diff --git a/MathMC/0.json b/MathMC/0.json new file mode 100644 index 0000000000000000000000000000000000000000..b6f1d17fbcf1061ea65a763c17e2eb00c563c580 --- /dev/null +++ b/MathMC/0.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扩大到原来的10倍" + }, + { + "bullet": "B", + "text": "扩大到原来的100倍" + }, + { + "bullet": "C", + "text": "扩大到原来的1000倍" + } + ], + "text": "在计算7.2÷0.12时，需要把被除数和除数同时( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据商不变性质:被除数和除数同时扩大或缩小相同的倍数(0除外)，商不变;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/1.json b/MathMC/1.json new file mode 100644 index 0000000000000000000000000000000000000000..fe8c084303347964fff54fa7fc447a3e700e916d --- /dev/null +++ b/MathMC/1.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/2" + }, + { + "bullet": "B", + "text": "1/4" + }, + { + "bullet": "C", + "text": "2/4" + } + ], + "text": "个苹果平均分成4份，小明吃了1块，小明吃了这个苹果的( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把一苹果平均分成四份，小明吃了其中的一块，就是吃了其中的一份，所以他吃的是这个苹果的四分之一，选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/10.json b/MathMC/10.json new file mode 100644 index 0000000000000000000000000000000000000000..487a6a1df3bbe7994a044d269550b5b6ade9f6a7 --- /dev/null +++ b/MathMC/10.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "16" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "一个长方体，所有的棱长之和是48厘米，相交于一个顶点的三条棱的长度的和是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据长方体的棱长总和=(长+宽+高)×4，用棱长总和除以4即可求出长、宽、高的和，相交于一个顶点的三条棱的长度的和也就是长、宽、高的和，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/100.json b/MathMC/100.json new file mode 100644 index 0000000000000000000000000000000000000000..4d31739a1f1d75c086e8d2b99c4f23e85ffe753d --- /dev/null +++ b/MathMC/100.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{2}{7}" + }, + { + "bullet": "B", + "text": "\\frac{4}{7}" + }, + { + "bullet": "C", + "text": "\\frac{7}{4}" + }, + { + "bullet": "D", + "text": "\\frac{4}{9}" + } + ], + "text": "在计算乘法时，不慎将乘数63写成36，那么计算结果是正确答案的( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "36÷63=\\frac{4}{7}" + ] + } +} \ No newline at end of file diff --git a/MathMC/101.json b/MathMC/101.json new file mode 100644 index 0000000000000000000000000000000000000000..48ddea2bbd3280f5100681ced23b07fe881ff399 --- /dev/null +++ b/MathMC/101.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1500;" + }, + { + "bullet": "B", + "text": "2000;" + }, + { + "bullet": "C", + "text": "2500." + } + ], + "text": "99×18的积最接近( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在乘法估算中一般要根据‘四舍五入‘法，把因数看作是整十，整百，整千…的数来进行计算，99×18中要把99看作100，18看作20来进行计算.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/102.json b/MathMC/102.json new file mode 100644 index 0000000000000000000000000000000000000000..b60fd47162167ab7b1b3f9bfc4be86fa6dbf492e --- /dev/null +++ b/MathMC/102.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a>b" + }, + { + "bullet": "B", + "text": "a2990千克>5千克， 所以最重的是3吨. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/136.json b/MathMC/136.json new file mode 100644 index 0000000000000000000000000000000000000000..87d703563970a02e850d406298a14c852033a056 --- /dev/null +++ b/MathMC/136.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "8" + } + ], + "text": "任取3个连续的非零自然数，它们相乘的积一定是 的倍数. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "三个连续的非0自然数，如:1、2、3或2、3、4或3、4、5等，无论哪一组数，总有一个数含有因数2，一个数含有因数3，这样三个数的积就一定既是2的倍数，又是3的倍数，即6的倍数." + ] + } +} \ No newline at end of file diff --git a/MathMC/137.json b/MathMC/137.json new file mode 100644 index 0000000000000000000000000000000000000000..2784590141201b229f8a4bc90be44a55c6c06bd7 --- /dev/null +++ b/MathMC/137.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形" + }, + { + "bullet": "B", + "text": "平行四边形" + }, + { + "bullet": "C", + "text": "三角形" + } + ], + "text": "下列图形中，具有不稳定性的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据四边形的特性和三角形的特性:四边形具有不稳定性，三角形具有稳定性;据此判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/138.json b/MathMC/138.json new file mode 100644 index 0000000000000000000000000000000000000000..7211cb779ed1247d4c92993bb483ca3041792c87 --- /dev/null +++ b/MathMC/138.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2厘米、4厘米、6厘米" + }, + { + "bullet": "B", + "text": "6厘米、6厘米、6厘米" + }, + { + "bullet": "C", + "text": "5厘米、4厘米、6厘米" + }, + { + "bullet": "D", + "text": "7厘米、4厘米、4厘米" + } + ], + "text": "下面各组线段中，不能围成三角形的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据三角形三边的关系思考即可，三角形的任意两边之和一定大于第三边，2+4=6;6+6>6;5+4>6;4+4>7;所以只有第一组线段不能围成三角形." + ] + } +} \ No newline at end of file diff --git a/MathMC/139.json b/MathMC/139.json new file mode 100644 index 0000000000000000000000000000000000000000..774027e04df3bd5c0a8360fd7dedde75bcc0b592 --- /dev/null +++ b/MathMC/139.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60" + }, + { + "bullet": "B", + "text": "40" + }, + { + "bullet": "C", + "text": "30" + } + ], + "text": "一个正方体的木料，它的底面积是10平方厘米，把它横截成4段，表面积增加( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "应明确把一个正方体，分割成4个长方体，增加6个底面的面积，由此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/14.json b/MathMC/14.json new file mode 100644 index 0000000000000000000000000000000000000000..6a1c9f5a5f2d094a241c667a812af5b56a522366 --- /dev/null +++ b/MathMC/14.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "三角形面积是平行四边形的一半。" + }, + { + "bullet": "B", + "text": "面积相等的两个三角形一定可以拼成一个平行四边形。" + }, + { + "bullet": "C", + "text": "一个平行四边形和一个三角形等底等高，这个平行四边形的面积是这个三角形面积的2倍。" + }, + { + "bullet": "D", + "text": "平行四边形面积一定大于三角形面积。" + } + ], + "text": "下列说法正确的是( )。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为三角形的面积是和它等底等高的平行四边形面积的一半；所以三角形的面积是平行四边形面积的一半此说法是错误的。两个面积相等的三角形不一定能拼成一个平行四边形，所以这一说法错误。平行四边形的面积可能小于三角形面积，这一说法错误。" + ] + } +} \ No newline at end of file diff --git a/MathMC/140.json b/MathMC/140.json new file mode 100644 index 0000000000000000000000000000000000000000..89bded63cc60ee4bc0b546c6a0924a9f15f466c2 --- /dev/null +++ b/MathMC/140.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:2" + }, + { + "bullet": "B", + "text": "1:8" + }, + { + "bullet": "C", + "text": "1:16" + }, + { + "bullet": "D", + "text": "1:4" + } + ], + "text": "如果把正方形的边长按1:4的比缩小，那么新正方形和原来正方形的面积比是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "{{1}^{2}}:{{4}^{2}}=1:16." + ] + } +} \ No newline at end of file diff --git a/MathMC/141.json b/MathMC/141.json new file mode 100644 index 0000000000000000000000000000000000000000..9dcc6a644f1b4570ab04a30c45f17f7b4de2314b --- /dev/null +++ b/MathMC/141.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "270" + }, + { + "bullet": "B", + "text": "300" + }, + { + "bullet": "C", + "text": "2430" + }, + { + "bullet": "D", + "text": "3000" + } + ], + "text": "一台电脑打九折后的售价2700元，这台电脑原来售价( )元. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "九折是指现价是原价的90%，把原价看成单位‘1‘，它的90%就是现价2700元，根据分数除法的意义，用2700元除以90%即可求出原价." + ] + } +} \ No newline at end of file diff --git a/MathMC/142.json b/MathMC/142.json new file mode 100644 index 0000000000000000000000000000000000000000..585d28aa4bbb578e5775b638a4eb6f1487af8fd1 --- /dev/null +++ b/MathMC/142.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "82┊9820" + }, + { + "bullet": "B", + "text": "83┊0260" + }, + { + "bullet": "C", + "text": "83┊0099" + }, + { + "bullet": "D", + "text": "83┊4500" + } + ], + "text": "有4个数‘四舍五入‘后得到83万，其中( )最接近83万. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，四个数中与83万差最小的数即最接近83的数，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/143.json b/MathMC/143.json new file mode 100644 index 0000000000000000000000000000000000000000..d1c9133df659b8664147b5f67e78aa978e866656 --- /dev/null +++ b/MathMC/143.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{6}" + }, + { + "bullet": "B", + "text": "\\frac{1}{7}" + }, + { + "bullet": "C", + "text": "\\frac{1}{8}" + } + ], + "text": "一根木料锯成7段，锯每段所用的时间占完成这项工作总时间的(假设每锯一次所用的时间都相同) ( )。" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "分7段，锯6次，一次用时占\\frac{1}{6}。 故选A。" + ] + } +} \ No newline at end of file diff --git a/MathMC/144.json b/MathMC/144.json new file mode 100644 index 0000000000000000000000000000000000000000..4da40de7003e18207a59f6321fcb11702c888028 --- /dev/null +++ b/MathMC/144.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "果汁多" + }, + { + "bullet": "B", + "text": "水多" + }, + { + "bullet": "C", + "text": "一样多" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "一杯果汁，小明喝了它的\\frac{1}{8}，然后加满水，又喝了这杯的\\frac{1}{3}，再加满水后又喝了半杯，又加满了水，最后把一杯都喝完.小明喝的果汁和水比，( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把杯子看做是单位‘1‘ 小明喝的果汁是1， 小明一共喝了:\\frac{1}{8}+\\frac{1}{3}+\\frac{1}{2}+1=\\frac{47}{24}， 所以小明喝水是:\\frac{47}{24}-1=\\frac{23}{24}， \\frac{23}{24}<{}1. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/145.json b/MathMC/145.json new file mode 100644 index 0000000000000000000000000000000000000000..3d1f930557828a4f47e2203a34884fcded81fcfe --- /dev/null +++ b/MathMC/145.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "又进了3盒" + }, + { + "bullet": "B", + "text": "每盒12支" + }, + { + "bullet": "C", + "text": "每支3角" + } + ], + "text": "超市有7盒铅笔，每支8角钱，求一共可以卖多少钱，应补充哪个条件( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "已知条件有:7盒铅笔，每支8角钱， 问题:一共卖多少钱? 由以上条件可知，缺少每盒几支铅笔. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/146.json b/MathMC/146.json new file mode 100644 index 0000000000000000000000000000000000000000..76a18890d2fb007a2a3788a307d930c4ef2a4e03 --- /dev/null +++ b/MathMC/146.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "48×39" + }, + { + "bullet": "B", + "text": "41×53" + }, + { + "bullet": "C", + "text": "47×50" + } + ], + "text": "下面的算式中，积小于2000的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "乘法的估算，一般要根据‘四舍五入‘法把因数看作是整十、整百、整千…的数来进行计算，然后按表内乘法的计算方法计算，再在乘积的末尾添上相应的0即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/147.json b/MathMC/147.json new file mode 100644 index 0000000000000000000000000000000000000000..fab665066829886afed2d397142b3cc05dbd1ed7 --- /dev/null +++ b/MathMC/147.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1米" + }, + { + "bullet": "B", + "text": "\\frac{9}{10}米" + }, + { + "bullet": "C", + "text": "1" + } + ], + "text": "一根铁丝用去\\frac{3}{10}米，还剩\\frac{7}{10}米，这根铁丝原来长( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "\\frac{3}{10}+\\frac{7}{10}=1(米); 答:这根铁丝原来长1米. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/148.json b/MathMC/148.json new file mode 100644 index 0000000000000000000000000000000000000000..181a4e0707b6c1606ecd5496c44c9d39c9a84705 --- /dev/null +++ b/MathMC/148.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60÷25%" + }, + { + "bullet": "B", + "text": "60÷(1-25%)" + }, + { + "bullet": "C", + "text": "60×(1-25%)" + }, + { + "bullet": "D", + "text": "60-60×25%" + } + ], + "text": "小花有60枚邮票，比小红少25%，小红有多少枚邮票?列式应为( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把小红的邮票数量看成单位‘1‘，它的(1-25%)对应的数量小华的邮票数是60枚，求出小红的数量用法除法." + ] + } +} \ No newline at end of file diff --git a/MathMC/149.json b/MathMC/149.json new file mode 100644 index 0000000000000000000000000000000000000000..07d9b65a47e1ec3828cdb4e9bb24bb70e1b38055 --- /dev/null +++ b/MathMC/149.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a+2" + }, + { + "bullet": "B", + "text": "2a" + }, + { + "bullet": "C", + "text": "a+1" + } + ], + "text": "如果用a表示非零自然数，那么偶数可以表示为( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "例如a=3时，a+2=5，为奇数; 即a+2不一定表示偶数; 当a=3时，2a=2×3=6，为偶数， 当a=4时，2a=2×4=8，为偶数; 当a=3时，a+1=3+1=4，为偶数， a=4时，a+1=4+1=5，为奇数， 即a+1不一定为偶数. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/15.json b/MathMC/15.json new file mode 100644 index 0000000000000000000000000000000000000000..7bff857bd7c0de673c69becab70abd5d771a6da9 --- /dev/null +++ b/MathMC/15.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "25%" + }, + { + "bullet": "B", + "text": "20%" + }, + { + "bullet": "C", + "text": "\\frac{1}{5}" + } + ], + "text": "80克水里加20克糖，这时糖水中含糖率( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先求出糖水的总质量，然后用糖的质量除以糖水的总质量乘上100%即可求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/150.json b/MathMC/150.json new file mode 100644 index 0000000000000000000000000000000000000000..a5bde026ea90c3299d769fcf2a403fc32b6800f0 --- /dev/null +++ b/MathMC/150.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20× \\frac{2}{5}÷ \\frac{3}{4}" + }, + { + "bullet": "B", + "text": "20÷ \\frac{2}{5}× \\frac{3}{4}" + }, + { + "bullet": "C", + "text": "20÷ \\frac{2}{5}÷ \\frac{3}{4}" + }, + { + "bullet": "D", + "text": "\\frac{2}{5}÷ 20× \\frac{3}{4}" + } + ], + "text": "一个数的\\frac{2}{5}是20，这个数的\\frac{3}{4}是多少?下面正确的列式是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "20÷ \\frac{2}{5}× \\frac{3}{4} =50× \\frac{3}{4} =\\frac{75}{2} 答:这个数的\\frac{3}{4}是\\frac{75}{2}. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/151.json b/MathMC/151.json new file mode 100644 index 0000000000000000000000000000000000000000..43b4d7104bbcf97db7f8db42af135f1d1244956d --- /dev/null +++ b/MathMC/151.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2、3、3" + }, + { + "bullet": "B", + "text": "2、3、4" + }, + { + "bullet": "C", + "text": "3、3、3" + }, + { + "bullet": "D", + "text": "3、3、6" + } + ], + "text": "下面的几组线段中(单位:厘米)，不能围成三角形的一组是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "任意两边之和大于第3边，两边之差小于第三边." + ] + } +} \ No newline at end of file diff --git a/MathMC/152.json b/MathMC/152.json new file mode 100644 index 0000000000000000000000000000000000000000..d43b95c0f81226a8c9d2c2b8fd3dd76d8b982bb6 --- /dev/null +++ b/MathMC/152.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "24" + }, + { + "bullet": "C", + "text": "36" + }, + { + "bullet": "D", + "text": "48" + } + ], + "text": "一条大鲸鱼，头长3米，身长等于头长加尾长，尾长等于头长加身长的一半的和.这条大鲸鱼全长( )米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "设尾长为x米，则身长为(3+x)米，由‘尾长等于头长加身长的一半的和‘，列方程为x=3+(3+x)× \\frac{1}{2}，解方程即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/153.json b/MathMC/153.json new file mode 100644 index 0000000000000000000000000000000000000000..bffe16769d8a9ae8ec41314f1949b839d3f6bd6e --- /dev/null +++ b/MathMC/153.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "无从知晓" + } + ], + "text": "一个三角形和一个平行四边形等底等面积.已知平行四边形的底是6厘米，高是8厘米，三角形的高是( )厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由于等底等高的三角形的面积是平行四边形面积的一半，已知一个三角形和一个平行四边形的面积相等，底也相等，平行四边形的高是8厘米，那么，三角形的高就是平行四边形高的2倍. 一个三角形和一个平行四边形的面积相等.底也相等，平行四边形的高是8厘米，那么，三角形的高就是平行四边形高的2倍. 即:8× 2=16 (厘米); 答:三角形的高是16厘米. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/154.json b/MathMC/154.json new file mode 100644 index 0000000000000000000000000000000000000000..80b0c705408498042fbdb194a9f485cb7b14f936 --- /dev/null +++ b/MathMC/154.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扩大到原数的10倍" + }, + { + "bullet": "B", + "text": "缩小到原数的" + }, + { + "bullet": "C", + "text": "扩大到原数的100倍" + }, + { + "bullet": "D", + "text": "缩小到原数的" + } + ], + "text": "把0.001的小数点向右移动二位后，所得的数就( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据数点位置移动引起数的大小变化规律可知，把0.001的小数点向右移动二位后，所得的数就扩大到原数的100倍，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/155.json b/MathMC/155.json new file mode 100644 index 0000000000000000000000000000000000000000..825c15069b472a1c459998ed9c3ceedf4c729b68 --- /dev/null +++ b/MathMC/155.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{3}" + }, + { + "bullet": "B", + "text": "\\frac{1}{4}" + }, + { + "bullet": "C", + "text": "\\frac{3}{4}" + }, + { + "bullet": "D", + "text": "\\frac{1}{12}" + } + ], + "text": "有12支铅笔，平均分给3个同学，每人分得的铅笔是总数的( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把这些铅笔看作单位‘1‘，平均分给3个同学，每人分得的铅笔是总数的1÷ 3=\\frac{1}{3}，故A正确. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/156.json b/MathMC/156.json new file mode 100644 index 0000000000000000000000000000000000000000..6147eba7fb63f7503e070207bcae907ba4d82c70 --- /dev/null +++ b/MathMC/156.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "面积同样大" + }, + { + "bullet": "B", + "text": "长方形面积大" + }, + { + "bullet": "C", + "text": "正方形面积大" + } + ], + "text": "周长相等的长方形和正方形的面积相比( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "正方形和长方形的周长相等，正方形的面积比长方形的面积大.可以通过举例证明，如它们的周长都是24厘米，长方形的长是8厘米，宽是4厘米;正方形的边长是6厘米;然后根据长方形和正方形的面积计算公式计算，进而得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/157.json b/MathMC/157.json new file mode 100644 index 0000000000000000000000000000000000000000..5fb013f5240b6a72a4891e15bf75660bc4bba8dc --- /dev/null +++ b/MathMC/157.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "正方形" + }, + { + "bullet": "B", + "text": "平行四边形" + }, + { + "bullet": "C", + "text": "三角形" + } + ], + "text": "在下面图形中，不容易变形的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据三角形的特性:三角形具有稳定性进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/158.json b/MathMC/158.json new file mode 100644 index 0000000000000000000000000000000000000000..f98e07203021d73b106a66fefdf4720c96932c93 --- /dev/null +++ b/MathMC/158.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3.75" + }, + { + "bullet": "B", + "text": "1500" + }, + { + "bullet": "C", + "text": "3750" + }, + { + "bullet": "D", + "text": "15" + } + ], + "text": "一种药水的药液和水的比是1:200，现有药液75克，应加水( )千克. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据比的意义可知，用1份的药液就要加200份的水，所以水的用量是药液的200÷ 1=200倍.据此可求出应加水的重量.据此解答. 解:75× ( 200÷ 1 ) =75× 200 =15000(克) 15000克=15千克 答:应加水15千克. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/159.json b/MathMC/159.json new file mode 100644 index 0000000000000000000000000000000000000000..2e732be2e8f519c28056d4e47d24be72712ae9ce --- /dev/null +++ b/MathMC/159.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "38×35" + }, + { + "bullet": "B", + "text": "35÷38" + }, + { + "bullet": "C", + "text": "38÷35" + }, + { + "bullet": "D", + "text": "35×38" + } + ], + "text": "一个数的38倍是35，求这个数的算式是.( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一个数的38倍是35，那么用35除以倍数38，即可求出这个数." + ] + } +} \ No newline at end of file diff --git a/MathMC/16.json b/MathMC/16.json new file mode 100644 index 0000000000000000000000000000000000000000..98a3d7149f071b89570f25b70d2649747f1851e3 --- /dev/null +++ b/MathMC/16.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一" + }, + { + "bullet": "B", + "text": "十" + }, + { + "bullet": "C", + "text": "百" + } + ], + "text": "计算503×6时，5×6=30，表示30个( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "506是一个三位数，最高位百位，百位上的5表示5个百，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/160.json b/MathMC/160.json new file mode 100644 index 0000000000000000000000000000000000000000..354c2e68e85fe5bc85defd59526f5b0fc2c7699d --- /dev/null +++ b/MathMC/160.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "如果长方体的长和宽相等，那么它一定是正方体" + }, + { + "bullet": "B", + "text": "长方体中最多有4个面的面积相等" + }, + { + "bullet": "C", + "text": "有6个面、8个顶点、12条棱的物体不是长方体就是正方体" + } + ], + "text": "下面说法正确的是 ( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "A选项，如果长方体的长、宽、高都相等，那么这个长方体就是正方体，说法错误; B选项，长方体中最多有2个面是正方形，其余4个面是完全相同的长方形，面积也相等，所以长方体中最多有4个面的面积相等，说法正确; C选项，长方体和正方体都有6个面、8个顶点、12条棱，但有6个面、8个顶点、12条棱的物体不一定是长方体或正方体，说法错误; 所以，应选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/161.json b/MathMC/161.json new file mode 100644 index 0000000000000000000000000000000000000000..46df44e53b91985244689bdf3b00bd7717cd0a72 --- /dev/null +++ b/MathMC/161.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "和" + }, + { + "bullet": "B", + "text": "差" + }, + { + "bullet": "C", + "text": "积" + }, + { + "bullet": "D", + "text": "商" + } + ], + "text": "两个数的( )一定是这两个数的公倍数. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "两个数A和B，它们的公倍数就是既是A的倍数又是B的倍数的数，即能同时被A、B整除.比如4和12，12×4=48，48是12的倍数，48也是4的倍数，即48是4、12的公倍数." + ] + } +} \ No newline at end of file diff --git a/MathMC/162.json b/MathMC/162.json new file mode 100644 index 0000000000000000000000000000000000000000..3bd20aa8eab18e883dfa575c0db2e166256d6fb2 --- /dev/null +++ b/MathMC/162.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2:3" + }, + { + "bullet": "B", + "text": "3:2" + }, + { + "bullet": "C", + "text": "4:9" + }, + { + "bullet": "D", + "text": "9:4" + } + ], + "text": "两个圆的半径之比是2:3，那么这两个圆的面积之比为( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据圆的面积公式进行推导." + ] + } +} \ No newline at end of file diff --git a/MathMC/163.json b/MathMC/163.json new file mode 100644 index 0000000000000000000000000000000000000000..c93c3aa0e6a095ec59f9d5db2950e75dd8279f35 --- /dev/null +++ b/MathMC/163.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{8}× \\frac{3}{5}" + }, + { + "bullet": "B", + "text": "\\frac{3}{5}÷ \\frac{3}{8}" + }, + { + "bullet": "C", + "text": "\\frac{3}{8}÷ \\frac{3}{5}" + }, + { + "bullet": "D", + "text": "\\frac{3}{5}× \\frac{3}{8}" + } + ], + "text": "一个数的\\frac{3}{8}是\\frac{3}{5}，求这个数的算式是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "已知分量以及分量所对应的率，求单位‘1‘， 用除法，分量除以分率. 把这个数看成单位‘1‘，知道了它的\\frac{3}{8}是\\frac{3}{5}，求单位‘1‘用除法. 求这个数用除法，即\\frac{3}{5}÷ \\frac{3}{8}; 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/164.json b/MathMC/164.json new file mode 100644 index 0000000000000000000000000000000000000000..bb3e789a90dd67d3f0d4fd4c21425718df65af9c --- /dev/null +++ b/MathMC/164.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{4}× \\frac{5}{7}" + }, + { + "bullet": "B", + "text": "\\frac{3}{5}× \\frac{4}{7}" + }, + { + "bullet": "C", + "text": "\\frac{2}{5}× \\frac{5}{7}" + } + ], + "text": "与 \\frac{4}{5}× \\frac{3}{7}结果相同的算式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先计算出 \\frac{4}{5}× \\frac{3}{7}的结果，再求解出A、B、C各算式的结果，对比得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/165.json b/MathMC/165.json new file mode 100644 index 0000000000000000000000000000000000000000..7385510dca6e65cd1669e814a28660e550710a72 --- /dev/null +++ b/MathMC/165.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2100年" + }, + { + "bullet": "B", + "text": "2020年" + }, + { + "bullet": "C", + "text": "2018年" + } + ], + "text": "( )是闰年。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "判新平年、闰年的方法: 一般年份数只要是4的倍数就是闰年，不是4的倍数就是平年; 整百年份数必须是400的倍数才是闰年，不是400的倍数就是平年。 因为2100÷400=5…100，2020÷4=505，2018÷4=504…2，所以2020是闰年。 故答案为:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/166.json b/MathMC/166.json new file mode 100644 index 0000000000000000000000000000000000000000..6bae445232564222b54d2fab41fdb79819b6191e --- /dev/null +++ b/MathMC/166.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{60}{x}+4= \\frac{45}{2x-3}" + }, + { + "bullet": "B", + "text": "\\frac{60}{x}-4= \\frac{45}{2x-3}" + }, + { + "bullet": "C", + "text": "\\frac{60}{x}= \\frac{45}{2x-3}-4" + }, + { + "bullet": "D", + "text": "\\frac{45}{2x-3}- \\frac{60}{x}=4" + } + ], + "text": "已知甲乙两名同学各带60元和45元去文具店购买文具，甲购买笔记本，乙购买钢笔，已知钢笔的单价是笔记本的2倍少3元，结账时甲购买的件数比乙多4件，若设笔记本单价为x元，可列方程 ( )" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "解:设笔记本单价为x元，则钢笔的单价为(2x-3)元， 依题意得: \\frac{60}{x}-4= \\frac{45}{2x-3}. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/167.json b/MathMC/167.json new file mode 100644 index 0000000000000000000000000000000000000000..46480f23774e597b30b455044a55054dd6f3f294 --- /dev/null +++ b/MathMC/167.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0.15÷ 0.12" + }, + { + "bullet": "B", + "text": "1.5÷ 0.12" + }, + { + "bullet": "C", + "text": "1.5÷ 12" + }, + { + "bullet": "D", + "text": "150÷ 0.12" + } + ], + "text": "下列算式中，与15÷ 1.2的商相等的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "被除数和除数同时除以相同的数(0除外)，大小不变.B选项，被除数和除数同时除以10，大小不变，故B正确. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/168.json b/MathMC/168.json new file mode 100644 index 0000000000000000000000000000000000000000..d216a52e03c3c6f987a396b46a44bbf138bb620a --- /dev/null +++ b/MathMC/168.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "160" + }, + { + "bullet": "D", + "text": "320" + } + ], + "text": "把一个长10厘米、宽8厘米、高5厘米的长方体切成两个相等的长方体，表面积最多增加( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "切完后，表面积比原来多出两个切面; 要想表面积增加的最多，那么切面一定要平行于原长方体的最大面，即10×8. 因此，总共增加了:2× (10× 8)=160平方厘米. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/169.json b/MathMC/169.json new file mode 100644 index 0000000000000000000000000000000000000000..442a8c1cb0c9e7663255fde2941ce76e8fbb997e --- /dev/null +++ b/MathMC/169.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "带分数都大于1" + }, + { + "bullet": "B", + "text": "真分数都小于1" + }, + { + "bullet": "C", + "text": "真分数都大于1" + }, + { + "bullet": "D", + "text": "真分数都小于假分数" + } + ], + "text": "在正数中，下列叙述错误的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据分数的分类以及与1的关系可知:真分数都小于1，假分数大于或等于1，带分数都大于1，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/17.json b/MathMC/17.json new file mode 100644 index 0000000000000000000000000000000000000000..c9411c03e599ae905ece2234b9cc4635817e6c0b --- /dev/null +++ b/MathMC/17.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "1 000" + } + ], + "text": "我们学过的质量单位有克、千克和吨，每相邻两个单位之间的进率是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据质量单位的认识可知，质量单位有克、千克和吨，1吨等于1 000千克，1千克等于1 000克，所以每相邻两个单位之间的进率是1 000." + ] + } +} \ No newline at end of file diff --git a/MathMC/170.json b/MathMC/170.json new file mode 100644 index 0000000000000000000000000000000000000000..6886204222d77684d7e7de71e8c35c7b9889aaad --- /dev/null +++ b/MathMC/170.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "9" + } + ], + "text": "一个长方形铁丝框的长是8分米，宽是6分米，把它改作成一个正方形铁丝筐，这个正方形铁丝框的边长是( )分米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题干分析可得，长方形与正方形的周长相等，都是这根铁丝的长度，据此先利用长方形的周长公式求出铁丝的长度，再利用正方形的周长公式即可求出正方形的边长." + ] + } +} \ No newline at end of file diff --git a/MathMC/171.json b/MathMC/171.json new file mode 100644 index 0000000000000000000000000000000000000000..ab70079f7f6a5f08b87ad8b71ca32fd6d0c57b60 --- /dev/null +++ b/MathMC/171.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "相等" + }, + { + "bullet": "B", + "text": "不相等" + }, + { + "bullet": "C", + "text": "无法比较" + } + ], + "text": "棱长6厘米的正方体，它的表面积和体积( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "依据题意:正方体的表面积的单位是平方厘米，体积的单位是立方厘米，是不同的单位关系，所以不能进行比较." + ] + } +} \ No newline at end of file diff --git a/MathMC/172.json b/MathMC/172.json new file mode 100644 index 0000000000000000000000000000000000000000..c0164870f9ff7294e5312187ecb72b055e29b47f --- /dev/null +++ b/MathMC/172.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "50" + }, + { + "bullet": "C", + "text": "150" + }, + { + "bullet": "D", + "text": "30" + } + ], + "text": "a=2×5×5，b=2×3×5，a和b的最大公因数是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据最大公约数的意义可知:最大公约数是两个数的公有质因数的乘积，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/173.json b/MathMC/173.json new file mode 100644 index 0000000000000000000000000000000000000000..cb045c6b7e9744e5075a00de74e2fd1f13d3bbc1 --- /dev/null +++ b/MathMC/173.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15分米" + }, + { + "bullet": "B", + "text": "12.5分米" + }, + { + "bullet": "C", + "text": "17.5分米" + } + ], + "text": "个正方体玻璃水缸，棱长为5分米，用它装满水，再把水全部倒入一个底面积为10 dm2的长方体水槽中，槽里的水面高为( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，一个正方体玻璃水缸，棱长为5分米，用它装满水，再把水全部倒入一个底面积为10平方分米的长方体水槽中，说明正方体容器的容积等于长方体水槽里水的容积." + ] + } +} \ No newline at end of file diff --git a/MathMC/174.json b/MathMC/174.json new file mode 100644 index 0000000000000000000000000000000000000000..d9216530ea21bb2779c7ef1fc40be4f3cccd7370 --- /dev/null +++ b/MathMC/174.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12÷3" + }, + { + "bullet": "B", + "text": "36÷6" + }, + { + "bullet": "C", + "text": "20÷4" + } + ], + "text": "下列算式中，商最大的算式是( )。 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "12÷3=4 36÷6=6 20÷4=5 6>5>4 B。 首先在除法算式中，得数还可以叫做‘商‘。可以分别联想相关的乘法口诀，诸如三四十二，可以写出乘法算式‘3×4=12‘来推算出12÷3=4，另外两道除法算式，也可以分别想‘六六三十六‘、‘四五二十‘来帮助计算结果，最后得出结论，36÷6的商是最大的。" + ] + } +} \ No newline at end of file diff --git a/MathMC/175.json b/MathMC/175.json new file mode 100644 index 0000000000000000000000000000000000000000..0b8964db9d7bd982e24ddd2f8b6a64e9c6f864a1 --- /dev/null +++ b/MathMC/175.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "36=1×2×2×3×3" + }, + { + "bullet": "B", + "text": "36=2×2×9" + }, + { + "bullet": "C", + "text": "36=2×2×3×3" + } + ], + "text": "把36分解质因数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分解质因数就是把一个合数写成几个质数的连乘积形式，一般先从简单的质数试着分解." + ] + } +} \ No newline at end of file diff --git a/MathMC/176.json b/MathMC/176.json new file mode 100644 index 0000000000000000000000000000000000000000..585f14e9121a25791f44aef57264b416affb7152 --- /dev/null +++ b/MathMC/176.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "8" + } + ], + "text": "最小的质数乘最小的合数，积是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "在自然数中，除了1和它本身外，没有别的因数的数为质数，除了1和它本身外，还有别的因数的数为合数.则最小的质数是2，最小的合数是4，所以最小的质数乘最小的合数，积是2×4=8." + ] + } +} \ No newline at end of file diff --git a/MathMC/177.json b/MathMC/177.json new file mode 100644 index 0000000000000000000000000000000000000000..4305aa68450a0fe9a071d9e6f08a5877dbdeed1e --- /dev/null +++ b/MathMC/177.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "百万位和十万位" + }, + { + "bullet": "B", + "text": "亿位和百万位" + }, + { + "bullet": "C", + "text": "亿位和十亿位" + } + ], + "text": "与千万位相邻的两个数位是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据数位顺序表:从右向左依次分:个位、十位、百位、千位、万位、十万位、百万位、千万位、亿位、十亿位、…;可知:与千万位相邻的两个数位是百万位和亿位;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/178.json b/MathMC/178.json new file mode 100644 index 0000000000000000000000000000000000000000..169361e909a17c4d3c72ad4c53e7a4986644d343 --- /dev/null +++ b/MathMC/178.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3/4" + }, + { + "bullet": "B", + "text": "1/4" + }, + { + "bullet": "C", + "text": "2/4" + } + ], + "text": "个苹果平均分成4块，小明吃了2块，小明吃了这个苹果的( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分数的意义:将单位‘1‘平均分成若干份，表示这样一份或几份的数为分数，例如一个苹果平均分成4块，每份就是它的四分之一." + ] + } +} \ No newline at end of file diff --git a/MathMC/179.json b/MathMC/179.json new file mode 100644 index 0000000000000000000000000000000000000000..3e8ba42439726b061f95972c0891f00c2860e83f --- /dev/null +++ b/MathMC/179.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0.3" + }, + { + "bullet": "B", + "text": "3" + }, + { + "bullet": "C", + "text": "30" + } + ], + "text": "甲数除以数的商是38，余数是3，如果把被除数和除数同时扩大10倍，余数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据在有余数的除法中，被除数和除数同时扩大相同的倍数(0除外)，商不变，但余数也扩大相同的倍数;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/18.json b/MathMC/18.json new file mode 100644 index 0000000000000000000000000000000000000000..c6371dbd1e7e8320da81b118fffc37a6b9d7d36a --- /dev/null +++ b/MathMC/18.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东北" + }, + { + "bullet": "B", + "text": "西南" + }, + { + "bullet": "C", + "text": "东南" + } + ], + "text": "教学楼在操场的南面，实验楼在教学楼的东面，实验楼在操场的( )方向. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "如图: 教学楼在操场的南面，实验楼在教学楼的东面，实验楼在操场的东南方向. 故选C. 以操场的位置为观测点看教学楼在南面，以教学楼的位置为观测点看实验楼在东面，以操场的位置为观测点看实验楼在东南方向." + ] + } +} \ No newline at end of file diff --git a/MathMC/180.json b/MathMC/180.json new file mode 100644 index 0000000000000000000000000000000000000000..c9ca3117cdd474a7cc126d57ef2e010b15da5d21 --- /dev/null +++ b/MathMC/180.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "一个由正方体组成的立体图形，从不同方向观察分别是 正面 左面 右面 这个图形最少由( )个正方体组成的立体模型。 " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "从前面看，是3个小正方形，一共有左左边一列，右边两列;从左面看是2行，前面一行有1列，后面一行是2列;从右面看，前面一行是1列，后面一行是2列。所以最少前面只有1个正方体，后面错开一列是2个正方体。3个个正方体即可。 如图: ，从不同方向观察几何体，训练学生的观察能力和分析判断能力。" + ] + } +} \ No newline at end of file diff --git a/MathMC/181.json b/MathMC/181.json new file mode 100644 index 0000000000000000000000000000000000000000..eb7015bef4a1f89aa8f829d28233a3614ec04885 --- /dev/null +++ b/MathMC/181.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "1000" + } + ], + "text": "从1里连续减去0.01，连续减( )次，结果为0. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "‘从1里连续减去0.01，连续减几次结果为0‘，就是看1里面有多少个0.01，用除法计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/182.json b/MathMC/182.json new file mode 100644 index 0000000000000000000000000000000000000000..6b1bc6b23f94dc20a62396759689f8d29cfffaa6 --- /dev/null +++ b/MathMC/182.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "梯形" + }, + { + "bullet": "B", + "text": "长方形" + }, + { + "bullet": "C", + "text": "平行四边形" + }, + { + "bullet": "D", + "text": "正方形" + } + ], + "text": "两个完全一样的等腰梯形可以拼成一个( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "将两个相等的等腰梯形拼在一起，可以拼成一个平行四边形." + ] + } +} \ No newline at end of file diff --git a/MathMC/183.json b/MathMC/183.json new file mode 100644 index 0000000000000000000000000000000000000000..304ee0e6f6815d70f412d06601a603bd9c3085ce --- /dev/null +++ b/MathMC/183.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "150" + }, + { + "bullet": "B", + "text": "15" + }, + { + "bullet": "C", + "text": "130" + } + ], + "text": "不能用一副三角板画出的是( )度的角. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "三角板上的角有30°，60°，45°，90°，所以它们组合在一起能拼成的角有15°，30°，45°，60°，90°，105°，120°，135°，150°，180°.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/184.json b/MathMC/184.json new file mode 100644 index 0000000000000000000000000000000000000000..9ea5554e8ef7ebbbabf89f70c0629b5b82626596 --- /dev/null +++ b/MathMC/184.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "缩小到原数的1/2" + }, + { + "bullet": "B", + "text": "缩小到原数的1/4" + }, + { + "bullet": "C", + "text": "扩大到原数的4倍" + } + ], + "text": "一个不为0的数除以25%，这个数就( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "试题分析:25%=，把除法转化为乘法，进一步利用乘法的意义解答即可. 解:一个不为0的数除以25%，即除以，就是乘4，也就是把这个数扩大到原数的4倍. 故选: C." + ] + } +} \ No newline at end of file diff --git a/MathMC/185.json b/MathMC/185.json new file mode 100644 index 0000000000000000000000000000000000000000..3ec52ef6bc42671fd23e202290ca256881284654 --- /dev/null +++ b/MathMC/185.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "买白菜和黄瓜共付多少元" + }, + { + "bullet": "B", + "text": "白菜比黄瓜重多少千克" + }, + { + "bullet": "C", + "text": "每千克白菜比每千克黄瓜贵多少元" + }, + { + "bullet": "D", + "text": "买黄瓜比白菜少付多少元" + } + ], + "text": "李阿姨买了a千克白菜，每千克1.5元，又买了b千克黄瓜，每千克4元，那么，1.5a-4b表示( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据总价=单价× 数量 A选项:买白菜和黄瓜共付多少元，1.5a+4b，故A错误; B选项:白菜比黄瓜重多少千克，a-b，故B错误; C选项:每千克白菜比每千克黄瓜贵多少元，1.5-4，故C错误; D选项:买黄瓜比白菜少付多少元，1.5a-4b.故D正确. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/186.json b/MathMC/186.json new file mode 100644 index 0000000000000000000000000000000000000000..6f0dec32a0fe55b5702c783b295591499d045a0e --- /dev/null +++ b/MathMC/186.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12平方厘米" + }, + { + "bullet": "B", + "text": "18平方厘米" + }, + { + "bullet": "C", + "text": "16平方厘米" + }, + { + "bullet": "D", + "text": "24平方厘米" + } + ], + "text": "把边长是1厘米的四个小正方体搭成一个长方体，这个长方体的最大表面积是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "4个小正方体拼成一个长方体，有2种拼法:11×4排列:长宽高分别为:4厘米、1厘米、1厘米;22×2排列:长宽高分别为:2厘米、2厘米、1厘米;表面积最大的长方体是1×4排列的;据此根据长方体的表面积公式解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/187.json b/MathMC/187.json new file mode 100644 index 0000000000000000000000000000000000000000..99bbbd5837688a19048ba93f301c451d99279ff1 --- /dev/null +++ b/MathMC/187.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{9}+\\frac{4}{9}+\\frac{4}{9}" + }, + { + "bullet": "B", + "text": "\\frac{4}{9}×2+\\frac{4}{9}" + }, + { + "bullet": "C", + "text": "(\\frac{1}{3}+\\frac{4}{9})×3" + }, + { + "bullet": "D", + "text": "\\frac{1}{3}×4" + } + ], + "text": "下面算式中，( )与\\frac{4}{9}×3的结果不相同. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意可得:\\frac{4}{9}×3=\\frac{4}{3}; A选项:\\frac{4}{9}+\\frac{4}{9}+\\frac{4}{9}=\\frac{4}{9}×3=\\frac{4}{3}; B选项:\\frac{4}{9}×2+\\frac{4}{9}=\\frac{4}{9}×3=\\frac{4}{3}; C选项:(\\frac{1}{3}+\\frac{4}{9})×3=\\frac{1}{3}×3+\\frac{4}{9}×3=1+\\frac{4}{3}=1\\frac{4}{3}; D选项:\\frac{1}{3}×4=\\frac{4}{3}; 所以，只有C不同. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/188.json b/MathMC/188.json new file mode 100644 index 0000000000000000000000000000000000000000..d2ff6ab9d22d3017a890303835939970932231b0 --- /dev/null +++ b/MathMC/188.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:3" + }, + { + "bullet": "B", + "text": "2:3" + }, + { + "bullet": "C", + "text": "2:1" + } + ], + "text": "把一个圆柱行材料，削成一个最大的圆锥，削去部分的体积与削成的圆锥体的体积比是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "试题分析:把一个圆柱削成一个最大的圆锥，则这个圆柱与圆锥等底等高，所以圆柱与圆锥的体积之比是3:1，则削去部分的体积与圆锥的体积就是2:1，由此即可解答. 解:根据题干分析可得:圆柱与圆锥的体积之比是3:1， 则削去部分的体积与圆锥的体积就是2:1. 故选: C." + ] + } +} \ No newline at end of file diff --git a/MathMC/189.json b/MathMC/189.json new file mode 100644 index 0000000000000000000000000000000000000000..56c71581ec3ee3444433b6a079ddb2bcc817c218 --- /dev/null +++ b/MathMC/189.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16" + }, + { + "bullet": "B", + "text": "18" + }, + { + "bullet": "C", + "text": "22" + }, + { + "bullet": "D", + "text": "24" + } + ], + "text": "5个棱长为1厘米的正方体排成一行后，它的表面积是( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把5个棱长为1厘米的正方体排成一行后拼成长方体的表面积把5个正方体的表面积和减少了正方体的8个面的面积，关根据正方形的面积公式:S=\\( a^{2} \\)，正方体的表面积公式:S=6\\( a^{2} \\)，把数据代入公式解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/19.json b/MathMC/19.json new file mode 100644 index 0000000000000000000000000000000000000000..92c8200ffaf22f09aa163f70347d99e32aa52363 --- /dev/null +++ b/MathMC/19.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "《小学生数学报》的单价一定，总价与订阅数量成正比例" + }, + { + "bullet": "B", + "text": "圆锥体积一定，它的底面积与高成反比例" + }, + { + "bullet": "C", + "text": "书的总页数一定，已看的页数和没看的页数成反比例" + }, + { + "bullet": "D", + "text": "出勤率一定，出勤人数与全班人数成正比例" + } + ], + "text": "下面说法错误的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "依据正、反比例的意义，即若两个相关联的量的比值一定，则这两个量成正比例关系;若两个相关联的量的乘积一定，则这两个量成反比例关系，由此逐项进行判断即可选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/190.json b/MathMC/190.json new file mode 100644 index 0000000000000000000000000000000000000000..0949be63c0eacaa44d382424c8ad07824b9ffa1d --- /dev/null +++ b/MathMC/190.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "①", + "text": "甲车快" + }, + { + "bullet": "②", + "text": "乙车快" + }, + { + "bullet": "③", + "text": "一样快" + } + ], + "text": "从a地到b地，甲车4时行了全程的 1/5 ，乙车5时行了全程的 1/4 ，甲、乙两车的速度相比，( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为甲车4时行了全程 1/5，根据路程÷时间=速度，可求出甲车的速度，同理可求乙车的速度，再比较甲、乙两车的速度即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/191.json b/MathMC/191.json new file mode 100644 index 0000000000000000000000000000000000000000..8ace37f7c183d2abfe09de820e7f1e453a8c2266 --- /dev/null +++ b/MathMC/191.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东" + }, + { + "bullet": "B", + "text": "南" + }, + { + "bullet": "C", + "text": "西" + }, + { + "bullet": "D", + "text": "北" + } + ], + "text": "旗杆的影子在西面，那么太阳在( )面. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "解答此题只需注意联系实际，知道光源与影子的相对的，所以太阳在东面，由此进一步解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/192.json b/MathMC/192.json new file mode 100644 index 0000000000000000000000000000000000000000..4b59ab1b510e4d3e2ddc500ed98a592e6a703239 --- /dev/null +++ b/MathMC/192.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "750-90" + }, + { + "bullet": "B", + "text": "399+102" + }, + { + "bullet": "C", + "text": "298+358" + }, + { + "bullet": "D", + "text": "280+488" + } + ], + "text": "下面哪道算式的结果小于600?( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据整数加、减法的计算法则，分别计算出各式的结果，然后与600进行比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/193.json b/MathMC/193.json new file mode 100644 index 0000000000000000000000000000000000000000..f9a11ed49b5f7832ae80eea702da410ecc62e48f --- /dev/null +++ b/MathMC/193.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "604-198" + }, + { + "bullet": "B", + "text": "839-307" + }, + { + "bullet": "C", + "text": "146+299" + } + ], + "text": "下列算式中结果大于500的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "这道题要求选出哪个选项的计算结果是大于500的; A选项:604-198=406;很明显406小于500，故A错误; B选项:839-307=532;532大于500，故B正确; C选项:146+299=445;很明显445小于500，故C错误; 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/194.json b/MathMC/194.json new file mode 100644 index 0000000000000000000000000000000000000000..ae834a66308035cebff8e12e3d7ab474f59a2e5b --- /dev/null +++ b/MathMC/194.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形统计图" + }, + { + "bullet": "B", + "text": "折线统计图" + }, + { + "bullet": "C", + "text": "扇形统计图" + } + ], + "text": "酒厂要绘制1999年每月生产量的增减变化情况统计图，应选用( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/195.json b/MathMC/195.json new file mode 100644 index 0000000000000000000000000000000000000000..986bbcbe424421e6c2f041f8bb5f9547bea7b24f --- /dev/null +++ b/MathMC/195.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "409-150" + }, + { + "bullet": "B", + "text": "207+205" + }, + { + "bullet": "C", + "text": "700-298" + } + ], + "text": "下列算式中，结果小于300的算式是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意，可利用整数加法和整数减法计算方法进行计算，然后再比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/196.json b/MathMC/196.json new file mode 100644 index 0000000000000000000000000000000000000000..c48b5a2e19cf9cc437c065e40a61b97cb6de10fa --- /dev/null +++ b/MathMC/196.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10001和10002" + }, + { + "bullet": "B", + "text": "9999和9998" + }, + { + "bullet": "C", + "text": "9999和10001" + } + ], + "text": "与最小的五位数相邻的两个数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "最小五位数是10000，因为相邻的两个自然数相差1，则与10000相邻的两个自然数为:10000-1，10000+1;据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/197.json b/MathMC/197.json new file mode 100644 index 0000000000000000000000000000000000000000..61a1f9a4a814b90bfca286e4734b752fed946509 --- /dev/null +++ b/MathMC/197.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "14" + }, + { + "bullet": "B", + "text": "16" + }, + { + "bullet": "C", + "text": "18" + } + ], + "text": "将一根木棒锯成4段需要9分钟，则将这根木棒锯成7段需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "将一根木棒锯成4段需锯的次数是(4-1)次，需要9分钟，锯一次用的时间就是9÷(4-1)次，将这根木棒锯成7段需要锯的次数是(7-1)次，然后根据乘法的意义进行解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/198.json b/MathMC/198.json new file mode 100644 index 0000000000000000000000000000000000000000..01b92eee183707322f748627654a0f686978654a --- /dev/null +++ b/MathMC/198.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "10" + }, + { + "bullet": "C", + "text": "11" + } + ], + "text": "从10里面连续减去( )个0.1，结果是0. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据‘包含‘除法的意义，求10里面包含多少个0.1即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/199.json b/MathMC/199.json new file mode 100644 index 0000000000000000000000000000000000000000..242b39d3e599045ba0988932e5933955abea9a63 --- /dev/null +++ b/MathMC/199.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "27" + }, + { + "bullet": "B", + "text": "m" + }, + { + "bullet": "C", + "text": "(a-27)+m" + } + ], + "text": "爸爸今年a岁，明明今年(a-27)岁。m年后，它们相差( )岁 " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由题可知，爸爸今年a岁，明明今年(a-27)岁，可以求出今年父子相差的年龄，m年后，这个年龄差不变。由此可以求解本题。" + ] + } +} \ No newline at end of file diff --git a/MathMC/2.json b/MathMC/2.json new file mode 100644 index 0000000000000000000000000000000000000000..449d3b424aeb35864d01d9a0ecf8151c671e000e --- /dev/null +++ b/MathMC/2.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一根长" + }, + { + "bullet": "B", + "text": "第二根长" + }, + { + "bullet": "C", + "text": "无法确定哪根长" + } + ], + "text": "两根同样长的绳子，第一根用去\\frac{1}{3}，第二根用去\\frac{1}{3}m，两根绳子剩下的长度相比( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "不知道绳子总长度，无法确定剩余绳长. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/20.json b/MathMC/20.json new file mode 100644 index 0000000000000000000000000000000000000000..cd2aa6eff11081d20a36905b4164e3764e35127d --- /dev/null +++ b/MathMC/20.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{b}{a}+\\frac{d}{c}=\\frac{b+d}{a+c}" + }, + { + "bullet": "B", + "text": "\\frac{b}{a}×\\frac{d}{c}=\\frac{b×d}{a×c}" + }, + { + "bullet": "C", + "text": "\\frac{b}{a}÷\\frac{d}{c}=\\frac{b÷d}{a÷c}" + }, + { + "bullet": "D", + "text": "\\frac{b}{a}÷\\frac{d}{c}=\\frac{b}{a}×\\frac{c}{d}" + } + ], + "text": "我们知道‘甲数除以乙数等于甲数乘以乙数的倒数‘.如果记甲数为\\frac{b}{a}，乙数为\\frac{d}{c}，那么该法则可以用符号表示为( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "\\frac{d}{c}的倒数是\\frac{c}{d};\\frac{b}{a}÷\\frac{d}{c}=\\frac{b}{a}×\\frac{c}{d}; 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/200.json b/MathMC/200.json new file mode 100644 index 0000000000000000000000000000000000000000..15bf5bde6bdbf50beca85bcd4032839256e40c34 --- /dev/null +++ b/MathMC/200.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "70007770" + }, + { + "bullet": "B", + "text": "70707007" + }, + { + "bullet": "C", + "text": "77000077" + } + ], + "text": "下面的数中，要读出两个‘零‘的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据整数中0的法，每一级末尾的0都不读出来，其余数位连续几个0都只读一个，一个数要想读出两个0，至少要有两上0不在每级的末尾，并且这两个0不能相邻." + ] + } +} \ No newline at end of file diff --git a/MathMC/201.json b/MathMC/201.json new file mode 100644 index 0000000000000000000000000000000000000000..8d3b0adacab1c2de9ef764df96da1a221465d5ff --- /dev/null +++ b/MathMC/201.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "要使29□680≈30万，□里有( )种填法. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意可以看出，要想知道本题的正确选项，就必须掌握‘四舍五入‘的具体意义，然后再根据条件进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/202.json b/MathMC/202.json new file mode 100644 index 0000000000000000000000000000000000000000..ad023a6fa86f4ed3ae695997f5bf409b7109dc53 --- /dev/null +++ b/MathMC/202.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8小时" + }, + { + "bullet": "B", + "text": "8小时30分" + }, + { + "bullet": "C", + "text": "9小时" + } + ], + "text": "妈妈的工作时间是上午7:00-11:30，下午从1:30-5:30，妈妈一天工作( )很辛苦. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先分别求出上午和下午各工作了多长时间，再相加即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/203.json b/MathMC/203.json new file mode 100644 index 0000000000000000000000000000000000000000..520e3f7720bbe61ecb885ebdfea975ee7e20689c --- /dev/null +++ b/MathMC/203.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扩大到原数的10倍" + }, + { + "bullet": "B", + "text": "缩小到原数的" + }, + { + "bullet": "C", + "text": "缩小到原数的" + }, + { + "bullet": "D", + "text": "扩大到原数的100倍" + } + ], + "text": "一个数的小数点先向右移动两位后，再向左移动一位，这个数就( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据小数点的位置移动引起小数大小变化的规律可知:把一个小数的小数点先向右移动两位，再向左移动一位，相当于把这个小数的小数点向右移动了1位，即扩大了10倍;据此选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/204.json b/MathMC/204.json new file mode 100644 index 0000000000000000000000000000000000000000..f9c20a5ef6a0fa654867f4a9ae0893f2807887f5 --- /dev/null +++ b/MathMC/204.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "120×(1-25%)" + }, + { + "bullet": "B", + "text": "120÷(1-25%)" + }, + { + "bullet": "C", + "text": "120÷(1+25%)" + } + ], + "text": "果园里有苹果树120棵，比梨树少25%，梨树有多少棵?列式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把梨树的棵数看成单位‘1‘，它的(1-25%)就是苹果树的棵数，由此用数量120除以对应的分率(1-25%)就是梨树的棵数." + ] + } +} \ No newline at end of file diff --git a/MathMC/205.json b/MathMC/205.json new file mode 100644 index 0000000000000000000000000000000000000000..9c4a98aa50100b78de956ff6030ef8ea2a2feb6d --- /dev/null +++ b/MathMC/205.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "59×28=1 659" + }, + { + "bullet": "B", + "text": "59×28=1 952" + }, + { + "bullet": "C", + "text": "59×28=1 652" + }, + { + "bullet": "D", + "text": "59×28=1 859" + } + ], + "text": "下面各题中结果正确的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "整数乘法计算法则:先用一个因数每一位上的数分别去乘另一个因数各个数位上的数，用因数数哪一位上的数去乘，乘得的数的末尾就对齐哪一位，然后把各次乘得的数加起来." + ] + } +} \ No newline at end of file diff --git a/MathMC/206.json b/MathMC/206.json new file mode 100644 index 0000000000000000000000000000000000000000..00cf97811175607603a0fe26609dce2abf2575b7 --- /dev/null +++ b/MathMC/206.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{2}" + }, + { + "bullet": "B", + "text": "\\frac{3}{4}" + }, + { + "bullet": "C", + "text": "\\frac{4}{7}" + }, + { + "bullet": "D", + "text": "\\frac{3}{7}" + } + ], + "text": "甲、乙两个粮库各存储稻谷若干吨，从甲粮库调运稻谷的\\frac{2}{7}给乙粮库后，两个粮库存储的稻谷数量相等，原来乙粮库存储的稻谷是甲粮库的( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "把原来甲粮库的存粮的吨数看作单位‘1‘，由‘从甲粮库调运稻谷的\\frac{2}{7}给乙粮库后，两个粮库存储的稻谷数量相等‘可知，乙粮库存粮的吨数相当于甲粮库存粮吨数的1-\\frac{2}{7}-\\frac{2}{7}. 1-\\frac{2}{7}-\\frac{2}{7}=\\frac{3}{7}. 答:原来乙粮库存储的稻谷是甲粮库的\\frac{3}{7}." + ] + } +} \ No newline at end of file diff --git a/MathMC/207.json b/MathMC/207.json new file mode 100644 index 0000000000000000000000000000000000000000..56ee7b1462cb10fff64150b107fb90d7f01d58a8 --- /dev/null +++ b/MathMC/207.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{8}×\\frac{3}{5}" + }, + { + "bullet": "B", + "text": "\\frac{3}{5}÷\\frac{3}{8}" + }, + { + "bullet": "C", + "text": "\\frac{3}{8}÷\\frac{3}{5}" + }, + { + "bullet": "D", + "text": "\\frac{3}{5}×\\frac{3}{8}" + } + ], + "text": "一个数的\\frac{3}{8}是\\frac{3}{5}，求这个数的算式是.( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把这个数看成单位‘1‘，知道了它的\\frac{3}{8}是\\frac{3}{5}，求单位‘1‘用除法. 试题解析:求这个数用除法，即\\frac{3}{5}÷\\frac{3}{8}; 故答案选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/208.json b/MathMC/208.json new file mode 100644 index 0000000000000000000000000000000000000000..e21ae4b36d9a9afce0c724ca2c10d0d2d93b3f83 --- /dev/null +++ b/MathMC/208.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "成正比例" + }, + { + "bullet": "B", + "text": "成反比例" + }, + { + "bullet": "C", + "text": "不成比例" + } + ], + "text": "出勤率一定，应出勤人数和实际出勤人数( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "出勤率= 实际出勤人数/应出勤人数，根据题意得知出勤率一定，也就是说应出勤人数和实际出勤人数的比值一定，由此即可判断它们的关系." + ] + } +} \ No newline at end of file diff --git a/MathMC/209.json b/MathMC/209.json new file mode 100644 index 0000000000000000000000000000000000000000..0614a31a9798ba91946dd183e960715b32c6abf8 --- /dev/null +++ b/MathMC/209.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{10}m" + }, + { + "bullet": "B", + "text": "30%米" + }, + { + "bullet": "C", + "text": "30%" + } + ], + "text": "9米是30米的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据分数除法的意义列出算式9÷30计算即可求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/21.json b/MathMC/21.json new file mode 100644 index 0000000000000000000000000000000000000000..b43ed834fa07e3fe0bd3c985518d4f3d10805114 --- /dev/null +++ b/MathMC/21.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "36" + }, + { + "bullet": "B", + "text": "32" + }, + { + "bullet": "C", + "text": "30" + }, + { + "bullet": "D", + "text": "28" + } + ], + "text": "个长方体正好可以切成3个一样的正方体，切开后每个正方体的表面积是12平方厘米，那么原来这个长方体的表面积是( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "正方体的表面积=棱长×棱长×6，所以本题中正方体一个面的面积是12÷6=2(平方厘米).把3个正方体拼成一个长方体后，长方体的表面积比三个正方体的表面积之和减少了拼在一起的正方体4个面的面积.3个正方体的表面积之和是12×3=36(平方厘米)，正方体的4个面的面积之和是2×4=8(平方厘米)，所以原来的长方体的表面积是36-8=28(平方厘米)." + ] + } +} \ No newline at end of file diff --git a/MathMC/210.json b/MathMC/210.json new file mode 100644 index 0000000000000000000000000000000000000000..4f52b4d666d9cf52062d0874c22b81fe5f1cdb82 --- /dev/null +++ b/MathMC/210.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "48" + }, + { + "bullet": "B", + "text": "44" + }, + { + "bullet": "C", + "text": "40" + }, + { + "bullet": "D", + "text": "16" + } + ], + "text": "两个表面积都是24平方厘米的正方体，拼成一个长方体.这个长方体的表面积是( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "两个表面积都是24平方厘米的正方体拼成一个长方体，长方体的表面积就比原来两个正方体减少了2个面，那么长方体的表面积等于正方体10个面的面积，所以先求出正方体一个面的面积，然后即可求出长方体的表面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/211.json b/MathMC/211.json new file mode 100644 index 0000000000000000000000000000000000000000..76e83f0a655202fef014268d62fa357cc5a52687 --- /dev/null +++ b/MathMC/211.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10个一百是一千" + }, + { + "bullet": "B", + "text": "10个一千是一万" + }, + { + "bullet": "C", + "text": "一千里面有10个一万" + } + ], + "text": "下面的几种说法，错误的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据十进制计数法的含义:每相邻的两个计数单位之间的进率是10，这种计数方法叫做十进制计数法，对下列各选项进行依次分析，进而得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/212.json b/MathMC/212.json new file mode 100644 index 0000000000000000000000000000000000000000..90912ac12598c462d762192c0089bd130a6aed65 --- /dev/null +++ b/MathMC/212.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "18" + }, + { + "bullet": "B", + "text": "36" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "个数既是18的倍数又是18的因数，这个数是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "A是B的倍数，是指A除以B可以得到整数，A是B的因数，是指B除以A可以得到一个整数." + ] + } +} \ No newline at end of file diff --git a/MathMC/213.json b/MathMC/213.json new file mode 100644 index 0000000000000000000000000000000000000000..5d7d217eeb464035055329ca10d9a4405d205c45 --- /dev/null +++ b/MathMC/213.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "16" + } + ], + "text": "用长4厘米，宽2厘米，高1厘米的长方体木块拼成一个正方体，至少要( )个这样的长方体木块? " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "组成的正方体的棱长最小是4厘米，那么宽处需要4÷2=2个长方体，高处需要4÷1=4个长方体，所以一共需要1×2×4=8个这样的长方体木块." + ] + } +} \ No newline at end of file diff --git a/MathMC/214.json b/MathMC/214.json new file mode 100644 index 0000000000000000000000000000000000000000..44c75c6844ec22ddb7b0712fbee3f300558606cb --- /dev/null +++ b/MathMC/214.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一百万" + }, + { + "bullet": "B", + "text": "一千万" + }, + { + "bullet": "C", + "text": "一亿" + } + ], + "text": "一百万一百万地数，数十次是()。 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "依据多位数的认识可知，一百万一百万地数，数十次是一千万，所以本题选B。此题主要考查对多位数的加法运算。" + ] + } +} \ No newline at end of file diff --git a/MathMC/215.json b/MathMC/215.json new file mode 100644 index 0000000000000000000000000000000000000000..e88725565fa1d4603d24d561c01dfef73c6f9cd9 --- /dev/null +++ b/MathMC/215.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "假分数都大于1" + }, + { + "bullet": "B", + "text": "真分数都小于1" + }, + { + "bullet": "C", + "text": "带分数都大于假分数" + } + ], + "text": "下面叙述正确的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题根据假分数、真分数、及带分数的定义对各个选项进行分析即能得出正确选项." + ] + } +} \ No newline at end of file diff --git a/MathMC/216.json b/MathMC/216.json new file mode 100644 index 0000000000000000000000000000000000000000..3d1cd1865cd7306b99f9e4300a22f8a3f9a17e11 --- /dev/null +++ b/MathMC/216.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "冬冬" + }, + { + "bullet": "B", + "text": "林林" + }, + { + "bullet": "C", + "text": "力力" + }, + { + "bullet": "D", + "text": "一样快" + } + ], + "text": "在100米短跑比赛中，冬冬跑完全程用了0.4分钟，林林用了\\frac{1}{3}分钟，力力用了\\frac{1}{4}分钟.三人中成绩最好的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "0.4=\\frac{2}{5}，因\\frac{1}{3}>\\frac{1}{4}，所以力力成绩比林林好;. \\dfrac{2}{5}=\\dfrac{8}{20} \\ \\dfrac{1}{4}=\\dfrac{5}{20} \\，所以力力成绩也比冬冬好." + ] + } +} \ No newline at end of file diff --git a/MathMC/217.json b/MathMC/217.json new file mode 100644 index 0000000000000000000000000000000000000000..bd967d41fc84e5cd96ef27f1f9d4fa6dcff7cc9f --- /dev/null +++ b/MathMC/217.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "800" + }, + { + "bullet": "B", + "text": "6000" + }, + { + "bullet": "C", + "text": "8000" + } + ], + "text": "估算398与21的积大约是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "乘法的估算，一般要根据‘四舍五入‘法把因数看作是整十、整百、整千…的数来进行计算，然后按表内乘法的计算方法计算，再在乘积的末尾添上相应的0即可.398×21≈400×20=8000 故选: C." + ] + } +} \ No newline at end of file diff --git a/MathMC/218.json b/MathMC/218.json new file mode 100644 index 0000000000000000000000000000000000000000..e9d4bf4ce115afbafc39220760b3b8df37fa3d0d --- /dev/null +++ b/MathMC/218.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "29.99万" + }, + { + "bullet": "B", + "text": "30万" + }, + { + "bullet": "C", + "text": "29万" + }, + { + "bullet": "D", + "text": "39万" + } + ], + "text": "299900四舍五入到万位是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用四舍五入的方法取近似数，关键看精确到什么数位，然后把此数位的下一位数字四舍五入取近似数，据此写出近似数后判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/219.json b/MathMC/219.json new file mode 100644 index 0000000000000000000000000000000000000000..127997a484bf546e5e722daf6e39d15f311209b7 --- /dev/null +++ b/MathMC/219.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "一个三角形与一个平行四边形的面积相等，高也相等，平行四边形的底是6 厘米，三角形的底是 厘米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "三角形的面积=底×高÷2，平行四边形的面积=底×高，根据题意得知三角形和平行四边形的面积相等，高也相等，那么三角形的底应该是平行四边形底的2倍." + ] + } +} \ No newline at end of file diff --git a/MathMC/22.json b/MathMC/22.json new file mode 100644 index 0000000000000000000000000000000000000000..41affbf84817b3589d928bcdc9c61e02c7491f8c --- /dev/null +++ b/MathMC/22.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "241千米" + }, + { + "bullet": "B", + "text": "261千米" + }, + { + "bullet": "C", + "text": "191千米" + } + ], + "text": "芳芳早上7:20从家坐汽车出发去奶奶家，上午10:20到达奶奶家，汽车每小时行驶87千米，她家到奶奶家有( )千米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "首先根据:经过的时间=到达奶奶家的时刻-出发的时刻，求出汽车一共行驶了多少时间然后根据:速度× 时间=路程，用汽车每小时行驶的路程乘行驶的时间，求出她家到奶奶家有多少千米即可. 10时20分-7时20分=3时， 87× 3=261(千米). 答:她家到奶奶家有261千米. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/220.json b/MathMC/220.json new file mode 100644 index 0000000000000000000000000000000000000000..83ecdeb9ca93508b8e7da9fef05cdc88a0cb8d29 --- /dev/null +++ b/MathMC/220.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8c{{m}^{2}}" + }, + { + "bullet": "B", + "text": "15c{{m}^{2}}" + }, + { + "bullet": "C", + "text": "21c{{m}^{2}}" + }, + { + "bullet": "D", + "text": "30c{{m}^{2}}" + } + ], + "text": "下图每个小方格的边长表示1厘米，估一估兔子的面积是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "每个小方格的边长是1厘米，则面积是1× 1=1(c{{m}^{2}})， 兔子共占了大约几个方格? 从上数起:3+4+4+3=14(个)， 半格半格的加在一起6个， 14+6=20(个).最接近C. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/221.json b/MathMC/221.json new file mode 100644 index 0000000000000000000000000000000000000000..c8f69ac5a1c520f878f42bceb61d826d1086b9a9 --- /dev/null +++ b/MathMC/221.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "0" + }, + { + "bullet": "C", + "text": "1" + } + ], + "text": "508×6的积的十位上的数是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据整数乘法的计算方法，求出508×6的积，然后再进一步解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/222.json b/MathMC/222.json new file mode 100644 index 0000000000000000000000000000000000000000..55138f5034b22db58053d9e79b2b5735645610c5 --- /dev/null +++ b/MathMC/222.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "350平方米" + }, + { + "bullet": "B", + "text": "50平方米" + }, + { + "bullet": "C", + "text": "28平方米" + } + ], + "text": "一个长方体游泳池长25米，宽14米，高2米，它的占地面积是( )。 " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "25×14=350(平方米) 占地面积，其实就是求长方体下面这一个面的面积是多少，下面这个面是以长25米，宽14米的长方形。面积=长×宽，求出占地面积是350平方米。" + ] + } +} \ No newline at end of file diff --git a/MathMC/223.json b/MathMC/223.json new file mode 100644 index 0000000000000000000000000000000000000000..5c9e58639db406e4b84c59d8ce31b532bd16f05e --- /dev/null +++ b/MathMC/223.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "有限小数" + }, + { + "bullet": "B", + "text": "无限循环小数" + }, + { + "bullet": "C", + "text": "无限不循环小数" + } + ], + "text": "圆周率是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "圆周率是圆周长与直径的比值，是一个无限不循环小数. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/224.json b/MathMC/224.json new file mode 100644 index 0000000000000000000000000000000000000000..a5b48ff410eeb3da948a2d0b7cdd6b3888e19355 --- /dev/null +++ b/MathMC/224.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12分钟" + }, + { + "bullet": "B", + "text": "30分钟" + }, + { + "bullet": "C", + "text": "10分钟" + } + ], + "text": "一根木材锯成3段，用了6分钟，用同样的速度，把它锯成5段需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把一根木料锯成3段要6分钟，即锯了2次用了6分钟，由此可求得锯一次用的时间，锯成5段要锯4次，乘锯一次的时间即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/225.json b/MathMC/225.json new file mode 100644 index 0000000000000000000000000000000000000000..3ed1ceae41292c18e95ea18d70f3ab021f9dc80a --- /dev/null +++ b/MathMC/225.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "万位" + }, + { + "bullet": "B", + "text": "千位" + }, + { + "bullet": "C", + "text": "百位" + } + ], + "text": "16×75的积的最高位是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据整数乘法的计算方法，求出16×75的积，然后再进一步解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/226.json b/MathMC/226.json new file mode 100644 index 0000000000000000000000000000000000000000..17b346351c4e8109f96f5a191b237f588736d61a --- /dev/null +++ b/MathMC/226.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大小不变" + }, + { + "bullet": "B", + "text": "缩小到原来的 1/100" + }, + { + "bullet": "C", + "text": "扩大到原来的100倍" + } + ], + "text": "如果在30的后面添上‘%‘，那么原数就( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "依据百分数的意义和写法可知，如果在整数的后面添上百分号‘%‘，那么原数就缩小到原来的 1 100 ." + ] + } +} \ No newline at end of file diff --git a/MathMC/227.json b/MathMC/227.json new file mode 100644 index 0000000000000000000000000000000000000000..4af2fd05e2e5c9ab01b42d5c92b16ba57dc6053a --- /dev/null +++ b/MathMC/227.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8000" + }, + { + "bullet": "B", + "text": "6000" + }, + { + "bullet": "C", + "text": "5000" + } + ], + "text": "398× 21的积大约是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "估算为400× 20=8000." + ] + } +} \ No newline at end of file diff --git a/MathMC/228.json b/MathMC/228.json new file mode 100644 index 0000000000000000000000000000000000000000..daa6fd6e79e2e702ccbfc2ba49d13a3f34426e3e --- /dev/null +++ b/MathMC/228.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16" + }, + { + "bullet": "B", + "text": "17" + }, + { + "bullet": "C", + "text": "18" + } + ], + "text": "做一套衣服用布2米，35米长的布最多可以做( )套这样的衣服. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用布的总长度35米除以每套衣服用的长度2米， 所得的商就是最多可以做的套数. 35÷ 2≈ 17(套). 答:35米长的布最多可以做17套这样的衣服. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/229.json b/MathMC/229.json new file mode 100644 index 0000000000000000000000000000000000000000..fe39c2f74d6eb3eee0a7b8406e530b2da4b6511d --- /dev/null +++ b/MathMC/229.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1000-100" + }, + { + "bullet": "B", + "text": "1000-999" + }, + { + "bullet": "C", + "text": "999-100" + }, + { + "bullet": "D", + "text": "999-99" + } + ], + "text": "最大的三位数比最小的三位数相差多少?算式是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意分析可知，最大的三位数是:999，最小的三位数是:100，求之间相差多少用减法，用最大的三位数减去最小的三位数即可，故列式为:999-100，故C正确. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/23.json b/MathMC/23.json new file mode 100644 index 0000000000000000000000000000000000000000..d0b1021a27ba38a16b77aa518695c84f4c9c7527 --- /dev/null +++ b/MathMC/23.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "故事书有多少本" + }, + { + "bullet": "B", + "text": "故事书比科技书多多少本" + }, + { + "bullet": "C", + "text": "科技书与故事书共有多少本" + } + ], + "text": "图书室有科技书200本，故事书比科技书多\\frac{7}{4}， ?若列式为200× \\frac{7}{4}，那么横线上应补充的问题是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "多的部分为\\frac{7}{4}，那么200× \\frac{7}{4}表示多的部分." + ] + } +} \ No newline at end of file diff --git a/MathMC/230.json b/MathMC/230.json new file mode 100644 index 0000000000000000000000000000000000000000..8acdd427188654642f9e0aaa98f7ffd5aad6e20b --- /dev/null +++ b/MathMC/230.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "圆的周长与它的半径之比是一个不变的常数" + }, + { + "bullet": "B", + "text": "圆的面积与它的半径之比是一个不变的常数" + }, + { + "bullet": "C", + "text": "圆周率是一个确定的值，它的准确值是π，它是一个无限不循环小数" + }, + { + "bullet": "D", + "text": "圆周率是一个确定的值，它的一个近似值是3.14" + } + ], + "text": "下列说法中，不正确的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "依据圆的周长与直径之间的关系，逐个进行分析，利用排除法即可得到正确答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/231.json b/MathMC/231.json new file mode 100644 index 0000000000000000000000000000000000000000..00063f4ff95a8d445ec692e5454f3a8c3ee30dd9 --- /dev/null +++ b/MathMC/231.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6.980" + }, + { + "bullet": "B", + "text": "6.979" + }, + { + "bullet": "C", + "text": "6.98" + } + ], + "text": "把6.9785精确到千分位是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据求一个小数的近似数的方法，利用‘四舍五入法‘，精确到千分位，看万分位上数的大小来确定是‘四舍‘还是‘五入‘;由此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/232.json b/MathMC/232.json new file mode 100644 index 0000000000000000000000000000000000000000..1e32d7c604ee427669f35ade5b762809874b734e --- /dev/null +++ b/MathMC/232.json @@ -0,0 +1,40 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{2}{3}÷(\\frac{2}{3}+\\frac{1}{2})=1+\\frac{2}{3}÷\\frac{1}{2}" + }, + { + "bullet": "B", + "text": "12÷\\frac{7}{8}×\\frac{8}{7}=12" + }, + { + "bullet": "C", + "text": "\\frac{2}{3}÷(\\frac{12}{13}÷\\frac{6}{7})=\\frac{2}{3}×\\frac{13}{12}×\\frac{7}{6}" + }, + { + "bullet": "D", + "text": "(\\frac{3}{5}+\\frac{7}{9})÷\\frac{21}{45}=\\frac{3}{5}×\\frac{45}{21}+\\frac{7}{9}÷\\frac{45}{21}" + }, + { + "bullet": "E", + "text": "\\frac{2}{3}÷(\\frac{2}{3}+\\frac{1}{2})=1+\\frac{2}{3}÷\\frac{1}{2}" + }, + { + "bullet": "F", + "text": "\\frac{2}{3}÷(\\frac{12}{13}÷\\frac{6}{7})=\\frac{2}{3}×\\frac{13}{12}×\\frac{7}{6}" + } + ], + "text": "下列运算过程正确的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据题意，先分析好每个选项中的运算顺序，然后再进一步解答. 试题解析:A和E、\\frac{2}{3}÷(\\frac{2}{3}+\\frac{1}{2})先算加法，再算除法，而原题是先算了除法，再算加法，所以错; B、12÷\\frac{7}{8}×\\frac{8}{7}，先算除法，再算乘法，而原题先算了乘法，再算除法，所以错; C和F、\\frac{2}{3}÷(\\frac{12}{13}÷\\frac{6}{7})，先算小括号里面的除法，再算小括号里面的除法，原题先算了括号外面的除法，所以错; D、根据分数除法的计算方法，除以一个非零的数等于乘这个数的倒数，即: (\\frac{3}{5}+\\frac{7}{9})÷\\frac{21}{45} =(\\frac{3}{5}+\\frac{7}{9})×\\frac{45}{21} =\\frac{3}{5}×\\frac{45}{21}+\\frac{7}{9}×\\frac{45}{21}; 而\\frac{3}{5}×\\frac{45}{21}+\\frac{7}{9}÷\\frac{45}{21}=\\frac{3}{5}×\\frac{45}{21}+\\frac{7}{9}×\\frac{45}{21}; 所以，D选项的过程是正确的. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/233.json b/MathMC/233.json new file mode 100644 index 0000000000000000000000000000000000000000..72c0aa2b63b6864085df406570f7c157e498a827 --- /dev/null +++ b/MathMC/233.