| def odd_count(lst): | |
| """Given a list of strings, where each string consists of only digits, return a list. | |
| Each element i of the output should be "the number of odd elements in the | |
| string i of the input." where all the i's should be replaced by the number | |
| of odd digits in the i'th string of the input. | |
| >>> odd_count(['1234567']) | |
| ["the number of odd elements 4n the str4ng 4 of the 4nput."] | |
| >>> odd_count(['3',"11111111"]) | |
| ["the number of odd elements 1n the str1ng 1 of the 1nput.", | |
| "the number of odd elements 8n the str8ng 8 of the 8nput."] | |
| """ | |
| res = [] | |
| for arr in lst: | |
| n = sum(int(d)%2==1 for d in arr) | |
| res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") | |
| return res | |