diff --git a/MathToF/0.json b/MathToF/0.json
new file mode 100644
index 0000000000000000000000000000000000000000..be1c8a52e063180d9bf76c4decf9eb9b83210b63
--- /dev/null
+++ b/MathToF/0.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分子和分母是不同的质数，这个分数一定是最简分数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "最简分数的意义:分子分母是互质数的分数就是最简分数，据此分析判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/1.json b/MathToF/1.json
new file mode 100644
index 0000000000000000000000000000000000000000..e23d4d52b6defeebf98090f6959b1efb4b5fe29e
--- /dev/null
+++ b/MathToF/1.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体的棱长之和是18米，从一个顶点出发的三条棱长度之和是45分米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在长方体中从一个顶点出发的三条棱的长度分别叫做长、宽、高，根据长方体的棱长总和=(长+宽+高)×4，所以用棱长总和除以4即可求出长、宽、高的和.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/10.json b/MathToF/10.json
new file mode 100644
index 0000000000000000000000000000000000000000..bece9a61cb94002ff454c1e7f3ac602ca9161994
--- /dev/null
+++ b/MathToF/10.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "面朝北方时，你的左手边是西方。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据方向的初步认识相关知识点。上北下南左西右东，当面朝北方时，后面是南，左面是西，右面是东。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/100.json b/MathToF/100.json
new file mode 100644
index 0000000000000000000000000000000000000000..4d183647e4766619e6329725af24bef35ea6dac8
--- /dev/null
+++ b/MathToF/100.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "294-86+14=294-100"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "294-86+14按照从左到右的顺序计算出结果，再与294-100的结果比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/101.json b/MathToF/101.json
new file mode 100644
index 0000000000000000000000000000000000000000..49b7b7596884752b1899564101fd98088431eb0d
--- /dev/null
+++ b/MathToF/101.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "中央电视台的《新闻联播》节目在每天的19时首播"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "中央电视台每天首次‘新闻联播‘的开始时间是晚上7:00，用24时计时法表示是19时，即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/102.json b/MathToF/102.json
new file mode 100644
index 0000000000000000000000000000000000000000..4ed6f791800667e75de1f3ba1119b29ff4e6213d
--- /dev/null
+++ b/MathToF/102.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方体的棱长是6厘米，它的表面积和体积相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正方体的表面积是指它的6个面的总面积;正方体的体积是指它所占空间的大小;正方体的表面积和体积单位不相同，没法比较它们的大小，由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/103.json b/MathToF/103.json
new file mode 100644
index 0000000000000000000000000000000000000000..db925668a36e9f753c75dcc873bf15a9d64a643d
--- /dev/null
+++ b/MathToF/103.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{12}{16}的分子增加6，要使分数大小不变，分母也应增加6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数性质的内容，直接进行填空解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/104.json b/MathToF/104.json
new file mode 100644
index 0000000000000000000000000000000000000000..d84701d5d0a3f96ed0caa5884b3b9768cb7655d9
--- /dev/null
+++ b/MathToF/104.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个等腰三角形的一个底角是a度，它的顶角是(180-2a)度."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分析:根据根据三角形的内角和是180°，两个底角相等，然后用180°减去两个a°，就是顶角，然后判断即可. 解答:180-a×2， =180-2a(度); 故答案为:正确. 点评:本题考查了三角形的内角和定理和等腰三角形的特征."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/105.json b/MathToF/105.json
new file mode 100644
index 0000000000000000000000000000000000000000..1d48b2386839f99d6bd93b3ef4a44407223e5437
--- /dev/null
+++ b/MathToF/105.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "有8颗外观相同的珍珠，其中有一颗是次品(次品比正品略轻)，用天平至少称3次才能保证找出次品"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把8个球分成(3，3，2)三组，把两个3个一组的放在天平上称，如平衡，则次品在2个的一组中，把这2个球分成(1，1)，放在天平上称，上跷的是次品.如不平衡，则把上跷的一组3个球分成(1，1，1)，任意两个放在天平上称，如平衡，没称的是次品，如不平衡，上跷的是次品.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/106.json b/MathToF/106.json
new file mode 100644
index 0000000000000000000000000000000000000000..940ff256b605649d1d3f0519d650add44a388f9c
--- /dev/null
+++ b/MathToF/106.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个战士实弹射击，12发子弹全部命中，命中率是120%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "命中率是指命中的次数占总次数的百分数，计算方法是:命中率= \\frac{命中次数}{总次数}×100%，由此求出命中率，再与120%比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/107.json b/MathToF/107.json
new file mode 100644
index 0000000000000000000000000000000000000000..2283e9c77c73d3852e4112e8311678d994d768cd
--- /dev/null
+++ b/MathToF/107.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{4}{3}× \\frac{3}{5}× \\frac{5}{4}=1，所以 \\frac{4}{3}、 \\frac{3}{5}、 \\frac{5}{4}互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义:乘积是1的两个数互为倒数.说明互为倒数的是两个数，不是三个数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/108.json b/MathToF/108.json
new file mode 100644
index 0000000000000000000000000000000000000000..121fd50c0ffcec762b28de66188bebb96bb0a3d5
--- /dev/null
+++ b/MathToF/108.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个因数扩大到原来的10倍，另一个因数也扩大到原来的10倍，它们的积就扩大到原来的20倍。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个因数扩大到原来的10倍，另一个因数也扩大到原来的10倍，积就扩大10*10=100倍，原题目说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/109.json b/MathToF/109.json
new file mode 100644
index 0000000000000000000000000000000000000000..e78a9e4ec8114478baa0b8a0ce32eea311fb9adf
--- /dev/null
+++ b/MathToF/109.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "五芳做10道题，做完的题和没有做的题成反比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/11.json b/MathToF/11.json
new file mode 100644
index 0000000000000000000000000000000000000000..849ce674f707e8283318565b698bd1f4d19fd053
--- /dev/null
+++ b/MathToF/11.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "从正面观察两组立体图形，看到的形状相同，但摆法可能不同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "从正面观察两组立体图形时，看到的形状可以相同，但是在几何体的后面视线挡住的地方，则可以任意的改变形状.比如，分别用1个和2个小正方体摆放几何体，用1个时从正面看是1个小正方形，用2个时只要一前一后摆放，从正面看到的仍然是1个小正方形，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/110.json b/MathToF/110.json
new file mode 100644
index 0000000000000000000000000000000000000000..11cebee847990b4397250433f3d0cbfd92309af6
--- /dev/null
+++ b/MathToF/110.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{5}{9}×8+2=(8+2)× \\frac{5}{9}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "乘法分配律的逆运算:一个数乘另一个数的积加它本身乘另一个数的积，可以把另外两个数加起来再乘这个数.如ac+bc=a×(b+c)，本题错用了乘法的分配律，只能先算乘法再算加法."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/111.json b/MathToF/111.json
new file mode 100644
index 0000000000000000000000000000000000000000..688768fa329ad918e4edf246a0b2a9b0ef1bdd4a
--- /dev/null
+++ b/MathToF/111.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "循环小数都是无限小数，无限小数都是循环小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题考查的学生对无限小数概念的掌握情况，无限小数包括循环小数和无限不循环小数，"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/112.json b/MathToF/112.json
new file mode 100644
index 0000000000000000000000000000000000000000..9dad0ec5b5f9302ca2010b57161252f023f21792
--- /dev/null
+++ b/MathToF/112.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数与231相加，和是841，求这个数，列式是231+841"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据减法的意义，已知和与其中的一个加数，求另一个加数，用减法列式，即用和减去这个已知的加数，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/113.json b/MathToF/113.json
new file mode 100644
index 0000000000000000000000000000000000000000..ef84c2f61d2bc16a86ab2f5d32de5da796405ba4
--- /dev/null
+++ b/MathToF/113.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个一样正方形可以拼成一个更大的正方形。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个一样的正方形拼成的图形如下: 只能拼成一个长方形，不能拼成一个正方形，只有至少4个完全一样的正方形才能拼成一个大正方形. 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/114.json b/MathToF/114.json
new file mode 100644
index 0000000000000000000000000000000000000000..1fef2952a38189f423d94ef6b124beccc1fb7112
--- /dev/null
+++ b/MathToF/114.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "冬冬发现自己的影子在东面，那么现在太阳在西面"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "发现自己的影子在东面，说明是下午，太阳在西方，下午面对太阳，也就是面对西方，我们的影子就在东方，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/115.json b/MathToF/115.json
new file mode 100644
index 0000000000000000000000000000000000000000..b6e094a7c33a6f0dbcc6d6214904b1557f8ab8d5
--- /dev/null
+++ b/MathToF/115.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一超市的营业时间从早上8:00到晚上8:00，一天的营业时间共是12小时"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先把时间化成24时计时法来表示，然后用营业结束时间减去营业开始时间，即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/116.json b/MathToF/116.json
new file mode 100644
index 0000000000000000000000000000000000000000..598c028a914b8f150459c52ddf6408b796ef57e7
--- /dev/null
+++ b/MathToF/116.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最大的三位数比最小的四位数少10。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最大的三位数是999，最小的四位数是1000，计算判断即可。 1000-999=1，所以最大的三位数比最小的四位数少10说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/117.json b/MathToF/117.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c22ed3ea2ab2aa7a3bb6abe1e38e2cb5cd9ba77
--- /dev/null
+++ b/MathToF/117.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三个连续自然数的和一定是3的倍数."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "设三个连续自然数中的第一个为a，则三个连续自然数的和为:  a+(a+1)+(a+2)=3×(a+1).  所以，所以三个连续自然数的和一定是3的倍数.  正确.  设三个连续自然数中的第一个为a，由这三个连续的自然数可表示为a、a+1，a+2.其和为:a+(a+1)+(a+2)=3×(a+1)，所以三个连续自然数的和一定是3的倍数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/118.json b/MathToF/118.json
new file mode 100644
index 0000000000000000000000000000000000000000..d58c57045e8abc341913bbcc517df0682aaeefba
--- /dev/null
+++ b/MathToF/118.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个长方体蓄水池长8米、宽4米、深2米，这个蓄水池占地面积是32平方米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "占地面积就是底面积，即:8×4=32平方米，根据此判断即可。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/119.json b/MathToF/119.json
new file mode 100644
index 0000000000000000000000000000000000000000..dc496df4ab45f5cba671ec8492e491f9da4dd71a
--- /dev/null