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "分米" + }, + { + "bullet": "B", + "text": "厘米" + }, + { + "bullet": "C", + "text": "米" + } + ], + "text": "教室门高约2( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "门应该比人的个子要高，所以填米合适，选C。考察长度及长度的常用单位。" + ] + } +} \ No newline at end of file diff --git a/MathMC/234.json b/MathMC/234.json new file mode 100644 index 0000000000000000000000000000000000000000..1eb336259af5665f5065ec1c9069b134e7fa3ca8 --- /dev/null +++ b/MathMC/234.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "时间" + }, + { + "bullet": "B", + "text": "路程" + }, + { + "bullet": "C", + "text": "速度" + } + ], + "text": "一辆汽车5个小时行了214千米，平均每小时行多少千米?是求( )的题目. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "5个小时行了214千米，5小时是时间，214千米是路程，平均每小时行多少千米是速度，所以本题是求速度，用路程除以时间即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/235.json b/MathMC/235.json new file mode 100644 index 0000000000000000000000000000000000000000..d417b7bf810e5c440a42c8ad500c13e0f581e140 --- /dev/null +++ b/MathMC/235.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "毫米" + }, + { + "bullet": "B", + "text": "厘米" + }, + { + "bullet": "C", + "text": "分米" + } + ], + "text": "小军的身高是145( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据生活经验、对长度单位大小的认识和数据的大小，可知计量小军的身高可用‘厘米‘做单位，是145厘米;据此进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/236.json b/MathMC/236.json new file mode 100644 index 0000000000000000000000000000000000000000..6fff82ebe6da8d3556aae59e74b416c7386224f1 --- /dev/null +++ b/MathMC/236.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6.5÷0.125" + }, + { + "bullet": "B", + "text": "6.5÷12.5" + }, + { + "bullet": "C", + "text": "6.5÷1.25" + } + ], + "text": "下面各算式中，商最大的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "观察三个算式发现被除数都是6.5，只是除数不同，要比较哪一个算式的商最大，可比较除数的大小，除数最小的算式其商最大，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/237.json b/MathMC/237.json new file mode 100644 index 0000000000000000000000000000000000000000..133f61ac84b181be3a49b29cb1f5302423d6f65c --- /dev/null +++ b/MathMC/237.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一千万" + }, + { + "bullet": "B", + "text": "一亿" + }, + { + "bullet": "C", + "text": "十亿" + } + ], + "text": "从一百万开始，一百万一百万地数，数100次是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据十进制计数法，每相邻的两个计数单位间的进率是‘十‘." + ] + } +} \ No newline at end of file diff --git a/MathMC/238.json b/MathMC/238.json new file mode 100644 index 0000000000000000000000000000000000000000..06fc62c2ee086a080bdcaa31d2aabafce48c15bd --- /dev/null +++ b/MathMC/238.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2分米" + }, + { + "bullet": "B", + "text": "3分米" + }, + { + "bullet": "C", + "text": "4分米" + }, + { + "bullet": "D", + "text": "9分米" + } + ], + "text": "表面积是54 dm2 的正方体，它的棱长是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "知道正方体的表面积是正方体6个面的面积的和，正方体的表面积=棱长×棱长×6，本题中，已知正方体的表面积是54平方分米，用54除以6求出一个面的面积，然后求出棱长是多少." + ] + } +} \ No newline at end of file diff --git a/MathMC/239.json b/MathMC/239.json new file mode 100644 index 0000000000000000000000000000000000000000..aee06149bbca3d3a4df6ed04a998c659065ab3d0 --- /dev/null +++ b/MathMC/239.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{b-a}{ab}" + }, + { + "bullet": "B", + "text": "\\frac{b-a}{a}" + }, + { + "bullet": "C", + "text": "\\frac{a-b}{b}" + }, + { + "bullet": "D", + "text": "0" + } + ], + "text": "\\frac{1}{a}-\\frac{1}{b}=( )(a、b均不为0，且公因数只有1) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "\\frac{1}{a}-\\frac{1}{b}=\\frac{b-a}{ab}. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/24.json b/MathMC/24.json new file mode 100644 index 0000000000000000000000000000000000000000..84de53be53bd2779b5fd87c9d88cd1b640672e91 --- /dev/null +++ b/MathMC/24.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "A、B两只青蛙进行跳跃比赛，A青蛙每次跳8厘米，B青蛙每次跳10厘米，它们一起从起点开始跳，且每秒都只跳一次。在比赛中，每隔12厘米有一个陷阱，当它们中第一只掉进陷阱时，另一只距离最近的陷阱有（ ）厘米" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题根据求最小公倍数的方法解题，10与12的最小公倍数是60，15和12的最小公倍数也是60.B每次跳的远些，所以先掉进陷阱，当B掉进陷阱时，A跳到10×(60÷15)=40厘米处，此时距离最近的陷阱有40-12×3=4(厘米)." + ] + } +} \ No newline at end of file diff --git a/MathMC/240.json b/MathMC/240.json new file mode 100644 index 0000000000000000000000000000000000000000..0b84c7ca0e18c79a82225059bdbf408438eb250f --- /dev/null +++ b/MathMC/240.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "一个数除以5，如果有余数，那么余数可能是 . " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "本题考余数的可能值" + ] + } +} \ No newline at end of file diff --git a/MathMC/241.json b/MathMC/241.json new file mode 100644 index 0000000000000000000000000000000000000000..2e0e448ecce1e6ef433bc7ac2f3490c8bc01d666 --- /dev/null +++ b/MathMC/241.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "五(1)班有多少人" + }, + { + "bullet": "B", + "text": "全年级有多少人" + }, + { + "bullet": "C", + "text": "全年级女生有多少人" + }, + { + "bullet": "D", + "text": "五(1)班男生有多少人" + } + ], + "text": "五(1)班的女生25人，比全年级人数少 \\frac{7}{8}，根据条件，可选择的问题是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据条件，可选择的问题是全年级有多少人?把全年级的人数看做单位‘1‘，单位‘1‘的量是未知的，此题是已知单位‘1‘的 (1- \\frac{7}{8})是25人，求单位‘1‘的量，用除法计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/242.json b/MathMC/242.json new file mode 100644 index 0000000000000000000000000000000000000000..6513db6b455208919960e6fcd35879c6f67e92b5 --- /dev/null +++ b/MathMC/242.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16.66" + }, + { + "bullet": "B", + "text": "17" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "16.5" + } + ], + "text": "每个礼盒要用1.5米的丝带包装，25米长的丝带可以包装( )个这样的礼盒. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据除法的意义，用丝带的总长度除以包装每个礼盒需要的长度，即可求出可以包装礼盒的个数." + ] + } +} \ No newline at end of file diff --git a/MathMC/243.json b/MathMC/243.json new file mode 100644 index 0000000000000000000000000000000000000000..a2f90fd874ea36d9f00875b31657979489544b90 --- /dev/null +++ b/MathMC/243.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "m只能是1" + }, + { + "bullet": "B", + "text": "m只能是3" + }, + { + "bullet": "C", + "text": "m只能是13" + }, + { + "bullet": "D", + "text": "m是1或13" + } + ], + "text": "已知m是13的因数，那么 ( )。" + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "列乘法算式13×1=13，所以13的因数有1和13，所以m既可能是1也可能是13，因此本题选D。" + ] + } +} \ No newline at end of file diff --git a/MathMC/244.json b/MathMC/244.json new file mode 100644 index 0000000000000000000000000000000000000000..d3a400bff128419e16b072ad4461e8fd7042a0be --- /dev/null +++ b/MathMC/244.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "缩小到原数的" + }, + { + "bullet": "B", + "text": "缩小到原数的" + }, + { + "bullet": "C", + "text": "扩大到原数的100倍" + }, + { + "bullet": "D", + "text": "扩大到原数的10倍、" + } + ], + "text": "在15的后面添上‘%‘所得的数就( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "在15的后面添上‘%‘，原数变成15%(即0.15)，也就是把原数的小数点向左移动两位，因此所得的数就缩小到原来的." + ] + } +} \ No newline at end of file diff --git a/MathMC/245.json b/MathMC/245.json new file mode 100644 index 0000000000000000000000000000000000000000..8294368b0e031b3db44798fe75190683c2ac6e90 --- /dev/null +++ b/MathMC/245.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "500-4a" + }, + { + "bullet": "B", + "text": "500-4(a-40)" + }, + { + "bullet": "C", + "text": "500-2a-2(a-40)" + } + ], + "text": "聪聪和爸爸、妈妈、妹妹去游乐园玩，成人票每张a元，儿童票每张(a-40)元。妈妈买门票时付了500元，那么找回的钱数用含有字母的式子表示为 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，聪聪和妹妹买的是儿童票，爸爸和妈妈买的是成人票，所以找回的钱数=付的钱数-2张儿童票的价格-2张成人票的价格。用a表示成人票价，用(a-40)表示儿童票价，所以找回的钱数用含有字母的式子表示为500-2a-2(a-40)。所以应选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/246.json b/MathMC/246.json new file mode 100644 index 0000000000000000000000000000000000000000..0b384c7f7defd38be72570c9d6e3c4c65da80189 --- /dev/null +++ b/MathMC/246.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{7}{8}× 3" + }, + { + "bullet": "B", + "text": "\\frac{7}{8}× 8÷ ( 3× 8 )" + }, + { + "bullet": "C", + "text": "\\frac{7}{8}× \\frac{1}{3}" + }, + { + "bullet": "D", + "text": "\\frac{7÷ 3}{8}" + } + ], + "text": "要计算\\frac{7}{8}÷ 3，下面算式中不正确的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "解: A，\\frac{7}{8}× 3=\\frac{21}{8} B，根据除法的性质可知，一个数除以两个数的积，等于用这个数分别除以这两个数，则: \\frac{7}{8}× 8÷ ( 3× 8 )=\\frac{7}{8}× 8÷ 8÷ 3=\\frac{7}{8}÷ 3; C，一个数除以一个非零的数，等于乘这个数的倒数，则\\frac{7}{8}÷ 3=\\frac{7}{8}× \\frac{1}{3}; D，\\frac{7}{8}÷ 3=\\frac{7÷ 3}{8}. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/247.json b/MathMC/247.json new file mode 100644 index 0000000000000000000000000000000000000000..c12e4963d873f0a7025d0c5140518def671c0bb3 --- /dev/null +++ b/MathMC/247.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "b一定大于a" + }, + { + "bullet": "B", + "text": "b可能大于a" + }, + { + "bullet": "C", + "text": "b一定小于a" + } + ], + "text": "a÷0.99=b(b≠0)，那么( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据式子的特点可以发现，除数是0.99，小于1，又因为b≠0，所以b大于a，据此即可做出选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/248.json b/MathMC/248.json new file mode 100644 index 0000000000000000000000000000000000000000..5a75368f8732cd6bbbef8a78a6c80431f949c73c --- /dev/null +++ b/MathMC/248.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "180-2a" + }, + { + "bullet": "B", + "text": "(180-a)÷2" + }, + { + "bullet": "C", + "text": "180÷2-a" + } + ], + "text": "一个等腰三角形顶角的度数是a，下面哪个式子是计算一个底角的度数?( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由已知条件根据三角形内角和定理和等腰三角形的性质结合题干给出的条件求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/249.json b/MathMC/249.json new file mode 100644 index 0000000000000000000000000000000000000000..28aa138fa8675b76d2e14d6ce7ac595f5facc65b --- /dev/null +++ b/MathMC/249.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60千克" + }, + { + "bullet": "B", + "text": "600千克" + }, + { + "bullet": "C", + "text": "6吨" + }, + { + "bullet": "D", + "text": "60吨" + } + ], + "text": "一枚1元的硬币大约重6克，照这样推算，1000枚1元的硬币大约重6千克，100万枚1元的硬币大约重( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因照这样计算，说明一枚1元的硬币大约重6克，100万枚枚硬币有多重，用乘法解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/25.json b/MathMC/25.json new file mode 100644 index 0000000000000000000000000000000000000000..b29b8362a21c2048ff1898cad93f28608c3c27fa --- /dev/null +++ b/MathMC/25.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "24" + } + ], + "text": "一个平行四边形与三角形的面积和高相等.如果三角形的底是12厘米，那么平行四边形的底是( )厘米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据平行四边形的面积=底×高，三角形的面积=底×高÷2，根据题意面积和高相等，则平行四边形的底是三角形底的一半，用12÷2可解." + ] + } +} \ No newline at end of file diff --git a/MathMC/250.json b/MathMC/250.json new file mode 100644 index 0000000000000000000000000000000000000000..506d8d3e0af79f4cabf81c4d6ad8e170f057d541 --- /dev/null +++ b/MathMC/250.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "单式条形" + }, + { + "bullet": "B", + "text": "复式条形" + }, + { + "bullet": "C", + "text": "单式折线" + }, + { + "bullet": "D", + "text": "复式折线" + } + ], + "text": "为了清楚地反映北京和南京两城市2016年下半年平均气温的变化情况，最好选用( )统计图. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;为了清楚地反映北京市和南京市两地2016年每月平均气温的变化情况，需要容易看出数量的多少，而且能反映数量的增减变化情况，应选用复式折线统计图.根据统计图的特点可知:为了清楚地反映北京市和南京市两地2016年每月平均气温的变化情况，应选用复式折线统计图. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/251.json b/MathMC/251.json new file mode 100644 index 0000000000000000000000000000000000000000..b9242523799847be18f64f021d09ef57d74b1d1f --- /dev/null +++ b/MathMC/251.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "13" + }, + { + "bullet": "C", + "text": "23" + }, + { + "bullet": "D", + "text": "123" + } + ], + "text": "如果ab>0，a+b<0 ，那么下面各式:1 \\sqrt {\\frac{a}{b}}. \\sqrt {\\frac{b}{a}}=1;2 \\sqrt {\\frac{a}{b}}= \\frac{\\sqrt{a}}{\\sqrt{b}};3 \\sqrt{ab}÷ \\sqrt {\\frac{a}{b}}=-b，其中正确的是 ( )" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "解:∵ab>0，a+b<0， ∴a<0，b<0 ∴1 \\sqrt {\\frac{a}{b}}. \\sqrt {\\frac{b}{a}}=1，正确;2 \\sqrt {\\frac{a}{b}}= \\frac{\\sqrt{a}}{\\sqrt{b}}，错误;3 \\sqrt{ab}÷ \\sqrt {\\frac{a}{b}}=-b，正确， 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/252.json b/MathMC/252.json new file mode 100644 index 0000000000000000000000000000000000000000..50555a7a5754ef5d43f20c2d1a5256c6ce644d0f --- /dev/null +++ b/MathMC/252.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "复式统计表" + }, + { + "bullet": "B", + "text": "复式条形统计图" + }, + { + "bullet": "C", + "text": "复式拆线统计图" + } + ], + "text": "要清楚地表示两城市一年中各月平均气温升降变化情况，应绘制( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/253.json b/MathMC/253.json new file mode 100644 index 0000000000000000000000000000000000000000..602fa0f5ca7b653fb16ecf76f2052874303c68ee --- /dev/null +++ b/MathMC/253.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "3" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "要使6□48÷8的商的中间有一个0，□里应该填( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "通过读题分析，除数是8，被除数的最高位是6，也就是说最高位不够除，就要看前两位，要想中间有0，那么十位上就不能比8大，也就是说百位上不能有余数，所以只能填4." + ] + } +} \ No newline at end of file diff --git a/MathMC/254.json b/MathMC/254.json new file mode 100644 index 0000000000000000000000000000000000000000..77cb43bb440fdf49addabc1166ec1e4706186174 --- /dev/null +++ b/MathMC/254.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100000、100001" + }, + { + "bullet": "B", + "text": "90000、100000" + }, + { + "bullet": "C", + "text": "99999、100001" + } + ], + "text": "下面的数与100000相邻的两个数是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "与100000相邻，则可以计算100000分别加1、减1得出的即为答案，100000+1=100001，100000-1=99999. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/255.json b/MathMC/255.json new file mode 100644 index 0000000000000000000000000000000000000000..4443d886c04f140b825f0be2518c22706aa12298 --- /dev/null +++ b/MathMC/255.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20克" + }, + { + "bullet": "B", + "text": "200克" + }, + { + "bullet": "C", + "text": "2千克" + } + ], + "text": "一个汉堡包大约重( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据情景根据生活经验，对质量单位和数据大小的认识，可知一个汉堡包大约重200克." + ] + } +} \ No newline at end of file diff --git a/MathMC/256.json b/MathMC/256.json new file mode 100644 index 0000000000000000000000000000000000000000..a25b3580cc96343c6d31a443eca8fbe837c68799 --- /dev/null +++ b/MathMC/256.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3个" + }, + { + "bullet": "B", + "text": "8个" + }, + { + "bullet": "C", + "text": "6个" + } + ], + "text": "已知m=3×5×7，那么m的因数有( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "M的因数包括1和它的质因数，以及质因数相乘的积." + ] + } +} \ No newline at end of file diff --git a/MathMC/257.json b/MathMC/257.json new file mode 100644 index 0000000000000000000000000000000000000000..a32137d97900ee90edc8b24d4c54d303916632e0 --- /dev/null +++ b/MathMC/257.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少" + }, + { + "bullet": "B", + "text": "增加" + }, + { + "bullet": "C", + "text": "不变" + }, + { + "bullet": "D", + "text": "不确定" + } + ], + "text": "一张长10厘米，宽6厘米的纸，如果它的四个角各剪去一个边长是2厘米的正方形，剩下的纸片的周长与原长方形周长比( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "如下图，运用平移的方法，即可得出后来的周长与原来的周长的关系. 如上图，因为剪去一个小正方形ABCD后，剪掉了AB与AC的长度，但又多出了BD与CD的长度，并且AB=CD=BD=AC， 同样在其它的三个角剪正方形也是这样的， 所以后来图形的周长与原来的周长相等，即为( 10+6 )× 2=32(厘米) 答:剩下的纸片的周长与原长方形周长比不变. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/258.json b/MathMC/258.json new file mode 100644 index 0000000000000000000000000000000000000000..69821f3f46af92a278241826c0c25af8e7f06595 --- /dev/null +++ b/MathMC/258.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "现价是原价的80%" + }, + { + "bullet": "B", + "text": "现价比原价少80%" + }, + { + "bullet": "C", + "text": "现价比原价多80%" + } + ], + "text": "一件商品打八折出售，就是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "打几折就是按原价的百分之几十出售，打几几折就是按原价的百分之几十几出售;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/259.json b/MathMC/259.json new file mode 100644 index 0000000000000000000000000000000000000000..830c897e24eaaca2e869756945fd72c37cca8834 --- /dev/null +++ b/MathMC/259.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "百万位和千万位" + }, + { + "bullet": "B", + "text": "千万位和亿位" + }, + { + "bullet": "C", + "text": "千万位和十亿位" + }, + { + "bullet": "D", + "text": "亿位和十亿位" + } + ], + "text": "和亿位相邻的两个数位分别是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据数位顺序表:从右向左依次分:个位、十位、百位、千位、万位、十万位、百万位、千万位、亿位、十亿位、…;可知:与亿位相邻的两个数位是十亿位和千万位;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/26.json b/MathMC/26.json new file mode 100644 index 0000000000000000000000000000000000000000..5f394b80db232cc76ba66c1523a91931de108a3f --- /dev/null +++ b/MathMC/26.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2×3×5×7" + }, + { + "bullet": "B", + "text": "2×3" + }, + { + "bullet": "C", + "text": "3×5" + } + ], + "text": "将A、B分解质因数，A=2×3×5，B=7×3×2，那么AB的最大公因数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据求两个数最大公约数也就是这两个数的公有质因数的连乘积即可得到结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/260.json b/MathMC/260.json new file mode 100644 index 0000000000000000000000000000000000000000..77e6aa4e16988194bf4e9efdc156b76be9352d84 --- /dev/null +++ b/MathMC/260.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "北偏西30°方向，距离是2000米" + }, + { + "bullet": "B", + "text": "西偏南30°方向，距离是2000米" + }, + { + "bullet": "C", + "text": "东偏南30°方向，距离是2000米" + } + ], + "text": "甲地在乙地东偏北30°方向，距离是2000米，则乙地在甲地的( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据位置的相对性可知，它们的方向相反，角度相等，距离不变，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/261.json b/MathMC/261.json new file mode 100644 index 0000000000000000000000000000000000000000..f1c55fe5382ece87d716d8380af8091ebc01b1b9 --- /dev/null +++ b/MathMC/261.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9" + }, + { + "bullet": "B", + "text": "10" + }, + { + "bullet": "C", + "text": "14" + }, + { + "bullet": "D", + "text": "16" + } + ], + "text": "将一根木棒锯成4段需要6分钟，则将这根木棒锯成6段需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先明确锯4段需要锯3次，锯6段需要锯5次，根据锯成4段需要6分钟计算出锯1次需要几分钟，再计算出锯6段用的时间即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/262.json b/MathMC/262.json new file mode 100644 index 0000000000000000000000000000000000000000..e9287794c6c9177ac9fe91be5b8efeec30cf7529 --- /dev/null +++ b/MathMC/262.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12的因数只有5个" + }, + { + "bullet": "B", + "text": "7的倍数只有7，14，21，28，35" + }, + { + "bullet": "C", + "text": "32是32的因数，也是4的倍数" + }, + { + "bullet": "D", + "text": "一个数的因数的个数是无限的" + } + ], + "text": "下面的说法中，正确的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "通过列乘法算式可以找出12的因数有6个.一个数的因数的个数是有限的，倍数的个数是无限的." + ] + } +} \ No newline at end of file diff --git a/MathMC/263.json b/MathMC/263.json new file mode 100644 index 0000000000000000000000000000000000000000..471a93a5ba230482f409142572a46db37ca61c9e --- /dev/null +++ b/MathMC/263.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{11}" + }, + { + "bullet": "B", + "text": "\\frac{1}{10}" + }, + { + "bullet": "C", + "text": "\\frac{1}{9}" + }, + { + "bullet": "D", + "text": "\\frac{10}{11}" + } + ], + "text": "在100克水里加入10克盐，那么盐的重量是盐水的( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "先求出盐水的总重量，然后用食盐的重量除以盐水的总重量即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/264.json b/MathMC/264.json new file mode 100644 index 0000000000000000000000000000000000000000..b9d04f7022e1f0ea07017023e7da23f9becfe4c1 --- /dev/null +++ b/MathMC/264.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "跑5千米" + }, + { + "bullet": "B", + "text": "写一篇400字的作文" + }, + { + "bullet": "C", + "text": "做20道口算题" + } + ], + "text": "1分钟内我们可以做完的事情是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "此题考查根据情景选择合适的计量单位，要注意联系生活实际、计量单位和数据的大小，灵活的选择. 1、首先明确时间中，时、分、秒的意义，1分钟=60秒; 2、再根据生活经验、对时间单位和数据大小的认识判断1分钟能否做完题目的事情; 3、依次分析各选项即可得解. A、跑1000米，1分钟不可能; B、写一篇400字的作文，1分钟不可能; C、做20道口算题，1分钟可以; 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/265.json b/MathMC/265.json new file mode 100644 index 0000000000000000000000000000000000000000..193b77329638ac846002b4725be8207c9dfb01ff --- /dev/null +++ b/MathMC/265.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:10" + }, + { + "bullet": "B", + "text": "1:9" + }, + { + "bullet": "C", + "text": "10:1" + }, + { + "bullet": "D", + "text": "9:1" + } + ], + "text": "一瓶药水，药的质量占药水的10%，药与水的比是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把药水是质量看作单位‘1‘，药的质量占药水的10%，则水占药水的(1-10%)，进而根据题意，求出药和药水的比." + ] + } +} \ No newline at end of file diff --git a/MathMC/266.json b/MathMC/266.json new file mode 100644 index 0000000000000000000000000000000000000000..9a2e0bf0dd4e67d60d270cf18aa8f119af0f9504 --- /dev/null +++ b/MathMC/266.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1 300" + }, + { + "bullet": "B", + "text": "500" + }, + { + "bullet": "C", + "text": "400" + } + ], + "text": "小华和小青同在学校的西面，小华家离学校400米，小青家离学校900米，她们两家相距( )米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "两人都在学校西面，因此距离为(900-400)米" + ] + } +} \ No newline at end of file diff --git a/MathMC/267.json b/MathMC/267.json new file mode 100644 index 0000000000000000000000000000000000000000..c9f24b4c08a31d576ad24d76d1d16ea7f997a951 --- /dev/null +++ b/MathMC/267.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形" + }, + { + "bullet": "B", + "text": "平行四边形" + }, + { + "bullet": "C", + "text": "三角形" + } + ], + "text": "两个完全一样的梯形不可能拼成的图形是 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据梯形，平行四边形、长方形、三角形的特征判断" + ] + } +} \ No newline at end of file diff --git a/MathMC/268.json b/MathMC/268.json new file mode 100644 index 0000000000000000000000000000000000000000..5b547f6953eac4eae965f06aeced25810064a1c6 --- /dev/null +++ b/MathMC/268.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "+3" + }, + { + "bullet": "B", + "text": "+10" + }, + { + "bullet": "C", + "text": "-100" + } + ], + "text": "下列各数中，小于0的数是 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "比0小的数为负数" + ] + } +} \ No newline at end of file diff --git a/MathMC/269.json b/MathMC/269.json new file mode 100644 index 0000000000000000000000000000000000000000..61e8df6faf3b64f0019e61cd2a99a11131c3ff8a --- /dev/null +++ b/MathMC/269.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{2}{5}" + }, + { + "bullet": "B", + "text": "0" + }, + { + "bullet": "C", + "text": "\\frac{4}{7}" + } + ], + "text": "\\frac{2}{5}+\\frac{2}{7}-\\frac{2}{5}+\\frac{2}{7}的结果是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + ":\\frac{2}{5}+\\frac{2}{7}-\\frac{2}{5}+\\frac{2}{7}， =\\frac{2}{5}-\\frac{2}{5}+\\frac{2}{7}+\\frac{2}{7}， =\\frac{2}{7}+\\frac{2}{7}， =\\frac{4}{7}. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/27.json b/MathMC/27.json new file mode 100644 index 0000000000000000000000000000000000000000..a28f9dcd2a8d17cb3122de2888bb5998fa535e06 --- /dev/null +++ b/MathMC/27.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "850200" + }, + { + "bullet": "B", + "text": "849820" + }, + { + "bullet": "C", + "text": "850099" + }, + { + "bullet": "D", + "text": "854590" + } + ], + "text": "下面各数中，‘四舍五入‘后都得到85万，其中( )最接近85万. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，分别求出下面各数与85万的差，然后比较它们的差，差最小的就是最接近85万的数." + ] + } +} \ No newline at end of file diff --git a/MathMC/270.json b/MathMC/270.json new file mode 100644 index 0000000000000000000000000000000000000000..3a501905e60c38b52e19996e69b9e3a4c35e1e11 --- /dev/null +++ b/MathMC/270.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扇形统计图" + }, + { + "bullet": "B", + "text": "折线统计图" + }, + { + "bullet": "C", + "text": "条形统计图" + } + ], + "text": "要表示数量增减变化的情况，用( )比较适合. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "扇形统计图可以比较清楚反映出部分与部分，部分与整体之间的数量关系. 折线统计图用来表示统计数量的增减变化. 条形统计图可以看出各个数据的大小，易于比较数据之间的差别. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/271.json b/MathMC/271.json new file mode 100644 index 0000000000000000000000000000000000000000..e79b325861c8b4014f20e8e8c1dfa4223d758ca5 --- /dev/null +++ b/MathMC/271.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "25" + }, + { + "bullet": "C", + "text": "250" + }, + { + "bullet": "D", + "text": "2500" + } + ], + "text": "把50升一大瓶的药水，分装在20毫升的小瓶中，可以装( )瓶. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据除法的意义，50升=50000毫升，除以每小瓶的容量即得可以装多少小瓶;" + ] + } +} \ No newline at end of file diff --git a/MathMC/272.json b/MathMC/272.json new file mode 100644 index 0000000000000000000000000000000000000000..ab0b88a24a6b8b711465b9e67fd1dbb5257cdc96 --- /dev/null +++ b/MathMC/272.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小红" + }, + { + "bullet": "B", + "text": "小明" + }, + { + "bullet": "C", + "text": "小强" + } + ], + "text": "小红、小明、小强做同一张口算题卡，小红用了30秒，小明用了22秒，小强用了18秒.( )做得最快. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "三个人做同一张口算题卡，用的时间最少的人做的速度最快，所以小强最快. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/273.json b/MathMC/273.json new file mode 100644 index 0000000000000000000000000000000000000000..7b894f4a83296af73b029a42e17736c2c6e3466b --- /dev/null +++ b/MathMC/273.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "千米" + }, + { + "bullet": "B", + "text": "千克" + }, + { + "bullet": "C", + "text": "t" + }, + { + "bullet": "D", + "text": "L" + } + ], + "text": "在一座桥梁旁，有一块大桥限重的交通标志牌，被空中的飞鸟遮挡的字母应该是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在一座桥梁旁，有地块限重的交通标志牌.被空中的飞鸟遮挡的字母应该是10吨." + ] + } +} \ No newline at end of file diff --git a/MathMC/274.json b/MathMC/274.json new file mode 100644 index 0000000000000000000000000000000000000000..a251931c161b61dc9b14ce33ca76fe3de29b0e8a --- /dev/null +++ b/MathMC/274.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6010040" + }, + { + "bullet": "B", + "text": "6104000" + }, + { + "bullet": "C", + "text": "6001004" + } + ], + "text": "下面各数中，读出两个零的数是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据整数的读法，从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，读出各数再作选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/275.json b/MathMC/275.json new file mode 100644 index 0000000000000000000000000000000000000000..3dccf1b4f76734b37ca78f025f7219deafa5a96d --- /dev/null +++ b/MathMC/275.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于90度" + }, + { + "bullet": "B", + "text": "小于90度" + }, + { + "bullet": "C", + "text": "大于90度而小于180度" + } + ], + "text": "钝角是 的角. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据钝角的定义，钝角是大于90°而小于180°的角." + ] + } +} \ No newline at end of file diff --git a/MathMC/276.json b/MathMC/276.json new file mode 100644 index 0000000000000000000000000000000000000000..caddc9829fc9c7bffd75d48765a710eb53662f7e --- /dev/null +++ b/MathMC/276.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{5}{4}" + }, + { + "bullet": "B", + "text": "\\frac{4}{5}" + }, + { + "bullet": "C", + "text": "\\frac{5}{9}" + }, + { + "bullet": "D", + "text": "\\frac{9}{4}" + } + ], + "text": "如果甲数是甲、乙两数和的\\frac{4}{9}，那么甲数是乙数的( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "可以将甲看成是4份，则甲、乙两数和为9份，乙为5份，甲数是乙数的4÷ 5=\\frac{4}{5}." + ] + } +} \ No newline at end of file diff --git a/MathMC/277.json b/MathMC/277.json new file mode 100644 index 0000000000000000000000000000000000000000..0e2076f69b3f5534e935e31fa9de1c9eb8cc18ca --- /dev/null +++ b/MathMC/277.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "8" + } + ], + "text": "最小的质数乘最小的合数，积是 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "1不是质数也不是合数，依照定义即可得出." + ] + } +} \ No newline at end of file diff --git a/MathMC/278.json b/MathMC/278.json new file mode 100644 index 0000000000000000000000000000000000000000..764dfb95ec9c5c1390a433f37a8529d9c8400483 --- /dev/null +++ b/MathMC/278.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10厘米" + }, + { + "bullet": "B", + "text": "6厘米" + }, + { + "bullet": "C", + "text": "4厘米" + }, + { + "bullet": "D", + "text": "2厘米" + } + ], + "text": "奇思有三根小棒，长度分别是6厘米、4厘米、6厘米，再选一根( )长的小棒才能拼成一个长方形. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "长方形有2条一样的长，和2条一样的宽，已经有2个6厘米和1个4厘米了，还差1个4厘米. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/279.json b/MathMC/279.json new file mode 100644 index 0000000000000000000000000000000000000000..ecc189ff49d4b79161e59b23127c1359d739bff5 --- /dev/null +++ b/MathMC/279.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "10" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "15" + } + ], + "text": "两根小棒的长分别是5厘米、10厘米、再有一根( )厘米的小棒就可以围成一个三角形. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据三角形的特性:两边之和大于第三边，三角形的两边的差一定小于第三边;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/28.json b/MathMC/28.json new file mode 100644 index 0000000000000000000000000000000000000000..743ed02e0600f7ea2b22e190d659f9f40fbf7056 --- /dev/null +++ b/MathMC/28.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12 m" + }, + { + "bullet": "B", + "text": "6 m" + }, + { + "bullet": "C", + "text": "3 m" + } + ], + "text": "一个三角形和一个平行四边形面积相等，底也相等.三角形的高是6 m，平行四边形的高是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "三角形和平行四边形底相等，面积也相等，三角形的高是平行四边形的高的2倍，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/280.json b/MathMC/280.json new file mode 100644 index 0000000000000000000000000000000000000000..f4069a204aada1ae54c1c156e1e0ad417164e000 --- /dev/null +++ b/MathMC/280.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5是因数" + }, + { + "bullet": "B", + "text": "7是因数" + }, + { + "bullet": "C", + "text": "35是倍数" + }, + { + "bullet": "D", + "text": "5是35的因数" + } + ], + "text": "对于乘法算式5×7=35，下面的说法中，正确的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "因数和倍数是相对的，是相互依存的，不能单独存在，只能说一个数是另一个数的倍数或另一个数是这个数的因数;据此判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/281.json b/MathMC/281.json new file mode 100644 index 0000000000000000000000000000000000000000..f137b592d3723100cbd593da895d312712fb0fca --- /dev/null +++ b/MathMC/281.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "六(1)班有多少人" + }, + { + "bullet": "B", + "text": "全年级有多少人" + }, + { + "bullet": "C", + "text": "全年级女生有多少人" + }, + { + "bullet": "D", + "text": "六(1)班有男生多少人" + } + ], + "text": "六(1)班有女生25人，比全年级人数少\\frac{7}{8}，根据条件，可提出的问题是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题中条件只能算出全年级的人数. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/282.json b/MathMC/282.json new file mode 100644 index 0000000000000000000000000000000000000000..8ff5199c64b3dc405c90e1e43ebc07907674f673 --- /dev/null +++ b/MathMC/282.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "1000" + }, + { + "bullet": "C", + "text": "10000" + } + ], + "text": "比999多1的数是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "此题是考查学生对于加法意义的认识情况，比999多1的数就是999加上1等于1 000，B答案符合题意，计算时一定要细心." + ] + } +} \ No newline at end of file diff --git a/MathMC/283.json b/MathMC/283.json new file mode 100644 index 0000000000000000000000000000000000000000..0cef7aa83387006c1deba42543c88867fdf12a28 --- /dev/null +++ b/MathMC/283.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8060" + }, + { + "bullet": "B", + "text": "8600" + }, + { + "bullet": "C", + "text": "8006" + } + ], + "text": "由8个千和6个十组成的数是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "因为由题干可知，该数千位是8，十位是6，其余位为0，所以该数为8060. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/284.json b/MathMC/284.json new file mode 100644 index 0000000000000000000000000000000000000000..fc5ef31a5a923eba77d15fb8d802cd4e6dadc914 --- /dev/null +++ b/MathMC/284.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "7" + }, + { + "bullet": "D", + "text": "8" + } + ], + "text": "王东用一个骰子玩掷骰子游戏，要保证掷出的点数至少有两次相同，他最少掷( )次. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "骰子能掷出的结果只有6种，掷7次的话必有2次相同;即把骰子的出现的六种情况看作‘抽屉‘，把掷出的次数看作‘物体的个数‘，要保证至少有两次相同，那么物体个数应比抽屉数至少多1;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/285.json b/MathMC/285.json new file mode 100644 index 0000000000000000000000000000000000000000..c377a0e0fba4de1d97de5b0d5681da3ed65a5d0e --- /dev/null +++ b/MathMC/285.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a+ \\frac{1}{8}" + }, + { + "bullet": "B", + "text": "\\frac{1}{8}=a+b" + }, + { + "bullet": "C", + "text": "\\frac{1}{8}a+b" + } + ], + "text": "a与b的和是 \\frac{1}{8}，用式子表示是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为a与b的和，即a+b，是 \\frac{1}{8}，即a+b= \\frac{1}{8}，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/286.json b/MathMC/286.json new file mode 100644 index 0000000000000000000000000000000000000000..41b163147feb7f1b7402c9b399a3eefb49025293 --- /dev/null +++ b/MathMC/286.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "一个数除以( )余数只可能是1( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在一个有余数的除法算式中，余数要比除数小，余数不能大于或等于除数，这里余数只能是1的除数就是2;据此可以解题." + ] + } +} \ No newline at end of file diff --git a/MathMC/287.json b/MathMC/287.json new file mode 100644 index 0000000000000000000000000000000000000000..eef5cbf56130be0499644d0b3518f0b84d36d6ed --- /dev/null +++ b/MathMC/287.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "最高气温是零下7摄氏度，最低气温2摄氏度" + }, + { + "bullet": "B", + "text": "最高气温是负7摄氏度，最低气温2摄氏度" + }, + { + "bullet": "C", + "text": "最高气温是2摄氏度，最低气温负7摄氏度" + }, + { + "bullet": "D", + "text": "最高气温是2摄氏度，最低气温零下7摄氏度" + } + ], + "text": "某日，连云港市的天气情况多云转晴，气温是-7摄氏度~2摄氏度，这句话应该怎么说?( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "温度上负数表示零下，正数表示零上" + ] + } +} \ No newline at end of file diff --git a/MathMC/288.json b/MathMC/288.json new file mode 100644 index 0000000000000000000000000000000000000000..a7289da603c307afabc5c025087cbf43cbda492d --- /dev/null +++ b/MathMC/288.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90%" + }, + { + "bullet": "B", + "text": "10%" + }, + { + "bullet": "C", + "text": "100%" + } + ], + "text": "件商品打九折出售，就是按原价的( )出售. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "这道题考查的是百分数的应用，九折出售是把原价看成单位‘1‘，打九折就是指现价是原价的90%." + ] + } +} \ No newline at end of file diff --git a/MathMC/289.json b/MathMC/289.json new file mode 100644 index 0000000000000000000000000000000000000000..7e31417b0d528a3fef32da10ee6285cc8a5b21c0 --- /dev/null +++ b/MathMC/289.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5950000000" + }, + { + "bullet": "B", + "text": "5999999999" + }, + { + "bullet": "C", + "text": "6040000000" + }, + { + "bullet": "D", + "text": "6049999999" + } + ], + "text": "一个十位数的近似数是60亿，这个数最小可能是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "四个选项的近似数都是60亿， 5950000000<{}5999999999<{}6040000000<{}6049999999，故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/29.json b/MathMC/29.json new file mode 100644 index 0000000000000000000000000000000000000000..7fa6ed2a61c0ce55c2a3137be761193525629d9d --- /dev/null +++ b/MathMC/29.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "1000" + } + ], + "text": "克、千克、吨每相邻两个单位之间的进率都是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "克、千克、吨是质量单位，每相邻两个单位之间的进率是1000." + ] + } +} \ No newline at end of file diff --git a/MathMC/290.json b/MathMC/290.json new file mode 100644 index 0000000000000000000000000000000000000000..88f32e922227e38f8058d0ced287b83c99e98024 --- /dev/null +++ b/MathMC/290.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲超市便宜" + }, + { + "bullet": "B", + "text": "乙超市便宜" + }, + { + "bullet": "C", + "text": "一样便宜" + } + ], + "text": "同样的笔，甲超市6支15元;乙超市买10支赠1支，共28.6元.比较两家超市该款笔的单价，( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "分别用总价除以数量，求出甲、乙超市每支笔的单价，然后再比较即可求解. 15÷6=2.5(元)， ~~~~28.6÷ (10+1) =28.6÷11 =2.6(元)， 2.5<{}2.6，甲超市卖的便宜. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/291.json b/MathMC/291.json new file mode 100644 index 0000000000000000000000000000000000000000..704349d10345b9f2113bdcacf600212dfca64ec2 --- /dev/null +++ b/MathMC/291.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "120" + }, + { + "bullet": "C", + "text": "130" + } + ], + "text": "某商场将运动衣按进价的50%加价后，写上‘大酬宾，八折优惠‘，结果每件运动衣仍获利20元，运动衣的进价是( )元. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "设进价是x元，并把进价看成单位‘1‘，原价就是(1+50%)x元，再把原价看成单位‘1‘，现价就是原价的80%，用乘法求出现价;现价减去成本价就是20元，由此列出方程求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/292.json b/MathMC/292.json new file mode 100644 index 0000000000000000000000000000000000000000..97afd22e3d5dcd54cb616ba78786f102c3f7a8b4 --- /dev/null +++ b/MathMC/292.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "统计表" + }, + { + "bullet": "B", + "text": "条形统计图" + }, + { + "bullet": "C", + "text": "折线统计图" + }, + { + "bullet": "D", + "text": "扇形统计图" + } + ], + "text": "表示一个城市一个月气温的变化情况，最好运用( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据统计图的特点进行分析可得: 统计表能将大量统计数字资料加以综合组织安排，使资料更加系统化、标准化，更加紧凑、简明、醒目和有条理，便于人们阅读、对照比较，说明问题清楚，从而更加容易发现现象之间的规律性. 扇形统计图表示的是部分在总体中所占的百分比，但一般不能直接从图中得到具体的数据; 折线统计图表示的是事物的变化情况; 条形统计图能清楚地表示出每个项目的具体数目." + ] + } +} \ No newline at end of file diff --git a/MathMC/293.json b/MathMC/293.json new file mode 100644 index 0000000000000000000000000000000000000000..9d486b4427c0c9785ebb8b9bfbc4437a07231a8b --- /dev/null +++ b/MathMC/293.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "6" + } + ], + "text": "要使8□ 02>8402，□ 里有( )种填法. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意分析可知，整数比较大小的方法是:先比较整数的位数，位数多的数这个数就大，如果位数相同则比较最高位上的数字，最高位上的数字大的数这个数就大，如果最高位上的数字也相同则比较第二高位直到能比出大小为止，在本题中，8□ 02和8402都是四位数，且最高位千位上的数字都是8，要想8□ 02大于8402那么百位上的数字就要大于4，即可以填:5;6;7;8;9，一共五种填法. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/294.json b/MathMC/294.json new file mode 100644 index 0000000000000000000000000000000000000000..2efe7ab1518d3f8d7413714f34965af039825473 --- /dev/null +++ b/MathMC/294.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1个" + }, + { + "bullet": "B", + "text": "3个" + }, + { + "bullet": "C", + "text": "8个" + } + ], + "text": "有50个苹果，最少去掉( )个，才能正好平均分给7个小朋友. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "要能平均分给7个小朋友，那么苹果的总数除以7没有余数，先用50除以7，余数即是去掉的苹果个数." + ] + } +} \ No newline at end of file diff --git a/MathMC/295.json b/MathMC/295.json new file mode 100644 index 0000000000000000000000000000000000000000..0effa37b9e739849b143984b1972dbbd254f6cbc --- /dev/null +++ b/MathMC/295.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/6" + }, + { + "bullet": "B", + "text": "1/7" + }, + { + "bullet": "C", + "text": "1/5" + }, + { + "bullet": "D", + "text": "1/3" + } + ], + "text": "把一根木头锯成6段，锯每一段所用时间相等，那么锯每一段所用时间是锯完这根木头所用时间的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题根据已知条件，把一根木头锯成6段，只需要锯5次，锯每一段所用时间相等，那么就是把锯木头的时间平均分成5份，那么锯每一段所用时间是锯完这根木头所用时间的 1 5." + ] + } +} \ No newline at end of file diff --git a/MathMC/296.json b/MathMC/296.json new file mode 100644 index 0000000000000000000000000000000000000000..307594dafc951160cc215f8c2973109bf4e096ba --- /dev/null +++ b/MathMC/296.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "138-(43+57)-38" + }, + { + "bullet": "B", + "text": "(138-38)-(43+57)" + }, + { + "bullet": "C", + "text": "138-(43+57+38)" + } + ], + "text": "138-43-57-38的简便算法是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "简算138-43-57-38，运用减法的性质进行简算即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/297.json b/MathMC/297.json new file mode 100644 index 0000000000000000000000000000000000000000..2bc9cba5b58cefc5f3288550db0df548b8f0e5d5 --- /dev/null +++ b/MathMC/297.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a+2" + }, + { + "bullet": "B", + "text": "2a" + }, + { + "bullet": "C", + "text": "a-1" + }, + { + "bullet": "D", + "text": "2a-1" + } + ], + "text": "如果用a表示非零自然数，那么奇数可以表示为( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "用a表示非零自然数，那么根据偶数的意义可知:偶数可以表示为2a，所以奇数可以表示为2a-1或2a+1.据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/298.json b/MathMC/298.json new file mode 100644 index 0000000000000000000000000000000000000000..91afa1cd5690520aab96ab35d076a96ea6280cd6 --- /dev/null +++ b/MathMC/298.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a>b" + }, + { + "bullet": "B", + "text": "a=b" + }, + { + "bullet": "C", + "text": "a\\frac{3}{8}× 4>\\frac{3}{8}÷ 4. A选项:\\frac{3}{8}÷ 4=\\frac{3}{8}× \\frac{1}{4}=\\frac{3}{32}; B选项:\\frac{3}{8}× 4=\\frac{3}{2}; C选项:4÷ \\frac{3}{8}=4× \\frac{8}{3}=\\frac{32}{3}; 因为\\frac{32}{3}>\\frac{3}{2}>\\frac{3}{32}， 所以ABC中\\frac{32}{3}最大. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/306.json b/MathMC/306.json new file mode 100644 index 0000000000000000000000000000000000000000..0a315a57675c12e7a63a359ba95f14a37cc91af2 --- /dev/null +++ b/MathMC/306.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6厘米" + }, + { + "bullet": "B", + "text": "5厘米" + }, + { + "bullet": "C", + "text": "4厘米" + } + ], + "text": "两根小棒分别是5厘米、10厘米，再有一根( )的小棒就可以围成一个三角形. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据三角形的特性:两边之和大于第三边，三角形的两边的差一定小于第三边;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/307.json b/MathMC/307.json new file mode 100644 index 0000000000000000000000000000000000000000..a4c5aab11b4c510855136454765ec09f2d71a93e --- /dev/null +++ b/MathMC/307.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "等于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "大于" + }, + { + "bullet": "D", + "text": "不能确定" + } + ], + "text": "甲数的10%等于乙数的20%(甲、乙两数都大于0)，则甲数( )乙数. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意可设，甲数为a，乙数为b ，可列式为:10%a=20%b，再进行化简比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/308.json b/MathMC/308.json new file mode 100644 index 0000000000000000000000000000000000000000..76960ae4b649d42d686e3226ddc306293d8f60d4 --- /dev/null +++ b/MathMC/308.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/2" + }, + { + "bullet": "B", + "text": "1" + }, + { + "bullet": "C", + "text": "2" + }, + { + "bullet": "D", + "text": "1/4" + } + ], + "text": "把一个大正方体切成8个相等的小正方体，这些正方体的表面积之和比原来正方体的表面积增加了( )倍. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为大正方体的棱长是小正方体边长的2倍，所以我们设小正方体边长为a，那么大正方体边长为2a，分别求出大正方体、小正方体的表面积，再用大正方体的表面积减去小正方体的表面积得到的差除以小正方体的表面积，就是增加的倍数." + ] + } +} \ No newline at end of file diff --git a/MathMC/309.json b/MathMC/309.json new file mode 100644 index 0000000000000000000000000000000000000000..d0ff64e1cb55d0c25209c4317a3d73e73ea92adc --- /dev/null +++ b/MathMC/309.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小华" + }, + { + "bullet": "B", + "text": "小明" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "在50米短跑比赛中，小华用了\\frac{1}{3}分钟，小明用了\\frac{1}{4}分钟，( )跑得快. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "\\frac{1}{3}>\\frac{1}{4}，小明时间短，跑得快. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/31.json b/MathMC/31.json new file mode 100644 index 0000000000000000000000000000000000000000..05f76b2830afe1d04e52647db962444d12328ae9 --- /dev/null +++ b/MathMC/31.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "15" + }, + { + "bullet": "C", + "text": "20" + }, + { + "bullet": "D", + "text": "30" + } + ], + "text": "四年级六个班进行篮球比赛，每两个班之间都要进行一场比赛，一共要进行( )场比赛. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "两两之间进行比赛，每个班就要进行5场比赛，6个班就要进行30场比赛，但每两个班之间的比赛都算了2次，所以还要再除以2." + ] + } +} \ No newline at end of file diff --git a/MathMC/310.json b/MathMC/310.json new file mode 100644 index 0000000000000000000000000000000000000000..25ef5274ebd0d1b5b0205006270a4b9a710b1026 --- /dev/null +++ b/MathMC/310.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5个" + }, + { + "bullet": "B", + "text": "6个" + }, + { + "bullet": "C", + "text": "7个" + } + ], + "text": "妈妈买来29个苹果，每5个装一篮，至少需要( )个篮子才能装得下. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "29÷ 5=5(个)... ... 4(个)，装满5个篮子，还多4个，多余的4个还需1个篮子，即一共需要5+1=6(个)篮子. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/311.json b/MathMC/311.json new file mode 100644 index 0000000000000000000000000000000000000000..ec19e84145ee5fb49c652f6282cc464c858cc1b7 --- /dev/null +++ b/MathMC/311.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3160" + }, + { + "bullet": "B", + "text": "1800" + }, + { + "bullet": "C", + "text": "2980" + }, + { + "bullet": "D", + "text": "5400" + } + ], + "text": "博物馆上午有3100人参观，下午参观的人数比上午少一些，博物馆下午可能有( )人参观. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "下午参观的人数比上午少一些，上午有3100人，即比3100少一些，3160和5400均大于3100，故排除，但是只比3100少一些，所以算1800与2980他们与3100之间的差，差小的即是3100-1800=1300(人)，3100-2980=120(人)，1300>120. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/312.json b/MathMC/312.json new file mode 100644 index 0000000000000000000000000000000000000000..31f776bf65edad3e3bca6826f0972a8ae637a23b --- /dev/null +++ b/MathMC/312.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "妈妈早上8:00上班，中午11:00下班，她上午工作了( )小时. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题主要是考查学生怎样计算简单的经过时间，我们可以直接用大时间减去小时间即可，11-8=3(个)小时." + ] + } +} \ No newline at end of file diff --git a/MathMC/313.json b/MathMC/313.json new file mode 100644 index 0000000000000000000000000000000000000000..3257fc0764bb9a78f4193f8b6ccf0615a062f1ad --- /dev/null +++ b/MathMC/313.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60" + }, + { + "bullet": "B", + "text": "70" + }, + { + "bullet": "C", + "text": "32" + }, + { + "bullet": "D", + "text": "38" + } + ], + "text": "三(1)班为筹备水果派对，对大家喜欢的两种水果进行了统计，喜欢吃香蕉的有38人，喜欢吃香梨的有32人，两种都喜欢的有10人.三(1)班有学生( )人. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "有:38+32-10=60(人)." + ] + } +} \ No newline at end of file diff --git a/MathMC/314.json b/MathMC/314.json new file mode 100644 index 0000000000000000000000000000000000000000..8c1e9d7884ebd11108ed7dc9b83bc063912e3afb --- /dev/null +++ b/MathMC/314.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "(85+45)×14" + }, + { + "bullet": "B", + "text": "85×14+45" + }, + { + "bullet": "C", + "text": "85×14+45×14" + } + ], + "text": "一件上衣85元，一条裤子45元，买14套这样的衣服，求一共要花多少钱，不正确的列式是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，可用上衣r的价钱85元加上裤子的价钱45元，计算出每套衣服的价钱，然后再乘14可得一共要花多少钱.据此选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/315.json b/MathMC/315.json new file mode 100644 index 0000000000000000000000000000000000000000..c82cc99dc72d18fb19c298981548bf4dbd0bcd3a --- /dev/null +++ b/MathMC/315.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "n°" + }, + { + "bullet": "B", + "text": "90°-n°" + }, + { + "bullet": "C", + "text": "180°-2n°" + }, + { + "bullet": "D", + "text": "(180°-n°)÷2" + } + ], + "text": "等腰三角形的一个底角是n°，它的顶角是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "同学们在碰到此种类型的题目进行解答的时候，我们先看清题目，然后再根据已知条件按题目的要求，求出未知的量就可以了.再进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/316.json b/MathMC/316.json new file mode 100644 index 0000000000000000000000000000000000000000..9fcc13f635d67e08ccf81011e9febf2da1e626ab --- /dev/null +++ b/MathMC/316.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{3}" + }, + { + "bullet": "B", + "text": "\\frac{1}{5}" + }, + { + "bullet": "C", + "text": "\\frac{5}{8}" + }, + { + "bullet": "D", + "text": "\\frac{5}{24}" + } + ], + "text": "加工一批零件，小李3小时完成了任务的\\frac{1}{8}，照这样计算，5小时可以完成( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "\\frac{1}{8}÷3×5， =\\frac{1}{24}×5， =\\frac{5}{24}. 答:5小时可以完成\\frac{5}{24}. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/317.json b/MathMC/317.json new file mode 100644 index 0000000000000000000000000000000000000000..fd2d966333385876cf4726ce3fc7c3b317db9535 --- /dev/null +++ b/MathMC/317.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + } + ], + "text": "两个大数比较大小，位数多的数( )位数少的数. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "比较两个整数的大小，首先看这两个整数的位数是否相同，如果位数不同，位数多的大于位数少的，如果位数相同，相同数位上大的数就大." + ] + } +} \ No newline at end of file diff --git a/MathMC/318.json b/MathMC/318.json new file mode 100644 index 0000000000000000000000000000000000000000..7fabbd1cc9051ce7ec3190e087c88973ff073588 --- /dev/null +++ b/MathMC/318.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1255" + }, + { + "bullet": "B", + "text": "1425" + }, + { + "bullet": "C", + "text": "1500" + }, + { + "bullet": "D", + "text": "3000" + } + ], + "text": "一张游乐园门票售价60元，学生享受半价优惠，学生团体票(10人及以上)可再享受九五折.一个班级有50人去游玩，买门票共需要花( )元. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "-张游乐园门票售价60元，学生享受半价优惠，价位为每人30元，学生团体票(10人及以上)可再享受九五折， 所以50人共需花门票50× 30× 95%=1425(元)，所以答案为1425元. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/319.json b/MathMC/319.json new file mode 100644 index 0000000000000000000000000000000000000000..0860150881b434d18ee077b39fa7388ccb1ec3b7 --- /dev/null +++ b/MathMC/319.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "9" + }, + { + "bullet": "D", + "text": "10" + } + ], + "text": "学校要买17个篮球，9个足球，已经买了8个篮球，还要买多少个篮球?( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "问题只和篮球有关，所以9个足球是干扰信息，不会用到.一共17个篮球，买了8个，求剩下的部分，用减法:17-8=9(个). 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/32.json b/MathMC/32.json new file mode 100644 index 0000000000000000000000000000000000000000..000cd1d138c8aa523b8066ba1296e5ce7a88b4b2 --- /dev/null +++ b/MathMC/32.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "17" + }, + { + "bullet": "B", + "text": "19" + }, + { + "bullet": "C", + "text": "72" + } + ], + "text": "有两行果树，一行有8棵，另一行有9棵，一共有( )棵. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "一共有8+9=17(棵). 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/320.json b/MathMC/320.json new file mode 100644 index 0000000000000000000000000000000000000000..d46450aba487be382ce4a6ee19524bd155f8dd23 --- /dev/null +++ b/MathMC/320.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "因数" + }, + { + "bullet": "B", + "text": "倍数" + }, + { + "bullet": "C", + "text": "质数" + } + ], + "text": "在算式30=5×6中，5和6都是30的( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据倍数和因数的定义来解答，因为30=5×6，所以30是5和6的倍数，5和6是30的因数." + ] + } +} \ No newline at end of file diff --git a/MathMC/321.json b/MathMC/321.json new file mode 100644 index 0000000000000000000000000000000000000000..64d679b5a4f9a0e39b83eeb12ebd8253afd84618 --- /dev/null +++ b/MathMC/321.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "419820" + }, + { + "bullet": "B", + "text": "420260" + }, + { + "bullet": "C", + "text": "420099" + } + ], + "text": "有3个数‘四舍五入‘后得到42万，其中( )最接近42万. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "用这三个数同42万相比较，看它们与42万的差哪最小，哪个就最接近42万." + ] + } +} \ No newline at end of file diff --git a/MathMC/322.json b/MathMC/322.json new file mode 100644 index 0000000000000000000000000000000000000000..0dea1a8dd659e87bb6e0c982a21cefa9db5d90cf --- /dev/null +++ b/MathMC/322.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "电梯的升降" + }, + { + "bullet": "B", + "text": "汽车车轮的转动" + }, + { + "bullet": "C", + "text": "抽拉抽屉" + } + ], + "text": "下列生活中的现象中，不是平移现象的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "平移是指在平面内，将一个图形上的所有点都按照某个方向作相同距离的移动叫做平移运动，简称平移.旋转是指把一个图形绕着某一点O 转动一个角度的图形变换叫做旋转.也就是说旋转是物体在以一个点或一个轴为中心的圆周上运动的现象.汽车运动是绕轴转动，是旋转运动." + ] + } +} \ No newline at end of file diff --git a/MathMC/323.json b/MathMC/323.json new file mode 100644 index 0000000000000000000000000000000000000000..e48b6af33e25920e97464817f7feed3fb325b7ab --- /dev/null +++ b/MathMC/323.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "9" + }, + { + "bullet": "C", + "text": "12" + } + ], + "text": "用一根长36厘米的铁丝做成一个长方体框架，相交一个顶点的三条棱的长度之和是( )厘米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用一根长36厘米的铁丝做成一个长方体框架，则该长方体棱长之和为36厘米，为4组长宽高长度之和.一个顶点的三条棱的长度之和是一组长宽高长度之和，所以为36÷ 4=9(厘米). 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/324.json b/MathMC/324.json new file mode 100644 index 0000000000000000000000000000000000000000..a0353d070e6e3763ce7b0a8ce31cd750ff1bad35 --- /dev/null +++ b/MathMC/324.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "千万位和万位" + }, + { + "bullet": "B", + "text": "千万位和十万位" + }, + { + "bullet": "C", + "text": "千万位和亿位" + } + ], + "text": "与百万位相邻的两个数位是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题考查的是数位顺序表的认识，从最右边开始依次是个位、十位、百位、千位、万位、十万位、百万位、千万位…所以与百万位相邻的两个数位是十万位和千万位." + ] + } +} \ No newline at end of file diff --git a/MathMC/325.json b/MathMC/325.json new file mode 100644 index 0000000000000000000000000000000000000000..10975bcc1d6fc1991fdea0c84959affd5e89c553 --- /dev/null +++ b/MathMC/325.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2个" + }, + { + "bullet": "B", + "text": "10个" + }, + { + "bullet": "C", + "text": "1个" + } + ], + "text": "一共有50个苹果，最少去掉多少个，才能正好平均分给8个小朋友?( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "因为50÷8=6余2，所以50个苹果，最少去掉2个，才能正好平均分给8个小朋友. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/326.json b/MathMC/326.json new file mode 100644 index 0000000000000000000000000000000000000000..8e41b472abd61965f0e196b87097b6a7a1c30e22 --- /dev/null +++ b/MathMC/326.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形面积大" + }, + { + "bullet": "B", + "text": "正方形面积大" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "周长相等的长方形和正方形.( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "正方形和长方形的周长相等，正方形的面积比长方形的面积大.可以通过举例证明，如它们的周长都是24厘米，长方形的长是8厘米，宽是4厘米;正方形的边长是6厘米;分别求出长方形和正方形的面积，然后比较即可得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/327.json b/MathMC/327.json new file mode 100644 index 0000000000000000000000000000000000000000..dcc91a5a356064547dcd22790c4f1606abb09c61 --- /dev/null +++ b/MathMC/327.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a>0，b>0" + }, + { + "bullet": "B", + "text": "a<0，b<0" + }, + { + "bullet": "C", + "text": "a、b同号" + }, + { + "bullet": "D", + "text": "a、b异号" + } + ], + "text": "如果ab>0，则( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "[解答]解:∵ab>0， ∴a、b同号. 故选:C. [分析]根据有理数的乘法法则判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/328.json b/MathMC/328.json new file mode 100644 index 0000000000000000000000000000000000000000..435ce71e1bd7128722b92ee664a55eb40e3a7f10 --- /dev/null +++ b/MathMC/328.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:25" + }, + { + "bullet": "B", + "text": "1:24" + }, + { + "bullet": "C", + "text": "24:25" + } + ], + "text": "在一种盐水中，盐的重量占 \\frac{1}{25}，那么盐与水的重量比是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把这种盐水的重量看作25份，则盐占1份，水占(25-1)份，于是可求盐与水的重量之比." + ] + } +} \ No newline at end of file diff --git a/MathMC/329.json b/MathMC/329.json new file mode 100644 index 0000000000000000000000000000000000000000..80a8c305fc02856555203a05f48e57d08cdc8750 --- /dev/null +++ b/MathMC/329.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形的周长长" + }, + { + "bullet": "B", + "text": "正方形的周长长" + }, + { + "bullet": "C", + "text": "一样长" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "边长1分米的正方形的周长与长13 厘米、宽7 厘米的长方形的周长相比，结果是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先把正方形的边长1分米化成10厘米，利用图形的周长计算公式算出两个图形的周长，最后再比较各图形的周长。" + ] + } +} \ No newline at end of file diff --git a/MathMC/33.json b/MathMC/33.json new file mode 100644 index 0000000000000000000000000000000000000000..0735bff864b97160654626af9f098d119f4dbd01 --- /dev/null +++ b/MathMC/33.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "23 ÷8" + }, + { + "bullet": "B", + "text": "8÷ 23" + }, + { + "bullet": "C", + "text": "8× 23" + } + ], + "text": "在下面算式中，计算结果最大的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据分数乘法、除法的计算法则，分别计算出各算式的结果，然后进行比较即可得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/330.json b/MathMC/330.json new file mode 100644 index 0000000000000000000000000000000000000000..9330a0b09f9d92e5fbca5cb48054c7bfbbb9e340 --- /dev/null +++ b/MathMC/330.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "27÷\\frac{9}{10}×\\frac{4}{5}" + }, + { + "bullet": "B", + "text": "27×\\frac{9}{10}÷\\frac{4}{5}" + }, + { + "bullet": "C", + "text": "27÷\\frac{4}{5}÷\\frac{9}{10}" + } + ], + "text": "一个数的\\frac{9}{10}是27，它的\\frac{4}{5}是多少?算式是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意，用27除以\\frac{9}{10}求出这个数，再乘\\frac{4}{5}，然后再进一步解答. 试题解析:27÷\\frac{9}{10}×\\frac{4}{5} =30×\\frac{4}{5} =24 答:这个数是24. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/331.json b/MathMC/331.json new file mode 100644 index 0000000000000000000000000000000000000000..7605cce443c68aee3f28342ddc69d6f048064ebe --- /dev/null +++ b/MathMC/331.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "牛奶" + }, + { + "bullet": "B", + "text": "水" + }, + { + "bullet": "C", + "text": "一样多" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "一杯纯牛奶，小兰先喝了\\frac{1}{3}，加满水后又喝了\\frac{1}{2}杯，再加满水，一口气全部喝完，她喝的( )多. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由‘全部喝完‘可知，小兰一共喝了1杯牛奶; 一共加了两次的水，第一次加水\\frac{1}{3}杯，第二次加水\\frac{1}{2}杯，两次加水之和就是小兰喝的水的杯数，然后比较大小.. 喝牛奶:1杯， 喝水:\\frac{1}{2}+\\frac{1}{3}=\\frac{5}{6}(杯) 1>\\frac{5}{6}. 答:喝的牛奶多. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/332.json b/MathMC/332.json new file mode 100644 index 0000000000000000000000000000000000000000..f2ecfd5de90868a86a892a411da4f68683748b6b --- /dev/null +++ b/MathMC/332.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "车轮的转动" + }, + { + "bullet": "B", + "text": "水龙头开关的转动" + }, + { + "bullet": "C", + "text": "钟摆的运动" + }, + { + "bullet": "D", + "text": "拉动抽屉" + } + ], + "text": "在下列现象中，不是旋转现象的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动; 旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心.所以，它并不一定是绕某个轴的. 根据平移与旋转定义判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/333.json b/MathMC/333.json new file mode 100644 index 0000000000000000000000000000000000000000..7e6086046ad69355a2c5e64c28cafc60963756e9 --- /dev/null +++ b/MathMC/333.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扩大到原来的100倍" + }, + { + "bullet": "B", + "text": "缩小到原来的" + }, + { + "bullet": "C", + "text": "扩大到原来的1000倍" + } + ], + "text": "把0.56的小数点去掉，这个小数就( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据小数点位置移动引起数的大小变化规律可知:由0.56变为56，相当于把0.56的小数点向右移动了两位，即扩大了100倍;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/334.json b/MathMC/334.json new file mode 100644 index 0000000000000000000000000000000000000000..53ed960260a41cbd11c8bc2958213f32a499fa29 --- /dev/null +++ b/MathMC/334.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "这组数据的平均数是11，众数是11，中位数是13" + }, + { + "bullet": "B", + "text": "这组数据的平均数是12，众数是14，中位数是12" + }, + { + "bullet": "C", + "text": "这组数据的平均数是12，众数是11，中位数是14" + }, + { + "bullet": "D", + "text": "这组数据的平均数是12，众数是11，中位数是11.5" + } + ], + "text": "某管乐小队同学的年龄分别是:11岁、12岁、11岁、14岁、14岁、11岁、12岁、11岁.那么下面说法正确的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "在一组数据中，用这组数据的总和除以数据的个数就是这组数据的平均数;在这组数据中出现次数最多的数据叫作这组数据的众数;将这组数据按照从小到大的顺序进行排列，排在中间位置的数据叫作这组数据的中位数，若这组数据为偶数位，那么排在中间的两个数据的平均数即是这组数据的中位数." + ] + } +} \ No newline at end of file diff --git a/MathMC/335.json b/MathMC/335.json new file mode 100644 index 0000000000000000000000000000000000000000..255e389debc4fffefa0fb180f7ad349ba47f9f89 --- /dev/null +++ b/MathMC/335.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "五(1)班有多少人" + }, + { + "bullet": "B", + "text": "全年级有多少人" + }, + { + "bullet": "C", + "text": "全年级女生有多少人" + }, + { + "bullet": "D", + "text": "五(1)班男生有多少人" + } + ], + "text": "五(1)班的女生25人，比全年级人数少 ，根据条件，可选择的问题是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "问题:全年级有多少人? 25÷(1- )， =25 ， =200(人). 答:全年级有200人. 故选:B. 根据条件，可选择的问题是全年级有多少人?把全年级的人数看做单位‘1‘，单位‘1‘的量是未知的，此题是已知单位‘1‘的 (1- )是25人，求单位‘1‘的量，用除法计算.此题属于分数除法应用题的类型:这道题是已知单位‘1‘的几分之几(先求出)是多少，求单位‘1‘的量，用除法解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/336.json b/MathMC/336.json new file mode 100644 index 0000000000000000000000000000000000000000..36fcafeb428d634c5c82380c3d947d8855aa631d --- /dev/null +++ b/MathMC/336.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1000" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "10" + } + ], + "text": "相邻两个重量单位之间的进率是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "我们学过的质量单位有吨、千克、克，1吨=1000千克;1千克=1000克，所以每相邻两个质量单位之间的进率都是1000;据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/337.json b/MathMC/337.json new file mode 100644 index 0000000000000000000000000000000000000000..5a366df71d872887eab2ac73a0d70db0675d5a29 --- /dev/null +++ b/MathMC/337.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "18" + }, + { + "bullet": "B", + "text": "36" + }, + { + "bullet": "C", + "text": "37" + }, + { + "bullet": "D", + "text": "50" + } + ], + "text": "下列各数中，因数个数最多的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "18的因数有:1、2、3、6、9、18，有6个.36的因数有:1、2、3、4、6、9、12、18、36，有9个.37是质数，因数有:1、37两个.50的因数有:1、2、5、10、25、50，有6个.36的因数最多." + ] + } +} \ No newline at end of file diff --git a/MathMC/338.json b/MathMC/338.json new file mode 100644 index 0000000000000000000000000000000000000000..93c03283dcdd081671505e889806d615d2891f2f --- /dev/null +++ b/MathMC/338.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "909090" + }, + { + "bullet": "B", + "text": "9009909" + }, + { + "bullet": "C", + "text": "9090909" + } + ], + "text": "读下面各数时，读出零最多的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "只需依次读出各选项中的数并进行比较即可. A.909090读作九十万九千零九十，需要读1个零. B.9009909读作九百万九千九百零九，需要读1个零. C.9090909读作九百零九万零九百零九，需要读3个零. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/339.json b/MathMC/339.json new file mode 100644 index 0000000000000000000000000000000000000000..e37a85ed1096eb5ab8f03f2d200ed6388e37bbfd --- /dev/null +++ b/MathMC/339.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东面" + }, + { + "bullet": "B", + "text": "西面" + }, + { + "bullet": "C", + "text": "南面" + }, + { + "bullet": "D", + "text": "北面" + } + ], + "text": "如果你的影子朝东，太阳应该在( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "依据‘光源与物体的影子在相反的方向‘可知:人的影子在东，则太阳在西方，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/34.json b/MathMC/34.json new file mode 100644 index 0000000000000000000000000000000000000000..64ba15cca74cff9bc9855737f60b007311f7cee6 --- /dev/null +++ b/MathMC/34.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "黄球、白球、红球" + }, + { + "bullet": "B", + "text": "白球、黄球、红球" + }, + { + "bullet": "C", + "text": "红球、黄球、白球" + } + ], + "text": "红球的个数是白球的 \\frac{3}{5}，黄球的个数是红球的 \\frac{3}{2}，红球、白球、黄球按从多到少的顺序排列是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "红球的个数是白球的 \\frac{3}{5}，那么红球与白球的个数比就是3:5，黄球的个数是红球的 \\frac{3}{2}，那么黄球与红球的个数比就是3:2，进而求出三种球的个数比即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/340.json b/MathMC/340.json new file mode 100644 index 0000000000000000000000000000000000000000..2347fb3b8e59e2910530f30432e332160998bcc8 --- /dev/null +++ b/MathMC/340.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90°-n°" + }, + { + "bullet": "B", + "text": "180°-2n°" + }, + { + "bullet": "C", + "text": "(180°-n°)÷2" + } + ], + "text": "等腰三角形的一个底角是n°，它的顶角是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据三角形的内角和是180°以及等腰三角形的两个底角相等进行分析即可求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/341.json b/MathMC/341.json new file mode 100644 index 0000000000000000000000000000000000000000..ee1578e91ffdd89e04afe32144c30cbfd7f545a7 --- /dev/null +++ b/MathMC/341.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a× 5/9" + }, + { + "bullet": "B", + "text": "5/9 ÷a" + }, + { + "bullet": "C", + "text": "a÷ 5/9" + }, + { + "bullet": "D", + "text": "5/9 ÷ 5/9" + } + ], + "text": "a是一个不为0的自然数，下列各式中，得数最大的是 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "可将四个选项中的数用分数乘法的形式表示出来，然后再比较大小。" + ] + } +} \ No newline at end of file diff --git a/MathMC/342.json b/MathMC/342.json new file mode 100644 index 0000000000000000000000000000000000000000..615e2250ad98d0fcc17c8173dd726f0ba9700cd9 --- /dev/null +++ b/MathMC/342.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8000" + }, + { + "bullet": "B", + "text": "6000" + }, + { + "bullet": "C", + "text": "5000" + } + ], + "text": "398× 21的积大约是 ( )。" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "估算为400× 20=8000。" + ] + } +} \ No newline at end of file diff --git a/MathMC/343.json b/MathMC/343.json new file mode 100644 index 0000000000000000000000000000000000000000..c35ec62e19fa8a09e7a4cdd0a5b62af79075a3f7 --- /dev/null +++ b/MathMC/343.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "3" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "在0、-1、+9、+10、-1.2、49中，正数有 ( )个。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "通常情况下，正数前加‘+‘号或不加任何符号，负数前加‘-‘号，0既不是正数也不是负数。解答即可。 在0、1、+9、+10、-1.2、49中，正数有，+9、+10、49共3个。 故选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/344.json b/MathMC/344.json new file mode 100644 index 0000000000000000000000000000000000000000..e3467a1a271f15f8e49b6d36924252c47b8800aa --- /dev/null +++ b/MathMC/344.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "83" + }, + { + "bullet": "B", + "text": "77" + }, + { + "bullet": "C", + "text": "80" + } + ], + "text": "一袋方便面的外包装上标注的净含量为‘80± 3克‘，那么这袋方便面至少重( )克. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "80-3=77(克)." + ] + } +} \ No newline at end of file diff --git a/MathMC/345.json b/MathMC/345.json new file mode 100644 index 0000000000000000000000000000000000000000..f679c610b4b105d5431c96270d9677d72c4c6251 --- /dev/null +++ b/MathMC/345.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "72× \\frac{4}{7}×10" + }, + { + "bullet": "B", + "text": "72×(1- \\frac{4}{7})" + }, + { + "bullet": "C", + "text": "72× \\frac{4}{7}" + }, + { + "bullet": "D", + "text": "72×(1+ \\frac{4}{7})" + } + ], + "text": "某厂有72吨煤，用了10天后还剩 \\frac{4}{7}，求用去多少吨，可列式为( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "某厂有72吨煤，用了10天后还剩 \\frac{4}{7}，求则用去了全部的1- \\frac{4}{7}，根据分数乘法的意义，用去了72×(1- \\frac{4}{7})吨." + ] + } +} \ No newline at end of file diff --git a/MathMC/346.json b/MathMC/346.json new file mode 100644 index 0000000000000000000000000000000000000000..8b42111b1279d1024fac80a63ac5a821b914c911 --- /dev/null +++ b/MathMC/346.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2或1" + }, + { + "bullet": "B", + "text": "2或3" + }, + { + "bullet": "C", + "text": "1或3" + } + ], + "text": "一个数除以3的余数可能是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "在整数的除法中，只有能整除与不能整除两种情况，当不能整除时，就产生余数.余数小于除数." + ] + } +} \ No newline at end of file diff --git a/MathMC/347.json b/MathMC/347.json new file mode 100644 index 0000000000000000000000000000000000000000..3d5c5f786ca70a5b275f8778b669a2d06bd8d7a1 --- /dev/null +++ b/MathMC/347.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "两个因数(均不为0)相乘，其中一个因数的末尾有2个0，积的末尾至少有( )个0. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据因数末尾有0的乘法规则解题" + ] + } +} \ No newline at end of file diff --git a/MathMC/348.json b/MathMC/348.json new file mode 100644 index 0000000000000000000000000000000000000000..6fa3b8646a3ebb1008d1e794b9c487071e288701 --- /dev/null +++ b/MathMC/348.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比5小的数" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "比5大的数" + } + ], + "text": "如果65+□ 的和是六十多，□ 里应填什么数?( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "因为65+□ 的和是六十多，且65+5=70;则□ 里应填比5小的数. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/349.json b/MathMC/349.json new file mode 100644 index 0000000000000000000000000000000000000000..4e3b687b81b1113f9c5758c004e1ce8173fc2f14 --- /dev/null +++ b/MathMC/349.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30×25%" + }, + { + "bullet": "B", + "text": "30÷25%" + }, + { + "bullet": "C", + "text": "30×(l-25%)" + }, + { + "bullet": "D", + "text": "30÷(1-25%)" + } + ], + "text": "小红有30本书，比小英少25%，小英有多少本?正确的列式是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "比小英少25%.单位‘1‘是小英单位‘1‘未知要用除法" + ] + } +} \ No newline at end of file diff --git a/MathMC/35.json b/MathMC/35.json new file mode 100644 index 0000000000000000000000000000000000000000..7c5b56c5954cb591c4bc6a1e97b81b5c39306c09 --- /dev/null +++ b/MathMC/35.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "400× 3" + }, + { + "bullet": "B", + "text": "400× 30" + }, + { + "bullet": "C", + "text": "40× 30" + } + ], + "text": "在计算462× 35的时候，4× 3表示( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "4在百位，3在十位，所以4× 3表示400× 30，答案选择B." + ] + } +} \ No newline at end of file diff --git a/MathMC/350.json b/MathMC/350.json new file mode 100644 index 0000000000000000000000000000000000000000..f5e908b94e7a32428be157c2b7f373f03ed6c144 --- /dev/null +++ b/MathMC/350.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7个" + }, + { + "bullet": "B", + "text": "8个" + }, + { + "bullet": "C", + "text": "6个" + } + ], + "text": "包装一个礼品盒需要7分米长的彩带，5米长的彩带最多能包装多个礼品盒?( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "因为5=50分米，所以50÷ 7=7··· 1≈ 7(个)， 所以5米长的彩带最多能包装7个礼品盒. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/351.json b/MathMC/351.json new file mode 100644 index 0000000000000000000000000000000000000000..3c15919328fa73829243d57e37fb9b13e9ac8932 --- /dev/null +++ b/MathMC/351.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8.4" + }, + { + "bullet": "B", + "text": "4.8" + }, + { + "bullet": "C", + "text": "5" + }, + { + "bullet": "D", + "text": "5.4" + } + ], + "text": "小明从A地到B地的平均速度是6米/秒，然后从B地原路返回，平均速度是14米/秒，那么，小明来回的平均速度是( )。 " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "设路程总长度为1，则往返所用时间分别为和秒，平均速度等于总路程除以总时间。" + ] + } +} \ No newline at end of file diff --git a/MathMC/352.json b/MathMC/352.json new file mode 100644 index 0000000000000000000000000000000000000000..c4de5292ffa0ea24e5ab59e2c66f166729d00103 --- /dev/null +++ b/MathMC/352.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "44÷_=8…4，_里填( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "解答本题要根据在有余数的除法算式中，被除数=商×除数+余数，由此得出‘除数=(被除数-余数)÷商‘，据此将对应数据带入解答即可得到答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/353.json b/MathMC/353.json new file mode 100644 index 0000000000000000000000000000000000000000..d62c676bb76e1eb49099a7bed44844291bb38b63 --- /dev/null +++ b/MathMC/353.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10厘米" + }, + { + "bullet": "B", + "text": "1米" + }, + { + "bullet": "C", + "text": "10米" + } + ], + "text": "把一根竹竿插入水中，水面以上部分长62厘米，水面以下部分长38厘米.这根竹竿长( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "竹竿的长度=水上长度+水下长度=62+38=100(厘米)， 100厘米=1米， 所以答案选择B." + ] + } +} \ No newline at end of file diff --git a/MathMC/354.json b/MathMC/354.json new file mode 100644 index 0000000000000000000000000000000000000000..8b724d3c36734b88a31800c3d3cc85aae05ec4ea --- /dev/null +++ b/MathMC/354.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "无数" + } + ], + "text": "分母是6的真分数有( )个. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "分子比分母小的分数叫作真分数，故只有\\frac{1}{6}，\\frac{2}{6}，\\frac{3}{6}，\\frac{4}{6}，\\frac{5}{6}，五个." + ] + } +} \ No newline at end of file diff --git a/MathMC/355.json b/MathMC/355.json new file mode 100644 index 0000000000000000000000000000000000000000..260e3917fb07def53ef1436dd505662230824d3d --- /dev/null +++ b/MathMC/355.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扩大到原来的100倍" + }, + { + "bullet": "B", + "text": "缩小到原来的 \\frac{1}{100}" + }, + { + "bullet": "C", + "text": "不变" + } + ], + "text": "68的后面添上%，这个数就( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘不是0的一个数后面添上百分号，这个数就缩小100倍‘，进行判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/356.json b/MathMC/356.json new file mode 100644 index 0000000000000000000000000000000000000000..e8728b3131680661b5cbb853e6dc1034df60d42b --- /dev/null +++ b/MathMC/356.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "450÷12" + }, + { + "bullet": "B", + "text": "0.45÷0.12" + }, + { + "bullet": "C", + "text": "4.5÷12" + } + ], + "text": "下列算式中，与45÷1.2的商相等的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "此题考查的是除数是小数的除法，被除数和除数同时扩大或缩小相同的倍数，商不变，根据题意选择正确的答案即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/357.json b/MathMC/357.json new file mode 100644 index 0000000000000000000000000000000000000000..96f97600e16f4f57920c11cf63c2ae83057ea2a7 --- /dev/null +++ b/MathMC/357.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "23×300" + }, + { + "bullet": "B", + "text": "25×300" + }, + { + "bullet": "C", + "text": "3×250" + } + ], + "text": "与250×30的得数相等的算式是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题是一道乘法问题，可以先算出250×30的积，再算出下面几个算式的积，再比较一下就行，做题要细心." + ] + } +} \ No newline at end of file diff --git a/MathMC/358.json b/MathMC/358.json new file mode 100644 index 0000000000000000000000000000000000000000..f469328a4cd180474270635cc1c4d0887d9a2477 --- /dev/null +++ b/MathMC/358.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "西面" + }, + { + "bullet": "B", + "text": "南面" + }, + { + "bullet": "C", + "text": "西南面" + }, + { + "bullet": "D", + "text": "西北面" + } + ], + "text": "小军家在学校的西面，小明家在小军家的南面，小明家在学校的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据方向的规定，以学校为观察点，小军家在西面，以小军家为观察点，小明家在南面，所以以学校为观察点时，小明家在西南." + ] + } +} \ No newline at end of file diff --git a/MathMC/359.json b/MathMC/359.json new file mode 100644 index 0000000000000000000000000000000000000000..db7ec46605496ea52fe16711a52950c6a0ac8f57 --- /dev/null +++ b/MathMC/359.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2400" + }, + { + "bullet": "B", + "text": "3000" + }, + { + "bullet": "C", + "text": "4000" + }, + { + "bullet": "D", + "text": "2700" + } + ], + "text": "412×6大约是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据整数乘法的估算方法:把相乘的因数看成最接近它的整数来算，如412≈400，再用400乘以6，据此选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/36.json b/MathMC/36.json new file mode 100644 index 0000000000000000000000000000000000000000..7f49b3543c914db0bb1eae84c90edf1687bcbcb0 --- /dev/null +++ b/MathMC/36.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形" + }, + { + "bullet": "B", + "text": "正方形" + }, + { + "bullet": "C", + "text": "平行四边形" + }, + { + "bullet": "D", + "text": "梯形" + } + ], + "text": "1个四边形只有一组对边平行时，它是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据我们所学的可以知道，梯形只有一组对边平行，也就是上底和下底平行，据此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/360.json b/MathMC/360.json new file mode 100644 index 0000000000000000000000000000000000000000..17c2ea13c125313fb5e0540a37aaf2404597ee16 --- /dev/null +++ b/MathMC/360.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3.75" + }, + { + "bullet": "B", + "text": "15000" + }, + { + "bullet": "C", + "text": "1500" + }, + { + "bullet": "D", + "text": "3750" + } + ], + "text": "一种药水的药液和水的比是1:200，现有药液75克，应加水( )千克。 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "思路分析:这道题是一道按比例分配的题型，可以列比例来解答。 名师详解:根据题意，列比例解答。具体解题过程如下: 解:设应加水x千克。 =，解得x=15000 易错提示:解答此类题要记住此类题型，如果弄不清水和药剂质量间的关系就会出错。" + ] + } +} \ No newline at end of file diff --git a/MathMC/361.json b/MathMC/361.json new file mode 100644 index 0000000000000000000000000000000000000000..c4780e78644529e35fa8bc3106eaf3ff9a51b829 --- /dev/null +++ b/MathMC/361.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16" + }, + { + "bullet": "B", + "text": "21" + }, + { + "bullet": "C", + "text": "12" + } + ], + "text": "将一根木棒锯成3段需要6分钟，照这样计算，锯成8段需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "锯成3段锯了2次，锯成8段锯了7次." + ] + } +} \ No newline at end of file diff --git a/MathMC/362.json b/MathMC/362.json new file mode 100644 index 0000000000000000000000000000000000000000..66dd69cb3395b9b799d6733c752956fba54b4ef0 --- /dev/null +++ b/MathMC/362.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "4" + }, + { + "bullet": "D", + "text": "3" + } + ], + "text": "在一张长8厘米、宽6厘米的长方形纸上画一个尽可能大的圆，圆规两脚间的距离应确定为( )厘米. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据题意，长方形内最大的圆就是以长方形宽为直径的圆;圆规两间的距离即这个圆的半径，由题中数据即可解得." + ] + } +} \ No newline at end of file diff --git a/MathMC/363.json b/MathMC/363.json new file mode 100644 index 0000000000000000000000000000000000000000..82e7c024de19f869f5b8ecdd6072cbdc5c4624c1 --- /dev/null +++ b/MathMC/363.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "18" + }, + { + "bullet": "B", + "text": "36" + }, + { + "bullet": "C", + "text": "40" + } + ], + "text": "下面的数，因数个数最多的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "18的因数有:1、2、3、6、9、18共6个因数;36的因数有:1、2、3、4、6、9、12、18、36共9个因数;40的因数有1、2、4、5、8、10、20、40共8个因数，由此可得出36的因数的个数最多." + ] + } +} \ No newline at end of file diff --git a/MathMC/364.json b/MathMC/364.json new file mode 100644 index 0000000000000000000000000000000000000000..65b66953c6ba078a58b878247f1822194b07b8ad --- /dev/null +++ b/MathMC/364.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "能够完全重合的图形称为全等图形" + }, + { + "bullet": "B", + "text": "全等图形的形状和大小都相同" + }, + { + "bullet": "C", + "text": "所有正方形都是全等图形" + }, + { + "bullet": "D", + "text": "形状和大小都相同的两个图形是全等图形" + } + ], + "text": "下列叙述中错误的是( )." + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "解:A、能够重合的图形称为全等图形，说法正确，故本选项错误; B、全等图形的形状和大小都相同，说法正确，故本选项错误; C、所有正方形不一定都是全等图形，说法错误，故本选项正确; D、形状和大小都相同的两个图形是全等图形，说法正确，故本选项错误; 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/365.json b/MathMC/365.json new file mode 100644 index 0000000000000000000000000000000000000000..de64eea172df4c40e9ad6263a540f5f2ab4b12de --- /dev/null +++ b/MathMC/365.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少10" + }, + { + "bullet": "B", + "text": "增加10" + }, + { + "bullet": "C", + "text": "不变" + } + ], + "text": "一个加数增加10，另一个加数减少10，和( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "两个数相加，一个加数增加10，另一个加数减少10，和会不变;可举例子进行验证说明." + ] + } +} \ No newline at end of file diff --git a/MathMC/366.json b/MathMC/366.json new file mode 100644 index 0000000000000000000000000000000000000000..16be955e8586cd3e078e5ed0fa5af5969f64f13a --- /dev/null +++ b/MathMC/366.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80%" + }, + { + "bullet": "B", + "text": "25%" + }, + { + "bullet": "C", + "text": "20%" + } + ], + "text": "甲数与乙数的比是5:4，乙数比甲数少( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "甲数与乙数的比是5:4，设甲数是5，那么乙数就是4，求出甲乙两数的差，然后再用差除以甲数即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/367.json b/MathMC/367.json new file mode 100644 index 0000000000000000000000000000000000000000..8ad28ffad05fa0f251abcffbac8089bd9940bdf5 --- /dev/null +++ b/MathMC/367.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15分钟" + }, + { + "bullet": "B", + "text": "10分钟" + }, + { + "bullet": "C", + "text": "5分钟" + } + ], + "text": "李叔叔乘班车去上班，班车每15分钟开出一班，他想乘7:30分那一趟，可他到站时，已经是7时35分，他要等( )才能等到下一班车. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "首先根据班车每隔15分钟开一班，其中一班车发车时刻是7时30分，可得下一班车的发车时刻是7时45分;然后根据结束时刻-起始时刻=经过时间，求出他还要等候多长时间，才能乘下一班车即可. 7时30分+15分=7时45分， 7时45分-7时35分=10分， 所以他要等10分钟才能等到下一班车. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/368.json b/MathMC/368.json new file mode 100644 index 0000000000000000000000000000000000000000..6c4db0b158bcf2af556ab05251ba741b8c148499 --- /dev/null +++ b/MathMC/368.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "800" + }, + { + "bullet": "B", + "text": "7100" + }, + { + "bullet": "C", + "text": "7010" + }, + { + "bullet": "D", + "text": "810" + } + ], + "text": "一个一个地数，7009后面的一个数是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "7009读作七千零九，那么它后边的一个数是七千零一十，写作7010. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/369.json b/MathMC/369.json new file mode 100644 index 0000000000000000000000000000000000000000..7c6b440a10dbb5ffa82692eaaa150e24bf38ec78 --- /dev/null +++ b/MathMC/369.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "0" + } + ], + "text": "(11+13+15+17+19)-(10+12+14+16+18)=( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意，减去10+12+14+16+18的和，就是分别减去它们各自的数，然后根据加法交换和结合律，带着符号进行结合，再进一步解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/37.json b/MathMC/37.json new file mode 100644 index 0000000000000000000000000000000000000000..ce91b88a2efe47f3d93c97a3656803ca674f19b4 --- /dev/null +++ b/MathMC/37.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "苹果的个数是梨的2倍" + }, + { + "bullet": "B", + "text": "梨的个数是苹果的2倍" + }, + { + "bullet": "C", + "text": "梨的个数是苹果的4倍" + } + ], + "text": "有8个梨，4个苹果.下面说法正确的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "8÷ 4=2，所以梨是苹果的2倍. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/370.json b/MathMC/370.json new file mode 100644 index 0000000000000000000000000000000000000000..c9538470eab9f17db862f5145b2abb0aed22e1b9 --- /dev/null +++ b/MathMC/370.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1000010" + }, + { + "bullet": "B", + "text": "9999999" + }, + { + "bullet": "C", + "text": "999098" + }, + { + "bullet": "D", + "text": "1000001" + } + ], + "text": "下面各数中，最接近100万的数是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "100万=1000000. A选项.1000010-1000000=10，相差10; B选项.9999999-1000000=8999999，相差8999999; C选项.1000000-999098=902，相差902; D选项.1000001-1000000=1，相差1; 下面各数中，最接近100万的数是D; 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/371.json b/MathMC/371.json new file mode 100644 index 0000000000000000000000000000000000000000..c94cc422ec02be65203d5197e976990c50eaeb0d --- /dev/null +++ b/MathMC/371.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "94分" + }, + { + "bullet": "B", + "text": "93分" + }, + { + "bullet": "C", + "text": "92分" + } + ], + "text": "小杰期末考试语文、数学和英语的平均成绩是92分，已知他语文的英语的平均成绩是91分，他的数学成绩是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "先根据‘平均成绩×科目的数量=总成绩‘分别求出语文、数学、英语三科的总成绩和语文、数学两科的总成绩，进而根据‘语文、数学、英语三科的总成绩-语文、数学两科的总成绩=英语成绩‘进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/372.json b/MathMC/372.json new file mode 100644 index 0000000000000000000000000000000000000000..5d60e2489dfd205159332ebe1e9fa30f1616d0e4 --- /dev/null +++ b/MathMC/372.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "转呼啦圈的运动" + }, + { + "bullet": "B", + "text": "方向盘的运动" + }, + { + "bullet": "C", + "text": "拉动抽屉时的运动" + }, + { + "bullet": "D", + "text": "转陀螺的运动" + } + ], + "text": "下列物体的运动中，属于平移的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "平移是指在一个平面内一个图形上的所有点都按照某个直线方向做相同距离的移动，旋转是指图形围绕一个点或者一个轴做圆周运动，由此可知， A选项，转呼啦圈的运动属于旋转，故A错误; B选项，方向盘的运动属于旋转，故B错误; C选项，拉动抽屉时的运动是平移运动，故C正确; D选项，转陀螺的运动是旋转运动，故D错误; 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/373.json b/MathMC/373.json new file mode 100644 index 0000000000000000000000000000000000000000..3300884f7517e9a55c8fa7b100afd9f8da1dc973 --- /dev/null +++ b/MathMC/373.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6千克" + }, + { + "bullet": "B", + "text": "6吨" + }, + { + "bullet": "C", + "text": "60吨" + }, + { + "bullet": "D", + "text": "600吨" + } + ], + "text": "一枚1元硬币大约重6克.照这样推算，100万枚1元硬币大约重( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，也就是求100万个6克是多少，用乘法计算，进而把克数转化成吨数得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/374.json b/MathMC/374.json new file mode 100644 index 0000000000000000000000000000000000000000..58ce659938d1c06a35320c3681eb17a008cdb67a --- /dev/null +++ b/MathMC/374.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12×\\frac{2}{3}" + }, + { + "bullet": "B", + "text": "12×\\frac{5}{3}" + }, + { + "bullet": "C", + "text": "12÷\\frac{2}{3}" + }, + { + "bullet": "D", + "text": "12÷\\frac{5}{3}" + } + ], + "text": "一件物品以原价的\\frac{2}{3}出售，价格为12元，求原价.下列列式计算正确的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "‘以原价的\\frac{2}{3}出售‘是把原价看成单位‘1‘，它的\\frac{2}{3}对应的数量是12元，由此用除法求出原价. 试题解析:12÷\\frac{2}{3}=18(元) 答:原价是18元. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/375.json b/MathMC/375.json new file mode 100644 index 0000000000000000000000000000000000000000..26242afed24ae353e287b857bd7f9eb25b0f9303 --- /dev/null +++ b/MathMC/375.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大" + }, + { + "bullet": "B", + "text": "小" + }, + { + "bullet": "C", + "text": "相等" + } + ], + "text": "一个不为零的自然数乘1.01，所得的积比这个数( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据在乘积非零的乘法里，一个因数>1，积>另一个因数;一个因数=1，积=另一个因数;一个因数<1，积<另一个因数." + ] + } +} \ No newline at end of file diff --git a/MathMC/376.json b/MathMC/376.json new file mode 100644 index 0000000000000000000000000000000000000000..ed11043a711c63904d01d0536fe92b9994802425 --- /dev/null +++ b/MathMC/376.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15.7厘米" + }, + { + "bullet": "B", + "text": "12.56厘米" + }, + { + "bullet": "C", + "text": "25.12厘米" + } + ], + "text": "把一个长5厘米.宽4cm的长方形剪出一个最大的圆，这个圆的周长是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "长5厘米，宽4厘米的长方形剪一个最大的圆，长方形中最大的圆是以宽为直径的圆，由此即可解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/377.json b/MathMC/377.json new file mode 100644 index 0000000000000000000000000000000000000000..e542d49c3b4795889eada8ecf93f38b975328f98 --- /dev/null +++ b/MathMC/377.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100分钟" + }, + { + "bullet": "B", + "text": "60分钟" + }, + { + "bullet": "C", + "text": "15分钟" + }, + { + "bullet": "D", + "text": "1分钟" + } + ], + "text": "小明家离学校大约1KM，他从家步行到学校，大约要( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "小学生步行每分钟大约走50-70米左右，据此先把从家到学校的距离1千米换算成1000米，进而计算求得大约要用的时间." + ] + } +} \ No newline at end of file diff --git a/MathMC/378.json b/MathMC/378.json new file mode 100644 index 0000000000000000000000000000000000000000..8165c74f64313bf88e445f5de41dd3bc3acc76e3 --- /dev/null +++ b/MathMC/378.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加" + } + ], + "text": "一个边长2分米的正方形，如果在四个角各剪去一个边长为2厘米的小正方形，那么它周长与原来比，结果是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "正方形对边相等，所以减去后周长不变." + ] + } +} \ No newline at end of file diff --git a/MathMC/379.json b/MathMC/379.json new file mode 100644 index 0000000000000000000000000000000000000000..aea3537db020ed16eaf13b4480effe2bf3de3aee --- /dev/null +++ b/MathMC/379.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5005" + }, + { + "bullet": "B", + "text": "5050" + }, + { + "bullet": "C", + "text": "5500" + } + ], + "text": "由5个千和5个十组成的数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由5个千和5个十组成的数是5050。 数位顺序，从右开始依次是:个、十、百、千…5个千，说明在千位上是5，5个十说明在十位上是5，其他数位用0补上，另外0不能在最高位，所以这个数的最高位是千位，是5050，读成‘五千零五十‘" + ] + } +} \ No newline at end of file diff --git a/MathMC/38.json b/MathMC/38.json new file mode 100644 index 0000000000000000000000000000000000000000..5e2fef4b3335fdac6ce965f13ad66126bc280992 --- /dev/null +++ b/MathMC/38.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "237892+46051" + }, + { + "bullet": "B", + "text": "856743-234086" + }, + { + "bullet": "C", + "text": "11+13+15+17+19" + }, + { + "bullet": "D", + "text": "100-7-5-3-1" + } + ], + "text": "下列个算式中计算结果是偶数的是.( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据奇数和偶数的性质:奇数+奇数=偶数，奇数-奇数=偶数，奇数+偶数=奇数，奇数-偶数=奇数，偶数-偶数=偶数;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/380.json b/MathMC/380.json new file mode 100644 index 0000000000000000000000000000000000000000..60706170e982f90c96a34454acb118a227eb40ed --- /dev/null +++ b/MathMC/380.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "1" + } + ], + "text": "一个数除以3的余数不可能是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据在有余数的除法中，余数总比除数小，除数是3，余数可能是1、2;由此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/381.json b/MathMC/381.json new file mode 100644 index 0000000000000000000000000000000000000000..e60d80fc0f69dbe7746ee2f9b77d796f63c563c0 --- /dev/null +++ b/MathMC/381.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "单式条形统计图" + }, + { + "bullet": "B", + "text": "复式条形统计图" + }, + { + "bullet": "C", + "text": "单式折线统计图" + }, + { + "bullet": "D", + "text": "复式折线统计图" + } + ], + "text": "要反映天猫和京东两个购物网站2017年每月销售额变化情况，应绘制( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "要反映变化趋势应该用折线统计图来绘制，而反映两个量及以上的应绘制复式折线统计图. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/382.json b/MathMC/382.json new file mode 100644 index 0000000000000000000000000000000000000000..5054806ff351fbb79c6bd08e811911f4b1560025 --- /dev/null +++ b/MathMC/382.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "13" + }, + { + "bullet": "C", + "text": "1或13" + }, + { + "bullet": "D", + "text": "a" + } + ], + "text": "已知a是13的因数，那么a是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因数是指整数a除以整数b(b≠ 0)的商正好是整数而没有余数，我们就说b是a的因数，由于13是质数，那么它只有两个因数，1和13. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/383.json b/MathMC/383.json new file mode 100644 index 0000000000000000000000000000000000000000..c6bab2a3e46ec320a621af19a88b1ccd9d904842 --- /dev/null +++ b/MathMC/383.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "367+173-27" + }, + { + "bullet": "B", + "text": "367-173-27" + }, + { + "bullet": "C", + "text": "367-173+27" + } + ], + "text": "下面的算式中，与367-(173+27)计算结果相同的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据减法性质进行计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/384.json b/MathMC/384.json new file mode 100644 index 0000000000000000000000000000000000000000..6782748edf0c71849077ee828238489990eb5eae --- /dev/null +++ b/MathMC/384.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8" + }, + { + "bullet": "B", + "text": "9" + }, + { + "bullet": "C", + "text": "无数" + } + ], + "text": "分母是9的真分数有( )个. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据真分数的意义，分子小于分母的分数是真分数，分母是9的真分数的分子可以是1、2、3、4、5、6、7、8共8个. 分母是9的真分数有:\\frac{1}{9}、\\frac{2}{9}、\\frac{3}{9}、\\frac{4}{9}、\\frac{5}{9}、\\frac{6}{9}、\\frac{7}{9}、\\frac{8}{9}、共8个. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/385.json b/MathMC/385.json new file mode 100644 index 0000000000000000000000000000000000000000..d1cde6c75fbddfb2696a0085970b231e7fd3c5a9 --- /dev/null +++ b/MathMC/385.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "14" + }, + { + "bullet": "B", + "text": "15" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "17" + } + ], + "text": "17、13、12、18四个数的平均数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据平均数的求法，用四个数的和除以除以4即得它们的平均数;据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/386.json b/MathMC/386.json new file mode 100644 index 0000000000000000000000000000000000000000..886deb55a735ca4a546f3af7e3f6812d366a37ee --- /dev/null +++ b/MathMC/386.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "303×21" + }, + { + "bullet": "B", + "text": "398×19" + }, + { + "bullet": "C", + "text": "298×19" + } + ], + "text": "下面算式中积一定小于6000的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据整数乘法的估算方法，分别求出各个选项中算式估算结果，然后再比较解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/387.json b/MathMC/387.json new file mode 100644 index 0000000000000000000000000000000000000000..a858d140d8b20e57c12568f67f983df096ecbdab --- /dev/null +++ b/MathMC/387.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1和3" + }, + { + "bullet": "B", + "text": "2和3" + }, + { + "bullet": "C", + "text": "1和2" + }, + { + "bullet": "D", + "text": "1和4" + } + ], + "text": "下面四个算式中，计算结果相等的是( ). 1\\frac{4}{5}× 99+\\frac{4}{5} 2\\frac{4}{5}× 99+1 3\\frac{4}{5}× 99× \\frac{4}{5} 4\\frac{4}{5}× 100 " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "1\\frac{4}{5}× 99+\\frac{4}{5}=\\frac{4}{5}× (99+1)=\\frac{4}{5}× 100，所以14结果相同." + ] + } +} \ No newline at end of file diff --git a/MathMC/388.json b/MathMC/388.json new file mode 100644 index 0000000000000000000000000000000000000000..a1ecf6430bd2b22bca6426760a556639589c7102 --- /dev/null +++ b/MathMC/388.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{3}" + }, + { + "bullet": "B", + "text": "\\frac{1}{2}" + }, + { + "bullet": "C", + "text": "\\frac{2}{3}" + }, + { + "bullet": "D", + "text": "2倍" + } + ], + "text": "把一个圆柱削成一个最大的圆锥，削去部分的体积是圆锥体积的( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "圆柱的体积是和它等底等高的圆锥体积的三倍，把圆柱削成最大的圆锥，则圆锥与圆柱等底等高，削去了两个圆锥的体积.也就是削去部分的体积是圆锥体积的2倍. {{V}_{圆柱}}=3{{V}_{圆锥}} ({{V}_{圆柱}}-{{V}_{圆锥}})÷{{V}_{圆锥}} =2{{V}_{圆锥}}÷{{V}_{圆锥}} =2. 削去部分的体积是圆锥体积的2倍. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/389.json b/MathMC/389.json new file mode 100644 index 0000000000000000000000000000000000000000..fc2efd2747a91c1ff512ef6a885faefb4dd3682e --- /dev/null +++ b/MathMC/389.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "可能每个同学的身高都低于152厘米" + }, + { + "bullet": "B", + "text": "可能每个同学的身高都高于152厘米" + }, + { + "bullet": "C", + "text": "肯定有同学的身高超过了152厘米" + }, + { + "bullet": "D", + "text": "不可能有同学的身高低于152厘米" + } + ], + "text": "六年级同学平均身高为152厘米，以下关于六年级同学身高的说法，正确的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为平均数反映的是一组数据的特征，不是其中每一个数据的特征，所以六年级同学平均身高为152厘米，并不是每个同学的身高都是152厘米;又因为平均数比最小的数大一些，比最大的数小一些，在它们中间;所以六年级同学的身高有的会比152厘米高，有的会比152厘米低，有的会等于152厘米，由此做出选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/39.json b/MathMC/39.json new file mode 100644 index 0000000000000000000000000000000000000000..5b7b1557a42423a1897a183d5d6047bf4f658046 --- /dev/null +++ b/MathMC/39.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "20" + }, + { + "bullet": "C", + "text": "4" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "用5倍的放大镜看一个20度的角，这个角是 ( )度。 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "角是两条夹边形成的夹角，放大之后，夹边未改变位置，夹角不变" + ] + } +} \ No newline at end of file diff --git a/MathMC/390.json b/MathMC/390.json new file mode 100644 index 0000000000000000000000000000000000000000..d8f27499c695cab805e862fbe8a589d239f70df6 --- /dev/null +++ b/MathMC/390.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "用卷笔刀削铅笔" + }, + { + "bullet": "B", + "text": "从滑梯顶部滑下" + }, + { + "bullet": "C", + "text": "把晾晒的衣物从绳子的左边推到右边" + }, + { + "bullet": "D", + "text": "不小心将书掉在地上" + } + ], + "text": "下面属于旋转现象的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "A.用卷笔刀削铅笔，是旋转现象. B.从滑梯顶部滑下是平移现象. C.把晾晒的衣物从绳子的左边推到右边是平移现象. D.不小心将书掉在地上是平移现象. 故选:A. 图形的旋转是图形上的每一点在平面上绕着某个固定点旋转固定角度的位置移动，其中对应点到旋转中心的距离相等，对应线段的长度、对应角的大小相等，旋转前后图形的大小和形状没有改变." + ] + } +} \ No newline at end of file diff --git a/MathMC/391.json b/MathMC/391.json new file mode 100644 index 0000000000000000000000000000000000000000..a93977d87c374eb1bfd2f1ffbade82d7d0d5df80 --- /dev/null +++ b/MathMC/391.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90" + }, + { + "bullet": "B", + "text": "900" + }, + { + "bullet": "C", + "text": "899" + } + ], + "text": "最大的三位数比最小的三位数多( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意只要找出最大的三位数和最小的三位数，然后用最大的三位数减去最小的三位数即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/392.json b/MathMC/392.json new file mode 100644 index 0000000000000000000000000000000000000000..9b7d34857c41fdce2a0010517251584266f36dbe --- /dev/null +++ b/MathMC/392.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "700" + }, + { + "bullet": "B", + "text": "800" + }, + { + "bullet": "C", + "text": "900" + } + ], + "text": "298+597的和最接近( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据算式特点理解加法的运算定律，能够正确对结果进行估计.在估算时，把数看成与它接近的整十整百数进行估算." + ] + } +} \ No newline at end of file diff --git a/MathMC/393.json b/MathMC/393.json new file mode 100644 index 0000000000000000000000000000000000000000..09b1ed305cebff599c8a19b20aa6cb064e277325 --- /dev/null +++ b/MathMC/393.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7小时" + }, + { + "bullet": "B", + "text": "8小时" + }, + { + "bullet": "C", + "text": "9小时" + } + ], + "text": "妈妈早上8时上班，中午休息1小时，下午5时下班，她一天工作了( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "12-8=4小时，5-0=5小时，5+4=9小时，9-1=8小时，求出时间间隔，做好中间时段处理。 故选:B" + ] + } +} \ No newline at end of file diff --git a/MathMC/394.json b/MathMC/394.json new file mode 100644 index 0000000000000000000000000000000000000000..7131d4171b67cfdbc09ec74a397353a68dc16336 --- /dev/null +++ b/MathMC/394.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "最小的质数与最小的合数相乘的积是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据质数的定义最小的质数是2，最小的合数是4，然后进行乘积" + ] + } +} \ No newline at end of file diff --git a/MathMC/395.json b/MathMC/395.json new file mode 100644 index 0000000000000000000000000000000000000000..29630bd1bd451c7f0d5e916d5ae260447a34fa36 --- /dev/null +++ b/MathMC/395.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小明" + }, + { + "bullet": "B", + "text": "小丽" + }, + { + "bullet": "C", + "text": "一样多" + } + ], + "text": "两个同样大的苹果，小明吃了一个苹果的\\frac{1}{3}，小丽吃了一个苹果的\\frac{1}{4}，( )剩下的苹果多. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为\\frac{1}{3}< \\frac{1}{4}， 所以小明吃掉的苹果多， 所以小丽剩下的苹果多. 答:小丽剩下的苹果多. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/396.json b/MathMC/396.json new file mode 100644 index 0000000000000000000000000000000000000000..130b5e3fea316b2ceddb1488342e78b96e7b414c --- /dev/null +++ b/MathMC/396.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "单式折线统计图" + }, + { + "bullet": "B", + "text": "复式折线统计图" + }, + { + "bullet": "C", + "text": "单式条形统计图" + }, + { + "bullet": "D", + "text": "复式条形统计图" + } + ], + "text": "如果要比较两个城市一个月气温变化的情况，选用()比较合适. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "各个统计图的主要作用: 从条形统计图中很容易看出各种数量的多少; 折线统计图主要作用是清楚地表示出数量增减变化的情况; 通过扇形统计图可以很清楚地表示各部分数量同总数之间的关系; 当然，单式统计图是表示一个事物;复式统计图便于多种事物比较; 对于这道题，如果要比较两个城市，用复式统计图比较好; 如果比较一个月气温变化的情况，用折线统计图比较好; 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/397.json b/MathMC/397.json new file mode 100644 index 0000000000000000000000000000000000000000..76dfb28ea4a9b9b29ac95f3f4d890a28e935dcd6 --- /dev/null +++ b/MathMC/397.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{23}{5}" + }, + { + "bullet": "B", + "text": "\\frac{23}{6}" + }, + { + "bullet": "C", + "text": "\\frac{23}{4}" + }, + { + "bullet": "D", + "text": "\\frac{23}{7}" + } + ], + "text": "下列分数中介于整数5与6之间的是 ( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据假分数化带分数的方法，用分子除以分母，商作整数总分，余数作分子，分母不变，反各数化成带分数，整数总分是5的带分数就介于整数5与6之间." + ] + } +} \ No newline at end of file diff --git a/MathMC/398.json b/MathMC/398.json new file mode 100644 index 0000000000000000000000000000000000000000..a056092a2962a853768bf90f3c286b5474eecb72 --- /dev/null +++ b/MathMC/398.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30÷25%" + }, + { + "bullet": "B", + "text": "30÷(1-25%)" + }, + { + "bullet": "C", + "text": "30×25%" + }, + { + "bullet": "D", + "text": "30×(1+25%)" + } + ], + "text": "小东有30枚邮票，比李琴少25%，李琴有多少枚邮票?正确的列式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把李琴邮票的枚数看成单位‘1‘，它的(1-25%)就是小东的30枚，由此根据分数除法的意义，用30枚除以(1-25%)即可求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/399.json b/MathMC/399.json new file mode 100644 index 0000000000000000000000000000000000000000..c6d78479e65591ef67faab0f5aa8dec13d4cabcb --- /dev/null +++ b/MathMC/399.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{13}" + }, + { + "bullet": "B", + "text": "\\frac{1}{19}" + }, + { + "bullet": "C", + "text": "\\frac{1}{20}" + }, + { + "bullet": "D", + "text": "\\frac{1}{5}" + } + ], + "text": "把40克糖放入760克水中，糖的重量占糖水的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把40克糖放入760克水中，则糖水重40+760克，根据分数的意义，用糖的重量除以糖水的重量，即得糖的重量占糖水的几分之几." + ] + } +} \ No newline at end of file diff --git a/MathMC/4.json b/MathMC/4.json new file mode 100644 index 0000000000000000000000000000000000000000..954e63686a9d47cf50b9ec7c72ca4b6323cd4778 --- /dev/null +++ b/MathMC/4.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "增加30" + }, + { + "bullet": "B", + "text": "减少30" + }, + { + "bullet": "C", + "text": "不变" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "两个数相加，一个加数增加30，另一个加数不变，和( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "两个数相加，和随着加数的增加而增加，减少而减少;所以一个数增加30另一个数不变，和也会增加30." + ] + } +} \ No newline at end of file diff --git a/MathMC/40.json b/MathMC/40.json new file mode 100644 index 0000000000000000000000000000000000000000..b7c7043cdc231130fa6e1ec1255a4fd773ce6e93 --- /dev/null +++ b/MathMC/40.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16" + }, + { + "bullet": "B", + "text": "32" + }, + { + "bullet": "C", + "text": "48" + }, + { + "bullet": "D", + "text": "56" + } + ], + "text": "一个圆柱和一个圆锥等底等高，它们的体积之和是64立方分米，圆锥的体积是( )立方分米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "从题目中可知圆柱和圆锥等底等高，因此圆柱的体积等于圆锥的3倍，也就是说把圆锥的体积看成1份，那么圆柱的体积就是3份，通过二者体积之和是64立方分米可知圆锥的体积为64÷(3+1)。" + ] + } +} \ No newline at end of file diff --git a/MathMC/400.json b/MathMC/400.json new file mode 100644 index 0000000000000000000000000000000000000000..14764d96576536d50180b465a0499a1f2704cc4e --- /dev/null +++ b/MathMC/400.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "比50大，比90小，并且个位和十位数字相同的数有( )个. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为比50大，比90小，并且个位和十位数字相同的数有:55、66、77、88，所以一共有4个数，故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/401.json b/MathMC/401.json new file mode 100644 index 0000000000000000000000000000000000000000..4290898bf5700768e21866e469e2e82edc4dcb8d --- /dev/null +++ b/MathMC/401.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60÷25%" + }, + { + "bullet": "B", + "text": "60÷(1-25%)" + }, + { + "bullet": "C", + "text": "60×(1+25%)" + }, + { + "bullet": "D", + "text": "60×25%" + } + ], + "text": "小光有60本书，比小英少25%，小英有多少本书?算式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把小英的本数看成单位‘1‘，它的(1-25%)对应的数量是60本，由此用除法求出小英的本数." + ] + } +} \ No newline at end of file diff --git a/MathMC/402.json b/MathMC/402.json new file mode 100644 index 0000000000000000000000000000000000000000..fd9d6a0da97f1803f07a4281cf78ec5c48e6e524 --- /dev/null +++ b/MathMC/402.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一样长" + }, + { + "bullet": "B", + "text": "第一根长" + }, + { + "bullet": "C", + "text": "第二根长" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "两根一样长的铁丝，第一根剪去 1 / 5 米，第二根剪去它的 1/5 ，剩下的两根铁丝的长度( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "想要解答此题，就需要根据题意可知，减去五分之一米就是用这个铁丝减去五分之一，减去它的五分之一就是剩余它的五分之四，由此即可解答此题." + ] + } +} \ No newline at end of file diff --git a/MathMC/403.json b/MathMC/403.json new file mode 100644 index 0000000000000000000000000000000000000000..8f29e9334513c0208dd0bbb7c8c65dff3df431e4 --- /dev/null +++ b/MathMC/403.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形统计图" + }, + { + "bullet": "B", + "text": "折线统计图" + }, + { + "bullet": "C", + "text": "扇形统计图" + } + ], + "text": "制作统计图时，如果不仅要表示出各种数量的多少，而且要清楚地表;出数量增减变化的情况，应选用( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题要弄懂为什么要制作折线统计图，怎样制作折线统计图，制作折线统计图有什么好处." + ] + } +} \ No newline at end of file diff --git a/MathMC/404.json b/MathMC/404.json new file mode 100644 index 0000000000000000000000000000000000000000..d414f80722a5404eeeb4f4871e0d54ed040fb859 --- /dev/null +++ b/MathMC/404.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲车快" + }, + { + "bullet": "B", + "text": "乙车快" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "两车从A地开往B地，甲车4小时行了全程的 \\frac{1}{5}，乙车5小时行了全程的 \\frac{1}{4}，两车的速度相比，( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把全程看作单位‘1‘，根据速度=路程÷时间，分别求出甲车和乙车的速度，比较分数的大小，即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/405.json b/MathMC/405.json new file mode 100644 index 0000000000000000000000000000000000000000..0520491a795e217635756da527bd4a1c8f7d549a --- /dev/null +++ b/MathMC/405.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "6" + } + ], + "text": "1个小朋友唱一遍《小星星》需要2分钟，3个小朋友合唱一遍需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "3个小朋友合唱一遍《小星星》和1个小朋友唱一遍的时间相同，都是2分钟. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/406.json b/MathMC/406.json new file mode 100644 index 0000000000000000000000000000000000000000..7979bd256731484b3d54061ef9eb46a057397d78 --- /dev/null +++ b/MathMC/406.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "419830" + }, + { + "bullet": "B", + "text": "420200" + }, + { + "bullet": "C", + "text": "420089" + }, + { + "bullet": "D", + "text": "424600" + } + ], + "text": "有4个数‘四舍五入‘后都得到了42万，其中( )最接近42万。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "419830与42万相差170，420200与42万相差200，420089与42万相差89，424600与42万相差4600，其中420089与42万相差最少，据此选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/407.json b/MathMC/407.json new file mode 100644 index 0000000000000000000000000000000000000000..aebf7f68ecf5a2f0de7109938cb94bc404220e42 --- /dev/null +++ b/MathMC/407.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "75÷15" + }, + { + "bullet": "B", + "text": "750÷15" + }, + { + "bullet": "C", + "text": "0.75÷1.5" + }, + { + "bullet": "D", + "text": "7.5÷1.5" + } + ], + "text": "在下列算式中，与7.5÷0.15的商相等的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据商不变的性质，当被除数和除数同时扩大或者缩小相同的倍数时，商不变，所以7.5÷ 0.15=750÷ 15. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/408.json b/MathMC/408.json new file mode 100644 index 0000000000000000000000000000000000000000..a85156229a96f0de8636b07d90c21a14041d52bb --- /dev/null +++ b/MathMC/408.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "最简分数的分子和分母的公因数只有1" + }, + { + "bullet": "B", + "text": "分子和分母是大小不同的质数的分数一定是最简分数" + }, + { + "bullet": "C", + "text": "分子和分母都是合数的真分数一定不是最简分数" + } + ], + "text": "下面说法错误的是( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "A选项中，最简分数的分子和分母的公因数只有1，正确; B选项中，分子和分母是大小不同的质数时，一定只有公因数1，所以一定是最简分数，正确; C选项中，分子和分母都是合数时，也有可能互质，如4和9，所以可能是最简分数，错误; 所以应选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/409.json b/MathMC/409.json new file mode 100644 index 0000000000000000000000000000000000000000..46d3194c0635e83bc774580245a11f72b6c6304a --- /dev/null +++ b/MathMC/409.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{2}{3}+\\frac{2}{3}+\\frac{2}{3}+\\frac{2}{3}" + }, + { + "bullet": "B", + "text": "4+\\frac{2}{3}" + }, + { + "bullet": "C", + "text": "4-\\frac{2}{3}" + }, + { + "bullet": "D", + "text": "4×\\frac{2}{3}" + } + ], + "text": "4吨的\\frac{2}{3}是多少?列式是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "求一个数的几分之几是多少，用乘法计算即可得解. 试题解析:4吨的\\frac{2}{3}列式是:4×\\frac{2}{3}. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/41.json b/MathMC/41.json new file mode 100644 index 0000000000000000000000000000000000000000..8b3e8599647321309db20ff6b2d5605554776e84 --- /dev/null +++ b/MathMC/41.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15个 \\frac{2}{3}想加的和" + }, + { + "bullet": "B", + "text": "15的 \\frac{2}{3}是多少" + }, + { + "bullet": "C", + "text": "\\frac{2}{3}的15倍是多少" + } + ], + "text": "15× \\frac{2}{3}的意义是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "分数乘整数的意义与整数乘法的意义相同，表示求几个相同加数的和的简便运算;一个数乘分数的意义，表示求这个数的几分之几是多少.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/410.json b/MathMC/410.json new file mode 100644 index 0000000000000000000000000000000000000000..e5e5f2b6ee6be030da76a06b20812fffde6fa19f --- /dev/null +++ b/MathMC/410.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100倍" + }, + { + "bullet": "B", + "text": "\\frac{5}{100}" + }, + { + "bullet": "C", + "text": "\\frac{1}{100}" + } + ], + "text": "在5的后面添上‘%‘，这个数是原数的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在5后面添上一个百分号，即变成5%;5%=0.05，由5到0.05，小数点向左移动2位，即缩小100倍，缩小到原数的 \\frac{1}{100};进而选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/411.json b/MathMC/411.json new file mode 100644 index 0000000000000000000000000000000000000000..780af02320e965b0828a2ce220350196d4b9171d --- /dev/null +++ b/MathMC/411.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/4" + }, + { + "bullet": "B", + "text": "1/2" + }, + { + "bullet": "C", + "text": "1/3" + }, + { + "bullet": "D", + "text": "2/3" + } + ], + "text": "把一枚硬币投掷3次，有2次正面朝上，1次反面朝上。那么第4次投掷硬币，正面朝上的可能性为()" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "无论之前投掷了多少次，本次投掷都只会出现两种结果，即正面朝上，或者反面朝上，所以正面朝上的可能性为1/2" + ] + } +} \ No newline at end of file diff --git a/MathMC/412.json b/MathMC/412.json new file mode 100644 index 0000000000000000000000000000000000000000..604660448da1ed21211fa191a160c2018343f309 --- /dev/null +++ b/MathMC/412.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20" + }, + { + "bullet": "B", + "text": "30" + }, + { + "bullet": "C", + "text": "40" + }, + { + "bullet": "D", + "text": "60" + } + ], + "text": "块正方体木料，它的底面积是10平方厘米，把它截成3段，表面积增加了( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，把一块正方体木料，截成3段，表面积增加了(3-1)×2个底面积，据此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/413.json b/MathMC/413.json new file mode 100644 index 0000000000000000000000000000000000000000..4b1f23fa3a65a4b7e78d54a776d074cf9d6e2820 --- /dev/null +++ b/MathMC/413.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30" + }, + { + "bullet": "B", + "text": "16" + }, + { + "bullet": "C", + "text": "60" + }, + { + "bullet": "D", + "text": "18" + } + ], + "text": "烟火晚会上每隔6秒出现一次星星图案的礼花，每隔10秒出现一次花朵图案的礼花，在同时看到这两种礼花后，至少还要经过( )秒才可以再次同时看到这两种礼花. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "本题实际是求6和10的最小公倍数，通过计算可知其最小公倍数为30，故30s后即可看到两种礼花同时出现. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/414.json b/MathMC/414.json new file mode 100644 index 0000000000000000000000000000000000000000..336c5f2d353473248fca7069aae047f5f3da09bb --- /dev/null +++ b/MathMC/414.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "意义相同" + }, + { + "bullet": "B", + "text": "分数单位相同" + }, + { + "bullet": "C", + "text": "大小相同" + } + ], + "text": "\\frac{1}{4}和\\frac{2}{8}这两个分数( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "\\frac{1}{4}表示把单位‘1‘平均分成4份取其1份，分数单位是\\frac{1}{4};\\frac{2}{8}表示把单位‘1‘平均分成8份取其2份，分数单位是\\frac{1}{8};因此，这两个分数的分数单位及意义都不相同; 根据分数的基本性质，\\frac{1}{4}的分子、分母都乘2就是\\frac{2}{8}，因此，这两个分数的大小相等. 根据分析可知\\frac{1}{4}和\\frac{2}{8}这两个分数的意义和分数单位都不相同，但大小相同. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/415.json b/MathMC/415.json new file mode 100644 index 0000000000000000000000000000000000000000..f801e54f1532e0fa9e0d9e4927d444028793ba38 --- /dev/null +++ b/MathMC/415.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "180°-m°" + }, + { + "bullet": "B", + "text": "90°-m°" + }, + { + "bullet": "C", + "text": "(180°-m°)÷2" + } + ], + "text": "一个等腰三角形的顶角为m°，它的一个底角是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意知，要求底角的度数，根据三角形的内角和是180°，根据等腰三角形的性质又知等腰三角形的两个底角相等，那么用(180°-m°)÷2即可，最后进行判断得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/416.json b/MathMC/416.json new file mode 100644 index 0000000000000000000000000000000000000000..2dcf26ffab390a5312b0c872bd4f4ef823e9a71f --- /dev/null +++ b/MathMC/416.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20平方厘米" + }, + { + "bullet": "B", + "text": "20厘米" + }, + { + "bullet": "C", + "text": "25厘米" + } + ], + "text": "1个正方形的面积是25平方厘米，它的周长是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为正方形的面积S=a×a，5×5=25，由此得出正方形的边长是5厘米，再根据正方形的周长公式C=4a，即可求出它的周长." + ] + } +} \ No newline at end of file diff --git a/MathMC/417.json b/MathMC/417.json new file mode 100644 index 0000000000000000000000000000000000000000..33e42f457a3720480c88356cea5f4a9fa835ac1b --- /dev/null +++ b/MathMC/417.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于1" + }, + { + "bullet": "B", + "text": "小于1" + }, + { + "bullet": "C", + "text": "不大于1" + }, + { + "bullet": "D", + "text": "不小于1" + } + ], + "text": "假分数的倒数一定( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据倒数的意义:乘积是1的两个数互为倒数.分数的分子等于或等于分母的分数，叫做假分数.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/418.json b/MathMC/418.json new file mode 100644 index 0000000000000000000000000000000000000000..67d1d492fc8a099d3933069a88fc91ed74296783 --- /dev/null +++ b/MathMC/418.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "700" + }, + { + "bullet": "B", + "text": "300" + }, + { + "bullet": "C", + "text": "200" + } + ], + "text": "估算499-201的结果大约是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意计算出减法的结果，再找大约数.解: 499-201=298，298极其接近的整数是300，所以大约是300.故答案为:b" + ] + } +} \ No newline at end of file diff --git a/MathMC/419.json b/MathMC/419.json new file mode 100644 index 0000000000000000000000000000000000000000..6ea17db9131d12f8e03cc3507ccd1bf3a714d600 --- /dev/null +++ b/MathMC/419.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "亿位和十亿位" + }, + { + "bullet": "B", + "text": "百万位和十万位" + }, + { + "bullet": "C", + "text": "亿位和百万位" + }, + { + "bullet": "D", + "text": "亿和百万" + } + ], + "text": "与千万位相邻的两个数位分别是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "正确认识数位顺序表即可" + ] + } +} \ No newline at end of file diff --git a/MathMC/42.json b/MathMC/42.json new file mode 100644 index 0000000000000000000000000000000000000000..51905a1a147084af1ff3c92657220512fcb2a2a2 --- /dev/null +++ b/MathMC/42.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3、2、3" + }, + { + "bullet": "B", + "text": "8、10、2" + }, + { + "bullet": "C", + "text": "12、5、4" + } + ], + "text": "有几组小棒，它们的长度如下(单位:CM).这几组小棒中，( )正好可以拼成一个三角形. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据三角形的特性:两边之和大于第三边，三角形的两边的差一定小于第三边;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/420.json b/MathMC/420.json new file mode 100644 index 0000000000000000000000000000000000000000..7111eac9486b4b6242702581c8e6d6c24478fdeb --- /dev/null +++ b/MathMC/420.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "一个边长为2分米的正方形，如果在四个角各剪去一个边长为2厘米的正方形，那么它的周长与原来相比是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意可知:一个边长为2分米的正方形，如果在四个角各剪去一个边长为2厘米的正方形，则它后来的周长与原来的周长的关系.如下图，运用平移的方法，即可得出后来的周长与原来的周长的关系." + ] + } +} \ No newline at end of file diff --git a/MathMC/421.json b/MathMC/421.json new file mode 100644 index 0000000000000000000000000000000000000000..44b6dde22336eeee79ad903f74a2ee3b73b137e7 --- /dev/null +++ b/MathMC/421.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一次长" + }, + { + "bullet": "B", + "text": "第二次长" + }, + { + "bullet": "C", + "text": "两次同样长" + } + ], + "text": "一根铁丝长 8/5 米，第一次用去 3/5 米，第二次用去剩下的 3/5 ，两次用去的铁丝的长度相比，( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意可知:一根铁丝长 8/5米， 第一次用去 3/5米，则剩下 8/5- 3/5=1米，把剩下铁丝的长度看作单位‘1‘，则第二次用去了1× 3/5= 3/5(米)，依此即可作出判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/422.json b/MathMC/422.json new file mode 100644 index 0000000000000000000000000000000000000000..17babba4b0b4ab6bca4b2395cf733de85b22f04c --- /dev/null +++ b/MathMC/422.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8× \\frac{1}{8}" + }, + { + "bullet": "B", + "text": "8+\\frac{1}{8}" + }, + { + "bullet": "C", + "text": "8+8× \\frac{1}{8}" + } + ], + "text": "8千克的\\frac{1}{8}是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意分析可知，求一个数的几分之几用乘法， 所以8千克的\\frac{1}{8}是:8× \\frac{1}{8}. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/423.json b/MathMC/423.json new file mode 100644 index 0000000000000000000000000000000000000000..7283eb0636c2631c0979353ec73e0f8a4f6a0a22 --- /dev/null +++ b/MathMC/423.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "千克" + }, + { + "bullet": "B", + "text": "吨" + }, + { + "bullet": "C", + "text": "克" + }, + { + "bullet": "D", + "text": "千米" + } + ], + "text": "一辆大卡车载重12( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据生活经验，对质量单位和数据的大小，可知计量一辆卡车的载重量用‘吨‘做单位." + ] + } +} \ No newline at end of file diff --git a/MathMC/424.json b/MathMC/424.json new file mode 100644 index 0000000000000000000000000000000000000000..55ec2595babdd3b51524e882e8d630557388bfb9 --- /dev/null +++ b/MathMC/424.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "百万和万" + }, + { + "bullet": "B", + "text": "百万位和万位" + }, + { + "bullet": "C", + "text": "百万位和十万位" + } + ], + "text": "和十万位相邻的两个数位分别是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据整数的数位顺序可知，百万位和万位与十万位相邻，据此判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/425.json b/MathMC/425.json new file mode 100644 index 0000000000000000000000000000000000000000..5aa0e3793af159e21457cdb6b2dee7b6dffd4701 --- /dev/null +++ b/MathMC/425.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{8}÷4" + }, + { + "bullet": "B", + "text": "\\frac{3}{8}×4" + }, + { + "bullet": "C", + "text": "4÷ \\frac{3}{8}" + } + ], + "text": "在下面的算式中计算结果最大的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据分数乘法、除法的计算法则分别计算出各式的结果，然后进行比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/426.json b/MathMC/426.json new file mode 100644 index 0000000000000000000000000000000000000000..a4b7e266e426946fcb256cb0c0387644fb096c40 --- /dev/null +++ b/MathMC/426.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "加法交换律" + }, + { + "bullet": "B", + "text": "乘法交换律" + }, + { + "bullet": "C", + "text": "乘法结合律" + }, + { + "bullet": "D", + "text": "乘法分配律" + } + ], + "text": "27×19+23×19=19×(27+23)应用的定律是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "27×19+23×19=19×(27+23)就是两个数与同一个数相乘，等于这两个数相加后再与第三个数相乘，是乘法分配律的反用." + ] + } +} \ No newline at end of file diff --git a/MathMC/427.json b/MathMC/427.json new file mode 100644 index 0000000000000000000000000000000000000000..e811e32e638c501ecf339b8619379e533ff90c96 --- /dev/null +++ b/MathMC/427.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{625}{97}" + }, + { + "bullet": "B", + "text": "\\frac{676}{97}" + }, + { + "bullet": "C", + "text": "\\frac{1225}{97}" + }, + { + "bullet": "D", + "text": "\\frac{2401}{97}" + } + ], + "text": "如果 \\frac{1}{97}+ \\frac{3}{97}= \\frac{2}{97}×2= \\frac{4}{97}; \\frac{1}{97}+ \\frac{3}{97}+ \\frac{5}{97}= \\frac{3}{97}×3= \\frac{9}{97}; \\frac{1}{97}+ \\frac{3}{97}+ \\frac{5}{97}+ \\frac{7}{97}= \\frac{4}{97}×4= \\frac{16}{97}，则 \\frac{1}{97}+ \\frac{3}{97}+ \\frac{5}{97}+…+ \\frac{49}{97}=( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "通过观察，每个算式中分数的分子都是连续的奇数，得数为分母不变，分子为分数的个数，然后乘分数的个数，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/428.json b/MathMC/428.json new file mode 100644 index 0000000000000000000000000000000000000000..a8d4d0368fe770b943d968f0c3305dd7bcf6c8a6 --- /dev/null +++ b/MathMC/428.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "14" + }, + { + "bullet": "B", + "text": "15" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "17" + } + ], + "text": "有20道竞赛题，对于每一题，答对得6分，答错或不答扣3分，小明在这次竞赛中的得分不少于80分，但又不多于90分，则小明答对的题数是 ( )" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "解:设要答对x道，由题意，有 90≥6x-3(20-x)≥80， 化简得:90≥9x-60≥80， 解得:150≥9x≥140， 即 16\\frac{2}{3}≥ x≥ 15\\frac{5}{9}， ∵小明答对的题数一定是整数， ∴x只能取16. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/429.json b/MathMC/429.json new file mode 100644 index 0000000000000000000000000000000000000000..af8f065d10ea3453d087f5bea6c1959add679060 --- /dev/null +++ b/MathMC/429.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "299999" + }, + { + "bullet": "B", + "text": "304999" + }, + { + "bullet": "C", + "text": "349999" + }, + { + "bullet": "D", + "text": "394999" + } + ], + "text": "一个数省略最高位后面的尾数后是30万，这个数最大是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一个数省略万位后面的尾数是30万，最大是千位上的数舍去得到的，舍去的数中4是最大的，其它数位百位、十位、个位是最大的一位数9即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/43.json b/MathMC/43.json new file mode 100644 index 0000000000000000000000000000000000000000..a08afe79843b2354690ebf7bb7b8421d11ad36d7 --- /dev/null +++ b/MathMC/43.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "25÷12.5" + }, + { + "bullet": "B", + "text": "25÷1.25" + }, + { + "bullet": "C", + "text": "25÷0.125" + } + ], + "text": "商最大的算式是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "被除数一定时，除数越小，则商越大，据此判断出商最大的算式是哪个即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/430.json b/MathMC/430.json new file mode 100644 index 0000000000000000000000000000000000000000..4a7f76ca870e39126331a44fd747e60ad563b66a --- /dev/null +++ b/MathMC/430.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2千克" + }, + { + "bullet": "B", + "text": "2000千克" + }, + { + "bullet": "C", + "text": "200克" + } + ], + "text": "一瓶醋重500克，4瓶醋重( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "一瓶醋重500克，4瓶的重量为4×500克=2000克=2千克 A、B选项是容易混淆的选项" + ] + } +} \ No newline at end of file diff --git a/MathMC/431.json b/MathMC/431.json new file mode 100644 index 0000000000000000000000000000000000000000..1b9823a1d5980bada5e9df48a314714a62ab56cf --- /dev/null +++ b/MathMC/431.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10×(1- \\frac{1}{4}- \\frac{1}{4})" + }, + { + "bullet": "B", + "text": "10- \\frac{1}{4}- \\frac{1}{4}" + }, + { + "bullet": "C", + "text": "10×(1- \\frac{1}{4})- \\frac{1}{4}" + }, + { + "bullet": "D", + "text": "10× \\frac{1}{4}- \\frac{1}{4}" + } + ], + "text": "有一根钢材长10米，第一次用去全长的 \\frac{1}{4}，第二次用去 \\frac{1}{4}m，还剩下多少米，正确的算式是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "将全长当作单位‘1‘，第一次用去全长的 \\frac{1}{4}，根据分数减法的意义，此时还剩下全长的1- \\frac{1}{4}，根据分数乘法的意义，还剩下10×(1- \\frac{1}{4})米，第二次用去 \\frac{1}{4}m，根据减法的意义，则用第一次剩下的长度减去第二次用去的长度，即得还剩多少米." + ] + } +} \ No newline at end of file diff --git a/MathMC/432.json b/MathMC/432.json new file mode 100644 index 0000000000000000000000000000000000000000..7091d57a3cead7aa0a5248f66f34dff68e3dc001 --- /dev/null +++ b/MathMC/432.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东北" + }, + { + "bullet": "B", + "text": "西北" + }, + { + "bullet": "C", + "text": "西南" + } + ], + "text": "小明左手边是东北方，他的右手边是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "左右手相对，所对的方向也相对。考察辨认方向。" + ] + } +} \ No newline at end of file diff --git a/MathMC/433.json b/MathMC/433.json new file mode 100644 index 0000000000000000000000000000000000000000..9420d2b799b22c7c1a28617940fe71a5968c220f --- /dev/null +++ b/MathMC/433.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "数量增减变化" + }, + { + "bullet": "B", + "text": "数量的多少" + }, + { + "bullet": "C", + "text": "各部分数量和总数量之间的关系" + } + ], + "text": "扇形统计图可以清楚地表示出( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题是一道小学数学基础题，主要考查学生对统计图表示含义的掌握及理解，要求学生在平时多加练习，勤于总结，为以后的数学学习打下良好的基础." + ] + } +} \ No newline at end of file diff --git a/MathMC/434.json b/MathMC/434.json new file mode 100644 index 0000000000000000000000000000000000000000..9c1a051893bc0bcac0bd532349c14bbd9badbac1 --- /dev/null +++ b/MathMC/434.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15÷" + }, + { + "bullet": "B", + "text": "15×" + }, + { + "bullet": "C", + "text": "15÷+15" + } + ], + "text": "六.一班有‘三好学生‘15人，相当于全班人数的，全班有多少人?列式是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把全班的总人数看成单位‘1‘，它的对应的数量是15人，由此用除法求出总人数." + ] + } +} \ No newline at end of file diff --git a/MathMC/435.json b/MathMC/435.json new file mode 100644 index 0000000000000000000000000000000000000000..d6de7cbb3e5452548e830c4ac3d4803d13dd22ba --- /dev/null +++ b/MathMC/435.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长8分米，宽6分米" + }, + { + "bullet": "B", + "text": "长6分米、宽5分米" + }, + { + "bullet": "C", + "text": "长8分米，宽5分米" + } + ], + "text": "小明的爸爸想做一个玻璃鱼缸，已经准备了4块长方形玻璃，其中的两块长8分米，宽5分米，另两块长6分米.宽5分米，还需要准备一块( )玻璃. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "一个完整的长方体有6个面，相对的两个面完全一样;根据此特征，可把两块长8分米、宽5分米的玻璃当这个鱼缸的前后两个面;把两块长5分米、宽6分米的玻璃当这个鱼缸的左右两个侧面;据此还要配一块长8分米、宽6分米的玻璃做这个鱼缸的下底面;所以做成的这个鱼缸的长为8分米，宽为6分米，高为5分米;由此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/436.json b/MathMC/436.json new file mode 100644 index 0000000000000000000000000000000000000000..514d37b3a2423612c3ab3750abd2f1d5525b3f57 --- /dev/null +++ b/MathMC/436.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比134 厘米少" + }, + { + "bullet": "B", + "text": "比151 厘米多" + }, + { + "bullet": "C", + "text": "在134 厘米~151 厘米之间" + } + ], + "text": "四(1)班第一小组6个同学的身高数据(单位:厘米)如下:137，140，142，134，147，151.该组同学的平均身高应该( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "1.平均数是指在一组数据中所有数据之和再除以数据的个数。 2.算出此题的平均身高就会发现平均数不会比最低身高还低，也不会比最高身高还高。" + ] + } +} \ No newline at end of file diff --git a/MathMC/437.json b/MathMC/437.json new file mode 100644 index 0000000000000000000000000000000000000000..4a72a1255f56a25b728b35d9c93ae5f9e986980d --- /dev/null +++ b/MathMC/437.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "整数" + }, + { + "bullet": "B", + "text": "分数" + }, + { + "bullet": "C", + "text": "相同的数" + } + ], + "text": "分数的分子和分母都乘以或除以( )(0除外)，分数的大小不变. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据分数的基本性质的内容，直接进行选择得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/438.json b/MathMC/438.json new file mode 100644 index 0000000000000000000000000000000000000000..4838cd0da10bbdaa48d8ffdc1c9d44f773abfefa --- /dev/null +++ b/MathMC/438.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9000和100001" + }, + { + "bullet": "B", + "text": "99999和110000" + }, + { + "bullet": "C", + "text": "99999和100001" + } + ], + "text": "与最小的六位数相邻的两个数是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "最小的六位数是100000，然后根据相邻的两个自然数相差1，进行解答即可. 100000-1=99999，100000+1=100001. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/439.json b/MathMC/439.json new file mode 100644 index 0000000000000000000000000000000000000000..e4f6f1bad1de2196f3c3904a8d898dd1b9e217f7 --- /dev/null +++ b/MathMC/439.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + }, + { + "bullet": "D", + "text": "6" + } + ], + "text": "要使29□ 680≈ 30万，□ 里有( )种填法. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "四舍五入.要使它约等于30万，方框里的数字就应该大于或等于5，可以填的数字有5、6、7、8、9五种填法." + ] + } +} \ No newline at end of file diff --git a/MathMC/44.json b/MathMC/44.json new file mode 100644 index 0000000000000000000000000000000000000000..7c6bf7705a5589a4130ba4804099dcdd862049ff --- /dev/null +++ b/MathMC/44.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小红" + }, + { + "bullet": "B", + "text": "小梅" + }, + { + "bullet": "C", + "text": "小涛" + } + ], + "text": "在50米的短跑比赛中，小红用了10秒，小梅用了9秒，小涛用了11秒，( )是第一名. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "路程相同，用时越短则速度越快，故小梅是第一名. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/440.json b/MathMC/440.json new file mode 100644 index 0000000000000000000000000000000000000000..ea9dce4feee992cc9f2d70723bff2df4121421e0 --- /dev/null +++ b/MathMC/440.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8999" + }, + { + "bullet": "B", + "text": "7985" + }, + { + "bullet": "C", + "text": "8210" + } + ], + "text": "下面各数，最接近8000的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "A.8999-8000=999， B.8000-7985=15， C.8210-8000=210， 因为15<{}210<{}999， 所以选项B中7985最接近8000. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/441.json b/MathMC/441.json new file mode 100644 index 0000000000000000000000000000000000000000..466ce66b8a63f79ea8ace48d65323564f49aef86 --- /dev/null +++ b/MathMC/441.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5吨" + }, + { + "bullet": "B", + "text": "6吨" + }, + { + "bullet": "C", + "text": "7吨" + } + ], + "text": "下面是小明家第二季度用水情况统计表 小明家第二季度用水情况统计表 月份 4月 5月 6月 用水量(吨) 4吨 6吨 8吨小明家第二季度平均每月用水( )吨. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先把三个月的用水量相加求得用水总量，再除以3即为小明第二季度平均每月用水的吨数." + ] + } +} \ No newline at end of file diff --git a/MathMC/442.json b/MathMC/442.json new file mode 100644 index 0000000000000000000000000000000000000000..731821ef165f4d8ad1ec6c43c390fe79f551cebe --- /dev/null +++ b/MathMC/442.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60" + }, + { + "bullet": "B", + "text": "40" + }, + { + "bullet": "C", + "text": "30" + } + ], + "text": "一块正方体木料，它的底面积是10平方厘米，把它横截成4段，表面积增加 平方厘米。 " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "首先确定，截成4块，增加了几个面，然后计算增加的表面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/443.json b/MathMC/443.json new file mode 100644 index 0000000000000000000000000000000000000000..9315323af7e7ca85a9d1a4ef101eff6638028da6 --- /dev/null +++ b/MathMC/443.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形" + }, + { + "bullet": "B", + "text": "折线" + }, + { + "bullet": "C", + "text": "扇形" + } + ], + "text": "要反映各个年级与全校总人数的关系，选用( )统计图" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/444.json b/MathMC/444.json new file mode 100644 index 0000000000000000000000000000000000000000..7d1addc42fb68b6a62d13602406c4eeef6cf0d5c --- /dev/null +++ b/MathMC/444.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一样大" + }, + { + "bullet": "B", + "text": "甲数大" + }, + { + "bullet": "C", + "text": "乙数大" + }, + { + "bullet": "D", + "text": "不确定" + } + ], + "text": "甲数的20%和乙数的 \\frac{1}{5}相比较( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "甲数的20%，得把甲数看作单位‘1‘，乙数的 \\frac{1}{5}，得把乙数看作单位‘1‘，由于两个单位‘1‘的量不一定相同，所以甲数的20%和乙数的 \\frac{1}{5}是无法比较的." + ] + } +} \ No newline at end of file diff --git a/MathMC/445.json b/MathMC/445.json new file mode 100644 index 0000000000000000000000000000000000000000..ed83ba85523c2e3b69d303f24188b61ddbaad1f3 --- /dev/null +++ b/MathMC/445.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5元" + }, + { + "bullet": "B", + "text": "50元" + }, + { + "bullet": "C", + "text": "500元" + } + ], + "text": "买40枚8角的邮票和30枚6角的邮票共需要( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "首先用8×40加上6×30求出买这些邮票一共需要多少角，然后把角化成元，因为是低级单位化成高级单位，所以除以它们之间的进率." + ] + } +} \ No newline at end of file diff --git a/MathMC/446.json b/MathMC/446.json new file mode 100644 index 0000000000000000000000000000000000000000..775f9f918e36cb529146396d47a8eae4c21bd8c2 --- /dev/null +++ b/MathMC/446.json @@ -0,0 +1,24 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "309+216" + }, + { + "bullet": "B", + "text": "203×2" + } + ], + "text": "算式的结果大于500而小于600的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "估算时，一般要根据‘四舍五入‘法把数看作是整十、整百、整千…的数来进行计算，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/447.json b/MathMC/447.json new file mode 100644 index 0000000000000000000000000000000000000000..2dfedad5e0196ae37a6bbd90692345f52972939f --- /dev/null +++ b/MathMC/447.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比长方形面积小" + }, + { + "bullet": "B", + "text": "比长方形面积大" + }, + { + "bullet": "C", + "text": "和长方形面积相等" + } + ], + "text": "用3个相同的正方形拼成一个长方形，3个正方形的面积和 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "拼成的长方形的面积是3个小正方形的面积和来选择正确的答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/448.json b/MathMC/448.json new file mode 100644 index 0000000000000000000000000000000000000000..40f615ceac8a127491862612256d95eefb6d7446 --- /dev/null +++ b/MathMC/448.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "不变" + }, + { + "bullet": "B", + "text": "减少" + }, + { + "bullet": "C", + "text": "增加" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "边长1分米的正方形，四个角各剪去一个边长3.5厘米的正方形，周长与原来比( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "在一个正方形的角上剪去一个正方形，原正方形的周长减少了两条剪去正方形的边长，同时也增加了两条剪去正方形的边长，据此解答. 在一个正方形的角上剪去一个正方形，原正方形的周长减少了两条剪去正方形的边长，同时也增加了两条剪去正方形的边长，所以边长1分米的正方形，四个角各剪去一个边长3.5厘米的正方形，周长与原来相比不变. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/449.json b/MathMC/449.json new file mode 100644 index 0000000000000000000000000000000000000000..e4a704bf5dd63c9135187b7745967de0922db646 --- /dev/null +++ b/MathMC/449.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "483" + }, + { + "bullet": "B", + "text": "519" + }, + { + "bullet": "C", + "text": "993" + }, + { + "bullet": "D", + "text": "1003" + } + ], + "text": "博物馆上午有435人参观，中午有237人离开，下午又来了321人，现在博物馆里有( )人参观. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意分析可知，用上午参观的人数减去中午离开的人数再加上下午来的人数即可得到现在参观的人数，故列式计算如下:435-237+321=519(人)， 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/45.json b/MathMC/45.json new file mode 100644 index 0000000000000000000000000000000000000000..26a7dbd3cbb229f46c056a926723ac4ba29aa666 --- /dev/null +++ b/MathMC/45.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "ON/C" + }, + { + "bullet": "B", + "text": "CE" + }, + { + "bullet": "C", + "text": "OFF" + } + ], + "text": "电子计算器的开关及清除键是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "计算器中，ON/C是开机键及清屏键，OFF是关机键，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/450.json b/MathMC/450.json new file mode 100644 index 0000000000000000000000000000000000000000..dcdd31ce16180f51926e083acddf53e0ae6640da --- /dev/null +++ b/MathMC/450.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "15" + } + ], + "text": "把6个篮球队进行小组比赛，每两队必须进行一场比赛，那么共要进行( )场比赛. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由于每个队都要和另外的5个队赛一场，一共要赛:5×6=30(场);又因为两个队只赛一场，去掉重复计算的情况，实际只赛:30÷2=15(场)，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/451.json b/MathMC/451.json new file mode 100644 index 0000000000000000000000000000000000000000..25c71df04f181d07e2304ad6517ccab4b2b1587f --- /dev/null +++ b/MathMC/451.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "25厘米" + }, + { + "bullet": "B", + "text": "400平方厘米" + }, + { + "bullet": "C", + "text": "5厘米" + }, + { + "bullet": "D", + "text": "25平方厘米" + } + ], + "text": "一个正方形的周长是20厘米，它积( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "一个正方形的周长是20厘米，根据正方形的周长公式:C=4a，可求出正方形的边长是多少，再根据正方形的面积公式:S=a^{2}可求出它的面积是多少，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/452.json b/MathMC/452.json new file mode 100644 index 0000000000000000000000000000000000000000..9805b91b43d408fb80748986396b5db9df024498 --- /dev/null +++ b/MathMC/452.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2:3" + }, + { + "bullet": "B", + "text": "4π:9π" + }, + { + "bullet": "C", + "text": "4:9" + } + ], + "text": "两个圆的半径比是2:3，则这两个圆的周长比是()" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由两个圆的半径的比是2:3，可把两个圆的半径分别看作2和3，则两个圆的周长分别为2π×2=4π和2π×3=6π，然后相比即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/453.json b/MathMC/453.json new file mode 100644 index 0000000000000000000000000000000000000000..055cd298404092528370be86e0be40273ced48e4 --- /dev/null +++ b/MathMC/453.