| def get_closest_vowel(word): | |
| """You are given a word. Your task is to find the closest vowel that stands between | |
| two consonants from the right side of the word (case sensitive). | |
| Vowels in the beginning and ending doesn't count. Return empty string if you didn't | |
| find any vowel met the above condition. | |
| You may assume that the given string contains English letter only. | |
| Example: | |
| get_closest_vowel("yogurt") ==> "u" | |
| get_closest_vowel("FULL") ==> "U" | |
| get_closest_vowel("quick") ==> "" | |
| get_closest_vowel("ab") ==> "" | |
| """ | |
| if len(word) < 3: | |
| return "" | |
| vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} | |
| for i in range(len(word)-2, 0, -1): | |
| if word[i] in vowels: | |
| if (word[i+1] not in vowels) and (word[i-1] not in vowels): | |
| return word[i] | |
| return "" | |