+++ b/MathToF/119.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算大面积的土地面积时用平方千米作单位，边长是1000米的正方形土地，面积是1平方千米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据1平方千米=1000000平方米，解答此题即可。 1000×1000=1000000(平方米) 1000000平方米=1平方千米 所以计算大面积的土地面积时用平方千米作单位，边长是1000米的正方形土地，面积是1平方千米，这句话是正确的。 故答案为:√。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/12.json b/MathToF/12.json
new file mode 100644
index 0000000000000000000000000000000000000000..b3ae1352e5e391ce9058a8cc661b0d388a60534b
--- /dev/null
+++ b/MathToF/12.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "加工一批零件，有100个合格零件，2个不合格零件，那么不合格率是2%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "理解不合格率，不合格率是指不合格的零件个数占零件总个数的百分之几，计算方法为: \\frac{不合格的零件个数}{零件总个数}×100%=不合格率，由此列式解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/120.json b/MathToF/120.json
new file mode 100644
index 0000000000000000000000000000000000000000..dcaea1323d1b7a8807941a765c5f084d0985ea75
--- /dev/null
+++ b/MathToF/120.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{1}{4}:1.5化成最简整数比是6:1，比值是6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "(1)根据比的基本性质，即比的前项和后项同时乘或除以一个相同的数(0除外)比值不变，进而把比化成最简比;  (2)根据求比值的方法，就用最简比的前项除以后项即得比值."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/121.json b/MathToF/121.json
new file mode 100644
index 0000000000000000000000000000000000000000..7443a130a59d8d452c3a1efbd1e53935d9e44178
--- /dev/null
+++ b/MathToF/121.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "假分数大于它的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在分数中，分子大于或等于分母的分数为假分数.乘积为1的两个数互为倒数.由此可知，当分子大于分母时，假分数大于它的倒数，当分子等于分母时，假分数等于它的倒数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/122.json b/MathToF/122.json
new file mode 100644
index 0000000000000000000000000000000000000000..6ddddb4e8251f9ed044488e6393e3f78b0e29034
--- /dev/null
+++ b/MathToF/122.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "边长是4米的正方形，它的周长和面积相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:周长和面积的单位不同，不能比较大小。 点评:"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/123.json b/MathToF/123.json
new file mode 100644
index 0000000000000000000000000000000000000000..b70d9458518115c9ae596f449656cf5228f0506d
--- /dev/null
+++ b/MathToF/123.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个等腰三角形的一个底角是a度，这个三角形的顶角是90-a度"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "已知等腰三角形的一个底角是a度，因为等腰三角形的两底角相等，根据三角形内角和是180度，用‘180-a×2‘解答即可得到顶角度数;据此解答判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/124.json b/MathToF/124.json
new file mode 100644
index 0000000000000000000000000000000000000000..52b5c72ff6ce7bbafe7126ffde8e1b5a932e7b77
--- /dev/null
+++ b/MathToF/124.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8.50元与8张1元和5张1角相等。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "8张1元和5张1角是8.50元，所以与8.50元相等，原说法正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/125.json b/MathToF/125.json
new file mode 100644
index 0000000000000000000000000000000000000000..1fbb4c7b850fbdf12dc11d7fad393d29f38408ff
--- /dev/null
+++ b/MathToF/125.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一百万一百万地数，数十次是一亿."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分析:根据相邻的两个计数单位间的进率是‘十‘，百万和千万，是两个相邻的计数单位，它们的进率都是‘十‘，而百万和亿不是相邻的计数单位，它们之间的进率不是‘十‘;由此求解. 解答:一百万一百万地数，数十次是一千万，数一百次是一亿. 故答案为:错误. 点评:此题考查十进制计数法，每相邻的两个计数单位间的进率是‘十‘."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/126.json b/MathToF/126.json
new file mode 100644
index 0000000000000000000000000000000000000000..380697d97ac659f64763ebfdc561db41c7a7f436
--- /dev/null
+++ b/MathToF/126.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3米的\\frac{1}{4}和1米的\\frac{3}{4}相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "3× \\frac{1}{4}= \\frac{3}{4}(米)1× \\frac{3}{4}= \\frac{3}{4}(米) \\frac{3}{4}= \\frac{3}{4} 所以，3米的 \\frac{1}{4}等于1米的 \\frac{3}{4}。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/127.json b/MathToF/127.json
new file mode 100644
index 0000000000000000000000000000000000000000..dde10d69caddbadcb8602b7bc60ba605ba882acf
--- /dev/null
+++ b/MathToF/127.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3米的 \\frac{1}{4}和1米的 \\frac{3}{4}相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分别把3米、1米看作单位‘1‘，根据一个数乘分数的意义，用乘法分别求出3米的 \\frac{1}{4}和1米的 \\frac{3}{4}，然后进行比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/128.json b/MathToF/128.json
new file mode 100644
index 0000000000000000000000000000000000000000..675def50e98e0c9014d3add790eef18fa29e44e5
--- /dev/null
+++ b/MathToF/128.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{4}{15}÷ \\frac{2}{3}也可以这样算 \\frac{4}{15}÷ \\frac{2}{3}= \\frac{4÷2}{15÷3}= \\frac{2}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分数除以分数，也可以用分母除以分母的商作分母，分子除以分子的商作分子，依此计算即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/129.json b/MathToF/129.json
new file mode 100644
index 0000000000000000000000000000000000000000..3903ff50a6a3bdfecae734e61d03ea706ceac65d
--- /dev/null
+++ b/MathToF/129.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "面朝南方时，你的左手边是西方。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据方向的初步认识相关知识点。根据上北下南左西右东，面朝南方，后面是北方，左边是东方，右边是西方。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/13.json b/MathToF/13.json
new file mode 100644
index 0000000000000000000000000000000000000000..da6ddd194866dd490432212b6e5cbb7fc86b8772
--- /dev/null
+++ b/MathToF/13.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3862004读作:三百八十六万二千零零四"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "这是一个七位数，最高位百万位上是3，十万位上是8，万位上是6，千位上是2，个位上是4，其余位上都是0，读这个数时，从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，由此得出这个数的读法，从而判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/130.json b/MathToF/130.json
new file mode 100644
index 0000000000000000000000000000000000000000..bfcf09c54d44021ff487b199b77b62c824ffee66
--- /dev/null
+++ b/MathToF/130.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "‘92‘中的‘9‘在个位上 ‘2‘在十位上。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "9在十位上，2在个位上，原说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/131.json b/MathToF/131.json
new file mode 100644
index 0000000000000000000000000000000000000000..b9a7795aabccf4aeb999fcf27a536707487c4bab
--- /dev/null
+++ b/MathToF/131.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把2块棱长都为2厘米的正方体拼成一个长方体，表面积增加了8平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由合拼图形的特征可知拼成一个长方体比2块棱长都为2厘米的正方体少了2个正方形的面，依此即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/132.json b/MathToF/132.json
new file mode 100644
index 0000000000000000000000000000000000000000..f31f24db91b1bb625deb268d3282c2f53189a222
--- /dev/null
+++ b/MathToF/132.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "女生与男生的人数比是5:6，表示女生比男生少 \\frac{1}{11}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "假设女生有5人，那么男生就有6人，先求出女生比男生少(6-5)人，把男生人数看作单位‘1‘，然后根据求一个数是另一个数的几分之几用除法计算得出，进而进行比较，得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/133.json b/MathToF/133.json
new file mode 100644
index 0000000000000000000000000000000000000000..07f33b47e7702fdf05640d227d47ee6d94c4de76
--- /dev/null
+++ b/MathToF/133.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果a× \\frac{1}{2}=b÷ \\frac{1}{4}(a、b都大于0)，那么a<b"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题可先将式中的除法算式变为乘法算式后，根据在积一个的情况下，其中一个因数越大，则另一个因数越小的乘法性质判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/134.json b/MathToF/134.json
new file mode 100644
index 0000000000000000000000000000000000000000..5c7179c00b7a0f7b8745d692f0db9c456679c00a
--- /dev/null
+++ b/MathToF/134.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2+2=2×2=\\( 2^{2} \\)，所以b+b=\\( b^{2} \\)"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "b+b表示两个2相加，而\\( b^{2} \\)表示两个2相乘，它们的意义不同，所以结果也就不一定相等;所以2+2=2×2=\\( 2^{2} \\)，这只是一个特殊例子，据此判断为错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/135.json b/MathToF/135.json
new file mode 100644
index 0000000000000000000000000000000000000000..2be19dae77f811040dd7ee75c9e9b7e9cd5f1bde
--- /dev/null
+++ b/MathToF/135.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三千四百零九万七千二百，用四舍五入法精确到万位是3410"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先根据多位数的写法，写出这个数，省略四舍五入到万，根据千位上数字的大小确定用‘四舍‘法、还是用‘五入‘法.省略尾数后，同时在后面写上‘万‘字."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/136.json b/MathToF/136.json
new file mode 100644
index 0000000000000000000000000000000000000000..32fc632b3a0b8efd7745d2b56cb59ee0ee0c238a
--- /dev/null
+++ b/MathToF/136.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方体的玻璃鱼缸，棱长是2分米，制作这个鱼缸至少需要玻璃24dm2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "制作这个鱼缸至少需要的玻璃就是求这个正方体的5个面的面积和，根据求正方体表面积方法求解，即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/137.json b/MathToF/137.json
new file mode 100644
index 0000000000000000000000000000000000000000..bd8f77e9f23ac51394480a5dd7c010a75b6210f7
--- /dev/null
+++ b/MathToF/137.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "295×59的乘积大约是1500. ."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:根据估算的方法，295估算时看作300，59估算时看作60，据此解答即可. 解:根据估算的方法得: 295×59≈300×60=18000. 故答案为:×."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/138.json b/MathToF/138.json
new file mode 100644
index 0000000000000000000000000000000000000000..c9a3896e9f1cd9701e479a9d178ba8785211e9ac
--- /dev/null
+++ b/MathToF/138.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "棱长是6厘米的正方体表面积和体积相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为正方体的表面积和体积单位不相同，没法比较它们的大小，  所以原题说法是错误的.  错误.  正方体的表面积和体积单位不相同，没法比较它们的大小，由此就解决即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/139.json b/MathToF/139.json
new file mode 100644
index 0000000000000000000000000000000000000000..df8731806d568b5f926af8d303308dc90d16c700
--- /dev/null
+++ b/MathToF/139.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数的和一定是偶数，两个奇数的积一定是奇数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1根据奇数和偶数的性质:两个偶数的和或差仍是偶数，两个奇数的和或差也是偶数，奇数和偶数的和或差是奇数;  2不能被2整数的数为奇数，则奇数中一定不含有因数2，所以两个奇数的积中也一定不含有因数2，所以两个奇数的积一定是奇数，解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/14.json b/MathToF/14.json
new file mode 100644
index 0000000000000000000000000000000000000000..bd7588073481ce209c9c7b90728c6bbf9383ce8d
--- /dev/null
