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humaneval.jsonl

@@ -129,3 +129,17 @@
 {"id": "humaneval_147", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n        For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    Example :\n        Input: n = 5\n        Output: 1\n        Explanation: \n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"\n", "rephrased_question": "def get_max_triples(n):\n    \"\"\"\n    Construct an array a of length n where a[i] = i*i - i + 1 (1-indexed). \n    Count the number of triples (i,j,k) with i<j<k such that a[i]+a[j]+a[k] is divisible by 3.\n    Example :\n        Input: n = 5\n        Output: 1\n        Explanation: \n        a = [1, 3, 7, 13, 21]\n        The only valid triple is (1, 7, 13).\n    \"\"\"", "answer": "    A = [i*i - i + 1 for i in range(1,n+1)]\n    ans = []\n    for i in range(n):\n        for j in range(i+1,n):\n            for k in range(j+1,n):\n                if (A[i]+A[j]+A[k])%3 == 0:\n                    ans += [(A[i],A[j],A[k])]\n    return len(ans)\n", "test": "def check(candidate):\n\n    assert candidate(5) == 1\n    assert candidate(6) == 4\n    assert candidate(10) == 36\n    assert candidate(100) == 53361\n", "entry_point": "get_max_triples"}
 {"id": "humaneval_148", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the closerst to the Sun \n    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n    Uranus, Neptune.\n    Write a function that takes two planet names as strings planet1 and planet2. \n    The function should return a tuple containing all planets whose orbits are \n    located between the orbit of planet1 and the orbit of planet2, sorted by \n    the proximity to the sun. \n    The function should return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n", "rephrased_question": "def bf(planet1, planet2):\n    '''\n    Given two planet names (among Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune),\n    return a tuple of all planets whose orbits lie strictly between the two given planets, \n    ordered by their distance from the Sun. If either name is invalid, return an empty tuple.\n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranus\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uranus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n    '''\n", "answer": "    planet_names = (\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\")\n    if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:\n        return ()\n    planet1_index = planet_names.index(planet1)\n    planet2_index = planet_names.index(planet2)\n    if planet1_index < planet2_index:\n        return (planet_names[planet1_index + 1: planet2_index])\n    else:\n        return (planet_names[planet2_index + 1 : planet1_index])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Jupiter\", \"Neptune\") == (\"Saturn\", \"Uranus\"), \"First test error: \" + str(len(candidate(\"Jupiter\", \"Neptune\")))      \n    assert candidate(\"Earth\", \"Mercury\") == (\"Venus\",), \"Second test error: \" + str(candidate(\"Earth\", \"Mercury\"))  \n    assert candidate(\"Mercury\", \"Uranus\") == (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"), \"Third test error: \" + str(candidate(\"Mercury\", \"Uranus\"))      \n    assert candidate(\"Neptune\", \"Venus\") == (\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\"), \"Fourth test error: \" + str(candidate(\"Neptune\", \"Venus\"))  \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"Earth\", \"Earth\") == ()\n    assert candidate(\"Mars\", \"Earth\") == ()\n    assert candidate(\"Jupiter\", \"Makemake\") == ()\n\n", "entry_point": "bf"}
 {"id": "humaneval_149", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef sorted_list_sum(lst):\n    \"\"\"Write a function that accepts a list of strings as a parameter,\n    deletes the strings that have odd lengths from it,\n    and returns the resulted list with a sorted order,\n    The list is always a list of strings and never an array of numbers,\n    and it may contain duplicates.\n    The order of the list should be ascending by length of each word, and you\n    should return the list sorted by that rule.\n    If two words have the same length, sort the list alphabetically.\n    The function should return a list of strings in sorted order.\n    You may assume that all words will have the same length.\n    For example:\n    assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n    assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n    \"\"\"\n", "rephrased_question": "def sorted_list_sum(lst):\n    \"\"\"Given a list of strings, remove all strings with odd lengths, then sort the \n    remaining strings primarily by length (ascending) and secondarily alphabetically \n    for ties. Return the sorted list.\n    For example:\n    assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n    assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n    \"\"\"", "answer": "    lst.sort()\n    new_lst = []\n    for i in lst:\n        if len(i)%2 == 0:\n            new_lst.append(i)\n    return sorted(new_lst, key=len)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n    assert candidate([\"school\", \"AI\", \"asdf\", \"b\"]) == [\"AI\", \"asdf\", \"school\"]\n    assert candidate([\"d\", \"b\", \"c\", \"a\"]) == []\n    assert candidate([\"d\", \"dcba\", \"abcd\", \"a\"]) == [\"abcd\", \"dcba\"]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([\"AI\", \"ai\", \"au\"]) == [\"AI\", \"ai\", \"au\"]\n    assert candidate([\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"]) == []\n    assert candidate(['aaaa', 'bbbb', 'dd', 'cc']) == [\"cc\", \"dd\", \"aaaa\", \"bbbb\"]\n\n", "entry_point": "sorted_list_sum"}