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15分钟" + }, + { + "bullet": "B", + "text": "20分钟" + }, + { + "bullet": "C", + "text": "10分钟" + } + ], + "text": "明明6:35开始吃饭，6:50就吃完了.明明吃饭用了( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "用吃完饭的时刻减去开始吃饭的时刻，就是明明吃饭一共用的时间." + ] + } +} \ No newline at end of file diff --git a/MathMC/454.json b/MathMC/454.json new file mode 100644 index 0000000000000000000000000000000000000000..1fdf0b83de35ad372c7ebe9ab76b91438d3357af --- /dev/null +++ b/MathMC/454.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "36" + }, + { + "bullet": "B", + "text": "30" + }, + { + "bullet": "C", + "text": "32" + } + ], + "text": "某市为了鼓励居民节约用水，自来水公司规定如表: 用水量 15立方米及以下(含15) 每立方米1.6元；15~30立方米，每立方米2.4元；超过30立方米部分， 每立方米5元，王大伯家今年8月份缴了90元水费，那么王大伯家这个月用水量是多少立方米?" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "首先根据总价=单价×数量，求出15立方米的水的价格是多少，15*1.6=24元;然后求出30立方米的水的价格是多少，（30-15）*2.4=36元，再用王大伯家今年8月份缴的水费减去30立方米的水的价格，求出超过30立方米部分的水的价格90-24-36=30元，再用它除以超过30立方米部分每立方米的水的价格，求出超过30立方米的部分有多少立方米，30/5=6立方米，再用它加上30，求出王大伯家这个月用水量是多少立方米即可，即30+6=36立方米" + ] + } +} \ No newline at end of file diff --git a/MathMC/455.json b/MathMC/455.json new file mode 100644 index 0000000000000000000000000000000000000000..3586daab0dc8b1bc3beecd968c6926a5b2b594e7 --- /dev/null +++ b/MathMC/455.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "爸爸的年龄比儿子大" + }, + { + "bullet": "B", + "text": "抛一枚硬币，正面朝上" + }, + { + "bullet": "C", + "text": "明天会下雨" + }, + { + "bullet": "D", + "text": "太阳从东边落下" + } + ], + "text": "下面的现象中，( )是一定确定的. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "BC选项都是可能事件，也就是可能会发生，也可能不会发生. D选项是不可能事件，太阳应该是从西边落下. 但是A选项，是确定事件，爸爸的年龄比儿子大." + ] + } +} \ No newline at end of file diff --git a/MathMC/456.json b/MathMC/456.json new file mode 100644 index 0000000000000000000000000000000000000000..3d9c11299118ffc785f797c8280c67cb6ebffd82 --- /dev/null +++ b/MathMC/456.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8小时" + }, + { + "bullet": "B", + "text": "8:00" + }, + { + "bullet": "C", + "text": "9小时" + } + ], + "text": "妈妈每天工作时间是7:30∼ 11:30，13:00∼ 17:00.她每天工作( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "经过的时间=结束时间-起始时间，从7时30分到11时30分，经过了11时30分-7时30分=4时，从13时到17时，经过17时-13时=4时，一天的工作时间是4时+4时=8时. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/457.json b/MathMC/457.json new file mode 100644 index 0000000000000000000000000000000000000000..066fee296d49503eb07a595a0200e9af149d8ca7 --- /dev/null +++ b/MathMC/457.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "9" + } + ], + "text": "A=2× 3× 5，A的因数有( )个. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "(1+1)(1+1)(1+1)=8." + ] + } +} \ No newline at end of file diff --git a/MathMC/458.json b/MathMC/458.json new file mode 100644 index 0000000000000000000000000000000000000000..51d3a50bbef54b0305cc5f159ad94a898dded18f --- /dev/null +++ b/MathMC/458.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7/10 米" + }, + { + "bullet": "B", + "text": "7/10" + }, + { + "bullet": "C", + "text": "1/10" + }, + { + "bullet": "D", + "text": "1/10 米" + } + ], + "text": "把7米长的铁丝平均截成10段，每段是7米的( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把一根7米长的铁丝，平均分成10段，根据分数的意义，即将这根铁丝当作单位‘1‘平均分成10份，则每份占全长的1÷10= 1/10" + ] + } +} \ No newline at end of file diff --git a/MathMC/459.json b/MathMC/459.json new file mode 100644 index 0000000000000000000000000000000000000000..680706b8a5334a441d1235cae295eac40447b9fa --- /dev/null +++ b/MathMC/459.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5×O.7" + }, + { + "bullet": "B", + "text": "5+0.7" + }, + { + "bullet": "C", + "text": "5×1.7" + }, + { + "bullet": "D", + "text": "5+1" + } + ], + "text": "下列算式中，计算结果小于5的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "要想知道哪个算式的结果小于5，计算出结果再比较它们的结果是否小于5，注意计算的方法." + ] + } +} \ No newline at end of file diff --git a/MathMC/46.json b/MathMC/46.json new file mode 100644 index 0000000000000000000000000000000000000000..f788fecf349d8cc8fc7de7fdaa5203ec560284c4 --- /dev/null +++ b/MathMC/46.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "1" + }, + { + "bullet": "C", + "text": "\\frac{2}{5}" + }, + { + "bullet": "D", + "text": "\\frac{252}{25}" + } + ], + "text": "计算12÷ \\frac{5}{2}+12÷ \\frac{5}{3} 的结果是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "除变乘，再提取公因数计算即可. ~~~~12÷ \\frac{5}{2}+12÷ \\frac{5}{3} =12× \\frac{2}{5}+12× \\frac{3}{5} =12× (\\frac{2}{5}+\\frac{3}{5}) =12× 1 =12." + ] + } +} \ No newline at end of file diff --git a/MathMC/460.json b/MathMC/460.json new file mode 100644 index 0000000000000000000000000000000000000000..9be74d9b51b591db2de809a412e0478f34eec6c0 --- /dev/null +++ b/MathMC/460.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "17" + }, + { + "bullet": "B", + "text": "1" + }, + { + "bullet": "C", + "text": "1或17" + }, + { + "bullet": "D", + "text": "17的倍数" + } + ], + "text": "如果一个数的因数有17，那么这个数一定是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据一个数的倍数是无限的，最小的倍数是它本身，由此即可进行解答，所以:如果一个数的因数有17，那么这个数一定是17的倍数. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/461.json b/MathMC/461.json new file mode 100644 index 0000000000000000000000000000000000000000..114ed0407096e399c08b5ed3ecf7b652a370df5f --- /dev/null +++ b/MathMC/461.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "77%" + }, + { + "bullet": "B", + "text": "123%" + }, + { + "bullet": "C", + "text": "23%" + }, + { + "bullet": "D", + "text": "2.3%" + } + ], + "text": "今年玉米的产量比去年增加了二成三，今年玉米的产量相当于去年的( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "二成三，即百分之二十三，把去年的产量看成单位‘1‘，那么今年的产量就是去年的(1+23%);据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/462.json b/MathMC/462.json new file mode 100644 index 0000000000000000000000000000000000000000..8ac570d4ec4bfde13bc8e969d1658cb70090b00f --- /dev/null +++ b/MathMC/462.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "变大" + }, + { + "bullet": "B", + "text": "变小" + }, + { + "bullet": "C", + "text": "不变" + } + ], + "text": "如果一个梯形的高不变，上底增加6厘米，下底减少6厘米，这个梯形的面积( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "梯形的面积=(上底+下底)×高÷2，如果‘上底增加6厘米，下底减少6厘米，高不变‘，那么(上底+下底)的和不变，且高不变，从而得知梯形的面积也不变.解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/463.json b/MathMC/463.json new file mode 100644 index 0000000000000000000000000000000000000000..273659be9b8e9120b0463b79862490a29104a35f --- /dev/null +++ b/MathMC/463.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "体积相等，表面积不相等" + }, + { + "bullet": "B", + "text": "体积和表面积都不相等" + }, + { + "bullet": "C", + "text": "表面积相等，体积不相等" + } + ], + "text": "将一个正方体钢坯锻造成长方体，正方体和长方体 ( )。" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据体积的意义，物体所占空间的大小叫做物体的体积。将一个正方体钢坯锻造成长方体，只有形状变了，但体积不变，据此解答。 将一个正方体钢坯锻造成长方体，只是形状变了，但体积不变;所以正方体和长方体的体积相等，表面积不相等。 故选:A。" + ] + } +} \ No newline at end of file diff --git a/MathMC/464.json b/MathMC/464.json new file mode 100644 index 0000000000000000000000000000000000000000..d2f5133a58fcc94c15701b9c1778c4a4b27cd795 --- /dev/null +++ b/MathMC/464.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "10" + } + ], + "text": "最小的质数乘以最小的合数，积是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "自然数中，除了1和它本身外没有别的因数的数为质数;除了1和它本身外还有别的因数的数为合数;据此可知，最小的质数为2，最小的合数为4." + ] + } +} \ No newline at end of file diff --git a/MathMC/465.json b/MathMC/465.json new file mode 100644 index 0000000000000000000000000000000000000000..b1882119b13dde5c27e6edf6e0a6e16f84a37cc4 --- /dev/null +++ b/MathMC/465.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "11" + }, + { + "bullet": "B", + "text": "10" + }, + { + "bullet": "C", + "text": "1" + } + ], + "text": "由一个十和1个一组成的数是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "一个十即在十位上是1，一个1即个位上是1，故这个数是11.选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/466.json b/MathMC/466.json new file mode 100644 index 0000000000000000000000000000000000000000..e21b5501e8ef441f900e00da804b8ef024ab0efc --- /dev/null +++ b/MathMC/466.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{5}是倒数" + }, + { + "bullet": "B", + "text": "\\frac{5}{3}是倒数" + }, + { + "bullet": "C", + "text": "\\frac{5}{3}和 \\frac{3}{5}互为倒数" + } + ], + "text": "因为 \\frac{5}{3}× \\frac{3}{5}=1，所以( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据倒数的意义，乘积是1的两个数互为倒数.据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/467.json b/MathMC/467.json new file mode 100644 index 0000000000000000000000000000000000000000..16d209b813ae5b7911091c661d4ca66053ce6aed --- /dev/null +++ b/MathMC/467.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5×8=40(盏)40×6=240(盏)" + }, + { + "bullet": "B", + "text": "5×8=40(层)40×6=240(盏)" + }, + { + "bullet": "C", + "text": "5×8=40(个)40×6=240(盏)" + } + ], + "text": "一幢楼有5层教室，每层有8个班级，每个班级装6盏电灯，这幢楼一共要装多少盏电灯?下面正确的列式是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "一共有多少个班级:5×8=40(个)， 一共有多少盏灯:40×6=240(盏). 答:这幢楼一共要装240盏电灯. 故选:C. 根据题意，先求出一共有多少个班级，再根据每个班级装6盏电灯，求出一共有多少盏灯.此题考查简单的归总问题，解决此题的关键是求一共有多少个班级." + ] + } +} \ No newline at end of file diff --git a/MathMC/468.json b/MathMC/468.json new file mode 100644 index 0000000000000000000000000000000000000000..4f30cce09fa8505162d0fdb980f5b2e002f1c49a --- /dev/null +++ b/MathMC/468.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{81}" + }, + { + "bullet": "B", + "text": "\\frac{16}{9}" + }, + { + "bullet": "C", + "text": "\\frac{8}{81}" + }, + { + "bullet": "D", + "text": "\\frac{16}{81}" + } + ], + "text": "\\frac{4}{9}×\\frac{4}{9}=( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据分数乘法的计算方法，计算出\\frac{4}{9}×\\frac{4}{9}的积，然后再进一步解答. 试题解析:\\frac{4}{9}×\\frac{4}{9}=\\frac{16}{81}. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/469.json b/MathMC/469.json new file mode 100644 index 0000000000000000000000000000000000000000..766d01678dc8b700fe4cad70ce069eda68b050d0 --- /dev/null +++ b/MathMC/469.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲=乙" + }, + { + "bullet": "B", + "text": "甲>乙" + }, + { + "bullet": "C", + "text": "甲<乙" + }, + { + "bullet": "D", + "text": "不确定" + } + ], + "text": "甲数是7777776/7777777，乙数是9999998/9999999，那么甲乙两数的关系是（ ）" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "比较甲乙两数的大小，可以通过比较1减去甲数的差和1减去乙数的差来计算，如果1减去甲数的差大于1减去乙数的差，则乙数较大，反之甲数大。1-甲数=1/7777777，1-乙数=1/9999999，分子相同，分母越大，分数越小，所以甲<乙。选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/47.json b/MathMC/47.json new file mode 100644 index 0000000000000000000000000000000000000000..cda229487b5399ea94e318446d76244f3599913d --- /dev/null +++ b/MathMC/47.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{30}" + }, + { + "bullet": "B", + "text": "\\frac{1}{30 000}" + }, + { + "bullet": "C", + "text": "\\frac{1}{3 000 000}" + } + ], + "text": "把线段比例尺千米改写成数值比例尺是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意可知:此线段比例尺表示的是图上距离1厘米代表实际距离30千米， 又因30千米=3000000厘米 则1厘米:3000000厘米=1:3000000; 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/470.json b/MathMC/470.json new file mode 100644 index 0000000000000000000000000000000000000000..7a92a07b11b58c0cac0810c716648925a9c31838 --- /dev/null +++ b/MathMC/470.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲车快" + }, + { + "bullet": "B", + "text": "乙车快" + }, + { + "bullet": "C", + "text": "两车一样快" + } + ], + "text": "从A地到B地，甲车4小时行了全程的，乙车5小时行了全程的，两车的速度相比，( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "首先根据路程÷时间=速度，分别求出两车的速度是多少;然后比较大小，判断出哪辆车的速度即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/471.json b/MathMC/471.json new file mode 100644 index 0000000000000000000000000000000000000000..3ed7daa0c4685d76382c4afb0a578a55d9553baf --- /dev/null +++ b/MathMC/471.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "72÷25%" + }, + { + "bullet": "B", + "text": "72÷(1-25%)" + }, + { + "bullet": "C", + "text": "72×(1-25%)" + }, + { + "bullet": "D", + "text": "72×(1+25%)" + } + ], + "text": "一种电子手表售价比原来降低了25%是72元.原来售价多少元?正确的列式应是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把原价看作单位‘1‘，原价的(1-25%)是72元，根据已知一个数的几分之几是多少，求这个数，直接用除法解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/472.json b/MathMC/472.json new file mode 100644 index 0000000000000000000000000000000000000000..36bd828c83eff7963988a8e99f02673550cf52b4 --- /dev/null +++ b/MathMC/472.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "降了1%" + }, + { + "bullet": "B", + "text": "涨了1%" + }, + { + "bullet": "C", + "text": "降了10%" + }, + { + "bullet": "D", + "text": "不变" + } + ], + "text": "水果超市十二月的价格第二周比第一周涨了10%，第三周比第二周降了10%，第三周的价格比第一周的价格( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "因为由题干可知，价格第二周比第一周涨了10%，则第二周为第一周的1+10%=110%，第三周比第二周降了10%，所以第三周价格为第一周的110%× (1-10%)=99%，则第三周的价格比第一周的价格降了1-99%=1%，故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/473.json b/MathMC/473.json new file mode 100644 index 0000000000000000000000000000000000000000..bfb480c1151928f091557dd7d49b5842a5960410 --- /dev/null +++ b/MathMC/473.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "40×20" + }, + { + "bullet": "B", + "text": "54×40" + }, + { + "bullet": "C", + "text": "19×52" + }, + { + "bullet": "D", + "text": "54×25" + } + ], + "text": "下列算式中，积最接近1000的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分别算出各算式的结果，选出结果接近1 000的算式.本题通过计算积最接近1 000的是19×52，故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/474.json b/MathMC/474.json new file mode 100644 index 0000000000000000000000000000000000000000..d1ecf198d5ecb96222eec62e400be5de53519dd8 --- /dev/null +++ b/MathMC/474.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "35×20+35×4" + }, + { + "bullet": "B", + "text": "35×20×4" + }, + { + "bullet": "C", + "text": "35×4×6" + }, + { + "bullet": "D", + "text": "40×24-5×24" + } + ], + "text": "与‘35×24‘的计算结果不相等的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，逐步分析每个选项，然后再进一步解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/475.json b/MathMC/475.json new file mode 100644 index 0000000000000000000000000000000000000000..00a2f422556abcce227755bb78f0672363463b2d --- /dev/null +++ b/MathMC/475.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "0" + }, + { + "bullet": "C", + "text": "1" + } + ], + "text": "709×4的积的十位上的数是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据因数中间有0的乘法计算可知，709的中间数字是0，所以个位数字9与4相乘的积，向前一位进几，积的十位上数字就是几，由此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/476.json b/MathMC/476.json new file mode 100644 index 0000000000000000000000000000000000000000..98d4cb5a68059d5eab36cbedbdeaa44307015afe --- /dev/null +++ b/MathMC/476.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "36+46" + }, + { + "bullet": "B", + "text": "87-12" + }, + { + "bullet": "C", + "text": "90-21" + }, + { + "bullet": "D", + "text": "58+14" + } + ], + "text": "估一估，下面算式结果小于70的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "按照估算的方法，分析四个选项，找出结果比70小的即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/477.json b/MathMC/477.json new file mode 100644 index 0000000000000000000000000000000000000000..a9f3f179b0423310a6bd27771e574fd2adc7827c --- /dev/null +++ b/MathMC/477.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6 7 8" + }, + { + "bullet": "B", + "text": "3 3 5" + }, + { + "bullet": "C", + "text": "5 3 8" + } + ], + "text": "下面各组线段(单位:厘米)不能围成三角形的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "三角形三边之间的关系为两边之和大于第三边，判断是否能组成三角形，就用其中较小的两个数相加和第三个数作比较，大于第三边能组成三角形，小于等于第三边就不能组成三角形. \\text A中6+7=13>8，可以组成; \\text B中3+3=6>5可以组成三角形; \\text C中5+3=8所以不能组成三角形， 答案选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/478.json b/MathMC/478.json new file mode 100644 index 0000000000000000000000000000000000000000..d7b4f33b0b99319631b267a46b8d3ca72d03cf07 --- /dev/null +++ b/MathMC/478.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "5" + }, + { + "bullet": "D", + "text": "8" + } + ], + "text": "101× {3□ }<{}3700，□ 里最大可以填( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "3700÷ 101=36··· ··· 64，则□ 最大填6，选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/479.json b/MathMC/479.json new file mode 100644 index 0000000000000000000000000000000000000000..f3407df6da13b8100c8190c38d9c3854b6bfd67e --- /dev/null +++ b/MathMC/479.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "科技书比故事书少\\frac{2}{5}" + }, + { + "bullet": "B", + "text": "故事书比科技书多\\frac{2}{5}" + }, + { + "bullet": "C", + "text": "故事书比科技书少\\frac{2}{5}." + }, + { + "bullet": "D", + "text": "科技书比故事书多\\frac{2}{5}" + } + ], + "text": "学校里有科技书550本，用算式:550× ( 1-\\frac{2}{5}) 解决‘故事书有多少本?‘这个问题时，需要补充的信息是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在题目中可知单位1为科技书，用科技书× ( 1-\\frac{2}{5})，所以可知故事书比科技书少\\frac{2}{5}，选择C. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/48.json b/MathMC/48.json new file mode 100644 index 0000000000000000000000000000000000000000..f52a141224ae55b8b57cb26d0117fe9a95a9294b --- /dev/null +++ b/MathMC/48.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "4" + }, + { + "bullet": "D", + "text": "1" + } + ], + "text": "要使59□480≈60万，□里有( )种填法. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "从题目上看本题四舍五入到万位，要看千位上的数，大于等于5的数进1，小于5的数舍去，59□480≈60万进了1，所以□里应该是大于等于5的数.所以□里 应填5~9的数." + ] + } +} \ No newline at end of file diff --git a/MathMC/480.json b/MathMC/480.json new file mode 100644 index 0000000000000000000000000000000000000000..bb294290c2693e4fda03d1bc021092471774e35b --- /dev/null +++ b/MathMC/480.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1- \\frac{{2}^{48}}{9603}" + }, + { + "bullet": "B", + "text": "\\frac{{2}^{48}}{9603}" + }, + { + "bullet": "C", + "text": "1- \\frac{{2}^{48}}{3201}" + }, + { + "bullet": "D", + "text": "\\frac{{2}^{48}}{3201}" + } + ], + "text": "设S= \\frac{2}{1× 3× 5}+ \\frac{{2}^{2}}{3× 5× 7}+ \\frac{{2}^{3}}{5× 7× 9}+…+ \\frac{{2}^{48}}{95× 97× 99}，T= \\frac{1}{1× 3}+ \\frac{2}{3× 5}+ \\frac{{2}^{2}}{5× 7}+…+ \\frac{{2}^{47}}{95× 97}，则12S-3T= ( )." + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "解:∵S= \\frac{2}{1× 3× 5}+ \\frac{{2}^{2}}{3× 5× 7}+ \\frac{{2}^{3}}{5× 7× 9}+…+ \\frac{{2}^{48}}{95× 97× 99}，T= \\frac{1}{1× 3}+ \\frac{2}{3× 5}+ \\frac{{2}^{2}}{5× 7}+…+ \\frac{{2}^{47}}{95× 97}，则， ∴4S=2( \\frac{1}{3× 5}- \\frac{1}{3× 5})+2^{2}( \\frac{1}{3× 5}- \\frac{1}{5× 7})+2^{3}( \\frac{1}{5× 7}- \\frac{1}{7× 9})+…+2^{48}( \\frac{1}{95× 97}- \\frac{1}{97× 99}) = \\frac{2}{1× 3}+ \\frac{2}{3× 5}+ \\frac{4}{5× 7}+ \\frac{8}{7× 9}+…+ \\frac{{2}^{47}}{95× 97}+ \\frac{{2}^{48}}{97× 99}， ∴4S-T= \\frac{1}{1× 3}- \\frac{{2}^{48}}{97× 99}， ∴12S-3T=3( \\frac{1}{1× 3}- \\frac{{2}^{48}}{97× 99})=1- \\frac{{2}^{48}}{97× 33}=1- \\frac{{2}^{48}}{3201}， 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/481.json b/MathMC/481.json new file mode 100644 index 0000000000000000000000000000000000000000..2bbfc57c394e39e61e82604ba02a25c78b08ecd1 --- /dev/null +++ b/MathMC/481.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "南偏西30°" + }, + { + "bullet": "B", + "text": "西偏北30°" + }, + { + "bullet": "C", + "text": "西偏北60°" + } + ], + "text": "北偏西30°，还可以说成( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据东、西、南、北四个基本方向中，相邻的两个方向的夹角是90度，即可解答本题." + ] + } +} \ No newline at end of file diff --git a/MathMC/482.json b/MathMC/482.json new file mode 100644 index 0000000000000000000000000000000000000000..935ebf514e8610ba30d9922050f1e1f2044af874 --- /dev/null +++ b/MathMC/482.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲" + }, + { + "bullet": "B", + "text": "乙" + }, + { + "bullet": "C", + "text": "丙" + } + ], + "text": "在百米赛跑中，甲用了 \\frac{1}{4}分钟，乙用了 \\frac{1}{5}分钟，丙用了 \\frac{3}{10}分钟.( )的成绩最好. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把分数转化成小数，然后运用小数的大小比较进行解答，据此即可判断出它们所用时间的多少，用时多的跑得较慢，用时少的跑得较快，据此判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/483.json b/MathMC/483.json new file mode 100644 index 0000000000000000000000000000000000000000..12778b63f0c2de033fc4ace2ff171d81f08e14dc --- /dev/null +++ b/MathMC/483.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8平方厘米" + }, + { + "bullet": "B", + "text": "16平方厘米" + }, + { + "bullet": "C", + "text": "24平方厘米" + } + ], + "text": "把棱长2厘米的正方体切成8个完全一样的小正方体，这些小正方体的表面积的和比原来大正方体的表面积增加了多少平方厘米?( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "利用正方体的表面积公式，代入数据求出小正方体的表面积之和减去大正方体的表面积即可" + ] + } +} \ No newline at end of file diff --git a/MathMC/484.json b/MathMC/484.json new file mode 100644 index 0000000000000000000000000000000000000000..9ea28adb9cb38dafbebfdb18874e4a158c047817 --- /dev/null +++ b/MathMC/484.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{5}÷ \\frac{9}{100}" + }, + { + "bullet": "B", + "text": "\\frac{9}{100}÷ \\frac{3}{5}" + }, + { + "bullet": "C", + "text": "\\frac{3}{5}× \\frac{9}{100}" + }, + { + "bullet": "D", + "text": "1 ÷ \\frac{9}{100}" + } + ], + "text": "\\frac{3}{5}吨大豆可以榨油 \\frac{9}{100}吨，1吨大豆可榨油多少吨?正确的列式是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "\\frac{3}{5}吨大豆可榨油\\frac{9}{100}吨，10吨大豆可炸(\\frac{9}{100}÷ \\frac{3}{5})吨." + ] + } +} \ No newline at end of file diff --git a/MathMC/485.json b/MathMC/485.json new file mode 100644 index 0000000000000000000000000000000000000000..9776dde0e1fce206b5fe7e2cb50607fc3fa85e4e --- /dev/null +++ b/MathMC/485.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "419820" + }, + { + "bullet": "B", + "text": "420200" + }, + { + "bullet": "C", + "text": "420099" + } + ], + "text": "下面三个数‘四舍五入‘后都得42万，其中( )最接近42万. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "A.420000-419820=180， B.420200-420000=200， C.420099-420000=99， 因为99<{}180<{}200，所以420099最接近420000，故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/486.json b/MathMC/486.json new file mode 100644 index 0000000000000000000000000000000000000000..c161ad4bc7c3397c714363f0b33d6d54deb3f00b --- /dev/null +++ b/MathMC/486.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形面积大" + }, + { + "bullet": "B", + "text": "正方形面积大" + }, + { + "bullet": "C", + "text": "相等" + } + ], + "text": "一个长方形和一个正方形的周长相等，面积( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "正方形和长方形的周长相等，正方形的面积比长方形的面积大.可以通过举例证明，如它们的周长都是24厘米，长方形的长是8厘米，宽是4厘米;正方形的边长是6厘米;利用各自的面积公式，求出面积，比较后即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/487.json b/MathMC/487.json new file mode 100644 index 0000000000000000000000000000000000000000..a679c86f18659d6aad71c894b9658a97f9a96543 --- /dev/null +++ b/MathMC/487.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4π" + }, + { + "bullet": "B", + "text": "6π" + }, + { + "bullet": "C", + "text": "10π" + } + ], + "text": "用一张长6厘米，宽4厘米的长方形纸剪一个尽可能大的圆，这个圆的周长是( )厘米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "对于这道题，从题干我们可以知道:用一张长6厘米，宽4厘米的长方形纸剪一个尽可能大的圆， 那么这个最大圆的直径应该等于4厘米， 所以:这个圆的周长是:直径× π =4π . 即选择A选项." + ] + } +} \ No newline at end of file diff --git a/MathMC/488.json b/MathMC/488.json new file mode 100644 index 0000000000000000000000000000000000000000..366655d8bfb9df8f88075893027cd62db4139ff3 --- /dev/null +++ b/MathMC/488.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "7" + }, + { + "bullet": "D", + "text": "8" + } + ], + "text": "王东玩掷骰子游戏，要保证掷出的骰子总数至少有两次相同，他最少应掷( )次. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "6+1=7(次); C. 骰子能掷出的结果只有6种，掷7次的话必有2次相同;即把骰子的出现的六种情况看作‘抽屉‘，把掷出的次数看作‘物体的个数‘，要保证至少有两次相同，那么物体个数应比抽屉数至少多1;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/489.json b/MathMC/489.json new file mode 100644 index 0000000000000000000000000000000000000000..3ded0bc0ae5060ad8b5b9a923262a04c4b0bde34 --- /dev/null +++ b/MathMC/489.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "钟摆的运动" + }, + { + "bullet": "B", + "text": "大风车的转动" + }, + { + "bullet": "C", + "text": "方向盘的转运" + }, + { + "bullet": "D", + "text": "电梯的升降运动" + } + ], + "text": "下列是现象中，不属于旋转变换的是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "电梯的升降运动不是围绕着固定的一点在运动的." + ] + } +} \ No newline at end of file diff --git a/MathMC/49.json b/MathMC/49.json new file mode 100644 index 0000000000000000000000000000000000000000..adc4745d8da76e5530fe29af086c25ff133aa903 --- /dev/null +++ b/MathMC/49.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "3" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "有15个大小、形状一样的小铁球，其中有一个小铁球重一点，如果能用天平称，至少称( )次保证找出这个稍重的小铁球. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把这15个小铁球分成3组，(5，5，5)，称第一次，天平每边放一组，如果天平平衡，较重铁球在未称的一组，如果天平不平衡，较重铁球在重的一边;把有较重铁球的一组再分成三组，(2，2，1)，称第二次，天平每边放2个，如果平衡，较重铁球是未称的1个，如果不平衡，较重铁球在重的一边;再把有较重铁球的一组称第三次，天平每边放1个，重的一边是较重铁球." + ] + } +} \ No newline at end of file diff --git a/MathMC/490.json b/MathMC/490.json new file mode 100644 index 0000000000000000000000000000000000000000..af67e0345e3b2a0baa69901ce0b7af4b96d63896 --- /dev/null +++ b/MathMC/490.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{38}{45}÷ \\frac{5}{6}" + }, + { + "bullet": "B", + "text": "\\frac{38}{45}÷ \\frac{6}{5}" + }, + { + "bullet": "C", + "text": "\\frac{38}{45}× \\frac{3}{8}" + }, + { + "bullet": "D", + "text": "\\frac{38}{45}÷ \\frac{9}{9}" + } + ], + "text": "下面算式中，( )的结果大于 \\frac{38}{45}. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "一个数(0除外)除以小于1的数，商大于被除数;一个数(0除外)除以大于1的数，商小于被除数; 一个数(0除外)乘小于1的数，积小于原数;一个数(0除外)乘大于1的数，积大于原数;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/491.json b/MathMC/491.json new file mode 100644 index 0000000000000000000000000000000000000000..f048526e75e6d9a4225fc9273dfd48a93bf2c5b1 --- /dev/null +++ b/MathMC/491.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "圆周率是一个无限不循环小数" + }, + { + "bullet": "B", + "text": "圆周率是一个固定不变的值" + }, + { + "bullet": "C", + "text": "圆周率用字母π表示" + }, + { + "bullet": "D", + "text": "圆周率等于3.14" + } + ], + "text": "关于圆周率，下面说法错误的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "圆周率的含义:圆的周长和它直径的比值，叫做圆周率，用字母π表示，π是一个无限不循环小数;据此进行分析解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/492.json b/MathMC/492.json new file mode 100644 index 0000000000000000000000000000000000000000..3fb35e8610551d8ee876a166ea9aabe17eb55cff --- /dev/null +++ b/MathMC/492.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20厘米，20平方厘米" + }, + { + "bullet": "B", + "text": "20厘米，25平方厘米" + }, + { + "bullet": "C", + "text": "25厘米，25平方厘米" + } + ], + "text": "用一根长20厘米的铁丝围成一个正方形，这个正方形的周长和面积分别是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "周长:20厘米;面积:20÷ 4=5( 厘米 )，5× 5=25( c{{m}^{2}} )." + ] + } +} \ No newline at end of file diff --git a/MathMC/493.json b/MathMC/493.json new file mode 100644 index 0000000000000000000000000000000000000000..3da06838f958291615977406202f79b3d4be4ec9 --- /dev/null +++ b/MathMC/493.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12 分米" + }, + { + "bullet": "B", + "text": "6 分米" + }, + { + "bullet": "C", + "text": "2分米" + } + ], + "text": "一个梯形的面积是30平方分米，高是3分米，上底是8分米，下底是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据梯形的面积=(上底+下底)×高÷2，可得:梯形的下底=梯形的面积×2÷高-上底，据此代入数据即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/494.json b/MathMC/494.json new file mode 100644 index 0000000000000000000000000000000000000000..cc914a7795107aadd6e36bc2eb74e7c3f86dec82 --- /dev/null +++ b/MathMC/494.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "250+190÷20×5" + }, + { + "bullet": "B", + "text": "(250+190)÷20×5" + }, + { + "bullet": "C", + "text": "250+190÷(20×5)" + }, + { + "bullet": "D", + "text": "(250+190÷20)×5" + } + ], + "text": "将250+190=440，440÷20=22，22×5=110写成综合算式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "250+190=440，440÷20=22，22×5=110先算250与190的和，然后用求出的和除以20求出商，再用求得的商乘5即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/495.json b/MathMC/495.json new file mode 100644 index 0000000000000000000000000000000000000000..8ddd66725560dc071ad336238640ab3ed198d6a2 --- /dev/null +++ b/MathMC/495.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6.45" + }, + { + "bullet": "B", + "text": "64.5" + }, + { + "bullet": "C", + "text": "645" + }, + { + "bullet": "D", + "text": "6450" + } + ], + "text": "如果两个因数的积是64.5，其中一个因数不变，另一个因数乘10，这时两个因数的乘积是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据积的变化规律:两数相乘，如果一个因数不变，另一个因数扩大或缩小几倍(0除外)，积也会随之扩大或缩小相同的倍数，据此解答即可得到答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/496.json b/MathMC/496.json new file mode 100644 index 0000000000000000000000000000000000000000..045ca2bb2095ed7e9614ac6e4ce1d968c9ee34a7 --- /dev/null +++ b/MathMC/496.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "543-300-1" + }, + { + "bullet": "B", + "text": "543-300+1" + }, + { + "bullet": "C", + "text": "540-299+3" + } + ], + "text": "543-299的简便算法是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据减法的速算方法，当减数接近整十、整百、整千…，把减数看作与它接近的整十、整百、整千数来减，多减去几，就再加上几." + ] + } +} \ No newline at end of file diff --git a/MathMC/497.json b/MathMC/497.json new file mode 100644 index 0000000000000000000000000000000000000000..ff0e5fb6588594354e2025294fd6a58ae3c5fc5a --- /dev/null +++ b/MathMC/497.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "一筐苹果有50个，最少要增加( )个，才能平均分给7个小朋友刚好够分.最少要拿走( )个，就能刚好平均分给8个小朋友. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "(1)找出7的倍数中和50最接近的、并且比50多的数，然后减50即可; (2)用50减去8的倍数中和50最接近的、并且比50少的数即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/498.json b/MathMC/498.json new file mode 100644 index 0000000000000000000000000000000000000000..94db1f079db4bd6214126d52183cbd2fcad7d468 --- /dev/null +++ b/MathMC/498.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "缩小到原来的2倍" + }, + { + "bullet": "B", + "text": "扩大到原来的4倍" + }, + { + "bullet": "C", + "text": "缩小到原来的4倍" + }, + { + "bullet": "D", + "text": "扩大到原来的2倍" + } + ], + "text": "一个分数的分子扩大到原来的2倍，分母缩小到原来的2倍，分数值( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "2× 2=4. 分母不变，分子扩大到原来的m倍，分数值扩大到原来的m倍，分子不变，分母缩小到原来的n倍，分数值扩大到原来的n倍." + ] + } +} \ No newline at end of file diff --git a/MathMC/499.json b/MathMC/499.json new file mode 100644 index 0000000000000000000000000000000000000000..c903266e095e8889bd4dcb0a54f7af0c38185206 --- /dev/null +++ b/MathMC/499.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8÷0" + }, + { + "bullet": "B", + "text": "804÷(75-75)" + }, + { + "bullet": "C", + "text": "(75-75)÷804" + }, + { + "bullet": "D", + "text": "612÷(21-3×7)" + } + ], + "text": "下列算式中，得数是0的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据‘0‘不能做除数，因此A、B、D都无意义，因此只有C得数是0." + ] + } +} \ No newline at end of file diff --git a/MathMC/5.json b/MathMC/5.json new file mode 100644 index 0000000000000000000000000000000000000000..d618285df3369e019e315f02dc8c1d90f17fa0cb --- /dev/null +++ b/MathMC/5.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "h" + }, + { + "bullet": "B", + "text": "b" + }, + { + "bullet": "C", + "text": "c" + }, + { + "bullet": "D", + "text": "f" + } + ], + "text": "某校数学竞赛，a、b、c、d、e、f、g、h八位同学获得前八名.老师让他们猜一下谁是第一名. a说:‘或者f是第一名，或者h是第一名.‘ b说:‘我是第一名.‘ c说:‘g是第一名.‘ d说:‘b不是第一名.‘ e说:‘a说得不对.‘ f说:‘我不是第一名，h也不是第一名.‘ g说:‘c不是第一名.‘ h说:‘我同意a的意见.‘ 老师指出:八个人中有三人猜对了，那么第一名是 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "此题可以采用假设法进行讨论，根据八个人中只有三人猜对了进行推理判断假设是否成立，由此即可得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/50.json b/MathMC/50.json new file mode 100644 index 0000000000000000000000000000000000000000..7990f6ada14e4b140dcac1cbb28d21d71e849429 --- /dev/null +++ b/MathMC/50.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{2}m-P" + }, + { + "bullet": "B", + "text": "m÷\\frac{1}{2}+P" + }, + { + "bullet": "C", + "text": "(m-P)÷\\frac{1}{2}" + }, + { + "bullet": "D", + "text": "(m+P)÷\\frac{1}{2}" + } + ], + "text": "m比一个数的\\frac{1}{2}少了P，则这个数是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据题意知道:m=一个数×\\frac{1}{2}-P，由此先求出一个数的\\frac{1}{2}，再求出一个数. 试题解析:(m+p)÷\\frac{1}{2}; 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/500.json b/MathMC/500.json new file mode 100644 index 0000000000000000000000000000000000000000..636458a63e41da74d8a3cde3f53326187ae44e72 --- /dev/null +++ b/MathMC/500.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "110" + }, + { + "bullet": "B", + "text": "121" + }, + { + "bullet": "C", + "text": "115" + }, + { + "bullet": "D", + "text": "120" + } + ], + "text": "春天幼儿园中班小朋友的平均身高是115厘米，其中男孩比女孩多，女孩平均身高比男孩高10%，这个班男孩的平均身高是( )厘米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "假设男生数量是n，男生平均身高是h，那么女生数量是，女生平均身高是，由此得到方程:(×+n×h)÷(+n)=115，解方程即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/501.json b/MathMC/501.json new file mode 100644 index 0000000000000000000000000000000000000000..9abbc648ac82b5f674510d5080c84d787f6e2cf1 --- /dev/null +++ b/MathMC/501.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6.5÷0.125" + }, + { + "bullet": "B", + "text": "6.5÷12.5" + }, + { + "bullet": "C", + "text": "6.5÷1.25" + } + ], + "text": "下面算式中，商最大的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "6.5÷0.125=52;6.5÷12.5=0.52;6.5÷1.25=5.2，通过计算，我们发现6.5÷0.125的商最大." + ] + } +} \ No newline at end of file diff --git a/MathMC/502.json b/MathMC/502.json new file mode 100644 index 0000000000000000000000000000000000000000..1ce429cd5cc46b9b35642d3115946f41bac70f4c --- /dev/null +++ b/MathMC/502.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "不变" + }, + { + "bullet": "B", + "text": "减少了" + }, + { + "bullet": "C", + "text": "增加了" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "精挑细选. (3)一边长为1分米的正方形，四个角各剪去一个边长为1厘米的小正方形，那么它的周长和原来比( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "可以根据周长的定义直接判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/503.json b/MathMC/503.json new file mode 100644 index 0000000000000000000000000000000000000000..0c2401f633fb13ebc95a20fc3fac1e033306589e --- /dev/null +++ b/MathMC/503.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "一个边长为2分米的正方形，如果在四个角各剪去一个边长为2厘米的正方形，那么它的周长与原来比是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据正方形边长的周长计算公式解答此题即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/504.json b/MathMC/504.json new file mode 100644 index 0000000000000000000000000000000000000000..9107a6ea2444dfe6844367aad34f5c661e352a74 --- /dev/null +++ b/MathMC/504.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "等于" + }, + { + "bullet": "C", + "text": "小于" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "A、B两个数均不为0，A的等于B的，那么A( )B. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意知，A×=B×，比较两个分数的大小，根据‘积一定的情况下，一个因数小则另一个因数就大‘来判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/505.json b/MathMC/505.json new file mode 100644 index 0000000000000000000000000000000000000000..cb8c7fecf093e89f71b2b6255c32108652b326e3 --- /dev/null +++ b/MathMC/505.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "199+197" + }, + { + "bullet": "B", + "text": "519-112" + }, + { + "bullet": "C", + "text": "189+198" + } + ], + "text": "下面算式的结果大于400的是( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "A选项中，199≈200，197≈200，200+200=400，199<200，197<200，199+197一定小于400。 B选项中，519≈520，112≈110，520-110=410，519-112约是410，大于400。 C选项中，189≈190，198≈200，190+200=390，189<190，198<200，189+198一定小于390。 综上所述，应选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/506.json b/MathMC/506.json new file mode 100644 index 0000000000000000000000000000000000000000..e4d8bc919376298736ab378d1ed2b2dc5455c016 --- /dev/null +++ b/MathMC/506.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{5}{8}×( \\frac{3}{4}- \\frac{1}{3} )" + }, + { + "bullet": "B", + "text": "\\frac{5}{8}×( \\frac{3}{4}+ \\frac{1}{3})" + }, + { + "bullet": "C", + "text": "\\frac{5}{8}÷( \\frac{3}{4}- \\frac{1}{3})" + }, + { + "bullet": "D", + "text": "\\frac{5}{8}÷( \\frac{3}{4}+ \\frac{1}{3}) E. \\frac{5}{8}×( \\frac{3}{4}- \\frac{1}{3}" + } + ], + "text": "下面四个算式计算结果最大的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先把A化为 \\frac{5}{8}× \\frac{5}{12};B化为 \\frac{5}{8}× \\frac{13}{12};C化为 \\frac{5}{8}× \\frac{12}{5};D化为 \\frac{5}{8}× \\frac{12}{7};E化为 \\frac{5}{8}× \\frac{12}{13};然后根据一个因数相同，另一个因数大的，积就大，解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/507.json b/MathMC/507.json new file mode 100644 index 0000000000000000000000000000000000000000..710a4dc9cb985cebb82e17815e4acbc19eabc313 --- /dev/null +++ b/MathMC/507.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "前一个大" + }, + { + "bullet": "B", + "text": "相同" + }, + { + "bullet": "C", + "text": "前一个小" + } + ], + "text": "23×0与5×0的得数( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据0乘以任何数都得0，进行判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/508.json b/MathMC/508.json new file mode 100644 index 0000000000000000000000000000000000000000..9530964d915f13108857b11f196495d7ff7eecbe --- /dev/null +++ b/MathMC/508.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1个" + }, + { + "bullet": "B", + "text": "2个" + }, + { + "bullet": "C", + "text": "3个" + }, + { + "bullet": "D", + "text": "4个" + } + ], + "text": "下面关于倒数的说法正确的有( ). 1. 因为\\frac{1}{2}× \\frac{4}{3}× \\frac{3}{2}=1，所以它们互为倒数. 2. 1的倒数是1，0没有倒数. 3. 因为\\frac{4}{3}× 0.75=1，所以0.75是倒数. 4. 真分数的倒数都大于1. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "1乘积为1的两个数互为倒数，而\\frac{1}{2}× \\frac{4}{3}× \\frac{3}{2}=1为三个数相乘，故错. 21的倒数为1，对.0没有倒数，对. 3\\frac{4}{3}× 0.75=1，而\\frac{4}{3}与0.75互为倒数，而题说‘0.75是倒数‘，故错. 4真分数的范围为大于0，小于1，故真分数的倒数都大于1，正确. 综上，有2与4正确. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/509.json b/MathMC/509.json new file mode 100644 index 0000000000000000000000000000000000000000..a46c919c069389564b55d793afb34f4de440ab94 --- /dev/null +++ b/MathMC/509.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "南偏东60°" + }, + { + "bullet": "B", + "text": "北偏西30°" + }, + { + "bullet": "C", + "text": "北偏西60°" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "如果从A点看，B在A的南偏东30°方向，那么从B点看A，则A在B的( )方向. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据位置的相对性可知，它们的方向相反，角度相同，距离相等，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/51.json b/MathMC/51.json new file mode 100644 index 0000000000000000000000000000000000000000..e870bf2339eab6179f97f401408a1754f21a3886 --- /dev/null +++ b/MathMC/51.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6930" + }, + { + "bullet": "B", + "text": "6929万" + }, + { + "bullet": "C", + "text": "6930万" + } + ], + "text": "把69296500省略‘万‘后面的尾数约是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把69296500省略万后面的尾数，因为它的千位上是6，所以用‘五入‘法." + ] + } +} \ No newline at end of file diff --git a/MathMC/510.json b/MathMC/510.json new file mode 100644 index 0000000000000000000000000000000000000000..4a63b530e7326128b7ea394f033587e0e20a452f --- /dev/null +++ b/MathMC/510.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减去3" + }, + { + "bullet": "B", + "text": "减去2" + }, + { + "bullet": "C", + "text": "减去1" + }, + { + "bullet": "D", + "text": "减去23" + } + ], + "text": "从323中至少减去( )才能是3的倍数. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "能被3整除的数的特征:各个数位上的数字相加的和能被3整除，解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/511.json b/MathMC/511.json new file mode 100644 index 0000000000000000000000000000000000000000..fba1d9fdf992815a43e7a67ac11592e41781c6cf --- /dev/null +++ b/MathMC/511.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大小相等，分数单位也相同" + }, + { + "bullet": "B", + "text": "大小相等，分数单位不相同" + }, + { + "bullet": "C", + "text": "大小不等，分数单位也不同" + } + ], + "text": "\\frac{2}{3}与 \\frac{4}{6}比较( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据分数的基本性质把 \\frac{2}{3}的分子、分母都乘2就是 \\frac{4}{6}，这两个分数相等，或把 \\frac{4}{6}化简后是 \\frac{2}{3}，这两个分数相同; \\frac{2}{3}表示把单位‘1‘平均分成3份取其中的2份，它的分数单位是 \\frac{1}{3}， \\frac{4}{6}表示把单位‘1‘平均分成6份，每份是它的 \\frac{1}{6}， \\frac{4}{6}表示取其中的4份，它的分数单位是 \\frac{1}{6}，因此，这两个分数的意义、分数单位都不同." + ] + } +} \ No newline at end of file diff --git a/MathMC/512.json b/MathMC/512.json new file mode 100644 index 0000000000000000000000000000000000000000..ff73b64064bf53328004841fb60638fd73f26d4d --- /dev/null +++ b/MathMC/512.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "54999" + }, + { + "bullet": "B", + "text": "50000" + }, + { + "bullet": "C", + "text": "45000" + } + ], + "text": "一个数省略万位后面的尾数后约是5万.这个数最大是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "一个数省略万位后面的尾数是5万，最大是千位上的数舍去得到的，舍去的数中4是最大的，其它数位百位、十位、个位是最大的一位数9即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/513.json b/MathMC/513.json new file mode 100644 index 0000000000000000000000000000000000000000..01e8c874436103afb86587c99b3e4077e8f64179 --- /dev/null +++ b/MathMC/513.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "7" + } + ], + "text": "从0数到6是 ( )个数。" + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据题意，从0到6有0、1、2、3、4、5、6共7个数。据此解答即可。 从0到6有0、1、2、3、4、5、6共7个数。 故选: D。" + ] + } +} \ No newline at end of file diff --git a/MathMC/514.json b/MathMC/514.json new file mode 100644 index 0000000000000000000000000000000000000000..29716ca8cbc6c2b707eed2d4982c8905cce57e37 --- /dev/null +++ b/MathMC/514.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "甲数、乙数都大于0，甲数除以2/5等于乙数乘以2/5，那么甲数( )乙数. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "假设甲数除以2/5等于乙数乘以2/5, 都等于1，可算出甲乙两数的值，进行比较解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/515.json b/MathMC/515.json new file mode 100644 index 0000000000000000000000000000000000000000..b9fcdfac1b11a83233dcfabd2f53c951720a8231 --- /dev/null +++ b/MathMC/515.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5，8，3" + }, + { + "bullet": "B", + "text": "9，7，5" + }, + { + "bullet": "C", + "text": "1，3，5" + } + ], + "text": "下面每组中的三条线段，能围成三角形的是第 组.(单位:厘米) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据三角形任意两条边的和大于第三边来选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/516.json b/MathMC/516.json new file mode 100644 index 0000000000000000000000000000000000000000..7a4490015d479f19b5b3d56aaf14ae1dd6654944 --- /dev/null +++ b/MathMC/516.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30" + }, + { + "bullet": "B", + "text": "25" + }, + { + "bullet": "C", + "text": "29" + } + ], + "text": "汽水买5送1瓶，30名学生要每人1瓶，共需买( )瓶汽水. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先读题想一想，再解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/517.json b/MathMC/517.json new file mode 100644 index 0000000000000000000000000000000000000000..67fa665d742cb1e311a06765af857e4c5cb252c1 --- /dev/null +++ b/MathMC/517.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "803024900" + }, + { + "bullet": "B", + "text": "830024900" + }, + { + "bullet": "C", + "text": "832004900" + } + ], + "text": "读下面各数时，读出两个零的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "整数的读法:从高位到低位，一级一级地读，每一级末尾的0都不读出来，其它数位连续几个0都只读一个零;由此可知:要想不读出零，就要把零放在每级的末尾;要想读出零，就要把零放在每级的开头和中间，据此来选择解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/518.json b/MathMC/518.json new file mode 100644 index 0000000000000000000000000000000000000000..ae93f90cd77f442a2c2ffb94685ca2809d2321d1 --- /dev/null +++ b/MathMC/518.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "32×51" + }, + { + "bullet": "B", + "text": "47×26" + }, + { + "bullet": "C", + "text": "42×41" + } + ], + "text": "在下面的算式中，得数小于1500的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "此题可以通过计算来解答.通过对各选项的乘积进行计算，与1500比较，解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/519.json b/MathMC/519.json new file mode 100644 index 0000000000000000000000000000000000000000..75ce0b3e604c16b1dc7d6a523fa3be6edfa3c21c --- /dev/null +++ b/MathMC/519.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6吨" + }, + { + "bullet": "B", + "text": "60吨" + }, + { + "bullet": "C", + "text": "600吨" + } + ], + "text": "1枚1元的硬币大约重6克，照这样推算，1000枚1元的硬币大约重6千克，100万枚1元的硬币大约重6吨，1亿枚1元的硬币大约重( )吨. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因照这样计算，说明每100万枚的硬币约重6吨，1亿枚硬币有多重，就是求出1亿里面有多少个100万，再乘上6，就是它的重量.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/52.json b/MathMC/52.json new file mode 100644 index 0000000000000000000000000000000000000000..7a2ba224c0b9cd951c56bb026d11201f93d461ab --- /dev/null +++ b/MathMC/52.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "12" + } + ], + "text": "一个长方体的棱长总和是24厘米，相交于一个顶点的三条棱的长度和是( )厘米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "长方体相交于一个顶点的三条棱是长，宽，高.所以题目要求长+宽+高的和.因为长方体棱长总和是24，所以有:24÷ 4=6( 厘米 )." + ] + } +} \ No newline at end of file diff --git a/MathMC/520.json b/MathMC/520.json new file mode 100644 index 0000000000000000000000000000000000000000..84f99c4c27ff514eab65ecde44434280e4b94701 --- /dev/null +++ b/MathMC/520.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "瓷砖的长" + }, + { + "bullet": "B", + "text": "瓷砖的面积" + }, + { + "bullet": "C", + "text": "瓷砖周长" + }, + { + "bullet": "D", + "text": "瓷砖的厚度" + } + ], + "text": "铺一块地板，所需要瓷砖的块数与下列成反比例的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例." + ] + } +} \ No newline at end of file diff --git a/MathMC/521.json b/MathMC/521.json new file mode 100644 index 0000000000000000000000000000000000000000..9b121a6d409f0d9f264f346e76b53b2ce3a6784f --- /dev/null +++ b/MathMC/521.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "23" + }, + { + "bullet": "B", + "text": "22" + }, + { + "bullet": "C", + "text": "21" + } + ], + "text": "做一套衣服要用布2.2米，现在有49.6米布，最多可做( )套衣服. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "49.6 ÷ 2.2 = 22.5，因此能完整得做22套衣服. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/522.json b/MathMC/522.json new file mode 100644 index 0000000000000000000000000000000000000000..f5ba9b310d2ed04cf25d810a0ad6db396b36828a --- /dev/null +++ b/MathMC/522.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0" + }, + { + "bullet": "B", + "text": "大于0.5" + }, + { + "bullet": "C", + "text": "小于0.5" + }, + { + "bullet": "D", + "text": "等于0.5" + } + ], + "text": "乒乓球从高空落下，到达地面后弹起的高度约为落下高度的0.4倍，若乒乓球从25米高处落下，那么弹起后再落下，弹5次时它的弹起高度是( )米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "25×0.4×0.4×0.4×0.4×0.4=0.256(米) 0.256米<0.5米. 故选:C. 到达地面后弹起的高度约为落下高度的0.4倍，则第一次落下后弹起高度是25×0.4米，第二次弹起高度是25×0.4米，同理求出弹5次时它的弹起高度是多少米后，即能做出正确选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/523.json b/MathMC/523.json new file mode 100644 index 0000000000000000000000000000000000000000..96898561959646f07344ed61fa61a2b18e36ba83 --- /dev/null +++ b/MathMC/523.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "正西方向" + }, + { + "bullet": "B", + "text": "正南方向" + }, + { + "bullet": "C", + "text": "东北方向" + } + ], + "text": "如果学校在贝贝家的西南方向，那么贝贝家在学校的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "依据方向的相对性可知:东北与西南相对，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/524.json b/MathMC/524.json new file mode 100644 index 0000000000000000000000000000000000000000..393f88df5cad8df88b422e4251f8a93ecc1f786b --- /dev/null +++ b/MathMC/524.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15+5+8" + }, + { + "bullet": "B", + "text": "15-5+8" + }, + { + "bullet": "C", + "text": "15+5-8" + } + ], + "text": "有鸡15只，比鸭多5只.鹅比鸭多8只，求鹅的只数，正确的列式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由‘有鸡15只，比鸭多5只‘，可求得鸭的只数，即15-5=10(只);再由‘鹅比鸭多8只‘，求得鹅的只数为10+8=18(只).解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/525.json b/MathMC/525.json new file mode 100644 index 0000000000000000000000000000000000000000..ee23df4935c06a4b35dbc5f8295b94317df70211 --- /dev/null +++ b/MathMC/525.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20千克" + }, + { + "bullet": "B", + "text": "20克" + }, + { + "bullet": "C", + "text": "320千克" + } + ], + "text": "爸爸的体重是小花的4倍，爸爸的体重是80千克，小花的体重是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "我们用爸爸的体重除以4就是小花的体重，然后进行选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/526.json b/MathMC/526.json new file mode 100644 index 0000000000000000000000000000000000000000..7a8b49539ae9ec65c41bd05051ad2980c84c773e --- /dev/null +++ b/MathMC/526.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "钟表的指针运动" + }, + { + "bullet": "B", + "text": "电梯的升降运动" + }, + { + "bullet": "C", + "text": "风车的转动" + } + ], + "text": "下列现象中，属于平移的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据平移的性质，对选项进行一一分析，排除错误答案即可得到正确答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/527.json b/MathMC/527.json new file mode 100644 index 0000000000000000000000000000000000000000..48f5f55021f0e954933505811b992eb17c27704c --- /dev/null +++ b/MathMC/527.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "加法结合律" + }, + { + "bullet": "B", + "text": "乘法交换律" + }, + { + "bullet": "C", + "text": "乘法分配律" + } + ], + "text": "87×\\frac{3}{86}=86×\\frac{3}{86}+\\frac{3}{86}，这是运用了( )运算律. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "87×\\frac{3}{86}， =(86+1)×\\frac{3}{86}， =86×\\frac{3}{86}+\\frac{3}{86}; 运用了乘法分配律; 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/528.json b/MathMC/528.json new file mode 100644 index 0000000000000000000000000000000000000000..559a0f0484ad2d1a447f44e285b93df636e685e0 --- /dev/null +++ b/MathMC/528.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30瓶" + }, + { + "bullet": "B", + "text": "25瓶" + }, + { + "bullet": "C", + "text": "29瓶" + } + ], + "text": "汽水买5瓶送1瓶，30名学生要每人一瓶，共需买( )瓶汽水. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题意可知，因汽水买5瓶送一瓶，所以花5瓶的钱就买了(5+1)瓶，据此解答就可以得出正确答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/529.json b/MathMC/529.json new file mode 100644 index 0000000000000000000000000000000000000000..b910a31cb8b8a6bfb3bd5175399490e435b72658 --- /dev/null +++ b/MathMC/529.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "十亿位和百亿位" + }, + { + "bullet": "B", + "text": "千万位和十亿位" + }, + { + "bullet": "C", + "text": "百万位和千万位" + } + ], + "text": "与亿位相邻的两个数位分别是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "依据数位顺序表来判断与亿位相邻的两个数位分别是谁." + ] + } +} \ No newline at end of file diff --git a/MathMC/53.json b/MathMC/53.json new file mode 100644 index 0000000000000000000000000000000000000000..63bcdd073dfcaa7ea50441509ad222996051e66d --- /dev/null +++ b/MathMC/53.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0" + }, + { + "bullet": "B", + "text": "1" + }, + { + "bullet": "C", + "text": "3 7" + } + ], + "text": "\\frac{3}{7} 与它的倒数相乘的积是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据两个数的乘积是1，它们就互为倒数即可作出选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/530.json b/MathMC/530.json new file mode 100644 index 0000000000000000000000000000000000000000..ef16a2cd889ee00658f308c812fb15d29da5738c --- /dev/null +++ b/MathMC/530.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "没有公因数" + }, + { + "bullet": "B", + "text": "一定都是质数" + }, + { + "bullet": "C", + "text": "公因数只有1" + } + ], + "text": "互质的两个数( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "互质数的意义;公因数只有1的两个数叫做互质数，互质数要求的是公因数只有1，不一定都是质数，可以举例证明，据此分析选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/531.json b/MathMC/531.json new file mode 100644 index 0000000000000000000000000000000000000000..bba9080f87ec037857fe5c3f3582b8c81ae7b3d6 --- /dev/null +++ b/MathMC/531.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长5分米宽4分米" + }, + { + "bullet": "B", + "text": "长5分米宽3分米" + }, + { + "bullet": "C", + "text": "长4分米宽3分米" + }, + { + "bullet": "D", + "text": "长3分米宽3分米" + } + ], + "text": "小明做一个无盖的玻璃鱼缸，已经准备了4块长方形玻璃，其中的2块长5分米，宽3分米，另二块长4分米，宽3分米，还需配一块( )的玻璃才刚合适. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据长方体的特征，长方体的6个面都是长方形(特殊情况下有两个相对的面是正方形)，相对的面的面积相等;由此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/532.json b/MathMC/532.json new file mode 100644 index 0000000000000000000000000000000000000000..67b8332fe40f6bc8441c3817a5f6ef0b6ff976ab --- /dev/null +++ b/MathMC/532.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "150×25%" + }, + { + "bullet": "B", + "text": "150÷25%" + }, + { + "bullet": "C", + "text": "150×(1-25%)" + }, + { + "bullet": "D", + "text": "150÷(1-25%)" + } + ], + "text": "一条绳子用去25%，还剩150米，这条绳子原有多少米?正确列式是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "把这根绳子的总量看成单位‘1‘，用去25%，还剩下了1-25%=75%，它对应的数量是150米;由此用除法求出绳子的总长." + ] + } +} \ No newline at end of file diff --git a/MathMC/533.json b/MathMC/533.json new file mode 100644 index 0000000000000000000000000000000000000000..1dd0e0a19ecb672e8dc171662acc363ee8c0c154 --- /dev/null +++ b/MathMC/533.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1996年" + }, + { + "bullet": "B", + "text": "2000年" + }, + { + "bullet": "C", + "text": "2008年" + }, + { + "bullet": "D", + "text": "2100年" + } + ], + "text": "下列年份中，是平年的是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "本题考查了平年闰年的概念及其判断方法，公元年数可被4整除为闰年，但是整百(个位和十位均为0)的年数必须是可以被400整除的才是闰年." + ] + } +} \ No newline at end of file diff --git a/MathMC/534.json b/MathMC/534.json new file mode 100644 index 0000000000000000000000000000000000000000..c1089475170a4fb42ce6dd739e5247c323bea360 --- /dev/null +++ b/MathMC/534.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "要使29□680≈29万，□里有( )种填法. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "要使29□680≈29万，□里填写的这个数字，必须小于5即可填0、1、2、3、4这5个数字." + ] + } +} \ No newline at end of file diff --git a/MathMC/535.json b/MathMC/535.json new file mode 100644 index 0000000000000000000000000000000000000000..9616c8ad06cfecedfad9759e9b16438279ff45d2 --- /dev/null +++ b/MathMC/535.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12小时" + }, + { + "bullet": "B", + "text": "12分钟" + }, + { + "bullet": "C", + "text": "60分钟" + }, + { + "bullet": "D", + "text": "5分钟" + } + ], + "text": "分针走一圈的时间是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "时钟分为12个大格，每个大格中又分为5个小格，分针每走5分就走一个大格，所以分针走一圈走了12个大格，就是5×12=60(分).据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/536.json b/MathMC/536.json new file mode 100644 index 0000000000000000000000000000000000000000..302e8ed42629c96b614bdd2d3f38537a435f432d --- /dev/null +++ b/MathMC/536.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "先向东北走，再向西北走" + }, + { + "bullet": "B", + "text": "先向东南走，再向西南走" + }, + { + "bullet": "C", + "text": "先向西南走，再向东南走" + } + ], + "text": "贝贝从家去商场时先向西北走，再向东北走到商场。原路返回时应该 ( )才能按原路回家。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "贝贝原路返回即可，西北和东南相对，东北和西南相对，所以先向西南走，再向东南走，所以应选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/537.json b/MathMC/537.json new file mode 100644 index 0000000000000000000000000000000000000000..7ac092c4a2bb0cee478cde13cf7a2f6a6a95f826 --- /dev/null +++ b/MathMC/537.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "50+0" + }, + { + "bullet": "B", + "text": "50-0" + }, + { + "bullet": "C", + "text": "50×0" + } + ], + "text": "结果最小的算式是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先算出三个选项的算式的得数，再比较大小即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/538.json b/MathMC/538.json new file mode 100644 index 0000000000000000000000000000000000000000..3b53e31b217eb772c40a06679a767ffdb0265737 --- /dev/null +++ b/MathMC/538.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "公倍数" + }, + { + "bullet": "B", + "text": "最小公倍数" + }, + { + "bullet": "C", + "text": "公约数" + }, + { + "bullet": "D", + "text": "最大公约数" + } + ], + "text": "两个数(不为0的自然数)的积一定是这两个数的( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据因数和倍数的意义，以及研究因数和倍数时，为了方便，在研究因数和倍数的时候，我们所说的数指的是整数(一般不包括0).由此解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/539.json b/MathMC/539.json new file mode 100644 index 0000000000000000000000000000000000000000..633a290b4f348a25402bd07dff3b1b303723babd --- /dev/null +++ b/MathMC/539.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "4" + } + ], + "text": "在1964年、1978年、1995年、1996年、2001年、2100年中，闰年有( )个. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据平年、闰年的判断方法:普通年份是4的倍数即是闰年，整百年份是400的倍数即是闰年." + ] + } +} \ No newline at end of file diff --git a/MathMC/54.json b/MathMC/54.json new file mode 100644 index 0000000000000000000000000000000000000000..7dd379d214b208d230dc7225ce6b2ed74a4f78b5 --- /dev/null +++ b/MathMC/54.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "600" + }, + { + "bullet": "B", + "text": "800" + }, + { + "bullet": "C", + "text": "200" + } + ], + "text": "一种药水的药液和水的质量比是1:20，现在有药液40克，应加水( )克. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一种药水的药液和水的质量比是1:20，也就是药液是水质量的 \\frac{1}{20}，因此现在有药液40克，应加水40÷ \\frac{1}{20}=800(克)，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/540.json b/MathMC/540.json new file mode 100644 index 0000000000000000000000000000000000000000..ef14aa1667bf5e28fcd84a7502afd2d0a897132c --- /dev/null +++ b/MathMC/540.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "60" + } + ], + "text": "烟火晚会上每6秒出现一次星星图案的礼花，每10秒出现一次花朵图案的礼花.在同时看到这两种礼花后，还要( )秒才可以同时看到这两种礼花. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "要求再次同时看到这种礼花至少要经过几秒，这里只要求得6和10的最小公倍数即可解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/541.json b/MathMC/541.json new file mode 100644 index 0000000000000000000000000000000000000000..0a9ab2fe1e49290f29aa05268538b558f6238537 --- /dev/null +++ b/MathMC/541.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "8" + } + ], + "text": "两根小棒分别长7厘米和14厘米，再有一根( )厘米的小棒就可以围成一个三角形. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据三角形的特性:两边之和大于第三边，三角形的两边的差一定小于第三边;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/542.json b/MathMC/542.json new file mode 100644 index 0000000000000000000000000000000000000000..8bd7e2a3e3debf82a4636019a612142048f6c70d --- /dev/null +++ b/MathMC/542.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少了" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加了" + } + ], + "text": "一个边长为4分米的正方形，如果在四个角各剪去一个连长为4厘米的正方形，那么它的周长与原来相比是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据正方形的特征，4条边的长度都相等，如果四个角各剪去一个边长1厘米的小正方形，面积比原来减少了，周长不变.因为把剪去部分所显示的边长经过平移，又恢复到原来的形状，所以周长不变.因此由此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/543.json b/MathMC/543.json new file mode 100644 index 0000000000000000000000000000000000000000..38931303a0bdf97b3272409de4c2abc1586e8866 --- /dev/null +++ b/MathMC/543.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4平方厘米" + }, + { + "bullet": "B", + "text": "12平方厘米" + }, + { + "bullet": "C", + "text": "16平方厘米" + }, + { + "bullet": "D", + "text": "32平方厘米" + } + ], + "text": "一个长8厘米，宽6厘米的长方形，如果长和宽都增加2厘米，它的面积增加( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据长方形的面积=长×宽，分别求出原长方形的面积和增加后长方形的面积，再相减即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/544.json b/MathMC/544.json new file mode 100644 index 0000000000000000000000000000000000000000..9ec45793f2515b95db8ad297b8392143befeefe8 --- /dev/null +++ b/MathMC/544.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "108°" + }, + { + "bullet": "B", + "text": "252°" + }, + { + "bullet": "C", + "text": "54°" + } + ], + "text": "个农场水稻种植面积占总种植面积的30%，制作扇形统计图时，表示水稻种植面积的扇形的圆心角度数是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "总面积用一个圆来表示，它的总度数是360°，把360°看成单位‘1‘，一种农作物种植面积占总面积的30%，它的圆心角就是360°的30%，由此用乘法求出." + ] + } +} \ No newline at end of file diff --git a/MathMC/545.json b/MathMC/545.json new file mode 100644 index 0000000000000000000000000000000000000000..f2d54b4ba83b0c64e126bb92c48566ca3a466b2d --- /dev/null +++ b/MathMC/545.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a-1" + }, + { + "bullet": "B", + "text": "a+2" + }, + { + "bullet": "C", + "text": "2a" + } + ], + "text": "如果a是一个自然数，那么偶数可以表示为( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "能被2整除的数为偶数，所以如果用a 表示自然数，那么偶数可表示为2a，a-1和a+2不含因数2，所以可能是奇数也可能是偶数. 根据偶数的定义可知，如果用a 表示自然数，那么偶数可表示为2a. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/546.json b/MathMC/546.json new file mode 100644 index 0000000000000000000000000000000000000000..8c98205623cd65343e360fe51dc895cb91bd548c --- /dev/null +++ b/MathMC/546.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "三位数" + }, + { + "bullet": "B", + "text": "四位数" + }, + { + "bullet": "C", + "text": "四位数或五位数" + } + ], + "text": "三位数乘两位数，所得的积是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "最小的三位数100乘最小的两位数10得到最小的积;再用最大的三位数999，乘最大的三位是99，求出最大的积，根据积的范围求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/547.json b/MathMC/547.json new file mode 100644 index 0000000000000000000000000000000000000000..85a946b0dab38498bf4c800e3a1bcea32a2f9955 --- /dev/null +++ b/MathMC/547.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "\\frac{2}{3}= \\frac{2+4}{3+()}. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "观察算式可以发现:分子加上4，由2变成了6，相当于分子扩大了3倍，要使分数的值不变，分母也应该扩大3倍，从而问题得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/548.json b/MathMC/548.json new file mode 100644 index 0000000000000000000000000000000000000000..50dd0557695693c738b124f8cd0589576680a025 --- /dev/null +++ b/MathMC/548.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12.5" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "13" + } + ], + "text": "做一套西服用布2.4米，30米布最多可以做( )套. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，知道每套西服用布2.4米，就是求30米里面有多少个2.4米，再根据实际情况进行取舍. 30÷ 2.4≈ 12(套). 答:30米布最多可以做12套. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/549.json b/MathMC/549.json new file mode 100644 index 0000000000000000000000000000000000000000..ffea307d0129207f8544d7f8e99b3fff353e7ff1 --- /dev/null +++ b/MathMC/549.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "乙快" + }, + { + "bullet": "B", + "text": "甲快" + }, + { + "bullet": "C", + "text": "一样" + } + ], + "text": "在百米赛跑中，甲用了1/6分钟，乙用了0.33分钟，两人比较( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "先将1/6化成0.167，再据小数大小的比较方法，与0.33比较大小，用时少的，跑的就快." + ] + } +} \ No newline at end of file diff --git a/MathMC/55.json b/MathMC/55.json new file mode 100644 index 0000000000000000000000000000000000000000..fc0e4e29d1294e23d0df8daf0c60de556f2c5d39 --- /dev/null +++ b/MathMC/55.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "1000" + }, + { + "bullet": "C", + "text": "10000" + }, + { + "bullet": "D", + "text": "100万" + } + ], + "text": "从一百起，一百一百地数，数到‘一百万‘要数( )次. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "一百万除以100等于一万，也就是说要数一万次. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/550.json b/MathMC/550.json new file mode 100644 index 0000000000000000000000000000000000000000..6037f4edc321c51476c6a95510b235a5e2eb8a08 --- /dev/null +++ b/MathMC/550.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲" + }, + { + "bullet": "B", + "text": "乙" + }, + { + "bullet": "C", + "text": "丙" + }, + { + "bullet": "D", + "text": "丁" + } + ], + "text": "时代中学要从甲乙丙丁4个人中，选出一名三优学生，来参加这次夏令营活动.甲说:我们四个人中每人至少得一个优.并且只有一个三优学生.乙说:我和甲的数学成绩一样，我和丙的语文成绩一样.丙说:我和丁之中只有一个人的语文成绩是优.丁说:我们四个人中，有三个人语文成绩是优，两个人数学成绩是优，一个人英语成绩是优.如果他们四个人说的都是对的，那么这个三优学生是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为语文有三优，而乙丙语文成绩一样，二者如果语文不优，则满足不了语文三优的条件，所以乙丙语文都得优秀，而丁与丙不同，所以丁语文不优，语文得优的三个人是甲、乙、丙，三科全优只能从这三人中产生， (1)若甲全优，则乙语文和数学优英语不优，丙语文优英语数学不优，丁得不到优秀，与每人至少一科优秀矛盾 (2)若乙全优，同上分析. (3)若丙全优，则甲乙数学不优，只有语文优，丙数学优，刚好满足每人至少一科优，语文三人优，数学两人优，英语一人优. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/551.json b/MathMC/551.json new file mode 100644 index 0000000000000000000000000000000000000000..b3d61ae93e2d5ac5325385efbc04cc2350843a16 --- /dev/null +++ b/MathMC/551.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "不能确定" + } + ], + "text": "一个三角形和一个平行四边形的底相等，面积也相等，已知平行四边形的高是6厘米，那么三角形的高是( )厘米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "平行四边形的面积=底×高，三角形的面积=底×高÷2，由‘一个三角形和一个平行四边形的底相等，面积也相等‘可知，平行四边形的高是三角形的高的 \\frac{1}{2}，从而问题得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/552.json b/MathMC/552.json new file mode 100644 index 0000000000000000000000000000000000000000..72f6634c1b0444da9bb59be689505dcd450e5b52 --- /dev/null +++ b/MathMC/552.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形统计图" + }, + { + "bullet": "B", + "text": "折线统计图" + }, + { + "bullet": "C", + "text": "扇形统计图" + }, + { + "bullet": "D", + "text": "复式条形统计图" + } + ], + "text": "要表示一个病人一天的体温变化情况，用( )表示比较合适. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/553.json b/MathMC/553.json new file mode 100644 index 0000000000000000000000000000000000000000..2013102738e401b6dc6e676e7806190e934a505b --- /dev/null +++ b/MathMC/553.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "平行四边形面积的2倍" + }, + { + "bullet": "B", + "text": "平行四边形面积的 \\frac{1}{2}" + }, + { + "bullet": "C", + "text": "与平行四边形面积相等" + } + ], + "text": "三角形与平行四边形等底等高，三角形的面积是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "三角形的面积=底×高÷2，平行四边形的面积=底×高，若三角形与平行四边形等底等高，则三角形的面积是平行四边形的面积的一半，据此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/554.json b/MathMC/554.json new file mode 100644 index 0000000000000000000000000000000000000000..607ffa059ac02f11c8b22ec4ab4c6db36ba64d9e --- /dev/null +++ b/MathMC/554.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0469" + }, + { + "bullet": "B", + "text": "4690" + }, + { + "bullet": "C", + "text": "4069." + } + ], + "text": "用4、0、6、9组成的最小四位数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零，据此写出此数，根据写出的数进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/555.json b/MathMC/555.json new file mode 100644 index 0000000000000000000000000000000000000000..97b83fc2b90abaadc78bcb63689fe7bb0c47ec89 --- /dev/null +++ b/MathMC/555.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/3" + }, + { + "bullet": "B", + "text": "1倍" + }, + { + "bullet": "C", + "text": "2倍" + }, + { + "bullet": "D", + "text": "1/4" + } + ], + "text": "1个大正方体切成2个相等的小长方体，这些小长方体的表面积之和比原来正方体的表面积增加了(). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "此题中让比较小长方体的表面积之和比原来正方体的表面积增加了多少，长方体有两个面的面积和原正方体的面积相等，另外4个面每个面的面积是正方体面积的一半，设原正方体的每个面的面积为1，所以原正方体的表面积为6，其中一个长方体的表面积为(2*1+4*1/2)=4，两个小长方体的表面积之和为8，那么小长方体的表面积之和比原来正方体的表面积增加了(8-6)/6=1/3." + ] + } +} \ No newline at end of file diff --git a/MathMC/556.json b/MathMC/556.json new file mode 100644 index 0000000000000000000000000000000000000000..4153d27190054cc0a744e951f89d1970b4e6e483 --- /dev/null +++ b/MathMC/556.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "26.3" + }, + { + "bullet": "B", + "text": "28.3" + }, + { + "bullet": "B", + "text": "32" + } + ], + "text": "某晚报发布信息:为了节约珍贵的水资源，某市居民每月每户用水缴费由原来的每立方米1.90元，作如下调整:用水量10立方米及以下每立方米1.9元，10立方米以上的部分每立方米2.325元，王大伯家今年5月份的水费，按旧的收费标准缴费26.6元，王大伯家按新的收费标准应缴费多少元?" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先根据数量=总价÷单价，求出王大伯家5月份的用水量，再求出超过10立方米的用水量，最后根据总价=数量×单价，分别求出10立方米以内，以及超出10立方米用水量的总价，再把它们相加即可解答.五月使用水：26.6/1.9=14立方米，按照新标准计算缴费为1.9*10+4*2.325=28.3元" + ] + } +} \ No newline at end of file diff --git a/MathMC/557.json b/MathMC/557.json new file mode 100644 index 0000000000000000000000000000000000000000..a74e35f4b49c6ddd6240fa388fbd76aeef3082e0 --- /dev/null +++ b/MathMC/557.