+++ b/MathToF/14.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.1和0.3之间只有一个小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数大小比较的方法，0.1和0.3之间的一位小数有0.2，0.1和0.3之间的两位小数有:0.11、0.12、0.13、…，0.1和0.3之间的三位小数有:0.111、0.121、0.131、…，…，所以小数0.1和0.3之间有无数个小数，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/140.json b/MathToF/140.json
new file mode 100644
index 0000000000000000000000000000000000000000..71fad64eec78e3e93e7cf74c70fb4197b616a040
--- /dev/null
+++ b/MathToF/140.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "为了清楚地展示冰箱全年的变化趋势，用折线统计图更合适"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/141.json b/MathToF/141.json
new file mode 100644
index 0000000000000000000000000000000000000000..c8a24df09e3bf76b430272146a40758a100503ab
--- /dev/null
+++ b/MathToF/141.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要反映某食品中各种营养成份的含量，最好选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/142.json b/MathToF/142.json
new file mode 100644
index 0000000000000000000000000000000000000000..05e9611bb5d6ded5f891d4d9354b135cfa0df967
--- /dev/null
+++ b/MathToF/142.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "绘制统计图时，要清楚的表示数量增减变化情况，应该选用折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先要清楚每一种统计图的特点:条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/143.json b/MathToF/143.json
new file mode 100644
index 0000000000000000000000000000000000000000..a1d2d44d1b94e116593ed17e2972827ef4fd90f3
--- /dev/null
+++ b/MathToF/143.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "19×49的结果比1000大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数乘法的计算方法先求出积，再进行比较解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/144.json b/MathToF/144.json
new file mode 100644
index 0000000000000000000000000000000000000000..cc4f1b8ba75288bf2b4cf4e6ef0cb6876af8f094
--- /dev/null
+++ b/MathToF/144.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "正方形、长方形、三角形都是轴对称图形。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为正方形、长方形、等腰三角形和圆分别沿一条直线折叠，直线两旁的部分能够完全重合，则说正方形、长方形、等腰三角形和圆都是轴对称图形; 但是除等腰三角形外的三角形沿一条直线折叠，直线两旁的部分不能够完全重合，则除等腰三角形外的三角形不是轴对称图形。故题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/145.json b/MathToF/145.json
new file mode 100644
index 0000000000000000000000000000000000000000..deb78490491c9d95168cb75d3f97f573829f3ba1
--- /dev/null
+++ b/MathToF/145.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "600与0相乘，结果是600."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "任何数与0相乘都得0，所以原题目说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/146.json b/MathToF/146.json
new file mode 100644
index 0000000000000000000000000000000000000000..ff45353f6d132c7383736c24719a5a3a9a28c712
--- /dev/null
+++ b/MathToF/146.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用两块同样大小的长方形可以拼成一个正方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "当两个完全相同的长方形可以拼成一个正方形时，是把两个长方形的一条边对在一起，拼成正方形的边长就是长方形的长，也是2个宽的长度，由此求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/147.json b/MathToF/147.json
new file mode 100644
index 0000000000000000000000000000000000000000..018f0f433aa484a80e80075b7baa36cc7309dbfc
--- /dev/null
+++ b/MathToF/147.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三位数乘两位数，其中有一个乘数中间有0，积的中间一定有0_"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设三位数是102，两位数是10或11，分别求出它们的乘积，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/148.json b/MathToF/148.json
new file mode 100644
index 0000000000000000000000000000000000000000..01878eb69f7814953ffd5df9f2c5d5bd5a0dcf1b
--- /dev/null
+++ b/MathToF/148.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "指南针的一端总是指向南方"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据指南针的特点，即可进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/149.json b/MathToF/149.json
new file mode 100644
index 0000000000000000000000000000000000000000..0aa54df92096000dba7729974b848f64a2e641a1
--- /dev/null
+++ b/MathToF/149.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根铁丝长98米，第一次用去18米，第二次用去32米，现在还剩多少米?列式:98-18+32"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "方法一:可用98分别减去第一次、第二次用去的长度即可得到剩余的长度;  方法二:可用18加32计算出共用去的长度，然后再用总长度减去用去的长度等于剩余的长度."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/15.json b/MathToF/15.json
new file mode 100644
index 0000000000000000000000000000000000000000..994274f01b6b1f92d1e455c1fd535649dc6a3806
--- /dev/null
+++ b/MathToF/15.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数的位数不同，位数多的那个数一定大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "比较两个整数的大小，首先看这两个整数的位数是否相同，如果位数不同，位数多的大于位数少的，如果位数相同，相同数位上大的数就大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/150.json b/MathToF/150.json
new file mode 100644
index 0000000000000000000000000000000000000000..66b2510fa38b70034594efb495d2034df669e40c
--- /dev/null
+++ b/MathToF/150.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘的积不一定大于这两个数相加的和"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，假设这两个数是1和2或3和4，然后再进一步解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/151.json b/MathToF/151.json
new file mode 100644
index 0000000000000000000000000000000000000000..2e52565d363517bc987ce4be65dceb43b2a0dd86
--- /dev/null
+++ b/MathToF/151.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在数列‘ \\frac{1}{1}， \\frac{3}{4}， \\frac{5}{9}， \\frac{7}{16}， \\frac{9}{25}， \\frac{11}{36}，…‘中，第10个数是 \\frac{19}{100}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "这组数据的分子从左到右分别是1、3、5、7…，即是从1开始相邻的奇数;分母分别是1、4、9、16…，即分别是1、2、3、4…各数的平方.因此，第10数的分子是19，分母是1\\( 0^{2} \\)，即100.也就是第10个数是 \\frac{19}{100}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/152.json b/MathToF/152.json
new file mode 100644
index 0000000000000000000000000000000000000000..9011745d4f58368d0962d5154988b399522ad084
--- /dev/null
+++ b/MathToF/152.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{4}{5}× \\frac{5}{9}× \\frac{9}{4}=1，所以 \\frac{4}{5}、 \\frac{5}{9}、 \\frac{9}{4}互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义:乘积是1的两个数互为倒数.说明互为倒数的是两个数之间的关系，不是三个数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/153.json b/MathToF/153.json
new file mode 100644
index 0000000000000000000000000000000000000000..7f721dbe291632017c33df9bdea9179ad48773e3
--- /dev/null
+++ b/MathToF/153.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲数是乙数的 \\frac{2}{3}，乙数就是甲数的 \\frac{3}{2}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "先把乙数看成单位‘1‘，甲数就是 \\frac{2}{3}，然后再用乙数1除以甲数即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/154.json b/MathToF/154.json
new file mode 100644
index 0000000000000000000000000000000000000000..7fee954960a624c66a37dc0b5b86efaf5d7f4830
--- /dev/null
+++ b/MathToF/154.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "从50数到60，一共数了10个数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求从50开始数起，数到60时，数了多少个数，用60减去50再加上1即可解答。 60-50+1=11(个) 所以从50数到60一共数了11个数;所以题干的说法是错误的。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/155.json b/MathToF/155.json
new file mode 100644
index 0000000000000000000000000000000000000000..18c86c6ef945fc9fed6637c60f5c6aee01f282e9
--- /dev/null
+++ b/MathToF/155.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3.28×0.06的积中有四位小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据小数乘法的计算方法进行分析即可进行解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/156.json b/MathToF/156.json
new file mode 100644
index 0000000000000000000000000000000000000000..67275f120d8a2ba050c82bd0812d66369692cc42
--- /dev/null
+++ b/MathToF/156.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "平行四边形的面积是与它等底等高的三角形面积的2倍."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "三角形面积公式的推导过程，若三角形和平行四边形等底等高，则平行四边形的面积是三角形的面积的2倍.所以原题说法正确.  正确.  三角形面积公式的推导过程，因为三角形S=ab÷2，平行四边形S=ab，若三角形和平行四边形等底等高，则平行四边形的面积是三角形的面积的2倍，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/157.json b/MathToF/157.json
new file mode 100644
index 0000000000000000000000000000000000000000..264d23ee93a61ed4066e66512ff92c6c6121496c
--- /dev/null
+++ b/MathToF/157.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "真分数都小于1，带分数都大于1。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "假分数是指分子大于或等于分母的分数，所以假分数都大于或等于1，真分数是指分子小于分母的分数，所以真分数都小于1;据此进行判断。 所有的假分数都大于1所有的真分数都小于1的说法是错误的; 理由:假分数是指分子大于或等于分母的分数，所以假分数都大于或等于1，带分数是分子大于分母的假分数。所以原题的说法正确。 故答案为:√。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/158.json b/MathToF/158.json
new file mode 100644
index 0000000000000000000000000000000000000000..12fbc177df4e9c37bdbb6bd8e789177dd0e043ff
--- /dev/null
+++ b/MathToF/158.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2×5=10，所以2和5都是10的因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为2×5=10，所以说2和5都是10因数，10是2和5的倍数;约数和倍数是相互依存的，是两个数之间的关系;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/159.json b/MathToF/159.json
new file mode 100644
index 0000000000000000000000000000000000000000..449ad733b023272dd62d992d26b878aeac9539a4
--- /dev/null
+++ b/MathToF/159.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个图形绕某一点顺时针旋转90°，其大小、形状、位置都不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据旋转的特征，一个图形绕某点顺时针旋转90°，某点的位置不动，其余各部分均绕此点按相同方向旋转相同的度数即可画出旋转后的图形，即旋转后形状、大小不变，只是位置发生变化."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/16.json b/MathToF/16.json
new file mode 100644
index 0000000000000000000000000000000000000000..6e26869288bce503c5184ad3a71d7f8e5f71b7b5
--- /dev/null
+++ b/MathToF/16.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求5个 \\frac{2}{5} 的和是多少?就是求5的 \\frac{2}{5}是多少?也就是求 \\frac{2}{5}的5倍是多少?"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分数乘整数的意与整数乘法的意义相同，都表示求几个相同加数的和的简算运算.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/160.json b/MathToF/160.json
new file mode 100644
index 0000000000000000000000000000000000000000..cf62f0b4c98f42fab8ffd02d7a6fe2ee482bdbb7
--- /dev/null
+++ b/MathToF/160.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把 \\frac{9}{10}米长的丝带截成相等的3段，每段占全长的 \\frac{3}{10}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把这条丝带的长度看作单位‘1‘，把它平均分成3段，每段占全长的 \\frac{1}{3}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/161.json b/MathToF/161.json
new file mode 100644