+{"id": "humaneval_150", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef x_or_y(n, x, y):\n    \"\"\"A simple program which should return the value of x if n is \n    a prime number and should return the value of y otherwise.\n\n    Examples:\n    for x_or_y(7, 34, 12) == 34\n    for x_or_y(15, 8, 5) == 5\n    \n    \"\"\"\n", "rephrased_question": "def x_or_y(n, x, y):\n    \"\"\"Implement a selector that yields x if the input integer n is prime; otherwise, yields y.\n\n    Examples:\n    for x_or_y(7, 34, 12) == 34\n    for x_or_y(15, 8, 5) == 5\n    \"\"\"", "answer": "    if n == 1:\n        return y\n    for i in range(2, n):\n        if n % i == 0:\n            return y\n            break\n    else:\n        return x\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(7, 34, 12) == 34\n    assert candidate(15, 8, 5) == 5\n    assert candidate(3, 33, 5212) == 33\n    assert candidate(1259, 3, 52) == 3\n    assert candidate(7919, -1, 12) == -1\n    assert candidate(3609, 1245, 583) == 583\n    assert candidate(91, 56, 129) == 129\n    assert candidate(6, 34, 1234) == 1234\n    \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 2, 0) == 0\n    assert candidate(2, 2, 0) == 2\n\n", "entry_point": "x_or_y"}
+{"id": "humaneval_151", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n", "rephrased_question": "def double_the_difference(lst):\n    '''\n    Compute the sum of the squares of all odd-valued elements in the list, but exclude\n    any non-integer or negative entries. An empty list yields 0.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n", "answer": "    return sum([i**2 for i in lst if i > 0 and i%2!=0 and \".\" not in str(i)])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([]) == 0 , \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([5, 4]) == 25 , \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate([0.1, 0.2, 0.3]) == 0 , \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate([-10, -20, -30]) == 0 , \"This prints if this assert fails 4 (good for debugging!)\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([-1, -2, 8]) == 0, \"This prints if this assert fails 5 (also good for debugging!)\"\n    assert candidate([0.2, 3, 5]) == 34, \"This prints if this assert fails 6 (also good for debugging!)\"\n    lst = list(range(-99, 100, 2))\n    odd_sum = sum([i**2 for i in lst if i%2!=0 and i > 0])\n    assert candidate(lst) == odd_sum , \"This prints if this assert fails 7 (good for debugging!)\"\n\n", "entry_point": "double_the_difference"}
+{"id": "humaneval_152", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef compare(game,guess):\n    \"\"\"I think we all remember that feeling when the result of some long-awaited\n    event is finally known. The feelings and thoughts you have at that moment are\n    definitely worth noting down and comparing.\n    Your task is to determine if a person correctly guessed the results of a number of matches.\n    You are given two arrays of scores and guesses of equal length, where each index shows a match. \n    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n    the value is 0, and if not, the value is the absolute difference between the guess and the score.\n    \n    \n    example:\n\n    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"\n", "rephrased_question": "def compare(game,guess):\n    \"\"\"Given two equal-length arrays representing actual scores and predicted scores\n    for a series of matches, produce an array of the absolute differences between each\n    corresponding pair. A perfect prediction yields 0 at that index.\n    \n    example:\n\n    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"", "answer": "    return [abs(x-y) for x,y in zip(game,guess)]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,2,3],[-1,-2,-3])==[2,4,6], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,2,3,5],[-1,2,3,4])==[2,0,0,1], \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "entry_point": "compare"}