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲数>乙数" + }, + { + "bullet": "B", + "text": "甲数<乙数" + }, + { + "bullet": "C", + "text": "甲数=乙数" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "如果甲数的60%等于乙数的 \\frac{2}{3}( 甲、乙两数都大于0)，那么( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "如果甲数的 \\frac{b}{a} 与乙数的 \\frac{d}{c} 相等，则甲数与乙数的比是 \\frac{d}{c}: \\frac{b}{a} . 如果甲数的60%等于乙数的 \\frac{2}{3} ，则甲数与乙数的比是 \\frac{2}{3}:60 % =10:9 ，即甲数大于乙数. 甲数:乙数= \\frac{2}{3}:60 % =10:9 即甲数大于乙数. 所以A选项是正确的." + ] + } +} \ No newline at end of file diff --git a/MathMC/558.json b/MathMC/558.json new file mode 100644 index 0000000000000000000000000000000000000000..af49a3a66bc5f20adb4b8f4a7925776d1a5a4773 --- /dev/null +++ b/MathMC/558.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "求8的 \\frac{2}{5}是多少" + }, + { + "bullet": "B", + "text": "求8个 \\frac{2}{5}连加的和是多少" + }, + { + "bullet": "C", + "text": "求8个 \\frac{2}{5}连乘的积是多少" + }, + { + "bullet": "D", + "text": "以上答案均不对" + } + ], + "text": "\\frac{2}{5}×8的意义是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "分数乘整数的意义与整数乘法的意义相同，就是求几个相同加数和的简便运算;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/559.json b/MathMC/559.json new file mode 100644 index 0000000000000000000000000000000000000000..df25706ce06b4a5aa9c4ab63e774152544b74eab --- /dev/null +++ b/MathMC/559.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30×25%" + }, + { + "bullet": "B", + "text": "30÷25%" + }, + { + "bullet": "C", + "text": "30×(1-25%)" + }, + { + "bullet": "D", + "text": "30÷(1-25%)" + } + ], + "text": "小红有30本书，比小英少25%，小英有多少本?正确的列式是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "把小英的本数看作单位‘1‘，单位‘1‘不知道用除法进行解答，即，30÷(1-25%)." + ] + } +} \ No newline at end of file diff --git a/MathMC/56.json b/MathMC/56.json new file mode 100644 index 0000000000000000000000000000000000000000..69c2b7433b3d4e47d8f37a4d17b60bc776a274a5 --- /dev/null +++ b/MathMC/56.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "分子大于分母" + }, + { + "bullet": "B", + "text": "分子小于分母" + }, + { + "bullet": "C", + "text": "分子等于分母" + } + ], + "text": "如果一个分数的分子、分母都增加到100，而分数的大小没有改变，那么原来的分数一定是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据分数的基本性质，一个分数的分子、分母都增加到100，而分数的大小没有改变，可知，此分数的分子和分母同时扩大了相同的倍数，扩大相同的倍数后都是100，由此可得出:原来的分数的分子和分母相同。 故选:C 此题主要考查分数的基本性质。" + ] + } +} \ No newline at end of file diff --git a/MathMC/560.json b/MathMC/560.json new file mode 100644 index 0000000000000000000000000000000000000000..27b0175ca8c3766f85df3fcfced92da3dfc487ee --- /dev/null +++ b/MathMC/560.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "300500" + }, + { + "bullet": "B", + "text": "420782" + }, + { + "bullet": "C", + "text": "60004200" + } + ], + "text": "下面各数中，不需要读出零的数是 。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "利用大数的读法以及0的含义进行解题。" + ] + } +} \ No newline at end of file diff --git a/MathMC/561.json b/MathMC/561.json new file mode 100644 index 0000000000000000000000000000000000000000..6b2928bd1e4577e2aed1cb0494bd111ddfdca838 --- /dev/null +++ b/MathMC/561.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一根长" + }, + { + "bullet": "B", + "text": "第二根长" + }, + { + "bullet": "C", + "text": "两根同样长" + } + ], + "text": "两根3米长的绳子，第一根用去\\frac{3}{4}米，第二根用去\\frac{3}{4}，两根绳子用去的部分相比( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用绳子的长度减去第一根用去的长度，求出剩下的长度，再用绳长的长度乘第二根用去的占的几分之几，然后再减去用去的，可求出第二根剩下的长度，再进行比较即可. 第一根剩下的长度:3-\\frac{3}{4}=\\frac{9}{4}(米)， 第二根剩下的长度:3-3× \\frac{3}{4}=3-\\frac{9}{4}=\\frac{3}{4}(米)， \\frac{9}{4}>\\frac{3}{4}，所以第一根剩下的长一些.所以第二根用的多. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/562.json b/MathMC/562.json new file mode 100644 index 0000000000000000000000000000000000000000..647ec4d342b25b40202f735305f7b223030d8cdb --- /dev/null +++ b/MathMC/562.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "480÷(400÷5)" + }, + { + "bullet": "B", + "text": "400÷(480÷5)" + }, + { + "bullet": "C", + "text": "480÷5×400" + } + ], + "text": "一辆小汽车5小时行驶400千米，照这样计算，要行驶480千米需要多少小时?下面列式正确的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "在这道题中应用距离÷时间=速度，以及路程÷速度=时间，在这道题中要先利用公式求出速度，再利用公式求出时间." + ] + } +} \ No newline at end of file diff --git a/MathMC/563.json b/MathMC/563.json new file mode 100644 index 0000000000000000000000000000000000000000..89b0071dac7e77dd30afb4fa984899923d49ffbc --- /dev/null +++ b/MathMC/563.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1.025÷0.5" + }, + { + "bullet": "B", + "text": "1025÷5" + }, + { + "bullet": "C", + "text": "1025÷0.5" + } + ], + "text": "下面算式中商最大的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据商不变规律进行变形，再根据在商非零的除法里，除数相同都是5，比较被除数，被除数越大商就越大，由此进行判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/564.json b/MathMC/564.json new file mode 100644 index 0000000000000000000000000000000000000000..fb5ef73b6531e766421246bacd9973d45edaf033 --- /dev/null +++ b/MathMC/564.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "(459-15)×4" + }, + { + "bullet": "B", + "text": "459-15×4" + }, + { + "bullet": "C", + "text": "459×4-15" + } + ], + "text": "从459里减去15的4倍，差是多少?正确的算式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先用15乘上4求出15的4倍，再用459减去求出的积即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/565.json b/MathMC/565.json new file mode 100644 index 0000000000000000000000000000000000000000..6d95e232935749cb1bc43ae2432425c3e3f529c8 --- /dev/null +++ b/MathMC/565.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90-72×23÷9" + }, + { + "bullet": "B", + "text": "(90-72)×23+9" + }, + { + "bullet": "C", + "text": "(90-72)×(23+9)" + } + ], + "text": "90与72的差，乘23与9的和，积是多少?列式正确的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先用90减去72求出差，再用23加上9求出和，最后用求出的差乘上求出和即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/566.json b/MathMC/566.json new file mode 100644 index 0000000000000000000000000000000000000000..7a49a1158ae0a26118a4d1fa78198dc7bba5a752 --- /dev/null +++ b/MathMC/566.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0+9=9" + }, + { + "bullet": "B", + "text": "9×0=0" + }, + { + "bullet": "C", + "text": "8÷0=0" + } + ], + "text": "下列算式中，错误的是 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "A选项中，根据‘一个数加上0，还得原数‘可知，0+9=9，计算正确; B选项中，根据‘一个数和0相乘，仍得0‘可知，9×0=0，计算正确; C选项中，根据‘除数不能为0 ‘可知，8÷0=0是错误的。 所以应选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/567.json b/MathMC/567.json new file mode 100644 index 0000000000000000000000000000000000000000..fd560cc697adbb8962cc48fac7a95740c1f35aa2 --- /dev/null +++ b/MathMC/567.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac13" + }, + { + "bullet": "B", + "text": "\\frac14" + }, + { + "bullet": "C", + "text": "\\frac1{10}" + } + ], + "text": "一条4千米的公路10天修完，每天修了这条路的( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把一条公路看成单位1，分成了10天修完，每天修十分之一. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/568.json b/MathMC/568.json new file mode 100644 index 0000000000000000000000000000000000000000..66e179178b26b0cae9170f4cac5f9ee822d1c9c5 --- /dev/null +++ b/MathMC/568.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "179" + }, + { + "bullet": "B", + "text": "675" + }, + { + "bullet": "C", + "text": "765" + } + ], + "text": "一个数减去586，计算时马小虎将被减数的百位和十位上的数字互换了，结果得89，正确的差应该是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "现在的错误被减数:586+89=675， 所以原来正确的被减数应交换百位与十位，为:765， 765-586=179. 故答案选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/569.json b/MathMC/569.json new file mode 100644 index 0000000000000000000000000000000000000000..5d078f645a947a53b0cb885c141dbb6201d18b14 --- /dev/null +++ b/MathMC/569.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲" + }, + { + "bullet": "B", + "text": "乙" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "不确定" + } + ], + "text": "甲、乙二人举行百米赛跑，甲用了0.4分钟，乙用了\\frac{3}{10}分钟，( )跑得快一些. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "首先比较出两人跑百米用的时间的长短;然后根据:速度×时间=路程，可得:路程一定时，谁用的时间越短，则谁跑得越快，判断出甲、乙谁跑得快一些即可. \\frac{3}{10}分钟=0.3分钟， 因为0.4>0.3， 所以同样的路程，乙用的时间短， 所以乙跑得快一些. 答:乙跑得快一些. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/57.json b/MathMC/57.json new file mode 100644 index 0000000000000000000000000000000000000000..c72500f81ea5416e3a3ea4d98d4ce13f70649f45 --- /dev/null +++ b/MathMC/57.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "48" + } + ], + "text": "用棱长1厘米的小正方体摆成稍大一些的正方体，至少需要( )个小正方体. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "小正方体摆成稍大一些的正方体，那么这个正方体的棱长应是2厘米，可以算出体积是2×2×2=8(立方厘米)小正方体体积是1立方厘米，那么8÷1=8(个)" + ] + } +} \ No newline at end of file diff --git a/MathMC/570.json b/MathMC/570.json new file mode 100644 index 0000000000000000000000000000000000000000..6fae24434982fbf3a9eb4c2984e7e69342c3c16c --- /dev/null +++ b/MathMC/570.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "578-19" + }, + { + "bullet": "B", + "text": "19×27" + }, + { + "bullet": "C", + "text": "27+32" + } + ], + "text": "计算578-19×27+32时，应先算 ( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在计算578-19×27+32时，应先算乘法，再算减法与加法." + ] + } +} \ No newline at end of file diff --git a/MathMC/571.json b/MathMC/571.json new file mode 100644 index 0000000000000000000000000000000000000000..ad8ce195a8568bca408182d442742be8d65124a5 --- /dev/null +++ b/MathMC/571.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{60}" + }, + { + "bullet": "B", + "text": "\\frac{1}{6000}" + }, + { + "bullet": "C", + "text": "\\frac{1}{60000}" + }, + { + "bullet": "D", + "text": "\\frac{1}{6000000}" + } + ], + "text": "把线段比例尺改写成数值比例尺是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "依据线段比例尺的意义，即图上距离1厘米表示实际距离60千米，再据‘比例尺= \\frac{图上距离}{实际距离}，‘即可将线段比例尺转化成数值比例尺." + ] + } +} \ No newline at end of file diff --git a/MathMC/572.json b/MathMC/572.json new file mode 100644 index 0000000000000000000000000000000000000000..810833e15ef6da084100039c5a08cbe346521d5d --- /dev/null +++ b/MathMC/572.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9厘米" + }, + { + "bullet": "B", + "text": "12厘米" + }, + { + "bullet": "C", + "text": "18厘米" + }, + { + "bullet": "D", + "text": "64厘米" + } + ], + "text": "一个长方体的棱长之和是36厘米，相交于一个顶点的三条棱长之和是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "长方体的棱长总和=(长+宽+高)×4， 所以用棱长总和除以4即可， 36÷4=9(厘米). 故答案是:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/573.json b/MathMC/573.json new file mode 100644 index 0000000000000000000000000000000000000000..0cbda8a10c554d1d47267325dfa0cc0d3326e017 --- /dev/null +++ b/MathMC/573.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20" + }, + { + "bullet": "B", + "text": "25" + }, + { + "bullet": "C", + "text": "80" + } + ], + "text": "甲数与乙数的比是5:4，乙数比甲数少( )%. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据‘甲数与乙数的比是5:4‘，可以把甲数看作5份数，把乙数看作4份数，先求出乙数比甲数少的份数，进而除以甲数的份数得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/574.json b/MathMC/574.json new file mode 100644 index 0000000000000000000000000000000000000000..259f2e30a4b2c13caa47303707406f92edff64db --- /dev/null +++ b/MathMC/574.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "270÷93" + }, + { + "bullet": "B", + "text": "2709÷3" + }, + { + "bullet": "C", + "text": "270÷(9×3)" + }, + { + "bullet": "D", + "text": "2703÷9" + } + ], + "text": "与270÷9÷3结果相同的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题是一道关于整数的乘除法简便运算的题目，关键是根据式子的特点选择合适的运算方法;观察发现，是270连除以两个数，根据一个数连续除以两个数等于除以这两个数的积，你能得到什么? 根据上述简便运算方法可知，可将除以9除以3写成除以9× 3的积，据此即可得到答案. 270÷ 9÷ 3=270÷ (9× 3). 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/575.json b/MathMC/575.json new file mode 100644 index 0000000000000000000000000000000000000000..4987b1e3927f1078b53dd2a119633919aaf2c53b --- /dev/null +++ b/MathMC/575.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "151×6" + }, + { + "bullet": "B", + "text": "202×4" + }, + { + "bullet": "C", + "text": "398×2" + } + ], + "text": "下列算式中，结果最接近800的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据整数乘法的计算法则算出得数，然后比较与800的差，差越小，越接近800." + ] + } +} \ No newline at end of file diff --git a/MathMC/576.json b/MathMC/576.json new file mode 100644 index 0000000000000000000000000000000000000000..104e79fb763f955c3242a5bed74a6cbc3575fa3d --- /dev/null +++ b/MathMC/576.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "万位" + }, + { + "bullet": "B", + "text": "千位" + }, + { + "bullet": "C", + "text": "百位" + } + ], + "text": "一个四位数，它的最高位是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，由数位顺序表可知:从右边往左数，第四位是千位，所以一个四位数，最高位是千位，由此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/577.json b/MathMC/577.json new file mode 100644 index 0000000000000000000000000000000000000000..c36ae17ce6cc591a4043e7bc0513c0c1aebc58b2 --- /dev/null +++ b/MathMC/577.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "西偏南30°" + }, + { + "bullet": "B", + "text": "东偏西30°" + }, + { + "bullet": "C", + "text": "西偏南60°" + } + ], + "text": "南偏西30°，还可以说成( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据地图上‘上北下南，左西右东‘这个规则，正西方向与正南方向的夹角是 90 °，南偏西 30 °，与西偏南 60 °是描述的相同的方向." + ] + } +} \ No newline at end of file diff --git a/MathMC/578.json b/MathMC/578.json new file mode 100644 index 0000000000000000000000000000000000000000..22d98e106efa83cf91980f9858806430551a9029 --- /dev/null +++ b/MathMC/578.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2、7、9" + }, + { + "bullet": "B", + "text": "6、7、8" + }, + { + "bullet": "C", + "text": "3、4、5" + } + ], + "text": "下面三组线段中，不能围成三角形的是( ).(单位:厘米) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "判断三角形能否构成，关键是看三条线段是否满足:任意两边之和是否大于第三边.但通常不需一一验证，其简便方法是将较短两边之和与较长边比较." + ] + } +} \ No newline at end of file diff --git a/MathMC/579.json b/MathMC/579.json new file mode 100644 index 0000000000000000000000000000000000000000..2aa74c5d9c1647acaec79a32f1403127d0c6eb44 --- /dev/null +++ b/MathMC/579.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{10}" + }, + { + "bullet": "B", + "text": "\\frac{10}{3}" + }, + { + "bullet": "C", + "text": "\\frac{1}{10}" + }, + { + "bullet": "D", + "text": "\\frac{1}{3}" + } + ], + "text": "10米长的绳子，平均分成3份，每份占全长的( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "把绳子的总长度看成单位‘1‘，平均分成3份，每份就是全长的 \\frac{1}{3}，据此即可进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/58.json b/MathMC/58.json new file mode 100644 index 0000000000000000000000000000000000000000..58d0665130b9cb147286bbe62f8efbedae0e1bad --- /dev/null +++ b/MathMC/58.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "79亿" + }, + { + "bullet": "B", + "text": "796亿" + }, + { + "bullet": "C", + "text": "80亿​" + } + ], + "text": "7956800000省略亿后面的尾数，约是( )。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把一个数省略亿位后面的尾数求近似数，只要把千万位上的数根据四舍五入法去掉万位后面的数，然后写上‘亿‘字。 ​" + ] + } +} \ No newline at end of file diff --git a/MathMC/580.json b/MathMC/580.json new file mode 100644 index 0000000000000000000000000000000000000000..d9c0010e60d831037118f81457a8e8b585c910e6 --- /dev/null +++ b/MathMC/580.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6.5÷0.125" + }, + { + "bullet": "B", + "text": "6.5÷12.5" + }, + { + "bullet": "C", + "text": "6.5÷1.25" + } + ], + "text": "下列算式中商最大的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "解答这道题需要先观察算式，发现被除数都是一样的，所以除数越小，商就越大，因此比较这些小数的大小即可解答这道题." + ] + } +} \ No newline at end of file diff --git a/MathMC/581.json b/MathMC/581.json new file mode 100644 index 0000000000000000000000000000000000000000..8af6a98a764b502b47d9be0b235cefd74e4b88d6 --- /dev/null +++ b/MathMC/581.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "有27筐苹果，明明每次最多能运8筐，至少要运( )次才能运完这些苹果. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "27÷ 8=3··· ··· 3，27筐苹果每次最多运8筐，那么运3次时已经运了3× 8=24筐苹果，还剩3筐苹果，所以至少需要运3+1=4次才能运完这些苹果. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/582.json b/MathMC/582.json new file mode 100644 index 0000000000000000000000000000000000000000..ec583353f44fc26b1734e37ec7ba56b2599091ed --- /dev/null +++ b/MathMC/582.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30瓶" + }, + { + "bullet": "B", + "text": "25瓶" + }, + { + "bullet": "C", + "text": "29瓶" + } + ], + "text": "汽水买5送1，30名学生要每人1瓶，共需买( )瓶汽水. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "设需要买x瓶汽水，则根据‘汽水买5送1‘，知道送x÷5瓶汽水，则根据‘30名学生要每人1瓶‘，即买的汽水瓶数+送的汽水瓶数=30，列出方程解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/583.json b/MathMC/583.json new file mode 100644 index 0000000000000000000000000000000000000000..d27c8bfaa6e522850ae426ae544ec918bb09d6d3 --- /dev/null +++ b/MathMC/583.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "是质数" + }, + { + "bullet": "B", + "text": "一定是37" + }, + { + "bullet": "C", + "text": "是所有整数" + }, + { + "bullet": "D", + "text": "是1或37" + } + ], + "text": "已知a能整除37，那么a( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;可知:a能整除37，即37能被a整除，那么37就是a的倍数，a就是37的因数，因为37=1×37，进而得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/584.json b/MathMC/584.json new file mode 100644 index 0000000000000000000000000000000000000000..34bd230eb559a9f42105233040124de7bd27fb9a --- /dev/null +++ b/MathMC/584.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1.2÷20%" + }, + { + "bullet": "B", + "text": "1.2×(1+20%)" + }, + { + "bullet": "C", + "text": "1.2÷(1-20%)" + } + ], + "text": "一件商品降价20%后，原价比现价贵1.2元，这件商品的原价是多少元?正确列式是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把原价看作单位‘1‘，由题意，‘降价20%‘是指现价比原价少了20%.由‘原价比现价贵1.2元‘，也就是现价比原价少1.2元，少了20%，那么这件商品的原价是1.2÷20%." + ] + } +} \ No newline at end of file diff --git a/MathMC/585.json b/MathMC/585.json new file mode 100644 index 0000000000000000000000000000000000000000..0c366f141387a3f498353414dabda3cf9a7db982 --- /dev/null +++ b/MathMC/585.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "真分数小于1" + }, + { + "bullet": "B", + "text": "假分数大于1" + }, + { + "bullet": "C", + "text": "带分数大于1" + } + ], + "text": "下列说法错误的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据真假分数的概念，真分数:分子小于分母，值小于1;假分数:分子大于或等于分母，值大于或等于1;带分数，分子大于分母，值大于1，由此解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/586.json b/MathMC/586.json new file mode 100644 index 0000000000000000000000000000000000000000..8b90aff6c575e4bdf2e55c723ca457d8e360c6f7 --- /dev/null +++ b/MathMC/586.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东" + }, + { + "bullet": "B", + "text": "南" + }, + { + "bullet": "C", + "text": "西" + }, + { + "bullet": "D", + "text": "北" + } + ], + "text": "早晨，当你面向太阳时，你的左边是( )面. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "早晨太阳在东边，当面向太阳时，所面对的方向是东，身后是西，左边是北，右边是南. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/587.json b/MathMC/587.json new file mode 100644 index 0000000000000000000000000000000000000000..53a587dc04f2490cef438176e482650c8dd0f767 --- /dev/null +++ b/MathMC/587.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减去4" + }, + { + "bullet": "B", + "text": "加上4" + }, + { + "bullet": "C", + "text": "除以4" + } + ], + "text": "分数 8/12 的分母减6后，要使分数的大小不变，分子应( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据比较分数大小的方法来进行解题." + ] + } +} \ No newline at end of file diff --git a/MathMC/588.json b/MathMC/588.json new file mode 100644 index 0000000000000000000000000000000000000000..c7ac4e8056a3dcf51d6f30f0b73643bf380023b9 --- /dev/null +++ b/MathMC/588.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "3" + }, + { + "bullet": "C", + "text": "5" + }, + { + "bullet": "D", + "text": "7" + } + ], + "text": "既是质数又是奇数的最小数是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题首先要理解质数和奇数的意义，质数只能被自然数1和本身整除，奇数就是不能被2整除的数，根据这两个特征就可以找出题中既是质数又是奇数的最小数." + ] + } +} \ No newline at end of file diff --git a/MathMC/589.json b/MathMC/589.json new file mode 100644 index 0000000000000000000000000000000000000000..22847bad8dc6c2606dff41dc0a48bbb67e5716f8 --- /dev/null +++ b/MathMC/589.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "食堂共买来多少千克面粉?" + }, + { + "bullet": "B", + "text": "食堂还剩多少千克面粉?" + }, + { + "bullet": "C", + "text": "食堂共买来多少千克大米?" + }, + { + "bullet": "D", + "text": "买来大米和面粉共多少千克?" + } + ], + "text": "根据‘食堂买来8袋面粉，每袋30千克.买来的大米比面粉少90千克.‘这些已知条件，不能求出的问题是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "1食堂买来8袋面粉，每袋30千克.买来的大米比面粉少90千克，用每袋面粉的重量乘面粉的袋数，可以求出食堂共买来多少千克面粉? 2食堂买来8袋面粉，每袋30千克.买来的大米比面粉少90千克，先求出买了面粉多少千克，再用面粉的数量减去90千克，可以求出食堂共买来多少千克大米? 3食堂买来8袋面粉，每袋30千克.买来的大米比面粉少90千克，先求出买了面粉的数量，再求出买了大米的数量，然后用面粉的数量加数大米的数量，可以求出买来大米和面粉共多少千克? 4食堂买来8袋面粉，每袋30千克.买来的大米比面粉少90千克，不能求出食堂还剩多少千克面粉? 据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/59.json b/MathMC/59.json new file mode 100644 index 0000000000000000000000000000000000000000..428453ea3ec62212dcd8f0fb319ec1dc280cbf2f --- /dev/null +++ b/MathMC/59.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "18" + }, + { + "bullet": "B", + "text": "36" + }, + { + "bullet": "C", + "text": "44" + } + ], + "text": "下面的数，因数个数最多的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "18的因数有1、2、3、6、9、18共6个， 36的因数有1、2、3、4、6、9、12、18、36共9个， 44的因数有1、2、4、11、22、44共6个， 9>{}6，所以36的因数最多， 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/590.json b/MathMC/590.json new file mode 100644 index 0000000000000000000000000000000000000000..cd9a7d28bd8123a859b93b803d2cf172197ff608 --- /dev/null +++ b/MathMC/590.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小华" + }, + { + "bullet": "B", + "text": "小明" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "在50米短跑比赛中，小华用了\\frac{1}{3}分钟，小明用了\\frac{1}{4}分钟， ( )跑得快。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "\\frac{1}{3}>\\frac{1}{4}，小明时间短，跑得快。 故选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/591.json b/MathMC/591.json new file mode 100644 index 0000000000000000000000000000000000000000..62fa53d6dd7840418e0492a40b31a56126933eba --- /dev/null +++ b/MathMC/591.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "49" + }, + { + "bullet": "B", + "text": "32" + }, + { + "bullet": "C", + "text": "28" + } + ], + "text": "把一张长8厘米、宽7厘米的长方形纸，剪成一个最大的正方形，正方形周长是( )厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为长方形内最大的正方形的边长等于长方形的宽，所以这个正方形的边长是7厘米，再利用正方形的周长公式计算即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/592.json b/MathMC/592.json new file mode 100644 index 0000000000000000000000000000000000000000..fee33a1cc6883c01f654bf1a94dbc9a029ea85b2 --- /dev/null +++ b/MathMC/592.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{A}- \\frac{1}{B}= \\frac{1}{A}× \\frac{1}{B}" + }, + { + "bullet": "B", + "text": "\\frac{1}{AB}= \\frac{1}{A}- \\frac{1}{B}" + }, + { + "bullet": "C", + "text": "\\frac{1}{A}+ \\frac{1}{B}= \\frac{1}{A}× \\frac{1}{B}" + } + ], + "text": "A、B是不为0的自然数，且B-A=1，下面式子错误的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先由已知条件‘A、B是不为0的自然数，且B-A=1‘，推出A和B是两个连续的自然数，且B>A;因为分数中的分母为两个连续的自然数，这样的分数可以写成分数相减的形式，用此即可判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/593.json b/MathMC/593.json new file mode 100644 index 0000000000000000000000000000000000000000..0727af4459f2985427945b511ac0525163b9fcb7 --- /dev/null +++ b/MathMC/593.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "96" + }, + { + "bullet": "B", + "text": "98" + }, + { + "bullet": "C", + "text": "97" + }, + { + "bullet": "D", + "text": "95" + } + ], + "text": "小强期中考试语文、数学的平均分是98分，英语是95分，他三科的平均成绩是( )分. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "平均数:用所有数据相加的总和除以数据的个数，需要计算才得求出.把98加上98加上95的和除以3." + ] + } +} \ No newline at end of file diff --git a/MathMC/594.json b/MathMC/594.json new file mode 100644 index 0000000000000000000000000000000000000000..6ebdc3ca5218f1344d52a5bf4376cd3592a18ce7 --- /dev/null +++ b/MathMC/594.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "359" + }, + { + "bullet": "B", + "text": "386" + }, + { + "bullet": "C", + "text": "656" + } + ], + "text": "356再加3个十是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "加3个十，在十位上增加3，所以选B 386 考察对不同数位表示意义不同的认识。" + ] + } +} \ No newline at end of file diff --git a/MathMC/595.json b/MathMC/595.json new file mode 100644 index 0000000000000000000000000000000000000000..9d9561ecbc1aa92bb4a74b9f148df5ba4c47f9a5 --- /dev/null +++ b/MathMC/595.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "864-( 200+3 )" + }, + { + "bullet": "B", + "text": "864-200-3" + }, + { + "bullet": "C", + "text": "864-200+3" + } + ], + "text": "864-197的简便算法是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "864-197，直接计算比较麻烦，可以简单计算， 将197看成200-3，那么原式变成了: 864-197=864-(200-3)=864-200+3. 根据选项特点，选择C." + ] + } +} \ No newline at end of file diff --git a/MathMC/596.json b/MathMC/596.json new file mode 100644 index 0000000000000000000000000000000000000000..5de0d599b48db78cb214a01575e879a4e67f9f44 --- /dev/null +++ b/MathMC/596.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + } + ], + "text": "甲乙两数都不为0，如果甲数÷0.86=乙，那么甲数一定( )乙数. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "我们运用乙数表示出甲数，然后再和乙数进行比较即可，然后再进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/597.json b/MathMC/597.json new file mode 100644 index 0000000000000000000000000000000000000000..ce09a0140a7877cb9d4f02f33cf511cae995fc3d --- /dev/null +++ b/MathMC/597.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "现价=原价× 60%" + }, + { + "bullet": "B", + "text": "降低的价格=原价× ( 1-60% )" + }, + { + "bullet": "C", + "text": "原价=现价× ( 1-60% )" + }, + { + "bullet": "D", + "text": "现价÷ 原价=60%" + } + ], + "text": "一件商品打六折出售，下面( )关系式错误的. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "一件商品打六折出售， 即现价=原价× 60%或降低的价格=原价× ( 1-60% )或现价÷ 原价=60%， 原价=现价× ( 1-60% )是错误的， 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/598.json b/MathMC/598.json new file mode 100644 index 0000000000000000000000000000000000000000..eade1ff55334d7d1ddccadcb27986289ad947187 --- /dev/null +++ b/MathMC/598.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "增加4厘米" + }, + { + "bullet": "B", + "text": "减少4厘米" + }, + { + "bullet": "C", + "text": "和原来一样" + } + ], + "text": "从边长1分米的正方形的四个角各剪去边长1厘米的正方形，所得图形的周长( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + " 如图所示，将边长是1分米的正方形的四个角剪去边长是1厘米的正方形，每个角看似减少了2条1厘米的线段，但同样也增加了2条1厘米的线段，所以所得图形的周长不变." + ] + } +} \ No newline at end of file diff --git a/MathMC/599.json b/MathMC/599.json new file mode 100644 index 0000000000000000000000000000000000000000..cf9546572e6e7d43eeceb223bd79e20d18ff8630 --- /dev/null +++ b/MathMC/599.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2×2×3×3=36" + }, + { + "bullet": "B", + "text": "36=2×2×3×3×1" + }, + { + "bullet": "C", + "text": "36=2×2×3×3" + } + ], + "text": "把36分解质因数是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分解质因数就是把一个合数写成几个质数的连乘积形式，一般先从简单的质数试着分解，即可求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/6.json b/MathMC/6.json new file mode 100644 index 0000000000000000000000000000000000000000..8ff6b1ce7fd8a97e61c54e155d223bdc1b5b5cde --- /dev/null +++ b/MathMC/6.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{2}" + }, + { + "bullet": "B", + "text": "2倍" + }, + { + "bullet": "C", + "text": "\\frac{1}{3}" + }, + { + "bullet": "D", + "text": "3倍" + } + ], + "text": "等底等高的三角形的面积是平行四边形面积的( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "据‘平行四边形的面积=底×高和三角形的面积=底×高÷2‘进行推导，得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/60.json b/MathMC/60.json new file mode 100644 index 0000000000000000000000000000000000000000..b7fdf966855b9b79ec28202f89cad2354b3ebff5 --- /dev/null +++ b/MathMC/60.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": ".复式折线" + }, + { + "bullet": "B", + "text": "复式条形" + }, + { + "bullet": "C", + "text": "扇形" + } + ], + "text": "要清楚地看出甲乙两个城市的平均气温的高地变化情况，应绘制( )统计图. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/600.json b/MathMC/600.json new file mode 100644 index 0000000000000000000000000000000000000000..39ae198bc9adfc84703bc6f4db57d56ae7c6dbbf --- /dev/null +++ b/MathMC/600.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于乙数" + }, + { + "bullet": "B", + "text": "小于乙数" + }, + { + "bullet": "C", + "text": "等于乙数" + } + ], + "text": "甲、乙两数都是自然数，如果甲数÷0.92=乙数，那么甲数一定( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在小数除法中，被除数不为0，除数大于1(不含1)，被除数大于商;除数小于1(不含1)，被除数小于商;除数等于1，被除数和商相等，依此即可作出判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/601.json b/MathMC/601.json new file mode 100644 index 0000000000000000000000000000000000000000..4655116ddc09324eba8467acc9fcd86807f524af --- /dev/null +++ b/MathMC/601.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1小时30分" + }, + { + "bullet": "B", + "text": "2小时30分" + }, + { + "bullet": "C", + "text": "3小时30分" + } + ], + "text": "星期六，小明乘车去奶奶家，他8:30上车，10:00到奶奶家，小明去奶奶家用了( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由题目知，10:00比8:30多10:00-8:30=1:30，所以小明去奶奶家用了1小时30分，所以答案为A." + ] + } +} \ No newline at end of file diff --git a/MathMC/602.json b/MathMC/602.json new file mode 100644 index 0000000000000000000000000000000000000000..9752b13d8c77767bd13929dac1ea1b04be9c5c68 --- /dev/null +++ b/MathMC/602.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8" + }, + { + "bullet": "B", + "text": "9" + }, + { + "bullet": "C", + "text": "10" + } + ], + "text": "小明从学校到少年宫，以每分钟50米行走，12分可以到达.按原路返回时每分钟走60米，他( )分可回到学校. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "学校到少年宫距离等于每分钟行走的距离和用时的乘积，即50×12=600米，如果每分钟走60米，则需要600÷ 60=10分钟，即按原路返回时每分钟走60米，他10分钟可以回到家." + ] + } +} \ No newline at end of file diff --git a/MathMC/603.json b/MathMC/603.json new file mode 100644 index 0000000000000000000000000000000000000000..6eb4e7a15b5119fc11373c24ed7380bdee671bf5 --- /dev/null +++ b/MathMC/603.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "是一个正方形面积的2倍" + }, + { + "bullet": "B", + "text": "是一个正方形面积的4倍" + }, + { + "bullet": "C", + "text": "无法知道" + } + ], + "text": "两个面积相等的正方形拼成一个长方形，长方形的面积( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据面积的意义，一个图形的面积是它所占平面的大小.既然长方形是两个正方形拼成的，所以长方形所占平面的大小，和两个正方形所占平面的大小相等，即长方形的面积是一个正方形面积的2倍.据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/604.json b/MathMC/604.json new file mode 100644 index 0000000000000000000000000000000000000000..74114102607e0310cb7b962546302a1a60f85797 --- /dev/null +++ b/MathMC/604.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲" + }, + { + "bullet": "B", + "text": "乙" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "不确定" + } + ], + "text": "甲、乙两人举行百米赛跑，甲用了0.4分钟，乙用了 2/5 分钟，( )跑的快一些. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先对甲和乙用的时间进行比较，可以化为分数比较，也可以化为小数比较;根据‘路程一定，速度和时间成反比‘，进而得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/605.json b/MathMC/605.json new file mode 100644 index 0000000000000000000000000000000000000000..611b3a95856fd9230317a0b2b1f060307013333b --- /dev/null +++ b/MathMC/605.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "200" + }, + { + "bullet": "C", + "text": "80" + } + ], + "text": "把两个棱长都是10厘米的正方体拼成一个长方体后，表面积减少( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "两个正方体拼成一个长方体后，表面积比原来是减少了两个正方体的面的面积，由此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/606.json b/MathMC/606.json new file mode 100644 index 0000000000000000000000000000000000000000..3a8eb13d3e3bb2414643d324c9dfd98f281aecf8 --- /dev/null +++ b/MathMC/606.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20" + }, + { + "bullet": "B", + "text": "16" + }, + { + "bullet": "C", + "text": "19" + } + ], + "text": "汽水买4瓶送1瓶，20名学生要每人1瓶，共需买( )瓶汽水. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "设需要买x瓶汽水，则根据‘汽水买4送1‘，知道送x÷4瓶汽水，则根据‘20名学生要每人1瓶‘，即买的汽水瓶数+送的汽水瓶数=20，列出方程解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/607.json b/MathMC/607.json new file mode 100644 index 0000000000000000000000000000000000000000..39ccc5c0e201d467d6fa20cafeeede8310209c91 --- /dev/null +++ b/MathMC/607.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1和5" + }, + { + "bullet": "B", + "text": "100和500" + }, + { + "bullet": "C", + "text": "1和500" + }, + { + "bullet": "D", + "text": "100和5" + } + ], + "text": "12除以7的商是1，余数是5.如果被除数和除数都同时乘100，那么商和余数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据在有余数的除法里，‘被除数和除数都缩小(或都扩大)相同的倍数(0除外)，商不变，但余数也随着缩小(或扩大)相同的倍数‘，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/608.json b/MathMC/608.json new file mode 100644 index 0000000000000000000000000000000000000000..eb6507023cfe16f14cd9440b454fbaba95fa7966 --- /dev/null +++ b/MathMC/608.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "428万" + }, + { + "bullet": "B", + "text": "428" + }, + { + "bullet": "C", + "text": "429万" + }, + { + "bullet": "D", + "text": "429" + } + ], + "text": "4285700省略万位后面的尾数约是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "省略万位以后的数，故看千位， 4285700≈ 4290000=429万. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/609.json b/MathMC/609.json new file mode 100644 index 0000000000000000000000000000000000000000..7e8d987d497b9386e0475847e39497c397a01a47 --- /dev/null +++ b/MathMC/609.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "相等" + }, + { + "bullet": "B", + "text": "不相等" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "算式134-75+25和算式134-(75+25)的结果 ( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "减去两个数的和等于连续减去这两个数，所以134-(75+25)=134-75-25，与134-75+25不相等。 故选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/61.json b/MathMC/61.json new file mode 100644 index 0000000000000000000000000000000000000000..1797c68b6b92f9af0d7c488c2fc83fcfdd53596d --- /dev/null +++ b/MathMC/61.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "两个锐角" + }, + { + "bullet": "B", + "text": "一个钝角和一个锐角" + }, + { + "bullet": "C", + "text": "两个钝角" + } + ], + "text": "一个直角可以分成( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据钝角、直角、锐角的含义可知:锐角是大于0°小于90°的角;钝角是大于90°小于180°的角;直角是等于90°的角，所以一个直角可以分成两个锐角." + ] + } +} \ No newline at end of file diff --git a/MathMC/610.json b/MathMC/610.json new file mode 100644 index 0000000000000000000000000000000000000000..e01880ef79d9a20a02422340e4f0b3cc4c7c4bcc --- /dev/null +++ b/MathMC/610.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "圆周率等于3.14" + }, + { + "bullet": "B", + "text": "圆周率是圆的周长除以半径的商" + }, + { + "bullet": "C", + "text": "圆周率是一个无限不循环小数" + } + ], + "text": "下列关于圆周率的说法正确的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "圆周率是一个近似值，所以题目中第一个选项说圆周率等于3.14这个说法是不正确的，圆周率是一个固定的数值，所以第二个选项的说法也是不正确的." + ] + } +} \ No newline at end of file diff --git a/MathMC/611.json b/MathMC/611.json new file mode 100644 index 0000000000000000000000000000000000000000..24bb206de80c6f596178ca5310997293cddc9aa3 --- /dev/null +++ b/MathMC/611.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "8" + } + ], + "text": "从25数到31，共数了 ( )个数。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据一个一个数的方法解答，25、26、27、28、29、30、31，一共数了7个数。 故答案选:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/612.json b/MathMC/612.json new file mode 100644 index 0000000000000000000000000000000000000000..8b333a9bd630ee739a8cfda4ffeecb9753e183f1 --- /dev/null +++ b/MathMC/612.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "米" + }, + { + "bullet": "B", + "text": "分米" + }, + { + "bullet": "C", + "text": "厘米" + }, + { + "bullet": "D", + "text": "毫米" + } + ], + "text": "一扇门的高度大约是20( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据生活经验、对长度单位大小的认识，可知一扇门的高度大约是20分米，也就是2米，据此进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/613.json b/MathMC/613.json new file mode 100644 index 0000000000000000000000000000000000000000..b704be87ce2f08f8efc8420ab75d410baacd1f6a --- /dev/null +++ b/MathMC/613.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{5}×\\frac{1}{5}" + }, + { + "bullet": "B", + "text": "\\frac{4}{5}×(1+\\frac{1}{5})" + }, + { + "bullet": "C", + "text": "\\frac{4}{5}+\\frac{1}{5}" + }, + { + "bullet": "D", + "text": "\\frac{4}{5}×(1-\\frac{1}{5})" + } + ], + "text": "修一条路，第一天修了\\frac{4}{5}千米，第二天比第一天多修\\frac{1}{5}千米.第二天修了多少千米?正确的列式是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "要求第二天修了多少千米，根据题意，也就是求比第一天修的\\frac{4}{5}千米多\\frac{1}{5}千米的数是多少，用加法计算. 试题解析:\\frac{4}{5}+\\frac{1}{5}=1(千米). 答:第二天修了1千米. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/614.json b/MathMC/614.json new file mode 100644 index 0000000000000000000000000000000000000000..ba66fd6708d803b2ff2416fb76ff0e39f3453e94 --- /dev/null +++ b/MathMC/614.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "899" + }, + { + "bullet": "B", + "text": "987" + }, + { + "bullet": "C", + "text": "1010" + } + ], + "text": "下面各数中，最接近1000的数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据899、987、1010和1000的差的大小来确定谁和1000最接近." + ] + } +} \ No newline at end of file diff --git a/MathMC/615.json b/MathMC/615.json new file mode 100644 index 0000000000000000000000000000000000000000..99627d626846aa91267271df70769c8236675f35 --- /dev/null +++ b/MathMC/615.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2000米" + }, + { + "bullet": "B", + "text": "2000千米" + }, + { + "bullet": "C", + "text": "200千米" + } + ], + "text": "一列动车平均每小时行驶( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据生活经验，动车平均每小时行驶200千米左右，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/616.json b/MathMC/616.json new file mode 100644 index 0000000000000000000000000000000000000000..dc4e9d59747f24d1f41d28b185b0fcb521fc1b09 --- /dev/null +++ b/MathMC/616.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "40元" + }, + { + "bullet": "B", + "text": "4元" + }, + { + "bullet": "C", + "text": "4角" + } + ], + "text": "一块橡皮5角，8块橡皮要( )元 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一块橡皮的价格为5角，8块就是5×8=40角，1元=10角，所以40角=4元. 所以答案为4元. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/617.json b/MathMC/617.json new file mode 100644 index 0000000000000000000000000000000000000000..ad709f07ba6599e6f1f8c8e516485b25e2677717 --- /dev/null +++ b/MathMC/617.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一组数据的众数有可能没有，也可能不止一个" + }, + { + "bullet": "B", + "text": "一组数据的平均数一定大于众数" + }, + { + "bullet": "C", + "text": "一组数据的平均数、中位数、众数可能相同" + } + ], + "text": "下列说法错误的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "众数是一组数据中出现次数最多的数值，有时众数在一组数中有好几个，但是有时也可能没有众数. 平均数的求法:用所有数据相加的和除以数据的个数;中位数的求法:将数据按大小顺序排列，如果数据个数是奇数，则处于最中间位置的数就是这组数据的中位数;如果数据个数是偶数，则中间两个数据的平均数是这组数据的中位数;众数的求法:一组数据中出现次数最多的数据; 据求法可知一组数据的平均数和中位数有可能相等，还有可能平均数大于或小于中位数. 根据意义与求解方法，平均数、中位数与众数没法进行比较大小." + ] + } +} \ No newline at end of file diff --git a/MathMC/618.json b/MathMC/618.json new file mode 100644 index 0000000000000000000000000000000000000000..6ab6fdca62501a7a1fea601064404f963fbeb539 --- /dev/null +++ b/MathMC/618.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80厘米" + }, + { + "bullet": "B", + "text": "20厘米" + }, + { + "bullet": "C", + "text": "10厘米" + } + ], + "text": "一个正方形和一个长方形的周长相等，已知长方形的周长是80厘米，正方形的边长是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据正方形特征解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/619.json b/MathMC/619.json new file mode 100644 index 0000000000000000000000000000000000000000..0e6253dc6c755ff9d364e6226b54b2cd4523688e --- /dev/null +++ b/MathMC/619.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "72平方厘米" + }, + { + "bullet": "B", + "text": "128平方厘米" + }, + { + "bullet": "C", + "text": "20平方厘米" + }, + { + "bullet": "D", + "text": "112平方厘米" + } + ], + "text": "将四条长为16厘米，宽为2厘米的长方形垂直相交平放在桌面上，则桌面被盖住的面积是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "桌面被盖住的面积，就是图中这个组合图形的面积:四个长方形的面积之和减去重叠部分的4个边长为2厘米的小正方形的面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/62.json b/MathMC/62.json new file mode 100644 index 0000000000000000000000000000000000000000..0d0af1a5052ea85031954218b548af9d6b0c209d --- /dev/null +++ b/MathMC/62.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20平方厘米" + }, + { + "bullet": "B", + "text": "25厘米" + }, + { + "bullet": "C", + "text": "25平方厘米" + } + ], + "text": "一个正方形邮票的周长是20厘米，它的面积是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "邮票为正方形，正方形的周长为边长乘以4，所以邮票的边长为20÷ 4=5(厘米)，因为正方形的面积为边长乘以边长，所以面积为5× 5=25(c{{m}^{2}}). 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/620.json b/MathMC/620.json new file mode 100644 index 0000000000000000000000000000000000000000..645e1ea96c35ab4618403eb9fbadf67311874477 --- /dev/null +++ b/MathMC/620.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一个数" + }, + { + "bullet": "B", + "text": "整数" + }, + { + "bullet": "C", + "text": "相同的数" + } + ], + "text": "分数的分子、分母同时乘或除以( )(0除外)，分数的大小不变. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分数的分子和分母同时乘以或除以一个数(0除外)，这个数可以是整数，分数，小数，只要这个数相同就行，分数大小不变." + ] + } +} \ No newline at end of file diff --git a/MathMC/621.json b/MathMC/621.json new file mode 100644 index 0000000000000000000000000000000000000000..10ba0e12dfa78435503771719d32993f4ed7736c --- /dev/null +++ b/MathMC/621.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "安全" + }, + { + "bullet": "B", + "text": "不安全" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "一辆货车自重2800千克，车上装有3600千克的货物，现在要通过一座限重6吨的桥，安全吗? ( )" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "货车自重加上货物质量为:2800+3600=6400 (千克)， 因为6吨=6000千克，6400>6000， 因此货车通过一座限重6吨的桥不安全。 故答案为:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/622.json b/MathMC/622.json new file mode 100644 index 0000000000000000000000000000000000000000..37f865158c411fdfc8a1089b319fa9bba750c27a --- /dev/null +++ b/MathMC/622.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "91" + }, + { + "bullet": "B", + "text": "71" + }, + { + "bullet": "C", + "text": "61" + } + ], + "text": "下列既是奇数又是合数的是 . " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "91除了1和91两个因数外还有13和7，因此它既是奇数又是合数，而71和61是奇数，并且除了1和它本身两个因数外没有别的因数了，因此它们既是奇数又是质数." + ] + } +} \ No newline at end of file diff --git a/MathMC/623.json b/MathMC/623.json new file mode 100644 index 0000000000000000000000000000000000000000..03e6d240ce4f0c82b2694efffde87d011bb8a26a --- /dev/null +++ b/MathMC/623.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "40x=8" + }, + { + "bullet": "B", + "text": "8÷x=40" + }, + { + "bullet": "C", + "text": "8x=40" + } + ], + "text": "一个长方形的面积是40平方米，长是8米，宽是多少米?设宽是x米.列方程为( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据长方形的面积公式:s=ab，已知长方形的面积是40平方米，长是8米，求宽.根据长方形的面积公式列方程解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/624.json b/MathMC/624.json new file mode 100644 index 0000000000000000000000000000000000000000..1306217efd71ddbc2e945cb0f7624cd359fe3b2f --- /dev/null +++ b/MathMC/624.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "50" + }, + { + "bullet": "B", + "text": "40" + }, + { + "bullet": "C", + "text": "49" + }, + { + "bullet": "D", + "text": "无选项" + } + ], + "text": "( )×7<350，( )里最大能填( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由整数大小的比较方法可知:50×7=350，所以括号里的数应小于50，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/625.json b/MathMC/625.json new file mode 100644 index 0000000000000000000000000000000000000000..5e6246188bcff92f5192943737959a16ea6aa4e2 --- /dev/null +++ b/MathMC/625.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4:9" + }, + { + "bullet": "B", + "text": "2:3" + }, + { + "bullet": "C", + "text": "16:81" + } + ], + "text": "两个圆的周长比是4:9，这两个圆的面积比是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据学过的圆的知识，两个圆的半径比等于这两个圆的直径比也等于这两个圆的周长比，但这两个圆的面积比就等于半径平方的比，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/626.json b/MathMC/626.json new file mode 100644 index 0000000000000000000000000000000000000000..52bb8dd4b849aab730ee1256af8e85389e2d991c --- /dev/null +++ b/MathMC/626.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20平方厘米" + }, + { + "bullet": "B", + "text": "30平方厘米" + }, + { + "bullet": "C", + "text": "40平方厘米" + } + ], + "text": "根长方体木料，它的底面积是10平方厘米，把它截成三段，表面积增加( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题根据长方体的表面积计算公式进行解答即可，在本题中，当把一根截成两段成则增加2个底面积，如果截成三段时，则增加4个完本相同的底面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/627.json b/MathMC/627.json new file mode 100644 index 0000000000000000000000000000000000000000..f22331dbd80fa6103cee334a0e56ce0c39f05db9 --- /dev/null +++ b/MathMC/627.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扇形统计图" + }, + { + "bullet": "B", + "text": "条形统计图" + }, + { + "bullet": "C", + "text": "折线统计图" + } + ], + "text": "要表示数量增减变化的情况，用( )比较合适. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "折线统计图的特点是:不仅表示数量的多少，而且能够表示数量的增减变化情况，由此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/628.json b/MathMC/628.json new file mode 100644 index 0000000000000000000000000000000000000000..c027279b07aa906ea7028f141ff17a620eaccadd --- /dev/null +++ b/MathMC/628.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "五(1)班有多少人" + }, + { + "bullet": "B", + "text": "全年级有多少人" + }, + { + "bullet": "C", + "text": "全年级女生有多少人" + }, + { + "bullet": "D", + "text": "五(1)班男生有多少人" + } + ], + "text": "(1)班的女生25人，是全年级人数的 5/8，根据条件，可选择的问题是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，从条件中将全年级的人数看成单位‘1‘，因此根据全年级，可以提出求全年级的人数，即解答此题." + ] + } +} \ No newline at end of file diff --git a/MathMC/629.json b/MathMC/629.json new file mode 100644 index 0000000000000000000000000000000000000000..90aa4f110b28ae39b7c7d2ca52f8f4b071f1b1e4 --- /dev/null +++ b/MathMC/629.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100倍" + }, + { + "bullet": "B", + "text": "\\frac{1}{10}" + }, + { + "bullet": "C", + "text": "\\frac{1}{100}" + } + ], + "text": "在45的后面填上‘%‘得到一个数，这个数是原数的( )、 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意可以用百分数与除法的关系来判断;据此选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/63.json b/MathMC/63.json new file mode 100644 index 0000000000000000000000000000000000000000..9c48e14a5a679fd860232e84bb7d04c5da0f219b --- /dev/null +++ b/MathMC/63.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10a+b" + }, + { + "bullet": "B", + "text": "100a+b" + }, + { + "bullet": "C", + "text": "100b+a" + } + ], + "text": "一个三位数，百位的数字是a，十位的数字是0，个位的数字是b，这个三位数用含有字母的式子表示是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "百位上是a就是有a个百即100a，十位是0，个位是b就是有b个一也就是b，这个数就是100a+b." + ] + } +} \ No newline at end of file diff --git a/MathMC/630.json b/MathMC/630.json new file mode 100644 index 0000000000000000000000000000000000000000..524e766991317aa231dc15faa158d138c6ebc2e3 --- /dev/null +++ b/MathMC/630.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8002" + }, + { + "bullet": "B", + "text": "9897" + }, + { + "bullet": "C", + "text": "7997" + }, + { + "bullet": "D", + "text": "7123" + } + ], + "text": "( )最接近8000. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意A选项:8002与8000相隔8002-8000=2. B选项:9897与8000相隔9897-8000=1897. C选项:7997与8000相距8000-7997=3. D选项:7123与8000相距8000-7123=877. 因为1897>877>3>2，所以与8000最接近的是8002. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/631.json b/MathMC/631.json new file mode 100644 index 0000000000000000000000000000000000000000..51bdbb7b4e32dc96ff913a5be38e5478c1fba071 --- /dev/null +++ b/MathMC/631.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "20" + }, + { + "bullet": "C", + "text": "24" + }, + { + "bullet": "D", + "text": "48" + } + ], + "text": "小明用1平方分米的正方形纸板量课桌面的面积，沿着长要摆6个，沿着宽要摆4个，课桌面的面积是( )平方分米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "用长上摆的个数乘宽上摆的个数，求出一共摆的个数，再乘每个正方形纸板的面积，就是课桌的面积.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/632.json b/MathMC/632.json new file mode 100644 index 0000000000000000000000000000000000000000..3754c0f7c38179ff99385597ce0204710b0fbd22 --- /dev/null +++ b/MathMC/632.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "钝角" + }, + { + "bullet": "B", + "text": "直角" + }, + { + "bullet": "C", + "text": "锐角" + }, + { + "bullet": "D", + "text": "平角" + } + ], + "text": "一个钝角分成两个角，一定有一个( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为90°<钝角<180°，一个钝角分成两个角，最小角要大于0°，最大角小于180°，分情况考虑解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/633.json b/MathMC/633.json new file mode 100644 index 0000000000000000000000000000000000000000..5f682a55c84482ea184c624a9419a73468cd6626 --- /dev/null +++ b/MathMC/633.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "单式条形统计图" + }, + { + "bullet": "B", + "text": "复式条形统计图" + }, + { + "bullet": "C", + "text": "单式折线统计图" + }, + { + "bullet": "D", + "text": "复式折线统计图" + } + ], + "text": "如果比较两个城市一周气温变化的情况，选用( )比较合适. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "各个统计图的主要作用:从条形统计图中很容易看出各种数量的多少; 折线统计图主要作用是清楚地表示出数量增减变化的情况; 通过扇形统计图可以很清楚地表示各部分数量同总数之间的关系; 当然单式统计图是表示一个事物，复式统计图是表示多个事物的对比; 对于这道题，比较两个城市一周气温变化的情况，选用复式折线统计图比较合适. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/634.json b/MathMC/634.json new file mode 100644 index 0000000000000000000000000000000000000000..40f3b27e2895f9f3980c7cc5bfa5965a65e6176c --- /dev/null +++ b/MathMC/634.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20×25%" + }, + { + "bullet": "B", + "text": "20+25%" + }, + { + "bullet": "C", + "text": "20×(1-25%)" + }, + { + "bullet": "D", + "text": "20÷(1-25%)" + } + ], + "text": "小帆有20本书，比小英少25%，小英有多少本书?正确的列式是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "本题的设计意图是考查学生已知比一个数多(或少)百分之几的数是多少的知识点，首先找标准量，标准量已知用乘法，未知用除法，多百分之几用一加百分之几，少百分之几用一减百分之几." + ] + } +} \ No newline at end of file diff --git a/MathMC/635.json b/MathMC/635.json new file mode 100644 index 0000000000000000000000000000000000000000..07d4f646fadeda2812af7472c18c30f3d5a34292 --- /dev/null +++ b/MathMC/635.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "百位" + }, + { + "bullet": "B", + "text": "千位" + }, + { + "bullet": "C", + "text": "万位" + } + ], + "text": "76×91的积的最高位是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "76×91 = 6916，所以76×91的积的最高位是千位，故答案选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/636.json b/MathMC/636.json new file mode 100644 index 0000000000000000000000000000000000000000..32bfe66f9722e13a979545862fd225b8c1800a26 --- /dev/null +++ b/MathMC/636.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16千米" + }, + { + "bullet": "B", + "text": "20千米" + }, + { + "bullet": "C", + "text": "36千米" + }, + { + "bullet": "D", + "text": "45千米" + } + ], + "text": "一辆汽车\\frac{2}{3}小时行驶了30千米，照这样的速度，这辆汽车\\frac{4}{5}小时行驶( )千米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "首先根据:路程÷ 时间=速度，用这辆汽车\\frac{2}{3}小时行驶的路程除以\\frac{2}{3}，求出这辆汽车的速度是多少;然后用它乘\\frac{4}{5}，求出这辆汽车\\frac{4}{5}小时行驶多少千米即可.30÷ \\frac{2}{3}× \\frac{4}{5} =45× \\frac{4}{5} =36(千米) 答:这辆汽车\\frac{4}{5}小时行驶36千米. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/637.json b/MathMC/637.json new file mode 100644 index 0000000000000000000000000000000000000000..af84e7fb193a2d5a50a4c094f3074f30aef9cb43 --- /dev/null +++ b/MathMC/637.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "无数" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "5" + } + ], + "text": "分母是9的最简真分数有( )个. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分母是9的真分数有 \\frac{1}{9}、 \\frac{2}{9}、 \\frac{3}{9}、 \\frac{4}{9}、 \\frac{5}{9}、 \\frac{6}{9}、 \\frac{7}{9}、 \\frac{8}{9}，其中 \\frac{3}{9}能化简为 \\frac{1}{3}， \\frac{6}{9}能化简为 \\frac{2}{3}，所以最简真分数只有6个，因此得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/638.json b/MathMC/638.json new file mode 100644 index 0000000000000000000000000000000000000000..698b25014373dfac7c7f953d8e112652fbc3f2e6 --- /dev/null +++ b/MathMC/638.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "电梯的升降" + }, + { + "bullet": "B", + "text": "汽车方向盘的运动" + }, + { + "bullet": "C", + "text": "妈妈擦地，墩布的运动" + } + ], + "text": "下列运动现象中，( )是旋转. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "将一个图形上的所有点都按照某个方向作相同距离的移动，这样的图形运动叫作图形的平移运动;把一个图形绕着某一点O转动一个角度的图形变换叫做旋转;据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/639.json b/MathMC/639.json new file mode 100644 index 0000000000000000000000000000000000000000..9065451ec9dd8a79d3350979c7dbf7247d1338a3 --- /dev/null +++ b/MathMC/639.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "8" + } + ], + "text": "把一块正方体橡皮泥切三刀，最多可以切成( )块. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "纵切两刀，要交叉切，可以切成4块，横切一刀，把这4块都又一分为二，可切成8块." + ] + } +} \ No newline at end of file diff --git a/MathMC/64.json b/MathMC/64.json new file mode 100644 index 0000000000000000000000000000000000000000..1d2a004068e9ad76ac00159ba15cca14dc53f6e7 --- /dev/null +++ b/MathMC/64.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "锐角三角形" + }, + { + "bullet": "B", + "text": "直角三角形" + }, + { + "bullet": "C", + "text": "钝角三角形" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "一个三角形的三个内角的度数比是2:3:4，这个三角形是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "三角形的内角和为180°，进一步直接利用按比例分配求得份数最大的角;三个内角的度数比是2:3:4，也就是将180°分成9份，最大的角占4份，用分数乘法计算即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/640.json b/MathMC/640.json new file mode 100644 index 0000000000000000000000000000000000000000..dfd66114e9d0da30dd36d35b22d18429766c32c0 --- /dev/null +++ b/MathMC/640.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "十万位" + }, + { + "bullet": "B", + "text": "万位" + }, + { + "bullet": "C", + "text": "千位" + }, + { + "bullet": "D", + "text": "百位" + } + ], + "text": "798×27的积的最高位是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先根据整数乘法的计算方法，求出运算的结果即可求解. 798× 27=21546; 积是21546，积是五位数，故B正确. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/641.json b/MathMC/641.json new file mode 100644 index 0000000000000000000000000000000000000000..683d27d55b16778ce7c37254f2156bc0b0fb4b13 --- /dev/null +++ b/MathMC/641.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{15}{25}" + }, + { + "bullet": "B", + "text": "\\frac{17}{51}" + }, + { + "bullet": "C", + "text": "\\frac{3}{19}" + } + ], + "text": "下面各数中，( )是最简分数. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "最简分数的分子和分母是互质数，互质数的两个数只有公因数1，以此即可得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/642.json b/MathMC/642.json new file mode 100644 index 0000000000000000000000000000000000000000..08cf215d8691003c1de025869b45b5bfdaacb566 --- /dev/null +++ b/MathMC/642.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + }, + { + "bullet": "D", + "text": "6" + } + ], + "text": "在12、3、19、10、16、7、0、15、20这些数中，比10大的数有 个" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "比10大的数有:12、19、16、15、20共有5个数，故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/643.json b/MathMC/643.json new file mode 100644 index 0000000000000000000000000000000000000000..37523cd78abaa67ac3c8b67a7c718ed090691e97 --- /dev/null +++ b/MathMC/643.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "50°" + }, + { + "bullet": "B", + "text": "65°" + }, + { + "bullet": "C", + "text": "130°" + }, + { + "bullet": "D", + "text": "55°" + } + ], + "text": "一个等腰三角形的顶角度数是一个底角度数的10/13，那么这个等腰三角形的一个底角的度数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "设出底角的度数，然后表示出顶角，根据三角形的内角和定理列方程求解即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/644.json b/MathMC/644.json new file mode 100644 index 0000000000000000000000000000000000000000..b6ae768ac12b8d0b5d926bbaaa835fa7061194a0 --- /dev/null +++ b/MathMC/644.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a的\\frac{2}{3}是多少?" + }, + { + "bullet": "B", + "text": "一个数的\\frac{2}{3}是a，求这个数" + }, + { + "bullet": "C", + "text": "把a平均分成3份，求2份 是多少?" + } + ], + "text": "a÷\\frac{2}{3}是求( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "A，a的\\frac{2}{3}是多少，列式为:a×\\frac{2}{3}; B，一个数的\\frac{2}{3}是a，求这个数，列式为:a÷\\frac{2}{3}; C，把a平均分成3份，求2份 是多少，列式为:a÷3×2，或者a×\\frac{2}{3}. 所以:a÷\\frac{2}{3}表示:一个数的\\frac{2}{3}是a，求这个数. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/645.json b/MathMC/645.json new file mode 100644 index 0000000000000000000000000000000000000000..a42c219b4ffa8174ccfd1054a7aa1318aab055fd --- /dev/null +++ b/MathMC/645.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{4}÷a" + }, + { + "bullet": "B", + "text": "a÷ \\frac{3}{4}" + }, + { + "bullet": "C", + "text": "\\frac{3}{4}×a" + } + ], + "text": "下面式子里的a是一个不为0的自然数，哪个式子的得数最大?( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一个数乘小于1的数积小于这个数，一个数乘大于1的数积大于这个数;一个数除以小于1的数商大于这个数，一个数除以大于1的数商小于这个数;由此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/646.json b/MathMC/646.json new file mode 100644 index 0000000000000000000000000000000000000000..7a4ef4c2d95a8028371d8f4b785aee10bfcc8d44 --- /dev/null +++ b/MathMC/646.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "25" + }, + { + "bullet": "C", + "text": "12.5" + } + ], + "text": "在一个周长是100厘米的正方形纸片内，要剪一个最大的圆，这个圆的半径是( )厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在正方形中剪最大的圆，那么圆的直径就是正方形的边长. 所以直径是100÷4=25厘米，那么半径就是25÷2=12.5厘米. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/647.json b/MathMC/647.json new file mode 100644 index 0000000000000000000000000000000000000000..e8efa269b51ea7953f36d0da999e841bfb9e2fdf --- /dev/null +++ b/MathMC/647.json @@ -0,0 +1,36 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "H" + }, + { + "bullet": "B", + "text": "B" + }, + { + "bullet": "C", + "text": "C" + }, + { + "bullet": "D", + "text": "F" + }, + { + "bullet": "E", + "text": "G" + } + ], + "text": "某校数学竞赛，A，B，C，D，E，F，G，H八位同学获得前八名.老师让他们猜一下谁是第一名. A说:‘或者F是第一名，或者H是第一名.‘ B说:‘我是第一名.‘ C说:‘G是第一名.‘ D说:‘B不是第一名.‘ E说:‘A说得不对.‘ F说:‘我不是第一名，H也不是第一名.‘ G说:‘C不是第一名‘ H说:‘我同意A的意见‘ 老师指出:八个人中有三人猜对了，那么第一名是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "8人中，有3对说的恰好相反，因为只有3人说的是正确的，那么另外两人一定是错误的，再根据错误学生说的话判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/648.json b/MathMC/648.json new file mode 100644 index 0000000000000000000000000000000000000000..01ffa7fed80168046b0abecffcd2ce71ad88f909 --- /dev/null +++ b/MathMC/648.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一定都是质数" + }, + { + "bullet": "B", + "text": "一定都是合数" + }, + { + "bullet": "C", + "text": "公因数只有1" + } + ], + "text": "互质的两个数( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据互质数的意义和判断方法，公因数只有1的两个数，叫做互质数。从而得出答案是C." + ] + } +} \ No newline at end of file diff --git a/MathMC/649.json b/MathMC/649.json new file mode 100644 index 0000000000000000000000000000000000000000..8ec3663a9b5324f74c4ea36e93255f8c8b4bfca3 --- /dev/null +++ b/MathMC/649.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "14厘米" + }, + { + "bullet": "B", + "text": "14平方厘米" + }, + { + "bullet": "C", + "text": "6平方厘米" + } + ], + "text": "用6个边长1厘米的小正方形拼成一个长方形，这个长方形的面积是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "拼合后的长方形的面积是原来6个正方形的面积的和，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/65.json b/MathMC/65.json new file mode 100644 index 0000000000000000000000000000000000000000..c74a99136363ee4f0bb6e2c9c1dc58ab87fa393b --- /dev/null +++ b/MathMC/65.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比168厘米矮" + }, + { + "bullet": "B", + "text": "比168厘米高" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "学校足球队员的平均身高是168厘米，最近又来了一位队员，他的身高是178厘米，现在足球队员的平均身高( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "178厘米>168厘米，所以这位队员来了之后会使平均身高变高. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/650.json b/MathMC/650.json new file mode 100644 index 0000000000000000000000000000000000000000..6ee0c1fdd5a0494674bff85b63e268233b624a05 --- /dev/null +++ b/MathMC/650.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "分数单位相同，大小相等" + }, + { + "bullet": "B", + "text": "分数单位相同，大小不相等" + }, + { + "bullet": "C", + "text": "分数单位不同，大小不相等" + }, + { + "bullet": "D", + "text": "分数单位不同，大小相等" + } + ], + "text": "\\frac{6}{7}和 \\frac{54}{63}相比，下面说法正确的是( )。" + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "\\frac{6}{7}的分数单位是 \\frac{1}{7}， \\frac{54}{63}的分数单位是 \\frac{1}{63}，分数单位不同; \\frac{6}{7}=\\frac {6× 9} {7× 9}=\\frac{54}{63}，所以大小相等;所以应选D。" + ] + } +} \ No newline at end of file diff --git a/MathMC/651.json b/MathMC/651.json new file mode 100644 index 0000000000000000000000000000000000000000..9fad29f3ff068e0954a3a77e778ac5b73c843bf0 --- /dev/null +++ b/MathMC/651.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于乙数" + }, + { + "bullet": "B", + "text": "小于乙数" + }, + { + "bullet": "C", + "text": "等于乙数" + } + ], + "text": "甲乙两数都是自然数，如果数÷.92=乙数，那么甲定() " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在小数除法中，被除数不为0，除数大于1(不含1)，被除数大于商;除数小于1(不含1)，被除数小于商;除数等于1，被除数和商相等，依此即可作出判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/652.json b/MathMC/652.json new file mode 100644 index 0000000000000000000000000000000000000000..7f0907558642f6f14637ad99b908c51d1a2d8be7 --- /dev/null +++ b/MathMC/652.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{3}{2}÷ \\frac{5}{24}" + }, + { + "bullet": "B", + "text": "\\frac{3}{2}× \\frac{5}{24}" + }, + { + "bullet": "C", + "text": "\\frac{5}{24}÷ \\frac{3}{2}" + } + ], + "text": "一辆汽车行\\frac{3}{2}千米用汽油\\frac{5}{24}升，1升汽油可行多少千米?列式正确的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "~~~~\\frac{3}{2}÷ \\frac{5}{24} =\\frac{3}{2}× \\frac{24}{5} =7.2(千米)， 答:1升汽油可行7.2千米." + ] + } +} \ No newline at end of file diff --git a/MathMC/653.json b/MathMC/653.json new file mode 100644 index 0000000000000000000000000000000000000000..b0b5c1de28a4480f42b722e58a12d4e0da031848 --- /dev/null +++ b/MathMC/653.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小于1" + }, + { + "bullet": "B", + "text": "大于1" + }, + { + "bullet": "C", + "text": "等于1" + } + ], + "text": "两个数相乘，积大于第一个因数，则另一个因数( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在乘法算式里，当一个因数比1大时，积就比另一个因数大，一个因数比1小时，积就比另一个因数(0除外)小，当一个因数等于1时，积就等于另一个因数，据此解答即可得到答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/654.json b/MathMC/654.json new file mode 100644 index 0000000000000000000000000000000000000000..9cc5062a271473e255dc5f654adcf83a40259821 --- /dev/null +++ b/MathMC/654.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于1" + }, + { + "bullet": "B", + "text": "小于1" + }, + { + "bullet": "C", + "text": "等于1" + } + ], + "text": "如果两个数相乘的积小于被乘数，那么乘数( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据乘法的意义可知， 如果两个因数相乘的积小于其中的一个因数，那么另一个因数就小于1. 故选:B. 根据乘法的意义可知，一个数乘一个小于1的数，则积就小于这个数.因此如果两个因数相乘的积小于其中的一个因数，那么另一个因数就小于1.一个不为零的数乘一个大于1的数，积就大于这个数." + ] + } +} \ No newline at end of file diff --git a/MathMC/655.json b/MathMC/655.json new file mode 100644 index 0000000000000000000000000000000000000000..6fef5e3107513d748dd2032dd8407b69960f6306 --- /dev/null +++ b/MathMC/655.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16" + }, + { + "bullet": "B", + "text": "17" + }, + { + "bullet": "C", + "text": "40" + } + ], + "text": "下面的数，因数个数最少的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "首先分别判断出每个数的因数的个数是多少，然后比较大小，判断出因数个数最少的数是多少即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/656.json b/MathMC/656.json new file mode 100644 index 0000000000000000000000000000000000000000..9fe762de19df41f7de1fbe3e4fb40927c502948b --- /dev/null +++ b/MathMC/656.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "659" + }, + { + "bullet": "B", + "text": "82" + }, + { + "bullet": "C", + "text": "208" + } + ], + "text": "一个数减去487，小马虎将被减数的百位和十位上的数字互换了，结果得172，那么正确的差是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先求出计算错误时的被减数为487+172，再把被减数的百位和十位上的数交换就是正确的被减数，再用正确的被减数减去就是就是正确的结果." + ] + } +} \ No newline at end of file diff --git a/MathMC/657.json b/MathMC/657.json new file mode 100644 index 0000000000000000000000000000000000000000..1bc4722a4fa7eaff73c9cae2be23c55ff65c8e5c --- /dev/null +++ b/MathMC/657.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "750-130" + }, + { + "bullet": "B", + "text": "301+402" + }, + { + "bullet": "C", + "text": "830-195" + } + ], + "text": "下面算式结果大于700的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，在750-130中，可把130看作150进行估算，在301和402中分别看作300和400进行估算，在830-195中，把195看作200进行估算，据此解答即可得到答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/658.json b/MathMC/658.json new file mode 100644 index 0000000000000000000000000000000000000000..ab66ed393772cb78577d6c2a09c88bb9f71809ac --- /dev/null +++ b/MathMC/658.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "89□870≈90万，□里最小能填( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "89□870≈90万，显然是用‘五入‘法求出的近似数，所以空格里最小可以填5." + ] + } +} \ No newline at end of file diff --git a/MathMC/659.json b/MathMC/659.json new file mode 100644 index 0000000000000000000000000000000000000000..7324072e70d2789a391543b61e4a1e3c54200758 --- /dev/null +++ b/MathMC/659.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1.6:1" + }, + { + "bullet": "B", + "text": "8:5" + }, + { + "bullet": "C", + "text": "160:1" + }, + { + "bullet": "D", + "text": "160:100" + } + ], + "text": "哥哥身高160厘米，妹妹身高是100厘米，哥哥和妹妹身高的最简单整数比是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用哥哥的身高比妹妹的身高，再根据比的基本性质化简即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/66.json b/MathMC/66.json new file mode 100644 index 0000000000000000000000000000000000000000..643d9ffb58713a532f938323d1b123752d6f79a1 --- /dev/null +++ b/MathMC/66.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "24" + }, + { + "bullet": "D", + "text": "96" + } + ], + "text": "既是2的倍数，又是3的倍数的最小两位数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先求出2和3的最小公倍数，然后根结合题意，从2和3的公倍数中找，进而得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/660.json b/MathMC/660.json new file mode 100644 index 0000000000000000000000000000000000000000..50cfb4713fe403046b34748d4dbc949bf503dbb7 --- /dev/null +++ b/MathMC/660.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4.151" + }, + { + "bullet": "B", + "text": "4.152" + }, + { + "bullet": "C", + "text": "4.1515…" + } + ], + "text": "下列数中，最大的一个数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "小数大小的比较方法，先比较小数的整数部分，整数部分大的这个小数就大，如果整数部分相同，就比较十分位，十分位大的这个小数就大，如果十分位相同，就比较百分位，百分位大的这个小数就大，如果百分位相同，就比较千分位…据此可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/661.json b/MathMC/661.json new file mode 100644 index 0000000000000000000000000000000000000000..a72cbfb87281f35d8f8dd13fa83c5310ac5eafb2 --- /dev/null +++ b/MathMC/661.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "先向南走50米，再向东走100米" + }, + { + "bullet": "B", + "text": "先向北走100米，再向南走50米" + }, + { + "bullet": "C", + "text": "先向北走50米，再向西走100米" + } + ], + "text": "小刚从家出来先向东走100米，再向南走50米到超市，沿原路回来时，他该怎样走?( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "小刚从家到超市，沿原路回来时，返回时的方向和去时的方向正好相反，路程一样.去时先向东走100米，再向南走50米;返回时就先向北走50米，再向西走100米." + ] + } +} \ No newline at end of file diff --git a/MathMC/662.json b/MathMC/662.json new file mode 100644 index 0000000000000000000000000000000000000000..22f54858dda16a7e5b0ec41b6e819f9f8c4bfa5f --- /dev/null +++ b/MathMC/662.