of the periodic table, was dispatched by the King to dispense with the infamous Dragon.\r\nThe task was not as straight forward as in may seem, as the Georgian Dragon had three heads and three tails. If this was not bad enough there was even more of a problem, the dragon had certain regenerative powers, so if one head is chopped off, a new head grows, also if Sir Mad Ade is to chop off one tail, two new tails grow.\r\nIf Sir Mad hacks off two tails, one new head grows. But if two heads are chopped off, nothing grows. \r\nYoung Sir Mad has with him a magical sword, blessed by the lady of the boating lake. The sword is capable of removing with a single blow either one head or two heads, or one tail or two tails, but never a combination of a head or a tail in one blow.\r\nWhat is the smallest number of strokes required by Sir Mad Ade to chop off all heads and tails of the dragon, thus killing it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSir Mad Ade managed it in nine strokes. \r\nThe best way to achieve this is that all of the tails must be converted to heads in such a way that the dragon is left with an even number of heads. \n\r\nThe way Sir Mad did this in the smallest number of strokes was to first convert the three tails to six tails by using three one-tail strokes, then converting the six tails to three heads via three two-tail strokes. Finally, the now six-headed dragon can be killed with three two-head strokes. \n\r\nThus, total of nine strokes to chop off all heads and tails of the dragon.\n<|im_start|>answer\nSir Mad Ade managed it in nine strokes. \r\nThe best way to achieve this is that all of the tails must be converted to heads in such a way that the dragon is left with an even number of heads. \n\r\nThe way Sir Mad did this in the smallest number of strokes was to first convert the three tails to six tails by using three one-tail strokes, then converting the six tails to three heads via three two-tail strokes. Finally, the now six-headed dragon can be killed with three two-head strokes. \n\r\nThus, total of nine strokes to chop off all heads and tails of the dragon.\n<|im_end|>" }, { "id": "#16440", "title": "Pigs 2", "fun": 2.33, "difficulty": 1.74, "author": "eiennikirei", "desc": "Farmer Brown owns one pregnant pig. How many pigs will he have after: \r\n1) The pig gives birth to 7 pigs, \r\n2) 3 of those give birth to 8 each, \r\n3) 2 of them give birth to 4 each, \r\n4) 1 of those pigs gives birth to 10 pigs? \n\r\nAssume that two pigs die in every litter of eight or more pigs.", "hint": "No hint available.", "answer": "He will have 40 pigs.\n\r\n1) The pig gives birth to 7 pigs = 8 \r\n2) 3 of those give birth to 8 each = 26 (two pigs die after every eight born) \r\n3) 2 of them give birth to 4 each = 32 \r\n4) 1 of those pigs gives birth to 10 pigs = 40 (two pigs die after every eight born)", "category": "Math", "date": "02/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFarmer Brown owns one pregnant pig. How many pigs will he have after: \r\n1) The pig gives birth to 7 pigs, \r\n2) 3 of those give birth to 8 each, \r\n3) 2 of them give birth to 4 each, \r\n4) 1 of those pigs gives birth to 10 pigs? \n\r\nAssume that two pigs die in every litter of eight or more pigs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe will have 40 pigs.\n\r\n1) The pig gives birth to 7 pigs = 8 \r\n2) 3 of those give birth to 8 each = 26 (two pigs die after every eight born) \r\n3) 2 of them give birth to 4 each = 32 \r\n4) 1 of those pigs gives birth to 10 pigs = 40 (two pigs die after every eight born)\n<|im_start|>answer\nHe will have 40 pigs.\n\r\n1) The pig gives birth to 7 pigs = 8 \r\n2) 3 of those give birth to 8 each = 26 (two pigs die after every eight born) \r\n3) 2 of them give birth to 4 each = 32 \r\n4) 1 of those pigs gives birth to 10 pigs = 40 (two pigs die after every eight born)\n<|im_end|>" }, { "id": "#9921", "title": "1-9 = 1:5", "fun": 2.33, "difficulty": 2.69, "author": "doggyxp", "desc": "Arrange the numbers 1 through 9 to form two numbers that appear in a 1:5 ratio, using each number only once. \n\r\neg. If it were the numbers 1 through 3 in a 1:4 ratio the answer would be: \n\r\n3:12", "hint": "No hint available.", "answer": "Possible solutions:\r\n2697 / 13485\r\n2769 / 13845\r\n2937 / 14685\r\n2967 / 14835\r\n2973 / 14865\r\n3297 / 16485\r\n3729 / 18645\r\n6297 / 31485\r\n7629 / 38145\r\n9237 / 46185\r\n9627 / 48135\r\n9723 / 48615", "category": "Math", "date": "01/20/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numbers 1 through 9 to form two numbers that appear in a 1:5 ratio, using each number only once. \n\r\neg. If it were the numbers 1 through 3 in a 1:4 ratio the answer would be: \n\r\n3:12\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPossible solutions:\r\n2697 / 13485\r\n2769 / 13845\r\n2937 / 14685\r\n2967 / 14835\r\n2973 / 14865\r\n3297 / 16485\r\n3729 / 18645\r\n6297 / 31485\r\n7629 / 38145\r\n9237 / 46185\r\n9627 / 48135\r\n9723 / 48615\n<|im_start|>answer\nPossible solutions:\r\n2697 / 13485\r\n2769 / 13845\r\n2937 / 14685\r\n2967 / 14835\r\n2973 / 14865\r\n3297 / 16485\r\n3729 / 18645\r\n6297 / 31485\r\n7629 / 38145\r\n9237 / 46185\r\n9627 / 48135\r\n9723 / 48615\n<|im_end|>" }, { "id": "#14163", "title": "Minutes Apart", "fun": 2.33, "difficulty": 2.16, "author": "mathemagician", "desc": "Fifty minutes ago, it was four times as many minutes past 7 P.M. as the number of minutes it currently is until 10 P.M.\n\r\nWhat is the current time?", "hint": "No hint available.", "answer": "The current time is 9:34 P.M.\n\r\nFifty minutes ago the time was 8:44, which is 104 minutes past 7:00.\n\r\nIt is currently 26 minutes until 10 P.M. 104 = 4 x 26.", "category": "Math", "date": "08/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFifty minutes ago, it was four times as many minutes past 7 P.M. as the number of minutes it currently is until 10 P.M.\n\r\nWhat is the current time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe current time is 9:34 P.M.\n\r\nFifty minutes ago the time was 8:44, which is 104 minutes past 7:00.\n\r\nIt is currently 26 minutes until 10 P.M. 104 = 4 x 26.\n<|im_start|>answer\nThe current time is 9:34 P.M.\n\r\nFifty minutes ago the time was 8:44, which is 104 minutes past 7:00.\n\r\nIt is currently 26 minutes until 10 P.M. 104 = 4 x 26.\n<|im_end|>" }, { "id": "#4554", "title": "Strange Room", "fun": 2.33, "difficulty": 1.87, "author": "mad-ade", "desc": "In the house of Mad Ade there is a strange room. In this strange room are 6 strange rugs and on each rug are 6 strange 6-legged tables. On each of the 6 strange 6-legged tables are 6 strange 6-legged creatures. \n\r\nHow many legs are in the strange room of Mad Ade's if there\r\nare no humans in the room?", "hint": "No hint available.", "answer": "1,512.\n\r\nHere's how:\r\n6 rugs, each with 6 tables on them, so there are 36 tables.\r\nEach table has 6 legs, or 216 legs total (36 X 6).\n\r\nEach table has 6 creatures on it, so there are 216 creatures (36 X 6).\r\nEach creature has 6 legs, so there are 1,296 creature legs (216 X 6).\n\r\n216 table legs + 1,296 creature legs = 1,512 total legs.", "category": "Math", "date": "06/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the house of Mad Ade there is a strange room. In this strange room are 6 strange rugs and on each rug are 6 strange 6-legged tables. On each of the 6 strange 6-legged tables are 6 strange 6-legged creatures. \n\r\nHow many legs are in the strange room of Mad Ade's if there\r\nare no humans in the room?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1,512.\n\r\nHere's how:\r\n6 rugs, each with 6 tables on them, so there are 36 tables.\r\nEach table has 6 legs, or 216 legs total (36 X 6).\n\r\nEach table has 6 creatures on it, so there are 216 creatures (36 X 6).\r\nEach creature has 6 legs, so there are 1,296 creature legs (216 X 6).\n\r\n216 table legs + 1,296 creature legs = 1,512 total legs.\n<|im_start|>answer\n1,512.\n\r\nHere's how:\r\n6 rugs, each with 6 tables on them, so there are 36 tables.\r\nEach table has 6 legs, or 216 legs total (36 X 6).\n\r\nEach table has 6 creatures on it, so there are 216 creatures (36 X 6).\r\nEach creature has 6 legs, so there are 1,296 creature legs (216 X 6).\n\r\n216 table legs + 1,296 creature legs = 1,512 total legs.\n<|im_end|>" }, { "id": "#5073", "title": "Madadian Wonks", "fun": 2.33, "difficulty": 2.07, "author": "mad-ade", "desc": "\"I see you have a Madadian stamp there, from the legendary country of MADADIA. Very nice design, especially the picture of Crown Prince Mad Ade eating a kebab. Do you have any more?\" asked Norma Leigh-Sober. \"No. I did have a 3-wonk, a 9-wonk, a 10-wonk, a 12-wonk, a 13-wonk, and a 14-wonk stamp,\" replied Rod Wolloper, \"But at the airport I used five of them to mail a postcard and a letter. The letter took twice as much postage as the postcard, and that left me with only this one stamp.\" \n\r\nWhat was its value (in wonk)?", "hint": "No hint available.", "answer": "The total value of the stamps is (3 + 9 + 10 + 12 + 13 + 14) = 61 \r\nThe 5 stamps used at the airport totalled a multiple of 3 wonk, so the remaining stamp must be of value = 1(mod 3). The only stamps meeting this condition are the 10-wonk and the 13-wonk. Assume the 13-wonk stamp remains. Then the total postage was \r\n(3 + 9 + 10 + 12 + 14) = 48 = (16) \r\nBut no combination of stamps will make 16, so the 13-wonk must not be the remaining stamp. If 10-wonk stamp remains, the total postage is \r\n(3 + 9 + 12 + 13 + 14) = 51 = (17) \r\nThus the postcard took (3 + 14) = 17 wonk, the letter took (9 + 12 + 13) = 34 wonk, and the 10-wonk stamp remains.", "category": "Math", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"I see you have a Madadian stamp there, from the legendary country of MADADIA. Very nice design, especially the picture of Crown Prince Mad Ade eating a kebab. Do you have any more?\" asked Norma Leigh-Sober. \"No. I did have a 3-wonk, a 9-wonk, a 10-wonk, a 12-wonk, a 13-wonk, and a 14-wonk stamp,\" replied Rod Wolloper, \"But at the airport I used five of them to mail a postcard and a letter. The letter took twice as much postage as the postcard, and that left me with only this one stamp.\" \n\r\nWhat was its value (in wonk)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe total value of the stamps is (3 + 9 + 10 + 12 + 13 + 14) = 61 \r\nThe 5 stamps used at the airport totalled a multiple of 3 wonk, so the remaining stamp must be of value = 1(mod 3). The only stamps meeting this condition are the 10-wonk and the 13-wonk. Assume the 13-wonk stamp remains. Then the total postage was \r\n(3 + 9 + 10 + 12 + 14) = 48 = (16) \r\nBut no combination of stamps will make 16, so the 13-wonk must not be the remaining stamp. If 10-wonk stamp remains, the total postage is \r\n(3 + 9 + 12 + 13 + 14) = 51 = (17) \r\nThus the postcard took (3 + 14) = 17 wonk, the letter took (9 + 12 + 13) = 34 wonk, and the 10-wonk stamp remains.\n<|im_start|>answer\nThe total value of the stamps is (3 + 9 + 10 + 12 + 13 + 14) = 61 \r\nThe 5 stamps used at the airport totalled a multiple of 3 wonk, so the remaining stamp must be of value = 1(mod 3). The only stamps meeting this condition are the 10-wonk and the 13-wonk. Assume the 13-wonk stamp remains. Then the total postage was \r\n(3 + 9 + 10 + 12 + 14) = 48 = (16) \r\nBut no combination of stamps will make 16, so the 13-wonk must not be the remaining stamp. If 10-wonk stamp remains, the total postage is \r\n(3 + 9 + 12 + 13 + 14) = 51 = (17) \r\nThus the postcard took (3 + 14) = 17 wonk, the letter took (9 + 12 + 13) = 34 wonk, and the 10-wonk stamp remains.\n<|im_end|>" }, { "id": "#27978", "title": "Red 8's", "fun": 2.33, "difficulty": 2.16, "author": "brules370", "desc": "We wrote down all the 3 digit numbers in an increasing order. We used a red pen for the even numbers digits and a blue pen for the odd numbers digits. How many red 8's are there on the paper?", "hint": "Do it in hundreds. First finds how many 8's there are from 100-199, then 200-299, and so on.", "answer": "From 100-109 there is 1 eight (108). From 110-119 there is another 8. So for every 10 numbers there is one number that has an 8. But, the ten digits from 180-189 are different since the tens column now has an eight. There are 5 even numbers in those 10 digits so there must be 5 eights but 188 has 2 eights and it is an even number. So, that means that there are 6 eights in the 180-188 digits. Altogether, the number of eights from 100-199 is 9+6. Since there are 9 hundred numbers (0-99 doesn't count), it would have been multiplied it by 9 but 800-899 is different so only multiply it by 8. Now, figure out how many eights are in the 800-899 numbers. There are more than 50 since there are 50 even numbers where the eight is the hundreds digit. But, 808, 818, etc have 2 eights. So, add 9 more eights because 880-889 is different. Now we have 8(9+6)+50+9 red 8's. There are 5 even numbers in the 880-889 numbers. So, add 5 but 888 has 3 eights so add 1 more. Now we have 8(9+6)+50+9+5+1. Then, simplify:\r\n8(9+6)+50+9+5+1\r\n=8(15)+50+9+5+1\r\n=120+50+9+5+1\r\n=185\n\r\nSo, the answer is that there are 185 red eights on the paper.", "category": "Logic", "date": "01/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWe wrote down all the 3 digit numbers in an increasing order. We used a red pen for the even numbers digits and a blue pen for the odd numbers digits. How many red 8's are there on the paper?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom 100-109 there is 1 eight (108). From 110-119 there is another 8. So for every 10 numbers there is one number that has an 8. But, the ten digits from 180-189 are different since the tens column now has an eight. There are 5 even numbers in those 10 digits so there must be 5 eights but 188 has 2 eights and it is an even number. So, that means that there are 6 eights in the 180-188 digits. Altogether, the number of eights from 100-199 is 9+6. Since there are 9 hundred numbers (0-99 doesn't count), it would have been multiplied it by 9 but 800-899 is different so only multiply it by 8. Now, figure out how many eights are in the 800-899 numbers. There are more than 50 since there are 50 even numbers where the eight is the hundreds digit. But, 808, 818, etc have 2 eights. So, add 9 more eights because 880-889 is different. Now we have 8(9+6)+50+9 red 8's. There are 5 even numbers in the 880-889 numbers. So, add 5 but 888 has 3 eights so add 1 more. Now we have 8(9+6)+50+9+5+1. Then, simplify:\r\n8(9+6)+50+9+5+1\r\n=8(15)+50+9+5+1\r\n=120+50+9+5+1\r\n=185\n\r\nSo, the answer is that there are 185 red eights on the paper.\n<|im_start|>answer\nFrom 100-109 there is 1 eight (108). From 110-119 there is another 8. So for every 10 numbers there is one number that has an 8. But, the ten digits from 180-189 are different since the tens column now has an eight. There are 5 even numbers in those 10 digits so there must be 5 eights but 188 has 2 eights and it is an even number. So, that means that there are 6 eights in the 180-188 digits. Altogether, the number of eights from 100-199 is 9+6. Since there are 9 hundred numbers (0-99 doesn't count), it would have been multiplied it by 9 but 800-899 is different so only multiply it by 8. Now, figure out how many eights are in the 800-899 numbers. There are more than 50 since there are 50 even numbers where the eight is the hundreds digit. But, 808, 818, etc have 2 eights. So, add 9 more eights because 880-889 is different. Now we have 8(9+6)+50+9 red 8's. There are 5 even numbers in the 880-889 numbers. So, add 5 but 888 has 3 eights so add 1 more. Now we have 8(9+6)+50+9+5+1. Then, simplify:\r\n8(9+6)+50+9+5+1\r\n=8(15)+50+9+5+1\r\n=120+50+9+5+1\r\n=185\n\r\nSo, the answer is that there are 185 red eights on the paper.\n<|im_end|>" }, { "id": "#30013", "title": "Eccentric Optic Solutions", "fun": 2.32, "difficulty": 0.89, "author": "princess0611", "desc": "Gilda and her three best friends, Belinda, Yancy, and Rhonda, all loved to wear glasses that stood out. They would try to find a pair of unique shades every time they went someplace new together to commemorate their trip. On one of their many road trips, they came across a gas station with all kinds of different glasses. They decided that with such a great selection, they would each get a completely different kind. From the following information, determine who got what shape of glasses and the color of each of their pairs.\n\r\nNames - Gilda, Yancy, Belinda, Rhonda\r\nGlasses Shapes - Crescent, Heart, Trapezoid, Cloud\r\nGlasses Colors - Blue, Red, Yellow, Green\n\r\n1) The four friends are Gilda, the one who bought the red glasses, the one who likes clouds, and the one who hates glasses with curvy frames.\n\r\n2) No one has the same first initial in their name as the first letter of the color they chose.\n\r\n3) Yancy did not buy red glasses.\n\r\n4) Belinda hates the color green, and she doesn't like glasses without curves.\n\r\n5) Yancy will only buy glasses with straight-lined frames.\n\r\n6) Rhonda's favorite color is green.\n\r\n7) Gilda loves things that remind her of the night sky.\n\r\n8) The person who had the cloud glasses chose green.", "hint": "No hint available.", "answer": "Gilda - crescent - yellow\r\nYancy - trapezoid - blue\r\nBelinda - heart - red\r\nRhonda - cloud - green", "category": "Logic-Grid", "date": "04/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGilda and her three best friends, Belinda, Yancy, and Rhonda, all loved to wear glasses that stood out. They would try to find a pair of unique shades every time they went someplace new together to commemorate their trip. On one of their many road trips, they came across a gas station with all kinds of different glasses. They decided that with such a great selection, they would each get a completely different kind. From the following information, determine who got what shape of glasses and the color of each of their pairs.\n\r\nNames - Gilda, Yancy, Belinda, Rhonda\r\nGlasses Shapes - Crescent, Heart, Trapezoid, Cloud\r\nGlasses Colors - Blue, Red, Yellow, Green\n\r\n1) The four friends are Gilda, the one who bought the red glasses, the one who likes clouds, and the one who hates glasses with curvy frames.\n\r\n2) No one has the same first initial in their name as the first letter of the color they chose.\n\r\n3) Yancy did not buy red glasses.\n\r\n4) Belinda hates the color green, and she doesn't like glasses without curves.\n\r\n5) Yancy will only buy glasses with straight-lined frames.\n\r\n6) Rhonda's favorite color is green.\n\r\n7) Gilda loves things that remind her of the night sky.\n\r\n8) The person who had the cloud glasses chose green.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGilda - crescent - yellow\r\nYancy - trapezoid - blue\r\nBelinda - heart - red\r\nRhonda - cloud - green\n<|im_start|>answer\nGilda - crescent - yellow\r\nYancy - trapezoid - blue\r\nBelinda - heart - red\r\nRhonda - cloud - green\n<|im_end|>" }, { "id": "#49376", "title": "After School", "fun": 2.32, "difficulty": 0.76, "author": "babyjuice", "desc": "Cameron, Kiara, Mike and Teresa each play different sports after school. Based on the clues below, can you determine each person's first name and last name and the sport that each of them plays?\n\r\nNames: Cameron, Kiara, Mike, Teresa\r\nLast Names: Phillips, Neal, Thomas, Stallworth\r\nSport: Soccer, swimming, basketball, tennis\n\r\nClues:\r\n1. Teresa, Cameron, and the Thomas boy all play a sport that uses a ball.\r\n2. Kiara and her friend, the Neal child, ride home from practice together. The child who plays tennis and Teresa ride separate buses home.\r\n3. Cameron thinks it's a pain to have to put on shin guards before he plays his sport, even though they do keep him from getting hurt. The Stallworth girl is glad that all she has to wear are shorts and a T-shirt to play her sport", "hint": "No hint available.", "answer": "Mike Thomas plays tennis.\r\nKiara Phillips swims.\r\nCameron Neal plays soccer.\r\nTeresa Stallworth plays basketball.", "category": "Logic-Grid", "date": "03/19/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCameron, Kiara, Mike and Teresa each play different sports after school. Based on the clues below, can you determine each person's first name and last name and the sport that each of them plays?\n\r\nNames: Cameron, Kiara, Mike, Teresa\r\nLast Names: Phillips, Neal, Thomas, Stallworth\r\nSport: Soccer, swimming, basketball, tennis\n\r\nClues:\r\n1. Teresa, Cameron, and the Thomas boy all play a sport that uses a ball.\r\n2. Kiara and her friend, the Neal child, ride home from practice together. The child who plays tennis and Teresa ride separate buses home.\r\n3. Cameron thinks it's a pain to have to put on shin guards before he plays his sport, even though they do keep him from getting hurt. The Stallworth girl is glad that all she has to wear are shorts and a T-shirt to play her sport\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike Thomas plays tennis.\r\nKiara Phillips swims.\r\nCameron Neal plays soccer.\r\nTeresa Stallworth plays basketball.\n<|im_start|>answer\nMike Thomas plays tennis.\r\nKiara Phillips swims.\r\nCameron Neal plays soccer.\r\nTeresa Stallworth plays basketball.\n<|im_end|>" }, { "id": "#13841", "title": "Which Job?", "fun": 2.32, "difficulty": 1.19, "author": "cccc", "desc": "Person A, B, and C all have a job.\r\nOne is a laborer, one is a farmer, and one is a soldier. You know:\n\r\nC is older than the soldier.\n\r\nA is not the same age as the farmer.\n\r\nThe farmer is younger than B.\n\r\nWho has what occupation?", "hint": "No hint available.", "answer": "A is the soldier, B is the laborer, C is the farmer.\n\r\nObviously, A and B are not the farmer.\n\r\nFrom the first clue and third clue we know C is not the soldier, because C the farmer is older than the soldier, and the farmer (C) is younger than B, thus B must be the laborer. \n\r\nAnd then A is the soldier.", "category": "Logic", "date": "07/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPerson A, B, and C all have a job.\r\nOne is a laborer, one is a farmer, and one is a soldier. You know:\n\r\nC is older than the soldier.\n\r\nA is not the same age as the farmer.\n\r\nThe farmer is younger than B.\n\r\nWho has what occupation?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA is the soldier, B is the laborer, C is the farmer.\n\r\nObviously, A and B are not the farmer.\n\r\nFrom the first clue and third clue we know C is not the soldier, because C the farmer is older than the soldier, and the farmer (C) is younger than B, thus B must be the laborer. \n\r\nAnd then A is the soldier.\n<|im_start|>answer\nA is the soldier, B is the laborer, C is the farmer.\n\r\nObviously, A and B are not the farmer.\n\r\nFrom the first clue and third clue we know C is not the soldier, because C the farmer is older than the soldier, and the farmer (C) is younger than B, thus B must be the laborer. \n\r\nAnd then A is the soldier.\n<|im_end|>" }, { "id": "#5126", "title": "9 Times the Sum", "fun": 2.32, "difficulty": 1.1, "author": "Cascas", "desc": "There is a number that is 9 times the sum of its digits. What is this number?", "hint": "No hint available.", "answer": "81", "category": "Math", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a number that is 9 times the sum of its digits. What is this number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n81\n<|im_start|>answer\n81\n<|im_end|>" }, { "id": "#4429", "title": "Vampires", "fun": 2.32, "difficulty": 2.96, "author": "im_para_noid", "desc": "Vampire numbers are the products of two progenitor numbers that when multiplied survive, scrambled together, in the vampire number. Consider one such case: 27x81=2,187. Another vampire number is 1,435, which is the product of 35 and 41. Find others.", "hint": "No hint available.", "answer": "21x60=1,260\r\n15x93=1,395\r\n1,234,554,321 x 9,162,361,086 = 11,311,432,469,283,552,606 with others that also work", "category": "Math", "date": "06/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nVampire numbers are the products of two progenitor numbers that when multiplied survive, scrambled together, in the vampire number. Consider one such case: 27x81=2,187. Another vampire number is 1,435, which is the product of 35 and 41. Find others.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21x60=1,260\r\n15x93=1,395\r\n1,234,554,321 x 9,162,361,086 = 11,311,432,469,283,552,606 with others that also work\n<|im_start|>answer\n21x60=1,260\r\n15x93=1,395\r\n1,234,554,321 x 9,162,361,086 = 11,311,432,469,283,552,606 with others that also work\n<|im_end|>" }, { "id": "#4346", "title": "Beggars", "fun": 2.32, "difficulty": 1.8900000000000001, "author": "mad-ade", "desc": "In the legendary country of MADADIA. Crowned Prince Mad Ade the second said: \"If I were to give seven coins to each beggar at my door, I would have twenty-four coins left. I lack thirty-two coins for being able to give them nine coins apiece.\"\n\r\nHow many beggars were there, and how many coins did Crowned Prince Mad Ade have?", "hint": "No hint available.", "answer": "28 beggars and 220 coins", "category": "Math", "date": "05/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary country of MADADIA. Crowned Prince Mad Ade the second said: \"If I were to give seven coins to each beggar at my door, I would have twenty-four coins left. I lack thirty-two coins for being able to give them nine coins apiece.\"\n\r\nHow many beggars were there, and how many coins did Crowned Prince Mad Ade have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n28 beggars and 220 coins\n<|im_start|>answer\n28 beggars and 220 coins\n<|im_end|>" }, { "id": "#1957", "title": "Painting a Room", "fun": 2.32, "difficulty": 1.52, "author": "missie", "desc": "A man can paint a room in four hours, and another man can paint the room in two hours. How long would it take if they worked together?", "hint": "No hint available.", "answer": "80 minutes.\n\r\nMan A can paint a room in 2 h:\r\n1 room/2 hours\n\r\nMan B can paint a room in 4 h:\r\n1 room/4 hours\n\r\nAdd the times together with the lowest common denominator of 4:\r\n2/4 + 1/4 = 3 rooms/4 hours\n\r\nWe know how long it takes to do three rooms, but we want to know how long it would take to paint one:\r\n3 divided by 3 = 1\r\n4 divided by 3 = 1.333... or 1 1/3 h\n\r\n1 1/3 h = 80 minutes", "category": "Math", "date": "01/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man can paint a room in four hours, and another man can paint the room in two hours. How long would it take if they worked together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n80 minutes.\n\r\nMan A can paint a room in 2 h:\r\n1 room/2 hours\n\r\nMan B can paint a room in 4 h:\r\n1 room/4 hours\n\r\nAdd the times together with the lowest common denominator of 4:\r\n2/4 + 1/4 = 3 rooms/4 hours\n\r\nWe know how long it takes to do three rooms, but we want to know how long it would take to paint one:\r\n3 divided by 3 = 1\r\n4 divided by 3 = 1.333... or 1 1/3 h\n\r\n1 1/3 h = 80 minutes\n<|im_start|>answer\n80 minutes.\n\r\nMan A can paint a room in 2 h:\r\n1 room/2 hours\n\r\nMan B can paint a room in 4 h:\r\n1 room/4 hours\n\r\nAdd the times together with the lowest common denominator of 4:\r\n2/4 + 1/4 = 3 rooms/4 hours\n\r\nWe know how long it takes to do three rooms, but we want to know how long it would take to paint one:\r\n3 divided by 3 = 1\r\n4 divided by 3 = 1.333... or 1 1/3 h\n\r\n1 1/3 h = 80 minutes\n<|im_end|>" }, { "id": "#1464", "title": "Chess Game", "fun": 2.32, "difficulty": 1.2, "author": "sam7630", "desc": "There were two men playing chess. They played 5 games, and each man won 3 games. How is this possible if they did not tie any games?", "hint": "How many men were playing?", "answer": "The men weren't playing each other. It never said they were. They were playing other people, and during the five games, each man won 3 of the five.", "category": "Logic", "date": "11/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were two men playing chess. They played 5 games, and each man won 3 games. How is this possible if they did not tie any games?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe men weren't playing each other. It never said they were. They were playing other people, and during the five games, each man won 3 of the five.\n<|im_start|>answer\nThe men weren't playing each other. It never said they were. They were playing other people, and during the five games, each man won 3 of the five.\n<|im_end|>" }, { "id": "#50002", "title": "Difficult Danny 2", "fun": 2.32, "difficulty": 2.68, "author": "eighsse", "desc": "Difficult Danny has acquired his nickname (and some other, less polite nicknames) due to the fact that, whenever he buys anything, he insists upon paying the exact amount, with precisely 100 pieces of currency. Danny wanted an xCube365 (it lasts 365 days before programmatically disabling itself, so that a new one must be purchased), the highly coveted gaming system that had just been released. It cost $230, but he managed to save up enough to buy one. He paid using some quantity (possibly zero) of each the following denominations of bills: $1, $5, $10, $20, $50, and $100. Of those six quantities (including any zeros), there is one -- and ONLY one -- distinct triplet that can be made into a true multiplication sentence. For example, if there were 2 ones, 3 twenties, and 6 tens, 2 x 3 = 6, so this would fit the rule. How many of each denomination did Danny use to buy the xCube365?", "hint": "No hint available.", "answer": "Can at least one of each denomination be used? That totals $186 with only 6 bills, plus at least $94 with the rest of the bills. This is too high. Can two or more of the denominations not be used? Any number multiplied by 0 is 0. Therefore, if there are two or more 0 quantities, any of the other three could be multiplied by one of the 0's, using the other 0 for the result. This means that there would be more than one triplet that fits the rule. So we know that exactly 5 of the 6 denominations are used.\n\r\nIf a $100 bill is used, there are only two combinations that have the proper total quantity of bills and dollar sum, but they both involve two 0-quantities. So $100 bill is the denomination that is not used. We now know that at least one of each of the other bills is used. That totals $86 with 5 bills, leaving 95 bills to make the other $144.\n\r\nThere are only 4 ways to make $144 with these denominations, which are listed in order from $1 bills to $50 bills in each of these sets: {84,10,1,0,0}, {89,1,5,0,0}, {89,3,2,1,0}, {94,0,0,0,1}. Adding in one of each bill, which we have already determined, gives {85,11,2,1,1}, {90,2,6,1,1}, {90,4,3,2,1}, {95,1,1,1,2}. {1,1,1} is the only triplet here that can make a true multiplication sentence: 1 x 1 = 1. Therefore, Danny paid with 95 $1 bills, a $5 bill, a $10 bill, a $20 bill, and 2 $50 bills.", "category": "Math", "date": "11/24/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDifficult Danny has acquired his nickname (and some other, less polite nicknames) due to the fact that, whenever he buys anything, he insists upon paying the exact amount, with precisely 100 pieces of currency. Danny wanted an xCube365 (it lasts 365 days before programmatically disabling itself, so that a new one must be purchased), the highly coveted gaming system that had just been released. It cost $230, but he managed to save up enough to buy one. He paid using some quantity (possibly zero) of each the following denominations of bills: $1, $5, $10, $20, $50, and $100. Of those six quantities (including any zeros), there is one -- and ONLY one -- distinct triplet that can be made into a true multiplication sentence. For example, if there were 2 ones, 3 twenties, and 6 tens, 2 x 3 = 6, so this would fit the rule. How many of each denomination did Danny use to buy the xCube365?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCan at least one of each denomination be used? That totals $186 with only 6 bills, plus at least $94 with the rest of the bills. This is too high. Can two or more of the denominations not be used? Any number multiplied by 0 is 0. Therefore, if there are two or more 0 quantities, any of the other three could be multiplied by one of the 0's, using the other 0 for the result. This means that there would be more than one triplet that fits the rule. So we know that exactly 5 of the 6 denominations are used.\n\r\nIf a $100 bill is used, there are only two combinations that have the proper total quantity of bills and dollar sum, but they both involve two 0-quantities. So $100 bill is the denomination that is not used. We now know that at least one of each of the other bills is used. That totals $86 with 5 bills, leaving 95 bills to make the other $144.\n\r\nThere are only 4 ways to make $144 with these denominations, which are listed in order from $1 bills to $50 bills in each of these sets: {84,10,1,0,0}, {89,1,5,0,0}, {89,3,2,1,0}, {94,0,0,0,1}. Adding in one of each bill, which we have already determined, gives {85,11,2,1,1}, {90,2,6,1,1}, {90,4,3,2,1}, {95,1,1,1,2}. {1,1,1} is the only triplet here that can make a true multiplication sentence: 1 x 1 = 1. Therefore, Danny paid with 95 $1 bills, a $5 bill, a $10 bill, a $20 bill, and 2 $50 bills.\n<|im_start|>answer\nCan at least one of each denomination be used? That totals $186 with only 6 bills, plus at least $94 with the rest of the bills. This is too high. Can two or more of the denominations not be used? Any number multiplied by 0 is 0. Therefore, if there are two or more 0 quantities, any of the other three could be multiplied by one of the 0's, using the other 0 for the result. This means that there would be more than one triplet that fits the rule. So we know that exactly 5 of the 6 denominations are used.\n\r\nIf a $100 bill is used, there are only two combinations that have the proper total quantity of bills and dollar sum, but they both involve two 0-quantities. So $100 bill is the denomination that is not used. We now know that at least one of each of the other bills is used. That totals $86 with 5 bills, leaving 95 bills to make the other $144.\n\r\nThere are only 4 ways to make $144 with these denominations, which are listed in order from $1 bills to $50 bills in each of these sets: {84,10,1,0,0}, {89,1,5,0,0}, {89,3,2,1,0}, {94,0,0,0,1}. Adding in one of each bill, which we have already determined, gives {85,11,2,1,1}, {90,2,6,1,1}, {90,4,3,2,1}, {95,1,1,1,2}. {1,1,1} is the only triplet here that can make a true multiplication sentence: 1 x 1 = 1. Therefore, Danny paid with 95 $1 bills, a $5 bill, a $10 bill, a $20 bill, and 2 $50 bills.\n<|im_end|>" }, { "id": "#40615", "title": "Hats Color", "fun": 2.32, "difficulty": 1.65, "author": "Carlos16", "desc": "Five men are standing in a circle. They know they are wearing at least 2 white hats and at least 2 black hats (no hats are any other colors). They do not know what color hat they are wearing. If the men use logic, how many of them will figure out what color their hat is, if nobody says anything?", "hint": "No hint available.", "answer": "Two men will see three hats of the same color, and one hat of a different color. Since they know there cannot be four hats with the same color, they will know their hat color is the same as the one man with the different colored hat. The two people who see those colors will know their hat color. The other three will see a balanced number of hat colors, so they won't know what color their hat is.\n\r\nAnswer: 2", "category": "Logic", "date": "02/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive men are standing in a circle. They know they are wearing at least 2 white hats and at least 2 black hats (no hats are any other colors). They do not know what color hat they are wearing. If the men use logic, how many of them will figure out what color their hat is, if nobody says anything?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwo men will see three hats of the same color, and one hat of a different color. Since they know there cannot be four hats with the same color, they will know their hat color is the same as the one man with the different colored hat. The two people who see those colors will know their hat color. The other three will see a balanced number of hat colors, so they won't know what color their hat is.\n\r\nAnswer: 2\n<|im_start|>answer\nTwo men will see three hats of the same color, and one hat of a different color. Since they know there cannot be four hats with the same color, they will know their hat color is the same as the one man with the different colored hat. The two people who see those colors will know their hat color. The other three will see a balanced number of hat colors, so they won't know what color their hat is.\n\r\nAnswer: 2\n<|im_end|>" }, { "id": "#17225", "title": "Wheel 2", "fun": 2.32, "difficulty": 2.36, "author": "slob", "desc": "Consider a vertical wheel of radius 10 cm. Now suppose a smaller wheel of radius 2 cm, is made to roll around the larger wheel in the same vertical plane while the larger wheel remains fixed. What is the total number of rotations the smaller wheel makes when its center makes one complete rotation about the larger wheel?", "hint": "No hint available.", "answer": "The correct answer is 6 rotations. Suppose you rotate the smaller wheel and the larger wheel together without rolling through one rotation clockwise, the small wheel has rotated through 1 turn clockwise. Now rotate the larger wheel back to its original position counter-clockwise through one rotation at the same time holding the center of the small wheel in the original position but allowing the wheel to rotate without sliding. It will rotate through 5 more turns due to the ratio of the circumferences of the wheels. The total number of rotations of the small wheel is 5 + 1 = 6.", "category": "Math", "date": "04/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nConsider a vertical wheel of radius 10 cm. Now suppose a smaller wheel of radius 2 cm, is made to roll around the larger wheel in the same vertical plane while the larger wheel remains fixed. What is the total number of rotations the smaller wheel makes when its center makes one complete rotation about the larger wheel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe correct answer is 6 rotations. Suppose you rotate the smaller wheel and the larger wheel together without rolling through one rotation clockwise, the small wheel has rotated through 1 turn clockwise. Now rotate the larger wheel back to its original position counter-clockwise through one rotation at the same time holding the center of the small wheel in the original position but allowing the wheel to rotate without sliding. It will rotate through 5 more turns due to the ratio of the circumferences of the wheels. The total number of rotations of the small wheel is 5 + 1 = 6.\n<|im_start|>answer\nThe correct answer is 6 rotations. Suppose you rotate the smaller wheel and the larger wheel together without rolling through one rotation clockwise, the small wheel has rotated through 1 turn clockwise. Now rotate the larger wheel back to its original position counter-clockwise through one rotation at the same time holding the center of the small wheel in the original position but allowing the wheel to rotate without sliding. It will rotate through 5 more turns due to the ratio of the circumferences of the wheels. The total number of rotations of the small wheel is 5 + 1 = 6.\n<|im_end|>" }, { "id": "#1259", "title": "Number Perplexer", "fun": 2.32, "difficulty": 1.97, "author": "dcs47", "desc": "Place two plus signs (+) and one minus sign (-) between these numbers in such a way that you get the answer shown.\r\n7 6 5 4 3 2 1 =535", "hint": "No hint available.", "answer": "7+6+543-21=535", "category": "Math", "date": "11/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlace two plus signs (+) and one minus sign (-) between these numbers in such a way that you get the answer shown.\r\n7 6 5 4 3 2 1 =535\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7+6+543-21=535\n<|im_start|>answer\n7+6+543-21=535\n<|im_end|>" }, { "id": "#32430", "title": "CrossDigit 2", "fun": 2.32, "difficulty": 2.02, "author": "dishu", "desc": "This teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 3 by 3 grid. The grid is arranged as follows:\n\r\nA1 A2 A3\r\nB1 B2 B3\r\nC1 C2 C3\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row can have the same digit appearing more than once.\r\n2: No column can have the same digit appearing more than once.\r\n3: 0 (Zero) is not permissible.\r\n4: Empty spaces cannot contain any digits. They are empty.\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A1 and C3.\r\n2. The sum of digits in row A equal 3.\r\n3. The sum of digits in row B equal 20.\r\n4. The sum of digits in row C equal 10.\r\n5. The sum of digits in column 1 equal 16.\r\n6. The sum of digits in column 2 equal 13.\r\n7. The sum of digits in column 3 equal 4.\n\r\nNow figure out which box contains which digit and do not forget the rules.", "hint": "A number can be present more than once in the grid, but not the same row or column.", "answer": "The digits are laid out as follows:\r\nA1: Blank, A2: 2, A3: 1\r\nB1: 9, B2: 8, B3: 3\r\nC1: 7, C2: 3, C3: Blank", "category": "Math", "date": "08/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 3 by 3 grid. The grid is arranged as follows:\n\r\nA1 A2 A3\r\nB1 B2 B3\r\nC1 C2 C3\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row can have the same digit appearing more than once.\r\n2: No column can have the same digit appearing more than once.\r\n3: 0 (Zero) is not permissible.\r\n4: Empty spaces cannot contain any digits. They are empty.\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A1 and C3.\r\n2. The sum of digits in row A equal 3.\r\n3. The sum of digits in row B equal 20.\r\n4. The sum of digits in row C equal 10.\r\n5. The sum of digits in column 1 equal 16.\r\n6. The sum of digits in column 2 equal 13.\r\n7. The sum of digits in column 3 equal 4.\n\r\nNow figure out which box contains which digit and do not forget the rules.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe digits are laid out as follows:\r\nA1: Blank, A2: 2, A3: 1\r\nB1: 9, B2: 8, B3: 3\r\nC1: 7, C2: 3, C3: Blank\n<|im_start|>answer\nThe digits are laid out as follows:\r\nA1: Blank, A2: 2, A3: 1\r\nB1: 9, B2: 8, B3: 3\r\nC1: 7, C2: 3, C3: Blank\n<|im_end|>" }, { "id": "#4582", "title": "Shopping Trip", "fun": 2.32, "difficulty": 1.29, "author": "mad-ade", "desc": "Mad Ade went to town with £50, but returned at night with £150. He \r\nbought a hat at a clothing store and a mega sized Kebab from the \"Sweaty Chef\" kebab shop, then he had his eyes tested.\n\r\nHere are a few facts: \r\nMad Ade gets paid every Thursday by check. \r\nThe banks are only open on Tuesdays, Thursdays, and Saturdays. \r\nThe eye doctor is closed on Saturday. \r\nThe \"Sweaty Chef\" kebab shop is closed on Thursday and Friday. \n\r\nOn what day did Mad Ade go to town?", "hint": "No hint available.", "answer": "Tuesday.\n\n\r\nSolution:\r\nSince Mad Ade returned with more money that he left with, he must have\r\ngone on a day when the bank was open. So he must have gone on\r\nTuesday, Thursday, or Saturday. But, he got his eyes tested, and \r\nsince the eye doctor is closed on Saturday, it couldn't have been \r\nSaturday. He also went to the \"Sweaty Chef\" which is closed Thursday and\r\nFriday, so that eliminates Thursday, so it must have been a \r\nTuesday when that Mad Ade went to town.", "category": "Logic", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade went to town with £50, but returned at night with £150. He \r\nbought a hat at a clothing store and a mega sized Kebab from the \"Sweaty Chef\" kebab shop, then he had his eyes tested.\n\r\nHere are a few facts: \r\nMad Ade gets paid every Thursday by check. \r\nThe banks are only open on Tuesdays, Thursdays, and Saturdays. \r\nThe eye doctor is closed on Saturday. \r\nThe \"Sweaty Chef\" kebab shop is closed on Thursday and Friday. \n\r\nOn what day did Mad Ade go to town?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTuesday.\n\n\r\nSolution:\r\nSince Mad Ade returned with more money that he left with, he must have\r\ngone on a day when the bank was open. So he must have gone on\r\nTuesday, Thursday, or Saturday. But, he got his eyes tested, and \r\nsince the eye doctor is closed on Saturday, it couldn't have been \r\nSaturday. He also went to the \"Sweaty Chef\" which is closed Thursday and\r\nFriday, so that eliminates Thursday, so it must have been a \r\nTuesday when that Mad Ade went to town.\n<|im_start|>answer\nTuesday.\n\n\r\nSolution:\r\nSince Mad Ade returned with more money that he left with, he must have\r\ngone on a day when the bank was open. So he must have gone on\r\nTuesday, Thursday, or Saturday. But, he got his eyes tested, and \r\nsince the eye doctor is closed on Saturday, it couldn't have been \r\nSaturday. He also went to the \"Sweaty Chef\" which is closed Thursday and\r\nFriday, so that eliminates Thursday, so it must have been a \r\nTuesday when that Mad Ade went to town.\n<|im_end|>" }, { "id": "#43855", "title": "What Time 2", "fun": 2.32, "difficulty": 1.08, "author": "twin27", "desc": "Chris was worried about a math test coming up, so he asked his teacher if he could stay after school so she could help him study. She said 'yes' and gave him a note, but to his surprise, it said:\n\r\n2^6*5^2\n\r\nWhat time did the teacher mean?", "hint": "No hint available.", "answer": "2^6*5^2 is 1600. 1600 would be 16:00, which in military time is 4:00 PM.\n\r\nChris walked into his teacher's room at 4:00 after school.\n\r\n\"How did you know to come at this time?\" his teacher asked.\n\r\n\"Well, I just did the math,\" said Chris, \"and that's the prime factorization of 1600, and 16:00 is military time for 4:00.\" \n\r\n\"You know all you need to,\" said the teacher.", "category": "Math", "date": "01/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChris was worried about a math test coming up, so he asked his teacher if he could stay after school so she could help him study. She said 'yes' and gave him a note, but to his surprise, it said:\n\r\n2^6*5^2\n\r\nWhat time did the teacher mean?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2^6*5^2 is 1600. 1600 would be 16:00, which in military time is 4:00 PM.\n\r\nChris walked into his teacher's room at 4:00 after school.\n\r\n\"How did you know to come at this time?\" his teacher asked.\n\r\n\"Well, I just did the math,\" said Chris, \"and that's the prime factorization of 1600, and 16:00 is military time for 4:00.\" \n\r\n\"You know all you need to,\" said the teacher.\n<|im_start|>answer\n2^6*5^2 is 1600. 1600 would be 16:00, which in military time is 4:00 PM.\n\r\nChris walked into his teacher's room at 4:00 after school.\n\r\n\"How did you know to come at this time?\" his teacher asked.\n\r\n\"Well, I just did the math,\" said Chris, \"and that's the prime factorization of 1600, and 16:00 is military time for 4:00.\" \n\r\n\"You know all you need to,\" said the teacher.\n<|im_end|>" }, { "id": "#2274", "title": "Mixed up Check", "fun": 2.32, "difficulty": 2.39, "author": "RayneeDay", "desc": "Slick Sammy once cashed a check at the bank. He had spent $0.68 before he realised that the bank clerk had made a mistake. He had transposed the dollars with the cents. Sammy now had exactly 2 times the value of the original check. What was the value of the original check?", "hint": "No hint available.", "answer": "The original check was for $10.21", "category": "Math", "date": "02/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSlick Sammy once cashed a check at the bank. He had spent $0.68 before he realised that the bank clerk had made a mistake. He had transposed the dollars with the cents. Sammy now had exactly 2 times the value of the original check. What was the value of the original check?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe original check was for $10.21\n<|im_start|>answer\nThe original check was for $10.21\n<|im_end|>" }, { "id": "#2871", "title": "Blindfolded Money Bowl", "fun": 2.32, "difficulty": 1.35, "author": "204_BLaZe_41", "desc": "If you were blindfolded and placed in front of a large bowl containing $50, $20, $10, and $5 bills, and you were allowed to take one bill at a time until you have taken four bills of the same denomination, what would be the largest amount of money you could draw?", "hint": "No hint available.", "answer": "$305. You could take 3-$50's. 3-$20's. 3-$10's. 3-$5's. And the last bill would be another $50 bill.", "category": "Math", "date": "03/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you were blindfolded and placed in front of a large bowl containing $50, $20, $10, and $5 bills, and you were allowed to take one bill at a time until you have taken four bills of the same denomination, what would be the largest amount of money you could draw?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$305. You could take 3-$50's. 3-$20's. 3-$10's. 3-$5's. And the last bill would be another $50 bill.\n<|im_start|>answer\n$305. You could take 3-$50's. 3-$20's. 3-$10's. 3-$5's. And the last bill would be another $50 bill.\n<|im_end|>" }, { "id": "#13688", "title": "Fill the Letters", "fun": 2.32, "difficulty": 1.8, "author": "cccc", "desc": "Each of the letters used in the equation below represents a number. For example, each \"H\" represents the same number.\n\r\nFill in all of the numbers. \n\r\nHE \r\n+ HE \r\n+ HE \r\n+ HE \r\n----- \r\nAH", "hint": "No hint available.", "answer": "23 \r\n+ 23 \r\n+ 23 \r\n+ 23 \r\n----- \r\n92", "category": "Math", "date": "07/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach of the letters used in the equation below represents a number. For example, each \"H\" represents the same number.\n\r\nFill in all of the numbers. \n\r\nHE \r\n+ HE \r\n+ HE \r\n+ HE \r\n----- \r\nAH\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n23 \r\n+ 23 \r\n+ 23 \r\n+ 23 \r\n----- \r\n92\n<|im_start|>answer\n23 \r\n+ 23 \r\n+ 23 \r\n+ 23 \r\n----- \r\n92\n<|im_end|>" }, { "id": "#48606", "title": "Fold Twice", "fun": 2.32, "difficulty": 2.0, "author": "shenqiang", "desc": "Fold a square piece of paper twice to form a smaller square, then cut it in half diagonally.\n\r\nHow many pieces is the paper cut to?", "hint": "A square has 2 diagonals.", "answer": "4 or 5.\n\r\nIt has 2 possibilities.\r\nCutting on one diagonal yields 4 triangles; cutting on the other diagonal yields 4 triangles and a square.\r\nIf the area of the original square paper is 16, it's possible to cut into 4 triangles of area 4 each, or 4 triangles of area 2 each and 1 square of area 8.", "category": "Math", "date": "03/29/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFold a square piece of paper twice to form a smaller square, then cut it in half diagonally.\n\r\nHow many pieces is the paper cut to?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 or 5.\n\r\nIt has 2 possibilities.\r\nCutting on one diagonal yields 4 triangles; cutting on the other diagonal yields 4 triangles and a square.\r\nIf the area of the original square paper is 16, it's possible to cut into 4 triangles of area 4 each, or 4 triangles of area 2 each and 1 square of area 8.\n<|im_start|>answer\n4 or 5.\n\r\nIt has 2 possibilities.\r\nCutting on one diagonal yields 4 triangles; cutting on the other diagonal yields 4 triangles and a square.\r\nIf the area of the original square paper is 16, it's possible to cut into 4 triangles of area 4 each, or 4 triangles of area 2 each and 1 square of area 8.\n<|im_end|>" }, { "id": "#4572", "title": "Fishing Trip", "fun": 2.32, "difficulty": 1.13, "author": "golffreak7205", "desc": "Bob went out to buy some fishing equipment. He spent half of what he had plus $5 at the first store. At the second store, he spent half of what was left plus $4, and at the third store, he spent half of the remainder plus $3. He then had $5 left to put aside for bait. How much money did he start with?", "hint": "No hint available.", "answer": "$90.00", "category": "Math", "date": "06/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob went out to buy some fishing equipment. He spent half of what he had plus $5 at the first store. At the second store, he spent half of what was left plus $4, and at the third store, he spent half of the remainder plus $3. He then had $5 left to put aside for bait. How much money did he start with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$90.00\n<|im_start|>answer\n$90.00\n<|im_end|>" }, { "id": "#360", "title": "Such a Deal!", "fun": 2.32, "difficulty": 1.99, "author": "Phyllis", "desc": "A man received an ad in the mail that promised to double his money. For every dollar he sent in, the ad guaranteed to return double his money minus a $24 service charge. He thought that was a pretty good deal, so he sent in his money. In the return mail he received double his money less the $24 service charge. He returned the money he had made and again it was doubled less the service charge. But, when he sent in the money a third time, he was charged the $24 service fee, but received no money back. How much money did the man lose?", "hint": "Work backwards.", "answer": "He lost $21. Work backwards. If his last payment was doubled, less $24, it must have been $12. Payment two must have been $18, and payment one $21.", "category": "Math", "date": "03/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man received an ad in the mail that promised to double his money. For every dollar he sent in, the ad guaranteed to return double his money minus a $24 service charge. He thought that was a pretty good deal, so he sent in his money. In the return mail he received double his money less the $24 service charge. He returned the money he had made and again it was doubled less the service charge. But, when he sent in the money a third time, he was charged the $24 service fee, but received no money back. How much money did the man lose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe lost $21. Work backwards. If his last payment was doubled, less $24, it must have been $12. Payment two must have been $18, and payment one $21.\n<|im_start|>answer\nHe lost $21. Work backwards. If his last payment was doubled, less $24, it must have been $12. Payment two must have been $18, and payment one $21.\n<|im_end|>" }, { "id": "#7649", "title": "Madadian Army", "fun": 2.32, "difficulty": 2.49, "author": "mad-ade", "desc": "Major Steve is forming a five-person Special Task Group for the Madadian army. The group must contain one leader, two bomb-experts and two soldiers. \n\r\nP, Q and R are possible bomb-experts. R, S and T are possible leaders. U, V and W are possible soldiers. Also, P and R prefers to work with each other in the same team. T prefers to work only if V works. \n\r\nHow many different possible Groups can Major Steve make?", "hint": "No hint available.", "answer": "Major Steve can make 8 different possible groups. \n\r\nAs 2 bomb-experts to be selected from the given 3 and also P & R prefers to work together, PR must be there in all the possible Groups. Also, T prefers to work only if V works. It doesn't mean that V won't work without T. \n\r\nHence, possible groups are: \r\nPR - S - UV \r\nPR - S - VW \r\nPR - S - WU \n\r\nPR - T - UV \r\nPR - T - VW \n\r\nPQ - R - UV \r\nPQ - R - VW \r\nPQ - R - WU \n\r\nHence, 8 different groups are possible.", "category": "Logic", "date": "09/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMajor Steve is forming a five-person Special Task Group for the Madadian army. The group must contain one leader, two bomb-experts and two soldiers. \n\r\nP, Q and R are possible bomb-experts. R, S and T are possible leaders. U, V and W are possible soldiers. Also, P and R prefers to work with each other in the same team. T prefers to work only if V works. \n\r\nHow many different possible Groups can Major Steve make?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMajor Steve can make 8 different possible groups. \n\r\nAs 2 bomb-experts to be selected from the given 3 and also P & R prefers to work together, PR must be there in all the possible Groups. Also, T prefers to work only if V works. It doesn't mean that V won't work without T. \n\r\nHence, possible groups are: \r\nPR - S - UV \r\nPR - S - VW \r\nPR - S - WU \n\r\nPR - T - UV \r\nPR - T - VW \n\r\nPQ - R - UV \r\nPQ - R - VW \r\nPQ - R - WU \n\r\nHence, 8 different groups are possible.\n<|im_start|>answer\nMajor Steve can make 8 different possible groups. \n\r\nAs 2 bomb-experts to be selected from the given 3 and also P & R prefers to work together, PR must be there in all the possible Groups. Also, T prefers to work only if V works. It doesn't mean that V won't work without T. \n\r\nHence, possible groups are: \r\nPR - S - UV \r\nPR - S - VW \r\nPR - S - WU \n\r\nPR - T - UV \r\nPR - T - VW \n\r\nPQ - R - UV \r\nPQ - R - VW \r\nPQ - R - WU \n\r\nHence, 8 different groups are possible.\n<|im_end|>" }, { "id": "#43444", "title": "Light Foot Fisher", "fun": 2.32, "difficulty": 0.98, "author": "Gerrard10", "desc": "There are two men fishing in the middle of a lake. They are doing well when a man calls from the edge of the lake and asks to join them. They say yes and he gathers his bait and rod and goes to them. The lake is fairly deep but the fisherman just walks over to them and starts to fish. How?", "hint": "No hint available.", "answer": "The men are ice fishing. The man can walk across the lake because it is ice.", "category": "Logic", "date": "10/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two men fishing in the middle of a lake. They are doing well when a man calls from the edge of the lake and asks to join them. They say yes and he gathers his bait and rod and goes to them. The lake is fairly deep but the fisherman just walks over to them and starts to fish. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe men are ice fishing. The man can walk across the lake because it is ice.\n<|im_start|>answer\nThe men are ice fishing. The man can walk across the lake because it is ice.\n<|im_end|>" }, { "id": "#5384", "title": "Goose Eggs", "fun": 2.32, "difficulty": 0.5700000000000001, "author": "im_para_noid", "desc": "If it takes twenty minutes to hard-boil one goose egg, how long will it take to hard-boil four goose eggs?", "hint": "No hint available.", "answer": "20 minutes; 4 eggs can be boiled at the same time.", "category": "Logic", "date": "07/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf it takes twenty minutes to hard-boil one goose egg, how long will it take to hard-boil four goose eggs?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20 minutes; 4 eggs can be boiled at the same time.\n<|im_start|>answer\n20 minutes; 4 eggs can be boiled at the same time.\n<|im_end|>" }, { "id": "#32676", "title": "Be Perfectly Frank", "fun": 2.32, "difficulty": 1.2, "author": "hottiexo247", "desc": "A hot dog vendor at a soccer game sells one half of his supply of hot dogs during the first half of the game. During intermission, he sells a total of five hot dogs. During the second half, he sells three eighths of his original supply. He is left with only four hot dogs. How many did he have to start with?", "hint": "No hint available.", "answer": "Five hot dogs (intermission) plus four hot dogs (left over) equals just one eighth of his original supply, because we know that a total of seven eighths was sold during the game itself. That means the vendor must have started the soccer game with 9 x 8 = 72 hot dogs.", "category": "Math", "date": "08/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA hot dog vendor at a soccer game sells one half of his supply of hot dogs during the first half of the game. During intermission, he sells a total of five hot dogs. During the second half, he sells three eighths of his original supply. He is left with only four hot dogs. How many did he have to start with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFive hot dogs (intermission) plus four hot dogs (left over) equals just one eighth of his original supply, because we know that a total of seven eighths was sold during the game itself. That means the vendor must have started the soccer game with 9 x 8 = 72 hot dogs.\n<|im_start|>answer\nFive hot dogs (intermission) plus four hot dogs (left over) equals just one eighth of his original supply, because we know that a total of seven eighths was sold during the game itself. That means the vendor must have started the soccer game with 9 x 8 = 72 hot dogs.\n<|im_end|>" }, { "id": "#29064", "title": "How Many Eggs", "fun": 2.32, "difficulty": 2.98, "author": "Draw", "desc": "Once upon a time, an old lady went to sell her vast quantity of eggs at the local market.\n\r\nWhen asked how many she had, she replied:\n\r\nSon, I can't count past 100 but I know that -\n\r\nIf you divide the number of eggs by 2 there will be one egg left.\r\nIf you divide the number of eggs by 3 there will be one egg left.\r\nIf you divide the number of eggs by 4 there will be one egg left.\r\nIf you divide the number of eggs by 5 there will be one egg left.\r\nIf you divide the number of eggs by 6 there will be one egg left.\r\nIf you divide the number of eggs by 7 there will be one egg left.\r\nIf you divide the number of eggs by 8 there will be one egg left.\r\nIf you divide the number of eggs by 9 there will be one egg left.\r\nIf you divide the number of eggs by 10 there will be one egg left.\n\r\nFinally, if you divide the number of eggs by 11 there will be NO EGGS left!\n\r\nWhat's the minimum number of eggs that the old lady could have?", "hint": "Recall that if n is a prime number, (n-1)!+1 is divisible by n.", "answer": "10!+1=3628801 eggs. This is an answer, but not the minimum.\n\r\nThe least common multiple of 1 to 11 is 27720.\n\r\n3628801=27720*130+25201.\n\r\nTherefore, the old lady had at least 25201 eggs.", "category": "Math", "date": "03/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce upon a time, an old lady went to sell her vast quantity of eggs at the local market.\n\r\nWhen asked how many she had, she replied:\n\r\nSon, I can't count past 100 but I know that -\n\r\nIf you divide the number of eggs by 2 there will be one egg left.\r\nIf you divide the number of eggs by 3 there will be one egg left.\r\nIf you divide the number of eggs by 4 there will be one egg left.\r\nIf you divide the number of eggs by 5 there will be one egg left.\r\nIf you divide the number of eggs by 6 there will be one egg left.\r\nIf you divide the number of eggs by 7 there will be one egg left.\r\nIf you divide the number of eggs by 8 there will be one egg left.\r\nIf you divide the number of eggs by 9 there will be one egg left.\r\nIf you divide the number of eggs by 10 there will be one egg left.\n\r\nFinally, if you divide the number of eggs by 11 there will be NO EGGS left!\n\r\nWhat's the minimum number of eggs that the old lady could have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10!+1=3628801 eggs. This is an answer, but not the minimum.\n\r\nThe least common multiple of 1 to 11 is 27720.\n\r\n3628801=27720*130+25201.\n\r\nTherefore, the old lady had at least 25201 eggs.\n<|im_start|>answer\n10!+1=3628801 eggs. This is an answer, but not the minimum.\n\r\nThe least common multiple of 1 to 11 is 27720.\n\r\n3628801=27720*130+25201.\n\r\nTherefore, the old lady had at least 25201 eggs.\n<|im_end|>" }, { "id": "#9458", "title": "Uncle Anaconda", "fun": 2.32, "difficulty": 1.96, "author": "k2w2man", "desc": "Uncle Anaconda saddled up his mare, Maggie in preparation for a month long hunting trip up at Python Peak, and planned to stay at the old lodge which is 117 miles away. They started out early Sunday morning and arrived at the lodge eight days later on Monday evening. Uncle Anaconda calculated that on each day of the trip, he and Maggie travelled one mile less than they had the day before. How many miles did Uncle Anaconda and Maggie travel on the last Monday of the trip?", "hint": "No hint available.", "answer": "9 miles.\n\r\nThe equation is as follows, with x being the last days travel. \r\nx + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) + (x + 7) + (x + 8 ) = 117\r\n9x + 36 = 117\r\n9x = 81\r\nx = 9", "category": "Math", "date": "12/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUncle Anaconda saddled up his mare, Maggie in preparation for a month long hunting trip up at Python Peak, and planned to stay at the old lodge which is 117 miles away. They started out early Sunday morning and arrived at the lodge eight days later on Monday evening. Uncle Anaconda calculated that on each day of the trip, he and Maggie travelled one mile less than they had the day before. How many miles did Uncle Anaconda and Maggie travel on the last Monday of the trip?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9 miles.\n\r\nThe equation is as follows, with x being the last days travel. \r\nx + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) + (x + 7) + (x + 8 ) = 117\r\n9x + 36 = 117\r\n9x = 81\r\nx = 9\n<|im_start|>answer\n9 miles.\n\r\nThe equation is as follows, with x being the last days travel. \r\nx + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) + (x + 7) + (x + 8 ) = 117\r\n9x + 36 = 117\r\n9x = 81\r\nx = 9\n<|im_end|>" }, { "id": "#13550", "title": "Four Card Monte", "fun": 2.32, "difficulty": 1.77, "author": "bobdole", "desc": "The face cards of a deck of red-backed playing cards and blue-backed playing cards are shuffled together. Then they are cut, one side is turned face up and they are shuffled together face-up and face-down. Then four cards are dealt out on the table like this:\n\r\nRed Blue King Jack \n\r\nHow many cards must you turn over to correctly answer the question: \r\n\"Does each red card on the table have a jack on the other side?\" \n\r\nYou must choose all of the cards to be flipped before any of them are flipped.", "hint": "No hint available.", "answer": "Only two: the red card and the king. Some people mistakenly include the jack, but it doesn't matter if the Jack showing is red or blue in order to answer the question.", "category": "Logic", "date": "07/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe face cards of a deck of red-backed playing cards and blue-backed playing cards are shuffled together. Then they are cut, one side is turned face up and they are shuffled together face-up and face-down. Then four cards are dealt out on the table like this:\n\r\nRed Blue King Jack \n\r\nHow many cards must you turn over to correctly answer the question: \r\n\"Does each red card on the table have a jack on the other side?\" \n\r\nYou must choose all of the cards to be flipped before any of them are flipped.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOnly two: the red card and the king. Some people mistakenly include the jack, but it doesn't matter if the Jack showing is red or blue in order to answer the question.\n<|im_start|>answer\nOnly two: the red card and the king. Some people mistakenly include the jack, but it doesn't matter if the Jack showing is red or blue in order to answer the question.\n<|im_end|>" }, { "id": "#30456", "title": "Divisible by 23", "fun": 2.32, "difficulty": 2.56, "author": "fairelamour", "desc": "I'm divisible by 23 and 3. \n\r\nCount from 1 to 100, and you'll meet the two-digit number in my thousands and hundreds place just before the two-digit number in my tens and ones place. \n\r\nI'm greater than 2,000, but less than 9,000. \n\r\nWhat number am I?", "hint": "Using the second clue, make a list of possibilities and use a calculator to check for divisibility.", "answer": "The number is 2829.\n\r\nSince the number is between 2,000 and 9,000, the smallest possible digit in the thousands place is 2. The number has to be divisible by 69 (the common multiple of 3 and 23). Using a calculator, you can start with the smallest number that answers the description in the second clue, 2021, and check. None of 2021, 2122, 2223, 2324, 2425, 2526, 2627, 2728 is divisible by 69, and 2829=69*41.", "category": "Math", "date": "05/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI'm divisible by 23 and 3. \n\r\nCount from 1 to 100, and you'll meet the two-digit number in my thousands and hundreds place just before the two-digit number in my tens and ones place. \n\r\nI'm greater than 2,000, but less than 9,000. \n\r\nWhat number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 2829.\n\r\nSince the number is between 2,000 and 9,000, the smallest possible digit in the thousands place is 2. The number has to be divisible by 69 (the common multiple of 3 and 23). Using a calculator, you can start with the smallest number that answers the description in the second clue, 2021, and check. None of 2021, 2122, 2223, 2324, 2425, 2526, 2627, 2728 is divisible by 69, and 2829=69*41.\n<|im_start|>answer\nThe number is 2829.\n\r\nSince the number is between 2,000 and 9,000, the smallest possible digit in the thousands place is 2. The number has to be divisible by 69 (the common multiple of 3 and 23). Using a calculator, you can start with the smallest number that answers the description in the second clue, 2021, and check. None of 2021, 2122, 2223, 2324, 2425, 2526, 2627, 2728 is divisible by 69, and 2829=69*41.\n<|im_end|>" }, { "id": "#2561", "title": "Tokar Smith", "fun": 2.32, "difficulty": 1.31, "author": "204_blaze_41", "desc": "Tokar Smith was racing around in his new sports car when he noticed that his throat was parched. He came to a screeching halt in front of the 'Soul-Ace Hotel' and the nine police cars which had been chasing him, slammed into the back of his car and each other's. How many bumpers will have been hit?", "hint": "No hint available.", "answer": "Eighteen. Since ten cars are involved, all the bumpers will have been hit except for the first one on Tokar's car, and the back one on the last police car.", "category": "Logic", "date": "03/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTokar Smith was racing around in his new sports car when he noticed that his throat was parched. He came to a screeching halt in front of the 'Soul-Ace Hotel' and the nine police cars which had been chasing him, slammed into the back of his car and each other's. How many bumpers will have been hit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEighteen. Since ten cars are involved, all the bumpers will have been hit except for the first one on Tokar's car, and the back one on the last police car.\n<|im_start|>answer\nEighteen. Since ten cars are involved, all the bumpers will have been hit except for the first one on Tokar's car, and the back one on the last police car.\n<|im_end|>" }, { "id": "#5047", "title": "Hat in the River", "fun": 2.32, "difficulty": 2.0, "author": "im_para_noid", "desc": "A river is flowing downstream at 15 mph relative to the shore. A rowing team is practicing rowing and at first they row upstream (against the current). They can only go 1.5 mph relative to the shore at this rate. The guy at the back end of the boat is wearing a hat when they begin, but after a while his hat falls into the water (and floats) and it is 15 minutes before they notice it. They then instantaneously reverse direction and row back to catch up with the hat, rowing with the same strength or power they were rowing with before. \n\r\nHow long will it take them to catch up with the hat as it is pushed downstream by the current ?", "hint": "No hint available.", "answer": "15 Minutes", "category": "Math", "date": "06/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA river is flowing downstream at 15 mph relative to the shore. A rowing team is practicing rowing and at first they row upstream (against the current). They can only go 1.5 mph relative to the shore at this rate. The guy at the back end of the boat is wearing a hat when they begin, but after a while his hat falls into the water (and floats) and it is 15 minutes before they notice it. They then instantaneously reverse direction and row back to catch up with the hat, rowing with the same strength or power they were rowing with before. \n\r\nHow long will it take them to catch up with the hat as it is pushed downstream by the current ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15 Minutes\n<|im_start|>answer\n15 Minutes\n<|im_end|>" }, { "id": "#9840", "title": "Acquainted", "fun": 2.32, "difficulty": 2.41, "author": "something", "desc": "You and your spouse invite four other couples to a party. During the course of the conversation, it is discovered that, prior to the party, each person except you was acquainted with a different number of the people present. Assuming the acquaintance relationship is symmetric (i.e., if you are acquainted with someone, that person is also acquainted with you), then how many people did your spouse know prior to the party? How many people did you know?", "hint": "No hint available.", "answer": "Start with the assumption that everybody knows their own spouses -- which means that everybody there knew at least one person. Discounting yourself, everyone knows a different number of people, which means that (again, discounting yourself) one person knows one, one person knows two, one person knows three, etc., up to one person who knows nine people (everybody else). Number the people (besides yourself) according to how many people they know, so that person 1 is the one who knows one person, person 2 is the one who knows two people, etc.\n\r\nNow pair up people with their spouses. If person 9 knows everybody else, s/he must be the only person who knows person 1, because person 1 only knows one person. So they must be married. Person 8 knows everybody except for person 1. Person 2 therefore knows person 8 and person 9. Person 9 is married to person 1, so person 2's spouse must be person 8. Person 7 knows everybody except for persons 1 and 2. Person 3 therefore knows persons 7, 8, and 9. Persons 8 and 9 are married to persons 2 and 1 respectively, so person 3's spouse must be person 7. Person 6 knows everybody except for persons 1, 2, and 3. Person 4 therefore knows persons 6, 7, 8, and 9. The only one of those not yet paired up is person 6, so person 4 and person 6 must be married.\n\r\nThis leaves person 5, who knows everyone except persons 1, 2, 3, and 4. These five people, therefore, must be persons 6, 7, 8, 9, and you. Since you are the only one of these five not yet paired up, person 5 must be your spouse. So your spouse knew five people prior to the party.\n\r\nThe above also determines that the people who know you are persons 5, 6, 7, 8, and 9. So you knew five people prior to the party also.", "category": "Logic", "date": "01/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou and your spouse invite four other couples to a party. During the course of the conversation, it is discovered that, prior to the party, each person except you was acquainted with a different number of the people present. Assuming the acquaintance relationship is symmetric (i.e., if you are acquainted with someone, that person is also acquainted with you), then how many people did your spouse know prior to the party? How many people did you know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStart with the assumption that everybody knows their own spouses -- which means that everybody there knew at least one person. Discounting yourself, everyone knows a different number of people, which means that (again, discounting yourself) one person knows one, one person knows two, one person knows three, etc., up to one person who knows nine people (everybody else). Number the people (besides yourself) according to how many people they know, so that person 1 is the one who knows one person, person 2 is the one who knows two people, etc.\n\r\nNow pair up people with their spouses. If person 9 knows everybody else, s/he must be the only person who knows person 1, because person 1 only knows one person. So they must be married. Person 8 knows everybody except for person 1. Person 2 therefore knows person 8 and person 9. Person 9 is married to person 1, so person 2's spouse must be person 8. Person 7 knows everybody except for persons 1 and 2. Person 3 therefore knows persons 7, 8, and 9. Persons 8 and 9 are married to persons 2 and 1 respectively, so person 3's spouse must be person 7. Person 6 knows everybody except for persons 1, 2, and 3. Person 4 therefore knows persons 6, 7, 8, and 9. The only one of those not yet paired up is person 6, so person 4 and person 6 must be married.\n\r\nThis leaves person 5, who knows everyone except persons 1, 2, 3, and 4. These five people, therefore, must be persons 6, 7, 8, 9, and you. Since you are the only one of these five not yet paired up, person 5 must be your spouse. So your spouse knew five people prior to the party.\n\r\nThe above also determines that the people who know you are persons 5, 6, 7, 8, and 9. So you knew five people prior to the party also.\n<|im_start|>answer\nStart with the assumption that everybody knows their own spouses -- which means that everybody there knew at least one person. Discounting yourself, everyone knows a different number of people, which means that (again, discounting yourself) one person knows one, one person knows two, one person knows three, etc., up to one person who knows nine people (everybody else). Number the people (besides yourself) according to how many people they know, so that person 1 is the one who knows one person, person 2 is the one who knows two people, etc.\n\r\nNow pair up people with their spouses. If person 9 knows everybody else, s/he must be the only person who knows person 1, because person 1 only knows one person. So they must be married. Person 8 knows everybody except for person 1. Person 2 therefore knows person 8 and person 9. Person 9 is married to person 1, so person 2's spouse must be person 8. Person 7 knows everybody except for persons 1 and 2. Person 3 therefore knows persons 7, 8, and 9. Persons 8 and 9 are married to persons 2 and 1 respectively, so person 3's spouse must be person 7. Person 6 knows everybody except for persons 1, 2, and 3. Person 4 therefore knows persons 6, 7, 8, and 9. The only one of those not yet paired up is person 6, so person 4 and person 6 must be married.\n\r\nThis leaves person 5, who knows everyone except persons 1, 2, 3, and 4. These five people, therefore, must be persons 6, 7, 8, 9, and you. Since you are the only one of these five not yet paired up, person 5 must be your spouse. So your spouse knew five people prior to the party.\n\r\nThe above also determines that the people who know you are persons 5, 6, 7, 8, and 9. So you knew five people prior to the party also.\n<|im_end|>" }, { "id": "#8709", "title": "Going to College", "fun": 2.32, "difficulty": 2.14, "author": "the_smart_one", "desc": "Four high school friends, one named Cathy, were about to go to college. Their last names were Williams, Burbank, Collin, and Gunderson. Each enrolled in a different college, one of them being a state college. From the clues below determine each person's full name, and the college he or she attended.\n\r\n1. No student's first name begins with the first letter as her or his last name, and no students first name's last letter is the same as his last name's last letter.\r\n2. Neither Hank or Williams went to the community college.\r\n3. Alan, Collin, and the student who went to the university all lived on the same street. The other student lived two blocks away.\r\n4. Gladys and Hank lived next door to each other.\r\n5. The private college accepted Hank's application, but he decided he could not afford to go there.", "hint": "No hint available.", "answer": "Hank Collin - State College\r\nGladys Burbank - University\r\nCathy Gunderson - Community College\r\nAlan Williams - Private College", "category": "Logic", "date": "12/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour high school friends, one named Cathy, were about to go to college. Their last names were Williams, Burbank, Collin, and Gunderson. Each enrolled in a different college, one of them being a state college. From the clues below determine each person's full name, and the college he or she attended.\n\r\n1. No student's first name begins with the first letter as her or his last name, and no students first name's last letter is the same as his last name's last letter.\r\n2. Neither Hank or Williams went to the community college.\r\n3. Alan, Collin, and the student who went to the university all lived on the same street. The other student lived two blocks away.\r\n4. Gladys and Hank lived next door to each other.\r\n5. The private college accepted Hank's application, but he decided he could not afford to go there.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHank Collin - State College\r\nGladys Burbank - University\r\nCathy Gunderson - Community College\r\nAlan Williams - Private College\n<|im_start|>answer\nHank Collin - State College\r\nGladys Burbank - University\r\nCathy Gunderson - Community College\r\nAlan Williams - Private College\n<|im_end|>" }, { "id": "#5551", "title": "Kebab Combination", "fun": 2.32, "difficulty": 2.0, "author": "mad-ade", "desc": "Mad Ade is in a bit of a dilemma. He has accidentally locked his Kebab in a combination safe. Only this safe uses letters instead of numbers. Only he has forgotten the combination. \n\r\nThese are the 6 letters used in the combination: A, B, C, D, E, F; with none of them being used twice. \n\r\nHere are three incorrect guesses Mad Ade has already made at the combination.\n\r\nC B A D F E\r\nA E D C B F\r\nE D F A C B\n\r\nIn the FIRST guess, only ONE letter is in its correct place.\r\nIn the SECOND guess, only TWO letters are in their correct places.\r\nIn the THIRD guess, only THREE letters are in their correct places.\r\nEach of the 6 letters is in its correct place once.\n\r\nWhat is the correct combination needed to rescue the Kebab?", "hint": "No hint available.", "answer": "The combination was EBDACF or AEFDCB (either will work).", "category": "Logic", "date": "07/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is in a bit of a dilemma. He has accidentally locked his Kebab in a combination safe. Only this safe uses letters instead of numbers. Only he has forgotten the combination. \n\r\nThese are the 6 letters used in the combination: A, B, C, D, E, F; with none of them being used twice. \n\r\nHere are three incorrect guesses Mad Ade has already made at the combination.\n\r\nC B A D F E\r\nA E D C B F\r\nE D F A C B\n\r\nIn the FIRST guess, only ONE letter is in its correct place.\r\nIn the SECOND guess, only TWO letters are in their correct places.\r\nIn the THIRD guess, only THREE letters are in their correct places.\r\nEach of the 6 letters is in its correct place once.\n\r\nWhat is the correct combination needed to rescue the Kebab?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe combination was EBDACF or AEFDCB (either will work).\n<|im_start|>answer\nThe combination was EBDACF or AEFDCB (either will work).\n<|im_end|>" }, { "id": "#35482", "title": "Cubes, Cubes, Everywhere!", "fun": 2.32, "difficulty": 2.66, "author": "t4mt", "desc": "In the far future, you find yourself a cube-maker. To make cubes, you would take a 12 by 12 by 12 Rubik's cube-like object. Normally, you would touch each tiny one by one by one cube and they would fall off. However, with new quantum technology, it has become more interesting. You may say the total number of possible cubes (not necessarily with side length one) in the twelve by twelve by twelve Rubik's cube, and hocus-pocus, cubes of all sizes would appear. Assuming that each side in the tiny cubes has length one and that you may only make cubes of integer side length, what number should you say for the new technology to work?", "hint": "For 1^3+2^3+... n^3, use (1+2+...n)^2.", "answer": "6084.\n\r\nFirst, try a easier problem. Try a two by two by two Rubik's cube. There are 8 tiny cubes and one 2 by 2 by 2 cube. It should come to your notice that you take 2^3+1^3. But just to check, you look at a standard Rubik's cube with side length 3. There are, predictably, 27 one by one cubes, 8 two by two cubes, and one 3 by 3 cube. That was 3^3 +2^3 + 1^3. Now you can come to the conclusion that for any Rubik's cube with side length n, there are n^3+(n-1)^3 + ... 2^3+1^3 total cubes with integer side length. Therefore, there are 1^3+2^3+...12^3 cubes in the Rubik's cube with side length 12. The hint gives the formula for adding a sequence of cubes. Thus, you would get (1+2+3+4+...+11+12)^2 = 6084 cubes.", "category": "Math", "date": "03/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the far future, you find yourself a cube-maker. To make cubes, you would take a 12 by 12 by 12 Rubik's cube-like object. Normally, you would touch each tiny one by one by one cube and they would fall off. However, with new quantum technology, it has become more interesting. You may say the total number of possible cubes (not necessarily with side length one) in the twelve by twelve by twelve Rubik's cube, and hocus-pocus, cubes of all sizes would appear. Assuming that each side in the tiny cubes has length one and that you may only make cubes of integer side length, what number should you say for the new technology to work?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6084.\n\r\nFirst, try a easier problem. Try a two by two by two Rubik's cube. There are 8 tiny cubes and one 2 by 2 by 2 cube. It should come to your notice that you take 2^3+1^3. But just to check, you look at a standard Rubik's cube with side length 3. There are, predictably, 27 one by one cubes, 8 two by two cubes, and one 3 by 3 cube. That was 3^3 +2^3 + 1^3. Now you can come to the conclusion that for any Rubik's cube with side length n, there are n^3+(n-1)^3 + ... 2^3+1^3 total cubes with integer side length. Therefore, there are 1^3+2^3+...12^3 cubes in the Rubik's cube with side length 12. The hint gives the formula for adding a sequence of cubes. Thus, you would get (1+2+3+4+...+11+12)^2 = 6084 cubes.\n<|im_start|>answer\n6084.\n\r\nFirst, try a easier problem. Try a two by two by two Rubik's cube. There are 8 tiny cubes and one 2 by 2 by 2 cube. It should come to your notice that you take 2^3+1^3. But just to check, you look at a standard Rubik's cube with side length 3. There are, predictably, 27 one by one cubes, 8 two by two cubes, and one 3 by 3 cube. That was 3^3 +2^3 + 1^3. Now you can come to the conclusion that for any Rubik's cube with side length n, there are n^3+(n-1)^3 + ... 2^3+1^3 total cubes with integer side length. Therefore, there are 1^3+2^3+...12^3 cubes in the Rubik's cube with side length 12. The hint gives the formula for adding a sequence of cubes. Thus, you would get (1+2+3+4+...+11+12)^2 = 6084 cubes.\n<|im_end|>" }, { "id": "#1307", "title": "In a Race", "fun": 2.32, "difficulty": 0.84, "author": "gokaran", "desc": "You are participating in a race. You overtake the second place runner.\n\r\nWhat position are you?", "hint": "No hint available.", "answer": "You overtake the second and you take his place so you arrived\r\nsecond.", "category": "Logic", "date": "11/07/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are participating in a race. You overtake the second place runner.\n\r\nWhat position are you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou overtake the second and you take his place so you arrived\r\nsecond.\n<|im_start|>answer\nYou overtake the second and you take his place so you arrived\r\nsecond.\n<|im_end|>" }, { "id": "#1726", "title": "No Eights", "fun": 2.32, "difficulty": 1.68, "author": "Nishoo", "desc": "Can you write down a mathematical expression equaling 24, which uses the same digit three times, and doesn't use the digit 8 ?", "hint": "No hint available.", "answer": "22 + 2", "category": "Math", "date": "12/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you write down a mathematical expression equaling 24, which uses the same digit three times, and doesn't use the digit 8 ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n22 + 2\n<|im_start|>answer\n22 + 2\n<|im_end|>" }, { "id": "#23780", "title": "Walk- A- Thon", "fun": 2.32, "difficulty": 2.48, "author": "flirtmaster123", "desc": "Alyssa, Juan, Myisha, Tracy, and Scott raised a total of $550.68 for the nearby homeless shelter by walking in a \"walk-a-thon.\" Before the walk, they each got promises (pledges) from a number of people to contribute money for each mile they walked. The total amount per mile which each person raised ranged from $7.10 a mile to $20.70 per mile, and the total distance each person walked ranged from 5 3/4 miles to 13 1/2 miles.\n\r\nAt the end of the walk-a-thon, they collected the exact amount that had been pledged to them for each mile they walked. All amounts are rounded to the nearest penny.\n\r\nUsing the information above and the clues below, how far did each person walk, and how much did they each earn to contribute to the shelter?\n\n\r\nAlyssa walked the fewest miles, but her total pledge per mile was 50% more than Scott's. \r\nJuan had a total of $10.35 pledged per mile, and walked 3 1/4 more miles than Alyssa. \r\nMyisha walked .25 mile more than Alyssa, but her total pledge per mile was twice Juan's. \r\nTracy had the least amount per mile pledged. \r\nScott walked twice as far as Alyssa and had an total of $1.45 more per mile pledged than Juan.", "hint": "Make a chart to figure out what the total pledge per mile to each person was, and how far each person walked.", "answer": "Alyssa walked 5.75 miles and received a total of $101.78 to contribute to the shelter.\n\r\nJuan walked 9 miles and received a total of $93.15 to contribute to the shelter.\n\r\nMyisha walked 6 miles and received a total of $124.20 to contribute to the shelter.\n\r\nTracy walked 13.5 miles and received a total of $95.85 to contribute to the shelter.\n\r\nScott walked 11.5 miles and received a total of $135.70 to contribute to the shelter.", "category": "Math", "date": "06/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlyssa, Juan, Myisha, Tracy, and Scott raised a total of $550.68 for the nearby homeless shelter by walking in a \"walk-a-thon.\" Before the walk, they each got promises (pledges) from a number of people to contribute money for each mile they walked. The total amount per mile which each person raised ranged from $7.10 a mile to $20.70 per mile, and the total distance each person walked ranged from 5 3/4 miles to 13 1/2 miles.\n\r\nAt the end of the walk-a-thon, they collected the exact amount that had been pledged to them for each mile they walked. All amounts are rounded to the nearest penny.\n\r\nUsing the information above and the clues below, how far did each person walk, and how much did they each earn to contribute to the shelter?\n\n\r\nAlyssa walked the fewest miles, but her total pledge per mile was 50% more than Scott's. \r\nJuan had a total of $10.35 pledged per mile, and walked 3 1/4 more miles than Alyssa. \r\nMyisha walked .25 mile more than Alyssa, but her total pledge per mile was twice Juan's. \r\nTracy had the least amount per mile pledged. \r\nScott walked twice as far as Alyssa and had an total of $1.45 more per mile pledged than Juan.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlyssa walked 5.75 miles and received a total of $101.78 to contribute to the shelter.\n\r\nJuan walked 9 miles and received a total of $93.15 to contribute to the shelter.\n\r\nMyisha walked 6 miles and received a total of $124.20 to contribute to the shelter.\n\r\nTracy walked 13.5 miles and received a total of $95.85 to contribute to the shelter.\n\r\nScott walked 11.5 miles and received a total of $135.70 to contribute to the shelter.\n<|im_start|>answer\nAlyssa walked 5.75 miles and received a total of $101.78 to contribute to the shelter.\n\r\nJuan walked 9 miles and received a total of $93.15 to contribute to the shelter.\n\r\nMyisha walked 6 miles and received a total of $124.20 to contribute to the shelter.\n\r\nTracy walked 13.5 miles and received a total of $95.85 to contribute to the shelter.\n\r\nScott walked 11.5 miles and received a total of $135.70 to contribute to the shelter.\n<|im_end|>" }, { "id": "#14616", "title": "Joe's Diner", "fun": 2.32, "difficulty": 2.68, "author": "master123", "desc": "Too many people knew the code to Joe's menu and he was losing a fortune in free pizza. Now he has a new code (based on the value of letters). Can you crack it, discover the price of pancakes, and win a free hamburger?\n\r\nMENU\r\nApple Pie ... $13.60\r\nIce cream ... $15.90\r\nChocolate cake ... $24.90\r\nPancakes ... $?", "hint": "No hint available.", "answer": "The letters are valued in reverse alphabetical order (A = 26 B = 25, etc) and multiplied by 10. Pancakes cost is $14.60", "category": "Math", "date": "08/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nToo many people knew the code to Joe's menu and he was losing a fortune in free pizza. Now he has a new code (based on the value of letters). Can you crack it, discover the price of pancakes, and win a free hamburger?\n\r\nMENU\r\nApple Pie ... $13.60\r\nIce cream ... $15.90\r\nChocolate cake ... $24.90\r\nPancakes ... $?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe letters are valued in reverse alphabetical order (A = 26 B = 25, etc) and multiplied by 10. Pancakes cost is $14.60\n<|im_start|>answer\nThe letters are valued in reverse alphabetical order (A = 26 B = 25, etc) and multiplied by 10. Pancakes cost is $14.60\n<|im_end|>" }, { "id": "#17847", "title": "Ones", "fun": 2.32, "difficulty": 2.56, "author": "Pitter", "desc": "How would you arrange six ones so that they make twelve?", "hint": "No hint available.", "answer": "11+11/11", "category": "Math", "date": "06/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow would you arrange six ones so that they make twelve?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11+11/11\n<|im_start|>answer\n11+11/11\n<|im_end|>" }, { "id": "#4138", "title": "Fat Bear", "fun": 2.31, "difficulty": 1.79, "author": "mad-ade", "desc": "Mad Ade has a greedy pet bear that will eat 65lbs of fish each day, except every 6th day which it will only eat 45lbs. Mad Ade is going away for 200 days, and is leaving his friend to feed the bear. How many pounds of fish will Mad Ade need to order to be delivered while he is away?", "hint": "No hint available.", "answer": "12,340lbs", "category": "Math", "date": "05/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has a greedy pet bear that will eat 65lbs of fish each day, except every 6th day which it will only eat 45lbs. Mad Ade is going away for 200 days, and is leaving his friend to feed the bear. How many pounds of fish will Mad Ade need to order to be delivered while he is away?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12,340lbs\n<|im_start|>answer\n12,340lbs\n<|im_end|>" }, { "id": "#14460", "title": "The Storage Bin", "fun": 2.31, "difficulty": 1.33, "author": "RainyMysteria", "desc": "A storage bin is one-third full of grain. After 100 kg of grain is poured into the bin, it is half full. How much grain can the storage bin hold?", "hint": "No hint available.", "answer": "The answer is 600 kg. \n\r\n100 kg is the difference between 1/2 of the bin and 1/3 of the bin: \n\r\n1/2 - 1/3 = 3/6 - 2/6 = 1/6. \n\r\nSince 100 kg fills 1/6 of the bin, the bin must hold a total of 600 kg.", "category": "Math", "date": "08/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA storage bin is one-third full of grain. After 100 kg of grain is poured into the bin, it is half full. How much grain can the storage bin hold?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 600 kg. \n\r\n100 kg is the difference between 1/2 of the bin and 1/3 of the bin: \n\r\n1/2 - 1/3 = 3/6 - 2/6 = 1/6. \n\r\nSince 100 kg fills 1/6 of the bin, the bin must hold a total of 600 kg.\n<|im_start|>answer\nThe answer is 600 kg. \n\r\n100 kg is the difference between 1/2 of the bin and 1/3 of the bin: \n\r\n1/2 - 1/3 = 3/6 - 2/6 = 1/6. \n\r\nSince 100 kg fills 1/6 of the bin, the bin must hold a total of 600 kg.\n<|im_end|>" }, { "id": "#5702", "title": "Some Old Books", "fun": 2.31, "difficulty": 1.87, "author": "master123", "desc": "The local library decided to hand out some of its old books to its 1400 borrowers. To each of the female borrowers they gave 6 books and to each male borrower they gave 4 books. If only half of the females in town and three quarters of the males in town accepted the books how many books were given away?", "hint": "Choose a random number of girls and then work it out.", "answer": "4200 books.\r\nSince each female was offered 6 books but only half of them accepted, on an average, each of them got 3 books. Also, since each male was offered 4 books and three quarters accepted, again an average male got 3 books. Since females and males got the same number of books per person, it doesn't matter how many females there actually are. \r\nSo, total books given away = 1400 x 3 = 4200.", "category": "Math", "date": "07/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe local library decided to hand out some of its old books to its 1400 borrowers. To each of the female borrowers they gave 6 books and to each male borrower they gave 4 books. If only half of the females in town and three quarters of the males in town accepted the books how many books were given away?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4200 books.\r\nSince each female was offered 6 books but only half of them accepted, on an average, each of them got 3 books. Also, since each male was offered 4 books and three quarters accepted, again an average male got 3 books. Since females and males got the same number of books per person, it doesn't matter how many females there actually are. \r\nSo, total books given away = 1400 x 3 = 4200.\n<|im_start|>answer\n4200 books.\r\nSince each female was offered 6 books but only half of them accepted, on an average, each of them got 3 books. Also, since each male was offered 4 books and three quarters accepted, again an average male got 3 books. Since females and males got the same number of books per person, it doesn't matter how many females there actually are. \r\nSo, total books given away = 1400 x 3 = 4200.\n<|im_end|>" }, { "id": "#1329", "title": "How Big is the Trout?", "fun": 2.31, "difficulty": 1.72, "author": "gokaran", "desc": "A trout's tail weighs eight pounds. Its head weighs as much as the tail and one-half of the body combined, and the body weighs as much as the head and tail combined. What does the whole trout weigh?", "hint": "No hint available.", "answer": "64 pounds. The head weighs 24 pounds, the body weighs 32 pounds and the tail weighs 8 pounds.", "category": "Math", "date": "11/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA trout's tail weighs eight pounds. Its head weighs as much as the tail and one-half of the body combined, and the body weighs as much as the head and tail combined. What does the whole trout weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n64 pounds. The head weighs 24 pounds, the body weighs 32 pounds and the tail weighs 8 pounds.\n<|im_start|>answer\n64 pounds. The head weighs 24 pounds, the body weighs 32 pounds and the tail weighs 8 pounds.\n<|im_end|>" }, { "id": "#4354", "title": "Boxers", "fun": 2.31, "difficulty": 1.53, "author": "mad-ade", "desc": "Mad Ade had managed to secure two tickets to a boxing match. There were two boxers in the boxing ring, plus the referee (regular boxing, not kick boxing). The fight is scheduled for 12 rounds but ends after 6 rounds, after one boxer knocks out the other boxer. Yet neither Mad Ade nor the ref saw any man throw a punch. How is this possible?", "hint": "No hint available.", "answer": "They are female boxers", "category": "Logic", "date": "05/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade had managed to secure two tickets to a boxing match. There were two boxers in the boxing ring, plus the referee (regular boxing, not kick boxing). The fight is scheduled for 12 rounds but ends after 6 rounds, after one boxer knocks out the other boxer. Yet neither Mad Ade nor the ref saw any man throw a punch. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are female boxers\n<|im_start|>answer\nThey are female boxers\n<|im_end|>" }, { "id": "#4137", "title": "Party", "fun": 2.31, "difficulty": 1.73, "author": "mad-ade", "desc": "Mad Ade has found himself at a party. There are 120 people at the party and 3 fifths of them are women. Also, 2 thirds of the 120 people are married. How many unmarried women could Mad Ade possibly meet at the party?", "hint": "No hint available.", "answer": "40", "category": "Math", "date": "05/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has found himself at a party. There are 120 people at the party and 3 fifths of them are women. Also, 2 thirds of the 120 people are married. How many unmarried women could Mad Ade possibly meet at the party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n40\n<|im_start|>answer\n40\n<|im_end|>" }, { "id": "#4154", "title": "Initial Family", "fun": 2.31, "difficulty": 0.96, "author": "mad-ade", "desc": "Some of Mad Ade's family are unable to spell, so as a result many members of the family are known only by a letter of the alphabet.\n\r\nA is the brother of B, C is the daughter of B. \r\nE is the sister of A, and Mad Ade is the brother of C. \r\nF is the father of E.\n\r\nWho is Mad Ade's Uncle?", "hint": "No hint available.", "answer": "A is Mad Ade's Uncle.", "category": "Logic", "date": "05/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome of Mad Ade's family are unable to spell, so as a result many members of the family are known only by a letter of the alphabet.\n\r\nA is the brother of B, C is the daughter of B. \r\nE is the sister of A, and Mad Ade is the brother of C. \r\nF is the father of E.\n\r\nWho is Mad Ade's Uncle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA is Mad Ade's Uncle.\n<|im_start|>answer\nA is Mad Ade's Uncle.\n<|im_end|>" }, { "id": "#39223", "title": "Three Brothers 2", "fun": 2.31, "difficulty": 1.68, "author": "clevermonkey", "desc": "The ages of three brothers, John, Andy, and Stan total 210. Stan is a fifth older again than Andy, and Andy is a quarter again older than John. How old is each brother?", "hint": "j + a + s = 210\r\ns = 1.2a\r\na = 1.25j\n\r\nthus\n\r\nj + 1.5j + 1.25j = 210", "answer": "j + a + s = 210\r\ns = 1.2a\r\na= 1.25j\n\r\nthus\n\r\nj + 1.5j + 1.25j = 210\r\n3.75j = 210\r\nj = 210/3.75\r\nj = 56\n\r\na = 1.25j\r\na = 1.25 * 56\r\na = 70\n\r\ns = 1.2a\r\ns = 1.2(70)\r\ns = 84\n\r\nJohn 56\r\nAndy 70\r\nStan 84", "category": "Math", "date": "11/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe ages of three brothers, John, Andy, and Stan total 210. Stan is a fifth older again than Andy, and Andy is a quarter again older than John. How old is each brother?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nj + a + s = 210\r\ns = 1.2a\r\na= 1.25j\n\r\nthus\n\r\nj + 1.5j + 1.25j = 210\r\n3.75j = 210\r\nj = 210/3.75\r\nj = 56\n\r\na = 1.25j\r\na = 1.25 * 56\r\na = 70\n\r\ns = 1.2a\r\ns = 1.2(70)\r\ns = 84\n\r\nJohn 56\r\nAndy 70\r\nStan 84\n<|im_start|>answer\nj + a + s = 210\r\ns = 1.2a\r\na= 1.25j\n\r\nthus\n\r\nj + 1.5j + 1.25j = 210\r\n3.75j = 210\r\nj = 210/3.75\r\nj = 56\n\r\na = 1.25j\r\na = 1.25 * 56\r\na = 70\n\r\ns = 1.2a\r\ns = 1.2(70)\r\ns = 84\n\r\nJohn 56\r\nAndy 70\r\nStan 84\n<|im_end|>" }, { "id": "#34336", "title": "Blinket Vehicle", "fun": 2.31, "difficulty": 1.39, "author": "DaleGriffin", "desc": "In the land of Clinkets, the local Winkets and Flinkets earn their wealth in stars, crescents, and nuggets. Every 5 stars equals the value of 1 crescent. Every 5 crescents is worth 1 nugget.\n\r\nChief Winket has 250 nuggets, 50 stars, and 200 crescents. \r\nHis counterpart, Chief Flinket, has twice as many crescents, 3 times as many stars, but just 200 nuggets. \r\nA new Blinket vehicle costs 483 nuggets.\n\r\nHow many more stars must each earn in order to have enough stars to buy a new Blinket vehicle?", "hint": "No hint available.", "answer": "Chief Winket needs 4,775 more stars.\r\nChief Flinket needs 4,925 more stars.\n\r\n(A new Blinket vehicle costs 483 nuggets, which is equivalent to 12,075 stars.\r\nFor Chief Winket subtract: 12,075 - 7,300 (all nuggets and crescents converted into star values)= 4,775 more stars.\r\nFor Chief Flinket subtract: 12,075 - 7,150 (all nuggets and crescents converted into star values)= 4,925 more stars.)", "category": "Math", "date": "12/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of Clinkets, the local Winkets and Flinkets earn their wealth in stars, crescents, and nuggets. Every 5 stars equals the value of 1 crescent. Every 5 crescents is worth 1 nugget.\n\r\nChief Winket has 250 nuggets, 50 stars, and 200 crescents. \r\nHis counterpart, Chief Flinket, has twice as many crescents, 3 times as many stars, but just 200 nuggets. \r\nA new Blinket vehicle costs 483 nuggets.\n\r\nHow many more stars must each earn in order to have enough stars to buy a new Blinket vehicle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChief Winket needs 4,775 more stars.\r\nChief Flinket needs 4,925 more stars.\n\r\n(A new Blinket vehicle costs 483 nuggets, which is equivalent to 12,075 stars.\r\nFor Chief Winket subtract: 12,075 - 7,300 (all nuggets and crescents converted into star values)= 4,775 more stars.\r\nFor Chief Flinket subtract: 12,075 - 7,150 (all nuggets and crescents converted into star values)= 4,925 more stars.)\n<|im_start|>answer\nChief Winket needs 4,775 more stars.\r\nChief Flinket needs 4,925 more stars.\n\r\n(A new Blinket vehicle costs 483 nuggets, which is equivalent to 12,075 stars.\r\nFor Chief Winket subtract: 12,075 - 7,300 (all nuggets and crescents converted into star values)= 4,775 more stars.\r\nFor Chief Flinket subtract: 12,075 - 7,150 (all nuggets and crescents converted into star values)= 4,925 more stars.)\n<|im_end|>" }, { "id": "#2614", "title": "Underwear", "fun": 2.31, "difficulty": 1.6300000000000001, "author": "204_BLaZe_41", "desc": "Every Tuesday evening Anthony Chubala drives up to his cottage to visit his wife Courtney B. On these weekly visits he drops off the clean clothes and picks up the dirty laundry. Since Courtney B. changes her underwear each morning, what is the minimum number of pairs of underwear she can own?", "hint": "No hint available.", "answer": "15. Every Tuesday Courtney B. receives seven pairs of underwear and also leaves seven for Anthony to wash. That equals 14, plus the pair she is wearing.", "category": "Logic", "date": "03/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery Tuesday evening Anthony Chubala drives up to his cottage to visit his wife Courtney B. On these weekly visits he drops off the clean clothes and picks up the dirty laundry. Since Courtney B. changes her underwear each morning, what is the minimum number of pairs of underwear she can own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15. Every Tuesday Courtney B. receives seven pairs of underwear and also leaves seven for Anthony to wash. That equals 14, plus the pair she is wearing.\n<|im_start|>answer\n15. Every Tuesday Courtney B. receives seven pairs of underwear and also leaves seven for Anthony to wash. That equals 14, plus the pair she is wearing.\n<|im_end|>" }, { "id": "#8632", "title": "Doctor and Lawyer", "fun": 2.31, "difficulty": 2.22, "author": "lesternoronha1", "desc": "There are 4 people: Mr. Cooper, his wife, their son and Mr. Cooper's mother. One is a doctor and another is a lawyer. \n\r\n1) If the doctor is younger than the lawyer, then the doctor and the lawyer are not blood relatives. \r\n2)If the doctor is a woman then the doctor and the lawyer are blood relatives. \r\n3) If the lawyer is a man, then the doctor is a man. \n\r\nWhose occupation do you know?", "hint": "No hint available.", "answer": "Mr. Cooper is the doctor.", "category": "Logic", "date": "11/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 4 people: Mr. Cooper, his wife, their son and Mr. Cooper's mother. One is a doctor and another is a lawyer. \n\r\n1) If the doctor is younger than the lawyer, then the doctor and the lawyer are not blood relatives. \r\n2)If the doctor is a woman then the doctor and the lawyer are blood relatives. \r\n3) If the lawyer is a man, then the doctor is a man. \n\r\nWhose occupation do you know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Cooper is the doctor.\n<|im_start|>answer\nMr. Cooper is the doctor.\n<|im_end|>" }, { "id": "#8585", "title": "Beautiful Question", "fun": 2.31, "difficulty": 1.96, "author": "lesternoronha1", "desc": "One day a beautiful maiden with beaming eyes, asked me which number when multiplied by 3, then increased by three-fourth's of the product, divided by 7, diminished by one third of the quotient, multiplied by itself, diminished by 52, the square root found , addition of 8, division by 10 gives the number 2?\n\r\nSeeing her beauty I forgot the question!!!\r\nCan you help me find the result of the above question?", "hint": "Go in the reverse order.", "answer": "28.\r\nReversing the whole process helps you find the answer.\r\n(2*10-8) squared ... will yield the result 28", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day a beautiful maiden with beaming eyes, asked me which number when multiplied by 3, then increased by three-fourth's of the product, divided by 7, diminished by one third of the quotient, multiplied by itself, diminished by 52, the square root found , addition of 8, division by 10 gives the number 2?\n\r\nSeeing her beauty I forgot the question!!!\r\nCan you help me find the result of the above question?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n28.\r\nReversing the whole process helps you find the answer.\r\n(2*10-8) squared ... will yield the result 28\n<|im_start|>answer\n28.\r\nReversing the whole process helps you find the answer.\r\n(2*10-8) squared ... will yield the result 28\n<|im_end|>" }, { "id": "#19378", "title": "Mad Ade's Magic Square", "fun": 2.31, "difficulty": 2.21, "author": "Mad-Ade", "desc": "Mad Ade placed the numbers 1-9 into a 3x3 grid, such that the four sides and the two diagonals each have the same sum (greater than 15.) What is the number in the center of the grid?", "hint": "No hint available.", "answer": "3\r\nthere is only one solution.\n\r\n7 2 9\r\n5 3 1\r\n6 4 8", "category": "Math", "date": "11/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade placed the numbers 1-9 into a 3x3 grid, such that the four sides and the two diagonals each have the same sum (greater than 15.) What is the number in the center of the grid?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3\r\nthere is only one solution.\n\r\n7 2 9\r\n5 3 1\r\n6 4 8\n<|im_start|>answer\n3\r\nthere is only one solution.\n\r\n7 2 9\r\n5 3 1\r\n6 4 8\n<|im_end|>" }, { "id": "#4864", "title": "One in Ten", "fun": 2.31, "difficulty": 2.05, "author": "mad-ade", "desc": "Replace each letter by a digit. Each letter must be represented by the same digit and no beginning letter of a word can be 0.\n\n\r\nO N E\r\nO N E\r\nO N E\r\nO N E+\r\n-------\r\nT E N", "hint": "No hint available.", "answer": "0 =1, N = 8 ,E = 2, T = 7\n\n\r\n1 8 2\r\n1 8 2\r\n1 8 2\r\n1 8 2+\r\n------\r\n7 2 8", "category": "Math", "date": "06/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nReplace each letter by a digit. Each letter must be represented by the same digit and no beginning letter of a word can be 0.\n\n\r\nO N E\r\nO N E\r\nO N E\r\nO N E+\r\n-------\r\nT E N\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0 =1, N = 8 ,E = 2, T = 7\n\n\r\n1 8 2\r\n1 8 2\r\n1 8 2\r\n1 8 2+\r\n------\r\n7 2 8\n<|im_start|>answer\n0 =1, N = 8 ,E = 2, T = 7\n\n\r\n1 8 2\r\n1 8 2\r\n1 8 2\r\n1 8 2+\r\n------\r\n7 2 8\n<|im_end|>" }, { "id": "#40343", "title": "What's the Grade?", "fun": 2.31, "difficulty": 0.65, "author": "LCVolleyball", "desc": "Just as Mrs. Brainkle was going to print the grades, her computer crashed! She hurriedly tried to remember who has received what grade and who had what last name.\n\n\r\n1. Bob loves to make people laugh and this is reflected in his last name.\n\r\n2. VanHalen is not only top of her class in music, but also in her school work.\n\r\n3. Bunntington is afraid to show his parents his grades because he knows he was the bottom of the class. \n\r\n4. Sue received a 79%.\n\r\n5. Ms. Wyven did not do as well as Mr. Jokerman. \n\r\n6. Ron was not proud, unlike Bob, who couldn't wait to get home.", "hint": "Lindsey and Sue are the 2 girls.\n\r\nBob and Ron are the 2 guys.", "answer": "Lindsey VanHalen passed with flying colors and a 99%.\n\r\nBob Jokerman will please his parents with a 89%.\n\r\nSue Wyven will have a stern talk from her parents because of her 79%.\n\r\nRon Bunntington is looking at a month of being grounded because of his 69%.", "category": "Logic-Grid", "date": "02/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJust as Mrs. Brainkle was going to print the grades, her computer crashed! She hurriedly tried to remember who has received what grade and who had what last name.\n\n\r\n1. Bob loves to make people laugh and this is reflected in his last name.\n\r\n2. VanHalen is not only top of her class in music, but also in her school work.\n\r\n3. Bunntington is afraid to show his parents his grades because he knows he was the bottom of the class. \n\r\n4. Sue received a 79%.\n\r\n5. Ms. Wyven did not do as well as Mr. Jokerman. \n\r\n6. Ron was not proud, unlike Bob, who couldn't wait to get home.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLindsey VanHalen passed with flying colors and a 99%.\n\r\nBob Jokerman will please his parents with a 89%.\n\r\nSue Wyven will have a stern talk from her parents because of her 79%.\n\r\nRon Bunntington is looking at a month of being grounded because of his 69%.\n<|im_start|>answer\nLindsey VanHalen passed with flying colors and a 99%.\n\r\nBob Jokerman will please his parents with a 89%.\n\r\nSue Wyven will have a stern talk from her parents because of her 79%.\n\r\nRon Bunntington is looking at a month of being grounded because of his 69%.\n<|im_end|>" }, { "id": "#1846", "title": "300 to 400", "fun": 2.31, "difficulty": 1.39, "author": "maxmars", "desc": "If you wrote all the integers from 300 to 400 how many times would you write the digit 3?", "hint": "No hint available.", "answer": "120 times", "category": "Math", "date": "12/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you wrote all the integers from 300 to 400 how many times would you write the digit 3?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n120 times\n<|im_start|>answer\n120 times\n<|im_end|>" }, { "id": "#4383", "title": "Truck Driving", "fun": 2.31, "difficulty": 1.68, "author": "mad-ade", "desc": "Once upon a time Mad Ade had a job as a truck driver. One day he had to leave his depot and drive his truck to the river dock to pick up supplies for his boss. At 4:05 PM, one-fifth of the way to the dock, he passes his favourite Kebab shop \"The Sweaty Chef\". At 4:15 PM, one-third of the way, he passes his favourite shop, \"Honest Ron's Second Hand Underpants Repair Shop and Swaparama\". At what time did Mad Ade reach the dock, assuming he didn't stop for a Kebab or a look around Honest Ron's?", "hint": "No hint available.", "answer": "5:05 PM \n\r\nAt 4:05 PM, Mad Ade passes the Kebab shop, one-fifth of the way to the dock. Also, at 4:15 PM, he passes the Underpant shop, one-third of the way. Thus, he travels 2/15 (1/3 - 1/5) of the distance in 10 minutes. \n\r\nAt 4:15 PM, Mad Ade has already travelled 1/3 of the distance. Thus 2/3 of the way is remaining, which can be travelled in \r\n= ( (2/3) * 10 ) / (2/15) \r\n= 50 minutes \n\r\nAt 4:15, Mad Ade was at Honest Ron's Underpants shop, and remaining way will take 50 more minutes. Hence, Mad Ade will reach the docks at 5:05 PM.", "category": "Logic", "date": "05/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce upon a time Mad Ade had a job as a truck driver. One day he had to leave his depot and drive his truck to the river dock to pick up supplies for his boss. At 4:05 PM, one-fifth of the way to the dock, he passes his favourite Kebab shop \"The Sweaty Chef\". At 4:15 PM, one-third of the way, he passes his favourite shop, \"Honest Ron's Second Hand Underpants Repair Shop and Swaparama\". At what time did Mad Ade reach the dock, assuming he didn't stop for a Kebab or a look around Honest Ron's?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5:05 PM \n\r\nAt 4:05 PM, Mad Ade passes the Kebab shop, one-fifth of the way to the dock. Also, at 4:15 PM, he passes the Underpant shop, one-third of the way. Thus, he travels 2/15 (1/3 - 1/5) of the distance in 10 minutes. \n\r\nAt 4:15 PM, Mad Ade has already travelled 1/3 of the distance. Thus 2/3 of the way is remaining, which can be travelled in \r\n= ( (2/3) * 10 ) / (2/15) \r\n= 50 minutes \n\r\nAt 4:15, Mad Ade was at Honest Ron's Underpants shop, and remaining way will take 50 more minutes. Hence, Mad Ade will reach the docks at 5:05 PM.\n<|im_start|>answer\n5:05 PM \n\r\nAt 4:05 PM, Mad Ade passes the Kebab shop, one-fifth of the way to the dock. Also, at 4:15 PM, he passes the Underpant shop, one-third of the way. Thus, he travels 2/15 (1/3 - 1/5) of the distance in 10 minutes. \n\r\nAt 4:15 PM, Mad Ade has already travelled 1/3 of the distance. Thus 2/3 of the way is remaining, which can be travelled in \r\n= ( (2/3) * 10 ) / (2/15) \r\n= 50 minutes \n\r\nAt 4:15, Mad Ade was at Honest Ron's Underpants shop, and remaining way will take 50 more minutes. Hence, Mad Ade will reach the docks at 5:05 PM.\n<|im_end|>" }, { "id": "#958", "title": "100 Golfers", "fun": 2.31, "difficulty": 1.48, "author": "Michelle", "desc": "There are 100 golfers in the local match play contest. Each match has only 2 players. If a player loses a match, he is immediately eliminated from the contest. How many matches will be played to determine the winner?", "hint": "No hint available.", "answer": "If there is to be only one winner, then there are 99 losers, therefore there were 99 matches. You can also do this with math: in round 1 there would be 50 matches to produce 50 winners, round 2 would have 25 matches to produce 25 winners, round 3 would have 12 matches to produce 12 winners ( one person of the 25 winners would have to wait until later to play again ), round 4 would have 6 matches to produce 6 winners, round 5 would have 3 matches to produce 3 winners, round 6 would have 2 matches ( the player left out before would now play to make it an even field ) to produce 2 winners, these 2 would play for the championship. So: 50+25+12+6+3+2+1=99", "category": "Math", "date": "10/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 100 golfers in the local match play contest. Each match has only 2 players. If a player loses a match, he is immediately eliminated from the contest. How many matches will be played to determine the winner?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf there is to be only one winner, then there are 99 losers, therefore there were 99 matches. You can also do this with math: in round 1 there would be 50 matches to produce 50 winners, round 2 would have 25 matches to produce 25 winners, round 3 would have 12 matches to produce 12 winners ( one person of the 25 winners would have to wait until later to play again ), round 4 would have 6 matches to produce 6 winners, round 5 would have 3 matches to produce 3 winners, round 6 would have 2 matches ( the player left out before would now play to make it an even field ) to produce 2 winners, these 2 would play for the championship. So: 50+25+12+6+3+2+1=99\n<|im_start|>answer\nIf there is to be only one winner, then there are 99 losers, therefore there were 99 matches. You can also do this with math: in round 1 there would be 50 matches to produce 50 winners, round 2 would have 25 matches to produce 25 winners, round 3 would have 12 matches to produce 12 winners ( one person of the 25 winners would have to wait until later to play again ), round 4 would have 6 matches to produce 6 winners, round 5 would have 3 matches to produce 3 winners, round 6 would have 2 matches ( the player left out before would now play to make it an even field ) to produce 2 winners, these 2 would play for the championship. So: 50+25+12+6+3+2+1=99\n<|im_end|>" }, { "id": "#9192", "title": "987654321", "fun": 2.31, "difficulty": 1.79, "author": "warrior", "desc": "How many addition signs should be put among the digits of the number 987654321 and where should they be put to get a total of 99?", "hint": "No hint available.", "answer": "Answer #1; Six addition signs are required:\n\r\n9+8+7+6+5+43+21 = 99\n\r\nAnswer #2; Seven addition signs could be used:\n\r\n9+8+7+65+4+3+2+1", "category": "Math", "date": "12/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many addition signs should be put among the digits of the number 987654321 and where should they be put to get a total of 99?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer #1; Six addition signs are required:\n\r\n9+8+7+6+5+43+21 = 99\n\r\nAnswer #2; Seven addition signs could be used:\n\r\n9+8+7+65+4+3+2+1\n<|im_start|>answer\nAnswer #1; Six addition signs are required:\n\r\n9+8+7+6+5+43+21 = 99\n\r\nAnswer #2; Seven addition signs could be used:\n\r\n9+8+7+65+4+3+2+1\n<|im_end|>" }, { "id": "#8923", "title": "Ten Coins", "fun": 2.31, "difficulty": 1.49, "author": "electronjohn", "desc": "A man has ten coins totaling $1.19. From these coins, he cannot make exact change for a dollar, half-dollar, quarter, dime, or nickel. What are the coins?", "hint": "He can have any of the coins listed, he just can not make change for them.", "answer": "A half-dollar, a quarter, four dimes, and four pennies.", "category": "Math", "date": "12/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man has ten coins totaling $1.19. From these coins, he cannot make exact change for a dollar, half-dollar, quarter, dime, or nickel. What are the coins?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA half-dollar, a quarter, four dimes, and four pennies.\n<|im_start|>answer\nA half-dollar, a quarter, four dimes, and four pennies.\n<|im_end|>" }, { "id": "#5451", "title": "Small Cubes", "fun": 2.31, "difficulty": 2.73, "author": "mad-ade", "desc": "A solid wooden cuboid is made which measures an exact, and even, number of centimetres along each of its edges. It is then painted black all over its exposed faces and, when the paint is dry, the cuboid is cut up into 1 centimetre cubes. These small cubes are counted and it is then found that the number having NO paint on them at all, is exactly the same as the number which do have some paint on them. What is the LEAST number of small cubes there could be in total?", "hint": "No hint available.", "answer": "Least is 960 (8 by 10 by 12)", "category": "Math", "date": "07/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA solid wooden cuboid is made which measures an exact, and even, number of centimetres along each of its edges. It is then painted black all over its exposed faces and, when the paint is dry, the cuboid is cut up into 1 centimetre cubes. These small cubes are counted and it is then found that the number having NO paint on them at all, is exactly the same as the number which do have some paint on them. What is the LEAST number of small cubes there could be in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeast is 960 (8 by 10 by 12)\n<|im_start|>answer\nLeast is 960 (8 by 10 by 12)\n<|im_end|>" }, { "id": "#4760", "title": "Kebab Pies", "fun": 2.31, "difficulty": 1.96, "author": "mad-ade", "desc": "Mad Ade was making Kebab pies to send to his friends. He has 100 kebab pies and 5 boxes to put them in.\n\r\nBox #1 and Box #2 together contain 52 Pies.\r\nBox #2 and Box #3 together contain 43 Pies.\r\nBox #3 and Box #4 together contain 34 Pies.\r\nBox #4 and Box #5 together contain 30 Pies.\n\r\nHow many Pies are there in each box?", "hint": "No hint available.", "answer": "Boxes #1, #2, #4, and #5 together contain 82 Pies. Therefore, Box #3 must contain 18 Pies. With that piece of information, you can figure out how many kebab pies the other bags contain: \r\nYou know Box #2 and Box #3 = 43 Pies; you know Box #3 = 18 Pies; therefore, Box #2 contains 25 Pies. \n\r\nYou know that Box #1 and Box #2 = 52 Pies; therefore, Box #1 contains 27.\n\r\nYou know Box #3 and Box #4 = 34 Pies; you know Box #3 = 18 Pies; therefore, Box #4 contains 16 Pies. \n\r\nYou know that Box # 4 and Box #5 = 30 Pies; you know that Box #4 contains 16 Pies; therefore, Box #5 contains 14 Pies.", "category": "Math", "date": "06/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was making Kebab pies to send to his friends. He has 100 kebab pies and 5 boxes to put them in.\n\r\nBox #1 and Box #2 together contain 52 Pies.\r\nBox #2 and Box #3 together contain 43 Pies.\r\nBox #3 and Box #4 together contain 34 Pies.\r\nBox #4 and Box #5 together contain 30 Pies.\n\r\nHow many Pies are there in each box?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoxes #1, #2, #4, and #5 together contain 82 Pies. Therefore, Box #3 must contain 18 Pies. With that piece of information, you can figure out how many kebab pies the other bags contain: \r\nYou know Box #2 and Box #3 = 43 Pies; you know Box #3 = 18 Pies; therefore, Box #2 contains 25 Pies. \n\r\nYou know that Box #1 and Box #2 = 52 Pies; therefore, Box #1 contains 27.\n\r\nYou know Box #3 and Box #4 = 34 Pies; you know Box #3 = 18 Pies; therefore, Box #4 contains 16 Pies. \n\r\nYou know that Box # 4 and Box #5 = 30 Pies; you know that Box #4 contains 16 Pies; therefore, Box #5 contains 14 Pies.\n<|im_start|>answer\nBoxes #1, #2, #4, and #5 together contain 82 Pies. Therefore, Box #3 must contain 18 Pies. With that piece of information, you can figure out how many kebab pies the other bags contain: \r\nYou know Box #2 and Box #3 = 43 Pies; you know Box #3 = 18 Pies; therefore, Box #2 contains 25 Pies. \n\r\nYou know that Box #1 and Box #2 = 52 Pies; therefore, Box #1 contains 27.\n\r\nYou know Box #3 and Box #4 = 34 Pies; you know Box #3 = 18 Pies; therefore, Box #4 contains 16 Pies. \n\r\nYou know that Box # 4 and Box #5 = 30 Pies; you know that Box #4 contains 16 Pies; therefore, Box #5 contains 14 Pies.\n<|im_end|>" }, { "id": "#18943", "title": "Tweeto's Puzzle !!!", "fun": 2.31, "difficulty": 2.58, "author": "lesternoronha1", "desc": "The other day I was surprised by the sudden arrival of my friend Tweeto. He had arrived that morning after a long and arduous journey by train. Although he was quite tired out by the sheer length of the journey, he never wanted to miss a chance to catch me off guard with my math. As soon as he came in, he lay down a puzzle before me which quite took me by surprise.\n\r\nHe said his train journey had taken him through six stations: Maver, Willow, Wonderland, Doku, Lemp, culminating in the Rudolf Railway terminal (named after my grandfather Rudolf, the world-famous RomanKachi), from where he'd taken a cab to my house. He was one amongst the few people in the train as it had chugged into Maver. \n\r\nThese were his observations :-\r\n1) At each of the stations Maver, Willow, Wonderland, Doku, Lemp and Rudolf, twice as many people got in as those that got down. \r\n2) Further, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, and so on up to in between 50 and 60 at Rudolf in the order of the stations mentioned above.\r\n3) Also, the difference between the number of people getting in at any two consecutive stations was at least 20.\r\n4) Finally, the total number of passengers getting down in all six stations together was an even number.\n\r\nHe wanted to know how many people (including him) were on the train before it had reached the Maver railway station if there were 227 people on it when it chugged into Rudolf (227 includes the people getting in and out at Rudolf). \n\r\nIt didn't take me long to disappoint him by finding the answer. Can you recreate history by solving my dear friend Tweeto's puzzle?", "hint": "No hint available.", "answer": "The observations given are :- \r\n1) At each of the stations Maver, Willow, Wonderland, Doku, Lemp and Rudolf, twice as many people got in as those that got down. \r\n2) Further, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, and so on up to in between 50 and 60 at Rudolf in the order of the stations mentioned above. \r\n3) Also, the difference between the number of people getting in at any two consecutive stations was at least 20. \r\n4) Finally, the total number of passengers getting down in all six stations together was an even number. \n\r\nFrom observations 1 and 3, since the difference between the number of people getting in at any two consecutive stations was at least 20, it means that the difference between the number of people getting down at any two consecutive stations was at least 10. \n\r\nLet us start with the people getting down at Rudolf. \r\nFrom observation 2, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, in between 20 and 30 at Wonderland, in between 30 and 40 at Doku, in between 40 and 50 at Lemp, and in between 50 and 60 at Rudolf. \n\r\nHence, the number of people getting down at Rudolf should be either 53 or 59. \r\nIf it is 53, then the number of people getting down at Lemp should be either 43 or 41, and that at Doku has to be 31 (keeping in mind the condition that the difference between the number of people getting down at any two consecutive stations was at least 10). However, we cannot get a prime number for Wonderland in between 20 and 30 with a difference of 10 from Doku then. \n\r\nThis means that the number of people getting down at Doku must be 37 and not 31. Then, the figures for Lemp and Rudolf have to be 47 and 59 respectively. Then, we get the number of people getting down at Wonderland as 23. Now the figure for Willow can be 11 or 13. But if it is 11, we are left with no prime number for Maver (with a difference of 10). Hence, the number of people getting down at Willow must be 13. \n\r\nNow the number of people getting down at Maver can be either 2 or 3. If this figure is 2, condition 4 would be violated, since the total number of passengers getting down in all six stations together would be an odd number. Hence, the figure for Maver should be 3. \n\r\nListing all these figures we have \n\r\n(1st column is Station, 2nd is Getting down, 3rd is Getting in) \n\r\nMaver 3 6 \r\nWillow 13 26 \r\nWonderland 23 46 \r\nDoku 37 74 \r\nLemp 47 94 \r\nRudolf 59 118 \r\nTotal 182 364 \n\r\nGiven that the number of people when the train chugged into Rudolf is 227, the number of people including Tweeto in the train before it reached Maver = \r\n(Number of people in the train at Rudolf) - (Net number of people who got in at the six stations) = \r\n(Number of people in the train at Rudolf) - (Number of people who got in at the six stations - Number of people who got out at the six stations) = \r\n227 - (364 - 182) = \r\n227 - 182 = \r\n45 people \n\r\nThus, I disappointed Tweeto by giving him the answer as 45 people.", "category": "Math", "date": "09/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe other day I was surprised by the sudden arrival of my friend Tweeto. He had arrived that morning after a long and arduous journey by train. Although he was quite tired out by the sheer length of the journey, he never wanted to miss a chance to catch me off guard with my math. As soon as he came in, he lay down a puzzle before me which quite took me by surprise.\n\r\nHe said his train journey had taken him through six stations: Maver, Willow, Wonderland, Doku, Lemp, culminating in the Rudolf Railway terminal (named after my grandfather Rudolf, the world-famous RomanKachi), from where he'd taken a cab to my house. He was one amongst the few people in the train as it had chugged into Maver. \n\r\nThese were his observations :-\r\n1) At each of the stations Maver, Willow, Wonderland, Doku, Lemp and Rudolf, twice as many people got in as those that got down. \r\n2) Further, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, and so on up to in between 50 and 60 at Rudolf in the order of the stations mentioned above.\r\n3) Also, the difference between the number of people getting in at any two consecutive stations was at least 20.\r\n4) Finally, the total number of passengers getting down in all six stations together was an even number.\n\r\nHe wanted to know how many people (including him) were on the train before it had reached the Maver railway station if there were 227 people on it when it chugged into Rudolf (227 includes the people getting in and out at Rudolf). \n\r\nIt didn't take me long to disappoint him by finding the answer. Can you recreate history by solving my dear friend Tweeto's puzzle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe observations given are :- \r\n1) At each of the stations Maver, Willow, Wonderland, Doku, Lemp and Rudolf, twice as many people got in as those that got down. \r\n2) Further, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, and so on up to in between 50 and 60 at Rudolf in the order of the stations mentioned above. \r\n3) Also, the difference between the number of people getting in at any two consecutive stations was at least 20. \r\n4) Finally, the total number of passengers getting down in all six stations together was an even number. \n\r\nFrom observations 1 and 3, since the difference between the number of people getting in at any two consecutive stations was at least 20, it means that the difference between the number of people getting down at any two consecutive stations was at least 10. \n\r\nLet us start with the people getting down at Rudolf. \r\nFrom observation 2, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, in between 20 and 30 at Wonderland, in between 30 and 40 at Doku, in between 40 and 50 at Lemp, and in between 50 and 60 at Rudolf. \n\r\nHence, the number of people getting down at Rudolf should be either 53 or 59. \r\nIf it is 53, then the number of people getting down at Lemp should be either 43 or 41, and that at Doku has to be 31 (keeping in mind the condition that the difference between the number of people getting down at any two consecutive stations was at least 10). However, we cannot get a prime number for Wonderland in between 20 and 30 with a difference of 10 from Doku then. \n\r\nThis means that the number of people getting down at Doku must be 37 and not 31. Then, the figures for Lemp and Rudolf have to be 47 and 59 respectively. Then, we get the number of people getting down at Wonderland as 23. Now the figure for Willow can be 11 or 13. But if it is 11, we are left with no prime number for Maver (with a difference of 10). Hence, the number of people getting down at Willow must be 13. \n\r\nNow the number of people getting down at Maver can be either 2 or 3. If this figure is 2, condition 4 would be violated, since the total number of passengers getting down in all six stations together would be an odd number. Hence, the figure for Maver should be 3. \n\r\nListing all these figures we have \n\r\n(1st column is Station, 2nd is Getting down, 3rd is Getting in) \n\r\nMaver 3 6 \r\nWillow 13 26 \r\nWonderland 23 46 \r\nDoku 37 74 \r\nLemp 47 94 \r\nRudolf 59 118 \r\nTotal 182 364 \n\r\nGiven that the number of people when the train chugged into Rudolf is 227, the number of people including Tweeto in the train before it reached Maver = \r\n(Number of people in the train at Rudolf) - (Net number of people who got in at the six stations) = \r\n(Number of people in the train at Rudolf) - (Number of people who got in at the six stations - Number of people who got out at the six stations) = \r\n227 - (364 - 182) = \r\n227 - 182 = \r\n45 people \n\r\nThus, I disappointed Tweeto by giving him the answer as 45 people.\n<|im_start|>answer\nThe observations given are :- \r\n1) At each of the stations Maver, Willow, Wonderland, Doku, Lemp and Rudolf, twice as many people got in as those that got down. \r\n2) Further, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, and so on up to in between 50 and 60 at Rudolf in the order of the stations mentioned above. \r\n3) Also, the difference between the number of people getting in at any two consecutive stations was at least 20. \r\n4) Finally, the total number of passengers getting down in all six stations together was an even number. \n\r\nFrom observations 1 and 3, since the difference between the number of people getting in at any two consecutive stations was at least 20, it means that the difference between the number of people getting down at any two consecutive stations was at least 10. \n\r\nLet us start with the people getting down at Rudolf. \r\nFrom observation 2, the number of people getting down at each of these stations were all prime numbers - one each in between 0 and 10 at Maver, in between 10 and 20 at Willow, in between 20 and 30 at Wonderland, in between 30 and 40 at Doku, in between 40 and 50 at Lemp, and in between 50 and 60 at Rudolf. \n\r\nHence, the number of people getting down at Rudolf should be either 53 or 59. \r\nIf it is 53, then the number of people getting down at Lemp should be either 43 or 41, and that at Doku has to be 31 (keeping in mind the condition that the difference between the number of people getting down at any two consecutive stations was at least 10). However, we cannot get a prime number for Wonderland in between 20 and 30 with a difference of 10 from Doku then. \n\r\nThis means that the number of people getting down at Doku must be 37 and not 31. Then, the figures for Lemp and Rudolf have to be 47 and 59 respectively. Then, we get the number of people getting down at Wonderland as 23. Now the figure for Willow can be 11 or 13. But if it is 11, we are left with no prime number for Maver (with a difference of 10). Hence, the number of people getting down at Willow must be 13. \n\r\nNow the number of people getting down at Maver can be either 2 or 3. If this figure is 2, condition 4 would be violated, since the total number of passengers getting down in all six stations together would be an odd number. Hence, the figure for Maver should be 3. \n\r\nListing all these figures we have \n\r\n(1st column is Station, 2nd is Getting down, 3rd is Getting in) \n\r\nMaver 3 6 \r\nWillow 13 26 \r\nWonderland 23 46 \r\nDoku 37 74 \r\nLemp 47 94 \r\nRudolf 59 118 \r\nTotal 182 364 \n\r\nGiven that the number of people when the train chugged into Rudolf is 227, the number of people including Tweeto in the train before it reached Maver = \r\n(Number of people in the train at Rudolf) - (Net number of people who got in at the six stations) = \r\n(Number of people in the train at Rudolf) - (Number of people who got in at the six stations - Number of people who got out at the six stations) = \r\n227 - (364 - 182) = \r\n227 - 182 = \r\n45 people \n\r\nThus, I disappointed Tweeto by giving him the answer as 45 people.\n<|im_end|>" }, { "id": "#3033", "title": "Five Hands", "fun": 2.31, "difficulty": 1.84, "author": "lil_thugsta", "desc": "What person has 5 (sometimes 4) hands but is still normal?", "hint": "No hint available.", "answer": "A person wearing a non digital watch - A person has 2 hands, + a minute hand on the watch, + an hour hand, and sometimes a second hand.", "category": "Logic", "date": "03/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat person has 5 (sometimes 4) hands but is still normal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA person wearing a non digital watch - A person has 2 hands, + a minute hand on the watch, + an hour hand, and sometimes a second hand.\n<|im_start|>answer\nA person wearing a non digital watch - A person has 2 hands, + a minute hand on the watch, + an hour hand, and sometimes a second hand.\n<|im_end|>" }, { "id": "#17176", "title": "Alphabet Soup", "fun": 2.31, "difficulty": 2.11, "author": "FrostedTangerine", "desc": "Jeremy sat down at the table, and prepared to eat his alphabet soup for brunch. Before putting anything in his mouth, Jeremy took out all of the letters in the bowl, and separated them into groups on his napkin. After counting them, he realized that there were:\n\r\n3- I, K, V, X, and Z's.\r\n6- A, D, F, L, and R's.\r\n7- B, C, M, N, P, Q, S, T, U, W, and Y's.\r\n8- E, G, H, J, and O's\n\r\nJeremy went ahead and ate 4 of the letters, all 4 of them were vowels. Then he fed 2 consonants to his dog. Then he picked out the letters in his name, from the napkin, and spelled his name further down from the rest of the letters: JEREMY\n\r\nAfter that, he recounted the letters from the soup, before putting them all back in the bowl. He did not put his spelled name back in the bowl. There were:\n\r\n2- I's.\r\n3- K, V, X and Z's.\r\n4- E's.\r\n5- R's.\r\n6- A, D, F, Q, L, Y, B and M's.\r\n7- C, J, N, O, P, S, T, U, and W's.\r\n8- G and H's.\n\r\nQUESTION: Which 4 vowels did Jeremy eat, and which 2 consonants did he feed his dog?", "hint": "Look at the remaining sets of letters, the ones left, after Jeremy ate 4 and fed 2 to his dog. Try to discover which letters now have less than before Jeremy ate 4 and fed 2 to his dog.", "answer": "He ate two E's, one I and one O. He fed his dog one B, and one Q. Don't believe me? Try it on a piece of paper! Write down all of the answers in the soup. Cross out the letters required to spell Jeremy. Then after reading the remaining letters in the soup, find the letters that were knocked down by one number. Cross out those. But I promise this is the answer!", "category": "Math", "date": "03/31/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeremy sat down at the table, and prepared to eat his alphabet soup for brunch. Before putting anything in his mouth, Jeremy took out all of the letters in the bowl, and separated them into groups on his napkin. After counting them, he realized that there were:\n\r\n3- I, K, V, X, and Z's.\r\n6- A, D, F, L, and R's.\r\n7- B, C, M, N, P, Q, S, T, U, W, and Y's.\r\n8- E, G, H, J, and O's\n\r\nJeremy went ahead and ate 4 of the letters, all 4 of them were vowels. Then he fed 2 consonants to his dog. Then he picked out the letters in his name, from the napkin, and spelled his name further down from the rest of the letters: JEREMY\n\r\nAfter that, he recounted the letters from the soup, before putting them all back in the bowl. He did not put his spelled name back in the bowl. There were:\n\r\n2- I's.\r\n3- K, V, X and Z's.\r\n4- E's.\r\n5- R's.\r\n6- A, D, F, Q, L, Y, B and M's.\r\n7- C, J, N, O, P, S, T, U, and W's.\r\n8- G and H's.\n\r\nQUESTION: Which 4 vowels did Jeremy eat, and which 2 consonants did he feed his dog?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe ate two E's, one I and one O. He fed his dog one B, and one Q. Don't believe me? Try it on a piece of paper! Write down all of the answers in the soup. Cross out the letters required to spell Jeremy. Then after reading the remaining letters in the soup, find the letters that were knocked down by one number. Cross out those. But I promise this is the answer!\n<|im_start|>answer\nHe ate two E's, one I and one O. He fed his dog one B, and one Q. Don't believe me? Try it on a piece of paper! Write down all of the answers in the soup. Cross out the letters required to spell Jeremy. Then after reading the remaining letters in the soup, find the letters that were knocked down by one number. Cross out those. But I promise this is the answer!\n<|im_end|>" }, { "id": "#39977", "title": "ABC-DEF-GHIJ", "fun": 2.31, "difficulty": 2.39, "author": "shenqiang", "desc": "A telephone number has the form ABC-DEF-GHIJ, where each letter represents a different digit. The digits in each part of the number are in decreasing order; that is, ABC, DEF, and GHIJ. Furthermore, D, E, and F are consecutive even digits; G, H, I, and J are consecutive odd digits; and A+B+C=9. What is A?", "hint": "No hint available.", "answer": "The consecutive even digits DEF can be 420, 642 or 864, while the consecutive odd digits GHIJ can be 7531 or 9753.\n\r\nSince A+B+C=9, none of them can be 9, and GHIJ must be 9753, and one of A, B, C is 1.\n\r\nThe other two add up to 8, which is obtained by 8+0.\n\r\nTherefore, A, the biggest number of the three, is 8.", "category": "Logic", "date": "01/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA telephone number has the form ABC-DEF-GHIJ, where each letter represents a different digit. The digits in each part of the number are in decreasing order; that is, ABC, DEF, and GHIJ. Furthermore, D, E, and F are consecutive even digits; G, H, I, and J are consecutive odd digits; and A+B+C=9. What is A?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe consecutive even digits DEF can be 420, 642 or 864, while the consecutive odd digits GHIJ can be 7531 or 9753.\n\r\nSince A+B+C=9, none of them can be 9, and GHIJ must be 9753, and one of A, B, C is 1.\n\r\nThe other two add up to 8, which is obtained by 8+0.\n\r\nTherefore, A, the biggest number of the three, is 8.\n<|im_start|>answer\nThe consecutive even digits DEF can be 420, 642 or 864, while the consecutive odd digits GHIJ can be 7531 or 9753.\n\r\nSince A+B+C=9, none of them can be 9, and GHIJ must be 9753, and one of A, B, C is 1.\n\r\nThe other two add up to 8, which is obtained by 8+0.\n\r\nTherefore, A, the biggest number of the three, is 8.\n<|im_end|>" }, { "id": "#4305", "title": "Watery Drink", "fun": 2.31, "difficulty": 1.96, "author": "mad-ade", "desc": "Mad Ade is stranded on a desert island (much to the relief of many). Other than just water, all he has to drink is a 20oz bottle of cola.\n\r\nTo conserve his luxury cola he decides that on the first day he will drink one oz and then refill the bottle back up with water. On the 2nd day he will drink 2oz and refill the bottle. On the 3rd day he will drink 3oz and so on... \n\r\nBy the time all the cola is gone, how much water has Mad Ade drunk?", "hint": "No hint available.", "answer": "Mad Ade has drunk 190oz of water. \n\r\nIt is given that the Mad Ade has 20oz bottle of Cola. \r\nAlso, he will drink 1oz on the first day and refill the bottle with water, \r\nwill drink 2oz on the second day and refill the bottle,\r\n will drink 3oz on the third day and refill the bottle, \r\nand so on till 20th day. \r\nThus at the end of 20 days, he must have drunk \r\n(1 + 2 + 3 + 4 + ..... +18 + 19 + 20) = 210oz of liquid. \n\r\nOut of that 210oz, 20oz is the Cola which he had initially. \n\r\nHence, Mad Ade must have drunk 190oz of water.", "category": "Math", "date": "05/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is stranded on a desert island (much to the relief of many). Other than just water, all he has to drink is a 20oz bottle of cola.\n\r\nTo conserve his luxury cola he decides that on the first day he will drink one oz and then refill the bottle back up with water. On the 2nd day he will drink 2oz and refill the bottle. On the 3rd day he will drink 3oz and so on... \n\r\nBy the time all the cola is gone, how much water has Mad Ade drunk?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade has drunk 190oz of water. \n\r\nIt is given that the Mad Ade has 20oz bottle of Cola. \r\nAlso, he will drink 1oz on the first day and refill the bottle with water, \r\nwill drink 2oz on the second day and refill the bottle,\r\n will drink 3oz on the third day and refill the bottle, \r\nand so on till 20th day. \r\nThus at the end of 20 days, he must have drunk \r\n(1 + 2 + 3 + 4 + ..... +18 + 19 + 20) = 210oz of liquid. \n\r\nOut of that 210oz, 20oz is the Cola which he had initially. \n\r\nHence, Mad Ade must have drunk 190oz of water.\n<|im_start|>answer\nMad Ade has drunk 190oz of water. \n\r\nIt is given that the Mad Ade has 20oz bottle of Cola. \r\nAlso, he will drink 1oz on the first day and refill the bottle with water, \r\nwill drink 2oz on the second day and refill the bottle,\r\n will drink 3oz on the third day and refill the bottle, \r\nand so on till 20th day. \r\nThus at the end of 20 days, he must have drunk \r\n(1 + 2 + 3 + 4 + ..... +18 + 19 + 20) = 210oz of liquid. \n\r\nOut of that 210oz, 20oz is the Cola which he had initially. \n\r\nHence, Mad Ade must have drunk 190oz of water.\n<|im_end|>" }, { "id": "#48899", "title": "Number Pyramid 2", "fun": 2.31, "difficulty": 2.35, "author": "westbrook1", "desc": "This teaser is a mixture of logic and math. In a number pyramid, the numbers 0-9 are each used once and formed into a pyramid, with one digits at the top, and right below it two digits, below those three digits, and below those four, all arranged in pyramid form. I can not show you a pyramid due to formatting issues. \n\r\nIn this puzzle, you will follow the clues given, and using these clues, create a number pyramid. There is only one answer.\n\r\nClues:\n\r\n1. The number at the apex, or top, of the pyramid minus the leftmost number in the fourth row equals 7.\n\r\n2. The middle, or second, number in the third row minus the rightmost number in the third row equals 4.\n\r\n3. The four numbers in row 4 sum to 8.\n\r\n4. In the second row, the rightmost number minus the leftmost number equals 1.\n\r\n5. The four rightmost numbers in each row sum to 25.\n\r\n6. The numbers 1 and 2 are not adjacent to each other.", "hint": "The apex of this pyramid is 9.", "answer": "Here is the way the number pyramid is filled out:\n\r\nRow 1: 9\r\nRow 2: 6, 7\r\nRow 3: 3, 8, 4\r\nRow 4: 2, 0, 1, 5", "category": "Logic", "date": "08/01/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is a mixture of logic and math. In a number pyramid, the numbers 0-9 are each used once and formed into a pyramid, with one digits at the top, and right below it two digits, below those three digits, and below those four, all arranged in pyramid form. I can not show you a pyramid due to formatting issues. \n\r\nIn this puzzle, you will follow the clues given, and using these clues, create a number pyramid. There is only one answer.\n\r\nClues:\n\r\n1. The number at the apex, or top, of the pyramid minus the leftmost number in the fourth row equals 7.\n\r\n2. The middle, or second, number in the third row minus the rightmost number in the third row equals 4.\n\r\n3. The four numbers in row 4 sum to 8.\n\r\n4. In the second row, the rightmost number minus the leftmost number equals 1.\n\r\n5. The four rightmost numbers in each row sum to 25.\n\r\n6. The numbers 1 and 2 are not adjacent to each other.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHere is the way the number pyramid is filled out:\n\r\nRow 1: 9\r\nRow 2: 6, 7\r\nRow 3: 3, 8, 4\r\nRow 4: 2, 0, 1, 5\n<|im_start|>answer\nHere is the way the number pyramid is filled out:\n\r\nRow 1: 9\r\nRow 2: 6, 7\r\nRow 3: 3, 8, 4\r\nRow 4: 2, 0, 1, 5\n<|im_end|>" }, { "id": "#45305", "title": "Equality", "fun": 2.31, "difficulty": 1.9000000000000001, "author": "wicked_one", "desc": "What mathematical signs do you have to use to make the following equality possible?\n\n\r\n1 1 1 = 6", "hint": "No hint available.", "answer": "(1 + 1 + 1)! = 6", "category": "Math", "date": "09/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat mathematical signs do you have to use to make the following equality possible?\n\n\r\n1 1 1 = 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(1 + 1 + 1)! = 6\n<|im_start|>answer\n(1 + 1 + 1)! = 6\n<|im_end|>" }, { "id": "#41772", "title": "Filling Glasses", "fun": 2.31, "difficulty": 1.83, "author": "jsteppergurl", "desc": "Joey has 8 drinking glasses, all of different sizes. He has lined them up from smallest to largest and numbered them #1 (smallest) to #8 (largest). He knows that glass #4 holds 10 ounces and that glass #7 holds a pint, or 16 ounces. Now he wants to figure out how much all the others hold!\n\r\nHe experiments by filling up different glasses with water and pouring the water back and forth into other glasses. Here are his results:\n\r\nPouring water from glasses #1 and #2 filled glass #4. \r\nPouring water from glasses #1 and #3 filled glass #5. \r\nPouring water from glasses #2 and #3 filled glass #6. \r\nPouring water from glasses #1 and #5 filled glass #7. \r\nPouring water from glasses #1 and #7 filled glass #8. \r\nPouring water twice from glass #3 filled glass #7. \r\nPouring water twice from glass #4 filled glass #8. \n\r\nHow much water does each glass hold?", "hint": "Rewrite each experiment as an equation, and then substitute the known quantities for #4 and #7 into the equations wherever you can.", "answer": "#1 holds 4 ounces \r\n#2 holds 6 ounces \r\n#3 holds 8 ounces \r\n#4 holds 10 ounces \r\n#5 holds 12 ounces \r\n#6 holds 14 ounces \r\n#7 holds 16 ounces \r\n#8 holds 20 ounces \n\n\r\nTo begin with, you know that glass #4 holds 10 ounces and that glass #7 holds 16 ounces. With this information and the given clues, you can quickly determine that glass #8 holds 20 ounces (10 ounces x 2 = 20 ounces) and that glass #3 holds 8 ounces (16 ounces / 2 = 8 ounces).\n\r\nNow you can substitute for the remaining equations and find that:\n\r\nSince #7 holds 16 ounces and #7 + #1 = #8, then #1 must hold 4 ounces (20 - 16 = 4). \r\nSince #1 + #2 = #4, then #2 must hold 6 ounces (10 - 4 = 6). \r\nSince #1 + #5 = #7, then #5 must hold 12 ounces (16 - 4 = 12). \r\nSince #2 + #3 = #6, then #6 must hold 14 ounces (6 + 8 = 14).", "category": "Math", "date": "05/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoey has 8 drinking glasses, all of different sizes. He has lined them up from smallest to largest and numbered them #1 (smallest) to #8 (largest). He knows that glass #4 holds 10 ounces and that glass #7 holds a pint, or 16 ounces. Now he wants to figure out how much all the others hold!\n\r\nHe experiments by filling up different glasses with water and pouring the water back and forth into other glasses. Here are his results:\n\r\nPouring water from glasses #1 and #2 filled glass #4. \r\nPouring water from glasses #1 and #3 filled glass #5. \r\nPouring water from glasses #2 and #3 filled glass #6. \r\nPouring water from glasses #1 and #5 filled glass #7. \r\nPouring water from glasses #1 and #7 filled glass #8. \r\nPouring water twice from glass #3 filled glass #7. \r\nPouring water twice from glass #4 filled glass #8. \n\r\nHow much water does each glass hold?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n#1 holds 4 ounces \r\n#2 holds 6 ounces \r\n#3 holds 8 ounces \r\n#4 holds 10 ounces \r\n#5 holds 12 ounces \r\n#6 holds 14 ounces \r\n#7 holds 16 ounces \r\n#8 holds 20 ounces \n\n\r\nTo begin with, you know that glass #4 holds 10 ounces and that glass #7 holds 16 ounces. With this information and the given clues, you can quickly determine that glass #8 holds 20 ounces (10 ounces x 2 = 20 ounces) and that glass #3 holds 8 ounces (16 ounces / 2 = 8 ounces).\n\r\nNow you can substitute for the remaining equations and find that:\n\r\nSince #7 holds 16 ounces and #7 + #1 = #8, then #1 must hold 4 ounces (20 - 16 = 4). \r\nSince #1 + #2 = #4, then #2 must hold 6 ounces (10 - 4 = 6). \r\nSince #1 + #5 = #7, then #5 must hold 12 ounces (16 - 4 = 12). \r\nSince #2 + #3 = #6, then #6 must hold 14 ounces (6 + 8 = 14).\n<|im_start|>answer\n#1 holds 4 ounces \r\n#2 holds 6 ounces \r\n#3 holds 8 ounces \r\n#4 holds 10 ounces \r\n#5 holds 12 ounces \r\n#6 holds 14 ounces \r\n#7 holds 16 ounces \r\n#8 holds 20 ounces \n\n\r\nTo begin with, you know that glass #4 holds 10 ounces and that glass #7 holds 16 ounces. With this information and the given clues, you can quickly determine that glass #8 holds 20 ounces (10 ounces x 2 = 20 ounces) and that glass #3 holds 8 ounces (16 ounces / 2 = 8 ounces).\n\r\nNow you can substitute for the remaining equations and find that:\n\r\nSince #7 holds 16 ounces and #7 + #1 = #8, then #1 must hold 4 ounces (20 - 16 = 4). \r\nSince #1 + #2 = #4, then #2 must hold 6 ounces (10 - 4 = 6). \r\nSince #1 + #5 = #7, then #5 must hold 12 ounces (16 - 4 = 12). \r\nSince #2 + #3 = #6, then #6 must hold 14 ounces (6 + 8 = 14).\n<|im_end|>" }, { "id": "#19095", "title": "Romankachi Card Game!!!", "fun": 2.31, "difficulty": 2.44, "author": "lesternoronha1", "desc": "I woke up late that morning to welcome a bright sunny day after a long and hectic week. It was a holiday and I was determined to spend the day playing cards with my friend Tweeto. Tweeto's favorite card game was the Romankachi card game. \n\r\nThe rules of the game are as follows :-\r\n1) One person 'serves' and the other 'receives' cards in each round.\r\n2) The person who serves cards in the round gains 2 cards if he wins the round and loses only 1 card if he loses the round.\r\n3) On the other hand, the person who receives cards in the round, gains only 1 card if he wins the round and loses 2 cards if he loses the round.\r\n4) Finally the person who wins in one round, serves in the next round.\r\n5) The game is stopped when a player loses all his cards.\n\r\nWe started off with 5 cards each and I served in the first round.\n\r\nAt the end of three rounds if I had exactly 4 cards then which of the following statements must be true:-\r\nA) Tweeto must have won exactly two rounds.\r\nB) I must have won the first round.\r\nC) Tweeto must have won the third round.\n\r\nNOTE: Out of the given set of 3 statements, it is not necessary that one and only one statement is true. One or more statements may be true.", "hint": "No hint available.", "answer": "Statements A and C must be true. \n\r\nThe rules of the Romankachi card game are given below.\r\n1) One person 'serves' and the other 'receives' cards in each round.\r\n2) The person who serves cards in the round gains 2 cards if he wins the round and loses only 1 card if he loses the round.\r\n3) On the other hand, the person who receives cards in the round, gains only 1 card if he wins the round and loses 2 cards if he loses the round.\r\n4) Finally the person who wins in one round, serves in the next round.\r\n5) The game is stopped when a player loses all his cards.\n\r\nThe given statements are \r\nA) Tweeto must have won exactly two rounds.\r\nB) I must have won the first round.\r\nC) Tweeto must have won the third round.\n\r\nSince we started the card game with 5 cards each and I started of the first round, at the end of three rounds I can have 4 cards due to any one of the following two results.\n\r\nFirst Result :\n\r\nI served in the first round and won. Hence I served in the second round but lost. Tweeto served in the third round and again I lost thus ending up with 4 cards.\r\nThe number of cards with me and Tweeto is tabulated below.\n\r\nRound Me Tweeto\r\nInitially 5 5 \r\nRound 1 7 3\r\nRound 2 6 4\r\nRound 3 4 6\n\r\nApplying the given statements to the above table, we can observe that statements A and C are true since Tweeto won exactly two rounds and Tweeto won the third round. Statement B is true here because I won the first round.\n\r\nSecond Result :\n\r\nI served in the first round and lost. Hence Tweeto served in the second round but he lost. I served in the third round and I lost thus ending up with 4 cards.\r\nThe number of cards with me and Tweeto is tabulated below.\n\r\nRound Me Tweeto\r\nInitially 5 5 \r\nRound 1 4 6\r\nRound 2 5 5\r\nRound 3 4 6\r\nApplying the given statements to the above table, we can observe that statements A and C are true since Tweeto won exactly two rounds and Tweeto won the third round. Statement B is false here because I lost the first round.\n\r\nHence it is clear from both the results that statements A and C must be true for me to end up with 4 cards at the end of three rounds.", "category": "Logic", "date": "10/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI woke up late that morning to welcome a bright sunny day after a long and hectic week. It was a holiday and I was determined to spend the day playing cards with my friend Tweeto. Tweeto's favorite card game was the Romankachi card game. \n\r\nThe rules of the game are as follows :-\r\n1) One person 'serves' and the other 'receives' cards in each round.\r\n2) The person who serves cards in the round gains 2 cards if he wins the round and loses only 1 card if he loses the round.\r\n3) On the other hand, the person who receives cards in the round, gains only 1 card if he wins the round and loses 2 cards if he loses the round.\r\n4) Finally the person who wins in one round, serves in the next round.\r\n5) The game is stopped when a player loses all his cards.\n\r\nWe started off with 5 cards each and I served in the first round.\n\r\nAt the end of three rounds if I had exactly 4 cards then which of the following statements must be true:-\r\nA) Tweeto must have won exactly two rounds.\r\nB) I must have won the first round.\r\nC) Tweeto must have won the third round.\n\r\nNOTE: Out of the given set of 3 statements, it is not necessary that one and only one statement is true. One or more statements may be true.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements A and C must be true. \n\r\nThe rules of the Romankachi card game are given below.\r\n1) One person 'serves' and the other 'receives' cards in each round.\r\n2) The person who serves cards in the round gains 2 cards if he wins the round and loses only 1 card if he loses the round.\r\n3) On the other hand, the person who receives cards in the round, gains only 1 card if he wins the round and loses 2 cards if he loses the round.\r\n4) Finally the person who wins in one round, serves in the next round.\r\n5) The game is stopped when a player loses all his cards.\n\r\nThe given statements are \r\nA) Tweeto must have won exactly two rounds.\r\nB) I must have won the first round.\r\nC) Tweeto must have won the third round.\n\r\nSince we started the card game with 5 cards each and I started of the first round, at the end of three rounds I can have 4 cards due to any one of the following two results.\n\r\nFirst Result :\n\r\nI served in the first round and won. Hence I served in the second round but lost. Tweeto served in the third round and again I lost thus ending up with 4 cards.\r\nThe number of cards with me and Tweeto is tabulated below.\n\r\nRound Me Tweeto\r\nInitially 5 5 \r\nRound 1 7 3\r\nRound 2 6 4\r\nRound 3 4 6\n\r\nApplying the given statements to the above table, we can observe that statements A and C are true since Tweeto won exactly two rounds and Tweeto won the third round. Statement B is true here because I won the first round.\n\r\nSecond Result :\n\r\nI served in the first round and lost. Hence Tweeto served in the second round but he lost. I served in the third round and I lost thus ending up with 4 cards.\r\nThe number of cards with me and Tweeto is tabulated below.\n\r\nRound Me Tweeto\r\nInitially 5 5 \r\nRound 1 4 6\r\nRound 2 5 5\r\nRound 3 4 6\r\nApplying the given statements to the above table, we can observe that statements A and C are true since Tweeto won exactly two rounds and Tweeto won the third round. Statement B is false here because I lost the first round.\n\r\nHence it is clear from both the results that statements A and C must be true for me to end up with 4 cards at the end of three rounds.\n<|im_start|>answer\nStatements A and C must be true. \n\r\nThe rules of the Romankachi card game are given below.\r\n1) One person 'serves' and the other 'receives' cards in each round.\r\n2) The person who serves cards in the round gains 2 cards if he wins the round and loses only 1 card if he loses the round.\r\n3) On the other hand, the person who receives cards in the round, gains only 1 card if he wins the round and loses 2 cards if he loses the round.\r\n4) Finally the person who wins in one round, serves in the next round.\r\n5) The game is stopped when a player loses all his cards.\n\r\nThe given statements are \r\nA) Tweeto must have won exactly two rounds.\r\nB) I must have won the first round.\r\nC) Tweeto must have won the third round.\n\r\nSince we started the card game with 5 cards each and I started of the first round, at the end of three rounds I can have 4 cards due to any one of the following two results.\n\r\nFirst Result :\n\r\nI served in the first round and won. Hence I served in the second round but lost. Tweeto served in the third round and again I lost thus ending up with 4 cards.\r\nThe number of cards with me and Tweeto is tabulated below.\n\r\nRound Me Tweeto\r\nInitially 5 5 \r\nRound 1 7 3\r\nRound 2 6 4\r\nRound 3 4 6\n\r\nApplying the given statements to the above table, we can observe that statements A and C are true since Tweeto won exactly two rounds and Tweeto won the third round. Statement B is true here because I won the first round.\n\r\nSecond Result :\n\r\nI served in the first round and lost. Hence Tweeto served in the second round but he lost. I served in the third round and I lost thus ending up with 4 cards.\r\nThe number of cards with me and Tweeto is tabulated below.\n\r\nRound Me Tweeto\r\nInitially 5 5 \r\nRound 1 4 6\r\nRound 2 5 5\r\nRound 3 4 6\r\nApplying the given statements to the above table, we can observe that statements A and C are true since Tweeto won exactly two rounds and Tweeto won the third round. Statement B is false here because I lost the first round.\n\r\nHence it is clear from both the results that statements A and C must be true for me to end up with 4 cards at the end of three rounds.\n<|im_end|>" }, { "id": "#11685", "title": "Al, Joe, and Beth", "fun": 2.31, "difficulty": 1.54, "author": "Pheonix_down", "desc": "Al says Beth is lying, Beth says Joe is lying, Joe accuses both of them of lying. \n\r\nWho is telling the truth?", "hint": "No hint available.", "answer": "Beth. \n\r\nJoe can't be telling the truth because then \r\nBeth would be lying, and Al's statement (which is also a lie) would mean that Beth is telling the truth. These two facts contradict each other. Therefore Joe is lying, which means that Beth is telling the truth, which in turn means that Al is lying.", "category": "Logic", "date": "04/10/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl says Beth is lying, Beth says Joe is lying, Joe accuses both of them of lying. \n\r\nWho is telling the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeth. \n\r\nJoe can't be telling the truth because then \r\nBeth would be lying, and Al's statement (which is also a lie) would mean that Beth is telling the truth. These two facts contradict each other. Therefore Joe is lying, which means that Beth is telling the truth, which in turn means that Al is lying.\n<|im_start|>answer\nBeth. \n\r\nJoe can't be telling the truth because then \r\nBeth would be lying, and Al's statement (which is also a lie) would mean that Beth is telling the truth. These two facts contradict each other. Therefore Joe is lying, which means that Beth is telling the truth, which in turn means that Al is lying.\n<|im_end|>" }, { "id": "#405", "title": "$1", "fun": 2.31, "difficulty": 1.67, "author": "Mr. G", "desc": "What fifty (American) coins equal exactly one dollar?", "hint": "No hint available.", "answer": "40 Pennies, 2 dimes, and 8 nickels.", "category": "Math", "date": "04/25/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat fifty (American) coins equal exactly one dollar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n40 Pennies, 2 dimes, and 8 nickels.\n<|im_start|>answer\n40 Pennies, 2 dimes, and 8 nickels.\n<|im_end|>" }, { "id": "#5138", "title": "Crossing Paths", "fun": 2.31, "difficulty": 2.3, "author": "cathalmccabe", "desc": "A person starts off walking in a perfectly straight line at uniform speed. After a mile, a second person starts walking at uniform speed from the same starting point and catches up with the first guy after another mile. At this time, the second person turns at an angle of 60 degrees west. They both continue walking in straight lines for a certain period of time. Then, the second person turns 60 degrees east. They both continue in straight lines. Will the second person cross the first's path in front, behind or at the same time?", "hint": "No hint available.", "answer": "They will intercept!\n\r\nPerson 2 catches up with the first guy after another mile\r\nThis tells us that person 2 is walking twice the speed of 1.\r\nHe goes off at an angle of 60 degrees, but his speed in the same direction as the first person is 2cos60\r\ncos60 is 1/2 so the speed in the same direction is the same.\r\nWhen he turns, his speed is 2sin60 = 1!\r\nIt doesn't matter when he turns, the paths will eventually meet up again!", "category": "Math", "date": "07/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA person starts off walking in a perfectly straight line at uniform speed. After a mile, a second person starts walking at uniform speed from the same starting point and catches up with the first guy after another mile. At this time, the second person turns at an angle of 60 degrees west. They both continue walking in straight lines for a certain period of time. Then, the second person turns 60 degrees east. They both continue in straight lines. Will the second person cross the first's path in front, behind or at the same time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey will intercept!\n\r\nPerson 2 catches up with the first guy after another mile\r\nThis tells us that person 2 is walking twice the speed of 1.\r\nHe goes off at an angle of 60 degrees, but his speed in the same direction as the first person is 2cos60\r\ncos60 is 1/2 so the speed in the same direction is the same.\r\nWhen he turns, his speed is 2sin60 = 1!\r\nIt doesn't matter when he turns, the paths will eventually meet up again!\n<|im_start|>answer\nThey will intercept!\n\r\nPerson 2 catches up with the first guy after another mile\r\nThis tells us that person 2 is walking twice the speed of 1.\r\nHe goes off at an angle of 60 degrees, but his speed in the same direction as the first person is 2cos60\r\ncos60 is 1/2 so the speed in the same direction is the same.\r\nWhen he turns, his speed is 2sin60 = 1!\r\nIt doesn't matter when he turns, the paths will eventually meet up again!\n<|im_end|>" }, { "id": "#8314", "title": "Tell The World", "fun": 2.31, "difficulty": 2.08, "author": "mad-ade", "desc": "Mad Ade is so pleased with the \"Sweaty Chef\" kebab shop he decides to tell everyone about it. Mad Ade passes the information on to four people in a matter of 30 minutes.\r\nEach of these four in turn passes the \"Sweaty Chef\" recommendation to four other separate people in the next 30 minutes and so on. \n\r\nHow long it will take for everybody in the world to get to know how Mad Ade feels about the \"Sweaty Chef\" kebab shop? \n\r\nAssume that nobody hears it more than once and the population of the world is approximately 5.6 billion.", "hint": "No hint available.", "answer": "All of 8 hours....you just have to do the math. \n\r\nThis many people know after this many minutes:\n\r\n5 = 30 \r\n21 = 60 \r\n85 = 90 \r\n341 = 20 \r\n1365 = 150 \r\n5461 = 180 \r\n21845 = 210 \r\n87381 = 240 \r\n349525 = 270 \r\n1398101 = 300 \r\n5592405 = 330 \r\n22369621 = 360 \r\n89478485 = 390 \r\n357913941 = 420 \r\n1431655765 = 450 \r\n5,726,623,061 = 480/60 = 8 hrs.", "category": "Math", "date": "11/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is so pleased with the \"Sweaty Chef\" kebab shop he decides to tell everyone about it. Mad Ade passes the information on to four people in a matter of 30 minutes.\r\nEach of these four in turn passes the \"Sweaty Chef\" recommendation to four other separate people in the next 30 minutes and so on. \n\r\nHow long it will take for everybody in the world to get to know how Mad Ade feels about the \"Sweaty Chef\" kebab shop? \n\r\nAssume that nobody hears it more than once and the population of the world is approximately 5.6 billion.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll of 8 hours....you just have to do the math. \n\r\nThis many people know after this many minutes:\n\r\n5 = 30 \r\n21 = 60 \r\n85 = 90 \r\n341 = 20 \r\n1365 = 150 \r\n5461 = 180 \r\n21845 = 210 \r\n87381 = 240 \r\n349525 = 270 \r\n1398101 = 300 \r\n5592405 = 330 \r\n22369621 = 360 \r\n89478485 = 390 \r\n357913941 = 420 \r\n1431655765 = 450 \r\n5,726,623,061 = 480/60 = 8 hrs.\n<|im_start|>answer\nAll of 8 hours....you just have to do the math. \n\r\nThis many people know after this many minutes:\n\r\n5 = 30 \r\n21 = 60 \r\n85 = 90 \r\n341 = 20 \r\n1365 = 150 \r\n5461 = 180 \r\n21845 = 210 \r\n87381 = 240 \r\n349525 = 270 \r\n1398101 = 300 \r\n5592405 = 330 \r\n22369621 = 360 \r\n89478485 = 390 \r\n357913941 = 420 \r\n1431655765 = 450 \r\n5,726,623,061 = 480/60 = 8 hrs.\n<|im_end|>" }, { "id": "#16175", "title": "Halftime Formations", "fun": 2.31, "difficulty": 2.0, "author": "adoontourious", "desc": "The vicinity high school marching band is planning a halftime show for the big football game of the season. As part of the show, they want to march onto the field in the formation of a triangle (forming a solid equilateral triangle) and then rearrange themselves into a square (forming a solid square).\n\r\nWhat is the minimum number of marching band members needed to do this?\n\r\nNote: the marching band has more than 1 person in it", "hint": "No hint available.", "answer": "The marching band needs 36 members in order to perform this maneuver.\n\r\nTriangular numbers are 1, 3, 6, 10, 15, 21, 28, 36 etc... Square numbers are 1, 4, 9, 16, 25, 36 etc... Other than 1 the next possible number to appear in both lists is 36.", "category": "Math", "date": "01/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe vicinity high school marching band is planning a halftime show for the big football game of the season. As part of the show, they want to march onto the field in the formation of a triangle (forming a solid equilateral triangle) and then rearrange themselves into a square (forming a solid square).\n\r\nWhat is the minimum number of marching band members needed to do this?\n\r\nNote: the marching band has more than 1 person in it\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe marching band needs 36 members in order to perform this maneuver.\n\r\nTriangular numbers are 1, 3, 6, 10, 15, 21, 28, 36 etc... Square numbers are 1, 4, 9, 16, 25, 36 etc... Other than 1 the next possible number to appear in both lists is 36.\n<|im_start|>answer\nThe marching band needs 36 members in order to perform this maneuver.\n\r\nTriangular numbers are 1, 3, 6, 10, 15, 21, 28, 36 etc... Square numbers are 1, 4, 9, 16, 25, 36 etc... Other than 1 the next possible number to appear in both lists is 36.\n<|im_end|>" }, { "id": "#47323", "title": "Two Cops, a Thief", "fun": 2.31, "difficulty": 0.64, "author": "Deckstatus", "desc": "Three people met at a corner of a street. They all are dressed like cops, so they don't know who's the thief (bad guy). The cops will tell the truth (because they are good), and the thief will tell the truth too to make himself appear like a good cop. They are A, B and C. And they say this:\n\r\nA:\"C's not the thief.\"\r\nB:\"One of you both is the thief!\"\r\nC:\"I'm not the thief.\"\n\r\nUsing this information, find out who the thief is.", "hint": "All statements are TRUE. So read each other, and figure out who's the thief. Easy.", "answer": "A's the thief. He says C's not the thief, and B says one of the other two is, which means he must not be. So the only one left is A.", "category": "Logic", "date": "06/24/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people met at a corner of a street. They all are dressed like cops, so they don't know who's the thief (bad guy). The cops will tell the truth (because they are good), and the thief will tell the truth too to make himself appear like a good cop. They are A, B and C. And they say this:\n\r\nA:\"C's not the thief.\"\r\nB:\"One of you both is the thief!\"\r\nC:\"I'm not the thief.\"\n\r\nUsing this information, find out who the thief is.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA's the thief. He says C's not the thief, and B says one of the other two is, which means he must not be. So the only one left is A.\n<|im_start|>answer\nA's the thief. He says C's not the thief, and B says one of the other two is, which means he must not be. So the only one left is A.\n<|im_end|>" }, { "id": "#20208", "title": "Rising Train Tracks", "fun": 2.31, "difficulty": 2.7600000000000002, "author": "tsimkin", "desc": "Henry is a new civil engineer, and is charged with planning the laying of a new type of ultra-rigid rails that expand only one inch per mile of length in temperature extremes. Henry's plan calls for the tracks (each of which is one mile in length) to be laid end-to-end with no gap between them, pinned to the ground at every other juncture, as shown below:\n\r\nv_______ _______vv_______ _______v\n\r\nHenry's boss sees the plan and says, \"You fool! What about when the tracks expand?\"\n\r\nHenry replies, \"The expansion will only be an inch over the whole mile length. If the tracks buckle, it will only be by an inch or two at most. The trains will certainly have no trouble bumping over these buckles.\"\n\r\nHenry's boss says, \"You're fired.\" Why was the boss so critical?", "hint": "Would Pythagoras have the same plan?", "answer": "The rise in the middle of the tracks would have been much greater than Henry surmised. Using the Pythagorean Theorem, you will have a triangle with a base of one mile (or 63,360 inches), and a hypotenuse of one mile plus one inch (or 63,361 inches). To find the height, take the square root of (the square of the base minus the square of the hypotenuse). SQRT((63,361)^2 - (63,360)^2) = 355.98 inches, or over 29 feet!", "category": "Math", "date": "01/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHenry is a new civil engineer, and is charged with planning the laying of a new type of ultra-rigid rails that expand only one inch per mile of length in temperature extremes. Henry's plan calls for the tracks (each of which is one mile in length) to be laid end-to-end with no gap between them, pinned to the ground at every other juncture, as shown below:\n\r\nv_______ _______vv_______ _______v\n\r\nHenry's boss sees the plan and says, \"You fool! What about when the tracks expand?\"\n\r\nHenry replies, \"The expansion will only be an inch over the whole mile length. If the tracks buckle, it will only be by an inch or two at most. The trains will certainly have no trouble bumping over these buckles.\"\n\r\nHenry's boss says, \"You're fired.\" Why was the boss so critical?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe rise in the middle of the tracks would have been much greater than Henry surmised. Using the Pythagorean Theorem, you will have a triangle with a base of one mile (or 63,360 inches), and a hypotenuse of one mile plus one inch (or 63,361 inches). To find the height, take the square root of (the square of the base minus the square of the hypotenuse). SQRT((63,361)^2 - (63,360)^2) = 355.98 inches, or over 29 feet!\n<|im_start|>answer\nThe rise in the middle of the tracks would have been much greater than Henry surmised. Using the Pythagorean Theorem, you will have a triangle with a base of one mile (or 63,360 inches), and a hypotenuse of one mile plus one inch (or 63,361 inches). To find the height, take the square root of (the square of the base minus the square of the hypotenuse). SQRT((63,361)^2 - (63,360)^2) = 355.98 inches, or over 29 feet!\n<|im_end|>" }, { "id": "#24713", "title": "Eagle Lunch", "fun": 2.31, "difficulty": 0.65, "author": "WENZY675", "desc": "One day at lunch, there were four eagles, whose names were Curly, Harry, Larry, and Moe. Each of them had a different type of fish, caught from different lakes. \n\r\n-Harry had a walleye, and he caught it from either Erie or Mina. \n\r\n-Moe did not have the mackerel, but he caught his fish from Lake Preston. \n\r\n-Larry had either the mackerel or cod, but he did not catch his fish from Huron. \n\r\n-Curly had bluegill, and he caught his fish from either Huron or Erie. \n\r\n-Larry caught his fish from the lake whose name is closest to the beginning of the alphabet.\n\r\nCan you figure out which eagle had which fish and from which lake it was caught?", "hint": "Curly had bluegill, not caught from Erie.", "answer": "Harry had walleye from Mina. Curly had the bluegill from Huron. Larry had mackerel from Erie. Moe had the cod from Preston.", "category": "Logic-Grid", "date": "07/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day at lunch, there were four eagles, whose names were Curly, Harry, Larry, and Moe. Each of them had a different type of fish, caught from different lakes. \n\r\n-Harry had a walleye, and he caught it from either Erie or Mina. \n\r\n-Moe did not have the mackerel, but he caught his fish from Lake Preston. \n\r\n-Larry had either the mackerel or cod, but he did not catch his fish from Huron. \n\r\n-Curly had bluegill, and he caught his fish from either Huron or Erie. \n\r\n-Larry caught his fish from the lake whose name is closest to the beginning of the alphabet.\n\r\nCan you figure out which eagle had which fish and from which lake it was caught?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry had walleye from Mina. Curly had the bluegill from Huron. Larry had mackerel from Erie. Moe had the cod from Preston.\n<|im_start|>answer\nHarry had walleye from Mina. Curly had the bluegill from Huron. Larry had mackerel from Erie. Moe had the cod from Preston.\n<|im_end|>" }, { "id": "#44295", "title": "Square Peg", "fun": 2.3, "difficulty": 1.44, "author": "mosca", "desc": "They say you can't put a square peg into a round hole, but it really depends on the sizes of the peg and the hole. What is the maximum size of a square peg that can be inserted into a round hole that is two centimeters in diameter?", "hint": "Think Pythagoras!", "answer": "The square root of two, or approximately 1.414 centimeters. \n\r\nIf the round hole is two cm. in diameter, a square peg that fits exactly inside it would have a diagonal equal to its diameter. A diagonal and two adjacent sides of the peg form an isosceles right triangle with the diagonal forming the hypotenuse. The sum of the squares of each of the two sides equals the square of the diagonal. This boils down to the square root of two, or approximately 1.414 centimeters.", "category": "Math", "date": "03/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThey say you can't put a square peg into a round hole, but it really depends on the sizes of the peg and the hole. What is the maximum size of a square peg that can be inserted into a round hole that is two centimeters in diameter?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe square root of two, or approximately 1.414 centimeters. \n\r\nIf the round hole is two cm. in diameter, a square peg that fits exactly inside it would have a diagonal equal to its diameter. A diagonal and two adjacent sides of the peg form an isosceles right triangle with the diagonal forming the hypotenuse. The sum of the squares of each of the two sides equals the square of the diagonal. This boils down to the square root of two, or approximately 1.414 centimeters.\n<|im_start|>answer\nThe square root of two, or approximately 1.414 centimeters. \n\r\nIf the round hole is two cm. in diameter, a square peg that fits exactly inside it would have a diagonal equal to its diameter. A diagonal and two adjacent sides of the peg form an isosceles right triangle with the diagonal forming the hypotenuse. The sum of the squares of each of the two sides equals the square of the diagonal. This boils down to the square root of two, or approximately 1.414 centimeters.\n<|im_end|>" }, { "id": "#8560", "title": "Kebabama Canal", "fun": 2.3, "difficulty": 1.77, "author": "mad-ade", "desc": "Since the turn of the last century one of the quickest ways to traverse from one end of the legendary land of Madadia to the other was via the Kebabama canal. Regular passenger cruises traveled the length of the Kebabama canal every day.\n\r\nOn one particular run there were six passengers who all required certain conditions whilst travelling on the three day journey.\n\r\nEach level of the cruiser contains six cabins numbered 1-6 consecutively, and were arranged in a row and are separated by thin dividers. These cabins must be assigned to the six passengers based on following facts. \n\r\nMiss Fortune's work as a travelling Kebab salesperson requires her to speak on the phone frequently throughout the day. \n\r\nMiss D'work prefers cabin number 5 as 5 is her lucky number. \n\r\nMr. Buss and Mr. Allot often talk to each other during their work as second hand underpants repairers and prefer to have adjacent cabins. \n\r\nMr. Lastrain, Mr. Buss and Mr. Meaner all smoke. Miss D'work is allergic to smoke and must have non-smokers adjacent to her. \n\r\nMr. Meaner needs silence during work.\n\r\nCan you tell the cabin numbers of each of them?", "hint": "No hint available.", "answer": "The cabins from left to right (1-6) are of Mr. Meaner, Mr. Lastrain, Mr. Buss, Mr. Allot, Miss D'work and Miss Fortune\n\r\nFrom (2), cabin number 5 is assigned to Miss D'work. \n\r\nAs Miss D'work is allergic to smoke and Mr. Lastrain, Mr. Buss & Mr. Meaner all smoke, they must be in cabin numbers 1, 2 and 3 not necessarily in the same order. Also, Miss Fortune and Mr. Allot must be in cabin 4 and 6. \n\r\nFrom (3), Mr. Buss must be in cabin 3 and Mr. Allot must be in cabin 4. Thus, Miss Fortune is in cabin 6. \n\r\nAs Mr. Meaner needs silence during work and Mr. Buss is in cabin 3 who often talks to Mr. Allot during work, Mr. Meaner must be in cabin 1. Hence, Mr. Lastrain is in cabin 2. \n\r\nThus, the cabins' numbers are \r\n1# Mr. Meaner, \r\n2# Mr. Lastrain, \r\n3# Mr. Buss, \r\n4# Mr. Allot, \r\n5# Miss D'work, \r\n6# Miss Fortune", "category": "Logic", "date": "11/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSince the turn of the last century one of the quickest ways to traverse from one end of the legendary land of Madadia to the other was via the Kebabama canal. Regular passenger cruises traveled the length of the Kebabama canal every day.\n\r\nOn one particular run there were six passengers who all required certain conditions whilst travelling on the three day journey.\n\r\nEach level of the cruiser contains six cabins numbered 1-6 consecutively, and were arranged in a row and are separated by thin dividers. These cabins must be assigned to the six passengers based on following facts. \n\r\nMiss Fortune's work as a travelling Kebab salesperson requires her to speak on the phone frequently throughout the day. \n\r\nMiss D'work prefers cabin number 5 as 5 is her lucky number. \n\r\nMr. Buss and Mr. Allot often talk to each other during their work as second hand underpants repairers and prefer to have adjacent cabins. \n\r\nMr. Lastrain, Mr. Buss and Mr. Meaner all smoke. Miss D'work is allergic to smoke and must have non-smokers adjacent to her. \n\r\nMr. Meaner needs silence during work.\n\r\nCan you tell the cabin numbers of each of them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cabins from left to right (1-6) are of Mr. Meaner, Mr. Lastrain, Mr. Buss, Mr. Allot, Miss D'work and Miss Fortune\n\r\nFrom (2), cabin number 5 is assigned to Miss D'work. \n\r\nAs Miss D'work is allergic to smoke and Mr. Lastrain, Mr. Buss & Mr. Meaner all smoke, they must be in cabin numbers 1, 2 and 3 not necessarily in the same order. Also, Miss Fortune and Mr. Allot must be in cabin 4 and 6. \n\r\nFrom (3), Mr. Buss must be in cabin 3 and Mr. Allot must be in cabin 4. Thus, Miss Fortune is in cabin 6. \n\r\nAs Mr. Meaner needs silence during work and Mr. Buss is in cabin 3 who often talks to Mr. Allot during work, Mr. Meaner must be in cabin 1. Hence, Mr. Lastrain is in cabin 2. \n\r\nThus, the cabins' numbers are \r\n1# Mr. Meaner, \r\n2# Mr. Lastrain, \r\n3# Mr. Buss, \r\n4# Mr. Allot, \r\n5# Miss D'work, \r\n6# Miss Fortune\n<|im_start|>answer\nThe cabins from left to right (1-6) are of Mr. Meaner, Mr. Lastrain, Mr. Buss, Mr. Allot, Miss D'work and Miss Fortune\n\r\nFrom (2), cabin number 5 is assigned to Miss D'work. \n\r\nAs Miss D'work is allergic to smoke and Mr. Lastrain, Mr. Buss & Mr. Meaner all smoke, they must be in cabin numbers 1, 2 and 3 not necessarily in the same order. Also, Miss Fortune and Mr. Allot must be in cabin 4 and 6. \n\r\nFrom (3), Mr. Buss must be in cabin 3 and Mr. Allot must be in cabin 4. Thus, Miss Fortune is in cabin 6. \n\r\nAs Mr. Meaner needs silence during work and Mr. Buss is in cabin 3 who often talks to Mr. Allot during work, Mr. Meaner must be in cabin 1. Hence, Mr. Lastrain is in cabin 2. \n\r\nThus, the cabins' numbers are \r\n1# Mr. Meaner, \r\n2# Mr. Lastrain, \r\n3# Mr. Buss, \r\n4# Mr. Allot, \r\n5# Miss D'work, \r\n6# Miss Fortune\n<|im_end|>" }, { "id": "#17410", "title": "Building a Boat", "fun": 2.3, "difficulty": 0.97, "author": "bomber2", "desc": "4 men can build 4 boats in 4 days. How long does it take 1 man to build 1 boat?", "hint": "No hint available.", "answer": "4 days. It takes 4 men to build 1 boat in 1 day and 4 boats in 4 days, therefore it takes 1 man to build 1 boat in 4 days.", "category": "Logic", "date": "04/18/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 men can build 4 boats in 4 days. How long does it take 1 man to build 1 boat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 days. It takes 4 men to build 1 boat in 1 day and 4 boats in 4 days, therefore it takes 1 man to build 1 boat in 4 days.\n<|im_start|>answer\n4 days. It takes 4 men to build 1 boat in 1 day and 4 boats in 4 days, therefore it takes 1 man to build 1 boat in 4 days.\n<|im_end|>" }, { "id": "#22669", "title": "Combinations of Combinations", "fun": 2.3, "difficulty": 1.54, "author": "dntdodrugsulosr", "desc": "A party is planned for Susie who is having her birthday in 2 weeks. At the party there is a choice of different party themes: castle theme, fiesta theme, animal theme, water theme and circus theme. You can pick 2 of these to use for her party (eg. a fiesta animal party). \n\r\nHow many combinations of parties are there?", "hint": "Combinations, not permutations.", "answer": "It's 5!/(5-2)!2! which is the equation for a combination. This all comes out as 5*4*3*2*1/3*2*1*2*1. After it gets cleaned up, you are left with 5*4/2 which is 10, so little Susie can have 10 different possible parties.", "category": "Math", "date": "05/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA party is planned for Susie who is having her birthday in 2 weeks. At the party there is a choice of different party themes: castle theme, fiesta theme, animal theme, water theme and circus theme. You can pick 2 of these to use for her party (eg. a fiesta animal party). \n\r\nHow many combinations of parties are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's 5!/(5-2)!2! which is the equation for a combination. This all comes out as 5*4*3*2*1/3*2*1*2*1. After it gets cleaned up, you are left with 5*4/2 which is 10, so little Susie can have 10 different possible parties.\n<|im_start|>answer\nIt's 5!/(5-2)!2! which is the equation for a combination. This all comes out as 5*4*3*2*1/3*2*1*2*1. After it gets cleaned up, you are left with 5*4/2 which is 10, so little Susie can have 10 different possible parties.\n<|im_end|>" }, { "id": "#20180", "title": "Every Year", "fun": 2.3, "difficulty": 1.11, "author": "jboo4u", "desc": "You use this all year, and just around Christmas, it seems to wear out! What is this?", "hint": "No hint available.", "answer": "A calendar", "category": "Logic", "date": "01/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou use this all year, and just around Christmas, it seems to wear out! What is this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA calendar\n<|im_start|>answer\nA calendar\n<|im_end|>" }, { "id": "#28021", "title": "Mr. Knowitall (knowitall)", "fun": 2.3, "difficulty": 0.7000000000000001, "author": "Shawnheyhey123", "desc": "One day, Mary Lynn went to a club with $100,000,000 in her purse. She got the money from the 'Give Money to Others Foundation' to give to the person who knew everything; his name was Mr. Knowitall. When she came up to a certain man she asked him, \"I'm supposed to give $100,000,000 to Mr. Knowitall; are you him?\" He replies, \"Uh... Yeah, I'm him, and who are you?\" She then leaves him taking the money with her. \r\nHow did she know he was not Mr. Knowitall?", "hint": "No hint available.", "answer": "If he was Mr. Knowitall, he would know who she was without asking her.", "category": "Logic", "date": "01/10/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, Mary Lynn went to a club with $100,000,000 in her purse. She got the money from the 'Give Money to Others Foundation' to give to the person who knew everything; his name was Mr. Knowitall. When she came up to a certain man she asked him, \"I'm supposed to give $100,000,000 to Mr. Knowitall; are you him?\" He replies, \"Uh... Yeah, I'm him, and who are you?\" She then leaves him taking the money with her. \r\nHow did she know he was not Mr. Knowitall?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf he was Mr. Knowitall, he would know who she was without asking her.\n<|im_start|>answer\nIf he was Mr. Knowitall, he would know who she was without asking her.\n<|im_end|>" }, { "id": "#48710", "title": "The Airport", "fun": 2.3, "difficulty": 1.16, "author": "Mathgeek007", "desc": "Jake was planning to go to another country to visit relatives. The trip to the airport was long and boring, and since he didn't have a license, his mother had to drive him.\n\r\nJake was driven to the airport once from his house when he realized that he forgot his passport at home. His mother went back, got it, then brought it back. He then said he left his wallet at home. She went to get it, came back, and he had some more bad news. He left his cell phone at home. She went to go get it, but exactly halfway back, she found it in the glove compartment. She brought it back to him immediately, and he went off with his flight.\n\r\nAssuming that the average car speed was 75 kph, the distance between the house and airport was exactly 50 km, and ignoring facts such as U-Turn time, time talking to son at the airport, time getting items, etc, how long did it take for Jake to leave, with the time starting when he left his house?", "hint": "How many times did the car drive exactly 50 kilometers?", "answer": "Reading the whole story, the car drove the distance 6 times. 3 times to the airport, two back, and two half-times. 6*50 is 300.\n\r\n300/75 is 4, so it took 4 hours ignoring other little details.", "category": "Math", "date": "05/09/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJake was planning to go to another country to visit relatives. The trip to the airport was long and boring, and since he didn't have a license, his mother had to drive him.\n\r\nJake was driven to the airport once from his house when he realized that he forgot his passport at home. His mother went back, got it, then brought it back. He then said he left his wallet at home. She went to get it, came back, and he had some more bad news. He left his cell phone at home. She went to go get it, but exactly halfway back, she found it in the glove compartment. She brought it back to him immediately, and he went off with his flight.\n\r\nAssuming that the average car speed was 75 kph, the distance between the house and airport was exactly 50 km, and ignoring facts such as U-Turn time, time talking to son at the airport, time getting items, etc, how long did it take for Jake to leave, with the time starting when he left his house?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nReading the whole story, the car drove the distance 6 times. 3 times to the airport, two back, and two half-times. 6*50 is 300.\n\r\n300/75 is 4, so it took 4 hours ignoring other little details.\n<|im_start|>answer\nReading the whole story, the car drove the distance 6 times. 3 times to the airport, two back, and two half-times. 6*50 is 300.\n\r\n300/75 is 4, so it took 4 hours ignoring other little details.\n<|im_end|>" }, { "id": "#41099", "title": "Mr. Fitzgerald's Windows", "fun": 2.3, "difficulty": 2.17, "author": "jsteppergurl", "desc": "There are two floors plus the attic in Mr. Fitzgerald's house. Mr. Fitzgerald is repairing all of the windows. He found out that the windows don't all have the same number of glass window panes.\n\r\nEach window on the second floor has 9 panes on top and 6 on the bottom. \r\nThere are two more windows on the first floor than on the second. \r\nEach window downstairs has eight panes of glass on top and eight on the bottom. \r\nThe attic has one window with four panes of glass. \r\nEach of the ten rooms of the house has at least one window. \r\nMr. Fitzgerald has counted 315 panes of glass in all.\n\r\nEach window needs one new lock. How many locks will Mr. Fitzgerald need for each window to have a new lock?", "hint": "Try making a table and finding a pattern. Maybe an equation will be necessary.", "answer": "There are 21 windows in all, so 21 locks will be needed.", "category": "Math", "date": "03/18/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two floors plus the attic in Mr. Fitzgerald's house. Mr. Fitzgerald is repairing all of the windows. He found out that the windows don't all have the same number of glass window panes.\n\r\nEach window on the second floor has 9 panes on top and 6 on the bottom. \r\nThere are two more windows on the first floor than on the second. \r\nEach window downstairs has eight panes of glass on top and eight on the bottom. \r\nThe attic has one window with four panes of glass. \r\nEach of the ten rooms of the house has at least one window. \r\nMr. Fitzgerald has counted 315 panes of glass in all.\n\r\nEach window needs one new lock. How many locks will Mr. Fitzgerald need for each window to have a new lock?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 21 windows in all, so 21 locks will be needed.\n<|im_start|>answer\nThere are 21 windows in all, so 21 locks will be needed.\n<|im_end|>" }, { "id": "#3146", "title": "14 1/2 degrees", "fun": 2.3, "difficulty": 1.19, "author": "204_blaze_41", "desc": "Shadow was examining an angle measuring 14 ½ degrees, using his magnifying glass that magnifies everything two times. Under the glass, how large would the angle measure?", "hint": "No hint available.", "answer": "14 ½ degrees.", "category": "Math", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nShadow was examining an angle measuring 14 ½ degrees, using his magnifying glass that magnifies everything two times. Under the glass, how large would the angle measure?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n14 ½ degrees.\n<|im_start|>answer\n14 ½ degrees.\n<|im_end|>" }, { "id": "#4129", "title": "Milk", "fun": 2.3, "difficulty": 1.06, "author": "cowcowloverjr", "desc": "A man wants to start a milk company. He wants to send milk by train but doesn't have anything to put it in. How does he ship it?", "hint": "No hint available.", "answer": "He just ships the cows.", "category": "Logic", "date": "05/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man wants to start a milk company. He wants to send milk by train but doesn't have anything to put it in. How does he ship it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe just ships the cows.\n<|im_start|>answer\nHe just ships the cows.\n<|im_end|>" }, { "id": "#18969", "title": "Chess League !!!", "fun": 2.3, "difficulty": 2.15, "author": "lesternoronha1", "desc": "Four players - Anand, Karpov, Ivanchuk, and Polgar - participated in a chess competition in which each player played exactly one game with each of the other three players. At the end of the competition the results were as follows :-\n\r\n1) Karpov won against Ivanchuk, who did not win against Anand.\r\n2) The number of games won by Anand is equal to the number of games won by Ivanchuk.\r\n3) No game ended in a draw.\n\r\nThen which of the following definitely is true :-\n\r\na) Ivanchuk lost to Polgar.\r\nb) Anand lost to Karpov.\r\nc) Polgar lost to Anand.\r\nd) Karpov lost to Polgar.", "hint": "No hint available.", "answer": "The given observations about the individual Round Robin games are as follows:\r\n1) Karpov won against Ivanchuk, who did not win against Anand.\r\n2) The number of games won by Anand is equal to the number of games won by Ivanchuk.\r\n3) No game ended in a draw.\n\r\nLet us represent Anand, Polgar, Karpov and Ivanchuk by A, P, K and I respectively.\n\r\nThe from the given data we have\n\r\nGame Winner\r\nA-K\r\nA-P\r\nA-I A\r\nK-P\r\nK-I I\r\nI-P\r\nsince Ivanchuk lost both the games against Karpov and Anand from observation 1.\n\r\nNow from observation 1, Anand has definitely won one game since he beat Ivanchuk. From observation 2, the number of games won by Anand is equal to the number of games won by Ivanchuk. Since Ivanchuk has lost both games, he should at least win the last game so that the number of games won by him is equal to those won by Anand. Also since Anand has won one game, he cannot win games against Karpov and Polgar since Ivanchuk cannot equal him then, after having lost two out of three games. Hence Anand must lose to Karpov and Polgar and Ivanchuk must win against Polgar.\n\r\nHence among the given statement b which suggests that Anand lost to Karpov must definitely be true.", "category": "Logic", "date": "09/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour players - Anand, Karpov, Ivanchuk, and Polgar - participated in a chess competition in which each player played exactly one game with each of the other three players. At the end of the competition the results were as follows :-\n\r\n1) Karpov won against Ivanchuk, who did not win against Anand.\r\n2) The number of games won by Anand is equal to the number of games won by Ivanchuk.\r\n3) No game ended in a draw.\n\r\nThen which of the following definitely is true :-\n\r\na) Ivanchuk lost to Polgar.\r\nb) Anand lost to Karpov.\r\nc) Polgar lost to Anand.\r\nd) Karpov lost to Polgar.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe given observations about the individual Round Robin games are as follows:\r\n1) Karpov won against Ivanchuk, who did not win against Anand.\r\n2) The number of games won by Anand is equal to the number of games won by Ivanchuk.\r\n3) No game ended in a draw.\n\r\nLet us represent Anand, Polgar, Karpov and Ivanchuk by A, P, K and I respectively.\n\r\nThe from the given data we have\n\r\nGame Winner\r\nA-K\r\nA-P\r\nA-I A\r\nK-P\r\nK-I I\r\nI-P\r\nsince Ivanchuk lost both the games against Karpov and Anand from observation 1.\n\r\nNow from observation 1, Anand has definitely won one game since he beat Ivanchuk. From observation 2, the number of games won by Anand is equal to the number of games won by Ivanchuk. Since Ivanchuk has lost both games, he should at least win the last game so that the number of games won by him is equal to those won by Anand. Also since Anand has won one game, he cannot win games against Karpov and Polgar since Ivanchuk cannot equal him then, after having lost two out of three games. Hence Anand must lose to Karpov and Polgar and Ivanchuk must win against Polgar.\n\r\nHence among the given statement b which suggests that Anand lost to Karpov must definitely be true.\n<|im_start|>answer\nThe given observations about the individual Round Robin games are as follows:\r\n1) Karpov won against Ivanchuk, who did not win against Anand.\r\n2) The number of games won by Anand is equal to the number of games won by Ivanchuk.\r\n3) No game ended in a draw.\n\r\nLet us represent Anand, Polgar, Karpov and Ivanchuk by A, P, K and I respectively.\n\r\nThe from the given data we have\n\r\nGame Winner\r\nA-K\r\nA-P\r\nA-I A\r\nK-P\r\nK-I I\r\nI-P\r\nsince Ivanchuk lost both the games against Karpov and Anand from observation 1.\n\r\nNow from observation 1, Anand has definitely won one game since he beat Ivanchuk. From observation 2, the number of games won by Anand is equal to the number of games won by Ivanchuk. Since Ivanchuk has lost both games, he should at least win the last game so that the number of games won by him is equal to those won by Anand. Also since Anand has won one game, he cannot win games against Karpov and Polgar since Ivanchuk cannot equal him then, after having lost two out of three games. Hence Anand must lose to Karpov and Polgar and Ivanchuk must win against Polgar.\n\r\nHence among the given statement b which suggests that Anand lost to Karpov must definitely be true.\n<|im_end|>" }, { "id": "#5213", "title": "Banana Questions", "fun": 2.3, "difficulty": 1.33, "author": "michelle", "desc": "Suppose 7 monkeys take 7 minutes to eat 7 bananas (eating at the same rate). \n\r\n(a) How many minutes would it take 4 monkeys to eat 4 bananas? \n\r\n(b) How many monkeys would it take to eat 63 bananas in 63 minutes?", "hint": "No hint available.", "answer": "They're all the same question:\r\n(a) It would take 7 minutes for 4 monkeys to eat 4 bananas; and \r\n(b) it would take 7 monkeys 63 minutes to eat 63 bananas.", "category": "Math", "date": "07/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose 7 monkeys take 7 minutes to eat 7 bananas (eating at the same rate). \n\r\n(a) How many minutes would it take 4 monkeys to eat 4 bananas? \n\r\n(b) How many monkeys would it take to eat 63 bananas in 63 minutes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey're all the same question:\r\n(a) It would take 7 minutes for 4 monkeys to eat 4 bananas; and \r\n(b) it would take 7 monkeys 63 minutes to eat 63 bananas.\n<|im_start|>answer\nThey're all the same question:\r\n(a) It would take 7 minutes for 4 monkeys to eat 4 bananas; and \r\n(b) it would take 7 monkeys 63 minutes to eat 63 bananas.\n<|im_end|>" }, { "id": "#4807", "title": "Pennies", "fun": 2.3, "difficulty": 1.69, "author": "mad-ade", "desc": "Someone offered Mad Ade a choice between a ton of pennies and five miles of pennies lined up with touching edges. Which should Mad Ade take if he wanted the most money? Here are some facts to help you decide: A penny weighs .09 ounces. A penny's diameter is .75 inches.", "hint": "No hint available.", "answer": "Five miles of pennies are worth more than the ton of pennies. \r\nUse a calculator to find the inches in a mile, then 5 miles. 316,800 inches divided by .75 inches = 422,400 pennies, or £4,224.\r\n 1 ton = 32,000 ounces divided by .09 ounces = 355,555.55 pennies, or £3,555.56.", "category": "Math", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSomeone offered Mad Ade a choice between a ton of pennies and five miles of pennies lined up with touching edges. Which should Mad Ade take if he wanted the most money? Here are some facts to help you decide: A penny weighs .09 ounces. A penny's diameter is .75 inches.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFive miles of pennies are worth more than the ton of pennies. \r\nUse a calculator to find the inches in a mile, then 5 miles. 316,800 inches divided by .75 inches = 422,400 pennies, or £4,224.\r\n 1 ton = 32,000 ounces divided by .09 ounces = 355,555.55 pennies, or £3,555.56.\n<|im_start|>answer\nFive miles of pennies are worth more than the ton of pennies. \r\nUse a calculator to find the inches in a mile, then 5 miles. 316,800 inches divided by .75 inches = 422,400 pennies, or £4,224.\r\n 1 ton = 32,000 ounces divided by .09 ounces = 355,555.55 pennies, or £3,555.56.\n<|im_end|>" }, { "id": "#8587", "title": "Number Trouble", "fun": 2.3, "difficulty": 2.0, "author": "lesternoronha1", "desc": "Find the lowest positive number divisible by all the single digit numbers 1 to 9.", "hint": "No hint available.", "answer": "The number is 2520.\n\r\n2*3*2*5*7*2*3=2520", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the lowest positive number divisible by all the single digit numbers 1 to 9.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 2520.\n\r\n2*3*2*5*7*2*3=2520\n<|im_start|>answer\nThe number is 2520.\n\r\n2*3*2*5*7*2*3=2520\n<|im_end|>" }, { "id": "#13826", "title": "Create an Equation", "fun": 2.3, "difficulty": 2.0, "author": "GeoGeo", "desc": "Create an equation by inserting the fewest possible arithmetic operators (plus and minus only) into:\n\r\n987654321 = 100\n\r\nFor example: 98+7-6+5-4+3-2-1=100 \n\r\nNote: the numbers must stay in reverse order from 9 down to 1.", "hint": "No hint available.", "answer": "98-76+54+3+21=100", "category": "Math", "date": "07/15/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCreate an equation by inserting the fewest possible arithmetic operators (plus and minus only) into:\n\r\n987654321 = 100\n\r\nFor example: 98+7-6+5-4+3-2-1=100 \n\r\nNote: the numbers must stay in reverse order from 9 down to 1.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n98-76+54+3+21=100\n<|im_start|>answer\n98-76+54+3+21=100\n<|im_end|>" }, { "id": "#10803", "title": "Clock Watcher", "fun": 2.3, "difficulty": 2.58, "author": "jimbo", "desc": "Some time after 2 O' Clock, the angle made between the minute hand and the vertical (12) on a clock is double the angle made between the hour hand and the vertical (12). What time is it?", "hint": "What is the rate of travel of each hand on a clock?", "answer": "2:24 The hour hand makes an angle of 72 degrees while the minute hand makes an angle of 144 degrees.\n\r\nAt exactly 2:00, the angle made by the hour hand is 60 degrees from vertical. If you let x = the number of minutes past 2:00 that we are looking for, then the hour hand will be at:\n\r\n60 degrees + x / 60 min* 30 degrees \n\r\nwhere x/60 min is the fraction of a full hour that has past, and is therefore the fractional distance that the hour hand has moved closer to the 3. The 30 degrees is the total angle between the 2 and the 3.\n\r\nThe final position of the minute hand will be:\n\r\nx/30 min * 180 degrees\n\r\nfor the same reasoning as with the hour hand.\n\r\nSince the minute hand will make twice the angle with vertical, you can set up the equation:\n\r\n2*(60 + x / 60 * 30) = x / 30 * 180\n\r\nSolving for x will give you 24 minutes. The time will be 2:24.", "category": "Math", "date": "02/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome time after 2 O' Clock, the angle made between the minute hand and the vertical (12) on a clock is double the angle made between the hour hand and the vertical (12). What time is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2:24 The hour hand makes an angle of 72 degrees while the minute hand makes an angle of 144 degrees.\n\r\nAt exactly 2:00, the angle made by the hour hand is 60 degrees from vertical. If you let x = the number of minutes past 2:00 that we are looking for, then the hour hand will be at:\n\r\n60 degrees + x / 60 min* 30 degrees \n\r\nwhere x/60 min is the fraction of a full hour that has past, and is therefore the fractional distance that the hour hand has moved closer to the 3. The 30 degrees is the total angle between the 2 and the 3.\n\r\nThe final position of the minute hand will be:\n\r\nx/30 min * 180 degrees\n\r\nfor the same reasoning as with the hour hand.\n\r\nSince the minute hand will make twice the angle with vertical, you can set up the equation:\n\r\n2*(60 + x / 60 * 30) = x / 30 * 180\n\r\nSolving for x will give you 24 minutes. The time will be 2:24.\n<|im_start|>answer\n2:24 The hour hand makes an angle of 72 degrees while the minute hand makes an angle of 144 degrees.\n\r\nAt exactly 2:00, the angle made by the hour hand is 60 degrees from vertical. If you let x = the number of minutes past 2:00 that we are looking for, then the hour hand will be at:\n\r\n60 degrees + x / 60 min* 30 degrees \n\r\nwhere x/60 min is the fraction of a full hour that has past, and is therefore the fractional distance that the hour hand has moved closer to the 3. The 30 degrees is the total angle between the 2 and the 3.\n\r\nThe final position of the minute hand will be:\n\r\nx/30 min * 180 degrees\n\r\nfor the same reasoning as with the hour hand.\n\r\nSince the minute hand will make twice the angle with vertical, you can set up the equation:\n\r\n2*(60 + x / 60 * 30) = x / 30 * 180\n\r\nSolving for x will give you 24 minutes. The time will be 2:24.\n<|im_end|>" }, { "id": "#24744", "title": "Three Squares a Day", "fun": 2.3, "difficulty": 2.73, "author": "phrebh", "desc": "Find three numbers, all under 500, where the sum of all three is a perfect square and the sums of any two of them are also perfect squares.", "hint": "No hint available.", "answer": "41, 80, 320", "category": "Math", "date": "07/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind three numbers, all under 500, where the sum of all three is a perfect square and the sums of any two of them are also perfect squares.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n41, 80, 320\n<|im_start|>answer\n41, 80, 320\n<|im_end|>" }, { "id": "#40215", "title": "Fly Away", "fun": 2.3, "difficulty": 2.62, "author": "shenqiang", "desc": "In the addition sum FLY+FLY+FLY=AWAY, each letter represents a different non-zero digit. What is the value of A+W+A+Y?", "hint": "They are NON-ZERO digits.", "answer": "From the ones digits, Y+Y+Y yield Y, and Y must equal 5 (it has been stated as non-zero). \r\nSince A is the highest digit, A is at most 2. However, because 1 is carried from the ones digits to the tens digits, A must equal 2, otherwise L will be 0. A=2 and L=7. The tens digits carry 2 to the hundreds digits, and the hundreds digits must carry 2 to the thousands digits. To avoid zero or duplicate numbers, F can only be 8 and W be 6. A+W+A+Y=2+6+2+5=15.", "category": "Math", "date": "01/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the addition sum FLY+FLY+FLY=AWAY, each letter represents a different non-zero digit. What is the value of A+W+A+Y?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom the ones digits, Y+Y+Y yield Y, and Y must equal 5 (it has been stated as non-zero). \r\nSince A is the highest digit, A is at most 2. However, because 1 is carried from the ones digits to the tens digits, A must equal 2, otherwise L will be 0. A=2 and L=7. The tens digits carry 2 to the hundreds digits, and the hundreds digits must carry 2 to the thousands digits. To avoid zero or duplicate numbers, F can only be 8 and W be 6. A+W+A+Y=2+6+2+5=15.\n<|im_start|>answer\nFrom the ones digits, Y+Y+Y yield Y, and Y must equal 5 (it has been stated as non-zero). \r\nSince A is the highest digit, A is at most 2. However, because 1 is carried from the ones digits to the tens digits, A must equal 2, otherwise L will be 0. A=2 and L=7. The tens digits carry 2 to the hundreds digits, and the hundreds digits must carry 2 to the thousands digits. To avoid zero or duplicate numbers, F can only be 8 and W be 6. A+W+A+Y=2+6+2+5=15.\n<|im_end|>" }, { "id": "#40613", "title": "How Many Legs?", "fun": 2.3, "difficulty": 1.55, "author": "Zacharko", "desc": "There are 7 girls on a bus. Each girl has 7 backpacks. Each backpack has 7 big cats. Each big cat has 7 little cats. If there is no one else on the bus, how many legs are on the bus?", "hint": "No hint available.", "answer": "10,990 legs\r\n7*2= the number of legs of the girls\r\n7*7*7*4= the number of legs of the big cats\r\n7*7*7*7*4= the number of legs of the little cats", "category": "Math", "date": "02/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 7 girls on a bus. Each girl has 7 backpacks. Each backpack has 7 big cats. Each big cat has 7 little cats. If there is no one else on the bus, how many legs are on the bus?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10,990 legs\r\n7*2= the number of legs of the girls\r\n7*7*7*4= the number of legs of the big cats\r\n7*7*7*7*4= the number of legs of the little cats\n<|im_start|>answer\n10,990 legs\r\n7*2= the number of legs of the girls\r\n7*7*7*4= the number of legs of the big cats\r\n7*7*7*7*4= the number of legs of the little cats\n<|im_end|>" }, { "id": "#5006", "title": "The Elevator 2", "fun": 2.3, "difficulty": 1.11, "author": "eahtriscuit", "desc": "Mr. Smith weighs 250 pounds. Ms. Katie weighs 100 pounds. Mr. Ron weighs 150 pounds. The elevator they need to ride only holds 300 pounds. They must all get to the top floor of the building. There must be an operator in the elevator at all times. How do they do it?", "hint": "Up small, down bigger, up smaller", "answer": "Mr. Ron and Ms. Katie go up to the top floor first. Mr. Ron gets off. Ms. Katie goes back down and gets off. Mr. Smith gets on and goes up. Mr. Ron get on the elevator and goes back down, picks up Ms. Katie and goes back up.", "category": "Math", "date": "06/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Smith weighs 250 pounds. Ms. Katie weighs 100 pounds. Mr. Ron weighs 150 pounds. The elevator they need to ride only holds 300 pounds. They must all get to the top floor of the building. There must be an operator in the elevator at all times. How do they do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Ron and Ms. Katie go up to the top floor first. Mr. Ron gets off. Ms. Katie goes back down and gets off. Mr. Smith gets on and goes up. Mr. Ron get on the elevator and goes back down, picks up Ms. Katie and goes back up.\n<|im_start|>answer\nMr. Ron and Ms. Katie go up to the top floor first. Mr. Ron gets off. Ms. Katie goes back down and gets off. Mr. Smith gets on and goes up. Mr. Ron get on the elevator and goes back down, picks up Ms. Katie and goes back up.\n<|im_end|>" }, { "id": "#3990", "title": "Unreal Estate", "fun": 2.3, "difficulty": 1.34, "author": "VCLMRS", "desc": "FOR SALE - Beautiful triangular block of land available for immediate purchase. Located in well-established upmarket neighbourhood, with tree-lined streets. Near large shopping centre and school - THIS BLOCK MEASURES 50M X 32M X 18M - and would be ideal for the buyer who is looking for an unusual site to build a house. Would you buy this block of land?", "hint": "Think geometry!", "answer": "You could not buy this block of land even if you wanted to! It doesn't exist. In a triangle, any two sides must always add up to MORE THAN the third side. But in this block, the sum of two sides (32M + 18M) EQUALS the third side (50M). So the \"land\" doesn't exist - it is a straight line!", "category": "Math", "date": "05/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFOR SALE - Beautiful triangular block of land available for immediate purchase. Located in well-established upmarket neighbourhood, with tree-lined streets. Near large shopping centre and school - THIS BLOCK MEASURES 50M X 32M X 18M - and would be ideal for the buyer who is looking for an unusual site to build a house. Would you buy this block of land?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou could not buy this block of land even if you wanted to! It doesn't exist. In a triangle, any two sides must always add up to MORE THAN the third side. But in this block, the sum of two sides (32M + 18M) EQUALS the third side (50M). So the \"land\" doesn't exist - it is a straight line!\n<|im_start|>answer\nYou could not buy this block of land even if you wanted to! It doesn't exist. In a triangle, any two sides must always add up to MORE THAN the third side. But in this block, the sum of two sides (32M + 18M) EQUALS the third side (50M). So the \"land\" doesn't exist - it is a straight line!\n<|im_end|>" }, { "id": "#33560", "title": "Lolly Store", "fun": 2.3, "difficulty": 1.7, "author": "grungy49", "desc": "You are a small child who likes to visit the lolly store.\n\r\nWhen you visit the lolly store to buy some lollies, on the way back you always run into three bullies, each at different locations. They all demand a quarter of the lollies you have on you. If the number of lollies you have isn't divisible by four they will not hesitate to break the lolly into halves or thirds.\n\r\nIf each lolly costs 20 cents, and you need to have 27 lollies by the time you reach your house (9 for your father, 9 for your mother and 9 for you), how much money will you need to bring to the store?\n\r\nAnd how much will each bully get? (1st bully, 2nd bully, 3rd bully)", "hint": "No hint available.", "answer": "1st question\n\r\nYou will need to bring $12.80 originally so you can buy 64 lollies.\n\r\nHere is a simple formula, working backwards from 27.\n\r\n27 / 0.75 = 36 (1 bully)\r\n36 / 0.75 = 48 (2 bullies)\r\n48 / 0.75 = 64 (3 bullies)\n\r\nSo, you will need to have 64 lollies before you reach any of the bullies.\n\r\n2nd question\n\r\nThis is easy once you have solved the first part. \r\n64 / 4 = 16\r\n48 / 4 = 12\r\n36 / 4 = 9\n\r\nSo the first bully will get 16 lollies, the second bully will get 12 lollies, and the third bully will get 9 lollies.", "category": "Math", "date": "10/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are a small child who likes to visit the lolly store.\n\r\nWhen you visit the lolly store to buy some lollies, on the way back you always run into three bullies, each at different locations. They all demand a quarter of the lollies you have on you. If the number of lollies you have isn't divisible by four they will not hesitate to break the lolly into halves or thirds.\n\r\nIf each lolly costs 20 cents, and you need to have 27 lollies by the time you reach your house (9 for your father, 9 for your mother and 9 for you), how much money will you need to bring to the store?\n\r\nAnd how much will each bully get? (1st bully, 2nd bully, 3rd bully)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st question\n\r\nYou will need to bring $12.80 originally so you can buy 64 lollies.\n\r\nHere is a simple formula, working backwards from 27.\n\r\n27 / 0.75 = 36 (1 bully)\r\n36 / 0.75 = 48 (2 bullies)\r\n48 / 0.75 = 64 (3 bullies)\n\r\nSo, you will need to have 64 lollies before you reach any of the bullies.\n\r\n2nd question\n\r\nThis is easy once you have solved the first part. \r\n64 / 4 = 16\r\n48 / 4 = 12\r\n36 / 4 = 9\n\r\nSo the first bully will get 16 lollies, the second bully will get 12 lollies, and the third bully will get 9 lollies.\n<|im_start|>answer\n1st question\n\r\nYou will need to bring $12.80 originally so you can buy 64 lollies.\n\r\nHere is a simple formula, working backwards from 27.\n\r\n27 / 0.75 = 36 (1 bully)\r\n36 / 0.75 = 48 (2 bullies)\r\n48 / 0.75 = 64 (3 bullies)\n\r\nSo, you will need to have 64 lollies before you reach any of the bullies.\n\r\n2nd question\n\r\nThis is easy once you have solved the first part. \r\n64 / 4 = 16\r\n48 / 4 = 12\r\n36 / 4 = 9\n\r\nSo the first bully will get 16 lollies, the second bully will get 12 lollies, and the third bully will get 9 lollies.\n<|im_end|>" }, { "id": "#24972", "title": "Nursery Playground", "fun": 2.3, "difficulty": 0.91, "author": "katey", "desc": "At the local nursery school, I was chatting to my daughter's friends and noticed a number of things.\n\r\nJessica has mousey coloured hair and the girl with black hair was wearing a green dress. \n\r\nLucy is not blonde, Lauren does not have brown hair, and Chloe was wearing a blue dress. \n\r\nThe blonde girl was not wearing red and Lauren was not wearing green. \n\r\nI can't remember which girl was wearing a yellow dress. \n\r\nCan you determine the colours of the girl's dresses and their hair?", "hint": "No hint available.", "answer": "Name Dress Colour Hair Colour\r\nJessica red mousey\r\nLauren yellow blonde\r\nLucy green black\r\nChloe blue brown", "category": "Logic-Grid", "date": "07/30/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the local nursery school, I was chatting to my daughter's friends and noticed a number of things.\n\r\nJessica has mousey coloured hair and the girl with black hair was wearing a green dress. \n\r\nLucy is not blonde, Lauren does not have brown hair, and Chloe was wearing a blue dress. \n\r\nThe blonde girl was not wearing red and Lauren was not wearing green. \n\r\nI can't remember which girl was wearing a yellow dress. \n\r\nCan you determine the colours of the girl's dresses and their hair?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName Dress Colour Hair Colour\r\nJessica red mousey\r\nLauren yellow blonde\r\nLucy green black\r\nChloe blue brown\n<|im_start|>answer\nName Dress Colour Hair Colour\r\nJessica red mousey\r\nLauren yellow blonde\r\nLucy green black\r\nChloe blue brown\n<|im_end|>" }, { "id": "#31227", "title": "Camping Trip", "fun": 2.3, "difficulty": 2.21, "author": "tsimkin", "desc": "Gretchen and Henry decide to go camping on a river. From where they put their canoes in the water, they paddle upstream for 3 hours, only to realize that their campground is located downstream from their starting point. They immediately turn around, and paddle downstream for the next 5 hours.\n\r\nThat night, they get some rest, make some s'mores, and tell ghost stories. They wake up the next morning to get back on the river, and paddle back to their starting point, 26 miles upriver.\n\r\nHenry, knowing that this river flows at a constant rate of 2 miles per hour, says, \"There's no way we're getting back by nightfall.\"\n\r\nGretchen does some quick math with a stick in the dirt, and says, \"If we paddle at the same constant rate we did yesterday, we'll be back in time for a 6:00 dinner.\"\n\r\nWhat time are they leaving?", "hint": "If they finished 26 miles downstream from their starting point, how fast would they paddle in standing water?", "answer": "They are leaving at 9:20 in the morning.\n\r\nIf you denote their speed in standing water as x (miles per hour), then their speed upstream is x-2 and their speed downstream is x+2. On day 1, they traveled a distance downstream of 5(x+2) - 3(x-2), which equalled 26 miles. Solving for x, we get x = 5 miles per hour.\n\r\nKnowing that they then need to travel upstream for those 26 miles to get home, their speed will be 3 miles per hour (= 5 - 2). It will therefore take them 8 2/3 hours, or 8 hours and 40 minutes.\n\r\nIn order to be back to their starting point by 6:00 pm, they therefore have to leave at 9:20 am.", "category": "Math", "date": "06/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGretchen and Henry decide to go camping on a river. From where they put their canoes in the water, they paddle upstream for 3 hours, only to realize that their campground is located downstream from their starting point. They immediately turn around, and paddle downstream for the next 5 hours.\n\r\nThat night, they get some rest, make some s'mores, and tell ghost stories. They wake up the next morning to get back on the river, and paddle back to their starting point, 26 miles upriver.\n\r\nHenry, knowing that this river flows at a constant rate of 2 miles per hour, says, \"There's no way we're getting back by nightfall.\"\n\r\nGretchen does some quick math with a stick in the dirt, and says, \"If we paddle at the same constant rate we did yesterday, we'll be back in time for a 6:00 dinner.\"\n\r\nWhat time are they leaving?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are leaving at 9:20 in the morning.\n\r\nIf you denote their speed in standing water as x (miles per hour), then their speed upstream is x-2 and their speed downstream is x+2. On day 1, they traveled a distance downstream of 5(x+2) - 3(x-2), which equalled 26 miles. Solving for x, we get x = 5 miles per hour.\n\r\nKnowing that they then need to travel upstream for those 26 miles to get home, their speed will be 3 miles per hour (= 5 - 2). It will therefore take them 8 2/3 hours, or 8 hours and 40 minutes.\n\r\nIn order to be back to their starting point by 6:00 pm, they therefore have to leave at 9:20 am.\n<|im_start|>answer\nThey are leaving at 9:20 in the morning.\n\r\nIf you denote their speed in standing water as x (miles per hour), then their speed upstream is x-2 and their speed downstream is x+2. On day 1, they traveled a distance downstream of 5(x+2) - 3(x-2), which equalled 26 miles. Solving for x, we get x = 5 miles per hour.\n\r\nKnowing that they then need to travel upstream for those 26 miles to get home, their speed will be 3 miles per hour (= 5 - 2). It will therefore take them 8 2/3 hours, or 8 hours and 40 minutes.\n\r\nIn order to be back to their starting point by 6:00 pm, they therefore have to leave at 9:20 am.\n<|im_end|>" }, { "id": "#1398", "title": "How Many Daughters", "fun": 2.3, "difficulty": 0.89, "author": "stormcloud99", "desc": "A man is asked what his daughters look like. He answers,\"They are all blondes but two, all brunettes but two and all redheads but two.\" How many daughters does he have?", "hint": "No hint available.", "answer": "He has 3 daughters. One blonde, one brunette, and one redhead.", "category": "Logic", "date": "11/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is asked what his daughters look like. He answers,\"They are all blondes but two, all brunettes but two and all redheads but two.\" How many daughters does he have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe has 3 daughters. One blonde, one brunette, and one redhead.\n<|im_start|>answer\nHe has 3 daughters. One blonde, one brunette, and one redhead.\n<|im_end|>" }, { "id": "#12167", "title": "Randy's Cucumbers", "fun": 2.3, "difficulty": 1.79, "author": "gabe1991", "desc": "Randy picked 102 cucumbers in one month, 96 cucumbers in the next month, 46 cucumbers the following month, and 4 cucumbers in the 4th month. He sold a total of 15.5 cucumbers in one day. Randy sold 19.5 cucumbers the next day. 23.5 cucumbers were sold the next day, and 27.5 cucumbers the following day. If the same pattern of cucumbers are being sold, how many cucumbers will Randy sell on the 62nd day?", "hint": "No hint available.", "answer": "None. Randy would've run out of cucumbers if the same pattern of cucumbers were being sold. Remember, he only had 248 cucumbers. The 62nd day would've been 259.5 cucumbers.", "category": "Math", "date": "05/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRandy picked 102 cucumbers in one month, 96 cucumbers in the next month, 46 cucumbers the following month, and 4 cucumbers in the 4th month. He sold a total of 15.5 cucumbers in one day. Randy sold 19.5 cucumbers the next day. 23.5 cucumbers were sold the next day, and 27.5 cucumbers the following day. If the same pattern of cucumbers are being sold, how many cucumbers will Randy sell on the 62nd day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNone. Randy would've run out of cucumbers if the same pattern of cucumbers were being sold. Remember, he only had 248 cucumbers. The 62nd day would've been 259.5 cucumbers.\n<|im_start|>answer\nNone. Randy would've run out of cucumbers if the same pattern of cucumbers were being sold. Remember, he only had 248 cucumbers. The 62nd day would've been 259.5 cucumbers.\n<|im_end|>" }, { "id": "#8316", "title": "Which House?", "fun": 2.3, "difficulty": 2.57, "author": "mad-ade", "desc": "Mad Ade is telling his friend, Shamus O'Stoatclencher, at which number house he lives at on \"Madadia Avenue\":\n\r\n(1) If my house number is a multiple of 3, then it is a number from 50 through 59. \n\r\n(2) If my house number is not a multiple of 4, then it is a number from 60 through 69. \n\r\n(3) If my house number is not a multiple of 6, then it is a number from 70 through 79.\"\n\r\nWhat is Mad Ade's house number?", "hint": "No hint available.", "answer": "Mad Ade's house number is 76. \n\r\nFrom (1) and (3), the house number must be from 50 to 59 or 70 to 79. Take any number. It will be either a multiple of 3 or not. Also, a number multiple of 6 is always a multiple of 3. Hence, the house number can be 51, 54, 57, 70, 71, 73, 74, 76, 77 or 79. \n\r\nFrom (2), if the house number is not a multiple of 4, then it is a number from 60 through 69. There is not a single number between 60 and 69 in short-listed numbers above. Hence, the house number must be a multiple of 4 i.e. 76.\n\r\nHence, Mad Ade's house number is 76.", "category": "Logic", "date": "11/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is telling his friend, Shamus O'Stoatclencher, at which number house he lives at on \"Madadia Avenue\":\n\r\n(1) If my house number is a multiple of 3, then it is a number from 50 through 59. \n\r\n(2) If my house number is not a multiple of 4, then it is a number from 60 through 69. \n\r\n(3) If my house number is not a multiple of 6, then it is a number from 70 through 79.\"\n\r\nWhat is Mad Ade's house number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade's house number is 76. \n\r\nFrom (1) and (3), the house number must be from 50 to 59 or 70 to 79. Take any number. It will be either a multiple of 3 or not. Also, a number multiple of 6 is always a multiple of 3. Hence, the house number can be 51, 54, 57, 70, 71, 73, 74, 76, 77 or 79. \n\r\nFrom (2), if the house number is not a multiple of 4, then it is a number from 60 through 69. There is not a single number between 60 and 69 in short-listed numbers above. Hence, the house number must be a multiple of 4 i.e. 76.\n\r\nHence, Mad Ade's house number is 76.\n<|im_start|>answer\nMad Ade's house number is 76. \n\r\nFrom (1) and (3), the house number must be from 50 to 59 or 70 to 79. Take any number. It will be either a multiple of 3 or not. Also, a number multiple of 6 is always a multiple of 3. Hence, the house number can be 51, 54, 57, 70, 71, 73, 74, 76, 77 or 79. \n\r\nFrom (2), if the house number is not a multiple of 4, then it is a number from 60 through 69. There is not a single number between 60 and 69 in short-listed numbers above. Hence, the house number must be a multiple of 4 i.e. 76.\n\r\nHence, Mad Ade's house number is 76.\n<|im_end|>" }, { "id": "#16147", "title": "Old MadDonalds Farm", "fun": 2.3, "difficulty": 2.35, "author": "mad-ade", "desc": "Out in the backwoods of southern Madadia lives Old MadDonald, he has a farm. And on that farm he has several types of livestock. \r\nHe had a the Famous Madadian Southern fried Chicken, (the one with six legs and no breast)\r\nThe equally well known Madadian self basting Turkey and also the amazing Duck La Orange.\r\nOld MadDonald lived alone and as a result became extremely bored at times and thus always tried different ways to amuse himself, some of them legal. One such way was to race the poultry livestock against each other.\r\nThe Southern Fried Chicken could fly at 5 mph but, as chickens are poor flyers and it had little in the line of muscle across its breast, it gets tired very soon. After only 2 minutes of flying, it has to walk at 1 mph for next three minutes before it could attempt to fly again.\r\nThe Self Basting Turkey could fly continuously at 4 mph, but he had a habit of swerving back and forth. So for every 3 feet he flies, he actually only travels 2 feet.\r\nThe Duck La Orange could fly straight and continuous at 2mph.\n\r\nWhich of the three of Old MadDonalds Birds would win a race over a distance of one mile ?", "hint": "No hint available.", "answer": "Surprisingly the Southern Fried Chicken would win the one-mile race. \n\r\nIf you were to calculate the average speed, you'll see that the chicken's average speed, after 5 minutes, is 2.6 mph. \r\nThe Self Basting Turkey's average speed is 2.67 mph. \r\nThe Duck La Orange, as stated above, has an average speed of 2 mph. \r\nBased on this information alone it appears that the Self Basting Turkey should win.\n\r\nThe catch is the fact that the one-mile race does not take an even multiple of five minutes to complete. The Southern Fried Chicken's average speed is only accurate after the full five minutes of flying/walking is completed. At any time before that, the chicken's mean speed will be higher. \n\r\nAfter 20 minutes have passed, the Southern Fried Chicken will have traveled a total of 0.87 miles, and the Self Basting Turkey will have traveled a distance of 0.89 miles. However, the S.F Chicken will then begin flying at 5 mph, and will overtake the S.B.Turkey. \n\r\nThe final results will be: \r\n1. Southern Fried Chicken - 21.6 minutes (21 minutes 36 seconds) \r\n2. Self Basting Turkey - 22.5 minutes (22 minutes 30 seconds) \r\n3. Duck La Orange - 30 minutes", "category": "Math", "date": "01/12/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOut in the backwoods of southern Madadia lives Old MadDonald, he has a farm. And on that farm he has several types of livestock. \r\nHe had a the Famous Madadian Southern fried Chicken, (the one with six legs and no breast)\r\nThe equally well known Madadian self basting Turkey and also the amazing Duck La Orange.\r\nOld MadDonald lived alone and as a result became extremely bored at times and thus always tried different ways to amuse himself, some of them legal. One such way was to race the poultry livestock against each other.\r\nThe Southern Fried Chicken could fly at 5 mph but, as chickens are poor flyers and it had little in the line of muscle across its breast, it gets tired very soon. After only 2 minutes of flying, it has to walk at 1 mph for next three minutes before it could attempt to fly again.\r\nThe Self Basting Turkey could fly continuously at 4 mph, but he had a habit of swerving back and forth. So for every 3 feet he flies, he actually only travels 2 feet.\r\nThe Duck La Orange could fly straight and continuous at 2mph.\n\r\nWhich of the three of Old MadDonalds Birds would win a race over a distance of one mile ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSurprisingly the Southern Fried Chicken would win the one-mile race. \n\r\nIf you were to calculate the average speed, you'll see that the chicken's average speed, after 5 minutes, is 2.6 mph. \r\nThe Self Basting Turkey's average speed is 2.67 mph. \r\nThe Duck La Orange, as stated above, has an average speed of 2 mph. \r\nBased on this information alone it appears that the Self Basting Turkey should win.\n\r\nThe catch is the fact that the one-mile race does not take an even multiple of five minutes to complete. The Southern Fried Chicken's average speed is only accurate after the full five minutes of flying/walking is completed. At any time before that, the chicken's mean speed will be higher. \n\r\nAfter 20 minutes have passed, the Southern Fried Chicken will have traveled a total of 0.87 miles, and the Self Basting Turkey will have traveled a distance of 0.89 miles. However, the S.F Chicken will then begin flying at 5 mph, and will overtake the S.B.Turkey. \n\r\nThe final results will be: \r\n1. Southern Fried Chicken - 21.6 minutes (21 minutes 36 seconds) \r\n2. Self Basting Turkey - 22.5 minutes (22 minutes 30 seconds) \r\n3. Duck La Orange - 30 minutes\n<|im_start|>answer\nSurprisingly the Southern Fried Chicken would win the one-mile race. \n\r\nIf you were to calculate the average speed, you'll see that the chicken's average speed, after 5 minutes, is 2.6 mph. \r\nThe Self Basting Turkey's average speed is 2.67 mph. \r\nThe Duck La Orange, as stated above, has an average speed of 2 mph. \r\nBased on this information alone it appears that the Self Basting Turkey should win.\n\r\nThe catch is the fact that the one-mile race does not take an even multiple of five minutes to complete. The Southern Fried Chicken's average speed is only accurate after the full five minutes of flying/walking is completed. At any time before that, the chicken's mean speed will be higher. \n\r\nAfter 20 minutes have passed, the Southern Fried Chicken will have traveled a total of 0.87 miles, and the Self Basting Turkey will have traveled a distance of 0.89 miles. However, the S.F Chicken will then begin flying at 5 mph, and will overtake the S.B.Turkey. \n\r\nThe final results will be: \r\n1. Southern Fried Chicken - 21.6 minutes (21 minutes 36 seconds) \r\n2. Self Basting Turkey - 22.5 minutes (22 minutes 30 seconds) \r\n3. Duck La Orange - 30 minutes\n<|im_end|>" }, { "id": "#9337", "title": "Sum of Squares", "fun": 2.3, "difficulty": 2.49, "author": "ccccc", "desc": "If the difference between two numbers is 9 and their product is 14, what is the sum of their squares?", "hint": "No hint available.", "answer": "109\n\r\nYou could solve this by setting up two equations:\n\r\nX - Y = 9\r\nX * Y = 14\n\r\nand solving for X and Y (which equal approximately 10.35 and 1.35 or -1.35 and -10.35, respectively). Then take X^2 + Y^2 to get 109.\n\r\nOr you could recognize that:\n\n\r\n(X-Y)^2 = X^2 - 2*X*Y + Y^2\n\r\nrearranging, \n\r\nX^2 + Y^2 = (X-Y)^2 + 2*X*Y\n\r\nThe left side of this equation is what we're looking for. From the original two equations, we know that:\n\r\nX-Y = 9 and therefore (X-Y)^2 = 81.\r\nX*Y = 14 and therefore 2*X*Y = 28.\n\r\n81 + 28 = 109, which is the answer.", "category": "Math", "date": "12/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the difference between two numbers is 9 and their product is 14, what is the sum of their squares?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n109\n\r\nYou could solve this by setting up two equations:\n\r\nX - Y = 9\r\nX * Y = 14\n\r\nand solving for X and Y (which equal approximately 10.35 and 1.35 or -1.35 and -10.35, respectively). Then take X^2 + Y^2 to get 109.\n\r\nOr you could recognize that:\n\n\r\n(X-Y)^2 = X^2 - 2*X*Y + Y^2\n\r\nrearranging, \n\r\nX^2 + Y^2 = (X-Y)^2 + 2*X*Y\n\r\nThe left side of this equation is what we're looking for. From the original two equations, we know that:\n\r\nX-Y = 9 and therefore (X-Y)^2 = 81.\r\nX*Y = 14 and therefore 2*X*Y = 28.\n\r\n81 + 28 = 109, which is the answer.\n<|im_start|>answer\n109\n\r\nYou could solve this by setting up two equations:\n\r\nX - Y = 9\r\nX * Y = 14\n\r\nand solving for X and Y (which equal approximately 10.35 and 1.35 or -1.35 and -10.35, respectively). Then take X^2 + Y^2 to get 109.\n\r\nOr you could recognize that:\n\n\r\n(X-Y)^2 = X^2 - 2*X*Y + Y^2\n\r\nrearranging, \n\r\nX^2 + Y^2 = (X-Y)^2 + 2*X*Y\n\r\nThe left side of this equation is what we're looking for. From the original two equations, we know that:\n\r\nX-Y = 9 and therefore (X-Y)^2 = 81.\r\nX*Y = 14 and therefore 2*X*Y = 28.\n\r\n81 + 28 = 109, which is the answer.\n<|im_end|>" }, { "id": "#42422", "title": "Buses", "fun": 2.3, "difficulty": 2.57, "author": "shenqiang", "desc": "Every day, Tom walks from home to school, and buses that travel in opposite directions commute on the way at constant intervals. Tom sets off from his home while one bus is just going past him and another bus is coming toward him. Tom arrives at school in 48 minutes while one bus is just going past him and another bus is coming toward him. It's known that buses are 6 times as fast as Tom, and Tom has seen a total of 26 buses on his way.\n\r\nHow long is the time interval between successive buses? Put another way, if you just miss your bus when you arrive at the bus stop, how long would you have to wait until your next bus comes along?", "hint": "No hint available.", "answer": "Let the buses' time interval be t and Tom's walking speed be v.\n\r\nA bus goes past him every 6vt/(6v-v)=6t/5, and a bus comes toward him every 6vt/(6v+v)=6t/7.\n\r\nTherefore, there are a total of 48/(6t/5)+1=40/t+1 buses that went past him, and 48/(6t/7)+1=56/t+1 buses that came toward him.\n\r\n40/t+1+56/t+1 implies t=4.\n\r\nOn each bus route, there is a 4 minute interval between buses.", "category": "Math", "date": "07/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery day, Tom walks from home to school, and buses that travel in opposite directions commute on the way at constant intervals. Tom sets off from his home while one bus is just going past him and another bus is coming toward him. Tom arrives at school in 48 minutes while one bus is just going past him and another bus is coming toward him. It's known that buses are 6 times as fast as Tom, and Tom has seen a total of 26 buses on his way.\n\r\nHow long is the time interval between successive buses? Put another way, if you just miss your bus when you arrive at the bus stop, how long would you have to wait until your next bus comes along?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet the buses' time interval be t and Tom's walking speed be v.\n\r\nA bus goes past him every 6vt/(6v-v)=6t/5, and a bus comes toward him every 6vt/(6v+v)=6t/7.\n\r\nTherefore, there are a total of 48/(6t/5)+1=40/t+1 buses that went past him, and 48/(6t/7)+1=56/t+1 buses that came toward him.\n\r\n40/t+1+56/t+1 implies t=4.\n\r\nOn each bus route, there is a 4 minute interval between buses.\n<|im_start|>answer\nLet the buses' time interval be t and Tom's walking speed be v.\n\r\nA bus goes past him every 6vt/(6v-v)=6t/5, and a bus comes toward him every 6vt/(6v+v)=6t/7.\n\r\nTherefore, there are a total of 48/(6t/5)+1=40/t+1 buses that went past him, and 48/(6t/7)+1=56/t+1 buses that came toward him.\n\r\n40/t+1+56/t+1 implies t=4.\n\r\nOn each bus route, there is a 4 minute interval between buses.\n<|im_end|>" }, { "id": "#31533", "title": "Lunch Bunch", "fun": 2.3, "difficulty": 1.8800000000000001, "author": "maxvu", "desc": "TODAY'S MENU\n\r\nHot Dog $ 0.95 \r\nJuice $ 0.50 \r\nBeef Taco $ 0.85 \r\nMilk $ 0.60 \r\nChips $ 0.55 \r\nIce Cream Bar $ 0.75 \n\r\nThe bills below show the lunch orders that Chantelle, Erick, Gregory, Kate, Rachel, and Sakina made for lunch, but the waitperson can't remember which person ordered each combination of food. Use the clues below to help.\n\r\nBills:\n\r\n1. Hot Dog, Milk, Ice Cream Bar\r\n2. Ice Cream Bar, Beef Taco, Chips\r\n3. Beef Taco, Juice, Chips\r\n4. Hot Dog, Milk, Chips\r\n5. Hot Dog, Juice, Chips\r\n6. Beef Taco, Milk, Chips\n\r\nClues:\n\r\n1. Erick got 3 quarters, a dime, and a nickel change from $3.00. \r\n2. Rachel doesn't like hot dogs. \r\n3. Chantelle spent the least, and Gregory spent the most. \r\n4. Rachel and Sakina paid the exact amount without using any coins. \n\r\nWhich order belongs to each person?", "hint": "Figure out the amount of each order. Then make a chart to eliminate the impossibilities.", "answer": "Gregory: Hot dog, milk, ice cream bar\r\nKate: Ice cream bar, beef taco, chips\r\nChantelle: Beef taco, juice, chips\r\nErick: Hot dog, milk, chips\r\nSakina: Hot dog, juice, chips\r\nRachel: Beef taco, milk, chips", "category": "Math", "date": "07/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTODAY'S MENU\n\r\nHot Dog $ 0.95 \r\nJuice $ 0.50 \r\nBeef Taco $ 0.85 \r\nMilk $ 0.60 \r\nChips $ 0.55 \r\nIce Cream Bar $ 0.75 \n\r\nThe bills below show the lunch orders that Chantelle, Erick, Gregory, Kate, Rachel, and Sakina made for lunch, but the waitperson can't remember which person ordered each combination of food. Use the clues below to help.\n\r\nBills:\n\r\n1. Hot Dog, Milk, Ice Cream Bar\r\n2. Ice Cream Bar, Beef Taco, Chips\r\n3. Beef Taco, Juice, Chips\r\n4. Hot Dog, Milk, Chips\r\n5. Hot Dog, Juice, Chips\r\n6. Beef Taco, Milk, Chips\n\r\nClues:\n\r\n1. Erick got 3 quarters, a dime, and a nickel change from $3.00. \r\n2. Rachel doesn't like hot dogs. \r\n3. Chantelle spent the least, and Gregory spent the most. \r\n4. Rachel and Sakina paid the exact amount without using any coins. \n\r\nWhich order belongs to each person?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGregory: Hot dog, milk, ice cream bar\r\nKate: Ice cream bar, beef taco, chips\r\nChantelle: Beef taco, juice, chips\r\nErick: Hot dog, milk, chips\r\nSakina: Hot dog, juice, chips\r\nRachel: Beef taco, milk, chips\n<|im_start|>answer\nGregory: Hot dog, milk, ice cream bar\r\nKate: Ice cream bar, beef taco, chips\r\nChantelle: Beef taco, juice, chips\r\nErick: Hot dog, milk, chips\r\nSakina: Hot dog, juice, chips\r\nRachel: Beef taco, milk, chips\n<|im_end|>" }, { "id": "#13389", "title": "Half Twin, Double Twin.", "fun": 2.3, "difficulty": 2.48, "author": "willymapo", "desc": "I met Ronny and Johnny at the zoo. They are identical twins that like math very much, so they were constantly adding, subtracting, multiplying and dividing any amounts. And they were very good at this, because usually they could make the operation fast and accurate. However, they have a flaw: when the boys were merely counting, they always got the wrong number. Ronny always gets twice the number of items he is counting and Johnny always gets half the number of items counted. \r\nWhen we were leaving at the afternoon, they were discussing the zoo experience: \r\nA: Did you see all those elephants? \r\nB: Yes, I counted them. They were three times the number of crocodiles I counted in the pool. \r\nA: Oh, I also counted the crocodiles; they were two-thirds the number of butterflies I counted in the garden. \r\nB: Really, I counted the butterflies and they were three quarters the number the long tailed monkeys I counted in the monkey pit. \r\nA: Sure, the long tailed monkeys I counted were just 8 more than the white headed monkeys in the trees. \r\nB: Hum, but the white headed monkeys I counted were one more that the number of giraffes I counted. \r\nA: Oh, well, I counted only 4 Giraffes. \n\r\nAll the above is correct (except for the counting). So, can you tell which brother is which, and how many animals were of each kind?", "hint": "No hint available.", "answer": "A is Ronny and B is Johnny. \n\r\nThere were: \r\n12 Elephants\r\n4 Crocodiles\r\n6 Butterflies\r\n8 Long tailed monkeys\r\n4 White headed monkeys\r\n2 Giraffes", "category": "Math", "date": "06/24/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI met Ronny and Johnny at the zoo. They are identical twins that like math very much, so they were constantly adding, subtracting, multiplying and dividing any amounts. And they were very good at this, because usually they could make the operation fast and accurate. However, they have a flaw: when the boys were merely counting, they always got the wrong number. Ronny always gets twice the number of items he is counting and Johnny always gets half the number of items counted. \r\nWhen we were leaving at the afternoon, they were discussing the zoo experience: \r\nA: Did you see all those elephants? \r\nB: Yes, I counted them. They were three times the number of crocodiles I counted in the pool. \r\nA: Oh, I also counted the crocodiles; they were two-thirds the number of butterflies I counted in the garden. \r\nB: Really, I counted the butterflies and they were three quarters the number the long tailed monkeys I counted in the monkey pit. \r\nA: Sure, the long tailed monkeys I counted were just 8 more than the white headed monkeys in the trees. \r\nB: Hum, but the white headed monkeys I counted were one more that the number of giraffes I counted. \r\nA: Oh, well, I counted only 4 Giraffes. \n\r\nAll the above is correct (except for the counting). So, can you tell which brother is which, and how many animals were of each kind?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA is Ronny and B is Johnny. \n\r\nThere were: \r\n12 Elephants\r\n4 Crocodiles\r\n6 Butterflies\r\n8 Long tailed monkeys\r\n4 White headed monkeys\r\n2 Giraffes\n<|im_start|>answer\nA is Ronny and B is Johnny. \n\r\nThere were: \r\n12 Elephants\r\n4 Crocodiles\r\n6 Butterflies\r\n8 Long tailed monkeys\r\n4 White headed monkeys\r\n2 Giraffes\n<|im_end|>" }, { "id": "#8669", "title": "Guttering", "fun": 2.3, "difficulty": 1.44, "author": "glennyboy02", "desc": "Glenn needs to repair the guttering on his house. His house is 7.2 metres high, and he places the ladder 1.8 metres from the base of the wall of the house. The ladder stretches 1 metre over the roof. What is the length of the ladder, rounded off to two decimal places?", "hint": "Try drawing a diagram.", "answer": "Use the Pythagorean Theorem. \n\r\nwhere L = ladder length\n\r\nL = (square root (7.2m squared + 1.8 m squared)) + 1m\r\nL = (square root (55.08m)) + 1m\r\nL = 7.42m + 1m\n\r\nTherefore, the length of the ladder is approximately 8.42 metres.", "category": "Math", "date": "11/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGlenn needs to repair the guttering on his house. His house is 7.2 metres high, and he places the ladder 1.8 metres from the base of the wall of the house. The ladder stretches 1 metre over the roof. What is the length of the ladder, rounded off to two decimal places?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUse the Pythagorean Theorem. \n\r\nwhere L = ladder length\n\r\nL = (square root (7.2m squared + 1.8 m squared)) + 1m\r\nL = (square root (55.08m)) + 1m\r\nL = 7.42m + 1m\n\r\nTherefore, the length of the ladder is approximately 8.42 metres.\n<|im_start|>answer\nUse the Pythagorean Theorem. \n\r\nwhere L = ladder length\n\r\nL = (square root (7.2m squared + 1.8 m squared)) + 1m\r\nL = (square root (55.08m)) + 1m\r\nL = 7.42m + 1m\n\r\nTherefore, the length of the ladder is approximately 8.42 metres.\n<|im_end|>" }, { "id": "#2800", "title": "Funky Relations", "fun": 2.3, "difficulty": 1.11, "author": "lil_thugsta", "desc": "Someone at a party introduces you to your mother's only sister's husband's sister in law. He has no brothers. What do you call this lady?", "hint": "No hint available.", "answer": "Mother, or Mom, or whatever you call your maternal relative.", "category": "Logic", "date": "03/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSomeone at a party introduces you to your mother's only sister's husband's sister in law. He has no brothers. What do you call this lady?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMother, or Mom, or whatever you call your maternal relative.\n<|im_start|>answer\nMother, or Mom, or whatever you call your maternal relative.\n<|im_end|>" }, { "id": "#1354", "title": "Aardvark to Beeville", "fun": 2.29, "difficulty": 1.61, "author": "psychodude57", "desc": "A man drove from Aardvark to Beeville. On the first day he travelled 1/3 of the distance. On day two he travelled 1/2 of the remaining distance. On day three he travelled 2/3 of the remaining distance. On day four, after covering 3/4 of the remaining distance, he was still 5 miles away from Beeville. How many miles had he covered so far?", "hint": "No hint available.", "answer": "175 miles.", "category": "Math", "date": "11/10/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man drove from Aardvark to Beeville. On the first day he travelled 1/3 of the distance. On day two he travelled 1/2 of the remaining distance. On day three he travelled 2/3 of the remaining distance. On day four, after covering 3/4 of the remaining distance, he was still 5 miles away from Beeville. How many miles had he covered so far?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n175 miles.\n<|im_start|>answer\n175 miles.\n<|im_end|>" }, { "id": "#7654", "title": "U.N.K.A.L", "fun": 2.29, "difficulty": 2.87, "author": "mad-ade", "desc": "MADADIA has been chosen to host the latest United Nations Kebab Annual Liaisons (U.N.K.A.L). \r\nMadadia's mayoress, Madka Owdiseez, has invited several wives of delegates of UNKAL for an informal luncheon. \r\nShe plans to seat her 9 guests in a row such that each lady will be able to converse with the person directly to her left and right. She has prepared the following list. \n\r\nMrs. F speaks English only. \r\nMrs. G speaks English and French. \r\nMrs. H speaks English and Russian. \r\nMrs. J speaks Russian only. \r\nMrs. K speaks English only. \r\nMrs. L speaks French only. \r\nMrs. M speaks French and German. \r\nMrs. N speaks English and German. \r\nMrs. O speaks English only. \n\r\nHow many distinct seating arrangements are possible? Give all possible seating arrangements. Bear in mind that Madka Owdiseez is not one of the 9 to be seated in a row.\n\r\nNote that ABCD and DCBA are the same", "hint": "No hint available.", "answer": "With each arrangement considered identical to its reverse, there are 126 possible arrangements. \n\r\n FKO are interchangeable, and can be arranged 6 ways. FKO stays together unless N is next to M outside GLM (more on that below). \n\r\nJH must be together, and J must be at the end, because H is the only other Russian speaker. JH has 2 slots in the above configuration (H next to FKO, with J on the outside). \n\r\nGLM has 1 slot in the above configuration (G next to FKO, opposite JH). \n\r\n2[JH]*6[FKO]*1[MLG]=12 arrangements, or 2 mirror groups of 6 arrangements each. Thus, 6 distinct arrangements - 1 for each FKO order. \n\r\nKeeping the above groups self-contained, N has 5 slots (2 within FKO, 1 between FKO and H, 1 between FKO and G, 1 beside M). That makes 30 arrangements - 5 for each FKO order. \n\r\nWhen N is in certain positions, however, the groups can break up. Unless N is next to M outside GLM, GLM can be GML. If N is between FKO and GLM, GLM can scramble, and G can be anywhere touching FKO, except N cannot touch L. When G-[L/M]-N are consecutive in either direction, FKO can straddle that subgroup. That makes 126 arrangements - 21 for each FKO order. \n\r\nHere are the 21 arrangements, using xxx for the interchangeable FKO. \n\r\nJHNxxxGLM, JHNxxxGML, JHxNxxGLM, JHxNxxGML \r\nJHxxNxGLM, JHxxNxGML, JHxxxNGLM, JHxxxNGML \r\nJHxxxNMGL, JHxxxNMLG, JHxxNMLGx, JHxNMLGxx \r\nJHNMLGxxx, JHxxxGLMN, JHxxGLMNx, JHxGLMNxx \r\nJHGLMNxxx, JHGxxxNML, JHxGxxNML, JHxxGxNML \r\nJHxxxGNML \n\r\nApply each FKO order - F-K-O, F-O-K, K-F-O, K-O-F, O-F-K, O-K-F - to each xxx above. That makes 21*6=126 arrangements.", "category": "Logic", "date": "09/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMADADIA has been chosen to host the latest United Nations Kebab Annual Liaisons (U.N.K.A.L). \r\nMadadia's mayoress, Madka Owdiseez, has invited several wives of delegates of UNKAL for an informal luncheon. \r\nShe plans to seat her 9 guests in a row such that each lady will be able to converse with the person directly to her left and right. She has prepared the following list. \n\r\nMrs. F speaks English only. \r\nMrs. G speaks English and French. \r\nMrs. H speaks English and Russian. \r\nMrs. J speaks Russian only. \r\nMrs. K speaks English only. \r\nMrs. L speaks French only. \r\nMrs. M speaks French and German. \r\nMrs. N speaks English and German. \r\nMrs. O speaks English only. \n\r\nHow many distinct seating arrangements are possible? Give all possible seating arrangements. Bear in mind that Madka Owdiseez is not one of the 9 to be seated in a row.\n\r\nNote that ABCD and DCBA are the same\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWith each arrangement considered identical to its reverse, there are 126 possible arrangements. \n\r\n FKO are interchangeable, and can be arranged 6 ways. FKO stays together unless N is next to M outside GLM (more on that below). \n\r\nJH must be together, and J must be at the end, because H is the only other Russian speaker. JH has 2 slots in the above configuration (H next to FKO, with J on the outside). \n\r\nGLM has 1 slot in the above configuration (G next to FKO, opposite JH). \n\r\n2[JH]*6[FKO]*1[MLG]=12 arrangements, or 2 mirror groups of 6 arrangements each. Thus, 6 distinct arrangements - 1 for each FKO order. \n\r\nKeeping the above groups self-contained, N has 5 slots (2 within FKO, 1 between FKO and H, 1 between FKO and G, 1 beside M). That makes 30 arrangements - 5 for each FKO order. \n\r\nWhen N is in certain positions, however, the groups can break up. Unless N is next to M outside GLM, GLM can be GML. If N is between FKO and GLM, GLM can scramble, and G can be anywhere touching FKO, except N cannot touch L. When G-[L/M]-N are consecutive in either direction, FKO can straddle that subgroup. That makes 126 arrangements - 21 for each FKO order. \n\r\nHere are the 21 arrangements, using xxx for the interchangeable FKO. \n\r\nJHNxxxGLM, JHNxxxGML, JHxNxxGLM, JHxNxxGML \r\nJHxxNxGLM, JHxxNxGML, JHxxxNGLM, JHxxxNGML \r\nJHxxxNMGL, JHxxxNMLG, JHxxNMLGx, JHxNMLGxx \r\nJHNMLGxxx, JHxxxGLMN, JHxxGLMNx, JHxGLMNxx \r\nJHGLMNxxx, JHGxxxNML, JHxGxxNML, JHxxGxNML \r\nJHxxxGNML \n\r\nApply each FKO order - F-K-O, F-O-K, K-F-O, K-O-F, O-F-K, O-K-F - to each xxx above. That makes 21*6=126 arrangements.\n<|im_start|>answer\nWith each arrangement considered identical to its reverse, there are 126 possible arrangements. \n\r\n FKO are interchangeable, and can be arranged 6 ways. FKO stays together unless N is next to M outside GLM (more on that below). \n\r\nJH must be together, and J must be at the end, because H is the only other Russian speaker. JH has 2 slots in the above configuration (H next to FKO, with J on the outside). \n\r\nGLM has 1 slot in the above configuration (G next to FKO, opposite JH). \n\r\n2[JH]*6[FKO]*1[MLG]=12 arrangements, or 2 mirror groups of 6 arrangements each. Thus, 6 distinct arrangements - 1 for each FKO order. \n\r\nKeeping the above groups self-contained, N has 5 slots (2 within FKO, 1 between FKO and H, 1 between FKO and G, 1 beside M). That makes 30 arrangements - 5 for each FKO order. \n\r\nWhen N is in certain positions, however, the groups can break up. Unless N is next to M outside GLM, GLM can be GML. If N is between FKO and GLM, GLM can scramble, and G can be anywhere touching FKO, except N cannot touch L. When G-[L/M]-N are consecutive in either direction, FKO can straddle that subgroup. That makes 126 arrangements - 21 for each FKO order. \n\r\nHere are the 21 arrangements, using xxx for the interchangeable FKO. \n\r\nJHNxxxGLM, JHNxxxGML, JHxNxxGLM, JHxNxxGML \r\nJHxxNxGLM, JHxxNxGML, JHxxxNGLM, JHxxxNGML \r\nJHxxxNMGL, JHxxxNMLG, JHxxNMLGx, JHxNMLGxx \r\nJHNMLGxxx, JHxxxGLMN, JHxxGLMNx, JHxGLMNxx \r\nJHGLMNxxx, JHGxxxNML, JHxGxxNML, JHxxGxNML \r\nJHxxxGNML \n\r\nApply each FKO order - F-K-O, F-O-K, K-F-O, K-O-F, O-F-K, O-K-F - to each xxx above. That makes 21*6=126 arrangements.\n<|im_end|>" }, { "id": "#19276", "title": "Truth, Lie or Both ...", "fun": 2.29, "difficulty": 2.5100000000000002, "author": "lesternoronha1", "desc": "There are three students Anu, Bob and Coy. They have exactly three books - one on Physics, one on Chemistry and one on Math. Each of these three books belongs to exactly one of the students. As I wanted to know the names of the respective owners of the books I asked them about the owners of the books. The following are the answers given by Anu, Bob and Coy.\n\r\nAnu : Physics book belongs to me. Maths book does not belong to Bob. Chemistry book does not belong to Coy.\r\nBob : Physics book does not belong to me. Chemistry book belongs to Coy. Maths book does not belong to Anu.\r\nCoy : Physics book does not belong to Anu. Maths book does not belong to me. Chemistry book does not belong to Bob.\n\r\nI knew that exactly one of them always speaks the truth, exactly one of them always lies and the third one alternates between truth and lie, in any order.\n\r\nWhich of the following statements can then be concluded?\n\r\n1) Anu always tells the truth.\r\n2) Coy always lies.\r\n3) Bob is the owner of the Chemistry book.\n\r\nNOTE: Out of the given set of 3 statements, it is not necessary that one and only one statement can be concluded. One or more statements can be concluded.", "hint": "No hint available.", "answer": "All the three given statements can be concluded.\n\r\nThe given statements are\r\n1) Anu always tells the truth.\r\n2) Coy always lies.\r\n3) Bob is the owner of the Chemistry book.\n\r\nThe answers given by Anu, Bob and Coy to my query about the owners of the Physics, Chemistry and Maths books are as follows :-\n\r\nAnu : Physics book belongs to me. Maths book does not belong to Bob. Chemistry book does not belong to Coy.\r\nBob : Physics book does not belong to me. Chemistry book belongs to Coy. Maths book does not belong to Anu.\r\nCoy : Physics book does not belong to Anu. Maths book does not belong to me. Chemistry book does not belong to Bob.\n\r\nCase 1 : Let us assume that Anu always tells the truth. \n\r\nThen according to Anu's answer,\r\nPhysics book belongs to Anu. \r\nChemistry book belongs to Bob.\r\nMaths book belongs to Coy.\n\r\nComparing Anu's reply with that of Bob's and Coy's replies, we can infer that\n\r\nBob speaks the truth, lies and speaks the truth respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nCoy lies three times when he says that the Physics book does not belong to Anu, the Maths book does not belong to him and the Chemistry book does not belong to Bob.\n\r\nHence under Case 1, Anu always speaks the truth, Bob alternates between truth and lie and Coy always lies. Also in this case the Chemistry book belongs to Bob.\n\r\nCase 2 : Let us assume that Bob always tells the truth. \n\r\nThen according to Bob's answer,\r\nPhysics book belongs to Anu. \r\nMaths book belongs to Bob.\r\nChemistry book belongs to Coy.\n\r\nComparing Bob's reply with that of Anu's and Coy's replies, we can infer that\n\r\nAnu speaks the truth, lies and lies respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nCoy lies, speaks the truth and speaks the truth respectively when he says that the Physics book does not belong to Anu, the Maths book does not belong to him and the Chemistry book does not belong to Bob.\n\r\nHence under Case 2, Bob always speaks the truth, Anu and Coy alternate between truth and lie and hence this case is not possible since it is given that exactly one of them always speaks the truth, exactly one of them always lies and the third one alternates between truth and lie, in any order.\n\r\nCase 3 : Let us assume that Coy always tells the truth. Here we can again make two sub cases.\n\r\na) According to Coy's answer,\r\nMaths book belongs to Anu. \r\nPhysics book belongs to Bob.\r\nChemistry book belongs to Coy.\n\r\nComparing Coy's reply with that of Anu's and Bob's replies, we can infer that\n\r\nAnu lies, speaks the truth and lies respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nBob lies, speaks the truth and lies respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nThis case is not possible since both Anu and Bob are alternating between truth and lie and there is no one person who always lies.\n\r\nb) According to Coy's answer,\r\nChemistry book belongs to Anu. \r\nMaths book belongs to Bob.\r\nPhysics book belongs to Coy.\n\r\nComparing Coy's reply with that of Anu's and Bob's replies, we can infer that\n\r\nAnu lies, lies and speaks the truth respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nBob speaks the truth, lies and speaks the truth respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nThis case is also not possible since both Anu and Bob are alternating between truth and lie and there is no one person who always lies.\n\r\nHence among the three cases, only Case 1 can be considered to be a valid case wherein Anu always speaks the truth, Bob alternates between truth and lie, Coy always lies and the Chemistry book belongs to Bob. Hence all the given statements 1, 2 and 3 can be concluded.", "category": "Logic", "date": "11/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three students Anu, Bob and Coy. They have exactly three books - one on Physics, one on Chemistry and one on Math. Each of these three books belongs to exactly one of the students. As I wanted to know the names of the respective owners of the books I asked them about the owners of the books. The following are the answers given by Anu, Bob and Coy.\n\r\nAnu : Physics book belongs to me. Maths book does not belong to Bob. Chemistry book does not belong to Coy.\r\nBob : Physics book does not belong to me. Chemistry book belongs to Coy. Maths book does not belong to Anu.\r\nCoy : Physics book does not belong to Anu. Maths book does not belong to me. Chemistry book does not belong to Bob.\n\r\nI knew that exactly one of them always speaks the truth, exactly one of them always lies and the third one alternates between truth and lie, in any order.\n\r\nWhich of the following statements can then be concluded?\n\r\n1) Anu always tells the truth.\r\n2) Coy always lies.\r\n3) Bob is the owner of the Chemistry book.\n\r\nNOTE: Out of the given set of 3 statements, it is not necessary that one and only one statement can be concluded. One or more statements can be concluded.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll the three given statements can be concluded.\n\r\nThe given statements are\r\n1) Anu always tells the truth.\r\n2) Coy always lies.\r\n3) Bob is the owner of the Chemistry book.\n\r\nThe answers given by Anu, Bob and Coy to my query about the owners of the Physics, Chemistry and Maths books are as follows :-\n\r\nAnu : Physics book belongs to me. Maths book does not belong to Bob. Chemistry book does not belong to Coy.\r\nBob : Physics book does not belong to me. Chemistry book belongs to Coy. Maths book does not belong to Anu.\r\nCoy : Physics book does not belong to Anu. Maths book does not belong to me. Chemistry book does not belong to Bob.\n\r\nCase 1 : Let us assume that Anu always tells the truth. \n\r\nThen according to Anu's answer,\r\nPhysics book belongs to Anu. \r\nChemistry book belongs to Bob.\r\nMaths book belongs to Coy.\n\r\nComparing Anu's reply with that of Bob's and Coy's replies, we can infer that\n\r\nBob speaks the truth, lies and speaks the truth respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nCoy lies three times when he says that the Physics book does not belong to Anu, the Maths book does not belong to him and the Chemistry book does not belong to Bob.\n\r\nHence under Case 1, Anu always speaks the truth, Bob alternates between truth and lie and Coy always lies. Also in this case the Chemistry book belongs to Bob.\n\r\nCase 2 : Let us assume that Bob always tells the truth. \n\r\nThen according to Bob's answer,\r\nPhysics book belongs to Anu. \r\nMaths book belongs to Bob.\r\nChemistry book belongs to Coy.\n\r\nComparing Bob's reply with that of Anu's and Coy's replies, we can infer that\n\r\nAnu speaks the truth, lies and lies respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nCoy lies, speaks the truth and speaks the truth respectively when he says that the Physics book does not belong to Anu, the Maths book does not belong to him and the Chemistry book does not belong to Bob.\n\r\nHence under Case 2, Bob always speaks the truth, Anu and Coy alternate between truth and lie and hence this case is not possible since it is given that exactly one of them always speaks the truth, exactly one of them always lies and the third one alternates between truth and lie, in any order.\n\r\nCase 3 : Let us assume that Coy always tells the truth. Here we can again make two sub cases.\n\r\na) According to Coy's answer,\r\nMaths book belongs to Anu. \r\nPhysics book belongs to Bob.\r\nChemistry book belongs to Coy.\n\r\nComparing Coy's reply with that of Anu's and Bob's replies, we can infer that\n\r\nAnu lies, speaks the truth and lies respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nBob lies, speaks the truth and lies respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nThis case is not possible since both Anu and Bob are alternating between truth and lie and there is no one person who always lies.\n\r\nb) According to Coy's answer,\r\nChemistry book belongs to Anu. \r\nMaths book belongs to Bob.\r\nPhysics book belongs to Coy.\n\r\nComparing Coy's reply with that of Anu's and Bob's replies, we can infer that\n\r\nAnu lies, lies and speaks the truth respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nBob speaks the truth, lies and speaks the truth respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nThis case is also not possible since both Anu and Bob are alternating between truth and lie and there is no one person who always lies.\n\r\nHence among the three cases, only Case 1 can be considered to be a valid case wherein Anu always speaks the truth, Bob alternates between truth and lie, Coy always lies and the Chemistry book belongs to Bob. Hence all the given statements 1, 2 and 3 can be concluded.\n<|im_start|>answer\nAll the three given statements can be concluded.\n\r\nThe given statements are\r\n1) Anu always tells the truth.\r\n2) Coy always lies.\r\n3) Bob is the owner of the Chemistry book.\n\r\nThe answers given by Anu, Bob and Coy to my query about the owners of the Physics, Chemistry and Maths books are as follows :-\n\r\nAnu : Physics book belongs to me. Maths book does not belong to Bob. Chemistry book does not belong to Coy.\r\nBob : Physics book does not belong to me. Chemistry book belongs to Coy. Maths book does not belong to Anu.\r\nCoy : Physics book does not belong to Anu. Maths book does not belong to me. Chemistry book does not belong to Bob.\n\r\nCase 1 : Let us assume that Anu always tells the truth. \n\r\nThen according to Anu's answer,\r\nPhysics book belongs to Anu. \r\nChemistry book belongs to Bob.\r\nMaths book belongs to Coy.\n\r\nComparing Anu's reply with that of Bob's and Coy's replies, we can infer that\n\r\nBob speaks the truth, lies and speaks the truth respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nCoy lies three times when he says that the Physics book does not belong to Anu, the Maths book does not belong to him and the Chemistry book does not belong to Bob.\n\r\nHence under Case 1, Anu always speaks the truth, Bob alternates between truth and lie and Coy always lies. Also in this case the Chemistry book belongs to Bob.\n\r\nCase 2 : Let us assume that Bob always tells the truth. \n\r\nThen according to Bob's answer,\r\nPhysics book belongs to Anu. \r\nMaths book belongs to Bob.\r\nChemistry book belongs to Coy.\n\r\nComparing Bob's reply with that of Anu's and Coy's replies, we can infer that\n\r\nAnu speaks the truth, lies and lies respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nCoy lies, speaks the truth and speaks the truth respectively when he says that the Physics book does not belong to Anu, the Maths book does not belong to him and the Chemistry book does not belong to Bob.\n\r\nHence under Case 2, Bob always speaks the truth, Anu and Coy alternate between truth and lie and hence this case is not possible since it is given that exactly one of them always speaks the truth, exactly one of them always lies and the third one alternates between truth and lie, in any order.\n\r\nCase 3 : Let us assume that Coy always tells the truth. Here we can again make two sub cases.\n\r\na) According to Coy's answer,\r\nMaths book belongs to Anu. \r\nPhysics book belongs to Bob.\r\nChemistry book belongs to Coy.\n\r\nComparing Coy's reply with that of Anu's and Bob's replies, we can infer that\n\r\nAnu lies, speaks the truth and lies respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nBob lies, speaks the truth and lies respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nThis case is not possible since both Anu and Bob are alternating between truth and lie and there is no one person who always lies.\n\r\nb) According to Coy's answer,\r\nChemistry book belongs to Anu. \r\nMaths book belongs to Bob.\r\nPhysics book belongs to Coy.\n\r\nComparing Coy's reply with that of Anu's and Bob's replies, we can infer that\n\r\nAnu lies, lies and speaks the truth respectively when he says that the Physics book belongs to him, the Maths book does not belong to Bob and the Chemistry book does not belong to Coy.\n\r\nBob speaks the truth, lies and speaks the truth respectively when he says that the Physics book does not belong to him, the Chemistry book belongs to Coy and the Maths book does not belong to Anu.\n\r\nThis case is also not possible since both Anu and Bob are alternating between truth and lie and there is no one person who always lies.\n\r\nHence among the three cases, only Case 1 can be considered to be a valid case wherein Anu always speaks the truth, Bob alternates between truth and lie, Coy always lies and the Chemistry book belongs to Bob. Hence all the given statements 1, 2 and 3 can be concluded.\n<|im_end|>" }, { "id": "#1243", "title": "Distance Between", "fun": 2.29, "difficulty": 1.44, "author": "gokaran", "desc": "Two men, starting at the same point, walk in opposite directions for 4 meters, turn left and walk another 3 meters. What is the distance between them?", "hint": "No hint available.", "answer": "10 meters", "category": "Math", "date": "10/31/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo men, starting at the same point, walk in opposite directions for 4 meters, turn left and walk another 3 meters. What is the distance between them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10 meters\n<|im_start|>answer\n10 meters\n<|im_end|>" }, { "id": "#28861", "title": "Ringing All Around", "fun": 2.29, "difficulty": 2.92, "author": "miyukina", "desc": "It's easy to see that a ring can completely hold (surround) two identical smaller rings with half the diameter, without overlapping. Three times the diameter, the bigger ring is space enough to seat seven rings; the outer six touching both the middle ring and the bigger circle/perimeter.\n\r\nUsing this basic information and your imagination, determine the maximum number of rings that could be housed inside another ring with four, five, six and seven times the diameter.", "hint": "I would say \"go and chop down your trees\" but Greenpeace people might sue me.", "answer": "For 4D (four times the diameter) ring, place the 2D ring exactly at the center inside 4D, and you will have donut-shaped empty space with a width of a D ring, around the 2D. The number of rings to be fit in this vacancy, R, is determined from the formula\n\r\nR < (n - 1)*pi\n\r\nwhere n is the nth times the diameter and R is an integer.\n\r\nThis formula is derived from the fact that the circumference of a polygon with R sides (made up by connecting all the nucleus of the rings in the donut area) is always smaller (actually is inscribed in) than the locus of the donut area. This locus is, of course, neither the donut's outer nor inner ring, but the one in between those two. \n\r\nIn a 4D ring:\r\ncentral 2D = 2\r\nR < (4 - 1)*pi = 9\r\nnumber of rings, x = 2 + 9 = 11\n\r\nIn 5D ring with 3D center:\r\nx = 7 + 12 = 19\n\r\n6D: x = 11 + 15 = 26\r\n7D: x = 19 + 18 = 37\n\r\nThe center for nth ring is always the (n - 2)th one. This calculation is based on the hypothesis that the accumulated/shared empty spaces (outside small rings) among central and donut area is small enough to fit for another ring.", "category": "Math", "date": "03/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's easy to see that a ring can completely hold (surround) two identical smaller rings with half the diameter, without overlapping. Three times the diameter, the bigger ring is space enough to seat seven rings; the outer six touching both the middle ring and the bigger circle/perimeter.\n\r\nUsing this basic information and your imagination, determine the maximum number of rings that could be housed inside another ring with four, five, six and seven times the diameter.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor 4D (four times the diameter) ring, place the 2D ring exactly at the center inside 4D, and you will have donut-shaped empty space with a width of a D ring, around the 2D. The number of rings to be fit in this vacancy, R, is determined from the formula\n\r\nR < (n - 1)*pi\n\r\nwhere n is the nth times the diameter and R is an integer.\n\r\nThis formula is derived from the fact that the circumference of a polygon with R sides (made up by connecting all the nucleus of the rings in the donut area) is always smaller (actually is inscribed in) than the locus of the donut area. This locus is, of course, neither the donut's outer nor inner ring, but the one in between those two. \n\r\nIn a 4D ring:\r\ncentral 2D = 2\r\nR < (4 - 1)*pi = 9\r\nnumber of rings, x = 2 + 9 = 11\n\r\nIn 5D ring with 3D center:\r\nx = 7 + 12 = 19\n\r\n6D: x = 11 + 15 = 26\r\n7D: x = 19 + 18 = 37\n\r\nThe center for nth ring is always the (n - 2)th one. This calculation is based on the hypothesis that the accumulated/shared empty spaces (outside small rings) among central and donut area is small enough to fit for another ring.\n<|im_start|>answer\nFor 4D (four times the diameter) ring, place the 2D ring exactly at the center inside 4D, and you will have donut-shaped empty space with a width of a D ring, around the 2D. The number of rings to be fit in this vacancy, R, is determined from the formula\n\r\nR < (n - 1)*pi\n\r\nwhere n is the nth times the diameter and R is an integer.\n\r\nThis formula is derived from the fact that the circumference of a polygon with R sides (made up by connecting all the nucleus of the rings in the donut area) is always smaller (actually is inscribed in) than the locus of the donut area. This locus is, of course, neither the donut's outer nor inner ring, but the one in between those two. \n\r\nIn a 4D ring:\r\ncentral 2D = 2\r\nR < (4 - 1)*pi = 9\r\nnumber of rings, x = 2 + 9 = 11\n\r\nIn 5D ring with 3D center:\r\nx = 7 + 12 = 19\n\r\n6D: x = 11 + 15 = 26\r\n7D: x = 19 + 18 = 37\n\r\nThe center for nth ring is always the (n - 2)th one. This calculation is based on the hypothesis that the accumulated/shared empty spaces (outside small rings) among central and donut area is small enough to fit for another ring.\n<|im_end|>" }, { "id": "#2856", "title": "Clock Strikes", "fun": 2.29, "difficulty": 1.49, "author": "204_BLaZe_41", "desc": "If a grandfather clock takes five seconds to strike 6 o'clock, how many seconds will it take to strike 12 o'clock?", "hint": "No hint available.", "answer": "Eleven. It will always be one second short of whatever the number since the time doesn't start until the first strike.", "category": "Logic", "date": "03/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a grandfather clock takes five seconds to strike 6 o'clock, how many seconds will it take to strike 12 o'clock?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEleven. It will always be one second short of whatever the number since the time doesn't start until the first strike.\n<|im_start|>answer\nEleven. It will always be one second short of whatever the number since the time doesn't start until the first strike.\n<|im_end|>" }, { "id": "#30302", "title": "** and ++", "fun": 2.29, "difficulty": 2.74, "author": "mercenary007", "desc": "If 3**5 = 27 but 5**3 = 35\n\r\n4++8 = 20 but 8++4 = 16\n\r\nThen what is the result of (8**7)++9?", "hint": "No hint available.", "answer": "The result is 106.\n\r\nFor the operator **, you add 4 to the second number and then multiply, so a**b = a * (b + 4)\n\r\nand a++b = a + (b * 2)\n\r\nSo therefore (8**7) ++9 = (8*(7 + 4)) ++ 9\n\r\n= 88++9\r\n= 88 + (9 *2)\r\n= 88 + 18\r\n= 106", "category": "Math", "date": "05/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 3**5 = 27 but 5**3 = 35\n\r\n4++8 = 20 but 8++4 = 16\n\r\nThen what is the result of (8**7)++9?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe result is 106.\n\r\nFor the operator **, you add 4 to the second number and then multiply, so a**b = a * (b + 4)\n\r\nand a++b = a + (b * 2)\n\r\nSo therefore (8**7) ++9 = (8*(7 + 4)) ++ 9\n\r\n= 88++9\r\n= 88 + (9 *2)\r\n= 88 + 18\r\n= 106\n<|im_start|>answer\nThe result is 106.\n\r\nFor the operator **, you add 4 to the second number and then multiply, so a**b = a * (b + 4)\n\r\nand a++b = a + (b * 2)\n\r\nSo therefore (8**7) ++9 = (8*(7 + 4)) ++ 9\n\r\n= 88++9\r\n= 88 + (9 *2)\r\n= 88 + 18\r\n= 106\n<|im_end|>" }, { "id": "#42696", "title": "Mixed Mexican Soccer Team", "fun": 2.29, "difficulty": 1.74, "author": "whsprec", "desc": "Mexico put together a mixed soccer team to compete against teams from other countries. Five members of the team, 2 women: Maria and Lylia, and 3 men: Alberto, Hugo, and Carlos, came from 5 different cities: Acapulco, Hermosillo, Monterrey, Huetamo, and Los Mochis. These 5 cities are found in 5 different states: Guerrero, Nuevo Leon, Sonora, Sinaloa, and Michoacan. Match the players to their home town and state.\n\r\n1) Hugo is from the state of Michoacan.\r\n2) Maria plays on the team with her husband who is from Hermosillo which lies in the state north of Sinaloa.\r\n3) Lylia is not from Sinaloa or Guerrero.\r\n4) Los Mochis is in Sinaloa and Hermosillo is the capital of Sonora.\r\n5) Alberto had dinner with Maria, who is from Los Mochis, and her husband at Lylia's home in Monterrey.\r\n6) Guerrero borders the state where Huetamo is found.", "hint": "No hint available.", "answer": "Hugo is from Huetamo in Michoacan\r\nMaria is from Los Mochis in Sinaloa\r\nCarlos is from Hermosillo in Sonora\r\nLylia is from Monterrey in Nuevo Leon\r\nAlberto is from Acapulco in Guerrero", "category": "Logic-Grid", "date": "08/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMexico put together a mixed soccer team to compete against teams from other countries. Five members of the team, 2 women: Maria and Lylia, and 3 men: Alberto, Hugo, and Carlos, came from 5 different cities: Acapulco, Hermosillo, Monterrey, Huetamo, and Los Mochis. These 5 cities are found in 5 different states: Guerrero, Nuevo Leon, Sonora, Sinaloa, and Michoacan. Match the players to their home town and state.\n\r\n1) Hugo is from the state of Michoacan.\r\n2) Maria plays on the team with her husband who is from Hermosillo which lies in the state north of Sinaloa.\r\n3) Lylia is not from Sinaloa or Guerrero.\r\n4) Los Mochis is in Sinaloa and Hermosillo is the capital of Sonora.\r\n5) Alberto had dinner with Maria, who is from Los Mochis, and her husband at Lylia's home in Monterrey.\r\n6) Guerrero borders the state where Huetamo is found.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHugo is from Huetamo in Michoacan\r\nMaria is from Los Mochis in Sinaloa\r\nCarlos is from Hermosillo in Sonora\r\nLylia is from Monterrey in Nuevo Leon\r\nAlberto is from Acapulco in Guerrero\n<|im_start|>answer\nHugo is from Huetamo in Michoacan\r\nMaria is from Los Mochis in Sinaloa\r\nCarlos is from Hermosillo in Sonora\r\nLylia is from Monterrey in Nuevo Leon\r\nAlberto is from Acapulco in Guerrero\n<|im_end|>" }, { "id": "#715", "title": "The Cork and the Coin", "fun": 2.29, "difficulty": 1.48, "author": "GarnetGurl", "desc": "If you were to put a coin into an empty bottle and then insert a cork into the neck, how could you remove the coin without taking out the cork or breaking the bottle?", "hint": "No hint available.", "answer": "Push the cork into the bottle and shake the coin out.", "category": "Logic", "date": "07/25/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you were to put a coin into an empty bottle and then insert a cork into the neck, how could you remove the coin without taking out the cork or breaking the bottle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPush the cork into the bottle and shake the coin out.\n<|im_start|>answer\nPush the cork into the bottle and shake the coin out.\n<|im_end|>" }, { "id": "#6486", "title": "Three Digit Number", "fun": 2.29, "difficulty": 1.94, "author": "mad-ade", "desc": "A 3 digit number is such that its unit digit is equal to the product of the other two digits which are prime. Also, the difference between its reverse and itself is 396. \n\r\nWhat is the sum of the three digits?", "hint": "No hint available.", "answer": "The required number is 236 and the sum is 11. \n\r\nIt is given that the first two digits of the required number are prime numbers i.e. 2, 3, 5 or 7. Note that 1 is neither prime nor composite. Also, the third digit is the multiplication of the first two digits. Thus, first two digits must be either 2 or 3 i.e. 22, 23, 32 or 33 which means that there are four possible numbers - 224, 236, 326 and 339. \n\r\nNow, it is also given that - the difference between its reverse and itself is 396. Only 236 satisfies this condition. Hence, the sum of the three digits is 11.", "category": "Math", "date": "08/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 3 digit number is such that its unit digit is equal to the product of the other two digits which are prime. Also, the difference between its reverse and itself is 396. \n\r\nWhat is the sum of the three digits?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe required number is 236 and the sum is 11. \n\r\nIt is given that the first two digits of the required number are prime numbers i.e. 2, 3, 5 or 7. Note that 1 is neither prime nor composite. Also, the third digit is the multiplication of the first two digits. Thus, first two digits must be either 2 or 3 i.e. 22, 23, 32 or 33 which means that there are four possible numbers - 224, 236, 326 and 339. \n\r\nNow, it is also given that - the difference between its reverse and itself is 396. Only 236 satisfies this condition. Hence, the sum of the three digits is 11.\n<|im_start|>answer\nThe required number is 236 and the sum is 11. \n\r\nIt is given that the first two digits of the required number are prime numbers i.e. 2, 3, 5 or 7. Note that 1 is neither prime nor composite. Also, the third digit is the multiplication of the first two digits. Thus, first two digits must be either 2 or 3 i.e. 22, 23, 32 or 33 which means that there are four possible numbers - 224, 236, 326 and 339. \n\r\nNow, it is also given that - the difference between its reverse and itself is 396. Only 236 satisfies this condition. Hence, the sum of the three digits is 11.\n<|im_end|>" }, { "id": "#1268", "title": "Aliens", "fun": 2.29, "difficulty": 1.34, "author": "Yanivster", "desc": "Five months from today, it will be exactly ten months from the day when a rumor about aliens coming to town in one month was spread.\r\nIn reality, the aliens arrived two months late.\r\nWhen did the aliens arrive?", "hint": "No hint available.", "answer": "Two months ago.", "category": "Logic", "date": "11/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive months from today, it will be exactly ten months from the day when a rumor about aliens coming to town in one month was spread.\r\nIn reality, the aliens arrived two months late.\r\nWhen did the aliens arrive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwo months ago.\n<|im_start|>answer\nTwo months ago.\n<|im_end|>" }, { "id": "#6222", "title": "3:15pm", "fun": 2.29, "difficulty": 1.91, "author": "mad-ade", "desc": "Once more, Mad Ade is waiting for the local Kebab shop to open.\r\nHe glances at his clock and notices the time is 3:15pm. Out of sheer boredom Mad Ade works out the angle between the minute and hour hand. \n\r\nWhat was the angle between the hour and the minute hands at 3:15pm?", "hint": "No hint available.", "answer": "7.5 degrees \n\r\nAt 3:15, the minute hand will be perfectly horizontal pointing towards 3, whereas the hour hand will be moving towards 4. Also, the hour hand must have covered 1/4 of angle between 3 and 4. \n\r\nThe angle between two adjacent digits is 360/12 = 30 degrees. \n\r\nHence, 1/4 of it is 7.5 degrees.", "category": "Logic", "date": "08/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce more, Mad Ade is waiting for the local Kebab shop to open.\r\nHe glances at his clock and notices the time is 3:15pm. Out of sheer boredom Mad Ade works out the angle between the minute and hour hand. \n\r\nWhat was the angle between the hour and the minute hands at 3:15pm?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7.5 degrees \n\r\nAt 3:15, the minute hand will be perfectly horizontal pointing towards 3, whereas the hour hand will be moving towards 4. Also, the hour hand must have covered 1/4 of angle between 3 and 4. \n\r\nThe angle between two adjacent digits is 360/12 = 30 degrees. \n\r\nHence, 1/4 of it is 7.5 degrees.\n<|im_start|>answer\n7.5 degrees \n\r\nAt 3:15, the minute hand will be perfectly horizontal pointing towards 3, whereas the hour hand will be moving towards 4. Also, the hour hand must have covered 1/4 of angle between 3 and 4. \n\r\nThe angle between two adjacent digits is 360/12 = 30 degrees. \n\r\nHence, 1/4 of it is 7.5 degrees.\n<|im_end|>" }, { "id": "#4900", "title": "Broken Ski Lift", "fun": 2.29, "difficulty": 1.85, "author": "mad-ade", "desc": "Mad Ade is on holiday enjoying a cross country skiing and kebab hunting holiday. After a busy day, Mad Ade is returning to his hotel and using the ski lift. Half way up, the ski lift suddenly breaks down, leaving Mad Ade and several other passengers stranded. Mad Ade notices that the empty chair that has stopped opposite him on the lift was marked with the number 81. Mad Ade's chair was number 9. How many ski chairs did the ski lift contain altogether, considering that all numbers are consecutive?", "hint": "No hint available.", "answer": "144\r\nThere is 71 difference between 9 and 81, so there are 71 chairs from Mad Ade's chair to the empty chair marked 81, and also another 71 from chair 81 back around to Mad Ade's number 9 chair.\r\n71+71=142+2(chairs 9+81)=144", "category": "Math", "date": "06/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is on holiday enjoying a cross country skiing and kebab hunting holiday. After a busy day, Mad Ade is returning to his hotel and using the ski lift. Half way up, the ski lift suddenly breaks down, leaving Mad Ade and several other passengers stranded. Mad Ade notices that the empty chair that has stopped opposite him on the lift was marked with the number 81. Mad Ade's chair was number 9. How many ski chairs did the ski lift contain altogether, considering that all numbers are consecutive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n144\r\nThere is 71 difference between 9 and 81, so there are 71 chairs from Mad Ade's chair to the empty chair marked 81, and also another 71 from chair 81 back around to Mad Ade's number 9 chair.\r\n71+71=142+2(chairs 9+81)=144\n<|im_start|>answer\n144\r\nThere is 71 difference between 9 and 81, so there are 71 chairs from Mad Ade's chair to the empty chair marked 81, and also another 71 from chair 81 back around to Mad Ade's number 9 chair.\r\n71+71=142+2(chairs 9+81)=144\n<|im_end|>" }, { "id": "#8595", "title": "Sweaty Chef's Kebab Shop", "fun": 2.29, "difficulty": 2.42, "author": "mad-ade", "desc": "In the \"Sweaty Chef\" kebab shop, there are many different types of food, all at various prices (in the local currency, Madadian Wonks).\r\nNone of the prices are listed individually, but are displayed as part of special meal deal groups.\r\nThere are four groups which consist of the \"Sweaty Chef's\" main sellers of Kebabs, Fries and pop (soda) as follows: \r\nGroup I : 1 Kebab, 1 Fries and 1 Pop \r\nGroup II : 1 Kebabs, 5 Fries and 7 Pop \r\nGroup III : 1 Kebabs, 7 Fries and 10 Pop \r\nGroup IV : 9 Kebabs, 23 Fries and 30 Pop \n\r\nGroup II costs 300 Madadian Wonks (MW) and Group III costs 390MW. \n\r\nCan you tell how much Group I and Group IV cost?", "hint": "No hint available.", "answer": "Group I costs 120MW and Group IV costs 1710MW.\n\r\nAssume that the values of one Kebab, one Fries and one Pop are K, F and P respectively. \n\r\nFrom Group II : K + 5F + 7P = 300 \r\nFrom Group III : K + 7F + 10P = 390 \n\r\nSubtracting above two equations : 2F + 3P = 90 \n\r\nFor Group I : \r\n= K + F + P\r\n= (K + 5F + 7P) - (4F + 6P) \r\n= (K + 5F + 7P) - 2(2F + 3P) \r\n= 300 - 2(90) \r\n= 300 - 180 \r\n= 120 \n\r\nSimilarly, for Group IV : \r\n= 9K + 23F + 30P \r\n= 9(K + 5F + 7P) - (22F + 33P) \r\n= 9(K + 5F + 7P) - 11(2F + 3P) \r\n= 9(300) - 11(90) \r\n= 2700 - 990 \r\n= 1710 \n\r\nThus, Group I costs 120MW and Group IV costs 1710MW.", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the \"Sweaty Chef\" kebab shop, there are many different types of food, all at various prices (in the local currency, Madadian Wonks).\r\nNone of the prices are listed individually, but are displayed as part of special meal deal groups.\r\nThere are four groups which consist of the \"Sweaty Chef's\" main sellers of Kebabs, Fries and pop (soda) as follows: \r\nGroup I : 1 Kebab, 1 Fries and 1 Pop \r\nGroup II : 1 Kebabs, 5 Fries and 7 Pop \r\nGroup III : 1 Kebabs, 7 Fries and 10 Pop \r\nGroup IV : 9 Kebabs, 23 Fries and 30 Pop \n\r\nGroup II costs 300 Madadian Wonks (MW) and Group III costs 390MW. \n\r\nCan you tell how much Group I and Group IV cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGroup I costs 120MW and Group IV costs 1710MW.\n\r\nAssume that the values of one Kebab, one Fries and one Pop are K, F and P respectively. \n\r\nFrom Group II : K + 5F + 7P = 300 \r\nFrom Group III : K + 7F + 10P = 390 \n\r\nSubtracting above two equations : 2F + 3P = 90 \n\r\nFor Group I : \r\n= K + F + P\r\n= (K + 5F + 7P) - (4F + 6P) \r\n= (K + 5F + 7P) - 2(2F + 3P) \r\n= 300 - 2(90) \r\n= 300 - 180 \r\n= 120 \n\r\nSimilarly, for Group IV : \r\n= 9K + 23F + 30P \r\n= 9(K + 5F + 7P) - (22F + 33P) \r\n= 9(K + 5F + 7P) - 11(2F + 3P) \r\n= 9(300) - 11(90) \r\n= 2700 - 990 \r\n= 1710 \n\r\nThus, Group I costs 120MW and Group IV costs 1710MW.\n<|im_start|>answer\nGroup I costs 120MW and Group IV costs 1710MW.\n\r\nAssume that the values of one Kebab, one Fries and one Pop are K, F and P respectively. \n\r\nFrom Group II : K + 5F + 7P = 300 \r\nFrom Group III : K + 7F + 10P = 390 \n\r\nSubtracting above two equations : 2F + 3P = 90 \n\r\nFor Group I : \r\n= K + F + P\r\n= (K + 5F + 7P) - (4F + 6P) \r\n= (K + 5F + 7P) - 2(2F + 3P) \r\n= 300 - 2(90) \r\n= 300 - 180 \r\n= 120 \n\r\nSimilarly, for Group IV : \r\n= 9K + 23F + 30P \r\n= 9(K + 5F + 7P) - (22F + 33P) \r\n= 9(K + 5F + 7P) - 11(2F + 3P) \r\n= 9(300) - 11(90) \r\n= 2700 - 990 \r\n= 1710 \n\r\nThus, Group I costs 120MW and Group IV costs 1710MW.\n<|im_end|>" }, { "id": "#727", "title": "Volleyball Team", "fun": 2.29, "difficulty": 1.45, "author": "vikass", "desc": "There are six players on a coed volleyball team. After an exhausting game, each girl drinks 5 cups of water. Each boy drinks 7 cups of water. The coach drinks 9 cups.\r\nA total of 43 cups of water is consumed by everyone. How many boys and how many girls are there on the team?", "hint": "No hint available.", "answer": "4 girls and 2 boys", "category": "Math", "date": "08/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are six players on a coed volleyball team. After an exhausting game, each girl drinks 5 cups of water. Each boy drinks 7 cups of water. The coach drinks 9 cups.\r\nA total of 43 cups of water is consumed by everyone. How many boys and how many girls are there on the team?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 girls and 2 boys\n<|im_start|>answer\n4 girls and 2 boys\n<|im_end|>" }, { "id": "#18365", "title": "Pete, Andy and The Lampposts", "fun": 2.29, "difficulty": 2.24, "author": "bintot", "desc": "Pete and Andy were employed by the local town authorities to repaint the lampposts on Main Street. \n\r\nPete, an early riser, arrived first on the job and had already painted three on the south side of the street when Andy turned up and pointed out that Pete was supposed to do the north side. So Pete started all over on the north side and Andy continued on the south side. \n\r\nWhen Andy finished his side he went across the street and painted six posts for Pete. \n\r\nThere were an equal number of lampposts on each side of the street. Which man painted more lampposts, and just how many more?", "hint": "No hint available.", "answer": "Andy must have painted six more lampposts than Pete, no matter how many lampposts there were. Let us say there were 20 on each side; then Andy painted 23 and Pete 17.", "category": "Math", "date": "07/27/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPete and Andy were employed by the local town authorities to repaint the lampposts on Main Street. \n\r\nPete, an early riser, arrived first on the job and had already painted three on the south side of the street when Andy turned up and pointed out that Pete was supposed to do the north side. So Pete started all over on the north side and Andy continued on the south side. \n\r\nWhen Andy finished his side he went across the street and painted six posts for Pete. \n\r\nThere were an equal number of lampposts on each side of the street. Which man painted more lampposts, and just how many more?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndy must have painted six more lampposts than Pete, no matter how many lampposts there were. Let us say there were 20 on each side; then Andy painted 23 and Pete 17.\n<|im_start|>answer\nAndy must have painted six more lampposts than Pete, no matter how many lampposts there were. Let us say there were 20 on each side; then Andy painted 23 and Pete 17.\n<|im_end|>" }, { "id": "#8590", "title": "Doughnut Pool", "fun": 2.29, "difficulty": 2.4, "author": "Gizzer", "desc": "Some office workers were holding a daily pool on the number of doughnuts their boss would eat each weekday morning during March. Each person set aside funds in their desk with which to bet. Each day from Monday, March 3rd, they all bet a dollar - Kevin bet on 2, Kate on 3 and Kathy on 3.5 doughnuts. Kathy won twice as many times as Kevin, who was right once more than Kate; sometimes there was no winner. By April, they all had $20 in their desks. How much was the most anyone could have had in their desk at the beginning of March?", "hint": "The pot does not accumulate if there is no winner - each person gets his \"stake\" back.", "answer": "$27\n\r\nThere would be 21 working days in a March where the first weekday is the third. The combination of wins in which anyone will have lost the most money has a total of 19 wins (10 for Kathy, 5 for Kevin and 4 for Kate). In this scenario, Kate would have lost 15 times ($15) and won 4 times ($8), for a net loss of $7. Since she now has $20, she must have started with $27.", "category": "Logic", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome office workers were holding a daily pool on the number of doughnuts their boss would eat each weekday morning during March. Each person set aside funds in their desk with which to bet. Each day from Monday, March 3rd, they all bet a dollar - Kevin bet on 2, Kate on 3 and Kathy on 3.5 doughnuts. Kathy won twice as many times as Kevin, who was right once more than Kate; sometimes there was no winner. By April, they all had $20 in their desks. How much was the most anyone could have had in their desk at the beginning of March?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$27\n\r\nThere would be 21 working days in a March where the first weekday is the third. The combination of wins in which anyone will have lost the most money has a total of 19 wins (10 for Kathy, 5 for Kevin and 4 for Kate). In this scenario, Kate would have lost 15 times ($15) and won 4 times ($8), for a net loss of $7. Since she now has $20, she must have started with $27.\n<|im_start|>answer\n$27\n\r\nThere would be 21 working days in a March where the first weekday is the third. The combination of wins in which anyone will have lost the most money has a total of 19 wins (10 for Kathy, 5 for Kevin and 4 for Kate). In this scenario, Kate would have lost 15 times ($15) and won 4 times ($8), for a net loss of $7. Since she now has $20, she must have started with $27.\n<|im_end|>" }, { "id": "#30948", "title": "Best Actor", "fun": 2.29, "difficulty": 1.16, "author": "dishu", "desc": "Four friends were arguing about whose favourite actor was the best. When the argument went on and on for a few hours, a well wisher suggested that the best actor be decided based on the number of box office hits he had last year. Can you figure out which friend liked which actor, and how many hits he had last year, based on following clues:\n\r\nFriends: Dis, Dip, Raj, Rich\r\nActors: Abby, Amit, Hrick, Aks\r\nNumber of box office successes : 1,2,3,5 (Assume each actor had a different number of hits)\n\n\r\n1. Dis hates Amit and Hrick.\r\n2. Raj seems to be the only fan of Hrick, a sentiment echoed by Hrick's declining popularity.\r\n3. Rich's favourite only had 2 hits last year.\r\n4. Though older than the rest, Dip's favourite is still popular and did not have the least number of hits.\r\n5. Abby won the \"maximum hits in last year\" award at a recent award function.\r\n6. Amit is the oldest actor around.", "hint": "No hint available.", "answer": "Friend Actor Hits\r\nDis Abby 5\r\nDip Amit 3\r\nRich Aks 2\r\nRaj Hrick 1", "category": "Logic-Grid", "date": "06/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends were arguing about whose favourite actor was the best. When the argument went on and on for a few hours, a well wisher suggested that the best actor be decided based on the number of box office hits he had last year. Can you figure out which friend liked which actor, and how many hits he had last year, based on following clues:\n\r\nFriends: Dis, Dip, Raj, Rich\r\nActors: Abby, Amit, Hrick, Aks\r\nNumber of box office successes : 1,2,3,5 (Assume each actor had a different number of hits)\n\n\r\n1. Dis hates Amit and Hrick.\r\n2. Raj seems to be the only fan of Hrick, a sentiment echoed by Hrick's declining popularity.\r\n3. Rich's favourite only had 2 hits last year.\r\n4. Though older than the rest, Dip's favourite is still popular and did not have the least number of hits.\r\n5. Abby won the \"maximum hits in last year\" award at a recent award function.\r\n6. Amit is the oldest actor around.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriend Actor Hits\r\nDis Abby 5\r\nDip Amit 3\r\nRich Aks 2\r\nRaj Hrick 1\n<|im_start|>answer\nFriend Actor Hits\r\nDis Abby 5\r\nDip Amit 3\r\nRich Aks 2\r\nRaj Hrick 1\n<|im_end|>" }, { "id": "#45106", "title": "The Experiment", "fun": 2.29, "difficulty": 2.26, "author": "solarsistim321", "desc": "Three human subjects underwent an experiment. They were each given one letter that could be found in the following words:\n\r\nThe, fit, lid, bet, and big.\n\r\nIf all three put their letters together, they would be able to spell one of the words above. However, the letter they were given could not be shared with any of the other four. They were all in the same room when a woman came through the door and sat down in front of them. She asked the first patient if he knew the what the word was that could be spelled using all three of the letters. He said yes. She then asked the other two patients and they both said yes.