+{"id": "humaneval_153", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef Strongest_Extension(class_name, extensions):\n    \"\"\"You will be given the name of a class (a string) and a list of extensions.\n    The extensions are to be used to load additional classes to the class. The\n    strength of the extension is as follows: Let CAP be the number of the uppercase\n    letters in the extension's name, and let SM be the number of lowercase letters \n    in the extension's name, the strength is given by the fraction CAP - SM. \n    You should find the strongest extension and return a string in this \n    format: ClassName.StrongestExtensionName.\n    If there are two or more extensions with the same strength, you should\n    choose the one that comes first in the list.\n    For example, if you are given \"Slices\" as the class and a list of the\n    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension \n    (its strength is -1).\n    Example:\n    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'\n    \"\"\"\n", "rephrased_question": "def Strongest_Extension(class_name, extensions):\n    \"\"\"Given a class name string and a list of extension name strings, compute each\n    extension's strength as (number of uppercase letters) - (number of lowercase letters).\n    Select the extension with the highest strength; in case of a tie, pick the one\n    that appears earliest in the list. Return the concatenation 'ClassName.StrongestExtension'.\n    For example, if you are given \"Slices\" as the class and a list of the\n    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension \n    (its strength is -1).\n    Example:\n    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'\n    \"\"\"", "answer": "    strong = extensions[0]\n    my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])\n    for s in extensions:\n        val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])\n        if val > my_val:\n            strong = s\n            my_val = val\n\n    ans = class_name + \".\" + strong\n    return ans\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'\n    assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'\n    assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__', '123NoooneB321']) == '__YESIMHERE.NuLl__'\n    assert candidate('K', ['Ta', 'TAR', 't234An', 'cosSo']) == 'K.TAR'\n    assert candidate('__HAHA', ['Tab', '123', '781345', '-_-']) == '__HAHA.123'\n    assert candidate('YameRore', ['HhAas', 'okIWILL123', 'WorkOut', 'Fails', '-_-']) == 'YameRore.okIWILL123'\n    assert candidate('finNNalLLly', ['Die', 'NowW', 'Wow', 'WoW']) == 'finNNalLLly.WoW'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('_', ['Bb', '91245']) == '_.Bb'\n    assert candidate('Sp', ['671235', 'Bb']) == 'Sp.671235'\n    \n", "entry_point": "Strongest_Extension"}
+{"id": "humaneval_154", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef cycpattern_check(a , b):\n    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word\n    cycpattern_check(\"abcd\",\"abd\") => False\n    cycpattern_check(\"hello\",\"ell\") => True\n    cycpattern_check(\"whassup\",\"psus\") => False\n    cycpattern_check(\"abab\",\"baa\") => True\n    cycpattern_check(\"efef\",\"eeff\") => False\n    cycpattern_check(\"himenss\",\"simen\") => True\n\n    \"\"\"\n", "rephrased_question": "def cycpattern_check(a , b):\n    \"\"\"Determine whether the second string, or any of its cyclic rotations, appears\n    as a contiguous substring within the first string.\n    cycpattern_check(\"abcd\",\"abd\") => False\n    cycpattern_check(\"hello\",\"ell\") => True\n    cycpattern_check(\"whassup\",\"psus\") => False\n    cycpattern_check(\"abab\",\"baa\") => True\n    cycpattern_check(\"efef\",\"eeff\") => False\n    cycpattern_check(\"himenss\",\"simen\") => True\n    \"\"\"", "answer": "    l = len(b)\n    pat = b + b\n    for i in range(len(a) - l + 1):\n        for j in range(l + 1):\n            if a[i:i+l] == pat[j:j+l]:\n                return True\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    #assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    #assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert  candidate(\"xyzw\",\"xyw\") == False , \"test #0\"\n    assert  candidate(\"yello\",\"ell\") == True , \"test #1\"\n    assert  candidate(\"whattup\",\"ptut\") == False , \"test #2\"\n    assert  candidate(\"efef\",\"fee\") == True , \"test #3\"\n    assert  candidate(\"abab\",\"aabb\") == False , \"test #4\"\n    assert  candidate(\"winemtt\",\"tinem\") == True , \"test #5\"\n\n", "entry_point": "cycpattern_check"}
+{"id": "humaneval_155", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef even_odd_count(num):\n    \"\"\"Given an integer. return a tuple that has the number of even and odd digits respectively.\n\n     Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n", "rephrased_question": "def even_odd_count(num):\n    \"\"\"Given an integer, return a tuple containing the counts of even digits and odd digits\n    in its decimal representation, respectively.\n\n     Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"", "answer": "    even_count = 0\n    odd_count = 0\n    for i in str(abs(num)):\n        if int(i)%2==0:\n            even_count +=1\n        else:\n            odd_count +=1\n    return (even_count, odd_count)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(7) == (0, 1)\n    assert candidate(-78) == (1, 1)\n    assert candidate(3452) == (2, 2)\n    assert candidate(346211) == (3, 3)\n    assert candidate(-345821) == (3, 3)\n    assert candidate(-2) == (1, 0)\n    assert candidate(-45347) == (2, 3)\n    assert candidate(0) == (1, 0)\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "entry_point": "even_odd_count"}