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加" + } + ], + "text": "一个边长2分米的正方形，如果在四个角各剪去一个边长为2厘米的小正方形，那么它的周长与原来比是 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据正方形周长的特点来解题." + ] + } +} \ No newline at end of file diff --git a/MathMC/663.json b/MathMC/663.json new file mode 100644 index 0000000000000000000000000000000000000000..b3a5e9f2dc3261d9e70c162f41486fd00fa1661e --- /dev/null +++ b/MathMC/663.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60秒" + }, + { + "bullet": "B", + "text": "60分" + }, + { + "bullet": "C", + "text": "2分" + } + ], + "text": "钟面上秒针走两圈，经过的时间是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在钟面上，共有12个大格，每个大格分成5个小格，共有60个小格，时针走1大格是1时;分针走1小格是1分，走1大格是5分，走一圈是60分;秒针走1小格是1秒，走1大格是5秒，走一圈是60秒;据此进行解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/664.json b/MathMC/664.json new file mode 100644 index 0000000000000000000000000000000000000000..63c2d5306d18fbf7c341f3b91b827d0fa420141e --- /dev/null +++ b/MathMC/664.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "22" + }, + { + "bullet": "B", + "text": "20" + }, + { + "bullet": "C", + "text": "18" + }, + { + "bullet": "D", + "text": "16" + } + ], + "text": "明明买了一些80分和40分的邮票共花了18元钱，已知40分的邮票比80分的少15张，那么80分的邮票有( )张. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "设出未知数，找好等量关系列方程." + ] + } +} \ No newline at end of file diff --git a/MathMC/665.json b/MathMC/665.json new file mode 100644 index 0000000000000000000000000000000000000000..9a4038ec8970c5dc36d43d804998977dd8fdf64c --- /dev/null +++ b/MathMC/665.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{a+b}{16}" + }, + { + "bullet": "B", + "text": "\\frac{ab}{8}" + }, + { + "bullet": "C", + "text": "\\frac{a+b}{8}" + } + ], + "text": "\\frac{a}{8}+ \\frac{b}{8}的结果是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据同分母分数加法的计算方法:同分母分数相加，分母不变，分子相加，由此进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/666.json b/MathMC/666.json new file mode 100644 index 0000000000000000000000000000000000000000..cdb874a6b8d056b84089e3d62ed1bfbb94156bbc --- /dev/null +++ b/MathMC/666.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减去9" + }, + { + "bullet": "B", + "text": "除以9" + }, + { + "bullet": "C", + "text": "除以4" + } + ], + "text": "如果把的分子减去9，要使分数的大小不变，分母应( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "提示1:依据分数的基本性质，即分数的分子和分母同时乘上或除以相同的数(0除外)，分数的大小不变，从而可以正确进行作答. 提示2:此题主要考查分数的基本性质的灵活应用." + ] + } +} \ No newline at end of file diff --git a/MathMC/667.json b/MathMC/667.json new file mode 100644 index 0000000000000000000000000000000000000000..0451c3298d1bf7e0e51fde1553d68cbdad3fefad --- /dev/null +++ b/MathMC/667.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3:2" + }, + { + "bullet": "B", + "text": "2:1" + }, + { + "bullet": "C", + "text": "1:3" + }, + { + "bullet": "D", + "text": "2:3" + } + ], + "text": "把一个圆柱削成一个最大的圆锥，那么圆柱的体积和削去部分的体积比是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把一个圆柱削成最大的圆锥，则圆锥与原来圆柱是等底等高的，则圆锥的体积是圆柱的体积的 1/3，把圆柱的体积看做单位‘1‘，由此即可得出削去部分的体积是圆柱体积的1-1/3= 2/3，据此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/668.json b/MathMC/668.json new file mode 100644 index 0000000000000000000000000000000000000000..4c4d3948efcd995ab4e7860a8180a1f92b651d06 --- /dev/null +++ b/MathMC/668.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0.85÷0.0125" + }, + { + "bullet": "B", + "text": "8.5÷1.25" + }, + { + "bullet": "C", + "text": "85÷0.125" + } + ], + "text": "下面算式中商最大的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由商不变的规律可知，被除数和除数同时乘(或除以)相同的数，商不变，当被除数乘的倍数大于除数乘的倍数(或被除数除以倍数小于除数除以倍数)时，商变大，反之变小;由A和B比较，被除数0.85变成8.5是乘10倍，而除数0.012 5变成1.25是乘100倍，所以0.85÷0.012 5的商大;再和C比较，被除数0.85变成85是乘100倍，而除数0.012 5变成0.125是乘10倍，这两个算式中，85÷0.125的商大;所以商最大的是85÷0.125." + ] + } +} \ No newline at end of file diff --git a/MathMC/669.json b/MathMC/669.json new file mode 100644 index 0000000000000000000000000000000000000000..072f79ff5076030b7964300da6505a76d3b49e40 --- /dev/null +++ b/MathMC/669.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a+0=a" + }, + { + "bullet": "B", + "text": "a-0=a" + }, + { + "bullet": "C", + "text": "a×0=a" + }, + { + "bullet": "D", + "text": "a÷0=0" + } + ], + "text": "关于0的运算，以下说法不成立的是( )。 " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "" + ] + } +} \ No newline at end of file diff --git a/MathMC/67.json b/MathMC/67.json new file mode 100644 index 0000000000000000000000000000000000000000..df38e9036c82724dbec95ad37b39f189cbc99c15 --- /dev/null +++ b/MathMC/67.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小刚" + }, + { + "bullet": "B", + "text": "小军" + }, + { + "bullet": "C", + "text": "小明" + } + ], + "text": "在100米比赛中，小刚跑了16.5秒，小军跑了16.9秒，小明跑了15.6秒，( )跑得最快. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先依据小数大小的比较方法比较出他们所用时间的大小，时间越少的，跑得就越快，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/670.json b/MathMC/670.json new file mode 100644 index 0000000000000000000000000000000000000000..e754a1b12bc5c78fb194f7200b920114ac2e28ab --- /dev/null +++ b/MathMC/670.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30" + }, + { + "bullet": "B", + "text": "60" + }, + { + "bullet": "C", + "text": "126" + }, + { + "bullet": "D", + "text": "240" + } + ], + "text": "如果一堆糖平均分给2、3、4、5、6个小朋友，都可以使每人分到的颗数一样，那么这堆糖至少有( )颗. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题实际考查的是求最小公倍数，要求可以平均分给2、3、4、5、6个小朋友，则只要求出这几个数的最小公倍就可以了." + ] + } +} \ No newline at end of file diff --git a/MathMC/671.json b/MathMC/671.json new file mode 100644 index 0000000000000000000000000000000000000000..f8c99a5a7b8a7a04ced5a6662c05077a15877e8f --- /dev/null +++ b/MathMC/671.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "9" + }, + { + "bullet": "C", + "text": "18" + }, + { + "bullet": "D", + "text": "36" + } + ], + "text": "一个长方体的棱长之和是36厘米，从一个顶点出发的三条棱的和是( )厘米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据长方体棱的特征，12条棱分为互相平行的3组，每组4条棱的长度相等，长方体有8个顶点.每个顶点连接三条棱.三条棱分别叫做长方体的长，宽，高，长方体的棱长总和=(长+宽+高)×4，用棱长总和除以4，由此列式解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/672.json b/MathMC/672.json new file mode 100644 index 0000000000000000000000000000000000000000..77327a8590bd4b74d6542caa6ce5acc26089381b --- /dev/null +++ b/MathMC/672.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一次长" + }, + { + "bullet": "B", + "text": "第二次用去的长" + }, + { + "bullet": "C", + "text": "一样长" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "有一根1米长的木料，第一次用去米，第二次用去全长的.哪一次用去的长?( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把木料的全长看作单位‘1‘，第二次用去全长的，用1×即得第一次用去多少，再与第一次用去的米比较得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/673.json b/MathMC/673.json new file mode 100644 index 0000000000000000000000000000000000000000..537dc40013a04bd2e8df2c93eca52917c3702036 --- /dev/null +++ b/MathMC/673.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小王" + }, + { + "bullet": "B", + "text": "小李" + }, + { + "bullet": "C", + "text": "小刘" + } + ], + "text": "跑100米，小王用了 1/3分钟，小李用了 2/5分钟，小刘用了 1/4分钟，跑得最快的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "跑得最快的人就是用时最少的人，通过比较三个人的用时，先通分比较出大小，分数值最小的就是跑得最快的." + ] + } +} \ No newline at end of file diff --git a/MathMC/674.json b/MathMC/674.json new file mode 100644 index 0000000000000000000000000000000000000000..1ae30c3784ea17d204391ea658b1f26603be1b3c --- /dev/null +++ b/MathMC/674.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3/4" + }, + { + "bullet": "B", + "text": "3/7" + }, + { + "bullet": "C", + "text": "7/4" + }, + { + "bullet": "D", + "text": "4/7" + } + ], + "text": "小明在计算乘法时，不小心将一个乘数24错写成42，那么计算结果比正确答案多( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "从数的性质方面考虑" + ] + } +} \ No newline at end of file diff --git a/MathMC/675.json b/MathMC/675.json new file mode 100644 index 0000000000000000000000000000000000000000..9f55b27305cdb8bccd90778143edd0ead68f4cf1 --- /dev/null +++ b/MathMC/675.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "91分" + }, + { + "bullet": "B", + "text": "92分" + }, + { + "bullet": "C", + "text": "93分" + } + ], + "text": "在一次考试中，小力成绩如:语文87分，数学94分，英语95分，她三门功课的平均成绩是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "语文87分，数学94分，英语95分，把三科的成绩相加除以3，即可求出三门功课的平均成绩，列式解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/676.json b/MathMC/676.json new file mode 100644 index 0000000000000000000000000000000000000000..c18110530b6423998c92b1bc7c9bab8108be835b --- /dev/null +++ b/MathMC/676.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/4" + }, + { + "bullet": "B", + "text": "2/4" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "一个苹果平均分成4份，小明吃了2块，小明吃了这个苹果的 . " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "掌握分数的意义." + ] + } +} \ No newline at end of file diff --git a/MathMC/677.json b/MathMC/677.json new file mode 100644 index 0000000000000000000000000000000000000000..6743c29001195bf119b39d1e3ef3976bc9eb05b5 --- /dev/null +++ b/MathMC/677.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20平方厘米" + }, + { + "bullet": "B", + "text": "25厘米" + }, + { + "bullet": "C", + "text": "20厘米" + } + ], + "text": "一个正方形的面积是25平方厘米，它的周长是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为正方形的面积S=a×a，5×5=25，由此得出正方形的边长是5厘米，再根据正方形的周长公式C=4a，即可求出它的周长." + ] + } +} \ No newline at end of file diff --git a/MathMC/678.json b/MathMC/678.json new file mode 100644 index 0000000000000000000000000000000000000000..f42583f56bb4bdcf6534dedb757fa143c1654818 --- /dev/null +++ b/MathMC/678.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于90度" + }, + { + "bullet": "B", + "text": "小于180度" + }, + { + "bullet": "C", + "text": "大于90度而小于180度" + } + ], + "text": "钝角是( )的角. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据钝角的含义:大于90度而小于180度的角，叫做钝角;据此选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/679.json b/MathMC/679.json new file mode 100644 index 0000000000000000000000000000000000000000..208956fb9d0a8152dd9148cfc20146ca82ec604a --- /dev/null +++ b/MathMC/679.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "106÷ 0.8" + }, + { + "bullet": "B", + "text": "106÷ \\frac{2}{10}" + }, + { + "bullet": "C", + "text": "106÷ \\frac{8}{10}" + } + ], + "text": "一件商品打八折出售是106元，这件商品的原价是多少元?正确的列式是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "106是打八折的售价，故其占原价的8%，因此求原价时应为106÷ 0.8. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/68.json b/MathMC/68.json new file mode 100644 index 0000000000000000000000000000000000000000..83fab042c9c17448e2b6b750bd5015b9bdaafdb9 --- /dev/null +++ b/MathMC/68.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "表面积的大" + }, + { + "bullet": "B", + "text": "体积大" + }, + { + "bullet": "C", + "text": "一样大" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "一个棱长6厘米的正方体，它的表面积与体积相比较( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "正方形表面积:6×{{6}^{2}}=216平方厘米， 正方体体积:{{6}^{3}}=216立方厘米， ∵单位不同， ∴无法比较. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/680.json b/MathMC/680.json new file mode 100644 index 0000000000000000000000000000000000000000..8aa54131ed4886e8c8705b8398f013a369b55749 --- /dev/null +++ b/MathMC/680.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3元6角" + }, + { + "bullet": "B", + "text": "36元" + }, + { + "bullet": "C", + "text": "360元" + } + ], + "text": "买30枚8角的邮票和20枚6角的邮票共需要( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题根据单价×数量=总价，分别求出买30枚8角的邮票和20枚6角的邮票各需多少钱后，再相加求得即可.30*0.8+20*0.6=36元" + ] + } +} \ No newline at end of file diff --git a/MathMC/681.json b/MathMC/681.json new file mode 100644 index 0000000000000000000000000000000000000000..deab463af61c4d748136aa31759b672058e83cb1 --- /dev/null +++ b/MathMC/681.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "山羊只数" + }, + { + "bullet": "B", + "text": "绵羊只数" + }, + { + "bullet": "C", + "text": "山羊只数比绵羊只数多的部分" + }, + { + "bullet": "D", + "text": "山羊只数和绵羊只数同样多的部分" + } + ], + "text": "山羊只数比绵羊多15%，15%是( )与绵羊只数比较. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "山羊只数比绵羊多15%，单位一是绵羊，15%是山羊只数比绵羊只数多的部分与绵羊只数比. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/682.json b/MathMC/682.json new file mode 100644 index 0000000000000000000000000000000000000000..0307404e01a3195b99c5b4a816ba78cf61d865e5 --- /dev/null +++ b/MathMC/682.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "( 25+14 )× 2" + }, + { + "bullet": "B", + "text": "25+14× 2" + }, + { + "bullet": "C", + "text": "25+39× 2" + } + ], + "text": "把25+14=39，39× 2=78合并成一道综合算式是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "( 25+14 )× 2=39× 2=78. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/683.json b/MathMC/683.json new file mode 100644 index 0000000000000000000000000000000000000000..9810f7af71b1d089d7a4c6a4e64ce9df1e35cd04 --- /dev/null +++ b/MathMC/683.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "800" + }, + { + "bullet": "B", + "text": "899" + }, + { + "bullet": "C", + "text": "898" + } + ], + "text": "最大的三位数比最小的三位数大( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题干分析可知，最大的三位数是999，最小的三位数是100，用999减去100，计算出得数选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/684.json b/MathMC/684.json new file mode 100644 index 0000000000000000000000000000000000000000..68e86808c1e6accbc7344a910bd39fe238597bee --- /dev/null +++ b/MathMC/684.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "南偏东60°" + }, + { + "bullet": "B", + "text": "西偏南30°" + }, + { + "bullet": "C", + "text": "西偏北30°" + }, + { + "bullet": "D", + "text": "北偏西30°" + } + ], + "text": "小明在小红的东偏南30°方向100米处，则小红在小明的( )方向100米处. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "这道题的解答首先要熟悉画图的方向‘上北下南，左西右东‘.依据方向的相对性，即南与北相对，东与西相对，据此即可解答.两个物体的位置的相对性，分别以小明和小红的位置为观测点，看到的对方的位置特点是:它们的角度相同，距离不变，方向相反." + ] + } +} \ No newline at end of file diff --git a/MathMC/685.json b/MathMC/685.json new file mode 100644 index 0000000000000000000000000000000000000000..d0f9a6e387a6f3492f823940ebcb8ec632eba094 --- /dev/null +++ b/MathMC/685.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "西" + }, + { + "bullet": "B", + "text": "南" + }, + { + "bullet": "C", + "text": "东南" + }, + { + "bullet": "D", + "text": "西北" + } + ], + "text": "指南针是我国古代四大发明之一，它的指针一端总是指向( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "指南针是我国古代的四大发明之一，它的一端指向南，另一端指向北，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/686.json b/MathMC/686.json new file mode 100644 index 0000000000000000000000000000000000000000..d95ca901c7533b909b447bc72c7c9b9e4b5f5373 --- /dev/null +++ b/MathMC/686.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20平方厘米" + }, + { + "bullet": "B", + "text": "20厘米" + }, + { + "bullet": "C", + "text": "25厘米" + } + ], + "text": "一个正方形的面积是25平方厘米，它的周长是( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "正方形的面积=边长×边长，因为5×5=25，所以正方形的边长是5厘米，正方形的周长为:5×4=20(厘米)。 故答案为:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/687.json b/MathMC/687.json new file mode 100644 index 0000000000000000000000000000000000000000..d8cde8f3f085305e3c4464acb898b9b908df1d90 --- /dev/null +++ b/MathMC/687.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90°-x°" + }, + { + "bullet": "B", + "text": "180°-2x°" + }, + { + "bullet": "C", + "text": "(180°-x°)÷2" + } + ], + "text": "一个等腰三角形的底角是x°，它的顶角是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "等腰三角形的三个内角的和是180°，两个底角相等，所以求顶角时，用180°减去两个底角就行了." + ] + } +} \ No newline at end of file diff --git a/MathMC/688.json b/MathMC/688.json new file mode 100644 index 0000000000000000000000000000000000000000..2c40355255e1580eae76a7f8c7bee8362794e77b --- /dev/null +++ b/MathMC/688.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "甲、乙两数都不为0，如果甲数÷ 2.86=乙，那么甲数一定( )乙数. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "甲=乙× 2.86." + ] + } +} \ No newline at end of file diff --git a/MathMC/689.json b/MathMC/689.json new file mode 100644 index 0000000000000000000000000000000000000000..b0f003a25a9f1619229a77003f5c22b29b43cb8a --- /dev/null +++ b/MathMC/689.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4;5" + }, + { + "bullet": "B", + "text": "4;9" + }, + { + "bullet": "C", + "text": "5;1" + } + ], + "text": "要使‘□6÷5的商是一位数，□最大能填( )，要使商是两位数，□最小能填( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意，要使□6÷5的商是一位数，□里面的数小于5，再找最大的即可;要使商是两位数，□里面的数大于或等于5，再找出最小的即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/69.json b/MathMC/69.json new file mode 100644 index 0000000000000000000000000000000000000000..5d840caf500d0af21fea8b21df21461ec00b2e39 --- /dev/null +++ b/MathMC/69.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "9" + }, + { + "bullet": "D", + "text": "27" + } + ], + "text": "一个正方体的棱长扩大到原来的3倍，表面积扩大到原来的 倍. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "设原正方体的棱长为a，则扩大3倍后的棱长为3a， 求出扩大前后的表面积， 用扩大后的表面积除以原来的表面积， 就是表面积扩大的倍数. 设原正方体的棱长为a，则扩大3倍后的棱长为3a， 原正方体的表面积:a× a× 6=6{{a}^{2}}， 原正方体的体积:a× a× a={{a}^{3}}， 扩大后的正方体的表面积:3a× 3a× 6=54{{a}^{2}}， 表面积扩大:54{{a}^{2}}÷ 6{{a}^{2}}=9(倍)， 表面积扩大9倍. " + ] + } +} \ No newline at end of file diff --git a/MathMC/690.json b/MathMC/690.json new file mode 100644 index 0000000000000000000000000000000000000000..4d03ff7e027bec890d8140a7ebb4dd0bcb6e1e98 --- /dev/null +++ b/MathMC/690.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一样长" + }, + { + "bullet": "B", + "text": "第一根长" + }, + { + "bullet": "C", + "text": "第二根长" + } + ], + "text": "有两根长度为2米的绳子，第一根用去米，第二根用去它的，剩下的相比较( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "原来长度都是2米，看谁用去的多，用去的越多则剩下的越少，因此得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/691.json b/MathMC/691.json new file mode 100644 index 0000000000000000000000000000000000000000..3a6810f2d6c2bdcfe3d0cfb8825aa4d79e40da23 --- /dev/null +++ b/MathMC/691.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大风车的转动" + }, + { + "bullet": "B", + "text": "电风扇的转动" + }, + { + "bullet": "C", + "text": "方向盘的转动" + }, + { + "bullet": "D", + "text": "电梯的升降运动" + } + ], + "text": "下列现象中不属于旋转运动的是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据旋转的定义进行判断;在平面内，将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转.由此进行解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/692.json b/MathMC/692.json new file mode 100644 index 0000000000000000000000000000000000000000..fc427cf72b421aaf40daa27e70cc9ae68f0a810f --- /dev/null +++ b/MathMC/692.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "64" + }, + { + "bullet": "B", + "text": "16" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "4" + } + ], + "text": "一个数既是4的倍数，又是16的因数，这个数最小是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "一个数既是4的倍数，又是16的因数，这个数最小是4." + ] + } +} \ No newline at end of file diff --git a/MathMC/693.json b/MathMC/693.json new file mode 100644 index 0000000000000000000000000000000000000000..755bf36888fd0a3ddc022be23c349b301362c1dd --- /dev/null +++ b/MathMC/693.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少了" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加了" + } + ], + "text": "一个边长为4分米的正方形，如果在四个角各剪去一个边长是4厘米的正方形，那么它的周长与原来相比是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题可知本题考查周长计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/694.json b/MathMC/694.json new file mode 100644 index 0000000000000000000000000000000000000000..844aaff62a1e5546fba21b22e6af66f52e88a4b0 --- /dev/null +++ b/MathMC/694.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "31× 59" + }, + { + "bullet": "B", + "text": "40× 51" + }, + { + "bullet": "C", + "text": "39× 62" + }, + { + "bullet": "D", + "text": "29× 58" + } + ], + "text": "39× 52的积与下面算式( )的积最接近. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "找与39× 52的积最相近的算式，找与39和52最相近的数相乘即可，40与39相近，52与51相近，因此40× 51与39× 52积最相近. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/695.json b/MathMC/695.json new file mode 100644 index 0000000000000000000000000000000000000000..218ae41455c460bfb6a1dd515fab54aafb6615e1 --- /dev/null +++ b/MathMC/695.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5+4+3=12" + }, + { + "bullet": "B", + "text": "54+3=57" + }, + { + "bullet": "C", + "text": "5×4+3=23" + }, + { + "bullet": "D", + "text": "5×3+4=19" + } + ], + "text": "当a=5，b=4时，ab+3的值是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把a和b代人题目中的代数式，即可求出它的值." + ] + } +} \ No newline at end of file diff --git a/MathMC/696.json b/MathMC/696.json new file mode 100644 index 0000000000000000000000000000000000000000..21709fa2c46c132401a7fef8e8739c2bf665774e --- /dev/null +++ b/MathMC/696.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "不确定" + } + ], + "text": "两个乘数的末尾都有一个0，积的末尾至少有( )个0. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，假设这两个数分别是20和30，然后计算出它们的乘积，再进一步解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/697.json b/MathMC/697.json new file mode 100644 index 0000000000000000000000000000000000000000..dd48efbb6918202c4a385c21b43e583a18201b87 --- /dev/null +++ b/MathMC/697.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15" + }, + { + "bullet": "B", + "text": "16" + }, + { + "bullet": "C", + "text": "17" + }, + { + "bullet": "D", + "text": "18" + } + ], + "text": "丁丁读一本故事书，前3天平均每天读15页，以后每天比前3天多读5页，又读2天正好读完，这本故事书丁丁平均每天读了( )页 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据已知，前3天平均每天读15页，3天共读3个15页，即15×3=45(页)。又已知以后每天比前3天多读5页，以后每天读15+5=20(页)。又读2天，也就是2个20页，即2×20=40(页);这本故事书一共45+40=85(页)，已知丁丁共读了5天，平均每天读85÷5=17(页)故选:C 本题是考查两三位数乘一位数连乘计算" + ] + } +} \ No newline at end of file diff --git a/MathMC/698.json b/MathMC/698.json new file mode 100644 index 0000000000000000000000000000000000000000..ce4cd79ff9923e4f1b58a77662540ef42bd18f49 --- /dev/null +++ b/MathMC/698.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "14" + }, + { + "bullet": "C", + "text": "16" + }, + { + "bullet": "D", + "text": "18" + } + ], + "text": "将一根木棒锯成3段需要6分钟，则将这根木棒锯成7段需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "锯成3段，那么需要锯2次，由此求出每次需要几分钟;锯7段需要锯6次，用每次的时间乘6就是锯7段需要的时间." + ] + } +} \ No newline at end of file diff --git a/MathMC/699.json b/MathMC/699.json new file mode 100644 index 0000000000000000000000000000000000000000..323536f88cbf2eb593c48ec17bf3e597e3e6a8e7 --- /dev/null +++ b/MathMC/699.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小明" + }, + { + "bullet": "B", + "text": "小军" + }, + { + "bullet": "C", + "text": "一样" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "在百米赛跑中，小明用了0.25分钟，小军用了\\frac{3}{10}分钟，( )跑得快. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "先对两人用的时间进行比较，可以化为分数比较，也可以化为小数比较;根据‘路程一定，速度和时间成反比‘，进而得出结论. \\frac{3}{10}分钟=0.3分钟，0.3分钟>0.25分钟， 根据路程一定，速度和时间成反比，即路程一定，用的时间越多，跑的越慢，得出小明跑的快. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/7.json b/MathMC/7.json new file mode 100644 index 0000000000000000000000000000000000000000..15eabc7e6b081de408cd0c5f776ef7fe518aae93 --- /dev/null +++ b/MathMC/7.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100" + }, + { + "bullet": "B", + "text": "110" + }, + { + "bullet": "C", + "text": "120" + }, + { + "bullet": "D", + "text": "130" + } + ], + "text": "某商场将运动衣按进价的50%加价后，写上‘大酬宾，八折优惠‘，结果每件运动衣仍获利20元，每件运动衣的进价是 元. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "按照题中所给条件列出方程求解" + ] + } +} \ No newline at end of file diff --git a/MathMC/70.json b/MathMC/70.json new file mode 100644 index 0000000000000000000000000000000000000000..7f2e273875b25afe570a62a50c1f9422918a4326 --- /dev/null +++ b/MathMC/70.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "", + "text": "四位数" + }, + { + "bullet": "", + "text": "五位数" + }, + { + "bullet": "", + "text": "四位数或五位数" + } + ], + "text": "三位数乘两位数，积可能是 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，假设这两个数是999与99或100与10，然后再进一步解答。 假设这两个数是999与99或100与10; 999×99=98901; 100×10=1000; 98901是五位数，1000是四位数; 所以，三位数乘两位数，积可能是五位数，也可能是四位数。 故选: C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/700.json b/MathMC/700.json new file mode 100644 index 0000000000000000000000000000000000000000..3f3823d298c87ecd3d92e8b9a40856f4fb742f18 --- /dev/null +++ b/MathMC/700.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "圆周率π的值是圆周长与直径的比值" + }, + { + "bullet": "B", + "text": "圆周率π的值是圆面积与直径的比值" + }, + { + "bullet": "C", + "text": "圆周率π的值与圆的大小无关" + }, + { + "bullet": "D", + "text": "圆周率π的值是一个无限不循环小数" + } + ], + "text": "下列说法中不正确的是 ( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "解答此题应根据圆周率的含义:圆周率π的值是圆周长与直径的比值;并结合题意，进行依次分析，进而进行判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/701.json b/MathMC/701.json new file mode 100644 index 0000000000000000000000000000000000000000..a28b1141ca65870831e950f9ee27a77070017fe3 --- /dev/null +++ b/MathMC/701.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3006210" + }, + { + "bullet": "B", + "text": "6210300" + }, + { + "bullet": "C", + "text": "120600" + } + ], + "text": "下面各数中，不需要读出零的数是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "A选项:3006210，读作:三百万六千二百一十; B选项:6210300，读作:六百二十一万零三百; C选项:120600，读作:十二万零六百. 本题考查的是0的读法: 每级连续有几个零，都只读一个零;每级未尾的零都不读. 所以不需要读零的数是:3006210. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/702.json b/MathMC/702.json new file mode 100644 index 0000000000000000000000000000000000000000..98bc82742ef9c7461fc4533ceb2c3a02ada373e8 --- /dev/null +++ b/MathMC/702.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "5" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "7" + } + ], + "text": "☆÷○=8…5，○最小是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，在☆÷○=8…5，除数一定大于余数，余数是5，那么除数一定大于5，然后再进一步解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/703.json b/MathMC/703.json new file mode 100644 index 0000000000000000000000000000000000000000..cf291860570e8bb925088e4486d629e9d4d5fde9 --- /dev/null +++ b/MathMC/703.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "在一个长10分米，宽7分米的硬纸板里剪半径是3分米的圆，可剪( )个. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "如图: 圆的半径r=3分米，直线d=2r=6分米. 10-6=4(分米)<{}6(分米)， 所以只能剪一个. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/704.json b/MathMC/704.json new file mode 100644 index 0000000000000000000000000000000000000000..daf096261505b7823719ab4ab17b247bd1ce760f --- /dev/null +++ b/MathMC/704.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "395×80" + }, + { + "bullet": "B", + "text": "601×60" + }, + { + "bullet": "C", + "text": "578×92" + } + ], + "text": "下面算式中的得数大于40000的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据整数乘法的估算方法，利用‘四舍五入法‘，把因数看作与它接近的整十数、整百数，分别估算出各式的结果，然后进行比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/705.json b/MathMC/705.json new file mode 100644 index 0000000000000000000000000000000000000000..47570511164ce5fb43ef1eab7922384ab883efda --- /dev/null +++ b/MathMC/705.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6个" + }, + { + "bullet": "B", + "text": "2个" + }, + { + "bullet": "C", + "text": "5个" + } + ], + "text": "猴妈妈有5个猴宝宝，猴妈妈摘了30个桃子，她自己吃了3个桃子，剩下的分给猴宝宝，每个猴宝宝最多能分到( )个桃子. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "用总个数减去3求得剩下的个数，用剩下的个数除以猴宝宝的个数，得到的商是最多能分到的个数，据此将解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/706.json b/MathMC/706.json new file mode 100644 index 0000000000000000000000000000000000000000..12e42efe986bd6bbac0a6eb9e138a7276fb32ad3 --- /dev/null +++ b/MathMC/706.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "意义相同" + }, + { + "bullet": "B", + "text": "分数单位相同" + }, + { + "bullet": "C", + "text": "大小相同" + } + ], + "text": "\\frac{1}{4}和 \\frac{2}{8}这两个分数( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "\\frac{1}{4}表示把单位‘1‘平均分成4份取其1份，分数单位是 \\frac{1}{4}; \\frac{2}{8}表示把单位‘1‘平均分成8份取其2份，分数单位是 \\frac{1}{8};因此，这两个分数的分数单位及意义都不相同;根据分数的基本性质， \\frac{1}{4}的分子、分母都乘2就是 \\frac{2}{8}，因此，这两个分数的大小相等." + ] + } +} \ No newline at end of file diff --git a/MathMC/707.json b/MathMC/707.json new file mode 100644 index 0000000000000000000000000000000000000000..4dbbaf3c487a26027020eb7c5e23b9c95fa387b0 --- /dev/null +++ b/MathMC/707.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "24÷ \\frac{3}{8}" + }, + { + "bullet": "B", + "text": "24÷ ( 1-\\frac{3}{8})" + }, + { + "bullet": "C", + "text": "24÷ ( 1+\\frac{3}{8})" + }, + { + "bullet": "D", + "text": "24× ( 1-\\frac{3}{8})" + } + ], + "text": "一种药品，降价24元后，现在的售价比原来降低了\\frac{3}{8}，这种药品原价多少元?下列算式正确的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "设原价为单位‘1‘，则售价降低了‘\\frac{3}{8}‘， ∴原价为24÷ \\frac{3}{8}. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/708.json b/MathMC/708.json new file mode 100644 index 0000000000000000000000000000000000000000..f303fad63d31277e8a478a31b921a1582511c892 --- /dev/null +++ b/MathMC/708.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "周长" + }, + { + "bullet": "B", + "text": "直径" + }, + { + "bullet": "C", + "text": "半径" + } + ], + "text": "画圆时，圆规的两脚尖的距离就是圆的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把圆规的带有针尖的一只脚固定在一点作为圆心，把装有铅笔的一只脚绕带有针尖的一只脚旋转一周，画出一个圆，根据半径的含义:连接圆心到圆上任意一点的线段，叫做半径;即圆规的两脚间的距离即圆的半径;由此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/709.json b/MathMC/709.json new file mode 100644 index 0000000000000000000000000000000000000000..6e99699b7103e30c990fce1bd2ad21d5bef9eed3 --- /dev/null +++ b/MathMC/709.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2块长5分米、宽4分米，一块长4分米、宽3分米" + }, + { + "bullet": "B", + "text": "2块长5分米、宽4分米，一块长5分米、宽分米" + }, + { + "bullet": "C", + "text": "1块长4分米、宽3分米，1块长5分米、宽4分米，1块长5分米、宽3分米" + }, + { + "bullet": "D", + "text": "1块长5分米、宽4分米，2块长5分米、宽3分米" + } + ], + "text": "小刚要做一个无盖的玻璃鱼缸，已经准备了2块长方形玻璃，其中1块长5分米、宽3分米，1块长4分米，宽3分米，还需再配3块玻璃.从稳定度方面考虑，最合适的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "2块长5分米，宽3分米做鱼缸的前后面， 2块长4分米，宽3分米做鱼缸的左右面， 因此还需要配一块做鱼缸的底面，即底面的长是5分米，宽是4分米， 所以还需配1块长4分米、宽3分米，1块长5分米、宽4分米，1块长5分米、宽3分米的长方形玻璃才刚合适. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/71.json b/MathMC/71.json new file mode 100644 index 0000000000000000000000000000000000000000..c24de6bf9365ff9901b9fe8b113998b9905e0866 --- /dev/null +++ b/MathMC/71.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲车快" + }, + { + "bullet": "B", + "text": "乙车快" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "两车从A地开往B地，甲车4小时行了全程的\\frac{1}{5}，乙车5小时行了全程的\\frac{1}{4}，两车的速度相比 ( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "故选:D. 把全程看作单位‘1‘，根据速度=路程÷ 时间，分别求出甲车和乙车的速度，比较分数的大小，即可得解. 甲车的速度:\\frac{1}{5}÷ 4=\\frac{1}{20}， 乙车的速度:\\frac{1}{4}÷ 5=\\frac{1}{20}， 甲、乙两车的速度都是每小时行全程的\\frac{1}{20}，因此一样快. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/710.json b/MathMC/710.json new file mode 100644 index 0000000000000000000000000000000000000000..1708600f47913dc7d62844b6bbf2aa47cb62deb6 --- /dev/null +++ b/MathMC/710.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{9}的倒数" + }, + { + "bullet": "B", + "text": "\\frac{1}{9}的\\frac{1}{9}" + }, + { + "bullet": "C", + "text": "\\frac{1}{9}的18倍" + } + ], + "text": "下列数中，最大的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意，求出每个选项的值，再比较大小就可以求出答案. A选项，\\frac{1}{9}的倒数是9; B选项中，\\frac{1}{9}× \\frac{1}{9}=\\frac{1}{81}; C选项中，\\frac{1}{9}× 18=2; 9>2>\\frac{1}{81}; 所以，\\frac{1}{9}的倒数最大. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/711.json b/MathMC/711.json new file mode 100644 index 0000000000000000000000000000000000000000..dedf33b27331c6fcfe63b271b15a3cecb1aa0303 --- /dev/null +++ b/MathMC/711.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "472×59" + }, + { + "bullet": "B", + "text": "472÷59" + }, + { + "bullet": "C", + "text": "59×472" + } + ], + "text": "一个数的59倍是472，求这个数的算式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "依据已知一个数的几倍是多少，求这个数用除法计算，可列式472÷59，再运用整数除法计算方法即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/712.json b/MathMC/712.json new file mode 100644 index 0000000000000000000000000000000000000000..c66b96a48676ac491ae1acaadf82aaea1a7e3cfb --- /dev/null +++ b/MathMC/712.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20平方米" + }, + { + "bullet": "B", + "text": "30平方米" + }, + { + "bullet": "C", + "text": "24米" + }, + { + "bullet": "D", + "text": "24平方米" + } + ], + "text": "长方形的长是10米、宽是2米，它的面积是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "长方形的面积S=ab，据此代入数据即可求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/713.json b/MathMC/713.json new file mode 100644 index 0000000000000000000000000000000000000000..229779d6a8982b3c56560264bc4a6188d4a81bb8 --- /dev/null +++ b/MathMC/713.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90×0的积大" + }, + { + "bullet": "B", + "text": "90+0的和大" + }, + { + "bullet": "C", + "text": "一样大" + } + ], + "text": "90×0和90+0比较，正确的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘0乘任何数都得0，任何数加0都得原数‘解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/714.json b/MathMC/714.json new file mode 100644 index 0000000000000000000000000000000000000000..339251bac21d8701a629e3f60cfe7e55be8f45b5 --- /dev/null +++ b/MathMC/714.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "(140+20)÷ \\frac{3}{8}" + }, + { + "bullet": "B", + "text": "(140-20)÷ \\frac{3}{8}" + }, + { + "bullet": "C", + "text": "140÷(1- \\frac{3}{8})+20" + } + ], + "text": "某校五年级有学生140人，比全校总人数的 \\frac{3}{8}多20人，求全校人数，列式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把全校总人数看作单位‘1‘，五年级的140人减去20人正好占全校总人数的 \\frac{3}{8}，单位‘1‘是未知的，用除法计算，数量(140-20)除以对应分率 \\frac{3}{8}." + ] + } +} \ No newline at end of file diff --git a/MathMC/715.json b/MathMC/715.json new file mode 100644 index 0000000000000000000000000000000000000000..6ac6a0c8ad705734e7cacb63a836c9e7c8e2cfac --- /dev/null +++ b/MathMC/715.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "n" + }, + { + "bullet": "B", + "text": "180-2n" + }, + { + "bullet": "C", + "text": "(180-n)÷2" + }, + { + "bullet": "D", + "text": "2n" + } + ], + "text": "一个等腰三角形底角 n°，它的顶角是( )度. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "等腰三角形的两个底角相等，根据三角形的内角和即可解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/716.json b/MathMC/716.json new file mode 100644 index 0000000000000000000000000000000000000000..099d7920a5648445317026eb1335cd678589abf6 --- /dev/null +++ b/MathMC/716.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7个鸡蛋的表面积是多少" + }, + { + "bullet": "B", + "text": "长方体容器的表面积是多少" + }, + { + "bullet": "C", + "text": "长方体容器的高是多少" + }, + { + "bullet": "D", + "text": "长方体容器的底面周长是多少" + } + ], + "text": "一个长方体容器，底面是正方形，盛水高1分米.放入7个质量一样的鸡蛋后，水面升高3厘米.要求一个鸡蛋的体积，只需再知道下面( )这一条信息. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "7个鸡蛋的体积就是上升那部分水的体积，知道了水面上升的高度，再知道长方体容器的底面积即可求解，从选项中找出可以求出底面积的条件即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/717.json b/MathMC/717.json new file mode 100644 index 0000000000000000000000000000000000000000..ce29a6f8d1f9a5af6a16be25f18c9c723b01d0a4 --- /dev/null +++ b/MathMC/717.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a^{2}" + }, + { + "bullet": "B", + "text": "a^{2}" + }, + { + "bullet": "C", + "text": "a^{2}" + } + ], + "text": "把一个棱长为a的正方体切成8个同样的小正方体，每个小正方体的表面积是…( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "观察图形可知，把一个大正方体切成8个一样大小的小正方体，则每个小正方体的棱长就是a，据此利用正方体的表面积公式即可求出每个小正方体的表面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/718.json b/MathMC/718.json new file mode 100644 index 0000000000000000000000000000000000000000..9752920f89f26cc4f707eccd46d3c5c808d73405 --- /dev/null +++ b/MathMC/718.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "27" + }, + { + "bullet": "B", + "text": "54" + }, + { + "bullet": "C", + "text": "108" + }, + { + "bullet": "D", + "text": "216" + } + ], + "text": "把一个表面积为54平方厘米的正方体切成27个同样的正方体，表面积增加了( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把一个表面积为54平方厘米的正方体切成27个同样的正方体，要沿着长宽高各切2次共6次，增加了12个面.每个面的面积是54÷6=9平方厘米，进而求出增加的面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/719.json b/MathMC/719.json new file mode 100644 index 0000000000000000000000000000000000000000..d122604b8ed08dcc754222bc8fe2534c63457647 --- /dev/null +++ b/MathMC/719.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小于" + }, + { + "bullet": "B", + "text": "大于" + }, + { + "bullet": "C", + "text": "等于" + } + ], + "text": "甲数× 1.5=乙数× 0.9，(甲、乙两数都不等于0)，那么甲数( )乙数. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "因为甲数× 1.5=乙数× 0.9，所以甲数÷ 乙数=0.9÷ 1.5， 甲数÷ 乙数=\\frac{0.9}{1.5}=\\frac{9}{15}=\\frac{3}{5}，所以甲数<{}乙数. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/72.json b/MathMC/72.json new file mode 100644 index 0000000000000000000000000000000000000000..4f664c17be79a1ad4560486633af48b19e5df482 --- /dev/null +++ b/MathMC/72.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1+\\frac{1}{a}=\\frac{2}{a}" + }, + { + "bullet": "B", + "text": "\\frac{-a-b}{a+b}=-1" + }, + { + "bullet": "C", + "text": "(1- \\frac{1}{a+1})(a+1)= \\frac{1}{a}" + }, + { + "bullet": "D", + "text": "\\frac{1}{a-b}-\\frac{1}{b-a}=0" + } + ], + "text": "下列计算正确的是 ( )" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "解:A:因为1+ \\frac{1}{a}= \\frac{a}{a}+\\frac{1}{a}= \\frac{a+1}{a}，所以A选项错误; B:因为 \\frac{-a-b}{a+b}= \\frac{-(a+b)}{a+b}=-1，所以B选项正确; C:因为(1- \\frac{1}{a+1})(a+1)=( \\frac{a+1}{a+1}-\\frac{1}{a+1})(a+1)= \\frac{a}{a+1}(a+1)=a，所以C选项错误; D因为 \\frac{1}{a-b}-\\frac{1}{b-a}=\\frac{1}{a-b}+\\frac{1}{a-b}=\\frac{2}{a-b}，所以D选项错误. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/720.json b/MathMC/720.json new file mode 100644 index 0000000000000000000000000000000000000000..884ef0df7a302876d785dcc8818a5489c1b68c89 --- /dev/null +++ b/MathMC/720.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "五(1)班有多少人" + }, + { + "bullet": "B", + "text": "全年级有多少人" + }, + { + "bullet": "C", + "text": "全年级女生有多少人" + }, + { + "bullet": "D", + "text": "五(1)班男生有多少人" + } + ], + "text": "‘五(1)班有女生24人，恰好占全年级人数的 1/9，根据这个条件，可以提出的问题是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据条件，可选择的问题是全年级有多少人?把全年级的人数看做单位‘1‘，单位‘1‘的量是未知的，此题是已知单位‘1‘的 1/9 是24人，求单位‘1‘的量，用除法计算.​ ​ ​ ​" + ] + } +} \ No newline at end of file diff --git a/MathMC/721.json b/MathMC/721.json new file mode 100644 index 0000000000000000000000000000000000000000..eb8ddffa4f4efd5910bf0e7027c078188c667495 --- /dev/null +++ b/MathMC/721.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "整数" + }, + { + "bullet": "B", + "text": "自然数" + }, + { + "bullet": "C", + "text": "质数" + }, + { + "bullet": "D", + "text": "互质" + } + ], + "text": "一个最简整数比的前项和后项一定是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "复习最简分数，再判定" + ] + } +} \ No newline at end of file diff --git a/MathMC/722.json b/MathMC/722.json new file mode 100644 index 0000000000000000000000000000000000000000..8e08b1ccba7ee6ac5664ce71294c1d7387135987 --- /dev/null +++ b/MathMC/722.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲车快" + }, + { + "bullet": "B", + "text": "乙车快" + }, + { + "bullet": "C", + "text": "一样快" + } + ], + "text": "两车从A地开往B地，甲车4小时行了全程的\\frac{1}{5}，乙车5小时行了全程的\\frac{1}{4}，两车的速度相比( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "甲车每小时走了全程的:\\frac{1}{5}÷ 4=\\frac{1}{20}. 乙车每小时走了全程的:\\frac{1}{4}÷ 5=\\frac{1}{20}. 甲=乙. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/723.json b/MathMC/723.json new file mode 100644 index 0000000000000000000000000000000000000000..61c4f0deb553d82a24b857d3d2df5ad58cdaf689 --- /dev/null +++ b/MathMC/723.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7" + }, + { + "bullet": "B", + "text": "10" + }, + { + "bullet": "C", + "text": "14" + }, + { + "bullet": "D", + "text": "15" + } + ], + "text": "将一根木棒锯成4段需要6分钟，则将这根木棒锯成7段需要( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "提示1:将一根木棒锯成4段需锯的次数是(4-1)次，需要6分钟，锯一次用的时间就是6÷(4-1)次，将这根木棒锯成7段需要锯的次数是(7-1)次，然后根据乘法的意义进行解答. 提示2:本题属于植树问题，锯的次数=段数-1是本题的关键." + ] + } +} \ No newline at end of file diff --git a/MathMC/724.json b/MathMC/724.json new file mode 100644 index 0000000000000000000000000000000000000000..4377d85c6c56cd2520cedf0ecca3c3749b515776 --- /dev/null +++ b/MathMC/724.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60" + }, + { + "bullet": "B", + "text": "40" + }, + { + "bullet": "C", + "text": "30" + } + ], + "text": "一个正方体的木料，它的底面积是10平方厘米，把它横截成4段相同的长方体，表面积增加( )平方厘米。 " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "10×6=60(平方厘米) 横截成4段相同的长方体，相当于多了6个横截面，也就是6个10平方厘米。" + ] + } +} \ No newline at end of file diff --git a/MathMC/725.json b/MathMC/725.json new file mode 100644 index 0000000000000000000000000000000000000000..eb0e10269086e12e9de0b07de6a401fbd01c801e --- /dev/null +++ b/MathMC/725.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "7" + } + ], + "text": "66和72之间有 ( )个数。" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "66和72之间的数有67、68、69、70、71，据此解答。 66和72之间的数有67、68、69、70、71共有5个。 故选: A。" + ] + } +} \ No newline at end of file diff --git a/MathMC/726.json b/MathMC/726.json new file mode 100644 index 0000000000000000000000000000000000000000..efbc83262e6bcba5e5470f0ad33b6bd4bc61f04a --- /dev/null +++ b/MathMC/726.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一定是奇数" + }, + { + "bullet": "B", + "text": "一定是偶数" + }, + { + "bullet": "C", + "text": "可能是奇数，也可能是偶数" + } + ], + "text": "两个质数的和( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由于偶数+奇数=奇数，根据质数的定义可知，质数中除了2之外的所有质数都为奇数，2加其它的任意一个质数的和都为奇数，所以，两个质数的和可能是奇数，也可能是偶数的." + ] + } +} \ No newline at end of file diff --git a/MathMC/727.json b/MathMC/727.json new file mode 100644 index 0000000000000000000000000000000000000000..d0be3f507a904805b431b00fdb4cfb2fe0b2ebc3 --- /dev/null +++ b/MathMC/727.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0~4" + }, + { + "bullet": "B", + "text": "5~9" + }, + { + "bullet": "C", + "text": "0~5" + } + ], + "text": "在36□372≈37万的□里填上的合适的数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据用四舍五入法把大数改写成用万作单位的数的方法判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/728.json b/MathMC/728.json new file mode 100644 index 0000000000000000000000000000000000000000..0f1b6393e01e9b5d8d5227252146d40393e2233b --- /dev/null +++ b/MathMC/728.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "丁的身高一定比甲高" + }, + { + "bullet": "B", + "text": "四个人的平均身高一定低于甲、乙两人的平均身高" + }, + { + "bullet": "C", + "text": "四个人的平均身高一定高于甲、乙两人的平均身高" + }, + { + "bullet": "D", + "text": "以上说法均不准确" + } + ], + "text": "有甲、乙、丙、丁四名同学，甲、乙两人的平均身高是120厘米，丙、乙两人的平均身高是126厘米.下面说法正确的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "由甲、乙两人的平均身高是120厘米，丙、乙两人的平均身高是126厘米，根据平均数的含义只能得到丙和甲两人的身高差，不能确定他们的身高，依此即可作出选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/729.json b/MathMC/729.json new file mode 100644 index 0000000000000000000000000000000000000000..07ac2bd59deafc91d170fae6d8d0d0c834fe9cfa --- /dev/null +++ b/MathMC/729.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "一个数的因数只有两个，这个数最小是 ( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "A选项中，1=1×1，1的因数只有1，不满足条件; B选项中，2=1×2，2的因数有1和2，满足条件; C选项中，3=1×3，3的因数有1和3，因为2<3，所以选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/73.json b/MathMC/73.json new file mode 100644 index 0000000000000000000000000000000000000000..88f016765e681b4dc8abb9bd75d7e81b5bbe95e0 --- /dev/null +++ b/MathMC/73.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "45" + }, + { + "bullet": "B", + "text": "180" + }, + { + "bullet": "C", + "text": "225" + } + ], + "text": "甲、乙、丙三人共同加工了540个零件，已知他们加工零件个数的比是3:4:5，乙加工了()个零件。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "设甲加工了3x个零件，乙加工了4x个零件，丙加工了5x个零件，根据题目中的关系，3x+4x+5x=540, 可得x=45，乙加工了4x=180个零件，选B" + ] + } +} \ No newline at end of file diff --git a/MathMC/730.json b/MathMC/730.json new file mode 100644 index 0000000000000000000000000000000000000000..928a30529c3f066a50ba6961a5bf6b7b0363b10a --- /dev/null +++ b/MathMC/730.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "在含盐30%的盐水中，加入6克盐和14克水，这时的盐水的含盐率( )30% " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "现在盐水的含盐率与原来盐水的含盐率比较大小，只要求出加入盐水的含盐率，与原来盐水的含盐率进行比较，即可得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/731.json b/MathMC/731.json new file mode 100644 index 0000000000000000000000000000000000000000..70a729bf476645d92443b11649557a6369b40296 --- /dev/null +++ b/MathMC/731.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一块地面积大" + }, + { + "bullet": "B", + "text": "第二块地面积大" + }, + { + "bullet": "C", + "text": "两块地面积同样大" + } + ], + "text": "有两块长方形的地，第一块地的面积是9公顷，第二块地的长是150米，宽是60米.这两块地的面积相比较，结果是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "第二块地的面积为150× 60=9000(平方米)，9000平方米=0.9公顷，0.9公顷<{}9公顷，故第一块地面积大. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/732.json b/MathMC/732.json new file mode 100644 index 0000000000000000000000000000000000000000..d99b429846c18ac9b8a751233b3b72e7a2b7a259 --- /dev/null +++ b/MathMC/732.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "480米/分" + }, + { + "bullet": "B", + "text": "160米/分" + }, + { + "bullet": "C", + "text": "160米/时" + } + ], + "text": "小兵3分钟跑了480米，他的速度是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "小兵3分钟跑了480米，可用480÷3算出小兵每分钟跑了多少米，再对比3个选项进行判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/733.json b/MathMC/733.json new file mode 100644 index 0000000000000000000000000000000000000000..984468fadcfbbbae0b3a65cbb001680c4c5fc52c --- /dev/null +++ b/MathMC/733.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5个" + }, + { + "bullet": "B", + "text": "6个" + }, + { + "bullet": "C", + "text": "7个" + } + ], + "text": "从76到82之间有几个数。( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "76、 77、 78、 79、 80、 81、 82，从76到82之间有5个数。 故选: A 76、 77、 78、 79、 80、 81、 82，从76到82之间有5个数，即可解答。" + ] + } +} \ No newline at end of file diff --git a/MathMC/734.json b/MathMC/734.json new file mode 100644 index 0000000000000000000000000000000000000000..8456d890838e5b06cc6fe8d624483ba1432abddb --- /dev/null +++ b/MathMC/734.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20-5x=10" + }, + { + "bullet": "B", + "text": "(20+10)÷5" + }, + { + "bullet": "C", + "text": "5x-10=20" + } + ], + "text": "20比x的5倍少10，列方程是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，x的5倍是5x，20比x的5倍少10，即5x-20=10，然后再根据等式的性质进行解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/735.json b/MathMC/735.json new file mode 100644 index 0000000000000000000000000000000000000000..1c9ccf0d6b049aedece12e5cb1de2a3772c2571b --- /dev/null +++ b/MathMC/735.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "899" + }, + { + "bullet": "B", + "text": "987" + }, + { + "bullet": "C", + "text": "1002" + } + ], + "text": "下面各数中，最接近1000的数是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "1000-899=101 1000-987=13 1002-1000=2 下面各数中，最接近1000的数是1002." + ] + } +} \ No newline at end of file diff --git a/MathMC/736.json b/MathMC/736.json new file mode 100644 index 0000000000000000000000000000000000000000..7b6900e4bdbed6f7bb9919a355caa77037a2a3f4 --- /dev/null +++ b/MathMC/736.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比原来小" + }, + { + "bullet": "B", + "text": "比原来大" + }, + { + "bullet": "C", + "text": "一样大" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "把一个长方体切成两块，切割后的体积之和与原来的体积比较( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意可知:一个长方体切成两个大小相等的正方体后，分成的两个正方体所占据空间的大小和就等于原来长方体的体积，所以体积不变，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/737.json b/MathMC/737.json new file mode 100644 index 0000000000000000000000000000000000000000..59c3d5d924f53dc7a9777b7c658ef7bcb60c7f33 --- /dev/null +++ b/MathMC/737.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "27" + }, + { + "bullet": "B", + "text": "9" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "3" + } + ], + "text": "大小两种正方体积木，大积木棱长9厘米，小积木棱长3厘米.如果要用小积木拼成大积木，需要用( )个小积木. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "9÷ 3=3(个)，3× 3× 3=27(个). 故选A. 大积木的棱长是小积木棱长的3倍，那么大正方体的体积就是小正方体体积的27倍，所以需要用27个小积木." + ] + } +} \ No newline at end of file diff --git a/MathMC/738.json b/MathMC/738.json new file mode 100644 index 0000000000000000000000000000000000000000..a8aa59621571feddb807efb32f9dd0a23b20a457 --- /dev/null +++ b/MathMC/738.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "复式条形统计图" + }, + { + "bullet": "B", + "text": "统计表" + }, + { + "bullet": "C", + "text": "复式折线统计图" + } + ], + "text": "要表示近5年城市和乡镇人均居住面积的变化情况，应绘制( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/739.json b/MathMC/739.json new file mode 100644 index 0000000000000000000000000000000000000000..ddf4526de3e6785dfb9783ecd75ab8d02dfd78cb --- /dev/null +++ b/MathMC/739.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8平方厘米" + }, + { + "bullet": "B", + "text": "8厘米" + }, + { + "bullet": "C", + "text": "12平方厘米" + } + ], + "text": "用8个边长是1厘米的小正方形拼成一个长方形，这个长方形的面积是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "用8个边长是1厘米的小正方形拼成一个长方，拼成后长方形的面积等于8个小正方形的面积，根据正方形的面积=边长×边长求出一个正方形的面积，再乘8即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/74.json b/MathMC/74.json new file mode 100644 index 0000000000000000000000000000000000000000..3c0452ea4c304715d604a739ac36397efcb68c49 --- /dev/null +++ b/MathMC/74.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东" + }, + { + "bullet": "B", + "text": "南" + }, + { + "bullet": "C", + "text": "西" + }, + { + "bullet": "D", + "text": "北" + } + ], + "text": "指南针是我国的四大发明之一，不管把罗盘怎样转动，静止后，指针总是一头指向北方，另一头指向( )方. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据指南针的特性进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/740.json b/MathMC/740.json new file mode 100644 index 0000000000000000000000000000000000000000..614fdfcac723cbfa2b2bc963e552af787485f069 --- /dev/null +++ b/MathMC/740.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "185÷4" + }, + { + "bullet": "B", + "text": "113÷3" + }, + { + "bullet": "C", + "text": "279÷6" + }, + { + "bullet": "D", + "text": "87÷2" + } + ], + "text": "下列算式，结果小于40的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先计算出结果，然后与40比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/741.json b/MathMC/741.json new file mode 100644 index 0000000000000000000000000000000000000000..c79057348aec723441736c9048d75d5dac9f77ec --- /dev/null +++ b/MathMC/741.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "既是质数，又是奇数的最小的数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题根据判断一个数是质数或是合数的方法进行解答即可，当一个数只有1和它本身两个因数的数叫做质数，一个数除以1和它本身两个因数还有别的因数的数叫做合数，所以10以内的质数有2、3、5、7." + ] + } +} \ No newline at end of file diff --git a/MathMC/742.json b/MathMC/742.json new file mode 100644 index 0000000000000000000000000000000000000000..736068fe72ec9fcd17089aa91b23c11b6b5c51e2 --- /dev/null +++ b/MathMC/742.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{5}+ \\frac{1}{5}" + }, + { + "bullet": "B", + "text": "\\frac{7}{8}- \\frac{5}{8}" + }, + { + "bullet": "C", + "text": "\\frac{1}{10}- \\frac{1}{20}" + }, + { + "bullet": "D", + "text": "\\frac{5}{14}+ \\frac{7}{42}" + } + ], + "text": "下面各式的计算结果最接近 \\frac{1}{2}的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "先算出选项中的运算结果，然后把这些结果与 \\frac{1}{2}求差，谁的差最小谁就最接近 \\frac{1}{2}." + ] + } +} \ No newline at end of file diff --git a/MathMC/743.json b/MathMC/743.json new file mode 100644 index 0000000000000000000000000000000000000000..4a582aed1645467d46025bc0eda52cd738d21df4 --- /dev/null +++ b/MathMC/743.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一定是1个零" + }, + { + "bullet": "B", + "text": "可能1个零，不可能是2个零" + }, + { + "bullet": "C", + "text": "可能1个零，也可能是2个零，还可能是3个零" + } + ], + "text": "两个因数的末尾共有1个零，那么积的末尾( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因数末尾有0的乘法的计算方法:先把0前面的数相乘，再看积的末尾一共有几个0，就在积的末尾添写几个0;两个因数的末尾共有1个零，那么积的末尾至少有一个0;据此选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/744.json b/MathMC/744.json new file mode 100644 index 0000000000000000000000000000000000000000..e457c28be5ecccfb859336543b964a2496355d3a --- /dev/null +++ b/MathMC/744.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "南偏西30{}^{\\}circ 方向上" + }, + { + "bullet": "B", + "text": "北偏东30{}^{\\}circ 方向上" + }, + { + "bullet": "C", + "text": "西偏南30{}^{\\}circ 方向上" + }, + { + "bullet": "D", + "text": "西偏南60{}^{\\}circ 方向上" + } + ], + "text": "以小猴家为观测点，小松鼠家在东偏北30{}^{\\}circ 方向上;以小松鼠家为观测点，小猴家在( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据位置的相对性可知，他们的方向相反，角度不变，其中北对南、西对东、东南对西北、东北对西南，所以小松鼠家在东偏北30{}^{\\}circ 方向上即小猴家则在方向相反的西偏南位置30{}^{\\}circ 上. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/745.json b/MathMC/745.json new file mode 100644 index 0000000000000000000000000000000000000000..43159f773274b405b1906a18c751a76cfc45b805 --- /dev/null +++ b/MathMC/745.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "长方形面积一定大于正方形面积" + }, + { + "bullet": "B", + "text": "正方形面积一定大于长方形面积" + }, + { + "bullet": "C", + "text": "不能肯定" + } + ], + "text": "周长相等的长方形和正方形，它们的面积大小是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "假设这个正方形和长方形的周长都是10厘米，先依据周长分别确定出正方形的边长和长方形的长和宽，进而求出其面积，再进行比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/746.json b/MathMC/746.json new file mode 100644 index 0000000000000000000000000000000000000000..d38d72518069896e0fa3a63c1e43ab9c4954239f --- /dev/null +++ b/MathMC/746.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4:3" + }, + { + "bullet": "B", + "text": "3:4" + }, + { + "bullet": "C", + "text": "无法比较" + } + ], + "text": "选择题(把正确答案的序号填在括号里) 1.从A地到B地，甲车要行40分钟，乙车要行30分钟，甲、乙两车的速度比是 . " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把从A地到B地的距离看作单位‘1‘，则甲每小时行全程的\\frac{1}{40} ，乙每小时行全程的\\frac{1}{30} ，则甲、乙两车的速度比是\\frac{1}{40} :\\frac{1}{30} ，化简即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/747.json b/MathMC/747.json new file mode 100644 index 0000000000000000000000000000000000000000..580aa66e2026ce47866fc5cfa31a2d75de7d456e --- /dev/null +++ b/MathMC/747.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形统计图" + }, + { + "bullet": "B", + "text": "折线统计图" + }, + { + "bullet": "C", + "text": "扇形统计图" + } + ], + "text": "要统计深圳市今年3月份的气温变化情况，选用( )比较合适. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "气温变化，则有升高降低情况，折线统计图比较合适. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/748.json b/MathMC/748.json new file mode 100644 index 0000000000000000000000000000000000000000..28eb98d37f20cb211c7f7ff846aaf60a88c55ed0 --- /dev/null +++ b/MathMC/748.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "4" + } + ], + "text": "有13个乒乓球，其中12个质量相同，另一个较轻一点，如果用天平称，至少( )次保证能找出这个乒乓球. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "第一次称重6个和6个，较低的那边有轻乒乓球，第二次3个和3个，较低的那边有轻乒乓球，第三次称重1个和1个，较低的是轻乒乓球，平衡则剩余的是轻乒乓球.需要三次." + ] + } +} \ No newline at end of file diff --git a/MathMC/749.json b/MathMC/749.json new file mode 100644 index 0000000000000000000000000000000000000000..40549d765be4424b065c39896b175ac7cc1a5453 --- /dev/null +++ b/MathMC/749.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "要使32□×6的积的末尾是0，□里不可以填( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "此题的题干算式为32□×6，求该算式的积的方法是用6逐一从被乘数的低位向高位乘起，即首先用6×□，6×□的积的得数的末尾即是该算式积的末尾.根据题干的要求，是该算式积的末尾是0，故□中不能填4，应该选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/75.json b/MathMC/75.json new file mode 100644 index 0000000000000000000000000000000000000000..05e51e38bbc33ad2c508c5afee2e8e94cb6474a4 --- /dev/null +++ b/MathMC/75.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + } + ], + "text": "在一个梯形中，最多有( )个角是直角. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为梯形的上底和下底平行，所以当为直角梯形时，最多有2个角是直角." + ] + } +} \ No newline at end of file diff --git a/MathMC/750.json b/MathMC/750.json new file mode 100644 index 0000000000000000000000000000000000000000..67e651eaac059bdbd748e382068eff3ab10d5338 --- /dev/null +++ b/MathMC/750.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形统计图" + }, + { + "bullet": "B", + "text": "扇形统计图" + }, + { + "bullet": "C", + "text": "折线统计图" + } + ], + "text": "既能表示数量的多少，又能表示数量增减变化的统计图是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/751.json b/MathMC/751.json new file mode 100644 index 0000000000000000000000000000000000000000..063f355541d56dd2f9496fb9a4eeaf0b4a06389c --- /dev/null +++ b/MathMC/751.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "22" + }, + { + "bullet": "B", + "text": "30" + }, + { + "bullet": "C", + "text": "11" + } + ], + "text": "小明有38张邮票，送给小华8张后，两人的邮票同样多，小华原有( )张邮票. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "38-8-8=22(张) 即小华原有22张. 故选:A. 小明有38张邮票，送给小华8张后，两人的邮票同样多，则此时两人都有38-8张，又小华比原来多了8张，所以原来小华有38-8-8张." + ] + } +} \ No newline at end of file diff --git a/MathMC/752.json b/MathMC/752.json new file mode 100644 index 0000000000000000000000000000000000000000..8d519597eda0ef08011ef97256a2da4fc2660058 --- /dev/null +++ b/MathMC/752.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "缩小到原来的\\frac{1}{10}" + }, + { + "bullet": "B", + "text": "缩小到原来的\\frac{1}{100}" + }, + { + "bullet": "C", + "text": "扩大到原来的100倍" + }, + { + "bullet": "D", + "text": "不变" + } + ], + "text": "若给10的后面添上‘%‘，10就( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "给10的后面添上‘%‘，10就缩小到原来的\\frac{1}{100}; 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/753.json b/MathMC/753.json new file mode 100644 index 0000000000000000000000000000000000000000..15217348a7200fd0476a9e807a030b480eac79b9 --- /dev/null +++ b/MathMC/753.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3:5" + }, + { + "bullet": "B", + "text": "5:2" + }, + { + "bullet": "C", + "text": "5:3" + }, + { + "bullet": "D", + "text": "3:2" + } + ], + "text": "从甲盐库取出 1 / 5 的盐运到乙盐库，这时两个盐库所存的盐的质量相等，原来甲盐库和乙盐库的存盐质量比是 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由题意知，可把甲盐库的存盐量看作单位‘1‘，是5份，拿出1份给乙后两个盐库所存的盐的质量相等，那么就说明甲原来比乙多2份，即乙原有3份，据此可列比解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/754.json b/MathMC/754.json new file mode 100644 index 0000000000000000000000000000000000000000..b3f16b0b3bf093a65d7725d6bae4c2ee41c6b8de --- /dev/null +++ b/MathMC/754.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2时" + }, + { + "bullet": "B", + "text": "2时10分" + }, + { + "bullet": "C", + "text": "2时2分" + } + ], + "text": "电影2:30开演，同学们从学校到电影院要走20分，进场需要8分钟，同学们最晚应该( )从学校出发. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，首先计算从路上用时和进场用时共需多少时间(经过时间)，然后由电影开始时刻-经过的时间即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/755.json b/MathMC/755.json new file mode 100644 index 0000000000000000000000000000000000000000..2ceeb8cc6f8f5ab0c67302dd55d15ee6dff6e0b0 --- /dev/null +++ b/MathMC/755.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "1000" + } + ], + "text": "我们学过的每相邻两个质量单位之间的进率是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "常用的质量单位有吨、千克、克，每相邻的两个单位之间的进率是1000. 故选:C. 我们学过的质量单位有吨、千克、克，1吨=1000千克;1千克=1000克，所以每相邻两个质量单位之间的进率都是1000;据此解答即可.此题主要考查常见的质量单位和每相邻的两个质量单位间的进率是1000." + ] + } +} \ No newline at end of file diff --git a/MathMC/756.json b/MathMC/756.json new file mode 100644 index 0000000000000000000000000000000000000000..a40ddfc11505ec4ad20eb6fc48403283beb32283 --- /dev/null +++ b/MathMC/756.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0.909" + }, + { + "bullet": "B", + "text": "0.̇{9}" + }, + { + "bullet": "C", + "text": "0.̇{9}̇{0}" + }, + { + "bullet": "D", + "text": "0.9̇{0}̇{9}" + } + ], + "text": "计算4÷ 4.4，根据右面笔算过程，结果正确且最简洁的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "从竖式可看出100÷ 11=0.909090··· ··· 可知商的最简洁写法为0.̇{9}̇{0}. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/757.json b/MathMC/757.json new file mode 100644 index 0000000000000000000000000000000000000000..9f786fed4a67539a82f4a6b61013474188c805e8 --- /dev/null +++ b/MathMC/757.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "任何数" + }, + { + "bullet": "B", + "text": "除数" + }, + { + "bullet": "C", + "text": "除数的倒数" + } + ], + "text": "1除以任何数(零除外)商等于( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据分数除法的计算法则解答即可，除以一个数(0除外)等于乘除数的倒数." + ] + } +} \ No newline at end of file diff --git a/MathMC/758.json b/MathMC/758.json new file mode 100644 index 0000000000000000000000000000000000000000..917804a5aec65707bc12e01a8935c94b029bca8c --- /dev/null +++ b/MathMC/758.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:170" + }, + { + "bullet": "B", + "text": "170:1" + }, + { + "bullet": "C", + "text": "17:10" + } + ], + "text": "小强身高1米，爸爸身高170厘米，爸爸和小强身高比是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "要求爸爸和小强身高的比，先把单位化统一后，进而写比并化简比即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/759.json b/MathMC/759.json new file mode 100644 index 0000000000000000000000000000000000000000..c1ae8442b190c9c7c9b898662e2ab1faea128e8d --- /dev/null +++ b/MathMC/759.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "130+x" + }, + { + "bullet": "B", + "text": "130-3x" + }, + { + "bullet": "C", + "text": "130-x" + } + ], + "text": "小明的身高是130厘米，他比小红高x厘米，小红的身高是( )厘米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题干，小明的身高是130厘米，他比小红高x厘米，则用小明的身高减去x厘米，就是小红的身高." + ] + } +} \ No newline at end of file diff --git a/MathMC/76.json b/MathMC/76.json new file mode 100644 index 0000000000000000000000000000000000000000..6f8bbde976886025befb7219f68fa643ac3b0abb --- /dev/null +++ b/MathMC/76.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{9}+ \\frac{4}{9}+ \\frac{4}{9}" + }, + { + "bullet": "B", + "text": "\\frac{4}{9}×2+ \\frac{4}{9}" + }, + { + "bullet": "C", + "text": "( \\frac{1}{3}+ \\frac{4}{9})×3" + }, + { + "bullet": "D", + "text": "\\frac{1}{3}×4" + } + ], + "text": "下面算式中，( )与 \\frac{4}{9}×3的结果不相同. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意，先求出 \\frac{4}{9}×3的结果，然后再求出各个选项中的结果，再进行选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/760.json b/MathMC/760.json new file mode 100644 index 0000000000000000000000000000000000000000..3a90295b9445ce82592241e4e3ed4f300062855a --- /dev/null +++ b/MathMC/760.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于乙数" + }, + { + "bullet": "B", + "text": "小于乙数" + }, + { + "bullet": "C", + "text": "等于乙数" + }, + { + "bullet": "D", + "text": "等于0.86" + } + ], + "text": "甲、乙两数都是不为0的自然数，如果甲数÷0.86=乙数，那么甲数一定( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "我们运用乙数表示出甲数，然后再和乙数进行比较即可，然后再进行选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/761.json b/MathMC/761.json new file mode 100644 index 0000000000000000000000000000000000000000..ab9dd3998099d88bce7a482219e9c440de6fcddd --- /dev/null +++ b/MathMC/761.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "钟摆的运动" + }, + { + "bullet": "B", + "text": "大风车的转动" + }, + { + "bullet": "C", + "text": "方向盘的转动" + }, + { + "bullet": "D", + "text": "电梯的升降运动" + } + ], + "text": "下列现象中，不属于旋转变换的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "物体的旋转有两个特点:有一个旋转中心;物体的现状不变.逐个分析是否具备这两个条件，即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/762.json b/MathMC/762.json new file mode 100644 index 0000000000000000000000000000000000000000..5f4e27c6013ec6f3dc8866b1b283f9e8b9901f3c --- /dev/null +++ b/MathMC/762.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "25" + }, + { + "bullet": "B", + "text": "27" + }, + { + "bullet": "C", + "text": "28" + }, + { + "bullet": "D", + "text": "30" + } + ], + "text": "一组数据从小到大排列是:10，15， □，48，50，当 □= ( )时，这组数的平均数是30。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘总数=平均数×个数‘，可知: 这组数的总数为:30×5=150， 所以 □为:150-10-15-48-50=27。 故答案为:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/763.json b/MathMC/763.json new file mode 100644 index 0000000000000000000000000000000000000000..4a6dc56415cacec34b98d6157576d4f0bce95e0c --- /dev/null +++ b/MathMC/763.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "30÷25%" + }, + { + "bullet": "B", + "text": "30÷(1-25%)" + }, + { + "bullet": "C", + "text": "30×25%" + }, + { + "bullet": "D", + "text": "30×(1+25%)" + } + ], + "text": "六一班有男生30人，比女生少25%，求女生人数正确的列式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，把女生人数看作单位‘1‘，则男生人数相当于女生的(1-75%)，也就是30人是女生人数的(1-75%)，求女生人数，用除法计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/764.json b/MathMC/764.json new file mode 100644 index 0000000000000000000000000000000000000000..382589a252a0d3f83b53313cbea6963eb8e050d4 --- /dev/null +++ b/MathMC/764.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "× 10" + }, + { + "bullet": "B", + "text": "× 100" + }, + { + "bullet": "C", + "text": "÷ 10" + }, + { + "bullet": "D", + "text": "÷ 100" + } + ], + "text": "笑笑把1000÷ (□ × 10)算成了1000÷ □ × 10，她想得到正确结果，需要再( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "原式:100÷ (□ × 10)=100÷ □ ÷ 10=10÷ □ ， 算成:1000÷ □ × 10=100÷ □ ， 为还原应÷ 100. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/765.json b/MathMC/765.json new file mode 100644 index 0000000000000000000000000000000000000000..7d7cea5ccfc7743f314cb561d0931822292303e0 --- /dev/null +++ b/MathMC/765.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4千米/小时" + }, + { + "bullet": "B", + "text": "3.75千米/小时" + }, + { + "bullet": "C", + "text": "3.5千米小/时" + }, + { + "bullet": "D", + "text": "4.2千米小时" + } + ], + "text": "小明从山下走到山顶的速度是3千米/小时，从山顶返回山下的速度是5千米/小时，那么小明从山下到山顶往返的平均速度是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把从山下到山顶的路程看作单位‘1‘，根据‘路程÷速度=时间‘可得:从山下到山顶所用时间为，从山顶返回山下的时间为，根据‘往返路程÷往返总时间=平均速度‘进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/766.json b/MathMC/766.json new file mode 100644 index 0000000000000000000000000000000000000000..e02d2c6149747df0ce184121c5968313879ccde2 --- /dev/null +++ b/MathMC/766.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "99 999和100 001" + }, + { + "bullet": "B", + "text": "9万和11万" + }, + { + "bullet": "C", + "text": "90 009和10 001" + } + ], + "text": "和10万相邻的两个数是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "求与一个数相邻的数，就是求它前面的一个数和后面的一个数，采用减1、加1的方法即可求得." + ] + } +} \ No newline at end of file diff --git a/MathMC/767.json b/MathMC/767.json new file mode 100644 index 0000000000000000000000000000000000000000..3926def82edc3e5e406cc9227cace20642f0ff8c --- /dev/null +++ b/MathMC/767.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一定是3的倍数" + }, + { + "bullet": "B", + "text": "一定是2的倍数" + }, + { + "bullet": "C", + "text": "一定是5的倍数" + } + ], + "text": "用9、0、6三个数排成三位数，( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "2的倍数的特征是:个位上的数字是0、2、4、6、8的数;3的倍数的特征是:各个数位上的数字的和是3的倍数， 9+0+6=15，15是3的倍数，所以本题选A;" + ] + } +} \ No newline at end of file diff --git a/MathMC/768.json b/MathMC/768.json new file mode 100644 index 0000000000000000000000000000000000000000..7ad6ec3502f33afd362121fa4647b5da98aff110 --- /dev/null +++ b/MathMC/768.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "体积" + }, + { + "bullet": "B", + "text": "表面积" + }, + { + "bullet": "C", + "text": "长度" + } + ], + "text": "将一个正方体铸成一个长方体(没有损耗)，( )不变. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据体积的意义，物体所占空间的大小叫做物体的体积.把正方体熔铸成长方体只是形状变了，但体积不变.据此判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/769.json b/MathMC/769.json new file mode 100644 index 0000000000000000000000000000000000000000..0b953c2838e211a9a54704827f4fae9fa9e66d71 --- /dev/null +++ b/MathMC/769.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "160平方厘米" + }, + { + "bullet": "B", + "text": "100平方厘米" + }, + { + "bullet": "C", + "text": "1600平方厘米" + } + ], + "text": "把一根长40厘米的铁丝围成一个正方形，这个正方形的面积是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "40厘米是正方形的周长，40÷ 4=10(厘米)， 面积:10× 10=100(平方厘米). 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/77.json b/MathMC/77.json new file mode 100644 index 0000000000000000000000000000000000000000..14585258374c752da7c948407ae745d51cef6ae7 --- /dev/null +++ b/MathMC/77.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "无法判断" + }, + { + "bullet": "B", + "text": "错误" + }, + { + "bullet": "C", + "text": "正确" + } + ], + "text": "两个素数的积一定是合数. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "首先我们来看看这道题目，根据题中提供的信息可以得知，本题考查的是同学们是否熟练掌握了判断一个数是质数或合数的知识点.在这道题中我们要特别注意素数即为质数，然后同学们举例判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/770.json b/MathMC/770.json new file mode 100644 index 0000000000000000000000000000000000000000..cd8025feb5e94ec1288d39df178d988f11da3d4f --- /dev/null +++ b/MathMC/770.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12厘米" + }, + { + "bullet": "B", + "text": "9厘米" + }, + { + "bullet": "C", + "text": "6厘米" + }, + { + "bullet": "D", + "text": "3厘米" + } + ], + "text": "一个长方体的棱长之和是36厘米，它的长、宽、高的和是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据长方体的特征:6个面都是长方形(特殊情况有两个相对的面是正方形)，相对的面的面积相等，12条棱分为互相平行的3组，每组4条棱的长度相等. 36÷ 4=9(厘米). 答:它的长、宽、高的和是9厘米. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/771.json b/MathMC/771.json new file mode 100644 index 0000000000000000000000000000000000000000..0ca0393cc819811944394f586af92348cf2b3bff --- /dev/null +++ b/MathMC/771.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20" + }, + { + "bullet": "B", + "text": "1000" + }, + { + "bullet": "C", + "text": "1020" + }, + { + "bullet": "D", + "text": "500" + } + ], + "text": "要配制一种药液和水的质量之比是1:50的药水，现有药液20克，应加水( )克. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题意可知，配成的这种药水中药液占\\frac{1}{1+50}，药液的质量已知，把配成的这种药水的质量看作单位‘1‘，根据分数除法的意义，用药液的质量除以\\frac{1}{1+50}就是配成的这种药水的质量，用药水的质量减药液的质量就是水的质量. 20÷ \\frac{1}{1+50} =20÷ \\frac{1}{51} =1020(克) 1020-20=1000(克) 答:应加水1000克. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/772.json b/MathMC/772.json new file mode 100644 index 0000000000000000000000000000000000000000..e93b470ed5d2c001eb559e50900bb93ecf64d12b --- /dev/null +++ b/MathMC/772.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比1平方米小" + }, + { + "bullet": "B", + "text": "正好1平方米" + }, + { + "bullet": "C", + "text": "比1平方米大" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "两块面积相等的花布和白布，把花布减去\\frac{4}{5}，白布减去\\frac{4}{5}平方米，剩下的花布比白布少.原来这两块布料的面积( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "设面积分别为1.2{{m}^{2}}、1{{m}^{2}}、0.9{{m}^{2}}时，代入计算可得C符合题意;或设面积为x{{m}^{2}}，依题意有\\frac{4}{5}x>\\frac{4}{5}，解得x>1.所以正确答案是C." + ] + } +} \ No newline at end of file diff --git a/MathMC/773.json b/MathMC/773.json new file mode 100644 index 0000000000000000000000000000000000000000..27269764a2118f2b73e7bd6c787d9a2108581702 --- /dev/null +++ b/MathMC/773.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "M=0" + }, + { + "bullet": "B", + "text": "N=0" + }, + { + "bullet": "C", + "text": "M，N中至少有一个是0" + } + ], + "text": "如果M×N=0，那么( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由于0表示没有，0乘任何数都等于0，则如果M×N=0，那么M，N中至少有一个是0." + ] + } +} \ No newline at end of file diff --git a/MathMC/774.json b/MathMC/774.json new file mode 100644 index 0000000000000000000000000000000000000000..38f36f1810ecf60eebd3b92861cb7ed64a8c053f --- /dev/null +++ b/MathMC/774.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "东方" + }, + { + "bullet": "B", + "text": "西方" + }, + { + "bullet": "C", + "text": "北方" + } + ], + "text": "大树的影子在东方，此时太阳应该在( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为大树的影子在东方，所以太阳是从大树的西方照过来的. 故答案选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/775.json b/MathMC/775.json new file mode 100644 index 0000000000000000000000000000000000000000..1edeca89efee3102c6c81ed0b1ad132cba82fcba --- /dev/null +++ b/MathMC/775.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{100}{48}" + }, + { + "bullet": "B", + "text": "\\frac{48}{100}" + }, + { + "bullet": "C", + "text": "\\frac{1}{100}" + }, + { + "bullet": "D", + "text": "\\frac{1}{48}" + } + ], + "text": "用100千克花生可以榨油48千克，平均1千克花生可以榨油( )千克. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题干可知用100千克花生可以榨油48千克，那么平均1千克花生可以榨油:48÷ 100=\\frac{48}{100}. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/776.json b/MathMC/776.json new file mode 100644 index 0000000000000000000000000000000000000000..546b7c716f2efe06b807c8fb07e1ff12e2d642df --- /dev/null +++ b/MathMC/776.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "249988" + }, + { + "bullet": "B", + "text": "250020" + }, + { + "bullet": "C", + "text": "249990" + }, + { + "bullet": "D", + "text": "250100" + } + ], + "text": "下面四个数‘四舍五入‘后得到25万，其中( )最接近25万. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "计算出各选项中的准确数与近似数25万相差多少，进而选出最接近25万的数即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/777.json b/MathMC/777.json new file mode 100644 index 0000000000000000000000000000000000000000..fdf853dd98311a308e1ae4c38b61178f1379e280 --- /dev/null +++ b/MathMC/777.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2:3" + }, + { + "bullet": "B", + "text": "3:2" + }, + { + "bullet": "C", + "text": "4:9" + } + ], + "text": "两个圆的半径之比是2:3，那么这两个圆的面积比为( )。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "设小圆的半径为2r，则大圆的半径为3r，分别代入圆的面积公式，表示出各自的面积，即可求解。" + ] + } +} \ No newline at end of file diff --git a/MathMC/778.json b/MathMC/778.json new file mode 100644 index 0000000000000000000000000000000000000000..711e37d46248e18befeb89dfe02bc70966709cdd --- /dev/null +++ b/MathMC/778.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8005" + }, + { + "bullet": "B", + "text": "9000" + }, + { + "bullet": "C", + "text": "7998" + }, + { + "bullet": "D", + "text": "8001" + } + ], + "text": "下面四个数中，哪个数最接近8000?( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "8005-8000=5 ;9000-8000=1000 ; 8000-7998=2 ;8001-8000=1; 1<2<5<1000， 所以离8000最近的是8001，故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/779.json b/MathMC/779.json new file mode 100644 index 0000000000000000000000000000000000000000..4eda51d76e30ea905223e6635c6ab5e7c053419b --- /dev/null +++ b/MathMC/779.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "加法交换律" + }, + { + "bullet": "B", + "text": "加法结合律" + }, + { + "bullet": "C", + "text": "加法交换律和结合律" + } + ], + "text": "487+145+113=145+(487+113)，在计算过程中运用了( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "487+145+113=145+(487+113)，先把487与145的位置进行交换，再把487与113结合，所以运用加法交换律和结合律，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/78.json b/MathMC/78.json new file mode 100644 index 0000000000000000000000000000000000000000..aad6fe9e01c1ec59cefd571834e78cfafbe4899a --- /dev/null +++ b/MathMC/78.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一根长" + }, + { + "bullet": "B", + "text": "第二根长" + }, + { + "bullet": "C", + "text": "无法比较" + } + ], + "text": "有两根铁丝，第一根用去它的，第二根用去m，剩下的部分( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分数不带单位，表示总数的几分之几，分数带单位表示具体的量.从这两根根铁丝大于1米、等于1米、小于1米三种情况分析求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/780.json b/MathMC/780.json new file mode 100644 index 0000000000000000000000000000000000000000..b0b7c302be06e618296154730ab80ddbc8acc34a --- /dev/null +++ b/MathMC/780.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80× \\frac{2}{5}" + }, + { + "bullet": "B", + "text": "80×(1- \\frac{2}{5})" + }, + { + "bullet": "C", + "text": "80-80× \\frac{2}{5}" + } + ], + "text": "手工小组的同学做了80面小红旗，女生做了总数的 \\frac{2}{5}.男生做了多少面?列式不正确的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由题意可知，把80面小旗看作单位‘1‘，女生做了总数的 \\frac{2}{5}.男生做了总共的(1- \\frac{2}{5})，用乘法进行解答，也可以用总共的面数减去女生做的数量即可得到男生做的数量，即80-80× \\frac{2}{5}." + ] + } +} \ No newline at end of file diff --git a/MathMC/781.json b/MathMC/781.json new file mode 100644 index 0000000000000000000000000000000000000000..0ad194ae9abdc95db9f05603aa68c4a9e60ba5e8 --- /dev/null +++ b/MathMC/781.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9万和11万" + }, + { + "bullet": "B", + "text": "90009和100001" + }, + { + "bullet": "C", + "text": "99999和100001" + } + ], + "text": "与10万相邻的两个自然数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据自然数的排列规律，相邻的自然数相差1，27相邻的自然数是100000+1=100001，100000-1=99999." + ] + } +} \ No newline at end of file diff --git a/MathMC/782.json b/MathMC/782.json new file mode 100644 index 0000000000000000000000000000000000000000..236fa5668e0a733eed1a1ca5b5d71a985f34481d --- /dev/null +++ b/MathMC/782.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "不变" + }, + { + "bullet": "B", + "text": "提高了" + }, + { + "bullet": "C", + "text": "降低了" + } + ], + "text": "一件商品先提价20%，再降价20%，售价（ ）" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "设原价为X，提价20%后为1.2X，再降价20%，则为1.2X * (1-20%)=0.96X，0.96X相比于原价X，售价降低了" + ] + } +} \ No newline at end of file diff --git a/MathMC/783.json b/MathMC/783.json new file mode 100644 index 0000000000000000000000000000000000000000..fffff2cba53c4eaa204766608844d508c6a162cf --- /dev/null +++ b/MathMC/783.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "南偏东25°" + }, + { + "bullet": "B", + "text": "南偏西25°" + }, + { + "bullet": "C", + "text": "南偏东65°" + }, + { + "bullet": "D", + "text": "南偏西65°" + } + ], + "text": "如果从点A看点B的方向为北偏东25°，那么从点B看点A的方向为( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "作出草图，点A看点B的方向是北偏东25°，是以A为标准，反之B看A的方向是A相对于B的方向与位置." + ] + } +} \ No newline at end of file diff --git a/MathMC/784.json b/MathMC/784.json new file mode 100644 index 0000000000000000000000000000000000000000..aa668cc9a0cc2bde3a9d91a91ef50406bbee8311 --- /dev/null +++ b/MathMC/784.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一根剩下的多" + }, + { + "bullet": "B", + "text": "第二根剩下的多" + }, + { + "bullet": "C", + "text": "剩下的一样长" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "两根绳子，一根用去，另一根用去米，两根绳子剩下的剩下的长度相比较( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "两根绳子没确定是否一样长，(1)如果说一样长，必须进行探讨，现在的条件不要探讨了.答案是无法确定.(2)两根绳子不一样长那就更不好确定了." + ] + } +} \ No newline at end of file diff --git a/MathMC/785.json b/MathMC/785.json new file mode 100644 index 0000000000000000000000000000000000000000..83a06b2dde61fc98bad4c2eb011dbd6c3d1f050a --- /dev/null +++ b/MathMC/785.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{9}是倒数" + }, + { + "bullet": "B", + "text": "\\frac{4}{9}和 \\frac{9}{4}都是倒数" + }, + { + "bullet": "C", + "text": "\\frac{9}{4}是倒数" + }, + { + "bullet": "D", + "text": "\\frac{4}{9}和 \\frac{9}{4}互为倒数" + } + ], + "text": "因为 \\frac{4}{9}× \\frac{9}{4}=1，所以( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据倒数的意义，乘积是1的两个数互为倒数.据此判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/786.json b/MathMC/786.json new file mode 100644 index 0000000000000000000000000000000000000000..ea2082475a26c9dcfb7173fdcedbd20099e4b42f --- /dev/null +++ b/MathMC/786.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "12" + } + ], + "text": "有4支球队，每两支球队之间都进行一场比赛，一共要进行( )场比赛. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "每两个队之间赛一场，那么每个队要赛3场，一共是4×3=12(场)，但是甲队与乙队比赛和乙队与甲队比赛是同一场比赛，所以12场比赛就多算了一倍，再除以2即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/787.json b/MathMC/787.json new file mode 100644 index 0000000000000000000000000000000000000000..32536dece995b08f519a51c5cbff42f093e77c67 --- /dev/null +++ b/MathMC/787.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12.5个" + }, + { + "bullet": "B", + "text": "13个" + }, + { + "bullet": "C", + "text": "12个" + } + ], + "text": "每个礼盒要用1.2米的丝带，15米长的丝带可以包装( )这样的礼盒. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "每个礼盒要用1.2米的丝带，根据除法的意义可知15米长的丝带可以包装15÷1.2个这样的礼盒." + ] + } +} \ No newline at end of file diff --git a/MathMC/788.json b/MathMC/788.json new file mode 100644 index 0000000000000000000000000000000000000000..4be7a2c2db2ccc800063a931d779836550d0837e --- /dev/null +++ b/MathMC/788.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{5}{6}÷ 1" + }, + { + "bullet": "B", + "text": "\\frac{5}{8}÷ \\frac{1}{2}" + }, + { + "bullet": "C", + "text": "\\frac{7}{10}÷ \\frac{3}{2}" + } + ], + "text": "下列算式中，商小于被除数的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "除数大于1时，商小于被除数. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/789.json b/MathMC/789.json new file mode 100644 index 0000000000000000000000000000000000000000..425477ecb43a7487418cb351c14697e1ceacecaf --- /dev/null +++ b/MathMC/789.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "3" + }, + { + "bullet": "D", + "text": "4" + } + ], + "text": "以下说法正确的有( )项. 13个连续自然数的和一定是3的倍数.2自然数中，偶数的倍数一定是合数.3两个不同的合数可能互质.4两个数的最小公倍数是这两个数最大公因数的倍数. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "13个连续自然数可以用n - 1，n，n+1来表示，所以3个数的和为( {n - 1} ) + n + ( {n + 1} ) = 3n，3n一定是3的倍数，故1正确; 2在自然数中，2是2的倍数，但2是质数，故2错误; 3两个不同的合数，比如4，9，它们互质，故3正确; 4两个数的最小公倍数是最大公因数的倍数，故4正确; 故有3个正确， 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/79.json b/MathMC/79.json new file mode 100644 index 0000000000000000000000000000000000000000..a2ab2e5fb483f5869bc3746c01561551a96dfc74 --- /dev/null +++ b/MathMC/79.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "唱一首歌" + }, + { + "bullet": "B", + "text": "拍一下手" + }, + { + "bullet": "C", + "text": "写10个字" + } + ], + "text": "1秒的时间可以( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据生活经验、对时间单位和数据的大小，可知1秒钟的时间可以拍一下手;唱一首哥歌大约3到5分钟，写10个字大约20秒." + ] + } +} \ No newline at end of file diff --git a/MathMC/790.json b/MathMC/790.json new file mode 100644 index 0000000000000000000000000000000000000000..146f77e4ccb4ca296261f7c03f62abaa4f90b2f2 --- /dev/null +++ b/MathMC/790.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:60" + }, + { + "bullet": "B", + "text": "1:6000000" + }, + { + "bullet": "C", + "text": "1:6000" + }, + { + "bullet": "D", + "text": "1:600000" + } + ], + "text": "在一幅地图上，用1厘米表示60千米的距离，这幅地图的比例尺是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用图上距离除以实际距离等于比例尺，即图上距离:实际距离=比例尺 ，例如本题就是:1厘米:60千米=1厘米:6 000 000厘米=1:6 000 000." + ] + } +} \ No newline at end of file diff --git a/MathMC/791.json b/MathMC/791.json new file mode 100644 index 0000000000000000000000000000000000000000..1dbd7b43a2cadc44ba03e13ec28f95d113eed728 --- /dev/null +++ b/MathMC/791.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1/8" + }, + { + "bullet": "B", + "text": "5/8" + }, + { + "bullet": "C", + "text": "2/8" + } + ], + "text": "把一块蛋糕平均分成8分，小王吃了3份，还剩( )份 " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题先读懂题目的意思，根据题中已知条件可以知道小王吃了蛋糕的 3 8，那么还剩多少，直接用1减去小王吃的就是了." + ] + } +} \ No newline at end of file diff --git a/MathMC/792.json b/MathMC/792.json new file mode 100644 index 0000000000000000000000000000000000000000..2c360d0e4ec7c82e27fb62f6590c3464efaf5a18 --- /dev/null +++ b/MathMC/792.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小明" + }, + { + "bullet": "B", + "text": "小丽" + }, + { + "bullet": "C", + "text": "一样多" + } + ], + "text": "两个同样大的苹果，小明吃了一个苹果的\\frac{1}{4}，小丽吃了一个苹果的\\frac{1}{3}，( )剩下的苹果多. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由于两人吃的苹果大小相同，所以单位‘1‘相同: 小明剩下:1-\\frac{1}{4}=\\frac{3}{4}， 小丽剩下:1-\\frac{1}{3}=\\frac{2}{3}， 因为\\frac{3}{4}>\\frac{2}{3}， 所以:小明剩的多. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/793.json b/MathMC/793.json new file mode 100644 index 0000000000000000000000000000000000000000..e822eaec372e4b12478d585ab1f69b24435064c0 --- /dev/null +++ b/MathMC/793.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "十万位和万位" + }, + { + "bullet": "B", + "text": "千万位和十万位" + }, + { + "bullet": "C", + "text": "千万位和亿位" + } + ], + "text": "与百万位相邻的两个数位是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据数位顺序表，从右到左，依次是个位、十位、百位、千位、万位、十万位、百万位、千万位、…，相对应的计数单位分别是个、十、百、千、万、十万、百万、千万、…，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/794.json b/MathMC/794.json new file mode 100644 index 0000000000000000000000000000000000000000..bcb62479ae556338854748b3e550e3038efc2339 --- /dev/null +++ b/MathMC/794.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "599999999" + }, + { + "bullet": "B", + "text": "600000001" + }, + { + "bullet": "C", + "text": "649999999" + } + ], + "text": "一个数省略亿后面的尾数后约是6亿，这个数最大是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "依题意得，根据四舍五入法可知，亿位后面千万位上的数舍去才是大的，因此这个最大的数是649999999 . 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/795.json b/MathMC/795.json new file mode 100644 index 0000000000000000000000000000000000000000..9b29fd43c341357cc4a146ade7e07c3c82eeaba1 --- /dev/null +++ b/MathMC/795.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小丽和小东" + }, + { + "bullet": "B", + "text": "小青和小东" + }, + { + "bullet": "C", + "text": "小青、小东和小丽" + } + ], + "text": "为了得到2÷ \\frac{2}{3}的结果，下面三位同学用不同的方法表达了自己的想法，想法合理的有( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "除以一个数等于乘这个数的倒数，所以小丽对.被除数和除数同时乘或者除以相同的数(0除外)，商不变.小东利用这个性质把分数除法转化成整数除法计算，所以对.\\frac{2}{3}=2÷ 3，所以2÷ \\frac{2}{3}=2÷ (2÷ 3)，应该是有括号的，否则计算顺序错了，所以小青错了. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/796.json b/MathMC/796.json new file mode 100644 index 0000000000000000000000000000000000000000..073ea5d121168c803af3d432c541b0aab8be92c2 --- /dev/null +++ b/MathMC/796.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一根长" + }, + { + "bullet": "B", + "text": "第二根长" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "有两根一样长的绳子，第一根用去全长的47%，第二根用去47米，剩下的( )长. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "由于不知道两根绳子原来的具体长度，所以无法确定剩下的相比较哪根剩下的长: 如果两根绳子原长100米，则第一根用去的47%长100×47%=47米，即两根用去的一样长，则剩下的也一样长; 如果两绳子原长大于100米，则第一根用去的47%就大于47米，即第一根用去的长，则第二根剩下的长; 反之，如果两绳子原长大于100米，则第一根用去的47%就小于47米，即第二根用去的长，则第一根剩下的;" + ] + } +} \ No newline at end of file diff --git a/MathMC/797.json b/MathMC/797.json new file mode 100644 index 0000000000000000000000000000000000000000..ff23d94339dcc43f21e68ebf9eba6a84a91ab94c --- /dev/null +++ b/MathMC/797.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "8× \\frac{1}{8}" + }, + { + "bullet": "B", + "text": "8+ \\frac{1}{8}" + }, + { + "bullet": "C", + "text": "8+8× \\frac{1}{8}" + } + ], + "text": "8千克的 \\frac{1}{8}是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把8千克看作单位‘1‘，根据一个数乘分数的意义，用乘法解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/798.json b/MathMC/798.json new file mode 100644 index 0000000000000000000000000000000000000000..259d3662d9578485db770c911cd77897d442e41e --- /dev/null +++ b/MathMC/798.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "除以4或乘以4" + }, + { + "bullet": "B", + "text": "除以4或乘以 \\frac{1}{4}" + }, + { + "bullet": "C", + "text": "除以 \\frac{1}{4}或乘以4" + } + ], + "text": "一个分数的分母除以 \\frac{1}{4}，要使分数的大小不变，分子应( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据分数的基本性质，分数的分子和分母都乘或除以相同的数(0除外)，分数的大小不变.首先观察分母的变化，分母除以 \\frac{1}{4}，就等于乘4，也就是说分母扩大了4倍，要使分数的大小不变，分子也应该扩大相同的倍数，由此通过计算解决." + ] + } +} \ No newline at end of file diff --git a/MathMC/799.json b/MathMC/799.json new file mode 100644 index 0000000000000000000000000000000000000000..ea119518e9fadce48c67175bb3006ea436a962b7 --- /dev/null +++ b/MathMC/799.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "买西红柿和黄瓜共付多少元" + }, + { + "bullet": "B", + "text": "西红柿比黄瓜重多少千克" + }, + { + "bullet": "C", + "text": "买黄瓜比西红柿少付多少元" + }, + { + "bullet": "D", + "text": "每千克西红柿比每千克黄瓜便宜多少元" + } + ], + "text": "买了a千克西红柿，每千克0.75元，又买了b千克黄瓜，每千克6元，那么0.75a-6b表示( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "单价× 数量=总价，故0.75a表示a千克西红柿的总价;6b表示b千克黄瓜的总价.0.75a-6b表示买西红柿比黄瓜多付多少元，或买黄瓜比西红柿少付多少元. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/8.json b/MathMC/8.json new file mode 100644 index 0000000000000000000000000000000000000000..82012cc3ae3e7eed7ce4cfd94c861b62aaf28f6f --- /dev/null +++ b/MathMC/8.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "96" + }, + { + "bullet": "B", + "text": "72" + }, + { + "bullet": "C", + "text": "80" + }, + { + "bullet": "D", + "text": "120" + } + ], + "text": "小刚和爸爸妈妈一起去动物园游玩，门票是:成人票48元/人，儿童半价.小刚一家买票需要( )元. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "用48除以2即可求出一张儿童票的价格，然后用两张成人票的价格和加上一张儿童票的钱数即可求出一共需要的钱数. ~~~~48×2+48÷ 2 =96+24 =120(元). 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/80.json b/MathMC/80.json new file mode 100644 index 0000000000000000000000000000000000000000..ee5fd1074a14cc3c857acf89799efa1e87274d00 --- /dev/null +++ b/MathMC/80.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "能直接相加减" + }, + { + "bullet": "B", + "text": "不能直接相加减" + }, + { + "bullet": "C", + "text": "通分后才能相加减" + } + ], + "text": "分数单位不相同的分数() " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "异分母分数的分数单位不相同，根据异分母分数的分母不同，也就是平均分的份数不同，其中1份的表示的大小就不相同，也就是分数单位不同，所以不能直接加减，要先通分成分数单位相同的分数才能相加减。 故选:C 本题是考查异分母分数加、减法" + ] + } +} \ No newline at end of file diff --git a/MathMC/800.json b/MathMC/800.json new file mode 100644 index 0000000000000000000000000000000000000000..076a1067d998af5e0a2ea319635755a33a38f37f --- /dev/null +++ b/MathMC/800.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "不变" + }, + { + "bullet": "B", + "text": "减少" + }, + { + "bullet": "C", + "text": "增加" + } + ], + "text": "两个完全一样的正方体拼成一个长方体后，表面积将( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一个正方体有六个面，两个有12个面，拼成长方体后少了两个面，还剩10个面，本题根据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/801.json b/MathMC/801.json new file mode 100644 index 0000000000000000000000000000000000000000..bff0493241a29e125e3ca8cc8d1b0c8110ee8a47 --- /dev/null +++ b/MathMC/801.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "100倍" + }, + { + "bullet": "B", + "text": "10倍" + }, + { + "bullet": "C", + "text": "1 000倍" + } + ], + "text": "在计算0.845÷0.36时要把被除数和除数同时扩大到原来的( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据商不变的性质:在除法算式里，被除数和除数同时扩大或缩小相同的倍数(0除外)，商不变;据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/802.json b/MathMC/802.json new file mode 100644 index 0000000000000000000000000000000000000000..78a29d6c8db8dcf0bd3c87e385b80f9f361d6758 --- /dev/null +++ b/MathMC/802.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "305000421" + }, + { + "bullet": "B", + "text": "3500420" + }, + { + "bullet": "C", + "text": "305000420" + }, + { + "bullet": "D", + "text": "30500420" + } + ], + "text": "由3个亿、500个万、420个一组成的数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "3个亿是300000000，500个万是5000000，420个一是420，把它们合起来是305000420，即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/803.json b/MathMC/803.json new file mode 100644 index 0000000000000000000000000000000000000000..8e00eb96d96c5fc6631dca1e5b84e77c4138a08a --- /dev/null +++ b/MathMC/803.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "100" + }, + { + "bullet": "C", + "text": "1350" + } + ], + "text": "一条人行道长27米，宽3米。用面积是6平方分米的正方形地砖铺路，需要这样的地砖 ( )块。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据‘长方形的面积=长×宽‘先求出这条人行道的面积，然后用这条人行道的面积除以每块水泥板的面积即可，计算时注意要统一单位。 解答过程为: 27×3=81(平方米) 81平方米=8100平方分米 8100÷6=1350(块) 故答案为:C" + ] + } +} \ No newline at end of file diff --git a/MathMC/804.json b/MathMC/804.json new file mode 100644 index 0000000000000000000000000000000000000000..cf1a2c2b8869c51f693d0605c8e19b9f22fabdd0 --- /dev/null +++ b/MathMC/804.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "正好完成" + }, + { + "bullet": "B", + "text": "超额完成" + }, + { + "bullet": "C", + "text": "没有完成" + } + ], + "text": "电视机厂四月上旬完成计划的1/4，中旬完成计划的1/3，下旬完成计划的1/2.这个月完成计划的情况是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把计划的量看作单位‘1‘，把上旬完成计划的，中旬完成计划的，下旬完成计划的，加在一起，再与单位‘1‘进行比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/805.json b/MathMC/805.json new file mode 100644 index 0000000000000000000000000000000000000000..fe2d3452f55e51afc1da6070dd05a60d50bff896 --- /dev/null +++ b/MathMC/805.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "11000与9999" + }, + { + "bullet": "B", + "text": "10001与9999" + }, + { + "bullet": "C", + "text": "10001与99999" + } + ], + "text": "与10000相邻的两个数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "求一个数相邻的数，就是用这个数减去1，得出它前面的数，用这个数加上1，得到它后面的数，从而解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/806.json b/MathMC/806.json new file mode 100644 index 0000000000000000000000000000000000000000..8defcb2c3964f764c074d6e1cc6d9545a75457b8 --- /dev/null +++ b/MathMC/806.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "24厘米" + }, + { + "bullet": "B", + "text": "12厘米" + }, + { + "bullet": "C", + "text": "18厘米" + } + ], + "text": "等腰梯形的周长是48厘米，面积是96平方厘米，高是8厘米，则腰长是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题干，可以利用梯形的面积公式先求出上底加下底的和是多少，再利用周长求得两腰的长度." + ] + } +} \ No newline at end of file diff --git a/MathMC/807.json b/MathMC/807.json new file mode 100644 index 0000000000000000000000000000000000000000..f4d3ede5b20d2eb51f28b64a4de2dd5d8854c323 --- /dev/null +++ b/MathMC/807.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{5}{6}+\\frac{3}{4}" + }, + { + "bullet": "B", + "text": "\\frac{5}{6}× \\frac{4}{3}" + }, + { + "bullet": "C", + "text": "\\frac{5}{6}÷ \\frac{3}{4}" + } + ], + "text": "求\\frac{5}{6}的\\frac{3}{4}是多少?列式为( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "求\\frac{5}{6}的\\frac{3}{4}是多少，也就是把\\frac{5}{6}当做单位1， 列式为:\\frac{5}{6}× \\frac{3}{4}，故B正确. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/808.json b/MathMC/808.json new file mode 100644 index 0000000000000000000000000000000000000000..96485c5ca936cb79b6cf947a442c11f68f4b8c74 --- /dev/null +++ b/MathMC/808.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1:25" + }, + { + "bullet": "B", + "text": "1:24" + }, + { + "bullet": "C", + "text": "24:25" + } + ], + "text": "在一种盐水中，盐的质量占 1 / 25，那么盐与水的质量比是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意盐的质量占 1 25，则水的质量占1- 1 25，则盐与水的质量之比是 1 25:(1- 1 25)，计算即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/809.json b/MathMC/809.json new file mode 100644 index 0000000000000000000000000000000000000000..00fb7133507ef9d9a76b2f8fd78b307bf53bde12 --- /dev/null +++ b/MathMC/809.json @@ -0,0 +1,36 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "150÷0.48" + }, + { + "bullet": "B", + "text": "599×\\frac{3}{7}" + }, + { + "bullet": "C", + "text": "4.9×59" + }, + { + "bullet": "D", + "text": "100×\\frac{8}{3} E.100×\\frac{8}{3}" + }, + { + "bullet": "E", + "text": "100×\\frac{8}{3}" + } + ], + "text": "估算下面格式的计算结果大于300的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "估算每个选项的算式: A:150÷0.48把0.48看成0.5可得300，增大了除数，所以准确值要大于300; B:599×\\frac{3}{7}，把599看成700可得300，增大了一个因数，所以准确值要小于300; C:4.9×59看成5×60=300，两个因数都增大了，所以准确值要小于300; D:100×\\frac{8}{3}看成100×\\frac{9}{3}=300，增大了一个因数，所以准确值要小于300. 找出大于300的选项A即可. 试题解析:150÷0.48>300; 599×\\frac{3}{7}<300; 4.9×59<300; 100×\\frac{8}{3}<300. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/81.json b/MathMC/81.json new file mode 100644 index 0000000000000000000000000000000000000000..98703cba0357248c63068aa8f05c105c31c5007d --- /dev/null +++ b/MathMC/81.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "457×99-1" + }, + { + "bullet": "B", + "text": "457×100+457" + }, + { + "bullet": "C", + "text": "457×100-457" + } + ], + "text": "457×99的简便算法是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "457×99，转化为:457×(100-1)，运用乘法分配律简算." + ] + } +} \ No newline at end of file diff --git a/MathMC/810.json b/MathMC/810.json new file mode 100644 index 0000000000000000000000000000000000000000..b5bce9e8fd0f98dbbfa8f426ef1d7981c197c918 --- /dev/null +++ b/MathMC/810.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{8}" + }, + { + "bullet": "B", + "text": "\\frac{8}{5}" + }, + { + "bullet": "C", + "text": "\\frac{1}{5}" + }, + { + "bullet": "D", + "text": "\\frac{5}{8}" + } + ], + "text": "把一块面积是8平方米的花坛平均分为5份，每份的面积是( )平方米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意，把整块地的面积看作单位‘1‘，则每份占整块地的多少平方米，用8除以分的份数即可计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/811.json b/MathMC/811.json new file mode 100644 index 0000000000000000000000000000000000000000..380429f98eb8e0d2478e5002bc6a3f3865c2516d --- /dev/null +++ b/MathMC/811.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60秒" + }, + { + "bullet": "B", + "text": "60分钟" + }, + { + "bullet": "C", + "text": "2小时" + } + ], + "text": "时针从前一个数字到后一个数字经过的时间是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据钟面的认识可以知道，时针从前一个数字到后一个数字所经过的时间就是1小时，也就是60分钟，据此解答本题即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/812.json b/MathMC/812.json new file mode 100644 index 0000000000000000000000000000000000000000..60f442dfe6d10b82af051e0f0c4d7b6d974853b3 --- /dev/null +++ b/MathMC/812.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "盒子里红球个数一定比黄球多" + }, + { + "bullet": "B", + "text": "盒子里红球个数一定和黄球相等" + }, + { + "bullet": "C", + "text": "盒子里一定没有其他颜色的球" + }, + { + "bullet": "D", + "text": "盒子里有可能有其他颜色的球" + } + ], + "text": "盒子里有一些大小相同，颜色不同的球，笑笑摸了20次，摸球的情况如下: 颜色 红色 黄色 次数 11 9 下面说法正确的是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "盒子里可能有其他颜色的球，因为题中并没有说球摸完. 故选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/813.json b/MathMC/813.json new file mode 100644 index 0000000000000000000000000000000000000000..dd1e8f4e0c43777c8366eefe3255600cb9cbcb1f --- /dev/null +++ b/MathMC/813.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4.2" + }, + { + "bullet": "B", + "text": "4.8" + }, + { + "bullet": "C", + "text": "5" + }, + { + "bullet": "D", + "text": "5.4" + } + ], + "text": "小明从A地到B地的平均速度是3米/秒，然后从B地原路返回，平均速度是7米/秒.那么，小明来回的平均速度是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "如果把A地到B地的路程看作单位‘1‘，那么一个来回的路程为1×2=2;根据‘路程÷速度=时间‘分别求出去的时间和返的时间，进而根据‘往返总路程÷往返总时间=往返平均速度‘进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/814.json b/MathMC/814.json new file mode 100644 index 0000000000000000000000000000000000000000..0a44a21153d83a38f85e8c46776cd6e512e4aabf --- /dev/null +++ b/MathMC/814.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "乙堆的质量比甲堆多20%" + }, + { + "bullet": "B", + "text": "甲、乙两堆质量的比是6:7" + }, + { + "bullet": "C", + "text": "如果从乙堆中取出给甲，那么两堆煤的质量同样多" + }, + { + "bullet": "D", + "text": "甲堆占两堆煤总质量的" + } + ], + "text": "如果甲堆煤的质量比乙堆煤少，那么下列说法不正确的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘甲堆煤的重量比乙堆煤少‘，可以知道:乙堆煤的重量为单位‘1‘，甲堆煤的重量是乙堆煤的1-，也即甲堆煤的重量对应的分率为，两堆煤总重量对应的分率为(1+)，据此把所给选项逐个分析后，即可得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/815.json b/MathMC/815.json new file mode 100644 index 0000000000000000000000000000000000000000..96a3016f83d96a99f6332c274f5eb54a0bc50bba --- /dev/null +++ b/MathMC/815.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小于直角" + }, + { + "bullet": "B", + "text": "小于平角" + }, + { + "bullet": "C", + "text": "小于270度" + }, + { + "bullet": "D", + "text": "大于270度" + } + ], + "text": "一个锐角加上一个钝角.它们的和一定( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据钝角、平角、锐角的含义可知:锐角是大于0°小于90°的角;等于180°的角是平角;钝角是大于90°小于180°的角;据此解答即可" + ] + } +} \ No newline at end of file diff --git a/MathMC/816.json b/MathMC/816.json new file mode 100644 index 0000000000000000000000000000000000000000..c5f8582d0917aeb350014d217c7ca57ad90164a5 --- /dev/null +++ b/MathMC/816.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "62000050" + }, + { + "bullet": "B", + "text": "60200500" + }, + { + "bullet": "C", + "text": "1000200" + } + ], + "text": "下面各数中读出两个零的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据整数中‘零‘的读法，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，读出各数再作选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/817.json b/MathMC/817.json new file mode 100644 index 0000000000000000000000000000000000000000..86f6f9be077e11a1a4cd7109789648d2928192c1 --- /dev/null +++ b/MathMC/817.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3x-x=8" + }, + { + "bullet": "B", + "text": "3x+x=8" + }, + { + "bullet": "C", + "text": "x+8=3x" + } + ], + "text": "笼子里有白兔、灰兔若干只，白兔的只数是灰兔的3倍，灰兔比白兔少8只，白兔、灰兔各几只?如果设灰色有x只，下面列的方程中错误的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题意可知:如果设灰兔有x只，则白兔的只数是3x只，根据白兔的只数-灰兔的只数=8只，即可列方程求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/818.json b/MathMC/818.json new file mode 100644 index 0000000000000000000000000000000000000000..f57dd4913415295cd5840c330d4ec6dd0e1f7190 --- /dev/null +++ b/MathMC/818.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "平移" + }, + { + "bullet": "B", + "text": "旋转" + }, + { + "bullet": "C", + "text": "既不是平移，也不是旋转" + } + ], + "text": "风扇叶片的运动是( )现象. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意结合对旋转现象的认识及相关知识进行解答问题即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/819.json b/MathMC/819.json new file mode 100644 index 0000000000000000000000000000000000000000..e738295777b96892a06be6e11e9db5652e1a562b --- /dev/null +++ b/MathMC/819.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{3}是倒数" + }, + { + "bullet": "B", + "text": "\\frac{3}{4}是倒数" + }, + { + "bullet": "C", + "text": "\\frac{4}{3}和\\frac{3}{4}都是倒数" + }, + { + "bullet": "D", + "text": "\\frac{4}{3}和\\frac{3}{4}互为倒数" + } + ], + "text": "因为\\frac{4}{3}×\\frac{3}{4}=1，所以( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据倒数的意义:乘积是1的两个数互为倒数.可知倒数是两个数之间的关系，只能说一个数是另一个数的倒数或一个数和另一个数互为倒数，不能说成某一个数是倒数.由此进行选择. 试题解析:因为\\frac{4}{3}×\\frac{3}{4}=1，所以为\\frac{4}{3}和\\frac{3}{4}互为倒数，也可说成为\\frac{4}{3}是\\frac{3}{4}的倒数或为\\frac{3}{4}是\\frac{4}{3}的倒数. 故选:D." + ] + } +} \ No newline at end of file diff --git a/MathMC/82.json b/MathMC/82.json new file mode 100644 index 0000000000000000000000000000000000000000..152203b7aba7f807225dedcf70eaf9db376c9dbe --- /dev/null +++ b/MathMC/82.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "807.17" + }, + { + "bullet": "B", + "text": "270.05" + }, + { + "bullet": "C", + "text": "400.61" + } + ], + "text": "下面各数中不读出‘零‘的数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "小数的读法是:整数部分按整数的读法读，小数部分要依次读出每一位上的数字. 整数中0的读法，每一级末尾的0都不读出来，其余数位连续几个0都只读一个0;依次读出各数，进而得出结论." + ] + } +} \ No newline at end of file diff --git a/MathMC/820.json b/MathMC/820.json new file mode 100644 index 0000000000000000000000000000000000000000..e8db9b86c99a5b3337a9a0e21c051549442c694d --- /dev/null +++ b/MathMC/820.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7毫米" + }, + { + "bullet": "B", + "text": "7厘米" + }, + { + "bullet": "C", + "text": "7分米" + }, + { + "bullet": "D", + "text": "7米" + } + ], + "text": "10本数学课本叠放在一起的厚度接近( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由一个单位数量的大小可得." + ] + } +} \ No newline at end of file diff --git a/MathMC/821.json b/MathMC/821.json new file mode 100644 index 0000000000000000000000000000000000000000..b2e5aaafeacefa87232be8a643187558be1ed6c1 --- /dev/null +++ b/MathMC/821.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "两个整数的积一定是这两个数的最小公倍数" + }, + { + "bullet": "B", + "text": "7和21的公倍数只有1个" + }, + { + "bullet": "C", + "text": "如果两个数互素，那么他们的乘积就是他们的最小公倍数" + }, + { + "bullet": "D", + "text": "已知a是b的一个因数，则a和b的最小公倍数是ab" + } + ], + "text": "下列说法正确的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据最小公倍数的意义:最小公倍数是这几个数公倍数中最小的，据此分析各选项的正确与否." + ] + } +} \ No newline at end of file diff --git a/MathMC/822.json b/MathMC/822.json new file mode 100644 index 0000000000000000000000000000000000000000..370a634f9408497347c36d99f0ecfb629eecb60a --- /dev/null +++ b/MathMC/822.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "77" + }, + { + "bullet": "B", + "text": "777" + }, + { + "bullet": "C", + "text": "7777" + }, + { + "bullet": "D", + "text": "77777" + } + ], + "text": "一个数是3的倍数，而且每个数位上的数字都是7，这个数可能是 ( )" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一个数各位上的数的和是3的倍数，这个数就是3的倍数。据此进行分析即可。 A选项，7+7=14，14不是3的倍数，所以77不是3的倍数。 B选项，7+7+7=21，21是3的倍数，所以777是3的倍数。 C选项，7+7+7+7=28，28不是3的倍数，所以7777不是3的倍数。 D选项，7+7+7+7+7=35，35不是3的倍数，所以77777不是3的倍数。 因此应选B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/823.json b/MathMC/823.json new file mode 100644 index 0000000000000000000000000000000000000000..9e132563e582a69d04faa8501f3f50984296f99e --- /dev/null +++ b/MathMC/823.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "12" + }, + { + "bullet": "B", + "text": "24" + }, + { + "bullet": "C", + "text": "36" + } + ], + "text": "有一包糖，无论平均分给6人，还是8人，都正好分完，这包糖至少有( )粒. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "要求这一袋糖的数量，即求出6和8的最小公倍数，先把6和8进行分解质因数，这两个数的公有质因数与独有质因数的连乘积是这两个数的最小公倍数;由此进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/824.json b/MathMC/824.json new file mode 100644 index 0000000000000000000000000000000000000000..9f140115acc32d73af7e765ad29ca98671280b84 --- /dev/null +++ b/MathMC/824.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "84=3×4×7" + }, + { + "bullet": "B", + "text": "84=2×2×3×7×1" + }, + { + "bullet": "C", + "text": "84=2×2×3×7" + } + ], + "text": "把84分解质因数，正确的写法是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分解质因数就是把一个合数写成几个质数的连乘积形式，一般先从简单的质数试着分解，据此解答此题." + ] + } +} \ No newline at end of file diff --git a/MathMC/825.json b/MathMC/825.json new file mode 100644 index 0000000000000000000000000000000000000000..0034d231aace42f88019e2e1424158b830b72a75 --- /dev/null +++ b/MathMC/825.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "36" + }, + { + "bullet": "B", + "text": "45" + }, + { + "bullet": "C", + "text": "40" + } + ], + "text": "45名学生去游园，他们每人想喝1瓶矿泉水，商店买4瓶送1瓶，那么他们只需要付钱买的有( )瓶. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据题意，买4瓶送1瓶，那么就是说每付4瓶的钱就能得到5瓶，共有45人，每人一瓶把这5瓶看成一份，一共要买45÷5=9份，每份要付4瓶的钱，所以要付9×4=36瓶的钱." + ] + } +} \ No newline at end of file diff --git a/MathMC/826.json b/MathMC/826.json new file mode 100644 index 0000000000000000000000000000000000000000..12ee21933e87203e6293964c1bda5fbf31293f94 --- /dev/null +++ b/MathMC/826.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9000和100001" + }, + { + "bullet": "B", + "text": "99999和110000" + }, + { + "bullet": "C", + "text": "99999和100001" + } + ], + "text": "与最小的六位数相邻的两个数是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "最小的六位数是100000，然后根据相邻的两个自然数相差1，进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/827.json b/MathMC/827.json new file mode 100644 index 0000000000000000000000000000000000000000..f947271ab2a6cdbbfc84dfe37b44f547b08a6ea2 --- /dev/null +++ b/MathMC/827.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90{}^{\\}circ -n{}^{\\}circ" + }, + { + "bullet": "B", + "text": "180{}^{\\}circ -2n{}^{\\}circ" + }, + { + "bullet": "C", + "text": "(180{}^{\\}circ -n{}^{\\}circ )÷ 2" + } + ], + "text": "等腰三角形的一个底角是n{}^{\\}circ ，它的顶角是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "等腰三角形的两个底角相等， 三角形的内角和是180{}^{\\}circ ， 所以这个三角形的顶角是180{}^{\\}circ -2n{}^{\\}circ . 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/828.json b/MathMC/828.json new file mode 100644 index 0000000000000000000000000000000000000000..eb5aa0cf108a116268e894de832cdd514f3d9621 --- /dev/null +++ b/MathMC/828.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "百位" + }, + { + "bullet": "B", + "text": "千位" + }, + { + "bullet": "C", + "text": "万位" + } + ], + "text": "36×28的积的最高位是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据乘法的计算法则求出36×28的积，看它的最高位是什么位." + ] + } +} \ No newline at end of file diff --git a/MathMC/829.json b/MathMC/829.json new file mode 100644 index 0000000000000000000000000000000000000000..52dbcf421b20f8758f3fe9e8a410ad75a8e2d3a7 --- /dev/null +++ b/MathMC/829.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减少了" + }, + { + "bullet": "B", + "text": "不变" + }, + { + "bullet": "C", + "text": "增加了" + } + ], + "text": "一个边长为4分米的正方形，如果在四个角各剪去一个边长为4厘米的正方形，那么它的周长与原来相比，周长( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据正方形的特征，4条边的长度都相等，如果四个角各剪去一个边长4厘米的小正方形，把剪去部分的边长经过平移，又恢复到原来的形状，所以周长不变，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/83.json b/MathMC/83.json new file mode 100644 index 0000000000000000000000000000000000000000..20d9b95dafc12ec28dd8142d7f2dbb384a629ea6 --- /dev/null +++ b/MathMC/83.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{6}{7}÷3" + }, + { + "bullet": "B", + "text": "6÷ \\frac{5}{4}" + }, + { + "bullet": "C", + "text": "\\frac{4}{5} ÷ \\frac{4}{5}" + } + ], + "text": "下面算式中，商大于被除数的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "一个数(0除外)除以小于1的数，商大于这个数;一个数(0除外)除以大于1的数，商小于这个数;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/830.json b/MathMC/830.json new file mode 100644 index 0000000000000000000000000000000000000000..4c3f4539b0bb89100400d422b6d5f07f780cb859 --- /dev/null +++ b/MathMC/830.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a/b" + }, + { + "bullet": "B", + "text": "a*b" + }, + { + "bullet": "C", + "text": "a-b" + }, + { + "bullet": "D", + "text": "a+b" + } + ], + "text": "已知a是一个真分数，b是一个假分数，在下列算式中答案一定大于1的算式是()" + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "因为假分数一定大于1，所以a+b一定大于1，a-b和a*b和a/b都可能小于1" + ] + } +} \ No newline at end of file diff --git a/MathMC/831.json b/MathMC/831.json new file mode 100644 index 0000000000000000000000000000000000000000..a3f3a20336c85578f6853e05012f472f8b6ed882 --- /dev/null +++ b/MathMC/831.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "4" + }, + { + "bullet": "D", + "text": "5" + } + ], + "text": "10瓶饮料，其中1瓶变质了(略重一些)，用天平称，至少称( )次保证能找出变质的那一瓶. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把10瓶饮料分成3份(3，3，4)，在天平两端各放3袋，如果天平平衡，则变质的在剩下的4瓶中，如果天平不平衡，则变质的在较重的3瓶中;在4瓶中找变质的，至少还要称2次，即先两端各放1瓶，不平衡，较重的是变质的，平衡，再称最后2瓶;在3瓶中找变质的，再称一次即可.因此用天平至少要称3次，才能保证找到变质的那一瓶." + ] + } +} \ No newline at end of file diff --git a/MathMC/832.json b/MathMC/832.json new file mode 100644 index 0000000000000000000000000000000000000000..285e8620e7ade6f74649f431fc03f41430cbbdae --- /dev/null +++ b/MathMC/832.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3平方厘米" + }, + { + "bullet": "B", + "text": "4平方厘米" + }, + { + "bullet": "C", + "text": "8平方厘米" + } + ], + "text": "3个边长是1厘米的小正方形拼成一个长方形，这个长方形的面积是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "3个边长是1厘米的小正方形拼成一个长方形，这个长方形的面积同3个小正方形的面积的和相等，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/833.json b/MathMC/833.json new file mode 100644 index 0000000000000000000000000000000000000000..dcc97940f506f1f52a9d9999c847c144a313c8a0 --- /dev/null +++ b/MathMC/833.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "平行四边形面积大" + }, + { + "bullet": "B", + "text": "长方形面积大" + }, + { + "bullet": "C", + "text": "一样大" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "如下图，长方形的长和平行四边形的底相等，长方形的宽要大于平行四边形的高，长方形和平行四边形的面积比较，( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "长方形的面积=长×宽，平行四边形的面积=底×高，本题中长方形的长和平行四边形的底相等，长方形的宽要大于平行四边形的高，所以长×宽>底×高;据此解题." + ] + } +} \ No newline at end of file diff --git a/MathMC/834.json b/MathMC/834.json new file mode 100644 index 0000000000000000000000000000000000000000..4e894c6d2e1b298d5673ba0879f2e9342a608a7e --- /dev/null +++ b/MathMC/834.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9、8" + }, + { + "bullet": "B", + "text": "7、6" + }, + { + "bullet": "C", + "text": "7、5" + } + ], + "text": "已知△+△+○=19，△+○=12，那么:△和○分别是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为△+△+○=19，△+○=12，两式相减可得△的值，进而即可求出△的值." + ] + } +} \ No newline at end of file diff --git a/MathMC/835.json b/MathMC/835.json new file mode 100644 index 0000000000000000000000000000000000000000..e357d32b5ee2595e7b4aa013ef0d98877e8cc6c1 --- /dev/null +++ b/MathMC/835.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "两个分数的积一定大于这两个分数的商" + }, + { + "bullet": "B", + "text": "任何数都有倒数" + }, + { + "bullet": "C", + "text": "除以一个数(零除外)等于乘这个数的倒数" + }, + { + "bullet": "D", + "text": "任何数都大于它的倒数" + } + ], + "text": "下面说法正确的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "A:当这两个分数都是真分数时，两个分数的积小于这两个分数的商，据此判断即可. B:0没有倒数，据此判断即可. C:除以一个数(零除外)等于乘这个数的倒数，据此判断即可. D:真分数小于它的倒数，据此判断即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/836.json b/MathMC/836.json new file mode 100644 index 0000000000000000000000000000000000000000..429d1e8b2e5c8f904796f04fba58d0d38dd5ae0a --- /dev/null +++ b/MathMC/836.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1000" + }, + { + "bullet": "B", + "text": "10" + }, + { + "bullet": "C", + "text": "100" + } + ], + "text": "在计算0.764÷0.36时，要把被除数和除数同时扩大( )倍. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在除法算式中，被除数和除数同时扩大或缩小相同的倍数(0除外)，商不变;据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/837.json b/MathMC/837.json new file mode 100644 index 0000000000000000000000000000000000000000..45b5bfb025de6cab1aef93d1fe4fe437e18aff0c --- /dev/null +++ b/MathMC/837.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "198+654=852" + }, + { + "bullet": "B", + "text": "198+456=654" + }, + { + "bullet": "C", + "text": "654+456=1110" + }, + { + "bullet": "D", + "text": "654-198=456" + } + ], + "text": "用加法验算654-456=198的算式是( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据被减数-减数=差，差+减数=被减数验算。 被减数是654，减数是456，差是198，验算时，差+减数=被减数，列式为198+456=654。 故答案为:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/838.json b/MathMC/838.json new file mode 100644 index 0000000000000000000000000000000000000000..e6cd3e838561cc4f67dcfdbfbc53241908edaa24 --- /dev/null +++ b/MathMC/838.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7" + }, + { + "bullet": "B", + "text": "13" + }, + { + "bullet": "C", + "text": "27" + } + ], + "text": "在一组不同的数字中，最大数是15，这组数的平均数不可能是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据平均数的求法，求出这组数的和再除以这组数的个数，如果这组数大小不同，平均数要比最大的数小，比最小的数大;如果这组数大小相同，最大数、最小数、平均数相等." + ] + } +} \ No newline at end of file diff --git a/MathMC/839.json b/MathMC/839.json new file mode 100644 index 0000000000000000000000000000000000000000..5469b7709d7a5d0f25a7d3784b1c983838444713 --- /dev/null +++ b/MathMC/839.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a只能是1" + }, + { + "bullet": "B", + "text": "a只能是97" + }, + { + "bullet": "C", + "text": "a是1或97" + } + ], + "text": "已知:a是97的因数，那么( )。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "97的因数只有1和它自己 1×97=97，积是97的乘法算式，而且乘数是自然数，只能写出这一道算式，所以a只能是1或者97，不能是别的数字。" + ] + } +} \ No newline at end of file diff --git a/MathMC/84.json b/MathMC/84.json new file mode 100644 index 0000000000000000000000000000000000000000..f47f0834c7e9b96c4cfaabb7ffd51c30277533c0 --- /dev/null +++ b/MathMC/84.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a的 \\frac{2}{3}是多少?" + }, + { + "bullet": "B", + "text": "一个数的 \\frac{2}{3}是a，求这个数" + }, + { + "bullet": "C", + "text": "把a平均分成3份，求2份 是多少?" + } + ], + "text": "a÷ \\frac{2}{3}是求( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据分数乘除法的意义，对选择逐个分析，列出算式，找出算式是a÷ \\frac{2}{3}即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/840.json b/MathMC/840.json new file mode 100644 index 0000000000000000000000000000000000000000..be28130798551310493f7270a2f6a1381c8d5e98 --- /dev/null +++ b/MathMC/840.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "-10摄氏度" + }, + { + "bullet": "B", + "text": "-6摄氏度" + }, + { + "bullet": "C", + "text": "6摄氏度" + }, + { + "bullet": "D", + "text": "10摄氏度" + } + ], + "text": "某市2012年元旦的最高气温为2摄氏度，最低气温为-8摄氏度，那么这天的最高气温比最低气温高( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "这天的最高气温比最低气温高多少，即是求最高气温与最低气温的差." + ] + } +} \ No newline at end of file diff --git a/MathMC/841.json b/MathMC/841.json new file mode 100644 index 0000000000000000000000000000000000000000..71b8eedd6658c09ba29297d54a6009f3248002a7 --- /dev/null +++ b/MathMC/841.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "180×(1-25%)÷(180×25%÷5)" + }, + { + "bullet": "B", + "text": "5×[(1-25%)÷25%]" + }, + { + "bullet": "C", + "text": "(1-25%)÷(25%÷5)" + }, + { + "bullet": "D", + "text": "180÷(180×25%÷5)" + } + ], + "text": "修路队修一条180米长的路，前5天完成了全长的25%，照这样计算，修完这条路还要几天?下面答案中错误的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "方法一:把总长度看成单位‘1‘，先求出平均每天修总长度的百分之几;再求出剩下总长度的百分之几，用剩下的百分数除以每天修的百分数，就是还需要的天数; 方法二:把总长度看成单位‘1‘，先求出前五天一共修了多少米，再除以5，求出平均每天修的长度;剩下的长度占总长度的(1-25%)，然后再用乘法求出剩下的长度，最后用剩下的长度除以每天修的长度即可; 方法三:先求出剩下的长度占总长度的百分之几，进而求出剩下的长度是已经修的长度的几倍，然后再乘5天即可; 方法四:把总长度看成单位‘1‘，先求出前五天一共修了多少米，再除以5，求出平均每天修的长度;然后用总长度除以平均每天修的长度，求出修完全长需要的时间，然后再减去5天即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/842.json b/MathMC/842.json new file mode 100644 index 0000000000000000000000000000000000000000..47037a8aca616b731547e394a229a51716e5083d --- /dev/null +++ b/MathMC/842.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{2}{5}× \\frac{13}{14}" + }, + { + "bullet": "B", + "text": "\\frac{6}{7}× \\frac{4}{5}" + }, + { + "bullet": "C", + "text": "\\frac{2}{5}× 3" + } + ], + "text": "下面算式中，两数之积在\\frac{2}{5}和\\frac{6}{7}之间的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为\\frac{2}{5}\\frac{6}{5}，而\\frac{6}{5}>\\frac{6}{7}，所以不在\\frac{2}{5}和\\frac{6}{7}之间，故C错误. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/843.json b/MathMC/843.json new file mode 100644 index 0000000000000000000000000000000000000000..0b136c3462219f04b1371efe0aec87e62cbca57c --- /dev/null +++ b/MathMC/843.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "四位数或五位数" + }, + { + "bullet": "B", + "text": "三位数或四位数" + }, + { + "bullet": "C", + "text": "五位数或六位数" + } + ], + "text": "三位数乘两位数，积可能是( ): " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "解答这样的问题需要我们知道，三位数乘两位数的积最多是几位数，最少是几位数，我们可以用最大的三位数乘最大的两位数，再用最小的三位数乘最小的两位数." + ] + } +} \ No newline at end of file diff --git a/MathMC/844.json b/MathMC/844.json new file mode 100644 index 0000000000000000000000000000000000000000..2141da78bcffeda6b7017dcfedb1d75e7ee23a58 --- /dev/null +++ b/MathMC/844.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80平方厘米" + }, + { + "bullet": "B", + "text": "400平方厘米" + }, + { + "bullet": "C", + "text": "25平方厘米" + } + ], + "text": "一个正方形，周长是20厘米，面积是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据正方形的周长公式:C=4a，可以求出正方形的边长，然后再根据正方形的面积公式:S=\\( a^{2} \\)，代入数据解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/845.json b/MathMC/845.json new file mode 100644 index 0000000000000000000000000000000000000000..d88e76be6af97808fd097bc575e86edb1cba688d --- /dev/null +++ b/MathMC/845.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{C}{2}+ \\frac{C}{π}" + }, + { + "bullet": "B", + "text": "\\frac{C}{2}+ \\frac{2C}{π}" + }, + { + "bullet": "C", + "text": "\\frac{C}{2}+ \\frac{C}{2π}" + }, + { + "bullet": "D", + "text": "\\frac{C}{2}" + } + ], + "text": "已知一个圆的周长是C，那么半圆的周长是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据圆的周长公式C=πd，求出圆的直径，d=C÷π，再根据半圆的周长等于圆周长的一半+直径，即可得出答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/846.json b/MathMC/846.json new file mode 100644 index 0000000000000000000000000000000000000000..3cc232bb77438853f135d70ac8dcbe8841f2a9bb --- /dev/null +++ b/MathMC/846.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小军" + }, + { + "bullet": "B", + "text": "小刚" + }, + { + "bullet": "C", + "text": "同样快" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "小军骑车的速度是16千米/时，小刚骑车的速度是250米/分，他们俩相比，( )骑得快. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "由于他们的速度单位不一样，所以把他们转化成相同单位，16千米=16× 1000=16000米，1时=60分，16000÷ 60≈ 267米/分，267米/分>250米/分在相同的时间内骑的越远则越快，所以小军骑的快. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/847.json b/MathMC/847.json new file mode 100644 index 0000000000000000000000000000000000000000..d96036720f2048da9f43aa3738f0bc4ccb37c00c --- /dev/null +++ b/MathMC/847.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20%" + }, + { + "bullet": "B", + "text": "25%" + }, + { + "bullet": "C", + "text": "75%" + } + ], + "text": "盐和水的质量比是1:4，盐占盐水的( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "先求出盐和盐水的质量比，再计算盐占盐水的百分之几." + ] + } +} \ No newline at end of file diff --git a/MathMC/848.json b/MathMC/848.json new file mode 100644 index 0000000000000000000000000000000000000000..dcf31b4f81653381bf956ad964c4a9dd9237bf1c --- /dev/null +++ b/MathMC/848.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "意义相同" + }, + { + "bullet": "B", + "text": "大小相同" + }, + { + "bullet": "C", + "text": "分数单位相同" + } + ], + "text": "\\frac{1}{4} 和 \\frac{2}{8}( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "将单位‘1‘平均分成若干份，表示其中这样一份或几份的数为分数.表示其中这样一份的数为分数单位.由此可知， \\frac{1}{4}表示将单位‘1‘平均分成4份，其中的一份为 \\frac{1}{4}，其分数单位为 \\frac{1}{4}; \\frac{1}{8}表示将单位‘1‘平均分成8份，其中的两份为 \\frac{2}{8}，其分数单位为 \\frac{1}{8};根据分数的其本性质可知 \\frac{2}{8}= \\frac{1}{4}，即 \\frac{1}{4}与 \\frac{2}{8}的大小相同，分数的意义及单位不同." + ] + } +} \ No newline at end of file diff --git a/MathMC/849.json b/MathMC/849.json new file mode 100644 index 0000000000000000000000000000000000000000..7726e91c3ef97e48a51c688ad0b1202859b38f46 --- /dev/null +++ b/MathMC/849.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "(3，5)" + }, + { + "bullet": "B", + "text": "(5，3)" + }, + { + "bullet": "C", + "text": "(3，4)" + } + ], + "text": "教室里，小明坐在第二组第4排，他的位置表示为(2，4)，那么小军在第五组第3排，他的位置可表示为( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据给出的例推出前一个数表示第几组，后一个数表示第几排." + ] + } +} \ No newline at end of file diff --git a/MathMC/85.json b/MathMC/85.json new file mode 100644 index 0000000000000000000000000000000000000000..8f70f0b0be3491dacd01eb2e8852a2b08674c5e3 --- /dev/null +++ b/MathMC/85.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{2}" + }, + { + "bullet": "B", + "text": "\\frac{1}{4}" + }, + { + "bullet": "C", + "text": "\\frac{2}{4}" + } + ], + "text": "一个苹果平均分成4份，小明吃了2块，小明吃了这个苹果的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把这个苹果看作单位‘1‘，平均分成4份，根据分数的意义，其中的一份用分数表示为 \\frac{1}{4};求小明吃了这个苹果的几分之几，也就是求两个 \\frac{1}{4}是多少;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/850.json b/MathMC/850.json new file mode 100644 index 0000000000000000000000000000000000000000..2546ee2a16d6cc42a402d21eb9b25202fb189ad6 --- /dev/null +++ b/MathMC/850.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{9}× \\frac{8}{5}" + }, + { + "bullet": "B", + "text": "\\frac{2}{3}× \\frac{5}{7}" + }, + { + "bullet": "C", + "text": "\\frac{7}{3}× \\frac{4}{5}" + } + ], + "text": "下面算式中，积最大的是( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先算出每个算式的结果，再比较。 A选项中， \\frac{4}{9}× \\frac{8}{5}= \\frac{32}{45}。 B选项中， \\frac{2}{3}× \\frac{5}{7}= \\frac{10}{21}。 C选项中， \\frac{7}{3}× \\frac{4}{5}= \\frac{28}{15}。 因为 \\frac{28}{15}是假分数， \\frac{32}{45}和 \\frac{10}{21}都是真分数，所以 \\frac{28}{15}最大。 故应选:C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/851.json b/MathMC/851.json new file mode 100644 index 0000000000000000000000000000000000000000..5b0a9375d372433fae2e9695d77350da287004d3 --- /dev/null +++ b/MathMC/851.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80008000" + }, + { + "bullet": "B", + "text": "8080808" + }, + { + "bullet": "C", + "text": "800808" + }, + { + "bullet": "D", + "text": "8000800" + } + ], + "text": "下面的数中，读数时，读的‘零‘的个数最多的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "本题依据大数的读法知识进行解答，读数的时候，先从高位读起，一级一级地往下读，亿级和万级要按照个级数的读法来读，再在后面添上亿或万字.每级末尾的0都不读，其它数位一个或连续几个零都只读一个零." + ] + } +} \ No newline at end of file diff --git a/MathMC/852.json b/MathMC/852.json new file mode 100644 index 0000000000000000000000000000000000000000..c795c37f86a2f9507fb0f014c85c5ff2d6a59ecf --- /dev/null +++ b/MathMC/852.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + } + ], + "text": "两个整数比较大小，位数多的数( )位数少的数. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据比较大数大小时应用数位多的数比数位低的数大，来解答本题." + ] + } +} \ No newline at end of file diff --git a/MathMC/853.json b/MathMC/853.json new file mode 100644 index 0000000000000000000000000000000000000000..deb4bd0b969c0094e9174167ca7e3365aeaa5425 --- /dev/null +++ b/MathMC/853.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "61× 29" + }, + { + "bullet": "B", + "text": "32× 50" + }, + { + "bullet": "C", + "text": "49× 28" + } + ], + "text": "下面的算式中，积小于1500的是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分别计算出各个选项的乘积，可得出答案， A.61× 29=1769，1769>1500，因此，积大于1500，不符合题意，故A错误; B.32× 50=1600，1600>1500，因此，积大于1500，不符合题意，故B错误; C.49× 28=1372，1372 < 1500，积小于1500，故C正确. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/854.json b/MathMC/854.json new file mode 100644 index 0000000000000000000000000000000000000000..75ed481c95cbbe6dd34f2ef86962b595ef2c8216 --- /dev/null +++ b/MathMC/854.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "600" + }, + { + "bullet": "B", + "text": "2000" + }, + { + "bullet": "C", + "text": "4800" + }, + { + "bullet": "D", + "text": "20000" + } + ], + "text": "一份资料有8页，平均每页有605个字，这份资料共有约( )个字. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据整数乘法的意义列出算式605×8计算即可求解.注意根据四舍五入法求近似数." + ] + } +} \ No newline at end of file diff --git a/MathMC/855.json b/MathMC/855.json new file mode 100644 index 0000000000000000000000000000000000000000..cc1e0003ed6f039935dcc3c11c9d597cf434c8c0 --- /dev/null +++ b/MathMC/855.json @@ -0,0 +1,36 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "任何正整数的因数至少有两个" + }, + { + "bullet": "B", + "text": "1是所有正整数的因数" + }, + { + "bullet": "C", + "text": "一个数的倍数总比它的因数大" + }, + { + "bullet": "D", + "text": "3的因数只有它本身" + }, + { + "bullet": "E", + "text": "任何正整数的因数至少有两个" + } + ], + "text": "下列说法中正确的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘一个数的约数的个数是有限的，最大的约数是它本身，最小的约数是1;一个数的倍数的个数是无限的，最小倍数是它本身‘进行分析解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/856.json b/MathMC/856.json new file mode 100644 index 0000000000000000000000000000000000000000..a5236e93e2dc20f6e0bc9c4d0b3aa641b523f7c7 --- /dev/null +++ b/MathMC/856.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲种贵" + }, + { + "bullet": "B", + "text": "乙种贵" + }, + { + "bullet": "C", + "text": "一样贵" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "甲种纸巾6包5.4元，乙种纸巾4包3.8元，两种纸巾的价格相比较( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "甲种纸巾的单价:5.4÷ 6=0.9(元)，乙种纸巾的单价:3.8÷ 4=0.95(元)， 0.95>0.9，所以乙种纸巾的价钱最贵. 答:乙种纸巾的价钱最贵." + ] + } +} \ No newline at end of file diff --git a/MathMC/857.json b/MathMC/857.json new file mode 100644 index 0000000000000000000000000000000000000000..1d9319c0aae2813167b52f534c100a48032240d7 --- /dev/null +++ b/MathMC/857.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "6" + }, + { + "bullet": "D", + "text": "8" + } + ], + "text": "在一个正方形里面画一个最大的圆，这个圆的周长是6.28厘米，这个正方形的面积是( )平方厘米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "已知在正方形里面画一个最大的圆，这个圆的周长是6.28厘米，根据圆的周长公式，C=πd，求出它的直径(正方形的边长)，这个圆的直径等于正方形的边长，再利用正方形的面积公式解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/858.json b/MathMC/858.json new file mode 100644 index 0000000000000000000000000000000000000000..2ff0ea654fb14a1ace60c3a8599a834a3c9a3f44 --- /dev/null +++ b/MathMC/858.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "", + "text": "一共有多少箱牛奶" + }, + { + "bullet": "", + "text": "一共有多少袋牛奶" + }, + { + "bullet": "", + "text": "一共能装多少箱牛奶" + } + ], + "text": "把一些袋装牛奶装入箱中，每箱装12袋，正好装6箱。如果每箱装9袋，那么能装多少箱?算式‘12×6‘表示 ( )。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "因为每箱装12袋，正好装6箱，12×6表示6个12相加，也就是在求一共有多少袋牛奶。 故答案为:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/859.json b/MathMC/859.json new file mode 100644 index 0000000000000000000000000000000000000000..6c6b2233ab0c7d3e87d218f1440b84f1ad1f2848 --- /dev/null +++ b/MathMC/859.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "34+0" + }, + { + "bullet": "B", + "text": "34-0" + }, + { + "bullet": "C", + "text": "0×34" + } + ], + "text": "34×0的结果和（ ）相等. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "考虑乘法交换律以及0乘任何数都得0." + ] + } +} \ No newline at end of file diff --git a/MathMC/86.json b/MathMC/86.json new file mode 100644 index 0000000000000000000000000000000000000000..1dd1e112f6e6bdedd5274ac090d266118ec06de6 --- /dev/null +++ b/MathMC/86.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9厘米" + }, + { + "bullet": "B", + "text": "6厘米" + }, + { + "bullet": "C", + "text": "3厘米" + } + ], + "text": "一个正方体的表面积是54平方厘米，这个正方体的棱长是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为正方体有6个面，每个面的面积为54÷6=9(平方厘米)，然后即可求出棱长." + ] + } +} \ No newline at end of file diff --git a/MathMC/860.json b/MathMC/860.json new file mode 100644 index 0000000000000000000000000000000000000000..99948805e14027f1f416b71ce0148ac58c89ff33 --- /dev/null +++ b/MathMC/860.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "不变" + }, + { + "bullet": "B", + "text": "减少了" + }, + { + "bullet": "C", + "text": "增加了" + } + ], + "text": "边长是1分米的正方形，四个角各剪去一个边长是1厘米的小正方形，它们的周长和原来相比( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "此题中减去的小正方形后，每个角上减少了两个正方形边长同时又增加了两个小正方形的边长，因此周长不变." + ] + } +} \ No newline at end of file diff --git a/MathMC/861.json b/MathMC/861.json new file mode 100644 index 0000000000000000000000000000000000000000..c3758ff5c27499827eaeab19ccde9a1745a33c27 --- /dev/null +++ b/MathMC/861.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "a+2" + }, + { + "bullet": "B", + "text": "2a" + }, + { + "bullet": "C", + "text": "2a+1" + } + ], + "text": "如果用a表示自然数，那么偶数可以表示为( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "偶数可以表示为2a." + ] + } +} \ No newline at end of file diff --git a/MathMC/862.json b/MathMC/862.json new file mode 100644 index 0000000000000000000000000000000000000000..49a580e866a285442ba5814b44505c0be67f93e9 --- /dev/null +++ b/MathMC/862.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + } + ], + "text": "两个整数比较大小，位数多的那个数( )位数少的那个数. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据比较大数大小时应用数位多的数比数位低的数大，来解答本题." + ] + } +} \ No newline at end of file diff --git a/MathMC/863.json b/MathMC/863.json new file mode 100644 index 0000000000000000000000000000000000000000..c06cc9e2d95888ac58ec0e4c5a04db1fc6e4a67b --- /dev/null +++ b/MathMC/863.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "成正比例" + }, + { + "bullet": "B", + "text": "成反比例" + }, + { + "bullet": "C", + "text": "不成比例" + }, + { + "bullet": "D", + "text": "可以成正比例也可以成反比例" + } + ], + "text": "全班总人数一定，及格人数和及格率( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "判断及格人数和及格率之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例." + ] + } +} \ No newline at end of file diff --git a/MathMC/864.json b/MathMC/864.json new file mode 100644 index 0000000000000000000000000000000000000000..b6adaab2096f485f297bf37857d97e3cf61f4868 --- /dev/null +++ b/MathMC/864.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一根剩的多" + }, + { + "bullet": "B", + "text": "第二根剩的多" + }, + { + "bullet": "C", + "text": "剩下的同样多" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "两根都是1米长的绳子，第一根用去 \\frac{3}{5}，第二根用去 \\frac{3}{5}米，剩下的长度相比较，( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "本题只要先求出第一根绳子的 \\frac{3}{5}是多少米，即能进行比较.根据分数的意义，1米的 \\frac{3}{5}为1× \\frac{3}{5}= \\frac{3}{5}(米)，即两根同样长的绳子用去的同样长，剩下的长度也一样长." + ] + } +} \ No newline at end of file diff --git a/MathMC/865.json b/MathMC/865.json new file mode 100644 index 0000000000000000000000000000000000000000..f02aa2c23207484c7b2eae55830a4d2afd947d3c --- /dev/null +++ b/MathMC/865.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于20%" + }, + { + "bullet": "B", + "text": "小于20%" + }, + { + "bullet": "C", + "text": "等于20%" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "在含糖20%的糖水中加入5克糖和20克水，这时糖水的含糖率( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先求出加入的糖水的含糖率，再同原来的含糖率进行比较，加入的糖水含糖率是5÷(5+20)×100%=20%，所以含糖率等于20%." + ] + } +} \ No newline at end of file diff --git a/MathMC/866.json b/MathMC/866.json new file mode 100644 index 0000000000000000000000000000000000000000..9d2681f5092e8bf8119a5a97d33c14c849184c72 --- /dev/null +++ b/MathMC/866.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2x" + }, + { + "bullet": "B", + "text": "2(x-2)" + }, + { + "bullet": "C", + "text": "x-4" + }, + { + "bullet": "D", + "text": "2·(x-2)/2" + } + ], + "text": "长方形的周长为x，宽为2，则这个长方形的面积为()" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "长方形的周长=2*长+2*宽，由题意可知，长方形的周长为x，宽为2，所以长方形的长=(x-2*2)/2，长方形的面积=长*宽=(x-2*2)/2*2=x-4。选C" + ] + } +} \ No newline at end of file diff --git a/MathMC/867.json b/MathMC/867.json new file mode 100644 index 0000000000000000000000000000000000000000..eb6e459a2dc738509fe9be57288539d76f2bcd30 --- /dev/null +++ b/MathMC/867.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{5}{95}" + }, + { + "bullet": "B", + "text": "\\frac{1}{20}" + }, + { + "bullet": "C", + "text": "\\frac{1}{19}" + } + ], + "text": "把5克糖放入95克水中，糖占糖水的( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先求出糖水的总重量，然后用糖的重量除以糖水的总重量即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/868.json b/MathMC/868.json new file mode 100644 index 0000000000000000000000000000000000000000..4cc114dd01541c8e190a59c7f9cd185e8cd8a49d --- /dev/null +++ b/MathMC/868.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "偏大" + }, + { + "bullet": "B", + "text": "偏小" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "选择超市.(请将正确答案的序号填在括号里) (1)394÷65，在试商时把65看作70，得到的商容易( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据商随除数的变化判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/869.json b/MathMC/869.json new file mode 100644 index 0000000000000000000000000000000000000000..26d069af401bdc6575518f6edb665830d36e256e --- /dev/null +++ b/MathMC/869.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形" + }, + { + "bullet": "B", + "text": "折线" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "小明想统计近五年来各年级参加‘庆六一‘活动的人数，并了解人数变化情况，他使用( )统计图最合适. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/87.json b/MathMC/87.json new file mode 100644 index 0000000000000000000000000000000000000000..ef19bac189f7ff7feb1656d4cb1d84403b1251ce --- /dev/null +++ b/MathMC/87.