\n\r\nWhat was the word and how did all three know having only one letter and not knowing the other two?", "hint": "Assume that they did not cheat in any way and that each genuinely knew only the letter that they were given and that they told the truth when they said yes.", "answer": "The word it spelled was 'the'.\n\r\nThe first subject answered yes, he knew the word. This told subject two that subject one had a letter that appeared only once throughout all five words. This means patient one's letter had to have been 'h', 'f', 'l', 'd', or 'g'. This in turn informed subject two that 'bet' could not be the word.\n\r\nThe third subject also made the same progress as subject two, figuring out that subject one's letter had to have been one that appeared only once. 'Bet' was then eliminated and subject two said yes, he knew the word. Subject three knew that if subject two knew the word, he had to have had a 'b', 'e', 'l', or 'd'. Subject three could then eliminate the word 'fit' from the list.\n\r\nPatient three could only have had either an 't' or an 'i'. If he had an 'i', the word could have been 'lid' or 'big', but since he said yes he must to have had an 't'.", "category": "Logic", "date": "08/20/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree human subjects underwent an experiment. They were each given one letter that could be found in the following words:\n\r\nThe, fit, lid, bet, and big.\n\r\nIf all three put their letters together, they would be able to spell one of the words above. However, the letter they were given could not be shared with any of the other four. They were all in the same room when a woman came through the door and sat down in front of them. She asked the first patient if he knew the what the word was that could be spelled using all three of the letters. He said yes. She then asked the other two patients and they both said yes.\n\r\nWhat was the word and how did all three know having only one letter and not knowing the other two?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe word it spelled was 'the'.\n\r\nThe first subject answered yes, he knew the word. This told subject two that subject one had a letter that appeared only once throughout all five words. This means patient one's letter had to have been 'h', 'f', 'l', 'd', or 'g'. This in turn informed subject two that 'bet' could not be the word.\n\r\nThe third subject also made the same progress as subject two, figuring out that subject one's letter had to have been one that appeared only once. 'Bet' was then eliminated and subject two said yes, he knew the word. Subject three knew that if subject two knew the word, he had to have had a 'b', 'e', 'l', or 'd'. Subject three could then eliminate the word 'fit' from the list.\n\r\nPatient three could only have had either an 't' or an 'i'. If he had an 'i', the word could have been 'lid' or 'big', but since he said yes he must to have had an 't'.\n<|im_start|>answer\nThe word it spelled was 'the'.\n\r\nThe first subject answered yes, he knew the word. This told subject two that subject one had a letter that appeared only once throughout all five words. This means patient one's letter had to have been 'h', 'f', 'l', 'd', or 'g'. This in turn informed subject two that 'bet' could not be the word.\n\r\nThe third subject also made the same progress as subject two, figuring out that subject one's letter had to have been one that appeared only once. 'Bet' was then eliminated and subject two said yes, he knew the word. Subject three knew that if subject two knew the word, he had to have had a 'b', 'e', 'l', or 'd'. Subject three could then eliminate the word 'fit' from the list.\n\r\nPatient three could only have had either an 't' or an 'i'. If he had an 'i', the word could have been 'lid' or 'big', but since he said yes he must to have had an 't'.\n<|im_end|>" }, { "id": "#22734", "title": "5 X 5 Chess Board Puzzle", "fun": 2.29, "difficulty": 2.29, "author": "rotwyla98", "desc": "You have a 5 x 5 chess board. You must place 5 queens so that you can place three pawns on the board and they will not be taken.", "hint": "No hint available.", "answer": "In (row, column) format\n\r\nQueens:\r\n(1,3)\r\n(2,1)\r\n(1,4)\r\n(3,1)\r\n(2,4)\n\r\nPawns:\r\n(4,5)\r\n(5,5)\r\n(5,2)\n\r\nThe board can also be rotated for all of the different positions.", "category": "Logic", "date": "05/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a 5 x 5 chess board. You must place 5 queens so that you can place three pawns on the board and they will not be taken.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn (row, column) format\n\r\nQueens:\r\n(1,3)\r\n(2,1)\r\n(1,4)\r\n(3,1)\r\n(2,4)\n\r\nPawns:\r\n(4,5)\r\n(5,5)\r\n(5,2)\n\r\nThe board can also be rotated for all of the different positions.\n<|im_start|>answer\nIn (row, column) format\n\r\nQueens:\r\n(1,3)\r\n(2,1)\r\n(1,4)\r\n(3,1)\r\n(2,4)\n\r\nPawns:\r\n(4,5)\r\n(5,5)\r\n(5,2)\n\r\nThe board can also be rotated for all of the different positions.\n<|im_end|>" }, { "id": "#954", "title": "Beanie Babies", "fun": 2.29, "difficulty": 1.53, "author": "Michelle", "desc": "Jenn has half the Beanie Babies that Mollie has. Allison has 3 times as many as Jenn. Together they have 72. How many Beanie Babies does each girl have?", "hint": "No hint available.", "answer": "If Mollie has twice as many Beanie Babies as Jenn and Allison has 3 times as many as Jenn, then the total of 72 must be divided by 6. 72/6=12. Therefore: Jenn has 12 Beanie Babies, Mollie has 24 Beanie Babies, and Allison has 36 Beanie Babies.", "category": "Math", "date": "10/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJenn has half the Beanie Babies that Mollie has. Allison has 3 times as many as Jenn. Together they have 72. How many Beanie Babies does each girl have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Mollie has twice as many Beanie Babies as Jenn and Allison has 3 times as many as Jenn, then the total of 72 must be divided by 6. 72/6=12. Therefore: Jenn has 12 Beanie Babies, Mollie has 24 Beanie Babies, and Allison has 36 Beanie Babies.\n<|im_start|>answer\nIf Mollie has twice as many Beanie Babies as Jenn and Allison has 3 times as many as Jenn, then the total of 72 must be divided by 6. 72/6=12. Therefore: Jenn has 12 Beanie Babies, Mollie has 24 Beanie Babies, and Allison has 36 Beanie Babies.\n<|im_end|>" }, { "id": "#5707", "title": "Weird Numbers", "fun": 2.29, "difficulty": 2.8, "author": "Sir_Col", "desc": "12 is an abundant number, because the sum of its proper divisors: 1+2+3+4+6=16, and this is larger than the number itself. However, you will notice that 1+2+3+6=12.\n\r\nA weird number is an abundant number, n, for which no subset of its proper divisors adds to n. What is the smallest weird number?", "hint": "They are very rare indeed. The smallest is somewhere between 50 and 100.", "answer": "The smallest weird number is 70.\r\nThe next three being 836, 4030 and 5830.", "category": "Math", "date": "07/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n12 is an abundant number, because the sum of its proper divisors: 1+2+3+4+6=16, and this is larger than the number itself. However, you will notice that 1+2+3+6=12.\n\r\nA weird number is an abundant number, n, for which no subset of its proper divisors adds to n. What is the smallest weird number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe smallest weird number is 70.\r\nThe next three being 836, 4030 and 5830.\n<|im_start|>answer\nThe smallest weird number is 70.\r\nThe next three being 836, 4030 and 5830.\n<|im_end|>" }, { "id": "#5292", "title": "Botulism Express Cafe", "fun": 2.29, "difficulty": 1.81, "author": "mad-ade", "desc": "Mad Ade is having an off day, and as a result doesn't fancy a Kebab. Instead he visits the \"Botulism Express\" cafe. The \"super economy, extra lard\" menu is as follows:-\r\nEgg and chips 72p \r\nEgg and bacon 84p \r\nEgg, chips and beans 94p \r\nEgg, chips and bacon 118p \r\nEgg, chips and 2 sausages 98p \n\r\nBut Mad Ade doesn't like eggs and so orders 'Chips, beans and 2 sausages'\r\nWhat should that cost?", "hint": "No hint available.", "answer": "82p", "category": "Math", "date": "07/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is having an off day, and as a result doesn't fancy a Kebab. Instead he visits the \"Botulism Express\" cafe. The \"super economy, extra lard\" menu is as follows:-\r\nEgg and chips 72p \r\nEgg and bacon 84p \r\nEgg, chips and beans 94p \r\nEgg, chips and bacon 118p \r\nEgg, chips and 2 sausages 98p \n\r\nBut Mad Ade doesn't like eggs and so orders 'Chips, beans and 2 sausages'\r\nWhat should that cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n82p\n<|im_start|>answer\n82p\n<|im_end|>" }, { "id": "#6290", "title": "Floods In Madadia", "fun": 2.29, "difficulty": 2.44, "author": "mad-ade", "desc": "Phil Fegit was sitting in his bedroom watching the torrential rain pour down on his home town of MADADIA. The water had caused floods throughout the town and water over six feet deep had forced people to abandon the downstairs of their homes and they had to retreat to the upstairs rooms. The yearly Kebab harvest had been washed away as the downpour had continued unabated for a full month.\r\nJust at that moment Phil's wife, Norma, walked into the bedroom and he commented upon the rain. She replied that she could really care less. No matter how much Phil tried to stress the importance of the rain falling in Madadia, she refused to take it seriously.\n\r\nHow come?", "hint": "No hint available.", "answer": "Phil was watching a news report about his home town on TV, he had recently moved away from the area and it was sunny where he was.\n\r\nHis wife wasn't from Madadia, hence she didn't care what happened there.", "category": "Logic", "date": "08/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPhil Fegit was sitting in his bedroom watching the torrential rain pour down on his home town of MADADIA. The water had caused floods throughout the town and water over six feet deep had forced people to abandon the downstairs of their homes and they had to retreat to the upstairs rooms. The yearly Kebab harvest had been washed away as the downpour had continued unabated for a full month.\r\nJust at that moment Phil's wife, Norma, walked into the bedroom and he commented upon the rain. She replied that she could really care less. No matter how much Phil tried to stress the importance of the rain falling in Madadia, she refused to take it seriously.\n\r\nHow come?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPhil was watching a news report about his home town on TV, he had recently moved away from the area and it was sunny where he was.\n\r\nHis wife wasn't from Madadia, hence she didn't care what happened there.\n<|im_start|>answer\nPhil was watching a news report about his home town on TV, he had recently moved away from the area and it was sunny where he was.\n\r\nHis wife wasn't from Madadia, hence she didn't care what happened there.\n<|im_end|>" }, { "id": "#14888", "title": "Ship Shape Shelves", "fun": 2.29, "difficulty": 1.73, "author": "Worsum", "desc": "The Fernandez family is making shelves to hang on wall brackets for the three kids' bedrooms. They bought a 4 foot by 8 foot sheet of plywood to cut into shelves 24 inches long by 8 inches deep. This would make the correct number of shelves, with no wood left over. They also bought some trim to edge the shelves. They are making Ricardo 3/4 as many shelves as they are making for Anthony. Corinthia is getting four more shelves than her brother Ricardo. \r\nHow many shelves are being made for each person?", "hint": "No hint available.", "answer": "Anthony gets 8 shelves. Ricardo gets 6 shelves. Corinthia gets 10 shelves. \r\nFrom a 4 ft by 8 ft piece of plywood they could cut 24 shelves measuring 24 in. by 8 in. deep. \r\nLet A = Anthony's number of shelves. \n\r\nThen Ricardo's shelves are 3/4 times A and Corinthia's shelves are 3/4 times A plus four more. \n\r\nA + (3/4 x A) + (3/4 x A) + 4 = 24 \n\r\n2.5A + 4 = 24 [combine like terms and convert fractions] \n\r\n2.5A = 20 [subtract 4 from each side of the equation] \n\r\nA = 8 [divide each side of the equation by 2.5] \n\r\nOnce you know the value of A (Anthony's number of shelves), you can find the answer for everybody else. So, Anthony gets 8 shelves, Ricardo gets 6, and Corinthia gets 10.", "category": "Math", "date": "09/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Fernandez family is making shelves to hang on wall brackets for the three kids' bedrooms. They bought a 4 foot by 8 foot sheet of plywood to cut into shelves 24 inches long by 8 inches deep. This would make the correct number of shelves, with no wood left over. They also bought some trim to edge the shelves. They are making Ricardo 3/4 as many shelves as they are making for Anthony. Corinthia is getting four more shelves than her brother Ricardo. \r\nHow many shelves are being made for each person?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnthony gets 8 shelves. Ricardo gets 6 shelves. Corinthia gets 10 shelves. \r\nFrom a 4 ft by 8 ft piece of plywood they could cut 24 shelves measuring 24 in. by 8 in. deep. \r\nLet A = Anthony's number of shelves. \n\r\nThen Ricardo's shelves are 3/4 times A and Corinthia's shelves are 3/4 times A plus four more. \n\r\nA + (3/4 x A) + (3/4 x A) + 4 = 24 \n\r\n2.5A + 4 = 24 [combine like terms and convert fractions] \n\r\n2.5A = 20 [subtract 4 from each side of the equation] \n\r\nA = 8 [divide each side of the equation by 2.5] \n\r\nOnce you know the value of A (Anthony's number of shelves), you can find the answer for everybody else. So, Anthony gets 8 shelves, Ricardo gets 6, and Corinthia gets 10.\n<|im_start|>answer\nAnthony gets 8 shelves. Ricardo gets 6 shelves. Corinthia gets 10 shelves. \r\nFrom a 4 ft by 8 ft piece of plywood they could cut 24 shelves measuring 24 in. by 8 in. deep. \r\nLet A = Anthony's number of shelves. \n\r\nThen Ricardo's shelves are 3/4 times A and Corinthia's shelves are 3/4 times A plus four more. \n\r\nA + (3/4 x A) + (3/4 x A) + 4 = 24 \n\r\n2.5A + 4 = 24 [combine like terms and convert fractions] \n\r\n2.5A = 20 [subtract 4 from each side of the equation] \n\r\nA = 8 [divide each side of the equation by 2.5] \n\r\nOnce you know the value of A (Anthony's number of shelves), you can find the answer for everybody else. So, Anthony gets 8 shelves, Ricardo gets 6, and Corinthia gets 10.\n<|im_end|>" }, { "id": "#3599", "title": "Sunday's Tomorrow", "fun": 2.29, "difficulty": 1.3, "author": "lil_thugsta", "desc": "What day would tomorrow be if yesterday was five days before the day after Sunday's tomorrow?", "hint": "No hint available.", "answer": "Saturday", "category": "Logic", "date": "04/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat day would tomorrow be if yesterday was five days before the day after Sunday's tomorrow?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSaturday\n<|im_start|>answer\nSaturday\n<|im_end|>" }, { "id": "#4941", "title": "Twisted T-Shirt", "fun": 2.29, "difficulty": 1.54, "author": "mad-ade", "desc": "Mad Ade was extremely hung over one morning after a particularly heavy beer and Kebab marathon. He has put on his T-shirt. Unfortunately it is inside out and back to front. Normally the washing label is on the inside of the left sleeve. Where is it now?", "hint": "No hint available.", "answer": "The label is now on the outside of Mad Ade's left sleeve.", "category": "Logic", "date": "06/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was extremely hung over one morning after a particularly heavy beer and Kebab marathon. He has put on his T-shirt. Unfortunately it is inside out and back to front. Normally the washing label is on the inside of the left sleeve. Where is it now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe label is now on the outside of Mad Ade's left sleeve.\n<|im_start|>answer\nThe label is now on the outside of Mad Ade's left sleeve.\n<|im_end|>" }, { "id": "#2632", "title": "Water Locks", "fun": 2.29, "difficulty": 2.83, "author": "jeanray", "desc": "A canal in UK has 13 locks and no water supply at the top.\r\nEach lock loses 7000 L of water when used.\r\nA truck capable of carrying 22 tons of water is rented to bring water from the bottom to the top.\r\nIs the contract reasonable, and why?", "hint": "Where are the water losses?", "answer": "At first thought:\r\nWe could think that 13 x 7,000 litres = 91,000 litres that would be lost, against 22 tons.\r\n22 tons equal 22,000 Litres (1 ton of water = 1000 kg = 1000 litres = 1 m3).\r\nSo we would lose 91,000 litres to gain 22,000 litres: contract is not worth it.\n\r\nOn second thought:\r\nCertainly, each lock loses 7,000 litres, but it takes the water from the level above!\r\nHence, by succession, we only lose 7,000 litres from the top level, no matter how many locks we have!\r\nThe balance, then, is 22,000 litres - 7,000 litres = 15,000 litres: the contract is worth it!\n\r\nOn third thought (the engineering approach):\r\nUnfortunately, waterways \"lose\" water in a continuous manner: by evaporation, by \"leaks\" to the underground water table, by \"leaks\" through the locks.\r\nNow come two more factors: the length of the canal (which determines the evaporation and leaks to underground), and the TIME it takes to bring the water upstream.\r\nIf the whole of the canal loses 3,000 litres/hour and it takes the boat 5 hours to reach the top, the exercise is pointless (just maintaining the levels). Less time, and it is worth it. More time, and it is worthless.\n\r\nOn fourth thought (the economics):\r\nIf the engineering balance is \"close to equilibrium\", economics may make the exercise worthwhile, by careful planning of the traffic on the canal, i.e. making every lock crossing with TWO boats: one up, one down.", "category": "Logic", "date": "03/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA canal in UK has 13 locks and no water supply at the top.\r\nEach lock loses 7000 L of water when used.\r\nA truck capable of carrying 22 tons of water is rented to bring water from the bottom to the top.\r\nIs the contract reasonable, and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt first thought:\r\nWe could think that 13 x 7,000 litres = 91,000 litres that would be lost, against 22 tons.\r\n22 tons equal 22,000 Litres (1 ton of water = 1000 kg = 1000 litres = 1 m3).\r\nSo we would lose 91,000 litres to gain 22,000 litres: contract is not worth it.\n\r\nOn second thought:\r\nCertainly, each lock loses 7,000 litres, but it takes the water from the level above!\r\nHence, by succession, we only lose 7,000 litres from the top level, no matter how many locks we have!\r\nThe balance, then, is 22,000 litres - 7,000 litres = 15,000 litres: the contract is worth it!\n\r\nOn third thought (the engineering approach):\r\nUnfortunately, waterways \"lose\" water in a continuous manner: by evaporation, by \"leaks\" to the underground water table, by \"leaks\" through the locks.\r\nNow come two more factors: the length of the canal (which determines the evaporation and leaks to underground), and the TIME it takes to bring the water upstream.\r\nIf the whole of the canal loses 3,000 litres/hour and it takes the boat 5 hours to reach the top, the exercise is pointless (just maintaining the levels). Less time, and it is worth it. More time, and it is worthless.\n\r\nOn fourth thought (the economics):\r\nIf the engineering balance is \"close to equilibrium\", economics may make the exercise worthwhile, by careful planning of the traffic on the canal, i.e. making every lock crossing with TWO boats: one up, one down.\n<|im_start|>answer\nAt first thought:\r\nWe could think that 13 x 7,000 litres = 91,000 litres that would be lost, against 22 tons.\r\n22 tons equal 22,000 Litres (1 ton of water = 1000 kg = 1000 litres = 1 m3).\r\nSo we would lose 91,000 litres to gain 22,000 litres: contract is not worth it.\n\r\nOn second thought:\r\nCertainly, each lock loses 7,000 litres, but it takes the water from the level above!\r\nHence, by succession, we only lose 7,000 litres from the top level, no matter how many locks we have!\r\nThe balance, then, is 22,000 litres - 7,000 litres = 15,000 litres: the contract is worth it!\n\r\nOn third thought (the engineering approach):\r\nUnfortunately, waterways \"lose\" water in a continuous manner: by evaporation, by \"leaks\" to the underground water table, by \"leaks\" through the locks.\r\nNow come two more factors: the length of the canal (which determines the evaporation and leaks to underground), and the TIME it takes to bring the water upstream.\r\nIf the whole of the canal loses 3,000 litres/hour and it takes the boat 5 hours to reach the top, the exercise is pointless (just maintaining the levels). Less time, and it is worth it. More time, and it is worthless.\n\r\nOn fourth thought (the economics):\r\nIf the engineering balance is \"close to equilibrium\", economics may make the exercise worthwhile, by careful planning of the traffic on the canal, i.e. making every lock crossing with TWO boats: one up, one down.\n<|im_end|>" }, { "id": "#15655", "title": "We Love Pennies", "fun": 2.29, "difficulty": 0.79, "author": "deskjet2187", "desc": "If you could have a penny a day for 30 days, doubled every day, or $10,000 right now, which would give you more money?", "hint": "No hint available.", "answer": "The pennies, because at the end of one month, you would already have a little over $1,000,000.", "category": "Math", "date": "12/04/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you could have a penny a day for 30 days, doubled every day, or $10,000 right now, which would give you more money?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pennies, because at the end of one month, you would already have a little over $1,000,000.\n<|im_start|>answer\nThe pennies, because at the end of one month, you would already have a little over $1,000,000.\n<|im_end|>" }, { "id": "#30969", "title": "Paper On, Dude!", "fun": 2.29, "difficulty": 2.89, "author": "norcekri", "desc": "The All-Portland Rock-Scissors-Paper League follows the canonical rules: at a given signal, both contestants reveal their choices. Rock beats scissors, scissors beats paper, and paper beats rock. However, for tournament play, the stakes are altered. Losers pay winners 3 chips if the latter wins with \"rock\", 2 points with \"scissors\", and 1 point with \"paper\". Each minute, everyone must find a new opponent, play one \"throw\", pay off, and get ready for the next switch.\r\n\tThe players with the most chips at the end of the evening get the big prizes: first place is a bag of Portland cement, second is a hedge trimmer, and third place is a choice of stationery. Also, any chips you've won are redeemable for drinks at the bar.\n\r\n\tKnowing nothing about the other players' preference, mind games, etc., what's your best strategy (mixture of rock, paper, and scissors) for maintaining your balance of chips throughout the evening?", "hint": "(1) The answer is not 1:1:1; this loses to people who throw nothing but rocks.\r\n\t(2) This is a \"zero-sum\" game: what one player wins, the other loses.\r\n\t(3) The game is \"symmetric\": everyone is playing with the same information, the same options, and the same risks.\r\n\t(4) The game is \"open\": there is no hidden information, such as secret agreements or rules that only one player knows.", "answer": "Randomly throw paper 1/2 the time, rock 1/3 of the time, and scissors the remaining 1/6.\n\r\nMethod:\r\n\tTo avoid dredging through matrix math, I'll present a couple of basic principles of game theory.\r\n\t(1) Playing the best strategy possible allows you to expose your overall strategy to your opponent without affecting your expected payoff. No matter what your opponent does in response, you'll still expect at least a given amount in the long run.\r\n\t(2) Since the game is symmetric and open, every player will have the same best strategy -- and the same expected payoff if they use it.\r\n\t(3) Since the game is zero-sum, that expected payoff must be zero.\r\n\t(4) Given the payoff structure, the best grand (overall) strategy will involve all three choices.\n\r\n\tWith these principles, we can now look for a strategy that gives an expected payoff of zero, regardless of what the opponent does. Granted, if we *knew* the opponent was playing some other strategy, we could change to get an advantage -- but getting the best stable payoff includes the assumption that the opponent will take advantage of any exposed weakness.\n\r\n\tSo, we're looking to mix our \"throws\" in some useful proportion that will give us a stable, zero payoff. First, let's compare against someone throwing nothing but rocks. If we throw rock, it's a tie (no payoff). If we throw scissors, we lose 3. If we throw paper, we win 1. This yields the equation\r\nE = 0*R -3*S +1*P\r\nwhere\r\nE = expected payoff\r\nR = proportion of rocks\r\nS = proportion of scissors\r\nP = proportion of paper\r\nAgainst an all-paper opponent:\r\nE = -1*R + 2*S -0*P\r\nAgainst someone running with scissors all the time:\r\nE = 3*R + 0*S -1*P\r\nWe know that E=0; we can now solve the three equations in three variables. We get a stable proportion, rather than a fixed answer. P = 3*S; R = 2*S. Normalizing to a total probability of 1, we get\r\nS = 1/6, R = 1/3, P = 1/2.\r\nQ.E.D.\n\r\nI realize that it's a bit counterintuitive that the choice with the best potential gain (rock) is not the largest proportion of the optimal mix. Rather, note that what *beats* rock gets the highest share, and what beats scissors gets the next highest.", "category": "Math", "date": "06/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe All-Portland Rock-Scissors-Paper League follows the canonical rules: at a given signal, both contestants reveal their choices. Rock beats scissors, scissors beats paper, and paper beats rock. However, for tournament play, the stakes are altered. Losers pay winners 3 chips if the latter wins with \"rock\", 2 points with \"scissors\", and 1 point with \"paper\". Each minute, everyone must find a new opponent, play one \"throw\", pay off, and get ready for the next switch.\r\n\tThe players with the most chips at the end of the evening get the big prizes: first place is a bag of Portland cement, second is a hedge trimmer, and third place is a choice of stationery. Also, any chips you've won are redeemable for drinks at the bar.\n\r\n\tKnowing nothing about the other players' preference, mind games, etc., what's your best strategy (mixture of rock, paper, and scissors) for maintaining your balance of chips throughout the evening?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRandomly throw paper 1/2 the time, rock 1/3 of the time, and scissors the remaining 1/6.\n\r\nMethod:\r\n\tTo avoid dredging through matrix math, I'll present a couple of basic principles of game theory.\r\n\t(1) Playing the best strategy possible allows you to expose your overall strategy to your opponent without affecting your expected payoff. No matter what your opponent does in response, you'll still expect at least a given amount in the long run.\r\n\t(2) Since the game is symmetric and open, every player will have the same best strategy -- and the same expected payoff if they use it.\r\n\t(3) Since the game is zero-sum, that expected payoff must be zero.\r\n\t(4) Given the payoff structure, the best grand (overall) strategy will involve all three choices.\n\r\n\tWith these principles, we can now look for a strategy that gives an expected payoff of zero, regardless of what the opponent does. Granted, if we *knew* the opponent was playing some other strategy, we could change to get an advantage -- but getting the best stable payoff includes the assumption that the opponent will take advantage of any exposed weakness.\n\r\n\tSo, we're looking to mix our \"throws\" in some useful proportion that will give us a stable, zero payoff. First, let's compare against someone throwing nothing but rocks. If we throw rock, it's a tie (no payoff). If we throw scissors, we lose 3. If we throw paper, we win 1. This yields the equation\r\nE = 0*R -3*S +1*P\r\nwhere\r\nE = expected payoff\r\nR = proportion of rocks\r\nS = proportion of scissors\r\nP = proportion of paper\r\nAgainst an all-paper opponent:\r\nE = -1*R + 2*S -0*P\r\nAgainst someone running with scissors all the time:\r\nE = 3*R + 0*S -1*P\r\nWe know that E=0; we can now solve the three equations in three variables. We get a stable proportion, rather than a fixed answer. P = 3*S; R = 2*S. Normalizing to a total probability of 1, we get\r\nS = 1/6, R = 1/3, P = 1/2.\r\nQ.E.D.\n\r\nI realize that it's a bit counterintuitive that the choice with the best potential gain (rock) is not the largest proportion of the optimal mix. Rather, note that what *beats* rock gets the highest share, and what beats scissors gets the next highest.\n<|im_start|>answer\nRandomly throw paper 1/2 the time, rock 1/3 of the time, and scissors the remaining 1/6.\n\r\nMethod:\r\n\tTo avoid dredging through matrix math, I'll present a couple of basic principles of game theory.\r\n\t(1) Playing the best strategy possible allows you to expose your overall strategy to your opponent without affecting your expected payoff. No matter what your opponent does in response, you'll still expect at least a given amount in the long run.\r\n\t(2) Since the game is symmetric and open, every player will have the same best strategy -- and the same expected payoff if they use it.\r\n\t(3) Since the game is zero-sum, that expected payoff must be zero.\r\n\t(4) Given the payoff structure, the best grand (overall) strategy will involve all three choices.\n\r\n\tWith these principles, we can now look for a strategy that gives an expected payoff of zero, regardless of what the opponent does. Granted, if we *knew* the opponent was playing some other strategy, we could change to get an advantage -- but getting the best stable payoff includes the assumption that the opponent will take advantage of any exposed weakness.\n\r\n\tSo, we're looking to mix our \"throws\" in some useful proportion that will give us a stable, zero payoff. First, let's compare against someone throwing nothing but rocks. If we throw rock, it's a tie (no payoff). If we throw scissors, we lose 3. If we throw paper, we win 1. This yields the equation\r\nE = 0*R -3*S +1*P\r\nwhere\r\nE = expected payoff\r\nR = proportion of rocks\r\nS = proportion of scissors\r\nP = proportion of paper\r\nAgainst an all-paper opponent:\r\nE = -1*R + 2*S -0*P\r\nAgainst someone running with scissors all the time:\r\nE = 3*R + 0*S -1*P\r\nWe know that E=0; we can now solve the three equations in three variables. We get a stable proportion, rather than a fixed answer. P = 3*S; R = 2*S. Normalizing to a total probability of 1, we get\r\nS = 1/6, R = 1/3, P = 1/2.\r\nQ.E.D.\n\r\nI realize that it's a bit counterintuitive that the choice with the best potential gain (rock) is not the largest proportion of the optimal mix. Rather, note that what *beats* rock gets the highest share, and what beats scissors gets the next highest.\n<|im_end|>" }, { "id": "#4083", "title": "Crazy Math", "fun": 2.29, "difficulty": 2.4, "author": "bluetwo", "desc": "prove the following:\n\r\n3.99999... = 4\n\r\n(by using '...' i mean that the 9's are repeating)", "hint": "No hint available.", "answer": "3.9999... = X\r\n3.9999... * 10 = 39.9999.... = 10X\r\n10X - 3.9999... = 9X\r\n39.9999... - 3.9999... = 36 = 9X\r\n36 / 9 = 9X / 9 = 4\r\ntherefore, X = 4", "category": "Math", "date": "05/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nprove the following:\n\r\n3.99999... = 4\n\r\n(by using '...' i mean that the 9's are repeating)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3.9999... = X\r\n3.9999... * 10 = 39.9999.... = 10X\r\n10X - 3.9999... = 9X\r\n39.9999... - 3.9999... = 36 = 9X\r\n36 / 9 = 9X / 9 = 4\r\ntherefore, X = 4\n<|im_start|>answer\n3.9999... = X\r\n3.9999... * 10 = 39.9999.... = 10X\r\n10X - 3.9999... = 9X\r\n39.9999... - 3.9999... = 36 = 9X\r\n36 / 9 = 9X / 9 = 4\r\ntherefore, X = 4\n<|im_end|>" }, { "id": "#28837", "title": "Small Chess Board", "fun": 2.29, "difficulty": 1.81, "author": "Draw", "desc": "Imagine a small chess board, with dimensions of 3 by 3. If you place a knight on the top left hand corner, how many different squares can the knight reach in less than four moves?", "hint": "No hint available.", "answer": "7 squares.\n\r\nAll but the centre and the bottom right squares.", "category": "Logic", "date": "02/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImagine a small chess board, with dimensions of 3 by 3. If you place a knight on the top left hand corner, how many different squares can the knight reach in less than four moves?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 squares.\n\r\nAll but the centre and the bottom right squares.\n<|im_start|>answer\n7 squares.\n\r\nAll but the centre and the bottom right squares.\n<|im_end|>" }, { "id": "#48779", "title": "Mixed Up Masqueraders", "fun": 2.29, "difficulty": 3.0, "author": "Mom2Ozzy", "desc": "Abbey is hosting a masquerade party for her birthday, which falls on Halloween. Half way through the night, Abbey and her three best friends decided to play a trick on their boyfriends by switching costumes! Talk about taking masquerading to a whole new level!\n\r\nCan you figure out who switched with whom?\n\r\n(Posed/... = Posed as...)\r\nMatch each girl with her original costume.\n\r\n1. George's girlfriend couldn't fit into the costume of the girl who pretended to be Beth.\n\r\n2. Harold's girlfriend, who switched into Cristy's costume, didn't originally go as a belly dancer.\n\r\n3.Beth didn't pretend to be the girl who pretended to be Donna.\n\r\n4. The girls who \"masqueraded\" as Beth and Donna are Freddy's girlfriend and the girl that the friend who originally went to the party as a ghost pretended to be.\n\r\n5. The girl who went to the party as a super hero changed into the kitty costume.\n\r\n6. The girl that Freddy's girlfriend posed as didn't arrive at the party as a kitty.\n\r\n7. Abbey's boyfriend is Eugene.", "hint": "No hint available.", "answer": "Abbey's original costume was a belly dancer to match Eugene's sheik costume, she posed as Donna.\n\r\nBeth's original costume was a superhero to match Harold's super villain costume, she posed as Cristy. \n\r\nCristy's original costume was a kitty to match Freddy's puppy costume, she posed as Beth.\n\r\nDonna's original costume was a ghost to match George's zombie costume, she posed as Abbey.", "category": "Logic-Grid", "date": "06/16/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAbbey is hosting a masquerade party for her birthday, which falls on Halloween. Half way through the night, Abbey and her three best friends decided to play a trick on their boyfriends by switching costumes! Talk about taking masquerading to a whole new level!\n\r\nCan you figure out who switched with whom?\n\r\n(Posed/... = Posed as...)\r\nMatch each girl with her original costume.\n\r\n1. George's girlfriend couldn't fit into the costume of the girl who pretended to be Beth.\n\r\n2. Harold's girlfriend, who switched into Cristy's costume, didn't originally go as a belly dancer.\n\r\n3.Beth didn't pretend to be the girl who pretended to be Donna.\n\r\n4. The girls who \"masqueraded\" as Beth and Donna are Freddy's girlfriend and the girl that the friend who originally went to the party as a ghost pretended to be.\n\r\n5. The girl who went to the party as a super hero changed into the kitty costume.\n\r\n6. The girl that Freddy's girlfriend posed as didn't arrive at the party as a kitty.\n\r\n7. Abbey's boyfriend is Eugene.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbbey's original costume was a belly dancer to match Eugene's sheik costume, she posed as Donna.\n\r\nBeth's original costume was a superhero to match Harold's super villain costume, she posed as Cristy. \n\r\nCristy's original costume was a kitty to match Freddy's puppy costume, she posed as Beth.\n\r\nDonna's original costume was a ghost to match George's zombie costume, she posed as Abbey.\n<|im_start|>answer\nAbbey's original costume was a belly dancer to match Eugene's sheik costume, she posed as Donna.\n\r\nBeth's original costume was a superhero to match Harold's super villain costume, she posed as Cristy. \n\r\nCristy's original costume was a kitty to match Freddy's puppy costume, she posed as Beth.\n\r\nDonna's original costume was a ghost to match George's zombie costume, she posed as Abbey.\n<|im_end|>" }, { "id": "#3392", "title": "Jewelry Robbery", "fun": 2.29, "difficulty": 1.43, "author": "204_BLaZe_41", "desc": "James received a near hysterical call from Tokar. 'Some thief pried my safe open and made off with all my wife's jewellery! Come over straight away, please!' When James arrived Tokar recounted his story. 'My wife's in the hospital so I've had to fend for myself. I was in the kitchen fixing dinner when I heard a loud noise in the basement. I rushed to the hall to see this woman race past me and out the front door. I suddenly realized she was carrying my wife's jewellery case. I ran down the street after her, but she was a very fast runner and after several blocks she lost me. I walked to a nearby phone and called you immediately.' James looked down at the damaged safe and remarked, 'You better not try that pathetic story on the insurance company or they'll charge you with fraud.' What's wrong with Tokar's story?", "hint": "No hint available.", "answer": "Tokar said he chased the thief, and when he lost her, he gave up and called from a nearby phone. At that point Tokar had not yet been down in the basement, so he could not have known the thief had pried the safe open.", "category": "Logic", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJames received a near hysterical call from Tokar. 'Some thief pried my safe open and made off with all my wife's jewellery! Come over straight away, please!' When James arrived Tokar recounted his story. 'My wife's in the hospital so I've had to fend for myself. I was in the kitchen fixing dinner when I heard a loud noise in the basement. I rushed to the hall to see this woman race past me and out the front door. I suddenly realized she was carrying my wife's jewellery case. I ran down the street after her, but she was a very fast runner and after several blocks she lost me. I walked to a nearby phone and called you immediately.' James looked down at the damaged safe and remarked, 'You better not try that pathetic story on the insurance company or they'll charge you with fraud.' What's wrong with Tokar's story?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTokar said he chased the thief, and when he lost her, he gave up and called from a nearby phone. At that point Tokar had not yet been down in the basement, so he could not have known the thief had pried the safe open.\n<|im_start|>answer\nTokar said he chased the thief, and when he lost her, he gave up and called from a nearby phone. At that point Tokar had not yet been down in the basement, so he could not have known the thief had pried the safe open.\n<|im_end|>" }, { "id": "#14155", "title": "Letter Logic", "fun": 2.29, "difficulty": 2.25, "author": "cool_star", "desc": "In the following puzzle every letter stands for a number, different letters have different numbers and same letters have the same numbers. To give you a head start the number five is already shown.\n\r\nEND\r\n+ 5G\r\n--------\r\nGAME\n\r\nWhat numbers do the letters stand for?", "hint": "No hint available.", "answer": "978\r\n+ 51\r\n------\r\n1029", "category": "Math", "date": "08/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the following puzzle every letter stands for a number, different letters have different numbers and same letters have the same numbers. To give you a head start the number five is already shown.\n\r\nEND\r\n+ 5G\r\n--------\r\nGAME\n\r\nWhat numbers do the letters stand for?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n978\r\n+ 51\r\n------\r\n1029\n<|im_start|>answer\n978\r\n+ 51\r\n------\r\n1029\n<|im_end|>" }, { "id": "#7054", "title": "The Least Letters", "fun": 2.29, "difficulty": 2.04, "author": "Mogmatt16", "desc": "What number with 3 or more digits can be spelled with the least letters? The digits can be on either side of the decimal.", "hint": "May I have a large container of orange juice?", "answer": "Pi.\n\r\n(In case you can't get the hint, each word has as many letters as the corresponding digits of Pi.)", "category": "Math", "date": "08/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number with 3 or more digits can be spelled with the least letters? The digits can be on either side of the decimal.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPi.\n\r\n(In case you can't get the hint, each word has as many letters as the corresponding digits of Pi.)\n<|im_start|>answer\nPi.\n\r\n(In case you can't get the hint, each word has as many letters as the corresponding digits of Pi.)\n<|im_end|>" }, { "id": "#8327", "title": "Plates at a Party", "fun": 2.29, "difficulty": 0.98, "author": "angelsweetie", "desc": "Tianna is planning her party. She bought a package of 2 dozen paper plates. This will give her 2 extras, and she'll still have enough for each person to have 2 plates: one plate for their hot dogs and chips, another for ice cream and cake. \n\r\nBesides her brother and sister, how many friends will she have at her party?", "hint": "No hint available.", "answer": "Tianna will have 8 friends at her party. \n\r\nA package of 2 dozen plates is 24. Since Tianna will have 2 extra plates, she will be using 22 plates. If each person uses 2 plates, that means there will be 11 people at the party. After subtracting herself, her brother, and her sister, Tianna will have 8 friends at her party.", "category": "Math", "date": "11/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTianna is planning her party. She bought a package of 2 dozen paper plates. This will give her 2 extras, and she'll still have enough for each person to have 2 plates: one plate for their hot dogs and chips, another for ice cream and cake. \n\r\nBesides her brother and sister, how many friends will she have at her party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTianna will have 8 friends at her party. \n\r\nA package of 2 dozen plates is 24. Since Tianna will have 2 extra plates, she will be using 22 plates. If each person uses 2 plates, that means there will be 11 people at the party. After subtracting herself, her brother, and her sister, Tianna will have 8 friends at her party.\n<|im_start|>answer\nTianna will have 8 friends at her party. \n\r\nA package of 2 dozen plates is 24. Since Tianna will have 2 extra plates, she will be using 22 plates. If each person uses 2 plates, that means there will be 11 people at the party. After subtracting herself, her brother, and her sister, Tianna will have 8 friends at her party.\n<|im_end|>" }, { "id": "#847", "title": "Candles", "fun": 2.29, "difficulty": 1.18, "author": "Michelle", "desc": "The stubs obtained by burning ten candles will yield one extra candle if you melt them all together. If you burned 100 candles, how many extra candles could you make?", "hint": "No hint available.", "answer": "11. The 10 extra from the 100 candles, and then one more from burning the extra 10.", "category": "Logic", "date": "09/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe stubs obtained by burning ten candles will yield one extra candle if you melt them all together. If you burned 100 candles, how many extra candles could you make?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11. The 10 extra from the 100 candles, and then one more from burning the extra 10.\n<|im_start|>answer\n11. The 10 extra from the 100 candles, and then one more from burning the extra 10.\n<|im_end|>" }, { "id": "#22495", "title": "Easy Confusion", "fun": 2.29, "difficulty": 1.86, "author": "super_duper08", "desc": "Replace each ? with the number 1, 2, 3, 4, or 5 to make the equation true. Each number is used only once, and a different number is used for each ?\n\r\n( ? + ? - ? X ?) / ? = 1\n\r\n/ means divide.\r\nX means multiply.\r\nThere are many different possible answers.", "hint": "Remember the order of operations or PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction).", "answer": "Possible answers:\n\r\n(3+4 - 1X2)/5=1\r\n(2+5 - 1X3)/4=1\r\n(2+5 - 1X4)/3=1\r\n(3+4 - 1X5)/2=1\n\r\nNote: The numbers that you add together can be reversed and/or the numbers that you multiply can be reversed.", "category": "Math", "date": "04/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nReplace each ? with the number 1, 2, 3, 4, or 5 to make the equation true. Each number is used only once, and a different number is used for each ?\n\r\n( ? + ? - ? X ?) / ? = 1\n\r\n/ means divide.\r\nX means multiply.\r\nThere are many different possible answers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPossible answers:\n\r\n(3+4 - 1X2)/5=1\r\n(2+5 - 1X3)/4=1\r\n(2+5 - 1X4)/3=1\r\n(3+4 - 1X5)/2=1\n\r\nNote: The numbers that you add together can be reversed and/or the numbers that you multiply can be reversed.\n<|im_start|>answer\nPossible answers:\n\r\n(3+4 - 1X2)/5=1\r\n(2+5 - 1X3)/4=1\r\n(2+5 - 1X4)/3=1\r\n(3+4 - 1X5)/2=1\n\r\nNote: The numbers that you add together can be reversed and/or the numbers that you multiply can be reversed.\n<|im_end|>" }, { "id": "#5630", "title": "Sevenlegs O'Lucky", "fun": 2.29, "difficulty": 2.28, "author": "mad-ade", "desc": "A room is 3 metres high by 4 metres wide by 5 metres long. In the middle of one of the end (smaller) walls is Mad Ade's pet spider, called SevenLegs O'Lucky. In the topmost corner of the opposite end wall he has spotted a female spider, in a blonde wig and eight bright blue contact lenses. SevenLegs O'Lucky wishes to get better acquainted with the female.\n\r\nWhat is the length of the shortest distance SevenLegs O'Lucky must scuttle to do that?", "hint": "No hint available.", "answer": "Sqrt(46.25) or 6.8 metres", "category": "Math", "date": "07/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA room is 3 metres high by 4 metres wide by 5 metres long. In the middle of one of the end (smaller) walls is Mad Ade's pet spider, called SevenLegs O'Lucky. In the topmost corner of the opposite end wall he has spotted a female spider, in a blonde wig and eight bright blue contact lenses. SevenLegs O'Lucky wishes to get better acquainted with the female.\n\r\nWhat is the length of the shortest distance SevenLegs O'Lucky must scuttle to do that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSqrt(46.25) or 6.8 metres\n<|im_start|>answer\nSqrt(46.25) or 6.8 metres\n<|im_end|>" }, { "id": "#4402", "title": "Family Grave", "fun": 2.29, "difficulty": 2.21, "author": "mad-ade", "desc": "Mad Ade was walking through a churchyard one day, and came across a gravestone with the following inscription.\n\r\nHere lies\r\nTwo grandmothers, with their two granddaughters;\r\nTwo husbands, with their two wives;\r\nTwo fathers, with their two daughters;\r\nTwo mothers, with their two sons;\r\nTwo maidens, with their two mothers;\r\nTwo sisters, with their two brothers.\n\r\nYet Mad Ade noted that there was only six names on the gravestone. How could this be possible?", "hint": "No hint available.", "answer": "If two widows had each a son, and each widow married the son of the other and had a daughter by the marriage, all the relationships will be found to result.", "category": "Logic", "date": "06/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was walking through a churchyard one day, and came across a gravestone with the following inscription.\n\r\nHere lies\r\nTwo grandmothers, with their two granddaughters;\r\nTwo husbands, with their two wives;\r\nTwo fathers, with their two daughters;\r\nTwo mothers, with their two sons;\r\nTwo maidens, with their two mothers;\r\nTwo sisters, with their two brothers.\n\r\nYet Mad Ade noted that there was only six names on the gravestone. How could this be possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf two widows had each a son, and each widow married the son of the other and had a daughter by the marriage, all the relationships will be found to result.\n<|im_start|>answer\nIf two widows had each a son, and each widow married the son of the other and had a daughter by the marriage, all the relationships will be found to result.\n<|im_end|>" }, { "id": "#3374", "title": "Knowing People at a Party", "fun": 2.29, "difficulty": 2.72, "author": "neo1", "desc": "Prove that at any party, there are two people who know the same number of people. Assume that if A knows B , then B knows A . Assume also that everyone knows himself or herself.", "hint": "Use indirect reasoning.", "answer": "Lets suppose that at a party, there are no two people who know the same number of people. Now lets say there are \"n\" people at the party. Now the nth person will know (n-1) people; (n-1)th person will know (n-2) people because no one knows the same number of people; similarly (n-2)th person will known (n-3) people. Thus, the 2nd person will know 1 person. Hence the 1st person[say A] will know 0 people or will know no one. Now since the nth person knows every one, he knows A .Therefore A knows the nth person. Hence our supposition is wrong and at least 2 people know the same number of people.", "category": "Math", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nProve that at any party, there are two people who know the same number of people. Assume that if A knows B , then B knows A . Assume also that everyone knows himself or herself.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLets suppose that at a party, there are no two people who know the same number of people. Now lets say there are \"n\" people at the party. Now the nth person will know (n-1) people; (n-1)th person will know (n-2) people because no one knows the same number of people; similarly (n-2)th person will known (n-3) people. Thus, the 2nd person will know 1 person. Hence the 1st person[say A] will know 0 people or will know no one. Now since the nth person knows every one, he knows A .Therefore A knows the nth person. Hence our supposition is wrong and at least 2 people know the same number of people.\n<|im_start|>answer\nLets suppose that at a party, there are no two people who know the same number of people. Now lets say there are \"n\" people at the party. Now the nth person will know (n-1) people; (n-1)th person will know (n-2) people because no one knows the same number of people; similarly (n-2)th person will known (n-3) people. Thus, the 2nd person will know 1 person. Hence the 1st person[say A] will know 0 people or will know no one. Now since the nth person knows every one, he knows A .Therefore A knows the nth person. Hence our supposition is wrong and at least 2 people know the same number of people.\n<|im_end|>" }, { "id": "#4630", "title": "Swimmer", "fun": 2.29, "difficulty": 1.87, "author": "mad-ade", "desc": "If, with the help of the current, a boy can swim from his boat to a jetty in 10 minutes (which is just half the time it would take him to swim that distance in still water) how long will it take him to swim back from the jetty to his boat, against the current ?", "hint": "No hint available.", "answer": "He will never make it. Since, in effect, the favourable current doubles the natural speed of boy, its rate must be the same as that at which he normally swims. Therefore, when swimming against it he will make no headway whatsoever.", "category": "Logic", "date": "06/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf, with the help of the current, a boy can swim from his boat to a jetty in 10 minutes (which is just half the time it would take him to swim that distance in still water) how long will it take him to swim back from the jetty to his boat, against the current ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe will never make it. Since, in effect, the favourable current doubles the natural speed of boy, its rate must be the same as that at which he normally swims. Therefore, when swimming against it he will make no headway whatsoever.\n<|im_start|>answer\nHe will never make it. Since, in effect, the favourable current doubles the natural speed of boy, its rate must be the same as that at which he normally swims. Therefore, when swimming against it he will make no headway whatsoever.\n<|im_end|>" }, { "id": "#21459", "title": "No Profit Today", "fun": 2.28, "difficulty": 1.35, "author": "od-1", "desc": "Mr.Od-1 owned a chain of toy stores. One day he received a shipment of new toy cars. The inventory manager marked them all up 10% and sent them out to all the stores. But after a few weeks, sales of the cars were minimal and Mr. Od-1 instructed that they be sold at cost to get rid of them. The next day Mr.Od-1 saw that the cars were all on sale at 10% off. He was quite upset at his inventory manager. \r\n\"What's the problem sir?\" asked the manager. \"I put them up 10% and then marked it down 10% to sell them at cost.\"\r\nThe manager was quickly demoted to a new position as janitor. But why?", "hint": "Do the math.", "answer": "He had lousy math skills.\r\nLet's say the cars cost $10.00 + 10% ($1)= $11.00\r\nBut $11.00 - 10% ($1.10) = $9.90 so he would lose 10 cents on every car.", "category": "Math", "date": "03/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr.Od-1 owned a chain of toy stores. One day he received a shipment of new toy cars. The inventory manager marked them all up 10% and sent them out to all the stores. But after a few weeks, sales of the cars were minimal and Mr. Od-1 instructed that they be sold at cost to get rid of them. The next day Mr.Od-1 saw that the cars were all on sale at 10% off. He was quite upset at his inventory manager. \r\n\"What's the problem sir?\" asked the manager. \"I put them up 10% and then marked it down 10% to sell them at cost.\"\r\nThe manager was quickly demoted to a new position as janitor. But why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe had lousy math skills.\r\nLet's say the cars cost $10.00 + 10% ($1)= $11.00\r\nBut $11.00 - 10% ($1.10) = $9.90 so he would lose 10 cents on every car.\n<|im_start|>answer\nHe had lousy math skills.\r\nLet's say the cars cost $10.00 + 10% ($1)= $11.00\r\nBut $11.00 - 10% ($1.10) = $9.90 so he would lose 10 cents on every car.\n<|im_end|>" }, { "id": "#38319", "title": "You've Piqued My Interest...", "fun": 2.28, "difficulty": 2.24, "author": "Hrsemn4", "desc": "Steve has a bank account that yields 10 percent monthly interest. The trick is that the interest only applies to an amount up to and including $25,000. One of his accounts already has $25,000 in it, Steve decides to deposit the amount of the monthly interest into a new account and let it continue to grow. Assume that the interest on his first account is tabulated before the second and that he has time to remove the excess money and deposit it before the interest is calculated on the subsequent account. Also, round all amounts up to the next penny. \n\r\nHow many months will it take Steve to reach $25,000 (or more) in the second account?", "hint": "No hint available.", "answer": "7 Months\n\r\nEach month Steve transfers the amount of accrued interest ($2,500) from his first account into his second. Interest is then calculated on the second account and that amount is added to the account balance. The monthly breakdown is as follows:\r\nMonth 1: \r\nStarting balance: $0 \r\n+ $2,500\r\nx 10% = $250\r\nEnding balance: $2,750\n\r\nMonth 2: \r\nStarting balance:$2750\r\n+ $2,500 = $5,250\r\nx 10% = $525\r\nEnding balance: $5,775\n\r\nMonth 3: \r\nStarting balance: $5,775\r\n+ $2,500 = $8,275\r\nx 10% = $827.50\r\nEnding balance: $9,102.50\n\r\nMonth 4:\r\nStarting balance: $9,102.50\r\n+ $2,500 = $11,602.50\r\nx 10% = $1,160.25\r\nEnding balance: $12,762.75\n\r\nMonth 5: \r\nStarting balance: $12,762.75\r\n+ $2,500 = $15,262.75\r\nx 10% = $1,526.28\r\nEnding balance: $16,789.03\n\r\nMonth 6: \r\nStarting balance: $16,789.03\r\n+ $2,500 = $19,289.03\r\nx 10% = $1,928.91\r\nEnding balance: $21,217.94\n\r\nMonth 7: \r\nStarting balance: $21,217.94\r\n+ $2,500 = $23,717.94\r\nx 10% = $2,371.80\r\nEnding balance: $26,089.74\n\r\nIt only took him 7 months to double his money! Don't you wish this were your bank account?", "category": "Math", "date": "09/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSteve has a bank account that yields 10 percent monthly interest. The trick is that the interest only applies to an amount up to and including $25,000. One of his accounts already has $25,000 in it, Steve decides to deposit the amount of the monthly interest into a new account and let it continue to grow. Assume that the interest on his first account is tabulated before the second and that he has time to remove the excess money and deposit it before the interest is calculated on the subsequent account. Also, round all amounts up to the next penny. \n\r\nHow many months will it take Steve to reach $25,000 (or more) in the second account?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 Months\n\r\nEach month Steve transfers the amount of accrued interest ($2,500) from his first account into his second. Interest is then calculated on the second account and that amount is added to the account balance. The monthly breakdown is as follows:\r\nMonth 1: \r\nStarting balance: $0 \r\n+ $2,500\r\nx 10% = $250\r\nEnding balance: $2,750\n\r\nMonth 2: \r\nStarting balance:$2750\r\n+ $2,500 = $5,250\r\nx 10% = $525\r\nEnding balance: $5,775\n\r\nMonth 3: \r\nStarting balance: $5,775\r\n+ $2,500 = $8,275\r\nx 10% = $827.50\r\nEnding balance: $9,102.50\n\r\nMonth 4:\r\nStarting balance: $9,102.50\r\n+ $2,500 = $11,602.50\r\nx 10% = $1,160.25\r\nEnding balance: $12,762.75\n\r\nMonth 5: \r\nStarting balance: $12,762.75\r\n+ $2,500 = $15,262.75\r\nx 10% = $1,526.28\r\nEnding balance: $16,789.03\n\r\nMonth 6: \r\nStarting balance: $16,789.03\r\n+ $2,500 = $19,289.03\r\nx 10% = $1,928.91\r\nEnding balance: $21,217.94\n\r\nMonth 7: \r\nStarting balance: $21,217.94\r\n+ $2,500 = $23,717.94\r\nx 10% = $2,371.80\r\nEnding balance: $26,089.74\n\r\nIt only took him 7 months to double his money! Don't you wish this were your bank account?\n<|im_start|>answer\n7 Months\n\r\nEach month Steve transfers the amount of accrued interest ($2,500) from his first account into his second. Interest is then calculated on the second account and that amount is added to the account balance. The monthly breakdown is as follows:\r\nMonth 1: \r\nStarting balance: $0 \r\n+ $2,500\r\nx 10% = $250\r\nEnding balance: $2,750\n\r\nMonth 2: \r\nStarting balance:$2750\r\n+ $2,500 = $5,250\r\nx 10% = $525\r\nEnding balance: $5,775\n\r\nMonth 3: \r\nStarting balance: $5,775\r\n+ $2,500 = $8,275\r\nx 10% = $827.50\r\nEnding balance: $9,102.50\n\r\nMonth 4:\r\nStarting balance: $9,102.50\r\n+ $2,500 = $11,602.50\r\nx 10% = $1,160.25\r\nEnding balance: $12,762.75\n\r\nMonth 5: \r\nStarting balance: $12,762.75\r\n+ $2,500 = $15,262.75\r\nx 10% = $1,526.28\r\nEnding balance: $16,789.03\n\r\nMonth 6: \r\nStarting balance: $16,789.03\r\n+ $2,500 = $19,289.03\r\nx 10% = $1,928.91\r\nEnding balance: $21,217.94\n\r\nMonth 7: \r\nStarting balance: $21,217.94\r\n+ $2,500 = $23,717.94\r\nx 10% = $2,371.80\r\nEnding balance: $26,089.74\n\r\nIt only took him 7 months to double his money! Don't you wish this were your bank account?\n<|im_end|>" }, { "id": "#41752", "title": "Hickory Dickory Dock, the Spider Went Round the Clock...", "fun": 2.28, "difficulty": 2.18, "author": "TRILLIONAIRE", "desc": "At exactly six o'clock, a spider started to walk at a constant speed from the hour hand anticlockwise round the edge of the clock face. When it reached the minute hand, it turned round (assume the turn was instantaneous) and walked in the opposite direction at the same constant speed. It reached the minute hand again after 20 minutes. At what time was this second meeting?", "hint": "No hint available.", "answer": "First, we set up the equation for the time (t) that the spider meets the minute hand the first time. The minute hand moves at 6 degrees per minute, and the spider moves at x degrees per minute. Since the spider starts at the 6 or at 180 degrees away from the minute hand, \n\r\n6(t) = 180 - x(t)\n\r\nNow if we say that the spider and minute hand are at the same spot, and start moving in the same direction, and the spider laps the minute hand (360 degrees plus the distance traveled by the minute hand, or 360 + 6(20) or 480 total degrees) then the distance traveled by the spider in 20 minutes must be 480 degrees. The spider, therefore, travels 24 degrees per minute.\n\r\nPlug 24 degrees per minute into the equation for x, and solve:\n\r\n6(t) = 180 -24(t)\r\n6(t) + 24(t) = 180\r\n30(t) = 180\r\nt = 6\n\r\nSo the first meeting is at 6 minutes after 6, or 6:06. 20 minutes later at the second meeting is 6:26.", "category": "Math", "date": "04/30/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt exactly six o'clock, a spider started to walk at a constant speed from the hour hand anticlockwise round the edge of the clock face. When it reached the minute hand, it turned round (assume the turn was instantaneous) and walked in the opposite direction at the same constant speed. It reached the minute hand again after 20 minutes. At what time was this second meeting?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, we set up the equation for the time (t) that the spider meets the minute hand the first time. The minute hand moves at 6 degrees per minute, and the spider moves at x degrees per minute. Since the spider starts at the 6 or at 180 degrees away from the minute hand, \n\r\n6(t) = 180 - x(t)\n\r\nNow if we say that the spider and minute hand are at the same spot, and start moving in the same direction, and the spider laps the minute hand (360 degrees plus the distance traveled by the minute hand, or 360 + 6(20) or 480 total degrees) then the distance traveled by the spider in 20 minutes must be 480 degrees. The spider, therefore, travels 24 degrees per minute.\n\r\nPlug 24 degrees per minute into the equation for x, and solve:\n\r\n6(t) = 180 -24(t)\r\n6(t) + 24(t) = 180\r\n30(t) = 180\r\nt = 6\n\r\nSo the first meeting is at 6 minutes after 6, or 6:06. 20 minutes later at the second meeting is 6:26.\n<|im_start|>answer\nFirst, we set up the equation for the time (t) that the spider meets the minute hand the first time. The minute hand moves at 6 degrees per minute, and the spider moves at x degrees per minute. Since the spider starts at the 6 or at 180 degrees away from the minute hand, \n\r\n6(t) = 180 - x(t)\n\r\nNow if we say that the spider and minute hand are at the same spot, and start moving in the same direction, and the spider laps the minute hand (360 degrees plus the distance traveled by the minute hand, or 360 + 6(20) or 480 total degrees) then the distance traveled by the spider in 20 minutes must be 480 degrees. The spider, therefore, travels 24 degrees per minute.\n\r\nPlug 24 degrees per minute into the equation for x, and solve:\n\r\n6(t) = 180 -24(t)\r\n6(t) + 24(t) = 180\r\n30(t) = 180\r\nt = 6\n\r\nSo the first meeting is at 6 minutes after 6, or 6:06. 20 minutes later at the second meeting is 6:26.\n<|im_end|>" }, { "id": "#18785", "title": "Bikes", "fun": 2.28, "difficulty": 1.3800000000000001, "author": "pretty_ponyz", "desc": "Apple Lake Bike Shop has a total of 32 bicycles and tricycles for rent. The shop owner checked all 74 wheels at the beginning of the season to make sure they were in good condition. None of the bicycles had training wheels.\n\r\nHow many of them are bicycles and how many are tricycles?", "hint": "Can there be 16 tricycles and 16 bicycles? Why not?", "answer": "By guessing numbers of each kind that add to 32, and calculating the number of wheels they have, you will find that the bike shop has 22 bicycles and 10 tricycles.", "category": "Math", "date": "09/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nApple Lake Bike Shop has a total of 32 bicycles and tricycles for rent. The shop owner checked all 74 wheels at the beginning of the season to make sure they were in good condition. None of the bicycles had training wheels.\n\r\nHow many of them are bicycles and how many are tricycles?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBy guessing numbers of each kind that add to 32, and calculating the number of wheels they have, you will find that the bike shop has 22 bicycles and 10 tricycles.\n<|im_start|>answer\nBy guessing numbers of each kind that add to 32, and calculating the number of wheels they have, you will find that the bike shop has 22 bicycles and 10 tricycles.\n<|im_end|>" }, { "id": "#8732", "title": "Time gain !!!", "fun": 2.28, "difficulty": 2.04, "author": "lesternoronha1", "desc": "A watch which gains 5 seconds every 3 minutes was set correctly at 7 a.m. In the afternoon of the same day, when the watch indicated a quarter past 4 o'clock, what was the true time?", "hint": "No hint available.", "answer": "The true time is 4 p.m.\n\r\nThe watch advanced 9 hours and 15 minutes (555 minutes) between 7 am and 4:15 pm.\n\r\nFor every 3 minutes and 5 seconds (185 seconds) that the watch advances, actual time progresses 3 minutes (180 seconds).\n\r\nTherefore you need to figure out how many 185-second intervals there are in 555 minutes and then figure out how much actual time passes in the same number of 180-second intervals.\n\r\nNumber of 185-second intervals in 555 minutes:\n\r\n(555 minutes * 60 seconds/minute)/185 seconds = 180 intervals\n\r\nAmount of time passing in 180, 180-second intervals:\n\r\n180 intervals * 180 seconds / (60 seconds/minute) = 540 minutes\n\r\nTherefore, in the time that the watch advanced 555 minutes, actual time advanced 540 minutes. The difference is 15 minutes, making the actual time 4:00 pm.", "category": "Math", "date": "11/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA watch which gains 5 seconds every 3 minutes was set correctly at 7 a.m. In the afternoon of the same day, when the watch indicated a quarter past 4 o'clock, what was the true time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe true time is 4 p.m.\n\r\nThe watch advanced 9 hours and 15 minutes (555 minutes) between 7 am and 4:15 pm.\n\r\nFor every 3 minutes and 5 seconds (185 seconds) that the watch advances, actual time progresses 3 minutes (180 seconds).\n\r\nTherefore you need to figure out how many 185-second intervals there are in 555 minutes and then figure out how much actual time passes in the same number of 180-second intervals.\n\r\nNumber of 185-second intervals in 555 minutes:\n\r\n(555 minutes * 60 seconds/minute)/185 seconds = 180 intervals\n\r\nAmount of time passing in 180, 180-second intervals:\n\r\n180 intervals * 180 seconds / (60 seconds/minute) = 540 minutes\n\r\nTherefore, in the time that the watch advanced 555 minutes, actual time advanced 540 minutes. The difference is 15 minutes, making the actual time 4:00 pm.\n<|im_start|>answer\nThe true time is 4 p.m.\n\r\nThe watch advanced 9 hours and 15 minutes (555 minutes) between 7 am and 4:15 pm.\n\r\nFor every 3 minutes and 5 seconds (185 seconds) that the watch advances, actual time progresses 3 minutes (180 seconds).\n\r\nTherefore you need to figure out how many 185-second intervals there are in 555 minutes and then figure out how much actual time passes in the same number of 180-second intervals.\n\r\nNumber of 185-second intervals in 555 minutes:\n\r\n(555 minutes * 60 seconds/minute)/185 seconds = 180 intervals\n\r\nAmount of time passing in 180, 180-second intervals:\n\r\n180 intervals * 180 seconds / (60 seconds/minute) = 540 minutes\n\r\nTherefore, in the time that the watch advanced 555 minutes, actual time advanced 540 minutes. The difference is 15 minutes, making the actual time 4:00 pm.\n<|im_end|>" }, { "id": "#9806", "title": "Balance Board Blues", "fun": 2.28, "difficulty": 2.16, "author": "IronMaiden980", "desc": "At the balance board, a teacher has set up a problem for her students. Using the information provided on the table below, can you determine how many C's you need to balance the \"A\" on Scale 4? A, B, and C denote different weights.\n\r\nScale 1: 1L balances 1C+1A\r\nScale 2: 1B+1C balances 1A\r\nScale 3: 3B balances 2L\r\nScale 4: 1A balances ?C", "hint": "No hint available.", "answer": "You need 5C. \n\r\n1. If you double the weights on Scale 1, you learn that 2L = 2C + 2A.\n\r\n2. By checking out Scale 3 you know that you can replace 2L in the above equation with 3B: 3B = 2C + 2A.\n\r\n3. Add 3C to each side. Now 3B + 3C = 5C + 2A.\n\r\n4. By checking Scale 2, you can replace each C + B with A: 3A = 5C + 2A.\n\r\n5. Subtract 2A from both sides, and get A = 5C.", "category": "Math", "date": "01/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the balance board, a teacher has set up a problem for her students. Using the information provided on the table below, can you determine how many C's you need to balance the \"A\" on Scale 4? A, B, and C denote different weights.\n\r\nScale 1: 1L balances 1C+1A\r\nScale 2: 1B+1C balances 1A\r\nScale 3: 3B balances 2L\r\nScale 4: 1A balances ?C\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou need 5C. \n\r\n1. If you double the weights on Scale 1, you learn that 2L = 2C + 2A.\n\r\n2. By checking out Scale 3 you know that you can replace 2L in the above equation with 3B: 3B = 2C + 2A.\n\r\n3. Add 3C to each side. Now 3B + 3C = 5C + 2A.\n\r\n4. By checking Scale 2, you can replace each C + B with A: 3A = 5C + 2A.\n\r\n5. Subtract 2A from both sides, and get A = 5C.\n<|im_start|>answer\nYou need 5C. \n\r\n1. If you double the weights on Scale 1, you learn that 2L = 2C + 2A.\n\r\n2. By checking out Scale 3 you know that you can replace 2L in the above equation with 3B: 3B = 2C + 2A.\n\r\n3. Add 3C to each side. Now 3B + 3C = 5C + 2A.\n\r\n4. By checking Scale 2, you can replace each C + B with A: 3A = 5C + 2A.\n\r\n5. Subtract 2A from both sides, and get A = 5C.\n<|im_end|>" }, { "id": "#10919", "title": "Weedy Willie", "fun": 2.28, "difficulty": 2.7, "author": "AllsatrASH08", "desc": "Weedy Willie was getting too old to work the land alone so he decided to divide his cornfield between himself and his four sons in proportion to their five work rates. He knew that Rastus, Wig, Twig and Swig together could plant a field of corn in five hours whereas Wig, Twig and Swig and himself together could manage the same task in six hours. So Weedy divided his field into a two-digit square number of parts and kept just one part for himself. Now, Wig, Twig and Swig were identical triplets so each received the same whole number of parts. How many parts did each son get?", "hint": "Let the work rates of the triplets combined (Wig, Twig and Swig), Rastus and Willie be x, y, z, respectively. Then\n\r\n5(x + y) = 6(x + z)", "answer": "Rastus received 9 parts and the triplets each got 13 parts.", "category": "Math", "date": "03/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWeedy Willie was getting too old to work the land alone so he decided to divide his cornfield between himself and his four sons in proportion to their five work rates. He knew that Rastus, Wig, Twig and Swig together could plant a field of corn in five hours whereas Wig, Twig and Swig and himself together could manage the same task in six hours. So Weedy divided his field into a two-digit square number of parts and kept just one part for himself. Now, Wig, Twig and Swig were identical triplets so each received the same whole number of parts. How many parts did each son get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRastus received 9 parts and the triplets each got 13 parts.\n<|im_start|>answer\nRastus received 9 parts and the triplets each got 13 parts.\n<|im_end|>" }, { "id": "#33037", "title": "Some Algebra 2", "fun": 2.28, "difficulty": 1.43, "author": "Crazycriely", "desc": "The length of a rectangle is 9 centimeters more than half the width. Find the length if the perimeter is 60 centimeters.", "hint": "the length= 9+1/2 the width.\r\n60= 2width + 2 length", "answer": "Length is 16 cm and the width is 14 cm.\n\r\nSolution:\r\n60cm=2width + 2 (9+1/2width)\n\r\nDistribute the 2 and you get\n\r\n60cm= 2width + 18 + 1width.\n\r\nCombine the widths. And subtract 18 from both sides.\n\r\n42cm= 3 width.\r\nDivide both sides by 3 to get the length of the width.\n\r\nWidth=14cm. Then plug it into the equation for the length and you should get 16cm.", "category": "Math", "date": "09/16/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe length of a rectangle is 9 centimeters more than half the width. Find the length if the perimeter is 60 centimeters.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLength is 16 cm and the width is 14 cm.\n\r\nSolution:\r\n60cm=2width + 2 (9+1/2width)\n\r\nDistribute the 2 and you get\n\r\n60cm= 2width + 18 + 1width.\n\r\nCombine the widths. And subtract 18 from both sides.\n\r\n42cm= 3 width.\r\nDivide both sides by 3 to get the length of the width.\n\r\nWidth=14cm. Then plug it into the equation for the length and you should get 16cm.\n<|im_start|>answer\nLength is 16 cm and the width is 14 cm.\n\r\nSolution:\r\n60cm=2width + 2 (9+1/2width)\n\r\nDistribute the 2 and you get\n\r\n60cm= 2width + 18 + 1width.\n\r\nCombine the widths. And subtract 18 from both sides.\n\r\n42cm= 3 width.\r\nDivide both sides by 3 to get the length of the width.\n\r\nWidth=14cm. Then plug it into the equation for the length and you should get 16cm.\n<|im_end|>" }, { "id": "#42753", "title": "Four Hats", "fun": 2.28, "difficulty": 0.86, "author": "AndrewWalker", "desc": "Four men sitting in a row each wear a different colored hat: red, yellow, blue, or green. From left to right, what is the order the men sit in?\n\r\nBlue is not beside red.\r\nYellow is on the far right.\r\nRed is to the right of Green.", "hint": "No hint available.", "answer": "Blue, Green, Red, Yellow\n\r\nYellow is a given (last). Because red and blue are not beside each other, green has to be between the two. Since red is to the right of green, blue must be on the far left (first).", "category": "Logic", "date": "08/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour men sitting in a row each wear a different colored hat: red, yellow, blue, or green. From left to right, what is the order the men sit in?\n\r\nBlue is not beside red.\r\nYellow is on the far right.\r\nRed is to the right of Green.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBlue, Green, Red, Yellow\n\r\nYellow is a given (last). Because red and blue are not beside each other, green has to be between the two. Since red is to the right of green, blue must be on the far left (first).\n<|im_start|>answer\nBlue, Green, Red, Yellow\n\r\nYellow is a given (last). Because red and blue are not beside each other, green has to be between the two. Since red is to the right of green, blue must be on the far left (first).\n<|im_end|>" }, { "id": "#2564", "title": "Shooting Arrows", "fun": 2.28, "difficulty": 1.79, "author": "204_blaze_41", "desc": "Paul and James shot 100 arrows, each managing to hit the target 50 times. With the score tied they broke for lunch. After the break, the shooting was not as sharp. Paul shot 89 arrows but only managed to hit the target 13 times. James shot 50 arrows without hitting the target once. Paul claimed that his percentage after the break was better than James', so therefore, he must be the better shot. James naturally disagreed. Who had the better average for the day?", "hint": "No hint available.", "answer": "Neither, they would be tied. Paul took 189 shots and hit the target 63 times, giving him 1/3 in hits. James shot 150 arrows and hit the target 50 times, also giving him 1/3 in hits.", "category": "Math", "date": "03/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPaul and James shot 100 arrows, each managing to hit the target 50 times. With the score tied they broke for lunch. After the break, the shooting was not as sharp. Paul shot 89 arrows but only managed to hit the target 13 times. James shot 50 arrows without hitting the target once. Paul claimed that his percentage after the break was better than James', so therefore, he must be the better shot. James naturally disagreed. Who had the better average for the day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNeither, they would be tied. Paul took 189 shots and hit the target 63 times, giving him 1/3 in hits. James shot 150 arrows and hit the target 50 times, also giving him 1/3 in hits.\n<|im_start|>answer\nNeither, they would be tied. Paul took 189 shots and hit the target 63 times, giving him 1/3 in hits. James shot 150 arrows and hit the target 50 times, also giving him 1/3 in hits.\n<|im_end|>" }, { "id": "#18141", "title": "A Lesson in Geography", "fun": 2.28, "difficulty": 2.01, "author": "andrewcs", "desc": "Which city comes next in this list?\n\r\n1. Buenos Aires\r\n2. La Paz\r\n3. Brasilia\r\n4. Santiago\r\n5. ???", "hint": "No hint available.", "answer": "Bogota\n\r\nThese are South American Capitals in order alphabetically by the countries.\n\r\n1. Argentina\r\n2. Bolivia\r\n3. Brazil\r\n4. Chile\r\n5. Columbia", "category": "Logic", "date": "07/06/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich city comes next in this list?\n\r\n1. Buenos Aires\r\n2. La Paz\r\n3. Brasilia\r\n4. Santiago\r\n5. ???\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBogota\n\r\nThese are South American Capitals in order alphabetically by the countries.\n\r\n1. Argentina\r\n2. Bolivia\r\n3. Brazil\r\n4. Chile\r\n5. Columbia\n<|im_start|>answer\nBogota\n\r\nThese are South American Capitals in order alphabetically by the countries.\n\r\n1. Argentina\r\n2. Bolivia\r\n3. Brazil\r\n4. Chile\r\n5. Columbia\n<|im_end|>" }, { "id": "#8567", "title": "Sweaty Chef's Xmas Party", "fun": 2.28, "difficulty": 2.45, "author": "mad-ade", "desc": "At the Christmas party of the \"Sweaty Chef\" kebab shop, the owner Mr Juan, took note of how many people were present. Although he was a bit tipsy when he made his note, and thus made a mistake. His notes were as follows:-\n\r\n1, There were 9 men and children. \n\r\n2, There were 2 more women than children. \n\r\n3, The number of different man-woman couples possible was 24. Note that if there were 7 men and 5 women, then there would have been 35 man-woman couples possible. \n\r\nAlso, of the three groups - men, women and children - at the party: \n\r\n4, There were 4 of one group. \n\r\n5, There were 6 of one group. \n\r\n6, There were 8 of one group.\r\nExactly one of the above 6 statements is false. \n\r\nCan you tell which one is false? Also, how many men, women and children are there at the party?", "hint": "No hint available.", "answer": "Statement (4) is false. There are 3 men, 8 women and 6 children. \r\nAssume that Statements (4), (5) and (6) are all true. Then, Statement (1) is false. But then Statement (2) and (3) both can not be true. Thus, contradictory to the fact that exactly one statement is false. \n\r\nSo Statement (4) or Statement (5) or Statement (6) is false. Also, Statements (1), (2) and (3) all are true. \n\r\nFrom (1) and (2), there are 11 men and women. Then from (3), there are 2 possible cases - either there are 8 men and 3 women or there are 3 men and 8 women. \n\r\nIf there are 8 men and 3 women, then there is 1 child. Then Statements (4) and (5) both are false, which is not possible. \n\r\nHence, there are 3 men, 8 women and 6 children. Statement (4) is false.", "category": "Logic", "date": "11/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the Christmas party of the \"Sweaty Chef\" kebab shop, the owner Mr Juan, took note of how many people were present. Although he was a bit tipsy when he made his note, and thus made a mistake. His notes were as follows:-\n\r\n1, There were 9 men and children. \n\r\n2, There were 2 more women than children. \n\r\n3, The number of different man-woman couples possible was 24. Note that if there were 7 men and 5 women, then there would have been 35 man-woman couples possible. \n\r\nAlso, of the three groups - men, women and children - at the party: \n\r\n4, There were 4 of one group. \n\r\n5, There were 6 of one group. \n\r\n6, There were 8 of one group.\r\nExactly one of the above 6 statements is false. \n\r\nCan you tell which one is false? Also, how many men, women and children are there at the party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement (4) is false. There are 3 men, 8 women and 6 children. \r\nAssume that Statements (4), (5) and (6) are all true. Then, Statement (1) is false. But then Statement (2) and (3) both can not be true. Thus, contradictory to the fact that exactly one statement is false. \n\r\nSo Statement (4) or Statement (5) or Statement (6) is false. Also, Statements (1), (2) and (3) all are true. \n\r\nFrom (1) and (2), there are 11 men and women. Then from (3), there are 2 possible cases - either there are 8 men and 3 women or there are 3 men and 8 women. \n\r\nIf there are 8 men and 3 women, then there is 1 child. Then Statements (4) and (5) both are false, which is not possible. \n\r\nHence, there are 3 men, 8 women and 6 children. Statement (4) is false.\n<|im_start|>answer\nStatement (4) is false. There are 3 men, 8 women and 6 children. \r\nAssume that Statements (4), (5) and (6) are all true. Then, Statement (1) is false. But then Statement (2) and (3) both can not be true. Thus, contradictory to the fact that exactly one statement is false. \n\r\nSo Statement (4) or Statement (5) or Statement (6) is false. Also, Statements (1), (2) and (3) all are true. \n\r\nFrom (1) and (2), there are 11 men and women. Then from (3), there are 2 possible cases - either there are 8 men and 3 women or there are 3 men and 8 women. \n\r\nIf there are 8 men and 3 women, then there is 1 child. Then Statements (4) and (5) both are false, which is not possible. \n\r\nHence, there are 3 men, 8 women and 6 children. Statement (4) is false.\n<|im_end|>" }, { "id": "#21518", "title": "What is a Car Worth?", "fun": 2.28, "difficulty": 1.86, "author": "tsimkin", "desc": "Henry is preparing to leave his parents' house, but before he goes, he needs a car and some money. His father agrees to give him $10,000 and a car if he works in the family store for a year. This sounds like a good deal to Henry, so he accepts.\n\r\nAfter working for 7 months, Henry decides he has done enough. He quits his job, and his father says, \"Fair enough. I will give you the car and $2,500.\"\n\r\nHenry replies, \"Knowing what the car is worth, that is perfectly fair.\"\n\r\nWhat is the car worth?", "hint": "No hint available.", "answer": "The car is worth $8,000.\n\r\nIf we denote the value of the car as 'c', then the value of 12 months of work would be 10000 + c, and the value of 7 months of work is 2500 + c.\n\r\nAssuming that the value of a month of work is constant, we have the value of a month of work equaling (10000 + c)/(12 months) = (2500 + c)/(7 months). Since the two are equal, we can solve for c.\n\r\n(7/12)*(10000 + c) = 2500 + c\r\n(70000/12) - 2500 = c - (7/12)*c\r\n3333.33 = (5/12)*c\r\n8000 = c", "category": "Math", "date": "03/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHenry is preparing to leave his parents' house, but before he goes, he needs a car and some money. His father agrees to give him $10,000 and a car if he works in the family store for a year. This sounds like a good deal to Henry, so he accepts.\n\r\nAfter working for 7 months, Henry decides he has done enough. He quits his job, and his father says, \"Fair enough. I will give you the car and $2,500.\"\n\r\nHenry replies, \"Knowing what the car is worth, that is perfectly fair.\"\n\r\nWhat is the car worth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe car is worth $8,000.\n\r\nIf we denote the value of the car as 'c', then the value of 12 months of work would be 10000 + c, and the value of 7 months of work is 2500 + c.\n\r\nAssuming that the value of a month of work is constant, we have the value of a month of work equaling (10000 + c)/(12 months) = (2500 + c)/(7 months). Since the two are equal, we can solve for c.\n\r\n(7/12)*(10000 + c) = 2500 + c\r\n(70000/12) - 2500 = c - (7/12)*c\r\n3333.33 = (5/12)*c\r\n8000 = c\n<|im_start|>answer\nThe car is worth $8,000.\n\r\nIf we denote the value of the car as 'c', then the value of 12 months of work would be 10000 + c, and the value of 7 months of work is 2500 + c.\n\r\nAssuming that the value of a month of work is constant, we have the value of a month of work equaling (10000 + c)/(12 months) = (2500 + c)/(7 months). Since the two are equal, we can solve for c.\n\r\n(7/12)*(10000 + c) = 2500 + c\r\n(70000/12) - 2500 = c - (7/12)*c\r\n3333.33 = (5/12)*c\r\n8000 = c\n<|im_end|>" }, { "id": "#42218", "title": "World Almanac", "fun": 2.28, "difficulty": 2.32, "author": "GrayPanther", "desc": "I am compiling the new world almanac and it now contains lots more pages. I know that it takes 333 digits to print the page numbers in sequence. How many numbered pages does the book have and how many times does the number 3 appear?", "hint": "No hint available.", "answer": "1-9: 9 digits, number 3 appears once;\r\n10-99: 180 digits, number 3 appears 19 times;\r\n333-9-180=144, 144/3=48.\r\nIn 100-147, number 3 appears 15 times.\n\r\nTherefore, there are 147 pages and the number 3 appears 35 times.", "category": "Math", "date": "06/13/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am compiling the new world almanac and it now contains lots more pages. I know that it takes 333 digits to print the page numbers in sequence. How many numbered pages does the book have and how many times does the number 3 appear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1-9: 9 digits, number 3 appears once;\r\n10-99: 180 digits, number 3 appears 19 times;\r\n333-9-180=144, 144/3=48.\r\nIn 100-147, number 3 appears 15 times.\n\r\nTherefore, there are 147 pages and the number 3 appears 35 times.\n<|im_start|>answer\n1-9: 9 digits, number 3 appears once;\r\n10-99: 180 digits, number 3 appears 19 times;\r\n333-9-180=144, 144/3=48.\r\nIn 100-147, number 3 appears 15 times.\n\r\nTherefore, there are 147 pages and the number 3 appears 35 times.\n<|im_end|>" }, { "id": "#8784", "title": "Tables and Chairs", "fun": 2.28, "difficulty": 2.64, "author": "lesternoronha1", "desc": "A factory that produces tables and chairs is equipped with 10 saws, 6 lathes, and 18 sanding machines. It takes a chair 10 minutes on a saw, 5 minutes on a lathe, and 5 minutes of sanding to be completed. It takes a table 5 minutes on a saw, 5 minutes on a lathe, and 20 minutes of sanding to be completed. A chair sells for $10 and a table sells for $20. How many tables and chairs should the factory produce per hour to yield the highest revenue, and what is that revenue?", "hint": "No hint available.", "answer": "The 10 saws can produce 600 minutes of work per hour (10 saws * 60 minutes).\r\nThe 6 lathes can produce 360 minutes of work per hour (6 lathes * 60 minutes).\r\nThe 18 sanding machines can produce 1080 minutes of work per hour (18 sanding machines * 60 minutes). \r\nLet c be the number of chairs produced per hour and t the number of tables produced per hour. \r\nThe number of saws limit the combination of chairs and tables to 600=10c+5t.\r\nThe number of lathes limit the combination of chairs and tables to 360=5c+5t.\r\nThe number of sanding machines limit the combination of chairs and tables to 1080=5c+20t. \r\nNext graph these three lines. It should be expected that the answer will lie on the intersection of two of these lines or to make all chairs or all tables. The intersection of the saw and sanding machine line occurs outside of how many chairs the lathe can make so this combination is not a viable answer. The saw and lathe lines cross at 48 chairs and 24 tables. The lathe and sanding machine lines cross at 24 chairs and 48 tables. \r\nNext determine the revenue at all points of intersection. \n\r\nChairs Tables Revenue\r\n60\t0\t600\r\n48\t24\t960\r\n24\t48\t1200\r\n0\t54\t1080\n\r\nSo the optimal answer is to make 24 chairs and 48 tables for revenue of $1200 per hour. \r\nTo check it will take 24*10 + 48*5 = 480 minutes of saw time. There are 600 minutes available so the saws will be idle 20% of the time. \r\nIt will take 24*5 + 48*5 = 360 minutes of lathe time which is exactly what we have. \r\nIt will take 24*5 + 48*20 = 1080 minutes of sanding machine time which is exactly what we have.", "category": "Math", "date": "11/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA factory that produces tables and chairs is equipped with 10 saws, 6 lathes, and 18 sanding machines. It takes a chair 10 minutes on a saw, 5 minutes on a lathe, and 5 minutes of sanding to be completed. It takes a table 5 minutes on a saw, 5 minutes on a lathe, and 20 minutes of sanding to be completed. A chair sells for $10 and a table sells for $20. How many tables and chairs should the factory produce per hour to yield the highest revenue, and what is that revenue?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 10 saws can produce 600 minutes of work per hour (10 saws * 60 minutes).\r\nThe 6 lathes can produce 360 minutes of work per hour (6 lathes * 60 minutes).\r\nThe 18 sanding machines can produce 1080 minutes of work per hour (18 sanding machines * 60 minutes). \r\nLet c be the number of chairs produced per hour and t the number of tables produced per hour. \r\nThe number of saws limit the combination of chairs and tables to 600=10c+5t.\r\nThe number of lathes limit the combination of chairs and tables to 360=5c+5t.\r\nThe number of sanding machines limit the combination of chairs and tables to 1080=5c+20t. \r\nNext graph these three lines. It should be expected that the answer will lie on the intersection of two of these lines or to make all chairs or all tables. The intersection of the saw and sanding machine line occurs outside of how many chairs the lathe can make so this combination is not a viable answer. The saw and lathe lines cross at 48 chairs and 24 tables. The lathe and sanding machine lines cross at 24 chairs and 48 tables. \r\nNext determine the revenue at all points of intersection. \n\r\nChairs Tables Revenue\r\n60\t0\t600\r\n48\t24\t960\r\n24\t48\t1200\r\n0\t54\t1080\n\r\nSo the optimal answer is to make 24 chairs and 48 tables for revenue of $1200 per hour. \r\nTo check it will take 24*10 + 48*5 = 480 minutes of saw time. There are 600 minutes available so the saws will be idle 20% of the time. \r\nIt will take 24*5 + 48*5 = 360 minutes of lathe time which is exactly what we have. \r\nIt will take 24*5 + 48*20 = 1080 minutes of sanding machine time which is exactly what we have.\n<|im_start|>answer\nThe 10 saws can produce 600 minutes of work per hour (10 saws * 60 minutes).\r\nThe 6 lathes can produce 360 minutes of work per hour (6 lathes * 60 minutes).\r\nThe 18 sanding machines can produce 1080 minutes of work per hour (18 sanding machines * 60 minutes). \r\nLet c be the number of chairs produced per hour and t the number of tables produced per hour. \r\nThe number of saws limit the combination of chairs and tables to 600=10c+5t.\r\nThe number of lathes limit the combination of chairs and tables to 360=5c+5t.\r\nThe number of sanding machines limit the combination of chairs and tables to 1080=5c+20t. \r\nNext graph these three lines. It should be expected that the answer will lie on the intersection of two of these lines or to make all chairs or all tables. The intersection of the saw and sanding machine line occurs outside of how many chairs the lathe can make so this combination is not a viable answer. The saw and lathe lines cross at 48 chairs and 24 tables. The lathe and sanding machine lines cross at 24 chairs and 48 tables. \r\nNext determine the revenue at all points of intersection. \n\r\nChairs Tables Revenue\r\n60\t0\t600\r\n48\t24\t960\r\n24\t48\t1200\r\n0\t54\t1080\n\r\nSo the optimal answer is to make 24 chairs and 48 tables for revenue of $1200 per hour. \r\nTo check it will take 24*10 + 48*5 = 480 minutes of saw time. There are 600 minutes available so the saws will be idle 20% of the time. \r\nIt will take 24*5 + 48*5 = 360 minutes of lathe time which is exactly what we have. \r\nIt will take 24*5 + 48*20 = 1080 minutes of sanding machine time which is exactly what we have.\n<|im_end|>" }, { "id": "#13067", "title": "Segment Redirected", "fun": 2.28, "difficulty": 1.8900000000000001, "author": "willymapo", "desc": "The professor drew a circle in the blackboard. He marked the center and named it A.\r\nThen he made a horizontal segment starting at the center and ending on the circle at point B. He named it Segment AB.\r\nThen he made a vertical segment, perpendicular to AB, starting at A and ending on the circle at point C. He named it Segment AC.\r\nThen he marked a point somewhere in the middle of AC and named it X. He started at X and made another horizontal segment, parallel to AB and perpendicular to AC, and ended it on the circle at point Y. He named it segment XY.\r\nThen He started at point Y at the circumference, and made another segment, parallel to AC and perpendicular to AB, that ended in a point around the middle of AB at a point that he called W.\r\nThen we saw the blackboard and there was a circle with a perfect rectangle in it, the rectangle made of points AXYW.\r\nThe professor then drew the last segment, from point X to point W, making then the diagonal segment XW of the rectangle.\r\nAnd He asked: If the diameter of the circle is 1 inch, then how long is the segment XW?", "hint": "No hint available.", "answer": "XW is 1/2 inch long, because both diagonals of a rectangle are equal, and the other diagonal (AY) makes up the radius of the circle, that is half the diameter.", "category": "Math", "date": "06/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe professor drew a circle in the blackboard. He marked the center and named it A.\r\nThen he made a horizontal segment starting at the center and ending on the circle at point B. He named it Segment AB.\r\nThen he made a vertical segment, perpendicular to AB, starting at A and ending on the circle at point C. He named it Segment AC.\r\nThen he marked a point somewhere in the middle of AC and named it X. He started at X and made another horizontal segment, parallel to AB and perpendicular to AC, and ended it on the circle at point Y. He named it segment XY.\r\nThen He started at point Y at the circumference, and made another segment, parallel to AC and perpendicular to AB, that ended in a point around the middle of AB at a point that he called W.\r\nThen we saw the blackboard and there was a circle with a perfect rectangle in it, the rectangle made of points AXYW.\r\nThe professor then drew the last segment, from point X to point W, making then the diagonal segment XW of the rectangle.\r\nAnd He asked: If the diameter of the circle is 1 inch, then how long is the segment XW?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nXW is 1/2 inch long, because both diagonals of a rectangle are equal, and the other diagonal (AY) makes up the radius of the circle, that is half the diameter.\n<|im_start|>answer\nXW is 1/2 inch long, because both diagonals of a rectangle are equal, and the other diagonal (AY) makes up the radius of the circle, that is half the diameter.\n<|im_end|>" }, { "id": "#8696", "title": "#/#= what?", "fun": 2.28, "difficulty": 1.46, "author": "stargirl", "desc": "I am a fraction that isn't improper. Both my Numerator and Denominator are prime numbers such that if they were multiplied together and then had 16 subtracted from the answer, it would equal 19. What are my numerator and denominator?", "hint": "No hint available.", "answer": "5/7. 5 and 7 are both prime and if you multiply them together you get 35. If you do 35-16 you get 19.", "category": "Math", "date": "11/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a fraction that isn't improper. Both my Numerator and Denominator are prime numbers such that if they were multiplied together and then had 16 subtracted from the answer, it would equal 19. What are my numerator and denominator?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5/7. 5 and 7 are both prime and if you multiply them together you get 35. If you do 35-16 you get 19.\n<|im_start|>answer\n5/7. 5 and 7 are both prime and if you multiply them together you get 35. If you do 35-16 you get 19.\n<|im_end|>" }, { "id": "#7520", "title": "Armless Aliens", "fun": 2.28, "difficulty": 2.8, "author": "warrior", "desc": "On planet ?*!@, the inhabitants are robots with various numbers of arms. The robots are grouped into tribes according to the numbers of arms they have so that in any tribe, no member has a different number of arms to the other members. Each tribe follows the same fertility ritual before bed each night, a ritual that also reveals the number of members in a tribe. In the ritual, each arm of a male links with an arm of a female, no male-female pair of robots linking more than once. The minimum number of robots required to link all arms once only is the number belonging to that tribe. Now one night, the Creaky tribe cornered half of the Rusty tribe and despite being outnumbered two to one, unscrewed one arm from each, there being an equal number of male and female victims. However, the Creaky tribe were extremely poor at arithmetic and had failed to realise that they needed 24 times their actual haul of spare arms in order that the number of links their members could then make, each with the same number of extra arms, was half the maximum number of links the Rusty tribe could then make. How many Creakies and Rusties were there?", "hint": "No hint available.", "answer": "ARMLESS ALIENS. There were 14 Creakies and 56 Rusties. A robot with n arms requires n females and vice-versa, and the number of members is 2n with n squared links. Let the Creaky tribe have x arms each and the Rusty tribe have y. Then the maximum number of links that the Rusty tribe can make after the mutilation is y(2y-1)/2. The number of extra arms each Creaky needs is 24y/2x allowing x(x + 24y/2x) links. Forming the links equation we have 2(y squared) - 49y - 4(x squared) = 0. We must have y=4x so that y - 4x is a factor. A long division shows that the condition for zero remainder is x=7 so y=28. The numbers of members are twice these.", "category": "Math", "date": "09/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn planet ?*!@, the inhabitants are robots with various numbers of arms. The robots are grouped into tribes according to the numbers of arms they have so that in any tribe, no member has a different number of arms to the other members. Each tribe follows the same fertility ritual before bed each night, a ritual that also reveals the number of members in a tribe. In the ritual, each arm of a male links with an arm of a female, no male-female pair of robots linking more than once. The minimum number of robots required to link all arms once only is the number belonging to that tribe. Now one night, the Creaky tribe cornered half of the Rusty tribe and despite being outnumbered two to one, unscrewed one arm from each, there being an equal number of male and female victims. However, the Creaky tribe were extremely poor at arithmetic and had failed to realise that they needed 24 times their actual haul of spare arms in order that the number of links their members could then make, each with the same number of extra arms, was half the maximum number of links the Rusty tribe could then make. How many Creakies and Rusties were there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nARMLESS ALIENS. There were 14 Creakies and 56 Rusties. A robot with n arms requires n females and vice-versa, and the number of members is 2n with n squared links. Let the Creaky tribe have x arms each and the Rusty tribe have y. Then the maximum number of links that the Rusty tribe can make after the mutilation is y(2y-1)/2. The number of extra arms each Creaky needs is 24y/2x allowing x(x + 24y/2x) links. Forming the links equation we have 2(y squared) - 49y - 4(x squared) = 0. We must have y=4x so that y - 4x is a factor. A long division shows that the condition for zero remainder is x=7 so y=28. The numbers of members are twice these.\n<|im_start|>answer\nARMLESS ALIENS. There were 14 Creakies and 56 Rusties. A robot with n arms requires n females and vice-versa, and the number of members is 2n with n squared links. Let the Creaky tribe have x arms each and the Rusty tribe have y. Then the maximum number of links that the Rusty tribe can make after the mutilation is y(2y-1)/2. The number of extra arms each Creaky needs is 24y/2x allowing x(x + 24y/2x) links. Forming the links equation we have 2(y squared) - 49y - 4(x squared) = 0. We must have y=4x so that y - 4x is a factor. A long division shows that the condition for zero remainder is x=7 so y=28. The numbers of members are twice these.\n<|im_end|>" }, { "id": "#47069", "title": "Computer Geeks", "fun": 2.28, "difficulty": 1.05, "author": "mathisnice", "desc": "Allison (Female), Bill (Male), Jill (Female), and Willy (Male) all love computers. Can you match their first names, last names, (Johnson, Reynolds, Smith, and White), favorite websites (BrainBashers, Facebook, Google, and Yahoo), and current web browsers (Chrome, Firefox, Internet Explorer [Explorer], and Safari) using the clues below? Good luck!\n\r\n1. Mr. White is addicted to brain teasers.\r\n2. The girls don't have Facebook accounts.\r\n3. Mr. Johnson hates anything to do with Google.\r\n4. Mr. White and Bill are best friends.\r\n5. Jill loves to search on Google.\r\n6. Smith has a Yahoo fan club.\r\n7. Willy's favorite browser is made by the same company as his Mac. Same for Jill, except she owns a Microsoft with Windows Vista.", "hint": "Chrome is made by Google, Inc. Apple makes Safari. Microsoft Windows makes Internet Explorer. BrainBashers is a teaser site.", "answer": "Allison Smith's favorite browser is Chrome and favorite website is Yahoo.\r\nBill Johnson's favorite browser is Firefox and favorite website is Facebook.\r\nJill Reynolds's favorite browser is Internet Explorer and favorite website is Google.\r\nWilly White's favorite browser is Safari and favorite website is BrainBashers.", "category": "Logic-Grid", "date": "05/22/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAllison (Female), Bill (Male), Jill (Female), and Willy (Male) all love computers. Can you match their first names, last names, (Johnson, Reynolds, Smith, and White), favorite websites (BrainBashers, Facebook, Google, and Yahoo), and current web browsers (Chrome, Firefox, Internet Explorer [Explorer], and Safari) using the clues below? Good luck!\n\r\n1. Mr. White is addicted to brain teasers.\r\n2. The girls don't have Facebook accounts.\r\n3. Mr. Johnson hates anything to do with Google.\r\n4. Mr. White and Bill are best friends.\r\n5. Jill loves to search on Google.\r\n6. Smith has a Yahoo fan club.\r\n7. Willy's favorite browser is made by the same company as his Mac. Same for Jill, except she owns a Microsoft with Windows Vista.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAllison Smith's favorite browser is Chrome and favorite website is Yahoo.\r\nBill Johnson's favorite browser is Firefox and favorite website is Facebook.\r\nJill Reynolds's favorite browser is Internet Explorer and favorite website is Google.\r\nWilly White's favorite browser is Safari and favorite website is BrainBashers.\n<|im_start|>answer\nAllison Smith's favorite browser is Chrome and favorite website is Yahoo.\r\nBill Johnson's favorite browser is Firefox and favorite website is Facebook.\r\nJill Reynolds's favorite browser is Internet Explorer and favorite website is Google.\r\nWilly White's favorite browser is Safari and favorite website is BrainBashers.\n<|im_end|>" }, { "id": "#18158", "title": "Donkey's Dilemma", "fun": 2.28, "difficulty": 1.56, "author": "wizecracker55", "desc": "A donkey is tied to a stake by a 10 foot rope. 20 feet away is a carrot. Yet he easily reaches and eats the carrot, without breaking the rope or any sort of help. How?", "hint": "No hint available.", "answer": "The donkey is ten feet away from the stake holding him to begin with. Ten more feet is the carrot patch (10+10=20). They're on opposite sides of his circle of movement.", "category": "Math", "date": "07/08/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA donkey is tied to a stake by a 10 foot rope. 20 feet away is a carrot. Yet he easily reaches and eats the carrot, without breaking the rope or any sort of help. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe donkey is ten feet away from the stake holding him to begin with. Ten more feet is the carrot patch (10+10=20). They're on opposite sides of his circle of movement.\n<|im_start|>answer\nThe donkey is ten feet away from the stake holding him to begin with. Ten more feet is the carrot patch (10+10=20). They're on opposite sides of his circle of movement.\n<|im_end|>" }, { "id": "#6348", "title": "Missing Clock Digit", "fun": 2.28, "difficulty": 2.2, "author": "mad-ade", "desc": "Mad Ade has several clocks which have appeared in several different teasers on this site. They are all kept in one room. When Mad Ade enters the room he notices something unusual about the times.\n\r\nClock 1 is at: 06:16\r\nClock 2 is at: 11:56\r\nClock 3 is at: 16:33\n\r\nUnfortunately the last digit is missing of Clock 4, it says 12:1?.\r\nWhat is the missing digit from clock 4?", "hint": "No hint available.", "answer": "The missing digit is 9 because all the digits of the other clocks add up to 13.\r\nClock 1 is 0+6+1+6=13\r\nClock 2 is 1+1+5+6=13\r\nClock 3 is 1+6+3+3=13\r\ntherefore Clock 4 must be 1+2+1+9=13", "category": "Logic", "date": "08/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has several clocks which have appeared in several different teasers on this site. They are all kept in one room. When Mad Ade enters the room he notices something unusual about the times.\n\r\nClock 1 is at: 06:16\r\nClock 2 is at: 11:56\r\nClock 3 is at: 16:33\n\r\nUnfortunately the last digit is missing of Clock 4, it says 12:1?.\r\nWhat is the missing digit from clock 4?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe missing digit is 9 because all the digits of the other clocks add up to 13.\r\nClock 1 is 0+6+1+6=13\r\nClock 2 is 1+1+5+6=13\r\nClock 3 is 1+6+3+3=13\r\ntherefore Clock 4 must be 1+2+1+9=13\n<|im_start|>answer\nThe missing digit is 9 because all the digits of the other clocks add up to 13.\r\nClock 1 is 0+6+1+6=13\r\nClock 2 is 1+1+5+6=13\r\nClock 3 is 1+6+3+3=13\r\ntherefore Clock 4 must be 1+2+1+9=13\n<|im_end|>" }, { "id": "#2110", "title": "What is True", "fun": 2.28, "difficulty": 1.14, "author": "ChemicalBoy08", "desc": "Which of the following statements is true? \n\r\n1. Only one of these statements is true.\r\n2. Only two of these statements are true.\r\n3. Only three of these statements are true.\r\n4. Only four of these statements are true.\r\n5. Only five of these statements are true.\r\n6. Only six of these statements are true.", "hint": "No hint available.", "answer": "Statement 1 is true.", "category": "Logic", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of the following statements is true? \n\r\n1. Only one of these statements is true.\r\n2. Only two of these statements are true.\r\n3. Only three of these statements are true.\r\n4. Only four of these statements are true.\r\n5. Only five of these statements are true.\r\n6. Only six of these statements are true.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatement 1 is true.\n<|im_start|>answer\nStatement 1 is true.\n<|im_end|>" }, { "id": "#2105", "title": "A Sign", "fun": 2.28, "difficulty": 1.85, "author": "ChemicalBoy08", "desc": "My local shop wanted to create a sign that said PUZZLES, and they had the following letters each one using a different font: PPPUUZZZZZLLLLESS. How many different ways could they have made the sign?", "hint": "No hint available.", "answer": "960.\r\n3 * 2 * 5 * 4 * 4 * 1 * 2", "category": "Math", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy local shop wanted to create a sign that said PUZZLES, and they had the following letters each one using a different font: PPPUUZZZZZLLLLESS. How many different ways could they have made the sign?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n960.\r\n3 * 2 * 5 * 4 * 4 * 1 * 2\n<|im_start|>answer\n960.\r\n3 * 2 * 5 * 4 * 4 * 1 * 2\n<|im_end|>" }, { "id": "#692", "title": "My Mom and I", "fun": 2.28, "difficulty": 1.6400000000000001, "author": "Christine", "desc": "My mom was 27 years old when I was born. How old will I be when my age is the exact reverse of my mother`s?", "hint": "No hint available.", "answer": "I would be 14, my mother would be 41.", "category": "Math", "date": "07/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy mom was 27 years old when I was born. How old will I be when my age is the exact reverse of my mother`s?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI would be 14, my mother would be 41.\n<|im_start|>answer\nI would be 14, my mother would be 41.\n<|im_end|>" }, { "id": "#8673", "title": "My Secret Word", "fun": 2.28, "difficulty": 2.08, "author": "lesternoronha1", "desc": "I gave Terrance a problem. One of the words listed below is my secret word.\n\r\n AIM DUE MOD OAT TIE\n\r\nWith this list in front of him, I told him that if I give him any one letter of my secret word, he could tell me the number of vowels in my secret word. Which word is my secret word?", "hint": "No hint available.", "answer": "If you were told any one of the letters of MOD you would not be able to determine whether the number of vowels in my secret word is one or two. Then my secret word cannot be AIM, DUE, MOD or OAT. Hence my secret word must be TIE.", "category": "Logic", "date": "12/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI gave Terrance a problem. One of the words listed below is my secret word.\n\r\n AIM DUE MOD OAT TIE\n\r\nWith this list in front of him, I told him that if I give him any one letter of my secret word, he could tell me the number of vowels in my secret word. Which word is my secret word?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you were told any one of the letters of MOD you would not be able to determine whether the number of vowels in my secret word is one or two. Then my secret word cannot be AIM, DUE, MOD or OAT. Hence my secret word must be TIE.\n<|im_start|>answer\nIf you were told any one of the letters of MOD you would not be able to determine whether the number of vowels in my secret word is one or two. Then my secret word cannot be AIM, DUE, MOD or OAT. Hence my secret word must be TIE.\n<|im_end|>" }, { "id": "#35280", "title": "Catalan Opera Singers", "fun": 2.28, "difficulty": 1.95, "author": "Thel", "desc": "Nuria was making a school project about the early days of four well-known Catalan opera singers. Unfortunately, she messed up her notes and has only some scraps of information left. Can you help her determine the name and surname of each of the singers, when they sung professionally for the first time and which opera was it?\n\r\nA note for opera lovers: the names and surnames do not correspond to the real ones (this is explained in the answer).\n\r\nA note for non-opera lovers: the hint reveals who composed each opera.\n\r\nNames: Montserrat, Victoria (women) Josep, Jaume (men)\r\nSurnames: Carreras, dels Angels, Aragall, Caballe\r\nProfessional Debut: 1945, 1957, 1961, 1970\r\nOpera: Le Nozze di Figaro, Norma, I Pagliacci, La Boheme\n\r\n1. The four singers are: Montserrat, the one who made his/her debut in 1961, the one who played a minor role in Norma and the one surnamed Caballe.\n\r\n2. Neither Jaume nor Victoria made their debut in 1970, nor did she sing in La Boheme.\n\r\n3. The four operas are: Le Nozze, the one staged in 1957, the one with dels Angels and I Pagliacci.\n\r\n4. La Boheme was staged in 1957.\n\r\n5. The one surnamed Carreras sung in an opera by Leoncavallo, and the 1945 debutante didn't sing in an opera by Bellini.\n\r\n6. Caballe was greatly applauded for his/her performance in Le Nozze.\n\r\n7. The men made their debut after the women.", "hint": "Le Nozze di Figaro = Mozart\r\nI Pagliacci = Leoncavallo\r\nNorma = Bellini\r\nLa Boheme = Puccini", "answer": "Montserrat Aragall, 1957, La Boheme (real name: Montserrat Caballe, well-known for her duet with Freddy Mercury during the Barcelona Olympics in 1992).\r\nVictoria Caballe, 1945, Nozze di Figaro (real name: Victoria dels Angels)\r\nJosep dels Angels, 1970, Norma (real name: Josep Carreras, part of \"The Three Tenors\" along with Placido Domingo and Pavarotti).\r\nJaume Carreras, 1961, I Pagliacci (real name: Jaume Aragall)\n\r\nIf you enjoy fine voices, be sure to check them out!", "category": "Logic-Grid", "date": "02/12/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNuria was making a school project about the early days of four well-known Catalan opera singers. Unfortunately, she messed up her notes and has only some scraps of information left. Can you help her determine the name and surname of each of the singers, when they sung professionally for the first time and which opera was it?\n\r\nA note for opera lovers: the names and surnames do not correspond to the real ones (this is explained in the answer).\n\r\nA note for non-opera lovers: the hint reveals who composed each opera.\n\r\nNames: Montserrat, Victoria (women) Josep, Jaume (men)\r\nSurnames: Carreras, dels Angels, Aragall, Caballe\r\nProfessional Debut: 1945, 1957, 1961, 1970\r\nOpera: Le Nozze di Figaro, Norma, I Pagliacci, La Boheme\n\r\n1. The four singers are: Montserrat, the one who made his/her debut in 1961, the one who played a minor role in Norma and the one surnamed Caballe.\n\r\n2. Neither Jaume nor Victoria made their debut in 1970, nor did she sing in La Boheme.\n\r\n3. The four operas are: Le Nozze, the one staged in 1957, the one with dels Angels and I Pagliacci.\n\r\n4. La Boheme was staged in 1957.\n\r\n5. The one surnamed Carreras sung in an opera by Leoncavallo, and the 1945 debutante didn't sing in an opera by Bellini.\n\r\n6. Caballe was greatly applauded for his/her performance in Le Nozze.\n\r\n7. The men made their debut after the women.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMontserrat Aragall, 1957, La Boheme (real name: Montserrat Caballe, well-known for her duet with Freddy Mercury during the Barcelona Olympics in 1992).\r\nVictoria Caballe, 1945, Nozze di Figaro (real name: Victoria dels Angels)\r\nJosep dels Angels, 1970, Norma (real name: Josep Carreras, part of \"The Three Tenors\" along with Placido Domingo and Pavarotti).\r\nJaume Carreras, 1961, I Pagliacci (real name: Jaume Aragall)\n\r\nIf you enjoy fine voices, be sure to check them out!\n<|im_start|>answer\nMontserrat Aragall, 1957, La Boheme (real name: Montserrat Caballe, well-known for her duet with Freddy Mercury during the Barcelona Olympics in 1992).\r\nVictoria Caballe, 1945, Nozze di Figaro (real name: Victoria dels Angels)\r\nJosep dels Angels, 1970, Norma (real name: Josep Carreras, part of \"The Three Tenors\" along with Placido Domingo and Pavarotti).\r\nJaume Carreras, 1961, I Pagliacci (real name: Jaume Aragall)\n\r\nIf you enjoy fine voices, be sure to check them out!\n<|im_end|>" }, { "id": "#43880", "title": "How Many Doctors", "fun": 2.28, "difficulty": 1.62, "author": "fishmed", "desc": "A group of doctors attended a conference. All but 40 were cardiologists. All but 50 were pediatricians. All but 60 were surgeons. These were the only types of doctors in attendance. How many in all attended the conference?", "hint": "No hint available.", "answer": "The total attendance was 75.\n\r\nx = total attendance\r\nx-40 = total cardiologists\r\nx-50 = total pediatricians\r\nx-60 = total surgeons\n\r\nFinal equation:\r\nx = x-40 + x-50 + x-60\r\nx = 3x - 150\r\n-2x = -150\r\nx = 75\n\r\n35 cardiologists\r\n25 pediatricians\r\n15 surgeons\r\n----\r\n75 total attendees", "category": "Math", "date": "01/09/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of doctors attended a conference. All but 40 were cardiologists. All but 50 were pediatricians. All but 60 were surgeons. These were the only types of doctors in attendance. How many in all attended the conference?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe total attendance was 75.\n\r\nx = total attendance\r\nx-40 = total cardiologists\r\nx-50 = total pediatricians\r\nx-60 = total surgeons\n\r\nFinal equation:\r\nx = x-40 + x-50 + x-60\r\nx = 3x - 150\r\n-2x = -150\r\nx = 75\n\r\n35 cardiologists\r\n25 pediatricians\r\n15 surgeons\r\n----\r\n75 total attendees\n<|im_start|>answer\nThe total attendance was 75.\n\r\nx = total attendance\r\nx-40 = total cardiologists\r\nx-50 = total pediatricians\r\nx-60 = total surgeons\n\r\nFinal equation:\r\nx = x-40 + x-50 + x-60\r\nx = 3x - 150\r\n-2x = -150\r\nx = 75\n\r\n35 cardiologists\r\n25 pediatricians\r\n15 surgeons\r\n----\r\n75 total attendees\n<|im_end|>" }, { "id": "#1885", "title": "The Race", "fun": 2.28, "difficulty": 1.49, "author": "jokester8000", "desc": "Two men are going to have a race. Each of them starts and ends at the same place as the other. They are running at the same speed and neither of them speeds up or slows down. The result is not a tie. How is this possible?", "hint": "No hint available.", "answer": "They each took separate routes and one route was longer than the other.", "category": "Logic", "date": "01/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo men are going to have a race. Each of them starts and ends at the same place as the other. They are running at the same speed and neither of them speeds up or slows down. The result is not a tie. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey each took separate routes and one route was longer than the other.\n<|im_start|>answer\nThey each took separate routes and one route was longer than the other.\n<|im_end|>" }, { "id": "#1244", "title": "What does she like?", "fun": 2.28, "difficulty": 1.5, "author": "gokaran", "desc": "Sally likes 225 but not 224; she likes 900 but not 800; she likes 144 but not 145. Which does she like: \n\r\na)1600\r\nb)1700", "hint": "No hint available.", "answer": "Answer is a) 1600\r\nSally likes perfect squares", "category": "Math", "date": "10/31/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally likes 225 but not 224; she likes 900 but not 800; she likes 144 but not 145. Which does she like: \n\r\na)1600\r\nb)1700\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer is a) 1600\r\nSally likes perfect squares\n<|im_start|>answer\nAnswer is a) 1600\r\nSally likes perfect squares\n<|im_end|>" }, { "id": "#29411", "title": "To Infinity and Beyond!", "fun": 2.28, "difficulty": 2.25, "author": "Cogmatic", "desc": "In the function f(x), f(x) equals the sum of the digits of x and the sum of the new number's digits and so on until one digit is remaining. For example:\n\r\nf(787)=f(7+8+7)=f(22)=f(2+2)=f(4)=4\r\nand\r\nf(9135899)=f(9+1+3+5+8+9+9)= f(44)=f(4+4)=f(8)=8\n\r\nSo, if we assume that infinity is equal to 9999999999999... with an infinite amount of digits, then what is f(infinity)?", "hint": "No hint available.", "answer": "f(infinity)=9\n\r\nAny number with all nines for digits will all add up to nine:\n\r\nf(9)=9\r\nf(99)=f(18)=f(9)=9\r\nf(999)=f(27)=f(9)=9\r\nf(99999999999999)=f(126)=f(9)=9", "category": "Math", "date": "03/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the function f(x), f(x) equals the sum of the digits of x and the sum of the new number's digits and so on until one digit is remaining. For example:\n\r\nf(787)=f(7+8+7)=f(22)=f(2+2)=f(4)=4\r\nand\r\nf(9135899)=f(9+1+3+5+8+9+9)= f(44)=f(4+4)=f(8)=8\n\r\nSo, if we assume that infinity is equal to 9999999999999... with an infinite amount of digits, then what is f(infinity)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nf(infinity)=9\n\r\nAny number with all nines for digits will all add up to nine:\n\r\nf(9)=9\r\nf(99)=f(18)=f(9)=9\r\nf(999)=f(27)=f(9)=9\r\nf(99999999999999)=f(126)=f(9)=9\n<|im_start|>answer\nf(infinity)=9\n\r\nAny number with all nines for digits will all add up to nine:\n\r\nf(9)=9\r\nf(99)=f(18)=f(9)=9\r\nf(999)=f(27)=f(9)=9\r\nf(99999999999999)=f(126)=f(9)=9\n<|im_end|>" }, { "id": "#639", "title": "His Widow's Sister", "fun": 2.28, "difficulty": 2.08, "author": "Jacob", "desc": "It was reported in the paper that Jim Jones had married his widow's sister. How did he do this?", "hint": "No hint available.", "answer": "Jim Jones married Ella in 1820; she died in 1830. In 1840 he married Ella's sister, Mary. She became his widow when he died in 1850, so in 1820 he married his widow's sister.", "category": "Logic", "date": "06/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was reported in the paper that Jim Jones had married his widow's sister. How did he do this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJim Jones married Ella in 1820; she died in 1830. In 1840 he married Ella's sister, Mary. She became his widow when he died in 1850, so in 1820 he married his widow's sister.\n<|im_start|>answer\nJim Jones married Ella in 1820; she died in 1830. In 1840 he married Ella's sister, Mary. She became his widow when he died in 1850, so in 1820 he married his widow's sister.\n<|im_end|>" }, { "id": "#6270", "title": "Add Something", "fun": 2.28, "difficulty": 1.51, "author": "Bintot", "desc": "Add something to 9 to make it six.", "hint": "No hint available.", "answer": "The Roman numeral for nine is IX. Add S to the beginning of it to make it SIX!", "category": "Logic", "date": "08/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdd something to 9 to make it six.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Roman numeral for nine is IX. Add S to the beginning of it to make it SIX!\n<|im_start|>answer\nThe Roman numeral for nine is IX. Add S to the beginning of it to make it SIX!\n<|im_end|>" }, { "id": "#6225", "title": "Wigan Smith", "fun": 2.28, "difficulty": 1.81, "author": "mad-ade", "desc": "Whilst trekking through the jungles of Madadia, the intrepid explorer \"Wigan Smith\" discovers an isolated tribe of the legendary Kebab people. The Kebab people's written alphabet contains only six letters (call the letters A, B, C, D, E and F). The tribe has a fear against using the same letter twice in the same word, believing the great Gods of the \"Chillisauce Volcano\" will be angered. So it's never done. \n\r\nIf each different sequence of letters constitutes a different word in the language, what is the maximum number of six-letter words that the language can employ?", "hint": "No hint available.", "answer": "The language can employ a maximum of 720 six-letter words. \n\r\nIt is a simple permutation problem of arranging 6 letters to get different six-letter words. And it can be done in 6! ways i.e. 720 ways. \n\r\nIn other words, the first letter can be any of the given 6 letters (A through F). Then, whatever the first letter is, the second letter will always be from the remaining 5 letters (as same letter can not be used twice), and the third letter will always be from the remaining 4 letters, and so on. Thus, the different possible six-letter words are 6*5*4*3*2*1 = 720.", "category": "Math", "date": "08/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhilst trekking through the jungles of Madadia, the intrepid explorer \"Wigan Smith\" discovers an isolated tribe of the legendary Kebab people. The Kebab people's written alphabet contains only six letters (call the letters A, B, C, D, E and F). The tribe has a fear against using the same letter twice in the same word, believing the great Gods of the \"Chillisauce Volcano\" will be angered. So it's never done. \n\r\nIf each different sequence of letters constitutes a different word in the language, what is the maximum number of six-letter words that the language can employ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe language can employ a maximum of 720 six-letter words. \n\r\nIt is a simple permutation problem of arranging 6 letters to get different six-letter words. And it can be done in 6! ways i.e. 720 ways. \n\r\nIn other words, the first letter can be any of the given 6 letters (A through F). Then, whatever the first letter is, the second letter will always be from the remaining 5 letters (as same letter can not be used twice), and the third letter will always be from the remaining 4 letters, and so on. Thus, the different possible six-letter words are 6*5*4*3*2*1 = 720.\n<|im_start|>answer\nThe language can employ a maximum of 720 six-letter words. \n\r\nIt is a simple permutation problem of arranging 6 letters to get different six-letter words. And it can be done in 6! ways i.e. 720 ways. \n\r\nIn other words, the first letter can be any of the given 6 letters (A through F). Then, whatever the first letter is, the second letter will always be from the remaining 5 letters (as same letter can not be used twice), and the third letter will always be from the remaining 4 letters, and so on. Thus, the different possible six-letter words are 6*5*4*3*2*1 = 720.\n<|im_end|>" }, { "id": "#4323", "title": "Walls", "fun": 2.28, "difficulty": 2.29, "author": "mad-ade", "desc": "Mad Ade has hired some builders to build a series of walls between sections of a large garden. There was just one more wall to be built than there were men in the group, and the number of hours the whole job took was one less than the number of men in the group. Assuming that all the walls were equal in size, and that any man on the team could build one wall by himself in exactly five hours and 15 minutes, how many men were in the group?", "hint": "No hint available.", "answer": "There were seven men in the group, \r\nwho built eight walls in six hours.", "category": "Math", "date": "05/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has hired some builders to build a series of walls between sections of a large garden. There was just one more wall to be built than there were men in the group, and the number of hours the whole job took was one less than the number of men in the group. Assuming that all the walls were equal in size, and that any man on the team could build one wall by himself in exactly five hours and 15 minutes, how many men were in the group?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were seven men in the group, \r\nwho built eight walls in six hours.\n<|im_start|>answer\nThere were seven men in the group, \r\nwho built eight walls in six hours.\n<|im_end|>" }, { "id": "#4862", "title": "Costly Kebabs", "fun": 2.28, "difficulty": 2.38, "author": "mad-ade", "desc": "Mad Ade stood in his local Kebab shop \"The Sweaty Chef\". He has $15 to spend. From the Menu he can see that:\n\r\nA, 2 Kebabs, 1 portion of chips and a can of pop = $7.90\r\nB, 1 Kebab, 1 burger, 2 chips and 2 cans of pop = $8.55\r\nC, 2 Burger, 1 chips and 3 cans of pop = $7.70\r\nD, 2 Kebabs, 1 Burger and 3 portions of chips = $11.25\n\r\nWould Mad Ade have enough money left after he had purchased 2 kebabs, 2 burgers, 2 chips and 2 cans of pop to be able to afford a carton of chilli sauce that cost 80p?", "hint": "No hint available.", "answer": "Unfortunately for Mad Ade, he would be 10p short.\r\nKebabs =$3.25 x2 = $6.50\r\nBurgers=$2.50 x2 = $5.00\r\nChips =$0.75 x2 = $1.50\r\nPop =$0.65 x2 = $1.30\n\r\n$6.50 + $5.00 + $1.50 + $1.30= $14.30 + $0.80 = $15.10", "category": "Math", "date": "06/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade stood in his local Kebab shop \"The Sweaty Chef\". He has $15 to spend. From the Menu he can see that:\n\r\nA, 2 Kebabs, 1 portion of chips and a can of pop = $7.90\r\nB, 1 Kebab, 1 burger, 2 chips and 2 cans of pop = $8.55\r\nC, 2 Burger, 1 chips and 3 cans of pop = $7.70\r\nD, 2 Kebabs, 1 Burger and 3 portions of chips = $11.25\n\r\nWould Mad Ade have enough money left after he had purchased 2 kebabs, 2 burgers, 2 chips and 2 cans of pop to be able to afford a carton of chilli sauce that cost 80p?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUnfortunately for Mad Ade, he would be 10p short.\r\nKebabs =$3.25 x2 = $6.50\r\nBurgers=$2.50 x2 = $5.00\r\nChips =$0.75 x2 = $1.50\r\nPop =$0.65 x2 = $1.30\n\r\n$6.50 + $5.00 + $1.50 + $1.30= $14.30 + $0.80 = $15.10\n<|im_start|>answer\nUnfortunately for Mad Ade, he would be 10p short.\r\nKebabs =$3.25 x2 = $6.50\r\nBurgers=$2.50 x2 = $5.00\r\nChips =$0.75 x2 = $1.50\r\nPop =$0.65 x2 = $1.30\n\r\n$6.50 + $5.00 + $1.50 + $1.30= $14.30 + $0.80 = $15.10\n<|im_end|>" }, { "id": "#5355", "title": "Nice Wallpaper", "fun": 2.28, "difficulty": 1.57, "author": "mad-ade", "desc": "Mad Ade bought 50 metres of wallpaper in a nice Greasy Kebab shop style, from a shop. He did not know it, but the metre-rule used to measure the paper was 1cm short. What length of wallpaper did he actually get?", "hint": "No hint available.", "answer": "49.5 metres", "category": "Math", "date": "07/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade bought 50 metres of wallpaper in a nice Greasy Kebab shop style, from a shop. He did not know it, but the metre-rule used to measure the paper was 1cm short. What length of wallpaper did he actually get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n49.5 metres\n<|im_start|>answer\n49.5 metres\n<|im_end|>" }, { "id": "#21654", "title": "Trucks", "fun": 2.28, "difficulty": 1.78, "author": "jocelyng", "desc": "A haulage contractor did not have room in his garage for 8 of his trucks. He therefore increased the size of his garage by 50 percent, which gave him room for 8 more trucks than he owned altogether. How many trucks did he own?", "hint": "No hint available.", "answer": "40 trucks: his original garage could hold 32 trucks. By increasing the size by 50%, the new garage could then hold 48 trucks - which is 8 more than he currently owned.", "category": "Math", "date": "03/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA haulage contractor did not have room in his garage for 8 of his trucks. He therefore increased the size of his garage by 50 percent, which gave him room for 8 more trucks than he owned altogether. How many trucks did he own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n40 trucks: his original garage could hold 32 trucks. By increasing the size by 50%, the new garage could then hold 48 trucks - which is 8 more than he currently owned.\n<|im_start|>answer\n40 trucks: his original garage could hold 32 trucks. By increasing the size by 50%, the new garage could then hold 48 trucks - which is 8 more than he currently owned.\n<|im_end|>" }, { "id": "#733", "title": "Car Wash", "fun": 2.28, "difficulty": 1.8, "author": "blkmagic", "desc": "If Bob can wash a car in 8 minutes and Joe can wash a car in 12 minutes, how long would it take to wash the car together?", "hint": "If Bob can do it in 8 with no help, how must faster can he do it with help?", "answer": "It would take 4 minutes and 48 seconds.\n\r\nIn 1 minute Bob washes 1/8 of the car and Joe washes 1/12 of the car. This makes 3/24ths and 2/24ths of the car washed, or a total of 5/24ths. Therefore the number of minutes taken for a whole car is 24/5, or 4.8 minutes.", "category": "Math", "date": "08/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf Bob can wash a car in 8 minutes and Joe can wash a car in 12 minutes, how long would it take to wash the car together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt would take 4 minutes and 48 seconds.\n\r\nIn 1 minute Bob washes 1/8 of the car and Joe washes 1/12 of the car. This makes 3/24ths and 2/24ths of the car washed, or a total of 5/24ths. Therefore the number of minutes taken for a whole car is 24/5, or 4.8 minutes.\n<|im_start|>answer\nIt would take 4 minutes and 48 seconds.\n\r\nIn 1 minute Bob washes 1/8 of the car and Joe washes 1/12 of the car. This makes 3/24ths and 2/24ths of the car washed, or a total of 5/24ths. Therefore the number of minutes taken for a whole car is 24/5, or 4.8 minutes.\n<|im_end|>" }, { "id": "#31493", "title": "Claire's Will", "fun": 2.28, "difficulty": 1.43, "author": "akl21", "desc": "Claire Agard, deceased at the age of ninety-seven, has left a will dedicating her sizable fortune to her niece, to her nephew, and to Johnny, her faithful assistant for the past twenty years. \n\r\nUnfortunately, she employed the services of one of the most unorganized solicitors in town, who lost the will and evoked the anger of just about every family member benefited by it (namely Johnny's wife, the niece's sons, and the nephew's already angry creditors).\n\r\nHowever, the young solicitor was flattered to be employed by the richest woman in the small town, so he took notes. It was simply too interesting for him to resist.\n\r\nCan you find out what each person's last name is, who received what amount of money, and who inherited what portion of her widespread real estate?\n\r\nFirst Names: Kara, Johnny, Reginald\r\nLast Names: Jennings, Ouna, Simpkins\r\nMonetary amounts: $2 million, $6 million, $800,000\r\nReal Estate portions: The Cabin, The Tudor, The Georgian\n\r\nClues:\n\r\n1. The heirs are: Kara, the person surnamed Ouna, and the person who inherited The Georgian.\n\r\n2. Johnny's last name is not Jennings. Kara's last name is not Ouna.\n\r\n3.Reginald has deep gambling debts, but his aunt was unsympathetic and gave him the least amount of money. He had had his eye on a piece of old, English-style property, though, and that she gave to him.\n\r\n4. Kara's last name is 25 letters away from her piece of real estate. \n\r\n5. Both of Johnny's initials are in the word 'Joker'.\n\r\n6. Reginald has often been subject to ridicule because of his last name.\n\r\n7. Ouna got 2 million, and a first-class backwoods lodge.\n\r\n8. The person who inherited 6 million also got a Tudor, and they were very excited to find that Claire had installed a swimming pool...party time!!!\n\r\nGood luck! (By the way, Kara has ensured a reward of $60,000 to the first to solve...)", "hint": "No hint available.", "answer": "Answer: Sorry, the reward wasn't real, but this answer is!\n\r\nFirst Name-Last Name-$-Real Estate\n\r\nJohnny-Ouna-$2 million-The Cabin\n\r\nKara-Jennings-$6 million- The Tudor\n\r\nReginald-Simpkins-$800,000- The Georgian", "category": "Logic-Grid", "date": "07/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nClaire Agard, deceased at the age of ninety-seven, has left a will dedicating her sizable fortune to her niece, to her nephew, and to Johnny, her faithful assistant for the past twenty years. \n\r\nUnfortunately, she employed the services of one of the most unorganized solicitors in town, who lost the will and evoked the anger of just about every family member benefited by it (namely Johnny's wife, the niece's sons, and the nephew's already angry creditors).\n\r\nHowever, the young solicitor was flattered to be employed by the richest woman in the small town, so he took notes. It was simply too interesting for him to resist.\n\r\nCan you find out what each person's last name is, who received what amount of money, and who inherited what portion of her widespread real estate?\n\r\nFirst Names: Kara, Johnny, Reginald\r\nLast Names: Jennings, Ouna, Simpkins\r\nMonetary amounts: $2 million, $6 million, $800,000\r\nReal Estate portions: The Cabin, The Tudor, The Georgian\n\r\nClues:\n\r\n1. The heirs are: Kara, the person surnamed Ouna, and the person who inherited The Georgian.\n\r\n2. Johnny's last name is not Jennings. Kara's last name is not Ouna.\n\r\n3.Reginald has deep gambling debts, but his aunt was unsympathetic and gave him the least amount of money. He had had his eye on a piece of old, English-style property, though, and that she gave to him.\n\r\n4. Kara's last name is 25 letters away from her piece of real estate. \n\r\n5. Both of Johnny's initials are in the word 'Joker'.\n\r\n6. Reginald has often been subject to ridicule because of his last name.\n\r\n7. Ouna got 2 million, and a first-class backwoods lodge.\n\r\n8. The person who inherited 6 million also got a Tudor, and they were very excited to find that Claire had installed a swimming pool...party time!!!\n\r\nGood luck! (By the way, Kara has ensured a reward of $60,000 to the first to solve...)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: Sorry, the reward wasn't real, but this answer is!\n\r\nFirst Name-Last Name-$-Real Estate\n\r\nJohnny-Ouna-$2 million-The Cabin\n\r\nKara-Jennings-$6 million- The Tudor\n\r\nReginald-Simpkins-$800,000- The Georgian\n<|im_start|>answer\nAnswer: Sorry, the reward wasn't real, but this answer is!\n\r\nFirst Name-Last Name-$-Real Estate\n\r\nJohnny-Ouna-$2 million-The Cabin\n\r\nKara-Jennings-$6 million- The Tudor\n\r\nReginald-Simpkins-$800,000- The Georgian\n<|im_end|>" }, { "id": "#3723", "title": "China Population", "fun": 2.28, "difficulty": 1.6, "author": "Skunkali", "desc": "If the population of China were to walk past you in single file, how long would it take?", "hint": "No hint available.", "answer": "It would never end due to the rate of reproduction......", "category": "Logic", "date": "04/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the population of China were to walk past you in single file, how long would it take?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt would never end due to the rate of reproduction......\n<|im_start|>answer\nIt would never end due to the rate of reproduction......\n<|im_end|>" }, { "id": "#8786", "title": "Zeros and Ones", "fun": 2.28, "difficulty": 2.61, "author": "lesternoronha1", "desc": "What is the smallest integer greater than 0 that can be written entirely with zeros and ones and is evenly divisible by 225?", "hint": "No hint available.", "answer": "The prime factorization of 225 is 5*5*3*3. So the answer will be both a factor of 25 and of 9. \r\nAll multiples of 25 end in either 00, 25, 50, or 75. The only one of these composed of 0's and 1's is obviously 00, so the answer must end in 00. The hard part is finding a series of 0's and 1's preceding the 00 that will make the entire number divisible by 9. \r\nIf you didn't already know the following trick then this problem would be very hard. If you did know it then the problem was likely very easy. The trick is that if the sum of digits of a number is divisible by 9 then the number itself is also divisible by 9. Note that this is true for 3 also. For example the number 17685 is divisible by 9 because 1+7+6+8+5=27, and 27 is divisible by 9. \r\nTo prove this let's consider any five digit number, abcde. This number can be expressed as follows. \n\r\na*10000 + b*1000 + c*100 + d*10 + e = a*(9999+1) + b*(999+1) + c*(99+1) + d*(9+1) + e*1 = a*9999 + b*999 + c*99 + d*9 + a + b + c + d + e = \r\n9*(a*1111 + b*111 + c*11 + d*1) + a + b + c + d + e . \n\r\n9*(a*1111 + b*111 + c*11 + d*1) must be divisible by 9 because it is a factor of 9. So if a+b+c+d+e is also a factor of 9 then the entire number must be a factor of 9. Note also that the remainder of abcde/9 is the same as the remainder of (a+b+c+d+e)/9. \r\nThe smallest number consisting of all 1's and divisible by 9 is thus 111,111,111. Adding the two zeros at the end results in the answer to the problem: 11,111,111,100.", "category": "Math", "date": "11/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest integer greater than 0 that can be written entirely with zeros and ones and is evenly divisible by 225?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe prime factorization of 225 is 5*5*3*3. So the answer will be both a factor of 25 and of 9. \r\nAll multiples of 25 end in either 00, 25, 50, or 75. The only one of these composed of 0's and 1's is obviously 00, so the answer must end in 00. The hard part is finding a series of 0's and 1's preceding the 00 that will make the entire number divisible by 9. \r\nIf you didn't already know the following trick then this problem would be very hard. If you did know it then the problem was likely very easy. The trick is that if the sum of digits of a number is divisible by 9 then the number itself is also divisible by 9. Note that this is true for 3 also. For example the number 17685 is divisible by 9 because 1+7+6+8+5=27, and 27 is divisible by 9. \r\nTo prove this let's consider any five digit number, abcde. This number can be expressed as follows. \n\r\na*10000 + b*1000 + c*100 + d*10 + e = a*(9999+1) + b*(999+1) + c*(99+1) + d*(9+1) + e*1 = a*9999 + b*999 + c*99 + d*9 + a + b + c + d + e = \r\n9*(a*1111 + b*111 + c*11 + d*1) + a + b + c + d + e . \n\r\n9*(a*1111 + b*111 + c*11 + d*1) must be divisible by 9 because it is a factor of 9. So if a+b+c+d+e is also a factor of 9 then the entire number must be a factor of 9. Note also that the remainder of abcde/9 is the same as the remainder of (a+b+c+d+e)/9. \r\nThe smallest number consisting of all 1's and divisible by 9 is thus 111,111,111. Adding the two zeros at the end results in the answer to the problem: 11,111,111,100.\n<|im_start|>answer\nThe prime factorization of 225 is 5*5*3*3. So the answer will be both a factor of 25 and of 9. \r\nAll multiples of 25 end in either 00, 25, 50, or 75. The only one of these composed of 0's and 1's is obviously 00, so the answer must end in 00. The hard part is finding a series of 0's and 1's preceding the 00 that will make the entire number divisible by 9. \r\nIf you didn't already know the following trick then this problem would be very hard. If you did know it then the problem was likely very easy. The trick is that if the sum of digits of a number is divisible by 9 then the number itself is also divisible by 9. Note that this is true for 3 also. For example the number 17685 is divisible by 9 because 1+7+6+8+5=27, and 27 is divisible by 9. \r\nTo prove this let's consider any five digit number, abcde. This number can be expressed as follows. \n\r\na*10000 + b*1000 + c*100 + d*10 + e = a*(9999+1) + b*(999+1) + c*(99+1) + d*(9+1) + e*1 = a*9999 + b*999 + c*99 + d*9 + a + b + c + d + e = \r\n9*(a*1111 + b*111 + c*11 + d*1) + a + b + c + d + e . \n\r\n9*(a*1111 + b*111 + c*11 + d*1) must be divisible by 9 because it is a factor of 9. So if a+b+c+d+e is also a factor of 9 then the entire number must be a factor of 9. Note also that the remainder of abcde/9 is the same as the remainder of (a+b+c+d+e)/9. \r\nThe smallest number consisting of all 1's and divisible by 9 is thus 111,111,111. Adding the two zeros at the end results in the answer to the problem: 11,111,111,100.\n<|im_end|>" }, { "id": "#14154", "title": "The Twelve Days of Christmas", "fun": 2.28, "difficulty": 1.46, "author": "cool_star", "desc": "The song 'The Twelve Days of Christmas' has many presents:\n\r\nA partridge in a pear tree\r\nTwo turtle doves\r\nThree french hens\r\nFour calling birds\r\nFive golden rings\r\nSix geese a-laying\r\nSeven swans a-swimming\r\nEight maids a-milking\r\nNine drummers drumming\r\nTen pipers piping\r\nEleven dancers dancing\r\nTwelve lords a-leaping\n\r\nThroughout the entire song, including all twelve 'verses', which present(s) shows up most often?", "hint": "Make sure to count FIVE golden rings every time that part is sung, not just one.", "answer": "The present that comes up most often are six geese a-laying and seven swans a-swimming which both come up 42 times.", "category": "Math", "date": "08/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe song 'The Twelve Days of Christmas' has many presents:\n\r\nA partridge in a pear tree\r\nTwo turtle doves\r\nThree french hens\r\nFour calling birds\r\nFive golden rings\r\nSix geese a-laying\r\nSeven swans a-swimming\r\nEight maids a-milking\r\nNine drummers drumming\r\nTen pipers piping\r\nEleven dancers dancing\r\nTwelve lords a-leaping\n\r\nThroughout the entire song, including all twelve 'verses', which present(s) shows up most often?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe present that comes up most often are six geese a-laying and seven swans a-swimming which both come up 42 times.\n<|im_start|>answer\nThe present that comes up most often are six geese a-laying and seven swans a-swimming which both come up 42 times.\n<|im_end|>" }, { "id": "#12929", "title": "Ring Sale", "fun": 2.28, "difficulty": 1.78, "author": "willymapo", "desc": "Once a man entered my office asking for help. He wanted to sell a ring and was hoping I could help. He said to me that if I got the ring to be sold at $100, he would give me a reward of $20. \r\nI saw the ring, and I thought that I could get a little more money, so I told him that I will try to sell it at $200 instead. He then told me that If I was able to sell it at that price, He will give me $35 instead as a reward.\r\nI tried to sell the ring, and the best price I could get was $140. \n\r\nWhat should my reward be?", "hint": "The first offer stands as it is. The second one is only a raise in the reward in case of a rise in the sale price.", "answer": "The original reward was $20.\r\nFor a $100 rise in the sale price, the reward could pass from $20 to $35, so there was a rise of $15 for the reward. That is, $1.5 per each $10 you obtain in the price. I got $40 above the original price, so I will get 4 * $1.5 = $6 plus the original $20 = $26.", "category": "Math", "date": "06/04/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce a man entered my office asking for help. He wanted to sell a ring and was hoping I could help. He said to me that if I got the ring to be sold at $100, he would give me a reward of $20. \r\nI saw the ring, and I thought that I could get a little more money, so I told him that I will try to sell it at $200 instead. He then told me that If I was able to sell it at that price, He will give me $35 instead as a reward.\r\nI tried to sell the ring, and the best price I could get was $140. \n\r\nWhat should my reward be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe original reward was $20.\r\nFor a $100 rise in the sale price, the reward could pass from $20 to $35, so there was a rise of $15 for the reward. That is, $1.5 per each $10 you obtain in the price. I got $40 above the original price, so I will get 4 * $1.5 = $6 plus the original $20 = $26.\n<|im_start|>answer\nThe original reward was $20.\r\nFor a $100 rise in the sale price, the reward could pass from $20 to $35, so there was a rise of $15 for the reward. That is, $1.5 per each $10 you obtain in the price. I got $40 above the original price, so I will get 4 * $1.5 = $6 plus the original $20 = $26.\n<|im_end|>" }, { "id": "#11652", "title": "Aging Man", "fun": 2.28, "difficulty": 1.41, "author": "Spikey", "desc": "Two years ago my age was a multiple of 6 and one year ago my age was a multiple of Five. \n\r\nHow old am I now? (I am less than 50)", "hint": "No hint available.", "answer": "I am 26.", "category": "Math", "date": "04/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo years ago my age was a multiple of 6 and one year ago my age was a multiple of Five. \n\r\nHow old am I now? (I am less than 50)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI am 26.\n<|im_start|>answer\nI am 26.\n<|im_end|>" }, { "id": "#27523", "title": "Three Digit Riddle", "fun": 2.28, "difficulty": 2.16, "author": "jinzcarmela", "desc": "I am a three digit number, of which when you subtract my reversed-digits self, I become a 198.\n\r\nWHAT AM I?", "hint": "No hint available.", "answer": "Any 3-digit number whose hundreds digit is two greater than its units digits will work.\n\r\nExamples:\n\r\n654 - 456 = 198\r\n836 - 638 = 198\r\n917 - 719 = 198", "category": "Math", "date": "12/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a three digit number, of which when you subtract my reversed-digits self, I become a 198.\n\r\nWHAT AM I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAny 3-digit number whose hundreds digit is two greater than its units digits will work.\n\r\nExamples:\n\r\n654 - 456 = 198\r\n836 - 638 = 198\r\n917 - 719 = 198\n<|im_start|>answer\nAny 3-digit number whose hundreds digit is two greater than its units digits will work.\n\r\nExamples:\n\r\n654 - 456 = 198\r\n836 - 638 = 198\r\n917 - 719 = 198\n<|im_end|>" }, { "id": "#4755", "title": "Boys and Dogs", "fun": 2.28, "difficulty": 2.0, "author": "mad-ade", "desc": "Mad Ade has been asked to judge a dog show. He sees a mix of boys and dogs, and counts 22 heads and 68 legs. How many boys and dogs are at the show?", "hint": "No hint available.", "answer": "The boys plus the dogs have a total of 22 heads, or B + D = 22. Subtracting D from each side of the preceding results in a value for B of 22 - D.\r\nThe boys' legs equal two times the number of boys, the dogs' legs equal four times the number of dogs, and the total number of legs equals 68, or 2B + 4D = 68. \r\nUsing the value for B already calculated, the last equation can be rewritten as 2 (22 - D) + 4D = 68, or 44 - 2D + 4D = 68, which, by addition and subtraction, becomes 2D = 24, or D = 12.\n\r\nThere are 12 dogs and 10 boys in the show. Mad Ade eventually awarded first prize to the hotdog he had for lunch.", "category": "Math", "date": "06/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has been asked to judge a dog show. He sees a mix of boys and dogs, and counts 22 heads and 68 legs. How many boys and dogs are at the show?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe boys plus the dogs have a total of 22 heads, or B + D = 22. Subtracting D from each side of the preceding results in a value for B of 22 - D.\r\nThe boys' legs equal two times the number of boys, the dogs' legs equal four times the number of dogs, and the total number of legs equals 68, or 2B + 4D = 68. \r\nUsing the value for B already calculated, the last equation can be rewritten as 2 (22 - D) + 4D = 68, or 44 - 2D + 4D = 68, which, by addition and subtraction, becomes 2D = 24, or D = 12.\n\r\nThere are 12 dogs and 10 boys in the show. Mad Ade eventually awarded first prize to the hotdog he had for lunch.\n<|im_start|>answer\nThe boys plus the dogs have a total of 22 heads, or B + D = 22. Subtracting D from each side of the preceding results in a value for B of 22 - D.\r\nThe boys' legs equal two times the number of boys, the dogs' legs equal four times the number of dogs, and the total number of legs equals 68, or 2B + 4D = 68. \r\nUsing the value for B already calculated, the last equation can be rewritten as 2 (22 - D) + 4D = 68, or 44 - 2D + 4D = 68, which, by addition and subtraction, becomes 2D = 24, or D = 12.\n\r\nThere are 12 dogs and 10 boys in the show. Mad Ade eventually awarded first prize to the hotdog he had for lunch.\n<|im_end|>" }, { "id": "#4011", "title": "Retiring Grandad", "fun": 2.28, "difficulty": 1.71, "author": "mad-ade", "desc": "Mad Ade's Grandad is 65 years old, and he wants to retire, but his boss says the minimum retirement age is 2 billion seconds old (nothing is normal in Mad Ade's world). Is Mad Ade's Grandad old enough to retire?", "hint": "No hint available.", "answer": "Yes, 2 billion seconds is 63 years 152 days 3 hours 33 minutes and 20 seconds", "category": "Math", "date": "05/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Grandad is 65 years old, and he wants to retire, but his boss says the minimum retirement age is 2 billion seconds old (nothing is normal in Mad Ade's world). Is Mad Ade's Grandad old enough to retire?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes, 2 billion seconds is 63 years 152 days 3 hours 33 minutes and 20 seconds\n<|im_start|>answer\nYes, 2 billion seconds is 63 years 152 days 3 hours 33 minutes and 20 seconds\n<|im_end|>" }, { "id": "#8459", "title": "Freddo Frogs", "fun": 2.28, "difficulty": 1.49, "author": "glennyboy02", "desc": "Sammie's mother gave Sammie $20. Before I continue with this teaser, you must realise that Sammie is a young girl who is obsessed with saving money! She will go to extraordinary lengths to save money, and she was also a chocoholic. Sammie wanted as much chocolate as possible through spending as little money as possible. \n\r\nAnyway, Sammie went to the shops one day, with her $20! By the way, I must mention that there is only one type of chocolate that this particular chocoholic eats, and that is \"Freddo Frogs\"! So, within these certain shops there are four chocolate shops that Sammie could visit.\n\r\nThey are as follows;\n\r\nGlenn's Scrumptious Choccies!\r\nFreddo frogs = $5 = 4 Freddo frogs\n\r\nGlenn's Yummy Chocolates!\r\nFreddo Frogs = $4 = 3 Freddo frogs\n\r\nGlenn's Haven for Chocoholics\r\nFreddo Frogs = $2.50 = 1 Freddo frog\n\r\nGlenn's Freddo Frogs\r\nFreddo Frogs = $10 = 7 Frogs\n\r\n(There was rumour going around that Glenn owned all the chocolate stores!)\n\r\nAnyway, time to think, which chocolate store would Sammie visit?", "hint": "No hint available.", "answer": "Sammie would visit Glenn's Scrumptious Choccies where she would purchase 16 frogs for $20!", "category": "Math", "date": "11/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSammie's mother gave Sammie $20. Before I continue with this teaser, you must realise that Sammie is a young girl who is obsessed with saving money! She will go to extraordinary lengths to save money, and she was also a chocoholic. Sammie wanted as much chocolate as possible through spending as little money as possible. \n\r\nAnyway, Sammie went to the shops one day, with her $20! By the way, I must mention that there is only one type of chocolate that this particular chocoholic eats, and that is \"Freddo Frogs\"! So, within these certain shops there are four chocolate shops that Sammie could visit.\n\r\nThey are as follows;\n\r\nGlenn's Scrumptious Choccies!\r\nFreddo frogs = $5 = 4 Freddo frogs\n\r\nGlenn's Yummy Chocolates!\r\nFreddo Frogs = $4 = 3 Freddo frogs\n\r\nGlenn's Haven for Chocoholics\r\nFreddo Frogs = $2.50 = 1 Freddo frog\n\r\nGlenn's Freddo Frogs\r\nFreddo Frogs = $10 = 7 Frogs\n\r\n(There was rumour going around that Glenn owned all the chocolate stores!)\n\r\nAnyway, time to think, which chocolate store would Sammie visit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSammie would visit Glenn's Scrumptious Choccies where she would purchase 16 frogs for $20!\n<|im_start|>answer\nSammie would visit Glenn's Scrumptious Choccies where she would purchase 16 frogs for $20!\n<|im_end|>" }, { "id": "#48354", "title": "Harry Potter", "fun": 2.28, "difficulty": 0.65, "author": "noey5799", "desc": "4 friends, Noey, Ruby, Amanda, and Dylan are having an argument over which Harry Potter book is better: Sorcerer's (or Philosopher's) Stone, Chamber of Secrets, Prisoner of Azkaban, or Goblet of Fire. They were also fighting over which character is better: Harry, Ron, Hermione, or Sirius.\n\r\nFriends: Noey, Dylan, Ruby, Amanda\r\nBooks: Sorcerer's (or Philosopher's) Stone, Chamber of Secrets, Prisoner of Azkaban, Goblet of Fire\r\nCharacters: Harry, Hermione, Ron, Sirius. \n\r\nFind out which friend likes which character, and which book.\n\r\n1. The 4 friends are, Dylan, the one whose initial is the same as her favorite character, the one who likes the Goblet of Fire and the one who likes the Prisoner of Azkaban. \n\r\n2. Amanda likes the adult character and her favorite book is the one where her favorite character is introduced. \n\r\n3. Noey thinks that the Triwizard Tournament is the best part in the whole series.\n\r\n4. Dylan's favorite is the Chamber of Secrets. \n\r\n5. Noey's favorite character is a girl. \n\r\n6. Dylan doesn't like the way Sirius was introduced in the Prisoner of Azkaban.\n\r\n7. The Triwizard Tournament took place in the Goblet of Fire.\n\r\n8. Sirius went to school with Harry's dad.", "hint": "SS is Sorcerer's Stone\r\nCOS is Chamber of Secrets\r\nPOA is Prisoner of Azkaban\r\nGOF is Goblet of Fire", "answer": "Ruby\r\nBook = Sorcerer's Stone\r\nCharacter = Ron\n\r\nNoey\r\nBook = Goblet of Fire\r\nCharacter = Hermione\n\r\nAmanda\r\nBook = Prisoner of Azkaban\r\nCharacter = Sirius\n\r\nDylan\r\nBook = Chamber of Secrets\r\nCharacter = Harry", "category": "Logic-Grid", "date": "01/01/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 friends, Noey, Ruby, Amanda, and Dylan are having an argument over which Harry Potter book is better: Sorcerer's (or Philosopher's) Stone, Chamber of Secrets, Prisoner of Azkaban, or Goblet of Fire. They were also fighting over which character is better: Harry, Ron, Hermione, or Sirius.\n\r\nFriends: Noey, Dylan, Ruby, Amanda\r\nBooks: Sorcerer's (or Philosopher's) Stone, Chamber of Secrets, Prisoner of Azkaban, Goblet of Fire\r\nCharacters: Harry, Hermione, Ron, Sirius. \n\r\nFind out which friend likes which character, and which book.\n\r\n1. The 4 friends are, Dylan, the one whose initial is the same as her favorite character, the one who likes the Goblet of Fire and the one who likes the Prisoner of Azkaban. \n\r\n2. Amanda likes the adult character and her favorite book is the one where her favorite character is introduced. \n\r\n3. Noey thinks that the Triwizard Tournament is the best part in the whole series.\n\r\n4. Dylan's favorite is the Chamber of Secrets. \n\r\n5. Noey's favorite character is a girl. \n\r\n6. Dylan doesn't like the way Sirius was introduced in the Prisoner of Azkaban.\n\r\n7. The Triwizard Tournament took place in the Goblet of Fire.\n\r\n8. Sirius went to school with Harry's dad.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRuby\r\nBook = Sorcerer's Stone\r\nCharacter = Ron\n\r\nNoey\r\nBook = Goblet of Fire\r\nCharacter = Hermione\n\r\nAmanda\r\nBook = Prisoner of Azkaban\r\nCharacter = Sirius\n\r\nDylan\r\nBook = Chamber of Secrets\r\nCharacter = Harry\n<|im_start|>answer\nRuby\r\nBook = Sorcerer's Stone\r\nCharacter = Ron\n\r\nNoey\r\nBook = Goblet of Fire\r\nCharacter = Hermione\n\r\nAmanda\r\nBook = Prisoner of Azkaban\r\nCharacter = Sirius\n\r\nDylan\r\nBook = Chamber of Secrets\r\nCharacter = Harry\n<|im_end|>" }, { "id": "#4041", "title": "Birthday Chocolates", "fun": 2.28, "difficulty": 1.66, "author": "mad-ade", "desc": "It is Mad Ade's birthday and he has a box of chocolates to share amongst the guests at his party. If he tries to give 3 chocs to each guest, then one guest will only end up with 2, but if he only handed out 2 per guest, he would have 15 spare for himself.\n\r\nHow many chocolates were in the box, and how many guests were at Mad Ade's party?", "hint": "No hint available.", "answer": "47 chocolates and 16 guests.", "category": "Math", "date": "05/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is Mad Ade's birthday and he has a box of chocolates to share amongst the guests at his party. If he tries to give 3 chocs to each guest, then one guest will only end up with 2, but if he only handed out 2 per guest, he would have 15 spare for himself.\n\r\nHow many chocolates were in the box, and how many guests were at Mad Ade's party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n47 chocolates and 16 guests.\n<|im_start|>answer\n47 chocolates and 16 guests.\n<|im_end|>" }, { "id": "#3493", "title": "Integer Product", "fun": 2.28, "difficulty": 1.12, "author": "magisastar", "desc": "What is the product of all non-negative integers less than or equal to 10?", "hint": "No hint available.", "answer": "Zero. 0 times anything will always equal zero.", "category": "Math", "date": "04/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the product of all non-negative integers less than or equal to 10?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZero. 0 times anything will always equal zero.\n<|im_start|>answer\nZero. 0 times anything will always equal zero.\n<|im_end|>" }, { "id": "#29912", "title": "Sum of Cubes", "fun": 2.28, "difficulty": 2.87, "author": "lessthanjake789", "desc": "What is the smallest number that is the sum of two different pairs of cubes?", "hint": "Cubic inches in a cubic foot might help.", "answer": "1729. \n\r\n1 cubed + 12 cubed = 1 + 12x12x12 = 1+1728=1729\r\n10 cubed + 9 cubed = 10x10x10 +9x9x9 = 1000 + 729 = 1729", "category": "Math", "date": "04/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest number that is the sum of two different pairs of cubes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1729. \n\r\n1 cubed + 12 cubed = 1 + 12x12x12 = 1+1728=1729\r\n10 cubed + 9 cubed = 10x10x10 +9x9x9 = 1000 + 729 = 1729\n<|im_start|>answer\n1729. \n\r\n1 cubed + 12 cubed = 1 + 12x12x12 = 1+1728=1729\r\n10 cubed + 9 cubed = 10x10x10 +9x9x9 = 1000 + 729 = 1729\n<|im_end|>" }, { "id": "#6349", "title": "Smashing Will", "fun": 2.27, "difficulty": 2.0, "author": "mad-ade", "desc": "Dick Hitch's Grandfather (the Richest antique kebab dealer in Madadia) had died recently and as part of the will he had left his favourite Grandson (Dick) a extremely valuable China figurine. Once Dick received the figurine he took it home and smashed it to pieces with a large hammer. As a result of his strange actions he was now a lot better off than before.\n\r\nHow could this be?", "hint": "No hint available.", "answer": "Because at home Dick already had a matching figurine at home, and by destroying the other one he made his unique, and as a result much more valuable.", "category": "Logic", "date": "08/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDick Hitch's Grandfather (the Richest antique kebab dealer in Madadia) had died recently and as part of the will he had left his favourite Grandson (Dick) a extremely valuable China figurine. Once Dick received the figurine he took it home and smashed it to pieces with a large hammer. As a result of his strange actions he was now a lot better off than before.\n\r\nHow could this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBecause at home Dick already had a matching figurine at home, and by destroying the other one he made his unique, and as a result much more valuable.\n<|im_start|>answer\nBecause at home Dick already had a matching figurine at home, and by destroying the other one he made his unique, and as a result much more valuable.\n<|im_end|>" }, { "id": "#22970", "title": "Grandmother 3 Times", "fun": 2.27, "difficulty": 2.01, "author": "ZOE5639", "desc": "Jill's birthday is in 3 weeks, she will be turning 60, and she is so happy to be able to spend it with her 3 daughters and 3 grandchildren.\r\nHer oldest daughter's name is Patti. Her middle daughter's name is Carol. Her youngest daughter's name is Rhonda. Jill is a grandmother 3 times over. Carol, her middle child, has an 11 year old daughter named Lindsey and an 8 year old son named J.D.\r\nIn no way, shape, form or fashion is Carol planning on having another child. Patti has a pit bull she jokes is her daughter, but no clearly visible, living, breathing, human children. Rhonda has a Dalmatian she calls her son; however, she also has no children running around. Rhonda would like to have 2 or 3 children one day. Unfortunately Patti has medical problems limiting her from being able to have kids, even though she really wants to have a child. But somehow, Jill has only 3 children and already has 3 grandchildren. HOW CAN THIS BE?", "hint": "No hint available.", "answer": "I said Patti has no clearly visible, living, breathing, human children and Rhonda has none running around either. However, Rhonda is 8 months pregnant, with a little one on the way, an already living and breathing baby. Add Carol's 2 kids and that makes 3.", "category": "Logic", "date": "05/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJill's birthday is in 3 weeks, she will be turning 60, and she is so happy to be able to spend it with her 3 daughters and 3 grandchildren.\r\nHer oldest daughter's name is Patti. Her middle daughter's name is Carol. Her youngest daughter's name is Rhonda. Jill is a grandmother 3 times over. Carol, her middle child, has an 11 year old daughter named Lindsey and an 8 year old son named J.D.\r\nIn no way, shape, form or fashion is Carol planning on having another child. Patti has a pit bull she jokes is her daughter, but no clearly visible, living, breathing, human children. Rhonda has a Dalmatian she calls her son; however, she also has no children running around. Rhonda would like to have 2 or 3 children one day. Unfortunately Patti has medical problems limiting her from being able to have kids, even though she really wants to have a child. But somehow, Jill has only 3 children and already has 3 grandchildren. HOW CAN THIS BE?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI said Patti has no clearly visible, living, breathing, human children and Rhonda has none running around either. However, Rhonda is 8 months pregnant, with a little one on the way, an already living and breathing baby. Add Carol's 2 kids and that makes 3.\n<|im_start|>answer\nI said Patti has no clearly visible, living, breathing, human children and Rhonda has none running around either. However, Rhonda is 8 months pregnant, with a little one on the way, an already living and breathing baby. Add Carol's 2 kids and that makes 3.\n<|im_end|>" }, { "id": "#13872", "title": "3 to 40", "fun": 2.27, "difficulty": 2.88, "author": "mathemagician", "desc": "I am thinking of an even number. The ratio of the sum of its digits to the product of its digits is 3 to 40 . The number is divisible by (40-3) .\n\r\nWhat is the smallest number that meets these requirements??", "hint": "Sum of the digits = 18\n\r\nProduct of the digits = 240", "answer": "5328 is the number.\n\r\n3/40 = 18/240\r\nS.O.D. = 18; P.O.D. = 240\r\n5328 / 37 = 144", "category": "Math", "date": "07/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am thinking of an even number. The ratio of the sum of its digits to the product of its digits is 3 to 40 . The number is divisible by (40-3) .\n\r\nWhat is the smallest number that meets these requirements??\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5328 is the number.\n\r\n3/40 = 18/240\r\nS.O.D. = 18; P.O.D. = 240\r\n5328 / 37 = 144\n<|im_start|>answer\n5328 is the number.\n\r\n3/40 = 18/240\r\nS.O.D. = 18; P.O.D. = 240\r\n5328 / 37 = 144\n<|im_end|>" }, { "id": "#4782", "title": "Babelfish Court", "fun": 2.27, "difficulty": 2.23, "author": "mad-ade", "desc": "Many moons ago Mad Ade lived in a block of houses called Babelfish Court.\r\nThere was a number of residents from different cultures all living together, speaking various languages. 3 speak Greek, Italian and English, 2 speak Greek and Italian, 7 speak English, 2 speak Italian and English, 1 speaks English and Greek, 1 speaks Italian only and 3 speak Greek only. How many residents are there altogether?", "hint": "No hint available.", "answer": "There are 13 Residents of Babelfish Court. \n\r\nIf we start by adding up the number of people who speak 1 language only.\r\n1 speaks Italian only \r\n3 speak Greek only\r\nEquals 4 people\n\r\nThen add up those who speak more than one language.\r\n3 speak Greek, Italian and English \r\n2 speak Greek and Italian \r\n2 speak Italian and English \r\n1 speak English and Greek\r\nEquals 8 people\n\r\n4 + 8 = 12\n\r\nHowever if you look at the people that speak more than one language 6 of them speak English but the clues tell you that 7 people speak English, hence 1 person speaks English only.\n\r\nSo \r\n4 + 8 + 1 = 13 Residents", "category": "Logic", "date": "06/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMany moons ago Mad Ade lived in a block of houses called Babelfish Court.\r\nThere was a number of residents from different cultures all living together, speaking various languages. 3 speak Greek, Italian and English, 2 speak Greek and Italian, 7 speak English, 2 speak Italian and English, 1 speaks English and Greek, 1 speaks Italian only and 3 speak Greek only. How many residents are there altogether?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 13 Residents of Babelfish Court. \n\r\nIf we start by adding up the number of people who speak 1 language only.\r\n1 speaks Italian only \r\n3 speak Greek only\r\nEquals 4 people\n\r\nThen add up those who speak more than one language.\r\n3 speak Greek, Italian and English \r\n2 speak Greek and Italian \r\n2 speak Italian and English \r\n1 speak English and Greek\r\nEquals 8 people\n\r\n4 + 8 = 12\n\r\nHowever if you look at the people that speak more than one language 6 of them speak English but the clues tell you that 7 people speak English, hence 1 person speaks English only.\n\r\nSo \r\n4 + 8 + 1 = 13 Residents\n<|im_start|>answer\nThere are 13 Residents of Babelfish Court. \n\r\nIf we start by adding up the number of people who speak 1 language only.\r\n1 speaks Italian only \r\n3 speak Greek only\r\nEquals 4 people\n\r\nThen add up those who speak more than one language.\r\n3 speak Greek, Italian and English \r\n2 speak Greek and Italian \r\n2 speak Italian and English \r\n1 speak English and Greek\r\nEquals 8 people\n\r\n4 + 8 = 12\n\r\nHowever if you look at the people that speak more than one language 6 of them speak English but the clues tell you that 7 people speak English, hence 1 person speaks English only.\n\r\nSo \r\n4 + 8 + 1 = 13 Residents\n<|im_end|>" }, { "id": "#4756", "title": "Tea, Coffee and Cola", "fun": 2.27, "difficulty": 2.1, "author": "mad-ade", "desc": "If a pound of tea has twice as much caffeine as a pound of coffee, and if a pound of tea is enough to make 160 cups of tea, and if a pound of coffee is enough to make 40 cups, and if a 12-ounce can of cola has about one-fourth the caffeine as a cup of coffee:\n\r\nHow much caffeine does one cup of tea have compared to one cup of coffee? \n\r\nHow much caffeine does one cup of tea have compared to a 12-ounce can of cola?", "hint": "No hint available.", "answer": "A cup of tea has one-half the caffeine that a cup of coffee has. \n\r\nA cup of tea has twice as much caffeine as a 12-ounce can of cola.", "category": "Math", "date": "06/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a pound of tea has twice as much caffeine as a pound of coffee, and if a pound of tea is enough to make 160 cups of tea, and if a pound of coffee is enough to make 40 cups, and if a 12-ounce can of cola has about one-fourth the caffeine as a cup of coffee:\n\r\nHow much caffeine does one cup of tea have compared to one cup of coffee? \n\r\nHow much caffeine does one cup of tea have compared to a 12-ounce can of cola?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA cup of tea has one-half the caffeine that a cup of coffee has. \n\r\nA cup of tea has twice as much caffeine as a 12-ounce can of cola.\n<|im_start|>answer\nA cup of tea has one-half the caffeine that a cup of coffee has. \n\r\nA cup of tea has twice as much caffeine as a 12-ounce can of cola.\n<|im_end|>" }, { "id": "#36910", "title": "Pepperland Preschool", "fun": 2.27, "difficulty": 0.72, "author": "beatlesgirl", "desc": "Drew, Diego, Dean, and Dominick all go to Pepperland Preschool. They each have a different teacher (Mr. Lennon, Mr. McCart, Mr. Harrison, or Mr. Starr) who makes his students color in one of the following colors: blue, red, yellow, or orange. Your job is to match each student with their teacher and then match that with the color the teacher makes his class write in. Good luck!\n\r\n1. Dominick must color in blue.\n\r\n2. Mr. Lennon doesn't like blue or orange.\n\r\n3. Mr. Starr tells his students to color in yellow.\n\r\n4. Drew's teacher is Mr. Harrison.\n\r\n5. Diego is coloring according to Mr. Starr's directions.", "hint": "No hint available.", "answer": "1. Drew's teacher is Mr. Harrison, who is making his class color in orange.\n\r\n2. Diego's teacher is Mr. Starr, who is making his class color in yellow.\n\r\n3. Dean's teacher is Mr. Lennon, who is making his class color in red.\n\r\n4. Dominick's teacher is Mr. McCart, who is making his class color in blue.", "category": "Logic-Grid", "date": "06/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDrew, Diego, Dean, and Dominick all go to Pepperland Preschool. They each have a different teacher (Mr. Lennon, Mr. McCart, Mr. Harrison, or Mr. Starr) who makes his students color in one of the following colors: blue, red, yellow, or orange. Your job is to match each student with their teacher and then match that with the color the teacher makes his class write in. Good luck!\n\r\n1. Dominick must color in blue.\n\r\n2. Mr. Lennon doesn't like blue or orange.\n\r\n3. Mr. Starr tells his students to color in yellow.\n\r\n4. Drew's teacher is Mr. Harrison.\n\r\n5. Diego is coloring according to Mr. Starr's directions.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Drew's teacher is Mr. Harrison, who is making his class color in orange.\n\r\n2. Diego's teacher is Mr. Starr, who is making his class color in yellow.\n\r\n3. Dean's teacher is Mr. Lennon, who is making his class color in red.\n\r\n4. Dominick's teacher is Mr. McCart, who is making his class color in blue.\n<|im_start|>answer\n1. Drew's teacher is Mr. Harrison, who is making his class color in orange.\n\r\n2. Diego's teacher is Mr. Starr, who is making his class color in yellow.\n\r\n3. Dean's teacher is Mr. Lennon, who is making his class color in red.\n\r\n4. Dominick's teacher is Mr. McCart, who is making his class color in blue.\n<|im_end|>" }, { "id": "#13747", "title": "Make 2003", "fun": 2.27, "difficulty": 2.91, "author": "vetriselvan", "desc": "It is easy to express 2004 as the sum of distinct positive numbers comprising the same digits: \n\r\n2004 = 725 + 752 + 527 or \r\n2004 = 617 + 671 + 716 or \r\n2004 = 509 + 590 + 905. \n\r\nIt is harder to write 2003 as the sum of distinct positive numbers with the same digits. \n\r\nWhat are they?", "hint": "You will need five numbers of three digits each.", "answer": "127 + 172 + 271 + 712 + 721 = 2003", "category": "Math", "date": "07/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is easy to express 2004 as the sum of distinct positive numbers comprising the same digits: \n\r\n2004 = 725 + 752 + 527 or \r\n2004 = 617 + 671 + 716 or \r\n2004 = 509 + 590 + 905. \n\r\nIt is harder to write 2003 as the sum of distinct positive numbers with the same digits. \n\r\nWhat are they?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n127 + 172 + 271 + 712 + 721 = 2003\n<|im_start|>answer\n127 + 172 + 271 + 712 + 721 = 2003\n<|im_end|>" }, { "id": "#12006", "title": "Of Great Interest", "fun": 2.27, "difficulty": 2.31, "author": "jimbo", "desc": "The Bank of Tasmania was offering a special deal for new customers. \"Open a new account and deposit $1 with us for 1 year and we will give you 100% interest.\" was the offer. \r\nNow Jimbo, being quick to spot a deal popped in to see the manager and enquired, \"Can I have my interest added quarterly?\" \r\n\"Why not?\" said the manager. \r\n\"What about monthly?\" suggested Jimbo. \r\n\"OK\", said the manager. \r\n\"How about daily...hourly...by the minute....?\" \r\n\"OK...OK...OK, whatever\", said the manager. \r\nJimbo was quite pleased with this deal. \r\nWhat is the maximum amount (rounded to the nearest cent) that Jimbo could find in his account at the end of the year?", "hint": "No hint available.", "answer": "Compound Interest = P(1+r)^n\r\nP=1 ($1). Since rate = 100% , r = 1.\r\nFor n periods per annum, rate is therefore r = 1/n\r\nThe limit as n approaches infinity of (1 + 1/n)^n = e (exponential growth constant) = 2.71828..\r\nJimbo would have at the most $2.72 to the nearest cent.", "category": "Math", "date": "04/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Bank of Tasmania was offering a special deal for new customers. \"Open a new account and deposit $1 with us for 1 year and we will give you 100% interest.\" was the offer. \r\nNow Jimbo, being quick to spot a deal popped in to see the manager and enquired, \"Can I have my interest added quarterly?\" \r\n\"Why not?\" said the manager. \r\n\"What about monthly?\" suggested Jimbo. \r\n\"OK\", said the manager. \r\n\"How about daily...hourly...by the minute....?\" \r\n\"OK...OK...OK, whatever\", said the manager. \r\nJimbo was quite pleased with this deal. \r\nWhat is the maximum amount (rounded to the nearest cent) that Jimbo could find in his account at the end of the year?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCompound Interest = P(1+r)^n\r\nP=1 ($1). Since rate = 100% , r = 1.\r\nFor n periods per annum, rate is therefore r = 1/n\r\nThe limit as n approaches infinity of (1 + 1/n)^n = e (exponential growth constant) = 2.71828..\r\nJimbo would have at the most $2.72 to the nearest cent.\n<|im_start|>answer\nCompound Interest = P(1+r)^n\r\nP=1 ($1). Since rate = 100% , r = 1.\r\nFor n periods per annum, rate is therefore r = 1/n\r\nThe limit as n approaches infinity of (1 + 1/n)^n = e (exponential growth constant) = 2.71828..\r\nJimbo would have at the most $2.72 to the nearest cent.\n<|im_end|>" }, { "id": "#2507", "title": "Log Cutter", "fun": 2.27, "difficulty": 1.03, "author": "Cascas", "desc": "Grul charges 5 dollars to cut a wooden log into two pieces. How much will he charge to cut a log into four pieces?", "hint": "No hint available.", "answer": "15 dollars (3 cuts at $5/cut)", "category": "Math", "date": "03/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrul charges 5 dollars to cut a wooden log into two pieces. How much will he charge to cut a log into four pieces?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15 dollars (3 cuts at $5/cut)\n<|im_start|>answer\n15 dollars (3 cuts at $5/cut)\n<|im_end|>" }, { "id": "#26679", "title": "Just a Thought", "fun": 2.27, "difficulty": 0.62, "author": "HogwartsGirl05", "desc": "Three friends were studying at the library. Their names were Helga, Johannes, and Sebastian. Each person was studying a different subject (History, Journalism, and Science) and checked out a different number of books (2, 5, and 9.) The computer at the library was down for repairs that day. The Librarian wrote down the titles of the books and the names of the students. The next day when the computer was back on-line she had forgotten who checked out how many books and on which topic. Can you help her get this sorted out?\n\r\nHere's what she remembers :\n\r\n1. The students were not studying subjects that started with the same letter as their names.\r\n2.The one who checked out the books on Journalism, checked out an even number of books.\r\n3. The number of books about history was not a square number.\r\n4.When he's not writing papers on the fall of Rome, Sebastian likes to read about ancient civilizations.", "hint": "No hint available.", "answer": "Student Subject Number\r\nHelga Journalism 2\r\nJohannes Science 9\r\nSebastian History 5", "category": "Logic-Grid", "date": "11/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends were studying at the library. Their names were Helga, Johannes, and Sebastian. Each person was studying a different subject (History, Journalism, and Science) and checked out a different number of books (2, 5, and 9.) The computer at the library was down for repairs that day. The Librarian wrote down the titles of the books and the names of the students. The next day when the computer was back on-line she had forgotten who checked out how many books and on which topic. Can you help her get this sorted out?\n\r\nHere's what she remembers :\n\r\n1. The students were not studying subjects that started with the same letter as their names.\r\n2.The one who checked out the books on Journalism, checked out an even number of books.\r\n3. The number of books about history was not a square number.\r\n4.When he's not writing papers on the fall of Rome, Sebastian likes to read about ancient civilizations.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStudent Subject Number\r\nHelga Journalism 2\r\nJohannes Science 9\r\nSebastian History 5\n<|im_start|>answer\nStudent Subject Number\r\nHelga Journalism 2\r\nJohannes Science 9\r\nSebastian History 5\n<|im_end|>" }, { "id": "#26735", "title": "Knight's Tour II", "fun": 2.27, "difficulty": 2.93, "author": "kiss", "desc": "The knight left Breadland, and went to a neighboring kingdom named Cakeland. Cakeland is much similar to Breadland, but unlike Breadland, Cakeland is 12x4. Cakelanders like cake, as well as Breadlanders like bread.\n\r\nThe knight was on a square of Cakeland, he wanted to visit each square of Cakeland exactly once, and return to the square he was originally on. Each step, the knight moved to one of the squares nearest to that on which it stands but the queen can't reach.\n\r\nThe knight thought that since Cakeland has an even number of squares, he could achieve his goal this time.\n\r\nHowever, the knight still failed.\n\r\nDo you know why?", "hint": "If you can't figure it out, try coloring Cakeland in another way:\n\r\na d a d...\r\nb c b c...\r\nc b c b...\r\nd a d a...\n\r\nThen there are 12 squares of each color.", "answer": "Color Cakeland as follows, i.e. each column alternatively abcd and dcba:\n\r\na d a d...\r\nb c b c...\r\nc b c b...\r\nd a d a...\n\r\nThen there are 12 squares of each color. Again we suppose that the lower left corner is black. Then a and c are normal white squares while b and d are normal black squares. Additionally, we notice that each a-square must be preceded and followed by a b-square. This will require more b-squares than a-squares, but there are 12 squares of each color.\n\r\nTherefore, the knight couldn't achieve his goal.", "category": "Math", "date": "11/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe knight left Breadland, and went to a neighboring kingdom named Cakeland. Cakeland is much similar to Breadland, but unlike Breadland, Cakeland is 12x4. Cakelanders like cake, as well as Breadlanders like bread.\n\r\nThe knight was on a square of Cakeland, he wanted to visit each square of Cakeland exactly once, and return to the square he was originally on. Each step, the knight moved to one of the squares nearest to that on which it stands but the queen can't reach.\n\r\nThe knight thought that since Cakeland has an even number of squares, he could achieve his goal this time.\n\r\nHowever, the knight still failed.\n\r\nDo you know why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nColor Cakeland as follows, i.e. each column alternatively abcd and dcba:\n\r\na d a d...\r\nb c b c...\r\nc b c b...\r\nd a d a...\n\r\nThen there are 12 squares of each color. Again we suppose that the lower left corner is black. Then a and c are normal white squares while b and d are normal black squares. Additionally, we notice that each a-square must be preceded and followed by a b-square. This will require more b-squares than a-squares, but there are 12 squares of each color.\n\r\nTherefore, the knight couldn't achieve his goal.\n<|im_start|>answer\nColor Cakeland as follows, i.e. each column alternatively abcd and dcba:\n\r\na d a d...\r\nb c b c...\r\nc b c b...\r\nd a d a...\n\r\nThen there are 12 squares of each color. Again we suppose that the lower left corner is black. Then a and c are normal white squares while b and d are normal black squares. Additionally, we notice that each a-square must be preceded and followed by a b-square. This will require more b-squares than a-squares, but there are 12 squares of each color.\n\r\nTherefore, the knight couldn't achieve his goal.\n<|im_end|>" }, { "id": "#29198", "title": "Soccer Seats", "fun": 2.27, "difficulty": 2.26, "author": "shenqiang", "desc": "The Centerville Soccer Field has 2 sections of seats, with 20 rows in each section. Each section has the same number of seats. There are fewer seats in the first row (row A) than in the last row (row T). The number of seats increases from row A to row T according to a pattern. The table below shows the number of seats for rows G through O of one section. Seats for the coming event to raise money for a homeless shelter sell for $3 each. All expenses will be paid by the local bank.\n\r\nRow Number of Seats \r\nG 72 \r\nH 75 \r\nI 78 \r\nJ 83 \r\nK 86 \r\nL 89 \r\nM 94 \r\nN 97 \r\nO 100 \n\r\nIf all the seats are sold, how much money will be raised?", "hint": "Start by using the chart to establish the pattern of the seats to solve this multi-step problem.", "answer": "First, the number of seats increases in each row by 3, 3, then 5. Working backward from row G, subtract 5, then 3, then 3, and so forth. Working ahead from row O, add 5, then 3, then 3, and so forth. See the chart below for the results. \r\nSecond, add the number of seats in each row to get the total seats per section: 86*21-122=1,684. \r\nThird, multiply the number of seats in each section by 2 for the total seats in the stadium: 3,368. \r\nLast, multiply the total number of seats by 3 for the amount of money raised: $10,104.\n\r\nRow Number of Seats \r\nA 50 \r\nB 53 \r\nC 56 \r\nD 61 \r\nE 64 \r\nF 67 \r\nG 72 \r\nH 75 \r\nI 78 \r\nJ 83 \r\nK 86 \r\nL 89 \r\nM 94 \r\nN 97 \r\nO 100 \r\nP 105 \r\nQ 108 \r\nR 111 \r\nS 116 \r\nT 119", "category": "Math", "date": "03/19/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Centerville Soccer Field has 2 sections of seats, with 20 rows in each section. Each section has the same number of seats. There are fewer seats in the first row (row A) than in the last row (row T). The number of seats increases from row A to row T according to a pattern. The table below shows the number of seats for rows G through O of one section. Seats for the coming event to raise money for a homeless shelter sell for $3 each. All expenses will be paid by the local bank.\n\r\nRow Number of Seats \r\nG 72 \r\nH 75 \r\nI 78 \r\nJ 83 \r\nK 86 \r\nL 89 \r\nM 94 \r\nN 97 \r\nO 100 \n\r\nIf all the seats are sold, how much money will be raised?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, the number of seats increases in each row by 3, 3, then 5. Working backward from row G, subtract 5, then 3, then 3, and so forth. Working ahead from row O, add 5, then 3, then 3, and so forth. See the chart below for the results. \r\nSecond, add the number of seats in each row to get the total seats per section: 86*21-122=1,684. \r\nThird, multiply the number of seats in each section by 2 for the total seats in the stadium: 3,368. \r\nLast, multiply the total number of seats by 3 for the amount of money raised: $10,104.\n\r\nRow Number of Seats \r\nA 50 \r\nB 53 \r\nC 56 \r\nD 61 \r\nE 64 \r\nF 67 \r\nG 72 \r\nH 75 \r\nI 78 \r\nJ 83 \r\nK 86 \r\nL 89 \r\nM 94 \r\nN 97 \r\nO 100 \r\nP 105 \r\nQ 108 \r\nR 111 \r\nS 116 \r\nT 119\n<|im_start|>answer\nFirst, the number of seats increases in each row by 3, 3, then 5. Working backward from row G, subtract 5, then 3, then 3, and so forth. Working ahead from row O, add 5, then 3, then 3, and so forth. See the chart below for the results. \r\nSecond, add the number of seats in each row to get the total seats per section: 86*21-122=1,684. \r\nThird, multiply the number of seats in each section by 2 for the total seats in the stadium: 3,368. \r\nLast, multiply the total number of seats by 3 for the amount of money raised: $10,104.\n\r\nRow Number of Seats \r\nA 50 \r\nB 53 \r\nC 56 \r\nD 61 \r\nE 64 \r\nF 67 \r\nG 72 \r\nH 75 \r\nI 78 \r\nJ 83 \r\nK 86 \r\nL 89 \r\nM 94 \r\nN 97 \r\nO 100 \r\nP 105 \r\nQ 108 \r\nR 111 \r\nS 116 \r\nT 119\n<|im_end|>" }, { "id": "#22602", "title": "1 Line Makes it True", "fun": 2.27, "difficulty": 1.69, "author": "settra626", "desc": "Take this equation:\n\r\nll-llll=ll\n\r\nNow move 1 line to make it true.", "hint": "The signs count.", "answer": "ll=llll-ll is the answer (You move 1 line from the equal sign and add it to the subtraction sign) this answer would technically be 2=4-2.", "category": "Math", "date": "05/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTake this equation:\n\r\nll-llll=ll\n\r\nNow move 1 line to make it true.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nll=llll-ll is the answer (You move 1 line from the equal sign and add it to the subtraction sign) this answer would technically be 2=4-2.\n<|im_start|>answer\nll=llll-ll is the answer (You move 1 line from the equal sign and add it to the subtraction sign) this answer would technically be 2=4-2.\n<|im_end|>" }, { "id": "#48954", "title": "What Does It Mean?", "fun": 2.27, "difficulty": 2.72, "author": "Mathgeek007", "desc": "There was a body pump class that lasted a long time, but it always changed. The instructor was a very smart person and liked to throw puzzles at the students. About 15 minutes into the class, one kid asked how much time there was left in the class. He said: \"Right now? Oh, I'd say seven.\" The kid was confused and knew the instructor was never going to tell anybody.\n\r\nAnother 5 minutes in, another kid asked how much time was left. The instructor said, \"About five now.\" Confused, the kid went back and the class continued.\n\r\nTen minutes later, a perplexed pupil in the front asked how much time was left. The instructor said, \"I think it's about three.\"\n\r\nSuddenly, the pupil clicked into what the puzzle was and how much time there was left of the class and how long the class was.\n\r\nHow much time was left of the class?", "hint": "No hint available.", "answer": "90 minutes.\n\r\nWhen the first student asked, 15 minutes in, the instructor said \"Seven\". 15 times 7 is 105, the amount of time left in the class.\n\r\nThe second student asked 5 minutes later (20 minutes in) and the instructor said \"Five.\" 20 times 5 is 100, the number of minutes left in the class.\n\r\nThe last student got \"Three\" when he asked again, at the 30 minute mark. 30 times 3 is 90, the number of minutes left in the class and the answer to this brain teaser.\n\r\nThe class was two hours long.", "category": "Math", "date": "08/15/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a body pump class that lasted a long time, but it always changed. The instructor was a very smart person and liked to throw puzzles at the students. About 15 minutes into the class, one kid asked how much time there was left in the class. He said: \"Right now? Oh, I'd say seven.\" The kid was confused and knew the instructor was never going to tell anybody.\n\r\nAnother 5 minutes in, another kid asked how much time was left. The instructor said, \"About five now.\" Confused, the kid went back and the class continued.\n\r\nTen minutes later, a perplexed pupil in the front asked how much time was left. The instructor said, \"I think it's about three.\"\n\r\nSuddenly, the pupil clicked into what the puzzle was and how much time there was left of the class and how long the class was.\n\r\nHow much time was left of the class?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n90 minutes.\n\r\nWhen the first student asked, 15 minutes in, the instructor said \"Seven\". 15 times 7 is 105, the amount of time left in the class.\n\r\nThe second student asked 5 minutes later (20 minutes in) and the instructor said \"Five.\" 20 times 5 is 100, the number of minutes left in the class.\n\r\nThe last student got \"Three\" when he asked again, at the 30 minute mark. 30 times 3 is 90, the number of minutes left in the class and the answer to this brain teaser.\n\r\nThe class was two hours long.\n<|im_start|>answer\n90 minutes.\n\r\nWhen the first student asked, 15 minutes in, the instructor said \"Seven\". 15 times 7 is 105, the amount of time left in the class.\n\r\nThe second student asked 5 minutes later (20 minutes in) and the instructor said \"Five.\" 20 times 5 is 100, the number of minutes left in the class.\n\r\nThe last student got \"Three\" when he asked again, at the 30 minute mark. 30 times 3 is 90, the number of minutes left in the class and the answer to this brain teaser.\n\r\nThe class was two hours long.\n<|im_end|>" }, { "id": "#19377", "title": "Mad Ade's Simple Math", "fun": 2.27, "difficulty": 2.73, "author": "Mad-Ade", "desc": "Mad Ade noticed that he could arrange the five odd digits (1,3,5,7,9) into a five-digit number, such that the first two digits (as a 2-digit number) times the last two digits (as a 2-digit number) minus the center digit results in a number composed of repetitions of one digit.\r\nMad Ade noted there were two possible answers.\r\nWhat are they?", "hint": "No hint available.", "answer": "Answers are 39157 and 57139\r\n39*57= 2223-1= 2222\r\n57*39= 2223-1= 2222", "category": "Math", "date": "11/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade noticed that he could arrange the five odd digits (1,3,5,7,9) into a five-digit number, such that the first two digits (as a 2-digit number) times the last two digits (as a 2-digit number) minus the center digit results in a number composed of repetitions of one digit.\r\nMad Ade noted there were two possible answers.\r\nWhat are they?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswers are 39157 and 57139\r\n39*57= 2223-1= 2222\r\n57*39= 2223-1= 2222\n<|im_start|>answer\nAnswers are 39157 and 57139\r\n39*57= 2223-1= 2222\r\n57*39= 2223-1= 2222\n<|im_end|>" }, { "id": "#18627", "title": "Madadian Dog Meat and Glue Factory Derby", "fun": 2.27, "difficulty": 1.77, "author": "mad-ade", "desc": "Five horses ran in the Madadian Dog Meat and Glue Factory derby.\n\r\nThere were no ties. \n\r\nGloostik did not come first. \n\r\nTasty Morsel was neither first nor last. \n\r\nMilkmans Treat came in one place after Gloostik. \n\r\nPotential Kebab was not second. \n\r\nRovers Dinner was two places below Potential Kebab.\r\nIn what order did the horses finish?", "hint": "No hint available.", "answer": "Let's find the possible places horses can finish. Possibilities are: \r\nGloostik - 2,3,4 (not 5th as Milkmans Treat came one place after him) \r\nTasty Morsel - 2,3,4 \r\nMilkmans Treat - 3,4,5 \r\nPotential Kebab - 1,3 (not 4th & 5th as Rovers Dinner is two place after him) \r\nRovers Dinner - 3,5 \n\r\nSo the result is: \r\n1 Potential Kebab \r\n2 Tasty Morsel \r\n3 Rovers Dinner \r\n4 Gloostik \r\n5 Milkmans Treat", "category": "Logic", "date": "08/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive horses ran in the Madadian Dog Meat and Glue Factory derby.\n\r\nThere were no ties. \n\r\nGloostik did not come first. \n\r\nTasty Morsel was neither first nor last. \n\r\nMilkmans Treat came in one place after Gloostik. \n\r\nPotential Kebab was not second. \n\r\nRovers Dinner was two places below Potential Kebab.\r\nIn what order did the horses finish?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet's find the possible places horses can finish. Possibilities are: \r\nGloostik - 2,3,4 (not 5th as Milkmans Treat came one place after him) \r\nTasty Morsel - 2,3,4 \r\nMilkmans Treat - 3,4,5 \r\nPotential Kebab - 1,3 (not 4th & 5th as Rovers Dinner is two place after him) \r\nRovers Dinner - 3,5 \n\r\nSo the result is: \r\n1 Potential Kebab \r\n2 Tasty Morsel \r\n3 Rovers Dinner \r\n4 Gloostik \r\n5 Milkmans Treat\n<|im_start|>answer\nLet's find the possible places horses can finish. Possibilities are: \r\nGloostik - 2,3,4 (not 5th as Milkmans Treat came one place after him) \r\nTasty Morsel - 2,3,4 \r\nMilkmans Treat - 3,4,5 \r\nPotential Kebab - 1,3 (not 4th & 5th as Rovers Dinner is two place after him) \r\nRovers Dinner - 3,5 \n\r\nSo the result is: \r\n1 Potential Kebab \r\n2 Tasty Morsel \r\n3 Rovers Dinner \r\n4 Gloostik \r\n5 Milkmans Treat\n<|im_end|>" }, { "id": "#10449", "title": "Creatures", "fun": 2.27, "difficulty": 2.48, "author": "skoolkid", "desc": "In a distant planet called Zlymph (pronounced: zl-i-mf) there were 6 different creatures there. \n\r\nOne was called Fymphy.\r\nAnother was called Lymfry.\r\nYet another was called Phyzygwy.\r\nThe next one was called Blympy.\r\nHyjyky was the name of another one.\r\nFinally, there was the Jygzyll.\n\r\nWhat you are trying to find out is the following things using the clues after this:\n\r\nWhat they enjoyed to eat,\r\nWhat they hated to eat,\r\nand what planet they were originally from.\n\r\nChoose from the following:\n\r\nFood: Humans, other creatures, dragons, dirt from the planet, metal, and salt.\n\r\nPlanets: Venus, Pluto, Sun, Mercury, Jupiter, and Uranus.\n\r\nCLUES!\r\n1. The one who hates dirt from the planet was from Uranus.\r\n2. The Blympy hates what the Jygzyll loves.\r\n3. The one who loves humans is from a gas planet.\r\n4. The Fymphy should be dehydrated.\r\n5. The Lymfry hates what the Fymphy loves.\r\n6. The one who hates humans is from Pluto.\r\n7. The one who loves dragons is from Venus.\r\n8. The Jygzyll hates what the Lymfry loves.\r\n9. The Hyjyky loves what the Phyzygwy hates.\r\n10. The Hyjyky hates what the Blympy loves.\r\n11. The Blympy hates what the Phyzygwy loves.\r\n12. The Jygzyll loves what the Fymphy hates.\r\n13. The Fymphy loves an organism that is both an herbivore and a carnivore.\r\n14. The Lymfry loves a mythical creature.\r\n15. No human can get near the place the Blympy is from.\r\n16. The Phyzygwy is from Mercury.\r\n17. The Blympy loves dirt from the planet.", "hint": "No hint available.", "answer": "Fymphy: Loves salt (clue 4), hates humans (clue 6), and is from Pluto (clue 6).\n\r\nLymfry: Loves dragons (clue 14), Hates salt (clue 4/5), and is from Venus (7).\n\r\nBlympy: Loves dirt from the planet (clue 17), hates metal, (clue 11), and is from the sun (clue 15).\n\r\nJygzyll: Loves humans (clue 12), hates dragons (clue 8), and is from Jupiter (clue 3).\n\r\nPhyzygwy: Loves metal (clue 11), hates other creatures (clue 9), and is from Mercury (clue 16).\n\r\nHyjyky: Loves other creatures (clue 9), hates dirt from the planet (clue 10), and is from Uranus (clue 1).", "category": "Logic", "date": "02/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a distant planet called Zlymph (pronounced: zl-i-mf) there were 6 different creatures there. \n\r\nOne was called Fymphy.\r\nAnother was called Lymfry.\r\nYet another was called Phyzygwy.\r\nThe next one was called Blympy.\r\nHyjyky was the name of another one.\r\nFinally, there was the Jygzyll.\n\r\nWhat you are trying to find out is the following things using the clues after this:\n\r\nWhat they enjoyed to eat,\r\nWhat they hated to eat,\r\nand what planet they were originally from.\n\r\nChoose from the following:\n\r\nFood: Humans, other creatures, dragons, dirt from the planet, metal, and salt.\n\r\nPlanets: Venus, Pluto, Sun, Mercury, Jupiter, and Uranus.\n\r\nCLUES!\r\n1. The one who hates dirt from the planet was from Uranus.\r\n2. The Blympy hates what the Jygzyll loves.\r\n3. The one who loves humans is from a gas planet.\r\n4. The Fymphy should be dehydrated.\r\n5. The Lymfry hates what the Fymphy loves.\r\n6. The one who hates humans is from Pluto.\r\n7. The one who loves dragons is from Venus.\r\n8. The Jygzyll hates what the Lymfry loves.\r\n9. The Hyjyky loves what the Phyzygwy hates.\r\n10. The Hyjyky hates what the Blympy loves.\r\n11. The Blympy hates what the Phyzygwy loves.\r\n12. The Jygzyll loves what the Fymphy hates.\r\n13. The Fymphy loves an organism that is both an herbivore and a carnivore.\r\n14. The Lymfry loves a mythical creature.\r\n15. No human can get near the place the Blympy is from.\r\n16. The Phyzygwy is from Mercury.\r\n17. The Blympy loves dirt from the planet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFymphy: Loves salt (clue 4), hates humans (clue 6), and is from Pluto (clue 6).\n\r\nLymfry: Loves dragons (clue 14), Hates salt (clue 4/5), and is from Venus (7).\n\r\nBlympy: Loves dirt from the planet (clue 17), hates metal, (clue 11), and is from the sun (clue 15).\n\r\nJygzyll: Loves humans (clue 12), hates dragons (clue 8), and is from Jupiter (clue 3).\n\r\nPhyzygwy: Loves metal (clue 11), hates other creatures (clue 9), and is from Mercury (clue 16).\n\r\nHyjyky: Loves other creatures (clue 9), hates dirt from the planet (clue 10), and is from Uranus (clue 1).\n<|im_start|>answer\nFymphy: Loves salt (clue 4), hates humans (clue 6), and is from Pluto (clue 6).\n\r\nLymfry: Loves dragons (clue 14), Hates salt (clue 4/5), and is from Venus (7).\n\r\nBlympy: Loves dirt from the planet (clue 17), hates metal, (clue 11), and is from the sun (clue 15).\n\r\nJygzyll: Loves humans (clue 12), hates dragons (clue 8), and is from Jupiter (clue 3).\n\r\nPhyzygwy: Loves metal (clue 11), hates other creatures (clue 9), and is from Mercury (clue 16).\n\r\nHyjyky: Loves other creatures (clue 9), hates dirt from the planet (clue 10), and is from Uranus (clue 1).\n<|im_end|>" }, { "id": "#19153", "title": "Cornerstones !!!", "fun": 2.27, "difficulty": 1.83, "author": "lesternoronha1", "desc": "Six boys A, B, C, D, E and F have to stand in a row. B and C are together, but they cannot be at either of the ends. F is at the right of E and there is exactly one boy between them. D cannot be next to F. Who should always stand at one of the ends?", "hint": "No hint available.", "answer": "D must always stand at one of the ends.\n\r\nThe observations that can be derived are:-\r\n1) B and C are together, but they cannot be at either of the ends.\r\n2) F is at the right of E and there is exactly one boy between them.\r\n3) D cannot be next to F.\n\r\nLet us first number the positions from 1 to 6(from left to right), place E and F in different positions and analyze the cases.\n\r\nFrom observation 2, we can derive the following cases:-\n\r\nCase 1 2 3 4 5 6\r\n1 _ _ _ E _ F\t\r\n2 _ _ E _ F _\r\n3 _ E _ F _ _\r\n4 E _ F _ _ _ \r\nwhere the blank spaces indicate positions where the others stand.\n\r\nConsidering each of the above cases individually we have,\n\r\nCase 1 : B, C and D cannot go into position 5, since B and C are together always and D cannot be next to F from observations 1 and 3 respectively. Hence A must go into position 5 and D into position 1 (since from observation 1, B and C cannot be at either of the ends).\n\r\nCase 2 : B and C cannot be given positions 1 and 2 (since from observation 1, B and C cannot be at either of the ends), neither do they fit into any other positions in this case. Hence this case is not possible.\n\r\nCase 3 : B and C cannot be given positions 5 and 6 (since from observation 1, B and C cannot be at either of the ends), neither do they fit into any other positions in this case. Hence this case is also not possible.\n\r\nCase 4 : B, C and D cannot go into position 2, since B and C are together always and D cannot be next to F from observations 1 and 3 respectively. Hence A must go into position 2 and D into position 6 (since from observation 1, B and C cannot be at either of the ends).\n\r\nFrom the above 4 cases it is clear that one of the cornerstones must always be D and the other can be either of E or F.", "category": "Logic", "date": "10/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix boys A, B, C, D, E and F have to stand in a row. B and C are together, but they cannot be at either of the ends. F is at the right of E and there is exactly one boy between them. D cannot be next to F. Who should always stand at one of the ends?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nD must always stand at one of the ends.\n\r\nThe observations that can be derived are:-\r\n1) B and C are together, but they cannot be at either of the ends.\r\n2) F is at the right of E and there is exactly one boy between them.\r\n3) D cannot be next to F.\n\r\nLet us first number the positions from 1 to 6(from left to right), place E and F in different positions and analyze the cases.\n\r\nFrom observation 2, we can derive the following cases:-\n\r\nCase 1 2 3 4 5 6\r\n1 _ _ _ E _ F\t\r\n2 _ _ E _ F _\r\n3 _ E _ F _ _\r\n4 E _ F _ _ _ \r\nwhere the blank spaces indicate positions where the others stand.\n\r\nConsidering each of the above cases individually we have,\n\r\nCase 1 : B, C and D cannot go into position 5, since B and C are together always and D cannot be next to F from observations 1 and 3 respectively. Hence A must go into position 5 and D into position 1 (since from observation 1, B and C cannot be at either of the ends).\n\r\nCase 2 : B and C cannot be given positions 1 and 2 (since from observation 1, B and C cannot be at either of the ends), neither do they fit into any other positions in this case. Hence this case is not possible.\n\r\nCase 3 : B and C cannot be given positions 5 and 6 (since from observation 1, B and C cannot be at either of the ends), neither do they fit into any other positions in this case. Hence this case is also not possible.\n\r\nCase 4 : B, C and D cannot go into position 2, since B and C are together always and D cannot be next to F from observations 1 and 3 respectively. Hence A must go into position 2 and D into position 6 (since from observation 1, B and C cannot be at either of the ends).\n\r\nFrom the above 4 cases it is clear that one of the cornerstones must always be D and the other can be either of E or F.\n<|im_start|>answer\nD must always stand at one of the ends.\n\r\nThe observations that can be derived are:-\r\n1) B and C are together, but they cannot be at either of the ends.\r\n2) F is at the right of E and there is exactly one boy between them.\r\n3) D cannot be next to F.\n\r\nLet us first number the positions from 1 to 6(from left to right), place E and F in different positions and analyze the cases.\n\r\nFrom observation 2, we can derive the following cases:-\n\r\nCase 1 2 3 4 5 6\r\n1 _ _ _ E _ F\t\r\n2 _ _ E _ F _\r\n3 _ E _ F _ _\r\n4 E _ F _ _ _ \r\nwhere the blank spaces indicate positions where the others stand.\n\r\nConsidering each of the above cases individually we have,\n\r\nCase 1 : B, C and D cannot go into position 5, since B and C are together always and D cannot be next to F from observations 1 and 3 respectively. Hence A must go into position 5 and D into position 1 (since from observation 1, B and C cannot be at either of the ends).\n\r\nCase 2 : B and C cannot be given positions 1 and 2 (since from observation 1, B and C cannot be at either of the ends), neither do they fit into any other positions in this case. Hence this case is not possible.\n\r\nCase 3 : B and C cannot be given positions 5 and 6 (since from observation 1, B and C cannot be at either of the ends), neither do they fit into any other positions in this case. Hence this case is also not possible.\n\r\nCase 4 : B, C and D cannot go into position 2, since B and C are together always and D cannot be next to F from observations 1 and 3 respectively. Hence A must go into position 2 and D into position 6 (since from observation 1, B and C cannot be at either of the ends).\n\r\nFrom the above 4 cases it is clear that one of the cornerstones must always be D and the other can be either of E or F.\n<|im_end|>" }, { "id": "#5730", "title": "£7.11 At The 7-11 store", "fun": 2.27, "difficulty": 2.37, "author": "mad-ade", "desc": "Mad Ade entered his local 7-11 store to purchase some provisions. He picked up some \"dead rat and scabby monkey\" flavoured crisps (potato chips for those of you who are American), a large bottle of pickled onion flavoured pop (soda), a left handed toilet roll and a tub of Kebab flavoured ice cream. At the checkout Mad Ade was told that the cost was £7.11. Mad Ade was curious that the cost was the same as the store name, so he inquired as to how the figure was derived. The acne riddled clerk said that he had simply multiplied the prices of the four individual items. Mad Ade complained as this had been done to him in another teaser (Entitled \"Five Pound Seventy Pence\" Teaser #4848), only with three amounts instead of four. He protested that the four prices should have been ADDED, not MULTIPLIED. The spotty clerk said that that was OK with him, but, the result was still the same: exactly £7.11.\n\r\nWhat were the prices of the four items?", "hint": "No hint available.", "answer": "The prices are: £1.20, £1.25, £1.50, and £3.16", "category": "Math", "date": "07/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade entered his local 7-11 store to purchase some provisions. He picked up some \"dead rat and scabby monkey\" flavoured crisps (potato chips for those of you who are American), a large bottle of pickled onion flavoured pop (soda), a left handed toilet roll and a tub of Kebab flavoured ice cream. At the checkout Mad Ade was told that the cost was £7.11. Mad Ade was curious that the cost was the same as the store name, so he inquired as to how the figure was derived. The acne riddled clerk said that he had simply multiplied the prices of the four individual items. Mad Ade complained as this had been done to him in another teaser (Entitled \"Five Pound Seventy Pence\" Teaser #4848), only with three amounts instead of four. He protested that the four prices should have been ADDED, not MULTIPLIED. The spotty clerk said that that was OK with him, but, the result was still the same: exactly £7.11.\n\r\nWhat were the prices of the four items?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe prices are: £1.20, £1.25, £1.50, and £3.16\n<|im_start|>answer\nThe prices are: £1.20, £1.25, £1.50, and £3.16\n<|im_end|>" }, { "id": "#31996", "title": "2^1100???", "fun": 2.27, "difficulty": 2.98, "author": "HiImDavid", "desc": "Your professor prepared a rigorous 150-question final exam to be completed in under 30 minutes, but unfortunately, he seems to have misplaced it, and can only remember one problem. So, he has decided to waive your final exam, if you can answer the one question he can remember from his original exam.\n\r\nWhich is greater, 2^1100 or 3^700? Approximately how many times greater is it (to the nearest 10)?", "hint": "The numbers are too big to deal with on a normal graphics calculator scale, think of it in terms of powers of ten.", "answer": "3^700 is greater, by approximately 710 times (711.0220569 to be exact).\n\r\nTo start, one must realize these numbers are too big to deal with by hand. So, one must use exponents and the \"log\" function on a calculator.\n\r\n2^1100=10^a\r\n2^x=10^1\r\nlog(10)/log(2)=x\r\n3.321928095=x\r\n1100/x=331.1329952\r\n2^3.321928095=10^1\r\n2^(331.132995*3.321928095)=10^(331.132995*1)\r\n2^1100=10^331.132995\n\r\nNow that we know what 2^1100 equals, apply the same concept to 3^700.\n\r\n3^700=10^b\r\n3^y=10^1\r\nlog(10)/log(3)=y\r\n2.095903274=y\r\n3^2.095903274=10^1\r\n3^(333.9848783*2.095903274)=10^(333.9848783*1)\r\n3^700=10^333.9848783\n\r\nSo, now we have 2^1100 and 3^700 in terms of \"ten to the power of\".\r\n2^1100=10^331.1379952\r\n3^700=10^333.9848783\n\r\nObviously, 3^700 is greater. To figure out how much greater, requires a little more work, but not much.\n\r\nFirst, subtract the exponents.\r\n333.9848783-331.1379952\r\nThis equals 2.851883073\r\nThen, take 10^2.851883073\r\nThis equals 711.0220569, which is around 710.\n\r\nThus, 3^700 is approximately 710 times greater than 2^1100. Congratulations, you passed your professor's exam.", "category": "Math", "date": "07/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour professor prepared a rigorous 150-question final exam to be completed in under 30 minutes, but unfortunately, he seems to have misplaced it, and can only remember one problem. So, he has decided to waive your final exam, if you can answer the one question he can remember from his original exam.\n\r\nWhich is greater, 2^1100 or 3^700? Approximately how many times greater is it (to the nearest 10)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3^700 is greater, by approximately 710 times (711.0220569 to be exact).\n\r\nTo start, one must realize these numbers are too big to deal with by hand. So, one must use exponents and the \"log\" function on a calculator.\n\r\n2^1100=10^a\r\n2^x=10^1\r\nlog(10)/log(2)=x\r\n3.321928095=x\r\n1100/x=331.1329952\r\n2^3.321928095=10^1\r\n2^(331.132995*3.321928095)=10^(331.132995*1)\r\n2^1100=10^331.132995\n\r\nNow that we know what 2^1100 equals, apply the same concept to 3^700.\n\r\n3^700=10^b\r\n3^y=10^1\r\nlog(10)/log(3)=y\r\n2.095903274=y\r\n3^2.095903274=10^1\r\n3^(333.9848783*2.095903274)=10^(333.9848783*1)\r\n3^700=10^333.9848783\n\r\nSo, now we have 2^1100 and 3^700 in terms of \"ten to the power of\".\r\n2^1100=10^331.1379952\r\n3^700=10^333.9848783\n\r\nObviously, 3^700 is greater. To figure out how much greater, requires a little more work, but not much.\n\r\nFirst, subtract the exponents.\r\n333.9848783-331.1379952\r\nThis equals 2.851883073\r\nThen, take 10^2.851883073\r\nThis equals 711.0220569, which is around 710.\n\r\nThus, 3^700 is approximately 710 times greater than 2^1100. Congratulations, you passed your professor's exam.\n<|im_start|>answer\n3^700 is greater, by approximately 710 times (711.0220569 to be exact).\n\r\nTo start, one must realize these numbers are too big to deal with by hand. So, one must use exponents and the \"log\" function on a calculator.\n\r\n2^1100=10^a\r\n2^x=10^1\r\nlog(10)/log(2)=x\r\n3.321928095=x\r\n1100/x=331.1329952\r\n2^3.321928095=10^1\r\n2^(331.132995*3.321928095)=10^(331.132995*1)\r\n2^1100=10^331.132995\n\r\nNow that we know what 2^1100 equals, apply the same concept to 3^700.\n\r\n3^700=10^b\r\n3^y=10^1\r\nlog(10)/log(3)=y\r\n2.095903274=y\r\n3^2.095903274=10^1\r\n3^(333.9848783*2.095903274)=10^(333.9848783*1)\r\n3^700=10^333.9848783\n\r\nSo, now we have 2^1100 and 3^700 in terms of \"ten to the power of\".\r\n2^1100=10^331.1379952\r\n3^700=10^333.9848783\n\r\nObviously, 3^700 is greater. To figure out how much greater, requires a little more work, but not much.\n\r\nFirst, subtract the exponents.\r\n333.9848783-331.1379952\r\nThis equals 2.851883073\r\nThen, take 10^2.851883073\r\nThis equals 711.0220569, which is around 710.\n\r\nThus, 3^700 is approximately 710 times greater than 2^1100. Congratulations, you passed your professor's exam.\n<|im_end|>" }, { "id": "#19581", "title": "Greengrocer's Cucumbers", "fun": 2.27, "difficulty": 2.23, "author": "Mad-Ade", "desc": "On a sunny morning, a greengrocer places 200 kilograms of cucumbers in cases in front of his shop. At that moment, the cucumbers are 99% water. In the afternoon, it turns out that it is the hottest day of the year, and as a result, the cucumbers dry out a little bit. At the end of the day, the greengrocer has not sold a single cucumber, and the cucumbers are only 98% water.\r\nHow many kilograms of cucumbers has the greengrocer left at the end of the day?", "hint": "No hint available.", "answer": "In the morning, the 200 kilograms of cucumbers are 99% water. So the non-water part of the cucumbers has a mass of 2 kilograms. At the end of the day, the cucumbers are 98% water. The remaining 2% is still the 2 kilograms of non-water material (which does not change when the water evaporates). If 2% equals 2 kilograms, then 100% equals 100 kilograms. So, the greengrocer has 100 kilograms of cucumbers left at the end of the day.", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn a sunny morning, a greengrocer places 200 kilograms of cucumbers in cases in front of his shop. At that moment, the cucumbers are 99% water. In the afternoon, it turns out that it is the hottest day of the year, and as a result, the cucumbers dry out a little bit. At the end of the day, the greengrocer has not sold a single cucumber, and the cucumbers are only 98% water.\r\nHow many kilograms of cucumbers has the greengrocer left at the end of the day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn the morning, the 200 kilograms of cucumbers are 99% water. So the non-water part of the cucumbers has a mass of 2 kilograms. At the end of the day, the cucumbers are 98% water. The remaining 2% is still the 2 kilograms of non-water material (which does not change when the water evaporates). If 2% equals 2 kilograms, then 100% equals 100 kilograms. So, the greengrocer has 100 kilograms of cucumbers left at the end of the day.\n<|im_start|>answer\nIn the morning, the 200 kilograms of cucumbers are 99% water. So the non-water part of the cucumbers has a mass of 2 kilograms. At the end of the day, the cucumbers are 98% water. The remaining 2% is still the 2 kilograms of non-water material (which does not change when the water evaporates). If 2% equals 2 kilograms, then 100% equals 100 kilograms. So, the greengrocer has 100 kilograms of cucumbers left at the end of the day.\n<|im_end|>" }, { "id": "#14619", "title": "Mad Ade's Garden", "fun": 2.27, "difficulty": 3.09, "author": "mad-ade", "desc": "Mad Ade, Who had suddenly and unexpectedly after years of selfless dedication to Kebabs, decided to grow some vegetable for himself and subsequently planted his garden late in May. He planted five different vegetables: Tomatoes, Peppers, Radishes, Lettuce, and Broccoli. For each he planted a different number of rows from one to five. The hard work involved with each planting was accomplished on a separate day, from May 25th to May 30th (On Sunday May 26th he didn't work in the garden). Each vegetable was planted in a different part of the garden, the north end, the south side, the east side, the west side or the northwest corner. Can you tell which vegetable was planted in each part of the garden, the day planted and the number of rows? \r\n1. Mad Ade turned the soil for the peppers three days after he dug hand-size rocks out of the radish patch. Mad Ade's bright rows of radishes went deeper than the broccoli but were not as deep as the tomatoes. Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli. Mad Ade believes the morning sun is bad for tomatoes and so kept those plants out of the eastern side of his garden.\r\n2. Mad Ade labored hard in the south side of the garden and was mighty proud of the three perfect rows there. On one week's last day, Mad Ade planted the east side of the garden. Mad Ade didn't put the peppers or the tomatoes in the northwest corner. Mad Ade planted an even number of rows in the Northwest corner of his garden. \r\n3. Mad Ade planted three rows before he planted two rows, but planted them after he planted four rows. Mad Ade figured the lettuce wouldn't last long so he planted fewer than three rows. Mad Ade planted the south garden one day before he planted the lettuce. Mad Ade planted more rows of peppers than he did broccoli (which was not planted in the west side of the garden and was not planted the 29th). \n\r\nWhich vegetable was planted in how many rows, on which day of May and in which side of Mad Ade's garden?", "hint": "No hint available.", "answer": "Please Note that 1.1 refers to clue 1, sentence 1, and thus 2.3 would be clue 2 sentence 3.\r\nExplanation:\r\n1.1 Mad Ade turned the soil for the peppers three days after he dug hand-size rocks out of the radish patch. \r\nRadishes are 25th or 27th. \r\nPeppers are 28th or 30th. \r\n1.3 Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli \r\nBroccoli is 28, 29 30 (and West is 27, 28, 29) \r\n3.3 Mad Ade planted the south garden one day before he planted the lettuce. \r\nLettuce 28, 29 30 (and South 27, 28, 29 ) \r\nTomatoes can only be 25th or 27th. \r\n2.2 On one week's last day, Mad Ade planted the east side of the garden. \r\nSaturday the 25th is East. \r\n1.4 Mad Ade believes the morning sun is bad for tomatoes and so kept those plants out of eastern side of his garden \r\nSo East, 25th is not Tomatoes. \r\nSo Radishes 25th and Tomatoes 27th. \r\nAnd 3 days later 28th = peppers. \r\n3.4 Mad Ade planted more rows of peppers than he did broccoli (which was not planted in the west side of the garden and was not planted the 29th). \r\nSo Broccoli 30th and Lettuce 29th. \r\n1.3 Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli.\r\nWest is 29th. \r\n3.2 Mad Ade figured the lettuce wouldn't last long so he planted fewer than three rows. \r\nSo Lettuce is one or two rows. \r\n2.4 Mad Ade planted an even number of rows in the Northwest corner of his garden. \r\nNorthwest is 2 or 4 rows. \r\n1.2 Mad Ade's bright rows of radishes went deeper than the broccoli but were not as deep as the tomatoes. \r\nRadishes are not one or five.\r\nBroccoli is not five or four.\r\nTomatoes is not one or two.\r\n2.3 Mad Ade didn't put the peppers nor the tomatoes in the northwest corner. \r\nNorthwest is broccoli. \r\nLettuce has one row. \r\n2.1 Mad Ade labored hard in the south side of the garden and was mighty proud of the three perfect rows there. \r\nSo South is three rows.\r\nRadishes are four. \r\n3.3 Mad Ade planted the south garden one day before he planted the lettuce. \r\nSo planted 3 in south on 28. \r\nFive rows of tomatoes were planted in the North Garden.\n\r\nSummary:\r\nTomatoes, Five, 27th, North \r\nPeppers, Three, 28th, South \r\nRadishes, Four, 25th, East \r\nLettuce, one, 29th, West \r\nBroccoli, two, 30th, Northwest", "category": "Logic", "date": "08/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade, Who had suddenly and unexpectedly after years of selfless dedication to Kebabs, decided to grow some vegetable for himself and subsequently planted his garden late in May. He planted five different vegetables: Tomatoes, Peppers, Radishes, Lettuce, and Broccoli. For each he planted a different number of rows from one to five. The hard work involved with each planting was accomplished on a separate day, from May 25th to May 30th (On Sunday May 26th he didn't work in the garden). Each vegetable was planted in a different part of the garden, the north end, the south side, the east side, the west side or the northwest corner. Can you tell which vegetable was planted in each part of the garden, the day planted and the number of rows? \r\n1. Mad Ade turned the soil for the peppers three days after he dug hand-size rocks out of the radish patch. Mad Ade's bright rows of radishes went deeper than the broccoli but were not as deep as the tomatoes. Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli. Mad Ade believes the morning sun is bad for tomatoes and so kept those plants out of the eastern side of his garden.\r\n2. Mad Ade labored hard in the south side of the garden and was mighty proud of the three perfect rows there. On one week's last day, Mad Ade planted the east side of the garden. Mad Ade didn't put the peppers or the tomatoes in the northwest corner. Mad Ade planted an even number of rows in the Northwest corner of his garden. \r\n3. Mad Ade planted three rows before he planted two rows, but planted them after he planted four rows. Mad Ade figured the lettuce wouldn't last long so he planted fewer than three rows. Mad Ade planted the south garden one day before he planted the lettuce. Mad Ade planted more rows of peppers than he did broccoli (which was not planted in the west side of the garden and was not planted the 29th). \n\r\nWhich vegetable was planted in how many rows, on which day of May and in which side of Mad Ade's garden?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPlease Note that 1.1 refers to clue 1, sentence 1, and thus 2.3 would be clue 2 sentence 3.\r\nExplanation:\r\n1.1 Mad Ade turned the soil for the peppers three days after he dug hand-size rocks out of the radish patch. \r\nRadishes are 25th or 27th. \r\nPeppers are 28th or 30th. \r\n1.3 Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli \r\nBroccoli is 28, 29 30 (and West is 27, 28, 29) \r\n3.3 Mad Ade planted the south garden one day before he planted the lettuce. \r\nLettuce 28, 29 30 (and South 27, 28, 29 ) \r\nTomatoes can only be 25th or 27th. \r\n2.2 On one week's last day, Mad Ade planted the east side of the garden. \r\nSaturday the 25th is East. \r\n1.4 Mad Ade believes the morning sun is bad for tomatoes and so kept those plants out of eastern side of his garden \r\nSo East, 25th is not Tomatoes. \r\nSo Radishes 25th and Tomatoes 27th. \r\nAnd 3 days later 28th = peppers. \r\n3.4 Mad Ade planted more rows of peppers than he did broccoli (which was not planted in the west side of the garden and was not planted the 29th). \r\nSo Broccoli 30th and Lettuce 29th. \r\n1.3 Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli.\r\nWest is 29th. \r\n3.2 Mad Ade figured the lettuce wouldn't last long so he planted fewer than three rows. \r\nSo Lettuce is one or two rows. \r\n2.4 Mad Ade planted an even number of rows in the Northwest corner of his garden. \r\nNorthwest is 2 or 4 rows. \r\n1.2 Mad Ade's bright rows of radishes went deeper than the broccoli but were not as deep as the tomatoes. \r\nRadishes are not one or five.\r\nBroccoli is not five or four.\r\nTomatoes is not one or two.\r\n2.3 Mad Ade didn't put the peppers nor the tomatoes in the northwest corner. \r\nNorthwest is broccoli. \r\nLettuce has one row. \r\n2.1 Mad Ade labored hard in the south side of the garden and was mighty proud of the three perfect rows there. \r\nSo South is three rows.\r\nRadishes are four. \r\n3.3 Mad Ade planted the south garden one day before he planted the lettuce. \r\nSo planted 3 in south on 28. \r\nFive rows of tomatoes were planted in the North Garden.\n\r\nSummary:\r\nTomatoes, Five, 27th, North \r\nPeppers, Three, 28th, South \r\nRadishes, Four, 25th, East \r\nLettuce, one, 29th, West \r\nBroccoli, two, 30th, Northwest\n<|im_start|>answer\nPlease Note that 1.1 refers to clue 1, sentence 1, and thus 2.3 would be clue 2 sentence 3.\r\nExplanation:\r\n1.1 Mad Ade turned the soil for the peppers three days after he dug hand-size rocks out of the radish patch. \r\nRadishes are 25th or 27th. \r\nPeppers are 28th or 30th. \r\n1.3 Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli \r\nBroccoli is 28, 29 30 (and West is 27, 28, 29) \r\n3.3 Mad Ade planted the south garden one day before he planted the lettuce. \r\nLettuce 28, 29 30 (and South 27, 28, 29 ) \r\nTomatoes can only be 25th or 27th. \r\n2.2 On one week's last day, Mad Ade planted the east side of the garden. \r\nSaturday the 25th is East. \r\n1.4 Mad Ade believes the morning sun is bad for tomatoes and so kept those plants out of eastern side of his garden \r\nSo East, 25th is not Tomatoes. \r\nSo Radishes 25th and Tomatoes 27th. \r\nAnd 3 days later 28th = peppers. \r\n3.4 Mad Ade planted more rows of peppers than he did broccoli (which was not planted in the west side of the garden and was not planted the 29th). \r\nSo Broccoli 30th and Lettuce 29th. \r\n1.3 Mad Ade rolled his trusty wheelbarrow into the west end of the garden one day before he planted the broccoli.\r\nWest is 29th. \r\n3.2 Mad Ade figured the lettuce wouldn't last long so he planted fewer than three rows. \r\nSo Lettuce is one or two rows. \r\n2.4 Mad Ade planted an even number of rows in the Northwest corner of his garden. \r\nNorthwest is 2 or 4 rows. \r\n1.2 Mad Ade's bright rows of radishes went deeper than the broccoli but were not as deep as the tomatoes. \r\nRadishes are not one or five.\r\nBroccoli is not five or four.\r\nTomatoes is not one or two.\r\n2.3 Mad Ade didn't put the peppers nor the tomatoes in the northwest corner. \r\nNorthwest is broccoli. \r\nLettuce has one row. \r\n2.1 Mad Ade labored hard in the south side of the garden and was mighty proud of the three perfect rows there. \r\nSo South is three rows.\r\nRadishes are four. \r\n3.3 Mad Ade planted the south garden one day before he planted the lettuce. \r\nSo planted 3 in south on 28. \r\nFive rows of tomatoes were planted in the North Garden.\n\r\nSummary:\r\nTomatoes, Five, 27th, North \r\nPeppers, Three, 28th, South \r\nRadishes, Four, 25th, East \r\nLettuce, one, 29th, West \r\nBroccoli, two, 30th, Northwest\n<|im_end|>" }, { "id": "#4306", "title": "Ball Pyramid", "fun": 2.27, "difficulty": 1.86, "author": "mad-ade", "desc": "Mad Ade has built a pyramid out of old tennis balls. One side of the bottom layer of a triangular pyramid has 12 balls. How many are there in the whole pyramid? \n\r\nNote that the pyramid is equilateral and solid.", "hint": "No hint available.", "answer": "There are total 364 balls. \n\r\nAs there are 12 balls along one side, it means that there are 12 layers of balls. The top most layer has 1 ball. The second layer has 3 (1+2) balls. The third layer has 6 (1+2+3) balls. The fourth layer has 10 (1+2+3+4) balls. The fifth layer has 15 (1+2+3+4+5) balls. Similarly, there are 21, 28, 36, 45, 55, 66 and 78 balls in the remaining layers. \n\r\nHence, the total number of balls are \r\n= 1 + 3 + 6 + 10 + 15 + 21 +28 + 36 + 45 + 55 + 66 + 78 \r\n= 364 balls", "category": "Math", "date": "05/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has built a pyramid out of old tennis balls. One side of the bottom layer of a triangular pyramid has 12 balls. How many are there in the whole pyramid? \n\r\nNote that the pyramid is equilateral and solid.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are total 364 balls. \n\r\nAs there are 12 balls along one side, it means that there are 12 layers of balls. The top most layer has 1 ball. The second layer has 3 (1+2) balls. The third layer has 6 (1+2+3) balls. The fourth layer has 10 (1+2+3+4) balls. The fifth layer has 15 (1+2+3+4+5) balls. Similarly, there are 21, 28, 36, 45, 55, 66 and 78 balls in the remaining layers. \n\r\nHence, the total number of balls are \r\n= 1 + 3 + 6 + 10 + 15 + 21 +28 + 36 + 45 + 55 + 66 + 78 \r\n= 364 balls\n<|im_start|>answer\nThere are total 364 balls. \n\r\nAs there are 12 balls along one side, it means that there are 12 layers of balls. The top most layer has 1 ball. The second layer has 3 (1+2) balls. The third layer has 6 (1+2+3) balls. The fourth layer has 10 (1+2+3+4) balls. The fifth layer has 15 (1+2+3+4+5) balls. Similarly, there are 21, 28, 36, 45, 55, 66 and 78 balls in the remaining layers. \n\r\nHence, the total number of balls are \r\n= 1 + 3 + 6 + 10 + 15 + 21 +28 + 36 + 45 + 55 + 66 + 78 \r\n= 364 balls\n<|im_end|>" }, { "id": "#24811", "title": "Weird Ribbons", "fun": 2.27, "difficulty": 1.17, "author": "phrebh", "desc": "Fred, Bob, and Tom were in a contest to decide who had made the best butter cow (a statue of a cow made entirely out of butter) for the Iowa State Fair. The ribbons were not typical in that the color of the ribbons for the top three places were green, orange, and purple, although not necessarily in the order. Using the clues, determine what place they finished in (1st, 2nd, or 3rd) and what color ribbon they received.\n\r\n1. Fred finished after Bob.\r\n2. Tom did not get second place.\r\n3. Only Tom got a ribbon with a color that did not share any letters with his name.\r\n4. The purple ribbon is for a later place than the green ribbon.\r\n5. The complementary color for the first place ribbon is blue.", "hint": "No hint available.", "answer": "Fred, green, 2nd.\r\nBob, orange, 1st.\r\nTom, purple, 3rd.", "category": "Logic-Grid", "date": "07/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred, Bob, and Tom were in a contest to decide who had made the best butter cow (a statue of a cow made entirely out of butter) for the Iowa State Fair. The ribbons were not typical in that the color of the ribbons for the top three places were green, orange, and purple, although not necessarily in the order. Using the clues, determine what place they finished in (1st, 2nd, or 3rd) and what color ribbon they received.\n\r\n1. Fred finished after Bob.\r\n2. Tom did not get second place.\r\n3. Only Tom got a ribbon with a color that did not share any letters with his name.\r\n4. The purple ribbon is for a later place than the green ribbon.\r\n5. The complementary color for the first place ribbon is blue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFred, green, 2nd.\r\nBob, orange, 1st.\r\nTom, purple, 3rd.\n<|im_start|>answer\nFred, green, 2nd.\r\nBob, orange, 1st.\r\nTom, purple, 3rd.\n<|im_end|>" }, { "id": "#20986", "title": "The Roman Road", "fun": 2.27, "difficulty": 1.49, "author": "Gandalf", "desc": "To move their armies, the Romans built over 50,000 miles of roads. Imagine driving all those miles! Now imagine driving those miles in the first gasoline-driven car that has only three wheels and could reach a top speed of about 10 miles per hour.\n\r\nFor safety's sake, let's bring along a spare tire. As you drive the 50,000 miles, you rotate the spare with the other tires so that all four tires get the same amount of wear. Can you figure out how many miles of wear each tire accumulates?", "hint": "No hint available.", "answer": "Since the four wheels of the three-wheeled car share the journey equally, simply take three-fourths of the total distance (50,000 miles) and you'll get 37,500 miles for each tire.", "category": "Math", "date": "02/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTo move their armies, the Romans built over 50,000 miles of roads. Imagine driving all those miles! Now imagine driving those miles in the first gasoline-driven car that has only three wheels and could reach a top speed of about 10 miles per hour.\n\r\nFor safety's sake, let's bring along a spare tire. As you drive the 50,000 miles, you rotate the spare with the other tires so that all four tires get the same amount of wear. Can you figure out how many miles of wear each tire accumulates?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince the four wheels of the three-wheeled car share the journey equally, simply take three-fourths of the total distance (50,000 miles) and you'll get 37,500 miles for each tire.\n<|im_start|>answer\nSince the four wheels of the three-wheeled car share the journey equally, simply take three-fourths of the total distance (50,000 miles) and you'll get 37,500 miles for each tire.\n<|im_end|>" }, { "id": "#6459", "title": "The Kebab Express", "fun": 2.27, "difficulty": 2.32, "author": "mad-ade", "desc": "In the land of MADADIA there are two cities, one called Kebabville and one called Kebabchester. Each at opposite ends of the country. There is a train service between the two cities called the \"Kebab Express\" that starts at 10:00pm for each city and arrives at their respective destinations at 11:30pm three days later. So a train will leave every day from either city at 10:00pm and arrive at the opposite city at 11:30pm in three days time.\r\nOne day Mad Ade got on the train at Kebabville and travelled all the way to Kebabchester. How many other \"Kebab Express\" trains would Mad Ade see go the opposite direction during his journey?", "hint": "No hint available.", "answer": "Mad Ade would see seven \"Kebab Express\" trains go past in the opposite direction.\r\nLet's say that Mad Ade travelled on the \"Kebab Express\" on Wednesday 10:00PM from Kebabville. The first train he would have crossed is the one scheduled to arrive at Kebabville at 11:30 PM the same day i.e. the one that left Kebabchester at 10:00 PM on last Sunday. \r\nHe will pass 7 other trains before arriving at his destination. The first, he will see approximately 45 minutes after departure. Then he will see one train approximately every 12 hours for three days. This is because the trains leave from each end of the track once every 24 hours travelling toward each other.\r\nAlso, he would have crossed the last train just before reaching Kebabchester on Saturday. \n\r\nThus, Mad Ade must have crossed 7 \"Kebab Expresses\" during his journey.", "category": "Logic", "date": "08/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of MADADIA there are two cities, one called Kebabville and one called Kebabchester. Each at opposite ends of the country. There is a train service between the two cities called the \"Kebab Express\" that starts at 10:00pm for each city and arrives at their respective destinations at 11:30pm three days later. So a train will leave every day from either city at 10:00pm and arrive at the opposite city at 11:30pm in three days time.\r\nOne day Mad Ade got on the train at Kebabville and travelled all the way to Kebabchester. How many other \"Kebab Express\" trains would Mad Ade see go the opposite direction during his journey?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade would see seven \"Kebab Express\" trains go past in the opposite direction.\r\nLet's say that Mad Ade travelled on the \"Kebab Express\" on Wednesday 10:00PM from Kebabville. The first train he would have crossed is the one scheduled to arrive at Kebabville at 11:30 PM the same day i.e. the one that left Kebabchester at 10:00 PM on last Sunday. \r\nHe will pass 7 other trains before arriving at his destination. The first, he will see approximately 45 minutes after departure. Then he will see one train approximately every 12 hours for three days. This is because the trains leave from each end of the track once every 24 hours travelling toward each other.\r\nAlso, he would have crossed the last train just before reaching Kebabchester on Saturday. \n\r\nThus, Mad Ade must have crossed 7 \"Kebab Expresses\" during his journey.\n<|im_start|>answer\nMad Ade would see seven \"Kebab Express\" trains go past in the opposite direction.\r\nLet's say that Mad Ade travelled on the \"Kebab Express\" on Wednesday 10:00PM from Kebabville. The first train he would have crossed is the one scheduled to arrive at Kebabville at 11:30 PM the same day i.e. the one that left Kebabchester at 10:00 PM on last Sunday. \r\nHe will pass 7 other trains before arriving at his destination. The first, he will see approximately 45 minutes after departure. Then he will see one train approximately every 12 hours for three days. This is because the trains leave from each end of the track once every 24 hours travelling toward each other.\r\nAlso, he would have crossed the last train just before reaching Kebabchester on Saturday. \n\r\nThus, Mad Ade must have crossed 7 \"Kebab Expresses\" during his journey.\n<|im_end|>" }, { "id": "#3899", "title": "Ranchers", "fun": 2.27, "difficulty": 1.44, "author": "Drunky", "desc": "Rancher Joe was describing his \"grand farm\" to everyone at the general store when Farmer Sam said it was probably just a little two horse farm. Joe straightened his shoulders and said, \"I'll have you know that my farm has all horses but two, all cows but two, and all pigs but two.\" How many animals does Joe own?", "hint": "No hint available.", "answer": "3, one of each type of animal.", "category": "Logic", "date": "05/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRancher Joe was describing his \"grand farm\" to everyone at the general store when Farmer Sam said it was probably just a little two horse farm. Joe straightened his shoulders and said, \"I'll have you know that my farm has all horses but two, all cows but two, and all pigs but two.\" How many animals does Joe own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3, one of each type of animal.\n<|im_start|>answer\n3, one of each type of animal.\n<|im_end|>" }, { "id": "#14653", "title": "Rebus vs. Math", "fun": 2.27, "difficulty": 2.02, "author": "mathemagician", "desc": "A survey was taken among 100 brainiacs. Of those surveyed, twice as many brainiacs like rebus teasers as math teasers. If 18 brainiacs like both rebus teasers and math teasers and 4 like neither kind of teaser, how many brainiacs like math teasers but not rebus teasers?", "hint": "No hint available.", "answer": "20 \n\r\nx = number that like math. \n\r\n2x = number that like rebus. \n\r\nAdd the number that like math to the number that like rebus. \r\nWe then must subtract off the number that likes both kinds of teasers and add the number that doesn't like either. The result will be equal to 100. \n\r\nMATH + REBUS - BOTH + NEITHER = 100 . \n\r\nx + 2x - 18 + 4 = 100. \n\r\nSo: \n\r\n3x - 14 = 100, and so x = 38. \n\r\nThus 38 like math teasers, but of that number 18 also like rebus teasers. That leaves 20 that like only the math teasers.", "category": "Math", "date": "09/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA survey was taken among 100 brainiacs. Of those surveyed, twice as many brainiacs like rebus teasers as math teasers. If 18 brainiacs like both rebus teasers and math teasers and 4 like neither kind of teaser, how many brainiacs like math teasers but not rebus teasers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20 \n\r\nx = number that like math. \n\r\n2x = number that like rebus. \n\r\nAdd the number that like math to the number that like rebus. \r\nWe then must subtract off the number that likes both kinds of teasers and add the number that doesn't like either. The result will be equal to 100. \n\r\nMATH + REBUS - BOTH + NEITHER = 100 . \n\r\nx + 2x - 18 + 4 = 100. \n\r\nSo: \n\r\n3x - 14 = 100, and so x = 38. \n\r\nThus 38 like math teasers, but of that number 18 also like rebus teasers. That leaves 20 that like only the math teasers.\n<|im_start|>answer\n20 \n\r\nx = number that like math. \n\r\n2x = number that like rebus. \n\r\nAdd the number that like math to the number that like rebus. \r\nWe then must subtract off the number that likes both kinds of teasers and add the number that doesn't like either. The result will be equal to 100. \n\r\nMATH + REBUS - BOTH + NEITHER = 100 . \n\r\nx + 2x - 18 + 4 = 100. \n\r\nSo: \n\r\n3x - 14 = 100, and so x = 38. \n\r\nThus 38 like math teasers, but of that number 18 also like rebus teasers. That leaves 20 that like only the math teasers.\n<|im_end|>" }, { "id": "#14082", "title": "Number Signs", "fun": 2.27, "difficulty": 1.95, "author": "Timothy", "desc": "For any number x, let x# be 2^x. For example, 3# = 2^3 = 8.\n\r\nWhat is 1###?", "hint": "No hint available.", "answer": "It is 16.\n\r\n1###=2^(1##)=2^(2^(1#))=2^(2^(2^1)).\n\r\n2^2 = 4 and 4^2 = 16.", "category": "Math", "date": "07/29/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor any number x, let x# be 2^x. For example, 3# = 2^3 = 8.\n\r\nWhat is 1###?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is 16.\n\r\n1###=2^(1##)=2^(2^(1#))=2^(2^(2^1)).\n\r\n2^2 = 4 and 4^2 = 16.\n<|im_start|>answer\nIt is 16.\n\r\n1###=2^(1##)=2^(2^(1#))=2^(2^(2^1)).\n\r\n2^2 = 4 and 4^2 = 16.\n<|im_end|>" }, { "id": "#17390", "title": "The Midgets of Helevater River", "fun": 2.27, "difficulty": 1.97, "author": "mad-ade", "desc": "During its long and colourful history, there have been many battles fought in and around Madadia. One such legendary battle was known as the \"Midgets of Helevater River\". The battle itself did not contain any midgets and was fought several miles from Helevater River, but it was named in honour of two midgets that helped transport the Madadian army across the afore mentioned river. \r\nOne officer and 357 weary Madadian soldiers needed to cross the river before engaging in battle. The only method of crossing the river was a small boat owned by two midgets that lived near the river. Unfortunately, it was a midget sized boat that could either hold two midgets or one full-sized person at any given time. \r\nHow many trips would it take to transport every single soldier across the river and still leave the two midgets in joint possession of their boat?", "hint": "No hint available.", "answer": "At least 1432 trips required. \n\r\nThe two midgets row to the opposite shore. \r\nOne gets out and the other brings the boat back. One soldier rows across; the soldier gets out, and the midget returns with the boat. \n\r\nThus, it takes 4 trips to get one soldier across and the boat brought back. \n\r\nHence it takes 4 x 358 = 1432 trips, to get the officer and his 357 soldiers across the river and the midgets left in joint possession of their boat.", "category": "Math", "date": "04/15/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring its long and colourful history, there have been many battles fought in and around Madadia. One such legendary battle was known as the \"Midgets of Helevater River\". The battle itself did not contain any midgets and was fought several miles from Helevater River, but it was named in honour of two midgets that helped transport the Madadian army across the afore mentioned river. \r\nOne officer and 357 weary Madadian soldiers needed to cross the river before engaging in battle. The only method of crossing the river was a small boat owned by two midgets that lived near the river. Unfortunately, it was a midget sized boat that could either hold two midgets or one full-sized person at any given time. \r\nHow many trips would it take to transport every single soldier across the river and still leave the two midgets in joint possession of their boat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt least 1432 trips required. \n\r\nThe two midgets row to the opposite shore. \r\nOne gets out and the other brings the boat back. One soldier rows across; the soldier gets out, and the midget returns with the boat. \n\r\nThus, it takes 4 trips to get one soldier across and the boat brought back. \n\r\nHence it takes 4 x 358 = 1432 trips, to get the officer and his 357 soldiers across the river and the midgets left in joint possession of their boat.\n<|im_start|>answer\nAt least 1432 trips required. \n\r\nThe two midgets row to the opposite shore. \r\nOne gets out and the other brings the boat back. One soldier rows across; the soldier gets out, and the midget returns with the boat. \n\r\nThus, it takes 4 trips to get one soldier across and the boat brought back. \n\r\nHence it takes 4 x 358 = 1432 trips, to get the officer and his 357 soldiers across the river and the midgets left in joint possession of their boat.\n<|im_end|>" }, { "id": "#29738", "title": "Efficient Coefficients", "fun": 2.27, "difficulty": 2.72, "author": "Cogmatic", "desc": "The sum of the four smallest coefficients in the expression\n\r\n(x+y)^123456789\n\r\nis a nine-digit number with each digit being a distinct number from the following set of numbers:\n\r\n1,2,3,4,5,6,7,8,9,0\n\r\nWhat number from the set does not appear as a digit in the sum?", "hint": "No hint available.", "answer": "7\n\r\nAccording to the Pascal triangle, the two coefficients at either end of of the expression (x+y)^z will be 1,1,z, and z. Therefore, the sum of the four smallest coefficients is\n\r\n1+1+123456789+123456789=246913580\n\r\nThe digit 7 is absent from this sum.", "category": "Math", "date": "04/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe sum of the four smallest coefficients in the expression\n\r\n(x+y)^123456789\n\r\nis a nine-digit number with each digit being a distinct number from the following set of numbers:\n\r\n1,2,3,4,5,6,7,8,9,0\n\r\nWhat number from the set does not appear as a digit in the sum?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7\n\r\nAccording to the Pascal triangle, the two coefficients at either end of of the expression (x+y)^z will be 1,1,z, and z. Therefore, the sum of the four smallest coefficients is\n\r\n1+1+123456789+123456789=246913580\n\r\nThe digit 7 is absent from this sum.\n<|im_start|>answer\n7\n\r\nAccording to the Pascal triangle, the two coefficients at either end of of the expression (x+y)^z will be 1,1,z, and z. Therefore, the sum of the four smallest coefficients is\n\r\n1+1+123456789+123456789=246913580\n\r\nThe digit 7 is absent from this sum.\n<|im_end|>" }, { "id": "#31929", "title": "Money Mystery", "fun": 2.27, "difficulty": 2.07, "author": "maxvu", "desc": "Cheri, Kelsey, Ramik, and Taylor had 16 coins altogether, consisting of 4 pennies, 4 dimes, and 8 nickels. They each had the same number of coins, but not an equal amount of money.\n\r\nClues:\n\r\n1. Taylor had the least amount of money, but just 1 cent less than Kelsey. \r\n2. Ramik had no pennies, but had the most money. \r\n3. Cheri and Kelsey are the only ones who had at least one of each coin. \n\r\nHow much money did each person have?", "hint": "Make a chart or a diagram and use the clues to solve.", "answer": "Cheri had 1 penny, 1 dime, and 2 nickels for a total of 21 cents.\r\nKelsey had 2 pennies, 1 dime, and 1 nickel for a total of 17 cents.\r\nRamik had 2 dimes and 2 nickels but no pennies for a total of 30 cents.\r\nTaylor had 1 penny, no dimes, and 3 nickels for a total of 16 cents.", "category": "Math", "date": "07/20/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCheri, Kelsey, Ramik, and Taylor had 16 coins altogether, consisting of 4 pennies, 4 dimes, and 8 nickels. They each had the same number of coins, but not an equal amount of money.\n\r\nClues:\n\r\n1. Taylor had the least amount of money, but just 1 cent less than Kelsey. \r\n2. Ramik had no pennies, but had the most money. \r\n3. Cheri and Kelsey are the only ones who had at least one of each coin. \n\r\nHow much money did each person have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCheri had 1 penny, 1 dime, and 2 nickels for a total of 21 cents.\r\nKelsey had 2 pennies, 1 dime, and 1 nickel for a total of 17 cents.\r\nRamik had 2 dimes and 2 nickels but no pennies for a total of 30 cents.\r\nTaylor had 1 penny, no dimes, and 3 nickels for a total of 16 cents.\n<|im_start|>answer\nCheri had 1 penny, 1 dime, and 2 nickels for a total of 21 cents.\r\nKelsey had 2 pennies, 1 dime, and 1 nickel for a total of 17 cents.\r\nRamik had 2 dimes and 2 nickels but no pennies for a total of 30 cents.\r\nTaylor had 1 penny, no dimes, and 3 nickels for a total of 16 cents.\n<|im_end|>" }, { "id": "#47577", "title": "Vacation Time 2", "fun": 2.27, "difficulty": 0.75, "author": "racoonieboy", "desc": "Carl, Katie, Lisa, and Matthew were all on vacation and wanted to go to somewhere other than where they always are.\n\r\nNames: Carl, Katie, Lisa, Matthew\r\nAges: 8, 11, 14, 17\r\nPlace: California, Florida, France, Mexico\r\nTime: 8:00 AM, 11:20 AM, 1:00 PM, 3:30 PM\n\r\n1) Matthew, who went before noon, went to visit his relatives in Mexico.\r\n2) The person who went to France left at 8:00 AM to avoid arriving there at night.\r\n3) Lisa, who isn't 14, didn't go to Florida.\r\n4) Carl, the youngest, went to California.\r\n5) The four people are: The one who went to France, Carl, the one who left at 11:20 AM, and the 11 year old.\r\n6) The girl who is 11 left at 3:30 PM.", "hint": "No hint available.", "answer": "Carl, who is 8, left at 1:00 PM to California.\r\nKatie, who is 11, left at 3:30 PM to Florida.\r\nLisa, who is 17, left at 8:00 AM to France.\r\nMatthew, who is 14, left at 11:20 AM to Mexico.", "category": "Logic-Grid", "date": "07/22/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCarl, Katie, Lisa, and Matthew were all on vacation and wanted to go to somewhere other than where they always are.\n\r\nNames: Carl, Katie, Lisa, Matthew\r\nAges: 8, 11, 14, 17\r\nPlace: California, Florida, France, Mexico\r\nTime: 8:00 AM, 11:20 AM, 1:00 PM, 3:30 PM\n\r\n1) Matthew, who went before noon, went to visit his relatives in Mexico.\r\n2) The person who went to France left at 8:00 AM to avoid arriving there at night.\r\n3) Lisa, who isn't 14, didn't go to Florida.\r\n4) Carl, the youngest, went to California.\r\n5) The four people are: The one who went to France, Carl, the one who left at 11:20 AM, and the 11 year old.\r\n6) The girl who is 11 left at 3:30 PM.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCarl, who is 8, left at 1:00 PM to California.\r\nKatie, who is 11, left at 3:30 PM to Florida.\r\nLisa, who is 17, left at 8:00 AM to France.\r\nMatthew, who is 14, left at 11:20 AM to Mexico.\n<|im_start|>answer\nCarl, who is 8, left at 1:00 PM to California.\r\nKatie, who is 11, left at 3:30 PM to Florida.\r\nLisa, who is 17, left at 8:00 AM to France.\r\nMatthew, who is 14, left at 11:20 AM to Mexico.\n<|im_end|>" }, { "id": "#4482", "title": "No Legs", "fun": 2.27, "difficulty": 1.18, "author": "odcsurferchick", "desc": "A man is walking down a street in Richmond. He sees a sign out of a store window that says \"Get a dog with no legs for only $233.\" What did the sign mean?", "hint": "Is there something missing?", "answer": "The \"dog with no legs\" was a hot dog. The man/woman that put the sign out forgot to put the decimal point before the 33. It would look like this: Get a dog with no legs for only $2.33.\"", "category": "Logic", "date": "06/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is walking down a street in Richmond. He sees a sign out of a store window that says \"Get a dog with no legs for only $233.\" What did the sign mean?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe \"dog with no legs\" was a hot dog. The man/woman that put the sign out forgot to put the decimal point before the 33. It would look like this: Get a dog with no legs for only $2.33.\"\n<|im_start|>answer\nThe \"dog with no legs\" was a hot dog. The man/woman that put the sign out forgot to put the decimal point before the 33. It would look like this: Get a dog with no legs for only $2.33.\"\n<|im_end|>" }, { "id": "#6278", "title": "Stu Pidfule", "fun": 2.27, "difficulty": 2.7, "author": "mad-ade", "desc": "In the legendary land of MADADIA, Stu Pidfule, the inventor of dehydrated water, died in a freak Kebab wrestling accident. In his will, he left a provision of money to each of his three children, Derek, Eric and Monkeyboy. Derek invested his money wisely. Eric spent his money wildly. Monkeyboy spent all his on some magic beans that didn't grow. Stu Pidfule had been determined to treat each child equally, and in a way he did, even though Derek, Eric and Monkeyboy all got different amounts.\n\r\nHow could this be?", "hint": "No hint available.", "answer": "He had left each of them the same thing. An amount equal to one year of their annual salary. So in reality he left them all the same thing.", "category": "Logic", "date": "08/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary land of MADADIA, Stu Pidfule, the inventor of dehydrated water, died in a freak Kebab wrestling accident. In his will, he left a provision of money to each of his three children, Derek, Eric and Monkeyboy. Derek invested his money wisely. Eric spent his money wildly. Monkeyboy spent all his on some magic beans that didn't grow. Stu Pidfule had been determined to treat each child equally, and in a way he did, even though Derek, Eric and Monkeyboy all got different amounts.\n\r\nHow could this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe had left each of them the same thing. An amount equal to one year of their annual salary. So in reality he left them all the same thing.\n<|im_start|>answer\nHe had left each of them the same thing. An amount equal to one year of their annual salary. So in reality he left them all the same thing.\n<|im_end|>" }, { "id": "#19329", "title": "6 Foot Feather", "fun": 2.27, "difficulty": 1.78, "author": "AXTON", "desc": "A six-foot tall, wide-shouldered American man told his Russian colleague, 'I weigh 38 kg'. The Russian replied 'I only weigh 26 kg'. \n\r\nHow is this possible?", "hint": "What type of men were they?", "answer": "The men are astronauts, and they are on Mars. Weight = mass x gravitational pull. On Mars, there is far less gravity and so a man weighing 100 kg on Earth weighs only 38 kg on Mars.", "category": "Logic", "date": "11/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA six-foot tall, wide-shouldered American man told his Russian colleague, 'I weigh 38 kg'. The Russian replied 'I only weigh 26 kg'. \n\r\nHow is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe men are astronauts, and they are on Mars. Weight = mass x gravitational pull. On Mars, there is far less gravity and so a man weighing 100 kg on Earth weighs only 38 kg on Mars.\n<|im_start|>answer\nThe men are astronauts, and they are on Mars. Weight = mass x gravitational pull. On Mars, there is far less gravity and so a man weighing 100 kg on Earth weighs only 38 kg on Mars.\n<|im_end|>" }, { "id": "#18843", "title": "5 Wood-cutting Machines", "fun": 2.27, "difficulty": 2.84, "author": "nenad", "desc": "In a wood-cutting factory, five large sawing machines stand in a windowless room. Each machine has an on/off switch attached, there being no doubt as to which switch controls which machine. Outside the door to the room are five back-up on/off switches, one for each machine inside. The power for each machine must first pass through the back-up switch, and then the machine switch before reaching the saw. The problem is, the new manager cannot decide how these back-up switches match with the machines inside the room. One day, the manager's brother visits. The manager takes him inside the sawing room where all five machines are at work and explains the problem. The brother announces that he intends to leave the room and that when he returns he will be able to match correctly the five switches outside the room to the five machines inside. The brother works alone, cannot see the machines from outside the room and solves the problem purely by operating switches. How is it possible?", "hint": "Aside from sight, use other senses.", "answer": "1) Turn off two machines while inside. Let's call those two machines turned off with inside switch 'inactive', and call remaining three machines 'active'.\n\r\n2) Go outside.\n\r\n3) Find out which two outside switches correspond to inactive machines, and which correspond to active machines. To do that, try all of following ten combinations, where 'x' represents turned-off outside switch, while 'O' represent turned on switch: xxx00,xx0x0,x0xx0,0xxx0,xx00x,x0x0x,0xx0x,x00xx,0x0xx,00xxx . Only one of these combinations is a 'silent' combination that eliminates all sound, by turning off all three active machines.\n\r\n4) Label outside switches related to active machines (those marked with 'x' in the silent combination) with A, B, and C. Label outside switches related to inactive machines with D and E. \n\r\n5) For inactive machines, turn D off and E on.\n\r\n6) For active machines, turn A and B on, and turn C off.\n\r\n7) Wait enough time for machine connected to C switch to cool off, and then turn B off, too.\n\r\n8) Go inside.\n\r\n9) The only machine that is still working inside is connected to outside switch A.\n\r\n10) Check both machines that were active and are now turned off. The one that is warmer is connected to switch B (since it was on most recently), and the cooler one is connected to switch C (which was turned off first).\n\r\n11) Turn inside switches on for both 'inactive' machines. The one that starts working is connected to outside switch E. The one that is still not working is connected to outside switch D.", "category": "Logic", "date": "09/16/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a wood-cutting factory, five large sawing machines stand in a windowless room. Each machine has an on/off switch attached, there being no doubt as to which switch controls which machine. Outside the door to the room are five back-up on/off switches, one for each machine inside. The power for each machine must first pass through the back-up switch, and then the machine switch before reaching the saw. The problem is, the new manager cannot decide how these back-up switches match with the machines inside the room. One day, the manager's brother visits. The manager takes him inside the sawing room where all five machines are at work and explains the problem. The brother announces that he intends to leave the room and that when he returns he will be able to match correctly the five switches outside the room to the five machines inside. The brother works alone, cannot see the machines from outside the room and solves the problem purely by operating switches. How is it possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Turn off two machines while inside. Let's call those two machines turned off with inside switch 'inactive', and call remaining three machines 'active'.\n\r\n2) Go outside.\n\r\n3) Find out which two outside switches correspond to inactive machines, and which correspond to active machines. To do that, try all of following ten combinations, where 'x' represents turned-off outside switch, while 'O' represent turned on switch: xxx00,xx0x0,x0xx0,0xxx0,xx00x,x0x0x,0xx0x,x00xx,0x0xx,00xxx . Only one of these combinations is a 'silent' combination that eliminates all sound, by turning off all three active machines.\n\r\n4) Label outside switches related to active machines (those marked with 'x' in the silent combination) with A, B, and C. Label outside switches related to inactive machines with D and E. \n\r\n5) For inactive machines, turn D off and E on.\n\r\n6) For active machines, turn A and B on, and turn C off.\n\r\n7) Wait enough time for machine connected to C switch to cool off, and then turn B off, too.\n\r\n8) Go inside.\n\r\n9) The only machine that is still working inside is connected to outside switch A.\n\r\n10) Check both machines that were active and are now turned off. The one that is warmer is connected to switch B (since it was on most recently), and the cooler one is connected to switch C (which was turned off first).\n\r\n11) Turn inside switches on for both 'inactive' machines. The one that starts working is connected to outside switch E. The one that is still not working is connected to outside switch D.\n<|im_start|>answer\n1) Turn off two machines while inside. Let's call those two machines turned off with inside switch 'inactive', and call remaining three machines 'active'.\n\r\n2) Go outside.\n\r\n3) Find out which two outside switches correspond to inactive machines, and which correspond to active machines. To do that, try all of following ten combinations, where 'x' represents turned-off outside switch, while 'O' represent turned on switch: xxx00,xx0x0,x0xx0,0xxx0,xx00x,x0x0x,0xx0x,x00xx,0x0xx,00xxx . Only one of these combinations is a 'silent' combination that eliminates all sound, by turning off all three active machines.\n\r\n4) Label outside switches related to active machines (those marked with 'x' in the silent combination) with A, B, and C. Label outside switches related to inactive machines with D and E. \n\r\n5) For inactive machines, turn D off and E on.\n\r\n6) For active machines, turn A and B on, and turn C off.\n\r\n7) Wait enough time for machine connected to C switch to cool off, and then turn B off, too.\n\r\n8) Go inside.\n\r\n9) The only machine that is still working inside is connected to outside switch A.\n\r\n10) Check both machines that were active and are now turned off. The one that is warmer is connected to switch B (since it was on most recently), and the cooler one is connected to switch C (which was turned off first).\n\r\n11) Turn inside switches on for both 'inactive' machines. The one that starts working is connected to outside switch E. The one that is still not working is connected to outside switch D.\n<|im_end|>" }, { "id": "#19518", "title": "Mad Ade's Odometer", "fun": 2.27, "difficulty": 1.85, "author": "Mad-Ade", "desc": "Whilst out driving his car, a Madadian built \"Wet Squib\", Mad Ade observes that the odometer reading forms a palindromic number. It displays the mileage as 13,931. \n\r\nMad Ade continues driving. Two hours later, Mad Ade looks at the odometer again and, to his surprise, it displays a different palindromic number! \n\r\nWhat is the most likely speed that Mad Ade is traveling?", "hint": "No hint available.", "answer": "55 mph. \r\nThe next palindrome that the odometer could display is 14,041. To reach this value, Mad Ade will have to travel 110 miles. If it took him 2 hours to reach this point, his average speed would have been 55 mph. \n\r\nAll other palindromes would have required too many miles to produce a logical speed. For example, the odometer's next palindrome is 14,141. From this, you can calculate an average speed of 105 mph -- unlikely for a Madadian built car.", "category": "Math", "date": "11/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhilst out driving his car, a Madadian built \"Wet Squib\", Mad Ade observes that the odometer reading forms a palindromic number. It displays the mileage as 13,931. \n\r\nMad Ade continues driving. Two hours later, Mad Ade looks at the odometer again and, to his surprise, it displays a different palindromic number! \n\r\nWhat is the most likely speed that Mad Ade is traveling?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n55 mph. \r\nThe next palindrome that the odometer could display is 14,041. To reach this value, Mad Ade will have to travel 110 miles. If it took him 2 hours to reach this point, his average speed would have been 55 mph. \n\r\nAll other palindromes would have required too many miles to produce a logical speed. For example, the odometer's next palindrome is 14,141. From this, you can calculate an average speed of 105 mph -- unlikely for a Madadian built car.\n<|im_start|>answer\n55 mph. \r\nThe next palindrome that the odometer could display is 14,041. To reach this value, Mad Ade will have to travel 110 miles. If it took him 2 hours to reach this point, his average speed would have been 55 mph. \n\r\nAll other palindromes would have required too many miles to produce a logical speed. For example, the odometer's next palindrome is 14,141. From this, you can calculate an average speed of 105 mph -- unlikely for a Madadian built car.\n<|im_end|>" }, { "id": "#22953", "title": "Too Many Children", "fun": 2.27, "difficulty": 2.81, "author": "stormtrooper", "desc": "A man has nine children born at regular intervals. The sum of the square of their ages is equal to the square of his own age. What are the ages of his children?", "hint": "No hint available.", "answer": "The ages are 2,5,8,11,14,17,20,23 and 26. The man's age is 48.", "category": "Math", "date": "05/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man has nine children born at regular intervals. The sum of the square of their ages is equal to the square of his own age. What are the ages of his children?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ages are 2,5,8,11,14,17,20,23 and 26. The man's age is 48.\n<|im_start|>answer\nThe ages are 2,5,8,11,14,17,20,23 and 26. The man's age is 48.\n<|im_end|>" }, { "id": "#1021", "title": "Unpunishable Crime", "fun": 2.27, "difficulty": 1.0, "author": "Michelle", "desc": "There is a certain crime, that if it is attempted it is punishable, but if it is committed it is unpunishable. What's the crime?", "hint": "No hint available.", "answer": "Suicide.", "category": "Logic", "date": "10/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a certain crime, that if it is attempted it is punishable, but if it is committed it is unpunishable. What's the crime?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSuicide.\n<|im_start|>answer\nSuicide.\n<|im_end|>" }, { "id": "#20981", "title": "Logic Question", "fun": 2.27, "difficulty": 1.83, "author": "crimonie", "desc": "Two Japanese people who have never seen each other meet at the New York Japanese Embassy. They decide to have drinks together at a nearby bar. One of them is the father of the other one's son. How is this possible?", "hint": "They each own a dog.", "answer": "The Japanese are husband and wife and both blind since birth.", "category": "Logic", "date": "02/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo Japanese people who have never seen each other meet at the New York Japanese Embassy. They decide to have drinks together at a nearby bar. One of them is the father of the other one's son. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Japanese are husband and wife and both blind since birth.\n<|im_start|>answer\nThe Japanese are husband and wife and both blind since birth.\n<|im_end|>" }, { "id": "#49107", "title": "Getting a Pet", "fun": 2.27, "difficulty": 0.31, "author": "juggler314", "desc": "Three people bought a pet one day. Their names were Zach, Rachel, and Hubert. The animals they bought were a snake, a parrot, and a guinea pig. They bought their pets for $100, $50, and $25.\n\r\nCan you find out which person bought which animal for which amount of money using these clues?\n\r\n1. Zach is allergic to birds.\r\n2. Hubert couldn't get the $100 pet, so he bought the snake.\r\n3. Rachel saved $10 a week for ten weeks in order to get her pet.\r\n4. The mammal was $25.", "hint": "No hint available.", "answer": "Zach - Guinea Pig - $25\r\nRachel - Parrot - $100\r\nHubert - Snake - $50", "category": "Logic-Grid", "date": "10/24/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people bought a pet one day. Their names were Zach, Rachel, and Hubert. The animals they bought were a snake, a parrot, and a guinea pig. They bought their pets for $100, $50, and $25.\n\r\nCan you find out which person bought which animal for which amount of money using these clues?\n\r\n1. Zach is allergic to birds.\r\n2. Hubert couldn't get the $100 pet, so he bought the snake.\r\n3. Rachel saved $10 a week for ten weeks in order to get her pet.\r\n4. The mammal was $25.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZach - Guinea Pig - $25\r\nRachel - Parrot - $100\r\nHubert - Snake - $50\n<|im_start|>answer\nZach - Guinea Pig - $25\r\nRachel - Parrot - $100\r\nHubert - Snake - $50\n<|im_end|>" }, { "id": "#7100", "title": "Tons of Books", "fun": 2.27, "difficulty": 1.69, "author": "tissue", "desc": "Tissue wrote 27 books over a 3 year time period. He wrote three times as many books in year 3 as in year 1. In year 2, he wrote more books than in year 1 and 3 combined. In no year did he write more than 15 books. How many books did he write in year 1, 2, and 3?", "hint": "No hint available.", "answer": "Year 1: 3\r\nYear 2: 15\r\nYear 3: 9", "category": "Math", "date": "09/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTissue wrote 27 books over a 3 year time period. He wrote three times as many books in year 3 as in year 1. In year 2, he wrote more books than in year 1 and 3 combined. In no year did he write more than 15 books. How many books did he write in year 1, 2, and 3?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYear 1: 3\r\nYear 2: 15\r\nYear 3: 9\n<|im_start|>answer\nYear 1: 3\r\nYear 2: 15\r\nYear 3: 9\n<|im_end|>" }, { "id": "#10682", "title": "Healthy Mind and Body", "fun": 2.27, "difficulty": 1.44, "author": "jimbo", "desc": "You have two magic pills! One decreases your life span by 10% and the other increases your life span by 10%. The trouble is, you don't know which is which. You take one but then start to worry that it was the bad one so you take the other one to counteract it. Will you now have a normal life span?", "hint": "No hint available.", "answer": "No! \n\r\n1.1 x 0.9 = 0.99. You'll still lose 1% of your life span!", "category": "Math", "date": "02/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have two magic pills! One decreases your life span by 10% and the other increases your life span by 10%. The trouble is, you don't know which is which. You take one but then start to worry that it was the bad one so you take the other one to counteract it. Will you now have a normal life span?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo! \n\r\n1.1 x 0.9 = 0.99. You'll still lose 1% of your life span!\n<|im_start|>answer\nNo! \n\r\n1.1 x 0.9 = 0.99. You'll still lose 1% of your life span!\n<|im_end|>" }, { "id": "#1262", "title": "Too Many Women", "fun": 2.27, "difficulty": 1.7, "author": "Yanivster", "desc": "In a far far land, there was a long war.\r\nMany men died in that war, and when it was over\r\nthere were not enough men to marry all the women in the kingdom.\r\nThe king wanted balance between men and women, so he issued an order that any woman who gives birth to a girl, will stop having children after that.\r\nHis theory was that there would be several families with one girl and one or no boys,\r\nbut there would also be families with several boys and only one girl, and so after a few years the number of males in the kingdom would increase.\r\nWhat was wrong with the king's plan and why won't it work?", "hint": "No hint available.", "answer": "Assuming that the birth rate between boys and girls is 1:1,\r\nAt first, half the women would give birth to boys, and half would give birth to girls.\r\nThen, only one half would be able to continue having children, so half of them will have boys, and half will have girls, and so on...\r\nAs you can see, the number of boys and girls remains the same.", "category": "Logic", "date": "11/02/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a far far land, there was a long war.\r\nMany men died in that war, and when it was over\r\nthere were not enough men to marry all the women in the kingdom.\r\nThe king wanted balance between men and women, so he issued an order that any woman who gives birth to a girl, will stop having children after that.\r\nHis theory was that there would be several families with one girl and one or no boys,\r\nbut there would also be families with several boys and only one girl, and so after a few years the number of males in the kingdom would increase.\r\nWhat was wrong with the king's plan and why won't it work?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAssuming that the birth rate between boys and girls is 1:1,\r\nAt first, half the women would give birth to boys, and half would give birth to girls.\r\nThen, only one half would be able to continue having children, so half of them will have boys, and half will have girls, and so on...\r\nAs you can see, the number of boys and girls remains the same.\n<|im_start|>answer\nAssuming that the birth rate between boys and girls is 1:1,\r\nAt first, half the women would give birth to boys, and half would give birth to girls.\r\nThen, only one half would be able to continue having children, so half of them will have boys, and half will have girls, and so on...\r\nAs you can see, the number of boys and girls remains the same.\n<|im_end|>" }, { "id": "#29473", "title": "Shoe Factory 2", "fun": 2.26, "difficulty": 2.36, "author": "BobbyKat", "desc": "If twenty people in a factory make 43 shoes in [(3)^0.5] / 2 hours, then how many shoes do they make in an eight hour day?", "hint": "The number of shoes has to be an integer.", "answer": "43 shoes / (3)^0.5/2 = 86 shoes / (3)^0.5 per hour \r\n86/(3)^0.5 * 8 = 397.2 \r\nTherefore 397 shoes could be made in a day.", "category": "Math", "date": "04/01/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf twenty people in a factory make 43 shoes in [(3)^0.5] / 2 hours, then how many shoes do they make in an eight hour day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n43 shoes / (3)^0.5/2 = 86 shoes / (3)^0.5 per hour \r\n86/(3)^0.5 * 8 = 397.2 \r\nTherefore 397 shoes could be made in a day.\n<|im_start|>answer\n43 shoes / (3)^0.5/2 = 86 shoes / (3)^0.5 per hour \r\n86/(3)^0.5 * 8 = 397.2 \r\nTherefore 397 shoes could be made in a day.\n<|im_end|>" }, { "id": "#10819", "title": "TV or not TV", "fun": 2.26, "difficulty": 2.3, "author": "mad-ade", "desc": "In the legendary country of Madadia, only three TV channels are available - Kebab Plus, MaddyOne and Madadia TV. \n\r\nOut of 4000 TV owners in Madadia, 1500 watch Kebab Plus, 2000 watch MaddyOne and 2500 watch Madadia TV. \n\r\nAmongst these, 500 viewers watch Kebab Plus and Maddyone, 800 watch Kebab Plus and Madadia TV, and 1000 watch MaddyOne and Madadia TV. \n\r\nHow many viewers watch all three channels?", "hint": "No hint available.", "answer": "300 viewers watch all three channels. \n\r\nLet's assume that total X viewers watch all three channels. \n\r\nTotal viewers who watch only Kebab Plus and MaddyOne = 500-X \r\nTotal viewers who watch only Kebab Plus and Madadia TV = 800-X \r\nTotal viewers who watch only MaddyOne and Madadia TV = 1000-X \n\r\nTotal viewers who watch only Kebab Plus \r\n= 1500 - (500-X) - (800-X) - X \r\n= 200 + X \n\r\nTotal viewers who watch only MaddyOne \r\n= 2000 - (500-X) - (1000-X) - X \r\n= 500 + X \n\r\nTotal viewers who watch only Madadia TV \r\n= 2500 - (1000-X) - (800-X) - X \r\n= 700 + X \n\r\nWe know that total viewers are 4000. Summing up all 7 values, \r\nX + (500 - X) + (800 - X) + (1000 - X) + (200 + X) + (500 + X) + (700 + X) = 4000 \r\nX + 3700 = 4000 \r\nX = 300 \n\r\nHence, total 300 viewers watch all three channels.", "category": "Math", "date": "03/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary country of Madadia, only three TV channels are available - Kebab Plus, MaddyOne and Madadia TV. \n\r\nOut of 4000 TV owners in Madadia, 1500 watch Kebab Plus, 2000 watch MaddyOne and 2500 watch Madadia TV. \n\r\nAmongst these, 500 viewers watch Kebab Plus and Maddyone, 800 watch Kebab Plus and Madadia TV, and 1000 watch MaddyOne and Madadia TV. \n\r\nHow many viewers watch all three channels?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n300 viewers watch all three channels. \n\r\nLet's assume that total X viewers watch all three channels. \n\r\nTotal viewers who watch only Kebab Plus and MaddyOne = 500-X \r\nTotal viewers who watch only Kebab Plus and Madadia TV = 800-X \r\nTotal viewers who watch only MaddyOne and Madadia TV = 1000-X \n\r\nTotal viewers who watch only Kebab Plus \r\n= 1500 - (500-X) - (800-X) - X \r\n= 200 + X \n\r\nTotal viewers who watch only MaddyOne \r\n= 2000 - (500-X) - (1000-X) - X \r\n= 500 + X \n\r\nTotal viewers who watch only Madadia TV \r\n= 2500 - (1000-X) - (800-X) - X \r\n= 700 + X \n\r\nWe know that total viewers are 4000. Summing up all 7 values, \r\nX + (500 - X) + (800 - X) + (1000 - X) + (200 + X) + (500 + X) + (700 + X) = 4000 \r\nX + 3700 = 4000 \r\nX = 300 \n\r\nHence, total 300 viewers watch all three channels.\n<|im_start|>answer\n300 viewers watch all three channels. \n\r\nLet's assume that total X viewers watch all three channels. \n\r\nTotal viewers who watch only Kebab Plus and MaddyOne = 500-X \r\nTotal viewers who watch only Kebab Plus and Madadia TV = 800-X \r\nTotal viewers who watch only MaddyOne and Madadia TV = 1000-X \n\r\nTotal viewers who watch only Kebab Plus \r\n= 1500 - (500-X) - (800-X) - X \r\n= 200 + X \n\r\nTotal viewers who watch only MaddyOne \r\n= 2000 - (500-X) - (1000-X) - X \r\n= 500 + X \n\r\nTotal viewers who watch only Madadia TV \r\n= 2500 - (1000-X) - (800-X) - X \r\n= 700 + X \n\r\nWe know that total viewers are 4000. Summing up all 7 values, \r\nX + (500 - X) + (800 - X) + (1000 - X) + (200 + X) + (500 + X) + (700 + X) = 4000 \r\nX + 3700 = 4000 \r\nX = 300 \n\r\nHence, total 300 viewers watch all three channels.\n<|im_end|>" }, { "id": "#13477", "title": "Annual Dancer's Ball", "fun": 2.26, "difficulty": 1.49, "author": "braingle44", "desc": "At the annual dancer's ball a number of very experienced dancers performed their favourite dance with their favourite partners. Alan danced the tango, whilst Becky watched the waltz. James and Charlotte were fantastic together. Keith was magnificent during his foxtrot and Simon excelled at the rumba. Jessica danced with Alan, but Laura did not dance with Simon. Can you determine who danced with whom and which dance they each enjoyed?", "hint": "No hint available.", "answer": "Alan danced with Jessica to the tango. Keith danced with Laura and enjoyed the foxtrot. James danced with Charlotte to the waltz. Simon danced with Becky, enjoying the rumba.", "category": "Logic", "date": "06/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the annual dancer's ball a number of very experienced dancers performed their favourite dance with their favourite partners. Alan danced the tango, whilst Becky watched the waltz. James and Charlotte were fantastic together. Keith was magnificent during his foxtrot and Simon excelled at the rumba. Jessica danced with Alan, but Laura did not dance with Simon. Can you determine who danced with whom and which dance they each enjoyed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlan danced with Jessica to the tango. Keith danced with Laura and enjoyed the foxtrot. James danced with Charlotte to the waltz. Simon danced with Becky, enjoying the rumba.\n<|im_start|>answer\nAlan danced with Jessica to the tango. Keith danced with Laura and enjoyed the foxtrot. James danced with Charlotte to the waltz. Simon danced with Becky, enjoying the rumba.\n<|im_end|>" }, { "id": "#8486", "title": "4 weights", "fun": 2.26, "difficulty": 2.67, "author": "lesternoronha1", "desc": "Lester has 40 kilograms of wheat. He has a simple balance and 4 weights of whole number denominations. The 4 weights are such that he is able to measure any whole number amount of wheat from 1 to 40 (no fractions). He can use a combination of two or more weights on any side of the balance as required. He can also use one weight on the left side and two or more weights on the right along with the wheat to weigh the required amount if necessary. What are the 4 weights Lester has?", "hint": "No hint available.", "answer": "The weights Lester uses are 1,3,9 and 27 kg.\n\r\nFor 1, 3, 4, 9, 10, 12, 13, 27, 28, 30, 31, 36, 37, 39 and 40 kg, he just needs to put the wheat on one side and the right combination of weights on the other side.\n\r\nFor 2, 8, 11, 26, 29, 35 and 38 kg he needs to put the wheat plus the 1 kg weight on one side and enough weights to make 1 more kg than he is trying to weigh up on the other side.\n\r\nFor 6, 7, 24, 25, 33, and 34 kg he needs to put the wheat plus the 3 kg weight on one side and enough weights to make 3 more kg than he is trying to weigh up on the other side.\n\r\nFor 5, 23, and 32 kg he needs to put the wheat plus the 1 and 3 kg weights on one side and enough weights to make 4 more kg than he is trying to weigh up on the other side.\n\r\nSimilarly,\r\n14 = 27-9-3-1\r\n15 = 27-9-3\r\n16 = 27+1-9-3\r\n17 = 27-9-1\r\n18 = 27-9\r\n19 = 27+1-9\r\n20 = 27+3-9-1\r\n21 = 27+3-9\r\n22 = 27+3+1-9\n\r\n...where negative numbers indicate weights that are on the same side of the wheat and positive numbers indicate weights that have been placed on the opposite side of the wheat.", "category": "Math", "date": "11/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester has 40 kilograms of wheat. He has a simple balance and 4 weights of whole number denominations. The 4 weights are such that he is able to measure any whole number amount of wheat from 1 to 40 (no fractions). He can use a combination of two or more weights on any side of the balance as required. He can also use one weight on the left side and two or more weights on the right along with the wheat to weigh the required amount if necessary. What are the 4 weights Lester has?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe weights Lester uses are 1,3,9 and 27 kg.\n\r\nFor 1, 3, 4, 9, 10, 12, 13, 27, 28, 30, 31, 36, 37, 39 and 40 kg, he just needs to put the wheat on one side and the right combination of weights on the other side.\n\r\nFor 2, 8, 11, 26, 29, 35 and 38 kg he needs to put the wheat plus the 1 kg weight on one side and enough weights to make 1 more kg than he is trying to weigh up on the other side.\n\r\nFor 6, 7, 24, 25, 33, and 34 kg he needs to put the wheat plus the 3 kg weight on one side and enough weights to make 3 more kg than he is trying to weigh up on the other side.\n\r\nFor 5, 23, and 32 kg he needs to put the wheat plus the 1 and 3 kg weights on one side and enough weights to make 4 more kg than he is trying to weigh up on the other side.\n\r\nSimilarly,\r\n14 = 27-9-3-1\r\n15 = 27-9-3\r\n16 = 27+1-9-3\r\n17 = 27-9-1\r\n18 = 27-9\r\n19 = 27+1-9\r\n20 = 27+3-9-1\r\n21 = 27+3-9\r\n22 = 27+3+1-9\n\r\n...where negative numbers indicate weights that are on the same side of the wheat and positive numbers indicate weights that have been placed on the opposite side of the wheat.\n<|im_start|>answer\nThe weights Lester uses are 1,3,9 and 27 kg.\n\r\nFor 1, 3, 4, 9, 10, 12, 13, 27, 28, 30, 31, 36, 37, 39 and 40 kg, he just needs to put the wheat on one side and the right combination of weights on the other side.\n\r\nFor 2, 8, 11, 26, 29, 35 and 38 kg he needs to put the wheat plus the 1 kg weight on one side and enough weights to make 1 more kg than he is trying to weigh up on the other side.\n\r\nFor 6, 7, 24, 25, 33, and 34 kg he needs to put the wheat plus the 3 kg weight on one side and enough weights to make 3 more kg than he is trying to weigh up on the other side.\n\r\nFor 5, 23, and 32 kg he needs to put the wheat plus the 1 and 3 kg weights on one side and enough weights to make 4 more kg than he is trying to weigh up on the other side.\n\r\nSimilarly,\r\n14 = 27-9-3-1\r\n15 = 27-9-3\r\n16 = 27+1-9-3\r\n17 = 27-9-1\r\n18 = 27-9\r\n19 = 27+1-9\r\n20 = 27+3-9-1\r\n21 = 27+3-9\r\n22 = 27+3+1-9\n\r\n...where negative numbers indicate weights that are on the same side of the wheat and positive numbers indicate weights that have been placed on the opposite side of the wheat.\n<|im_end|>" }, { "id": "#10313", "title": "Flying Around", "fun": 2.26, "difficulty": 1.87, "author": "ka-boom", "desc": "Assume a red plane leaves from city A to city B and at the same time a blue plane from city B heads toward city A. The wind current is around 5 mph and is traveling against the Blue plane. Both planes are travelling at 120 miles per hour relative to the wind (not the ground). If the distance between the two cities is 300 miles, after how long will the two planes meet?", "hint": "No hint available.", "answer": "Set up 2 equations:\r\ndistance = rate * time\r\nspeed going with the wind = 120 + 5\r\nspeed against the wind = 120 - 5\n\r\nd = (120+5)t\r\n300 - d = (120-5)t\n\r\nAdd the two equations together:\r\n300 = 125t + 115t\r\n300 = 240t\r\n1.25 = t\r\nThey will meet in 1.25 hrs.", "category": "Math", "date": "02/07/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAssume a red plane leaves from city A to city B and at the same time a blue plane from city B heads toward city A. The wind current is around 5 mph and is traveling against the Blue plane. Both planes are travelling at 120 miles per hour relative to the wind (not the ground). If the distance between the two cities is 300 miles, after how long will the two planes meet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSet up 2 equations:\r\ndistance = rate * time\r\nspeed going with the wind = 120 + 5\r\nspeed against the wind = 120 - 5\n\r\nd = (120+5)t\r\n300 - d = (120-5)t\n\r\nAdd the two equations together:\r\n300 = 125t + 115t\r\n300 = 240t\r\n1.25 = t\r\nThey will meet in 1.25 hrs.\n<|im_start|>answer\nSet up 2 equations:\r\ndistance = rate * time\r\nspeed going with the wind = 120 + 5\r\nspeed against the wind = 120 - 5\n\r\nd = (120+5)t\r\n300 - d = (120-5)t\n\r\nAdd the two equations together:\r\n300 = 125t + 115t\r\n300 = 240t\r\n1.25 = t\r\nThey will meet in 1.25 hrs.\n<|im_end|>" }, { "id": "#1283", "title": "5 Apples and 5 Girls", "fun": 2.26, "difficulty": 1.36, "author": "anneofgg14", "desc": "There are 5 girls in a room and 5 apples in a basket. Each girl takes 1 apple. Now, there is still one apple left in the basket. How is that possible?", "hint": "One girl took more than just the one apple.", "answer": "One girl takes the basket with an apple in it.", "category": "Logic", "date": "11/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 5 girls in a room and 5 apples in a basket. Each girl takes 1 apple. Now, there is still one apple left in the basket. How is that possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne girl takes the basket with an apple in it.\n<|im_start|>answer\nOne girl takes the basket with an apple in it.\n<|im_end|>" }, { "id": "#17393", "title": "Secret Ingredient", "fun": 2.26, "difficulty": 1.62, "author": "mad-ade", "desc": "Mustapha Scratche, owner of the \"Sweaty Chef Kebab Shop\" was just about to weigh out the ingredients of his world famous \"Colon disinfecting mega grease injection\" kebab. \r\nHe needed to separate a 20 kg block of the secret ingredient into 2 kg blocks, but could only find a 5 kg and 9 kg weight. \r\nUsing a traditional balance scale, how could he measure out the ingredients precisely and as simply as possible?", "hint": "No hint available.", "answer": "Using the 9 kg weight he can measure 9 kg from the 20 kg block. The remaining block of ingredients now weighs 11 kg. He then measures 9 kg from this to leave a 2 kg block. Finally, he can use this 2 kg block to measure and weigh all the rest into 2 kg blocks.", "category": "Logic", "date": "04/18/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMustapha Scratche, owner of the \"Sweaty Chef Kebab Shop\" was just about to weigh out the ingredients of his world famous \"Colon disinfecting mega grease injection\" kebab. \r\nHe needed to separate a 20 kg block of the secret ingredient into 2 kg blocks, but could only find a 5 kg and 9 kg weight. \r\nUsing a traditional balance scale, how could he measure out the ingredients precisely and as simply as possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUsing the 9 kg weight he can measure 9 kg from the 20 kg block. The remaining block of ingredients now weighs 11 kg. He then measures 9 kg from this to leave a 2 kg block. Finally, he can use this 2 kg block to measure and weigh all the rest into 2 kg blocks.\n<|im_start|>answer\nUsing the 9 kg weight he can measure 9 kg from the 20 kg block. The remaining block of ingredients now weighs 11 kg. He then measures 9 kg from this to leave a 2 kg block. Finally, he can use this 2 kg block to measure and weigh all the rest into 2 kg blocks.\n<|im_end|>" }, { "id": "#48394", "title": "Art Logic", "fun": 2.26, "difficulty": 2.64, "author": "quesadillaman12", "desc": "A plain white cube has gone through 4 steps to become what it is now. The steps (not necessarily in order) are:\r\na) The whole cube being painted red\r\nb) A white circle being painted on every face except for the top and back\r\nc) The front and back faces being painted black\r\nd) The top, back, and bottom being painted blue\n\r\nAll of the following facts about painting the cube are true:\n\r\n1. After the last of the four steps, the top face was all purple, the left and right faces were red with a pink circle in each of their centers, the front black with a gray circle, the bottom purple with a light blue circle, and the back completely dark blue.\r\n2. Color mixing goes as follows:\r\n-Red+Blue=Purple\r\n-Black+White=Gray\r\n-Red+White=Pink\r\n-Blue+White=Light Blue\r\n-Red+Black=Maroon\r\n-Blue+Black=Dark Blue\r\n3. Once black is added to a face, it will mix with the colors on the face if possible, but it cannot be changed at all afterwards. This is not true with white.\r\n4. Any area where two colors have been mixed cannot change color.\r\n5. Exactly one of the following is true:\r\n-Black was added first.\r\n-Red was added before blue.\r\n-Blue was added after white.\r\n-White was added last.\n\r\nIn what order were the colors added?", "hint": "If the back face is dark blue, then blue was added before black.", "answer": "White, blue, black, red.\n\r\nBecause there are both gray and dark blue regions, black was added after both white and blue. This means black was not first, and neither blue nor white was last.\r\nBlack has to have been added before red, because if it wasn't, the front face would be maroon with a pink center. So black was not last, and red was not first.\r\nSince neither blue, black, nor white was last, red had to be added last. Combining this with other facts, white and blue could not be added third. So black was third.\r\nGoing back to the statements of which one is true, we can now figure out the lies. Red was added last, so statement 4 is false. Black was added third, so statement 1 is false. Red was not added before any other colors, so statement 2 is false. This makes statement 3 true. White was added before blue, so white is first, and blue is second. The order white, blue, black, red is now revealed.", "category": "Logic", "date": "01/17/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA plain white cube has gone through 4 steps to become what it is now. The steps (not necessarily in order) are:\r\na) The whole cube being painted red\r\nb) A white circle being painted on every face except for the top and back\r\nc) The front and back faces being painted black\r\nd) The top, back, and bottom being painted blue\n\r\nAll of the following facts about painting the cube are true:\n\r\n1. After the last of the four steps, the top face was all purple, the left and right faces were red with a pink circle in each of their centers, the front black with a gray circle, the bottom purple with a light blue circle, and the back completely dark blue.\r\n2. Color mixing goes as follows:\r\n-Red+Blue=Purple\r\n-Black+White=Gray\r\n-Red+White=Pink\r\n-Blue+White=Light Blue\r\n-Red+Black=Maroon\r\n-Blue+Black=Dark Blue\r\n3. Once black is added to a face, it will mix with the colors on the face if possible, but it cannot be changed at all afterwards. This is not true with white.\r\n4. Any area where two colors have been mixed cannot change color.\r\n5. Exactly one of the following is true:\r\n-Black was added first.\r\n-Red was added before blue.\r\n-Blue was added after white.\r\n-White was added last.\n\r\nIn what order were the colors added?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhite, blue, black, red.\n\r\nBecause there are both gray and dark blue regions, black was added after both white and blue. This means black was not first, and neither blue nor white was last.\r\nBlack has to have been added before red, because if it wasn't, the front face would be maroon with a pink center. So black was not last, and red was not first.\r\nSince neither blue, black, nor white was last, red had to be added last. Combining this with other facts, white and blue could not be added third. So black was third.\r\nGoing back to the statements of which one is true, we can now figure out the lies. Red was added last, so statement 4 is false. Black was added third, so statement 1 is false. Red was not added before any other colors, so statement 2 is false. This makes statement 3 true. White was added before blue, so white is first, and blue is second. The order white, blue, black, red is now revealed.\n<|im_start|>answer\nWhite, blue, black, red.\n\r\nBecause there are both gray and dark blue regions, black was added after both white and blue. This means black was not first, and neither blue nor white was last.\r\nBlack has to have been added before red, because if it wasn't, the front face would be maroon with a pink center. So black was not last, and red was not first.\r\nSince neither blue, black, nor white was last, red had to be added last. Combining this with other facts, white and blue could not be added third. So black was third.\r\nGoing back to the statements of which one is true, we can now figure out the lies. Red was added last, so statement 4 is false. Black was added third, so statement 1 is false. Red was not added before any other colors, so statement 2 is false. This makes statement 3 true. White was added before blue, so white is first, and blue is second. The order white, blue, black, red is now revealed.\n<|im_end|>" }, { "id": "#4159", "title": "Trains", "fun": 2.26, "difficulty": 1.03, "author": "O_wise_one", "desc": "Two trains, going opposite directions, enter a tunnel at exactly 12:00. There is only one track, and there is only room in the tunnel for one train at a time. Never the less, three minutes later, both trains come out of the tunnel on the opposite side they came in. How is this possible?", "hint": "No hint available.", "answer": "One went in at 12:00 pm, the other at 12:00 am", "category": "Logic", "date": "05/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo trains, going opposite directions, enter a tunnel at exactly 12:00. There is only one track, and there is only room in the tunnel for one train at a time. Never the less, three minutes later, both trains come out of the tunnel on the opposite side they came in. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne went in at 12:00 pm, the other at 12:00 am\n<|im_start|>answer\nOne went in at 12:00 pm, the other at 12:00 am\n<|im_end|>" }, { "id": "#4923", "title": "Equal Mowing", "fun": 2.26, "difficulty": 2.8, "author": "mad-ade", "desc": "Mad Ade's kids, Mad Ade junior and little Miss Mad Ade were going to cut the grass on their square lawn, while their dad was out buying a bumper family sized kebab with extra grease. They agreed that each should cut one-half of the area. Junior went first, and cut a border 2 metres wide all the way around.\r\nAfter doing a few sums, Little Miss agreed that exactly one-half had been cut and happily cut the rest.\n\r\nWhat was the area of the lawn?", "hint": "No hint available.", "answer": "Area of lawn was 186.51 square metres", "category": "Math", "date": "06/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's kids, Mad Ade junior and little Miss Mad Ade were going to cut the grass on their square lawn, while their dad was out buying a bumper family sized kebab with extra grease. They agreed that each should cut one-half of the area. Junior went first, and cut a border 2 metres wide all the way around.\r\nAfter doing a few sums, Little Miss agreed that exactly one-half had been cut and happily cut the rest.\n\r\nWhat was the area of the lawn?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nArea of lawn was 186.51 square metres\n<|im_start|>answer\nArea of lawn was 186.51 square metres\n<|im_end|>" }, { "id": "#8637", "title": "50% Larger", "fun": 2.26, "difficulty": 2.72, "author": "mad-ade", "desc": "Find the smallest number such that if its rightmost digit is placed at its left end, the new number so formed is precisely 50% larger than the original number.", "hint": "No hint available.", "answer": "The answer is 285714. \n\r\nIf its rightmost digit is placed at its left end, the new number is 428571 which is 50% larger than the original number 285714.", "category": "Math", "date": "11/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the smallest number such that if its rightmost digit is placed at its left end, the new number so formed is precisely 50% larger than the original number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 285714. \n\r\nIf its rightmost digit is placed at its left end, the new number is 428571 which is 50% larger than the original number 285714.\n<|im_start|>answer\nThe answer is 285714. \n\r\nIf its rightmost digit is placed at its left end, the new number is 428571 which is 50% larger than the original number 285714.\n<|im_end|>" }, { "id": "#3875", "title": "Minutes", "fun": 2.26, "difficulty": 2.04, "author": "missie", "desc": "Exactly how many minutes is it before eight o'clock, if 40 minutes ago, it was three times as many minutes past four o'clock?", "hint": "No hint available.", "answer": "50 minutes.", "category": "Math", "date": "05/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nExactly how many minutes is it before eight o'clock, if 40 minutes ago, it was three times as many minutes past four o'clock?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n50 minutes.\n<|im_start|>answer\n50 minutes.\n<|im_end|>" }, { "id": "#6394", "title": "Box of Kebabs", "fun": 2.26, "difficulty": 2.11, "author": "mad-ade", "desc": "A box of kebabs weighs 25 kg divided by a quarter of it own weight. How much does the box of kebabs weigh?", "hint": "No hint available.", "answer": "10kg\r\n25 divided by 2.5 = 10", "category": "Math", "date": "08/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA box of kebabs weighs 25 kg divided by a quarter of it own weight. How much does the box of kebabs weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10kg\r\n25 divided by 2.5 = 10\n<|im_start|>answer\n10kg\r\n25 divided by 2.5 = 10\n<|im_end|>" }, { "id": "#5266", "title": "Total Odds", "fun": 2.26, "difficulty": 1.75, "author": "mad-ade", "desc": "All of the odd numbers from 1 to 999 are added together.\r\nWhat is the total?", "hint": "No hint available.", "answer": "250,000 (1 + 999) + (3 + 997) + . .(etc) . . . . + (499 + 501)", "category": "Math", "date": "07/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAll of the odd numbers from 1 to 999 are added together.\r\nWhat is the total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n250,000 (1 + 999) + (3 + 997) + . .(etc) . . . . + (499 + 501)\n<|im_start|>answer\n250,000 (1 + 999) + (3 + 997) + . .(etc) . . . . + (499 + 501)\n<|im_end|>" }, { "id": "#44106", "title": "Multiples of 7", "fun": 2.26, "difficulty": 1.25, "author": "shenqiang", "desc": "There are eight different 2-digit numbers: AD, BA, BG, CE, DB, DH, EF, and FC. Each is less than 70 and divisible by 7. Each of the distinct letters represents a different digit. The same letter represents the same digit. Given E=5, what is G?", "hint": "No hint available.", "answer": "8.\n\r\nSince E=5, F=6 and C=3.\r\nThe remaining numbers divisible by 7 are 14, 21, 28, 42 and 49. The number 1 appears in the tens digit only once; therefore, A=1, B=2, D=4, G=8, and H=9.", "category": "Logic", "date": "02/15/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are eight different 2-digit numbers: AD, BA, BG, CE, DB, DH, EF, and FC. Each is less than 70 and divisible by 7. Each of the distinct letters represents a different digit. The same letter represents the same digit. Given E=5, what is G?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8.\n\r\nSince E=5, F=6 and C=3.\r\nThe remaining numbers divisible by 7 are 14, 21, 28, 42 and 49. The number 1 appears in the tens digit only once; therefore, A=1, B=2, D=4, G=8, and H=9.\n<|im_start|>answer\n8.\n\r\nSince E=5, F=6 and C=3.\r\nThe remaining numbers divisible by 7 are 14, 21, 28, 42 and 49. The number 1 appears in the tens digit only once; therefore, A=1, B=2, D=4, G=8, and H=9.\n<|im_end|>" }, { "id": "#8880", "title": "6 Acorns", "fun": 2.26, "difficulty": 2.15, "author": "scharfy", "desc": "6 acorns there, have a look\r\n3 from them my mother took.\r\n2 were yellow, 1 was blue, \r\nThe other 3 I didn't think, just threw.\r\nBut when I was older one day\r\nhome I came to have a stay.\r\nTo my surprise there they were\r\nall 6 of them, there they are.\r\nThe 3 I threw were colored red\r\nBut in my delight came some dread,\r\nthey weren't in proper line I'd had.\n\n\r\nLet's give them names to make it easier.\r\nName Color Size\r\nA = Yellow = Small\r\nB = Red = Small\r\nC = Blue = Medium\r\nD = Red = Medium\r\nE = Yellow = Medium\r\nF = Red = Large\n\r\nI'll give clues for you to find the answer\r\n1)The smallest is always found between two mediums.\r\n2)The order starts and finishes with a red colored acorn.\r\n3)The blue acorn can be found in the 4th position.\r\n4)Red is not found beside its own.\n\r\nWhat order are they in?", "hint": "No hint available.", "answer": "The correct order is as follows:\n\r\nF, E, B, C, A, D", "category": "Logic", "date": "12/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n6 acorns there, have a look\r\n3 from them my mother took.\r\n2 were yellow, 1 was blue, \r\nThe other 3 I didn't think, just threw.\r\nBut when I was older one day\r\nhome I came to have a stay.\r\nTo my surprise there they were\r\nall 6 of them, there they are.\r\nThe 3 I threw were colored red\r\nBut in my delight came some dread,\r\nthey weren't in proper line I'd had.\n\n\r\nLet's give them names to make it easier.\r\nName Color Size\r\nA = Yellow = Small\r\nB = Red = Small\r\nC = Blue = Medium\r\nD = Red = Medium\r\nE = Yellow = Medium\r\nF = Red = Large\n\r\nI'll give clues for you to find the answer\r\n1)The smallest is always found between two mediums.\r\n2)The order starts and finishes with a red colored acorn.\r\n3)The blue acorn can be found in the 4th position.\r\n4)Red is not found beside its own.\n\r\nWhat order are they in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe correct order is as follows:\n\r\nF, E, B, C, A, D\n<|im_start|>answer\nThe correct order is as follows:\n\r\nF, E, B, C, A, D\n<|im_end|>" }, { "id": "#18621", "title": "The Sweaty Chef's Kebab Machine.", "fun": 2.26, "difficulty": 1.92, "author": "mad-ade", "desc": "In the \"Sweaty Chef Kebab shop\" there are many workers, full time and part time.\r\nTwo of those workers are Bea O'Problem and Jaqueline Hyde. One day they were asked to clean out the well-used and grease-encrusted Kebab machine. \r\nIt would take Bea an hour to do the job on her own, but it would only take Jaqueline 45 minutes. If they worked together for the first 12 minutes, then Bea left to do something else (like scrape salad off the pavement outside the shop), how long would it take Jaqueline to finish the job on her own?", "hint": "No hint available.", "answer": "Bea takes 60 mins to do a job \r\nJaqueline takes 45 mins to do a job (both given) \n\r\nIn 12 mins, Bea does 12/60 = 1/5 = 3/15ths of the job \n\r\nIn 12 mins, Jaqueline does 12/45 = 4/15ths of the job \n\r\nThus in 12 mins 7/15ths of the job has been done, and thus there is 1-7/15 = 8/15ths left to do \n\r\nSo on her own, to complete 8/15ths of a job that would take her 8/15 x 45 = 24 mins \n\r\nSo it would take Jaqueline 24 mins to complete the rest of the job on her own", "category": "Math", "date": "08/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the \"Sweaty Chef Kebab shop\" there are many workers, full time and part time.\r\nTwo of those workers are Bea O'Problem and Jaqueline Hyde. One day they were asked to clean out the well-used and grease-encrusted Kebab machine. \r\nIt would take Bea an hour to do the job on her own, but it would only take Jaqueline 45 minutes. If they worked together for the first 12 minutes, then Bea left to do something else (like scrape salad off the pavement outside the shop), how long would it take Jaqueline to finish the job on her own?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBea takes 60 mins to do a job \r\nJaqueline takes 45 mins to do a job (both given) \n\r\nIn 12 mins, Bea does 12/60 = 1/5 = 3/15ths of the job \n\r\nIn 12 mins, Jaqueline does 12/45 = 4/15ths of the job \n\r\nThus in 12 mins 7/15ths of the job has been done, and thus there is 1-7/15 = 8/15ths left to do \n\r\nSo on her own, to complete 8/15ths of a job that would take her 8/15 x 45 = 24 mins \n\r\nSo it would take Jaqueline 24 mins to complete the rest of the job on her own\n<|im_start|>answer\nBea takes 60 mins to do a job \r\nJaqueline takes 45 mins to do a job (both given) \n\r\nIn 12 mins, Bea does 12/60 = 1/5 = 3/15ths of the job \n\r\nIn 12 mins, Jaqueline does 12/45 = 4/15ths of the job \n\r\nThus in 12 mins 7/15ths of the job has been done, and thus there is 1-7/15 = 8/15ths left to do \n\r\nSo on her own, to complete 8/15ths of a job that would take her 8/15 x 45 = 24 mins \n\r\nSo it would take Jaqueline 24 mins to complete the rest of the job on her own\n<|im_end|>" }, { "id": "#19610", "title": "Mad Ade's Cousin's Raise", "fun": 2.26, "difficulty": 2.6, "author": "Mad-Ade", "desc": "In the legendary land of Madadia, everything is wonderful. There is no inflation, so Madadian wonks (local currency 100 winks = 1 wonk) are constant in value.