+{"id": "humaneval_156", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n", "rephrased_question": "def int_to_mini_roman(number):\n    \"\"\"\n    Convert a positive integer (1 \u2264 number \u2264 1000) into its Roman numeral representation\n    as a lowercase string.\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"", "answer": "    num = [1, 4, 5, 9, 10, 40, 50, 90,  \n           100, 400, 500, 900, 1000] \n    sym = [\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\",  \n           \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\"] \n    i = 12\n    res = ''\n    while number: \n        div = number // num[i] \n        number %= num[i] \n        while div: \n            res += sym[i] \n            div -= 1\n        i -= 1\n    return res.lower()\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(19) == 'xix'\n    assert candidate(152) == 'clii'\n    assert candidate(251) == 'ccli'\n    assert candidate(426) == 'cdxxvi'\n    assert candidate(500) == 'd'\n    assert candidate(1) == 'i'\n    assert candidate(4) == 'iv'\n    assert candidate(43) == 'xliii'\n    assert candidate(90) == 'xc'\n    assert candidate(94) == 'xciv'\n    assert candidate(532) == 'dxxxii'\n    assert candidate(900) == 'cm'\n    assert candidate(994) == 'cmxciv'\n    assert candidate(1000) == 'm'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "entry_point": "int_to_mini_roman"}
+{"id": "humaneval_157", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n", "rephrased_question": "def right_angle_triangle(a, b, c):\n    '''\n    Verify whether the three given side lengths can form a right-angled triangle.\n    A triangle is right-angled if the square of one side equals the sum of the squares\n    of the other two.\n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n", "answer": "    return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3, 4, 5) == True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1, 2, 3) == False\n    assert candidate(10, 6, 8) == True\n    assert candidate(2, 2, 2) == False\n    assert candidate(7, 24, 25) == True\n    assert candidate(10, 5, 7) == False\n    assert candidate(5, 12, 13) == True\n    assert candidate(15, 8, 17) == True\n    assert candidate(48, 55, 73) == True\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1, 1) == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(2, 2, 10) == False\n\n", "entry_point": "right_angle_triangle"}
+{"id": "humaneval_158", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    The list contains different words. Return the word with maximum number\n    of unique characters. If multiple strings have maximum number of unique\n    characters, return the one which comes first in lexicographical order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"\"aaaaaaa\"\n    \"\"\"\n", "rephrased_question": "def find_max(words):\n    \"\"\"Given a list of strings, identify the string with the greatest number of distinct\n    characters. If multiple strings tie for this maximum, return the one that appears\n    earliest in lexicographic (alphabetical) order.\n\n    find_max([\"name\", \"of\", \"string\"]) == \"string\"\n    find_max([\"name\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"aaaaaaa\"\n    \"\"\"", "answer": "    return sorted(words, key = lambda x: (-len(set(x)), x))[0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert (candidate([\"name\", \"of\", \"string\"]) == \"string\"), \"t1\"\n    assert (candidate([\"name\", \"enam\", \"game\"]) == \"enam\"), 't2'\n    assert (candidate([\"aaaaaaa\", \"bb\", \"cc\"]) == \"aaaaaaa\"), 't3'\n    assert (candidate([\"abc\", \"cba\"]) == \"abc\"), 't4'\n    assert (candidate([\"play\", \"this\", \"game\", \"of\",\"footbott\"]) == \"footbott\"), 't5'\n    assert (candidate([\"we\", \"are\", \"gonna\", \"rock\"]) == \"gonna\"), 't6'\n    assert (candidate([\"we\", \"are\", \"a\", \"mad\", \"nation\"]) == \"nation\"), 't7'\n    assert (candidate([\"this\", \"is\", \"a\", \"prrk\"]) == \"this\"), 't8'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert (candidate([\"b\"]) == \"b\"), 't9'\n    assert (candidate([\"play\", \"play\", \"play\"]) == \"play\"), 't10'\n\n", "entry_point": "find_max"}