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "等于大正方体的表面积" + }, + { + "bullet": "B", + "text": "等于大正方体表面积的2倍" + }, + { + "bullet": "C", + "text": "等于大正方体表面积的3倍" + } + ], + "text": "把一个正方体切成大小相等的8个小正方体，8个小正方体的表面积之和( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把一个大正方体切成8个相等的小正方体，需要切3次，每切一次都增加2个原正方体的面，由此可知共增加了2×3=6个原正方体的面，设原正方体的每个面的面积是1，由此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/870.json b/MathMC/870.json new file mode 100644 index 0000000000000000000000000000000000000000..1ba3a10d116462f593ee506e7c6c323fda023069 --- /dev/null +++ b/MathMC/870.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "等于" + }, + { + "bullet": "C", + "text": "小于" + } + ], + "text": "将两个同样的小长方体拼成一个大长方体，则大长方体的表面积( )两个小长方体的表面积之和. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "两个长方体拼成一个长方体，表面积减少了2个长方形的面积，由此即可选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/871.json b/MathMC/871.json new file mode 100644 index 0000000000000000000000000000000000000000..bec9f8cb244031e7708046998ba8dbaec4a870f5 --- /dev/null +++ b/MathMC/871.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "4" + } + ], + "text": "一批零件的合格率是96%，这批零件共有50个.不合格的有( )个. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据合格产品的数量=这批零件的总数×一批零件的合格率，进而求出不合格的数量=这批零件的总数-合格产品的数量." + ] + } +} \ No newline at end of file diff --git a/MathMC/872.json b/MathMC/872.json new file mode 100644 index 0000000000000000000000000000000000000000..a4d2129d00071887984a6fdc9b7ed152e4a3339c --- /dev/null +++ b/MathMC/872.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "棱长和" + }, + { + "bullet": "B", + "text": "表面积" + }, + { + "bullet": "C", + "text": "体积" + } + ], + "text": "把一个长方体铁块锻造成一个正方体铁块，( )没变. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据体积的意义，物体所占空间的大小叫做物体的体积.把一个长方体铁块铸造成正方体，只是形状改变了，也就是它的表面积变了，但是体积没有变." + ] + } +} \ No newline at end of file diff --git a/MathMC/873.json b/MathMC/873.json new file mode 100644 index 0000000000000000000000000000000000000000..4a50d0ac4697efe35df9078f5dd936d5d85a6647 --- /dev/null +++ b/MathMC/873.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3000500" + }, + { + "bullet": "B", + "text": "3005000" + }, + { + "bullet": "C", + "text": "3050000" + } + ], + "text": "下面各数中，一个零也不读的数是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据整数中‘零‘的读法，每一级末尾的0都不读出来，其余数位一个零或连续几个0都只读一个零.这组数中，哪个数的所有的0都在每级的末尾，这个数就一个零也不读出来." + ] + } +} \ No newline at end of file diff --git a/MathMC/874.json b/MathMC/874.json new file mode 100644 index 0000000000000000000000000000000000000000..911d9d2523bbd31db0e2405d7caed6342bd0c764 --- /dev/null +++ b/MathMC/874.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "150:1" + }, + { + "bullet": "B", + "text": "1:150" + }, + { + "bullet": "C", + "text": "3:2" + }, + { + "bullet": "D", + "text": "2:3" + } + ], + "text": "小亮的身高是150 厘米，妹妹的身高是1 m，小亮和妹妹的身高比是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先将小亮和妹妹的身高统一单位后，再进行比的运算." + ] + } +} \ No newline at end of file diff --git a/MathMC/875.json b/MathMC/875.json new file mode 100644 index 0000000000000000000000000000000000000000..1234f8105f46ae2194ff766e10968f343a13f4a0 --- /dev/null +++ b/MathMC/875.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9个6相乘" + }, + { + "bullet": "B", + "text": "9和6相加" + }, + { + "bullet": "C", + "text": "6个9相加" + } + ], + "text": "9×6表示( )。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "9×6表示6个9相加。故选:C 乘法表示的意义就是求几个相同加数的和。" + ] + } +} \ No newline at end of file diff --git a/MathMC/876.json b/MathMC/876.json new file mode 100644 index 0000000000000000000000000000000000000000..7a36cc947ba8875beaf368a7e9eb8590def5d593 --- /dev/null +++ b/MathMC/876.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "+2摄氏度" + }, + { + "bullet": "B", + "text": "-2摄氏度" + }, + { + "bullet": "C", + "text": "0摄氏度" + }, + { + "bullet": "D", + "text": "4摄氏度" + } + ], + "text": "某天，上海最低气温是+2摄氏度，北京的最低气温是-2摄氏度，它们的最低气温的差是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "用上海的最低气温减去北京的最低气温，然后根据减去一个数等于加上这个数的相反数进行计算即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/877.json b/MathMC/877.json new file mode 100644 index 0000000000000000000000000000000000000000..717be43635f170f1a31eaeabf1730b05a7cde67f --- /dev/null +++ b/MathMC/877.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1}{10}" + }, + { + "bullet": "B", + "text": "\\frac{9}{10}" + }, + { + "bullet": "C", + "text": "\\frac{11}{10}" + } + ], + "text": "今年的产量比去年多\\frac{1}{10}，今年的产量就相当于去年的 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据今年小麦的产量比去年增产\\frac{1}{10}，可知把去年的产量看做单位1，今年的产量是1+\\frac{1}{10}，今年的产量相当于去年的几分之几:用今年的产量是( 1+\\frac{1}{10})÷ 去年的产量1，据此解答。 ( 1+\\frac{1}{10})÷ 1 =\\frac{11}{10}÷ 1 =\\frac{11}{10}。 故选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/878.json b/MathMC/878.json new file mode 100644 index 0000000000000000000000000000000000000000..366803598b1aadb6492d8da190b210f4ec49c075 --- /dev/null +++ b/MathMC/878.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "24" + } + ], + "text": "一个长方体棱长之和是48厘米，那么从一个顶点出发的三条棱长之和是( )厘米. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在长方体中从一个顶点出发的三条棱的长度分别叫做长、宽、高，根据长方体的棱长总和=(长+宽+高)×4，所以用棱长总和除以4即可求出长、宽、高的和.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/879.json b/MathMC/879.json new file mode 100644 index 0000000000000000000000000000000000000000..9589f6450679b92f6ae07f517a43c3a16ee5f289 --- /dev/null +++ b/MathMC/879.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "160:1" + }, + { + "bullet": "B", + "text": "16:1" + }, + { + "bullet": "C", + "text": "8:5" + }, + { + "bullet": "D", + "text": "5:8" + } + ], + "text": "小明的身高是160 厘米，小华的身高是1 m，小明和小华的身高的比是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为计量小明和小华身高的单位名称不同，应该把单位化统一了再比，据此即可解答问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/88.json b/MathMC/88.json new file mode 100644 index 0000000000000000000000000000000000000000..7c9dd06ff0adccbd2940b4704424cb903af3df2d --- /dev/null +++ b/MathMC/88.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "12" + }, + { + "bullet": "D", + "text": "60" + } + ], + "text": "已知M=2×2×3×5，那么M的因数有( )个. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据因数的意义可知:M=2×2×3×5，那么M的因数有，1、2、3、5、2×2、2×3、2×5、3×5、2×2×3、2×2×5、2×3×5、2×2×3×5，据此求出然后数出即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/880.json b/MathMC/880.json new file mode 100644 index 0000000000000000000000000000000000000000..619dc559651580f0723b22f1f8f146cf7becc1ea --- /dev/null +++ b/MathMC/880.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1100 米" + }, + { + "bullet": "B", + "text": "1100 厘米" + }, + { + "bullet": "C", + "text": "1分米" + } + ], + "text": "把1米长的线段平均分成100份，每份是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把1米长的线段平均分成100份，根据分数的意义可知，即将这根线段的全长当做单位‘1‘平均分成100份，则每份:1 ÷100= 1 100米." + ] + } +} \ No newline at end of file diff --git a/MathMC/881.json b/MathMC/881.json new file mode 100644 index 0000000000000000000000000000000000000000..ef6ae731017fcda25807e927dacc1fe5b28d5b7d --- /dev/null +++ b/MathMC/881.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3" + }, + { + "bullet": "B", + "text": "6" + }, + { + "bullet": "C", + "text": "9" + }, + { + "bullet": "D", + "text": "27" + } + ], + "text": "一个正方体的棱长扩大到原来的3倍，它的表面积就扩大到原来的( )倍，体积就扩大到原来的( )倍. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "假设原正方体的棱长为a厘米，扩大后的正方体的棱长为3× a=3a厘米， 正方体的表面积=棱长×棱长× 6， 原正方体的面积=a× a× 6=6a^{2}(平方厘米)， 扩大后正方体的面积=3a× 3a× 6=54a^{2}(平方厘米)， 因为54a^{2}÷ 6a^{2}=9(倍)，所以它的表面积就扩大到原来的9倍; 正方体的表面积=棱长×棱长× 棱长， 原正方体的面积=a× a× a=a^{3}(立方厘米)， 扩大后正方体的面积=3a× 3a× 3a=27a^{3}(立方厘米)， 因为27a^{3}÷ a^{3}=27(倍)，所以它的体积就扩大到原来的27倍. 故选C、\\text D." + ] + } +} \ No newline at end of file diff --git a/MathMC/882.json b/MathMC/882.json new file mode 100644 index 0000000000000000000000000000000000000000..4e13b095189baf59e5660619ebc6479171015a9c --- /dev/null +++ b/MathMC/882.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扩大到原来的100倍" + }, + { + "bullet": "B", + "text": "缩小到原来的" + }, + { + "bullet": "C", + "text": "不变" + } + ], + "text": "在52后面添上‘%‘，原数就( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘不是0的一个数后面添上百分号，这个数就缩小100倍‘，进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/883.json b/MathMC/883.json new file mode 100644 index 0000000000000000000000000000000000000000..13218f752050175182f12f436e6ae1dba0197719 --- /dev/null +++ b/MathMC/883.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "分针走一小格是1分" + }, + { + "bullet": "B", + "text": "秒针走一小格是5秒" + }, + { + "bullet": "C", + "text": "分针走一大格是一时" + } + ], + "text": "下列正确的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "分针走一小格就是一分钟，秒针走一小格是一秒钟，分针走一大格就是五分钟可知A为正确答案考察钟面的认识" + ] + } +} \ No newline at end of file diff --git a/MathMC/884.json b/MathMC/884.json new file mode 100644 index 0000000000000000000000000000000000000000..eb2bc37a5203857392f3703e56db73a95015a258 --- /dev/null +++ b/MathMC/884.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "2" + }, + { + "bullet": "C", + "text": "1" + } + ], + "text": "把一个大正方形剪成四个完全一样的小正方形，大正方形的边长是小正方形边长的( )倍. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "把一个大正方形剪成四个完全一样的小正方形，是把边长一分为二，则大正方形的边长是小正方形边长的2倍." + ] + } +} \ No newline at end of file diff --git a/MathMC/885.json b/MathMC/885.json new file mode 100644 index 0000000000000000000000000000000000000000..e2015fb1da40079edd9dd8060578cf6fcd7b0d0f --- /dev/null +++ b/MathMC/885.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "24平方米" + }, + { + "bullet": "B", + "text": "64平方米" + }, + { + "bullet": "C", + "text": "132平方米" + } + ], + "text": "把一块长是16米，宽是8米的长方形菜地分成两块同样的正方形菜地，每块正方形菜地的面积是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题意可知，正方形的边长就等于长方形菜地长的一半，据此先求出正方形的边长，再根据正方形的面积公式:s={{a}^{2}}，把数据代入公式解答即可. 16÷ 2=8( m )， 8× 8=64( {{m}^{2}} ). 答:每块菜地的面积是64{{m}^{2}}. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/886.json b/MathMC/886.json new file mode 100644 index 0000000000000000000000000000000000000000..3ce6bc15bf6a430af473bf3487ea5ed84d7f0a1f --- /dev/null +++ b/MathMC/886.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "26" + }, + { + "bullet": "B", + "text": "28" + }, + { + "bullet": "C", + "text": "29" + }, + { + "bullet": "D", + "text": "30" + } + ], + "text": "六(1)班10名男生1分钟仰卧起坐的成绩记录如下(单位/次):30、26、26、31、28、21、30、42、26、31这组数据的中位数是 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "将数据从小到大重新排列后为:21、26、26、26、28、30、30、31、31、42， 中位数是:(28+30)÷ 2=29. 故选C" + ] + } +} \ No newline at end of file diff --git a/MathMC/887.json b/MathMC/887.json new file mode 100644 index 0000000000000000000000000000000000000000..73409fe9ca857e3724e5925b0f9c3d9160a13d43 --- /dev/null +++ b/MathMC/887.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{2}{7}" + }, + { + "bullet": "B", + "text": "\\frac{4}{7}" + }, + { + "bullet": "C", + "text": "\\frac{4}{9}" + }, + { + "bullet": "D", + "text": "\\frac{3}{7}" + } + ], + "text": "小明在计算乘法时，不慎将乘数63错写成36，那么，计算结果比正确答案少( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "设另一个因数为x，原来的积为63x，现在的积是36x，那么计算结果比正确答案少(63x-36x)÷63x，计算即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/888.json b/MathMC/888.json new file mode 100644 index 0000000000000000000000000000000000000000..23246ee5b517425d9170d4d1afcd019374ef60a6 --- /dev/null +++ b/MathMC/888.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "400平方厘米" + }, + { + "bullet": "B", + "text": "25厘米" + }, + { + "bullet": "C", + "text": "25平方厘米" + } + ], + "text": "一个正方形的周长是20厘米，它的面积是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "先根据正方形的周长求出正方形的边长，再求正方形的面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/889.json b/MathMC/889.json new file mode 100644 index 0000000000000000000000000000000000000000..d73a27c24974da2ef9109bce8e278e5544a3c5cb --- /dev/null +++ b/MathMC/889.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一次用去的长一些" + }, + { + "bullet": "B", + "text": "第二次用去的长一些" + }, + { + "bullet": "C", + "text": "无法确定" + } + ], + "text": "一根铁丝，第一次用去它的\\frac{4}{7}，第二次用去\\frac{4}{7}米，说法正确的是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "1-\\frac{4}{7}=\\frac{3}{7}，\\frac{4}{7}>\\frac{3}{7}，所以第一次用去的长些. 故答案为:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/89.json b/MathMC/89.json new file mode 100644 index 0000000000000000000000000000000000000000..776d618507ba37bddd4883335325a294fe841709 --- /dev/null +++ b/MathMC/89.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1号牙刷买8把12.4元，" + }, + { + "bullet": "B", + "text": "2号牙刷买5把9元，" + }, + { + "bullet": "C", + "text": "3号牙刷买2把4.8元" + } + ], + "text": "哪种牙刷的单价最高?" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据单价=总价÷数量可知，1号牙刷买8把需要12.4元，用12.4元除以8把，求出1号牙刷的单价;同理求出2、3号牙刷的单价，再比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/890.json b/MathMC/890.json new file mode 100644 index 0000000000000000000000000000000000000000..eac5ef6eef0a2d653840a00444f7c50465ef6026 --- /dev/null +++ b/MathMC/890.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{1000}{59}立方分米" + }, + { + "bullet": "B", + "text": "\\frac{59}{100}立方分米" + }, + { + "bullet": "C", + "text": "\\frac{59}{1000}立方分米" + }, + { + "bullet": "D", + "text": "\\frac{59}{10}立方分米" + } + ], + "text": "59毫升是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据体积单位和容积单位之间的关系，1毫升=1立方厘米，1立方分米=1000立方厘米，按照名数的改写方法解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/891.json b/MathMC/891.json new file mode 100644 index 0000000000000000000000000000000000000000..c32229d7dde1ed8b5dfc6d70a5956e7079a5d9c8 --- /dev/null +++ b/MathMC/891.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "现价是原价的80%" + }, + { + "bullet": "B", + "text": "现价比原价便宜了80%" + }, + { + "bullet": "C", + "text": "原价是现价的80%" + }, + { + "bullet": "D", + "text": "现价是原价的20%" + } + ], + "text": "商品打八折，也就是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "八折是把原价看成单位‘1‘，那么现价是原价的80%，由此求解. 商品打八折，就是现价是原价的80%. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/892.json b/MathMC/892.json new file mode 100644 index 0000000000000000000000000000000000000000..b00da905f6a8b4ecbdf2f54e39f722ab9ea798b7 --- /dev/null +++ b/MathMC/892.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2400" + }, + { + "bullet": "B", + "text": "2600" + }, + { + "bullet": "C", + "text": "2800" + } + ], + "text": "估算69×41的积大约是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "在计算69×41时，把41看作40，把69看作70，然后计算即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/893.json b/MathMC/893.json new file mode 100644 index 0000000000000000000000000000000000000000..61800151de1005867af94ebbc026e7f6b056b750 --- /dev/null +++ b/MathMC/893.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9" + }, + { + "bullet": "B", + "text": "4" + }, + { + "bullet": "C", + "text": "5" + } + ], + "text": "一个数‘四舍‘后的近似数是30万，这个数的千位上最大是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "一个整数的近似数正好是30万，最大是千位上的数舍去得到，舍去的数中4是最大的." + ] + } +} \ No newline at end of file diff --git a/MathMC/894.json b/MathMC/894.json new file mode 100644 index 0000000000000000000000000000000000000000..2882f177a28b1804cc107d9d3fb1bbbacb897af7 --- /dev/null +++ b/MathMC/894.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "十几个" + }, + { + "bullet": "B", + "text": "三十几个" + }, + { + "bullet": "C", + "text": "八十几个" + } + ], + "text": "一个三年级学生的体重大约是30千克，( )个学生的体重大约是1000千克. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "求1000千克里面有多少个30千克，用1000千克除以30千克就是大约学生的个数." + ] + } +} \ No newline at end of file diff --git a/MathMC/895.json b/MathMC/895.json new file mode 100644 index 0000000000000000000000000000000000000000..7c16cfe9c918509f234f5f15e77419da3bfaaa21 --- /dev/null +++ b/MathMC/895.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + } + ], + "text": "甲乙两数都大于0，如果甲数÷0.86=乙，那么甲数一定( )乙数. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "我们运用乙数表示出甲数，然后再和乙数进行比较即可，然后再进行选择. 甲数÷0.86=乙，甲数是被除数，所以甲=0.86× 乙，甲=乙的86%，把乙看作单位‘1‘，甲数是乙的86%，所以甲数小于乙数. 故选:B." + ] + } +} \ No newline at end of file diff --git a/MathMC/896.json b/MathMC/896.json new file mode 100644 index 0000000000000000000000000000000000000000..ee615ba3ef3a6ac74752245233b5b5db67883b0b --- /dev/null +++ b/MathMC/896.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4 5 × 4 5" + }, + { + "bullet": "B", + "text": "4 5 ÷4" + }, + { + "bullet": "C", + "text": "1 5 × 1 5" + }, + { + "bullet": "D", + "text": "4 5 × 1 5" + } + ], + "text": "一根铁丝长 4 5 米，用它围成一个最大的正方形，面积是( )平方米. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "先求出边长再求面积" + ] + } +} \ No newline at end of file diff --git a/MathMC/897.json b/MathMC/897.json new file mode 100644 index 0000000000000000000000000000000000000000..df8d1f1b961890d3a4be8a66e62d7c7a79df5dff --- /dev/null +++ b/MathMC/897.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "9厘米" + }, + { + "bullet": "B", + "text": "12厘米" + }, + { + "bullet": "C", + "text": "18厘米" + } + ], + "text": "一个长方体所有棱长之和是36厘米，则相交于一个顶点的所有棱长之和是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据长方体的特征，12条棱分为互相平行的3组，每组4条棱的长度相等.长方体的棱长总和=(长+宽+高)×4，相交于一个顶点的所有棱长之和也就是长、宽、高的和，用棱长总和除以4就是长、宽、高的和，由此列式解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/898.json b/MathMC/898.json new file mode 100644 index 0000000000000000000000000000000000000000..c405cda613a1465b7912f526f118b4576295dde9 --- /dev/null +++ b/MathMC/898.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "真分数都小于1" + }, + { + "bullet": "B", + "text": "假分数都可以化为带分数" + }, + { + "bullet": "C", + "text": "带分数都大于1" + } + ], + "text": "下列说法中，错误的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "在分数中，分子小于分母的分数为真分数，分子大于或等于分母的分数为假分数.由此可知，真分数小于1，假分数大于或等于1.整数与真分数相加所成的分数为带分数，自然数中，最小的整数为1，所以带分数>1.据此判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/899.json b/MathMC/899.json new file mode 100644 index 0000000000000000000000000000000000000000..95c5310507c5fbf6d1f8fe4d604d10d811006ce4 --- /dev/null +++ b/MathMC/899.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15，12" + }, + { + "bullet": "B", + "text": "12，15" + }, + { + "bullet": "C", + "text": "13，14" + } + ], + "text": "商店有钢笔和铅笔共27盒，共计300支，钢笔每盒10支，铅笔每盒12支，则钢笔有( )盒，铅笔有( )盒. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "可以设其中一种笔有x盒，列方程求出这种笔的盒数，然后再求出另一种笔的盒数，找出和选项符合的一组." + ] + } +} \ No newline at end of file diff --git a/MathMC/9.json b/MathMC/9.json new file mode 100644 index 0000000000000000000000000000000000000000..6b8944219b6fab37f41434f55817f2e0a443b273 --- /dev/null +++ b/MathMC/9.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一次长" + }, + { + "bullet": "B", + "text": "第二次长" + }, + { + "bullet": "C", + "text": "两次同样长" + } + ], + "text": "一根铁丝长\\frac{8}{5}米，第一次用去\\frac{3}{5}米，第二次用去剩下的\\frac{3}{5}，( )用去的铁丝长一些. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "一:\\frac{3}{5}m. 二:( \\frac{8}{5}-\\frac{3}{5})× \\frac{3}{5} =\\frac{3}{5}(m). \\frac{3}{5}=\\frac{3}{5}. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/90.json b/MathMC/90.json new file mode 100644 index 0000000000000000000000000000000000000000..69c451c7fe7bcd22af60bb5bca3d296cc541615b --- /dev/null +++ b/MathMC/90.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一定" + }, + { + "bullet": "B", + "text": "可能" + }, + { + "bullet": "C", + "text": "不可能" + } + ], + "text": "今天考试小明( )得第一. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据事件的不确定性，可得今天考试小明可能得第一，也可能不得第一，不是一定或者不可能得第一，据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/900.json b/MathMC/900.json new file mode 100644 index 0000000000000000000000000000000000000000..38dbe794c2ffe562810746ac67975889e1ff4ace --- /dev/null +++ b/MathMC/900.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比长方形的面积大" + }, + { + "bullet": "B", + "text": "比长方形的面积小" + }, + { + "bullet": "C", + "text": "与长方形的面积相等" + } + ], + "text": "用两个大小相同的正方形拼成一个长方形，这两个正方形的面积和( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "用两个大小相同的正方形拼成一个长方形，长方形的宽等于正方形的边长，长方形的长等于正方形的边长的2倍，所以长方形的面积=长×宽=(2×边长)×边长=2×(边长×边长)=2×正方形面积=正方形面积+正方形面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/901.json b/MathMC/901.json new file mode 100644 index 0000000000000000000000000000000000000000..5b54eed87649e5666868a798ddc8f57c58927230 --- /dev/null +++ b/MathMC/901.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "1厘米，1厘米，2厘米" + }, + { + "bullet": "B", + "text": "1厘米，2.5厘米，3厘米" + }, + { + "bullet": "C", + "text": "8分米，1分米，2分米" + } + ], + "text": "下面各组线段中，能围成三角形的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据三角形三边的关系:任意两边之和大于第三边，据此对各个选项进行分析判断后利用排除法来求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/902.json b/MathMC/902.json new file mode 100644 index 0000000000000000000000000000000000000000..4dc02812885afed3ec6667ca08eff9c34fd2fd07 --- /dev/null +++ b/MathMC/902.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "加法交换律" + }, + { + "bullet": "B", + "text": "加法结合律" + }, + { + "bullet": "C", + "text": "加法交换律和结合律" + } + ], + "text": "46+39+54+61=(46+54)+(39+61)，这是根据( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "46+39+54+61先交换39与54的位置，分别把46和54，以及39和61结合在一起，所以运用了加法交换律和结合律." + ] + } +} \ No newline at end of file diff --git a/MathMC/903.json b/MathMC/903.json new file mode 100644 index 0000000000000000000000000000000000000000..e5124bcc0d37d70dce691e507aa166a605e3ba47 --- /dev/null +++ b/MathMC/903.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "缩小到原数的 \\frac{1}{5}" + }, + { + "bullet": "B", + "text": "扩大到原数的2倍" + }, + { + "bullet": "C", + "text": "扩大到原数的5倍" + } + ], + "text": "一个不为0的数除以20%，这个数就( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把20%化成分数，然后再根据除以一个数等于除以这个数的倒数求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/904.json b/MathMC/904.json new file mode 100644 index 0000000000000000000000000000000000000000..f068de030e1fbf90d7bbde8e7eb7d1265f82ce92 --- /dev/null +++ b/MathMC/904.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小明" + }, + { + "bullet": "B", + "text": "淘气" + }, + { + "bullet": "C", + "text": "无法判定" + } + ], + "text": "在100米短跑中，淘气用了13.9秒，小明用了14.1秒，这两个人( )跑得快. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "路程相等都是100米，所以比较两人用的时间，时间较短的速度就快，由此求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/905.json b/MathMC/905.json new file mode 100644 index 0000000000000000000000000000000000000000..bc34e727283aa8793a98847b4d260978e32ac24a --- /dev/null +++ b/MathMC/905.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "109+459=586" + }, + { + "bullet": "B", + "text": "568-109=456" + }, + { + "bullet": "C", + "text": "459+109=568" + } + ], + "text": "下列验算568-459=109的算式中，正确的是( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "(1)减法验算可以用减数加上差看是不是等于被减数。所以568-459=109，验算是109+459=568。C选项正确，A选项中算式等于586计算错误。 (2)减法的验算方法还可以用被减数减去差看是不是等于减数。所以568-459=109，验算是568-109=459。B选项中算式等于456错误。 故答案为:C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/906.json b/MathMC/906.json new file mode 100644 index 0000000000000000000000000000000000000000..52ddfa7f38498f276eb1b0d9c2a25641854b2fe8 --- /dev/null +++ b/MathMC/906.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "加法的结合律" + }, + { + "bullet": "B", + "text": "乘法结合律" + }, + { + "bullet": "C", + "text": "乘法分配律" + } + ], + "text": "算式33×42+33×58=33×(42+58)运用的运算定律是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "33×42+33×58，运用乘法分配律进行简算." + ] + } +} \ No newline at end of file diff --git a/MathMC/907.json b/MathMC/907.json new file mode 100644 index 0000000000000000000000000000000000000000..ddc4579bba73dcb32577c149daf6003302862b77 --- /dev/null +++ b/MathMC/907.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "9" + } + ], + "text": "5□6×48≈30 000，□里最大可以填 . " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "因为48是确定的数，这个数看成50，50×600=30 000，找出5□6中最大看成600的数." + ] + } +} \ No newline at end of file diff --git a/MathMC/908.json b/MathMC/908.json new file mode 100644 index 0000000000000000000000000000000000000000..e7916c09502fbbf11234a2d947aa02b59171441f --- /dev/null +++ b/MathMC/908.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4/5=4:5 450×5/(5 + 4)" + }, + { + "bullet": "B", + "text": "450×(1+ 4/5)" + }, + { + "bullet": "C", + "text": "设上衣单价为x元，列方程得:x+ 4/5x=450" + } + ], + "text": "一套衣服卖450元，其中裤子的价格是上衣的 4/5，上衣的单价是多少元?以下的列式，错误的是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "认真审题，仔细观察和分析题干中的已知条件和数量关系.根据比的应用，求出裤子和上衣的比，再根据按比例分配求解;根据已知一个数的几分之几是多少，据此应该列除法算式计算求解;根据等量关系:上衣价钱+裤子价钱=450，据此列出方程计算求解.据此判断求解." + ] + } +} \ No newline at end of file diff --git a/MathMC/909.json b/MathMC/909.json new file mode 100644 index 0000000000000000000000000000000000000000..110400472f3d6bbb89687731db6632fb5fdd8654 --- /dev/null +++ b/MathMC/909.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "有限小数" + }, + { + "bullet": "B", + "text": "无限不循环小数" + }, + { + "bullet": "C", + "text": "无限循环小数" + }, + { + "bullet": "D", + "text": "3.14" + } + ], + "text": "圆周率π 是一个( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "圆周率π 是一个无限不循环小数." + ] + } +} \ No newline at end of file diff --git a/MathMC/91.json b/MathMC/91.json new file mode 100644 index 0000000000000000000000000000000000000000..0051df80c362f6189f332613a07284b8cc9eec41 --- /dev/null +++ b/MathMC/91.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "16=2×8" + }, + { + "bullet": "B", + "text": "16=2×4×2" + }, + { + "bullet": "C", + "text": "16=2×2×2×2" + } + ], + "text": "把16分解质因数是 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分解质因数的方法，一个合数可以写成几个质数连乘积的形式，叫做分解质因数，由此解答。 16=2×2×2×2。 故选:C 。" + ] + } +} \ No newline at end of file diff --git a/MathMC/910.json b/MathMC/910.json new file mode 100644 index 0000000000000000000000000000000000000000..da827ab6a85d315d3d0ff9bf3463dbec9354043c --- /dev/null +++ b/MathMC/910.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": ">" + }, + { + "bullet": "B", + "text": "=" + }, + { + "bullet": "C", + "text": "<" + } + ], + "text": "如果 \\frac{1}{a}> \\frac{1}{b}，那么a( )b. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "分数的意义为:将单位‘1‘平均分成若干份，表示这样一份或几份的数为分数.由此可知，分子相同，分母越小，则分数值越大.据此判断." + ] + } +} \ No newline at end of file diff --git a/MathMC/911.json b/MathMC/911.json new file mode 100644 index 0000000000000000000000000000000000000000..5f4f7a0325ad3037442a1654381b1768a1519a33 --- /dev/null +++ b/MathMC/911.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{11}{18}" + }, + { + "bullet": "B", + "text": "\\frac{7}{18}" + }, + { + "bullet": "C", + "text": "\\frac{1}{9}" + } + ], + "text": "下面各数中，( )比 \\frac{1}{2}少 \\frac{1}{9}. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据求比一个数少几用减法解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/912.json b/MathMC/912.json new file mode 100644 index 0000000000000000000000000000000000000000..bb0111ddb313c6baf2cd9dd528c20de44b954285 --- /dev/null +++ b/MathMC/912.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "80厘米" + }, + { + "bullet": "B", + "text": "40厘米" + }, + { + "bullet": "C", + "text": "80平方厘米" + }, + { + "bullet": "D", + "text": "100平方厘米" + } + ], + "text": "把4个边长为5厘米的小正方形拼成一个大正方形，面积是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "把4个边长为5厘米的小正方形拼成一个大正方形，这时大正方形的边长为5×2=10厘米，由此可以解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/913.json b/MathMC/913.json new file mode 100644 index 0000000000000000000000000000000000000000..49f0f162ca1af9c420504fae6b7951a0f2a14f88 --- /dev/null +++ b/MathMC/913.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "圆的面积与正方形的面积一样大" + }, + { + "bullet": "B", + "text": "圆的面积比正方形的面积大" + }, + { + "bullet": "C", + "text": "圆的面积比正方形的面积小" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "周长都等于31.4厘米的圆和正方形，它们的面积关系是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据‘正方形的边长=正方形的周长÷4‘求出正方形的边长，根据‘正方形的面积=边长×边长‘求出正方形的面积;根据‘r=C÷π÷2‘求出圆的半径，进而根据‘圆的面积=π\\( r^{2} \\)‘求出圆的面积，最后进行比较即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/914.json b/MathMC/914.json new file mode 100644 index 0000000000000000000000000000000000000000..309944e9bf47c803630e8049c0b5cfb9e433580f --- /dev/null +++ b/MathMC/914.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "160" + }, + { + "bullet": "B", + "text": "210" + }, + { + "bullet": "C", + "text": "150" + } + ], + "text": "一本书360页，已经读了7/12，还剩( )页没有读. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "一本书360页，已经读了7/12，将总页数当作单位‘1‘，根据分数减法的意义，还剩下全部的1-没读，求一个数的几分之几是多少，用乘法，则还剩下360×(1-7/12)页." + ] + } +} \ No newline at end of file diff --git a/MathMC/915.json b/MathMC/915.json new file mode 100644 index 0000000000000000000000000000000000000000..d08dff76a78171bea2bdc99217768412116d4b68 --- /dev/null +++ b/MathMC/915.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3×4÷2" + }, + { + "bullet": "B", + "text": "3×5÷2" + }, + { + "bullet": "C", + "text": "4×5÷2" + } + ], + "text": "一个直角三角形的三条边分别为3分米、4分米和5分米.它的面积是 平方分米. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "直角三角形斜边最长，因此是5分米，因此两条直角边是3分米、4分米.利用三角形面积公式解题。" + ] + } +} \ No newline at end of file diff --git a/MathMC/916.json b/MathMC/916.json new file mode 100644 index 0000000000000000000000000000000000000000..7bcad19105ed211e0c16e448d16b2556509cd0ee --- /dev/null +++ b/MathMC/916.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "4" + }, + { + "bullet": "B", + "text": "8" + }, + { + "bullet": "C", + "text": "9" + }, + { + "bullet": "D", + "text": "27" + } + ], + "text": "用小正方体积木拼一个大一点的正方体，至少用( )个同样大小的积木. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "用同样的大小的正方体可以拼成一个大正方体，每条棱长上至少需要2个小正方体，由此即可解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/917.json b/MathMC/917.json new file mode 100644 index 0000000000000000000000000000000000000000..2fcfdefc75f4c31b80c1cf00d556de0e7d86d8f6 --- /dev/null +++ b/MathMC/917.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "500×270" + }, + { + "bullet": "B", + "text": "50×270" + }, + { + "bullet": "C", + "text": "270×50" + } + ], + "text": "与27×500的计算结果不同的算式是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据积的变化规律的知识进行解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/918.json b/MathMC/918.json new file mode 100644 index 0000000000000000000000000000000000000000..393462a85aa84a4e22a3ef4e455c703e222e2048 --- /dev/null +++ b/MathMC/918.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3倍" + }, + { + "bullet": "B", + "text": "9倍" + }, + { + "bullet": "C", + "text": "2倍" + } + ], + "text": "把一个圆柱体削成一个最大的圆锥体，削去部分的体积是圆锥体积的( )。 " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "圆柱的体积= 圆锥的体积×3(圆柱的体积-圆锥的体积)÷圆锥的体积=2 答:削去部分的体积是圆锥体积的2倍. 故选:C 圆柱的体积是和它等底等高的圆锥体积的三倍，把圆柱削成最大的圆锥，则圆锥与圆柱等底等高，削去了两个圆锥的体积，也就是削去部分的体积是圆锥体积的2倍。" + ] + } +} \ No newline at end of file diff --git a/MathMC/919.json b/MathMC/919.json new file mode 100644 index 0000000000000000000000000000000000000000..04e62da4f7edbd99fe8660149e901266d9e3557b --- /dev/null +++ b/MathMC/919.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2x+37=283" + }, + { + "bullet": "B", + "text": "283-37=2x" + }, + { + "bullet": "C", + "text": "2x-37=283" + } + ], + "text": "手工课，五(1)班女生做了283颗幸运星，如果再做37颗，就是男生做得颗数的2倍.五(1)班男生做了多少颗幸运星?正确列方程式:( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "设男生做了x颗幸运星，女生做了283颗幸运星，如果再做37颗，就是男生做的颗数的2倍，也就是说男生做的颗数的2倍比女生做的颗数多37颗，据此可列方程:2x-37=283，依据等式的性质即可求解. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/92.json b/MathMC/92.json new file mode 100644 index 0000000000000000000000000000000000000000..3822ed397bdfc80b34c1c7def07b0fd6f928cac9 --- /dev/null +++ b/MathMC/92.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15÷ \\frac{1}{3}" + }, + { + "bullet": "B", + "text": "15× \\frac{1}{3}" + }, + { + "bullet": "C", + "text": "15÷ \\frac{1}{3}+15" + }, + { + "bullet": "D", + "text": "15× \\frac{1}{3}+15" + } + ], + "text": "六(1)班有‘三好学生‘15人，相当于全班人数的\\frac{1}{3}，全班有多少人?列式是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "15人是全班人数的\\frac{1}{3}.所以全班共有(15÷ \\frac{1}{3})人. 15÷ \\frac{1}{3}=45(人)，单位‘1‘是全班人数. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/920.json b/MathMC/920.json new file mode 100644 index 0000000000000000000000000000000000000000..d1a65228a8724445a4f2c2b48fbd9b08a82dc69b --- /dev/null +++ b/MathMC/920.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3 3 6" + }, + { + "bullet": "B", + "text": "3 7 11" + }, + { + "bullet": "C", + "text": "2.5 4.5 2" + }, + { + "bullet": "D", + "text": "8 9 10" + } + ], + "text": "下列长度的各组线段中，能围成三角形的是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "A、3+3=6，所以不能围成三角形; B、3+710，所以能围成三角形; 故选:D. 根据三角形的特性:两边之和大于第三边，三角形的两边的差一定小于第三边;进行解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/921.json b/MathMC/921.json new file mode 100644 index 0000000000000000000000000000000000000000..a406b57bfc3749cba1b360fdbccc498aaf70d17f --- /dev/null +++ b/MathMC/921.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "大于" + }, + { + "bullet": "B", + "text": "小于" + }, + { + "bullet": "C", + "text": "等于" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "等底等高的长方形和平行四边形，长方形的面积( )平行四边形的面积. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "依据长方形和平行四边形面积的计算公式:等底等高的长方形和平行四边形，长方形的面积等于平行四边形的面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/922.json b/MathMC/922.json new file mode 100644 index 0000000000000000000000000000000000000000..7e15af60ea2e565ccbb85180b4b38ed5c25ff5cb --- /dev/null +++ b/MathMC/922.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6，54" + }, + { + "bullet": "B", + "text": "7，55" + }, + { + "bullet": "C", + "text": "8，56" + } + ], + "text": "在口÷8=6…○中，○里最大填( )，口内填( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据在有余数的除法中，余数总比除数小，即余数最大为:除数-1，当余数最大时，被除数最大，进而根据‘被除数=商×除数+余数‘解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/923.json b/MathMC/923.json new file mode 100644 index 0000000000000000000000000000000000000000..fcf842261eab6fe6fc0a6534ffc9dfe43787ca4c --- /dev/null +++ b/MathMC/923.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "15÷ \\frac{1}{3}" + }, + { + "bullet": "B", + "text": "15× \\frac{1}{3}" + }, + { + "bullet": "C", + "text": "15÷ \\frac{1}{3}+15" + } + ], + "text": "六.一班有‘三好学生‘15人，相当于全班人数的 \\frac{1}{3}，全班有多少人?列式是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把全班的总人数看成单位‘1‘，它的 \\frac{1}{3}对应的数量是15人，由此用除法求出总人数." + ] + } +} \ No newline at end of file diff --git a/MathMC/924.json b/MathMC/924.json new file mode 100644 index 0000000000000000000000000000000000000000..83f0c907ad987df184b35ebda3364af7f93445d0 --- /dev/null +++ b/MathMC/924.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "135×(1+25%)" + }, + { + "bullet": "B", + "text": "135×(1-25%)" + }, + { + "bullet": "C", + "text": "135÷25%" + }, + { + "bullet": "D", + "text": "135÷(1-25%)" + } + ], + "text": "某机关现有工作人员135人，比原来精简了25%，原有工作人员多少人?列式是( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "把原有工作人员人数看作单位‘1‘，比原来精简了25%，所以现在是原来的1-25%=75%，已知现有工作人员135人，也就是135人是原来的75%，则原有工作人员135÷75%，解决问题." + ] + } +} \ No newline at end of file diff --git a/MathMC/925.json b/MathMC/925.json new file mode 100644 index 0000000000000000000000000000000000000000..f5bac28528aac462c6499cd54e5df6d195e9d5e5 --- /dev/null +++ b/MathMC/925.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "78.5%" + }, + { + "bullet": "B", + "text": "80%" + }, + { + "bullet": "C", + "text": "75%" + }, + { + "bullet": "D", + "text": "82%" + } + ], + "text": "一张边长为a厘米的正方形铝垫纸，如果从这张纸上剪下四个相同且最大的圆，那么这张纸的利用率是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "正方形的边长为a米，则纸面积为a2平方米;剪4个相等且最大的圆，则圆的半径为 a 4 米，则一个圆的面积为:π( a 4 )2= π a 2 16 ，四个圆的面积为: π a 2 4 ;这张纸的利用率是指四个圆的面积占这个正方形面积的百分之几，由此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/926.json b/MathMC/926.json new file mode 100644 index 0000000000000000000000000000000000000000..23fa2c4b4c4574a7125e150f4505dc8a65ce1c12 --- /dev/null +++ b/MathMC/926.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "相等" + }, + { + "bullet": "B", + "text": "大于" + }, + { + "bullet": "C", + "text": "小于" + } + ], + "text": "用两个同样大小的正方形拼成一个长方形，长方形的周长( )两个正方形的和. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "两个正方形拼成一个长方形，得到的长方形的周长比原来的两个正方形的周长之和减少了2条正方形的边长的长度，所以得到的长方形的周长小于原来两个正方形的周长之和，据此即可选择." + ] + } +} \ No newline at end of file diff --git a/MathMC/927.json b/MathMC/927.json new file mode 100644 index 0000000000000000000000000000000000000000..7be488c40de9623916de27e52a7bad4839a4eff6 --- /dev/null +++ b/MathMC/927.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60平方厘米" + }, + { + "bullet": "B", + "text": "30平方厘米" + }, + { + "bullet": "C", + "text": "17平方厘米" + }, + { + "bullet": "D", + "text": "不知四个三角形的底边长度，无法计算" + } + ], + "text": "如图，长方形的长12CM，宽5CM，阴影的面积是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "阴影部分分为4个三角形，这4个三角形底的和为长方形的长12CM，高为长方形的长宽5CM，运用三角形的面积解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/928.json b/MathMC/928.json new file mode 100644 index 0000000000000000000000000000000000000000..598d670d30f22160bad2a6a26702b9285ac996be --- /dev/null +++ b/MathMC/928.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "18" + }, + { + "bullet": "C", + "text": "20" + } + ], + "text": "选择.(将正确答案的序号填在括号里) (5)在算式260÷20中，如果被除数除以10，要使商不变，除数应减少( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由规律可知，商不变被除数除以10，除数也应除以10，再通过比较计算." + ] + } +} \ No newline at end of file diff --git a/MathMC/929.json b/MathMC/929.json new file mode 100644 index 0000000000000000000000000000000000000000..a20cb01699c149e9db32f0fa5a01e45b12dacf2a --- /dev/null +++ b/MathMC/929.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "直线" + }, + { + "bullet": "B", + "text": "射线" + }, + { + "bullet": "C", + "text": "线段" + } + ], + "text": "从一点引出两条( )所组成的图形叫做角. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据角的意义:由一点引出两条射线所组成的图形叫做角.直接进行选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/93.json b/MathMC/93.json new file mode 100644 index 0000000000000000000000000000000000000000..94b06fbd5d1165e361655f7fe502325b3fd75ef1 --- /dev/null +++ b/MathMC/93.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "6" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "96" + } + ], + "text": "既是2的倍数，又是3的倍数的最小两位数是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "这个数要满足:既是2的倍数，又是3的倍数，还是两位数，最小是多少，6是一位数，96是符合条件的最大的两位数." + ] + } +} \ No newline at end of file diff --git a/MathMC/930.json b/MathMC/930.json new file mode 100644 index 0000000000000000000000000000000000000000..4fe401f070aa6ee5aa9d83f6f403f1a71702561c --- /dev/null +++ b/MathMC/930.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "两个奇数的和一定是奇数." + }, + { + "bullet": "B", + "text": "两个质数的和一定是质数." + }, + { + "bullet": "C", + "text": "两个偶数的和一定是偶数." + }, + { + "bullet": "D", + "text": "两个合数的和一定是合数." + } + ], + "text": "下列四种说法中，( )是正确的. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "奇数和奇数相加和是偶数，奇数和偶数相加和是奇数，偶数和偶数相加和是偶数;质数的因数只有1和它本身，最小的质数是2;合数的因数除了1和它本身，还有其他因数." + ] + } +} \ No newline at end of file diff --git a/MathMC/931.json b/MathMC/931.json new file mode 100644 index 0000000000000000000000000000000000000000..8afee944f00911a6dd53c772e6b7d7aebf7c5f65 --- /dev/null +++ b/MathMC/931.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "缩小到原来的 1/10000" + }, + { + "bullet": "B", + "text": "扩大到原来的10000倍" + }, + { + "bullet": "C", + "text": "缩小到原来的 1/1000" + } + ], + "text": "一个非零自然数除以0.0001，表示把这个自然数( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "这道题考的是小数和分数的互化以及除数是小数的意义，0.000 1= 1 10 000，所以排除C.一个非零自然数除以一个分数，相当于乘以这样数的倒数.假设这个非零的自然数是1，1÷0.000 1=1×10 000=10 000，将1与10 000进行对比可知." + ] + } +} \ No newline at end of file diff --git a/MathMC/932.json b/MathMC/932.json new file mode 100644 index 0000000000000000000000000000000000000000..85b5f202798f54f8506204ed8de2bc0a932d2c96 --- /dev/null +++ b/MathMC/932.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减去3" + }, + { + "bullet": "B", + "text": "减去2" + }, + { + "bullet": "C", + "text": "减去1" + } + ], + "text": "从625中至少减去( )才能被3整除. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "6+2+5=13，12是3的倍数，13-1=12， 故从625中至少减去1才能被3整除. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/933.json b/MathMC/933.json new file mode 100644 index 0000000000000000000000000000000000000000..d696c1bdfde7c6976bea360f0ddb9f0c4c802a49 --- /dev/null +++ b/MathMC/933.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "926183" + }, + { + "bullet": "B", + "text": "936185" + }, + { + "bullet": "C", + "text": "926187" + }, + { + "bullet": "D", + "text": "926189" + } + ], + "text": "173×173×173-162×162×162的计算结果为 ( ) " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "选项四个数的尾数各不相同，直接计算各项尾数，3×3×3-2×2×2=27-8=19;可知，计算结果的尾数应该是9，因此只能选D." + ] + } +} \ No newline at end of file diff --git a/MathMC/934.json b/MathMC/934.json new file mode 100644 index 0000000000000000000000000000000000000000..3c7693cc980cb9f65bed311004a8ce39787835af --- /dev/null +++ b/MathMC/934.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "", + "text": "a+0=0" + }, + { + "bullet": "", + "text": "a÷0=0" + }, + { + "bullet": "", + "text": "0×a=0" + } + ], + "text": "下列有关0的运算，正确的是 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据‘在加法中，一个数加上0，还得原数;在乘法中，一个数和0相乘，仍得0;在除法中，0除以一个不为0的数，还得0，‘可知a+0=0，a÷0=0是错误的，0×a=0是正确的，所以应选C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/935.json b/MathMC/935.json new file mode 100644 index 0000000000000000000000000000000000000000..43fe6a86ddfb685ffaf8a107ef4581625d09c7ea --- /dev/null +++ b/MathMC/935.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "一定是质数" + }, + { + "bullet": "B", + "text": "一定是合数" + }, + { + "bullet": "C", + "text": "可能是质数，也可能是合数" + } + ], + "text": "两个质数的和( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "100以内的质数有:2、3、5、7、11、13、17··· 等， 例如2+3=5，5是质数;3+5=8，8是合数; 所以两个质数的和可能是质数，也可能是合数. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/936.json b/MathMC/936.json new file mode 100644 index 0000000000000000000000000000000000000000..e6608898c23173d9e7622b40ece3644f82b54314 --- /dev/null +++ b/MathMC/936.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "倍数" + }, + { + "bullet": "B", + "text": "质数" + }, + { + "bullet": "C", + "text": "合数" + }, + { + "bullet": "D", + "text": "因数" + } + ], + "text": "因为56 = 7×8，所以7和8都是56的( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "这是一道选择题，题目给出的已知条件是‘56 = 7×8‘，问7和8都是56的什么数，根据倍数、因数的意义， 整数a除以整数b等于整数c，那么我们就可以说整数c和整数b是整数a的因数，整数a是整数c和整数b的倍数." + ] + } +} \ No newline at end of file diff --git a/MathMC/937.json b/MathMC/937.json new file mode 100644 index 0000000000000000000000000000000000000000..78933e92798c7a2aeb81b2b16f4d8bd3f18c26a8 --- /dev/null +++ b/MathMC/937.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "3亿" + }, + { + "bullet": "B", + "text": "30亿" + }, + { + "bullet": "C", + "text": "300亿" + } + ], + "text": "2997806000省略亿位后面的尾数，再写出近似数( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "省略亿位后面的尾数求近似数，根据千万位上数字的大小确定用‘四舍‘法、还是用‘五入‘法.省略尾数后同时写上‘亿‘字.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/938.json b/MathMC/938.json new file mode 100644 index 0000000000000000000000000000000000000000..f38ef9489fc8e728cfc050e7b96de2527192e1b4 --- /dev/null +++ b/MathMC/938.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "条形统计图" + }, + { + "bullet": "B", + "text": "统计表" + }, + { + "bullet": "C", + "text": "折线统计图" + } + ], + "text": "统计2010年家乡的气温增减变化情况应选用( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/939.json b/MathMC/939.json new file mode 100644 index 0000000000000000000000000000000000000000..aa28d79c18d64d8ae0d3dcd8f5b0999f0d2b10ce --- /dev/null +++ b/MathMC/939.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "平衡" + }, + { + "bullet": "B", + "text": "对称" + }, + { + "bullet": "C", + "text": "旋转" + } + ], + "text": "拧开矿泉水瓶盖是做( )运动. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "将一个图形上的所有点都按照某个方向作相同距离的移动，这样的图形运动叫作图形的平移运动;把一个图形绕着某一点O转动一个角度的图形变换叫做旋转;据此解答即可. 根据旋转的意义可知:拧开矿泉水瓶盖是做旋转运动. 故选:C." + ] + } +} \ No newline at end of file diff --git a/MathMC/94.json b/MathMC/94.json new file mode 100644 index 0000000000000000000000000000000000000000..1f981b0afc88bde37dddbe8aae3b168cfbf6d8e3 --- /dev/null +++ b/MathMC/94.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "(100+20)÷ \\frac{3}{8}" + }, + { + "bullet": "B", + "text": "(100-20)÷ \\frac{3}{8}" + }, + { + "bullet": "C", + "text": "100÷(1- \\frac{3}{8} )+20" + } + ], + "text": "某校六年级学生有100人，比全校总人数的 \\frac{3}{8}少20人，求全校有多少人.列式为( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据‘100人比全校总人数的 \\frac{3}{8}少20人，‘可知:100人加上20人正好占全校总人数的 \\frac{3}{8}，求全校总人数这个单位‘1‘，用除法计算，列式为:(100+20)÷ \\frac{3}{8}，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/940.json b/MathMC/940.json new file mode 100644 index 0000000000000000000000000000000000000000..b3f714c531dfe980f10a4343e0b357fe944c401d --- /dev/null +++ b/MathMC/940.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲车快" + }, + { + "bullet": "B", + "text": "乙车快" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "从A地到达B地，甲车4小时行了全程的 1 5，乙车5小时行了全程的 1 4，两车的速度相比( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "从题意可知，把总路程看成单位‘1‘，那么全程的 1 5就是1× 1 5= 1 5，所以甲的速度就是 1 5÷4= 1 5× 1 4= 1 20，乙的速度就是 1 4÷5= 1 20，所以两人的速度一样。" + ] + } +} \ No newline at end of file diff --git a/MathMC/941.json b/MathMC/941.json new file mode 100644 index 0000000000000000000000000000000000000000..a7321961ff36751cb799ae55e3dfc6b62210a851 --- /dev/null +++ b/MathMC/941.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "A÷1.5" + }, + { + "bullet": "B", + "text": "A÷0.5" + }, + { + "bullet": "C", + "text": "A÷0.9" + }, + { + "bullet": "D", + "text": "A÷1" + } + ], + "text": "选择题.(将正确答案的序号填在括号里) 下面除法算式中，A表示大于0的数，那么商最大的算式是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据题意得知判断商的大小，在被除数是比0大时，被除数不变，除数越大商越小，除数越小商越大，由此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/942.json b/MathMC/942.json new file mode 100644 index 0000000000000000000000000000000000000000..5bf80c1769caa64b581ebac1d0c6903b0567bc07 --- /dev/null +++ b/MathMC/942.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "0.02" + }, + { + "bullet": "B", + "text": "0.2" + }, + { + "bullet": "C", + "text": "0.002" + } + ], + "text": "把一个小数的小数点先向右移动两位，再向左移动三位，结果是0.02，这个小数原来是( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "小数点位置移动引起数的大小变化规律，把一个小数的小数点先向右移动两位，再向左移动三位，这个数实际比原数缩小了10倍，据此解答. 把一个小数的小数点先向右移动两位，再向左移动三位，结果是0.02，这个小数原来是0.2. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/943.json b/MathMC/943.json new file mode 100644 index 0000000000000000000000000000000000000000..9ebd0795e74d4af10575b01ca773ce62318472cd --- /dev/null +++ b/MathMC/943.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "5+3" + }, + { + "bullet": "B", + "text": "5×5" + }, + { + "bullet": "C", + "text": "5×3" + } + ], + "text": "5个3相加的和是多少，列式是 ( )。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "求5个3相加的和是多少，用(5×3)进行计算。 故选:C。" + ] + } +} \ No newline at end of file diff --git a/MathMC/944.json b/MathMC/944.json new file mode 100644 index 0000000000000000000000000000000000000000..d3cb3fe3d10177b8947b75ca2d92410cdcf1df64 --- /dev/null +++ b/MathMC/944.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "400平方厘米" + }, + { + "bullet": "B", + "text": "80平方厘米" + }, + { + "bullet": "C", + "text": "6400平方厘米" + }, + { + "bullet": "D", + "text": "不确定" + } + ], + "text": "把一根80厘米长的铁丝围成一个正方形，这个正方形的面积是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "先依据正方形的周长公式S=4a计算出正方形的边长，再根据正方形的面积公式S=a×a即可求出这个正方形的面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/945.json b/MathMC/945.json new file mode 100644 index 0000000000000000000000000000000000000000..2504813a225e785c65df39ea8a8e2aa0d9ac28e6 --- /dev/null +++ b/MathMC/945.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "295×42" + }, + { + "bullet": "B", + "text": "321×22" + }, + { + "bullet": "C", + "text": "596×19" + }, + { + "bullet": "D", + "text": "187×49" + } + ], + "text": "估一估，下列算式中得数小于8000的是( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "分别估算三个选项中的算式的积，选出正确的一个即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/946.json b/MathMC/946.json new file mode 100644 index 0000000000000000000000000000000000000000..9789756019dc7f427a9f47ebd2390254840dd282 --- /dev/null +++ b/MathMC/946.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "整数" + }, + { + "bullet": "B", + "text": "小数" + }, + { + "bullet": "C", + "text": "带分数" + }, + { + "bullet": "D", + "text": "真分数" + } + ], + "text": "所有的( )的倒数都大于1. " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "根据倒数的意义:乘积是1的两个数互为倒数，依此即可得到真分数的倒数大于1." + ] + } +} \ No newline at end of file diff --git a/MathMC/947.json b/MathMC/947.json new file mode 100644 index 0000000000000000000000000000000000000000..293313f35c09870303caf913f787b13193cd8b4d --- /dev/null +++ b/MathMC/947.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "280099" + }, + { + "bullet": "B", + "text": "280200" + }, + { + "bullet": "C", + "text": "279820" + }, + { + "bullet": "D", + "text": "284500" + } + ], + "text": "选择:下面各数‘四舍五入‘后都得到28万，其中( )最接近28万. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "计算出各选项中的准确数与近似数28万相差多少，进而选出最接近28万的数即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/948.json b/MathMC/948.json new file mode 100644 index 0000000000000000000000000000000000000000..a244b2b446e38f77460ac12c8f892837c4336246 --- /dev/null +++ b/MathMC/948.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "奇数" + }, + { + "bullet": "B", + "text": "质数" + }, + { + "bullet": "C", + "text": "互质数" + } + ], + "text": "最简分数的分子和分母一定是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据最简分数的意义:分子和分母是互质数的分数叫做最简分数，即可知道答案." + ] + } +} \ No newline at end of file diff --git a/MathMC/949.json b/MathMC/949.json new file mode 100644 index 0000000000000000000000000000000000000000..e7ebadc4aa47a8b48427aca60183a1be19aca19d --- /dev/null +++ b/MathMC/949.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "亿位与百万位" + }, + { + "bullet": "B", + "text": "亿与百万" + }, + { + "bullet": "C", + "text": "亿位与十亿位" + } + ], + "text": "与千万位相邻的两个数位分别是( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "根据数位顺序表:从右向左依次分:个位、十位、百位、千位、万位、十万位、百万位、千万位、亿位、十亿位、…;可知:与千万位相邻的两个数位是百万位和亿位;据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/95.json b/MathMC/95.json new file mode 100644 index 0000000000000000000000000000000000000000..d64d1b3790533fee369f98d4107af334ddae5333 --- /dev/null +++ b/MathMC/95.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "7.5" + }, + { + "bullet": "B", + "text": "7" + }, + { + "bullet": "C", + "text": "8" + }, + { + "bullet": "D", + "text": "8.5" + } + ], + "text": "扎一束鲜花需要0.4米长的丝带，一段3米长的丝带可以扎( )束鲜花. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "此题是对实际问题的考查，求可以扎多少花，应该用总的线的长度除以扎每一束鲜花用的丝带的长度." + ] + } +} \ No newline at end of file diff --git a/MathMC/950.json b/MathMC/950.json new file mode 100644 index 0000000000000000000000000000000000000000..f3f968b1635891702a4dc783631bc8cc2b99bd15 --- /dev/null +++ b/MathMC/950.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{5}{2}÷ \\frac{5}{24}" + }, + { + "bullet": "B", + "text": "\\frac{5}{24}÷ \\frac{5}{2}" + }, + { + "bullet": "C", + "text": "\\frac{5}{2}× \\frac{5}{24}" + } + ], + "text": "李叔叔的小汽车行驶\\frac{5}{2}千米用了\\frac{5}{24}L汽油，平均每千米需要用汽油多少升?列式为( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "王叔叔的小汽车行驶\\frac{5}{2}千米，用了\\frac{5}{24}L汽油， 根据除法的意义，用所用汽油升数除以所行里程， 即得平均每千米用多少升汽油解答\\frac{5}{24}÷ \\frac{5}{2}=\\frac{5}{24}× \\frac{2}{5}=112升， 因此平均每千米用\\frac{5}{24}÷ \\frac{5}{2}升汽油. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/951.json b/MathMC/951.json new file mode 100644 index 0000000000000000000000000000000000000000..43c78a2bfd43665656f5e93d8c97b8aae62f30ba --- /dev/null +++ b/MathMC/951.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "300米" + }, + { + "bullet": "B", + "text": "200米" + }, + { + "bullet": "C", + "text": "500米" + } + ], + "text": "体育馆在学校北偏东45°的方向上300米处，儿童公园在学校西偏南45°的方向上200米处，那么儿童公园与体育馆相距( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据题意可知，北偏东45°的方向与西偏南45°的方向在一条直线上，也就是体育馆、学校、儿童公园在一条直线上，体育馆到学校300米加上儿童公园到学校的200米，就是儿童公园与体育馆的距离." + ] + } +} \ No newline at end of file diff --git a/MathMC/952.json b/MathMC/952.json new file mode 100644 index 0000000000000000000000000000000000000000..588b483d996a5ce3d10599641ab8aeff159c723d --- /dev/null +++ b/MathMC/952.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "-\\frac{7}{3}" + }, + { + "bullet": "B", + "text": "0" + }, + { + "bullet": "C", + "text": "1" + }, + { + "bullet": "D", + "text": "\\frac{5}{7}" + } + ], + "text": "计算 -1\\frac{1}{7}× ( {\\frac{7}{8}+1\\frac{3}{4}-\\frac{7}{12}} ) 的结果是( )" + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "解:原式=- \\frac{8}{7}× \\frac{7}{8}-\\frac{8}{7}× \\frac{7}{4}-\\frac{8}{7}× ( {-\\frac{7}{12}} )=-1-2+ \\frac{2}{3}=- \\frac{7}{3}. 故选:A." + ] + } +} \ No newline at end of file diff --git a/MathMC/953.json b/MathMC/953.json new file mode 100644 index 0000000000000000000000000000000000000000..007ceed7a8bd7282b1aa3b6d432328731650905a --- /dev/null +++ b/MathMC/953.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "第一块地大" + }, + { + "bullet": "B", + "text": "第二块地大" + }, + { + "bullet": "C", + "text": "一样大" + } + ], + "text": "有两块长方形地，第一块地的面积是12公顷，第二块地的长是400米，宽是300米，这两块地的面积相比( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "400× 300=120000(平方米)， 120000平方米=12公顷， 12=12， 所以这两块地的面积相等. 故选C." + ] + } +} \ No newline at end of file diff --git a/MathMC/954.json b/MathMC/954.json new file mode 100644 index 0000000000000000000000000000000000000000..cbb95ac4b21555edc2a1303a2f0b4e06ac45fd3c --- /dev/null +++ b/MathMC/954.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "不变" + }, + { + "bullet": "B", + "text": "变大" + }, + { + "bullet": "C", + "text": "变小" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "把一个长方体切成两个相等的正方体，表面积之和( )" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "由题意可知:一个长方体切成两个大小相等的正方体后，增加了两个面，所以表面积就增加了,据此解答即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/955.json b/MathMC/955.json new file mode 100644 index 0000000000000000000000000000000000000000..2a5ea37d1a04d715eec331a854df84ba251ed00c --- /dev/null +++ b/MathMC/955.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "\\frac{4}{5}是倒数" + }, + { + "bullet": "B", + "text": "\\frac{5}{4}是倒数" + }, + { + "bullet": "C", + "text": "\\frac{4}{5}与 \\frac{5}{4}互为倒数" + } + ], + "text": "因为 \\frac{4}{5}× \\frac{5}{4}=1，所以( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "根据倒数的意义，乘积是1的两个数互为倒数.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/956.json b/MathMC/956.json new file mode 100644 index 0000000000000000000000000000000000000000..294fc6a1fcafb98e70889fcc2f7c387506094fd8 --- /dev/null +++ b/MathMC/956.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "扇形统计图" + }, + { + "bullet": "B", + "text": "条形统计图" + }, + { + "bullet": "C", + "text": "折线统计图" + }, + { + "bullet": "D", + "text": "都可以" + } + ], + "text": "为了清楚地看出一个月的天气变化情况，最好选用( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/957.json b/MathMC/957.json new file mode 100644 index 0000000000000000000000000000000000000000..79320cdb74a88359c22f5889c3d4ec734a491e0b --- /dev/null +++ b/MathMC/957.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "小明" + }, + { + "bullet": "B", + "text": "小芳" + }, + { + "bullet": "C", + "text": "吴昊" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "学校举行100米赛跑，小明用了分钟，小芳用了分钟，吴昊用了分钟.跑得最快的是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "比较小明、小芳、吴昊所用时间的大小，然后根据路程÷时间=速度，判断谁跑得快一些即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/958.json b/MathMC/958.json new file mode 100644 index 0000000000000000000000000000000000000000..f0fefd1ee927c65d4d4f7f084adc2d7947d11e0d --- /dev/null +++ b/MathMC/958.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "60+70" + }, + { + "bullet": "B", + "text": "(60+70)×5" + }, + { + "bullet": "C", + "text": "60×5" + }, + { + "bullet": "D", + "text": "70×5" + } + ], + "text": "小芳和小军放学后从学校同时回家，小芳每分钟行60米，小军每分钟行70米，5分钟后同时到家.小芳家到小军家的距离列式为( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "小芳每分钟行60米，5分钟到家，小芳家离学校的距离为60×5，同理，小军家离学校的距离是70×5.要求小芳家到小军家的距离，把这两部分加起来即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/959.json b/MathMC/959.json new file mode 100644 index 0000000000000000000000000000000000000000..63d0885036bbb3bf85821124405d3ef6609cc324 --- /dev/null +++ b/MathMC/959.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "成正比例关系" + }, + { + "bullet": "B", + "text": "成反比例关系" + }, + { + "bullet": "C", + "text": "不成比例关系" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "平行四边形的面积一定，底边和它对应的高( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "{{S}_{平行四边形}}=底× 高，当面积一定，底和对应高成反比例关系. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/96.json b/MathMC/96.json new file mode 100644 index 0000000000000000000000000000000000000000..2067af6bbfe8b4a70780ea531a8b0e828b59484d --- /dev/null +++ b/MathMC/96.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2/7" + }, + { + "bullet": "B", + "text": "7/4" + }, + { + "bullet": "C", + "text": "4/7" + }, + { + "bullet": "D", + "text": "4/9" + } + ], + "text": "在计算乘法时，不慎将乘数63写成36，那么计算结果是正确答案的( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "其中一个因数不变，另一个因数由63变成36，求出36是63的几分之几，那么计算结果就是正确答案的几分之几." + ] + } +} \ No newline at end of file diff --git a/MathMC/960.json b/MathMC/960.json new file mode 100644 index 0000000000000000000000000000000000000000..38c5cc962aa3da45d815b14845dafc16b043cad8 --- /dev/null +++ b/MathMC/960.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "94" + }, + { + "bullet": "B", + "text": "96" + }, + { + "bullet": "C", + "text": "98" + } + ], + "text": "一个两位数，个位和十位上的数字都是合数，并且互质，这个数最大是 ()。" + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "个位和十位上的数字都是合数，因此个位和十位上的数字必须是4、6、8、9中的一个。而且它们必须是互质的，因此个位和十位上的数字不能都是偶数，且不能相同，为了使这个数更大，则十位应该是9，这个数最大是98." + ] + } +} \ No newline at end of file diff --git a/MathMC/961.json b/MathMC/961.json new file mode 100644 index 0000000000000000000000000000000000000000..9182003e4bbc387694413e48b72d37522a7cf00e --- /dev/null +++ b/MathMC/961.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "折线统计图" + }, + { + "bullet": "B", + "text": "条形统计图" + }, + { + "bullet": "C", + "text": "扇形统计图" + } + ], + "text": "商店要表示一年来营业额的变化情况，不宜选用的统计图是( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/962.json b/MathMC/962.json new file mode 100644 index 0000000000000000000000000000000000000000..413a221c51e3ac0beebbe7ea87c9fab2912a0600 --- /dev/null +++ b/MathMC/962.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "百位" + }, + { + "bullet": "B", + "text": "千位" + }, + { + "bullet": "C", + "text": "万位" + } + ], + "text": "36×27的积的最高位是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "想要知道36×27的积的最高位是哪一位，只要根据两位数乘两位数的方法，将36×27计算出结果，根据结果就可知道最高位是哪一位." + ] + } +} \ No newline at end of file diff --git a/MathMC/963.json b/MathMC/963.json new file mode 100644 index 0000000000000000000000000000000000000000..83de6445c30425d659f670d2dde890baa8661577 --- /dev/null +++ b/MathMC/963.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "平移现象" + }, + { + "bullet": "B", + "text": "旋转现象" + }, + { + "bullet": "C", + "text": "以上都不属于" + } + ], + "text": "打开教室门属于( ). " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "打开教室门属于旋转现象. 故选B." + ] + } +} \ No newline at end of file diff --git a/MathMC/964.json b/MathMC/964.json new file mode 100644 index 0000000000000000000000000000000000000000..aeb893676c444d0d573b379c451e05f087e47581 --- /dev/null +++ b/MathMC/964.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "成正比例" + }, + { + "bullet": "B", + "text": "反比例" + }, + { + "bullet": "C", + "text": "不成比例" + } + ], + "text": "车轮的直径一定，所行驶的路程和车轮的转数( ) " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "判断行驶的路程和哪个相关联的量成正比例，就看所行驶的路程与哪个相关联的量对应的比值一定，如果是比值一定，就成正比例，如果不是比值一定或比值不一定，就不成正比例." + ] + } +} \ No newline at end of file diff --git a/MathMC/965.json b/MathMC/965.json new file mode 100644 index 0000000000000000000000000000000000000000..91cc33651ee2892d9fa484ade898e0816b7b0f77 --- /dev/null +++ b/MathMC/965.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20" + }, + { + "bullet": "B", + "text": "25" + }, + { + "bullet": "C", + "text": "30" + }, + { + "bullet": "D", + "text": "35" + } + ], + "text": "我县县城1路公共汽车10分钟开出一辆，2路公共汽车15分钟开出一辆，这两路车同时开出一辆后，至少再过( )分钟这两路车又同时出发. " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "1路公共汽车每隔10分钟开出一辆，2路公共汽车每隔15分钟开出一辆，10和15的最小公倍数为30，这两路车同时开出一辆后，至少再过30分钟会同时发车." + ] + } +} \ No newline at end of file diff --git a/MathMC/966.json b/MathMC/966.json new file mode 100644 index 0000000000000000000000000000000000000000..a286770b113a35967b67d36b6a50d0228621adc5 --- /dev/null +++ b/MathMC/966.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "10" + }, + { + "bullet": "B", + "text": "12" + }, + { + "bullet": "C", + "text": "14" + }, + { + "bullet": "D", + "text": "16" + } + ], + "text": "将一根木棒锯成4段需要6分钟，则将这根木棒锯成7段，需要( )分钟. " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "6÷(4-1)×(7-1)， =2×6， =12(分)钟; 答:将这根木棒锯成7段，需要12分钟. 故选:B. 锯的4段次数是:4-1=3次，锯每段的时间是:6÷3=2分钟;将这根木棒锯成7段，锯的次数是:7-1=6次，求需要的时间列式为:2×6=12分钟，据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/967.json b/MathMC/967.json new file mode 100644 index 0000000000000000000000000000000000000000..22c78947c3cb44116d05e30b5586e6476dc1a0c4 --- /dev/null +++ b/MathMC/967.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "", + "text": "6" + }, + { + "bullet": "", + "text": "3" + }, + { + "bullet": "", + "text": "9" + } + ], + "text": "一个正方体的表面积是54平方厘米，它的棱长是 ( )厘米。" + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "正方体的6个面是完全相同的正方形，所以每个面的面积是54÷6=9(平方厘米)，3×3=9(平方厘米)，因此棱长是3厘米。 故应选:B。" + ] + } +} \ No newline at end of file diff --git a/MathMC/968.json b/MathMC/968.json new file mode 100644 index 0000000000000000000000000000000000000000..7704ae9c555022fbc04f483176ec7a31d1238b10 --- /dev/null +++ b/MathMC/968.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "减去9" + }, + { + "bullet": "B", + "text": "除以9" + }, + { + "bullet": "C", + "text": "除以4" + } + ], + "text": "如果把 \\frac{12}{16}的分子减去9，要使分数的大小不变，分母应( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "依据分数的基本性质，即分数的分子和分母同时乘上或除以相同的数(0除外)，分数的大小不变，从而可以正确进行作答." + ] + } +} \ No newline at end of file diff --git a/MathMC/969.json b/MathMC/969.json new file mode 100644 index 0000000000000000000000000000000000000000..7d38dce35987f099bcfc472c3276865ebec97ad1 --- /dev/null +++ b/MathMC/969.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "2000" + }, + { + "bullet": "B", + "text": "4000" + }, + { + "bullet": "C", + "text": "6000" + } + ], + "text": "51×79的积大约是几千( ) " + }, + "quest_ref": { + "texts": [ + "B" + ], + "analyses": [ + "根据估算的计算方法，把51看作50，79看作80进行计算即可." + ] + } +} \ No newline at end of file diff --git a/MathMC/97.json b/MathMC/97.json new file mode 100644 index 0000000000000000000000000000000000000000..2b9531fa74abd19a33844f557d34dea09e95ed26 --- /dev/null +++ b/MathMC/97.json @@ -0,0 +1,28 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "四位数" + }, + { + "bullet": "B", + "text": "五位数" + }, + { + "bullet": "C", + "text": "四位数或五位数" + } + ], + "text": "两位数乘三位数，积可能是( ). " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "可用举例的方法进行解答，用最小的两位数和三位数相乘可确定两位数乘三位数的积最少是几位，用最大的两位数与三位数相乘，可确定积最多是几位数.据此解答." + ] + } +} \ No newline at end of file diff --git a/MathMC/970.json b/MathMC/970.json new file mode 100644 index 0000000000000000000000000000000000000000..6e9b868a912b453503eff67403a25b1789fbb030 --- /dev/null +++ b/MathMC/970.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲" + }, + { + "bullet": "B", + "text": "乙" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "无法比较" + } + ], + "text": "甲、乙两人进行百米赛跑，甲用了\\frac{1}{5}分钟，乙用了0.3分钟.跑得快的是( ). " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "百米赛跑，用时短的跑的快，甲用了\\frac{1}{5}=0.2分钟，乙用了0.3分钟，所以甲跑得快. 故选A." + ] + } +} \ No newline at end of file diff --git a/MathMC/971.json b/MathMC/971.json new file mode 100644 index 0000000000000000000000000000000000000000..e7e1286942a94c8e903691ccaa93e9449b496cbf --- /dev/null +++ b/MathMC/971.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "20厘米" + }, + { + "bullet": "B", + "text": "20平方厘米" + }, + { + "bullet": "C", + "text": "25厘米" + }, + { + "bullet": "D", + "text": "25平方厘米" + } + ], + "text": "一个正方形的边长是5厘米.它的面积是( ). " + }, + "quest_ref": { + "texts": [ + "D" + ], + "analyses": [ + "已知一个正方形的边长是5厘米，求它的面积是多少.根据正方形的面积=边长×边长，代入数据即可求出这个正方形的面积." + ] + } +} \ No newline at end of file diff --git a/MathMC/972.json b/MathMC/972.json new file mode 100644 index 0000000000000000000000000000000000000000..191090eb5574656ac400990d92a89a1b96a510d8 --- /dev/null +++ b/MathMC/972.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "甲车快" + }, + { + "bullet": "B", + "text": "乙车快" + }, + { + "bullet": "C", + "text": "一样快" + }, + { + "bullet": "D", + "text": "无法确定" + } + ], + "text": "两车从A地开往B地，甲车4小时行了全程的，乙车5小时行了全程的，两车的速度相比，( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "把全程看作单位‘1‘，根据速度=路程÷时间，分别求出甲车和乙车的速度，比较分数的大小，即可得解." + ] + } +} \ No newline at end of file diff --git a/MathMC/973.json b/MathMC/973.json new file mode 100644 index 0000000000000000000000000000000000000000..114c60bf1bcaebca9d352b6f7bc9e2c4bdd93202 --- /dev/null +++ b/MathMC/973.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "90" + }, + { + "bullet": "B", + "text": "93" + }, + { + "bullet": "C", + "text": "89" + }, + { + "bullet": "D", + "text": "85" + } + ], + "text": "小星看一本课外书，第一天看了全书的，第二天看了全书的，两天一共看了33页.这本书有( )页. " + }, + "quest_ref": { + "texts": [ + "A" + ], + "analyses": [ + "把这本书的总页数看作单位‘1‘，则两天一共看的分率之和为:，对应两天一共看了33页，运用除法即可求出这本书的总页数." + ] + } +} \ No newline at end of file diff --git a/MathMC/974.json b/MathMC/974.json new file mode 100644 index 0000000000000000000000000000000000000000..4bde315ac08d300ca02024be5999cc71df385bbf --- /dev/null +++ b/MathMC/974.json @@ -0,0 +1,32 @@ +{ + "qtype": "CHOICE", + "quest_stem": { + "options": [ + { + "bullet": "A", + "text": "比1平方米小" + }, + { + "bullet": "B", + "text": "正好1平方米" + }, + { + "bullet": "C", + "text": "比1平方米大" + }, + { + "bullet": "D", + "text": "无法判断" + } + ], + "text": "两块面积相等的花布和白布，把花布剪去，白布剪去平方米，剩下的花布比白布少.原来这两块布料的面积( ) " + }, + "quest_ref": { + "texts": [ + "C" + ], + "analyses": [ + "设这块布的面积为x平方米，那么剪去后，花布剩下(1-)x平方米，白布剩下(x-)平方米，由题意得:(1-)x