\r\nMad Ade's cousin Manic Martin works as an accountant in one of Madadia's leading accounting firms.\r\nAfter his first year his salary was a straight 10,000 wonks, with which Manic Martin was quite happy. His manager was so impressed with his work he offered Manic Martin a wage rise.\r\nNow this being Madadia, things are not always done as they are elsewhere, the wage rise was offered over a 17.5 year contract period, These contracts are immutably binding, and will still be paid to benefactors in the event of death or permanent disability.\r\nManic Martin has a choice of how to receive his raise. The first option was for an immediate 5% raise to 10,500 wonks annually, with an additional 5% raise every 6 months. The second option was for an immediate 10% raise to 11,000 wonks annually, with an additional 10% raise every year. Manic Martin's salary, based upon his current annual, was paid bi-weekly.\r\nWhich deal would benefit Manic Martin the most?", "hint": "No hint available.", "answer": "The 5% semi-annual raise yields a higher return. \r\nThis may have been your first guess, but there is something odd about the answer. At the start of the problem, the 10% raise is earning more- 11,000 annually vs. 10,500. After the first year, the 5% option has earned 10,762 compared to 11,000. \n\r\nWhat are the two options earning at the moment the contract closes, after 17.5 years? Surprisingly, the 5% option only realizes a little more than 55,160, compared to the 10% option which is still ahead with just under 56,000. \n\r\nSo where's the advantage in the 5% option? It hides in the second half of every year. Even in the first year, the 5% option makes more in the second six months than the 10% option. For the first few years, this is not enough to offset the difference. But cumulatively, over seventeen and a half years, 5% realizes a grand total of 390.27 more than the 10% option. This in spite of the fact that the 10% option starts with a higher salary- and finishes with a higher salary.", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary land of Madadia, everything is wonderful. There is no inflation, so Madadian wonks (local currency 100 winks = 1 wonk) are constant in value.\r\nMad Ade's cousin Manic Martin works as an accountant in one of Madadia's leading accounting firms.\r\nAfter his first year his salary was a straight 10,000 wonks, with which Manic Martin was quite happy. His manager was so impressed with his work he offered Manic Martin a wage rise.\r\nNow this being Madadia, things are not always done as they are elsewhere, the wage rise was offered over a 17.5 year contract period, These contracts are immutably binding, and will still be paid to benefactors in the event of death or permanent disability.\r\nManic Martin has a choice of how to receive his raise. The first option was for an immediate 5% raise to 10,500 wonks annually, with an additional 5% raise every 6 months. The second option was for an immediate 10% raise to 11,000 wonks annually, with an additional 10% raise every year. Manic Martin's salary, based upon his current annual, was paid bi-weekly.\r\nWhich deal would benefit Manic Martin the most?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 5% semi-annual raise yields a higher return. \r\nThis may have been your first guess, but there is something odd about the answer. At the start of the problem, the 10% raise is earning more- 11,000 annually vs. 10,500. After the first year, the 5% option has earned 10,762 compared to 11,000. \n\r\nWhat are the two options earning at the moment the contract closes, after 17.5 years? Surprisingly, the 5% option only realizes a little more than 55,160, compared to the 10% option which is still ahead with just under 56,000. \n\r\nSo where's the advantage in the 5% option? It hides in the second half of every year. Even in the first year, the 5% option makes more in the second six months than the 10% option. For the first few years, this is not enough to offset the difference. But cumulatively, over seventeen and a half years, 5% realizes a grand total of 390.27 more than the 10% option. This in spite of the fact that the 10% option starts with a higher salary- and finishes with a higher salary.\n<|im_start|>answer\nThe 5% semi-annual raise yields a higher return. \r\nThis may have been your first guess, but there is something odd about the answer. At the start of the problem, the 10% raise is earning more- 11,000 annually vs. 10,500. After the first year, the 5% option has earned 10,762 compared to 11,000. \n\r\nWhat are the two options earning at the moment the contract closes, after 17.5 years? Surprisingly, the 5% option only realizes a little more than 55,160, compared to the 10% option which is still ahead with just under 56,000. \n\r\nSo where's the advantage in the 5% option? It hides in the second half of every year. Even in the first year, the 5% option makes more in the second six months than the 10% option. For the first few years, this is not enough to offset the difference. But cumulatively, over seventeen and a half years, 5% realizes a grand total of 390.27 more than the 10% option. This in spite of the fact that the 10% option starts with a higher salary- and finishes with a higher salary.\n<|im_end|>" }, { "id": "#15321", "title": "Willy Wallace's Window Cleaning", "fun": 2.26, "difficulty": 1.98, "author": "timmyboym", "desc": "Willy Wallace, the window cleaner, washes skyscraper windows every day. The skyscrapers all have 109 windows, and Willy Wallace washes 37 windows each day. There are a lot of skyscrapers towering next to each other (all identical to each other), and Willy Wallace is told to wash as many as he can. At the end of a particular day, he has washed only 1 window of a particular skyscraper. What day is this? How many full skyscrapers has he washed?", "hint": "No hint available.", "answer": "It is day 56 and he has washed 19 skyscrapers. He has washed 1 window of skyscraper number 20.", "category": "Math", "date": "11/04/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWilly Wallace, the window cleaner, washes skyscraper windows every day. The skyscrapers all have 109 windows, and Willy Wallace washes 37 windows each day. There are a lot of skyscrapers towering next to each other (all identical to each other), and Willy Wallace is told to wash as many as he can. At the end of a particular day, he has washed only 1 window of a particular skyscraper. What day is this? How many full skyscrapers has he washed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is day 56 and he has washed 19 skyscrapers. He has washed 1 window of skyscraper number 20.\n<|im_start|>answer\nIt is day 56 and he has washed 19 skyscrapers. He has washed 1 window of skyscraper number 20.\n<|im_end|>" }, { "id": "#14105", "title": "Family Ties", "fun": 2.26, "difficulty": 0.92, "author": "jubjub", "desc": "Mr. Black and his sister were passing by a hotel when Mr. Black said, \"My nephew is in there, and I would like to say hi.\" \r\n\"Since I don't have a nephew, I'll continue walking home,\" said Mr. Black's sister. \n\r\nWhat relation is the sister to the mysterious nephew?", "hint": "No hint available.", "answer": "His mother.", "category": "Logic", "date": "07/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Black and his sister were passing by a hotel when Mr. Black said, \"My nephew is in there, and I would like to say hi.\" \r\n\"Since I don't have a nephew, I'll continue walking home,\" said Mr. Black's sister. \n\r\nWhat relation is the sister to the mysterious nephew?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHis mother.\n<|im_start|>answer\nHis mother.\n<|im_end|>" }, { "id": "#5264", "title": "Car Boot Sale", "fun": 2.26, "difficulty": 2.42, "author": "mad-ade", "desc": "Mad Ade recently found just the things he wanted at a car-boot sale.\r\nThe way their prices were displayed was interesting. \r\n FIVE for 10p \r\n TWELVE for 18p \r\n FIFTEEN for 20p \r\n NINETEEN for 24p \n\r\n Mad Ade eventually worked out the 'logic' of the prices.\r\nWhat did ELEVEN cost him?", "hint": "No hint available.", "answer": "The logic seemed to be\r\nOdd numbers + 5\r\nEven numbers + 6\r\n=> ELEVEN for 16p", "category": "Math", "date": "07/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade recently found just the things he wanted at a car-boot sale.\r\nThe way their prices were displayed was interesting. \r\n FIVE for 10p \r\n TWELVE for 18p \r\n FIFTEEN for 20p \r\n NINETEEN for 24p \n\r\n Mad Ade eventually worked out the 'logic' of the prices.\r\nWhat did ELEVEN cost him?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe logic seemed to be\r\nOdd numbers + 5\r\nEven numbers + 6\r\n=> ELEVEN for 16p\n<|im_start|>answer\nThe logic seemed to be\r\nOdd numbers + 5\r\nEven numbers + 6\r\n=> ELEVEN for 16p\n<|im_end|>" }, { "id": "#14648", "title": "Farley's Fishing", "fun": 2.26, "difficulty": 2.72, "author": "taniapereira99", "desc": "Fred Farley spent his summers up north in a cottage on Stoney Lake. There, he often debated with his friends what type of bait was best to use for the fish in the waters. He decided one year to hold a fishing tournament with the best fishers on the lake, each using a different casting lure. 5 men competed (Fred Farley was NOT one of them) and points were awarded in four categories to determine a winner:\n\r\nGreatest total Weight of fish caught: 4 points\r\nGreatest Number of fish caught: 3 points\r\nLargest Fish: 2 points\r\nSecond-largest fish: 1 point\r\nWinning more than one category: 1 bonus point\n\r\nTwo fishermen did not win any of the categories and first place ended up being a tie between two men who received the same amount of points.\n\r\nFrom the statements below, determine the first and last name of each of the contestants, what casting lure was used, and who won each category.\n\r\n1. Mike (who was one of the category winners), Mr. Black (who is not Terry), and the one that used the plastic worm live near each other.\n\r\n2. Vick, who did not win the total weight category, did not use the spinner bait; nor did Mr. McNess.\n\r\n3. The one that used the weighted jig, who was not Terry, did not win any of the categories.\n\r\n4. Neither Sam nor Mr. Larson live near any of the other three contestants, nor did either use a spinner bait or deep-running crank bait.\n\r\n5. The fisherman who won the largest-fish category, who was not Mr. Smith, used spinner bait.\n\r\n6. Mr. Jones, who caught the most fish, did not use a deep-running crank bait.\n\r\n7. Both Mr. McNess (who did not use a deep running crank bait) and Terry (who did not use a plastic worm) had boat trouble and started after the others.\n\r\n8. A wounded-minnow was used as one of the casting lures, and Kevin was one of the contestants.", "hint": "Since only 3 of the contestants won the 4 categories, one of them won two and earned a bonus point. Since there were two first places, the only possible outcome was that they both received 4 points. Therefore, one contestant won the total weight category (4 points), and another won the largest, second largest category and earned a bonus point (2 + 1 + 1 points).", "answer": "Kevin Black, spinner bait, largest fish and second largest fish category, bonus for winning two categories, 4 points.\r\nMike Smith, crank bait, total weight, 4 points\r\nSam McNess, weighted jig, no category, 0 points\r\nTerry Larson, wounded minnow bait, no category, 0 points\r\nVick Jones, plastic worm, most fish, 3 points.\n\r\nFrom 1: Mike won a category, is not Mr. Black, and did not use the plastic worm. Mr. Black is not Mike or Terry and did not use the plastic worm.\n\r\nFrom 2: Vick is not Mr. Mc Ness, did not win total weight and did not use the spinner bait. Mr. McNess did not use the spinner bait.\n\r\nFrom 3: Terry did not use the weighted jig. The weighted jig won no category.\n\r\nFrom 4: Sam is not Larson or Black, and did not use the spinner, deep running crank or plastic worm bait. Mr. Larson is not Mike, and did not use the spinner, deep running crank or plastic worm bait.\n\r\nFrom 5: Mr. Smith did not win the largest fish or use the spinner bait. The largest fish was caught using the spinner bait. \n\r\nSince Vick and Sam did not use the spinner, they did not win the largest fish category. Since Mike won a category, he did not use the jig.\n\r\nFrom 6: Mr. Jones won the most fish and, therefore, did not use the spinner bait, did not use the deep running crank bait either. Therefore, Black used the spinner and was the largest fish winner. Since Vick did not win the largest fish, by elimination, Kevin is Mr. Black.\n\r\nFrom 7: Mr. McNess is not Terry and did not use a deep running crank bait. Therefore, Smith could have only used the crank bait. Terry did not use a worm. Therefore, Vick used the worm and Sam used the weighted jig (and therefore won no category). \n\r\nThe worm (used by Vick) was thereby only used by either McNess or Jones, and since 2 says Vick is not Mc Ness, Vick is therefore Jones.\n\r\nTerry, then, is Larson and won no category. Mike then wins the total weight category.\n\r\nThen by summing up the leftover information, Terry uses the minnow and leaves Mike with the deep-running crank bait. That, in turn, makes Mike's last name Smith. Sam is then McNess.", "category": "Logic", "date": "09/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred Farley spent his summers up north in a cottage on Stoney Lake. There, he often debated with his friends what type of bait was best to use for the fish in the waters. He decided one year to hold a fishing tournament with the best fishers on the lake, each using a different casting lure. 5 men competed (Fred Farley was NOT one of them) and points were awarded in four categories to determine a winner:\n\r\nGreatest total Weight of fish caught: 4 points\r\nGreatest Number of fish caught: 3 points\r\nLargest Fish: 2 points\r\nSecond-largest fish: 1 point\r\nWinning more than one category: 1 bonus point\n\r\nTwo fishermen did not win any of the categories and first place ended up being a tie between two men who received the same amount of points.\n\r\nFrom the statements below, determine the first and last name of each of the contestants, what casting lure was used, and who won each category.\n\r\n1. Mike (who was one of the category winners), Mr. Black (who is not Terry), and the one that used the plastic worm live near each other.\n\r\n2. Vick, who did not win the total weight category, did not use the spinner bait; nor did Mr. McNess.\n\r\n3. The one that used the weighted jig, who was not Terry, did not win any of the categories.\n\r\n4. Neither Sam nor Mr. Larson live near any of the other three contestants, nor did either use a spinner bait or deep-running crank bait.\n\r\n5. The fisherman who won the largest-fish category, who was not Mr. Smith, used spinner bait.\n\r\n6. Mr. Jones, who caught the most fish, did not use a deep-running crank bait.\n\r\n7. Both Mr. McNess (who did not use a deep running crank bait) and Terry (who did not use a plastic worm) had boat trouble and started after the others.\n\r\n8. A wounded-minnow was used as one of the casting lures, and Kevin was one of the contestants.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKevin Black, spinner bait, largest fish and second largest fish category, bonus for winning two categories, 4 points.\r\nMike Smith, crank bait, total weight, 4 points\r\nSam McNess, weighted jig, no category, 0 points\r\nTerry Larson, wounded minnow bait, no category, 0 points\r\nVick Jones, plastic worm, most fish, 3 points.\n\r\nFrom 1: Mike won a category, is not Mr. Black, and did not use the plastic worm. Mr. Black is not Mike or Terry and did not use the plastic worm.\n\r\nFrom 2: Vick is not Mr. Mc Ness, did not win total weight and did not use the spinner bait. Mr. McNess did not use the spinner bait.\n\r\nFrom 3: Terry did not use the weighted jig. The weighted jig won no category.\n\r\nFrom 4: Sam is not Larson or Black, and did not use the spinner, deep running crank or plastic worm bait. Mr. Larson is not Mike, and did not use the spinner, deep running crank or plastic worm bait.\n\r\nFrom 5: Mr. Smith did not win the largest fish or use the spinner bait. The largest fish was caught using the spinner bait. \n\r\nSince Vick and Sam did not use the spinner, they did not win the largest fish category. Since Mike won a category, he did not use the jig.\n\r\nFrom 6: Mr. Jones won the most fish and, therefore, did not use the spinner bait, did not use the deep running crank bait either. Therefore, Black used the spinner and was the largest fish winner. Since Vick did not win the largest fish, by elimination, Kevin is Mr. Black.\n\r\nFrom 7: Mr. McNess is not Terry and did not use a deep running crank bait. Therefore, Smith could have only used the crank bait. Terry did not use a worm. Therefore, Vick used the worm and Sam used the weighted jig (and therefore won no category). \n\r\nThe worm (used by Vick) was thereby only used by either McNess or Jones, and since 2 says Vick is not Mc Ness, Vick is therefore Jones.\n\r\nTerry, then, is Larson and won no category. Mike then wins the total weight category.\n\r\nThen by summing up the leftover information, Terry uses the minnow and leaves Mike with the deep-running crank bait. That, in turn, makes Mike's last name Smith. Sam is then McNess.\n<|im_start|>answer\nKevin Black, spinner bait, largest fish and second largest fish category, bonus for winning two categories, 4 points.\r\nMike Smith, crank bait, total weight, 4 points\r\nSam McNess, weighted jig, no category, 0 points\r\nTerry Larson, wounded minnow bait, no category, 0 points\r\nVick Jones, plastic worm, most fish, 3 points.\n\r\nFrom 1: Mike won a category, is not Mr. Black, and did not use the plastic worm. Mr. Black is not Mike or Terry and did not use the plastic worm.\n\r\nFrom 2: Vick is not Mr. Mc Ness, did not win total weight and did not use the spinner bait. Mr. McNess did not use the spinner bait.\n\r\nFrom 3: Terry did not use the weighted jig. The weighted jig won no category.\n\r\nFrom 4: Sam is not Larson or Black, and did not use the spinner, deep running crank or plastic worm bait. Mr. Larson is not Mike, and did not use the spinner, deep running crank or plastic worm bait.\n\r\nFrom 5: Mr. Smith did not win the largest fish or use the spinner bait. The largest fish was caught using the spinner bait. \n\r\nSince Vick and Sam did not use the spinner, they did not win the largest fish category. Since Mike won a category, he did not use the jig.\n\r\nFrom 6: Mr. Jones won the most fish and, therefore, did not use the spinner bait, did not use the deep running crank bait either. Therefore, Black used the spinner and was the largest fish winner. Since Vick did not win the largest fish, by elimination, Kevin is Mr. Black.\n\r\nFrom 7: Mr. McNess is not Terry and did not use a deep running crank bait. Therefore, Smith could have only used the crank bait. Terry did not use a worm. Therefore, Vick used the worm and Sam used the weighted jig (and therefore won no category). \n\r\nThe worm (used by Vick) was thereby only used by either McNess or Jones, and since 2 says Vick is not Mc Ness, Vick is therefore Jones.\n\r\nTerry, then, is Larson and won no category. Mike then wins the total weight category.\n\r\nThen by summing up the leftover information, Terry uses the minnow and leaves Mike with the deep-running crank bait. That, in turn, makes Mike's last name Smith. Sam is then McNess.\n<|im_end|>" }, { "id": "#37998", "title": "Guess Your Color to Escape!", "fun": 2.26, "difficulty": 2.46, "author": "spinnercat", "desc": "A warden at a prison decides to give some prisoners a chance to escape by working together to solve a puzzle. He prepares a colored hat for every one of them and tells them the rules. The hats can be either black or white and will be placed on everyone's head. The prisoners will get a chance to discuss a strategy together, which they will all follow, then they will be marched out into a large room where they will see everybody else's hat color. Each prisoner will then simultaneously guess which of the two hat colors they have. If every one of them is right, or every one of them is wrong, they will all go free. However, the prisoners will not be allowed to communicate in any way during this process. Also, the warden will hear their strategy and place hats any way he can to prevent them from going free. What strategy do they use to escape?", "hint": "Think about it for two people and then three people. What will be the difference between what a white hatted person sees and a black hatted person sees?", "answer": "Every prisoner should count up how many black hats they see. If they count an odd number of black hats, they say that they have a black hat. If they count an even number of black hats, then they say that they have a white hat.", "category": "Logic", "date": "08/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA warden at a prison decides to give some prisoners a chance to escape by working together to solve a puzzle. He prepares a colored hat for every one of them and tells them the rules. The hats can be either black or white and will be placed on everyone's head. The prisoners will get a chance to discuss a strategy together, which they will all follow, then they will be marched out into a large room where they will see everybody else's hat color. Each prisoner will then simultaneously guess which of the two hat colors they have. If every one of them is right, or every one of them is wrong, they will all go free. However, the prisoners will not be allowed to communicate in any way during this process. Also, the warden will hear their strategy and place hats any way he can to prevent them from going free. What strategy do they use to escape?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEvery prisoner should count up how many black hats they see. If they count an odd number of black hats, they say that they have a black hat. If they count an even number of black hats, then they say that they have a white hat.\n<|im_start|>answer\nEvery prisoner should count up how many black hats they see. If they count an odd number of black hats, they say that they have a black hat. If they count an even number of black hats, then they say that they have a white hat.\n<|im_end|>" }, { "id": "#18054", "title": "Mad Ade's Escalator Journey", "fun": 2.26, "difficulty": 2.07, "author": "mad-ade", "desc": "Mad Ade once had a job working in the famous Madadian department store \"Horrids\".\r\nHe used the stores escalator on a daily basis as he skived from duty to duty.\r\nHe noticed on one particularly boring day that if he ran up 8 stairs of the escalator from the bottom step, the journey to the top took exactly 40 seconds.\r\nOn a later escalator trip he noticed that if he ran up 15 stairs of the escalator the journey time decreased to only 22.5 seconds.\n\r\nKnowing this, how long would it take Mad Ade to complete the full journey if he did not run up any stairs at all?\r\nCan you work out how many steps of the escalator are actually visible at any one time?", "hint": "No hint available.", "answer": "It takes Mad Ade 60 seconds to reach the top, and there are 24 steps visible on the escalator when it's stationary. \n\r\nRunning up 7 more steps reduces the time by 17.5 seconds, so running up 1 step reduces the time by 2.5 seconds, so each step takes 2.5 seconds. \n\r\nSo the escalator cycles through 24 steps on a complete trip from base to top. To illustrate: \n\r\n8+(40/2.5)=24 steps \r\n15+(22.5/2.5)=24 steps \n\r\nThe escalator cycles through all 24 steps in 24(2.5)=60 seconds", "category": "Logic", "date": "06/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade once had a job working in the famous Madadian department store \"Horrids\".\r\nHe used the stores escalator on a daily basis as he skived from duty to duty.\r\nHe noticed on one particularly boring day that if he ran up 8 stairs of the escalator from the bottom step, the journey to the top took exactly 40 seconds.\r\nOn a later escalator trip he noticed that if he ran up 15 stairs of the escalator the journey time decreased to only 22.5 seconds.\n\r\nKnowing this, how long would it take Mad Ade to complete the full journey if he did not run up any stairs at all?\r\nCan you work out how many steps of the escalator are actually visible at any one time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt takes Mad Ade 60 seconds to reach the top, and there are 24 steps visible on the escalator when it's stationary. \n\r\nRunning up 7 more steps reduces the time by 17.5 seconds, so running up 1 step reduces the time by 2.5 seconds, so each step takes 2.5 seconds. \n\r\nSo the escalator cycles through 24 steps on a complete trip from base to top. To illustrate: \n\r\n8+(40/2.5)=24 steps \r\n15+(22.5/2.5)=24 steps \n\r\nThe escalator cycles through all 24 steps in 24(2.5)=60 seconds\n<|im_start|>answer\nIt takes Mad Ade 60 seconds to reach the top, and there are 24 steps visible on the escalator when it's stationary. \n\r\nRunning up 7 more steps reduces the time by 17.5 seconds, so running up 1 step reduces the time by 2.5 seconds, so each step takes 2.5 seconds. \n\r\nSo the escalator cycles through 24 steps on a complete trip from base to top. To illustrate: \n\r\n8+(40/2.5)=24 steps \r\n15+(22.5/2.5)=24 steps \n\r\nThe escalator cycles through all 24 steps in 24(2.5)=60 seconds\n<|im_end|>" }, { "id": "#15204", "title": "Mad Ade's Watch", "fun": 2.26, "difficulty": 2.53, "author": "mad-ade", "desc": "Predictably Mad Ade is once again waiting for the \"Sweaty Chef Kebab Shop\" to open (he always arrives early). \r\nIn this instance he has arrived over an hour early and as a consequence stands looking at his watch and counting the seconds and minutes until the \"Sweaty Chef\" opens.\r\nHe noticed something odd about his watch: \r\nThe minute and the hour hand meet every 65 minutes exactly. \n\r\nHow much does the watch lose or gain time and by how much per hour?", "hint": "No hint available.", "answer": "The minute and the hour hand should meet 11 times in 12 hours in a normal watch i.e. they meet after every \r\n= (12 * 60) / 11 minutes \r\n= 65.45 minutes or 65 minutes and 27.16 seconds \n\r\nBut in Mad Ade's case they meet after every 65 minutes, which means the watch is gaining 27.16 seconds per hour.", "category": "Math", "date": "10/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPredictably Mad Ade is once again waiting for the \"Sweaty Chef Kebab Shop\" to open (he always arrives early). \r\nIn this instance he has arrived over an hour early and as a consequence stands looking at his watch and counting the seconds and minutes until the \"Sweaty Chef\" opens.\r\nHe noticed something odd about his watch: \r\nThe minute and the hour hand meet every 65 minutes exactly. \n\r\nHow much does the watch lose or gain time and by how much per hour?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe minute and the hour hand should meet 11 times in 12 hours in a normal watch i.e. they meet after every \r\n= (12 * 60) / 11 minutes \r\n= 65.45 minutes or 65 minutes and 27.16 seconds \n\r\nBut in Mad Ade's case they meet after every 65 minutes, which means the watch is gaining 27.16 seconds per hour.\n<|im_start|>answer\nThe minute and the hour hand should meet 11 times in 12 hours in a normal watch i.e. they meet after every \r\n= (12 * 60) / 11 minutes \r\n= 65.45 minutes or 65 minutes and 27.16 seconds \n\r\nBut in Mad Ade's case they meet after every 65 minutes, which means the watch is gaining 27.16 seconds per hour.\n<|im_end|>" }, { "id": "#8066", "title": "Arthur Minit's Clock", "fun": 2.26, "difficulty": 2.81, "author": "mad-ade", "desc": "Mad Ade was visiting his friend, computer tycoon and Olympic Kebab hurling champion, Mike Rohsopht.\n\r\nHe was there on Sunday and when the radio gave the time at the hour, Mad Ade noticed that the Madadian antique clock, designed by Madadian clock maker Arthur Minit (teaser #4891) was exactly 3 minutes slow.\n\r\n\"It loses 7 minutes every hour,\" said Mad Ade's friend. \"No more and no less, but I've gotten used to it that way.\"\n\r\nWhen Mad Ade spent a second evening with Mike Rohsopht later that same month, he remarked on the fact that the clock was dead right by radio time at the hour.\r\nIt was rather late in the evening, but Mike assured Mad Ade that his treasured Arthur Minit clock had not been adjusted nor fixed since his last visit.\n\r\nWhat day of the week was Mad Ade's second visit?", "hint": "No hint available.", "answer": "The answer is 17 days and 3 hours later, which would have been a Wednesday.\r\nThis is the only other time in the same month when the two would agree at all.\n\r\nIn 17 days the slow clock loses 17*24*7 minutes = 2856 minutes, or 47 hours and 36 minutes. In 3 hours more it loses 21 minutes, so it has lost a total of 47 hours and 57 minutes. Modulo 12 hours, it has \"gained\" 3 minutes so as to make up the 3 minutes it was slow on Sunday. It is now (fortnight plus 3 days) exactly accurate.\n\r\nSince the clock was not adjusted since the last visit, it's also possible that the radio time shifted by one hour due to a change to or from summer daylight saving time. However, it turns out that the only additional possibilities that need to be considered are those of 4 days 15 hours later, when the clock would have lost 12 hours 57 minutes, and 29 days 15 hours later, when the clock would have lost 3 days 10 hours 57 minutes. Without even considering the rules for when in the month the\r\nclock is changed, these possible solutions are ruled out because we know that both visits were in the evening (\"Mad Ade spent a second evening with Mike Rohsopht\") and they involve times in a different part of the day.", "category": "Math", "date": "10/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was visiting his friend, computer tycoon and Olympic Kebab hurling champion, Mike Rohsopht.\n\r\nHe was there on Sunday and when the radio gave the time at the hour, Mad Ade noticed that the Madadian antique clock, designed by Madadian clock maker Arthur Minit (teaser #4891) was exactly 3 minutes slow.\n\r\n\"It loses 7 minutes every hour,\" said Mad Ade's friend. \"No more and no less, but I've gotten used to it that way.\"\n\r\nWhen Mad Ade spent a second evening with Mike Rohsopht later that same month, he remarked on the fact that the clock was dead right by radio time at the hour.\r\nIt was rather late in the evening, but Mike assured Mad Ade that his treasured Arthur Minit clock had not been adjusted nor fixed since his last visit.\n\r\nWhat day of the week was Mad Ade's second visit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 17 days and 3 hours later, which would have been a Wednesday.\r\nThis is the only other time in the same month when the two would agree at all.\n\r\nIn 17 days the slow clock loses 17*24*7 minutes = 2856 minutes, or 47 hours and 36 minutes. In 3 hours more it loses 21 minutes, so it has lost a total of 47 hours and 57 minutes. Modulo 12 hours, it has \"gained\" 3 minutes so as to make up the 3 minutes it was slow on Sunday. It is now (fortnight plus 3 days) exactly accurate.\n\r\nSince the clock was not adjusted since the last visit, it's also possible that the radio time shifted by one hour due to a change to or from summer daylight saving time. However, it turns out that the only additional possibilities that need to be considered are those of 4 days 15 hours later, when the clock would have lost 12 hours 57 minutes, and 29 days 15 hours later, when the clock would have lost 3 days 10 hours 57 minutes. Without even considering the rules for when in the month the\r\nclock is changed, these possible solutions are ruled out because we know that both visits were in the evening (\"Mad Ade spent a second evening with Mike Rohsopht\") and they involve times in a different part of the day.\n<|im_start|>answer\nThe answer is 17 days and 3 hours later, which would have been a Wednesday.\r\nThis is the only other time in the same month when the two would agree at all.\n\r\nIn 17 days the slow clock loses 17*24*7 minutes = 2856 minutes, or 47 hours and 36 minutes. In 3 hours more it loses 21 minutes, so it has lost a total of 47 hours and 57 minutes. Modulo 12 hours, it has \"gained\" 3 minutes so as to make up the 3 minutes it was slow on Sunday. It is now (fortnight plus 3 days) exactly accurate.\n\r\nSince the clock was not adjusted since the last visit, it's also possible that the radio time shifted by one hour due to a change to or from summer daylight saving time. However, it turns out that the only additional possibilities that need to be considered are those of 4 days 15 hours later, when the clock would have lost 12 hours 57 minutes, and 29 days 15 hours later, when the clock would have lost 3 days 10 hours 57 minutes. Without even considering the rules for when in the month the\r\nclock is changed, these possible solutions are ruled out because we know that both visits were in the evening (\"Mad Ade spent a second evening with Mike Rohsopht\") and they involve times in a different part of the day.\n<|im_end|>" }, { "id": "#32429", "title": "CrossDigit 1", "fun": 2.26, "difficulty": 1.59, "author": "dishu", "desc": "This teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 3 by 3 grid. The grid is arranged as follows:\n\r\nA1 A2 A3\r\nB1 B2 B3\r\nC1 C2 C3\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row can have the same digit appearing more than once.\r\n2: No column can have the same digit appearing more than once.\r\n3: 0 (Zero) is not permissible.\r\n4: Empty spaces cannot contain any digits. They are empty.\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A3, B3 and C1.\r\n2. The sum of digits in row A equal 15.\r\n3. The sum of digits in row B equal 3.\r\n4. The sum of digits in row C equal 13.\r\n5. The sum of digits in column 1 equal 7.\r\n6. The sum of digits in column 2 equal 19.\r\n7. The sum of digits in column 3 equal 5.\n\r\nNow figure out which box contains which digit and do not forget the rules.", "hint": "No hint available.", "answer": "The digits are laid out as follows:\r\nA1: 6, A2: 9, A3: Blank\r\nB1: 1, B2: 2, B3: Blank\r\nC1: Blank, C2: 8, C3: 5", "category": "Math", "date": "08/13/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 3 by 3 grid. The grid is arranged as follows:\n\r\nA1 A2 A3\r\nB1 B2 B3\r\nC1 C2 C3\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row can have the same digit appearing more than once.\r\n2: No column can have the same digit appearing more than once.\r\n3: 0 (Zero) is not permissible.\r\n4: Empty spaces cannot contain any digits. They are empty.\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A3, B3 and C1.\r\n2. The sum of digits in row A equal 15.\r\n3. The sum of digits in row B equal 3.\r\n4. The sum of digits in row C equal 13.\r\n5. The sum of digits in column 1 equal 7.\r\n6. The sum of digits in column 2 equal 19.\r\n7. The sum of digits in column 3 equal 5.\n\r\nNow figure out which box contains which digit and do not forget the rules.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe digits are laid out as follows:\r\nA1: 6, A2: 9, A3: Blank\r\nB1: 1, B2: 2, B3: Blank\r\nC1: Blank, C2: 8, C3: 5\n<|im_start|>answer\nThe digits are laid out as follows:\r\nA1: 6, A2: 9, A3: Blank\r\nB1: 1, B2: 2, B3: Blank\r\nC1: Blank, C2: 8, C3: 5\n<|im_end|>" }, { "id": "#21464", "title": "1 = 2", "fun": 2.26, "difficulty": 2.33, "author": "munchtipq", "desc": "Bob and Sue were having a discussion one day about 1 and 2. Sue reckoned she had seen a way that you could make 1 = 2 but Bob who wasn't called 'logical Bob' for nothing was obviously adamant that this just wasn't possible. Sue said \"Ok smarty pants here's the equation to prove you wrong\"...\n\r\nAssumptions: There are two numbers, a and b, and they are equal.\n\r\nProof:\n\r\na = b\n\r\nMultiply the equation by b\n\r\nab = b^2\n\r\nSubtract a^2 from the equation\n\r\nab - a^2 = b^2 - a^2\n\r\nFactor difference of squares\n\r\nab - a^2 = (b - a)(b + a)\n\r\nFactor a on the left-hand side\n\r\na(b - a) = (b - a)(b + a)\n\r\nDivide by common factor\n\r\na = (b + a)\n\r\nSubstitute a for b\n\r\na = (a + a)\n\r\nSimplify\n\r\na = 2a\n\r\nDivide by common factor\n\r\n1 = 2\n\r\nQuestion:\n\r\nBob didn't take long and found the line where there is a crucial mistake in the working though was understanding of Sue's issue as it is well hidden... can you see it?", "hint": "Give a and b a value and look at the numbers at each step.", "answer": "Going from a(b - a) = (b - a)(b + a) to a = (b + a) is not allowed, because the equation is divided by (b - a), which is equal to 0, given that a = b.", "category": "Math", "date": "03/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob and Sue were having a discussion one day about 1 and 2. Sue reckoned she had seen a way that you could make 1 = 2 but Bob who wasn't called 'logical Bob' for nothing was obviously adamant that this just wasn't possible. Sue said \"Ok smarty pants here's the equation to prove you wrong\"...\n\r\nAssumptions: There are two numbers, a and b, and they are equal.\n\r\nProof:\n\r\na = b\n\r\nMultiply the equation by b\n\r\nab = b^2\n\r\nSubtract a^2 from the equation\n\r\nab - a^2 = b^2 - a^2\n\r\nFactor difference of squares\n\r\nab - a^2 = (b - a)(b + a)\n\r\nFactor a on the left-hand side\n\r\na(b - a) = (b - a)(b + a)\n\r\nDivide by common factor\n\r\na = (b + a)\n\r\nSubstitute a for b\n\r\na = (a + a)\n\r\nSimplify\n\r\na = 2a\n\r\nDivide by common factor\n\r\n1 = 2\n\r\nQuestion:\n\r\nBob didn't take long and found the line where there is a crucial mistake in the working though was understanding of Sue's issue as it is well hidden... can you see it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGoing from a(b - a) = (b - a)(b + a) to a = (b + a) is not allowed, because the equation is divided by (b - a), which is equal to 0, given that a = b.\n<|im_start|>answer\nGoing from a(b - a) = (b - a)(b + a) to a = (b + a) is not allowed, because the equation is divided by (b - a), which is equal to 0, given that a = b.\n<|im_end|>" }, { "id": "#4066", "title": "The Magic Shop", "fun": 2.26, "difficulty": 2.18, "author": "GoldieLuvNeopets", "desc": "One day a mysterious figure burst into Laura's Magic Shop and posed her with a puzzle. \n\r\nSlapping down a huge amount of money on the counter, he said \"Divide $1083 (in whole dollar increments) into a number of bags, so that I can ask for any amount between $1 and $1083, and you can give me the proper amount by giving me a certain number of these bags without opening them. \n\r\nIf you are correct, you keep the money. If you aren't, you owe me one of your special potions...\"\n\r\nLaura took the challenge, being a very smart girl. What is the minimum number of bags Laura will require?", "hint": "No hint available.", "answer": "11 bags, filled as follows. \n\r\n1, 2, 4, 8, 16, 32, 60, 64, 126, 256, 512", "category": "Math", "date": "05/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day a mysterious figure burst into Laura's Magic Shop and posed her with a puzzle. \n\r\nSlapping down a huge amount of money on the counter, he said \"Divide $1083 (in whole dollar increments) into a number of bags, so that I can ask for any amount between $1 and $1083, and you can give me the proper amount by giving me a certain number of these bags without opening them. \n\r\nIf you are correct, you keep the money. If you aren't, you owe me one of your special potions...\"\n\r\nLaura took the challenge, being a very smart girl. What is the minimum number of bags Laura will require?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11 bags, filled as follows. \n\r\n1, 2, 4, 8, 16, 32, 60, 64, 126, 256, 512\n<|im_start|>answer\n11 bags, filled as follows. \n\r\n1, 2, 4, 8, 16, 32, 60, 64, 126, 256, 512\n<|im_end|>" }, { "id": "#322", "title": "The Handshakes.", "fun": 2.26, "difficulty": 1.1, "author": "Mr. G", "desc": "Four people shake hands with each other only once. How many handshakes occurred?", "hint": "No hint available.", "answer": "Six.\r\nIf each person is named A, B, C, and D, then the six handshakes are AB, AC, AD, BC, BD, and CD", "category": "Math", "date": "03/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people shake hands with each other only once. How many handshakes occurred?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSix.\r\nIf each person is named A, B, C, and D, then the six handshakes are AB, AC, AD, BC, BD, and CD\n<|im_start|>answer\nSix.\r\nIf each person is named A, B, C, and D, then the six handshakes are AB, AC, AD, BC, BD, and CD\n<|im_end|>" }, { "id": "#4865", "title": "Young Old Lady", "fun": 2.26, "difficulty": 1.69, "author": "mad-ade", "desc": "Whilst relieving his bladder in a shop doorway one Friday night, Mad Ade met a lady who has 2 children, 3 grandchildren, and 4 great grandchildren. The lady who had all of these kids told Mad Ade that she was only 25. \n\r\nHow is this possible?", "hint": "No hint available.", "answer": "The lady was born on 29th February. Her birthday comes once every 4 years. Thus, her age is 25, but she is actually 100 years old. By the way, she reported Mad Ade to the police.", "category": "Logic", "date": "06/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhilst relieving his bladder in a shop doorway one Friday night, Mad Ade met a lady who has 2 children, 3 grandchildren, and 4 great grandchildren. The lady who had all of these kids told Mad Ade that she was only 25. \n\r\nHow is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lady was born on 29th February. Her birthday comes once every 4 years. Thus, her age is 25, but she is actually 100 years old. By the way, she reported Mad Ade to the police.\n<|im_start|>answer\nThe lady was born on 29th February. Her birthday comes once every 4 years. Thus, her age is 25, but she is actually 100 years old. By the way, she reported Mad Ade to the police.\n<|im_end|>" }, { "id": "#3352", "title": "Half the Distance", "fun": 2.26, "difficulty": 1.83, "author": "lil_thugsta", "desc": "You can imagine an arrow in flight, toward a target. For the arrow to reach the target, the arrow must first travel half of the overall distance from the starting point to the target. Next, the arrow must travel half of the remaining distance.\n\r\nFor example, if the starting distance was 10m, the arrow first travels 5m, then 2.5m.\n\r\nIf you extends this concept further, you can imagine the resulting distances getting smaller and smaller. Will the arrow ever reach the target?", "hint": "No hint available.", "answer": "Yes. This is because the sum of an infinite series can be a finite number. Thus, 1/2 + 1/4 + 1/8 + ... = 1 and the arrow hits the target.", "category": "Math", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou can imagine an arrow in flight, toward a target. For the arrow to reach the target, the arrow must first travel half of the overall distance from the starting point to the target. Next, the arrow must travel half of the remaining distance.\n\r\nFor example, if the starting distance was 10m, the arrow first travels 5m, then 2.5m.\n\r\nIf you extends this concept further, you can imagine the resulting distances getting smaller and smaller. Will the arrow ever reach the target?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes. This is because the sum of an infinite series can be a finite number. Thus, 1/2 + 1/4 + 1/8 + ... = 1 and the arrow hits the target.\n<|im_start|>answer\nYes. This is because the sum of an infinite series can be a finite number. Thus, 1/2 + 1/4 + 1/8 + ... = 1 and the arrow hits the target.\n<|im_end|>" }, { "id": "#4567", "title": "Weighing Stuff", "fun": 2.26, "difficulty": 2.26, "author": "mad-ade", "desc": "Due to the local Kebab shop being closed, Mad Ade has some spare time on his hands, so he is playing around with a two-plate scale and finds that the scale stays in equilibrium if one plate is filled with two keys, two coins and three toy soldiers OR one apple, one toy soldier and one lemon, and the other plate with a weight of 100 grams. One coin, one key, one soldier and one plum together weigh 50 grams. The lemon, the apple and the plum weigh exactly the same as one coin, one key, one soldier and one pen. \n\r\nHow much does the pen weigh?", "hint": "No hint available.", "answer": "50 grams.", "category": "Math", "date": "06/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDue to the local Kebab shop being closed, Mad Ade has some spare time on his hands, so he is playing around with a two-plate scale and finds that the scale stays in equilibrium if one plate is filled with two keys, two coins and three toy soldiers OR one apple, one toy soldier and one lemon, and the other plate with a weight of 100 grams. One coin, one key, one soldier and one plum together weigh 50 grams. The lemon, the apple and the plum weigh exactly the same as one coin, one key, one soldier and one pen. \n\r\nHow much does the pen weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n50 grams.\n<|im_start|>answer\n50 grams.\n<|im_end|>" }, { "id": "#5550", "title": "Anniversary", "fun": 2.26, "difficulty": 1.67, "author": "mad-ade", "desc": "On Mad Ade's parents' wedding anniversary, four years ago, Mad Ade's mother was able to say to Mad Ade's father, that she had been married to him for three-fifths of her life, but that he had been married to her for only one-half of his life.\r\nBut then, there is a 10-year difference in Mr and Mrs Mad Ade seniors' ages. \r\nHow long have they been married and what were their ages four years ago?", "hint": "No hint available.", "answer": "They have been married 34 years (= 30 + 4)\r\nFour years ago Mad Ade's mother was 50 (3/5 of 50= 30)\r\nMad Ade's father was 60 (1/2 of 60= 30)", "category": "Math", "date": "07/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Mad Ade's parents' wedding anniversary, four years ago, Mad Ade's mother was able to say to Mad Ade's father, that she had been married to him for three-fifths of her life, but that he had been married to her for only one-half of his life.\r\nBut then, there is a 10-year difference in Mr and Mrs Mad Ade seniors' ages. \r\nHow long have they been married and what were their ages four years ago?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey have been married 34 years (= 30 + 4)\r\nFour years ago Mad Ade's mother was 50 (3/5 of 50= 30)\r\nMad Ade's father was 60 (1/2 of 60= 30)\n<|im_start|>answer\nThey have been married 34 years (= 30 + 4)\r\nFour years ago Mad Ade's mother was 50 (3/5 of 50= 30)\r\nMad Ade's father was 60 (1/2 of 60= 30)\n<|im_end|>" }, { "id": "#2234", "title": "A + B = C", "fun": 2.26, "difficulty": 1.69, "author": "joelfelix21", "desc": "If A + B = C, what does C + D equal?", "hint": "No hint available.", "answer": "G, because each letter represents the number it is in the alphabet.\r\nFor example: A = 1, B = 2, etc.", "category": "Logic", "date": "02/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf A + B = C, what does C + D equal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nG, because each letter represents the number it is in the alphabet.\r\nFor example: A = 1, B = 2, etc.\n<|im_start|>answer\nG, because each letter represents the number it is in the alphabet.\r\nFor example: A = 1, B = 2, etc.\n<|im_end|>" }, { "id": "#4257", "title": "Two Pages of a Book", "fun": 2.26, "difficulty": 1.58, "author": "arij", "desc": "When Sumei opens a book, two pages face her. If the product of the two page numbers is 3192, what are the two page numbers?", "hint": "No hint available.", "answer": "56 and 57", "category": "Math", "date": "05/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Sumei opens a book, two pages face her. If the product of the two page numbers is 3192, what are the two page numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n56 and 57\n<|im_start|>answer\n56 and 57\n<|im_end|>" }, { "id": "#4629", "title": "Shipwrecked Again", "fun": 2.26, "difficulty": 1.6, "author": "mad-ade", "desc": "Once again Mad Ade had been shipwrecked and was the shipwreck's lone survivor. Stranded on a desert island, dreaming of Kebabs and dying of thirst, Mad Ade luckily found a little pocket of water on the shore which had pooled in a rock. Unfortunately, the only thing he had salvaged from the ship was a spoon which was of little use in scooping out the water. Since the crevasse is too narrow to make a ladle, how does Mad Ade manage to spoon the water out?", "hint": "No hint available.", "answer": "Mad Ade began dropping the readily available pebbles into the hole until the water level had risen enough for the spoon to be effective; but sadly for Mad Ade he never got a kebab.", "category": "Logic", "date": "06/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce again Mad Ade had been shipwrecked and was the shipwreck's lone survivor. Stranded on a desert island, dreaming of Kebabs and dying of thirst, Mad Ade luckily found a little pocket of water on the shore which had pooled in a rock. Unfortunately, the only thing he had salvaged from the ship was a spoon which was of little use in scooping out the water. Since the crevasse is too narrow to make a ladle, how does Mad Ade manage to spoon the water out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade began dropping the readily available pebbles into the hole until the water level had risen enough for the spoon to be effective; but sadly for Mad Ade he never got a kebab.\n<|im_start|>answer\nMad Ade began dropping the readily available pebbles into the hole until the water level had risen enough for the spoon to be effective; but sadly for Mad Ade he never got a kebab.\n<|im_end|>" }, { "id": "#4863", "title": "Big Number", "fun": 2.26, "difficulty": 1.66, "author": "mad-ade", "desc": "Multiply by 7 the number of 8's immediately followed by 3, but not by 5, in the number below: \n\r\n381654783298514285838385737983256941837408326 \n\r\nIt looks a lot harder than it really is!", "hint": "No hint available.", "answer": "Simply count the occurrences of 83 \r\nThere are 6 (six) 8's followed by 3 \r\nNow multiply it by 7 \n\r\nHence the answer is 42.", "category": "Math", "date": "06/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMultiply by 7 the number of 8's immediately followed by 3, but not by 5, in the number below: \n\r\n381654783298514285838385737983256941837408326 \n\r\nIt looks a lot harder than it really is!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSimply count the occurrences of 83 \r\nThere are 6 (six) 8's followed by 3 \r\nNow multiply it by 7 \n\r\nHence the answer is 42.\n<|im_start|>answer\nSimply count the occurrences of 83 \r\nThere are 6 (six) 8's followed by 3 \r\nNow multiply it by 7 \n\r\nHence the answer is 42.\n<|im_end|>" }, { "id": "#21650", "title": "2 < 1", "fun": 2.26, "difficulty": 2.1, "author": "munchtipq", "desc": "Sue was disappointed after Bob showed her that 2 was not, in fact, equal to 1. She was not quite done, though. She told Bob that while 2 may not be equal to 1, she could show conclusively that 2 was in fact less than 1. Bob said it couldn't be done, of course, and Sue offered the following:\n\r\nProof:\n\r\n1 < 2\n\r\nMultiply the equation by log (0.5)\n\r\n1 * log(0.5) < 2 * log(0.5)\n\r\nMake the log factors exponents\n\r\nlog(0.5 ^ 1) < log(0.5 ^ 2)\n\r\nCarry out the exponentiation\n\r\nlog(0.5) < log(0.25)\n\r\nRaise 10 to the power of each side of the inequality\n\r\n10^(log(0.5)) < 10^(log(0.25))\n\r\nBy definition of logarithms, 10^log(a) = a, so...\n\r\n0.5 < 0.25\n\r\nThen just multiply both sides by 4\n\r\n2 < 1\n\r\nQuestion:\n\r\nBob found the problem almost immediately. Can you?", "hint": "Remember that the logarithm of any number less than 1 is less than 0.", "answer": "When Sue multiplied the inequality by log(0.5), she was multiplying by a negative number, and multiplying an inequality by a negative number switches the direction. This first step should result in:\n\r\n1 * log(0.5) > 2 * log(0.5), which leads to 2 > 1, as expected.", "category": "Math", "date": "03/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSue was disappointed after Bob showed her that 2 was not, in fact, equal to 1. She was not quite done, though. She told Bob that while 2 may not be equal to 1, she could show conclusively that 2 was in fact less than 1. Bob said it couldn't be done, of course, and Sue offered the following:\n\r\nProof:\n\r\n1 < 2\n\r\nMultiply the equation by log (0.5)\n\r\n1 * log(0.5) < 2 * log(0.5)\n\r\nMake the log factors exponents\n\r\nlog(0.5 ^ 1) < log(0.5 ^ 2)\n\r\nCarry out the exponentiation\n\r\nlog(0.5) < log(0.25)\n\r\nRaise 10 to the power of each side of the inequality\n\r\n10^(log(0.5)) < 10^(log(0.25))\n\r\nBy definition of logarithms, 10^log(a) = a, so...\n\r\n0.5 < 0.25\n\r\nThen just multiply both sides by 4\n\r\n2 < 1\n\r\nQuestion:\n\r\nBob found the problem almost immediately. Can you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen Sue multiplied the inequality by log(0.5), she was multiplying by a negative number, and multiplying an inequality by a negative number switches the direction. This first step should result in:\n\r\n1 * log(0.5) > 2 * log(0.5), which leads to 2 > 1, as expected.\n<|im_start|>answer\nWhen Sue multiplied the inequality by log(0.5), she was multiplying by a negative number, and multiplying an inequality by a negative number switches the direction. This first step should result in:\n\r\n1 * log(0.5) > 2 * log(0.5), which leads to 2 > 1, as expected.\n<|im_end|>" }, { "id": "#21150", "title": "Twice Shy", "fun": 2.26, "difficulty": 2.39, "author": "Atropus", "desc": "Steven was writing out an equation in English, when he realised that if he multiplied ten by two, his answer (twenty) also had twice as many letters as the word ten.\n\r\nTen (3 letters) x2= Twenty (6 letters)\n\r\nHow many other integers are there that if you double the number, you get an answer with twice the number of letters?", "hint": "No hint available.", "answer": "4.\n\r\nSix (3 letters) x2= Twelve (6 letters)\r\nNine (4 letters) x2= Eighteen (8 letters)\r\nFifty (5 letters) x2= One Hundred (10 letters)\r\nFifty One (8 letters) x2= One Hundred and Two (16 letters)", "category": "Math", "date": "02/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSteven was writing out an equation in English, when he realised that if he multiplied ten by two, his answer (twenty) also had twice as many letters as the word ten.\n\r\nTen (3 letters) x2= Twenty (6 letters)\n\r\nHow many other integers are there that if you double the number, you get an answer with twice the number of letters?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4.\n\r\nSix (3 letters) x2= Twelve (6 letters)\r\nNine (4 letters) x2= Eighteen (8 letters)\r\nFifty (5 letters) x2= One Hundred (10 letters)\r\nFifty One (8 letters) x2= One Hundred and Two (16 letters)\n<|im_start|>answer\n4.\n\r\nSix (3 letters) x2= Twelve (6 letters)\r\nNine (4 letters) x2= Eighteen (8 letters)\r\nFifty (5 letters) x2= One Hundred (10 letters)\r\nFifty One (8 letters) x2= One Hundred and Two (16 letters)\n<|im_end|>" }, { "id": "#3937", "title": "MA + A = AM", "fun": 2.26, "difficulty": 1.73, "author": "mad-ade", "desc": "MA + A = AM\r\nWhat digits are represented by the letters M and A?", "hint": "No hint available.", "answer": "M=8\r\nA=9\r\n89+9=98.", "category": "Math", "date": "05/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMA + A = AM\r\nWhat digits are represented by the letters M and A?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nM=8\r\nA=9\r\n89+9=98.\n<|im_start|>answer\nM=8\r\nA=9\r\n89+9=98.\n<|im_end|>" }, { "id": "#21836", "title": "Aging Couple", "fun": 2.26, "difficulty": 0.81, "author": "stormtrooper", "desc": "The age of a man is the same as his wife's age with the digits reversed. The sum of their ages is 99 and the man is 9 years older than his wife.\r\nHow old is the man?", "hint": "If AB represented the man's age, what represents the wife's age? Which is greater, A or B? What is the sum of A and B?", "answer": "The man is 54 years old.", "category": "Math", "date": "03/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe age of a man is the same as his wife's age with the digits reversed. The sum of their ages is 99 and the man is 9 years older than his wife.\r\nHow old is the man?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe man is 54 years old.\n<|im_start|>answer\nThe man is 54 years old.\n<|im_end|>" }, { "id": "#52371", "title": "The Number Lier", "fun": 2.26, "difficulty": 2.36, "author": "Rove_Tarts", "desc": "There are 3 numbers 0-9.\n\r\nEric knows the product and says, \"I know the numbers.\"\n\r\nThen, everyone is told that one digit is exactly one greater than another.\n\r\nThen, Luke is told one of the numbers and says, \"Eric lied.\"\n\r\nThen you are told the numbers add up to 11.\n\r\nWhat are the numbers?", "hint": "No hint available.", "answer": "0, 5, 6\n\r\nEric knows the product and claimed that he knows the numbers.\n\r\nLuke is told a number and then he knows Eric lied.\r\nIf Luke had received an 8, the combination could be 8,8,8, which is the only combination that multiplies to 512; Luke wouldn't know Eric lied.\r\nIf Luke received 6, the combination could be 6,7,7 which is the only combination that multiplies to 294, so Luke wouldn't know Eric lied.\r\nIf Luke received 2 or 7; 2x7x7=98.\r\n4 or 5; 4x5x5=100.\r\n3 or 9; 3x9x9=243.\r\n1; 1x1x1=1.\r\nLuke would only know that Eric lied if Luke was given a 0.\r\nTherefore one of the digits is 0.\n\r\nThe remaining two digits must add to 11 because 11-0=11.\n\r\nTwo of the digits are one apart so that leaves:\r\n0 & 1 + 10\r\n5 & 6 + 0\n\r\nHowever, 10 isn't an option so it must be 0, 5, 6.", "category": "Logic", "date": "02/23/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 3 numbers 0-9.\n\r\nEric knows the product and says, \"I know the numbers.\"\n\r\nThen, everyone is told that one digit is exactly one greater than another.\n\r\nThen, Luke is told one of the numbers and says, \"Eric lied.\"\n\r\nThen you are told the numbers add up to 11.\n\r\nWhat are the numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0, 5, 6\n\r\nEric knows the product and claimed that he knows the numbers.\n\r\nLuke is told a number and then he knows Eric lied.\r\nIf Luke had received an 8, the combination could be 8,8,8, which is the only combination that multiplies to 512; Luke wouldn't know Eric lied.\r\nIf Luke received 6, the combination could be 6,7,7 which is the only combination that multiplies to 294, so Luke wouldn't know Eric lied.\r\nIf Luke received 2 or 7; 2x7x7=98.\r\n4 or 5; 4x5x5=100.\r\n3 or 9; 3x9x9=243.\r\n1; 1x1x1=1.\r\nLuke would only know that Eric lied if Luke was given a 0.\r\nTherefore one of the digits is 0.\n\r\nThe remaining two digits must add to 11 because 11-0=11.\n\r\nTwo of the digits are one apart so that leaves:\r\n0 & 1 + 10\r\n5 & 6 + 0\n\r\nHowever, 10 isn't an option so it must be 0, 5, 6.\n<|im_start|>answer\n0, 5, 6\n\r\nEric knows the product and claimed that he knows the numbers.\n\r\nLuke is told a number and then he knows Eric lied.\r\nIf Luke had received an 8, the combination could be 8,8,8, which is the only combination that multiplies to 512; Luke wouldn't know Eric lied.\r\nIf Luke received 6, the combination could be 6,7,7 which is the only combination that multiplies to 294, so Luke wouldn't know Eric lied.\r\nIf Luke received 2 or 7; 2x7x7=98.\r\n4 or 5; 4x5x5=100.\r\n3 or 9; 3x9x9=243.\r\n1; 1x1x1=1.\r\nLuke would only know that Eric lied if Luke was given a 0.\r\nTherefore one of the digits is 0.\n\r\nThe remaining two digits must add to 11 because 11-0=11.\n\r\nTwo of the digits are one apart so that leaves:\r\n0 & 1 + 10\r\n5 & 6 + 0\n\r\nHowever, 10 isn't an option so it must be 0, 5, 6.\n<|im_end|>" }, { "id": "#13346", "title": "Sum of Reciprocals", "fun": 2.26, "difficulty": 2.19, "author": "nuccha", "desc": "If the sum of two numbers is 8, and their product is 14, what is the sum of their reciprocals?\n\r\nIf you're clever, you can solve this without having to figure out what each of the numbers is.", "hint": "No hint available.", "answer": "4/7\n\r\nNote: 1/a + 1/b = (a+b)/ab \r\nand since a+b=8 and ab = 14 \r\nthen 1/a + 1/b = 8/14 = 4/7", "category": "Math", "date": "06/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the sum of two numbers is 8, and their product is 14, what is the sum of their reciprocals?\n\r\nIf you're clever, you can solve this without having to figure out what each of the numbers is.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4/7\n\r\nNote: 1/a + 1/b = (a+b)/ab \r\nand since a+b=8 and ab = 14 \r\nthen 1/a + 1/b = 8/14 = 4/7\n<|im_start|>answer\n4/7\n\r\nNote: 1/a + 1/b = (a+b)/ab \r\nand since a+b=8 and ab = 14 \r\nthen 1/a + 1/b = 8/14 = 4/7\n<|im_end|>" }, { "id": "#3977", "title": "Three Brothers", "fun": 2.26, "difficulty": 1.3, "author": "Eowyn", "desc": "If the age of each of the three brothers were laid together, we would get 40. What was the age of each brother when you know that the eldest brother is as twice as old as the youngest brother, and the number 4 added to the youngest's age will give us the age of the brother in-between?", "hint": "No hint available.", "answer": "The youngest one is 9 years old, the one in the middle is 13, and the eldest is 18.\n\r\nBecause:\r\nThe youngest = x\r\nThe one in the middle = x+4\r\nThe eldest = 2x\n\r\nx+(x+4)+2x=40\r\n x+x+4+2x=40\r\n x+x+2x=40-4\r\n 4x=36\r\n 4x/4=36/4\r\n x=9", "category": "Math", "date": "05/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the age of each of the three brothers were laid together, we would get 40. What was the age of each brother when you know that the eldest brother is as twice as old as the youngest brother, and the number 4 added to the youngest's age will give us the age of the brother in-between?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe youngest one is 9 years old, the one in the middle is 13, and the eldest is 18.\n\r\nBecause:\r\nThe youngest = x\r\nThe one in the middle = x+4\r\nThe eldest = 2x\n\r\nx+(x+4)+2x=40\r\n x+x+4+2x=40\r\n x+x+2x=40-4\r\n 4x=36\r\n 4x/4=36/4\r\n x=9\n<|im_start|>answer\nThe youngest one is 9 years old, the one in the middle is 13, and the eldest is 18.\n\r\nBecause:\r\nThe youngest = x\r\nThe one in the middle = x+4\r\nThe eldest = 2x\n\r\nx+(x+4)+2x=40\r\n x+x+4+2x=40\r\n x+x+2x=40-4\r\n 4x=36\r\n 4x/4=36/4\r\n x=9\n<|im_end|>" }, { "id": "#28251", "title": "Three Consecutive Primes", "fun": 2.26, "difficulty": 2.62, "author": "kiss", "desc": "Which three consecutive prime numbers, when multiplied together, give the product 190747?", "hint": "No hint available.", "answer": "53, 59 and 61.", "category": "Math", "date": "01/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich three consecutive prime numbers, when multiplied together, give the product 190747?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n53, 59 and 61.\n<|im_start|>answer\n53, 59 and 61.\n<|im_end|>" }, { "id": "#35262", "title": "Reduce, Reuse, Recycle", "fun": 2.26, "difficulty": 1.45, "author": "shdwhawk", "desc": "For every 3kg of aluminium trash that Mr Green recycles, he can make 20 new biscuit tins. How many biscuit tins can he obtain from 11kg of aluminium trash and how many kilograms of aluminium material will be left over?", "hint": "Simple maths.", "answer": "He can make 73 biscuit tins. He will have 0.05kg of aluminium material left. \n\r\n3kg make 20 tins. Therefore 9kg will make 60 tins. \r\n11kg - 9kg = 2kg \r\n20 tins use 3kg, 1 tin will use 0.15kg, 13 tins will use 1.95kg. \r\n2kg - 1.95kg = 0.05kg. \r\n60 tins + 13 tins = 73 tins.", "category": "Math", "date": "02/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor every 3kg of aluminium trash that Mr Green recycles, he can make 20 new biscuit tins. How many biscuit tins can he obtain from 11kg of aluminium trash and how many kilograms of aluminium material will be left over?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe can make 73 biscuit tins. He will have 0.05kg of aluminium material left. \n\r\n3kg make 20 tins. Therefore 9kg will make 60 tins. \r\n11kg - 9kg = 2kg \r\n20 tins use 3kg, 1 tin will use 0.15kg, 13 tins will use 1.95kg. \r\n2kg - 1.95kg = 0.05kg. \r\n60 tins + 13 tins = 73 tins.\n<|im_start|>answer\nHe can make 73 biscuit tins. He will have 0.05kg of aluminium material left. \n\r\n3kg make 20 tins. Therefore 9kg will make 60 tins. \r\n11kg - 9kg = 2kg \r\n20 tins use 3kg, 1 tin will use 0.15kg, 13 tins will use 1.95kg. \r\n2kg - 1.95kg = 0.05kg. \r\n60 tins + 13 tins = 73 tins.\n<|im_end|>" }, { "id": "#2908", "title": "Bicycle Ride", "fun": 2.26, "difficulty": 1.53, "author": "204_BLaZe_41", "desc": "Rex rode his bicycle 300 km. Three tires were used equally in accumulating this distance. How many km of wear did each tire sustain?", "hint": "No hint available.", "answer": "200 km. For every km travelled, each of two tires sustained one km of usage. Therefore, in total of 300 km travelled, there would be a total of 600 km of wear. And 600 divided by three is 200.", "category": "Math", "date": "03/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRex rode his bicycle 300 km. Three tires were used equally in accumulating this distance. How many km of wear did each tire sustain?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n200 km. For every km travelled, each of two tires sustained one km of usage. Therefore, in total of 300 km travelled, there would be a total of 600 km of wear. And 600 divided by three is 200.\n<|im_start|>answer\n200 km. For every km travelled, each of two tires sustained one km of usage. Therefore, in total of 300 km travelled, there would be a total of 600 km of wear. And 600 divided by three is 200.\n<|im_end|>" }, { "id": "#38635", "title": "Susan's Trip", "fun": 2.26, "difficulty": 1.82, "author": "calmsavior", "desc": "Susan starts at point A, walks 15 feet in one direction, makes a 90 degree turn to the left, walks 20 feet, walks in a perfect circle around point A, and takes the same path she took leaving point A, until she is back at point A. Assuming she walks at a constant rate of 4 feet per second, makes no stops until she arrives at point A again, and that we do not consider acceleration, how long is her entire trip (rounded to the nearest second)?", "hint": "No hint available.", "answer": "57 seconds.\n\r\nFirst off, the formula of Speed = Distance / Time can be rewritten as Time = Distance / Speed. (On both sides of the equation we can multiply by Time and divide by Speed.) We will need this equation later.\n\r\nWe know Susan travels 15 feet in one direction and 20 feet in another and does this again on her return trip. Using the Pythagorean Theorem we find that the radius of the circle is 25 feet; therefore, the diameter is 50 feet and the circumference is about 157.1 feet. We can then plug all our values into the equation (units in feet cancel out, leaving seconds):\n\r\nTime = (15 ft. + 20 ft. + 157.1 ft. + 20 ft. + 15 ft.) / (4 ft. per second) = 57 seconds (rounded to the nearest second).", "category": "Math", "date": "10/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSusan starts at point A, walks 15 feet in one direction, makes a 90 degree turn to the left, walks 20 feet, walks in a perfect circle around point A, and takes the same path she took leaving point A, until she is back at point A. Assuming she walks at a constant rate of 4 feet per second, makes no stops until she arrives at point A again, and that we do not consider acceleration, how long is her entire trip (rounded to the nearest second)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n57 seconds.\n\r\nFirst off, the formula of Speed = Distance / Time can be rewritten as Time = Distance / Speed. (On both sides of the equation we can multiply by Time and divide by Speed.) We will need this equation later.\n\r\nWe know Susan travels 15 feet in one direction and 20 feet in another and does this again on her return trip. Using the Pythagorean Theorem we find that the radius of the circle is 25 feet; therefore, the diameter is 50 feet and the circumference is about 157.1 feet. We can then plug all our values into the equation (units in feet cancel out, leaving seconds):\n\r\nTime = (15 ft. + 20 ft. + 157.1 ft. + 20 ft. + 15 ft.) / (4 ft. per second) = 57 seconds (rounded to the nearest second).\n<|im_start|>answer\n57 seconds.\n\r\nFirst off, the formula of Speed = Distance / Time can be rewritten as Time = Distance / Speed. (On both sides of the equation we can multiply by Time and divide by Speed.) We will need this equation later.\n\r\nWe know Susan travels 15 feet in one direction and 20 feet in another and does this again on her return trip. Using the Pythagorean Theorem we find that the radius of the circle is 25 feet; therefore, the diameter is 50 feet and the circumference is about 157.1 feet. We can then plug all our values into the equation (units in feet cancel out, leaving seconds):\n\r\nTime = (15 ft. + 20 ft. + 157.1 ft. + 20 ft. + 15 ft.) / (4 ft. per second) = 57 seconds (rounded to the nearest second).\n<|im_end|>" }, { "id": "#2862", "title": "Number Nine", "fun": 2.26, "difficulty": 1.31, "author": "204_BLaZe_41", "desc": "A new medical building containing 100 offices has just been completed. Clyde was hired to paint the numbers 1-100 on the doors. How many times will Clyde have to paint the number nine?", "hint": "No hint available.", "answer": "Twenty times.\n\r\n9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99", "category": "Math", "date": "03/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA new medical building containing 100 offices has just been completed. Clyde was hired to paint the numbers 1-100 on the doors. How many times will Clyde have to paint the number nine?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwenty times.\n\r\n9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99\n<|im_start|>answer\nTwenty times.\n\r\n9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99\n<|im_end|>" }, { "id": "#2003", "title": "Triangle sizes", "fun": 2.26, "difficulty": 1.3, "author": "Mogmatt16", "desc": "Which triangle has the most area? Is it \r\none with sides measuring:\n\r\nA) 23 in., 20 in., & 10 in.\r\nB) 2 in., 3 in., & 5 in.\r\nC) 15 in. 7 in., & 22 in.", "hint": "No hint available.", "answer": "A is the largest. B & C don't form \r\ntriangles! Those sides can only form a\r\nline. A is the only real triangle.", "category": "Math", "date": "01/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich triangle has the most area? Is it \r\none with sides measuring:\n\r\nA) 23 in., 20 in., & 10 in.\r\nB) 2 in., 3 in., & 5 in.\r\nC) 15 in. 7 in., & 22 in.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA is the largest. B & C don't form \r\ntriangles! Those sides can only form a\r\nline. A is the only real triangle.\n<|im_start|>answer\nA is the largest. B & C don't form \r\ntriangles! Those sides can only form a\r\nline. A is the only real triangle.\n<|im_end|>" }, { "id": "#14995", "title": "Mad Ade's Chess Night", "fun": 2.26, "difficulty": 2.3, "author": "mad-ade", "desc": "Mr. and Mrs. Mad Ade & Mr. and Mrs. Potato competed in a Chess tournament. Of the three games played:\n\r\nIn only the first game were the two players married to each other, \n\r\nThe men won two games and the women won one game. \n\r\nThe Mad Ades won more games than the Potatos. \n\r\nAnyone who lost a game did not play a subsequent game.\r\nWho did not lose a game?", "hint": "No hint available.", "answer": "Mrs. Potato did not lose a game. \n\r\nList out all the possibilities and remove the possibilities which contradict the given conditions. \n\r\nThere are only 3 possibilities:\r\nMr. Mad Ade won one game, Mrs. Mad Ade won one game and Mr. Potato won one game. \n\r\nMr. Mad Ade one two games and Mrs. Mad Ade won one game. \n\r\nMr. Mad Ade won two games and Mrs. Potato won one game.\n\n\r\nIf (I) is correct, then Mr. Potato beats Mrs. Potato in the first game. Then Mr. Potato would have lost to either Mr. Mad Ade or Mrs. Mad Ade in the second game. And Mr. and Mrs. Mad Ade would have played the third game which contradicts the statement (1). So (I) is not correct. \n\r\nSimilarly, (II) is not correct. \n\r\n(III) is correct. Mr. and Mrs. Mad Ade played the first game and Mr. Mad Ade won the game. Mr. Mad Ade won the second game against Mr. Potato and lost the third game against Mrs. Potato. \n\r\nThus, only Mrs. Potato did not lose a game.", "category": "Logic", "date": "10/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. and Mrs. Mad Ade & Mr. and Mrs. Potato competed in a Chess tournament. Of the three games played:\n\r\nIn only the first game were the two players married to each other, \n\r\nThe men won two games and the women won one game. \n\r\nThe Mad Ades won more games than the Potatos. \n\r\nAnyone who lost a game did not play a subsequent game.\r\nWho did not lose a game?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMrs. Potato did not lose a game. \n\r\nList out all the possibilities and remove the possibilities which contradict the given conditions. \n\r\nThere are only 3 possibilities:\r\nMr. Mad Ade won one game, Mrs. Mad Ade won one game and Mr. Potato won one game. \n\r\nMr. Mad Ade one two games and Mrs. Mad Ade won one game. \n\r\nMr. Mad Ade won two games and Mrs. Potato won one game.\n\n\r\nIf (I) is correct, then Mr. Potato beats Mrs. Potato in the first game. Then Mr. Potato would have lost to either Mr. Mad Ade or Mrs. Mad Ade in the second game. And Mr. and Mrs. Mad Ade would have played the third game which contradicts the statement (1). So (I) is not correct. \n\r\nSimilarly, (II) is not correct. \n\r\n(III) is correct. Mr. and Mrs. Mad Ade played the first game and Mr. Mad Ade won the game. Mr. Mad Ade won the second game against Mr. Potato and lost the third game against Mrs. Potato. \n\r\nThus, only Mrs. Potato did not lose a game.\n<|im_start|>answer\nMrs. Potato did not lose a game. \n\r\nList out all the possibilities and remove the possibilities which contradict the given conditions. \n\r\nThere are only 3 possibilities:\r\nMr. Mad Ade won one game, Mrs. Mad Ade won one game and Mr. Potato won one game. \n\r\nMr. Mad Ade one two games and Mrs. Mad Ade won one game. \n\r\nMr. Mad Ade won two games and Mrs. Potato won one game.\n\n\r\nIf (I) is correct, then Mr. Potato beats Mrs. Potato in the first game. Then Mr. Potato would have lost to either Mr. Mad Ade or Mrs. Mad Ade in the second game. And Mr. and Mrs. Mad Ade would have played the third game which contradicts the statement (1). So (I) is not correct. \n\r\nSimilarly, (II) is not correct. \n\r\n(III) is correct. Mr. and Mrs. Mad Ade played the first game and Mr. Mad Ade won the game. Mr. Mad Ade won the second game against Mr. Potato and lost the third game against Mrs. Potato. \n\r\nThus, only Mrs. Potato did not lose a game.\n<|im_end|>" }, { "id": "#42699", "title": "Who Bought What?", "fun": 2.26, "difficulty": 0.97, "author": "Cammi_27", "desc": "Sally, Samantha, Molly, and Kaylee all went shoe shopping together. They each had different tastes and ended up with heels, flipflops, flats, or wedges. All the shoes were different colors: green, blue, black, or white. The girls also picked different patterns for their shoes: stars, solid, stripes, or fruit. \n\r\n1) Sally and Samantha's shoes were complete opposites in style and color, but not in patterns.\n\r\n2) Molly liked high shoes but thought twice before buying another pair of them.\n\r\n3) Samantha's whole wardrobe was white, so she bought another pair of white shoes to match.\n\r\n4) Sally loved flats and finally bought a patterned pair.\n\r\n5) Kaylee could never find a pair of shoes that was not the color green, but she finally did.\n\r\n6) Samantha didn't like high shoes at all, but Kaylee talked her into it because she got wedges herself.\n\r\n7) Sally loved to stare at the night sky, so her shoes matched the sky in pattern and had a black background.\n\r\n8) Kaylee bought a pair of blue shoes.\n\r\n9) Molly only liked solid colored shoes.\n\r\n10) Kaylee loved stripes and bought a nice pair of striped shoes.\n\r\n11) Samantha's favorite food is fruit, and that's the pattern she found on her favorite pair of shoes.\n\n\r\nHint will tell Samantha's shoe color, style, and pattern.", "hint": "Samantha bought white heels with little pictures of fruit on them.", "answer": "Samantha bought white heels with little pictures of fruit on them.\n\r\nSally bought a pair of black flats with stars on them.\n\r\nKaylee bought a pair of wedges with blue stripes on them.\n\r\nMolly bought green, solid colored flipflops.", "category": "Logic-Grid", "date": "08/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally, Samantha, Molly, and Kaylee all went shoe shopping together. They each had different tastes and ended up with heels, flipflops, flats, or wedges. All the shoes were different colors: green, blue, black, or white. The girls also picked different patterns for their shoes: stars, solid, stripes, or fruit. \n\r\n1) Sally and Samantha's shoes were complete opposites in style and color, but not in patterns.\n\r\n2) Molly liked high shoes but thought twice before buying another pair of them.\n\r\n3) Samantha's whole wardrobe was white, so she bought another pair of white shoes to match.\n\r\n4) Sally loved flats and finally bought a patterned pair.\n\r\n5) Kaylee could never find a pair of shoes that was not the color green, but she finally did.\n\r\n6) Samantha didn't like high shoes at all, but Kaylee talked her into it because she got wedges herself.\n\r\n7) Sally loved to stare at the night sky, so her shoes matched the sky in pattern and had a black background.\n\r\n8) Kaylee bought a pair of blue shoes.\n\r\n9) Molly only liked solid colored shoes.\n\r\n10) Kaylee loved stripes and bought a nice pair of striped shoes.\n\r\n11) Samantha's favorite food is fruit, and that's the pattern she found on her favorite pair of shoes.\n\n\r\nHint will tell Samantha's shoe color, style, and pattern.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSamantha bought white heels with little pictures of fruit on them.\n\r\nSally bought a pair of black flats with stars on them.\n\r\nKaylee bought a pair of wedges with blue stripes on them.\n\r\nMolly bought green, solid colored flipflops.\n<|im_start|>answer\nSamantha bought white heels with little pictures of fruit on them.\n\r\nSally bought a pair of black flats with stars on them.\n\r\nKaylee bought a pair of wedges with blue stripes on them.\n\r\nMolly bought green, solid colored flipflops.\n<|im_end|>" }, { "id": "#1380", "title": "How Many Chickens", "fun": 2.25, "difficulty": 1.8900000000000001, "author": "psychodude57", "desc": "In Farmer Donald's hay loft there are a number of ants, mice and chickens. There are ten times as many ants as mice and there are four times as many mice as chickens. Altogether there are 1806 feet. How many chickens are there?", "hint": "No hint available.", "answer": "There are 7 chickens, 28 mice and 280 ants.", "category": "Math", "date": "11/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Farmer Donald's hay loft there are a number of ants, mice and chickens. There are ten times as many ants as mice and there are four times as many mice as chickens. Altogether there are 1806 feet. How many chickens are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 7 chickens, 28 mice and 280 ants.\n<|im_start|>answer\nThere are 7 chickens, 28 mice and 280 ants.\n<|im_end|>" }, { "id": "#50436", "title": "The Box of Chocolates", "fun": 2.25, "difficulty": 2.34, "author": "e333", "desc": "Serena has received a box of chocolates as a birthday present. The box contains 12 chocolates of different shapes (one is hemispherical) and flavours (four of which are: dark chocolate, white chocolate-hazelnut, tiramisu and milk chocolate-cherry). The 12 chocolates are divided into three rows of 4 chocolate per line. With the help of the clues and the drawing, can you figure out the shape, the flavour and the position in the box of each chocolate?\r\n1. The following four chocolates are in the same row (but not necessarily in this\r\norder): the flower-shaped chocolate (which isn't gianduia flavour), the dark\r\nchocolate-orange chocolate (which isn't pentagonal-shaped), the chocolate just below the white chocolate and the heart-shaped milk chocolate-cognac flavoured chocolate.\r\n2. Every row contains only one chocolate made from dark chocolate and only one\r\nfrom milk chocolate and they aren't next to each other.\r\n3. The cremino flavoured chocolate is just to the left of the heart-shaped chocolate and just above the trapezoid-shaped one.\r\n4. The hexagonal-shaped chocolate is just below the dark chocolate-orange one and is in the same row as the dark chocolate-hazelnut one but further to the right.\r\n5. Both the caramel chocolate and the square-shaped chocolate (which isn't made from dark chocolate) are in the central part of the box but neither in the same row nor one below the other.\r\n6. The round chocolate (which isn't dark chocolate-orange flavour) is further to the left than the pentagonal-shaped chocolate (which isn't #4) but further to the right than the gianduia flavoured one. These three chocolates are in different rows.\r\n7. Chocolate #5 isn't the cremino flavoured chocolate. The two white-chocolate chocolates are in the first two rows. The rectangular-shaped chocolate is next to the oval-shaped milk chocolate. Chocolate #9 isn't rhombus-shaped. The triangularshaped\r\nchocolate is #1.", "hint": "No hint available.", "answer": "Solution:\r\nPosition - Shape - Flavour\r\n1 - Triangular - Dark chocolate\r\n2 - Square - Gianduia\r\n3 - Rectangular - White chocolate\r\n4 - Oval - Milk chocolate\r\n5 - Flower - White chocolate-hazelnut\r\n6 - Rhombus - Dark chocolate-orange\r\n7 - Round - Cremino\r\n8 - Heart - Milk chocolate-cognac\r\n9 - Hemispherical - Dark chocolate hazelnut\r\n10 - Hexagonal - Tiramisu\r\n11 - Trapezoid - Caramel\r\n12 - Pentagonal - Milk chocolate-cherry", "category": "Logic", "date": "09/27/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSerena has received a box of chocolates as a birthday present. The box contains 12 chocolates of different shapes (one is hemispherical) and flavours (four of which are: dark chocolate, white chocolate-hazelnut, tiramisu and milk chocolate-cherry). The 12 chocolates are divided into three rows of 4 chocolate per line. With the help of the clues and the drawing, can you figure out the shape, the flavour and the position in the box of each chocolate?\r\n1. The following four chocolates are in the same row (but not necessarily in this\r\norder): the flower-shaped chocolate (which isn't gianduia flavour), the dark\r\nchocolate-orange chocolate (which isn't pentagonal-shaped), the chocolate just below the white chocolate and the heart-shaped milk chocolate-cognac flavoured chocolate.\r\n2. Every row contains only one chocolate made from dark chocolate and only one\r\nfrom milk chocolate and they aren't next to each other.\r\n3. The cremino flavoured chocolate is just to the left of the heart-shaped chocolate and just above the trapezoid-shaped one.\r\n4. The hexagonal-shaped chocolate is just below the dark chocolate-orange one and is in the same row as the dark chocolate-hazelnut one but further to the right.\r\n5. Both the caramel chocolate and the square-shaped chocolate (which isn't made from dark chocolate) are in the central part of the box but neither in the same row nor one below the other.\r\n6. The round chocolate (which isn't dark chocolate-orange flavour) is further to the left than the pentagonal-shaped chocolate (which isn't #4) but further to the right than the gianduia flavoured one. These three chocolates are in different rows.\r\n7. Chocolate #5 isn't the cremino flavoured chocolate. The two white-chocolate chocolates are in the first two rows. The rectangular-shaped chocolate is next to the oval-shaped milk chocolate. Chocolate #9 isn't rhombus-shaped. The triangularshaped\r\nchocolate is #1.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSolution:\r\nPosition - Shape - Flavour\r\n1 - Triangular - Dark chocolate\r\n2 - Square - Gianduia\r\n3 - Rectangular - White chocolate\r\n4 - Oval - Milk chocolate\r\n5 - Flower - White chocolate-hazelnut\r\n6 - Rhombus - Dark chocolate-orange\r\n7 - Round - Cremino\r\n8 - Heart - Milk chocolate-cognac\r\n9 - Hemispherical - Dark chocolate hazelnut\r\n10 - Hexagonal - Tiramisu\r\n11 - Trapezoid - Caramel\r\n12 - Pentagonal - Milk chocolate-cherry\n<|im_start|>answer\nSolution:\r\nPosition - Shape - Flavour\r\n1 - Triangular - Dark chocolate\r\n2 - Square - Gianduia\r\n3 - Rectangular - White chocolate\r\n4 - Oval - Milk chocolate\r\n5 - Flower - White chocolate-hazelnut\r\n6 - Rhombus - Dark chocolate-orange\r\n7 - Round - Cremino\r\n8 - Heart - Milk chocolate-cognac\r\n9 - Hemispherical - Dark chocolate hazelnut\r\n10 - Hexagonal - Tiramisu\r\n11 - Trapezoid - Caramel\r\n12 - Pentagonal - Milk chocolate-cherry\n<|im_end|>" }, { "id": "#113", "title": "Change for a Dollar", "fun": 2.25, "difficulty": 2.63, "author": "duckrocket", "desc": "Assuming you have enough coins of 1, 5, 10, 25 and 50 cents, how many ways are there to make change for a dollar?", "hint": "There are more than 200.", "answer": "There are 292 ways.", "category": "Math", "date": "01/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAssuming you have enough coins of 1, 5, 10, 25 and 50 cents, how many ways are there to make change for a dollar?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 292 ways.\n<|im_start|>answer\nThere are 292 ways.\n<|im_end|>" }, { "id": "#5396", "title": "Inherited Clocks", "fun": 2.25, "difficulty": 2.08, "author": "mad-ade", "desc": "Mad Ade has inherited two clocks. One from his Great Grandmother who sadly perished in a unfortunate skateboarding accident and one from his strange uncle Syndey, who gave up drinking, and died of thirst.\r\n One of them gains 6 seconds in every hour, while the other loses 9 seconds in every hour. If they are both set to show the same time, and then set going, how long will it be before they are exactly 1 hour different.", "hint": "No hint available.", "answer": "240 hours.", "category": "Math", "date": "07/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has inherited two clocks. One from his Great Grandmother who sadly perished in a unfortunate skateboarding accident and one from his strange uncle Syndey, who gave up drinking, and died of thirst.\r\n One of them gains 6 seconds in every hour, while the other loses 9 seconds in every hour. If they are both set to show the same time, and then set going, how long will it be before they are exactly 1 hour different.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n240 hours.\n<|im_start|>answer\n240 hours.\n<|im_end|>" }, { "id": "#23071", "title": "In a Class", "fun": 2.25, "difficulty": 1.0, "author": "SBen20", "desc": "4 students had 4 grades on a test. Figure out who had what grade, and what their final class score was. \n\r\nNames: John, George, Sally, Sara\r\nGrades: A, B+, B, B-\r\nFinal scores: 95%, 88%, 80%, 75%\n\r\nJohn did not earn the lowest grade and he did not earn the highest score.\n\r\nA girl earned the highest grade. A boy earned the highest score.\n\r\nSara earned a higher grade than George. George earned a higher score than Sally. \n\r\nWhoever earned a B+ earned an 88%. No male earned the B.\n\r\nSara did better than Sally in both score and grade.", "hint": "John and George are boys, Sally and Sara are girls.", "answer": "John: B+, 88%\r\nGeorge: B-, 95%\r\nSally: B, 75%\r\nSara: A, 80%", "category": "Logic-Grid", "date": "05/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 students had 4 grades on a test. Figure out who had what grade, and what their final class score was. \n\r\nNames: John, George, Sally, Sara\r\nGrades: A, B+, B, B-\r\nFinal scores: 95%, 88%, 80%, 75%\n\r\nJohn did not earn the lowest grade and he did not earn the highest score.\n\r\nA girl earned the highest grade. A boy earned the highest score.\n\r\nSara earned a higher grade than George. George earned a higher score than Sally. \n\r\nWhoever earned a B+ earned an 88%. No male earned the B.\n\r\nSara did better than Sally in both score and grade.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn: B+, 88%\r\nGeorge: B-, 95%\r\nSally: B, 75%\r\nSara: A, 80%\n<|im_start|>answer\nJohn: B+, 88%\r\nGeorge: B-, 95%\r\nSally: B, 75%\r\nSara: A, 80%\n<|im_end|>" }, { "id": "#4420", "title": "Sweet Tooth for Wonkles and Winkles", "fun": 2.25, "difficulty": 2.05, "author": "mad-ade", "desc": "In the land of MADADIA there are two popular types of sweets/candies. Wonkles and Winkles. If six winkles and three wonkles cost 15p, and you can buy nine wonkles and three winkles for the same 15p, what will it cost to buy one hundred wonkles?", "hint": "No hint available.", "answer": "wonkles cost 1p winkles 2p.\r\nTherefore 100 Wonkles = £1", "category": "Math", "date": "06/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of MADADIA there are two popular types of sweets/candies. Wonkles and Winkles. If six winkles and three wonkles cost 15p, and you can buy nine wonkles and three winkles for the same 15p, what will it cost to buy one hundred wonkles?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nwonkles cost 1p winkles 2p.\r\nTherefore 100 Wonkles = £1\n<|im_start|>answer\nwonkles cost 1p winkles 2p.\r\nTherefore 100 Wonkles = £1\n<|im_end|>" }, { "id": "#14222", "title": "Magic Rods", "fun": 2.25, "difficulty": 2.52, "author": "Smithy", "desc": "You need to make a set of five rods for a magic trick, with numbers on them ranging from 1 to 31 inclusive (although each rod does not contain all of the numbers). Then you ask people to pick a number and show you only the top number of whatever rods it is on. From that you have to guess which number the person picked. This has to be done within a few seconds and isn't a matter of remembering what numbers are on them. \n\r\nWhat numbers should be on each of the six rods?", "hint": "Think of a system used in computers.", "answer": "The numbers should be:\n\r\nRod 1: 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31\n\r\nRod 2: 2,3,6,7,10,11,14,15,18,19,22,23,26,27,30,31\n\r\nRod 3: 4,5,6,7,12,13,14,15,20,21,22,23,28,29,30,31\n\r\nRod 4: 8,9,10,11,12,13,14,15,24,25,26,27,28,29,30,31\n\r\nRod 5: 16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31\n\r\nThis uses the same idea as the binary system. All you do is add up the first numbers of the rods that have the number on. It works because the first numbers of each rod are 1,2,4,8 & 16, and using those numbers you can make any numbers from 1 to 31. For example, to make 25 you use the numbers 1,8 and 16, which are rods 1,4 and 5, so 25 is only written on those three rods.", "category": "Math", "date": "08/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou need to make a set of five rods for a magic trick, with numbers on them ranging from 1 to 31 inclusive (although each rod does not contain all of the numbers). Then you ask people to pick a number and show you only the top number of whatever rods it is on. From that you have to guess which number the person picked. This has to be done within a few seconds and isn't a matter of remembering what numbers are on them. \n\r\nWhat numbers should be on each of the six rods?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers should be:\n\r\nRod 1: 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31\n\r\nRod 2: 2,3,6,7,10,11,14,15,18,19,22,23,26,27,30,31\n\r\nRod 3: 4,5,6,7,12,13,14,15,20,21,22,23,28,29,30,31\n\r\nRod 4: 8,9,10,11,12,13,14,15,24,25,26,27,28,29,30,31\n\r\nRod 5: 16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31\n\r\nThis uses the same idea as the binary system. All you do is add up the first numbers of the rods that have the number on. It works because the first numbers of each rod are 1,2,4,8 & 16, and using those numbers you can make any numbers from 1 to 31. For example, to make 25 you use the numbers 1,8 and 16, which are rods 1,4 and 5, so 25 is only written on those three rods.\n<|im_start|>answer\nThe numbers should be:\n\r\nRod 1: 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31\n\r\nRod 2: 2,3,6,7,10,11,14,15,18,19,22,23,26,27,30,31\n\r\nRod 3: 4,5,6,7,12,13,14,15,20,21,22,23,28,29,30,31\n\r\nRod 4: 8,9,10,11,12,13,14,15,24,25,26,27,28,29,30,31\n\r\nRod 5: 16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31\n\r\nThis uses the same idea as the binary system. All you do is add up the first numbers of the rods that have the number on. It works because the first numbers of each rod are 1,2,4,8 & 16, and using those numbers you can make any numbers from 1 to 31. For example, to make 25 you use the numbers 1,8 and 16, which are rods 1,4 and 5, so 25 is only written on those three rods.\n<|im_end|>" }, { "id": "#16557", "title": "Soup Cans", "fun": 2.25, "difficulty": 1.65, "author": "adoontourious", "desc": "Adoontourious designs food displays for the Nile Supermarket chain. For one of his displays, he wants to set up soup cans in the form of a square pyramid. He's decided to use 9 cans for each side of the square base of the pyramid. \r\nIf each carton holds 24 soup cans, how many cartons will adoontourious need to open to build the pyramid?", "hint": "No hint available.", "answer": "Adoontourious will need to open 12 cartons. \n\r\nThe 9-by-9 square base of the pyramid will have 81 cans. Building upward, the next layer will have 8 x 8, or 64 cans. The next layer will have 7 x 7, or 49 cans, and so on up to the top layer (which will have just 1 can). Add the cans in all 9 layers, and you'll find that the total number of cans needed to build the pyramid is 285. \n\r\nDivide the total number of cans by the number of cans in a carton : 285 ÷ 24 = 11.87. Since adoontourious can't open 11.87 cartons, he'll have to open 12 cartons : 12 x 24 = 288. Then he'll be left with 3 extra cans!", "category": "Math", "date": "02/13/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdoontourious designs food displays for the Nile Supermarket chain. For one of his displays, he wants to set up soup cans in the form of a square pyramid. He's decided to use 9 cans for each side of the square base of the pyramid. \r\nIf each carton holds 24 soup cans, how many cartons will adoontourious need to open to build the pyramid?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdoontourious will need to open 12 cartons. \n\r\nThe 9-by-9 square base of the pyramid will have 81 cans. Building upward, the next layer will have 8 x 8, or 64 cans. The next layer will have 7 x 7, or 49 cans, and so on up to the top layer (which will have just 1 can). Add the cans in all 9 layers, and you'll find that the total number of cans needed to build the pyramid is 285. \n\r\nDivide the total number of cans by the number of cans in a carton : 285 ÷ 24 = 11.87. Since adoontourious can't open 11.87 cartons, he'll have to open 12 cartons : 12 x 24 = 288. Then he'll be left with 3 extra cans!\n<|im_start|>answer\nAdoontourious will need to open 12 cartons. \n\r\nThe 9-by-9 square base of the pyramid will have 81 cans. Building upward, the next layer will have 8 x 8, or 64 cans. The next layer will have 7 x 7, or 49 cans, and so on up to the top layer (which will have just 1 can). Add the cans in all 9 layers, and you'll find that the total number of cans needed to build the pyramid is 285. \n\r\nDivide the total number of cans by the number of cans in a carton : 285 ÷ 24 = 11.87. Since adoontourious can't open 11.87 cartons, he'll have to open 12 cartons : 12 x 24 = 288. Then he'll be left with 3 extra cans!\n<|im_end|>" }, { "id": "#7454", "title": "Score", "fun": 2.25, "difficulty": 1.46, "author": "supershlop", "desc": "I scored a goal but I didn't get a point. Why not?", "hint": "No hint available.", "answer": "I scored in the wrong goal!", "category": "Logic", "date": "09/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI scored a goal but I didn't get a point. Why not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI scored in the wrong goal!\n<|im_start|>answer\nI scored in the wrong goal!\n<|im_end|>" }, { "id": "#48245", "title": "Flinch!", "fun": 2.25, "difficulty": 1.09, "author": "Magyk555", "desc": "One day at the John's house, Jonah and Patrick were playing a game. The rules of the game were simple. You try to make the other person flinch without touching them. You have five seconds to do this. If you do this in five seconds, you earn a point. Instead of using points, Jonah and Patrick used pieces of popcorn. After a certain amount of time, Jonah had seventeen pieces, while Patrick only had eleven. After more time, Jonah doubled his amount, while Patrick tripled his amount! After even more time, Jonah gained seven pieces, while Patrick gained only four.\n\r\nHow many pieces of popcorn does Jonah have to give to Patrick, so that they both have an equal amount of popcorn?", "hint": "No hint available.", "answer": "Jonah has to give Patrick two pieces of popcorn so that they both have an equal amount of popcorn. See below for an explanation.\n\r\nJonah-17x2=34\r\nJonah-34+7=41\r\nPatrick-11x3=33\r\nPatrick-33+4=37\n\r\nJonah ended with 41 pieces, while Patrick ended up with 37 pieces. If Jonah then gives two to Patrick, they will both have 39 pieces of popcorn.", "category": "Math", "date": "12/05/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day at the John's house, Jonah and Patrick were playing a game. The rules of the game were simple. You try to make the other person flinch without touching them. You have five seconds to do this. If you do this in five seconds, you earn a point. Instead of using points, Jonah and Patrick used pieces of popcorn. After a certain amount of time, Jonah had seventeen pieces, while Patrick only had eleven. After more time, Jonah doubled his amount, while Patrick tripled his amount! After even more time, Jonah gained seven pieces, while Patrick gained only four.\n\r\nHow many pieces of popcorn does Jonah have to give to Patrick, so that they both have an equal amount of popcorn?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJonah has to give Patrick two pieces of popcorn so that they both have an equal amount of popcorn. See below for an explanation.\n\r\nJonah-17x2=34\r\nJonah-34+7=41\r\nPatrick-11x3=33\r\nPatrick-33+4=37\n\r\nJonah ended with 41 pieces, while Patrick ended up with 37 pieces. If Jonah then gives two to Patrick, they will both have 39 pieces of popcorn.\n<|im_start|>answer\nJonah has to give Patrick two pieces of popcorn so that they both have an equal amount of popcorn. See below for an explanation.\n\r\nJonah-17x2=34\r\nJonah-34+7=41\r\nPatrick-11x3=33\r\nPatrick-33+4=37\n\r\nJonah ended with 41 pieces, while Patrick ended up with 37 pieces. If Jonah then gives two to Patrick, they will both have 39 pieces of popcorn.\n<|im_end|>" }, { "id": "#4381", "title": "Rotten Apples", "fun": 2.25, "difficulty": 2.14, "author": "mad-ade", "desc": "Mad Ade's Father (Mr Mad Ade snr) asked young Mad Ade to go shopping for apples one day. He gives young Mad Ade exactly £1 (100 pence) and instructs him that he must spend all of it and buy exactly 100 apples from the market. \n\r\nNow, the market sells three kinds of apples. Good apples are priced at 10 pence, Average apples at 5 pence and Rotten apples at 0.5 pence. \n\r\nIt does not matter what type of apples young Mad Ade buys, as long as there is 100 in total. How many of each apple must young Mad Ade buy in order to fulfil his father's (Mr Mad Ade snr) instructions?", "hint": "No hint available.", "answer": "Assume that young Mad Ade will buy total of X apples of 10 pence each, Y apples of 5 pence each and Z apples of 0.5 pence each. \n\r\nAs young Mad Ade must buy 100 apples, \r\nX + Y + Z = 100 ----------I \n\r\nAlso, the total price must be 100 pence, \r\n10 * X + 5 * Y + 0.5 * Z = 100 \r\n20 * X + 10 * Y + Z = 200 ----------II \n\r\nSubtracting equation I from equation II, \r\n19 * X + 9 * Y = 100 \n\r\nIt is obvious that values of X, Y and Z are integers. So using trial and error, X = 1 and Y = 9 \n\r\nUsing values of X and Y, then Z = 90 \n\r\n1 Good apple = 10 pence \r\n9 Average apple = 45 pence \r\n90 rotten apples = 45 pence \r\nHence, total of 100 apples for 100 pence.", "category": "Math", "date": "05/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Father (Mr Mad Ade snr) asked young Mad Ade to go shopping for apples one day. He gives young Mad Ade exactly £1 (100 pence) and instructs him that he must spend all of it and buy exactly 100 apples from the market. \n\r\nNow, the market sells three kinds of apples. Good apples are priced at 10 pence, Average apples at 5 pence and Rotten apples at 0.5 pence. \n\r\nIt does not matter what type of apples young Mad Ade buys, as long as there is 100 in total. How many of each apple must young Mad Ade buy in order to fulfil his father's (Mr Mad Ade snr) instructions?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAssume that young Mad Ade will buy total of X apples of 10 pence each, Y apples of 5 pence each and Z apples of 0.5 pence each. \n\r\nAs young Mad Ade must buy 100 apples, \r\nX + Y + Z = 100 ----------I \n\r\nAlso, the total price must be 100 pence, \r\n10 * X + 5 * Y + 0.5 * Z = 100 \r\n20 * X + 10 * Y + Z = 200 ----------II \n\r\nSubtracting equation I from equation II, \r\n19 * X + 9 * Y = 100 \n\r\nIt is obvious that values of X, Y and Z are integers. So using trial and error, X = 1 and Y = 9 \n\r\nUsing values of X and Y, then Z = 90 \n\r\n1 Good apple = 10 pence \r\n9 Average apple = 45 pence \r\n90 rotten apples = 45 pence \r\nHence, total of 100 apples for 100 pence.\n<|im_start|>answer\nAssume that young Mad Ade will buy total of X apples of 10 pence each, Y apples of 5 pence each and Z apples of 0.5 pence each. \n\r\nAs young Mad Ade must buy 100 apples, \r\nX + Y + Z = 100 ----------I \n\r\nAlso, the total price must be 100 pence, \r\n10 * X + 5 * Y + 0.5 * Z = 100 \r\n20 * X + 10 * Y + Z = 200 ----------II \n\r\nSubtracting equation I from equation II, \r\n19 * X + 9 * Y = 100 \n\r\nIt is obvious that values of X, Y and Z are integers. So using trial and error, X = 1 and Y = 9 \n\r\nUsing values of X and Y, then Z = 90 \n\r\n1 Good apple = 10 pence \r\n9 Average apple = 45 pence \r\n90 rotten apples = 45 pence \r\nHence, total of 100 apples for 100 pence.\n<|im_end|>" }, { "id": "#5220", "title": "Average Marks", "fun": 2.25, "difficulty": 1.52, "author": "Cascas", "desc": "Teacher: You appeared for 8 quizzes, and your average marks in them were 82. \r\nStudent: How did I fare in English? \r\nTeacher: Well, your average in English Language and English Literature is 61. \r\nStudent: So, how was my performance in the remaining subjects? \r\nTeacher: I am sure you can figure that out for yourself. \n\r\nCan you help the student find his average marks in the remaining subjects?", "hint": "No hint available.", "answer": "Total marks in 8 subjects = 8 x 82 = 656. \n\r\nTotal marks in 2 English subjects = 2 x 61 = 122. \n\r\nTotal marks in remaining 6 subjects = 656 - 122 = 534. \n\r\nAverage marks in remaining 6 subjects = 534 / 6 = 89.", "category": "Math", "date": "07/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTeacher: You appeared for 8 quizzes, and your average marks in them were 82. \r\nStudent: How did I fare in English? \r\nTeacher: Well, your average in English Language and English Literature is 61. \r\nStudent: So, how was my performance in the remaining subjects? \r\nTeacher: I am sure you can figure that out for yourself. \n\r\nCan you help the student find his average marks in the remaining subjects?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTotal marks in 8 subjects = 8 x 82 = 656. \n\r\nTotal marks in 2 English subjects = 2 x 61 = 122. \n\r\nTotal marks in remaining 6 subjects = 656 - 122 = 534. \n\r\nAverage marks in remaining 6 subjects = 534 / 6 = 89.\n<|im_start|>answer\nTotal marks in 8 subjects = 8 x 82 = 656. \n\r\nTotal marks in 2 English subjects = 2 x 61 = 122. \n\r\nTotal marks in remaining 6 subjects = 656 - 122 = 534. \n\r\nAverage marks in remaining 6 subjects = 534 / 6 = 89.\n<|im_end|>" }, { "id": "#4875", "title": "Untrue Ages", "fun": 2.25, "difficulty": 2.14, "author": "mad-ade", "desc": "Boris Downhillski and Mad Ade have a conversation.\n\r\nBoris says: \"I am certainly not over 40.\"\r\nMad Ade says: \"I am 38 and you are at least 5 years older than me.\"\r\nNow Boris says: \"You are at least 39.\"\r\nAll the statements by the two are false. How old are they really?", "hint": "No hint available.", "answer": "Boris is 41 and Mad Ade is 37. \n\r\nSeeing as they are both lying then the real conversation should really run like this:\r\nBoris says: \"I am certainly over 40.\"\r\nMad Ade says: \"I am not 38 and you are at most 4 years older than me.\"\r\nNow Boris says: \"You are at most 38.\"\r\nFrom first statement it is clear that Boris is over 40. Also, from next 2 statements it is clear that Mad Ade is less than 38. Hence the possibilities are : \r\nBoris = 41, 42, 43, 44, 45, ...... \r\nMad Ade = 37, 36, 35, 34, 33, ...... \n\r\nIt also says that the difference between their age is maximum 4 years. Hence, there is only one possible pair i.e. 41 and 37, all other combination have differences more than 4.\n\r\nHence the answer - Boris is 41 and Mad Ade is 37.", "category": "Logic", "date": "06/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBoris Downhillski and Mad Ade have a conversation.\n\r\nBoris says: \"I am certainly not over 40.\"\r\nMad Ade says: \"I am 38 and you are at least 5 years older than me.\"\r\nNow Boris says: \"You are at least 39.\"\r\nAll the statements by the two are false. How old are they really?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoris is 41 and Mad Ade is 37. \n\r\nSeeing as they are both lying then the real conversation should really run like this:\r\nBoris says: \"I am certainly over 40.\"\r\nMad Ade says: \"I am not 38 and you are at most 4 years older than me.\"\r\nNow Boris says: \"You are at most 38.\"\r\nFrom first statement it is clear that Boris is over 40. Also, from next 2 statements it is clear that Mad Ade is less than 38. Hence the possibilities are : \r\nBoris = 41, 42, 43, 44, 45, ...... \r\nMad Ade = 37, 36, 35, 34, 33, ...... \n\r\nIt also says that the difference between their age is maximum 4 years. Hence, there is only one possible pair i.e. 41 and 37, all other combination have differences more than 4.\n\r\nHence the answer - Boris is 41 and Mad Ade is 37.\n<|im_start|>answer\nBoris is 41 and Mad Ade is 37. \n\r\nSeeing as they are both lying then the real conversation should really run like this:\r\nBoris says: \"I am certainly over 40.\"\r\nMad Ade says: \"I am not 38 and you are at most 4 years older than me.\"\r\nNow Boris says: \"You are at most 38.\"\r\nFrom first statement it is clear that Boris is over 40. Also, from next 2 statements it is clear that Mad Ade is less than 38. Hence the possibilities are : \r\nBoris = 41, 42, 43, 44, 45, ...... \r\nMad Ade = 37, 36, 35, 34, 33, ...... \n\r\nIt also says that the difference between their age is maximum 4 years. Hence, there is only one possible pair i.e. 41 and 37, all other combination have differences more than 4.\n\r\nHence the answer - Boris is 41 and Mad Ade is 37.\n<|im_end|>" }, { "id": "#2456", "title": "One from Nine", "fun": 2.25, "difficulty": 1.43, "author": "SandiMcgee1", "desc": "How do you take 1 away from 9 and get 10?", "hint": "No hint available.", "answer": "Use Roman Numerals\n\r\nIX - I = X", "category": "Math", "date": "02/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow do you take 1 away from 9 and get 10?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUse Roman Numerals\n\r\nIX - I = X\n<|im_start|>answer\nUse Roman Numerals\n\r\nIX - I = X\n<|im_end|>" }, { "id": "#4891", "title": "Backwards Clock", "fun": 2.25, "difficulty": 2.77, "author": "mad-ade", "desc": "With the death of Arthur Minit, the legendary country of MADADIA's only clock maker, no one else had much experience yet with making clocks. The new church of MADADIA had just been completed and a new clock was needed to fit into the bell tower. A clock was made by the locals, using the books of Arthur Minit as a guide.The newly made clock was officially put into use when it showed 6 o'clock. But soon it was noticed that the hour-hand and minute-hand had been interchanged and attached to the wrong spindles. The result was that the hour-hand moved with a speed twelve times higher than the minute-hand. When a clock maker arrived from another area, a remarkable thing happened: on the moment he inspected the clock, it showed exactly the right time. \n\r\nThe Question: If the clock started in the 6 o'clock position, then what was the first moment that it showed the correct time again?", "hint": "No hint available.", "answer": "Suppose that a second pair of hands turns together with the wrong pair of hands, but then in the correct way. When the wrong pair is in the same position as the correct pair, this means that the time is shown in the right way. First look at the hour-hands that are at the twelve. One turns with the correct speed, the other with a speed that is twelve times as small. These two hands are in the same position again when the 'slow' hand has progressed x minutes. The fast hand then has progressed 60+x minutes. For the time x that passed, then holds: (60+x)/12 = x. This means that x = 5 5/11 minutes. \r\nFor the minutes-hands that start at six holds the same. The confused clock therefore shows the correct time again at 5 5/11 minutes past 7.", "category": "Logic", "date": "06/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWith the death of Arthur Minit, the legendary country of MADADIA's only clock maker, no one else had much experience yet with making clocks. The new church of MADADIA had just been completed and a new clock was needed to fit into the bell tower. A clock was made by the locals, using the books of Arthur Minit as a guide.The newly made clock was officially put into use when it showed 6 o'clock. But soon it was noticed that the hour-hand and minute-hand had been interchanged and attached to the wrong spindles. The result was that the hour-hand moved with a speed twelve times higher than the minute-hand. When a clock maker arrived from another area, a remarkable thing happened: on the moment he inspected the clock, it showed exactly the right time. \n\r\nThe Question: If the clock started in the 6 o'clock position, then what was the first moment that it showed the correct time again?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSuppose that a second pair of hands turns together with the wrong pair of hands, but then in the correct way. When the wrong pair is in the same position as the correct pair, this means that the time is shown in the right way. First look at the hour-hands that are at the twelve. One turns with the correct speed, the other with a speed that is twelve times as small. These two hands are in the same position again when the 'slow' hand has progressed x minutes. The fast hand then has progressed 60+x minutes. For the time x that passed, then holds: (60+x)/12 = x. This means that x = 5 5/11 minutes. \r\nFor the minutes-hands that start at six holds the same. The confused clock therefore shows the correct time again at 5 5/11 minutes past 7.\n<|im_start|>answer\nSuppose that a second pair of hands turns together with the wrong pair of hands, but then in the correct way. When the wrong pair is in the same position as the correct pair, this means that the time is shown in the right way. First look at the hour-hands that are at the twelve. One turns with the correct speed, the other with a speed that is twelve times as small. These two hands are in the same position again when the 'slow' hand has progressed x minutes. The fast hand then has progressed 60+x minutes. For the time x that passed, then holds: (60+x)/12 = x. This means that x = 5 5/11 minutes. \r\nFor the minutes-hands that start at six holds the same. The confused clock therefore shows the correct time again at 5 5/11 minutes past 7.\n<|im_end|>" }, { "id": "#2252", "title": "Cat and Pigeon", "fun": 2.25, "difficulty": 2.03, "author": "PyroTekniks", "desc": "Downs, Heath, Field, Forest, and Marsh are five elderly pigeon fanciers who were worried by the marauding cats owned by five elderly spinsters, and, hoping to get control of the cats, they married these ladies. The scheme worked well for each of them so far as his own cat and pigeons were concerned; but it was not long before each cat had claimed a victim and each fancier had lost his favorite pigeon. \n\r\nMrs. Downs' cat killed the pigeon owned by the man who married the owner of the cat which killed Mr. Marsh's pigeon. \n\r\nMr. Downs' pigeon was killed by Mrs. Heath's cat. \n\r\nMr. Forest's pigeon was killed by the cat owned by the lady who married the man whose pigeon was killed by Mrs. Field's cat. \n\r\nWho was the owner of the pigeon killed by Mrs. Forest's cat?", "hint": "No hint available.", "answer": "Mr. Heath's pigeon was killed by Mrs. Forest's cat.", "category": "Logic", "date": "02/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDowns, Heath, Field, Forest, and Marsh are five elderly pigeon fanciers who were worried by the marauding cats owned by five elderly spinsters, and, hoping to get control of the cats, they married these ladies. The scheme worked well for each of them so far as his own cat and pigeons were concerned; but it was not long before each cat had claimed a victim and each fancier had lost his favorite pigeon. \n\r\nMrs. Downs' cat killed the pigeon owned by the man who married the owner of the cat which killed Mr. Marsh's pigeon. \n\r\nMr. Downs' pigeon was killed by Mrs. Heath's cat. \n\r\nMr. Forest's pigeon was killed by the cat owned by the lady who married the man whose pigeon was killed by Mrs. Field's cat. \n\r\nWho was the owner of the pigeon killed by Mrs. Forest's cat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Heath's pigeon was killed by Mrs. Forest's cat.\n<|im_start|>answer\nMr. Heath's pigeon was killed by Mrs. Forest's cat.\n<|im_end|>" }, { "id": "#21024", "title": "Who Won 2", "fun": 2.25, "difficulty": 1.05, "author": "this_is_just_me", "desc": "Rob, Randy, Rich, and Ray had a race together. Rob couldn't catch up to Randy, and Randy couldn't catch up with Rich. Rich beat Ray, and Rob also beat Ray. What order did they finish in?", "hint": "No hint available.", "answer": "Rich\r\nRandy\r\nRob\r\nRay", "category": "Logic", "date": "02/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRob, Randy, Rich, and Ray had a race together. Rob couldn't catch up to Randy, and Randy couldn't catch up with Rich. Rich beat Ray, and Rob also beat Ray. What order did they finish in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRich\r\nRandy\r\nRob\r\nRay\n<|im_start|>answer\nRich\r\nRandy\r\nRob\r\nRay\n<|im_end|>" }, { "id": "#11051", "title": "Struck Down", "fun": 2.25, "difficulty": 2.26, "author": "jimbo", "desc": "One hundred people stand in a row \r\nEach has a rank from go to whoa \r\nEvery fifth one is struck from the line \r\nThis is repeated time after time \r\n'til at last there is only five left in line\r\nWhat is the original rank of the one on the end this time?", "hint": "They line up numbered from 1 to 100 and every fifth person leaves the line. This continues till only 5 remain.", "answer": "Initially the rank of the last person is 100. Every fifth person is struck out of the line. Since 100 is divisible by 5 this person leaves. Thus the last 2 ranking persons are now the (original) 99th and 98th and there are 80 people left. Every fifth person now leaves, including the last one originally ranked 99 so the last person is now the original ranked 98th. 80/5 is 16 so 16 have left with 64 remaining. Now, 12 leave (64/5) down to 52. Then 10 leave (52/5) with 42 remaining. 8 leave with 34 remaining; 6 leave with 28 remaining; 5 leave with 23 remaining...19...16...13..11...9,8,7,6,5. To this point none of the remaining queues have been evenly divisible by 5 so the last person has always stayed. The person originally ranked 98th is still here!", "category": "Math", "date": "03/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne hundred people stand in a row \r\nEach has a rank from go to whoa \r\nEvery fifth one is struck from the line \r\nThis is repeated time after time \r\n'til at last there is only five left in line\r\nWhat is the original rank of the one on the end this time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nInitially the rank of the last person is 100. Every fifth person is struck out of the line. Since 100 is divisible by 5 this person leaves. Thus the last 2 ranking persons are now the (original) 99th and 98th and there are 80 people left. Every fifth person now leaves, including the last one originally ranked 99 so the last person is now the original ranked 98th. 80/5 is 16 so 16 have left with 64 remaining. Now, 12 leave (64/5) down to 52. Then 10 leave (52/5) with 42 remaining. 8 leave with 34 remaining; 6 leave with 28 remaining; 5 leave with 23 remaining...19...16...13..11...9,8,7,6,5. To this point none of the remaining queues have been evenly divisible by 5 so the last person has always stayed. The person originally ranked 98th is still here!\n<|im_start|>answer\nInitially the rank of the last person is 100. Every fifth person is struck out of the line. Since 100 is divisible by 5 this person leaves. Thus the last 2 ranking persons are now the (original) 99th and 98th and there are 80 people left. Every fifth person now leaves, including the last one originally ranked 99 so the last person is now the original ranked 98th. 80/5 is 16 so 16 have left with 64 remaining. Now, 12 leave (64/5) down to 52. Then 10 leave (52/5) with 42 remaining. 8 leave with 34 remaining; 6 leave with 28 remaining; 5 leave with 23 remaining...19...16...13..11...9,8,7,6,5. To this point none of the remaining queues have been evenly divisible by 5 so the last person has always stayed. The person originally ranked 98th is still here!\n<|im_end|>" }, { "id": "#13824", "title": "Can a Number be a Palindrome?", "fun": 2.25, "difficulty": 1.24, "author": "bobdole", "desc": "What number, when multiplied by itself, is a palindrome when used nine times or fewer? \n\r\nFor example, if the digit is \"A\", then the products: \n\r\nAA x AAA \r\nA x AAAAA \r\nAAA x AAA \r\nAAAAAA x AAAAA \r\netc. \n\r\nwould all have palindromes for answers. \n\r\nA palindrome is a word (or in this case a number) which is read the same way forward and backward.", "hint": "No hint available.", "answer": "1 is one answer. \r\n1x1=1\r\n11x11=121\r\n111x111=12321\r\n1111x1111=1234321\r\n11x111111=1222221 etc, etc...", "category": "Math", "date": "07/15/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number, when multiplied by itself, is a palindrome when used nine times or fewer? \n\r\nFor example, if the digit is \"A\", then the products: \n\r\nAA x AAA \r\nA x AAAAA \r\nAAA x AAA \r\nAAAAAA x AAAAA \r\netc. \n\r\nwould all have palindromes for answers. \n\r\nA palindrome is a word (or in this case a number) which is read the same way forward and backward.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 is one answer. \r\n1x1=1\r\n11x11=121\r\n111x111=12321\r\n1111x1111=1234321\r\n11x111111=1222221 etc, etc...\n<|im_start|>answer\n1 is one answer. \r\n1x1=1\r\n11x11=121\r\n111x111=12321\r\n1111x1111=1234321\r\n11x111111=1222221 etc, etc...\n<|im_end|>" }, { "id": "#11128", "title": "Torks' Non-Escape", "fun": 2.25, "difficulty": 2.4, "author": "mad-ade", "desc": "When world-famous Madadian philosopher Torks G'Arbage was imprisoned for being a disturbing influence and relieving himself in a public place, he was held in high esteem by his guards, many of whom had followed Torks' teachings. All four of the guards hoped that something would occur that would facilitate his escape. One evening, the guard who was on duty accidentally on purpose left the cell door open so that Torks G'Arbage could leave for distant parts. \n\r\nTorks G'Arbage did not attempt to escape, as it was his philosophy that if you accept society's rules, you must also accept its punishments. However, the open door was considered by the Madadian authorities to be a serious matter. It was not clear which guard was on that evening. When questioned, the four guards made the following statements in their defence: \n\r\nNorris McDim: \r\nA) I did not leave the door open. \r\nB) Morris was the one who did it. \n\r\nNobby Shifty: \r\nA) I was not the one who was on duty that evening. \r\nB) Norris was on duty. \n\r\nMorris the Daft: \r\nA) Nobby was the one on duty that evening. \r\nB) I hoped Torks G'Arbage would escape. \n\r\nRobby O'Mental: \r\nA) I did not leave the door open. \r\nB) I was not surprised that Torks G'Arbage did not attempt to escape. \n\r\nConsidering that, in total, three statements are true and five statements are false, which guard is guilty?", "hint": "No hint available.", "answer": "Robby left the door open. \n\r\nThe one truth given is that all 4 guards hoped that Torks G'Arbage would escape, so statement B from Morris is a truth. \n\r\nThere are only 3 truthful statements. \n\r\nIf Norris had done it, then Nobby made 2 truthful statements and Robby's statement A would be true; making a total of 4 truths, so it can't be Norris. \n\r\nIf Nobby had done it, statement A from Norris would be true, both of Morris's statements would be true, and Robby's statement A would be true; again a total of 4, so it can't be Nobby. \n\r\nIf Morris had left the cell open, both of Norris's statements would be true, as would Nobby's statement A, Morris's statement B, and Robby's statement A; a total of 5 truths. \n\r\nIn Robby's case, in detail:\n\r\nNorris A True \r\nB False \r\nNobby A True \r\nB False \r\nMorris A False \r\nB True \r\nDave A False \r\nB False (why did he bother to leave the \r\ncell door open?)", "category": "Logic", "date": "03/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen world-famous Madadian philosopher Torks G'Arbage was imprisoned for being a disturbing influence and relieving himself in a public place, he was held in high esteem by his guards, many of whom had followed Torks' teachings. All four of the guards hoped that something would occur that would facilitate his escape. One evening, the guard who was on duty accidentally on purpose left the cell door open so that Torks G'Arbage could leave for distant parts. \n\r\nTorks G'Arbage did not attempt to escape, as it was his philosophy that if you accept society's rules, you must also accept its punishments. However, the open door was considered by the Madadian authorities to be a serious matter. It was not clear which guard was on that evening. When questioned, the four guards made the following statements in their defence: \n\r\nNorris McDim: \r\nA) I did not leave the door open. \r\nB) Morris was the one who did it. \n\r\nNobby Shifty: \r\nA) I was not the one who was on duty that evening. \r\nB) Norris was on duty. \n\r\nMorris the Daft: \r\nA) Nobby was the one on duty that evening. \r\nB) I hoped Torks G'Arbage would escape. \n\r\nRobby O'Mental: \r\nA) I did not leave the door open. \r\nB) I was not surprised that Torks G'Arbage did not attempt to escape. \n\r\nConsidering that, in total, three statements are true and five statements are false, which guard is guilty?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRobby left the door open. \n\r\nThe one truth given is that all 4 guards hoped that Torks G'Arbage would escape, so statement B from Morris is a truth. \n\r\nThere are only 3 truthful statements. \n\r\nIf Norris had done it, then Nobby made 2 truthful statements and Robby's statement A would be true; making a total of 4 truths, so it can't be Norris. \n\r\nIf Nobby had done it, statement A from Norris would be true, both of Morris's statements would be true, and Robby's statement A would be true; again a total of 4, so it can't be Nobby. \n\r\nIf Morris had left the cell open, both of Norris's statements would be true, as would Nobby's statement A, Morris's statement B, and Robby's statement A; a total of 5 truths. \n\r\nIn Robby's case, in detail:\n\r\nNorris A True \r\nB False \r\nNobby A True \r\nB False \r\nMorris A False \r\nB True \r\nDave A False \r\nB False (why did he bother to leave the \r\ncell door open?)\n<|im_start|>answer\nRobby left the door open. \n\r\nThe one truth given is that all 4 guards hoped that Torks G'Arbage would escape, so statement B from Morris is a truth. \n\r\nThere are only 3 truthful statements. \n\r\nIf Norris had done it, then Nobby made 2 truthful statements and Robby's statement A would be true; making a total of 4 truths, so it can't be Norris. \n\r\nIf Nobby had done it, statement A from Norris would be true, both of Morris's statements would be true, and Robby's statement A would be true; again a total of 4, so it can't be Nobby. \n\r\nIf Morris had left the cell open, both of Norris's statements would be true, as would Nobby's statement A, Morris's statement B, and Robby's statement A; a total of 5 truths. \n\r\nIn Robby's case, in detail:\n\r\nNorris A True \r\nB False \r\nNobby A True \r\nB False \r\nMorris A False \r\nB True \r\nDave A False \r\nB False (why did he bother to leave the \r\ncell door open?)\n<|im_end|>" }, { "id": "#32064", "title": "Travel Tally", "fun": 2.25, "difficulty": 1.66, "author": "lips", "desc": "On the first 5 days of vacation, the Williams family drove 1,427 miles. They left on Friday, and the minimum and maximum distances for one day's trip were 200 and 355 miles. They arrived at their destination late on Tuesday.\n\r\n1. Since they left late, they drove the least number of miles on the first day. \r\n2. They drove 105 miles more on the second day than on the first. \r\n3. On Monday they drove the most. \r\n4. On Tuesday they drove 68 miles less than on Saturday. \n\r\nHow many miles did they drive each day?", "hint": "Make a chart, and then work backwards using the clues.", "answer": "On the first 5 days of vacation, the Williams family drove the following miles:\n\r\nFriday: 200 miles\r\nSaturday: 305 miles\r\nSunday: 330 miles\r\nMonday: 355 miles\r\nTuesday: 237 miles", "category": "Math", "date": "07/26/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn the first 5 days of vacation, the Williams family drove 1,427 miles. They left on Friday, and the minimum and maximum distances for one day's trip were 200 and 355 miles. They arrived at their destination late on Tuesday.\n\r\n1. Since they left late, they drove the least number of miles on the first day. \r\n2. They drove 105 miles more on the second day than on the first. \r\n3. On Monday they drove the most. \r\n4. On Tuesday they drove 68 miles less than on Saturday. \n\r\nHow many miles did they drive each day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn the first 5 days of vacation, the Williams family drove the following miles:\n\r\nFriday: 200 miles\r\nSaturday: 305 miles\r\nSunday: 330 miles\r\nMonday: 355 miles\r\nTuesday: 237 miles\n<|im_start|>answer\nOn the first 5 days of vacation, the Williams family drove the following miles:\n\r\nFriday: 200 miles\r\nSaturday: 305 miles\r\nSunday: 330 miles\r\nMonday: 355 miles\r\nTuesday: 237 miles\n<|im_end|>" }, { "id": "#47725", "title": "My Name is and I Have Moved From", "fun": 2.25, "difficulty": 0.5, "author": "srigimi3", "desc": "4 kids enter a classroom in Texas.\r\nThey each have moved from a state.\r\nThe kids names are Allie, David, Gina, and Jake.\r\nTheir last names are Forrester, Logan, Morgan, and Miller.\r\nThey have moved from Nevada, North Dakota, Wisconsin, and Arizona.\n\r\nThese are the clues.\r\n1. David is not from Arizona.\r\n2. The kid who has the last name Forrester is from North Dakota.\r\n3. Allie's last name is Miller.\r\n4. Gina's last name is NOT Logan and she is from Wisconsin.\r\n5. Jake's last name is NOT Morgan and he is NOT from North Dakota.\r\n6. The kid with the last name Morgan is from Wisconsin.\r\n7. The kid who's moved from Arizona last name is Miller.\r\n8. Jake is from Nevada but his last name is NOT Forrester.\n\n\r\nWhat are their whole names and where did they move from?", "hint": "No hint available.", "answer": "David Forrester has moved from North Dakota.\r\nJake Logan has moved from Nevada.\r\nGina Morgan has moved from Wisconsin.\r\nAllie Miller has moved from Arizona.", "category": "Logic-Grid", "date": "08/12/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 kids enter a classroom in Texas.\r\nThey each have moved from a state.\r\nThe kids names are Allie, David, Gina, and Jake.\r\nTheir last names are Forrester, Logan, Morgan, and Miller.\r\nThey have moved from Nevada, North Dakota, Wisconsin, and Arizona.\n\r\nThese are the clues.\r\n1. David is not from Arizona.\r\n2. The kid who has the last name Forrester is from North Dakota.\r\n3. Allie's last name is Miller.\r\n4. Gina's last name is NOT Logan and she is from Wisconsin.\r\n5. Jake's last name is NOT Morgan and he is NOT from North Dakota.\r\n6. The kid with the last name Morgan is from Wisconsin.\r\n7. The kid who's moved from Arizona last name is Miller.\r\n8. Jake is from Nevada but his last name is NOT Forrester.\n\n\r\nWhat are their whole names and where did they move from?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDavid Forrester has moved from North Dakota.\r\nJake Logan has moved from Nevada.\r\nGina Morgan has moved from Wisconsin.\r\nAllie Miller has moved from Arizona.\n<|im_start|>answer\nDavid Forrester has moved from North Dakota.\r\nJake Logan has moved from Nevada.\r\nGina Morgan has moved from Wisconsin.\r\nAllie Miller has moved from Arizona.\n<|im_end|>" }, { "id": "#6058", "title": "Captain Election", "fun": 2.25, "difficulty": 1.66, "author": "glennyboy02", "desc": "In an election for school captain, 320 votes were cast for five candidates. The winner's margin over the four candidates was 9, 13, 18 and 25. What was the lowest number of votes?", "hint": "No hint available.", "answer": "52\n\r\nx + (x-9) + (x-13) + (x-18) + (x-25) = 320. Solve this and get x = 77. Therefore the lowest score is 77 - 25 = 52.", "category": "Math", "date": "07/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn an election for school captain, 320 votes were cast for five candidates. The winner's margin over the four candidates was 9, 13, 18 and 25. What was the lowest number of votes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n52\n\r\nx + (x-9) + (x-13) + (x-18) + (x-25) = 320. Solve this and get x = 77. Therefore the lowest score is 77 - 25 = 52.\n<|im_start|>answer\n52\n\r\nx + (x-9) + (x-13) + (x-18) + (x-25) = 320. Solve this and get x = 77. Therefore the lowest score is 77 - 25 = 52.\n<|im_end|>" }, { "id": "#5301", "title": "5:6:7", "fun": 2.25, "difficulty": 1.59, "author": "cleverclogs", "desc": "36 sweets are shared out in the ratio 5:6:7. My share is '6'. If 18 more sweets are shared out, how many sweets do I have?", "hint": "No hint available.", "answer": "36 in to 5:6:7 = 10:12:14\r\n +\r\n18 in to 5:6:7 = 5 :6 :7\n\r\nTherefore I have 18 sweets altogether.", "category": "Math", "date": "07/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n36 sweets are shared out in the ratio 5:6:7. My share is '6'. If 18 more sweets are shared out, how many sweets do I have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n36 in to 5:6:7 = 10:12:14\r\n +\r\n18 in to 5:6:7 = 5 :6 :7\n\r\nTherefore I have 18 sweets altogether.\n<|im_start|>answer\n36 in to 5:6:7 = 10:12:14\r\n +\r\n18 in to 5:6:7 = 5 :6 :7\n\r\nTherefore I have 18 sweets altogether.\n<|im_end|>" }, { "id": "#4844", "title": "Packet of Nuts", "fun": 2.25, "difficulty": 2.67, "author": "mad-ade", "desc": "Mad Ade has bought a mixed packet of nuts which contains 1 pound of walnuts and 2 pounds of Brazil nuts. It costs £1.98. Mad Ade noticed that a packet containing 4 pounds of filberts and 1 pound of walnuts costs £2.48. And for £2.99, Mad Ade can buy a mixed packet containing 3 pounds of almonds, 1 pound of walnuts, and 1 pound of filberts. Whilst looking at the nudie mags on the top shelf of the shop Mad Ade wondered exactly how much a packet containing 1 pound of each type of nut would cost", "hint": "No hint available.", "answer": "It is impossible to work out the cost per pound of each of the different nuts. However, the cost of various combinations can be worked out. If you combine 3 packets of the first kind with 1 packet of the second kind and 2 of the third packet, you get 6 pounds for £14.40. A mixture of 1 pound of each, therefore, should cost you (£14.40 / 6) = £2.40 . Mad Ade paid with a five pound note and bought a copy of \"Kebab Fanciers Weekly\" with the change", "category": "Math", "date": "06/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has bought a mixed packet of nuts which contains 1 pound of walnuts and 2 pounds of Brazil nuts. It costs £1.98. Mad Ade noticed that a packet containing 4 pounds of filberts and 1 pound of walnuts costs £2.48. And for £2.99, Mad Ade can buy a mixed packet containing 3 pounds of almonds, 1 pound of walnuts, and 1 pound of filberts. Whilst looking at the nudie mags on the top shelf of the shop Mad Ade wondered exactly how much a packet containing 1 pound of each type of nut would cost\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is impossible to work out the cost per pound of each of the different nuts. However, the cost of various combinations can be worked out. If you combine 3 packets of the first kind with 1 packet of the second kind and 2 of the third packet, you get 6 pounds for £14.40. A mixture of 1 pound of each, therefore, should cost you (£14.40 / 6) = £2.40 . Mad Ade paid with a five pound note and bought a copy of \"Kebab Fanciers Weekly\" with the change\n<|im_start|>answer\nIt is impossible to work out the cost per pound of each of the different nuts. However, the cost of various combinations can be worked out. If you combine 3 packets of the first kind with 1 packet of the second kind and 2 of the third packet, you get 6 pounds for £14.40. A mixture of 1 pound of each, therefore, should cost you (£14.40 / 6) = £2.40 . Mad Ade paid with a five pound note and bought a copy of \"Kebab Fanciers Weekly\" with the change\n<|im_end|>" }, { "id": "#6397", "title": "Statue", "fun": 2.25, "difficulty": 1.9000000000000001, "author": "mad-ade", "desc": "In the land of MADADIA world famous sculptor, Chip Itout, was working on his latest creation, \"The Kebab of Venus\". He began with a block of marble that weighed 125 pounds. On the first day Chip chisels off 35% of the block. On the second day he removed 20% of what was remaining and on the third day he cut away 25% of what was left. What was the weight of the finished \"Kebab of Venus\" statue?", "hint": "No hint available.", "answer": "48.75 pounds\r\nday 1 he removes 43.75lbs(35%of 125lbs) leaving 81.25lbs\r\nday 2 he removes 16.25lbs(20%of 81.25lbs) leaving 65lbs\r\nday 3 he removes 16.25lbs(25%of 65lbs) leaving 48.75lbs", "category": "Math", "date": "08/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of MADADIA world famous sculptor, Chip Itout, was working on his latest creation, \"The Kebab of Venus\". He began with a block of marble that weighed 125 pounds. On the first day Chip chisels off 35% of the block. On the second day he removed 20% of what was remaining and on the third day he cut away 25% of what was left. What was the weight of the finished \"Kebab of Venus\" statue?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n48.75 pounds\r\nday 1 he removes 43.75lbs(35%of 125lbs) leaving 81.25lbs\r\nday 2 he removes 16.25lbs(20%of 81.25lbs) leaving 65lbs\r\nday 3 he removes 16.25lbs(25%of 65lbs) leaving 48.75lbs\n<|im_start|>answer\n48.75 pounds\r\nday 1 he removes 43.75lbs(35%of 125lbs) leaving 81.25lbs\r\nday 2 he removes 16.25lbs(20%of 81.25lbs) leaving 65lbs\r\nday 3 he removes 16.25lbs(25%of 65lbs) leaving 48.75lbs\n<|im_end|>" }, { "id": "#1388", "title": "Camel and Watermelons", "fun": 2.25, "difficulty": 2.69, "author": "Rado", "desc": "In city A on desert, there is a guy with his camel and 1000 watermelons. He wants to sell the watermelons in city B where a fair takes place. The distance between A and B is 99km. \r\nHowever, the camel can only carry a maximum of 100 watermelons at a time. In addition to that, the camel eats one watermelon per each kilometer it travels. \r\nThe guy wants to bring to the fair as many watermelons as possible. How can he do it? And what is the maximum number?", "hint": "What if the distance was just 1km? What if it was 2? What if it was 5?", "answer": "If the distance was 1, the obvious maximum would be 981 (as the camel needs to travel 19 times). If the distance was 2, the result is same as if the man had 981 watermelons and to go only 1km, so the result would be 962. When using this method, we can calculate that the final number of watermelons is 140. (Note: The result for distance of 6 is 886 but from this moment the camel needs to travel only 17 times to get all the watermelons 1km further, so the result for distance of 7 is 869)", "category": "Math", "date": "11/13/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn city A on desert, there is a guy with his camel and 1000 watermelons. He wants to sell the watermelons in city B where a fair takes place. The distance between A and B is 99km. \r\nHowever, the camel can only carry a maximum of 100 watermelons at a time. In addition to that, the camel eats one watermelon per each kilometer it travels. \r\nThe guy wants to bring to the fair as many watermelons as possible. How can he do it? And what is the maximum number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the distance was 1, the obvious maximum would be 981 (as the camel needs to travel 19 times). If the distance was 2, the result is same as if the man had 981 watermelons and to go only 1km, so the result would be 962. When using this method, we can calculate that the final number of watermelons is 140. (Note: The result for distance of 6 is 886 but from this moment the camel needs to travel only 17 times to get all the watermelons 1km further, so the result for distance of 7 is 869)\n<|im_start|>answer\nIf the distance was 1, the obvious maximum would be 981 (as the camel needs to travel 19 times). If the distance was 2, the result is same as if the man had 981 watermelons and to go only 1km, so the result would be 962. When using this method, we can calculate that the final number of watermelons is 140. (Note: The result for distance of 6 is 886 but from this moment the camel needs to travel only 17 times to get all the watermelons 1km further, so the result for distance of 7 is 869)\n<|im_end|>" }, { "id": "#4222", "title": "Telegraph Poles", "fun": 2.25, "difficulty": 1.83, "author": "mad-ade", "desc": "Mad Ade is driving alone at a constant speed. Ahead of him at the road side are 20 telegraph poles, each at an equal distance from each other. Mad Ade times himself and notices that it took 24 seconds from when he passed the first pole to reach the 12th telegraph pole. How long would it take in total to reach the last pole?", "hint": "No hint available.", "answer": "41.45 seconds.", "category": "Math", "date": "05/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is driving alone at a constant speed. Ahead of him at the road side are 20 telegraph poles, each at an equal distance from each other. Mad Ade times himself and notices that it took 24 seconds from when he passed the first pole to reach the 12th telegraph pole. How long would it take in total to reach the last pole?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n41.45 seconds.\n<|im_start|>answer\n41.45 seconds.\n<|im_end|>" }, { "id": "#6344", "title": "Kebab Delivery", "fun": 2.25, "difficulty": 2.12, "author": "mad-ade", "desc": "The owner of the \"Sweaty Chef\" kebab shop Mr. Juan, had ordered a fresh delivery of kebabs. Mr. Juan was a bit of a strange character and insisted that the kebabs must be delivered in a certain manner. When they arrived they were in boxes, so Mr. Juan weighed each box individually. The boxes weighed as follows:-\n\r\nBox 1 33kg\r\nBox 2 35kg\r\nBox 3 60kg\r\nBox 4 42kg\r\nBox 5 15kg\n\r\nWhich box did Mr. Juan reject and why?", "hint": "No hint available.", "answer": "Box 2, because Mr. Juan doesn't mind how heavy each box is as long as the digits in their weight adds up to 6. Because that is his lucky number and he is very superstitious.", "category": "Logic", "date": "08/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe owner of the \"Sweaty Chef\" kebab shop Mr. Juan, had ordered a fresh delivery of kebabs. Mr. Juan was a bit of a strange character and insisted that the kebabs must be delivered in a certain manner. When they arrived they were in boxes, so Mr. Juan weighed each box individually. The boxes weighed as follows:-\n\r\nBox 1 33kg\r\nBox 2 35kg\r\nBox 3 60kg\r\nBox 4 42kg\r\nBox 5 15kg\n\r\nWhich box did Mr. Juan reject and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBox 2, because Mr. Juan doesn't mind how heavy each box is as long as the digits in their weight adds up to 6. Because that is his lucky number and he is very superstitious.\n<|im_start|>answer\nBox 2, because Mr. Juan doesn't mind how heavy each box is as long as the digits in their weight adds up to 6. Because that is his lucky number and he is very superstitious.\n<|im_end|>" }, { "id": "#2151", "title": "Fast and Slow Watches", "fun": 2.25, "difficulty": 1.57, "author": "missie", "desc": "My husband and I can't seem to get our watches to work properly. His consistently runs one minute per hour fast, and mine runs two minutes per hour slow. This morning we nearly missed a wedding because our watches were an hour apart and we looked at the slower one. How many hours had elapsed since we set both of them properly?", "hint": "No hint available.", "answer": "20 hours", "category": "Math", "date": "01/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy husband and I can't seem to get our watches to work properly. His consistently runs one minute per hour fast, and mine runs two minutes per hour slow. This morning we nearly missed a wedding because our watches were an hour apart and we looked at the slower one. How many hours had elapsed since we set both of them properly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20 hours\n<|im_start|>answer\n20 hours\n<|im_end|>" }, { "id": "#19940", "title": "A Race", "fun": 2.25, "difficulty": 0.7000000000000001, "author": "AlexHayward", "desc": "A racecar driver enters a local race on a small oval track. The race is ten laps long. He completes the race in its entirety and wins. How many times did he pass the start/finish line during the race?", "hint": "No hint available.", "answer": "He will pass it eleven times. He has to cross it at the beginning of the race to begin his first lap. He will then pass it once for every lap he completes.", "category": "Logic", "date": "12/17/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA racecar driver enters a local race on a small oval track. The race is ten laps long. He completes the race in its entirety and wins. How many times did he pass the start/finish line during the race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe will pass it eleven times. He has to cross it at the beginning of the race to begin his first lap. He will then pass it once for every lap he completes.\n<|im_start|>answer\nHe will pass it eleven times. He has to cross it at the beginning of the race to begin his first lap. He will then pass it once for every lap he completes.\n<|im_end|>" }, { "id": "#7263", "title": "Kimme", "fun": 2.25, "difficulty": 2.1, "author": "stardust", "desc": "Kimme's mother never leaves her alone. Then one night Kimme's mother tucked her in her bed and went away. How come?", "hint": "No hint available.", "answer": "Kimme and her mother are kangaroos. Her mother tucked her in her pouch and hopped away.", "category": "Logic", "date": "09/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKimme's mother never leaves her alone. Then one night Kimme's mother tucked her in her bed and went away. How come?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKimme and her mother are kangaroos. Her mother tucked her in her pouch and hopped away.\n<|im_start|>answer\nKimme and her mother are kangaroos. Her mother tucked her in her pouch and hopped away.\n<|im_end|>" }, { "id": "#10054", "title": "Centuries Old", "fun": 2.25, "difficulty": 1.07, "author": "mollynoodl", "desc": "I met a woman in a store. She said that she lived through 3 centuries, but that she was slightly more than 100 years old. She wasn't lying, but how can this be?", "hint": "No hint available.", "answer": "She was born at the end of one century, lived through a full one, and was currently living in the beginning of the 3rd. (Example: Born in 1899, lived 1900-1999, living in 2000-2003.)", "category": "Logic", "date": "01/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI met a woman in a store. She said that she lived through 3 centuries, but that she was slightly more than 100 years old. She wasn't lying, but how can this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe was born at the end of one century, lived through a full one, and was currently living in the beginning of the 3rd. (Example: Born in 1899, lived 1900-1999, living in 2000-2003.)\n<|im_start|>answer\nShe was born at the end of one century, lived through a full one, and was currently living in the beginning of the 3rd. (Example: Born in 1899, lived 1900-1999, living in 2000-2003.)\n<|im_end|>" }, { "id": "#8151", "title": "Countries of the World", "fun": 2.25, "difficulty": 2.87, "author": "bluelightnign", "desc": "A man named Stewart is traveling all over the world. First he travels to Cape Town in South Africa. Then to Jakarta in Indonesia. Then to Canberra in Australia. Then to Rome in Italy. Then to Panama City in Panama. Where does he travel next?", "hint": "He travels to a continent he has not traveled to.", "answer": "Santiago in Chile. He travels to each continent in alphabetical order then to the capital of the country that has the most southern latitude.", "category": "Logic", "date": "10/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man named Stewart is traveling all over the world. First he travels to Cape Town in South Africa. Then to Jakarta in Indonesia. Then to Canberra in Australia. Then to Rome in Italy. Then to Panama City in Panama. Where does he travel next?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSantiago in Chile. He travels to each continent in alphabetical order then to the capital of the country that has the most southern latitude.\n<|im_start|>answer\nSantiago in Chile. He travels to each continent in alphabetical order then to the capital of the country that has the most southern latitude.\n<|im_end|>" }, { "id": "#8594", "title": "Sweaty Chef", "fun": 2.25, "difficulty": 2.02, "author": "mad-ade", "desc": "A man went into the \"Sweaty Chef\" Kebab shop and ate a meal costing 105 Madadian Wonks (local currency Madadian Wonk=MW), giving the owner, Mr Juan, a 500 MW note. He kept the change, came back a few minutes later and ordered some kebabs for his girlfriend. He gave the cashier a 100MW note and received 20MW in change. \r\nThe following day the bank told Mr Juan that both the 500MW and the 100MW notes were counterfeit. \n\r\nHow much money did the\"Sweaty Chef\" lose? Ignore the profit of the takeaway.", "hint": "No hint available.", "answer": "600 Madadian Wonks\n\r\nSince the man's entire payment for each visit was counterfeit, everything he took - food and change - constituted a loss to the \"Sweaty Chef\". \n\r\nOn the man's first visit, the restaurant lost the 105MW meal that the man ate and the 395MW that the cashier gave the man in change. Thus, 500MW. \n\r\nOn the man's second visit, the restaurant lost the 80MW meal that the man's girlfriend took, and the 20MW that the cashier gave the man in change. Thus, 100MW.\n\r\nIn all, the \"Sweaty Chef\" lost 600MW in notes and food (or 415MW in just notes, but they should also count the value of the food lost).", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man went into the \"Sweaty Chef\" Kebab shop and ate a meal costing 105 Madadian Wonks (local currency Madadian Wonk=MW), giving the owner, Mr Juan, a 500 MW note. He kept the change, came back a few minutes later and ordered some kebabs for his girlfriend. He gave the cashier a 100MW note and received 20MW in change. \r\nThe following day the bank told Mr Juan that both the 500MW and the 100MW notes were counterfeit. \n\r\nHow much money did the\"Sweaty Chef\" lose? Ignore the profit of the takeaway.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n600 Madadian Wonks\n\r\nSince the man's entire payment for each visit was counterfeit, everything he took - food and change - constituted a loss to the \"Sweaty Chef\". \n\r\nOn the man's first visit, the restaurant lost the 105MW meal that the man ate and the 395MW that the cashier gave the man in change. Thus, 500MW. \n\r\nOn the man's second visit, the restaurant lost the 80MW meal that the man's girlfriend took, and the 20MW that the cashier gave the man in change. Thus, 100MW.\n\r\nIn all, the \"Sweaty Chef\" lost 600MW in notes and food (or 415MW in just notes, but they should also count the value of the food lost).\n<|im_start|>answer\n600 Madadian Wonks\n\r\nSince the man's entire payment for each visit was counterfeit, everything he took - food and change - constituted a loss to the \"Sweaty Chef\". \n\r\nOn the man's first visit, the restaurant lost the 105MW meal that the man ate and the 395MW that the cashier gave the man in change. Thus, 500MW. \n\r\nOn the man's second visit, the restaurant lost the 80MW meal that the man's girlfriend took, and the 20MW that the cashier gave the man in change. Thus, 100MW.\n\r\nIn all, the \"Sweaty Chef\" lost 600MW in notes and food (or 415MW in just notes, but they should also count the value of the food lost).\n<|im_end|>" }, { "id": "#8893", "title": "Buying a Puppy", "fun": 2.25, "difficulty": 2.32, "author": "lesternoronha1", "desc": "A man wishes to sell a puppy for $11. A customer wants to buy it but only has foreign currency. The exchange rate for the foreign currency is 11 round coins = $15, 11 square coins = $16, 11 triangular coins = $17. How many of each coinage should the customer pay?", "hint": "No hint available.", "answer": "7 circular coins and 1 square coin. \n\r\nLet x be the number of circular coins, y be the number of square coins, and z be the number of triangular coins. Thus: \r\nx*(15/11) + y*(16/11) + z*(17/11) = 11. \r\nMultiplying by 11: \r\n15x + 16y + 17z = 121. \r\nFrom here we have to use trial and error or educated guessing. Personally I divided 121 by 15 to get 8 plus a remainder of 1. It was then obvious that x=7, y=1, and z=0 would solve the equation.", "category": "Math", "date": "12/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man wishes to sell a puppy for $11. A customer wants to buy it but only has foreign currency. The exchange rate for the foreign currency is 11 round coins = $15, 11 square coins = $16, 11 triangular coins = $17. How many of each coinage should the customer pay?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 circular coins and 1 square coin. \n\r\nLet x be the number of circular coins, y be the number of square coins, and z be the number of triangular coins. Thus: \r\nx*(15/11) + y*(16/11) + z*(17/11) = 11. \r\nMultiplying by 11: \r\n15x + 16y + 17z = 121. \r\nFrom here we have to use trial and error or educated guessing. Personally I divided 121 by 15 to get 8 plus a remainder of 1. It was then obvious that x=7, y=1, and z=0 would solve the equation.\n<|im_start|>answer\n7 circular coins and 1 square coin. \n\r\nLet x be the number of circular coins, y be the number of square coins, and z be the number of triangular coins. Thus: \r\nx*(15/11) + y*(16/11) + z*(17/11) = 11. \r\nMultiplying by 11: \r\n15x + 16y + 17z = 121. \r\nFrom here we have to use trial and error or educated guessing. Personally I divided 121 by 15 to get 8 plus a remainder of 1. It was then obvious that x=7, y=1, and z=0 would solve the equation.\n<|im_end|>" }, { "id": "#39812", "title": "Postage Possibilities", "fun": 2.25, "difficulty": 1.71, "author": "icestar12", "desc": "Cory's family is sending family photographs with letters to friends, and the weight of each envelope will require 55 cents postage. They have a selection of the following different stamps from which to choose:\n\r\n52-cent Hubert H. Humphrey stamp \r\n32-cent flag stamp \r\n23-cent Mary Cassatt stamp \r\n20-cent bird stamp \r\n15-cent Buffalo Bill Cody stamp \r\n3-cent bird stamp \r\nCory wants each envelope to have exactly 55 cents in postage, and to have a different combination of stamps.\n\r\nWhat are the different stamp combinations Cory can use on the envelopes, if he has room for no more than 5 stamps on an envelope?", "hint": "No hint available.", "answer": "A 32-cent flag stamp, a 20-cent bird stamp, and a 3-cent bird stamp \r\nA 32-cent flag stamp and a 23-cent Mary Cassatt stamp \r\nA 52-cent Hubert H. Humphrey stamp and a 3-cent bird stamp \r\nTwo 20-cent bird stamps and a 15-cent Buffalo Bill Cody stamp \r\nTwo 23-cent Mary Cassatt stamps and three 3-cent bird stamps", "category": "Math", "date": "12/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCory's family is sending family photographs with letters to friends, and the weight of each envelope will require 55 cents postage. They have a selection of the following different stamps from which to choose:\n\r\n52-cent Hubert H. Humphrey stamp \r\n32-cent flag stamp \r\n23-cent Mary Cassatt stamp \r\n20-cent bird stamp \r\n15-cent Buffalo Bill Cody stamp \r\n3-cent bird stamp \r\nCory wants each envelope to have exactly 55 cents in postage, and to have a different combination of stamps.\n\r\nWhat are the different stamp combinations Cory can use on the envelopes, if he has room for no more than 5 stamps on an envelope?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA 32-cent flag stamp, a 20-cent bird stamp, and a 3-cent bird stamp \r\nA 32-cent flag stamp and a 23-cent Mary Cassatt stamp \r\nA 52-cent Hubert H. Humphrey stamp and a 3-cent bird stamp \r\nTwo 20-cent bird stamps and a 15-cent Buffalo Bill Cody stamp \r\nTwo 23-cent Mary Cassatt stamps and three 3-cent bird stamps\n<|im_start|>answer\nA 32-cent flag stamp, a 20-cent bird stamp, and a 3-cent bird stamp \r\nA 32-cent flag stamp and a 23-cent Mary Cassatt stamp \r\nA 52-cent Hubert H. Humphrey stamp and a 3-cent bird stamp \r\nTwo 20-cent bird stamps and a 15-cent Buffalo Bill Cody stamp \r\nTwo 23-cent Mary Cassatt stamps and three 3-cent bird stamps\n<|im_end|>" }, { "id": "#1554", "title": "AAAACCCDFGHIIIIKKLM...", "fun": 2.25, "difficulty": 2.15, "author": "sam7630", "desc": "Can you figure out what these letters represent?\n\r\nAAAACCCDFGHIIIIKKLMMMMMMMMNNNNNNNNOOOPRSSTTUVVWWWW", "hint": "There are 50 letters total.", "answer": "The first letters of the US states in alphabetical order:\n\r\nAlabama, Alaska, Arizona, Arkansas, California, Colorado, Connecticut, Delaware, Florida, Georgia, Hawaii, Idaho, Illinois, Indiana, Iowa, Kansas, Kentucky, Louisiana, Maine, Maryland, Massachusetts, Michigan, Minnesota, Mississippi, Missouri, Montana, Nebraska, Nevada, New Hampshire, New Jersey, New Mexico, New York, North Carolina, North Dakota, Ohio, Oklahoma, Oregon, Pennsylvania, Rhode Island, South Carolina, South Dakota, Tennessee, Texas, Utah, Vermont, Virginia, Washington, West Virginia, Wisconsin, and Wyoming.", "category": "Logic", "date": "11/30/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you figure out what these letters represent?\n\r\nAAAACCCDFGHIIIIKKLMMMMMMMMNNNNNNNNOOOPRSSTTUVVWWWW\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first letters of the US states in alphabetical order:\n\r\nAlabama, Alaska, Arizona, Arkansas, California, Colorado, Connecticut, Delaware, Florida, Georgia, Hawaii, Idaho, Illinois, Indiana, Iowa, Kansas, Kentucky, Louisiana, Maine, Maryland, Massachusetts, Michigan, Minnesota, Mississippi, Missouri, Montana, Nebraska, Nevada, New Hampshire, New Jersey, New Mexico, New York, North Carolina, North Dakota, Ohio, Oklahoma, Oregon, Pennsylvania, Rhode Island, South Carolina, South Dakota, Tennessee, Texas, Utah, Vermont, Virginia, Washington, West Virginia, Wisconsin, and Wyoming.\n<|im_start|>answer\nThe first letters of the US states in alphabetical order:\n\r\nAlabama, Alaska, Arizona, Arkansas, California, Colorado, Connecticut, Delaware, Florida, Georgia, Hawaii, Idaho, Illinois, Indiana, Iowa, Kansas, Kentucky, Louisiana, Maine, Maryland, Massachusetts, Michigan, Minnesota, Mississippi, Missouri, Montana, Nebraska, Nevada, New Hampshire, New Jersey, New Mexico, New York, North Carolina, North Dakota, Ohio, Oklahoma, Oregon, Pennsylvania, Rhode Island, South Carolina, South Dakota, Tennessee, Texas, Utah, Vermont, Virginia, Washington, West Virginia, Wisconsin, and Wyoming.\n<|im_end|>" }, { "id": "#3850", "title": "1, 3, 6", "fun": 2.25, "difficulty": 1.66, "author": "skye", "desc": "Your numbers are as follows:\r\n1, 3, 6, 10, 15, 21, 28\n\r\nWhat will be the 12th number?", "hint": "Look at the order of the number. I.E. 1 was 1. 2 was 3.", "answer": "78. Take the order of what I am asking you. That is 12. Then take that number (12) and multiply it by the number following it. (13) Then divide it by 2. You have your answer. This is also called the triangle puzzle.", "category": "Math", "date": "05/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour numbers are as follows:\r\n1, 3, 6, 10, 15, 21, 28\n\r\nWhat will be the 12th number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n78. Take the order of what I am asking you. That is 12. Then take that number (12) and multiply it by the number following it. (13) Then divide it by 2. You have your answer. This is also called the triangle puzzle.\n<|im_start|>answer\n78. Take the order of what I am asking you. That is 12. Then take that number (12) and multiply it by the number following it. (13) Then divide it by 2. You have your answer. This is also called the triangle puzzle.\n<|im_end|>" }, { "id": "#19154", "title": "Who Likes Whom ?", "fun": 2.25, "difficulty": 1.8800000000000001, "author": "lesternoronha1", "desc": "The relationships of a person X with 3 people P, Q and R are given below.\n\r\n1) X likes at least one of the three people.\r\n2) If X likes P, but not R, then he also likes Q.\r\n3) X likes both R and Q, or he likes neither of them.\r\n4) If X likes R, then he also likes P.\n\r\nWhich of the following statements can be deduced from the above?\r\nA) X likes P, Q and R.\r\nB) X likes only P.\r\nC) X likes only Q.\r\nD) X likes P and Q only.\n\r\nNOTE: Out of the given set of 4 statements, it is not necessary that one and only one statement can be deduced. One or more statements may be possible to be deduced.", "hint": "No hint available.", "answer": "Only statement A which states that X likes P, Q and R can be deduced.\n\r\nThe relationships given are\r\n1) X likes at least one of the three people.\r\n2) If X likes P, but not R, then he also likes Q.\r\n3) X likes both R and Q, or he likes neither of them.\r\n4) If X likes R, then he also likes P.\n\r\nThe statements given are\r\nA) X likes P, Q and R.\r\nB) X likes only P.\r\nC) X likes only Q.\r\nD) X likes P and Q only.\n\r\nFrom relationship 3, we can get the following two cases:-\n\r\nCase 1 : Let us assume that X neither likes R nor Q. It implies that he likes P since from relationship 1, he likes at least one of the three. However relationship 2 which says that if X likes P, but not R, then X also likes Q contradicts the above observation.\n\r\nCase 2 : Let us assume that X likes both R and Q. Then from relationship 4, X likes P also, since he likes R. This does not violate any of the given relationships.\n\r\nSince we know that only the above two cases are possible and Case 1 being ruled out due to contradictory statements, from observation 2 we can deduce only statement A which says that X likes P, Q and R.", "category": "Logic", "date": "10/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe relationships of a person X with 3 people P, Q and R are given below.\n\r\n1) X likes at least one of the three people.\r\n2) If X likes P, but not R, then he also likes Q.\r\n3) X likes both R and Q, or he likes neither of them.\r\n4) If X likes R, then he also likes P.\n\r\nWhich of the following statements can be deduced from the above?\r\nA) X likes P, Q and R.\r\nB) X likes only P.\r\nC) X likes only Q.\r\nD) X likes P and Q only.\n\r\nNOTE: Out of the given set of 4 statements, it is not necessary that one and only one statement can be deduced. One or more statements may be possible to be deduced.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOnly statement A which states that X likes P, Q and R can be deduced.\n\r\nThe relationships given are\r\n1) X likes at least one of the three people.\r\n2) If X likes P, but not R, then he also likes Q.\r\n3) X likes both R and Q, or he likes neither of them.\r\n4) If X likes R, then he also likes P.\n\r\nThe statements given are\r\nA) X likes P, Q and R.\r\nB) X likes only P.\r\nC) X likes only Q.\r\nD) X likes P and Q only.\n\r\nFrom relationship 3, we can get the following two cases:-\n\r\nCase 1 : Let us assume that X neither likes R nor Q. It implies that he likes P since from relationship 1, he likes at least one of the three. However relationship 2 which says that if X likes P, but not R, then X also likes Q contradicts the above observation.\n\r\nCase 2 : Let us assume that X likes both R and Q. Then from relationship 4, X likes P also, since he likes R. This does not violate any of the given relationships.\n\r\nSince we know that only the above two cases are possible and Case 1 being ruled out due to contradictory statements, from observation 2 we can deduce only statement A which says that X likes P, Q and R.\n<|im_start|>answer\nOnly statement A which states that X likes P, Q and R can be deduced.\n\r\nThe relationships given are\r\n1) X likes at least one of the three people.\r\n2) If X likes P, but not R, then he also likes Q.\r\n3) X likes both R and Q, or he likes neither of them.\r\n4) If X likes R, then he also likes P.\n\r\nThe statements given are\r\nA) X likes P, Q and R.\r\nB) X likes only P.\r\nC) X likes only Q.\r\nD) X likes P and Q only.\n\r\nFrom relationship 3, we can get the following two cases:-\n\r\nCase 1 : Let us assume that X neither likes R nor Q. It implies that he likes P since from relationship 1, he likes at least one of the three. However relationship 2 which says that if X likes P, but not R, then X also likes Q contradicts the above observation.\n\r\nCase 2 : Let us assume that X likes both R and Q. Then from relationship 4, X likes P also, since he likes R. This does not violate any of the given relationships.\n\r\nSince we know that only the above two cases are possible and Case 1 being ruled out due to contradictory statements, from observation 2 we can deduce only statement A which says that X likes P, Q and R.\n<|im_end|>" }, { "id": "#3894", "title": "Fishy", "fun": 2.25, "difficulty": 1.61, "author": "mad-ade", "desc": "There are three fish in a pond, whose combined weights equal 15 pounds.\r\nThe lightest fish is a quarter of the weight of the other two fish combined. The heaviest is a pound lighter than the other two fish combined.\n\r\nHow much does each fish weigh?", "hint": "No hint available.", "answer": "3, 5 and 7 pounds", "category": "Math", "date": "05/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three fish in a pond, whose combined weights equal 15 pounds.\r\nThe lightest fish is a quarter of the weight of the other two fish combined. The heaviest is a pound lighter than the other two fish combined.\n\r\nHow much does each fish weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3, 5 and 7 pounds\n<|im_start|>answer\n3, 5 and 7 pounds\n<|im_end|>" }, { "id": "#4551", "title": "Boats and Planes", "fun": 2.25, "difficulty": 2.04, "author": "mad-ade", "desc": "A ship went on a voyage. After it had travelled 180 miles a plane started with 10 times the speed of the ship, following the same path as the ship. Find the distance when they meet from starting point.", "hint": "No hint available.", "answer": "200 miles \n\r\nGiven that speed of the plane is 10 times the speed of the ship. So it is obvious that the distance covered by plane will be 10 times the distance covered by the ship for the given time. \r\ni.e. Distance covered by plane = 10 * (Distance covered by ship after plane started) \n\r\nNow from the given data, \r\nDistance covered by plane = 180 + Distance covered by ship after plane started \r\n10 * (Distance covered by ship after plane started) = 180 + Distance covered by ship after plane started \r\n9 * (Distance covered by ship after plane started) = 180 \r\nDistance covered by ship after plane started = 20 miles \n\r\nTotal distance covered by ship from starting point \r\n= 180 + 20 \r\n= 200 miles", "category": "Math", "date": "06/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA ship went on a voyage. After it had travelled 180 miles a plane started with 10 times the speed of the ship, following the same path as the ship. Find the distance when they meet from starting point.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n200 miles \n\r\nGiven that speed of the plane is 10 times the speed of the ship. So it is obvious that the distance covered by plane will be 10 times the distance covered by the ship for the given time. \r\ni.e. Distance covered by plane = 10 * (Distance covered by ship after plane started) \n\r\nNow from the given data, \r\nDistance covered by plane = 180 + Distance covered by ship after plane started \r\n10 * (Distance covered by ship after plane started) = 180 + Distance covered by ship after plane started \r\n9 * (Distance covered by ship after plane started) = 180 \r\nDistance covered by ship after plane started = 20 miles \n\r\nTotal distance covered by ship from starting point \r\n= 180 + 20 \r\n= 200 miles\n<|im_start|>answer\n200 miles \n\r\nGiven that speed of the plane is 10 times the speed of the ship. So it is obvious that the distance covered by plane will be 10 times the distance covered by the ship for the given time. \r\ni.e. Distance covered by plane = 10 * (Distance covered by ship after plane started) \n\r\nNow from the given data, \r\nDistance covered by plane = 180 + Distance covered by ship after plane started \r\n10 * (Distance covered by ship after plane started) = 180 + Distance covered by ship after plane started \r\n9 * (Distance covered by ship after plane started) = 180 \r\nDistance covered by ship after plane started = 20 miles \n\r\nTotal distance covered by ship from starting point \r\n= 180 + 20 \r\n= 200 miles\n<|im_end|>" }, { "id": "#5452", "title": "Santa's Dilemma", "fun": 2.25, "difficulty": 2.25, "author": "mad-ade", "desc": "Father Christmas had a problem. He was making up a batch of dolls but could not remember exactly how many of each kind he needed. He knew that he needed 57 in total, that 27 had to have blue eyes, and 29 had to have fair hair. His assistant gnome pointed out that some had to have both features and remembered that 3 dolls were needed having blue eyes and fair hair, but which were not able to say 'Mama'. This prompted the old man to remember that he needed a total of 34 dolls able to say 'Mama', of whom 17 needed to have fair hair. The assistant was going around in circles juggling all this information but couldn't work it out. He pressed for any other bits of information that Father Christmas just might be able to manage, no matter how trivial. The only items he got were: \"Every doll had at least 1 of the features named\"; \"That there was one combination of features not asked for at all\" and \"Several children had asked for all 3 features in the one doll\". That was enough!\n\r\nHow many fair-haired, blue-eyed dolls saying 'Mama' were needed?", "hint": "No hint available.", "answer": "13 dolls were needed", "category": "Math", "date": "07/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFather Christmas had a problem. He was making up a batch of dolls but could not remember exactly how many of each kind he needed. He knew that he needed 57 in total, that 27 had to have blue eyes, and 29 had to have fair hair. His assistant gnome pointed out that some had to have both features and remembered that 3 dolls were needed having blue eyes and fair hair, but which were not able to say 'Mama'. This prompted the old man to remember that he needed a total of 34 dolls able to say 'Mama', of whom 17 needed to have fair hair. The assistant was going around in circles juggling all this information but couldn't work it out. He pressed for any other bits of information that Father Christmas just might be able to manage, no matter how trivial. The only items he got were: \"Every doll had at least 1 of the features named\"; \"That there was one combination of features not asked for at all\" and \"Several children had asked for all 3 features in the one doll\". That was enough!\n\r\nHow many fair-haired, blue-eyed dolls saying 'Mama' were needed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n13 dolls were needed\n<|im_start|>answer\n13 dolls were needed\n<|im_end|>" }, { "id": "#25045", "title": "Brotherly Love", "fun": 2.25, "difficulty": 0.97, "author": "lisha_kc", "desc": "Tim, Ron, and Bob are brothers, and each of their wives (Ute, Linda, Mildred) have birthdays coming up one right after the other. However, the husbands don't know what to get for their own wives, so the brothers decided to get a present for one of their sisters-in-law. The gifts were a bracelet, a rug, and tickets to a ballet. Find out which brother got a gift for whom, what they bought, and the order of the birthdays.\n\r\n1. The order of the birthdays were: Mildred, the person Tim bought something for, and the one who got the tickets.\r\n2. Tim loves his wife Ute, but didn't realize their daughter was going to be in a ballet.\r\n3. Bob's wife, Linda, hates Ute, so Bob didn't buy anything for her.\r\n4. Mildred helped Tim pick out the bracelet he bought after her birthday party.\r\n5. No husband actually purchased a gift for his own wife.", "hint": "No hint available.", "answer": "Mildred's birthday was first and Bob bought her a rug (from her husband Ron).\r\nLinda's birthday was the next day and Tim bought her a bracelet (from her husband Bob).\r\nUte's birthday was last and Ron bought her the ballet tickets (from her husband Tim).", "category": "Logic-Grid", "date": "08/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTim, Ron, and Bob are brothers, and each of their wives (Ute, Linda, Mildred) have birthdays coming up one right after the other. However, the husbands don't know what to get for their own wives, so the brothers decided to get a present for one of their sisters-in-law. The gifts were a bracelet, a rug, and tickets to a ballet. Find out which brother got a gift for whom, what they bought, and the order of the birthdays.\n\r\n1. The order of the birthdays were: Mildred, the person Tim bought something for, and the one who got the tickets.\r\n2. Tim loves his wife Ute, but didn't realize their daughter was going to be in a ballet.\r\n3. Bob's wife, Linda, hates Ute, so Bob didn't buy anything for her.\r\n4. Mildred helped Tim pick out the bracelet he bought after her birthday party.\r\n5. No husband actually purchased a gift for his own wife.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMildred's birthday was first and Bob bought her a rug (from her husband Ron).\r\nLinda's birthday was the next day and Tim bought her a bracelet (from her husband Bob).\r\nUte's birthday was last and Ron bought her the ballet tickets (from her husband Tim).\n<|im_start|>answer\nMildred's birthday was first and Bob bought her a rug (from her husband Ron).\r\nLinda's birthday was the next day and Tim bought her a bracelet (from her husband Bob).\r\nUte's birthday was last and Ron bought her the ballet tickets (from her husband Tim).\n<|im_end|>" }, { "id": "#22444", "title": "Sharing Marbles", "fun": 2.25, "difficulty": 1.91, "author": "tsimkin", "desc": "Henry and Gretchen each collected marbles, and they were discussing sharing their collections. Here is the conversation they had:\n\r\nHenry: \"If I shared with Lizzie, we would each get 10 marbles.\"\n\r\nGretchen: \"If Lizzie shared with Courtney, who has 10 marbles, they would each end up with half as many marbles as I have.\"\n\r\nHenry: \"Now I know how many marbles we will each end up with if we share.\"\n\r\nHow many marbles will they each have?", "hint": "No hint available.", "answer": "15.\n\r\nUsing the variables H, G, L, and C to stand for Henry, Gretchen, Lizzie, and Courtney, we get:\r\n(H + L)/2 = 10, so\r\nH + L = 20\n\r\n(L + C)/2 = G/2, so\r\n(L + 10)/2 = G/2, and\r\nL + 10 = G\n\r\n(H + G)/2 = (H + L + 10)/2 = (H + L)/2 + 5\n\r\nSince we know (H + L)/2 = 10, we get (H + G)/2 = 15.\n\r\nYou can also plug in numbers to make this work. If Henry has 10, Lizzie has 10, Courtney has 10, and Gretchen has 20, all of these answers hold. Even if you change the mix (e.g., H = 5, L = 15, C = 10, G = 25), the answer remains the same.", "category": "Math", "date": "04/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHenry and Gretchen each collected marbles, and they were discussing sharing their collections. Here is the conversation they had:\n\r\nHenry: \"If I shared with Lizzie, we would each get 10 marbles.\"\n\r\nGretchen: \"If Lizzie shared with Courtney, who has 10 marbles, they would each end up with half as many marbles as I have.\"\n\r\nHenry: \"Now I know how many marbles we will each end up with if we share.\"\n\r\nHow many marbles will they each have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15.\n\r\nUsing the variables H, G, L, and C to stand for Henry, Gretchen, Lizzie, and Courtney, we get:\r\n(H + L)/2 = 10, so\r\nH + L = 20\n\r\n(L + C)/2 = G/2, so\r\n(L + 10)/2 = G/2, and\r\nL + 10 = G\n\r\n(H + G)/2 = (H + L + 10)/2 = (H + L)/2 + 5\n\r\nSince we know (H + L)/2 = 10, we get (H + G)/2 = 15.\n\r\nYou can also plug in numbers to make this work. If Henry has 10, Lizzie has 10, Courtney has 10, and Gretchen has 20, all of these answers hold. Even if you change the mix (e.g., H = 5, L = 15, C = 10, G = 25), the answer remains the same.\n<|im_start|>answer\n15.\n\r\nUsing the variables H, G, L, and C to stand for Henry, Gretchen, Lizzie, and Courtney, we get:\r\n(H + L)/2 = 10, so\r\nH + L = 20\n\r\n(L + C)/2 = G/2, so\r\n(L + 10)/2 = G/2, and\r\nL + 10 = G\n\r\n(H + G)/2 = (H + L + 10)/2 = (H + L)/2 + 5\n\r\nSince we know (H + L)/2 = 10, we get (H + G)/2 = 15.\n\r\nYou can also plug in numbers to make this work. If Henry has 10, Lizzie has 10, Courtney has 10, and Gretchen has 20, all of these answers hold. Even if you change the mix (e.g., H = 5, L = 15, C = 10, G = 25), the answer remains the same.\n<|im_end|>" }, { "id": "#16129", "title": "Sale", "fun": 2.25, "difficulty": 1.36, "author": "AXTON", "desc": "Your local shop is having a sale where you take 50% off the marked price of everything, and then a further 25% off that.\n\r\nWhat Percentage do you save?", "hint": "No hint available.", "answer": "62.5% \n\r\nFor example: \r\n$100 - (50% of $100) = $50 \r\n$50 - (25% of $50) = $37.50 \r\n$100 - $37.50 = $62.50", "category": "Math", "date": "01/10/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour local shop is having a sale where you take 50% off the marked price of everything, and then a further 25% off that.\n\r\nWhat Percentage do you save?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n62.5% \n\r\nFor example: \r\n$100 - (50% of $100) = $50 \r\n$50 - (25% of $50) = $37.50 \r\n$100 - $37.50 = $62.50\n<|im_start|>answer\n62.5% \n\r\nFor example: \r\n$100 - (50% of $100) = $50 \r\n$50 - (25% of $50) = $37.50 \r\n$100 - $37.50 = $62.50\n<|im_end|>" }, { "id": "#6831", "title": "Clock Ticks", "fun": 2.25, "difficulty": 2.64, "author": "naveen_the_great", "desc": "A man had a clock with an hour hand and a minute hand of the same length and indistinguishable. If the clock was set going at noon, what would be the first time that it would be impossible, by reason of the similarity of the hands, to be sure of the correct time? \n\r\nIn grappling with this little problem, you may assume that it is possible to indicate fractions of a second. On this assumption, an exact answer can be given.", "hint": "No hint available.", "answer": "The first time would be 5 and 5\\143 minutes past 12, which might also indicate 60\\143 minutes past 1. Expressed slightly less accurately, 5 minutes past 12 and about half a minute past 1.", "category": "Math", "date": "08/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man had a clock with an hour hand and a minute hand of the same length and indistinguishable. If the clock was set going at noon, what would be the first time that it would be impossible, by reason of the similarity of the hands, to be sure of the correct time? \n\r\nIn grappling with this little problem, you may assume that it is possible to indicate fractions of a second. On this assumption, an exact answer can be given.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first time would be 5 and 5\\143 minutes past 12, which might also indicate 60\\143 minutes past 1. Expressed slightly less accurately, 5 minutes past 12 and about half a minute past 1.\n<|im_start|>answer\nThe first time would be 5 and 5\\143 minutes past 12, which might also indicate 60\\143 minutes past 1. Expressed slightly less accurately, 5 minutes past 12 and about half a minute past 1.\n<|im_end|>" }, { "id": "#25030", "title": "Selling Houses", "fun": 2.25, "difficulty": 0.7000000000000001, "author": "jajajaja", "desc": "Jennifer, Carol and Tim all own properties in rather exclusive areas of town, and have recently had them valued.\n\r\nCarol lives in Sunflower Rise, but her property is not worth £75 000.\n\r\nThe property in Joy Row worked out as the cheapest despite it being a lovely road.\n\r\nTim lives in a terrace house, although there are no terraced houses along Crispin Way.\n\r\nJennifer's property is not a Bungalow.\n\r\nCan you work out from these clues which person lives where, in which property and how much their house was valued?", "hint": "rs=rise", "answer": "Jennifer, Flat, Crispin Way, £75 000\r\nCarol, Bungalow, Sunflower Rise, £100 000\r\nTim, Terrace, Joy Row, £40 000", "category": "Logic-Grid", "date": "08/03/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJennifer, Carol and Tim all own properties in rather exclusive areas of town, and have recently had them valued.\n\r\nCarol lives in Sunflower Rise, but her property is not worth £75 000.\n\r\nThe property in Joy Row worked out as the cheapest despite it being a lovely road.\n\r\nTim lives in a terrace house, although there are no terraced houses along Crispin Way.\n\r\nJennifer's property is not a Bungalow.\n\r\nCan you work out from these clues which person lives where, in which property and how much their house was valued?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJennifer, Flat, Crispin Way, £75 000\r\nCarol, Bungalow, Sunflower Rise, £100 000\r\nTim, Terrace, Joy Row, £40 000\n<|im_start|>answer\nJennifer, Flat, Crispin Way, £75 000\r\nCarol, Bungalow, Sunflower Rise, £100 000\r\nTim, Terrace, Joy Row, £40 000\n<|im_end|>" }, { "id": "#1288", "title": "21 Spokes", "fun": 2.25, "difficulty": 1.1, "author": "beans", "desc": "An old fashioned bike wheel has 21 spokes, how many spaces are there in between them?", "hint": "No hint available.", "answer": "21, most people will think one more or less", "category": "Math", "date": "11/04/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn old fashioned bike wheel has 21 spokes, how many spaces are there in between them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21, most people will think one more or less\n<|im_start|>answer\n21, most people will think one more or less\n<|im_end|>" }, { "id": "#18802", "title": "SUMthing to Think About", "fun": 2.25, "difficulty": 2.03, "author": "woteva", "desc": "Placing any mathematical symbols before or after each number, make a sum equal to 9.99\n\r\n3 1 3 3 3", "hint": "No hint available.", "answer": "3 x 1 x 3 . 3 3 =9.99", "category": "Math", "date": "09/09/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlacing any mathematical symbols before or after each number, make a sum equal to 9.99\n\r\n3 1 3 3 3\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 x 1 x 3 . 3 3 =9.99\n<|im_start|>answer\n3 x 1 x 3 . 3 3 =9.99\n<|im_end|>" }, { "id": "#11499", "title": "1316", "fun": 2.25, "difficulty": 1.61, "author": "smileysteve", "desc": "Can you make the number 1316 using only the numbers 4 and 7 twice each? You may only use the sign ( ) in the problem.", "hint": "Putting something in parentheses is the same thing as multiplying it. Like 4(3)=12, if you didn't already know that.", "answer": "4(7)47=1316\n\r\n4 x 7 = 28\r\n28 x 47 = 1316", "category": "Math", "date": "03/31/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you make the number 1316 using only the numbers 4 and 7 twice each? You may only use the sign ( ) in the problem.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4(7)47=1316\n\r\n4 x 7 = 28\r\n28 x 47 = 1316\n<|im_start|>answer\n4(7)47=1316\n\r\n4 x 7 = 28\r\n28 x 47 = 1316\n<|im_end|>" }, { "id": "#15830", "title": "Patio Plans", "fun": 2.25, "difficulty": 2.7600000000000002, "author": "beanie89", "desc": "Jill is helping plan her family's new patio. It will be an irregular hexagon. They will use 1-foot-square stone tiles. Here are her notes. \n\r\n1. The perimeter of the deck is outlined by ABCDEF. \r\n2. Line AB is against the house. It is 16 feet long. \r\n3. AF is perpendicular to AB. \r\n4.AF and BC are parallel. \r\n5.BC and AF are each 6 feet long. \r\n6.Points F and C are connected by FC; FC is parallel to AB. \r\n7.Points G and H are on FC. \r\n8.FG and HC are each 4 feet long. \r\n9. ED is 8 feet long. It is parallel to AB. \r\n10. DH is perpendicular to HC. It is 4 feet long. \r\n11. EG is perpendicular to FG. It is 4 feet long. \r\n12. Angle BCD is 135 degrees. \r\n13. Angle AFE is 135 degrees. \n\r\nIf they order 6 more tiles than they would ideally need (to allow for breakage), how many patio tiles should they order? \n\r\nAssume that tiles can be cut cleanly so that any leftover pieces can be used for other parts of the deck.", "hint": "No hint available.", "answer": "The area of the deck is 144 square feet. They will need 150 tiles. \n\r\nExplanation \n\r\nThe area of ABCF is 96 square feet. \r\nThe area of DEGH is 32 square feet. \r\nThe area of CDH and EFG combined is 16 square feet. You will be able to complete these sections with 8 tiles each after cutting four of the tiles in half diagonally. \r\nThe total area is 144 square feet. Allowing 6 extra tiles for breakage brings the order to 150 tiles.", "category": "Math", "date": "12/17/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJill is helping plan her family's new patio. It will be an irregular hexagon. They will use 1-foot-square stone tiles. Here are her notes. \n\r\n1. The perimeter of the deck is outlined by ABCDEF. \r\n2. Line AB is against the house. It is 16 feet long. \r\n3. AF is perpendicular to AB. \r\n4.AF and BC are parallel. \r\n5.BC and AF are each 6 feet long. \r\n6.Points F and C are connected by FC; FC is parallel to AB. \r\n7.Points G and H are on FC. \r\n8.FG and HC are each 4 feet long. \r\n9. ED is 8 feet long. It is parallel to AB. \r\n10. DH is perpendicular to HC. It is 4 feet long. \r\n11. EG is perpendicular to FG. It is 4 feet long. \r\n12. Angle BCD is 135 degrees. \r\n13. Angle AFE is 135 degrees. \n\r\nIf they order 6 more tiles than they would ideally need (to allow for breakage), how many patio tiles should they order? \n\r\nAssume that tiles can be cut cleanly so that any leftover pieces can be used for other parts of the deck.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe area of the deck is 144 square feet. They will need 150 tiles. \n\r\nExplanation \n\r\nThe area of ABCF is 96 square feet. \r\nThe area of DEGH is 32 square feet. \r\nThe area of CDH and EFG combined is 16 square feet. You will be able to complete these sections with 8 tiles each after cutting four of the tiles in half diagonally. \r\nThe total area is 144 square feet. Allowing 6 extra tiles for breakage brings the order to 150 tiles.\n<|im_start|>answer\nThe area of the deck is 144 square feet. They will need 150 tiles. \n\r\nExplanation \n\r\nThe area of ABCF is 96 square feet. \r\nThe area of DEGH is 32 square feet. \r\nThe area of CDH and EFG combined is 16 square feet. You will be able to complete these sections with 8 tiles each after cutting four of the tiles in half diagonally. \r\nThe total area is 144 square feet. Allowing 6 extra tiles for breakage brings the order to 150 tiles.\n<|im_end|>" }, { "id": "#8846", "title": "Crossing a Bridge", "fun": 2.25, "difficulty": 2.79, "author": "lesternoronha1", "desc": "Three people (A, B, and C) need to cross a bridge. A can cross the bridge in 10 minutes, B can cross in 5 minutes, and C can cross in 2 minutes. There is also a bicycle available and any person can cross the bridge in 1 minute with the bicycle. What is the shortest time that all men can get across the bridge? Each man travels at their own constant rate.", "hint": "The bicycle may be left at any point along the bridge and may be ridden in either direction. Every man should finish at the same time.", "answer": "A's speed is 1/10 (in bridges per minute), B's speed is 1/5, C's speed is 1/2, and the bicycle's speed is 1. \r\nThe fastest way to get everyone across is for B and C to start out on foot and A to start out with the bicycle. At a point y, A will get off the bicycle and walk the rest of the way. Eventually C will get to the bicycle abandoned by A, then ride back to a point x, leaving the bicycle there, then turning around and walk until he reaches the end. Person B will walk until he reaches the bicycle left by C and then ride the rest of the way. \r\nBelow are the times that each will take to cross, in terms of x and y: \r\nA: 1*y + 10*(1-y) \r\nB: 5*x + 1*(1-x) \r\nC: 2*y + (y-x) + 2*(1-x) \r\nNext equate these equations: 10 - 9y = -3x + 3y + 2 = 4x + 1. \r\nTo solve set up two linear equations: \r\n10 - 9y = -3x + 3y + 2 -> 3x - 12y = -8 \r\n10 - 9y = 4x + 1 -> 4x + 9y = 9 \r\nThen solve for x and y: \r\nx = 12/25, y=59/75. \r\nGiven these points it will take each person 73/25 = 2.92 minutes to cross. Since they all start and end at the same time, the total duration to cross the bridge is also 2.92 minutes.", "category": "Math", "date": "12/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people (A, B, and C) need to cross a bridge. A can cross the bridge in 10 minutes, B can cross in 5 minutes, and C can cross in 2 minutes. There is also a bicycle available and any person can cross the bridge in 1 minute with the bicycle. What is the shortest time that all men can get across the bridge? Each man travels at their own constant rate.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA's speed is 1/10 (in bridges per minute), B's speed is 1/5, C's speed is 1/2, and the bicycle's speed is 1. \r\nThe fastest way to get everyone across is for B and C to start out on foot and A to start out with the bicycle. At a point y, A will get off the bicycle and walk the rest of the way. Eventually C will get to the bicycle abandoned by A, then ride back to a point x, leaving the bicycle there, then turning around and walk until he reaches the end. Person B will walk until he reaches the bicycle left by C and then ride the rest of the way. \r\nBelow are the times that each will take to cross, in terms of x and y: \r\nA: 1*y + 10*(1-y) \r\nB: 5*x + 1*(1-x) \r\nC: 2*y + (y-x) + 2*(1-x) \r\nNext equate these equations: 10 - 9y = -3x + 3y + 2 = 4x + 1. \r\nTo solve set up two linear equations: \r\n10 - 9y = -3x + 3y + 2 -> 3x - 12y = -8 \r\n10 - 9y = 4x + 1 -> 4x + 9y = 9 \r\nThen solve for x and y: \r\nx = 12/25, y=59/75. \r\nGiven these points it will take each person 73/25 = 2.92 minutes to cross. Since they all start and end at the same time, the total duration to cross the bridge is also 2.92 minutes.\n<|im_start|>answer\nA's speed is 1/10 (in bridges per minute), B's speed is 1/5, C's speed is 1/2, and the bicycle's speed is 1. \r\nThe fastest way to get everyone across is for B and C to start out on foot and A to start out with the bicycle. At a point y, A will get off the bicycle and walk the rest of the way. Eventually C will get to the bicycle abandoned by A, then ride back to a point x, leaving the bicycle there, then turning around and walk until he reaches the end. Person B will walk until he reaches the bicycle left by C and then ride the rest of the way. \r\nBelow are the times that each will take to cross, in terms of x and y: \r\nA: 1*y + 10*(1-y) \r\nB: 5*x + 1*(1-x) \r\nC: 2*y + (y-x) + 2*(1-x) \r\nNext equate these equations: 10 - 9y = -3x + 3y + 2 = 4x + 1. \r\nTo solve set up two linear equations: \r\n10 - 9y = -3x + 3y + 2 -> 3x - 12y = -8 \r\n10 - 9y = 4x + 1 -> 4x + 9y = 9 \r\nThen solve for x and y: \r\nx = 12/25, y=59/75. \r\nGiven these points it will take each person 73/25 = 2.92 minutes to cross. Since they all start and end at the same time, the total duration to cross the bridge is also 2.92 minutes.\n<|im_end|>" }, { "id": "#42376", "title": "Hickory Dickory Clock", "fun": 2.25, "difficulty": 2.0, "author": "Abstain", "desc": "Hickory, dickory, dock, a mouse has messed up the clock. Something, at least, has messed up the old alarm clock in Randy's bedroom. Sometimes it runs backward, with the hands moving counter-clockwise.\n\r\nWhen Randy looked at the clock yesterday morning, it showed a quarter to 10. It then ran backward for 14 hours, 6 minutes, and then forward for 5 hours, 53 minutes, and finally backward again for 10 hours, 41 minutes.\n\r\nRandy's clock is a standard 12-hour analog clock.\n\r\nWhat time will the clock now show?", "hint": "Remember that in adding and subtracting minutes, there are exactly 60 minutes in an hour. Randy's clock shows only 12 hours.", "answer": "The clock will show 2:51, or 51 minutes after 2.\n\r\nIn considering time, we have to think in units of 12 (hours) and 60 (minutes).\n\r\nThe clock showed 45 minutes after 9 when Randy first checked it.\n\r\nAfter the first 12 hours of the 14 hours and 6 minutes of running backward, the clock was back at 45 minutes after 9. Then it ran back an additional 2 hours and 6 minutes to 39 minutes after 7.\n\r\nAfter running forward for 5 hours and 53 minutes, the clock showed 32 minutes after 1.\n\r\nAfter going backward again for 1 hour, the clock showed 32 minutes after 12. Then, after it ran back the remaining 9 hours and 41 minutes, it showed 51 minutes after 2.", "category": "Math", "date": "06/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHickory, dickory, dock, a mouse has messed up the clock. Something, at least, has messed up the old alarm clock in Randy's bedroom. Sometimes it runs backward, with the hands moving counter-clockwise.\n\r\nWhen Randy looked at the clock yesterday morning, it showed a quarter to 10. It then ran backward for 14 hours, 6 minutes, and then forward for 5 hours, 53 minutes, and finally backward again for 10 hours, 41 minutes.\n\r\nRandy's clock is a standard 12-hour analog clock.\n\r\nWhat time will the clock now show?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe clock will show 2:51, or 51 minutes after 2.\n\r\nIn considering time, we have to think in units of 12 (hours) and 60 (minutes).\n\r\nThe clock showed 45 minutes after 9 when Randy first checked it.\n\r\nAfter the first 12 hours of the 14 hours and 6 minutes of running backward, the clock was back at 45 minutes after 9. Then it ran back an additional 2 hours and 6 minutes to 39 minutes after 7.\n\r\nAfter running forward for 5 hours and 53 minutes, the clock showed 32 minutes after 1.\n\r\nAfter going backward again for 1 hour, the clock showed 32 minutes after 12. Then, after it ran back the remaining 9 hours and 41 minutes, it showed 51 minutes after 2.\n<|im_start|>answer\nThe clock will show 2:51, or 51 minutes after 2.\n\r\nIn considering time, we have to think in units of 12 (hours) and 60 (minutes).\n\r\nThe clock showed 45 minutes after 9 when Randy first checked it.\n\r\nAfter the first 12 hours of the 14 hours and 6 minutes of running backward, the clock was back at 45 minutes after 9. Then it ran back an additional 2 hours and 6 minutes to 39 minutes after 7.\n\r\nAfter running forward for 5 hours and 53 minutes, the clock showed 32 minutes after 1.\n\r\nAfter going backward again for 1 hour, the clock showed 32 minutes after 12. Then, after it ran back the remaining 9 hours and 41 minutes, it showed 51 minutes after 2.\n<|im_end|>" }, { "id": "#5265", "title": "Math's Date", "fun": 2.25, "difficulty": 1.36, "author": "mad-ade", "desc": "The 9th November 1999 had an unusual feature.\r\nIf it was written in the form 9/11/99 then it could be seen that 9 x 11 = 99\r\nOr, in words: day x month = year (Last two digits)\r\nWhat was the first date in this new century that this did happen?", "hint": "No hint available.", "answer": "1/1/01", "category": "Math", "date": "07/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 9th November 1999 had an unusual feature.\r\nIf it was written in the form 9/11/99 then it could be seen that 9 x 11 = 99\r\nOr, in words: day x month = year (Last two digits)\r\nWhat was the first date in this new century that this did happen?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1/1/01\n<|im_start|>answer\n1/1/01\n<|im_end|>" }, { "id": "#4762", "title": "Finders Keepers", "fun": 2.25, "difficulty": 1.55, "author": "mad-ade", "desc": "Mad Ade found £4. Putting that £4 together with the money he had before his good luck, he now had 5 times the amount of money he would have had if he had lost £4. How much money did Mad Ade have before he found the £4?", "hint": "No hint available.", "answer": "Before Mad Ade found the £4, he had £6. If he had lost £4 from the £6, he would have had only £2 left. The £4 Mad Ade found plus the £6 he already had means he now has £10, which is 5 times the £2 he would have had if Mad Ade had lost £4 instead of finding £4.", "category": "Math", "date": "06/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade found £4. Putting that £4 together with the money he had before his good luck, he now had 5 times the amount of money he would have had if he had lost £4. How much money did Mad Ade have before he found the £4?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBefore Mad Ade found the £4, he had £6. If he had lost £4 from the £6, he would have had only £2 left. The £4 Mad Ade found plus the £6 he already had means he now has £10, which is 5 times the £2 he would have had if Mad Ade had lost £4 instead of finding £4.\n<|im_start|>answer\nBefore Mad Ade found the £4, he had £6. If he had lost £4 from the £6, he would have had only £2 left. The £4 Mad Ade found plus the £6 he already had means he now has £10, which is 5 times the £2 he would have had if Mad Ade had lost £4 instead of finding £4.\n<|im_end|>" }, { "id": "#4385", "title": "noon, moon, soon", "fun": 2.25, "difficulty": 2.35, "author": "mad-ade", "desc": "Find the values of each of the alphabets.\n\r\nN O O N\r\nS O O N\r\nM O O N+\r\n----------\r\nJ U N E\n\r\nbear in mind that no row begins or ends with a zero and if X=1 then all x's equal 1", "hint": "No hint available.", "answer": "2 4 4 2\r\n1 4 4 2\r\n5 4 4 2+\r\n----------\r\n9 3 2 6", "category": "Math", "date": "05/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the values of each of the alphabets.\n\r\nN O O N\r\nS O O N\r\nM O O N+\r\n----------\r\nJ U N E\n\r\nbear in mind that no row begins or ends with a zero and if X=1 then all x's equal 1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 4 4 2\r\n1 4 4 2\r\n5 4 4 2+\r\n----------\r\n9 3 2 6\n<|im_start|>answer\n2 4 4 2\r\n1 4 4 2\r\n5 4 4 2+\r\n----------\r\n9 3 2 6\n<|im_end|>" }, { "id": "#18851", "title": "Triathlon 2", "fun": 2.25, "difficulty": 2.5, "author": "cnmne", "desc": "The last contestant has just completed the cycling leg of the triathlon. The 15 clues that follow are with respect to this point in the race. From the clues you must determine: the color of shorts each runner is wearing, the positions at the end of the cycling leg, and the final standings.\n\r\nContestants in the race: Alvin, Brian, Chuck, David, Ethan, Frank\r\nColors of their shorts: red, orange, yellow, green, blue, violet\n\r\n1) Brian moved up two places, now just behind the runner in the red shorts.\r\n2) The runner in the yellow shorts fell down, lost an even number of positions, and was now in last place.\r\n3) Frank moved ahead of the runner who wore the blue shorts.\r\n4) The runner in the orange shorts took over the lead.\r\n5) Ethan and the runner in the green shorts switched places.\r\n6) David moved ahead of Brian, who was not wearing the blue shorts.\r\n7) Chuck stubbed his toe, lost one position, and was now just ahead of Alvin.\r\n8) Ethan and Brian, neither one who wore the violet shorts, switched places.\r\n9) Alvin moved ahead of the runners who wore the green and orange shorts.\r\n10) David dropped behind the runners who wore the blue and violet shorts.\r\n11) The runner in the yellow shorts moved ahead of David.\r\n12) Chuck moved ahead of the runner who wore the orange shorts.\r\n13) With a burst of speed, David moved ahead of Ethan, Frank, and the runner in the yellow shorts.\r\n14) Ethan moved ahead of the runner who wore the red shorts.\r\n15) Out of breath, the runner wearing the green shorts fell behind Brian, who now trailed the runner wearing the yellow shorts. No further position changes occur. The race ends.", "hint": "No hint available.", "answer": "Set up a grid of names versus colors. From the clues, mark off combinations that can not exist. From this, it can be found that Brian wears orange. This leaves Ethan wearing blue. From Clue 7 and Clue 9, Chuck can only be orange or green. From Clue 12, Chuck can not be orange, therefore he must be green. This leaves David wearing red, Frank wearing violet, and Alvin wearing yellow. This establishes: Alvin = yellow, Brian = orange, Chuck = green, David = red, Ethan = blue, Frank = violet\n\r\nTo determine the final results, work backward, substituting names for colors. From Clue 15, Alvin beats Brian beats Chuck. From Clue 14, Ethan beats David. From Clue 13, David beats Frank beats Alvin. This establishes the final results as: Ethan, David, Frank, Alvin, Brian, Chuck.\n\r\nNow work backward to determine the cycling standings, substituting names for colors. You need to determine what the standings would have had to have been prior to each clue. Before Clue 15: Ethan, David, Frank, Alvin, Chuck, Brian. Before Clue 14: David, Ethan, Frank, Alvin, Chuck, Brian. Before Clue 13: Ethan, Frank, Alvin, David, Chuck, Brian. Before Clue 12: Ethan, Frank, Alvin, David, Brian, Chuck. Before Clue 11: Ethan, Frank, David, Alvin, Brian, Chuck. Before Clue 10: David, Ethan, Frank, Alvin, Brian, Chuck. Before Clue 9: David, Ethan, Frank, Brian, Chuck, Alvin. Before Clue 8: David, Brian, Frank, Ethan, Chuck, Alvin. Before Clue 7: David, Brian, Frank, Chuck, Ethan, Alvin. Before Clue 6: Brian, David, Frank, Chuck, Ethan, Alvin. Before Clue 5: Brian, David, Frank, Ethan, Chuck, Alvin. Before Clue 4: David, Frank, Ethan, Chuck, Alvin (Brian unknown). Before Clue 3: David, Ethan, Frank, Chuck, Alvin (Brian unknown). Before Clue 2: David, Ethan, Frank, Chuck (Alvin and Brian unknown). Before Clue 1 (which establishes the standings after the cycling leg): David, Ethan, Alvin, Brian, Frank, Chuck.", "category": "Logic", "date": "09/15/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe last contestant has just completed the cycling leg of the triathlon. The 15 clues that follow are with respect to this point in the race. From the clues you must determine: the color of shorts each runner is wearing, the positions at the end of the cycling leg, and the final standings.\n\r\nContestants in the race: Alvin, Brian, Chuck, David, Ethan, Frank\r\nColors of their shorts: red, orange, yellow, green, blue, violet\n\r\n1) Brian moved up two places, now just behind the runner in the red shorts.\r\n2) The runner in the yellow shorts fell down, lost an even number of positions, and was now in last place.\r\n3) Frank moved ahead of the runner who wore the blue shorts.\r\n4) The runner in the orange shorts took over the lead.\r\n5) Ethan and the runner in the green shorts switched places.\r\n6) David moved ahead of Brian, who was not wearing the blue shorts.\r\n7) Chuck stubbed his toe, lost one position, and was now just ahead of Alvin.\r\n8) Ethan and Brian, neither one who wore the violet shorts, switched places.\r\n9) Alvin moved ahead of the runners who wore the green and orange shorts.\r\n10) David dropped behind the runners who wore the blue and violet shorts.\r\n11) The runner in the yellow shorts moved ahead of David.\r\n12) Chuck moved ahead of the runner who wore the orange shorts.\r\n13) With a burst of speed, David moved ahead of Ethan, Frank, and the runner in the yellow shorts.\r\n14) Ethan moved ahead of the runner who wore the red shorts.\r\n15) Out of breath, the runner wearing the green shorts fell behind Brian, who now trailed the runner wearing the yellow shorts. No further position changes occur. The race ends.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSet up a grid of names versus colors. From the clues, mark off combinations that can not exist. From this, it can be found that Brian wears orange. This leaves Ethan wearing blue. From Clue 7 and Clue 9, Chuck can only be orange or green. From Clue 12, Chuck can not be orange, therefore he must be green. This leaves David wearing red, Frank wearing violet, and Alvin wearing yellow. This establishes: Alvin = yellow, Brian = orange, Chuck = green, David = red, Ethan = blue, Frank = violet\n\r\nTo determine the final results, work backward, substituting names for colors. From Clue 15, Alvin beats Brian beats Chuck. From Clue 14, Ethan beats David. From Clue 13, David beats Frank beats Alvin. This establishes the final results as: Ethan, David, Frank, Alvin, Brian, Chuck.\n\r\nNow work backward to determine the cycling standings, substituting names for colors. You need to determine what the standings would have had to have been prior to each clue. Before Clue 15: Ethan, David, Frank, Alvin, Chuck, Brian. Before Clue 14: David, Ethan, Frank, Alvin, Chuck, Brian. Before Clue 13: Ethan, Frank, Alvin, David, Chuck, Brian. Before Clue 12: Ethan, Frank, Alvin, David, Brian, Chuck. Before Clue 11: Ethan, Frank, David, Alvin, Brian, Chuck. Before Clue 10: David, Ethan, Frank, Alvin, Brian, Chuck. Before Clue 9: David, Ethan, Frank, Brian, Chuck, Alvin. Before Clue 8: David, Brian, Frank, Ethan, Chuck, Alvin. Before Clue 7: David, Brian, Frank, Chuck, Ethan, Alvin. Before Clue 6: Brian, David, Frank, Chuck, Ethan, Alvin. Before Clue 5: Brian, David, Frank, Ethan, Chuck, Alvin. Before Clue 4: David, Frank, Ethan, Chuck, Alvin (Brian unknown). Before Clue 3: David, Ethan, Frank, Chuck, Alvin (Brian unknown). Before Clue 2: David, Ethan, Frank, Chuck (Alvin and Brian unknown). Before Clue 1 (which establishes the standings after the cycling leg): David, Ethan, Alvin, Brian, Frank, Chuck.\n<|im_start|>answer\nSet up a grid of names versus colors. From the clues, mark off combinations that can not exist. From this, it can be found that Brian wears orange. This leaves Ethan wearing blue. From Clue 7 and Clue 9, Chuck can only be orange or green. From Clue 12, Chuck can not be orange, therefore he must be green. This leaves David wearing red, Frank wearing violet, and Alvin wearing yellow. This establishes: Alvin = yellow, Brian = orange, Chuck = green, David = red, Ethan = blue, Frank = violet\n\r\nTo determine the final results, work backward, substituting names for colors. From Clue 15, Alvin beats Brian beats Chuck. From Clue 14, Ethan beats David. From Clue 13, David beats Frank beats Alvin. This establishes the final results as: Ethan, David, Frank, Alvin, Brian, Chuck.\n\r\nNow work backward to determine the cycling standings, substituting names for colors. You need to determine what the standings would have had to have been prior to each clue. Before Clue 15: Ethan, David, Frank, Alvin, Chuck, Brian. Before Clue 14: David, Ethan, Frank, Alvin, Chuck, Brian. Before Clue 13: Ethan, Frank, Alvin, David, Chuck, Brian. Before Clue 12: Ethan, Frank, Alvin, David, Brian, Chuck. Before Clue 11: Ethan, Frank, David, Alvin, Brian, Chuck. Before Clue 10: David, Ethan, Frank, Alvin, Brian, Chuck. Before Clue 9: David, Ethan, Frank, Brian, Chuck, Alvin. Before Clue 8: David, Brian, Frank, Ethan, Chuck, Alvin. Before Clue 7: David, Brian, Frank, Chuck, Ethan, Alvin. Before Clue 6: Brian, David, Frank, Chuck, Ethan, Alvin. Before Clue 5: Brian, David, Frank, Ethan, Chuck, Alvin. Before Clue 4: David, Frank, Ethan, Chuck, Alvin (Brian unknown). Before Clue 3: David, Ethan, Frank, Chuck, Alvin (Brian unknown). Before Clue 2: David, Ethan, Frank, Chuck (Alvin and Brian unknown). Before Clue 1 (which establishes the standings after the cycling leg): David, Ethan, Alvin, Brian, Frank, Chuck.\n<|im_end|>" }, { "id": "#959", "title": "Between the Trains", "fun": 2.24, "difficulty": 1.92, "author": "Michelle", "desc": "Two trains are on a head on collision course. The trains are currently 65 miles apart. The north bound train is traveling at 55 miles per hour and the south bound train is traveling at 80 miles per hour. What is the distance between the trains two minutes before they collide?", "hint": "No hint available.", "answer": "If the trains are moving toward each other we combine their speeds to give us their speed basis. So: 55+80=135mph. Divide this speed by 60 minutes to give the speed they are traveling each minute=2.25 miles/minute. Therefore: 2 minutes before impact they are 4.5 miles apart.", "category": "Math", "date": "10/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo trains are on a head on collision course. The trains are currently 65 miles apart. The north bound train is traveling at 55 miles per hour and the south bound train is traveling at 80 miles per hour. What is the distance between the trains two minutes before they collide?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the trains are moving toward each other we combine their speeds to give us their speed basis. So: 55+80=135mph. Divide this speed by 60 minutes to give the speed they are traveling each minute=2.25 miles/minute. Therefore: 2 minutes before impact they are 4.5 miles apart.\n<|im_start|>answer\nIf the trains are moving toward each other we combine their speeds to give us their speed basis. So: 55+80=135mph. Divide this speed by 60 minutes to give the speed they are traveling each minute=2.25 miles/minute. Therefore: 2 minutes before impact they are 4.5 miles apart.\n<|im_end|>" }, { "id": "#8596", "title": "Madadian Cricket", "fun": 2.24, "difficulty": 2.57, "author": "mad-ade", "desc": "Smelly O'Riley, Drooling David and Gangly Gordon played in a Cricket match between Madadia and England. \n\r\nNone of them scored more than 99 runs. \r\nIf you add the digits of the runs scored by Smelly to his own score, you will get the runs scored by David. \r\nIf you reverse the digits of the runs scored by David, you will get the runs scored by Gangly. \r\nThe total runs scored by them is 240.\r\nCan you figure out their individual scores?", "hint": "No hint available.", "answer": "Smelly, David and Gangly scored 75, 87 and 78 respectively. \n\r\nSmelly's score must be less than 86, otherwise David's score would be more than 99. Also, he must have scored at least 42 - in case David and Gangly scored 99 each. \n\r\nAlso, as none of them scored more than 99 and the total runs scored by them is 240; their individual scores must be around 80.", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSmelly O'Riley, Drooling David and Gangly Gordon played in a Cricket match between Madadia and England. \n\r\nNone of them scored more than 99 runs. \r\nIf you add the digits of the runs scored by Smelly to his own score, you will get the runs scored by David. \r\nIf you reverse the digits of the runs scored by David, you will get the runs scored by Gangly. \r\nThe total runs scored by them is 240.\r\nCan you figure out their individual scores?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSmelly, David and Gangly scored 75, 87 and 78 respectively. \n\r\nSmelly's score must be less than 86, otherwise David's score would be more than 99. Also, he must have scored at least 42 - in case David and Gangly scored 99 each. \n\r\nAlso, as none of them scored more than 99 and the total runs scored by them is 240; their individual scores must be around 80.\n<|im_start|>answer\nSmelly, David and Gangly scored 75, 87 and 78 respectively. \n\r\nSmelly's score must be less than 86, otherwise David's score would be more than 99. Also, he must have scored at least 42 - in case David and Gangly scored 99 each. \n\r\nAlso, as none of them scored more than 99 and the total runs scored by them is 240; their individual scores must be around 80.\n<|im_end|>" }, { "id": "#8867", "title": "The Three Santas", "fun": 2.24, "difficulty": 2.16, "author": "the_smart_one", "desc": "Storburty children become quite confused when, in the month of December, they see three Father Christmases (or is it Fathers Christmas?) heading for the public bar of the Horn of Plenty at lunchtime - but, of course, they're just three retired gentlemen who stand in for the real Santa in local stores in the festive season. From the clues given below, can you work out each Santa's full name, and the name and address of the store he works for? \n\r\nThe first names are Alf, Fred, and Ted. The surnames are Frost, Snow, and Winter. The names of the stores are Letten's, Nadine's, and Thurlow's. The addresses are King St, Market Hill, and North St.\n\r\n1. Fred is the Santa at Thurlow's, where he worked on 'goods in' before his retirement. \r\n2. Nardine's store is on the Market Hill, in the shadow of the town's Christmas tree. \r\n3. Mr. Winter, who doesn't play Santa for Letten's isn't employed by the shop in King Street. \r\n4. Ted, who works for the department store in North Street, isn't surnamed Snow.", "hint": "No hint available.", "answer": "Fred works for Thurlow's (clue 1), and Nardine's is in Market Hill (clue 2), so Ted's employers in North Street (clue 4) must be Letten's. By elimination, Fred must work in King Street and Alf must work for Nardine's. Winter can't be Fred or Ted (clue 3), so it must be Frost, and Fred must be Snow.\r\nIN SUMMARY:\r\nAlf Winter-Nadine's-Market Hill\r\nFred Snow-Thurlow's-King Street\r\nTed Frost-Letten's-North Street", "category": "Logic", "date": "12/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStorburty children become quite confused when, in the month of December, they see three Father Christmases (or is it Fathers Christmas?) heading for the public bar of the Horn of Plenty at lunchtime - but, of course, they're just three retired gentlemen who stand in for the real Santa in local stores in the festive season. From the clues given below, can you work out each Santa's full name, and the name and address of the store he works for? \n\r\nThe first names are Alf, Fred, and Ted. The surnames are Frost, Snow, and Winter. The names of the stores are Letten's, Nadine's, and Thurlow's. The addresses are King St, Market Hill, and North St.\n\r\n1. Fred is the Santa at Thurlow's, where he worked on 'goods in' before his retirement. \r\n2. Nardine's store is on the Market Hill, in the shadow of the town's Christmas tree. \r\n3. Mr. Winter, who doesn't play Santa for Letten's isn't employed by the shop in King Street. \r\n4. Ted, who works for the department store in North Street, isn't surnamed Snow.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFred works for Thurlow's (clue 1), and Nardine's is in Market Hill (clue 2), so Ted's employers in North Street (clue 4) must be Letten's. By elimination, Fred must work in King Street and Alf must work for Nardine's. Winter can't be Fred or Ted (clue 3), so it must be Frost, and Fred must be Snow.\r\nIN SUMMARY:\r\nAlf Winter-Nadine's-Market Hill\r\nFred Snow-Thurlow's-King Street\r\nTed Frost-Letten's-North Street\n<|im_start|>answer\nFred works for Thurlow's (clue 1), and Nardine's is in Market Hill (clue 2), so Ted's employers in North Street (clue 4) must be Letten's. By elimination, Fred must work in King Street and Alf must work for Nardine's. Winter can't be Fred or Ted (clue 3), so it must be Frost, and Fred must be Snow.\r\nIN SUMMARY:\r\nAlf Winter-Nadine's-Market Hill\r\nFred Snow-Thurlow's-King Street\r\nTed Frost-Letten's-North Street\n<|im_end|>" }, { "id": "#16789", "title": "More or Less", "fun": 2.24, "difficulty": 1.19, "author": "adoontourious", "desc": "I was doing my math homework last night with Benji's radio blaring (as usual) in the background. \r\n\"Hey, Mike, did you hear that commercial?\" Benji called from the next room. \r\n\"No. What's it for?\" \r\n\"Remember that stereo you heard about at Sweeters? Then, when you got to the store, they'd raised the price by 25%. Now, they say they've lowered the prices on their stereos by 25%. So the one you wanted has to be the same price as it was at first.\" \r\n\"Sounds good,\" I said. \"But if the price is down 25%, I think it's gotta cost even less than it cost at first.\" \r\n\"No way. Up 25%, then down 25%, means you're back where you started from,\" Benji tried to assure me. \n\r\nWho's right about the price, Mike or Benji? Is the price of the stereo the same as it was when Mike first heard about it or is the price even less than it was at first?", "hint": "No hint available.", "answer": "Mike is right. The price of the stereo is less than it was before the 25% increase and the 25% decrease. \n\r\nPretend that the stereo cost $1,000. You know that 25% of 1,000 is 250. So, after the 25% increase, the cost of the stereo was $1,250. Now find 25% of $1,250. Subtract this amount ($312.50) from $1,250 to find the reduced price. It's $937.50 - that's $62.50 less than the original price of $1,000!", "category": "Math", "date": "02/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was doing my math homework last night with Benji's radio blaring (as usual) in the background. \r\n\"Hey, Mike, did you hear that commercial?\" Benji called from the next room. \r\n\"No. What's it for?\" \r\n\"Remember that stereo you heard about at Sweeters? Then, when you got to the store, they'd raised the price by 25%. Now, they say they've lowered the prices on their stereos by 25%. So the one you wanted has to be the same price as it was at first.\" \r\n\"Sounds good,\" I said. \"But if the price is down 25%, I think it's gotta cost even less than it cost at first.\" \r\n\"No way. Up 25%, then down 25%, means you're back where you started from,\" Benji tried to assure me. \n\r\nWho's right about the price, Mike or Benji? Is the price of the stereo the same as it was when Mike first heard about it or is the price even less than it was at first?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike is right. The price of the stereo is less than it was before the 25% increase and the 25% decrease. \n\r\nPretend that the stereo cost $1,000. You know that 25% of 1,000 is 250. So, after the 25% increase, the cost of the stereo was $1,250. Now find 25% of $1,250. Subtract this amount ($312.50) from $1,250 to find the reduced price. It's $937.50 - that's $62.50 less than the original price of $1,000!\n<|im_start|>answer\nMike is right. The price of the stereo is less than it was before the 25% increase and the 25% decrease. \n\r\nPretend that the stereo cost $1,000. You know that 25% of 1,000 is 250. So, after the 25% increase, the cost of the stereo was $1,250. Now find 25% of $1,250. Subtract this amount ($312.50) from $1,250 to find the reduced price. It's $937.50 - that's $62.50 less than the original price of $1,000!\n<|im_end|>" }, { "id": "#19623", "title": "Madadian Farm Animals", "fun": 2.24, "difficulty": 2.73, "author": "Mad-Ade", "desc": "Old Farmer McDoughnut owns a piece of grassland in the heart of Madadia and has three animals: a Madadian Burger Cow, a Spare Kebab Goat, and a Scotch Egg laying Goose. McDoughnut discovered the following: \r\nWhen the cow and the goat graze on the field together, there is no more grass after 45 days. \r\nWhen the cow and the goose graze on the field together, there is no more grass after 60 days. \r\nWhen the cow grazes on the field alone, there is no more grass after 90 days. \r\nWhen the goat and the goose graze on the field together, there is no more grass after 90 days also. \n\r\n For how long can the three animals graze on the field together?", "hint": "No hint available.", "answer": "The cow, the goat, and the goose eat grass with a constant speed (amount per day): v1 for the cow, v2 for the goat, v3 for the goose. \r\nThe grass grows with a constant amount per day (k). \r\nThe amount of grass at the beginning is h. \r\nThere is given: \r\nWhen the cow and the goat graze on the field together, there is no grass left after 45 days. Therefore, h-45x(v1+v2-k) = 0, so v1+v2-k = h/45 = 4xh/180. \r\nWhen the cow and the goose graze on the field together, there is no grass left after 60 days. Therefore, h-60x(v1+v3-k) = 0, so v1+v3-k = h/60 = 3xh/180. \r\nWhen the cow grazes on the field alone, there is no grass left after 90 days. Therefore, h-90x(v1-k) = 0, so v1-k = h/90 = 2xh/180. \r\nWhen the goat and the goose graze on the field together, there is also no grass left after 90 days. Therefore, h-90x(v2+v3-k) = 0, so v2+v3-k = h/90 = 2xh/180. \r\nFrom this follows:\r\nv1 = 3 x h/180,\r\nv2 = 2 x h/180,\r\nv3 = 1 x h/180,\r\nk = 1 x h/180. \n\r\nThen holds for the time t that the three animals can graze together: h-tx(v1+v2+v3-k) = 0, so t = h/(v1+v2+v3-k) = h/(3xh/180+2xh/180+1xh/180-1xh/180) = 36. The three animals can graze together for 36 days.", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOld Farmer McDoughnut owns a piece of grassland in the heart of Madadia and has three animals: a Madadian Burger Cow, a Spare Kebab Goat, and a Scotch Egg laying Goose. McDoughnut discovered the following: \r\nWhen the cow and the goat graze on the field together, there is no more grass after 45 days. \r\nWhen the cow and the goose graze on the field together, there is no more grass after 60 days. \r\nWhen the cow grazes on the field alone, there is no more grass after 90 days. \r\nWhen the goat and the goose graze on the field together, there is no more grass after 90 days also. \n\r\n For how long can the three animals graze on the field together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cow, the goat, and the goose eat grass with a constant speed (amount per day): v1 for the cow, v2 for the goat, v3 for the goose. \r\nThe grass grows with a constant amount per day (k). \r\nThe amount of grass at the beginning is h. \r\nThere is given: \r\nWhen the cow and the goat graze on the field together, there is no grass left after 45 days. Therefore, h-45x(v1+v2-k) = 0, so v1+v2-k = h/45 = 4xh/180. \r\nWhen the cow and the goose graze on the field together, there is no grass left after 60 days. Therefore, h-60x(v1+v3-k) = 0, so v1+v3-k = h/60 = 3xh/180. \r\nWhen the cow grazes on the field alone, there is no grass left after 90 days. Therefore, h-90x(v1-k) = 0, so v1-k = h/90 = 2xh/180. \r\nWhen the goat and the goose graze on the field together, there is also no grass left after 90 days. Therefore, h-90x(v2+v3-k) = 0, so v2+v3-k = h/90 = 2xh/180. \r\nFrom this follows:\r\nv1 = 3 x h/180,\r\nv2 = 2 x h/180,\r\nv3 = 1 x h/180,\r\nk = 1 x h/180. \n\r\nThen holds for the time t that the three animals can graze together: h-tx(v1+v2+v3-k) = 0, so t = h/(v1+v2+v3-k) = h/(3xh/180+2xh/180+1xh/180-1xh/180) = 36. The three animals can graze together for 36 days.\n<|im_start|>answer\nThe cow, the goat, and the goose eat grass with a constant speed (amount per day): v1 for the cow, v2 for the goat, v3 for the goose. \r\nThe grass grows with a constant amount per day (k). \r\nThe amount of grass at the beginning is h. \r\nThere is given: \r\nWhen the cow and the goat graze on the field together, there is no grass left after 45 days. Therefore, h-45x(v1+v2-k) = 0, so v1+v2-k = h/45 = 4xh/180. \r\nWhen the cow and the goose graze on the field together, there is no grass left after 60 days. Therefore, h-60x(v1+v3-k) = 0, so v1+v3-k = h/60 = 3xh/180. \r\nWhen the cow grazes on the field alone, there is no grass left after 90 days. Therefore, h-90x(v1-k) = 0, so v1-k = h/90 = 2xh/180. \r\nWhen the goat and the goose graze on the field together, there is also no grass left after 90 days. Therefore, h-90x(v2+v3-k) = 0, so v2+v3-k = h/90 = 2xh/180. \r\nFrom this follows:\r\nv1 = 3 x h/180,\r\nv2 = 2 x h/180,\r\nv3 = 1 x h/180,\r\nk = 1 x h/180. \n\r\nThen holds for the time t that the three animals can graze together: h-tx(v1+v2+v3-k) = 0, so t = h/(v1+v2+v3-k) = h/(3xh/180+2xh/180+1xh/180-1xh/180) = 36. The three animals can graze together for 36 days.\n<|im_end|>" }, { "id": "#30038", "title": "Ones and Zero's", "fun": 2.24, "difficulty": 2.52, "author": "cms271828", "desc": "What's so special about this number?\n\r\n11.00100100001111110110101...", "hint": "Use binary.", "answer": "The number is pi in binary.\n\r\nWith standard binary, 4 is 100, 2 is 10, 1 is 1.\r\nContinuing this process...\r\n1/2=0.1, 1/4=0.01, 1/8=0.001 and so on.", "category": "Math", "date": "04/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat's so special about this number?\n\r\n11.00100100001111110110101...\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is pi in binary.\n\r\nWith standard binary, 4 is 100, 2 is 10, 1 is 1.\r\nContinuing this process...\r\n1/2=0.1, 1/4=0.01, 1/8=0.001 and so on.\n<|im_start|>answer\nThe number is pi in binary.\n\r\nWith standard binary, 4 is 100, 2 is 10, 1 is 1.\r\nContinuing this process...\r\n1/2=0.1, 1/4=0.01, 1/8=0.001 and so on.\n<|im_end|>" }, { "id": "#3986", "title": "Three Sages", "fun": 2.24, "difficulty": 1.8, "author": "valeriy", "desc": "Once three sages decided to learn who of them is the smartest. So they went to the 4th sage and asked him to help them decide who is the smartest. The 4th one said, \"I have five hats: two black and three white. Now I'll tie your eyes and put one of the hats on your heads. After that I'll untie your eyes and you will be able to see the hats of the other two sages, but you won't be able to see the hat on your head. And he who is able to state what color is the hat that is on his own head will be the smartest.\" After a while one of the sages told what color is the hat on his head.\n\r\nHow did he do that?", "hint": "All of the sages had white hats.", "answer": "Sage A thinks, \"If sage B sees a black hat on my head he would think, 'if sage C sees that I and A, both have black hats, he would say that he has a white one. He didn't say that so I have a white one.' Sage B did not say that, so I have a white one!\"", "category": "Logic", "date": "05/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce three sages decided to learn who of them is the smartest. So they went to the 4th sage and asked him to help them decide who is the smartest. The 4th one said, \"I have five hats: two black and three white. Now I'll tie your eyes and put one of the hats on your heads. After that I'll untie your eyes and you will be able to see the hats of the other two sages, but you won't be able to see the hat on your head. And he who is able to state what color is the hat that is on his own head will be the smartest.\" After a while one of the sages told what color is the hat on his head.\n\r\nHow did he do that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSage A thinks, \"If sage B sees a black hat on my head he would think, 'if sage C sees that I and A, both have black hats, he would say that he has a white one. He didn't say that so I have a white one.' Sage B did not say that, so I have a white one!\"\n<|im_start|>answer\nSage A thinks, \"If sage B sees a black hat on my head he would think, 'if sage C sees that I and A, both have black hats, he would say that he has a white one. He didn't say that so I have a white one.' Sage B did not say that, so I have a white one!\"\n<|im_end|>" }, { "id": "#10397", "title": "Beating Nick Faldo", "fun": 2.24, "difficulty": 2.12, "author": "godinaj", "desc": "An amateur golfer challenged former Masters Champion Nick Faldo to a match. The amateur was to pick the time and place of the match. Nick Faldo accepted the challenge and met the man at the assigned time and place. The amateur easily defeated Faldo. How did this happen?", "hint": "No hint available.", "answer": "The amateur golfer was a blind man and they played at midnight. The amateur was at no disadvantage while Nick Faldo obviously was. Blind golfers often play with the help of a spotter.", "category": "Logic", "date": "02/12/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn amateur golfer challenged former Masters Champion Nick Faldo to a match. The amateur was to pick the time and place of the match. Nick Faldo accepted the challenge and met the man at the assigned time and place. The amateur easily defeated Faldo. How did this happen?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe amateur golfer was a blind man and they played at midnight. The amateur was at no disadvantage while Nick Faldo obviously was. Blind golfers often play with the help of a spotter.\n<|im_start|>answer\nThe amateur golfer was a blind man and they played at midnight. The amateur was at no disadvantage while Nick Faldo obviously was. Blind golfers often play with the help of a spotter.\n<|im_end|>" }, { "id": "#38071", "title": "Pole in a Lake", "fun": 2.24, "difficulty": 1.84, "author": "tigersrule", "desc": "There is a pole in a lake. One-half of the pole is in the ground, another one-third in the water, and 12 ft. are out of the water. (ft.=feet)\r\nHow long is the pole?", "hint": "No hint available.", "answer": "72 ft.", "category": "Math", "date": "09/02/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a pole in a lake. One-half of the pole is in the ground, another one-third in the water, and 12 ft. are out of the water. (ft.=feet)\r\nHow long is the pole?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n72 ft.\n<|im_start|>answer\n72 ft.\n<|im_end|>" }, { "id": "#43548", "title": "How Old is ____? #1", "fun": 2.24, "difficulty": 0.71, "author": "angelsluvme", "desc": "Jessica is 11 years older than Joe. Joe is two years younger than Tina. Tina is 8 years old. Angela is half as old as Jessica but George is 3 times as old as Angela. How old is George?", "hint": "Use a decimal if needed.", "answer": "25.5", "category": "Math", "date": "11/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJessica is 11 years older than Joe. Joe is two years younger than Tina. Tina is 8 years old. Angela is half as old as Jessica but George is 3 times as old as Angela. How old is George?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n25.5\n<|im_start|>answer\n25.5\n<|im_end|>" }, { "id": "#19519", "title": "Mad Ade's Train Accident", "fun": 2.24, "difficulty": 2.43, "author": "Mad-Ade", "desc": "Mad Ade was going by train from Kebabchester to Penistone, and an hour after setting off an accident happened to the train. \n\r\nDespite this the train had to continue the journey at three-fifths of the former speed. It made Mad Ade two hours late at Penistone, and the driver said that if only the accident had happened fifty miles farther on the train would have arrived forty minutes sooner. Can you tell from that statement just how far it is from Kebabchester to Penistone?", "hint": "No hint available.", "answer": "The distance from Kebabchester to Penistone must be 200 miles. \n\r\nThe train went 50 miles at 50 m.p.h. and 150 miles at 30 m.p.h. \n\r\nIf the accident had occurred 50 miles farther on, it would have gone 100 miles at 50 m.p.h. and 100 miles at 30 m.p.h.", "category": "Math", "date": "11/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was going by train from Kebabchester to Penistone, and an hour after setting off an accident happened to the train. \n\r\nDespite this the train had to continue the journey at three-fifths of the former speed. It made Mad Ade two hours late at Penistone, and the driver said that if only the accident had happened fifty miles farther on the train would have arrived forty minutes sooner. Can you tell from that statement just how far it is from Kebabchester to Penistone?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe distance from Kebabchester to Penistone must be 200 miles. \n\r\nThe train went 50 miles at 50 m.p.h. and 150 miles at 30 m.p.h. \n\r\nIf the accident had occurred 50 miles farther on, it would have gone 100 miles at 50 m.p.h. and 100 miles at 30 m.p.h.\n<|im_start|>answer\nThe distance from Kebabchester to Penistone must be 200 miles. \n\r\nThe train went 50 miles at 50 m.p.h. and 150 miles at 30 m.p.h. \n\r\nIf the accident had occurred 50 miles farther on, it would have gone 100 miles at 50 m.p.h. and 100 miles at 30 m.p.h.\n<|im_end|>" }, { "id": "#2523", "title": "Family Matters", "fun": 2.24, "difficulty": 1.0, "author": "lil_thugsta", "desc": "If the only brother of your dad's sister had a child, what would the child's relationship to you be?", "hint": "No hint available.", "answer": "You are that person.", "category": "Logic", "date": "03/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the only brother of your dad's sister had a child, what would the child's relationship to you be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou are that person.\n<|im_start|>answer\nYou are that person.\n<|im_end|>" }, { "id": "#10533", "title": "Soda Bottle", "fun": 2.24, "difficulty": 2.26, "author": "Bobbrt", "desc": "You have a typical soda bottle, which is designed such that the bottom 3/4 is a perfect cylinder and the top 1/4 is an irregular shape. The bottle is filled about half way with soda. Using only a ruler, how can you determine exactly what percentage of the bottle's volume is filled?", "hint": "No hint available.", "answer": "First measure the height of the liquid in the bottle with the bottle upright. Then, turn the bottle upside-down and measure the amount of space: the distance from the top of the liquid to the bottom of the bottle.\r\nYou have now found the heights of liquid and air in terms of the cylinder only. You have essentially taken the irregular shape out of the equation. Simply divide the height of the liquid by the sum of the two heights to get the volume percent of the liquid in the bottle.", "category": "Math", "date": "02/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a typical soda bottle, which is designed such that the bottom 3/4 is a perfect cylinder and the top 1/4 is an irregular shape. The bottle is filled about half way with soda. Using only a ruler, how can you determine exactly what percentage of the bottle's volume is filled?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst measure the height of the liquid in the bottle with the bottle upright. Then, turn the bottle upside-down and measure the amount of space: the distance from the top of the liquid to the bottom of the bottle.\r\nYou have now found the heights of liquid and air in terms of the cylinder only. You have essentially taken the irregular shape out of the equation. Simply divide the height of the liquid by the sum of the two heights to get the volume percent of the liquid in the bottle.\n<|im_start|>answer\nFirst measure the height of the liquid in the bottle with the bottle upright. Then, turn the bottle upside-down and measure the amount of space: the distance from the top of the liquid to the bottom of the bottle.\r\nYou have now found the heights of liquid and air in terms of the cylinder only. You have essentially taken the irregular shape out of the equation. Simply divide the height of the liquid by the sum of the two heights to get the volume percent of the liquid in the bottle.\n<|im_end|>" }, { "id": "#40896", "title": "What 3 Digit Number Am I?", "fun": 2.24, "difficulty": 1.39, "author": "suprfrek96", "desc": "I am a three digit number. My second digit is four times my third digit. My first digit is seven less than my second digit. What number am I?", "hint": "All digits equal 11.", "answer": "182", "category": "Math", "date": "03/06/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a three digit number. My second digit is four times my third digit. My first digit is seven less than my second digit. What number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n182\n<|im_start|>answer\n182\n<|im_end|>" }, { "id": "#3940", "title": "Coin Logic", "fun": 2.24, "difficulty": 1.53, "author": "mad-ade", "desc": "Bob and John were counting how many £1 coins they each had. Bob said to John, \"If I were to give you one of my coins, you would have twice as much as me\". John replied, \"If I were to give you one of my pound coins, then we would both have the same amount\".\n\r\nWhat is the minimum amount of £1 coins they could each have in this situation?", "hint": "No hint available.", "answer": "Bob has 5 £1 coins.\r\nJohn has 7 £1 coins.", "category": "Logic", "date": "05/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob and John were counting how many £1 coins they each had. Bob said to John, \"If I were to give you one of my coins, you would have twice as much as me\". John replied, \"If I were to give you one of my pound coins, then we would both have the same amount\".\n\r\nWhat is the minimum amount of £1 coins they could each have in this situation?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob has 5 £1 coins.\r\nJohn has 7 £1 coins.\n<|im_start|>answer\nBob has 5 £1 coins.\r\nJohn has 7 £1 coins.\n<|im_end|>" }, { "id": "#4763", "title": "Aunties Daughters", "fun": 2.24, "difficulty": 1.85, "author": "mad-ade", "desc": "Mad Ade's Aunty, Betty Swollocks, has 6 daughters. Each daughter is 4 years older than her next younger sister. The oldest daughter is 3 times as old as her youngest sister. \n\r\nHow old is each of Aunty Betty's daughters?", "hint": "No hint available.", "answer": "From youngest to oldest, the 6 daughters are 10, 14, 18, 22, 26, and 30.", "category": "Math", "date": "06/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Aunty, Betty Swollocks, has 6 daughters. Each daughter is 4 years older than her next younger sister. The oldest daughter is 3 times as old as her youngest sister. \n\r\nHow old is each of Aunty Betty's daughters?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom youngest to oldest, the 6 daughters are 10, 14, 18, 22, 26, and 30.\n<|im_start|>answer\nFrom youngest to oldest, the 6 daughters are 10, 14, 18, 22, 26, and 30.\n<|im_end|>" }, { "id": "#6180", "title": "One Eleventh", "fun": 2.24, "difficulty": 2.75, "author": "im_para_noid", "desc": "Arrange the digits 1, 1, 2, 3, 3, 4, 4, 5, and 7 to form a single fraction that equals 1/11", "hint": "No hint available.", "answer": "One solutions is 4321/47531=1/11", "category": "Math", "date": "08/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the digits 1, 1, 2, 3, 3, 4, 4, 5, and 7 to form a single fraction that equals 1/11\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne solutions is 4321/47531=1/11\n<|im_start|>answer\nOne solutions is 4321/47531=1/11\n<|im_end|>" }, { "id": "#6488", "title": "S.U.K.S", "fun": 2.24, "difficulty": 2.0, "author": "mad-ade", "desc": "In the General meeting of MADADIA's \"Secret Union of the Kebab Society\" or S.U.K.S as it is sometime known, The chairman, Mr. Thorny Kator said, \"The repairs to the Club, after the last all night kebab wrestling meeting, will come to a total of 3120 wonks (Madadian currency).\" \"So therefore I propose that this amount should be met by the members, each paying an equal amount.\" The proposal was immediately agreed, more out of embarrassment than anything else. However, four members of the S.U.K.S chose to resign, leaving the remaining S.U.K.S members to pay an extra 26 Wonks each. \n\r\nHow many members did S.U.K.S originally have?", "hint": "No hint available.", "answer": "The club originally had 24 members. \n\r\nExplanation: When the club had 24 members, the cost to each member was 130 Wonks (130*24=3120). When the club was reduced, by 4, to 20, the cost to each member was 156 Wonks (156*20=3120), which is 130+26.", "category": "Math", "date": "08/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the General meeting of MADADIA's \"Secret Union of the Kebab Society\" or S.U.K.S as it is sometime known, The chairman, Mr. Thorny Kator said, \"The repairs to the Club, after the last all night kebab wrestling meeting, will come to a total of 3120 wonks (Madadian currency).\" \"So therefore I propose that this amount should be met by the members, each paying an equal amount.\" The proposal was immediately agreed, more out of embarrassment than anything else. However, four members of the S.U.K.S chose to resign, leaving the remaining S.U.K.S members to pay an extra 26 Wonks each. \n\r\nHow many members did S.U.K.S originally have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe club originally had 24 members. \n\r\nExplanation: When the club had 24 members, the cost to each member was 130 Wonks (130*24=3120). When the club was reduced, by 4, to 20, the cost to each member was 156 Wonks (156*20=3120), which is 130+26.\n<|im_start|>answer\nThe club originally had 24 members. \n\r\nExplanation: When the club had 24 members, the cost to each member was 130 Wonks (130*24=3120). When the club was reduced, by 4, to 20, the cost to each member was 156 Wonks (156*20=3120), which is 130+26.\n<|im_end|>" }, { "id": "#2350", "title": "Fred and Ethel", "fun": 2.24, "difficulty": 2.17, "author": "Iambraindead", "desc": "Fred and Ethel go to the golf course. They meet 3 other couples there, and everybody gets introduced. After introductions, Fred asks everyone how many hands they shook. He gets seven different answers. Presume that no one shook their partner's hand\n\r\nHow many hands did Ethel shake?", "hint": "No hint available.", "answer": "3\n\r\nSince no one shakes his own hand or his spouse's, the most handshakes is 6. Since there are seven different answers, then the given answers are 0 through 6. If Mr A shook 6 hands, Mrs A had to be the one who shook no hands. Similarly, if Mr B shook 5 hands, then Mrs B could only have shaken 1 hand; and Mr and Mrs C shook 4 and 2 hands respectively; and Mr and Mrs D would have shaken 3 hands each. Since only one person could have given an answer of 3, then Fred had to be Mr D, meaning that Ethel was Mrs D. This means that Ethel shook 3 hands.", "category": "Logic", "date": "02/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred and Ethel go to the golf course. They meet 3 other couples there, and everybody gets introduced. After introductions, Fred asks everyone how many hands they shook. He gets seven different answers. Presume that no one shook their partner's hand\n\r\nHow many hands did Ethel shake?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3\n\r\nSince no one shakes his own hand or his spouse's, the most handshakes is 6. Since there are seven different answers, then the given answers are 0 through 6. If Mr A shook 6 hands, Mrs A had to be the one who shook no hands. Similarly, if Mr B shook 5 hands, then Mrs B could only have shaken 1 hand; and Mr and Mrs C shook 4 and 2 hands respectively; and Mr and Mrs D would have shaken 3 hands each. Since only one person could have given an answer of 3, then Fred had to be Mr D, meaning that Ethel was Mrs D. This means that Ethel shook 3 hands.\n<|im_start|>answer\n3\n\r\nSince no one shakes his own hand or his spouse's, the most handshakes is 6. Since there are seven different answers, then the given answers are 0 through 6. If Mr A shook 6 hands, Mrs A had to be the one who shook no hands. Similarly, if Mr B shook 5 hands, then Mrs B could only have shaken 1 hand; and Mr and Mrs C shook 4 and 2 hands respectively; and Mr and Mrs D would have shaken 3 hands each. Since only one person could have given an answer of 3, then Fred had to be Mr D, meaning that Ethel was Mrs D. This means that Ethel shook 3 hands.\n<|im_end|>" }, { "id": "#22936", "title": "Sneak Thief", "fun": 2.24, "difficulty": 2.02, "author": "terranmarine", "desc": "A thief has been at work in a classroom. When the pupils return from lunch, 80 percent of them have lost a pencil, 85 percent have lost a pen, 74 percent have lost a ruler, and 68 percent have lost an eraser.\n\r\nWhat percentage, at least, must have lost all four items?", "hint": "No hint available.", "answer": "If you assume that there are 100 pupils, then adding the percentages together will give the total number of losses: 80+85+74+68=307. This means that there are 3 losses each for each pupil, with 7 pupils losing all 4 items. Therefore, the smallest percentage of pupils that lost all four items is 7%.", "category": "Math", "date": "05/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA thief has been at work in a classroom. When the pupils return from lunch, 80 percent of them have lost a pencil, 85 percent have lost a pen, 74 percent have lost a ruler, and 68 percent have lost an eraser.\n\r\nWhat percentage, at least, must have lost all four items?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you assume that there are 100 pupils, then adding the percentages together will give the total number of losses: 80+85+74+68=307. This means that there are 3 losses each for each pupil, with 7 pupils losing all 4 items. Therefore, the smallest percentage of pupils that lost all four items is 7%.\n<|im_start|>answer\nIf you assume that there are 100 pupils, then adding the percentages together will give the total number of losses: 80+85+74+68=307. This means that there are 3 losses each for each pupil, with 7 pupils losing all 4 items. Therefore, the smallest percentage of pupils that lost all four items is 7%.\n<|im_end|>" }, { "id": "#10951", "title": "Psychopets", "fun": 2.24, "difficulty": 2.29, "author": "jimbo", "desc": "In a small country town, some of the pets were confused about their identities. 20% of the cats thought they were dogs while 20% of the dogs thought they were cats. The local veterinarian psychiatrist took a survey and found that 40% of all the cats and dogs thought they were cats. What percentage of all the cats and dogs were really cats?", "hint": "Paws up all those who think they are a cat!", "answer": "Let there be x cats and y dogs.\r\n80% of x + 20% of y = 40%(x+y)\r\n40% of x = 20% of y\r\n2x = y\r\nThe number of dogs is double the number of cats.\r\nSay there are 100 cats and 200 dogs. 33 1/3% of all of the animals are really members of the meow generation!", "category": "Math", "date": "03/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a small country town, some of the pets were confused about their identities. 20% of the cats thought they were dogs while 20% of the dogs thought they were cats. The local veterinarian psychiatrist took a survey and found that 40% of all the cats and dogs thought they were cats. What percentage of all the cats and dogs were really cats?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet there be x cats and y dogs.\r\n80% of x + 20% of y = 40%(x+y)\r\n40% of x = 20% of y\r\n2x = y\r\nThe number of dogs is double the number of cats.\r\nSay there are 100 cats and 200 dogs. 33 1/3% of all of the animals are really members of the meow generation!\n<|im_start|>answer\nLet there be x cats and y dogs.\r\n80% of x + 20% of y = 40%(x+y)\r\n40% of x = 20% of y\r\n2x = y\r\nThe number of dogs is double the number of cats.\r\nSay there are 100 cats and 200 dogs. 33 1/3% of all of the animals are really members of the meow generation!\n<|im_end|>" }, { "id": "#48921", "title": "The Three Identical Persons", "fun": 2.24, "difficulty": 1.21, "author": "efurosibina", "desc": "A policeman was chasing a criminal and suddenly the criminal dashed into a particular house. The policeman followed suit and found out that there were three identical persons watching a particular program on the television. At first, the policeman was confused but after asking each person a simple question separately, he was able to detect the culprit. What question did he ask each person?", "hint": "Television past event.", "answer": "The policeman asked each person this question: \"What was the previous program on the television?\". The culprit had no idea what the last program shown was, hence, his arrest ensued.", "category": "Logic", "date": "08/03/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA policeman was chasing a criminal and suddenly the criminal dashed into a particular house. The policeman followed suit and found out that there were three identical persons watching a particular program on the television. At first, the policeman was confused but after asking each person a simple question separately, he was able to detect the culprit. What question did he ask each person?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe policeman asked each person this question: \"What was the previous program on the television?\". The culprit had no idea what the last program shown was, hence, his arrest ensued.\n<|im_start|>answer\nThe policeman asked each person this question: \"What was the previous program on the television?\". The culprit had no idea what the last program shown was, hence, his arrest ensued.\n<|im_end|>" }, { "id": "#22919", "title": "Carousel", "fun": 2.24, "difficulty": 2.02, "author": "phrebh", "desc": "Fred was in Washington, D.C., on a school trip to visit the Smithsonian. After lunch the teachers took the students to the Carousel on the Mall (this happened before they closed it down).\n\r\nWhile Fred was enjoying his ride, he noticed that one-third of the number of his classmates riding ahead of him, plus three-fourths of them riding behind him, equaled the total number of students on the carousel.\n\r\nHow many students were riding the carousel?", "hint": "No hint available.", "answer": "13.\n\r\nThe number of students ahead of him equals the number behind him. So,\n\r\n1/3x + 3/4x = x + 1\n\r\nWhen finding the common denominator for the left-hand side of the equation, we get 12, and the sum of the numerators then equals 13.", "category": "Math", "date": "05/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred was in Washington, D.C., on a school trip to visit the Smithsonian. After lunch the teachers took the students to the Carousel on the Mall (this happened before they closed it down).\n\r\nWhile Fred was enjoying his ride, he noticed that one-third of the number of his classmates riding ahead of him, plus three-fourths of them riding behind him, equaled the total number of students on the carousel.\n\r\nHow many students were riding the carousel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n13.\n\r\nThe number of students ahead of him equals the number behind him. So,\n\r\n1/3x + 3/4x = x + 1\n\r\nWhen finding the common denominator for the left-hand side of the equation, we get 12, and the sum of the numerators then equals 13.\n<|im_start|>answer\n13.\n\r\nThe number of students ahead of him equals the number behind him. So,\n\r\n1/3x + 3/4x = x + 1\n\r\nWhen finding the common denominator for the left-hand side of the equation, we get 12, and the sum of the numerators then equals 13.\n<|im_end|>" }, { "id": "#40234", "title": "Costume Party", "fun": 2.24, "difficulty": 1.04, "author": "icestar12", "desc": "Costume Party \n\n\r\n Fiona, George, Rachel, and Patrick are planning their costumes for a party. Each will wear a different costume. There will be a pirate, a ghost, a Martian, and a gorilla.\n\r\nNo one will have a costume that begins with the same letter as the name of the person wearing it. \r\nThe Martian is a boy. \r\nThe gorilla is a girl. \r\nPatrick likes science fiction and space characters. \r\nFiona didn't want to be a ghost this year. \r\nWhich costume will each of the party-goers wear?", "hint": "No hint available.", "answer": "Fiona will be the gorilla.\r\nGeorge will be the pirate.\r\nRachel will be the ghost.\r\nPatrick will be the Martian.", "category": "Logic", "date": "01/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCostume Party \n\n\r\n Fiona, George, Rachel, and Patrick are planning their costumes for a party. Each will wear a different costume. There will be a pirate, a ghost, a Martian, and a gorilla.\n\r\nNo one will have a costume that begins with the same letter as the name of the person wearing it. \r\nThe Martian is a boy. \r\nThe gorilla is a girl. \r\nPatrick likes science fiction and space characters. \r\nFiona didn't want to be a ghost this year. \r\nWhich costume will each of the party-goers wear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFiona will be the gorilla.\r\nGeorge will be the pirate.\r\nRachel will be the ghost.\r\nPatrick will be the Martian.\n<|im_start|>answer\nFiona will be the gorilla.\r\nGeorge will be the pirate.\r\nRachel will be the ghost.\r\nPatrick will be the Martian.\n<|im_end|>" }, { "id": "#7522", "title": "Greatest Human", "fun": 2.24, "difficulty": 2.67, "author": "warrior", "desc": "In a survey to find the greatest human being, the top four people and their occupation were listed in Clock magazine. However, only one entry in each field was correctly positioned. The following facts were true. (1) Albert was two places above the bricklayer, (2) Darling was one place below Charles, (3) Curious was two places below the welder. Can you find the 1st name, surname and occupation for each position?\n\r\nFirst Name\r\n1st place - Isaac\r\n2nd place - Albert\r\n3rd place - Marie\r\n4th place - Charles\n\r\nSurname\r\n1st place - Newtune\r\n2nd place - Eyeline\r\n3rd place - Curious\r\n4th place - Darling\n\r\nOccupation\r\n1st place - Welder\r\n2nd place - Gardener\r\n3rd place - Cleaner\r\n4th place - Bricklayer", "hint": "No hint available.", "answer": "Using (1), Albert is at 1 or 2. If he is at 1, then from (3), Charles is at 2 or 3. However, with Charles at 2 (and Darling at 3), from (2), Curious can only be at 4 and so it is not possible to find just one correct entry in the Surname list (Newtune and Eyeline must be both correct or both incorrect). If Charles is at 3 (with Darling at 4), then from (2), Curious can only be at 3. This gives both Curious and Darling correct (invalid). So Albert must be at 2 (with the bricklayer at 4). From (3), Charles can be at 1 or 3. However, if Charles is at 3 (with Darling at 4), then both Curious and Darling are correct (invalid). So Charles is at 1 (with Darling at 2). From (2), Curious can now be at 3 or 4, but if Curious is at 3 (with the welder at 1) then both the welder and bricklayer are correct (invalid).", "category": "Logic", "date": "09/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a survey to find the greatest human being, the top four people and their occupation were listed in Clock magazine. However, only one entry in each field was correctly positioned. The following facts were true. (1) Albert was two places above the bricklayer, (2) Darling was one place below Charles, (3) Curious was two places below the welder. Can you find the 1st name, surname and occupation for each position?\n\r\nFirst Name\r\n1st place - Isaac\r\n2nd place - Albert\r\n3rd place - Marie\r\n4th place - Charles\n\r\nSurname\r\n1st place - Newtune\r\n2nd place - Eyeline\r\n3rd place - Curious\r\n4th place - Darling\n\r\nOccupation\r\n1st place - Welder\r\n2nd place - Gardener\r\n3rd place - Cleaner\r\n4th place - Bricklayer\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUsing (1), Albert is at 1 or 2. If he is at 1, then from (3), Charles is at 2 or 3. However, with Charles at 2 (and Darling at 3), from (2), Curious can only be at 4 and so it is not possible to find just one correct entry in the Surname list (Newtune and Eyeline must be both correct or both incorrect). If Charles is at 3 (with Darling at 4), then from (2), Curious can only be at 3. This gives both Curious and Darling correct (invalid). So Albert must be at 2 (with the bricklayer at 4). From (3), Charles can be at 1 or 3. However, if Charles is at 3 (with Darling at 4), then both Curious and Darling are correct (invalid). So Charles is at 1 (with Darling at 2). From (2), Curious can now be at 3 or 4, but if Curious is at 3 (with the welder at 1) then both the welder and bricklayer are correct (invalid).\n<|im_start|>answer\nUsing (1), Albert is at 1 or 2. If he is at 1, then from (3), Charles is at 2 or 3. However, with Charles at 2 (and Darling at 3), from (2), Curious can only be at 4 and so it is not possible to find just one correct entry in the Surname list (Newtune and Eyeline must be both correct or both incorrect). If Charles is at 3 (with Darling at 4), then from (2), Curious can only be at 3. This gives both Curious and Darling correct (invalid). So Albert must be at 2 (with the bricklayer at 4). From (3), Charles can be at 1 or 3. However, if Charles is at 3 (with Darling at 4), then both Curious and Darling are correct (invalid). So Charles is at 1 (with Darling at 2). From (2), Curious can now be at 3 or 4, but if Curious is at 3 (with the welder at 1) then both the welder and bricklayer are correct (invalid).\n<|im_end|>" }, { "id": "#3910", "title": "Time Please", "fun": 2.24, "difficulty": 1.77, "author": "mad-ade", "desc": "What time is it when the number of minutes since midnight is nine times that of minutes till mid day?", "hint": "No hint available.", "answer": "10:48am", "category": "Math", "date": "05/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat time is it when the number of minutes since midnight is nine times that of minutes till mid day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10:48am\n<|im_start|>answer\n10:48am\n<|im_end|>" }, { "id": "#4180", "title": "Suspended Meter Stick", "fun": 2.24, "difficulty": 2.42, "author": "cathalmccabe", "desc": "A meter stick is suspended exactly at its 45 cm mark from a piece of string, and an 8kg is fixed to the stick and hangs from the 0cm mark. You have six 1kg weights you can hang anywhere on the stick (you can put more than one on the same point if you wish). How can you get the system to balance?", "hint": "No hint available.", "answer": "The turning force of the 8kg is 360\r\nThe max force on the other side would be if you put all 6 on the 100cm mark - 6*55 turning force = 330 Which isn't enough to balance, so the only way you can to this is by moving the point of suspension of the metre stick!\r\nIf you change the point of suspension to the 40cm mark, the 8kg has a turning force of 320; so you could put 5kg at the 100cm mark giving a turning force of 5*60, and put 1kg at the 60cm mark, giving a turn of 1*20 =320 in total\r\n(There are other ways to do this if you chose a different point of suspension, but this is the key to the puzzle.)", "category": "Math", "date": "05/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA meter stick is suspended exactly at its 45 cm mark from a piece of string, and an 8kg is fixed to the stick and hangs from the 0cm mark. You have six 1kg weights you can hang anywhere on the stick (you can put more than one on the same point if you wish). How can you get the system to balance?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe turning force of the 8kg is 360\r\nThe max force on the other side would be if you put all 6 on the 100cm mark - 6*55 turning force = 330 Which isn't enough to balance, so the only way you can to this is by moving the point of suspension of the metre stick!\r\nIf you change the point of suspension to the 40cm mark, the 8kg has a turning force of 320; so you could put 5kg at the 100cm mark giving a turning force of 5*60, and put 1kg at the 60cm mark, giving a turn of 1*20 =320 in total\r\n(There are other ways to do this if you chose a different point of suspension, but this is the key to the puzzle.)\n<|im_start|>answer\nThe turning force of the 8kg is 360\r\nThe max force on the other side would be if you put all 6 on the 100cm mark - 6*55 turning force = 330 Which isn't enough to balance, so the only way you can to this is by moving the point of suspension of the metre stick!\r\nIf you change the point of suspension to the 40cm mark, the 8kg has a turning force of 320; so you could put 5kg at the 100cm mark giving a turning force of 5*60, and put 1kg at the 60cm mark, giving a turn of 1*20 =320 in total\r\n(There are other ways to do this if you chose a different point of suspension, but this is the key to the puzzle.)\n<|im_end|>" }, { "id": "#32298", "title": "Timmy's Birthday Dilemma", "fun": 2.24, "difficulty": 0.6900000000000001, "author": "Mellew", "desc": "Timmy was seven on his last birthday and he will be nine on his next birthday.\n\r\nCan this statement be true?", "hint": "No hint available.", "answer": "Yes. Today is Timmy's birthday.", "category": "Logic", "date": "08/05/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTimmy was seven on his last birthday and he will be nine on his next birthday.\n\r\nCan this statement be true?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes. Today is Timmy's birthday.\n<|im_start|>answer\nYes. Today is Timmy's birthday.\n<|im_end|>" }, { "id": "#33966", "title": "Pyramids By the Block", "fun": 2.24, "difficulty": 2.92, "author": "stil", "desc": "In a catalog, you read about a set of blocks. There are 1029 blocks; all are identical in volume. They can be assembled into several tiers which are 1 foot thick and stack to form a pyramid. (The pyramid has a square base; its four sides are equivalent isosceles triangles.) How tall is this pyramid?", "hint": "You might want to start at the top.", "answer": "It is 7 feet tall.\r\nThe top tier is also the peak. Suppose it is a single block and see how the numbers behave.\r\nIts four triangular surfaces share edges with its square base; the length of each such edge we will call b. (Assuming this length is 1 foot will also work.) The peak is a smaller pyramid so its volume, v1 = ( b * b * 1 ) / 3. Because a second tier will not change any of the angles involved, new triangles will be similar to old and all changes in measurement of length will be proportional. A pyramid 2 tiers tall would have v2 = ( 2*b * 2*b * 2 ) / 3 = 8*v1. For 3 tiers, v3 = ( 3*b * 3*b * 3 ) / 3 = 27*v1. It becomes clear that a cube number must be a factor of the number of blocks.\r\n1029 = 3 * 7^3, so there are 7 tiers. (The peak being formed by 3 separate blocks, every tier has 3 times as many blocks as in the supposition. Because 7 is a prime number, there is no smaller number of tiers which would satisfy the question.)", "category": "Math", "date": "11/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a catalog, you read about a set of blocks. There are 1029 blocks; all are identical in volume. They can be assembled into several tiers which are 1 foot thick and stack to form a pyramid. (The pyramid has a square base; its four sides are equivalent isosceles triangles.) How tall is this pyramid?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is 7 feet tall.\r\nThe top tier is also the peak. Suppose it is a single block and see how the numbers behave.\r\nIts four triangular surfaces share edges with its square base; the length of each such edge we will call b. (Assuming this length is 1 foot will also work.) The peak is a smaller pyramid so its volume, v1 = ( b * b * 1 ) / 3. Because a second tier will not change any of the angles involved, new triangles will be similar to old and all changes in measurement of length will be proportional. A pyramid 2 tiers tall would have v2 = ( 2*b * 2*b * 2 ) / 3 = 8*v1. For 3 tiers, v3 = ( 3*b * 3*b * 3 ) / 3 = 27*v1. It becomes clear that a cube number must be a factor of the number of blocks.\r\n1029 = 3 * 7^3, so there are 7 tiers. (The peak being formed by 3 separate blocks, every tier has 3 times as many blocks as in the supposition. Because 7 is a prime number, there is no smaller number of tiers which would satisfy the question.)\n<|im_start|>answer\nIt is 7 feet tall.\r\nThe top tier is also the peak. Suppose it is a single block and see how the numbers behave.\r\nIts four triangular surfaces share edges with its square base; the length of each such edge we will call b. (Assuming this length is 1 foot will also work.) The peak is a smaller pyramid so its volume, v1 = ( b * b * 1 ) / 3. Because a second tier will not change any of the angles involved, new triangles will be similar to old and all changes in measurement of length will be proportional. A pyramid 2 tiers tall would have v2 = ( 2*b * 2*b * 2 ) / 3 = 8*v1. For 3 tiers, v3 = ( 3*b * 3*b * 3 ) / 3 = 27*v1. It becomes clear that a cube number must be a factor of the number of blocks.\r\n1029 = 3 * 7^3, so there are 7 tiers. (The peak being formed by 3 separate blocks, every tier has 3 times as many blocks as in the supposition. Because 7 is a prime number, there is no smaller number of tiers which would satisfy the question.)\n<|im_end|>" }, { "id": "#24698", "title": "Kitty Katastrophe", "fun": 2.24, "difficulty": 0.44, "author": "babygurl4949", "desc": "There are three kittens named Kody, Kaleb, and Kraig. They all have different colored fur: orange, blue, and yellow. They also live in different houses: the hotel, the mansion, and the condo. You have to figure out the fur color of each kitten and which house they live in. \n\r\n1. Kody doesn't live in the condo.\n\r\n2. The cat that lives in the mansion doesn't have orange fur. \n\r\n3. Kaleb lives in the hotel.\n\r\n4. Kody's favorite color is blue, but that is not his fur color.\n\r\n5. The cat that lives in the hotel has orange fur.", "hint": "No hint available.", "answer": "Kody, yellow, mansion\r\nKaleb, orange, hotel\r\nKraig, blue, condo", "category": "Logic-Grid", "date": "07/20/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three kittens named Kody, Kaleb, and Kraig. They all have different colored fur: orange, blue, and yellow. They also live in different houses: the hotel, the mansion, and the condo. You have to figure out the fur color of each kitten and which house they live in. \n\r\n1. Kody doesn't live in the condo.\n\r\n2. The cat that lives in the mansion doesn't have orange fur. \n\r\n3. Kaleb lives in the hotel.\n\r\n4. Kody's favorite color is blue, but that is not his fur color.\n\r\n5. The cat that lives in the hotel has orange fur.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKody, yellow, mansion\r\nKaleb, orange, hotel\r\nKraig, blue, condo\n<|im_start|>answer\nKody, yellow, mansion\r\nKaleb, orange, hotel\r\nKraig, blue, condo\n<|im_end|>" }, { "id": "#10315", "title": "Another Mixture", "fun": 2.24, "difficulty": 1.75, "author": "ka-boom", "desc": "Dr. Joe has 2 liters of 70% benzene solution and 4 liters of 40% benzene solution. Dr. Joe decides to combine both solutions together, creating a 6-liter solution. What is the new percentage of benzene after everything is combined?", "hint": "No hint available.", "answer": "The new solution will be 50% benzene.\n\r\nFirst calculate the amount of benzene that you have:\r\n2(.70) = 1.4 liters in the 2-liter solution.\r\n4(.40) = 1.6 liters in the 4-liter solution.\n\r\nTo get the final percentage, add these up and divide by the total amount of solution:\n\r\n(1.4 + 1.6) / 6.0 = 0.5 = 50% solution.", "category": "Math", "date": "02/07/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDr. Joe has 2 liters of 70% benzene solution and 4 liters of 40% benzene solution. Dr. Joe decides to combine both solutions together, creating a 6-liter solution. What is the new percentage of benzene after everything is combined?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe new solution will be 50% benzene.\n\r\nFirst calculate the amount of benzene that you have:\r\n2(.70) = 1.4 liters in the 2-liter solution.\r\n4(.40) = 1.6 liters in the 4-liter solution.\n\r\nTo get the final percentage, add these up and divide by the total amount of solution:\n\r\n(1.4 + 1.6) / 6.0 = 0.5 = 50% solution.\n<|im_start|>answer\nThe new solution will be 50% benzene.\n\r\nFirst calculate the amount of benzene that you have:\r\n2(.70) = 1.4 liters in the 2-liter solution.\r\n4(.40) = 1.6 liters in the 4-liter solution.\n\r\nTo get the final percentage, add these up and divide by the total amount of solution:\n\r\n(1.4 + 1.6) / 6.0 = 0.5 = 50% solution.\n<|im_end|>" }, { "id": "#2403", "title": "Bricks", "fun": 2.24, "difficulty": 1.93, "author": "Mad-ade", "desc": "If one brick weighs 10 pounds plus half a brick, what does a brick and a half weigh?", "hint": "Imagine a set of scales balanced on one side by a full brick and on the other by a 10 pound weight and half a brick.", "answer": "30 pounds. One brick weighs 20 pounds.\r\nHalf a brick + 10 lbs = full brick(20lbs)", "category": "Math", "date": "02/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf one brick weighs 10 pounds plus half a brick, what does a brick and a half weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n30 pounds. One brick weighs 20 pounds.\r\nHalf a brick + 10 lbs = full brick(20lbs)\n<|im_start|>answer\n30 pounds. One brick weighs 20 pounds.\r\nHalf a brick + 10 lbs = full brick(20lbs)\n<|im_end|>" }, { "id": "#18614", "title": "Madadian Combined Cheese and Dog Show", "fun": 2.24, "difficulty": 2.35, "author": "mad-ade", "desc": "Mad Ade, Daft Derrick, Sue Denim, two pieces of Madadian \"Kebabrie\" Cheese, two pieces of Madadian \"Chillirella\" Cheese, and \"Beef Curry\" the dog were on their way to the annual Madadian combined Cheese and Dog show (it's Madadian, these things happen). \r\nMad Ade's \"Kebabretta\" scooter can only carry two objects at a time.\n\r\nMad Ade, Daft Derrick and Sue Denim can all drive the scooter. If Mad Ade is not around, Daft Derrick will eat the \"Kebabrie\"; if Daft Derrick is not around, Mad Ade will eat the \"Chillirella\". If Sue Denim is not around, \"Beef Curry\" will eat the cheese and bite Mad Ade and Daft Derrick.\n\r\nCan they all get to the Cheese/Dog show without anything bad happening?\n\r\nIf so, what's the smallest number of trips needed (each way counts as one trip)?", "hint": "No hint available.", "answer": "Yes, they can do it, and the smallest number of trips is 17. There are essentially two ways of doing this in 17 steps. One way is: \n\r\nSue Denim and \"Beef Curry\"; Sue Denim; Sue Denim and \"Kebabrie\"; Sue Denim and \"Beef Curry\"; Mad Ade and \"Kebabrie\"; Mad Ade; Daft Derrick and Mad Ade; Daft Derrick; Sue Denim and \"Beef Curry\"; Mad Ade; Daft Derrick and Mad Ade; Daft Derrick; Daft Derrick and \"Chillirella\"; Sue Denim and \"Beef Curry\"; Sue Denim and \"Chillirella\"; Sue Denim; Sue Denim and \"Beef Curry\". \n\r\nThe other method is to do this in reverse. Another way of looking at it is that we're swapping \"Kebabrie\" and \"Chillirella\", Daft Derrick and Mad Ade, since from the point of view of the other restrictions this changes nothing.", "category": "Logic", "date": "08/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade, Daft Derrick, Sue Denim, two pieces of Madadian \"Kebabrie\" Cheese, two pieces of Madadian \"Chillirella\" Cheese, and \"Beef Curry\" the dog were on their way to the annual Madadian combined Cheese and Dog show (it's Madadian, these things happen). \r\nMad Ade's \"Kebabretta\" scooter can only carry two objects at a time.\n\r\nMad Ade, Daft Derrick and Sue Denim can all drive the scooter. If Mad Ade is not around, Daft Derrick will eat the \"Kebabrie\"; if Daft Derrick is not around, Mad Ade will eat the \"Chillirella\". If Sue Denim is not around, \"Beef Curry\" will eat the cheese and bite Mad Ade and Daft Derrick.\n\r\nCan they all get to the Cheese/Dog show without anything bad happening?\n\r\nIf so, what's the smallest number of trips needed (each way counts as one trip)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes, they can do it, and the smallest number of trips is 17. There are essentially two ways of doing this in 17 steps. One way is: \n\r\nSue Denim and \"Beef Curry\"; Sue Denim; Sue Denim and \"Kebabrie\"; Sue Denim and \"Beef Curry\"; Mad Ade and \"Kebabrie\"; Mad Ade; Daft Derrick and Mad Ade; Daft Derrick; Sue Denim and \"Beef Curry\"; Mad Ade; Daft Derrick and Mad Ade; Daft Derrick; Daft Derrick and \"Chillirella\"; Sue Denim and \"Beef Curry\"; Sue Denim and \"Chillirella\"; Sue Denim; Sue Denim and \"Beef Curry\". \n\r\nThe other method is to do this in reverse. Another way of looking at it is that we're swapping \"Kebabrie\" and \"Chillirella\", Daft Derrick and Mad Ade, since from the point of view of the other restrictions this changes nothing.\n<|im_start|>answer\nYes, they can do it, and the smallest number of trips is 17. There are essentially two ways of doing this in 17 steps. One way is: \n\r\nSue Denim and \"Beef Curry\"; Sue Denim; Sue Denim and \"Kebabrie\"; Sue Denim and \"Beef Curry\"; Mad Ade and \"Kebabrie\"; Mad Ade; Daft Derrick and Mad Ade; Daft Derrick; Sue Denim and \"Beef Curry\"; Mad Ade; Daft Derrick and Mad Ade; Daft Derrick; Daft Derrick and \"Chillirella\"; Sue Denim and \"Beef Curry\"; Sue Denim and \"Chillirella\"; Sue Denim; Sue Denim and \"Beef Curry\". \n\r\nThe other method is to do this in reverse. Another way of looking at it is that we're swapping \"Kebabrie\" and \"Chillirella\", Daft Derrick and Mad Ade, since from the point of view of the other restrictions this changes nothing.\n<|im_end|>" }, { "id": "#10532", "title": "Buying Steaks", "fun": 2.24, "difficulty": 1.92, "author": "Bobbrt", "desc": "You are buying steaks at a butcher's. You see that he has 12 steaks: six worth $4 each and six worth $6 each. The butcher tells you, however, that if you let him pick the steaks he will charge you $4 apiece and if you pick the steaks he will charge you $6 apiece, no matter which steaks are chosen. What should you do to get the best deal?\n\r\nAssume that the actual number of steaks you purchase is of no concern, except for the butcher's deal. In other words you'd be just as happy buying 5 steaks as you would buying no steaks.", "hint": "No hint available.", "answer": "You should ask the butcher to give you eleven steaks, and let him choose.\n\r\nIf you choose the steaks, you will obviously pay the maximum price possible ($6 each), no matter how many steaks you buy.\n\r\nIf you let the butcher choose, he will pick the six $4 steaks first, so the only way you can make him give you some $6 steaks is to order more than six. Ordering all twelve would mean that you paid $4 per steak, averaging $5 each in value. You saved $1 per steak.\n\r\nHowever, if you order all 12 then you are technically choosing the steaks (because saying \"give me all of them\" is just a shorter way of saying \"give me that one, and that one, and...\"), so you would have to ask for 11 and let the butcher pick them at his discretion.", "category": "Logic", "date": "02/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are buying steaks at a butcher's. You see that he has 12 steaks: six worth $4 each and six worth $6 each. The butcher tells you, however, that if you let him pick the steaks he will charge you $4 apiece and if you pick the steaks he will charge you $6 apiece, no matter which steaks are chosen. What should you do to get the best deal?\n\r\nAssume that the actual number of steaks you purchase is of no concern, except for the butcher's deal. In other words you'd be just as happy buying 5 steaks as you would buying no steaks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou should ask the butcher to give you eleven steaks, and let him choose.\n\r\nIf you choose the steaks, you will obviously pay the maximum price possible ($6 each), no matter how many steaks you buy.\n\r\nIf you let the butcher choose, he will pick the six $4 steaks first, so the only way you can make him give you some $6 steaks is to order more than six. Ordering all twelve would mean that you paid $4 per steak, averaging $5 each in value. You saved $1 per steak.\n\r\nHowever, if you order all 12 then you are technically choosing the steaks (because saying \"give me all of them\" is just a shorter way of saying \"give me that one, and that one, and...\"), so you would have to ask for 11 and let the butcher pick them at his discretion.\n<|im_start|>answer\nYou should ask the butcher to give you eleven steaks, and let him choose.\n\r\nIf you choose the steaks, you will obviously pay the maximum price possible ($6 each), no matter how many steaks you buy.\n\r\nIf you let the butcher choose, he will pick the six $4 steaks first, so the only way you can make him give you some $6 steaks is to order more than six. Ordering all twelve would mean that you paid $4 per steak, averaging $5 each in value. You saved $1 per steak.\n\r\nHowever, if you order all 12 then you are technically choosing the steaks (because saying \"give me all of them\" is just a shorter way of saying \"give me that one, and that one, and...\"), so you would have to ask for 11 and let the butcher pick them at his discretion.\n<|im_end|>" }, { "id": "#41845", "title": "Four Men", "fun": 2.24, "difficulty": 0.96, "author": "brain23", "desc": "One day, a man in a coffee shop left his wallet filled with gold on the floor. Someone found it and asked who owned the wallet. Four men claimed it. If the men who don't have the gold are lying, and the one who has the gold is telling the truth, which one has the gold?\n\r\nBob: Joe owns the wallet.\r\nMike: I own the wallet.\r\nSteve: Bob owns the wallet.\r\nJoe: I own the wallet.", "hint": "No hint available.", "answer": "Mike owns the wallet. The way we can determine this is by looking at Bob's statement, which says Joe owns the wallet. Joe says he owns the wallet. If Bob is telling the truth, that means Joe owns the wallet, and Bob also owns the wallet since he is telling the truth. Since only 1 person has the wallet, Bob must be lying, and so is Joe. Steve also must be lying because he says Bob owns the wallet. Mike is the only one left, and he must be telling the truth.", "category": "Logic", "date": "05/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, a man in a coffee shop left his wallet filled with gold on the floor. Someone found it and asked who owned the wallet. Four men claimed it. If the men who don't have the gold are lying, and the one who has the gold is telling the truth, which one has the gold?\n\r\nBob: Joe owns the wallet.\r\nMike: I own the wallet.\r\nSteve: Bob owns the wallet.\r\nJoe: I own the wallet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike owns the wallet. The way we can determine this is by looking at Bob's statement, which says Joe owns the wallet. Joe says he owns the wallet. If Bob is telling the truth, that means Joe owns the wallet, and Bob also owns the wallet since he is telling the truth. Since only 1 person has the wallet, Bob must be lying, and so is Joe. Steve also must be lying because he says Bob owns the wallet. Mike is the only one left, and he must be telling the truth.\n<|im_start|>answer\nMike owns the wallet. The way we can determine this is by looking at Bob's statement, which says Joe owns the wallet. Joe says he owns the wallet. If Bob is telling the truth, that means Joe owns the wallet, and Bob also owns the wallet since he is telling the truth. Since only 1 person has the wallet, Bob must be lying, and so is Joe. Steve also must be lying because he says Bob owns the wallet. Mike is the only one left, and he must be telling the truth.\n<|im_end|>" }, { "id": "#24339", "title": "Big Happy Family", "fun": 2.24, "difficulty": 1.06, "author": "trickster2005", "desc": "Karen has four children that are different ages: 13, 7, 6 and 2. Each of the children has a favorite toy: a robot, cars, Lego's, and blocks. Also each of the children has a favorite holiday: Valentine's Day, Christmas, Thanksgiving and Mother's Day. \n\r\nWho's who and what do they like?\n\r\n1. Shaun is not old enough for school. She's also the youngest.\r\n2. Dashun does not understand Valentine's Day.\r\n3. Lego's are great for six year olds.\r\n4. Kris prefers cars.\r\n5. Marcy is in love for the first time, which means she loves February 14th.\r\n6. Kris is one of the middle children.\r\n7. Blocks are fun for toddlers.\r\n8. Thanksgiving is the best holiday for the six year old.\r\n9. The second child loves Christmas.", "hint": "No hint available.", "answer": "Marcy 13, Valentine's Day, robot\r\nKris 7, Christmas, cars\r\nDashun 6, Thanksgiving, Lego's.\r\nShaun 2, Mother's Day, blocks", "category": "Logic-Grid", "date": "07/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKaren has four children that are different ages: 13, 7, 6 and 2. Each of the children has a favorite toy: a robot, cars, Lego's, and blocks. Also each of the children has a favorite holiday: Valentine's Day, Christmas, Thanksgiving and Mother's Day. \n\r\nWho's who and what do they like?\n\r\n1. Shaun is not old enough for school. She's also the youngest.\r\n2. Dashun does not understand Valentine's Day.\r\n3. Lego's are great for six year olds.\r\n4. Kris prefers cars.\r\n5. Marcy is in love for the first time, which means she loves February 14th.\r\n6. Kris is one of the middle children.\r\n7. Blocks are fun for toddlers.\r\n8. Thanksgiving is the best holiday for the six year old.\r\n9. The second child loves Christmas.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMarcy 13, Valentine's Day, robot\r\nKris 7, Christmas, cars\r\nDashun 6, Thanksgiving, Lego's.\r\nShaun 2, Mother's Day, blocks\n<|im_start|>answer\nMarcy 13, Valentine's Day, robot\r\nKris 7, Christmas, cars\r\nDashun 6, Thanksgiving, Lego's.\r\nShaun 2, Mother's Day, blocks\n<|im_end|>" }, { "id": "#2020", "title": "Cressida", "fun": 2.24, "difficulty": 1.41, "author": "missie", "desc": "Cressida didn't like to tell her age, so when she was asked, her mother answered for her. Her mother said, \"I'm just seven times as old as she is now. In twenty years, she'll be just half the age that I will be then.\" \r\nHow old is clever little Cressida?", "hint": "No hint available.", "answer": "Cressida is four years old.", "category": "Math", "date": "01/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCressida didn't like to tell her age, so when she was asked, her mother answered for her. Her mother said, \"I'm just seven times as old as she is now. In twenty years, she'll be just half the age that I will be then.\" \r\nHow old is clever little Cressida?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCressida is four years old.\n<|im_start|>answer\nCressida is four years old.\n<|im_end|>" }, { "id": "#8961", "title": "Gossiping", "fun": 2.24, "difficulty": 2.73, "author": "lesternoronha1", "desc": "n people each know a different piece of gossip. They can telephone each other and exchange all the information they know (so that after the call they both know anything that either of them knew before the call). What is the smallest number of calls needed so that everyone knows everything?", "hint": "No hint available.", "answer": "1 for n=2\r\n3 for n=3\r\n2n-4 for n>=4\n\r\nThis can be achieved as follows: choose four people (A, B, C, and D) as the \"core group\". Each person outside the core group phones a member of the core group (it doesn't matter which); this takes n-4 calls. Now the core group makes 4 calls: A-B, C-D, A-C, and B-D. At this point, each member of the core group knows everything. Now, each person outside the core group calls anybody who knows everything; this again requires n-4 calls, for a total of 2n-4.", "category": "Math", "date": "12/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nn people each know a different piece of gossip. They can telephone each other and exchange all the information they know (so that after the call they both know anything that either of them knew before the call). What is the smallest number of calls needed so that everyone knows everything?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 for n=2\r\n3 for n=3\r\n2n-4 for n>=4\n\r\nThis can be achieved as follows: choose four people (A, B, C, and D) as the \"core group\". Each person outside the core group phones a member of the core group (it doesn't matter which); this takes n-4 calls. Now the core group makes 4 calls: A-B, C-D, A-C, and B-D. At this point, each member of the core group knows everything. Now, each person outside the core group calls anybody who knows everything; this again requires n-4 calls, for a total of 2n-4.\n<|im_start|>answer\n1 for n=2\r\n3 for n=3\r\n2n-4 for n>=4\n\r\nThis can be achieved as follows: choose four people (A, B, C, and D) as the \"core group\". Each person outside the core group phones a member of the core group (it doesn't matter which); this takes n-4 calls. Now the core group makes 4 calls: A-B, C-D, A-C, and B-D. At this point, each member of the core group knows everything. Now, each person outside the core group calls anybody who knows everything; this again requires n-4 calls, for a total of 2n-4.\n<|im_end|>" }, { "id": "#24909", "title": "Pizza Problem", "fun": 2.24, "difficulty": 2.0, "author": "DancAllNiteLong", "desc": "Xavier ordered a large pizza for lunch. The pizza had a diameter of 18 inches, and was cut into 8 pieces. Xavier ate 4 full pieces. But he only ate 1/4 of the fifth piece.\r\nLater on, Xavier felt very ill and went to see a doctor. The doctor couldn't help Xavier unless he knew the exact amount of pizza in his patient's stomach.\r\nWhat should Xavier tell his doctor?", "hint": "Use 3.141593 as pi. Don't round the decimals...the doctor needs to know the exact amount!", "answer": "Xavier ate 135.186658 sq. units of pizza.\r\nArea of pizza = 254.469005\r\n(8 pieces) 1 piece = 31.808626\r\n4 full pieces = 127.234502\r\n1/4 of one slice = 7.952156\r\n127.234502 + 7.952156 = 135.186658", "category": "Math", "date": "07/27/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nXavier ordered a large pizza for lunch. The pizza had a diameter of 18 inches, and was cut into 8 pieces. Xavier ate 4 full pieces. But he only ate 1/4 of the fifth piece.\r\nLater on, Xavier felt very ill and went to see a doctor. The doctor couldn't help Xavier unless he knew the exact amount of pizza in his patient's stomach.\r\nWhat should Xavier tell his doctor?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nXavier ate 135.186658 sq. units of pizza.\r\nArea of pizza = 254.469005\r\n(8 pieces) 1 piece = 31.808626\r\n4 full pieces = 127.234502\r\n1/4 of one slice = 7.952156\r\n127.234502 + 7.952156 = 135.186658\n<|im_start|>answer\nXavier ate 135.186658 sq. units of pizza.\r\nArea of pizza = 254.469005\r\n(8 pieces) 1 piece = 31.808626\r\n4 full pieces = 127.234502\r\n1/4 of one slice = 7.952156\r\n127.234502 + 7.952156 = 135.186658\n<|im_end|>" }, { "id": "#36804", "title": "Stand By Me", "fun": 2.24, "difficulty": 2.37, "author": "Battery", "desc": "John was trying to take a short cut through a very narrow tunnel when he heard the whistle of an approaching train behind him. Having reached three-eighths of the length of the tunnel, he could have turned back and cleared the entrance of the tunnel, running at 10 miles per hour, just as the train entered. Alternatively, if he kept running forward at that same rate of speed, the train would reach him the moment he would jump clear of the tracks. At what speed was the train moving?", "hint": "No hint available.", "answer": "At 40 miles per hour, the train would enter the tunnel when John was still two-eighths from the exit or a quarter of the tunnel's length. If the train was to reach him at the exit, it would have to travel at four times John's speed, i.e. 40 miles per hour.", "category": "Math", "date": "06/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn was trying to take a short cut through a very narrow tunnel when he heard the whistle of an approaching train behind him. Having reached three-eighths of the length of the tunnel, he could have turned back and cleared the entrance of the tunnel, running at 10 miles per hour, just as the train entered. Alternatively, if he kept running forward at that same rate of speed, the train would reach him the moment he would jump clear of the tracks. At what speed was the train moving?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt 40 miles per hour, the train would enter the tunnel when John was still two-eighths from the exit or a quarter of the tunnel's length. If the train was to reach him at the exit, it would have to travel at four times John's speed, i.e. 40 miles per hour.\n<|im_start|>answer\nAt 40 miles per hour, the train would enter the tunnel when John was still two-eighths from the exit or a quarter of the tunnel's length. If the train was to reach him at the exit, it would have to travel at four times John's speed, i.e. 40 miles per hour.\n<|im_end|>" }, { "id": "#4873", "title": "Overnight Lock Up", "fun": 2.24, "difficulty": 2.07, "author": "mad-ade", "desc": "Mad Ade and two of his friends ( Smelly Nelly and Strange Bob O'Flatulent) accidentally got themselves locked in the store room of the \"Sweaty Chef\" kebab shop overnight. After several minutes of being locked in, hunger struck and Mad Ade found some unguarded kebabs in a box. The three friends divided the kebabs equally. After all of them had eaten 4 kebabs each, the total number of kebabs remaining is equal to the number of kebabs each had after division. How many kebabs had Mad Ade found in the box?", "hint": "No hint available.", "answer": "18 \n\r\nAssume that initially there were 3*X Kebabs. \n\r\nSo they got X kebabs each after division. \n\r\nAll of them ate 4 kebabs. So now they have (X - 4) kebabs each. \n\r\nBut it is given that, after they ate 4 kebabs each, total number of kebabs remaining is equal to the kebabs each had after division i.e. X \n\r\nTherefore, the equation is \r\n3 * (X - 4) = X \r\n3 * X - 12 = X \r\n2 * X = 12 \r\nX = 6 \n\r\nTherefore the total kebabs before division is = 3 * X = 18. Although by the time they were released the next day a lot more kebabs and numerous cans of pop had mysteriously \"disappeared\"", "category": "Math", "date": "06/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade and two of his friends ( Smelly Nelly and Strange Bob O'Flatulent) accidentally got themselves locked in the store room of the \"Sweaty Chef\" kebab shop overnight. After several minutes of being locked in, hunger struck and Mad Ade found some unguarded kebabs in a box. The three friends divided the kebabs equally. After all of them had eaten 4 kebabs each, the total number of kebabs remaining is equal to the number of kebabs each had after division. How many kebabs had Mad Ade found in the box?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n18 \n\r\nAssume that initially there were 3*X Kebabs. \n\r\nSo they got X kebabs each after division. \n\r\nAll of them ate 4 kebabs. So now they have (X - 4) kebabs each. \n\r\nBut it is given that, after they ate 4 kebabs each, total number of kebabs remaining is equal to the kebabs each had after division i.e. X \n\r\nTherefore, the equation is \r\n3 * (X - 4) = X \r\n3 * X - 12 = X \r\n2 * X = 12 \r\nX = 6 \n\r\nTherefore the total kebabs before division is = 3 * X = 18. Although by the time they were released the next day a lot more kebabs and numerous cans of pop had mysteriously \"disappeared\"\n<|im_start|>answer\n18 \n\r\nAssume that initially there were 3*X Kebabs. \n\r\nSo they got X kebabs each after division. \n\r\nAll of them ate 4 kebabs. So now they have (X - 4) kebabs each. \n\r\nBut it is given that, after they ate 4 kebabs each, total number of kebabs remaining is equal to the kebabs each had after division i.e. X \n\r\nTherefore, the equation is \r\n3 * (X - 4) = X \r\n3 * X - 12 = X \r\n2 * X = 12 \r\nX = 6 \n\r\nTherefore the total kebabs before division is = 3 * X = 18. Although by the time they were released the next day a lot more kebabs and numerous cans of pop had mysteriously \"disappeared\"\n<|im_end|>" }, { "id": "#33593", "title": "Tie the Knot", "fun": 2.24, "difficulty": 1.73, "author": "say_aah", "desc": "Two thin ropes hang from the high ceiling of an empty room, just \r\nfar enough apart from each other that you cannot grab both at the\r\nsame time. How can you tie a knot with both ends using only a pair of scissors?", "hint": "The scissors do not need to be sharp to solve this.", "answer": "Tie the scissors to one of the ropes and swing it. Then grab the other rope and grab the scissors as they come towards you. Tie the knot.", "category": "Logic", "date": "10/21/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo thin ropes hang from the high ceiling of an empty room, just \r\nfar enough apart from each other that you cannot grab both at the\r\nsame time. How can you tie a knot with both ends using only a pair of scissors?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTie the scissors to one of the ropes and swing it. Then grab the other rope and grab the scissors as they come towards you. Tie the knot.\n<|im_start|>answer\nTie the scissors to one of the ropes and swing it. Then grab the other rope and grab the scissors as they come towards you. Tie the knot.\n<|im_end|>" }, { "id": "#6821", "title": "Profit", "fun": 2.24, "difficulty": 2.06, "author": "dumbell", "desc": "I will sell you 4 CD's for £15 or 7 CD's for £24. I don't mind which as I make the same profit on either deal. \n\r\nToday I sold 26 CD's. How much profit did I make?", "hint": "No hint available.", "answer": "£15.\n\r\nIf you write your info out as an equation:\n\r\n 7 CD's + profit = £24\r\n- 4 CD's + profit = £15\r\n _____________________\n\r\n 3 CD's = £9\n\r\nyou see that each CD costs £3. So 4 CD's cost £12 and my profit is £3. I said I make the same on either deal.\n\r\nThe only way I can sell 26 CD's is by 5 deals (3@4CD's & 2@7CD's). Making £3 on each means total profit is £15.", "category": "Math", "date": "08/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI will sell you 4 CD's for £15 or 7 CD's for £24. I don't mind which as I make the same profit on either deal. \n\r\nToday I sold 26 CD's. How much profit did I make?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n£15.\n\r\nIf you write your info out as an equation:\n\r\n 7 CD's + profit = £24\r\n- 4 CD's + profit = £15\r\n _____________________\n\r\n 3 CD's = £9\n\r\nyou see that each CD costs £3. So 4 CD's cost £12 and my profit is £3. I said I make the same on either deal.\n\r\nThe only way I can sell 26 CD's is by 5 deals (3@4CD's & 2@7CD's). Making £3 on each means total profit is £15.\n<|im_start|>answer\n£15.\n\r\nIf you write your info out as an equation:\n\r\n 7 CD's + profit = £24\r\n- 4 CD's + profit = £15\r\n _____________________\n\r\n 3 CD's = £9\n\r\nyou see that each CD costs £3. So 4 CD's cost £12 and my profit is £3. I said I make the same on either deal.\n\r\nThe only way I can sell 26 CD's is by 5 deals (3@4CD's & 2@7CD's). Making £3 on each means total profit is £15.\n<|im_end|>" }, { "id": "#9544", "title": "A Couple of Pets", "fun": 2.24, "difficulty": 0.96, "author": "IronMaiden980", "desc": "Speaking of her beloved pets, Jessica reports, \"He weighs exactly twice as much as she does and together they weigh 27 pounds.\" She also notes that her dog's weight is an odd number. How much do her dog and cat each weigh?", "hint": "No hint available.", "answer": "Little Ruffina the dog weighs in at a feathery 9 pounds while Tip the tomcat tilts the scale at 18 pounds.", "category": "Math", "date": "01/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSpeaking of her beloved pets, Jessica reports, \"He weighs exactly twice as much as she does and together they weigh 27 pounds.\" She also notes that her dog's weight is an odd number. How much do her dog and cat each weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLittle Ruffina the dog weighs in at a feathery 9 pounds while Tip the tomcat tilts the scale at 18 pounds.\n<|im_start|>answer\nLittle Ruffina the dog weighs in at a feathery 9 pounds while Tip the tomcat tilts the scale at 18 pounds.\n<|im_end|>" }, { "id": "#3520", "title": "Students in a Line", "fun": 2.24, "difficulty": 1.84, "author": "Tori", "desc": "Six students were in a line. The teacher gave them instructions on where to get in the line. Get in line according to the color of your hair and the color of your eyes. Lightest to darkest. Suzie had brown hair and green eyes. Sharon has yellow hair and orange eyes. Gil has orange hair and dark blue eyes. John has brown hair and yellow eyes. Tori has black hair and blue eyes. Vickie has yellow hair and brown eyes. What order were they in?", "hint": "No hint available.", "answer": "1.Sharon\r\n2.Vickie\r\n3.Gil\r\n4.John\r\n5.Suzie\r\n6. Tori", "category": "Logic", "date": "04/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix students were in a line. The teacher gave them instructions on where to get in the line. Get in line according to the color of your hair and the color of your eyes. Lightest to darkest. Suzie had brown hair and green eyes. Sharon has yellow hair and orange eyes. Gil has orange hair and dark blue eyes. John has brown hair and yellow eyes. Tori has black hair and blue eyes. Vickie has yellow hair and brown eyes. What order were they in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1.Sharon\r\n2.Vickie\r\n3.Gil\r\n4.John\r\n5.Suzie\r\n6. Tori\n<|im_start|>answer\n1.Sharon\r\n2.Vickie\r\n3.Gil\r\n4.John\r\n5.Suzie\r\n6. Tori\n<|im_end|>" }, { "id": "#3782", "title": "Cutting Classes", "fun": 2.24, "difficulty": 1.6, "author": "GoldieLuvNeopets", "desc": "Three classmates each had a day (Monday, Wednesday, or Friday) off school last week for a different reason. From the clues given below, can you identify their full names, say which day each missed, and work out the reason for his or her absence?\n\r\nClues:\n\r\n1. Daniel did not have Monday off, but he had to go to the hospital to have his broken arm put into plaster.\n\r\n2.Geraldine was off school earlier in the week than the pupil (last name Skipper) who had a heavy cold.\n\r\n3. Lucy's day off wasn't Wednesday, and the upset stomach was not mentioned in the note her mother (not the mother of Ms. Twagg) wrote explaining why she was absent.\n\r\nOther Info:\r\nSomeone else's surname is Hookey.", "hint": "Try putting this information into a grid, it's easier to work it out that way. Use elimination to figure it out.", "answer": "Name - Day Absent - Reason\r\nLucy Skipper - Friday - Heavy Cold\r\nDaniel Hookey - Wednesday - Broken Arm\r\nGeraldine Twagg - Monday - Upset Stomach", "category": "Logic", "date": "04/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree classmates each had a day (Monday, Wednesday, or Friday) off school last week for a different reason. From the clues given below, can you identify their full names, say which day each missed, and work out the reason for his or her absence?\n\r\nClues:\n\r\n1. Daniel did not have Monday off, but he had to go to the hospital to have his broken arm put into plaster.\n\r\n2.Geraldine was off school earlier in the week than the pupil (last name Skipper) who had a heavy cold.\n\r\n3. Lucy's day off wasn't Wednesday, and the upset stomach was not mentioned in the note her mother (not the mother of Ms. Twagg) wrote explaining why she was absent.\n\r\nOther Info:\r\nSomeone else's surname is Hookey.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName - Day Absent - Reason\r\nLucy Skipper - Friday - Heavy Cold\r\nDaniel Hookey - Wednesday - Broken Arm\r\nGeraldine Twagg - Monday - Upset Stomach\n<|im_start|>answer\nName - Day Absent - Reason\r\nLucy Skipper - Friday - Heavy Cold\r\nDaniel Hookey - Wednesday - Broken Arm\r\nGeraldine Twagg - Monday - Upset Stomach\n<|im_end|>" }, { "id": "#2168", "title": "Pound of Gold", "fun": 2.24, "difficulty": 1.41, "author": "Cascas", "desc": "Which would be worth more, a pound of $10 pure gold coins or half a pound of $20 pure gold coins; or would they be worth the same amount?", "hint": "No hint available.", "answer": "A pound of gold is always worth more than half a pound of gold.", "category": "Math", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich would be worth more, a pound of $10 pure gold coins or half a pound of $20 pure gold coins; or would they be worth the same amount?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA pound of gold is always worth more than half a pound of gold.\n<|im_start|>answer\nA pound of gold is always worth more than half a pound of gold.\n<|im_end|>" }, { "id": "#48373", "title": "More Calendar Cubes", "fun": 2.24, "difficulty": 1.8900000000000001, "author": "MarcM1098", "desc": "My grandmother has a pair of calendar cubes; each cube has six digits on it, one on each face.\r\nEvery morning, she re-arranges them to show the day of the month as a two-digit number (01 to 31).\n\r\nEven though some numbers appear on both cubes, you can easily tell them apart because one cube is ivory and the other is brown.\r\nI noticed that it was possible to use the ivory cube in the tens place and the brown cube in the ones place for SEVEN days in a row (within one month)!\r\nCan you figure out what digits are on each cube?", "hint": "Both cubes need a 1 (to form 11) and a 2 (to form 22).\r\nThe 0 must be paired with every other digit, so it must be on both cubes too.\r\nThis leaves six spaces (three on each die) to fit seven digits (3, 4, 5, 6, 7, 8, 9).\r\nOne digit can be re-used in an interesting way!", "answer": "The ivory cube has 012345; the brown cube has 012678.\r\nThe 6 on the brown cube is also a 9, just turn it upside-down!\n\r\nThere are two times each month where it is possible to keep the ivory cube in the tens place for seven days in a row:\r\n06 07 08 09 10 11 12 and 16 17 18 19 20 21 22.", "category": "Logic", "date": "01/10/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy grandmother has a pair of calendar cubes; each cube has six digits on it, one on each face.\r\nEvery morning, she re-arranges them to show the day of the month as a two-digit number (01 to 31).\n\r\nEven though some numbers appear on both cubes, you can easily tell them apart because one cube is ivory and the other is brown.\r\nI noticed that it was possible to use the ivory cube in the tens place and the brown cube in the ones place for SEVEN days in a row (within one month)!\r\nCan you figure out what digits are on each cube?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ivory cube has 012345; the brown cube has 012678.\r\nThe 6 on the brown cube is also a 9, just turn it upside-down!\n\r\nThere are two times each month where it is possible to keep the ivory cube in the tens place for seven days in a row:\r\n06 07 08 09 10 11 12 and 16 17 18 19 20 21 22.\n<|im_start|>answer\nThe ivory cube has 012345; the brown cube has 012678.\r\nThe 6 on the brown cube is also a 9, just turn it upside-down!\n\r\nThere are two times each month where it is possible to keep the ivory cube in the tens place for seven days in a row:\r\n06 07 08 09 10 11 12 and 16 17 18 19 20 21 22.\n<|im_end|>" }, { "id": "#9450", "title": "Mark's Sweets", "fun": 2.24, "difficulty": 1.42, "author": "SPRITEBABE44", "desc": "Mark has two younger sisters who each always get twice as many sweets as him. If Mark's mum gives them 30 sweets to \"share\" and each of his sisters give him 1/4 of their sweets, how many does he have left after feeding Rover, his dog, 1/3 of them and eating 1/4 of them left after Rover has eaten his share?", "hint": "No hint available.", "answer": "Six. He originally started with 6, but then receives another 6 after the donations from his sisters. He then has 12. He then gives his dog 4 sweets leaving him with 8 - after eating 1/4 of these, he has 6 sweets left - like he started with!!!", "category": "Math", "date": "12/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMark has two younger sisters who each always get twice as many sweets as him. If Mark's mum gives them 30 sweets to \"share\" and each of his sisters give him 1/4 of their sweets, how many does he have left after feeding Rover, his dog, 1/3 of them and eating 1/4 of them left after Rover has eaten his share?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSix. He originally started with 6, but then receives another 6 after the donations from his sisters. He then has 12. He then gives his dog 4 sweets leaving him with 8 - after eating 1/4 of these, he has 6 sweets left - like he started with!!!\n<|im_start|>answer\nSix. He originally started with 6, but then receives another 6 after the donations from his sisters. He then has 12. He then gives his dog 4 sweets leaving him with 8 - after eating 1/4 of these, he has 6 sweets left - like he started with!!!\n<|im_end|>" }, { "id": "#19588", "title": "Prime Directive", "fun": 2.24, "difficulty": 2.98, "author": "cnmne", "desc": "Arrange the numerals \"11337799\" to form an 8-digit number (referred to as \"ABCDEFGH\") that meets the following conditions:\n\r\n1) ABCDEFGH is a prime number\r\n2) HGFEDCBA (reversing the digits) is a prime number\r\n3) all consecutive 2-digit subsets of ABCDEFGH are prime numbers (AB, BC, CD, DE, EF, FG, GH are all prime)\r\n4) all consecutive 2-digit subsets of HGFEDCBA are prime numbers (HG, GF, FE, ED, DC, CB, BA are all prime)", "hint": "No hint available.", "answer": "97131379 (97, 71, 13, 31, 13, 37, 79) and its reverse 97313179 (97, 73, 31, 13, 31, 17, 79)\n\r\nThe only available 2-digit prime numbers are: 11, 13, 17, 19, 31, 37, 71, 73, 79, and 97. The number pairs that are prime in both directions are: 11/11, 13/31, 17/71, 37/73, and 79/97 (19 is eliminated since its reverse, 91, is not prime). With these numbers, it can be seen that 9 can only be paired with 7. Therefore, the solution must be of the form 97????79, 9797????, or ????7979. ???? must therefore be 1313, 3131, or 3113. This leaves the possible solution pairs of 97131379/97313179, 97971313/31317979, 97973131/13137979, 97973113/31137979, and 97311379/97311379 (the last pair being a palindrome). Of these, only 97131379 and its reverse, 97313179, are prime numbers.", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numerals \"11337799\" to form an 8-digit number (referred to as \"ABCDEFGH\") that meets the following conditions:\n\r\n1) ABCDEFGH is a prime number\r\n2) HGFEDCBA (reversing the digits) is a prime number\r\n3) all consecutive 2-digit subsets of ABCDEFGH are prime numbers (AB, BC, CD, DE, EF, FG, GH are all prime)\r\n4) all consecutive 2-digit subsets of HGFEDCBA are prime numbers (HG, GF, FE, ED, DC, CB, BA are all prime)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n97131379 (97, 71, 13, 31, 13, 37, 79) and its reverse 97313179 (97, 73, 31, 13, 31, 17, 79)\n\r\nThe only available 2-digit prime numbers are: 11, 13, 17, 19, 31, 37, 71, 73, 79, and 97. The number pairs that are prime in both directions are: 11/11, 13/31, 17/71, 37/73, and 79/97 (19 is eliminated since its reverse, 91, is not prime). With these numbers, it can be seen that 9 can only be paired with 7. Therefore, the solution must be of the form 97????79, 9797????, or ????7979. ???? must therefore be 1313, 3131, or 3113. This leaves the possible solution pairs of 97131379/97313179, 97971313/31317979, 97973131/13137979, 97973113/31137979, and 97311379/97311379 (the last pair being a palindrome). Of these, only 97131379 and its reverse, 97313179, are prime numbers.\n<|im_start|>answer\n97131379 (97, 71, 13, 31, 13, 37, 79) and its reverse 97313179 (97, 73, 31, 13, 31, 17, 79)\n\r\nThe only available 2-digit prime numbers are: 11, 13, 17, 19, 31, 37, 71, 73, 79, and 97. The number pairs that are prime in both directions are: 11/11, 13/31, 17/71, 37/73, and 79/97 (19 is eliminated since its reverse, 91, is not prime). With these numbers, it can be seen that 9 can only be paired with 7. Therefore, the solution must be of the form 97????79, 9797????, or ????7979. ???? must therefore be 1313, 3131, or 3113. This leaves the possible solution pairs of 97131379/97313179, 97971313/31317979, 97973131/13137979, 97973113/31137979, and 97311379/97311379 (the last pair being a palindrome). Of these, only 97131379 and its reverse, 97313179, are prime numbers.