index 0000000000000000000000000000000000000000..7ceeba6deb0219e47c3084d72210d9841e75e96f
--- /dev/null
+++ b/MathToF/161.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形的三个内角的度数比是2:3:5，这个三角形一定是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为三角形的内角度数和是180°，三角形的最大的角的度数占内角度数和的 \\frac{5}{10}，根据一个数乘分数的意义，求出最大角，进而判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/162.json b/MathToF/162.json
new file mode 100644
index 0000000000000000000000000000000000000000..73effd6920eb771066b7dd99c1d8d89276f822e0
--- /dev/null
+++ b/MathToF/162.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为12÷0.3=40，所以，12能被0.3整除，40是12的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "整除是指:整数‘a‘除以大于0的整数‘b‘，商为整数，且余数为零，我们就说a能被b整除;被除数、除数、商都是整数才是整除.而倍数关系也是对于整数而言的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/163.json b/MathToF/163.json
new file mode 100644
index 0000000000000000000000000000000000000000..82272c285b08c689ffa867bdd47d5df283ba26b9
--- /dev/null
+++ b/MathToF/163.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "185乘97与53的差，积是多少?列式是:185×97-53"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最后求积，所以先用97减去53求出差，再用185乘求出的差即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/164.json b/MathToF/164.json
new file mode 100644
index 0000000000000000000000000000000000000000..407a3a8ff5e4aed29477de3a7bb82898e775dfd5
--- /dev/null
+++ b/MathToF/164.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1号点在2号点的南偏西40°的方向上，那么2号点在1号点的北偏东40°的方向上。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1号点在2号点的南偏西40°的方向上，那么2号点在1号点的北偏东40°的方向上"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/165.json b/MathToF/165.json
new file mode 100644
index 0000000000000000000000000000000000000000..48aa9f1306f0d1d84a1f59f8951ccc3a50b6f60c
--- /dev/null
+++ b/MathToF/165.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最大的两位数比最小的三位数多1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要求最小的三位数和最大的两位数相差多少，可先确定最小的三位数和最大的两位数各是多少，然后用三位数减去两位数即可得出答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/166.json b/MathToF/166.json
new file mode 100644
index 0000000000000000000000000000000000000000..65808f9e424476fcf963574cf043e114a5449a78
--- /dev/null
+++ b/MathToF/166.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个苹果分给3个小朋友，每个小朋友分得这个苹果的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为不是平均分的，所以无法知道分得几分之几，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/167.json b/MathToF/167.json
new file mode 100644
index 0000000000000000000000000000000000000000..d0deb80ea3934f218fe2dda95607f80e747d5b80
--- /dev/null
+++ b/MathToF/167.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方形的面积都比正方形的面积大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方形的面积=长×宽，正方形的面积=边长×边长，因为题干中长方形的长与宽，正方形的边长没有确定，所以它们的面积无法比较，据此解答即可得到答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/168.json b/MathToF/168.json
new file mode 100644
index 0000000000000000000000000000000000000000..0a38041bf716c3e28ffcccf188be54c3d06c165f
--- /dev/null
+++ b/MathToF/168.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "32只鸽子飞回7个鸽舍，至少有5只鸽子要飞进同个鸽舍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把7个鸽笼看作7个抽屉，把32只白鸽看作32个元素，那么每个抽屉需要放32÷7=4(个)…4(个)，所以每个抽屉需要放4个，剩下的4个不论怎么放，总有一个抽屉里至少有:4+1=5(个)，所以，至少有一个鸽笼要飞进5只白鸽，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/169.json b/MathToF/169.json
new file mode 100644
index 0000000000000000000000000000000000000000..e5bf4b831b939dec8529da62aa9dde890ebeceda
--- /dev/null
+++ b/MathToF/169.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "根据500-40=460，460÷20=23，列成综合算式是500-40÷20"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "500-40=460，460÷20=23，先用500减去40求出差，再用求出的差除以20即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/17.json b/MathToF/17.json
new file mode 100644
index 0000000000000000000000000000000000000000..3692304422884dfb756766195d243cf2b7aa508b
--- /dev/null
+++ b/MathToF/17.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一件商品先提价20%，后再打八折出售，这件商品的价格不变。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "解:(1+20%)×80% =120%×80%， =96%。 即打折后的价格是原价的96%。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/170.json b/MathToF/170.json
new file mode 100644
index 0000000000000000000000000000000000000000..939ef079e602350f9c6e710f884391c0d7924569
--- /dev/null
+++ b/MathToF/170.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "妈妈买了51个苹果，吃了20个后，还剩下31个"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "51-20=31，所以还剩下31个没吃买了的51个苹果减去已经吃了的20个，得到还剩下的31个"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/171.json b/MathToF/171.json
new file mode 100644
index 0000000000000000000000000000000000000000..bbac54fb4d707d752d43e6b4b6b5cc4e3302fa53
--- /dev/null
+++ b/MathToF/171.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{2}{3}= \\frac{4}{6}，所以它们的分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为 \\frac{2}{3}= \\frac{4}{6}，所以它们的大小相等，但是它们的分数单位不相同， \\frac{2}{3}的分数单位是 \\frac{1}{3}， \\frac{4}{6}的分数单位是 \\frac{1}{6}，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/172.json b/MathToF/172.json
new file mode 100644
index 0000000000000000000000000000000000000000..3a6e15f16a4544cc6abca1a6bc448c063311c7a1
--- /dev/null
+++ b/MathToF/172.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数除以一个数，等于分数乘这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "除数不能为0，应加上这个限制条件，由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/173.json b/MathToF/173.json
new file mode 100644
index 0000000000000000000000000000000000000000..791e3243d0b83f6bb92299afe5d0d9b059a11c42
--- /dev/null
+++ b/MathToF/173.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用长24厘米的铁丝围成的长方形的面积比正方形面积大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "围成正方形的边长就是24÷4=6厘米，进一步求出正方形的面积，围成长方形的周长是24厘米，所以长与宽的和就是24÷2=12厘米，可令长方形的长是7厘米，宽是5厘米，然后求出长方形的面积，通过面积的比较再作出选择."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/174.json b/MathToF/174.json
new file mode 100644
index 0000000000000000000000000000000000000000..dbb708d477906ca7d92fde8961df0455e242755b
--- /dev/null
+++ b/MathToF/174.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "大、小两个圆的半径比是3:5，那么，大、小两个圆的周长比也是3:5"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "设小圆的半径为3r，则大圆的半径为5r，代入圆的周长公式，表示出各自的周长，即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/175.json b/MathToF/175.json
new file mode 100644
index 0000000000000000000000000000000000000000..ea6dde8d7348b46e84317ea41aa2d8b018546ccc
--- /dev/null
+++ b/MathToF/175.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "封闭图形一周的长度，是它的周长"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据周长的定义知道，围成封闭图形的所有边的总长度就是它的周长，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/176.json b/MathToF/176.json
new file mode 100644
index 0000000000000000000000000000000000000000..3d907d28b11902c3ca75b4338168fc563d89c289
--- /dev/null
+++ b/MathToF/176.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把3千克糖平均分给8个小朋友，每个小朋友分得这些糖的 \\frac{3}{8}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求每个小朋友分得这些糖的几分之几，就是把这些糖的总质量看作单位‘1‘，平均分为8份，求一份是这些糖的总质量几分之几，用1÷8解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/177.json b/MathToF/177.json
new file mode 100644
index 0000000000000000000000000000000000000000..d429a94a4b0623801e9f0cae31e90e6278652578
--- /dev/null
+++ b/MathToF/177.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以3，余数可能是1、2、3"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，余数总比除数小，然后列举出所有的余数，继而判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/178.json b/MathToF/178.json
new file mode 100644
index 0000000000000000000000000000000000000000..0ef7e562514010ce66378ae86c447fea65effe94
--- /dev/null
+++ b/MathToF/178.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果女生人数比男生人数少 \\frac{1}{5}，那么男生人数就比女生人数多20%。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把男生人数看作单位‘1‘，女生人数比男生人数少 \\frac{1}{5}，也就是说女生人数是男生人数的1- \\frac{1}{5}= \\frac{4}{5}，先求出男生人数比女生人数多的分率，再除以女生人数即可解答。 \\frac{1}{5}÷(1- \\frac{1}{5}) = \\frac{1}{5}÷ \\frac{4}{5} =25% 25%>20% 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/179.json b/MathToF/179.json
new file mode 100644
index 0000000000000000000000000000000000000000..72b022e7821266eb1eb91ebe6aa33da078a0b897
--- /dev/null
+++ b/MathToF/179.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用电子计算器计算时，按顺序从头到尾的计算。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正确答案:用电子计算器计算时，先计算小括号里的减法，再计算除法。由于小括号里的差是作除数，所以需要先把结果记录下来，消除数据后，再用被除数除以这个差。(√)"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/18.json b/MathToF/18.json
new file mode 100644
index 0000000000000000000000000000000000000000..54df62ab1a690bff9d18cef4321111e0d3fb69b1
--- /dev/null
+++ b/MathToF/18.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5个8相加的和写出算式是5+8"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "5个8相加的和，写成加法算式是:8+8+8+8+8，根据乘法的意义写成乘法算式就是8×5."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/180.json b/MathToF/180.json
new file mode 100644
index 0000000000000000000000000000000000000000..535f3ae3b40d75a25384dc16f398e3635380517c
--- /dev/null
+++ b/MathToF/180.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数除以整数(0除外)，等于这个分数乘这个整数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数除法法则，即除以一个数(0除外)，就等于乘这个数的倒数，即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/181.json b/MathToF/181.json
new file mode 100644
index 0000000000000000000000000000000000000000..856b3ab1a7d77c2d9a527a6e2783754ce307e8db
--- /dev/null
+++ b/MathToF/181.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体最多有4个面面积相等，最多有8条棱长度相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据长方体的特征，它有12条棱，分为3组，互相平行的一组4条棱的长度相等;它的6个面都是长方形(特殊情况有两个相对的面是正方形)，相对的面的面积相等;如果有8条棱的长度相等，说明它有两个相对的面是正方形.由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/182.json b/MathToF/182.json
new file mode 100644
index 0000000000000000000000000000000000000000..1463e126c84ce66bf286a111878b3f8ae4d0246f
--- /dev/null
+++ b/MathToF/182.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "大于1的数的倒数都小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.求一个数的倒数，把分子和分母调换位置，可以通过举例证明."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/183.json b/MathToF/183.json