+{"id": "humaneval_159", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots thet exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n", "rephrased_question": "def eat(number, need, remaining):\n    \"\"\"\n    Simulate a rabbit's carrot consumption: it has already eaten `number` carrots,\n    needs to eat `need` more, and there are `remaining` carrots available.\n    The rabbit eats as many as possible, up to `need`, but only if enough remain;\n    otherwise it eats all remaining carrots. Return a list [total_eaten, carrots_left]\n    after this eating session.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots thet exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"", "answer": "    if(need <= remaining):\n        return [ number + need , remaining-need ]\n    else:\n        return [ number + remaining , 0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(5, 6, 10) == [11, 4], \"Error\"\n    assert candidate(4, 8, 9) == [12, 1], \"Error\"\n    assert candidate(1, 10, 10) == [11, 0], \"Error\"\n    assert candidate(2, 11, 5) == [7, 0], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(4, 5, 7) == [9, 2], \"Error\"\n    assert candidate(4, 5, 1) == [5, 0], \"Error\"\n\n", "entry_point": "eat"}
+{"id": "humaneval_160", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebric \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator['+', '*', '-']\n    array = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n\n    \"\"\"\n", "rephrased_question": "def do_algebra(operator, operand):\n    \"\"\"\n    Construct an arithmetic expression by interleaving the given operator list\n    (containing strings like '+', '-', '*', '//', '**') with the integer operands.\n    The number of operators is one less than the number of operands. Evaluate the\n    expression following standard operator precedence and return the result.\n\n    Example:\n    operator['+', '*', '-']\n    array = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n    \"\"\"", "answer": "    expression = str(operand[0])\n    for oprt, oprn in zip(operator, operand[1:]):\n        expression+= oprt + str(oprn)\n    return eval(expression)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37\n    assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9\n    assert candidate(['//', '*'], [7, 3, 4]) == 8, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "entry_point": "do_algebra"}
+{"id": "humaneval_161", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef solve(s):\n    \"\"\"You are given a string s.\n    if s[i] is a letter, reverse its case from lower to upper or vise versa, \n    otherwise keep it as it is.\n    If the string contains no letters, reverse the string.\n    The function should return the resulted string.\n    Examples\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n", "rephrased_question": "def solve(s):\n    \"\"\"Transform a string by toggling the case of every alphabetic character (lower \u2194 upper).\n    Non-alphabetic characters remain unchanged. However, if the string contains no letters,\n    reverse the entire string. Return the resulting string.\n    Examples\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"", "answer": "    flg = 0\n    idx = 0\n    new_str = list(s)\n    for i in s:\n        if i.isalpha():\n            new_str[idx] = i.swapcase()\n            flg = 1\n        idx += 1\n    s = \"\"\n    for i in new_str:\n        s += i\n    if flg == 0:\n        return s[len(s)::-1]\n    return s\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"AsDf\") == \"aSdF\"\n    assert candidate(\"1234\") == \"4321\"\n    assert candidate(\"ab\") == \"AB\"\n    assert candidate(\"#a@C\") == \"#A@c\"\n    assert candidate(\"#AsdfW^45\") == \"#aSDFw^45\"\n    assert candidate(\"#6@2\") == \"2@6#\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"#$a^D\") == \"#$A^d\"\n    assert candidate(\"#ccc\") == \"#CCC\"\n\n    # Don't remove this line:\n", "entry_point": "solve"}
+{"id": "humaneval_162", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    \"\"\"\n", "rephrased_question": "def string_to_md5(text):\n    \"\"\"\n    Compute the MD5 hash of the input string and return its hexadecimal representation.\n    If the input is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    \"\"\"", "answer": "    import hashlib\n    return hashlib.md5(text.encode('ascii')).hexdigest() if text else None\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    assert candidate('') == None\n    assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'\n    assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "entry_point": "string_to_md5"}
+{"id": "humaneval_163", "domain": "humaneval", "source_dataset": "openai/openai_humaneval", "original_question": "\ndef generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n", "rephrased_question": "def generate_integers(a, b):\n    \"\"\"\n    Given two positive integers, produce a list of all even digits that appear in the\n    decimal representations of any integer between a and b inclusive, sorted ascending.\n    The order of a and b does not matter.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"", "answer": "    lower = max(2, min(a, b))\n    upper = min(8, max(a, b))\n\n    return [i for i in range(lower, upper+1) if i % 2 == 0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(2, 10) == [2, 4, 6, 8], \"Test 1\"\n    assert candidate(10, 2) == [2, 4, 6, 8], \"Test 2\"\n    assert candidate(132, 2) == [2, 4, 6, 8], \"Test 3\"\n    assert candidate(17,89) == [], \"Test 4\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "entry_point": "generate_integers"}