\n<|im_end|>" }, { "id": "#18776", "title": "Mad Ade's House Number", "fun": 2.24, "difficulty": 2.71, "author": "Mad-Ade", "desc": "Mad Ade lives on a long street In Sunny Madadia and he has noticed that the sum of the house numbers up to his own house, \"The Kebabers rest\", but excluding it, equals the sum of the numbers of his house to the end of the road. If the houses are numbered consecutively, starting from 1, what are the possible numbers of Mad Ade's house? \r\nThere are less than 1000 houses on the road.", "hint": "No hint available.", "answer": "There are four possible answers if the total number of Houses is no more than 1000.\r\nMad Ade's house could be #3 out of 3, #15 out of 20, #85 out of 119, or #493 out of 696.", "category": "Math", "date": "09/16/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade lives on a long street In Sunny Madadia and he has noticed that the sum of the house numbers up to his own house, \"The Kebabers rest\", but excluding it, equals the sum of the numbers of his house to the end of the road. If the houses are numbered consecutively, starting from 1, what are the possible numbers of Mad Ade's house? \r\nThere are less than 1000 houses on the road.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are four possible answers if the total number of Houses is no more than 1000.\r\nMad Ade's house could be #3 out of 3, #15 out of 20, #85 out of 119, or #493 out of 696.\n<|im_start|>answer\nThere are four possible answers if the total number of Houses is no more than 1000.\r\nMad Ade's house could be #3 out of 3, #15 out of 20, #85 out of 119, or #493 out of 696.\n<|im_end|>" }, { "id": "#4471", "title": "Broken Clock Face", "fun": 2.24, "difficulty": 1.93, "author": "mad-ade", "desc": "A clock on the wall falls to the floor and the face breaks into three pieces. The numbers on each piece add up to the same total. What are the numbers on each piece?", "hint": "The sum of the numbers on each piece is 26.", "answer": "piece 1: 11, 12, 1, 2 \r\npiece 2: 10, 3, 9, 4 \r\npiece 3: 5, 6, 7, 8", "category": "Math", "date": "06/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA clock on the wall falls to the floor and the face breaks into three pieces. The numbers on each piece add up to the same total. What are the numbers on each piece?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\npiece 1: 11, 12, 1, 2 \r\npiece 2: 10, 3, 9, 4 \r\npiece 3: 5, 6, 7, 8\n<|im_start|>answer\npiece 1: 11, 12, 1, 2 \r\npiece 2: 10, 3, 9, 4 \r\npiece 3: 5, 6, 7, 8\n<|im_end|>" }, { "id": "#30176", "title": "Multiple Divisors", "fun": 2.23, "difficulty": 2.94, "author": "cnmne", "desc": "Professor Abacus is looking for a number. The number must have 10 digits. It must contain all 10 numerals (0 through 9, once each). It must also be evenly divisible by all integers 2 through 18. Find one of the four possible solutions.", "hint": "No hint available.", "answer": "First, use prime factorization to determine the lowest common multiple (LCM).\n\r\n2 = 2\r\n3 = 3\r\n4 = 2 * 2\r\n5 = 5\r\n6 = 2 * 3\r\n7 = 7\r\n8 = 2 * 2 * 2\r\n9 = 3 * 3\r\n10 = 2 * 5\r\n11 = 11\r\n12 = 2 * 2 * 3\r\n13 = 13\r\n14 = 2 * 7\r\n15 = 3 * 5\r\n16 = 2 * 2 * 2 * 2\r\n17 = 17\r\n18 = 2 * 3 * 3\n\r\nLCM = 2 * 2 * 2 * 2 * 3 * 3 * 5 * 7 * 11 * 13 * 17 = 12252240.\n\r\nThe smallest 10-digit number that is a multiple of the LCM is 1004683680 (12252240 * 82). The largest 10-digit number that is a multiple of the LCM is 9997827840 (12252240 * 816). The solution must be somewhere between these two numbers.\n\r\nTo solve, multiply the LCM by each of the integers 82 through 816. The four solutions are:\n\r\n2438195760 = 12252240 * 199\r\n3785942160 = 12252240 * 309\r\n4753869120 = 12252240 * 388\r\n4876391520 = 12252240 * 398", "category": "Math", "date": "04/30/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nProfessor Abacus is looking for a number. The number must have 10 digits. It must contain all 10 numerals (0 through 9, once each). It must also be evenly divisible by all integers 2 through 18. Find one of the four possible solutions.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst, use prime factorization to determine the lowest common multiple (LCM).\n\r\n2 = 2\r\n3 = 3\r\n4 = 2 * 2\r\n5 = 5\r\n6 = 2 * 3\r\n7 = 7\r\n8 = 2 * 2 * 2\r\n9 = 3 * 3\r\n10 = 2 * 5\r\n11 = 11\r\n12 = 2 * 2 * 3\r\n13 = 13\r\n14 = 2 * 7\r\n15 = 3 * 5\r\n16 = 2 * 2 * 2 * 2\r\n17 = 17\r\n18 = 2 * 3 * 3\n\r\nLCM = 2 * 2 * 2 * 2 * 3 * 3 * 5 * 7 * 11 * 13 * 17 = 12252240.\n\r\nThe smallest 10-digit number that is a multiple of the LCM is 1004683680 (12252240 * 82). The largest 10-digit number that is a multiple of the LCM is 9997827840 (12252240 * 816). The solution must be somewhere between these two numbers.\n\r\nTo solve, multiply the LCM by each of the integers 82 through 816. The four solutions are:\n\r\n2438195760 = 12252240 * 199\r\n3785942160 = 12252240 * 309\r\n4753869120 = 12252240 * 388\r\n4876391520 = 12252240 * 398\n<|im_start|>answer\nFirst, use prime factorization to determine the lowest common multiple (LCM).\n\r\n2 = 2\r\n3 = 3\r\n4 = 2 * 2\r\n5 = 5\r\n6 = 2 * 3\r\n7 = 7\r\n8 = 2 * 2 * 2\r\n9 = 3 * 3\r\n10 = 2 * 5\r\n11 = 11\r\n12 = 2 * 2 * 3\r\n13 = 13\r\n14 = 2 * 7\r\n15 = 3 * 5\r\n16 = 2 * 2 * 2 * 2\r\n17 = 17\r\n18 = 2 * 3 * 3\n\r\nLCM = 2 * 2 * 2 * 2 * 3 * 3 * 5 * 7 * 11 * 13 * 17 = 12252240.\n\r\nThe smallest 10-digit number that is a multiple of the LCM is 1004683680 (12252240 * 82). The largest 10-digit number that is a multiple of the LCM is 9997827840 (12252240 * 816). The solution must be somewhere between these two numbers.\n\r\nTo solve, multiply the LCM by each of the integers 82 through 816. The four solutions are:\n\r\n2438195760 = 12252240 * 199\r\n3785942160 = 12252240 * 309\r\n4753869120 = 12252240 * 388\r\n4876391520 = 12252240 * 398\n<|im_end|>" }, { "id": "#11010", "title": "Kebab Line Up", "fun": 2.23, "difficulty": 2.85, "author": "mad-ade", "desc": "Four men are in a line at the Madadian Police station, charged with unlicensed kebab breeding. \r\nThe men are Mad Ade, Buster Artery, Cliff Hedge and Donny Moe - and they are standing in a straight line. \n\r\nOne man is fair, handsome and unscarred. \n\r\nTwo men who are not fair, are each standing next to Mad Ade \n\r\nBuster Artery is the only man standing next to exactly one handsome man. \n\r\nCliff Hedge is the only man not standing next to exactly one scarred man. \n\r\nWho is fair, handsome and unscarred?", "hint": "No hint available.", "answer": "Cliff Hedge is fair, handsome and unscarred. \n\r\nFrom (2), both the men standing next to Mad Ade are not fair. Also, exactly one man is fair, handsome and unscarred. Hence, there are two cases: \n\r\nCase 1 :: ? (N, ?, ?) : Mad Ade (Y, Y, N) : ? (N, ?, ?) : ? (?, ?, ?) \r\nCase 2 :: ? (N, ?, ?) : Mad Ade (?, ?, ?) : ? (N, ?, ?) : ? (Y, Y, N) \n\r\nNote the representation - Name (Fair, Handsome, Scarred). \"Y\" stands for Yes and \"N\" stands for No. Mad Ade (Y, Y, N) means Mad Ade is Fair, Handsome and Unscarred.(oh, how true this is..NOT) \n\r\nIt is clear that either Mad Ade or the man at the extreme right is fair, handsome and unscarred. \n\r\nFrom (4), it is deduced that Cliff Hedge is standing next to unscarred man and each of the other men standing next to exactly one scarred man. \n\r\nCase 1 :: Cliff Hedge (N, ?, N) : Mad Ade (Y, Y, N) : ? (N, ?, Y) : ? (?, ?, Y) \r\nCase 2 :: ? (N, ?, Y) : Mad Ade (?, ?, Y) : ? (N, ?, N) : Cliff Hedge (Y, Y, N) \n\r\nFrom (3), Buster Artery is the only man standing next to exactly one handsome man. But in Case 1, Cliff Hedge is standing next to exactly one handsome man. Hence, Case 1 is not possible and Case 2 is the correct one. \n\r\nCase 2 :: ? (N, ?, Y) : Mad Ade (?, ?, Y) : ? (N, ?, N) : Cliff Hedge (Y, Y, N) \n\r\nAgain from (3) and (4), there are 2 possibilities as shown below. \n\r\nCase 2a :: Donny Moe (N, N, Y) : Mad Ade (?, N, Y) : Buster Artery (N, N, N) : Cliff Hedge (Y, Y, N) \r\nCase 2b :: Buster Artery (N, N, Y) : Mad Ade (?, Y, Y) : Donny Moe (N, N, N) : Cliff Hedge (Y, Y, N) \n\r\nThus, Cliff Hedge is fair, handsome and unscarred. Also, Mad Ade may be either fair or not fair.", "category": "Logic", "date": "03/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour men are in a line at the Madadian Police station, charged with unlicensed kebab breeding. \r\nThe men are Mad Ade, Buster Artery, Cliff Hedge and Donny Moe - and they are standing in a straight line. \n\r\nOne man is fair, handsome and unscarred. \n\r\nTwo men who are not fair, are each standing next to Mad Ade \n\r\nBuster Artery is the only man standing next to exactly one handsome man. \n\r\nCliff Hedge is the only man not standing next to exactly one scarred man. \n\r\nWho is fair, handsome and unscarred?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCliff Hedge is fair, handsome and unscarred. \n\r\nFrom (2), both the men standing next to Mad Ade are not fair. Also, exactly one man is fair, handsome and unscarred. Hence, there are two cases: \n\r\nCase 1 :: ? (N, ?, ?) : Mad Ade (Y, Y, N) : ? (N, ?, ?) : ? (?, ?, ?) \r\nCase 2 :: ? (N, ?, ?) : Mad Ade (?, ?, ?) : ? (N, ?, ?) : ? (Y, Y, N) \n\r\nNote the representation - Name (Fair, Handsome, Scarred). \"Y\" stands for Yes and \"N\" stands for No. Mad Ade (Y, Y, N) means Mad Ade is Fair, Handsome and Unscarred.(oh, how true this is..NOT) \n\r\nIt is clear that either Mad Ade or the man at the extreme right is fair, handsome and unscarred. \n\r\nFrom (4), it is deduced that Cliff Hedge is standing next to unscarred man and each of the other men standing next to exactly one scarred man. \n\r\nCase 1 :: Cliff Hedge (N, ?, N) : Mad Ade (Y, Y, N) : ? (N, ?, Y) : ? (?, ?, Y) \r\nCase 2 :: ? (N, ?, Y) : Mad Ade (?, ?, Y) : ? (N, ?, N) : Cliff Hedge (Y, Y, N) \n\r\nFrom (3), Buster Artery is the only man standing next to exactly one handsome man. But in Case 1, Cliff Hedge is standing next to exactly one handsome man. Hence, Case 1 is not possible and Case 2 is the correct one. \n\r\nCase 2 :: ? (N, ?, Y) : Mad Ade (?, ?, Y) : ? (N, ?, N) : Cliff Hedge (Y, Y, N) \n\r\nAgain from (3) and (4), there are 2 possibilities as shown below. \n\r\nCase 2a :: Donny Moe (N, N, Y) : Mad Ade (?, N, Y) : Buster Artery (N, N, N) : Cliff Hedge (Y, Y, N) \r\nCase 2b :: Buster Artery (N, N, Y) : Mad Ade (?, Y, Y) : Donny Moe (N, N, N) : Cliff Hedge (Y, Y, N) \n\r\nThus, Cliff Hedge is fair, handsome and unscarred. Also, Mad Ade may be either fair or not fair.\n<|im_start|>answer\nCliff Hedge is fair, handsome and unscarred. \n\r\nFrom (2), both the men standing next to Mad Ade are not fair. Also, exactly one man is fair, handsome and unscarred. Hence, there are two cases: \n\r\nCase 1 :: ? (N, ?, ?) : Mad Ade (Y, Y, N) : ? (N, ?, ?) : ? (?, ?, ?) \r\nCase 2 :: ? (N, ?, ?) : Mad Ade (?, ?, ?) : ? (N, ?, ?) : ? (Y, Y, N) \n\r\nNote the representation - Name (Fair, Handsome, Scarred). \"Y\" stands for Yes and \"N\" stands for No. Mad Ade (Y, Y, N) means Mad Ade is Fair, Handsome and Unscarred.(oh, how true this is..NOT) \n\r\nIt is clear that either Mad Ade or the man at the extreme right is fair, handsome and unscarred. \n\r\nFrom (4), it is deduced that Cliff Hedge is standing next to unscarred man and each of the other men standing next to exactly one scarred man. \n\r\nCase 1 :: Cliff Hedge (N, ?, N) : Mad Ade (Y, Y, N) : ? (N, ?, Y) : ? (?, ?, Y) \r\nCase 2 :: ? (N, ?, Y) : Mad Ade (?, ?, Y) : ? (N, ?, N) : Cliff Hedge (Y, Y, N) \n\r\nFrom (3), Buster Artery is the only man standing next to exactly one handsome man. But in Case 1, Cliff Hedge is standing next to exactly one handsome man. Hence, Case 1 is not possible and Case 2 is the correct one. \n\r\nCase 2 :: ? (N, ?, Y) : Mad Ade (?, ?, Y) : ? (N, ?, N) : Cliff Hedge (Y, Y, N) \n\r\nAgain from (3) and (4), there are 2 possibilities as shown below. \n\r\nCase 2a :: Donny Moe (N, N, Y) : Mad Ade (?, N, Y) : Buster Artery (N, N, N) : Cliff Hedge (Y, Y, N) \r\nCase 2b :: Buster Artery (N, N, Y) : Mad Ade (?, Y, Y) : Donny Moe (N, N, N) : Cliff Hedge (Y, Y, N) \n\r\nThus, Cliff Hedge is fair, handsome and unscarred. Also, Mad Ade may be either fair or not fair.\n<|im_end|>" }, { "id": "#9246", "title": "Homeroom", "fun": 2.23, "difficulty": 2.34, "author": "something", "desc": "There are three teachers: Mrs. Shatto, Mrs. Watts, and Mrs. Peterson. There are four subjects: Math, Science, Social Studies, and English. All teachers teach their homeroom students what they teach all other kids. They also each teach one other thing. The students switch classes in the morning.\r\nMrs. Peterson teaches Science and English.\r\nMrs. Shatto teaches Math and Social Studies.\r\nMrs. Watts teaches Science and Social Studies.\r\nMrs. Shatto's kids do not get Social Studies taught to them in the morning.\r\nMrs. Peterson's kids get taught Social Studies and English in the morning.\n\r\nWhen does each teacher teach each subject and to who?", "hint": "No hint available.", "answer": "Mrs Peterson: Morning-English (everyone); Afternoon-Science (Peterson)\r\nMrs Shatto: Morning-Math (Everyone); Afternoon-Social Studies (Peterson)\r\nMrs Watts: Morning-Social Studies (Peterson) & Science (Shatto) Afternoon-Science (Watts)", "category": "Logic", "date": "12/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three teachers: Mrs. Shatto, Mrs. Watts, and Mrs. Peterson. There are four subjects: Math, Science, Social Studies, and English. All teachers teach their homeroom students what they teach all other kids. They also each teach one other thing. The students switch classes in the morning.\r\nMrs. Peterson teaches Science and English.\r\nMrs. Shatto teaches Math and Social Studies.\r\nMrs. Watts teaches Science and Social Studies.\r\nMrs. Shatto's kids do not get Social Studies taught to them in the morning.\r\nMrs. Peterson's kids get taught Social Studies and English in the morning.\n\r\nWhen does each teacher teach each subject and to who?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMrs Peterson: Morning-English (everyone); Afternoon-Science (Peterson)\r\nMrs Shatto: Morning-Math (Everyone); Afternoon-Social Studies (Peterson)\r\nMrs Watts: Morning-Social Studies (Peterson) & Science (Shatto) Afternoon-Science (Watts)\n<|im_start|>answer\nMrs Peterson: Morning-English (everyone); Afternoon-Science (Peterson)\r\nMrs Shatto: Morning-Math (Everyone); Afternoon-Social Studies (Peterson)\r\nMrs Watts: Morning-Social Studies (Peterson) & Science (Shatto) Afternoon-Science (Watts)\n<|im_end|>" }, { "id": "#41684", "title": "Two Thieves", "fun": 2.23, "difficulty": 1.61, "author": "Carlos16", "desc": "Haley, Octavio, Ray, and Kate are found in an alley at midnight and accused of robbing a house. If only the two thieves' statements are false, then who were the thieves?\n\r\nKate: It was Haley and Octavio.\r\nHaley: It was Kate and Ray.\r\nOctavio: It was Kate and I.\r\nRay: It wasn't me.", "hint": "No hint available.", "answer": "Octavio cannot be telling the truth since he is incriminating himself. Octavio must be lying, and Kate cannot be his partner. Since Kate is telling the truth, Haley and Octavio were the thieves.\n\r\nAnswer: Octavio and Haley", "category": "Logic", "date": "04/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHaley, Octavio, Ray, and Kate are found in an alley at midnight and accused of robbing a house. If only the two thieves' statements are false, then who were the thieves?\n\r\nKate: It was Haley and Octavio.\r\nHaley: It was Kate and Ray.\r\nOctavio: It was Kate and I.\r\nRay: It wasn't me.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOctavio cannot be telling the truth since he is incriminating himself. Octavio must be lying, and Kate cannot be his partner. Since Kate is telling the truth, Haley and Octavio were the thieves.\n\r\nAnswer: Octavio and Haley\n<|im_start|>answer\nOctavio cannot be telling the truth since he is incriminating himself. Octavio must be lying, and Kate cannot be his partner. Since Kate is telling the truth, Haley and Octavio were the thieves.\n\r\nAnswer: Octavio and Haley\n<|im_end|>" }, { "id": "#1961", "title": "Cats Except One", "fun": 2.23, "difficulty": 0.72, "author": "missie", "desc": "All Mrs. Pollywollyweisenheimer's pets are dogs except one, and all her pets are cats except one. How many dogs and cats does she have?", "hint": "No hint available.", "answer": "1 cat\r\n1 dog", "category": "Logic", "date": "01/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAll Mrs. Pollywollyweisenheimer's pets are dogs except one, and all her pets are cats except one. How many dogs and cats does she have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 cat\r\n1 dog\n<|im_start|>answer\n1 cat\r\n1 dog\n<|im_end|>" }, { "id": "#19155", "title": "The Chairman", "fun": 2.23, "difficulty": 1.79, "author": "lesternoronha1", "desc": "Five men among A, B, C, D and E sitting in this order at a round table had to decide as to who among them would be the chairman by voting. None of the five members voted for himself or his neighbors. The first ballot was a tie off. The second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory. Who voted for B in the first ballot?", "hint": "No hint available.", "answer": "D voted for B in the first ballot.\n\r\nA, B, C, D and E are sitting in this order at a round table.\n\r\nThe observations given are\r\n1) None of the five members voted for himself or his neighbors.\r\n2) The first ballot was a tie off.\r\n3) The second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory.\n\r\nFrom observation 1, we can deduce the following table for the first ballot:-\n\r\nPerson --> Voted for\r\nA --> D or C\r\nB --> E or D\r\nC --> A or E \t\r\nD --> A or B\r\nE --> B or C\n\r\nFrom observation 2, all of them must have got one vote each since the first ballot was a tie off. Now the above table can be split into one of the following two tables using observation 2.\n\r\nTable 1:\n\r\nPerson --> Voted for\r\nA --> D\r\nB --> E\r\nC --> A\r\nD --> B\r\nE --> C\n\r\n OR\n\r\nTable 2:\n\r\nPerson --> Voted for\r\nA --> C\r\nB --> D\r\nC --> E\r\nD --> A\r\nE --> B\n\r\nThe two tables above would ensure a tie-off for the first ballot. \n\r\nNow from observation 3, the second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory. This situation can emerge only if table 1 is the initial voting pattern and not table 2 (since from table 2, C anyway votes for E. If the others stuck to their choices, the second ballot would also result in a tie off). Keeping the initial pattern to be table 1, E won the second ballot because he received two votes from B and C.\n\r\nHence if table 1 was the initial voting pattern, then D voted for B in the first ballot.", "category": "Logic", "date": "10/21/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive men among A, B, C, D and E sitting in this order at a round table had to decide as to who among them would be the chairman by voting. None of the five members voted for himself or his neighbors. The first ballot was a tie off. The second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory. Who voted for B in the first ballot?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nD voted for B in the first ballot.\n\r\nA, B, C, D and E are sitting in this order at a round table.\n\r\nThe observations given are\r\n1) None of the five members voted for himself or his neighbors.\r\n2) The first ballot was a tie off.\r\n3) The second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory.\n\r\nFrom observation 1, we can deduce the following table for the first ballot:-\n\r\nPerson --> Voted for\r\nA --> D or C\r\nB --> E or D\r\nC --> A or E \t\r\nD --> A or B\r\nE --> B or C\n\r\nFrom observation 2, all of them must have got one vote each since the first ballot was a tie off. Now the above table can be split into one of the following two tables using observation 2.\n\r\nTable 1:\n\r\nPerson --> Voted for\r\nA --> D\r\nB --> E\r\nC --> A\r\nD --> B\r\nE --> C\n\r\n OR\n\r\nTable 2:\n\r\nPerson --> Voted for\r\nA --> C\r\nB --> D\r\nC --> E\r\nD --> A\r\nE --> B\n\r\nThe two tables above would ensure a tie-off for the first ballot. \n\r\nNow from observation 3, the second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory. This situation can emerge only if table 1 is the initial voting pattern and not table 2 (since from table 2, C anyway votes for E. If the others stuck to their choices, the second ballot would also result in a tie off). Keeping the initial pattern to be table 1, E won the second ballot because he received two votes from B and C.\n\r\nHence if table 1 was the initial voting pattern, then D voted for B in the first ballot.\n<|im_start|>answer\nD voted for B in the first ballot.\n\r\nA, B, C, D and E are sitting in this order at a round table.\n\r\nThe observations given are\r\n1) None of the five members voted for himself or his neighbors.\r\n2) The first ballot was a tie off.\r\n3) The second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory.\n\r\nFrom observation 1, we can deduce the following table for the first ballot:-\n\r\nPerson --> Voted for\r\nA --> D or C\r\nB --> E or D\r\nC --> A or E \t\r\nD --> A or B\r\nE --> B or C\n\r\nFrom observation 2, all of them must have got one vote each since the first ballot was a tie off. Now the above table can be split into one of the following two tables using observation 2.\n\r\nTable 1:\n\r\nPerson --> Voted for\r\nA --> D\r\nB --> E\r\nC --> A\r\nD --> B\r\nE --> C\n\r\n OR\n\r\nTable 2:\n\r\nPerson --> Voted for\r\nA --> C\r\nB --> D\r\nC --> E\r\nD --> A\r\nE --> B\n\r\nThe two tables above would ensure a tie-off for the first ballot. \n\r\nNow from observation 3, the second time, C voted for E while the others stuck to their old choices, thereby resulting in E's victory. This situation can emerge only if table 1 is the initial voting pattern and not table 2 (since from table 2, C anyway votes for E. If the others stuck to their choices, the second ballot would also result in a tie off). Keeping the initial pattern to be table 1, E won the second ballot because he received two votes from B and C.\n\r\nHence if table 1 was the initial voting pattern, then D voted for B in the first ballot.\n<|im_end|>" }, { "id": "#19048", "title": "Romankachi Goodies !!!", "fun": 2.23, "difficulty": 1.98, "author": "lesternoronha1", "desc": "Last week, I'd been to the famous Romankachi cookie store \"Cookie World\" and found that there were three types of cookies to my liking - kachie costing $11 each, chococook costing $7 each and peacon costing $8 each. I had spent any amount between $45 and $50 (Both values inclusive). In how many ways could I have purchased the items, if I wanted to purchase at least one of each type of cookie ?", "hint": "No hint available.", "answer": "There are 6 ways.\n\r\nSince it is given that one item each has to be definitely bought, the minimum amount spent by me was $11 + $7 + $8 = $26. Using this minimum amount I should have bought at least one kachie, one chococook and one peacon cookies.\n\r\nSince my total expenditure was $45 to $50, the extra amount I still have to spend (after having spent the minimum amount of $26) is $19 to $24, both $45 and $50 inclusive.\n\r\nThis extra amount can be spent in 6 possible ways as shown below :-\r\n1) 2*11 = $22 (two kachie cookies). \r\n2) 1*11 + 1*8 = $19 (one kachie cookie and one peacon cookie).\r\n3) 2*7 + 1*8 = $22 (two chococook cookies and one peacon cookie).\r\n4) 2*8 + 1*7 = $23 (two peacon cookies and one chococook cookie).\r\n5) 7*3 = $21 (three chococook cookies)\r\n6) 8*3 = $24 (three peacon cookies).\n\r\nHence there are six ways of spending the extra amount.", "category": "Logic", "date": "10/05/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast week, I'd been to the famous Romankachi cookie store \"Cookie World\" and found that there were three types of cookies to my liking - kachie costing $11 each, chococook costing $7 each and peacon costing $8 each. I had spent any amount between $45 and $50 (Both values inclusive). In how many ways could I have purchased the items, if I wanted to purchase at least one of each type of cookie ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 6 ways.\n\r\nSince it is given that one item each has to be definitely bought, the minimum amount spent by me was $11 + $7 + $8 = $26. Using this minimum amount I should have bought at least one kachie, one chococook and one peacon cookies.\n\r\nSince my total expenditure was $45 to $50, the extra amount I still have to spend (after having spent the minimum amount of $26) is $19 to $24, both $45 and $50 inclusive.\n\r\nThis extra amount can be spent in 6 possible ways as shown below :-\r\n1) 2*11 = $22 (two kachie cookies). \r\n2) 1*11 + 1*8 = $19 (one kachie cookie and one peacon cookie).\r\n3) 2*7 + 1*8 = $22 (two chococook cookies and one peacon cookie).\r\n4) 2*8 + 1*7 = $23 (two peacon cookies and one chococook cookie).\r\n5) 7*3 = $21 (three chococook cookies)\r\n6) 8*3 = $24 (three peacon cookies).\n\r\nHence there are six ways of spending the extra amount.\n<|im_start|>answer\nThere are 6 ways.\n\r\nSince it is given that one item each has to be definitely bought, the minimum amount spent by me was $11 + $7 + $8 = $26. Using this minimum amount I should have bought at least one kachie, one chococook and one peacon cookies.\n\r\nSince my total expenditure was $45 to $50, the extra amount I still have to spend (after having spent the minimum amount of $26) is $19 to $24, both $45 and $50 inclusive.\n\r\nThis extra amount can be spent in 6 possible ways as shown below :-\r\n1) 2*11 = $22 (two kachie cookies). \r\n2) 1*11 + 1*8 = $19 (one kachie cookie and one peacon cookie).\r\n3) 2*7 + 1*8 = $22 (two chococook cookies and one peacon cookie).\r\n4) 2*8 + 1*7 = $23 (two peacon cookies and one chococook cookie).\r\n5) 7*3 = $21 (three chococook cookies)\r\n6) 8*3 = $24 (three peacon cookies).\n\r\nHence there are six ways of spending the extra amount.\n<|im_end|>" }, { "id": "#1058", "title": "Used Car", "fun": 2.23, "difficulty": 1.12, "author": "Michelle", "desc": "Michelle Knaw bought a used car for $600 and sold it for $800. She later bought it back for $1000 and resold it for $1200. Did Michelle make any profit and if so how much?", "hint": "No hint available.", "answer": "At first it appears that Michelle made a profit of $200, however this is not the case. Michelle made a total profit of $400 since she made $200 profit each time she sold the car.", "category": "Math", "date": "10/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMichelle Knaw bought a used car for $600 and sold it for $800. She later bought it back for $1000 and resold it for $1200. Did Michelle make any profit and if so how much?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt first it appears that Michelle made a profit of $200, however this is not the case. Michelle made a total profit of $400 since she made $200 profit each time she sold the car.\n<|im_start|>answer\nAt first it appears that Michelle made a profit of $200, however this is not the case. Michelle made a total profit of $400 since she made $200 profit each time she sold the car.\n<|im_end|>" }, { "id": "#48683", "title": "The Four Integers II", "fun": 2.23, "difficulty": 1.96, "author": "Mathgeek007", "desc": "Using the below 5 clues, what four integers am I thinking of?\n\r\nThe lowest integer divided by the second-lowest is the highest.\n\r\nOnly one integer is positive.\n\r\nThey are all single-digited.\n\r\nThe sum of all the numbers is -7.\n\r\nThe second highest number is not a negative.", "hint": "No hint available.", "answer": "2, 0, -3, -6.\n\r\nBased on the info...\n\r\nOne integer is positive. The highest. If the second is not negative, and there is only one positive, it must be 0.\n\r\nThe sum is -7.\n\r\n-6 / -3 = 2", "category": "Math", "date": "05/09/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the below 5 clues, what four integers am I thinking of?\n\r\nThe lowest integer divided by the second-lowest is the highest.\n\r\nOnly one integer is positive.\n\r\nThey are all single-digited.\n\r\nThe sum of all the numbers is -7.\n\r\nThe second highest number is not a negative.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2, 0, -3, -6.\n\r\nBased on the info...\n\r\nOne integer is positive. The highest. If the second is not negative, and there is only one positive, it must be 0.\n\r\nThe sum is -7.\n\r\n-6 / -3 = 2\n<|im_start|>answer\n2, 0, -3, -6.\n\r\nBased on the info...\n\r\nOne integer is positive. The highest. If the second is not negative, and there is only one positive, it must be 0.\n\r\nThe sum is -7.\n\r\n-6 / -3 = 2\n<|im_end|>" }, { "id": "#20456", "title": "Color Cars", "fun": 2.23, "difficulty": 1.49, "author": "akronone85", "desc": "An old man was sitting down on his front yard watching cars go by for the remainder of the day. The first car to go past was a red car, to which he responded \"nice\". A few minutes later an orange car goes by, and he said \"pretty\". After another few minutes a yellow car goes by and the man said \"man! The next car is going to be easy\". The next car goes by and it was the right color car the man was hoping for. What should the color of the last car be?", "hint": "No hint available.", "answer": "The color is green since the cars are going by the colors of the rainbow.", "category": "Logic", "date": "01/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn old man was sitting down on his front yard watching cars go by for the remainder of the day. The first car to go past was a red car, to which he responded \"nice\". A few minutes later an orange car goes by, and he said \"pretty\". After another few minutes a yellow car goes by and the man said \"man! The next car is going to be easy\". The next car goes by and it was the right color car the man was hoping for. What should the color of the last car be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe color is green since the cars are going by the colors of the rainbow.\n<|im_start|>answer\nThe color is green since the cars are going by the colors of the rainbow.\n<|im_end|>" }, { "id": "#8586", "title": "Prime Operations", "fun": 2.23, "difficulty": 2.18, "author": "lesternoronha1", "desc": "Solve the following with the conditions given :-\n\r\n D A\r\n - B C\r\n ------\r\n B D\n\r\na) All the numbers used A, B, C and D are prime.\r\nb) The answer BD is also a prime number.\r\nc) The numbers DA and BC are not prime.\r\nd) Also the number A < C.\r\nFind the numbers A, B, C and D.", "hint": "No hint available.", "answer": "The computation above is nothing but\n\r\n 72\r\n - 35\r\n -----\r\n 37", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSolve the following with the conditions given :-\n\r\n D A\r\n - B C\r\n ------\r\n B D\n\r\na) All the numbers used A, B, C and D are prime.\r\nb) The answer BD is also a prime number.\r\nc) The numbers DA and BC are not prime.\r\nd) Also the number A < C.\r\nFind the numbers A, B, C and D.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe computation above is nothing but\n\r\n 72\r\n - 35\r\n -----\r\n 37\n<|im_start|>answer\nThe computation above is nothing but\n\r\n 72\r\n - 35\r\n -----\r\n 37\n<|im_end|>" }, { "id": "#3430", "title": "Egg Drop", "fun": 2.23, "difficulty": 1.77, "author": "tech_guy5", "desc": "An egg has to fall 100 feet, but it can't break upon landing (or in the air). Its fall can't be slowed down, nor can its landing be cushioned in any way. How is it done?", "hint": "No hint available.", "answer": "Drop it from more than 100 feet high. It won't break for the first 100 feet.", "category": "Logic", "date": "04/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn egg has to fall 100 feet, but it can't break upon landing (or in the air). Its fall can't be slowed down, nor can its landing be cushioned in any way. How is it done?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDrop it from more than 100 feet high. It won't break for the first 100 feet.\n<|im_start|>answer\nDrop it from more than 100 feet high. It won't break for the first 100 feet.\n<|im_end|>" }, { "id": "#46201", "title": "Cobbler Street Neighborhood", "fun": 2.23, "difficulty": 0.85, "author": "nidhikaila", "desc": "On Cobbler Street, 4 people live in different colored houses. Each of them has exactly one pet and exactly one car. From the clues given below, see if you can figure out what goes where.\n\r\n1. Smith loves walking his pet dog every morning, and he stops by at Hannah's for a coffee afterwards. \r\n2. The yellow house has a Chevy in the garage and Charlie, the owner, often talks of selling it. \r\n3. The owner of the Audi has a really tiny pet. \r\n4. The red house has a Ford in the garage. \r\n5. The owner of the white house has a goldfish for a pet. \r\n6. The sqeaky clean rat is Beth's pride as a pet. \r\n7. The cat is the most aggressive pet on the block, though she is pretty agreeable when the rat stops by. \r\n8. Smith drives a Ford to work, and his neighbor drives a Ferrari.\r\n9 The owner of the brown house does not own a Ferrari.", "hint": "No hint available.", "answer": "Smith lives in a red house, drives a Ford and has a dog. \r\nHannah lives in a white house, drives a Ferrari and has a goldfish. \r\nCharlie lives in a yellow house, drives a Chevy and has a cat. \r\nBeth lives in a brown house, drives an Audi and has a rat.", "category": "Logic-Grid", "date": "01/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Cobbler Street, 4 people live in different colored houses. Each of them has exactly one pet and exactly one car. From the clues given below, see if you can figure out what goes where.\n\r\n1. Smith loves walking his pet dog every morning, and he stops by at Hannah's for a coffee afterwards. \r\n2. The yellow house has a Chevy in the garage and Charlie, the owner, often talks of selling it. \r\n3. The owner of the Audi has a really tiny pet. \r\n4. The red house has a Ford in the garage. \r\n5. The owner of the white house has a goldfish for a pet. \r\n6. The sqeaky clean rat is Beth's pride as a pet. \r\n7. The cat is the most aggressive pet on the block, though she is pretty agreeable when the rat stops by. \r\n8. Smith drives a Ford to work, and his neighbor drives a Ferrari.\r\n9 The owner of the brown house does not own a Ferrari.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSmith lives in a red house, drives a Ford and has a dog. \r\nHannah lives in a white house, drives a Ferrari and has a goldfish. \r\nCharlie lives in a yellow house, drives a Chevy and has a cat. \r\nBeth lives in a brown house, drives an Audi and has a rat.\n<|im_start|>answer\nSmith lives in a red house, drives a Ford and has a dog. \r\nHannah lives in a white house, drives a Ferrari and has a goldfish. \r\nCharlie lives in a yellow house, drives a Chevy and has a cat. \r\nBeth lives in a brown house, drives an Audi and has a rat.\n<|im_end|>" }, { "id": "#18777", "title": "Even More Mad Ade Clocks", "fun": 2.23, "difficulty": 2.42, "author": "Mad-Ade", "desc": "Mad Ade sat at home, waiting for his favourite TV program \"I'm a celebrity, Get me a Kebab\" to start. He glanced at his clock and began to wonder strange and wondrous things, but that is another story altogether. \r\nHe realised that he could leave 6 adjacent numbers of the face of a clock intact and rearrange the other 6 in such a way that the sum of every pair of adjacent numbers is prime. \r\nUnfortunately the TV program started at that point so he never actually got around to doing it. Can you find the two possible solutions to Mad Ade's clock teaser?", "hint": "No hint available.", "answer": "Imagining the number on a clock face in a clockwise order they would be\n\r\n1 2 3 4 7 10 9 8 5 6 11 12\r\nOr\r\n1 2 3 4 9 10 7 6 5 8 11 12", "category": "Logic", "date": "09/13/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade sat at home, waiting for his favourite TV program \"I'm a celebrity, Get me a Kebab\" to start. He glanced at his clock and began to wonder strange and wondrous things, but that is another story altogether. \r\nHe realised that he could leave 6 adjacent numbers of the face of a clock intact and rearrange the other 6 in such a way that the sum of every pair of adjacent numbers is prime. \r\nUnfortunately the TV program started at that point so he never actually got around to doing it. Can you find the two possible solutions to Mad Ade's clock teaser?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nImagining the number on a clock face in a clockwise order they would be\n\r\n1 2 3 4 7 10 9 8 5 6 11 12\r\nOr\r\n1 2 3 4 9 10 7 6 5 8 11 12\n<|im_start|>answer\nImagining the number on a clock face in a clockwise order they would be\n\r\n1 2 3 4 7 10 9 8 5 6 11 12\r\nOr\r\n1 2 3 4 9 10 7 6 5 8 11 12\n<|im_end|>" }, { "id": "#2952", "title": "Low Ball", "fun": 2.23, "difficulty": 1.8900000000000001, "author": "rohddawg", "desc": "In bowling, if you are playing a game of low ball, what is the best possible score you can achieve?", "hint": "In low ball if you throw a gutter ball or hit no pins it automatically counts as a strike or spare.", "answer": "20\r\nThe best you can do is to hit 1 pin on each throw of a ball. 10 frames, 2 balls per frame. 20 points.", "category": "Logic", "date": "03/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn bowling, if you are playing a game of low ball, what is the best possible score you can achieve?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20\r\nThe best you can do is to hit 1 pin on each throw of a ball. 10 frames, 2 balls per frame. 20 points.\n<|im_start|>answer\n20\r\nThe best you can do is to hit 1 pin on each throw of a ball. 10 frames, 2 balls per frame. 20 points.\n<|im_end|>" }, { "id": "#776", "title": "Who Is Telling The Truth?", "fun": 2.23, "difficulty": 1.14, "author": "Nike01", "desc": "The judge listened to the four well-known crooks and said, \"You're lying your heads off!\" The officer laughed and said: \"I happen to know ONE of these crooks IS telling the truth.\" The judge snapped: \"Well, what do you have to say in defense, you crooks?\"\n\r\nAl said: \"Only one of us is lying.\"\r\nSal: \"No, I tell you, just two of us are lying.\"\r\nCal: \"Look here, three of us are lying.\"\r\nTom: \"Nope, not true! Four of us are telling the truth.\"\n\r\nSo which one IS telling the truth?", "hint": "No hint available.", "answer": "Cal is telling the truth.", "category": "Logic", "date": "08/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe judge listened to the four well-known crooks and said, \"You're lying your heads off!\" The officer laughed and said: \"I happen to know ONE of these crooks IS telling the truth.\" The judge snapped: \"Well, what do you have to say in defense, you crooks?\"\n\r\nAl said: \"Only one of us is lying.\"\r\nSal: \"No, I tell you, just two of us are lying.\"\r\nCal: \"Look here, three of us are lying.\"\r\nTom: \"Nope, not true! Four of us are telling the truth.\"\n\r\nSo which one IS telling the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCal is telling the truth.\n<|im_start|>answer\nCal is telling the truth.\n<|im_end|>" }, { "id": "#17090", "title": "Find the Number 2", "fun": 2.23, "difficulty": 1.9000000000000001, "author": "liltunalol", "desc": "Find the five-digit number in which the first digit is one less than the second and three times the third, the second digit is two less than the fourth, and the second and third digits, when added together, make the fourth. The sum of all digits is 25.", "hint": "The sum, 25, will let you find the last digit.", "answer": "67,291", "category": "Math", "date": "03/20/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the five-digit number in which the first digit is one less than the second and three times the third, the second digit is two less than the fourth, and the second and third digits, when added together, make the fourth. The sum of all digits is 25.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n67,291\n<|im_start|>answer\n67,291\n<|im_end|>" }, { "id": "#8613", "title": "Driving Through the Country", "fun": 2.23, "difficulty": 1.55, "author": "lesternoronha1", "desc": "I decided to drive through the country leisurely. On the first day I did only 7 miles. On the last day I did 51 miles increasing my journey 4 miles each day. How many days did I travel and how far?", "hint": "No hint available.", "answer": "Actually this can be done by Arithmetic Progression taking the first term as 7 and the difference as 4. We use the formula \r\n Sn = (a+l)n/2\r\n where n=12, a=7 and l=51\r\n Also last term is given as 51. 348 miles in 12 days", "category": "Math", "date": "11/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI decided to drive through the country leisurely. On the first day I did only 7 miles. On the last day I did 51 miles increasing my journey 4 miles each day. How many days did I travel and how far?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nActually this can be done by Arithmetic Progression taking the first term as 7 and the difference as 4. We use the formula \r\n Sn = (a+l)n/2\r\n where n=12, a=7 and l=51\r\n Also last term is given as 51. 348 miles in 12 days\n<|im_start|>answer\nActually this can be done by Arithmetic Progression taking the first term as 7 and the difference as 4. We use the formula \r\n Sn = (a+l)n/2\r\n where n=12, a=7 and l=51\r\n Also last term is given as 51. 348 miles in 12 days\n<|im_end|>" }, { "id": "#4806", "title": "Cheeky Mice", "fun": 2.23, "difficulty": 1.07, "author": "mad-ade", "desc": "Five mice Squeeky, Tweeky, Shuffles, Muffles, and Derek were nibbling at Mad Ade's Kebab on the kitchen table, but \"Cooking Fat,\" Mad Ade's cat chased them back into their hole. Shuffles made it back third, and Derek was fourth. Muffles was after Derek, and Tweeky was not second. Which mouse was first, and which was last?", "hint": "No hint available.", "answer": "Tweeky was first and Muffles was last.", "category": "Logic", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive mice Squeeky, Tweeky, Shuffles, Muffles, and Derek were nibbling at Mad Ade's Kebab on the kitchen table, but \"Cooking Fat,\" Mad Ade's cat chased them back into their hole. Shuffles made it back third, and Derek was fourth. Muffles was after Derek, and Tweeky was not second. Which mouse was first, and which was last?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTweeky was first and Muffles was last.\n<|im_start|>answer\nTweeky was first and Muffles was last.\n<|im_end|>" }, { "id": "#4785", "title": "Moving Escalator", "fun": 2.23, "difficulty": 2.06, "author": "mad-ade", "desc": "If it takes Mad Ade 2 minutes to walk up a moving escalator in the same direction as the escalator, but 6 minutes - at the very same pace - down the same escalator, how much faster than the escalator is Mad Ade walking.", "hint": "No hint available.", "answer": "Mad Ade is walking twice as fast as the escalator\n\r\nMad Ade's average speed upwards is just the average speed of his walking (call this W) plus the average speed of the escalator (call this E); and his average speed down is just the average speed of his walking minus plus the average speed of the escalator.\n\r\nSo \n\r\nTime to walk up 2(W + E) = time to walk down 6(W - E)\n\r\nThis reduces to W = 2E\n\r\nor twice as fast as the escalator", "category": "Math", "date": "06/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf it takes Mad Ade 2 minutes to walk up a moving escalator in the same direction as the escalator, but 6 minutes - at the very same pace - down the same escalator, how much faster than the escalator is Mad Ade walking.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade is walking twice as fast as the escalator\n\r\nMad Ade's average speed upwards is just the average speed of his walking (call this W) plus the average speed of the escalator (call this E); and his average speed down is just the average speed of his walking minus plus the average speed of the escalator.\n\r\nSo \n\r\nTime to walk up 2(W + E) = time to walk down 6(W - E)\n\r\nThis reduces to W = 2E\n\r\nor twice as fast as the escalator\n<|im_start|>answer\nMad Ade is walking twice as fast as the escalator\n\r\nMad Ade's average speed upwards is just the average speed of his walking (call this W) plus the average speed of the escalator (call this E); and his average speed down is just the average speed of his walking minus plus the average speed of the escalator.\n\r\nSo \n\r\nTime to walk up 2(W + E) = time to walk down 6(W - E)\n\r\nThis reduces to W = 2E\n\r\nor twice as fast as the escalator\n<|im_end|>" }, { "id": "#18052", "title": "Mad Ade's Bank Account", "fun": 2.23, "difficulty": 1.71, "author": "mad-ade", "desc": "Mad Ade went to the Madadian National Bank and checked his account there. He noted that he had 300 Madadian wonks (local currency), before he made a deposit, in his account. \r\nAt the same time Nutty Norman, Mad Ade's friend, was at the bank and noted that he had 450 Madadian Wonks in his account before making a withdrawal.\n\r\nOutside Mad Ade and Nutty Norman were chatting and they discovered a couple of interesting facts.\r\n1, After they had both made their respective transactions they both ended up having the same account balance.\r\n2, The percentage increase in Mad Ade's account was the same as the decrease in Nutty Normans account.\n\r\nSo what was the account balance of each account and respective percentage changes of Mad Ade's and Nutty Normans accounts?", "hint": "No hint available.", "answer": "1. Mad Ade's account increased by 20% that means 60 Wonks so total 360 Wonks \n\r\n2. Nutty Norman's withdrawal percent is 20% that means 90 Wonks so balance is 360 Wonks. \n\r\nso both have same account balance of 360 Madadian Wonks, and the increase and decreased percentage for each account was 20%\n\r\n300 + 60(20% of 300) = 360 \r\n450 - 90(20% of 450) = 360", "category": "Math", "date": "06/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade went to the Madadian National Bank and checked his account there. He noted that he had 300 Madadian wonks (local currency), before he made a deposit, in his account. \r\nAt the same time Nutty Norman, Mad Ade's friend, was at the bank and noted that he had 450 Madadian Wonks in his account before making a withdrawal.\n\r\nOutside Mad Ade and Nutty Norman were chatting and they discovered a couple of interesting facts.\r\n1, After they had both made their respective transactions they both ended up having the same account balance.\r\n2, The percentage increase in Mad Ade's account was the same as the decrease in Nutty Normans account.\n\r\nSo what was the account balance of each account and respective percentage changes of Mad Ade's and Nutty Normans accounts?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. Mad Ade's account increased by 20% that means 60 Wonks so total 360 Wonks \n\r\n2. Nutty Norman's withdrawal percent is 20% that means 90 Wonks so balance is 360 Wonks. \n\r\nso both have same account balance of 360 Madadian Wonks, and the increase and decreased percentage for each account was 20%\n\r\n300 + 60(20% of 300) = 360 \r\n450 - 90(20% of 450) = 360\n<|im_start|>answer\n1. Mad Ade's account increased by 20% that means 60 Wonks so total 360 Wonks \n\r\n2. Nutty Norman's withdrawal percent is 20% that means 90 Wonks so balance is 360 Wonks. \n\r\nso both have same account balance of 360 Madadian Wonks, and the increase and decreased percentage for each account was 20%\n\r\n300 + 60(20% of 300) = 360 \r\n450 - 90(20% of 450) = 360\n<|im_end|>" }, { "id": "#42783", "title": "What's My Number 2", "fun": 2.23, "difficulty": 1.11, "author": "Magical_Faeire", "desc": "What's my number?\n\r\nI am a three digit number. My tens digit is five more than my ones digit. My hundreds digit is eight less than my tens digit. What number am I?", "hint": "No hint available.", "answer": "194", "category": "Math", "date": "08/12/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat's my number?\n\r\nI am a three digit number. My tens digit is five more than my ones digit. My hundreds digit is eight less than my tens digit. What number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n194\n<|im_start|>answer\n194\n<|im_end|>" }, { "id": "#22606", "title": "Rainbow Reasoning", "fun": 2.23, "difficulty": 1.83, "author": "Tammy93", "desc": "It is a little known fact that due to an error in the original design of the rainbow, the order of the colors- red, orange, yellow, green, blue, indigo, violet- is actually incorrect!\n\r\nConsider the letters of \"rainbow\"\n\r\nR A I N B O W\n\r\nPlace one and only one color under each of the seven letter so that each color is under a letter that it contains. Now consider only their first letters.\r\nIf there are no adjacent vowels then the correct order is _ _ _ _ _ _ _", "hint": "No hint available.", "answer": "ROVGBIY\r\n(Red, orAnge, vIolet, greeN, Blue, indigO, yelloW.)", "category": "Logic", "date": "05/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt is a little known fact that due to an error in the original design of the rainbow, the order of the colors- red, orange, yellow, green, blue, indigo, violet- is actually incorrect!\n\r\nConsider the letters of \"rainbow\"\n\r\nR A I N B O W\n\r\nPlace one and only one color under each of the seven letter so that each color is under a letter that it contains. Now consider only their first letters.\r\nIf there are no adjacent vowels then the correct order is _ _ _ _ _ _ _\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nROVGBIY\r\n(Red, orAnge, vIolet, greeN, Blue, indigO, yelloW.)\n<|im_start|>answer\nROVGBIY\r\n(Red, orAnge, vIolet, greeN, Blue, indigO, yelloW.)\n<|im_end|>" }, { "id": "#48707", "title": "Symbolistic I", "fun": 2.23, "difficulty": 1.67, "author": "Mathgeek007", "desc": "I will give you a group of numbers with an equals sign somewhere in the middle. Your goal is to add addition, subtraction, multiplication and division signs to make a true math statement. For example:\n\r\n45=731\n\r\nThe answer is...\n\r\n4+5=7+3-1\n\r\nGet it? Here's your puzzle.\n\r\n453402=1022", "hint": "Each side is equal to 51.", "answer": "453-402=102/2", "category": "Math", "date": "05/09/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI will give you a group of numbers with an equals sign somewhere in the middle. Your goal is to add addition, subtraction, multiplication and division signs to make a true math statement. For example:\n\r\n45=731\n\r\nThe answer is...\n\r\n4+5=7+3-1\n\r\nGet it? Here's your puzzle.\n\r\n453402=1022\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n453-402=102/2\n<|im_start|>answer\n453-402=102/2\n<|im_end|>" }, { "id": "#2107", "title": "(6 ? 3)", "fun": 2.23, "difficulty": 1.76, "author": "ChemicalBoy08", "desc": "Can you replace the question marks with math symbols and make the equation correct: \n\r\n(6 ? 3) ? 2 ? (4 ? 3) = 6", "hint": "No hint available.", "answer": "(6 + 3) * 2 - (4 * 3) = 6\r\nor\r\n(6 - 3) * 2 * (4 - 3) = 6\r\nor\r\n(6 - 3) + 2 + (4 - 3) = 6.", "category": "Math", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you replace the question marks with math symbols and make the equation correct: \n\r\n(6 ? 3) ? 2 ? (4 ? 3) = 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(6 + 3) * 2 - (4 * 3) = 6\r\nor\r\n(6 - 3) * 2 * (4 - 3) = 6\r\nor\r\n(6 - 3) + 2 + (4 - 3) = 6.\n<|im_start|>answer\n(6 + 3) * 2 - (4 * 3) = 6\r\nor\r\n(6 - 3) * 2 * (4 - 3) = 6\r\nor\r\n(6 - 3) + 2 + (4 - 3) = 6.\n<|im_end|>" }, { "id": "#29717", "title": "Eighth Powers", "fun": 2.23, "difficulty": 2.87, "author": "shenqiang", "desc": "There are three 8-digit natural numbers, each of them equals the sum of the eighth powers of its digits.\n\r\nTwo of them are:\n\r\n24678050=256+65536+1679616+5764801+16777216+0+390625+0\r\n88593477=16777216+16777216+390625+43046721+6561+65536+5764801+5764801\n\r\nDo you know what the remaining one is? It does not begin with 0, otherwise it isn't an 8-digit number.", "hint": "It is between 24678050 and 88593477.", "answer": "24678051.", "category": "Math", "date": "04/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three 8-digit natural numbers, each of them equals the sum of the eighth powers of its digits.\n\r\nTwo of them are:\n\r\n24678050=256+65536+1679616+5764801+16777216+0+390625+0\r\n88593477=16777216+16777216+390625+43046721+6561+65536+5764801+5764801\n\r\nDo you know what the remaining one is? It does not begin with 0, otherwise it isn't an 8-digit number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n24678051.\n<|im_start|>answer\n24678051.\n<|im_end|>" }, { "id": "#19766", "title": "Color Riddle", "fun": 2.23, "difficulty": 1.71, "author": "icepenguin13", "desc": "Which one of the colors (not all of that color, just one part of a group) should be changed to make the pattern correct : \n\r\n1) Black : Red \r\n2) Blue : White \r\n3) Yellow : Black \r\n4) Red : Red \r\n5) Black : White \r\n6) Blue : Black \r\n7) Yellow: Red \r\n8) Red : Blue \r\n9) Black : Black \r\n10) Blue : Red \r\n11) Yellow : White \r\n12) Red : Black", "hint": "No hint available.", "answer": "The latter part of # 8 should be white. The pattern on the left goes black, blue, yellow, red, black, etc, and the pattern on the right goes red, white, black, red, etc.", "category": "Logic", "date": "12/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich one of the colors (not all of that color, just one part of a group) should be changed to make the pattern correct : \n\r\n1) Black : Red \r\n2) Blue : White \r\n3) Yellow : Black \r\n4) Red : Red \r\n5) Black : White \r\n6) Blue : Black \r\n7) Yellow: Red \r\n8) Red : Blue \r\n9) Black : Black \r\n10) Blue : Red \r\n11) Yellow : White \r\n12) Red : Black\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe latter part of # 8 should be white. The pattern on the left goes black, blue, yellow, red, black, etc, and the pattern on the right goes red, white, black, red, etc.\n<|im_start|>answer\nThe latter part of # 8 should be white. The pattern on the left goes black, blue, yellow, red, black, etc, and the pattern on the right goes red, white, black, red, etc.\n<|im_end|>" }, { "id": "#5212", "title": "Tricycles", "fun": 2.23, "difficulty": 1.29, "author": "michelle", "desc": "There are a total of 14 bicycles and tricycles. If the total number of wheels is 34, how many tricycles are there?", "hint": "No hint available.", "answer": "2(b) + 3(t) = 34\r\n[2 * bicycles + 3 * tricycles = amount of wheels]\n\r\nb + t = 14\r\n[bicycles + tricycles = 14]\n\r\nManipulate the second equation to exclude a variable:\n\r\nb + t - t = 14 - t\r\nb = 14 - t\n\r\nThen combine the two statements to keep true and solve:\n\r\n2(14 - t) + 3(t) = 34\r\n28 - 2t + 3t = 34\r\nt = 6\n\r\nIf b = 14 - t\r\nb = 14 - 8\r\nb = 8\n\r\nTherefore there are 6 tricycles and 8 bicycles.", "category": "Math", "date": "07/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are a total of 14 bicycles and tricycles. If the total number of wheels is 34, how many tricycles are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2(b) + 3(t) = 34\r\n[2 * bicycles + 3 * tricycles = amount of wheels]\n\r\nb + t = 14\r\n[bicycles + tricycles = 14]\n\r\nManipulate the second equation to exclude a variable:\n\r\nb + t - t = 14 - t\r\nb = 14 - t\n\r\nThen combine the two statements to keep true and solve:\n\r\n2(14 - t) + 3(t) = 34\r\n28 - 2t + 3t = 34\r\nt = 6\n\r\nIf b = 14 - t\r\nb = 14 - 8\r\nb = 8\n\r\nTherefore there are 6 tricycles and 8 bicycles.\n<|im_start|>answer\n2(b) + 3(t) = 34\r\n[2 * bicycles + 3 * tricycles = amount of wheels]\n\r\nb + t = 14\r\n[bicycles + tricycles = 14]\n\r\nManipulate the second equation to exclude a variable:\n\r\nb + t - t = 14 - t\r\nb = 14 - t\n\r\nThen combine the two statements to keep true and solve:\n\r\n2(14 - t) + 3(t) = 34\r\n28 - 2t + 3t = 34\r\nt = 6\n\r\nIf b = 14 - t\r\nb = 14 - 8\r\nb = 8\n\r\nTherefore there are 6 tricycles and 8 bicycles.\n<|im_end|>" }, { "id": "#5689", "title": "Casket Test", "fun": 2.23, "difficulty": 1.8800000000000001, "author": "glennyboy02", "desc": "You are one of many young men claiming the right to the throne. A simple test is devised to see who will become King. If you pass the test you will be King, however, if you fail, you will lose your life. Three caskets are placed in front of you, a gold casket, a silver casket and a lead casket. Two of these caskets contain a skull and cross bones representing death, while the other contains the King's crown. Each casket has an inscription.\n\r\nGold- Who chooseth me shall gain what many men desire.\r\nSilver- Who chooseth me shall get as much as he deserves.\r\nLead- Who chooseth me must give and hazard all he hath.\n\r\nWhich casket leads to death, which leads to glory, your fate is in your own hands!", "hint": "No hint available.", "answer": "If you chose the gold casket you were wrong as: \r\n'All that glisters is not gold,\r\nOften have you heard that told;\r\nMany a man his life hath sold\r\nHad you been as wise as bold,\r\nYoung in limbs, in judgment old,\r\nYour answer had not been inscrolled \r\nFare you well, your suit is cold.'\n\r\nIf you chose the silver casket you were wrong as:\r\n'The fire seven times tried this;\r\nSeven times tried that judgment is\r\nThat did never choose amiss.\r\nSome there be that shadows kiss;\r\nSuch have but a shadow's bliss;\r\nThere be fools alive, I wis'\r\nSilvered over, and so was this.\n\r\nIf you chose the leaden casket you would be King as:\r\n'You that choose not by the view,\r\nChance as fair and choose as true!\r\nSince this fortune falls to you,\r\nBe content and seek no new.'", "category": "Logic", "date": "07/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are one of many young men claiming the right to the throne. A simple test is devised to see who will become King. If you pass the test you will be King, however, if you fail, you will lose your life. Three caskets are placed in front of you, a gold casket, a silver casket and a lead casket. Two of these caskets contain a skull and cross bones representing death, while the other contains the King's crown. Each casket has an inscription.\n\r\nGold- Who chooseth me shall gain what many men desire.\r\nSilver- Who chooseth me shall get as much as he deserves.\r\nLead- Who chooseth me must give and hazard all he hath.\n\r\nWhich casket leads to death, which leads to glory, your fate is in your own hands!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you chose the gold casket you were wrong as: \r\n'All that glisters is not gold,\r\nOften have you heard that told;\r\nMany a man his life hath sold\r\nHad you been as wise as bold,\r\nYoung in limbs, in judgment old,\r\nYour answer had not been inscrolled \r\nFare you well, your suit is cold.'\n\r\nIf you chose the silver casket you were wrong as:\r\n'The fire seven times tried this;\r\nSeven times tried that judgment is\r\nThat did never choose amiss.\r\nSome there be that shadows kiss;\r\nSuch have but a shadow's bliss;\r\nThere be fools alive, I wis'\r\nSilvered over, and so was this.\n\r\nIf you chose the leaden casket you would be King as:\r\n'You that choose not by the view,\r\nChance as fair and choose as true!\r\nSince this fortune falls to you,\r\nBe content and seek no new.'\n<|im_start|>answer\nIf you chose the gold casket you were wrong as: \r\n'All that glisters is not gold,\r\nOften have you heard that told;\r\nMany a man his life hath sold\r\nHad you been as wise as bold,\r\nYoung in limbs, in judgment old,\r\nYour answer had not been inscrolled \r\nFare you well, your suit is cold.'\n\r\nIf you chose the silver casket you were wrong as:\r\n'The fire seven times tried this;\r\nSeven times tried that judgment is\r\nThat did never choose amiss.\r\nSome there be that shadows kiss;\r\nSuch have but a shadow's bliss;\r\nThere be fools alive, I wis'\r\nSilvered over, and so was this.\n\r\nIf you chose the leaden casket you would be King as:\r\n'You that choose not by the view,\r\nChance as fair and choose as true!\r\nSince this fortune falls to you,\r\nBe content and seek no new.'\n<|im_end|>" }, { "id": "#42861", "title": "A Bad Day at PizzaShop", "fun": 2.23, "difficulty": 0.73, "author": "brainyboy615", "desc": "PizzaShop was having a great day when the order forms for three customers were misplaced! Fortunately, the employees taking the orders remember a few small details. Help PizzaShop and you could win free pizza for a month! Do you have what it takes to get PizzaShop out of this plight?\n\r\nClues: \n\r\n1. The three people are Mr. Smith, the man with the large pizza, and the man with the sausage pizza. \n\r\n2. Mr. Woods ordered a pepperoni pizza.\n\r\n3. The cheese pizza was larger than at least one other pizza.", "hint": "Mr. Woods has a big family.", "answer": "Mr. Smith ordered a medium cheese pizza.\n\r\nMr. Jones ordered a small sausage pizza.\n\r\nMr. Woods ordered a large pepperoni pizza.", "category": "Logic-Grid", "date": "08/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPizzaShop was having a great day when the order forms for three customers were misplaced! Fortunately, the employees taking the orders remember a few small details. Help PizzaShop and you could win free pizza for a month! Do you have what it takes to get PizzaShop out of this plight?\n\r\nClues: \n\r\n1. The three people are Mr. Smith, the man with the large pizza, and the man with the sausage pizza. \n\r\n2. Mr. Woods ordered a pepperoni pizza.\n\r\n3. The cheese pizza was larger than at least one other pizza.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Smith ordered a medium cheese pizza.\n\r\nMr. Jones ordered a small sausage pizza.\n\r\nMr. Woods ordered a large pepperoni pizza.\n<|im_start|>answer\nMr. Smith ordered a medium cheese pizza.\n\r\nMr. Jones ordered a small sausage pizza.\n\r\nMr. Woods ordered a large pepperoni pizza.\n<|im_end|>" }, { "id": "#38874", "title": "True or False", "fun": 2.23, "difficulty": 2.8, "author": "shenqiang", "desc": "Choose true or false to these statements, and your choices must be consistent.\n\r\n1. You chose \"True\" at most once. \r\n2. You chose \"False\" at most once. \r\n3. You chose \"True\" at most twice. \r\n4. You chose \"False\" at most twice. \r\n5. You chose \"True\" at most three times. \r\n6. You chose \"False\" at most three times. \r\n7. You chose \"True\" at most four times. \r\n8. You chose \"False\" at most four times. \r\n9. You chose \"True\" at most five times. \r\n10. You chose \"False\" at most five times.", "hint": "How many statements do you choose true, and how many statements do you choose false?", "answer": "You can't choose true in both statements 1 and 2, at least one of them must be false. Similar logic exists in statements 3 and 4, and 5 and 6.\n\r\nStatements 7 and 10 are contradictory, you must choose one of them true and the other false. Similar logic exists in statements 8 and 9.\n\r\nTherefore, you choose \"false\" at least 5 times and \"true\" at least 2 times. By trial and error you see that statements 5, 7 and 9 are true, and the others are false.", "category": "Logic", "date": "10/21/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nChoose true or false to these statements, and your choices must be consistent.\n\r\n1. You chose \"True\" at most once. \r\n2. You chose \"False\" at most once. \r\n3. You chose \"True\" at most twice. \r\n4. You chose \"False\" at most twice. \r\n5. You chose \"True\" at most three times. \r\n6. You chose \"False\" at most three times. \r\n7. You chose \"True\" at most four times. \r\n8. You chose \"False\" at most four times. \r\n9. You chose \"True\" at most five times. \r\n10. You chose \"False\" at most five times.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou can't choose true in both statements 1 and 2, at least one of them must be false. Similar logic exists in statements 3 and 4, and 5 and 6.\n\r\nStatements 7 and 10 are contradictory, you must choose one of them true and the other false. Similar logic exists in statements 8 and 9.\n\r\nTherefore, you choose \"false\" at least 5 times and \"true\" at least 2 times. By trial and error you see that statements 5, 7 and 9 are true, and the others are false.\n<|im_start|>answer\nYou can't choose true in both statements 1 and 2, at least one of them must be false. Similar logic exists in statements 3 and 4, and 5 and 6.\n\r\nStatements 7 and 10 are contradictory, you must choose one of them true and the other false. Similar logic exists in statements 8 and 9.\n\r\nTherefore, you choose \"false\" at least 5 times and \"true\" at least 2 times. By trial and error you see that statements 5, 7 and 9 are true, and the others are false.\n<|im_end|>" }, { "id": "#1848", "title": "Three Days", "fun": 2.23, "difficulty": 1.44, "author": "missie", "desc": "Last week, it took me three days to go from A to B, but then four days to go from B to A. What are A and B?", "hint": "No hint available.", "answer": "Sunday and Wednesday", "category": "Logic", "date": "12/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast week, it took me three days to go from A to B, but then four days to go from B to A. What are A and B?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSunday and Wednesday\n<|im_start|>answer\nSunday and Wednesday\n<|im_end|>" }, { "id": "#1218", "title": "Magic Cup", "fun": 2.23, "difficulty": 1.27, "author": "jennifer", "desc": "If a magician holds a cup above his head and it is filled to the top, how is it possible that when he drops this cup, no water comes out?", "hint": "No hint available.", "answer": "The cup does not contain water. It has some other liquid in it.", "category": "Logic", "date": "10/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a magician holds a cup above his head and it is filled to the top, how is it possible that when he drops this cup, no water comes out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cup does not contain water. It has some other liquid in it.\n<|im_start|>answer\nThe cup does not contain water. It has some other liquid in it.\n<|im_end|>" }, { "id": "#2045", "title": "Walk the Dog", "fun": 2.23, "difficulty": 1.81, "author": "ripstein", "desc": "Mark took his dog for a walk. It did not walk in front of him, behind him, above him, below him, or to one side of him. Also, he wasn't carrying it. Where did the dog walk?", "hint": "No hint available.", "answer": "The dog walked on Mark's OTHER side.", "category": "Logic", "date": "01/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMark took his dog for a walk. It did not walk in front of him, behind him, above him, below him, or to one side of him. Also, he wasn't carrying it. Where did the dog walk?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe dog walked on Mark's OTHER side.\n<|im_start|>answer\nThe dog walked on Mark's OTHER side.\n<|im_end|>" }, { "id": "#7150", "title": "Checkerboard", "fun": 2.23, "difficulty": 2.19, "author": "mozven", "desc": "How many squares of any size are there on an 8x8 checkerboard?", "hint": "There is one 8x8 square, four 7x7 squares...", "answer": "204 squares \n\r\nThere is one 8x8 square, four 7x7 squares, nine 6x6 squares, 16 5x5 squares, 25 4x4 squares, 36 3x3 squares, 49 2x2 squares, and 64 1x1 squares. It can be written like this:\r\n(1^2)+(2^2)+(3^2)+(4^2)+(5^2)+(6^2)+(7^2)+(8^2)=204 squares", "category": "Math", "date": "09/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many squares of any size are there on an 8x8 checkerboard?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n204 squares \n\r\nThere is one 8x8 square, four 7x7 squares, nine 6x6 squares, 16 5x5 squares, 25 4x4 squares, 36 3x3 squares, 49 2x2 squares, and 64 1x1 squares. It can be written like this:\r\n(1^2)+(2^2)+(3^2)+(4^2)+(5^2)+(6^2)+(7^2)+(8^2)=204 squares\n<|im_start|>answer\n204 squares \n\r\nThere is one 8x8 square, four 7x7 squares, nine 6x6 squares, 16 5x5 squares, 25 4x4 squares, 36 3x3 squares, 49 2x2 squares, and 64 1x1 squares. It can be written like this:\r\n(1^2)+(2^2)+(3^2)+(4^2)+(5^2)+(6^2)+(7^2)+(8^2)=204 squares\n<|im_end|>" }, { "id": "#3851", "title": "What's His Job", "fun": 2.23, "difficulty": 1.44, "author": "cowgirl", "desc": "When asked what he does for a living, Logan says he just sits around all day and makes faces. What is Logan's job?", "hint": "No hint available.", "answer": "He makes clocks", "category": "Logic", "date": "05/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen asked what he does for a living, Logan says he just sits around all day and makes faces. What is Logan's job?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe makes clocks\n<|im_start|>answer\nHe makes clocks\n<|im_end|>" }, { "id": "#2904", "title": "Running a Red Light", "fun": 2.23, "difficulty": 1.19, "author": "204_BLaZe_41", "desc": "A cop was stopped at a red light. Professor Bundle, who had his mind on a lecture he was about to give, drove his car right by him and through the light without stopping. The cop witnessed the entire scene but made no attempt to stop him. Why not?", "hint": "No hint available.", "answer": "Professor Bundle was driving through a green light, in front of the cop who was stopped at a red light.", "category": "Logic", "date": "03/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cop was stopped at a red light. Professor Bundle, who had his mind on a lecture he was about to give, drove his car right by him and through the light without stopping. The cop witnessed the entire scene but made no attempt to stop him. Why not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nProfessor Bundle was driving through a green light, in front of the cop who was stopped at a red light.\n<|im_start|>answer\nProfessor Bundle was driving through a green light, in front of the cop who was stopped at a red light.\n<|im_end|>" }, { "id": "#40997", "title": "Math Situations #1", "fun": 2.23, "difficulty": 1.4, "author": "Fire_Shell96", "desc": "In a coin collecting book 30 nickels can fit in each of 8 pages and 36 dimes can fit on each of 6 pages. If the nickel book is 5/8 full and the dime book is 75% full, how much money is in the book?", "hint": "Convert the fraction and percentage to a decimal.", "answer": "The answer is $23.70.\n\r\nThis can be calculated through multiplication.\n\r\n5/8 is equivalent to .625. The total amount of money that can be stored into the nickel section of the book is $12. 12x.625=7.5, or $7.50. \n\r\n75% is equivalent to .75. The total amount of money that can be stored in the dime section of the book is $21.60. 21.6x.75=16.2, or $16.20.\n\r\nIf you add these numbers ($7.50 and $16.20) you end up with a sum of $23.70.", "category": "Math", "date": "03/12/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a coin collecting book 30 nickels can fit in each of 8 pages and 36 dimes can fit on each of 6 pages. If the nickel book is 5/8 full and the dime book is 75% full, how much money is in the book?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is $23.70.\n\r\nThis can be calculated through multiplication.\n\r\n5/8 is equivalent to .625. The total amount of money that can be stored into the nickel section of the book is $12. 12x.625=7.5, or $7.50. \n\r\n75% is equivalent to .75. The total amount of money that can be stored in the dime section of the book is $21.60. 21.6x.75=16.2, or $16.20.\n\r\nIf you add these numbers ($7.50 and $16.20) you end up with a sum of $23.70.\n<|im_start|>answer\nThe answer is $23.70.\n\r\nThis can be calculated through multiplication.\n\r\n5/8 is equivalent to .625. The total amount of money that can be stored into the nickel section of the book is $12. 12x.625=7.5, or $7.50. \n\r\n75% is equivalent to .75. The total amount of money that can be stored in the dime section of the book is $21.60. 21.6x.75=16.2, or $16.20.\n\r\nIf you add these numbers ($7.50 and $16.20) you end up with a sum of $23.70.\n<|im_end|>" }, { "id": "#41362", "title": "As Old As The Trees", "fun": 2.23, "difficulty": 2.11, "author": "TRILLIONAIRE", "desc": "During its first year a species of tree reaches a height of 7cm. It continues to grow for another 9 years attaining its maximum height at 10 years of age. Each year it continues to grow at the rate of double the previous year's height. At what age will the tree be half its maximum height?\n\r\nNote: The tree grows at a constant speed throughout the year.", "hint": "No hint available.", "answer": "9.25 years\n\n\r\nEvery year the tree is 3 times as high as it was the previous year.\n\r\nThat means if it is x high, it will gain 2x throughout the year, totaling 3x at the end. We want to find when it is 1.5x.\n\r\nIf it gains 2x every year, it will gain x every six months, or .5x every 3 months. Also stated as .5x every quarter of a year or .25 years.\n\r\nSo .25 of the way through the year, it will be half the height it will be at the end of the year.", "category": "Math", "date": "04/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring its first year a species of tree reaches a height of 7cm. It continues to grow for another 9 years attaining its maximum height at 10 years of age. Each year it continues to grow at the rate of double the previous year's height. At what age will the tree be half its maximum height?\n\r\nNote: The tree grows at a constant speed throughout the year.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9.25 years\n\n\r\nEvery year the tree is 3 times as high as it was the previous year.\n\r\nThat means if it is x high, it will gain 2x throughout the year, totaling 3x at the end. We want to find when it is 1.5x.\n\r\nIf it gains 2x every year, it will gain x every six months, or .5x every 3 months. Also stated as .5x every quarter of a year or .25 years.\n\r\nSo .25 of the way through the year, it will be half the height it will be at the end of the year.\n<|im_start|>answer\n9.25 years\n\n\r\nEvery year the tree is 3 times as high as it was the previous year.\n\r\nThat means if it is x high, it will gain 2x throughout the year, totaling 3x at the end. We want to find when it is 1.5x.\n\r\nIf it gains 2x every year, it will gain x every six months, or .5x every 3 months. Also stated as .5x every quarter of a year or .25 years.\n\r\nSo .25 of the way through the year, it will be half the height it will be at the end of the year.\n<|im_end|>" }, { "id": "#5101", "title": "Two Digit Numbers", "fun": 2.23, "difficulty": 2.19, "author": "mad-ade", "desc": "Take the 2-digit number 45.\r\nSquare it (45 x 45) to make 2025\r\nSplit this 4-digit number in half to make 20 and 25\r\nAdd them (20 + 25) to make 45\r\nWhich is what you started with.\r\nCan you find another 2-digit number which does the same?", "hint": "No hint available.", "answer": "55 or 99", "category": "Math", "date": "07/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTake the 2-digit number 45.\r\nSquare it (45 x 45) to make 2025\r\nSplit this 4-digit number in half to make 20 and 25\r\nAdd them (20 + 25) to make 45\r\nWhich is what you started with.\r\nCan you find another 2-digit number which does the same?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n55 or 99\n<|im_start|>answer\n55 or 99\n<|im_end|>" }, { "id": "#1719", "title": "Bases", "fun": 2.23, "difficulty": 1.69, "author": "Bigman", "desc": "How can 1+1=10?", "hint": "No hint available.", "answer": "1+1=10 only if you use base 2 instead of base 10.", "category": "Math", "date": "12/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can 1+1=10?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1+1=10 only if you use base 2 instead of base 10.\n<|im_start|>answer\n1+1=10 only if you use base 2 instead of base 10.\n<|im_end|>" }, { "id": "#18992", "title": "Romankachi Cars !!!", "fun": 2.23, "difficulty": 1.83, "author": "lesternoronha1", "desc": "Four new models rolled out of RomanKachi Motors Ltd. this season, each of which is of a different weight and a different cost. They are the Jaguar, the Miroza, the Scotto and the Venz.\r\n1) The heaviest car is the cheapest and the lightest car the costliest.\r\n2) Miroza, the second heaviest, is the third costliest.\r\n3) Scotto is heavier than Venz and costlier to Jaguar.\n\r\nCan you find which model is the cheapest and which model the costliest ?", "hint": "No hint available.", "answer": "The cheapest and the costliest models are the Jaguar and the Venz respectively.\n\r\nFour new models the Jaguar, the Miroza, the Scotto and the Venz are of different weight and cost.\r\nThe conditions given are \r\n1) The heaviest car is the cheapest and the lightest car the costliest.\r\n2) Miroza, the second heaviest, is the third costliest.\r\n3) Scotto is heavier than Venz and costlier to Jaguar.\n\r\nLet us take the car X as the heaviest and the car Y as the lightest.\r\nThen from condition 1 above, we can write the following table :-\n\r\n Weight \t Cost\r\n1 X\t Y\r\n2 Miroza \r\n3 Miroza\r\n4 Y\t X\r\nsince from condition 2, Miroza, the second heaviest, is the third costliest.\n\r\nAlso from condition 3, we have Scotto to be heavier than Venz and costlier to Jaguar. Hence Scotto can neither be the heaviest (since Jaguar must be heavier than it because Jaguar is cheaper to it) nor the costliest (since Venz must be costlier than it because Venz is lighter to it). Hence Scotto is the third in weight and second in cost. \n\r\nAs Scotto is heavier than Venz, the car 'Y' must be Venz and the car 'X' must be Jaguar. \r\nThus the final arrangement is shown below :-\n\r\n Weight \t Cost\r\n1 Jaguar\t Venz\r\n2 Miroza\t Scotto\r\n3 Scotto\t Miroza\r\n4 Venz\t Jaguar\n\r\nHence Jaguar is the cheapest model and Venz the costliest model.", "category": "Logic", "date": "10/06/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour new models rolled out of RomanKachi Motors Ltd. this season, each of which is of a different weight and a different cost. They are the Jaguar, the Miroza, the Scotto and the Venz.\r\n1) The heaviest car is the cheapest and the lightest car the costliest.\r\n2) Miroza, the second heaviest, is the third costliest.\r\n3) Scotto is heavier than Venz and costlier to Jaguar.\n\r\nCan you find which model is the cheapest and which model the costliest ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cheapest and the costliest models are the Jaguar and the Venz respectively.\n\r\nFour new models the Jaguar, the Miroza, the Scotto and the Venz are of different weight and cost.\r\nThe conditions given are \r\n1) The heaviest car is the cheapest and the lightest car the costliest.\r\n2) Miroza, the second heaviest, is the third costliest.\r\n3) Scotto is heavier than Venz and costlier to Jaguar.\n\r\nLet us take the car X as the heaviest and the car Y as the lightest.\r\nThen from condition 1 above, we can write the following table :-\n\r\n Weight \t Cost\r\n1 X\t Y\r\n2 Miroza \r\n3 Miroza\r\n4 Y\t X\r\nsince from condition 2, Miroza, the second heaviest, is the third costliest.\n\r\nAlso from condition 3, we have Scotto to be heavier than Venz and costlier to Jaguar. Hence Scotto can neither be the heaviest (since Jaguar must be heavier than it because Jaguar is cheaper to it) nor the costliest (since Venz must be costlier than it because Venz is lighter to it). Hence Scotto is the third in weight and second in cost. \n\r\nAs Scotto is heavier than Venz, the car 'Y' must be Venz and the car 'X' must be Jaguar. \r\nThus the final arrangement is shown below :-\n\r\n Weight \t Cost\r\n1 Jaguar\t Venz\r\n2 Miroza\t Scotto\r\n3 Scotto\t Miroza\r\n4 Venz\t Jaguar\n\r\nHence Jaguar is the cheapest model and Venz the costliest model.\n<|im_start|>answer\nThe cheapest and the costliest models are the Jaguar and the Venz respectively.\n\r\nFour new models the Jaguar, the Miroza, the Scotto and the Venz are of different weight and cost.\r\nThe conditions given are \r\n1) The heaviest car is the cheapest and the lightest car the costliest.\r\n2) Miroza, the second heaviest, is the third costliest.\r\n3) Scotto is heavier than Venz and costlier to Jaguar.\n\r\nLet us take the car X as the heaviest and the car Y as the lightest.\r\nThen from condition 1 above, we can write the following table :-\n\r\n Weight \t Cost\r\n1 X\t Y\r\n2 Miroza \r\n3 Miroza\r\n4 Y\t X\r\nsince from condition 2, Miroza, the second heaviest, is the third costliest.\n\r\nAlso from condition 3, we have Scotto to be heavier than Venz and costlier to Jaguar. Hence Scotto can neither be the heaviest (since Jaguar must be heavier than it because Jaguar is cheaper to it) nor the costliest (since Venz must be costlier than it because Venz is lighter to it). Hence Scotto is the third in weight and second in cost. \n\r\nAs Scotto is heavier than Venz, the car 'Y' must be Venz and the car 'X' must be Jaguar. \r\nThus the final arrangement is shown below :-\n\r\n Weight \t Cost\r\n1 Jaguar\t Venz\r\n2 Miroza\t Scotto\r\n3 Scotto\t Miroza\r\n4 Venz\t Jaguar\n\r\nHence Jaguar is the cheapest model and Venz the costliest model.\n<|im_end|>" }, { "id": "#4618", "title": "Sandcastles", "fun": 2.23, "difficulty": 1.56, "author": "mad-ade", "desc": "If it takes 20 buckets of sand to make a sandcastle, how many buckets will it need to make another castle of the same shape, but twice as big in each direction ?", "hint": "No hint available.", "answer": "160 buckets. Since the large castle will be twice as long, twice as wide and twice as high, it will be 2 * 2 * 2 = 8 times the mass of the small one.", "category": "Math", "date": "06/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf it takes 20 buckets of sand to make a sandcastle, how many buckets will it need to make another castle of the same shape, but twice as big in each direction ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n160 buckets. Since the large castle will be twice as long, twice as wide and twice as high, it will be 2 * 2 * 2 = 8 times the mass of the small one.\n<|im_start|>answer\n160 buckets. Since the large castle will be twice as long, twice as wide and twice as high, it will be 2 * 2 * 2 = 8 times the mass of the small one.\n<|im_end|>" }, { "id": "#7647", "title": "Nastee's Workers", "fun": 2.23, "difficulty": 2.69, "author": "mad-ade", "desc": "In the early years of the last century, a MADADIAN industrialist, Nastee, had employed 100 labourers to build his new improved Kebab and Rat Poison factory. Things were a little different those days, and the employment of labourers' wives and children was commonplace, although Nastee did not allow any woman to work without her husband. Also, at least half the men working came with their wives. \n\r\nHe paid five Madadian Wonks per day to each man, four Wonks to each woman and one Wonk to each child. He gave out 200 Wonks every evening. \n\r\nHow many men, women and children were working with Nastee?", "hint": "No hint available.", "answer": "16 men, 12 women and 72 children were working with Nastee.\n\r\nLet's assume that there were X men, Y women and Z children working with Nastee Hence, \n\r\nX + Y + Z = 100 \r\n5X + 4Y + Z = 200 \n\r\nEliminating X and Y in turn from these equations, we get \r\nX = 3Z - 200 \r\nY = 300 - 4Z \n\r\nIf a woman works, her husband also works, and at least half the men working came with their wives; the value of Y lies between X and X/2. Substituting these limiting values in equations, we get \n\r\nif Y = X, \r\n300 - 4Z = 3Z - 200 \r\n7Z = 500 \r\nZ = 500/7 i.e. 71.428 \n\r\nif Y = X/2, \r\n300 - 4Z = (3Z - 200)/2 \r\n600 - 8Z = 3Z - 200 \r\n11Z = 800 \r\nZ = 800/11 i.e. 72.727 \n\r\nBut Z must be an integer, hence Z=72. Also, X=16 and Y=12 \n\r\nThere were 16 men, 12 women and 72 children working with Nastee.", "category": "Math", "date": "09/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the early years of the last century, a MADADIAN industrialist, Nastee, had employed 100 labourers to build his new improved Kebab and Rat Poison factory. Things were a little different those days, and the employment of labourers' wives and children was commonplace, although Nastee did not allow any woman to work without her husband. Also, at least half the men working came with their wives. \n\r\nHe paid five Madadian Wonks per day to each man, four Wonks to each woman and one Wonk to each child. He gave out 200 Wonks every evening. \n\r\nHow many men, women and children were working with Nastee?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16 men, 12 women and 72 children were working with Nastee.\n\r\nLet's assume that there were X men, Y women and Z children working with Nastee Hence, \n\r\nX + Y + Z = 100 \r\n5X + 4Y + Z = 200 \n\r\nEliminating X and Y in turn from these equations, we get \r\nX = 3Z - 200 \r\nY = 300 - 4Z \n\r\nIf a woman works, her husband also works, and at least half the men working came with their wives; the value of Y lies between X and X/2. Substituting these limiting values in equations, we get \n\r\nif Y = X, \r\n300 - 4Z = 3Z - 200 \r\n7Z = 500 \r\nZ = 500/7 i.e. 71.428 \n\r\nif Y = X/2, \r\n300 - 4Z = (3Z - 200)/2 \r\n600 - 8Z = 3Z - 200 \r\n11Z = 800 \r\nZ = 800/11 i.e. 72.727 \n\r\nBut Z must be an integer, hence Z=72. Also, X=16 and Y=12 \n\r\nThere were 16 men, 12 women and 72 children working with Nastee.\n<|im_start|>answer\n16 men, 12 women and 72 children were working with Nastee.\n\r\nLet's assume that there were X men, Y women and Z children working with Nastee Hence, \n\r\nX + Y + Z = 100 \r\n5X + 4Y + Z = 200 \n\r\nEliminating X and Y in turn from these equations, we get \r\nX = 3Z - 200 \r\nY = 300 - 4Z \n\r\nIf a woman works, her husband also works, and at least half the men working came with their wives; the value of Y lies between X and X/2. Substituting these limiting values in equations, we get \n\r\nif Y = X, \r\n300 - 4Z = 3Z - 200 \r\n7Z = 500 \r\nZ = 500/7 i.e. 71.428 \n\r\nif Y = X/2, \r\n300 - 4Z = (3Z - 200)/2 \r\n600 - 8Z = 3Z - 200 \r\n11Z = 800 \r\nZ = 800/11 i.e. 72.727 \n\r\nBut Z must be an integer, hence Z=72. Also, X=16 and Y=12 \n\r\nThere were 16 men, 12 women and 72 children working with Nastee.\n<|im_end|>" }, { "id": "#11081", "title": "Which Does She Like?", "fun": 2.23, "difficulty": 1.7, "author": "Sciocleseus", "desc": "If Susan likes the number pair 1689 and 6891, which of the following number pairs does she also like?\n\r\n1981 and 1891\r\n19 and 91\r\n190 and 160\r\n1198911 and 1168611", "hint": "Turn your head and you might see what answer to this riddle be.", "answer": "1198911 and 1168611\n\r\nIf you turn 1198911 upside down by rotating it clockwise 180 degrees, you get the number 1168611.\n\r\nThe same goes for 1689 and 6891.", "category": "Math", "date": "03/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf Susan likes the number pair 1689 and 6891, which of the following number pairs does she also like?\n\r\n1981 and 1891\r\n19 and 91\r\n190 and 160\r\n1198911 and 1168611\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1198911 and 1168611\n\r\nIf you turn 1198911 upside down by rotating it clockwise 180 degrees, you get the number 1168611.\n\r\nThe same goes for 1689 and 6891.\n<|im_start|>answer\n1198911 and 1168611\n\r\nIf you turn 1198911 upside down by rotating it clockwise 180 degrees, you get the number 1168611.\n\r\nThe same goes for 1689 and 6891.\n<|im_end|>" }, { "id": "#1826", "title": "Lots of Sheep", "fun": 2.23, "difficulty": 1.61, "author": "missie", "desc": "An Australian farmer dies and leaves his sheep to his three sons. Alfred is to get 20 percent more than John, and 25 percent more than Charles. John's share is 3600 sheep.\n\r\nHow many sheep does Charles get?", "hint": "No hint available.", "answer": "3,456 Sheep", "category": "Math", "date": "12/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn Australian farmer dies and leaves his sheep to his three sons. Alfred is to get 20 percent more than John, and 25 percent more than Charles. John's share is 3600 sheep.\n\r\nHow many sheep does Charles get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3,456 Sheep\n<|im_start|>answer\n3,456 Sheep\n<|im_end|>" }, { "id": "#1134", "title": "Fore to Aft", "fun": 2.23, "difficulty": 1.94, "author": "Michelle", "desc": "What runs fore to aft on one side of the ship, and aft to fore on the other side?", "hint": "No hint available.", "answer": "The name of the ship.", "category": "Logic", "date": "10/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat runs fore to aft on one side of the ship, and aft to fore on the other side?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe name of the ship.\n<|im_start|>answer\nThe name of the ship.\n<|im_end|>" }, { "id": "#8368", "title": "Books, Books, Books!", "fun": 2.23, "difficulty": 2.5100000000000002, "author": "PopaG", "desc": "George loves reading books. He reads 100 chapters a day. All the chapters are the same length, 40 pages. But the word number on each page changes. If it was the first page of a chapter it would have one word if it were the second it would have three words, the third page would have six and if it were the fourth page it would have 10. The page number and number of words correspond with each other and there is a distinct formula that would get the answer under any circumstances. What is it?", "hint": "The tenth page would have 55 words. The page number=n.", "answer": "where n = page number\r\nwords = (n(n+1))/2", "category": "Math", "date": "11/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGeorge loves reading books. He reads 100 chapters a day. All the chapters are the same length, 40 pages. But the word number on each page changes. If it was the first page of a chapter it would have one word if it were the second it would have three words, the third page would have six and if it were the fourth page it would have 10. The page number and number of words correspond with each other and there is a distinct formula that would get the answer under any circumstances. What is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nwhere n = page number\r\nwords = (n(n+1))/2\n<|im_start|>answer\nwhere n = page number\r\nwords = (n(n+1))/2\n<|im_end|>" }, { "id": "#3755", "title": "Letter Math", "fun": 2.23, "difficulty": 1.94, "author": "cathalmccabe", "desc": "A, B, C, D, E, represent the numbers 1, 2, 3, 4, 5, but not in that order. Can you work out what they are? \n\r\nE + B + D = CA\r\nB * D = CA\r\nA * B + E = CD", "hint": "Work out all the possible sums of three numbers; 1-5\r\nWork out all the possible products of two numbers 1-5\r\nYou should be able to get CA and E from this.", "answer": "To check:\n\r\nA = 2\r\nB = 4\r\nC = 1\r\nD = 3\r\nE = 5\n\r\n5 + 4 + 3 = 12\r\n4 * 3 = 12\r\n2 * 4 + 5 = 13\n\r\nSolution:\n\r\nThere is only one sum of three numbers that will give a possible double digit number:\n\r\n3 + 4 + 5= 12 \r\nC=1\r\nA=2\r\n(Must be more than 9, 10 is not possible because there is no zero, and the digits must be different so it can't be 11; can't get higher than 12 with three numbers)\r\nThere are only two numbers which will give a product of 12. 3 and 4\r\nB + D are 3 and 4 (although you don't know which) but B + D = 7 so\r\nE=5\n\r\n2 * B + 5 = 13\r\nB = 4\r\nD = 3\n\r\nHope you liked it!", "category": "Math", "date": "04/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA, B, C, D, E, represent the numbers 1, 2, 3, 4, 5, but not in that order. Can you work out what they are? \n\r\nE + B + D = CA\r\nB * D = CA\r\nA * B + E = CD\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo check:\n\r\nA = 2\r\nB = 4\r\nC = 1\r\nD = 3\r\nE = 5\n\r\n5 + 4 + 3 = 12\r\n4 * 3 = 12\r\n2 * 4 + 5 = 13\n\r\nSolution:\n\r\nThere is only one sum of three numbers that will give a possible double digit number:\n\r\n3 + 4 + 5= 12 \r\nC=1\r\nA=2\r\n(Must be more than 9, 10 is not possible because there is no zero, and the digits must be different so it can't be 11; can't get higher than 12 with three numbers)\r\nThere are only two numbers which will give a product of 12. 3 and 4\r\nB + D are 3 and 4 (although you don't know which) but B + D = 7 so\r\nE=5\n\r\n2 * B + 5 = 13\r\nB = 4\r\nD = 3\n\r\nHope you liked it!\n<|im_start|>answer\nTo check:\n\r\nA = 2\r\nB = 4\r\nC = 1\r\nD = 3\r\nE = 5\n\r\n5 + 4 + 3 = 12\r\n4 * 3 = 12\r\n2 * 4 + 5 = 13\n\r\nSolution:\n\r\nThere is only one sum of three numbers that will give a possible double digit number:\n\r\n3 + 4 + 5= 12 \r\nC=1\r\nA=2\r\n(Must be more than 9, 10 is not possible because there is no zero, and the digits must be different so it can't be 11; can't get higher than 12 with three numbers)\r\nThere are only two numbers which will give a product of 12. 3 and 4\r\nB + D are 3 and 4 (although you don't know which) but B + D = 7 so\r\nE=5\n\r\n2 * B + 5 = 13\r\nB = 4\r\nD = 3\n\r\nHope you liked it!\n<|im_end|>" }, { "id": "#48625", "title": "Odd Man Out", "fun": 2.23, "difficulty": 2.71, "author": "Mathgeek007", "desc": "Which is the odd one out?\n\r\nDie\r\nDay\r\nGee\r\nGun\r\nScale", "hint": "No hint available.", "answer": "Gun is.\n\r\nA die, when two opposite side's values are added, makes seven.\r\nThere are seven days in a week.\r\nGee (G) is the seventh letter in the alphabet.\r\nThere are 7 different notes in a musical scale. (Excluding the repeated letter)\n\r\nGun is the odd man out.", "category": "Logic", "date": "04/10/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is the odd one out?\n\r\nDie\r\nDay\r\nGee\r\nGun\r\nScale\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGun is.\n\r\nA die, when two opposite side's values are added, makes seven.\r\nThere are seven days in a week.\r\nGee (G) is the seventh letter in the alphabet.\r\nThere are 7 different notes in a musical scale. (Excluding the repeated letter)\n\r\nGun is the odd man out.\n<|im_start|>answer\nGun is.\n\r\nA die, when two opposite side's values are added, makes seven.\r\nThere are seven days in a week.\r\nGee (G) is the seventh letter in the alphabet.\r\nThere are 7 different notes in a musical scale. (Excluding the repeated letter)\n\r\nGun is the odd man out.\n<|im_end|>" }, { "id": "#19252", "title": "Lotto Luck", "fun": 2.23, "difficulty": 3.1, "author": "cnmne", "desc": "Professor Abacus is purchasing a ticket for the Deca Lotto. The lotto number has ten digits, using the numerals 0 through 9, each numeral used once. The clerk asked what number he wanted to pick. Professor Abacus handed the clerk a piece of paper with nine statements, saying \"If you can correctly figure out the number, I will give you half of whatever I win.\" What is the number?\n\r\n1) The sum of the first five digits is a prime number.\r\n2) The sum of the last five digits is a triangle number*.\r\n3) The sum of the digits in the odd positions is an odd number.\r\n4) The sum of the middle two digits is a square number.\r\n5) The sum of the middle four digits is a cube number.\r\n6) The difference between the 1st and 10th digits is two.\r\n7) The difference between the 2nd and 9th digits is three.\r\n8) The difference between the 3rd and 8th digits is four.\r\n9) The numeral 4 is somewhere in the first five positions.\n\r\n* You can form a triangle arrangement by building it in the pattern row 1 = 1, row 2 = 2, row 3 = 3 etc. eg. 10 is a classic triangle number as per ten pin bowling. They are arranged in a triangle 1, 2, 3, 4.", "hint": "No hint available.", "answer": "7342105869\n\r\n7 + 3 + 4 + 2 + 1 = 17 (prime), 0 + 5 + 8 + 6 + 9 = 28 (triangle), 7 + 4 + 1 + 5 + 6 = 23 (odd), 1 + 0 = 1 (square), 2 + 1 + 0 + 5 = 8 (cube), the difference between 7 and 9 is 2, the difference between 3 and 6 is 3, the difference between 4 and 8 is 4, 4 is in the 3rd position.", "category": "Logic", "date": "10/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nProfessor Abacus is purchasing a ticket for the Deca Lotto. The lotto number has ten digits, using the numerals 0 through 9, each numeral used once. The clerk asked what number he wanted to pick. Professor Abacus handed the clerk a piece of paper with nine statements, saying \"If you can correctly figure out the number, I will give you half of whatever I win.\" What is the number?\n\r\n1) The sum of the first five digits is a prime number.\r\n2) The sum of the last five digits is a triangle number*.\r\n3) The sum of the digits in the odd positions is an odd number.\r\n4) The sum of the middle two digits is a square number.\r\n5) The sum of the middle four digits is a cube number.\r\n6) The difference between the 1st and 10th digits is two.\r\n7) The difference between the 2nd and 9th digits is three.\r\n8) The difference between the 3rd and 8th digits is four.\r\n9) The numeral 4 is somewhere in the first five positions.\n\r\n* You can form a triangle arrangement by building it in the pattern row 1 = 1, row 2 = 2, row 3 = 3 etc. eg. 10 is a classic triangle number as per ten pin bowling. They are arranged in a triangle 1, 2, 3, 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7342105869\n\r\n7 + 3 + 4 + 2 + 1 = 17 (prime), 0 + 5 + 8 + 6 + 9 = 28 (triangle), 7 + 4 + 1 + 5 + 6 = 23 (odd), 1 + 0 = 1 (square), 2 + 1 + 0 + 5 = 8 (cube), the difference between 7 and 9 is 2, the difference between 3 and 6 is 3, the difference between 4 and 8 is 4, 4 is in the 3rd position.\n<|im_start|>answer\n7342105869\n\r\n7 + 3 + 4 + 2 + 1 = 17 (prime), 0 + 5 + 8 + 6 + 9 = 28 (triangle), 7 + 4 + 1 + 5 + 6 = 23 (odd), 1 + 0 = 1 (square), 2 + 1 + 0 + 5 = 8 (cube), the difference between 7 and 9 is 2, the difference between 3 and 6 is 3, the difference between 4 and 8 is 4, 4 is in the 3rd position.\n<|im_end|>" }, { "id": "#15202", "title": "Golden Kebab Tokens", "fun": 2.23, "difficulty": 2.82, "author": "mad-ade", "desc": "A group of Mad-Ade's friends, although fewer than 10, found a number of Golden kebab tokens which they were able to divide equally among them. \n\r\nAfter this division had been done, Norha Bone - one of the friends, suggested that it would be more equitable to divide the Golden kebab tokens by families rather than by individuals. Among them, there were two groups with two sisters; of course Norha Bone was not in either group. The rest of the friends were unrelated to each other. A re-division by families would have meant that the Golden kebab tokens per family were 5 more than the Golden kebab tokens per friend. \n\r\nThe friends argued among themselves over this way of dividing the Golden kebab tokens. Before a final decision is made, Wendy Boatkumsin - one of the friends, decided that she did not want any Golden kebab tokens. Her share was equally divided (without breaking/cutting any Kebab token) among the other friends. \n\r\nFinally, Norha Bone decided to withdraw her suggestion of dividing the Golden kebab tokens by families. \n\r\nHow many friends were there and how many Golden kebab tokens did each friend end up with?", "hint": "No hint available.", "answer": "There were a total of 6 friends. Each end up with 12 Golden kebab tokens. \n\r\nThe number of Golden kebab tokens is evenly divisible by the number of friends as well as the number of families. \n\r\nLet's assume that N is the number of Golden kebab tokens each friend received initially and G is the total number of friends. \n\r\nThen, total number of Golden kebab tokens = NG \n\r\nIf the Golden kebab tokens had been divided by families rather than by individuals, the number of recipients would be (G - 2) and each share would be (N + 5). \r\nAgain, total number of Golden kebab tokens = (N + 5)(G - 2) \n\r\nBut, the total number of the Golden kebab tokens is the same. \r\nNG = (N + 5)(G - 2) \r\nNG = NG -2N +5G -10 \r\n2N = 5G -10 \r\nN = (5/2)G - 5 \n\r\nNow, N and G are the positive integers and also total number of Golden kebab tokens must be divisible by G, (G-1) and (G-2). This is because initially there were G friends; then since it was divided family wise, the total number of units, the coins were to be divided would be (G-2) (as two groups had two sisters, so two friends got combined as one group, one per group); and after Wendy Boatkumsin backed out, there were (G-1) friends. \n\r\nNow trying different EVEN values for G, starting with 2; there were total 6 friends and 60 Golden kebab tokens. The Golden kebab tokens are divided among 5 friends and hence each friend ends up with 12 Golden kebab tokens.", "category": "Logic", "date": "10/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of Mad-Ade's friends, although fewer than 10, found a number of Golden kebab tokens which they were able to divide equally among them. \n\r\nAfter this division had been done, Norha Bone - one of the friends, suggested that it would be more equitable to divide the Golden kebab tokens by families rather than by individuals. Among them, there were two groups with two sisters; of course Norha Bone was not in either group. The rest of the friends were unrelated to each other. A re-division by families would have meant that the Golden kebab tokens per family were 5 more than the Golden kebab tokens per friend. \n\r\nThe friends argued among themselves over this way of dividing the Golden kebab tokens. Before a final decision is made, Wendy Boatkumsin - one of the friends, decided that she did not want any Golden kebab tokens. Her share was equally divided (without breaking/cutting any Kebab token) among the other friends. \n\r\nFinally, Norha Bone decided to withdraw her suggestion of dividing the Golden kebab tokens by families. \n\r\nHow many friends were there and how many Golden kebab tokens did each friend end up with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere were a total of 6 friends. Each end up with 12 Golden kebab tokens. \n\r\nThe number of Golden kebab tokens is evenly divisible by the number of friends as well as the number of families. \n\r\nLet's assume that N is the number of Golden kebab tokens each friend received initially and G is the total number of friends. \n\r\nThen, total number of Golden kebab tokens = NG \n\r\nIf the Golden kebab tokens had been divided by families rather than by individuals, the number of recipients would be (G - 2) and each share would be (N + 5). \r\nAgain, total number of Golden kebab tokens = (N + 5)(G - 2) \n\r\nBut, the total number of the Golden kebab tokens is the same. \r\nNG = (N + 5)(G - 2) \r\nNG = NG -2N +5G -10 \r\n2N = 5G -10 \r\nN = (5/2)G - 5 \n\r\nNow, N and G are the positive integers and also total number of Golden kebab tokens must be divisible by G, (G-1) and (G-2). This is because initially there were G friends; then since it was divided family wise, the total number of units, the coins were to be divided would be (G-2) (as two groups had two sisters, so two friends got combined as one group, one per group); and after Wendy Boatkumsin backed out, there were (G-1) friends. \n\r\nNow trying different EVEN values for G, starting with 2; there were total 6 friends and 60 Golden kebab tokens. The Golden kebab tokens are divided among 5 friends and hence each friend ends up with 12 Golden kebab tokens.\n<|im_start|>answer\nThere were a total of 6 friends. Each end up with 12 Golden kebab tokens. \n\r\nThe number of Golden kebab tokens is evenly divisible by the number of friends as well as the number of families. \n\r\nLet's assume that N is the number of Golden kebab tokens each friend received initially and G is the total number of friends. \n\r\nThen, total number of Golden kebab tokens = NG \n\r\nIf the Golden kebab tokens had been divided by families rather than by individuals, the number of recipients would be (G - 2) and each share would be (N + 5). \r\nAgain, total number of Golden kebab tokens = (N + 5)(G - 2) \n\r\nBut, the total number of the Golden kebab tokens is the same. \r\nNG = (N + 5)(G - 2) \r\nNG = NG -2N +5G -10 \r\n2N = 5G -10 \r\nN = (5/2)G - 5 \n\r\nNow, N and G are the positive integers and also total number of Golden kebab tokens must be divisible by G, (G-1) and (G-2). This is because initially there were G friends; then since it was divided family wise, the total number of units, the coins were to be divided would be (G-2) (as two groups had two sisters, so two friends got combined as one group, one per group); and after Wendy Boatkumsin backed out, there were (G-1) friends. \n\r\nNow trying different EVEN values for G, starting with 2; there were total 6 friends and 60 Golden kebab tokens. The Golden kebab tokens are divided among 5 friends and hence each friend ends up with 12 Golden kebab tokens.\n<|im_end|>" }, { "id": "#26222", "title": "The Same Number", "fun": 2.23, "difficulty": 2.07, "author": "metallicman", "desc": "Bill and Bob were trying to see whose arm was longer. So, what they first did was put each other's arm side to side and saw that they both looked similar in size. \r\n Next, they measured the length of their arm from the shoulder to the tip of the finger and divided that by the length from their elbow to the tip of the finger. They both got the same number, but when they just took the shoulder measuring, Bill's arm was longer. How can this be?", "hint": "No hint available.", "answer": "Phi. On any part of the body, such as the arm, phi, or 1.61803399, will always be the outcome. The length of the entire arm divided by the length just from the elbow will always equal that, just like the finger and the leg, and the body. It is also true on animals and even plants.", "category": "Math", "date": "10/05/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBill and Bob were trying to see whose arm was longer. So, what they first did was put each other's arm side to side and saw that they both looked similar in size. \r\n Next, they measured the length of their arm from the shoulder to the tip of the finger and divided that by the length from their elbow to the tip of the finger. They both got the same number, but when they just took the shoulder measuring, Bill's arm was longer. How can this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPhi. On any part of the body, such as the arm, phi, or 1.61803399, will always be the outcome. The length of the entire arm divided by the length just from the elbow will always equal that, just like the finger and the leg, and the body. It is also true on animals and even plants.\n<|im_start|>answer\nPhi. On any part of the body, such as the arm, phi, or 1.61803399, will always be the outcome. The length of the entire arm divided by the length just from the elbow will always equal that, just like the finger and the leg, and the body. It is also true on animals and even plants.\n<|im_end|>" }, { "id": "#15201", "title": "Mad Ade's Blocks", "fun": 2.23, "difficulty": 2.73, "author": "mad-ade", "desc": "Mad Ade was looking after his two year old Nephew (He charges two Kebabs an hour if you are in need of a babysitter).\r\nHis Nephew had 4 play blocks each with 6 sides. Each side has a letter from the alphabet. No letters are ever repeated. By arranging the blocks in different ways Mad Ade's nephew managed (By complete and utter fluke) to spell all the words listed below: \n\r\nBODY\r\nMAZE\r\nCURT\r\nMOVE\r\nDRAW\r\nNOTE \r\nFEAR\r\nPICK\r\nHUNT\r\nQUIT\r\nJOKE\r\nSNOB\r\nKNEW\r\nTYPE\r\nLIFE \n\r\nNow Mad Ade is relatively simple and missed the potential teaser in the situation, his mind firmly fixed on the Kebabs he was earning.\r\nCan you figure out how the letters are arranged on the 4 blocks?", "hint": "No hint available.", "answer": "Out of the 26 letters in the alphabet, Only G and X are not used. \n\r\nThere are 7 words with letter 'E' - MAZE, MOVE, NOTE, FEAR, JOKE, KNEW, TYPE, LIFE. It means that none of the letters in these 7 words can be on the same block as the letter 'E'. Hence, the other 5 letters must be from B, C, D, H, Q, S, U. \n\r\nAs BODY is one of the possible word, B and D can not be on the same block.Similarly, C and U also can not be on the same block as CURT is one of the possible word. Hence, E, H, Q, S are on the same block. \n\r\nAlso, S and B can not be on the same block (SNOB). Q and U can not be on the same block (QUIT). Hence, first Block contains C, D, E, H, Q, S \n\n\r\nthe easiest way is to write down 4 rows each with A to Z, except G and X. Take each word one by one, remove not possible letters and circle the possible letters. \n\r\nThe letters on four blocks are: \r\nBlock 1 : C, D, E, H, Q, S \r\nBlock 2 : A, B, K, L, T, V \r\nBlock 3 : F, O, P, U, W, Z \r\nBlock 4 : I, J, M, N, R, Y", "category": "Logic", "date": "10/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was looking after his two year old Nephew (He charges two Kebabs an hour if you are in need of a babysitter).\r\nHis Nephew had 4 play blocks each with 6 sides. Each side has a letter from the alphabet. No letters are ever repeated. By arranging the blocks in different ways Mad Ade's nephew managed (By complete and utter fluke) to spell all the words listed below: \n\r\nBODY\r\nMAZE\r\nCURT\r\nMOVE\r\nDRAW\r\nNOTE \r\nFEAR\r\nPICK\r\nHUNT\r\nQUIT\r\nJOKE\r\nSNOB\r\nKNEW\r\nTYPE\r\nLIFE \n\r\nNow Mad Ade is relatively simple and missed the potential teaser in the situation, his mind firmly fixed on the Kebabs he was earning.\r\nCan you figure out how the letters are arranged on the 4 blocks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOut of the 26 letters in the alphabet, Only G and X are not used. \n\r\nThere are 7 words with letter 'E' - MAZE, MOVE, NOTE, FEAR, JOKE, KNEW, TYPE, LIFE. It means that none of the letters in these 7 words can be on the same block as the letter 'E'. Hence, the other 5 letters must be from B, C, D, H, Q, S, U. \n\r\nAs BODY is one of the possible word, B and D can not be on the same block.Similarly, C and U also can not be on the same block as CURT is one of the possible word. Hence, E, H, Q, S are on the same block. \n\r\nAlso, S and B can not be on the same block (SNOB). Q and U can not be on the same block (QUIT). Hence, first Block contains C, D, E, H, Q, S \n\n\r\nthe easiest way is to write down 4 rows each with A to Z, except G and X. Take each word one by one, remove not possible letters and circle the possible letters. \n\r\nThe letters on four blocks are: \r\nBlock 1 : C, D, E, H, Q, S \r\nBlock 2 : A, B, K, L, T, V \r\nBlock 3 : F, O, P, U, W, Z \r\nBlock 4 : I, J, M, N, R, Y\n<|im_start|>answer\nOut of the 26 letters in the alphabet, Only G and X are not used. \n\r\nThere are 7 words with letter 'E' - MAZE, MOVE, NOTE, FEAR, JOKE, KNEW, TYPE, LIFE. It means that none of the letters in these 7 words can be on the same block as the letter 'E'. Hence, the other 5 letters must be from B, C, D, H, Q, S, U. \n\r\nAs BODY is one of the possible word, B and D can not be on the same block.Similarly, C and U also can not be on the same block as CURT is one of the possible word. Hence, E, H, Q, S are on the same block. \n\r\nAlso, S and B can not be on the same block (SNOB). Q and U can not be on the same block (QUIT). Hence, first Block contains C, D, E, H, Q, S \n\n\r\nthe easiest way is to write down 4 rows each with A to Z, except G and X. Take each word one by one, remove not possible letters and circle the possible letters. \n\r\nThe letters on four blocks are: \r\nBlock 1 : C, D, E, H, Q, S \r\nBlock 2 : A, B, K, L, T, V \r\nBlock 3 : F, O, P, U, W, Z \r\nBlock 4 : I, J, M, N, R, Y\n<|im_end|>" }, { "id": "#4955", "title": "TV shows", "fun": 2.23, "difficulty": 1.8900000000000001, "author": "glennyboy02", "desc": "95 people were asked what type of TV programs they liked out of news, movies and documentaries.\n\r\n64 like news\r\n80 like movies\r\n2 like only documentaries\r\n23 like movies and documentaries\r\n51 like movies and news\r\n34 like only movies and news\r\n10 like only news and documentaries\n\r\nHow many people like all three types of TV shows?", "hint": "No hint available.", "answer": "17 like all three types\n\r\nThe breakdown of the results is as follows:\n\r\n2 like only documentaries\r\n23 like only movies\r\n3 like only news\r\n6 like only movies and documentaries\r\n34 like only movies and news\r\n10 like only news and documentaries\r\n17 like all three types\r\n---\r\n95 total viewers\n\r\nThe following equations satisfy the given conditions:\n\r\n3 like only news + 34 like only movies and news + 10 like only news and documentaries + 17 like all three types = 64 like news\n\r\n23 like only movies + 6 like only movies and documentaries + 34 like only movies and news + 17 like all three types = 80 like movies\n\r\n2 like only documentaries\n\r\n6 like only movies and documentaries + 17 like all three types = 23 like movies and documentaries\n\r\n34 like only movies and news + 17 like all three types = 51 like movies and news\n\r\n34 like only movies and news\n\r\n10 like only movies and documentaries", "category": "Logic", "date": "06/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n95 people were asked what type of TV programs they liked out of news, movies and documentaries.\n\r\n64 like news\r\n80 like movies\r\n2 like only documentaries\r\n23 like movies and documentaries\r\n51 like movies and news\r\n34 like only movies and news\r\n10 like only news and documentaries\n\r\nHow many people like all three types of TV shows?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n17 like all three types\n\r\nThe breakdown of the results is as follows:\n\r\n2 like only documentaries\r\n23 like only movies\r\n3 like only news\r\n6 like only movies and documentaries\r\n34 like only movies and news\r\n10 like only news and documentaries\r\n17 like all three types\r\n---\r\n95 total viewers\n\r\nThe following equations satisfy the given conditions:\n\r\n3 like only news + 34 like only movies and news + 10 like only news and documentaries + 17 like all three types = 64 like news\n\r\n23 like only movies + 6 like only movies and documentaries + 34 like only movies and news + 17 like all three types = 80 like movies\n\r\n2 like only documentaries\n\r\n6 like only movies and documentaries + 17 like all three types = 23 like movies and documentaries\n\r\n34 like only movies and news + 17 like all three types = 51 like movies and news\n\r\n34 like only movies and news\n\r\n10 like only movies and documentaries\n<|im_start|>answer\n17 like all three types\n\r\nThe breakdown of the results is as follows:\n\r\n2 like only documentaries\r\n23 like only movies\r\n3 like only news\r\n6 like only movies and documentaries\r\n34 like only movies and news\r\n10 like only news and documentaries\r\n17 like all three types\r\n---\r\n95 total viewers\n\r\nThe following equations satisfy the given conditions:\n\r\n3 like only news + 34 like only movies and news + 10 like only news and documentaries + 17 like all three types = 64 like news\n\r\n23 like only movies + 6 like only movies and documentaries + 34 like only movies and news + 17 like all three types = 80 like movies\n\r\n2 like only documentaries\n\r\n6 like only movies and documentaries + 17 like all three types = 23 like movies and documentaries\n\r\n34 like only movies and news + 17 like all three types = 51 like movies and news\n\r\n34 like only movies and news\n\r\n10 like only movies and documentaries\n<|im_end|>" }, { "id": "#18329", "title": "Latte", "fun": 2.23, "difficulty": 1.9000000000000001, "author": "gander", "desc": "Follow these instructions: \r\nTake an 8 oz espresso and drink 1/6 of it. But it's just too strong, so you replace what you drank with hot milk. Now you drink 1/3 more and it's still to strong, so you fill it back up again with more hot milk. Now drink 1/2 of your brew. This time fill it up again with hot milk and drink the entire mix. \r\nQuestion is: \r\nHave you had more hot milk than the espresso? And how much of each have you had?", "hint": "No hint available.", "answer": "You have had the same amount of hot milk as you have the espresso. 8 oz. of espresso (1/6 plus 1/3 plus 1/2) is equal to the hot milk.", "category": "Math", "date": "07/23/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFollow these instructions: \r\nTake an 8 oz espresso and drink 1/6 of it. But it's just too strong, so you replace what you drank with hot milk. Now you drink 1/3 more and it's still to strong, so you fill it back up again with more hot milk. Now drink 1/2 of your brew. This time fill it up again with hot milk and drink the entire mix. \r\nQuestion is: \r\nHave you had more hot milk than the espresso? And how much of each have you had?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou have had the same amount of hot milk as you have the espresso. 8 oz. of espresso (1/6 plus 1/3 plus 1/2) is equal to the hot milk.\n<|im_start|>answer\nYou have had the same amount of hot milk as you have the espresso. 8 oz. of espresso (1/6 plus 1/3 plus 1/2) is equal to the hot milk.\n<|im_end|>" }, { "id": "#2139", "title": "Chicken or Egg", "fun": 2.23, "difficulty": 1.81, "author": "Mogmatt16", "desc": "This is answerable: \r\nWhich came first? The chicken or the chicken egg?", "hint": "Think evolution.", "answer": "The egg came first. The creature that gave birth to the modern day chicken was not a modern day chicken. This is because mutations occur from parent to offspring, not in an animal.", "category": "Logic", "date": "01/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis is answerable: \r\nWhich came first? The chicken or the chicken egg?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe egg came first. The creature that gave birth to the modern day chicken was not a modern day chicken. This is because mutations occur from parent to offspring, not in an animal.\n<|im_start|>answer\nThe egg came first. The creature that gave birth to the modern day chicken was not a modern day chicken. This is because mutations occur from parent to offspring, not in an animal.\n<|im_end|>" }, { "id": "#19014", "title": "Code Breaker", "fun": 2.23, "difficulty": 2.82, "author": "cnmne", "desc": "Professor Abacus has scrambled the numerals 0 through 9 to form a 10-digit security code. Each numeral is used only once. Given the following clues, what is the security code?\n\r\n1) The 4th and 5th digits form a triangle number.\r\n2) The 5th and 6th digits form a prime number.\r\n3) The 8th digit is three more than the 2nd digit.\r\n4) The 10th digit is less than the 1st digit.\r\n5) The sum of the 1st and 6th digits is twice the 9th digit.\r\n6) The sum of the 3rd, 6th, and 9th digits equals 14.\r\n7) There are three digits between the numerals 8 and 9.\r\n8) There are no more than four digits between the numerals 1 and 4.\r\n9) The numeral 5 is somewhere in the first five positions.", "hint": "No hint available.", "answer": "9452831760\n\r\n28 is a triangle number, 83 is a prime number, 7 is three more than 4, 0 is less than 9, 9 + 3 is twice 6, 5 + 3 + 6 = 14, there are three digits between 8 and 9, there are four digits between 1 and 4, 5 is in the 3rd position.", "category": "Logic", "date": "10/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nProfessor Abacus has scrambled the numerals 0 through 9 to form a 10-digit security code. Each numeral is used only once. Given the following clues, what is the security code?\n\r\n1) The 4th and 5th digits form a triangle number.\r\n2) The 5th and 6th digits form a prime number.\r\n3) The 8th digit is three more than the 2nd digit.\r\n4) The 10th digit is less than the 1st digit.\r\n5) The sum of the 1st and 6th digits is twice the 9th digit.\r\n6) The sum of the 3rd, 6th, and 9th digits equals 14.\r\n7) There are three digits between the numerals 8 and 9.\r\n8) There are no more than four digits between the numerals 1 and 4.\r\n9) The numeral 5 is somewhere in the first five positions.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9452831760\n\r\n28 is a triangle number, 83 is a prime number, 7 is three more than 4, 0 is less than 9, 9 + 3 is twice 6, 5 + 3 + 6 = 14, there are three digits between 8 and 9, there are four digits between 1 and 4, 5 is in the 3rd position.\n<|im_start|>answer\n9452831760\n\r\n28 is a triangle number, 83 is a prime number, 7 is three more than 4, 0 is less than 9, 9 + 3 is twice 6, 5 + 3 + 6 = 14, there are three digits between 8 and 9, there are four digits between 1 and 4, 5 is in the 3rd position.\n<|im_end|>" }, { "id": "#14796", "title": "Alien Ambassadors", "fun": 2.23, "difficulty": 2.87, "author": "MerconiumMax", "desc": "The boffins from NASA have received and decoded a digital message from the Galactic Council, informing them that four alien ambassadors from the solar system are due to visit Earth in the next 24 hours. The aliens are Agurgle from Uranus, Wym-Inar from Venus, ChimChim from Pluto and Mr. Arthur Johnson from Saturn. 24 hours later, they receive a mystery message saying that if any alien comes off the ship that is green, tentacled and slimy, then they are actually an undercover assassin from Neptune. By then, however, the aliens have all landed and are in adjacent decontamination booths, waiting to be let in to NASA Headquarters. One alien turns out to be green, tentacled and slimy! \r\nFrom the clues below, who is the Neptunian Assassin? \n\n\r\n1) Wym-Inar from Venus is the only ambassador in a booth next to exactly one tentacled alien.\n\r\n2). Two of the ambassadors who are not green, are each in booths next to Agurgle from Uranus.\n\r\n3) ChimChim from Pluto is the only ambassador not in a booth next to exactly one Un-slimy alien. \n\r\nWho do the NASA boffins not let out of the booth?", "hint": "Don't get too confused with the Un-slimy bit.", "answer": "ChimChim from Pluto is green, tentacled and slimy and so, is the Assassin.\n\r\nLooking at clue 2 we know that both the ambassadors standing next to Agurgle from Uranus are not green. Also, from the body of the teaser, we also know only one alien is green, tentacled and slimy. So there are two deductions to be made: (Note the key is - Alien (Green, Tentacled, Un-Slimey). Where \"Y\" stands for Yes and \"N\" stands for No. \"?\" denotes unknown, and each set of braces[] indicates a booth) \n\r\nEither Deduction A \n\r\n[ N, ?, ?] [Agurgle from Uranus Y, Y, N] [ N, ?, ?] [ ?, ?, ?] \n\r\nOr Deduction B \n\r\n[N, ?, ?] [Agurgle from Uranus ?, ?, ?][ N, ?, ?] [Y, Y, N] \n\r\nYou can see that either Agurgle from Uranus or the alien at the extreme right hand booth is green, tentacled and slimy. \n\r\nNow taking clue 3, you can work out that ChimChim from Pluto's booth is next to a slimy alien AND each of the other aliens' booths are next to precisely one slimy alien. \n\r\nSo, based on the first set of deductions, you can infer the following. \n\r\nDeduction A (ii): \r\n[ChimChim from Pluto N, ?, N] [Agurgle from Uranus Y, Y, N] [N, ?, Y] [?, ?, Y] \n\n\r\nOr Deduction B (ii): \r\n[N, ?, Y] [Agurgle from Uranus ?, ?, Y][ N, ?, N] [ChimChim from Pluto Y, Y, N] \n\r\nYou can then use clue 1 to eliminate one of these deductions: Wym-Inar from Venus is the only alien in a booth next to exactly one tentacled alien. But in Deduction A(ii), ChimChim from Pluto's booth is next to exactly one tentacled alien. Therefore, Deduction A (ii) is not possible and Deduction B (ii) is the correct one. \n\r\nDeduction B (ii):\r\n[N, ?, Y] [Agurgle from Uranus ?, ?, Y][ N, ?, N] [ChimChim from Pluto Y, Y, N] \n\r\nSo, looking again at clues 2 and 3, there are a further 2 possible deductions to be made. \n\r\nDeduction A (iii) \n\r\n[Mr. Arthur Johnson from Saturn N, N, Y] [Agurgle from Uranus] [?, N, Y] [Wym-Inar from Venus N, N, N][ChimChim from Pluto Y, Y, N] \n\r\nDeduction B (iii) \r\n[Wym-Inar from Venus N, N, Y][Agurgle from Uranus ?, Y, Y][Mr. Arthur Johnson from Saturn N, N, N][ChimChim from Pluto Y, Y, N] \n\r\nSo, ChimChim from Pluto is green, tentacled and slimy, and is therefore our Neptunian Assassin.", "category": "Logic", "date": "09/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe boffins from NASA have received and decoded a digital message from the Galactic Council, informing them that four alien ambassadors from the solar system are due to visit Earth in the next 24 hours. The aliens are Agurgle from Uranus, Wym-Inar from Venus, ChimChim from Pluto and Mr. Arthur Johnson from Saturn. 24 hours later, they receive a mystery message saying that if any alien comes off the ship that is green, tentacled and slimy, then they are actually an undercover assassin from Neptune. By then, however, the aliens have all landed and are in adjacent decontamination booths, waiting to be let in to NASA Headquarters. One alien turns out to be green, tentacled and slimy! \r\nFrom the clues below, who is the Neptunian Assassin? \n\n\r\n1) Wym-Inar from Venus is the only ambassador in a booth next to exactly one tentacled alien.\n\r\n2). Two of the ambassadors who are not green, are each in booths next to Agurgle from Uranus.\n\r\n3) ChimChim from Pluto is the only ambassador not in a booth next to exactly one Un-slimy alien. \n\r\nWho do the NASA boffins not let out of the booth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChimChim from Pluto is green, tentacled and slimy and so, is the Assassin.\n\r\nLooking at clue 2 we know that both the ambassadors standing next to Agurgle from Uranus are not green. Also, from the body of the teaser, we also know only one alien is green, tentacled and slimy. So there are two deductions to be made: (Note the key is - Alien (Green, Tentacled, Un-Slimey). Where \"Y\" stands for Yes and \"N\" stands for No. \"?\" denotes unknown, and each set of braces[] indicates a booth) \n\r\nEither Deduction A \n\r\n[ N, ?, ?] [Agurgle from Uranus Y, Y, N] [ N, ?, ?] [ ?, ?, ?] \n\r\nOr Deduction B \n\r\n[N, ?, ?] [Agurgle from Uranus ?, ?, ?][ N, ?, ?] [Y, Y, N] \n\r\nYou can see that either Agurgle from Uranus or the alien at the extreme right hand booth is green, tentacled and slimy. \n\r\nNow taking clue 3, you can work out that ChimChim from Pluto's booth is next to a slimy alien AND each of the other aliens' booths are next to precisely one slimy alien. \n\r\nSo, based on the first set of deductions, you can infer the following. \n\r\nDeduction A (ii): \r\n[ChimChim from Pluto N, ?, N] [Agurgle from Uranus Y, Y, N] [N, ?, Y] [?, ?, Y] \n\n\r\nOr Deduction B (ii): \r\n[N, ?, Y] [Agurgle from Uranus ?, ?, Y][ N, ?, N] [ChimChim from Pluto Y, Y, N] \n\r\nYou can then use clue 1 to eliminate one of these deductions: Wym-Inar from Venus is the only alien in a booth next to exactly one tentacled alien. But in Deduction A(ii), ChimChim from Pluto's booth is next to exactly one tentacled alien. Therefore, Deduction A (ii) is not possible and Deduction B (ii) is the correct one. \n\r\nDeduction B (ii):\r\n[N, ?, Y] [Agurgle from Uranus ?, ?, Y][ N, ?, N] [ChimChim from Pluto Y, Y, N] \n\r\nSo, looking again at clues 2 and 3, there are a further 2 possible deductions to be made. \n\r\nDeduction A (iii) \n\r\n[Mr. Arthur Johnson from Saturn N, N, Y] [Agurgle from Uranus] [?, N, Y] [Wym-Inar from Venus N, N, N][ChimChim from Pluto Y, Y, N] \n\r\nDeduction B (iii) \r\n[Wym-Inar from Venus N, N, Y][Agurgle from Uranus ?, Y, Y][Mr. Arthur Johnson from Saturn N, N, N][ChimChim from Pluto Y, Y, N] \n\r\nSo, ChimChim from Pluto is green, tentacled and slimy, and is therefore our Neptunian Assassin.\n<|im_start|>answer\nChimChim from Pluto is green, tentacled and slimy and so, is the Assassin.\n\r\nLooking at clue 2 we know that both the ambassadors standing next to Agurgle from Uranus are not green. Also, from the body of the teaser, we also know only one alien is green, tentacled and slimy. So there are two deductions to be made: (Note the key is - Alien (Green, Tentacled, Un-Slimey). Where \"Y\" stands for Yes and \"N\" stands for No. \"?\" denotes unknown, and each set of braces[] indicates a booth) \n\r\nEither Deduction A \n\r\n[ N, ?, ?] [Agurgle from Uranus Y, Y, N] [ N, ?, ?] [ ?, ?, ?] \n\r\nOr Deduction B \n\r\n[N, ?, ?] [Agurgle from Uranus ?, ?, ?][ N, ?, ?] [Y, Y, N] \n\r\nYou can see that either Agurgle from Uranus or the alien at the extreme right hand booth is green, tentacled and slimy. \n\r\nNow taking clue 3, you can work out that ChimChim from Pluto's booth is next to a slimy alien AND each of the other aliens' booths are next to precisely one slimy alien. \n\r\nSo, based on the first set of deductions, you can infer the following. \n\r\nDeduction A (ii): \r\n[ChimChim from Pluto N, ?, N] [Agurgle from Uranus Y, Y, N] [N, ?, Y] [?, ?, Y] \n\n\r\nOr Deduction B (ii): \r\n[N, ?, Y] [Agurgle from Uranus ?, ?, Y][ N, ?, N] [ChimChim from Pluto Y, Y, N] \n\r\nYou can then use clue 1 to eliminate one of these deductions: Wym-Inar from Venus is the only alien in a booth next to exactly one tentacled alien. But in Deduction A(ii), ChimChim from Pluto's booth is next to exactly one tentacled alien. Therefore, Deduction A (ii) is not possible and Deduction B (ii) is the correct one. \n\r\nDeduction B (ii):\r\n[N, ?, Y] [Agurgle from Uranus ?, ?, Y][ N, ?, N] [ChimChim from Pluto Y, Y, N] \n\r\nSo, looking again at clues 2 and 3, there are a further 2 possible deductions to be made. \n\r\nDeduction A (iii) \n\r\n[Mr. Arthur Johnson from Saturn N, N, Y] [Agurgle from Uranus] [?, N, Y] [Wym-Inar from Venus N, N, N][ChimChim from Pluto Y, Y, N] \n\r\nDeduction B (iii) \r\n[Wym-Inar from Venus N, N, Y][Agurgle from Uranus ?, Y, Y][Mr. Arthur Johnson from Saturn N, N, N][ChimChim from Pluto Y, Y, N] \n\r\nSo, ChimChim from Pluto is green, tentacled and slimy, and is therefore our Neptunian Assassin.\n<|im_end|>" }, { "id": "#955", "title": "How Tall are They?", "fun": 2.22, "difficulty": 1.73, "author": "Michelle", "desc": "Kevin is 14 inches taller than George. The difference between Kevin and Richard is two inches less than that between Richard and George. Kevin at 6'6\" is the tallest. How tall are Richard and George?", "hint": "No hint available.", "answer": "If Kevin is 6'6\" tall, George must be 5'4\" tall, and Richard must be 6' tall because he is 6\" shorter than Kevin and 8\" taller than George.", "category": "Math", "date": "10/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKevin is 14 inches taller than George. The difference between Kevin and Richard is two inches less than that between Richard and George. Kevin at 6'6\" is the tallest. How tall are Richard and George?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Kevin is 6'6\" tall, George must be 5'4\" tall, and Richard must be 6' tall because he is 6\" shorter than Kevin and 8\" taller than George.\n<|im_start|>answer\nIf Kevin is 6'6\" tall, George must be 5'4\" tall, and Richard must be 6' tall because he is 6\" shorter than Kevin and 8\" taller than George.\n<|im_end|>" }, { "id": "#23776", "title": "Confusion Over Jewels", "fun": 2.22, "difficulty": 1.03, "author": "rajasekhar", "desc": "Young Princess Rana of Rajasthan has four pieces of jewelry that are family heirlooms: a necklace, a bracelet, a ring, and a brooch. Being a fashion-conscious person, she doesn't like to wear the same thing twice.\n\r\n How many different combinations of crown jewels can she wear?", "hint": "She may wear any number of jewels at a time.", "answer": "The answer is 15. The Princess can wear four combinations of one piece of jewelry; six combinations of two, four combinations of three and one combination of all the jewels. The total is 15 different combinations.", "category": "Math", "date": "06/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYoung Princess Rana of Rajasthan has four pieces of jewelry that are family heirlooms: a necklace, a bracelet, a ring, and a brooch. Being a fashion-conscious person, she doesn't like to wear the same thing twice.\n\r\n How many different combinations of crown jewels can she wear?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 15. The Princess can wear four combinations of one piece of jewelry; six combinations of two, four combinations of three and one combination of all the jewels. The total is 15 different combinations.\n<|im_start|>answer\nThe answer is 15. The Princess can wear four combinations of one piece of jewelry; six combinations of two, four combinations of three and one combination of all the jewels. The total is 15 different combinations.\n<|im_end|>" }, { "id": "#20861", "title": "The Balcony Scene", "fun": 2.22, "difficulty": 2.93, "author": "Sane", "desc": "You are a scenery creator for plays and you have just been asked to create the Balcony for Romeo and Juliet.\n\r\nThe stage is 7m from the floor to the spotlights.\r\nThe balcony has to be a full circle (the other half will act as a platform for the actors waiting on the other side of the wall). \r\nThe balcony floor is 30cm thick.\r\nThe balcony needs a 1m(height) x 10cm(thickness) solid fence surrounding the perimeter of the half that will be seen by the audience.\r\nThe floor of the balcony must be exactly 4m from the ground.\r\nThe balcony is like so in order for the spot light (that shines at a 45 degree angle to the roof) will cover the entire balcony precisely when it is positioned above the middle of the balcony.\r\nPine is cheap at exactly $1 per 5000cm^3, tax included.\n\r\nExactly how much money will you spend to build the balcony?\n\r\nConversions:\n\r\n100cm = 1m\r\n2.54cm = 1inch", "hint": "If the floor of the balcony is 4 meters from the ground, and the room is 7 meters, then the floor is 3 meters from the spotlight. If the spot light shines at a 45 degree angle and the spot light will cover the entire balcony precisely when it is positioned above the middle of the balcony, then the radius of the balcony floor will be 3 meters (if the hypotenuse of a triangle is at a 45 degree angle to the y axis (and the side x is 90 degrees to the side y), the side x will always equal the side y and the remaining side will be the hypotenuse of those [the rules of an isosceles triangle]).", "answer": "[SEE HINT]\r\nTherefore, the stage will be solved by the formula for a cylinder, [pi(r)^2]h where r = 300cm and h = 30cm (rule 3).\n\r\nThe balcony now needs a 100 cm x 10 cm solid fence. This now defies the simple rules of perimeter, you must incorporate the loss of radius per added centimeter towards the middle. In other words, you solve for the perimeter 10 times with the thickness valued as 1, incorporating the new radius each time. Remember, since it is only on one half, each answer must be halved.\n\r\n2pi(r) finds the perimeter. Then multiplied by the height will be formulated 2pi(r)h where r = 300cm and h = 100cm. Since we only need half of that, it will be [2pi(r)h]/2 = pi(r)h.\n\r\nThen we need to find the 9 other rings incorporating the loss of radius.\n\r\npi(r-1)h + pi(r-2)h + pi(r-3)h + pi(r-4)h + pi(r-5)h + pi(r-6)h + pi(r-7)h + pi(r-8)h + pi(r-9)h\n\r\nThis added to pi(r)h will yield the volume of the fence surrounding half of the stage.\n\r\nThus, the final equation will be: \n\r\nlet a represent the height of the room, then b represent the height of the balcony off the floor, then f represent the thickness of the balcony floor, then r represent a-b or the radius of the balcony floor, then h represent the height of the fence. \n\r\nV = {[pi(a-b)^2]f + [pi(r)h + pi(r-1)h + pi(r-2)h + pi(r-3)h + pi(r-4)h + pi(r-5)h + pi(r-6)h + pi(r-7)h + pi(r-8)h + pi(r-9)h]} \r\n= {[pi(90000)30] + [pi(300)100 + pi(299)100 + pi(298)100 ... ... pi(291)100]} \r\n= {(2 700 000pi) + [30 000pi + 29 900pi + 29 800pi + 29 700pi ... ... 29 100pi]} \r\n~= 8482300.16469244 + 928340.629135783 \r\n~= 9410640.79382822 cm^3 \n\r\nIf pine is cheap at exactly $1 per 5000cm^3, tax included, \n\r\nthe price is then: \n\r\nP ~= (9410640.79382822 / 5000) * 1.00 \r\n~= $1882.13", "category": "Math", "date": "02/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are a scenery creator for plays and you have just been asked to create the Balcony for Romeo and Juliet.\n\r\nThe stage is 7m from the floor to the spotlights.\r\nThe balcony has to be a full circle (the other half will act as a platform for the actors waiting on the other side of the wall). \r\nThe balcony floor is 30cm thick.\r\nThe balcony needs a 1m(height) x 10cm(thickness) solid fence surrounding the perimeter of the half that will be seen by the audience.\r\nThe floor of the balcony must be exactly 4m from the ground.\r\nThe balcony is like so in order for the spot light (that shines at a 45 degree angle to the roof) will cover the entire balcony precisely when it is positioned above the middle of the balcony.\r\nPine is cheap at exactly $1 per 5000cm^3, tax included.\n\r\nExactly how much money will you spend to build the balcony?\n\r\nConversions:\n\r\n100cm = 1m\r\n2.54cm = 1inch\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n[SEE HINT]\r\nTherefore, the stage will be solved by the formula for a cylinder, [pi(r)^2]h where r = 300cm and h = 30cm (rule 3).\n\r\nThe balcony now needs a 100 cm x 10 cm solid fence. This now defies the simple rules of perimeter, you must incorporate the loss of radius per added centimeter towards the middle. In other words, you solve for the perimeter 10 times with the thickness valued as 1, incorporating the new radius each time. Remember, since it is only on one half, each answer must be halved.\n\r\n2pi(r) finds the perimeter. Then multiplied by the height will be formulated 2pi(r)h where r = 300cm and h = 100cm. Since we only need half of that, it will be [2pi(r)h]/2 = pi(r)h.\n\r\nThen we need to find the 9 other rings incorporating the loss of radius.\n\r\npi(r-1)h + pi(r-2)h + pi(r-3)h + pi(r-4)h + pi(r-5)h + pi(r-6)h + pi(r-7)h + pi(r-8)h + pi(r-9)h\n\r\nThis added to pi(r)h will yield the volume of the fence surrounding half of the stage.\n\r\nThus, the final equation will be: \n\r\nlet a represent the height of the room, then b represent the height of the balcony off the floor, then f represent the thickness of the balcony floor, then r represent a-b or the radius of the balcony floor, then h represent the height of the fence. \n\r\nV = {[pi(a-b)^2]f + [pi(r)h + pi(r-1)h + pi(r-2)h + pi(r-3)h + pi(r-4)h + pi(r-5)h + pi(r-6)h + pi(r-7)h + pi(r-8)h + pi(r-9)h]} \r\n= {[pi(90000)30] + [pi(300)100 + pi(299)100 + pi(298)100 ... ... pi(291)100]} \r\n= {(2 700 000pi) + [30 000pi + 29 900pi + 29 800pi + 29 700pi ... ... 29 100pi]} \r\n~= 8482300.16469244 + 928340.629135783 \r\n~= 9410640.79382822 cm^3 \n\r\nIf pine is cheap at exactly $1 per 5000cm^3, tax included, \n\r\nthe price is then: \n\r\nP ~= (9410640.79382822 / 5000) * 1.00 \r\n~= $1882.13\n<|im_start|>answer\n[SEE HINT]\r\nTherefore, the stage will be solved by the formula for a cylinder, [pi(r)^2]h where r = 300cm and h = 30cm (rule 3).\n\r\nThe balcony now needs a 100 cm x 10 cm solid fence. This now defies the simple rules of perimeter, you must incorporate the loss of radius per added centimeter towards the middle. In other words, you solve for the perimeter 10 times with the thickness valued as 1, incorporating the new radius each time. Remember, since it is only on one half, each answer must be halved.\n\r\n2pi(r) finds the perimeter. Then multiplied by the height will be formulated 2pi(r)h where r = 300cm and h = 100cm. Since we only need half of that, it will be [2pi(r)h]/2 = pi(r)h.\n\r\nThen we need to find the 9 other rings incorporating the loss of radius.\n\r\npi(r-1)h + pi(r-2)h + pi(r-3)h + pi(r-4)h + pi(r-5)h + pi(r-6)h + pi(r-7)h + pi(r-8)h + pi(r-9)h\n\r\nThis added to pi(r)h will yield the volume of the fence surrounding half of the stage.\n\r\nThus, the final equation will be: \n\r\nlet a represent the height of the room, then b represent the height of the balcony off the floor, then f represent the thickness of the balcony floor, then r represent a-b or the radius of the balcony floor, then h represent the height of the fence. \n\r\nV = {[pi(a-b)^2]f + [pi(r)h + pi(r-1)h + pi(r-2)h + pi(r-3)h + pi(r-4)h + pi(r-5)h + pi(r-6)h + pi(r-7)h + pi(r-8)h + pi(r-9)h]} \r\n= {[pi(90000)30] + [pi(300)100 + pi(299)100 + pi(298)100 ... ... pi(291)100]} \r\n= {(2 700 000pi) + [30 000pi + 29 900pi + 29 800pi + 29 700pi ... ... 29 100pi]} \r\n~= 8482300.16469244 + 928340.629135783 \r\n~= 9410640.79382822 cm^3 \n\r\nIf pine is cheap at exactly $1 per 5000cm^3, tax included, \n\r\nthe price is then: \n\r\nP ~= (9410640.79382822 / 5000) * 1.00 \r\n~= $1882.13\n<|im_end|>" }, { "id": "#6525", "title": "Billy And Virginia", "fun": 2.22, "difficulty": 0.99, "author": "missie", "desc": "Billy started out on a trip from Virginia with a full tank of fuel, 12 gallons exactly. However, the moment Billy started out, the fuel tank sprung a leak. Billy travelled at 50 mph until he ran out of fuel exactly 4 hours later. Billy knows that the car does 25 miles for each gallon. How much fuel had Billy lost through the hole?", "hint": "No hint available.", "answer": "Billy had lost 4 gallons. Since he travelled at 50 mph for 4 hours = 200 miles, Billy used 8 gallons for his journey.", "category": "Math", "date": "08/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBilly started out on a trip from Virginia with a full tank of fuel, 12 gallons exactly. However, the moment Billy started out, the fuel tank sprung a leak. Billy travelled at 50 mph until he ran out of fuel exactly 4 hours later. Billy knows that the car does 25 miles for each gallon. How much fuel had Billy lost through the hole?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBilly had lost 4 gallons. Since he travelled at 50 mph for 4 hours = 200 miles, Billy used 8 gallons for his journey.\n<|im_start|>answer\nBilly had lost 4 gallons. Since he travelled at 50 mph for 4 hours = 200 miles, Billy used 8 gallons for his journey.\n<|im_end|>" }, { "id": "#48620", "title": "Holding Hands", "fun": 2.22, "difficulty": 1.31, "author": "mjk13", "desc": "A man and woman run through a field holding hands. They bound toward the sunset, happy as can be. Suddenly, the man moves off of his straight line course and starts veering to his left. At the same time, the woman begins running off to her right.\r\nThey continue this for a full minute, but never let go of each others hands. How is this possible?", "hint": "Think of the way they are facing. (Cardinal directions)", "answer": "They start off facing each other, with the woman facing east and the man west. They start running west (the woman runs backwards). Then when they veer off, they head south (to the woman's right and the man's left).", "category": "Logic", "date": "04/10/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man and woman run through a field holding hands. They bound toward the sunset, happy as can be. Suddenly, the man moves off of his straight line course and starts veering to his left. At the same time, the woman begins running off to her right.\r\nThey continue this for a full minute, but never let go of each others hands. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey start off facing each other, with the woman facing east and the man west. They start running west (the woman runs backwards). Then when they veer off, they head south (to the woman's right and the man's left).\n<|im_start|>answer\nThey start off facing each other, with the woman facing east and the man west. They start running west (the woman runs backwards). Then when they veer off, they head south (to the woman's right and the man's left).\n<|im_end|>" }, { "id": "#23159", "title": "11 By 8", "fun": 2.22, "difficulty": 2.26, "author": "superben", "desc": "Use any math symbols and eleven 8's to make a total of 10,000.", "hint": "No hint available.", "answer": "88888/8 - 8888/8", "category": "Math", "date": "05/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUse any math symbols and eleven 8's to make a total of 10,000.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n88888/8 - 8888/8\n<|im_start|>answer\n88888/8 - 8888/8\n<|im_end|>" }, { "id": "#23188", "title": "One Small Story...", "fun": 2.22, "difficulty": 1.73, "author": "Muzozavr", "desc": "Mr. Weft is kidnapped. He is in a locked room. The door is locked by a 4-symbol code. \n\r\nHis kidnapper said, \"I am an evil kidnapper. But I LOVE riddles, puzzles... so I'll give you one. The door is locked by code, as you well know. Take this letter with a small riddle. From this riddle you can get a door-code and get out. But be quick, after 3 days I'll change the code, so you can't get out anymore. Start the riddle!\"\n\r\nThe letter reads: \n\r\nThe first letter, which you get today: \"Cambridge's alleys stop everyone.\"\n\r\nWeft thought HARD. But he can't find an answer. \n\r\nHelp him!", "hint": "Read this teaser again and again... concentrate on one of words.... the \" symbols in the letter are also important...", "answer": "CASE\n\r\nTHE FIRST LETTER... the letter must be understood in another way... Take the first letters. The \"symbols\" show where to start and where to end.", "category": "Logic", "date": "05/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Weft is kidnapped. He is in a locked room. The door is locked by a 4-symbol code. \n\r\nHis kidnapper said, \"I am an evil kidnapper. But I LOVE riddles, puzzles... so I'll give you one. The door is locked by code, as you well know. Take this letter with a small riddle. From this riddle you can get a door-code and get out. But be quick, after 3 days I'll change the code, so you can't get out anymore. Start the riddle!\"\n\r\nThe letter reads: \n\r\nThe first letter, which you get today: \"Cambridge's alleys stop everyone.\"\n\r\nWeft thought HARD. But he can't find an answer. \n\r\nHelp him!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCASE\n\r\nTHE FIRST LETTER... the letter must be understood in another way... Take the first letters. The \"symbols\" show where to start and where to end.\n<|im_start|>answer\nCASE\n\r\nTHE FIRST LETTER... the letter must be understood in another way... Take the first letters. The \"symbols\" show where to start and where to end.\n<|im_end|>" }, { "id": "#8636", "title": "Wonks / Winks", "fun": 2.22, "difficulty": 2.42, "author": "mad-ade", "desc": "In the land of Madadia they have their own Currency called the Wonk, which is made up of one hundred Winks.\r\nMad Ade entered the Bank of Madadia and requested to withdraw a specific amount of Wonks and Winks\n\r\nX Wonks and Y Winks.\n\r\nThe Cashier misheard Mad Ade's request and accidentally gave Mad Ade Y Wonks and X Winks. Neither Mad Ade or the cashier noticed the mistake, so Mad Ade left the bank. \n\r\nAfter spending 20 Winks in the \"Sweaty Chef\" Kebab shop, Mad Ade counts his money, and to his surprise, he has double the amount he wanted to withdraw to begin with. \n\r\nFind X and Y. (1Wonk = 100 Winks)", "hint": "No hint available.", "answer": "As given, the person wanted to withdraw 100X + Y Winks. \n\r\nBut he got 100Y + X Winks. \n\r\nAfter spending 20 Winks, he has double the amount he wanted to withdraw. Hence, the equation is\r\n 2 * (100X + Y) = 100Y + X - 20\r\n 200X + 2Y = 100Y +X - 20\r\n 199X - 98Y = -20\r\n 98Y - 199X = 20\n\n\r\nNow, we got one equation; but there are 2 variables. We have to apply little bit of logic over here. We know that if we interchange X & Y, amount gets double. So Y should be twice of X or one more than twice of X i.e. Y = 2X or Y = 2X+1 \n\r\nCase I : Y=2X \r\nSolving two equations simultaneously \r\n98Y - 199X = 20 \r\nY - 2X = 0 \r\nWe get X = - 20/3 & Y = - 40/2 \n\r\nCase II : Y=2X+1 \r\nSolving two equations simultaneously \r\n98Y - 199X = 20 \r\nY - 2X = 1 \r\nWe get X = 26 & Y = 53 \n\r\nNow, its obvious that he wanted to withdraw 26 Wonks and 53 Winks", "category": "Math", "date": "11/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the land of Madadia they have their own Currency called the Wonk, which is made up of one hundred Winks.\r\nMad Ade entered the Bank of Madadia and requested to withdraw a specific amount of Wonks and Winks\n\r\nX Wonks and Y Winks.\n\r\nThe Cashier misheard Mad Ade's request and accidentally gave Mad Ade Y Wonks and X Winks. Neither Mad Ade or the cashier noticed the mistake, so Mad Ade left the bank. \n\r\nAfter spending 20 Winks in the \"Sweaty Chef\" Kebab shop, Mad Ade counts his money, and to his surprise, he has double the amount he wanted to withdraw to begin with. \n\r\nFind X and Y. (1Wonk = 100 Winks)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAs given, the person wanted to withdraw 100X + Y Winks. \n\r\nBut he got 100Y + X Winks. \n\r\nAfter spending 20 Winks, he has double the amount he wanted to withdraw. Hence, the equation is\r\n 2 * (100X + Y) = 100Y + X - 20\r\n 200X + 2Y = 100Y +X - 20\r\n 199X - 98Y = -20\r\n 98Y - 199X = 20\n\n\r\nNow, we got one equation; but there are 2 variables. We have to apply little bit of logic over here. We know that if we interchange X & Y, amount gets double. So Y should be twice of X or one more than twice of X i.e. Y = 2X or Y = 2X+1 \n\r\nCase I : Y=2X \r\nSolving two equations simultaneously \r\n98Y - 199X = 20 \r\nY - 2X = 0 \r\nWe get X = - 20/3 & Y = - 40/2 \n\r\nCase II : Y=2X+1 \r\nSolving two equations simultaneously \r\n98Y - 199X = 20 \r\nY - 2X = 1 \r\nWe get X = 26 & Y = 53 \n\r\nNow, its obvious that he wanted to withdraw 26 Wonks and 53 Winks\n<|im_start|>answer\nAs given, the person wanted to withdraw 100X + Y Winks. \n\r\nBut he got 100Y + X Winks. \n\r\nAfter spending 20 Winks, he has double the amount he wanted to withdraw. Hence, the equation is\r\n 2 * (100X + Y) = 100Y + X - 20\r\n 200X + 2Y = 100Y +X - 20\r\n 199X - 98Y = -20\r\n 98Y - 199X = 20\n\n\r\nNow, we got one equation; but there are 2 variables. We have to apply little bit of logic over here. We know that if we interchange X & Y, amount gets double. So Y should be twice of X or one more than twice of X i.e. Y = 2X or Y = 2X+1 \n\r\nCase I : Y=2X \r\nSolving two equations simultaneously \r\n98Y - 199X = 20 \r\nY - 2X = 0 \r\nWe get X = - 20/3 & Y = - 40/2 \n\r\nCase II : Y=2X+1 \r\nSolving two equations simultaneously \r\n98Y - 199X = 20 \r\nY - 2X = 1 \r\nWe get X = 26 & Y = 53 \n\r\nNow, its obvious that he wanted to withdraw 26 Wonks and 53 Winks\n<|im_end|>" }, { "id": "#28696", "title": "Mountain of Love", "fun": 2.22, "difficulty": 2.67, "author": "miyukina", "desc": "Once upon a time, in the Kingdom of Snow, there lived the fair Princess Miyuki, who had always been fascinated by fairy tales and the stories of the wonders of the world. She believed that her sleeping, handsome prince was cursed to be one of the mummies in the pyramids of Egypt, and when she was done being Fantaghiro-saving-her-Romualdo, her prince would then build a beautiful palace as a monument of their love (which of course would be more beautiful than Taj Mahal) where both of them will live happily ever after...\n\r\nSo, you see, that's why Princess Miyuki had refused each and every love declaration or marriage proposal that came her way. \n\r\nBut of course, what's a story without the brave and wise heroic prince? Here comes Prince Hajikidama of the Marbles Kingdom. He's no mummy, but his brilliant(?) brain deduced that in order to win the princess' heart, he'd have to give her what she wanted most - her fantasy, and his token of understanding (her childish delusional nature). \n\r\nIn the end, labouring his mind's creativity department for all its worth, Prince Hajikidama decided that a 'Mountain of Love', reaching so high it collected the never-fallen-snow in Marbles Kingdom, might do the trick. That actually is a tetrahedral-shaped (pyramid with 4 equilateral triangular faces) crystallic marbles-made structure (like a giant pile of apples or oranges at a greengrocer's store) consisting of one marble crowning on the top layer, three on the next-to-top layer, six on the third layer, ten on the fourth layer, and so forth. If there are exactly 1,000,000 layers, specify the total number of marbles needed in the construction of entire mountain.", "hint": "No hint available.", "answer": "The formula is\n\r\nS = n(n+1)(n+2)/6\n\r\nso when n = 1,000,000\n\r\nS = 166,667,166,667,000,000", "category": "Math", "date": "02/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOnce upon a time, in the Kingdom of Snow, there lived the fair Princess Miyuki, who had always been fascinated by fairy tales and the stories of the wonders of the world. She believed that her sleeping, handsome prince was cursed to be one of the mummies in the pyramids of Egypt, and when she was done being Fantaghiro-saving-her-Romualdo, her prince would then build a beautiful palace as a monument of their love (which of course would be more beautiful than Taj Mahal) where both of them will live happily ever after...\n\r\nSo, you see, that's why Princess Miyuki had refused each and every love declaration or marriage proposal that came her way. \n\r\nBut of course, what's a story without the brave and wise heroic prince? Here comes Prince Hajikidama of the Marbles Kingdom. He's no mummy, but his brilliant(?) brain deduced that in order to win the princess' heart, he'd have to give her what she wanted most - her fantasy, and his token of understanding (her childish delusional nature). \n\r\nIn the end, labouring his mind's creativity department for all its worth, Prince Hajikidama decided that a 'Mountain of Love', reaching so high it collected the never-fallen-snow in Marbles Kingdom, might do the trick. That actually is a tetrahedral-shaped (pyramid with 4 equilateral triangular faces) crystallic marbles-made structure (like a giant pile of apples or oranges at a greengrocer's store) consisting of one marble crowning on the top layer, three on the next-to-top layer, six on the third layer, ten on the fourth layer, and so forth. If there are exactly 1,000,000 layers, specify the total number of marbles needed in the construction of entire mountain.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe formula is\n\r\nS = n(n+1)(n+2)/6\n\r\nso when n = 1,000,000\n\r\nS = 166,667,166,667,000,000\n<|im_start|>answer\nThe formula is\n\r\nS = n(n+1)(n+2)/6\n\r\nso when n = 1,000,000\n\r\nS = 166,667,166,667,000,000\n<|im_end|>" }, { "id": "#2323", "title": "Triangled", "fun": 2.22, "difficulty": 2.03, "author": "mishiko", "desc": "1,4,9,16,25 are all squared numbers.\r\n?,?,?,?,? are all triangled numbers.\r\nFill in the blanks.", "hint": "If writing on paper use dots to help you.", "answer": "1,3,6,10,15", "category": "Math", "date": "02/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n1,4,9,16,25 are all squared numbers.\r\n?,?,?,?,? are all triangled numbers.\r\nFill in the blanks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1,3,6,10,15\n<|im_start|>answer\n1,3,6,10,15\n<|im_end|>" }, { "id": "#42691", "title": "Singing Stars", "fun": 2.22, "difficulty": 0.85, "author": "eggface", "desc": "It's the Grand Final for the Choir Festival, and the judges have lost their list telling them which choirs are competing, the order in which the choirs will perform, and the colours of each choir.\n\r\nThe choirs are: Music Notes, Chord Singer, Pop 'n Rock and Sing-a-Song.\r\nThe choir colours are: red, blue, pink and green.\n\r\n1) Both Pop 'n Rock and Chord Singer have primary colours.\r\n2) The pink choir performed first.\r\n3) The last choir to perform was Sing-a-Song.\r\n4) Pop 'n Rock didn't perform second.\r\n5) The blue choir didn't perform third.\n\r\nCan you determine the information before the Grand Final begins?", "hint": "No hint available.", "answer": "Music Notes was pink and performed first.\r\nChord Singer was blue and performed second.\r\nPop 'n Rock was red and performed third.\r\nSing-a-Song was green and performed last.", "category": "Logic-Grid", "date": "08/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's the Grand Final for the Choir Festival, and the judges have lost their list telling them which choirs are competing, the order in which the choirs will perform, and the colours of each choir.\n\r\nThe choirs are: Music Notes, Chord Singer, Pop 'n Rock and Sing-a-Song.\r\nThe choir colours are: red, blue, pink and green.\n\r\n1) Both Pop 'n Rock and Chord Singer have primary colours.\r\n2) The pink choir performed first.\r\n3) The last choir to perform was Sing-a-Song.\r\n4) Pop 'n Rock didn't perform second.\r\n5) The blue choir didn't perform third.\n\r\nCan you determine the information before the Grand Final begins?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMusic Notes was pink and performed first.\r\nChord Singer was blue and performed second.\r\nPop 'n Rock was red and performed third.\r\nSing-a-Song was green and performed last.\n<|im_start|>answer\nMusic Notes was pink and performed first.\r\nChord Singer was blue and performed second.\r\nPop 'n Rock was red and performed third.\r\nSing-a-Song was green and performed last.\n<|im_end|>" }, { "id": "#3137", "title": "Pumpkin", "fun": 2.22, "difficulty": 1.85, "author": "204_blaze_41", "desc": "A particular pumpkin weighs ¾ of a kilogram plus ¾ of itself. How much does this pumpkin weigh?", "hint": "No hint available.", "answer": "3 kilograms. Since this pumpkin weighs ¾ of a kilogram plus ¾ of itself, then ¼ of a pumpkin weighs ¾ of a kilogram and a whole pumpkin must then weigh 3 kilograms.", "category": "Math", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA particular pumpkin weighs ¾ of a kilogram plus ¾ of itself. How much does this pumpkin weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 kilograms. Since this pumpkin weighs ¾ of a kilogram plus ¾ of itself, then ¼ of a pumpkin weighs ¾ of a kilogram and a whole pumpkin must then weigh 3 kilograms.\n<|im_start|>answer\n3 kilograms. Since this pumpkin weighs ¾ of a kilogram plus ¾ of itself, then ¼ of a pumpkin weighs ¾ of a kilogram and a whole pumpkin must then weigh 3 kilograms.\n<|im_end|>" }, { "id": "#4144", "title": "Losing Time", "fun": 2.22, "difficulty": 1.9000000000000001, "author": "librashorty", "desc": "I was recently given a new watch for my birthday. However, as usual with my presents, it was quite useless as it loses 6 minutes every hour. I set it using my friend's accurate watch at midnight and it now shows 10:39am. I know that the watch stopped 21 minutes ago so what is the correct time now?", "hint": "No hint available.", "answer": "12:11pm; since the clock is losing 6 minutes every hour, for every real hour which has passed, the clock will only show 54 minutes. Since the clock shows 10:39am, we know that 639 clock minutes have passed. This therefore equals 710 real minutes and hence 11 hrs 50 mins. The clock stopped 21 minutes ago, therefore the time must now be 12:11pm.", "category": "Math", "date": "05/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI was recently given a new watch for my birthday. However, as usual with my presents, it was quite useless as it loses 6 minutes every hour. I set it using my friend's accurate watch at midnight and it now shows 10:39am. I know that the watch stopped 21 minutes ago so what is the correct time now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12:11pm; since the clock is losing 6 minutes every hour, for every real hour which has passed, the clock will only show 54 minutes. Since the clock shows 10:39am, we know that 639 clock minutes have passed. This therefore equals 710 real minutes and hence 11 hrs 50 mins. The clock stopped 21 minutes ago, therefore the time must now be 12:11pm.\n<|im_start|>answer\n12:11pm; since the clock is losing 6 minutes every hour, for every real hour which has passed, the clock will only show 54 minutes. Since the clock shows 10:39am, we know that 639 clock minutes have passed. This therefore equals 710 real minutes and hence 11 hrs 50 mins. The clock stopped 21 minutes ago, therefore the time must now be 12:11pm.\n<|im_end|>" }, { "id": "#4303", "title": "Good Ideas", "fun": 2.22, "difficulty": 2.5100000000000002, "author": "mad-ade", "desc": "some\r\ngood +\r\n-----\r\nideas\n\r\nExchange the letter for numbers to make the sum work, bear in mind that none of the rows of numbers begin or end in zero, and if x=2 then all X's equal 2.", "hint": "No hint available.", "answer": "8795\r\n4773 +\r\n----\r\n13568", "category": "Math", "date": "05/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nsome\r\ngood +\r\n-----\r\nideas\n\r\nExchange the letter for numbers to make the sum work, bear in mind that none of the rows of numbers begin or end in zero, and if x=2 then all X's equal 2.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8795\r\n4773 +\r\n----\r\n13568\n<|im_start|>answer\n8795\r\n4773 +\r\n----\r\n13568\n<|im_end|>" }, { "id": "#930", "title": "The Rushed Carpenter", "fun": 2.22, "difficulty": 1.21, "author": "Michelle", "desc": "A carpenter was in a terrible hurry. He had to work as quickly as possible to cut a very heavy 10 foot plank into 10 equal sections. If it takes 1 minute per cut, how long will it take him to get the 10 equal pieces?", "hint": "No hint available.", "answer": "9 minutes. It only takes 9 cuts to get 10 equal sections.", "category": "Math", "date": "10/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA carpenter was in a terrible hurry. He had to work as quickly as possible to cut a very heavy 10 foot plank into 10 equal sections. If it takes 1 minute per cut, how long will it take him to get the 10 equal pieces?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9 minutes. It only takes 9 cuts to get 10 equal sections.\n<|im_start|>answer\n9 minutes. It only takes 9 cuts to get 10 equal sections.\n<|im_end|>" }, { "id": "#35364", "title": "More Mystery Numbers", "fun": 2.22, "difficulty": 3.01, "author": "cnmne", "desc": "There is a 10-digit number, represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) A + D = a square number\r\n2) G + J = a triangle number\r\n3) B + I = an even number\r\n4) E * F = an odd number\r\n5) C * H = a prime number\r\n6) A / G = G / C\r\n7) E + I = B + H", "hint": "A triangle number can be expressed as the sum of the numbers 1 to n, for any integer value of n. Therefore the triangle numbers are 1, 3, 6, 10, 15, 21, 28, ...", "answer": "4615972308\n\r\nFor the product of two numbers to be a prime number (clue #5), one of those two numbers must be 1. Therefore, either C or H must be 1.\n\r\nTo achieve the required proportion (clue #6), the numerals [AGC] must be one of the following combinations: 931 or 421 or 842.\n\r\nIf [AGC] = 842, then D would have to be 1 (clue #1). Since either C or H must be 1, then D can not be 1. Since D can not be 1, then A can not be 8. Therefore, [AGC] can not be 842. The only remaining possibilities for [AGC] are 931 and 421. In either case, C = 1.\n\r\nIf [AGC] = 931, then D must be either 0 or 7 (clue #1) and J must be either 0 or 7 (clue #2). Therefore, between them, D and J must use 0 and 7. E and F must both be odd (clue #4). However, four of the odd numerals would already be assigned (A = 9, G = 3, C = 1, either D or J = 7). Therefore, [AGC] can not be 931. This means that [AGC] must be 421. Therefore, A = 4 and G = 2.\n\r\nSince G = 2, then J = 8 (clue #2). J can not be 1 or 4, since those two numerals are now assigned.\n\r\nThe only remaining letters that can be assigned to 6 are B and I. D can not be 6, as it would not produce a square number (clue #1). Neither E nor F can be 6, since that would not produce an odd number (clue #4). H can not be 6, as it would not produce a prime number (clue #5). Since either B or I must be 6, then 6 must be paired with 0 (clue #3), as the other even numerals have now been assigned.\n\r\nSince B and I share 0 and 6, then D = 5 (clue #1).\n\r\nSince B and I share 0 and 6, then E and H must also be separated by 6 (clue #7). The only remaining numerals that satisfy this requirement are 3 and 9. This means that F = 7. This sets H = 3 and E = 9, which then sets B = 6 and I = 0.", "category": "Logic", "date": "02/19/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a 10-digit number, represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) A + D = a square number\r\n2) G + J = a triangle number\r\n3) B + I = an even number\r\n4) E * F = an odd number\r\n5) C * H = a prime number\r\n6) A / G = G / C\r\n7) E + I = B + H\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4615972308\n\r\nFor the product of two numbers to be a prime number (clue #5), one of those two numbers must be 1. Therefore, either C or H must be 1.\n\r\nTo achieve the required proportion (clue #6), the numerals [AGC] must be one of the following combinations: 931 or 421 or 842.\n\r\nIf [AGC] = 842, then D would have to be 1 (clue #1). Since either C or H must be 1, then D can not be 1. Since D can not be 1, then A can not be 8. Therefore, [AGC] can not be 842. The only remaining possibilities for [AGC] are 931 and 421. In either case, C = 1.\n\r\nIf [AGC] = 931, then D must be either 0 or 7 (clue #1) and J must be either 0 or 7 (clue #2). Therefore, between them, D and J must use 0 and 7. E and F must both be odd (clue #4). However, four of the odd numerals would already be assigned (A = 9, G = 3, C = 1, either D or J = 7). Therefore, [AGC] can not be 931. This means that [AGC] must be 421. Therefore, A = 4 and G = 2.\n\r\nSince G = 2, then J = 8 (clue #2). J can not be 1 or 4, since those two numerals are now assigned.\n\r\nThe only remaining letters that can be assigned to 6 are B and I. D can not be 6, as it would not produce a square number (clue #1). Neither E nor F can be 6, since that would not produce an odd number (clue #4). H can not be 6, as it would not produce a prime number (clue #5). Since either B or I must be 6, then 6 must be paired with 0 (clue #3), as the other even numerals have now been assigned.\n\r\nSince B and I share 0 and 6, then D = 5 (clue #1).\n\r\nSince B and I share 0 and 6, then E and H must also be separated by 6 (clue #7). The only remaining numerals that satisfy this requirement are 3 and 9. This means that F = 7. This sets H = 3 and E = 9, which then sets B = 6 and I = 0.\n<|im_start|>answer\n4615972308\n\r\nFor the product of two numbers to be a prime number (clue #5), one of those two numbers must be 1. Therefore, either C or H must be 1.\n\r\nTo achieve the required proportion (clue #6), the numerals [AGC] must be one of the following combinations: 931 or 421 or 842.\n\r\nIf [AGC] = 842, then D would have to be 1 (clue #1). Since either C or H must be 1, then D can not be 1. Since D can not be 1, then A can not be 8. Therefore, [AGC] can not be 842. The only remaining possibilities for [AGC] are 931 and 421. In either case, C = 1.\n\r\nIf [AGC] = 931, then D must be either 0 or 7 (clue #1) and J must be either 0 or 7 (clue #2). Therefore, between them, D and J must use 0 and 7. E and F must both be odd (clue #4). However, four of the odd numerals would already be assigned (A = 9, G = 3, C = 1, either D or J = 7). Therefore, [AGC] can not be 931. This means that [AGC] must be 421. Therefore, A = 4 and G = 2.\n\r\nSince G = 2, then J = 8 (clue #2). J can not be 1 or 4, since those two numerals are now assigned.\n\r\nThe only remaining letters that can be assigned to 6 are B and I. D can not be 6, as it would not produce a square number (clue #1). Neither E nor F can be 6, since that would not produce an odd number (clue #4). H can not be 6, as it would not produce a prime number (clue #5). Since either B or I must be 6, then 6 must be paired with 0 (clue #3), as the other even numerals have now been assigned.\n\r\nSince B and I share 0 and 6, then D = 5 (clue #1).\n\r\nSince B and I share 0 and 6, then E and H must also be separated by 6 (clue #7). The only remaining numerals that satisfy this requirement are 3 and 9. This means that F = 7. This sets H = 3 and E = 9, which then sets B = 6 and I = 0.\n<|im_end|>" }, { "id": "#8621", "title": "Jack's Savings", "fun": 2.22, "difficulty": 1.75, "author": "stonemug", "desc": "Jack donates 5% of his household income to various charities. He spends 5% of his income on gas. He spends 10% of his income on food. Another 20% of his income goes to pay his utilities. He spends another 20% on his house payment. He spends another 15% on his credit cards bills. He spends 15% on his income on his truck payment. He also spends 8% on his Health club member ship. If Jack makes $44,000 a year, how much will he be putting back in his savings account each month, if he is only wanting to deposit 35% of what's left after all his expenses? (The percentages were figured for one calendar year.)", "hint": "No hint available.", "answer": "$25.67\n\r\n5% Charities\r\n5% Gas\r\n10% Food\r\n20% Utilities\r\n20% House payment\r\n15% Credit cards\r\n15% Truck payment\r\n8% Health club\n\r\nTotal expenses = 98% (of his total yearly income)\n\r\n$44,000 x 98% = $43,120 (total spent on expenses)\r\n$44,000 - $43,120 = $880 (total left after expenses)\r\n$880 x 35% = $308.00 (total deposited in his Saving account during 1 year)\r\n$308.00 divided by 12 = $25.67 (amount deposited in his account every month)", "category": "Math", "date": "11/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack donates 5% of his household income to various charities. He spends 5% of his income on gas. He spends 10% of his income on food. Another 20% of his income goes to pay his utilities. He spends another 20% on his house payment. He spends another 15% on his credit cards bills. He spends 15% on his income on his truck payment. He also spends 8% on his Health club member ship. If Jack makes $44,000 a year, how much will he be putting back in his savings account each month, if he is only wanting to deposit 35% of what's left after all his expenses? (The percentages were figured for one calendar year.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$25.67\n\r\n5% Charities\r\n5% Gas\r\n10% Food\r\n20% Utilities\r\n20% House payment\r\n15% Credit cards\r\n15% Truck payment\r\n8% Health club\n\r\nTotal expenses = 98% (of his total yearly income)\n\r\n$44,000 x 98% = $43,120 (total spent on expenses)\r\n$44,000 - $43,120 = $880 (total left after expenses)\r\n$880 x 35% = $308.00 (total deposited in his Saving account during 1 year)\r\n$308.00 divided by 12 = $25.67 (amount deposited in his account every month)\n<|im_start|>answer\n$25.67\n\r\n5% Charities\r\n5% Gas\r\n10% Food\r\n20% Utilities\r\n20% House payment\r\n15% Credit cards\r\n15% Truck payment\r\n8% Health club\n\r\nTotal expenses = 98% (of his total yearly income)\n\r\n$44,000 x 98% = $43,120 (total spent on expenses)\r\n$44,000 - $43,120 = $880 (total left after expenses)\r\n$880 x 35% = $308.00 (total deposited in his Saving account during 1 year)\r\n$308.00 divided by 12 = $25.67 (amount deposited in his account every month)\n<|im_end|>" }, { "id": "#9404", "title": "Snapoker Tie-Breakers", "fun": 2.22, "difficulty": 2.89, "author": "snaps", "desc": "The card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frenetic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nAssume that all four players are equally matched at card-grabbing such that, following the grab, the cards are evenly distributed amongst all four players. What is the lowest card total at which you can be assured you will not be required to drink a glass of milk through your nose in order to break a tie for the maximum 4 points?", "hint": "No hint available.", "answer": "If all four players hold the same number of cards, the lowest card total that would never require a tie-break is 142.\n\r\nIf all four players hold the same number of cards, the highest single hand card total at which a tie-breaker might be needed is 141. In this case, the two players who would be required to drink milk through their noses would each have had a hand consisting of a joker and two 8s, 9s, 10s, jacks, queens and kings. Any score above 141 can not be duplicated in a single hand of Snapoker, thus making 142 the lowest total to which a tie-breaker will not need to be applied.", "category": "Math", "date": "12/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frenetic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nAssume that all four players are equally matched at card-grabbing such that, following the grab, the cards are evenly distributed amongst all four players. What is the lowest card total at which you can be assured you will not be required to drink a glass of milk through your nose in order to break a tie for the maximum 4 points?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf all four players hold the same number of cards, the lowest card total that would never require a tie-break is 142.\n\r\nIf all four players hold the same number of cards, the highest single hand card total at which a tie-breaker might be needed is 141. In this case, the two players who would be required to drink milk through their noses would each have had a hand consisting of a joker and two 8s, 9s, 10s, jacks, queens and kings. Any score above 141 can not be duplicated in a single hand of Snapoker, thus making 142 the lowest total to which a tie-breaker will not need to be applied.\n<|im_start|>answer\nIf all four players hold the same number of cards, the lowest card total that would never require a tie-break is 142.\n\r\nIf all four players hold the same number of cards, the highest single hand card total at which a tie-breaker might be needed is 141. In this case, the two players who would be required to drink milk through their noses would each have had a hand consisting of a joker and two 8s, 9s, 10s, jacks, queens and kings. Any score above 141 can not be duplicated in a single hand of Snapoker, thus making 142 the lowest total to which a tie-breaker will not need to be applied.\n<|im_end|>" }, { "id": "#8386", "title": "Between 100 and 500", "fun": 2.22, "difficulty": 1.39, "author": "timmyboym", "desc": "I am a number between 100 and 500. I am odd. If you double me you will get a number between 200 and 249. My last digit is not 1 and my middle digit is 2.\n\r\nWhat number am I?", "hint": "No hint available.", "answer": "123", "category": "Math", "date": "11/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a number between 100 and 500. I am odd. If you double me you will get a number between 200 and 249. My last digit is not 1 and my middle digit is 2.\n\r\nWhat number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n123\n<|im_start|>answer\n123\n<|im_end|>" }, { "id": "#8573", "title": "Primes by Primes", "fun": 2.22, "difficulty": 1.75, "author": "lesternoronha1", "desc": "Consider two-digit prime numbers. Whenever you add the two digits you get a number which is not prime i.e. It may be divisible by 2,3, etc. However there are only five two-digit prime numbers whose digits when added give a result that is divisible by 5. Three are 19,23 and 73. \n\r\nCan you find the other two prime numbers whose digits add up to a number divisible by 5?", "hint": "No hint available.", "answer": "They are 37 and 41.", "category": "Math", "date": "11/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nConsider two-digit prime numbers. Whenever you add the two digits you get a number which is not prime i.e. It may be divisible by 2,3, etc. However there are only five two-digit prime numbers whose digits when added give a result that is divisible by 5. Three are 19,23 and 73. \n\r\nCan you find the other two prime numbers whose digits add up to a number divisible by 5?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are 37 and 41.\n<|im_start|>answer\nThey are 37 and 41.\n<|im_end|>" }, { "id": "#40652", "title": "Military Fun 3", "fun": 2.22, "difficulty": 2.89, "author": "soccerguy0428", "desc": "Please do Military Fun and Military Fun 2 first before doing this teaser. This teaser continues on from the first and second times the friends got together, and will give away the answer to Military Fun and Military Fun 2. So, please do those teasers first.\n\r\nThis time the same 10 friends are going to go through a training camp so that they can be ready for their next pretend battle. More friends are finding out about this military fun and want to join, Private Brianna and Private Ben have come into this group too. Today the friends will be running 3 laps around the park. At the end of the race, the friends will move up or down in ranks according on how they did. If you can't move up or down any ranks, you will stay in the same rank that you are currently in. The scoring will be as follows\n\r\n1st Place- Move up 5 ranks\r\n2nd Place- Move up 4 ranks\r\n3rd Place- Move up 3 ranks\r\n4th and 5th Places- Move up 1 rank each\r\n6th and 7th Places- Stay the same rank\r\n8th and 9th Places- Move down 1 rank each\r\n10th and 11th Places- Move down 2 ranks each\r\n12th Place- Move down 3 ranks\n\r\nThe ranks people have right now:\n\r\nLieutenant General Stephen \r\nColonel Anna\r\nMajor Felicia \r\nCaptain Clark\r\nSergeant Abby\r\nSergeant Brad\r\nCorporal Jessica\r\nPrivate Paul\r\nPrivate Kelsey\r\nPrivate Luke\r\nPrivate Brianna\r\nPrivate Ben\n\r\nThis is a list of the ranks again, just in case anyone forgot it.\r\nRanks\r\n1. Lieutenant General\r\n2. Brigadier General\r\n3. Colonel\r\n4. Lieutenant Colonel\r\n5. Major\r\n6. Captain\r\n7. First Lieutenant\r\n8. Second Lieutenant\r\n9. First Sergeant\r\n10. Sergeant\r\n11. Corporal\r\n12. Private\n\r\nThe First Lap:\n\r\nStephen, Ben, Paul, and Jessica took off sprinting taking the top 4 spots. Felicia and Brianna aren't far behind though. Kelsey, Anna and Abby were bringing up the back as they had a late start.\n\r\nIn the top 4 runners, the bottom two ranked people were doing the best and the top ranked person was doing the worst. The Major was in 6th place as Brianna passed her for 5th. Luke was just about to pass Felicia, but tripped and fell back to 9th place as Clark and Brad passed him in that order. The back three girls were in their places according to their rank, the highest rank being 10th place and the lowest rank being 12th place.\n\r\nThe Second Lap:\n\r\nPaul slipped on a water puddle and fell back to third place, leaving the person he was right by, way in front. Clark moved up 2 spots, pushing those two people back one place each. Then, Felicia and Anna switched places, and Luke and Brad switched places. The people in 11th and 12th ended up switching places just before the third lap as well.\n\r\nThe Third Lap:\n\r\nThe two people in 10th and 11th place switched spots, the two people in 5th and 6th places switched spots, and the two people in 7th and 8th places switched spots. Brad ended up getting passed by the two people directly behind him, and Jessica was passed by the person directly behind her. Everyone then finished in the order that they are currently in. \n\r\nCan you figure out which place everyone is in, and what rank they will be after this race?", "hint": "No hint available.", "answer": "The Order the finished in was: Ben, Paul, Jessica, Stephen, Brianna, Clark, Luke, Anna, Kelsey, Felicia, Brad, Abby.\n\r\nHere is how they got there:\n\r\nOn the first lap the top 4 runners were Stephen, Ben, Paul, and Jessica. Felicia and Brianna weren't far behind which means they were in 5th and 6th place. With Kelsey, Anna, and Abby in the back (10th, 11th, and 12th places), that means Luke, Brad, and Clark were in 7th, 8th, and 9th. In the top 4 runners, the bottom two ranked people are Ben and Paul, which means that they were in 1st and 2nd, and the top ranked person was doing the worst, Stephen, which means that he was in 4th putting Jessica in 3rd place. Brianna was in 5th place, and Major Felicia was in 6th place. Clark and Brad passed Luke in a certain order, making Clark 7th, Brad 8th, and Luke 9th. The three girls in back then were in their places according to their rank, so that put Anna in 10th, Abby in 11th, and Kelsey in 12th. So, now we know what place everyone is after this lap.\n\r\nOn the second lap Paul slipped and was passed by Jessica, putting Ben in 1st, Jessica in 2nd, and Paul in 3rd. Clark moved up 2 spots putting him in 5th place, Brianna in 6th place, and Felicia in 7th place. Felicia then switched places with Anna, which put Felicia in 10th place, and Anna in 7th place. Luke and Brad switched places as well, which put Luke in 8th, and Brad in 9th. The 11th and 12th place people switched places too, which put Kelsey in 11th, and Abby in 12th.\n\r\nOn the third lap the 10th and 11th place people switched spots, putting Kelsey in 10th, and Felicia in 11th. 5th and 6th place switched, making Brianna in 5th, and Clark in 6th, and the 7th and 8th place people switched, putting Luke in 7th and Anna in 8th. Brad was passed by the two people who were directly behind him which made Kelsey in 9th, Felicia in 10th, and Brad in 11th. Jessica was also passed by Paul, the person directly behind her, putting Paul in 2nd, and Jessica in 3rd.\n\r\nTheir new ranks are:\r\nLieutenant General Stephen\r\nLieutenant Colonel Anna \r\nCaptain Clark\r\nFirst Lieutenant Ben\r\nFirst Lieutenant Felicia\r\nSecond Lieutenant Jessica\r\nSecond Lieutenant Paul\r\nCorporal Brianna\r\nPrivate Luke\r\nPrivate Kelsey\r\nPrivate Brad\r\nPrivate Abby", "category": "Logic", "date": "02/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlease do Military Fun and Military Fun 2 first before doing this teaser. This teaser continues on from the first and second times the friends got together, and will give away the answer to Military Fun and Military Fun 2. So, please do those teasers first.\n\r\nThis time the same 10 friends are going to go through a training camp so that they can be ready for their next pretend battle. More friends are finding out about this military fun and want to join, Private Brianna and Private Ben have come into this group too. Today the friends will be running 3 laps around the park. At the end of the race, the friends will move up or down in ranks according on how they did. If you can't move up or down any ranks, you will stay in the same rank that you are currently in. The scoring will be as follows\n\r\n1st Place- Move up 5 ranks\r\n2nd Place- Move up 4 ranks\r\n3rd Place- Move up 3 ranks\r\n4th and 5th Places- Move up 1 rank each\r\n6th and 7th Places- Stay the same rank\r\n8th and 9th Places- Move down 1 rank each\r\n10th and 11th Places- Move down 2 ranks each\r\n12th Place- Move down 3 ranks\n\r\nThe ranks people have right now:\n\r\nLieutenant General Stephen \r\nColonel Anna\r\nMajor Felicia \r\nCaptain Clark\r\nSergeant Abby\r\nSergeant Brad\r\nCorporal Jessica\r\nPrivate Paul\r\nPrivate Kelsey\r\nPrivate Luke\r\nPrivate Brianna\r\nPrivate Ben\n\r\nThis is a list of the ranks again, just in case anyone forgot it.\r\nRanks\r\n1. Lieutenant General\r\n2. Brigadier General\r\n3. Colonel\r\n4. Lieutenant Colonel\r\n5. Major\r\n6. Captain\r\n7. First Lieutenant\r\n8. Second Lieutenant\r\n9. First Sergeant\r\n10. Sergeant\r\n11. Corporal\r\n12. Private\n\r\nThe First Lap:\n\r\nStephen, Ben, Paul, and Jessica took off sprinting taking the top 4 spots. Felicia and Brianna aren't far behind though. Kelsey, Anna and Abby were bringing up the back as they had a late start.\n\r\nIn the top 4 runners, the bottom two ranked people were doing the best and the top ranked person was doing the worst. The Major was in 6th place as Brianna passed her for 5th. Luke was just about to pass Felicia, but tripped and fell back to 9th place as Clark and Brad passed him in that order. The back three girls were in their places according to their rank, the highest rank being 10th place and the lowest rank being 12th place.\n\r\nThe Second Lap:\n\r\nPaul slipped on a water puddle and fell back to third place, leaving the person he was right by, way in front. Clark moved up 2 spots, pushing those two people back one place each. Then, Felicia and Anna switched places, and Luke and Brad switched places. The people in 11th and 12th ended up switching places just before the third lap as well.\n\r\nThe Third Lap:\n\r\nThe two people in 10th and 11th place switched spots, the two people in 5th and 6th places switched spots, and the two people in 7th and 8th places switched spots. Brad ended up getting passed by the two people directly behind him, and Jessica was passed by the person directly behind her. Everyone then finished in the order that they are currently in. \n\r\nCan you figure out which place everyone is in, and what rank they will be after this race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Order the finished in was: Ben, Paul, Jessica, Stephen, Brianna, Clark, Luke, Anna, Kelsey, Felicia, Brad, Abby.\n\r\nHere is how they got there:\n\r\nOn the first lap the top 4 runners were Stephen, Ben, Paul, and Jessica. Felicia and Brianna weren't far behind which means they were in 5th and 6th place. With Kelsey, Anna, and Abby in the back (10th, 11th, and 12th places), that means Luke, Brad, and Clark were in 7th, 8th, and 9th. In the top 4 runners, the bottom two ranked people are Ben and Paul, which means that they were in 1st and 2nd, and the top ranked person was doing the worst, Stephen, which means that he was in 4th putting Jessica in 3rd place. Brianna was in 5th place, and Major Felicia was in 6th place. Clark and Brad passed Luke in a certain order, making Clark 7th, Brad 8th, and Luke 9th. The three girls in back then were in their places according to their rank, so that put Anna in 10th, Abby in 11th, and Kelsey in 12th. So, now we know what place everyone is after this lap.\n\r\nOn the second lap Paul slipped and was passed by Jessica, putting Ben in 1st, Jessica in 2nd, and Paul in 3rd. Clark moved up 2 spots putting him in 5th place, Brianna in 6th place, and Felicia in 7th place. Felicia then switched places with Anna, which put Felicia in 10th place, and Anna in 7th place. Luke and Brad switched places as well, which put Luke in 8th, and Brad in 9th. The 11th and 12th place people switched places too, which put Kelsey in 11th, and Abby in 12th.\n\r\nOn the third lap the 10th and 11th place people switched spots, putting Kelsey in 10th, and Felicia in 11th. 5th and 6th place switched, making Brianna in 5th, and Clark in 6th, and the 7th and 8th place people switched, putting Luke in 7th and Anna in 8th. Brad was passed by the two people who were directly behind him which made Kelsey in 9th, Felicia in 10th, and Brad in 11th. Jessica was also passed by Paul, the person directly behind her, putting Paul in 2nd, and Jessica in 3rd.\n\r\nTheir new ranks are:\r\nLieutenant General Stephen\r\nLieutenant Colonel Anna \r\nCaptain Clark\r\nFirst Lieutenant Ben\r\nFirst Lieutenant Felicia\r\nSecond Lieutenant Jessica\r\nSecond Lieutenant Paul\r\nCorporal Brianna\r\nPrivate Luke\r\nPrivate Kelsey\r\nPrivate Brad\r\nPrivate Abby\n<|im_start|>answer\nThe Order the finished in was: Ben, Paul, Jessica, Stephen, Brianna, Clark, Luke, Anna, Kelsey, Felicia, Brad, Abby.\n\r\nHere is how they got there:\n\r\nOn the first lap the top 4 runners were Stephen, Ben, Paul, and Jessica. Felicia and Brianna weren't far behind which means they were in 5th and 6th place. With Kelsey, Anna, and Abby in the back (10th, 11th, and 12th places), that means Luke, Brad, and Clark were in 7th, 8th, and 9th. In the top 4 runners, the bottom two ranked people are Ben and Paul, which means that they were in 1st and 2nd, and the top ranked person was doing the worst, Stephen, which means that he was in 4th putting Jessica in 3rd place. Brianna was in 5th place, and Major Felicia was in 6th place. Clark and Brad passed Luke in a certain order, making Clark 7th, Brad 8th, and Luke 9th. The three girls in back then were in their places according to their rank, so that put Anna in 10th, Abby in 11th, and Kelsey in 12th. So, now we know what place everyone is after this lap.\n\r\nOn the second lap Paul slipped and was passed by Jessica, putting Ben in 1st, Jessica in 2nd, and Paul in 3rd. Clark moved up 2 spots putting him in 5th place, Brianna in 6th place, and Felicia in 7th place. Felicia then switched places with Anna, which put Felicia in 10th place, and Anna in 7th place. Luke and Brad switched places as well, which put Luke in 8th, and Brad in 9th. The 11th and 12th place people switched places too, which put Kelsey in 11th, and Abby in 12th.\n\r\nOn the third lap the 10th and 11th place people switched spots, putting Kelsey in 10th, and Felicia in 11th. 5th and 6th place switched, making Brianna in 5th, and Clark in 6th, and the 7th and 8th place people switched, putting Luke in 7th and Anna in 8th. Brad was passed by the two people who were directly behind him which made Kelsey in 9th, Felicia in 10th, and Brad in 11th. Jessica was also passed by Paul, the person directly behind her, putting Paul in 2nd, and Jessica in 3rd.\n\r\nTheir new ranks are:\r\nLieutenant General Stephen\r\nLieutenant Colonel Anna \r\nCaptain Clark\r\nFirst Lieutenant Ben\r\nFirst Lieutenant Felicia\r\nSecond Lieutenant Jessica\r\nSecond Lieutenant Paul\r\nCorporal Brianna\r\nPrivate Luke\r\nPrivate Kelsey\r\nPrivate Brad\r\nPrivate Abby\n<|im_end|>" }, { "id": "#19152", "title": "Catching Up", "fun": 2.22, "difficulty": 1.8900000000000001, "author": "lesternoronha1", "desc": "Rakesh and Shyam are competing in a 100m race. Initially, Rakesh runs at twice Shyam's speed for the first fifty meters. After the 50m mark, Rakesh runs at 1/4th his initial speed while Shyam continues to run at his original speed. At what distance from the finish line does Shyam catch up with Rakesh?", "hint": "No hint available.", "answer": "Shyam catches up with Rakesh at a distance of 25m from the finish line.\n\r\nLet Rakesh's and Shyam's speeds be 'r' and 's' initially.\r\nThen we have for the first 50m, Rakesh's speed = Twice Shyam's speed i.e., r = 2s.\n\r\nAfter the 50m mark, Rakesh's speed = 1/4th his original speed = Half of Shyam's speed \r\ni.e., r = s/2.\n\r\nNow let Rakesh and Shyam meet at 'X' m from the start line, after a time 't'.\n\r\nTime taken by Rakesh to cover 'X' m = Time taken by Shyam to cover 'X' m\r\n(since they meet after having covered X m.)\n\r\nTime taken by Rakesh to cover 'X'm = \r\n(Time taken by Rakesh to cover first 50 m) + (Time taken by Rakesh to cover the remaining 'X-50' m) =\r\n(50/2s) + ((X-50)/(s/2))\r\n(since Rakesh's speed is 2s for first 50m and then onwards s/2)\n\r\nTime taken by Shyam to cover 'X' m = (X/s)\r\n(since Shyam ran at the same speed s throughout)\n\r\nHence \r\n(50/2s) + ((X-50)/(s/2)) = (X/s)\r\n25/s + ((2X-100)/s) = X/s\r\n(25+2X-100)/s = X/s\n\r\nHence X = 25+2X-100 i.e., X = 75m\r\nThus Rakesh and Shyam meet at a distance of 75m from the start line.\n\r\nHence Rakesh and Shyam should be meeting from the finish line at a distance \r\n= 100 - X = 100 - 75 = 25m", "category": "Math", "date": "10/16/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRakesh and Shyam are competing in a 100m race. Initially, Rakesh runs at twice Shyam's speed for the first fifty meters. After the 50m mark, Rakesh runs at 1/4th his initial speed while Shyam continues to run at his original speed. At what distance from the finish line does Shyam catch up with Rakesh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShyam catches up with Rakesh at a distance of 25m from the finish line.\n\r\nLet Rakesh's and Shyam's speeds be 'r' and 's' initially.\r\nThen we have for the first 50m, Rakesh's speed = Twice Shyam's speed i.e., r = 2s.\n\r\nAfter the 50m mark, Rakesh's speed = 1/4th his original speed = Half of Shyam's speed \r\ni.e., r = s/2.\n\r\nNow let Rakesh and Shyam meet at 'X' m from the start line, after a time 't'.\n\r\nTime taken by Rakesh to cover 'X' m = Time taken by Shyam to cover 'X' m\r\n(since they meet after having covered X m.)\n\r\nTime taken by Rakesh to cover 'X'm = \r\n(Time taken by Rakesh to cover first 50 m) + (Time taken by Rakesh to cover the remaining 'X-50' m) =\r\n(50/2s) + ((X-50)/(s/2))\r\n(since Rakesh's speed is 2s for first 50m and then onwards s/2)\n\r\nTime taken by Shyam to cover 'X' m = (X/s)\r\n(since Shyam ran at the same speed s throughout)\n\r\nHence \r\n(50/2s) + ((X-50)/(s/2)) = (X/s)\r\n25/s + ((2X-100)/s) = X/s\r\n(25+2X-100)/s = X/s\n\r\nHence X = 25+2X-100 i.e., X = 75m\r\nThus Rakesh and Shyam meet at a distance of 75m from the start line.\n\r\nHence Rakesh and Shyam should be meeting from the finish line at a distance \r\n= 100 - X = 100 - 75 = 25m\n<|im_start|>answer\nShyam catches up with Rakesh at a distance of 25m from the finish line.\n\r\nLet Rakesh's and Shyam's speeds be 'r' and 's' initially.\r\nThen we have for the first 50m, Rakesh's speed = Twice Shyam's speed i.e., r = 2s.\n\r\nAfter the 50m mark, Rakesh's speed = 1/4th his original speed = Half of Shyam's speed \r\ni.e., r = s/2.\n\r\nNow let Rakesh and Shyam meet at 'X' m from the start line, after a time 't'.\n\r\nTime taken by Rakesh to cover 'X' m = Time taken by Shyam to cover 'X' m\r\n(since they meet after having covered X m.)\n\r\nTime taken by Rakesh to cover 'X'm = \r\n(Time taken by Rakesh to cover first 50 m) + (Time taken by Rakesh to cover the remaining 'X-50' m) =\r\n(50/2s) + ((X-50)/(s/2))\r\n(since Rakesh's speed is 2s for first 50m and then onwards s/2)\n\r\nTime taken by Shyam to cover 'X' m = (X/s)\r\n(since Shyam ran at the same speed s throughout)\n\r\nHence \r\n(50/2s) + ((X-50)/(s/2)) = (X/s)\r\n25/s + ((2X-100)/s) = X/s\r\n(25+2X-100)/s = X/s\n\r\nHence X = 25+2X-100 i.e., X = 75m\r\nThus Rakesh and Shyam meet at a distance of 75m from the start line.\n\r\nHence Rakesh and Shyam should be meeting from the finish line at a distance \r\n= 100 - X = 100 - 75 = 25m\n<|im_end|>" }, { "id": "#23959", "title": "Profit.", "fun": 2.22, "difficulty": 1.76, "author": "chidam11", "desc": "A shopkeeper sells no more than 20 shirts of each color. At least twice as many green ones are sold as white ones. If the profit on each white shirt is $20 and that of green $25 how many of each kind has to be sold to get maximum profit?", "hint": "No hint available.", "answer": "Maximum profit is $700,to achieve this white and green shirts are to be made 10 and 20 respectively.", "category": "Math", "date": "06/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA shopkeeper sells no more than 20 shirts of each color. At least twice as many green ones are sold as white ones. If the profit on each white shirt is $20 and that of green $25 how many of each kind has to be sold to get maximum profit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMaximum profit is $700,to achieve this white and green shirts are to be made 10 and 20 respectively.\n<|im_start|>answer\nMaximum profit is $700,to achieve this white and green shirts are to be made 10 and 20 respectively.\n<|im_end|>" }, { "id": "#43892", "title": "Eliza Pseudonym and the Seven Restaurants", "fun": 2.22, "difficulty": 2.32, "author": "mathgrant", "desc": "During a seven-day period from Sunday through Saturday, Eliza Pseudonym has dined at seven different local restaurants (including Idaho Fried Chicken) twice each: once for lunch, and once on a different day for dinner. Each restaurant is located on a different street (from 1st through 7th). Using the following clues, determine where each restaurant is located, and which restaurant Eliza ate at for lunch and for dinner each day.\n\r\n1. Wednesday was the only day on which Eliza ate at two restaurants on consecutively numbered streets.\r\n2. Eliza had lunch at the restaurant located on the 6th Street on Monday.\r\n3. Eliza ate at Chick-Empty-A on Tuesday and Friday.\r\n4. Eliza ate at Long John Bronze's on two consecutive days.\r\n5. Eliza ate her lunch at the 1st Street restaurant precisely three days after she ate her dinner at the 5th Street restaurant.\r\n6. On Sunday, Eliza did not have the restaurant on 4th Street for lunch, nor did she eat at Waffle Habitat for dinner.\r\n7. On one paticular day, Eliza ate at Dice's Pizza (located on an odd numbered street) and Taco Marimba, in some order.\r\n8. During the three-day period from Sunday through Tuesday, Eliza had eaten something at all seven restaurants excluding the one located on 7th Street; during the three-day period from Thursday through Saturday, Eliza had eaten something at all seven restaurants excluding Questionnos.", "hint": "No hint available.", "answer": "Waffle House is on 1st Street. Eliza ate there for lunch on Friday and dinner on Monday.\r\nTaco Marimba is on 2nd Street. Eliza ate there for lunch on Sunday and dinner on Saturday.\r\nChick-Empty-A is on 3rd Street. Eliza ate there Tuesday for lunch and Friday for dinner.\r\nIdaho Fried Chicken is on 4th Street. Eliza ate there Thursday for lunch and Sunday for dinner.\r\nDice's Pizza is on 5th Street. Eliza ate lunch there on Saturday and dinner there on Tuesday. \r\nQuestionnos's is on 6th Street. Eliza ate lunch there on Monday and dinner there on Wednesday.\r\nLong John Bronze's is on 7th Street. Eliza ate there for lunch on Wednesday, and dinner on Thursday.", "category": "Logic", "date": "01/10/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a seven-day period from Sunday through Saturday, Eliza Pseudonym has dined at seven different local restaurants (including Idaho Fried Chicken) twice each: once for lunch, and once on a different day for dinner. Each restaurant is located on a different street (from 1st through 7th). Using the following clues, determine where each restaurant is located, and which restaurant Eliza ate at for lunch and for dinner each day.\n\r\n1. Wednesday was the only day on which Eliza ate at two restaurants on consecutively numbered streets.\r\n2. Eliza had lunch at the restaurant located on the 6th Street on Monday.\r\n3. Eliza ate at Chick-Empty-A on Tuesday and Friday.\r\n4. Eliza ate at Long John Bronze's on two consecutive days.\r\n5. Eliza ate her lunch at the 1st Street restaurant precisely three days after she ate her dinner at the 5th Street restaurant.\r\n6. On Sunday, Eliza did not have the restaurant on 4th Street for lunch, nor did she eat at Waffle Habitat for dinner.\r\n7. On one paticular day, Eliza ate at Dice's Pizza (located on an odd numbered street) and Taco Marimba, in some order.\r\n8. During the three-day period from Sunday through Tuesday, Eliza had eaten something at all seven restaurants excluding the one located on 7th Street; during the three-day period from Thursday through Saturday, Eliza had eaten something at all seven restaurants excluding Questionnos.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWaffle House is on 1st Street. Eliza ate there for lunch on Friday and dinner on Monday.\r\nTaco Marimba is on 2nd Street. Eliza ate there for lunch on Sunday and dinner on Saturday.\r\nChick-Empty-A is on 3rd Street. Eliza ate there Tuesday for lunch and Friday for dinner.\r\nIdaho Fried Chicken is on 4th Street. Eliza ate there Thursday for lunch and Sunday for dinner.\r\nDice's Pizza is on 5th Street. Eliza ate lunch there on Saturday and dinner there on Tuesday. \r\nQuestionnos's is on 6th Street. Eliza ate lunch there on Monday and dinner there on Wednesday.\r\nLong John Bronze's is on 7th Street. Eliza ate there for lunch on Wednesday, and dinner on Thursday.\n<|im_start|>answer\nWaffle House is on 1st Street. Eliza ate there for lunch on Friday and dinner on Monday.\r\nTaco Marimba is on 2nd Street. Eliza ate there for lunch on Sunday and dinner on Saturday.\r\nChick-Empty-A is on 3rd Street. Eliza ate there Tuesday for lunch and Friday for dinner.\r\nIdaho Fried Chicken is on 4th Street. Eliza ate there Thursday for lunch and Sunday for dinner.\r\nDice's Pizza is on 5th Street. Eliza ate lunch there on Saturday and dinner there on Tuesday. \r\nQuestionnos's is on 6th Street. Eliza ate lunch there on Monday and dinner there on Wednesday.\r\nLong John Bronze's is on 7th Street. Eliza ate there for lunch on Wednesday, and dinner on Thursday.\n<|im_end|>" }, { "id": "#3144", "title": "Car Rally", "fun": 2.22, "difficulty": 1.45, "author": "204_blaze_41", "desc": "The Soul-Ace Hotel held its annual car rally. Sandy Beach was the favourite to win since she won the last three years in a row. Also in the race were Tim Duncan, Anthony Imp, and Chewy Chubalba. Duncan, who finished three places in front of last place Chewy Chubalba, came two places in front of seventh place Anthony Imp. How many people were in the rally?", "hint": "No hint available.", "answer": "Eight.", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Soul-Ace Hotel held its annual car rally. Sandy Beach was the favourite to win since she won the last three years in a row. Also in the race were Tim Duncan, Anthony Imp, and Chewy Chubalba. Duncan, who finished three places in front of last place Chewy Chubalba, came two places in front of seventh place Anthony Imp. How many people were in the rally?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEight.\n<|im_start|>answer\nEight.\n<|im_end|>" }, { "id": "#4282", "title": "Evaporation", "fun": 2.22, "difficulty": 1.79, "author": "mad-ade", "desc": "Mad Ade has left a glass of water on the window ledge in direct sun light. On the first day 1/3 of the water evaporates. On the second day 3/4 of the remainder evaporates. By the end of the second day Mad Ade remembers the glass. How much water is left expressed as a fraction?", "hint": "No hint available.", "answer": "1/6 of the water is left.", "category": "Math", "date": "05/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has left a glass of water on the window ledge in direct sun light. On the first day 1/3 of the water evaporates. On the second day 3/4 of the remainder evaporates. By the end of the second day Mad Ade remembers the glass. How much water is left expressed as a fraction?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1/6 of the water is left.\n<|im_start|>answer\n1/6 of the water is left.\n<|im_end|>" }, { "id": "#19609", "title": "Prewrapped Salad Free Kebabs", "fun": 2.22, "difficulty": 2.17, "author": "Mad-Ade", "desc": "Mad Ade's Uncle Frenzied Fred owns a small prewrapped salad free kebab stand. When he places his prepackaged Kebabs on display he notices that he has 1 left over if he places them in groups of three. The same happens if he tries to place them in groups of 5, 7, or 9.\r\nIt is only when he places the kebabs in groups of 11 that all the kebabs are used.\r\nHow many prewrapped salad free Kebabs did Frenzied Fred have at least?", "hint": "No hint available.", "answer": "Assume the number of Kebabs is A. Then A-1 is divisible by 3, 5, 7 and 9. So, A-1 is a multiple of 5*7*9 = 315 (note: 9 is also a multiple of 3, so 3 must not be included!). We are looking for a value of N for which holds that 315*N + 1 is divisible by 11. After some trying it turns out that N = 3. This means that Mad Ade's uncle has 946 prewrapped salad free Kebabs.", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Uncle Frenzied Fred owns a small prewrapped salad free kebab stand. When he places his prepackaged Kebabs on display he notices that he has 1 left over if he places them in groups of three. The same happens if he tries to place them in groups of 5, 7, or 9.\r\nIt is only when he places the kebabs in groups of 11 that all the kebabs are used.\r\nHow many prewrapped salad free Kebabs did Frenzied Fred have at least?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAssume the number of Kebabs is A. Then A-1 is divisible by 3, 5, 7 and 9. So, A-1 is a multiple of 5*7*9 = 315 (note: 9 is also a multiple of 3, so 3 must not be included!). We are looking for a value of N for which holds that 315*N + 1 is divisible by 11. After some trying it turns out that N = 3. This means that Mad Ade's uncle has 946 prewrapped salad free Kebabs.\n<|im_start|>answer\nAssume the number of Kebabs is A. Then A-1 is divisible by 3, 5, 7 and 9. So, A-1 is a multiple of 5*7*9 = 315 (note: 9 is also a multiple of 3, so 3 must not be included!). We are looking for a value of N for which holds that 315*N + 1 is divisible by 11. After some trying it turns out that N = 3. This means that Mad Ade's uncle has 946 prewrapped salad free Kebabs.\n<|im_end|>" }, { "id": "#9730", "title": "Meals", "fun": 2.22, "difficulty": 1.43, "author": "Amorn01380", "desc": "In an office of 180 people the canteen offers a choice of lasagna, vegetable curry and gammon steak Hawaii. On Tuesday, 60 people chose lasagna, and two thirds chose gammon steak Hawaii. How many chose veggie curry?", "hint": "No hint available.", "answer": "None. 60 people chose lasagna, and the other 120 (two-thirds of 180) chose steak.", "category": "Math", "date": "01/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn an office of 180 people the canteen offers a choice of lasagna, vegetable curry and gammon steak Hawaii. On Tuesday, 60 people chose lasagna, and two thirds chose gammon steak Hawaii. How many chose veggie curry?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNone. 60 people chose lasagna, and the other 120 (two-thirds of 180) chose steak.\n<|im_start|>answer\nNone. 60 people chose lasagna, and the other 120 (two-thirds of 180) chose steak.\n<|im_end|>" }, { "id": "#464", "title": "My Bottle Deposit", "fun": 2.22, "difficulty": 1.75, "author": "Mr. G", "desc": "In Delaware, you must pay a deposit on all bottles and you can return your bottles to receive your deposit back. If you buy a bottle of soda for $2 and the deposit is $1.60 less than the actual cost of the soda, how much is the deposit for?", "hint": "The answer is not 40 cents.", "answer": "The answer is 20 cents. Since the deposit is $1.60 LESS than the cost of the soda, that the total for the cost for the soda must be $1.80, plus 20 cents deposit, which equals the $2 you paid for the soda.", "category": "Math", "date": "05/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Delaware, you must pay a deposit on all bottles and you can return your bottles to receive your deposit back. If you buy a bottle of soda for $2 and the deposit is $1.60 less than the actual cost of the soda, how much is the deposit for?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 20 cents. Since the deposit is $1.60 LESS than the cost of the soda, that the total for the cost for the soda must be $1.80, plus 20 cents deposit, which equals the $2 you paid for the soda.\n<|im_start|>answer\nThe answer is 20 cents. Since the deposit is $1.60 LESS than the cost of the soda, that the total for the cost for the soda must be $1.80, plus 20 cents deposit, which equals the $2 you paid for the soda.\n<|im_end|>" }, { "id": "#29318", "title": "Chemical Company", "fun": 2.22, "difficulty": 2.94, "author": "BobbyKat", "desc": "A chemical company spends x million dollars on research and finds that its profit can be expressed as a function of the amount of money spent on research. If Profit(x)= 30 + 6 log (x+2) how much will the company have to spend on research to increase its profit from its present level, with a research investment of 5 million dollars (P(5)), to 80 million dollars.", "hint": "1) assume all number's have millions as units.", "answer": "P(5) = 30 + 6 log(5 + 2)\r\n----------------------------\r\n log 2\r\n= 46.84 million dollars\r\n80 = 30 + 6 log2 (x + 2)\r\n50 / 6 = log2 (x + 2)\r\n250/6 = (x + 2)\r\nx = 320.54 million dollars.\n\r\nTherefore: increase in spending = 320.54 - 5 = 315.54 million", "category": "Math", "date": "03/25/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA chemical company spends x million dollars on research and finds that its profit can be expressed as a function of the amount of money spent on research. If Profit(x)= 30 + 6 log (x+2) how much will the company have to spend on research to increase its profit from its present level, with a research investment of 5 million dollars (P(5)), to 80 million dollars.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nP(5) = 30 + 6 log(5 + 2)\r\n----------------------------\r\n log 2\r\n= 46.84 million dollars\r\n80 = 30 + 6 log2 (x + 2)\r\n50 / 6 = log2 (x + 2)\r\n250/6 = (x + 2)\r\nx = 320.54 million dollars.\n\r\nTherefore: increase in spending = 320.54 - 5 = 315.54 million\n<|im_start|>answer\nP(5) = 30 + 6 log(5 + 2)\r\n----------------------------\r\n log 2\r\n= 46.84 million dollars\r\n80 = 30 + 6 log2 (x + 2)\r\n50 / 6 = log2 (x + 2)\r\n250/6 = (x + 2)\r\nx = 320.54 million dollars.\n\r\nTherefore: increase in spending = 320.54 - 5 = 315.54 million\n<|im_end|>" }, { "id": "#20946", "title": "Mix 'n Match", "fun": 2.22, "difficulty": 0.71, "author": "MrBasKetBall", "desc": "An older sister bragged that she had 30 different new outfits to wear to school.\n\r\nHer younger brother said, \"That's not true. You have 3 pairs of jeans, 5 shirts, and 2 pairs of shoes. There's no way that makes 30 different outfits. You only have 10 outfits.\"\n\r\nWho is correct and why?", "hint": "No hint available.", "answer": "The older sister is correct. There are 30 different ways to mix and match the pants, shirts, and shoes.\n\r\nOne pair of jeans goes with 5 shirts, so there are (3 x 5) or 15 jeans/shirts combinations. Each of these combinations can be worn with either of two pairs of shoes, which makes (15 x 2) or 30 different outfits.", "category": "Math", "date": "02/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn older sister bragged that she had 30 different new outfits to wear to school.\n\r\nHer younger brother said, \"That's not true. You have 3 pairs of jeans, 5 shirts, and 2 pairs of shoes. There's no way that makes 30 different outfits. You only have 10 outfits.\"\n\r\nWho is correct and why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe older sister is correct. There are 30 different ways to mix and match the pants, shirts, and shoes.\n\r\nOne pair of jeans goes with 5 shirts, so there are (3 x 5) or 15 jeans/shirts combinations. Each of these combinations can be worn with either of two pairs of shoes, which makes (15 x 2) or 30 different outfits.\n<|im_start|>answer\nThe older sister is correct. There are 30 different ways to mix and match the pants, shirts, and shoes.\n\r\nOne pair of jeans goes with 5 shirts, so there are (3 x 5) or 15 jeans/shirts combinations. Each of these combinations can be worn with either of two pairs of shoes, which makes (15 x 2) or 30 different outfits.\n<|im_end|>" }, { "id": "#1138", "title": "Dad in the Rain", "fun": 2.22, "difficulty": 0.97, "author": "Michelle", "desc": "My dad was out for a walk when it started to rain. He didn't have an umbrella and he wasn't wearing a hat. His clothes got soaked, yet not a hair on his head got wet. How could this happen?", "hint": "No hint available.", "answer": "My dad is bald.", "category": "Logic", "date": "10/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy dad was out for a walk when it started to rain. He didn't have an umbrella and he wasn't wearing a hat. His clothes got soaked, yet not a hair on his head got wet. How could this happen?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMy dad is bald.\n<|im_start|>answer\nMy dad is bald.\n<|im_end|>" }, { "id": "#18973", "title": "Water in 4 Jugs", "fun": 2.22, "difficulty": 2.47, "author": "nenad", "desc": "You have four jugs:\r\nA: 10-liter jug, filled with water\r\nB: 10-liter jug, filled with water\r\nC: 10-liter jug, empty\r\nD: 9-liter jug, empty\n\r\nYour objective is to end up having 1 liter in any 10-liter jug and 4 liters in 9-liter jug.\r\nYou have nothing else at your disposal and you can not measure using eye or shape of jugs. \r\nAlso water can only be transferred between jugs and not dumped out from any of the jugs.", "hint": "Not much of a hint, but it can be solved in 20 steps.", "answer": "If we label jugs as stated in problem , ABCD, with 9-liter jug being D, problem can be solved in 20 steps, as shown below. Each step is shown in one row, where line start with number of step, followed by information from what jug we poured water into what jug, and how much ... ie. A -> (9) -> D means we poured 9 liters of water from jug A (being 1st 10-liter jug) to jug D (being 9-liter jug). Finally in row we show how much water we have in each jug after performed this step.\n\n\r\n---------------------------------\r\n#s From-Qty-To A B C D\r\n---------------------------------\r\n 0: = 10 10 0 0\r\n 1: A ->( 9)-> D = 1 10 0 9\r\n 2: D ->( 9)-> C = 1 10 9 0\r\n 3: A ->( 1)-> D = 0 10 9 1\r\n 4: B ->( 8)-> D = 0 2 9 9\r\n 5: D ->( 9)-> A = 9 2 9 0\r\n 6: A ->( 1)-> C = 8 2 10 0\r\n 7: B ->( 2)-> D = 8 0 10 2\r\n 8: C ->( 7)-> D = 8 0 3 9\r\n 9: D ->( 2)-> A = 10 0 3 7\r\n10: D ->( 7)-> B = 10 7 3 0\r\n11: A ->( 9)-> D = 1 7 3 9\r\n12: A ->( 1)-> C = 0 7 4 9\r\n13: D ->( 9)-> A = 9 7 4 0\r\n14: A ->( 3)-> B = 6 10 4 0\r\n15: B ->( 9)-> D = 6 1 4 9\r\n16: B ->( 1)-> C = 6 0 5 9\r\n17: D ->( 4)-> A = 10 0 5 5\r\n18: D ->( 5)-> B = 10 5 5 0\r\n19: A ->( 9)-> D = 1 5 5 9\r\n20: D ->( 5)-> B = 1 10 5 4\n\r\nAfter 20th step we end up with 1 liter in first 10-liter jug (A), and 4 liters in 9-liter jug (D), as requested in problem.", "category": "Logic", "date": "09/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have four jugs:\r\nA: 10-liter jug, filled with water\r\nB: 10-liter jug, filled with water\r\nC: 10-liter jug, empty\r\nD: 9-liter jug, empty\n\r\nYour objective is to end up having 1 liter in any 10-liter jug and 4 liters in 9-liter jug.\r\nYou have nothing else at your disposal and you can not measure using eye or shape of jugs. \r\nAlso water can only be transferred between jugs and not dumped out from any of the jugs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf we label jugs as stated in problem , ABCD, with 9-liter jug being D, problem can be solved in 20 steps, as shown below. Each step is shown in one row, where line start with number of step, followed by information from what jug we poured water into what jug, and how much ... ie. A -> (9) -> D means we poured 9 liters of water from jug A (being 1st 10-liter jug) to jug D (being 9-liter jug). Finally in row we show how much water we have in each jug after performed this step.\n\n\r\n---------------------------------\r\n#s From-Qty-To A B C D\r\n---------------------------------\r\n 0: = 10 10 0 0\r\n 1: A ->( 9)-> D = 1 10 0 9\r\n 2: D ->( 9)-> C = 1 10 9 0\r\n 3: A ->( 1)-> D = 0 10 9 1\r\n 4: B ->( 8)-> D = 0 2 9 9\r\n 5: D ->( 9)-> A = 9 2 9 0\r\n 6: A ->( 1)-> C = 8 2 10 0\r\n 7: B ->( 2)-> D = 8 0 10 2\r\n 8: C ->( 7)-> D = 8 0 3 9\r\n 9: D ->( 2)-> A = 10 0 3 7\r\n10: D ->( 7)-> B = 10 7 3 0\r\n11: A ->( 9)-> D = 1 7 3 9\r\n12: A ->( 1)-> C = 0 7 4 9\r\n13: D ->( 9)-> A = 9 7 4 0\r\n14: A ->( 3)-> B = 6 10 4 0\r\n15: B ->( 9)-> D = 6 1 4 9\r\n16: B ->( 1)-> C = 6 0 5 9\r\n17: D ->( 4)-> A = 10 0 5 5\r\n18: D ->( 5)-> B = 10 5 5 0\r\n19: A ->( 9)-> D = 1 5 5 9\r\n20: D ->( 5)-> B = 1 10 5 4\n\r\nAfter 20th step we end up with 1 liter in first 10-liter jug (A), and 4 liters in 9-liter jug (D), as requested in problem.\n<|im_start|>answer\nIf we label jugs as stated in problem , ABCD, with 9-liter jug being D, problem can be solved in 20 steps, as shown below. Each step is shown in one row, where line start with number of step, followed by information from what jug we poured water into what jug, and how much ... ie. A -> (9) -> D means we poured 9 liters of water from jug A (being 1st 10-liter jug) to jug D (being 9-liter jug). Finally in row we show how much water we have in each jug after performed this step.\n\n\r\n---------------------------------\r\n#s From-Qty-To A B C D\r\n---------------------------------\r\n 0: = 10 10 0 0\r\n 1: A ->( 9)-> D = 1 10 0 9\r\n 2: D ->( 9)-> C = 1 10 9 0\r\n 3: A ->( 1)-> D = 0 10 9 1\r\n 4: B ->( 8)-> D = 0 2 9 9\r\n 5: D ->( 9)-> A = 9 2 9 0\r\n 6: A ->( 1)-> C = 8 2 10 0\r\n 7: B ->( 2)-> D = 8 0 10 2\r\n 8: C ->( 7)-> D = 8 0 3 9\r\n 9: D ->( 2)-> A = 10 0 3 7\r\n10: D ->( 7)-> B = 10 7 3 0\r\n11: A ->( 9)-> D = 1 7 3 9\r\n12: A ->( 1)-> C = 0 7 4 9\r\n13: D ->( 9)-> A = 9 7 4 0\r\n14: A ->( 3)-> B = 6 10 4 0\r\n15: B ->( 9)-> D = 6 1 4 9\r\n16: B ->( 1)-> C = 6 0 5 9\r\n17: D ->( 4)-> A = 10 0 5 5\r\n18: D ->( 5)-> B = 10 5 5 0\r\n19: A ->( 9)-> D = 1 5 5 9\r\n20: D ->( 5)-> B = 1 10 5 4\n\r\nAfter 20th step we end up with 1 liter in first 10-liter jug (A), and 4 liters in 9-liter jug (D), as requested in problem.\n<|im_end|>" }, { "id": "#6941", "title": "Susie, Ned, Tom, Sal", "fun": 2.22, "difficulty": 1.33, "author": "sullivan", "desc": "Susie is six years old. Her brother Ned is four years younger than Tom. Sal is a decade older than Tom. Sal is three times Susie's age. How old are Ned, Tom and Sal?", "hint": "No hint available.", "answer": "Ned is four, Tom is eight, and Sal is eighteen.", "category": "Math", "date": "08/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSusie is six years old. Her brother Ned is four years younger than Tom. Sal is a decade older than Tom. Sal is three times Susie's age. How old are Ned, Tom and Sal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNed is four, Tom is eight, and Sal is eighteen.\n<|im_start|>answer\nNed is four, Tom is eight, and Sal is eighteen.\n<|im_end|>" }, { "id": "#13129", "title": "To Grandmother's House", "fun": 2.22, "difficulty": 1.45, "author": "adoontourious", "desc": "1) Scott and his family live 15 miles south of grandma.\n\r\n2) Steffi lives 20 miles north of Byron.\n\r\n3) Robin lives 5 miles south of Scott.\n\r\n4) Bryon lives 10 miles north of Robin.\n\r\n5) Caitlin lives 15 miles south of Bryon\n\r\nHow far does each live from grandma's house?", "hint": "No hint available.", "answer": "Bryon lives 10 miles south of grandma.\r\nSteffi lives 10 miles north of grandma.\r\nScott lives 15 miles to the south.\r\nRobin lives 20 miles to the south.\r\nCaitlin lives 25 miles to the south.", "category": "Logic", "date": "06/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n1) Scott and his family live 15 miles south of grandma.\n\r\n2) Steffi lives 20 miles north of Byron.\n\r\n3) Robin lives 5 miles south of Scott.\n\r\n4) Bryon lives 10 miles north of Robin.\n\r\n5) Caitlin lives 15 miles south of Bryon\n\r\nHow far does each live from grandma's house?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBryon lives 10 miles south of grandma.\r\nSteffi lives 10 miles north of grandma.\r\nScott lives 15 miles to the south.\r\nRobin lives 20 miles to the south.\r\nCaitlin lives 25 miles to the south.\n<|im_start|>answer\nBryon lives 10 miles south of grandma.\r\nSteffi lives 10 miles north of grandma.\r\nScott lives 15 miles to the south.\r\nRobin lives 20 miles to the south.\r\nCaitlin lives 25 miles to the south.\n<|im_end|>" }, { "id": "#6695", "title": "Stormy Story", "fun": 2.22, "difficulty": 1.27, "author": "Drunky", "desc": "A man burst into a police station soaking wet and starts screaming \"MY WIFE HAS BEEN MURDERED MY WIFE HAS BEEN MURDERED!\" \n\r\nA police officer asked what happened and the man explained that when they were walking along the cliffs of the shore, he heard a big roll of thunder come out of nowhere. He turned around startled to see what happened and then a huge bolt of lightning struck and his wife screamed. He turned around and saw his wife laying mangled on the sharp rocks of the cliff bottom, and he saw a man running away. \n\r\nThe officer said that the man was obviously lying and had him arrested for the murder of his wife. How did the officer know?", "hint": "No hint available.", "answer": "The lightning would travel faster than the thunder so the man's story would be inaccurate since he says he heard the thunder, then saw the lightning.", "category": "Logic", "date": "08/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man burst into a police station soaking wet and starts screaming \"MY WIFE HAS BEEN MURDERED MY WIFE HAS BEEN MURDERED!\" \n\r\nA police officer asked what happened and the man explained that when they were walking along the cliffs of the shore, he heard a big roll of thunder come out of nowhere. He turned around startled to see what happened and then a huge bolt of lightning struck and his wife screamed. He turned around and saw his wife laying mangled on the sharp rocks of the cliff bottom, and he saw a man running away. \n\r\nThe officer said that the man was obviously lying and had him arrested for the murder of his wife. How did the officer know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lightning would travel faster than the thunder so the man's story would be inaccurate since he says he heard the thunder, then saw the lightning.\n<|im_start|>answer\nThe lightning would travel faster than the thunder so the man's story would be inaccurate since he says he heard the thunder, then saw the lightning.\n<|im_end|>" }, { "id": "#36449", "title": "The Giggling Pixies", "fun": 2.22, "difficulty": 1.24, "author": "coolblue", "desc": "There were two giggling pixies, the old one and the young one. The old one is 120 years old, and the young one is 32 years old. How old will the old pixie be when he is exactly twice as old as the young one?", "hint": "No hint available.", "answer": "The old pixie is 88 years older than the young pixie. This means that the old pixie would be 176 years old when the young pixie would be 88 years old. However, do not worry because neither of these creatures will be able to age that much.", "category": "Math", "date": "04/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were two giggling pixies, the old one and the young one. The old one is 120 years old, and the young one is 32 years old. How old will the old pixie be when he is exactly twice as old as the young one?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe old pixie is 88 years older than the young pixie. This means that the old pixie would be 176 years old when the young pixie would be 88 years old. However, do not worry because neither of these creatures will be able to age that much.\n<|im_start|>answer\nThe old pixie is 88 years older than the young pixie. This means that the old pixie would be 176 years old when the young pixie would be 88 years old. However, do not worry because neither of these creatures will be able to age that much.\n<|im_end|>" }, { "id": "#14361", "title": "Boys and Girls", "fun": 2.22, "difficulty": 1.39, "author": "adoontourious", "desc": "Each child in a family has at least 4 brothers and 4 sisters. What is the smallest number of children the family might have?", "hint": "No hint available.", "answer": "If each boy in the family has at least 4 brothers, then the smallest number of boys is 5. \n\r\nSimilarly , if each girl in the family has at least 4 sisters, then the smallest number of girls is 5. \n\r\nThus, the smallest number of children the family might have is 10.", "category": "Math", "date": "08/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach child in a family has at least 4 brothers and 4 sisters. What is the smallest number of children the family might have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf each boy in the family has at least 4 brothers, then the smallest number of boys is 5. \n\r\nSimilarly , if each girl in the family has at least 4 sisters, then the smallest number of girls is 5. \n\r\nThus, the smallest number of children the family might have is 10.\n<|im_start|>answer\nIf each boy in the family has at least 4 brothers, then the smallest number of boys is 5. \n\r\nSimilarly , if each girl in the family has at least 4 sisters, then the smallest number of girls is 5. \n\r\nThus, the smallest number of children the family might have is 10.\n<|im_end|>" }, { "id": "#16578", "title": "21 Blocks", "fun": 2.22, "difficulty": 2.1, "author": "Drakar", "desc": "One day, Drakar was studying for an algebra test when he noticed that his younger sibling made a pyramid of 21 blocks. Each row, from the bottom up, had one less block than the lower one. \n\r\n\"Hmm, I wonder how many different pyramids I can make. Now, I can only switch the blocks with other blocks on the row. So blocks in the fourth row can only be switched with other blocks from the fourth row. And I can switch blocks from as many rows I like, and count it as one different pyramid.\"\n\r\nAfter thinking for a minute he took out a calculator and quickly figured out the answer. How many different pyramids can be made?", "hint": "First, find the number of rows. Next, find the number of combinations each individual one has.", "answer": "24,883,200 different pyramids. \n\r\nFirst of all, there are six rows. (1 + 2 + 3 + 4 + 5 + 6 = 21) Now, the first row, if we disposed of the rest, has only one combination. The second has two, and the third has six. From this we can figure out that each row has a number of combinations equal to the last row's times the number of blocks in the current one. So four has 24, five has 120, and six, 720. \n\r\nNow, while six has 720, each one of the fifth row's combinations gives you 720 MORE rows. same with five to four, etc. So we do 720 * 120 * 24 * 6 * 2 * 1. This ends up as 24,883,200 different pyramids.", "category": "Math", "date": "02/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, Drakar was studying for an algebra test when he noticed that his younger sibling made a pyramid of 21 blocks. Each row, from the bottom up, had one less block than the lower one. \n\r\n\"Hmm, I wonder how many different pyramids I can make. Now, I can only switch the blocks with other blocks on the row. So blocks in the fourth row can only be switched with other blocks from the fourth row. And I can switch blocks from as many rows I like, and count it as one different pyramid.\"\n\r\nAfter thinking for a minute he took out a calculator and quickly figured out the answer. How many different pyramids can be made?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n24,883,200 different pyramids. \n\r\nFirst of all, there are six rows. (1 + 2 + 3 + 4 + 5 + 6 = 21) Now, the first row, if we disposed of the rest, has only one combination. The second has two, and the third has six. From this we can figure out that each row has a number of combinations equal to the last row's times the number of blocks in the current one. So four has 24, five has 120, and six, 720. \n\r\nNow, while six has 720, each one of the fifth row's combinations gives you 720 MORE rows. same with five to four, etc. So we do 720 * 120 * 24 * 6 * 2 * 1. This ends up as 24,883,200 different pyramids.\n<|im_start|>answer\n24,883,200 different pyramids. \n\r\nFirst of all, there are six rows. (1 + 2 + 3 + 4 + 5 + 6 = 21) Now, the first row, if we disposed of the rest, has only one combination. The second has two, and the third has six. From this we can figure out that each row has a number of combinations equal to the last row's times the number of blocks in the current one. So four has 24, five has 120, and six, 720. \n\r\nNow, while six has 720, each one of the fifth row's combinations gives you 720 MORE rows. same with five to four, etc. So we do 720 * 120 * 24 * 6 * 2 * 1. This ends up as 24,883,200 different pyramids.\n<|im_end|>" }, { "id": "#4524", "title": "Odds of the Lottery", "fun": 2.22, "difficulty": 1.52, "author": "Mogmatt16", "desc": "Assume a lottery is held where there are 5 winning numbers from 1 to 50 inclusive, and no number is repeated. Do you stand to make more money by picking your own numbers or having a computer give you random numbers?", "hint": "Try to pick some random numbers yourself.", "answer": "You have better odds of making more money if you let the computer pick. If you have ever seen someone try to make random numbers, most people can't. If you are trying to pick random numbers, you will probably never pick 1-2-3-4-5 unless you are trying to make up for not picking numbers like that. However, a computer picking random numbers would likely pick that as much as the winning numbers would be that. So, your odds would be better to get the numbers from a computer because there would be less people to share the money with since the numbers are less easily reproduced.\n\r\nBut, your odds of winning were never really good in the first place.", "category": "Logic", "date": "06/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAssume a lottery is held where there are 5 winning numbers from 1 to 50 inclusive, and no number is repeated. Do you stand to make more money by picking your own numbers or having a computer give you random numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou have better odds of making more money if you let the computer pick. If you have ever seen someone try to make random numbers, most people can't. If you are trying to pick random numbers, you will probably never pick 1-2-3-4-5 unless you are trying to make up for not picking numbers like that. However, a computer picking random numbers would likely pick that as much as the winning numbers would be that. So, your odds would be better to get the numbers from a computer because there would be less people to share the money with since the numbers are less easily reproduced.\n\r\nBut, your odds of winning were never really good in the first place.\n<|im_start|>answer\nYou have better odds of making more money if you let the computer pick. If you have ever seen someone try to make random numbers, most people can't. If you are trying to pick random numbers, you will probably never pick 1-2-3-4-5 unless you are trying to make up for not picking numbers like that. However, a computer picking random numbers would likely pick that as much as the winning numbers would be that. So, your odds would be better to get the numbers from a computer because there would be less people to share the money with since the numbers are less easily reproduced.\n\r\nBut, your odds of winning were never really good in the first place.\n<|im_end|>" }, { "id": "#4362", "title": "North Pole", "fun": 2.22, "difficulty": 1.26, "author": "librashorty", "desc": "How far will you travel if you start at the equator and go to the North Pole always heading north-west?", "hint": "No hint available.", "answer": "Infinity. You will never reach the North Pole. If you were at the North Pole, the only direction in which you can leave is South. Therefore you must arrive by walking North. But you are walking North-west.", "category": "Logic", "date": "05/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow far will you travel if you start at the equator and go to the North Pole always heading north-west?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nInfinity. You will never reach the North Pole. If you were at the North Pole, the only direction in which you can leave is South. Therefore you must arrive by walking North. But you are walking North-west.\n<|im_start|>answer\nInfinity. You will never reach the North Pole. If you were at the North Pole, the only direction in which you can leave is South. Therefore you must arrive by walking North. But you are walking North-west.\n<|im_end|>" }, { "id": "#6773", "title": "Half of Two", "fun": 2.22, "difficulty": 0.8300000000000001, "author": "k2w2man", "desc": "Is half of two plus two equal to two or three?", "hint": "No hint available.", "answer": "Three. It seems that it could almost be either, \r\nbut if you follow the mathematical orders of operation, \r\ndivision is performed before addition. So... half of two \r\nis one. Then add two, and the answer is three.", "category": "Math", "date": "08/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIs half of two plus two equal to two or three?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree. It seems that it could almost be either, \r\nbut if you follow the mathematical orders of operation, \r\ndivision is performed before addition. So... half of two \r\nis one. Then add two, and the answer is three.\n<|im_start|>answer\nThree. It seems that it could almost be either, \r\nbut if you follow the mathematical orders of operation, \r\ndivision is performed before addition. So... half of two \r\nis one. Then add two, and the answer is three.\n<|im_end|>" }, { "id": "#35156", "title": "Food Fight Fiasco #2", "fun": 2.22, "difficulty": 2.7, "author": "t4mt", "desc": "The food fight is breaking out, and you are a prisoner. To determine if you really are the brain you claim you are, the other boss asks you the following with a 30-second time limit:\n\r\n He writes down the following numbers:\r\n1, 2, 3, 4, 5, 6, 7, 9, 2, 4, 3, 9, 1, 5.\n\r\nThe following numbers are used to create 7 distinct 2-digit prime numbers. Note that 1, 2, 3, 4, 5, and 9 must be used exactly twice while 6 and 7 must be used exactly once. What is the sum of those prime numbers?", "hint": "Note that any 2 digit number can be written as 10t+u, where t is the ten's digit, and u is the one's digit.", "answer": "313 \n\r\n2, 4, and 6 cannot be in the one's place because that would make the number divisible by 2. 5 cannot also be in the ones place because that would make it divisible by 5. Thus, the sum of the primes is 10(2+4+5+6+2+4+5) + 1+3+7+9+1+3+9 = 313 \n\r\nIt is also possible to figure out the prime numbers, although that will probably take longer than 30 seconds.", "category": "Math", "date": "02/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe food fight is breaking out, and you are a prisoner. To determine if you really are the brain you claim you are, the other boss asks you the following with a 30-second time limit:\n\r\n He writes down the following numbers:\r\n1, 2, 3, 4, 5, 6, 7, 9, 2, 4, 3, 9, 1, 5.\n\r\nThe following numbers are used to create 7 distinct 2-digit prime numbers. Note that 1, 2, 3, 4, 5, and 9 must be used exactly twice while 6 and 7 must be used exactly once. What is the sum of those prime numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n313 \n\r\n2, 4, and 6 cannot be in the one's place because that would make the number divisible by 2. 5 cannot also be in the ones place because that would make it divisible by 5. Thus, the sum of the primes is 10(2+4+5+6+2+4+5) + 1+3+7+9+1+3+9 = 313 \n\r\nIt is also possible to figure out the prime numbers, although that will probably take longer than 30 seconds.\n<|im_start|>answer\n313 \n\r\n2, 4, and 6 cannot be in the one's place because that would make the number divisible by 2. 5 cannot also be in the ones place because that would make it divisible by 5. Thus, the sum of the primes is 10(2+4+5+6+2+4+5) + 1+3+7+9+1+3+9 = 313 \n\r\nIt is also possible to figure out the prime numbers, although that will probably take longer than 30 seconds.\n<|im_end|>" }, { "id": "#45241", "title": "Dinner Dilema", "fun": 2.22, "difficulty": 0.51, "author": "twin27", "desc": "Four boys walk into a diner and ask the waitress for \"the usual\", but the waitress has forgotten who gets what! Can you help her find out by using what she does remember?\n\r\n1. Jon did not eat the sandwich or burger.\r\n2. The person who ate the burger had orange soda.\r\n3. Bill had cherry soda.\r\n4. Eli did not have orange soda.\r\n5. The person with the sandwich and the person with the salad have the same number of letters in their name.\r\n6. The person who had the sandwich did not have the strawberry soda.", "hint": "No hint available.", "answer": "Jon had salad and strawberry soda.\r\nBill had Pizza with cherry soda.\r\nEli had a sandwich with grape soda.\r\nDanny had a burger with orange soda.", "category": "Logic-Grid", "date": "09/07/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour boys walk into a diner and ask the waitress for \"the usual\", but the waitress has forgotten who gets what! Can you help her find out by using what she does remember?\n\r\n1. Jon did not eat the sandwich or burger.\r\n2. The person who ate the burger had orange soda.\r\n3. Bill had cherry soda.\r\n4. Eli did not have orange soda.\r\n5. The person with the sandwich and the person with the salad have the same number of letters in their name.\r\n6. The person who had the sandwich did not have the strawberry soda.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJon had salad and strawberry soda.\r\nBill had Pizza with cherry soda.\r\nEli had a sandwich with grape soda.\r\nDanny had a burger with orange soda.\n<|im_start|>answer\nJon had salad and strawberry soda.\r\nBill had Pizza with cherry soda.\r\nEli had a sandwich with grape soda.\r\nDanny had a burger with orange soda.\n<|im_end|>" }, { "id": "#1824", "title": "Attorney in Alabama", "fun": 2.22, "difficulty": 0.78, "author": "missie", "desc": "A doctor has a brother who is an attorney in Alabama, but the attorney in Alabama does not have a brother who is a doctor.\n\r\nHow can this be?", "hint": "No hint available.", "answer": "The doctor is his sister.", "category": "Logic", "date": "12/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA doctor has a brother who is an attorney in Alabama, but the attorney in Alabama does not have a brother who is a doctor.\n\r\nHow can this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe doctor is his sister.\n<|im_start|>answer\nThe doctor is his sister.\n<|im_end|>" }, { "id": "#18970", "title": "Colored Buildings !!!", "fun": 2.22, "difficulty": 1.94, "author": "lesternoronha1", "desc": "Five buildings, each of a different color among Red, Blue, Green, Yellow and Orange, are located in a row. All the buildings are of different heights. \n\r\nSome of the observations about the buildings are given below:-\r\n1) The tallest building is adjacent to two buildings.\r\n2) The blue colored building is exactly between the orange and red colored buildings and it is exactly in between the green and the yellow colored buildings.\r\n3) The orange colored building is the second shortest and is adjacent to the tallest building.\r\n4) The second tallest building, which is colored green, is at one of the ends and is to the immediate left of the shortest building.\n\r\nWhat is the color of the tallest building?", "hint": "No hint available.", "answer": "The observations given are as follows :-\r\n1) The tallest building is adjacent to two buildings.\r\n2) The blue colored building is exactly between the orange and red colored buildings and it is exactly in between the green and the yellow colored buildings.\r\n3) The orange colored building is the second shortest and is adjacent to the tallest building.\r\n4) The second tallest building, which is colored green, is at one of the ends and is to the immediate left of the shortest building.\n\r\nFrom observation 2, the blue building must be exactly at the center of the row of 5 buildings. Hence the order should be\n\r\nBuilding1 \r\nBuilding2 \r\nBlue \r\nBuilding3 \r\nBuilding4 \n\r\nFrom observations 3 and 4, we get that green is the second tallest building and orange is the fourth tallest building. From observation 4, we get that the Green colored building is at one of the ends and is to the immediate left of the shortest building. Also from observation 2, the Orange and Red colored buildings should be equidistant from the Blue colored building and the Green and the Yellow colored buildings must also be equidistant the Blue colored building. Hence the order after all these observations should be\n\r\nGreen \r\nOrange/Red (shortest) \r\nBlue \r\nOrange/Red \r\nYellow \n\r\nFrom observation 3, orange is the second shortest building and hence it cannot be to the right of Green, since from observation 4, green sits next to the shortest building. \r\nHence Red is the shortest building. Thus the final order is \n\r\nGreen \r\nRed \r\nBlue \r\nOrange \r\nYellow\n\r\nNow from observation 1, we have the tallest building is adjacent to two other buildings. In the order above only three colored buildings namely Red, Blue and Orange are adjacent to two other buildings. Since Red is the shortest and Orange the second shortest, the building colored Blue must be the tallest out of the given buildings.\n\r\nHence the Blue colored building is the tallest among the given buildings.", "category": "Logic", "date": "09/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive buildings, each of a different color among Red, Blue, Green, Yellow and Orange, are located in a row. All the buildings are of different heights. \n\r\nSome of the observations about the buildings are given below:-\r\n1) The tallest building is adjacent to two buildings.\r\n2) The blue colored building is exactly between the orange and red colored buildings and it is exactly in between the green and the yellow colored buildings.\r\n3) The orange colored building is the second shortest and is adjacent to the tallest building.\r\n4) The second tallest building, which is colored green, is at one of the ends and is to the immediate left of the shortest building.\n\r\nWhat is the color of the tallest building?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe observations given are as follows :-\r\n1) The tallest building is adjacent to two buildings.\r\n2) The blue colored building is exactly between the orange and red colored buildings and it is exactly in between the green and the yellow colored buildings.\r\n3) The orange colored building is the second shortest and is adjacent to the tallest building.\r\n4) The second tallest building, which is colored green, is at one of the ends and is to the immediate left of the shortest building.\n\r\nFrom observation 2, the blue building must be exactly at the center of the row of 5 buildings. Hence the order should be\n\r\nBuilding1 \r\nBuilding2 \r\nBlue \r\nBuilding3 \r\nBuilding4 \n\r\nFrom observations 3 and 4, we get that green is the second tallest building and orange is the fourth tallest building. From observation 4, we get that the Green colored building is at one of the ends and is to the immediate left of the shortest building. Also from observation 2, the Orange and Red colored buildings should be equidistant from the Blue colored building and the Green and the Yellow colored buildings must also be equidistant the Blue colored building. Hence the order after all these observations should be\n\r\nGreen \r\nOrange/Red (shortest) \r\nBlue \r\nOrange/Red \r\nYellow \n\r\nFrom observation 3, orange is the second shortest building and hence it cannot be to the right of Green, since from observation 4, green sits next to the shortest building. \r\nHence Red is the shortest building. Thus the final order is \n\r\nGreen \r\nRed \r\nBlue \r\nOrange \r\nYellow\n\r\nNow from observation 1, we have the tallest building is adjacent to two other buildings. In the order above only three colored buildings namely Red, Blue and Orange are adjacent to two other buildings. Since Red is the shortest and Orange the second shortest, the building colored Blue must be the tallest out of the given buildings.\n\r\nHence the Blue colored building is the tallest among the given buildings.\n<|im_start|>answer\nThe observations given are as follows :-\r\n1) The tallest building is adjacent to two buildings.\r\n2) The blue colored building is exactly between the orange and red colored buildings and it is exactly in between the green and the yellow colored buildings.\r\n3) The orange colored building is the second shortest and is adjacent to the tallest building.\r\n4) The second tallest building, which is colored green, is at one of the ends and is to the immediate left of the shortest building.\n\r\nFrom observation 2, the blue building must be exactly at the center of the row of 5 buildings. Hence the order should be\n\r\nBuilding1 \r\nBuilding2 \r\nBlue \r\nBuilding3 \r\nBuilding4 \n\r\nFrom observations 3 and 4, we get that green is the second tallest building and orange is the fourth tallest building. From observation 4, we get that the Green colored building is at one of the ends and is to the immediate left of the shortest building. Also from observation 2, the Orange and Red colored buildings should be equidistant from the Blue colored building and the Green and the Yellow colored buildings must also be equidistant the Blue colored building. Hence the order after all these observations should be\n\r\nGreen \r\nOrange/Red (shortest) \r\nBlue \r\nOrange/Red \r\nYellow \n\r\nFrom observation 3, orange is the second shortest building and hence it cannot be to the right of Green, since from observation 4, green sits next to the shortest building. \r\nHence Red is the shortest building. Thus the final order is \n\r\nGreen \r\nRed \r\nBlue \r\nOrange \r\nYellow\n\r\nNow from observation 1, we have the tallest building is adjacent to two other buildings. In the order above only three colored buildings namely Red, Blue and Orange are adjacent to two other buildings. Since Red is the shortest and Orange the second shortest, the building colored Blue must be the tallest out of the given buildings.\n\r\nHence the Blue colored building is the tallest among the given buildings.\n<|im_end|>" }, { "id": "#4068", "title": "The Fontaine Sisters", "fun": 2.22, "difficulty": 2.05, "author": "GoldieLuvNeopets", "desc": "The Fontaine sisters are seamstresses by trade. They have been commissioned to create as many 2 by 3 feet rectangular Jolly Roger flags as they can for the pirates in their village, so Loretta Fontaine has gone out to buy cloth to embroider. \n\r\nDark cloth costs $150 a foot and comes in a roll five feet wide. It can be bought in any length (even down to the inch). She has a total of $1,260 to spend on the cloth.\n\r\nHow many WHOLE Jolly Roger flags will they be able to make?", "hint": "No hint available.", "answer": "Six. If you divide the $1260 by 150, you get the length that can be bought, 8.4 feet, so there will be a rectangle of 8.4 by 5. If this is cut into 2 rectangles, 8.4 * 2 and 8.4 * 3, from one rectangle, 2 can be cut, and from the other, 4 can be cut, making 6.", "category": "Math", "date": "05/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Fontaine sisters are seamstresses by trade. They have been commissioned to create as many 2 by 3 feet rectangular Jolly Roger flags as they can for the pirates in their village, so Loretta Fontaine has gone out to buy cloth to embroider. \n\r\nDark cloth costs $150 a foot and comes in a roll five feet wide. It can be bought in any length (even down to the inch). She has a total of $1,260 to spend on the cloth.\n\r\nHow many WHOLE Jolly Roger flags will they be able to make?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSix. If you divide the $1260 by 150, you get the length that can be bought, 8.4 feet, so there will be a rectangle of 8.4 by 5. If this is cut into 2 rectangles, 8.4 * 2 and 8.4 * 3, from one rectangle, 2 can be cut, and from the other, 4 can be cut, making 6.\n<|im_start|>answer\nSix. If you divide the $1260 by 150, you get the length that can be bought, 8.4 feet, so there will be a rectangle of 8.4 by 5. If this is cut into 2 rectangles, 8.4 * 2 and 8.4 * 3, from one rectangle, 2 can be cut, and from the other, 4 can be cut, making 6.\n<|im_end|>" }, { "id": "#3961", "title": "Sweatybeard the Pirate", "fun": 2.22, "difficulty": 2.19, "author": "mad-ade", "desc": "Sweatybeard the pirate was counting his latest haul of treasure which consisted of rings, necklaces and earrings. There are 26 items altogether. He has 2 and a half times as many rings as necklaces and the number of pairs of earrings is 4 less than the number of rings.\r\nHow many earring does Sweatybeard have?", "hint": "No hint available.", "answer": "12 earrings (6 pairs)", "category": "Math", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSweatybeard the pirate was counting his latest haul of treasure which consisted of rings, necklaces and earrings. There are 26 items altogether. He has 2 and a half times as many rings as necklaces and the number of pairs of earrings is 4 less than the number of rings.\r\nHow many earring does Sweatybeard have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12 earrings (6 pairs)\n<|im_start|>answer\n12 earrings (6 pairs)\n<|im_end|>" }, { "id": "#8421", "title": "Draw a Line for an A", "fun": 2.22, "difficulty": 1.78, "author": "stonemug", "desc": "A math teacher I had in high school gave a challenge to the class at the beginning of the semester. The challenge was going to be worth an A for the semester. The challenge was to draw a picture of a line and turn it in. With in a matter a few minutes the teacher had 30 pieces of paper on his desk with straight lines on them. The teacher threw them all in the trash saying none of them were right. Why?", "hint": "No hint available.", "answer": "The teacher informed us according the laws of Mathematics and Geometry a line has no dimension and continues on forever (dimension being depth, width, or height). Therefore drawing a true line is impossible.", "category": "Math", "date": "11/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA math teacher I had in high school gave a challenge to the class at the beginning of the semester. The challenge was going to be worth an A for the semester. The challenge was to draw a picture of a line and turn it in. With in a matter a few minutes the teacher had 30 pieces of paper on his desk with straight lines on them. The teacher threw them all in the trash saying none of them were right. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe teacher informed us according the laws of Mathematics and Geometry a line has no dimension and continues on forever (dimension being depth, width, or height). Therefore drawing a true line is impossible.\n<|im_start|>answer\nThe teacher informed us according the laws of Mathematics and Geometry a line has no dimension and continues on forever (dimension being depth, width, or height). Therefore drawing a true line is impossible.\n<|im_end|>" }, { "id": "#13261", "title": "Prime territory", "fun": 2.22, "difficulty": 2.12, "author": "pooja", "desc": "We know that a prime number is a number whose only factors are itself and 1. We also know that there is only one even prime number - and that is 2. Now for the puzzle, which is to find a three-digit number with the following properties:\n\r\n1) Each of the three digits is a prime number and,\n\r\n2) Each of those digits divides evenly into the three-digit number.", "hint": "No hint available.", "answer": "The only number that satisfies both conditions is 735.", "category": "Math", "date": "06/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWe know that a prime number is a number whose only factors are itself and 1. We also know that there is only one even prime number - and that is 2. Now for the puzzle, which is to find a three-digit number with the following properties:\n\r\n1) Each of the three digits is a prime number and,\n\r\n2) Each of those digits divides evenly into the three-digit number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe only number that satisfies both conditions is 735.\n<|im_start|>answer\nThe only number that satisfies both conditions is 735.\n<|im_end|>" }, { "id": "#21709", "title": "Dino Photo?", "fun": 2.21, "difficulty": 0.7000000000000001, "author": "mufffin09", "desc": "Ms. Tina Gull, who is notorious for her gullibility, asked her friend the detective a question.\r\n \"Detective Brown, I met a man who found a cave painting. He gave me and a friend the opportunity to buy it from the archaeological team. Are you interested in going in on the deal with me?\" \n\r\nDetective Brown thought for a moment and asked Ms. Tina, \r\n\"What was this painting of?\"\r\nMs. Tina answered, \"There are two cave people going hunting. One has a spear and the other a bunch of stones. They are stalking a dinosaur. Then, in another picture, they are actually killing the thing, throwing the spear and everything!''\r\nDetective Brown thought for a while and politely told her he wouldn't go in on the deal and advised her not to either as this was a scam (again). \n\r\nWhy did he say this?", "hint": "Think about what the cave people were doing.", "answer": "The cave painting has to be fake. If it was drawn by ancient people, they would not have known dinosaurs had existed, as dinosaurs died out about 63 million years before the first hominid evolved.", "category": "Logic", "date": "03/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMs. Tina Gull, who is notorious for her gullibility, asked her friend the detective a question.\r\n \"Detective Brown, I met a man who found a cave painting. He gave me and a friend the opportunity to buy it from the archaeological team. Are you interested in going in on the deal with me?\" \n\r\nDetective Brown thought for a moment and asked Ms. Tina, \r\n\"What was this painting of?\"\r\nMs. Tina answered, \"There are two cave people going hunting. One has a spear and the other a bunch of stones. They are stalking a dinosaur. Then, in another picture, they are actually killing the thing, throwing the spear and everything!''\r\nDetective Brown thought for a while and politely told her he wouldn't go in on the deal and advised her not to either as this was a scam (again). \n\r\nWhy did he say this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cave painting has to be fake. If it was drawn by ancient people, they would not have known dinosaurs had existed, as dinosaurs died out about 63 million years before the first hominid evolved.\n<|im_start|>answer\nThe cave painting has to be fake. If it was drawn by ancient people, they would not have known dinosaurs had existed, as dinosaurs died out about 63 million years before the first hominid evolved.\n<|im_end|>" }, { "id": "#8679", "title": "How Many Books?", "fun": 2.21, "difficulty": 1.79, "author": "the_smart_one", "desc": "John has 15 books, and poses himself with a challenge: ''If I placed each book side by side, I wonder how many different combinations I could arrange these books in...''. \n\r\nHow many combinations are there?", "hint": "No hint available.", "answer": "1307674368000\n\r\n15x14x13x12x11x10x9x8x7x6x5x4x3x2x1=1307674368000", "category": "Math", "date": "11/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJohn has 15 books, and poses himself with a challenge: ''If I placed each book side by side, I wonder how many different combinations I could arrange these books in...''. \n\r\nHow many combinations are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1307674368000\n\r\n15x14x13x12x11x10x9x8x7x6x5x4x3x2x1=1307674368000\n<|im_start|>answer\n1307674368000\n\r\n15x14x13x12x11x10x9x8x7x6x5x4x3x2x1=1307674368000\n<|im_end|>" }, { "id": "#2504", "title": "Earring in a Coffee", "fun": 2.21, "difficulty": 1.16, "author": "Cascas", "desc": "Matt asked his secretary to make coffee. While it was being made, her earring fell into the cup. Even though the cup had coffee in it, it didn't get wet. Why?", "hint": "No hint available.", "answer": "The cup had dry instant coffee in it.", "category": "Logic", "date": "03/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMatt asked his secretary to make coffee. While it was being made, her earring fell into the cup. Even though the cup had coffee in it, it didn't get wet. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe cup had dry instant coffee in it.\n<|im_start|>answer\nThe cup had dry instant coffee in it.\n<|im_end|>" }, { "id": "#19273", "title": "Boutique Bouquets ...", "fun": 2.21, "difficulty": 2.74, "author": "lesternoronha1", "desc": "The owner of a Romankachi flower boutique follows a particular pattern for his business. During a period of inflation, he raises his prices by Y% and during a slowdown he decreases his existing prices by Y%. After a year in which there was inflation first, followed by a slowdown, the cost of a Red Rose bouquet decreases by 162 Roka (Roka being the native Romankachi currency). After another year in which there was inflation once more followed by a slowdown, the cost of this bouquet reduces by a further 147.42 Roka. What was the original price of the Red Rose bouquet ?", "hint": "No hint available.", "answer": "The original price of the Red Rose bouquet is 1800 Roka.\n\r\nLet the original price of the Red Rose bouquet be 'B' Roka.\r\nIt is given that during a period of inflation, he raises his prices by Y% and during a slowdown he decreases his existing prices by Y%.\n\r\nHence after a year in which there was inflation first, followed by a slowdown, and the cost of a Red Rose bouquet decreased by 162 Roka, the price of the bouquet \r\n= B(1+Y)(1-Y) \r\n= B(1-Y^2)\r\n(since B(1+Y) is the price during inflation and B(1-Y)(1+Y) the price during the slowdown)\n\r\nTherefore the decrease in price after one year \r\n= B - B(1-Y^2)\r\n= B - B + B*Y^2\r\n= B*Y^2 = 162 ... Equation 1\n\r\nHence after another year in which there was inflation first, followed by a slowdown, and the cost of a Red Rose bouquet decreased by 147.42 Roka, the price of the bouquet \r\n= B(1-Y^2)(1+Y)(1-Y)\r\n= B(1-Y^2)(1-Y^2)\r\n= B(1-Y^2)^2\r\n(since B(1-Y^2) is the price at the end of the previous year and B(1-Y^2)(1+Y)(1-Y) the price during the slowdown this year)\n\r\nTherefore the decrease in price this year \r\n= B(1-Y^2) - B(1-Y^2)^2\r\n= B(1-Y^2)[1 - (1-Y^2)]\r\n= B(1-Y^2)( Y^2) = 147.42 ... Equation 2\n\r\nDividing Equation 2 by Equation 1, we get\r\n(1-Y^2) = 0.91 => Y^2 = 0.09\n\r\nSubstituting the above value of Y^2 in equation 1, we get \r\nB*0.09 = 162\r\nHence B = 162/0.09 = 1800 Roka.\n\r\nTherefore the original price of the Red Rose bouquet is 1800 Roka.", "category": "Math", "date": "10/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe owner of a Romankachi flower boutique follows a particular pattern for his business. During a period of inflation, he raises his prices by Y% and during a slowdown he decreases his existing prices by Y%. After a year in which there was inflation first, followed by a slowdown, the cost of a Red Rose bouquet decreases by 162 Roka (Roka being the native Romankachi currency). After another year in which there was inflation once more followed by a slowdown, the cost of this bouquet reduces by a further 147.42 Roka. What was the original price of the Red Rose bouquet ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe original price of the Red Rose bouquet is 1800 Roka.\n\r\nLet the original price of the Red Rose bouquet be 'B' Roka.\r\nIt is given that during a period of inflation, he raises his prices by Y% and during a slowdown he decreases his existing prices by Y%.\n\r\nHence after a year in which there was inflation first, followed by a slowdown, and the cost of a Red Rose bouquet decreased by 162 Roka, the price of the bouquet \r\n= B(1+Y)(1-Y) \r\n= B(1-Y^2)\r\n(since B(1+Y) is the price during inflation and B(1-Y)(1+Y) the price during the slowdown)\n\r\nTherefore the decrease in price after one year \r\n= B - B(1-Y^2)\r\n= B - B + B*Y^2\r\n= B*Y^2 = 162 ... Equation 1\n\r\nHence after another year in which there was inflation first, followed by a slowdown, and the cost of a Red Rose bouquet decreased by 147.42 Roka, the price of the bouquet \r\n= B(1-Y^2)(1+Y)(1-Y)\r\n= B(1-Y^2)(1-Y^2)\r\n= B(1-Y^2)^2\r\n(since B(1-Y^2) is the price at the end of the previous year and B(1-Y^2)(1+Y)(1-Y) the price during the slowdown this year)\n\r\nTherefore the decrease in price this year \r\n= B(1-Y^2) - B(1-Y^2)^2\r\n= B(1-Y^2)[1 - (1-Y^2)]\r\n= B(1-Y^2)( Y^2) = 147.42 ... Equation 2\n\r\nDividing Equation 2 by Equation 1, we get\r\n(1-Y^2) = 0.91 => Y^2 = 0.09\n\r\nSubstituting the above value of Y^2 in equation 1, we get \r\nB*0.09 = 162\r\nHence B = 162/0.09 = 1800 Roka.\n\r\nTherefore the original price of the Red Rose bouquet is 1800 Roka.\n<|im_start|>answer\nThe original price of the Red Rose bouquet is 1800 Roka.\n\r\nLet the original price of the Red Rose bouquet be 'B' Roka.\r\nIt is given that during a period of inflation, he raises his prices by Y% and during a slowdown he decreases his existing prices by Y%.\n\r\nHence after a year in which there was inflation first, followed by a slowdown, and the cost of a Red Rose bouquet decreased by 162 Roka, the price of the bouquet \r\n= B(1+Y)(1-Y) \r\n= B(1-Y^2)\r\n(since B(1+Y) is the price during inflation and B(1-Y)(1+Y) the price during the slowdown)\n\r\nTherefore the decrease in price after one year \r\n= B - B(1-Y^2)\r\n= B - B + B*Y^2\r\n= B*Y^2 = 162 ... Equation 1\n\r\nHence after another year in which there was inflation first, followed by a slowdown, and the cost of a Red Rose bouquet decreased by 147.42 Roka, the price of the bouquet \r\n= B(1-Y^2)(1+Y)(1-Y)\r\n= B(1-Y^2)(1-Y^2)\r\n= B(1-Y^2)^2\r\n(since B(1-Y^2) is the price at the end of the previous year and B(1-Y^2)(1+Y)(1-Y) the price during the slowdown this year)\n\r\nTherefore the decrease in price this year \r\n= B(1-Y^2) - B(1-Y^2)^2\r\n= B(1-Y^2)[1 - (1-Y^2)]\r\n= B(1-Y^2)( Y^2) = 147.42 ... Equation 2\n\r\nDividing Equation 2 by Equation 1, we get\r\n(1-Y^2) = 0.91 => Y^2 = 0.09\n\r\nSubstituting the above value of Y^2 in equation 1, we get \r\nB*0.09 = 162\r\nHence B = 162/0.09 = 1800 Roka.\n\r\nTherefore the original price of the Red Rose bouquet is 1800 Roka.\n<|im_end|>" }, { "id": "#726", "title": "Book Price", "fun": 2.21, "difficulty": 1.59, "author": "vikass", "desc": "A book costs $5.00 plus one half of its price. How much does the book cost?", "hint": "No hint available.", "answer": "$10.00", "category": "Math", "date": "08/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA book costs $5.00 plus one half of its price. How much does the book cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$10.00\n<|im_start|>answer\n$10.00\n<|im_end|>" }, { "id": "#11054", "title": "Facially Inept", "fun": 2.21, "difficulty": 1.71, "author": "mad-ade", "desc": "There is a school reunion at Mad Ade's old school, Saint Crippens school for the Facially inept. He meets up with a group of his old gang, or at least the ones not locked away for their own safety. They reminisce about old times and lie about how well they are now doing. After a few drinks, they decide to try and work out who is the ugliest of the gang. \n\r\nNobby is Uglier than Bobby and prettier than Mad Ade. \n\r\nRobby is Uglier than Norris and prettier than Boris. \n\r\nMorris is Uglier than Bill and prettier than Norris. \n\r\nBobby is Uglier than Phil and prettier than Gill. \n\r\nBill is Uglier than Mad Ade and prettier than Robby. \n\r\nGill is prettier than Mad Ade. \n\r\nWho is the Ugliest?", "hint": "No hint available.", "answer": "Boris is the Ugliest. \n\r\nDiscard whoever are prettier than someone. \n\r\nFrom (1) Mad Ade is Uglier than Nobby and Bobby. \r\nFrom (5) Robby is Uglier than Bill and Mad Ade. \r\nFrom (2) Boris is Uglier than Robby and Norris. \n\r\nFrom above 3 deductions, Boris is Uglier than Nobby, Bobby, Bill, Mad Ade, Robby and Norris. \n\r\nAlso, \r\nFrom (3) Norris is Uglier than Morris and Bill. \r\nFrom (4) Gill is Uglier than Bobby and Phil. \r\nFrom (6) Mad Ade is Uglier than Gill. \n\r\nFrom above 3 deductions, Mad Ade is Uglier than Bobby, Phil and Gill. Also, Norris is Uglier than Morris and Bill. But as seen earlier, Boris is Uglier than Mad Ade and Norris. \n\r\nHence, Boris is the Ugliest.", "category": "Logic", "date": "03/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a school reunion at Mad Ade's old school, Saint Crippens school for the Facially inept. He meets up with a group of his old gang, or at least the ones not locked away for their own safety. They reminisce about old times and lie about how well they are now doing. After a few drinks, they decide to try and work out who is the ugliest of the gang. \n\r\nNobby is Uglier than Bobby and prettier than Mad Ade. \n\r\nRobby is Uglier than Norris and prettier than Boris. \n\r\nMorris is Uglier than Bill and prettier than Norris. \n\r\nBobby is Uglier than Phil and prettier than Gill. \n\r\nBill is Uglier than Mad Ade and prettier than Robby. \n\r\nGill is prettier than Mad Ade. \n\r\nWho is the Ugliest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoris is the Ugliest. \n\r\nDiscard whoever are prettier than someone. \n\r\nFrom (1) Mad Ade is Uglier than Nobby and Bobby. \r\nFrom (5) Robby is Uglier than Bill and Mad Ade. \r\nFrom (2) Boris is Uglier than Robby and Norris. \n\r\nFrom above 3 deductions, Boris is Uglier than Nobby, Bobby, Bill, Mad Ade, Robby and Norris. \n\r\nAlso, \r\nFrom (3) Norris is Uglier than Morris and Bill. \r\nFrom (4) Gill is Uglier than Bobby and Phil. \r\nFrom (6) Mad Ade is Uglier than Gill. \n\r\nFrom above 3 deductions, Mad Ade is Uglier than Bobby, Phil and Gill. Also, Norris is Uglier than Morris and Bill. But as seen earlier, Boris is Uglier than Mad Ade and Norris. \n\r\nHence, Boris is the Ugliest.\n<|im_start|>answer\nBoris is the Ugliest. \n\r\nDiscard whoever are prettier than someone. \n\r\nFrom (1) Mad Ade is Uglier than Nobby and Bobby. \r\nFrom (5) Robby is Uglier than Bill and Mad Ade. \r\nFrom (2) Boris is Uglier than Robby and Norris. \n\r\nFrom above 3 deductions, Boris is Uglier than Nobby, Bobby, Bill, Mad Ade, Robby and Norris. \n\r\nAlso, \r\nFrom (3) Norris is Uglier than Morris and Bill. \r\nFrom (4) Gill is Uglier than Bobby and Phil. \r\nFrom (6) Mad Ade is Uglier than Gill. \n\r\nFrom above 3 deductions, Mad Ade is Uglier than Bobby, Phil and Gill. Also, Norris is Uglier than Morris and Bill. But as seen earlier, Boris is Uglier than Mad Ade and Norris. \n\r\nHence, Boris is the Ugliest.\n<|im_end|>" }, { "id": "#19379", "title": "Mad Ade's Magic Square #2", "fun": 2.21, "difficulty": 2.31, "author": "Mad-Ade", "desc": "Mad Ade placed the numbers 1 through 9 into a 3x3 grid, such that in each of the 8 directions of 3 squares (horizontally, vertically and diagonally) the sum of the first and last numbers minus the center number gives the same result.", "hint": "No hint available.", "answer": "There is only one answer\r\n2 1 4 \r\n3 5 7 \r\n6 9 8", "category": "Math", "date": "11/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade placed the numbers 1 through 9 into a 3x3 grid, such that in each of the 8 directions of 3 squares (horizontally, vertically and diagonally) the sum of the first and last numbers minus the center number gives the same result.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere is only one answer\r\n2 1 4 \r\n3 5 7 \r\n6 9 8\n<|im_start|>answer\nThere is only one answer\r\n2 1 4 \r\n3 5 7 \r\n6 9 8\n<|im_end|>" }, { "id": "#34996", "title": "Pumpkin Sale", "fun": 2.21, "difficulty": 0.99, "author": "Thel", "desc": "Last week, I went to market with a whole crop of pumpkins which I had grown in my pumpkin patch. I sold half of them plus half a pumpkin, and found that I had one whole pumpkin left. How many pumpkins did I take to market?", "hint": "As a novice farmer, my first crop wasn't anything to go by.", "answer": "I took three pumpkins to market.", "category": "Math", "date": "01/23/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLast week, I went to market with a whole crop of pumpkins which I had grown in my pumpkin patch. I sold half of them plus half a pumpkin, and found that I had one whole pumpkin left. How many pumpkins did I take to market?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI took three pumpkins to market.\n<|im_start|>answer\nI took three pumpkins to market.\n<|im_end|>" }, { "id": "#23146", "title": "How Much Brine is in the Tank?", "fun": 2.21, "difficulty": 2.5100000000000002, "author": "hahor", "desc": "There is a brine in a storage tank that contains 2.5% sodium chloride (NaCl)in water. When you add another kilogram of NaCl the concentration goes up to 3%.\r\nHow much brine was originally in the storage tank?", "hint": "No hint available.", "answer": "Let there be X kg of NaCl and W kg of water in the original solution.\n\r\nFrom the first statement, \r\nX / (X + W) = 2.5% = 0.025 ---- (1)\n\r\nAfter adding 1 kg of NaCl, \r\n(X + 1) / (X + 1 + W) = 3% = 0.03 ---- (2)\n\r\nFrom (1): (X + W) / X = 1 / 0.025 = 40\n\r\n(1a): W = 39X\n\r\nFrom (2): (X + 1) / (X + 1 + 39 X) = 0.03\n\r\n(2a): X = 4.85 kg \n\r\n(1b): W = 189.15 kg\n\r\nX + W = 194 kg (original amount of brine in storage tank)", "category": "Math", "date": "05/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a brine in a storage tank that contains 2.5% sodium chloride (NaCl)in water. When you add another kilogram of NaCl the concentration goes up to 3%.\r\nHow much brine was originally in the storage tank?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet there be X kg of NaCl and W kg of water in the original solution.\n\r\nFrom the first statement, \r\nX / (X + W) = 2.5% = 0.025 ---- (1)\n\r\nAfter adding 1 kg of NaCl, \r\n(X + 1) / (X + 1 + W) = 3% = 0.03 ---- (2)\n\r\nFrom (1): (X + W) / X = 1 / 0.025 = 40\n\r\n(1a): W = 39X\n\r\nFrom (2): (X + 1) / (X + 1 + 39 X) = 0.03\n\r\n(2a): X = 4.85 kg \n\r\n(1b): W = 189.15 kg\n\r\nX + W = 194 kg (original amount of brine in storage tank)\n<|im_start|>answer\nLet there be X kg of NaCl and W kg of water in the original solution.\n\r\nFrom the first statement, \r\nX / (X + W) = 2.5% = 0.025 ---- (1)\n\r\nAfter adding 1 kg of NaCl, \r\n(X + 1) / (X + 1 + W) = 3% = 0.03 ---- (2)\n\r\nFrom (1): (X + W) / X = 1 / 0.025 = 40\n\r\n(1a): W = 39X\n\r\nFrom (2): (X + 1) / (X + 1 + 39 X) = 0.03\n\r\n(2a): X = 4.85 kg \n\r\n(1b): W = 189.15 kg\n\r\nX + W = 194 kg (original amount of brine in storage tank)\n<|im_end|>" }, { "id": "#18097", "title": "ABCDEFGH", "fun": 2.21, "difficulty": 1.68, "author": "beijing200820", "desc": "ABCDEFGH*H=AAAAAAAAA\r\nWhat is H?", "hint": "No hint available.", "answer": "12345679*9=111111111, so H is 9.", "category": "Math", "date": "07/02/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nABCDEFGH*H=AAAAAAAAA\r\nWhat is H?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12345679*9=111111111, so H is 9.\n<|im_start|>answer\n12345679*9=111111111, so H is 9.\n<|im_end|>" }, { "id": "#4693", "title": "Pay Raise", "fun": 2.21, "difficulty": 2.04, "author": "mad-ade", "desc": "A worker earns a 5% raise.\r\nA year later, the worker receives a 2.5% cut in pay.\r\nNow his salary is $22,702.68. \n\r\nWhat was his salary to begin with?", "hint": "No hint available.", "answer": "$22,176", "category": "Math", "date": "06/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA worker earns a 5% raise.\r\nA year later, the worker receives a 2.5% cut in pay.\r\nNow his salary is $22,702.68. \n\r\nWhat was his salary to begin with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$22,176\n<|im_start|>answer\n$22,176\n<|im_end|>" }, { "id": "#1528", "title": "Two Twice", "fun": 2.21, "difficulty": 1.12, "author": "LiL_MaN", "desc": "What is 2 times the half of 2 twice?", "hint": "No hint available.", "answer": "4", "category": "Math", "date": "11/26/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is 2 times the half of 2 twice?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4\n<|im_start|>answer\n4\n<|im_end|>" }, { "id": "#46349", "title": "50+50", "fun": 2.21, "difficulty": 2.2, "author": "gap6297", "desc": "When does 50+50=75?", "hint": "No hint available.", "answer": "When you are calculating percentages. \n\r\nFor example, if an item is originally $100, and goes on sale, 50 percent off, and you have a coupon for an additional 50 percent off, then the total is 75 percent off.", "category": "Math", "date": "02/10/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen does 50+50=75?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen you are calculating percentages. \n\r\nFor example, if an item is originally $100, and goes on sale, 50 percent off, and you have a coupon for an additional 50 percent off, then the total is 75 percent off.\n<|im_start|>answer\nWhen you are calculating percentages. \n\r\nFor example, if an item is originally $100, and goes on sale, 50 percent off, and you have a coupon for an additional 50 percent off, then the total is 75 percent off.\n<|im_end|>" }, { "id": "#2394", "title": "Walkers", "fun": 2.21, "difficulty": 1.36, "author": "RomanPhoenix", "desc": "Margaret and Bob are walking. They \r\nstay side by side the whole time. Bob\r\nwalked 4 miles, while Margaret only walked\r\n2. How can this be?", "hint": "Y M C A", "answer": "They are both on treadmills.", "category": "Logic", "date": "02/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMargaret and Bob are walking. They \r\nstay side by side the whole time. Bob\r\nwalked 4 miles, while Margaret only walked\r\n2. How can this be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are both on treadmills.\n<|im_start|>answer\nThey are both on treadmills.\n<|im_end|>" }, { "id": "#39120", "title": "Age By Numbers", "fun": 2.21, "difficulty": 1.3800000000000001, "author": "luna_lovegood", "desc": "The White family has 3 children. Figure out how old each one is, how much they weigh and how tall they are. One child is 17, one is 15, and one is 14. One child weighs 150 lbs, one weighs 130 lbs, and one weighs 110 lbs. One child is 5'1\", one is 5'3\", and one is 5'6\".\n\r\nBob is 2 inches taller that the oldest.\r\nThe youngest weighs the most.\r\nCarol is 15.\r\nThe middle child weighs 110 lbs. \r\nThe oldest is 20 lbs heavier than Carol.\r\nSue is 5'1\".\r\nThe youngest weighs 40 lbs more than Carol.\r\nThe oldest weighs 130 lbs.", "hint": "No hint available.", "answer": "Sue is 17, weighs 130 lbs, and is 5'1\".\r\nCarol is 15, weighs 110 lbs, and is 5'6\".\r\nBob is 14, weighs 150 lbs, and is 5'3\".", "category": "Logic", "date": "11/09/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe White family has 3 children. Figure out how old each one is, how much they weigh and how tall they are. One child is 17, one is 15, and one is 14. One child weighs 150 lbs, one weighs 130 lbs, and one weighs 110 lbs. One child is 5'1\", one is 5'3\", and one is 5'6\".\n\r\nBob is 2 inches taller that the oldest.\r\nThe youngest weighs the most.\r\nCarol is 15.\r\nThe middle child weighs 110 lbs. \r\nThe oldest is 20 lbs heavier than Carol.\r\nSue is 5'1\".\r\nThe youngest weighs 40 lbs more than Carol.\r\nThe oldest weighs 130 lbs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSue is 17, weighs 130 lbs, and is 5'1\".\r\nCarol is 15, weighs 110 lbs, and is 5'6\".\r\nBob is 14, weighs 150 lbs, and is 5'3\".\n<|im_start|>answer\nSue is 17, weighs 130 lbs, and is 5'1\".\r\nCarol is 15, weighs 110 lbs, and is 5'6\".\r\nBob is 14, weighs 150 lbs, and is 5'3\".\n<|im_end|>" }, { "id": "#44742", "title": "After Square, But Before Cube", "fun": 2.21, "difficulty": 1.45, "author": "whsprec", "desc": "What is the smallest integer where the integer before it is a perfect square and the integer after it is a perfect cube?", "hint": "No hint available.", "answer": "26. The integer before 26 is 25 or 5 squared, and the next number is 27 or 3 cubed.", "category": "Math", "date": "06/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest integer where the integer before it is a perfect square and the integer after it is a perfect cube?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n26. The integer before 26 is 25 or 5 squared, and the next number is 27 or 3 cubed.\n<|im_start|>answer\n26. The integer before 26 is 25 or 5 squared, and the next number is 27 or 3 cubed.\n<|im_end|>" }, { "id": "#4001", "title": "Corked Bottle", "fun": 2.21, "difficulty": 1.3800000000000001, "author": "mad-ade", "desc": "A bottle with a cork costs £25. The bottle on its own costs £20 more than the cork. How much does each item cost?", "hint": "No hint available.", "answer": "Bottle £22.50\r\ncork £2.50", "category": "Math", "date": "05/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bottle with a cork costs £25. The bottle on its own costs £20 more than the cork. How much does each item cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBottle £22.50\r\ncork £2.50\n<|im_start|>answer\nBottle £22.50\r\ncork £2.50\n<|im_end|>" }, { "id": "#3433", "title": "Yes or No", "fun": 2.21, "difficulty": 2.35, "author": "Drunky", "desc": "The answer I give is yes, but what I mean is no.\r\nWhat was the question?", "hint": "No hint available.", "answer": "Do you mind?", "category": "Logic", "date": "04/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe answer I give is yes, but what I mean is no.\r\nWhat was the question?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDo you mind?\n<|im_start|>answer\nDo you mind?\n<|im_end|>" }, { "id": "#8531", "title": "Number Relatives", "fun": 2.21, "difficulty": 2.25, "author": "lesternoronha1", "desc": "Lester gives his friend Terrance a problem. He has to find 2 three-digit numbers which should satisfy the following conditions:\n\r\nThere are two numbers x and y with xsystem\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLester gives his friend Terrance a problem. He has to find 2 three-digit numbers which should satisfy the following conditions:\n\r\nThere are two numbers x and y with x\n<|im_start|>assistant\n<|im_start|>think\nThere are two possible answers. Terrance calculates the numbers to be either: 137 and 265, or 269 and 387.\n<|im_start|>answer\nThere are two possible answers. Terrance calculates the numbers to be either: 137 and 265, or 269 and 387.\n<|im_end|>" }, { "id": "#32767", "title": "Painting the Faculty Room", "fun": 2.21, "difficulty": 2.35, "author": "moonsliver86", "desc": "The Math Department wanted to surprise Dean TJ by painting the Faculty Room pink. \n\r\nIt is known that Prof. Jaime, the Geometry teacher, and Prof. Basil, the Algebra teacher, can paint the room in 12 days. \n\r\nOn the other hand, Prof. Wilhelm, the Calculus teacher, and Prof. Nichel, the Trigonometry teacher, can paint the room in 16 days. \n\r\nIf Jaime and Wilhelm can finish painting the room in only 8 days, how long will it take Nichel and Basil to finish painting the room?", "hint": "Nichel and Basil don't like each other very much.", "answer": "Let us first set our variables:\n\r\nJ - Jaime's rate\r\nB - Basil's rate\r\nW - Wilhelm's rate\r\nN - Nichel's rate\n\r\nWe are given that:\r\n(1) J + B = 1/12\r\n(2) W + N = 1/16\r\n(3) J + W = 1/8\n\r\nWe are asked to look for B+N.\n\r\nNote that: \n\r\nJ+B+W+N=J+W+B+N\r\n(J+B)+(W+N)=(J+W)+(B+N)\r\n1/12 + 1/16 = 1/8 + (B+N)\r\n(B+N) = 1/48\n\r\nTherefore, it would take Nichel and Basil 48 days to finish painting the room.", "category": "Math", "date": "08/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Math Department wanted to surprise Dean TJ by painting the Faculty Room pink. \n\r\nIt is known that Prof. Jaime, the Geometry teacher, and Prof. Basil, the Algebra teacher, can paint the room in 12 days. \n\r\nOn the other hand, Prof. Wilhelm, the Calculus teacher, and Prof. Nichel, the Trigonometry teacher, can paint the room in 16 days. \n\r\nIf Jaime and Wilhelm can finish painting the room in only 8 days, how long will it take Nichel and Basil to finish painting the room?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet us first set our variables:\n\r\nJ - Jaime's rate\r\nB - Basil's rate\r\nW - Wilhelm's rate\r\nN - Nichel's rate\n\r\nWe are given that:\r\n(1) J + B = 1/12\r\n(2) W + N = 1/16\r\n(3) J + W = 1/8\n\r\nWe are asked to look for B+N.\n\r\nNote that: \n\r\nJ+B+W+N=J+W+B+N\r\n(J+B)+(W+N)=(J+W)+(B+N)\r\n1/12 + 1/16 = 1/8 + (B+N)\r\n(B+N) = 1/48\n\r\nTherefore, it would take Nichel and Basil 48 days to finish painting the room.\n<|im_start|>answer\nLet us first set our variables:\n\r\nJ - Jaime's rate\r\nB - Basil's rate\r\nW - Wilhelm's rate\r\nN - Nichel's rate\n\r\nWe are given that:\r\n(1) J + B = 1/12\r\n(2) W + N = 1/16\r\n(3) J + W = 1/8\n\r\nWe are asked to look for B+N.\n\r\nNote that: \n\r\nJ+B+W+N=J+W+B+N\r\n(J+B)+(W+N)=(J+W)+(B+N)\r\n1/12 + 1/16 = 1/8 + (B+N)\r\n(B+N) = 1/48\n\r\nTherefore, it would take Nichel and Basil 48 days to finish painting the room.\n<|im_end|>" }, { "id": "#12638", "title": "Kebab Shop Line Up", "fun": 2.21, "difficulty": 2.84, "author": "mad-ade", "desc": "There had been a break in at the \"Sweaty Chef\" Kebab shop, and the new owner, Mustapha Bettaname, had been robbed of his secret kebab recipe. The police had one eye witness, Al Kaholic, the local wino and world champion turps nudger. \n\r\nA Police line up of 11 suspects was made to stand in a straight line to have an Identity Parade. The main culprit was asked to stand in the center of the line-up. \n\r\n1) Barb Dwyre and Chris Mass stood to the right of the main culprit \r\n2) Two suspects stood between Ewan Watarmy and Lou Stooth \r\n3) Seven suspects stood between Mike Rhosopht and Phil Mypokits \r\n4) Gerry Atrick stood to the right of Hugo Phurst \r\n5) Robin Banks and Polly Ester-Phants stood either side of Ewan Watarmy \r\n6) Diddy Dewit and Polly Ester-Phants stood to the left of the main culprit \r\n7) Six suspects stood between Chris Mass and Ewan Watarmy \r\n8) Two suspects stood between Ewan Watarmy and Diddy Dewit \n\r\nWho is the main culprit? \n\r\nCan you tell the positions of all the suspects?", "hint": "No hint available.", "answer": "Suspects from left to right: Diddy Dewit, (Mike Rhosopht/Phil Mypokits), (Robin Banks/Polly Ester-Phants), Ewan Watarmy, (Robin Banks/Polly Ester-Phants), HUGO PHURST, Lou Stooth, (Barb Dwyre/Gerry Atrick), (Barb Dwyre/Gerry Atrick), (Mike Rhosopht/Phil Mypokits), Chris Mass \n\r\nLet's number the positions 1 to 11 from left to right. Hence, the main culprit is at position 6. Now, looking at the clues 7, 5, 2 and 8 together: \r\nPosition 1 - Diddy Dewit or Lou Stooth \r\nPosition 3 - Polly Ester-Phants or Robin Banks \r\nPosition 4 - Ewan Watarmy \r\nPosition 5 - Polly Ester-Phants or Robin Banks \r\nPosition 7 - Diddy Dewit or Lou Stooth \r\nPosition 11 - Chris Mass \n\r\nFrom clue (3), the only possible positions for Mike Rhosopht and Phil Mypokits are Position 2 and Position 10. \n\r\nNow there are 3 positions remaining - 6, 8 and 9 and remaining 3 suspects are Hugo Phurst, Barb Dwyre and Gerry Atrick. But from clue (1), Barb Dwyre stood to the right of the main culprit i.e. Barb Dwyre must be on position 8 or 9 as position 6 is for the main culprit. So either Hugo Phurst or Gerry Atrick is the main culprit. \n\r\nFrom (4), Gerry Atrick stood to the right of Hugo Phurst. Hence, Hugo Phurst is the main culprit. \n\r\nSuspects from left to right are: Diddy Dewit, (Mike Rhosopht/Phil Mypokits), (Robin Banks/Polly Ester-Phants), Ewan Watarmy, (Robin Banks/Polly Ester-Phants), HUGO PHURST, Lou Stooth, (Barb Dwyre/Gerry Atrick), (Barb Dwyre/Gerry Atrick), (Mike Rhosopht/Phil Mypokits), Chris Mass. \n\r\nThus, \r\nDiddy Dewit (1), Ewan Watarmy (4), Hugo Phurst (6), Lou Stooth (7) and Chris Mass (11) are the suspects whose positions are fixed. \n\r\nMike Rhosopht and Phil Mypokits are at position 2 or 10. \n\r\nRobin Banks and Polly Ester-Phants are at position 3 or 5. \n\r\nBarb Dwyre and Gerry Atrick are at position 8 or 9.", "category": "Logic", "date": "05/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere had been a break in at the \"Sweaty Chef\" Kebab shop, and the new owner, Mustapha Bettaname, had been robbed of his secret kebab recipe. The police had one eye witness, Al Kaholic, the local wino and world champion turps nudger. \n\r\nA Police line up of 11 suspects was made to stand in a straight line to have an Identity Parade. The main culprit was asked to stand in the center of the line-up. \n\r\n1) Barb Dwyre and Chris Mass stood to the right of the main culprit \r\n2) Two suspects stood between Ewan Watarmy and Lou Stooth \r\n3) Seven suspects stood between Mike Rhosopht and Phil Mypokits \r\n4) Gerry Atrick stood to the right of Hugo Phurst \r\n5) Robin Banks and Polly Ester-Phants stood either side of Ewan Watarmy \r\n6) Diddy Dewit and Polly Ester-Phants stood to the left of the main culprit \r\n7) Six suspects stood between Chris Mass and Ewan Watarmy \r\n8) Two suspects stood between Ewan Watarmy and Diddy Dewit \n\r\nWho is the main culprit? \n\r\nCan you tell the positions of all the suspects?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSuspects from left to right: Diddy Dewit, (Mike Rhosopht/Phil Mypokits), (Robin Banks/Polly Ester-Phants), Ewan Watarmy, (Robin Banks/Polly Ester-Phants), HUGO PHURST, Lou Stooth, (Barb Dwyre/Gerry Atrick), (Barb Dwyre/Gerry Atrick), (Mike Rhosopht/Phil Mypokits), Chris Mass \n\r\nLet's number the positions 1 to 11 from left to right. Hence, the main culprit is at position 6. Now, looking at the clues 7, 5, 2 and 8 together: \r\nPosition 1 - Diddy Dewit or Lou Stooth \r\nPosition 3 - Polly Ester-Phants or Robin Banks \r\nPosition 4 - Ewan Watarmy \r\nPosition 5 - Polly Ester-Phants or Robin Banks \r\nPosition 7 - Diddy Dewit or Lou Stooth \r\nPosition 11 - Chris Mass \n\r\nFrom clue (3), the only possible positions for Mike Rhosopht and Phil Mypokits are Position 2 and Position 10. \n\r\nNow there are 3 positions remaining - 6, 8 and 9 and remaining 3 suspects are Hugo Phurst, Barb Dwyre and Gerry Atrick. But from clue (1), Barb Dwyre stood to the right of the main culprit i.e. Barb Dwyre must be on position 8 or 9 as position 6 is for the main culprit. So either Hugo Phurst or Gerry Atrick is the main culprit. \n\r\nFrom (4), Gerry Atrick stood to the right of Hugo Phurst. Hence, Hugo Phurst is the main culprit. \n\r\nSuspects from left to right are: Diddy Dewit, (Mike Rhosopht/Phil Mypokits), (Robin Banks/Polly Ester-Phants), Ewan Watarmy, (Robin Banks/Polly Ester-Phants), HUGO PHURST, Lou Stooth, (Barb Dwyre/Gerry Atrick), (Barb Dwyre/Gerry Atrick), (Mike Rhosopht/Phil Mypokits), Chris Mass. \n\r\nThus, \r\nDiddy Dewit (1), Ewan Watarmy (4), Hugo Phurst (6), Lou Stooth (7) and Chris Mass (11) are the suspects whose positions are fixed. \n\r\nMike Rhosopht and Phil Mypokits are at position 2 or 10. \n\r\nRobin Banks and Polly Ester-Phants are at position 3 or 5. \n\r\nBarb Dwyre and Gerry Atrick are at position 8 or 9.\n<|im_start|>answer\nSuspects from left to right: Diddy Dewit, (Mike Rhosopht/Phil Mypokits), (Robin Banks/Polly Ester-Phants), Ewan Watarmy, (Robin Banks/Polly Ester-Phants), HUGO PHURST, Lou Stooth, (Barb Dwyre/Gerry Atrick), (Barb Dwyre/Gerry Atrick), (Mike Rhosopht/Phil Mypokits), Chris Mass \n\r\nLet's number the positions 1 to 11 from left to right. Hence, the main culprit is at position 6. Now, looking at the clues 7, 5, 2 and 8 together: \r\nPosition 1 - Diddy Dewit or Lou Stooth \r\nPosition 3 - Polly Ester-Phants or Robin Banks \r\nPosition 4 - Ewan Watarmy \r\nPosition 5 - Polly Ester-Phants or Robin Banks \r\nPosition 7 - Diddy Dewit or Lou Stooth \r\nPosition 11 - Chris Mass \n\r\nFrom clue (3), the only possible positions for Mike Rhosopht and Phil Mypokits are Position 2 and Position 10. \n\r\nNow there are 3 positions remaining - 6, 8 and 9 and remaining 3 suspects are Hugo Phurst, Barb Dwyre and Gerry Atrick. But from clue (1), Barb Dwyre stood to the right of the main culprit i.e. Barb Dwyre must be on position 8 or 9 as position 6 is for the main culprit. So either Hugo Phurst or Gerry Atrick is the main culprit. \n\r\nFrom (4), Gerry Atrick stood to the right of Hugo Phurst. Hence, Hugo Phurst is the main culprit. \n\r\nSuspects from left to right are: Diddy Dewit, (Mike Rhosopht/Phil Mypokits), (Robin Banks/Polly Ester-Phants), Ewan Watarmy, (Robin Banks/Polly Ester-Phants), HUGO PHURST, Lou Stooth, (Barb Dwyre/Gerry Atrick), (Barb Dwyre/Gerry Atrick), (Mike Rhosopht/Phil Mypokits), Chris Mass. \n\r\nThus, \r\nDiddy Dewit (1), Ewan Watarmy (4), Hugo Phurst (6), Lou Stooth (7) and Chris Mass (11) are the suspects whose positions are fixed. \n\r\nMike Rhosopht and Phil Mypokits are at position 2 or 10. \n\r\nRobin Banks and Polly Ester-Phants are at position 3 or 5. \n\r\nBarb Dwyre and Gerry Atrick are at position 8 or 9.\n<|im_end|>" }, { "id": "#4759", "title": "Attic Clearance", "fun": 2.21, "difficulty": 1.79, "author": "mad-ade", "desc": "Mad Ade was clearing some junk from his attic to make room for his used Pizza box collection. Whilst cleaning he came across several insects and spiders. Altogether Mad Ade counted a total of 48 legs, how many insects and how many spiders were in the Attic?", "hint": "No hint available.", "answer": "Four insects (24 legs) and three spiders (24 legs). No other combination will work.", "category": "Math", "date": "06/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was clearing some junk from his attic to make room for his used Pizza box collection. Whilst cleaning he came across several insects and spiders. Altogether Mad Ade counted a total of 48 legs, how many insects and how many spiders were in the Attic?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFour insects (24 legs) and three spiders (24 legs). No other combination will work.\n<|im_start|>answer\nFour insects (24 legs) and three spiders (24 legs). No other combination will work.\n<|im_end|>" }, { "id": "#979", "title": "Dumplings", "fun": 2.21, "difficulty": 1.71, "author": "Michelle", "desc": "Kerry loves dumplings. He can eat 32 of them in an hour. His brother Pete needs 3 hours to eat the same amount. How long will it take them both together to eat 32 dumplings?", "hint": "No hint available.", "answer": "If Kerry eats 3 times as fast as Pete, he must be able to eat 3 times as many dumplings as his brother. Therefore, Kerry eats 24 while Pete eats 8 ( 32 / 4 = 8 ). Together it takes them 45 minutes.", "category": "Math", "date": "10/04/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKerry loves dumplings. He can eat 32 of them in an hour. His brother Pete needs 3 hours to eat the same amount. How long will it take them both together to eat 32 dumplings?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf Kerry eats 3 times as fast as Pete, he must be able to eat 3 times as many dumplings as his brother. Therefore, Kerry eats 24 while Pete eats 8 ( 32 / 4 = 8 ). Together it takes them 45 minutes.\n<|im_start|>answer\nIf Kerry eats 3 times as fast as Pete, he must be able to eat 3 times as many dumplings as his brother. Therefore, Kerry eats 24 while Pete eats 8 ( 32 / 4 = 8 ). Together it takes them 45 minutes.\n<|im_end|>" }, { "id": "#19173", "title": "PIN the PIN !!!", "fun": 2.21, "difficulty": 2.13, "author": "lesternoronha1", "desc": "Akash was trying to remember the PIN of his credit card. The PIN consisted of four characters, three of which were digits from 0 to 9 and one of which was a letter of the alphabet. If Akash can try different possibilities at the rate of 5 possibilities per minute and he works for 8 hours a day everyday, then find out the number of days in which he can try out all the combinations possible for the PIN.", "hint": "No hint available.", "answer": "The number of days required to try all the combinations is 43 1/3 days.\n\r\nThe four character code consists of 3 digits 0 to 9 and 1 letter of the alphabet A to Z.\n\r\nLet us assume the first character of the PIN to be an alphabet and the remaining three characters to be digits.\n\r\nThen the number of possible PINs \r\n= 26*10*10*10\n\r\nThis is the number of PINs with the first character of the PIN being an alphabet.\n\r\nHowever we can have the alphabet as the second character, third character or fourth character of the PIN. Thus there are four different combinations.\n\r\nHence the total number of such four character PINS available \r\n= 4*26*10*10*10 = 104000.\n\r\nAt the rate of 5 possibilities, taking 8 hours a day, Akash would take\r\n104000/(5*60*8) = \r\n104000/(300*8) = 43 1/3 days.", "category": "Math", "date": "10/19/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAkash was trying to remember the PIN of his credit card. The PIN consisted of four characters, three of which were digits from 0 to 9 and one of which was a letter of the alphabet. If Akash can try different possibilities at the rate of 5 possibilities per minute and he works for 8 hours a day everyday, then find out the number of days in which he can try out all the combinations possible for the PIN.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number of days required to try all the combinations is 43 1/3 days.\n\r\nThe four character code consists of 3 digits 0 to 9 and 1 letter of the alphabet A to Z.\n\r\nLet us assume the first character of the PIN to be an alphabet and the remaining three characters to be digits.\n\r\nThen the number of possible PINs \r\n= 26*10*10*10\n\r\nThis is the number of PINs with the first character of the PIN being an alphabet.\n\r\nHowever we can have the alphabet as the second character, third character or fourth character of the PIN. Thus there are four different combinations.\n\r\nHence the total number of such four character PINS available \r\n= 4*26*10*10*10 = 104000.\n\r\nAt the rate of 5 possibilities, taking 8 hours a day, Akash would take\r\n104000/(5*60*8) = \r\n104000/(300*8) = 43 1/3 days.\n<|im_start|>answer\nThe number of days required to try all the combinations is 43 1/3 days.\n\r\nThe four character code consists of 3 digits 0 to 9 and 1 letter of the alphabet A to Z.\n\r\nLet us assume the first character of the PIN to be an alphabet and the remaining three characters to be digits.\n\r\nThen the number of possible PINs \r\n= 26*10*10*10\n\r\nThis is the number of PINs with the first character of the PIN being an alphabet.\n\r\nHowever we can have the alphabet as the second character, third character or fourth character of the PIN. Thus there are four different combinations.\n\r\nHence the total number of such four character PINS available \r\n= 4*26*10*10*10 = 104000.\n\r\nAt the rate of 5 possibilities, taking 8 hours a day, Akash would take\r\n104000/(5*60*8) = \r\n104000/(300*8) = 43 1/3 days.\n<|im_end|>" }, { "id": "#8889", "title": "Pizza Pieces", "fun": 2.21, "difficulty": 2.8, "author": "lesternoronha1", "desc": "What is the largest number of pieces you can form with n straight cuts of a pizza?\n\r\nThe pieces do not need to be of equal size.", "hint": "No hint available.", "answer": "The answer is n*(n+1)/2 + 1.\r\nWith every cut you should cut through every previous cut. As long as you keep doing this you will always be able to do so again with your next cut. The number of additional pieces formed on cut x will always be x. The sum of all integers from 1 to n is n*(n+1)/2. So the sum of additional pieces cut will be n*(n+1)/2. \r\nFinally add 1 because we start with 1 piece: n*(n+1)/2 + 1.", "category": "Math", "date": "12/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the largest number of pieces you can form with n straight cuts of a pizza?\n\r\nThe pieces do not need to be of equal size.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is n*(n+1)/2 + 1.\r\nWith every cut you should cut through every previous cut. As long as you keep doing this you will always be able to do so again with your next cut. The number of additional pieces formed on cut x will always be x. The sum of all integers from 1 to n is n*(n+1)/2. So the sum of additional pieces cut will be n*(n+1)/2. \r\nFinally add 1 because we start with 1 piece: n*(n+1)/2 + 1.\n<|im_start|>answer\nThe answer is n*(n+1)/2 + 1.\r\nWith every cut you should cut through every previous cut. As long as you keep doing this you will always be able to do so again with your next cut. The number of additional pieces formed on cut x will always be x. The sum of all integers from 1 to n is n*(n+1)/2. So the sum of additional pieces cut will be n*(n+1)/2. \r\nFinally add 1 because we start with 1 piece: n*(n+1)/2 + 1.\n<|im_end|>" }, { "id": "#8717", "title": "Food Scarcity", "fun": 2.21, "difficulty": 2.27, "author": "lesternoronha1", "desc": "A garrison of 3300 men had provisions for 32 days, when given at the rate of 850 gms. per head. At the end of 7 days, a reinforcement arrives and it is found that the provisions will last 17 days more, when given at the rate of 825 gms. per head. \r\nWhat is the strength of the reinforcement?", "hint": "No hint available.", "answer": "Strength of reinforcement = 1700. Hence total men = 5000.\n\r\nThe key equation is:\r\n(# of men) x (food per man) * (# of days) = (food consumed in the given time)\n\r\nFirst figure out the initial amount of food:\r\n3300 men x 850 g/man x 32 days = 89760000 grams\n\r\nFood used after 7 days:\r\n3300 men x 850 g/man x 7 days = 1963500 grams\n\r\nFood remaining after 7 days:\r\n89760000 - 1963500 = 70125000 grams\n\r\nNow you know everything but the number of men present for the last 17 days. Just use the same equation to figure it out:\r\n(# of men) x 825 g/man x 17 days = 70125000 grams\n\r\nSolve for the number of men to get 5000. This means that 5000 - 3300 = 1700 men were provided with the reinforcement.", "category": "Math", "date": "11/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA garrison of 3300 men had provisions for 32 days, when given at the rate of 850 gms. per head. At the end of 7 days, a reinforcement arrives and it is found that the provisions will last 17 days more, when given at the rate of 825 gms. per head. \r\nWhat is the strength of the reinforcement?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStrength of reinforcement = 1700. Hence total men = 5000.\n\r\nThe key equation is:\r\n(# of men) x (food per man) * (# of days) = (food consumed in the given time)\n\r\nFirst figure out the initial amount of food:\r\n3300 men x 850 g/man x 32 days = 89760000 grams\n\r\nFood used after 7 days:\r\n3300 men x 850 g/man x 7 days = 1963500 grams\n\r\nFood remaining after 7 days:\r\n89760000 - 1963500 = 70125000 grams\n\r\nNow you know everything but the number of men present for the last 17 days. Just use the same equation to figure it out:\r\n(# of men) x 825 g/man x 17 days = 70125000 grams\n\r\nSolve for the number of men to get 5000. This means that 5000 - 3300 = 1700 men were provided with the reinforcement.\n<|im_start|>answer\nStrength of reinforcement = 1700. Hence total men = 5000.\n\r\nThe key equation is:\r\n(# of men) x (food per man) * (# of days) = (food consumed in the given time)\n\r\nFirst figure out the initial amount of food:\r\n3300 men x 850 g/man x 32 days = 89760000 grams\n\r\nFood used after 7 days:\r\n3300 men x 850 g/man x 7 days = 1963500 grams\n\r\nFood remaining after 7 days:\r\n89760000 - 1963500 = 70125000 grams\n\r\nNow you know everything but the number of men present for the last 17 days. Just use the same equation to figure it out:\r\n(# of men) x 825 g/man x 17 days = 70125000 grams\n\r\nSolve for the number of men to get 5000. This means that 5000 - 3300 = 1700 men were provided with the reinforcement.\n<|im_end|>" }, { "id": "#19080", "title": "Bike-Mania", "fun": 2.21, "difficulty": 2.14, "author": "lesternoronha1", "desc": "A motorcycle workshop owner had dismantled some motorcycles, so as to get three varieties of brakes - B1, B2 and B3, four varieties of Engines - SL, SK, EZ and RX, and three varieties of tires - MRF, BS and MCN. It was further known that B1 cannot be with SL or SK. EZ must be with B3. MRF must be with SL and vice versa. MCN or BS cannot be with SK. If B2 brakes are to be fitted, then which of the following must also be used?\n\r\n1) SK engine and MCN tyres.\r\n2) MCN tyres and SK engine or RX engine.\r\n3) SL engine and MRF tyres.\r\n4) None of these.", "hint": "No hint available.", "answer": "If B2 brakes are to be fitted, statement 3 i.e., SL engine and MRF tires must also be used.\n\r\nThe given choices to be used along with B2 brakes are\r\n1) SK engine and MCN tires.\r\n2) MCN tires and SK engine or RX engine.\r\n3) SL engine and MRF tires.\r\n4) None of these.\n\r\nThe given observations are\r\nA) B1 cannot be with SL or SK.\r\nB) EZ must be with B3.\r\nC) MRF must be with SL and vice versa.\r\nD) MCN or BS cannot be with SK.\n\r\nFrom observation A, brake B1 must be with engines EZ or RX (since it cannot be with SL or SK). But from observation B, engine EZ must be with B3. Hence brake B1 must be with RX.\n\r\nThus B2 must be with either engine SL or engine SK. If engine SK is selected, we cannot use either of tires MCN or BS from observation D. MRF tires cannot be used with SK engine because MRF must be with SL and vice versa from observation C.\n\r\nTherefore if brake B2 is used, engine SL along with tires MRF must be used.", "category": "Logic", "date": "10/13/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA motorcycle workshop owner had dismantled some motorcycles, so as to get three varieties of brakes - B1, B2 and B3, four varieties of Engines - SL, SK, EZ and RX, and three varieties of tires - MRF, BS and MCN. It was further known that B1 cannot be with SL or SK. EZ must be with B3. MRF must be with SL and vice versa. MCN or BS cannot be with SK. If B2 brakes are to be fitted, then which of the following must also be used?\n\r\n1) SK engine and MCN tyres.\r\n2) MCN tyres and SK engine or RX engine.\r\n3) SL engine and MRF tyres.\r\n4) None of these.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf B2 brakes are to be fitted, statement 3 i.e., SL engine and MRF tires must also be used.\n\r\nThe given choices to be used along with B2 brakes are\r\n1) SK engine and MCN tires.\r\n2) MCN tires and SK engine or RX engine.\r\n3) SL engine and MRF tires.\r\n4) None of these.\n\r\nThe given observations are\r\nA) B1 cannot be with SL or SK.\r\nB) EZ must be with B3.\r\nC) MRF must be with SL and vice versa.\r\nD) MCN or BS cannot be with SK.\n\r\nFrom observation A, brake B1 must be with engines EZ or RX (since it cannot be with SL or SK). But from observation B, engine EZ must be with B3. Hence brake B1 must be with RX.\n\r\nThus B2 must be with either engine SL or engine SK. If engine SK is selected, we cannot use either of tires MCN or BS from observation D. MRF tires cannot be used with SK engine because MRF must be with SL and vice versa from observation C.\n\r\nTherefore if brake B2 is used, engine SL along with tires MRF must be used.\n<|im_start|>answer\nIf B2 brakes are to be fitted, statement 3 i.e., SL engine and MRF tires must also be used.\n\r\nThe given choices to be used along with B2 brakes are\r\n1) SK engine and MCN tires.\r\n2) MCN tires and SK engine or RX engine.\r\n3) SL engine and MRF tires.\r\n4) None of these.\n\r\nThe given observations are\r\nA) B1 cannot be with SL or SK.\r\nB) EZ must be with B3.\r\nC) MRF must be with SL and vice versa.\r\nD) MCN or BS cannot be with SK.\n\r\nFrom observation A, brake B1 must be with engines EZ or RX (since it cannot be with SL or SK). But from observation B, engine EZ must be with B3. Hence brake B1 must be with RX.\n\r\nThus B2 must be with either engine SL or engine SK. If engine SK is selected, we cannot use either of tires MCN or BS from observation D. MRF tires cannot be used with SK engine because MRF must be with SL and vice versa from observation C.\n\r\nTherefore if brake B2 is used, engine SL along with tires MRF must be used.\n<|im_end|>" }, { "id": "#5352", "title": "Adecyclopaedia", "fun": 2.21, "difficulty": 1.6, "author": "mad-ade", "desc": "Mad Ade recently bought a 10-volume set of encyclopaedias.\r\nAt present he has only arranged the first 9 volumes in order on his shelf, as shown below.\n\r\n8,5,4,9,1,7,6,3,2\n\r\nUsing Mad Ade's system, where should Volume 10 go?", "hint": "No hint available.", "answer": "Between 6 and 3, they are arranged alphabetically", "category": "Logic", "date": "07/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade recently bought a 10-volume set of encyclopaedias.\r\nAt present he has only arranged the first 9 volumes in order on his shelf, as shown below.\n\r\n8,5,4,9,1,7,6,3,2\n\r\nUsing Mad Ade's system, where should Volume 10 go?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBetween 6 and 3, they are arranged alphabetically\n<|im_start|>answer\nBetween 6 and 3, they are arranged alphabetically\n<|im_end|>" }, { "id": "#8668", "title": "Square's Area", "fun": 2.21, "difficulty": 1.67, "author": "glennyboy02", "desc": "A square has the area of (x+y) squared. What is the perimeter of this square?", "hint": "No hint available.", "answer": "A square has four EQUAL sides. So the area of a square is A x A. \r\nOr x + y. Thus making one side = x + y\r\n4 times x + y = 4(x+y)\r\nPERIMETER = 4(x+y)", "category": "Math", "date": "11/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA square has the area of (x+y) squared. What is the perimeter of this square?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA square has four EQUAL sides. So the area of a square is A x A. \r\nOr x + y. Thus making one side = x + y\r\n4 times x + y = 4(x+y)\r\nPERIMETER = 4(x+y)\n<|im_start|>answer\nA square has four EQUAL sides. So the area of a square is A x A. \r\nOr x + y. Thus making one side = x + y\r\n4 times x + y = 4(x+y)\r\nPERIMETER = 4(x+y)\n<|im_end|>" }, { "id": "#13932", "title": "Lying Thieves", "fun": 2.21, "difficulty": 2.02, "author": "cool_star", "desc": "A priceless jewel was stolen from a museum. The suspicion was placed on three people: Joe, George, and Sam. \n\r\nAt their trial, Joe claimed that George was innocent, while George claimed that Sam was innocent and Sam mumbled something that no one understood. \n\r\nIf an innocent person always tells the truth, and a guilty person always lies, which of the three suspects is guilty, if only one person committed this crime?", "hint": "No hint available.", "answer": "None of the three suspects are guilty. \n\r\nIf Joe was guilty, it would mean that he was lying when he said that George was innocent and George would be guilty too, which cannot happen. If George was guilty, it would mean that Sam was guilty too, because George said that Sam was innocent. If Sam was guilty, it would mean that George was guilty too, because he claimed that Sam was innocent. Therefore none of the three suspects were guilty.", "category": "Logic", "date": "07/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA priceless jewel was stolen from a museum. The suspicion was placed on three people: Joe, George, and Sam. \n\r\nAt their trial, Joe claimed that George was innocent, while George claimed that Sam was innocent and Sam mumbled something that no one understood. \n\r\nIf an innocent person always tells the truth, and a guilty person always lies, which of the three suspects is guilty, if only one person committed this crime?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNone of the three suspects are guilty. \n\r\nIf Joe was guilty, it would mean that he was lying when he said that George was innocent and George would be guilty too, which cannot happen. If George was guilty, it would mean that Sam was guilty too, because George said that Sam was innocent. If Sam was guilty, it would mean that George was guilty too, because he claimed that Sam was innocent. Therefore none of the three suspects were guilty.\n<|im_start|>answer\nNone of the three suspects are guilty. \n\r\nIf Joe was guilty, it would mean that he was lying when he said that George was innocent and George would be guilty too, which cannot happen. If George was guilty, it would mean that Sam was guilty too, because George said that Sam was innocent. If Sam was guilty, it would mean that George was guilty too, because he claimed that Sam was innocent. Therefore none of the three suspects were guilty.