new file mode 100644
index 0000000000000000000000000000000000000000..c09d09fc1886f62adc0808654b8fd027b73e2ad9
--- /dev/null
+++ b/MathToF/183.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数与298相加，和是645，求这个数.列式是:298+645"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据减法的意义，已知和与其中的一个加数，求另一个加数，用减法列式，即用和减去这个已知的加数，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/184.json b/MathToF/184.json
new file mode 100644
index 0000000000000000000000000000000000000000..1320052ed2bc5a49f505a480ddde3883e6b2bcfa
--- /dev/null
+++ b/MathToF/184.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "自行车行走的里程一定，车轮的转数和车轮的直径成反比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据自行车的周长×自行车的转数=路程，也就是直径×π×转数=路程(一定)，把π移到右边，直径×转数=路程÷π，路程一定，路程÷π也一定，直径和转数的积一定，所以成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/185.json b/MathToF/185.json
new file mode 100644
index 0000000000000000000000000000000000000000..97963e2dafd9ffb6ec76fd5986e8ddd6d0b57b30
--- /dev/null
+++ b/MathToF/185.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5.4÷0.06=54÷6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据商不变的性质，被除数5.4变为54，扩大了10倍;要使商不变，0.06也应扩大10倍是0.6，而不是6"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/186.json b/MathToF/186.json
new file mode 100644
index 0000000000000000000000000000000000000000..922adbf102d43ce1261cf2378619ac3a8ccd19e8
--- /dev/null
+++ b/MathToF/186.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "车轮的半径一定，车轮的转数和它前进的距离成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两种量成不成比例，成什么比例，就看这两种量是否是1相关联;2一种量变化，另一种量也随着变化，变化方向相同或相反;3对应的比值或乘积一定;如果这两种量相关联的量都是变量，且对应的比值一定，就成正比例;如果两种量相关联的量都是变量，且对应的乘积一定，就成反比例;如果是其它的量一定或乘积、比值不一定，就不成比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/187.json b/MathToF/187.json
new file mode 100644
index 0000000000000000000000000000000000000000..fbf556265acc5d81761f4d746cc6016419aaab26
--- /dev/null
+++ b/MathToF/187.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3:5可以读作五分之三，也可以读作三比五。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比的写法可知比可以写成用比号表示的形式，也可写成分数的形式。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/188.json b/MathToF/188.json
new file mode 100644
index 0000000000000000000000000000000000000000..88717551da318f09eb281a593ead342fa242ea0e
--- /dev/null
+++ b/MathToF/188.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，积一定大于任何一个因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个数(0 除外)乘大于1的数，积比原来的数大;一个数(0 除外)乘小于1的数，积比原来的数小.据此进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/189.json b/MathToF/189.json
new file mode 100644
index 0000000000000000000000000000000000000000..d8854d3d08bde7ebdb7aedf4a625e09482348c00
--- /dev/null
+++ b/MathToF/189.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数的积一定是这两个数的公倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "如果两个数是非零的自然数，这两个数的乘积一定是这两个数的公倍数这是正确的，举例证明即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/19.json b/MathToF/19.json
new file mode 100644
index 0000000000000000000000000000000000000000..c8e5e3ff3e22ed2e8da28309160125f14d2d0779
--- /dev/null
+++ b/MathToF/19.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分针走一圈经过的时间是60秒。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "钟面一周分成了12个大格，分针走一周是1小时，即60分钟，时针走一大格是1小时，走一周是12小时，因此得解。 分针走一圈的时间是1小时，即60分钟; 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/190.json b/MathToF/190.json
new file mode 100644
index 0000000000000000000000000000000000000000..217162b515d84844798757c30388b3fc6c64c36e
--- /dev/null
+++ b/MathToF/190.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "19后面的一个数是18，18前面的一个数是19。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数的加减法，19后面的是20，18前面的数是17。  考查整数的加法和减法。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/191.json b/MathToF/191.json
new file mode 100644
index 0000000000000000000000000000000000000000..c16a809ca839800d7cbc9a93450de77793554442
--- /dev/null
+++ b/MathToF/191.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在比例 \\frac{4}{9}:a= \\frac{4}{9}:b 中，a和b互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比例的基本性质，即两内项之积等于两外项之积，即可求出a和b的乘积，若乘积为1，则互为倒数，反之，不互为倒数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/192.json b/MathToF/192.json
new file mode 100644
index 0000000000000000000000000000000000000000..f51e5c8e1ef51a3de1bd359cab1c2ebdffd198fb
--- /dev/null
+++ b/MathToF/192.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "开水龙头是旋转现象，荡秋千是平移现象"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据平移的意义，在平面内，将一个图形沿某个方向移动一定的距离，这样的图形运动称为平移;根据旋转的意义，在平面内，将一个图形饶一个定点沿某个方向转动一个角度，这样的图形运动称为旋转."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/193.json b/MathToF/193.json
new file mode 100644
index 0000000000000000000000000000000000000000..adcec7627bd85c0a7b30c289d551454cf247aa11
--- /dev/null
+++ b/MathToF/193.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.38去掉小数点后，得到的数是原数的100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把0.38的小数点去掉，就是把它的小数点向右移动2位，根据小数点的移动与小数大小的变化规律可知小数点向右移动2位，扩大了100倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/194.json b/MathToF/194.json
new file mode 100644
index 0000000000000000000000000000000000000000..ea7c05fe7d3106a04211c1cacf06c6f2f3496a83
--- /dev/null
+++ b/MathToF/194.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以整数(0除外)，等于乘这个整数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数除法的计算法则，甲数除以乙数(0除外)，等于甲数乘乙数的倒数.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/195.json b/MathToF/195.json
new file mode 100644
index 0000000000000000000000000000000000000000..b79225eb2226bbe70b76e38123a9eadc1ff86578
--- /dev/null
+++ b/MathToF/195.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2.5× \\frac{1}{10}×4=1，所以2.5、 \\frac{1}{10}、4互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义:乘积是1的两个数互为倒数.说明互为倒数的是两个数之间的关系，不是三个数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/196.json b/MathToF/196.json
new file mode 100644
index 0000000000000000000000000000000000000000..80a54cafc785e95895035b963e5c30c90446501a
--- /dev/null
+++ b/MathToF/196.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体的长、宽、高都扩大到原来的2倍，那么表面积扩大为原来的4倍，体积扩大为原来的8倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先根据长方体的表面积=(长×宽+长×高+宽×高)×2，如果长方体的长、宽、高都扩大到原来的2倍，则长×宽、长×高、宽×高都扩大到原来的4倍，所以表面积扩大为原来的4倍;然后根据长方体的体积=长×宽×高，如果长方体的长、宽、高都扩大到原来的2倍，则长×宽×高扩大到原来的8倍，所以体积扩大为原来的8倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/197.json b/MathToF/197.json
new file mode 100644
index 0000000000000000000000000000000000000000..3efd5985c95c51ba923294fdf04e3cb5599d1d3b
--- /dev/null
+++ b/MathToF/197.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5是因数，10是倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/198.json b/MathToF/198.json
new file mode 100644
index 0000000000000000000000000000000000000000..95252b09e044e3564df06f0c4d3361c8fde90d11
--- /dev/null
+++ b/MathToF/198.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一台原价2000元的洗衣机，先降价10% 后来又提价10%，这时价格还是2000元."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分析:先把原价看成单位‘1‘，降价后的钱数是原价的(1-10%)，由此用乘法求出降价后的价格;再把降价后的价格看成单位‘1‘，现价是它的(1+10%)，再用乘法求出现价，然后与2000比较即可. 解答:2000×(1-10%)×(1+10%)， =2000×90%×110%， =1980(元); 这时的现价是1980元，不是2000元. 故答案为:×. 点评:解决本题关键是区分两个10%的不同单位‘1‘."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/199.json b/MathToF/199.json
new file mode 100644
index 0000000000000000000000000000000000000000..a92af351da8e68a0ac9a93d67784e85624dc1b80
--- /dev/null
+++ b/MathToF/199.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "高翔同学每天做眼保健操时间大约是9分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据生活经验、对时间单位大小的认识，可知:高翔同学每天做眼保健操时间大约是9分钟."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/2.json b/MathToF/2.json
new file mode 100644
index 0000000000000000000000000000000000000000..8e8d3563ec8c10813e8b39811509d6418a45bf1f
--- /dev/null
+++ b/MathToF/2.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "棱长8厘米的正方体，表面积和体积相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "(1)意义不同，正方体 的表面积是指组成正方体所有面的总面积，而正方体的体积是指正方体所占空间的大小;  (2)计算方法不同，表面积=a×a×6，而体积=a×a×a;  (3)计量单位不同，表面积用面积单位，而体积用体积单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/20.json b/MathToF/20.json
new file mode 100644
index 0000000000000000000000000000000000000000..819e0ae79d46aa5cb53b0bdaca43a4cd148d7876
--- /dev/null
+++ b/MathToF/20.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "折线统计图比条形统计图更能直观地表示出数量的增减变化情况"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/200.json b/MathToF/200.json
new file mode 100644
index 0000000000000000000000000000000000000000..c316d37d44d15b2cecc3ede385f598ab29421d95
--- /dev/null
+++ b/MathToF/200.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3.5÷2和3.5×0.5都表示求3.5的一半是多少"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据小数除法的计算法则，把除数转化为乘它的倒数，再根据一个数乘小数(分数)的意义，一个数乘一位小数表示求这个数的十分之几是多少.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/201.json b/MathToF/201.json
new file mode 100644
index 0000000000000000000000000000000000000000..1554a47fd519da761f33abe9bffa49b22d78c96c
--- /dev/null
+++ b/MathToF/201.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一堆苹果的\\frac{3}{4}一定比另一堆苹果的\\frac{1}{4}多。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为两堆苹果的多少不确定也就是单位‘1‘的具体数量不确定，所以没法比较它们的多少，故题目说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/202.json b/MathToF/202.json
new file mode 100644
index 0000000000000000000000000000000000000000..20987ddb6c599ad65906e53ceeb5890da4ffecba
--- /dev/null
+++ b/MathToF/202.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数的7倍是49，求这个数，列式为49-7=42"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "已知一个数的7倍是49，求这个数用除法计算，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/203.json b/MathToF/203.json
new file mode 100644
index 0000000000000000000000000000000000000000..fd4200e5d46d0862eaf11b2daaa0710723b835c3
--- /dev/null
+++ b/MathToF/203.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆形只有4条对称轴"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据轴对称图形的定义:在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是这个轴对称图形的一条对称轴，由此即可作答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/204.json b/MathToF/204.json