\n<|im_end|>" }, { "id": "#1426", "title": "Square Root of 2", "fun": 2.21, "difficulty": 2.84, "author": "mrice", "desc": "An iterative equation is one where an initial value is put into the equation to obtain a result, which is in turn put back into the equation as an input and the process is repeated for either a fixed number of times or until a final value is achieved (where you get the same number out as you put in). \n\r\nFor example, if you start with the iterative equation,\n\r\nA{n+1} = 1/A{n} + 1\n\r\nAnd you put in an initial value of 1, you would get 2 as the result. Put the 2 back in as the input and you would get 1.5, and so on.\n\r\nThere is a simple iterative equation which, when repeated just five times, will give you a very good approximation of the square root of two (accurate to three decimal places, or less than 0.1%). What's more, you can put in any positive (and almost any negative) initial value into the equation (even zero) and you will end up at the same answer. This equation does not contain any square root expressions; just single-order algebra. Can you figure it out?", "hint": "The only mathematical operators you need are addition and division. Try beginning with the expression:\n\r\nA^2 = 2\n\r\nAnd keep in mind that this equation converges on a value. Don't give up!", "answer": "A{n+1} = (A{n} + 2) / (A{n} + 1}\n\r\nTo prove to yourself that this is right, assume that for a sufficiently large number of iterations, A{n+1} = A{n}, so you can rewrite the equation as:\n\r\nA(A+1) = A + 2\n\r\n... A^2 + A = A + 2\r\n... A^2 = 2\r\n... A = SQRT(2) !", "category": "Math", "date": "11/16/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn iterative equation is one where an initial value is put into the equation to obtain a result, which is in turn put back into the equation as an input and the process is repeated for either a fixed number of times or until a final value is achieved (where you get the same number out as you put in). \n\r\nFor example, if you start with the iterative equation,\n\r\nA{n+1} = 1/A{n} + 1\n\r\nAnd you put in an initial value of 1, you would get 2 as the result. Put the 2 back in as the input and you would get 1.5, and so on.\n\r\nThere is a simple iterative equation which, when repeated just five times, will give you a very good approximation of the square root of two (accurate to three decimal places, or less than 0.1%). What's more, you can put in any positive (and almost any negative) initial value into the equation (even zero) and you will end up at the same answer. This equation does not contain any square root expressions; just single-order algebra. Can you figure it out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA{n+1} = (A{n} + 2) / (A{n} + 1}\n\r\nTo prove to yourself that this is right, assume that for a sufficiently large number of iterations, A{n+1} = A{n}, so you can rewrite the equation as:\n\r\nA(A+1) = A + 2\n\r\n... A^2 + A = A + 2\r\n... A^2 = 2\r\n... A = SQRT(2) !\n<|im_start|>answer\nA{n+1} = (A{n} + 2) / (A{n} + 1}\n\r\nTo prove to yourself that this is right, assume that for a sufficiently large number of iterations, A{n+1} = A{n}, so you can rewrite the equation as:\n\r\nA(A+1) = A + 2\n\r\n... A^2 + A = A + 2\r\n... A^2 = 2\r\n... A = SQRT(2) !\n<|im_end|>" }, { "id": "#2409", "title": "Man in the Winter", "fun": 2.21, "difficulty": 1.2, "author": "ka_ado7", "desc": "One winter day, there was a man standing in the middle of someone's front yard. The person stayed there for several weeks without moving and the owner of the yard didn't mind. Eventually the man left.\n\r\nWho was the man?", "hint": "You can make them in winter.", "answer": "A snowman.", "category": "Logic", "date": "02/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne winter day, there was a man standing in the middle of someone's front yard. The person stayed there for several weeks without moving and the owner of the yard didn't mind. Eventually the man left.\n\r\nWho was the man?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA snowman.\n<|im_start|>answer\nA snowman.\n<|im_end|>" }, { "id": "#10818", "title": "Kebab Race", "fun": 2.21, "difficulty": 1.76, "author": "mad-ade", "desc": "Mad Ade and Rod Lightning decide to race each other to the \"Sweaty Chef Kebab Shop\", exactly one mile away, and then back again. \r\nMad Ade, being the Kebab lard-ladened beast he is, ran (more like staggered) at 10 miles per hour to the kebab shop, but managed a whopping 30 miles per hour back (down hill with a following tail wind). \r\nRod Lightning, on the other hand, being less kilogramically challenged than Mad Ade, ran at a constant 20 miles per hour each way. \r\nWho won the race?", "hint": "No hint available.", "answer": "Rod did, because at 20 mph, when he reached the \"Sweaty Chef\" Mad Ade (running at half the speed of Rod) was only half way there, and by the time Rod had run home again, Mad Ade would have just made it to his favourite kebab shop.", "category": "Math", "date": "03/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade and Rod Lightning decide to race each other to the \"Sweaty Chef Kebab Shop\", exactly one mile away, and then back again. \r\nMad Ade, being the Kebab lard-ladened beast he is, ran (more like staggered) at 10 miles per hour to the kebab shop, but managed a whopping 30 miles per hour back (down hill with a following tail wind). \r\nRod Lightning, on the other hand, being less kilogramically challenged than Mad Ade, ran at a constant 20 miles per hour each way. \r\nWho won the race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRod did, because at 20 mph, when he reached the \"Sweaty Chef\" Mad Ade (running at half the speed of Rod) was only half way there, and by the time Rod had run home again, Mad Ade would have just made it to his favourite kebab shop.\n<|im_start|>answer\nRod did, because at 20 mph, when he reached the \"Sweaty Chef\" Mad Ade (running at half the speed of Rod) was only half way there, and by the time Rod had run home again, Mad Ade would have just made it to his favourite kebab shop.\n<|im_end|>" }, { "id": "#1870", "title": "Bolt of Cloth", "fun": 2.21, "difficulty": 1.59, "author": "missie", "desc": "A bolt of cloth is colored as follows: one-third and one-quarter of it are black, the other 8 yards are gray. How long is the bolt?", "hint": "No hint available.", "answer": "19.2 yards", "category": "Math", "date": "12/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA bolt of cloth is colored as follows: one-third and one-quarter of it are black, the other 8 yards are gray. How long is the bolt?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19.2 yards\n<|im_start|>answer\n19.2 yards\n<|im_end|>" }, { "id": "#6277", "title": "OQLHR", "fun": 2.21, "difficulty": 2.43, "author": "mad-ade", "desc": "What would be the missing letter ?\n\r\nO Q L H R\r\nI J F E Q\r\n--------------\r\nF G F C ?", "hint": "No hint available.", "answer": "The missing letter is A.\n\r\nNumber the letters in order eg: A=1 B=2 C=3 etc.. then subtract the middle from the top, to give the bottom number. Assign that number to the appropriate letter to give the answer.", "category": "Logic", "date": "08/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat would be the missing letter ?\n\r\nO Q L H R\r\nI J F E Q\r\n--------------\r\nF G F C ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe missing letter is A.\n\r\nNumber the letters in order eg: A=1 B=2 C=3 etc.. then subtract the middle from the top, to give the bottom number. Assign that number to the appropriate letter to give the answer.\n<|im_start|>answer\nThe missing letter is A.\n\r\nNumber the letters in order eg: A=1 B=2 C=3 etc.. then subtract the middle from the top, to give the bottom number. Assign that number to the appropriate letter to give the answer.\n<|im_end|>" }, { "id": "#4195", "title": "Undiscovered Planet", "fun": 2.21, "difficulty": 2.78, "author": "cathalmccabe", "desc": "You land on an unknown planet which has a radius of 10km and is completely round and smooth. You start from your ship and walk straight for 17.345 kilometers. You turn left and walk straight for 47.124 kilometers. How far are you from your ship?", "hint": "No hint available.", "answer": "14.142135623730950488016887242097\r\nOr square root of 200!\r\nIf you imagine you are facing a globe head on, you have the north pole at the top of the globe and the south pole at the bottom. Imagine a \"west pole\" and \"east pole\" to the left and right of the globe.\r\nIf you are at the north pole and turn left, you will walk through the \"west pole\" (right and you go through the \"east pole\")\r\nIf you walk on an axis from the north pole towards the south pole and make a left or right turn you will always walk through these imaginary east and west poles. So in the question 17.345 kilometers is irrelevant, only the turn. \r\n(It also doesn't matter where you start on the planet, the distance at the end will still be the same.)\r\n47.124 is approximately 3/4 of the circumference of this planet, which will leave you directly on the imaginary east pole. The distance is now the hypotenuse of a right angle triangle of side 10km.\r\nAnswer: root 200 or approximately 14km!\r\n(If you got the distance as 15.7km - the distance you would have to walk back, then that's ok too!)", "category": "Math", "date": "05/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou land on an unknown planet which has a radius of 10km and is completely round and smooth. You start from your ship and walk straight for 17.345 kilometers. You turn left and walk straight for 47.124 kilometers. How far are you from your ship?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n14.142135623730950488016887242097\r\nOr square root of 200!\r\nIf you imagine you are facing a globe head on, you have the north pole at the top of the globe and the south pole at the bottom. Imagine a \"west pole\" and \"east pole\" to the left and right of the globe.\r\nIf you are at the north pole and turn left, you will walk through the \"west pole\" (right and you go through the \"east pole\")\r\nIf you walk on an axis from the north pole towards the south pole and make a left or right turn you will always walk through these imaginary east and west poles. So in the question 17.345 kilometers is irrelevant, only the turn. \r\n(It also doesn't matter where you start on the planet, the distance at the end will still be the same.)\r\n47.124 is approximately 3/4 of the circumference of this planet, which will leave you directly on the imaginary east pole. The distance is now the hypotenuse of a right angle triangle of side 10km.\r\nAnswer: root 200 or approximately 14km!\r\n(If you got the distance as 15.7km - the distance you would have to walk back, then that's ok too!)\n<|im_start|>answer\n14.142135623730950488016887242097\r\nOr square root of 200!\r\nIf you imagine you are facing a globe head on, you have the north pole at the top of the globe and the south pole at the bottom. Imagine a \"west pole\" and \"east pole\" to the left and right of the globe.\r\nIf you are at the north pole and turn left, you will walk through the \"west pole\" (right and you go through the \"east pole\")\r\nIf you walk on an axis from the north pole towards the south pole and make a left or right turn you will always walk through these imaginary east and west poles. So in the question 17.345 kilometers is irrelevant, only the turn. \r\n(It also doesn't matter where you start on the planet, the distance at the end will still be the same.)\r\n47.124 is approximately 3/4 of the circumference of this planet, which will leave you directly on the imaginary east pole. The distance is now the hypotenuse of a right angle triangle of side 10km.\r\nAnswer: root 200 or approximately 14km!\r\n(If you got the distance as 15.7km - the distance you would have to walk back, then that's ok too!)\n<|im_end|>" }, { "id": "#3149", "title": "Cab Fares", "fun": 2.21, "difficulty": 2.77, "author": "204_blaze_41", "desc": "Bill, Bob, Frank, and Jim, who all drive cabs, work a particularly busy street that runs east and west. The street has no traffic lights. Oddly enough, an equal number of pedestrians walk in each direction at four kilometres per hour. The four cab drivers were discussing the best way to pick up a fare. Bill said he was going to sit beside the curb and wait until a fare came along. Bob said he was going to cruise west at four kilometres an hour; therefore, he would have twice the chance of picking up a fare as Bill. Frank said he was going to cruise east at eight kilometres an hour and his chances were twice as good as either Bill's or Bob's. Jim claimed that they were all wrong. He was going to drive west at 12kmh and his chances of picking up a fare were twice as good as Frank's. Of the claims that were made which were correct and which were wrong?", "hint": "No hint available.", "answer": "Bill made no claim, Bob's claim was false, Frank's claim was true, and Jim's claim was false. Let's assume that 100 people passed Bill going east at four kph, and 100 people passed him going west at four kph. Bob, who was driving west at four kph, wouldn't pass anyone walking west, but would pass 200 people walking east. This would put him no further ahead than Bill. Frank, who was driving east and 300 people going west. Jim, who was going west at 12kph, would pass 200 people going west and 400 people going east. His statement about doubling his chances over Frank was false.", "category": "Math", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBill, Bob, Frank, and Jim, who all drive cabs, work a particularly busy street that runs east and west. The street has no traffic lights. Oddly enough, an equal number of pedestrians walk in each direction at four kilometres per hour. The four cab drivers were discussing the best way to pick up a fare. Bill said he was going to sit beside the curb and wait until a fare came along. Bob said he was going to cruise west at four kilometres an hour; therefore, he would have twice the chance of picking up a fare as Bill. Frank said he was going to cruise east at eight kilometres an hour and his chances were twice as good as either Bill's or Bob's. Jim claimed that they were all wrong. He was going to drive west at 12kmh and his chances of picking up a fare were twice as good as Frank's. Of the claims that were made which were correct and which were wrong?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBill made no claim, Bob's claim was false, Frank's claim was true, and Jim's claim was false. Let's assume that 100 people passed Bill going east at four kph, and 100 people passed him going west at four kph. Bob, who was driving west at four kph, wouldn't pass anyone walking west, but would pass 200 people walking east. This would put him no further ahead than Bill. Frank, who was driving east and 300 people going west. Jim, who was going west at 12kph, would pass 200 people going west and 400 people going east. His statement about doubling his chances over Frank was false.\n<|im_start|>answer\nBill made no claim, Bob's claim was false, Frank's claim was true, and Jim's claim was false. Let's assume that 100 people passed Bill going east at four kph, and 100 people passed him going west at four kph. Bob, who was driving west at four kph, wouldn't pass anyone walking west, but would pass 200 people walking east. This would put him no further ahead than Bill. Frank, who was driving east and 300 people going west. Jim, who was going west at 12kph, would pass 200 people going west and 400 people going east. His statement about doubling his chances over Frank was false.\n<|im_end|>" }, { "id": "#44377", "title": "Eliza Pseudonym and Puzzlanian Idol", "fun": 2.21, "difficulty": 2.15, "author": "mathgrant", "desc": "Eliza Pseudonym and her friends Anna, Barbra, Carla, Delilah, and Fiona are close followers of the hit television series Puzzlanian Idol, where contestants compete to win a recording contract by singing live on the show in an attempt to garner the votes of viewers. After many grueling weeks of singing and heart-breaking eliminations, the six remaining contestants performed on the most recent episode, following which the aforementioned Puzzlanian Idol fans phoned in their votes for their favorite contestant; each person voted for a different contestant. From the clues below, determine each contestant's first and last name (one first name is Luke, and one surname is White), the order in which they performed, and who voted for each one.\n\r\n1. No two contestants have the same combination of first and last initials. No two contestants who performed consecutively have the same first initial or the same last initial.\r\n2. Delilah voted for the person who performed third.\r\n3. The contestant surnamed Pelkey performed sometime before Leah.\r\n4. The contestant for whom Carla voted performed sometime after Mark Green (who wasn't the fourth contestant to perform).\r\n5. The recipient of Barbra's vote performed sometime after the contestant surnamed Black, but sometime before the contestant surnamed Brown (who was the third contestant to perform after the one surnamed Black).\r\n6. The second contestant to sing was surnamed Gray.\r\n7. Anna did not cast her vote either for John (who performed sometime after Jude) or for the contestant who sang fifth on the show.\r\n8. Fiona voted for Matthew.", "hint": "No hint available.", "answer": "1st: Matthew Black, Fiona\r\n2nd: Luke Gray, Barbra\r\n3rd: Jude Pelkey, Delilah\r\n4th: Leah Brown, Anna\r\n5th: Mark Green, Eliza\r\n6th: John White, Carla", "category": "Logic", "date": "04/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEliza Pseudonym and her friends Anna, Barbra, Carla, Delilah, and Fiona are close followers of the hit television series Puzzlanian Idol, where contestants compete to win a recording contract by singing live on the show in an attempt to garner the votes of viewers. After many grueling weeks of singing and heart-breaking eliminations, the six remaining contestants performed on the most recent episode, following which the aforementioned Puzzlanian Idol fans phoned in their votes for their favorite contestant; each person voted for a different contestant. From the clues below, determine each contestant's first and last name (one first name is Luke, and one surname is White), the order in which they performed, and who voted for each one.\n\r\n1. No two contestants have the same combination of first and last initials. No two contestants who performed consecutively have the same first initial or the same last initial.\r\n2. Delilah voted for the person who performed third.\r\n3. The contestant surnamed Pelkey performed sometime before Leah.\r\n4. The contestant for whom Carla voted performed sometime after Mark Green (who wasn't the fourth contestant to perform).\r\n5. The recipient of Barbra's vote performed sometime after the contestant surnamed Black, but sometime before the contestant surnamed Brown (who was the third contestant to perform after the one surnamed Black).\r\n6. The second contestant to sing was surnamed Gray.\r\n7. Anna did not cast her vote either for John (who performed sometime after Jude) or for the contestant who sang fifth on the show.\r\n8. Fiona voted for Matthew.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st: Matthew Black, Fiona\r\n2nd: Luke Gray, Barbra\r\n3rd: Jude Pelkey, Delilah\r\n4th: Leah Brown, Anna\r\n5th: Mark Green, Eliza\r\n6th: John White, Carla\n<|im_start|>answer\n1st: Matthew Black, Fiona\r\n2nd: Luke Gray, Barbra\r\n3rd: Jude Pelkey, Delilah\r\n4th: Leah Brown, Anna\r\n5th: Mark Green, Eliza\r\n6th: John White, Carla\n<|im_end|>" }, { "id": "#8554", "title": "Delayed Trains", "fun": 2.21, "difficulty": 2.49, "author": "lesternoronha1", "desc": "Mrs. John grumbles about bad time-keeping trains like everybody else. On one particular morning she was justified, though. The train left on time for the one hour journey and it arrived 5 minutes late. However, Mrs. John's watch showed it to be 3 minutes early, so she adjusted her watch by putting it forward 3 minutes. Her watch kept time during the day, and on the return journey in the evening the train started on time, according to her watch, and arrived on time, according to the station clock. If the train traveled 25 percent faster on the return journey than it did on the morning journey, was the station clock fast or slow, and by how much?", "hint": "No hint available.", "answer": "The station clock is 3 minutes fast. The morning journey took 65 minutes, and the evening journey therefore took 52 minutes, and the train arrived 57 minutes after it should have left, that is, 3 minutes early.", "category": "Math", "date": "11/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. John grumbles about bad time-keeping trains like everybody else. On one particular morning she was justified, though. The train left on time for the one hour journey and it arrived 5 minutes late. However, Mrs. John's watch showed it to be 3 minutes early, so she adjusted her watch by putting it forward 3 minutes. Her watch kept time during the day, and on the return journey in the evening the train started on time, according to her watch, and arrived on time, according to the station clock. If the train traveled 25 percent faster on the return journey than it did on the morning journey, was the station clock fast or slow, and by how much?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe station clock is 3 minutes fast. The morning journey took 65 minutes, and the evening journey therefore took 52 minutes, and the train arrived 57 minutes after it should have left, that is, 3 minutes early.\n<|im_start|>answer\nThe station clock is 3 minutes fast. The morning journey took 65 minutes, and the evening journey therefore took 52 minutes, and the train arrived 57 minutes after it should have left, that is, 3 minutes early.\n<|im_end|>" }, { "id": "#22539", "title": "Star Wars Puzzle", "fun": 2.21, "difficulty": 1.08, "author": "stormtrooper", "desc": "On Endor, OC means a bundle of 8 sticks, OCTA means a bundle of 8 OCs, OCTIL means a bundle of 8 OCTAs, and OCTILLA means a bundle of 8 OCTILs. One day, a band of primitive Ewoks gather an OCTILLA. How many sticks did they gather?", "hint": "No hint available.", "answer": "Since OC=8, OCTA=8x8=64, and OCTIL=8x64=512, Then\r\nOCTILLA=8x512=4096", "category": "Math", "date": "04/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Endor, OC means a bundle of 8 sticks, OCTA means a bundle of 8 OCs, OCTIL means a bundle of 8 OCTAs, and OCTILLA means a bundle of 8 OCTILs. One day, a band of primitive Ewoks gather an OCTILLA. How many sticks did they gather?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince OC=8, OCTA=8x8=64, and OCTIL=8x64=512, Then\r\nOCTILLA=8x512=4096\n<|im_start|>answer\nSince OC=8, OCTA=8x8=64, and OCTIL=8x64=512, Then\r\nOCTILLA=8x512=4096\n<|im_end|>" }, { "id": "#10711", "title": "4 Triangles", "fun": 2.21, "difficulty": 1.26, "author": "ninjaxdream", "desc": "You have 6 matches, now try and make 4 triangles. You cannot snap the matches and the matches can not overlap.", "hint": "No hint available.", "answer": "Make a triangular based pyramid.", "category": "Logic", "date": "02/25/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have 6 matches, now try and make 4 triangles. You cannot snap the matches and the matches can not overlap.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMake a triangular based pyramid.\n<|im_start|>answer\nMake a triangular based pyramid.\n<|im_end|>" }, { "id": "#33151", "title": "CrossDigit 6", "fun": 2.21, "difficulty": 2.19, "author": "dishu", "desc": "This teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digit. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A3, A4, B4, C1, D1 and D2.\r\n2. The sum of digits in row A equal 4.\r\n3. The sum of digits in row B equal 17.\r\n4. The sum of digits in row C equal 23.\r\n5. The sum of digits in row D equal 4.\r\n6. The sum of digits in column 1 equal 7.\r\n7. The sum of digits in column 2 equal 20.\r\n8. The sum of digits in column 3 equal 9.\r\n9. The sum of digits in column 4 equal 12.\n\r\nNow figure out which box contains which digit and do not forget the rules.", "hint": "A number can be present more than once in the grid, but not the same row or column.", "answer": "The solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 3, A3: Blank, A4: Blank\r\nB1: 6, B2: 9, B3: 2, B4: Blank\r\nC1: Blank, C2: 8, C3: 6, C4: 9\r\nD1: Blank, D2: Blank, D3: 1, D4: 3", "category": "Math", "date": "09/24/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThis teaser is similar to a crossword puzzle, but there is a twist. Instead of words, it uses digits 1-9 and empty (black in crossword puzzles) spaces in a 4 by 4 grid. The grid is arranged as follows:\n\n\r\nA1 A2 A3 A4\r\nB1 B2 B3 B4\r\nC1 C2 C3 C4\r\nD1 D2 D3 D4\n\r\nWith the help of the given rules and clues, you have to figure out which box contains which digit.\n\r\nThe rules are: \n\r\n1: No row or column can have the same digit appearing more than once.\r\n2: 0 (Zero) is not permissible.\r\n3: Empty spaces cannot contain any digit. They are empty.\n\n\r\nAnd the clues are:\n\r\n1. The empty spaces are A3, A4, B4, C1, D1 and D2.\r\n2. The sum of digits in row A equal 4.\r\n3. The sum of digits in row B equal 17.\r\n4. The sum of digits in row C equal 23.\r\n5. The sum of digits in row D equal 4.\r\n6. The sum of digits in column 1 equal 7.\r\n7. The sum of digits in column 2 equal 20.\r\n8. The sum of digits in column 3 equal 9.\r\n9. The sum of digits in column 4 equal 12.\n\r\nNow figure out which box contains which digit and do not forget the rules.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 3, A3: Blank, A4: Blank\r\nB1: 6, B2: 9, B3: 2, B4: Blank\r\nC1: Blank, C2: 8, C3: 6, C4: 9\r\nD1: Blank, D2: Blank, D3: 1, D4: 3\n<|im_start|>answer\nThe solution grid looks like this: \n\r\nThe digits are laid out as follows:\r\nA1: 1, A2: 3, A3: Blank, A4: Blank\r\nB1: 6, B2: 9, B3: 2, B4: Blank\r\nC1: Blank, C2: 8, C3: 6, C4: 9\r\nD1: Blank, D2: Blank, D3: 1, D4: 3\n<|im_end|>" }, { "id": "#42960", "title": "Two-Digit Number", "fun": 2.21, "difficulty": 0.93, "author": "cacmjc", "desc": "I am a two-digit number. The sum of my digits is 11. I am divisible by both 4 and 7. What number am I?", "hint": "No hint available.", "answer": "56", "category": "Math", "date": "09/01/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a two-digit number. The sum of my digits is 11. I am divisible by both 4 and 7. What number am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n56\n<|im_start|>answer\n56\n<|im_end|>" }, { "id": "#1292", "title": "Wedding Day", "fun": 2.21, "difficulty": 1.55, "author": "Yanivster", "desc": "On their wedding day, the ratio between the groom's age and the bride's age was 3:1. 15 Years later the ratio would be 2:1. How old were they when they got married?", "hint": "No hint available.", "answer": "The groom was 45, the bride was 15.", "category": "Math", "date": "11/04/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn their wedding day, the ratio between the groom's age and the bride's age was 3:1. 15 Years later the ratio would be 2:1. How old were they when they got married?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe groom was 45, the bride was 15.\n<|im_start|>answer\nThe groom was 45, the bride was 15.\n<|im_end|>" }, { "id": "#19620", "title": "Mad Ade's Math Teaser", "fun": 2.21, "difficulty": 2.53, "author": "Mad-Ade", "desc": "4_4_4_4_4_4_4_4_4 = 2000\n\r\n Put any mathematical operator in the equation to make the target number of the equation equal to 2000. \r\nThe blank spaces are only to separate the 9 fours and not necessarily the positions of the mathematical operators.", "hint": "No hint available.", "answer": "(4 * 4 + 4) * (4 * 4 + 4) * (4 / 4 + 4) = 20 * 20 * 5 = 2000\n\r\n(444 - 44) * (4 * 4 + 4) / 4 = 400 * 5 = 2000", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4_4_4_4_4_4_4_4_4 = 2000\n\r\n Put any mathematical operator in the equation to make the target number of the equation equal to 2000. \r\nThe blank spaces are only to separate the 9 fours and not necessarily the positions of the mathematical operators.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(4 * 4 + 4) * (4 * 4 + 4) * (4 / 4 + 4) = 20 * 20 * 5 = 2000\n\r\n(444 - 44) * (4 * 4 + 4) / 4 = 400 * 5 = 2000\n<|im_start|>answer\n(4 * 4 + 4) * (4 * 4 + 4) * (4 / 4 + 4) = 20 * 20 * 5 = 2000\n\r\n(444 - 44) * (4 * 4 + 4) / 4 = 400 * 5 = 2000\n<|im_end|>" }, { "id": "#777", "title": "A Question Of Ages", "fun": 2.21, "difficulty": 1.31, "author": "Nike01", "desc": "Two youngsters are chatting about their ages. Tom is just three times as old as Mary, but in two years time he will be twice as old as she is. How old is each youngster?", "hint": "No hint available.", "answer": "Tom is 6 and Mary is 2.", "category": "Math", "date": "08/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo youngsters are chatting about their ages. Tom is just three times as old as Mary, but in two years time he will be twice as old as she is. How old is each youngster?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTom is 6 and Mary is 2.\n<|im_start|>answer\nTom is 6 and Mary is 2.\n<|im_end|>" }, { "id": "#9440", "title": "Jog Back", "fun": 2.21, "difficulty": 1.36, "author": "lesternoronha1", "desc": "A man was going on a one-way bus trip. He intended to ride for a certain distance, get off the bus and walk back to town. \n\r\nIf the bus travels at a rate of nine miles per hour and he was to jog back to town at a rate of three miles per hour, how far would he ride so that he'd be back in eight hours?", "hint": "No hint available.", "answer": "Eighteen miles. Since he is riding three times as fast as he can jog, three-quarters of his time must be spent jogging. Since he rode for two hours, travelling 18 miles, and jogged for six hours, travelling at three mph he made the round trip in eight hours.", "category": "Math", "date": "12/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man was going on a one-way bus trip. He intended to ride for a certain distance, get off the bus and walk back to town. \n\r\nIf the bus travels at a rate of nine miles per hour and he was to jog back to town at a rate of three miles per hour, how far would he ride so that he'd be back in eight hours?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEighteen miles. Since he is riding three times as fast as he can jog, three-quarters of his time must be spent jogging. Since he rode for two hours, travelling 18 miles, and jogged for six hours, travelling at three mph he made the round trip in eight hours.\n<|im_start|>answer\nEighteen miles. Since he is riding three times as fast as he can jog, three-quarters of his time must be spent jogging. Since he rode for two hours, travelling 18 miles, and jogged for six hours, travelling at three mph he made the round trip in eight hours.\n<|im_end|>" }, { "id": "#40874", "title": "Page Numbers", "fun": 2.21, "difficulty": 1.06, "author": "doubleugh", "desc": "If you opened up a book to two pages, would the sum be even or odd? If you multiplied them would it be even or odd? If you opened a book to two different pages, would the answers stay the same to the two questions above?", "hint": "If you need help, get a book and see.", "answer": "The sum would be ODD.\r\nThe product would be EVEN.\r\nThe answer WOULD stay the same if you opened to two different pages.", "category": "Math", "date": "03/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you opened up a book to two pages, would the sum be even or odd? If you multiplied them would it be even or odd? If you opened a book to two different pages, would the answers stay the same to the two questions above?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe sum would be ODD.\r\nThe product would be EVEN.\r\nThe answer WOULD stay the same if you opened to two different pages.\n<|im_start|>answer\nThe sum would be ODD.\r\nThe product would be EVEN.\r\nThe answer WOULD stay the same if you opened to two different pages.\n<|im_end|>" }, { "id": "#15415", "title": "Collins Market", "fun": 2.21, "difficulty": 1.94, "author": "rckergrl87", "desc": "Cassidy, Gabriella, Keinan, Ross, and Shaun all plan to meet in front of the Collins Market at 11 a.m. They will each be coming from a different direction. Except for Shaun, they each will go directly to the market. \n\r\nCassidy lives 2.5 miles from the market. She can walk one mile in 20 minutes. \r\nGabriella will ride her bike. She lives twice as far from the store as Cassidy. She rides at 10 mph. \r\nThough Keinan lives 1 mile closer to the store than Cassidy, he must walk up a hill, so he walks at a rate of about 2 mph. \r\nRoss also rides his bike, but it will take him 1.5 times as long to get to the store as Gabriella. \r\nShaun will ride his bike the 10 miles from his home. He rides 5 mph faster than Gabriella, but plans to stop at the library on the way for 15 minutes. \r\nIf no one allows any extra time, what time must each person leave home to get to the market at 11 a.m.?", "hint": "Make a chart. Use the formula distance = rate x time. Be sure you are using the same units for everyone, and for all parts of the formula.", "answer": "Cassidy must leave at 10:10.\n\r\nGabriella must leave at 10:30.\n\r\nKeinan must leave at 10:15.\n\r\nRoss must leave at 10:15.\n\r\nShaun must leave at 10:05. \n\r\nExplanation: \n\r\nCassidy needs 50 minutes to go 2.5 miles, so she must leave at 10:10.\r\nGabriella needs 30 minutes to go 5 miles, so she must leave at 10:30.\n\r\nKeinan needs 45 minutes to go 1.5 miles, so he must leave at 10:15.\n\r\nRoss will take one and a half times as long to get to the store as Gabriella. Since it will take her 30 minutes, it will take him one and a half times as long, or 45 minutes. He must leave at 10:15. (Enough information is given so that it is not necessary to know the distance.)\n\r\nShaun needs a total of 55 minutes. (This includes 40 minutes to bike, plus 15 minutes for the stop at the library.) He must leave at 10:05.", "category": "Math", "date": "11/12/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCassidy, Gabriella, Keinan, Ross, and Shaun all plan to meet in front of the Collins Market at 11 a.m. They will each be coming from a different direction. Except for Shaun, they each will go directly to the market. \n\r\nCassidy lives 2.5 miles from the market. She can walk one mile in 20 minutes. \r\nGabriella will ride her bike. She lives twice as far from the store as Cassidy. She rides at 10 mph. \r\nThough Keinan lives 1 mile closer to the store than Cassidy, he must walk up a hill, so he walks at a rate of about 2 mph. \r\nRoss also rides his bike, but it will take him 1.5 times as long to get to the store as Gabriella. \r\nShaun will ride his bike the 10 miles from his home. He rides 5 mph faster than Gabriella, but plans to stop at the library on the way for 15 minutes. \r\nIf no one allows any extra time, what time must each person leave home to get to the market at 11 a.m.?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCassidy must leave at 10:10.\n\r\nGabriella must leave at 10:30.\n\r\nKeinan must leave at 10:15.\n\r\nRoss must leave at 10:15.\n\r\nShaun must leave at 10:05. \n\r\nExplanation: \n\r\nCassidy needs 50 minutes to go 2.5 miles, so she must leave at 10:10.\r\nGabriella needs 30 minutes to go 5 miles, so she must leave at 10:30.\n\r\nKeinan needs 45 minutes to go 1.5 miles, so he must leave at 10:15.\n\r\nRoss will take one and a half times as long to get to the store as Gabriella. Since it will take her 30 minutes, it will take him one and a half times as long, or 45 minutes. He must leave at 10:15. (Enough information is given so that it is not necessary to know the distance.)\n\r\nShaun needs a total of 55 minutes. (This includes 40 minutes to bike, plus 15 minutes for the stop at the library.) He must leave at 10:05.\n<|im_start|>answer\nCassidy must leave at 10:10.\n\r\nGabriella must leave at 10:30.\n\r\nKeinan must leave at 10:15.\n\r\nRoss must leave at 10:15.\n\r\nShaun must leave at 10:05. \n\r\nExplanation: \n\r\nCassidy needs 50 minutes to go 2.5 miles, so she must leave at 10:10.\r\nGabriella needs 30 minutes to go 5 miles, so she must leave at 10:30.\n\r\nKeinan needs 45 minutes to go 1.5 miles, so he must leave at 10:15.\n\r\nRoss will take one and a half times as long to get to the store as Gabriella. Since it will take her 30 minutes, it will take him one and a half times as long, or 45 minutes. He must leave at 10:15. (Enough information is given so that it is not necessary to know the distance.)\n\r\nShaun needs a total of 55 minutes. (This includes 40 minutes to bike, plus 15 minutes for the stop at the library.) He must leave at 10:05.\n<|im_end|>" }, { "id": "#20964", "title": "Hours of Sleep", "fun": 2.21, "difficulty": 1.37, "author": "NathanM", "desc": "Adam's mom is 20% younger than her husband who is 50. If you add both their ages up, have the mom and dad spent more time sleeping (sleep is a third of your life) than Adam and his two brothers aged 14, 11 and 5 have been alive for?", "hint": "No hint available.", "answer": "20% of 50 is 10. 50-10 =40\r\n50 + 40 = 90\r\n90/3 is 30\r\n14 + 11 + 5 = 30 so their parents have slept the equal amount as their three children have been alive.", "category": "Math", "date": "02/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdam's mom is 20% younger than her husband who is 50. If you add both their ages up, have the mom and dad spent more time sleeping (sleep is a third of your life) than Adam and his two brothers aged 14, 11 and 5 have been alive for?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20% of 50 is 10. 50-10 =40\r\n50 + 40 = 90\r\n90/3 is 30\r\n14 + 11 + 5 = 30 so their parents have slept the equal amount as their three children have been alive.\n<|im_start|>answer\n20% of 50 is 10. 50-10 =40\r\n50 + 40 = 90\r\n90/3 is 30\r\n14 + 11 + 5 = 30 so their parents have slept the equal amount as their three children have been alive.\n<|im_end|>" }, { "id": "#2233", "title": "Paper Room", "fun": 2.21, "difficulty": 1.76, "author": "Trev", "desc": "A room is 12' x 8' when it is designed on paper. You decide to make it square, and take 2 feet off the length and add it to the width to make it 2 feet wider. The room is now 10' x 10'. The total square footage of the first room was 96sq feet, the total footage of the second room is 100sq feet. Where did the extra 4sq feet come from?", "hint": "No hint available.", "answer": "The 2' taken off the first room is 2' x 8' for a total size of 16sq feet. To add it onto the second room you make it 2' x 10', which is 20sq feet. That's the extra 4 sq feet.", "category": "Math", "date": "02/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA room is 12' x 8' when it is designed on paper. You decide to make it square, and take 2 feet off the length and add it to the width to make it 2 feet wider. The room is now 10' x 10'. The total square footage of the first room was 96sq feet, the total footage of the second room is 100sq feet. Where did the extra 4sq feet come from?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 2' taken off the first room is 2' x 8' for a total size of 16sq feet. To add it onto the second room you make it 2' x 10', which is 20sq feet. That's the extra 4 sq feet.\n<|im_start|>answer\nThe 2' taken off the first room is 2' x 8' for a total size of 16sq feet. To add it onto the second room you make it 2' x 10', which is 20sq feet. That's the extra 4 sq feet.\n<|im_end|>" }, { "id": "#8734", "title": "Dimensional Increase of a Cube", "fun": 2.2, "difficulty": 1.46, "author": "lesternoronha1", "desc": "If the length of each edge of a cube is increased by 50%, find the percentage increase in the cube's surface area.", "hint": "No hint available.", "answer": "The percentage increase in the surface area of the cube = 125%.\n\r\nThe surface area of a cube is (x^2 * 6), where x is the length of a side.\r\nIf you increase x by 50%, the new surface area is (1.5*x)^2 * 6. Divide the area of the new cube by the area of the original cube to get the ratio of the areas:\n\r\n[(1.5*x)^2 * 6] / [x^2 * 6] = 1.5^2 = 2.25\n\r\n(2.25 - 1) * 100% = 125% increase.", "category": "Math", "date": "11/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the length of each edge of a cube is increased by 50%, find the percentage increase in the cube's surface area.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe percentage increase in the surface area of the cube = 125%.\n\r\nThe surface area of a cube is (x^2 * 6), where x is the length of a side.\r\nIf you increase x by 50%, the new surface area is (1.5*x)^2 * 6. Divide the area of the new cube by the area of the original cube to get the ratio of the areas:\n\r\n[(1.5*x)^2 * 6] / [x^2 * 6] = 1.5^2 = 2.25\n\r\n(2.25 - 1) * 100% = 125% increase.\n<|im_start|>answer\nThe percentage increase in the surface area of the cube = 125%.\n\r\nThe surface area of a cube is (x^2 * 6), where x is the length of a side.\r\nIf you increase x by 50%, the new surface area is (1.5*x)^2 * 6. Divide the area of the new cube by the area of the original cube to get the ratio of the areas:\n\r\n[(1.5*x)^2 * 6] / [x^2 * 6] = 1.5^2 = 2.25\n\r\n(2.25 - 1) * 100% = 125% increase.\n<|im_end|>" }, { "id": "#5083", "title": "Under 3000", "fun": 2.2, "difficulty": 2.83, "author": "alex", "desc": "There is a number less than 3000 that when divided by 2 leaves a remainder of 1, when divided by 3 leaves a remainder of 2, when divided by 4 leaves a remainder of 3, When divided by 5 leaves a remainder of 4, when divided by 6 leaves a remainder of 5, and so on up to nine. What is that number?", "hint": "No hint available.", "answer": "2519", "category": "Math", "date": "06/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a number less than 3000 that when divided by 2 leaves a remainder of 1, when divided by 3 leaves a remainder of 2, when divided by 4 leaves a remainder of 3, When divided by 5 leaves a remainder of 4, when divided by 6 leaves a remainder of 5, and so on up to nine. What is that number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2519\n<|im_start|>answer\n2519\n<|im_end|>" }, { "id": "#33775", "title": "Easy As Cake", "fun": 2.2, "difficulty": 2.86, "author": "stil", "desc": "In our business, my two partners and I cut a lot of cake.\r\nWe work exclusively with square cakes. The cakes come in sizes that are meant to be divided into a square number of square pieces. Each portion comes decorated with an \"X\" stretching to its corners, which makes it easy to cut the usual square pieces and also offer half and quarter portions.\r\nThese markings also help on Wednesday when we savor the previous week's success by dividing a cake equally amongst ourselves. Even when a good week deserves a 64-portion cake, we can each ceremonially make a single standard cut (straight and perpendicular to the plate), and we each go home with a single piece of cake.\r\nUsing no other cuts or devices, how do we evenly divide the 8-by-8 cake? (EXTRA - How could we get 7 (and only 7) equal-size pieces from the same size cake?)", "hint": "Think smaller.", "answer": "To get three twenty-one-and-one-third (64/3) portion-sized pieces, we momentarily ignore the 28 X's/portions/square-units which form the 32 unit perimeter of the cake. There is more than one way to divide the 6-by-6 (36 X) cake inside into three equal pieces. Using one based on its 24 unit perimeter, this cake could be divided into 24 wedges of equal size. Each triangular piece would have as its base one unit of the perimeter; the other two sides would be formed by cuts to the center of the cake. Every triangle would have the same altitude (3 units) giving the same area (A = ½ * b * h = ½ * 1 * 3 = 3/2 square units). 8 adjacent triangles, even though they include a corner or two, will be 12 square units or 1/3 of the \"inner\" cake. \r\nBefore we make any actual cuts, we return the ignored 28 portions to the picture and then make those three cuts extended to the true perimeter. The 24 triangles pictured previously increase in altitude to 4 units. By rules of similar triangles, the base increases by the same 1/3 (33 1/3%) to 1 1/3 units. The area of 8 extended triangles is 8 * ½ * 4/3 * 4 = 64/3 portions, which is exactly one-third of the cake. \r\n(The perimeter of a 7-by-7 square can be formed by connecting the centers of the X's in the \"ignored\" 28 portions. Applying the above methods but now grouping 28 triangles into foursomes, we get 7 equal size pieces.)", "category": "Math", "date": "10/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn our business, my two partners and I cut a lot of cake.\r\nWe work exclusively with square cakes. The cakes come in sizes that are meant to be divided into a square number of square pieces. Each portion comes decorated with an \"X\" stretching to its corners, which makes it easy to cut the usual square pieces and also offer half and quarter portions.\r\nThese markings also help on Wednesday when we savor the previous week's success by dividing a cake equally amongst ourselves. Even when a good week deserves a 64-portion cake, we can each ceremonially make a single standard cut (straight and perpendicular to the plate), and we each go home with a single piece of cake.\r\nUsing no other cuts or devices, how do we evenly divide the 8-by-8 cake? (EXTRA - How could we get 7 (and only 7) equal-size pieces from the same size cake?)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTo get three twenty-one-and-one-third (64/3) portion-sized pieces, we momentarily ignore the 28 X's/portions/square-units which form the 32 unit perimeter of the cake. There is more than one way to divide the 6-by-6 (36 X) cake inside into three equal pieces. Using one based on its 24 unit perimeter, this cake could be divided into 24 wedges of equal size. Each triangular piece would have as its base one unit of the perimeter; the other two sides would be formed by cuts to the center of the cake. Every triangle would have the same altitude (3 units) giving the same area (A = ½ * b * h = ½ * 1 * 3 = 3/2 square units). 8 adjacent triangles, even though they include a corner or two, will be 12 square units or 1/3 of the \"inner\" cake. \r\nBefore we make any actual cuts, we return the ignored 28 portions to the picture and then make those three cuts extended to the true perimeter. The 24 triangles pictured previously increase in altitude to 4 units. By rules of similar triangles, the base increases by the same 1/3 (33 1/3%) to 1 1/3 units. The area of 8 extended triangles is 8 * ½ * 4/3 * 4 = 64/3 portions, which is exactly one-third of the cake. \r\n(The perimeter of a 7-by-7 square can be formed by connecting the centers of the X's in the \"ignored\" 28 portions. Applying the above methods but now grouping 28 triangles into foursomes, we get 7 equal size pieces.)\n<|im_start|>answer\nTo get three twenty-one-and-one-third (64/3) portion-sized pieces, we momentarily ignore the 28 X's/portions/square-units which form the 32 unit perimeter of the cake. There is more than one way to divide the 6-by-6 (36 X) cake inside into three equal pieces. Using one based on its 24 unit perimeter, this cake could be divided into 24 wedges of equal size. Each triangular piece would have as its base one unit of the perimeter; the other two sides would be formed by cuts to the center of the cake. Every triangle would have the same altitude (3 units) giving the same area (A = ½ * b * h = ½ * 1 * 3 = 3/2 square units). 8 adjacent triangles, even though they include a corner or two, will be 12 square units or 1/3 of the \"inner\" cake. \r\nBefore we make any actual cuts, we return the ignored 28 portions to the picture and then make those three cuts extended to the true perimeter. The 24 triangles pictured previously increase in altitude to 4 units. By rules of similar triangles, the base increases by the same 1/3 (33 1/3%) to 1 1/3 units. The area of 8 extended triangles is 8 * ½ * 4/3 * 4 = 64/3 portions, which is exactly one-third of the cake. \r\n(The perimeter of a 7-by-7 square can be formed by connecting the centers of the X's in the \"ignored\" 28 portions. Applying the above methods but now grouping 28 triangles into foursomes, we get 7 equal size pieces.)\n<|im_end|>" }, { "id": "#44967", "title": "Money Product", "fun": 2.2, "difficulty": 1.66, "author": "Carlos16", "desc": "Four people combined their money and have a total of $30. Assume that only one person is lying. What is the product of Allie and John's dollar amount?\n\r\nSebastian: I don't have any money.\r\nJohn: Jessica has less money than Sebastian.\r\nJessica: I have $15 more than John.\r\nAllie: I have one fourth of what Jessica has.", "hint": "No hint available.", "answer": "John is definitely the liar. If Sebastian would have more than Jessica, he would have more than $15 more than John. Jessica would have exactly $15 more than John. Combined that would be more than $30.\n\r\nJo + Al + Je = 30\r\nAl = Je/4\r\nJo = Je - 15\n\r\nSebastian is not included in the equation because he has $0.\n\r\nCombine everything like terms:\r\nJe - 15 + (Je/4) + Je = 30\n\r\nDo the math, and you will get 20.\n\r\nSo that means that Jessica has $20, so John has $5, and Allie has $5.\r\nJohn's dollar amount times Allie's is 25.\n\r\nAnswer: 25", "category": "Math", "date": "07/29/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people combined their money and have a total of $30. Assume that only one person is lying. What is the product of Allie and John's dollar amount?\n\r\nSebastian: I don't have any money.\r\nJohn: Jessica has less money than Sebastian.\r\nJessica: I have $15 more than John.\r\nAllie: I have one fourth of what Jessica has.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn is definitely the liar. If Sebastian would have more than Jessica, he would have more than $15 more than John. Jessica would have exactly $15 more than John. Combined that would be more than $30.\n\r\nJo + Al + Je = 30\r\nAl = Je/4\r\nJo = Je - 15\n\r\nSebastian is not included in the equation because he has $0.\n\r\nCombine everything like terms:\r\nJe - 15 + (Je/4) + Je = 30\n\r\nDo the math, and you will get 20.\n\r\nSo that means that Jessica has $20, so John has $5, and Allie has $5.\r\nJohn's dollar amount times Allie's is 25.\n\r\nAnswer: 25\n<|im_start|>answer\nJohn is definitely the liar. If Sebastian would have more than Jessica, he would have more than $15 more than John. Jessica would have exactly $15 more than John. Combined that would be more than $30.\n\r\nJo + Al + Je = 30\r\nAl = Je/4\r\nJo = Je - 15\n\r\nSebastian is not included in the equation because he has $0.\n\r\nCombine everything like terms:\r\nJe - 15 + (Je/4) + Je = 30\n\r\nDo the math, and you will get 20.\n\r\nSo that means that Jessica has $20, so John has $5, and Allie has $5.\r\nJohn's dollar amount times Allie's is 25.\n\r\nAnswer: 25\n<|im_end|>" }, { "id": "#4809", "title": "Weighing Vegetables", "fun": 2.2, "difficulty": 1.75, "author": "mad-ade", "desc": "Mad Ade was weighing vegetables with a pair of scales. Mad Ade noticed that the scales will balance if 1 head of cabbage and 1 lemon are on one side and 7 tomatoes are on the other. Also 3 lemons will balance with 1 ½ tomatoes. How many tomatoes did Mad Ade need to balance with 1 head of cabbage?", "hint": "No hint available.", "answer": "1 head of cabbage will balance with 6 ½ tomatoes. If 3 lemons balance with 1 ½ tomatoes, then 1 lemon is equal in weight to ½ tomato. To find out how many tomatoes balance with the cabbage, subtract the equivalent of a lemon, or half a tomato, from each side.", "category": "Math", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was weighing vegetables with a pair of scales. Mad Ade noticed that the scales will balance if 1 head of cabbage and 1 lemon are on one side and 7 tomatoes are on the other. Also 3 lemons will balance with 1 ½ tomatoes. How many tomatoes did Mad Ade need to balance with 1 head of cabbage?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 head of cabbage will balance with 6 ½ tomatoes. If 3 lemons balance with 1 ½ tomatoes, then 1 lemon is equal in weight to ½ tomato. To find out how many tomatoes balance with the cabbage, subtract the equivalent of a lemon, or half a tomato, from each side.\n<|im_start|>answer\n1 head of cabbage will balance with 6 ½ tomatoes. If 3 lemons balance with 1 ½ tomatoes, then 1 lemon is equal in weight to ½ tomato. To find out how many tomatoes balance with the cabbage, subtract the equivalent of a lemon, or half a tomato, from each side.\n<|im_end|>" }, { "id": "#11210", "title": "The 3 Men", "fun": 2.2, "difficulty": 1.57, "author": "Jake101", "desc": "3 men had $227 altogether. Joe had $35 more than George, while Craig had $7 more than Joe. \r\nHow much did they each have?", "hint": "No hint available.", "answer": "Craig had $92, Joe had $85, and George had $50.", "category": "Math", "date": "03/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n3 men had $227 altogether. Joe had $35 more than George, while Craig had $7 more than Joe. \r\nHow much did they each have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCraig had $92, Joe had $85, and George had $50.\n<|im_start|>answer\nCraig had $92, Joe had $85, and George had $50.\n<|im_end|>" }, { "id": "#1641", "title": "Rope Riddle", "fun": 2.2, "difficulty": 0.77, "author": "Nishoo", "desc": "You have a piece of thick rope which when set fire to at any end, burns for exactly an hour. How will you use it to measure half an hour ?", "hint": "No hint available.", "answer": "Set fire to the rope from both ends at the same time and it will burn for half an hour.", "category": "Logic", "date": "12/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a piece of thick rope which when set fire to at any end, burns for exactly an hour. How will you use it to measure half an hour ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSet fire to the rope from both ends at the same time and it will burn for half an hour.\n<|im_start|>answer\nSet fire to the rope from both ends at the same time and it will burn for half an hour.\n<|im_end|>" }, { "id": "#676", "title": "Piggy Bank", "fun": 2.2, "difficulty": 1.33, "author": "vikass", "desc": "You have stealthily raided your small child's piggy bank. You feel guilty as you count the money. You have the same number of dimes and quarters, totaling exactly $2.45. When you turn honest and put it back, how many of each coin will you need to replace? (Note that your child keeps a record of how much she puts in and in what denomination)", "hint": "No hint available.", "answer": "Let x represent the number of dimes, which is the same as the quarters. Then 10x represents the value of the dimes (x times 10 cents), and 25x represents the value of the quarters, in cents.\n\r\n10x + 25x = 245\r\n35x = 245\r\nx = 7\n\r\nTherefore, there were 7 dimes and 7 quarters totaling exactly $2.45", "category": "Math", "date": "07/14/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have stealthily raided your small child's piggy bank. You feel guilty as you count the money. You have the same number of dimes and quarters, totaling exactly $2.45. When you turn honest and put it back, how many of each coin will you need to replace? (Note that your child keeps a record of how much she puts in and in what denomination)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet x represent the number of dimes, which is the same as the quarters. Then 10x represents the value of the dimes (x times 10 cents), and 25x represents the value of the quarters, in cents.\n\r\n10x + 25x = 245\r\n35x = 245\r\nx = 7\n\r\nTherefore, there were 7 dimes and 7 quarters totaling exactly $2.45\n<|im_start|>answer\nLet x represent the number of dimes, which is the same as the quarters. Then 10x represents the value of the dimes (x times 10 cents), and 25x represents the value of the quarters, in cents.\n\r\n10x + 25x = 245\r\n35x = 245\r\nx = 7\n\r\nTherefore, there were 7 dimes and 7 quarters totaling exactly $2.45\n<|im_end|>" }, { "id": "#7073", "title": "The Great Sale", "fun": 2.2, "difficulty": 1.4, "author": "kidkilowatt", "desc": "If you had a coupon for 20% off any item in the store and you wanted to purchase a jacket that originally cost a hundred dollars that was now advertized as 40% off, how much would that jacket be?", "hint": "No hint available.", "answer": "48 dollars. 40% off of 100 is minus 40 dollars from the price which makes it 60. Then the 20% off the 60 dollars makes it 48 dollars.", "category": "Math", "date": "08/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you had a coupon for 20% off any item in the store and you wanted to purchase a jacket that originally cost a hundred dollars that was now advertized as 40% off, how much would that jacket be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n48 dollars. 40% off of 100 is minus 40 dollars from the price which makes it 60. Then the 20% off the 60 dollars makes it 48 dollars.\n<|im_start|>answer\n48 dollars. 40% off of 100 is minus 40 dollars from the price which makes it 60. Then the 20% off the 60 dollars makes it 48 dollars.\n<|im_end|>" }, { "id": "#6772", "title": "A 30 Year Old Man", "fun": 2.2, "difficulty": 1.25, "author": "k2w2man", "desc": "A 30 year old man married a 25 year old woman. She died at age 50 \r\nand her husband was so devastated that he cried for years. Ten \r\nyears after he stopped crying, he died. If he had lived to be 80, \r\nhow many years was he a widower?", "hint": "No hint available.", "answer": "He was a widower for 25 years.", "category": "Math", "date": "08/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 30 year old man married a 25 year old woman. She died at age 50 \r\nand her husband was so devastated that he cried for years. Ten \r\nyears after he stopped crying, he died. If he had lived to be 80, \r\nhow many years was he a widower?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe was a widower for 25 years.\n<|im_start|>answer\nHe was a widower for 25 years.\n<|im_end|>" }, { "id": "#19622", "title": "Madadian Ferries", "fun": 2.2, "difficulty": 2.72, "author": "Mad-Ade", "desc": "On the great \"Chilli\" lake of Madadia are two ferry boats that transport tourists from one side to the other.\r\nOne boat is the \"Lead Balloon\", the other is the \"Iceberg Magnet\". They travel from the Kebab Fountains on the east side of the lake and the Lard Sculpture on the west side of the lake.\r\nEach ferry travels at a constant speed, although the \"Lead Balloon\" is faster than the \"Iceberg Magnet\".\r\nThe two boats leave from opposite shores at the same time. They pass at a point of 720 yards from Lard Sculptures. Upon arriving at the opposite shore, each boat stays in its slip for 5 minutes, and then starts back. They pass again 400 yards from Kebab Fountains. Assume both boats travel along a straight line. How far is it from Kebab Fountains to Lard Sculptures by water?", "hint": "No hint available.", "answer": "Let X = the distance between the two ports. Note that the 5 minutes spent in their slips is irrelevant to solving the problem.\n\r\nThe ratio of the distance traveled by the two boats when they pass each other for the first time is: (X - 720) / 720.\n\r\nThe ratio of the total distance traveled by the two boats when they pass each other for the second time is: (2x - 400) / (X + 400).\n\r\nSince the boats travel at a constant speed, the ratios are equal.\n\r\n(X - 720) / 720 = (2X - 400) / (X + 400)\n\r\n(X - 720) * (X + 400) = (2X - 400) * 720\n\r\nX^2 - 320X - 288000 = 1440X - 288000\n\r\nX^2 - 320X = 1440X\n\r\nX^2 = 1760X\n\r\nX = 1760\n\r\nKebab Fountains and Lard Sculpture are 1760 yards apart.", "category": "Math", "date": "12/01/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn the great \"Chilli\" lake of Madadia are two ferry boats that transport tourists from one side to the other.\r\nOne boat is the \"Lead Balloon\", the other is the \"Iceberg Magnet\". They travel from the Kebab Fountains on the east side of the lake and the Lard Sculpture on the west side of the lake.\r\nEach ferry travels at a constant speed, although the \"Lead Balloon\" is faster than the \"Iceberg Magnet\".\r\nThe two boats leave from opposite shores at the same time. They pass at a point of 720 yards from Lard Sculptures. Upon arriving at the opposite shore, each boat stays in its slip for 5 minutes, and then starts back. They pass again 400 yards from Kebab Fountains. Assume both boats travel along a straight line. How far is it from Kebab Fountains to Lard Sculptures by water?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet X = the distance between the two ports. Note that the 5 minutes spent in their slips is irrelevant to solving the problem.\n\r\nThe ratio of the distance traveled by the two boats when they pass each other for the first time is: (X - 720) / 720.\n\r\nThe ratio of the total distance traveled by the two boats when they pass each other for the second time is: (2x - 400) / (X + 400).\n\r\nSince the boats travel at a constant speed, the ratios are equal.\n\r\n(X - 720) / 720 = (2X - 400) / (X + 400)\n\r\n(X - 720) * (X + 400) = (2X - 400) * 720\n\r\nX^2 - 320X - 288000 = 1440X - 288000\n\r\nX^2 - 320X = 1440X\n\r\nX^2 = 1760X\n\r\nX = 1760\n\r\nKebab Fountains and Lard Sculpture are 1760 yards apart.\n<|im_start|>answer\nLet X = the distance between the two ports. Note that the 5 minutes spent in their slips is irrelevant to solving the problem.\n\r\nThe ratio of the distance traveled by the two boats when they pass each other for the first time is: (X - 720) / 720.\n\r\nThe ratio of the total distance traveled by the two boats when they pass each other for the second time is: (2x - 400) / (X + 400).\n\r\nSince the boats travel at a constant speed, the ratios are equal.\n\r\n(X - 720) / 720 = (2X - 400) / (X + 400)\n\r\n(X - 720) * (X + 400) = (2X - 400) * 720\n\r\nX^2 - 320X - 288000 = 1440X - 288000\n\r\nX^2 - 320X = 1440X\n\r\nX^2 = 1760X\n\r\nX = 1760\n\r\nKebab Fountains and Lard Sculpture are 1760 yards apart.\n<|im_end|>" }, { "id": "#14518", "title": "Mad Ade's Fishing Trip", "fun": 2.2, "difficulty": 3.12, "author": "mad-ade", "desc": "Mad Ade went on an eight day fly fishing trip around the purple ridged mountains of Madadia and got to fish seven days of it last May. On every day, from May 14 to the 21st, except the 16th, when a severe thunderstorm kept him in his tent, he fished around Madadia. Though he caught many fish--all of which he released--each day, one special fish stood out. Each special fish was of a different variety: Monkey Trout, Brookside Trout, Cut Throat, Dolly Varden, Humpback, Lake Trout, and Rainbow, and a different size: 8 inches, 16 inches, 17 inches, 19 inches, 22 inches, 24 inches, and 27 inches. Every day, Mad Ade tried a different secret fishing spot: Big Little Falls, Bottle Well, Deep Channel, Old Cutbank, Big Rock Isle, Dish Creek, and Little Curl. And each special fish was caught on a different fly that Mad Ade tied himself: a Parachute Adams, an Elk Hair Caddis, a Humpy, a MayFly, Mad Ade's Little Mouse, a Stonefly Nymph, and a Yuk Bug. Three of the flies, Mad Ade's little Mouse, the Yuk Bug, and Stonefly Nymph, were fished as wet flies, the rest were fished as dry flies.\n\n\r\n1) Mad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. His shiny Dolly Varden was not the fish lured from the depths of Bottle Well. Mad Ade caught either the smallest or his second to largest fish on his third fishing day. \r\n2) Mad Ade caught a fish off Big Rock Isle on the 19th. He fought either the Humpback or the 24 inch monster on the 21st. On the fourth day of his trip, Mad Ade landed a fish over twenty inches long by the Old Cutbank on a wet fly. The fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls. \r\n3) Mad Ade caught the 24 inch fish on his Little Mouse after he caught the Dolly Varden, but before he hooked a real jumper with his Parachute Adams. Because he preferred dry flies, Mad Ade only used dry flies after using a wet fly on the 19th. Mad Ade used a Mayfly to fish Dish Creek. Mad Ade caught his fish on the Mayfly three calendar days (two fishing days) after he caught a fish with the Stonefly Nymph. \r\n4) Mad Ade's five mile hike, along a mountain trail to Big Little Falls, paid off on his last day with a prized Humpback trout. At least four fishing days passed between the time that Mad Ade used the Stonefly Nymph and his Humpy. The Monkey Trout Mad Ade caught on the 17th was longer than the Rainbow he caught, but smaller than his Lake Trout. \r\n5) The deep hole of Bottle Well yielded Mad Ade a 19 incher on the first or second day of his trip. With one exception, Mad Ade caught fish of even sizes on even number days and fish of odd sizes on odd days. Although they both jumped and splashed over the water the same way, the Rainbow Mad Ade caught was bigger than his Cut Throat.", "hint": "No hint available.", "answer": "Mad Ade caught a fish off Big Rock Isle on the 19th (2).\r\nThe Monkey Trout Mad Ade caught on the 17th (4).\r\nMad Ade caught either the smallest or his second to largest fish on his third fishing day. (1) \r\n17th is 8 or 24.\r\nOn the fourth day of his trip, Mad Ade landed a fish over twenty inches long by the Old Cutbank on a wet fly. (2) \r\n17th is 24 and Cutbank.\r\nMad Ade caught the 24 inch fish on his Little Mouse (3).\r\nWith one exception, Mad Ade caught fish of even sizes on even number days and fish of odd sizes on odd days. (5) \r\nHe fought either the Humpback or the 24 inch monster on the 21st. \r\nHumpback is 21st. (2) \r\nMad Ade's five mile hike, along a mountain trail to Big Little Falls, paid off on his last day with a prized Humpback trout. (5) \r\nHumpback is Big Little Falls. \r\nThe deep hole of Bottle Well yielded Mad Ade a 19 incher on the first or second day of his trip. (5) \r\nFirst day is 14th, so 19 incher had to be second day, 15th. \r\n15th then is Bottle. \r\nMad Ade caught the 24 inch fish on his Little Mouse after he caught the Dolly Varden (3).\r\nMouse is 24 inch fish on 17th. \r\nDolly is 14th or 15th. \r\nMad Ade caught his fish on the Mayfly three calendar days (two fishing days) after he caught a fish with the Stonefly nymph. (3) \r\nMayfly can only be 18th, as Mouse is 17th. \r\nStonefly is 15th.\r\nMad Ade used a Mayfly to fish Dish Creek. \r\nAt least four fishing days passed between the time that Mad Ade used the Stonefly Nymph and his Humpy. (4) \r\nStonefly is 15th, so Humpy is 21st.\r\nMad Ade only used dry flies after using a wet fly on the 19th. (3) \r\nOnly wet fly left is Yuk Bug, so Yuk Bug is 19th. \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nElk Hair Caddis can only be 14th. \r\nParachute Adams, the only fly left, is 20th. \r\nHis shiny Dolly Varden was not the fish lured from the depths of Bottle Well. Bottle is 15th, so Dolly is 14th. (1) \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nBrookside, 8 inches, (even) can only be Mayfly or Adams. \r\nThe fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls. (2) \r\nAdams can only be Little Curl or Deep Channel. It's not Channel (1) and not Little Curl (2), so Brookside is Dish Creek. \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nSo, Deep Channel is 20th, and 14th is Little Curl (last one). \r\nThe Monkey Trout Mad Ade caught on the 17th was longer than the Rainbow he caught, but smaller than his Lake Trout. (4) 17th is Monkey, 24 inches, so Lake can only be 27. Only odd without a named fish name is 19th. \r\nSo 19th is Lake Trout and 27 inches. \r\n21st is 17 inches, only odd left. \r\nDeep Channel is 22 inches. \r\nThe fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls (2).\r\nLittle Curl is less than 17 inches. 16 inches. \r\nAlthough they both jumped and splashed over the water the same way, the Rainbow Mad Ade caught was bigger than his Cut Throat. (5) \r\nSo, Rainbow is 22 inches and Cut Throat 19 inches. \n\r\nSummary:\r\n14th, Elk Hair Caddis, Dolly Varden, 16, Little Curl \r\n15th, Stonefly Nymph, Cutthroat, 19, Bottle Well \r\n17th, Mad Ade's Little Mouse, Monkey Trout, 24, Old Cutbank \r\n18th, Mayfly, Brookside Trout, 8, Dish Creek \r\n19th, Yuk Bug, Lake Trout, 27, Big Rock Isle \r\n20th, Parachute Adams, Rainbow, 22, Deep Channel \r\n21st, Humpy, Humpback Trout, 17, Big Little Falls", "category": "Logic", "date": "08/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade went on an eight day fly fishing trip around the purple ridged mountains of Madadia and got to fish seven days of it last May. On every day, from May 14 to the 21st, except the 16th, when a severe thunderstorm kept him in his tent, he fished around Madadia. Though he caught many fish--all of which he released--each day, one special fish stood out. Each special fish was of a different variety: Monkey Trout, Brookside Trout, Cut Throat, Dolly Varden, Humpback, Lake Trout, and Rainbow, and a different size: 8 inches, 16 inches, 17 inches, 19 inches, 22 inches, 24 inches, and 27 inches. Every day, Mad Ade tried a different secret fishing spot: Big Little Falls, Bottle Well, Deep Channel, Old Cutbank, Big Rock Isle, Dish Creek, and Little Curl. And each special fish was caught on a different fly that Mad Ade tied himself: a Parachute Adams, an Elk Hair Caddis, a Humpy, a MayFly, Mad Ade's Little Mouse, a Stonefly Nymph, and a Yuk Bug. Three of the flies, Mad Ade's little Mouse, the Yuk Bug, and Stonefly Nymph, were fished as wet flies, the rest were fished as dry flies.\n\n\r\n1) Mad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. His shiny Dolly Varden was not the fish lured from the depths of Bottle Well. Mad Ade caught either the smallest or his second to largest fish on his third fishing day. \r\n2) Mad Ade caught a fish off Big Rock Isle on the 19th. He fought either the Humpback or the 24 inch monster on the 21st. On the fourth day of his trip, Mad Ade landed a fish over twenty inches long by the Old Cutbank on a wet fly. The fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls. \r\n3) Mad Ade caught the 24 inch fish on his Little Mouse after he caught the Dolly Varden, but before he hooked a real jumper with his Parachute Adams. Because he preferred dry flies, Mad Ade only used dry flies after using a wet fly on the 19th. Mad Ade used a Mayfly to fish Dish Creek. Mad Ade caught his fish on the Mayfly three calendar days (two fishing days) after he caught a fish with the Stonefly Nymph. \r\n4) Mad Ade's five mile hike, along a mountain trail to Big Little Falls, paid off on his last day with a prized Humpback trout. At least four fishing days passed between the time that Mad Ade used the Stonefly Nymph and his Humpy. The Monkey Trout Mad Ade caught on the 17th was longer than the Rainbow he caught, but smaller than his Lake Trout. \r\n5) The deep hole of Bottle Well yielded Mad Ade a 19 incher on the first or second day of his trip. With one exception, Mad Ade caught fish of even sizes on even number days and fish of odd sizes on odd days. Although they both jumped and splashed over the water the same way, the Rainbow Mad Ade caught was bigger than his Cut Throat.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade caught a fish off Big Rock Isle on the 19th (2).\r\nThe Monkey Trout Mad Ade caught on the 17th (4).\r\nMad Ade caught either the smallest or his second to largest fish on his third fishing day. (1) \r\n17th is 8 or 24.\r\nOn the fourth day of his trip, Mad Ade landed a fish over twenty inches long by the Old Cutbank on a wet fly. (2) \r\n17th is 24 and Cutbank.\r\nMad Ade caught the 24 inch fish on his Little Mouse (3).\r\nWith one exception, Mad Ade caught fish of even sizes on even number days and fish of odd sizes on odd days. (5) \r\nHe fought either the Humpback or the 24 inch monster on the 21st. \r\nHumpback is 21st. (2) \r\nMad Ade's five mile hike, along a mountain trail to Big Little Falls, paid off on his last day with a prized Humpback trout. (5) \r\nHumpback is Big Little Falls. \r\nThe deep hole of Bottle Well yielded Mad Ade a 19 incher on the first or second day of his trip. (5) \r\nFirst day is 14th, so 19 incher had to be second day, 15th. \r\n15th then is Bottle. \r\nMad Ade caught the 24 inch fish on his Little Mouse after he caught the Dolly Varden (3).\r\nMouse is 24 inch fish on 17th. \r\nDolly is 14th or 15th. \r\nMad Ade caught his fish on the Mayfly three calendar days (two fishing days) after he caught a fish with the Stonefly nymph. (3) \r\nMayfly can only be 18th, as Mouse is 17th. \r\nStonefly is 15th.\r\nMad Ade used a Mayfly to fish Dish Creek. \r\nAt least four fishing days passed between the time that Mad Ade used the Stonefly Nymph and his Humpy. (4) \r\nStonefly is 15th, so Humpy is 21st.\r\nMad Ade only used dry flies after using a wet fly on the 19th. (3) \r\nOnly wet fly left is Yuk Bug, so Yuk Bug is 19th. \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nElk Hair Caddis can only be 14th. \r\nParachute Adams, the only fly left, is 20th. \r\nHis shiny Dolly Varden was not the fish lured from the depths of Bottle Well. Bottle is 15th, so Dolly is 14th. (1) \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nBrookside, 8 inches, (even) can only be Mayfly or Adams. \r\nThe fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls. (2) \r\nAdams can only be Little Curl or Deep Channel. It's not Channel (1) and not Little Curl (2), so Brookside is Dish Creek. \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nSo, Deep Channel is 20th, and 14th is Little Curl (last one). \r\nThe Monkey Trout Mad Ade caught on the 17th was longer than the Rainbow he caught, but smaller than his Lake Trout. (4) 17th is Monkey, 24 inches, so Lake can only be 27. Only odd without a named fish name is 19th. \r\nSo 19th is Lake Trout and 27 inches. \r\n21st is 17 inches, only odd left. \r\nDeep Channel is 22 inches. \r\nThe fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls (2).\r\nLittle Curl is less than 17 inches. 16 inches. \r\nAlthough they both jumped and splashed over the water the same way, the Rainbow Mad Ade caught was bigger than his Cut Throat. (5) \r\nSo, Rainbow is 22 inches and Cut Throat 19 inches. \n\r\nSummary:\r\n14th, Elk Hair Caddis, Dolly Varden, 16, Little Curl \r\n15th, Stonefly Nymph, Cutthroat, 19, Bottle Well \r\n17th, Mad Ade's Little Mouse, Monkey Trout, 24, Old Cutbank \r\n18th, Mayfly, Brookside Trout, 8, Dish Creek \r\n19th, Yuk Bug, Lake Trout, 27, Big Rock Isle \r\n20th, Parachute Adams, Rainbow, 22, Deep Channel \r\n21st, Humpy, Humpback Trout, 17, Big Little Falls\n<|im_start|>answer\nMad Ade caught a fish off Big Rock Isle on the 19th (2).\r\nThe Monkey Trout Mad Ade caught on the 17th (4).\r\nMad Ade caught either the smallest or his second to largest fish on his third fishing day. (1) \r\n17th is 8 or 24.\r\nOn the fourth day of his trip, Mad Ade landed a fish over twenty inches long by the Old Cutbank on a wet fly. (2) \r\n17th is 24 and Cutbank.\r\nMad Ade caught the 24 inch fish on his Little Mouse (3).\r\nWith one exception, Mad Ade caught fish of even sizes on even number days and fish of odd sizes on odd days. (5) \r\nHe fought either the Humpback or the 24 inch monster on the 21st. \r\nHumpback is 21st. (2) \r\nMad Ade's five mile hike, along a mountain trail to Big Little Falls, paid off on his last day with a prized Humpback trout. (5) \r\nHumpback is Big Little Falls. \r\nThe deep hole of Bottle Well yielded Mad Ade a 19 incher on the first or second day of his trip. (5) \r\nFirst day is 14th, so 19 incher had to be second day, 15th. \r\n15th then is Bottle. \r\nMad Ade caught the 24 inch fish on his Little Mouse after he caught the Dolly Varden (3).\r\nMouse is 24 inch fish on 17th. \r\nDolly is 14th or 15th. \r\nMad Ade caught his fish on the Mayfly three calendar days (two fishing days) after he caught a fish with the Stonefly nymph. (3) \r\nMayfly can only be 18th, as Mouse is 17th. \r\nStonefly is 15th.\r\nMad Ade used a Mayfly to fish Dish Creek. \r\nAt least four fishing days passed between the time that Mad Ade used the Stonefly Nymph and his Humpy. (4) \r\nStonefly is 15th, so Humpy is 21st.\r\nMad Ade only used dry flies after using a wet fly on the 19th. (3) \r\nOnly wet fly left is Yuk Bug, so Yuk Bug is 19th. \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nElk Hair Caddis can only be 14th. \r\nParachute Adams, the only fly left, is 20th. \r\nHis shiny Dolly Varden was not the fish lured from the depths of Bottle Well. Bottle is 15th, so Dolly is 14th. (1) \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nBrookside, 8 inches, (even) can only be Mayfly or Adams. \r\nThe fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls. (2) \r\nAdams can only be Little Curl or Deep Channel. It's not Channel (1) and not Little Curl (2), so Brookside is Dish Creek. \r\nMad Ade caught the smallest of his special fish, a little Brookside, after he caught the fish on his Elk Hair Caddis, but before he caught the fish in Deep Channel. (1) \r\nSo, Deep Channel is 20th, and 14th is Little Curl (last one). \r\nThe Monkey Trout Mad Ade caught on the 17th was longer than the Rainbow he caught, but smaller than his Lake Trout. (4) 17th is Monkey, 24 inches, so Lake can only be 27. Only odd without a named fish name is 19th. \r\nSo 19th is Lake Trout and 27 inches. \r\n21st is 17 inches, only odd left. \r\nDeep Channel is 22 inches. \r\nThe fish Mad Ade landed with a net at Little Curl was larger than the one he worked onto shore at Dish Creek, but it was not as large as the one he lifted from the water at Big Little Falls (2).\r\nLittle Curl is less than 17 inches. 16 inches. \r\nAlthough they both jumped and splashed over the water the same way, the Rainbow Mad Ade caught was bigger than his Cut Throat. (5) \r\nSo, Rainbow is 22 inches and Cut Throat 19 inches. \n\r\nSummary:\r\n14th, Elk Hair Caddis, Dolly Varden, 16, Little Curl \r\n15th, Stonefly Nymph, Cutthroat, 19, Bottle Well \r\n17th, Mad Ade's Little Mouse, Monkey Trout, 24, Old Cutbank \r\n18th, Mayfly, Brookside Trout, 8, Dish Creek \r\n19th, Yuk Bug, Lake Trout, 27, Big Rock Isle \r\n20th, Parachute Adams, Rainbow, 22, Deep Channel \r\n21st, Humpy, Humpback Trout, 17, Big Little Falls\n<|im_end|>" }, { "id": "#28886", "title": "Overtime", "fun": 2.2, "difficulty": 1.4, "author": "hamburger", "desc": "Jimmy worked many overtime hours this week, and his normal weekly pay tripled. He received an additional $700. What is his normal salary?", "hint": "No hint available.", "answer": "$350\n\r\nUse the equation:\n\r\n3x=x+700 (where X is his normal pay) \n\r\nSubtract an x from each side and you should get 2X=700.\n\r\nDivide by 2, and we see his weekly salary is $350.", "category": "Math", "date": "03/03/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJimmy worked many overtime hours this week, and his normal weekly pay tripled. He received an additional $700. What is his normal salary?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$350\n\r\nUse the equation:\n\r\n3x=x+700 (where X is his normal pay) \n\r\nSubtract an x from each side and you should get 2X=700.\n\r\nDivide by 2, and we see his weekly salary is $350.\n<|im_start|>answer\n$350\n\r\nUse the equation:\n\r\n3x=x+700 (where X is his normal pay) \n\r\nSubtract an x from each side and you should get 2X=700.\n\r\nDivide by 2, and we see his weekly salary is $350.\n<|im_end|>" }, { "id": "#4584", "title": "Three Numbers", "fun": 2.2, "difficulty": 1.33, "author": "mad-ade", "desc": "Find three whole, positive numbers that have the same answer\r\nwhen multiplied together as when added together.", "hint": "No hint available.", "answer": "1,2,3\n\r\n1 x 2 x 3 = 6\r\n and\r\n1 + 2 + 3 = 6", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind three whole, positive numbers that have the same answer\r\nwhen multiplied together as when added together.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1,2,3\n\r\n1 x 2 x 3 = 6\r\n and\r\n1 + 2 + 3 = 6\n<|im_start|>answer\n1,2,3\n\r\n1 x 2 x 3 = 6\r\n and\r\n1 + 2 + 3 = 6\n<|im_end|>" }, { "id": "#3707", "title": "Three Dads", "fun": 2.2, "difficulty": 2.39, "author": "fruitloop986", "desc": "I have 3 dads and 4 sisters. My immediate family (living in my house) consists of 7. Two of my sisters only have 2 dads. How is this possible?", "hint": "My nephew lives with me and I'm the middle child.", "answer": "I have a biological dad, who I don't know. An adopted dad- my sisters' dad and a step dad- who lives with me. My two younger sisters never knew my biological dad. My oldest sister (19) lives by herself. Her son lives with me, my 3 other sisters, my mom, and step dad.", "category": "Logic", "date": "04/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have 3 dads and 4 sisters. My immediate family (living in my house) consists of 7. Two of my sisters only have 2 dads. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI have a biological dad, who I don't know. An adopted dad- my sisters' dad and a step dad- who lives with me. My two younger sisters never knew my biological dad. My oldest sister (19) lives by herself. Her son lives with me, my 3 other sisters, my mom, and step dad.\n<|im_start|>answer\nI have a biological dad, who I don't know. An adopted dad- my sisters' dad and a step dad- who lives with me. My two younger sisters never knew my biological dad. My oldest sister (19) lives by herself. Her son lives with me, my 3 other sisters, my mom, and step dad.\n<|im_end|>" }, { "id": "#9477", "title": "Rare Snapoker Hands 2", "fun": 2.2, "difficulty": 2.79, "author": "snaps", "desc": "The card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frenetic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nIn a game of Snapoker I was playing the other day, my good friend Kasy managed to grab 13 cards that formed an alternating-colours straight (ie. the odd cards were all red, the evens were all black). How many different ways can a 13-card alternating-colour straight be formed from a Snapoker deck? Note that jokers can not be used in forming a straight.", "hint": "No hint available.", "answer": "There are 32,768 possible ways a 13-card alternating-colour straight can be formed in a Snapoker deck.\n\r\nTo form a 13-card alternating-colour straight in Snapoker the following cards can be used:\r\n2 x red aces\r\n4 x black twos\r\n2 x red threes\r\n2 x black fours\r\n2 x red fives\r\n2 x black sixes\r\n2 x red sevens\r\n2 x black eights\r\n4 x red nines\r\n2 x black tens\r\n2 x red jacks\r\n2 x black queens\r\n2 x red kings\n\r\nTherefore, there are 2x4x2x2x2x2x2x2x4x2x2x2x2 = 32,768 possible 13-card alternating-colour straights that can be formed.", "category": "Math", "date": "12/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe card game Snapoker is a very complex game for four players, requiring the use of two decks of cards with all odd spades, even hearts, prime diamonds (including aces) and non-prime clubs (including aces) removed. Note that jacks are 11, queens are 12, kings are 13. Two jokers are added to the deck and are each worth 15. The cards are dealt among the four players. A hand starts when the dealer shouts \"Let's Snapoker!\" Following a frenetic minute of randomly throwing all cards onto the table, and at the dealer's call of \"Heeeeeeere, piggy, piggy, piggy!\" players are required to grab as many cards as they can. Once all cards have been grabbed, the total value of the cards in each player's hand is added up. Points (4, 3, 2 and 1) are awarded to players on each hand, with the highest card total receiving maximum points. In the event of a tie, the player who can drink a glass of milk through their nose the quickest will receive the greater points. A running score is kept throughout the game. The game is over when someone reaches a total of 518 points or when a fight breaks out, which is a common occurrence.\n\r\nIn a game of Snapoker I was playing the other day, my good friend Kasy managed to grab 13 cards that formed an alternating-colours straight (ie. the odd cards were all red, the evens were all black). How many different ways can a 13-card alternating-colour straight be formed from a Snapoker deck? Note that jokers can not be used in forming a straight.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 32,768 possible ways a 13-card alternating-colour straight can be formed in a Snapoker deck.\n\r\nTo form a 13-card alternating-colour straight in Snapoker the following cards can be used:\r\n2 x red aces\r\n4 x black twos\r\n2 x red threes\r\n2 x black fours\r\n2 x red fives\r\n2 x black sixes\r\n2 x red sevens\r\n2 x black eights\r\n4 x red nines\r\n2 x black tens\r\n2 x red jacks\r\n2 x black queens\r\n2 x red kings\n\r\nTherefore, there are 2x4x2x2x2x2x2x2x4x2x2x2x2 = 32,768 possible 13-card alternating-colour straights that can be formed.\n<|im_start|>answer\nThere are 32,768 possible ways a 13-card alternating-colour straight can be formed in a Snapoker deck.\n\r\nTo form a 13-card alternating-colour straight in Snapoker the following cards can be used:\r\n2 x red aces\r\n4 x black twos\r\n2 x red threes\r\n2 x black fours\r\n2 x red fives\r\n2 x black sixes\r\n2 x red sevens\r\n2 x black eights\r\n4 x red nines\r\n2 x black tens\r\n2 x red jacks\r\n2 x black queens\r\n2 x red kings\n\r\nTherefore, there are 2x4x2x2x2x2x2x2x4x2x2x2x2 = 32,768 possible 13-card alternating-colour straights that can be formed.\n<|im_end|>" }, { "id": "#8566", "title": "College of Kebabology", "fun": 2.2, "difficulty": 1.77, "author": "mad-ade", "desc": "In a certain year, the number of girls who graduated from the Madadian High School was twice the number of boys. If 3/4 of the girls and 5/6 of the boys went to Madadia's college of Kebabology immediately after graduation, what fraction of the graduates that year went to college immediately after graduation?", "hint": "No hint available.", "answer": "Assume that number of boys graduated from the Madadian High School = B \r\nTherefore, number of girls graduated from the Madadian High School = 2*B \n\r\nIt is given that 3/4 of the girls and 5/6 of the boys went to the college of kebabology immediately after graduation. \r\nHence, total students went to the college \r\n= (3/4)(2*B) + (5/6)(B) \r\n= B * (3/2 + 5/6) \r\n= (7/3)B \n\r\nFraction of the graduates that year went to college immediately after graduation \r\n= [(7/3)B] / [3*B] \r\n= 7/9 \n\r\nTherefore, the answer is 7/9", "category": "Math", "date": "11/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a certain year, the number of girls who graduated from the Madadian High School was twice the number of boys. If 3/4 of the girls and 5/6 of the boys went to Madadia's college of Kebabology immediately after graduation, what fraction of the graduates that year went to college immediately after graduation?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAssume that number of boys graduated from the Madadian High School = B \r\nTherefore, number of girls graduated from the Madadian High School = 2*B \n\r\nIt is given that 3/4 of the girls and 5/6 of the boys went to the college of kebabology immediately after graduation. \r\nHence, total students went to the college \r\n= (3/4)(2*B) + (5/6)(B) \r\n= B * (3/2 + 5/6) \r\n= (7/3)B \n\r\nFraction of the graduates that year went to college immediately after graduation \r\n= [(7/3)B] / [3*B] \r\n= 7/9 \n\r\nTherefore, the answer is 7/9\n<|im_start|>answer\nAssume that number of boys graduated from the Madadian High School = B \r\nTherefore, number of girls graduated from the Madadian High School = 2*B \n\r\nIt is given that 3/4 of the girls and 5/6 of the boys went to the college of kebabology immediately after graduation. \r\nHence, total students went to the college \r\n= (3/4)(2*B) + (5/6)(B) \r\n= B * (3/2 + 5/6) \r\n= (7/3)B \n\r\nFraction of the graduates that year went to college immediately after graduation \r\n= [(7/3)B] / [3*B] \r\n= 7/9 \n\r\nTherefore, the answer is 7/9\n<|im_end|>" }, { "id": "#24168", "title": "Old Oak Tree", "fun": 2.2, "difficulty": 2.63, "author": "drussel3", "desc": "Homer had always contemplated the size of the old oak tree in the field behind his house. Standing 5 feet away from the 8 foot high fence in the back of the yard, he could just barely see the top leaves of the tree over the top of the fence. He knew that the tree was 200 feet from the fence. Homer was 6 feet tall, making his line of vision, 67 inches from the ground.\n\r\nEstimate how tall the old oak tree is.", "hint": "TAN A = opposite / adjacent, remember trigonometry", "answer": "tree height = TAN of angle of vision * distance to the tree = 104.7 feet tall\n\r\nFirst you need to figure out the angle of vision. The angle of the line of vision over the fence, is the same angle of vision of the eye to the tree top. Height of eyes (67 inches), height of fence (8 ft = 96 inches), distance to fence (5 ft = 60 in)\n\n\r\nAngle of vision = inverse TAN ( (96 - 67) / 60) = 25.80 degrees\n\r\nDistance to tree = 5 ft + 200 ft = 2460 inches\n\r\nTree height from eye level = TAN (25.80 deg) * 2460 inches = 1189 inches\n\r\nTree height estimate = 1189 inches + 67 inches = 104.7 feet\n\r\nThis is an old lumberjack method of estimating a tree height. With pure math the height of 104.7 feet is correct. With the measurement capabilities available to any lumberjack (or any average Homer) precise measurements are not possible. Thus the need to clarify these calculations as estimates.", "category": "Math", "date": "07/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHomer had always contemplated the size of the old oak tree in the field behind his house. Standing 5 feet away from the 8 foot high fence in the back of the yard, he could just barely see the top leaves of the tree over the top of the fence. He knew that the tree was 200 feet from the fence. Homer was 6 feet tall, making his line of vision, 67 inches from the ground.\n\r\nEstimate how tall the old oak tree is.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\ntree height = TAN of angle of vision * distance to the tree = 104.7 feet tall\n\r\nFirst you need to figure out the angle of vision. The angle of the line of vision over the fence, is the same angle of vision of the eye to the tree top. Height of eyes (67 inches), height of fence (8 ft = 96 inches), distance to fence (5 ft = 60 in)\n\n\r\nAngle of vision = inverse TAN ( (96 - 67) / 60) = 25.80 degrees\n\r\nDistance to tree = 5 ft + 200 ft = 2460 inches\n\r\nTree height from eye level = TAN (25.80 deg) * 2460 inches = 1189 inches\n\r\nTree height estimate = 1189 inches + 67 inches = 104.7 feet\n\r\nThis is an old lumberjack method of estimating a tree height. With pure math the height of 104.7 feet is correct. With the measurement capabilities available to any lumberjack (or any average Homer) precise measurements are not possible. Thus the need to clarify these calculations as estimates.\n<|im_start|>answer\ntree height = TAN of angle of vision * distance to the tree = 104.7 feet tall\n\r\nFirst you need to figure out the angle of vision. The angle of the line of vision over the fence, is the same angle of vision of the eye to the tree top. Height of eyes (67 inches), height of fence (8 ft = 96 inches), distance to fence (5 ft = 60 in)\n\n\r\nAngle of vision = inverse TAN ( (96 - 67) / 60) = 25.80 degrees\n\r\nDistance to tree = 5 ft + 200 ft = 2460 inches\n\r\nTree height from eye level = TAN (25.80 deg) * 2460 inches = 1189 inches\n\r\nTree height estimate = 1189 inches + 67 inches = 104.7 feet\n\r\nThis is an old lumberjack method of estimating a tree height. With pure math the height of 104.7 feet is correct. With the measurement capabilities available to any lumberjack (or any average Homer) precise measurements are not possible. Thus the need to clarify these calculations as estimates.\n<|im_end|>" }, { "id": "#4139", "title": "Shrinking Pizza", "fun": 2.2, "difficulty": 1.6400000000000001, "author": "mad-ade", "desc": "On Monday Mad Ade orders a pizza, to be delivered. When it arrives he eats half straight away. On Tuesday he eats half of what is left, same on Wednesday, Thursday, Friday, Saturday and Sunday, each day eating half of what was left from the day before. By the end of Sunday, how much of the Pizza will Mad Ade have eaten?", "hint": "No hint available.", "answer": "127/128 (99.22%)", "category": "Math", "date": "05/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Monday Mad Ade orders a pizza, to be delivered. When it arrives he eats half straight away. On Tuesday he eats half of what is left, same on Wednesday, Thursday, Friday, Saturday and Sunday, each day eating half of what was left from the day before. By the end of Sunday, how much of the Pizza will Mad Ade have eaten?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n127/128 (99.22%)\n<|im_start|>answer\n127/128 (99.22%)\n<|im_end|>" }, { "id": "#6460", "title": "Six Nines", "fun": 2.2, "difficulty": 2.07, "author": "mad-ade", "desc": "Without introducing \"+\" signs, arrange six \"9's\" in such a way that they add up to 100.", "hint": "No hint available.", "answer": "(999-99)/9 = 900/9 = 100 \n\r\n(99 -(-9/9))* 9/9= (99 -(-1)) * 1 = 100 \n\r\n99 99/99", "category": "Math", "date": "08/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWithout introducing \"+\" signs, arrange six \"9's\" in such a way that they add up to 100.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n(999-99)/9 = 900/9 = 100 \n\r\n(99 -(-9/9))* 9/9= (99 -(-1)) * 1 = 100 \n\r\n99 99/99\n<|im_start|>answer\n(999-99)/9 = 900/9 = 100 \n\r\n(99 -(-9/9))* 9/9= (99 -(-1)) * 1 = 100 \n\r\n99 99/99\n<|im_end|>" }, { "id": "#12637", "title": "Kebab Wrestlers Pool Game", "fun": 2.2, "difficulty": 2.66, "author": "mad-ade", "desc": "Four members of the Madadian pro-celebrity Kebab wrestling team took part in a charity pool match to raise money for new spandex sequined grease proof leotards \n\r\nAl Gore-Rhythm, Annie Buddyhome, Dan Druff and Hayden Seek participated in the POOL competition. \n\r\nFACTS \r\n1, There are total of 15 balls. \n\r\n2, For each ball potted, the player will receive one point. \n\r\n3, They all will play each other once. \n\r\n4, A game will end when all the balls are potted. \n\r\n5, The winner will be the player who scored the most points. \n\r\nOUTCOMES \r\n1, Hayden Seek finished with 18 points. \n\r\n2, Al Gore-Rhythm finished with odd number of points. \n\r\n3, Dan Druff beat Hayden Seek by 5 points in the match between them. \n\r\n4, There was one point difference in match between Annie Buddyhome and Al Gore-Rhythm. \n\r\n5, Al Gore-Rhythm scored twice as many points as Dan Druff in their game. \n\r\n6, Hayden Seek scored one point less against Al Gore-Rhythm than he did against Dan Druff. \n\r\n7, Dan Druff scored 7 points against Annie Buddyhome. \n\r\nWho won the competition? \n\r\nHow many points did each player score?", "hint": "No hint available.", "answer": "1) Hayden Seek finished with 18 points. - This was a given so my answer needs no explanation. \r\n3) Dan Druff beat Hayden Seek by 5 points. - Therefore, the score was 10 Dan Druff and 5 Hayden Seek; because there is only 15 balls which equals 15 points per game \r\nThere was one point difference in match between Annie Buddyhome and Al Gore-Rhythm. - The final score had to be 7 and 8 and since Al Gore-Rhythm finished with an odd score, If you trialed both numbers you will notice Al Gore-Rhythm equaled out to have the 8 points therefore, Annie Buddyhome had the 7 points. \r\nAl Gore-Rhythm scored twice as many points as Dan Druff in their game. - Al Gore-Rhythm equaled 10 points and Dan Druff equaled 5 points so the score would be double winner and half for the loser. \r\nHayden Seek scored one point less against Al Gore-Rhythm than he did against Dan Druff. Since the score was 10/5 with Dan Druff winning, that means that Hayden Seek scored 4 points in this game because of one point less. \r\nDan Druff scored 7 points against Annie Buddyhome- Once again 15 points and the game is over, Dan Druff scores 7 and Annie Buddyhome scores 8. \r\nBy process of elimination; since Hayden Seek scores 18 points total and you can figure out the 5 points against Dan Druff and the 4 points against Al Gore-Rhythm 9 points was the only number that would fit into the equation. \n\r\nThus the scores are Al Gore-Rhythm 8 and Annie Buddyhome 7 \r\nAnnie Buddyhome 8 and Dan Druff 7 \r\nDan Druff 10 and Hayden Seek 5 \r\nHayden Seek 4 and Al Gore-Rhythm 11 \r\nAl Gore-Rhythm 10 and Dan Druff 5 \r\nAnnie Buddyhome 6 and Hayden Seek 9 \n\r\nAl Gore-Rhythm 11+10+8= 29 points (odd) \r\nAnnie Buddyhome 8+7+6=21 points \r\nHayden Seek 5+4+9=18 points (given) \r\nDan Druff 7+10+5=22 points \n\r\nTherefore the conclusion is that Al Gore-Rhythm won with 29 points and Dan Druff came in second place with 22 points. Annie Buddyhome is third place with 21 points and last is Hayden Seek with 18 points.", "category": "Logic", "date": "05/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour members of the Madadian pro-celebrity Kebab wrestling team took part in a charity pool match to raise money for new spandex sequined grease proof leotards \n\r\nAl Gore-Rhythm, Annie Buddyhome, Dan Druff and Hayden Seek participated in the POOL competition. \n\r\nFACTS \r\n1, There are total of 15 balls. \n\r\n2, For each ball potted, the player will receive one point. \n\r\n3, They all will play each other once. \n\r\n4, A game will end when all the balls are potted. \n\r\n5, The winner will be the player who scored the most points. \n\r\nOUTCOMES \r\n1, Hayden Seek finished with 18 points. \n\r\n2, Al Gore-Rhythm finished with odd number of points. \n\r\n3, Dan Druff beat Hayden Seek by 5 points in the match between them. \n\r\n4, There was one point difference in match between Annie Buddyhome and Al Gore-Rhythm. \n\r\n5, Al Gore-Rhythm scored twice as many points as Dan Druff in their game. \n\r\n6, Hayden Seek scored one point less against Al Gore-Rhythm than he did against Dan Druff. \n\r\n7, Dan Druff scored 7 points against Annie Buddyhome. \n\r\nWho won the competition? \n\r\nHow many points did each player score?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Hayden Seek finished with 18 points. - This was a given so my answer needs no explanation. \r\n3) Dan Druff beat Hayden Seek by 5 points. - Therefore, the score was 10 Dan Druff and 5 Hayden Seek; because there is only 15 balls which equals 15 points per game \r\nThere was one point difference in match between Annie Buddyhome and Al Gore-Rhythm. - The final score had to be 7 and 8 and since Al Gore-Rhythm finished with an odd score, If you trialed both numbers you will notice Al Gore-Rhythm equaled out to have the 8 points therefore, Annie Buddyhome had the 7 points. \r\nAl Gore-Rhythm scored twice as many points as Dan Druff in their game. - Al Gore-Rhythm equaled 10 points and Dan Druff equaled 5 points so the score would be double winner and half for the loser. \r\nHayden Seek scored one point less against Al Gore-Rhythm than he did against Dan Druff. Since the score was 10/5 with Dan Druff winning, that means that Hayden Seek scored 4 points in this game because of one point less. \r\nDan Druff scored 7 points against Annie Buddyhome- Once again 15 points and the game is over, Dan Druff scores 7 and Annie Buddyhome scores 8. \r\nBy process of elimination; since Hayden Seek scores 18 points total and you can figure out the 5 points against Dan Druff and the 4 points against Al Gore-Rhythm 9 points was the only number that would fit into the equation. \n\r\nThus the scores are Al Gore-Rhythm 8 and Annie Buddyhome 7 \r\nAnnie Buddyhome 8 and Dan Druff 7 \r\nDan Druff 10 and Hayden Seek 5 \r\nHayden Seek 4 and Al Gore-Rhythm 11 \r\nAl Gore-Rhythm 10 and Dan Druff 5 \r\nAnnie Buddyhome 6 and Hayden Seek 9 \n\r\nAl Gore-Rhythm 11+10+8= 29 points (odd) \r\nAnnie Buddyhome 8+7+6=21 points \r\nHayden Seek 5+4+9=18 points (given) \r\nDan Druff 7+10+5=22 points \n\r\nTherefore the conclusion is that Al Gore-Rhythm won with 29 points and Dan Druff came in second place with 22 points. Annie Buddyhome is third place with 21 points and last is Hayden Seek with 18 points.\n<|im_start|>answer\n1) Hayden Seek finished with 18 points. - This was a given so my answer needs no explanation. \r\n3) Dan Druff beat Hayden Seek by 5 points. - Therefore, the score was 10 Dan Druff and 5 Hayden Seek; because there is only 15 balls which equals 15 points per game \r\nThere was one point difference in match between Annie Buddyhome and Al Gore-Rhythm. - The final score had to be 7 and 8 and since Al Gore-Rhythm finished with an odd score, If you trialed both numbers you will notice Al Gore-Rhythm equaled out to have the 8 points therefore, Annie Buddyhome had the 7 points. \r\nAl Gore-Rhythm scored twice as many points as Dan Druff in their game. - Al Gore-Rhythm equaled 10 points and Dan Druff equaled 5 points so the score would be double winner and half for the loser. \r\nHayden Seek scored one point less against Al Gore-Rhythm than he did against Dan Druff. Since the score was 10/5 with Dan Druff winning, that means that Hayden Seek scored 4 points in this game because of one point less. \r\nDan Druff scored 7 points against Annie Buddyhome- Once again 15 points and the game is over, Dan Druff scores 7 and Annie Buddyhome scores 8. \r\nBy process of elimination; since Hayden Seek scores 18 points total and you can figure out the 5 points against Dan Druff and the 4 points against Al Gore-Rhythm 9 points was the only number that would fit into the equation. \n\r\nThus the scores are Al Gore-Rhythm 8 and Annie Buddyhome 7 \r\nAnnie Buddyhome 8 and Dan Druff 7 \r\nDan Druff 10 and Hayden Seek 5 \r\nHayden Seek 4 and Al Gore-Rhythm 11 \r\nAl Gore-Rhythm 10 and Dan Druff 5 \r\nAnnie Buddyhome 6 and Hayden Seek 9 \n\r\nAl Gore-Rhythm 11+10+8= 29 points (odd) \r\nAnnie Buddyhome 8+7+6=21 points \r\nHayden Seek 5+4+9=18 points (given) \r\nDan Druff 7+10+5=22 points \n\r\nTherefore the conclusion is that Al Gore-Rhythm won with 29 points and Dan Druff came in second place with 22 points. Annie Buddyhome is third place with 21 points and last is Hayden Seek with 18 points.\n<|im_end|>" }, { "id": "#11860", "title": "My number is...", "fun": 2.2, "difficulty": 1.55, "author": "Jakchole", "desc": "My old phone number was (314) 159-2653. Why is this so special?", "hint": "No hint available.", "answer": "It's the first nine numbers of pi: 3.141592653...", "category": "Math", "date": "04/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy old phone number was (314) 159-2653. Why is this so special?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt's the first nine numbers of pi: 3.141592653...\n<|im_start|>answer\nIt's the first nine numbers of pi: 3.141592653...\n<|im_end|>" }, { "id": "#19380", "title": "More Mad Ade Chess Problems", "fun": 2.2, "difficulty": 2.36, "author": "Mad-Ade", "desc": "Mad Ade has placed five Queens on a chessboard, such that every square including those occupied by the Queens are under attack.\r\nImagine the chessboard is set out with reference points 1 to 8 on the vertical and A to H across the horizontal.\r\nAt what positions would the five Queens need to be?", "hint": "No hint available.", "answer": "A5, D5, E5, F5, H1", "category": "Logic", "date": "11/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has placed five Queens on a chessboard, such that every square including those occupied by the Queens are under attack.\r\nImagine the chessboard is set out with reference points 1 to 8 on the vertical and A to H across the horizontal.\r\nAt what positions would the five Queens need to be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA5, D5, E5, F5, H1\n<|im_start|>answer\nA5, D5, E5, F5, H1\n<|im_end|>" }, { "id": "#4527", "title": "Cats and Dogs", "fun": 2.2, "difficulty": 1.45, "author": "mad-ade", "desc": "Mad Ade's family has dogs and cats as its pets. At every meal the pets eat 32 cookies. The dogs eat 5 cookies each and the cats eat 4 cookies each. \n\r\nHow many dogs and how many cats does Mad Ade's family have?", "hint": "No hint available.", "answer": "4 dogs (eating 4 x 5 or 20 cookies) and \r\n3 cats (eating 4 x 3 or 12 cookies).", "category": "Math", "date": "06/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's family has dogs and cats as its pets. At every meal the pets eat 32 cookies. The dogs eat 5 cookies each and the cats eat 4 cookies each. \n\r\nHow many dogs and how many cats does Mad Ade's family have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 dogs (eating 4 x 5 or 20 cookies) and \r\n3 cats (eating 4 x 3 or 12 cookies).\n<|im_start|>answer\n4 dogs (eating 4 x 5 or 20 cookies) and \r\n3 cats (eating 4 x 3 or 12 cookies).\n<|im_end|>" }, { "id": "#20890", "title": "The Flag Pole", "fun": 2.2, "difficulty": 2.86, "author": "Sane", "desc": "Oh no! Our flag has fallen down from the flag pole (stupid cheap string)! Quick, we need to figure out how much string we need to get it back up there...\n\r\nThe problem is, I don't remember its exact length! \n\r\nAll I can remember is that the pole was built to be exactly 14 times the height of the flag. \r\nThe flag's height is equal to the ground to the pulley system. \r\nThe string wraps evenly around the pole 4 times.\r\nThe string only goes up from the pulley system to the bottom of the flag (the returning string is built into the pole).\r\nThe pulley system is attached 1 meter off the ground.\r\nOh yes, and the diameter of the pole is 10cm.\n\r\nSo quickly! We don't have much time until everyone sees, how much string do we need?\n\n\r\nConversions:\n\r\n100cm = 1m\r\n2.54cm = 1 inch", "hint": "The string covers 12 meters of distance in 4 rotations.\n\r\nUse the Pythagorean theorem.", "answer": "If the pulley system is attached 1 meter off the ground and the flag's height is equal to the ground to the pulley system, then the flag must be 1 meter high. If the string only goes up from the pulley system to the bottom of the flag and the flag pole is 14 meters in height, then the string must cover 12 meters in total (14-1-1). \n\r\nIf the diameter of the pole is 10cm and the height covered is 12 meters (1200cm), then, unwrapped in to a rectangle, it would be pi(10) (since the circumference of a circle is pi{d}) by 1200 cm rectangle. \n\r\nIf the string wraps around in 4 even rotations, that means the rectangle divided on the y plane into 4 equal sections would represent one rotation per section. Finding the hypotenuse of each section (a^2 + b^2 = c^2) would then yield the distance covered per rotation. \n\r\nThis may be better represented with the following diagram: \r\n._________ \r\n|________/| -- The Unwrapped Pole -- \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| 1200 CM \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\npi(10) CM \n\r\n._________ \r\n|________/| -- ONE SECTION -- \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| 300 CM \r\n|___/_____| \r\n|__/______| \r\n|_/_______| <---- The string is the hypotenuse of this right angled triangle\r\n|/________| \r\npi(10) CM \n\r\nThe string's distance in one rotation would be expressed by the following equation: \n\r\na^2 + b^2 = c^2 \r\nc = [300^2 + pi(10)^2]^1/2 \r\nTherefore, in 4 rotations it would be the above * 4. \n\r\nThe final equation is thus expressed as:\n\r\nlet a represent the total height of the pole, then f represent the height of the flag, then rot represent the number of rotations, then p represent the height of the pulley, then d represent the diameter of the pole \n\r\ns = rot * [ ({a-f-p}/4)^2 + d(pi)^2 ]^½ \r\n= 4 * [ ({1400-100-100}/4) ^ 2 + 10(pi)^2 ]^½ \r\n= 4 * [ 90 000 + 10(pi)^2 ]^½ \r\n= 1206.561796 \n\r\nTherefore, the string covers approximately 1206.561796 cm in 12 meters when there are 4 even rotations. \n\r\n( Or: The string = number of rotations {#to multiply by the amount of distance covered in ONE rotation} [ ([total distance covered]/4 {#to equal the height in one rotation} ) ^ 2 + circumference ^ 2 {#to equal the width in one rotation ] ^ square root {#to calculate the distance of the string in one rotation} )\n\r\n{#} = comment", "category": "Math", "date": "02/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOh no! Our flag has fallen down from the flag pole (stupid cheap string)! Quick, we need to figure out how much string we need to get it back up there...\n\r\nThe problem is, I don't remember its exact length! \n\r\nAll I can remember is that the pole was built to be exactly 14 times the height of the flag. \r\nThe flag's height is equal to the ground to the pulley system. \r\nThe string wraps evenly around the pole 4 times.\r\nThe string only goes up from the pulley system to the bottom of the flag (the returning string is built into the pole).\r\nThe pulley system is attached 1 meter off the ground.\r\nOh yes, and the diameter of the pole is 10cm.\n\r\nSo quickly! We don't have much time until everyone sees, how much string do we need?\n\n\r\nConversions:\n\r\n100cm = 1m\r\n2.54cm = 1 inch\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the pulley system is attached 1 meter off the ground and the flag's height is equal to the ground to the pulley system, then the flag must be 1 meter high. If the string only goes up from the pulley system to the bottom of the flag and the flag pole is 14 meters in height, then the string must cover 12 meters in total (14-1-1). \n\r\nIf the diameter of the pole is 10cm and the height covered is 12 meters (1200cm), then, unwrapped in to a rectangle, it would be pi(10) (since the circumference of a circle is pi{d}) by 1200 cm rectangle. \n\r\nIf the string wraps around in 4 even rotations, that means the rectangle divided on the y plane into 4 equal sections would represent one rotation per section. Finding the hypotenuse of each section (a^2 + b^2 = c^2) would then yield the distance covered per rotation. \n\r\nThis may be better represented with the following diagram: \r\n._________ \r\n|________/| -- The Unwrapped Pole -- \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| 1200 CM \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\npi(10) CM \n\r\n._________ \r\n|________/| -- ONE SECTION -- \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| 300 CM \r\n|___/_____| \r\n|__/______| \r\n|_/_______| <---- The string is the hypotenuse of this right angled triangle\r\n|/________| \r\npi(10) CM \n\r\nThe string's distance in one rotation would be expressed by the following equation: \n\r\na^2 + b^2 = c^2 \r\nc = [300^2 + pi(10)^2]^1/2 \r\nTherefore, in 4 rotations it would be the above * 4. \n\r\nThe final equation is thus expressed as:\n\r\nlet a represent the total height of the pole, then f represent the height of the flag, then rot represent the number of rotations, then p represent the height of the pulley, then d represent the diameter of the pole \n\r\ns = rot * [ ({a-f-p}/4)^2 + d(pi)^2 ]^½ \r\n= 4 * [ ({1400-100-100}/4) ^ 2 + 10(pi)^2 ]^½ \r\n= 4 * [ 90 000 + 10(pi)^2 ]^½ \r\n= 1206.561796 \n\r\nTherefore, the string covers approximately 1206.561796 cm in 12 meters when there are 4 even rotations. \n\r\n( Or: The string = number of rotations {#to multiply by the amount of distance covered in ONE rotation} [ ([total distance covered]/4 {#to equal the height in one rotation} ) ^ 2 + circumference ^ 2 {#to equal the width in one rotation ] ^ square root {#to calculate the distance of the string in one rotation} )\n\r\n{#} = comment\n<|im_start|>answer\nIf the pulley system is attached 1 meter off the ground and the flag's height is equal to the ground to the pulley system, then the flag must be 1 meter high. If the string only goes up from the pulley system to the bottom of the flag and the flag pole is 14 meters in height, then the string must cover 12 meters in total (14-1-1). \n\r\nIf the diameter of the pole is 10cm and the height covered is 12 meters (1200cm), then, unwrapped in to a rectangle, it would be pi(10) (since the circumference of a circle is pi{d}) by 1200 cm rectangle. \n\r\nIf the string wraps around in 4 even rotations, that means the rectangle divided on the y plane into 4 equal sections would represent one rotation per section. Finding the hypotenuse of each section (a^2 + b^2 = c^2) would then yield the distance covered per rotation. \n\r\nThis may be better represented with the following diagram: \r\n._________ \r\n|________/| -- The Unwrapped Pole -- \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| 1200 CM \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\n|________/| \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| \r\n|___/_____| \r\n|__/______| \r\n|_/_______| \r\n|/________| \r\npi(10) CM \n\r\n._________ \r\n|________/| -- ONE SECTION -- \r\n|_______/_| \r\n|______/__| \r\n|_____/___| \r\n|____/____| 300 CM \r\n|___/_____| \r\n|__/______| \r\n|_/_______| <---- The string is the hypotenuse of this right angled triangle\r\n|/________| \r\npi(10) CM \n\r\nThe string's distance in one rotation would be expressed by the following equation: \n\r\na^2 + b^2 = c^2 \r\nc = [300^2 + pi(10)^2]^1/2 \r\nTherefore, in 4 rotations it would be the above * 4. \n\r\nThe final equation is thus expressed as:\n\r\nlet a represent the total height of the pole, then f represent the height of the flag, then rot represent the number of rotations, then p represent the height of the pulley, then d represent the diameter of the pole \n\r\ns = rot * [ ({a-f-p}/4)^2 + d(pi)^2 ]^½ \r\n= 4 * [ ({1400-100-100}/4) ^ 2 + 10(pi)^2 ]^½ \r\n= 4 * [ 90 000 + 10(pi)^2 ]^½ \r\n= 1206.561796 \n\r\nTherefore, the string covers approximately 1206.561796 cm in 12 meters when there are 4 even rotations. \n\r\n( Or: The string = number of rotations {#to multiply by the amount of distance covered in ONE rotation} [ ([total distance covered]/4 {#to equal the height in one rotation} ) ^ 2 + circumference ^ 2 {#to equal the width in one rotation ] ^ square root {#to calculate the distance of the string in one rotation} )\n\r\n{#} = comment\n<|im_end|>" }, { "id": "#8733", "title": "Cone Comparisons", "fun": 2.2, "difficulty": 2.15, "author": "lesternoronha1", "desc": "If the heights of two cones are in the ratio of 1:3 and their diameters in the ratio 3:5, respectively, find the ratio of their volumes.\n\r\nThe hint will give you the equation for the volume of a cone if you don't know it.", "hint": "The volume of a cone is:\n\r\nV = 1/3 * pi * r^2 * h", "answer": "Ratio of their volumes = 3:25.\n\r\nThe volume of cone 1 is:\n\r\nV(1) = 1/3 * pi * r(1)^2 * h(1)\n\r\nExpressed in terms of r(1) and h(1), the volume of cone 2 is:\n\r\nV(2) = 1/3 * pi * (5/3*r(1))^2 * (3*h(1))\n\r\nIf you divide the first equation by the second, you get:\n\r\nV(1)/V(2) = 9/25 * 1/3 (all other terms cancel)\n\r\nV(1) / V(2) = 3/25", "category": "Math", "date": "11/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the heights of two cones are in the ratio of 1:3 and their diameters in the ratio 3:5, respectively, find the ratio of their volumes.\n\r\nThe hint will give you the equation for the volume of a cone if you don't know it.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRatio of their volumes = 3:25.\n\r\nThe volume of cone 1 is:\n\r\nV(1) = 1/3 * pi * r(1)^2 * h(1)\n\r\nExpressed in terms of r(1) and h(1), the volume of cone 2 is:\n\r\nV(2) = 1/3 * pi * (5/3*r(1))^2 * (3*h(1))\n\r\nIf you divide the first equation by the second, you get:\n\r\nV(1)/V(2) = 9/25 * 1/3 (all other terms cancel)\n\r\nV(1) / V(2) = 3/25\n<|im_start|>answer\nRatio of their volumes = 3:25.\n\r\nThe volume of cone 1 is:\n\r\nV(1) = 1/3 * pi * r(1)^2 * h(1)\n\r\nExpressed in terms of r(1) and h(1), the volume of cone 2 is:\n\r\nV(2) = 1/3 * pi * (5/3*r(1))^2 * (3*h(1))\n\r\nIf you divide the first equation by the second, you get:\n\r\nV(1)/V(2) = 9/25 * 1/3 (all other terms cancel)\n\r\nV(1) / V(2) = 3/25\n<|im_end|>" }, { "id": "#40720", "title": "Countown #1", "fun": 2.2, "difficulty": 1.93, "author": "MazzaTravels", "desc": "50 10 10 8 6 3\n\r\nUsing all the numbers above just once, can you make the number 832?", "hint": "No hint available.", "answer": "Solution:\r\n((10 + 10) x 3 + (50 - 6)) x 8 = 832", "category": "Math", "date": "02/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n50 10 10 8 6 3\n\r\nUsing all the numbers above just once, can you make the number 832?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSolution:\r\n((10 + 10) x 3 + (50 - 6)) x 8 = 832\n<|im_start|>answer\nSolution:\r\n((10 + 10) x 3 + (50 - 6)) x 8 = 832\n<|im_end|>" }, { "id": "#7635", "title": "Bank Man", "fun": 2.2, "difficulty": 2.42, "author": "bluelightnign", "desc": "There are 10 people who could be the owner of the bank. They all sit in separate chairs across a long table facing north. The table is made of aluminium. The owner of the bank sits next to M. M sits on the left side of the banker. M sits next to C. C sits 4 places to the left of L. L sits next to O and rarely talks to S, E or Z, because they hate him and because they sit on the far right of the bank. O does not sit next to the owner of the bank. The two people left are F and T. T hates the owner of the bank and is considering resigning. Give the names of all the bankers from left to right.", "hint": "Think from the banker's point of view and draw a diagram.", "answer": "TCMBFLOSEZ.", "category": "Logic", "date": "09/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 10 people who could be the owner of the bank. They all sit in separate chairs across a long table facing north. The table is made of aluminium. The owner of the bank sits next to M. M sits on the left side of the banker. M sits next to C. C sits 4 places to the left of L. L sits next to O and rarely talks to S, E or Z, because they hate him and because they sit on the far right of the bank. O does not sit next to the owner of the bank. The two people left are F and T. T hates the owner of the bank and is considering resigning. Give the names of all the bankers from left to right.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTCMBFLOSEZ.\n<|im_start|>answer\nTCMBFLOSEZ.\n<|im_end|>" }, { "id": "#19087", "title": "Little Cubes", "fun": 2.2, "difficulty": 2.12, "author": "ched4r", "desc": "You have 2 identical cubes. You cut the first cube into smaller, equally sized cubes and leave the second cube as it is.\n\r\nYou have two options: to paint all the small cubes with silver OR the remaining big cube with gold. Gold paint is five times more expensive than silver paint.\n\r\nWhich of the two options is cheaper, if the first cube is cut into\n\r\na) 27 b) 125 c) 1000 small cubes?", "hint": "To get the amount of paint needed calculate the surface areas of the small cubes and the big cube.\n\r\nIf the length of the big cube's side is x, its surface area is 6 * x^2.\n\r\nIf a big cube is cut into 3x3x3 = 27 small cubes, the length of a small cube's side is x/3.", "answer": "a) Paint the small cubes.\r\nb) Choose whichever option you wish, they're both equally expensive.\r\nc) Paint the big cube.\n\r\nIf you have N small cubes and a big cube's side length is X, the side length of a small cube is X divided by the cube root of N.\n\r\nThe big cube's surface area is \r\n6X^2\r\nThe small cubes' total surface area is N*6*(X/cbrt(N))^2\n\r\nSo if you have 27 small cubes, their total surface area is\r\n27*6*(X/cbrt(27))^2\r\n= 162*(X^2/3^2)\r\n= 162X^2 / 9 \r\n= 18X^2\n\r\nMultiply the big cube's surface area with 5 (gold paint is 5 times more expensive than silver)\n\r\nBig cube \"price\" compared to the small cubes' price\n\r\na) 30X^2 > 18X^2\n\r\nb) 30X^2 = 30X^2\n\r\nc) 30X^2 < 60X^2", "category": "Math", "date": "10/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have 2 identical cubes. You cut the first cube into smaller, equally sized cubes and leave the second cube as it is.\n\r\nYou have two options: to paint all the small cubes with silver OR the remaining big cube with gold. Gold paint is five times more expensive than silver paint.\n\r\nWhich of the two options is cheaper, if the first cube is cut into\n\r\na) 27 b) 125 c) 1000 small cubes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) Paint the small cubes.\r\nb) Choose whichever option you wish, they're both equally expensive.\r\nc) Paint the big cube.\n\r\nIf you have N small cubes and a big cube's side length is X, the side length of a small cube is X divided by the cube root of N.\n\r\nThe big cube's surface area is \r\n6X^2\r\nThe small cubes' total surface area is N*6*(X/cbrt(N))^2\n\r\nSo if you have 27 small cubes, their total surface area is\r\n27*6*(X/cbrt(27))^2\r\n= 162*(X^2/3^2)\r\n= 162X^2 / 9 \r\n= 18X^2\n\r\nMultiply the big cube's surface area with 5 (gold paint is 5 times more expensive than silver)\n\r\nBig cube \"price\" compared to the small cubes' price\n\r\na) 30X^2 > 18X^2\n\r\nb) 30X^2 = 30X^2\n\r\nc) 30X^2 < 60X^2\n<|im_start|>answer\na) Paint the small cubes.\r\nb) Choose whichever option you wish, they're both equally expensive.\r\nc) Paint the big cube.\n\r\nIf you have N small cubes and a big cube's side length is X, the side length of a small cube is X divided by the cube root of N.\n\r\nThe big cube's surface area is \r\n6X^2\r\nThe small cubes' total surface area is N*6*(X/cbrt(N))^2\n\r\nSo if you have 27 small cubes, their total surface area is\r\n27*6*(X/cbrt(27))^2\r\n= 162*(X^2/3^2)\r\n= 162X^2 / 9 \r\n= 18X^2\n\r\nMultiply the big cube's surface area with 5 (gold paint is 5 times more expensive than silver)\n\r\nBig cube \"price\" compared to the small cubes' price\n\r\na) 30X^2 > 18X^2\n\r\nb) 30X^2 = 30X^2\n\r\nc) 30X^2 < 60X^2\n<|im_end|>" }, { "id": "#32883", "title": "1 to 12", "fun": 2.2, "difficulty": 2.42, "author": "moonsliver86", "desc": "The numbers 182 and 322 can be expressed as the sum of product pairs chosen from the numbers 1 to 12.\n\r\n182 = 1x12 + 2x11 + 3x10 + 4x9 + 5x8 + 6x7\n\r\n322 = 1x2 + 3x4 + 5x6 + 7x8 + 9x10 + 11x12\n\r\nCan the numbers 180, 217, 299, 400 be written the same way?", "hint": "No hint available.", "answer": "182 is the smallest number that can be written that way. 322 is the largest number that can be written that way.\n\r\nTherefore, \n\r\n180 - no, it can not be written that way\n\r\n217 = 1x12 + 2x5 + 3x9 + 4x8 + 6x11 + 7x10\n\r\n299 = 1x2 + 3x6 + 4x8 + 5x9 + 7x10 + 11x12\n\r\n400 - no, it can not be written that way", "category": "Math", "date": "09/08/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe numbers 182 and 322 can be expressed as the sum of product pairs chosen from the numbers 1 to 12.\n\r\n182 = 1x12 + 2x11 + 3x10 + 4x9 + 5x8 + 6x7\n\r\n322 = 1x2 + 3x4 + 5x6 + 7x8 + 9x10 + 11x12\n\r\nCan the numbers 180, 217, 299, 400 be written the same way?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n182 is the smallest number that can be written that way. 322 is the largest number that can be written that way.\n\r\nTherefore, \n\r\n180 - no, it can not be written that way\n\r\n217 = 1x12 + 2x5 + 3x9 + 4x8 + 6x11 + 7x10\n\r\n299 = 1x2 + 3x6 + 4x8 + 5x9 + 7x10 + 11x12\n\r\n400 - no, it can not be written that way\n<|im_start|>answer\n182 is the smallest number that can be written that way. 322 is the largest number that can be written that way.\n\r\nTherefore, \n\r\n180 - no, it can not be written that way\n\r\n217 = 1x12 + 2x5 + 3x9 + 4x8 + 6x11 + 7x10\n\r\n299 = 1x2 + 3x6 + 4x8 + 5x9 + 7x10 + 11x12\n\r\n400 - no, it can not be written that way\n<|im_end|>" }, { "id": "#1671", "title": "Sewer Pipe", "fun": 2.2, "difficulty": 0.91, "author": "Boddo", "desc": "Two people enter opposite ends of a sewer pipe wide enough to fit only one person, yet they both come out the other end. How do they do it?", "hint": "No hint available.", "answer": "At different times.", "category": "Logic", "date": "12/11/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo people enter opposite ends of a sewer pipe wide enough to fit only one person, yet they both come out the other end. How do they do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAt different times.\n<|im_start|>answer\nAt different times.\n<|im_end|>" }, { "id": "#4550", "title": "3 Digit Number", "fun": 2.2, "difficulty": 1.77, "author": "mad-ade", "desc": "I am a 3 digit number,\r\nI am evenly divisible by 2, 3, 6, 7,\r\nMy 3rd digit is the square root of the 1st digit,\r\nAnd my 2nd digit is the sum of the 1st and 3rd.\r\nWhat Number Am I?", "hint": "No hint available.", "answer": "462\n\r\nCondition one:\r\n462/2 = 231.0\r\n462/3 = 154.0\r\n462/6 = 77.0\r\n462/7 = 66.0\n\r\nCondition two:\r\nThe square root of 4 (the 1st digit) = 2 (the 3rd digit)\n\r\n And finally, Condition three:\r\n4 (the 1st digit) + 2 (the 3rd digit) = 6 (the 2nd digit)", "category": "Math", "date": "06/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a 3 digit number,\r\nI am evenly divisible by 2, 3, 6, 7,\r\nMy 3rd digit is the square root of the 1st digit,\r\nAnd my 2nd digit is the sum of the 1st and 3rd.\r\nWhat Number Am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n462\n\r\nCondition one:\r\n462/2 = 231.0\r\n462/3 = 154.0\r\n462/6 = 77.0\r\n462/7 = 66.0\n\r\nCondition two:\r\nThe square root of 4 (the 1st digit) = 2 (the 3rd digit)\n\r\n And finally, Condition three:\r\n4 (the 1st digit) + 2 (the 3rd digit) = 6 (the 2nd digit)\n<|im_start|>answer\n462\n\r\nCondition one:\r\n462/2 = 231.0\r\n462/3 = 154.0\r\n462/6 = 77.0\r\n462/7 = 66.0\n\r\nCondition two:\r\nThe square root of 4 (the 1st digit) = 2 (the 3rd digit)\n\r\n And finally, Condition three:\r\n4 (the 1st digit) + 2 (the 3rd digit) = 6 (the 2nd digit)\n<|im_end|>" }, { "id": "#13920", "title": "Less than 3 Million", "fun": 2.2, "difficulty": 2.22, "author": "Lemens", "desc": "How many 7 digit EVEN numbers less than 3,000,000 can be formed using the digits, 1, 2, 2, 3, 5, 5, and 6?", "hint": "You must account for the identical digits to make sure you don't double count.", "answer": "If the digit: \n\r\n1 is first and 2 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\n1 is first and 6 is last, there are 30 ways to form a 7 digit even number less than 3,000,000. \n\r\n2 is first and 6 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\n2 is first and 2 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\nSo, adding up all the different combinations that can be formed we get: \n\r\n60+30+60+60 = 210. \n\r\nIn total, 210 ways to form a 7 digit even number less than 3,000,000 using the digits 1, 2, 2, 3, 5, 5, and 6.", "category": "Math", "date": "07/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many 7 digit EVEN numbers less than 3,000,000 can be formed using the digits, 1, 2, 2, 3, 5, 5, and 6?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the digit: \n\r\n1 is first and 2 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\n1 is first and 6 is last, there are 30 ways to form a 7 digit even number less than 3,000,000. \n\r\n2 is first and 6 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\n2 is first and 2 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\nSo, adding up all the different combinations that can be formed we get: \n\r\n60+30+60+60 = 210. \n\r\nIn total, 210 ways to form a 7 digit even number less than 3,000,000 using the digits 1, 2, 2, 3, 5, 5, and 6.\n<|im_start|>answer\nIf the digit: \n\r\n1 is first and 2 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\n1 is first and 6 is last, there are 30 ways to form a 7 digit even number less than 3,000,000. \n\r\n2 is first and 6 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\n2 is first and 2 is last, there are 60 ways to form a 7 digit even number less than 3,000,000. \n\r\nSo, adding up all the different combinations that can be formed we get: \n\r\n60+30+60+60 = 210. \n\r\nIn total, 210 ways to form a 7 digit even number less than 3,000,000 using the digits 1, 2, 2, 3, 5, 5, and 6.\n<|im_end|>" }, { "id": "#1753", "title": "Out of Time", "fun": 2.19, "difficulty": 1.3, "author": "missie", "desc": "A man didn't have any radios or TVs and his clock stopped working. He needed the time, so he drove over to his friend's house and got the time. Without knowing how long it takes to get to his friend's house he put the correct time on his clock when he got home. How?", "hint": "No hint available.", "answer": "He was wearing a watch.", "category": "Logic", "date": "12/19/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man didn't have any radios or TVs and his clock stopped working. He needed the time, so he drove over to his friend's house and got the time. Without knowing how long it takes to get to his friend's house he put the correct time on his clock when he got home. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe was wearing a watch.\n<|im_start|>answer\nHe was wearing a watch.\n<|im_end|>" }, { "id": "#40031", "title": "10x10x10 Cube", "fun": 2.19, "difficulty": 1.68, "author": "letmeforget8", "desc": "You are given a 10x10x10 cube composed of 1x1x1 \"mini-cubes\" glued together. If the outer most layer falls off, how many \"mini-cubes\" would have fallen off?", "hint": "No hint available.", "answer": "10x10x10-8x8x8=488.", "category": "Math", "date": "01/13/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are given a 10x10x10 cube composed of 1x1x1 \"mini-cubes\" glued together. If the outer most layer falls off, how many \"mini-cubes\" would have fallen off?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10x10x10-8x8x8=488.\n<|im_start|>answer\n10x10x10-8x8x8=488.\n<|im_end|>" }, { "id": "#19254", "title": "Equal Numbers?", "fun": 2.19, "difficulty": 1.91, "author": "ScoutMan", "desc": "Using a simple mathematical procedure, I can say that 1, 19, 1999, 2278, 4563739, and 35461 are all equal. How am I able to do this?", "hint": "It is basic math.", "answer": "I simply add all digits of each number together, and keep adding until my answer is a single digit number. For example, 1+9+9+9=28, and 2+8=10, and 1+0=1, so 1999 is equal to 1. An interesting side note is that each time you get a single digit answer of 3, 6, or 9, the starting number is divisible by 3.", "category": "Math", "date": "10/25/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing a simple mathematical procedure, I can say that 1, 19, 1999, 2278, 4563739, and 35461 are all equal. How am I able to do this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI simply add all digits of each number together, and keep adding until my answer is a single digit number. For example, 1+9+9+9=28, and 2+8=10, and 1+0=1, so 1999 is equal to 1. An interesting side note is that each time you get a single digit answer of 3, 6, or 9, the starting number is divisible by 3.\n<|im_start|>answer\nI simply add all digits of each number together, and keep adding until my answer is a single digit number. For example, 1+9+9+9=28, and 2+8=10, and 1+0=1, so 1999 is equal to 1. An interesting side note is that each time you get a single digit answer of 3, 6, or 9, the starting number is divisible by 3.\n<|im_end|>" }, { "id": "#18526", "title": "When was I Married", "fun": 2.19, "difficulty": 1.98, "author": "am53", "desc": "Joe Simmons of New York married his second wife in 1900. His age in whole years at his death was one twenty-ninth of the year of his birth. In the year he died he had already celebrated his birthday. How old was he at his second wedding?", "hint": "No hint available.", "answer": "He was born in 1856, died in 1920 (at age 64), and was 44 at his second wedding in 1900.", "category": "Math", "date": "08/10/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe Simmons of New York married his second wife in 1900. His age in whole years at his death was one twenty-ninth of the year of his birth. In the year he died he had already celebrated his birthday. How old was he at his second wedding?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe was born in 1856, died in 1920 (at age 64), and was 44 at his second wedding in 1900.\n<|im_start|>answer\nHe was born in 1856, died in 1920 (at age 64), and was 44 at his second wedding in 1900.\n<|im_end|>" }, { "id": "#16558", "title": "Stickers Gotcha Stuck?", "fun": 2.19, "difficulty": 1.16, "author": "adoontourious", "desc": "My little sister barged into my room clutching a paper bag. \"Betcha can't guess how many stickers I bought for $6.25!\" \n\r\n\"I guess I won't bother to guess. There's no way anyone could know how many stickers are in that bag,\" I told her. \n\r\n\"Figure it out,\" said the little smart aleck. \"The stickers were all the same price. The number I bought is the same as the number of cents in each price.\" \n\r\n\"Hmmm...well, OK now I know it but I'm not going to tell you!\" (I hate to admit when I'm stuck.) \n\r\nHow many stickers are in the bag and how much did each one cost?", "hint": "No hint available.", "answer": "25 stickers costing 25 cents each \n\r\n$6.25 equals 625 cents \n\r\nAnd 625 / 25 = 25", "category": "Math", "date": "02/13/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy little sister barged into my room clutching a paper bag. \"Betcha can't guess how many stickers I bought for $6.25!\" \n\r\n\"I guess I won't bother to guess. There's no way anyone could know how many stickers are in that bag,\" I told her. \n\r\n\"Figure it out,\" said the little smart aleck. \"The stickers were all the same price. The number I bought is the same as the number of cents in each price.\" \n\r\n\"Hmmm...well, OK now I know it but I'm not going to tell you!\" (I hate to admit when I'm stuck.) \n\r\nHow many stickers are in the bag and how much did each one cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n25 stickers costing 25 cents each \n\r\n$6.25 equals 625 cents \n\r\nAnd 625 / 25 = 25\n<|im_start|>answer\n25 stickers costing 25 cents each \n\r\n$6.25 equals 625 cents \n\r\nAnd 625 / 25 = 25\n<|im_end|>" }, { "id": "#10820", "title": "Long March", "fun": 2.19, "difficulty": 2.52, "author": "mad-ade", "desc": "The Madadian army is out on manoeuvre. At the head of the platoon is Major Dumsaw and at the rear of the platoon is Private Dartes. The platoon is 50 metres long. \r\nPrivate Dartes (the last person in the platoon) wants to give a letter to Major Dumsaw (the first person) leading the platoon. So while the platoon is marching Private Dartes runs ahead, reaches the major and hands over the letter to him and without stopping he runs and comes back to his original position. \n\r\nIn the meantime the whole platoon has moved ahead by 50m. \n\r\nThe question is how much distance did Private Dartes cover in that time, assuming that he ran the whole distance with uniform speed?", "hint": "No hint available.", "answer": "Private Dartes covered 120.71 metres. \n\r\nIt is given that the platoon and the Private moved with uniform speed. Also, they both moved for the identical amount of time. Hence, the ratio of the distance they covered - while person moving forward and backwards - are equal. \n\r\nLet's assume that when Dartes reached the major, the platoon moved X metres forward. \n\r\nThus, while moving forward Dartes moved (50+X) metres whereas the platoon moved X metres. \n\r\nSimilarly, while moving back Dartes moved [50-(50-X)] X metres whereas the platoon moved (50-X) metres. \n\r\nNow, as the ratios are equal, \r\n(50+X)/X = X/(50-X) \r\n(50+X)*(50-X) = X*X \n\r\nSolving, X=35.355 metres \n\r\nThus, total distance covered by Private Dartes \r\n= (50+X) + X \r\n= 2*X + 50 \r\n= 2*(35.355) + 50 \r\n= 120.71 metres \n\n\r\nNote that at first glance, one might think that the total distance covered by Private Dartes is 100 metres, as he ran the total length of the platoon (50 metres) twice. TRUE, but that's the relative distance covered by the last person i.e. assuming that the platoon is stationary.", "category": "Math", "date": "03/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Madadian army is out on manoeuvre. At the head of the platoon is Major Dumsaw and at the rear of the platoon is Private Dartes. The platoon is 50 metres long. \r\nPrivate Dartes (the last person in the platoon) wants to give a letter to Major Dumsaw (the first person) leading the platoon. So while the platoon is marching Private Dartes runs ahead, reaches the major and hands over the letter to him and without stopping he runs and comes back to his original position. \n\r\nIn the meantime the whole platoon has moved ahead by 50m. \n\r\nThe question is how much distance did Private Dartes cover in that time, assuming that he ran the whole distance with uniform speed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPrivate Dartes covered 120.71 metres. \n\r\nIt is given that the platoon and the Private moved with uniform speed. Also, they both moved for the identical amount of time. Hence, the ratio of the distance they covered - while person moving forward and backwards - are equal. \n\r\nLet's assume that when Dartes reached the major, the platoon moved X metres forward. \n\r\nThus, while moving forward Dartes moved (50+X) metres whereas the platoon moved X metres. \n\r\nSimilarly, while moving back Dartes moved [50-(50-X)] X metres whereas the platoon moved (50-X) metres. \n\r\nNow, as the ratios are equal, \r\n(50+X)/X = X/(50-X) \r\n(50+X)*(50-X) = X*X \n\r\nSolving, X=35.355 metres \n\r\nThus, total distance covered by Private Dartes \r\n= (50+X) + X \r\n= 2*X + 50 \r\n= 2*(35.355) + 50 \r\n= 120.71 metres \n\n\r\nNote that at first glance, one might think that the total distance covered by Private Dartes is 100 metres, as he ran the total length of the platoon (50 metres) twice. TRUE, but that's the relative distance covered by the last person i.e. assuming that the platoon is stationary.\n<|im_start|>answer\nPrivate Dartes covered 120.71 metres. \n\r\nIt is given that the platoon and the Private moved with uniform speed. Also, they both moved for the identical amount of time. Hence, the ratio of the distance they covered - while person moving forward and backwards - are equal. \n\r\nLet's assume that when Dartes reached the major, the platoon moved X metres forward. \n\r\nThus, while moving forward Dartes moved (50+X) metres whereas the platoon moved X metres. \n\r\nSimilarly, while moving back Dartes moved [50-(50-X)] X metres whereas the platoon moved (50-X) metres. \n\r\nNow, as the ratios are equal, \r\n(50+X)/X = X/(50-X) \r\n(50+X)*(50-X) = X*X \n\r\nSolving, X=35.355 metres \n\r\nThus, total distance covered by Private Dartes \r\n= (50+X) + X \r\n= 2*X + 50 \r\n= 2*(35.355) + 50 \r\n= 120.71 metres \n\n\r\nNote that at first glance, one might think that the total distance covered by Private Dartes is 100 metres, as he ran the total length of the platoon (50 metres) twice. TRUE, but that's the relative distance covered by the last person i.e. assuming that the platoon is stationary.\n<|im_end|>" }, { "id": "#3694", "title": "Grazing Cow", "fun": 2.19, "difficulty": 2.41, "author": "cathalmccabe", "desc": "A cow is tied in a rectangular field, 20m by 10 m.\r\nThe cow is tied to the middle of one of the 20m long fences by a rope 25m long. There is a gap the cow can squeeze through in the middle of the other 20m long fence (assume a point).\r\nHow much land can the cow graze on?", "hint": "No hint available.", "answer": "He can get to the whole area of the field, + the area of a semi circle outside the field, and 2 areas of quarter circles where the rope extends around the sides of the fences.\n\r\n20*10 + (pi*15^2)/2 + 2* (pi*5^2)/4\r\n200+pi*112.5 + pi*12.5\r\n200 + pi * 125\n\r\nApprox 593 square metres.", "category": "Math", "date": "04/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cow is tied in a rectangular field, 20m by 10 m.\r\nThe cow is tied to the middle of one of the 20m long fences by a rope 25m long. There is a gap the cow can squeeze through in the middle of the other 20m long fence (assume a point).\r\nHow much land can the cow graze on?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe can get to the whole area of the field, + the area of a semi circle outside the field, and 2 areas of quarter circles where the rope extends around the sides of the fences.\n\r\n20*10 + (pi*15^2)/2 + 2* (pi*5^2)/4\r\n200+pi*112.5 + pi*12.5\r\n200 + pi * 125\n\r\nApprox 593 square metres.\n<|im_start|>answer\nHe can get to the whole area of the field, + the area of a semi circle outside the field, and 2 areas of quarter circles where the rope extends around the sides of the fences.\n\r\n20*10 + (pi*15^2)/2 + 2* (pi*5^2)/4\r\n200+pi*112.5 + pi*12.5\r\n200 + pi * 125\n\r\nApprox 593 square metres.\n<|im_end|>" }, { "id": "#463", "title": "Give me half!", "fun": 2.19, "difficulty": 0.8200000000000001, "author": "Mr. G", "desc": "8 is half of 16, and 16 is half of 32. What is 64 divided by 1/2?", "hint": "The answer isn`t 32!", "answer": "The answer is 128. The question wanted you to divide by 1/2 not by 2.", "category": "Math", "date": "05/15/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n8 is half of 16, and 16 is half of 32. What is 64 divided by 1/2?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 128. The question wanted you to divide by 1/2 not by 2.\n<|im_start|>answer\nThe answer is 128. The question wanted you to divide by 1/2 not by 2.\n<|im_end|>" }, { "id": "#10288", "title": "Mixtures", "fun": 2.19, "difficulty": 1.14, "author": "ka-boom", "desc": "You have a 10-liter mixture of 90% ethanol and 10% water. How much water would you have to add in order break the mixture down to 50% ethanol?", "hint": "No hint available.", "answer": "8 liters.\n\r\nSince you start out with 9 liters of ethanol, you need to end up with 18 liters overall for the ethanol content to equal 50%. To get 18 liters, just add 8 liters to the original 10-liter solution.", "category": "Math", "date": "02/06/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have a 10-liter mixture of 90% ethanol and 10% water. How much water would you have to add in order break the mixture down to 50% ethanol?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8 liters.\n\r\nSince you start out with 9 liters of ethanol, you need to end up with 18 liters overall for the ethanol content to equal 50%. To get 18 liters, just add 8 liters to the original 10-liter solution.\n<|im_start|>answer\n8 liters.\n\r\nSince you start out with 9 liters of ethanol, you need to end up with 18 liters overall for the ethanol content to equal 50%. To get 18 liters, just add 8 liters to the original 10-liter solution.\n<|im_end|>" }, { "id": "#19113", "title": "Hexing Hexes", "fun": 2.19, "difficulty": 2.5100000000000002, "author": "snaps", "desc": "There is a link between the words below and their associated numbers. Can you figure out what it is?\n\r\nA = 10\r\nAD = 173\r\nADD = 2781\r\nACE = 2776\r\nACED = 44269\r\nFACE = 64206\r\nFACED = 1027309", "hint": "The title itself is a clue.", "answer": "The words are actually numbers in hexadecimal form (base 16), while the numbers are their decimal (base 10) equivalent.\n\r\nCounting in hexadecimal (with corresponding decimal values in brackets) is:\r\n0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A (10), B (11), C (12), D (13), E (14), F (15),\r\n10 (16), 11 (17), 12 (18), 13 (19), 14 (20), 15 (21), 16 (22), 17 (23), 18 (24), 19 (25), 1A (26), 1B (27), 1C (28), 1D (29), 1E (30), 1F (31),\r\n20 (32), 21 (33) ...\n\r\nNote that for decimal, the place values are 1, 10, 100, 1000, etc. For hexadecimal, the place values are 1, 16 (10), 256 (100), 4096 (1000).", "category": "Math", "date": "10/10/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a link between the words below and their associated numbers. Can you figure out what it is?\n\r\nA = 10\r\nAD = 173\r\nADD = 2781\r\nACE = 2776\r\nACED = 44269\r\nFACE = 64206\r\nFACED = 1027309\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe words are actually numbers in hexadecimal form (base 16), while the numbers are their decimal (base 10) equivalent.\n\r\nCounting in hexadecimal (with corresponding decimal values in brackets) is:\r\n0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A (10), B (11), C (12), D (13), E (14), F (15),\r\n10 (16), 11 (17), 12 (18), 13 (19), 14 (20), 15 (21), 16 (22), 17 (23), 18 (24), 19 (25), 1A (26), 1B (27), 1C (28), 1D (29), 1E (30), 1F (31),\r\n20 (32), 21 (33) ...\n\r\nNote that for decimal, the place values are 1, 10, 100, 1000, etc. For hexadecimal, the place values are 1, 16 (10), 256 (100), 4096 (1000).\n<|im_start|>answer\nThe words are actually numbers in hexadecimal form (base 16), while the numbers are their decimal (base 10) equivalent.\n\r\nCounting in hexadecimal (with corresponding decimal values in brackets) is:\r\n0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A (10), B (11), C (12), D (13), E (14), F (15),\r\n10 (16), 11 (17), 12 (18), 13 (19), 14 (20), 15 (21), 16 (22), 17 (23), 18 (24), 19 (25), 1A (26), 1B (27), 1C (28), 1D (29), 1E (30), 1F (31),\r\n20 (32), 21 (33) ...\n\r\nNote that for decimal, the place values are 1, 10, 100, 1000, etc. For hexadecimal, the place values are 1, 16 (10), 256 (100), 4096 (1000).\n<|im_end|>" }, { "id": "#4848", "title": "Five Pound Seventy Pence", "fun": 2.19, "difficulty": 2.71, "author": "mad-ade", "desc": "Mad Ade was in his local news agents looking at the various magazines on display, He picked a copy of \"Kebabs and Me\" a copy of \"Everything You Ever Wanted to Know About Nylon Underpants\" and a copy of \"Indoor Hang Gliding\". He passed the magazines to the shop keeper, who duly entered the amounts of each magazine into the till. \"Wow, hang on a minute\" said Mad Ade. \"You just pressed the multiplication button each time between amounts instead of the addition button.\" The shop keeper smiled with new false teeth and replied, \"it doesn't matter either way, it still comes to £5.70p\".\n\r\nWhat were the prices of the magazines, that could either be multiplied or added to make £5.70", "hint": "No hint available.", "answer": "£2.85*£1.60*£1.25= £5.70\r\n£2.85+£1.60+£1.25=£5.70", "category": "Math", "date": "06/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was in his local news agents looking at the various magazines on display, He picked a copy of \"Kebabs and Me\" a copy of \"Everything You Ever Wanted to Know About Nylon Underpants\" and a copy of \"Indoor Hang Gliding\". He passed the magazines to the shop keeper, who duly entered the amounts of each magazine into the till. \"Wow, hang on a minute\" said Mad Ade. \"You just pressed the multiplication button each time between amounts instead of the addition button.\" The shop keeper smiled with new false teeth and replied, \"it doesn't matter either way, it still comes to £5.70p\".\n\r\nWhat were the prices of the magazines, that could either be multiplied or added to make £5.70\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n£2.85*£1.60*£1.25= £5.70\r\n£2.85+£1.60+£1.25=£5.70\n<|im_start|>answer\n£2.85*£1.60*£1.25= £5.70\r\n£2.85+£1.60+£1.25=£5.70\n<|im_end|>" }, { "id": "#16324", "title": "Eggs!", "fun": 2.19, "difficulty": 1.42, "author": "liltunalol", "desc": "Half a crate of eggs holds half a dozen cartons, each of which holds half a dozen eggs. The truck just delivered a crate and a half. How many eggs?", "hint": "No hint available.", "answer": "108 eggs.\n\r\nHalf a crate holds 6 cartons of 6 eggs = 36 eggs.\r\nA crate and a half was delivered which is 3 x (half a crate), therefore 3 x 36 eggs = 108 eggs.", "category": "Math", "date": "01/25/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHalf a crate of eggs holds half a dozen cartons, each of which holds half a dozen eggs. The truck just delivered a crate and a half. How many eggs?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n108 eggs.\n\r\nHalf a crate holds 6 cartons of 6 eggs = 36 eggs.\r\nA crate and a half was delivered which is 3 x (half a crate), therefore 3 x 36 eggs = 108 eggs.\n<|im_start|>answer\n108 eggs.\n\r\nHalf a crate holds 6 cartons of 6 eggs = 36 eggs.\r\nA crate and a half was delivered which is 3 x (half a crate), therefore 3 x 36 eggs = 108 eggs.\n<|im_end|>" }, { "id": "#20526", "title": "Two and a Half", "fun": 2.19, "difficulty": 2.64, "author": "doggyxp", "desc": "Two and a half artists spend two and a half hours painting two and a half models on two and a half canvases. How many artists are necessary to paint twenty-four models on twenty-four canvases in twenty hours?", "hint": "No hint available.", "answer": "Three artists would do the trick. This is because twenty-four artists would paint twenty-four models in two and a half hours. Since the available time increases eight-fold (2.5 * 8 = 20), it is possible to reduce the number of painters by the same number of times (24 / 8 = 3).", "category": "Math", "date": "01/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo and a half artists spend two and a half hours painting two and a half models on two and a half canvases. How many artists are necessary to paint twenty-four models on twenty-four canvases in twenty hours?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree artists would do the trick. This is because twenty-four artists would paint twenty-four models in two and a half hours. Since the available time increases eight-fold (2.5 * 8 = 20), it is possible to reduce the number of painters by the same number of times (24 / 8 = 3).\n<|im_start|>answer\nThree artists would do the trick. This is because twenty-four artists would paint twenty-four models in two and a half hours. Since the available time increases eight-fold (2.5 * 8 = 20), it is possible to reduce the number of painters by the same number of times (24 / 8 = 3).\n<|im_end|>" }, { "id": "#3891", "title": "Pints, Inches and Seconds", "fun": 2.19, "difficulty": 1.92, "author": "mad-ade", "desc": "Which of these is the largest number?\n\r\n1. Half pints in 45 gallons\r\n2. Half inches in 10 yards\r\n3. Half seconds in 6 minutes", "hint": "No hint available.", "answer": "They are all the same: 720", "category": "Math", "date": "05/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich of these is the largest number?\n\r\n1. Half pints in 45 gallons\r\n2. Half inches in 10 yards\r\n3. Half seconds in 6 minutes\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are all the same: 720\n<|im_start|>answer\nThey are all the same: 720\n<|im_end|>" }, { "id": "#299", "title": "An Injured Child", "fun": 2.19, "difficulty": 0.75, "author": "Phyllis", "desc": "A child is injured in an accident and is rushed to the hospital. The doctor takes one look at the child and says: \"I can't treat him, that's my son.\" The doctor is not the child's father. How do you explain this?", "hint": "How many parents do you have?", "answer": "The doctor is a woman and is the child's mother.", "category": "Logic", "date": "02/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA child is injured in an accident and is rushed to the hospital. The doctor takes one look at the child and says: \"I can't treat him, that's my son.\" The doctor is not the child's father. How do you explain this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe doctor is a woman and is the child's mother.\n<|im_start|>answer\nThe doctor is a woman and is the child's mother.\n<|im_end|>" }, { "id": "#1741", "title": "Fill in the Blanks", "fun": 2.19, "difficulty": 2.07, "author": "JOKESTER8000", "desc": "Can you fill in the blanks using +, -, / and * to make the equation work out?\n\r\n7 7 7 1 2 3 6 2=8", "hint": "No hint available.", "answer": "Two possible answers are:\n\r\n7*7/7*1+2+3-6+2=8 and\r\n7+7+7*1-2-3-6-2=8", "category": "Math", "date": "12/18/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you fill in the blanks using +, -, / and * to make the equation work out?\n\r\n7 7 7 1 2 3 6 2=8\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwo possible answers are:\n\r\n7*7/7*1+2+3-6+2=8 and\r\n7+7+7*1-2-3-6-2=8\n<|im_start|>answer\nTwo possible answers are:\n\r\n7*7/7*1+2+3-6+2=8 and\r\n7+7+7*1-2-3-6-2=8\n<|im_end|>" }, { "id": "#11053", "title": "Kebab Dinner", "fun": 2.19, "difficulty": 2.29, "author": "mad-ade", "desc": "On every Sunday Mad Ade, Thorny Kator and Bill Sticker lunch together at \"Sweaty Chef Kebab Shop\" where they order Kebab and napalm chilli sauce based on following facts. \n\r\nUnless neither Mad Ade nor Thorny Kator have Kebab and napalm chilli sauce, Bill Sticker must have it. \n\r\nIf Mad Ade does not have Kebab and napalm chilli sauce, either Thorny Kator or Bill Sticker or both have it. \n\r\nBill Sticker has Kebab and napalm chilli sauce only if either Mad Ade or Thorny Kator or both have it. \n\r\nThorny Kator and Bill Sticker never have Kebab and napalm chilli sauce together. \n\r\nWho orders Kebab and napalm chilli sauce?", "hint": "No hint available.", "answer": "Mad Ade and Bill Sticker both have Kebab and napalm chilli sauce, whereas Thorny Kator never does. \n\r\nFact (2) can be alternatively stated that \"either Mad Ade or Thorny Kator or Bill Sticker must have Kebab and napalm chilli sauce\". \n\r\nFrom Fact (3), it can be inferred that either Mad Ade or Thorny Kator must have Kebab and napalm chilli sauce. \n\r\nNow, from Fact (1), it is apparent that Bill Sticker too must have Kebab and napalm chilli sauce. But according to Fact (4), Thorny Kator cannot have Kebab and napalm chilli sauce when Bill Sticker does. \n\r\nThus, Mad Ade and Bill Sticker both have Kebab and napalm chilli sauce, whereas Thorny Kator never does.", "category": "Logic", "date": "03/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn every Sunday Mad Ade, Thorny Kator and Bill Sticker lunch together at \"Sweaty Chef Kebab Shop\" where they order Kebab and napalm chilli sauce based on following facts. \n\r\nUnless neither Mad Ade nor Thorny Kator have Kebab and napalm chilli sauce, Bill Sticker must have it. \n\r\nIf Mad Ade does not have Kebab and napalm chilli sauce, either Thorny Kator or Bill Sticker or both have it. \n\r\nBill Sticker has Kebab and napalm chilli sauce only if either Mad Ade or Thorny Kator or both have it. \n\r\nThorny Kator and Bill Sticker never have Kebab and napalm chilli sauce together. \n\r\nWho orders Kebab and napalm chilli sauce?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade and Bill Sticker both have Kebab and napalm chilli sauce, whereas Thorny Kator never does. \n\r\nFact (2) can be alternatively stated that \"either Mad Ade or Thorny Kator or Bill Sticker must have Kebab and napalm chilli sauce\". \n\r\nFrom Fact (3), it can be inferred that either Mad Ade or Thorny Kator must have Kebab and napalm chilli sauce. \n\r\nNow, from Fact (1), it is apparent that Bill Sticker too must have Kebab and napalm chilli sauce. But according to Fact (4), Thorny Kator cannot have Kebab and napalm chilli sauce when Bill Sticker does. \n\r\nThus, Mad Ade and Bill Sticker both have Kebab and napalm chilli sauce, whereas Thorny Kator never does.\n<|im_start|>answer\nMad Ade and Bill Sticker both have Kebab and napalm chilli sauce, whereas Thorny Kator never does. \n\r\nFact (2) can be alternatively stated that \"either Mad Ade or Thorny Kator or Bill Sticker must have Kebab and napalm chilli sauce\". \n\r\nFrom Fact (3), it can be inferred that either Mad Ade or Thorny Kator must have Kebab and napalm chilli sauce. \n\r\nNow, from Fact (1), it is apparent that Bill Sticker too must have Kebab and napalm chilli sauce. But according to Fact (4), Thorny Kator cannot have Kebab and napalm chilli sauce when Bill Sticker does. \n\r\nThus, Mad Ade and Bill Sticker both have Kebab and napalm chilli sauce, whereas Thorny Kator never does.\n<|im_end|>" }, { "id": "#12537", "title": "Madadian TV Dilemma", "fun": 2.19, "difficulty": 2.63, "author": "mad-ade", "desc": "For a TV entertainment show on Madadian TV entitled \"I am a Celebrity, get me a Kebab!!\" the producer, Mad Ade (no relation) must choose a group of two Directors and two Musicians. At least one of them must be an Actor and at least one a Singer. \n\r\nAvailable Directors are Holly Wood, Jed I. Knight, Ty Tanick, Winnie DePooh and Zoltan Pepper. \n\r\nAvailable Musicians are Howard Eyeno, Eve O'Looshun, Di O'Bolic and Brighton Early. \n\r\nTy Tanick, Howard Eyeno and Eve O'Looshun are Actors. \n\r\nWinnie DePooh and Brighton Early are Singers. \n\r\nHoward Eyeno will not sit in the same room with Ty Tanick, and will take part only if Holly Wood is there. \n\r\nWinnie DePooh refuses to take part with Eve O'Looshun. \n\r\nZoltan Pepper refuses to take part with Brighton Early. \r\nHow many acceptable groups can the producer put together?", "hint": "No hint available.", "answer": "There are 60 possible groupings of two directors and two musicians. However, some of them are not acceptable, because they do not include both an actor and a singer. This brings the possible combinations down to 36. When you eliminate the combinations that represent people who refuse to work together, you end up with 9.The acceptable groups are: \r\n1) Holly Wood, Jed I. Knight, Howard Eyeno, and Brighton Early; \r\n2) Holly Wood, Jed I. Knight, Eve O'Looshun, and Brighton Early; \r\n3) Holly Wood, Ty Tanick, Eve O'Looshun, and Brighton Early; \r\n4) Holly Wood, Ty Tanick, Di O'Bolic, and Brighton Early; \r\n5) Holly Wood, Winnie DePooh, Howard Eyeno, and Di O'Bolic; \r\n6) Holly Wood, Winnie DePooh, Howard Eyeno, and Brighton Early; \r\n7) Jed I. Knight, Ty Tanick, Eve O'Looshun, and Brighton Early; \r\n8) Jed I. Knight, Ty Tanick, Di O'Bolic, and Brighton Early; \r\n9) Ty Tanick, Winnie DePooh, Di O'Bolic, and Brighton Early. \r\nSome interesting points arise here. For instance, Brighton Early appears in eight of the nine groups, while Zoltan Pepper doesn't appear at all. He's completely blocked out by his own and others' conditions on working with certain people, and Brighton Early benefits greatly by being the only musician/singer, especially when he doesn't refuse to work with anyone else. Winnie DePooh doesn't get a similar advantage by being the only director/singer because he refuses to work with Eve O'Looshun, which limits his availability. I guess the moral of the story is, be willing to work with anybody and you'll be able to work more.", "category": "Logic", "date": "05/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor a TV entertainment show on Madadian TV entitled \"I am a Celebrity, get me a Kebab!!\" the producer, Mad Ade (no relation) must choose a group of two Directors and two Musicians. At least one of them must be an Actor and at least one a Singer. \n\r\nAvailable Directors are Holly Wood, Jed I. Knight, Ty Tanick, Winnie DePooh and Zoltan Pepper. \n\r\nAvailable Musicians are Howard Eyeno, Eve O'Looshun, Di O'Bolic and Brighton Early. \n\r\nTy Tanick, Howard Eyeno and Eve O'Looshun are Actors. \n\r\nWinnie DePooh and Brighton Early are Singers. \n\r\nHoward Eyeno will not sit in the same room with Ty Tanick, and will take part only if Holly Wood is there. \n\r\nWinnie DePooh refuses to take part with Eve O'Looshun. \n\r\nZoltan Pepper refuses to take part with Brighton Early. \r\nHow many acceptable groups can the producer put together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 60 possible groupings of two directors and two musicians. However, some of them are not acceptable, because they do not include both an actor and a singer. This brings the possible combinations down to 36. When you eliminate the combinations that represent people who refuse to work together, you end up with 9.The acceptable groups are: \r\n1) Holly Wood, Jed I. Knight, Howard Eyeno, and Brighton Early; \r\n2) Holly Wood, Jed I. Knight, Eve O'Looshun, and Brighton Early; \r\n3) Holly Wood, Ty Tanick, Eve O'Looshun, and Brighton Early; \r\n4) Holly Wood, Ty Tanick, Di O'Bolic, and Brighton Early; \r\n5) Holly Wood, Winnie DePooh, Howard Eyeno, and Di O'Bolic; \r\n6) Holly Wood, Winnie DePooh, Howard Eyeno, and Brighton Early; \r\n7) Jed I. Knight, Ty Tanick, Eve O'Looshun, and Brighton Early; \r\n8) Jed I. Knight, Ty Tanick, Di O'Bolic, and Brighton Early; \r\n9) Ty Tanick, Winnie DePooh, Di O'Bolic, and Brighton Early. \r\nSome interesting points arise here. For instance, Brighton Early appears in eight of the nine groups, while Zoltan Pepper doesn't appear at all. He's completely blocked out by his own and others' conditions on working with certain people, and Brighton Early benefits greatly by being the only musician/singer, especially when he doesn't refuse to work with anyone else. Winnie DePooh doesn't get a similar advantage by being the only director/singer because he refuses to work with Eve O'Looshun, which limits his availability. I guess the moral of the story is, be willing to work with anybody and you'll be able to work more.\n<|im_start|>answer\nThere are 60 possible groupings of two directors and two musicians. However, some of them are not acceptable, because they do not include both an actor and a singer. This brings the possible combinations down to 36. When you eliminate the combinations that represent people who refuse to work together, you end up with 9.The acceptable groups are: \r\n1) Holly Wood, Jed I. Knight, Howard Eyeno, and Brighton Early; \r\n2) Holly Wood, Jed I. Knight, Eve O'Looshun, and Brighton Early; \r\n3) Holly Wood, Ty Tanick, Eve O'Looshun, and Brighton Early; \r\n4) Holly Wood, Ty Tanick, Di O'Bolic, and Brighton Early; \r\n5) Holly Wood, Winnie DePooh, Howard Eyeno, and Di O'Bolic; \r\n6) Holly Wood, Winnie DePooh, Howard Eyeno, and Brighton Early; \r\n7) Jed I. Knight, Ty Tanick, Eve O'Looshun, and Brighton Early; \r\n8) Jed I. Knight, Ty Tanick, Di O'Bolic, and Brighton Early; \r\n9) Ty Tanick, Winnie DePooh, Di O'Bolic, and Brighton Early. \r\nSome interesting points arise here. For instance, Brighton Early appears in eight of the nine groups, while Zoltan Pepper doesn't appear at all. He's completely blocked out by his own and others' conditions on working with certain people, and Brighton Early benefits greatly by being the only musician/singer, especially when he doesn't refuse to work with anyone else. Winnie DePooh doesn't get a similar advantage by being the only director/singer because he refuses to work with Eve O'Looshun, which limits his availability. I guess the moral of the story is, be willing to work with anybody and you'll be able to work more.\n<|im_end|>" }, { "id": "#31718", "title": "Solar System Model", "fun": 2.19, "difficulty": 2.46, "author": "maxvu", "desc": "Kate and Shireen are making a model of the solar system on the ceiling of their classroom. They plan to place their model of the Sun at the southwest corner of the ceiling, and they will mark out the relative distances of the planets along a line from the southwest corner to the northeast corner. The classroom measures 42 ft by 66 ft. \n\r\nIn order to make the best use of the ceiling space, the girls decide to place their model of Pluto at the northeast corner. They understand that placing Pluto there automatically determines the scale of their model. But in order to know where to place the other planets, the girls need to know what that scale is.\n\r\nAssuming Pluto, the farthest planet, is 5.9 * 10^9 km from the Sun, approximately what distance in the real solar system does 1 centimeter on the model now represent?", "hint": "1. Use the Pythagorean Theorem. \r\n2. To convert feet to centimeters, multiply by 30.48.", "answer": "On the solar system model, 1 cm represents approximately 2.5 * 10^6 km in the real solar system.\n\r\nSince the room measures 42 ft by 66 ft, the diagonal distance between the southwest and northeast corners, by the Pythagorean Theorem, is the square root of (42^2 + 66^2) sqft = 78 ft (rounded) or 2377 cm.\n\r\nSo, if 2377 cm in the model represents a real distance of 5900 * 10^6 km, then 1 cm represents 5900/2377 * 10^6 km or 2.5 * 10^6 km.", "category": "Math", "date": "07/12/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKate and Shireen are making a model of the solar system on the ceiling of their classroom. They plan to place their model of the Sun at the southwest corner of the ceiling, and they will mark out the relative distances of the planets along a line from the southwest corner to the northeast corner. The classroom measures 42 ft by 66 ft. \n\r\nIn order to make the best use of the ceiling space, the girls decide to place their model of Pluto at the northeast corner. They understand that placing Pluto there automatically determines the scale of their model. But in order to know where to place the other planets, the girls need to know what that scale is.\n\r\nAssuming Pluto, the farthest planet, is 5.9 * 10^9 km from the Sun, approximately what distance in the real solar system does 1 centimeter on the model now represent?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn the solar system model, 1 cm represents approximately 2.5 * 10^6 km in the real solar system.\n\r\nSince the room measures 42 ft by 66 ft, the diagonal distance between the southwest and northeast corners, by the Pythagorean Theorem, is the square root of (42^2 + 66^2) sqft = 78 ft (rounded) or 2377 cm.\n\r\nSo, if 2377 cm in the model represents a real distance of 5900 * 10^6 km, then 1 cm represents 5900/2377 * 10^6 km or 2.5 * 10^6 km.\n<|im_start|>answer\nOn the solar system model, 1 cm represents approximately 2.5 * 10^6 km in the real solar system.\n\r\nSince the room measures 42 ft by 66 ft, the diagonal distance between the southwest and northeast corners, by the Pythagorean Theorem, is the square root of (42^2 + 66^2) sqft = 78 ft (rounded) or 2377 cm.\n\r\nSo, if 2377 cm in the model represents a real distance of 5900 * 10^6 km, then 1 cm represents 5900/2377 * 10^6 km or 2.5 * 10^6 km.\n<|im_end|>" }, { "id": "#38492", "title": "Ten Numbers", "fun": 2.19, "difficulty": 2.89, "author": "holly1447591", "desc": "There are ten natural numbers, two of which are equal. Adding any nine of them, we can get the following sums:\n\r\n82, 83, 84, 85, 87, 89, 90, 91, 92.\n\r\nFind the largest number of the ten.", "hint": "No hint available.", "answer": "There are ten possible sums, arrived at by alternately excluding each one of the ten numbers. Two of the sums are equal. If we add the ten sums, it should equal nine times the sum of the ten numbers, as each number will be present within all of the sums nine times. \n\r\n82+83+84+85+87+89+90+91+92=87*9=783, which is divisible by 9, therefore the repeated sum must be divisible by 9. The only sum which meets this criteria is 90.\n\r\nThe sum of the ten numbers is (783+90)/9=97. The largest number is found by subtracting the lowest sum of nine numbers (which excluded the largest of the ten numbers) from the sum of all ten numbers. Thus: 97-82=15. 15 is the largest number of the ten.", "category": "Math", "date": "09/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are ten natural numbers, two of which are equal. Adding any nine of them, we can get the following sums:\n\r\n82, 83, 84, 85, 87, 89, 90, 91, 92.\n\r\nFind the largest number of the ten.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are ten possible sums, arrived at by alternately excluding each one of the ten numbers. Two of the sums are equal. If we add the ten sums, it should equal nine times the sum of the ten numbers, as each number will be present within all of the sums nine times. \n\r\n82+83+84+85+87+89+90+91+92=87*9=783, which is divisible by 9, therefore the repeated sum must be divisible by 9. The only sum which meets this criteria is 90.\n\r\nThe sum of the ten numbers is (783+90)/9=97. The largest number is found by subtracting the lowest sum of nine numbers (which excluded the largest of the ten numbers) from the sum of all ten numbers. Thus: 97-82=15. 15 is the largest number of the ten.\n<|im_start|>answer\nThere are ten possible sums, arrived at by alternately excluding each one of the ten numbers. Two of the sums are equal. If we add the ten sums, it should equal nine times the sum of the ten numbers, as each number will be present within all of the sums nine times. \n\r\n82+83+84+85+87+89+90+91+92=87*9=783, which is divisible by 9, therefore the repeated sum must be divisible by 9. The only sum which meets this criteria is 90.\n\r\nThe sum of the ten numbers is (783+90)/9=97. The largest number is found by subtracting the lowest sum of nine numbers (which excluded the largest of the ten numbers) from the sum of all ten numbers. Thus: 97-82=15. 15 is the largest number of the ten.\n<|im_end|>" }, { "id": "#6347", "title": "Four Sons", "fun": 2.19, "difficulty": 1.45, "author": "mad-ade", "desc": "Mad Ade's uncle, Rod Wolloper, has 4 sons. In 13 years the combined ages of the four sons will be 96. So what would their combined ages be in just 7 years?", "hint": "No hint available.", "answer": "72, each year the combined ages of the sons increases by four.\n\r\nSo 13 years =96yrs \r\n13yrs - 7yrs = 6yrs\r\n6yrs * 4yrs = 24yrs \r\n96yrs - 24yrs = 72 yrs", "category": "Math", "date": "08/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's uncle, Rod Wolloper, has 4 sons. In 13 years the combined ages of the four sons will be 96. So what would their combined ages be in just 7 years?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n72, each year the combined ages of the sons increases by four.\n\r\nSo 13 years =96yrs \r\n13yrs - 7yrs = 6yrs\r\n6yrs * 4yrs = 24yrs \r\n96yrs - 24yrs = 72 yrs\n<|im_start|>answer\n72, each year the combined ages of the sons increases by four.\n\r\nSo 13 years =96yrs \r\n13yrs - 7yrs = 6yrs\r\n6yrs * 4yrs = 24yrs \r\n96yrs - 24yrs = 72 yrs\n<|im_end|>" }, { "id": "#5697", "title": "Tunnel Vision", "fun": 2.19, "difficulty": 2.02, "author": "Bobbrt", "desc": "A train passes through a long tunnel in the mountains. The train is 125 meters long, and travels at 40 kilometers per hour.\r\nJust as the last car is completely inside the tunnel, a man begins walking from the end of the train to the front. He walks at 5 kilometers per hour and reaches the front of the train just as it emerges into the daylight.\r\nHow long is the tunnel?", "hint": "No hint available.", "answer": "Let x = the length of the tunnel in meters. The man travels x meters at 45 kilometers per hour (the combined speed of the train and his walking) in the same time that the train travels (x-125) meters at 40 kilometers per hour.\r\nThe equation x/45 = (x-125)/40 solves to x=1125. Therefore, the length of the tunnel is 1125 meters.", "category": "Math", "date": "07/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA train passes through a long tunnel in the mountains. The train is 125 meters long, and travels at 40 kilometers per hour.\r\nJust as the last car is completely inside the tunnel, a man begins walking from the end of the train to the front. He walks at 5 kilometers per hour and reaches the front of the train just as it emerges into the daylight.\r\nHow long is the tunnel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet x = the length of the tunnel in meters. The man travels x meters at 45 kilometers per hour (the combined speed of the train and his walking) in the same time that the train travels (x-125) meters at 40 kilometers per hour.\r\nThe equation x/45 = (x-125)/40 solves to x=1125. Therefore, the length of the tunnel is 1125 meters.\n<|im_start|>answer\nLet x = the length of the tunnel in meters. The man travels x meters at 45 kilometers per hour (the combined speed of the train and his walking) in the same time that the train travels (x-125) meters at 40 kilometers per hour.\r\nThe equation x/45 = (x-125)/40 solves to x=1125. Therefore, the length of the tunnel is 1125 meters.\n<|im_end|>" }, { "id": "#13854", "title": "Creating a Newspaper", "fun": 2.19, "difficulty": 1.91, "author": "Lemens", "desc": "The newspaper has 4 different pages of the classifieds, 2 different pages of sports, 7 different pages of entertainment, 5 different pages of business, and 30 different pages of the front news section. How many different ways can be used to create a \"miniature sample\" of the paper by having the sample consist of 1 page from each section?", "hint": "Use the Fundamental Counting Principle to solve.", "answer": "4x2x7x5x30 = 8400\n\r\nTherefore, there are 8400 different ways to create the \"miniature sample\" of the paper.", "category": "Math", "date": "07/16/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe newspaper has 4 different pages of the classifieds, 2 different pages of sports, 7 different pages of entertainment, 5 different pages of business, and 30 different pages of the front news section. How many different ways can be used to create a \"miniature sample\" of the paper by having the sample consist of 1 page from each section?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4x2x7x5x30 = 8400\n\r\nTherefore, there are 8400 different ways to create the \"miniature sample\" of the paper.\n<|im_start|>answer\n4x2x7x5x30 = 8400\n\r\nTherefore, there are 8400 different ways to create the \"miniature sample\" of the paper.\n<|im_end|>" }, { "id": "#8835", "title": "Who's the Shortest?", "fun": 2.19, "difficulty": 1.02, "author": "warrior", "desc": "James is taller than Kate and Carly. Sammy is shorter than Kate. Natalie is shorter than Kate and Sammy, however Sammy is shorter than Carly. \n\r\nWho is the shortest?", "hint": "No hint available.", "answer": "Natalie.\n\r\nSammy is shorter than Kate and Carly, who are both shorter than James. Since Natalie is shorter than Sammy, she must be the shortest.", "category": "Logic", "date": "11/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJames is taller than Kate and Carly. Sammy is shorter than Kate. Natalie is shorter than Kate and Sammy, however Sammy is shorter than Carly. \n\r\nWho is the shortest?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNatalie.\n\r\nSammy is shorter than Kate and Carly, who are both shorter than James. Since Natalie is shorter than Sammy, she must be the shortest.\n<|im_start|>answer\nNatalie.\n\r\nSammy is shorter than Kate and Carly, who are both shorter than James. Since Natalie is shorter than Sammy, she must be the shortest.\n<|im_end|>" }, { "id": "#3841", "title": "Can you make 67", "fun": 2.19, "difficulty": 1.5, "author": "bighippo4", "desc": "How do you make 67 with 6 (six) \"sixes\" using math symbols?", "hint": "No hint available.", "answer": "66 + (66/66)", "category": "Math", "date": "05/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow do you make 67 with 6 (six) \"sixes\" using math symbols?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n66 + (66/66)\n<|im_start|>answer\n66 + (66/66)\n<|im_end|>" }, { "id": "#16341", "title": "Maria's Party", "fun": 2.19, "difficulty": 1.19, "author": "catsrfun37", "desc": "Maria is going to her father's mom's husband's grandma's daughter's party. Everyone only had 1 child. Whose birthday party is Maria going to and what relation is that person to her?", "hint": "No hint available.", "answer": "It is her great grandma's party. It is her father's mom's (her grandma) husband's (granddad)grandmom's (great great grandma) daughter (great grandma).", "category": "Logic", "date": "01/27/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMaria is going to her father's mom's husband's grandma's daughter's party. Everyone only had 1 child. Whose birthday party is Maria going to and what relation is that person to her?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is her great grandma's party. It is her father's mom's (her grandma) husband's (granddad)grandmom's (great great grandma) daughter (great grandma).\n<|im_start|>answer\nIt is her great grandma's party. It is her father's mom's (her grandma) husband's (granddad)grandmom's (great great grandma) daughter (great grandma).\n<|im_end|>" }, { "id": "#26013", "title": "What Two Numbers", "fun": 2.19, "difficulty": 2.08, "author": "metallicman", "desc": "What two numbers are used in this number pattern?\n\r\n50, 50, 100, 100, 50, 51, 53, 52, 50....", "hint": "No hint available.", "answer": "The numbers 1 and 2.\n\r\nFirst it is in this order: multiplication, division, addition, and subtraction. Each step always begins with 1 and then 2, then it returns to 1 for the next step.\n\r\nStep 1) 50x1=50 then 50x2=100; \n\r\nStep 2) 100/1=100 then 100/2=50; \n\r\nStep 3) 50+1=51 then 51+2=53; \n\r\nStep 4) 53-1= 52 then 52-2=50.", "category": "Math", "date": "09/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat two numbers are used in this number pattern?\n\r\n50, 50, 100, 100, 50, 51, 53, 52, 50....\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers 1 and 2.\n\r\nFirst it is in this order: multiplication, division, addition, and subtraction. Each step always begins with 1 and then 2, then it returns to 1 for the next step.\n\r\nStep 1) 50x1=50 then 50x2=100; \n\r\nStep 2) 100/1=100 then 100/2=50; \n\r\nStep 3) 50+1=51 then 51+2=53; \n\r\nStep 4) 53-1= 52 then 52-2=50.\n<|im_start|>answer\nThe numbers 1 and 2.\n\r\nFirst it is in this order: multiplication, division, addition, and subtraction. Each step always begins with 1 and then 2, then it returns to 1 for the next step.\n\r\nStep 1) 50x1=50 then 50x2=100; \n\r\nStep 2) 100/1=100 then 100/2=50; \n\r\nStep 3) 50+1=51 then 51+2=53; \n\r\nStep 4) 53-1= 52 then 52-2=50.\n<|im_end|>" }, { "id": "#12534", "title": "Mad Ade's Taxi", "fun": 2.19, "difficulty": 2.36, "author": "mad-ade", "desc": "Mad Ade rents a private car for a Kebabville-Dopeytown-Kebabville trip. It costs him 300 Madadian Wonks every day. \n\r\nOne day the car driver informed Mad Ade that there were two students from Sillychester who wished to go from Sillychester to Dopeytown and back to Sillychester. Sillychester is halfway between Kebabville and Dopeytown. Mad Ade asked the driver to let the students travel with him. \n\r\nOn the first day when they came, Mad Ade said, \"If you tell me the mathematically correct price you should pay individually for your portion of the trip, I will let you travel for free.\" \n\r\nHow much should the individual student pay for their journey?", "hint": "No hint available.", "answer": "The individual student should pay 50 Wonks for their journey. \n\r\nNote that 3 persons are travelling between Sillychester and Dopeytown. \n\r\nThe entire trip costs 300 Wonks to Mad Ade. Hence, half of the trip costs 150 Wonks. \n\r\nFor Kebabville-Sillychester-Kebabville, only one person i.e. Mad Ade is travelling. Hence, he would pay 150 Wonks. \n\r\nFor Sillychester-Dopeytown-Sillychester, three persons i.e Mad Ade and two students, are travelling. Hence, each student would pay 50 Wonks.", "category": "Math", "date": "05/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade rents a private car for a Kebabville-Dopeytown-Kebabville trip. It costs him 300 Madadian Wonks every day. \n\r\nOne day the car driver informed Mad Ade that there were two students from Sillychester who wished to go from Sillychester to Dopeytown and back to Sillychester. Sillychester is halfway between Kebabville and Dopeytown. Mad Ade asked the driver to let the students travel with him. \n\r\nOn the first day when they came, Mad Ade said, \"If you tell me the mathematically correct price you should pay individually for your portion of the trip, I will let you travel for free.\" \n\r\nHow much should the individual student pay for their journey?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe individual student should pay 50 Wonks for their journey. \n\r\nNote that 3 persons are travelling between Sillychester and Dopeytown. \n\r\nThe entire trip costs 300 Wonks to Mad Ade. Hence, half of the trip costs 150 Wonks. \n\r\nFor Kebabville-Sillychester-Kebabville, only one person i.e. Mad Ade is travelling. Hence, he would pay 150 Wonks. \n\r\nFor Sillychester-Dopeytown-Sillychester, three persons i.e Mad Ade and two students, are travelling. Hence, each student would pay 50 Wonks.\n<|im_start|>answer\nThe individual student should pay 50 Wonks for their journey. \n\r\nNote that 3 persons are travelling between Sillychester and Dopeytown. \n\r\nThe entire trip costs 300 Wonks to Mad Ade. Hence, half of the trip costs 150 Wonks. \n\r\nFor Kebabville-Sillychester-Kebabville, only one person i.e. Mad Ade is travelling. Hence, he would pay 150 Wonks. \n\r\nFor Sillychester-Dopeytown-Sillychester, three persons i.e Mad Ade and two students, are travelling. Hence, each student would pay 50 Wonks.\n<|im_end|>" }, { "id": "#43430", "title": "Sir Richard Murder", "fun": 2.19, "difficulty": 0.63, "author": "eggface", "desc": "\"What? Another murder?\" exclaimed Mr. Lombang after hearing the news that the incredibly wealthy Sir Richard had been murdered. Mr. Lombang found this case very similar to the murder of Miss Brown and, sure enough, Sir Whitehall, an ex-murderer, was on the list of suspects.\n\r\nThe suspects are the dashing young Lord Burgundy, the elderly Lady Green, and the rather arrogant Sir Whitehall. The places where the murder could have been committed are the kitchen, lounge, and bedroom. The weapons that are likely to have been used are a length of strong twine, an ancient dagger, and a gun.\n\r\nAll that Mr. Lombang knows is that the murderer had access to the gun, so help him to uncover the truth using these clues:\n\r\n1. Sir Whitehall had no access to the twine, although it was rumored by all of the staff that he kept a dagger in his room in case of assassination.\r\n2. The person in the bedroom was at the opposite side of the house to the gun.\r\n3. Sir Whitehall was verified to have been complaining to the cook in the kitchen for the majority of the evening.\r\n4. Lady Green constantly complained about the quality of the couches in the lounge and kept clear of them as a result.\r\n5. The person with the dagger was in the kitchen.\n\r\nCan you work out who murdered Sir Richard and in what room?", "hint": "No hint available.", "answer": "Lord Burgundy was in the lounge with the gun.\r\nSir Whitehall was in the kitchen with his dagger.\r\nLady Green was in her bedroom with the twine.\n\r\nSo Sir Richard was killed by Lord Burgundy with the gun in the lounge.", "category": "Logic-Grid", "date": "10/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n\"What? Another murder?\" exclaimed Mr. Lombang after hearing the news that the incredibly wealthy Sir Richard had been murdered. Mr. Lombang found this case very similar to the murder of Miss Brown and, sure enough, Sir Whitehall, an ex-murderer, was on the list of suspects.\n\r\nThe suspects are the dashing young Lord Burgundy, the elderly Lady Green, and the rather arrogant Sir Whitehall. The places where the murder could have been committed are the kitchen, lounge, and bedroom. The weapons that are likely to have been used are a length of strong twine, an ancient dagger, and a gun.\n\r\nAll that Mr. Lombang knows is that the murderer had access to the gun, so help him to uncover the truth using these clues:\n\r\n1. Sir Whitehall had no access to the twine, although it was rumored by all of the staff that he kept a dagger in his room in case of assassination.\r\n2. The person in the bedroom was at the opposite side of the house to the gun.\r\n3. Sir Whitehall was verified to have been complaining to the cook in the kitchen for the majority of the evening.\r\n4. Lady Green constantly complained about the quality of the couches in the lounge and kept clear of them as a result.\r\n5. The person with the dagger was in the kitchen.\n\r\nCan you work out who murdered Sir Richard and in what room?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLord Burgundy was in the lounge with the gun.\r\nSir Whitehall was in the kitchen with his dagger.\r\nLady Green was in her bedroom with the twine.\n\r\nSo Sir Richard was killed by Lord Burgundy with the gun in the lounge.\n<|im_start|>answer\nLord Burgundy was in the lounge with the gun.\r\nSir Whitehall was in the kitchen with his dagger.\r\nLady Green was in her bedroom with the twine.\n\r\nSo Sir Richard was killed by Lord Burgundy with the gun in the lounge.\n<|im_end|>" }, { "id": "#24781", "title": "Big Family", "fun": 2.19, "difficulty": 1.26, "author": "Cogito", "desc": "How can your brother/sister become your brother/sister in law?", "hint": "No hint available.", "answer": "You and your sibling both marry siblings.", "category": "Logic", "date": "07/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can your brother/sister become your brother/sister in law?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou and your sibling both marry siblings.\n<|im_start|>answer\nYou and your sibling both marry siblings.\n<|im_end|>" }, { "id": "#480", "title": "Sam Walks and Rides...", "fun": 2.19, "difficulty": 1.3800000000000001, "author": "Sydgal47", "desc": "Sam walks to her best friend's house at 2 miles per hour. She eats lunch there for 1 hour and then borrows a bike and rides home 5 times faster than she could walk. There are 10 miles between the two houses. What time must Sam leave from her house in the morning to be back by 4:00 p.m.?", "hint": "No hint available.", "answer": "9:00 am", "category": "Math", "date": "05/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSam walks to her best friend's house at 2 miles per hour. She eats lunch there for 1 hour and then borrows a bike and rides home 5 times faster than she could walk. There are 10 miles between the two houses. What time must Sam leave from her house in the morning to be back by 4:00 p.m.?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9:00 am\n<|im_start|>answer\n9:00 am\n<|im_end|>" }, { "id": "#4552", "title": "E-mails", "fun": 2.19, "difficulty": 2.17, "author": "mad-ade", "desc": "Mad Ade sends an e-mail to two friends, asking each of them to copy the e-mail and send it to two of their friends, those in turn send it to two of their friends, and so on. \n\r\nHow many e-mails would have been sent by the time 30 sets of e-mails had been forwarded?", "hint": "No hint available.", "answer": "2147483646 \n\r\nMad Ade sent the mail to 2 persons. Those 2 sent the mail to 2 persons each, total 4 persons. Now, those 4 person sent mail to a total of 8 persons, then 8 to 16 persons, 16 to 32 persons and so on.... Hence, it a series of 2, 4, 8, 16, 32 up to 30 numbers.\n\r\nIt is a geometric series with a common ratio 2 and first number is also 2. Summation of such series is given by A * (Rn - 1) / (R - 1) where \r\nA = first term \r\nR = common ratio \r\nn = total numbers \n\r\nSo, total number of times mail sent by the time 30 sets of e-mails had been forwarded\r\n= 2 * (2^30 - 1) / (2 - 1) \r\n= 2 * (1073741824 - 1) \r\n= 2 * 1073741823 \r\n= 2147483646", "category": "Math", "date": "06/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade sends an e-mail to two friends, asking each of them to copy the e-mail and send it to two of their friends, those in turn send it to two of their friends, and so on. \n\r\nHow many e-mails would have been sent by the time 30 sets of e-mails had been forwarded?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2147483646 \n\r\nMad Ade sent the mail to 2 persons. Those 2 sent the mail to 2 persons each, total 4 persons. Now, those 4 person sent mail to a total of 8 persons, then 8 to 16 persons, 16 to 32 persons and so on.... Hence, it a series of 2, 4, 8, 16, 32 up to 30 numbers.\n\r\nIt is a geometric series with a common ratio 2 and first number is also 2. Summation of such series is given by A * (Rn - 1) / (R - 1) where \r\nA = first term \r\nR = common ratio \r\nn = total numbers \n\r\nSo, total number of times mail sent by the time 30 sets of e-mails had been forwarded\r\n= 2 * (2^30 - 1) / (2 - 1) \r\n= 2 * (1073741824 - 1) \r\n= 2 * 1073741823 \r\n= 2147483646\n<|im_start|>answer\n2147483646 \n\r\nMad Ade sent the mail to 2 persons. Those 2 sent the mail to 2 persons each, total 4 persons. Now, those 4 person sent mail to a total of 8 persons, then 8 to 16 persons, 16 to 32 persons and so on.... Hence, it a series of 2, 4, 8, 16, 32 up to 30 numbers.\n\r\nIt is a geometric series with a common ratio 2 and first number is also 2. Summation of such series is given by A * (Rn - 1) / (R - 1) where \r\nA = first term \r\nR = common ratio \r\nn = total numbers \n\r\nSo, total number of times mail sent by the time 30 sets of e-mails had been forwarded\r\n= 2 * (2^30 - 1) / (2 - 1) \r\n= 2 * (1073741824 - 1) \r\n= 2 * 1073741823 \r\n= 2147483646\n<|im_end|>" }, { "id": "#4581", "title": "Cube Piles", "fun": 2.19, "difficulty": 1.66, "author": "mad-ade", "desc": "Mad Ade managed to arranged twenty cubes in four piles of differing amounts. Using these clues can you work out how many cubes Mad Ade put in each pile:\n\r\n1. All piles contain an even number of cubes\n\r\n2. There are twice as many cubes in the first pile as in the second pile. \n\r\n3. The largest number of cubes is in the first pile.\n\r\n4. All piles have a different number of cubes.\n\r\n5. Each pile has at least one cube. \n\r\nHow many cubes would be in each pile?", "hint": "No hint available.", "answer": "pile 1 - 8, \r\npile 2 - 4, \r\npile 3 - 2 or 6, \r\npile 4 - 6 or 2.", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade managed to arranged twenty cubes in four piles of differing amounts. Using these clues can you work out how many cubes Mad Ade put in each pile:\n\r\n1. All piles contain an even number of cubes\n\r\n2. There are twice as many cubes in the first pile as in the second pile. \n\r\n3. The largest number of cubes is in the first pile.\n\r\n4. All piles have a different number of cubes.\n\r\n5. Each pile has at least one cube. \n\r\nHow many cubes would be in each pile?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\npile 1 - 8, \r\npile 2 - 4, \r\npile 3 - 2 or 6, \r\npile 4 - 6 or 2.\n<|im_start|>answer\npile 1 - 8, \r\npile 2 - 4, \r\npile 3 - 2 or 6, \r\npile 4 - 6 or 2.\n<|im_end|>" }, { "id": "#23839", "title": "A Frantic Father's Day", "fun": 2.19, "difficulty": 1.11, "author": "cka92", "desc": "Three forgetful best friends (Frankie, Emily, and Alana, yes, they're all girls) realized the day just before Father's day that they had not gotten their dads gifts! They called each other up and made a plan to go shopping. However, none of the girls could agree on where to buy a gift, so they went to three different stores and bought three different gifts. You must determine the girls' fathers' names, the store they went to, and the gifts they bought.\r\nTheir Names: Frankie, Alana, and Emily\r\nTheir dad's Names: Dan, Rich, and Max\r\nThe Stores: Super Fan, Ducks Unlimited, and Bass Pro Shops\r\nThe Gifts: ball cap, duck call, and a coffee mug\n\r\n1. Emily knew her dad loved to be outdoors, so she chose not to go to Super Fan and buy a coffee mug.\n\r\n2. Max's daughter didn't have to think long to know her father wouldn't want to wear a hat.\n\r\n3.Alana's father Rich, likes being outdoors, but that's not the kind of store Alana chose to go to.\n\r\n4. The gift Frankie chose to get makes noises.\n\r\n5. The girl that went to Ducks Unlimited had to call Alana to ask her opinion on which color gift she should get her father.", "hint": "Are you sure you need a hint? I mean, this is the easiest teaser I could come up with. But if you really need a hint, or you figured out that that last clue was pretty much pointless, the colored gift in the last clue is something you would wear.", "answer": "Frankie; Max; Duck Call; Bass Pro Shops\r\nAlana; Rich; Coffee Mug; Super Fan\r\nEmily; Dan; Ball Cap; Ducks Unlimited", "category": "Logic-Grid", "date": "06/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree forgetful best friends (Frankie, Emily, and Alana, yes, they're all girls) realized the day just before Father's day that they had not gotten their dads gifts! They called each other up and made a plan to go shopping. However, none of the girls could agree on where to buy a gift, so they went to three different stores and bought three different gifts. You must determine the girls' fathers' names, the store they went to, and the gifts they bought.\r\nTheir Names: Frankie, Alana, and Emily\r\nTheir dad's Names: Dan, Rich, and Max\r\nThe Stores: Super Fan, Ducks Unlimited, and Bass Pro Shops\r\nThe Gifts: ball cap, duck call, and a coffee mug\n\r\n1. Emily knew her dad loved to be outdoors, so she chose not to go to Super Fan and buy a coffee mug.\n\r\n2. Max's daughter didn't have to think long to know her father wouldn't want to wear a hat.\n\r\n3.Alana's father Rich, likes being outdoors, but that's not the kind of store Alana chose to go to.\n\r\n4. The gift Frankie chose to get makes noises.\n\r\n5. The girl that went to Ducks Unlimited had to call Alana to ask her opinion on which color gift she should get her father.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrankie; Max; Duck Call; Bass Pro Shops\r\nAlana; Rich; Coffee Mug; Super Fan\r\nEmily; Dan; Ball Cap; Ducks Unlimited\n<|im_start|>answer\nFrankie; Max; Duck Call; Bass Pro Shops\r\nAlana; Rich; Coffee Mug; Super Fan\r\nEmily; Dan; Ball Cap; Ducks Unlimited\n<|im_end|>" }, { "id": "#40228", "title": "Big Polygon", "fun": 2.19, "difficulty": 2.57, "author": "shenqiang", "desc": "The four edges of a quadrangle have lengths 1, 5, 5, and 7, and the two edges with length 5 are perpendicular. Four squares are built from the four edges. The adjacent vertices of these squares are connected so that a big polygon is formed. Find the area of this big polygon.", "hint": "Since 5^2+5^2=1^2+7^2, by connecting the diagonal of the original quadrangle, we see that the edge with length 1 is also perpendicular to the edge with length 7.", "answer": "The big polygon is made up of the original quadrangle, four squares, two right-angled triangles, and two remaining triangles.\n\r\nThe area of the original quadrangle is (5*5+1*7)/2=16, which is also the sum of the areas of the two right-angled triangles. The four squares total 1^2+5^2+5^2+7^2=100. The sum of the areas of the two remaining triangles also equal the area of the original quadrangle. This is easily seen by rotating the triangles by 90 degrees, and connecting the other diagonal of the original quadrangle.\n\r\nTherefore, the total area is 100+16*3=148.", "category": "Math", "date": "01/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe four edges of a quadrangle have lengths 1, 5, 5, and 7, and the two edges with length 5 are perpendicular. Four squares are built from the four edges. The adjacent vertices of these squares are connected so that a big polygon is formed. Find the area of this big polygon.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe big polygon is made up of the original quadrangle, four squares, two right-angled triangles, and two remaining triangles.\n\r\nThe area of the original quadrangle is (5*5+1*7)/2=16, which is also the sum of the areas of the two right-angled triangles. The four squares total 1^2+5^2+5^2+7^2=100. The sum of the areas of the two remaining triangles also equal the area of the original quadrangle. This is easily seen by rotating the triangles by 90 degrees, and connecting the other diagonal of the original quadrangle.\n\r\nTherefore, the total area is 100+16*3=148.\n<|im_start|>answer\nThe big polygon is made up of the original quadrangle, four squares, two right-angled triangles, and two remaining triangles.\n\r\nThe area of the original quadrangle is (5*5+1*7)/2=16, which is also the sum of the areas of the two right-angled triangles. The four squares total 1^2+5^2+5^2+7^2=100. The sum of the areas of the two remaining triangles also equal the area of the original quadrangle. This is easily seen by rotating the triangles by 90 degrees, and connecting the other diagonal of the original quadrangle.\n\r\nTherefore, the total area is 100+16*3=148.\n<|im_end|>" }, { "id": "#19597", "title": "Remember That Train Scene In 'Stand By Me'?", "fun": 2.19, "difficulty": 2.69, "author": "strzynski", "desc": "A man is standing on a railway bridge joining locations A and B. He is 3/8 the distance across, walking from A to B. He hears a train approaching behind him (from A's side); it is traveling 80 kph (that's kilometers per hour for you non-metric fans!) If he were to run back to A, he would meet the train at A. If he were to run to B, the train would overtake him at B.\n\r\nHow fast can the man run?", "hint": "You will never know exact distances in this problem, nor will you actually need to. Remember distance equals rate times time, or D = RT. I recommend drawing a picture to map out other distances, such as the man to A and B, respectively.", "answer": "Start by assigning some variables. We have three - the distance from the train to A, which I will call x; the distance from A to B, which I will call y; and the rate of the running man, in kph, which I will call z.\n\r\nThe man is 3/8 the distance of A to B (which is y), so he is 3/8 y from A and 5/8 y from B (please note that the 'y' belongs in the numerator - the top of the fraction - not the bottom, so to be truly technical it is (3y)/8 and (5y)/8).\n\r\nThe time it takes the train to reach A is its rate divided by the distance, or 80/x. The time it takes the man to reach A would then be z/(3/8 y). Since they meet there, 80/x = z / (3/8 y). Solve for z, and simplify, to get z = 30y /x. \r\nThe time it takes the train to reach B is 80/(x + y), and the time it takes the man is z/(5/8 y). Again, since they meet there, 80/(x + y) = z/(5/8 y), and we get z = 50y /(x + y).\r\nSet these two z-values equal to each other, so that 30y /x = 50y / (x + y), and cross-multiply. You then get 30xy + 30 y^2 = 50xy. Regroup to get 30y^2 = 20xy. Divide by 30y to get y = 2/3 x. Don't worry about y being 0 and making this pointless - y is a distance, and distances *can't* be 0, right?\n\r\nSo what does that do for us? Well, y is 2/3 of x. That means that the distance from A to B is 2/3 the distance from the train to A. Now, the man himself is 3/8 the distance from A to B (y), so he is 3/8 of 2/3 x away from A, or just 1/4 x away from A. So, in the time it takes the train to travel x, the man travels 1/4 x. So the man is running at 1/4 the speed of the train, or 20kph.\n\r\nFeel like checking? OK. The train travels x and 2/3 x to get to B, or just 5/3 x. The man travels 5/8 y, or 5/8 (2/3 x), which is 5/12 x. And 5/3 divided by 5/12 is 1/4 again, so there you go.", "category": "Math", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is standing on a railway bridge joining locations A and B. He is 3/8 the distance across, walking from A to B. He hears a train approaching behind him (from A's side); it is traveling 80 kph (that's kilometers per hour for you non-metric fans!) If he were to run back to A, he would meet the train at A. If he were to run to B, the train would overtake him at B.\n\r\nHow fast can the man run?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStart by assigning some variables. We have three - the distance from the train to A, which I will call x; the distance from A to B, which I will call y; and the rate of the running man, in kph, which I will call z.\n\r\nThe man is 3/8 the distance of A to B (which is y), so he is 3/8 y from A and 5/8 y from B (please note that the 'y' belongs in the numerator - the top of the fraction - not the bottom, so to be truly technical it is (3y)/8 and (5y)/8).\n\r\nThe time it takes the train to reach A is its rate divided by the distance, or 80/x. The time it takes the man to reach A would then be z/(3/8 y). Since they meet there, 80/x = z / (3/8 y). Solve for z, and simplify, to get z = 30y /x. \r\nThe time it takes the train to reach B is 80/(x + y), and the time it takes the man is z/(5/8 y). Again, since they meet there, 80/(x + y) = z/(5/8 y), and we get z = 50y /(x + y).\r\nSet these two z-values equal to each other, so that 30y /x = 50y / (x + y), and cross-multiply. You then get 30xy + 30 y^2 = 50xy. Regroup to get 30y^2 = 20xy. Divide by 30y to get y = 2/3 x. Don't worry about y being 0 and making this pointless - y is a distance, and distances *can't* be 0, right?\n\r\nSo what does that do for us? Well, y is 2/3 of x. That means that the distance from A to B is 2/3 the distance from the train to A. Now, the man himself is 3/8 the distance from A to B (y), so he is 3/8 of 2/3 x away from A, or just 1/4 x away from A. So, in the time it takes the train to travel x, the man travels 1/4 x. So the man is running at 1/4 the speed of the train, or 20kph.\n\r\nFeel like checking? OK. The train travels x and 2/3 x to get to B, or just 5/3 x. The man travels 5/8 y, or 5/8 (2/3 x), which is 5/12 x. And 5/3 divided by 5/12 is 1/4 again, so there you go.\n<|im_start|>answer\nStart by assigning some variables. We have three - the distance from the train to A, which I will call x; the distance from A to B, which I will call y; and the rate of the running man, in kph, which I will call z.\n\r\nThe man is 3/8 the distance of A to B (which is y), so he is 3/8 y from A and 5/8 y from B (please note that the 'y' belongs in the numerator - the top of the fraction - not the bottom, so to be truly technical it is (3y)/8 and (5y)/8).\n\r\nThe time it takes the train to reach A is its rate divided by the distance, or 80/x. The time it takes the man to reach A would then be z/(3/8 y). Since they meet there, 80/x = z / (3/8 y). Solve for z, and simplify, to get z = 30y /x. \r\nThe time it takes the train to reach B is 80/(x + y), and the time it takes the man is z/(5/8 y). Again, since they meet there, 80/(x + y) = z/(5/8 y), and we get z = 50y /(x + y).\r\nSet these two z-values equal to each other, so that 30y /x = 50y / (x + y), and cross-multiply. You then get 30xy + 30 y^2 = 50xy. Regroup to get 30y^2 = 20xy. Divide by 30y to get y = 2/3 x. Don't worry about y being 0 and making this pointless - y is a distance, and distances *can't* be 0, right?\n\r\nSo what does that do for us? Well, y is 2/3 of x. That means that the distance from A to B is 2/3 the distance from the train to A. Now, the man himself is 3/8 the distance from A to B (y), so he is 3/8 of 2/3 x away from A, or just 1/4 x away from A. So, in the time it takes the train to travel x, the man travels 1/4 x. So the man is running at 1/4 the speed of the train, or 20kph.\n\r\nFeel like checking? OK. The train travels x and 2/3 x to get to B, or just 5/3 x. The man travels 5/8 y, or 5/8 (2/3 x), which is 5/12 x. And 5/3 divided by 5/12 is 1/4 again, so there you go.\n<|im_end|>" }, { "id": "#11691", "title": "Special Composer", "fun": 2.19, "difficulty": 1.23, "author": "silver_sword", "desc": "A music teacher once told his student a fast way to make good compositions. The secret is to choose a famous composition, turn it around, and you will get your own original composition! \n\r\nThe student happily tried this secret, and it indeed works. However, this secret does not work when he uses his music teacher's compositions. Why?", "hint": "No hint available.", "answer": "The teacher's compositions were derived from the same secret, and hence when the student used his teacher's secret on his teacher's compositions, he got back a composition which was unoriginal.", "category": "Logic", "date": "04/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA music teacher once told his student a fast way to make good compositions. The secret is to choose a famous composition, turn it around, and you will get your own original composition! \n\r\nThe student happily tried this secret, and it indeed works. However, this secret does not work when he uses his music teacher's compositions. Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe teacher's compositions were derived from the same secret, and hence when the student used his teacher's secret on his teacher's compositions, he got back a composition which was unoriginal.\n<|im_start|>answer\nThe teacher's compositions were derived from the same secret, and hence when the student used his teacher's secret on his teacher's compositions, he got back a composition which was unoriginal.\n<|im_end|>" }, { "id": "#3141", "title": "Break In", "fun": 2.19, "difficulty": 1.08, "author": "204_blaze_41", "desc": "Flossy returned to her apartment one evening to find that it had been broken into and vandalized. Pictures were smashed, personal letters were ripped, furniture was slashed, obscene graffiti written on the wall, and her favourite dresses torn. Flossy told Shadow that she suspected her ex-boyfriend, Sid. Shadow went to see Sid and explained that Flossy's apartment had been broken into. Sid said he knew nothing about it, but would be happy to help catch the person who wrote such nasty things and caused such damage. Shadow spoke with Sid for a few more minutes then told him he was under arrest for the crime. How did he know that Sid was the vandal?", "hint": "No hint available.", "answer": "Sid mentioned the obscene graffiti but denied knowledge of the break-in.", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFlossy returned to her apartment one evening to find that it had been broken into and vandalized. Pictures were smashed, personal letters were ripped, furniture was slashed, obscene graffiti written on the wall, and her favourite dresses torn. Flossy told Shadow that she suspected her ex-boyfriend, Sid. Shadow went to see Sid and explained that Flossy's apartment had been broken into. Sid said he knew nothing about it, but would be happy to help catch the person who wrote such nasty things and caused such damage. Shadow spoke with Sid for a few more minutes then told him he was under arrest for the crime. How did he know that Sid was the vandal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSid mentioned the obscene graffiti but denied knowledge of the break-in.\n<|im_start|>answer\nSid mentioned the obscene graffiti but denied knowledge of the break-in.\n<|im_end|>" }, { "id": "#1992", "title": "Prizes", "fun": 2.19, "difficulty": 1.01, "author": "Majeen", "desc": "Caris, Tina and Stephen each won a prize at the Christmas party. Caris gave her chocolate to Tina in exchange for her water pistol. Caris then changed with Stephen for the book. Then Tina and Stephen swapped prizes. Who has which present?", "hint": "No hint available.", "answer": "Stephen now has the chocolate. Tina now has the water pistol. Caris now has the book.", "category": "Logic", "date": "01/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCaris, Tina and Stephen each won a prize at the Christmas party. Caris gave her chocolate to Tina in exchange for her water pistol. Caris then changed with Stephen for the book. Then Tina and Stephen swapped prizes. Who has which present?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStephen now has the chocolate. Tina now has the water pistol. Caris now has the book.\n<|im_start|>answer\nStephen now has the chocolate. Tina now has the water pistol. Caris now has the book.\n<|im_end|>" }, { "id": "#40061", "title": "Increasing Order", "fun": 2.19, "difficulty": 2.33, "author": "shenqiang", "desc": "The following numbers are in increasing order: 3/5 < 7/a < 9/4 < 5/b < 16/(a+b), where a and b are positive integers. What is the value of a+b?", "hint": "No hint available.", "answer": "3/5<7/a implies 3a<35, or a<=11;\r\n7/a<9/4 implies 28<9a, or a>=4;\r\n9/4<5/b implies 9b<20, or b<=2;\r\n5/b<16/(a+b) implies 5(a+b)<16b, or 5a<11b.\n\r\nWe see that a is at least 4, but b can be only 1 or 2. Since 5a<11b, a=4 and b=2, whose sum is 6.", "category": "Math", "date": "01/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following numbers are in increasing order: 3/5 < 7/a < 9/4 < 5/b < 16/(a+b), where a and b are positive integers. What is the value of a+b?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3/5<7/a implies 3a<35, or a<=11;\r\n7/a<9/4 implies 28<9a, or a>=4;\r\n9/4<5/b implies 9b<20, or b<=2;\r\n5/b<16/(a+b) implies 5(a+b)<16b, or 5a<11b.\n\r\nWe see that a is at least 4, but b can be only 1 or 2. Since 5a<11b, a=4 and b=2, whose sum is 6.\n<|im_start|>answer\n3/5<7/a implies 3a<35, or a<=11;\r\n7/a<9/4 implies 28<9a, or a>=4;\r\n9/4<5/b implies 9b<20, or b<=2;\r\n5/b<16/(a+b) implies 5(a+b)<16b, or 5a<11b.\n\r\nWe see that a is at least 4, but b can be only 1 or 2. Since 5a<11b, a=4 and b=2, whose sum is 6.\n<|im_end|>" }, { "id": "#49086", "title": "One Weird Soccer Game", "fun": 2.19, "difficulty": 0.6000000000000001, "author": "dawnrising", "desc": "One day, two soccer teams played a soccer game. Each team scored on two kicks during the course of the game. However, all kicks were shot into the same goal. How is this possible?", "hint": "Soccer teams play 2 halves of 45 minutes.", "answer": "The teams scored their points in different halves. They switch sides during halftime. So they were all shot into one of the goals.", "category": "Logic", "date": "10/16/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, two soccer teams played a soccer game. Each team scored on two kicks during the course of the game. However, all kicks were shot into the same goal. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe teams scored their points in different halves. They switch sides during halftime. So they were all shot into one of the goals.\n<|im_start|>answer\nThe teams scored their points in different halves. They switch sides during halftime. So they were all shot into one of the goals.\n<|im_end|>" }, { "id": "#4136", "title": "More Babies", "fun": 2.19, "difficulty": 1.7, "author": "mad-ade", "desc": "If 300 babies are born each second of the day throughout the world, then how many were born in the year 2001?", "hint": "No hint available.", "answer": "9,460,800,000.", "category": "Math", "date": "05/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 300 babies are born each second of the day throughout the world, then how many were born in the year 2001?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9,460,800,000.\n<|im_start|>answer\n9,460,800,000.\n<|im_end|>" }, { "id": "#1245", "title": "Half as Long Till Midnight", "fun": 2.19, "difficulty": 1.53, "author": "gokaran", "desc": "If it were two hours later, it would be half as long until midnight as it would be if it were an hour later. What time is it now?", "hint": "No hint available.", "answer": "21:00\r\n2 hours later (23:00 - 1 hour before midnight) is half the time until midnight as 1 hour later (22:00 - 2 hours before midnight).", "category": "Math", "date": "10/31/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf it were two hours later, it would be half as long until midnight as it would be if it were an hour later. What time is it now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21:00\r\n2 hours later (23:00 - 1 hour before midnight) is half the time until midnight as 1 hour later (22:00 - 2 hours before midnight).\n<|im_start|>answer\n21:00\r\n2 hours later (23:00 - 1 hour before midnight) is half the time until midnight as 1 hour later (22:00 - 2 hours before midnight).\n<|im_end|>" }, { "id": "#50949", "title": "Simple Addition #3", "fun": 2.19, "difficulty": 0.51, "author": "TheRiddleTroll", "desc": "Add one straight line to the statement below to make it true.\r\n2+2=2", "hint": "You might be trying too hard.", "answer": "Slash through the equal sign.", "category": "Math", "date": "12/30/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdd one straight line to the statement below to make it true.\r\n2+2=2\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSlash through the equal sign.\n<|im_start|>answer\nSlash through the equal sign.\n<|im_end|>" }, { "id": "#4617", "title": "Password", "fun": 2.19, "difficulty": 2.73, "author": "mad-ade", "desc": "When Mad Ade was a private eye he never ceased to astound everyone by how quickly he could wrap up a case. One day he was out to solve yet another crime. It seems that someone had mischievously hacked into the online database maintained by \"Honest Ron's Secondhand Underwear Emporium\", and changed their password. The hacker then sent an untraceable e-mail that read: \"wish about happiness but never ask, 341223.\" Within a few minutes Mad Ade has found the new password, allowing the company to get back on track.\n\r\nWhat was the password?", "hint": "No hint available.", "answer": "Kebabs.\n\r\n Reverse the order of the numbers given, then from beginning to end, that is the number of the letter in each word; once you have all 6 letters reverse them and that forms the password.", "category": "Logic", "date": "06/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Mad Ade was a private eye he never ceased to astound everyone by how quickly he could wrap up a case. One day he was out to solve yet another crime. It seems that someone had mischievously hacked into the online database maintained by \"Honest Ron's Secondhand Underwear Emporium\", and changed their password. The hacker then sent an untraceable e-mail that read: \"wish about happiness but never ask, 341223.\" Within a few minutes Mad Ade has found the new password, allowing the company to get back on track.\n\r\nWhat was the password?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKebabs.\n\r\n Reverse the order of the numbers given, then from beginning to end, that is the number of the letter in each word; once you have all 6 letters reverse them and that forms the password.\n<|im_start|>answer\nKebabs.\n\r\n Reverse the order of the numbers given, then from beginning to end, that is the number of the letter in each word; once you have all 6 letters reverse them and that forms the password.\n<|im_end|>" }, { "id": "#39292", "title": "Jack and Jill", "fun": 2.19, "difficulty": 2.41, "author": "jamesbond", "desc": "Jack and Jill have grown up now, so much so that their ages add up to 64.\r\nBut Jill is confused as to how old each of them is. Jack gives her a clue: \"I am 5 times as old as you were when I was as old as you are now.\"\n\r\nCan you help Jill recall their ages correctly?", "hint": "Jack is much older than Jill than you might think...", "answer": "Jack: 40 yrs. old\r\nJill: 24 yrs. old\n\r\nExplanation:\n\r\nLet the present age of Jack be x and that of Jill be y. So, clearly, like everyone of you would have got: x+y=64.\n\r\nThe other equation is a bit tricky.\n\r\nJACK JILL\n\r\ny yrs. ? \n\r\n(Their ages when Jack was the age that Jill is at present)\n\r\nx yrs. y yrs.\n\r\n(Their present ages)\n\r\nSince we have moved back (x-y) yrs. to make Jack y yrs. old, to find the age of Jill at that time, we go back (x-y) yrs. from her present age. So, her age was y-(x-y) yrs. = 2y-x yrs.\n\r\nSince Jack's present age is 5 times that age, x= 5(2y-x). Hence, we get the second equation.\n\r\nSolving them, x=40 and y=24.", "category": "Math", "date": "11/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack and Jill have grown up now, so much so that their ages add up to 64.\r\nBut Jill is confused as to how old each of them is. Jack gives her a clue: \"I am 5 times as old as you were when I was as old as you are now.\"\n\r\nCan you help Jill recall their ages correctly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJack: 40 yrs. old\r\nJill: 24 yrs. old\n\r\nExplanation:\n\r\nLet the present age of Jack be x and that of Jill be y. So, clearly, like everyone of you would have got: x+y=64.\n\r\nThe other equation is a bit tricky.\n\r\nJACK JILL\n\r\ny yrs. ? \n\r\n(Their ages when Jack was the age that Jill is at present)\n\r\nx yrs. y yrs.\n\r\n(Their present ages)\n\r\nSince we have moved back (x-y) yrs. to make Jack y yrs. old, to find the age of Jill at that time, we go back (x-y) yrs. from her present age. So, her age was y-(x-y) yrs. = 2y-x yrs.\n\r\nSince Jack's present age is 5 times that age, x= 5(2y-x). Hence, we get the second equation.\n\r\nSolving them, x=40 and y=24.\n<|im_start|>answer\nJack: 40 yrs. old\r\nJill: 24 yrs. old\n\r\nExplanation:\n\r\nLet the present age of Jack be x and that of Jill be y. So, clearly, like everyone of you would have got: x+y=64.\n\r\nThe other equation is a bit tricky.\n\r\nJACK JILL\n\r\ny yrs. ? \n\r\n(Their ages when Jack was the age that Jill is at present)\n\r\nx yrs. y yrs.\n\r\n(Their present ages)\n\r\nSince we have moved back (x-y) yrs. to make Jack y yrs. old, to find the age of Jill at that time, we go back (x-y) yrs. from her present age. So, her age was y-(x-y) yrs. = 2y-x yrs.\n\r\nSince Jack's present age is 5 times that age, x= 5(2y-x). Hence, we get the second equation.\n\r\nSolving them, x=40 and y=24.\n<|im_end|>" }, { "id": "#18626", "title": "Mad Ade's Grid #2", "fun": 2.19, "difficulty": 2.71, "author": "mad-ade", "desc": "Mad Ade has drawn another grid, this time it is 20 squares by 10 squares.\r\nHow many different squares and rectangles(combined figure not individual) can be found in that grid?", "hint": "No hint available.", "answer": "11550 \n\r\nTotal number of Squares/rectangles = (Summation of row numbers) * (Summation of column numbers) \n\r\nHere there are 20 rows and 10 columns or vice versa. Hence, total possible squares/rectangles \r\n= ( 20 + 19 + 18 + 17 + 16 + .... + 3 + 2 + 1 ) * ( 10 + 9 +8 + 7 + .... + 3 + 2 + 1) \r\n= ( 210 ) * (55) \r\n= 11550 \n\r\nHence, total 11,550 different rectangles are possible.", "category": "Math", "date": "08/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade has drawn another grid, this time it is 20 squares by 10 squares.\r\nHow many different squares and rectangles(combined figure not individual) can be found in that grid?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11550 \n\r\nTotal number of Squares/rectangles = (Summation of row numbers) * (Summation of column numbers) \n\r\nHere there are 20 rows and 10 columns or vice versa. Hence, total possible squares/rectangles \r\n= ( 20 + 19 + 18 + 17 + 16 + .... + 3 + 2 + 1 ) * ( 10 + 9 +8 + 7 + .... + 3 + 2 + 1) \r\n= ( 210 ) * (55) \r\n= 11550 \n\r\nHence, total 11,550 different rectangles are possible.\n<|im_start|>answer\n11550 \n\r\nTotal number of Squares/rectangles = (Summation of row numbers) * (Summation of column numbers) \n\r\nHere there are 20 rows and 10 columns or vice versa. Hence, total possible squares/rectangles \r\n= ( 20 + 19 + 18 + 17 + 16 + .... + 3 + 2 + 1 ) * ( 10 + 9 +8 + 7 + .... + 3 + 2 + 1) \r\n= ( 210 ) * (55) \r\n= 11550 \n\r\nHence, total 11,550 different rectangles are possible.\n<|im_end|>" }, { "id": "#44119", "title": "Half Again As Big", "fun": 2.19, "difficulty": 3.4, "author": "javaguru", "desc": "What is the smallest integer such that if you rotate the number to the left you get a number that is exactly one and a half times the original number?\n\r\n(To rotate the number left, take the first digit off the front and append it to the end of the number. 2591 rotated to the left is 5912.)", "hint": "The number has 16 digits. I repeat, the number has 16 digits.", "answer": "1,176,470,588,235,294\r\nx 1.5 =\r\n1,764,705,882,352,941\n\n\r\nHere's how you find the number:\n\r\nYou needed to find a repeating fraction such that the number of repeating digits is one less than the number. This would be a prime number, and seven is the lowest number with this property. With this property, every digit in the repeating fraction appears in each place exactly once (i.e., every repeated digit appears as the first digit after the decimal exactly once for n/p where p > n > 0).\n\r\nNow you need to find any occurrences where the nth digit is followed by the 1.5nth digit. 'n' will obviously be even.\n\r\nThe repeating digits in 1/7 and their corresponding 'n' where the digits are the first digit after the decimal point are:\n\r\n142857 - repeating digits\r\n132645 - n\n\r\nThe ordered pairs of adjacent values of n are (1,3), (3,2), (2,6), (6,4), (4,5) and (5,1). None of these has the second number equal to one and a half times the first number.\n\r\nThe next prime number p with a repeating fraction for 1/p containing p-1 repeating digits is 17. The repeating digits for 1/17 are:\n\r\n.0588235294117647\n\r\nThe easiest way to assign 'n' for each digit is to list all of the digit pairs in order:\n\r\nXX - n (digit)\r\n05 - 1 (1)\r\n11 - 2 (11)\r\n17 - 3 (12)\r\n23 - 4 (5)\r\n29 - 5 (8)\r\n35 - 6 (6)\r\n41 - 7 (10)\r\n47 - 8 (15)\r\n52 - 9 (7)\r\n58 - 10 (2)\r\n64 - 11 (14)\r\n70 - 12 (16)\r\n76 - 13 (13)\r\n82 - 14 (4)\r\n88 - 15 (3)\r\n94 - 16 (9)\n\r\nChecking the even-numbered values of n in the above table reveals that ALL even values of n less than 2/3 of 17 are followed by the 1.5n digit. The values of n are and their digit places are:\n\r\n2,3 (11,12)\r\n4,6 (5,6)\r\n6,9 (6,7)\r\n8,12 (15,16)\r\n10,15 (2,3)\n\r\nSo the five smallest numbers with this property are:\n\r\n1176470588235294\r\n2352941176470588\r\n3529411764705882\r\n4705882352941176\r\n5882352941176470\n\r\nNotice that 2352941176470588 can be rotated TWICE, yielding 1.5 times the number each time since the 4->6->9 n digits are in order.", "category": "Math", "date": "02/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest integer such that if you rotate the number to the left you get a number that is exactly one and a half times the original number?\n\r\n(To rotate the number left, take the first digit off the front and append it to the end of the number. 2591 rotated to the left is 5912.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1,176,470,588,235,294\r\nx 1.5 =\r\n1,764,705,882,352,941\n\n\r\nHere's how you find the number:\n\r\nYou needed to find a repeating fraction such that the number of repeating digits is one less than the number. This would be a prime number, and seven is the lowest number with this property. With this property, every digit in the repeating fraction appears in each place exactly once (i.e., every repeated digit appears as the first digit after the decimal exactly once for n/p where p > n > 0).\n\r\nNow you need to find any occurrences where the nth digit is followed by the 1.5nth digit. 'n' will obviously be even.\n\r\nThe repeating digits in 1/7 and their corresponding 'n' where the digits are the first digit after the decimal point are:\n\r\n142857 - repeating digits\r\n132645 - n\n\r\nThe ordered pairs of adjacent values of n are (1,3), (3,2), (2,6), (6,4), (4,5) and (5,1). None of these has the second number equal to one and a half times the first number.\n\r\nThe next prime number p with a repeating fraction for 1/p containing p-1 repeating digits is 17. The repeating digits for 1/17 are:\n\r\n.0588235294117647\n\r\nThe easiest way to assign 'n' for each digit is to list all of the digit pairs in order:\n\r\nXX - n (digit)\r\n05 - 1 (1)\r\n11 - 2 (11)\r\n17 - 3 (12)\r\n23 - 4 (5)\r\n29 - 5 (8)\r\n35 - 6 (6)\r\n41 - 7 (10)\r\n47 - 8 (15)\r\n52 - 9 (7)\r\n58 - 10 (2)\r\n64 - 11 (14)\r\n70 - 12 (16)\r\n76 - 13 (13)\r\n82 - 14 (4)\r\n88 - 15 (3)\r\n94 - 16 (9)\n\r\nChecking the even-numbered values of n in the above table reveals that ALL even values of n less than 2/3 of 17 are followed by the 1.5n digit. The values of n are and their digit places are:\n\r\n2,3 (11,12)\r\n4,6 (5,6)\r\n6,9 (6,7)\r\n8,12 (15,16)\r\n10,15 (2,3)\n\r\nSo the five smallest numbers with this property are:\n\r\n1176470588235294\r\n2352941176470588\r\n3529411764705882\r\n4705882352941176\r\n5882352941176470\n\r\nNotice that 2352941176470588 can be rotated TWICE, yielding 1.5 times the number each time since the 4->6->9 n digits are in order.\n<|im_start|>answer\n1,176,470,588,235,294\r\nx 1.5 =\r\n1,764,705,882,352,941\n\n\r\nHere's how you find the number:\n\r\nYou needed to find a repeating fraction such that the number of repeating digits is one less than the number. This would be a prime number, and seven is the lowest number with this property. With this property, every digit in the repeating fraction appears in each place exactly once (i.e., every repeated digit appears as the first digit after the decimal exactly once for n/p where p > n > 0).\n\r\nNow you need to find any occurrences where the nth digit is followed by the 1.5nth digit. 'n' will obviously be even.\n\r\nThe repeating digits in 1/7 and their corresponding 'n' where the digits are the first digit after the decimal point are:\n\r\n142857 - repeating digits\r\n132645 - n\n\r\nThe ordered pairs of adjacent values of n are (1,3), (3,2), (2,6), (6,4), (4,5) and (5,1). None of these has the second number equal to one and a half times the first number.\n\r\nThe next prime number p with a repeating fraction for 1/p containing p-1 repeating digits is 17. The repeating digits for 1/17 are:\n\r\n.0588235294117647\n\r\nThe easiest way to assign 'n' for each digit is to list all of the digit pairs in order:\n\r\nXX - n (digit)\r\n05 - 1 (1)\r\n11 - 2 (11)\r\n17 - 3 (12)\r\n23 - 4 (5)\r\n29 - 5 (8)\r\n35 - 6 (6)\r\n41 - 7 (10)\r\n47 - 8 (15)\r\n52 - 9 (7)\r\n58 - 10 (2)\r\n64 - 11 (14)\r\n70 - 12 (16)\r\n76 - 13 (13)\r\n82 - 14 (4)\r\n88 - 15 (3)\r\n94 - 16 (9)\n\r\nChecking the even-numbered values of n in the above table reveals that ALL even values of n less than 2/3 of 17 are followed by the 1.5n digit. The values of n are and their digit places are:\n\r\n2,3 (11,12)\r\n4,6 (5,6)\r\n6,9 (6,7)\r\n8,12 (15,16)\r\n10,15 (2,3)\n\r\nSo the five smallest numbers with this property are:\n\r\n1176470588235294\r\n2352941176470588\r\n3529411764705882\r\n4705882352941176\r\n5882352941176470\n\r\nNotice that 2352941176470588 can be rotated TWICE, yielding 1.5 times the number each time since the 4->6->9 n digits are in order.\n<|im_end|>" }, { "id": "#6395", "title": "Nobby, Bobby and Rover Again", "fun": 2.19, "difficulty": 1.9000000000000001, "author": "mad-ade", "desc": "Nobby, Bobby and Rover wish to share a certain amount of money. Nobby is entitled to three fifths of the money, Bobby is entitled to 15% and lastly Rover will get £70.\r\nHow much money was there to begin with?", "hint": "No hint available.", "answer": "£280, Nobby got three fifths (£168), Bobby got 15%(£42) and Rover has the remaining £70.", "category": "Math", "date": "08/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNobby, Bobby and Rover wish to share a certain amount of money. Nobby is entitled to three fifths of the money, Bobby is entitled to 15% and lastly Rover will get £70.\r\nHow much money was there to begin with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n£280, Nobby got three fifths (£168), Bobby got 15%(£42) and Rover has the remaining £70.\n<|im_start|>answer\n£280, Nobby got three fifths (£168), Bobby got 15%(£42) and Rover has the remaining £70.\n<|im_end|>" }, { "id": "#4315", "title": "1 1 2 2 3 3", "fun": 2.19, "difficulty": 2.46, "author": "im_para_noid", "desc": "Insert any of the symbols: +, -, /, or * anywhere between the digits below so that they equal 133\n\r\n1 1 2 2 3 3", "hint": "No hint available.", "answer": "1 * 1 + 2 * 2 * 33", "category": "Math", "date": "05/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nInsert any of the symbols: +, -, /, or * anywhere between the digits below so that they equal 133\n\r\n1 1 2 2 3 3\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 * 1 + 2 * 2 * 33\n<|im_start|>answer\n1 * 1 + 2 * 2 * 33\n<|im_end|>" }, { "id": "#8413", "title": "Mother's Day", "fun": 2.19, "difficulty": 1.37, "author": "something", "desc": "Alex and Ethan go shopping for their mother on Mother's Day. Alex buys something for $12 and Ethan buys something for $28. They want to share the price. How much does Alex have to pay Ethan to get an even price for both of them?", "hint": "No hint available.", "answer": "$8. That would make Ethan's price $20 and Alex's price $20.", "category": "Math", "date": "11/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlex and Ethan go shopping for their mother on Mother's Day. Alex buys something for $12 and Ethan buys something for $28. They want to share the price. How much does Alex have to pay Ethan to get an even price for both of them?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$8. That would make Ethan's price $20 and Alex's price $20.\n<|im_start|>answer\n$8. That would make Ethan's price $20 and Alex's price $20.\n<|im_end|>" }, { "id": "#48571", "title": "Patterns In Four", "fun": 2.19, "difficulty": 1.17, "author": "MysteriousLight", "desc": "Find the pattern and figure out the next number in the 5th sequence.\r\n2,5,1,8\r\n7,1,1,9\r\n4,2,3,9\r\n4,3,1,8\r\n1,2,4,_", "hint": "Another sequence that can fit is:\r\n1,2,3,6", "answer": "The pattern:\r\nThe first 3 numbers add up to the fourth number.\r\nThe next number in the 5th sequence:\r\n7.", "category": "Logic", "date": "03/18/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the pattern and figure out the next number in the 5th sequence.\r\n2,5,1,8\r\n7,1,1,9\r\n4,2,3,9\r\n4,3,1,8\r\n1,2,4,_\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pattern:\r\nThe first 3 numbers add up to the fourth number.\r\nThe next number in the 5th sequence:\r\n7.\n<|im_start|>answer\nThe pattern:\r\nThe first 3 numbers add up to the fourth number.\r\nThe next number in the 5th sequence:\r\n7.\n<|im_end|>" }, { "id": "#2074", "title": "Turning Soldiers", "fun": 2.19, "difficulty": 1.07, "author": "Cascas", "desc": "A group of soldiers were standing in the sun facing due west. Their sergeant shouted at them:\n\r\nRight turn!\r\nAbout turn!\r\nLeft turn!\n\r\nWhat direction are the soldiers now facing?", "hint": "A right turn is 90 degrees, an about turn is 180, and a left turn is also 90 degrees.", "answer": "East.", "category": "Logic", "date": "01/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of soldiers were standing in the sun facing due west. Their sergeant shouted at them:\n\r\nRight turn!\r\nAbout turn!\r\nLeft turn!\n\r\nWhat direction are the soldiers now facing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEast.\n<|im_start|>answer\nEast.\n<|im_end|>" }, { "id": "#46207", "title": "The Cards", "fun": 2.18, "difficulty": 1.32, "author": "162129", "desc": "Pamela, Phillipe, Pilar, and Pablo whose main sports (in no particular order) were skating, skiing, basketball, and tennis, were seated at a square table playing cards.\r\n1.) The boys sat opposite each other.\r\n2.) The skater sat opposite to Pablo.\r\n3.) The basketball player sat to the right of Pablo.\r\n4.) Pilar didn't like tennis or basketball.\r\n5.) Pablo sat at spot #1.\n\r\nWhat was each person's sport, and at which number on the table did each person sit?\r\nTable:\n\r\n1\n\r\n4 2\n\r\n3", "hint": "No hint available.", "answer": "Pamela plays basketball, Phillipe skates, Pilar skis, and Pablo plays tennis.\r\nThey sit at the following spots.\r\n1: Pablo\r\n2: Pilar\r\n3: Phillipe\r\n4: Pamela", "category": "Logic", "date": "01/17/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPamela, Phillipe, Pilar, and Pablo whose main sports (in no particular order) were skating, skiing, basketball, and tennis, were seated at a square table playing cards.\r\n1.) The boys sat opposite each other.\r\n2.) The skater sat opposite to Pablo.\r\n3.) The basketball player sat to the right of Pablo.\r\n4.) Pilar didn't like tennis or basketball.\r\n5.) Pablo sat at spot #1.\n\r\nWhat was each person's sport, and at which number on the table did each person sit?\r\nTable:\n\r\n1\n\r\n4 2\n\r\n3\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPamela plays basketball, Phillipe skates, Pilar skis, and Pablo plays tennis.\r\nThey sit at the following spots.\r\n1: Pablo\r\n2: Pilar\r\n3: Phillipe\r\n4: Pamela\n<|im_start|>answer\nPamela plays basketball, Phillipe skates, Pilar skis, and Pablo plays tennis.\r\nThey sit at the following spots.\r\n1: Pablo\r\n2: Pilar\r\n3: Phillipe\r\n4: Pamela\n<|im_end|>" }, { "id": "#3901", "title": "Infinity+1", "fun": 2.18, "difficulty": 1.46, "author": "Mogmatt16", "desc": "Which is more, infinity or infinity plus one? Why?", "hint": "One is not necessarily one more than the other.", "answer": "They are equal.\r\nDon't believe me?\r\nThink about it like this: You have an infinite group and an infinite plus one group. If each item in a group has another to go with it in the other group, there is an equal amount.\r\nfor this we'll say X is the one.\r\nHere are the groups:\n\r\n[x,1,2,3,4,5,6,7....]\r\n[1,2,3,4,5,6,7,8....]\n\r\nSee how the groups match up evenly? Because both will go on forever, each number will have a match.\r\nBut what if you add in the X at the end? You can't. There's no end to infinity. So there's no place to put it at the end.", "category": "Math", "date": "05/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is more, infinity or infinity plus one? Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are equal.\r\nDon't believe me?\r\nThink about it like this: You have an infinite group and an infinite plus one group. If each item in a group has another to go with it in the other group, there is an equal amount.\r\nfor this we'll say X is the one.\r\nHere are the groups:\n\r\n[x,1,2,3,4,5,6,7....]\r\n[1,2,3,4,5,6,7,8....]\n\r\nSee how the groups match up evenly? Because both will go on forever, each number will have a match.\r\nBut what if you add in the X at the end? You can't. There's no end to infinity. So there's no place to put it at the end.\n<|im_start|>answer\nThey are equal.\r\nDon't believe me?\r\nThink about it like this: You have an infinite group and an infinite plus one group. If each item in a group has another to go with it in the other group, there is an equal amount.\r\nfor this we'll say X is the one.\r\nHere are the groups:\n\r\n[x,1,2,3,4,5,6,7....]\r\n[1,2,3,4,5,6,7,8....]\n\r\nSee how the groups match up evenly? Because both will go on forever, each number will have a match.\r\nBut what if you add in the X at the end? You can't. There's no end to infinity. So there's no place to put it at the end.\n<|im_end|>" }, { "id": "#4643", "title": "llamas", "fun": 2.18, "difficulty": 1.55, "author": "im_para_noid", "desc": "Your friend has a number of llamas in his zoo. The number of llamas plus ten chinchillas is two less than five times the number of llamas. How many llamas does your friend have?", "hint": "No hint available.", "answer": "Three. The relevant equation is L+10=5L-2", "category": "Math", "date": "06/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour friend has a number of llamas in his zoo. The number of llamas plus ten chinchillas is two less than five times the number of llamas. How many llamas does your friend have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree. The relevant equation is L+10=5L-2\n<|im_start|>answer\nThree. The relevant equation is L+10=5L-2\n<|im_end|>" }, { "id": "#42378", "title": "Multiplying Mice", "fun": 2.18, "difficulty": 2.04, "author": "letmeforget7", "desc": "Marco's Uncle Oscar gave him 2 mice, which he named Whiskers and Oscar. But Marco discovered that he made a big mistake. Oscar should have been named Oscarella. She just had 8 babies - 4 males and 4 females!\n\r\n\"Ten mice aren't so many,\" said Marco to his mother. \"And they're cute.\"\n\r\n\"Yes,\" said his mother, \"but these cute baby mice can breed when they are 6 weeks old. The babies are born after 3 weeks of pregnancy.\"\n\r\nIf each female mouse has only 1 litter and all the litters have 8 babies, half males and half females, how many mice will Marco have in 18 weeks?", "hint": "Make a time chart.\n\r\nRemember, the question asks you to assume that each female mouse has only 1 litter.", "answer": "After 18 weeks there will be a total of 170 mice.\n\r\nEach of the 4 young females just born will have 8 babies in 9 weeks, making 32 babies; 16 of the babies will be male and 16 will be female. \r\nThe 16 females in those litters will have 8 * 16 = 128 babies. \r\nIn 18 weeks, Marco will have the 2 original mice (Whiskers and Oscarella) + 8 babies + 32 babies + 128 babies = 170 mice. \r\nThat's a lot of mice!", "category": "Math", "date": "06/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMarco's Uncle Oscar gave him 2 mice, which he named Whiskers and Oscar. But Marco discovered that he made a big mistake. Oscar should have been named Oscarella. She just had 8 babies - 4 males and 4 females!\n\r\n\"Ten mice aren't so many,\" said Marco to his mother. \"And they're cute.\"\n\r\n\"Yes,\" said his mother, \"but these cute baby mice can breed when they are 6 weeks old. The babies are born after 3 weeks of pregnancy.\"\n\r\nIf each female mouse has only 1 litter and all the litters have 8 babies, half males and half females, how many mice will Marco have in 18 weeks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAfter 18 weeks there will be a total of 170 mice.\n\r\nEach of the 4 young females just born will have 8 babies in 9 weeks, making 32 babies; 16 of the babies will be male and 16 will be female. \r\nThe 16 females in those litters will have 8 * 16 = 128 babies. \r\nIn 18 weeks, Marco will have the 2 original mice (Whiskers and Oscarella) + 8 babies + 32 babies + 128 babies = 170 mice. \r\nThat's a lot of mice!\n<|im_start|>answer\nAfter 18 weeks there will be a total of 170 mice.\n\r\nEach of the 4 young females just born will have 8 babies in 9 weeks, making 32 babies; 16 of the babies will be male and 16 will be female. \r\nThe 16 females in those litters will have 8 * 16 = 128 babies. \r\nIn 18 weeks, Marco will have the 2 original mice (Whiskers and Oscarella) + 8 babies + 32 babies + 128 babies = 170 mice. \r\nThat's a lot of mice!\n<|im_end|>" }, { "id": "#21553", "title": "Growing Soccer League", "fun": 2.18, "difficulty": 2.5100000000000002, "author": "tsimkin", "desc": "Participation in the local soccer league is 10 percent greater than it was last year. The number of boys increased by 5 percent, and the number of girls increased by 20 percent. What fraction of the soccer league is now girls?", "hint": "No hint available.", "answer": "4/11.\n\r\nIf b and g are the current number of boys and girls, respectively, we have:\n\r\n(b/1.05) + (g/1.20) = [(b+g)/1.10]\r\nor\r\n(b/g)*(1/1.05 - 1/1.10) = (1/1.10) - (1/1.20)\r\nThen\r\nb/g = 7/4\r\nso that\r\n(b+g)/g = 11/4\r\nand\r\ng/(b+g) = 4/11", "category": "Math", "date": "03/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nParticipation in the local soccer league is 10 percent greater than it was last year. The number of boys increased by 5 percent, and the number of girls increased by 20 percent. What fraction of the soccer league is now girls?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4/11.\n\r\nIf b and g are the current number of boys and girls, respectively, we have:\n\r\n(b/1.05) + (g/1.20) = [(b+g)/1.10]\r\nor\r\n(b/g)*(1/1.05 - 1/1.10) = (1/1.10) - (1/1.20)\r\nThen\r\nb/g = 7/4\r\nso that\r\n(b+g)/g = 11/4\r\nand\r\ng/(b+g) = 4/11\n<|im_start|>answer\n4/11.\n\r\nIf b and g are the current number of boys and girls, respectively, we have:\n\r\n(b/1.05) + (g/1.20) = [(b+g)/1.10]\r\nor\r\n(b/g)*(1/1.05 - 1/1.10) = (1/1.10) - (1/1.20)\r\nThen\r\nb/g = 7/4\r\nso that\r\n(b+g)/g = 11/4\r\nand\r\ng/(b+g) = 4/11\n<|im_end|>" }, { "id": "#2208", "title": "Common Transportation", "fun": 2.18, "difficulty": 2.0, "author": "Cascas", "desc": "A survey was taken of mechanical modes of transportation to get to work. What was the most common method?", "hint": "No hint available.", "answer": "Elevator", "category": "Logic", "date": "01/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA survey was taken of mechanical modes of transportation to get to work. What was the most common method?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nElevator\n<|im_start|>answer\nElevator\n<|im_end|>" }, { "id": "#1074", "title": "Crossing Hands", "fun": 2.18, "difficulty": 1.6400000000000001, "author": "Michelle", "desc": "How many times do the hour and minute hand cross each other in a twelve hour period?", "hint": "No hint available.", "answer": "10 times if you start when the hands are already on top of each other, otherwise it's 11 times.", "category": "Math", "date": "10/09/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many times do the hour and minute hand cross each other in a twelve hour period?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10 times if you start when the hands are already on top of each other, otherwise it's 11 times.\n<|im_start|>answer\n10 times if you start when the hands are already on top of each other, otherwise it's 11 times.\n<|im_end|>" }, { "id": "#1051", "title": "Girl Scout Hike", "fun": 2.18, "difficulty": 1.94, "author": "Michelle", "desc": "Stopping along the trail to rest, Judy saw that one third of her Girl Scouts were behind her and three fifths were ahead. Including Judy, what was the total number of scouts in her group?", "hint": "No hint available.", "answer": "15 total girl scouts.", "category": "Logic", "date": "10/04/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStopping along the trail to rest, Judy saw that one third of her Girl Scouts were behind her and three fifths were ahead. Including Judy, what was the total number of scouts in her group?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15 total girl scouts.\n<|im_start|>answer\n15 total girl scouts.\n<|im_end|>" }, { "id": "#19050", "title": "Neighbourhood Woes !!!", "fun": 2.18, "difficulty": 2.14, "author": "lesternoronha1", "desc": "In Rangeelia, a neighbour situated west of our country, the native people can be divided into three types: Lalpilas, Pilharas and Haralals. Lalpilas always get confused between red and yellow (i.e. they see yellow as red and vice versa) but can see any other color properly. Pilharas always get confused between yellow and green (i.e. they see yellow as green and vice versa) but can see any other color properly. Haralals always get confused between green and red (i.e. they see green as red and vice versa) but can see any other color properly. \n\r\nThree people Amar, Akbar and Anthony, who belong to Rangeelia, made the following statements about Gabbar Singh, the famous dacoit of Rangeelia, when he was last seen by them :-\n\r\nAmar : Gabbar Singh was wearing a green shirt.\r\nAkbar : Gabbar Singh was not wearing a yellow shirt.\r\nAnthony : Gabbar Singh was wearing a red shirt.\n\r\nIf none of Amar, Akbar or Anthony is a Haralal, then what was the color of Gabbar Singh's shirt ?", "hint": "No hint available.", "answer": "Gabbar Singh was wearing a yellow shirt. \n\r\nIt is given that \r\nLalpilas always get confused between red and yellow (i.e. they see yellow as red and vice versa) but can see any other color properly. \r\nPilharas always get confused between yellow and green (i.e. they see yellow as green and vice versa) but can see any other color properly. \r\nHaralals always get confused between green and red (i.e. they see green as red and vice versa) but can see any other color properly. \n\r\nThe statements made by Amar, Akbar and Anthony are\n\r\nAmar : Gabbar Singh was wearing a green shirt.\r\nAkbar : Gabbar Singh was not wearing a yellow shirt.\r\nAnthony : Gabbar Singh was wearing a red shirt.\n\r\nSince none of Amar, Akbar or Anthony is a Haralal, Gabbar Singh could not have worn a red or green shirt. \r\nIf Gabbar had worn a red shirt, then Amar would not have made such a statement (since only Haralals get confused between red and green and it is given that Amar is not a Haralal).\r\nIf Gabbar had worn a green shirt, then Anthony would not have made such a statement (since only Haralals get confused between red and green and it is given that Anthony is not a Haralal).\n\r\nSo the only possibility is that Gabbar Singh wore a yellow shirt. \r\nAmar, who is probably a Pilhara, confused yellow with green. \r\nAkbar, who is probably a Pilhara or a Lalpila, confused yellow with either green or red and hence said that he was not in yellow.\r\nAnthony who is probably a Lalpila confused yellow with red.", "category": "Logic", "date": "10/05/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn Rangeelia, a neighbour situated west of our country, the native people can be divided into three types: Lalpilas, Pilharas and Haralals. Lalpilas always get confused between red and yellow (i.e. they see yellow as red and vice versa) but can see any other color properly. Pilharas always get confused between yellow and green (i.e. they see yellow as green and vice versa) but can see any other color properly. Haralals always get confused between green and red (i.e. they see green as red and vice versa) but can see any other color properly. \n\r\nThree people Amar, Akbar and Anthony, who belong to Rangeelia, made the following statements about Gabbar Singh, the famous dacoit of Rangeelia, when he was last seen by them :-\n\r\nAmar : Gabbar Singh was wearing a green shirt.\r\nAkbar : Gabbar Singh was not wearing a yellow shirt.\r\nAnthony : Gabbar Singh was wearing a red shirt.\n\r\nIf none of Amar, Akbar or Anthony is a Haralal, then what was the color of Gabbar Singh's shirt ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGabbar Singh was wearing a yellow shirt. \n\r\nIt is given that \r\nLalpilas always get confused between red and yellow (i.e. they see yellow as red and vice versa) but can see any other color properly. \r\nPilharas always get confused between yellow and green (i.e. they see yellow as green and vice versa) but can see any other color properly. \r\nHaralals always get confused between green and red (i.e. they see green as red and vice versa) but can see any other color properly. \n\r\nThe statements made by Amar, Akbar and Anthony are\n\r\nAmar : Gabbar Singh was wearing a green shirt.\r\nAkbar : Gabbar Singh was not wearing a yellow shirt.\r\nAnthony : Gabbar Singh was wearing a red shirt.\n\r\nSince none of Amar, Akbar or Anthony is a Haralal, Gabbar Singh could not have worn a red or green shirt. \r\nIf Gabbar had worn a red shirt, then Amar would not have made such a statement (since only Haralals get confused between red and green and it is given that Amar is not a Haralal).\r\nIf Gabbar had worn a green shirt, then Anthony would not have made such a statement (since only Haralals get confused between red and green and it is given that Anthony is not a Haralal).\n\r\nSo the only possibility is that Gabbar Singh wore a yellow shirt. \r\nAmar, who is probably a Pilhara, confused yellow with green. \r\nAkbar, who is probably a Pilhara or a Lalpila, confused yellow with either green or red and hence said that he was not in yellow.\r\nAnthony who is probably a Lalpila confused yellow with red.\n<|im_start|>answer\nGabbar Singh was wearing a yellow shirt. \n\r\nIt is given that \r\nLalpilas always get confused between red and yellow (i.e. they see yellow as red and vice versa) but can see any other color properly. \r\nPilharas always get confused between yellow and green (i.e. they see yellow as green and vice versa) but can see any other color properly. \r\nHaralals always get confused between green and red (i.e. they see green as red and vice versa) but can see any other color properly. \n\r\nThe statements made by Amar, Akbar and Anthony are\n\r\nAmar : Gabbar Singh was wearing a green shirt.\r\nAkbar : Gabbar Singh was not wearing a yellow shirt.\r\nAnthony : Gabbar Singh was wearing a red shirt.\n\r\nSince none of Amar, Akbar or Anthony is a Haralal, Gabbar Singh could not have worn a red or green shirt. \r\nIf Gabbar had worn a red shirt, then Amar would not have made such a statement (since only Haralals get confused between red and green and it is given that Amar is not a Haralal).\r\nIf Gabbar had worn a green shirt, then Anthony would not have made such a statement (since only Haralals get confused between red and green and it is given that Anthony is not a Haralal).\n\r\nSo the only possibility is that Gabbar Singh wore a yellow shirt. \r\nAmar, who is probably a Pilhara, confused yellow with green. \r\nAkbar, who is probably a Pilhara or a Lalpila, confused yellow with either green or red and hence said that he was not in yellow.\r\nAnthony who is probably a Lalpila confused yellow with red.\n<|im_end|>" }, { "id": "#4627", "title": "Zodiac Math", "fun": 2.18, "difficulty": 1.68, "author": "mad-ade", "desc": "Multiply the number of letters in the sign of the lion by the number of letters in the sign of the bull. Subtract the number of letters in the sign of the fish. Divide by the number of letters in the sign of the crab. Multiply by the number of letters in the sign of the twins. What is the answer?", "hint": "No hint available.", "answer": "12.\n\r\n3 (Leo) x 6 (Taurus) = 18\r\n18 - 6 (Pisces) = 12\r\n12 / 6 (Cancer) = 2\r\n2 x 6 (Gemini) = 12", "category": "Math", "date": "06/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMultiply the number of letters in the sign of the lion by the number of letters in the sign of the bull. Subtract the number of letters in the sign of the fish. Divide by the number of letters in the sign of the crab. Multiply by the number of letters in the sign of the twins. What is the answer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12.\n\r\n3 (Leo) x 6 (Taurus) = 18\r\n18 - 6 (Pisces) = 12\r\n12 / 6 (Cancer) = 2\r\n2 x 6 (Gemini) = 12\n<|im_start|>answer\n12.\n\r\n3 (Leo) x 6 (Taurus) = 18\r\n18 - 6 (Pisces) = 12\r\n12 / 6 (Cancer) = 2\r\n2 x 6 (Gemini) = 12\n<|im_end|>" }, { "id": "#38704", "title": "A Five Digit Square", "fun": 2.18, "difficulty": 2.48, "author": "shenqiang", "desc": "There is a five digit square number, each digit is also a nonzero square number, and its digits are in ascending order.\n\r\nWhat is it?", "hint": "No hint available.", "answer": "11449=107^2.", "category": "Math", "date": "10/09/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a five digit square number, each digit is also a nonzero square number, and its digits are in ascending order.\n\r\nWhat is it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11449=107^2.\n<|im_start|>answer\n11449=107^2.\n<|im_end|>" }, { "id": "#8582", "title": "Part by Part", "fun": 2.18, "difficulty": 2.1, "author": "lesternoronha1", "desc": "Can you split 34 into 2 parts such that 4/7 of one part is equal to 2/5 of the other?", "hint": "No hint available.", "answer": "Let X and Y be the two parts.\r\nThen solving the equations \r\nX+Y=34 and\r\n(4/7)X=(2/5)Y,\r\nwe get X=14 and Y=20.", "category": "Math", "date": "11/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you split 34 into 2 parts such that 4/7 of one part is equal to 2/5 of the other?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet X and Y be the two parts.\r\nThen solving the equations \r\nX+Y=34 and\r\n(4/7)X=(2/5)Y,\r\nwe get X=14 and Y=20.\n<|im_start|>answer\nLet X and Y be the two parts.\r\nThen solving the equations \r\nX+Y=34 and\r\n(4/7)X=(2/5)Y,\r\nwe get X=14 and Y=20.\n<|im_end|>" }, { "id": "#37613", "title": "Stacking CD's", "fun": 2.18, "difficulty": 1.44, "author": "The-stranger0", "desc": "Andrew has a new 3 foot wide bookcase with two shelves, each 15 inches high. He plans to store his CD's on the shelves using new CD racks. Each CD rack is 17 inches wide and 7 inches high, and holds 3 stacks of 12 CD's. \n\r\nWill Andrew have enough room for his 250 CD's in the bookcase if he uses the two shelves inside the bookcase and doesn't put any CD's on top of it? How many CD's will he be able to store?", "hint": "Drawing a diagram may be helpful.", "answer": "Yes, Andrew will have enough room on the two shelves to fit his 250 CD's. In fact, he will be able to fit up to 288 CD's.\n\r\nEach CD rack holds 36 CD's. (12 x 3 = 36) \r\nEach shelf is 3 feet or 36 inches wide, and therefore wide enough to hold 2 CD racks. (2 x 17 = 34) \r\nEach shelf is 15 inches high, and therefore high enough to hold 2 layers of CD racks. (2 x 7 = 14) \r\nTherefore, each shelf holds 4 CD racks, or 36 x 4 = 144 CD's. \r\nThere are two shelves, each holding 144 CD's, or 288 CD's in all.", "category": "Math", "date": "08/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAndrew has a new 3 foot wide bookcase with two shelves, each 15 inches high. He plans to store his CD's on the shelves using new CD racks. Each CD rack is 17 inches wide and 7 inches high, and holds 3 stacks of 12 CD's. \n\r\nWill Andrew have enough room for his 250 CD's in the bookcase if he uses the two shelves inside the bookcase and doesn't put any CD's on top of it? How many CD's will he be able to store?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes, Andrew will have enough room on the two shelves to fit his 250 CD's. In fact, he will be able to fit up to 288 CD's.\n\r\nEach CD rack holds 36 CD's. (12 x 3 = 36) \r\nEach shelf is 3 feet or 36 inches wide, and therefore wide enough to hold 2 CD racks. (2 x 17 = 34) \r\nEach shelf is 15 inches high, and therefore high enough to hold 2 layers of CD racks. (2 x 7 = 14) \r\nTherefore, each shelf holds 4 CD racks, or 36 x 4 = 144 CD's. \r\nThere are two shelves, each holding 144 CD's, or 288 CD's in all.\n<|im_start|>answer\nYes, Andrew will have enough room on the two shelves to fit his 250 CD's. In fact, he will be able to fit up to 288 CD's.\n\r\nEach CD rack holds 36 CD's. (12 x 3 = 36) \r\nEach shelf is 3 feet or 36 inches wide, and therefore wide enough to hold 2 CD racks. (2 x 17 = 34) \r\nEach shelf is 15 inches high, and therefore high enough to hold 2 layers of CD racks. (2 x 7 = 14) \r\nTherefore, each shelf holds 4 CD racks, or 36 x 4 = 144 CD's. \r\nThere are two shelves, each holding 144 CD's, or 288 CD's in all.\n<|im_end|>" }, { "id": "#32111", "title": "What Number Reaches 0?", "fun": 2.18, "difficulty": 1.9000000000000001, "author": "npf2005", "desc": "Counting down, first by one place, then by two places, then by three and so on (adding one extra place each time), like this example - 15, 14, 12, 9, 5, 0. If each of these numbers were the start of a separate sequence, which would have 0 in it?\n\r\n102, 103, 104, 105 or 106?", "hint": "No hint available.", "answer": "105", "category": "Math", "date": "07/28/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCounting down, first by one place, then by two places, then by three and so on (adding one extra place each time), like this example - 15, 14, 12, 9, 5, 0. If each of these numbers were the start of a separate sequence, which would have 0 in it?\n\r\n102, 103, 104, 105 or 106?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n105\n<|im_start|>answer\n105\n<|im_end|>" }, { "id": "#4043", "title": "Two Ages", "fun": 2.18, "difficulty": 1.65, "author": "mad-ade", "desc": "Three years ago Mad Ade was 3 years more than 3 times older than his son (Mad Ade junior). Now Mad Ade is 10 years more than twice his son's age.\n\r\nHow old is Mad Ade?", "hint": "No hint available.", "answer": "36, his son is 13, by the way.", "category": "Math", "date": "05/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree years ago Mad Ade was 3 years more than 3 times older than his son (Mad Ade junior). Now Mad Ade is 10 years more than twice his son's age.\n\r\nHow old is Mad Ade?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n36, his son is 13, by the way.\n<|im_start|>answer\n36, his son is 13, by the way.\n<|im_end|>" }, { "id": "#4505", "title": "Basketball", "fun": 2.18, "difficulty": 1.9000000000000001, "author": "angie", "desc": "Kevin and Angie are playing basketball at night. They both can play well, except for one thing. Whenever Angie misses, Kevin gets the ball in. But when Angie gets the ball in, Kevin misses. Kevin's dad says that he has to come in because tomorrow Kevin has school. (Just to let you know, Kevin and Angie are neighbors) Angie's on vacation so she doesn't have to go in. But she'll go in when Kevin goes in because she messes up a lot when she's alone at night. Kevin says that when he gets the ball in the hoop, he'll go in. But Angie keeps on getting the ball in. Kevin's dad is getting mad when Kevin has an idea. What's his idea to get the ball in?", "hint": "When does Angie mess up at night?", "answer": "Right when Angie's about to try to get the ball in, Kevin pretends to leave causing her to miss. Then Kevin gets the ball in. (Angie's a little mad, but she gets over it)", "category": "Logic", "date": "06/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKevin and Angie are playing basketball at night. They both can play well, except for one thing. Whenever Angie misses, Kevin gets the ball in. But when Angie gets the ball in, Kevin misses. Kevin's dad says that he has to come in because tomorrow Kevin has school. (Just to let you know, Kevin and Angie are neighbors) Angie's on vacation so she doesn't have to go in. But she'll go in when Kevin goes in because she messes up a lot when she's alone at night. Kevin says that when he gets the ball in the hoop, he'll go in. But Angie keeps on getting the ball in. Kevin's dad is getting mad when Kevin has an idea. What's his idea to get the ball in?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRight when Angie's about to try to get the ball in, Kevin pretends to leave causing her to miss. Then Kevin gets the ball in. (Angie's a little mad, but she gets over it)\n<|im_start|>answer\nRight when Angie's about to try to get the ball in, Kevin pretends to leave causing her to miss. Then Kevin gets the ball in. (Angie's a little mad, but she gets over it)\n<|im_end|>" }, { "id": "#23539", "title": "Find the Area", "fun": 2.18, "difficulty": 1.43, "author": "Tammy93", "desc": "Five congruent squares are put together without gaps or overlap to form a figure shaped like a plus sign. The perimeter of the figure is 72 cm. Find the area of the figure, in sq cm.", "hint": "Find the length of one side of the figure.", "answer": "Answer: 180 square centimeters\n\r\nExplanation: Because the five squares are congruent, the 12 sides of the figure are all equal in length. Then the length of one side is 72/12 = 6 cm. Therefore, the area of each square is 36 sq cm and the area of the figure, 5 x 36, is 180 sq cm.", "category": "Math", "date": "06/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive congruent squares are put together without gaps or overlap to form a figure shaped like a plus sign. The perimeter of the figure is 72 cm. Find the area of the figure, in sq cm.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: 180 square centimeters\n\r\nExplanation: Because the five squares are congruent, the 12 sides of the figure are all equal in length. Then the length of one side is 72/12 = 6 cm. Therefore, the area of each square is 36 sq cm and the area of the figure, 5 x 36, is 180 sq cm.\n<|im_start|>answer\nAnswer: 180 square centimeters\n\r\nExplanation: Because the five squares are congruent, the 12 sides of the figure are all equal in length. Then the length of one side is 72/12 = 6 cm. Therefore, the area of each square is 36 sq cm and the area of the figure, 5 x 36, is 180 sq cm.\n<|im_end|>" }, { "id": "#39479", "title": "Headbands I", "fun": 2.18, "difficulty": 2.71, "author": "zeepuzzlemaster", "desc": "You are part of a group of 500 people who have been captured by an evil tribe. The tribe leader, who appreciates a person with good logic, decides that he will propose a challenge of many headband problems. \n\r\n The first challenge is that each person will get a random headband of one of two colors, black or white. There are 500 of each (500 black and 500 white). If you look at yours or say a word after you have been given your headband and before you have guessed, the evil people will kill everybody. Also, if you make any movement with your body other than your eyes, you will ALL die.\n\r\n At the count of 10, each person will shout out what color they think their headband is. If you or anyone else is right, you will survive for the next challenge. If not, you will be killed immediately. You are given some time to discuss your strategy; then you are given your headbands.\n\r\n How many survivors can you guarantee, assuming the tribe leader is not lying and that each person will follow your instructions? For example, if you tell everybody to guess, you can guarantee zero survivors because you have a slight chance of getting zero survivors.", "hint": "You can guarantee a lot less than you think...", "answer": "You can guarantee that 1/2 of the people will survive.\n\r\n What to do? Partner everybody up and tell one person to guess the same color as the other person's headband, and the other person to guess the color of the headband that they see.\n\r\n For example if Person #1 guesses the same and Person #2 guesses opposite...\n\r\n Person #1=Black Person #2=Black Person #1 Survives\n\r\n Person #1= White Person #2=White Person #1 Survives\n\r\n Person #1=Black Person #2=White Person #2 Survives\n\r\n Person #1=White Person #2=Black Person #2 Survives\n\r\n Note: You cannot tell person #1 to guess the same color as the second person's hat and then the second person to guess that color, because everybody has to guess at the same time.", "category": "Logic", "date": "12/06/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are part of a group of 500 people who have been captured by an evil tribe. The tribe leader, who appreciates a person with good logic, decides that he will propose a challenge of many headband problems. \n\r\n The first challenge is that each person will get a random headband of one of two colors, black or white. There are 500 of each (500 black and 500 white). If you look at yours or say a word after you have been given your headband and before you have guessed, the evil people will kill everybody. Also, if you make any movement with your body other than your eyes, you will ALL die.\n\r\n At the count of 10, each person will shout out what color they think their headband is. If you or anyone else is right, you will survive for the next challenge. If not, you will be killed immediately. You are given some time to discuss your strategy; then you are given your headbands.\n\r\n How many survivors can you guarantee, assuming the tribe leader is not lying and that each person will follow your instructions? For example, if you tell everybody to guess, you can guarantee zero survivors because you have a slight chance of getting zero survivors.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou can guarantee that 1/2 of the people will survive.\n\r\n What to do? Partner everybody up and tell one person to guess the same color as the other person's headband, and the other person to guess the color of the headband that they see.\n\r\n For example if Person #1 guesses the same and Person #2 guesses opposite...\n\r\n Person #1=Black Person #2=Black Person #1 Survives\n\r\n Person #1= White Person #2=White Person #1 Survives\n\r\n Person #1=Black Person #2=White Person #2 Survives\n\r\n Person #1=White Person #2=Black Person #2 Survives\n\r\n Note: You cannot tell person #1 to guess the same color as the second person's hat and then the second person to guess that color, because everybody has to guess at the same time.\n<|im_start|>answer\nYou can guarantee that 1/2 of the people will survive.\n\r\n What to do? Partner everybody up and tell one person to guess the same color as the other person's headband, and the other person to guess the color of the headband that they see.\n\r\n For example if Person #1 guesses the same and Person #2 guesses opposite...\n\r\n Person #1=Black Person #2=Black Person #1 Survives\n\r\n Person #1= White Person #2=White Person #1 Survives\n\r\n Person #1=Black Person #2=White Person #2 Survives\n\r\n Person #1=White Person #2=Black Person #2 Survives\n\r\n Note: You cannot tell person #1 to guess the same color as the second person's hat and then the second person to guess that color, because everybody has to guess at the same time.\n<|im_end|>" }, { "id": "#14994", "title": "Mad Ade's Five Tyres", "fun": 2.18, "difficulty": 2.22, "author": "mad-ade", "desc": "Mad Ade bought a brand new car, a Madadian Kebabolet, with one extra spare tyre. Each tyre can sustain for a maximum of 1200 kms. \n\r\nIf all the tyres were used equally, how far can the car travel?", "hint": "No hint available.", "answer": "1500kms \n\r\nYou would have to rotate the tires every 300kms \n\r\nLet me demonstrate (distance is that remaining on each tyre in 100 kms) \n\r\n12--12 \n\r\n12--12 \n\r\n12 \n\r\nrotate tyres after 3 \n\r\n9--9 \n\r\n9--12 \n\r\n9 \n\r\nrotate tyres after 3 (6 cumulative) \n\r\n6--9 \n\r\n6--9 \n\r\n6 \n\r\nrotate tyres after 3 (9 cumulative) \n\r\n6--6 \n\r\n3--6 \n\r\n3 \n\r\nrotate tyres after 3 (12 cumulative) \n\r\n3--3 \n\r\n3--3 \n\r\n0 \n\r\ndrive the final 3 to the tyre shop (15 cumulative)", "category": "Math", "date": "10/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade bought a brand new car, a Madadian Kebabolet, with one extra spare tyre. Each tyre can sustain for a maximum of 1200 kms. \n\r\nIf all the tyres were used equally, how far can the car travel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1500kms \n\r\nYou would have to rotate the tires every 300kms \n\r\nLet me demonstrate (distance is that remaining on each tyre in 100 kms) \n\r\n12--12 \n\r\n12--12 \n\r\n12 \n\r\nrotate tyres after 3 \n\r\n9--9 \n\r\n9--12 \n\r\n9 \n\r\nrotate tyres after 3 (6 cumulative) \n\r\n6--9 \n\r\n6--9 \n\r\n6 \n\r\nrotate tyres after 3 (9 cumulative) \n\r\n6--6 \n\r\n3--6 \n\r\n3 \n\r\nrotate tyres after 3 (12 cumulative) \n\r\n3--3 \n\r\n3--3 \n\r\n0 \n\r\ndrive the final 3 to the tyre shop (15 cumulative)\n<|im_start|>answer\n1500kms \n\r\nYou would have to rotate the tires every 300kms \n\r\nLet me demonstrate (distance is that remaining on each tyre in 100 kms) \n\r\n12--12 \n\r\n12--12 \n\r\n12 \n\r\nrotate tyres after 3 \n\r\n9--9 \n\r\n9--12 \n\r\n9 \n\r\nrotate tyres after 3 (6 cumulative) \n\r\n6--9 \n\r\n6--9 \n\r\n6 \n\r\nrotate tyres after 3 (9 cumulative) \n\r\n6--6 \n\r\n3--6 \n\r\n3 \n\r\nrotate tyres after 3 (12 cumulative) \n\r\n3--3 \n\r\n3--3 \n\r\n0 \n\r\ndrive the final 3 to the tyre shop (15 cumulative)\n<|im_end|>" }, { "id": "#11052", "title": "Madadian Grand National", "fun": 2.18, "difficulty": 1.76, "author": "mad-ade", "desc": "Five horses ran, or rather limped and wheezed, in the Madadian Grand National race. \n\r\nThere were no ties. \n\r\nMilkmans Delight did not come first. \n\r\nDogmeat Reject was neither first nor last. \n\r\nThree Legged Dobbin came in one place after Milkmans Delight. \n\r\nGlue Pot Boy was not second. \n\r\nPotential Kebab was two places below Glue Pot Boy. \n\r\nIn what order did the horses finish?", "hint": "No hint available.", "answer": "Let's find the possible places horses can finish. Possibilities are: \r\nMilkmans Delight - 2,3,4 (not 5th as Three Legged Dobbin came one place after him) \r\nDogmeat Reject - 2,3,4 \r\nThree Legged Dobbin - 3,4,5 \r\nGlue Pot Boy - 1,3 (not 4th & 5th as Potential Kebab is two place after him) \r\nPotential Kebab - 3,5 \n\r\nSo the result is: \r\n1 Glue Pot Boy \r\n2 Dogmeat Reject \r\n3 Potential Kebab \r\n4 Milkmans Delight \r\n5 Three Legged Dobbin", "category": "Logic", "date": "03/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive horses ran, or rather limped and wheezed, in the Madadian Grand National race. \n\r\nThere were no ties. \n\r\nMilkmans Delight did not come first. \n\r\nDogmeat Reject was neither first nor last. \n\r\nThree Legged Dobbin came in one place after Milkmans Delight. \n\r\nGlue Pot Boy was not second. \n\r\nPotential Kebab was two places below Glue Pot Boy. \n\r\nIn what order did the horses finish?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet's find the possible places horses can finish. Possibilities are: \r\nMilkmans Delight - 2,3,4 (not 5th as Three Legged Dobbin came one place after him) \r\nDogmeat Reject - 2,3,4 \r\nThree Legged Dobbin - 3,4,5 \r\nGlue Pot Boy - 1,3 (not 4th & 5th as Potential Kebab is two place after him) \r\nPotential Kebab - 3,5 \n\r\nSo the result is: \r\n1 Glue Pot Boy \r\n2 Dogmeat Reject \r\n3 Potential Kebab \r\n4 Milkmans Delight \r\n5 Three Legged Dobbin\n<|im_start|>answer\nLet's find the possible places horses can finish. Possibilities are: \r\nMilkmans Delight - 2,3,4 (not 5th as Three Legged Dobbin came one place after him) \r\nDogmeat Reject - 2,3,4 \r\nThree Legged Dobbin - 3,4,5 \r\nGlue Pot Boy - 1,3 (not 4th & 5th as Potential Kebab is two place after him) \r\nPotential Kebab - 3,5 \n\r\nSo the result is: \r\n1 Glue Pot Boy \r\n2 Dogmeat Reject \r\n3 Potential Kebab \r\n4 Milkmans Delight \r\n5 Three Legged Dobbin\n<|im_end|>" }, { "id": "#14169", "title": "The Matching Hands of Time", "fun": 2.18, "difficulty": 2.36, "author": "brainiac2003", "desc": "During a normal 12 hour cycle (midnight to noon, or vice versa), how many times will the hour and minute hands line up exactly, and at what times, to the nearest second, will this happen? (Count midnight and noon as once only, as on a clock, they are the same time.)", "hint": "In one hour, the minute hand travels around a full circle of three hundred and sixty degrees, while the hour hand travels only thirty degrees in the same time.\n\r\nAlso keep in mind that the minute (or hour) hand will be in the same relative position after a 360 degree rotation.", "answer": "There are 11 times during a 12 hour cycle when this happens.\n\r\nHere is the explanation of what times this happens:\n\r\nIf we let T represent the number of hours that elapse, then we can say that the minute hand moves 360 degrees per hour and the hour hand moves 30 degrees per hour. Let M be the relative position of the minute hand, and H the relative position of the hour hand, measured in degrees (relative to the 12 o'clock position).\n\r\nAs equations, we will have\n\r\nH = 30*T, M = 360*T\n\r\nNow, we can measure the angle between the two hands as M - H.\n\r\nM - H = 330*T.\n\r\nThe hands will line up when there is no angular difference between the two. That is, either the angle is zero, or some exact multiple of 360 degrees.\n\r\nSo, 330*T = 360*K, where K is some whole integer value.\n\r\nHence, T = (12/11)*K, where T represents hours after 12:00.\n\r\nHere, K can be any integer value from 0 to 10. If K = 0, then the time is 12:00 (the starting time). For K = 11, T = 12, which again is 12:00. The other values in between will give exact values of T in hours, which can be converted to hours, minutes and seconds. The exact times when the hands line up are:\n\r\n12:00:00, 1:05:27, 2:10:55, 3:16:22, 4:21:49. 5:27:16, 6:32:44, 7:38:11, 8:43:38, 9:49:05, and 10:54:33. The next time after this will again be 12:00:00.", "category": "Math", "date": "08/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring a normal 12 hour cycle (midnight to noon, or vice versa), how many times will the hour and minute hands line up exactly, and at what times, to the nearest second, will this happen? (Count midnight and noon as once only, as on a clock, they are the same time.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 11 times during a 12 hour cycle when this happens.\n\r\nHere is the explanation of what times this happens:\n\r\nIf we let T represent the number of hours that elapse, then we can say that the minute hand moves 360 degrees per hour and the hour hand moves 30 degrees per hour. Let M be the relative position of the minute hand, and H the relative position of the hour hand, measured in degrees (relative to the 12 o'clock position).\n\r\nAs equations, we will have\n\r\nH = 30*T, M = 360*T\n\r\nNow, we can measure the angle between the two hands as M - H.\n\r\nM - H = 330*T.\n\r\nThe hands will line up when there is no angular difference between the two. That is, either the angle is zero, or some exact multiple of 360 degrees.\n\r\nSo, 330*T = 360*K, where K is some whole integer value.\n\r\nHence, T = (12/11)*K, where T represents hours after 12:00.\n\r\nHere, K can be any integer value from 0 to 10. If K = 0, then the time is 12:00 (the starting time). For K = 11, T = 12, which again is 12:00. The other values in between will give exact values of T in hours, which can be converted to hours, minutes and seconds. The exact times when the hands line up are:\n\r\n12:00:00, 1:05:27, 2:10:55, 3:16:22, 4:21:49. 5:27:16, 6:32:44, 7:38:11, 8:43:38, 9:49:05, and 10:54:33. The next time after this will again be 12:00:00.\n<|im_start|>answer\nThere are 11 times during a 12 hour cycle when this happens.\n\r\nHere is the explanation of what times this happens:\n\r\nIf we let T represent the number of hours that elapse, then we can say that the minute hand moves 360 degrees per hour and the hour hand moves 30 degrees per hour. Let M be the relative position of the minute hand, and H the relative position of the hour hand, measured in degrees (relative to the 12 o'clock position).\n\r\nAs equations, we will have\n\r\nH = 30*T, M = 360*T\n\r\nNow, we can measure the angle between the two hands as M - H.\n\r\nM - H = 330*T.\n\r\nThe hands will line up when there is no angular difference between the two. That is, either the angle is zero, or some exact multiple of 360 degrees.\n\r\nSo, 330*T = 360*K, where K is some whole integer value.\n\r\nHence, T = (12/11)*K, where T represents hours after 12:00.\n\r\nHere, K can be any integer value from 0 to 10. If K = 0, then the time is 12:00 (the starting time). For K = 11, T = 12, which again is 12:00. The other values in between will give exact values of T in hours, which can be converted to hours, minutes and seconds. The exact times when the hands line up are:\n\r\n12:00:00, 1:05:27, 2:10:55, 3:16:22, 4:21:49. 5:27:16, 6:32:44, 7:38:11, 8:43:38, 9:49:05, and 10:54:33. The next time after this will again be 12:00:00.\n<|im_end|>" }, { "id": "#3422", "title": "Opposite Day", "fun": 2.18, "difficulty": 1.6, "author": "Mogmatt16", "desc": "Why can you never say \"It is opposite day today!\" and be telling the truth?", "hint": "No hint available.", "answer": "If it was opposite day and you said that, you would mean it isn't opposite day. If it wasn't opposite day, then you'd be telling the truth. Then it would be opposite day and you'd be saying it wasn't opposite day. And so on and so forth.", "category": "Logic", "date": "04/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhy can you never say \"It is opposite day today!\" and be telling the truth?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf it was opposite day and you said that, you would mean it isn't opposite day. If it wasn't opposite day, then you'd be telling the truth. Then it would be opposite day and you'd be saying it wasn't opposite day. And so on and so forth.\n<|im_start|>answer\nIf it was opposite day and you said that, you would mean it isn't opposite day. If it wasn't opposite day, then you'd be telling the truth. Then it would be opposite day and you'd be saying it wasn't opposite day. And so on and so forth.\n<|im_end|>" }, { "id": "#39936", "title": "Parallel Sides", "fun": 2.18, "difficulty": 2.53, "author": "shenqiang", "desc": "A square with sides of length 1 is divided into two congruent trapezoids and a pentagon, which have equal areas, by joining the center of the square with points on three of the sides. What is the length of the longer parallel side of each trapezoid?", "hint": "No hint available.", "answer": "The area of a trapezoid is 1/3, with height 1/2 and shorter parallel side 1/2.\n\r\nSince the area equals 1/2*height*(sum of parallel sides), the length of the longer parallel side will equal 5/6.", "category": "Math", "date": "01/06/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA square with sides of length 1 is divided into two congruent trapezoids and a pentagon, which have equal areas, by joining the center of the square with points on three of the sides. What is the length of the longer parallel side of each trapezoid?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe area of a trapezoid is 1/3, with height 1/2 and shorter parallel side 1/2.\n\r\nSince the area equals 1/2*height*(sum of parallel sides), the length of the longer parallel side will equal 5/6.\n<|im_start|>answer\nThe area of a trapezoid is 1/3, with height 1/2 and shorter parallel side 1/2.\n\r\nSince the area equals 1/2*height*(sum of parallel sides), the length of the longer parallel side will equal 5/6.\n<|im_end|>" }, { "id": "#4892", "title": "Elvis's Pants", "fun": 2.18, "difficulty": 1.56, "author": "mad-ade", "desc": "Mad Ade decides to buy a nice pair of antique underpants from \"Honest Ron's Second Hand Underpants Emporium\". He pays £60 for a pair that allegedly belonged to Elvis Presley's uncle's best friend's former cellmate's little brother, and he is very content with the garment. After a year, the value of the pants has increased to £70 and he decides to sell the semi famous underwear. But already a few days later he regrets his decision to sell the beautiful undergarments, and he buys it again. Unfortunately he has to pay £80 to get it back, so he loses £10. After another year of owning the Elvis related pants, he finally decides to sell them for £90. \n\r\nThe Question: What is the overall profit that Mad Ade makes?", "hint": "No hint available.", "answer": "In the first trade, Mad Ade buys something for £60 and sells it again for £70, so he makes a profit of £10. In the second trade, Mad Ade buys something for £80 and sells it again for £90, so he makes again a profit of £10. \n\r\nConclusion: Mad Ade makes an overall profit of £10 + £10 = £20.", "category": "Math", "date": "06/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade decides to buy a nice pair of antique underpants from \"Honest Ron's Second Hand Underpants Emporium\". He pays £60 for a pair that allegedly belonged to Elvis Presley's uncle's best friend's former cellmate's little brother, and he is very content with the garment. After a year, the value of the pants has increased to £70 and he decides to sell the semi famous underwear. But already a few days later he regrets his decision to sell the beautiful undergarments, and he buys it again. Unfortunately he has to pay £80 to get it back, so he loses £10. After another year of owning the Elvis related pants, he finally decides to sell them for £90. \n\r\nThe Question: What is the overall profit that Mad Ade makes?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn the first trade, Mad Ade buys something for £60 and sells it again for £70, so he makes a profit of £10. In the second trade, Mad Ade buys something for £80 and sells it again for £90, so he makes again a profit of £10. \n\r\nConclusion: Mad Ade makes an overall profit of £10 + £10 = £20.\n<|im_start|>answer\nIn the first trade, Mad Ade buys something for £60 and sells it again for £70, so he makes a profit of £10. In the second trade, Mad Ade buys something for £80 and sells it again for £90, so he makes again a profit of £10. \n\r\nConclusion: Mad Ade makes an overall profit of £10 + £10 = £20.\n<|im_end|>" }, { "id": "#5353", "title": "Turn Turn Turn", "fun": 2.18, "difficulty": 1.98, "author": "mad-ade", "desc": "There is a chain of five gear-wheels, identified as A to E, each one meshing properly with its immediate neighbour(s) in a straight line. The number next to each letter shows how many teeth that particular gear-wheel has.\n\r\nA=48\r\nB=16\r\nC=64\r\nD=24\r\nE=32\n\r\nWhen A is turned clockwise ten full turns, in which direction does E turn, and how many times?", "hint": "No hint available.", "answer": "Clockwise. 15 full turns.", "category": "Math", "date": "07/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a chain of five gear-wheels, identified as A to E, each one meshing properly with its immediate neighbour(s) in a straight line. The number next to each letter shows how many teeth that particular gear-wheel has.\n\r\nA=48\r\nB=16\r\nC=64\r\nD=24\r\nE=32\n\r\nWhen A is turned clockwise ten full turns, in which direction does E turn, and how many times?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nClockwise. 15 full turns.\n<|im_start|>answer\nClockwise. 15 full turns.\n<|im_end|>" }, { "id": "#24200", "title": "Huh?", "fun": 2.18, "difficulty": 2.67, "author": "superben", "desc": "What is the relationship between these 5 sets of numbers? 1, 1 ; 10, 4 ; 30, 12 ; 100, 16 ; 1000, 64.", "hint": "Bases", "answer": "The first number is base 4, the second base 10.( Base 4 has places 1, 4, 16, 64 and so on)", "category": "Math", "date": "07/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the relationship between these 5 sets of numbers? 1, 1 ; 10, 4 ; 30, 12 ; 100, 16 ; 1000, 64.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first number is base 4, the second base 10.( Base 4 has places 1, 4, 16, 64 and so on)\n<|im_start|>answer\nThe first number is base 4, the second base 10.( Base 4 has places 1, 4, 16, 64 and so on)\n<|im_end|>" }, { "id": "#7238", "title": "Foot Facts", "fun": 2.18, "difficulty": 1.71, "author": "NuttyPrince", "desc": "A psychologist visits Africa with his family on a vacation. One day, although this trip was to get away from work and reduce stress in the office, he decides to conduct an experiment, trying to link foot size to intelligence. As he was nearing the end of his experiment he was startled to find that the people with bigger feet had a larger intelligence! But soon after he found out the reason and went home disappointed at the thought that he found an actual link.\r\nWhat did the psychologist find out?", "hint": "No hint available.", "answer": "He was taking the foot size of everyone, including children. The reason that he thought he found the link is because the people with the smaller feet were the children, but the people with the larger feet were the adults who had received a better education.", "category": "Logic", "date": "09/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA psychologist visits Africa with his family on a vacation. One day, although this trip was to get away from work and reduce stress in the office, he decides to conduct an experiment, trying to link foot size to intelligence. As he was nearing the end of his experiment he was startled to find that the people with bigger feet had a larger intelligence! But soon after he found out the reason and went home disappointed at the thought that he found an actual link.\r\nWhat did the psychologist find out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe was taking the foot size of everyone, including children. The reason that he thought he found the link is because the people with the smaller feet were the children, but the people with the larger feet were the adults who had received a better education.\n<|im_start|>answer\nHe was taking the foot size of everyone, including children. The reason that he thought he found the link is because the people with the smaller feet were the children, but the people with the larger feet were the adults who had received a better education.\n<|im_end|>" }, { "id": "#44012", "title": "Gardening Troubles", "fun": 2.18, "difficulty": 0.67, "author": "eggface", "desc": "Gardeners Frank, George, and Ben all work on large properties. One of them tends to the Smith's garden, one tends to the Jones's garden, and one tends to the Maple's garden. In one garden, only native plants are grown. In another, exotic plants are everywhere. In the third garden, vegetables are grown for the family's supper. Using the clues below, work out which gardener grows which plants in which garden. Good luck!\n\r\nClues:\r\n1. Frank is the only gardener who grows vegetables.\r\n2. The exotic plants aren't grown in the Smith's garden.\r\n3. George doesn't work at the Jones's.\r\n4. Vegetables are grown at the Jones's.\r\n5. Ben doesn't work at the Smith's.", "hint": "No hint available.", "answer": "Frank grows vegetables in the Jones's garden.\r\nBen grows exotic plants in the Maple's garden.\r\nGeorge grows native plants in the Smith's garden.", "category": "Logic-Grid", "date": "01/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGardeners Frank, George, and Ben all work on large properties. One of them tends to the Smith's garden, one tends to the Jones's garden, and one tends to the Maple's garden. In one garden, only native plants are grown. In another, exotic plants are everywhere. In the third garden, vegetables are grown for the family's supper. Using the clues below, work out which gardener grows which plants in which garden. Good luck!\n\r\nClues:\r\n1. Frank is the only gardener who grows vegetables.\r\n2. The exotic plants aren't grown in the Smith's garden.\r\n3. George doesn't work at the Jones's.\r\n4. Vegetables are grown at the Jones's.\r\n5. Ben doesn't work at the Smith's.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrank grows vegetables in the Jones's garden.\r\nBen grows exotic plants in the Maple's garden.\r\nGeorge grows native plants in the Smith's garden.\n<|im_start|>answer\nFrank grows vegetables in the Jones's garden.\r\nBen grows exotic plants in the Maple's garden.\r\nGeorge grows native plants in the Smith's garden.\n<|im_end|>" }, { "id": "#24517", "title": "Six Friends Don't Like Waiting in Line!", "fun": 2.18, "difficulty": 0.89, "author": "monkies_r2_kool", "desc": "Six friends (Tina, Brittney, Cassandra, Kaitlyn, Janna, and Cara) went to the mall. They were all standing in line waiting for the cashier to come back. How were they standing?\n\r\n1. Cassandra did not like that she was last in the line.\r\n2. Janna was always in front.\r\n3. Tina was in front of Cara but behind Kaitlyn.\r\n4. Brittney was in immediately in front of Cassandra.", "hint": "No hint available.", "answer": "Janna, Kaitlyn, Tina, Cara, Brittney, Cassandra.", "category": "Logic", "date": "07/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix friends (Tina, Brittney, Cassandra, Kaitlyn, Janna, and Cara) went to the mall. They were all standing in line waiting for the cashier to come back. How were they standing?\n\r\n1. Cassandra did not like that she was last in the line.\r\n2. Janna was always in front.\r\n3. Tina was in front of Cara but behind Kaitlyn.\r\n4. Brittney was in immediately in front of Cassandra.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJanna, Kaitlyn, Tina, Cara, Brittney, Cassandra.\n<|im_start|>answer\nJanna, Kaitlyn, Tina, Cara, Brittney, Cassandra.\n<|im_end|>" }, { "id": "#6886", "title": "150 in Darts", "fun": 2.18, "difficulty": 2.71, "author": "klopper", "desc": "How many different ways can 150 be scored with a set of 3 darts on a standard dartboard?", "hint": "Concern yourself with number combinations only, not specific doubles or triples ie:D18 & T12 are both 36", "answer": "16 \n\r\n(60 60 30,60 57 33,60 54 36,60 51 39,60 48 42,60 45 45,57 57 36,57 54 39,57 51 42,57 48 45,54 54 42,54 51 45,54 48 48,51 51 48,60 40 50,50 50 50)", "category": "Math", "date": "08/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many different ways can 150 be scored with a set of 3 darts on a standard dartboard?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16 \n\r\n(60 60 30,60 57 33,60 54 36,60 51 39,60 48 42,60 45 45,57 57 36,57 54 39,57 51 42,57 48 45,54 54 42,54 51 45,54 48 48,51 51 48,60 40 50,50 50 50)\n<|im_start|>answer\n16 \n\r\n(60 60 30,60 57 33,60 54 36,60 51 39,60 48 42,60 45 45,57 57 36,57 54 39,57 51 42,57 48 45,54 54 42,54 51 45,54 48 48,51 51 48,60 40 50,50 50 50)\n<|im_end|>" }, { "id": "#8583", "title": "Number Unknown", "fun": 2.18, "difficulty": 1.6400000000000001, "author": "lesternoronha1", "desc": "There is a number, the second digit of which is smaller than the first digit by 4 and if the number is divided by the digit's sum, the quotient would be 7. Find the number.", "hint": "No hint available.", "answer": "The number is 84.", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a number, the second digit of which is smaller than the first digit by 4 and if the number is divided by the digit's sum, the quotient would be 7. Find the number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 84.\n<|im_start|>answer\nThe number is 84.\n<|im_end|>" }, { "id": "#17460", "title": "Mother May I", "fun": 2.18, "difficulty": 1.81, "author": "basketbalfreak4", "desc": "Lizzie is babysitting her little sister Mary, and Mary's friends Terri, Sherri, and Kerry. They are playing Mother May I. In this game every player asks, \"Mother may I take (1,2,3, or 4) of (some type of) step forward. The leader, Lizzie, says, \"Yes, you may\" or \"No, you may not.\" \n\r\nIf the leader answers \"no\" the player stays in the same place. If the player forgets to say \"Mother May I,\" she has to go back the number of steps she asked for. There are baby steps, hops, or giant steps. A baby step is 6 inches, a hop is 12 inches, and a giant step is 24 inches. \n\r\nIn the lines below, * indicates those turns in which the leader said \"no\" and ** indicates those turns in which the player forgot to say, \"Mother May I.\" \n\r\nAfter six turns: \n\r\nMary has asked for 3 baby steps, 2* hops, 1 giant step, 1 baby step, 4 hops, and 1** giant step. \n\r\nTerri has asked for 2 baby steps, 1** hop, 1 giant step, 1* baby step, 4 baby steps, and 2 hops. \n\r\nSheri has asked for 3 hops, 1 giant step, 1* baby step, 4* hops, 1 baby step, and 2 hops. \n\r\nKerry has asked for 3** hops, 4 hops, 1 giant step, 1* baby step, 4 hops, and 1 giant step. \n\r\nWho is the closest to the finish line?", "hint": "Make a number line.", "answer": "Kerry is closest to the finish line.\n\r\nSteps converted into feet:\n\r\nMary has gone +1 1/2+0+2+1/2+4-2 = +6 feet;\n\r\nTerri has gone +1-1+2+0+2+2 = +6 feet;\n\r\nSherri has gone +3+2+0+0+1/2+2 = +7 1/2 feet;\n\r\nKerry has gone -3+4+2+0+4+2 = +9 feet.", "category": "Math", "date": "04/23/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLizzie is babysitting her little sister Mary, and Mary's friends Terri, Sherri, and Kerry. They are playing Mother May I. In this game every player asks, \"Mother may I take (1,2,3, or 4) of (some type of) step forward. The leader, Lizzie, says, \"Yes, you may\" or \"No, you may not.\" \n\r\nIf the leader answers \"no\" the player stays in the same place. If the player forgets to say \"Mother May I,\" she has to go back the number of steps she asked for. There are baby steps, hops, or giant steps. A baby step is 6 inches, a hop is 12 inches, and a giant step is 24 inches. \n\r\nIn the lines below, * indicates those turns in which the leader said \"no\" and ** indicates those turns in which the player forgot to say, \"Mother May I.\" \n\r\nAfter six turns: \n\r\nMary has asked for 3 baby steps, 2* hops, 1 giant step, 1 baby step, 4 hops, and 1** giant step. \n\r\nTerri has asked for 2 baby steps, 1** hop, 1 giant step, 1* baby step, 4 baby steps, and 2 hops. \n\r\nSheri has asked for 3 hops, 1 giant step, 1* baby step, 4* hops, 1 baby step, and 2 hops. \n\r\nKerry has asked for 3** hops, 4 hops, 1 giant step, 1* baby step, 4 hops, and 1 giant step. \n\r\nWho is the closest to the finish line?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKerry is closest to the finish line.\n\r\nSteps converted into feet:\n\r\nMary has gone +1 1/2+0+2+1/2+4-2 = +6 feet;\n\r\nTerri has gone +1-1+2+0+2+2 = +6 feet;\n\r\nSherri has gone +3+2+0+0+1/2+2 = +7 1/2 feet;\n\r\nKerry has gone -3+4+2+0+4+2 = +9 feet.\n<|im_start|>answer\nKerry is closest to the finish line.\n\r\nSteps converted into feet:\n\r\nMary has gone +1 1/2+0+2+1/2+4-2 = +6 feet;\n\r\nTerri has gone +1-1+2+0+2+2 = +6 feet;\n\r\nSherri has gone +3+2+0+0+1/2+2 = +7 1/2 feet;\n\r\nKerry has gone -3+4+2+0+4+2 = +9 feet.\n<|im_end|>" }, { "id": "#1331", "title": "Cask & Water", "fun": 2.18, "difficulty": 1.13, "author": "Chronos", "desc": "A cask contains 20 gallons of water.\r\nWhat can you add to it to make it have 12 gallons?", "hint": "No hint available.", "answer": "Holes", "category": "Logic", "date": "11/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA cask contains 20 gallons of water.\r\nWhat can you add to it to make it have 12 gallons?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHoles\n<|im_start|>answer\nHoles\n<|im_end|>" }, { "id": "#17764", "title": "The Magician", "fun": 2.18, "difficulty": 0.9400000000000001, "author": "allsatrash08", "desc": "A 6-foot tall magician had a water glass and was holding the glass above his head. He let it drop to the carpet without spilling a single drop of water. \n\r\nHow could he manage to drop the glass from a height of six feet and not spill a drop of water?", "hint": "No hint available.", "answer": "It was an empty glass.", "category": "Logic", "date": "05/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 6-foot tall magician had a water glass and was holding the glass above his head. He let it drop to the carpet without spilling a single drop of water. \n\r\nHow could he manage to drop the glass from a height of six feet and not spill a drop of water?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt was an empty glass.\n<|im_start|>answer\nIt was an empty glass.\n<|im_end|>" }, { "id": "#16917", "title": "Five Girl Race", "fun": 2.18, "difficulty": 0.99, "author": "Newf", "desc": "Five girls took part in a race. Amanda finished before Julie but behind Kim. Cris finished before Kayla but behind Julie. What was the finishing order?", "hint": "No hint available.", "answer": "Kim\r\nAmanda\r\nJulie\r\nCris\r\nKayla", "category": "Logic", "date": "03/08/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive girls took part in a race. Amanda finished before Julie but behind Kim. Cris finished before Kayla but behind Julie. What was the finishing order?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKim\r\nAmanda\r\nJulie\r\nCris\r\nKayla\n<|im_start|>answer\nKim\r\nAmanda\r\nJulie\r\nCris\r\nKayla\n<|im_end|>" }, { "id": "#16340", "title": "Fan", "fun": 2.18, "difficulty": 1.67, "author": "smartathlt", "desc": "A fan turns 60 right angles in 10 seconds. How many full circles will the fan turn in 1 minute?", "hint": "No hint available.", "answer": "90 circles. There are four right angles in a circle, so 15 full circles (60/4) in 10 seconds. There are six 10-second increments in a minute, so six times 15 is 90.", "category": "Math", "date": "01/27/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fan turns 60 right angles in 10 seconds. How many full circles will the fan turn in 1 minute?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n90 circles. There are four right angles in a circle, so 15 full circles (60/4) in 10 seconds. There are six 10-second increments in a minute, so six times 15 is 90.\n<|im_start|>answer\n90 circles. There are four right angles in a circle, so 15 full circles (60/4) in 10 seconds. There are six 10-second increments in a minute, so six times 15 is 90.\n<|im_end|>" }, { "id": "#50405", "title": "Joe's Age", "fun": 2.18, "difficulty": 0.7000000000000001, "author": "Ghostology", "desc": "Joe's age plus 3 is a square number\n\r\nJoe's age minus 3 is the square root\n\r\nWhat is Joe's age?", "hint": "No hint available.", "answer": "Joe is 6 years old\n\r\n6 + 3 = 9\n\r\n6 - 3 = 3\n\r\n3^2 = 9", "category": "Math", "date": "07/28/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe's age plus 3 is a square number\n\r\nJoe's age minus 3 is the square root\n\r\nWhat is Joe's age?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoe is 6 years old\n\r\n6 + 3 = 9\n\r\n6 - 3 = 3\n\r\n3^2 = 9\n<|im_start|>answer\nJoe is 6 years old\n\r\n6 + 3 = 9\n\r\n6 - 3 = 3\n\r\n3^2 = 9\n<|im_end|>" }, { "id": "#2942", "title": "Space Race", "fun": 2.18, "difficulty": 2.36, "author": "captbob61", "desc": "If planet A is circling the sun at 5000 miles per hour, and is 30,000 miles from the sun, how fast does planet B have to go to keep up if it is 50,000 miles from the sun?", "hint": "Circumference of a circle = 2*pi*radius", "answer": "8333 miles per hour.\r\nBecause circumference of a circle is first order, 2*pi*r, the ratio can be set up: 5000/30000= X/50000\r\n5000*50000/30000= 5000*5/3= 25/3*1000= 8.333*1000= 8333. No calculator needed!", "category": "Math", "date": "03/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf planet A is circling the sun at 5000 miles per hour, and is 30,000 miles from the sun, how fast does planet B have to go to keep up if it is 50,000 miles from the sun?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8333 miles per hour.\r\nBecause circumference of a circle is first order, 2*pi*r, the ratio can be set up: 5000/30000= X/50000\r\n5000*50000/30000= 5000*5/3= 25/3*1000= 8.333*1000= 8333. No calculator needed!\n<|im_start|>answer\n8333 miles per hour.\r\nBecause circumference of a circle is first order, 2*pi*r, the ratio can be set up: 5000/30000= X/50000\r\n5000*50000/30000= 5000*5/3= 25/3*1000= 8.333*1000= 8333. No calculator needed!\n<|im_end|>" }, { "id": "#28578", "title": "Threes, Fives and Sevens", "fun": 2.18, "difficulty": 2.96, "author": "shenqiang", "desc": "Which is the smallest natural number that satisfies the following conditions:\n\r\n(1) Its digits consist only of, and only of 3's, 5's and 7's.\r\n(2) Its digital sum is divisible by 3, 5 and 7.\r\n(3) The number itself is divisible by 3, 5 and 7.", "hint": "It's easier than some of you might think.", "answer": "From condition 2, its digital sum is at least 105.\n\r\nFrom condition 3, it must end with 5, but its divisibility by 3 is guaranteed, so we only have to check 7.\n\r\nFrom condition 1 and 2, it has an odd number of digits. 105/7=15, so it has more than 15, and at least 17 digits. We can have:\n\r\n(1) 13 7's, 1 5, and 3 3's;\r\n(2) 12 7's, 3 5's, and 2 3's;\r\n(3) 11 7's, 5 5's, and 1 3.\n\r\nIn the second case, we verify that neither 33557777777777775 nor 33575777777777775 is divisible by 7, but 33577577777777775 is divisible by 7 (the quotient is 4796796825396825.)\n\r\nIn the first case, the only number they make that is less than 33577577777777775 is 33377777777777775, which is not divisible by 7.\n\r\nIn the third case, they can't make a number less than 33577577777777775.\n\r\nTherefore, the number we're looking for is 33577577777777775.", "category": "Math", "date": "02/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is the smallest natural number that satisfies the following conditions:\n\r\n(1) Its digits consist only of, and only of 3's, 5's and 7's.\r\n(2) Its digital sum is divisible by 3, 5 and 7.\r\n(3) The number itself is divisible by 3, 5 and 7.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom condition 2, its digital sum is at least 105.\n\r\nFrom condition 3, it must end with 5, but its divisibility by 3 is guaranteed, so we only have to check 7.\n\r\nFrom condition 1 and 2, it has an odd number of digits. 105/7=15, so it has more than 15, and at least 17 digits. We can have:\n\r\n(1) 13 7's, 1 5, and 3 3's;\r\n(2) 12 7's, 3 5's, and 2 3's;\r\n(3) 11 7's, 5 5's, and 1 3.\n\r\nIn the second case, we verify that neither 33557777777777775 nor 33575777777777775 is divisible by 7, but 33577577777777775 is divisible by 7 (the quotient is 4796796825396825.)\n\r\nIn the first case, the only number they make that is less than 33577577777777775 is 33377777777777775, which is not divisible by 7.\n\r\nIn the third case, they can't make a number less than 33577577777777775.\n\r\nTherefore, the number we're looking for is 33577577777777775.\n<|im_start|>answer\nFrom condition 2, its digital sum is at least 105.\n\r\nFrom condition 3, it must end with 5, but its divisibility by 3 is guaranteed, so we only have to check 7.\n\r\nFrom condition 1 and 2, it has an odd number of digits. 105/7=15, so it has more than 15, and at least 17 digits. We can have:\n\r\n(1) 13 7's, 1 5, and 3 3's;\r\n(2) 12 7's, 3 5's, and 2 3's;\r\n(3) 11 7's, 5 5's, and 1 3.\n\r\nIn the second case, we verify that neither 33557777777777775 nor 33575777777777775 is divisible by 7, but 33577577777777775 is divisible by 7 (the quotient is 4796796825396825.)\n\r\nIn the first case, the only number they make that is less than 33577577777777775 is 33377777777777775, which is not divisible by 7.\n\r\nIn the third case, they can't make a number less than 33577577777777775.\n\r\nTherefore, the number we're looking for is 33577577777777775.\n<|im_end|>" }, { "id": "#51247", "title": "A Line For the Sign", "fun": 2.18, "difficulty": 1.73, "author": "kzmonopoly", "desc": "The sign DENTAL SUPPORT can be changed into a sign promoting another type of doctor by adding a line to one of the letters in the sign. How do you accomplish this?", "hint": "What two letters differ by a line?", "answer": "Add a line to the bottom of the T to make DENIAL SUPPORT, a sign promoting a therapist instead of a dentist.", "category": "Logic", "date": "06/24/17", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe sign DENTAL SUPPORT can be changed into a sign promoting another type of doctor by adding a line to one of the letters in the sign. How do you accomplish this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdd a line to the bottom of the T to make DENIAL SUPPORT, a sign promoting a therapist instead of a dentist.\n<|im_start|>answer\nAdd a line to the bottom of the T to make DENIAL SUPPORT, a sign promoting a therapist instead of a dentist.\n<|im_end|>" }, { "id": "#52401", "title": "I Know He Knows; You Don't Know I Don't", "fun": 2.18, "difficulty": 1.9000000000000001, "author": "Rove_Tarts", "desc": "-I walk into a room\r\n-I know everyone who knows who was first in the room\r\n-You walk in after me\r\n-You don't know everyone who knows who was first in the room\n\r\nHow many people are now in the room?", "hint": "Try to figure out how many were to start then add 2.", "answer": "There are 4 in the room \n\r\nAt least 2 people enter the room; me and you. \n\r\nIf 1 person were in the room to start, I would know who was first in the room, as well as everyone who who knows who was first in the room.\n\r\nTherefore, if you walk in with 1 other person & I, you know we both know who was first.\n\r\nIf there were 0, same story.\n\r\nIf there are 3 or more, I don't know who knows who was first in the room, because only 2 of them know.\n\r\nTherefore, the answer is 4.", "category": "Logic", "date": "06/08/20", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n-I walk into a room\r\n-I know everyone who knows who was first in the room\r\n-You walk in after me\r\n-You don't know everyone who knows who was first in the room\n\r\nHow many people are now in the room?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 4 in the room \n\r\nAt least 2 people enter the room; me and you. \n\r\nIf 1 person were in the room to start, I would know who was first in the room, as well as everyone who who knows who was first in the room.\n\r\nTherefore, if you walk in with 1 other person & I, you know we both know who was first.\n\r\nIf there were 0, same story.\n\r\nIf there are 3 or more, I don't know who knows who was first in the room, because only 2 of them know.\n\r\nTherefore, the answer is 4.\n<|im_start|>answer\nThere are 4 in the room \n\r\nAt least 2 people enter the room; me and you. \n\r\nIf 1 person were in the room to start, I would know who was first in the room, as well as everyone who who knows who was first in the room.\n\r\nTherefore, if you walk in with 1 other person & I, you know we both know who was first.\n\r\nIf there were 0, same story.\n\r\nIf there are 3 or more, I don't know who knows who was first in the room, because only 2 of them know.\n\r\nTherefore, the answer is 4.\n<|im_end|>" }, { "id": "#18944", "title": "The Romankachi Clock Problem !!!", "fun": 2.18, "difficulty": 2.87, "author": "lesternoronha1", "desc": "I always remember the days when I was at high school, whiling away my time with my friends. Those were the days when I'd spent the maximum time with my grandfather Rudolf the world-famous Romankachi. He'd come over to our house at one of the weekends leaving behind his Romankachi estate in the village in capable hands. One day when I returned home from school, he put this clock problem in front of me which I was required to solve in the alloted time frame. \n\r\nConsidering time represented in twelve hour format H:M1M2 where H is a single-digit or a two-digit number indicating the hours and M1 and M2 the digits indicating the minutes (M1 representing the tens digit of the minutes and M2 the units digit of the minutes), he wanted me to find out that in a day how such instances would occur so that H is exactly divisible by M1 and gives M2 as quotient? \n\r\nHe further added that if H:M1M2 was the time represented in 24-hour format instead of a 12-hour format, then how many instances were there in a day such that H is exactly divisible by M1 giving M2 as the quotient? In the 24 hour format, 12 o' clock midnight is represented as 00:00.", "hint": "No hint available.", "answer": "Clearing the scope of the problem, we have to divide H by M1 getting M2 as the quotient with remainder as 0. \n\r\nFirst let us consider the time format to be a 12-hour format. \r\nHere H can take values from 1 to 12.\r\nFor M1 = 0, no value exists since divisor itself is 0.\r\nFor M1 = 1, M2 takes values from 1 to 9 i.e., 9 values, for H = 1 to 9.\r\nFor M1 = 2, M2 takes values from 1 to 6 i.e., 6 values, for H = 2, 4, 6, 8, 10 and 12.\r\nFor M1 = 3, M2 takes values from 1 to 4 i.e., 4 values, for H = 3, 6, 9, and 12.\r\nFor M1 = 4, M2 takes values from 1 to 3 i.e., 3 values, for H = 4, 8, and 12.\r\nFor M1 = 5, M2 takes values from 1 to 2 i.e., 2 values, for H = 5 and 10.\r\nAny further values of M1 cannot be considered since M1M2 will then exceed 60 minutes which is not possible.\r\nHence the total = 9+6+4+3+2 = 24\r\nThis is for 12 hours.\r\nIn a day the number of instances where H is exactly divisible by M1 giving M2 as quotient is =\r\n24 * 2 = 48 instances in a 12-hour format.\n\r\nNow let us consider the time format to be a 24-hour format.\r\nHere H can take values from 0 to 23.\r\nFor M1 = 0, no value exists since divisor itself is 0.\r\nFor M1 = 1, M2 takes values from 0 to 9 i.e., 10 values, for H = 0 to 9.\r\nFor M1 = 2, M2 takes values from 0 to 9 i.e., 10 values, for H = 0, 2, 4, 6, 8, 10, 12, 14, 16, and 18.\r\nFor M1 = 3, M2 takes values from 0 to 7 i.e., 8 values, for H = 0, 3, 6, 9, 12, 15, 18 and 21.\r\nFor M1 = 4, M2 takes values from 0 to 5 i.e., 6 values, for H = 0, 4, 8, 12, 16, and 20.\r\nFor M1 = 5, M2 takes values from 0 to 4 i.e., 5 values, for H = 0, 5, 10, 15 and 20.\r\nAny further values of M1 cannot be considered since M1M2 will then exceed 60 minutes which is not possible.\r\nHence the total = 10+10+8+6+5 = 39\r\nThis is for 24 hours.\r\nIn a day the number of instances where H is exactly divisible by M1 giving M2 as quotient is =\r\n39 instances in a 24-hour format.", "category": "Math", "date": "09/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI always remember the days when I was at high school, whiling away my time with my friends. Those were the days when I'd spent the maximum time with my grandfather Rudolf the world-famous Romankachi. He'd come over to our house at one of the weekends leaving behind his Romankachi estate in the village in capable hands. One day when I returned home from school, he put this clock problem in front of me which I was required to solve in the alloted time frame. \n\r\nConsidering time represented in twelve hour format H:M1M2 where H is a single-digit or a two-digit number indicating the hours and M1 and M2 the digits indicating the minutes (M1 representing the tens digit of the minutes and M2 the units digit of the minutes), he wanted me to find out that in a day how such instances would occur so that H is exactly divisible by M1 and gives M2 as quotient? \n\r\nHe further added that if H:M1M2 was the time represented in 24-hour format instead of a 12-hour format, then how many instances were there in a day such that H is exactly divisible by M1 giving M2 as the quotient? In the 24 hour format, 12 o' clock midnight is represented as 00:00.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nClearing the scope of the problem, we have to divide H by M1 getting M2 as the quotient with remainder as 0. \n\r\nFirst let us consider the time format to be a 12-hour format. \r\nHere H can take values from 1 to 12.\r\nFor M1 = 0, no value exists since divisor itself is 0.\r\nFor M1 = 1, M2 takes values from 1 to 9 i.e., 9 values, for H = 1 to 9.\r\nFor M1 = 2, M2 takes values from 1 to 6 i.e., 6 values, for H = 2, 4, 6, 8, 10 and 12.\r\nFor M1 = 3, M2 takes values from 1 to 4 i.e., 4 values, for H = 3, 6, 9, and 12.\r\nFor M1 = 4, M2 takes values from 1 to 3 i.e., 3 values, for H = 4, 8, and 12.\r\nFor M1 = 5, M2 takes values from 1 to 2 i.e., 2 values, for H = 5 and 10.\r\nAny further values of M1 cannot be considered since M1M2 will then exceed 60 minutes which is not possible.\r\nHence the total = 9+6+4+3+2 = 24\r\nThis is for 12 hours.\r\nIn a day the number of instances where H is exactly divisible by M1 giving M2 as quotient is =\r\n24 * 2 = 48 instances in a 12-hour format.\n\r\nNow let us consider the time format to be a 24-hour format.\r\nHere H can take values from 0 to 23.\r\nFor M1 = 0, no value exists since divisor itself is 0.\r\nFor M1 = 1, M2 takes values from 0 to 9 i.e., 10 values, for H = 0 to 9.\r\nFor M1 = 2, M2 takes values from 0 to 9 i.e., 10 values, for H = 0, 2, 4, 6, 8, 10, 12, 14, 16, and 18.\r\nFor M1 = 3, M2 takes values from 0 to 7 i.e., 8 values, for H = 0, 3, 6, 9, 12, 15, 18 and 21.\r\nFor M1 = 4, M2 takes values from 0 to 5 i.e., 6 values, for H = 0, 4, 8, 12, 16, and 20.\r\nFor M1 = 5, M2 takes values from 0 to 4 i.e., 5 values, for H = 0, 5, 10, 15 and 20.\r\nAny further values of M1 cannot be considered since M1M2 will then exceed 60 minutes which is not possible.\r\nHence the total = 10+10+8+6+5 = 39\r\nThis is for 24 hours.\r\nIn a day the number of instances where H is exactly divisible by M1 giving M2 as quotient is =\r\n39 instances in a 24-hour format.\n<|im_start|>answer\nClearing the scope of the problem, we have to divide H by M1 getting M2 as the quotient with remainder as 0. \n\r\nFirst let us consider the time format to be a 12-hour format. \r\nHere H can take values from 1 to 12.\r\nFor M1 = 0, no value exists since divisor itself is 0.\r\nFor M1 = 1, M2 takes values from 1 to 9 i.e., 9 values, for H = 1 to 9.\r\nFor M1 = 2, M2 takes values from 1 to 6 i.e., 6 values, for H = 2, 4, 6, 8, 10 and 12.\r\nFor M1 = 3, M2 takes values from 1 to 4 i.e., 4 values, for H = 3, 6, 9, and 12.\r\nFor M1 = 4, M2 takes values from 1 to 3 i.e., 3 values, for H = 4, 8, and 12.\r\nFor M1 = 5, M2 takes values from 1 to 2 i.e., 2 values, for H = 5 and 10.\r\nAny further values of M1 cannot be considered since M1M2 will then exceed 60 minutes which is not possible.\r\nHence the total = 9+6+4+3+2 = 24\r\nThis is for 12 hours.\r\nIn a day the number of instances where H is exactly divisible by M1 giving M2 as quotient is =\r\n24 * 2 = 48 instances in a 12-hour format.\n\r\nNow let us consider the time format to be a 24-hour format.\r\nHere H can take values from 0 to 23.\r\nFor M1 = 0, no value exists since divisor itself is 0.\r\nFor M1 = 1, M2 takes values from 0 to 9 i.e., 10 values, for H = 0 to 9.\r\nFor M1 = 2, M2 takes values from 0 to 9 i.e., 10 values, for H = 0, 2, 4, 6, 8, 10, 12, 14, 16, and 18.\r\nFor M1 = 3, M2 takes values from 0 to 7 i.e., 8 values, for H = 0, 3, 6, 9, 12, 15, 18 and 21.\r\nFor M1 = 4, M2 takes values from 0 to 5 i.e., 6 values, for H = 0, 4, 8, 12, 16, and 20.\r\nFor M1 = 5, M2 takes values from 0 to 4 i.e., 5 values, for H = 0, 5, 10, 15 and 20.\r\nAny further values of M1 cannot be considered since M1M2 will then exceed 60 minutes which is not possible.\r\nHence the total = 10+10+8+6+5 = 39\r\nThis is for 24 hours.\r\nIn a day the number of instances where H is exactly divisible by M1 giving M2 as quotient is =\r\n39 instances in a 24-hour format.\n<|im_end|>" }, { "id": "#4954", "title": "Captain", "fun": 2.18, "difficulty": 1.58, "author": "glennyboy02", "desc": "Three girls, Naomi, Elizabeth and Anna, were being considered girls captain and vice-captain, and two boys Luke and Kuan, were being considered for boys captain and vice-captain. In how many different ways could the captains and vice captains be chosen?", "hint": "No hint available.", "answer": "12", "category": "Math", "date": "06/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree girls, Naomi, Elizabeth and Anna, were being considered girls captain and vice-captain, and two boys Luke and Kuan, were being considered for boys captain and vice-captain. In how many different ways could the captains and vice captains be chosen?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12\n<|im_start|>answer\n12\n<|im_end|>" }, { "id": "#43443", "title": "Lego Wars", "fun": 2.18, "difficulty": 1.3800000000000001, "author": "phrebh", "desc": "Three friends had three kids who were all named after Star Wars characters. For Christmas one year, all three kids (Han, Leia, and Luke) got different Star Wars Lego sets as gifts (the Millennium Falcon, an AT-AT, and an Imperial Star Destroyer). Each set had a different number of pieces (1345, 1432, or 1569) and each kid took a different amount of time to complete the model (2, 3, or 4 hours). Using the clues below, can you figure out which kid got which model, how many pieces it had, and how long it took them to build it?\n\r\n1. The model with the most pieces took the most time to complete, but the model with the least pieces did not take the least amount of time to complete.\r\n2. The models weren't to scale, so the Millennium Falcon actually had more pieces than the Imperial Star Destroyer, a fact that Luke was upset to learn since he likes bigger models.\r\n3. Han spent the three hours between opening his gifts and lunch building his model.", "hint": "No hint available.", "answer": "Han built the AT-AT, which had 1345 pieces, in 3 hours.\r\nLeia built the Millennium Falcon, which had 1569 pieces, in 4 hours.\r\nLuke built the Imperial Star Destroyer, which had 1432 pieces, in 2 hours.", "category": "Logic-Grid", "date": "10/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends had three kids who were all named after Star Wars characters. For Christmas one year, all three kids (Han, Leia, and Luke) got different Star Wars Lego sets as gifts (the Millennium Falcon, an AT-AT, and an Imperial Star Destroyer). Each set had a different number of pieces (1345, 1432, or 1569) and each kid took a different amount of time to complete the model (2, 3, or 4 hours). Using the clues below, can you figure out which kid got which model, how many pieces it had, and how long it took them to build it?\n\r\n1. The model with the most pieces took the most time to complete, but the model with the least pieces did not take the least amount of time to complete.\r\n2. The models weren't to scale, so the Millennium Falcon actually had more pieces than the Imperial Star Destroyer, a fact that Luke was upset to learn since he likes bigger models.\r\n3. Han spent the three hours between opening his gifts and lunch building his model.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHan built the AT-AT, which had 1345 pieces, in 3 hours.\r\nLeia built the Millennium Falcon, which had 1569 pieces, in 4 hours.\r\nLuke built the Imperial Star Destroyer, which had 1432 pieces, in 2 hours.\n<|im_start|>answer\nHan built the AT-AT, which had 1345 pieces, in 3 hours.\r\nLeia built the Millennium Falcon, which had 1569 pieces, in 4 hours.\r\nLuke built the Imperial Star Destroyer, which had 1432 pieces, in 2 hours.\n<|im_end|>" }, { "id": "#4062", "title": "Number Column", "fun": 2.18, "difficulty": 2.57, "author": "cathalmccabe", "desc": "What numbers do the \"*\" represent? (Two different numbers)\n\r\n41431\r\n3252*\r\n73956\r\n23032\r\n96988\r\n6446*", "hint": "Think about the columns", "answer": "5 AND 3\n\r\nADD the first two numbers in a column to get the third number, ADD the fourth number to get the fifth MINUS the SECOND number to get the last\n\r\nFor the first column:\r\n4 + 3 = 7 + 2 = 9 - 3 = 6", "category": "Math", "date": "05/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat numbers do the \"*\" represent? (Two different numbers)\n\r\n41431\r\n3252*\r\n73956\r\n23032\r\n96988\r\n6446*\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 AND 3\n\r\nADD the first two numbers in a column to get the third number, ADD the fourth number to get the fifth MINUS the SECOND number to get the last\n\r\nFor the first column:\r\n4 + 3 = 7 + 2 = 9 - 3 = 6\n<|im_start|>answer\n5 AND 3\n\r\nADD the first two numbers in a column to get the third number, ADD the fourth number to get the fifth MINUS the SECOND number to get the last\n\r\nFor the first column:\r\n4 + 3 = 7 + 2 = 9 - 3 = 6\n<|im_end|>" }, { "id": "#3942", "title": "How Long to Count", "fun": 2.18, "difficulty": 2.07, "author": "mad-ade", "desc": "How long would it take to count to one billion, if you counted 200 every minute and were given one day off every four years?", "hint": "No hint available.", "answer": "9 years, 187 days, 5 hours, 20 minutes.\r\nthe days off were there to account for leap years.", "category": "Math", "date": "05/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow long would it take to count to one billion, if you counted 200 every minute and were given one day off every four years?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9 years, 187 days, 5 hours, 20 minutes.\r\nthe days off were there to account for leap years.\n<|im_start|>answer\n9 years, 187 days, 5 hours, 20 minutes.\r\nthe days off were there to account for leap years.\n<|im_end|>" }, { "id": "#16537", "title": "Five", "fun": 2.18, "difficulty": 1.55, "author": "XOLPLINKINPARK", "desc": "What number gives the same result when it is added to 5 as when it is multiplied by 5?", "hint": "No hint available.", "answer": "1.25 \n\r\n1.25 + 5 = 6.25 \r\n1.25 x 5 = 6.25", "category": "Math", "date": "02/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number gives the same result when it is added to 5 as when it is multiplied by 5?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1.25 \n\r\n1.25 + 5 = 6.25 \r\n1.25 x 5 = 6.25\n<|im_start|>answer\n1.25 \n\r\n1.25 + 5 = 6.25 \r\n1.25 x 5 = 6.25\n<|im_end|>" }, { "id": "#42966", "title": "Tom and John", "fun": 2.18, "difficulty": 1.25, "author": "cacmjc", "desc": "The sum of the ages of Tom and John is 20 years. In 4 years, John's age will be three-fourths of Tom's age. How old is Tom now?", "hint": "No hint available.", "answer": "12", "category": "Math", "date": "09/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe sum of the ages of Tom and John is 20 years. In 4 years, John's age will be three-fourths of Tom's age. How old is Tom now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12\n<|im_start|>answer\n12\n<|im_end|>" }, { "id": "#6561", "title": "Not October", "fun": 2.18, "difficulty": 0.74, "author": "Bintot", "desc": "What occurs once in June and twice in August, but never occurs in October?", "hint": "No hint available.", "answer": "The letter U.", "category": "Logic", "date": "08/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat occurs once in June and twice in August, but never occurs in October?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe letter U.\n<|im_start|>answer\nThe letter U.\n<|im_end|>" }, { "id": "#4422", "title": "Out to Lunch", "fun": 2.17, "difficulty": 2.42, "author": "mad-ade", "desc": "Mad Ade travels on a cycle from home to his favourite kebab shop on a straight road with wind against him. He took 4 hours to reach there. \n\r\nOn the way back, Mad Ade took 3 hours to reach Home as the wind was in the same direction. \n\r\nIf there is no wind, how much time does Mad Ade take to travel from home to the kebab shop?", "hint": "No hint available.", "answer": "Let distance between home and the kebab shop is D. \n\r\nMad Ade took 4 hours to reach the kebab shop. So speed while travelling towards the kebab shop is D/4. \n\r\nSimilarly, he took 3 hours to reach home. So speed while coming back is D/3. \n\r\nThere is a speed difference of 7*D/12, which is the wind helping Mad Ade in 1 direction, & slowing him in the other direction. Average the 2 speeds, & you have the speed that person can travel in no wind, which is 7*D/24. \n\r\nHence, Mad Ade will take D / (7*D/24) hours to travel distance D which is 24/7 hours. \n\r\nAnswer is 3 hours 25 minutes 42 seconds", "category": "Math", "date": "06/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade travels on a cycle from home to his favourite kebab shop on a straight road with wind against him. He took 4 hours to reach there. \n\r\nOn the way back, Mad Ade took 3 hours to reach Home as the wind was in the same direction. \n\r\nIf there is no wind, how much time does Mad Ade take to travel from home to the kebab shop?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet distance between home and the kebab shop is D. \n\r\nMad Ade took 4 hours to reach the kebab shop. So speed while travelling towards the kebab shop is D/4. \n\r\nSimilarly, he took 3 hours to reach home. So speed while coming back is D/3. \n\r\nThere is a speed difference of 7*D/12, which is the wind helping Mad Ade in 1 direction, & slowing him in the other direction. Average the 2 speeds, & you have the speed that person can travel in no wind, which is 7*D/24. \n\r\nHence, Mad Ade will take D / (7*D/24) hours to travel distance D which is 24/7 hours. \n\r\nAnswer is 3 hours 25 minutes 42 seconds\n<|im_start|>answer\nLet distance between home and the kebab shop is D. \n\r\nMad Ade took 4 hours to reach the kebab shop. So speed while travelling towards the kebab shop is D/4. \n\r\nSimilarly, he took 3 hours to reach home. So speed while coming back is D/3. \n\r\nThere is a speed difference of 7*D/12, which is the wind helping Mad Ade in 1 direction, & slowing him in the other direction. Average the 2 speeds, & you have the speed that person can travel in no wind, which is 7*D/24. \n\r\nHence, Mad Ade will take D / (7*D/24) hours to travel distance D which is 24/7 hours. \n\r\nAnswer is 3 hours 25 minutes 42 seconds\n<|im_end|>" }, { "id": "#4783", "title": "Pet Emporium", "fun": 2.17, "difficulty": 1.71, "author": "mad-ade", "desc": "One of Mad Ade's after-school jobs when he was younger was at \"Dodgy Pete's second hand Pet Emporium\". His boss, Dodgy Pete himself, told Mad Ade to stack 35 cartons of \"chicken and postman\" flavoured dog food so that each row of cartons would have one more than the row above it. How many rows of cartons did Mad Ade have when he was finished?", "hint": "No hint available.", "answer": "7 rows. 8 cartons in the bottom row, 2 in the top.", "category": "Logic", "date": "06/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne of Mad Ade's after-school jobs when he was younger was at \"Dodgy Pete's second hand Pet Emporium\". His boss, Dodgy Pete himself, told Mad Ade to stack 35 cartons of \"chicken and postman\" flavoured dog food so that each row of cartons would have one more than the row above it. How many rows of cartons did Mad Ade have when he was finished?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 rows. 8 cartons in the bottom row, 2 in the top.\n<|im_start|>answer\n7 rows. 8 cartons in the bottom row, 2 in the top.\n<|im_end|>" }, { "id": "#2008", "title": "Paper Plate Challenge", "fun": 2.17, "difficulty": 1.51, "author": "Mogmatt16", "desc": "Your father has given you a challenge: you and he will take turns placing paper plates on your own half of a table. Whoever is the last one able to place a plate is the winner. Assuming your father goes first, how can you guarantee you will win? You better be able to do it; it's double or nothing on your allowance!", "hint": "Going second is a key part to this plan.", "answer": "Mirror all of your father's moves. As long he can place a plate, you can place a plate.", "category": "Logic", "date": "01/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour father has given you a challenge: you and he will take turns placing paper plates on your own half of a table. Whoever is the last one able to place a plate is the winner. Assuming your father goes first, how can you guarantee you will win? You better be able to do it; it's double or nothing on your allowance!\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMirror all of your father's moves. As long he can place a plate, you can place a plate.\n<|im_start|>answer\nMirror all of your father's moves. As long he can place a plate, you can place a plate.\n<|im_end|>" }, { "id": "#37710", "title": "Like Oil and Water", "fun": 2.17, "difficulty": 1.75, "author": "leftclick", "desc": "Imagine two jugs, the first containing one litre of oil, the second containing one litre of water. Ten millilitres is poured from the first jug into the second, and then ten millilitres is poured from the second jug into the first.\n\r\nWhich of the jugs now contains more of the liquid from the other jug? (Is there more oil in the second jug, or water in the first jug?)", "hint": "Look at the category - this is not a Science teaser! It doesn't matter whether or not oil floats on water...", "answer": "The first jug always ends up with the same amount of water as the second jug has oil.\n\r\nIt doesn't matter whether more water or oil is transferred the second time. At the end, the total volume in each jug is the same, and the total volume of each liquid is the same. All that has happened is a certain (unknown) amount of oil from the first jug has been swapped with the same amount of water from the second jug.", "category": "Logic", "date": "08/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImagine two jugs, the first containing one litre of oil, the second containing one litre of water. Ten millilitres is poured from the first jug into the second, and then ten millilitres is poured from the second jug into the first.\n\r\nWhich of the jugs now contains more of the liquid from the other jug? (Is there more oil in the second jug, or water in the first jug?)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe first jug always ends up with the same amount of water as the second jug has oil.\n\r\nIt doesn't matter whether more water or oil is transferred the second time. At the end, the total volume in each jug is the same, and the total volume of each liquid is the same. All that has happened is a certain (unknown) amount of oil from the first jug has been swapped with the same amount of water from the second jug.\n<|im_start|>answer\nThe first jug always ends up with the same amount of water as the second jug has oil.\n\r\nIt doesn't matter whether more water or oil is transferred the second time. At the end, the total volume in each jug is the same, and the total volume of each liquid is the same. All that has happened is a certain (unknown) amount of oil from the first jug has been swapped with the same amount of water from the second jug.\n<|im_end|>" }, { "id": "#7122", "title": "How Old", "fun": 2.17, "difficulty": 1.36, "author": "master123", "desc": "Kevin is 5 years old; James is also 5 years old and Rebecca is 7 years old. How old is Bernadette?", "hint": "No hint available.", "answer": "10 years old, the length of the name in years.", "category": "Logic", "date": "09/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKevin is 5 years old; James is also 5 years old and Rebecca is 7 years old. How old is Bernadette?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10 years old, the length of the name in years.\n<|im_start|>answer\n10 years old, the length of the name in years.\n<|im_end|>" }, { "id": "#23541", "title": "How Many Fares?", "fun": 2.17, "difficulty": 1.23, "author": "Tammy93", "desc": "A student at Harvard decided to become his own employer by using his car as a taxi for the summer. It costs the student $693.00 to insure his car for the 4 months of summer. He spends $452.00 per month on gas. If he lives at home and has no other expenses for the 4 months of summer and charges an average of $7.00 per fare, how many fares will he have to get to be able to pay his tuition of $3280.00?", "hint": "Let the number of fares= x", "answer": "$3280.00 + ($452)4 + $693.00=\r\n$5781.00\n\r\n$5781.00/$7.00 = 825.85 \r\nTherefore 826 fares are necessary to have enough money", "category": "Math", "date": "06/09/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA student at Harvard decided to become his own employer by using his car as a taxi for the summer. It costs the student $693.00 to insure his car for the 4 months of summer. He spends $452.00 per month on gas. If he lives at home and has no other expenses for the 4 months of summer and charges an average of $7.00 per fare, how many fares will he have to get to be able to pay his tuition of $3280.00?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$3280.00 + ($452)4 + $693.00=\r\n$5781.00\n\r\n$5781.00/$7.00 = 825.85 \r\nTherefore 826 fares are necessary to have enough money\n<|im_start|>answer\n$3280.00 + ($452)4 + $693.00=\r\n$5781.00\n\r\n$5781.00/$7.00 = 825.85 \r\nTherefore 826 fares are necessary to have enough money\n<|im_end|>" }, { "id": "#20697", "title": "=JE", "fun": 2.17, "difficulty": 2.88, "author": "doggyxp", "desc": "Each letter in the sets of equations below represents a number; substitute the numbers in to make the expressions correct. Each letter always represents the same number.\n\r\nABC/3=JE\r\nDEF/6=JE\r\nGHJ/9=JE", "hint": "No hint available.", "answer": "219/3=73\r\n438/6=73\r\n657/9=73", "category": "Math", "date": "01/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach letter in the sets of equations below represents a number; substitute the numbers in to make the expressions correct. Each letter always represents the same number.\n\r\nABC/3=JE\r\nDEF/6=JE\r\nGHJ/9=JE\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n219/3=73\r\n438/6=73\r\n657/9=73\n<|im_start|>answer\n219/3=73\r\n438/6=73\r\n657/9=73\n<|im_end|>" }, { "id": "#30803", "title": "Nyuk Nyuk Nyuk", "fun": 2.17, "difficulty": 1.08, "author": "phrebh", "desc": "Three friends (Jerome, Louis, and Moses) were discussing the genius of the Three Stooges when they broke out into an argument over who was the worst 'third' Stooge (Curly Joe, Joe, or Shemp) and which schtick was the funniest (Eye Poke, Hair Pull, Stomach Punch). Using the clues below, determine who disliked which replacement and what gag they thought was the best.\n\r\n1. Moses was no fan of the eye poke.\r\n2. The person who disliked Shemp the most thought that the hair pull was the funniest.\r\n3. Jerome had no problem with Joe.\r\n4. Moses kind of liked Curly Joe's work.\r\n5. Louis hated the hair pull.\r\n6. Jerome thought the stomach punch looked too mean.\r\n7. Someone really liked to see Joe get punched in the stomach.\r\n8. Louis thought that the name 'Curly' was sacred and always disliked Curly Joe for using it.", "hint": "No hint available.", "answer": "Jerome disliked Shemp and liked the hair pull.\r\nLouis disliked Curly Joe and liked the eye poke.\r\nMoses disliked Joe and liked the stomach punch.", "category": "Logic-Grid", "date": "05/31/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends (Jerome, Louis, and Moses) were discussing the genius of the Three Stooges when they broke out into an argument over who was the worst 'third' Stooge (Curly Joe, Joe, or Shemp) and which schtick was the funniest (Eye Poke, Hair Pull, Stomach Punch). Using the clues below, determine who disliked which replacement and what gag they thought was the best.\n\r\n1. Moses was no fan of the eye poke.\r\n2. The person who disliked Shemp the most thought that the hair pull was the funniest.\r\n3. Jerome had no problem with Joe.\r\n4. Moses kind of liked Curly Joe's work.\r\n5. Louis hated the hair pull.\r\n6. Jerome thought the stomach punch looked too mean.\r\n7. Someone really liked to see Joe get punched in the stomach.\r\n8. Louis thought that the name 'Curly' was sacred and always disliked Curly Joe for using it.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJerome disliked Shemp and liked the hair pull.\r\nLouis disliked Curly Joe and liked the eye poke.\r\nMoses disliked Joe and liked the stomach punch.\n<|im_start|>answer\nJerome disliked Shemp and liked the hair pull.\r\nLouis disliked Curly Joe and liked the eye poke.\r\nMoses disliked Joe and liked the stomach punch.\n<|im_end|>" }, { "id": "#1444", "title": "$100 Bill", "fun": 2.17, "difficulty": 1.23, "author": "dariban", "desc": "Joe and Bob are walking down the street. Joe stumbles across a $100 bill on the sidewalk across the street. Joe picks up the bill and tells Bob, \"Since you were with me when I found this, I'll give you half.\" So they go to the bank and half it up. But Joe decides that since he found the $100, he should have 10 more dollars than Bob. How much would Joe have and how much would Bob have?", "hint": "No hint available.", "answer": "Joe- $55\r\nBob- $45", "category": "Math", "date": "11/18/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe and Bob are walking down the street. Joe stumbles across a $100 bill on the sidewalk across the street. Joe picks up the bill and tells Bob, \"Since you were with me when I found this, I'll give you half.\" So they go to the bank and half it up. But Joe decides that since he found the $100, he should have 10 more dollars than Bob. How much would Joe have and how much would Bob have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoe- $55\r\nBob- $45\n<|im_start|>answer\nJoe- $55\r\nBob- $45\n<|im_end|>" }, { "id": "#19275", "title": "Chess-o-mania !!!", "fun": 2.17, "difficulty": 2.69, "author": "lesternoronha1", "desc": "In a chess tournament conducted by the Romankachi World Chess Federation, every person played one game with every other person in the group. The total number of games that men played between themselves exceeded those played by men with women by 18. If there were 4 women on the tournament, totally how many games were played in the tournament?", "hint": "No hint available.", "answer": "Totally 120 games were played in the tournament.\n\r\nLet N be the number of men in the tournament.\r\nThen the number of games played by men between themselves\r\n= N*(N-1)/2\n\r\nThe number of games played by men with women\r\n= 4*N \r\n(since there were 4 women in the tournament)\n\r\nIt is given that the total number of games that men played between themselves exceeded those played by men with women by 18.\n\r\nHence\r\nN*(N-1)/2 - 4*N = 18\r\nN*(N-1) - 8*N = 36\r\nN*N - N - 8*N = 36\r\nN^2 - 9*N - 36 = 0\n\r\nFactorizing we get,\r\nN^2 - 12*N + 3*N - 36 = 0\r\nN*(N - 12) + 3*(N - 12) = 0\r\n(N - 12)(N + 3) = 0\r\nHence N = 12 or -3 (not possible).\n\r\nHence the number of men in the chess tournament \r\n= N = 12\n\r\nTherefore the total number of people participating in the chess tournament = 12 + 4 = 16.\n\r\nThe total number of games played in the tournament \r\n= T*(T-1)/2 \r\n= 16*15/2\r\n= 120", "category": "Math", "date": "10/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a chess tournament conducted by the Romankachi World Chess Federation, every person played one game with every other person in the group. The total number of games that men played between themselves exceeded those played by men with women by 18. If there were 4 women on the tournament, totally how many games were played in the tournament?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTotally 120 games were played in the tournament.\n\r\nLet N be the number of men in the tournament.\r\nThen the number of games played by men between themselves\r\n= N*(N-1)/2\n\r\nThe number of games played by men with women\r\n= 4*N \r\n(since there were 4 women in the tournament)\n\r\nIt is given that the total number of games that men played between themselves exceeded those played by men with women by 18.\n\r\nHence\r\nN*(N-1)/2 - 4*N = 18\r\nN*(N-1) - 8*N = 36\r\nN*N - N - 8*N = 36\r\nN^2 - 9*N - 36 = 0\n\r\nFactorizing we get,\r\nN^2 - 12*N + 3*N - 36 = 0\r\nN*(N - 12) + 3*(N - 12) = 0\r\n(N - 12)(N + 3) = 0\r\nHence N = 12 or -3 (not possible).\n\r\nHence the number of men in the chess tournament \r\n= N = 12\n\r\nTherefore the total number of people participating in the chess tournament = 12 + 4 = 16.\n\r\nThe total number of games played in the tournament \r\n= T*(T-1)/2 \r\n= 16*15/2\r\n= 120\n<|im_start|>answer\nTotally 120 games were played in the tournament.\n\r\nLet N be the number of men in the tournament.\r\nThen the number of games played by men between themselves\r\n= N*(N-1)/2\n\r\nThe number of games played by men with women\r\n= 4*N \r\n(since there were 4 women in the tournament)\n\r\nIt is given that the total number of games that men played between themselves exceeded those played by men with women by 18.\n\r\nHence\r\nN*(N-1)/2 - 4*N = 18\r\nN*(N-1) - 8*N = 36\r\nN*N - N - 8*N = 36\r\nN^2 - 9*N - 36 = 0\n\r\nFactorizing we get,\r\nN^2 - 12*N + 3*N - 36 = 0\r\nN*(N - 12) + 3*(N - 12) = 0\r\n(N - 12)(N + 3) = 0\r\nHence N = 12 or -3 (not possible).\n\r\nHence the number of men in the chess tournament \r\n= N = 12\n\r\nTherefore the total number of people participating in the chess tournament = 12 + 4 = 16.\n\r\nThe total number of games played in the tournament \r\n= T*(T-1)/2 \r\n= 16*15/2\r\n= 120\n<|im_end|>" }, { "id": "#44354", "title": "A Race with Friends", "fun": 2.17, "difficulty": 0.71, "author": "Shnazzle", "desc": "Some friends wanted to know who was the fastest, so they held a running race around the park. Justine, Hannah, Meagan, Georgia and Ellen placed in the race. Using the clues given, work out who got what place from 1st to 5th and what colour shirt they were wearing.\n\n\r\n1. Georgia wasn't wearing a red or a pink shirt because Hannah and Meagan were.\n\r\n2. Ellen was wearing yellow and did not come in 2nd or 3rd.\n\r\n3. Meagan was faster than Georgia and Ellen but not Justine.\n\r\n4. Georgia was not the slowest but not in the top 3.\n\r\n5. Hannah came in first and wasn't wearing pink.\n\r\n6. Meagan didn't come in 1st or 2nd.\n\r\n7. Green was not being worn by Georgia.", "hint": "Some of the clues are not necessary but they can still be helpful.", "answer": "Hannah came in 1st and was wearing red.\r\nJustine came in 2nd and was wearing green.\r\nMeagan came in 3rd and was wearing pink.\r\nGeorgia came in 4th and was wearing blue.\r\nEllen came in 5th and was wearing yellow.", "category": "Logic-Grid", "date": "04/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome friends wanted to know who was the fastest, so they held a running race around the park. Justine, Hannah, Meagan, Georgia and Ellen placed in the race. Using the clues given, work out who got what place from 1st to 5th and what colour shirt they were wearing.\n\n\r\n1. Georgia wasn't wearing a red or a pink shirt because Hannah and Meagan were.\n\r\n2. Ellen was wearing yellow and did not come in 2nd or 3rd.\n\r\n3. Meagan was faster than Georgia and Ellen but not Justine.\n\r\n4. Georgia was not the slowest but not in the top 3.\n\r\n5. Hannah came in first and wasn't wearing pink.\n\r\n6. Meagan didn't come in 1st or 2nd.\n\r\n7. Green was not being worn by Georgia.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHannah came in 1st and was wearing red.\r\nJustine came in 2nd and was wearing green.\r\nMeagan came in 3rd and was wearing pink.\r\nGeorgia came in 4th and was wearing blue.\r\nEllen came in 5th and was wearing yellow.\n<|im_start|>answer\nHannah came in 1st and was wearing red.\r\nJustine came in 2nd and was wearing green.\r\nMeagan came in 3rd and was wearing pink.\r\nGeorgia came in 4th and was wearing blue.\r\nEllen came in 5th and was wearing yellow.\n<|im_end|>" }, { "id": "#5356", "title": "1st of February", "fun": 2.17, "difficulty": 1.43, "author": "mad-ade", "desc": "If there are 5 Mondays, 5 Tuesdays and 5 Wednesdays in January, on what day of the week will February 1st fall?", "hint": "No hint available.", "answer": "Thursday", "category": "Logic", "date": "07/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf there are 5 Mondays, 5 Tuesdays and 5 Wednesdays in January, on what day of the week will February 1st fall?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThursday\n<|im_start|>answer\nThursday\n<|im_end|>" }, { "id": "#3050", "title": "Murder in a House", "fun": 2.17, "difficulty": 1.3800000000000001, "author": "lil_thugsta", "desc": "There was once a round house. One raining day the gardener was watering the flowers, the maid was sweeping the corners of the house, the chauffeur was sleeping in the car and a murder took place.\r\nWhat is wrong with each person's alibi?", "hint": "No hint available.", "answer": "The maid couldn't sweep corners, it's a round house.\r\nThe gardener shouldn't water flowers when it's raining.\r\nThe chauffeur shouldn't sleep in the car, he's driving.", "category": "Logic", "date": "03/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was once a round house. One raining day the gardener was watering the flowers, the maid was sweeping the corners of the house, the chauffeur was sleeping in the car and a murder took place.\r\nWhat is wrong with each person's alibi?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe maid couldn't sweep corners, it's a round house.\r\nThe gardener shouldn't water flowers when it's raining.\r\nThe chauffeur shouldn't sleep in the car, he's driving.\n<|im_start|>answer\nThe maid couldn't sweep corners, it's a round house.\r\nThe gardener shouldn't water flowers when it's raining.\r\nThe chauffeur shouldn't sleep in the car, he's driving.\n<|im_end|>" }, { "id": "#18882", "title": "RomanKachi Locker !!!", "fun": 2.17, "difficulty": 2.35, "author": "lesternoronha1", "desc": "I went to attend the funeral of my uncle, Randervaz the second, of the rich and famous Romankachi dynasty. He'd died the previous day after a long ailment of cancer. Having attended the funeral, I met my uncle's lawyer on the way out from the cemetery. He told me that my uncle had bequeathed part or all of his property to me in his will. However, he'd given strict instructions to his lawyer not to read this will until I satisfy a condition mentioned in his will. I had to get a legal document with my uncle's signature on it which said that now the will could be read out. However, this was locked away in one of the lockers of the Romankachi state bank. Saying this, he handed me an envelope addressed to me by my uncle. The envelope had a clue in it to lead me to the specified locker.\n\r\nWhen I opened the letter, it read as follows :-\n\r\n\"Dearest nephew, you must already be knowing that you have to get a document with my signature on it from the Romankachi state bank in order for the will to be read out. All that I can tell you is that the locker is numbered 'bcb', such that\r\n(ab)*(ba)=(bcb),\r\nwhere a, b and c are all distinct positive integers from 1 to 9. The number 'ab' represents the two digit number whose 10's digit is a and units digit is b. The numbers 'ba' and 'bcb' also have similar meanings. Best of luck, Ruddy.\"\n\r\nCan you find the locker number and help me out?", "hint": "No hint available.", "answer": "The equation given in the letter is\r\n(ab)*(ba)=bcb\n\r\nNow (10a + b)*(10b + a) = bcb, given that the number 'ab' represents the two digit number whose 10's digit is a and units digit is b and so on for 'ba' and 'bcb'.\n\r\nHence 100*a*b + 10*(a^2 + b^2) + a*b = bcb, where ^ represents the operation \"to the power of\".\n\r\nThis is possible if ab = b and a^2 + b^2 = c, that is if a = 1 and hence 1 + b^2 = c.\n\r\nTrying out various number from 1 to 9 for c in the above equation, I strike upon a combination that satisfies this equation 1 + b^2 = c, i.e. 1 + 2^2 = 5.\n\r\nThus a = 1, b = 2 and c = 5.\r\nTherefore the locker number must be 252.\r\nVerifying (ab)*(ba)=bcb, I got (12)*(21)=252", "category": "Math", "date": "09/20/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI went to attend the funeral of my uncle, Randervaz the second, of the rich and famous Romankachi dynasty. He'd died the previous day after a long ailment of cancer. Having attended the funeral, I met my uncle's lawyer on the way out from the cemetery. He told me that my uncle had bequeathed part or all of his property to me in his will. However, he'd given strict instructions to his lawyer not to read this will until I satisfy a condition mentioned in his will. I had to get a legal document with my uncle's signature on it which said that now the will could be read out. However, this was locked away in one of the lockers of the Romankachi state bank. Saying this, he handed me an envelope addressed to me by my uncle. The envelope had a clue in it to lead me to the specified locker.\n\r\nWhen I opened the letter, it read as follows :-\n\r\n\"Dearest nephew, you must already be knowing that you have to get a document with my signature on it from the Romankachi state bank in order for the will to be read out. All that I can tell you is that the locker is numbered 'bcb', such that\r\n(ab)*(ba)=(bcb),\r\nwhere a, b and c are all distinct positive integers from 1 to 9. The number 'ab' represents the two digit number whose 10's digit is a and units digit is b. The numbers 'ba' and 'bcb' also have similar meanings. Best of luck, Ruddy.\"\n\r\nCan you find the locker number and help me out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe equation given in the letter is\r\n(ab)*(ba)=bcb\n\r\nNow (10a + b)*(10b + a) = bcb, given that the number 'ab' represents the two digit number whose 10's digit is a and units digit is b and so on for 'ba' and 'bcb'.\n\r\nHence 100*a*b + 10*(a^2 + b^2) + a*b = bcb, where ^ represents the operation \"to the power of\".\n\r\nThis is possible if ab = b and a^2 + b^2 = c, that is if a = 1 and hence 1 + b^2 = c.\n\r\nTrying out various number from 1 to 9 for c in the above equation, I strike upon a combination that satisfies this equation 1 + b^2 = c, i.e. 1 + 2^2 = 5.\n\r\nThus a = 1, b = 2 and c = 5.\r\nTherefore the locker number must be 252.\r\nVerifying (ab)*(ba)=bcb, I got (12)*(21)=252\n<|im_start|>answer\nThe equation given in the letter is\r\n(ab)*(ba)=bcb\n\r\nNow (10a + b)*(10b + a) = bcb, given that the number 'ab' represents the two digit number whose 10's digit is a and units digit is b and so on for 'ba' and 'bcb'.\n\r\nHence 100*a*b + 10*(a^2 + b^2) + a*b = bcb, where ^ represents the operation \"to the power of\".\n\r\nThis is possible if ab = b and a^2 + b^2 = c, that is if a = 1 and hence 1 + b^2 = c.\n\r\nTrying out various number from 1 to 9 for c in the above equation, I strike upon a combination that satisfies this equation 1 + b^2 = c, i.e. 1 + 2^2 = 5.\n\r\nThus a = 1, b = 2 and c = 5.\r\nTherefore the locker number must be 252.\r\nVerifying (ab)*(ba)=bcb, I got (12)*(21)=252\n<|im_end|>" }, { "id": "#4009", "title": "Horse Weight", "fun": 2.17, "difficulty": 1.54, "author": "mad-ade", "desc": "If Mad Ade has a horse that weighs 600 kilos plus a third of its own weight, how much does it weigh?", "hint": "No hint available.", "answer": "900 kilos (600= 2 thirds therefore 300 = 1 third)", "category": "Math", "date": "05/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf Mad Ade has a horse that weighs 600 kilos plus a third of its own weight, how much does it weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n900 kilos (600= 2 thirds therefore 300 = 1 third)\n<|im_start|>answer\n900 kilos (600= 2 thirds therefore 300 = 1 third)\n<|im_end|>" }, { "id": "#6393", "title": "Letter Mix", "fun": 2.17, "difficulty": 1.5, "author": "mad-ade", "desc": "S T U V W X Y Z\n\r\nWhich letter is two to the right of the letter that is three to the left of the letter that is four to the right of U ?", "hint": "No hint available.", "answer": "X", "category": "Logic", "date": "08/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nS T U V W X Y Z\n\r\nWhich letter is two to the right of the letter that is three to the left of the letter that is four to the right of U ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nX\n<|im_start|>answer\nX\n<|im_end|>" }, { "id": "#20054", "title": "Nurse, Accountant and Electrician", "fun": 2.17, "difficulty": 0.72, "author": "Nicky101", "desc": "Nicky, Jared, and Antoine are an electrician, accountant and nurse. Jared is the electrician's brother and Antoine has never met the electrician or the accountant. Which person has each job?", "hint": "No hint available.", "answer": "Antoine is the nurse. Jared is the accountant. Nicky is the electrician.", "category": "Logic", "date": "12/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNicky, Jared, and Antoine are an electrician, accountant and nurse. Jared is the electrician's brother and Antoine has never met the electrician or the accountant. Which person has each job?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAntoine is the nurse. Jared is the accountant. Nicky is the electrician.\n<|im_start|>answer\nAntoine is the nurse. Jared is the accountant. Nicky is the electrician.\n<|im_end|>" }, { "id": "#40518", "title": "Summer Paintings", "fun": 2.17, "difficulty": 1.55, "author": "lab123", "desc": "At a recent painting competition, Eileen's rendition of a Constable was not last. Jenny only just managed to avoid last place and came third. The lady who painted a Monet was very successful and took first place. Ada beat the lady who painted the Taylor and the lady who painted the Van Gogh beat Vera. Can you determine who painted what and who won?", "hint": "No hint available.", "answer": "# Name Artist\r\n1 Ada Monet\r\n2 Eileen Constable\r\n3 Jenny Van Gogh\r\n4 Vera Taylor", "category": "Logic", "date": "02/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt a recent painting competition, Eileen's rendition of a Constable was not last. Jenny only just managed to avoid last place and came third. The lady who painted a Monet was very successful and took first place. Ada beat the lady who painted the Taylor and the lady who painted the Van Gogh beat Vera. Can you determine who painted what and who won?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n# Name Artist\r\n1 Ada Monet\r\n2 Eileen Constable\r\n3 Jenny Van Gogh\r\n4 Vera Taylor\n<|im_start|>answer\n# Name Artist\r\n1 Ada Monet\r\n2 Eileen Constable\r\n3 Jenny Van Gogh\r\n4 Vera Taylor\n<|im_end|>" }, { "id": "#16272", "title": "Profit Performances", "fun": 2.17, "difficulty": 1.76, "author": "adoontourious", "desc": "Every spring the town of Vicinity holds an arts festival in which local groups perform and artists sell crafts. The festival organizers raise money by charging each performing group $50.00. This year, members of the high school gymnastics team gave a demonstration. They charged a $2.50 admission fee. The team owed $62.50 for repairs to its parallel bars. Profits were shared equally among the six team members. \n\r\nIf 113 people saw the demonstration, how much profit did each team member get? Was any money left over?", "hint": "No hint available.", "answer": "Each gymnast got $28.33. There was $0.02 left over. \n\r\nThe 113 audience members paid a total of $282.50 (113 x $2.50). After subtracting the $50 fee and the $62.50 repair cost, there was a profit of $170. Dividing 6 team members into $170 gave each team member $28.33 with $0.02 left over. They all decided to go bowling, except for Irena, who was saving up for a CD player.", "category": "Math", "date": "01/20/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEvery spring the town of Vicinity holds an arts festival in which local groups perform and artists sell crafts. The festival organizers raise money by charging each performing group $50.00. This year, members of the high school gymnastics team gave a demonstration. They charged a $2.50 admission fee. The team owed $62.50 for repairs to its parallel bars. Profits were shared equally among the six team members. \n\r\nIf 113 people saw the demonstration, how much profit did each team member get? Was any money left over?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach gymnast got $28.33. There was $0.02 left over. \n\r\nThe 113 audience members paid a total of $282.50 (113 x $2.50). After subtracting the $50 fee and the $62.50 repair cost, there was a profit of $170. Dividing 6 team members into $170 gave each team member $28.33 with $0.02 left over. They all decided to go bowling, except for Irena, who was saving up for a CD player.\n<|im_start|>answer\nEach gymnast got $28.33. There was $0.02 left over. \n\r\nThe 113 audience members paid a total of $282.50 (113 x $2.50). After subtracting the $50 fee and the $62.50 repair cost, there was a profit of $170. Dividing 6 team members into $170 gave each team member $28.33 with $0.02 left over. They all decided to go bowling, except for Irena, who was saving up for a CD player.\n<|im_end|>" }, { "id": "#15472", "title": "The Amazing Flea", "fun": 2.17, "difficulty": 1.8800000000000001, "author": "spectramotion", "desc": "Imagine an amazingly magical flea that can spring two feet, three inches every hop. How many hops must it take to go around the world, the circumference being 25,020 miles? Also, how long would it require for the journey if it took sixty hops every minute? \r\nRemember this is a special flea and can live for a long time and hop on water.", "hint": "No hint available.", "answer": "It would take 58,713,600 hops, requiring one year, three hundred and fourteen days, thirteen hours and twenty minutes.", "category": "Math", "date": "11/19/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImagine an amazingly magical flea that can spring two feet, three inches every hop. How many hops must it take to go around the world, the circumference being 25,020 miles? Also, how long would it require for the journey if it took sixty hops every minute? \r\nRemember this is a special flea and can live for a long time and hop on water.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt would take 58,713,600 hops, requiring one year, three hundred and fourteen days, thirteen hours and twenty minutes.\n<|im_start|>answer\nIt would take 58,713,600 hops, requiring one year, three hundred and fourteen days, thirteen hours and twenty minutes.\n<|im_end|>" }, { "id": "#13882", "title": "The 199th Gas Station", "fun": 2.17, "difficulty": 1.37, "author": "smileysteve", "desc": "The 199th Gas Station is very large. It has ten rows of 10 double-sided pairs of pumps. The pump I am at is the only non-working pump. \n\r\nHow many working gas pumps are there at the 199th Gas Station?", "hint": "No hint available.", "answer": "399 pumps.\n\r\n10(rows) X 10 X 2 X 2 - 1 = 399", "category": "Math", "date": "07/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe 199th Gas Station is very large. It has ten rows of 10 double-sided pairs of pumps. The pump I am at is the only non-working pump. \n\r\nHow many working gas pumps are there at the 199th Gas Station?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n399 pumps.\n\r\n10(rows) X 10 X 2 X 2 - 1 = 399\n<|im_start|>answer\n399 pumps.\n\r\n10(rows) X 10 X 2 X 2 - 1 = 399\n<|im_end|>" }, { "id": "#11136", "title": "What are My Numbers?", "fun": 2.17, "difficulty": 1.39, "author": "karelmania", "desc": "What a pair we are,\r\nOur sum is 100,\r\nOur product tells you more,\r\nFor it is our sum times 24.\n\r\nWhat are the numbers?", "hint": "No hint available.", "answer": "40 and 60.\n\r\n40 + 60 = 100\r\n40 * 60 = 2400", "category": "Math", "date": "03/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat a pair we are,\r\nOur sum is 100,\r\nOur product tells you more,\r\nFor it is our sum times 24.\n\r\nWhat are the numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n40 and 60.\n\r\n40 + 60 = 100\r\n40 * 60 = 2400\n<|im_start|>answer\n40 and 60.\n\r\n40 + 60 = 100\r\n40 * 60 = 2400\n<|im_end|>" }, { "id": "#22910", "title": "Petals in the Rose", "fun": 2.17, "difficulty": 2.77, "author": "DummyisDumb", "desc": "You roll five dice. \r\nIf you roll 5, 3, 2, 1, 6 you get 8 points.\r\n2, 2, 3, 5, 1 = 8 points\r\n6, 5, 4, 3, 2 = 8 points\r\n1, 2, 6, 6, 6 = 6 points\r\n2, 2, 5, 6, 6 = 6 points\r\n4, 3, 6, 2, 6 = ? points", "hint": "No hint available.", "answer": "7 points. You get one point per vowel.", "category": "Logic", "date": "05/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou roll five dice. \r\nIf you roll 5, 3, 2, 1, 6 you get 8 points.\r\n2, 2, 3, 5, 1 = 8 points\r\n6, 5, 4, 3, 2 = 8 points\r\n1, 2, 6, 6, 6 = 6 points\r\n2, 2, 5, 6, 6 = 6 points\r\n4, 3, 6, 2, 6 = ? points\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7 points. You get one point per vowel.\n<|im_start|>answer\n7 points. You get one point per vowel.\n<|im_end|>" }, { "id": "#23797", "title": "British Pound Change Making", "fun": 2.17, "difficulty": 2.29, "author": "dutchymonster", "desc": "I have £10.\r\nWhat is the smallest combination of coins/notes required to make every possible combination between 1p - £10?", "hint": "In the UK we use;\r\n£50 note\r\n£20 note\r\n£10 note\r\n£5 note\r\n£2 coin\r\n£1 coin\r\n50p coin\r\n20p coin\r\n10p coin\r\n5p coin\r\n2p coin\r\n1p coin", "answer": "You would need;\r\n1 x £5\r\n1 x £2\r\n2 x £1\r\n1 x 50p\r\n1 x 20p\r\n2 x 10p\r\n1 x 5p\r\n2 x 2p\r\n1 x 1p\r\n___________\r\ntotal = £10", "category": "Math", "date": "06/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have £10.\r\nWhat is the smallest combination of coins/notes required to make every possible combination between 1p - £10?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou would need;\r\n1 x £5\r\n1 x £2\r\n2 x £1\r\n1 x 50p\r\n1 x 20p\r\n2 x 10p\r\n1 x 5p\r\n2 x 2p\r\n1 x 1p\r\n___________\r\ntotal = £10\n<|im_start|>answer\nYou would need;\r\n1 x £5\r\n1 x £2\r\n2 x £1\r\n1 x 50p\r\n1 x 20p\r\n2 x 10p\r\n1 x 5p\r\n2 x 2p\r\n1 x 1p\r\n___________\r\ntotal = £10\n<|im_end|>" }, { "id": "#1727", "title": "Relationships", "fun": 2.17, "difficulty": 0.93, "author": "Nishoo", "desc": "If the only sister of your mother's only brother has an only child, what is that child's relationship to you ?", "hint": "No hint available.", "answer": "That child is you, yourself.", "category": "Logic", "date": "12/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the only sister of your mother's only brother has an only child, what is that child's relationship to you ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThat child is you, yourself.\n<|im_start|>answer\nThat child is you, yourself.\n<|im_end|>" }, { "id": "#4946", "title": "Cow Boy", "fun": 2.17, "difficulty": 1.37, "author": "madman44", "desc": "If Cow Boy is 6 and Cow Man is 4 times older than Cow Boy, how old will Cow Man be when Cow Boy is 3 times older?", "hint": "No hint available.", "answer": "Cow Man will be 36 years old.\n\r\n6 x 4 = 24\r\n6 x 3 = 18\r\n18 - 6 = 12\r\n12 + 24 = 36", "category": "Math", "date": "06/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf Cow Boy is 6 and Cow Man is 4 times older than Cow Boy, how old will Cow Man be when Cow Boy is 3 times older?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCow Man will be 36 years old.\n\r\n6 x 4 = 24\r\n6 x 3 = 18\r\n18 - 6 = 12\r\n12 + 24 = 36\n<|im_start|>answer\nCow Man will be 36 years old.\n\r\n6 x 4 = 24\r\n6 x 3 = 18\r\n18 - 6 = 12\r\n12 + 24 = 36\n<|im_end|>" }, { "id": "#42251", "title": "Tall and Short of a Store", "fun": 2.17, "difficulty": 0.75, "author": "whsprec", "desc": "Four people, of varying heights, each bought a different item at a store. The customer's names were Rafael, Lennox, Pierre, and Frank. Their heights were 3'1\", 5'2\", 6'4\", and 7'3\". They bought either a toothbrush, a basketball, a bag of candy, or a golf tee. Match the customer to their height and the item they bought.\n\r\n1) The shortest person bought the golf tee.\r\n2) Rafael is neither the tallest nor shortest and he did not buy the candy.\r\n3) Lennox bought the toothbrush.\r\n4) Frank is 5'2\".", "hint": "No hint available.", "answer": "Rafael- 6'4\" basketball\r\nLennox- 7'3\" toothbrush\r\nPierre- 3'1\" golf tee\r\nFrank- 5'2\" bag of candy", "category": "Logic-Grid", "date": "06/15/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people, of varying heights, each bought a different item at a store. The customer's names were Rafael, Lennox, Pierre, and Frank. Their heights were 3'1\", 5'2\", 6'4\", and 7'3\". They bought either a toothbrush, a basketball, a bag of candy, or a golf tee. Match the customer to their height and the item they bought.\n\r\n1) The shortest person bought the golf tee.\r\n2) Rafael is neither the tallest nor shortest and he did not buy the candy.\r\n3) Lennox bought the toothbrush.\r\n4) Frank is 5'2\".\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRafael- 6'4\" basketball\r\nLennox- 7'3\" toothbrush\r\nPierre- 3'1\" golf tee\r\nFrank- 5'2\" bag of candy\n<|im_start|>answer\nRafael- 6'4\" basketball\r\nLennox- 7'3\" toothbrush\r\nPierre- 3'1\" golf tee\r\nFrank- 5'2\" bag of candy\n<|im_end|>" }, { "id": "#2131", "title": "The Cats", "fun": 2.17, "difficulty": 1.17, "author": "Joelfelix21", "desc": "In a normal square room there are 2 cats in each corner. Opposite each cat are 2 cats and next to each cat is 1 cat.\n\r\nHow many cats are there?", "hint": "No hint available.", "answer": "8 Cats", "category": "Math", "date": "01/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a normal square room there are 2 cats in each corner. Opposite each cat are 2 cats and next to each cat is 1 cat.\n\r\nHow many cats are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8 Cats\n<|im_start|>answer\n8 Cats\n<|im_end|>" }, { "id": "#37769", "title": "Baby on the Brain!!", "fun": 2.17, "difficulty": 1.06, "author": "fssef3", "desc": "There are three mothers. Each has a son. Each son is wearing a solid color shirt. Each son is eating a different baby food for lunch.\n\r\nThe first letter of each son's name is not the same as the first letter of the baby food they are eating.\n\r\nMothers' names: Rebecca, Amanda, Kelly\r\nSons' names: Carson, Adam, Brian\r\nBaby shirts: Blue, Red, Green\r\nBaby foods: Carrot, Apple, Bean\n\r\n1. Rebecca's son is wearing green.\r\n2. Amanda's son is eating apple baby food.\r\n3. The red shirt belongs to the son that is eating carrot baby food.\r\n4. Adam is eating the bean baby food.\r\n5. The first letter in Amanda is not the same as her baby's first initial.\r\n6. Kelly hates the smell of the bean baby food.", "hint": "No hint available.", "answer": "Rebecca-Adam-Green-Bean\r\nAmanda-Carson-Blue-Apple\r\nKelly-Brian-Red-Carrot", "category": "Logic-Grid", "date": "08/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three mothers. Each has a son. Each son is wearing a solid color shirt. Each son is eating a different baby food for lunch.\n\r\nThe first letter of each son's name is not the same as the first letter of the baby food they are eating.\n\r\nMothers' names: Rebecca, Amanda, Kelly\r\nSons' names: Carson, Adam, Brian\r\nBaby shirts: Blue, Red, Green\r\nBaby foods: Carrot, Apple, Bean\n\r\n1. Rebecca's son is wearing green.\r\n2. Amanda's son is eating apple baby food.\r\n3. The red shirt belongs to the son that is eating carrot baby food.\r\n4. Adam is eating the bean baby food.\r\n5. The first letter in Amanda is not the same as her baby's first initial.\r\n6. Kelly hates the smell of the bean baby food.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRebecca-Adam-Green-Bean\r\nAmanda-Carson-Blue-Apple\r\nKelly-Brian-Red-Carrot\n<|im_start|>answer\nRebecca-Adam-Green-Bean\r\nAmanda-Carson-Blue-Apple\r\nKelly-Brian-Red-Carrot\n<|im_end|>" }, { "id": "#9514", "title": "Four Digit Number", "fun": 2.17, "difficulty": 1.61, "author": "NuttieKiwis263", "desc": "What is the highest four-digit number, with no zeros, in which the first digit is one-quarter of the third digit, the second digit is three times the first digit, and the third and last digits are the same?", "hint": "No hint available.", "answer": "2688", "category": "Math", "date": "12/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the highest four-digit number, with no zeros, in which the first digit is one-quarter of the third digit, the second digit is three times the first digit, and the third and last digits are the same?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2688\n<|im_start|>answer\n2688\n<|im_end|>" }, { "id": "#9785", "title": "Jamming It Up", "fun": 2.17, "difficulty": 1.28, "author": "lesternoronha1", "desc": "Mary was making apricot jam. She put all the apricots in the pot and stirred them up. Then she remembered she had to add 1 ounce of lemon juice for every two apricots. How did she figure out how much lemon juice to put?", "hint": "No hint available.", "answer": "She counted the pits.", "category": "Logic", "date": "01/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMary was making apricot jam. She put all the apricots in the pot and stirred them up. Then she remembered she had to add 1 ounce of lemon juice for every two apricots. How did she figure out how much lemon juice to put?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe counted the pits.\n<|im_start|>answer\nShe counted the pits.\n<|im_end|>" }, { "id": "#17710", "title": "How Young?", "fun": 2.17, "difficulty": 2.57, "author": "jholman", "desc": "Mr. and Mrs. Silver have three daughters.\n\r\nWhen the youngest was born, you could multiply the middle child's age by three to get the oldest sister's age. \n\r\nNine years ago, you could add the middle child's age to the youngest child's age to get the oldest child's age.\n\r\nWhat is the youngest that the oldest child can be now?", "hint": "You can create two equations, where the three variables are:\r\n- the age of the middle child when the youngest child was born\r\n- the age of the oldest child when the youngest child was born\r\n- the age of the youngest child 9 years ago.", "answer": "The oldest child must presently be at least 14 years old.\n\r\nAges at youngest child's birth (youngest to oldest):\r\n0, y, z\n\r\nAges 9 years ago (or x years after the youngest child was born; youngest to oldest):\r\n0+x, y+x, z+x\n\r\nThere are two restrictions:\r\n(1) At the youngest child's birth we know that 3y=z\r\n(2) Nine years ago, the oldest child must be the sum of her two youngest sibling's ages, so x+x+y=x+z\n\r\nSimplifying the two equations, we get:\r\nz=3y\r\nx=2y\n\r\nFrom there, we input the lowest possible value of y, and calculate the oldest child's present age:\r\nz+x+9\r\n(3y)+(2y)+9\r\n3+2+9 = 14", "category": "Math", "date": "05/22/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. and Mrs. Silver have three daughters.\n\r\nWhen the youngest was born, you could multiply the middle child's age by three to get the oldest sister's age. \n\r\nNine years ago, you could add the middle child's age to the youngest child's age to get the oldest child's age.\n\r\nWhat is the youngest that the oldest child can be now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe oldest child must presently be at least 14 years old.\n\r\nAges at youngest child's birth (youngest to oldest):\r\n0, y, z\n\r\nAges 9 years ago (or x years after the youngest child was born; youngest to oldest):\r\n0+x, y+x, z+x\n\r\nThere are two restrictions:\r\n(1) At the youngest child's birth we know that 3y=z\r\n(2) Nine years ago, the oldest child must be the sum of her two youngest sibling's ages, so x+x+y=x+z\n\r\nSimplifying the two equations, we get:\r\nz=3y\r\nx=2y\n\r\nFrom there, we input the lowest possible value of y, and calculate the oldest child's present age:\r\nz+x+9\r\n(3y)+(2y)+9\r\n3+2+9 = 14\n<|im_start|>answer\nThe oldest child must presently be at least 14 years old.\n\r\nAges at youngest child's birth (youngest to oldest):\r\n0, y, z\n\r\nAges 9 years ago (or x years after the youngest child was born; youngest to oldest):\r\n0+x, y+x, z+x\n\r\nThere are two restrictions:\r\n(1) At the youngest child's birth we know that 3y=z\r\n(2) Nine years ago, the oldest child must be the sum of her two youngest sibling's ages, so x+x+y=x+z\n\r\nSimplifying the two equations, we get:\r\nz=3y\r\nx=2y\n\r\nFrom there, we input the lowest possible value of y, and calculate the oldest child's present age:\r\nz+x+9\r\n(3y)+(2y)+9\r\n3+2+9 = 14\n<|im_end|>" }, { "id": "#3656", "title": "Multiply 12345678987654321", "fun": 2.17, "difficulty": 1.62, "author": "sparkle", "desc": "What number can be multiplied against itself to give 12345678987654321?", "hint": "No hint available.", "answer": "111111111", "category": "Math", "date": "04/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number can be multiplied against itself to give 12345678987654321?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n111111111\n<|im_start|>answer\n111111111\n<|im_end|>" }, { "id": "#3913", "title": "Split the Fortune", "fun": 2.17, "difficulty": 1.62, "author": "mad-ade", "desc": "A rich man dies, leaving a £10,000,000 fortune, and a will with instructions on how to split it between his 5 sons, 4 daughters and his widow. The will states that each daughter should receive an equal amount, each son an amount double that of the daughters, and his widow three times the amount received by each son.\n\r\nHow much do they each inherit?", "hint": "No hint available.", "answer": "Daughters = £500,000 each = £2 million\r\nSons = £1,000,000 each = £5 million\r\nwidow = £3,000,000 = £3 million\r\n-----------\r\n£10 million", "category": "Math", "date": "05/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA rich man dies, leaving a £10,000,000 fortune, and a will with instructions on how to split it between his 5 sons, 4 daughters and his widow. The will states that each daughter should receive an equal amount, each son an amount double that of the daughters, and his widow three times the amount received by each son.\n\r\nHow much do they each inherit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDaughters = £500,000 each = £2 million\r\nSons = £1,000,000 each = £5 million\r\nwidow = £3,000,000 = £3 million\r\n-----------\r\n£10 million\n<|im_start|>answer\nDaughters = £500,000 each = £2 million\r\nSons = £1,000,000 each = £5 million\r\nwidow = £3,000,000 = £3 million\r\n-----------\r\n£10 million\n<|im_end|>" }, { "id": "#5058", "title": "Skateboarding", "fun": 2.17, "difficulty": 1.98, "author": "something", "desc": "When you repeat a trick, the point value of the trick decreases by ½. Kickflips are worth 360 points the first time you do them and melons are worth 20% more the first time you do them. Jason likes to skate. One day he got 1278 points doing only 5 melons and kickflips. How many of each trick did Jason do?", "hint": "No hint available.", "answer": "3 kickflips and 2 melons.\r\nKickflips are worth 360 points the first time you do them and melons are worth 20% more the first time you do them, so melons are worth 432 points. One of the ways to do this teaser is with guess and check. If you have three kickflips, each one ½ of the previous one, then you would have 360 points for the first one, 180 points for the second one, and 90 points for the third. If you add all these together, you would have 630 points for the kickflips. For the melons, the first one is 432 points and the second is 216 points. If you add them together you get 648 points. if you add 630 of the kickflips and 648 of the melons, you get 1278 points in all.", "category": "Math", "date": "06/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen you repeat a trick, the point value of the trick decreases by ½. Kickflips are worth 360 points the first time you do them and melons are worth 20% more the first time you do them. Jason likes to skate. One day he got 1278 points doing only 5 melons and kickflips. How many of each trick did Jason do?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3 kickflips and 2 melons.\r\nKickflips are worth 360 points the first time you do them and melons are worth 20% more the first time you do them, so melons are worth 432 points. One of the ways to do this teaser is with guess and check. If you have three kickflips, each one ½ of the previous one, then you would have 360 points for the first one, 180 points for the second one, and 90 points for the third. If you add all these together, you would have 630 points for the kickflips. For the melons, the first one is 432 points and the second is 216 points. If you add them together you get 648 points. if you add 630 of the kickflips and 648 of the melons, you get 1278 points in all.\n<|im_start|>answer\n3 kickflips and 2 melons.\r\nKickflips are worth 360 points the first time you do them and melons are worth 20% more the first time you do them, so melons are worth 432 points. One of the ways to do this teaser is with guess and check. If you have three kickflips, each one ½ of the previous one, then you would have 360 points for the first one, 180 points for the second one, and 90 points for the third. If you add all these together, you would have 630 points for the kickflips. For the melons, the first one is 432 points and the second is 216 points. If you add them together you get 648 points. if you add 630 of the kickflips and 648 of the melons, you get 1278 points in all.\n<|im_end|>" }, { "id": "#19112", "title": "Book Stacks", "fun": 2.17, "difficulty": 1.48, "author": "dumbell", "desc": "In the Bookulike bookshop, the assistants are preparing for a signing session by the internationally renowned economist Emma Chizzit, to launch her latest title 'Last of the Big Spenders.'\n\r\nCopies are piled up on a flat table in four equal stacks. From one side, only 9 spines in each stack are visible because they are piled up alternately: in other words, any book lying on top of another will have its spine facing in the exact opposite direction to that of the book below it.\n\r\nWhat is the least possible number of copies on the table?", "hint": "No hint available.", "answer": "68 books\n\r\nIf the bottom book on each stack has its spine showing, and the top one does too, that would give 17 books to a pile (s + showing, n = not: SNSNSNSNSNSNSNSNS). 17 x 4 = 68", "category": "Math", "date": "10/11/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the Bookulike bookshop, the assistants are preparing for a signing session by the internationally renowned economist Emma Chizzit, to launch her latest title 'Last of the Big Spenders.'\n\r\nCopies are piled up on a flat table in four equal stacks. From one side, only 9 spines in each stack are visible because they are piled up alternately: in other words, any book lying on top of another will have its spine facing in the exact opposite direction to that of the book below it.\n\r\nWhat is the least possible number of copies on the table?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n68 books\n\r\nIf the bottom book on each stack has its spine showing, and the top one does too, that would give 17 books to a pile (s + showing, n = not: SNSNSNSNSNSNSNSNS). 17 x 4 = 68\n<|im_start|>answer\n68 books\n\r\nIf the bottom book on each stack has its spine showing, and the top one does too, that would give 17 books to a pile (s + showing, n = not: SNSNSNSNSNSNSNSNS). 17 x 4 = 68\n<|im_end|>" }, { "id": "#1573", "title": "Sleepover", "fun": 2.17, "difficulty": 1.24, "author": "sam1234", "desc": "A friend slept over at my house last week. In the morning, I knocked on her door and asked her a question. She said yes, so I knew she was lying. What did I ask?", "hint": "No hint available.", "answer": "\"Are you asleep?\"", "category": "Logic", "date": "12/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA friend slept over at my house last week. In the morning, I knocked on her door and asked her a question. She said yes, so I knew she was lying. What did I ask?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n\"Are you asleep?\"\n<|im_start|>answer\n\"Are you asleep?\"\n<|im_end|>" }, { "id": "#32680", "title": "Teasergle V", "fun": 2.17, "difficulty": 1.45, "author": "phrebh", "desc": "Fred likes to spend time at his favorite brain teaser oriented site, Teasergle, playing his favorite game, Lunch Lobber. Currently, he has $2,550,000,000 in the bank in the game. He knows that he earns $44,000,000 every day he plays, and he spends $150,000,000 each week to increase his skill level in the game.\n\r\nCan you help him figure out how many weeks, to the nearest whole week, he's been playing?", "hint": "No hint available.", "answer": "16 weeks.\n\r\n2,550,000,000 = 44,000,000 x 7 x W - 150,000,000 x W\n\r\n2,550,000,000 = 308,000,000 x W - 150,000,000 x W\n\r\n2,550,000,000 = 158,000,000 x W\n\r\nW = 16.139", "category": "Math", "date": "08/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFred likes to spend time at his favorite brain teaser oriented site, Teasergle, playing his favorite game, Lunch Lobber. Currently, he has $2,550,000,000 in the bank in the game. He knows that he earns $44,000,000 every day he plays, and he spends $150,000,000 each week to increase his skill level in the game.\n\r\nCan you help him figure out how many weeks, to the nearest whole week, he's been playing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16 weeks.\n\r\n2,550,000,000 = 44,000,000 x 7 x W - 150,000,000 x W\n\r\n2,550,000,000 = 308,000,000 x W - 150,000,000 x W\n\r\n2,550,000,000 = 158,000,000 x W\n\r\nW = 16.139\n<|im_start|>answer\n16 weeks.\n\r\n2,550,000,000 = 44,000,000 x 7 x W - 150,000,000 x W\n\r\n2,550,000,000 = 308,000,000 x W - 150,000,000 x W\n\r\n2,550,000,000 = 158,000,000 x W\n\r\nW = 16.139\n<|im_end|>" }, { "id": "#49991", "title": "Open Up!", "fun": 2.17, "difficulty": 0.5700000000000001, "author": "fishmed", "desc": "It's 3 am, the doorbell rings and wakes you up. It's your parents and they are here for breakfast. You have strawberry jam, honey, wine, bread, and cheese . What is the 1st thing you open?", "hint": "No hint available.", "answer": "Your eyes. You were sleeping, remember?", "category": "Logic", "date": "11/03/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's 3 am, the doorbell rings and wakes you up. It's your parents and they are here for breakfast. You have strawberry jam, honey, wine, bread, and cheese . What is the 1st thing you open?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYour eyes. You were sleeping, remember?\n<|im_start|>answer\nYour eyes. You were sleeping, remember?\n<|im_end|>" }, { "id": "#19079", "title": "Losing Weight Drastically !", "fun": 2.17, "difficulty": 2.22, "author": "lesternoronha1", "desc": "An astronaut, who stays on the moon for 1 to 2 months, loses between 1 and 10 kg. If the stay is for 3 to 5 months, the loss of weight is between 11 and 20 kg. If the stay is for 6 to 12 months, the loss is between 21 and 30 kg. A group of astronauts who stayed on the moon and returned, lost 105 kg. If they stayed for exactly 122 days on the moon, what could be the range of the number of astronauts in the team?", "hint": "No hint available.", "answer": "The number of astronauts in the team must be from 6 to 9.\n\r\nIt is given that \r\n1) If the stay on the moon is for 1 to 2 months, the astronaut loses between 1 and 10 kg.\r\n2) If the stay on the moon is for 3 to 5 months, the astronaut loses between 11 and 20 kg.\r\n3) If the stay on the moon is for 6 to 12 months, the astronaut loses between 21 and 30 kg.\n\r\nThe astronauts stayed on the moon for 122 days, i.e. approximately 4 months. The total loss of weight is given to be 105 kg.\n\r\nIt is given that if the astronauts stay on the moon 3 to 5 months, each astronaut loses between 11 and 20 kg.\n\r\nAssuming that each astronaut lost the minimum possible weight in 4 months i.e., 11 kg, the maximum number of astronauts would be 9 (since 9*11 gives 99 which is less than 105. The maximum number cannot be 10 since even if they had lost the minimum weight, they would have lost 110 kg, which is more than the given 105 kg).\n\r\nIf they had lost the maximum possible weight i.e., 20 kg, then the minimum number of astronauts would be 6 (since 6*20 gives 120 which is greater than 105. The minimum number cannot be 5 since even if they had lost the maximum weight, they would have lost 100 kg which is less than the given 105 kg).\n\r\nHence the range of the astronauts that stayed on the moon must be between 6 and 9.", "category": "Math", "date": "10/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn astronaut, who stays on the moon for 1 to 2 months, loses between 1 and 10 kg. If the stay is for 3 to 5 months, the loss of weight is between 11 and 20 kg. If the stay is for 6 to 12 months, the loss is between 21 and 30 kg. A group of astronauts who stayed on the moon and returned, lost 105 kg. If they stayed for exactly 122 days on the moon, what could be the range of the number of astronauts in the team?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number of astronauts in the team must be from 6 to 9.\n\r\nIt is given that \r\n1) If the stay on the moon is for 1 to 2 months, the astronaut loses between 1 and 10 kg.\r\n2) If the stay on the moon is for 3 to 5 months, the astronaut loses between 11 and 20 kg.\r\n3) If the stay on the moon is for 6 to 12 months, the astronaut loses between 21 and 30 kg.\n\r\nThe astronauts stayed on the moon for 122 days, i.e. approximately 4 months. The total loss of weight is given to be 105 kg.\n\r\nIt is given that if the astronauts stay on the moon 3 to 5 months, each astronaut loses between 11 and 20 kg.\n\r\nAssuming that each astronaut lost the minimum possible weight in 4 months i.e., 11 kg, the maximum number of astronauts would be 9 (since 9*11 gives 99 which is less than 105. The maximum number cannot be 10 since even if they had lost the minimum weight, they would have lost 110 kg, which is more than the given 105 kg).\n\r\nIf they had lost the maximum possible weight i.e., 20 kg, then the minimum number of astronauts would be 6 (since 6*20 gives 120 which is greater than 105. The minimum number cannot be 5 since even if they had lost the maximum weight, they would have lost 100 kg which is less than the given 105 kg).\n\r\nHence the range of the astronauts that stayed on the moon must be between 6 and 9.\n<|im_start|>answer\nThe number of astronauts in the team must be from 6 to 9.\n\r\nIt is given that \r\n1) If the stay on the moon is for 1 to 2 months, the astronaut loses between 1 and 10 kg.\r\n2) If the stay on the moon is for 3 to 5 months, the astronaut loses between 11 and 20 kg.\r\n3) If the stay on the moon is for 6 to 12 months, the astronaut loses between 21 and 30 kg.\n\r\nThe astronauts stayed on the moon for 122 days, i.e. approximately 4 months. The total loss of weight is given to be 105 kg.\n\r\nIt is given that if the astronauts stay on the moon 3 to 5 months, each astronaut loses between 11 and 20 kg.\n\r\nAssuming that each astronaut lost the minimum possible weight in 4 months i.e., 11 kg, the maximum number of astronauts would be 9 (since 9*11 gives 99 which is less than 105. The maximum number cannot be 10 since even if they had lost the minimum weight, they would have lost 110 kg, which is more than the given 105 kg).\n\r\nIf they had lost the maximum possible weight i.e., 20 kg, then the minimum number of astronauts would be 6 (since 6*20 gives 120 which is greater than 105. The minimum number cannot be 5 since even if they had lost the maximum weight, they would have lost 100 kg which is less than the given 105 kg).\n\r\nHence the range of the astronauts that stayed on the moon must be between 6 and 9.\n<|im_end|>" }, { "id": "#4969", "title": "Give to Charity", "fun": 2.17, "difficulty": 1.19, "author": "cleverclogs", "desc": "If I give a third of my money to charity and a quarter of what's left to you, I am left with 45. How much did I originally have?", "hint": "No hint available.", "answer": "If you divide 45 by 3 you get 15 which is a quarter of what was left after I gave some to charity. Add these and you get 60, so 60 is how much I had after I gave some to you. 60 is 2/3 of my original amount. 60 divided by 2 = 30. Added to 60 = 90. So 90 is my original amount of money!", "category": "Math", "date": "06/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf I give a third of my money to charity and a quarter of what's left to you, I am left with 45. How much did I originally have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you divide 45 by 3 you get 15 which is a quarter of what was left after I gave some to charity. Add these and you get 60, so 60 is how much I had after I gave some to you. 60 is 2/3 of my original amount. 60 divided by 2 = 30. Added to 60 = 90. So 90 is my original amount of money!\n<|im_start|>answer\nIf you divide 45 by 3 you get 15 which is a quarter of what was left after I gave some to charity. Add these and you get 60, so 60 is how much I had after I gave some to you. 60 is 2/3 of my original amount. 60 divided by 2 = 30. Added to 60 = 90. So 90 is my original amount of money!\n<|im_end|>" }, { "id": "#8758", "title": "Four glasses", "fun": 2.16, "difficulty": 2.1, "author": "lesternoronha1", "desc": "Four glasses are placed in the four corners of a square rotating table, each glass is either up or down. You wish to turn them all in the same direction, either all up or all down. You may do so by grasping any two glasses and, optionally, turning either over. \n\r\nThere are two catches: \r\n1) You are blindfolded and \r\n2) the table is spun after each time you touch the glasses. \r\nAssuming that a bell rings when you have them all facing the same way, how do you do it?", "hint": "No hint available.", "answer": "1) Turn two adjacent glasses up. \r\n2) Turn two diagonal glasses up. \r\n3) Pull out two diagonal glasses. If one is down, turn it up and you're done. If not, turn one down and replace. \r\n4) Take two adjacent glasses. Invert them both. \r\n5) Take two diagonal glasses. Invert them both.", "category": "Logic", "date": "12/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour glasses are placed in the four corners of a square rotating table, each glass is either up or down. You wish to turn them all in the same direction, either all up or all down. You may do so by grasping any two glasses and, optionally, turning either over. \n\r\nThere are two catches: \r\n1) You are blindfolded and \r\n2) the table is spun after each time you touch the glasses. \r\nAssuming that a bell rings when you have them all facing the same way, how do you do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Turn two adjacent glasses up. \r\n2) Turn two diagonal glasses up. \r\n3) Pull out two diagonal glasses. If one is down, turn it up and you're done. If not, turn one down and replace. \r\n4) Take two adjacent glasses. Invert them both. \r\n5) Take two diagonal glasses. Invert them both.\n<|im_start|>answer\n1) Turn two adjacent glasses up. \r\n2) Turn two diagonal glasses up. \r\n3) Pull out two diagonal glasses. If one is down, turn it up and you're done. If not, turn one down and replace. \r\n4) Take two adjacent glasses. Invert them both. \r\n5) Take two diagonal glasses. Invert them both.\n<|im_end|>" }, { "id": "#3744", "title": "Swimming Pool", "fun": 2.16, "difficulty": 0.8300000000000001, "author": "Christopher", "desc": "There is a public swimming pool whose dimensions are 1,020 feet by 980 feet by 7 feet. This pool will hold 3,890 gallons of water. Someone goes into the swimming pool and goes all the way to the bottom of it. He/She comes back to the top of the pool not wet. There is no special equipment used to keep the person dry in any way or to dry the person in any way, other than the sun and wind of course.", "hint": "Is there a detail left out that most swimming pools would have?", "answer": "The pool was not filled with water.", "category": "Logic", "date": "04/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a public swimming pool whose dimensions are 1,020 feet by 980 feet by 7 feet. This pool will hold 3,890 gallons of water. Someone goes into the swimming pool and goes all the way to the bottom of it. He/She comes back to the top of the pool not wet. There is no special equipment used to keep the person dry in any way or to dry the person in any way, other than the sun and wind of course.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe pool was not filled with water.\n<|im_start|>answer\nThe pool was not filled with water.\n<|im_end|>" }, { "id": "#40499", "title": "Diagonals of a Dodecagon", "fun": 2.16, "difficulty": 2.08, "author": "shenqiang", "desc": "Jim and Tom play a game.\n\r\nA dodecagon (i.e., a 12-sided polygon) is drawn on a piece of paper. They take turns drawing diagonals, i.e., a line segment to connect two non-adjacent vertices. However, they are not allowed to draw a diagonal that intersects another diagonal already drawn.\n\r\nIf a player can't draw another diagonal, he loses and his opponent wins. Jim draws first and Tom draws second. What's the correct strategy for Jim to win?", "hint": "If you think that the correct strategy is for Jim to first draw a \"longest diagonal\", which divides the dodecagon into two halves, then mimic Tom's moves, you're tricked.", "answer": "If a player wins, then the dodecagon must have been divided into triangles, which requires EXACTLY NINE cuts.\n\r\nTherefore, Jim ALWAYS wins no matter what strategy he uses!", "category": "Logic", "date": "02/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJim and Tom play a game.\n\r\nA dodecagon (i.e., a 12-sided polygon) is drawn on a piece of paper. They take turns drawing diagonals, i.e., a line segment to connect two non-adjacent vertices. However, they are not allowed to draw a diagonal that intersects another diagonal already drawn.\n\r\nIf a player can't draw another diagonal, he loses and his opponent wins. Jim draws first and Tom draws second. What's the correct strategy for Jim to win?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf a player wins, then the dodecagon must have been divided into triangles, which requires EXACTLY NINE cuts.\n\r\nTherefore, Jim ALWAYS wins no matter what strategy he uses!\n<|im_start|>answer\nIf a player wins, then the dodecagon must have been divided into triangles, which requires EXACTLY NINE cuts.\n\r\nTherefore, Jim ALWAYS wins no matter what strategy he uses!\n<|im_end|>" }, { "id": "#44416", "title": "Mystery Number 4", "fun": 2.16, "difficulty": 2.7, "author": "cnmne", "desc": "There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\nNote: a leading zero (0) can be used in the following equations.\n\r\n1) CD * 3 = AJ\r\n2) GH * 2 = JA\r\n3) D * H = BE\r\n4) B * H = FI", "hint": "No hint available.", "answer": "8627350941\n\r\nA = 8, B = 6, C = 2, D = 7, E = 3, F = 5, G = 0, H = 9, I = 4, J = 1\n\r\n1) 27 * 3 = 81\r\n2) 09 * 2 = 18\r\n3) 7 * 9 = 63\r\n4) 6 * 9 = 54\n\r\nA) Calculate the possible equations for CD * 3 = AJ. Eliminate any equation whose product has two digits that are the same. Eliminate any equation whose product shares a common digit with the multiplicand.\r\n32 * 3 = 96\r\n29 * 3 = 87\r\n27 * 3 = 81\r\n26 * 3 = 78\r\n23 * 3 = 69\r\n21 * 3 = 63\r\n19 * 3 = 57\r\n18 * 3 = 54\r\n16 * 3 = 48\r\n12 * 3 = 36\r\n09 * 3 = 27\r\n08 * 3 = 24\r\n07 * 3 = 21\r\n06 * 3 = 18\r\n04 * 3 = 12\r\nB) Calculate the possible equations for GH * 2 = JA. Eliminate any equation whose product has two digits that are the same. Eliminate any equation whose product shares a common digit with the multiplicand.\r\n48 * 2 = 96\r\n47 * 2 = 94\r\n46 * 2 = 92\r\n45 * 2 = 90\r\n43 * 2 = 86\r\n41 * 2 = 82\r\n39 * 2 = 78\r\n38 * 2 = 76\r\n36 * 2 = 72\r\n35 * 2 = 70\r\n34 * 2 = 68\r\n32 * 2 = 64\r\n31 * 2 = 62\r\n29 * 2 = 58\r\n28 * 2 = 56\r\n27 * 2 = 54\r\n23 * 2 = 46\r\n19 * 2 = 38\r\n18 * 2 = 36\r\n17 * 2 = 34\r\n16 * 2 = 32\r\n15 * 2 = 30\r\n14 * 2 = 28\r\n13 * 2 = 26\r\n09 * 2 = 18\r\n08 * 2 = 16\r\n07 * 2 = 14\r\nC) Pair together any two equations whose products are reversed digits.\r\n29 * 3 = 87 and 39 * 2 = 78\r\n27 * 3 = 81 and 09 * 2 = 18\r\n23 * 3 = 69 and 48 * 2 = 96\r\n21 * 3 = 63 and 18 * 2 = 36\r\n09 * 3 = 27 and 36 * 2 = 72\r\n07 * 3 = 21 and 06 * 2 = 12\r\nD) Eliminate any pair of formulas where the multiplicands share at least one digit. For those remaining pairs, calculate D * H = BE.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63\r\n23 * 3 = 69 and 48 * 2 = 96 and\t3 * 8 = 24\r\n09 * 3 = 27 and 36 * 2 = 72 and\t9 * 6 = 54\r\nE) Eliminate any trio of formulas where the third product shares at least one digit with the first two multiplicands or products. For those remaining trios, calculate B * H = FI.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63 and 6 * 9 = 54\r\n09 * 3 = 27 and 36 * 2 = 72 and\t9 * 6 = 54 and 5 * 6 = 30\r\nF) Eliminate any set of formulas where the fourth product shares at least one digit with the first three multiplicands or products.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63 and 6 * 9 = 54", "category": "Logic", "date": "05/04/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\nNote: a leading zero (0) can be used in the following equations.\n\r\n1) CD * 3 = AJ\r\n2) GH * 2 = JA\r\n3) D * H = BE\r\n4) B * H = FI\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8627350941\n\r\nA = 8, B = 6, C = 2, D = 7, E = 3, F = 5, G = 0, H = 9, I = 4, J = 1\n\r\n1) 27 * 3 = 81\r\n2) 09 * 2 = 18\r\n3) 7 * 9 = 63\r\n4) 6 * 9 = 54\n\r\nA) Calculate the possible equations for CD * 3 = AJ. Eliminate any equation whose product has two digits that are the same. Eliminate any equation whose product shares a common digit with the multiplicand.\r\n32 * 3 = 96\r\n29 * 3 = 87\r\n27 * 3 = 81\r\n26 * 3 = 78\r\n23 * 3 = 69\r\n21 * 3 = 63\r\n19 * 3 = 57\r\n18 * 3 = 54\r\n16 * 3 = 48\r\n12 * 3 = 36\r\n09 * 3 = 27\r\n08 * 3 = 24\r\n07 * 3 = 21\r\n06 * 3 = 18\r\n04 * 3 = 12\r\nB) Calculate the possible equations for GH * 2 = JA. Eliminate any equation whose product has two digits that are the same. Eliminate any equation whose product shares a common digit with the multiplicand.\r\n48 * 2 = 96\r\n47 * 2 = 94\r\n46 * 2 = 92\r\n45 * 2 = 90\r\n43 * 2 = 86\r\n41 * 2 = 82\r\n39 * 2 = 78\r\n38 * 2 = 76\r\n36 * 2 = 72\r\n35 * 2 = 70\r\n34 * 2 = 68\r\n32 * 2 = 64\r\n31 * 2 = 62\r\n29 * 2 = 58\r\n28 * 2 = 56\r\n27 * 2 = 54\r\n23 * 2 = 46\r\n19 * 2 = 38\r\n18 * 2 = 36\r\n17 * 2 = 34\r\n16 * 2 = 32\r\n15 * 2 = 30\r\n14 * 2 = 28\r\n13 * 2 = 26\r\n09 * 2 = 18\r\n08 * 2 = 16\r\n07 * 2 = 14\r\nC) Pair together any two equations whose products are reversed digits.\r\n29 * 3 = 87 and 39 * 2 = 78\r\n27 * 3 = 81 and 09 * 2 = 18\r\n23 * 3 = 69 and 48 * 2 = 96\r\n21 * 3 = 63 and 18 * 2 = 36\r\n09 * 3 = 27 and 36 * 2 = 72\r\n07 * 3 = 21 and 06 * 2 = 12\r\nD) Eliminate any pair of formulas where the multiplicands share at least one digit. For those remaining pairs, calculate D * H = BE.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63\r\n23 * 3 = 69 and 48 * 2 = 96 and\t3 * 8 = 24\r\n09 * 3 = 27 and 36 * 2 = 72 and\t9 * 6 = 54\r\nE) Eliminate any trio of formulas where the third product shares at least one digit with the first two multiplicands or products. For those remaining trios, calculate B * H = FI.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63 and 6 * 9 = 54\r\n09 * 3 = 27 and 36 * 2 = 72 and\t9 * 6 = 54 and 5 * 6 = 30\r\nF) Eliminate any set of formulas where the fourth product shares at least one digit with the first three multiplicands or products.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63 and 6 * 9 = 54\n<|im_start|>answer\n8627350941\n\r\nA = 8, B = 6, C = 2, D = 7, E = 3, F = 5, G = 0, H = 9, I = 4, J = 1\n\r\n1) 27 * 3 = 81\r\n2) 09 * 2 = 18\r\n3) 7 * 9 = 63\r\n4) 6 * 9 = 54\n\r\nA) Calculate the possible equations for CD * 3 = AJ. Eliminate any equation whose product has two digits that are the same. Eliminate any equation whose product shares a common digit with the multiplicand.\r\n32 * 3 = 96\r\n29 * 3 = 87\r\n27 * 3 = 81\r\n26 * 3 = 78\r\n23 * 3 = 69\r\n21 * 3 = 63\r\n19 * 3 = 57\r\n18 * 3 = 54\r\n16 * 3 = 48\r\n12 * 3 = 36\r\n09 * 3 = 27\r\n08 * 3 = 24\r\n07 * 3 = 21\r\n06 * 3 = 18\r\n04 * 3 = 12\r\nB) Calculate the possible equations for GH * 2 = JA. Eliminate any equation whose product has two digits that are the same. Eliminate any equation whose product shares a common digit with the multiplicand.\r\n48 * 2 = 96\r\n47 * 2 = 94\r\n46 * 2 = 92\r\n45 * 2 = 90\r\n43 * 2 = 86\r\n41 * 2 = 82\r\n39 * 2 = 78\r\n38 * 2 = 76\r\n36 * 2 = 72\r\n35 * 2 = 70\r\n34 * 2 = 68\r\n32 * 2 = 64\r\n31 * 2 = 62\r\n29 * 2 = 58\r\n28 * 2 = 56\r\n27 * 2 = 54\r\n23 * 2 = 46\r\n19 * 2 = 38\r\n18 * 2 = 36\r\n17 * 2 = 34\r\n16 * 2 = 32\r\n15 * 2 = 30\r\n14 * 2 = 28\r\n13 * 2 = 26\r\n09 * 2 = 18\r\n08 * 2 = 16\r\n07 * 2 = 14\r\nC) Pair together any two equations whose products are reversed digits.\r\n29 * 3 = 87 and 39 * 2 = 78\r\n27 * 3 = 81 and 09 * 2 = 18\r\n23 * 3 = 69 and 48 * 2 = 96\r\n21 * 3 = 63 and 18 * 2 = 36\r\n09 * 3 = 27 and 36 * 2 = 72\r\n07 * 3 = 21 and 06 * 2 = 12\r\nD) Eliminate any pair of formulas where the multiplicands share at least one digit. For those remaining pairs, calculate D * H = BE.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63\r\n23 * 3 = 69 and 48 * 2 = 96 and\t3 * 8 = 24\r\n09 * 3 = 27 and 36 * 2 = 72 and\t9 * 6 = 54\r\nE) Eliminate any trio of formulas where the third product shares at least one digit with the first two multiplicands or products. For those remaining trios, calculate B * H = FI.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63 and 6 * 9 = 54\r\n09 * 3 = 27 and 36 * 2 = 72 and\t9 * 6 = 54 and 5 * 6 = 30\r\nF) Eliminate any set of formulas where the fourth product shares at least one digit with the first three multiplicands or products.\r\n27 * 3 = 81 and 09 * 2 = 18 and \t7 * 9 = 63 and 6 * 9 = 54\n<|im_end|>" }, { "id": "#18269", "title": "How Many are Left?", "fun": 2.16, "difficulty": 2.2, "author": "scoutman", "desc": "Anna has 4 guns with 5 loaded clips, Bobby has 3 guns with 5.5 loaded clips, and Chuck has 2 guns with 4.25 loaded clips. During a day of target shooting on Scoutman's range, Chuck shoots 3.5 clips, Anna shoots 3.25 clips, and Bobby shoots 3.75 clips. At the end of the day, how many guns still have loaded clips? \n\r\nAssume that each shooter shoots all bullets in a clip before starting to use the next one.", "hint": "Count the clips, not the bullets. A loaded clip has 1 or more bullets in it.", "answer": "Anna has 1.75 clips left, so she has 2 guns with loaded clips. Bobby also has 1.75 clips left, and thus has 2 guns with loaded clips. Chuck has 0.75 clips left, so he has 1 gun with a loaded clip. So the answer is 5 of the 9 guns still have loaded clips.", "category": "Math", "date": "07/19/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnna has 4 guns with 5 loaded clips, Bobby has 3 guns with 5.5 loaded clips, and Chuck has 2 guns with 4.25 loaded clips. During a day of target shooting on Scoutman's range, Chuck shoots 3.5 clips, Anna shoots 3.25 clips, and Bobby shoots 3.75 clips. At the end of the day, how many guns still have loaded clips? \n\r\nAssume that each shooter shoots all bullets in a clip before starting to use the next one.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnna has 1.75 clips left, so she has 2 guns with loaded clips. Bobby also has 1.75 clips left, and thus has 2 guns with loaded clips. Chuck has 0.75 clips left, so he has 1 gun with a loaded clip. So the answer is 5 of the 9 guns still have loaded clips.\n<|im_start|>answer\nAnna has 1.75 clips left, so she has 2 guns with loaded clips. Bobby also has 1.75 clips left, and thus has 2 guns with loaded clips. Chuck has 0.75 clips left, so he has 1 gun with a loaded clip. So the answer is 5 of the 9 guns still have loaded clips.\n<|im_end|>" }, { "id": "#14705", "title": "Squares and What?", "fun": 2.16, "difficulty": 2.67, "author": "egghead", "desc": "What to do these numbers have in common, besides being perfect squares? \n\r\n1) 25 \r\n2) 100 \r\n3) 169 \r\n4) 225", "hint": "25 = 16 + 9 \r\n100 = 36 + 64", "answer": "All of these are expressible in the form a*a=b*b+c*c: \n\r\n1) 25 = 4*4+3*3 \r\n2) 100 = 6*6+8*8 \r\n3) 169 = 12*12+5*5 \r\n4) 225 = 12*12+9*9", "category": "Math", "date": "09/08/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat to do these numbers have in common, besides being perfect squares? \n\r\n1) 25 \r\n2) 100 \r\n3) 169 \r\n4) 225\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll of these are expressible in the form a*a=b*b+c*c: \n\r\n1) 25 = 4*4+3*3 \r\n2) 100 = 6*6+8*8 \r\n3) 169 = 12*12+5*5 \r\n4) 225 = 12*12+9*9\n<|im_start|>answer\nAll of these are expressible in the form a*a=b*b+c*c: \n\r\n1) 25 = 4*4+3*3 \r\n2) 100 = 6*6+8*8 \r\n3) 169 = 12*12+5*5 \r\n4) 225 = 12*12+9*9\n<|im_end|>" }, { "id": "#16083", "title": "Sisters", "fun": 2.16, "difficulty": 1.36, "author": "curtiss82", "desc": "If only one of these statements is true, how many sisters have I got?\n\r\n1.) \"I've got ten or more sisters.\"\r\n2.) \"I've got less than ten sisters.\"\r\n3.) \"I've got at least one sister.\"", "hint": "No hint available.", "answer": "None. If statement 3 is true, then statement 1 can also be true, and vice versa. Statement 2 can be true by itself, but only if I have no sisters.", "category": "Logic", "date": "01/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf only one of these statements is true, how many sisters have I got?\n\r\n1.) \"I've got ten or more sisters.\"\r\n2.) \"I've got less than ten sisters.\"\r\n3.) \"I've got at least one sister.\"\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNone. If statement 3 is true, then statement 1 can also be true, and vice versa. Statement 2 can be true by itself, but only if I have no sisters.\n<|im_start|>answer\nNone. If statement 3 is true, then statement 1 can also be true, and vice versa. Statement 2 can be true by itself, but only if I have no sisters.\n<|im_end|>" }, { "id": "#22904", "title": "Stuck in a Locked Room", "fun": 2.16, "difficulty": 1.81, "author": "DennysGirl", "desc": "You are locked in a room. The only things in the room with you are a bed, a poster on the wall, and a dresser with lots of junk in it. The key for the door is in the lock on the other side of the door. How do you unlock the door?", "hint": "The door can be unlocked from both sides.", "answer": "First you take down the poster and slide it under the door. Then, you go into your dresser full of junk, find a paper clip and straighten it out. Wedge the key free with the paper clip. The key will fall onto the poster. You slide the poster back into the room, pick up the key and unlock the door!", "category": "Logic", "date": "05/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are locked in a room. The only things in the room with you are a bed, a poster on the wall, and a dresser with lots of junk in it. The key for the door is in the lock on the other side of the door. How do you unlock the door?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst you take down the poster and slide it under the door. Then, you go into your dresser full of junk, find a paper clip and straighten it out. Wedge the key free with the paper clip. The key will fall onto the poster. You slide the poster back into the room, pick up the key and unlock the door!\n<|im_start|>answer\nFirst you take down the poster and slide it under the door. Then, you go into your dresser full of junk, find a paper clip and straighten it out. Wedge the key free with the paper clip. The key will fall onto the poster. You slide the poster back into the room, pick up the key and unlock the door!\n<|im_end|>" }, { "id": "#2321", "title": "Range Mean Mode Median", "fun": 2.16, "difficulty": 2.09, "author": "jokester8000", "desc": "Find a set of 7 natural numbers with a range, mean, mode, and median of 7.", "hint": "No hint available.", "answer": "5 5 6 7 7 7 12", "category": "Math", "date": "02/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind a set of 7 natural numbers with a range, mean, mode, and median of 7.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 5 6 7 7 7 12\n<|im_start|>answer\n5 5 6 7 7 7 12\n<|im_end|>" }, { "id": "#2101", "title": "How Far is France", "fun": 2.16, "difficulty": 2.65, "author": "ChemicalBoy08", "desc": "My electronic world atlas has developed another fault, I did a listing of miles from England to particular countries and here is the result: \n\r\nAustralia - 500 miles\r\nPeru - 8,000 miles\r\nIndia - 4,500 miles\r\nScotland - 9,500 miles \n\r\nHow far away did it list France as?", "hint": "No hint available.", "answer": "3,000 miles.\r\nTake the alphabetic position of the first letter, take half and then multiply by 1000. F = 6, halved = 3, * 1000 = 3,000.", "category": "Math", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy electronic world atlas has developed another fault, I did a listing of miles from England to particular countries and here is the result: \n\r\nAustralia - 500 miles\r\nPeru - 8,000 miles\r\nIndia - 4,500 miles\r\nScotland - 9,500 miles \n\r\nHow far away did it list France as?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3,000 miles.\r\nTake the alphabetic position of the first letter, take half and then multiply by 1000. F = 6, halved = 3, * 1000 = 3,000.\n<|im_start|>answer\n3,000 miles.\r\nTake the alphabetic position of the first letter, take half and then multiply by 1000. F = 6, halved = 3, * 1000 = 3,000.\n<|im_end|>" }, { "id": "#15411", "title": "The Ice-cream Dollars", "fun": 2.16, "difficulty": 2.09, "author": "timmyboym", "desc": "In the small town of Ice-cremia, the only currency is ice-cream dollars. On the great lake, better known as Clear Lake, there are some golden fish. Each fish is worth 81 ice-cream dollars. At the Ice market, you can buy icy-cold drinks. The most popular drink is a can-o-coke. Each can-o-coke is worth 11 ice-cream dollars. After catching a golden fish and selling it, Timmyboym spends all his money on cans-o-coke, until he can't afford any more. When he has exactly 0 ice-cream dollars, how many cans-o-coke does he have? How many fish has he sold?", "hint": "No hint available.", "answer": "81. 81 x $11= 891, which can be divided equally into 81 (the price of a fish), to get eleven. He has 81 cans-o-coke, and has sold 11 fish.", "category": "Math", "date": "11/12/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the small town of Ice-cremia, the only currency is ice-cream dollars. On the great lake, better known as Clear Lake, there are some golden fish. Each fish is worth 81 ice-cream dollars. At the Ice market, you can buy icy-cold drinks. The most popular drink is a can-o-coke. Each can-o-coke is worth 11 ice-cream dollars. After catching a golden fish and selling it, Timmyboym spends all his money on cans-o-coke, until he can't afford any more. When he has exactly 0 ice-cream dollars, how many cans-o-coke does he have? How many fish has he sold?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n81. 81 x $11= 891, which can be divided equally into 81 (the price of a fish), to get eleven. He has 81 cans-o-coke, and has sold 11 fish.\n<|im_start|>answer\n81. 81 x $11= 891, which can be divided equally into 81 (the price of a fish), to get eleven. He has 81 cans-o-coke, and has sold 11 fish.\n<|im_end|>" }, { "id": "#11615", "title": "Highest Value", "fun": 2.16, "difficulty": 2.07, "author": "beckywebster", "desc": "Using the digits 1 to 9 only once each, create three 3 digit numbers. Your goal is to create three numbers which, when multiplied together, give the highest value.", "hint": "No hint available.", "answer": "763 x 852 x 941 = 611721516", "category": "Math", "date": "04/07/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the digits 1 to 9 only once each, create three 3 digit numbers. Your goal is to create three numbers which, when multiplied together, give the highest value.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n763 x 852 x 941 = 611721516\n<|im_start|>answer\n763 x 852 x 941 = 611721516\n<|im_end|>" }, { "id": "#40168", "title": "Zach's Birthday Party", "fun": 2.16, "difficulty": 1.54, "author": "icestar12", "desc": "At Zach's birthday party, Zach is seated along with 7 guests at a rectangular table. Zach knows Gabe and Brooks from Cub Scouts, Christopher is his cousin, and Emily, Ian, Julie, and Lafern are from Zach's class. Zach is sitting at the head of the table, with the girls all sitting on one side, to Zach's right. His cousin is sitting at the opposite end of the table between Julie and Ian. Brooks is in the middle, opposite Emily.\n\r\nWhere is everyone sitting at the party?", "hint": "No hint available.", "answer": "Starting with Christopher at the head of the table and moving clockwise around the table, the seating plan is as follows: Christopher, Julie, Emily, Lafern, Zach (opposite Christopher), Gabe, Brooks, and Ian.", "category": "Logic", "date": "01/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt Zach's birthday party, Zach is seated along with 7 guests at a rectangular table. Zach knows Gabe and Brooks from Cub Scouts, Christopher is his cousin, and Emily, Ian, Julie, and Lafern are from Zach's class. Zach is sitting at the head of the table, with the girls all sitting on one side, to Zach's right. His cousin is sitting at the opposite end of the table between Julie and Ian. Brooks is in the middle, opposite Emily.\n\r\nWhere is everyone sitting at the party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStarting with Christopher at the head of the table and moving clockwise around the table, the seating plan is as follows: Christopher, Julie, Emily, Lafern, Zach (opposite Christopher), Gabe, Brooks, and Ian.\n<|im_start|>answer\nStarting with Christopher at the head of the table and moving clockwise around the table, the seating plan is as follows: Christopher, Julie, Emily, Lafern, Zach (opposite Christopher), Gabe, Brooks, and Ian.\n<|im_end|>" }, { "id": "#28470", "title": "Threes and Sevens 2", "fun": 2.16, "difficulty": 2.84, "author": "shenqiang", "desc": "Which is the smallest natural number that satisfies the following conditions:\n\r\n(1) Its digits consist of, and only of 3's and 7's.\r\n(2) Its digital sum is divisible by 3 and 7.\r\n(3) The number itself is divisible by 3 and 7.", "hint": "It's not very hard.", "answer": "From conditions 1 and 2, we know that we need at least 3 7's and 7 3's.\n\r\nTheir sum is divisible by 3, therefore any number they make is divisible by 3.\n\r\nBy trial and error, we see that none of 3333333777, 3333337377, 3333337737, 3333337773, 3333373377, 3333373737, 3333373773, 3333377337 and 3333377373 is divisible by 7.\n\r\n3333377733 is divisible by 7 (the quotient is 476196819.)\n\r\nTherefore, the number we're looking for is 3333377733.", "category": "Math", "date": "02/06/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is the smallest natural number that satisfies the following conditions:\n\r\n(1) Its digits consist of, and only of 3's and 7's.\r\n(2) Its digital sum is divisible by 3 and 7.\r\n(3) The number itself is divisible by 3 and 7.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFrom conditions 1 and 2, we know that we need at least 3 7's and 7 3's.\n\r\nTheir sum is divisible by 3, therefore any number they make is divisible by 3.\n\r\nBy trial and error, we see that none of 3333333777, 3333337377, 3333337737, 3333337773, 3333373377, 3333373737, 3333373773, 3333377337 and 3333377373 is divisible by 7.\n\r\n3333377733 is divisible by 7 (the quotient is 476196819.)\n\r\nTherefore, the number we're looking for is 3333377733.\n<|im_start|>answer\nFrom conditions 1 and 2, we know that we need at least 3 7's and 7 3's.\n\r\nTheir sum is divisible by 3, therefore any number they make is divisible by 3.\n\r\nBy trial and error, we see that none of 3333333777, 3333337377, 3333337737, 3333337773, 3333373377, 3333373737, 3333373773, 3333377337 and 3333377373 is divisible by 7.\n\r\n3333377733 is divisible by 7 (the quotient is 476196819.)\n\r\nTherefore, the number we're looking for is 3333377733.\n<|im_end|>" }, { "id": "#16443", "title": "Impossible Triangle?", "fun": 2.16, "difficulty": 1.07, "author": "Mogmatt16", "desc": "For a right triangle, a^2+b^2=c^2. \r\n'c' is always the hypotenuse (longest side) while 'a' and 'b' are called the legs. \r\nKnowing this, can a triangle be made from sides of 11, 14, and 20?", "hint": "That's not right...", "answer": "Yes; however it will not be a right triangle.", "category": "Math", "date": "02/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor a right triangle, a^2+b^2=c^2. \r\n'c' is always the hypotenuse (longest side) while 'a' and 'b' are called the legs. \r\nKnowing this, can a triangle be made from sides of 11, 14, and 20?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes; however it will not be a right triangle.\n<|im_start|>answer\nYes; however it will not be a right triangle.\n<|im_end|>" }, { "id": "#33797", "title": "The Gigantic Bird", "fun": 2.16, "difficulty": 1.7, "author": "aish_28", "desc": "The three rowed their boat towards the ship. Even before they were half-way there, a gigantic bird swooped down on them and plucked them up. They were carried to a distant land where they were deposited in a nest high in a tree.\n\r\nFrom the statements that follow, what was the wing span of the gigantic bird and how far did it carry the three sailors?\n\r\n1. If the wingspan of the gigantic bird was either 20 or 30 metres wide, it carried the three sailors for 50 leagues.\r\n2. If the gigantic bird carried the three shipmates 75 leagues, its wingspan was not 40 or 50 metres wide.\r\n3. If the wingspan of the gigantic bird was 40 or 50 metres wide, it carried the three sailors 75 leagues.\r\n4. If the gigantic bird's wingspan was not 40 or 50 metres wide, then it was 20 or 30 metres wide.", "hint": "No hint available.", "answer": "The bird's wingspan was 20 or 30 metres wide; it carried the shipmates 50 leagues.", "category": "Logic", "date": "11/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe three rowed their boat towards the ship. Even before they were half-way there, a gigantic bird swooped down on them and plucked them up. They were carried to a distant land where they were deposited in a nest high in a tree.\n\r\nFrom the statements that follow, what was the wing span of the gigantic bird and how far did it carry the three sailors?\n\r\n1. If the wingspan of the gigantic bird was either 20 or 30 metres wide, it carried the three sailors for 50 leagues.\r\n2. If the gigantic bird carried the three shipmates 75 leagues, its wingspan was not 40 or 50 metres wide.\r\n3. If the wingspan of the gigantic bird was 40 or 50 metres wide, it carried the three sailors 75 leagues.\r\n4. If the gigantic bird's wingspan was not 40 or 50 metres wide, then it was 20 or 30 metres wide.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe bird's wingspan was 20 or 30 metres wide; it carried the shipmates 50 leagues.\n<|im_start|>answer\nThe bird's wingspan was 20 or 30 metres wide; it carried the shipmates 50 leagues.\n<|im_end|>" }, { "id": "#37711", "title": "The Medical Test", "fun": 2.16, "difficulty": 2.3, "author": "leftclick", "desc": "A medical test is being administered to people to screen for a particular disease. What percentage of the people who test positive would actually have the disease, if the disease is present in 1 person in 1000 and the test gives a positive result for 5% of people who do not actually have the disease?", "hint": "No hint available.", "answer": "1 person in 51, or around 1.96% of those who test positive, would actually have the disease.\n\r\nThe disease is present in 0.1% of cases, and the test gives a false positive 5% of the time, for a total of 5.1% positive results. Of these, only 0.1% actually have the disease, for a ratio of 0.1% / 5.1% = 1/51 or approximately 1.960784%", "category": "Math", "date": "08/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA medical test is being administered to people to screen for a particular disease. What percentage of the people who test positive would actually have the disease, if the disease is present in 1 person in 1000 and the test gives a positive result for 5% of people who do not actually have the disease?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 person in 51, or around 1.96% of those who test positive, would actually have the disease.\n\r\nThe disease is present in 0.1% of cases, and the test gives a false positive 5% of the time, for a total of 5.1% positive results. Of these, only 0.1% actually have the disease, for a ratio of 0.1% / 5.1% = 1/51 or approximately 1.960784%\n<|im_start|>answer\n1 person in 51, or around 1.96% of those who test positive, would actually have the disease.\n\r\nThe disease is present in 0.1% of cases, and the test gives a false positive 5% of the time, for a total of 5.1% positive results. Of these, only 0.1% actually have the disease, for a ratio of 0.1% / 5.1% = 1/51 or approximately 1.960784%\n<|im_end|>" }, { "id": "#14773", "title": "Lies 2", "fun": 2.16, "difficulty": 1.25, "author": "odcsurferchick", "desc": "A man walks up to you and says - \"everything I say to you is a lie.\"\r\nIs he telling you the truth or is he lying?", "hint": "No hint available.", "answer": "He's lying. Even though he's lying when he says \"everything\" he says is a lie, some of the things he says can be a lie, and this is one of them.", "category": "Logic", "date": "09/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man walks up to you and says - \"everything I say to you is a lie.\"\r\nIs he telling you the truth or is he lying?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe's lying. Even though he's lying when he says \"everything\" he says is a lie, some of the things he says can be a lie, and this is one of them.\n<|im_start|>answer\nHe's lying. Even though he's lying when he says \"everything\" he says is a lie, some of the things he says can be a lie, and this is one of them.\n<|im_end|>" }, { "id": "#18961", "title": "Romankachi Stationery!", "fun": 2.16, "difficulty": 2.2, "author": "lesternoronha1", "desc": "One of my very close friends, Raimo the shrewd has opened a new stationery store called \"The Romankachi Bookstore\" in honor of my grandfather Rudolf the world-famous Romankachi who had helped him a lot financially in recent times. Among other stationery items, pencils, erasers and sharpeners were available at this shop.\n\r\nRaimo told me that he could make profits in pencils, erasers and sharpeners only by adhering to the following:\r\n1) A pencil, an eraser and a sharpener together to cost 7k (k being Kachin, the local Romankachi currency).\r\n2) The cost of a sharpener would be more than that of 3 erasers.\r\n3) No two items among pencils, erasers and sharpeners would be sold at the same cost.\n\r\nIf all the costs are integers, can you look through Raimo's shrewdness and find out the cost of each of the stationery items mentioned above?", "hint": "No hint available.", "answer": "It has been mentioned that all the costs are integers and no two items cost the same.\n\r\nAlso\r\n1) A pencil, an eraser and a sharpener together to cost 7k.\r\n2) The cost of a sharpener would be more than that of 3 erasers.\n\r\nNow, let the cost of a pencil, an eraser and a sharpener be X, Y and Z respectively.\r\nThen X+Y+Z = 7 from condition 1 above.\r\nAlso Z > 3Y from condition 2 above.\n\r\nLet the cost of each eraser Y=1, the smallest possible integer.\r\nThen Z > 3 (from condition 2).\n\r\nLet us consider the different values that Z can take:\n\r\nLet Z=4.\r\nThen X = 7-Y-Z (from equation X+Y+Z = 7).\r\nThen X = 7-1-4 = 2\r\nHence X = 2, Y = 1 and Z = 4.\n\r\nLet Z=5.\r\nThen X+Y = 2 (from equation X+Y+Z = 7).\r\nHence X = Y = 1.\r\nThis cannot be possible since it has been mentioned that no two items cost the same.\n\r\nFor any higher values of Z, we do not get integer values for X and Y.\n\r\nHence each pencil, eraser and sharpener must cost 2k, 1k and 4k respectively.", "category": "Math", "date": "09/27/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne of my very close friends, Raimo the shrewd has opened a new stationery store called \"The Romankachi Bookstore\" in honor of my grandfather Rudolf the world-famous Romankachi who had helped him a lot financially in recent times. Among other stationery items, pencils, erasers and sharpeners were available at this shop.\n\r\nRaimo told me that he could make profits in pencils, erasers and sharpeners only by adhering to the following:\r\n1) A pencil, an eraser and a sharpener together to cost 7k (k being Kachin, the local Romankachi currency).\r\n2) The cost of a sharpener would be more than that of 3 erasers.\r\n3) No two items among pencils, erasers and sharpeners would be sold at the same cost.\n\r\nIf all the costs are integers, can you look through Raimo's shrewdness and find out the cost of each of the stationery items mentioned above?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt has been mentioned that all the costs are integers and no two items cost the same.\n\r\nAlso\r\n1) A pencil, an eraser and a sharpener together to cost 7k.\r\n2) The cost of a sharpener would be more than that of 3 erasers.\n\r\nNow, let the cost of a pencil, an eraser and a sharpener be X, Y and Z respectively.\r\nThen X+Y+Z = 7 from condition 1 above.\r\nAlso Z > 3Y from condition 2 above.\n\r\nLet the cost of each eraser Y=1, the smallest possible integer.\r\nThen Z > 3 (from condition 2).\n\r\nLet us consider the different values that Z can take:\n\r\nLet Z=4.\r\nThen X = 7-Y-Z (from equation X+Y+Z = 7).\r\nThen X = 7-1-4 = 2\r\nHence X = 2, Y = 1 and Z = 4.\n\r\nLet Z=5.\r\nThen X+Y = 2 (from equation X+Y+Z = 7).\r\nHence X = Y = 1.\r\nThis cannot be possible since it has been mentioned that no two items cost the same.\n\r\nFor any higher values of Z, we do not get integer values for X and Y.\n\r\nHence each pencil, eraser and sharpener must cost 2k, 1k and 4k respectively.\n<|im_start|>answer\nIt has been mentioned that all the costs are integers and no two items cost the same.\n\r\nAlso\r\n1) A pencil, an eraser and a sharpener together to cost 7k.\r\n2) The cost of a sharpener would be more than that of 3 erasers.\n\r\nNow, let the cost of a pencil, an eraser and a sharpener be X, Y and Z respectively.\r\nThen X+Y+Z = 7 from condition 1 above.\r\nAlso Z > 3Y from condition 2 above.\n\r\nLet the cost of each eraser Y=1, the smallest possible integer.\r\nThen Z > 3 (from condition 2).\n\r\nLet us consider the different values that Z can take:\n\r\nLet Z=4.\r\nThen X = 7-Y-Z (from equation X+Y+Z = 7).\r\nThen X = 7-1-4 = 2\r\nHence X = 2, Y = 1 and Z = 4.\n\r\nLet Z=5.\r\nThen X+Y = 2 (from equation X+Y+Z = 7).\r\nHence X = Y = 1.\r\nThis cannot be possible since it has been mentioned that no two items cost the same.\n\r\nFor any higher values of Z, we do not get integer values for X and Y.\n\r\nHence each pencil, eraser and sharpener must cost 2k, 1k and 4k respectively.\n<|im_end|>" }, { "id": "#1056", "title": "97% Caffeine Free", "fun": 2.16, "difficulty": 1.53, "author": "Michelle", "desc": "If you were given a can of cola that was 97% caffeine free, how many cans of it would you have to drink in order to consume the same amount of caffeine found in a regular cola?", "hint": "No hint available.", "answer": "33 1/3 cans. If there is 3% caffeine found in the cola, it would take 100 divided by 3 to equal the same amount.", "category": "Math", "date": "10/08/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you were given a can of cola that was 97% caffeine free, how many cans of it would you have to drink in order to consume the same amount of caffeine found in a regular cola?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n33 1/3 cans. If there is 3% caffeine found in the cola, it would take 100 divided by 3 to equal the same amount.\n<|im_start|>answer\n33 1/3 cans. If there is 3% caffeine found in the cola, it would take 100 divided by 3 to equal the same amount.\n<|im_end|>" }, { "id": "#6343", "title": "What is Where?", "fun": 2.16, "difficulty": 1.57, "author": "mad-ade", "desc": "A B C D E F G H\n\n\r\nWhat letter is three to the right of the letter that is immediately to the left of the letter that is two to the right of the letter that is three to the left of the letter F ?", "hint": "No hint available.", "answer": "The letter G", "category": "Logic", "date": "08/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA B C D E F G H\n\n\r\nWhat letter is three to the right of the letter that is immediately to the left of the letter that is two to the right of the letter that is three to the left of the letter F ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe letter G\n<|im_start|>answer\nThe letter G\n<|im_end|>" }, { "id": "#9690", "title": "Math Signs", "fun": 2.16, "difficulty": 2.19, "author": "julia", "desc": "Insert the correct mathematical signs to make the following calculations work: \n\r\n 7 8 20 32 = 44\n\r\n 9 3 42 12 = 94.5\n\r\n 8 2 12 9 = 57\n\r\n6 7 15 13 = 44 \n\r\n5 32 6 20 = 18.75", "hint": "No hint available.", "answer": "You could have come up with something different, but this is my answer:\n\r\n7 x 8 + 20 - 32 = 44\n\r\n9 x 3 x 42 / 12 = 94.5\n\r\n8 / 2 x 12 + 9 = 57\n\r\n6 x 7 + 15 - 13 = 44\n\r\n5 / 32 x 6 x 20 = 18.75", "category": "Math", "date": "01/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nInsert the correct mathematical signs to make the following calculations work: \n\r\n 7 8 20 32 = 44\n\r\n 9 3 42 12 = 94.5\n\r\n 8 2 12 9 = 57\n\r\n6 7 15 13 = 44 \n\r\n5 32 6 20 = 18.75\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou could have come up with something different, but this is my answer:\n\r\n7 x 8 + 20 - 32 = 44\n\r\n9 x 3 x 42 / 12 = 94.5\n\r\n8 / 2 x 12 + 9 = 57\n\r\n6 x 7 + 15 - 13 = 44\n\r\n5 / 32 x 6 x 20 = 18.75\n<|im_start|>answer\nYou could have come up with something different, but this is my answer:\n\r\n7 x 8 + 20 - 32 = 44\n\r\n9 x 3 x 42 / 12 = 94.5\n\r\n8 / 2 x 12 + 9 = 57\n\r\n6 x 7 + 15 - 13 = 44\n\r\n5 / 32 x 6 x 20 = 18.75\n<|im_end|>" }, { "id": "#22559", "title": "Dinner Party Fractions", "fun": 2.16, "difficulty": 1.8800000000000001, "author": "RaunchyTacos", "desc": "At the party, the host decided to serve his dishes in this pattern... For every 2 guests, he would serve one plate of meat. For every 3 guests, he would serve one plate of rice. And for every 4 guests he would serve one plate of sauce. At the end of the party, a servant told the host that they had served a total of 65 dishes. If 65 dishes were served, than how many guests were at the party?", "hint": "No hint available.", "answer": "There was a total of 60 guests. I came upon this answer because 1/2 of 60 + 1/3 of 60 + 1/4 of 60 = 65. 30(# of meat dishes) + 20(# of rice dishes) + 15(# of sauce dishes) = 60 total guests", "category": "Math", "date": "04/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the party, the host decided to serve his dishes in this pattern... For every 2 guests, he would serve one plate of meat. For every 3 guests, he would serve one plate of rice. And for every 4 guests he would serve one plate of sauce. At the end of the party, a servant told the host that they had served a total of 65 dishes. If 65 dishes were served, than how many guests were at the party?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere was a total of 60 guests. I came upon this answer because 1/2 of 60 + 1/3 of 60 + 1/4 of 60 = 65. 30(# of meat dishes) + 20(# of rice dishes) + 15(# of sauce dishes) = 60 total guests\n<|im_start|>answer\nThere was a total of 60 guests. I came upon this answer because 1/2 of 60 + 1/3 of 60 + 1/4 of 60 = 65. 30(# of meat dishes) + 20(# of rice dishes) + 15(# of sauce dishes) = 60 total guests\n<|im_end|>" }, { "id": "#3690", "title": "Wash Cloths and Cleaner", "fun": 2.16, "difficulty": 2.14, "author": "cathalmccabe", "desc": "A shopkeeper has two products, a wash cloth and a cleaning product.\r\nThe wash cloth sells at £0.32, and the cleaner at £0.74.\r\nHowever, people buy lots of the wash cloths, but little of the cleaner. He wants to get rid of the cleaner by selling off all the remaining stock by bundling wash cloths with it.\r\nHe wants to keep the same profit margins as he would have originally.\r\nIf the average price for each item is £0.40, what is the smallest possible bundle, and what does it cost?", "hint": "No hint available.", "answer": "He bundles 17 wash cloths with 4 cleaners for £8.40.\n\r\nLet x = quantity of wash cloths\r\nLet y = quantity of cleaners\n\r\n(0.32x + 0.74y) / (x + y) = 0.40\r\n0.32x + 0.74y = 0.40x + 0.40y\r\n0.34y = 0.08x\r\n0.17y = 0.04x\n\r\nThe smallest integers are: x = 17 wash clothes, y = 4 cleaners. The total cost is: 0.32(17) + 0.74(4) = 8.40. The average cost is 8.40 divided by 21 items, or 0.40.", "category": "Math", "date": "04/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA shopkeeper has two products, a wash cloth and a cleaning product.\r\nThe wash cloth sells at £0.32, and the cleaner at £0.74.\r\nHowever, people buy lots of the wash cloths, but little of the cleaner. He wants to get rid of the cleaner by selling off all the remaining stock by bundling wash cloths with it.\r\nHe wants to keep the same profit margins as he would have originally.\r\nIf the average price for each item is £0.40, what is the smallest possible bundle, and what does it cost?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe bundles 17 wash cloths with 4 cleaners for £8.40.\n\r\nLet x = quantity of wash cloths\r\nLet y = quantity of cleaners\n\r\n(0.32x + 0.74y) / (x + y) = 0.40\r\n0.32x + 0.74y = 0.40x + 0.40y\r\n0.34y = 0.08x\r\n0.17y = 0.04x\n\r\nThe smallest integers are: x = 17 wash clothes, y = 4 cleaners. The total cost is: 0.32(17) + 0.74(4) = 8.40. The average cost is 8.40 divided by 21 items, or 0.40.\n<|im_start|>answer\nHe bundles 17 wash cloths with 4 cleaners for £8.40.\n\r\nLet x = quantity of wash cloths\r\nLet y = quantity of cleaners\n\r\n(0.32x + 0.74y) / (x + y) = 0.40\r\n0.32x + 0.74y = 0.40x + 0.40y\r\n0.34y = 0.08x\r\n0.17y = 0.04x\n\r\nThe smallest integers are: x = 17 wash clothes, y = 4 cleaners. The total cost is: 0.32(17) + 0.74(4) = 8.40. The average cost is 8.40 divided by 21 items, or 0.40.\n<|im_end|>" }, { "id": "#35513", "title": "Form Into a Shape", "fun": 2.16, "difficulty": 1.0, "author": "nascarfan19", "desc": "A man is sitting on a bench. He sees another man walking by and says, \"Would you like to win some money?\" He tells him that with 4 small sticks, all the same size, he has to form them into a rectangle. The man forms them into a square and wins the money. How does he win the money?", "hint": "No hint available.", "answer": "A square is a type of rectangle, but not all rectangles are squares.", "category": "Math", "date": "03/03/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is sitting on a bench. He sees another man walking by and says, \"Would you like to win some money?\" He tells him that with 4 small sticks, all the same size, he has to form them into a rectangle. The man forms them into a square and wins the money. How does he win the money?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA square is a type of rectangle, but not all rectangles are squares.\n<|im_start|>answer\nA square is a type of rectangle, but not all rectangles are squares.\n<|im_end|>" }, { "id": "#5909", "title": "Last Time we Met", "fun": 2.16, "difficulty": 2.72, "author": "Bintot", "desc": "Said Alf to Bert, \"The last time we met, our ages were both prime numbers, and when I was a quarter of the age I am now, you were that age plus half the age your father would have been thirty years previous to when he was six times the age you would have been when I was half your age\". Said Bert to Alf \"I'm off down the pub\". How old were Alf and Bert the last time they met?", "hint": "No hint available.", "answer": "Alf and Bert were 2 and 5 years old respectively the last time they met. If A and B are Alf and Bert's present ages and a and b are their ages when Alf was half Bert's age then\n\r\nB - 3A/4 = (A/4) + (6b - 30)/2\n\r\nSince their ages have always had the same difference we have\n\r\nB - A = 3b - 15 = b - a\n\r\nand since 2a = b then a = 3 and b = 6. So their ages differ by 3. Since all primes except 2 are odd and differ by an even number we can only have 2 and 5, Bert being the older of the two. The father plays no part in the problem!", "category": "Math", "date": "07/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSaid Alf to Bert, \"The last time we met, our ages were both prime numbers, and when I was a quarter of the age I am now, you were that age plus half the age your father would have been thirty years previous to when he was six times the age you would have been when I was half your age\". Said Bert to Alf \"I'm off down the pub\". How old were Alf and Bert the last time they met?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlf and Bert were 2 and 5 years old respectively the last time they met. If A and B are Alf and Bert's present ages and a and b are their ages when Alf was half Bert's age then\n\r\nB - 3A/4 = (A/4) + (6b - 30)/2\n\r\nSince their ages have always had the same difference we have\n\r\nB - A = 3b - 15 = b - a\n\r\nand since 2a = b then a = 3 and b = 6. So their ages differ by 3. Since all primes except 2 are odd and differ by an even number we can only have 2 and 5, Bert being the older of the two. The father plays no part in the problem!\n<|im_start|>answer\nAlf and Bert were 2 and 5 years old respectively the last time they met. If A and B are Alf and Bert's present ages and a and b are their ages when Alf was half Bert's age then\n\r\nB - 3A/4 = (A/4) + (6b - 30)/2\n\r\nSince their ages have always had the same difference we have\n\r\nB - A = 3b - 15 = b - a\n\r\nand since 2a = b then a = 3 and b = 6. So their ages differ by 3. Since all primes except 2 are odd and differ by an even number we can only have 2 and 5, Bert being the older of the two. The father plays no part in the problem!\n<|im_end|>" }, { "id": "#24837", "title": "Driving Away", "fun": 2.15, "difficulty": 1.44, "author": "dreaminggemini", "desc": "Four friends (Sarah, Max, Jen, and Maison) are going to see a movie together that starts at 12:30pm. They each have different last names and drive different types of cars. Can you figure out which last name and vehicle belongs to each person, and what time they left for the movie?\n\r\nFirst names: Sarah, Max, Jen, Maison\r\nLast names: Sadler, Pack, Melkus, Baron\r\nCars: Mustang, Camaro, Jeep, Van\r\nTime left: 11:00, 11:15, 11:30, 12:00\n\r\n1) Sarah married a man named John Sadler. She was not the first to leave her house.\n\r\n2) Max (who did not leave first) does not drive a Mustang.\n\r\n3) Maison Baron left his house 30 minutes after Jen (who does not own a Mustang).\n\r\n4) The person who left second owns a Van.\n\r\n5) The woman with the last name Pack drives a Camaro.\n\r\n6) The person who left last (who is not Mr. Melkus) owns a Jeep.", "hint": "No hint available.", "answer": "First name/Last name/Car/Time\n\r\nJen Pack/Camaro/11:00\r\nMax Melkus/Van/11:15\r\nMaison Baron/Mustang/11:30\r\nSarah Sadler/Jeep/12:00", "category": "Logic-Grid", "date": "07/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends (Sarah, Max, Jen, and Maison) are going to see a movie together that starts at 12:30pm. They each have different last names and drive different types of cars. Can you figure out which last name and vehicle belongs to each person, and what time they left for the movie?\n\r\nFirst names: Sarah, Max, Jen, Maison\r\nLast names: Sadler, Pack, Melkus, Baron\r\nCars: Mustang, Camaro, Jeep, Van\r\nTime left: 11:00, 11:15, 11:30, 12:00\n\r\n1) Sarah married a man named John Sadler. She was not the first to leave her house.\n\r\n2) Max (who did not leave first) does not drive a Mustang.\n\r\n3) Maison Baron left his house 30 minutes after Jen (who does not own a Mustang).\n\r\n4) The person who left second owns a Van.\n\r\n5) The woman with the last name Pack drives a Camaro.\n\r\n6) The person who left last (who is not Mr. Melkus) owns a Jeep.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst name/Last name/Car/Time\n\r\nJen Pack/Camaro/11:00\r\nMax Melkus/Van/11:15\r\nMaison Baron/Mustang/11:30\r\nSarah Sadler/Jeep/12:00\n<|im_start|>answer\nFirst name/Last name/Car/Time\n\r\nJen Pack/Camaro/11:00\r\nMax Melkus/Van/11:15\r\nMaison Baron/Mustang/11:30\r\nSarah Sadler/Jeep/12:00\n<|im_end|>" }, { "id": "#18663", "title": "The Missing Wonk", "fun": 2.15, "difficulty": 2.23, "author": "Mad-Ade", "desc": "Two women, SHEEZA PHOOL and SHIRLEY KNOTT, were selling Kebananas (a cross between a Kebab and a Banana, full of greasy goodness) in the Madadian open market. SHEEZA PHOOL was selling 3 Kebananas for a Wonk (Madadian currency/ 100 Winks= 1 Wonk) and SHIRLEY KNOTT was selling 2 Kebananas for a Wonk. \n\r\nOne day each of them had 30 Kebananas unsold. They put together the two lots of Kebananas and decided to sell 5 Kebananas for Ws. 2. According to their calculation, 3 Kebananas for Ws. 1 and 2 Kebananas for Ws. 1 was exactly the same as 5 Kebananas for Ws. 2 \n\r\nNow, they were expecting to get Ws. 25 for the Kebananas, as they would have got, if sold separately. But to their surprise they got only Ws. 24 for the entire lot of the 60 Kebananas. \n\r\nWhere did the one Wonk go?", "hint": "No hint available.", "answer": "SHEEZA PHOOL was selling 3 Kebananas for a Wonk. Hence, the average price of one Kebanana is (1/3) = Ws. 0.3333 \n\r\nSHIRLEY KNOTT was selling 2 Kebananas for a Wonk. Hence, the average price of one Kebanana is (1/2) = Ws. 0.5 \n\r\nNow they put together 60 Kebananas. Hence, the average price of one Kebanana is (0.3333+0.5)/2 = Ws. 0.4167 \n\r\nBut, they were selling 5 Kebananas for Ws. 2. Hence, the average price of one Kebanana is 2/5 = Ws. 0.4 \n\r\nThe difference is (0.4167 - 0.4) = 0.0167 \r\nThere are 60 Kebananas. Hence (0.0167 * 60) = 1 \n\r\nSo here is that one Wonk. Thus, one Wonk didn't go anywhere, they did their math wrong.", "category": "Math", "date": "09/01/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo women, SHEEZA PHOOL and SHIRLEY KNOTT, were selling Kebananas (a cross between a Kebab and a Banana, full of greasy goodness) in the Madadian open market. SHEEZA PHOOL was selling 3 Kebananas for a Wonk (Madadian currency/ 100 Winks= 1 Wonk) and SHIRLEY KNOTT was selling 2 Kebananas for a Wonk. \n\r\nOne day each of them had 30 Kebananas unsold. They put together the two lots of Kebananas and decided to sell 5 Kebananas for Ws. 2. According to their calculation, 3 Kebananas for Ws. 1 and 2 Kebananas for Ws. 1 was exactly the same as 5 Kebananas for Ws. 2 \n\r\nNow, they were expecting to get Ws. 25 for the Kebananas, as they would have got, if sold separately. But to their surprise they got only Ws. 24 for the entire lot of the 60 Kebananas. \n\r\nWhere did the one Wonk go?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSHEEZA PHOOL was selling 3 Kebananas for a Wonk. Hence, the average price of one Kebanana is (1/3) = Ws. 0.3333 \n\r\nSHIRLEY KNOTT was selling 2 Kebananas for a Wonk. Hence, the average price of one Kebanana is (1/2) = Ws. 0.5 \n\r\nNow they put together 60 Kebananas. Hence, the average price of one Kebanana is (0.3333+0.5)/2 = Ws. 0.4167 \n\r\nBut, they were selling 5 Kebananas for Ws. 2. Hence, the average price of one Kebanana is 2/5 = Ws. 0.4 \n\r\nThe difference is (0.4167 - 0.4) = 0.0167 \r\nThere are 60 Kebananas. Hence (0.0167 * 60) = 1 \n\r\nSo here is that one Wonk. Thus, one Wonk didn't go anywhere, they did their math wrong.\n<|im_start|>answer\nSHEEZA PHOOL was selling 3 Kebananas for a Wonk. Hence, the average price of one Kebanana is (1/3) = Ws. 0.3333 \n\r\nSHIRLEY KNOTT was selling 2 Kebananas for a Wonk. Hence, the average price of one Kebanana is (1/2) = Ws. 0.5 \n\r\nNow they put together 60 Kebananas. Hence, the average price of one Kebanana is (0.3333+0.5)/2 = Ws. 0.4167 \n\r\nBut, they were selling 5 Kebananas for Ws. 2. Hence, the average price of one Kebanana is 2/5 = Ws. 0.4 \n\r\nThe difference is (0.4167 - 0.4) = 0.0167 \r\nThere are 60 Kebananas. Hence (0.0167 * 60) = 1 \n\r\nSo here is that one Wonk. Thus, one Wonk didn't go anywhere, they did their math wrong.\n<|im_end|>" }, { "id": "#15917", "title": "Mad Ade's Bus Journey", "fun": 2.15, "difficulty": 1.83, "author": "mad-ade", "desc": "Mad Ade goes to work, testing Kebabs at the local \"Sweaty Chef Kebab shop\", by bus. One day he falls asleep when the bus still has twice as far to go as it has already gone. \n\r\nHalfway through the trip he wakes up as the bus bounces over some bad potholes. When he finally falls asleep again, the bus still has half the distance to go that it has already traveled. Fortunately, Mad Ade wakes up at the end of his trip. \n\r\nWhat portion of the total trip did Mad Ade sleep?", "hint": "No hint available.", "answer": "Mad Ade is asleep for a total of 1/2 of the trip. \n\r\nYou can divide the trip into 6 equal parts. \n\r\nMad Ade falls asleep 2/6 (1/3) of the way through the trip. He awakes at 3/6 of the way through the trip. So far, he has slept 1/6 of the way. \n\r\nHe falls asleep again at 4/6 (or 2/3) of the way through the trip and sleeps until he gets off. He therefore sleeps 2/6 more.\n\r\n1/6 plus 2/6 equals 3/6 or 1/2. \n\r\nIf you wanted to use numbers as an example. Say the trip is 90 miles long. \r\n90 X 2/6= 30 He has twice as far to travel as he already has so at this point he would still have to travel 60 miles. \n\r\n1/2 way through the trip is 90 X 3/6=45. \n\r\nSo far he has slept for 15 miles. \n\r\nHe falls asleep again when he still has half the distance left that he already has traveled. 90 X 4/6 =60 miles (traveled so far). Half of 60 is 30 miles. So he has 30 miles left to travel and he is asleep during this time. 30 + 15=45 which is half of 90.", "category": "Math", "date": "12/22/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade goes to work, testing Kebabs at the local \"Sweaty Chef Kebab shop\", by bus. One day he falls asleep when the bus still has twice as far to go as it has already gone. \n\r\nHalfway through the trip he wakes up as the bus bounces over some bad potholes. When he finally falls asleep again, the bus still has half the distance to go that it has already traveled. Fortunately, Mad Ade wakes up at the end of his trip. \n\r\nWhat portion of the total trip did Mad Ade sleep?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMad Ade is asleep for a total of 1/2 of the trip. \n\r\nYou can divide the trip into 6 equal parts. \n\r\nMad Ade falls asleep 2/6 (1/3) of the way through the trip. He awakes at 3/6 of the way through the trip. So far, he has slept 1/6 of the way. \n\r\nHe falls asleep again at 4/6 (or 2/3) of the way through the trip and sleeps until he gets off. He therefore sleeps 2/6 more.\n\r\n1/6 plus 2/6 equals 3/6 or 1/2. \n\r\nIf you wanted to use numbers as an example. Say the trip is 90 miles long. \r\n90 X 2/6= 30 He has twice as far to travel as he already has so at this point he would still have to travel 60 miles. \n\r\n1/2 way through the trip is 90 X 3/6=45. \n\r\nSo far he has slept for 15 miles. \n\r\nHe falls asleep again when he still has half the distance left that he already has traveled. 90 X 4/6 =60 miles (traveled so far). Half of 60 is 30 miles. So he has 30 miles left to travel and he is asleep during this time. 30 + 15=45 which is half of 90.\n<|im_start|>answer\nMad Ade is asleep for a total of 1/2 of the trip. \n\r\nYou can divide the trip into 6 equal parts. \n\r\nMad Ade falls asleep 2/6 (1/3) of the way through the trip. He awakes at 3/6 of the way through the trip. So far, he has slept 1/6 of the way. \n\r\nHe falls asleep again at 4/6 (or 2/3) of the way through the trip and sleeps until he gets off. He therefore sleeps 2/6 more.\n\r\n1/6 plus 2/6 equals 3/6 or 1/2. \n\r\nIf you wanted to use numbers as an example. Say the trip is 90 miles long. \r\n90 X 2/6= 30 He has twice as far to travel as he already has so at this point he would still have to travel 60 miles. \n\r\n1/2 way through the trip is 90 X 3/6=45. \n\r\nSo far he has slept for 15 miles. \n\r\nHe falls asleep again when he still has half the distance left that he already has traveled. 90 X 4/6 =60 miles (traveled so far). Half of 60 is 30 miles. So he has 30 miles left to travel and he is asleep during this time. 30 + 15=45 which is half of 90.\n<|im_end|>" }, { "id": "#13915", "title": "Which Shape?", "fun": 2.15, "difficulty": 1.31, "author": "jacintan", "desc": "Which two-dimensional shape has an infinite number of lines of symmetry?", "hint": "No hint available.", "answer": "A circle. No matter what direction you make a slice through the center, the two halves will be symmetric.", "category": "Math", "date": "07/20/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich two-dimensional shape has an infinite number of lines of symmetry?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA circle. No matter what direction you make a slice through the center, the two halves will be symmetric.\n<|im_start|>answer\nA circle. No matter what direction you make a slice through the center, the two halves will be symmetric.\n<|im_end|>" }, { "id": "#38569", "title": "You're Going Where!?", "fun": 2.15, "difficulty": 0.59, "author": "Panther91", "desc": "It's the middle of January in Green Bay, Wisconsin. Jake is all packed up and ready to go for his vacation. \"So Jake,\" his friend Sara asks, \"Where are you going for your vacation?\" \"To the beach in Australia,\" Jake replies. Sara responds, \"But it's January and you're gonna go to a beach of all places?\" \"Don't worry Sara,\" Jake says, \"In Australia, it is perfectly normal to do so.\" Why is that?", "hint": "Think in reverse.", "answer": "In places located in the Southern Hemisphere, the seasons are in reverse from the Northern Hemisphere. So it would be summer instead of winter in Australia during January.", "category": "Logic", "date": "10/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt's the middle of January in Green Bay, Wisconsin. Jake is all packed up and ready to go for his vacation. \"So Jake,\" his friend Sara asks, \"Where are you going for your vacation?\" \"To the beach in Australia,\" Jake replies. Sara responds, \"But it's January and you're gonna go to a beach of all places?\" \"Don't worry Sara,\" Jake says, \"In Australia, it is perfectly normal to do so.\" Why is that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIn places located in the Southern Hemisphere, the seasons are in reverse from the Northern Hemisphere. So it would be summer instead of winter in Australia during January.\n<|im_start|>answer\nIn places located in the Southern Hemisphere, the seasons are in reverse from the Northern Hemisphere. So it would be summer instead of winter in Australia during January.\n<|im_end|>" }, { "id": "#5267", "title": "St. George's Cross", "fun": 2.15, "difficulty": 2.06, "author": "mad-ade", "desc": "The drawing is of the flag of St. George.\r\nIt consists of a red cross on a white background.\r\nBoth arms of the red cross are the same width.\r\nThe flag measures 60 cm by 91 cm.\r\nIf the area of the red arms is equal to the area of white,\r\nwhat should be the width of the red arms?", "hint": "No hint available.", "answer": "21 cm wide", "category": "Math", "date": "07/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe drawing is of the flag of St. George.\r\nIt consists of a red cross on a white background.\r\nBoth arms of the red cross are the same width.\r\nThe flag measures 60 cm by 91 cm.\r\nIf the area of the red arms is equal to the area of white,\r\nwhat should be the width of the red arms?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n21 cm wide\n<|im_start|>answer\n21 cm wide\n<|im_end|>" }, { "id": "#21957", "title": "Gamble'n", "fun": 2.15, "difficulty": 2.87, "author": "Blademaster", "desc": "You have $6.20 and are in a casino with a certain game with a 50-50 chance exactly of winning. In 5 bets, what are your chances of winning $.20?\n\r\n(P.S. Forget weighted value and losing all your money!)", "hint": "No hint available.", "answer": "Your chances of winning are 96.875%.\r\nThis is possible by on your first bet, bet 20 cents. If you lose, bet 40 so you make up for the 20 you lost and get 20 more. Then go to 80, slowly doubling you inputs until you reach $3.20. You then have a 3.125% chance of losing.\r\nThis is basically 50% * 50% * 50% * 50% * 50% = 3.125% chance of losing.\n\r\nDon't do this in a real casino, because with weighted-value, in the one situation you lose, you lose all your money!", "category": "Math", "date": "04/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have $6.20 and are in a casino with a certain game with a 50-50 chance exactly of winning. In 5 bets, what are your chances of winning $.20?\n\r\n(P.S. Forget weighted value and losing all your money!)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYour chances of winning are 96.875%.\r\nThis is possible by on your first bet, bet 20 cents. If you lose, bet 40 so you make up for the 20 you lost and get 20 more. Then go to 80, slowly doubling you inputs until you reach $3.20. You then have a 3.125% chance of losing.\r\nThis is basically 50% * 50% * 50% * 50% * 50% = 3.125% chance of losing.\n\r\nDon't do this in a real casino, because with weighted-value, in the one situation you lose, you lose all your money!\n<|im_start|>answer\nYour chances of winning are 96.875%.\r\nThis is possible by on your first bet, bet 20 cents. If you lose, bet 40 so you make up for the 20 you lost and get 20 more. Then go to 80, slowly doubling you inputs until you reach $3.20. You then have a 3.125% chance of losing.\r\nThis is basically 50% * 50% * 50% * 50% * 50% = 3.125% chance of losing.\n\r\nDon't do this in a real casino, because with weighted-value, in the one situation you lose, you lose all your money!\n<|im_end|>" }, { "id": "#19274", "title": "Student Averages ...", "fun": 2.15, "difficulty": 2.86, "author": "lesternoronha1", "desc": "The average marks of girls in a class is equal to the number of boys and the average marks of boys in a class is equal to the number of girls. If the class average is 4 less than the average of the boys' average marks and the girls' average marks, find the minimum double digit number of students in the class.", "hint": "No hint available.", "answer": "The minimum double digit strength of the class is 18.\n\r\nLet the number of girls in the class be X and the number of boys in the class be Y.\r\nThen the average marks of the girls and boys is Y and X respectively.\n\r\nClass average \r\n= (Total marks/Total number of students) \r\n= (Total marks scored by girls and boys/Total number of students in the class)\r\n= ((Y*X + X*Y)/(Y+X))\r\n= ((2*X*Y)/(X+Y))\n\r\nThe average of the boys' average and the girls' average \r\n= (X+Y)/2\n\r\nIt is given that the class average is 4 less than the average of the boys' average marks and the girls' average marks.\n\r\nHence \r\n(X+Y)/2 - ((2*X*Y)/(X+Y)) = 4\n\r\nMultiplying the above equation throughout by 2*(X+Y), we get\r\n(X+Y)^2 - 4*X*Y = 8*(X+Y)\r\nX^2 + Y^2 + 2*X*Y - 4*X*Y = 8*(X+Y)\r\nX^2 + Y^2 - 2*X*Y = 8*(X+Y)\r\n(X-Y)^2 = 8*(X+Y)\n\r\nIn order for the Right Hand Side in the above equation to be a perfect square, the value of (X+Y) should be of the type 2k^2 i.e. 2, 8, 18, 32, 50, 72 etc.\n\r\nIt is given that the minimum double digit strength of the class has to be found.\n\r\nTherefore the minimum double digit strength of the class = X+Y = 18.", "category": "Math", "date": "10/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe average marks of girls in a class is equal to the number of boys and the average marks of boys in a class is equal to the number of girls. If the class average is 4 less than the average of the boys' average marks and the girls' average marks, find the minimum double digit number of students in the class.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe minimum double digit strength of the class is 18.\n\r\nLet the number of girls in the class be X and the number of boys in the class be Y.\r\nThen the average marks of the girls and boys is Y and X respectively.\n\r\nClass average \r\n= (Total marks/Total number of students) \r\n= (Total marks scored by girls and boys/Total number of students in the class)\r\n= ((Y*X + X*Y)/(Y+X))\r\n= ((2*X*Y)/(X+Y))\n\r\nThe average of the boys' average and the girls' average \r\n= (X+Y)/2\n\r\nIt is given that the class average is 4 less than the average of the boys' average marks and the girls' average marks.\n\r\nHence \r\n(X+Y)/2 - ((2*X*Y)/(X+Y)) = 4\n\r\nMultiplying the above equation throughout by 2*(X+Y), we get\r\n(X+Y)^2 - 4*X*Y = 8*(X+Y)\r\nX^2 + Y^2 + 2*X*Y - 4*X*Y = 8*(X+Y)\r\nX^2 + Y^2 - 2*X*Y = 8*(X+Y)\r\n(X-Y)^2 = 8*(X+Y)\n\r\nIn order for the Right Hand Side in the above equation to be a perfect square, the value of (X+Y) should be of the type 2k^2 i.e. 2, 8, 18, 32, 50, 72 etc.\n\r\nIt is given that the minimum double digit strength of the class has to be found.\n\r\nTherefore the minimum double digit strength of the class = X+Y = 18.\n<|im_start|>answer\nThe minimum double digit strength of the class is 18.\n\r\nLet the number of girls in the class be X and the number of boys in the class be Y.\r\nThen the average marks of the girls and boys is Y and X respectively.\n\r\nClass average \r\n= (Total marks/Total number of students) \r\n= (Total marks scored by girls and boys/Total number of students in the class)\r\n= ((Y*X + X*Y)/(Y+X))\r\n= ((2*X*Y)/(X+Y))\n\r\nThe average of the boys' average and the girls' average \r\n= (X+Y)/2\n\r\nIt is given that the class average is 4 less than the average of the boys' average marks and the girls' average marks.\n\r\nHence \r\n(X+Y)/2 - ((2*X*Y)/(X+Y)) = 4\n\r\nMultiplying the above equation throughout by 2*(X+Y), we get\r\n(X+Y)^2 - 4*X*Y = 8*(X+Y)\r\nX^2 + Y^2 + 2*X*Y - 4*X*Y = 8*(X+Y)\r\nX^2 + Y^2 - 2*X*Y = 8*(X+Y)\r\n(X-Y)^2 = 8*(X+Y)\n\r\nIn order for the Right Hand Side in the above equation to be a perfect square, the value of (X+Y) should be of the type 2k^2 i.e. 2, 8, 18, 32, 50, 72 etc.\n\r\nIt is given that the minimum double digit strength of the class has to be found.\n\r\nTherefore the minimum double digit strength of the class = X+Y = 18.\n<|im_end|>" }, { "id": "#571", "title": "Birthday Jellybeans", "fun": 2.15, "difficulty": 1.34, "author": "Squidgy", "desc": "Molly's big sister was trying to get a share of her birthday jellybeans. Katy said, \"Put some in my pockets; one in the first, two in the second, four in the third, and so on, doubling the number in each pocket. I have three pockets in my jeans and three in my jacket.\" How many was Katy expecting?", "hint": "No hint available.", "answer": "63 jelly beans", "category": "Math", "date": "06/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMolly's big sister was trying to get a share of her birthday jellybeans. Katy said, \"Put some in my pockets; one in the first, two in the second, four in the third, and so on, doubling the number in each pocket. I have three pockets in my jeans and three in my jacket.\" How many was Katy expecting?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n63 jelly beans\n<|im_start|>answer\n63 jelly beans\n<|im_end|>" }, { "id": "#43981", "title": "What Six Digit Number Am I?", "fun": 2.15, "difficulty": 1.4, "author": "Lord_Hawk", "desc": "I am a six digit number. My digits add up to 31, and all of my digits are distinct, and between 1 to 9 inclusive. All of my digits except one are odd. My second is 6 greater than my third, which is 5 less than my fifth. My last is 1 less than the previous digit, and the fourth is greater than the third. My first is equal to the sum of my fourth and fifth.", "hint": "The second and third numbers have to be 7 & 1.", "answer": "The second and third numbers have to be 7 & 1. The alternative 9 & 3 wouldn't work because that would make the fifth number 8 when the only even number is 6. The rest falls easily into place.\n\r\nSo I am 971365.", "category": "Math", "date": "01/22/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI am a six digit number. My digits add up to 31, and all of my digits are distinct, and between 1 to 9 inclusive. All of my digits except one are odd. My second is 6 greater than my third, which is 5 less than my fifth. My last is 1 less than the previous digit, and the fourth is greater than the third. My first is equal to the sum of my fourth and fifth.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe second and third numbers have to be 7 & 1. The alternative 9 & 3 wouldn't work because that would make the fifth number 8 when the only even number is 6. The rest falls easily into place.\n\r\nSo I am 971365.\n<|im_start|>answer\nThe second and third numbers have to be 7 & 1. The alternative 9 & 3 wouldn't work because that would make the fifth number 8 when the only even number is 6. The rest falls easily into place.\n\r\nSo I am 971365.\n<|im_end|>" }, { "id": "#42421", "title": "Marco's Mice", "fun": 2.15, "difficulty": 1.8, "author": "letmeforget6", "desc": "Marco's Uncle Oscar gave him a pair of piebald mice for his birthday. Marco named one mouse Whiskers and the other one Oscar after his favorite uncle. Now Marco has to buy supplies for his mice. He wants to buy a cage, an exercise wheel, a water bottle, one bag of wood shavings, and 12 ounces of Mouse Chow.\n\r\nAt the Fin 'n' Fur pet store, he found a nice big cage for $29.90, a water bottle for $4.50, an exercise wheel for $6.00, bags of wood shavings priced at 3 for $13.95, and 12 ounces of Mouse Chow at $0.56 an ounce. Luckily, the cage, water bottle, and exercise wheel are on sale at 10% off.\n\r\nThe store also has a Pet Starter Kit that includes a cage with a built-in wheel, a water bottle, a bag of wood shavings, and 12 ounces of Mouse Chow, all for $44.95. A 5% sales tax applies to all non-food items, including the complete Pet Starter Kit. The tax is applied after a sale price is determined.\n\r\nWhich collection of supplies is the better deal: purchasing each item separately or purchasing the Pet Starter Kit?", "hint": "1. Keep in mind how much of each item Marco wants to buy. \r\n2. Remember to calculate the 10% discount for items on sale.", "answer": "The Pet Starter Kit is the better deal.\n\r\nThe total cost of the Pet Starter Kit after the 5% sales tax is applied is $47.20.\n\r\nThe sum of the cost of the individual items is $47.73, before the tax is applied. Since the Mouse Chow is a food item, the total amount to be taxed is only $41.01. After applying the 5% sales tax and adding the cost of the Mouse Chow, the total cost of the individual items is $49.78.\n\r\nMarco will save $2.58 by buying the Pet Starter Kit.", "category": "Math", "date": "07/05/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMarco's Uncle Oscar gave him a pair of piebald mice for his birthday. Marco named one mouse Whiskers and the other one Oscar after his favorite uncle. Now Marco has to buy supplies for his mice. He wants to buy a cage, an exercise wheel, a water bottle, one bag of wood shavings, and 12 ounces of Mouse Chow.\n\r\nAt the Fin 'n' Fur pet store, he found a nice big cage for $29.90, a water bottle for $4.50, an exercise wheel for $6.00, bags of wood shavings priced at 3 for $13.95, and 12 ounces of Mouse Chow at $0.56 an ounce. Luckily, the cage, water bottle, and exercise wheel are on sale at 10% off.\n\r\nThe store also has a Pet Starter Kit that includes a cage with a built-in wheel, a water bottle, a bag of wood shavings, and 12 ounces of Mouse Chow, all for $44.95. A 5% sales tax applies to all non-food items, including the complete Pet Starter Kit. The tax is applied after a sale price is determined.\n\r\nWhich collection of supplies is the better deal: purchasing each item separately or purchasing the Pet Starter Kit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Pet Starter Kit is the better deal.\n\r\nThe total cost of the Pet Starter Kit after the 5% sales tax is applied is $47.20.\n\r\nThe sum of the cost of the individual items is $47.73, before the tax is applied. Since the Mouse Chow is a food item, the total amount to be taxed is only $41.01. After applying the 5% sales tax and adding the cost of the Mouse Chow, the total cost of the individual items is $49.78.\n\r\nMarco will save $2.58 by buying the Pet Starter Kit.\n<|im_start|>answer\nThe Pet Starter Kit is the better deal.\n\r\nThe total cost of the Pet Starter Kit after the 5% sales tax is applied is $47.20.\n\r\nThe sum of the cost of the individual items is $47.73, before the tax is applied. Since the Mouse Chow is a food item, the total amount to be taxed is only $41.01. After applying the 5% sales tax and adding the cost of the Mouse Chow, the total cost of the individual items is $49.78.\n\r\nMarco will save $2.58 by buying the Pet Starter Kit.\n<|im_end|>" }, { "id": "#3962", "title": "All the Zeros", "fun": 2.15, "difficulty": 2.0, "author": "mad-ade", "desc": "If you were to write every number from 1 to 1000, How many zeros (0) would you write altogether in total?", "hint": "No hint available.", "answer": "192", "category": "Math", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you were to write every number from 1 to 1000, How many zeros (0) would you write altogether in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n192\n<|im_start|>answer\n192\n<|im_end|>" }, { "id": "#17850", "title": "What Letter?", "fun": 2.15, "difficulty": 2.45, "author": "fishmed", "desc": "Write on a piece of paper a 5x5 letter square using the alphabet, minus the letter Q, where A is in the upper left-hand corner and Z is in the lower right-hand corner. After you have done this, can you tell me which letter comes just above the letter which comes between the letter just before the letter just below B and the letter just before the letter just above Y?", "hint": "No hint available.", "answer": "The letter is G.\n\r\nThe two letters to initially find are F & S. The letter above the one which is between them is G.", "category": "Logic", "date": "06/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWrite on a piece of paper a 5x5 letter square using the alphabet, minus the letter Q, where A is in the upper left-hand corner and Z is in the lower right-hand corner. After you have done this, can you tell me which letter comes just above the letter which comes between the letter just before the letter just below B and the letter just before the letter just above Y?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe letter is G.\n\r\nThe two letters to initially find are F & S. The letter above the one which is between them is G.\n<|im_start|>answer\nThe letter is G.\n\r\nThe two letters to initially find are F & S. The letter above the one which is between them is G.\n<|im_end|>" }, { "id": "#2259", "title": "10+10 =20?", "fun": 2.15, "difficulty": 2.19, "author": "rml417", "desc": "10+10 doesn't equal 20. If you add 50, you'll get 11. How is that?", "hint": "Think of the time.", "answer": "If it was 10 hours and 10 minutes, it's never 20. And if you add 50 minutes, the time becomes 11 (hours)", "category": "Math", "date": "02/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n10+10 doesn't equal 20. If you add 50, you'll get 11. How is that?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf it was 10 hours and 10 minutes, it's never 20. And if you add 50 minutes, the time becomes 11 (hours)\n<|im_start|>answer\nIf it was 10 hours and 10 minutes, it's never 20. And if you add 50 minutes, the time becomes 11 (hours)\n<|im_end|>" }, { "id": "#1915", "title": "B+Y=G", "fun": 2.15, "difficulty": 1.24, "author": "sam7630", "desc": "B+Y=G\r\nR+Y=O\r\nR+B=P\n\r\nWhat does R+W equal?", "hint": "No hint available.", "answer": "R=red\r\nO=orange\r\nY=yellow\r\nG=green\r\nB=blue\r\nP=purple\r\nPi=pink\r\nW=white\n\r\nR+W is red plus white, which is Pi, or pink.", "category": "Logic", "date": "01/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nB+Y=G\r\nR+Y=O\r\nR+B=P\n\r\nWhat does R+W equal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nR=red\r\nO=orange\r\nY=yellow\r\nG=green\r\nB=blue\r\nP=purple\r\nPi=pink\r\nW=white\n\r\nR+W is red plus white, which is Pi, or pink.\n<|im_start|>answer\nR=red\r\nO=orange\r\nY=yellow\r\nG=green\r\nB=blue\r\nP=purple\r\nPi=pink\r\nW=white\n\r\nR+W is red plus white, which is Pi, or pink.\n<|im_end|>" }, { "id": "#32838", "title": "1000 Point Star", "fun": 2.15, "difficulty": 3.19, "author": "lessthanjake789", "desc": "Typical \"stars\" are drawn in connected, but not repeated, line segments. For example, a 5-point star is drawn as such - line segments AC, CE, EB, BD, DA. The segments must always alternate a constant number of points (in the above case, skipping 1 point in between). \r\nGiven the information that there is only 1 way to draw a 5-point star, and that there is NO way to draw a 6-point star (in continuous lines, that is), and there are 2 ways to draw a 7-point star, how many different ways are there to draw a 1000-point star?", "hint": "It's not guess work. Think of factors and mirror images. Try drawing out examples.", "answer": "199. \n\r\nFirst, let's examine the 5-point star and why there is only that one, described, way to draw it. Starting at A, you cannot go straight to point B, otherwise you will have a pentagon, not a star. Same with point E. AC and AD (and their progressions) yield identical pictures (notice that the last segment in the AC one is DA, literally reverse all the letters to get AD ending in CA). \n\r\nNow, for a 6-point star, there are points A, B, C, D, E, and F. Starting at A, we cannot go to B or F, because then we have a hexagon. If we go AC, then we must go CE, then CA... making a triangle, not a 6-point star. Going backwards, AE, EC, EA; mirror image. If we skip 2 points, we go AD, then DA, a straight line, hardly a 6-point star. \n\r\nFor a 7-point star, A-G, AB and AG are not possible, as that's a heptagon. AC, CE, EG, GB, BD, DF, FA is one way to draw the star, skipping one point in between. Also, AD, DG, GC, CF, FB, BE, EA, skipping two points in between each, is the other way. The last two line possibilities, AF and AE are mirror images of the two working scenarios. \n\r\nExamining the above information a little more deeply, we see that we must divide all possible drawings by two, to get rid of the mirror images. Also, we cannot use the point immediately to the left, that is AB as a segment. This explains why there is only 1 way for a 5-point, and 2 for a 7-point, but does not explain the 6-point. Of those remaining points (dealing only with the first half, again, mirror images), those that are factors of the number of total points do not work, because you will end up back at the starting point before hitting every number. AC is a factor in six because it passes point B, so it's 2. AD is a factor of 3 (B, C and D). Not only factors, but multiples of factors, as well (for example, skipping 4 points in the 6-point still does not work). \n\r\nUsing the knowledge of mirrors, first point impossibility (AB) and factors, we see that the number 1000 is made up of 10^3, or 2^3*5^3. Without going through every factor, it's quickly and easily discernible that of the numbers 1-1000, 2 or multiples of it encompass 500 numbers, all evens. Any multiple of 5 includes 200 numbers, half of which end in 0 and are already included with the 2's, so there are 600 unique factors and multiples between 1 and 1000. That leaves us with 400 that are *not*, which should explain how many unique stars we can make. Remember to cut it in half because of mirroring, leaving us with 200, and to discount the AB segment (factor of 1), leaving us with 199. (If you discount AB, and THEN halve it, remember you needed to remove A[Z], the mirror image of that point).", "category": "Logic", "date": "09/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTypical \"stars\" are drawn in connected, but not repeated, line segments. For example, a 5-point star is drawn as such - line segments AC, CE, EB, BD, DA. The segments must always alternate a constant number of points (in the above case, skipping 1 point in between). \r\nGiven the information that there is only 1 way to draw a 5-point star, and that there is NO way to draw a 6-point star (in continuous lines, that is), and there are 2 ways to draw a 7-point star, how many different ways are there to draw a 1000-point star?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n199. \n\r\nFirst, let's examine the 5-point star and why there is only that one, described, way to draw it. Starting at A, you cannot go straight to point B, otherwise you will have a pentagon, not a star. Same with point E. AC and AD (and their progressions) yield identical pictures (notice that the last segment in the AC one is DA, literally reverse all the letters to get AD ending in CA). \n\r\nNow, for a 6-point star, there are points A, B, C, D, E, and F. Starting at A, we cannot go to B or F, because then we have a hexagon. If we go AC, then we must go CE, then CA... making a triangle, not a 6-point star. Going backwards, AE, EC, EA; mirror image. If we skip 2 points, we go AD, then DA, a straight line, hardly a 6-point star. \n\r\nFor a 7-point star, A-G, AB and AG are not possible, as that's a heptagon. AC, CE, EG, GB, BD, DF, FA is one way to draw the star, skipping one point in between. Also, AD, DG, GC, CF, FB, BE, EA, skipping two points in between each, is the other way. The last two line possibilities, AF and AE are mirror images of the two working scenarios. \n\r\nExamining the above information a little more deeply, we see that we must divide all possible drawings by two, to get rid of the mirror images. Also, we cannot use the point immediately to the left, that is AB as a segment. This explains why there is only 1 way for a 5-point, and 2 for a 7-point, but does not explain the 6-point. Of those remaining points (dealing only with the first half, again, mirror images), those that are factors of the number of total points do not work, because you will end up back at the starting point before hitting every number. AC is a factor in six because it passes point B, so it's 2. AD is a factor of 3 (B, C and D). Not only factors, but multiples of factors, as well (for example, skipping 4 points in the 6-point still does not work). \n\r\nUsing the knowledge of mirrors, first point impossibility (AB) and factors, we see that the number 1000 is made up of 10^3, or 2^3*5^3. Without going through every factor, it's quickly and easily discernible that of the numbers 1-1000, 2 or multiples of it encompass 500 numbers, all evens. Any multiple of 5 includes 200 numbers, half of which end in 0 and are already included with the 2's, so there are 600 unique factors and multiples between 1 and 1000. That leaves us with 400 that are *not*, which should explain how many unique stars we can make. Remember to cut it in half because of mirroring, leaving us with 200, and to discount the AB segment (factor of 1), leaving us with 199. (If you discount AB, and THEN halve it, remember you needed to remove A[Z], the mirror image of that point).\n<|im_start|>answer\n199. \n\r\nFirst, let's examine the 5-point star and why there is only that one, described, way to draw it. Starting at A, you cannot go straight to point B, otherwise you will have a pentagon, not a star. Same with point E. AC and AD (and their progressions) yield identical pictures (notice that the last segment in the AC one is DA, literally reverse all the letters to get AD ending in CA). \n\r\nNow, for a 6-point star, there are points A, B, C, D, E, and F. Starting at A, we cannot go to B or F, because then we have a hexagon. If we go AC, then we must go CE, then CA... making a triangle, not a 6-point star. Going backwards, AE, EC, EA; mirror image. If we skip 2 points, we go AD, then DA, a straight line, hardly a 6-point star. \n\r\nFor a 7-point star, A-G, AB and AG are not possible, as that's a heptagon. AC, CE, EG, GB, BD, DF, FA is one way to draw the star, skipping one point in between. Also, AD, DG, GC, CF, FB, BE, EA, skipping two points in between each, is the other way. The last two line possibilities, AF and AE are mirror images of the two working scenarios. \n\r\nExamining the above information a little more deeply, we see that we must divide all possible drawings by two, to get rid of the mirror images. Also, we cannot use the point immediately to the left, that is AB as a segment. This explains why there is only 1 way for a 5-point, and 2 for a 7-point, but does not explain the 6-point. Of those remaining points (dealing only with the first half, again, mirror images), those that are factors of the number of total points do not work, because you will end up back at the starting point before hitting every number. AC is a factor in six because it passes point B, so it's 2. AD is a factor of 3 (B, C and D). Not only factors, but multiples of factors, as well (for example, skipping 4 points in the 6-point still does not work). \n\r\nUsing the knowledge of mirrors, first point impossibility (AB) and factors, we see that the number 1000 is made up of 10^3, or 2^3*5^3. Without going through every factor, it's quickly and easily discernible that of the numbers 1-1000, 2 or multiples of it encompass 500 numbers, all evens. Any multiple of 5 includes 200 numbers, half of which end in 0 and are already included with the 2's, so there are 600 unique factors and multiples between 1 and 1000. That leaves us with 400 that are *not*, which should explain how many unique stars we can make. Remember to cut it in half because of mirroring, leaving us with 200, and to discount the AB segment (factor of 1), leaving us with 199. (If you discount AB, and THEN halve it, remember you needed to remove A[Z], the mirror image of that point).\n<|im_end|>" }, { "id": "#6403", "title": "Digit Deficiencies", "fun": 2.15, "difficulty": 2.73, "author": "mrbump999", "desc": "Use all the digits from 1 to 9 to complete the equation\n\r\n??? x 3? = ????", "hint": "1?? x 3? = ?254", "answer": "186 x 39 = 7254", "category": "Math", "date": "08/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUse all the digits from 1 to 9 to complete the equation\n\r\n??? x 3? = ????\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n186 x 39 = 7254\n<|im_start|>answer\n186 x 39 = 7254\n<|im_end|>" }, { "id": "#35783", "title": "Special Number 2", "fun": 2.15, "difficulty": 1.37, "author": "coolcow35", "desc": "What is the highest 2-digit number that is divisible by 3 and 2 numerals apart?\n\r\nFor example:\n\r\n24. The 2 and 4 are two numerals apart, and 24 is a two-digit number divisible by 3. You need to find the HIGHEST one.", "hint": "No hint available.", "answer": "75.\n\r\n5 and 7 are two numerals apart and it is divisible by 3.", "category": "Math", "date": "03/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the highest 2-digit number that is divisible by 3 and 2 numerals apart?\n\r\nFor example:\n\r\n24. The 2 and 4 are two numerals apart, and 24 is a two-digit number divisible by 3. You need to find the HIGHEST one.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n75.\n\r\n5 and 7 are two numerals apart and it is divisible by 3.\n<|im_start|>answer\n75.\n\r\n5 and 7 are two numerals apart and it is divisible by 3.\n<|im_end|>" }, { "id": "#42231", "title": "Grobi's Treat", "fun": 2.15, "difficulty": 2.5100000000000002, "author": "BadBunnee02", "desc": "Grobi is a very unique creature.\n\r\nGrobi:\n\r\n1...is round in shape.\r\n2...is six inches in diameter.\r\n3...lives on an acre-sized flat field.\r\n4...moves only by jumping; cannot walk, crawl, fly, or move in any manner other than jumping.\r\n5...can jump, in any one jump, a minimum of 6 inches or a maximum of 72 inches (6 feet) across the field (cannot jump straight up-down). Grobi can therefore, in any one jump, jump any distance across the field at or between the 6-72 inch limits.\r\n6...can jump directly north, south, east, or west only; cannot jump diagonally.\r\n7...must jump four times in any one direction (N-S-E-W) before changing direction (N-S-E-W) or to continue in the same direction (N-S-E-W).\r\n8...dines on mushrooms which grow in the field. The mushrooms grow to a maximum of six inches in diameter and to a height of an inch.\r\n9...can ingest a mushroom only by landing directly atop the mushroom. \r\n10...is very adept at precisely determining distances.\n\r\nOne day Grobi - happily jumping around in the middle of the field - locates a six-inch diameter mushroom six inches away (center of Grobi to center of mushroom distance) directly west of Grobi.\n\r\nGrobi quickly (and accurately) calculates that FOUR jumps is the fastest way to get to the mushroom and eat, which Grobi does.\n\r\nDescribe the route taken by Grobi to eat the mushroom including the direction of jumps, each approximate jump-distance, and the specific number of jumps in each direction.", "hint": "No need to \"invent\" anything new for Grobi such as extraordinary motivating or grasping or ingestion appendages. The problem can be solved using the information given. Key words in the puzzle are \"happily jumping around\".", "answer": "Grobi had already taken ONE jump to the east (in a new four-jump 'direction' series) when the mushroom was located to the west. Grobi therefore had to take THREE more jumps to the east before being able to change direction and head back west. Grobi took three minimum jumps (six inches or so each) to the east and then a long (24 inches or so) FOURTH jump to the west to land atop the mushroom.\n\r\nNo other conditions would solve the puzzle as written:\n\r\n1. If Grobi had been jumping west (as part of a four-jump 'direction' series), or had just concluded a four-jump 'direction' series, then the mushroom could have been attained in one jump.\n\r\n2. If Grobi had been jumping north or south (as part of a four-jump 'direction' series) then four additional jumps (even if able to change direction) would have put Grobi out of alignment with the mushroom.\n\r\n3. If Grobi had been jumping east (and had done two or three jumps as part of a four-jump 'direction' series) then the mushroom could have been attained in two or three additional jumps and not the four that was Grobi's correct calculation.", "category": "Logic", "date": "06/14/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGrobi is a very unique creature.\n\r\nGrobi:\n\r\n1...is round in shape.\r\n2...is six inches in diameter.\r\n3...lives on an acre-sized flat field.\r\n4...moves only by jumping; cannot walk, crawl, fly, or move in any manner other than jumping.\r\n5...can jump, in any one jump, a minimum of 6 inches or a maximum of 72 inches (6 feet) across the field (cannot jump straight up-down). Grobi can therefore, in any one jump, jump any distance across the field at or between the 6-72 inch limits.\r\n6...can jump directly north, south, east, or west only; cannot jump diagonally.\r\n7...must jump four times in any one direction (N-S-E-W) before changing direction (N-S-E-W) or to continue in the same direction (N-S-E-W).\r\n8...dines on mushrooms which grow in the field. The mushrooms grow to a maximum of six inches in diameter and to a height of an inch.\r\n9...can ingest a mushroom only by landing directly atop the mushroom. \r\n10...is very adept at precisely determining distances.\n\r\nOne day Grobi - happily jumping around in the middle of the field - locates a six-inch diameter mushroom six inches away (center of Grobi to center of mushroom distance) directly west of Grobi.\n\r\nGrobi quickly (and accurately) calculates that FOUR jumps is the fastest way to get to the mushroom and eat, which Grobi does.\n\r\nDescribe the route taken by Grobi to eat the mushroom including the direction of jumps, each approximate jump-distance, and the specific number of jumps in each direction.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGrobi had already taken ONE jump to the east (in a new four-jump 'direction' series) when the mushroom was located to the west. Grobi therefore had to take THREE more jumps to the east before being able to change direction and head back west. Grobi took three minimum jumps (six inches or so each) to the east and then a long (24 inches or so) FOURTH jump to the west to land atop the mushroom.\n\r\nNo other conditions would solve the puzzle as written:\n\r\n1. If Grobi had been jumping west (as part of a four-jump 'direction' series), or had just concluded a four-jump 'direction' series, then the mushroom could have been attained in one jump.\n\r\n2. If Grobi had been jumping north or south (as part of a four-jump 'direction' series) then four additional jumps (even if able to change direction) would have put Grobi out of alignment with the mushroom.\n\r\n3. If Grobi had been jumping east (and had done two or three jumps as part of a four-jump 'direction' series) then the mushroom could have been attained in two or three additional jumps and not the four that was Grobi's correct calculation.\n<|im_start|>answer\nGrobi had already taken ONE jump to the east (in a new four-jump 'direction' series) when the mushroom was located to the west. Grobi therefore had to take THREE more jumps to the east before being able to change direction and head back west. Grobi took three minimum jumps (six inches or so each) to the east and then a long (24 inches or so) FOURTH jump to the west to land atop the mushroom.\n\r\nNo other conditions would solve the puzzle as written:\n\r\n1. If Grobi had been jumping west (as part of a four-jump 'direction' series), or had just concluded a four-jump 'direction' series, then the mushroom could have been attained in one jump.\n\r\n2. If Grobi had been jumping north or south (as part of a four-jump 'direction' series) then four additional jumps (even if able to change direction) would have put Grobi out of alignment with the mushroom.\n\r\n3. If Grobi had been jumping east (and had done two or three jumps as part of a four-jump 'direction' series) then the mushroom could have been attained in two or three additional jumps and not the four that was Grobi's correct calculation.\n<|im_end|>" }, { "id": "#23957", "title": "Deck Building", "fun": 2.15, "difficulty": 2.43, "author": "drussel3", "desc": "Ralph wanted to buy all the lumber for his deck in one trip, and not have to go back to the lumberyard 45 miles away. He didn't want to buy more than he needed because wood is expensive and he had nowhere to store it.\n\r\nRalph's plans for his deck called for standard 2x4 - 8 foot long pine boards with 3/8\" spacing between each board for drainage. His deck was to be 8 feet deep by 30 feet long. The last board farthest from the doorwall could be cut lengthwise to fit if necessary, thus giving him a smaller width board at the end where no one is likely to see it.\n\r\nHow many 2x4's did he buy?", "hint": "The boards are to be laid flat, not on end. No tricks in the deck layout, the board placement, or the 3/8\" drainage spacing.", "answer": "He purchased (93) 2x4's with no cutting required (not 83 boards). Standard 2x4 lumber is actually 1.5\" x 3.5\" in size. \n\r\n30 foot = 360 inches = x (3.5\") + (x-1) (0.375\")\r\nwhere x is the number of boards\n\r\nLumber is referred to by its nominal size, in this instance, 2x4. It starts out as 2\" x 4\" when it is first rough sawn from the log. It is then dried and planed to its finished size of 1.5\" x 3.5\".", "category": "Math", "date": "06/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRalph wanted to buy all the lumber for his deck in one trip, and not have to go back to the lumberyard 45 miles away. He didn't want to buy more than he needed because wood is expensive and he had nowhere to store it.\n\r\nRalph's plans for his deck called for standard 2x4 - 8 foot long pine boards with 3/8\" spacing between each board for drainage. His deck was to be 8 feet deep by 30 feet long. The last board farthest from the doorwall could be cut lengthwise to fit if necessary, thus giving him a smaller width board at the end where no one is likely to see it.\n\r\nHow many 2x4's did he buy?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe purchased (93) 2x4's with no cutting required (not 83 boards). Standard 2x4 lumber is actually 1.5\" x 3.5\" in size. \n\r\n30 foot = 360 inches = x (3.5\") + (x-1) (0.375\")\r\nwhere x is the number of boards\n\r\nLumber is referred to by its nominal size, in this instance, 2x4. It starts out as 2\" x 4\" when it is first rough sawn from the log. It is then dried and planed to its finished size of 1.5\" x 3.5\".\n<|im_start|>answer\nHe purchased (93) 2x4's with no cutting required (not 83 boards). Standard 2x4 lumber is actually 1.5\" x 3.5\" in size. \n\r\n30 foot = 360 inches = x (3.5\") + (x-1) (0.375\")\r\nwhere x is the number of boards\n\r\nLumber is referred to by its nominal size, in this instance, 2x4. It starts out as 2\" x 4\" when it is first rough sawn from the log. It is then dried and planed to its finished size of 1.5\" x 3.5\".\n<|im_end|>" }, { "id": "#3291", "title": "A Walk in Manhattan", "fun": 2.15, "difficulty": 2.0, "author": "204_blaze_41", "desc": "It happened in midtown Manhattan during the July 4th celebration; Sam walked several kilometres from West 32nd Street all the way to West 63rd Street without seeing anyone or being seen by anyone. It was a clear sunny day and he could see where he was going. He did not use any disguise or unusual method of transportation. Even though Manhattan was swarming with people not one person saw him. How could this be possible?", "hint": "No hint available.", "answer": "He was walking through the city sewer system.", "category": "Logic", "date": "04/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt happened in midtown Manhattan during the July 4th celebration; Sam walked several kilometres from West 32nd Street all the way to West 63rd Street without seeing anyone or being seen by anyone. It was a clear sunny day and he could see where he was going. He did not use any disguise or unusual method of transportation. Even though Manhattan was swarming with people not one person saw him. How could this be possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe was walking through the city sewer system.\n<|im_start|>answer\nHe was walking through the city sewer system.\n<|im_end|>" }, { "id": "#21054", "title": "Hungry Dog", "fun": 2.15, "difficulty": 0.8300000000000001, "author": "HughJazz510", "desc": "A dog is on a chain leash on one side of a railroad track. His food is on the other side of the track. The dog's leash is long enough for him to be able to cross to the other side the track, but it is not long enough for him to reach his food. How can he break the chain leash to get the food?", "hint": "The dog must get to the side where the food is on to somehow break the leash.", "answer": "The dog can break the chain leash by crossing the track and waiting for a train to run over the leash and break it.", "category": "Logic", "date": "02/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA dog is on a chain leash on one side of a railroad track. His food is on the other side of the track. The dog's leash is long enough for him to be able to cross to the other side the track, but it is not long enough for him to reach his food. How can he break the chain leash to get the food?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe dog can break the chain leash by crossing the track and waiting for a train to run over the leash and break it.\n<|im_start|>answer\nThe dog can break the chain leash by crossing the track and waiting for a train to run over the leash and break it.\n<|im_end|>" }, { "id": "#40038", "title": "Six Digits", "fun": 2.15, "difficulty": 2.05, "author": "shenqiang", "desc": "Please replace the question marks with the digits 1,2,3,4,5,6 in the expression \"??-(??/?+?)\" to find the largest possible result. \n\r\nThe result must be an integer.", "hint": "No hint available.", "answer": "Denote by AB-(CD/E+F). To get the largest possible result, AB must be large and the subtrahend must be small. The largest value of AB is 65, the subtrahend is made up of 1 through 4, whose smallest value is obviously 12/4+3=6. Therefore, the largest possible result is 65-6=59.", "category": "Math", "date": "01/13/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlease replace the question marks with the digits 1,2,3,4,5,6 in the expression \"??-(??/?+?)\" to find the largest possible result. \n\r\nThe result must be an integer.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDenote by AB-(CD/E+F). To get the largest possible result, AB must be large and the subtrahend must be small. The largest value of AB is 65, the subtrahend is made up of 1 through 4, whose smallest value is obviously 12/4+3=6. Therefore, the largest possible result is 65-6=59.\n<|im_start|>answer\nDenote by AB-(CD/E+F). To get the largest possible result, AB must be large and the subtrahend must be small. The largest value of AB is 65, the subtrahend is made up of 1 through 4, whose smallest value is obviously 12/4+3=6. Therefore, the largest possible result is 65-6=59.\n<|im_end|>" }, { "id": "#9176", "title": "8998971798998", "fun": 2.15, "difficulty": 2.62, "author": "ccccc", "desc": "8998971798998\n\n\r\nWhat is so special about this set of numbers, aside from the fact that it is a palindrome?", "hint": "No hint available.", "answer": "As well as originally being a palindrome, when you add up the individual numbers the answer is also a palindrome (101).", "category": "Math", "date": "12/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n8998971798998\n\n\r\nWhat is so special about this set of numbers, aside from the fact that it is a palindrome?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAs well as originally being a palindrome, when you add up the individual numbers the answer is also a palindrome (101).\n<|im_start|>answer\nAs well as originally being a palindrome, when you add up the individual numbers the answer is also a palindrome (101).\n<|im_end|>" }, { "id": "#18755", "title": "Mad Ade's Digital Watch", "fun": 2.15, "difficulty": 2.48, "author": "Mad-Ade", "desc": "Mad Ade is once more perched outside the \"Sweaty Chef Kebab Shop\" waiting for it to open. He glances at his new digital watch and notices that the time and date display used 10 digits in its HH:MM:SS Month/Day format.\r\nIt was 17:59:56 09/03.\r\nMad Ade wondered to himself, if all ten digits 0-9 appear on the display, what is (a) the earliest, and (b) the latest date and time in the year this could happen?\r\nObviously he didn't work out the answer as the doors opened and his mind turned to more important things.\n\r\nWhat would the answer be?", "hint": "No hint available.", "answer": "A, The earliest time of the year is 17:48:59 03/26\r\nB, The latest time of the year is 17:56:43 09/28", "category": "Logic", "date": "09/06/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is once more perched outside the \"Sweaty Chef Kebab Shop\" waiting for it to open. He glances at his new digital watch and notices that the time and date display used 10 digits in its HH:MM:SS Month/Day format.\r\nIt was 17:59:56 09/03.\r\nMad Ade wondered to himself, if all ten digits 0-9 appear on the display, what is (a) the earliest, and (b) the latest date and time in the year this could happen?\r\nObviously he didn't work out the answer as the doors opened and his mind turned to more important things.\n\r\nWhat would the answer be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA, The earliest time of the year is 17:48:59 03/26\r\nB, The latest time of the year is 17:56:43 09/28\n<|im_start|>answer\nA, The earliest time of the year is 17:48:59 03/26\r\nB, The latest time of the year is 17:56:43 09/28\n<|im_end|>" }, { "id": "#36906", "title": "Population Explosion", "fun": 2.15, "difficulty": 2.83, "author": "cnmne", "desc": "A group of 100 people start a colony on the first day of the year. Each year, the birth rate is 4% of the population at the beginning of the year, and the death rate is 3% of the population at the beginning of the year. The resulting births and deaths are truncated to a whole number. These rates are constant. For example, consider a population of 99 people at the start of a year. A 4% birth rate would be 3.96, truncated to 3 births during the year. A 3% death rate would be 2.97, truncated to 2 deaths during the year. The population at the end of that year would be 99 + 3 - 2 = 100. Based on the stated birth and death rates, what is the LAST year that the population increases by only 1?", "hint": "No hint available.", "answer": "The last year the population would increase by only one would be the 61st year.\n\r\n1) Beginning with the 1st year, the number of births will be 4 (4% of 100 = 4) and the number of deaths will be 3 (3% of 100 = 3), which results in a population increase of 1. The population will increase at the rate of 1 per year for 25 years, reaching 125 at the end of the 25th year.\r\n2) Beginning with the 26th year, the number of births per year will increase to 5 (4% of 125 = 5), while the deaths will still be 3. The population will increase at the rate of 2 per year, reaching 135 at the end of the 30th year.\r\n3) Beginning with the 31st year, the number of deaths per year will increase to 4 (3% of 135 = 4.05), while the births will still be 5. The population will increase at the rate of 1 per year, reaching 150 at the end of the 45th year.\r\n4) Beginning with the 46th year, the number of births per year will increase to 6 (4% of 150 = 6), while the deaths will still be 4. The population will increase at the rate of 2 per year, reaching 168 at the end of the 54th year.\r\n5) Beginning with the 55th year, the number of deaths per year will increase to 5 (3% of 168 = 5.04), while the births will still be 6. The population will increase at the rate of 1 per year, reaching 175 at the end of the 61st year.\r\n6) Beginning with the 62nd year, the number of births per year will increase to 7 (4% of 175 = 7), while the deaths will still be 5. The population will increase at the rate of 2 per year, reaching 201 at the end of the 75th year.\r\n7) Beginning with the 76th year, the number of births per year will increase to 8 (4% of 201 = 8.04) and the number of deaths will increase to 6 (3% of 201 = 6.03). The population will continue to increase at the rate of 2 per year. The population will never again increase by only 1 per year.\n\r\nAlthough the 26th year is the first year that the population increases by more than 1, the 25th year is not the last year that it increases by 1. The last year that the population increases by 1 is the 61st year, when the population reaches 175.", "category": "Math", "date": "06/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of 100 people start a colony on the first day of the year. Each year, the birth rate is 4% of the population at the beginning of the year, and the death rate is 3% of the population at the beginning of the year. The resulting births and deaths are truncated to a whole number. These rates are constant. For example, consider a population of 99 people at the start of a year. A 4% birth rate would be 3.96, truncated to 3 births during the year. A 3% death rate would be 2.97, truncated to 2 deaths during the year. The population at the end of that year would be 99 + 3 - 2 = 100. Based on the stated birth and death rates, what is the LAST year that the population increases by only 1?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe last year the population would increase by only one would be the 61st year.\n\r\n1) Beginning with the 1st year, the number of births will be 4 (4% of 100 = 4) and the number of deaths will be 3 (3% of 100 = 3), which results in a population increase of 1. The population will increase at the rate of 1 per year for 25 years, reaching 125 at the end of the 25th year.\r\n2) Beginning with the 26th year, the number of births per year will increase to 5 (4% of 125 = 5), while the deaths will still be 3. The population will increase at the rate of 2 per year, reaching 135 at the end of the 30th year.\r\n3) Beginning with the 31st year, the number of deaths per year will increase to 4 (3% of 135 = 4.05), while the births will still be 5. The population will increase at the rate of 1 per year, reaching 150 at the end of the 45th year.\r\n4) Beginning with the 46th year, the number of births per year will increase to 6 (4% of 150 = 6), while the deaths will still be 4. The population will increase at the rate of 2 per year, reaching 168 at the end of the 54th year.\r\n5) Beginning with the 55th year, the number of deaths per year will increase to 5 (3% of 168 = 5.04), while the births will still be 6. The population will increase at the rate of 1 per year, reaching 175 at the end of the 61st year.\r\n6) Beginning with the 62nd year, the number of births per year will increase to 7 (4% of 175 = 7), while the deaths will still be 5. The population will increase at the rate of 2 per year, reaching 201 at the end of the 75th year.\r\n7) Beginning with the 76th year, the number of births per year will increase to 8 (4% of 201 = 8.04) and the number of deaths will increase to 6 (3% of 201 = 6.03). The population will continue to increase at the rate of 2 per year. The population will never again increase by only 1 per year.\n\r\nAlthough the 26th year is the first year that the population increases by more than 1, the 25th year is not the last year that it increases by 1. The last year that the population increases by 1 is the 61st year, when the population reaches 175.\n<|im_start|>answer\nThe last year the population would increase by only one would be the 61st year.\n\r\n1) Beginning with the 1st year, the number of births will be 4 (4% of 100 = 4) and the number of deaths will be 3 (3% of 100 = 3), which results in a population increase of 1. The population will increase at the rate of 1 per year for 25 years, reaching 125 at the end of the 25th year.\r\n2) Beginning with the 26th year, the number of births per year will increase to 5 (4% of 125 = 5), while the deaths will still be 3. The population will increase at the rate of 2 per year, reaching 135 at the end of the 30th year.\r\n3) Beginning with the 31st year, the number of deaths per year will increase to 4 (3% of 135 = 4.05), while the births will still be 5. The population will increase at the rate of 1 per year, reaching 150 at the end of the 45th year.\r\n4) Beginning with the 46th year, the number of births per year will increase to 6 (4% of 150 = 6), while the deaths will still be 4. The population will increase at the rate of 2 per year, reaching 168 at the end of the 54th year.\r\n5) Beginning with the 55th year, the number of deaths per year will increase to 5 (3% of 168 = 5.04), while the births will still be 6. The population will increase at the rate of 1 per year, reaching 175 at the end of the 61st year.\r\n6) Beginning with the 62nd year, the number of births per year will increase to 7 (4% of 175 = 7), while the deaths will still be 5. The population will increase at the rate of 2 per year, reaching 201 at the end of the 75th year.\r\n7) Beginning with the 76th year, the number of births per year will increase to 8 (4% of 201 = 8.04) and the number of deaths will increase to 6 (3% of 201 = 6.03). The population will continue to increase at the rate of 2 per year. The population will never again increase by only 1 per year.\n\r\nAlthough the 26th year is the first year that the population increases by more than 1, the 25th year is not the last year that it increases by 1. The last year that the population increases by 1 is the 61st year, when the population reaches 175.\n<|im_end|>" }, { "id": "#21973", "title": "Taylor Trucking", "fun": 2.15, "difficulty": 1.62, "author": "MrBasKetBall", "desc": "Mr. Taylor loaded lumber at the Taylor Trucking warehouse. Then he drove 60 miles north where he dropped the lumber off at a furniture factory and picked up a load of furniture. He continued driving north another 40 miles where he dropped off the furniture. He returned 40 miles south to the furniture factory, picked up another load, and continued south another 120 miles. He dropped the furniture off, then continued south 10 miles to pick up more. With the truck loaded, he turned around and headed north 60 miles where he left the truck overnight.\n\r\nMr. Ward loaded another truck at the Taylor Trucking warehouse. He drove west 40 miles and unloaded the boxes at the Handy Home Hardware Center. He picked up a dozen cartons and drove east with them 70 miles to Eastville. There he filled his truck and drove on east another 100 miles. He unloaded his truck and returned 125 miles west to his home. \n\r\nHow many miles did each driver travel, and how far was each driver from the Taylor Trucking Warehouse at the end of the day?", "hint": "Draw a diagram to illustrate how far each man traveled. Label your diagram with North, South, East and West and keep track of how far each man drove in each direction as well as the total mileage.", "answer": "Mr. Taylor drove 330 miles and ended up 10 miles from the Taylor Trucking Warehouse.\r\nMr. Ward drove 335 and ended up 5 miles from the Taylor Trucking Warehouse.", "category": "Math", "date": "04/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Taylor loaded lumber at the Taylor Trucking warehouse. Then he drove 60 miles north where he dropped the lumber off at a furniture factory and picked up a load of furniture. He continued driving north another 40 miles where he dropped off the furniture. He returned 40 miles south to the furniture factory, picked up another load, and continued south another 120 miles. He dropped the furniture off, then continued south 10 miles to pick up more. With the truck loaded, he turned around and headed north 60 miles where he left the truck overnight.\n\r\nMr. Ward loaded another truck at the Taylor Trucking warehouse. He drove west 40 miles and unloaded the boxes at the Handy Home Hardware Center. He picked up a dozen cartons and drove east with them 70 miles to Eastville. There he filled his truck and drove on east another 100 miles. He unloaded his truck and returned 125 miles west to his home. \n\r\nHow many miles did each driver travel, and how far was each driver from the Taylor Trucking Warehouse at the end of the day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Taylor drove 330 miles and ended up 10 miles from the Taylor Trucking Warehouse.\r\nMr. Ward drove 335 and ended up 5 miles from the Taylor Trucking Warehouse.\n<|im_start|>answer\nMr. Taylor drove 330 miles and ended up 10 miles from the Taylor Trucking Warehouse.\r\nMr. Ward drove 335 and ended up 5 miles from the Taylor Trucking Warehouse.\n<|im_end|>" }, { "id": "#2592", "title": "Shopkeeper", "fun": 2.15, "difficulty": 2.44, "author": "bilbobaggins", "desc": "A shopkeeper has £25.83p in his till.\r\nIt is made up of 4 different coins.\r\nThere are the same number of each coin.\n\r\n£1 coin is the highest coin to be used, so the available coins are: 1p, 2p, 5p, 10p, 20p, 50p, and £1.\n\r\nWhich 4 coins are used and how many of them are there?", "hint": "No hint available.", "answer": "He uses twenty-one £1 coins, \r\ntwenty-one 20p,\r\ntwenty-one 2p, and\r\ntwenty-one 1p.\r\nTotal: £25.83p", "category": "Math", "date": "03/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA shopkeeper has £25.83p in his till.\r\nIt is made up of 4 different coins.\r\nThere are the same number of each coin.\n\r\n£1 coin is the highest coin to be used, so the available coins are: 1p, 2p, 5p, 10p, 20p, 50p, and £1.\n\r\nWhich 4 coins are used and how many of them are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe uses twenty-one £1 coins, \r\ntwenty-one 20p,\r\ntwenty-one 2p, and\r\ntwenty-one 1p.\r\nTotal: £25.83p\n<|im_start|>answer\nHe uses twenty-one £1 coins, \r\ntwenty-one 20p,\r\ntwenty-one 2p, and\r\ntwenty-one 1p.\r\nTotal: £25.83p\n<|im_end|>" }, { "id": "#21795", "title": "It's All Greek to Me", "fun": 2.15, "difficulty": 1.43, "author": "tiggs", "desc": "There are three modern children, so obsessed with Greek mythology, that they've actually started to believe it. Each kid (Sarah, Christian, and Stacy) worship three different gods (Hermes, Helios, and Demeter) in three different countries (USA, Romania, and Greece).\n\r\n1.The Herald of the gods is worshiped by the American girl.\n\r\n2. Stacy used to use Drachma to buy things.\n\r\n3. The one who lives in Bucharest loves the sun.\n\r\n4. Stacy worships the Goddess.\n\r\n5. Demeter's worshiper is the closest to Mount Olympus.\n\r\n6. Christian shares his homeland with Dracula.\n\r\n7. Had Sarah loved Roman Mythology, she would worship Mercury.\n\r\n8. Sarah's country is the largest of the three.", "hint": "A herald is a messenger.\n\r\n Largest countries\r\n1=Russia\r\n2=Canada\r\n3=China\r\n4=USA...\r\n? Romania\r\n? Greece\r\n Country capitals\r\nGreece=Athens\r\nUSA=Washington DC\r\nRomania=Bucharest\n\r\nApollo was not the sun in Greek myth.", "answer": "Sarah worships Hermes in America\r\n Stacy worships Demeter in Greece\r\nChristian worships Helios in Romania\n\r\nClue #1 states that The American girl worships the herald of the gods. Hermes was a messenger to Zeus in Greek Myth. Clue #2 states that Stacy used to use Drachma to buy things. Greece used to use the Drachma as currency, but lately, has switched over to the Euro. Clue #3 states that the kid who lives in Bucharest loves the sun. This means that s/he worships the sun, Helios, in Greek Mythology. Also Bucharest is the capital of Romania, meaning that the kid who worships Helios lives in Romania. Clue #4 states that Stacy worships a Goddess. This means that she worships Demeter, the only Goddess out of the three. Clue #5 states that Demeter's worshiper is the closest to Mount Olympus, in Greece. Since clue #4 establishes that Stacy worships Demeter, that means that she lives in Greece. Clue #6 says that Christian shares his homeland with Dracula. This means that Christian is from Romania, because Dracula was from Romania (although not Transylvania). Since clue #3 said that the Romanian one worships Helios, we know that Christian worships Helios. Clue #7 states that Sarah would have worshiped Mercury, had she loved Roman Mythology. Mercury was the name the Romans gave to Hermes. Clue# 8 stated that Sarah lived in the largest of the three countries. This could only be America, since the United States is the fourth largest country in the world, smaller only than Russia, Canada, and China. Oh, the last hint under ''Hint'', was because Helios was the sun in Greek Mythology. Apollo was the God of light.", "category": "Logic-Grid", "date": "03/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three modern children, so obsessed with Greek mythology, that they've actually started to believe it. Each kid (Sarah, Christian, and Stacy) worship three different gods (Hermes, Helios, and Demeter) in three different countries (USA, Romania, and Greece).\n\r\n1.The Herald of the gods is worshiped by the American girl.\n\r\n2. Stacy used to use Drachma to buy things.\n\r\n3. The one who lives in Bucharest loves the sun.\n\r\n4. Stacy worships the Goddess.\n\r\n5. Demeter's worshiper is the closest to Mount Olympus.\n\r\n6. Christian shares his homeland with Dracula.\n\r\n7. Had Sarah loved Roman Mythology, she would worship Mercury.\n\r\n8. Sarah's country is the largest of the three.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSarah worships Hermes in America\r\n Stacy worships Demeter in Greece\r\nChristian worships Helios in Romania\n\r\nClue #1 states that The American girl worships the herald of the gods. Hermes was a messenger to Zeus in Greek Myth. Clue #2 states that Stacy used to use Drachma to buy things. Greece used to use the Drachma as currency, but lately, has switched over to the Euro. Clue #3 states that the kid who lives in Bucharest loves the sun. This means that s/he worships the sun, Helios, in Greek Mythology. Also Bucharest is the capital of Romania, meaning that the kid who worships Helios lives in Romania. Clue #4 states that Stacy worships a Goddess. This means that she worships Demeter, the only Goddess out of the three. Clue #5 states that Demeter's worshiper is the closest to Mount Olympus, in Greece. Since clue #4 establishes that Stacy worships Demeter, that means that she lives in Greece. Clue #6 says that Christian shares his homeland with Dracula. This means that Christian is from Romania, because Dracula was from Romania (although not Transylvania). Since clue #3 said that the Romanian one worships Helios, we know that Christian worships Helios. Clue #7 states that Sarah would have worshiped Mercury, had she loved Roman Mythology. Mercury was the name the Romans gave to Hermes. Clue# 8 stated that Sarah lived in the largest of the three countries. This could only be America, since the United States is the fourth largest country in the world, smaller only than Russia, Canada, and China. Oh, the last hint under ''Hint'', was because Helios was the sun in Greek Mythology. Apollo was the God of light.\n<|im_start|>answer\nSarah worships Hermes in America\r\n Stacy worships Demeter in Greece\r\nChristian worships Helios in Romania\n\r\nClue #1 states that The American girl worships the herald of the gods. Hermes was a messenger to Zeus in Greek Myth. Clue #2 states that Stacy used to use Drachma to buy things. Greece used to use the Drachma as currency, but lately, has switched over to the Euro. Clue #3 states that the kid who lives in Bucharest loves the sun. This means that s/he worships the sun, Helios, in Greek Mythology. Also Bucharest is the capital of Romania, meaning that the kid who worships Helios lives in Romania. Clue #4 states that Stacy worships a Goddess. This means that she worships Demeter, the only Goddess out of the three. Clue #5 states that Demeter's worshiper is the closest to Mount Olympus, in Greece. Since clue #4 establishes that Stacy worships Demeter, that means that she lives in Greece. Clue #6 says that Christian shares his homeland with Dracula. This means that Christian is from Romania, because Dracula was from Romania (although not Transylvania). Since clue #3 said that the Romanian one worships Helios, we know that Christian worships Helios. Clue #7 states that Sarah would have worshiped Mercury, had she loved Roman Mythology. Mercury was the name the Romans gave to Hermes. Clue# 8 stated that Sarah lived in the largest of the three countries. This could only be America, since the United States is the fourth largest country in the world, smaller only than Russia, Canada, and China. Oh, the last hint under ''Hint'', was because Helios was the sun in Greek Mythology. Apollo was the God of light.\n<|im_end|>" }, { "id": "#4284", "title": "Cheers", "fun": 2.15, "difficulty": 1.43, "author": "mad-ade", "desc": "Mad Ade is at a big dinner party with 67 other guests. After shaking hands with everyone, they all sit down at a large circular table. Mad Ade makes a toast and everyone clinks glasses with the person to their left. \n\r\nHow many clinks to the left were there in total?", "hint": "No hint available.", "answer": "68, there can only be one left sided clink per person, and there are 68 people there.", "category": "Logic", "date": "05/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade is at a big dinner party with 67 other guests. After shaking hands with everyone, they all sit down at a large circular table. Mad Ade makes a toast and everyone clinks glasses with the person to their left. \n\r\nHow many clinks to the left were there in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n68, there can only be one left sided clink per person, and there are 68 people there.\n<|im_start|>answer\n68, there can only be one left sided clink per person, and there are 68 people there.\n<|im_end|>" }, { "id": "#4324", "title": "Strange Currency", "fun": 2.15, "difficulty": 1.79, "author": "mad-ade", "desc": "In the legendary country of MADADIA there was a unique form of currency, consisting of Wobbles, Chobbles and Pobbles. If 2 wobbles are worth 3 chobbles, and 4 chobbles are worth 1 pobble, then 6 pobbles are worth how many wobbles?", "hint": "No hint available.", "answer": "It is given that \r\n2 wobbles = 3 chobbles \r\n8 wobbles = 12 chobbles ----- (I) \n\r\nAlso, given that \r\n4 chobbles = 1 pobble \r\n12 chobbles = 3 pobbles \r\n8 wobbles = 3 pobbles ----- From (I) \n\r\nTherefore, \r\n6 pobbles = 16 wobbles", "category": "Math", "date": "05/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the legendary country of MADADIA there was a unique form of currency, consisting of Wobbles, Chobbles and Pobbles. If 2 wobbles are worth 3 chobbles, and 4 chobbles are worth 1 pobble, then 6 pobbles are worth how many wobbles?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt is given that \r\n2 wobbles = 3 chobbles \r\n8 wobbles = 12 chobbles ----- (I) \n\r\nAlso, given that \r\n4 chobbles = 1 pobble \r\n12 chobbles = 3 pobbles \r\n8 wobbles = 3 pobbles ----- From (I) \n\r\nTherefore, \r\n6 pobbles = 16 wobbles\n<|im_start|>answer\nIt is given that \r\n2 wobbles = 3 chobbles \r\n8 wobbles = 12 chobbles ----- (I) \n\r\nAlso, given that \r\n4 chobbles = 1 pobble \r\n12 chobbles = 3 pobbles \r\n8 wobbles = 3 pobbles ----- From (I) \n\r\nTherefore, \r\n6 pobbles = 16 wobbles\n<|im_end|>" }, { "id": "#49973", "title": "Gone Fishing", "fun": 2.15, "difficulty": 0.41000000000000003, "author": "Hercules", "desc": "Sam, Harry, and Alicia all went on a fishing trip. One fish was caught at 9:00 am, one at 8:45 am, and one at 9:30 am. Three types of fish were caught: tuna, bass, and mackerel. Can you figure out who caught what fish and at what time?\n\r\nClues are as follows:\n\r\n1. Sam didn't catch the mackerel.\r\n2. Harry fell asleep after Sam and Alicia caught their fish, only to be surprised with a bite.\r\n3. Alicia made fun of her comrade for catching a tiny tuna fish.\r\n4. Sam didn't get the first catch.\r\n5. Harry was proud of his fish, which wasn't a mackerel.\r\n6. The tuna was caught third.", "hint": "No hint available.", "answer": "Harry caught the tuna at 9:30.\r\nSam caught the bass at 9:00.\r\nAlicia caught the mackerel at 8:45.", "category": "Logic-Grid", "date": "10/13/13", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSam, Harry, and Alicia all went on a fishing trip. One fish was caught at 9:00 am, one at 8:45 am, and one at 9:30 am. Three types of fish were caught: tuna, bass, and mackerel. Can you figure out who caught what fish and at what time?\n\r\nClues are as follows:\n\r\n1. Sam didn't catch the mackerel.\r\n2. Harry fell asleep after Sam and Alicia caught their fish, only to be surprised with a bite.\r\n3. Alicia made fun of her comrade for catching a tiny tuna fish.\r\n4. Sam didn't get the first catch.\r\n5. Harry was proud of his fish, which wasn't a mackerel.\r\n6. The tuna was caught third.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry caught the tuna at 9:30.\r\nSam caught the bass at 9:00.\r\nAlicia caught the mackerel at 8:45.\n<|im_start|>answer\nHarry caught the tuna at 9:30.\r\nSam caught the bass at 9:00.\r\nAlicia caught the mackerel at 8:45.\n<|im_end|>" }, { "id": "#38941", "title": "College Football Scramble", "fun": 2.15, "difficulty": 0.9, "author": "onua9159", "desc": "The results of the season have been scrambled! Help reorganize everything!\n\r\nFour Teams - Ohio State, Florida, USC, LSU\r\nFour Quarterbacks - John Throw, Fred Passer, Joe Accurate, Hugh Rusher\r\nFinal Rankings - 1st, 2nd, 3rd, 4th\n\r\nClues:\n\r\n1. Florida finished 4th.\r\n2. John Throw plays in his hometown, close to the Hollywood sign.\r\n3. LSU finished higher than Florida, but lower than USC, who did not finish first.\r\n4. Joe Accurate played on the team that finished 1st.\r\n5. Hugh Rusher plays for Florida.", "hint": "The Hollywood sign is located in Los Angeles, California.", "answer": "Ohio State finished 1st with QB Joe Accurate.\r\nUSC finished 2nd with QB John Throw.\r\nLSU finished 3rd with QB Fred Passer.\r\nFlorida finished 4th with QB Hugh Rusher.", "category": "Logic-Grid", "date": "10/25/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe results of the season have been scrambled! Help reorganize everything!\n\r\nFour Teams - Ohio State, Florida, USC, LSU\r\nFour Quarterbacks - John Throw, Fred Passer, Joe Accurate, Hugh Rusher\r\nFinal Rankings - 1st, 2nd, 3rd, 4th\n\r\nClues:\n\r\n1. Florida finished 4th.\r\n2. John Throw plays in his hometown, close to the Hollywood sign.\r\n3. LSU finished higher than Florida, but lower than USC, who did not finish first.\r\n4. Joe Accurate played on the team that finished 1st.\r\n5. Hugh Rusher plays for Florida.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOhio State finished 1st with QB Joe Accurate.\r\nUSC finished 2nd with QB John Throw.\r\nLSU finished 3rd with QB Fred Passer.\r\nFlorida finished 4th with QB Hugh Rusher.\n<|im_start|>answer\nOhio State finished 1st with QB Joe Accurate.\r\nUSC finished 2nd with QB John Throw.\r\nLSU finished 3rd with QB Fred Passer.\r\nFlorida finished 4th with QB Hugh Rusher.\n<|im_end|>" }, { "id": "#1776", "title": "7 7 7 7 7 7 7 7=14", "fun": 2.15, "difficulty": 1.59, "author": "jokester8000", "desc": "Fill in the blanks using addition, subtraction, multiplication and division signs, using each sign at least once, to make the equation true:\n\r\n7 7 7 7 7 7 7 7=14", "hint": "No hint available.", "answer": "7+7+7/7*7-7-7+7=14", "category": "Math", "date": "12/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFill in the blanks using addition, subtraction, multiplication and division signs, using each sign at least once, to make the equation true:\n\r\n7 7 7 7 7 7 7 7=14\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7+7+7/7*7-7-7+7=14\n<|im_start|>answer\n7+7+7/7*7-7-7+7=14\n<|im_end|>" }, { "id": "#19174", "title": "Ages Ago My Age ...", "fun": 2.15, "difficulty": 2.19, "author": "lesternoronha1", "desc": "My friend Rupesh said to me: \"Five years ago, the sum of my age and my son's age was a third of five times the average of the present ages of my son and myself.\" If the son will be 15 years old in 5 years time, how old is Rupesh now?", "hint": "No hint available.", "answer": "Rupesh's present age is 50 years.\n\r\nLet the ages of Rupesh and his son 5 years ago be R and S respectively.\n\r\nThe from the statement of Rupesh which states that \"Five years ago, the sum of my age and my son's age was a third of five times the average of the present ages of my son and myself.\", we can write\n\r\nR+S = (1/3)*(5)*(R+5+S+5)/2 \r\nR+S = (5/3)* (R+S+10)/2\r\nR+S = (5/6)*(R+S+10)\n\r\nIt is also given in the problem that the son will be 15 years old in 5 years time \r\ni.e., S+10 = 15. or S = 5 years.\n\r\nSubstituting the value of S in the above equation we get,\r\nR+5 = (5/6)*(R+5+10) \r\nR+5 = (5/6)*(R+15)\r\n6R+30 = 5R+75\r\nR = 45 years.\r\nThis was Rupesh's age 5 years ago.\r\nHence his age today is 45 + 5 \r\n= 50 years.", "category": "Math", "date": "10/17/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy friend Rupesh said to me: \"Five years ago, the sum of my age and my son's age was a third of five times the average of the present ages of my son and myself.\" If the son will be 15 years old in 5 years time, how old is Rupesh now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRupesh's present age is 50 years.\n\r\nLet the ages of Rupesh and his son 5 years ago be R and S respectively.\n\r\nThe from the statement of Rupesh which states that \"Five years ago, the sum of my age and my son's age was a third of five times the average of the present ages of my son and myself.\", we can write\n\r\nR+S = (1/3)*(5)*(R+5+S+5)/2 \r\nR+S = (5/3)* (R+S+10)/2\r\nR+S = (5/6)*(R+S+10)\n\r\nIt is also given in the problem that the son will be 15 years old in 5 years time \r\ni.e., S+10 = 15. or S = 5 years.\n\r\nSubstituting the value of S in the above equation we get,\r\nR+5 = (5/6)*(R+5+10) \r\nR+5 = (5/6)*(R+15)\r\n6R+30 = 5R+75\r\nR = 45 years.\r\nThis was Rupesh's age 5 years ago.\r\nHence his age today is 45 + 5 \r\n= 50 years.\n<|im_start|>answer\nRupesh's present age is 50 years.\n\r\nLet the ages of Rupesh and his son 5 years ago be R and S respectively.\n\r\nThe from the statement of Rupesh which states that \"Five years ago, the sum of my age and my son's age was a third of five times the average of the present ages of my son and myself.\", we can write\n\r\nR+S = (1/3)*(5)*(R+5+S+5)/2 \r\nR+S = (5/3)* (R+S+10)/2\r\nR+S = (5/6)*(R+S+10)\n\r\nIt is also given in the problem that the son will be 15 years old in 5 years time \r\ni.e., S+10 = 15. or S = 5 years.\n\r\nSubstituting the value of S in the above equation we get,\r\nR+5 = (5/6)*(R+5+10) \r\nR+5 = (5/6)*(R+15)\r\n6R+30 = 5R+75\r\nR = 45 years.\r\nThis was Rupesh's age 5 years ago.\r\nHence his age today is 45 + 5 \r\n= 50 years.\n<|im_end|>" }, { "id": "#11129", "title": "Madadian Motor Cars", "fun": 2.15, "difficulty": 2.46, "author": "mad-ade", "desc": "Madadian Multi-Squillionaire Sheik Ratelunroll has bought four prestige cars from the Madadian Motor Company (MMC) - The Silver Dream, The Golden Pleasure, The Devine Lightning, and a The Rusting Bucket, - as presents for his sons' birthdays, all of which are next week (strange things like this happen in Madadia all the time). Given the following information, what will each son get? \n\r\n1, Derek will not get The Golden Pleasure unless Berrick gets The Silver Dream and Eric gets The Rusting Bucket. \n\r\n2, Berrick will not get The Rusting Bucket unless Merick gets The Devine Lightning and Derek gets The Silver Dream. \n\r\n3, Eric will not get The Devine Lightning unless Derek gets The Golden Pleasure and Berrick gets The Silver Dream. \n\r\n4, Derek will not get The Silver Dream unless Merick gets The Devine Lightning and Eric gets The Rusting Bucket. \n\r\n5, Berrick will not get The Silver Dream unless Derek gets The Devine Lightning and Eric gets The Rusting Bucket. \n\r\n6, Derek will not get The Devine Lightning unless Berrick gets The Golden Pleasure and Merick gets The Silver Dream. \n\r\n7, Merick will not get The Devine Lightning unless Berrick gets The Golden Pleasure and Derek gets The Rusting Bucket. \n\r\n8, Derek will not get The Rusting Bucket unless Berrick gets The Devine Lightning and Eric gets The Golden Pleasure. \n\r\n9, Merick will not get The Silver Dream unless Eric gets The Golden Pleasure.", "hint": "No hint available.", "answer": "Starting with the simplest requirement, #9, assume that Eric does in fact get The Golden Pleasure, then Merick gets The Silver Dream. This leaves The Rusting Bucket and The Devine Lightning for Berrick and Derek. Going to rule #8, Eric already has The Golden Pleasure, so if Berrick gets The Devine Lightning, then Derek can have The Rusting Bucket. This gives us the following that complies with rules 8 & 9: \n\r\nEric = The Golden Pleasure \r\nMerick = The Silver Dream \r\nBerrick = The Devine Lightning \r\nDerek = The Rusting Bucket \n\r\nNow, to see if this works, just check it out against rules 1 through 7, where you'll find no rules are violated and everyone's happy except Derek who got stuck with The Rusting Bucket.", "category": "Logic", "date": "03/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMadadian Multi-Squillionaire Sheik Ratelunroll has bought four prestige cars from the Madadian Motor Company (MMC) - The Silver Dream, The Golden Pleasure, The Devine Lightning, and a The Rusting Bucket, - as presents for his sons' birthdays, all of which are next week (strange things like this happen in Madadia all the time). Given the following information, what will each son get? \n\r\n1, Derek will not get The Golden Pleasure unless Berrick gets The Silver Dream and Eric gets The Rusting Bucket. \n\r\n2, Berrick will not get The Rusting Bucket unless Merick gets The Devine Lightning and Derek gets The Silver Dream. \n\r\n3, Eric will not get The Devine Lightning unless Derek gets The Golden Pleasure and Berrick gets The Silver Dream. \n\r\n4, Derek will not get The Silver Dream unless Merick gets The Devine Lightning and Eric gets The Rusting Bucket. \n\r\n5, Berrick will not get The Silver Dream unless Derek gets The Devine Lightning and Eric gets The Rusting Bucket. \n\r\n6, Derek will not get The Devine Lightning unless Berrick gets The Golden Pleasure and Merick gets The Silver Dream. \n\r\n7, Merick will not get The Devine Lightning unless Berrick gets The Golden Pleasure and Derek gets The Rusting Bucket. \n\r\n8, Derek will not get The Rusting Bucket unless Berrick gets The Devine Lightning and Eric gets The Golden Pleasure. \n\r\n9, Merick will not get The Silver Dream unless Eric gets The Golden Pleasure.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStarting with the simplest requirement, #9, assume that Eric does in fact get The Golden Pleasure, then Merick gets The Silver Dream. This leaves The Rusting Bucket and The Devine Lightning for Berrick and Derek. Going to rule #8, Eric already has The Golden Pleasure, so if Berrick gets The Devine Lightning, then Derek can have The Rusting Bucket. This gives us the following that complies with rules 8 & 9: \n\r\nEric = The Golden Pleasure \r\nMerick = The Silver Dream \r\nBerrick = The Devine Lightning \r\nDerek = The Rusting Bucket \n\r\nNow, to see if this works, just check it out against rules 1 through 7, where you'll find no rules are violated and everyone's happy except Derek who got stuck with The Rusting Bucket.\n<|im_start|>answer\nStarting with the simplest requirement, #9, assume that Eric does in fact get The Golden Pleasure, then Merick gets The Silver Dream. This leaves The Rusting Bucket and The Devine Lightning for Berrick and Derek. Going to rule #8, Eric already has The Golden Pleasure, so if Berrick gets The Devine Lightning, then Derek can have The Rusting Bucket. This gives us the following that complies with rules 8 & 9: \n\r\nEric = The Golden Pleasure \r\nMerick = The Silver Dream \r\nBerrick = The Devine Lightning \r\nDerek = The Rusting Bucket \n\r\nNow, to see if this works, just check it out against rules 1 through 7, where you'll find no rules are violated and everyone's happy except Derek who got stuck with The Rusting Bucket.\n<|im_end|>" }, { "id": "#18223", "title": "CD Sale", "fun": 2.15, "difficulty": 1.93, "author": "Therulerofthem", "desc": "There was a sale going on at the CD store. To make it easier for the store, they needed to find out how many CDs were in each different style of music. 25% were blues, 15% were pop, 25% were classical and 15% were rock. The remaining 24 CD's are jazz. \r\nHow many CDs are in each style? \r\nHow many CDs are there in total?", "hint": "No hint available.", "answer": "First you add up the percents: \r\n25% + 15% + 25% + 15% = 80% \n\r\nSubtract 80% from 100% to get 20% (the percentage of jazz CDs). \n\r\nDivide 24 by 20 to get 1.2 (that is, 1% corresponds to 1.2 CDs) then multiply the percentages by 1.2 to get how many CDs are in each musical style. \r\nBlues: 25% x 1.2 = 30 CDs \r\nPop: 15% x 1.2 = 18 CDs \r\nClassical: 25% x 1.2 = 30 CDs \r\nRock: 15% x 1.2 = 18 CDs \r\nThese are the answers to the first question. \n\r\nTo find the second answer: \r\n30 + 18 + 30 + 18 + 24 = 120 CDs in total.", "category": "Math", "date": "07/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere was a sale going on at the CD store. To make it easier for the store, they needed to find out how many CDs were in each different style of music. 25% were blues, 15% were pop, 25% were classical and 15% were rock. The remaining 24 CD's are jazz. \r\nHow many CDs are in each style? \r\nHow many CDs are there in total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst you add up the percents: \r\n25% + 15% + 25% + 15% = 80% \n\r\nSubtract 80% from 100% to get 20% (the percentage of jazz CDs). \n\r\nDivide 24 by 20 to get 1.2 (that is, 1% corresponds to 1.2 CDs) then multiply the percentages by 1.2 to get how many CDs are in each musical style. \r\nBlues: 25% x 1.2 = 30 CDs \r\nPop: 15% x 1.2 = 18 CDs \r\nClassical: 25% x 1.2 = 30 CDs \r\nRock: 15% x 1.2 = 18 CDs \r\nThese are the answers to the first question. \n\r\nTo find the second answer: \r\n30 + 18 + 30 + 18 + 24 = 120 CDs in total.\n<|im_start|>answer\nFirst you add up the percents: \r\n25% + 15% + 25% + 15% = 80% \n\r\nSubtract 80% from 100% to get 20% (the percentage of jazz CDs). \n\r\nDivide 24 by 20 to get 1.2 (that is, 1% corresponds to 1.2 CDs) then multiply the percentages by 1.2 to get how many CDs are in each musical style. \r\nBlues: 25% x 1.2 = 30 CDs \r\nPop: 15% x 1.2 = 18 CDs \r\nClassical: 25% x 1.2 = 30 CDs \r\nRock: 15% x 1.2 = 18 CDs \r\nThese are the answers to the first question. \n\r\nTo find the second answer: \r\n30 + 18 + 30 + 18 + 24 = 120 CDs in total.\n<|im_end|>" }, { "id": "#4808", "title": "Pocket Money", "fun": 2.15, "difficulty": 1.65, "author": "mad-ade", "desc": "Mad Ade's Uncle \"Hugh J'Nobonim\" has 11 Children, to whom he distributes exactly $9.00 a week in pocket money. He gives his sons 50p a week, while his lucky daughters receive $1 a week. How many sons and how many daughters does he have?", "hint": "No hint available.", "answer": "He has 4 boys and 7 girls.", "category": "Math", "date": "06/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Uncle \"Hugh J'Nobonim\" has 11 Children, to whom he distributes exactly $9.00 a week in pocket money. He gives his sons 50p a week, while his lucky daughters receive $1 a week. How many sons and how many daughters does he have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe has 4 boys and 7 girls.\n<|im_start|>answer\nHe has 4 boys and 7 girls.\n<|im_end|>" }, { "id": "#5194", "title": "Price Difference", "fun": 2.15, "difficulty": 2.41, "author": "cpfc", "desc": "Nick has always wanted one, so he goes out and buys a brand new one for £5000. Unfortunately the next day he breaks it, so he goes out again and gets another brand new one. This time however, it only costs him £25. The next day someone offers to buy it off of him for £6000. \n\r\nWhat is it ?", "hint": "No hint available.", "answer": "A personalised number plate.", "category": "Logic", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNick has always wanted one, so he goes out and buys a brand new one for £5000. Unfortunately the next day he breaks it, so he goes out again and gets another brand new one. This time however, it only costs him £25. The next day someone offers to buy it off of him for £6000. \n\r\nWhat is it ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA personalised number plate.\n<|im_start|>answer\nA personalised number plate.\n<|im_end|>" }, { "id": "#3727", "title": "Half Empty - Half Full", "fun": 2.14, "difficulty": 1.57, "author": "fruitloop986", "desc": "Is the glass half empty or half full? \n\r\nOne of those never ending questions?", "hint": "There is always an answer to a question. Even if it is wrong or right there's always an answer.", "answer": "Both.\r\nhalf empty- if someone drank some, spilled or dumped some, because it was full to start.\r\nhalf full- if someone puts some thing in the glass, because it was empty to start.", "category": "Logic", "date": "04/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIs the glass half empty or half full? \n\r\nOne of those never ending questions?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBoth.\r\nhalf empty- if someone drank some, spilled or dumped some, because it was full to start.\r\nhalf full- if someone puts some thing in the glass, because it was empty to start.\n<|im_start|>answer\nBoth.\r\nhalf empty- if someone drank some, spilled or dumped some, because it was full to start.\r\nhalf full- if someone puts some thing in the glass, because it was empty to start.\n<|im_end|>" }, { "id": "#2295", "title": "Odd Ball", "fun": 2.14, "difficulty": 2.62, "author": "tommo", "desc": "You are given 14 balls, one of which is marked as a reference ball. 12 of the other balls are the same weight as the reference ball but the other ball may be slightly heavier, slightly lighter or the same weight as the reference ball. Using a balance scale how can you determine which is the odd ball, if any, with just three weighings?", "hint": "No hint available.", "answer": "Split the 14 balls into three groups: one of 4 unknown balls, one of 5 unknown balls and one of 4 unknown plus the reference ball.\n\r\n1st balance: Balance the two groups of 5 balls.\r\na) If the balance is not equal, designate the heavy side balls H and the light side balls L. The group of 4 unbalanced balls must be good balls.\n\r\n If the 5 unknown is heavier (5 H > 4 L + ref): take the ref ball, one H, and two L's, and place to one side.\n\r\n2nd balance: Balance the remaining balls like this: 2H+L against 2H+L.\r\na) If the balance is equal, then one of the two L's placed to one side is a light ball or the H placed to one side is a heavy ball. \r\n3rd balance: Balance the two L's against each other. If unequal, the lighter side is a light ball. If equal, the H is a heavy ball.\r\nb) If the 2nd balance is not equal, then either the 2H has the heavy ball or the opposing L is light.\r\n3rd balance: Balance the two H balls from the heavier side against each other. If equal, then L is a light ball. If not, the heavier H is a heavy ball. \n\r\n If the 5 unknown is lighter (5 L > 4 H + ref): take the ref ball, one L, and two H's, and place to one side.\n\r\n2nd balance: Balance the remaining balls like this: 2L+H against 2L+H.\r\na) If the balance is equal, then one of the two H's placed to one side is a heavy ball or the L placed to one side is a light ball. \r\n3rd balance: Balance the two H's against each other. If unequal, the heavier side is a heavy ball. If equal, the L is a light ball.\r\nb) If the 2nd balance is not equal, then either the 2L has the light ball or the opposing H is heavy.\r\n3rd balance: Balance the two L balls from the lighter side against each other. If equal, then the H is a heavy ball. If not, the lighter L is a light ball.\n\r\nb) If the first balance is equal, then the odd ball could be in the group of 4 unknown balls. The other 10 must all be good balls.\n\r\n2nd balance: Place one of the 4 unknown balls to one side and balance the remaining three against three good reference balls from the 10 good balls.\r\n\ta) If the balance is equal, then the ball placed to one side could be the odd ball.\r\n\t3rd balance: Balance this ball against a reference to determine if it's good or not.\r\n\tb) If the 3 unknown are heavier then: 3rd balance: balance two of the three balls against each other. If equal, the unbalanced ball is heavy. If not equal, the heavy side has a heavy ball. \r\nc) If the 3 unknown are lighter then:\r\n3rd balance: balance two of the three balls against each other. If equal, the unbalanced ball is lighter. If not, equal the lighter side has a lighter ball.", "category": "Logic", "date": "02/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are given 14 balls, one of which is marked as a reference ball. 12 of the other balls are the same weight as the reference ball but the other ball may be slightly heavier, slightly lighter or the same weight as the reference ball. Using a balance scale how can you determine which is the odd ball, if any, with just three weighings?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSplit the 14 balls into three groups: one of 4 unknown balls, one of 5 unknown balls and one of 4 unknown plus the reference ball.\n\r\n1st balance: Balance the two groups of 5 balls.\r\na) If the balance is not equal, designate the heavy side balls H and the light side balls L. The group of 4 unbalanced balls must be good balls.\n\r\n If the 5 unknown is heavier (5 H > 4 L + ref): take the ref ball, one H, and two L's, and place to one side.\n\r\n2nd balance: Balance the remaining balls like this: 2H+L against 2H+L.\r\na) If the balance is equal, then one of the two L's placed to one side is a light ball or the H placed to one side is a heavy ball. \r\n3rd balance: Balance the two L's against each other. If unequal, the lighter side is a light ball. If equal, the H is a heavy ball.\r\nb) If the 2nd balance is not equal, then either the 2H has the heavy ball or the opposing L is light.\r\n3rd balance: Balance the two H balls from the heavier side against each other. If equal, then L is a light ball. If not, the heavier H is a heavy ball. \n\r\n If the 5 unknown is lighter (5 L > 4 H + ref): take the ref ball, one L, and two H's, and place to one side.\n\r\n2nd balance: Balance the remaining balls like this: 2L+H against 2L+H.\r\na) If the balance is equal, then one of the two H's placed to one side is a heavy ball or the L placed to one side is a light ball. \r\n3rd balance: Balance the two H's against each other. If unequal, the heavier side is a heavy ball. If equal, the L is a light ball.\r\nb) If the 2nd balance is not equal, then either the 2L has the light ball or the opposing H is heavy.\r\n3rd balance: Balance the two L balls from the lighter side against each other. If equal, then the H is a heavy ball. If not, the lighter L is a light ball.\n\r\nb) If the first balance is equal, then the odd ball could be in the group of 4 unknown balls. The other 10 must all be good balls.\n\r\n2nd balance: Place one of the 4 unknown balls to one side and balance the remaining three against three good reference balls from the 10 good balls.\r\n\ta) If the balance is equal, then the ball placed to one side could be the odd ball.\r\n\t3rd balance: Balance this ball against a reference to determine if it's good or not.\r\n\tb) If the 3 unknown are heavier then: 3rd balance: balance two of the three balls against each other. If equal, the unbalanced ball is heavy. If not equal, the heavy side has a heavy ball. \r\nc) If the 3 unknown are lighter then:\r\n3rd balance: balance two of the three balls against each other. If equal, the unbalanced ball is lighter. If not, equal the lighter side has a lighter ball.\n<|im_start|>answer\nSplit the 14 balls into three groups: one of 4 unknown balls, one of 5 unknown balls and one of 4 unknown plus the reference ball.\n\r\n1st balance: Balance the two groups of 5 balls.\r\na) If the balance is not equal, designate the heavy side balls H and the light side balls L. The group of 4 unbalanced balls must be good balls.\n\r\n If the 5 unknown is heavier (5 H > 4 L + ref): take the ref ball, one H, and two L's, and place to one side.\n\r\n2nd balance: Balance the remaining balls like this: 2H+L against 2H+L.\r\na) If the balance is equal, then one of the two L's placed to one side is a light ball or the H placed to one side is a heavy ball. \r\n3rd balance: Balance the two L's against each other. If unequal, the lighter side is a light ball. If equal, the H is a heavy ball.\r\nb) If the 2nd balance is not equal, then either the 2H has the heavy ball or the opposing L is light.\r\n3rd balance: Balance the two H balls from the heavier side against each other. If equal, then L is a light ball. If not, the heavier H is a heavy ball. \n\r\n If the 5 unknown is lighter (5 L > 4 H + ref): take the ref ball, one L, and two H's, and place to one side.\n\r\n2nd balance: Balance the remaining balls like this: 2L+H against 2L+H.\r\na) If the balance is equal, then one of the two H's placed to one side is a heavy ball or the L placed to one side is a light ball. \r\n3rd balance: Balance the two H's against each other. If unequal, the heavier side is a heavy ball. If equal, the L is a light ball.\r\nb) If the 2nd balance is not equal, then either the 2L has the light ball or the opposing H is heavy.\r\n3rd balance: Balance the two L balls from the lighter side against each other. If equal, then the H is a heavy ball. If not, the lighter L is a light ball.\n\r\nb) If the first balance is equal, then the odd ball could be in the group of 4 unknown balls. The other 10 must all be good balls.\n\r\n2nd balance: Place one of the 4 unknown balls to one side and balance the remaining three against three good reference balls from the 10 good balls.\r\n\ta) If the balance is equal, then the ball placed to one side could be the odd ball.\r\n\t3rd balance: Balance this ball against a reference to determine if it's good or not.\r\n\tb) If the 3 unknown are heavier then: 3rd balance: balance two of the three balls against each other. If equal, the unbalanced ball is heavy. If not equal, the heavy side has a heavy ball. \r\nc) If the 3 unknown are lighter then:\r\n3rd balance: balance two of the three balls against each other. If equal, the unbalanced ball is lighter. If not, equal the lighter side has a lighter ball.\n<|im_end|>" }, { "id": "#1723", "title": "A Pleasing Number", "fun": 2.14, "difficulty": 2.9, "author": "Nishoo", "desc": "Which two closest together whole numbers that, when multiplied, produce the pleasant looking number: 1234567890 ?", "hint": "No hint available.", "answer": "34,227 and 36,070.\n\r\nThe only factors of 1234567890 are 2, 3, 3, 5, 3607 and 3803. Testing the various products of these factors reveals that 34,227 and 36,070 are the closest pair of numbers that produce 1234567890.", "category": "Math", "date": "12/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich two closest together whole numbers that, when multiplied, produce the pleasant looking number: 1234567890 ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n34,227 and 36,070.\n\r\nThe only factors of 1234567890 are 2, 3, 3, 5, 3607 and 3803. Testing the various products of these factors reveals that 34,227 and 36,070 are the closest pair of numbers that produce 1234567890.\n<|im_start|>answer\n34,227 and 36,070.\n\r\nThe only factors of 1234567890 are 2, 3, 3, 5, 3607 and 3803. Testing the various products of these factors reveals that 34,227 and 36,070 are the closest pair of numbers that produce 1234567890.\n<|im_end|>" }, { "id": "#13054", "title": "Making 24", "fun": 2.14, "difficulty": 2.3, "author": "heather777", "desc": "Try using any operation you want to make the each set of four numbers equal 24. You have to use all four numbers. You can rearrange the numbers if you need to. \n\r\n1. 2, 4, 3, 9\r\n2. 5, 1, 3, 2\r\n3. 4, 5, 6, 2\r\n4. 2, 5, 2, 1\r\n5. 8, 4, 8, 7\r\n6. -3, 6, -2, -4", "hint": "No hint available.", "answer": "1. (2x4x9)/3\r\n2. 5(2+3)-1 \r\n3. (5x6)-2-4\r\n4. (5+1)x(2x2)\r\n5. (8x7)-(8x4)\r\n6. (-3+6)x(-2x-4)", "category": "Math", "date": "06/11/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTry using any operation you want to make the each set of four numbers equal 24. You have to use all four numbers. You can rearrange the numbers if you need to. \n\r\n1. 2, 4, 3, 9\r\n2. 5, 1, 3, 2\r\n3. 4, 5, 6, 2\r\n4. 2, 5, 2, 1\r\n5. 8, 4, 8, 7\r\n6. -3, 6, -2, -4\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. (2x4x9)/3\r\n2. 5(2+3)-1 \r\n3. (5x6)-2-4\r\n4. (5+1)x(2x2)\r\n5. (8x7)-(8x4)\r\n6. (-3+6)x(-2x-4)\n<|im_start|>answer\n1. (2x4x9)/3\r\n2. 5(2+3)-1 \r\n3. (5x6)-2-4\r\n4. (5+1)x(2x2)\r\n5. (8x7)-(8x4)\r\n6. (-3+6)x(-2x-4)\n<|im_end|>" }, { "id": "#19422", "title": "Power Play", "fun": 2.14, "difficulty": 2.97, "author": "jimrcook", "desc": "A four digit number (not beginning with 0) can be represented by ABCD. There is one number such that ABCD=A^B*C^D, where A^B means A raised to the B power. Can you find it?", "hint": "No hint available.", "answer": "The only number is 2592. 2^5 is 32 and 9^2 is 81. 32*81 is 2592.", "category": "Math", "date": "11/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA four digit number (not beginning with 0) can be represented by ABCD. There is one number such that ABCD=A^B*C^D, where A^B means A raised to the B power. Can you find it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe only number is 2592. 2^5 is 32 and 9^2 is 81. 32*81 is 2592.\n<|im_start|>answer\nThe only number is 2592. 2^5 is 32 and 9^2 is 81. 32*81 is 2592.\n<|im_end|>" }, { "id": "#35913", "title": "Karate Cows!", "fun": 2.14, "difficulty": 0.63, "author": "cowman12", "desc": "Cowman has became the new teacher of a karate class. He must meet the cow class, learn their breeds, and their belt color.\n\r\nStudents: Adam, Seth, Kyle\n\r\nBreeds: Hereford, Beefmaster, Canary Isle\n\r\nBelts: White, Red, Black\n\r\n1) The black belt is a Hereford.\n\r\n2) Seth is a red belt.\n\r\n3) Kyle is a Beefmaster.", "hint": "No hint available.", "answer": "Kyle-White Belt-Beefmaster\n\r\nSeth-Red Belt-Canary Isle\n\r\nAdam-Black Belt-Hereford", "category": "Logic-Grid", "date": "03/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCowman has became the new teacher of a karate class. He must meet the cow class, learn their breeds, and their belt color.\n\r\nStudents: Adam, Seth, Kyle\n\r\nBreeds: Hereford, Beefmaster, Canary Isle\n\r\nBelts: White, Red, Black\n\r\n1) The black belt is a Hereford.\n\r\n2) Seth is a red belt.\n\r\n3) Kyle is a Beefmaster.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKyle-White Belt-Beefmaster\n\r\nSeth-Red Belt-Canary Isle\n\r\nAdam-Black Belt-Hereford\n<|im_start|>answer\nKyle-White Belt-Beefmaster\n\r\nSeth-Red Belt-Canary Isle\n\r\nAdam-Black Belt-Hereford\n<|im_end|>" }, { "id": "#16654", "title": "Max Mars's First Caper", "fun": 2.14, "difficulty": 1.82, "author": "something", "desc": "When Max Mars was working for a living as a bootlegger, his customers brought him the barley, he would manufacture moonshine. Shady always took 10% of the whisky as his payment. One day, Sr. Amxam, Max Mars's best friend, received exactly one liter of whisky after Max had removed his fee. How much whisky was produced from Sam's barley before the fee was removed?", "hint": "No hint available.", "answer": ": There must have been one liter and 1/9th of a liter before shady removed his fee. Since one liter represents 90% of the total produced, we know that nine units will equal one liter. We also know that nine of Max's portions will equal one liter and therefore we can conclude that the total produced was one liter plus 1/9th of a liter.", "category": "Math", "date": "02/19/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Max Mars was working for a living as a bootlegger, his customers brought him the barley, he would manufacture moonshine. Shady always took 10% of the whisky as his payment. One day, Sr. Amxam, Max Mars's best friend, received exactly one liter of whisky after Max had removed his fee. How much whisky was produced from Sam's barley before the fee was removed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n: There must have been one liter and 1/9th of a liter before shady removed his fee. Since one liter represents 90% of the total produced, we know that nine units will equal one liter. We also know that nine of Max's portions will equal one liter and therefore we can conclude that the total produced was one liter plus 1/9th of a liter.\n<|im_start|>answer\n: There must have been one liter and 1/9th of a liter before shady removed his fee. Since one liter represents 90% of the total produced, we know that nine units will equal one liter. We also know that nine of Max's portions will equal one liter and therefore we can conclude that the total produced was one liter plus 1/9th of a liter.\n<|im_end|>" }, { "id": "#3661", "title": "Man Wrinkle", "fun": 2.14, "difficulty": 1.2, "author": "Angelicious", "desc": "Man Wrinkle spent 1/4 of his life as a boy,1/8 as a youth, and 1/2 as an active man.If Man Wrinkle spent 11 years as an old man, then how many years did he spend as an active man?", "hint": "Fraction of life spent by Man Wrinkle as an old man= 1-(1/4+1/8+1/2)=...", "answer": "44 years as an active man.", "category": "Math", "date": "04/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMan Wrinkle spent 1/4 of his life as a boy,1/8 as a youth, and 1/2 as an active man.If Man Wrinkle spent 11 years as an old man, then how many years did he spend as an active man?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n44 years as an active man.\n<|im_start|>answer\n44 years as an active man.\n<|im_end|>" }, { "id": "#4367", "title": "1990", "fun": 2.14, "difficulty": 2.67, "author": "arij", "desc": "Insert +, -, x or / in suitable places on the left hand side of = so as to make the equation true: \n\r\n999999999999999 = 1990", "hint": "No hint available.", "answer": "99 / 99 + 999 + 999 - 9 + 99 - 99 = 1990", "category": "Math", "date": "05/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nInsert +, -, x or / in suitable places on the left hand side of = so as to make the equation true: \n\r\n999999999999999 = 1990\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n99 / 99 + 999 + 999 - 9 + 99 - 99 = 1990\n<|im_start|>answer\n99 / 99 + 999 + 999 - 9 + 99 - 99 = 1990\n<|im_end|>" }, { "id": "#17972", "title": "Integers of a Feather", "fun": 2.14, "difficulty": 2.9, "author": "cnmne", "desc": "In the finite set of integers 1 through 50000000, the following six integers share a characteristic that no other integers in the set share. What is the characteristic?\n\r\n1, 36, 1225, 41616, 1413721, 48024900", "hint": "No hint available.", "answer": "They are the only triangle numbers that are also squares of whole numbers.\n\r\n1 = 1^2\r\n36 = 6^2\r\n1225 = 35^2\r\n41616 = 204^2\r\n1413721 = 1189^2\r\n48024900 = 6930^2", "category": "Math", "date": "06/21/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the finite set of integers 1 through 50000000, the following six integers share a characteristic that no other integers in the set share. What is the characteristic?\n\r\n1, 36, 1225, 41616, 1413721, 48024900\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey are the only triangle numbers that are also squares of whole numbers.\n\r\n1 = 1^2\r\n36 = 6^2\r\n1225 = 35^2\r\n41616 = 204^2\r\n1413721 = 1189^2\r\n48024900 = 6930^2\n<|im_start|>answer\nThey are the only triangle numbers that are also squares of whole numbers.\n\r\n1 = 1^2\r\n36 = 6^2\r\n1225 = 35^2\r\n41616 = 204^2\r\n1413721 = 1189^2\r\n48024900 = 6930^2\n<|im_end|>" }, { "id": "#18613", "title": "Madadian Kebabrie Cheese", "fun": 2.14, "difficulty": 2.5, "author": "mad-ade", "desc": "Mad Ade's Great Uncle Gaseous O' Windpants owned the Madadian Grocery store \"The Beggars Can't Be Choosers\". Madadia was well renowned for its pungent cheeses, especially its \"Kebabrie\" and \"Chillirella\".\r\nOn display in the store were six cheese pieces weighing 15, 16, 18, 19 , 20 and 31 Pounds. Five out of the six pieces are \"Kebabrie\" and the remaining one is \"Chillirella\".\r\nNorma Leigh-Sobar purchased two pieces of \"Kebabrie\" and Laura Anne-Hardy also purchased some \"Kebabrie\" , but she purchased twice as much in weight than Norma .\r\nHow much does the remaining \"Chillirella\" weigh?", "hint": "No hint available.", "answer": "Norma Leigh-Sobar must have purchased at least 31 pounds and so Laura Anne-Hardy must have bought three wedges since the two heaviest wedges together only total 51 pounds.\r\nSince Laura bought twice what Norma bought, the total amount of cheese bought by the two together equals 3 times that purchased by Norma alone. Now, the total weight of all the wedges at the grocery divided by 3 leaves a remainder of 2, so the \"Chillirella\" wedge must leave a remainder of 2 when divided by 3. But the only such wedge is the 20 pound wedge, thus the \"Chillirella\" wedge must have weighed 20 pounds.\r\nThus Norma purchased the 15 and 18 pound pieces which equals 33 pounds and Laura purchased the 16, 19 and 31 pound pieces which equals 66 pounds.", "category": "Logic", "date": "08/23/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade's Great Uncle Gaseous O' Windpants owned the Madadian Grocery store \"The Beggars Can't Be Choosers\". Madadia was well renowned for its pungent cheeses, especially its \"Kebabrie\" and \"Chillirella\".\r\nOn display in the store were six cheese pieces weighing 15, 16, 18, 19 , 20 and 31 Pounds. Five out of the six pieces are \"Kebabrie\" and the remaining one is \"Chillirella\".\r\nNorma Leigh-Sobar purchased two pieces of \"Kebabrie\" and Laura Anne-Hardy also purchased some \"Kebabrie\" , but she purchased twice as much in weight than Norma .\r\nHow much does the remaining \"Chillirella\" weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNorma Leigh-Sobar must have purchased at least 31 pounds and so Laura Anne-Hardy must have bought three wedges since the two heaviest wedges together only total 51 pounds.\r\nSince Laura bought twice what Norma bought, the total amount of cheese bought by the two together equals 3 times that purchased by Norma alone. Now, the total weight of all the wedges at the grocery divided by 3 leaves a remainder of 2, so the \"Chillirella\" wedge must leave a remainder of 2 when divided by 3. But the only such wedge is the 20 pound wedge, thus the \"Chillirella\" wedge must have weighed 20 pounds.\r\nThus Norma purchased the 15 and 18 pound pieces which equals 33 pounds and Laura purchased the 16, 19 and 31 pound pieces which equals 66 pounds.\n<|im_start|>answer\nNorma Leigh-Sobar must have purchased at least 31 pounds and so Laura Anne-Hardy must have bought three wedges since the two heaviest wedges together only total 51 pounds.\r\nSince Laura bought twice what Norma bought, the total amount of cheese bought by the two together equals 3 times that purchased by Norma alone. Now, the total weight of all the wedges at the grocery divided by 3 leaves a remainder of 2, so the \"Chillirella\" wedge must leave a remainder of 2 when divided by 3. But the only such wedge is the 20 pound wedge, thus the \"Chillirella\" wedge must have weighed 20 pounds.\r\nThus Norma purchased the 15 and 18 pound pieces which equals 33 pounds and Laura purchased the 16, 19 and 31 pound pieces which equals 66 pounds.\n<|im_end|>" }, { "id": "#38853", "title": "Two Dozen", "fun": 2.14, "difficulty": 1.94, "author": "Fire_Shell96", "desc": "Using the following digits, create the number 24.\n\r\n5,5,5,1\n\r\n(You may use each digit only once.)", "hint": "None", "answer": "5(5-1/5)", "category": "Math", "date": "10/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing the following digits, create the number 24.\n\r\n5,5,5,1\n\r\n(You may use each digit only once.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5(5-1/5)\n<|im_start|>answer\n5(5-1/5)\n<|im_end|>" }, { "id": "#1254", "title": "Pat", "fun": 2.14, "difficulty": 1.25, "author": "abes", "desc": "A man names his kid \"Pat the second\", and yet the man's name isn't Pat, so why did he name his kid this?", "hint": "No hint available.", "answer": "The child's mother's name was Pat.", "category": "Logic", "date": "11/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man names his kid \"Pat the second\", and yet the man's name isn't Pat, so why did he name his kid this?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe child's mother's name was Pat.\n<|im_start|>answer\nThe child's mother's name was Pat.\n<|im_end|>" }, { "id": "#1672", "title": "Tire Trouble", "fun": 2.14, "difficulty": 1.49, "author": "Boddo", "desc": "A police officer is chasing after a bank robber in his vehicle. The robber, who is in his getaway car, shoots out of the window and hits the officer's tire. The officer catches up and arrests the robber even though his tire had burst. How did he do it?", "hint": "No hint available.", "answer": "He shot the spare tire.", "category": "Logic", "date": "12/11/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA police officer is chasing after a bank robber in his vehicle. The robber, who is in his getaway car, shoots out of the window and hits the officer's tire. The officer catches up and arrests the robber even though his tire had burst. How did he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe shot the spare tire.\n<|im_start|>answer\nHe shot the spare tire.\n<|im_end|>" }, { "id": "#1019", "title": "Divided by Two", "fun": 2.14, "difficulty": 1.54, "author": "Michelle", "desc": "Which can be evenly divided by two?\n\r\n1 2 3 4 5 6 7 8 9", "hint": "No hint available.", "answer": "All of them. In the case of 7, it can be evenly divided into two parts, each being 3.5. Same goes for the other odd numbers.", "category": "Math", "date": "10/06/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich can be evenly divided by two?\n\r\n1 2 3 4 5 6 7 8 9\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAll of them. In the case of 7, it can be evenly divided into two parts, each being 3.5. Same goes for the other odd numbers.\n<|im_start|>answer\nAll of them. In the case of 7, it can be evenly divided into two parts, each being 3.5. Same goes for the other odd numbers.\n<|im_end|>" }, { "id": "#13260", "title": "Store 24", "fun": 2.14, "difficulty": 1.26, "author": "pooja", "desc": "Using six 1's and three plus signs, can you form an expression that equals to 24?", "hint": "Put all the one's together", "answer": "11 + 11 + 1 + 1 = 24", "category": "Math", "date": "06/18/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing six 1's and three plus signs, can you form an expression that equals to 24?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11 + 11 + 1 + 1 = 24\n<|im_start|>answer\n11 + 11 + 1 + 1 = 24\n<|im_end|>" }, { "id": "#14237", "title": "100 Percent", "fun": 2.14, "difficulty": 1.31, "author": "scoutman", "desc": "What two 2-digit numbers add up to 100 and together contain a digit that is present three times?", "hint": "If the numbers had to add up to 56, the answer would be 23 and 33. The 3 is present three times in these two numbers.", "answer": "45 and 55", "category": "Math", "date": "08/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat two 2-digit numbers add up to 100 and together contain a digit that is present three times?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n45 and 55\n<|im_start|>answer\n45 and 55\n<|im_end|>" }, { "id": "#13568", "title": "Who Hates Who?", "fun": 2.14, "difficulty": 1.27, "author": "funnyhunnie20", "desc": "Kayla, Jenna, Beth, and Shelby each hate one of Hannah, Chelsey, Jorden and Austin. Find out who hates who. \n\r\n1. Kayla does not hate Chelsey or Austin. \r\n2. Shelby and Austin are best friends. \r\n3. Jenna hates a male. \r\n4. Beth and Jorden are never apart! That's why Kayla is never with them. \r\n5. Hannah and Beth got in a HUGE fight last year and have never made up.", "hint": "No hint available.", "answer": "Kayla hates Jorden\r\nBeth hates Hannah\r\nShelby hates Chelsey \r\nJenna hates Austin", "category": "Logic", "date": "07/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKayla, Jenna, Beth, and Shelby each hate one of Hannah, Chelsey, Jorden and Austin. Find out who hates who. \n\r\n1. Kayla does not hate Chelsey or Austin. \r\n2. Shelby and Austin are best friends. \r\n3. Jenna hates a male. \r\n4. Beth and Jorden are never apart! That's why Kayla is never with them. \r\n5. Hannah and Beth got in a HUGE fight last year and have never made up.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKayla hates Jorden\r\nBeth hates Hannah\r\nShelby hates Chelsey \r\nJenna hates Austin\n<|im_start|>answer\nKayla hates Jorden\r\nBeth hates Hannah\r\nShelby hates Chelsey \r\nJenna hates Austin\n<|im_end|>" }, { "id": "#3911", "title": "Add and Multiply 1.5", "fun": 2.14, "difficulty": 1.51, "author": "mad-ade", "desc": "What number gives the same answer when added to or multiplied by 1.5?", "hint": "No hint available.", "answer": "3\r\n3+1.5= 4.5\r\n3x1.5= 4.5", "category": "Math", "date": "05/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number gives the same answer when added to or multiplied by 1.5?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3\r\n3+1.5= 4.5\r\n3x1.5= 4.5\n<|im_start|>answer\n3\r\n3+1.5= 4.5\r\n3x1.5= 4.5\n<|im_end|>" }, { "id": "#18334", "title": "Mall Madness", "fun": 2.14, "difficulty": 1.47, "author": "thebuddhawithin", "desc": "Elizabeth headed to the mall with $60. If she spends 1/4 of her money on clothes, $30 on CD's, and 10% of her original money pigging out at the food court, how much cash will she have left?", "hint": "No hint available.", "answer": "She will have nine dollars left.\n\r\nElizabeth spent $15 on clothes (1/4 of $60 = $15), $30 on CD's, and $6 on food (10% of $60 = $6). Add this together, and she spent a total of 51 dollars at the mall. Subtract this from her original 60, and she is left with $9.", "category": "Math", "date": "07/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nElizabeth headed to the mall with $60. If she spends 1/4 of her money on clothes, $30 on CD's, and 10% of her original money pigging out at the food court, how much cash will she have left?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe will have nine dollars left.\n\r\nElizabeth spent $15 on clothes (1/4 of $60 = $15), $30 on CD's, and $6 on food (10% of $60 = $6). Add this together, and she spent a total of 51 dollars at the mall. Subtract this from her original 60, and she is left with $9.\n<|im_start|>answer\nShe will have nine dollars left.\n\r\nElizabeth spent $15 on clothes (1/4 of $60 = $15), $30 on CD's, and $6 on food (10% of $60 = $6). Add this together, and she spent a total of 51 dollars at the mall. Subtract this from her original 60, and she is left with $9.\n<|im_end|>" }, { "id": "#2462", "title": "Golden Ratio", "fun": 2.14, "difficulty": 2.33, "author": "tommo", "desc": "Which positive number is equal to its inverse plus one?", "hint": "No hint available.", "answer": "x =1/x + 1\r\nx=1.61803398875", "category": "Math", "date": "02/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich positive number is equal to its inverse plus one?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nx =1/x + 1\r\nx=1.61803398875\n<|im_start|>answer\nx =1/x + 1\r\nx=1.61803398875\n<|im_end|>" }, { "id": "#4007", "title": "Doctors and Nurses", "fun": 2.14, "difficulty": 1.59, "author": "mad-ade", "desc": "If a hospital has 360 doctors and nurses, and the ratio of doctors to nurses is 7 to 11, how many nurses are there?", "hint": "No hint available.", "answer": "220", "category": "Math", "date": "05/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a hospital has 360 doctors and nurses, and the ratio of doctors to nurses is 7 to 11, how many nurses are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n220\n<|im_start|>answer\n220\n<|im_end|>" }, { "id": "#42633", "title": "4 X 4", "fun": 2.14, "difficulty": 2.86, "author": "chevybaby02", "desc": "Below there are sixteen numbers. Assuming that any three of the numbers may be drawn at random, what are the chances that three numbers will be drawn whose sum equals six? \n\r\n1 2 3 1\r\n2 3 1 2\r\n3 1 2 3\r\n1 2 3 1", "hint": "No hint available.", "answer": "This is a bit tricky and I initially thought the answer was 1/16 or 6.2% but it is really 2/7 or 28.6%. \n\r\nEither drawing '2 2 2' or some combination of '1 2 3' adds up to be 6. The chances of getting '2 2 2' are 5/16 (5 2s out of 16) times 4/15 (4 2s left out of 15) times 3/14 (3 2s left out of 14). This is 5/16 * 4/15 * 3/14 which equals 1/56. \n\r\nThe chances of getting some combination of '1 2 3' is equal to 6/16 (6 1s in the list) times 5/15 (5 2s out of 15 numbers left) times 5/14 (5 3s out of 14 numbers left) times the number of different combinations of '1 2 3' which is 6. This is 6/16 * 5/15 * 5/14 * 6 which equals 15/56. \n\r\n1/56 + 15/56 = 16/56 or 2/7 or ~28.6%.", "category": "Math", "date": "07/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBelow there are sixteen numbers. Assuming that any three of the numbers may be drawn at random, what are the chances that three numbers will be drawn whose sum equals six? \n\r\n1 2 3 1\r\n2 3 1 2\r\n3 1 2 3\r\n1 2 3 1\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis is a bit tricky and I initially thought the answer was 1/16 or 6.2% but it is really 2/7 or 28.6%. \n\r\nEither drawing '2 2 2' or some combination of '1 2 3' adds up to be 6. The chances of getting '2 2 2' are 5/16 (5 2s out of 16) times 4/15 (4 2s left out of 15) times 3/14 (3 2s left out of 14). This is 5/16 * 4/15 * 3/14 which equals 1/56. \n\r\nThe chances of getting some combination of '1 2 3' is equal to 6/16 (6 1s in the list) times 5/15 (5 2s out of 15 numbers left) times 5/14 (5 3s out of 14 numbers left) times the number of different combinations of '1 2 3' which is 6. This is 6/16 * 5/15 * 5/14 * 6 which equals 15/56. \n\r\n1/56 + 15/56 = 16/56 or 2/7 or ~28.6%.\n<|im_start|>answer\nThis is a bit tricky and I initially thought the answer was 1/16 or 6.2% but it is really 2/7 or 28.6%. \n\r\nEither drawing '2 2 2' or some combination of '1 2 3' adds up to be 6. The chances of getting '2 2 2' are 5/16 (5 2s out of 16) times 4/15 (4 2s left out of 15) times 3/14 (3 2s left out of 14). This is 5/16 * 4/15 * 3/14 which equals 1/56. \n\r\nThe chances of getting some combination of '1 2 3' is equal to 6/16 (6 1s in the list) times 5/15 (5 2s out of 15 numbers left) times 5/14 (5 3s out of 14 numbers left) times the number of different combinations of '1 2 3' which is 6. This is 6/16 * 5/15 * 5/14 * 6 which equals 15/56. \n\r\n1/56 + 15/56 = 16/56 or 2/7 or ~28.6%.\n<|im_end|>" }, { "id": "#18630", "title": "Mad Ade's Chess Problem Again", "fun": 2.14, "difficulty": 2.62, "author": "mad-ade", "desc": "Mad Ade was standing outside waiting as usual for the Sweaty Chef Kebab Shop to open and was staring into the shop window of the store next door. He noticed a chess set on display.\r\nHe wondered how many ways are there of arranging the sixteen black or white pieces of the chess set on the first two rows of the board? \r\nObviously, Mad Ade did not bother working it out as the Kebab shop opened almost immediately as he thought about it.\r\nWhat would have been the answer if Mad Ade wasn't so greedy and had worked it out?\n\n\r\nGiven that each pawn is identical and each rook, knight and bishop is identical to its pair.", "hint": "No hint available.", "answer": "For 16 pieces that are all different the answer is 16! (!=factorial ie. 16x15x14...x1) \n\r\nBut, we have duplicate combinations because there are identical pieces being used. The number of duplicate combinations is = \r\n2 (for Rooks) x 2 (for Knights) x 2(for Bishops) x 8! (for Pawns). \r\nThis gives 8x8! = 322560. \n\r\nDividing 16! by 322560 gives us the number of unique combinations for a normal chess set = 64864800 different ways.", "category": "Logic", "date": "08/24/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade was standing outside waiting as usual for the Sweaty Chef Kebab Shop to open and was staring into the shop window of the store next door. He noticed a chess set on display.\r\nHe wondered how many ways are there of arranging the sixteen black or white pieces of the chess set on the first two rows of the board? \r\nObviously, Mad Ade did not bother working it out as the Kebab shop opened almost immediately as he thought about it.\r\nWhat would have been the answer if Mad Ade wasn't so greedy and had worked it out?\n\n\r\nGiven that each pawn is identical and each rook, knight and bishop is identical to its pair.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor 16 pieces that are all different the answer is 16! (!=factorial ie. 16x15x14...x1) \n\r\nBut, we have duplicate combinations because there are identical pieces being used. The number of duplicate combinations is = \r\n2 (for Rooks) x 2 (for Knights) x 2(for Bishops) x 8! (for Pawns). \r\nThis gives 8x8! = 322560. \n\r\nDividing 16! by 322560 gives us the number of unique combinations for a normal chess set = 64864800 different ways.\n<|im_start|>answer\nFor 16 pieces that are all different the answer is 16! (!=factorial ie. 16x15x14...x1) \n\r\nBut, we have duplicate combinations because there are identical pieces being used. The number of duplicate combinations is = \r\n2 (for Rooks) x 2 (for Knights) x 2(for Bishops) x 8! (for Pawns). \r\nThis gives 8x8! = 322560. \n\r\nDividing 16! by 322560 gives us the number of unique combinations for a normal chess set = 64864800 different ways.\n<|im_end|>" }, { "id": "#19077", "title": "Gifting Away !", "fun": 2.14, "difficulty": 2.07, "author": "lesternoronha1", "desc": "Five gift boxes have to be prepared to be given to five of my nephews. I have 5 cakes, 6 toffees, 4 pastries and 3 toys. Each of the boxes should contain at least one cake, at least one toffee, at least 3 items and at the most 4 items. Pastry and toy cannot be in the same box. No box can contain two toys.\n\r\nWhich of the following must be true?\n\r\n1) Exactly one box should contain 2 toffees and 1 toy.\r\n2) Exactly one box should contain 2 toffees.\r\n3) Exactly one box should contain 2 pastries.\n\r\nNOTE: Out of the given set of 3 statements, it is not necessary that one and only one statement is true. One or more statements may be true.", "hint": "No hint available.", "answer": "Statements 1 and 2 are true.\n\r\nThe given statements are \r\n1) Exactly one box should contain 2 toffees and 1 toy.\r\n2) Exactly one box should contain 2 toffees.\r\n3) Exactly one box should contain 2 pastries.\n\r\nAlso the given observations are\r\nA) Each of the box should contain at least one cake, at least one toffee, at least 3 items and at the most 4 items.\r\nB) Pastry and toy cannot be in the same box.\r\nC) No box can contain two toys.\n\r\nUsing observations A and C, the following is the definite distribution to be made :-\n\r\nBoxes 1 2 3 4 5\n\r\nCake 1 1 1 1 1\r\nToffee 1 1 1 1 1\r\nPastry\r\nToy 1 1 1\n\r\nsince the cakes and toffees must follow observation A of at least 1 in each of the boxes and toys must follow observation C of no more than one toy in a box.\n\r\nWe have 4 pastries and 1 toffee remaining to be distributed to these 5 boxes.\n\r\nFrom observation B, since pastry and toy cannot be in the same box, the 4 pastries must go to boxes 4 and 5. Also in order to keep with the later part of observation A of at least 3 items and at most 4 items, these four pastries must be packed 2 each into boxes 4 and 5.\n\r\nThe remaining toffee must go into one of the three boxes 1, 2 or 3. Let us assume that this toffee goes to box 1.\n\r\nHence the final distribution is as follows :-\n\r\nBoxes 1 2 3 4 5\n\r\nCake 1 1 1 1 1\r\nToffee 2 1 1 1 1\r\nPastry 2 2\r\nToy 1 1 1\n\r\nComparing the given statements with the above distribution we can see that statements 1 and 2 are true since they refer to box 1 and statement 3 is false because more than one box is available with two pastries.", "category": "Logic", "date": "10/07/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive gift boxes have to be prepared to be given to five of my nephews. I have 5 cakes, 6 toffees, 4 pastries and 3 toys. Each of the boxes should contain at least one cake, at least one toffee, at least 3 items and at the most 4 items. Pastry and toy cannot be in the same box. No box can contain two toys.\n\r\nWhich of the following must be true?\n\r\n1) Exactly one box should contain 2 toffees and 1 toy.\r\n2) Exactly one box should contain 2 toffees.\r\n3) Exactly one box should contain 2 pastries.\n\r\nNOTE: Out of the given set of 3 statements, it is not necessary that one and only one statement is true. One or more statements may be true.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStatements 1 and 2 are true.\n\r\nThe given statements are \r\n1) Exactly one box should contain 2 toffees and 1 toy.\r\n2) Exactly one box should contain 2 toffees.\r\n3) Exactly one box should contain 2 pastries.\n\r\nAlso the given observations are\r\nA) Each of the box should contain at least one cake, at least one toffee, at least 3 items and at the most 4 items.\r\nB) Pastry and toy cannot be in the same box.\r\nC) No box can contain two toys.\n\r\nUsing observations A and C, the following is the definite distribution to be made :-\n\r\nBoxes 1 2 3 4 5\n\r\nCake 1 1 1 1 1\r\nToffee 1 1 1 1 1\r\nPastry\r\nToy 1 1 1\n\r\nsince the cakes and toffees must follow observation A of at least 1 in each of the boxes and toys must follow observation C of no more than one toy in a box.\n\r\nWe have 4 pastries and 1 toffee remaining to be distributed to these 5 boxes.\n\r\nFrom observation B, since pastry and toy cannot be in the same box, the 4 pastries must go to boxes 4 and 5. Also in order to keep with the later part of observation A of at least 3 items and at most 4 items, these four pastries must be packed 2 each into boxes 4 and 5.\n\r\nThe remaining toffee must go into one of the three boxes 1, 2 or 3. Let us assume that this toffee goes to box 1.\n\r\nHence the final distribution is as follows :-\n\r\nBoxes 1 2 3 4 5\n\r\nCake 1 1 1 1 1\r\nToffee 2 1 1 1 1\r\nPastry 2 2\r\nToy 1 1 1\n\r\nComparing the given statements with the above distribution we can see that statements 1 and 2 are true since they refer to box 1 and statement 3 is false because more than one box is available with two pastries.\n<|im_start|>answer\nStatements 1 and 2 are true.\n\r\nThe given statements are \r\n1) Exactly one box should contain 2 toffees and 1 toy.\r\n2) Exactly one box should contain 2 toffees.\r\n3) Exactly one box should contain 2 pastries.\n\r\nAlso the given observations are\r\nA) Each of the box should contain at least one cake, at least one toffee, at least 3 items and at the most 4 items.\r\nB) Pastry and toy cannot be in the same box.\r\nC) No box can contain two toys.\n\r\nUsing observations A and C, the following is the definite distribution to be made :-\n\r\nBoxes 1 2 3 4 5\n\r\nCake 1 1 1 1 1\r\nToffee 1 1 1 1 1\r\nPastry\r\nToy 1 1 1\n\r\nsince the cakes and toffees must follow observation A of at least 1 in each of the boxes and toys must follow observation C of no more than one toy in a box.\n\r\nWe have 4 pastries and 1 toffee remaining to be distributed to these 5 boxes.\n\r\nFrom observation B, since pastry and toy cannot be in the same box, the 4 pastries must go to boxes 4 and 5. Also in order to keep with the later part of observation A of at least 3 items and at most 4 items, these four pastries must be packed 2 each into boxes 4 and 5.\n\r\nThe remaining toffee must go into one of the three boxes 1, 2 or 3. Let us assume that this toffee goes to box 1.\n\r\nHence the final distribution is as follows :-\n\r\nBoxes 1 2 3 4 5\n\r\nCake 1 1 1 1 1\r\nToffee 2 1 1 1 1\r\nPastry 2 2\r\nToy 1 1 1\n\r\nComparing the given statements with the above distribution we can see that statements 1 and 2 are true since they refer to box 1 and statement 3 is false because more than one box is available with two pastries.\n<|im_end|>" }, { "id": "#25497", "title": "Cat Quirks", "fun": 2.14, "difficulty": 1.67, "author": "deepsea", "desc": "Deepsea lives with both her mother and grandmother. Even though it's a small house, each of them has room for their beloved pet cat. Like the family they live with, the cats have quirks (one likes fruit, another sneezes like a co-worker of their owners and the last likes to go outside). The cats are all of different breeds. Baby is a Calico, Fluffy is a Persian and Chico is a Tabby. \n\r\nGiven the clues, can you figure out which cat belongs to which person and what each cat's quirk is? \n\r\n1) Fluffy will only eat cat food.\r\n2) Only one cat is female.\r\n3) The female cat has the youngest owner.\r\n4) Despite the fact that the outdoor cat is the youngest, he/she has the oldest owner.\r\n5) When it comes to the fruit eater, mangoes are his favorite.", "hint": "All calico cats are female.", "answer": "Fluffy-Grandma-Outside\r\nChico-Mother-Fruit\r\nBaby-Deepsea-Sneeze", "category": "Logic-Grid", "date": "08/25/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDeepsea lives with both her mother and grandmother. Even though it's a small house, each of them has room for their beloved pet cat. Like the family they live with, the cats have quirks (one likes fruit, another sneezes like a co-worker of their owners and the last likes to go outside). The cats are all of different breeds. Baby is a Calico, Fluffy is a Persian and Chico is a Tabby. \n\r\nGiven the clues, can you figure out which cat belongs to which person and what each cat's quirk is? \n\r\n1) Fluffy will only eat cat food.\r\n2) Only one cat is female.\r\n3) The female cat has the youngest owner.\r\n4) Despite the fact that the outdoor cat is the youngest, he/she has the oldest owner.\r\n5) When it comes to the fruit eater, mangoes are his favorite.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFluffy-Grandma-Outside\r\nChico-Mother-Fruit\r\nBaby-Deepsea-Sneeze\n<|im_start|>answer\nFluffy-Grandma-Outside\r\nChico-Mother-Fruit\r\nBaby-Deepsea-Sneeze\n<|im_end|>" }, { "id": "#871", "title": "Share the Money", "fun": 2.14, "difficulty": 2.32, "author": "Michelle", "desc": "Nine boys and three girls agreed to share equally their pocket money. Every boy gave an equal sum to every girl, and every girl gave another equal sum to every boy. Every child then possessed exactly the same amount. What was the smallest possible amount that each child then possessed?", "hint": "No hint available.", "answer": "Every boy and girl had three cents at the beginning. Then every boy gave one cent to every girl and the boys were left with nothing and the girls were left with 12 cents each. Then every girl gave one cent to every boy and they were all finally left with three cents each.", "category": "Math", "date": "09/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNine boys and three girls agreed to share equally their pocket money. Every boy gave an equal sum to every girl, and every girl gave another equal sum to every boy. Every child then possessed exactly the same amount. What was the smallest possible amount that each child then possessed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEvery boy and girl had three cents at the beginning. Then every boy gave one cent to every girl and the boys were left with nothing and the girls were left with 12 cents each. Then every girl gave one cent to every boy and they were all finally left with three cents each.\n<|im_start|>answer\nEvery boy and girl had three cents at the beginning. Then every boy gave one cent to every girl and the boys were left with nothing and the girls were left with 12 cents each. Then every girl gave one cent to every boy and they were all finally left with three cents each.\n<|im_end|>" }, { "id": "#21793", "title": "5x5 Magic Square", "fun": 2.14, "difficulty": 2.71, "author": "Jacoby", "desc": "Arrange the numbers from 1 to 25 in a 5x5 grid so that each row, column, and diagonal adds up to the same number.", "hint": "All of the rows, columns, and diagonals add up to 65.", "answer": "17 24 01 08 15\r\n23 05 07 14 16\r\n04 06 13 20 22\r\n10 12 19 21 03\r\n11 18 25 02 09", "category": "Math", "date": "03/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numbers from 1 to 25 in a 5x5 grid so that each row, column, and diagonal adds up to the same number.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n17 24 01 08 15\r\n23 05 07 14 16\r\n04 06 13 20 22\r\n10 12 19 21 03\r\n11 18 25 02 09\n<|im_start|>answer\n17 24 01 08 15\r\n23 05 07 14 16\r\n04 06 13 20 22\r\n10 12 19 21 03\r\n11 18 25 02 09\n<|im_end|>" }, { "id": "#310", "title": "A Compounding Question.", "fun": 2.14, "difficulty": 1.74, "author": "Mr. G", "desc": "Simplify the following expression:\n\r\n(a/b) / (c/d) - (d/c) / (b/a)", "hint": "No hint available.", "answer": "Zero.", "category": "Math", "date": "02/26/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSimplify the following expression:\n\r\n(a/b) / (c/d) - (d/c) / (b/a)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZero.\n<|im_start|>answer\nZero.\n<|im_end|>" }, { "id": "#26031", "title": "A Trio of Seventh Grade Students", "fun": 2.14, "difficulty": 0.55, "author": "Acestudent04", "desc": "Three seventh grade students all got their test grades back from their teachers on Friday. Determine their test grades, last names, and teachers.\n\r\nTest grades- 100, 80, 50\n\r\nStudents- Abby, Alison, Adam \n\r\nLast names- Anderson, Grey, Smith\n\r\nTeachers- Mrs. Boggs, Mrs. Hui, Mr. Sharp\n\n\r\n1. Adam failed, but he does not have either of the female teachers.\n\r\n2. The Anderson student made 100 and is not male.\n\r\n3. Mrs. Hui enjoys having Alison in her class, but the student with the last name Anderson was not enrolled in her class.\n\r\n4.The student with the last name Grey is female.", "hint": "Adam is male, Abby and Alison are female.", "answer": "Abby Anderson\r\n100\r\nMrs.Boggs\n\r\nAlison Grey\r\n80\r\nMrs.Hui\n\r\nAdam Smith\r\n50\r\nMr.Sharp", "category": "Logic-Grid", "date": "09/22/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree seventh grade students all got their test grades back from their teachers on Friday. Determine their test grades, last names, and teachers.\n\r\nTest grades- 100, 80, 50\n\r\nStudents- Abby, Alison, Adam \n\r\nLast names- Anderson, Grey, Smith\n\r\nTeachers- Mrs. Boggs, Mrs. Hui, Mr. Sharp\n\n\r\n1. Adam failed, but he does not have either of the female teachers.\n\r\n2. The Anderson student made 100 and is not male.\n\r\n3. Mrs. Hui enjoys having Alison in her class, but the student with the last name Anderson was not enrolled in her class.\n\r\n4.The student with the last name Grey is female.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbby Anderson\r\n100\r\nMrs.Boggs\n\r\nAlison Grey\r\n80\r\nMrs.Hui\n\r\nAdam Smith\r\n50\r\nMr.Sharp\n<|im_start|>answer\nAbby Anderson\r\n100\r\nMrs.Boggs\n\r\nAlison Grey\r\n80\r\nMrs.Hui\n\r\nAdam Smith\r\n50\r\nMr.Sharp\n<|im_end|>" }, { "id": "#35879", "title": "Cows Causing Catastrophes", "fun": 2.14, "difficulty": 0.58, "author": "cowman12", "desc": "The crazy cows on Cowman's farm have stampeded out of their pens. They have been continuously roaming the pasture. Cowman's servant, MiniCowman, needs to have all the cows back in their pens by milking time. Milking time is at 3:30 PM. It's already 3:00 PM! Each cow has their own pen. After returning the cows to their proper pen, MiniCowman will have to line up the cows in the milking line, sorted by breed. The cows will also need to be branded. You must find the correct brand symbol for each cow. Can you help MiniCowman? Use the clues below.\n\r\nCow Names: Bessie, Doris, Helen\n\r\nCow Breeds: Holstein, Jersey, Brown Swiss\n\r\nBrands: El Rancho, Mrs.Cow, Beef\n\r\n1) The Jersey is branded El Rancho.\n\r\n2) Doris is not the Jersey.\n\r\n3) Helen is branded Beef.\n\r\n4) The Brown Swiss is branded Mrs. Cow.", "hint": "No hint available.", "answer": "Bessie, the Jersey, is branded El Rancho.\n\r\nDoris, the Brown Swiss, is branded Mrs. Cow.\n\r\nHelen, the Holstein, is branded Beef.", "category": "Logic-Grid", "date": "03/26/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe crazy cows on Cowman's farm have stampeded out of their pens. They have been continuously roaming the pasture. Cowman's servant, MiniCowman, needs to have all the cows back in their pens by milking time. Milking time is at 3:30 PM. It's already 3:00 PM! Each cow has their own pen. After returning the cows to their proper pen, MiniCowman will have to line up the cows in the milking line, sorted by breed. The cows will also need to be branded. You must find the correct brand symbol for each cow. Can you help MiniCowman? Use the clues below.\n\r\nCow Names: Bessie, Doris, Helen\n\r\nCow Breeds: Holstein, Jersey, Brown Swiss\n\r\nBrands: El Rancho, Mrs.Cow, Beef\n\r\n1) The Jersey is branded El Rancho.\n\r\n2) Doris is not the Jersey.\n\r\n3) Helen is branded Beef.\n\r\n4) The Brown Swiss is branded Mrs. Cow.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBessie, the Jersey, is branded El Rancho.\n\r\nDoris, the Brown Swiss, is branded Mrs. Cow.\n\r\nHelen, the Holstein, is branded Beef.\n<|im_start|>answer\nBessie, the Jersey, is branded El Rancho.\n\r\nDoris, the Brown Swiss, is branded Mrs. Cow.\n\r\nHelen, the Holstein, is branded Beef.\n<|im_end|>" }, { "id": "#16381", "title": "Tax", "fun": 2.14, "difficulty": 1.77, "author": "liltunalol", "desc": "The local city leaders have just placed a 13% tax on hotel rooms. This is on top of a 2% sales tax for the country and a 10% luxury tax. A room now costs $100 per night. How much would it cost without the tax?", "hint": "No hint available.", "answer": "$80. The $100 includes the $80 plus the 25% tax.", "category": "Math", "date": "01/31/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe local city leaders have just placed a 13% tax on hotel rooms. This is on top of a 2% sales tax for the country and a 10% luxury tax. A room now costs $100 per night. How much would it cost without the tax?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$80. The $100 includes the $80 plus the 25% tax.\n<|im_start|>answer\n$80. The $100 includes the $80 plus the 25% tax.\n<|im_end|>" }, { "id": "#43347", "title": "CDs", "fun": 2.14, "difficulty": 0.98, "author": "LavaIcee", "desc": "Karla has ten songs that she likes, but they are all on different CDs. It takes her 15 seconds to switch between CDs and each song is exactly 2 minutes and 48 seconds long. How many seconds will it take for Karla to finish listening to all of her favorite songs if she started with a CD in her player, and didn't take the last one out?", "hint": "No hint available.", "answer": "1815", "category": "Math", "date": "10/16/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKarla has ten songs that she likes, but they are all on different CDs. It takes her 15 seconds to switch between CDs and each song is exactly 2 minutes and 48 seconds long. How many seconds will it take for Karla to finish listening to all of her favorite songs if she started with a CD in her player, and didn't take the last one out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1815\n<|im_start|>answer\n1815\n<|im_end|>" }, { "id": "#19586", "title": "Little Mad Ade's School Day", "fun": 2.14, "difficulty": 2.67, "author": "Mad-Ade", "desc": "Little Mad Ade, son of Mad Ade, leaves home in the morning to go to school. As he leaves the house he looks at the clock in the mirror. The clock has no number indication and for this reason the boy makes a mistake in interpreting the time (mirror-image). Just assuming the clock must be out of order, the Little Mad Ade cycles to school, where he arrives after twenty minutes. At that moment, the clock at school shows a time that is two and a half hours later than the time that Little Mad Ade saw on the clock at home. \r\n At what time did he reach school?", "hint": "No hint available.", "answer": "The difference between the real time and the time of the mirror image is two hours and ten minutes (two and a half hours, minus the twenty minutes of cycling). Therefore, the original time on the clock at home that morning could only have been five minutes past seven: \n\r\nThe difference between these clocks is exactly 2 hours and ten minutes (note that also five minutes past one can be mirrored in a similar way, but this is not in the morning!).\n\r\nConclusion: Little Mad Ade reaches school at five minutes past seven (plus twenty minutes of cycling) which is twenty-five minutes past seven!...", "category": "Logic", "date": "11/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittle Mad Ade, son of Mad Ade, leaves home in the morning to go to school. As he leaves the house he looks at the clock in the mirror. The clock has no number indication and for this reason the boy makes a mistake in interpreting the time (mirror-image). Just assuming the clock must be out of order, the Little Mad Ade cycles to school, where he arrives after twenty minutes. At that moment, the clock at school shows a time that is two and a half hours later than the time that Little Mad Ade saw on the clock at home. \r\n At what time did he reach school?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe difference between the real time and the time of the mirror image is two hours and ten minutes (two and a half hours, minus the twenty minutes of cycling). Therefore, the original time on the clock at home that morning could only have been five minutes past seven: \n\r\nThe difference between these clocks is exactly 2 hours and ten minutes (note that also five minutes past one can be mirrored in a similar way, but this is not in the morning!).\n\r\nConclusion: Little Mad Ade reaches school at five minutes past seven (plus twenty minutes of cycling) which is twenty-five minutes past seven!...\n<|im_start|>answer\nThe difference between the real time and the time of the mirror image is two hours and ten minutes (two and a half hours, minus the twenty minutes of cycling). Therefore, the original time on the clock at home that morning could only have been five minutes past seven: \n\r\nThe difference between these clocks is exactly 2 hours and ten minutes (note that also five minutes past one can be mirrored in a similar way, but this is not in the morning!).\n\r\nConclusion: Little Mad Ade reaches school at five minutes past seven (plus twenty minutes of cycling) which is twenty-five minutes past seven!...\n<|im_end|>" }, { "id": "#40142", "title": "2x3 Checkerboard", "fun": 2.14, "difficulty": 2.74, "author": "shenqiang", "desc": "There is a 2x3 checkerboard with 6 unit squares that are labeled as 1 through 6. If we are going to divide it into at least two rectangles whose sides are all integers, how many different ways are there?", "hint": "Since the cells are labeled, ways that are the same upon reflection or symmetry are considered different ways.", "answer": "There are 33 different ways of dividing it.\n\r\n2 rectangles:\r\n4+2: 2 ways;\r\n3+3: 1 way, 3 ways accumulated;\n\r\n3 rectangles:\r\n4+1+1: 2 ways, 5 ways accumulated;\r\n3+2+1: 4 ways, 9 ways accumulated;\r\n2+2+2: 3 ways, 12 ways accumulated;\n\r\n4 rectangles:\r\n3+1+1+1: 2 ways, 14 ways accumulated;\r\n2+2+1+1: 11 ways, 25 ways accumulated;\n\r\n5 rectangles:\r\n2+1+1+1+1: 7 ways, 32 ways accumulated;\n\r\n6 rectangles:\r\n1+1+1+1+1+1: 1 way, 33 ways accumulated.", "category": "Math", "date": "01/21/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a 2x3 checkerboard with 6 unit squares that are labeled as 1 through 6. If we are going to divide it into at least two rectangles whose sides are all integers, how many different ways are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are 33 different ways of dividing it.\n\r\n2 rectangles:\r\n4+2: 2 ways;\r\n3+3: 1 way, 3 ways accumulated;\n\r\n3 rectangles:\r\n4+1+1: 2 ways, 5 ways accumulated;\r\n3+2+1: 4 ways, 9 ways accumulated;\r\n2+2+2: 3 ways, 12 ways accumulated;\n\r\n4 rectangles:\r\n3+1+1+1: 2 ways, 14 ways accumulated;\r\n2+2+1+1: 11 ways, 25 ways accumulated;\n\r\n5 rectangles:\r\n2+1+1+1+1: 7 ways, 32 ways accumulated;\n\r\n6 rectangles:\r\n1+1+1+1+1+1: 1 way, 33 ways accumulated.\n<|im_start|>answer\nThere are 33 different ways of dividing it.\n\r\n2 rectangles:\r\n4+2: 2 ways;\r\n3+3: 1 way, 3 ways accumulated;\n\r\n3 rectangles:\r\n4+1+1: 2 ways, 5 ways accumulated;\r\n3+2+1: 4 ways, 9 ways accumulated;\r\n2+2+2: 3 ways, 12 ways accumulated;\n\r\n4 rectangles:\r\n3+1+1+1: 2 ways, 14 ways accumulated;\r\n2+2+1+1: 11 ways, 25 ways accumulated;\n\r\n5 rectangles:\r\n2+1+1+1+1: 7 ways, 32 ways accumulated;\n\r\n6 rectangles:\r\n1+1+1+1+1+1: 1 way, 33 ways accumulated.\n<|im_end|>" }, { "id": "#40548", "title": "How Many Days in a Year?", "fun": 2.14, "difficulty": 1.87, "author": "cheesepie", "desc": "How many days are there in a 400 year period (Gregorian cycle)?", "hint": "Leap Frog!", "answer": "146,097 days\r\n146,000 days and 97 leap days\n\r\nIt doesn't matter what year it started on because a Gregorian cycle contains the same pattern of days and years.", "category": "Math", "date": "02/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many days are there in a 400 year period (Gregorian cycle)?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n146,097 days\r\n146,000 days and 97 leap days\n\r\nIt doesn't matter what year it started on because a Gregorian cycle contains the same pattern of days and years.\n<|im_start|>answer\n146,097 days\r\n146,000 days and 97 leap days\n\r\nIt doesn't matter what year it started on because a Gregorian cycle contains the same pattern of days and years.\n<|im_end|>" }, { "id": "#6295", "title": "Super Skateboards", "fun": 2.14, "difficulty": 2.65, "author": "pilp07", "desc": "Alec, Brett and Chris each purchased parts for their skateboards at the sports store. Alec and Brett wanted to build new skateboards, so they each needed to purchase a deck, trucks, bearings and wheels. Chris only needed new wheels. The store offers a 10% discount for purchases over $250, so the boys decided to pay for all the parts together to qualify for the discount. Altogether, the boys spent $266.40. The clues below reflect the price of the items before the discount is applied. \n\r\nThe cost of all the bearings for the 2 boys combined was $1 more than the deck for Alec's skateboard. \n\r\nThey each bought the same kinds of wheels. Together they spent $75 for the 3 sets of wheels. Each set contained 4 wheels. \n\r\nThe total cost of the bearings came to $24 less than the total cost of the wheels. \n\r\nAlec spent $5 more for his deck than Brett spent for his. However, Brett spent $5 more on trucks than Alec. \n\r\nBrett spent $3 more on bearings than twice the amount Alec spent on bearings.\n\r\nHow much did each person spend?", "hint": "No hint available.", "answer": "Alec spent $113.40.\r\nBrett spent $130.50.\r\nChris spent $22.50. \n\r\nComponent Alec Brett Chris Total \r\nDeck $50 $45 $0 $95 \r\nTrucks 35 40 $0 75 \r\nWheels 25 25 25 75 \r\nBearings 16 35 $0 51 \r\nTotal before discount $126 $145 $25 $296 \r\nless 10% discount $12.60 $14.50 $2.50 $29.60 \r\nAmount spent $113.40 $130.50 $22.50 $266.40 \n\n\r\nExplanation: \n\r\nFirst find the original price of all the items combined. $266.40 is the price after the 10% discount was applied. \r\nThat means $266.40 is equal to 90% of the original price. \r\nWrite an equation and then cross multiply:\r\n266.40\r\n--------------------------------------------------------------------------------\r\nx = 9\r\n--------------------------------------------------------------------------------\r\nx \n\r\nThe original price for all the items was $296. \n\n\r\nWrite an equation: (let the first letter of each word represent the total cost spent for that item).\r\nD + T + W + B = 296 \n\r\nGiven: The wheels cost $75.\r\nD + T + W + B = 296\r\nD + T -75 + B = 296 - 75\r\nD + T + B = 221 \n\r\nThe total cost of the bearings came to $24 less than the total cost of the wheels.\r\nB = W - 24\r\nB = 75 - 24\r\nB = 51 \n\r\nThe cost of all the bearings for the 2 boys combined was $1 more than the deck for Alec's skateboard.\r\nAlec's skateboard = 51 - 1\r\nAlec's skateboard = 50 \n\r\nAlec spent $5 more for his deck than Brett spent for his. \r\nAlec spent $50. Therefore, $50 - 5 = Brett's deck\r\nBrett's deck = $45.\r\nHowever, Brett spent $5 more on trucks than Alec.\r\nAdd the amounts known on all of the items so far and subtract from the total original cost.\r\nWheels: 75\r\nDecks: 95\r\nBearings: 51\r\n75 + 95 + 51 = 221\r\nSub total: 221 \r\nTherefore, the total amount spent on trucks was $75. \n\n\r\nTotal amount on trucks was $75. To find the amount each boy spent: use a formula or guess and check (What 2 numbers total 75, if one is 5 more than the other?)\r\nLet x = the amount Alec spent on trucks.\r\nx + (x+5) = 75\r\n2x + 5 = 75\r\n2x = 70\r\nx = 35\r\nAlec spent $35 on trucks. Brett spent $5 more than Alec. Therefore, Brett spent $40 on trucks. \n\r\nBrett spent $3 more than twice the amount Alec spent on bearings. \r\nHere, let x = the amount Alec spent on bearings.\r\nBrett spent $3 more than twice the amount Alec spent on bearings, so write the value of Brett's bearings as 2x + 3. \r\nAmount Alec spent + amount Brett spent = $51\r\nx + (2x + 3) = 51\r\n3x + 3 = 51\r\n3x = 48\r\nx = 16 \n\r\nAlec's spent $16 on bearings.\r\nBrett spent $35 on bearings", "category": "Math", "date": "08/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlec, Brett and Chris each purchased parts for their skateboards at the sports store. Alec and Brett wanted to build new skateboards, so they each needed to purchase a deck, trucks, bearings and wheels. Chris only needed new wheels. The store offers a 10% discount for purchases over $250, so the boys decided to pay for all the parts together to qualify for the discount. Altogether, the boys spent $266.40. The clues below reflect the price of the items before the discount is applied. \n\r\nThe cost of all the bearings for the 2 boys combined was $1 more than the deck for Alec's skateboard. \n\r\nThey each bought the same kinds of wheels. Together they spent $75 for the 3 sets of wheels. Each set contained 4 wheels. \n\r\nThe total cost of the bearings came to $24 less than the total cost of the wheels. \n\r\nAlec spent $5 more for his deck than Brett spent for his. However, Brett spent $5 more on trucks than Alec. \n\r\nBrett spent $3 more on bearings than twice the amount Alec spent on bearings.\n\r\nHow much did each person spend?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlec spent $113.40.\r\nBrett spent $130.50.\r\nChris spent $22.50. \n\r\nComponent Alec Brett Chris Total \r\nDeck $50 $45 $0 $95 \r\nTrucks 35 40 $0 75 \r\nWheels 25 25 25 75 \r\nBearings 16 35 $0 51 \r\nTotal before discount $126 $145 $25 $296 \r\nless 10% discount $12.60 $14.50 $2.50 $29.60 \r\nAmount spent $113.40 $130.50 $22.50 $266.40 \n\n\r\nExplanation: \n\r\nFirst find the original price of all the items combined. $266.40 is the price after the 10% discount was applied. \r\nThat means $266.40 is equal to 90% of the original price. \r\nWrite an equation and then cross multiply:\r\n266.40\r\n--------------------------------------------------------------------------------\r\nx = 9\r\n--------------------------------------------------------------------------------\r\nx \n\r\nThe original price for all the items was $296. \n\n\r\nWrite an equation: (let the first letter of each word represent the total cost spent for that item).\r\nD + T + W + B = 296 \n\r\nGiven: The wheels cost $75.\r\nD + T + W + B = 296\r\nD + T -75 + B = 296 - 75\r\nD + T + B = 221 \n\r\nThe total cost of the bearings came to $24 less than the total cost of the wheels.\r\nB = W - 24\r\nB = 75 - 24\r\nB = 51 \n\r\nThe cost of all the bearings for the 2 boys combined was $1 more than the deck for Alec's skateboard.\r\nAlec's skateboard = 51 - 1\r\nAlec's skateboard = 50 \n\r\nAlec spent $5 more for his deck than Brett spent for his. \r\nAlec spent $50. Therefore, $50 - 5 = Brett's deck\r\nBrett's deck = $45.\r\nHowever, Brett spent $5 more on trucks than Alec.\r\nAdd the amounts known on all of the items so far and subtract from the total original cost.\r\nWheels: 75\r\nDecks: 95\r\nBearings: 51\r\n75 + 95 + 51 = 221\r\nSub total: 221 \r\nTherefore, the total amount spent on trucks was $75. \n\n\r\nTotal amount on trucks was $75. To find the amount each boy spent: use a formula or guess and check (What 2 numbers total 75, if one is 5 more than the other?)\r\nLet x = the amount Alec spent on trucks.\r\nx + (x+5) = 75\r\n2x + 5 = 75\r\n2x = 70\r\nx = 35\r\nAlec spent $35 on trucks. Brett spent $5 more than Alec. Therefore, Brett spent $40 on trucks. \n\r\nBrett spent $3 more than twice the amount Alec spent on bearings. \r\nHere, let x = the amount Alec spent on bearings.\r\nBrett spent $3 more than twice the amount Alec spent on bearings, so write the value of Brett's bearings as 2x + 3. \r\nAmount Alec spent + amount Brett spent = $51\r\nx + (2x + 3) = 51\r\n3x + 3 = 51\r\n3x = 48\r\nx = 16 \n\r\nAlec's spent $16 on bearings.\r\nBrett spent $35 on bearings\n<|im_start|>answer\nAlec spent $113.40.\r\nBrett spent $130.50.\r\nChris spent $22.50. \n\r\nComponent Alec Brett Chris Total \r\nDeck $50 $45 $0 $95 \r\nTrucks 35 40 $0 75 \r\nWheels 25 25 25 75 \r\nBearings 16 35 $0 51 \r\nTotal before discount $126 $145 $25 $296 \r\nless 10% discount $12.60 $14.50 $2.50 $29.60 \r\nAmount spent $113.40 $130.50 $22.50 $266.40 \n\n\r\nExplanation: \n\r\nFirst find the original price of all the items combined. $266.40 is the price after the 10% discount was applied. \r\nThat means $266.40 is equal to 90% of the original price. \r\nWrite an equation and then cross multiply:\r\n266.40\r\n--------------------------------------------------------------------------------\r\nx = 9\r\n--------------------------------------------------------------------------------\r\nx \n\r\nThe original price for all the items was $296. \n\n\r\nWrite an equation: (let the first letter of each word represent the total cost spent for that item).\r\nD + T + W + B = 296 \n\r\nGiven: The wheels cost $75.\r\nD + T + W + B = 296\r\nD + T -75 + B = 296 - 75\r\nD + T + B = 221 \n\r\nThe total cost of the bearings came to $24 less than the total cost of the wheels.\r\nB = W - 24\r\nB = 75 - 24\r\nB = 51 \n\r\nThe cost of all the bearings for the 2 boys combined was $1 more than the deck for Alec's skateboard.\r\nAlec's skateboard = 51 - 1\r\nAlec's skateboard = 50 \n\r\nAlec spent $5 more for his deck than Brett spent for his. \r\nAlec spent $50. Therefore, $50 - 5 = Brett's deck\r\nBrett's deck = $45.\r\nHowever, Brett spent $5 more on trucks than Alec.\r\nAdd the amounts known on all of the items so far and subtract from the total original cost.\r\nWheels: 75\r\nDecks: 95\r\nBearings: 51\r\n75 + 95 + 51 = 221\r\nSub total: 221 \r\nTherefore, the total amount spent on trucks was $75. \n\n\r\nTotal amount on trucks was $75. To find the amount each boy spent: use a formula or guess and check (What 2 numbers total 75, if one is 5 more than the other?)\r\nLet x = the amount Alec spent on trucks.\r\nx + (x+5) = 75\r\n2x + 5 = 75\r\n2x = 70\r\nx = 35\r\nAlec spent $35 on trucks. Brett spent $5 more than Alec. Therefore, Brett spent $40 on trucks. \n\r\nBrett spent $3 more than twice the amount Alec spent on bearings. \r\nHere, let x = the amount Alec spent on bearings.\r\nBrett spent $3 more than twice the amount Alec spent on bearings, so write the value of Brett's bearings as 2x + 3. \r\nAmount Alec spent + amount Brett spent = $51\r\nx + (2x + 3) = 51\r\n3x + 3 = 51\r\n3x = 48\r\nx = 16 \n\r\nAlec's spent $16 on bearings.\r\nBrett spent $35 on bearings\n<|im_end|>" }, { "id": "#230", "title": "Bouncy Ball", "fun": 2.14, "difficulty": 2.6, "author": "Phyllis", "desc": "If you drop a bouncy ball from a distance of 9 feet from the floor, the ball will continue to bounce. Assume that each time it bounces back two thirds of the distance of the previous bounce. How far will the ball travel before it stops?", "hint": "Geometric series...", "answer": "45 feet.\n\r\nThe distance can be calculated as 9 + (9)*(2/3)*(2) + (9)*(2/3)*(2/3)*(2)+..., with the 2 accounting for the upward and downward travel distance. Adding 9 to this will result in the formation of an infinite geometric series: 18*(2/3)^0 + 18*(2/3)^1 +... Factoring out the 18 will result in a series that is equal to (1/(1-(2/3))), which equals 3. Multiplying by the 18 and then subtracting the nine used to create the series will result in 54 - 9 = 45.", "category": "Math", "date": "02/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you drop a bouncy ball from a distance of 9 feet from the floor, the ball will continue to bounce. Assume that each time it bounces back two thirds of the distance of the previous bounce. How far will the ball travel before it stops?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n45 feet.\n\r\nThe distance can be calculated as 9 + (9)*(2/3)*(2) + (9)*(2/3)*(2/3)*(2)+..., with the 2 accounting for the upward and downward travel distance. Adding 9 to this will result in the formation of an infinite geometric series: 18*(2/3)^0 + 18*(2/3)^1 +... Factoring out the 18 will result in a series that is equal to (1/(1-(2/3))), which equals 3. Multiplying by the 18 and then subtracting the nine used to create the series will result in 54 - 9 = 45.\n<|im_start|>answer\n45 feet.\n\r\nThe distance can be calculated as 9 + (9)*(2/3)*(2) + (9)*(2/3)*(2/3)*(2)+..., with the 2 accounting for the upward and downward travel distance. Adding 9 to this will result in the formation of an infinite geometric series: 18*(2/3)^0 + 18*(2/3)^1 +... Factoring out the 18 will result in a series that is equal to (1/(1-(2/3))), which equals 3. Multiplying by the 18 and then subtracting the nine used to create the series will result in 54 - 9 = 45.\n<|im_end|>" }, { "id": "#12182", "title": "Secret code", "fun": 2.14, "difficulty": 1.8900000000000001, "author": "sunnyfunny", "desc": "Marcy has a date to a upcoming prom. She and her friend Diana had made a secret code, so Marcy wrote a secret note to Marcy. Marcy's dad came in hours later and found the note that Marcy wrote. The boy's name that was on the note was smeared out. The note said: \r\nDear Diana,\r\n ??? asked me to the dance!\r\n From,\r\n Marcy\n\r\nA few days later, Marcy brought up the secret note up to her Dad and asked to see if he could translate the name of the boy. It was the same note as the other one Marcy's Dad had read a few days before. The note said:\r\nV)*. V~*=*,\r\n ~*= *$#v)v +) d\\\\ d@) v*=])!\r\n C.\\\\+,\r\n +*.]2\n\r\nA few days later, Marcy's Dad came up to her and told her the boy's name. It was Ian. Marcy was shocked! How did Marcy's Dad know?", "hint": "No hint available.", "answer": "Marcy's dad knew because he used the other note with the boy's name smeared out. The note was the same, so the letters in the old note would be the unknown symbols. The \"i\" in Diana would be the first letter in the boy's name because it was in the smeared spot. He knew it was \"i\" because the \"i\" in Diana had the same symbol as the letter in the boy's name. The boy's first letter in his name was I. The \"a\" in dance would be the second letter because in \"dance\" in the secret letter, it was the same symbol as the second letter. He did the same with the \"n\" because the \"n\" in Diana had the same symbol as the last letter in the boy's name.", "category": "Logic", "date": "05/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMarcy has a date to a upcoming prom. She and her friend Diana had made a secret code, so Marcy wrote a secret note to Marcy. Marcy's dad came in hours later and found the note that Marcy wrote. The boy's name that was on the note was smeared out. The note said: \r\nDear Diana,\r\n ??? asked me to the dance!\r\n From,\r\n Marcy\n\r\nA few days later, Marcy brought up the secret note up to her Dad and asked to see if he could translate the name of the boy. It was the same note as the other one Marcy's Dad had read a few days before. The note said:\r\nV)*. V~*=*,\r\n ~*= *$#v)v +) d\\\\ d@) v*=])!\r\n C.\\\\+,\r\n +*.]2\n\r\nA few days later, Marcy's Dad came up to her and told her the boy's name. It was Ian. Marcy was shocked! How did Marcy's Dad know?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMarcy's dad knew because he used the other note with the boy's name smeared out. The note was the same, so the letters in the old note would be the unknown symbols. The \"i\" in Diana would be the first letter in the boy's name because it was in the smeared spot. He knew it was \"i\" because the \"i\" in Diana had the same symbol as the letter in the boy's name. The boy's first letter in his name was I. The \"a\" in dance would be the second letter because in \"dance\" in the secret letter, it was the same symbol as the second letter. He did the same with the \"n\" because the \"n\" in Diana had the same symbol as the last letter in the boy's name.\n<|im_start|>answer\nMarcy's dad knew because he used the other note with the boy's name smeared out. The note was the same, so the letters in the old note would be the unknown symbols. The \"i\" in Diana would be the first letter in the boy's name because it was in the smeared spot. He knew it was \"i\" because the \"i\" in Diana had the same symbol as the letter in the boy's name. The boy's first letter in his name was I. The \"a\" in dance would be the second letter because in \"dance\" in the secret letter, it was the same symbol as the second letter. He did the same with the \"n\" because the \"n\" in Diana had the same symbol as the last letter in the boy's name.\n<|im_end|>" }, { "id": "#21574", "title": "The Drink", "fun": 2.14, "difficulty": 1.46, "author": "indian_dude", "desc": "There are two men walking in the desert, but neither knows each other. One of them is dying of thirst and the other has a full jug of water. The man with the jug offers the man a drink, but only if he follows three simple rules. \r\nRule 1: He cannot have the jug, because it is his only one. \r\nRule 2: He cannot remove the cork from the spout and drink this way. \r\nRule 3: He cannot poke a hole into the cork or the jug. \r\nSo, the thirsty man accepted his rules and then, he finished his drink and left. How did he do it?", "hint": "No hint available.", "answer": "Since the man with the jug offered the other a drink and put forth the rules, he himself opened the jug and gave him a drink. You would think that the thirsty one would have the jug, but it was the one with the jug who opened it and gave him a drink.", "category": "Logic", "date": "03/16/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two men walking in the desert, but neither knows each other. One of them is dying of thirst and the other has a full jug of water. The man with the jug offers the man a drink, but only if he follows three simple rules. \r\nRule 1: He cannot have the jug, because it is his only one. \r\nRule 2: He cannot remove the cork from the spout and drink this way. \r\nRule 3: He cannot poke a hole into the cork or the jug. \r\nSo, the thirsty man accepted his rules and then, he finished his drink and left. How did he do it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince the man with the jug offered the other a drink and put forth the rules, he himself opened the jug and gave him a drink. You would think that the thirsty one would have the jug, but it was the one with the jug who opened it and gave him a drink.\n<|im_start|>answer\nSince the man with the jug offered the other a drink and put forth the rules, he himself opened the jug and gave him a drink. You would think that the thirsty one would have the jug, but it was the one with the jug who opened it and gave him a drink.\n<|im_end|>" }, { "id": "#23246", "title": "Monkey Taxi Service", "fun": 2.14, "difficulty": 1.29, "author": "mufffin09", "desc": "Sarah's Simian Taxi Service can transport 120 monkeys in 4 cars. Elphie comes in with her flying monkeys that have broken wings. She wants to transport as many of them as she can to the vet (although the vet might have a heart attack upon sight of the winged monkeys, and the green girl!) with the amount of cars available. Sarah has ten cars available. How many monkeys can Elphie get to the vet?", "hint": "No hint available.", "answer": "She can transport 300 monkeys. \n\r\nIf 4 cars hold 120 monkeys, you do 120/4 and you will get the unit rate, which is 30 monkeys per car. You then do 30 monkeys x 10 cars and get 300 total monkeys.", "category": "Math", "date": "05/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSarah's Simian Taxi Service can transport 120 monkeys in 4 cars. Elphie comes in with her flying monkeys that have broken wings. She wants to transport as many of them as she can to the vet (although the vet might have a heart attack upon sight of the winged monkeys, and the green girl!) with the amount of cars available. Sarah has ten cars available. How many monkeys can Elphie get to the vet?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe can transport 300 monkeys. \n\r\nIf 4 cars hold 120 monkeys, you do 120/4 and you will get the unit rate, which is 30 monkeys per car. You then do 30 monkeys x 10 cars and get 300 total monkeys.