new file mode 100644
index 0000000000000000000000000000000000000000..f5cb87c53efe5d2fe0affe972e31d87e6a4a85c1
--- /dev/null
+++ b/MathToF/204.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果两个圆柱的侧面积相等，那么它们的底面周长也一定相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "侧面积等于底面周长乘高，仅由侧面积相等不能确定底面周长也相等。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/205.json b/MathToF/205.json
new file mode 100644
index 0000000000000000000000000000000000000000..06a36d80e8ca27b7dc7a36cffaa1fdd9095aec32
--- /dev/null
+++ b/MathToF/205.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "围成长方体的6个面最多有两个面是正方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据长方体的特征，6个面都是长方形(特殊情况有两个相对的面是正方形)，相对的面的面积相等.由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/206.json b/MathToF/206.json
new file mode 100644
index 0000000000000000000000000000000000000000..22d2fc5750344f560d513a0eb7a2669982945210
--- /dev/null
+++ b/MathToF/206.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2^{2}=2×2，所以a^{2}=a×2。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个数的平方等于这个数乘这个数，所以a^{2}=a×a"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/207.json b/MathToF/207.json
new file mode 100644
index 0000000000000000000000000000000000000000..610ffdb5c50ba853814ffd6ef355bf9fd61e59b8
--- /dev/null
+++ b/MathToF/207.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个因数的末尾都没有0，积的末尾也可能有多个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "假设这两个数分别是8和125，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/208.json b/MathToF/208.json
new file mode 100644
index 0000000000000000000000000000000000000000..7c79c2eb9491525e1e963642390b9b90c9a86e8b
--- /dev/null
+++ b/MathToF/208.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体的面不可能是正方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方体的特征，长方体的6个都是长方形(特殊情况有两个相对的面是正方形)，相对面的面积相等.据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/209.json b/MathToF/209.json
new file mode 100644
index 0000000000000000000000000000000000000000..4dfc4a897b30fe2ebc840d3c704499b76b89c698
--- /dev/null
+++ b/MathToF/209.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小朋友洗一次澡大约要用1分钟的时间"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据实际情景，小朋友洗一次澡大约要用1小时的时间，因此得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/21.json b/MathToF/21.json
new file mode 100644
index 0000000000000000000000000000000000000000..ae517216668f20a2ed4fb16d1620f89b81dffb43
--- /dev/null
+++ b/MathToF/21.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "妈妈一天工作8小时"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一天有24小时，妈妈一天只工作8小时，其他时间休息，因此得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/210.json b/MathToF/210.json
new file mode 100644
index 0000000000000000000000000000000000000000..687507a65a7483fc75f43d2429599cf425284794
--- /dev/null
+++ b/MathToF/210.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "乘以一个数，等于除以这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "逆用分数除法的计算法则判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/211.json b/MathToF/211.json
new file mode 100644
index 0000000000000000000000000000000000000000..b6dd235ed920db4a3f247ef98e42e61a0f8f581c
--- /dev/null
+++ b/MathToF/211.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在任何梯形中都能分割出一个三角形和一个平行四边形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "将三角板的一条直角边和直尺的上边缘都与梯形的一个腰重合，然后平移直尺，当直尺的上边缘正好与梯形上底的另一个端点重合时，过这个端点沿直尺上边缘画线段，与梯形的下底交于一点，此线段即为平行于梯形腰的线段，这样就可以把梯形分成一个三角形和平行四边形."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/212.json b/MathToF/212.json
new file mode 100644
index 0000000000000000000000000000000000000000..7714f0f1e06f8a961a8dea050e14bc8cead50e6d
--- /dev/null
+++ b/MathToF/212.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "学校举行课外书阅读比赛，四(1)班同学平均得分95分，四(2)班同学平均得分也是95分，那么四(1)班得分最高的同学和四(2)班得分最高的同学得分一定相同。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "平均成绩相同并不能反映最高成绩的相同，平均数只反映了一组数据的平均大小。故题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/213.json b/MathToF/213.json
new file mode 100644
index 0000000000000000000000000000000000000000..93d2a8858e0d39b1c1957e4408bb49f0247302b6
--- /dev/null
+++ b/MathToF/213.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "7、3、9 可以组成3个两位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "可以分两步完成:先确定十位上的数，可以是3个数中任意一个数，共有3种可能，则个位上的数就有剩下的2个数中任意一个数的可能，则运用乘法原理计算共有3×2=6(个)."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/214.json b/MathToF/214.json
new file mode 100644
index 0000000000000000000000000000000000000000..9dbda339074054151e598d1b3bc493159bd97451
--- /dev/null
+++ b/MathToF/214.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "平年第二季度比闰年第二季度少一天"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据年月日的知识可知:一年12个月，分为4个季度，一个季度3个月，第二季度有:4、5、6月，4月和6月是小月有30天，5月是大月有31天，这是不变的，第二季度每年都是:30+30+31=91天，据此分析判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/215.json b/MathToF/215.json
new file mode 100644
index 0000000000000000000000000000000000000000..495eeaee792112e669670038dda933237c515e32
--- /dev/null
+++ b/MathToF/215.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1除以一个不是0的数，商是这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整数可以看作分母为1的分数，然后根据倒数的意义求解即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/216.json b/MathToF/216.json
new file mode 100644
index 0000000000000000000000000000000000000000..c5ddf37df51e016148c653bace6bbebf07823919
--- /dev/null
+++ b/MathToF/216.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分子和分母都是合数，这个分数一定不是最简分数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分子和分母都是合数，但这两个合数如果互质，则这个分数也是最简分数，如 \\frac{8}{9}，所以分子和分母都是合数，这个分数一定不是最简分数，错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/217.json b/MathToF/217.json
new file mode 100644
index 0000000000000000000000000000000000000000..8473a4a807b44f776cebebc42ce837b81afbbf36
--- /dev/null
+++ b/MathToF/217.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在整数7的后面添上两个0，这个数就扩大到原来的100倍。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整数7的后面添上两个0是700，这个数扩大哦到原来的100倍，原说法正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/218.json b/MathToF/218.json
new file mode 100644
index 0000000000000000000000000000000000000000..770e3170a4396de645368ead4d74923cbe635fe6
--- /dev/null
+++ b/MathToF/218.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母都乘上或除以一个相同的自然数，分数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分子和分母同时乘以或者除以相同的数(零除外)，分数的大小不变，这叫做分数的基本性质.明白自然数包括‘0‘，再根据分数的基本性质判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/219.json b/MathToF/219.json
new file mode 100644
index 0000000000000000000000000000000000000000..0881f8f63b11e6683c714b8aa4da59920ab6f13b
--- /dev/null
+++ b/MathToF/219.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "12÷6=2，所以6和2都是12的因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/22.json b/MathToF/22.json
new file mode 100644
index 0000000000000000000000000000000000000000..2f109d2f97f9f6b8775ecd7e62ef940cd637b5b4
--- /dev/null
+++ b/MathToF/22.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "开着的电风扇叶片的运动属于旋转现象。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "电风扇的运动是风叶绕中心轴转动，根据旋转的意义，把一个图形绕着某一点转动一个角度的图形变换叫做旋转，因此，电风扇的运动是旋转。题目说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/220.json b/MathToF/220.json
new file mode 100644
index 0000000000000000000000000000000000000000..bed9615277c6c9c04441d08d1c99ef2ca3f02cb6
--- /dev/null
+++ b/MathToF/220.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一杯牛奶，牛奶与水的比是1:4，喝掉一半后，牛奶与水的比是1:2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为这杯牛奶中牛奶与水的比1:4，喝掉一半后，即这杯牛奶的浓度不变，所以剩下的牛奶中牛奶与水的比不变.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/221.json b/MathToF/221.json
new file mode 100644
index 0000000000000000000000000000000000000000..33d630ba2ea3d90d26c91b828f2cb0d51ae50105
--- /dev/null
+++ b/MathToF/221.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相加的和一定是小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设这两个小数是2.6和1.4，然后再进一步解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/222.json b/MathToF/222.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c5492e69c238800d140d4c52b2b8b5efa740402
--- /dev/null
+++ b/MathToF/222.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1456-(324+456)=1456-456-324"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "减法性质:一个数连续减去两个数，可以用这个数减去两个数的和.如a-b-c=a-(b+c).据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/223.json b/MathToF/223.json
new file mode 100644
index 0000000000000000000000000000000000000000..18a09b4d6258a364f7510984f5716f377beb2015
--- /dev/null
+++ b/MathToF/223.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个乘数的末尾共有2个0，积的末尾只有2个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个乘数的末尾共有2个0，积的最后两位一定是0，不是只有2个0，如:40×50=2000，积的末尾有3个0."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/224.json b/MathToF/224.json
new file mode 100644
index 0000000000000000000000000000000000000000..eecb78b848d423ead34cacdaf9af29c9919523d2
--- /dev/null
+++ b/MathToF/224.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "我们学过的质量单位有吨、千克、克，它们相邻两个单位间的进率都是1000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "常用的质量单位有克、千克、吨，每相邻两个单位间的进率都是1000."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/225.json b/MathToF/225.json
new file mode 100644
index 0000000000000000000000000000000000000000..d3da29b2e221e38500af2fd05bff60db9b9b4f29
--- /dev/null
+++ b/MathToF/225.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个棱长4厘米的正方体，它的表面积和体积相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据正方体的表面积的意义、体积的意义，正方体的表面积是指它的6个面的总面积;正方体的体积是指正方体所占空间的大小;表面积与体积不是同类量，根本不能进行比较.据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/226.json b/MathToF/226.json
new file mode 100644
index 0000000000000000000000000000000000000000..e668e91e3595944af750b48bdeb7a8ba1640dd58
--- /dev/null