\n<|im_start|>answer\nShe can transport 300 monkeys. \n\r\nIf 4 cars hold 120 monkeys, you do 120/4 and you will get the unit rate, which is 30 monkeys per car. You then do 30 monkeys x 10 cars and get 300 total monkeys.\n<|im_end|>" }, { "id": "#877", "title": "Candy", "fun": 2.13, "difficulty": 1.94, "author": "Michelle", "desc": "A long time ago, candy was being sold at three prices: red candy at one for a penny, green candy at two for a penny, and blue candy at three for a penny. Some children (as many boys as girls) were given a total of seven pennies to spend on the candy. Each child received exactly the same value in candy. How many pieces of candy and what color candy did each child receive?", "hint": "No hint available.", "answer": "There must have been three boys and three girls, each of whom received two pieces of blue candy priced at three for a penny, and one piece of green candy priced at two for a penny. The total cost of the candy would be exactly 7 cents.", "category": "Logic", "date": "09/26/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA long time ago, candy was being sold at three prices: red candy at one for a penny, green candy at two for a penny, and blue candy at three for a penny. Some children (as many boys as girls) were given a total of seven pennies to spend on the candy. Each child received exactly the same value in candy. How many pieces of candy and what color candy did each child receive?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere must have been three boys and three girls, each of whom received two pieces of blue candy priced at three for a penny, and one piece of green candy priced at two for a penny. The total cost of the candy would be exactly 7 cents.\n<|im_start|>answer\nThere must have been three boys and three girls, each of whom received two pieces of blue candy priced at three for a penny, and one piece of green candy priced at two for a penny. The total cost of the candy would be exactly 7 cents.\n<|im_end|>" }, { "id": "#29101", "title": "5 * 7 = 37", "fun": 2.13, "difficulty": 1.96, "author": "DakarMorad", "desc": "According to basic algebra, (A + B)(A - B) is equal to A^2 - B^2 (A^2 is \"A squared\"). Substituting 1 for B, we get A^2 - 1^2.\n\r\nA^2 - 1^2 is the same as A^2 + (-1^2). Since -1 times -1 is one, we end up with A^2 + 1.\n\r\nIf we substitute 6 for A, we get (6+1)(6-1) = 6^2+1, or 37. Since 6+1 is 7 and 6-1 is 5, five times seven is thirty-seven.\n\r\nWhat's wrong with this proof?", "hint": "No hint available.", "answer": "A^2 - 1^2 is NOT the same as A^2 + (-1^2). It is actually A^2 + -(1^2), or the negative of 1 * 1.", "category": "Math", "date": "03/14/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAccording to basic algebra, (A + B)(A - B) is equal to A^2 - B^2 (A^2 is \"A squared\"). Substituting 1 for B, we get A^2 - 1^2.\n\r\nA^2 - 1^2 is the same as A^2 + (-1^2). Since -1 times -1 is one, we end up with A^2 + 1.\n\r\nIf we substitute 6 for A, we get (6+1)(6-1) = 6^2+1, or 37. Since 6+1 is 7 and 6-1 is 5, five times seven is thirty-seven.\n\r\nWhat's wrong with this proof?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA^2 - 1^2 is NOT the same as A^2 + (-1^2). It is actually A^2 + -(1^2), or the negative of 1 * 1.\n<|im_start|>answer\nA^2 - 1^2 is NOT the same as A^2 + (-1^2). It is actually A^2 + -(1^2), or the negative of 1 * 1.\n<|im_end|>" }, { "id": "#2382", "title": "1000!", "fun": 2.13, "difficulty": 2.75, "author": "coco_nut", "desc": "How many trailing zeros are in the number 1000!?", "hint": "No hint available.", "answer": "The ! stands for factorial. So, there are exactly 249 trailing zeros in 1000!\n\r\nThe only way to get a trailing zero is by multiplying a factor of 1000! which is 2 by a factor of 1000! which is 5. The modified problem is thus: How many such pairs of factors are there?\n\r\nThere are 500 = 1000/2 numbers between 1 and 1000 (inclusive) which are even, so there are at least 500 factors of 2 in 1000!. There are 200 = 1000/5 numbers which are multiples of 5. But in addition there are 40 = 1000/25 numbers which are multiples of 25, each of which gives one factor of five in addition to the one counted in the 200 and the one counted in the 40 above. Finally there is 1 = [1000/625] number which is a multiple of 625, this gives one further factor of 5. Thus there are exactly 200 + 40 + 8 + 1 = 249 factors of 5 in 1000! and since there are more than sufficient factors of 2, there are exactly 249 trailing zeros in 1000!", "category": "Math", "date": "02/22/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many trailing zeros are in the number 1000!?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ! stands for factorial. So, there are exactly 249 trailing zeros in 1000!\n\r\nThe only way to get a trailing zero is by multiplying a factor of 1000! which is 2 by a factor of 1000! which is 5. The modified problem is thus: How many such pairs of factors are there?\n\r\nThere are 500 = 1000/2 numbers between 1 and 1000 (inclusive) which are even, so there are at least 500 factors of 2 in 1000!. There are 200 = 1000/5 numbers which are multiples of 5. But in addition there are 40 = 1000/25 numbers which are multiples of 25, each of which gives one factor of five in addition to the one counted in the 200 and the one counted in the 40 above. Finally there is 1 = [1000/625] number which is a multiple of 625, this gives one further factor of 5. Thus there are exactly 200 + 40 + 8 + 1 = 249 factors of 5 in 1000! and since there are more than sufficient factors of 2, there are exactly 249 trailing zeros in 1000!\n<|im_start|>answer\nThe ! stands for factorial. So, there are exactly 249 trailing zeros in 1000!\n\r\nThe only way to get a trailing zero is by multiplying a factor of 1000! which is 2 by a factor of 1000! which is 5. The modified problem is thus: How many such pairs of factors are there?\n\r\nThere are 500 = 1000/2 numbers between 1 and 1000 (inclusive) which are even, so there are at least 500 factors of 2 in 1000!. There are 200 = 1000/5 numbers which are multiples of 5. But in addition there are 40 = 1000/25 numbers which are multiples of 25, each of which gives one factor of five in addition to the one counted in the 200 and the one counted in the 40 above. Finally there is 1 = [1000/625] number which is a multiple of 625, this gives one further factor of 5. Thus there are exactly 200 + 40 + 8 + 1 = 249 factors of 5 in 1000! and since there are more than sufficient factors of 2, there are exactly 249 trailing zeros in 1000!\n<|im_end|>" }, { "id": "#42119", "title": "Nice Rides", "fun": 2.13, "difficulty": 0.73, "author": "whsprec", "desc": "4 friends own 4 luxury cars, which are 4 different colors. The names of the friends are Chris, Jessica, Lee, and Samantha. They own either an Aston Martin, a Ferrari, a Bentley, or a Rolls-Royce which are either Green, Red, Silver, or Blue. Match the owner to the car and the color.\n\r\n1) Jessica and Lee do not own a Rolls-Royce, but one of them drives a blue car.\r\n2) The person who drives the Ferrari has less than 6 letters in their name.\r\n3) When Lee hit Chris's Bently, the silver mark from Lee's car clashed with the red.", "hint": "No hint available.", "answer": "Jessica - Blue Aston Martin\r\nLee - Silver Ferrari\r\nSamantha - Green Rolls-Royce\r\nChris - Red Bentley", "category": "Logic-Grid", "date": "06/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 friends own 4 luxury cars, which are 4 different colors. The names of the friends are Chris, Jessica, Lee, and Samantha. They own either an Aston Martin, a Ferrari, a Bentley, or a Rolls-Royce which are either Green, Red, Silver, or Blue. Match the owner to the car and the color.\n\r\n1) Jessica and Lee do not own a Rolls-Royce, but one of them drives a blue car.\r\n2) The person who drives the Ferrari has less than 6 letters in their name.\r\n3) When Lee hit Chris's Bently, the silver mark from Lee's car clashed with the red.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJessica - Blue Aston Martin\r\nLee - Silver Ferrari\r\nSamantha - Green Rolls-Royce\r\nChris - Red Bentley\n<|im_start|>answer\nJessica - Blue Aston Martin\r\nLee - Silver Ferrari\r\nSamantha - Green Rolls-Royce\r\nChris - Red Bentley\n<|im_end|>" }, { "id": "#3283", "title": "Chess Matches", "fun": 2.13, "difficulty": 2.5, "author": "yor18", "desc": "In my class there are 60 students. We decided to hold a chess tournament.\n\r\nIn the first phase, every one plays 6 matches each, each match with a different player.\n\r\nWhat is the minimum number of people that will have to back out if all participants play 6 matches ONLY? Also how many matches will be played in the first phase?", "hint": "No hint available.", "answer": "The number of players that need to back out is 4. Number of matches is 168.\n\r\nFor 6 people to play each other, a minimum of 7 people are required. So the total number of players is a multiple of 7. The nearest is therefore 56 (7x8).\r\nNumber, of matches = 7 students per group x 6 matches per student / 2 students per match x 8 groups = 7 x 6 / 2 x 8 = 168", "category": "Math", "date": "04/05/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn my class there are 60 students. We decided to hold a chess tournament.\n\r\nIn the first phase, every one plays 6 matches each, each match with a different player.\n\r\nWhat is the minimum number of people that will have to back out if all participants play 6 matches ONLY? Also how many matches will be played in the first phase?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number of players that need to back out is 4. Number of matches is 168.\n\r\nFor 6 people to play each other, a minimum of 7 people are required. So the total number of players is a multiple of 7. The nearest is therefore 56 (7x8).\r\nNumber, of matches = 7 students per group x 6 matches per student / 2 students per match x 8 groups = 7 x 6 / 2 x 8 = 168\n<|im_start|>answer\nThe number of players that need to back out is 4. Number of matches is 168.\n\r\nFor 6 people to play each other, a minimum of 7 people are required. So the total number of players is a multiple of 7. The nearest is therefore 56 (7x8).\r\nNumber, of matches = 7 students per group x 6 matches per student / 2 students per match x 8 groups = 7 x 6 / 2 x 8 = 168\n<|im_end|>" }, { "id": "#2568", "title": "Workout", "fun": 2.13, "difficulty": 1.14, "author": "204_blaze_41", "desc": "While working out with weights, John Sy had his personal trainer put a 25 pound weight on each end of the bar, a 10 pound weight on each end, and then three 2 pound weights on each end. John then took over and lifted the bar above his head. How much did John lift altogether?", "hint": "No hint available.", "answer": "John lifted 82 pounds, plus the weight of the bar.", "category": "Math", "date": "03/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile working out with weights, John Sy had his personal trainer put a 25 pound weight on each end of the bar, a 10 pound weight on each end, and then three 2 pound weights on each end. John then took over and lifted the bar above his head. How much did John lift altogether?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn lifted 82 pounds, plus the weight of the bar.\n<|im_start|>answer\nJohn lifted 82 pounds, plus the weight of the bar.\n<|im_end|>" }, { "id": "#815", "title": "Weigh the Beer", "fun": 2.13, "difficulty": 1.42, "author": "Michelle", "desc": "A balance scale is perfectly balanced when there are three cans of beer on one side of the scale and one can of beer and a one-half pound bar of gold on the other. Since all the cans of beer are exactly the same size and weight, how much does one can of beer weigh?", "hint": "No hint available.", "answer": "One-quarter pound.", "category": "Math", "date": "09/16/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA balance scale is perfectly balanced when there are three cans of beer on one side of the scale and one can of beer and a one-half pound bar of gold on the other. Since all the cans of beer are exactly the same size and weight, how much does one can of beer weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne-quarter pound.\n<|im_start|>answer\nOne-quarter pound.\n<|im_end|>" }, { "id": "#42429", "title": "Computer Shipments", "fun": 2.13, "difficulty": 1.39, "author": "Abstain", "desc": "Nell Computers wants to hire Overnite Delivery Service to truck computers from the warehouse to stores. Overnite has 2 trucks - 1 large and 1 small. The large truck is twice as high, twice as wide, and twice as long as the small one. Overnite has decided to charge $500 per shipment for each delivery made with a fully loaded small truck.\n\r\nAssuming that charges are based on each truck's volume, what should Overnite charge for each delivery made with a fully loaded large truck?", "hint": "It's not $1,000!", "answer": "Overnite Delivery Service should charge $4,000 for a large truckload.\n\r\nSince each dimension of the large truck (height, width, and length) is twice that of the small truck, the volume of the large truck is 8 times that of the small truck. So, for a large truckload, Overnite should charge 8 times the price of a small truckload. That's 8 * $500, or $4,000.", "category": "Math", "date": "07/06/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNell Computers wants to hire Overnite Delivery Service to truck computers from the warehouse to stores. Overnite has 2 trucks - 1 large and 1 small. The large truck is twice as high, twice as wide, and twice as long as the small one. Overnite has decided to charge $500 per shipment for each delivery made with a fully loaded small truck.\n\r\nAssuming that charges are based on each truck's volume, what should Overnite charge for each delivery made with a fully loaded large truck?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOvernite Delivery Service should charge $4,000 for a large truckload.\n\r\nSince each dimension of the large truck (height, width, and length) is twice that of the small truck, the volume of the large truck is 8 times that of the small truck. So, for a large truckload, Overnite should charge 8 times the price of a small truckload. That's 8 * $500, or $4,000.\n<|im_start|>answer\nOvernite Delivery Service should charge $4,000 for a large truckload.\n\r\nSince each dimension of the large truck (height, width, and length) is twice that of the small truck, the volume of the large truck is 8 times that of the small truck. So, for a large truckload, Overnite should charge 8 times the price of a small truckload. That's 8 * $500, or $4,000.\n<|im_end|>" }, { "id": "#1995", "title": "Christmas", "fun": 2.13, "difficulty": 1.42, "author": "Majeen", "desc": "For Christmas, six brothers and sisters received some CD albums as presents. The albums were by Madonna, Steps, Robbie Williams, Boyzone, Mozart and Shania Twain. Using these clues, can you determine who received which CD? \n\r\nKevin chose a CD by a solo girl singer. \r\nLaura hates pop music but got an album she wanted. \r\nJames chose a solo singer. \r\nRebecca chose a girl singer, but not Madonna. \r\nJoanne and Steve both chose CDs by groups. \r\nSteve chose Steps.", "hint": "No hint available.", "answer": "Kevin chose Madonna. Laura chose Mozart. James chose Robbie Williams. Rebecca chose Shania Twain. Joanne chose Boyzone. Steve chose Steps.", "category": "Logic", "date": "01/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor Christmas, six brothers and sisters received some CD albums as presents. The albums were by Madonna, Steps, Robbie Williams, Boyzone, Mozart and Shania Twain. Using these clues, can you determine who received which CD? \n\r\nKevin chose a CD by a solo girl singer. \r\nLaura hates pop music but got an album she wanted. \r\nJames chose a solo singer. \r\nRebecca chose a girl singer, but not Madonna. \r\nJoanne and Steve both chose CDs by groups. \r\nSteve chose Steps.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKevin chose Madonna. Laura chose Mozart. James chose Robbie Williams. Rebecca chose Shania Twain. Joanne chose Boyzone. Steve chose Steps.\n<|im_start|>answer\nKevin chose Madonna. Laura chose Mozart. James chose Robbie Williams. Rebecca chose Shania Twain. Joanne chose Boyzone. Steve chose Steps.\n<|im_end|>" }, { "id": "#6648", "title": "Captain Cook", "fun": 2.13, "difficulty": 0.74, "author": "superadam", "desc": "Captain James Cook made three trips around the world, and died during one of them. In which trip did he die?", "hint": "No hint available.", "answer": "The third.", "category": "Logic", "date": "08/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCaptain James Cook made three trips around the world, and died during one of them. In which trip did he die?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe third.\n<|im_start|>answer\nThe third.\n<|im_end|>" }, { "id": "#1673", "title": "Coin Circle", "fun": 2.13, "difficulty": 1.97, "author": "starman", "desc": "Place any circular coin down flat on a table. Can you do a simple calculation to estimate to the nearest whole number of coins the maximum number of coins of the same size that will fit in a concentric circle around the center coin? Each surrounding coin must touch the center coin and also lie flat on the table", "hint": "Use the formula Circumference = pi x diameter.", "answer": "Six\n\r\nSince the surrounding coins will touch approximately at their diameters (d) we are looking for how many diameters of this size coin there are at the circumference (C) where the coins touch. This circumference falls at approximately 2 x the radius (r) of the coins from the center of the circle. The diameter of this circumference would be approximately 4 x r or 2 d. The circumference would then be pi (3.14) x 2 d = 6.28 d. Since each diameter of a coin represents one coin there would be approximately 6.28 coins. The coins would only touch at their widest part or diameter if they were laid out in a straight line. Since they are in a circular pattern they actually touch slightly below their widest diameters so the actual diameter of the circumference is slightly less than 2d. Thus we know that there would be slightly fewer than 6.28 coins and the closest whole number estimate is six.", "category": "Math", "date": "12/11/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPlace any circular coin down flat on a table. Can you do a simple calculation to estimate to the nearest whole number of coins the maximum number of coins of the same size that will fit in a concentric circle around the center coin? Each surrounding coin must touch the center coin and also lie flat on the table\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSix\n\r\nSince the surrounding coins will touch approximately at their diameters (d) we are looking for how many diameters of this size coin there are at the circumference (C) where the coins touch. This circumference falls at approximately 2 x the radius (r) of the coins from the center of the circle. The diameter of this circumference would be approximately 4 x r or 2 d. The circumference would then be pi (3.14) x 2 d = 6.28 d. Since each diameter of a coin represents one coin there would be approximately 6.28 coins. The coins would only touch at their widest part or diameter if they were laid out in a straight line. Since they are in a circular pattern they actually touch slightly below their widest diameters so the actual diameter of the circumference is slightly less than 2d. Thus we know that there would be slightly fewer than 6.28 coins and the closest whole number estimate is six.\n<|im_start|>answer\nSix\n\r\nSince the surrounding coins will touch approximately at their diameters (d) we are looking for how many diameters of this size coin there are at the circumference (C) where the coins touch. This circumference falls at approximately 2 x the radius (r) of the coins from the center of the circle. The diameter of this circumference would be approximately 4 x r or 2 d. The circumference would then be pi (3.14) x 2 d = 6.28 d. Since each diameter of a coin represents one coin there would be approximately 6.28 coins. The coins would only touch at their widest part or diameter if they were laid out in a straight line. Since they are in a circular pattern they actually touch slightly below their widest diameters so the actual diameter of the circumference is slightly less than 2d. Thus we know that there would be slightly fewer than 6.28 coins and the closest whole number estimate is six.\n<|im_end|>" }, { "id": "#42926", "title": "The Dance-Off", "fun": 2.13, "difficulty": 0.56, "author": "whsprec", "desc": "2 boys and 2 girls entered a dance competition. The boys were named Neko and Tyler and the girls were Anna and Shelby. Each dancer danced to a different genre: rap, pop, rock, or techno. Match the dancer to the style and their place.\n\r\n1) The boys danced to techno and pop.\r\n2) The person who danced to rap did not come in 2nd or 3rd place, but techno came in 4th.\r\n3) Anna came in 3rd place.\r\n4) Shelby doesn't like rock and Tyler doesn't like techno.", "hint": "No hint available.", "answer": "1st place Shelby danced to rap.\r\n2nd place Tyler danced to pop.\r\n3rd place Anna danced to rock.\r\n4th place Neko danced to techno.", "category": "Logic-Grid", "date": "08/28/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n2 boys and 2 girls entered a dance competition. The boys were named Neko and Tyler and the girls were Anna and Shelby. Each dancer danced to a different genre: rap, pop, rock, or techno. Match the dancer to the style and their place.\n\r\n1) The boys danced to techno and pop.\r\n2) The person who danced to rap did not come in 2nd or 3rd place, but techno came in 4th.\r\n3) Anna came in 3rd place.\r\n4) Shelby doesn't like rock and Tyler doesn't like techno.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1st place Shelby danced to rap.\r\n2nd place Tyler danced to pop.\r\n3rd place Anna danced to rock.\r\n4th place Neko danced to techno.\n<|im_start|>answer\n1st place Shelby danced to rap.\r\n2nd place Tyler danced to pop.\r\n3rd place Anna danced to rock.\r\n4th place Neko danced to techno.\n<|im_end|>" }, { "id": "#12807", "title": "Time Lines", "fun": 2.13, "difficulty": 2.63, "author": "Codammanus", "desc": "A. 'My shortest business-related call today was from 5:55pm-5:55:29pm.'\n\r\nB. 'With the exception of one, five-day work week, I worked every day in September.\n\r\nC. 'Sum of 3 Right angles and one 19 degree angle.'\n\r\nD. 'The chess marathon lasted from 12noon-4am.'\n\r\nE. 'The show comes on at 4:30. It goes off at 5:30'\n\r\nWhich two of the five time-related quotes does not belong there?", "hint": "No hint available.", "answer": "The two that do not belong are A and E\n\r\nAll of the other time-related quotes result in Perfect Squares.\n\r\nB. September has 30 days. Take away a five-day work week and you have 25.\n\r\nC. 3 Right angles and one 19 degree angle gives you 289.\n\r\nD. The chess marathon ran for a total of 16 hours.", "category": "Math", "date": "05/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA. 'My shortest business-related call today was from 5:55pm-5:55:29pm.'\n\r\nB. 'With the exception of one, five-day work week, I worked every day in September.\n\r\nC. 'Sum of 3 Right angles and one 19 degree angle.'\n\r\nD. 'The chess marathon lasted from 12noon-4am.'\n\r\nE. 'The show comes on at 4:30. It goes off at 5:30'\n\r\nWhich two of the five time-related quotes does not belong there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe two that do not belong are A and E\n\r\nAll of the other time-related quotes result in Perfect Squares.\n\r\nB. September has 30 days. Take away a five-day work week and you have 25.\n\r\nC. 3 Right angles and one 19 degree angle gives you 289.\n\r\nD. The chess marathon ran for a total of 16 hours.\n<|im_start|>answer\nThe two that do not belong are A and E\n\r\nAll of the other time-related quotes result in Perfect Squares.\n\r\nB. September has 30 days. Take away a five-day work week and you have 25.\n\r\nC. 3 Right angles and one 19 degree angle gives you 289.\n\r\nD. The chess marathon ran for a total of 16 hours.\n<|im_end|>" }, { "id": "#44704", "title": "Once Prime, Always Prime", "fun": 2.13, "difficulty": 1.62, "author": "whsprec", "desc": "What is the smallest prime number with 3 distinct digits that remains prime no matter which one of its digits is removed?", "hint": "No hint available.", "answer": "137.\r\nWhen you remove a number you get 13, 17, or 37.\r\nWhen you remove 2 numbers you get 1, 3, or 7. All prime.", "category": "Math", "date": "06/21/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest prime number with 3 distinct digits that remains prime no matter which one of its digits is removed?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n137.\r\nWhen you remove a number you get 13, 17, or 37.\r\nWhen you remove 2 numbers you get 1, 3, or 7. All prime.\n<|im_start|>answer\n137.\r\nWhen you remove a number you get 13, 17, or 37.\r\nWhen you remove 2 numbers you get 1, 3, or 7. All prime.\n<|im_end|>" }, { "id": "#40376", "title": "The Prime Tetrahedron", "fun": 2.13, "difficulty": 2.54, "author": "shenqiang", "desc": "The six edges of tetrahedron ABCD measure 17, 23, 37, 67, 89 and 101 units. If the length of edge AB is 101, what is the length of edge CD?", "hint": "The sum of the lengths of two edges of a triangle must be greater than the length of the third edge.", "answer": "Since AC+BC>AB and AD+BD>AB, the only combinations of AC+BC and AD+BD are 89+17 and 67+37, or 89+23 and 67+37.\n\r\nIf they're 89+17 and 67+37, the remaining edge is 23, and we can make two triangles: 23, 67, 89 and 23, 17, 37.\n\r\nIf they're 89+23 and 67+37, the remaining edge is 17, but then there's no way to make the other two triangles.\n\r\nTherefore, CD=23.", "category": "Math", "date": "02/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe six edges of tetrahedron ABCD measure 17, 23, 37, 67, 89 and 101 units. If the length of edge AB is 101, what is the length of edge CD?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince AC+BC>AB and AD+BD>AB, the only combinations of AC+BC and AD+BD are 89+17 and 67+37, or 89+23 and 67+37.\n\r\nIf they're 89+17 and 67+37, the remaining edge is 23, and we can make two triangles: 23, 67, 89 and 23, 17, 37.\n\r\nIf they're 89+23 and 67+37, the remaining edge is 17, but then there's no way to make the other two triangles.\n\r\nTherefore, CD=23.\n<|im_start|>answer\nSince AC+BC>AB and AD+BD>AB, the only combinations of AC+BC and AD+BD are 89+17 and 67+37, or 89+23 and 67+37.\n\r\nIf they're 89+17 and 67+37, the remaining edge is 23, and we can make two triangles: 23, 67, 89 and 23, 17, 37.\n\r\nIf they're 89+23 and 67+37, the remaining edge is 17, but then there's no way to make the other two triangles.\n\r\nTherefore, CD=23.\n<|im_end|>" }, { "id": "#2200", "title": "Eating Apples", "fun": 2.13, "difficulty": 1.32, "author": "Sinead", "desc": "If I ate 6 apples, but my brother ate 4, and my cousin ate 8 and got a stomach ache and threw up 2 but we only bought 2 bags with 17 apples each, and then my mom snuck 1, how many more can I eat?", "hint": "No hint available.", "answer": "15", "category": "Math", "date": "01/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf I ate 6 apples, but my brother ate 4, and my cousin ate 8 and got a stomach ache and threw up 2 but we only bought 2 bags with 17 apples each, and then my mom snuck 1, how many more can I eat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15\n<|im_start|>answer\n15\n<|im_end|>" }, { "id": "#24297", "title": "Question All Day Long", "fun": 2.13, "difficulty": 0.89, "author": "xmadnetx", "desc": "What question can a person ask all day long, get a different answer each time, and yet all the answers were correct?", "hint": "No hint available.", "answer": "What time is it?", "category": "Logic", "date": "07/06/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat question can a person ask all day long, get a different answer each time, and yet all the answers were correct?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhat time is it?\n<|im_start|>answer\nWhat time is it?\n<|im_end|>" }, { "id": "#18384", "title": "3x3", "fun": 2.13, "difficulty": 2.88, "author": "superdobe", "desc": "Arrange the digits 1-9 in a 3x3 square using each once only according to the following rules. Exactly one prime is directly above a prime two less. Each pair of opposite corners sums to the same square total and exactly two columns share another square total. Exactly one prime is directly to the left of a non-prime two greater. Directly above exactly one square digit is a digit four greater. Directly to the right of exactly one cubic digit is a digit one greater", "hint": "No hint available.", "answer": "897-top\r\n635-middle\r\n241-bottom", "category": "Math", "date": "07/28/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the digits 1-9 in a 3x3 square using each once only according to the following rules. Exactly one prime is directly above a prime two less. Each pair of opposite corners sums to the same square total and exactly two columns share another square total. Exactly one prime is directly to the left of a non-prime two greater. Directly above exactly one square digit is a digit four greater. Directly to the right of exactly one cubic digit is a digit one greater\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n897-top\r\n635-middle\r\n241-bottom\n<|im_start|>answer\n897-top\r\n635-middle\r\n241-bottom\n<|im_end|>" }, { "id": "#12535", "title": "Mad Ade's Matches", "fun": 2.13, "difficulty": 2.68, "author": "mad-ade", "desc": "Mad Ade bought a little box of midget matches, each one inch in length. He found that he could arrange them all in the form of a triangle whose area was just as many square inches as there were matches. \n\r\nMad Ade then used up six of the matches, and found that with the remainder he could again construct another triangle whose area was just as many square inches as there were matches. \n\r\nAnd using another six matches Mad Ade could again do precisely the same. \n\r\nHow many matches were there in the box originally? \n\r\nNote that the match-box can hold maximum of 50 matches.", "hint": "There are two possible answers!", "answer": "Initially, there were either 42 or 36 matches in the match-box. \n\r\nThere are 42 matches in the box with which he could form a triangle 20, 15, 7, with an area of 42 square inches. After 6 matches had been used, the remaining 36 matches would form a triangle 17, 10, 9, with an area of 36 square inches. After using another 6 matches, the remaining 30 matches would form a triangle 13, 12, 5, with an area of 30 square inches. After using another 6, the 24 remaining would form a triangle 10, 8, 6, with an area of 24 square inches. \n\r\nThus, there are two possible answers. There were either 42 or 36 matches in the match-box. \n\n\r\nAlso it is interesting to know that there are just 5 such triangles for which the perimeter and the area is the same (assuming all sides are integers) and they are :\r\n24 (10, 8, 6) \n\r\n30 (13, 12, 5) \n\r\n36 (17, 10, 9) \n\r\n42 (20, 15, 7) \n\r\n60 (29, 25, 6)", "category": "Math", "date": "05/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade bought a little box of midget matches, each one inch in length. He found that he could arrange them all in the form of a triangle whose area was just as many square inches as there were matches. \n\r\nMad Ade then used up six of the matches, and found that with the remainder he could again construct another triangle whose area was just as many square inches as there were matches. \n\r\nAnd using another six matches Mad Ade could again do precisely the same. \n\r\nHow many matches were there in the box originally? \n\r\nNote that the match-box can hold maximum of 50 matches.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nInitially, there were either 42 or 36 matches in the match-box. \n\r\nThere are 42 matches in the box with which he could form a triangle 20, 15, 7, with an area of 42 square inches. After 6 matches had been used, the remaining 36 matches would form a triangle 17, 10, 9, with an area of 36 square inches. After using another 6 matches, the remaining 30 matches would form a triangle 13, 12, 5, with an area of 30 square inches. After using another 6, the 24 remaining would form a triangle 10, 8, 6, with an area of 24 square inches. \n\r\nThus, there are two possible answers. There were either 42 or 36 matches in the match-box. \n\n\r\nAlso it is interesting to know that there are just 5 such triangles for which the perimeter and the area is the same (assuming all sides are integers) and they are :\r\n24 (10, 8, 6) \n\r\n30 (13, 12, 5) \n\r\n36 (17, 10, 9) \n\r\n42 (20, 15, 7) \n\r\n60 (29, 25, 6)\n<|im_start|>answer\nInitially, there were either 42 or 36 matches in the match-box. \n\r\nThere are 42 matches in the box with which he could form a triangle 20, 15, 7, with an area of 42 square inches. After 6 matches had been used, the remaining 36 matches would form a triangle 17, 10, 9, with an area of 36 square inches. After using another 6 matches, the remaining 30 matches would form a triangle 13, 12, 5, with an area of 30 square inches. After using another 6, the 24 remaining would form a triangle 10, 8, 6, with an area of 24 square inches. \n\r\nThus, there are two possible answers. There were either 42 or 36 matches in the match-box. \n\n\r\nAlso it is interesting to know that there are just 5 such triangles for which the perimeter and the area is the same (assuming all sides are integers) and they are :\r\n24 (10, 8, 6) \n\r\n30 (13, 12, 5) \n\r\n36 (17, 10, 9) \n\r\n42 (20, 15, 7) \n\r\n60 (29, 25, 6)\n<|im_end|>" }, { "id": "#6820", "title": "Wrong Price", "fun": 2.13, "difficulty": 1.9000000000000001, "author": "dumbell", "desc": "If you purchased some games (costing a total of £27.80) plus 32 cans of cola, 88 postcards and a large amount of 12p sweets, why would your suspicions be justified if the total cost was £64.78?", "hint": "No hint available.", "answer": "£64.78 is not divisible by four, but all the parts of the total (2780, 32, 88, 12) are.", "category": "Math", "date": "08/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you purchased some games (costing a total of £27.80) plus 32 cans of cola, 88 postcards and a large amount of 12p sweets, why would your suspicions be justified if the total cost was £64.78?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n£64.78 is not divisible by four, but all the parts of the total (2780, 32, 88, 12) are.\n<|im_start|>answer\n£64.78 is not divisible by four, but all the parts of the total (2780, 32, 88, 12) are.\n<|im_end|>" }, { "id": "#45152", "title": "Landlords and Roommates", "fun": 2.13, "difficulty": 1.65, "author": "whsprec", "desc": "Four college students were the landlords from four different apartment companies all on the same street. Times were tough, so each student had to take in a roommate. From the clues below, can you find the landlord, the roommate, the company, and the position on the street from left to right?\n\r\n1 - The landlord of Eastbrooke did not live next door to his fellow landlord Max.\r\n2 - Larry stayed at one of the end apartments, which was not Wilson Acres.\r\n3 - Daniel, who ran the apartment just to the right of where Russell was staying, was next door to the Sherwin Hills apartments, which was not at the end of the line.\r\n4 - Robert stayed next door to Wilson Acres.\r\n5 - Max ran the apartments next door to where Larry was staying.\r\n6 - Brandon ran the apartments that had only one apartment next door, the one where Robert was staying.\r\n7 - Aaron is a landlord, Tony is a roommate, and Commerce is a company.", "hint": "No hint available.", "answer": "Eastbrooke is first with landlord Aaron and roommate Russell.\r\nWilson Acres in second with landlord Daniel and roommate Tony.\r\nSherwin Hills is third with landlord Max and roommate Robert.\r\nCommerce is last with landlord Brandon and roommate Larry.", "category": "Logic", "date": "08/26/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour college students were the landlords from four different apartment companies all on the same street. Times were tough, so each student had to take in a roommate. From the clues below, can you find the landlord, the roommate, the company, and the position on the street from left to right?\n\r\n1 - The landlord of Eastbrooke did not live next door to his fellow landlord Max.\r\n2 - Larry stayed at one of the end apartments, which was not Wilson Acres.\r\n3 - Daniel, who ran the apartment just to the right of where Russell was staying, was next door to the Sherwin Hills apartments, which was not at the end of the line.\r\n4 - Robert stayed next door to Wilson Acres.\r\n5 - Max ran the apartments next door to where Larry was staying.\r\n6 - Brandon ran the apartments that had only one apartment next door, the one where Robert was staying.\r\n7 - Aaron is a landlord, Tony is a roommate, and Commerce is a company.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEastbrooke is first with landlord Aaron and roommate Russell.\r\nWilson Acres in second with landlord Daniel and roommate Tony.\r\nSherwin Hills is third with landlord Max and roommate Robert.\r\nCommerce is last with landlord Brandon and roommate Larry.\n<|im_start|>answer\nEastbrooke is first with landlord Aaron and roommate Russell.\r\nWilson Acres in second with landlord Daniel and roommate Tony.\r\nSherwin Hills is third with landlord Max and roommate Robert.\r\nCommerce is last with landlord Brandon and roommate Larry.\n<|im_end|>" }, { "id": "#43173", "title": "Justin's Marbles", "fun": 2.13, "difficulty": 2.82, "author": "cnmne", "desc": "Justin has a bag of marbles and nine friends. He gives Mike exactly 1/2 of the marbles. He gives Paul exactly 1/3 of the remaining marbles. He gives Dave exactly 1/4 of the remaining marbles. He gives Bert exactly 1/5 of the remaining marbles. He gives Kyle exactly 1/6 of the remaining marbles. He gives Andy 1/7 of the remaining marbles. He gives Rick 1/8 of the remaining marbles. He gives Fred 1/9 of the remaining marbles. He gives Will 1/10 of the remaining marbles. What is the smallest quantity of marbles that Justin still has in the bag?", "hint": "No hint available.", "answer": "For each friend that Justin gives marbles, you need to calculate the fraction of the original quantity of marbles that Justin keeps in his possession (keep), the fraction of the original quantity of marbles that Justin gives to that friend (give), and the prime factorization of the denominator of the fraction given to that friend (factor).\n\r\nMike: keep 1 * 1/2 = 1/2, give 1 * 1/2 = 1/2, factor 2 = 2\r\nPaul: keep 1/2 * 2/3 = 1/3, give 1/2 * 1/3 = 1/6, factor 6 = 2 * 3\r\nDave: keep 1/3 * 3/4 = 1/4, give 1/3 * 1/4 = 1/12, factor 12 = 2 * 2 * 3\r\nBert: keep 1/4 * 4/5 = 1/5, give 1/4 * 1/5 = 1/20, factor 20 = 2 * 2 * 5\r\nKyle: keep 1/5 * 5/6 = 1/6, give 1/5 * 1/6 = 1/30, factor 30 = 2 * 3 * 5\r\nAndy: keep 1/6 * 6/7 = 1/7, give 1/6 * 1/7 = 1/42, factor 42 = 2 * 3 * 7\r\nRick: keep 1/7 * 7/8 = 1/8, give 1/7 * 1/8 = 1/56, factor 56 = 2 * 2 * 2 * 7\r\nFred: keep 1/8 * 8/9 = 1/9, give 1/8 * 1/9 = 1/72, factor 72 = 2 * 2 * 2 * 3 * 3\r\nWill: keep 1/9 * 9/10 = 1/10, give 1/9 * 1/10 = 1/90, factor 90 = 2 * 3 * 3 * 5\n\r\nThe lowest common multiple of the denominators of the \"give\" fractions is:\r\n2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520\n\r\nThe quantity of marbles that Justin still possesses is:\r\n2520 * 1/10 = 252\n\r\nJustin starts with 2520 marbles.\r\nMike gets 1/2 of 2520, or 1260. Justin still has 1/2 of 2520, or 1260.\r\nPaul gets 1/3 of 1260, or 420. Justin still has 2/3 of 1260, or 840.\r\nDave gets 1/4 of 840, or 210. Justin still has 3/4 of 840, or 630.\r\nBert gets 1/5 of 630, or 126. Justin still has 4/5 of 630, or 504.\r\nKyle gets 1/6 of 504, or 84. Justin still has 5/6 of 504, or 420.\r\nAndy gets 1/7 of 420, or 60. Justin still has 6/7 of 420, or 360.\r\nRick gets 1/8 of 360, or 45. Justin still has 7/8 of 360, or 315.\r\nFred gets 1/9 of 315, or 35. Justin still has 8/9 of 315, or 280.\r\nWill gets 1/10 of 280, or 28. Justin still has 9/10 of 280, or 252.", "category": "Math", "date": "09/24/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJustin has a bag of marbles and nine friends. He gives Mike exactly 1/2 of the marbles. He gives Paul exactly 1/3 of the remaining marbles. He gives Dave exactly 1/4 of the remaining marbles. He gives Bert exactly 1/5 of the remaining marbles. He gives Kyle exactly 1/6 of the remaining marbles. He gives Andy 1/7 of the remaining marbles. He gives Rick 1/8 of the remaining marbles. He gives Fred 1/9 of the remaining marbles. He gives Will 1/10 of the remaining marbles. What is the smallest quantity of marbles that Justin still has in the bag?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFor each friend that Justin gives marbles, you need to calculate the fraction of the original quantity of marbles that Justin keeps in his possession (keep), the fraction of the original quantity of marbles that Justin gives to that friend (give), and the prime factorization of the denominator of the fraction given to that friend (factor).\n\r\nMike: keep 1 * 1/2 = 1/2, give 1 * 1/2 = 1/2, factor 2 = 2\r\nPaul: keep 1/2 * 2/3 = 1/3, give 1/2 * 1/3 = 1/6, factor 6 = 2 * 3\r\nDave: keep 1/3 * 3/4 = 1/4, give 1/3 * 1/4 = 1/12, factor 12 = 2 * 2 * 3\r\nBert: keep 1/4 * 4/5 = 1/5, give 1/4 * 1/5 = 1/20, factor 20 = 2 * 2 * 5\r\nKyle: keep 1/5 * 5/6 = 1/6, give 1/5 * 1/6 = 1/30, factor 30 = 2 * 3 * 5\r\nAndy: keep 1/6 * 6/7 = 1/7, give 1/6 * 1/7 = 1/42, factor 42 = 2 * 3 * 7\r\nRick: keep 1/7 * 7/8 = 1/8, give 1/7 * 1/8 = 1/56, factor 56 = 2 * 2 * 2 * 7\r\nFred: keep 1/8 * 8/9 = 1/9, give 1/8 * 1/9 = 1/72, factor 72 = 2 * 2 * 2 * 3 * 3\r\nWill: keep 1/9 * 9/10 = 1/10, give 1/9 * 1/10 = 1/90, factor 90 = 2 * 3 * 3 * 5\n\r\nThe lowest common multiple of the denominators of the \"give\" fractions is:\r\n2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520\n\r\nThe quantity of marbles that Justin still possesses is:\r\n2520 * 1/10 = 252\n\r\nJustin starts with 2520 marbles.\r\nMike gets 1/2 of 2520, or 1260. Justin still has 1/2 of 2520, or 1260.\r\nPaul gets 1/3 of 1260, or 420. Justin still has 2/3 of 1260, or 840.\r\nDave gets 1/4 of 840, or 210. Justin still has 3/4 of 840, or 630.\r\nBert gets 1/5 of 630, or 126. Justin still has 4/5 of 630, or 504.\r\nKyle gets 1/6 of 504, or 84. Justin still has 5/6 of 504, or 420.\r\nAndy gets 1/7 of 420, or 60. Justin still has 6/7 of 420, or 360.\r\nRick gets 1/8 of 360, or 45. Justin still has 7/8 of 360, or 315.\r\nFred gets 1/9 of 315, or 35. Justin still has 8/9 of 315, or 280.\r\nWill gets 1/10 of 280, or 28. Justin still has 9/10 of 280, or 252.\n<|im_start|>answer\nFor each friend that Justin gives marbles, you need to calculate the fraction of the original quantity of marbles that Justin keeps in his possession (keep), the fraction of the original quantity of marbles that Justin gives to that friend (give), and the prime factorization of the denominator of the fraction given to that friend (factor).\n\r\nMike: keep 1 * 1/2 = 1/2, give 1 * 1/2 = 1/2, factor 2 = 2\r\nPaul: keep 1/2 * 2/3 = 1/3, give 1/2 * 1/3 = 1/6, factor 6 = 2 * 3\r\nDave: keep 1/3 * 3/4 = 1/4, give 1/3 * 1/4 = 1/12, factor 12 = 2 * 2 * 3\r\nBert: keep 1/4 * 4/5 = 1/5, give 1/4 * 1/5 = 1/20, factor 20 = 2 * 2 * 5\r\nKyle: keep 1/5 * 5/6 = 1/6, give 1/5 * 1/6 = 1/30, factor 30 = 2 * 3 * 5\r\nAndy: keep 1/6 * 6/7 = 1/7, give 1/6 * 1/7 = 1/42, factor 42 = 2 * 3 * 7\r\nRick: keep 1/7 * 7/8 = 1/8, give 1/7 * 1/8 = 1/56, factor 56 = 2 * 2 * 2 * 7\r\nFred: keep 1/8 * 8/9 = 1/9, give 1/8 * 1/9 = 1/72, factor 72 = 2 * 2 * 2 * 3 * 3\r\nWill: keep 1/9 * 9/10 = 1/10, give 1/9 * 1/10 = 1/90, factor 90 = 2 * 3 * 3 * 5\n\r\nThe lowest common multiple of the denominators of the \"give\" fractions is:\r\n2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520\n\r\nThe quantity of marbles that Justin still possesses is:\r\n2520 * 1/10 = 252\n\r\nJustin starts with 2520 marbles.\r\nMike gets 1/2 of 2520, or 1260. Justin still has 1/2 of 2520, or 1260.\r\nPaul gets 1/3 of 1260, or 420. Justin still has 2/3 of 1260, or 840.\r\nDave gets 1/4 of 840, or 210. Justin still has 3/4 of 840, or 630.\r\nBert gets 1/5 of 630, or 126. Justin still has 4/5 of 630, or 504.\r\nKyle gets 1/6 of 504, or 84. Justin still has 5/6 of 504, or 420.\r\nAndy gets 1/7 of 420, or 60. Justin still has 6/7 of 420, or 360.\r\nRick gets 1/8 of 360, or 45. Justin still has 7/8 of 360, or 315.\r\nFred gets 1/9 of 315, or 35. Justin still has 8/9 of 315, or 280.\r\nWill gets 1/10 of 280, or 28. Justin still has 9/10 of 280, or 252.\n<|im_end|>" }, { "id": "#39142", "title": "The Eight Queens", "fun": 2.13, "difficulty": 2.84, "author": "Hrsemn4", "desc": "One of the most famous logic puzzles is the \"Eight Queens puzzle\". The object of this puzzle is to place 8 chess queens on a standard 8x8 chessboard so that no queen can be captured by any of the other queens.\n\r\nLogically, no queen can share the same row, column, or diagonal with any other queen.\n\r\nCan you discover an arrangement that works?", "hint": "No hint available.", "answer": "There are actually 12 completely unique solutions to this puzzle (unique meaning not simply rotating or flipping the board).\n\r\nUsing a standard system of numbering rows 1-8 moving away from the player and noting columns with letters a-h, here are the solutions:\n\r\n1) a1, g2, e3, h4, b5, d6, f7, c8\r\n2) a1, g2, d3, f4, h5, b6, e7, c8\r\n3) c1, a2, g3, e4, h5, b6, d7, f8\r\n4) d1, a2, e3, h4, b5, g6, c7, f8\r\n5) e1, a2, h3, d4, b5, g6, c7, f8\r\n6) e1, a2, d3, f4, h5, b6, g7, c8\r\n7) e1, a2, h3, f4, c5, g6, b7, d8\r\n8) e1, c2, a3, g4, b5, h6, f7, d8\r\n9) e1, g2, a3, d4, b5, h6, f7, c8\r\n10) f1, a2, e3, b4, h5, c6, g7, d8\r\n11) f1, c2, a3, h4, d5, b6, g7, e8\r\n12) g1, a2, c3, h4, f5, d6, b7, e8", "category": "Logic", "date": "11/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne of the most famous logic puzzles is the \"Eight Queens puzzle\". The object of this puzzle is to place 8 chess queens on a standard 8x8 chessboard so that no queen can be captured by any of the other queens.\n\r\nLogically, no queen can share the same row, column, or diagonal with any other queen.\n\r\nCan you discover an arrangement that works?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThere are actually 12 completely unique solutions to this puzzle (unique meaning not simply rotating or flipping the board).\n\r\nUsing a standard system of numbering rows 1-8 moving away from the player and noting columns with letters a-h, here are the solutions:\n\r\n1) a1, g2, e3, h4, b5, d6, f7, c8\r\n2) a1, g2, d3, f4, h5, b6, e7, c8\r\n3) c1, a2, g3, e4, h5, b6, d7, f8\r\n4) d1, a2, e3, h4, b5, g6, c7, f8\r\n5) e1, a2, h3, d4, b5, g6, c7, f8\r\n6) e1, a2, d3, f4, h5, b6, g7, c8\r\n7) e1, a2, h3, f4, c5, g6, b7, d8\r\n8) e1, c2, a3, g4, b5, h6, f7, d8\r\n9) e1, g2, a3, d4, b5, h6, f7, c8\r\n10) f1, a2, e3, b4, h5, c6, g7, d8\r\n11) f1, c2, a3, h4, d5, b6, g7, e8\r\n12) g1, a2, c3, h4, f5, d6, b7, e8\n<|im_start|>answer\nThere are actually 12 completely unique solutions to this puzzle (unique meaning not simply rotating or flipping the board).\n\r\nUsing a standard system of numbering rows 1-8 moving away from the player and noting columns with letters a-h, here are the solutions:\n\r\n1) a1, g2, e3, h4, b5, d6, f7, c8\r\n2) a1, g2, d3, f4, h5, b6, e7, c8\r\n3) c1, a2, g3, e4, h5, b6, d7, f8\r\n4) d1, a2, e3, h4, b5, g6, c7, f8\r\n5) e1, a2, h3, d4, b5, g6, c7, f8\r\n6) e1, a2, d3, f4, h5, b6, g7, c8\r\n7) e1, a2, h3, f4, c5, g6, b7, d8\r\n8) e1, c2, a3, g4, b5, h6, f7, d8\r\n9) e1, g2, a3, d4, b5, h6, f7, c8\r\n10) f1, a2, e3, b4, h5, c6, g7, d8\r\n11) f1, c2, a3, h4, d5, b6, g7, e8\r\n12) g1, a2, c3, h4, f5, d6, b7, e8\n<|im_end|>" }, { "id": "#6652", "title": "Jack & Jill", "fun": 2.13, "difficulty": 2.89, "author": "majd", "desc": "Jack and Jill are climbing down a vertical wall. They both use ropes hanging from the ceiling of a huge room. They start at the same time from the top of the wall which is 16 meters tall. The race is divided into two stages; the first 8 meters and the last 8 meters. A penalty of half a minute waiting time is placed upon whoever loses the first stage (first 8 meters) and it commences as soon as the winner finishes the first 8 meters.\n\r\nThe following describes their climbing techniques:\n\r\n1. Jack climbs down in a zigzag way (moving one step downwards diagonally at a fixed angle from the horizon line). In each step movement he completes the distance of 1 meter diagonally. Initially, his feet are distant 60 cm apart aligned on a perfectly horizontal line. It takes him 15 seconds to complete each move. Jack has to rest for 1 minute for every 8 meters he vertically completes.\r\n2. Jill hops down according to a perfect half circular arc movement. In each hop, she moves a distance of 1.57 meters along the arc path (not the vertical). It takes her 15 seconds to complete each hop. Jill has to rest for 1 minute for every 6 meters she vertically completes.\n\r\nWho will reach the ground first and how many additional minutes will it take the loser to finish the race?", "hint": "No hint available.", "answer": "Jack will win the race and it will take an additional half minute to catch up with him.\n\r\nJacks moves 0.8 meters vertically in each step movement:\n\r\nAccording to Pythagoras theorem for right angled triangle:\n\r\nA^2 = B^2+C^2 (where A is the hypotenuse)\r\nReplacing A by the diagonally crossed distance, B by the distance between Jack's feet and C by the vertically climbed distance:\r\n1^2 = 0.6^2+C^2\r\nC = 0.8 m\n\r\nJill moves 1 meter vertically in each hop.\n\r\nAccording to the circle circumference calculation:\n\r\nCircumference = Diameter * Pi \r\n(where Pi = 3.14 and Diameter is the vertically climbed down distance)\r\n2 * 1.57 = D * 3.14\r\nDiameter = 1 meter\n\r\n1.Time: 1.5 minutes elapsing\r\nJack: Finished 4.8 meters\t\r\nJill: Finished 6.0 meters and starting her 1 minute rest\n\r\n2.Time: 2.5 minutes elapsing\r\nJack: Finished 8.0 meters (crossed an additional 3.2 meters in 1 minute while Jill is resting)\t\t\r\nJill: Finished 6.0 meters and ending her 1 minute rest\r\nNote: Losing the first stage (8 meters), Jill has to wait for half minute penalty time and at the same time Jack starts his 1 minute rest having crossed 8.0 meters.\n\r\n3. Time: 3.0 minutes elapsing\r\nJack: Finished 8.0 meters and still resting for another half a minute\r\nJill: Finished 6.0 meters and resuming her climb down having finished the half \r\nminute penalty\n\r\n4.Time: 3.5 minutes elapsing\r\nJack: Finished 8.0 meters and ending his 1 minute rest\t\t\r\nJill: Finished 8.0 meters (crossed an additional 2.0 meters in half minute while Jack is resting)\t\n\r\n5. Time: 4.5 minutes elapsing\r\nJack: Finished 11.2 meters \t\t\r\nJill: Finished 12.0 meters and starting her 1 minute rest\n\r\n6.Time: 5.5 minutes elapsing\r\nJack: Finished 14.4 meters (crossed an additional 3.2 meters in 1 minute while Jill is resting)\t\t\r\nJill: Finished 12.0 meters and ending her 1 minute rest\n\r\n7.Time: 6.0 minutes elapsing\r\nJack: Finishing the race (16 meters) as the winner\r\nJill: Finished 14.0 meters and needing another two meters to finish the race which will take her an additional half minute", "category": "Math", "date": "08/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack and Jill are climbing down a vertical wall. They both use ropes hanging from the ceiling of a huge room. They start at the same time from the top of the wall which is 16 meters tall. The race is divided into two stages; the first 8 meters and the last 8 meters. A penalty of half a minute waiting time is placed upon whoever loses the first stage (first 8 meters) and it commences as soon as the winner finishes the first 8 meters.\n\r\nThe following describes their climbing techniques:\n\r\n1. Jack climbs down in a zigzag way (moving one step downwards diagonally at a fixed angle from the horizon line). In each step movement he completes the distance of 1 meter diagonally. Initially, his feet are distant 60 cm apart aligned on a perfectly horizontal line. It takes him 15 seconds to complete each move. Jack has to rest for 1 minute for every 8 meters he vertically completes.\r\n2. Jill hops down according to a perfect half circular arc movement. In each hop, she moves a distance of 1.57 meters along the arc path (not the vertical). It takes her 15 seconds to complete each hop. Jill has to rest for 1 minute for every 6 meters she vertically completes.\n\r\nWho will reach the ground first and how many additional minutes will it take the loser to finish the race?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJack will win the race and it will take an additional half minute to catch up with him.\n\r\nJacks moves 0.8 meters vertically in each step movement:\n\r\nAccording to Pythagoras theorem for right angled triangle:\n\r\nA^2 = B^2+C^2 (where A is the hypotenuse)\r\nReplacing A by the diagonally crossed distance, B by the distance between Jack's feet and C by the vertically climbed distance:\r\n1^2 = 0.6^2+C^2\r\nC = 0.8 m\n\r\nJill moves 1 meter vertically in each hop.\n\r\nAccording to the circle circumference calculation:\n\r\nCircumference = Diameter * Pi \r\n(where Pi = 3.14 and Diameter is the vertically climbed down distance)\r\n2 * 1.57 = D * 3.14\r\nDiameter = 1 meter\n\r\n1.Time: 1.5 minutes elapsing\r\nJack: Finished 4.8 meters\t\r\nJill: Finished 6.0 meters and starting her 1 minute rest\n\r\n2.Time: 2.5 minutes elapsing\r\nJack: Finished 8.0 meters (crossed an additional 3.2 meters in 1 minute while Jill is resting)\t\t\r\nJill: Finished 6.0 meters and ending her 1 minute rest\r\nNote: Losing the first stage (8 meters), Jill has to wait for half minute penalty time and at the same time Jack starts his 1 minute rest having crossed 8.0 meters.\n\r\n3. Time: 3.0 minutes elapsing\r\nJack: Finished 8.0 meters and still resting for another half a minute\r\nJill: Finished 6.0 meters and resuming her climb down having finished the half \r\nminute penalty\n\r\n4.Time: 3.5 minutes elapsing\r\nJack: Finished 8.0 meters and ending his 1 minute rest\t\t\r\nJill: Finished 8.0 meters (crossed an additional 2.0 meters in half minute while Jack is resting)\t\n\r\n5. Time: 4.5 minutes elapsing\r\nJack: Finished 11.2 meters \t\t\r\nJill: Finished 12.0 meters and starting her 1 minute rest\n\r\n6.Time: 5.5 minutes elapsing\r\nJack: Finished 14.4 meters (crossed an additional 3.2 meters in 1 minute while Jill is resting)\t\t\r\nJill: Finished 12.0 meters and ending her 1 minute rest\n\r\n7.Time: 6.0 minutes elapsing\r\nJack: Finishing the race (16 meters) as the winner\r\nJill: Finished 14.0 meters and needing another two meters to finish the race which will take her an additional half minute\n<|im_start|>answer\nJack will win the race and it will take an additional half minute to catch up with him.\n\r\nJacks moves 0.8 meters vertically in each step movement:\n\r\nAccording to Pythagoras theorem for right angled triangle:\n\r\nA^2 = B^2+C^2 (where A is the hypotenuse)\r\nReplacing A by the diagonally crossed distance, B by the distance between Jack's feet and C by the vertically climbed distance:\r\n1^2 = 0.6^2+C^2\r\nC = 0.8 m\n\r\nJill moves 1 meter vertically in each hop.\n\r\nAccording to the circle circumference calculation:\n\r\nCircumference = Diameter * Pi \r\n(where Pi = 3.14 and Diameter is the vertically climbed down distance)\r\n2 * 1.57 = D * 3.14\r\nDiameter = 1 meter\n\r\n1.Time: 1.5 minutes elapsing\r\nJack: Finished 4.8 meters\t\r\nJill: Finished 6.0 meters and starting her 1 minute rest\n\r\n2.Time: 2.5 minutes elapsing\r\nJack: Finished 8.0 meters (crossed an additional 3.2 meters in 1 minute while Jill is resting)\t\t\r\nJill: Finished 6.0 meters and ending her 1 minute rest\r\nNote: Losing the first stage (8 meters), Jill has to wait for half minute penalty time and at the same time Jack starts his 1 minute rest having crossed 8.0 meters.\n\r\n3. Time: 3.0 minutes elapsing\r\nJack: Finished 8.0 meters and still resting for another half a minute\r\nJill: Finished 6.0 meters and resuming her climb down having finished the half \r\nminute penalty\n\r\n4.Time: 3.5 minutes elapsing\r\nJack: Finished 8.0 meters and ending his 1 minute rest\t\t\r\nJill: Finished 8.0 meters (crossed an additional 2.0 meters in half minute while Jack is resting)\t\n\r\n5. Time: 4.5 minutes elapsing\r\nJack: Finished 11.2 meters \t\t\r\nJill: Finished 12.0 meters and starting her 1 minute rest\n\r\n6.Time: 5.5 minutes elapsing\r\nJack: Finished 14.4 meters (crossed an additional 3.2 meters in 1 minute while Jill is resting)\t\t\r\nJill: Finished 12.0 meters and ending her 1 minute rest\n\r\n7.Time: 6.0 minutes elapsing\r\nJack: Finishing the race (16 meters) as the winner\r\nJill: Finished 14.0 meters and needing another two meters to finish the race which will take her an additional half minute\n<|im_end|>" }, { "id": "#443", "title": "It takes a clock", "fun": 2.13, "difficulty": 1.73, "author": "Spikejw1", "desc": "It takes a clock 2 seconds to strike 2 o`clock.\n\r\nHow long will it take to strike 3 o`clock?", "hint": "No hint available.", "answer": "It will take 4 seconds.\n\r\nSince the clock strikes 2 o`clock in 2 seconds, these two seconds are the interval between two strikes. Between the first and the third strike there are two intervals, so it will be 4 seconds.", "category": "Logic", "date": "05/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt takes a clock 2 seconds to strike 2 o`clock.\n\r\nHow long will it take to strike 3 o`clock?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt will take 4 seconds.\n\r\nSince the clock strikes 2 o`clock in 2 seconds, these two seconds are the interval between two strikes. Between the first and the third strike there are two intervals, so it will be 4 seconds.\n<|im_start|>answer\nIt will take 4 seconds.\n\r\nSince the clock strikes 2 o`clock in 2 seconds, these two seconds are the interval between two strikes. Between the first and the third strike there are two intervals, so it will be 4 seconds.\n<|im_end|>" }, { "id": "#2307", "title": "Too Slow", "fun": 2.13, "difficulty": 1.19, "author": "mishiko", "desc": "You have 1 minute to answer this question:\r\n(7463+35235723-857572+32427472+325235-2352+3567-2-4564)x0x5765x45x2 = ?", "hint": "No hint available.", "answer": "0 because if you multiply anything by 0 you get 0.", "category": "Math", "date": "02/12/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have 1 minute to answer this question:\r\n(7463+35235723-857572+32427472+325235-2352+3567-2-4564)x0x5765x45x2 = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n0 because if you multiply anything by 0 you get 0.\n<|im_start|>answer\n0 because if you multiply anything by 0 you get 0.\n<|im_end|>" }, { "id": "#5167", "title": "Geography and Maths", "fun": 2.13, "difficulty": 2.06, "author": "hippychick", "desc": "If 3=e what does 50337=?", "hint": "Think about the title.", "answer": "Leeds=A town. If you put the numbers 50337 in a calculator and turned it upside down it would read Leeds.", "category": "Math", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 3=e what does 50337=?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLeeds=A town. If you put the numbers 50337 in a calculator and turned it upside down it would read Leeds.\n<|im_start|>answer\nLeeds=A town. If you put the numbers 50337 in a calculator and turned it upside down it would read Leeds.\n<|im_end|>" }, { "id": "#3358", "title": "Pointing Fingers", "fun": 2.13, "difficulty": 1.5, "author": "204_BLaZe_41", "desc": "Have you ever heard the phrase, \"never point a finger at someone because there will always be three pointing back at you\".\n\r\nIf there were three people talking to each other, and two of them point one finger at a 3rd person. If the third person points one finger from each hand at each of the other two, how many fingers will be pointing at the third person?", "hint": "No hint available.", "answer": "Eight.\n\r\n6 from himself\r\n2 from the 2 other people", "category": "Math", "date": "04/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHave you ever heard the phrase, \"never point a finger at someone because there will always be three pointing back at you\".\n\r\nIf there were three people talking to each other, and two of them point one finger at a 3rd person. If the third person points one finger from each hand at each of the other two, how many fingers will be pointing at the third person?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEight.\n\r\n6 from himself\r\n2 from the 2 other people\n<|im_start|>answer\nEight.\n\r\n6 from himself\r\n2 from the 2 other people\n<|im_end|>" }, { "id": "#3736", "title": "10 + 10 equals 4", "fun": 2.13, "difficulty": 1.54, "author": "cathalmccabe", "desc": "How can 10 + 10 equal to four?", "hint": "No hint available.", "answer": "If the first 2 figures are written in binary; 10 is the decimal 2 written in binary.\r\n2 + 2 = 4", "category": "Math", "date": "04/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can 10 + 10 equal to four?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the first 2 figures are written in binary; 10 is the decimal 2 written in binary.\r\n2 + 2 = 4\n<|im_start|>answer\nIf the first 2 figures are written in binary; 10 is the decimal 2 written in binary.\r\n2 + 2 = 4\n<|im_end|>" }, { "id": "#672", "title": "Help Jeff", "fun": 2.13, "difficulty": 2.15, "author": "vikass", "desc": "Jeff likes racing his little sports car, but he knows that safety should always be kept in mind, so he practices regularly. On one particular day, Jeff goes out to the practice track and does two laps at an average of 100 km/h, two laps at an average of 102 km/h, two laps at an average of 140km/h and two laps at an average of 150 km/h. Now Jeff would like to know what his average speed was during that practice session. Can you help him?", "hint": "No hint available.", "answer": "The answer is 119 and NOT 123. How? Well, you have probably made the fatal assumption that time is not important here in Jeff's world and yet you should know that time is important everywhere.", "category": "Math", "date": "06/29/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeff likes racing his little sports car, but he knows that safety should always be kept in mind, so he practices regularly. On one particular day, Jeff goes out to the practice track and does two laps at an average of 100 km/h, two laps at an average of 102 km/h, two laps at an average of 140km/h and two laps at an average of 150 km/h. Now Jeff would like to know what his average speed was during that practice session. Can you help him?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is 119 and NOT 123. How? Well, you have probably made the fatal assumption that time is not important here in Jeff's world and yet you should know that time is important everywhere.\n<|im_start|>answer\nThe answer is 119 and NOT 123. How? Well, you have probably made the fatal assumption that time is not important here in Jeff's world and yet you should know that time is important everywhere.\n<|im_end|>" }, { "id": "#6925", "title": "Wonder Number", "fun": 2.13, "difficulty": 2.06, "author": "majd", "desc": "Try to find out a multi-digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times.", "hint": "No hint available.", "answer": "The number is: 12345679\r\n12345679 * 9 = 111111111\r\n12345679 * 18 = 222222222\r\n12345679 * 27 = 333333333\r\nAnd so on...", "category": "Math", "date": "08/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTry to find out a multi-digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is: 12345679\r\n12345679 * 9 = 111111111\r\n12345679 * 18 = 222222222\r\n12345679 * 27 = 333333333\r\nAnd so on...\n<|im_start|>answer\nThe number is: 12345679\r\n12345679 * 9 = 111111111\r\n12345679 * 18 = 222222222\r\n12345679 * 27 = 333333333\r\nAnd so on...\n<|im_end|>" }, { "id": "#21404", "title": "Quocorrian Math 3", "fun": 2.13, "difficulty": 2.94, "author": "CPlusPlusMan", "desc": "Bound by your promise to stay on Quocorria until you've mastered all of their numbering systems, you find yourself still stuck on Quocorria. \n\r\nNow, while attending a Quocorrian mathematical seminar, the speaker mentions yet another form of math. After the speech, you approach him with questions on this system. Being like the rest of the Quocorrians you've met, he only gives you a sheet of paper, this time with six problems on it, and leaves.\n\r\nHere's the paper:\r\n2+2=11\r\n6-4=28\r\n4*5=100\r\n10/5=10\r\n3-4=13\r\n4+3*5-6=9497\n\r\nSo, knowing that those are all true, what's 3*6?", "hint": "This system is not commutative. 3+2 is not the same as 2+3.\r\nThe Order of Operations is the same as our own.\r\n1+1=5.5", "answer": "90. \n\r\nIn this system, you multiply the rightmost number by 1, the second rightmost number by 10, the third by 100, and so on. Solve the problem like that, and divide by two. \n\r\nSo 2+2 would look like (20+2)/2.\r\n4+3*5-6 would look like (4000+300*50-6)/2", "category": "Math", "date": "03/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBound by your promise to stay on Quocorria until you've mastered all of their numbering systems, you find yourself still stuck on Quocorria. \n\r\nNow, while attending a Quocorrian mathematical seminar, the speaker mentions yet another form of math. After the speech, you approach him with questions on this system. Being like the rest of the Quocorrians you've met, he only gives you a sheet of paper, this time with six problems on it, and leaves.\n\r\nHere's the paper:\r\n2+2=11\r\n6-4=28\r\n4*5=100\r\n10/5=10\r\n3-4=13\r\n4+3*5-6=9497\n\r\nSo, knowing that those are all true, what's 3*6?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n90. \n\r\nIn this system, you multiply the rightmost number by 1, the second rightmost number by 10, the third by 100, and so on. Solve the problem like that, and divide by two. \n\r\nSo 2+2 would look like (20+2)/2.\r\n4+3*5-6 would look like (4000+300*50-6)/2\n<|im_start|>answer\n90. \n\r\nIn this system, you multiply the rightmost number by 1, the second rightmost number by 10, the third by 100, and so on. Solve the problem like that, and divide by two. \n\r\nSo 2+2 would look like (20+2)/2.\r\n4+3*5-6 would look like (4000+300*50-6)/2\n<|im_end|>" }, { "id": "#23005", "title": "Getting Nowhere", "fun": 2.13, "difficulty": 1.65, "author": "jacintan", "desc": "I'm running really fast on top of something that doesn't have a motor and cannot move by itself, yet I'm not getting anywhere. How is this possible?", "hint": "No hint available.", "answer": "I'm on a log that's floating in the water, turning around as I run.", "category": "Logic", "date": "05/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI'm running really fast on top of something that doesn't have a motor and cannot move by itself, yet I'm not getting anywhere. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI'm on a log that's floating in the water, turning around as I run.\n<|im_start|>answer\nI'm on a log that's floating in the water, turning around as I run.\n<|im_end|>" }, { "id": "#21139", "title": "It All Adds Up", "fun": 2.12, "difficulty": 2.0, "author": "fishmed", "desc": "The first number to have its factors add up to be more than itself is 12 (6, 4, 3, 2, 1). This does not include the number itself. Quickly now, what are the next three numbers for which this can be said?", "hint": "No hint available.", "answer": "18 (9, 6, 3, 2, 1)\r\n20 (10, 5, 4, 2, 1)\r\n24 (12, 8, 6, 4, 3, 2, 1)", "category": "Math", "date": "02/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe first number to have its factors add up to be more than itself is 12 (6, 4, 3, 2, 1). This does not include the number itself. Quickly now, what are the next three numbers for which this can be said?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n18 (9, 6, 3, 2, 1)\r\n20 (10, 5, 4, 2, 1)\r\n24 (12, 8, 6, 4, 3, 2, 1)\n<|im_start|>answer\n18 (9, 6, 3, 2, 1)\r\n20 (10, 5, 4, 2, 1)\r\n24 (12, 8, 6, 4, 3, 2, 1)\n<|im_end|>" }, { "id": "#699", "title": "Street Cars", "fun": 2.12, "difficulty": 2.13, "author": "vikass", "desc": "A man is walking down a street along which runs a streetcar line. He notices that, for every 40 streetcars\r\nwhich pass him traveling in the same direction as he, 60 pass in the opposite direction. If the man`s walking speed is 3 miles per hour, what is the average speed of the streetcars?", "hint": "No hint available.", "answer": "15 miles per hour", "category": "Math", "date": "07/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man is walking down a street along which runs a streetcar line. He notices that, for every 40 streetcars\r\nwhich pass him traveling in the same direction as he, 60 pass in the opposite direction. If the man`s walking speed is 3 miles per hour, what is the average speed of the streetcars?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15 miles per hour\n<|im_start|>answer\n15 miles per hour\n<|im_end|>" }, { "id": "#5281", "title": "x/z", "fun": 2.12, "difficulty": 2.08, "author": "Bobbrt", "desc": "If x/y = 4/7 and z/y = 3/2, then x/z = ? Give the answer as a fraction.", "hint": "No hint available.", "answer": "8/21\r\nJust take x/y * y/z = x/z. (the y's cancel each other)\r\nTherefore 4/7 * 2/3 = 8/21.", "category": "Math", "date": "07/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf x/y = 4/7 and z/y = 3/2, then x/z = ? Give the answer as a fraction.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8/21\r\nJust take x/y * y/z = x/z. (the y's cancel each other)\r\nTherefore 4/7 * 2/3 = 8/21.\n<|im_start|>answer\n8/21\r\nJust take x/y * y/z = x/z. (the y's cancel each other)\r\nTherefore 4/7 * 2/3 = 8/21.\n<|im_end|>" }, { "id": "#20801", "title": "Happy Birthday to You...", "fun": 2.12, "difficulty": 0.6000000000000001, "author": "ixilight_raven", "desc": "Sally wanted to know the birthday of four of her friends: DJ, Ali, Sean, Amy. They wouldn't tell her directly, but they each gave her one clue:\r\n1. DJ's Birthday is on an odd numbered day.\r\n2. Ali's Birthday is on the 6th\r\n3. Sean's Birthday is in April.\r\n4. Both Amy and DJ have birthdays like 12/12 (December 12th)\n\r\nCan you help Sally?", "hint": "No hint available.", "answer": "Ali: February 6th\r\nSean: April 9th\r\nDJ: July 7th\r\nAmy: October 10th", "category": "Logic-Grid", "date": "02/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSally wanted to know the birthday of four of her friends: DJ, Ali, Sean, Amy. They wouldn't tell her directly, but they each gave her one clue:\r\n1. DJ's Birthday is on an odd numbered day.\r\n2. Ali's Birthday is on the 6th\r\n3. Sean's Birthday is in April.\r\n4. Both Amy and DJ have birthdays like 12/12 (December 12th)\n\r\nCan you help Sally?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAli: February 6th\r\nSean: April 9th\r\nDJ: July 7th\r\nAmy: October 10th\n<|im_start|>answer\nAli: February 6th\r\nSean: April 9th\r\nDJ: July 7th\r\nAmy: October 10th\n<|im_end|>" }, { "id": "#25711", "title": "Lifestyles", "fun": 2.12, "difficulty": 1.22, "author": "SOCCER_CHICK", "desc": "Your goal is to figure out where the three friends live, what pets they keep and how old their houses are.\n\r\n1) Prince Line doesn't allow pets.\n\r\n2) Jamie is the oldest friend.\n\r\n3) Crystal hates lizards.\n\r\n4) The three friends are:Tammy; the one who lives on Queen Ave; and the one with a 4-year old house.\n\r\n5) Main Street is an old road and has no new houses.\n\r\n6) The oldest person has no pets.\n\r\n7) The 45-year old house is owned by someone with a pet fish.", "hint": "4 yrs is young, 45 is middle, and 98 is old.", "answer": "Crystal-Queen Ave-fish-45 yrs\r\nJamie-Prince Line-none-4 yrs\r\nTammy-Main Street-lizard-98 yrs", "category": "Logic-Grid", "date": "09/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYour goal is to figure out where the three friends live, what pets they keep and how old their houses are.\n\r\n1) Prince Line doesn't allow pets.\n\r\n2) Jamie is the oldest friend.\n\r\n3) Crystal hates lizards.\n\r\n4) The three friends are:Tammy; the one who lives on Queen Ave; and the one with a 4-year old house.\n\r\n5) Main Street is an old road and has no new houses.\n\r\n6) The oldest person has no pets.\n\r\n7) The 45-year old house is owned by someone with a pet fish.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCrystal-Queen Ave-fish-45 yrs\r\nJamie-Prince Line-none-4 yrs\r\nTammy-Main Street-lizard-98 yrs\n<|im_start|>answer\nCrystal-Queen Ave-fish-45 yrs\r\nJamie-Prince Line-none-4 yrs\r\nTammy-Main Street-lizard-98 yrs\n<|im_end|>" }, { "id": "#16350", "title": "Perfect Pyramid 2", "fun": 2.12, "difficulty": 2.63, "author": "cnmne", "desc": "Arrange the numbers 1 through 15 in the shape of a pyramid (1 number at the peak, 2 numbers in the second row down, 3 in the next row down, 4 in the next row, and 5 in the bottom row). The numbers must be arranged such that each number is equal to the difference of the two numbers directly below it. For example, if 6 and 13 are next to each other in the same row, then 7 must be placed on top of them.\n\r\nTo demonstrate, a three-level pyramid using the numbers 1 through 6 could be arranged as follows:\r\ntop row: 2\r\nsecond row: 5 3\r\nbottom row: 6 1 4", "hint": "No hint available.", "answer": "top row: 5\r\nsecond row: 9 4\r\nthird row: 2 11 7\r\nfourth row: 10 12 1 8\r\nbottom row: 13 3 15 14 6", "category": "Math", "date": "01/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the numbers 1 through 15 in the shape of a pyramid (1 number at the peak, 2 numbers in the second row down, 3 in the next row down, 4 in the next row, and 5 in the bottom row). The numbers must be arranged such that each number is equal to the difference of the two numbers directly below it. For example, if 6 and 13 are next to each other in the same row, then 7 must be placed on top of them.\n\r\nTo demonstrate, a three-level pyramid using the numbers 1 through 6 could be arranged as follows:\r\ntop row: 2\r\nsecond row: 5 3\r\nbottom row: 6 1 4\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\ntop row: 5\r\nsecond row: 9 4\r\nthird row: 2 11 7\r\nfourth row: 10 12 1 8\r\nbottom row: 13 3 15 14 6\n<|im_start|>answer\ntop row: 5\r\nsecond row: 9 4\r\nthird row: 2 11 7\r\nfourth row: 10 12 1 8\r\nbottom row: 13 3 15 14 6\n<|im_end|>" }, { "id": "#36133", "title": "3 More Integers", "fun": 2.12, "difficulty": 0.98, "author": "mik512", "desc": "What are the only three consecutive numbers that when all are added, the sum equals double the last integer?", "hint": "x + y + z = 2z", "answer": "1, 2, and 3!", "category": "Math", "date": "04/10/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat are the only three consecutive numbers that when all are added, the sum equals double the last integer?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1, 2, and 3!\n<|im_start|>answer\n1, 2, and 3!\n<|im_end|>" }, { "id": "#31530", "title": "Vacation Books", "fun": 2.12, "difficulty": 1.37, "author": "holly1447591", "desc": "Morgan came home from her vacation at Grandma's with 6 books. While she was away she purchased 3 books at the book store and got 1 book as a gift. During her stay at Grandma's, she also gave her cousin the 2 books that she finished.\n\r\nHow many books did she take with her when she left for her trip?", "hint": "Work backwards.", "answer": "Morgan started with 4 books.\n\r\nThis is one way to work backwards:\n\r\nMorgan returned with 6 books.\n\r\nShe gave away 2 of the books that she had. \r\nSo add those two books back to her total. \r\n6 + 2 = 8\n\r\nShe had received 1 book that she had not brought with her. \r\nSo subtract that book from her total. \r\n8 - 1 = 7\n\r\nShe bought 3 books that she had not brought with her. \r\nSo subtract those books from her total. \r\n7 - 3 = 4\n\r\nShe must have left for vacation with 4 books.", "category": "Math", "date": "07/04/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMorgan came home from her vacation at Grandma's with 6 books. While she was away she purchased 3 books at the book store and got 1 book as a gift. During her stay at Grandma's, she also gave her cousin the 2 books that she finished.\n\r\nHow many books did she take with her when she left for her trip?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMorgan started with 4 books.\n\r\nThis is one way to work backwards:\n\r\nMorgan returned with 6 books.\n\r\nShe gave away 2 of the books that she had. \r\nSo add those two books back to her total. \r\n6 + 2 = 8\n\r\nShe had received 1 book that she had not brought with her. \r\nSo subtract that book from her total. \r\n8 - 1 = 7\n\r\nShe bought 3 books that she had not brought with her. \r\nSo subtract those books from her total. \r\n7 - 3 = 4\n\r\nShe must have left for vacation with 4 books.\n<|im_start|>answer\nMorgan started with 4 books.\n\r\nThis is one way to work backwards:\n\r\nMorgan returned with 6 books.\n\r\nShe gave away 2 of the books that she had. \r\nSo add those two books back to her total. \r\n6 + 2 = 8\n\r\nShe had received 1 book that she had not brought with her. \r\nSo subtract that book from her total. \r\n8 - 1 = 7\n\r\nShe bought 3 books that she had not brought with her. \r\nSo subtract those books from her total. \r\n7 - 3 = 4\n\r\nShe must have left for vacation with 4 books.\n<|im_end|>" }, { "id": "#45695", "title": "Slumber Party Complications", "fun": 2.12, "difficulty": 0.79, "author": "dswilborn", "desc": "Hailey's mother thought that throwing her daughter a slumber party would be a simple matter of buying snacks and renting videos. She soon learned she was wrong, as each guest came with notes containing special instructions from their parents. Can you determine from the clues below which girl is which?\n\r\n1. Hailey invited her cousin (who was not Amaya), a classmate from school, and a friend from karate class.\n\r\n2. Samantha's note did not indicate that she had allergies.\n\r\n3. Hailey's mother was not pleased when she realized she had to wake up one of the girls at 5 am due to a karate meet she was attending.\n\r\n4. Kylie was either the girl who had to take medication before dinner or the cousin.\n\r\n5. Hailey's mom had never met Samantha before, but knew Amaya from school.", "hint": "Hailey's mom had met the cousin many times before!", "answer": "Kylie is Hailey's cousin who has allergies.\r\nAmaya is Hailey's classmate who takes medication.\r\nSamantha is the friend from karate who had to leave early.", "category": "Logic-Grid", "date": "11/10/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHailey's mother thought that throwing her daughter a slumber party would be a simple matter of buying snacks and renting videos. She soon learned she was wrong, as each guest came with notes containing special instructions from their parents. Can you determine from the clues below which girl is which?\n\r\n1. Hailey invited her cousin (who was not Amaya), a classmate from school, and a friend from karate class.\n\r\n2. Samantha's note did not indicate that she had allergies.\n\r\n3. Hailey's mother was not pleased when she realized she had to wake up one of the girls at 5 am due to a karate meet she was attending.\n\r\n4. Kylie was either the girl who had to take medication before dinner or the cousin.\n\r\n5. Hailey's mom had never met Samantha before, but knew Amaya from school.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKylie is Hailey's cousin who has allergies.\r\nAmaya is Hailey's classmate who takes medication.\r\nSamantha is the friend from karate who had to leave early.\n<|im_start|>answer\nKylie is Hailey's cousin who has allergies.\r\nAmaya is Hailey's classmate who takes medication.\r\nSamantha is the friend from karate who had to leave early.\n<|im_end|>" }, { "id": "#23872", "title": "Nature Hunt", "fun": 2.12, "difficulty": 0.65, "author": "LittleWriter", "desc": "Anabell, Scarlet, Wind and Josh went on a nature hunt in the park. Each one found something different. One found a deer, one found a rabbit burrow, one found a rare kind of ivy and one found bright orange berries. Who found what and in what order did they find them?\n\r\n1) Nothing the boys found has to do with animals.\n\r\n2) Scarlet loves bunnies.\n\r\n3) Neither girl likes berries.\n\r\n4) Josh was the last to find something.\n\r\n5) The one who found the ivy was first.\n\r\n6) A girl was not first.\n\r\n7) Wind found the ivy.\n\r\n8) Anabell was third.", "hint": "They each like what they found.\n\r\nWind is a boy.", "answer": "Wind found the ivy first.\r\nScarlet found the rabbit burrow second.\r\nAnabell found the deer third.\r\nJosh found the berries fourth.", "category": "Logic-Grid", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnabell, Scarlet, Wind and Josh went on a nature hunt in the park. Each one found something different. One found a deer, one found a rabbit burrow, one found a rare kind of ivy and one found bright orange berries. Who found what and in what order did they find them?\n\r\n1) Nothing the boys found has to do with animals.\n\r\n2) Scarlet loves bunnies.\n\r\n3) Neither girl likes berries.\n\r\n4) Josh was the last to find something.\n\r\n5) The one who found the ivy was first.\n\r\n6) A girl was not first.\n\r\n7) Wind found the ivy.\n\r\n8) Anabell was third.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWind found the ivy first.\r\nScarlet found the rabbit burrow second.\r\nAnabell found the deer third.\r\nJosh found the berries fourth.\n<|im_start|>answer\nWind found the ivy first.\r\nScarlet found the rabbit burrow second.\r\nAnabell found the deer third.\r\nJosh found the berries fourth.\n<|im_end|>" }, { "id": "#40740", "title": "How Many are There?", "fun": 2.12, "difficulty": 1.5, "author": "TRILLIONAIRE", "desc": "Fill in the blanks to make the sentences correct:\n\n\n\r\nNumber 1)\n\r\nIn this sentence there are three a's, two c's, two d's, twenty six e's, four f's, six h's, ten i's, thirteen n's, five o's, _____ r's, twenty seven s's, seventeen t's, two u's, six v's, six w's, five x's, and three y's. \n\n\r\nNumber 2)\n\r\nIn this sentence there are three a's, one b, two c's, two d's, thirty e's, four f's, two g's, nine h's, eight i's, one j, one k, three l's, sixteen n's, twelve o's, eleven r's, twenty three s's, twenty two t's, ____ u's, three v's, nine w's, two x's, and four y's.", "hint": "No hint available.", "answer": "1) Seven\r\n2) Four", "category": "Logic", "date": "02/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFill in the blanks to make the sentences correct:\n\n\n\r\nNumber 1)\n\r\nIn this sentence there are three a's, two c's, two d's, twenty six e's, four f's, six h's, ten i's, thirteen n's, five o's, _____ r's, twenty seven s's, seventeen t's, two u's, six v's, six w's, five x's, and three y's. \n\n\r\nNumber 2)\n\r\nIn this sentence there are three a's, one b, two c's, two d's, thirty e's, four f's, two g's, nine h's, eight i's, one j, one k, three l's, sixteen n's, twelve o's, eleven r's, twenty three s's, twenty two t's, ____ u's, three v's, nine w's, two x's, and four y's.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1) Seven\r\n2) Four\n<|im_start|>answer\n1) Seven\r\n2) Four\n<|im_end|>" }, { "id": "#25075", "title": "Lucky Numbers and Favorite Letters", "fun": 2.12, "difficulty": 0.64, "author": "ujniko", "desc": "A teacher asked his students to write on one piece of paper their favorite letter and on another their lucky numbers. Four of his students forgot to write their names down. They were Anna Reams, Ethan Gold, Maria Scott, and Ryan Martin. The teacher asked whose they were and the students decided to write him clues. The clues were:\n\r\n*Maria's lucky number is either 5 or 30.\n\r\n*Ethan's favorite letter is R.\n\r\n*The person whose name starts with the letter closest to the beginning of the alphabet has the same favorite letter as the first letter in their name.\n\r\n*Ryan's lucky number is even.\n\r\n*Anna's lucky number is either 5 or 15.\n\r\n*Ryan's favorite letter is the letter that starts his last name.", "hint": "No hint available.", "answer": "Ryan= 30, M\r\nMaria = 5, E\r\nEthan= 3, R\r\nAnna = 15, A", "category": "Logic-Grid", "date": "08/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA teacher asked his students to write on one piece of paper their favorite letter and on another their lucky numbers. Four of his students forgot to write their names down. They were Anna Reams, Ethan Gold, Maria Scott, and Ryan Martin. The teacher asked whose they were and the students decided to write him clues. The clues were:\n\r\n*Maria's lucky number is either 5 or 30.\n\r\n*Ethan's favorite letter is R.\n\r\n*The person whose name starts with the letter closest to the beginning of the alphabet has the same favorite letter as the first letter in their name.\n\r\n*Ryan's lucky number is even.\n\r\n*Anna's lucky number is either 5 or 15.\n\r\n*Ryan's favorite letter is the letter that starts his last name.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRyan= 30, M\r\nMaria = 5, E\r\nEthan= 3, R\r\nAnna = 15, A\n<|im_start|>answer\nRyan= 30, M\r\nMaria = 5, E\r\nEthan= 3, R\r\nAnna = 15, A\n<|im_end|>" }, { "id": "#43461", "title": "Who Are The Liars?", "fun": 2.12, "difficulty": 2.5, "author": "shenqiang", "desc": "Twelve men are in a room, some of them always tell lies, while the others always tell the truth.\n\r\nThe first man says: \"None of us is a truthteller.\"\r\nThe second man says: \"At most one of us is a truthteller.\"\r\nThe third man says: \"At most two of us are truthtellers.\"\r\n...\r\nThe twelfth and last man says: \"At most eleven of us are truthtellers.\"\n\r\nWho are the liars?", "hint": "It's OK to use trial and error, however, there might exist better methods.", "answer": "If there are exactly N liars, then the last N men are truthtellers, leaving the first (12-N) men to be liars.\n\r\nTherefore, N=12-N, N=6. The first 6 men are liars, and the last 6 men are truthtellers.", "category": "Logic", "date": "10/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwelve men are in a room, some of them always tell lies, while the others always tell the truth.\n\r\nThe first man says: \"None of us is a truthteller.\"\r\nThe second man says: \"At most one of us is a truthteller.\"\r\nThe third man says: \"At most two of us are truthtellers.\"\r\n...\r\nThe twelfth and last man says: \"At most eleven of us are truthtellers.\"\n\r\nWho are the liars?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf there are exactly N liars, then the last N men are truthtellers, leaving the first (12-N) men to be liars.\n\r\nTherefore, N=12-N, N=6. The first 6 men are liars, and the last 6 men are truthtellers.\n<|im_start|>answer\nIf there are exactly N liars, then the last N men are truthtellers, leaving the first (12-N) men to be liars.\n\r\nTherefore, N=12-N, N=6. The first 6 men are liars, and the last 6 men are truthtellers.\n<|im_end|>" }, { "id": "#12164", "title": "On a Plane", "fun": 2.12, "difficulty": 2.13, "author": "Peat", "desc": "Whenever I move, I change planes. How can this be since I never fly?", "hint": "Geometry", "answer": "This ellipsoid called Earth is made up of an infinite number of geometric planes, as is any sphere. We can only be perpendicular to one plane at a time, so whenever we move it is always a movement between different planes, in a geometric sense. Thus whenever we move we change planes.", "category": "Math", "date": "05/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhenever I move, I change planes. How can this be since I never fly?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThis ellipsoid called Earth is made up of an infinite number of geometric planes, as is any sphere. We can only be perpendicular to one plane at a time, so whenever we move it is always a movement between different planes, in a geometric sense. Thus whenever we move we change planes.\n<|im_start|>answer\nThis ellipsoid called Earth is made up of an infinite number of geometric planes, as is any sphere. We can only be perpendicular to one plane at a time, so whenever we move it is always a movement between different planes, in a geometric sense. Thus whenever we move we change planes.\n<|im_end|>" }, { "id": "#14993", "title": "Bodyguards", "fun": 2.12, "difficulty": 2.19, "author": "mad-ade", "desc": "Beau Vine and Faye Slift, the world famous Madadian Movie stars, together have more than 10 but fewer than 30 bodyguards. One day, one of the bodyguards, Knuckles, decided to leave Beau Vine and join Faye Slift. Now both the females had the same number of bodyguards. \n\r\nEventually, Knuckles rejoined Beau Vine. Also, Masher decided to leave Faye Slift and join Beau Vine. Now, both the females had a prime number of bodyguards. \n\r\nHow many bodyguards did each have now?", "hint": "No hint available.", "answer": "Beau Vine has 11 bodyguards and Faye Slift has 7 bodyguards. \n\r\nIf one bodyguard is moved from one group to the other, it decreases one group by one and increases the other by one. \n\r\nBefore Knuckles joined Faye Slift, Beau Vine had two more bodyguards than Faye Slift (since Knuckles's switch made the number of bodyguards of both the females equal).\n\r\nWhen Knuckles switched back to Beau Vine, once again Beau Vine had two more bodyguards than Faye Slift. Then, Masher moved from Faye Slift to Beau Vine, decreasing Faye Slift's bodyguards by one and increasing Beau Vine's bodyguards by one. Hence, Beau Vine had four more bodyguards than Faye Slift. \n\r\nIt is given that together they had more than 10 but fewer than 30 bodyguards. Also, at the end they both had prime number of bodyguards. The only numbers fit the given conditions are 7 and 11. \n\r\nHence, now Beau Vine has 11 bodyguards and Faye Slift has 7 bodyguards.", "category": "Math", "date": "10/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBeau Vine and Faye Slift, the world famous Madadian Movie stars, together have more than 10 but fewer than 30 bodyguards. One day, one of the bodyguards, Knuckles, decided to leave Beau Vine and join Faye Slift. Now both the females had the same number of bodyguards. \n\r\nEventually, Knuckles rejoined Beau Vine. Also, Masher decided to leave Faye Slift and join Beau Vine. Now, both the females had a prime number of bodyguards. \n\r\nHow many bodyguards did each have now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBeau Vine has 11 bodyguards and Faye Slift has 7 bodyguards. \n\r\nIf one bodyguard is moved from one group to the other, it decreases one group by one and increases the other by one. \n\r\nBefore Knuckles joined Faye Slift, Beau Vine had two more bodyguards than Faye Slift (since Knuckles's switch made the number of bodyguards of both the females equal).\n\r\nWhen Knuckles switched back to Beau Vine, once again Beau Vine had two more bodyguards than Faye Slift. Then, Masher moved from Faye Slift to Beau Vine, decreasing Faye Slift's bodyguards by one and increasing Beau Vine's bodyguards by one. Hence, Beau Vine had four more bodyguards than Faye Slift. \n\r\nIt is given that together they had more than 10 but fewer than 30 bodyguards. Also, at the end they both had prime number of bodyguards. The only numbers fit the given conditions are 7 and 11. \n\r\nHence, now Beau Vine has 11 bodyguards and Faye Slift has 7 bodyguards.\n<|im_start|>answer\nBeau Vine has 11 bodyguards and Faye Slift has 7 bodyguards. \n\r\nIf one bodyguard is moved from one group to the other, it decreases one group by one and increases the other by one. \n\r\nBefore Knuckles joined Faye Slift, Beau Vine had two more bodyguards than Faye Slift (since Knuckles's switch made the number of bodyguards of both the females equal).\n\r\nWhen Knuckles switched back to Beau Vine, once again Beau Vine had two more bodyguards than Faye Slift. Then, Masher moved from Faye Slift to Beau Vine, decreasing Faye Slift's bodyguards by one and increasing Beau Vine's bodyguards by one. Hence, Beau Vine had four more bodyguards than Faye Slift. \n\r\nIt is given that together they had more than 10 but fewer than 30 bodyguards. Also, at the end they both had prime number of bodyguards. The only numbers fit the given conditions are 7 and 11. \n\r\nHence, now Beau Vine has 11 bodyguards and Faye Slift has 7 bodyguards.\n<|im_end|>" }, { "id": "#10545", "title": "The Fan", "fun": 2.12, "difficulty": 1.61, "author": "ka-boom", "desc": "Joe Bob just installed a fan system to cool off from the summer heat. The fan spins at a maximum speed of 40 mph and is controlled by a 360 degree turning knob. Assuming the fan is spinning at 15 mph, how much would the knob have to be turned in order to go at a constant speed of 25 mph?", "hint": "No hint available.", "answer": "90 degrees.\n\r\nYou want to increase the speed by 10 mph, which is 1/4 of the total scale (10 mph divided by 40 mph). To do this you need to adjust the knob 1/4 of its total range. \n\r\n1/4 of 360 degrees is 90 degrees.", "category": "Math", "date": "02/19/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe Bob just installed a fan system to cool off from the summer heat. The fan spins at a maximum speed of 40 mph and is controlled by a 360 degree turning knob. Assuming the fan is spinning at 15 mph, how much would the knob have to be turned in order to go at a constant speed of 25 mph?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n90 degrees.\n\r\nYou want to increase the speed by 10 mph, which is 1/4 of the total scale (10 mph divided by 40 mph). To do this you need to adjust the knob 1/4 of its total range. \n\r\n1/4 of 360 degrees is 90 degrees.\n<|im_start|>answer\n90 degrees.\n\r\nYou want to increase the speed by 10 mph, which is 1/4 of the total scale (10 mph divided by 40 mph). To do this you need to adjust the knob 1/4 of its total range. \n\r\n1/4 of 360 degrees is 90 degrees.\n<|im_end|>" }, { "id": "#10099", "title": "Solution Problem", "fun": 2.12, "difficulty": 2.22, "author": "ka-boom", "desc": "A truck had a 14-quart coolant system that contained a 45% antifreeze solution. How many quarts of this solution would have to be drained and replaced with pure antifreeze to achieve a 75% antifreeze solution in the truck?", "hint": "No hint available.", "answer": "Set up the problem as an equation. \n\r\nAntifreeze left after draining = 45% *(14 - x) \r\nAntifreeze replaced = x \r\nFinal amount of antifreeze = .75 * 14 = 10.5 \n\r\nSo the balance is:\r\nAntifreeze left after draining + Antifreeze replaced = Final amount of antifreeze\n\r\n.45(14 - x) + 1x = 10.5\n\r\n6.3 - .45x + x= 10.5 \r\n.55x = 4.2 \r\nx = 7.64 quarts", "category": "Math", "date": "02/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA truck had a 14-quart coolant system that contained a 45% antifreeze solution. How many quarts of this solution would have to be drained and replaced with pure antifreeze to achieve a 75% antifreeze solution in the truck?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSet up the problem as an equation. \n\r\nAntifreeze left after draining = 45% *(14 - x) \r\nAntifreeze replaced = x \r\nFinal amount of antifreeze = .75 * 14 = 10.5 \n\r\nSo the balance is:\r\nAntifreeze left after draining + Antifreeze replaced = Final amount of antifreeze\n\r\n.45(14 - x) + 1x = 10.5\n\r\n6.3 - .45x + x= 10.5 \r\n.55x = 4.2 \r\nx = 7.64 quarts\n<|im_start|>answer\nSet up the problem as an equation. \n\r\nAntifreeze left after draining = 45% *(14 - x) \r\nAntifreeze replaced = x \r\nFinal amount of antifreeze = .75 * 14 = 10.5 \n\r\nSo the balance is:\r\nAntifreeze left after draining + Antifreeze replaced = Final amount of antifreeze\n\r\n.45(14 - x) + 1x = 10.5\n\r\n6.3 - .45x + x= 10.5 \r\n.55x = 4.2 \r\nx = 7.64 quarts\n<|im_end|>" }, { "id": "#965", "title": "Equations", "fun": 2.12, "difficulty": 2.23, "author": "Michelle", "desc": "What values of X and Y would make these equations work?\n\r\n6751X + 3249Y = 26751\r\n3249X + 6751Y = 23249", "hint": "No hint available.", "answer": "Add the equations to give: 10000X + 10000Y = 50000\r\nDivide by 10000 to give: X + Y = 5\r\nSubtract to give: 3502X - 3502Y = 3502\r\nDivide by 3502 to give: X - Y = 1\r\nTherefore: X = 3 and Y = 2", "category": "Math", "date": "10/03/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat values of X and Y would make these equations work?\n\r\n6751X + 3249Y = 26751\r\n3249X + 6751Y = 23249\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdd the equations to give: 10000X + 10000Y = 50000\r\nDivide by 10000 to give: X + Y = 5\r\nSubtract to give: 3502X - 3502Y = 3502\r\nDivide by 3502 to give: X - Y = 1\r\nTherefore: X = 3 and Y = 2\n<|im_start|>answer\nAdd the equations to give: 10000X + 10000Y = 50000\r\nDivide by 10000 to give: X + Y = 5\r\nSubtract to give: 3502X - 3502Y = 3502\r\nDivide by 3502 to give: X - Y = 1\r\nTherefore: X = 3 and Y = 2\n<|im_end|>" }, { "id": "#18740", "title": "Prime Children", "fun": 2.12, "difficulty": 1.35, "author": "kesavan7777", "desc": "A mother has some children whose product of their ages (in number of years) is 17. Now can you infer two important things from this information? \n\r\nNOTE: Assume all children are a 'whole number' (no decimals) age.", "hint": "17 is a prime number.", "answer": "17=17x1x1x1.....x1\n\r\n1. The eldest child must be 17 years\n\r\n2. All other children (may be twins or triplets or quintuplicates or more than this number at the same birth) must be 1 year old each born at the same birth.", "category": "Logic", "date": "09/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA mother has some children whose product of their ages (in number of years) is 17. Now can you infer two important things from this information? \n\r\nNOTE: Assume all children are a 'whole number' (no decimals) age.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n17=17x1x1x1.....x1\n\r\n1. The eldest child must be 17 years\n\r\n2. All other children (may be twins or triplets or quintuplicates or more than this number at the same birth) must be 1 year old each born at the same birth.\n<|im_start|>answer\n17=17x1x1x1.....x1\n\r\n1. The eldest child must be 17 years\n\r\n2. All other children (may be twins or triplets or quintuplicates or more than this number at the same birth) must be 1 year old each born at the same birth.\n<|im_end|>" }, { "id": "#16049", "title": "The Mystery of Number 11", "fun": 2.12, "difficulty": 2.97, "author": "apr2001", "desc": "Can you find the largest number possible containing any of 9 of 10 digits, considering 0 also a number, that is divisible by 11 without a remainder?\n\r\n(Note: each number may appear only one time.)", "hint": "No hint available.", "answer": "987652413, is the highest number possible containing any of 9 of 10 digits and is divisible by 11 without a remainder.", "category": "Math", "date": "01/05/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you find the largest number possible containing any of 9 of 10 digits, considering 0 also a number, that is divisible by 11 without a remainder?\n\r\n(Note: each number may appear only one time.)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n987652413, is the highest number possible containing any of 9 of 10 digits and is divisible by 11 without a remainder.\n<|im_start|>answer\n987652413, is the highest number possible containing any of 9 of 10 digits and is divisible by 11 without a remainder.\n<|im_end|>" }, { "id": "#1490", "title": "Quick Thinking", "fun": 2.11, "difficulty": 1.18, "author": "tepuchi", "desc": "What is the number that is one half of one quarter of one tenth of 400?", "hint": "No hint available.", "answer": "5. \r\n1/10 of 400 is 40. 1/4 of 40 is 10, and 1/2 of 10 is 5.", "category": "Math", "date": "11/22/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the number that is one half of one quarter of one tenth of 400?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5. \r\n1/10 of 400 is 40. 1/4 of 40 is 10, and 1/2 of 10 is 5.\n<|im_start|>answer\n5. \r\n1/10 of 400 is 40. 1/4 of 40 is 10, and 1/2 of 10 is 5.\n<|im_end|>" }, { "id": "#14899", "title": "Zinger?", "fun": 2.11, "difficulty": 2.8, "author": "jess1118", "desc": "The following numbers are zingers: \r\n9, 57, 41, 89, 33, and 17. \n\r\nThe following are not zingers: \r\n2, 8, 59, 13, 68, and 36. \n\r\nWhat is a zinger?", "hint": "Think multiplication.", "answer": "A zinger in this context is a number that is multiplied by eight and increased by one. For example, 8 x 2 = 16 and 16 + 1= 17. Therefore 17 is a zinger.", "category": "Math", "date": "09/24/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following numbers are zingers: \r\n9, 57, 41, 89, 33, and 17. \n\r\nThe following are not zingers: \r\n2, 8, 59, 13, 68, and 36. \n\r\nWhat is a zinger?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA zinger in this context is a number that is multiplied by eight and increased by one. For example, 8 x 2 = 16 and 16 + 1= 17. Therefore 17 is a zinger.\n<|im_start|>answer\nA zinger in this context is a number that is multiplied by eight and increased by one. For example, 8 x 2 = 16 and 16 + 1= 17. Therefore 17 is a zinger.\n<|im_end|>" }, { "id": "#8584", "title": "Sixteen 4's", "fun": 2.11, "difficulty": 2.09, "author": "lesternoronha1", "desc": "Can you make a total of 1000 by using sixteen 4's and only the arithmetic symbol \"+\" any number of times?", "hint": "Try all combinations.", "answer": "444+444+44+44+4+4+4+4+4+4", "category": "Math", "date": "11/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you make a total of 1000 by using sixteen 4's and only the arithmetic symbol \"+\" any number of times?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n444+444+44+44+4+4+4+4+4+4\n<|im_start|>answer\n444+444+44+44+4+4+4+4+4+4\n<|im_end|>" }, { "id": "#4942", "title": "Race Driver", "fun": 2.11, "difficulty": 2.0, "author": "mad-ade", "desc": "A racing driver drove around a 6-mile track at 140 miles per hour for 3 miles, 168 miles per hour for 1.5 miles, and 210 miles per hour for 1.5 miles. What was his average speed for the entire 6 miles?", "hint": "No hint available.", "answer": "160mph", "category": "Math", "date": "06/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA racing driver drove around a 6-mile track at 140 miles per hour for 3 miles, 168 miles per hour for 1.5 miles, and 210 miles per hour for 1.5 miles. What was his average speed for the entire 6 miles?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n160mph\n<|im_start|>answer\n160mph\n<|im_end|>" }, { "id": "#819", "title": "Unscrew a Lightbulb", "fun": 2.11, "difficulty": 1.35, "author": "Michelle", "desc": "If you screw a lightbulb into a socket by turning the bulb toward the right with your right hand, which way would you turn the socket with your left hand in order to unscrew it while holding the bulb stationary?", "hint": "No hint available.", "answer": "You would screw the socket to the right.", "category": "Logic", "date": "09/16/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you screw a lightbulb into a socket by turning the bulb toward the right with your right hand, which way would you turn the socket with your left hand in order to unscrew it while holding the bulb stationary?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou would screw the socket to the right.\n<|im_start|>answer\nYou would screw the socket to the right.\n<|im_end|>" }, { "id": "#39290", "title": "Digital Product", "fun": 2.11, "difficulty": 2.94, "author": "shenqiang", "desc": "The digital product (i.e. product of all its digits) of a positive integer equals the cube of a two-digit integer.\n\r\nWhat's the minimal value of the original number?", "hint": "If you think it's 5558, then you're missing something.", "answer": "It must have 4 digits. If the product is 1000, it's at least 5558. \n\r\nThe product can't be 11^3 because 11 is prime.\n\r\nBut if the product is 12^3, the least number is 3889.", "category": "Math", "date": "11/20/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe digital product (i.e. product of all its digits) of a positive integer equals the cube of a two-digit integer.\n\r\nWhat's the minimal value of the original number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt must have 4 digits. If the product is 1000, it's at least 5558. \n\r\nThe product can't be 11^3 because 11 is prime.\n\r\nBut if the product is 12^3, the least number is 3889.\n<|im_start|>answer\nIt must have 4 digits. If the product is 1000, it's at least 5558. \n\r\nThe product can't be 11^3 because 11 is prime.\n\r\nBut if the product is 12^3, the least number is 3889.\n<|im_end|>" }, { "id": "#11725", "title": "Skydiving", "fun": 2.11, "difficulty": 1.19, "author": "divawoman11520", "desc": "Quintuplets, Sara, Kara, Mara, Lara, and Tara all went skydiving. Sara went before Mara, but after Kara. Lara went first. If Tara went after Mara, in what order did the girls go?", "hint": "Sara is 3rd.", "answer": "Lara went first, then Kara, then Sara, then Mara, and then Tara.", "category": "Logic", "date": "04/12/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nQuintuplets, Sara, Kara, Mara, Lara, and Tara all went skydiving. Sara went before Mara, but after Kara. Lara went first. If Tara went after Mara, in what order did the girls go?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLara went first, then Kara, then Sara, then Mara, and then Tara.\n<|im_start|>answer\nLara went first, then Kara, then Sara, then Mara, and then Tara.\n<|im_end|>" }, { "id": "#12088", "title": "Cutting the Cake", "fun": 2.11, "difficulty": 1.92, "author": "misiu", "desc": "During her birthday party, Mary noticed that from a rectangular cake a rectangular piece was missing (it doesn't matter where). With two guests remaining without cake, she wanted to give them equal pieces of the cake. Remembering Professor Voronka's geometry class, she said, \"I know how to cut the cake in half using a single cut!\" and proceeds to do so. \n\r\nHow did she cut the cake using a SINGLE STRAIGHT cut? Can you think of another way?\n\r\nAssume that the cake is uniform so that both pieces will have the same ingredients no matter how the cake is cut.", "hint": "To the first way:\n\r\nThis wouldn't be possible if the cake was two-dimensional.\n\r\nTo the second way:\n\r\nWhat are the ways you can divide a rectangle in half using a straight line? (There are more than 4)\n\r\nMajor Hint:\n\r\nWhere do these lines all cross?", "answer": "First Way:\n\r\nCut the cake horizontally in the middle.\n\r\nSecond Way:\n\r\nCut the cake along the centers of the two rectangles. (i.e., the missing piece and the entire cake)", "category": "Math", "date": "04/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDuring her birthday party, Mary noticed that from a rectangular cake a rectangular piece was missing (it doesn't matter where). With two guests remaining without cake, she wanted to give them equal pieces of the cake. Remembering Professor Voronka's geometry class, she said, \"I know how to cut the cake in half using a single cut!\" and proceeds to do so. \n\r\nHow did she cut the cake using a SINGLE STRAIGHT cut? Can you think of another way?\n\r\nAssume that the cake is uniform so that both pieces will have the same ingredients no matter how the cake is cut.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst Way:\n\r\nCut the cake horizontally in the middle.\n\r\nSecond Way:\n\r\nCut the cake along the centers of the two rectangles. (i.e., the missing piece and the entire cake)\n<|im_start|>answer\nFirst Way:\n\r\nCut the cake horizontally in the middle.\n\r\nSecond Way:\n\r\nCut the cake along the centers of the two rectangles. (i.e., the missing piece and the entire cake)\n<|im_end|>" }, { "id": "#35205", "title": "Drilling Through A Sphere", "fun": 2.11, "difficulty": 2.96, "author": "MarcM1098", "desc": "I just drilled straight through the center of a solid sphere, resulting in a 6cm long cylindrical hole. What is the volume remaining in the sphere?\n\r\nHere are some formulas you may find useful:\r\nVolume of sphere = (4/3)Pi(r^3)\r\nVolume of cap = (1/6)Pi(3R^2+h^2)h\r\nVolume of cylinder = Pi(R^2)H\n\r\nr = radius of sphere\r\nh = height of cap\r\nR = radius of hole (the cap and the cylinder share this radius)\r\nH = height of cylinder (6cm)\n\r\nThe portion of the sphere that was removed can be thought of as a cylinder with a cap at both ends. A cap is flat on one side (touching the cylinder) and spherical on the other side (the original surface of the sphere).", "hint": "Hint for a hard solution:\r\nThe sphere's diameter (2r) must be the same as the length of the cylinder (H) plus the height of the two caps (2h), so 2r=H+2h.\n\r\nA right-angled triangle is formed by the radius of the cylinder (R) and half the height of the cylinder (H/2), with the radius of the sphere (r) forming the hypotenuse. Using Pythagoras, R^2+(H/2)^2=r^2.\n\r\nHint for an easy solution:\r\nAssume there is a real answer. Therefore, the answer does not depend on the radius of the hole (R). Use whatever value is easiest.", "answer": "The volume is exactly 36Pi cm^3 (about 113.1 cm^3).\n\r\nHard solution:\r\nThe sphere's diameter (2r) must be the same as the length of the cylinder (H) plus the height of the two caps (2h), so 2r=H+2h.\r\nThus, 2h=2r-H and H=6, so 2h=2r-6 or simply h=r-3.\n\r\nA right-angled triangle is formed by the radius of the cylinder (R) and half the height of the cylinder (H/2), with the radius of the sphere (r) forming the hypotenuse. Using Pythagoras: R^2+(H/2)^2=r^2.\r\nThus, R^2=r^2-(H/2)^2 and H=6, so R^2=r^2-9.\n\r\nVolume of cap = (1/6)Pi(3R^2+h^2)h\r\n(replace R^2 and h with values computed above)\r\n= (1/6)Pi(3(r^2-9)+(r-3)^2)(r-3)\r\n= (1/6)Pi(3r^2-27+r^2-6r+9)(r-3)\r\n= (1/6)Pi(4r^2-6r-18)(r-3)\r\n= (1/6)Pi(4r^3-6r^2-18r-12r^2+18r+54)\r\n= (1/6)Pi(4r^3-18r^2+54)\r\n= (2/3)Pi(r^3)-3Pi(r^2)+9Pi\n\r\nVolume of cylinder = Pi(R^2)H\r\n(replace R^2 with value computed above, and H with given value of 6)\r\n= Pi(r^2-9)6\r\n= 6Pi(r^2)-54Pi\n\r\nVolume of sphere remaining = sphere - 2 caps - cylinder\r\n= [ (4/3)Pi(r^3) ] - [ 2 ((2/3)Pi(r^3)-3Pi(r^2)+9Pi) ] - [ 6Pi(r^2)-54Pi ]\r\n= [ (4/3)Pi(r^3) ] - [ (4/3)Pi(r^3)-6Pi(r^2)+18Pi ] - [ 6Pi(r^2) - 54Pi ]\r\n= (4/3)Pi(r^3) - (4/3)Pi(r^3) + 6Pi(r^2) - 18Pi - 6Pi(r^2) + 54Pi\r\n= 36Pi\n\r\nEasy solution:\r\nAssume the hole is infinitely small (i.e. a radius of 0). Then, the volume of the cylinder (and the volume of the caps) is 0. The height of the cap is 0, so the radius of the sphere (r) is 3cm (half of the length of the cylindrical hole). Thus:\n\r\nVolume of sphere remaining = sphere - 2 caps - cylinder\r\n= (4/3)Pi(r^3) - 0 - 0\r\n= (4/3)Pi(3^3)\r\n= 36Pi", "category": "Math", "date": "02/05/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI just drilled straight through the center of a solid sphere, resulting in a 6cm long cylindrical hole. What is the volume remaining in the sphere?\n\r\nHere are some formulas you may find useful:\r\nVolume of sphere = (4/3)Pi(r^3)\r\nVolume of cap = (1/6)Pi(3R^2+h^2)h\r\nVolume of cylinder = Pi(R^2)H\n\r\nr = radius of sphere\r\nh = height of cap\r\nR = radius of hole (the cap and the cylinder share this radius)\r\nH = height of cylinder (6cm)\n\r\nThe portion of the sphere that was removed can be thought of as a cylinder with a cap at both ends. A cap is flat on one side (touching the cylinder) and spherical on the other side (the original surface of the sphere).\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe volume is exactly 36Pi cm^3 (about 113.1 cm^3).\n\r\nHard solution:\r\nThe sphere's diameter (2r) must be the same as the length of the cylinder (H) plus the height of the two caps (2h), so 2r=H+2h.\r\nThus, 2h=2r-H and H=6, so 2h=2r-6 or simply h=r-3.\n\r\nA right-angled triangle is formed by the radius of the cylinder (R) and half the height of the cylinder (H/2), with the radius of the sphere (r) forming the hypotenuse. Using Pythagoras: R^2+(H/2)^2=r^2.\r\nThus, R^2=r^2-(H/2)^2 and H=6, so R^2=r^2-9.\n\r\nVolume of cap = (1/6)Pi(3R^2+h^2)h\r\n(replace R^2 and h with values computed above)\r\n= (1/6)Pi(3(r^2-9)+(r-3)^2)(r-3)\r\n= (1/6)Pi(3r^2-27+r^2-6r+9)(r-3)\r\n= (1/6)Pi(4r^2-6r-18)(r-3)\r\n= (1/6)Pi(4r^3-6r^2-18r-12r^2+18r+54)\r\n= (1/6)Pi(4r^3-18r^2+54)\r\n= (2/3)Pi(r^3)-3Pi(r^2)+9Pi\n\r\nVolume of cylinder = Pi(R^2)H\r\n(replace R^2 with value computed above, and H with given value of 6)\r\n= Pi(r^2-9)6\r\n= 6Pi(r^2)-54Pi\n\r\nVolume of sphere remaining = sphere - 2 caps - cylinder\r\n= [ (4/3)Pi(r^3) ] - [ 2 ((2/3)Pi(r^3)-3Pi(r^2)+9Pi) ] - [ 6Pi(r^2)-54Pi ]\r\n= [ (4/3)Pi(r^3) ] - [ (4/3)Pi(r^3)-6Pi(r^2)+18Pi ] - [ 6Pi(r^2) - 54Pi ]\r\n= (4/3)Pi(r^3) - (4/3)Pi(r^3) + 6Pi(r^2) - 18Pi - 6Pi(r^2) + 54Pi\r\n= 36Pi\n\r\nEasy solution:\r\nAssume the hole is infinitely small (i.e. a radius of 0). Then, the volume of the cylinder (and the volume of the caps) is 0. The height of the cap is 0, so the radius of the sphere (r) is 3cm (half of the length of the cylindrical hole). Thus:\n\r\nVolume of sphere remaining = sphere - 2 caps - cylinder\r\n= (4/3)Pi(r^3) - 0 - 0\r\n= (4/3)Pi(3^3)\r\n= 36Pi\n<|im_start|>answer\nThe volume is exactly 36Pi cm^3 (about 113.1 cm^3).\n\r\nHard solution:\r\nThe sphere's diameter (2r) must be the same as the length of the cylinder (H) plus the height of the two caps (2h), so 2r=H+2h.\r\nThus, 2h=2r-H and H=6, so 2h=2r-6 or simply h=r-3.\n\r\nA right-angled triangle is formed by the radius of the cylinder (R) and half the height of the cylinder (H/2), with the radius of the sphere (r) forming the hypotenuse. Using Pythagoras: R^2+(H/2)^2=r^2.\r\nThus, R^2=r^2-(H/2)^2 and H=6, so R^2=r^2-9.\n\r\nVolume of cap = (1/6)Pi(3R^2+h^2)h\r\n(replace R^2 and h with values computed above)\r\n= (1/6)Pi(3(r^2-9)+(r-3)^2)(r-3)\r\n= (1/6)Pi(3r^2-27+r^2-6r+9)(r-3)\r\n= (1/6)Pi(4r^2-6r-18)(r-3)\r\n= (1/6)Pi(4r^3-6r^2-18r-12r^2+18r+54)\r\n= (1/6)Pi(4r^3-18r^2+54)\r\n= (2/3)Pi(r^3)-3Pi(r^2)+9Pi\n\r\nVolume of cylinder = Pi(R^2)H\r\n(replace R^2 with value computed above, and H with given value of 6)\r\n= Pi(r^2-9)6\r\n= 6Pi(r^2)-54Pi\n\r\nVolume of sphere remaining = sphere - 2 caps - cylinder\r\n= [ (4/3)Pi(r^3) ] - [ 2 ((2/3)Pi(r^3)-3Pi(r^2)+9Pi) ] - [ 6Pi(r^2)-54Pi ]\r\n= [ (4/3)Pi(r^3) ] - [ (4/3)Pi(r^3)-6Pi(r^2)+18Pi ] - [ 6Pi(r^2) - 54Pi ]\r\n= (4/3)Pi(r^3) - (4/3)Pi(r^3) + 6Pi(r^2) - 18Pi - 6Pi(r^2) + 54Pi\r\n= 36Pi\n\r\nEasy solution:\r\nAssume the hole is infinitely small (i.e. a radius of 0). Then, the volume of the cylinder (and the volume of the caps) is 0. The height of the cap is 0, so the radius of the sphere (r) is 3cm (half of the length of the cylindrical hole). Thus:\n\r\nVolume of sphere remaining = sphere - 2 caps - cylinder\r\n= (4/3)Pi(r^3) - 0 - 0\r\n= (4/3)Pi(3^3)\r\n= 36Pi\n<|im_end|>" }, { "id": "#4024", "title": "Infinity Divides Infinity", "fun": 2.11, "difficulty": 1.66, "author": "arij", "desc": "What do you get when infinity divides infinity?", "hint": "No hint available.", "answer": "The answer is indeterminate (it could be any number).\n\r\nInfinity is an unknown number. We can't say that the numerator infinity is exactly equal to the denominator infinity.", "category": "Math", "date": "05/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat do you get when infinity divides infinity?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is indeterminate (it could be any number).\n\r\nInfinity is an unknown number. We can't say that the numerator infinity is exactly equal to the denominator infinity.\n<|im_start|>answer\nThe answer is indeterminate (it could be any number).\n\r\nInfinity is an unknown number. We can't say that the numerator infinity is exactly equal to the denominator infinity.\n<|im_end|>" }, { "id": "#12007", "title": "Disappearing Numbers", "fun": 2.11, "difficulty": 2.4, "author": "jimbo", "desc": "For every number that exists between 0 and 1 (say for example 2/3) there exists exactly one other number called its reciprocal (in this case 3/2) that is bigger than 1.\r\nAlso, for every number that exists between 0 and 1 (say 0.5) there is exactly one number that exists, found by adding 1 (1.5) that must lie between 1 and 2.\r\nSince every number between 0 and 1 corresponds to exactly one number between 1 and 2 and at the same time corresponds to a number bigger than 1 then there must be the same number of numbers that lie between 1 and 2 as there are bigger than 1.\r\nThat means that all of the numbers bigger than 1 lie between 1 and 2 so there aren't any numbers bigger than 2.\r\nThis is clearly false, so where is the error?", "hint": "Reversing the reasoning will give you the same correspondence. Every number bigger than 1 has a reciprocal less than 1 and every number between 1 and 2 has a corresponding number less than 1 found by subtracting 1. No error here.", "answer": "The problem lies in how many numbers there are. There are an infinite number of numbers between 0 and 1 and hence an infinite number of numbers between 1 and 2 and also greater than 2. Surprisingly there can be different sized infinities so you cannot say that two infinite quantities are equal. (Take 1 away from infinite and you still have infinite).", "category": "Math", "date": "04/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFor every number that exists between 0 and 1 (say for example 2/3) there exists exactly one other number called its reciprocal (in this case 3/2) that is bigger than 1.\r\nAlso, for every number that exists between 0 and 1 (say 0.5) there is exactly one number that exists, found by adding 1 (1.5) that must lie between 1 and 2.\r\nSince every number between 0 and 1 corresponds to exactly one number between 1 and 2 and at the same time corresponds to a number bigger than 1 then there must be the same number of numbers that lie between 1 and 2 as there are bigger than 1.\r\nThat means that all of the numbers bigger than 1 lie between 1 and 2 so there aren't any numbers bigger than 2.\r\nThis is clearly false, so where is the error?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe problem lies in how many numbers there are. There are an infinite number of numbers between 0 and 1 and hence an infinite number of numbers between 1 and 2 and also greater than 2. Surprisingly there can be different sized infinities so you cannot say that two infinite quantities are equal. (Take 1 away from infinite and you still have infinite).\n<|im_start|>answer\nThe problem lies in how many numbers there are. There are an infinite number of numbers between 0 and 1 and hence an infinite number of numbers between 1 and 2 and also greater than 2. Surprisingly there can be different sized infinities so you cannot say that two infinite quantities are equal. (Take 1 away from infinite and you still have infinite).\n<|im_end|>" }, { "id": "#18441", "title": "3 + 4", "fun": 2.11, "difficulty": 2.7600000000000002, "author": "AXTON", "desc": "How is it possible that 3 + 4 = 5?", "hint": "No hint available.", "answer": "Using VECTORS\n\r\ni.e. 3 m North + 4 m East\r\n = 5 metres North East\n\r\n3^2 = 9\r\n4^2 = 16 \r\n9 + 16 = 25\r\nSQ Root of 25 = 5", "category": "Logic", "date": "08/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow is it possible that 3 + 4 = 5?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nUsing VECTORS\n\r\ni.e. 3 m North + 4 m East\r\n = 5 metres North East\n\r\n3^2 = 9\r\n4^2 = 16 \r\n9 + 16 = 25\r\nSQ Root of 25 = 5\n<|im_start|>answer\nUsing VECTORS\n\r\ni.e. 3 m North + 4 m East\r\n = 5 metres North East\n\r\n3^2 = 9\r\n4^2 = 16 \r\n9 + 16 = 25\r\nSQ Root of 25 = 5\n<|im_end|>" }, { "id": "#41633", "title": "Percentages", "fun": 2.11, "difficulty": 1.45, "author": "shenqiang", "desc": "If A is 50% larger than C, and B is 25% larger than C, then A is what percent larger than B?", "hint": "No hint available.", "answer": "A is 1.5C, and B is 1.25C. Therefore, A is (1.5C-1.25C)/(1.25C)*100%=20% larger than B.\n\r\nOr, suppose C is 4, then A is 6 and B is 5. 6 is 20% larger than 5.", "category": "Math", "date": "04/23/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf A is 50% larger than C, and B is 25% larger than C, then A is what percent larger than B?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA is 1.5C, and B is 1.25C. Therefore, A is (1.5C-1.25C)/(1.25C)*100%=20% larger than B.\n\r\nOr, suppose C is 4, then A is 6 and B is 5. 6 is 20% larger than 5.\n<|im_start|>answer\nA is 1.5C, and B is 1.25C. Therefore, A is (1.5C-1.25C)/(1.25C)*100%=20% larger than B.\n\r\nOr, suppose C is 4, then A is 6 and B is 5. 6 is 20% larger than 5.\n<|im_end|>" }, { "id": "#728", "title": "Cost of the Trip", "fun": 2.11, "difficulty": 1.7, "author": "vikass", "desc": "Michelle rents a car to take her to the airport in the morning and return her home that evening. Halfway to the airport, she picks up a friend who accompanies her to the airport. That night, she and her friend return back to Michelle`s place. The total cost is $20.00. If the amount is to be split fairly, how much money should Michelle pay?", "hint": "No hint available.", "answer": "$12.50", "category": "Math", "date": "08/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMichelle rents a car to take her to the airport in the morning and return her home that evening. Halfway to the airport, she picks up a friend who accompanies her to the airport. That night, she and her friend return back to Michelle`s place. The total cost is $20.00. If the amount is to be split fairly, how much money should Michelle pay?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$12.50\n<|im_start|>answer\n$12.50\n<|im_end|>" }, { "id": "#42174", "title": "Alcohol", "fun": 2.11, "difficulty": 1.23, "author": "annvie9", "desc": "There are three things on the table:\r\nA shot glass that can hold up to 4 fluid ounces, a martini glass that can hold up to 16 fluid ounces, and a mug that can hold up to 32 fluid ounces.\r\nAll of them are completely filled with wine.\r\nThe shot glass contains 50% of alcohol. The martini glass contains 12.5% of alcohol. The mug contains 6.25% of alcohol.\n\r\nWhich contains the most alcohol?", "hint": "No hint available.", "answer": "They all have the same amount of alcohol.\n\r\nSince the shot glass can hold up to 4 fluid ounces, 50% of it would be 2 fluid ounces. The martini glass, which holds up to 16 fluid ounces, has 12.5% of alcohol, which is equivalent to 2 fluid ounces, just like the shot glass. The 32 fluid ounce mug has 6.25% of alcohol, which is also 2 fluid ounces. All of them have 2 fluid ounces of alcohol.", "category": "Math", "date": "06/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three things on the table:\r\nA shot glass that can hold up to 4 fluid ounces, a martini glass that can hold up to 16 fluid ounces, and a mug that can hold up to 32 fluid ounces.\r\nAll of them are completely filled with wine.\r\nThe shot glass contains 50% of alcohol. The martini glass contains 12.5% of alcohol. The mug contains 6.25% of alcohol.\n\r\nWhich contains the most alcohol?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThey all have the same amount of alcohol.\n\r\nSince the shot glass can hold up to 4 fluid ounces, 50% of it would be 2 fluid ounces. The martini glass, which holds up to 16 fluid ounces, has 12.5% of alcohol, which is equivalent to 2 fluid ounces, just like the shot glass. The 32 fluid ounce mug has 6.25% of alcohol, which is also 2 fluid ounces. All of them have 2 fluid ounces of alcohol.\n<|im_start|>answer\nThey all have the same amount of alcohol.\n\r\nSince the shot glass can hold up to 4 fluid ounces, 50% of it would be 2 fluid ounces. The martini glass, which holds up to 16 fluid ounces, has 12.5% of alcohol, which is equivalent to 2 fluid ounces, just like the shot glass. The 32 fluid ounce mug has 6.25% of alcohol, which is also 2 fluid ounces. All of them have 2 fluid ounces of alcohol.\n<|im_end|>" }, { "id": "#13921", "title": "Commuting", "fun": 2.11, "difficulty": 1.62, "author": "Lemens", "desc": "In a company: \r\n595 people have driven to work \r\n170 people have taken the train to work\r\n85 people have driven and taken the train to work\r\n170 people live at the company \n\r\nIn total, how many people work at this particular company?", "hint": "Don't count the people who drive and take the train as two different people.", "answer": "Since 85 people drive and take the train to work, you have to subtract them out of the 595 people who drive to work and the 170 people who take the train to work. This way, you will not double count these people.\n\r\nSo, 595-85=510 and 170-85=85\n\r\nNow, you can treat these people as individuals and add them all together.\n\r\n510 people drive + 85 people taking the train + 170 living at the company + 85 people who drive and take the train = 850 people in total.", "category": "Math", "date": "07/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a company: \r\n595 people have driven to work \r\n170 people have taken the train to work\r\n85 people have driven and taken the train to work\r\n170 people live at the company \n\r\nIn total, how many people work at this particular company?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince 85 people drive and take the train to work, you have to subtract them out of the 595 people who drive to work and the 170 people who take the train to work. This way, you will not double count these people.\n\r\nSo, 595-85=510 and 170-85=85\n\r\nNow, you can treat these people as individuals and add them all together.\n\r\n510 people drive + 85 people taking the train + 170 living at the company + 85 people who drive and take the train = 850 people in total.\n<|im_start|>answer\nSince 85 people drive and take the train to work, you have to subtract them out of the 595 people who drive to work and the 170 people who take the train to work. This way, you will not double count these people.\n\r\nSo, 595-85=510 and 170-85=85\n\r\nNow, you can treat these people as individuals and add them all together.\n\r\n510 people drive + 85 people taking the train + 170 living at the company + 85 people who drive and take the train = 850 people in total.\n<|im_end|>" }, { "id": "#50268", "title": "Book Problems", "fun": 2.11, "difficulty": 0.52, "author": "klsowell", "desc": "Three friends - Jack, Lucy, and Elaine - recently joined a writing club, but they got their stories all mixed up! Using the clues, can you determine whose story is whose, and how many words each one has?\n\r\nNames: Jack, Lucy, Elaine\r\nStory Titles: The Pirate's Quest, Into the Garden, Aether Dreams\r\nNumbers of Words: 2000, 5000, 10000,\n\r\nClues:\n\r\n1. The three stories are: the one with 10000 words, the one entitled The Pirate's Quest, and Elaine's story.\n\r\n2. The writer of Into the Garden thought her book would be the longest, but it ended up the shortest.\n\r\n3. Jack's book had nothing to do with flowers or magic; he instead chose a more boy-ish theme.\n\r\n4. Lucy's book had a magical, multi-dimensional theme that had nothing to do with pirates or gardens.", "hint": "No hint available.", "answer": "The Pirate's Quest was 5000 words long and was written by Jack.\r\nInto the Garden was 2000 words long and was written by Elaine.\r\nAether Dreams was 10000 words long and was written by Lucy.", "category": "Logic-Grid", "date": "04/27/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends - Jack, Lucy, and Elaine - recently joined a writing club, but they got their stories all mixed up! Using the clues, can you determine whose story is whose, and how many words each one has?\n\r\nNames: Jack, Lucy, Elaine\r\nStory Titles: The Pirate's Quest, Into the Garden, Aether Dreams\r\nNumbers of Words: 2000, 5000, 10000,\n\r\nClues:\n\r\n1. The three stories are: the one with 10000 words, the one entitled The Pirate's Quest, and Elaine's story.\n\r\n2. The writer of Into the Garden thought her book would be the longest, but it ended up the shortest.\n\r\n3. Jack's book had nothing to do with flowers or magic; he instead chose a more boy-ish theme.\n\r\n4. Lucy's book had a magical, multi-dimensional theme that had nothing to do with pirates or gardens.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Pirate's Quest was 5000 words long and was written by Jack.\r\nInto the Garden was 2000 words long and was written by Elaine.\r\nAether Dreams was 10000 words long and was written by Lucy.\n<|im_start|>answer\nThe Pirate's Quest was 5000 words long and was written by Jack.\r\nInto the Garden was 2000 words long and was written by Elaine.\r\nAether Dreams was 10000 words long and was written by Lucy.\n<|im_end|>" }, { "id": "#12517", "title": "Nuts and Bolts", "fun": 2.11, "difficulty": 1.7, "author": "gogogo1", "desc": "You are making your way through the Australian bush at night when you get a flat tyre. You start removing the nuts one by one to fill it with a can of 'Fix-a-flat' when your 4-year old kid kicks the bolts from the pile. It is dark and you can't see. \n\r\nHow can you find the nuts when it is dark?", "hint": "What part of your car do you use to see at night?", "answer": "Turn on the headlights and use the wing mirror to reflect the light.", "category": "Logic", "date": "05/21/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are making your way through the Australian bush at night when you get a flat tyre. You start removing the nuts one by one to fill it with a can of 'Fix-a-flat' when your 4-year old kid kicks the bolts from the pile. It is dark and you can't see. \n\r\nHow can you find the nuts when it is dark?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTurn on the headlights and use the wing mirror to reflect the light.\n<|im_start|>answer\nTurn on the headlights and use the wing mirror to reflect the light.\n<|im_end|>" }, { "id": "#1555", "title": "X is a Y", "fun": 2.11, "difficulty": 1.86, "author": "sam7630", "desc": "An X is a Y, but a Y is not an X. \n\r\nReplace X and Y with words to make the sentence make sense.", "hint": "Think out of the BOX", "answer": "a SQUARE is a RECTANGLE, but a RECTANGLE is not a SQUARE.", "category": "Logic", "date": "11/30/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAn X is a Y, but a Y is not an X. \n\r\nReplace X and Y with words to make the sentence make sense.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na SQUARE is a RECTANGLE, but a RECTANGLE is not a SQUARE.\n<|im_start|>answer\na SQUARE is a RECTANGLE, but a RECTANGLE is not a SQUARE.\n<|im_end|>" }, { "id": "#3476", "title": "Jannet & Andy", "fun": 2.11, "difficulty": 1.47, "author": "missie", "desc": "Jannet and Andy were having a reading competition. They both read the same book. Andy finished the book in an hour and ten minutes and Jannet finished it in eighty minutes. Who reads faster?", "hint": "No hint available.", "answer": "Andy because he had ten less minutes than Jannet.", "category": "Math", "date": "04/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJannet and Andy were having a reading competition. They both read the same book. Andy finished the book in an hour and ten minutes and Jannet finished it in eighty minutes. Who reads faster?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndy because he had ten less minutes than Jannet.\n<|im_start|>answer\nAndy because he had ten less minutes than Jannet.\n<|im_end|>" }, { "id": "#3370", "title": "Game of Darts", "fun": 2.11, "difficulty": 2.46, "author": "cathalmccabe", "desc": "If playing darts, what is the lowest possible score you CAN'T get with three darts on a standard dart board?", "hint": "No hint available.", "answer": "163\n\r\nScoring combinations to achieve 0 thru 162 points:\n\r\nall three darts miss --- 0 points\n\r\n1st misses (0 points), 2nd misses (0 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 1 thru 20 points\n\r\n1st misses (0 points), 2nd hits single 20 (20 points), 3rd hits single 1 thru 20 (0 thru 20 points) --- 21 thru 40 points\n\r\n1st misses (0 points), 2nd hits double 20 (40 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 41 thru 60 points\n\r\n1st misses (0 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 61 thru 80 points\n\r\n1st hits double 20 (40 points), 2nd hits double 20 (40 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 81 thru 100 points\n\r\n1st hits double 20 (40 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 101 thru 120 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 121 thru 140 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 7 (21 points) --- 60 + 60 + 21 = 141 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 11 (22 points) --- 60 + 60 + 22 = 142 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 13 (26 points) --- 60 + 57 + 26 = 143 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 15 (30 points) --- 60 + 54 + 30 = 144 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits double 17 (34 points) --- 60 + 51 + 34 = 145 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits double 19 (38 points) --- 60 + 48 + 38 = 146 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits triple 13 (39 points) --- 60 + 48 + 39 = 147 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits double 20 (40 points) --- 60 + 48 + 40 = 148 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 16 (32 points) --- 60 + 57 + 32 = 149 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 18 (36 points) --- 60 + 54 + 36 = 150 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits double 20 (40 points) --- 60 + 51 + 40 = 151 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 16 (32 points) --- 60 + 60 + 32 = 152 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 18 (36 points) --- 60 + 57 + 36 = 153 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 20 (40 points) --- 60 + 54 + 40 = 154 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 19 (38 points) --- 60 + 57 + 38 = 155 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 18 (36 points) --- 60 + 60 + 36 = 156 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 20 (40 points) --- 60 + 57 + 40 = 157 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 19 (38 points) --- 60 + 60 + 38 = 158 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 13 (39 points) --- 60 + 60 + 39 = 159 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 20 (40 points) --- 60 + 60 + 40 = 160 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits center bull's eye (50 points) --- 60 + 51 + 50 = 161 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 14 (42 points) --- 60 + 60 + 42 = 162 points\n\r\n163 points can not be achieved for the following reasons:\n\r\nIf two darts each hit a triple 20 for 60 points each, that produces 120 points, which requires another 43 points to reach 163. 43, being prime, can not be achieved with any single, double, or triple score.\n\r\nIf one dart hits triple 20 and another hits the center bull's eye, that achieves 110 points, leaving the need for an additional 53 points. 53 is prime, so can not be reached by any hit.\n\r\nIf two darts both hit the center bull's eye for 100 points, that still leaves a need for 63 points. 63 is not prime, but can not be reached, since it would require a triple 21 (there is no 21 on a dart board).", "category": "Math", "date": "04/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf playing darts, what is the lowest possible score you CAN'T get with three darts on a standard dart board?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n163\n\r\nScoring combinations to achieve 0 thru 162 points:\n\r\nall three darts miss --- 0 points\n\r\n1st misses (0 points), 2nd misses (0 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 1 thru 20 points\n\r\n1st misses (0 points), 2nd hits single 20 (20 points), 3rd hits single 1 thru 20 (0 thru 20 points) --- 21 thru 40 points\n\r\n1st misses (0 points), 2nd hits double 20 (40 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 41 thru 60 points\n\r\n1st misses (0 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 61 thru 80 points\n\r\n1st hits double 20 (40 points), 2nd hits double 20 (40 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 81 thru 100 points\n\r\n1st hits double 20 (40 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 101 thru 120 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 121 thru 140 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 7 (21 points) --- 60 + 60 + 21 = 141 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 11 (22 points) --- 60 + 60 + 22 = 142 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 13 (26 points) --- 60 + 57 + 26 = 143 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 15 (30 points) --- 60 + 54 + 30 = 144 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits double 17 (34 points) --- 60 + 51 + 34 = 145 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits double 19 (38 points) --- 60 + 48 + 38 = 146 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits triple 13 (39 points) --- 60 + 48 + 39 = 147 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits double 20 (40 points) --- 60 + 48 + 40 = 148 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 16 (32 points) --- 60 + 57 + 32 = 149 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 18 (36 points) --- 60 + 54 + 36 = 150 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits double 20 (40 points) --- 60 + 51 + 40 = 151 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 16 (32 points) --- 60 + 60 + 32 = 152 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 18 (36 points) --- 60 + 57 + 36 = 153 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 20 (40 points) --- 60 + 54 + 40 = 154 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 19 (38 points) --- 60 + 57 + 38 = 155 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 18 (36 points) --- 60 + 60 + 36 = 156 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 20 (40 points) --- 60 + 57 + 40 = 157 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 19 (38 points) --- 60 + 60 + 38 = 158 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 13 (39 points) --- 60 + 60 + 39 = 159 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 20 (40 points) --- 60 + 60 + 40 = 160 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits center bull's eye (50 points) --- 60 + 51 + 50 = 161 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 14 (42 points) --- 60 + 60 + 42 = 162 points\n\r\n163 points can not be achieved for the following reasons:\n\r\nIf two darts each hit a triple 20 for 60 points each, that produces 120 points, which requires another 43 points to reach 163. 43, being prime, can not be achieved with any single, double, or triple score.\n\r\nIf one dart hits triple 20 and another hits the center bull's eye, that achieves 110 points, leaving the need for an additional 53 points. 53 is prime, so can not be reached by any hit.\n\r\nIf two darts both hit the center bull's eye for 100 points, that still leaves a need for 63 points. 63 is not prime, but can not be reached, since it would require a triple 21 (there is no 21 on a dart board).\n<|im_start|>answer\n163\n\r\nScoring combinations to achieve 0 thru 162 points:\n\r\nall three darts miss --- 0 points\n\r\n1st misses (0 points), 2nd misses (0 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 1 thru 20 points\n\r\n1st misses (0 points), 2nd hits single 20 (20 points), 3rd hits single 1 thru 20 (0 thru 20 points) --- 21 thru 40 points\n\r\n1st misses (0 points), 2nd hits double 20 (40 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 41 thru 60 points\n\r\n1st misses (0 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 61 thru 80 points\n\r\n1st hits double 20 (40 points), 2nd hits double 20 (40 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 81 thru 100 points\n\r\n1st hits double 20 (40 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 101 thru 120 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits single 1 thru 20 (1 thru 20 points) --- 121 thru 140 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 7 (21 points) --- 60 + 60 + 21 = 141 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 11 (22 points) --- 60 + 60 + 22 = 142 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 13 (26 points) --- 60 + 57 + 26 = 143 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 15 (30 points) --- 60 + 54 + 30 = 144 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits double 17 (34 points) --- 60 + 51 + 34 = 145 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits double 19 (38 points) --- 60 + 48 + 38 = 146 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits triple 13 (39 points) --- 60 + 48 + 39 = 147 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 16 (48 points), 3rd hits double 20 (40 points) --- 60 + 48 + 40 = 148 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 16 (32 points) --- 60 + 57 + 32 = 149 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 18 (36 points) --- 60 + 54 + 36 = 150 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits double 20 (40 points) --- 60 + 51 + 40 = 151 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 16 (32 points) --- 60 + 60 + 32 = 152 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 18 (36 points) --- 60 + 57 + 36 = 153 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 18 (54 points), 3rd hits double 20 (40 points) --- 60 + 54 + 40 = 154 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 19 (38 points) --- 60 + 57 + 38 = 155 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 18 (36 points) --- 60 + 60 + 36 = 156 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 19 (57 points), 3rd hits double 20 (40 points) --- 60 + 57 + 40 = 157 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 19 (38 points) --- 60 + 60 + 38 = 158 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 13 (39 points) --- 60 + 60 + 39 = 159 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits double 20 (40 points) --- 60 + 60 + 40 = 160 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 17 (51 points), 3rd hits center bull's eye (50 points) --- 60 + 51 + 50 = 161 points\n\r\n1st hits triple 20 (60 points), 2nd hits triple 20 (60 points), 3rd hits triple 14 (42 points) --- 60 + 60 + 42 = 162 points\n\r\n163 points can not be achieved for the following reasons:\n\r\nIf two darts each hit a triple 20 for 60 points each, that produces 120 points, which requires another 43 points to reach 163. 43, being prime, can not be achieved with any single, double, or triple score.\n\r\nIf one dart hits triple 20 and another hits the center bull's eye, that achieves 110 points, leaving the need for an additional 53 points. 53 is prime, so can not be reached by any hit.\n\r\nIf two darts both hit the center bull's eye for 100 points, that still leaves a need for 63 points. 63 is not prime, but can not be reached, since it would require a triple 21 (there is no 21 on a dart board).\n<|im_end|>" }, { "id": "#2918", "title": "Two Pound Stick", "fun": 2.11, "difficulty": 1.57, "author": "204_BLaZe_41", "desc": "Jack found a stick that weighed exactly two pounds. If Jack cut the stick into eight equal pieces, how much would each piece weigh?", "hint": "No hint available.", "answer": "Each piece would weigh just less than a quarter of a pound. (The sawdust created from the cut would cause the loss) \n\r\nThis is similar to the situation that appeared in Shakespeare's play \"The Merchant of Venice\". When Shylock won a pound of Antonio's flesh, he was allotted only the pound of flesh. This meant he could take a pound of flesh, but he could only do it on condition that he takes no blood or even a fraction more than one pound of flesh.", "category": "Math", "date": "03/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack found a stick that weighed exactly two pounds. If Jack cut the stick into eight equal pieces, how much would each piece weigh?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEach piece would weigh just less than a quarter of a pound. (The sawdust created from the cut would cause the loss) \n\r\nThis is similar to the situation that appeared in Shakespeare's play \"The Merchant of Venice\". When Shylock won a pound of Antonio's flesh, he was allotted only the pound of flesh. This meant he could take a pound of flesh, but he could only do it on condition that he takes no blood or even a fraction more than one pound of flesh.\n<|im_start|>answer\nEach piece would weigh just less than a quarter of a pound. (The sawdust created from the cut would cause the loss) \n\r\nThis is similar to the situation that appeared in Shakespeare's play \"The Merchant of Venice\". When Shylock won a pound of Antonio's flesh, he was allotted only the pound of flesh. This meant he could take a pound of flesh, but he could only do it on condition that he takes no blood or even a fraction more than one pound of flesh.\n<|im_end|>" }, { "id": "#42914", "title": "How Old Are They 2", "fun": 2.11, "difficulty": 1.1, "author": "cacmjc", "desc": "Patty is 3 times as old as her brother, Terry. In 10 years, the sum of their ages will be 36.\n\r\nHow old are they now?", "hint": "Set up an equation.", "answer": "Patty is 12 and Terry is 4.", "category": "Math", "date": "08/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPatty is 3 times as old as her brother, Terry. In 10 years, the sum of their ages will be 36.\n\r\nHow old are they now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPatty is 12 and Terry is 4.\n<|im_start|>answer\nPatty is 12 and Terry is 4.\n<|im_end|>" }, { "id": "#44434", "title": "The Triathletes", "fun": 2.11, "difficulty": 0.81, "author": "bigpat", "desc": "Andy, Bob, and Carl are three friends who are triathletes. One day they decided to race each triathlon event (Swimming, Cycling, and Running) separately to see how they stacked up.\n\r\nCan you figure out who placed where in each of the three events?\n\r\n- One person (who placed ahead of Andy in swimming) didn't place first in cycling, second in swimming, or third in running.\r\n- Carl didn't place ahead of Andy in running or swimming.\r\n- A person placed second in all events.", "hint": "No hint available.", "answer": "Andy - 2nd swimming, 2nd cycling, 2nd running\r\nBob - 1st swimming, 3rd cycling, 1st running\r\nCarl - 3rd swimming, 1st cycling, 3rd running", "category": "Logic-Grid", "date": "05/10/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAndy, Bob, and Carl are three friends who are triathletes. One day they decided to race each triathlon event (Swimming, Cycling, and Running) separately to see how they stacked up.\n\r\nCan you figure out who placed where in each of the three events?\n\r\n- One person (who placed ahead of Andy in swimming) didn't place first in cycling, second in swimming, or third in running.\r\n- Carl didn't place ahead of Andy in running or swimming.\r\n- A person placed second in all events.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndy - 2nd swimming, 2nd cycling, 2nd running\r\nBob - 1st swimming, 3rd cycling, 1st running\r\nCarl - 3rd swimming, 1st cycling, 3rd running\n<|im_start|>answer\nAndy - 2nd swimming, 2nd cycling, 2nd running\r\nBob - 1st swimming, 3rd cycling, 1st running\r\nCarl - 3rd swimming, 1st cycling, 3rd running\n<|im_end|>" }, { "id": "#27696", "title": "Ball Game Snacks", "fun": 2.11, "difficulty": 0.89, "author": "EnderofGames", "desc": "A man took his two sons to a baseball game. Each of the three wore a different kind of shoes and clothing. They were hungry, so each either had icecream, a hotdog, or peanuts, and no one had the same thing to eat.\n\r\nA) The father was not wearing loafers.\r\nB) The younger brother was wearing sandals, but did not have ice cream or peanuts.\r\nC) The older brother was wearing a jacket and had ice cream.\r\nD) The person wearing the sweater had a hot dog.", "hint": "Bro. = Brother.", "answer": "Father: Sneakers, Sweatshirt, and Peanuts.\r\nOlder Brother: Loafers, Jacket, and Ice Cream.\r\nYounger Brother: Sandals, Sweater, and a Hot Dog", "category": "Logic-Grid", "date": "12/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man took his two sons to a baseball game. Each of the three wore a different kind of shoes and clothing. They were hungry, so each either had icecream, a hotdog, or peanuts, and no one had the same thing to eat.\n\r\nA) The father was not wearing loafers.\r\nB) The younger brother was wearing sandals, but did not have ice cream or peanuts.\r\nC) The older brother was wearing a jacket and had ice cream.\r\nD) The person wearing the sweater had a hot dog.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFather: Sneakers, Sweatshirt, and Peanuts.\r\nOlder Brother: Loafers, Jacket, and Ice Cream.\r\nYounger Brother: Sandals, Sweater, and a Hot Dog\n<|im_start|>answer\nFather: Sneakers, Sweatshirt, and Peanuts.\r\nOlder Brother: Loafers, Jacket, and Ice Cream.\r\nYounger Brother: Sandals, Sweater, and a Hot Dog\n<|im_end|>" }, { "id": "#45817", "title": "Thanksgiving", "fun": 2.11, "difficulty": 0.7000000000000001, "author": "pokegirl09", "desc": "Ann, Mike, Lyn, and Bill, whose last names are Juarez, Newton, Myers, and Ken, each have a favorite Thanksgiving dish - turkey, dressing, cranberry sauce, and pumpkin pie. Sort out the clues and match up everything.\n\r\n1. Juarez has her favorite dish after the main meal.\n\r\n2. Mike loves his favorite dish with lots of onion and celery in it.\n\r\n3. Myers has her favorite dish served in slices (light and dark).\n\r\n4. Ann hates sweets.\n\r\n5. Newton is allergic to cranberries.", "hint": "No hint available.", "answer": "Ann, Myers, turkey\n\r\nMike, Newton, dressing\n\r\nLyn, Juarez, pumpkin pie\n\r\nBill, Ken, cranberry sauce", "category": "Logic-Grid", "date": "11/25/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnn, Mike, Lyn, and Bill, whose last names are Juarez, Newton, Myers, and Ken, each have a favorite Thanksgiving dish - turkey, dressing, cranberry sauce, and pumpkin pie. Sort out the clues and match up everything.\n\r\n1. Juarez has her favorite dish after the main meal.\n\r\n2. Mike loves his favorite dish with lots of onion and celery in it.\n\r\n3. Myers has her favorite dish served in slices (light and dark).\n\r\n4. Ann hates sweets.\n\r\n5. Newton is allergic to cranberries.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnn, Myers, turkey\n\r\nMike, Newton, dressing\n\r\nLyn, Juarez, pumpkin pie\n\r\nBill, Ken, cranberry sauce\n<|im_start|>answer\nAnn, Myers, turkey\n\r\nMike, Newton, dressing\n\r\nLyn, Juarez, pumpkin pie\n\r\nBill, Ken, cranberry sauce\n<|im_end|>" }, { "id": "#50611", "title": "Equalities", "fun": 2.11, "difficulty": 2.43, "author": "Genius39", "desc": "Observe the following equations.\r\n55 = 131\r\n90 = 194\r\n-35 = -31\r\n10 = 50\r\n-50 = -58\r\nIn this sense, find the equation wherein the number on the left side of the equation is also the number on the right side of the equation. (a=a)", "hint": "Do you feel sick keeping on solving?", "answer": "-40 = -40.\r\nThe first number is the temperature in Celsius while the second one is the temperature in Fahrenheit.\r\nFor the hint: Do you feel SICK keeping on solving?\r\nSICK gives a clue to FEVER, leading you to think of TEMPERATURE.", "category": "Math", "date": "07/19/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nObserve the following equations.\r\n55 = 131\r\n90 = 194\r\n-35 = -31\r\n10 = 50\r\n-50 = -58\r\nIn this sense, find the equation wherein the number on the left side of the equation is also the number on the right side of the equation. (a=a)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-40 = -40.\r\nThe first number is the temperature in Celsius while the second one is the temperature in Fahrenheit.\r\nFor the hint: Do you feel SICK keeping on solving?\r\nSICK gives a clue to FEVER, leading you to think of TEMPERATURE.\n<|im_start|>answer\n-40 = -40.\r\nThe first number is the temperature in Celsius while the second one is the temperature in Fahrenheit.\r\nFor the hint: Do you feel SICK keeping on solving?\r\nSICK gives a clue to FEVER, leading you to think of TEMPERATURE.\n<|im_end|>" }, { "id": "#23845", "title": "Missed Birthday Present!", "fun": 2.11, "difficulty": 1.06, "author": "verdah", "desc": "Jay received this note from his Uncle Mario: P.S. I planned to enclose $50.00 with the note, but I sealed the envelope and forgot.\r\nDoes the note make sense? Why or why not?", "hint": "No hint available.", "answer": "No, it does not make sense. If he wrote that he planned to enclose the money and then forgot, how did he write that? Even if he went back and ripped the seal, he still could have put the money in.", "category": "Logic", "date": "06/19/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJay received this note from his Uncle Mario: P.S. I planned to enclose $50.00 with the note, but I sealed the envelope and forgot.\r\nDoes the note make sense? Why or why not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo, it does not make sense. If he wrote that he planned to enclose the money and then forgot, how did he write that? Even if he went back and ripped the seal, he still could have put the money in.\n<|im_start|>answer\nNo, it does not make sense. If he wrote that he planned to enclose the money and then forgot, how did he write that? Even if he went back and ripped the seal, he still could have put the money in.\n<|im_end|>" }, { "id": "#44165", "title": "Lines and Dots", "fun": 2.11, "difficulty": 1.18, "author": "Jarhead", "desc": "If 2 lines and 4 dots equals 14 and 3 lines and 2 dots equals 17, what does 1 line and 3 dots equal?\n\r\n2 lines + 4 dots = 14\r\n3 lines + 2 dots = 17\r\n1 line + 3 dots = ?", "hint": "No hint available.", "answer": "8\n\r\nThis is Mayan math. A line represents 5, a dot represents 1, and a shell represents 0 (place holder.)", "category": "Math", "date": "02/23/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 2 lines and 4 dots equals 14 and 3 lines and 2 dots equals 17, what does 1 line and 3 dots equal?\n\r\n2 lines + 4 dots = 14\r\n3 lines + 2 dots = 17\r\n1 line + 3 dots = ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8\n\r\nThis is Mayan math. A line represents 5, a dot represents 1, and a shell represents 0 (place holder.)\n<|im_start|>answer\n8\n\r\nThis is Mayan math. A line represents 5, a dot represents 1, and a shell represents 0 (place holder.)\n<|im_end|>" }, { "id": "#18247", "title": "Pattern 15", "fun": 2.11, "difficulty": 1.4, "author": "oosunshyneoo", "desc": "Five different whole numbers add up to 15, Multiply those same five numbers and you get 120. What are the five numbers?", "hint": "No hint available.", "answer": "1 x 2 x 3 x 4 x 5 = 120\r\n1 + 2 + 3 + 4 + 5 = 15", "category": "Math", "date": "07/18/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive different whole numbers add up to 15, Multiply those same five numbers and you get 120. What are the five numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 x 2 x 3 x 4 x 5 = 120\r\n1 + 2 + 3 + 4 + 5 = 15\n<|im_start|>answer\n1 x 2 x 3 x 4 x 5 = 120\r\n1 + 2 + 3 + 4 + 5 = 15\n<|im_end|>" }, { "id": "#12711", "title": "A Journey to Flower-Heaven", "fun": 2.11, "difficulty": 2.82, "author": "kvakk", "desc": "Hi. My name is mister Kvakk. I live in a very big house in the country. Outside my house I have a lot of big gardens. In one of them I have hundreds of beautiful, delicious, red flowers.\r\nAt my house, my dog is waiting. I have told him about this flower-heaven-garden with hundreds of flowers, and it really wants to find that garden to eat the flowers (yes, my dog eats flowers).\r\nHowever, this flower-heaven is far away, and my dog wants to go there as soon as possible. It has to travel through some other gardens on its way, but it wants to travel between as few other gardens as possible.\r\nYour mission is to find the best route for my dog, from my house to the flower-heaven. The dog wants to go through as few gardens as possible on its way.\n\r\nHere are some facts about my gardens:\r\n1. There are two gardens between my (mister Kvakk's) house and the house of my neighbour Quack, if you take the shortest route.\r\n2. The only garden between The lawn and Soria is The field\r\n3. It's one garden between The field and flower-heaven\r\n4. One possible route (but not the shortest) from Kvakk to flower-heaven, is: The pool, Soria, Star, The mountain\r\n5. To go from Kvakk to Quack as fast as possible, you don't need to go through The field, The forest, The angels valley or Star\r\n6. You can go from The forest to The mountain by going through Longo\r\n7. Duck country and The forest are my only two gardens that lie against Quack's house\r\n8. From the garden The field, you can go directly to The lawn, Longo, The pool, Soria, Star and Kvakk's house\r\n9. There are two gardens between Quack and flower-heaven. These are not the same gardens that are between Kvakk and Quack\r\n10. Quack's house is to the east of Kvakk's house\r\n11. Flower-heaven is south-west of Quack's house\r\n12. Except for the two houses and flower-heaven, ten gardens of different size and shape are named in this teaser\r\n13. You can go into flower-heaven from three different gardens\r\n14. If you are at Star, you must go through one garden to come to flower-heaven\r\n15. Star, The lawn, The mountain, The pool, Soria, The forest, Duck Country and the two houses lie beside the sea. It is not possible for the dog to travel through the sea. Luckily, no other gardens lie beside the sea. \r\n16. The angel's valley is between flower-heaven and The forest \n\r\nThrough which gardens should my dog travel?", "hint": "It's easiest to solve this if you try to draw a kind of map. You should maybe start by using the information points in this order: 1, 10, 7, 9, 11, 4, 5, 6, 8", "answer": "-You should start by drawing the two houses and the two gardens between them (1). The house to the west is my (mister Kvakk's) house (10).\r\n-From 7 we know that the garden to the left of Quack is either Duck country or The forest\r\n-Use 9 and 11 to draw flower-heaven to the south of Quack. The first garden to the south of Quack is either Duck country or The forest\r\n-Use 4 to draw the four gardens The pool, Soria, Star and The mountain between Kvakk and flower-heaven\r\n-From 5 you see that you don't need to go through The forest to go from Kvakk to Quack. Therefore, the garden to the left of Quack must be Duck country. And so on, the garden to the south must be The forest.\r\n-Use 6 to draw in the garden Longo\r\n-And finally, use 8 to draw the garden The field\r\n-By 3 and 13 we know se the solution. The three gardens that lie against flower-haven must be The angels valley, Longo and The mountain.\n\r\nThe shortest route (measured in number of gardens) is: Kvakk's house / The field / Longo / Flower-heaven", "category": "Logic", "date": "05/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHi. My name is mister Kvakk. I live in a very big house in the country. Outside my house I have a lot of big gardens. In one of them I have hundreds of beautiful, delicious, red flowers.\r\nAt my house, my dog is waiting. I have told him about this flower-heaven-garden with hundreds of flowers, and it really wants to find that garden to eat the flowers (yes, my dog eats flowers).\r\nHowever, this flower-heaven is far away, and my dog wants to go there as soon as possible. It has to travel through some other gardens on its way, but it wants to travel between as few other gardens as possible.\r\nYour mission is to find the best route for my dog, from my house to the flower-heaven. The dog wants to go through as few gardens as possible on its way.\n\r\nHere are some facts about my gardens:\r\n1. There are two gardens between my (mister Kvakk's) house and the house of my neighbour Quack, if you take the shortest route.\r\n2. The only garden between The lawn and Soria is The field\r\n3. It's one garden between The field and flower-heaven\r\n4. One possible route (but not the shortest) from Kvakk to flower-heaven, is: The pool, Soria, Star, The mountain\r\n5. To go from Kvakk to Quack as fast as possible, you don't need to go through The field, The forest, The angels valley or Star\r\n6. You can go from The forest to The mountain by going through Longo\r\n7. Duck country and The forest are my only two gardens that lie against Quack's house\r\n8. From the garden The field, you can go directly to The lawn, Longo, The pool, Soria, Star and Kvakk's house\r\n9. There are two gardens between Quack and flower-heaven. These are not the same gardens that are between Kvakk and Quack\r\n10. Quack's house is to the east of Kvakk's house\r\n11. Flower-heaven is south-west of Quack's house\r\n12. Except for the two houses and flower-heaven, ten gardens of different size and shape are named in this teaser\r\n13. You can go into flower-heaven from three different gardens\r\n14. If you are at Star, you must go through one garden to come to flower-heaven\r\n15. Star, The lawn, The mountain, The pool, Soria, The forest, Duck Country and the two houses lie beside the sea. It is not possible for the dog to travel through the sea. Luckily, no other gardens lie beside the sea. \r\n16. The angel's valley is between flower-heaven and The forest \n\r\nThrough which gardens should my dog travel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-You should start by drawing the two houses and the two gardens between them (1). The house to the west is my (mister Kvakk's) house (10).\r\n-From 7 we know that the garden to the left of Quack is either Duck country or The forest\r\n-Use 9 and 11 to draw flower-heaven to the south of Quack. The first garden to the south of Quack is either Duck country or The forest\r\n-Use 4 to draw the four gardens The pool, Soria, Star and The mountain between Kvakk and flower-heaven\r\n-From 5 you see that you don't need to go through The forest to go from Kvakk to Quack. Therefore, the garden to the left of Quack must be Duck country. And so on, the garden to the south must be The forest.\r\n-Use 6 to draw in the garden Longo\r\n-And finally, use 8 to draw the garden The field\r\n-By 3 and 13 we know se the solution. The three gardens that lie against flower-haven must be The angels valley, Longo and The mountain.\n\r\nThe shortest route (measured in number of gardens) is: Kvakk's house / The field / Longo / Flower-heaven\n<|im_start|>answer\n-You should start by drawing the two houses and the two gardens between them (1). The house to the west is my (mister Kvakk's) house (10).\r\n-From 7 we know that the garden to the left of Quack is either Duck country or The forest\r\n-Use 9 and 11 to draw flower-heaven to the south of Quack. The first garden to the south of Quack is either Duck country or The forest\r\n-Use 4 to draw the four gardens The pool, Soria, Star and The mountain between Kvakk and flower-heaven\r\n-From 5 you see that you don't need to go through The forest to go from Kvakk to Quack. Therefore, the garden to the left of Quack must be Duck country. And so on, the garden to the south must be The forest.\r\n-Use 6 to draw in the garden Longo\r\n-And finally, use 8 to draw the garden The field\r\n-By 3 and 13 we know se the solution. The three gardens that lie against flower-haven must be The angels valley, Longo and The mountain.\n\r\nThe shortest route (measured in number of gardens) is: Kvakk's house / The field / Longo / Flower-heaven\n<|im_end|>" }, { "id": "#5060", "title": "Take a Cruise", "fun": 2.11, "difficulty": 2.06, "author": "something", "desc": "Bob spent $963.47 on a luxury cruise from Oahu to Maui to the Bahamas. He planned to stay 2 days in the Bahamas before he went back to Hawaii. During the cruise, he spent 1 day of his time water skiing, 3 days sleeping, 2 days reading, 13 hours relaxing, 12 hours rock-climbing, and 23 hours swimming. How many days was the cruise?", "hint": "No hint available.", "answer": "16 days because it's 8 days there and 8 days back.", "category": "Math", "date": "06/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob spent $963.47 on a luxury cruise from Oahu to Maui to the Bahamas. He planned to stay 2 days in the Bahamas before he went back to Hawaii. During the cruise, he spent 1 day of his time water skiing, 3 days sleeping, 2 days reading, 13 hours relaxing, 12 hours rock-climbing, and 23 hours swimming. How many days was the cruise?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16 days because it's 8 days there and 8 days back.\n<|im_start|>answer\n16 days because it's 8 days there and 8 days back.\n<|im_end|>" }, { "id": "#1149", "title": "Time in a day", "fun": 2.11, "difficulty": 1.8900000000000001, "author": "Ichabod Clay", "desc": "Take 24 hours. Subtract that from a day. How many seconds do you have left?", "hint": "Don't go too fast on this one. Try to remember how many days are in a year. (not 365....exactly)", "answer": "About 59 seconds. Remember, a day isn't exactly 24 hours since every year has 365 1/4 days. (6/365)*60*60 = 59.178", "category": "Math", "date": "10/17/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTake 24 hours. Subtract that from a day. How many seconds do you have left?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAbout 59 seconds. Remember, a day isn't exactly 24 hours since every year has 365 1/4 days. (6/365)*60*60 = 59.178\n<|im_start|>answer\nAbout 59 seconds. Remember, a day isn't exactly 24 hours since every year has 365 1/4 days. (6/365)*60*60 = 59.178\n<|im_end|>" }, { "id": "#9414", "title": "One O'clock", "fun": 2.11, "difficulty": 1.24, "author": "ccccc", "desc": "If 2 hours ago it was as long after one o'clock in the afternoon as it was before one o'clock in the morning. What time \r\nwould it be now?", "hint": "No hint available.", "answer": "Nine o'clock. Since there are 12 hours between the 2 times, and half of that time is six, then the halfway mark would have to be 7 o'clock. If it were 7 o'clock two hours ago, the time would now be nine o'clock.", "category": "Math", "date": "12/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 2 hours ago it was as long after one o'clock in the afternoon as it was before one o'clock in the morning. What time \r\nwould it be now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNine o'clock. Since there are 12 hours between the 2 times, and half of that time is six, then the halfway mark would have to be 7 o'clock. If it were 7 o'clock two hours ago, the time would now be nine o'clock.\n<|im_start|>answer\nNine o'clock. Since there are 12 hours between the 2 times, and half of that time is six, then the halfway mark would have to be 7 o'clock. If it were 7 o'clock two hours ago, the time would now be nine o'clock.\n<|im_end|>" }, { "id": "#10832", "title": "Madadian Cruise", "fun": 2.11, "difficulty": 2.38, "author": "mad-ade", "desc": "On Sunday, December 22, four Madadian cruise ships - W, X, Y, Z - started their series of winter cruises to various ports around Madadia.\n\r\nShip W left at 4:00 PM on Sunday, December 22, for a series of 8-days cruises to Madport. \n\r\nShip X left at 4:30 PM on Sunday, December 22, for a series of alternating 11-days and 13-days cruises to Adeville. \n\r\nShip Y left at 5:00 PM on Sunday, December 22, for a series of 5-days cruises to Kebabtown. \n\r\nShip Z left on Monday for a series of 7-days cruises.\r\nEach ship is scheduled to return back early in the morning after the last day of the cruise and leave again late in the afternoon of the same day. \n\r\nOn how many days occasions between December 22 and February 28 will three ships be moored at the port?", "hint": "No hint available.", "answer": "On no occasions (other than start date December 22) between December 22 and February 28, three ships will be moored at the port. \n\r\nFind out the days on when each ship will be in port:\r\nShip W will be in port on days 1, 9, 17, 25, 33, 41, 49, 57 and 65. \n\r\nShip X will be in port on days 1, 12, 25, 36, 49, 60 and 73. \n\r\nShip Y will be in port on days 1, 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61 and 66. \n\r\nShip Z will be in port on days 1, 2, 9, 16, 23, 30, 37, 44, 51, 58 and 65.\r\nFrom above data, it is clear that - on no occasion (other than December 22) will three ships be moored at the port. \n\r\nAlso, on 8 occasions, there will be 2 ships moored at the port.", "category": "Logic", "date": "03/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn Sunday, December 22, four Madadian cruise ships - W, X, Y, Z - started their series of winter cruises to various ports around Madadia.\n\r\nShip W left at 4:00 PM on Sunday, December 22, for a series of 8-days cruises to Madport. \n\r\nShip X left at 4:30 PM on Sunday, December 22, for a series of alternating 11-days and 13-days cruises to Adeville. \n\r\nShip Y left at 5:00 PM on Sunday, December 22, for a series of 5-days cruises to Kebabtown. \n\r\nShip Z left on Monday for a series of 7-days cruises.\r\nEach ship is scheduled to return back early in the morning after the last day of the cruise and leave again late in the afternoon of the same day. \n\r\nOn how many days occasions between December 22 and February 28 will three ships be moored at the port?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOn no occasions (other than start date December 22) between December 22 and February 28, three ships will be moored at the port. \n\r\nFind out the days on when each ship will be in port:\r\nShip W will be in port on days 1, 9, 17, 25, 33, 41, 49, 57 and 65. \n\r\nShip X will be in port on days 1, 12, 25, 36, 49, 60 and 73. \n\r\nShip Y will be in port on days 1, 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61 and 66. \n\r\nShip Z will be in port on days 1, 2, 9, 16, 23, 30, 37, 44, 51, 58 and 65.\r\nFrom above data, it is clear that - on no occasion (other than December 22) will three ships be moored at the port. \n\r\nAlso, on 8 occasions, there will be 2 ships moored at the port.\n<|im_start|>answer\nOn no occasions (other than start date December 22) between December 22 and February 28, three ships will be moored at the port. \n\r\nFind out the days on when each ship will be in port:\r\nShip W will be in port on days 1, 9, 17, 25, 33, 41, 49, 57 and 65. \n\r\nShip X will be in port on days 1, 12, 25, 36, 49, 60 and 73. \n\r\nShip Y will be in port on days 1, 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61 and 66. \n\r\nShip Z will be in port on days 1, 2, 9, 16, 23, 30, 37, 44, 51, 58 and 65.\r\nFrom above data, it is clear that - on no occasion (other than December 22) will three ships be moored at the port. \n\r\nAlso, on 8 occasions, there will be 2 ships moored at the port.\n<|im_end|>" }, { "id": "#6057", "title": "Binary Code", "fun": 2.11, "difficulty": 2.33, "author": "george1978", "desc": "What is the hexadecimal code for the following binary code? 11111111", "hint": "Remember 0's and 1's in computer terms mean on and off, and binary starts at 1 and keeps doubling itself to infinity. Also, hexadecimal consists of combinations of numbers and letters A thru F.", "answer": "FF, or the equivalent of 255, which is the actual technical value of a 256 MB stick of RAM.", "category": "Math", "date": "07/30/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the hexadecimal code for the following binary code? 11111111\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFF, or the equivalent of 255, which is the actual technical value of a 256 MB stick of RAM.\n<|im_start|>answer\nFF, or the equivalent of 255, which is the actual technical value of a 256 MB stick of RAM.\n<|im_end|>" }, { "id": "#19031", "title": "Water From 3 Jugs Into Two Pools", "fun": 2.11, "difficulty": 2.78, "author": "nenad", "desc": "You have:\r\n- two 10-liter jugs, full of water\r\n- one 9-liter jug, empty\r\n- two large pools, empty\n\r\nYour objective is to end up having 4 liters of water in each pool, and one liter of water in the 9-liter jug.\n\r\nYou have nothing else at your disposal and you can not measure using eye or shape of jugs. You can not pour water from pools, only into them.", "hint": "This needs 29 steps to fill two pools with 4-liters, and an additional 4 steps to get 1 liter in the 9-liter jug, for a total of 33 steps.", "answer": "Label the 10-liter jugs as A and B, the 9-liter jug as C, and the two pools as Pa and Pb. The problem can be solved in 33 steps, as shown below. Each step is shown in one row, starting with the step number, followed by the jug we poured water from, then the quantity of water, then the jug/pool we poured water into... i.e. A ->( 1)-> Pb means we poured 1 liter of water from jug A (being 1st 10-liter jug) to pool Pb (being 2nd pool). Finally in the row we show how much water we have in each jug/pool after performing this step. \n\n\r\n------------------------------------\r\n#: From -> Qty -> To = A B C Pa Pb\r\n------------------------------------\r\n 0: _____________ = 10 10 0 0 0\r\n 1: A ->( 9)-> C = 1 10 9 0 0\r\n 2: A ->( 1)-> Pa = 0 10 9 1 0\r\n 3: C ->( 9)-> A = 9 10 0 1 0\r\n 4: B ->( 9)-> C = 9 1 9 1 0\r\n 5: B ->( 1)-> Pa = 9 0 9 2 0\r\n 6: C ->( 1)-> A = 10 0 8 2 0\r\n 7: C ->( 8)-> B = 10 8 0 2 0\r\n 8: A ->( 9)-> C = 1 8 9 2 0\r\n 9: A ->( 1)-> Pa = 0 8 9 3 0\r\n10: C ->( 9)-> A = 9 8 0 3 0\r\n11: A ->( 2)-> B = 7 10 0 3 0\r\n12: B ->( 9)-> C = 7 1 9 3 0\r\n13: B ->( 1)-> Pa = 7 0 9 4 0\r\n14: C ->( 3)-> A = 10 0 6 4 0\r\n15: C ->( 6)-> B = 10 6 0 4 0\r\n16: A ->( 9)-> C = 1 6 9 4 0\r\n17: A ->( 1)-> Pb = 0 6 9 4 1\r\n18: C ->( 9)-> A = 9 6 0 4 1\r\n19: A ->( 4)-> B = 5 10 0 4 1\r\n20: B ->( 9)-> C = 5 1 9 4 1\r\n21: B ->( 1)-> Pb = 5 0 9 4 2\r\n22: C ->( 5)-> A = 10 0 4 4 2\r\n23: C ->( 4)-> B = 10 4 0 4 2\r\n24: A ->( 9)-> C = 1 4 9 4 2\r\n25: A ->( 1)-> Pb = 0 4 9 4 3\r\n26: C ->( 9)-> A = 9 4 0 4 3\r\n27: A ->( 6)-> B = 3 10 0 4 3\r\n28: B ->( 9)-> C = 3 1 9 4 3\r\n29: B ->( 1)-> Pb = 3 0 9 4 4\r\n30: C ->( 7)-> A = 10 0 2 4 4\r\n31: C ->( 2)-> B = 10 2 0 4 4\r\n32: A ->( 9)-> C = 1 2 9 4 4\r\n33: C ->( 8)-> B = 1 10 1 4 4\n\r\nAfter the 33rd step we end up with 4 liters in each pool (Pa and Pb), and 1 liter in the 9-liter jug (C), as requested in the problem.", "category": "Logic", "date": "10/04/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have:\r\n- two 10-liter jugs, full of water\r\n- one 9-liter jug, empty\r\n- two large pools, empty\n\r\nYour objective is to end up having 4 liters of water in each pool, and one liter of water in the 9-liter jug.\n\r\nYou have nothing else at your disposal and you can not measure using eye or shape of jugs. You can not pour water from pools, only into them.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLabel the 10-liter jugs as A and B, the 9-liter jug as C, and the two pools as Pa and Pb. The problem can be solved in 33 steps, as shown below. Each step is shown in one row, starting with the step number, followed by the jug we poured water from, then the quantity of water, then the jug/pool we poured water into... i.e. A ->( 1)-> Pb means we poured 1 liter of water from jug A (being 1st 10-liter jug) to pool Pb (being 2nd pool). Finally in the row we show how much water we have in each jug/pool after performing this step. \n\n\r\n------------------------------------\r\n#: From -> Qty -> To = A B C Pa Pb\r\n------------------------------------\r\n 0: _____________ = 10 10 0 0 0\r\n 1: A ->( 9)-> C = 1 10 9 0 0\r\n 2: A ->( 1)-> Pa = 0 10 9 1 0\r\n 3: C ->( 9)-> A = 9 10 0 1 0\r\n 4: B ->( 9)-> C = 9 1 9 1 0\r\n 5: B ->( 1)-> Pa = 9 0 9 2 0\r\n 6: C ->( 1)-> A = 10 0 8 2 0\r\n 7: C ->( 8)-> B = 10 8 0 2 0\r\n 8: A ->( 9)-> C = 1 8 9 2 0\r\n 9: A ->( 1)-> Pa = 0 8 9 3 0\r\n10: C ->( 9)-> A = 9 8 0 3 0\r\n11: A ->( 2)-> B = 7 10 0 3 0\r\n12: B ->( 9)-> C = 7 1 9 3 0\r\n13: B ->( 1)-> Pa = 7 0 9 4 0\r\n14: C ->( 3)-> A = 10 0 6 4 0\r\n15: C ->( 6)-> B = 10 6 0 4 0\r\n16: A ->( 9)-> C = 1 6 9 4 0\r\n17: A ->( 1)-> Pb = 0 6 9 4 1\r\n18: C ->( 9)-> A = 9 6 0 4 1\r\n19: A ->( 4)-> B = 5 10 0 4 1\r\n20: B ->( 9)-> C = 5 1 9 4 1\r\n21: B ->( 1)-> Pb = 5 0 9 4 2\r\n22: C ->( 5)-> A = 10 0 4 4 2\r\n23: C ->( 4)-> B = 10 4 0 4 2\r\n24: A ->( 9)-> C = 1 4 9 4 2\r\n25: A ->( 1)-> Pb = 0 4 9 4 3\r\n26: C ->( 9)-> A = 9 4 0 4 3\r\n27: A ->( 6)-> B = 3 10 0 4 3\r\n28: B ->( 9)-> C = 3 1 9 4 3\r\n29: B ->( 1)-> Pb = 3 0 9 4 4\r\n30: C ->( 7)-> A = 10 0 2 4 4\r\n31: C ->( 2)-> B = 10 2 0 4 4\r\n32: A ->( 9)-> C = 1 2 9 4 4\r\n33: C ->( 8)-> B = 1 10 1 4 4\n\r\nAfter the 33rd step we end up with 4 liters in each pool (Pa and Pb), and 1 liter in the 9-liter jug (C), as requested in the problem.\n<|im_start|>answer\nLabel the 10-liter jugs as A and B, the 9-liter jug as C, and the two pools as Pa and Pb. The problem can be solved in 33 steps, as shown below. Each step is shown in one row, starting with the step number, followed by the jug we poured water from, then the quantity of water, then the jug/pool we poured water into... i.e. A ->( 1)-> Pb means we poured 1 liter of water from jug A (being 1st 10-liter jug) to pool Pb (being 2nd pool). Finally in the row we show how much water we have in each jug/pool after performing this step. \n\n\r\n------------------------------------\r\n#: From -> Qty -> To = A B C Pa Pb\r\n------------------------------------\r\n 0: _____________ = 10 10 0 0 0\r\n 1: A ->( 9)-> C = 1 10 9 0 0\r\n 2: A ->( 1)-> Pa = 0 10 9 1 0\r\n 3: C ->( 9)-> A = 9 10 0 1 0\r\n 4: B ->( 9)-> C = 9 1 9 1 0\r\n 5: B ->( 1)-> Pa = 9 0 9 2 0\r\n 6: C ->( 1)-> A = 10 0 8 2 0\r\n 7: C ->( 8)-> B = 10 8 0 2 0\r\n 8: A ->( 9)-> C = 1 8 9 2 0\r\n 9: A ->( 1)-> Pa = 0 8 9 3 0\r\n10: C ->( 9)-> A = 9 8 0 3 0\r\n11: A ->( 2)-> B = 7 10 0 3 0\r\n12: B ->( 9)-> C = 7 1 9 3 0\r\n13: B ->( 1)-> Pa = 7 0 9 4 0\r\n14: C ->( 3)-> A = 10 0 6 4 0\r\n15: C ->( 6)-> B = 10 6 0 4 0\r\n16: A ->( 9)-> C = 1 6 9 4 0\r\n17: A ->( 1)-> Pb = 0 6 9 4 1\r\n18: C ->( 9)-> A = 9 6 0 4 1\r\n19: A ->( 4)-> B = 5 10 0 4 1\r\n20: B ->( 9)-> C = 5 1 9 4 1\r\n21: B ->( 1)-> Pb = 5 0 9 4 2\r\n22: C ->( 5)-> A = 10 0 4 4 2\r\n23: C ->( 4)-> B = 10 4 0 4 2\r\n24: A ->( 9)-> C = 1 4 9 4 2\r\n25: A ->( 1)-> Pb = 0 4 9 4 3\r\n26: C ->( 9)-> A = 9 4 0 4 3\r\n27: A ->( 6)-> B = 3 10 0 4 3\r\n28: B ->( 9)-> C = 3 1 9 4 3\r\n29: B ->( 1)-> Pb = 3 0 9 4 4\r\n30: C ->( 7)-> A = 10 0 2 4 4\r\n31: C ->( 2)-> B = 10 2 0 4 4\r\n32: A ->( 9)-> C = 1 2 9 4 4\r\n33: C ->( 8)-> B = 1 10 1 4 4\n\r\nAfter the 33rd step we end up with 4 liters in each pool (Pa and Pb), and 1 liter in the 9-liter jug (C), as requested in the problem.\n<|im_end|>" }, { "id": "#49152", "title": "Mystery Number 8", "fun": 2.11, "difficulty": 3.07, "author": "cnmne", "desc": "There is a ten digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) If A > B, then C = 5 or 7, else C = 0 or 1.\r\n2) If B > C, then D = 1 or 2, else D = 4 or 9.\r\n3) If C > D, then E = 6 or 9, else E = 3 or 5.\r\n4) If D > E, then F = 2 or 4, else F = 1 or 6.\r\n5) If E > F, then G = 5 or 6, else G = 0 or 7.\r\n6) If F > G, then H = 1 or 4, else H = 8 or 9.\r\n7) If G > H, then I = 0 or 8, else I = 6 or 7.\r\n8) If H > I, then J = 3 or 8, else J = 2 or 5.\r\n9) If I > J, then A = 3 or 7, else A = 4 or 8.\r\n10) If J > A, then B = 0 or 9, else B = 2 or 3.", "hint": "No hint available.", "answer": "8274965103\n\r\nA = 8, B = 2, C = 7, D = 4, E = 9, F = 6, G = 5, H = 1, I = 0, J = 3\n\r\n1) A = 8 (I < J)\r\n2) B = 2 (J < A)\r\n3) C = 7 (A > B)\r\n4) D = 4 (B < C)\r\n5) E = 9 (C > D)\r\n6) F = 6 (D < E)\r\n7) G = 5 (E > F)\r\n8) H = 1 (F > G)\r\n9) I = 0 (G > H)\r\n10) J = 3 (H > I)\n\r\nBrute force methods can be used to arrive at a solution. However, process of elimination does work. For example, assign 8 to H. I can not exceed H, so J would have to be 3 (8 already assigned to H). G can not exceed H, so I would have to be either 6 or 7. I would be greater than J, so A would have to be 7 (3 already assigned to J), meaning I would have to be 6. J is less than A, so B would be 2 (3 already assigned to J). A is greater than B, so C would be 5 (7 already assigned to A). The only remaining numeral for G is 0, which means F would have to be greater than G, meaning H would have to be either 1 or 4. H has already been assigned 8, rendering that assignment impossible. Continue eliminating possibilities in the order shown below.\n\r\nA) H can not be 8. C can not be 1. C can not be 0. B can not be 9. D can not be 1. D can not be 2. F can not be 1.\r\nB) H must be 1. H can not be 4. H can not be 9.\r\nC) G can not be 0. I can not be 6. I can not be 7. B can not be 0.\r\nD) I must be 0. I can not be 8.\r\nE) J can not be 2. J can not be 5. J can not be 8.\r\nF) J must be 3. A can not be 3. B can not be 3. E can not be 3.\r\nG) B must be 2. F can not be 2.\r\nH) A must be 8. A can not be 4. A can not be 7.\r\nI) D can not be 9.\r\nJ) E must be 9. E can not be 5. E can not be 6.\r\nK) D must be 4. F can not be 4.\r\nL) F must be 6. G can not be 6.\r\nM) G must be 5. C can not be 5. G can not be 5.\r\nN) C must be 7.", "category": "Logic", "date": "11/26/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) If A > B, then C = 5 or 7, else C = 0 or 1.\r\n2) If B > C, then D = 1 or 2, else D = 4 or 9.\r\n3) If C > D, then E = 6 or 9, else E = 3 or 5.\r\n4) If D > E, then F = 2 or 4, else F = 1 or 6.\r\n5) If E > F, then G = 5 or 6, else G = 0 or 7.\r\n6) If F > G, then H = 1 or 4, else H = 8 or 9.\r\n7) If G > H, then I = 0 or 8, else I = 6 or 7.\r\n8) If H > I, then J = 3 or 8, else J = 2 or 5.\r\n9) If I > J, then A = 3 or 7, else A = 4 or 8.\r\n10) If J > A, then B = 0 or 9, else B = 2 or 3.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n8274965103\n\r\nA = 8, B = 2, C = 7, D = 4, E = 9, F = 6, G = 5, H = 1, I = 0, J = 3\n\r\n1) A = 8 (I < J)\r\n2) B = 2 (J < A)\r\n3) C = 7 (A > B)\r\n4) D = 4 (B < C)\r\n5) E = 9 (C > D)\r\n6) F = 6 (D < E)\r\n7) G = 5 (E > F)\r\n8) H = 1 (F > G)\r\n9) I = 0 (G > H)\r\n10) J = 3 (H > I)\n\r\nBrute force methods can be used to arrive at a solution. However, process of elimination does work. For example, assign 8 to H. I can not exceed H, so J would have to be 3 (8 already assigned to H). G can not exceed H, so I would have to be either 6 or 7. I would be greater than J, so A would have to be 7 (3 already assigned to J), meaning I would have to be 6. J is less than A, so B would be 2 (3 already assigned to J). A is greater than B, so C would be 5 (7 already assigned to A). The only remaining numeral for G is 0, which means F would have to be greater than G, meaning H would have to be either 1 or 4. H has already been assigned 8, rendering that assignment impossible. Continue eliminating possibilities in the order shown below.\n\r\nA) H can not be 8. C can not be 1. C can not be 0. B can not be 9. D can not be 1. D can not be 2. F can not be 1.\r\nB) H must be 1. H can not be 4. H can not be 9.\r\nC) G can not be 0. I can not be 6. I can not be 7. B can not be 0.\r\nD) I must be 0. I can not be 8.\r\nE) J can not be 2. J can not be 5. J can not be 8.\r\nF) J must be 3. A can not be 3. B can not be 3. E can not be 3.\r\nG) B must be 2. F can not be 2.\r\nH) A must be 8. A can not be 4. A can not be 7.\r\nI) D can not be 9.\r\nJ) E must be 9. E can not be 5. E can not be 6.\r\nK) D must be 4. F can not be 4.\r\nL) F must be 6. G can not be 6.\r\nM) G must be 5. C can not be 5. G can not be 5.\r\nN) C must be 7.\n<|im_start|>answer\n8274965103\n\r\nA = 8, B = 2, C = 7, D = 4, E = 9, F = 6, G = 5, H = 1, I = 0, J = 3\n\r\n1) A = 8 (I < J)\r\n2) B = 2 (J < A)\r\n3) C = 7 (A > B)\r\n4) D = 4 (B < C)\r\n5) E = 9 (C > D)\r\n6) F = 6 (D < E)\r\n7) G = 5 (E > F)\r\n8) H = 1 (F > G)\r\n9) I = 0 (G > H)\r\n10) J = 3 (H > I)\n\r\nBrute force methods can be used to arrive at a solution. However, process of elimination does work. For example, assign 8 to H. I can not exceed H, so J would have to be 3 (8 already assigned to H). G can not exceed H, so I would have to be either 6 or 7. I would be greater than J, so A would have to be 7 (3 already assigned to J), meaning I would have to be 6. J is less than A, so B would be 2 (3 already assigned to J). A is greater than B, so C would be 5 (7 already assigned to A). The only remaining numeral for G is 0, which means F would have to be greater than G, meaning H would have to be either 1 or 4. H has already been assigned 8, rendering that assignment impossible. Continue eliminating possibilities in the order shown below.\n\r\nA) H can not be 8. C can not be 1. C can not be 0. B can not be 9. D can not be 1. D can not be 2. F can not be 1.\r\nB) H must be 1. H can not be 4. H can not be 9.\r\nC) G can not be 0. I can not be 6. I can not be 7. B can not be 0.\r\nD) I must be 0. I can not be 8.\r\nE) J can not be 2. J can not be 5. J can not be 8.\r\nF) J must be 3. A can not be 3. B can not be 3. E can not be 3.\r\nG) B must be 2. F can not be 2.\r\nH) A must be 8. A can not be 4. A can not be 7.\r\nI) D can not be 9.\r\nJ) E must be 9. E can not be 5. E can not be 6.\r\nK) D must be 4. F can not be 4.\r\nL) F must be 6. G can not be 6.\r\nM) G must be 5. C can not be 5. G can not be 5.\r\nN) C must be 7.\n<|im_end|>" }, { "id": "#4770", "title": "Green and Yellow", "fun": 2.11, "difficulty": 1.22, "author": "librashorty", "desc": "If even numbers are green and odd numbers are yellow, what colour is yellow + yellow?", "hint": "No hint available.", "answer": "green", "category": "Math", "date": "06/16/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf even numbers are green and odd numbers are yellow, what colour is yellow + yellow?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\ngreen\n<|im_start|>answer\ngreen\n<|im_end|>" }, { "id": "#34834", "title": "Food Fight Fiasco #1", "fun": 2.1, "difficulty": 2.8, "author": "t4mt", "desc": "You are in a food fight. An enemy is holding a hot sauce and will spray you with the fiery substance unless you answer the following question correctly:\n\r\nA right cylinder, with a diameter congruent to its height is inscribed in a right cone with height 12 units and radius 5 units. If their axes coincide, find the radius of the cylinder.", "hint": "Hint #1: By inscribed, your enemy means that the cylinder's whole bottom face is touching the cone's bottom face, and the cylinder is touching the cone with the circumference of the top face.\n\r\nHint #2: There are many ways to solve this, but a simple method is to imagine one triangle inside another.", "answer": "30/11. As mentioned in the hint, there are many methods in which to solve this. One less complex method is to imagine the axis of the cone form a right triangle. This triangle shares the dimensions of the cone, so it is 12 by 5. We are given that the diameter of the cylinder is congruent to the height, so we can deduce that the radius is half the length of the height. Imagine a radius that intersects the hypotenuse of the triangle discussed above. Let's call it x. Therefore, we get a right triangle with a smaller right triangle inside. Since two of the angles are the same (the top and the right angles), we can say that the two triangles are similar. Since the height of the cylinder is 2x (twice the length of the radius x), the height of the smaller right triangle is 12-2x. Thus, we can set up a proportion: 12/5 = 12-2x/x.\n\r\nNext we can cross-multiply to get 12x=60-10x. If we add 10x on both sides, we get 22x=60, and dividing 22 from both sides yields x=60/22=30/11.", "category": "Math", "date": "01/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are in a food fight. An enemy is holding a hot sauce and will spray you with the fiery substance unless you answer the following question correctly:\n\r\nA right cylinder, with a diameter congruent to its height is inscribed in a right cone with height 12 units and radius 5 units. If their axes coincide, find the radius of the cylinder.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n30/11. As mentioned in the hint, there are many methods in which to solve this. One less complex method is to imagine the axis of the cone form a right triangle. This triangle shares the dimensions of the cone, so it is 12 by 5. We are given that the diameter of the cylinder is congruent to the height, so we can deduce that the radius is half the length of the height. Imagine a radius that intersects the hypotenuse of the triangle discussed above. Let's call it x. Therefore, we get a right triangle with a smaller right triangle inside. Since two of the angles are the same (the top and the right angles), we can say that the two triangles are similar. Since the height of the cylinder is 2x (twice the length of the radius x), the height of the smaller right triangle is 12-2x. Thus, we can set up a proportion: 12/5 = 12-2x/x.\n\r\nNext we can cross-multiply to get 12x=60-10x. If we add 10x on both sides, we get 22x=60, and dividing 22 from both sides yields x=60/22=30/11.\n<|im_start|>answer\n30/11. As mentioned in the hint, there are many methods in which to solve this. One less complex method is to imagine the axis of the cone form a right triangle. This triangle shares the dimensions of the cone, so it is 12 by 5. We are given that the diameter of the cylinder is congruent to the height, so we can deduce that the radius is half the length of the height. Imagine a radius that intersects the hypotenuse of the triangle discussed above. Let's call it x. Therefore, we get a right triangle with a smaller right triangle inside. Since two of the angles are the same (the top and the right angles), we can say that the two triangles are similar. Since the height of the cylinder is 2x (twice the length of the radius x), the height of the smaller right triangle is 12-2x. Thus, we can set up a proportion: 12/5 = 12-2x/x.\n\r\nNext we can cross-multiply to get 12x=60-10x. If we add 10x on both sides, we get 22x=60, and dividing 22 from both sides yields x=60/22=30/11.\n<|im_end|>" }, { "id": "#40225", "title": "What's Your Number?", "fun": 2.1, "difficulty": 2.02, "author": "TRILLIONAIRE", "desc": "Start with a number larger than 0, square it, add 4, double it, take away 3, multiply times 4 and finally subtract the original number. If you were now left with 20, what number did you start with?", "hint": "It's between 0 and 5.", "answer": "1/8", "category": "Math", "date": "01/27/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStart with a number larger than 0, square it, add 4, double it, take away 3, multiply times 4 and finally subtract the original number. If you were now left with 20, what number did you start with?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1/8\n<|im_start|>answer\n1/8\n<|im_end|>" }, { "id": "#45693", "title": "What Does This Represent?", "fun": 2.1, "difficulty": 2.28, "author": "Aaronnp", "desc": "What does the bottom line represent?\n\r\n312831303130313130313031\n\r\n312831303130313130313031\n\r\n312831303130313130313031\n\r\n312931303130313130313031", "hint": "No hint available.", "answer": "A leap year.", "category": "Logic", "date": "11/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat does the bottom line represent?\n\r\n312831303130313130313031\n\r\n312831303130313130313031\n\r\n312831303130313130313031\n\r\n312931303130313130313031\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA leap year.\n<|im_start|>answer\nA leap year.\n<|im_end|>" }, { "id": "#30636", "title": "Food Court", "fun": 2.1, "difficulty": 1.12, "author": "rednek", "desc": "Deborah, Samantha, Eli and Aaron all went to the mall. When they all were hungry, they went to the food court. Their choices were: Chinese, Italian, Mexican, and Southern. However, they all went together to get their food. What food did they order and in what order did they get their food?\n\r\n1. Eli loves sushi.\n\r\n2. Samantha went before Aaron.\n\r\n3. Aaron likes Southern and Mexican, and he went second.\n\r\n4. Deborah loves pinto's and cheese.\n\r\n5. Eli went right after Aaron.\n\r\n6. Samantha went before Deborah, and she loves Chicken Alfredo.", "hint": "No hint available.", "answer": "Deborah-Mexican-Fourth\r\nSamantha-Italian-First\r\nEli-Chinese-Third\r\nAaron-Southern-Second", "category": "Logic-Grid", "date": "05/22/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDeborah, Samantha, Eli and Aaron all went to the mall. When they all were hungry, they went to the food court. Their choices were: Chinese, Italian, Mexican, and Southern. However, they all went together to get their food. What food did they order and in what order did they get their food?\n\r\n1. Eli loves sushi.\n\r\n2. Samantha went before Aaron.\n\r\n3. Aaron likes Southern and Mexican, and he went second.\n\r\n4. Deborah loves pinto's and cheese.\n\r\n5. Eli went right after Aaron.\n\r\n6. Samantha went before Deborah, and she loves Chicken Alfredo.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDeborah-Mexican-Fourth\r\nSamantha-Italian-First\r\nEli-Chinese-Third\r\nAaron-Southern-Second\n<|im_start|>answer\nDeborah-Mexican-Fourth\r\nSamantha-Italian-First\r\nEli-Chinese-Third\r\nAaron-Southern-Second\n<|im_end|>" }, { "id": "#5983", "title": "Card Game", "fun": 2.1, "difficulty": 1.54, "author": "mollynoodl", "desc": "My favorite card game was invented a while back. It was invented a year after my father was born, and a year before my mother was born. My oldest parent's age is more than 20+19, but less than 82/2. When was this game invented?", "hint": "/ means \"divided by\" on a calculator.", "answer": "39 years ago.\n\r\nIf the oldest parent is between 39 and 41, then he/she is 40. If the game was invented one year after the oldest parent (the dad), then it was 39 years ago (40-1).", "category": "Math", "date": "07/28/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy favorite card game was invented a while back. It was invented a year after my father was born, and a year before my mother was born. My oldest parent's age is more than 20+19, but less than 82/2. When was this game invented?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n39 years ago.\n\r\nIf the oldest parent is between 39 and 41, then he/she is 40. If the game was invented one year after the oldest parent (the dad), then it was 39 years ago (40-1).\n<|im_start|>answer\n39 years ago.\n\r\nIf the oldest parent is between 39 and 41, then he/she is 40. If the game was invented one year after the oldest parent (the dad), then it was 39 years ago (40-1).\n<|im_end|>" }, { "id": "#879", "title": "A Time Teaser", "fun": 2.1, "difficulty": 2.1, "author": "Michelle", "desc": "Between two and three o'clock, someone looked at the clock and mistook the minute hand for the hour hand. Consequently the time appeared to be fifty-five minutes earlier than it actually was. What time was it?", "hint": "There is a fraction involved in the precise answer, however this is not a mathematics test. If you get the answer within the nearest minute or so, consider your answer correct.", "answer": "The time must have been precisely 5 and 5/11 minutes past two o'clock. If you got 5 minutes or 5 and a half minutes after two, consider yourself correct.", "category": "Math", "date": "09/26/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBetween two and three o'clock, someone looked at the clock and mistook the minute hand for the hour hand. Consequently the time appeared to be fifty-five minutes earlier than it actually was. What time was it?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe time must have been precisely 5 and 5/11 minutes past two o'clock. If you got 5 minutes or 5 and a half minutes after two, consider yourself correct.\n<|im_start|>answer\nThe time must have been precisely 5 and 5/11 minutes past two o'clock. If you got 5 minutes or 5 and a half minutes after two, consider yourself correct.\n<|im_end|>" }, { "id": "#23492", "title": "That's Odd", "fun": 2.1, "difficulty": 2.34, "author": "Kerplunk82", "desc": "I'm thinking of an odd whole number between 2 and 300. Add 73 to the number and then divide by two. That result plus the lowest possible number will equal four times the difference between the number and the highest possible number. What is the number?", "hint": "Use straightforward algebra.", "answer": "257", "category": "Math", "date": "06/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI'm thinking of an odd whole number between 2 and 300. Add 73 to the number and then divide by two. That result plus the lowest possible number will equal four times the difference between the number and the highest possible number. What is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n257\n<|im_start|>answer\n257\n<|im_end|>" }, { "id": "#48672", "title": "Symbolism II", "fun": 2.1, "difficulty": 2.65, "author": "Mathgeek007", "desc": "I give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nAlso, do not follow the order of operations, perform in the order of the numbers (ie: 3+3*3 normally equals 12, but not following the order of operations, equals 18.)\n\r\nNow, for your puzzle.\r\n5463186333\r\n+--*=", "hint": "Each side equals 99.", "answer": "54+63-18=6-3*33", "category": "Math", "date": "04/28/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nAlso, do not follow the order of operations, perform in the order of the numbers (ie: 3+3*3 normally equals 12, but not following the order of operations, equals 18.)\n\r\nNow, for your puzzle.\r\n5463186333\r\n+--*=\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n54+63-18=6-3*33\n<|im_start|>answer\n54+63-18=6-3*33\n<|im_end|>" }, { "id": "#39227", "title": "Bishops Amok", "fun": 2.1, "difficulty": 2.63, "author": "Hrsemn4", "desc": "One variation of the famous \"Eight Queens Puzzle\" is the \"Bishop Puzzle\". \n\r\nWe know that you can place up to 8 queens on a chessboard with no other pieces in such a fashion that no queen can be taken. We also know that you can place 32 knights on the board in such a fashion that none can be taken. \n\r\nDo you know how many bishops you can place on a standard 8x8 chessboard so that no piece can be taken? What is their placement?", "hint": "No hint available.", "answer": "Fourteen bishops can be placed on the board.\n\r\nThere are a number of solutions for this problem, but the simplest is the following placement.\r\n1) b8\r\n2) c8\r\n3) d8\r\n4) e8\r\n5) f8\r\n6) g8\r\n7) a1\r\n8) b1\r\n9) c1\r\n10) d1\r\n11) e1\r\n12) f1\r\n13) g1\r\n14) h1", "category": "Logic", "date": "11/16/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne variation of the famous \"Eight Queens Puzzle\" is the \"Bishop Puzzle\". \n\r\nWe know that you can place up to 8 queens on a chessboard with no other pieces in such a fashion that no queen can be taken. We also know that you can place 32 knights on the board in such a fashion that none can be taken. \n\r\nDo you know how many bishops you can place on a standard 8x8 chessboard so that no piece can be taken? What is their placement?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFourteen bishops can be placed on the board.\n\r\nThere are a number of solutions for this problem, but the simplest is the following placement.\r\n1) b8\r\n2) c8\r\n3) d8\r\n4) e8\r\n5) f8\r\n6) g8\r\n7) a1\r\n8) b1\r\n9) c1\r\n10) d1\r\n11) e1\r\n12) f1\r\n13) g1\r\n14) h1\n<|im_start|>answer\nFourteen bishops can be placed on the board.\n\r\nThere are a number of solutions for this problem, but the simplest is the following placement.\r\n1) b8\r\n2) c8\r\n3) d8\r\n4) e8\r\n5) f8\r\n6) g8\r\n7) a1\r\n8) b1\r\n9) c1\r\n10) d1\r\n11) e1\r\n12) f1\r\n13) g1\r\n14) h1\n<|im_end|>" }, { "id": "#41688", "title": "Water and Ice", "fun": 2.1, "difficulty": 2.23, "author": "shenqiang", "desc": "When water changes into ice, the volume increases by one ninth. Consider a 20 cm-tall cylindrical beaker, full of ice. On top of the beaker, there is a cone of ice of the same diameter and 5 cm-tall. When all the ice melts into water, what is the height of the water in the beaker?", "hint": "Is the cylinder enough to hold all the water?", "answer": "When water changes into ice, the volume increases by one ninth. This means that the ratio of the volumes of water and ice is 9:10.\n\r\nA 5 cm-tall cone of ice is as large as a 5/3 cm-tall cylinder, which makes a total of 20+5/3=65/3 cm of ice, and will yield 65/3*9/10=19.5 cm of water. Because 19.5<20, the cylinder itself can hold all the water, and the cone is emptied. Therefore, the height of water is 19.5 cm.", "category": "Math", "date": "04/26/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen water changes into ice, the volume increases by one ninth. Consider a 20 cm-tall cylindrical beaker, full of ice. On top of the beaker, there is a cone of ice of the same diameter and 5 cm-tall. When all the ice melts into water, what is the height of the water in the beaker?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nWhen water changes into ice, the volume increases by one ninth. This means that the ratio of the volumes of water and ice is 9:10.\n\r\nA 5 cm-tall cone of ice is as large as a 5/3 cm-tall cylinder, which makes a total of 20+5/3=65/3 cm of ice, and will yield 65/3*9/10=19.5 cm of water. Because 19.5<20, the cylinder itself can hold all the water, and the cone is emptied. Therefore, the height of water is 19.5 cm.\n<|im_start|>answer\nWhen water changes into ice, the volume increases by one ninth. This means that the ratio of the volumes of water and ice is 9:10.\n\r\nA 5 cm-tall cone of ice is as large as a 5/3 cm-tall cylinder, which makes a total of 20+5/3=65/3 cm of ice, and will yield 65/3*9/10=19.5 cm of water. Because 19.5<20, the cylinder itself can hold all the water, and the cone is emptied. Therefore, the height of water is 19.5 cm.\n<|im_end|>" }, { "id": "#7465", "title": "10%", "fun": 2.1, "difficulty": 1.49, "author": "timmyboym", "desc": "Solve the following equation:\r\n10% of 10% of (10/10-10)", "hint": "Don't think positive.", "answer": "-0.09", "category": "Math", "date": "09/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSolve the following equation:\r\n10% of 10% of (10/10-10)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-0.09\n<|im_start|>answer\n-0.09\n<|im_end|>" }, { "id": "#4585", "title": "Gulp!", "fun": 2.1, "difficulty": 1.94, "author": "Mogmatt16", "desc": "There is a club of 50 superstitious people. At their last meeting, 14 people got inducted, now for a total of 64. The leader proposed a toast to the new members. Assuming there is 500ml of their choice beverage in each glass, how much was drunk at the toast?", "hint": "They are superstitious.", "answer": "25000ml. If you said 32000ml, you forgot, they are superstitious and it is supposedly bad luck to drink to your own toast.", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a club of 50 superstitious people. At their last meeting, 14 people got inducted, now for a total of 64. The leader proposed a toast to the new members. Assuming there is 500ml of their choice beverage in each glass, how much was drunk at the toast?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n25000ml. If you said 32000ml, you forgot, they are superstitious and it is supposedly bad luck to drink to your own toast.\n<|im_start|>answer\n25000ml. If you said 32000ml, you forgot, they are superstitious and it is supposedly bad luck to drink to your own toast.\n<|im_end|>" }, { "id": "#38817", "title": "The Football Fans", "fun": 2.1, "difficulty": 2.46, "author": "Trickster1992", "desc": "Thirty fans hire a bus to attend a football game. On the way to the stadium, they realize that exactly half of them are fans of one team and the other half are fans of the other team. With still some way to go before reaching the stadium, the bus develops mechanical problems and the driver announces to his passengers that the only way to continue the journey is for half of them to get out and walk. There is a huge fight that doesn't stop until the driver speaks to them again and suggests a way of selecting the passengers who are to get off the bus.\n\r\n\"All of you,\" he said, \"get into a big circle. When you are ready, beginning at this spot, I'll count nine people clockwise. The ninth person leaves the circle and continues on foot. Then I'll count another nine starting from where I stopped, and the ninth person leaves the circle and continues on foot. And so on until fifteen people have left the circle.\"\n\r\nSuppose that you are one of the fans. How should you arrange all the other fans of your team so that none of them will have to leave?", "hint": "No hint available.", "answer": "If the two teams are A and B and you are a supporter of team A and don't want any of your fellow supporters to end up walking to the stadium, organize them in a circle starting at the point where the driver starts and reading clockwise as follows: A, A, A, A, B, B, B, B, B, A, A, B, A, A, A, B, A, B, B, A, A, B, B, B, A, B, B, A, A, B.", "category": "Logic", "date": "10/17/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThirty fans hire a bus to attend a football game. On the way to the stadium, they realize that exactly half of them are fans of one team and the other half are fans of the other team. With still some way to go before reaching the stadium, the bus develops mechanical problems and the driver announces to his passengers that the only way to continue the journey is for half of them to get out and walk. There is a huge fight that doesn't stop until the driver speaks to them again and suggests a way of selecting the passengers who are to get off the bus.\n\r\n\"All of you,\" he said, \"get into a big circle. When you are ready, beginning at this spot, I'll count nine people clockwise. The ninth person leaves the circle and continues on foot. Then I'll count another nine starting from where I stopped, and the ninth person leaves the circle and continues on foot. And so on until fifteen people have left the circle.\"\n\r\nSuppose that you are one of the fans. How should you arrange all the other fans of your team so that none of them will have to leave?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf the two teams are A and B and you are a supporter of team A and don't want any of your fellow supporters to end up walking to the stadium, organize them in a circle starting at the point where the driver starts and reading clockwise as follows: A, A, A, A, B, B, B, B, B, A, A, B, A, A, A, B, A, B, B, A, A, B, B, B, A, B, B, A, A, B.\n<|im_start|>answer\nIf the two teams are A and B and you are a supporter of team A and don't want any of your fellow supporters to end up walking to the stadium, organize them in a circle starting at the point where the driver starts and reading clockwise as follows: A, A, A, A, B, B, B, B, B, A, A, B, A, A, A, B, A, B, B, A, A, B, B, B, A, B, B, A, A, B.\n<|im_end|>" }, { "id": "#10833", "title": "Madadian Subway", "fun": 2.1, "difficulty": 2.02, "author": "mad-ade", "desc": "Madadia is served by 6 subway lines - A, E, I, O, U and Z.\n\r\nWhen it snows, morning service on line E is delayed. \n\r\nWhen it rains or snows, service on the lines A, U and Z is delayed both morning and afternoon. \n\r\nWhen the temperature drops below 20 C, afternoon service is cancelled on either line A or line O, but not both. \n\r\nWhen the temperature rises above 40 C, afternoon service is cancelled on either line I or line Z, but not both. \n\r\nWhen service on line A is delayed or cancelled, service on line I is also delayed. \n\r\nWhen service on line Z is delayed or cancelled, service on line E is also delayed.\r\nOn February 10, it snows all day with the temperature at 18C. On how many lines service will be delayed or cancelled, including both morning and afternoon?", "hint": "No hint available.", "answer": "The service will be delayed or cancelled on 5 lines - A, E, I, U and Z except line O. \n\r\nGo through each statement and cross the subway line with delayed or cancelled service. \n\r\nIt is given that it snows all day with the temperature at 18C. \r\nFrom (1), line E is delayed. \r\nFrom (2), line A, U and Z are delayed. \r\nFrom (3), either line A or line O is cancelled. \r\nFrom (5), line I is delayed because of line A delay. \r\nFrom (6), line E is delayed because of line Z delay. \n\r\nAs service on line A is delayed, service on line O can not be. Hence, service will be delayed or cancelled on 5 lines - A, E, I, U and Z except line O.", "category": "Logic", "date": "03/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMadadia is served by 6 subway lines - A, E, I, O, U and Z.\n\r\nWhen it snows, morning service on line E is delayed. \n\r\nWhen it rains or snows, service on the lines A, U and Z is delayed both morning and afternoon. \n\r\nWhen the temperature drops below 20 C, afternoon service is cancelled on either line A or line O, but not both. \n\r\nWhen the temperature rises above 40 C, afternoon service is cancelled on either line I or line Z, but not both. \n\r\nWhen service on line A is delayed or cancelled, service on line I is also delayed. \n\r\nWhen service on line Z is delayed or cancelled, service on line E is also delayed.\r\nOn February 10, it snows all day with the temperature at 18C. On how many lines service will be delayed or cancelled, including both morning and afternoon?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe service will be delayed or cancelled on 5 lines - A, E, I, U and Z except line O. \n\r\nGo through each statement and cross the subway line with delayed or cancelled service. \n\r\nIt is given that it snows all day with the temperature at 18C. \r\nFrom (1), line E is delayed. \r\nFrom (2), line A, U and Z are delayed. \r\nFrom (3), either line A or line O is cancelled. \r\nFrom (5), line I is delayed because of line A delay. \r\nFrom (6), line E is delayed because of line Z delay. \n\r\nAs service on line A is delayed, service on line O can not be. Hence, service will be delayed or cancelled on 5 lines - A, E, I, U and Z except line O.\n<|im_start|>answer\nThe service will be delayed or cancelled on 5 lines - A, E, I, U and Z except line O. \n\r\nGo through each statement and cross the subway line with delayed or cancelled service. \n\r\nIt is given that it snows all day with the temperature at 18C. \r\nFrom (1), line E is delayed. \r\nFrom (2), line A, U and Z are delayed. \r\nFrom (3), either line A or line O is cancelled. \r\nFrom (5), line I is delayed because of line A delay. \r\nFrom (6), line E is delayed because of line Z delay. \n\r\nAs service on line A is delayed, service on line O can not be. Hence, service will be delayed or cancelled on 5 lines - A, E, I, U and Z except line O.\n<|im_end|>" }, { "id": "#10172", "title": "Madadian Holiday", "fun": 2.1, "difficulty": 2.24, "author": "Mad-ade", "desc": "A group of workers from the Madadian Kebab Recycling Factory went on a holiday to the sun soaked coast of Madadia. It rained for 13 days. But when it rained in the morning, the afternoon was lovely. And when it rained in the afternoon, the day was preceded by clear morning. \n\r\nAltogether there were 11 very nice mornings and 12 very nice afternoons. How many days did their holiday last?", "hint": "No hint available.", "answer": "The holiday lasted for 18 days. \n\r\nLet's assume the number of days as follows: \r\nRain in the morning and lovely afternoon = X days \r\nClear morning and rain in the afternoon = Y days \r\nNo rain in the morning and in the afternoon = Z days \n\r\nNumber of days with rain = X + Y = 13 days \r\nNumber of days with clear mornings = Y + Z = 11 days \r\nNumber of days with clear afternoons = X + Z = 12 days \n\r\nSolving above 3 equations, we get X = 7, Y = 6 and Z = 5 \n\r\nHence, total number of days on holiday = 18 days.", "category": "Math", "date": "02/01/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA group of workers from the Madadian Kebab Recycling Factory went on a holiday to the sun soaked coast of Madadia. It rained for 13 days. But when it rained in the morning, the afternoon was lovely. And when it rained in the afternoon, the day was preceded by clear morning. \n\r\nAltogether there were 11 very nice mornings and 12 very nice afternoons. How many days did their holiday last?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe holiday lasted for 18 days. \n\r\nLet's assume the number of days as follows: \r\nRain in the morning and lovely afternoon = X days \r\nClear morning and rain in the afternoon = Y days \r\nNo rain in the morning and in the afternoon = Z days \n\r\nNumber of days with rain = X + Y = 13 days \r\nNumber of days with clear mornings = Y + Z = 11 days \r\nNumber of days with clear afternoons = X + Z = 12 days \n\r\nSolving above 3 equations, we get X = 7, Y = 6 and Z = 5 \n\r\nHence, total number of days on holiday = 18 days.\n<|im_start|>answer\nThe holiday lasted for 18 days. \n\r\nLet's assume the number of days as follows: \r\nRain in the morning and lovely afternoon = X days \r\nClear morning and rain in the afternoon = Y days \r\nNo rain in the morning and in the afternoon = Z days \n\r\nNumber of days with rain = X + Y = 13 days \r\nNumber of days with clear mornings = Y + Z = 11 days \r\nNumber of days with clear afternoons = X + Z = 12 days \n\r\nSolving above 3 equations, we get X = 7, Y = 6 and Z = 5 \n\r\nHence, total number of days on holiday = 18 days.\n<|im_end|>" }, { "id": "#3143", "title": "Breaking Curfew", "fun": 2.1, "difficulty": 1.85, "author": "204_blaze_41", "desc": "The coach of the college baseball team, Mike Buck, was checking the residence grounds to be certain his players were in by curfew. Suddenly, he heard a loud crash and turned to catch a glimpse of a man running into the residence. Buck thought it was his star right-handed pitcher, James Macullah, but he couldn't be sure. Buck went to James' room and opened the door. James stood in the middle of the room, his right leg in his pants and his left leg out. James, looking at the wristwatch on his left arm said, \"I heard a loud crash and was getting dressed to see what happened\", he stammered. \"Forget the bull,\" said Buck, \"I'm certain it was you who just ran in here. For that little caper, you won't be playing tomorrow.\" How could Buck be so certain it was James who had been out after curfew?", "hint": "No hint available.", "answer": "Mike was certain it was James because he was getting undressed not dressed as he claimed. A right-handed person will put their left leg in their pants when dressing.", "category": "Logic", "date": "04/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe coach of the college baseball team, Mike Buck, was checking the residence grounds to be certain his players were in by curfew. Suddenly, he heard a loud crash and turned to catch a glimpse of a man running into the residence. Buck thought it was his star right-handed pitcher, James Macullah, but he couldn't be sure. Buck went to James' room and opened the door. James stood in the middle of the room, his right leg in his pants and his left leg out. James, looking at the wristwatch on his left arm said, \"I heard a loud crash and was getting dressed to see what happened\", he stammered. \"Forget the bull,\" said Buck, \"I'm certain it was you who just ran in here. For that little caper, you won't be playing tomorrow.\" How could Buck be so certain it was James who had been out after curfew?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike was certain it was James because he was getting undressed not dressed as he claimed. A right-handed person will put their left leg in their pants when dressing.\n<|im_start|>answer\nMike was certain it was James because he was getting undressed not dressed as he claimed. A right-handed person will put their left leg in their pants when dressing.\n<|im_end|>" }, { "id": "#9997", "title": "Guess the Number", "fun": 2.1, "difficulty": 2.04, "author": "jokester8000", "desc": "Guess the five-digit number using the following clues.\n\r\n1. The second digit is a multiple of the first digit.\r\n2. The third digit is the product of the first two digits.\r\n3. All but one digit are even.\r\n4. Either the first and second or the second and the third are the same digit.\r\n5. The fifth digit is equal to the square of the second digit.\r\n6. Divide the fourth digit by 2 and you will get the fifth digit.", "hint": "for number 2 no answers go over nine", "answer": "12284", "category": "Math", "date": "01/23/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nGuess the five-digit number using the following clues.\n\r\n1. The second digit is a multiple of the first digit.\r\n2. The third digit is the product of the first two digits.\r\n3. All but one digit are even.\r\n4. Either the first and second or the second and the third are the same digit.\r\n5. The fifth digit is equal to the square of the second digit.\r\n6. Divide the fourth digit by 2 and you will get the fifth digit.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12284\n<|im_start|>answer\n12284\n<|im_end|>" }, { "id": "#35629", "title": "Be Quiet Children!", "fun": 2.1, "difficulty": 2.94, "author": "t4mt", "desc": "One day, a frustrated math teacher lost his patience with his students' non-stop chatting. Thus, he decided to give the ultimate hard problem:\n\r\nFind the only positive integer number less than 20,000 that is also a sum of three positive integers, all containing exactly 7 factors. \n\r\nThere was a steady silence. Can you break the silence by figuring it out?", "hint": "For the prime factorization of positive integer x, we get\r\nx=[y(sub 1)^K (sub 1)][y(sub 2)^ K (sub 2)]..., where y sub(n) is a prime number, and K sub(n) is the power to which y sub(n) is raised, we can figure out the number of prime factors by:\r\n[K(sub 1) + 1][K(sub 2) + 1]...\n\r\nFor example, the prime factorization of 228 is (2^2)(3^1)(19^1). 228 has 12 factors, since (2+1)(1+1)(1+1) = 12.", "answer": "16,418. \r\nFirst, you need to figure out the separate integers. If you have read the hint, you would know how to use prime factorization to your advantage. The only way to get 7 as the number of factors is 1 x 7. So the prime factorization of any number with 7 factors is n^6 times x^0, where n and x are both primes. But if you look, x^0, for all nonzero values of x, is 1! So, any number with exactly 7 factors must be a prime raised to the sixth power. This yields 2^6 +3^6+5^6 = 16418. Any prime 7 or greater to the sixth power is greater than 20,000.", "category": "Math", "date": "03/09/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, a frustrated math teacher lost his patience with his students' non-stop chatting. Thus, he decided to give the ultimate hard problem:\n\r\nFind the only positive integer number less than 20,000 that is also a sum of three positive integers, all containing exactly 7 factors. \n\r\nThere was a steady silence. Can you break the silence by figuring it out?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n16,418. \r\nFirst, you need to figure out the separate integers. If you have read the hint, you would know how to use prime factorization to your advantage. The only way to get 7 as the number of factors is 1 x 7. So the prime factorization of any number with 7 factors is n^6 times x^0, where n and x are both primes. But if you look, x^0, for all nonzero values of x, is 1! So, any number with exactly 7 factors must be a prime raised to the sixth power. This yields 2^6 +3^6+5^6 = 16418. Any prime 7 or greater to the sixth power is greater than 20,000.\n<|im_start|>answer\n16,418. \r\nFirst, you need to figure out the separate integers. If you have read the hint, you would know how to use prime factorization to your advantage. The only way to get 7 as the number of factors is 1 x 7. So the prime factorization of any number with 7 factors is n^6 times x^0, where n and x are both primes. But if you look, x^0, for all nonzero values of x, is 1! So, any number with exactly 7 factors must be a prime raised to the sixth power. This yields 2^6 +3^6+5^6 = 16418. Any prime 7 or greater to the sixth power is greater than 20,000.\n<|im_end|>" }, { "id": "#49098", "title": "Restaurant", "fun": 2.1, "difficulty": 0.5, "author": "wolvesstar97", "desc": "Ricardo, Steve, and Will went to a restaurant. They each ordered different dishes, and when they left, they each took a different flavor of mint. The dishes that they ordered were Chicken Soup, Greek Salad, and Steak. The types of mints available were Classic, Lemon, and Menthol. \n\r\nCLUES:\n\r\nRicardo did not order the steak.\r\nThe person that ordered the salad didn't have menthol.\r\nSteve (who did not have the classic mint) did not order the salad.\r\nWill ordered the soup.\r\nWill did not have the lemon mint.\r\nSteve did not have the menthol.\r\nThe person who ordered the soup did not have a classic mint.", "hint": "No hint available.", "answer": "Ricardo had the salad and the classic mint. \r\nSteve had the steak and took a lemon mint.\r\nWill had the soup and had a menthol mint.", "category": "Logic-Grid", "date": "10/21/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRicardo, Steve, and Will went to a restaurant. They each ordered different dishes, and when they left, they each took a different flavor of mint. The dishes that they ordered were Chicken Soup, Greek Salad, and Steak. The types of mints available were Classic, Lemon, and Menthol. \n\r\nCLUES:\n\r\nRicardo did not order the steak.\r\nThe person that ordered the salad didn't have menthol.\r\nSteve (who did not have the classic mint) did not order the salad.\r\nWill ordered the soup.\r\nWill did not have the lemon mint.\r\nSteve did not have the menthol.\r\nThe person who ordered the soup did not have a classic mint.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRicardo had the salad and the classic mint. \r\nSteve had the steak and took a lemon mint.\r\nWill had the soup and had a menthol mint.\n<|im_start|>answer\nRicardo had the salad and the classic mint. \r\nSteve had the steak and took a lemon mint.\r\nWill had the soup and had a menthol mint.\n<|im_end|>" }, { "id": "#29117", "title": "Tinman's Finals", "fun": 2.1, "difficulty": 1.39, "author": "metallicman", "desc": "Tinman had seven finals split between tomorrow and the day after tomorrow. They have been put in a certain order on each day. Figure out the order from these clues:\n\r\nFirst day: Final 1 _____ Final 5 _____ \n\r\nSecond day: Final 2 _____ Final 6", "hint": "No hint available.", "answer": "First day: Final 1, Final 3, Final 5, Final 7\r\nSecond day: Final 2, Final 4, Final 6\n\r\nThe finals were put in odd/even order.", "category": "Logic", "date": "03/15/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTinman had seven finals split between tomorrow and the day after tomorrow. They have been put in a certain order on each day. Figure out the order from these clues:\n\r\nFirst day: Final 1 _____ Final 5 _____ \n\r\nSecond day: Final 2 _____ Final 6\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFirst day: Final 1, Final 3, Final 5, Final 7\r\nSecond day: Final 2, Final 4, Final 6\n\r\nThe finals were put in odd/even order.\n<|im_start|>answer\nFirst day: Final 1, Final 3, Final 5, Final 7\r\nSecond day: Final 2, Final 4, Final 6\n\r\nThe finals were put in odd/even order.\n<|im_end|>" }, { "id": "#10150", "title": "Mathematicians", "fun": 2.1, "difficulty": 3.14, "author": "rajeshwar", "desc": "There are 4 mathematicians - Brahma, Sachin, Prashant and Nakul - having lunch in a hotel. Suddenly, Brahma thinks of 2 integer numbers greater than 1 and says, \"The sum of the numbers is...\" and he whispers the sum to Sachin. Then he says, \"The product of the numbers is...\" and he whispers the product to Prashant. After that, the following conversation takes place : \n\r\nSachin : Prashant, I don't think that we know the numbers. \r\nPrashant : Aha! Now I know the numbers. \r\nSachin : Oh, now I also know the numbers. \r\nNakul : Now I also know the numbers. \n\r\nHow did they know the numbers?", "hint": "No hint available.", "answer": "The numbers are 4 and 13. \n\r\nAs Sachin is initially confident that they (i.e. he and Prashant) don't know the numbers, we can conclude that - \r\n1) The sum must not be expressible as sum of two primes, otherwise Sachin could not have been sure in advance that Prashant did not know the numbers. \r\n2) The product cannot be less than 12, otherwise there would only be one choice and Prashant would have figured that out also. \n\r\nSuch possible sum are - 11, 17, 23, 27, 29, 35, 37, 41, 47, 51, 53, 57, 59, 65, 67, 71, 77, 79, 83, 87, 89, 93, 95, 97, 101, 107, 113, 117, 119, 121, 123, 125, 127, 131, 135, 137, 143, 145, 147, 149, 155, 157, 161, 163, 167, 171, 173, 177, 179, 185, 187, 189, 191, 197, .... \n\r\nLet's examine them one by one. \n\r\nIf the sum of two numbers is 11, Sachin will think that the numbers would be (2,9), (3,8 ), (4,7) or (5,6). \n\r\nSachin : \"As 11 is not expressible as sum of two primes, Prashant can't know the numbers.\" \n\r\nHere, the product would be 18(2*9), 24(3*8 ), 28(4*7) or 30(5*6). In all the cases except for product 30, Prashant would know the numbers. \n\r\n- if product of two numbers is 18: \r\nPrashant : \"Since the product is 18, the sum could be either 11(2,9) or 9(3,6). But if the sum was 9, Sachin would have deduced that I might know the numbers as (2,7) is the possible prime numbers pair. Hence, the numbers must be 2 and 9.\" (OR in other words, 9 is not in the Possible Sum List).\n\r\n- if product of two numbers is 24: \r\nPrashant : \"Since the product is 24, the sum could be either 14(2,12), 11(3,8 ) or 10(4,6). But 14 and 10 are not in the Possible Sum List. Hence, the numbers must be 3 and 8.\" \n\r\n- if product of two numbers is 28: \r\nPrashant : \"Since the product is 28, the sum could be either 16(2,14) or 11(4,7). But 16 is not in the Possible Sum List. Hence, the numbers must be 4 and 7.\" \n\r\n- if product of two numbers is 30: \r\nPrashant : \"Since the product is 30, the sum could be either 17(2,15), 13(3,10) or 11(5,6). But 13 is not in the Possible Sum List. Hence, the numbers must be either (2,15) or (5,6).\" Here, Prashant won't be sure of the numbers. \n\r\nHence, Prashant will be sure of the numbers if the product is either 18, 24 or 28. \n\r\nSachin : \"Since Prashant knows the numbers, they must be either (3,8 ), (4,7) or (5,6).\" But he won't be sure. Hence, the sum is not 11. \n\r\nSummerising data for sum 11: \r\nPossible Sum PRODUCT Possible Sum \r\n2+9 18 2+9=11 (possible) \r\n3+6=9 \r\n3+8 24 2+12=14 \r\n3+8=11 (possible) \r\n4+6=10 \r\n4+7 28 2+12=14 \r\n3+8=11 (possible) \r\n4+6=10 \r\n5+6 30 2+15=17 (possible) \r\n3+10=13 \r\n5+6=11 (possible) \n\n\r\nFollowing the same procedure for 17: \r\nPossible Sum PRODUCT Possible Sum \r\n2+15 30 2+15=17 (possible) \r\n3+10= 13 \r\n5+6=11 (possible) \r\n3+14 42 2+21=23 (possible) \r\n3+14=17 (possible) \r\n6+7=13 \r\n4+13 52 2+26=28 \r\n4+13=17 (possible) \r\n5+12 60 2+30=32 \r\n3+20=23 (possible) \r\n4+15=19 \r\n5+12=17 (possible) \r\n6+10=16 \r\n6+11 66 2+33=35 (possible) \r\n3+22=25 \r\n6+11=17 (possible) \n\r\n7+10 70 2+35=37 (possible) \r\n5+14=19 \r\n7+10=17 (possible) \r\n8+9 72 2+36=38 \r\n3+24=27 (possible) \r\n4+18=22 \r\n6+12=18 \r\n8+9=17 (possible) \n\n\r\nHere, Prashant will be sure of the numbers if the product is 52. \n\r\nSachin : \"Since Prashant knows the numbers, they must be (4,13).\" \n\r\nFor all other numbers in the Possible Sum List, Prashant might be sure of the numbers, but Sachin won't. \n\n\r\nHere is the step by step explanation: \n\r\nSachin : \"As the sum is 17, two numbers can be either (2,15), (3,14), (4,13), (5,12), (6,11), (7,10) or (8,9). Also, as none of them is a prime numbers pair, Prashant won't be knowing numbers either.\" \n\r\nPrashant : \"Since Sachin is sure that both of us don't know the numbers, the sum must be one of the Possible Sum List. Further, as the product is 52, two numbers can be either (2,26) or (4,13). But if they were (2,26), Sachin would not have been sure in advance that I don't know the numbers as 28 (2+26) is not in the Possible Sum List. Hence, the two numbers are 4 and 13.\" \n\r\nSachin : \"As Prashant now knows both the numbers, out of all possible products - 30(2,15), 42(3,14), 52(4,13), 60(5,12), 66(6,11), 70(7,10), 72(8,9) - there is one product for which list of all possible sum contains ONLY ONE sum from the Possible Sum List. And also, no such two lists exist. [see table above for 17] Hence, two numbers are 4 and 13.\" \n\r\nNakul figured out both the numbers just as we did by observing the conversation between Sachin and Prashant. \n\r\nIt is interesting to note that there are no other such two numbers. We checked all the possible sums till 500!!!", "category": "Math", "date": "01/31/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 4 mathematicians - Brahma, Sachin, Prashant and Nakul - having lunch in a hotel. Suddenly, Brahma thinks of 2 integer numbers greater than 1 and says, \"The sum of the numbers is...\" and he whispers the sum to Sachin. Then he says, \"The product of the numbers is...\" and he whispers the product to Prashant. After that, the following conversation takes place : \n\r\nSachin : Prashant, I don't think that we know the numbers. \r\nPrashant : Aha! Now I know the numbers. \r\nSachin : Oh, now I also know the numbers. \r\nNakul : Now I also know the numbers. \n\r\nHow did they know the numbers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers are 4 and 13. \n\r\nAs Sachin is initially confident that they (i.e. he and Prashant) don't know the numbers, we can conclude that - \r\n1) The sum must not be expressible as sum of two primes, otherwise Sachin could not have been sure in advance that Prashant did not know the numbers. \r\n2) The product cannot be less than 12, otherwise there would only be one choice and Prashant would have figured that out also. \n\r\nSuch possible sum are - 11, 17, 23, 27, 29, 35, 37, 41, 47, 51, 53, 57, 59, 65, 67, 71, 77, 79, 83, 87, 89, 93, 95, 97, 101, 107, 113, 117, 119, 121, 123, 125, 127, 131, 135, 137, 143, 145, 147, 149, 155, 157, 161, 163, 167, 171, 173, 177, 179, 185, 187, 189, 191, 197, .... \n\r\nLet's examine them one by one. \n\r\nIf the sum of two numbers is 11, Sachin will think that the numbers would be (2,9), (3,8 ), (4,7) or (5,6). \n\r\nSachin : \"As 11 is not expressible as sum of two primes, Prashant can't know the numbers.\" \n\r\nHere, the product would be 18(2*9), 24(3*8 ), 28(4*7) or 30(5*6). In all the cases except for product 30, Prashant would know the numbers. \n\r\n- if product of two numbers is 18: \r\nPrashant : \"Since the product is 18, the sum could be either 11(2,9) or 9(3,6). But if the sum was 9, Sachin would have deduced that I might know the numbers as (2,7) is the possible prime numbers pair. Hence, the numbers must be 2 and 9.\" (OR in other words, 9 is not in the Possible Sum List).\n\r\n- if product of two numbers is 24: \r\nPrashant : \"Since the product is 24, the sum could be either 14(2,12), 11(3,8 ) or 10(4,6). But 14 and 10 are not in the Possible Sum List. Hence, the numbers must be 3 and 8.\" \n\r\n- if product of two numbers is 28: \r\nPrashant : \"Since the product is 28, the sum could be either 16(2,14) or 11(4,7). But 16 is not in the Possible Sum List. Hence, the numbers must be 4 and 7.\" \n\r\n- if product of two numbers is 30: \r\nPrashant : \"Since the product is 30, the sum could be either 17(2,15), 13(3,10) or 11(5,6). But 13 is not in the Possible Sum List. Hence, the numbers must be either (2,15) or (5,6).\" Here, Prashant won't be sure of the numbers. \n\r\nHence, Prashant will be sure of the numbers if the product is either 18, 24 or 28. \n\r\nSachin : \"Since Prashant knows the numbers, they must be either (3,8 ), (4,7) or (5,6).\" But he won't be sure. Hence, the sum is not 11. \n\r\nSummerising data for sum 11: \r\nPossible Sum PRODUCT Possible Sum \r\n2+9 18 2+9=11 (possible) \r\n3+6=9 \r\n3+8 24 2+12=14 \r\n3+8=11 (possible) \r\n4+6=10 \r\n4+7 28 2+12=14 \r\n3+8=11 (possible) \r\n4+6=10 \r\n5+6 30 2+15=17 (possible) \r\n3+10=13 \r\n5+6=11 (possible) \n\n\r\nFollowing the same procedure for 17: \r\nPossible Sum PRODUCT Possible Sum \r\n2+15 30 2+15=17 (possible) \r\n3+10= 13 \r\n5+6=11 (possible) \r\n3+14 42 2+21=23 (possible) \r\n3+14=17 (possible) \r\n6+7=13 \r\n4+13 52 2+26=28 \r\n4+13=17 (possible) \r\n5+12 60 2+30=32 \r\n3+20=23 (possible) \r\n4+15=19 \r\n5+12=17 (possible) \r\n6+10=16 \r\n6+11 66 2+33=35 (possible) \r\n3+22=25 \r\n6+11=17 (possible) \n\r\n7+10 70 2+35=37 (possible) \r\n5+14=19 \r\n7+10=17 (possible) \r\n8+9 72 2+36=38 \r\n3+24=27 (possible) \r\n4+18=22 \r\n6+12=18 \r\n8+9=17 (possible) \n\n\r\nHere, Prashant will be sure of the numbers if the product is 52. \n\r\nSachin : \"Since Prashant knows the numbers, they must be (4,13).\" \n\r\nFor all other numbers in the Possible Sum List, Prashant might be sure of the numbers, but Sachin won't. \n\n\r\nHere is the step by step explanation: \n\r\nSachin : \"As the sum is 17, two numbers can be either (2,15), (3,14), (4,13), (5,12), (6,11), (7,10) or (8,9). Also, as none of them is a prime numbers pair, Prashant won't be knowing numbers either.\" \n\r\nPrashant : \"Since Sachin is sure that both of us don't know the numbers, the sum must be one of the Possible Sum List. Further, as the product is 52, two numbers can be either (2,26) or (4,13). But if they were (2,26), Sachin would not have been sure in advance that I don't know the numbers as 28 (2+26) is not in the Possible Sum List. Hence, the two numbers are 4 and 13.\" \n\r\nSachin : \"As Prashant now knows both the numbers, out of all possible products - 30(2,15), 42(3,14), 52(4,13), 60(5,12), 66(6,11), 70(7,10), 72(8,9) - there is one product for which list of all possible sum contains ONLY ONE sum from the Possible Sum List. And also, no such two lists exist. [see table above for 17] Hence, two numbers are 4 and 13.\" \n\r\nNakul figured out both the numbers just as we did by observing the conversation between Sachin and Prashant. \n\r\nIt is interesting to note that there are no other such two numbers. We checked all the possible sums till 500!!!\n<|im_start|>answer\nThe numbers are 4 and 13. \n\r\nAs Sachin is initially confident that they (i.e. he and Prashant) don't know the numbers, we can conclude that - \r\n1) The sum must not be expressible as sum of two primes, otherwise Sachin could not have been sure in advance that Prashant did not know the numbers. \r\n2) The product cannot be less than 12, otherwise there would only be one choice and Prashant would have figured that out also. \n\r\nSuch possible sum are - 11, 17, 23, 27, 29, 35, 37, 41, 47, 51, 53, 57, 59, 65, 67, 71, 77, 79, 83, 87, 89, 93, 95, 97, 101, 107, 113, 117, 119, 121, 123, 125, 127, 131, 135, 137, 143, 145, 147, 149, 155, 157, 161, 163, 167, 171, 173, 177, 179, 185, 187, 189, 191, 197, .... \n\r\nLet's examine them one by one. \n\r\nIf the sum of two numbers is 11, Sachin will think that the numbers would be (2,9), (3,8 ), (4,7) or (5,6). \n\r\nSachin : \"As 11 is not expressible as sum of two primes, Prashant can't know the numbers.\" \n\r\nHere, the product would be 18(2*9), 24(3*8 ), 28(4*7) or 30(5*6). In all the cases except for product 30, Prashant would know the numbers. \n\r\n- if product of two numbers is 18: \r\nPrashant : \"Since the product is 18, the sum could be either 11(2,9) or 9(3,6). But if the sum was 9, Sachin would have deduced that I might know the numbers as (2,7) is the possible prime numbers pair. Hence, the numbers must be 2 and 9.\" (OR in other words, 9 is not in the Possible Sum List).\n\r\n- if product of two numbers is 24: \r\nPrashant : \"Since the product is 24, the sum could be either 14(2,12), 11(3,8 ) or 10(4,6). But 14 and 10 are not in the Possible Sum List. Hence, the numbers must be 3 and 8.\" \n\r\n- if product of two numbers is 28: \r\nPrashant : \"Since the product is 28, the sum could be either 16(2,14) or 11(4,7). But 16 is not in the Possible Sum List. Hence, the numbers must be 4 and 7.\" \n\r\n- if product of two numbers is 30: \r\nPrashant : \"Since the product is 30, the sum could be either 17(2,15), 13(3,10) or 11(5,6). But 13 is not in the Possible Sum List. Hence, the numbers must be either (2,15) or (5,6).\" Here, Prashant won't be sure of the numbers. \n\r\nHence, Prashant will be sure of the numbers if the product is either 18, 24 or 28. \n\r\nSachin : \"Since Prashant knows the numbers, they must be either (3,8 ), (4,7) or (5,6).\" But he won't be sure. Hence, the sum is not 11. \n\r\nSummerising data for sum 11: \r\nPossible Sum PRODUCT Possible Sum \r\n2+9 18 2+9=11 (possible) \r\n3+6=9 \r\n3+8 24 2+12=14 \r\n3+8=11 (possible) \r\n4+6=10 \r\n4+7 28 2+12=14 \r\n3+8=11 (possible) \r\n4+6=10 \r\n5+6 30 2+15=17 (possible) \r\n3+10=13 \r\n5+6=11 (possible) \n\n\r\nFollowing the same procedure for 17: \r\nPossible Sum PRODUCT Possible Sum \r\n2+15 30 2+15=17 (possible) \r\n3+10= 13 \r\n5+6=11 (possible) \r\n3+14 42 2+21=23 (possible) \r\n3+14=17 (possible) \r\n6+7=13 \r\n4+13 52 2+26=28 \r\n4+13=17 (possible) \r\n5+12 60 2+30=32 \r\n3+20=23 (possible) \r\n4+15=19 \r\n5+12=17 (possible) \r\n6+10=16 \r\n6+11 66 2+33=35 (possible) \r\n3+22=25 \r\n6+11=17 (possible) \n\r\n7+10 70 2+35=37 (possible) \r\n5+14=19 \r\n7+10=17 (possible) \r\n8+9 72 2+36=38 \r\n3+24=27 (possible) \r\n4+18=22 \r\n6+12=18 \r\n8+9=17 (possible) \n\n\r\nHere, Prashant will be sure of the numbers if the product is 52. \n\r\nSachin : \"Since Prashant knows the numbers, they must be (4,13).\" \n\r\nFor all other numbers in the Possible Sum List, Prashant might be sure of the numbers, but Sachin won't. \n\n\r\nHere is the step by step explanation: \n\r\nSachin : \"As the sum is 17, two numbers can be either (2,15), (3,14), (4,13), (5,12), (6,11), (7,10) or (8,9). Also, as none of them is a prime numbers pair, Prashant won't be knowing numbers either.\" \n\r\nPrashant : \"Since Sachin is sure that both of us don't know the numbers, the sum must be one of the Possible Sum List. Further, as the product is 52, two numbers can be either (2,26) or (4,13). But if they were (2,26), Sachin would not have been sure in advance that I don't know the numbers as 28 (2+26) is not in the Possible Sum List. Hence, the two numbers are 4 and 13.\" \n\r\nSachin : \"As Prashant now knows both the numbers, out of all possible products - 30(2,15), 42(3,14), 52(4,13), 60(5,12), 66(6,11), 70(7,10), 72(8,9) - there is one product for which list of all possible sum contains ONLY ONE sum from the Possible Sum List. And also, no such two lists exist. [see table above for 17] Hence, two numbers are 4 and 13.\" \n\r\nNakul figured out both the numbers just as we did by observing the conversation between Sachin and Prashant. \n\r\nIt is interesting to note that there are no other such two numbers. We checked all the possible sums till 500!!!\n<|im_end|>" }, { "id": "#1316", "title": "Three Pills", "fun": 2.1, "difficulty": 1.11, "author": "Michelle", "desc": "If a doctor gives you three pills and tells you to take one pill every half hour, how long will they last?", "hint": "No hint available.", "answer": "One Hour. You would take the first pill immediately, the second a half hour later, and the third exactly one hour after taking the first.", "category": "Logic", "date": "11/07/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf a doctor gives you three pills and tells you to take one pill every half hour, how long will they last?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOne Hour. You would take the first pill immediately, the second a half hour later, and the third exactly one hour after taking the first.\n<|im_start|>answer\nOne Hour. You would take the first pill immediately, the second a half hour later, and the third exactly one hour after taking the first.\n<|im_end|>" }, { "id": "#3834", "title": "Ann And Real Estate", "fun": 2.1, "difficulty": 2.2, "author": "missie", "desc": "Ann purchased a house for $166,902. She wants to sell it for a profit of exactly 13%. However, she does not want to sell it herself. She wants a Real Estate Agent to sell it for her. The Agent must make a commission of exactly 5.7% (in addition to Ann's 13% profit). How much must the Agent sell the house for? Give your answer to the nearest dollar.", "hint": "No hint available.", "answer": "The Agent must sell Ann's house for $ 200000.\r\nThe Agent gets $ 11400 as commission (i.e., 0.057 x 200000).\r\nAnn gets (including profit) $ 188600, i.e., 200000 - 11400.\r\nIt may be noted that: (188600 - 166902) / 166902 x 100 = 13%. \r\nImportantly, profit is calculated on purchase cost (by Ann) and commission is calculated on selling price (by the Agent). \n\r\nThe problem may also be solved by setting up the following equation:\r\nPurchase Cost + Ann's Profit + Agent's Commission = Selling Price \r\n166902 + (13/100) 166902 + (5.7/100) S = S \r\nwhere S is the Selling Price in $. \r\nThe equation may be solved as shown below.\r\n188600 + 0.057 S = S \r\nS = 188600 / (1 - 0.057) = 200000.", "category": "Math", "date": "05/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnn purchased a house for $166,902. She wants to sell it for a profit of exactly 13%. However, she does not want to sell it herself. She wants a Real Estate Agent to sell it for her. The Agent must make a commission of exactly 5.7% (in addition to Ann's 13% profit). How much must the Agent sell the house for? Give your answer to the nearest dollar.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Agent must sell Ann's house for $ 200000.\r\nThe Agent gets $ 11400 as commission (i.e., 0.057 x 200000).\r\nAnn gets (including profit) $ 188600, i.e., 200000 - 11400.\r\nIt may be noted that: (188600 - 166902) / 166902 x 100 = 13%. \r\nImportantly, profit is calculated on purchase cost (by Ann) and commission is calculated on selling price (by the Agent). \n\r\nThe problem may also be solved by setting up the following equation:\r\nPurchase Cost + Ann's Profit + Agent's Commission = Selling Price \r\n166902 + (13/100) 166902 + (5.7/100) S = S \r\nwhere S is the Selling Price in $. \r\nThe equation may be solved as shown below.\r\n188600 + 0.057 S = S \r\nS = 188600 / (1 - 0.057) = 200000.\n<|im_start|>answer\nThe Agent must sell Ann's house for $ 200000.\r\nThe Agent gets $ 11400 as commission (i.e., 0.057 x 200000).\r\nAnn gets (including profit) $ 188600, i.e., 200000 - 11400.\r\nIt may be noted that: (188600 - 166902) / 166902 x 100 = 13%. \r\nImportantly, profit is calculated on purchase cost (by Ann) and commission is calculated on selling price (by the Agent). \n\r\nThe problem may also be solved by setting up the following equation:\r\nPurchase Cost + Ann's Profit + Agent's Commission = Selling Price \r\n166902 + (13/100) 166902 + (5.7/100) S = S \r\nwhere S is the Selling Price in $. \r\nThe equation may be solved as shown below.\r\n188600 + 0.057 S = S \r\nS = 188600 / (1 - 0.057) = 200000.\n<|im_end|>" }, { "id": "#23599", "title": "Sisters 2", "fun": 2.1, "difficulty": 0.85, "author": "sk8ergrl", "desc": "A 40 year old woman hadn't seen her sister in 4 years. They decided to get together and meet at a mall with their kids. The first woman has a boy and 2 girls. The second has 2 boys and 2 girls. How many sisters are there in all?", "hint": "Don't forget about the moms.", "answer": "6", "category": "Logic", "date": "06/12/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA 40 year old woman hadn't seen her sister in 4 years. They decided to get together and meet at a mall with their kids. The first woman has a boy and 2 girls. The second has 2 boys and 2 girls. How many sisters are there in all?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6\n<|im_start|>answer\n6\n<|im_end|>" }, { "id": "#39670", "title": "Left A-Loan", "fun": 2.09, "difficulty": 1.37, "author": "cyberstar5150", "desc": "A man comes up to you and hands you $1000 in cash. He then says:\n\r\n\"Now, don't spend it all, because I'm going to go off and find the largest integer, and after I find it, I'm going to want you to give me $1 back.\"\n\r\nGiven this stipulation, how much money has he *really* given you?", "hint": "No hint available.", "answer": "$1000.\n\r\nHe's off to find the largest integer, so he's NEVER going to come back for that dollar.", "category": "Logic", "date": "12/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man comes up to you and hands you $1000 in cash. He then says:\n\r\n\"Now, don't spend it all, because I'm going to go off and find the largest integer, and after I find it, I'm going to want you to give me $1 back.\"\n\r\nGiven this stipulation, how much money has he *really* given you?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$1000.\n\r\nHe's off to find the largest integer, so he's NEVER going to come back for that dollar.\n<|im_start|>answer\n$1000.\n\r\nHe's off to find the largest integer, so he's NEVER going to come back for that dollar.\n<|im_end|>" }, { "id": "#11131", "title": "What Age?", "fun": 2.09, "difficulty": 1.71, "author": "jitterbugxx5", "desc": "Jessica was 10 when Andreas was born. Jessica's cousin was 17 when she had Andreas. Now Andreas's mom is 47.\n\r\nHow old are Andreas and Jessica now?", "hint": "No hint available.", "answer": "Jessica is 40\r\nAndreas is 30\n\r\nHere's how:\r\nSince Andreas's mom was 17 when she had Andreas, Andreas must be 17 years younger, so she is 30. Since Jessica was 10 when Andreas was born, Jessica must still be 10 years older, making her 40.", "category": "Math", "date": "03/13/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJessica was 10 when Andreas was born. Jessica's cousin was 17 when she had Andreas. Now Andreas's mom is 47.\n\r\nHow old are Andreas and Jessica now?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJessica is 40\r\nAndreas is 30\n\r\nHere's how:\r\nSince Andreas's mom was 17 when she had Andreas, Andreas must be 17 years younger, so she is 30. Since Jessica was 10 when Andreas was born, Jessica must still be 10 years older, making her 40.\n<|im_start|>answer\nJessica is 40\r\nAndreas is 30\n\r\nHere's how:\r\nSince Andreas's mom was 17 when she had Andreas, Andreas must be 17 years younger, so she is 30. Since Jessica was 10 when Andreas was born, Jessica must still be 10 years older, making her 40.\n<|im_end|>" }, { "id": "#48671", "title": "Symbolism I", "fun": 2.09, "difficulty": 2.28, "author": "Mathgeek007", "desc": "I give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nNow, here's your puzzle.\r\n173476210\r\n++--=", "hint": "Each side equals 0.", "answer": "17-3+47-62+1=0", "category": "Math", "date": "04/27/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nNow, here's your puzzle.\r\n173476210\r\n++--=\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n17-3+47-62+1=0\n<|im_start|>answer\n17-3+47-62+1=0\n<|im_end|>" }, { "id": "#41116", "title": "Perfectly Balanced", "fun": 2.09, "difficulty": 1.36, "author": "rockstar1234567", "desc": "Tom spun a geometric object (such as a cylinder, cube, pyramid, rectangular prism, etc.) like a top. However, when it stopped, it was still standing up with no noticeable differences. How is this possible?", "hint": "Perfect in all ways.", "answer": "Tom actually spun a sphere. It didn't matter if it spun or not, it looked the same.", "category": "Math", "date": "03/19/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTom spun a geometric object (such as a cylinder, cube, pyramid, rectangular prism, etc.) like a top. However, when it stopped, it was still standing up with no noticeable differences. How is this possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTom actually spun a sphere. It didn't matter if it spun or not, it looked the same.\n<|im_start|>answer\nTom actually spun a sphere. It didn't matter if it spun or not, it looked the same.\n<|im_end|>" }, { "id": "#10901", "title": "Prime Numbers", "fun": 2.09, "difficulty": 1.84, "author": "mollynoodl", "desc": "Prime numbers have only two factors, themselves and one. How many prime numbers are there between 10 and 100 who have a sum of 8 when their 2 digits are added together?", "hint": "No hint available.", "answer": "Three: 17, 53, and 71.", "category": "Math", "date": "03/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nPrime numbers have only two factors, themselves and one. How many prime numbers are there between 10 and 100 who have a sum of 8 when their 2 digits are added together?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree: 17, 53, and 71.\n<|im_start|>answer\nThree: 17, 53, and 71.\n<|im_end|>" }, { "id": "#37574", "title": "Summer Spa Retreat", "fun": 2.09, "difficulty": 1.13, "author": "sayso09", "desc": "My little sister decided to have a spa retreat slumber party just before school started. Our mother went along with this plan and recruited my friends to work the party. During the course of the party, three of my friends got into heated arguments with three of my little sister's friends and also got stuck at three different stations that they hated. Since I did not see these arguments go on, I had to ask other people at the party for information. The problem is, I only got pieces of information, and I need help putting the pieces together.\n\r\nMy three friends are Megan, Rene, and Leslie.\r\nMy sister's three friends are Erica, Hannah, and Candice.\r\nThe three stations are massages, pedicures, and manicures.\n\n\r\n1. My three friends are Megan, the girl who didn't want to do massages, and the girl who fought with Hannah.\r\n2. Megan hated feet and wished she could have been giving manicures.\r\n3. Candice got into an argument with the girl who worked at the massage table.\r\n4. Rene worked at the manicure station but hated the fumes.", "hint": "No hint available.", "answer": "Megan - Erica - pedicures\r\nLeslie - Candice - massages\r\nRene - Hannah - manicures", "category": "Logic-Grid", "date": "07/28/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy little sister decided to have a spa retreat slumber party just before school started. Our mother went along with this plan and recruited my friends to work the party. During the course of the party, three of my friends got into heated arguments with three of my little sister's friends and also got stuck at three different stations that they hated. Since I did not see these arguments go on, I had to ask other people at the party for information. The problem is, I only got pieces of information, and I need help putting the pieces together.\n\r\nMy three friends are Megan, Rene, and Leslie.\r\nMy sister's three friends are Erica, Hannah, and Candice.\r\nThe three stations are massages, pedicures, and manicures.\n\n\r\n1. My three friends are Megan, the girl who didn't want to do massages, and the girl who fought with Hannah.\r\n2. Megan hated feet and wished she could have been giving manicures.\r\n3. Candice got into an argument with the girl who worked at the massage table.\r\n4. Rene worked at the manicure station but hated the fumes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMegan - Erica - pedicures\r\nLeslie - Candice - massages\r\nRene - Hannah - manicures\n<|im_start|>answer\nMegan - Erica - pedicures\r\nLeslie - Candice - massages\r\nRene - Hannah - manicures\n<|im_end|>" }, { "id": "#38688", "title": "Class Troubles", "fun": 2.09, "difficulty": 1.1, "author": "mik512", "desc": "Adam has five classes before lunch. He has English, Social Studies, Math, Art, and Computer Tech but can't remember what period each class is. He also can't remember what teacher he has with what class.\n\r\n1. English comes after Art.\r\n2. English comes before Social Studies.\r\n3. Adam goes straight to lunch from Computer Tech.\r\n4. He is always late to add from English.\r\n5. He has English with the only teacher that has a Z in her name.\r\n6. His Computer Tech teacher is a tool.\r\n7. He has Art with Mr. T.\r\n8. His Math teacher is almost a bird's eating habit.\r\n9. He has Social Studies with the only Mrs.\n\r\nWhat is Adam's schedule before lunch?", "hint": "No hint available.", "answer": "Period 1 - Art - Mr. Tompson\r\nPeriod 2 - English - Ms. Ortiz\r\nPeriod 3 - Math - Mr. Beck\r\nPeriod 4 - Social Studies - Mrs. Motal\r\nPeriod 5 - Computer Tech - Mr. Comb", "category": "Logic-Grid", "date": "10/08/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdam has five classes before lunch. He has English, Social Studies, Math, Art, and Computer Tech but can't remember what period each class is. He also can't remember what teacher he has with what class.\n\r\n1. English comes after Art.\r\n2. English comes before Social Studies.\r\n3. Adam goes straight to lunch from Computer Tech.\r\n4. He is always late to add from English.\r\n5. He has English with the only teacher that has a Z in her name.\r\n6. His Computer Tech teacher is a tool.\r\n7. He has Art with Mr. T.\r\n8. His Math teacher is almost a bird's eating habit.\r\n9. He has Social Studies with the only Mrs.\n\r\nWhat is Adam's schedule before lunch?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPeriod 1 - Art - Mr. Tompson\r\nPeriod 2 - English - Ms. Ortiz\r\nPeriod 3 - Math - Mr. Beck\r\nPeriod 4 - Social Studies - Mrs. Motal\r\nPeriod 5 - Computer Tech - Mr. Comb\n<|im_start|>answer\nPeriod 1 - Art - Mr. Tompson\r\nPeriod 2 - English - Ms. Ortiz\r\nPeriod 3 - Math - Mr. Beck\r\nPeriod 4 - Social Studies - Mrs. Motal\r\nPeriod 5 - Computer Tech - Mr. Comb\n<|im_end|>" }, { "id": "#10088", "title": "Making Punch", "fun": 2.09, "difficulty": 1.13, "author": "Gmoney-Gdog", "desc": "Ruby is making a bowl of punch. She needs 7 cups of water. Ruby doesn't have a measuring cup, but she has three pitchers. One pitcher holds 9 cups of water. Another pitcher holds 6 cups of water. The last pitcher holds 4 cups of water. How can Ruby measure exactly 7 cups of water with her pitchers?", "hint": "She can't just put 7 cups in the 9 cup pitcher...", "answer": "Ruby can fill the pitcher that holds 4 cups. Then she can fill the 9 cup pitcher and pour the water into the 6 cup pitcher. When the 6 cup pitcher is full, the 9 cup pitcher will be left with 3 cups. Ruby still has the 4 cup pitcher filled. 3 cups with another 4 cups is 7 cups.", "category": "Math", "date": "01/28/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRuby is making a bowl of punch. She needs 7 cups of water. Ruby doesn't have a measuring cup, but she has three pitchers. One pitcher holds 9 cups of water. Another pitcher holds 6 cups of water. The last pitcher holds 4 cups of water. How can Ruby measure exactly 7 cups of water with her pitchers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRuby can fill the pitcher that holds 4 cups. Then she can fill the 9 cup pitcher and pour the water into the 6 cup pitcher. When the 6 cup pitcher is full, the 9 cup pitcher will be left with 3 cups. Ruby still has the 4 cup pitcher filled. 3 cups with another 4 cups is 7 cups.\n<|im_start|>answer\nRuby can fill the pitcher that holds 4 cups. Then she can fill the 9 cup pitcher and pour the water into the 6 cup pitcher. When the 6 cup pitcher is full, the 9 cup pitcher will be left with 3 cups. Ruby still has the 4 cup pitcher filled. 3 cups with another 4 cups is 7 cups.\n<|im_end|>" }, { "id": "#13792", "title": "The Average Student", "fun": 2.09, "difficulty": 1.3800000000000001, "author": "cool_star", "desc": "Kelly got a very poor grade on her first homework assignment at her new school. She got only one star out of five stars! She wanted to do better, and get an average of four stars. How many more five star homework assignments does she have to do to achieve this goal?", "hint": "No hint available.", "answer": "She needs three five star homework assignments. 3x5=15 plus the one star equals 16. Then, 16 divided by 4 homework assignments equals 4!", "category": "Math", "date": "07/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKelly got a very poor grade on her first homework assignment at her new school. She got only one star out of five stars! She wanted to do better, and get an average of four stars. How many more five star homework assignments does she have to do to achieve this goal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe needs three five star homework assignments. 3x5=15 plus the one star equals 16. Then, 16 divided by 4 homework assignments equals 4!\n<|im_start|>answer\nShe needs three five star homework assignments. 3x5=15 plus the one star equals 16. Then, 16 divided by 4 homework assignments equals 4!\n<|im_end|>" }, { "id": "#18625", "title": "University of Kebabology", "fun": 2.09, "difficulty": 1.74, "author": "mad-ade", "desc": "At the Madadian University of Kebabology there are 126 1st year students, 375 2nd year students, 293 3rd year students and 187 4th year students.\r\nIf the University were to randomly award a student, what is the percentage chance that it would be a 4th year student?", "hint": "No hint available.", "answer": "19% \n\r\nDivide the number of 4 th years (187) by the total number of students (981), and then multiply the number by 100 to convert to a percentage. \n\r\nHence the answer is (187/981)*100 = 19%", "category": "Math", "date": "08/29/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt the Madadian University of Kebabology there are 126 1st year students, 375 2nd year students, 293 3rd year students and 187 4th year students.\r\nIf the University were to randomly award a student, what is the percentage chance that it would be a 4th year student?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19% \n\r\nDivide the number of 4 th years (187) by the total number of students (981), and then multiply the number by 100 to convert to a percentage. \n\r\nHence the answer is (187/981)*100 = 19%\n<|im_start|>answer\n19% \n\r\nDivide the number of 4 th years (187) by the total number of students (981), and then multiply the number by 100 to convert to a percentage. \n\r\nHence the answer is (187/981)*100 = 19%\n<|im_end|>" }, { "id": "#18225", "title": "If At First You Don't Succeed..", "fun": 2.09, "difficulty": 1.16, "author": "andrewcs", "desc": "A ship was sailing dangerously close to rocks in the water. To save their ship, they threw out the anchor, but since it was not tied down, it sank to the bottom. In one last desperate attempt to save the ship, they threw over a 500lb steel ball. Much to everyone's amazement, the ball floated, then the ship crashed. How is it possible that the ball floated?", "hint": "No hint available.", "answer": "The ball was hollow; there was enough air inside the ball to keep it afloat.", "category": "Logic", "date": "07/14/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA ship was sailing dangerously close to rocks in the water. To save their ship, they threw out the anchor, but since it was not tied down, it sank to the bottom. In one last desperate attempt to save the ship, they threw over a 500lb steel ball. Much to everyone's amazement, the ball floated, then the ship crashed. How is it possible that the ball floated?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe ball was hollow; there was enough air inside the ball to keep it afloat.\n<|im_start|>answer\nThe ball was hollow; there was enough air inside the ball to keep it afloat.\n<|im_end|>" }, { "id": "#35912", "title": "A Whole New Farm!", "fun": 2.08, "difficulty": 0.88, "author": "cowman12", "desc": "Cowman recently needed to relocate to Cowville to find a new farm. He needs to meet the new crew and find their jobs and which breeds they are assigned to.\n\r\nWorkers: Chris, Alex, Jake\n\r\nJobs: Breeder, Feeder, Milker\n\r\nBreeds: Holstein, Jersey, Angus\n\r\n1) The breeder is assigned to the Angus cows.\n\r\n2) Chris is in charge of the Jersey cows.\n\r\n3) Jake is the milker.\n\r\n4) The milker is in charge of the Holstein cows.", "hint": "No hint available.", "answer": "Chris-Feeder-Jersey\n\r\nAlex-Breeder-Angus\n\r\nJake-Milker-Holstein", "category": "Logic-Grid", "date": "03/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCowman recently needed to relocate to Cowville to find a new farm. He needs to meet the new crew and find their jobs and which breeds they are assigned to.\n\r\nWorkers: Chris, Alex, Jake\n\r\nJobs: Breeder, Feeder, Milker\n\r\nBreeds: Holstein, Jersey, Angus\n\r\n1) The breeder is assigned to the Angus cows.\n\r\n2) Chris is in charge of the Jersey cows.\n\r\n3) Jake is the milker.\n\r\n4) The milker is in charge of the Holstein cows.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nChris-Feeder-Jersey\n\r\nAlex-Breeder-Angus\n\r\nJake-Milker-Holstein\n<|im_start|>answer\nChris-Feeder-Jersey\n\r\nAlex-Breeder-Angus\n\r\nJake-Milker-Holstein\n<|im_end|>" }, { "id": "#18945", "title": "The Romankachi Siblings !!!", "fun": 2.08, "difficulty": 2.6, "author": "lesternoronha1", "desc": "We were all celebrating the 25th birthday of my beloved sister, Lavi the kindhearted Romankachi. She was younger to me Rudy the business-minded Romankachi by two years and to our elder brother Fred the well-settled Romankachi by four years. Just as the celebrations were in full swing, I realized something about our ages. I found that I could say at least two things definitely about each of the following two integer values formed by manipulating our ages taken as integers:-\n\r\na) The number formed by adding 1 to the product of Lavi's and my age considered during any one year right since she was a year old.\n\r\nb) The number formed by adding 1 to the product of Fred's and my ages considered during any one year right since I was a year old.\n\r\nThough I forgot about this the next moment and got busy enjoying myself, could you tell what were the two things that flashed across my mind.\n\r\nConsider all ages to be integer values. Also during any given year, Lavi was exactly two years younger to me and exactly four years younger to Fred.", "hint": "I'm exactly two years elder to Lavi and exactly two years younger to Fred.", "answer": "a) The number formed by adding 1 to the product of Lavi's and my age considered during any one year right since she was a year old.\n\r\nThe two things that I could definitely say about the above integer value are :-\r\n1) It is a perfect square.\r\n2) The number formed is the square of a number 1 less than my age in that year.\n\r\nExample: When Lavi was 3, I was 5 -> (3*5)+1 gives 16 which is the square of 4, which is 1 less than my age(5) in that year. \n\n\r\nb) The number formed by adding 1 to the product of Fred's and my ages considered during any one year right since I was a year old.\n\r\nThe two things that I could definitely say about the above integer value are :-\r\n1) It is a perfect square.\r\n2) The number formed is square of a number 1 more than my age in that year.\n\r\nExample: when I was 6, Fred was 8-> (6*8)+1 gives 49 which is the square of 7, a number 1 more than my age(6) in that year.", "category": "Math", "date": "09/26/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWe were all celebrating the 25th birthday of my beloved sister, Lavi the kindhearted Romankachi. She was younger to me Rudy the business-minded Romankachi by two years and to our elder brother Fred the well-settled Romankachi by four years. Just as the celebrations were in full swing, I realized something about our ages. I found that I could say at least two things definitely about each of the following two integer values formed by manipulating our ages taken as integers:-\n\r\na) The number formed by adding 1 to the product of Lavi's and my age considered during any one year right since she was a year old.\n\r\nb) The number formed by adding 1 to the product of Fred's and my ages considered during any one year right since I was a year old.\n\r\nThough I forgot about this the next moment and got busy enjoying myself, could you tell what were the two things that flashed across my mind.\n\r\nConsider all ages to be integer values. Also during any given year, Lavi was exactly two years younger to me and exactly four years younger to Fred.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na) The number formed by adding 1 to the product of Lavi's and my age considered during any one year right since she was a year old.\n\r\nThe two things that I could definitely say about the above integer value are :-\r\n1) It is a perfect square.\r\n2) The number formed is the square of a number 1 less than my age in that year.\n\r\nExample: When Lavi was 3, I was 5 -> (3*5)+1 gives 16 which is the square of 4, which is 1 less than my age(5) in that year. \n\n\r\nb) The number formed by adding 1 to the product of Fred's and my ages considered during any one year right since I was a year old.\n\r\nThe two things that I could definitely say about the above integer value are :-\r\n1) It is a perfect square.\r\n2) The number formed is square of a number 1 more than my age in that year.\n\r\nExample: when I was 6, Fred was 8-> (6*8)+1 gives 49 which is the square of 7, a number 1 more than my age(6) in that year.\n<|im_start|>answer\na) The number formed by adding 1 to the product of Lavi's and my age considered during any one year right since she was a year old.\n\r\nThe two things that I could definitely say about the above integer value are :-\r\n1) It is a perfect square.\r\n2) The number formed is the square of a number 1 less than my age in that year.\n\r\nExample: When Lavi was 3, I was 5 -> (3*5)+1 gives 16 which is the square of 4, which is 1 less than my age(5) in that year. \n\n\r\nb) The number formed by adding 1 to the product of Fred's and my ages considered during any one year right since I was a year old.\n\r\nThe two things that I could definitely say about the above integer value are :-\r\n1) It is a perfect square.\r\n2) The number formed is square of a number 1 more than my age in that year.\n\r\nExample: when I was 6, Fred was 8-> (6*8)+1 gives 49 which is the square of 7, a number 1 more than my age(6) in that year.\n<|im_end|>" }, { "id": "#3833", "title": "A Pole In A Lake", "fun": 2.08, "difficulty": 1.39, "author": "missie", "desc": "There is a pole in a lake. One-half of the pole is in the ground, another one-third of it is covered by water, and 9 ft is out of the water. What is the total length of the pole in ft?", "hint": "No hint available.", "answer": "Fraction of pole in the ground = 1/2 \r\nFraction of pole covered by water = 1/3 \r\nFraction of pole in the ground and covered by water = 1/2 + 1/3 = (3 + 2)/6 = 5/6 \r\nFraction of pole out of water = 1 - 5/6 = 1/6 \r\nThus, one-sixth of the pole (out of water) is 9 ft.\r\nSo, total length of pole = 54 ft.\n\r\nIt may be noted that:\r\nLength of pole in the ground = 54/2 = 27 ft.\r\nLength of pole covered by water = 54/3 = 18 ft.\r\nLength of pole out of water = 9 ft.\n\n\r\nThe problem may also be solved by setting up the following equation: x/2 + x/3 + 9 = x \r\nwhere x denotes the total length of the pole in ft. \r\nThe equation may be solved as shown below.\r\n5x/6 + 9 = x \r\n9 = x - 5x/6 = x/6\r\nx/6 = 9 or x = 54.", "category": "Math", "date": "05/01/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a pole in a lake. One-half of the pole is in the ground, another one-third of it is covered by water, and 9 ft is out of the water. What is the total length of the pole in ft?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFraction of pole in the ground = 1/2 \r\nFraction of pole covered by water = 1/3 \r\nFraction of pole in the ground and covered by water = 1/2 + 1/3 = (3 + 2)/6 = 5/6 \r\nFraction of pole out of water = 1 - 5/6 = 1/6 \r\nThus, one-sixth of the pole (out of water) is 9 ft.\r\nSo, total length of pole = 54 ft.\n\r\nIt may be noted that:\r\nLength of pole in the ground = 54/2 = 27 ft.\r\nLength of pole covered by water = 54/3 = 18 ft.\r\nLength of pole out of water = 9 ft.\n\n\r\nThe problem may also be solved by setting up the following equation: x/2 + x/3 + 9 = x \r\nwhere x denotes the total length of the pole in ft. \r\nThe equation may be solved as shown below.\r\n5x/6 + 9 = x \r\n9 = x - 5x/6 = x/6\r\nx/6 = 9 or x = 54.\n<|im_start|>answer\nFraction of pole in the ground = 1/2 \r\nFraction of pole covered by water = 1/3 \r\nFraction of pole in the ground and covered by water = 1/2 + 1/3 = (3 + 2)/6 = 5/6 \r\nFraction of pole out of water = 1 - 5/6 = 1/6 \r\nThus, one-sixth of the pole (out of water) is 9 ft.\r\nSo, total length of pole = 54 ft.\n\r\nIt may be noted that:\r\nLength of pole in the ground = 54/2 = 27 ft.\r\nLength of pole covered by water = 54/3 = 18 ft.\r\nLength of pole out of water = 9 ft.\n\n\r\nThe problem may also be solved by setting up the following equation: x/2 + x/3 + 9 = x \r\nwhere x denotes the total length of the pole in ft. \r\nThe equation may be solved as shown below.\r\n5x/6 + 9 = x \r\n9 = x - 5x/6 = x/6\r\nx/6 = 9 or x = 54.\n<|im_end|>" }, { "id": "#48171", "title": "Office Day", "fun": 2.08, "difficulty": 0.54, "author": "Oldcustard", "desc": "Steve, Reggie, Gordon and Frank all work at an office skyscraper. They all work on different floors, and all leave at different times.\n\r\nThe data:\r\nNames: Steve, Reggie, Gordon, Frank\r\nFloors: 1, 2, 3, 4\r\nTimes: 3:00, 3:30, 4:15, 5:00\n\r\nThe clues are:\r\n1) Frank has to be home in time for the quarter past 3 basketball match!\r\n2) Steve's floor is higher than Reggie's, but lower than Gordon's.\r\n3) Gordon has a wonderful view from his office!\r\n4) The person on floor 1 leaves the latest.\r\n5) The noisy cars driving right by his window leave Reggie in a bad mood.\r\n6) Frank's office is above Steve's.\r\n7) Steve leaves the office 1 hour and 15 minutes after Frank, but only 45 minutes after the person on floor 4.", "hint": "No hint available.", "answer": "Steve, 2, 4:15\r\nReggie, 1, 5:00\r\nGordon, 4, 3:30\r\nFrank, 3, 3:00", "category": "Logic-Grid", "date": "11/02/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSteve, Reggie, Gordon and Frank all work at an office skyscraper. They all work on different floors, and all leave at different times.\n\r\nThe data:\r\nNames: Steve, Reggie, Gordon, Frank\r\nFloors: 1, 2, 3, 4\r\nTimes: 3:00, 3:30, 4:15, 5:00\n\r\nThe clues are:\r\n1) Frank has to be home in time for the quarter past 3 basketball match!\r\n2) Steve's floor is higher than Reggie's, but lower than Gordon's.\r\n3) Gordon has a wonderful view from his office!\r\n4) The person on floor 1 leaves the latest.\r\n5) The noisy cars driving right by his window leave Reggie in a bad mood.\r\n6) Frank's office is above Steve's.\r\n7) Steve leaves the office 1 hour and 15 minutes after Frank, but only 45 minutes after the person on floor 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSteve, 2, 4:15\r\nReggie, 1, 5:00\r\nGordon, 4, 3:30\r\nFrank, 3, 3:00\n<|im_start|>answer\nSteve, 2, 4:15\r\nReggie, 1, 5:00\r\nGordon, 4, 3:30\r\nFrank, 3, 3:00\n<|im_end|>" }, { "id": "#43852", "title": "If Seven Becomes 40...", "fun": 2.08, "difficulty": 1.78, "author": "KarateGirl098", "desc": "If seven becomes 40, three becomes 0, and eight becomes 55, then what does one become?", "hint": "No hint available.", "answer": "-8. Using this formula, square the number (multiply it by itself) and subtract nine.\n\r\n7 x 7 = 49 - 9 = 40\n\r\n3 x 3 = 9 - 9 = 0\n\r\n8 x 8 = 64 - 9 = 55\n\r\nand...\r\n1 x 1 = 1 - 9 = -8", "category": "Math", "date": "01/05/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf seven becomes 40, three becomes 0, and eight becomes 55, then what does one become?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-8. Using this formula, square the number (multiply it by itself) and subtract nine.\n\r\n7 x 7 = 49 - 9 = 40\n\r\n3 x 3 = 9 - 9 = 0\n\r\n8 x 8 = 64 - 9 = 55\n\r\nand...\r\n1 x 1 = 1 - 9 = -8\n<|im_start|>answer\n-8. Using this formula, square the number (multiply it by itself) and subtract nine.\n\r\n7 x 7 = 49 - 9 = 40\n\r\n3 x 3 = 9 - 9 = 0\n\r\n8 x 8 = 64 - 9 = 55\n\r\nand...\r\n1 x 1 = 1 - 9 = -8\n<|im_end|>" }, { "id": "#3857", "title": "224455", "fun": 2.08, "difficulty": 2.33, "author": "missie", "desc": "Can you find a three-digit number such that when you reverse the numbers you get a larger number and the product of these two numbers is 224455?", "hint": "No hint available.", "answer": "385*583", "category": "Math", "date": "05/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you find a three-digit number such that when you reverse the numbers you get a larger number and the product of these two numbers is 224455?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n385*583\n<|im_start|>answer\n385*583\n<|im_end|>" }, { "id": "#23316", "title": "Darth, Hunter, Settra, and Toad", "fun": 2.08, "difficulty": 0.84, "author": "goofyguy", "desc": "Toad eats 50 apples. Darth eats half of Toad's amount, Settra eats Darth's amount divided by 5, and Hunter eats 20 times Settra's amount. How many did Hunter eat?", "hint": "Darth eats 25.", "answer": "Hunter eats 100 apples.", "category": "Math", "date": "05/31/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nToad eats 50 apples. Darth eats half of Toad's amount, Settra eats Darth's amount divided by 5, and Hunter eats 20 times Settra's amount. How many did Hunter eat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHunter eats 100 apples.\n<|im_start|>answer\nHunter eats 100 apples.\n<|im_end|>" }, { "id": "#5180", "title": "Pears, Apples and Oranges", "fun": 2.08, "difficulty": 1.53, "author": "cleverclogs", "desc": "Some pears are weighed against some apples and some oranges in the ratio 6:2:5. If I have 39 pears and no apples or oranges, how many apples and oranges will I need?", "hint": "No hint available.", "answer": "I will need 13 apples and 32 and a half oranges.", "category": "Math", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSome pears are weighed against some apples and some oranges in the ratio 6:2:5. If I have 39 pears and no apples or oranges, how many apples and oranges will I need?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI will need 13 apples and 32 and a half oranges.\n<|im_start|>answer\nI will need 13 apples and 32 and a half oranges.\n<|im_end|>" }, { "id": "#11012", "title": "Mad Ade's Fridge", "fun": 2.08, "difficulty": 2.5100000000000002, "author": "mad-ade", "desc": "Mad Ade says to Rod Lightning, \"Can you figure out how many Kebabs I have in my fridge?\" He gives 3 clues to Rod Lightning: If the number of Kebabs I have:-\n\r\n1, is a multiple of 5, it is a number between 1 and 19.\r\n2, is not a multiple of 8, it is a number between 20 and 29.\r\n3, is not a multiple of 10, it is a number between 30 and 39.\n\r\nHow many Kebabs does Mad Ade have in his fridge?", "hint": "No hint available.", "answer": "32 Kebabs.\n\r\nLet's apply all 3 conditions separately and put all possible numbers together. \n\r\nFirst condition says that if a multiple of 5, then the number is between 1 and 19. Hence, the possible numbers are (5, 10, 15, 21, 22, 23, 24, 26, 27, 28, 29, 31, 32, 33, 34, 36, 37, 38, 39) \n\r\nSecond condition says that if not a multiple of 8, then the number is between 20 and 29. Hence, the possible numbers are (8, 16, 20, 21, 22, 23, 25, 26, 27, 28, 29, 32) \n\r\nThird condition says that if not a multiple of 10, then the number is between 30 and 39. Hence, the possible numbers are (10, 20, 31, 32, 33, 34, 35, 36, 37, 38, 39) \n\r\nOnly number 32 is there in all 3 result sets. That means that only number 32 satisfies all three conditions. Hence, Mad Ade must have 32 Kebabs in his fridge.", "category": "Math", "date": "03/09/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade says to Rod Lightning, \"Can you figure out how many Kebabs I have in my fridge?\" He gives 3 clues to Rod Lightning: If the number of Kebabs I have:-\n\r\n1, is a multiple of 5, it is a number between 1 and 19.\r\n2, is not a multiple of 8, it is a number between 20 and 29.\r\n3, is not a multiple of 10, it is a number between 30 and 39.\n\r\nHow many Kebabs does Mad Ade have in his fridge?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n32 Kebabs.\n\r\nLet's apply all 3 conditions separately and put all possible numbers together. \n\r\nFirst condition says that if a multiple of 5, then the number is between 1 and 19. Hence, the possible numbers are (5, 10, 15, 21, 22, 23, 24, 26, 27, 28, 29, 31, 32, 33, 34, 36, 37, 38, 39) \n\r\nSecond condition says that if not a multiple of 8, then the number is between 20 and 29. Hence, the possible numbers are (8, 16, 20, 21, 22, 23, 25, 26, 27, 28, 29, 32) \n\r\nThird condition says that if not a multiple of 10, then the number is between 30 and 39. Hence, the possible numbers are (10, 20, 31, 32, 33, 34, 35, 36, 37, 38, 39) \n\r\nOnly number 32 is there in all 3 result sets. That means that only number 32 satisfies all three conditions. Hence, Mad Ade must have 32 Kebabs in his fridge.\n<|im_start|>answer\n32 Kebabs.\n\r\nLet's apply all 3 conditions separately and put all possible numbers together. \n\r\nFirst condition says that if a multiple of 5, then the number is between 1 and 19. Hence, the possible numbers are (5, 10, 15, 21, 22, 23, 24, 26, 27, 28, 29, 31, 32, 33, 34, 36, 37, 38, 39) \n\r\nSecond condition says that if not a multiple of 8, then the number is between 20 and 29. Hence, the possible numbers are (8, 16, 20, 21, 22, 23, 25, 26, 27, 28, 29, 32) \n\r\nThird condition says that if not a multiple of 10, then the number is between 30 and 39. Hence, the possible numbers are (10, 20, 31, 32, 33, 34, 35, 36, 37, 38, 39) \n\r\nOnly number 32 is there in all 3 result sets. That means that only number 32 satisfies all three conditions. Hence, Mad Ade must have 32 Kebabs in his fridge.\n<|im_end|>" }, { "id": "#4587", "title": "(a x a) x 2 = (a + 5) x 81", "fun": 2.08, "difficulty": 1.9000000000000001, "author": "Cleverclogs", "desc": "I have an integer which, when squared and then multiplied by two is equal to that integer five higher than it multiplied by eighty one.\n\r\n(a x a) x 2 = (a + 5) x 81\n\r\nWhat is my number?", "hint": "Square a number and then multiply it by two. Divide your answer by the number five higher than it and if the answer is less than 81 it is too low. If the answer is more than 81 it is too high.", "answer": "My number is 45.\r\n(a = 45)", "category": "Math", "date": "06/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have an integer which, when squared and then multiplied by two is equal to that integer five higher than it multiplied by eighty one.\n\r\n(a x a) x 2 = (a + 5) x 81\n\r\nWhat is my number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMy number is 45.\r\n(a = 45)\n<|im_start|>answer\nMy number is 45.\r\n(a = 45)\n<|im_end|>" }, { "id": "#39976", "title": "Find the Sum", "fun": 2.08, "difficulty": 2.62, "author": "shenqiang", "desc": "Find the sum of all prime numbers between 1 and 100 that are simultaneously 1 greater than a multiple of 4 and 1 less than a multiple of 5.", "hint": "No hint available.", "answer": "Numbers that are 1 greater than a multiple of 4 are 5, 9, 13, 17, 21... where 9 is 1 less than a multiple of 5. lcm(4, 5)=20, therefore the pattern repeats in each 20 numbers.\n\r\n9 (composite)\t29 (prime)\t49 (composite)\t69 (composite)\t89 (prime)\n\r\nTherefore, the sum of all such numbers is 29+89=118.", "category": "Math", "date": "01/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the sum of all prime numbers between 1 and 100 that are simultaneously 1 greater than a multiple of 4 and 1 less than a multiple of 5.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNumbers that are 1 greater than a multiple of 4 are 5, 9, 13, 17, 21... where 9 is 1 less than a multiple of 5. lcm(4, 5)=20, therefore the pattern repeats in each 20 numbers.\n\r\n9 (composite)\t29 (prime)\t49 (composite)\t69 (composite)\t89 (prime)\n\r\nTherefore, the sum of all such numbers is 29+89=118.\n<|im_start|>answer\nNumbers that are 1 greater than a multiple of 4 are 5, 9, 13, 17, 21... where 9 is 1 less than a multiple of 5. lcm(4, 5)=20, therefore the pattern repeats in each 20 numbers.\n\r\n9 (composite)\t29 (prime)\t49 (composite)\t69 (composite)\t89 (prime)\n\r\nTherefore, the sum of all such numbers is 29+89=118.\n<|im_end|>" }, { "id": "#3648", "title": "Twelve Thousand", "fun": 2.08, "difficulty": 1.34, "author": "Angelicious", "desc": "Can you write down this number using digits?\n\r\nTwelve thousand twelve hundred twelve", "hint": "No hint available.", "answer": "13,212", "category": "Math", "date": "04/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you write down this number using digits?\n\r\nTwelve thousand twelve hundred twelve\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n13,212\n<|im_start|>answer\n13,212\n<|im_end|>" }, { "id": "#4065", "title": "Sandwiches", "fun": 2.08, "difficulty": 1.28, "author": "GoldieLuvNeopets", "desc": "Mrs. Doyle the Housekeeper has made a big, big pile of sandwiches for the party of friends visiting her house tonight. When she counts them, she realises that she can equally split the sandwiches between two friends and have none left over. She can also split them between three friends, four friends, five friends and six friends equally and every time there will be no sandwiches left over. In each case, the sandwiches are not cut into pieces.\n\r\nWhat is the smallest amount of sandwiches that Mrs. Doyle could have made?", "hint": "No hint available.", "answer": "60 sandwiches", "category": "Math", "date": "05/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Doyle the Housekeeper has made a big, big pile of sandwiches for the party of friends visiting her house tonight. When she counts them, she realises that she can equally split the sandwiches between two friends and have none left over. She can also split them between three friends, four friends, five friends and six friends equally and every time there will be no sandwiches left over. In each case, the sandwiches are not cut into pieces.\n\r\nWhat is the smallest amount of sandwiches that Mrs. Doyle could have made?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n60 sandwiches\n<|im_start|>answer\n60 sandwiches\n<|im_end|>" }, { "id": "#2030", "title": "Finish Together", "fun": 2.08, "difficulty": 1.4, "author": "jokester8000", "desc": "Three people are having a race. It takes Bob three minutes to finish a lap. It takes Travis 6 minutes to finish a lap. Jil takes 9 minutes to finish a lap. After how many minutes will they all finish at the same time?", "hint": "No hint available.", "answer": "18 minutes.\r\nAfter 6 laps Bob has gone for 18 minutes.\r\nAfter 3 laps Travis has gone for 18 minutes.\r\nAfter 2 laps Jil has gone for 18 minutes.", "category": "Math", "date": "01/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree people are having a race. It takes Bob three minutes to finish a lap. It takes Travis 6 minutes to finish a lap. Jil takes 9 minutes to finish a lap. After how many minutes will they all finish at the same time?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n18 minutes.\r\nAfter 6 laps Bob has gone for 18 minutes.\r\nAfter 3 laps Travis has gone for 18 minutes.\r\nAfter 2 laps Jil has gone for 18 minutes.\n<|im_start|>answer\n18 minutes.\r\nAfter 6 laps Bob has gone for 18 minutes.\r\nAfter 3 laps Travis has gone for 18 minutes.\r\nAfter 2 laps Jil has gone for 18 minutes.\n<|im_end|>" }, { "id": "#646", "title": "The Circular Table", "fun": 2.08, "difficulty": 1.62, "author": "Spencer", "desc": "A lady has an expensive table and wants to find the exact middle of the table. How does she do this without making any marks on the table?", "hint": "No hint available.", "answer": "The lady gets a piece of paper the size of the table, then she folds the paper in half in both ways. She puts a dot right where the two folds meet. That is where the middle of the table is!", "category": "Logic", "date": "08/25/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA lady has an expensive table and wants to find the exact middle of the table. How does she do this without making any marks on the table?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lady gets a piece of paper the size of the table, then she folds the paper in half in both ways. She puts a dot right where the two folds meet. That is where the middle of the table is!\n<|im_start|>answer\nThe lady gets a piece of paper the size of the table, then she folds the paper in half in both ways. She puts a dot right where the two folds meet. That is where the middle of the table is!\n<|im_end|>" }, { "id": "#42274", "title": "The Legend of Zelda Logic Grid", "fun": 2.08, "difficulty": 0.47000000000000003, "author": "beatlesman12", "desc": "Link, Zelda, and Ganondorf fought three different evil creatures. The creatures were an octorock, an iron knuckle, and a poe. They fought them with three different weapons, too. The weapons were a bow and arrows, magic, and a sword. Also, Zelda is a girl and Link and Ganondorf are boys. Determine who fought what creature and with what weapon.\n\r\n1. Ganondorf did not fight a creature with the same number of syllables in his name.\r\n2. The iron knuckle was not fought against with magic.\r\n3. The girl fought the octorock.\r\n4. Link has a sword and did not fight the poe.\r\n5. Zelda fought with the bow and arrows.", "hint": "No hint available.", "answer": "Link, Iron Knuckle, Sword\n\r\nZelda, Octorock, Bow and Arrows\n\r\nGanondorf, Poe, Magic", "category": "Logic-Grid", "date": "06/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLink, Zelda, and Ganondorf fought three different evil creatures. The creatures were an octorock, an iron knuckle, and a poe. They fought them with three different weapons, too. The weapons were a bow and arrows, magic, and a sword. Also, Zelda is a girl and Link and Ganondorf are boys. Determine who fought what creature and with what weapon.\n\r\n1. Ganondorf did not fight a creature with the same number of syllables in his name.\r\n2. The iron knuckle was not fought against with magic.\r\n3. The girl fought the octorock.\r\n4. Link has a sword and did not fight the poe.\r\n5. Zelda fought with the bow and arrows.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLink, Iron Knuckle, Sword\n\r\nZelda, Octorock, Bow and Arrows\n\r\nGanondorf, Poe, Magic\n<|im_start|>answer\nLink, Iron Knuckle, Sword\n\r\nZelda, Octorock, Bow and Arrows\n\r\nGanondorf, Poe, Magic\n<|im_end|>" }, { "id": "#2735", "title": "Two Numbers", "fun": 2.08, "difficulty": 1.25, "author": "zoltan_90", "desc": "What numbers when added or multiplied together produce the same result both ways?", "hint": "No hint available.", "answer": "2 and 2 or 0 and 0", "category": "Math", "date": "03/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat numbers when added or multiplied together produce the same result both ways?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2 and 2 or 0 and 0\n<|im_start|>answer\n2 and 2 or 0 and 0\n<|im_end|>" }, { "id": "#3959", "title": "Bob and Rob", "fun": 2.08, "difficulty": 1.21, "author": "mad-ade", "desc": "Bob is forty, Rob is thirteen. How many years ago was Bob 4 times older than Rob?", "hint": "No hint available.", "answer": "4 years ago.\r\nBob 36\r\nRob 9", "category": "Math", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob is forty, Rob is thirteen. How many years ago was Bob 4 times older than Rob?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 years ago.\r\nBob 36\r\nRob 9\n<|im_start|>answer\n4 years ago.\r\nBob 36\r\nRob 9\n<|im_end|>" }, { "id": "#36433", "title": "After School Activities For Merry, Pippin and Kate", "fun": 2.08, "difficulty": 0.78, "author": "merrypippin246", "desc": "Merry, Pippin, and Kate all have after school activities. Your job is to find out who does what activity and when they do it. \r\nPeople: Merry, Pippin, and Kate\n\r\nAfter school activities: swimming, running, and gymnastics\n\r\nDays: Wednesday, Thursday, and Friday\n\r\nClues:\r\n1) After school on Thursday, the swimmer goes to lessons.\r\n2) Kate's activity happens every Friday.\r\n3) Pippin is training to be a runner.", "hint": "No hint available.", "answer": "Merry - Swimming - Thursday\r\nPippin - Running - Wednesday\r\nKate - Gymnastics - Friday", "category": "Logic-Grid", "date": "04/27/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMerry, Pippin, and Kate all have after school activities. Your job is to find out who does what activity and when they do it. \r\nPeople: Merry, Pippin, and Kate\n\r\nAfter school activities: swimming, running, and gymnastics\n\r\nDays: Wednesday, Thursday, and Friday\n\r\nClues:\r\n1) After school on Thursday, the swimmer goes to lessons.\r\n2) Kate's activity happens every Friday.\r\n3) Pippin is training to be a runner.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMerry - Swimming - Thursday\r\nPippin - Running - Wednesday\r\nKate - Gymnastics - Friday\n<|im_start|>answer\nMerry - Swimming - Thursday\r\nPippin - Running - Wednesday\r\nKate - Gymnastics - Friday\n<|im_end|>" }, { "id": "#2613", "title": "Squirrel", "fun": 2.08, "difficulty": 1.8, "author": "204_BLaZe_41", "desc": "Suppose a squirrel is behind the trunk of a tree, which it keeps between itself and a hunter who is circling the tree. In this case does the hunter actually walk around the squirrel?", "hint": "No hint available.", "answer": "Yes he does! To go around is to encircle entirely about. Therefore, this would ignore any rotary motion of the object being circled, in this case, the squirrel. The hunter does go around the squirrel since the hunter goes around the tree which the squirrel has not left.", "category": "Logic", "date": "03/09/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSuppose a squirrel is behind the trunk of a tree, which it keeps between itself and a hunter who is circling the tree. In this case does the hunter actually walk around the squirrel?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYes he does! To go around is to encircle entirely about. Therefore, this would ignore any rotary motion of the object being circled, in this case, the squirrel. The hunter does go around the squirrel since the hunter goes around the tree which the squirrel has not left.\n<|im_start|>answer\nYes he does! To go around is to encircle entirely about. Therefore, this would ignore any rotary motion of the object being circled, in this case, the squirrel. The hunter does go around the squirrel since the hunter goes around the tree which the squirrel has not left.\n<|im_end|>" }, { "id": "#2294", "title": "Pokemon", "fun": 2.08, "difficulty": 1.59, "author": "jokester8000", "desc": "Little Jon is playing with some Pokemon cards. His hit points stands like this: 100 out of 200. He has two cards that will heal him halfway each. If he uses both cards how many hit points would he have left?", "hint": "No hint available.", "answer": "175 out of 200", "category": "Math", "date": "02/11/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLittle Jon is playing with some Pokemon cards. His hit points stands like this: 100 out of 200. He has two cards that will heal him halfway each. If he uses both cards how many hit points would he have left?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n175 out of 200\n<|im_start|>answer\n175 out of 200\n<|im_end|>" }, { "id": "#38725", "title": "Keeping Track", "fun": 2.08, "difficulty": 0.85, "author": "rcb2049", "desc": "Mrs. Bunselmyer, the principal, was trying to keep track of all after school activities. She has 5 left to go and needs some help. All she has to decipher this are these clues.\n\r\nFIRST NAMES: Jimmy, Rachel, Eric, Melissa, and Joe\r\nLAST NAMES: Brady, James, Bizzell, Dirt, Thompson\r\nACTIVITIES: Band, Key Club, Student Council, Chorus, and Tutoring\n\r\n1. Rachel is a straight A student.\r\n2. Mr. Bizzell wants to join the local Kiwanis.\r\n3. Joe's last name is not Dirt.\r\n4. Jimmy loves his Tuba.\r\n5. Mr. James was elected by the student body.\r\n6. Melissa loves to sing.\r\n7. Mr. Dirt loves his Tuba.\r\n8. Ms. Brady is a straight A student.\r\n9. Joe was elected president by the student body.\r\n10. Eric loves unlocking things.", "hint": "The student in tutoring is helping struggling kids.", "answer": "Jimmy Dirt-Band\r\nRachel Brady-Tutoring\r\nEric Bizzell-Key Club\r\nMelissa Thompson-Chorus\r\nJoe James-Student Council", "category": "Logic-Grid", "date": "10/11/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMrs. Bunselmyer, the principal, was trying to keep track of all after school activities. She has 5 left to go and needs some help. All she has to decipher this are these clues.\n\r\nFIRST NAMES: Jimmy, Rachel, Eric, Melissa, and Joe\r\nLAST NAMES: Brady, James, Bizzell, Dirt, Thompson\r\nACTIVITIES: Band, Key Club, Student Council, Chorus, and Tutoring\n\r\n1. Rachel is a straight A student.\r\n2. Mr. Bizzell wants to join the local Kiwanis.\r\n3. Joe's last name is not Dirt.\r\n4. Jimmy loves his Tuba.\r\n5. Mr. James was elected by the student body.\r\n6. Melissa loves to sing.\r\n7. Mr. Dirt loves his Tuba.\r\n8. Ms. Brady is a straight A student.\r\n9. Joe was elected president by the student body.\r\n10. Eric loves unlocking things.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJimmy Dirt-Band\r\nRachel Brady-Tutoring\r\nEric Bizzell-Key Club\r\nMelissa Thompson-Chorus\r\nJoe James-Student Council\n<|im_start|>answer\nJimmy Dirt-Band\r\nRachel Brady-Tutoring\r\nEric Bizzell-Key Club\r\nMelissa Thompson-Chorus\r\nJoe James-Student Council\n<|im_end|>" }, { "id": "#31282", "title": "Summer Jobs", "fun": 2.08, "difficulty": 1.1, "author": "Tammy93", "desc": "Ansa, Joe, and Trevor all work at a summer park. One of them is a day camp director, one a lifeguard, and one a swim team coach. Because of their jobs, they wear different colored shirts to work.\n\r\nAnsa, Joe, and Trevor had a meeting. Joe said that his swim team would have practice tomorrow. Joe told the person wearing the blue shirt that he was working late tomorrow. Trevor told the lifeguard that the other guards should also wear red shirts when they work. Then, the person wearing the green shirt left the meeting.\n\r\nWhat is each person's job, and what color shirt is each person wearing?", "hint": "No hint available.", "answer": "Ansa is the lifeguard and wears a red shirt.\r\nJoe is the swim team coach and wears a green shirt.\r\nTrevor is the camp director and wears a blue shirt.", "category": "Logic-Grid", "date": "06/23/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAnsa, Joe, and Trevor all work at a summer park. One of them is a day camp director, one a lifeguard, and one a swim team coach. Because of their jobs, they wear different colored shirts to work.\n\r\nAnsa, Joe, and Trevor had a meeting. Joe said that his swim team would have practice tomorrow. Joe told the person wearing the blue shirt that he was working late tomorrow. Trevor told the lifeguard that the other guards should also wear red shirts when they work. Then, the person wearing the green shirt left the meeting.\n\r\nWhat is each person's job, and what color shirt is each person wearing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnsa is the lifeguard and wears a red shirt.\r\nJoe is the swim team coach and wears a green shirt.\r\nTrevor is the camp director and wears a blue shirt.\n<|im_start|>answer\nAnsa is the lifeguard and wears a red shirt.\r\nJoe is the swim team coach and wears a green shirt.\r\nTrevor is the camp director and wears a blue shirt.\n<|im_end|>" }, { "id": "#33059", "title": "Snappy's Potions", "fun": 2.08, "difficulty": 0.5, "author": "12345_lewis2", "desc": "Help! Snappy (a VERY forgetful successor of Snape) has forgotten which potion goes where, or what it does!\n\r\nColors: Red, Green, Blue\r\nPlaces: Shelf, Floor, Table\r\nEffects: Invisibility, Polyjuice, Luck\n\r\n1. He remembers that the Polyjuice Potion goes on the shelf, but it was clearly not red.\n\r\n2. The Luck Potion would break if placed on the floor. Snappy would NOT like that! It is not red.\n\r\n3. The Polyjuice potion is not blue.", "hint": "No hint available.", "answer": "Polyjuice Potion: green, on shelf\r\nLuck Potion: blue, on table\r\nInvisibility: red, on floor", "category": "Logic-Grid", "date": "09/18/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHelp! Snappy (a VERY forgetful successor of Snape) has forgotten which potion goes where, or what it does!\n\r\nColors: Red, Green, Blue\r\nPlaces: Shelf, Floor, Table\r\nEffects: Invisibility, Polyjuice, Luck\n\r\n1. He remembers that the Polyjuice Potion goes on the shelf, but it was clearly not red.\n\r\n2. The Luck Potion would break if placed on the floor. Snappy would NOT like that! It is not red.\n\r\n3. The Polyjuice potion is not blue.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPolyjuice Potion: green, on shelf\r\nLuck Potion: blue, on table\r\nInvisibility: red, on floor\n<|im_start|>answer\nPolyjuice Potion: green, on shelf\r\nLuck Potion: blue, on table\r\nInvisibility: red, on floor\n<|im_end|>" }, { "id": "#23849", "title": "Pizza", "fun": 2.07, "difficulty": 1.55, "author": "qwerty7", "desc": "Al and Sally buy a small and a medium pizza. The small pizza has 5 slices. The medium pepperoni pizza has 8 slices. If Sally eats 4 times as many slices as Al, and is a vegetarian, how many slices of pizza did she eat?", "hint": "No hint available.", "answer": "4 slices. Al must only have eaten one.", "category": "Math", "date": "06/21/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAl and Sally buy a small and a medium pizza. The small pizza has 5 slices. The medium pepperoni pizza has 8 slices. If Sally eats 4 times as many slices as Al, and is a vegetarian, how many slices of pizza did she eat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4 slices. Al must only have eaten one.\n<|im_start|>answer\n4 slices. Al must only have eaten one.\n<|im_end|>" }, { "id": "#38782", "title": "Shirts, Pants, and Hats", "fun": 2.07, "difficulty": 1.1, "author": "luna_lovegood", "desc": "Bobby has 5 shirts: red, blue, green, yellow, and black. He has 4 hats, red, blue, green, and black. He has 3 pairs of pants. How many outfits can he make?", "hint": "No hint available.", "answer": "5 x 4 x 3 = 60\n\r\nHe can make sixty outfits.", "category": "Math", "date": "10/15/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBobby has 5 shirts: red, blue, green, yellow, and black. He has 4 hats, red, blue, green, and black. He has 3 pairs of pants. How many outfits can he make?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 x 4 x 3 = 60\n\r\nHe can make sixty outfits.\n<|im_start|>answer\n5 x 4 x 3 = 60\n\r\nHe can make sixty outfits.\n<|im_end|>" }, { "id": "#35998", "title": "Foods and Neighborhoods", "fun": 2.07, "difficulty": 0.68, "author": "nascarfan19", "desc": "Austin, Mary, and Zachary all have different favorite foods. They also live in three different neighborhoods in Chelsea, Missouri.\n\r\nNames - Austin, Mary, Zachary\r\nFoods - Cheeseburger, Ice Cream, Pizza\r\nNeighborhoods - Cherry Hills, Old Fairway, Nantucket\n\r\n1) Whoever likes the ice cream lives in Nantucket.\r\n2) Whoever lives in Cherry Hills, his/her favorite food is not the cheeseburger.\r\n3) Mary lives in Old Fairway.\r\n4) Zachary lives in Cherry Hills.", "hint": "No hint available.", "answer": "Austin - Ice Cream, Nantucket\r\nMary - Cheeseburger, Old Fairway\r\nZachary - Pizza, Cherry Hills", "category": "Logic-Grid", "date": "04/01/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAustin, Mary, and Zachary all have different favorite foods. They also live in three different neighborhoods in Chelsea, Missouri.\n\r\nNames - Austin, Mary, Zachary\r\nFoods - Cheeseburger, Ice Cream, Pizza\r\nNeighborhoods - Cherry Hills, Old Fairway, Nantucket\n\r\n1) Whoever likes the ice cream lives in Nantucket.\r\n2) Whoever lives in Cherry Hills, his/her favorite food is not the cheeseburger.\r\n3) Mary lives in Old Fairway.\r\n4) Zachary lives in Cherry Hills.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAustin - Ice Cream, Nantucket\r\nMary - Cheeseburger, Old Fairway\r\nZachary - Pizza, Cherry Hills\n<|im_start|>answer\nAustin - Ice Cream, Nantucket\r\nMary - Cheeseburger, Old Fairway\r\nZachary - Pizza, Cherry Hills\n<|im_end|>" }, { "id": "#45193", "title": "Red to Black", "fun": 2.07, "difficulty": 1.85, "author": "Omaha345", "desc": "What goes into the water red and comes out black?", "hint": "No hint available.", "answer": "A red-hot poker", "category": "Logic", "date": "08/31/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat goes into the water red and comes out black?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA red-hot poker\n<|im_start|>answer\nA red-hot poker\n<|im_end|>" }, { "id": "#20421", "title": "The Trip", "fun": 2.07, "difficulty": 1.08, "author": "holly1447591", "desc": "A family took a trip to a city. The trip was to be one hour long. They left at 6:00 and got there at 6:00. What happened?", "hint": "No hint available.", "answer": "The city was an hour behind them.", "category": "Logic", "date": "01/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA family took a trip to a city. The trip was to be one hour long. They left at 6:00 and got there at 6:00. What happened?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe city was an hour behind them.\n<|im_start|>answer\nThe city was an hour behind them.\n<|im_end|>" }, { "id": "#20401", "title": "Birthday Party", "fun": 2.07, "difficulty": 0.76, "author": "hcut3", "desc": "Five guests arrived to little Latoya's B-day at 5 different times with 5 different presents. The children were Andrea, Joseph, Anthony, Brian, and Hannah. The times they arrived were noon, 12:02 p.m, 12:07 p.m.. 12:09 p.m., and 12:13 p.m. The presents that Latoya received were a doll, ball, card with money, clothes, and a game. Figure out who brought which gift and at what time they had arrived to the party.\n\r\n1)Joseph was first and Anthony was right after him and neither of them brought the ball or clothes.\n\r\n2) A boy did not bring the doll.\n\r\n3) Hannah was not last and she did not bring the doll.\n\r\n4) Brian was after Hannah but before Andrea and he did not bring the game, clothes, or card with money.\n\r\n5) Andrea told Latoya that she heard the 1st person tell the 3rd person that the 2nd person had given her a card with some money in it for her birthday.", "hint": "No hint available.", "answer": "Joseph-Game-12:00\r\nAnthony-Card with money-12:02\r\nHannah-Clothes-12:07\r\nBrian-Ball-12:09\r\nAndrea-Doll-12:13", "category": "Logic-Grid", "date": "01/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFive guests arrived to little Latoya's B-day at 5 different times with 5 different presents. The children were Andrea, Joseph, Anthony, Brian, and Hannah. The times they arrived were noon, 12:02 p.m, 12:07 p.m.. 12:09 p.m., and 12:13 p.m. The presents that Latoya received were a doll, ball, card with money, clothes, and a game. Figure out who brought which gift and at what time they had arrived to the party.\n\r\n1)Joseph was first and Anthony was right after him and neither of them brought the ball or clothes.\n\r\n2) A boy did not bring the doll.\n\r\n3) Hannah was not last and she did not bring the doll.\n\r\n4) Brian was after Hannah but before Andrea and he did not bring the game, clothes, or card with money.\n\r\n5) Andrea told Latoya that she heard the 1st person tell the 3rd person that the 2nd person had given her a card with some money in it for her birthday.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoseph-Game-12:00\r\nAnthony-Card with money-12:02\r\nHannah-Clothes-12:07\r\nBrian-Ball-12:09\r\nAndrea-Doll-12:13\n<|im_start|>answer\nJoseph-Game-12:00\r\nAnthony-Card with money-12:02\r\nHannah-Clothes-12:07\r\nBrian-Ball-12:09\r\nAndrea-Doll-12:13\n<|im_end|>" }, { "id": "#44561", "title": "First Date", "fun": 2.07, "difficulty": 1.94, "author": "whsprec", "desc": "Six couples at a party were talking about where they met and what they did on their first date. However, at the end of the night all the items were in the correct column, but only one item was in the correct row. Find the correct husband and wife, where they met, and what they did for their first date.\n\r\nHusband Wife Met Date\r\nMike Kenya High School Dance\r\nTommy Kristin College Boating\r\nDaniel Casey Blind-date Riding\r\nQuentin Rose Work Concert\r\nAaron Daisy Neighbors Play\r\nHenry Janet Class Skating\n\r\n1- Quentin is one place above Janet.\r\n2- Boating is one place below Kristin, but one above Daniel.\r\n3- Work was two places below Tommy, but three places below Casey.\r\n4-Tommy is not adjacent to Aaron.\r\n5- Blind-date is one place below Play.\r\n6- Aaron is one place above Skating but two below High School.\r\n7- Kenya is one place above Concert but three above Neighbors.", "hint": "No hint available.", "answer": "Husband Wife Met Date\r\nHenry Kenya College Play\r\nQuentin Casey Blind-date Concert\r\nTommy Janet High School Dance\r\nMike Kristin Neighbors Riding\r\nAaron Rose Work Boating\r\nDaniel Daisy Class Skating", "category": "Logic", "date": "06/03/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix couples at a party were talking about where they met and what they did on their first date. However, at the end of the night all the items were in the correct column, but only one item was in the correct row. Find the correct husband and wife, where they met, and what they did for their first date.\n\r\nHusband Wife Met Date\r\nMike Kenya High School Dance\r\nTommy Kristin College Boating\r\nDaniel Casey Blind-date Riding\r\nQuentin Rose Work Concert\r\nAaron Daisy Neighbors Play\r\nHenry Janet Class Skating\n\r\n1- Quentin is one place above Janet.\r\n2- Boating is one place below Kristin, but one above Daniel.\r\n3- Work was two places below Tommy, but three places below Casey.\r\n4-Tommy is not adjacent to Aaron.