+++ b/MathToF/226.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果男生人数比女生人数多 \\frac{1}{8}，那么女生人数就比男生人数少 \\frac{1}{8}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "男生人数比女生人数多 \\frac{1}{8}，是以女生人数为单位‘1‘，女生人数比男生人数少，是以男生人数为单位‘1‘，单位‘1‘不同，所以多的和少的分数是不可能一样的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/227.json b/MathToF/227.json
new file mode 100644
index 0000000000000000000000000000000000000000..a4b3dfadf4320ecfdd9796dd0d88befeed71ccdc
--- /dev/null
+++ b/MathToF/227.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个圆柱削成一个最大的圆锥，削去部分的体积是圆锥体积的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "圆柱的体积是和它等底等高的圆锥体积的三倍，把圆柱削成最大的圆锥，则圆锥与圆柱等底等高，消去了两个圆锥的体积.也就是削去部分的体积是圆锥体积的2倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/228.json b/MathToF/228.json
new file mode 100644
index 0000000000000000000000000000000000000000..cb1cc5c0cff72be23f315a57d01dd069a78b7b54
--- /dev/null
+++ b/MathToF/228.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3米的 \\frac{1}{5}和1米的 \\frac{3}{5}一样长"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "要比较3米的 \\frac{1}{5}和1米的 \\frac{3}{5}的大小可通过计算进行比较，3米的 \\frac{1}{5}是3× \\frac{1}{5}= \\frac{3}{5}(米)，1米的 \\frac{3}{5}是1× \\frac{3}{5}= \\frac{3}{5}(米)，然后比较大小即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/229.json b/MathToF/229.json
new file mode 100644
index 0000000000000000000000000000000000000000..a9bf5fd4b1ed7077486091b933488067ad72b329
--- /dev/null
+++ b/MathToF/229.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5÷( \\frac{5}{7}+ \\frac{5}{9})=5÷ \\frac{5}{7}+5÷ \\frac{5}{9}=16"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "乘法的分配律的内容是:两个数的和与一个数相乘，可以先把它们分别与这个数相乘，再相加，积不变."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/23.json b/MathToF/23.json
new file mode 100644
index 0000000000000000000000000000000000000000..fccefc2eea67005692137a750e0ba27540a93379
--- /dev/null
+++ b/MathToF/23.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "有限小数比无限小数小"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "有限小数有的比无限小数大，有的比无限小数小.可以举出反例加以解答即可，比如0.7比0.666666...大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/230.json b/MathToF/230.json
new file mode 100644
index 0000000000000000000000000000000000000000..43272f1e965fa090f4d1613c1f87288825b27a79
--- /dev/null
+++ b/MathToF/230.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小明面向西方，他的左边是南方，右边是北方"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "小明面向西方，他的左边是南方，右边是北方，可以亲自体验一下，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/231.json b/MathToF/231.json
new file mode 100644
index 0000000000000000000000000000000000000000..510d807ee05dd1742f4e92a398e2ed69e97af76a
--- /dev/null
+++ b/MathToF/231.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0+0+0+0=0×4=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "求几个相同加数的和的简便运算，叫做乘法.依此即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/232.json b/MathToF/232.json
new file mode 100644
index 0000000000000000000000000000000000000000..3cf4a8a1fe1ce4f968f60e677bad95c4f49cb258
--- /dev/null
+++ b/MathToF/232.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一辆卡车每次可运水泥3吨"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据生活经验、对质量单位和数据大小的认识，可知计量一辆卡车每次可运水泥的重量，应用质量单位，结合数据可知:应用‘吨‘做单位;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/233.json b/MathToF/233.json
new file mode 100644
index 0000000000000000000000000000000000000000..23a1ec1dd5f9bd5db7c01e26556d322f3d29fee8
--- /dev/null
+++ b/MathToF/233.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在50米赛跑中，小东用了11秒，小刚用了10秒，小东跑得快"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "路程相同的情况下，谁用的时间少，谁跑的就快，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/234.json b/MathToF/234.json
new file mode 100644
index 0000000000000000000000000000000000000000..91bb346fc3382f6d290f44e036149c16bdc0b75a
--- /dev/null
+++ b/MathToF/234.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在小数0.7和0.9之间只有一个小数0.8。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0.7和0.9之间有无数个小数，如0.71，0.72，0.79，0.777..."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/235.json b/MathToF/235.json
new file mode 100644
index 0000000000000000000000000000000000000000..0ba9b5af3456d788b8f59a2b8007d46e2f60c7a0
--- /dev/null
+++ b/MathToF/235.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "4个同样大小正方形，可以拼成一个大的正方形，也可以拼成一个长方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "用4个同样大小的正方形拼组，有2种不同的拼组方法:一字排列，可以组成一个长方形，2×2排列，可以组成一个正方形，据此即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/236.json b/MathToF/236.json
new file mode 100644
index 0000000000000000000000000000000000000000..5b559fb2f938dd69e5486115c86e29e4d42861bc
--- /dev/null
+++ b/MathToF/236.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两位数乘两位数，其中一个因数的末尾有一个0，积的末尾一定只有一个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "其中一个因数末尾有一个零，说明另一个因数末尾没有0，根据一因数末尾有零的乘法的计算法则可知，可以先把这个末尾有零的因数的零前面的数与另一个因数相乘，然后在乘得的积的后面加上两个零，所以积的末尾至少有1个0，但积的末尾不一定只有一个零，可以举出反例证明."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/237.json b/MathToF/237.json
new file mode 100644
index 0000000000000000000000000000000000000000..33e54158045eb8b6e40a47437866301f45a3aa42
--- /dev/null
+++ b/MathToF/237.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个圆柱削成最大的圆锥，削去部分的体积是圆锥的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把一个圆柱削成一个最大的圆锥，则这个圆柱与圆锥等底等高，所以圆柱是圆锥的体积的3倍，则削去部分的体积是圆锥的体积就是的2倍，由此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/238.json b/MathToF/238.json
new file mode 100644
index 0000000000000000000000000000000000000000..d5ef7b8ca8b338b7bf8509f8e25afd5806fbfade
--- /dev/null
+++ b/MathToF/238.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲厂生产一批化肥要用2小时，乙厂生产这批化肥要用3小时，乙厂的工作效率比甲厂的快"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把工作总量看作单位‘1‘，除以工作时间即工作效率，然后即可比较出快慢."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/239.json b/MathToF/239.json
new file mode 100644
index 0000000000000000000000000000000000000000..460fb2bf7efa04ef4ea4c20575c462376a101f14
--- /dev/null
+++ b/MathToF/239.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "电风扇转动时，扇叶的运动是平移现象。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个图形整体沿某一方向移动一定的距离，图形的这种移动，叫做平移;在平面内，一个图形绕着一个定点旋转一定的角度得到另一个图形的变化叫做旋转。 电风扇转动时，扇叶的运动是旋转现象。原题说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/24.json b/MathToF/24.json
new file mode 100644
index 0000000000000000000000000000000000000000..947f51bd7569708b180726e70acfc1001c5342a6
--- /dev/null
+++ b/MathToF/24.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果x=y÷4，(x、y都不等于0)，那么x与y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/240.json b/MathToF/240.json
new file mode 100644
index 0000000000000000000000000000000000000000..df39885c82a7bfc5383088bfef66d39e50984252
--- /dev/null
+++ b/MathToF/240.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果 \\frac{n}{m}是真分数，则 \\frac{m}{n}一定是假分数(m和n都不为0)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "真分数是指分子小于分母的分数，但它们的倒数都是分子大于分母的分数即假分数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/241.json b/MathToF/241.json
new file mode 100644
index 0000000000000000000000000000000000000000..81240d6b8370602f7fa2a533eaed5f4c2d114208
--- /dev/null
+++ b/MathToF/241.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一批产品共110个，110个合格，合格率是100%"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "先理解合格率，合格率是指合格的产品数占产品总数的百分之几，计算方法为:合格产品数÷产品总数×100%=合格率，由此代入数据列式解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/242.json b/MathToF/242.json
new file mode 100644
index 0000000000000000000000000000000000000000..ef7adbac396544eebd91b10559c17c34c496ba5f
--- /dev/null
+++ b/MathToF/242.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个直角三角形三条边分别是6厘米、8厘米、10厘米，这个三角形的面积是40平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据在直角三角形中斜边最长，可知道:这个直角三角形的直角边分别是8厘米和6厘米，利用三角形的面积公式即可求其面积."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/243.json b/MathToF/243.json
new file mode 100644
index 0000000000000000000000000000000000000000..d012ce92995330315faa76db2abde302403c18c7
--- /dev/null
+++ b/MathToF/243.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把175-87=88，88÷2=44，这两个算式写成一个算式是:175-87÷2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先算减法175-87=88，再算除法88÷2=44，由此顺序列出综合算式即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/244.json b/MathToF/244.json
new file mode 100644
index 0000000000000000000000000000000000000000..acdef82d15a2d614e75a974f76a4701588235e51
--- /dev/null
+++ b/MathToF/244.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在100克水中放入10克糖，糖的质量占糖水质量的10%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "运用加法求出糖水的质量:100+10=110(克);用糖的质量除以糖水的质量，即得糖占糖水的百分之几."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/245.json b/MathToF/245.json
new file mode 100644
index 0000000000000000000000000000000000000000..2050f4eeb8bd389f5a5185db0a0ca25e96d5f6a9
--- /dev/null
+++ b/MathToF/245.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "194÷4的商接近40"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "除法的估算，一般要根据‘四舍五入‘法把数看作是整十、整百、整千…的数来进行计算，然后按表内除法的计算方法计算即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/246.json b/MathToF/246.json
new file mode 100644
index 0000000000000000000000000000000000000000..cb014f73cb3d4ba16bbef05b21f0623a748ba89c
--- /dev/null
+++ b/MathToF/246.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "9÷ \\frac{2}{3}=9× \\frac{2}{3}=6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数除法除法的计算法则，求出结果即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/247.json b/MathToF/247.json
new file mode 100644
index 0000000000000000000000000000000000000000..8e73752ee8386569dcb69e105664c5667f84ad88
--- /dev/null
+++ b/MathToF/247.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "为清楚地表示出数量的增减变化情况，可选用折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/248.json b/MathToF/248.json
new file mode 100644
index 0000000000000000000000000000000000000000..336bab906a77728086d442000cc6ee89f5fc127d
--- /dev/null
+++ b/MathToF/248.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三个连续的非零自然数中，一定有一个数是3的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据3的倍数的特征，各位上的数字之和是3的倍数，这个数一定是3的倍数，所有的非零自然数除以3的余数只有3种情况:正好整除、余数是1、余数是2，且周期出现，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/249.json b/MathToF/249.json