\r\n5- Blind-date is one place below Play.\r\n6- Aaron is one place above Skating but two below High School.\r\n7- Kenya is one place above Concert but three above Neighbors.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHusband Wife Met Date\r\nHenry Kenya College Play\r\nQuentin Casey Blind-date Concert\r\nTommy Janet High School Dance\r\nMike Kristin Neighbors Riding\r\nAaron Rose Work Boating\r\nDaniel Daisy Class Skating\n<|im_start|>answer\nHusband Wife Met Date\r\nHenry Kenya College Play\r\nQuentin Casey Blind-date Concert\r\nTommy Janet High School Dance\r\nMike Kristin Neighbors Riding\r\nAaron Rose Work Boating\r\nDaniel Daisy Class Skating\n<|im_end|>" }, { "id": "#5880", "title": "Reverse Engineering", "fun": 2.07, "difficulty": 2.86, "author": "dewtell", "desc": "While rating some Braingle teasers recently, I started taking notes on how my\r\nvote affected the ratings. Some of my data is presented below. Can you figure out what is the likely formula that computes the ratings from the votes? Can you determine for each teaser how many votes were cast for each attribute prior to mine, and how many of those were positive (fun/hard)? Remember, not every voter necessarily votes for both attributes.\n\r\nNotation: The notation for Teaser A below shows that it started with a fun rating of 2 and difficulty 1.33, based on 6 voters, that I voted positively on the first attribute (fun) and negatively on the second (easy), and that it wound up with ratings of 2.29 and 1.14, respectively, after my vote.\n\r\nTeaser A: (2.00, 1.33)[6] (+, -) -> (2.29, 1.14)\r\nTeaser B: (1.14, 0.67)[7] (-, -) -> (1.00, 0.57)\r\nTeaser C: (3.00, 0.67)[8] (+, +) -> (3.11, 1.14)\r\nTeaser D: (3.11, 0.89)[9] (+, -) -> (3.20, 0.80)\r\nTeaser E: (2.33, 2.46)[13] (+, -) -> (2.46, 2.29)", "hint": "Try to recognize common fractions represented by the decimal\r\npart of each rating. Also: remember that the ratings range from 0 to 4.", "answer": "The apparent formula, for p positive votes out of v cast, is 4*p/v. The following lists the fractions that gave rise to the data above. To get the number of positive votes, divide the numerators by 4.\n\r\nTeaser A: (12/6, 8/6)[6] (+, -) -> (16/7, 8/7)\r\nTeaser B: (8/7, 4/6)[7] (-, -) -> (8/8, 4/7)\r\nTeaser C: (24/8, 4/6)[8] (+, +) -> (28/9, 8/7)\r\nTeaser D: (28/9, 8/9)[9] (+, -) -> (32/10, 8/10)\r\nTeaser E: (28/12, 32/13)[13] (+, -) -> (32/13, 32/14)", "category": "Math", "date": "07/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile rating some Braingle teasers recently, I started taking notes on how my\r\nvote affected the ratings. Some of my data is presented below. Can you figure out what is the likely formula that computes the ratings from the votes? Can you determine for each teaser how many votes were cast for each attribute prior to mine, and how many of those were positive (fun/hard)? Remember, not every voter necessarily votes for both attributes.\n\r\nNotation: The notation for Teaser A below shows that it started with a fun rating of 2 and difficulty 1.33, based on 6 voters, that I voted positively on the first attribute (fun) and negatively on the second (easy), and that it wound up with ratings of 2.29 and 1.14, respectively, after my vote.\n\r\nTeaser A: (2.00, 1.33)[6] (+, -) -> (2.29, 1.14)\r\nTeaser B: (1.14, 0.67)[7] (-, -) -> (1.00, 0.57)\r\nTeaser C: (3.00, 0.67)[8] (+, +) -> (3.11, 1.14)\r\nTeaser D: (3.11, 0.89)[9] (+, -) -> (3.20, 0.80)\r\nTeaser E: (2.33, 2.46)[13] (+, -) -> (2.46, 2.29)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe apparent formula, for p positive votes out of v cast, is 4*p/v. The following lists the fractions that gave rise to the data above. To get the number of positive votes, divide the numerators by 4.\n\r\nTeaser A: (12/6, 8/6)[6] (+, -) -> (16/7, 8/7)\r\nTeaser B: (8/7, 4/6)[7] (-, -) -> (8/8, 4/7)\r\nTeaser C: (24/8, 4/6)[8] (+, +) -> (28/9, 8/7)\r\nTeaser D: (28/9, 8/9)[9] (+, -) -> (32/10, 8/10)\r\nTeaser E: (28/12, 32/13)[13] (+, -) -> (32/13, 32/14)\n<|im_start|>answer\nThe apparent formula, for p positive votes out of v cast, is 4*p/v. The following lists the fractions that gave rise to the data above. To get the number of positive votes, divide the numerators by 4.\n\r\nTeaser A: (12/6, 8/6)[6] (+, -) -> (16/7, 8/7)\r\nTeaser B: (8/7, 4/6)[7] (-, -) -> (8/8, 4/7)\r\nTeaser C: (24/8, 4/6)[8] (+, +) -> (28/9, 8/7)\r\nTeaser D: (28/9, 8/9)[9] (+, -) -> (32/10, 8/10)\r\nTeaser E: (28/12, 32/13)[13] (+, -) -> (32/13, 32/14)\n<|im_end|>" }, { "id": "#2166", "title": "Mirror Image", "fun": 2.07, "difficulty": 1.3, "author": "Cascas", "desc": "If you saw yourself in a mirror holding a letter d in your left hand, what would you be doing?", "hint": "No hint available.", "answer": "Holding a letter b in your right hand.", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you saw yourself in a mirror holding a letter d in your left hand, what would you be doing?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHolding a letter b in your right hand.\n<|im_start|>answer\nHolding a letter b in your right hand.\n<|im_end|>" }, { "id": "#27646", "title": "It's Party Time!", "fun": 2.07, "difficulty": 0.89, "author": "zigthepig", "desc": "Zig has a party coming up soon and has to decide which things should she get of what colour and where she should get them from. Using the clues can you decide what she chose and where she got each thing?\n\r\n1. The balloon is red.\r\n2. The cake isn't blue.\r\n3. The silly string isn't orange.\r\n4. The party hat is orange.\r\n5. The cake is from Decoeat.\r\n6. The silly string isn't from Party Cracks.\r\n7. The Balloon is not from Canso.\r\n8. The Party Hat is from Party Cracks.", "hint": "No hint available.", "answer": "Balloon, Red, Pops.\r\nCake, Green, Decoeat.\r\nSilly String, Blue, Canso.\r\nParty Hat, Orange, Party Cracks", "category": "Logic-Grid", "date": "12/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nZig has a party coming up soon and has to decide which things should she get of what colour and where she should get them from. Using the clues can you decide what she chose and where she got each thing?\n\r\n1. The balloon is red.\r\n2. The cake isn't blue.\r\n3. The silly string isn't orange.\r\n4. The party hat is orange.\r\n5. The cake is from Decoeat.\r\n6. The silly string isn't from Party Cracks.\r\n7. The Balloon is not from Canso.\r\n8. The Party Hat is from Party Cracks.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBalloon, Red, Pops.\r\nCake, Green, Decoeat.\r\nSilly String, Blue, Canso.\r\nParty Hat, Orange, Party Cracks\n<|im_start|>answer\nBalloon, Red, Pops.\r\nCake, Green, Decoeat.\r\nSilly String, Blue, Canso.\r\nParty Hat, Orange, Party Cracks\n<|im_end|>" }, { "id": "#21288", "title": "Quocorrian Math 1", "fun": 2.07, "difficulty": 2.98, "author": "CPlusPlusMan", "desc": "While on your interplanetary vacation, you decide to stop at the planet Quocorri, a planet known for its many mathematical achievements.\n\r\nWhile there, you decide to pick up on some of the Quocorrians mathematical variations. The Quocorrians won't tell you exactly how it works, only that it has some relationship to the Standard English math. They also give you four, true, Quocorrian math problems. They are:\n\r\n2+2=9\r\n4*1=1\r\n5-2=16\r\n-3+2=64\n\r\nSo, according to this system, what is 6/2?", "hint": "The system is not a number system (decimal, binary, hexadecimal...), but a variation of the way we do math.", "answer": "81. \r\nIn this system of Quocorrian math, you change the operation to its opposite (+ to -, * to / and vice versa), and solve regularly. Then, you subtract three from that answer. Finally, you square that to get your answer.", "category": "Math", "date": "03/01/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhile on your interplanetary vacation, you decide to stop at the planet Quocorri, a planet known for its many mathematical achievements.\n\r\nWhile there, you decide to pick up on some of the Quocorrians mathematical variations. The Quocorrians won't tell you exactly how it works, only that it has some relationship to the Standard English math. They also give you four, true, Quocorrian math problems. They are:\n\r\n2+2=9\r\n4*1=1\r\n5-2=16\r\n-3+2=64\n\r\nSo, according to this system, what is 6/2?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n81. \r\nIn this system of Quocorrian math, you change the operation to its opposite (+ to -, * to / and vice versa), and solve regularly. Then, you subtract three from that answer. Finally, you square that to get your answer.\n<|im_start|>answer\n81. \r\nIn this system of Quocorrian math, you change the operation to its opposite (+ to -, * to / and vice versa), and solve regularly. Then, you subtract three from that answer. Finally, you square that to get your answer.\n<|im_end|>" }, { "id": "#22206", "title": "Picture Day!", "fun": 2.07, "difficulty": 0.79, "author": "mpspss", "desc": "It was picture day and everyone was getting their pictures taken. May, Alex, and Eric got their pictures taken at different times. It was either 9:00 AM, 11:30 AM, or 2:15 PM. They also had different hair colors. It was either red, black, or blond.\n\r\n1) May does not have black hair.\r\n2) Eric got his picture taken after 1:00 PM.\r\n3) Alex has red hair.\r\n4) Alex had lunch between the hours of 11:00 AM and 2:45 PM.", "hint": "No hint available.", "answer": "May has blond hair and got her picture taken at 11:30 AM.\n\r\nAlex has red hair and got his photo taken at 9:00 AM.\n\r\nEric has black hair and got his photo taken at 2:15 PM.", "category": "Logic-Grid", "date": "04/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIt was picture day and everyone was getting their pictures taken. May, Alex, and Eric got their pictures taken at different times. It was either 9:00 AM, 11:30 AM, or 2:15 PM. They also had different hair colors. It was either red, black, or blond.\n\r\n1) May does not have black hair.\r\n2) Eric got his picture taken after 1:00 PM.\r\n3) Alex has red hair.\r\n4) Alex had lunch between the hours of 11:00 AM and 2:45 PM.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMay has blond hair and got her picture taken at 11:30 AM.\n\r\nAlex has red hair and got his photo taken at 9:00 AM.\n\r\nEric has black hair and got his photo taken at 2:15 PM.\n<|im_start|>answer\nMay has blond hair and got her picture taken at 11:30 AM.\n\r\nAlex has red hair and got his photo taken at 9:00 AM.\n\r\nEric has black hair and got his photo taken at 2:15 PM.\n<|im_end|>" }, { "id": "#49538", "title": "Go Team!", "fun": 2.07, "difficulty": 1.12, "author": "fishmed", "desc": "The following table represents the attendance at Still's High School football games this month. \n\r\nGame 1: 456\r\nGame 2: 508\r\nGame 3: 399\r\nGame 4: 550\r\nGame 5: n\n\r\nIf the median attendance for the five games was 456, and no two games had the same attendance, which of the following numbers represents the highest possible attendance for game 5? \n\r\n400, 455, 457, 478, 549", "hint": "No hint available.", "answer": "The median of five numbers can be found by putting the numbers in increasing order and picking the middle, or third, number from the list. Putting the four numbers you know in increasing order produces the following list:\n\r\n399, 456, 508, 550\n\r\nAs the median is 456, it has to be the middle number of the list of five. That being said, the highest possible attendance of the list given, and the answer to this teaser is, 455.", "category": "Math", "date": "07/21/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe following table represents the attendance at Still's High School football games this month. \n\r\nGame 1: 456\r\nGame 2: 508\r\nGame 3: 399\r\nGame 4: 550\r\nGame 5: n\n\r\nIf the median attendance for the five games was 456, and no two games had the same attendance, which of the following numbers represents the highest possible attendance for game 5? \n\r\n400, 455, 457, 478, 549\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe median of five numbers can be found by putting the numbers in increasing order and picking the middle, or third, number from the list. Putting the four numbers you know in increasing order produces the following list:\n\r\n399, 456, 508, 550\n\r\nAs the median is 456, it has to be the middle number of the list of five. That being said, the highest possible attendance of the list given, and the answer to this teaser is, 455.\n<|im_start|>answer\nThe median of five numbers can be found by putting the numbers in increasing order and picking the middle, or third, number from the list. Putting the four numbers you know in increasing order produces the following list:\n\r\n399, 456, 508, 550\n\r\nAs the median is 456, it has to be the middle number of the list of five. That being said, the highest possible attendance of the list given, and the answer to this teaser is, 455.\n<|im_end|>" }, { "id": "#43006", "title": "The Soccer Ball Logic Grid", "fun": 2.07, "difficulty": 0.56, "author": "beatlesman12", "desc": "Four friends own different color soccer balls in different sizes. Determine who has what color soccer ball and what size it is.\n\r\nKids: Ian, Jessica, Henry, Will\r\nColors: Red, White, Blue, Green\r\nSize: 2, 3, 4, 5\n\r\n1. None of the boys own a white soccer ball.\r\n2. Ian has a ball that is bigger than a 2 but smaller than a 5.\r\n3. The kids are Jessica, the kid with the red size 4 soccer ball, Henry and his green ball, and Will.\r\n4. Will has a size 3 soccer ball.\r\n5. Jessica does not have a size 5.", "hint": "Size 2 is the smallest size and 5 is the biggest.", "answer": "Ian, Red, 4\r\nJessica, White, 2\r\nHenry, Green, 5\r\nWill, Blue, 3", "category": "Logic-Grid", "date": "09/06/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour friends own different color soccer balls in different sizes. Determine who has what color soccer ball and what size it is.\n\r\nKids: Ian, Jessica, Henry, Will\r\nColors: Red, White, Blue, Green\r\nSize: 2, 3, 4, 5\n\r\n1. None of the boys own a white soccer ball.\r\n2. Ian has a ball that is bigger than a 2 but smaller than a 5.\r\n3. The kids are Jessica, the kid with the red size 4 soccer ball, Henry and his green ball, and Will.\r\n4. Will has a size 3 soccer ball.\r\n5. Jessica does not have a size 5.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIan, Red, 4\r\nJessica, White, 2\r\nHenry, Green, 5\r\nWill, Blue, 3\n<|im_start|>answer\nIan, Red, 4\r\nJessica, White, 2\r\nHenry, Green, 5\r\nWill, Blue, 3\n<|im_end|>" }, { "id": "#10436", "title": "Circle", "fun": 2.07, "difficulty": 1.81, "author": "ka-boom", "desc": "Imagine a square, with each side 4 cm long, inscribed in a circle. What is the radius of the circle?", "hint": "No hint available.", "answer": "Since each corner is touching the circle, find the hypotenuse using the Pythagorean Theorem:\n\r\n4^2 + 4^2 = x^2\r\nx = Hypotenuse = 5.657\r\nDivide by 2 to get the radius:\r\nRadius = 2.828", "category": "Math", "date": "02/14/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImagine a square, with each side 4 cm long, inscribed in a circle. What is the radius of the circle?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSince each corner is touching the circle, find the hypotenuse using the Pythagorean Theorem:\n\r\n4^2 + 4^2 = x^2\r\nx = Hypotenuse = 5.657\r\nDivide by 2 to get the radius:\r\nRadius = 2.828\n<|im_start|>answer\nSince each corner is touching the circle, find the hypotenuse using the Pythagorean Theorem:\n\r\n4^2 + 4^2 = x^2\r\nx = Hypotenuse = 5.657\r\nDivide by 2 to get the radius:\r\nRadius = 2.828\n<|im_end|>" }, { "id": "#44631", "title": "Books, Books and more Books", "fun": 2.07, "difficulty": 0.53, "author": "brainyboy615", "desc": "Jake, John, Joe, and Jack each have a different favorite book series. These include \"Harry Potter\", \"The Lord of the Rings\", \"Sherlock Holmes\", and \"The Hardy Boys\". Using the clues, figure out who likes which book series.\n\r\n1. Jake and Joe love mysteries, while John and Jack prefer magic and fantasy.\n\r\n2. \"Joe\" is the name of a character in Joe's favorite series. \n\r\n3. John's Halloween costume, based on his favorite series, includes glasses and a black robe.", "hint": "\"Sherlock Holmes\" has no magic in it, and \"The Lord of the Rings\" is not a mystery.", "answer": "Jake - \"Sherlock Holmes\"\n\r\nJoe - \"The Hardy Boys\"\n\r\nJohn - \"Harry Potter\"\n\r\nJack - \"The Lord of the Rings\"", "category": "Logic", "date": "06/12/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJake, John, Joe, and Jack each have a different favorite book series. These include \"Harry Potter\", \"The Lord of the Rings\", \"Sherlock Holmes\", and \"The Hardy Boys\". Using the clues, figure out who likes which book series.\n\r\n1. Jake and Joe love mysteries, while John and Jack prefer magic and fantasy.\n\r\n2. \"Joe\" is the name of a character in Joe's favorite series. \n\r\n3. John's Halloween costume, based on his favorite series, includes glasses and a black robe.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJake - \"Sherlock Holmes\"\n\r\nJoe - \"The Hardy Boys\"\n\r\nJohn - \"Harry Potter\"\n\r\nJack - \"The Lord of the Rings\"\n<|im_start|>answer\nJake - \"Sherlock Holmes\"\n\r\nJoe - \"The Hardy Boys\"\n\r\nJohn - \"Harry Potter\"\n\r\nJack - \"The Lord of the Rings\"\n<|im_end|>" }, { "id": "#7130", "title": "Ascending Order", "fun": 2.07, "difficulty": 2.4, "author": "neo1", "desc": "Arrange the following numbers in ascending order without using a calculator.\n\r\n2^6666 , 3^3333 , 6^2222", "hint": "No hint available.", "answer": "3^3333<6^2222<2^6666", "category": "Math", "date": "09/02/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nArrange the following numbers in ascending order without using a calculator.\n\r\n2^6666 , 3^3333 , 6^2222\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3^3333<6^2222<2^6666\n<|im_start|>answer\n3^3333<6^2222<2^6666\n<|im_end|>" }, { "id": "#17394", "title": "Mad Ade's Kebab Essay", "fun": 2.07, "difficulty": 2.86, "author": "mad-ade", "desc": "When Mad Ade was at University he completed an essay on \"The molecular construction of a standard Kebab\". After printing the work he was surprised to find that the number of digits used to number all the pages was a multiple of the number of actual pages the essay contained. \n\r\nUsing this information can you work out how many pages the essay contained in total? \r\nJust to help, the essay was more than 1000 pages but less than 10,000 pages.", "hint": "No hint available.", "answer": "1107 pages. \n\r\nThe number of digits used to number all the pages is 3321. \r\n1-9: 9 digits \r\n10-99: 180 digits \r\n100-999: 2700 digits \r\n1000-1107: 432 digits \r\nTotal: 3321 digits \n\r\n3321/1107= 3", "category": "Math", "date": "04/18/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhen Mad Ade was at University he completed an essay on \"The molecular construction of a standard Kebab\". After printing the work he was surprised to find that the number of digits used to number all the pages was a multiple of the number of actual pages the essay contained. \n\r\nUsing this information can you work out how many pages the essay contained in total? \r\nJust to help, the essay was more than 1000 pages but less than 10,000 pages.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1107 pages. \n\r\nThe number of digits used to number all the pages is 3321. \r\n1-9: 9 digits \r\n10-99: 180 digits \r\n100-999: 2700 digits \r\n1000-1107: 432 digits \r\nTotal: 3321 digits \n\r\n3321/1107= 3\n<|im_start|>answer\n1107 pages. \n\r\nThe number of digits used to number all the pages is 3321. \r\n1-9: 9 digits \r\n10-99: 180 digits \r\n100-999: 2700 digits \r\n1000-1107: 432 digits \r\nTotal: 3321 digits \n\r\n3321/1107= 3\n<|im_end|>" }, { "id": "#5289", "title": "One Million Seconds", "fun": 2.07, "difficulty": 1.91, "author": "mad-ade", "desc": "The year 2001 started at the midnight which falls between 31st December 2000 and 1st January 2001.\r\n What was the day, date and time exactly one million seconds later?", "hint": "No hint available.", "answer": "Friday 12th January, 13:46:40\r\nJust after a quarter to two in the afternoon.", "category": "Math", "date": "07/07/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe year 2001 started at the midnight which falls between 31st December 2000 and 1st January 2001.\r\n What was the day, date and time exactly one million seconds later?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriday 12th January, 13:46:40\r\nJust after a quarter to two in the afternoon.\n<|im_start|>answer\nFriday 12th January, 13:46:40\r\nJust after a quarter to two in the afternoon.\n<|im_end|>" }, { "id": "#187", "title": "`t` to the 1/8th power", "fun": 2.07, "difficulty": 2.49, "author": "trojan5x", "desc": "How might a mathematician describe a number `t` held to the following condition:\r\nWhen (t+1) is subtracted from t and the result is raised to the 1/8th power.", "hint": "No hint available.", "answer": "Imaginary Number.\r\nWhenever (t+1) is subtracted from `t`, you will simply be left with -1. -1 raised to the 1/8th power is the same as taking the positive root of something. When taking the positive root of any negative number, you are left with an imaginary number.", "category": "Math", "date": "02/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow might a mathematician describe a number `t` held to the following condition:\r\nWhen (t+1) is subtracted from t and the result is raised to the 1/8th power.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nImaginary Number.\r\nWhenever (t+1) is subtracted from `t`, you will simply be left with -1. -1 raised to the 1/8th power is the same as taking the positive root of something. When taking the positive root of any negative number, you are left with an imaginary number.\n<|im_start|>answer\nImaginary Number.\r\nWhenever (t+1) is subtracted from `t`, you will simply be left with -1. -1 raised to the 1/8th power is the same as taking the positive root of something. When taking the positive root of any negative number, you are left with an imaginary number.\n<|im_end|>" }, { "id": "#4936", "title": "Eleven Thousand", "fun": 2.06, "difficulty": 1.28, "author": "librashorty", "desc": "Write down the number eleven thousand, eleven hundred, and eleven. \n\r\nWhat do you have?", "hint": "No hint available.", "answer": "12,111", "category": "Math", "date": "06/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWrite down the number eleven thousand, eleven hundred, and eleven. \n\r\nWhat do you have?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12,111\n<|im_start|>answer\n12,111\n<|im_end|>" }, { "id": "#4228", "title": "Three Quarters", "fun": 2.06, "difficulty": 1.71, "author": "librashorty", "desc": "What number is three quarters of eight ninths of one half of 2001?", "hint": "No hint available.", "answer": "667", "category": "Math", "date": "05/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number is three quarters of eight ninths of one half of 2001?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n667\n<|im_start|>answer\n667\n<|im_end|>" }, { "id": "#24270", "title": "First Dates", "fun": 2.06, "difficulty": 0.76, "author": "irock3001", "desc": "Michelle, Loren, and Chelsea are going on their dates. Their date's names are David, Grant, and Dan, in no particular order. They each have a flower they are given on their dates. The flowers are: carnation, rose, and corsage, again, in no particular order.\n\r\nClues:\n\r\n1. The girl whose favorite flower was the corsage went out with Grant.\r\n2. Dan gave his date a rose.\r\n3. Michelle hates carnations. They make her think of spiders' webs, for whatever reason.\r\n4. Loren and Grant never really got along.\r\n5. Chelsea just can't stand Grant or Dan.", "hint": "The girl's favorite flower is the one they are given.", "answer": "Michelle went with Grant, and she got a corsage.\r\nLoren went with Dan, and she got a rose.\r\nChelsea went with David, and she got a carnation.", "category": "Logic-Grid", "date": "07/04/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMichelle, Loren, and Chelsea are going on their dates. Their date's names are David, Grant, and Dan, in no particular order. They each have a flower they are given on their dates. The flowers are: carnation, rose, and corsage, again, in no particular order.\n\r\nClues:\n\r\n1. The girl whose favorite flower was the corsage went out with Grant.\r\n2. Dan gave his date a rose.\r\n3. Michelle hates carnations. They make her think of spiders' webs, for whatever reason.\r\n4. Loren and Grant never really got along.\r\n5. Chelsea just can't stand Grant or Dan.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMichelle went with Grant, and she got a corsage.\r\nLoren went with Dan, and she got a rose.\r\nChelsea went with David, and she got a carnation.\n<|im_start|>answer\nMichelle went with Grant, and she got a corsage.\r\nLoren went with Dan, and she got a rose.\r\nChelsea went with David, and she got a carnation.\n<|im_end|>" }, { "id": "#48559", "title": "1 + 2; 2 + 3", "fun": 2.06, "difficulty": 2.39, "author": "Oxiproxd9", "desc": "In this scenario, 1 + 2 = 3. However, 2 + 3 = 4. What is the scenario?", "hint": "3 + 4 = 5\r\n4 + 5 = 6\r\n5 + 6 = 7", "answer": "The numbers are ordinal numbers, and the scenario is Fibonacci numbers.\n\r\n#1 is 0\r\n#2 is 1\r\n#3 is also 1\r\n#4 is 2\r\n#5 is 3\r\n#6 is 5\r\nand #7 is 8", "category": "Math", "date": "03/18/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn this scenario, 1 + 2 = 3. However, 2 + 3 = 4. What is the scenario?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe numbers are ordinal numbers, and the scenario is Fibonacci numbers.\n\r\n#1 is 0\r\n#2 is 1\r\n#3 is also 1\r\n#4 is 2\r\n#5 is 3\r\n#6 is 5\r\nand #7 is 8\n<|im_start|>answer\nThe numbers are ordinal numbers, and the scenario is Fibonacci numbers.\n\r\n#1 is 0\r\n#2 is 1\r\n#3 is also 1\r\n#4 is 2\r\n#5 is 3\r\n#6 is 5\r\nand #7 is 8\n<|im_end|>" }, { "id": "#47557", "title": "Mystery Number 5", "fun": 2.06, "difficulty": 3.22, "author": "cnmne", "desc": "There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) A + B + C + D + E is a multiple of 6.\r\n2) F + G + H + I + J is a multiple of 5.\r\n3) A + C + E + G + I is a multiple of 9.\r\n4) B + D + F + H + J is a multiple of 2.\r\n5) AB is a multiple of 3.\r\n6) CD is a multiple of 4.\r\n7) EF is a multiple of 7.\r\n8) GH is a multiple of 8.\r\n9) IJ is a multiple of 10.\r\n10) FE, HC, and JA are all prime numbers.", "hint": "No hint available.", "answer": "5736912480\n\r\nA = 5, B = 7, C = 3, D = 6, E = 9, F = 1, G = 2, H = 4, I = 8, J = 0\n\r\n1) 5 + 7 + 3 + 6 + 9 = 30, which is a multiple of 6.\r\n2) 1 + 2 + 4 + 8 + 0 = 15, which is a multiple of 5.\r\n3) 5 + 3 + 9 + 2 + 8 = 27, which is a multiple of 9.\r\n4) 7 + 6 + 1 + 4 + 0 = 18, which is a multiple of 2.\r\n5) 57 is a multiple of 3.\r\n6) 36 is a multiple of 4.\r\n7) 91 is a multiple of 7.\r\n8) 24 is a multiple of 8.\r\n9) 80 is a multiple of 10.\r\n10) 19, 43, and 05 are prime numbers.\n\r\nA) The sum of digits 0 through 9 is 45. To satisfy Conditions 1 and 2, a pair of multiples must equal 45. The only pair that satisfies those conditions are 30 (multiple of 6) and 15 (multiple of 5). Likewise, to satisfy Conditions 3 and 4, the pair of multiples must be 27 (multiple of 9) and 18 (multiple of 2).\r\nB) Make lists of the multiples of 3, 4, 7, 8, and 10 (for Conditions 5 through 9). Delete multiples whose digits are the same (33, 44, 66, 77, 88, 99).\r\nC) To satisfy Condition 9, J must be 0. Delete multiples that require 0 in a different location. For JA to be prime (Condition 10), A must be: 2, 3, 5, or 7. Delete multiples of 3 that have another digit for A.\r\nD) For FE and HC to be prime (Condition 10), C and E can not be even or 5. Delete multiples of 4 and 7 that have another digit for C and E.\r\nE) Per Condition 4, B + D + F + H + J = 18. D, H, and J must be even (required to form multiples of even numbers). To attain the sum of 18 (an even number), B and F must either be both odd or both even. If both are even, then the sum of those five digits would be 20. B and F must be odd. Delete multiples of 3 and 7 that have an even digit for B and F. The only remaining multiple of 7 is 91. E is 9 and F is 1. Delete multiples that require 1 or 9 in a different location.\r\nF) The only remaining options for AB contain 7. Delete multiples that require 7 in a different location. The only remaining options for CD contain 3. Delete multiples that require 3 in a different location.\r\nG) To satisfy Condition 1, CD must be 36 and AB must be either 57 or 75. C is 3 and D is 6. Delete multiples that require 5, 6, or 7 in a different location.\r\nH) The only remaining options for GH contain 4. Delete multiples that require 4 in a different location.\r\nI) Per Condition 3, A + C + E + G + I = 27. Since C =3 and I = 9, the other three must total 15. There is only one combination of remaining multiples (57, 24, and 80) that can satisfy this condition. A is 5, G is 2, and I is 8. B is 7 and H is 4.", "category": "Logic", "date": "07/24/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) A + B + C + D + E is a multiple of 6.\r\n2) F + G + H + I + J is a multiple of 5.\r\n3) A + C + E + G + I is a multiple of 9.\r\n4) B + D + F + H + J is a multiple of 2.\r\n5) AB is a multiple of 3.\r\n6) CD is a multiple of 4.\r\n7) EF is a multiple of 7.\r\n8) GH is a multiple of 8.\r\n9) IJ is a multiple of 10.\r\n10) FE, HC, and JA are all prime numbers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5736912480\n\r\nA = 5, B = 7, C = 3, D = 6, E = 9, F = 1, G = 2, H = 4, I = 8, J = 0\n\r\n1) 5 + 7 + 3 + 6 + 9 = 30, which is a multiple of 6.\r\n2) 1 + 2 + 4 + 8 + 0 = 15, which is a multiple of 5.\r\n3) 5 + 3 + 9 + 2 + 8 = 27, which is a multiple of 9.\r\n4) 7 + 6 + 1 + 4 + 0 = 18, which is a multiple of 2.\r\n5) 57 is a multiple of 3.\r\n6) 36 is a multiple of 4.\r\n7) 91 is a multiple of 7.\r\n8) 24 is a multiple of 8.\r\n9) 80 is a multiple of 10.\r\n10) 19, 43, and 05 are prime numbers.\n\r\nA) The sum of digits 0 through 9 is 45. To satisfy Conditions 1 and 2, a pair of multiples must equal 45. The only pair that satisfies those conditions are 30 (multiple of 6) and 15 (multiple of 5). Likewise, to satisfy Conditions 3 and 4, the pair of multiples must be 27 (multiple of 9) and 18 (multiple of 2).\r\nB) Make lists of the multiples of 3, 4, 7, 8, and 10 (for Conditions 5 through 9). Delete multiples whose digits are the same (33, 44, 66, 77, 88, 99).\r\nC) To satisfy Condition 9, J must be 0. Delete multiples that require 0 in a different location. For JA to be prime (Condition 10), A must be: 2, 3, 5, or 7. Delete multiples of 3 that have another digit for A.\r\nD) For FE and HC to be prime (Condition 10), C and E can not be even or 5. Delete multiples of 4 and 7 that have another digit for C and E.\r\nE) Per Condition 4, B + D + F + H + J = 18. D, H, and J must be even (required to form multiples of even numbers). To attain the sum of 18 (an even number), B and F must either be both odd or both even. If both are even, then the sum of those five digits would be 20. B and F must be odd. Delete multiples of 3 and 7 that have an even digit for B and F. The only remaining multiple of 7 is 91. E is 9 and F is 1. Delete multiples that require 1 or 9 in a different location.\r\nF) The only remaining options for AB contain 7. Delete multiples that require 7 in a different location. The only remaining options for CD contain 3. Delete multiples that require 3 in a different location.\r\nG) To satisfy Condition 1, CD must be 36 and AB must be either 57 or 75. C is 3 and D is 6. Delete multiples that require 5, 6, or 7 in a different location.\r\nH) The only remaining options for GH contain 4. Delete multiples that require 4 in a different location.\r\nI) Per Condition 3, A + C + E + G + I = 27. Since C =3 and I = 9, the other three must total 15. There is only one combination of remaining multiples (57, 24, and 80) that can satisfy this condition. A is 5, G is 2, and I is 8. B is 7 and H is 4.\n<|im_start|>answer\n5736912480\n\r\nA = 5, B = 7, C = 3, D = 6, E = 9, F = 1, G = 2, H = 4, I = 8, J = 0\n\r\n1) 5 + 7 + 3 + 6 + 9 = 30, which is a multiple of 6.\r\n2) 1 + 2 + 4 + 8 + 0 = 15, which is a multiple of 5.\r\n3) 5 + 3 + 9 + 2 + 8 = 27, which is a multiple of 9.\r\n4) 7 + 6 + 1 + 4 + 0 = 18, which is a multiple of 2.\r\n5) 57 is a multiple of 3.\r\n6) 36 is a multiple of 4.\r\n7) 91 is a multiple of 7.\r\n8) 24 is a multiple of 8.\r\n9) 80 is a multiple of 10.\r\n10) 19, 43, and 05 are prime numbers.\n\r\nA) The sum of digits 0 through 9 is 45. To satisfy Conditions 1 and 2, a pair of multiples must equal 45. The only pair that satisfies those conditions are 30 (multiple of 6) and 15 (multiple of 5). Likewise, to satisfy Conditions 3 and 4, the pair of multiples must be 27 (multiple of 9) and 18 (multiple of 2).\r\nB) Make lists of the multiples of 3, 4, 7, 8, and 10 (for Conditions 5 through 9). Delete multiples whose digits are the same (33, 44, 66, 77, 88, 99).\r\nC) To satisfy Condition 9, J must be 0. Delete multiples that require 0 in a different location. For JA to be prime (Condition 10), A must be: 2, 3, 5, or 7. Delete multiples of 3 that have another digit for A.\r\nD) For FE and HC to be prime (Condition 10), C and E can not be even or 5. Delete multiples of 4 and 7 that have another digit for C and E.\r\nE) Per Condition 4, B + D + F + H + J = 18. D, H, and J must be even (required to form multiples of even numbers). To attain the sum of 18 (an even number), B and F must either be both odd or both even. If both are even, then the sum of those five digits would be 20. B and F must be odd. Delete multiples of 3 and 7 that have an even digit for B and F. The only remaining multiple of 7 is 91. E is 9 and F is 1. Delete multiples that require 1 or 9 in a different location.\r\nF) The only remaining options for AB contain 7. Delete multiples that require 7 in a different location. The only remaining options for CD contain 3. Delete multiples that require 3 in a different location.\r\nG) To satisfy Condition 1, CD must be 36 and AB must be either 57 or 75. C is 3 and D is 6. Delete multiples that require 5, 6, or 7 in a different location.\r\nH) The only remaining options for GH contain 4. Delete multiples that require 4 in a different location.\r\nI) Per Condition 3, A + C + E + G + I = 27. Since C =3 and I = 9, the other three must total 15. There is only one combination of remaining multiples (57, 24, and 80) that can satisfy this condition. A is 5, G is 2, and I is 8. B is 7 and H is 4.\n<|im_end|>" }, { "id": "#43450", "title": "Clocks", "fun": 2.06, "difficulty": 1.26, "author": "twin27", "desc": "A clock has twelve hours in a rotation of the hour hand, sixty minutes in the rotation of the minute hand, and sixty seconds in a rotation of a second hand. Using the following things, starting at 0 hours and 0 seconds, how much time is passing in all these intervals?\r\n5 rotations of the second hand\r\n2/12 rotation of the hour hand\r\n3/6 rotation of the minute hand\r\n3/4 rotation of the minute hand", "hint": "No hint available.", "answer": "The answer is three hours and twenty minutes. Five rotations of the second hand is five minutes, because a full rotation of the second hand is a minute. 2/12 rotations of the hour hand is two hours. 3/6 rotations of the minute hand is 30 minutes because 3/6 is equal to 1/2. 3/4 rotations of the minute hand is 45 minutes.", "category": "Math", "date": "10/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA clock has twelve hours in a rotation of the hour hand, sixty minutes in the rotation of the minute hand, and sixty seconds in a rotation of a second hand. Using the following things, starting at 0 hours and 0 seconds, how much time is passing in all these intervals?\r\n5 rotations of the second hand\r\n2/12 rotation of the hour hand\r\n3/6 rotation of the minute hand\r\n3/4 rotation of the minute hand\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe answer is three hours and twenty minutes. Five rotations of the second hand is five minutes, because a full rotation of the second hand is a minute. 2/12 rotations of the hour hand is two hours. 3/6 rotations of the minute hand is 30 minutes because 3/6 is equal to 1/2. 3/4 rotations of the minute hand is 45 minutes.\n<|im_start|>answer\nThe answer is three hours and twenty minutes. Five rotations of the second hand is five minutes, because a full rotation of the second hand is a minute. 2/12 rotations of the hour hand is two hours. 3/6 rotations of the minute hand is 30 minutes because 3/6 is equal to 1/2. 3/4 rotations of the minute hand is 45 minutes.\n<|im_end|>" }, { "id": "#4481", "title": "Lighting Candles", "fun": 2.06, "difficulty": 1.61, "author": "kkats4", "desc": "A man walks into a dark room with only one match. What does he light first, a birthday candle (one that would go on a cake but in this case isn't on one), a regular candle, or a bonfire? The match is lit.", "hint": "No hint available.", "answer": "The birthday candle, because he can carry it to the regular candle, then light that, and then use both candles to light the bonfire!", "category": "Logic", "date": "06/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA man walks into a dark room with only one match. What does he light first, a birthday candle (one that would go on a cake but in this case isn't on one), a regular candle, or a bonfire? The match is lit.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe birthday candle, because he can carry it to the regular candle, then light that, and then use both candles to light the bonfire!\n<|im_start|>answer\nThe birthday candle, because he can carry it to the regular candle, then light that, and then use both candles to light the bonfire!\n<|im_end|>" }, { "id": "#44758", "title": "Bingo Card 3", "fun": 2.06, "difficulty": 2.7600000000000002, "author": "cnmne", "desc": "You are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) For each column, the numbers are in either ascending order or descending order.\r\n2) Row 1: the numbers are prime.\r\n3) Row 5: the numbers are composite.\r\n4) Column I: the numbers are spaced at equal intervals.\r\n5) Column O: the numbers are spaced at different intervals.\r\n6) The sum of the numbers in Row 1 equals the sum of the numbers in Row 5.\r\n7) The product of B4 and O5 equals the product of B5 and O4.\r\n8) The product of I2 and G2 equals the product of I3 and G3.\r\n9) N4 is midway between B4 and G4.\r\n10) Each column has one multiple of 6.\r\n11) There is only one square number on the card.", "hint": "No hint available.", "answer": "11 17 41 59 61\r\n12 18 36 57 63\r\n13 19 -- 54 66\r\n14 20 33 52 70\r\n15 21 32 46 75\n\r\n1) Per clue 2, eliminate non-prime numbers from Row 1.\r\n2) Per clue 3, eliminate non-composite numbers from Row 5.\r\n3) Per clue 1, eliminate numbers that do not fit any possible (ascending or descending) sequence from Rows 2 through 4.\r\n4) Per clue 4, determine the possible sequences for Column I. In conjunction with clue 8, eliminate numbers from Columns I and G.\r\n5) Per clue 10, I2 must be 18 or 24, and G3 must be 48 or 54. Eliminate additional numbers from Column G.\r\n6) Per clue 7, determine what combinations of numbers work. Eliminate those that to not work from B4, B5, O4, and O5.\r\n7) Per clue 5, in order to have four different intervals, the spread from top to bottom must be at least 10. Eliminate from O1: 67 and 71. Eliminate from O5: 64 and 70. In conjunction with clue 7, only one combination of numbers works: O4 must be 70, O5 must be 75, B4 must be 14, and B5 must be 15. This leaves O1 as 61.\r\n8) Per clue 10, 66 must be in either O2 or O3. 66 can not be in O2, because that would create an interval of 5 (which already exists between O4 and O5) between O1 and O2. O3 must be 66. O2 must be either 63 or 64.\r\n9) Per clue 9, N4 must be 33 and G4 must be 52. This leaves G1 as 59, G2 as 57, and G3 as 54.\r\n10) Per clues 4 and 8, Column I can be determined. I1 must be 17, I2 must be 18, I3 must be 19, I4 must be 20, and I5 must be 21.\r\n11) Per clue 6, Column N must be in descending order. N5 must be 32.\r\n12) Per clue 6, the only combination of numbers that works produces a sum of 189. B1 must be 11, N1 must be 41, G5 must be 46.\r\n13) Per clue 1, B2 must be 12 and B3 must be 13.\r\n14) Per clue 10, N2 must be 36. Per clue 11, O2 must be 63.", "category": "Logic", "date": "06/30/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) For each column, the numbers are in either ascending order or descending order.\r\n2) Row 1: the numbers are prime.\r\n3) Row 5: the numbers are composite.\r\n4) Column I: the numbers are spaced at equal intervals.\r\n5) Column O: the numbers are spaced at different intervals.\r\n6) The sum of the numbers in Row 1 equals the sum of the numbers in Row 5.\r\n7) The product of B4 and O5 equals the product of B5 and O4.\r\n8) The product of I2 and G2 equals the product of I3 and G3.\r\n9) N4 is midway between B4 and G4.\r\n10) Each column has one multiple of 6.\r\n11) There is only one square number on the card.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n11 17 41 59 61\r\n12 18 36 57 63\r\n13 19 -- 54 66\r\n14 20 33 52 70\r\n15 21 32 46 75\n\r\n1) Per clue 2, eliminate non-prime numbers from Row 1.\r\n2) Per clue 3, eliminate non-composite numbers from Row 5.\r\n3) Per clue 1, eliminate numbers that do not fit any possible (ascending or descending) sequence from Rows 2 through 4.\r\n4) Per clue 4, determine the possible sequences for Column I. In conjunction with clue 8, eliminate numbers from Columns I and G.\r\n5) Per clue 10, I2 must be 18 or 24, and G3 must be 48 or 54. Eliminate additional numbers from Column G.\r\n6) Per clue 7, determine what combinations of numbers work. Eliminate those that to not work from B4, B5, O4, and O5.\r\n7) Per clue 5, in order to have four different intervals, the spread from top to bottom must be at least 10. Eliminate from O1: 67 and 71. Eliminate from O5: 64 and 70. In conjunction with clue 7, only one combination of numbers works: O4 must be 70, O5 must be 75, B4 must be 14, and B5 must be 15. This leaves O1 as 61.\r\n8) Per clue 10, 66 must be in either O2 or O3. 66 can not be in O2, because that would create an interval of 5 (which already exists between O4 and O5) between O1 and O2. O3 must be 66. O2 must be either 63 or 64.\r\n9) Per clue 9, N4 must be 33 and G4 must be 52. This leaves G1 as 59, G2 as 57, and G3 as 54.\r\n10) Per clues 4 and 8, Column I can be determined. I1 must be 17, I2 must be 18, I3 must be 19, I4 must be 20, and I5 must be 21.\r\n11) Per clue 6, Column N must be in descending order. N5 must be 32.\r\n12) Per clue 6, the only combination of numbers that works produces a sum of 189. B1 must be 11, N1 must be 41, G5 must be 46.\r\n13) Per clue 1, B2 must be 12 and B3 must be 13.\r\n14) Per clue 10, N2 must be 36. Per clue 11, O2 must be 63.\n<|im_start|>answer\n11 17 41 59 61\r\n12 18 36 57 63\r\n13 19 -- 54 66\r\n14 20 33 52 70\r\n15 21 32 46 75\n\r\n1) Per clue 2, eliminate non-prime numbers from Row 1.\r\n2) Per clue 3, eliminate non-composite numbers from Row 5.\r\n3) Per clue 1, eliminate numbers that do not fit any possible (ascending or descending) sequence from Rows 2 through 4.\r\n4) Per clue 4, determine the possible sequences for Column I. In conjunction with clue 8, eliminate numbers from Columns I and G.\r\n5) Per clue 10, I2 must be 18 or 24, and G3 must be 48 or 54. Eliminate additional numbers from Column G.\r\n6) Per clue 7, determine what combinations of numbers work. Eliminate those that to not work from B4, B5, O4, and O5.\r\n7) Per clue 5, in order to have four different intervals, the spread from top to bottom must be at least 10. Eliminate from O1: 67 and 71. Eliminate from O5: 64 and 70. In conjunction with clue 7, only one combination of numbers works: O4 must be 70, O5 must be 75, B4 must be 14, and B5 must be 15. This leaves O1 as 61.\r\n8) Per clue 10, 66 must be in either O2 or O3. 66 can not be in O2, because that would create an interval of 5 (which already exists between O4 and O5) between O1 and O2. O3 must be 66. O2 must be either 63 or 64.\r\n9) Per clue 9, N4 must be 33 and G4 must be 52. This leaves G1 as 59, G2 as 57, and G3 as 54.\r\n10) Per clues 4 and 8, Column I can be determined. I1 must be 17, I2 must be 18, I3 must be 19, I4 must be 20, and I5 must be 21.\r\n11) Per clue 6, Column N must be in descending order. N5 must be 32.\r\n12) Per clue 6, the only combination of numbers that works produces a sum of 189. B1 must be 11, N1 must be 41, G5 must be 46.\r\n13) Per clue 1, B2 must be 12 and B3 must be 13.\r\n14) Per clue 10, N2 must be 36. Per clue 11, O2 must be 63.\n<|im_end|>" }, { "id": "#6624", "title": "1200 Elephants", "fun": 2.06, "difficulty": 1.72, "author": "michelle", "desc": "There are 1200 elephants in a herd. Some have pink and green stripes, some are all pink and some are all blue. One third are pure pink. Is it true that 400 elephants are definitely blue? Yes/No and Why?", "hint": "No hint available.", "answer": "No. The other 800 elephants can be any mix of all blue and pink and green stripes", "category": "Math", "date": "08/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 1200 elephants in a herd. Some have pink and green stripes, some are all pink and some are all blue. One third are pure pink. Is it true that 400 elephants are definitely blue? Yes/No and Why?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNo. The other 800 elephants can be any mix of all blue and pink and green stripes\n<|im_start|>answer\nNo. The other 800 elephants can be any mix of all blue and pink and green stripes\n<|im_end|>" }, { "id": "#44560", "title": "Mix-up at the Airport", "fun": 2.06, "difficulty": 1.96, "author": "whsprec", "desc": "Six students traveled to Europe as part of a foreign exchange program. Upon reaching the airport they realized that they had mixed up the order their flights left and the details of where they were going. Although each detail is in the correct column, only one entry in each column is correctly positioned. Match the name and surname of each student, which school they are from, and which country they are visiting.\n\r\nName Surname Country School\r\nMatt Jones France Eastside\r\nWill Smith Germany Northside\r\nIris Cantrell England Sky View\r\nJosh James Russia Southside\r\nSara Clark Italy Westside\r\nTiara Recko Spain Central\n\r\n1) France is three places above Central\r\n2) Smith is somewhere above Recko and 2 places above the Sky View\r\n3) Sara is 2 places below Germany\r\n4) Clark is 1 row below both Will and Italy\r\n5) Tiara is immediately below Sara but 3 places below Jones\r\n6) Will is 1 row below Westside and somewhere above Iris\r\n7) Northside is 2 rows above England", "hint": "No hint available.", "answer": "Name Surname Country School\r\nMatt Jones Germany Southside\r\nJosh Cantrell France Northside\r\nSara James Spain Eastside\r\nTiara Smith England Westside\r\nWill Recko Italy Central\r\nIris Clark Russia Sky View", "category": "Logic", "date": "06/01/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSix students traveled to Europe as part of a foreign exchange program. Upon reaching the airport they realized that they had mixed up the order their flights left and the details of where they were going. Although each detail is in the correct column, only one entry in each column is correctly positioned. Match the name and surname of each student, which school they are from, and which country they are visiting.\n\r\nName Surname Country School\r\nMatt Jones France Eastside\r\nWill Smith Germany Northside\r\nIris Cantrell England Sky View\r\nJosh James Russia Southside\r\nSara Clark Italy Westside\r\nTiara Recko Spain Central\n\r\n1) France is three places above Central\r\n2) Smith is somewhere above Recko and 2 places above the Sky View\r\n3) Sara is 2 places below Germany\r\n4) Clark is 1 row below both Will and Italy\r\n5) Tiara is immediately below Sara but 3 places below Jones\r\n6) Will is 1 row below Westside and somewhere above Iris\r\n7) Northside is 2 rows above England\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nName Surname Country School\r\nMatt Jones Germany Southside\r\nJosh Cantrell France Northside\r\nSara James Spain Eastside\r\nTiara Smith England Westside\r\nWill Recko Italy Central\r\nIris Clark Russia Sky View\n<|im_start|>answer\nName Surname Country School\r\nMatt Jones Germany Southside\r\nJosh Cantrell France Northside\r\nSara James Spain Eastside\r\nTiara Smith England Westside\r\nWill Recko Italy Central\r\nIris Clark Russia Sky View\n<|im_end|>" }, { "id": "#2970", "title": "Solve for x", "fun": 2.06, "difficulty": 1.72, "author": "rohddawg", "desc": "Solve for x\n\r\n x^(1/2) = x^2", "hint": "There are two possible answers.", "answer": "1 and 0 both work.", "category": "Math", "date": "03/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSolve for x\n\r\n x^(1/2) = x^2\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1 and 0 both work.\n<|im_start|>answer\n1 and 0 both work.\n<|im_end|>" }, { "id": "#41735", "title": "Square Flag", "fun": 2.06, "difficulty": 2.35, "author": "cnmne", "desc": "A square flag has a blue field with two white diagonal bars that form a cross. Each bar extends across the entire diagonal, from corner to corner. The cross occupies half of the flag's area. The flag measures 60 inches on each side. To the nearest 0.01, what is the width of the bars?", "hint": "No hint available.", "answer": "12.43 inches\n\r\na) The square flag measures 60 inches on a side, so its area is 60*60 = 3600.\r\nb) The white cross occupies half of the area, or 3600/2 = 1800.\r\nc) Since the flag is square, the cross divides the flag's blue field into four equal-sized isosceles right triangles. Each of those triangles has an area of 1800/4 = 450.\r\nd) The area (A) of an isosceles right triangle is calculated by the formula 0.5(X^2) = A, where X is the length of one of the two perpendicular legs. 0.5(X^2) = 450, or X^2 = 900, or X = 30. These perpendicular legs form the border between the field and the cross.\r\ne) The hypotenuse (H) of an isosceles right triangle is calculated by the formula H = (2(X^2))^(1/2), where X is the length of one of the two perpendicular legs. H = (2(30^2))^(1/2) = (2(900)^(1/2) = 1800^(1/2) = 42.43.\r\nf) The hypotenuse of each triangle lies along the perimeter in the center of each side of the flag. The remaining length of each side is split equally between the two bars, leaving (60-42.43)/2 , or 8.79, for each bar.\r\ng) Where the bars extend into the corners of the flag, isosceles right triangles with legs of 8.79 are formed. Again, use the formula H = (2(X^2))^(1/2). H = (2(8.79^2))^(1/2) = (2(77.26))^(1/2) = 154.52^(1/2) = 12.43 = H. The hypotenuse of 12.43 is the width of the bars.", "category": "Math", "date": "04/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA square flag has a blue field with two white diagonal bars that form a cross. Each bar extends across the entire diagonal, from corner to corner. The cross occupies half of the flag's area. The flag measures 60 inches on each side. To the nearest 0.01, what is the width of the bars?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n12.43 inches\n\r\na) The square flag measures 60 inches on a side, so its area is 60*60 = 3600.\r\nb) The white cross occupies half of the area, or 3600/2 = 1800.\r\nc) Since the flag is square, the cross divides the flag's blue field into four equal-sized isosceles right triangles. Each of those triangles has an area of 1800/4 = 450.\r\nd) The area (A) of an isosceles right triangle is calculated by the formula 0.5(X^2) = A, where X is the length of one of the two perpendicular legs. 0.5(X^2) = 450, or X^2 = 900, or X = 30. These perpendicular legs form the border between the field and the cross.\r\ne) The hypotenuse (H) of an isosceles right triangle is calculated by the formula H = (2(X^2))^(1/2), where X is the length of one of the two perpendicular legs. H = (2(30^2))^(1/2) = (2(900)^(1/2) = 1800^(1/2) = 42.43.\r\nf) The hypotenuse of each triangle lies along the perimeter in the center of each side of the flag. The remaining length of each side is split equally between the two bars, leaving (60-42.43)/2 , or 8.79, for each bar.\r\ng) Where the bars extend into the corners of the flag, isosceles right triangles with legs of 8.79 are formed. Again, use the formula H = (2(X^2))^(1/2). H = (2(8.79^2))^(1/2) = (2(77.26))^(1/2) = 154.52^(1/2) = 12.43 = H. The hypotenuse of 12.43 is the width of the bars.\n<|im_start|>answer\n12.43 inches\n\r\na) The square flag measures 60 inches on a side, so its area is 60*60 = 3600.\r\nb) The white cross occupies half of the area, or 3600/2 = 1800.\r\nc) Since the flag is square, the cross divides the flag's blue field into four equal-sized isosceles right triangles. Each of those triangles has an area of 1800/4 = 450.\r\nd) The area (A) of an isosceles right triangle is calculated by the formula 0.5(X^2) = A, where X is the length of one of the two perpendicular legs. 0.5(X^2) = 450, or X^2 = 900, or X = 30. These perpendicular legs form the border between the field and the cross.\r\ne) The hypotenuse (H) of an isosceles right triangle is calculated by the formula H = (2(X^2))^(1/2), where X is the length of one of the two perpendicular legs. H = (2(30^2))^(1/2) = (2(900)^(1/2) = 1800^(1/2) = 42.43.\r\nf) The hypotenuse of each triangle lies along the perimeter in the center of each side of the flag. The remaining length of each side is split equally between the two bars, leaving (60-42.43)/2 , or 8.79, for each bar.\r\ng) Where the bars extend into the corners of the flag, isosceles right triangles with legs of 8.79 are formed. Again, use the formula H = (2(X^2))^(1/2). H = (2(8.79^2))^(1/2) = (2(77.26))^(1/2) = 154.52^(1/2) = 12.43 = H. The hypotenuse of 12.43 is the width of the bars.\n<|im_end|>" }, { "id": "#22968", "title": "School Subjects", "fun": 2.06, "difficulty": 0.58, "author": "beachbabe1218", "desc": "Three friends go to three different schools and like three different subjects. Who goes to what school and likes which subject?\n\r\nNames: Jeff, Sarah, Melissa\r\nSchools: Long, Meadow, First\r\nSubjects: Math, Science, Spanish\n\r\nJeff likes math.\n\r\nSarah doesn't attend Meadow.\n\r\nThe girl that attends Meadow likes science.\n\r\nThe person that attends First likes math.", "hint": "No hint available.", "answer": "Jeff-First-Math\r\nSarah-Long-Spanish\r\nMelissa-Meadow-Science", "category": "Logic-Grid", "date": "05/17/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends go to three different schools and like three different subjects. Who goes to what school and likes which subject?\n\r\nNames: Jeff, Sarah, Melissa\r\nSchools: Long, Meadow, First\r\nSubjects: Math, Science, Spanish\n\r\nJeff likes math.\n\r\nSarah doesn't attend Meadow.\n\r\nThe girl that attends Meadow likes science.\n\r\nThe person that attends First likes math.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJeff-First-Math\r\nSarah-Long-Spanish\r\nMelissa-Meadow-Science\n<|im_start|>answer\nJeff-First-Math\r\nSarah-Long-Spanish\r\nMelissa-Meadow-Science\n<|im_end|>" }, { "id": "#4940", "title": "Square Table", "fun": 2.06, "difficulty": 1.04, "author": "PaulReed", "desc": "There are four people and all of them are sitting at a SQUARE table playing a game. Their names are Mary, Helen, Paul, and John. You have to read the clues below and figure out who sits where at the table.\n\r\nJohn is at the left of Mary\r\nMary sits on the right side of the table\r\nHelen is on the right of Mary\r\nSo where does Paul sit?", "hint": "No hint available.", "answer": "Paul sits on the left of John and across from Mary", "category": "Logic", "date": "06/25/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four people and all of them are sitting at a SQUARE table playing a game. Their names are Mary, Helen, Paul, and John. You have to read the clues below and figure out who sits where at the table.\n\r\nJohn is at the left of Mary\r\nMary sits on the right side of the table\r\nHelen is on the right of Mary\r\nSo where does Paul sit?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPaul sits on the left of John and across from Mary\n<|im_start|>answer\nPaul sits on the left of John and across from Mary\n<|im_end|>" }, { "id": "#19684", "title": "Superheroes", "fun": 2.06, "difficulty": 0.61, "author": "something", "desc": "In the town of Superherovilletonfield, mild mannered people turn into not-so-mild mannered superheroes on a regular basis. The villain of the superheroes, Evil McMeanieman, wants to find out everything about the superheroes. He hires you to figure out their Superhero names, alter egos, and jobs. \n\r\nSuperhero name: \n\r\nUltra Dude \r\nThe Puppyeyes Kid \r\nIcecream Man \n\r\nAlter Ego: \n\r\nTurkey Pharrelson \r\nLuther Flixterbaccher \r\nAndrew A. Andrewston \n\r\nJobs: \n\r\nJournalist \r\nPhotographer \r\nFast Food \n\r\n1. The Icecream Man doesn't serve fast food. \r\n2. Flixterbaccher isn't a Journalist. \r\n3. Andrewston is Ultra Dude. \r\n4. The Journalist is Puppyeyes Kid..", "hint": "No hint available.", "answer": "Andrew A. Andrewston - Ultra Dude - Fast Food\n\r\nTurkey Pharrelson - Puppyeyes Kid - Journalist\n\r\nLuther Flixterbaccher - Icecream Man - Photographer", "category": "Logic-Grid", "date": "12/03/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn the town of Superherovilletonfield, mild mannered people turn into not-so-mild mannered superheroes on a regular basis. The villain of the superheroes, Evil McMeanieman, wants to find out everything about the superheroes. He hires you to figure out their Superhero names, alter egos, and jobs. \n\r\nSuperhero name: \n\r\nUltra Dude \r\nThe Puppyeyes Kid \r\nIcecream Man \n\r\nAlter Ego: \n\r\nTurkey Pharrelson \r\nLuther Flixterbaccher \r\nAndrew A. Andrewston \n\r\nJobs: \n\r\nJournalist \r\nPhotographer \r\nFast Food \n\r\n1. The Icecream Man doesn't serve fast food. \r\n2. Flixterbaccher isn't a Journalist. \r\n3. Andrewston is Ultra Dude. \r\n4. The Journalist is Puppyeyes Kid..\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAndrew A. Andrewston - Ultra Dude - Fast Food\n\r\nTurkey Pharrelson - Puppyeyes Kid - Journalist\n\r\nLuther Flixterbaccher - Icecream Man - Photographer\n<|im_start|>answer\nAndrew A. Andrewston - Ultra Dude - Fast Food\n\r\nTurkey Pharrelson - Puppyeyes Kid - Journalist\n\r\nLuther Flixterbaccher - Icecream Man - Photographer\n<|im_end|>" }, { "id": "#27655", "title": "Cats", "fun": 2.05, "difficulty": 0.96, "author": "kiss", "desc": "There are cats in a drawer. Each cat is in a corner, and each cat sees three cats. Do you know how many cats are there?", "hint": "No hint available.", "answer": "Four.", "category": "Logic", "date": "12/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are cats in a drawer. Each cat is in a corner, and each cat sees three cats. Do you know how many cats are there?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFour.\n<|im_start|>answer\nFour.\n<|im_end|>" }, { "id": "#7015", "title": "Hat Colors", "fun": 2.05, "difficulty": 1.46, "author": "jitterbugxx5", "desc": "There are four men. One is wearing a violet hat, one is wearing an indigo hat, and the other is wearing a blue hat. What color is the fourth man's hat?", "hint": "look at the pattern", "answer": "The fourth man's hat is green because their hats are the color of the rainbow.", "category": "Logic", "date": "08/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are four men. One is wearing a violet hat, one is wearing an indigo hat, and the other is wearing a blue hat. What color is the fourth man's hat?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe fourth man's hat is green because their hats are the color of the rainbow.\n<|im_start|>answer\nThe fourth man's hat is green because their hats are the color of the rainbow.\n<|im_end|>" }, { "id": "#873", "title": "Who's Engaged?", "fun": 2.05, "difficulty": 0.63, "author": "Michelle", "desc": "Melissa, Abbey and Lisa are engaged to the three men below, each of whom has a different job. Who is engaged to whom, and what are their jobs? \n\r\n1. The programmer's future wife is not Lisa.\r\n2. Jason is the accountant.\r\n3. Jeffery is dating Melissa. \r\n4. Jack is a salesman. \r\n5. Abbey is not engaged to the accountant.", "hint": "No hint available.", "answer": "Melissa - Jeffery - Programmer\n\r\nLisa - Jason - Accountant\n\r\nAbbey - Jack - Salesman", "category": "Logic-Grid", "date": "09/23/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMelissa, Abbey and Lisa are engaged to the three men below, each of whom has a different job. Who is engaged to whom, and what are their jobs? \n\r\n1. The programmer's future wife is not Lisa.\r\n2. Jason is the accountant.\r\n3. Jeffery is dating Melissa. \r\n4. Jack is a salesman. \r\n5. Abbey is not engaged to the accountant.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMelissa - Jeffery - Programmer\n\r\nLisa - Jason - Accountant\n\r\nAbbey - Jack - Salesman\n<|im_start|>answer\nMelissa - Jeffery - Programmer\n\r\nLisa - Jason - Accountant\n\r\nAbbey - Jack - Salesman\n<|im_end|>" }, { "id": "#7349", "title": "Mental Money", "fun": 2.05, "difficulty": 1.29, "author": "Timmyboym", "desc": "If I lost 50% of all my money and then regained 50% but am now $50 off my old total, what was my old total?", "hint": "No hint available.", "answer": "$200\r\nSince you don't know if you end up $50 more or $50 less than your old total, you have to try each of two equations: \n\r\n1) 0.5*X + 0.5*(0.5*X) = X - 50\r\n2) 0.5*X + 0.5*0.5*X = X + 50 \n\r\nWhere X is the original amount.\n\r\nThe answer to (1) is X = 200 and the answer to (2) is X = -200. Obviously he couldn't have started with -$200, so the answer must be $200.", "category": "Math", "date": "09/10/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf I lost 50% of all my money and then regained 50% but am now $50 off my old total, what was my old total?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$200\r\nSince you don't know if you end up $50 more or $50 less than your old total, you have to try each of two equations: \n\r\n1) 0.5*X + 0.5*(0.5*X) = X - 50\r\n2) 0.5*X + 0.5*0.5*X = X + 50 \n\r\nWhere X is the original amount.\n\r\nThe answer to (1) is X = 200 and the answer to (2) is X = -200. Obviously he couldn't have started with -$200, so the answer must be $200.\n<|im_start|>answer\n$200\r\nSince you don't know if you end up $50 more or $50 less than your old total, you have to try each of two equations: \n\r\n1) 0.5*X + 0.5*(0.5*X) = X - 50\r\n2) 0.5*X + 0.5*0.5*X = X + 50 \n\r\nWhere X is the original amount.\n\r\nThe answer to (1) is X = 200 and the answer to (2) is X = -200. Obviously he couldn't have started with -$200, so the answer must be $200.\n<|im_end|>" }, { "id": "#10895", "title": "Drash and Rabb", "fun": 2.05, "difficulty": 2.27, "author": "timmyboym", "desc": "On the Planet Necro there are two types of metals. One is Drash which weighs 127 Necrograms, and Rabb which weighs 50 Necrograms. You have as much play-doh, Drash, and Rabb as you need. You have a balance scale and you need to make a ball of play-doh equal to 304 Necrograms. How?", "hint": "No hint available.", "answer": "Put the Rabb on the scales. Put play-doh on the opposite side so it balances the Rabb. Then divide the play-doh in half so that each half balances the other. Now you have a 25 Necrogram ball of play-doh. Now put the Drash on the scales and enough play-doh to balance it, then mix the 127 and 25 Necrogram balls of play-doh together. That makes 152 Necrograms. Put that ball on the scales and enough play-doh to balance that. Combine these and you will have a 304 Necrogram ball of play-doh.", "category": "Math", "date": "03/05/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOn the Planet Necro there are two types of metals. One is Drash which weighs 127 Necrograms, and Rabb which weighs 50 Necrograms. You have as much play-doh, Drash, and Rabb as you need. You have a balance scale and you need to make a ball of play-doh equal to 304 Necrograms. How?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPut the Rabb on the scales. Put play-doh on the opposite side so it balances the Rabb. Then divide the play-doh in half so that each half balances the other. Now you have a 25 Necrogram ball of play-doh. Now put the Drash on the scales and enough play-doh to balance it, then mix the 127 and 25 Necrogram balls of play-doh together. That makes 152 Necrograms. Put that ball on the scales and enough play-doh to balance that. Combine these and you will have a 304 Necrogram ball of play-doh.\n<|im_start|>answer\nPut the Rabb on the scales. Put play-doh on the opposite side so it balances the Rabb. Then divide the play-doh in half so that each half balances the other. Now you have a 25 Necrogram ball of play-doh. Now put the Drash on the scales and enough play-doh to balance it, then mix the 127 and 25 Necrogram balls of play-doh together. That makes 152 Necrograms. Put that ball on the scales and enough play-doh to balance that. Combine these and you will have a 304 Necrogram ball of play-doh.\n<|im_end|>" }, { "id": "#2034", "title": "9000", "fun": 2.05, "difficulty": 1.34, "author": "jokester8000", "desc": "What three consecutive numbers sum to 9000?", "hint": "No hint available.", "answer": "2999 3000 3001", "category": "Math", "date": "01/15/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat three consecutive numbers sum to 9000?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2999 3000 3001\n<|im_start|>answer\n2999 3000 3001\n<|im_end|>" }, { "id": "#23198", "title": "People and Pepsi", "fun": 2.05, "difficulty": 0.56, "author": "orlie0618", "desc": "There are three people.... Katy, Jen, and Rory who like to drink....Diet Pepsi, Pepsi, and Pepsi with lime. \r\nOne has red hair, one has orange hair and one has black hair. Which is which? Figure it out!!!\n\n\r\nKaty doesn't have red hair.\n\r\nThe one who drinks Pepsi likes the color orange.\n\r\nJen likes a sour taste on the end of her Pepsi.\n\r\nKaty's on a diet.", "hint": "It's not that hard. Sheesh....it's my first one!!", "answer": "Katy-black-Diet Pepsi\r\nJen-red-Pepsi with lime\r\nRory-orange-Pepsi", "category": "Logic-Grid", "date": "05/26/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three people.... Katy, Jen, and Rory who like to drink....Diet Pepsi, Pepsi, and Pepsi with lime. \r\nOne has red hair, one has orange hair and one has black hair. Which is which? Figure it out!!!\n\n\r\nKaty doesn't have red hair.\n\r\nThe one who drinks Pepsi likes the color orange.\n\r\nJen likes a sour taste on the end of her Pepsi.\n\r\nKaty's on a diet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKaty-black-Diet Pepsi\r\nJen-red-Pepsi with lime\r\nRory-orange-Pepsi\n<|im_start|>answer\nKaty-black-Diet Pepsi\r\nJen-red-Pepsi with lime\r\nRory-orange-Pepsi\n<|im_end|>" }, { "id": "#43009", "title": "6+6=14", "fun": 2.05, "difficulty": 2.48, "author": "shenqiang", "desc": "If 6+6=14, what does 6*6 equal?", "hint": "When does 6+6=14?", "answer": "6+6=14 in the octal system. Therefore, 6*6, in octal, is 44.", "category": "Math", "date": "09/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 6+6=14, what does 6*6 equal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6+6=14 in the octal system. Therefore, 6*6, in octal, is 44.\n<|im_start|>answer\n6+6=14 in the octal system. Therefore, 6*6, in octal, is 44.\n<|im_end|>" }, { "id": "#40543", "title": "2,2,2?", "fun": 2.05, "difficulty": 1.14, "author": "Pope_Greg4", "desc": "How can the numbers 2 2 2 be arranged to equal 3?", "hint": "Order of operations", "answer": "2+(2/2)=3", "category": "Math", "date": "02/16/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow can the numbers 2 2 2 be arranged to equal 3?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2+(2/2)=3\n<|im_start|>answer\n2+(2/2)=3\n<|im_end|>" }, { "id": "#20873", "title": "Polygons", "fun": 2.05, "difficulty": 1.3800000000000001, "author": "luckanani", "desc": "A boy was told to identify a polygon. The teacher gave him 3 clues:\r\n1. I have 4 equal sides.\r\n2. All my angles add to 360 degrees\r\n3. I'm not a square.\r\nWhat am I?", "hint": "No hint available.", "answer": "A rhombus, because all the sides are the same length, all the angles add to 360 degrees and it isn't a square.", "category": "Math", "date": "02/07/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA boy was told to identify a polygon. The teacher gave him 3 clues:\r\n1. I have 4 equal sides.\r\n2. All my angles add to 360 degrees\r\n3. I'm not a square.\r\nWhat am I?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA rhombus, because all the sides are the same length, all the angles add to 360 degrees and it isn't a square.\n<|im_start|>answer\nA rhombus, because all the sides are the same length, all the angles add to 360 degrees and it isn't a square.\n<|im_end|>" }, { "id": "#31005", "title": "Books, Authors and Characters", "fun": 2.05, "difficulty": 1.03, "author": "dishu", "desc": "The four friends are fighting again. This time, it's about how their favourite characters were shaped up in their favourite books by their favourite authors. The fight became so bad that the friends became clueless about who was in which book and who wrote which book. Can you match their favourite characters with their books and authors with the help of these clues?\n\r\nFriends: Dis, Dip, Raj, Rich\r\nCharacter: Marple, Huck, Hermione, Darcy\r\nBook: Sleeping Murder, Tom Sawyer, Harry Potter, Pride and Prejudice\r\nAuthors: Agatha Christie, Mark Twain, J.K. Rowling, Jane Austen\n\r\n1. Rich and Dip hate the childish Harry Potter books.\r\n2. Rich fell in love with Darcy's attitude in Jane Austen's classic.\r\n3. Raj just can't stop admiring Hermione's comfort with magic.\r\n4. Dis is a fan of murder mysteries. \r\n5. Dip became Mark Twain's fan because of Twain's imagination in shaping Huck's character.\r\n6. Jane Austen's novel's title did not include any person's name, just emotions/ideas.\r\n7. Agatha Christie was awarded the title of Mystery Queen for her murder mysteries.", "hint": "The knowledge of the books will be a great help but is not necessarily required.", "answer": "Friend, Character, Book, Author:\n\r\nDis, Marple, Sleeping Murder, Agatha Christie\r\nDip, Huck, Tom Sawyer, Mark Twain\r\nRaj, Hermione, Harry Potter, J.K. Rowling\r\nRich, Darcy, Pride and Prejudice, Jane Austen", "category": "Logic-Grid", "date": "06/11/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe four friends are fighting again. This time, it's about how their favourite characters were shaped up in their favourite books by their favourite authors. The fight became so bad that the friends became clueless about who was in which book and who wrote which book. Can you match their favourite characters with their books and authors with the help of these clues?\n\r\nFriends: Dis, Dip, Raj, Rich\r\nCharacter: Marple, Huck, Hermione, Darcy\r\nBook: Sleeping Murder, Tom Sawyer, Harry Potter, Pride and Prejudice\r\nAuthors: Agatha Christie, Mark Twain, J.K. Rowling, Jane Austen\n\r\n1. Rich and Dip hate the childish Harry Potter books.\r\n2. Rich fell in love with Darcy's attitude in Jane Austen's classic.\r\n3. Raj just can't stop admiring Hermione's comfort with magic.\r\n4. Dis is a fan of murder mysteries. \r\n5. Dip became Mark Twain's fan because of Twain's imagination in shaping Huck's character.\r\n6. Jane Austen's novel's title did not include any person's name, just emotions/ideas.\r\n7. Agatha Christie was awarded the title of Mystery Queen for her murder mysteries.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFriend, Character, Book, Author:\n\r\nDis, Marple, Sleeping Murder, Agatha Christie\r\nDip, Huck, Tom Sawyer, Mark Twain\r\nRaj, Hermione, Harry Potter, J.K. Rowling\r\nRich, Darcy, Pride and Prejudice, Jane Austen\n<|im_start|>answer\nFriend, Character, Book, Author:\n\r\nDis, Marple, Sleeping Murder, Agatha Christie\r\nDip, Huck, Tom Sawyer, Mark Twain\r\nRaj, Hermione, Harry Potter, J.K. Rowling\r\nRich, Darcy, Pride and Prejudice, Jane Austen\n<|im_end|>" }, { "id": "#10143", "title": "Drills Are Us", "fun": 2.05, "difficulty": 1.13, "author": "od-1", "desc": "Mr. Od-1 had to purchase some drill bits by phone from his supplier, but neither he nor the supplier could remember if they came in packs of 10, 12 or 6. Mr. Od-1 hated the thought of getting opened packs if the supplier guessed wrong. \r\nWhat is the minimum number of drill bits Mr. Od-1 could buy to ensure he got full packs regardless of whether there were 6, 10 or 12 drill bits per pack?", "hint": "No hint available.", "answer": "60. \n\r\n60 can be divided evenly by 6, 10 and 12. If there are 6 per pack he gets 10 packs, if 10 per pack he gets 6 packs and if 12 per pack he gets 5 packs.", "category": "Math", "date": "01/31/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Od-1 had to purchase some drill bits by phone from his supplier, but neither he nor the supplier could remember if they came in packs of 10, 12 or 6. Mr. Od-1 hated the thought of getting opened packs if the supplier guessed wrong. \r\nWhat is the minimum number of drill bits Mr. Od-1 could buy to ensure he got full packs regardless of whether there were 6, 10 or 12 drill bits per pack?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n60. \n\r\n60 can be divided evenly by 6, 10 and 12. If there are 6 per pack he gets 10 packs, if 10 per pack he gets 6 packs and if 12 per pack he gets 5 packs.\n<|im_start|>answer\n60. \n\r\n60 can be divided evenly by 6, 10 and 12. If there are 6 per pack he gets 10 packs, if 10 per pack he gets 6 packs and if 12 per pack he gets 5 packs.\n<|im_end|>" }, { "id": "#48968", "title": "Multicolour Doors - Easy", "fun": 2.05, "difficulty": 0.31, "author": "coolcat101202", "desc": "Three friends all live in houses with painted doors. Can you use these clues to find out what colour door they have and what road they live on?\n\r\nFriends - Carly, Harry, Alan\r\nColours - Red, Blue, Pink\r\nStreets - Oak St, South Ave, Drury Ave\n\r\n1) Carly just loves the colour pink and she was ecstatic when her mom painted the door for her.\n\r\n2) Alan's always around at Harry's house. It's easy to get there because Oak St is only just around the corner from Alan's house.\n\r\n3) South Ave has mostly white doors, so the red one, belonging to one of the friends, stands out easily to the passing cars.\n\r\n4) Alan thinks that his friend's blue door clashes badly with their house but he doesn't want to tell them in case he hurts their feelings.", "hint": "No hint available.", "answer": "Harry lives on Oak St and has a blue door.\n\r\nCarly lives on Drury Ave and has a pink door.\n\r\nAlan lives on South Ave and has a red door.", "category": "Logic-Grid", "date": "08/20/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends all live in houses with painted doors. Can you use these clues to find out what colour door they have and what road they live on?\n\r\nFriends - Carly, Harry, Alan\r\nColours - Red, Blue, Pink\r\nStreets - Oak St, South Ave, Drury Ave\n\r\n1) Carly just loves the colour pink and she was ecstatic when her mom painted the door for her.\n\r\n2) Alan's always around at Harry's house. It's easy to get there because Oak St is only just around the corner from Alan's house.\n\r\n3) South Ave has mostly white doors, so the red one, belonging to one of the friends, stands out easily to the passing cars.\n\r\n4) Alan thinks that his friend's blue door clashes badly with their house but he doesn't want to tell them in case he hurts their feelings.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHarry lives on Oak St and has a blue door.\n\r\nCarly lives on Drury Ave and has a pink door.\n\r\nAlan lives on South Ave and has a red door.\n<|im_start|>answer\nHarry lives on Oak St and has a blue door.\n\r\nCarly lives on Drury Ave and has a pink door.\n\r\nAlan lives on South Ave and has a red door.\n<|im_end|>" }, { "id": "#49196", "title": "Jobs", "fun": 2.05, "difficulty": 0.41000000000000003, "author": "CrazyPineapple", "desc": "There are 3 people: Mr. Bob, Mr. Jim, and Mr. Smith. Each one of them has a different job. The jobs are a firefighter, a police officer, and a nurse. Each one of them has one day off: Monday, Thursday, or Sunday. Using the clues below, find out who does what job, and what day they have off.\n\n\r\n1. Mr. Jim wishes he was a nurse because it pays more money than his current job.\r\n2. Mr. Smith has a weekend day off.\r\n3. The person who has Thursday off, is not a firefighter.\r\n4. Mr. Bob is a firefighter.", "hint": "No hint available.", "answer": "Mr. Jim is a police officer, and he has Thursday off.\r\nMr. Bob is a firefighter, and he has Monday off.\r\nMr. Smith is a Nurse, and he has Sunday off.", "category": "Logic-Grid", "date": "12/17/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 3 people: Mr. Bob, Mr. Jim, and Mr. Smith. Each one of them has a different job. The jobs are a firefighter, a police officer, and a nurse. Each one of them has one day off: Monday, Thursday, or Sunday. Using the clues below, find out who does what job, and what day they have off.\n\n\r\n1. Mr. Jim wishes he was a nurse because it pays more money than his current job.\r\n2. Mr. Smith has a weekend day off.\r\n3. The person who has Thursday off, is not a firefighter.\r\n4. Mr. Bob is a firefighter.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Jim is a police officer, and he has Thursday off.\r\nMr. Bob is a firefighter, and he has Monday off.\r\nMr. Smith is a Nurse, and he has Sunday off.\n<|im_start|>answer\nMr. Jim is a police officer, and he has Thursday off.\r\nMr. Bob is a firefighter, and he has Monday off.\r\nMr. Smith is a Nurse, and he has Sunday off.\n<|im_end|>" }, { "id": "#9275", "title": "The Babysitter", "fun": 2.05, "difficulty": 1.58, "author": "lesternoronha1", "desc": "A babysitter came over one day to babysit 10 children. She decided to give them a snack. In a jar there were 10 cookies. She wants to give each one a cookie, but still keep one in the jar. How will she do it? \n\r\n(WITHOUT BREAKING ANY COOKIES, EACH CHILD HAS TO GET A WHOLE COOKIE!)", "hint": "No hint available.", "answer": "She hands the 10th child the jar with one cookie left in it.", "category": "Logic", "date": "12/21/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA babysitter came over one day to babysit 10 children. She decided to give them a snack. In a jar there were 10 cookies. She wants to give each one a cookie, but still keep one in the jar. How will she do it? \n\r\n(WITHOUT BREAKING ANY COOKIES, EACH CHILD HAS TO GET A WHOLE COOKIE!)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nShe hands the 10th child the jar with one cookie left in it.\n<|im_start|>answer\nShe hands the 10th child the jar with one cookie left in it.\n<|im_end|>" }, { "id": "#11535", "title": "Shampoo", "fun": 2.05, "difficulty": 0.59, "author": "Rosey27", "desc": "A girl needs to buy shampoo. Her choices are:\n\r\nVolumizing: $1.75 \r\nRegular: $1.00 \r\nScented: $1.50 \r\nRevitalizing: $2.50 \r\nExtra Shine: $2.00 \n\r\nWhich one will she buy? \n\r\nUse the clues below: \n\r\n1. It costs more than a dollar.\r\n2. The cost ends in zero.\r\n3. She will need to use coins if she wants to give exact change.\r\n4. She already has perfume.", "hint": "No hint available.", "answer": "Revitalizing.\n\r\nIt costs more than a dollar, its cost ends in zero, it is not an even dollar so coins will need to be used to make the fifty cents, and since she has perfume she doesn't need the scented shampoo.", "category": "Logic", "date": "04/02/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA girl needs to buy shampoo. Her choices are:\n\r\nVolumizing: $1.75 \r\nRegular: $1.00 \r\nScented: $1.50 \r\nRevitalizing: $2.50 \r\nExtra Shine: $2.00 \n\r\nWhich one will she buy? \n\r\nUse the clues below: \n\r\n1. It costs more than a dollar.\r\n2. The cost ends in zero.\r\n3. She will need to use coins if she wants to give exact change.\r\n4. She already has perfume.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRevitalizing.\n\r\nIt costs more than a dollar, its cost ends in zero, it is not an even dollar so coins will need to be used to make the fifty cents, and since she has perfume she doesn't need the scented shampoo.\n<|im_start|>answer\nRevitalizing.\n\r\nIt costs more than a dollar, its cost ends in zero, it is not an even dollar so coins will need to be used to make the fifty cents, and since she has perfume she doesn't need the scented shampoo.\n<|im_end|>" }, { "id": "#8040", "title": "Maze Girl", "fun": 2.04, "difficulty": 2.9, "author": "bluelightnign", "desc": "A treasure is hidden in the middle of a maze. Each step is 1 m. The person starts at the entrance of the maze. She travels at 3 km's per hour. She starts facing north. \n\r\nShe takes 4 steps forward, then turns right. She then takes 2 steps and turns 45 degrees northwest. She then walks until she is exactly north of where she began. She then turns 90 degrees to her right, then walks in that exact direction until she is directly north of where she first turned 45 degrees. She then turns and faces directly north. She walks twice as far as she has already walked and turns left. She then walks a 1/4 as far as she has walked at an angle of 45 degrees. She then turns north and walks twice as far as she has previously walked north. She then turns right and takes 9 steps. She picks up the ruby and walks the same distance she has previously walked in the maze, but instead she continues walking east. After she walks this far, she sits down on a bench in the maze and is arrested. How long did the girl spend walking in the maze until she was arrested? She walked twice as fast after she got the ruby. Answer in seconds.", "hint": "After she walks two paces northwest, she walks another two paces northeast because she does not turn north after walking two paces northwest.", "answer": "4m + 2m + (2m x tan 45 degrees) + (2m x tan 45 degrees) + 20m + 1m + 48m + 9m + 88 = 176 m. 88 m at 3 km per hour = (1/((3km/0.088km)) x 3600) = 105.6 seconds.\r\nDouble the speed = 105.6/2 = 52.8 seconds.\r\nTime spent in maze = 158.4 seconds.", "category": "Math", "date": "10/24/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA treasure is hidden in the middle of a maze. Each step is 1 m. The person starts at the entrance of the maze. She travels at 3 km's per hour. She starts facing north. \n\r\nShe takes 4 steps forward, then turns right. She then takes 2 steps and turns 45 degrees northwest. She then walks until she is exactly north of where she began. She then turns 90 degrees to her right, then walks in that exact direction until she is directly north of where she first turned 45 degrees. She then turns and faces directly north. She walks twice as far as she has already walked and turns left. She then walks a 1/4 as far as she has walked at an angle of 45 degrees. She then turns north and walks twice as far as she has previously walked north. She then turns right and takes 9 steps. She picks up the ruby and walks the same distance she has previously walked in the maze, but instead she continues walking east. After she walks this far, she sits down on a bench in the maze and is arrested. How long did the girl spend walking in the maze until she was arrested? She walked twice as fast after she got the ruby. Answer in seconds.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4m + 2m + (2m x tan 45 degrees) + (2m x tan 45 degrees) + 20m + 1m + 48m + 9m + 88 = 176 m. 88 m at 3 km per hour = (1/((3km/0.088km)) x 3600) = 105.6 seconds.\r\nDouble the speed = 105.6/2 = 52.8 seconds.\r\nTime spent in maze = 158.4 seconds.\n<|im_start|>answer\n4m + 2m + (2m x tan 45 degrees) + (2m x tan 45 degrees) + 20m + 1m + 48m + 9m + 88 = 176 m. 88 m at 3 km per hour = (1/((3km/0.088km)) x 3600) = 105.6 seconds.\r\nDouble the speed = 105.6/2 = 52.8 seconds.\r\nTime spent in maze = 158.4 seconds.\n<|im_end|>" }, { "id": "#38546", "title": "Which Socks Should You Wear?", "fun": 2.04, "difficulty": 1.37, "author": "wannamarryharry", "desc": "A drawer contains 10 red socks and 10 black socks that are all mixed up. What is the fewest number of socks you can take from the drawer without looking and be sure to get a pair of the same color?", "hint": "There are two socks in each pair of socks.", "answer": "Three socks; you will have either two socks of one color or three socks of one color.", "category": "Math", "date": "09/30/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA drawer contains 10 red socks and 10 black socks that are all mixed up. What is the fewest number of socks you can take from the drawer without looking and be sure to get a pair of the same color?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThree socks; you will have either two socks of one color or three socks of one color.\n<|im_start|>answer\nThree socks; you will have either two socks of one color or three socks of one color.\n<|im_end|>" }, { "id": "#42321", "title": "Fish, Planes, and Flags", "fun": 2.04, "difficulty": 2.31, "author": "Abstain", "desc": "David's father is in charge of decorating the 2-layer cake for Great Grampa's birthday. Great Grampa's birthday is on the Fourth of July, he used to be a pilot, and he loves fishing. David and his father have decided to decorate the sides of the bottom layer of the cake (measuring 9 in. * 15 in.) with fish and the sides of the top layer (6 in. * 9 in.) with airplanes. They are going to wrap a flag around each corner of both layers. Each decoration is 1 inch wide, and each flag is folded so that one-half inch of flag shows at each side of the corner.\n\r\nShow one corner of one layer with the Polish flag in place, with 1/2 of the flag visible on each side.\n\r\n\"We need 2 inches between all decorations,\" says David's father. \"Otherwise it will look too crowded.\"\n\r\nHow many decorations of each kind do David and his father need?", "hint": "Start with a diagram of the longest side, and plan the arrangement for that side. Don't forget the flags!", "answer": "David and his father need 8 flags, 12 fish, and 6 airplanes.\n\r\nDavid and his father will place 12 fish decorations along the bottom layer of the cake.\n\r\nEach of the longer sides of the bottom layer measures 15 in. Allowing 1/2 in. at each end for the flags and 2 in. between all the 1 in. decorations, they can place 4 fish along each 15 in. side like this:\n\r\n(flag) (fish) (fish) (fish) (fish) (flag) \r\n1/2 in. +2 in. +1 in. +2 in. +1 in. +2 in. + 1 in. +2 in. +1 in. +2 in. + 1/2 in. = 15 in. \n\r\nEach of the shorter sides of the bottom layer measures 9 in. They can place 2 fish along this short side:\n\r\n(flag) (fish) (fish) (flag) \r\n1/2 in. +2 in. +1 in. +2 in. +1 in. +2 in. + 1/2 in. = 9 in. \n\r\nAltogether, they can fit 12 fish (4 + 4 + 2 + 2 = 12) along the bottom layer.\n\r\nThe longer side of the top layer is the same length as the shorter side of the bottom layer. David and his father can fit 4 (2 + 2) airplanes on the longer sides of the top layer. \n\r\nOn each 6-in. side of the top layer they can fit just 1 airplane, like this: \n\r\n(flag) (plane) (flag) \r\n1/2 in. + 2 in. + 1 in. + 2 in. + 1/2 in. = 6 in. \n\r\nAltogether, they can fit 6 airplanes (2 + 2 + 1 + 1 = 6) on the top layer.", "category": "Math", "date": "06/23/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDavid's father is in charge of decorating the 2-layer cake for Great Grampa's birthday. Great Grampa's birthday is on the Fourth of July, he used to be a pilot, and he loves fishing. David and his father have decided to decorate the sides of the bottom layer of the cake (measuring 9 in. * 15 in.) with fish and the sides of the top layer (6 in. * 9 in.) with airplanes. They are going to wrap a flag around each corner of both layers. Each decoration is 1 inch wide, and each flag is folded so that one-half inch of flag shows at each side of the corner.\n\r\nShow one corner of one layer with the Polish flag in place, with 1/2 of the flag visible on each side.\n\r\n\"We need 2 inches between all decorations,\" says David's father. \"Otherwise it will look too crowded.\"\n\r\nHow many decorations of each kind do David and his father need?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDavid and his father need 8 flags, 12 fish, and 6 airplanes.\n\r\nDavid and his father will place 12 fish decorations along the bottom layer of the cake.\n\r\nEach of the longer sides of the bottom layer measures 15 in. Allowing 1/2 in. at each end for the flags and 2 in. between all the 1 in. decorations, they can place 4 fish along each 15 in. side like this:\n\r\n(flag) (fish) (fish) (fish) (fish) (flag) \r\n1/2 in. +2 in. +1 in. +2 in. +1 in. +2 in. + 1 in. +2 in. +1 in. +2 in. + 1/2 in. = 15 in. \n\r\nEach of the shorter sides of the bottom layer measures 9 in. They can place 2 fish along this short side:\n\r\n(flag) (fish) (fish) (flag) \r\n1/2 in. +2 in. +1 in. +2 in. +1 in. +2 in. + 1/2 in. = 9 in. \n\r\nAltogether, they can fit 12 fish (4 + 4 + 2 + 2 = 12) along the bottom layer.\n\r\nThe longer side of the top layer is the same length as the shorter side of the bottom layer. David and his father can fit 4 (2 + 2) airplanes on the longer sides of the top layer. \n\r\nOn each 6-in. side of the top layer they can fit just 1 airplane, like this: \n\r\n(flag) (plane) (flag) \r\n1/2 in. + 2 in. + 1 in. + 2 in. + 1/2 in. = 6 in. \n\r\nAltogether, they can fit 6 airplanes (2 + 2 + 1 + 1 = 6) on the top layer.\n<|im_start|>answer\nDavid and his father need 8 flags, 12 fish, and 6 airplanes.\n\r\nDavid and his father will place 12 fish decorations along the bottom layer of the cake.\n\r\nEach of the longer sides of the bottom layer measures 15 in. Allowing 1/2 in. at each end for the flags and 2 in. between all the 1 in. decorations, they can place 4 fish along each 15 in. side like this:\n\r\n(flag) (fish) (fish) (fish) (fish) (flag) \r\n1/2 in. +2 in. +1 in. +2 in. +1 in. +2 in. + 1 in. +2 in. +1 in. +2 in. + 1/2 in. = 15 in. \n\r\nEach of the shorter sides of the bottom layer measures 9 in. They can place 2 fish along this short side:\n\r\n(flag) (fish) (fish) (flag) \r\n1/2 in. +2 in. +1 in. +2 in. +1 in. +2 in. + 1/2 in. = 9 in. \n\r\nAltogether, they can fit 12 fish (4 + 4 + 2 + 2 = 12) along the bottom layer.\n\r\nThe longer side of the top layer is the same length as the shorter side of the bottom layer. David and his father can fit 4 (2 + 2) airplanes on the longer sides of the top layer. \n\r\nOn each 6-in. side of the top layer they can fit just 1 airplane, like this: \n\r\n(flag) (plane) (flag) \r\n1/2 in. + 2 in. + 1 in. + 2 in. + 1/2 in. = 6 in. \n\r\nAltogether, they can fit 6 airplanes (2 + 2 + 1 + 1 = 6) on the top layer.\n<|im_end|>" }, { "id": "#3471", "title": "Special Number", "fun": 2.04, "difficulty": 2.87, "author": "spysniper21", "desc": "What is so special about this particular sequence of numbers?\n\r\n425260376469080434957", "hint": "No hint available.", "answer": "If you add 1 to every digit of pi(3.1415926535...) you get the sequence.", "category": "Math", "date": "04/13/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is so special about this particular sequence of numbers?\n\r\n425260376469080434957\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf you add 1 to every digit of pi(3.1415926535...) you get the sequence.\n<|im_start|>answer\nIf you add 1 to every digit of pi(3.1415926535...) you get the sequence.\n<|im_end|>" }, { "id": "#43406", "title": "The Four Digit Number", "fun": 2.04, "difficulty": 1.3800000000000001, "author": "twin27", "desc": "There are 4 digits in a number. Using these clues, figure out what the digits are. Each blank can only contain a one digit number. The answer and clues will use this lettering to put them in an order.\n\r\n_ _ _ _\r\nA B C D\n\r\nHere are the clues.\r\nDigit C is one more than digit A, which is twice digit D, which is ten less than digit A plus 8. Digit B is digit A+C+D minus two.\n\r\nWhat is the number?", "hint": "No hint available.", "answer": "Digit A is 4, digit B is 9, digit C is 5, and digit D is 2. So the numeral is 4952.", "category": "Math", "date": "10/23/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are 4 digits in a number. Using these clues, figure out what the digits are. Each blank can only contain a one digit number. The answer and clues will use this lettering to put them in an order.\n\r\n_ _ _ _\r\nA B C D\n\r\nHere are the clues.\r\nDigit C is one more than digit A, which is twice digit D, which is ten less than digit A plus 8. Digit B is digit A+C+D minus two.\n\r\nWhat is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDigit A is 4, digit B is 9, digit C is 5, and digit D is 2. So the numeral is 4952.\n<|im_start|>answer\nDigit A is 4, digit B is 9, digit C is 5, and digit D is 2. So the numeral is 4952.\n<|im_end|>" }, { "id": "#22251", "title": "New Squares", "fun": 2.04, "difficulty": 2.9, "author": "filetmerlot", "desc": "4 7 9\r\n2 8 7\r\n3 6 4\n\r\n6 9 3\r\n7 8 8\r\n6 1 0\n\r\n8 3 5\r\n2 4 9\r\n1 9 2\n\r\n5 7 6\r\n3 1 8\r\nx x+1 x+2\n\r\nWhat number does x represent?", "hint": "No hint available.", "answer": "2. \r\nMultiply the top row across, then the second row across. The sum of these two will be the written as the third row. 5x7x6=210\r\n3x1x8=24\r\nTherefore 210+24=234.", "category": "Math", "date": "04/14/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n4 7 9\r\n2 8 7\r\n3 6 4\n\r\n6 9 3\r\n7 8 8\r\n6 1 0\n\r\n8 3 5\r\n2 4 9\r\n1 9 2\n\r\n5 7 6\r\n3 1 8\r\nx x+1 x+2\n\r\nWhat number does x represent?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2. \r\nMultiply the top row across, then the second row across. The sum of these two will be the written as the third row. 5x7x6=210\r\n3x1x8=24\r\nTherefore 210+24=234.\n<|im_start|>answer\n2. \r\nMultiply the top row across, then the second row across. The sum of these two will be the written as the third row. 5x7x6=210\r\n3x1x8=24\r\nTherefore 210+24=234.\n<|im_end|>" }, { "id": "#43446", "title": "Four Athletes", "fun": 2.04, "difficulty": 1.6400000000000001, "author": "shenqiang", "desc": "Alan, Brian, Charlie and Dave took part in a running competition. There were no ties.\n\r\nAlan said: \"I'm second, and Brian is third.\"\r\nBrian said: \"I'm second, and Charlie is last.\"\r\nCharlie said: \"I'm third, and Dave is second.\"\r\nDave said: \"I'm third, and Alan is first.\"\n\r\nHowever, each person made one true statement true and one false statement. Can you determine which place Charlie ran?", "hint": "Look carefully.", "answer": "Alan, Brain and Charlie each made a statement about who ran second. However, only one person could run second, therefore, at least two of these three statements must be false.\n\r\nHence, their other three statements must have at least two true ones: \"Brian is third\", \"Charlie is last\", and \"Charlie is third\". Obviously, \"Charlie is third\" must be false, and Charlie must be last.", "category": "Logic", "date": "10/29/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAlan, Brian, Charlie and Dave took part in a running competition. There were no ties.\n\r\nAlan said: \"I'm second, and Brian is third.\"\r\nBrian said: \"I'm second, and Charlie is last.\"\r\nCharlie said: \"I'm third, and Dave is second.\"\r\nDave said: \"I'm third, and Alan is first.\"\n\r\nHowever, each person made one true statement true and one false statement. Can you determine which place Charlie ran?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlan, Brain and Charlie each made a statement about who ran second. However, only one person could run second, therefore, at least two of these three statements must be false.\n\r\nHence, their other three statements must have at least two true ones: \"Brian is third\", \"Charlie is last\", and \"Charlie is third\". Obviously, \"Charlie is third\" must be false, and Charlie must be last.\n<|im_start|>answer\nAlan, Brain and Charlie each made a statement about who ran second. However, only one person could run second, therefore, at least two of these three statements must be false.\n\r\nHence, their other three statements must have at least two true ones: \"Brian is third\", \"Charlie is last\", and \"Charlie is third\". Obviously, \"Charlie is third\" must be false, and Charlie must be last.\n<|im_end|>" }, { "id": "#2072", "title": "Clown Party", "fun": 2.04, "difficulty": 1.37, "author": "jokester8000", "desc": "Jake wants to hire a clown for his daughter's birthday. It costs him $18.45. He has the clown come from 10am to 7pm. How much is the hourly rate?", "hint": "No hint available.", "answer": "$2.05 an hour.", "category": "Math", "date": "01/19/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJake wants to hire a clown for his daughter's birthday. It costs him $18.45. He has the clown come from 10am to 7pm. How much is the hourly rate?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n$2.05 an hour.\n<|im_start|>answer\n$2.05 an hour.\n<|im_end|>" }, { "id": "#10063", "title": "All In The Family", "fun": 2.04, "difficulty": 1.37, "author": "Gmoney-Gdog", "desc": "Joe's dad is three times older than Joe. Joe's grandfather is twice as old as Joe's dad. The sum of all their ages is 100. How old are Joe, his dad, and his grandfather?", "hint": "No hint available.", "answer": "Joe is 10, his father is 30, and his grandfather is 60.\n\r\nSet up the equations:\n\r\nD = 3 * J\r\nG = 2 * D\r\nJ + D + G = 100\n\r\nSolve these to get the answer.", "category": "Math", "date": "01/26/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoe's dad is three times older than Joe. Joe's grandfather is twice as old as Joe's dad. The sum of all their ages is 100. How old are Joe, his dad, and his grandfather?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoe is 10, his father is 30, and his grandfather is 60.\n\r\nSet up the equations:\n\r\nD = 3 * J\r\nG = 2 * D\r\nJ + D + G = 100\n\r\nSolve these to get the answer.\n<|im_start|>answer\nJoe is 10, his father is 30, and his grandfather is 60.\n\r\nSet up the equations:\n\r\nD = 3 * J\r\nG = 2 * D\r\nJ + D + G = 100\n\r\nSolve these to get the answer.\n<|im_end|>" }, { "id": "#40706", "title": "Follow the Rules!", "fun": 2.04, "difficulty": 2.06, "author": "kratsg", "desc": "You have four cards on the table:\n\r\n[ BRAIN ] [ strain ] [ MIND ] [ teaser ]\n\r\nYou know that each card has capitalized letters on one side and lowercase letters on the other. There is a rule that says, \"If a card has 'BRAIN' on one side, it must have 'strain' on the other.\"\n\r\nWhich card(s) must be turned over to make sure that the rule was not violated?", "hint": "Rules, rules, rules...", "answer": "Two cards: [ BRAIN ] and [ teaser ].\n\r\nLet's examine this card by card...\n\r\n[ BRAIN ] - this must have [ strain ] on the other side or else we would violate the rule, therefore we must turn this card over.\n\r\n[ strain ] - this \"can\" have but doesn't require [ BRAIN ] on the other side. If it does, the rule is not violated. If it doesn't, the rule is still not violated. Therefore, we do not need to turn this card over.\n\r\n[ MIND ] - will not violate the rule since it was stated that lowercase must be on the other side of this card. We do not need to turn this over.\n\r\n[ teaser ] - this can violate the rule. First situation is not having [ BRAIN ] on the other side which does not violate the rule. Second situation is having [ BRAIN ] on the other side which DOES violate the rule. Therefore, we need to turn this one over too.", "category": "Logic", "date": "02/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou have four cards on the table:\n\r\n[ BRAIN ] [ strain ] [ MIND ] [ teaser ]\n\r\nYou know that each card has capitalized letters on one side and lowercase letters on the other. There is a rule that says, \"If a card has 'BRAIN' on one side, it must have 'strain' on the other.\"\n\r\nWhich card(s) must be turned over to make sure that the rule was not violated?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTwo cards: [ BRAIN ] and [ teaser ].\n\r\nLet's examine this card by card...\n\r\n[ BRAIN ] - this must have [ strain ] on the other side or else we would violate the rule, therefore we must turn this card over.\n\r\n[ strain ] - this \"can\" have but doesn't require [ BRAIN ] on the other side. If it does, the rule is not violated. If it doesn't, the rule is still not violated. Therefore, we do not need to turn this card over.\n\r\n[ MIND ] - will not violate the rule since it was stated that lowercase must be on the other side of this card. We do not need to turn this over.\n\r\n[ teaser ] - this can violate the rule. First situation is not having [ BRAIN ] on the other side which does not violate the rule. Second situation is having [ BRAIN ] on the other side which DOES violate the rule. Therefore, we need to turn this one over too.\n<|im_start|>answer\nTwo cards: [ BRAIN ] and [ teaser ].\n\r\nLet's examine this card by card...\n\r\n[ BRAIN ] - this must have [ strain ] on the other side or else we would violate the rule, therefore we must turn this card over.\n\r\n[ strain ] - this \"can\" have but doesn't require [ BRAIN ] on the other side. If it does, the rule is not violated. If it doesn't, the rule is still not violated. Therefore, we do not need to turn this card over.\n\r\n[ MIND ] - will not violate the rule since it was stated that lowercase must be on the other side of this card. We do not need to turn this over.\n\r\n[ teaser ] - this can violate the rule. First situation is not having [ BRAIN ] on the other side which does not violate the rule. Second situation is having [ BRAIN ] on the other side which DOES violate the rule. Therefore, we need to turn this one over too.\n<|im_end|>" }, { "id": "#40557", "title": "Dartboard", "fun": 2.04, "difficulty": 2.04, "author": "TRILLIONAIRE", "desc": "Robin scored exactly 100 on a dart board with a bulls-eye of 40 points and rings of 39, 24, 17 and 16 points. How many darts did Robin throw and where did they land?", "hint": "Robin's darts landed in only two different zones.", "answer": "Robin scored 100 points by throwing six darts that scored 17, 17, 17, 17, 16, and 16.", "category": "Math", "date": "02/17/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nRobin scored exactly 100 on a dart board with a bulls-eye of 40 points and rings of 39, 24, 17 and 16 points. How many darts did Robin throw and where did they land?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nRobin scored 100 points by throwing six darts that scored 17, 17, 17, 17, 16, and 16.\n<|im_start|>answer\nRobin scored 100 points by throwing six darts that scored 17, 17, 17, 17, 16, and 16.\n<|im_end|>" }, { "id": "#40846", "title": "What is the Number?", "fun": 2.04, "difficulty": 2.69, "author": "lab123", "desc": "There is a number. \n\r\n1. If it is not a multiple of 4, then it is between 60 and 69.\r\n2. If it is a multiple of 3 it is between 50 and 59.\r\n3. If it is not a multiple of 6 it is between 70 and 79. \n\r\nWhat is the number?", "hint": "No hint available.", "answer": "76", "category": "Math", "date": "03/04/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a number. \n\r\n1. If it is not a multiple of 4, then it is between 60 and 69.\r\n2. If it is a multiple of 3 it is between 50 and 59.\r\n3. If it is not a multiple of 6 it is between 70 and 79. \n\r\nWhat is the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n76\n<|im_start|>answer\n76\n<|im_end|>" }, { "id": "#44639", "title": "Pay it Off", "fun": 2.04, "difficulty": 1.1, "author": "Rob7", "desc": "Using only three bills, and not using a $10 bill, how can you pay a person $35 that you owe?", "hint": "The three bills are two $20s and a $5 bill.", "answer": "You pay the person $40 using two $20 bills. Then the person pays you back $5, using a $5 bill. You paid $35, and three bills were used.", "category": "Logic", "date": "06/13/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nUsing only three bills, and not using a $10 bill, how can you pay a person $35 that you owe?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nYou pay the person $40 using two $20 bills. Then the person pays you back $5, using a $5 bill. You paid $35, and three bills were used.\n<|im_start|>answer\nYou pay the person $40 using two $20 bills. Then the person pays you back $5, using a $5 bill. You paid $35, and three bills were used.\n<|im_end|>" }, { "id": "#3758", "title": "Sums in a Code", "fun": 2.03, "difficulty": 2.48, "author": "FTM-Byau", "desc": "Crack this code (Letters represent numbers 0-9)\r\nYou add horizontally, (HCA+ZAA=BKZ)\r\nAnd add vertically (BKZ+HRC=AKLR)\n\r\nHCA+ZAA = BKZ\r\nCCL+CAK = HRC\r\n______________\r\nLTM+RZR = AKLR", "hint": "No hint available.", "answer": "631+211= 842\r\n339+314= 653\r\n____________\r\n970+525=1495", "category": "Math", "date": "04/29/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCrack this code (Letters represent numbers 0-9)\r\nYou add horizontally, (HCA+ZAA=BKZ)\r\nAnd add vertically (BKZ+HRC=AKLR)\n\r\nHCA+ZAA = BKZ\r\nCCL+CAK = HRC\r\n______________\r\nLTM+RZR = AKLR\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n631+211= 842\r\n339+314= 653\r\n____________\r\n970+525=1495\n<|im_start|>answer\n631+211= 842\r\n339+314= 653\r\n____________\r\n970+525=1495\n<|im_end|>" }, { "id": "#1378", "title": "Only 8's", "fun": 2.03, "difficulty": 1.25, "author": "psychodude57", "desc": "What is the smallest integer, which, when multiplied by 2 gives a number consisting of only 8's?", "hint": "No hint available.", "answer": "4.", "category": "Math", "date": "11/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the smallest integer, which, when multiplied by 2 gives a number consisting of only 8's?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n4.\n<|im_start|>answer\n4.\n<|im_end|>" }, { "id": "#6619", "title": "Add Up", "fun": 2.03, "difficulty": 1.78, "author": "Bekki", "desc": "If John is 7 and Bob is 3 years older than John and Jack is half the age of Bob and Sally is Jack's age plus 8, then how old is Sally?", "hint": "No hint available.", "answer": "John is 7, Bob is 3 years older. Bob is 10.\r\nJack is half Bob's age. Jack is 5.\r\nSally is Jack's age plus 8. Sally is 13.", "category": "Math", "date": "08/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf John is 7 and Bob is 3 years older than John and Jack is half the age of Bob and Sally is Jack's age plus 8, then how old is Sally?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn is 7, Bob is 3 years older. Bob is 10.\r\nJack is half Bob's age. Jack is 5.\r\nSally is Jack's age plus 8. Sally is 13.\n<|im_start|>answer\nJohn is 7, Bob is 3 years older. Bob is 10.\r\nJack is half Bob's age. Jack is 5.\r\nSally is Jack's age plus 8. Sally is 13.\n<|im_end|>" }, { "id": "#35680", "title": "3 Integers", "fun": 2.03, "difficulty": 0.87, "author": "mik512", "desc": "What are the only three consecutive increasing integers that when you add the first two you get the third?", "hint": "a+b=c", "answer": "1, 2, and 3", "category": "Math", "date": "03/14/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat are the only three consecutive increasing integers that when you add the first two you get the third?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1, 2, and 3\n<|im_start|>answer\n1, 2, and 3\n<|im_end|>" }, { "id": "#40298", "title": "Nine Tests", "fun": 2.03, "difficulty": 1.83, "author": "shenqiang", "desc": "Naoki took nine tests, each out of 100. His average on these nine tests is 68. If his lowest mark is omitted, what is his highest possible resulting average?", "hint": "No hint available.", "answer": "Of course, if he got 0 in one of the tests, and gets omitted, then the resulting average will be the highest. 68x9/8=76.5 points.", "category": "Math", "date": "02/02/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNaoki took nine tests, each out of 100. His average on these nine tests is 68. If his lowest mark is omitted, what is his highest possible resulting average?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nOf course, if he got 0 in one of the tests, and gets omitted, then the resulting average will be the highest. 68x9/8=76.5 points.\n<|im_start|>answer\nOf course, if he got 0 in one of the tests, and gets omitted, then the resulting average will be the highest. 68x9/8=76.5 points.\n<|im_end|>" }, { "id": "#21187", "title": "Favorite Colors", "fun": 2.03, "difficulty": 0.51, "author": "JessicaLynn", "desc": "Jessica, Jennifer, and Jordan all have different favorite colors. (yellow, purple, and red.) They also have three different favorite foods. Figure out who likes what color and what food (french fries, hamburgers, and ice cream) with these clues.\n\r\n 1) Jessica, whose favorite color is not red, loves ice cream the most. \r\n2) The person who likes red also likes hamburgers.\r\n3) Jordan's favorite color is yellow.", "hint": "No hint available.", "answer": "Jordan-yellow-french fries \r\nJessica-purple-ice cream\r\nJennifer-red-hamburgers", "category": "Logic-Grid", "date": "02/23/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJessica, Jennifer, and Jordan all have different favorite colors. (yellow, purple, and red.) They also have three different favorite foods. Figure out who likes what color and what food (french fries, hamburgers, and ice cream) with these clues.\n\r\n 1) Jessica, whose favorite color is not red, loves ice cream the most. \r\n2) The person who likes red also likes hamburgers.\r\n3) Jordan's favorite color is yellow.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJordan-yellow-french fries \r\nJessica-purple-ice cream\r\nJennifer-red-hamburgers\n<|im_start|>answer\nJordan-yellow-french fries \r\nJessica-purple-ice cream\r\nJennifer-red-hamburgers\n<|im_end|>" }, { "id": "#651", "title": "Half of Five", "fun": 2.03, "difficulty": 2.0, "author": "vikass", "desc": "If half of 5 is 3; then how much is \r\none-third of 10?", "hint": "No hint available.", "answer": "Answer: 4\r\nIf half of five is 3, then 5 is not actually\r\nfive; it represents 6. If 5 represents six,\r\nthen 10 would in fact represent 12.", "category": "Logic", "date": "06/27/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf half of 5 is 3; then how much is \r\none-third of 10?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAnswer: 4\r\nIf half of five is 3, then 5 is not actually\r\nfive; it represents 6. If 5 represents six,\r\nthen 10 would in fact represent 12.\n<|im_start|>answer\nAnswer: 4\r\nIf half of five is 3, then 5 is not actually\r\nfive; it represents 6. If 5 represents six,\r\nthen 10 would in fact represent 12.\n<|im_end|>" }, { "id": "#31489", "title": "Sports, Girls and Activities", "fun": 2.03, "difficulty": 0.81, "author": "brain_dead", "desc": "Four very different girls all play sports. None of them play the same sport. Each girl does something in her spare time, that is not a sport. So, you need to figure out which girl plays what sport, and what she does in her spare time.\n\r\n~Sports~ \r\nBaseball\r\nSoftball\r\nGolf\r\nCheerleading\n\r\n~Girls~\r\nTrina\r\nBri\r\nJonica\r\nNikki\n\r\n~Spare time~\r\nRead\r\nSings\r\nArts and crafts\r\nShops\n\r\n~Clues~\r\n* Nikki's sport is played with a ball.\r\n* Trina is super flexible.\r\n* Jonica is not very creative.\r\n* Bri plays with the biggest ball of the group.\r\n* Trina is at all the games, but is not playing them.\r\n* Nikki always knows when sales are going on.\r\n* Trina is creative.\r\n* Jonica can't read.\r\n* Nikki plays with a bat.\r\n* Jonica has an amazing voice.", "hint": "No hint available.", "answer": "Trina is a cheerleader and does arts and crafts.\r\nJonica plays golf and sings.\r\nBri plays softball and reads.\r\nNikki plays baseball and shops.", "category": "Logic-Grid", "date": "07/02/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour very different girls all play sports. None of them play the same sport. Each girl does something in her spare time, that is not a sport. So, you need to figure out which girl plays what sport, and what she does in her spare time.\n\r\n~Sports~ \r\nBaseball\r\nSoftball\r\nGolf\r\nCheerleading\n\r\n~Girls~\r\nTrina\r\nBri\r\nJonica\r\nNikki\n\r\n~Spare time~\r\nRead\r\nSings\r\nArts and crafts\r\nShops\n\r\n~Clues~\r\n* Nikki's sport is played with a ball.\r\n* Trina is super flexible.\r\n* Jonica is not very creative.\r\n* Bri plays with the biggest ball of the group.\r\n* Trina is at all the games, but is not playing them.\r\n* Nikki always knows when sales are going on.\r\n* Trina is creative.\r\n* Jonica can't read.\r\n* Nikki plays with a bat.\r\n* Jonica has an amazing voice.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTrina is a cheerleader and does arts and crafts.\r\nJonica plays golf and sings.\r\nBri plays softball and reads.\r\nNikki plays baseball and shops.\n<|im_start|>answer\nTrina is a cheerleader and does arts and crafts.\r\nJonica plays golf and sings.\r\nBri plays softball and reads.\r\nNikki plays baseball and shops.\n<|im_end|>" }, { "id": "#3963", "title": "Fish Length", "fun": 2.03, "difficulty": 2.09, "author": "mad-ade", "desc": "A fish has a tail as long as its head and a quarter the length of its body. Its body is 3 quarters of its total length. Its head is 4 inches long.\n\r\nHow long is the fish?", "hint": "No hint available.", "answer": "128 inches\r\nhead = 4 inches\r\nbody = 96 inches\r\ntail = 28 inches", "category": "Math", "date": "05/08/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA fish has a tail as long as its head and a quarter the length of its body. Its body is 3 quarters of its total length. Its head is 4 inches long.\n\r\nHow long is the fish?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n128 inches\r\nhead = 4 inches\r\nbody = 96 inches\r\ntail = 28 inches\n<|im_start|>answer\n128 inches\r\nhead = 4 inches\r\nbody = 96 inches\r\ntail = 28 inches\n<|im_end|>" }, { "id": "#4724", "title": "7/28", "fun": 2.03, "difficulty": 1.6, "author": "librashorty", "desc": "If 7/28 of 64 is 16 and 9/12 of 100 is 75 and 3/9 of 33 is 11, what is 5/15 of 45?", "hint": "No hint available.", "answer": "15; using normal math", "category": "Math", "date": "06/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf 7/28 of 64 is 16 and 9/12 of 100 is 75 and 3/9 of 33 is 11, what is 5/15 of 45?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n15; using normal math\n<|im_start|>answer\n15; using normal math\n<|im_end|>" }, { "id": "#48781", "title": "Terminate Average", "fun": 2.03, "difficulty": 2.37, "author": "Mathgeek007", "desc": "There is a scoring system in which the highest is 4, and the lowest is 1, and you may only vote whole numbers.\n\r\nImagine that six people voted before you, and they all voted the same thing, however you do not know what they rated. You vote seventh, and your two friends behind you would vote whatever you did.\n\r\nIf you are the one in the end tallying the scores, and you want the average to be a simple, terminating decimal number, what would your best bet to vote for be?", "hint": "No hint available.", "answer": "The format of the answers will be...\n\r\n[Previous 6], [Your Choice], [Average of all 9]\n\r\n1, 1, 1\r\n1, 2, 1.3(cont)\r\n1, 3, 1.6(cont)\r\n1, 4, 2\n\r\n2, 1, 1.6(cont)\r\n2, 2, 2\r\n2, 3, 2.3(cont)\r\n2, 4, 2.6(cont)\n\r\n3, 1, 2.3(cont)\r\n3, 2, 2.6(cont)\r\n3, 3, 3\r\n3, 4, 3.3(cont)\n\r\n4, 1, 3\r\n4, 2, 3.3(cont)\r\n4, 3, 3.6(cont)\r\n4, 4, 4\n\r\nIf you choose 1, then you have a 2/4 chance of having a terminating end average.\n\r\nIf you choose 2, then you will have a 1/4 chance of having a terminating average.\n\r\nIf you choose 3, then you will have a 1/4 chance of having a terminating average.\n\r\nIf you choose 4, then you will have a 2/4 chance of having a terminating average.\n\r\nYour best bets are choosing 1 or 4. Now, you can still vote based on whether you liked it or not. If you did, then you choose 4. If you didn't, choose 1. If you choose 1 or 4, it won't have a difference on whether the average is terminating or not.", "category": "Math", "date": "05/31/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a scoring system in which the highest is 4, and the lowest is 1, and you may only vote whole numbers.\n\r\nImagine that six people voted before you, and they all voted the same thing, however you do not know what they rated. You vote seventh, and your two friends behind you would vote whatever you did.\n\r\nIf you are the one in the end tallying the scores, and you want the average to be a simple, terminating decimal number, what would your best bet to vote for be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe format of the answers will be...\n\r\n[Previous 6], [Your Choice], [Average of all 9]\n\r\n1, 1, 1\r\n1, 2, 1.3(cont)\r\n1, 3, 1.6(cont)\r\n1, 4, 2\n\r\n2, 1, 1.6(cont)\r\n2, 2, 2\r\n2, 3, 2.3(cont)\r\n2, 4, 2.6(cont)\n\r\n3, 1, 2.3(cont)\r\n3, 2, 2.6(cont)\r\n3, 3, 3\r\n3, 4, 3.3(cont)\n\r\n4, 1, 3\r\n4, 2, 3.3(cont)\r\n4, 3, 3.6(cont)\r\n4, 4, 4\n\r\nIf you choose 1, then you have a 2/4 chance of having a terminating end average.\n\r\nIf you choose 2, then you will have a 1/4 chance of having a terminating average.\n\r\nIf you choose 3, then you will have a 1/4 chance of having a terminating average.\n\r\nIf you choose 4, then you will have a 2/4 chance of having a terminating average.\n\r\nYour best bets are choosing 1 or 4. Now, you can still vote based on whether you liked it or not. If you did, then you choose 4. If you didn't, choose 1. If you choose 1 or 4, it won't have a difference on whether the average is terminating or not.\n<|im_start|>answer\nThe format of the answers will be...\n\r\n[Previous 6], [Your Choice], [Average of all 9]\n\r\n1, 1, 1\r\n1, 2, 1.3(cont)\r\n1, 3, 1.6(cont)\r\n1, 4, 2\n\r\n2, 1, 1.6(cont)\r\n2, 2, 2\r\n2, 3, 2.3(cont)\r\n2, 4, 2.6(cont)\n\r\n3, 1, 2.3(cont)\r\n3, 2, 2.6(cont)\r\n3, 3, 3\r\n3, 4, 3.3(cont)\n\r\n4, 1, 3\r\n4, 2, 3.3(cont)\r\n4, 3, 3.6(cont)\r\n4, 4, 4\n\r\nIf you choose 1, then you have a 2/4 chance of having a terminating end average.\n\r\nIf you choose 2, then you will have a 1/4 chance of having a terminating average.\n\r\nIf you choose 3, then you will have a 1/4 chance of having a terminating average.\n\r\nIf you choose 4, then you will have a 2/4 chance of having a terminating average.\n\r\nYour best bets are choosing 1 or 4. Now, you can still vote based on whether you liked it or not. If you did, then you choose 4. If you didn't, choose 1. If you choose 1 or 4, it won't have a difference on whether the average is terminating or not.\n<|im_end|>" }, { "id": "#37603", "title": "Soccer Strain", "fun": 2.03, "difficulty": 0.63, "author": "MikeMan1216", "desc": "Mike, Chris, and Kyle all play soccer (football). They all play for different teams: the Shooters, the Kickers, and the Scorers. Each team wears a different colored jersey: green, yellow, and blue. Decide the team each person plays for and their uniform color.\n\r\n1. Mike doesn't play for the Shooters.\n\r\n2. The player who plays for the Shooters wears the green jersey.\n\r\n3. Chris plays for the Scorers.\n\r\n4. The blue jersey belongs to the Scorers.", "hint": "No hint available.", "answer": "Mike plays for the Kickers and wears a yellow jersey.\r\nChris plays for the Scorers and wears a blue jersey.\r\nKyle plays for the Shooters and wears a green jersey.", "category": "Logic-Grid", "date": "07/31/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMike, Chris, and Kyle all play soccer (football). They all play for different teams: the Shooters, the Kickers, and the Scorers. Each team wears a different colored jersey: green, yellow, and blue. Decide the team each person plays for and their uniform color.\n\r\n1. Mike doesn't play for the Shooters.\n\r\n2. The player who plays for the Shooters wears the green jersey.\n\r\n3. Chris plays for the Scorers.\n\r\n4. The blue jersey belongs to the Scorers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike plays for the Kickers and wears a yellow jersey.\r\nChris plays for the Scorers and wears a blue jersey.\r\nKyle plays for the Shooters and wears a green jersey.\n<|im_start|>answer\nMike plays for the Kickers and wears a yellow jersey.\r\nChris plays for the Scorers and wears a blue jersey.\r\nKyle plays for the Shooters and wears a green jersey.\n<|im_end|>" }, { "id": "#45263", "title": "Mr. and Mrs. Crazy: Squimes", "fun": 2.03, "difficulty": 2.94, "author": "CaIceDevil", "desc": "Mr. and Mrs. Crazy were just one step away from winning the $1,000,000 prize in the contest. In order for them to win, they must answer this question:\n\r\nWhat are the only ten 8-digit squimes?\r\nIn case you don't know what a squime is, it is any number that:\r\n-has no zero\r\n-has all different digits\r\n-starts and ends with a single-digit prime or single-digit square number\r\n-each pair of consecutive digits is a square or prime\n\r\nMr. and Mrs. Crazy solved it and won one million dollars. What were their answers?", "hint": "A squime cannot contain the number 8 since no square or prime ends with 8.\n\r\nThe largest squime has at most eight digits, since it cannot contain\r\n8 or 0. If we use 2, it must come first because no square or\r\n2-digit prime ends in 2. No 2-digit prime ends in 5 and only 25 is\r\nsquare. If, therefore, we use 5, it must come after 2. So we begin\r\nwith 25.", "answer": "The 8-digit squimes are:\r\n25316479\r\n25316497\r\n25364179\r\n25364197\r\n25364719\r\n25364971\r\n25371649\r\n25971643\r\n25973164\r\n25973641", "category": "Math", "date": "09/11/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. and Mrs. Crazy were just one step away from winning the $1,000,000 prize in the contest. In order for them to win, they must answer this question:\n\r\nWhat are the only ten 8-digit squimes?\r\nIn case you don't know what a squime is, it is any number that:\r\n-has no zero\r\n-has all different digits\r\n-starts and ends with a single-digit prime or single-digit square number\r\n-each pair of consecutive digits is a square or prime\n\r\nMr. and Mrs. Crazy solved it and won one million dollars. What were their answers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe 8-digit squimes are:\r\n25316479\r\n25316497\r\n25364179\r\n25364197\r\n25364719\r\n25364971\r\n25371649\r\n25971643\r\n25973164\r\n25973641\n<|im_start|>answer\nThe 8-digit squimes are:\r\n25316479\r\n25316497\r\n25364179\r\n25364197\r\n25364719\r\n25364971\r\n25371649\r\n25971643\r\n25973164\r\n25973641\n<|im_end|>" }, { "id": "#22987", "title": "Glasses or Contacts?", "fun": 2.03, "difficulty": 0.91, "author": "DennysGirl", "desc": "Three friends need glasses. One wears glasses, one wears contacts, and the other wears special sunglasses that can also become regular glasses. Figure out who wears what and how much they paid for their corrective eyewear.\n\r\nClues: \r\n1. The sunglasses are 3 times the cost of the glasses, but the contacts are half the cost of the glasses.\r\n2. Dennis spent under $200.\r\n3. Alice spent more than Serena, who spent less than Dennis.", "hint": "No hint available.", "answer": "The glasses are $165. The sunglasses are 3 times that, which means they cost $495. But the contacts are half the cost of the glasses, which is $82.50.\r\nDennis spent under $200, so he didn't buy the sunglasses. Serena spent less than Dennis (who spent under $200) so she didn't buy the sunglasses either. Which means Alice bought the sunglasses. Dennis spent more than Serena, so he bought the glasses and Serena got the contacts.\n\r\nDennis/glasses/$165\r\nAlice/sunglasses/$495\r\nSerena/contacts/$82.50", "category": "Logic-Grid", "date": "05/18/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends need glasses. One wears glasses, one wears contacts, and the other wears special sunglasses that can also become regular glasses. Figure out who wears what and how much they paid for their corrective eyewear.\n\r\nClues: \r\n1. The sunglasses are 3 times the cost of the glasses, but the contacts are half the cost of the glasses.\r\n2. Dennis spent under $200.\r\n3. Alice spent more than Serena, who spent less than Dennis.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe glasses are $165. The sunglasses are 3 times that, which means they cost $495. But the contacts are half the cost of the glasses, which is $82.50.\r\nDennis spent under $200, so he didn't buy the sunglasses. Serena spent less than Dennis (who spent under $200) so she didn't buy the sunglasses either. Which means Alice bought the sunglasses. Dennis spent more than Serena, so he bought the glasses and Serena got the contacts.\n\r\nDennis/glasses/$165\r\nAlice/sunglasses/$495\r\nSerena/contacts/$82.50\n<|im_start|>answer\nThe glasses are $165. The sunglasses are 3 times that, which means they cost $495. But the contacts are half the cost of the glasses, which is $82.50.\r\nDennis spent under $200, so he didn't buy the sunglasses. Serena spent less than Dennis (who spent under $200) so she didn't buy the sunglasses either. Which means Alice bought the sunglasses. Dennis spent more than Serena, so he bought the glasses and Serena got the contacts.\n\r\nDennis/glasses/$165\r\nAlice/sunglasses/$495\r\nSerena/contacts/$82.50\n<|im_end|>" }, { "id": "#193", "title": "A square and its lines...", "fun": 2.02, "difficulty": 2.73, "author": "trojan5x", "desc": "Imagine a square that has each side consisting, half of length `a` and half length `b`. Inside the square there is a diamond, with each corner touching the midpoint of each side of the square. Each side of the diamond has length `c`. If one were to set the area of the square equal to the area of all the shapes inside the square, what would remain?", "hint": "No hint available.", "answer": "The Pythagorean Theorem.\n\nThe area of a square is `length squared`. First find the area of the entire square. The length is (a+b). The area of the square is (a+b)^2. Inside the box there is a diamond with length `c`. The diamond is simply a square tilted 45 degrees. The area of the diamond is c^2. There are also 4 triangles with area 1/2ab. Set them equal:\n(a+b)^2=c^2 + 4(1/2ab) Expand...\na^2 + 2ab + b^2= c^2 + 2ab\nSubtract `2ab` from both sides and you are left with the Pythagorean Theorem.\na^2 + b^2 = c^2", "category": "Math", "date": "02/01/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nImagine a square that has each side consisting, half of length `a` and half length `b`. Inside the square there is a diamond, with each corner touching the midpoint of each side of the square. Each side of the diamond has length `c`. If one were to set the area of the square equal to the area of all the shapes inside the square, what would remain?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe Pythagorean Theorem.\n\nThe area of a square is `length squared`. First find the area of the entire square. The length is (a+b). The area of the square is (a+b)^2. Inside the box there is a diamond with length `c`. The diamond is simply a square tilted 45 degrees. The area of the diamond is c^2. There are also 4 triangles with area 1/2ab. Set them equal:\n(a+b)^2=c^2 + 4(1/2ab) Expand...\na^2 + 2ab + b^2= c^2 + 2ab\nSubtract `2ab` from both sides and you are left with the Pythagorean Theorem.\na^2 + b^2 = c^2\n<|im_start|>answer\nThe Pythagorean Theorem.\n\nThe area of a square is `length squared`. First find the area of the entire square. The length is (a+b). The area of the square is (a+b)^2. Inside the box there is a diamond with length `c`. The diamond is simply a square tilted 45 degrees. The area of the diamond is c^2. There are also 4 triangles with area 1/2ab. Set them equal:\n(a+b)^2=c^2 + 4(1/2ab) Expand...\na^2 + 2ab + b^2= c^2 + 2ab\nSubtract `2ab` from both sides and you are left with the Pythagorean Theorem.\na^2 + b^2 = c^2\n<|im_end|>" }, { "id": "#40696", "title": "1 to 20", "fun": 2.02, "difficulty": 2.05, "author": "shenqiang", "desc": "Divide the numbers from 1 to 20 into 10 pairs. Multiply the numbers in each pair, then add the ten products.\n\r\nWhat is the difference between the maximum possible sum and the minimum possible sum?", "hint": "If you can't get it, try 1 to 4.\r\n1*2+3*4, 1*3+2*4, 1*4+2*3...", "answer": "The maximum possible sum is 1*2+3*4+...+19*20=1430.\n\r\nThe minimum possible sum is 1*20+2*19+...+10*11=770.\n\r\n1430-770=660.", "category": "Math", "date": "02/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nDivide the numbers from 1 to 20 into 10 pairs. Multiply the numbers in each pair, then add the ten products.\n\r\nWhat is the difference between the maximum possible sum and the minimum possible sum?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe maximum possible sum is 1*2+3*4+...+19*20=1430.\n\r\nThe minimum possible sum is 1*20+2*19+...+10*11=770.\n\r\n1430-770=660.\n<|im_start|>answer\nThe maximum possible sum is 1*2+3*4+...+19*20=1430.\n\r\nThe minimum possible sum is 1*20+2*19+...+10*11=770.\n\r\n1430-770=660.\n<|im_end|>" }, { "id": "#1960", "title": "Shooting Practice", "fun": 2.02, "difficulty": 1.25, "author": "missie", "desc": "Will and Jim were practicing target shooting, and they each scored 75 out of 100. They took a break and then Will tried again and hit 35 out of 50. Jim did not shoot anymore. Who had the best average for the day?", "hint": "No hint available.", "answer": "Jim's average is higher.", "category": "Math", "date": "01/06/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWill and Jim were practicing target shooting, and they each scored 75 out of 100. They took a break and then Will tried again and hit 35 out of 50. Jim did not shoot anymore. Who had the best average for the day?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJim's average is higher.\n<|im_start|>answer\nJim's average is higher.\n<|im_end|>" }, { "id": "#8579", "title": "Sum of the Parts", "fun": 2.02, "difficulty": 1.78, "author": "lesternoronha1", "desc": "There is a number which is greater than the sum of its third, tenth, and twelfth parts by 58. Can you find the number?", "hint": "No hint available.", "answer": "The number is 120.", "category": "Math", "date": "11/18/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a number which is greater than the sum of its third, tenth, and twelfth parts by 58. Can you find the number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number is 120.\n<|im_start|>answer\nThe number is 120.\n<|im_end|>" }, { "id": "#23710", "title": "Reid's Auto Repair", "fun": 2.02, "difficulty": 2.43, "author": "Akilah", "desc": "Help the secretary at Reid's Auto Repair Shop figure out what person dropped what car and color off, what the car problem is and what time they dropped it for repair. All cars were picked up at 5:30.\n\r\nClients - Chuck, Laura, Tom, Vicki, Hilary\r\nCars - Honda, Toyota, Lexus, VW buggy, Chevrolet\r\nColors - Red, Blue, Black, Purple, L. Green\r\nTimes - 11:30, 12:00, 1:45, 4:30, 5:15\r\nProblems - Diagnostic, Transmission, Oil change, tune up, wheel alignment\n\r\n1. No owner has a car that begins with the same letter as their name. \r\n2. Chuck is a 16 yr. old goth. Loves the color black.\r\n3. Tom has a high paying job and drives an expensive car.\r\n4. Hilary loves purple and is claustrophobic.\r\n5. Chuck has a Toyota.\r\n6. All of Vicki's accessories including car are red.\r\n7. Chuck had a 10 min. lunch at 11: 10 was back at school 11:55 after running a few errands.\r\n8. Tom loves primary colors.\r\n9. Tom noticed a change in his car and took it to get it looked at.\r\n10. Vicki is a wedding and party planner and has high mileage on her car and couldn't get to the shop until 4:30.\r\n11. Diagnosing a car to see what's wrong takes 20 min. or less.\r\n12. Laura doesn't have a car at 12:00.\r\n13. Hilary gets off work at 1:00.\r\n14. Oil changes need at least 1 hr.\r\n15. A transmission job takes the longest. \r\n16. Laura is always messing up her tires.", "hint": "The primary colors are red, yellow and blue\r\nYou get an oil change after a certain amount of miles.", "answer": "Tom/Lexus/ Blue/ Diagnostic/ 5:15\r\nChuck/Toyota/Black/ Transmission/ 11:30\r\nVicki/ Honda/ Red/ oil change/ 4:30 \r\nLaura/ VW buggy/ L. green / wheel alignment / 12:00\r\nHilary/Chevrolet/ Purple/ Tune Up/ 1:45", "category": "Logic-Grid", "date": "06/15/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHelp the secretary at Reid's Auto Repair Shop figure out what person dropped what car and color off, what the car problem is and what time they dropped it for repair. All cars were picked up at 5:30.\n\r\nClients - Chuck, Laura, Tom, Vicki, Hilary\r\nCars - Honda, Toyota, Lexus, VW buggy, Chevrolet\r\nColors - Red, Blue, Black, Purple, L. Green\r\nTimes - 11:30, 12:00, 1:45, 4:30, 5:15\r\nProblems - Diagnostic, Transmission, Oil change, tune up, wheel alignment\n\r\n1. No owner has a car that begins with the same letter as their name. \r\n2. Chuck is a 16 yr. old goth. Loves the color black.\r\n3. Tom has a high paying job and drives an expensive car.\r\n4. Hilary loves purple and is claustrophobic.\r\n5. Chuck has a Toyota.\r\n6. All of Vicki's accessories including car are red.\r\n7. Chuck had a 10 min. lunch at 11: 10 was back at school 11:55 after running a few errands.\r\n8. Tom loves primary colors.\r\n9. Tom noticed a change in his car and took it to get it looked at.\r\n10. Vicki is a wedding and party planner and has high mileage on her car and couldn't get to the shop until 4:30.\r\n11. Diagnosing a car to see what's wrong takes 20 min. or less.\r\n12. Laura doesn't have a car at 12:00.\r\n13. Hilary gets off work at 1:00.\r\n14. Oil changes need at least 1 hr.\r\n15. A transmission job takes the longest. \r\n16. Laura is always messing up her tires.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTom/Lexus/ Blue/ Diagnostic/ 5:15\r\nChuck/Toyota/Black/ Transmission/ 11:30\r\nVicki/ Honda/ Red/ oil change/ 4:30 \r\nLaura/ VW buggy/ L. green / wheel alignment / 12:00\r\nHilary/Chevrolet/ Purple/ Tune Up/ 1:45\n<|im_start|>answer\nTom/Lexus/ Blue/ Diagnostic/ 5:15\r\nChuck/Toyota/Black/ Transmission/ 11:30\r\nVicki/ Honda/ Red/ oil change/ 4:30 \r\nLaura/ VW buggy/ L. green / wheel alignment / 12:00\r\nHilary/Chevrolet/ Purple/ Tune Up/ 1:45\n<|im_end|>" }, { "id": "#44160", "title": "Beep Beep Beep", "fun": 2.02, "difficulty": 2.22, "author": "bigSWAFF_69_", "desc": "If the following is correct:\n\r\n12:48 = 18\r\n1:03 = 13\r\n6:59 = 17\n\r\nWhat would 9:37 equal?", "hint": "No hint available.", "answer": "14\n\r\nWhen appearing on a standard digital clock, the different digits are made up different numbers of segments.\n\r\n\"1\" is made up of 2 segments\r\n\"2\" is 5\r\n\"3\" is 5\r\n\"4\" is 4\r\n\"5\" is 5\r\n\"6\" is 6\r\n\"7\" is 3\r\n\"8\" is 7\r\n\"9\" is 6\r\n\"0\" is 6\n\r\nAdd the numbers of segments to reach the answer.", "category": "Math", "date": "02/23/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf the following is correct:\n\r\n12:48 = 18\r\n1:03 = 13\r\n6:59 = 17\n\r\nWhat would 9:37 equal?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n14\n\r\nWhen appearing on a standard digital clock, the different digits are made up different numbers of segments.\n\r\n\"1\" is made up of 2 segments\r\n\"2\" is 5\r\n\"3\" is 5\r\n\"4\" is 4\r\n\"5\" is 5\r\n\"6\" is 6\r\n\"7\" is 3\r\n\"8\" is 7\r\n\"9\" is 6\r\n\"0\" is 6\n\r\nAdd the numbers of segments to reach the answer.\n<|im_start|>answer\n14\n\r\nWhen appearing on a standard digital clock, the different digits are made up different numbers of segments.\n\r\n\"1\" is made up of 2 segments\r\n\"2\" is 5\r\n\"3\" is 5\r\n\"4\" is 4\r\n\"5\" is 5\r\n\"6\" is 6\r\n\"7\" is 3\r\n\"8\" is 7\r\n\"9\" is 6\r\n\"0\" is 6\n\r\nAdd the numbers of segments to reach the answer.\n<|im_end|>" }, { "id": "#5928", "title": "Reverse Engineering II", "fun": 2.02, "difficulty": 2.94, "author": "dewtell", "desc": "The formula discovered in \"Reverse Engineering I\" doesn't seem to apply exactly to many Braingle ratings once the number of voters gets larger. What is your best guess at the number of votes cast for each attribute of the following teasers prior to my vote, and how many of those were positive (fun/hard)? What do you think is the likely source of any \"experimental error\" between the formula and these reported ratings? (Notation is the same as in \"Reverse Engineering I\"). Multiple answers may be possible, because of the difficulty of determining how much of the reported data constitutes \"experimental error.\"\n\r\nTeaser M: (1.38, 1.20)[16] (+, -) -> (1.53, 1.13)\r\nTeaser N: (2.00, 2.22)[18] (+, -) -> (2.11, 2.11)\r\nTeaser O: (1.04, 2.82)[25] (-, +) -> (1.00, 2.87)\r\nTeaser P: (2.13, 1.72)[44] (+, -) -> (2.17, 1.68)", "hint": "No hint available.", "answer": "The formula from part I, for p positive votes out of v cast, was 4*p/v. I searched for fractions with denominators close to the reported number of voters and numerators that were multiples of 4 to try to find a good fit. Here are some of the best possibilities, with the resulting decimals reported below. Divide numerators by 4 to get the number of positive votes.\n\r\nTeaser M: (16/12, 16/13)[16] (+, -) -> (20/13, 16/14)\r\n(1.33, 1.23)[16] (+, -) -> (1.54, 1.14). It's hard to find a good match for this one. Another possibility is 20/15->24/16 (1.33->1.5) for the first rating, which is further off from the data, but doesn't require as many non-voters.\n\r\nTeaser N: (36/18, 40/18)[18] (+, -) -> (40/19, 40/19)\r\n(2.00, 2.22)[18] (+, -) -> (2.11, 2.11) An exact match to the data.\n\r\nTeaser O: (24/23, 68/24)[25] (-, +) -> (24/24, 72/25)\r\n(1.04, 2.83)[25] (-, +) -> (1.00, 2.88) Pretty close.\n\r\nTeaser P: (92/43, 72/42)[44] (+, -) -> (96/44, 72/43)\r\n(2.14, 1.71)[44] (+, -) -> (2.18, 1.67) Off by .01 in every figure.\n\r\nThe above errors (particularly on Teaser M) would be hard to account for if the site were recomputing the ratings every time from p and v. We know that the site keeps track of v for each category, in order to qualify entries for the various lists. But the site may recalculate p every time from the previous (rounded) ranking, which could cause errors that could accumulate or cancel, depending on how unlucky/lucky you were about what order people voted in. This could account for the errors in the above data. If this is the problem, the best fix would be to keep a separate count of p for each ranking. A temporary fix would be to at least round p off to the nearest integer when deriving it from the previous ranking, which works up to around 200 votes or so.", "category": "Math", "date": "07/26/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe formula discovered in \"Reverse Engineering I\" doesn't seem to apply exactly to many Braingle ratings once the number of voters gets larger. What is your best guess at the number of votes cast for each attribute of the following teasers prior to my vote, and how many of those were positive (fun/hard)? What do you think is the likely source of any \"experimental error\" between the formula and these reported ratings? (Notation is the same as in \"Reverse Engineering I\"). Multiple answers may be possible, because of the difficulty of determining how much of the reported data constitutes \"experimental error.\"\n\r\nTeaser M: (1.38, 1.20)[16] (+, -) -> (1.53, 1.13)\r\nTeaser N: (2.00, 2.22)[18] (+, -) -> (2.11, 2.11)\r\nTeaser O: (1.04, 2.82)[25] (-, +) -> (1.00, 2.87)\r\nTeaser P: (2.13, 1.72)[44] (+, -) -> (2.17, 1.68)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe formula from part I, for p positive votes out of v cast, was 4*p/v. I searched for fractions with denominators close to the reported number of voters and numerators that were multiples of 4 to try to find a good fit. Here are some of the best possibilities, with the resulting decimals reported below. Divide numerators by 4 to get the number of positive votes.\n\r\nTeaser M: (16/12, 16/13)[16] (+, -) -> (20/13, 16/14)\r\n(1.33, 1.23)[16] (+, -) -> (1.54, 1.14). It's hard to find a good match for this one. Another possibility is 20/15->24/16 (1.33->1.5) for the first rating, which is further off from the data, but doesn't require as many non-voters.\n\r\nTeaser N: (36/18, 40/18)[18] (+, -) -> (40/19, 40/19)\r\n(2.00, 2.22)[18] (+, -) -> (2.11, 2.11) An exact match to the data.\n\r\nTeaser O: (24/23, 68/24)[25] (-, +) -> (24/24, 72/25)\r\n(1.04, 2.83)[25] (-, +) -> (1.00, 2.88) Pretty close.\n\r\nTeaser P: (92/43, 72/42)[44] (+, -) -> (96/44, 72/43)\r\n(2.14, 1.71)[44] (+, -) -> (2.18, 1.67) Off by .01 in every figure.\n\r\nThe above errors (particularly on Teaser M) would be hard to account for if the site were recomputing the ratings every time from p and v. We know that the site keeps track of v for each category, in order to qualify entries for the various lists. But the site may recalculate p every time from the previous (rounded) ranking, which could cause errors that could accumulate or cancel, depending on how unlucky/lucky you were about what order people voted in. This could account for the errors in the above data. If this is the problem, the best fix would be to keep a separate count of p for each ranking. A temporary fix would be to at least round p off to the nearest integer when deriving it from the previous ranking, which works up to around 200 votes or so.\n<|im_start|>answer\nThe formula from part I, for p positive votes out of v cast, was 4*p/v. I searched for fractions with denominators close to the reported number of voters and numerators that were multiples of 4 to try to find a good fit. Here are some of the best possibilities, with the resulting decimals reported below. Divide numerators by 4 to get the number of positive votes.\n\r\nTeaser M: (16/12, 16/13)[16] (+, -) -> (20/13, 16/14)\r\n(1.33, 1.23)[16] (+, -) -> (1.54, 1.14). It's hard to find a good match for this one. Another possibility is 20/15->24/16 (1.33->1.5) for the first rating, which is further off from the data, but doesn't require as many non-voters.\n\r\nTeaser N: (36/18, 40/18)[18] (+, -) -> (40/19, 40/19)\r\n(2.00, 2.22)[18] (+, -) -> (2.11, 2.11) An exact match to the data.\n\r\nTeaser O: (24/23, 68/24)[25] (-, +) -> (24/24, 72/25)\r\n(1.04, 2.83)[25] (-, +) -> (1.00, 2.88) Pretty close.\n\r\nTeaser P: (92/43, 72/42)[44] (+, -) -> (96/44, 72/43)\r\n(2.14, 1.71)[44] (+, -) -> (2.18, 1.67) Off by .01 in every figure.\n\r\nThe above errors (particularly on Teaser M) would be hard to account for if the site were recomputing the ratings every time from p and v. We know that the site keeps track of v for each category, in order to qualify entries for the various lists. But the site may recalculate p every time from the previous (rounded) ranking, which could cause errors that could accumulate or cancel, depending on how unlucky/lucky you were about what order people voted in. This could account for the errors in the above data. If this is the problem, the best fix would be to keep a separate count of p for each ranking. A temporary fix would be to at least round p off to the nearest integer when deriving it from the previous ranking, which works up to around 200 votes or so.\n<|im_end|>" }, { "id": "#5653", "title": "Stumper", "fun": 2.02, "difficulty": 2.9, "author": "bubblebobboy", "desc": "See if you can solve this stumper\n\r\n HI\r\n X TO\r\n --\r\n JRRO", "hint": "R=7 and H=4 and I is not equal to 1!!!", "answer": "H=4\r\nI=6\r\nT=8\r\nO=2\r\nJ=3\r\nR=7", "category": "Math", "date": "07/17/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSee if you can solve this stumper\n\r\n HI\r\n X TO\r\n --\r\n JRRO\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nH=4\r\nI=6\r\nT=8\r\nO=2\r\nJ=3\r\nR=7\n<|im_start|>answer\nH=4\r\nI=6\r\nT=8\r\nO=2\r\nJ=3\r\nR=7\n<|im_end|>" }, { "id": "#36562", "title": "Chores", "fun": 2.01, "difficulty": 0.67, "author": "merrypippin246", "desc": "Today is Sunday, and you know what that means, chores, chores, and more chores. Sally, Jamie, and Max were given some chores. Use the following clues to find out who did what, and how long it took them.\n\r\nPeople: Sally, Jamie, and Max\n\r\nChores: Empty the trash cans, Clean the cat litter, and vacuum\n\r\nTimes: 15 minutes, 30 minutes, and 45 minutes\n\r\nClues:\r\n1) Sally cleans the cat litter.\r\n2) Jamie's chore doesn't take 30 minutes.\r\n3) Max doesn't vacuum.\r\n4) Sally's chore takes 45 minutes.", "hint": "No hint available.", "answer": "Sally - Cat litter - 45 minutes\r\nJamie - Vacuum - 15 minutes\r\nMax - Empty trash cans - 30 minutes", "category": "Logic-Grid", "date": "05/08/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nToday is Sunday, and you know what that means, chores, chores, and more chores. Sally, Jamie, and Max were given some chores. Use the following clues to find out who did what, and how long it took them.\n\r\nPeople: Sally, Jamie, and Max\n\r\nChores: Empty the trash cans, Clean the cat litter, and vacuum\n\r\nTimes: 15 minutes, 30 minutes, and 45 minutes\n\r\nClues:\r\n1) Sally cleans the cat litter.\r\n2) Jamie's chore doesn't take 30 minutes.\r\n3) Max doesn't vacuum.\r\n4) Sally's chore takes 45 minutes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSally - Cat litter - 45 minutes\r\nJamie - Vacuum - 15 minutes\r\nMax - Empty trash cans - 30 minutes\n<|im_start|>answer\nSally - Cat litter - 45 minutes\r\nJamie - Vacuum - 15 minutes\r\nMax - Empty trash cans - 30 minutes\n<|im_end|>" }, { "id": "#40711", "title": "On a Roller Coaster Ride", "fun": 2.01, "difficulty": 1.32, "author": "doubleugh", "desc": "At an amusement park, there are three roller coasters. A survey asked three hundred people which one was their favorite. The results show that Roller Coaster #1 was not more popular than #2. #2 was not more popular than #3 and #3 was not more popular than #1. Which one was most popular?", "hint": "No hint available.", "answer": "Their popularity was the same. If #1 was more popular than #3 that would work, except for the fact that #1 can't be more popular than #2 and so on.", "category": "Logic", "date": "02/25/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt an amusement park, there are three roller coasters. A survey asked three hundred people which one was their favorite. The results show that Roller Coaster #1 was not more popular than #2. #2 was not more popular than #3 and #3 was not more popular than #1. Which one was most popular?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTheir popularity was the same. If #1 was more popular than #3 that would work, except for the fact that #1 can't be more popular than #2 and so on.\n<|im_start|>answer\nTheir popularity was the same. If #1 was more popular than #3 that would work, except for the fact that #1 can't be more popular than #2 and so on.\n<|im_end|>" }, { "id": "#1782", "title": "240", "fun": 2.01, "difficulty": 1.32, "author": "maxmars", "desc": "What number is two-thirds of one-half of one-fourth of 240?", "hint": "No hint available.", "answer": "20", "category": "Math", "date": "12/21/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number is two-thirds of one-half of one-fourth of 240?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n20\n<|im_start|>answer\n20\n<|im_end|>" }, { "id": "#20936", "title": "Pets and Owners", "fun": 2.01, "difficulty": 0.9, "author": "Unicorns", "desc": "There were 3 Owners - John, Sally and Chloe\n\r\nEach person had a Pet - Hamster, Cat and Dog\n\r\nAnd each pet was bought in a certain month - August, March and October.\n\r\nCan you work out which pet belongs to which owner and when the pet was bought?\n\r\nClues - \n\r\n1. The owner that owns the hamster did not buy it in March.\n\r\n2. Sally did not buy her hamster in October.\n\r\n3. The owner bought his dog in March.", "hint": "No hint available.", "answer": "1. John - Dog - March\r\n2. Sally - Hamster - August\r\n3. Chloe - Cat - October", "category": "Logic-Grid", "date": "02/10/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were 3 Owners - John, Sally and Chloe\n\r\nEach person had a Pet - Hamster, Cat and Dog\n\r\nAnd each pet was bought in a certain month - August, March and October.\n\r\nCan you work out which pet belongs to which owner and when the pet was bought?\n\r\nClues - \n\r\n1. The owner that owns the hamster did not buy it in March.\n\r\n2. Sally did not buy her hamster in October.\n\r\n3. The owner bought his dog in March.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1. John - Dog - March\r\n2. Sally - Hamster - August\r\n3. Chloe - Cat - October\n<|im_start|>answer\n1. John - Dog - March\r\n2. Sally - Hamster - August\r\n3. Chloe - Cat - October\n<|im_end|>" }, { "id": "#41404", "title": "Magician Party", "fun": 2.01, "difficulty": 0.68, "author": "pandastampede", "desc": "There are three magicians throwing a party. They each bring three things. They are Frog Leg Surprise, Super Duper Party Scoopers, and Merlin's Masterpiece. The magician's first names are Merlin, Dontanella, and Malfonzo. The last names are Orlando, Froggy, and Sidney.\n\r\n-Dontanella's last name is the name of an American City in Florida.\r\n-Merlin DID NOT bring the Merlin's Masterpiece.\r\n-Mister Froggy brought the Merlin's Masterpiece.\r\n-Merlin's food doesn't have three rhyming words in it.\r\n-Merlin's last name sounds like a city in Australia.\r\n-Malfonzo brought Merlin's Masterpiece.\n\r\nWho brought what and what is their last name?", "hint": "No hint available.", "answer": "-Dontanella Orlando brought the Super Duper Party Scoopers.\r\n-Merlin Sidney brought the Frog Leg Surprise.\r\n-Malfonzo Froggy brought Merlin's Masterpiece.", "category": "Logic-Grid", "date": "04/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three magicians throwing a party. They each bring three things. They are Frog Leg Surprise, Super Duper Party Scoopers, and Merlin's Masterpiece. The magician's first names are Merlin, Dontanella, and Malfonzo. The last names are Orlando, Froggy, and Sidney.\n\r\n-Dontanella's last name is the name of an American City in Florida.\r\n-Merlin DID NOT bring the Merlin's Masterpiece.\r\n-Mister Froggy brought the Merlin's Masterpiece.\r\n-Merlin's food doesn't have three rhyming words in it.\r\n-Merlin's last name sounds like a city in Australia.\r\n-Malfonzo brought Merlin's Masterpiece.\n\r\nWho brought what and what is their last name?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-Dontanella Orlando brought the Super Duper Party Scoopers.\r\n-Merlin Sidney brought the Frog Leg Surprise.\r\n-Malfonzo Froggy brought Merlin's Masterpiece.\n<|im_start|>answer\n-Dontanella Orlando brought the Super Duper Party Scoopers.\r\n-Merlin Sidney brought the Frog Leg Surprise.\r\n-Malfonzo Froggy brought Merlin's Masterpiece.\n<|im_end|>" }, { "id": "#2221", "title": "Negative 1", "fun": 2.0, "difficulty": 1.76, "author": "birdbrain", "desc": "What is the square root of -1?", "hint": "No hint available.", "answer": "1i\n\r\ni stands for imaginary number", "category": "Math", "date": "01/31/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the square root of -1?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1i\n\r\ni stands for imaginary number\n<|im_start|>answer\n1i\n\r\ni stands for imaginary number\n<|im_end|>" }, { "id": "#2109", "title": "Prime Number", "fun": 2.0, "difficulty": 2.85, "author": "ChemicalBoy08", "desc": "What is the 1000th prime number?", "hint": "It is smaller than 10000", "answer": "7919", "category": "Math", "date": "01/20/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the 1000th prime number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n7919\n<|im_start|>answer\n7919\n<|im_end|>" }, { "id": "#5179", "title": "What's my Number?", "fun": 2.0, "difficulty": 1.45, "author": "cleverclogs", "desc": "My number is represented by 'a' in the following equation. Can you work out what my number is?\n\r\n a + 20 - 3 = 2a - 34 + 14", "hint": "No hint available.", "answer": "a = 37\r\nMy number is 37.", "category": "Math", "date": "07/03/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMy number is represented by 'a' in the following equation. Can you work out what my number is?\n\r\n a + 20 - 3 = 2a - 34 + 14\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\na = 37\r\nMy number is 37.\n<|im_start|>answer\na = 37\r\nMy number is 37.\n<|im_end|>" }, { "id": "#15993", "title": "Palindrome", "fun": 2.0, "difficulty": 3.12, "author": "curtiss82", "desc": "What is the only non-palindromic integer whose cube is a palindrome?", "hint": "A palindrome is a number that reads the same forward as it does backward. An example would be 1221. An integer is a number that has no decimal places. A cube is the result of multiplying a number by itself three times.", "answer": "2201\n\r\n2201^3 = 10662526601", "category": "Math", "date": "12/30/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is the only non-palindromic integer whose cube is a palindrome?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2201\n\r\n2201^3 = 10662526601\n<|im_start|>answer\n2201\n\r\n2201^3 = 10662526601\n<|im_end|>" }, { "id": "#42311", "title": "What Breed?", "fun": 2.0, "difficulty": 0.74, "author": "eggface", "desc": "Mr. Blake is always losing things, and now he has lost the list containing the information about a new range of species. See if you can work out which animal has which qualities.\n\r\nThe animals are: Doggus, Cattus, Deerus, and Mousus. Each of them has spots, stripes, and/or humps. Each animal also is a different colour.\n\r\nDoggus is the only one with spots.\r\nDeerus only has humps, while the Mousus only has stripes. \r\nMousus dislikes primary colours, unlike the rest of the animals.\r\nThe animal with two features is blue.\r\nDeerus dislikes the colour red.", "hint": "No hint available.", "answer": "Doggus Sleepus has spots and is red.\r\nCattus Spoiledus has stripes and humps and is blue.\r\nDeerus Shyus has humps and is yellow.\r\nMousus Cheesus has stripes and is green.", "category": "Logic-Grid", "date": "06/22/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Blake is always losing things, and now he has lost the list containing the information about a new range of species. See if you can work out which animal has which qualities.\n\r\nThe animals are: Doggus, Cattus, Deerus, and Mousus. Each of them has spots, stripes, and/or humps. Each animal also is a different colour.\n\r\nDoggus is the only one with spots.\r\nDeerus only has humps, while the Mousus only has stripes. \r\nMousus dislikes primary colours, unlike the rest of the animals.\r\nThe animal with two features is blue.\r\nDeerus dislikes the colour red.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDoggus Sleepus has spots and is red.\r\nCattus Spoiledus has stripes and humps and is blue.\r\nDeerus Shyus has humps and is yellow.\r\nMousus Cheesus has stripes and is green.\n<|im_start|>answer\nDoggus Sleepus has spots and is red.\r\nCattus Spoiledus has stripes and humps and is blue.\r\nDeerus Shyus has humps and is yellow.\r\nMousus Cheesus has stripes and is green.\n<|im_end|>" }, { "id": "#48832", "title": "Feather Bluster", "fun": 2.0, "difficulty": 0.9, "author": "bubbubfilt", "desc": "Joseph collects bird feathers. He has three nice ones: an eagle, a raven, and a starling. Each one is displayed with a differently colored index card. They are arranged in a certain order.\r\nUnfortunately, Joseph's sister knocked over his collection. She only remembers four things. Can you help her put it back together?\n\r\n1. The eagle feather is not by the feather with the red card.\r\n2. The third feather is either green or blue.\r\n3. The starling feather was by the eagle feather.\r\n4. The feather with the green card was right behind the one with the blue card.", "hint": "No hint available.", "answer": "The raven feather was first. It was with the red card.\r\nThe starling feather was second. It was with the blue card.\r\nThe eagle feather was last. It was with the green card.", "category": "Logic-Grid", "date": "06/26/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoseph collects bird feathers. He has three nice ones: an eagle, a raven, and a starling. Each one is displayed with a differently colored index card. They are arranged in a certain order.\r\nUnfortunately, Joseph's sister knocked over his collection. She only remembers four things. Can you help her put it back together?\n\r\n1. The eagle feather is not by the feather with the red card.\r\n2. The third feather is either green or blue.\r\n3. The starling feather was by the eagle feather.\r\n4. The feather with the green card was right behind the one with the blue card.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe raven feather was first. It was with the red card.\r\nThe starling feather was second. It was with the blue card.\r\nThe eagle feather was last. It was with the green card.\n<|im_start|>answer\nThe raven feather was first. It was with the red card.\r\nThe starling feather was second. It was with the blue card.\r\nThe eagle feather was last. It was with the green card.\n<|im_end|>" }, { "id": "#42391", "title": "Circle's Corner", "fun": 2.0, "difficulty": 2.7, "author": "Cogmatic", "desc": "Consider the two lines AO and BO. These two lines intersect at point O and are perpendicular to each other.\n\r\nIf you were to draw a circle that were to intersect these two lines at points A and B and only at points A and B, what would be the smallest integral size of the larger arc AB in degrees?", "hint": "Integral means \"in integers\".\n\r\nAn arc is a portion of a circle.", "answer": "181 degrees.\n\r\nIf you created a circle with points A, B, and O on it, since angle AOB is a right angle, line AB is the diameter of this circle. Therefore, arc AB would be 180 degrees if it actually were to intersect O as well as A and B.\n\r\nHowever, the problem says the arc can only intersect A and B. To do this, the circle must be slightly larger than the one described above. As stated in the problem, the larger arc must be the next largest integer size, which is 181 degrees.", "category": "Math", "date": "06/30/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nConsider the two lines AO and BO. These two lines intersect at point O and are perpendicular to each other.\n\r\nIf you were to draw a circle that were to intersect these two lines at points A and B and only at points A and B, what would be the smallest integral size of the larger arc AB in degrees?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n181 degrees.\n\r\nIf you created a circle with points A, B, and O on it, since angle AOB is a right angle, line AB is the diameter of this circle. Therefore, arc AB would be 180 degrees if it actually were to intersect O as well as A and B.\n\r\nHowever, the problem says the arc can only intersect A and B. To do this, the circle must be slightly larger than the one described above. As stated in the problem, the larger arc must be the next largest integer size, which is 181 degrees.\n<|im_start|>answer\n181 degrees.\n\r\nIf you created a circle with points A, B, and O on it, since angle AOB is a right angle, line AB is the diameter of this circle. Therefore, arc AB would be 180 degrees if it actually were to intersect O as well as A and B.\n\r\nHowever, the problem says the arc can only intersect A and B. To do this, the circle must be slightly larger than the one described above. As stated in the problem, the larger arc must be the next largest integer size, which is 181 degrees.\n<|im_end|>" }, { "id": "#45384", "title": "A Pitchers Game", "fun": 2.0, "difficulty": 2.03, "author": "snowmonster", "desc": "Can you explain how a baseball pitcher could win a nine-inning game without once pitching to a batter?", "hint": "No hint available.", "answer": "He could if he were a substitute pitcher brought into the game at the top of the ninth inning with the score tied, two outs, and a man on first base. If he then picked the man off at first base, the side would be retired and his team would come to bat. If his team then scored the winning run, in the bottom of the ninth, he would be the winner without ever having pitched to a single batter.", "category": "Logic", "date": "09/27/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nCan you explain how a baseball pitcher could win a nine-inning game without once pitching to a batter?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHe could if he were a substitute pitcher brought into the game at the top of the ninth inning with the score tied, two outs, and a man on first base. If he then picked the man off at first base, the side would be retired and his team would come to bat. If his team then scored the winning run, in the bottom of the ninth, he would be the winner without ever having pitched to a single batter.\n<|im_start|>answer\nHe could if he were a substitute pitcher brought into the game at the top of the ninth inning with the score tied, two outs, and a man on first base. If he then picked the man off at first base, the side would be retired and his team would come to bat. If his team then scored the winning run, in the bottom of the ninth, he would be the winner without ever having pitched to a single batter.\n<|im_end|>" }, { "id": "#43379", "title": "Mystery Number 3", "fun": 2.0, "difficulty": 2.79, "author": "cnmne", "desc": "There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) B + C + F + J = E + G + H + I = AD\r\n2) B - H = J - G = 3\r\n3) C - F = E - I = 5\r\n4) B * I = AJ", "hint": "No hint available.", "answer": "2951804637\n\r\nA = 2, B = 9, C = 5, D = 1, E = 8, F = 0, G = 4, H = 6, I = 3, J = 7\n\r\n1) 9 + 5 + 0 + 7 = 8 + 4 + 6 + 3 = 21\r\n2) 8 - 3 = 5 - 0 = 5\r\n3) 7 - 4 = 9 - 6 = 3\r\n4) 9 * 3 = 27\n\r\nA) The sum of the ten digits is 45. Two digits (A and D) form a two-digit number. If A and D are 8 and 9, then the remaining eight digits sum to 28. If A and D are 0 and 1, then the remaining digits sum to 44. These sums must be split equally between two groups of four digits. Therefore, each group of four digits must sum to one of the following: 14, 15, 16, 17, 18, 19, 20, 21, 22.\r\nB) If the sum of each group is 14, then A and D must be a combination of 1 and 4, which sum to 5. Subtract 5 from 45, leaving 40. Divide 40 by 2, leaving 20. 20 does not equal 14, so the sum of each group can not be 14. Repeating the preceding sequence for each of the possible sums leaves only two possible results: 18 (1 + 8 = 9, 45 - 9 = 36, 36 / 2 = 18) and 21 (2 + 1 = 3, 45 - 3 = 42, 42 / 2 = 21). A must be: 1, 2. D must be: 1, 8.\r\nC) To satisfy equation #2, B and J must be 3 greater than H and G, respectively. B and J must each be one of the following: 3, 5, 6, 7, 8, 9. H and G must each be one of the following: 0, 2, 3, 4, 5, 6.\r\nD) To satisfy equation #3, C and E must be 5 greater than F and I, respectively. C and E must each be one of the following: 5, 7, 8, 9. F and I must each be one of the following: 0, 2, 3, 4.\r\nE) For equation #4, there are six possibilities for B and four possibilities for I, creating 24 possible equations. Eliminate any equation where A is not 1 or 2. Eliminate any equation where J is not 3, 5, 6, 7, 8, or 9. Eliminate any equation where any digit is duplicated. B must be: 6, 7, 8, 9. I must be: 2, 3, 4. J must be: 6, 7, 8.\r\nF) Returning to equations #2 and #3, eliminate additional possibilities. E must be: 7, 8, 9. G must be: 3, 4, 5. H must be: 3, 4, 5, 6. This results in F = 0 and C = 5.\r\nG) Since H can not be 5, B can not be 8. Since G can not be 5, J can not be 8. Going back to equation #4, eliminate those equations where either B or J is 8. B = 9, I = 3, A = 2, and J = 7.\r\nH) The last four letters can now be assigned values. D = 1, E = 8, G = 4, and H = 6.", "category": "Logic", "date": "10/20/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) B + C + F + J = E + G + H + I = AD\r\n2) B - H = J - G = 3\r\n3) C - F = E - I = 5\r\n4) B * I = AJ\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n2951804637\n\r\nA = 2, B = 9, C = 5, D = 1, E = 8, F = 0, G = 4, H = 6, I = 3, J = 7\n\r\n1) 9 + 5 + 0 + 7 = 8 + 4 + 6 + 3 = 21\r\n2) 8 - 3 = 5 - 0 = 5\r\n3) 7 - 4 = 9 - 6 = 3\r\n4) 9 * 3 = 27\n\r\nA) The sum of the ten digits is 45. Two digits (A and D) form a two-digit number. If A and D are 8 and 9, then the remaining eight digits sum to 28. If A and D are 0 and 1, then the remaining digits sum to 44. These sums must be split equally between two groups of four digits. Therefore, each group of four digits must sum to one of the following: 14, 15, 16, 17, 18, 19, 20, 21, 22.\r\nB) If the sum of each group is 14, then A and D must be a combination of 1 and 4, which sum to 5. Subtract 5 from 45, leaving 40. Divide 40 by 2, leaving 20. 20 does not equal 14, so the sum of each group can not be 14. Repeating the preceding sequence for each of the possible sums leaves only two possible results: 18 (1 + 8 = 9, 45 - 9 = 36, 36 / 2 = 18) and 21 (2 + 1 = 3, 45 - 3 = 42, 42 / 2 = 21). A must be: 1, 2. D must be: 1, 8.\r\nC) To satisfy equation #2, B and J must be 3 greater than H and G, respectively. B and J must each be one of the following: 3, 5, 6, 7, 8, 9. H and G must each be one of the following: 0, 2, 3, 4, 5, 6.\r\nD) To satisfy equation #3, C and E must be 5 greater than F and I, respectively. C and E must each be one of the following: 5, 7, 8, 9. F and I must each be one of the following: 0, 2, 3, 4.\r\nE) For equation #4, there are six possibilities for B and four possibilities for I, creating 24 possible equations. Eliminate any equation where A is not 1 or 2. Eliminate any equation where J is not 3, 5, 6, 7, 8, or 9. Eliminate any equation where any digit is duplicated. B must be: 6, 7, 8, 9. I must be: 2, 3, 4. J must be: 6, 7, 8.\r\nF) Returning to equations #2 and #3, eliminate additional possibilities. E must be: 7, 8, 9. G must be: 3, 4, 5. H must be: 3, 4, 5, 6. This results in F = 0 and C = 5.\r\nG) Since H can not be 5, B can not be 8. Since G can not be 5, J can not be 8. Going back to equation #4, eliminate those equations where either B or J is 8. B = 9, I = 3, A = 2, and J = 7.\r\nH) The last four letters can now be assigned values. D = 1, E = 8, G = 4, and H = 6.\n<|im_start|>answer\n2951804637\n\r\nA = 2, B = 9, C = 5, D = 1, E = 8, F = 0, G = 4, H = 6, I = 3, J = 7\n\r\n1) 9 + 5 + 0 + 7 = 8 + 4 + 6 + 3 = 21\r\n2) 8 - 3 = 5 - 0 = 5\r\n3) 7 - 4 = 9 - 6 = 3\r\n4) 9 * 3 = 27\n\r\nA) The sum of the ten digits is 45. Two digits (A and D) form a two-digit number. If A and D are 8 and 9, then the remaining eight digits sum to 28. If A and D are 0 and 1, then the remaining digits sum to 44. These sums must be split equally between two groups of four digits. Therefore, each group of four digits must sum to one of the following: 14, 15, 16, 17, 18, 19, 20, 21, 22.\r\nB) If the sum of each group is 14, then A and D must be a combination of 1 and 4, which sum to 5. Subtract 5 from 45, leaving 40. Divide 40 by 2, leaving 20. 20 does not equal 14, so the sum of each group can not be 14. Repeating the preceding sequence for each of the possible sums leaves only two possible results: 18 (1 + 8 = 9, 45 - 9 = 36, 36 / 2 = 18) and 21 (2 + 1 = 3, 45 - 3 = 42, 42 / 2 = 21). A must be: 1, 2. D must be: 1, 8.\r\nC) To satisfy equation #2, B and J must be 3 greater than H and G, respectively. B and J must each be one of the following: 3, 5, 6, 7, 8, 9. H and G must each be one of the following: 0, 2, 3, 4, 5, 6.\r\nD) To satisfy equation #3, C and E must be 5 greater than F and I, respectively. C and E must each be one of the following: 5, 7, 8, 9. F and I must each be one of the following: 0, 2, 3, 4.\r\nE) For equation #4, there are six possibilities for B and four possibilities for I, creating 24 possible equations. Eliminate any equation where A is not 1 or 2. Eliminate any equation where J is not 3, 5, 6, 7, 8, or 9. Eliminate any equation where any digit is duplicated. B must be: 6, 7, 8, 9. I must be: 2, 3, 4. J must be: 6, 7, 8.\r\nF) Returning to equations #2 and #3, eliminate additional possibilities. E must be: 7, 8, 9. G must be: 3, 4, 5. H must be: 3, 4, 5, 6. This results in F = 0 and C = 5.\r\nG) Since H can not be 5, B can not be 8. Since G can not be 5, J can not be 8. Going back to equation #4, eliminate those equations where either B or J is 8. B = 9, I = 3, A = 2, and J = 7.\r\nH) The last four letters can now be assigned values. D = 1, E = 8, G = 4, and H = 6.\n<|im_end|>" }, { "id": "#49281", "title": "Soccer Match", "fun": 2.0, "difficulty": 0.97, "author": "Gwabu", "desc": "A soccer team played six matches, out of which they won two, drew two and lost two. During these matches the team scored three goals and conceded two goals.\r\nWhat were the results of all six matches?", "hint": "No hint available.", "answer": "Matches:\n\r\n- won 1-0 , 2-0\r\n- lost 0-1 , 0-1\r\n- draw 0-0 , 0-0", "category": "Logic", "date": "02/06/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA soccer team played six matches, out of which they won two, drew two and lost two. During these matches the team scored three goals and conceded two goals.\r\nWhat were the results of all six matches?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMatches:\n\r\n- won 1-0 , 2-0\r\n- lost 0-1 , 0-1\r\n- draw 0-0 , 0-0\n<|im_start|>answer\nMatches:\n\r\n- won 1-0 , 2-0\r\n- lost 0-1 , 0-1\r\n- draw 0-0 , 0-0\n<|im_end|>" }, { "id": "#43969", "title": "Class Photo 2", "fun": 2.0, "difficulty": 2.45, "author": "cnmne", "desc": "Kevin's class picture has 28 photos arranged in a 7 x 4 grid. The photos in the top row are numbered 1 through 7 from left to right, with the photos in the remaining rows similarly numbered. Given the following clues (bordering includes horizontal, vertical, and diagonal), where is Kevin's picture?\n\r\nX X X X X X X (1 - 7)\r\nX X X X X X X (8 - 14)\r\nX X X X X X X (15 - 21)\r\nX X X X X X X (22 - 28)\n\r\n1) There are 11 boys and 17 girls.\r\n2) No boy is next to another boy horizontally or vertically.\r\n3) There are no more than three boys in each row.\r\n4) One column has only girls.\r\n5) Three boys are not along the edge of the picture.\r\n6) The second boy is at an odd position.\r\n7) The range of the boys' positions is 24.\r\n8) The median of the boys' positions is 12 or 13 or 14.\r\n9) There are boys in two corners.\r\n10) Kevin occupies an even position, and is the only boy who borders a unique number of girls.", "hint": "No hint available.", "answer": "A) There are five boys prior to the median, meaning that there are three boys in each of the first two rows. If the first boy is at location 4, then there could only be two boys in the first row. The first boy must be located before position 4, therefore a girl must occupy: 28 (clue 7). The second boy can not be at position 4 (clue 6). The earliest position that the third boy could occupy is position 5. Therefore, a girl must occupy: 4.\r\nB) If boys are at positions 1 (a corner) and 25 (clue 7), then a boy would have to be at either position 7 or 22 (clue 9). In either case, more than three boys would not be along the edge of the picture, violating clue 5. Therefore, a girl must occupy: 1. Boys must occupy: 7 and 22 (clue 9). Girls must occupy: 6, 14, 15, and 23.\r\nC) For three boys to be in the first row, the second boy must occupy: 5 (which also satisfies clue 6). A girl must occupy 12. Per clue 8, a boy must occupy: 13. A girl must occupy: 20. To avoid violating clue 5, boys must occupy: 8 and 21. A girl must occupy: 9.\r\nD) Clues 8 and 9 have now been satisfied, and 16 of the 28 positions have been filled. To satisfy clues 1 through 7, the last 12 positions can be filled in four different ways. However, only one of those ways will satisfy clue 10. In the three ways that do not work, the boy that borders a unique number of girls is located at an odd position.\n\r\nStep A Step B Step C Step D\r\nxxxGxxx GxxGxGB GxxGBGB GBGGBGB\r\nxxxxxxx xxxxxxG BGxxGBG BGBGGBG\r\nxxxxxxx Gxxxxxx GxxxxGB GBGGGGB\r\nxxxxxxG BGxxxxG BGxxxxG BGBGBGG\n\r\nThe boys in the first row border (3, 4, 2) girls.\r\nThe boys in the second row border (3, 6, 5) girls.\r\nThe boys in the third row border (4, 4) girls.\r\nThe boys in the fourth row border (2, 4, 5) girls.\n\r\nThe only boy that borders a unique number of girls is the boy who borders six girls, which is at position 10. Kevin is at position 10.", "category": "Logic", "date": "01/21/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKevin's class picture has 28 photos arranged in a 7 x 4 grid. The photos in the top row are numbered 1 through 7 from left to right, with the photos in the remaining rows similarly numbered. Given the following clues (bordering includes horizontal, vertical, and diagonal), where is Kevin's picture?\n\r\nX X X X X X X (1 - 7)\r\nX X X X X X X (8 - 14)\r\nX X X X X X X (15 - 21)\r\nX X X X X X X (22 - 28)\n\r\n1) There are 11 boys and 17 girls.\r\n2) No boy is next to another boy horizontally or vertically.\r\n3) There are no more than three boys in each row.\r\n4) One column has only girls.\r\n5) Three boys are not along the edge of the picture.\r\n6) The second boy is at an odd position.\r\n7) The range of the boys' positions is 24.\r\n8) The median of the boys' positions is 12 or 13 or 14.\r\n9) There are boys in two corners.\r\n10) Kevin occupies an even position, and is the only boy who borders a unique number of girls.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA) There are five boys prior to the median, meaning that there are three boys in each of the first two rows. If the first boy is at location 4, then there could only be two boys in the first row. The first boy must be located before position 4, therefore a girl must occupy: 28 (clue 7). The second boy can not be at position 4 (clue 6). The earliest position that the third boy could occupy is position 5. Therefore, a girl must occupy: 4.\r\nB) If boys are at positions 1 (a corner) and 25 (clue 7), then a boy would have to be at either position 7 or 22 (clue 9). In either case, more than three boys would not be along the edge of the picture, violating clue 5. Therefore, a girl must occupy: 1. Boys must occupy: 7 and 22 (clue 9). Girls must occupy: 6, 14, 15, and 23.\r\nC) For three boys to be in the first row, the second boy must occupy: 5 (which also satisfies clue 6). A girl must occupy 12. Per clue 8, a boy must occupy: 13. A girl must occupy: 20. To avoid violating clue 5, boys must occupy: 8 and 21. A girl must occupy: 9.\r\nD) Clues 8 and 9 have now been satisfied, and 16 of the 28 positions have been filled. To satisfy clues 1 through 7, the last 12 positions can be filled in four different ways. However, only one of those ways will satisfy clue 10. In the three ways that do not work, the boy that borders a unique number of girls is located at an odd position.\n\r\nStep A Step B Step C Step D\r\nxxxGxxx GxxGxGB GxxGBGB GBGGBGB\r\nxxxxxxx xxxxxxG BGxxGBG BGBGGBG\r\nxxxxxxx Gxxxxxx GxxxxGB GBGGGGB\r\nxxxxxxG BGxxxxG BGxxxxG BGBGBGG\n\r\nThe boys in the first row border (3, 4, 2) girls.\r\nThe boys in the second row border (3, 6, 5) girls.\r\nThe boys in the third row border (4, 4) girls.\r\nThe boys in the fourth row border (2, 4, 5) girls.\n\r\nThe only boy that borders a unique number of girls is the boy who borders six girls, which is at position 10. Kevin is at position 10.\n<|im_start|>answer\nA) There are five boys prior to the median, meaning that there are three boys in each of the first two rows. If the first boy is at location 4, then there could only be two boys in the first row. The first boy must be located before position 4, therefore a girl must occupy: 28 (clue 7). The second boy can not be at position 4 (clue 6). The earliest position that the third boy could occupy is position 5. Therefore, a girl must occupy: 4.\r\nB) If boys are at positions 1 (a corner) and 25 (clue 7), then a boy would have to be at either position 7 or 22 (clue 9). In either case, more than three boys would not be along the edge of the picture, violating clue 5. Therefore, a girl must occupy: 1. Boys must occupy: 7 and 22 (clue 9). Girls must occupy: 6, 14, 15, and 23.\r\nC) For three boys to be in the first row, the second boy must occupy: 5 (which also satisfies clue 6). A girl must occupy 12. Per clue 8, a boy must occupy: 13. A girl must occupy: 20. To avoid violating clue 5, boys must occupy: 8 and 21. A girl must occupy: 9.\r\nD) Clues 8 and 9 have now been satisfied, and 16 of the 28 positions have been filled. To satisfy clues 1 through 7, the last 12 positions can be filled in four different ways. However, only one of those ways will satisfy clue 10. In the three ways that do not work, the boy that borders a unique number of girls is located at an odd position.\n\r\nStep A Step B Step C Step D\r\nxxxGxxx GxxGxGB GxxGBGB GBGGBGB\r\nxxxxxxx xxxxxxG BGxxGBG BGBGGBG\r\nxxxxxxx Gxxxxxx GxxxxGB GBGGGGB\r\nxxxxxxG BGxxxxG BGxxxxG BGBGBGG\n\r\nThe boys in the first row border (3, 4, 2) girls.\r\nThe boys in the second row border (3, 6, 5) girls.\r\nThe boys in the third row border (4, 4) girls.\r\nThe boys in the fourth row border (2, 4, 5) girls.\n\r\nThe only boy that borders a unique number of girls is the boy who borders six girls, which is at position 10. Kevin is at position 10.\n<|im_end|>" }, { "id": "#48289", "title": "Function Table #2", "fun": 2.0, "difficulty": 1.57, "author": "Magyk555", "desc": "A function table is a table of order pairs that follow a rule. A rule tells how one number is related to another. In this brainteaser, I will give you a function table (sometimes called an input-output table) and you need to figure out what the rule is. I will give you an example.\n\r\nExample:\n\r\nInput(A) Output(B)\r\n7(A), 9(B)\r\n13(A), 15(B)\r\n1(A), 3(B)\r\n3(A), 5(B)\r\n9(A), 11(B)\r\nThe rule in this example is add 2. Now here is the real deal. Find out what the rule is. \r\n*This one will be harder than the example. Way harder.\n\r\nInput(A) Output(B)\r\n6(A), 4.5(B)\r\n23(A), 17.25(B)\r\n9(A), 6.75(B)\r\n10(A), 7.5(B)\r\n45(A), 33.75(B)", "hint": "No hint available.", "answer": "The rule to this function table is multiply A by 3, and then divide that number by 4. If you want to see it in an equation, look below.\n\r\n(Ax3)/4=B\r\nAnother way to write it:\r\n(A*3)/4=B", "category": "Math", "date": "12/11/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA function table is a table of order pairs that follow a rule. A rule tells how one number is related to another. In this brainteaser, I will give you a function table (sometimes called an input-output table) and you need to figure out what the rule is. I will give you an example.\n\r\nExample:\n\r\nInput(A) Output(B)\r\n7(A), 9(B)\r\n13(A), 15(B)\r\n1(A), 3(B)\r\n3(A), 5(B)\r\n9(A), 11(B)\r\nThe rule in this example is add 2. Now here is the real deal. Find out what the rule is. \r\n*This one will be harder than the example. Way harder.\n\r\nInput(A) Output(B)\r\n6(A), 4.5(B)\r\n23(A), 17.25(B)\r\n9(A), 6.75(B)\r\n10(A), 7.5(B)\r\n45(A), 33.75(B)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe rule to this function table is multiply A by 3, and then divide that number by 4. If you want to see it in an equation, look below.\n\r\n(Ax3)/4=B\r\nAnother way to write it:\r\n(A*3)/4=B\n<|im_start|>answer\nThe rule to this function table is multiply A by 3, and then divide that number by 4. If you want to see it in an equation, look below.\n\r\n(Ax3)/4=B\r\nAnother way to write it:\r\n(A*3)/4=B\n<|im_end|>" }, { "id": "#50301", "title": "Balance Beams 2", "fun": 2.0, "difficulty": 1.9000000000000001, "author": "MarcM1098", "desc": "Two beams (rows of numbers) are given below. The first beam has a sum of 17; the second beam has a sum of 22. Your challenge is to balance the beams, so that the two rows have the same sum. You are only allowed to move two numbers; all of the numbers must be used in the answer.\n\r\n1 2 5 9\r\n3 4 7 8", "hint": "The sum of all the numbers is odd.\r\nOne of the numbers must be moved in a tricky way to make a larger number.", "answer": "Move the 1 to the bottom row, placing it immediately to the left of the 3, making a 13.\r\nMove the 8 to the top row. Both beams now have a sum of 24.\n\r\n8 2 5 9\r\n13 4 7", "category": "Math", "date": "05/09/14", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo beams (rows of numbers) are given below. The first beam has a sum of 17; the second beam has a sum of 22. Your challenge is to balance the beams, so that the two rows have the same sum. You are only allowed to move two numbers; all of the numbers must be used in the answer.\n\r\n1 2 5 9\r\n3 4 7 8\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMove the 1 to the bottom row, placing it immediately to the left of the 3, making a 13.\r\nMove the 8 to the top row. Both beams now have a sum of 24.\n\r\n8 2 5 9\r\n13 4 7\n<|im_start|>answer\nMove the 1 to the bottom row, placing it immediately to the left of the 3, making a 13.\r\nMove the 8 to the top row. Both beams now have a sum of 24.\n\r\n8 2 5 9\r\n13 4 7\n<|im_end|>" }, { "id": "#20351", "title": "Baseball Diamond", "fun": 1.99, "difficulty": 0.8200000000000001, "author": "josbuc", "desc": "Three men (Manny, Moe, and Jack) with last names Buchalter, Bowser, and Burkhart each play a different position on the baseball diamond (centerfield, catcher, and pitcher). \n\r\nCan you figure out the last name and position of each player?\n\r\nClues\r\n1. Manny is the furthest away from the plate.\r\n2. Jack's last name has a repeated letter in it.\r\n3. Moe has to wear a lot of equipment.\r\n4. Manny has one letter in his last name that is within five letters from the end of the alphabet.", "hint": "No hint available.", "answer": "Moe- Buchalter- catcher\r\nJack- Burkhart- pitcher\r\nManny- Bowser- centerfield", "category": "Logic-Grid", "date": "01/11/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree men (Manny, Moe, and Jack) with last names Buchalter, Bowser, and Burkhart each play a different position on the baseball diamond (centerfield, catcher, and pitcher). \n\r\nCan you figure out the last name and position of each player?\n\r\nClues\r\n1. Manny is the furthest away from the plate.\r\n2. Jack's last name has a repeated letter in it.\r\n3. Moe has to wear a lot of equipment.\r\n4. Manny has one letter in his last name that is within five letters from the end of the alphabet.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMoe- Buchalter- catcher\r\nJack- Burkhart- pitcher\r\nManny- Bowser- centerfield\n<|im_start|>answer\nMoe- Buchalter- catcher\r\nJack- Burkhart- pitcher\r\nManny- Bowser- centerfield\n<|im_end|>" }, { "id": "#2319", "title": "Jill and Her Dog", "fun": 1.99, "difficulty": 1.18, "author": "rml417", "desc": "Jill walks her dog three times every day.\r\nEach walk lasts 13 minutes. How many times does she walk her dog in one year?", "hint": "No hint available.", "answer": "1095. You don't have to worry about the 13. \r\nAll you have to do is 3 x 365 = 1095\n\r\n(In a leap year, Jill walks her dog 1098 times.)", "category": "Math", "date": "02/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJill walks her dog three times every day.\r\nEach walk lasts 13 minutes. How many times does she walk her dog in one year?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1095. You don't have to worry about the 13. \r\nAll you have to do is 3 x 365 = 1095\n\r\n(In a leap year, Jill walks her dog 1098 times.)\n<|im_start|>answer\n1095. You don't have to worry about the 13. \r\nAll you have to do is 3 x 365 = 1095\n\r\n(In a leap year, Jill walks her dog 1098 times.)\n<|im_end|>" }, { "id": "#21298", "title": "Quocorrian Math 2", "fun": 1.99, "difficulty": 2.97, "author": "CPlusPlusMan", "desc": "After being intrigued by Quocorria's mathematical systems, you decide to extend your stay on this mathematically advanced planet. \n\r\nWhile talking to a Quocorrian professor, he mentions Quocorria's other numbering systems. Your curiosity gets the best of you, so you decide you won't leave Quocorria until you master all of their systems. \n\r\nThe professor gives you a piece of paper with four true math problems on it. Like before, you must discover the system.\r\nNote: This is a different system than last time\r\nHere are the problems:\r\n2+2=12\r\n5-3=62\r\n3x4=61\r\n6/3=83\n\r\nSo, using this system, what is 1-3?", "hint": "Again, this is not an actual number system (decimal, binary, hexadecimal) but a variation on the way we do math.", "answer": "18. \n\r\nIn this system, you multiply each number by -1, changing it to its opposite. Then, do the operation normally. Then, add the two numbers together and square it. Add that to the original. \n\r\nFor all you equation people...\r\n-a*-b+(a+b)^2\r\nWith the * being the indicated operation.", "category": "Math", "date": "03/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAfter being intrigued by Quocorria's mathematical systems, you decide to extend your stay on this mathematically advanced planet. \n\r\nWhile talking to a Quocorrian professor, he mentions Quocorria's other numbering systems. Your curiosity gets the best of you, so you decide you won't leave Quocorria until you master all of their systems. \n\r\nThe professor gives you a piece of paper with four true math problems on it. Like before, you must discover the system.\r\nNote: This is a different system than last time\r\nHere are the problems:\r\n2+2=12\r\n5-3=62\r\n3x4=61\r\n6/3=83\n\r\nSo, using this system, what is 1-3?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n18. \n\r\nIn this system, you multiply each number by -1, changing it to its opposite. Then, do the operation normally. Then, add the two numbers together and square it. Add that to the original. \n\r\nFor all you equation people...\r\n-a*-b+(a+b)^2\r\nWith the * being the indicated operation.\n<|im_start|>answer\n18. \n\r\nIn this system, you multiply each number by -1, changing it to its opposite. Then, do the operation normally. Then, add the two numbers together and square it. Add that to the original. \n\r\nFor all you equation people...\r\n-a*-b+(a+b)^2\r\nWith the * being the indicated operation.\n<|im_end|>" }, { "id": "#43862", "title": "Sweet Tooth 2", "fun": 1.99, "difficulty": 0.35000000000000003, "author": "kaipolani114", "desc": "Each of these children have a favorite candy that they can't live without. Match up each child with their age and favorite candy. Their names are Aaron, Ashley, and Andrew. Their ages range from 3 to 5 years old. Their favorite candy is either Skittles, Hershey's Kisses, or Jolly Ranchers.\n\n\r\n1. Ashley is allergic to chocolate.\r\n2. Aaron does not like Jolly Ranchers.\r\n3. Andrew is the oldest.\r\n4. Ashley is younger than Andrew but older than Aaron.\r\n5. Andrew likes Jolly Ranchers.", "hint": "No hint available.", "answer": "Aaron is 3 years old and likes Hershey's Kisses.\r\nAshley is 4 years old and likes Skittles.\r\nAndrew is 5 years old and likes Jolly Ranchers.", "category": "Logic-Grid", "date": "01/06/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nEach of these children have a favorite candy that they can't live without. Match up each child with their age and favorite candy. Their names are Aaron, Ashley, and Andrew. Their ages range from 3 to 5 years old. Their favorite candy is either Skittles, Hershey's Kisses, or Jolly Ranchers.\n\n\r\n1. Ashley is allergic to chocolate.\r\n2. Aaron does not like Jolly Ranchers.\r\n3. Andrew is the oldest.\r\n4. Ashley is younger than Andrew but older than Aaron.\r\n5. Andrew likes Jolly Ranchers.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAaron is 3 years old and likes Hershey's Kisses.\r\nAshley is 4 years old and likes Skittles.\r\nAndrew is 5 years old and likes Jolly Ranchers.\n<|im_start|>answer\nAaron is 3 years old and likes Hershey's Kisses.\r\nAshley is 4 years old and likes Skittles.\r\nAndrew is 5 years old and likes Jolly Ranchers.\n<|im_end|>" }, { "id": "#45585", "title": "X-Men", "fun": 1.98, "difficulty": 2.31, "author": "Aaronnp", "desc": "Which is the odd one out?\n\r\nStorm\r\nBeast\r\nNightcrawler\r\nCyclops\r\nAngel\r\nIceman\r\nRogue", "hint": "It has nothing to do with the show, comic or movie.", "answer": "Cyclops.\n\r\nWhy? Because the other names don't have any repeated letters", "category": "Logic", "date": "11/01/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhich is the odd one out?\n\r\nStorm\r\nBeast\r\nNightcrawler\r\nCyclops\r\nAngel\r\nIceman\r\nRogue\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nCyclops.\n\r\nWhy? Because the other names don't have any repeated letters\n<|im_start|>answer\nCyclops.\n\r\nWhy? Because the other names don't have any repeated letters\n<|im_end|>" }, { "id": "#43400", "title": "Red, Yellow, and Blue", "fun": 1.98, "difficulty": 0.6900000000000001, "author": "shenqiang", "desc": "Adam, Bob, and Charlie are wearing clothes and hats of three colors: red, yellow, and blue. From the clues below, figure out the color of hat and clothes each man is wearing.\n\r\n1. Adam doesn't wear a red hat, and Bob doesn't wear a yellow hat.\r\n2. The person who wears a red hat doesn't wear blue clothes.\r\n3. The person who wears a yellow hat wears red clothes.\r\n4. Bob doesn't wear yellow clothes.", "hint": "No hint available.", "answer": "Adam wears a yellow hat and red clothes.\r\nBob wears a blue hat and blue clothes.\r\nCharlie wears a red hat and yellow clothes.", "category": "Logic-Grid", "date": "10/23/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAdam, Bob, and Charlie are wearing clothes and hats of three colors: red, yellow, and blue. From the clues below, figure out the color of hat and clothes each man is wearing.\n\r\n1. Adam doesn't wear a red hat, and Bob doesn't wear a yellow hat.\r\n2. The person who wears a red hat doesn't wear blue clothes.\r\n3. The person who wears a yellow hat wears red clothes.\r\n4. Bob doesn't wear yellow clothes.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAdam wears a yellow hat and red clothes.\r\nBob wears a blue hat and blue clothes.\r\nCharlie wears a red hat and yellow clothes.\n<|im_start|>answer\nAdam wears a yellow hat and red clothes.\r\nBob wears a blue hat and blue clothes.\r\nCharlie wears a red hat and yellow clothes.\n<|im_end|>" }, { "id": "#5961", "title": "Kebab Mate", "fun": 1.98, "difficulty": 2.13, "author": "mad-ade", "desc": "Mad Ade regularly plays chess with his best friend, Dim Dave McLoweyecue. They play just one game per day and the loser must give the winner a kebab. After a period of time Mad Ade had bought Dim Dave 5 kebabs whereas Dim Dave had bought Mad Ade 21 kebabs. So how many games were played in total if there were no tied matches?", "hint": "No hint available.", "answer": "Dim Dave McLoweyecue received 5 kebabs and won 5 games. Mad Ade received 21 kebabs and won 21 games. \n\r\nThus, the total number of games that they played was 26.", "category": "Math", "date": "07/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMad Ade regularly plays chess with his best friend, Dim Dave McLoweyecue. They play just one game per day and the loser must give the winner a kebab. After a period of time Mad Ade had bought Dim Dave 5 kebabs whereas Dim Dave had bought Mad Ade 21 kebabs. So how many games were played in total if there were no tied matches?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDim Dave McLoweyecue received 5 kebabs and won 5 games. Mad Ade received 21 kebabs and won 21 games. \n\r\nThus, the total number of games that they played was 26.\n<|im_start|>answer\nDim Dave McLoweyecue received 5 kebabs and won 5 games. Mad Ade received 21 kebabs and won 21 games. \n\r\nThus, the total number of games that they played was 26.\n<|im_end|>" }, { "id": "#2180", "title": "Poppers", "fun": 1.98, "difficulty": 1.31, "author": "Sinead", "desc": "If it took 5 seconds for one popper to pop, 5 seconds for two poppers to pop, 5 seconds for three poppers to pop, 5 seconds for four poppers to pop, how many seconds would it take for 100 poppers to pop?", "hint": "No hint available.", "answer": "5 seconds. They all go at the same time!", "category": "Logic", "date": "01/27/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf it took 5 seconds for one popper to pop, 5 seconds for two poppers to pop, 5 seconds for three poppers to pop, 5 seconds for four poppers to pop, how many seconds would it take for 100 poppers to pop?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5 seconds. They all go at the same time!\n<|im_start|>answer\n5 seconds. They all go at the same time!\n<|im_end|>" }, { "id": "#5215", "title": "Pillar's Shadow", "fun": 1.97, "difficulty": 1.21, "author": "Cascas", "desc": "A pillar 6 feet tall casts a shadow 2 feet long on the ground. If the pillar was 24 feet tall, how many feet in length would the shadow be?", "hint": "No hint available.", "answer": "The lengths of the shadows are to one another as the heights of the pillars. Thus, \n\r\nLength of the shadow for a pillar 24 feet tall \r\n= (24 / 6) x 2 = 8 feet.", "category": "Math", "date": "07/04/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA pillar 6 feet tall casts a shadow 2 feet long on the ground. If the pillar was 24 feet tall, how many feet in length would the shadow be?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe lengths of the shadows are to one another as the heights of the pillars. Thus, \n\r\nLength of the shadow for a pillar 24 feet tall \r\n= (24 / 6) x 2 = 8 feet.\n<|im_start|>answer\nThe lengths of the shadows are to one another as the heights of the pillars. Thus, \n\r\nLength of the shadow for a pillar 24 feet tall \r\n= (24 / 6) x 2 = 8 feet.\n<|im_end|>" }, { "id": "#49422", "title": "Variable Switch", "fun": 1.97, "difficulty": 2.26, "author": "rob77", "desc": "You're a computer programmer, and the program you're writing has numeric variables A and B. You need the computer to switch the variables so that the number in variable A becomes variable B, and the number in variable B becomes variable A. Adding a third variable would use more memory though, so how can you do that switch without using another variable? Use commands such as B=B-A to assign a new value to B.", "hint": "You can do it in three steps.", "answer": "B = A+B\r\nA = B-A\r\nB = B-A\n\r\nUsing an example, if A=5 and B=4:\r\nB = 5+4\r\nA = 9-5\r\nB = 9-4\r\nA is now 4 and B is now 5.", "category": "Logic", "date": "04/16/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou're a computer programmer, and the program you're writing has numeric variables A and B. You need the computer to switch the variables so that the number in variable A becomes variable B, and the number in variable B becomes variable A. Adding a third variable would use more memory though, so how can you do that switch without using another variable? Use commands such as B=B-A to assign a new value to B.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nB = A+B\r\nA = B-A\r\nB = B-A\n\r\nUsing an example, if A=5 and B=4:\r\nB = 5+4\r\nA = 9-5\r\nB = 9-4\r\nA is now 4 and B is now 5.\n<|im_start|>answer\nB = A+B\r\nA = B-A\r\nB = B-A\n\r\nUsing an example, if A=5 and B=4:\r\nB = 5+4\r\nA = 9-5\r\nB = 9-4\r\nA is now 4 and B is now 5.\n<|im_end|>" }, { "id": "#45827", "title": "Mystery Number 6", "fun": 1.96, "difficulty": 3.07, "author": "cnmne", "desc": "There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) Digit A is either a square number or a triangle number, but not both.\r\n2) Digit B is either an even number or a cube number, but not both.\r\n3) Digit C is either a cube number or a triangle number, but not both.\r\n4) Digit D is either an odd number or a square number, but not both.\r\n5) Digit E is either an odd number or a cube number, but not both.\r\n6) Digit F is either an odd number or a triangle number, but not both.\r\n7) Digit G is either an odd number or a prime number, but not both.\r\n8) Digit H is either an even number or a square number, but not both.\r\n9) Digit I is either a square number or a cube number, but not both.\r\n10) Digit J is either a prime number or a triangle number, but not both.\r\n11) A < B, C < D, E < F, G < H, I < J\r\n12) A + B + C + D + E < F + G + H + I + J", "hint": "No hint available.", "answer": "3605891247\n\r\nA = 3, B = 6, C = 0, D = 5, E = 8, F = 9, G = 1, H = 2, I = 4, J = 7\n\r\n1) 3 is a triangle number, but not a square number.\r\n2) 6 is an even number, but not a cube number.\r\n3) 0 is a cube number, but not a triangle number.\r\n4) 5 is an odd number, but not a square number.\r\n5) 8 is a cube number, but not an odd number.\r\n6) 9 is an odd number, but not a triangle number.\r\n7) 1 is an odd number, but not a prime number.\r\n8) 2 is an even number, but not a square number.\r\n9) 4 is a square number, but not a cube number.\r\n10) 7 is a prime number, but not a triangle number.\r\n11) 3 < 6, 0 < 5, 8 < 9, 1 < 2, 4 < 7\r\n12) 3 + 6 + 0 + 5 + 8 = 22, 9 + 1 + 2 + 4 + 7 = 23, 22 < 23\n\r\nA) First, determine what two subsets of numbers qualify for each digit. However, each digit can only be in one of the subsets, not both.\r\nB) Digit A can not be 0 (a leading zero is not allowed).\r\nC) Next, eliminate those numbers that do not satisfy Condition 11. Digit I can only be 4. Digit A can only be 3. Digit B can only be 6. Digit C can only be 0.\r\nD) Digit D and Digit J must be some combination of 5 and 7. Digit E can only be 8. Digit F can only be 9. Digit G can only be 1. Digit H can only be 2.\r\nE) To satisfy Condition 12, Digit D is 5 and Digit J is 7.", "category": "Logic", "date": "11/30/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?\n\r\n1) Digit A is either a square number or a triangle number, but not both.\r\n2) Digit B is either an even number or a cube number, but not both.\r\n3) Digit C is either a cube number or a triangle number, but not both.\r\n4) Digit D is either an odd number or a square number, but not both.\r\n5) Digit E is either an odd number or a cube number, but not both.\r\n6) Digit F is either an odd number or a triangle number, but not both.\r\n7) Digit G is either an odd number or a prime number, but not both.\r\n8) Digit H is either an even number or a square number, but not both.\r\n9) Digit I is either a square number or a cube number, but not both.\r\n10) Digit J is either a prime number or a triangle number, but not both.\r\n11) A < B, C < D, E < F, G < H, I < J\r\n12) A + B + C + D + E < F + G + H + I + J\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3605891247\n\r\nA = 3, B = 6, C = 0, D = 5, E = 8, F = 9, G = 1, H = 2, I = 4, J = 7\n\r\n1) 3 is a triangle number, but not a square number.\r\n2) 6 is an even number, but not a cube number.\r\n3) 0 is a cube number, but not a triangle number.\r\n4) 5 is an odd number, but not a square number.\r\n5) 8 is a cube number, but not an odd number.\r\n6) 9 is an odd number, but not a triangle number.\r\n7) 1 is an odd number, but not a prime number.\r\n8) 2 is an even number, but not a square number.\r\n9) 4 is a square number, but not a cube number.\r\n10) 7 is a prime number, but not a triangle number.\r\n11) 3 < 6, 0 < 5, 8 < 9, 1 < 2, 4 < 7\r\n12) 3 + 6 + 0 + 5 + 8 = 22, 9 + 1 + 2 + 4 + 7 = 23, 22 < 23\n\r\nA) First, determine what two subsets of numbers qualify for each digit. However, each digit can only be in one of the subsets, not both.\r\nB) Digit A can not be 0 (a leading zero is not allowed).\r\nC) Next, eliminate those numbers that do not satisfy Condition 11. Digit I can only be 4. Digit A can only be 3. Digit B can only be 6. Digit C can only be 0.\r\nD) Digit D and Digit J must be some combination of 5 and 7. Digit E can only be 8. Digit F can only be 9. Digit G can only be 1. Digit H can only be 2.\r\nE) To satisfy Condition 12, Digit D is 5 and Digit J is 7.\n<|im_start|>answer\n3605891247\n\r\nA = 3, B = 6, C = 0, D = 5, E = 8, F = 9, G = 1, H = 2, I = 4, J = 7\n\r\n1) 3 is a triangle number, but not a square number.\r\n2) 6 is an even number, but not a cube number.\r\n3) 0 is a cube number, but not a triangle number.\r\n4) 5 is an odd number, but not a square number.\r\n5) 8 is a cube number, but not an odd number.\r\n6) 9 is an odd number, but not a triangle number.\r\n7) 1 is an odd number, but not a prime number.\r\n8) 2 is an even number, but not a square number.\r\n9) 4 is a square number, but not a cube number.\r\n10) 7 is a prime number, but not a triangle number.\r\n11) 3 < 6, 0 < 5, 8 < 9, 1 < 2, 4 < 7\r\n12) 3 + 6 + 0 + 5 + 8 = 22, 9 + 1 + 2 + 4 + 7 = 23, 22 < 23\n\r\nA) First, determine what two subsets of numbers qualify for each digit. However, each digit can only be in one of the subsets, not both.\r\nB) Digit A can not be 0 (a leading zero is not allowed).\r\nC) Next, eliminate those numbers that do not satisfy Condition 11. Digit I can only be 4. Digit A can only be 3. Digit B can only be 6. Digit C can only be 0.\r\nD) Digit D and Digit J must be some combination of 5 and 7. Digit E can only be 8. Digit F can only be 9. Digit G can only be 1. Digit H can only be 2.\r\nE) To satisfy Condition 12, Digit D is 5 and Digit J is 7.\n<|im_end|>" }, { "id": "#48488", "title": "Birthday Number", "fun": 1.96, "difficulty": 1.53, "author": "shenqiang", "desc": "A \"birthday number\" is defined as follows: add all digits of the month and day of the birthday. For example, November 24th has \"birthday number\" 1+1+2+4=8.\n\r\nWhat are the birthdays that share the second smallest birthday number?", "hint": "What is the smallest birthday number?", "answer": "The smallest birthday number is 2, as in 1.1 and 10.1.\n\r\nThe second smallest birthday number is 3, as in 1.2, 1.11, 1.20, 2.1, 2.10, 10.2, 10.11, 10.20, 11.1, 11.10.", "category": "Math", "date": "02/19/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA \"birthday number\" is defined as follows: add all digits of the month and day of the birthday. For example, November 24th has \"birthday number\" 1+1+2+4=8.\n\r\nWhat are the birthdays that share the second smallest birthday number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe smallest birthday number is 2, as in 1.1 and 10.1.\n\r\nThe second smallest birthday number is 3, as in 1.2, 1.11, 1.20, 2.1, 2.10, 10.2, 10.11, 10.20, 11.1, 11.10.\n<|im_start|>answer\nThe smallest birthday number is 2, as in 1.1 and 10.1.\n\r\nThe second smallest birthday number is 3, as in 1.2, 1.11, 1.20, 2.1, 2.10, 10.2, 10.11, 10.20, 11.1, 11.10.\n<|im_end|>" }, { "id": "#35747", "title": "Who and Where", "fun": 1.96, "difficulty": 0.92, "author": "nascarfan19", "desc": "Bob got second place. Joe finished two places after Bob. Billy got one place in front of Joe. Who finished first?", "hint": "No hint available.", "answer": "None of those listed finished first.\r\nBilly finished 3rd.\r\nJoe finished 4th.", "category": "Logic", "date": "03/18/07", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob got second place. Joe finished two places after Bob. Billy got one place in front of Joe. Who finished first?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nNone of those listed finished first.\r\nBilly finished 3rd.\r\nJoe finished 4th.\n<|im_start|>answer\nNone of those listed finished first.\r\nBilly finished 3rd.\r\nJoe finished 4th.\n<|im_end|>" }, { "id": "#20197", "title": "The CD Store", "fun": 1.96, "difficulty": 0.8, "author": "besbball917", "desc": "Bob went to the CD store and bought 3 CDs by 3 different artists with a different song on each CD. Each CD cost a different amount. \n\r\nThe three artists were Martina McBride, Tim McGraw, and Keith Urban. The songs were Live Like You Were Dying, How Far, and Days Go By. The prices were $14.95, $12.99, and $13.50. With these hints, try to match up the artist, song and price that go together.\n\r\n1. Keith Urban's CD cost the least.\r\n2. The highest priced CD had the song, Days Go By on it.\r\n3. Tim McGraw sings How Far.\r\n4. Martina McBride's CD costs $14.95", "hint": "If you know country music, don't think that that will help you because I mixed up the songs and the artists.", "answer": "Martina McBride - Days Go By - $14.95\r\nKeith Urban - Live Like You Were Dying - $12.99\r\nTim McGraw - How Far - $13.50", "category": "Logic-Grid", "date": "01/02/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob went to the CD store and bought 3 CDs by 3 different artists with a different song on each CD. Each CD cost a different amount. \n\r\nThe three artists were Martina McBride, Tim McGraw, and Keith Urban. The songs were Live Like You Were Dying, How Far, and Days Go By. The prices were $14.95, $12.99, and $13.50. With these hints, try to match up the artist, song and price that go together.\n\r\n1. Keith Urban's CD cost the least.\r\n2. The highest priced CD had the song, Days Go By on it.\r\n3. Tim McGraw sings How Far.\r\n4. Martina McBride's CD costs $14.95\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMartina McBride - Days Go By - $14.95\r\nKeith Urban - Live Like You Were Dying - $12.99\r\nTim McGraw - How Far - $13.50\n<|im_start|>answer\nMartina McBride - Days Go By - $14.95\r\nKeith Urban - Live Like You Were Dying - $12.99\r\nTim McGraw - How Far - $13.50\n<|im_end|>" }, { "id": "#1172", "title": "Dots on a Line", "fun": 1.96, "difficulty": 1.52, "author": "Ichabod Clay", "desc": "How many points can you place on a single line?", "hint": "No hint available.", "answer": "An infinite amount. Remember, a line stretches on forever.", "category": "Math", "date": "10/20/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nHow many points can you place on a single line?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAn infinite amount. Remember, a line stretches on forever.\n<|im_start|>answer\nAn infinite amount. Remember, a line stretches on forever.\n<|im_end|>" }, { "id": "#1553", "title": "f(g(2))", "fun": 1.95, "difficulty": 2.11, "author": "jrung14", "desc": "What is f(g(2)) if f(x)= 2x-3 and g(x)= x+4", "hint": "No hint available.", "answer": "9", "category": "Math", "date": "11/30/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is f(g(2)) if f(x)= 2x-3 and g(x)= x+4\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n9\n<|im_start|>answer\n9\n<|im_end|>" }, { "id": "#50498", "title": "Line Drawings", "fun": 1.95, "difficulty": 2.19, "author": "duhya", "desc": "We all know and love those drawing puzzles in which you have to draw a symbol without retracing or lifting your pencil. The quickest way to check if a symbol can be drawn with such restrictions is to count the vertices in which an odd number of line segments meet. \r\n If there are more than three vertices in which this occurs, the symbol cannot be drawn. \n\r\n Can a symbol have only one vertex in which this occurs?", "hint": "Odds and ends", "answer": "It cannot. \n\r\n There must be an even amount of vertices in which this occurs, as these signify the ends of a line segment. It cannot have only one, as a line segment with one ending does not exist.", "category": "Logic", "date": "02/13/15", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWe all know and love those drawing puzzles in which you have to draw a symbol without retracing or lifting your pencil. The quickest way to check if a symbol can be drawn with such restrictions is to count the vertices in which an odd number of line segments meet. \r\n If there are more than three vertices in which this occurs, the symbol cannot be drawn. \n\r\n Can a symbol have only one vertex in which this occurs?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIt cannot. \n\r\n There must be an even amount of vertices in which this occurs, as these signify the ends of a line segment. It cannot have only one, as a line segment with one ending does not exist.\n<|im_start|>answer\nIt cannot. \n\r\n There must be an even amount of vertices in which this occurs, as these signify the ends of a line segment. It cannot have only one, as a line segment with one ending does not exist.\n<|im_end|>" }, { "id": "#21741", "title": "Construction Dilemma", "fun": 1.95, "difficulty": 2.96, "author": "Sane", "desc": "Mr. Math, or Sane, was hired by Nortel to design the dimensions for their building. He decided to make the building an open cylindrical area inscribed in a perfect cube.\n\r\nBut a tragic incident caused Sane to become sick and not be able to communicate! The only dimension that he had written down was for the corner office, 16 by 8 meters (which extends to the edge of the open area). \n\r\nThe construction workers can not start over now, as they've already begun building. But if they want to finish the Nortel building in time, they will need to know the final dimension of the perfect cube and cylinder! Can anyone here help them?\n\r\nAlternate: If the construction workers became ambitious and decided to make all the offices out of solid wood, approximately how much would it cost them at $10 per m^3?", "hint": "Formulate an equation where the hypotenuse of the two squared unknown distances will equal the radius of the building.", "answer": "Formulate an equation where the hypotenuse of the two squared unknown distances will equal the radius of the building.\n\r\n(Since our answer only needs two dimensions, we will convert them into square (building), circle (open area), and rectangle (corner office).\n\r\n[The Pythagorean theorem will solve for the root of the radius]\n\r\nLet a represent the length of the rectangle, then x-a be the radius of the circle minus the length of the rectangle, same to b (to width of the rectangle):\r\na^2 + b^2 = x^2\r\n(x - a)^2 + (x - b)^2 = x^2\r\nx^2 = (x - 16)(x - 16) + (x - 8)(x - 8)\n\r\n[Use foil to expand the brackets]\r\nx^2 = (x^2 - 16x - 16x + 256) + (x^2 - 8x - 8x + 64)\r\nx^2 = 2x^2 - 48x + 320\n\r\n[Order as a quadratic equation]\r\nx^2 - 48x + 320 = 0\n\r\n[Factor the equation using the quadratic formula with X excluded]\n\r\nLet a equal 1, b equal 48, and c equal 320 as temporary variables in the factoring equation:\r\nx = -b{+/-}[b^2 - 4ac]^1/2 / 2a \r\nx = -48{+/-}[2304 - 1280]^1/2 / 2\r\nx = -48{+/-}32 / 2\r\nx = -40 and x = -8\n\r\n[Input those numbers into the now factored equation]\r\n(x - 40)(x - 8) = 0\n\r\nIf the radius were 8, then that would mean the corner office would end up extending into the circular area (because the corner office is 16 x 8).\r\nTherefore, the diameter of the cylinder or the dimensions of the building must be 40 * 2 (radius x 2) to make 80m x 80m. \n\n\n\r\nAlternate: The volume of the building is expressed by:\r\nv = l * w * h\n\r\nBut remember, since the cylinder is open space, we need to figure it too. \n\r\nThe volume of the cylinder is expressed by:\r\nv = pi(r^2) * h\n\r\nTherefore, the volume of solid wood is the volume of the building less the empty area:\n\r\nv = [l * w * h] - [pi(r^2) * h]\r\nv = [80 * 80 * 80] - [pi(40^2) * 80]\r\nv ~= 512 000 - 402124\r\nv ~= 109 876 m^3\n\r\nIf wood is $10 per m^3:\r\n10 * 109876 = $1 098 760", "category": "Math", "date": "03/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMr. Math, or Sane, was hired by Nortel to design the dimensions for their building. He decided to make the building an open cylindrical area inscribed in a perfect cube.\n\r\nBut a tragic incident caused Sane to become sick and not be able to communicate! The only dimension that he had written down was for the corner office, 16 by 8 meters (which extends to the edge of the open area). \n\r\nThe construction workers can not start over now, as they've already begun building. But if they want to finish the Nortel building in time, they will need to know the final dimension of the perfect cube and cylinder! Can anyone here help them?\n\r\nAlternate: If the construction workers became ambitious and decided to make all the offices out of solid wood, approximately how much would it cost them at $10 per m^3?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nFormulate an equation where the hypotenuse of the two squared unknown distances will equal the radius of the building.\n\r\n(Since our answer only needs two dimensions, we will convert them into square (building), circle (open area), and rectangle (corner office).\n\r\n[The Pythagorean theorem will solve for the root of the radius]\n\r\nLet a represent the length of the rectangle, then x-a be the radius of the circle minus the length of the rectangle, same to b (to width of the rectangle):\r\na^2 + b^2 = x^2\r\n(x - a)^2 + (x - b)^2 = x^2\r\nx^2 = (x - 16)(x - 16) + (x - 8)(x - 8)\n\r\n[Use foil to expand the brackets]\r\nx^2 = (x^2 - 16x - 16x + 256) + (x^2 - 8x - 8x + 64)\r\nx^2 = 2x^2 - 48x + 320\n\r\n[Order as a quadratic equation]\r\nx^2 - 48x + 320 = 0\n\r\n[Factor the equation using the quadratic formula with X excluded]\n\r\nLet a equal 1, b equal 48, and c equal 320 as temporary variables in the factoring equation:\r\nx = -b{+/-}[b^2 - 4ac]^1/2 / 2a \r\nx = -48{+/-}[2304 - 1280]^1/2 / 2\r\nx = -48{+/-}32 / 2\r\nx = -40 and x = -8\n\r\n[Input those numbers into the now factored equation]\r\n(x - 40)(x - 8) = 0\n\r\nIf the radius were 8, then that would mean the corner office would end up extending into the circular area (because the corner office is 16 x 8).\r\nTherefore, the diameter of the cylinder or the dimensions of the building must be 40 * 2 (radius x 2) to make 80m x 80m. \n\n\n\r\nAlternate: The volume of the building is expressed by:\r\nv = l * w * h\n\r\nBut remember, since the cylinder is open space, we need to figure it too. \n\r\nThe volume of the cylinder is expressed by:\r\nv = pi(r^2) * h\n\r\nTherefore, the volume of solid wood is the volume of the building less the empty area:\n\r\nv = [l * w * h] - [pi(r^2) * h]\r\nv = [80 * 80 * 80] - [pi(40^2) * 80]\r\nv ~= 512 000 - 402124\r\nv ~= 109 876 m^3\n\r\nIf wood is $10 per m^3:\r\n10 * 109876 = $1 098 760\n<|im_start|>answer\nFormulate an equation where the hypotenuse of the two squared unknown distances will equal the radius of the building.\n\r\n(Since our answer only needs two dimensions, we will convert them into square (building), circle (open area), and rectangle (corner office).\n\r\n[The Pythagorean theorem will solve for the root of the radius]\n\r\nLet a represent the length of the rectangle, then x-a be the radius of the circle minus the length of the rectangle, same to b (to width of the rectangle):\r\na^2 + b^2 = x^2\r\n(x - a)^2 + (x - b)^2 = x^2\r\nx^2 = (x - 16)(x - 16) + (x - 8)(x - 8)\n\r\n[Use foil to expand the brackets]\r\nx^2 = (x^2 - 16x - 16x + 256) + (x^2 - 8x - 8x + 64)\r\nx^2 = 2x^2 - 48x + 320\n\r\n[Order as a quadratic equation]\r\nx^2 - 48x + 320 = 0\n\r\n[Factor the equation using the quadratic formula with X excluded]\n\r\nLet a equal 1, b equal 48, and c equal 320 as temporary variables in the factoring equation:\r\nx = -b{+/-}[b^2 - 4ac]^1/2 / 2a \r\nx = -48{+/-}[2304 - 1280]^1/2 / 2\r\nx = -48{+/-}32 / 2\r\nx = -40 and x = -8\n\r\n[Input those numbers into the now factored equation]\r\n(x - 40)(x - 8) = 0\n\r\nIf the radius were 8, then that would mean the corner office would end up extending into the circular area (because the corner office is 16 x 8).\r\nTherefore, the diameter of the cylinder or the dimensions of the building must be 40 * 2 (radius x 2) to make 80m x 80m. \n\n\n\r\nAlternate: The volume of the building is expressed by:\r\nv = l * w * h\n\r\nBut remember, since the cylinder is open space, we need to figure it too. \n\r\nThe volume of the cylinder is expressed by:\r\nv = pi(r^2) * h\n\r\nTherefore, the volume of solid wood is the volume of the building less the empty area:\n\r\nv = [l * w * h] - [pi(r^2) * h]\r\nv = [80 * 80 * 80] - [pi(40^2) * 80]\r\nv ~= 512 000 - 402124\r\nv ~= 109 876 m^3\n\r\nIf wood is $10 per m^3:\r\n10 * 109876 = $1 098 760\n<|im_end|>" }, { "id": "#45005", "title": "Video Games", "fun": 1.94, "difficulty": 0.56, "author": "JACK_IN4", "desc": "Three kids have three new video games on different systems and made in different years. Find out which game belongs to whom, what system it's for, and what year it was made.\n\r\nSally has a 1996 Video game.\r\nBob doesn't have Yourlefty.\r\nNathan has a 2009 game.\r\nRapidspider wasn't made in 2007.\r\nNathan doesn't have a Nintendo 64.\r\nBob has a Playstaytion 3.\r\nSawer isn't a Wii game.\r\nRapidspider is an old game.", "hint": "All the game names are made up.", "answer": "Bob has Sawer for the Playstation 3 made in 2007.\r\nSally has Rapidspider for the Nintendo 64 made in 1996.\r\nNathan has Yourlefty for the Wii made in 2009.", "category": "Logic-Grid", "date": "08/03/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree kids have three new video games on different systems and made in different years. Find out which game belongs to whom, what system it's for, and what year it was made.\n\r\nSally has a 1996 Video game.\r\nBob doesn't have Yourlefty.\r\nNathan has a 2009 game.\r\nRapidspider wasn't made in 2007.\r\nNathan doesn't have a Nintendo 64.\r\nBob has a Playstaytion 3.\r\nSawer isn't a Wii game.\r\nRapidspider is an old game.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob has Sawer for the Playstation 3 made in 2007.\r\nSally has Rapidspider for the Nintendo 64 made in 1996.\r\nNathan has Yourlefty for the Wii made in 2009.\n<|im_start|>answer\nBob has Sawer for the Playstation 3 made in 2007.\r\nSally has Rapidspider for the Nintendo 64 made in 1996.\r\nNathan has Yourlefty for the Wii made in 2009.\n<|im_end|>" }, { "id": "#49184", "title": "16, 1, 4, 12, -2, ?", "fun": 1.94, "difficulty": 1.93, "author": "CrazyPineapple", "desc": "What number can replace the question mark in the puzzle? There is a pattern!\n\r\n1, 2, 15, 12\n\r\n-9, 10, 20, 43, -3, -1, -30\n\r\n8, 17, 4, 1\n\r\n16, 1, 4, 12, -2, ?", "hint": "No hint available.", "answer": "The number -1 can replace the question mark! Each string of numbers adds up to 30.", "category": "Math", "date": "12/12/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat number can replace the question mark in the puzzle? There is a pattern!\n\r\n1, 2, 15, 12\n\r\n-9, 10, 20, 43, -3, -1, -30\n\r\n8, 17, 4, 1\n\r\n16, 1, 4, 12, -2, ?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe number -1 can replace the question mark! Each string of numbers adds up to 30.\n<|im_start|>answer\nThe number -1 can replace the question mark! Each string of numbers adds up to 30.\n<|im_end|>" }, { "id": "#34131", "title": "Fun at the Beach", "fun": 1.92, "difficulty": 0.89, "author": "Dontrelle", "desc": "Jeffrey, Cody, and Dontrelle went to the beach. They all had three different color towels, (blue, green, and yellow) and they all had a different type of food (hot dog, hamburger, ham sandwich). What you need to do is solve the puzzle.\n\n\r\n#1 Jeffrey has the yellow towel.\n\r\n#2 Cody doesn't have the hot dog.\n\r\n#3 Dontrelle doesn't have the green towel.\n\r\n#4 Jeffrey has the ham sandwich.", "hint": "No hint available.", "answer": "Jeffrey has the yellow towel and the ham sandwich.\n\r\nCody has the green towel and the hamburger.\n\r\nDontrelle has the blue towel and the hot dog.", "category": "Logic-Grid", "date": "11/27/06", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJeffrey, Cody, and Dontrelle went to the beach. They all had three different color towels, (blue, green, and yellow) and they all had a different type of food (hot dog, hamburger, ham sandwich). What you need to do is solve the puzzle.\n\n\r\n#1 Jeffrey has the yellow towel.\n\r\n#2 Cody doesn't have the hot dog.\n\r\n#3 Dontrelle doesn't have the green towel.\n\r\n#4 Jeffrey has the ham sandwich.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJeffrey has the yellow towel and the ham sandwich.\n\r\nCody has the green towel and the hamburger.\n\r\nDontrelle has the blue towel and the hot dog.\n<|im_start|>answer\nJeffrey has the yellow towel and the ham sandwich.\n\r\nCody has the green towel and the hamburger.\n\r\nDontrelle has the blue towel and the hot dog.\n<|im_end|>" }, { "id": "#44397", "title": "Cake Carelessness", "fun": 1.92, "difficulty": 0.75, "author": "cakewalk13", "desc": "Four people were celebrating birthdays on April 4th. They all ordered cakes from Caketown. The only problem is, the baker mixed up all of the orders! Can you figure out who ordered what?\n\r\n1. For his topping, Felipe realized he needed to buy something to make it bright.\r\n2. Kat ordered glaze.\r\n3. The color of Kat's cake is the color of a vanilla bean.\r\n4. The cake that Jane ordered is named after the game in which the players roll glass spheres around.\r\n5. The one whose cake is frosted like a donut has berries.\r\n6. Similar to confetti, Jane loves these toppings on her cake.\r\n7. Ever read the Swiss Family Robinson? What they used to treat animals' wounds is what Timmy's frosting tastes like. It's similar to margarine.\r\n8. The Mexican man loves the taste of vanilla, so that's the frosting he picked.\r\n9. Easter is almost here! The one who has dripping wax wants his cake the color of chicks.\r\n10. Timmy loves flowers. He also loves rich, yummy cake that has a name like what you measure weight with.", "hint": "Felipe requested candles on his cake.", "answer": "Timmy: roses, buttercream, pound cake\r\nJane: sprinkles, chocolate, marble cake\r\nFelipe: candles, vanilla, yellow cake\r\nKat: berries, glaze, chocolate cake", "category": "Logic-Grid", "date": "04/29/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFour people were celebrating birthdays on April 4th. They all ordered cakes from Caketown. The only problem is, the baker mixed up all of the orders! Can you figure out who ordered what?\n\r\n1. For his topping, Felipe realized he needed to buy something to make it bright.\r\n2. Kat ordered glaze.\r\n3. The color of Kat's cake is the color of a vanilla bean.\r\n4. The cake that Jane ordered is named after the game in which the players roll glass spheres around.\r\n5. The one whose cake is frosted like a donut has berries.\r\n6. Similar to confetti, Jane loves these toppings on her cake.\r\n7. Ever read the Swiss Family Robinson? What they used to treat animals' wounds is what Timmy's frosting tastes like. It's similar to margarine.\r\n8. The Mexican man loves the taste of vanilla, so that's the frosting he picked.\r\n9. Easter is almost here! The one who has dripping wax wants his cake the color of chicks.\r\n10. Timmy loves flowers. He also loves rich, yummy cake that has a name like what you measure weight with.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTimmy: roses, buttercream, pound cake\r\nJane: sprinkles, chocolate, marble cake\r\nFelipe: candles, vanilla, yellow cake\r\nKat: berries, glaze, chocolate cake\n<|im_start|>answer\nTimmy: roses, buttercream, pound cake\r\nJane: sprinkles, chocolate, marble cake\r\nFelipe: candles, vanilla, yellow cake\r\nKat: berries, glaze, chocolate cake\n<|im_end|>" }, { "id": "#49299", "title": "Snack Time at Rachel's", "fun": 1.92, "difficulty": 0.24, "author": "Rhythmic", "desc": "One day, Rachel had her two best friends over for a play date. When it came time for a snack, her mom asked her to find out what everyone wanted. Rachel was happy to help because she loved playing hostess. However, when Rachel got back to her mom, she couldn't quite remember everything. Can you help her figure it out?\n\r\nFriends: Katie, Rachel, Sophie\r\nFoods: apple slices, banana slices, orange slices\r\nDrinks: juice, milk, water\n\r\n1) Of course, Rachel remembered that she wanted milk and orange slices.\n\r\n2) Although she couldn't remember who it was, Rachel knew that the person who wanted juice also wanted apple slices.\n\r\n3) Rachel knew that Sophie didn't like apples.", "hint": "No hint available.", "answer": "Katie wanted juice and apple slices.\r\nRachel wanted milk and orange slices.\r\nSophie wanted water and banana slices.", "category": "Logic-Grid", "date": "02/06/12", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nOne day, Rachel had her two best friends over for a play date. When it came time for a snack, her mom asked her to find out what everyone wanted. Rachel was happy to help because she loved playing hostess. However, when Rachel got back to her mom, she couldn't quite remember everything. Can you help her figure it out?\n\r\nFriends: Katie, Rachel, Sophie\r\nFoods: apple slices, banana slices, orange slices\r\nDrinks: juice, milk, water\n\r\n1) Of course, Rachel remembered that she wanted milk and orange slices.\n\r\n2) Although she couldn't remember who it was, Rachel knew that the person who wanted juice also wanted apple slices.\n\r\n3) Rachel knew that Sophie didn't like apples.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKatie wanted juice and apple slices.\r\nRachel wanted milk and orange slices.\r\nSophie wanted water and banana slices.\n<|im_start|>answer\nKatie wanted juice and apple slices.\r\nRachel wanted milk and orange slices.\r\nSophie wanted water and banana slices.\n<|im_end|>" }, { "id": "#43594", "title": "How Old is ____? #2", "fun": 1.91, "difficulty": 0.54, "author": "angelsluvme", "desc": "Jane is 34. Kevin is 11. Lucy is half as old as Jane but three years younger than Mike. Mike is 3 times as old as Greg. How old is Greg?", "hint": "Some useless information might be added. Use a decimal if needed.", "answer": "6.7 years", "category": "Math", "date": "11/24/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJane is 34. Kevin is 11. Lucy is half as old as Jane but three years younger than Mike. Mike is 3 times as old as Greg. How old is Greg?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n6.7 years\n<|im_start|>answer\n6.7 years\n<|im_end|>" }, { "id": "#3495", "title": "Take The Cake", "fun": 1.91, "difficulty": 1.47, "author": "Sinead", "desc": "Tonight you are having a sleepover. Your mom bakes a cake, but there is only enough for you and 3 other people. How much would you each get?", "hint": "No hint available.", "answer": "1/4", "category": "Math", "date": "04/14/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTonight you are having a sleepover. Your mom bakes a cake, but there is only enough for you and 3 other people. How much would you each get?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1/4\n<|im_start|>answer\n1/4\n<|im_end|>" }, { "id": "#41432", "title": "Free Wish Day!", "fun": 1.91, "difficulty": 0.72, "author": "brain23", "desc": "November 13 is Annual Free Wish Day! Each child in the universe gets to meet one fairy and wish for something. Unfortunately, Jorgen Von Strangle, the toughest fairy in the universe, can't remember who got what! Can you help him remember before he explodes the Earth?\n\r\n1. Trixie did not wish for the chocolate shake.\r\n2. A. J.'s fairy was Cosmo.\r\n3. Jorgen was about to visit Earth when he heard Chester wish for something other than a hamburger.\r\n4. Jorgen remembered that he had sent Juandissimo over to Trixie's house for the wish.\r\n5. A. J. was really hungry at the moment, so he got Cosmo to give him a hamburger.", "hint": "Juan = Juandissimmo\r\nShake = Chocolate Shake", "answer": "A.J had Cosmo grant him a hamburger.\r\nChester had Wanda give him a chocolate shake.\r\nTrixie had Juandissimmo grant her some fries.", "category": "Logic-Grid", "date": "04/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nNovember 13 is Annual Free Wish Day! Each child in the universe gets to meet one fairy and wish for something. Unfortunately, Jorgen Von Strangle, the toughest fairy in the universe, can't remember who got what! Can you help him remember before he explodes the Earth?\n\r\n1. Trixie did not wish for the chocolate shake.\r\n2. A. J.'s fairy was Cosmo.\r\n3. Jorgen was about to visit Earth when he heard Chester wish for something other than a hamburger.\r\n4. Jorgen remembered that he had sent Juandissimo over to Trixie's house for the wish.\r\n5. A. J. was really hungry at the moment, so he got Cosmo to give him a hamburger.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA.J had Cosmo grant him a hamburger.\r\nChester had Wanda give him a chocolate shake.\r\nTrixie had Juandissimmo grant her some fries.\n<|im_start|>answer\nA.J had Cosmo grant him a hamburger.\r\nChester had Wanda give him a chocolate shake.\r\nTrixie had Juandissimmo grant her some fries.\n<|im_end|>" }, { "id": "#50785", "title": "Houses on the Street", "fun": 1.91, "difficulty": 0.64, "author": "nidhikaila", "desc": "Sapna, Ashish and Bharat live in the same lane. Their houses are of different colors, but attached to each other and in the same lane. What we do not know, is: \r\nA. Who lives in which colored house. \r\nB. Which house comes first, which next, and which last. \n\r\nSee if you can answer both questions after the clues below: \r\n1.\tThe red house is next to the blue house but not next to the green house. \r\n2.\tSapna and Ashish are not neighbors. \r\n3.\tBharat loves going to the green house to the left of his house. \r\n4.\tSapna and Bharat never visit each other's house. \r\n5.\tThe right most house comes first in the lane.", "hint": "No hint available.", "answer": "Sapna - Red - 1 \r\nBharat - Blue - 2 \r\nAshish - Green - 3", "category": "Logic-Grid", "date": "04/11/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nSapna, Ashish and Bharat live in the same lane. Their houses are of different colors, but attached to each other and in the same lane. What we do not know, is: \r\nA. Who lives in which colored house. \r\nB. Which house comes first, which next, and which last. \n\r\nSee if you can answer both questions after the clues below: \r\n1.\tThe red house is next to the blue house but not next to the green house. \r\n2.\tSapna and Ashish are not neighbors. \r\n3.\tBharat loves going to the green house to the left of his house. \r\n4.\tSapna and Bharat never visit each other's house. \r\n5.\tThe right most house comes first in the lane.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSapna - Red - 1 \r\nBharat - Blue - 2 \r\nAshish - Green - 3\n<|im_start|>answer\nSapna - Red - 1 \r\nBharat - Blue - 2 \r\nAshish - Green - 3\n<|im_end|>" }, { "id": "#21823", "title": "Who What and Where", "fun": 1.9000000000000001, "difficulty": 1.08, "author": "eina_23052", "desc": "Amanda, Paulina and Khrystyna were all swimming in a lake. They all wanted to do different water sports and different times at different places on the lake. Please help them sort out their little problem. The groups are:\n\r\nParticipants: Amanda, Paulina, Khrystyna\n\r\nSports: water skiing, wake boarding, diving\n\r\nTimes: 1 pm, 3pm, 4pm\n\n\r\nClues:\r\n1. Khrystyna does not want to miss her tea time at 4pm because of Paulina.\n\r\n2. Amanda does not know how to ski.\n\r\n3. Paulina does not go back into the water until 4 pm.\n\r\n4. Khrystyna wants to use the boat as a platform right after lunch.", "hint": "No hint available.", "answer": "Khrystyna - 1pm - diving\r\nAmanda - 3pm - Wake boarding\r\nPaulina - 4pm - skiing", "category": "Logic-Grid", "date": "03/29/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAmanda, Paulina and Khrystyna were all swimming in a lake. They all wanted to do different water sports and different times at different places on the lake. Please help them sort out their little problem. The groups are:\n\r\nParticipants: Amanda, Paulina, Khrystyna\n\r\nSports: water skiing, wake boarding, diving\n\r\nTimes: 1 pm, 3pm, 4pm\n\n\r\nClues:\r\n1. Khrystyna does not want to miss her tea time at 4pm because of Paulina.\n\r\n2. Amanda does not know how to ski.\n\r\n3. Paulina does not go back into the water until 4 pm.\n\r\n4. Khrystyna wants to use the boat as a platform right after lunch.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nKhrystyna - 1pm - diving\r\nAmanda - 3pm - Wake boarding\r\nPaulina - 4pm - skiing\n<|im_start|>answer\nKhrystyna - 1pm - diving\r\nAmanda - 3pm - Wake boarding\r\nPaulina - 4pm - skiing\n<|im_end|>" }, { "id": "#20668", "title": "The Music Outlet", "fun": 1.9000000000000001, "difficulty": 1.17, "author": "do_you_yahoo", "desc": "Joel, Tim, Allison, and Hayley are all shopping at The Music Outlet. Each buys a CD. The CDs are Hilary Duff, Mud On The Tires, The Chronicles of Life and Death (by Good Charlotte), and Sweat. The prices of the CDs are $14, $16.50, $15.95, and $17. Who bought which CD?\n\r\n1) Joel didn't buy Sweat.\r\n2) Tim likes Good Charlotte, but bought Sweat instead.\r\n3) Allison didn't buy Hilary Duff, Sweat, or The Chronicles of Life and Death.\r\n4) Hayley hates Good Charlotte.\r\n5) Sweat costs $16.50.\r\n6) The Chronicles of Life and Death was the most expensive CD.\r\n7) Hilary Duff didn't cost $15.95 or $16.50.", "hint": "The name of each person has something to do with the band or artist that recorded the CD that the person bought.", "answer": "Joel-The Chronicles of Life and Death-$17\r\nTim-Sweat-$16.50\r\nAllison-Mud on The Tires-$15.95\r\nHayley-Hilary Duff-$14", "category": "Logic-Grid", "date": "01/28/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJoel, Tim, Allison, and Hayley are all shopping at The Music Outlet. Each buys a CD. The CDs are Hilary Duff, Mud On The Tires, The Chronicles of Life and Death (by Good Charlotte), and Sweat. The prices of the CDs are $14, $16.50, $15.95, and $17. Who bought which CD?\n\r\n1) Joel didn't buy Sweat.\r\n2) Tim likes Good Charlotte, but bought Sweat instead.\r\n3) Allison didn't buy Hilary Duff, Sweat, or The Chronicles of Life and Death.\r\n4) Hayley hates Good Charlotte.\r\n5) Sweat costs $16.50.\r\n6) The Chronicles of Life and Death was the most expensive CD.\r\n7) Hilary Duff didn't cost $15.95 or $16.50.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJoel-The Chronicles of Life and Death-$17\r\nTim-Sweat-$16.50\r\nAllison-Mud on The Tires-$15.95\r\nHayley-Hilary Duff-$14\n<|im_start|>answer\nJoel-The Chronicles of Life and Death-$17\r\nTim-Sweat-$16.50\r\nAllison-Mud on The Tires-$15.95\r\nHayley-Hilary Duff-$14\n<|im_end|>" }, { "id": "#44396", "title": "Parade Problem", "fun": 1.8900000000000001, "difficulty": 0.55, "author": "cakewalk13", "desc": "3 different families went to the Fourth of July picnic in their town of Fernpot. The Annual Parade and Picnic of Fabulous Fernpot was famous for miles around for being perfect, but something went wrong! The Lloyds, the Cosytens, and the Dungbungs all mixed up their stuff. Can you figure out whose basket, blanket, and 4th of July banner is whose?\n\r\nClues:\r\n1. The Lloyd's son was best friends with the checked blanket owner and the canvas basket owner.\r\n2. The ones who own the flag are not the Dungbungs.\r\n3. The Cosyten family has the \"Go America!\" banner.\r\n4. The Lloyds think patterns are much too exciting, so they have a beige blanket.\r\n5. The Cosytens do not have the canvas basket.\r\n6. Before the picnic, the Dungbungs realized that their blanket was stained, so they bought a new one that was striped.\r\n7. Mrs. Lloyd grew up on a farm and she made her family's basket out of something that horses eat.", "hint": "No hint available.", "answer": "Lloyds: solid blanket, straw basket, flag\r\nCosytens: checked blanket, cloth basket, \"Go America!\" banner\r\nDungbungs: striped blanket, canvas basket, \"Hooray, USA!\" banner", "category": "Logic-Grid", "date": "04/29/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\n3 different families went to the Fourth of July picnic in their town of Fernpot. The Annual Parade and Picnic of Fabulous Fernpot was famous for miles around for being perfect, but something went wrong! The Lloyds, the Cosytens, and the Dungbungs all mixed up their stuff. Can you figure out whose basket, blanket, and 4th of July banner is whose?\n\r\nClues:\r\n1. The Lloyd's son was best friends with the checked blanket owner and the canvas basket owner.\r\n2. The ones who own the flag are not the Dungbungs.\r\n3. The Cosyten family has the \"Go America!\" banner.\r\n4. The Lloyds think patterns are much too exciting, so they have a beige blanket.\r\n5. The Cosytens do not have the canvas basket.\r\n6. Before the picnic, the Dungbungs realized that their blanket was stained, so they bought a new one that was striped.\r\n7. Mrs. Lloyd grew up on a farm and she made her family's basket out of something that horses eat.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLloyds: solid blanket, straw basket, flag\r\nCosytens: checked blanket, cloth basket, \"Go America!\" banner\r\nDungbungs: striped blanket, canvas basket, \"Hooray, USA!\" banner\n<|im_start|>answer\nLloyds: solid blanket, straw basket, flag\r\nCosytens: checked blanket, cloth basket, \"Go America!\" banner\r\nDungbungs: striped blanket, canvas basket, \"Hooray, USA!\" banner\n<|im_end|>" }, { "id": "#18352", "title": "Zero Work", "fun": 1.8800000000000001, "difficulty": 1.67, "author": "scoutman", "desc": "Is zero even or odd?", "hint": "No hint available.", "answer": "Zero is even, because it comes between two odd numbers, 1 and -1.", "category": "Math", "date": "07/25/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIs zero even or odd?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nZero is even, because it comes between two odd numbers, 1 and -1.\n<|im_start|>answer\nZero is even, because it comes between two odd numbers, 1 and -1.\n<|im_end|>" }, { "id": "#47963", "title": "Bingo Card 4", "fun": 1.8800000000000001, "difficulty": 3.08, "author": "cnmne", "desc": "You are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) Each numeral (0 through 9) appears one time in Row 1.\r\n2) The sum of the numbers in Row 4 is a square number.\r\n3) There is only one two-digit prime number in each row.\r\n4) The range of the numbers in Column N is 8.\r\n5) Each number in Column G has a tens digit that is less than the units digit.\r\n6) Each number in Column O is odd.\r\n7) In only one column are the numbers in descending order from top to bottom.\r\n8) Each column has only one numeral that appears exactly two times.\r\n9) The smallest number in each column is located in Row 5.\r\n10) The sums of each column share a single common prime factor.\r\n11) The numeral 5 only appears one time on the card.\r\n12) The sum of the numbers in each diagonal is an odd number.\r\n13) The product of B3 and O3 has a units digit of 2.\r\n14) The product of I3 and G3 has a units digit of 4.", "hint": "No hint available.", "answer": "10 24 39 58 67\r\n 9 28 40 49 71\r\n 8 22 -- 47 69\r\n 3 30 42 48 73\r\n 1 20 34 46 61\n\r\n1) Per clue 5, eliminate the appropriate numbers in Column G. Of the remaining numbers, at least one with a tens digit of 5 will have to be used. Per clues 1 and 11, only one number can have the numeral 5, so that number must be at G1. Eliminate all numbers that contain a 5 from all other locations.\r\n2) Per clue 6, eliminate all even numbers from Column O.\r\n3) Per clue 1, eliminate any number from Row 1 with only one digit or duplicate digits. By analyzing combinations of numbers, the following can be determined: B1 contains a 1, delete 30, I1 contains a 2, delete 23, delete 63 and 73, O1 contains a 6. In conjunction with clue 3, delete 29 and 59.\r\n4) Per clue 10, analyze the various possible sums of Columns G and O. The only common prime factor is 31. Each column must sum to a multiple of 31 (based on available numbers: B to 31, I to 124, N to 155, G to 248, and O to 341). G1 must be 58. All two-digit prime numbers (clue 3) must be in Columns G and O. O1 must be 67. Per clue 1, N1 must be 39. Per clue 9, G5 must be 46 and O5 must be 61.\r\n5) For Column N, there is only set of numbers that sums to 155, and satisfies clues 4, 8, and 9 (34, 39, 40, 42). N5 must be 34.\r\n6) For Column I, there are two sets of numbers that sum to 124, and satisfy clues 8 and 9 (16, 24, 26, 28, 30 and 20, 22, 24, 28, 30). To satisfy clue 1, I1 must be 24. B1 must be 10. To satisfy clue 12, G4 must be 48 and B5 must be odd.\r\n7) The column that satisfies clue 7 is Column B. To satisfy clue 8, B2 must be 9 and B5 must be 1.\r\n8) To satisfy clue 2, the only square number that can be achieved is 196. B4 must be 3, I4 must be 30, N4 must be 42, and O4 must be 73.\r\n9) B3 must be 8. N2 must be 40.\r\n10) To satisfy clue 13, O3 must be 69. This leaves O2 being 71. To satisfy clue 3, G3 must be 47. This leaves G2 being 49.\r\n11) To satisfy clue 14, I3 must be 22. Finally, to achieve a sum of 124 (multiple of 31), I2 must be 28 and I5 must be 20.", "category": "Logic", "date": "09/16/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nYou are given a stack of bingo cards. Your task is to find a specific card. Given the following clues, what is the number arrangement of that card?\n\r\nColumns, left to right, are: B (contains numbers 1 through 15), I (contains numbers 16 through 30), N (contains numbers 31 through 45), G (contains numbers 46 through 60), O (contains numbers 61 through 75). Rows, top to bottom, are: 1, 2, 3, 4, 5. An example of coordinate nomenclature: B1 identifies column B row 1. N3 is a free space (contains no number). No number appears more than once.\n\r\n1) Each numeral (0 through 9) appears one time in Row 1.\r\n2) The sum of the numbers in Row 4 is a square number.\r\n3) There is only one two-digit prime number in each row.\r\n4) The range of the numbers in Column N is 8.\r\n5) Each number in Column G has a tens digit that is less than the units digit.\r\n6) Each number in Column O is odd.\r\n7) In only one column are the numbers in descending order from top to bottom.\r\n8) Each column has only one numeral that appears exactly two times.\r\n9) The smallest number in each column is located in Row 5.\r\n10) The sums of each column share a single common prime factor.\r\n11) The numeral 5 only appears one time on the card.\r\n12) The sum of the numbers in each diagonal is an odd number.\r\n13) The product of B3 and O3 has a units digit of 2.\r\n14) The product of I3 and G3 has a units digit of 4.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n10 24 39 58 67\r\n 9 28 40 49 71\r\n 8 22 -- 47 69\r\n 3 30 42 48 73\r\n 1 20 34 46 61\n\r\n1) Per clue 5, eliminate the appropriate numbers in Column G. Of the remaining numbers, at least one with a tens digit of 5 will have to be used. Per clues 1 and 11, only one number can have the numeral 5, so that number must be at G1. Eliminate all numbers that contain a 5 from all other locations.\r\n2) Per clue 6, eliminate all even numbers from Column O.\r\n3) Per clue 1, eliminate any number from Row 1 with only one digit or duplicate digits. By analyzing combinations of numbers, the following can be determined: B1 contains a 1, delete 30, I1 contains a 2, delete 23, delete 63 and 73, O1 contains a 6. In conjunction with clue 3, delete 29 and 59.\r\n4) Per clue 10, analyze the various possible sums of Columns G and O. The only common prime factor is 31. Each column must sum to a multiple of 31 (based on available numbers: B to 31, I to 124, N to 155, G to 248, and O to 341). G1 must be 58. All two-digit prime numbers (clue 3) must be in Columns G and O. O1 must be 67. Per clue 1, N1 must be 39. Per clue 9, G5 must be 46 and O5 must be 61.\r\n5) For Column N, there is only set of numbers that sums to 155, and satisfies clues 4, 8, and 9 (34, 39, 40, 42). N5 must be 34.\r\n6) For Column I, there are two sets of numbers that sum to 124, and satisfy clues 8 and 9 (16, 24, 26, 28, 30 and 20, 22, 24, 28, 30). To satisfy clue 1, I1 must be 24. B1 must be 10. To satisfy clue 12, G4 must be 48 and B5 must be odd.\r\n7) The column that satisfies clue 7 is Column B. To satisfy clue 8, B2 must be 9 and B5 must be 1.\r\n8) To satisfy clue 2, the only square number that can be achieved is 196. B4 must be 3, I4 must be 30, N4 must be 42, and O4 must be 73.\r\n9) B3 must be 8. N2 must be 40.\r\n10) To satisfy clue 13, O3 must be 69. This leaves O2 being 71. To satisfy clue 3, G3 must be 47. This leaves G2 being 49.\r\n11) To satisfy clue 14, I3 must be 22. Finally, to achieve a sum of 124 (multiple of 31), I2 must be 28 and I5 must be 20.\n<|im_start|>answer\n10 24 39 58 67\r\n 9 28 40 49 71\r\n 8 22 -- 47 69\r\n 3 30 42 48 73\r\n 1 20 34 46 61\n\r\n1) Per clue 5, eliminate the appropriate numbers in Column G. Of the remaining numbers, at least one with a tens digit of 5 will have to be used. Per clues 1 and 11, only one number can have the numeral 5, so that number must be at G1. Eliminate all numbers that contain a 5 from all other locations.\r\n2) Per clue 6, eliminate all even numbers from Column O.\r\n3) Per clue 1, eliminate any number from Row 1 with only one digit or duplicate digits. By analyzing combinations of numbers, the following can be determined: B1 contains a 1, delete 30, I1 contains a 2, delete 23, delete 63 and 73, O1 contains a 6. In conjunction with clue 3, delete 29 and 59.\r\n4) Per clue 10, analyze the various possible sums of Columns G and O. The only common prime factor is 31. Each column must sum to a multiple of 31 (based on available numbers: B to 31, I to 124, N to 155, G to 248, and O to 341). G1 must be 58. All two-digit prime numbers (clue 3) must be in Columns G and O. O1 must be 67. Per clue 1, N1 must be 39. Per clue 9, G5 must be 46 and O5 must be 61.\r\n5) For Column N, there is only set of numbers that sums to 155, and satisfies clues 4, 8, and 9 (34, 39, 40, 42). N5 must be 34.\r\n6) For Column I, there are two sets of numbers that sum to 124, and satisfy clues 8 and 9 (16, 24, 26, 28, 30 and 20, 22, 24, 28, 30). To satisfy clue 1, I1 must be 24. B1 must be 10. To satisfy clue 12, G4 must be 48 and B5 must be odd.\r\n7) The column that satisfies clue 7 is Column B. To satisfy clue 8, B2 must be 9 and B5 must be 1.\r\n8) To satisfy clue 2, the only square number that can be achieved is 196. B4 must be 3, I4 must be 30, N4 must be 42, and O4 must be 73.\r\n9) B3 must be 8. N2 must be 40.\r\n10) To satisfy clue 13, O3 must be 69. This leaves O2 being 71. To satisfy clue 3, G3 must be 47. This leaves G2 being 49.\r\n11) To satisfy clue 14, I3 must be 22. Finally, to achieve a sum of 124 (multiple of 31), I2 must be 28 and I5 must be 20.\n<|im_end|>" }, { "id": "#45154", "title": "Greed is Good!", "fun": 1.8800000000000001, "difficulty": 1.58, "author": "addspras", "desc": "Two stockbrokers, Mr. Greed and Mr. Avarice, hold stocks of Company Gordon and Company Gekko respectively. Both stockbrokers sell their respective stocks of Company Gordon and Company Gekko for $1000 each. Stockbroker Mr. Greed calculates his profit based on cost price while Stockbroker Mr. Avarice calculates his profit based on selling price. While both claim to their clients to have made 25% profit, who is really hoodwinking his client and who has actually made more money for his client?", "hint": "No hint available.", "answer": "Stockbroker Mr. Greed calculates his profit % on cost price so his cost price is $1000/1.25= $800 and has thus made a profit of $200.\n\r\nStockbroker Mr. Avarice has calculated his profit % on selling price, so his cost price should be $1000*(1-.25)= $ 750, hence his profit is $ 250, so in reality Stockbroker Mr. Avarice has made more money for his client! Who ever said greed is good?!", "category": "Math", "date": "08/28/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo stockbrokers, Mr. Greed and Mr. Avarice, hold stocks of Company Gordon and Company Gekko respectively. Both stockbrokers sell their respective stocks of Company Gordon and Company Gekko for $1000 each. Stockbroker Mr. Greed calculates his profit based on cost price while Stockbroker Mr. Avarice calculates his profit based on selling price. While both claim to their clients to have made 25% profit, who is really hoodwinking his client and who has actually made more money for his client?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nStockbroker Mr. Greed calculates his profit % on cost price so his cost price is $1000/1.25= $800 and has thus made a profit of $200.\n\r\nStockbroker Mr. Avarice has calculated his profit % on selling price, so his cost price should be $1000*(1-.25)= $ 750, hence his profit is $ 250, so in reality Stockbroker Mr. Avarice has made more money for his client! Who ever said greed is good?!\n<|im_start|>answer\nStockbroker Mr. Greed calculates his profit % on cost price so his cost price is $1000/1.25= $800 and has thus made a profit of $200.\n\r\nStockbroker Mr. Avarice has calculated his profit % on selling price, so his cost price should be $1000*(1-.25)= $ 750, hence his profit is $ 250, so in reality Stockbroker Mr. Avarice has made more money for his client! Who ever said greed is good?!\n<|im_end|>" }, { "id": "#41451", "title": "Merlin's Pet", "fun": 1.87, "difficulty": 0.5700000000000001, "author": "pandastampede", "desc": "Merlin was walking to the pet store of Camelot thinking of the type of pet he wanted. He knew that the store carried griffins, trolls, and goblins. Later down the road he was thinking that, if he got a certain type of animal, they would need different qualities of food. The qualities were good, better, and best. Then he decides that the animals would need a certain size house for them to live in. The sizes are small, medium, and large. If Merlin draws a chart, which animal would get what food and what house?\r\n- The troll needs the biggest house, but not the best quality food.\r\n- The griffin needs the best quality food, but is too big for the smallest house.\r\n- The goblin needs the medium quality food. It also doesn't need a large house", "hint": "No hint available.", "answer": "- The griffin needs the best quality food and the medium sized house.\r\n- The goblin needs the medium quality food and the smallest house.\r\n- The troll gets the low quality food and the largest house.", "category": "Logic-Grid", "date": "04/10/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nMerlin was walking to the pet store of Camelot thinking of the type of pet he wanted. He knew that the store carried griffins, trolls, and goblins. Later down the road he was thinking that, if he got a certain type of animal, they would need different qualities of food. The qualities were good, better, and best. Then he decides that the animals would need a certain size house for them to live in. The sizes are small, medium, and large. If Merlin draws a chart, which animal would get what food and what house?\r\n- The troll needs the biggest house, but not the best quality food.\r\n- The griffin needs the best quality food, but is too big for the smallest house.\r\n- The goblin needs the medium quality food. It also doesn't need a large house\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n- The griffin needs the best quality food and the medium sized house.\r\n- The goblin needs the medium quality food and the smallest house.\r\n- The troll gets the low quality food and the largest house.\n<|im_start|>answer\n- The griffin needs the best quality food and the medium sized house.\r\n- The goblin needs the medium quality food and the smallest house.\r\n- The troll gets the low quality food and the largest house.\n<|im_end|>" }, { "id": "#41424", "title": "COOKers From FETCH!", "fun": 1.87, "difficulty": 0.64, "author": "brain23", "desc": "The Season 2 FETCHers may no longer be on the show, but that doesn't mean they have to work at diners! Four FETCHers (Mike, Willie, Nina, and Bridget) had to take orders for four people (John, Todd, Paul, and Benjamin) who each ordered a different thing (Burger, Chicken, Fruit, Cookies). Could you figure it out?\n\r\n1. Mike saw on his list that he had to cook chicken.\r\n2. John ordered fruit.\r\n3. Mike had to take orders for Todd. He didn't like it.\r\n4. Paul happily ate his burger cooked by Willie.\r\n5. Benjamin told Bridget to get cookies. She ate a few, though.", "hint": "No hint available.", "answer": "Mike cooked chicken for Todd.\r\nWillie cooked a burger for Paul.\r\nNina got fruit for John.\r\nBridget baked Benjamin cookies.", "category": "Logic-Grid", "date": "04/08/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe Season 2 FETCHers may no longer be on the show, but that doesn't mean they have to work at diners! Four FETCHers (Mike, Willie, Nina, and Bridget) had to take orders for four people (John, Todd, Paul, and Benjamin) who each ordered a different thing (Burger, Chicken, Fruit, Cookies). Could you figure it out?\n\r\n1. Mike saw on his list that he had to cook chicken.\r\n2. John ordered fruit.\r\n3. Mike had to take orders for Todd. He didn't like it.\r\n4. Paul happily ate his burger cooked by Willie.\r\n5. Benjamin told Bridget to get cookies. She ate a few, though.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMike cooked chicken for Todd.\r\nWillie cooked a burger for Paul.\r\nNina got fruit for John.\r\nBridget baked Benjamin cookies.\n<|im_start|>answer\nMike cooked chicken for Todd.\r\nWillie cooked a burger for Paul.\r\nNina got fruit for John.\r\nBridget baked Benjamin cookies.\n<|im_end|>" }, { "id": "#48638", "title": "Add to a Square Number", "fun": 1.87, "difficulty": 2.85, "author": "shenqiang", "desc": "A, B and C are positive integers such that 3^A+5^B+7^C is a square number.\n\r\nWhat is the minimum value of this square number?", "hint": "No hint available.", "answer": "3^3+5^1+7^2=81.", "category": "Math", "date": "04/14/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA, B and C are positive integers such that 3^A+5^B+7^C is a square number.\n\r\nWhat is the minimum value of this square number?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n3^3+5^1+7^2=81.\n<|im_start|>answer\n3^3+5^1+7^2=81.\n<|im_end|>" }, { "id": "#19709", "title": "Chess Games", "fun": 1.86, "difficulty": 3.0, "author": "AXTON", "desc": "The number of possible ways of playing the first four moves for both players in a game of chess is \r\n318 979 564 000\r\nHow many different possible moves can be made in the first ten moves by each player?", "hint": "No hint available.", "answer": "169 518 829 100 544 000", "category": "Math", "date": "12/05/04", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThe number of possible ways of playing the first four moves for both players in a game of chess is \r\n318 979 564 000\r\nHow many different possible moves can be made in the first ten moves by each player?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n169 518 829 100 544 000\n<|im_start|>answer\n169 518 829 100 544 000\n<|im_end|>" }, { "id": "#20568", "title": "Who Came First?", "fun": 1.86, "difficulty": 0.44, "author": "Crazy-G", "desc": "Bob, Andy, and Frank are trying to figure out which one is the oldest, middle child, the youngest, plus, whose birthday comes first.\n\r\nAges:\r\n8\r\n6\r\n5\n\r\nBirthdays:\r\nDecember\r\nJune\r\nMay\n\r\n1. Frank hates the fact that his birthday clashes with Christmas.\r\n2. Bob can count his age with one whole hand.\r\n3. Andy's birthday is in May.\r\n4. Frank is 6.", "hint": "No hint available.", "answer": "Bob: 5, June\n\r\nAndy: 8, May\n\r\nFrank: 6, December", "category": "Logic-Grid", "date": "01/24/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBob, Andy, and Frank are trying to figure out which one is the oldest, middle child, the youngest, plus, whose birthday comes first.\n\r\nAges:\r\n8\r\n6\r\n5\n\r\nBirthdays:\r\nDecember\r\nJune\r\nMay\n\r\n1. Frank hates the fact that his birthday clashes with Christmas.\r\n2. Bob can count his age with one whole hand.\r\n3. Andy's birthday is in May.\r\n4. Frank is 6.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBob: 5, June\n\r\nAndy: 8, May\n\r\nFrank: 6, December\n<|im_start|>answer\nBob: 5, June\n\r\nAndy: 8, May\n\r\nFrank: 6, December\n<|im_end|>" }, { "id": "#48226", "title": "Function Table #1", "fun": 1.86, "difficulty": 2.38, "author": "Magyk555", "desc": "A function table is a table of order pairs that follow a rule. A rule tells how one number is related to another. In this brainteaser, I will give you a function table (sometimes called an input-output table) and you need to figure out what the rule is. I will give you an example.\n\r\nExample:\n\r\nInput(A), Output(B)\r\n7(A), 9(B)\r\n13(A), 15(B)\r\n1(A), 3(B)\r\n3(A), 5(B)\r\n9(A), 11(B) \r\nThe rule in this example is add 2. Now here is the real deal. Find out what the rule is. \r\n*This one will be harder than the example. Way harder.\n\r\nInput(A), Output(B)\r\n7(A),\t 23.98(B)\r\n13(A),\t 42.82(B)\r\n39(A),\t 124.46(B)\r\n1(A),\t 5.14(B)\r\n100(A),\t 316(B)", "hint": "Pi\n\r\n*Pi is just a part of it.", "answer": "The rule to this function table is multiply A by pi (3.14) and add two. If you want to see it in an equation look below.\n\r\nA x 3.14 + 2 = B\r\nAnother way to write it:\r\nA * 3.14 + 2 = B", "category": "Math", "date": "11/22/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA function table is a table of order pairs that follow a rule. A rule tells how one number is related to another. In this brainteaser, I will give you a function table (sometimes called an input-output table) and you need to figure out what the rule is. I will give you an example.\n\r\nExample:\n\r\nInput(A), Output(B)\r\n7(A), 9(B)\r\n13(A), 15(B)\r\n1(A), 3(B)\r\n3(A), 5(B)\r\n9(A), 11(B) \r\nThe rule in this example is add 2. Now here is the real deal. Find out what the rule is. \r\n*This one will be harder than the example. Way harder.\n\r\nInput(A), Output(B)\r\n7(A),\t 23.98(B)\r\n13(A),\t 42.82(B)\r\n39(A),\t 124.46(B)\r\n1(A),\t 5.14(B)\r\n100(A),\t 316(B)\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe rule to this function table is multiply A by pi (3.14) and add two. If you want to see it in an equation look below.\n\r\nA x 3.14 + 2 = B\r\nAnother way to write it:\r\nA * 3.14 + 2 = B\n<|im_start|>answer\nThe rule to this function table is multiply A by pi (3.14) and add two. If you want to see it in an equation look below.\n\r\nA x 3.14 + 2 = B\r\nAnother way to write it:\r\nA * 3.14 + 2 = B\n<|im_end|>" }, { "id": "#41294", "title": "Favorite Televison Show?", "fun": 1.85, "difficulty": 0.72, "author": "pinkhakix3", "desc": "Three girls are finding out each other's favorite TV show. Can you find out whose favorite TV show is whose and their ages based on the facts below?\n\r\nNames: Emma, Madison, and Brooke\r\nAges: 9, 10, and 11\r\nTV shows: Hannah Montana, iCarly, and Full House\n\r\n1. Emma's favorite character is Stephanie and she is 11 .\n\r\n2. Madison is not 9 years old.\n\r\n3. The person whose favorite show is Full House is not 10.\n\r\n4. The person whose favorite show is Hannah Montana is Madison.\n\r\n5. The girl whose favorite show is iCarly is not Emma.", "hint": "No hint available.", "answer": "Emma-Full House-11\r\nMadison-Hannah Montana-10\r\nBrooke-iCarly-9", "category": "Logic-Grid", "date": "03/31/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree girls are finding out each other's favorite TV show. Can you find out whose favorite TV show is whose and their ages based on the facts below?\n\r\nNames: Emma, Madison, and Brooke\r\nAges: 9, 10, and 11\r\nTV shows: Hannah Montana, iCarly, and Full House\n\r\n1. Emma's favorite character is Stephanie and she is 11 .\n\r\n2. Madison is not 9 years old.\n\r\n3. The person whose favorite show is Full House is not 10.\n\r\n4. The person whose favorite show is Hannah Montana is Madison.\n\r\n5. The girl whose favorite show is iCarly is not Emma.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nEmma-Full House-11\r\nMadison-Hannah Montana-10\r\nBrooke-iCarly-9\n<|im_start|>answer\nEmma-Full House-11\r\nMadison-Hannah Montana-10\r\nBrooke-iCarly-9\n<|im_end|>" }, { "id": "#21004", "title": "Who's on First?", "fun": 1.85, "difficulty": 0.6900000000000001, "author": "DennysGirl", "desc": "Bases are loaded. Based on the clues below, can you figure out each person's last name, and their position?\n\r\nnames: Alice, Emily, David\r\nlast names: Price, Smith, Smart\r\nplaces: catcher, pitcher, left field\n\r\n1)Alice Smart is the farthest away from home base.\r\n2)Price is the pitcher.\r\n3)Emily's arm is tired from being overused.", "hint": "No hint available.", "answer": "Alice Smart-left field\r\nDavid Smith-catcher\r\nEmily Price-pitcher", "category": "Logic-Grid", "date": "02/13/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nBases are loaded. Based on the clues below, can you figure out each person's last name, and their position?\n\r\nnames: Alice, Emily, David\r\nlast names: Price, Smith, Smart\r\nplaces: catcher, pitcher, left field\n\r\n1)Alice Smart is the farthest away from home base.\r\n2)Price is the pitcher.\r\n3)Emily's arm is tired from being overused.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nAlice Smart-left field\r\nDavid Smith-catcher\r\nEmily Price-pitcher\n<|im_start|>answer\nAlice Smart-left field\r\nDavid Smith-catcher\r\nEmily Price-pitcher\n<|im_end|>" }, { "id": "#20276", "title": "Formula", "fun": 1.84, "difficulty": 3.36, "author": "DakarMorad", "desc": "If you use a certain formula on 13, you end up with 7.\n\r\nUnder the same formula, 2352 becomes 16, 246 becomes 14, 700 turns into 16, and 1030 becomes 14.\n\r\nWhat would 9304 become?", "hint": "No hint available.", "answer": "19. Convert the number to binary, add one for every zero, and add two for every 1.\n\r\n9304 becomes 10010001011000, which has 9 zeros and 5 ones.", "category": "Math", "date": "01/08/05", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIf you use a certain formula on 13, you end up with 7.\n\r\nUnder the same formula, 2352 becomes 16, 246 becomes 14, 700 turns into 16, and 1030 becomes 14.\n\r\nWhat would 9304 become?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n19. Convert the number to binary, add one for every zero, and add two for every 1.\n\r\n9304 becomes 10010001011000, which has 9 zeros and 5 ones.\n<|im_start|>answer\n19. Convert the number to binary, add one for every zero, and add two for every 1.\n\r\n9304 becomes 10010001011000, which has 9 zeros and 5 ones.\n<|im_end|>" }, { "id": "#48738", "title": "Symbolism IV", "fun": 1.84, "difficulty": 2.53, "author": "Mathgeek007", "desc": "I give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nAlso, do not follow the order of operations, perform in the order of the numbers (i.e.: 3+3*3 normally equals 12, but not following the order of operations, equals 18.)\n\r\nNow, here's your puzzle.\n\r\n12764237100100100\n\r\n++--//=\n\r\nNOTE: Equal zeroes do not count (0=0) in these puzzles.", "hint": "Each side adds up to 100.", "answer": "1276/4+2/3-7=100-100+100", "category": "Math", "date": "06/15/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nAlso, do not follow the order of operations, perform in the order of the numbers (i.e.: 3+3*3 normally equals 12, but not following the order of operations, equals 18.)\n\r\nNow, here's your puzzle.\n\r\n12764237100100100\n\r\n++--//=\n\r\nNOTE: Equal zeroes do not count (0=0) in these puzzles.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n1276/4+2/3-7=100-100+100\n<|im_start|>answer\n1276/4+2/3-7=100-100+100\n<|im_end|>" }, { "id": "#50837", "title": "Dreams of Architecture Students", "fun": 1.84, "difficulty": 2.19, "author": "bloody-albatros", "desc": "Jack and Joe are architecture students. For their masterpiece they plan to build an exceptional monument on the plaza of their university.\n\r\nThat plaza has a diameter of 100 meters and has the shape of a perfect circle.\n\r\n\"Lets build an ark that everyone can see from near or far\" suggests Jack. \n\r\nJoe replies, \"Nah, that is too common, besides it would be much nicer to combine the roundness with squareness!\" \n\r\nJack: \"I am not even sure if these words really exist, but what do you have in mind, Joe?\"\n\r\nJoe: \"I see a giant rectangular triangle. The poles on the circumference of the plaza; And in the upper angle - the right angle - we install a flood light to enlighten the whole plaza!\"\n\r\nJack: \"Fantastic! Because of the upcoming anniversary, we build that triangle 75 meters in height!\"\n\r\n\"Do not be ridiculous! That is not possible!\" Joe cried out.\n\r\nIs Joe right? Is it possible or not?", "hint": "Thales' theorem", "answer": "The maximum height of the rectangular triangle (with the right angle in the air) is defined by the hypotenuse. \n\r\nThe largest hypotenuse in the plaza would fit in the exact diameter, namely 100m. \n\r\nThe maximum height is exact the half of the hypotenuse.\n\r\nSo it can only have 50 meters in height.\n\r\nJoe is right, the rectangular triangle with 75m height is not possible.", "category": "Math", "date": "08/08/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack and Joe are architecture students. For their masterpiece they plan to build an exceptional monument on the plaza of their university.\n\r\nThat plaza has a diameter of 100 meters and has the shape of a perfect circle.\n\r\n\"Lets build an ark that everyone can see from near or far\" suggests Jack. \n\r\nJoe replies, \"Nah, that is too common, besides it would be much nicer to combine the roundness with squareness!\" \n\r\nJack: \"I am not even sure if these words really exist, but what do you have in mind, Joe?\"\n\r\nJoe: \"I see a giant rectangular triangle. The poles on the circumference of the plaza; And in the upper angle - the right angle - we install a flood light to enlighten the whole plaza!\"\n\r\nJack: \"Fantastic! Because of the upcoming anniversary, we build that triangle 75 meters in height!\"\n\r\n\"Do not be ridiculous! That is not possible!\" Joe cried out.\n\r\nIs Joe right? Is it possible or not?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe maximum height of the rectangular triangle (with the right angle in the air) is defined by the hypotenuse. \n\r\nThe largest hypotenuse in the plaza would fit in the exact diameter, namely 100m. \n\r\nThe maximum height is exact the half of the hypotenuse.\n\r\nSo it can only have 50 meters in height.\n\r\nJoe is right, the rectangular triangle with 75m height is not possible.\n<|im_start|>answer\nThe maximum height of the rectangular triangle (with the right angle in the air) is defined by the hypotenuse. \n\r\nThe largest hypotenuse in the plaza would fit in the exact diameter, namely 100m. \n\r\nThe maximum height is exact the half of the hypotenuse.\n\r\nSo it can only have 50 meters in height.\n\r\nJoe is right, the rectangular triangle with 75m height is not possible.\n<|im_end|>" }, { "id": "#48468", "title": "Lazy Jack", "fun": 1.84, "difficulty": 0.58, "author": "MysteriousLight", "desc": "I have a friend whose name is Jack. He is really lazy. His science homework is to bring in one pound of something. He said that he's too lazy to find something that weighs a pound and something to hold it. He asked me to get those two things for him. I have 3 options: a thick wooden box that is holding a pound of bricks, a one-pounder shoulder bag, and a stack of a pound of books wrapped in one layer of thin wrapping paper. I want to give Jack the heaviest of my three objects. Which one should I choose?", "hint": "This is not a trick question: there is an answer.", "answer": "I should choose the box of a pound of bricks-- a thick wooden box weighs more than thin wrapping paper. Every object (other than the box and paper) weighs a pound. The box full of a pound of bricks weighs most.", "category": "Logic", "date": "02/10/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI have a friend whose name is Jack. He is really lazy. His science homework is to bring in one pound of something. He said that he's too lazy to find something that weighs a pound and something to hold it. He asked me to get those two things for him. I have 3 options: a thick wooden box that is holding a pound of bricks, a one-pounder shoulder bag, and a stack of a pound of books wrapped in one layer of thin wrapping paper. I want to give Jack the heaviest of my three objects. Which one should I choose?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nI should choose the box of a pound of bricks-- a thick wooden box weighs more than thin wrapping paper. Every object (other than the box and paper) weighs a pound. The box full of a pound of bricks weighs most.\n<|im_start|>answer\nI should choose the box of a pound of bricks-- a thick wooden box weighs more than thin wrapping paper. Every object (other than the box and paper) weighs a pound. The box full of a pound of bricks weighs most.\n<|im_end|>" }, { "id": "#44843", "title": "Star Students", "fun": 1.83, "difficulty": 0.8, "author": "allybee", "desc": "In a magazine article, three popular TV personalities talk about their time in college, studying for careers that they never pursued after getting into television. Can you piece together the full name, TV job, and area studied of each woman?\n\r\n1. It wasn't Donna who was trained as a teacher.\n\r\n2. Ms. Knight was an actress in the film \"Magic\".\n\r\n3. Laura is a news anchor.\n\r\n4. Susan Niven never had any ambition to be a nurse.\n\r\n5. It isn't the one-time student teacher who now presents current affairs programs.", "hint": "No hint available.", "answer": "Donna Knight: actress, nurse\r\nLaura Robins: news anchor, teacher\r\nSusan Niven: presenter, lawyer", "category": "Logic-Grid", "date": "07/12/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nIn a magazine article, three popular TV personalities talk about their time in college, studying for careers that they never pursued after getting into television. Can you piece together the full name, TV job, and area studied of each woman?\n\r\n1. It wasn't Donna who was trained as a teacher.\n\r\n2. Ms. Knight was an actress in the film \"Magic\".\n\r\n3. Laura is a news anchor.\n\r\n4. Susan Niven never had any ambition to be a nurse.\n\r\n5. It isn't the one-time student teacher who now presents current affairs programs.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nDonna Knight: actress, nurse\r\nLaura Robins: news anchor, teacher\r\nSusan Niven: presenter, lawyer\n<|im_start|>answer\nDonna Knight: actress, nurse\r\nLaura Robins: news anchor, teacher\r\nSusan Niven: presenter, lawyer\n<|im_end|>" }, { "id": "#44449", "title": "Remember to Cross the T's and Dot the I's", "fun": 1.83, "difficulty": 2.49, "author": "da1bearsfan", "desc": "LTVX\r\nAFHKNZ\r\n_ _ _\n\r\nWhat three letters fill in the blanks?", "hint": "- The title has a partial clue.\r\n- Look down.\r\n- They are grouped horizontally.", "answer": "E M W\n\r\nThe first row requires two straight lines to make. (LTVX)\n\r\nThe Second row requires three straight lines to make. (AFHKNZ)\n\r\nFollowing the pattern, the next row should have four straight lines to make, and the only letters that do that are EMW. \n\r\n(Also everything has been so far in alphabetical order so it has to be \"EMW\", not EWM, MEW, MWE, WME, or WEM.)", "category": "Logic", "date": "05/13/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nLTVX\r\nAFHKNZ\r\n_ _ _\n\r\nWhat three letters fill in the blanks?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nE M W\n\r\nThe first row requires two straight lines to make. (LTVX)\n\r\nThe Second row requires three straight lines to make. (AFHKNZ)\n\r\nFollowing the pattern, the next row should have four straight lines to make, and the only letters that do that are EMW. \n\r\n(Also everything has been so far in alphabetical order so it has to be \"EMW\", not EWM, MEW, MWE, WME, or WEM.)\n<|im_start|>answer\nE M W\n\r\nThe first row requires two straight lines to make. (LTVX)\n\r\nThe Second row requires three straight lines to make. (AFHKNZ)\n\r\nFollowing the pattern, the next row should have four straight lines to make, and the only letters that do that are EMW. \n\r\n(Also everything has been so far in alphabetical order so it has to be \"EMW\", not EWM, MEW, MWE, WME, or WEM.)\n<|im_end|>" }, { "id": "#2400", "title": "Halfsies", "fun": 1.83, "difficulty": 1.34, "author": "Mad-ade", "desc": "What is a half times a half?", "hint": "Try it on a calculator.", "answer": "A quarter.", "category": "Math", "date": "02/23/02", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nWhat is a half times a half?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nA quarter.\n<|im_start|>answer\nA quarter.\n<|im_end|>" }, { "id": "#44486", "title": "Mix-up at School", "fun": 1.82, "difficulty": 2.03, "author": "whsprec", "desc": "At school, there were six substitutes one day. Unfortunately, the list containing the teachers' names, the subject they teach, and who the substitutes are was mixed up. Each item is in the correct column, but only 1 entry in each column is in the correct order. Using the clues below, can you the match the teacher to the subject and find out who the substitute is?\n\r\nTeacher\tSubject\tSubstitute\r\nCambell\tMath\tGreen\r\nReese\tEnglish\tJohnson\r\nHolloman\tArt\tCutler\r\nDixon \tP.E.\tMoss\r\nMeeks\tSpanish\tDail\t\r\nHall\tFoods\tDills\n\r\n1) Art is 2 places below Moss, but only 1 below Meeks.\r\n2) Cutler is 2 places above Foods, but only 1 below Holloman.\r\n3) Dail is somewhere below P.E., which is somewhere below Reese.\r\n4) Hall is 2 places below English, which is 1 place above Green.\r\n5) Cambell is somewhere below Art which is somewhere above Dills.", "hint": "No hint available.", "answer": "Teacher\tSubject\tSubstitute\r\nReese\tMath\tJohnson\r\nHolloman\tP.E.\tMoss\r\nMeeks\tEnglish\tCutler\r\nDixon\tArt\tGreen\r\nHall \tFoods\tDills\r\nCambell\tSpanish\tDail", "category": "Logic", "date": "05/19/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nAt school, there were six substitutes one day. Unfortunately, the list containing the teachers' names, the subject they teach, and who the substitutes are was mixed up. Each item is in the correct column, but only 1 entry in each column is in the correct order. Using the clues below, can you the match the teacher to the subject and find out who the substitute is?\n\r\nTeacher\tSubject\tSubstitute\r\nCambell\tMath\tGreen\r\nReese\tEnglish\tJohnson\r\nHolloman\tArt\tCutler\r\nDixon \tP.E.\tMoss\r\nMeeks\tSpanish\tDail\t\r\nHall\tFoods\tDills\n\r\n1) Art is 2 places below Moss, but only 1 below Meeks.\r\n2) Cutler is 2 places above Foods, but only 1 below Holloman.\r\n3) Dail is somewhere below P.E., which is somewhere below Reese.\r\n4) Hall is 2 places below English, which is 1 place above Green.\r\n5) Cambell is somewhere below Art which is somewhere above Dills.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nTeacher\tSubject\tSubstitute\r\nReese\tMath\tJohnson\r\nHolloman\tP.E.\tMoss\r\nMeeks\tEnglish\tCutler\r\nDixon\tArt\tGreen\r\nHall \tFoods\tDills\r\nCambell\tSpanish\tDail\n<|im_start|>answer\nTeacher\tSubject\tSubstitute\r\nReese\tMath\tJohnson\r\nHolloman\tP.E.\tMoss\r\nMeeks\tEnglish\tCutler\r\nDixon\tArt\tGreen\r\nHall \tFoods\tDills\r\nCambell\tSpanish\tDail\n<|im_end|>" }, { "id": "#47753", "title": "Land Problem", "fun": 1.82, "difficulty": 2.38, "author": "quizwizAhn", "desc": "A, B, and C each had land: am^2 (m^2=square meters), bm^2, and cm^2 (this is c square meter, not square centimeter!) big. A sold 1/4 of his land to B, then B sold 1/3 of the land he had (after he bought land from A) to C. If A, B, and C now have the same amount of land, what does (b+c)/a equal to?", "hint": "I advise that you use a letter (ex: k) to compare the three measures.\r\n(and just in case, 1/3 is read as one-third, and so on.)", "answer": "5/4\n\r\n(multiplication symbols are not written down)\r\nSteps: (3/4)a=2/3((1/4)a+b)=1/3((1/4)a+b)+c\n\r\n3a/4=(a+4b)/6=(a+4b+12c)/12=k\n\r\na=(4/3)k, b=(7/6)k, c=(1/2)k\n\r\n(b+c)/a = (7k/6 + 1k/2)/(4k/3) = (10k/6)(3/4k) = 5/4", "category": "Math", "date": "08/14/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA, B, and C each had land: am^2 (m^2=square meters), bm^2, and cm^2 (this is c square meter, not square centimeter!) big. A sold 1/4 of his land to B, then B sold 1/3 of the land he had (after he bought land from A) to C. If A, B, and C now have the same amount of land, what does (b+c)/a equal to?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n5/4\n\r\n(multiplication symbols are not written down)\r\nSteps: (3/4)a=2/3((1/4)a+b)=1/3((1/4)a+b)+c\n\r\n3a/4=(a+4b)/6=(a+4b+12c)/12=k\n\r\na=(4/3)k, b=(7/6)k, c=(1/2)k\n\r\n(b+c)/a = (7k/6 + 1k/2)/(4k/3) = (10k/6)(3/4k) = 5/4\n<|im_start|>answer\n5/4\n\r\n(multiplication symbols are not written down)\r\nSteps: (3/4)a=2/3((1/4)a+b)=1/3((1/4)a+b)+c\n\r\n3a/4=(a+4b)/6=(a+4b+12c)/12=k\n\r\na=(4/3)k, b=(7/6)k, c=(1/2)k\n\r\n(b+c)/a = (7k/6 + 1k/2)/(4k/3) = (10k/6)(3/4k) = 5/4\n<|im_end|>" }, { "id": "#48676", "title": "\"Family Guy\" Clue", "fun": 1.82, "difficulty": 0.24, "author": "Ginge", "desc": "There have been murders in the Griffin household. Conclude who was killed by whom and how. \n\r\nKillers: Peter, Stewie, Chris\n\r\nVictims: Lois, Meg, Brian\n\r\nWeapons: Gun, Knife, Rope\n\r\nWhat you know:\r\n1) Peter killed Meg.\r\n2) Stewie shot someone to death.\r\n3) Chris did not kill Brian or strangle anyone to death.", "hint": "No hint available.", "answer": "Peter strangled Meg with the rope.\r\nStewie shot Brian with the gun.\r\nChris stabbed Lois with the knife.", "category": "Logic-Grid", "date": "04/28/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere have been murders in the Griffin household. Conclude who was killed by whom and how. \n\r\nKillers: Peter, Stewie, Chris\n\r\nVictims: Lois, Meg, Brian\n\r\nWeapons: Gun, Knife, Rope\n\r\nWhat you know:\r\n1) Peter killed Meg.\r\n2) Stewie shot someone to death.\r\n3) Chris did not kill Brian or strangle anyone to death.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nPeter strangled Meg with the rope.\r\nStewie shot Brian with the gun.\r\nChris stabbed Lois with the knife.\n<|im_start|>answer\nPeter strangled Meg with the rope.\r\nStewie shot Brian with the gun.\r\nChris stabbed Lois with the knife.\n<|im_end|>" }, { "id": "#47769", "title": "Ms. Zany's Lectures", "fun": 1.82, "difficulty": 2.36, "author": "stil", "desc": "Students-\r\nI am pleased that my little study hall presentations have been so well received. Though few of you have actually seen one, the number of requests for future participation has been overwhelming. (My pleasure would have been greater if my teaching name, Miss Hoehne, had not morphed into \"Ms. Zany.\") \r\nI want to thank the interns who made it possible for me to escape some of my administrative duties. Without their help, I would not have had the time to proctor an occasional study hall. With their approaching departure, the presentations will come to an end or, at least, an indefinite hiatus. \r\nNext week will be your last chance for a while to witness any of these presentations. All five of the current crop will be recreated and consolidated for recording in Fink College's video studio. (One fifth of a mile from our campus.) It is already clear the studio's size will not accommodate everyone interested and eligible, so the following questions have been made part of the elimination process. (The formal application provides spaces for the answers.)\n\r\nTwelve items are to be divided into groups of three or four items. The items in the group will be listed, e.g. 1, blue, bench, A. You will guess a target arrangement, e.g. bench, A, 1, blue. You will score one point for each match, e.g. If the target established beforehand is \"bench, A, blue, 1,\" your guess would score two points. To maximize your score, do you choose to guess about three groups of four items or about four groups of three items? \n\r\nThe described test would use our school's computer network, so it will be possible to tell when exactly 250 tests have been completed. Of the first 250 pupils completing these tests, how many will have scored exactly eleven points?", "hint": "Declaring what has been implied: blanks and repetition are prevented by use of the school's computer system.", "answer": "Probability makes four groups of three the higher scorer.\n\r\nThere are 6 ways to arrange 3 items.\r\nOnly 1 guess in 6 scores all 3 points contributing 1/2 point to the average. \r\n3 guesses in 6 score 1 point contributing 1/2 point to the average.\r\nThe remaining 2 of the 6 guesses contribute nothing to the average.\r\nEach grouping averages 1 point, so 4 groupings will net on average 4 points.\n\r\nThere are 24 ways to arrange 4 items.\r\nOnly 1 guess in 24 scores all 4 points contributing 1/6 point to the average. \r\n6 guesses in 24 score 2 points contributing 1/2 point to the average.\r\n8 guesses in 24 score 1 point contributing 1/3 point to the average.\r\nThe remaining 9 of the 24 guesses contribute nothing to the average.\r\nAgain each grouping averages 1 point, so 3 groupings will on average net only 3 points.\n\r\nRegardless of which test or mix of tests is taken, the answer is zero. There is no way to get exactly 11 correct, because there is no way to get just 1 wrong.", "category": "Math", "date": "08/31/10", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nStudents-\r\nI am pleased that my little study hall presentations have been so well received. Though few of you have actually seen one, the number of requests for future participation has been overwhelming. (My pleasure would have been greater if my teaching name, Miss Hoehne, had not morphed into \"Ms. Zany.\") \r\nI want to thank the interns who made it possible for me to escape some of my administrative duties. Without their help, I would not have had the time to proctor an occasional study hall. With their approaching departure, the presentations will come to an end or, at least, an indefinite hiatus. \r\nNext week will be your last chance for a while to witness any of these presentations. All five of the current crop will be recreated and consolidated for recording in Fink College's video studio. (One fifth of a mile from our campus.) It is already clear the studio's size will not accommodate everyone interested and eligible, so the following questions have been made part of the elimination process. (The formal application provides spaces for the answers.)\n\r\nTwelve items are to be divided into groups of three or four items. The items in the group will be listed, e.g. 1, blue, bench, A. You will guess a target arrangement, e.g. bench, A, 1, blue. You will score one point for each match, e.g. If the target established beforehand is \"bench, A, blue, 1,\" your guess would score two points. To maximize your score, do you choose to guess about three groups of four items or about four groups of three items? \n\r\nThe described test would use our school's computer network, so it will be possible to tell when exactly 250 tests have been completed. Of the first 250 pupils completing these tests, how many will have scored exactly eleven points?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nProbability makes four groups of three the higher scorer.\n\r\nThere are 6 ways to arrange 3 items.\r\nOnly 1 guess in 6 scores all 3 points contributing 1/2 point to the average. \r\n3 guesses in 6 score 1 point contributing 1/2 point to the average.\r\nThe remaining 2 of the 6 guesses contribute nothing to the average.\r\nEach grouping averages 1 point, so 4 groupings will net on average 4 points.\n\r\nThere are 24 ways to arrange 4 items.\r\nOnly 1 guess in 24 scores all 4 points contributing 1/6 point to the average. \r\n6 guesses in 24 score 2 points contributing 1/2 point to the average.\r\n8 guesses in 24 score 1 point contributing 1/3 point to the average.\r\nThe remaining 9 of the 24 guesses contribute nothing to the average.\r\nAgain each grouping averages 1 point, so 3 groupings will on average net only 3 points.\n\r\nRegardless of which test or mix of tests is taken, the answer is zero. There is no way to get exactly 11 correct, because there is no way to get just 1 wrong.\n<|im_start|>answer\nProbability makes four groups of three the higher scorer.\n\r\nThere are 6 ways to arrange 3 items.\r\nOnly 1 guess in 6 scores all 3 points contributing 1/2 point to the average. \r\n3 guesses in 6 score 1 point contributing 1/2 point to the average.\r\nThe remaining 2 of the 6 guesses contribute nothing to the average.\r\nEach grouping averages 1 point, so 4 groupings will net on average 4 points.\n\r\nThere are 24 ways to arrange 4 items.\r\nOnly 1 guess in 24 scores all 4 points contributing 1/6 point to the average. \r\n6 guesses in 24 score 2 points contributing 1/2 point to the average.\r\n8 guesses in 24 score 1 point contributing 1/3 point to the average.\r\nThe remaining 9 of the 24 guesses contribute nothing to the average.\r\nAgain each grouping averages 1 point, so 3 groupings will on average net only 3 points.\n\r\nRegardless of which test or mix of tests is taken, the answer is zero. There is no way to get exactly 11 correct, because there is no way to get just 1 wrong.\n<|im_end|>" }, { "id": "#44337", "title": "Computer Mix-up", "fun": 1.81, "difficulty": 0.32, "author": "Shnazzle", "desc": "Katie, Peter and Thomas were fighting for which computer they would get in the house. Use these clues to find out who got a computer in which room and what game they were playing.\n\r\n1. The computer in the study was being used by someone playing minesweeper.\n\r\n2. Tetris was being played by Peter.\n\r\n3. The dining room was not being used by Peter or Thomas.\n\r\n4. Thomas was not in the lounge room but was playing minesweeper.\n\r\n5. Katie wasn't playing tetris.\n\r\n6. Peter was in the lounge room.", "hint": "You can do this teaser without the grid-solver but it will be much easier.", "answer": "Here are the answers - \n\r\nComputer 1. \r\n- lounge room\r\n- Peter\r\n- tetris\n\r\nComputer 2.\r\n- study\r\n- Thomas\r\n- minesweeper\n\r\nComputer 3. \r\n- dining room \r\n- Katie\r\n- pinball", "category": "Logic-Grid", "date": "04/10/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nKatie, Peter and Thomas were fighting for which computer they would get in the house. Use these clues to find out who got a computer in which room and what game they were playing.\n\r\n1. The computer in the study was being used by someone playing minesweeper.\n\r\n2. Tetris was being played by Peter.\n\r\n3. The dining room was not being used by Peter or Thomas.\n\r\n4. Thomas was not in the lounge room but was playing minesweeper.\n\r\n5. Katie wasn't playing tetris.\n\r\n6. Peter was in the lounge room.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nHere are the answers - \n\r\nComputer 1. \r\n- lounge room\r\n- Peter\r\n- tetris\n\r\nComputer 2.\r\n- study\r\n- Thomas\r\n- minesweeper\n\r\nComputer 3. \r\n- dining room \r\n- Katie\r\n- pinball\n<|im_start|>answer\nHere are the answers - \n\r\nComputer 1. \r\n- lounge room\r\n- Peter\r\n- tetris\n\r\nComputer 2.\r\n- study\r\n- Thomas\r\n- minesweeper\n\r\nComputer 3. \r\n- dining room \r\n- Katie\r\n- pinball\n<|im_end|>" }, { "id": "#48390", "title": "Teachers", "fun": 1.81, "difficulty": 0.43, "author": "Magyk555", "desc": "There are three teachers. Their names are Mr. Jones, Mr. Smith, and Mr. Johns. Each teacher has a favorite student. The students' names are Nathan, Bob, and Jim. Each teacher is a certain age. The ages are 30, 35, and 40. Your job is to find out how old each teacher is, and find out who their favorite student is.\n\r\nClue 1: The oldest teacher likes Bob the most.\r\nClue 2: Mr. Jones is not the oldest or the youngest teacher.\r\nClue 3: Mr. Jones does not like Nathan.\r\nClue 4: Mr. Smith is not the oldest teacher.", "hint": "No hint available.", "answer": "Mr. Jones likes Jim the best and is 35.\r\nMr. Johns likes Bob the best and is 40.\r\nMr. Smith likes Nathan the best and is 30.", "category": "Logic-Grid", "date": "01/15/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three teachers. Their names are Mr. Jones, Mr. Smith, and Mr. Johns. Each teacher has a favorite student. The students' names are Nathan, Bob, and Jim. Each teacher is a certain age. The ages are 30, 35, and 40. Your job is to find out how old each teacher is, and find out who their favorite student is.\n\r\nClue 1: The oldest teacher likes Bob the most.\r\nClue 2: Mr. Jones is not the oldest or the youngest teacher.\r\nClue 3: Mr. Jones does not like Nathan.\r\nClue 4: Mr. Smith is not the oldest teacher.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMr. Jones likes Jim the best and is 35.\r\nMr. Johns likes Bob the best and is 40.\r\nMr. Smith likes Nathan the best and is 30.\n<|im_start|>answer\nMr. Jones likes Jim the best and is 35.\r\nMr. Johns likes Bob the best and is 40.\r\nMr. Smith likes Nathan the best and is 30.\n<|im_end|>" }, { "id": "#40366", "title": "Ordered Triple", "fun": 1.8, "difficulty": 2.63, "author": "shenqiang", "desc": "Find the number of ordered triples (A, B, C) where A, B and C are positive integers, A is a factor of B, A is a factor of C, and A+B+C=30.", "hint": "If A is a factor of both B and C, A must be a factor of the three numbers' sum 30.", "answer": "If A=1, then the possibilities are B=1, C=28; ..., B=28, C=1, 28 possibilities;\r\nIf A=2, then the possibilities are B=2, C=26; ..., B=26, C=2, 13 possibilities, 41 accumulated;\r\nIf A=3, then the possibilities are B=3, C=24; ..., B=24, C=3, 8 possibilities, 49 accumulated;\r\nIf A=5, then the possibilities are B=5, C=20; ..., B=20, C=5, 4 possibilities, 53 accumulated;\r\nIf A=6, then the possibilities are B=6, C=18; ..., B=18, C=6, 3 possibilities, 56 accumulated;\r\nIf A=10, then the only possibility is B=10, C=10, 57 possibilities accumulated.", "category": "Math", "date": "02/07/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the number of ordered triples (A, B, C) where A, B and C are positive integers, A is a factor of B, A is a factor of C, and A+B+C=30.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nIf A=1, then the possibilities are B=1, C=28; ..., B=28, C=1, 28 possibilities;\r\nIf A=2, then the possibilities are B=2, C=26; ..., B=26, C=2, 13 possibilities, 41 accumulated;\r\nIf A=3, then the possibilities are B=3, C=24; ..., B=24, C=3, 8 possibilities, 49 accumulated;\r\nIf A=5, then the possibilities are B=5, C=20; ..., B=20, C=5, 4 possibilities, 53 accumulated;\r\nIf A=6, then the possibilities are B=6, C=18; ..., B=18, C=6, 3 possibilities, 56 accumulated;\r\nIf A=10, then the only possibility is B=10, C=10, 57 possibilities accumulated.\n<|im_start|>answer\nIf A=1, then the possibilities are B=1, C=28; ..., B=28, C=1, 28 possibilities;\r\nIf A=2, then the possibilities are B=2, C=26; ..., B=26, C=2, 13 possibilities, 41 accumulated;\r\nIf A=3, then the possibilities are B=3, C=24; ..., B=24, C=3, 8 possibilities, 49 accumulated;\r\nIf A=5, then the possibilities are B=5, C=20; ..., B=20, C=5, 4 possibilities, 53 accumulated;\r\nIf A=6, then the possibilities are B=6, C=18; ..., B=18, C=6, 3 possibilities, 56 accumulated;\r\nIf A=10, then the only possibility is B=10, C=10, 57 possibilities accumulated.\n<|im_end|>" }, { "id": "#48694", "title": "Symbolism III", "fun": 1.8, "difficulty": 2.31, "author": "Mathgeek007", "desc": "I give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nAlso, do not follow the order of operations, perform in the order of the numbers (ie: 3+3*3 normally equals 12, but not following the order of operations, equals 18.)\n\r\nNow, here's your puzzle.\n\r\n8733191520\r\n+--*=", "hint": "Each side equals 100.", "answer": "87+33-19-1=5*20", "category": "Math", "date": "05/09/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nI give you some numbers in a specific order, and a few symbols. Arrange those symbols however you can to make a correct math equation. You must use all of them.\n\r\nFor example...\n\r\n753452120\r\n+-=\r\nAnswer:\r\n7+534-521=20\n\r\nAlso, do not follow the order of operations, perform in the order of the numbers (ie: 3+3*3 normally equals 12, but not following the order of operations, equals 18.)\n\r\nNow, here's your puzzle.\n\r\n8733191520\r\n+--*=\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n87+33-19-1=5*20\n<|im_start|>answer\n87+33-19-1=5*20\n<|im_end|>" }, { "id": "#43035", "title": "Integers", "fun": 1.77, "difficulty": 0.9400000000000001, "author": "cacmjc", "desc": "Two integers have a difference of 6 and a sum of -18. What are the integers?", "hint": "No hint available.", "answer": "-6 and -12", "category": "Math", "date": "09/09/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nTwo integers have a difference of 6 and a sum of -18. What are the integers?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\n-6 and -12\n<|im_start|>answer\n-6 and -12\n<|im_end|>" }, { "id": "#44518", "title": "5 Weddings and a Mistake", "fun": 1.76, "difficulty": 1.91, "author": "whsprec", "desc": "A church is having 5 weddings in one day. However, due to a clerical error, the church has no idea which couple they are expecting and in what order they are scheduled to be wed. Each name is in the correct column, but only 1 of the names within each column actually appears in the correct row. Using the clues below, match the grooms, the brides, and the surnames, then place each couple in its proper order.\n\r\nGroom\tBride\tSurname\r\nPeter\tAmber\tKent\r\nPaul\tElonna\tDixen\r\nJames\tBrittany\tAdams\r\nMatthew\tWhitley\tMoss\r\nLuke\tChelsea\tSmith\n\r\n1) Luke is 1 place after Whitley.\r\n2) Chelsea is 1 place before the Mosses.\r\n3) James is not marrying Whitley nor is he a Moss.\r\n4) The Kents are 1 place before Brittany, who is 2 places after James.\r\n5) Peter is 2 places before the Smiths.", "hint": "No hint available.", "answer": "Groom\tBride\tSurname\r\nJames\tElonna\tDixen\r\nPeter\tWhitley\tKent\r\nLuke\tBrittany\tAdams\r\nMatthew\tChelsea\tSmith\r\nPaul\tAmber\tMoss", "category": "Logic", "date": "05/25/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nA church is having 5 weddings in one day. However, due to a clerical error, the church has no idea which couple they are expecting and in what order they are scheduled to be wed. Each name is in the correct column, but only 1 of the names within each column actually appears in the correct row. Using the clues below, match the grooms, the brides, and the surnames, then place each couple in its proper order.\n\r\nGroom\tBride\tSurname\r\nPeter\tAmber\tKent\r\nPaul\tElonna\tDixen\r\nJames\tBrittany\tAdams\r\nMatthew\tWhitley\tMoss\r\nLuke\tChelsea\tSmith\n\r\n1) Luke is 1 place after Whitley.\r\n2) Chelsea is 1 place before the Mosses.\r\n3) James is not marrying Whitley nor is he a Moss.\r\n4) The Kents are 1 place before Brittany, who is 2 places after James.\r\n5) Peter is 2 places before the Smiths.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nGroom\tBride\tSurname\r\nJames\tElonna\tDixen\r\nPeter\tWhitley\tKent\r\nLuke\tBrittany\tAdams\r\nMatthew\tChelsea\tSmith\r\nPaul\tAmber\tMoss\n<|im_start|>answer\nGroom\tBride\tSurname\r\nJames\tElonna\tDixen\r\nPeter\tWhitley\tKent\r\nLuke\tBrittany\tAdams\r\nMatthew\tChelsea\tSmith\r\nPaul\tAmber\tMoss\n<|im_end|>" }, { "id": "#41307", "title": "A Couple Of Couples", "fun": 1.73, "difficulty": 0.7000000000000001, "author": "pinkhakix3", "desc": "Three friends went out with their dates. They were all very nervous! The girls decided to keep in touch with each other during their dates. They all kept in touch in different ways. Can you figure out who their dates were and how they kept in touch?\n\r\nGirls: Mary Ann, Isabella, and Lorraine\n\r\nBoys: Ryan, Sean, and Jeremy\n\r\nWays to keep in touch: Texting, calling, and AIM (on a cell phone). Everyone can receive texts, calling, or instant message but may not be able to send them out.\n\r\n1. Ryan was on a date with a girl without an 'E' in her name.\n\r\n2. Isabella's parents took away her texting after a large bill the week before. \n\r\n3. Lorraine used AIM.\n\r\n4. Mary Ann's date got annoyed when her phone kept ringing. She didn't use calling.\n\r\n5. Sean's date used AIM.\n\r\n6. Jeremy's date used calling.", "hint": "2 names were taken from a Disney Channel show. They are a couple.", "answer": "Mary Ann- Ryan- texting\r\nIsabella- Jeremy- calling\r\nLorraine- Sean- AIM", "category": "Logic-Grid", "date": "04/01/08", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree friends went out with their dates. They were all very nervous! The girls decided to keep in touch with each other during their dates. They all kept in touch in different ways. Can you figure out who their dates were and how they kept in touch?\n\r\nGirls: Mary Ann, Isabella, and Lorraine\n\r\nBoys: Ryan, Sean, and Jeremy\n\r\nWays to keep in touch: Texting, calling, and AIM (on a cell phone). Everyone can receive texts, calling, or instant message but may not be able to send them out.\n\r\n1. Ryan was on a date with a girl without an 'E' in her name.\n\r\n2. Isabella's parents took away her texting after a large bill the week before. \n\r\n3. Lorraine used AIM.\n\r\n4. Mary Ann's date got annoyed when her phone kept ringing. She didn't use calling.\n\r\n5. Sean's date used AIM.\n\r\n6. Jeremy's date used calling.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nMary Ann- Ryan- texting\r\nIsabella- Jeremy- calling\r\nLorraine- Sean- AIM\n<|im_start|>answer\nMary Ann- Ryan- texting\r\nIsabella- Jeremy- calling\r\nLorraine- Sean- AIM\n<|im_end|>" }, { "id": "#50846", "title": "Pizza Pie", "fun": 1.73, "difficulty": 0.31, "author": "Ares72", "desc": "Jack ate 1/8 of his pizza and Jill ate 1/8 of her pizza. How is it possible that Jill ate 3 times as much pizza?", "hint": "No hint available.", "answer": "Jill's pizza was 3 times as big as Jack's pizza.", "category": "Logic", "date": "06/07/16", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nJack ate 1/8 of his pizza and Jill ate 1/8 of her pizza. How is it possible that Jill ate 3 times as much pizza?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJill's pizza was 3 times as big as Jack's pizza.\n<|im_start|>answer\nJill's pizza was 3 times as big as Jack's pizza.\n<|im_end|>" }, { "id": "#48475", "title": "Three Young Women", "fun": 1.7, "difficulty": 0.43, "author": "cookies466", "desc": "There are three young newly married women, and each has a daughter. Determine whose daughter is whose, and how old each child is. \r\nWomen: Sara, Katherine, and Mallory\r\nDaughters: Abby, Jessica, and Eliana\r\nAges: 4, 5, and 6\n\r\nClues: \r\n1. Sara and her daughter have lunch once a week with Katherine and her daughter Eliana (who is 5). \r\n2. Jessica's mother doesn't like talking to Sara and her husband.\r\n3. Sara's daughter is 6.", "hint": "No hint available.", "answer": "Sara's daughter is Abby, and she is 6.\r\nKatherine's daughter is Eliana, and she is 5.\r\nMallory's daughter is Jessica, and she is 4.", "category": "Logic-Grid", "date": "02/13/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are three young newly married women, and each has a daughter. Determine whose daughter is whose, and how old each child is. \r\nWomen: Sara, Katherine, and Mallory\r\nDaughters: Abby, Jessica, and Eliana\r\nAges: 4, 5, and 6\n\r\nClues: \r\n1. Sara and her daughter have lunch once a week with Katherine and her daughter Eliana (who is 5). \r\n2. Jessica's mother doesn't like talking to Sara and her husband.\r\n3. Sara's daughter is 6.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nSara's daughter is Abby, and she is 6.\r\nKatherine's daughter is Eliana, and she is 5.\r\nMallory's daughter is Jessica, and she is 4.\n<|im_start|>answer\nSara's daughter is Abby, and she is 6.\r\nKatherine's daughter is Eliana, and she is 5.\r\nMallory's daughter is Jessica, and she is 4.\n<|im_end|>" }, { "id": "#10221", "title": "Neighbors", "fun": 1.7, "difficulty": 0.85, "author": "cutie", "desc": "There are two people, Meg and Kat. Meg lives in Florida, Kat lives in Georgia. They're next-door neighbors. \n\r\nHow is that possible?", "hint": "No hint available.", "answer": "The border line of Florida and Georgia is in between them.", "category": "Logic", "date": "02/03/03", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere are two people, Meg and Kat. Meg lives in Florida, Kat lives in Georgia. They're next-door neighbors. \n\r\nHow is that possible?\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nThe border line of Florida and Georgia is in between them.\n<|im_start|>answer\nThe border line of Florida and Georgia is in between them.\n<|im_end|>" }, { "id": "#142", "title": "Circles in a triangle", "fun": 1.68, "difficulty": 3.17, "author": "offsky", "desc": "Find the radius of the inscribed and circumscribed circles for a triangle.", "hint": "No hint available.", "answer": "Let a, b, and c be the sides of the triangle. Let s be the semiperimeter, i.e. s = (a + b + c) / 2. Let A be the area of the triangle, and let x be the radius of the incircle. \n\r\nDivide the triangle into three smaller triangles by drawing a line segment from each vertex to the incenter. The areas of the smaller triangles are ax/2, bx/2, and cx/2. Thus, A = ax/2 + bx/2 + cx/2, or A = sx. \n\r\nWe use Heron`s formula, which is A = sqrt(s(s-a)(s-b)(s-c)). This gives us x = sqrt((s-a)(s-b)(s-c)/s). \n\r\nThe radius of the circumscribed circle is given by R = abc/4A.", "category": "Math", "date": "01/12/01", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nFind the radius of the inscribed and circumscribed circles for a triangle.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nLet a, b, and c be the sides of the triangle. Let s be the semiperimeter, i.e. s = (a + b + c) / 2. Let A be the area of the triangle, and let x be the radius of the incircle. \n\r\nDivide the triangle into three smaller triangles by drawing a line segment from each vertex to the incenter. The areas of the smaller triangles are ax/2, bx/2, and cx/2. Thus, A = ax/2 + bx/2 + cx/2, or A = sx. \n\r\nWe use Heron`s formula, which is A = sqrt(s(s-a)(s-b)(s-c)). This gives us x = sqrt((s-a)(s-b)(s-c)/s). \n\r\nThe radius of the circumscribed circle is given by R = abc/4A.\n<|im_start|>answer\nLet a, b, and c be the sides of the triangle. Let s be the semiperimeter, i.e. s = (a + b + c) / 2. Let A be the area of the triangle, and let x be the radius of the incircle. \n\r\nDivide the triangle into three smaller triangles by drawing a line segment from each vertex to the incenter. The areas of the smaller triangles are ax/2, bx/2, and cx/2. Thus, A = ax/2 + bx/2 + cx/2, or A = sx. \n\r\nWe use Heron`s formula, which is A = sqrt(s(s-a)(s-b)(s-c)). This gives us x = sqrt((s-a)(s-b)(s-c)/s). \n\r\nThe radius of the circumscribed circle is given by R = abc/4A.\n<|im_end|>" }, { "id": "#48925", "title": "A Fishing Trip", "fun": 1.65, "difficulty": 0.6900000000000001, "author": "weatherandgaame", "desc": "There were three customers and each wanted a different item. Each of these customers wanted to go fishing at a different time of the day.\r\nCustomers: John, Brian, and Max\r\nTime of Day: 6:15am, 6:00 pm, and 8:00 pm\r\nItems: Fishing Pole, Worms, and Cut Shad\n\r\n1. John went fishing in the morning.\r\n2. One person who didn't go at 6 o'clock got the Cut Shad.\r\n3. Max likes to fish at night.\r\n4. The person who bought the worms went at 8 o'clock.\r\n5. Brian left everything but his tackle box at home.", "hint": "No hint available.", "answer": "John went at 6:15 am and bought Cut Shad.\r\nBrian went at 6:00 pm and bought a Fishing Pole.\r\nMax went at 8:00 pm and bought Worms.", "category": "Logic-Grid", "date": "08/10/11", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThere were three customers and each wanted a different item. Each of these customers wanted to go fishing at a different time of the day.\r\nCustomers: John, Brian, and Max\r\nTime of Day: 6:15am, 6:00 pm, and 8:00 pm\r\nItems: Fishing Pole, Worms, and Cut Shad\n\r\n1. John went fishing in the morning.\r\n2. One person who didn't go at 6 o'clock got the Cut Shad.\r\n3. Max likes to fish at night.\r\n4. The person who bought the worms went at 8 o'clock.\r\n5. Brian left everything but his tackle box at home.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nJohn went at 6:15 am and bought Cut Shad.\r\nBrian went at 6:00 pm and bought a Fishing Pole.\r\nMax went at 8:00 pm and bought Worms.\n<|im_start|>answer\nJohn went at 6:15 am and bought Cut Shad.\r\nBrian went at 6:00 pm and bought a Fishing Pole.\r\nMax went at 8:00 pm and bought Worms.\n<|im_end|>" }, { "id": "#45084", "title": "Let There be Cake!", "fun": 1.6, "difficulty": 0.34, "author": "mir77", "desc": "Three kids ordered cakes, but the cooks mixed up the orders. Use these hints to find out what cake each student had:\n\r\n1: Bobby hates chocolate.\n\r\n2: Charlotte would not be caught DEAD with vanilla.\n\r\n3: Melonie ordered the fruit flavored cake.\n\r\n4: Bobby was having a birthday.\n\r\n5: Charlotte loved anything creamy.\n\r\n6: Melonie loves to have little candies on her cake.", "hint": "No hint available.", "answer": "Bobby had vanilla and candles.\n\r\nCharlotte had chocolate and frosting.\n\r\nMelonie had strawberry and sprinkles.", "category": "Logic-Grid", "date": "08/17/09", "text": "<|im_start|>system\nYou are Qwen, created by Alibaba Cloud. You are a helpful assistant.\n<|im_end|>\n<|im_start|>user\nThree kids ordered cakes, but the cooks mixed up the orders. Use these hints to find out what cake each student had:\n\r\n1: Bobby hates chocolate.\n\r\n2: Charlotte would not be caught DEAD with vanilla.\n\r\n3: Melonie ordered the fruit flavored cake.\n\r\n4: Bobby was having a birthday.\n\r\n5: Charlotte loved anything creamy.\n\r\n6: Melonie loves to have little candies on her cake.\n<|im_end|>\n<|im_start|>assistant\n<|im_start|>think\nBobby had vanilla and candles.\n\r\nCharlotte had chocolate and frosting.\n\r\nMelonie had strawberry and sprinkles.\n<|im_start|>answer\nBobby had vanilla and candles.\n\r\nCharlotte had chocolate and frosting.\n\r\nMelonie had strawberry and sprinkles.\n<|im_end|>" } ]