new file mode 100644
index 0000000000000000000000000000000000000000..f76c5eae63b1b531f95a211a3c6bd19f71780f00
--- /dev/null
+++ b/MathToF/249.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "笔算减法时，哪一位不够减，从前一位退1，在本位上加1再减"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，由减法的计算方法进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/25.json b/MathToF/25.json
new file mode 100644
index 0000000000000000000000000000000000000000..a56784758b79512f9b5d7d79f1a9f1086b6c0815
--- /dev/null
+++ b/MathToF/25.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一辆客车2小时行了160千米，照这样的速度，它一天可以行1920千米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一天有24小时，即有12个2小时，列竖式算出12×16=192，被乘数扩大10倍，则答案为1920。则判断正确。   理解题意后，列出算式，根据竖式运算得出12×16的答案，再由积的变化规律得出答案后作出判断。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/250.json b/MathToF/250.json
new file mode 100644
index 0000000000000000000000000000000000000000..7f506a9af757935c93ea9df88546d2af9b78a2d1
--- /dev/null
+++ b/MathToF/250.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "学校举行课外阅读比赛，四(1)班同学平均得分95分，四(2)班同学平均得分也是95分，那么四(1)班得分最高的同学和四(2)班得分最高的同学得分一定相同。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "平均数据代表一组数据的平均特征，并不代表每个数据，因此每个班的最高分不一定相同。 故题目中说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/251.json b/MathToF/251.json
new file mode 100644
index 0000000000000000000000000000000000000000..f5150dd0fc414a50762adff6d1405574cc220a72
--- /dev/null
+++ b/MathToF/251.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "15×12=15×2×6"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在计算15×12时，把12看作2×6，因为15与2结合能凑成整十数进行简算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/252.json b/MathToF/252.json
new file mode 100644
index 0000000000000000000000000000000000000000..d06f7b708bab0f1d4937f7eeb6d0e7ae619b6b90
--- /dev/null
+++ b/MathToF/252.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "晚上，当你面对北极星时，你的左边是西，右边是东"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "面对北极星就是面对北方，因为北极星在天的北面，后面是北的对面南，左面是西，右面是东，可以晚上面对北极星亲自体验一下更好理解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/253.json b/MathToF/253.json
new file mode 100644
index 0000000000000000000000000000000000000000..09ae951249030909ea07b1d0e496e44c0cfa08ae
--- /dev/null
+++ b/MathToF/253.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "乘数的末尾有3个0，积的末尾也可能有3个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，假设一个数是2000，另一个数是3或5，分别求出它们的乘积，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/254.json b/MathToF/254.json
new file mode 100644
index 0000000000000000000000000000000000000000..4dacb423ab68952c88fec2766bb4a2716f5a7bf7
--- /dev/null
+++ b/MathToF/254.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果5.4×a>5.4×b(a、b都不为0)那么a>b"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据一个因数不变，另一个因数越大(0除外)，积越大;由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/255.json b/MathToF/255.json
new file mode 100644
index 0000000000000000000000000000000000000000..dfad85e35a0d78568f63cde0c404c50f995dbded
--- /dev/null
+++ b/MathToF/255.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "面积1平方米的图形，一定是边长为1米的正方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题没说是什么图形，如:长是5米、宽是0.2米的长方形它的面积是:5×0.2=1(平方米)，所以不能确定是什么图形;据此即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/256.json b/MathToF/256.json
new file mode 100644
index 0000000000000000000000000000000000000000..f8a059b592f7cc6b7961b68e58e775e0f53d7cf7
--- /dev/null
+++ b/MathToF/256.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "十万十万地数，九百九十万后面一个数是九百九十一万"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "十万十万地数，九百九十万后面一个数是九百九十万加上十万，是一千万."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/257.json b/MathToF/257.json
new file mode 100644
index 0000000000000000000000000000000000000000..989dc1e96dc2d59ac82588130a5288fcc1ee75aa
--- /dev/null
+++ b/MathToF/257.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "折线统计图既可以表示数量的多少，又可以表示数量的增减变化情况."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "折线统计图既可以表示数量的多少，又可以表示数量的增减变化情况。正确  根据折线统计图的特点，折线统计图既可以表示数量的多少，又可以表示数量的增减变化情况。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/258.json b/MathToF/258.json
new file mode 100644
index 0000000000000000000000000000000000000000..f0eaf1afa0af65c86eabc8f0ffe8d6defa15dffa
--- /dev/null
+++ b/MathToF/258.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "车轮直径一定，所行驶的路程和车轮转数成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/259.json b/MathToF/259.json
new file mode 100644
index 0000000000000000000000000000000000000000..996587c85b8c311d3f90b18bdbe5723c7989e345
--- /dev/null
+++ b/MathToF/259.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "16的因数有1、2、4、4、8、16这6个"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据找一个数因数的方法，列举出16的因数，即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/26.json b/MathToF/26.json
new file mode 100644
index 0000000000000000000000000000000000000000..2d08985a4382464b2e072bc181ee238f3992f05b
--- /dev/null
+++ b/MathToF/26.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "34-4-6=34-(4+6)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "运用了加法结合律，原说法正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/260.json b/MathToF/260.json
new file mode 100644
index 0000000000000000000000000000000000000000..6702d5619942dd1b8c5dddd2246ed1b44a1bf984
--- /dev/null
+++ b/MathToF/260.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{3}{10}=30%，所以 \\frac{3}{10}米=30%米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的意义与百分数的意义不相同.百分数是表示一个数是另一个数的百分之几的数，也叫百分率或百分比;百分数不能表示某一具体数量，而分数能表示具体的数量;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/261.json b/MathToF/261.json
new file mode 100644
index 0000000000000000000000000000000000000000..fc7f68198f9cfaba6f4a40189f74d504863d147b
--- /dev/null
+++ b/MathToF/261.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "带分数比假分数大，假分数比真分数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "带分数是分子大于分母的假分数的另一种表现形式，所以带分数是假分数中的一部分，它们无法比较大小.据此判断为错误;假分数就是分子大于或等于分母的分数，假分数大于等于1;真分数是分子小于分母的分数，真分数都小于1，所以假分数比真分数大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/262.json b/MathToF/262.json
new file mode 100644
index 0000000000000000000000000000000000000000..135424aa75f272170b804b23b7fcf9e0c5e0f0cc
--- /dev/null
+++ b/MathToF/262.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为0.6小于0.83，所以0.6的计数单位小于0.83的计数单位"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0.6是一位小数，计数单位是0.1，0.83是两位小数，计数单位是0.01，0.1>0.01，所以0.6的计数单位大于0.83的计数单位;由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/263.json b/MathToF/263.json
new file mode 100644
index 0000000000000000000000000000000000000000..fb28053a8bab7ad2094b1945534091b1b6132022
--- /dev/null
+++ b/MathToF/263.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数的和是偶数，两个奇数的积是合数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据奇数和偶数的性质:两个偶数的和或差仍是偶数，两个奇数的和或差也是偶数，奇数和偶数的和或差是奇数;根据奇数的意义可知，1是奇数，任何一个非零自然数相乘与1相乘仍得原数，又根据质数的意义，质数中除了2之外，都为奇数，则两个奇数相乘的积不一定是合数，如1×3=3，积仍为质数。 根据奇数和偶数的性质可知，两个奇数的和是一定偶数。 根据奇数、质数与合数的意义可知，两个奇数的积是不一定合数，如1×3=3，积仍为质数。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/264.json b/MathToF/264.json
new file mode 100644
index 0000000000000000000000000000000000000000..03f5873bf44781089a809fcea456ca1acc36b7e9
--- /dev/null
+++ b/MathToF/264.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "120÷3×4=120÷(3×4)"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "120÷3×4按照从左到右的顺序计算，120÷(3×4)按照先算小括号里面的乘法，再算括号外的除法，计算出算式的结果，再比较."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/265.json b/MathToF/265.json
new file mode 100644
index 0000000000000000000000000000000000000000..162671ecb900605ec4d5b56ca8a2a52771c5398e
--- /dev/null
+++ b/MathToF/265.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相乘，积一定小于其中任何一个数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个小数都大于1时，它们的积，都大于任意一个因数.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/266.json b/MathToF/266.json
new file mode 100644
index 0000000000000000000000000000000000000000..2779c065d3de72c6424e65cf760137649dffb09f
--- /dev/null
+++ b/MathToF/266.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "面对早晨的太阳，你的右手边是南方"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "早晨的太阳是在东面，当你面对太阳时，说明你面向东方，又因为东和西相对，所以即可得出你的后面是西面，左面是北面，右面是南面，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/267.json b/MathToF/267.json
new file mode 100644
index 0000000000000000000000000000000000000000..b2f40d38b0facde5f49ec3edc678ab3b134bcadb
--- /dev/null
+++ b/MathToF/267.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个自然数，缩小10倍后仍是自然数，原数一定是2和5的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "试题分析:个位上是0，2，4，6，8的自然数一定能被2整除，个位上是0或5的自然数一定能被5整除.据此解答. 解:根据分析知:个位上是0的自然数符合能被2和5整除数的特征，所以个位上是0的自然数一定是2和5的倍数，缩小10倍，10是2和5的倍数. 所以一个自然数，缩小10倍后仍是自然数，原数一定是2和5的倍数说法正确. 故答案为:√."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/268.json b/MathToF/268.json
new file mode 100644
index 0000000000000000000000000000000000000000..9923b10ef9e60724c874284cac3e1d71f25fc7e0
--- /dev/null
+++ b/MathToF/268.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求6个 \\frac{3}{4}相加的和是多少，列式为6+ \\frac{3}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据乘法的意义列出乘法算式求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/269.json b/MathToF/269.json
new file mode 100644
index 0000000000000000000000000000000000000000..28d9659661451464ce0cb6aabafd2f327601d17c
--- /dev/null
+++ b/MathToF/269.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三角形的面积与和它等底等高的平行四边形面积比是1:2"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为两个完全一样的三角形可以拼成一个平行四边形，所以三角形的面积是与它等底等高的平行四边形面积的 \\frac{1}{2}.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/27.json b/MathToF/27.json
new file mode 100644
index 0000000000000000000000000000000000000000..7ff7f0395a85230f899e0e58dfd6ea11823ec376
--- /dev/null
+++ b/MathToF/27.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把6分解质因数是6=1×2×3"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分解质因数就是把一个合数写成几个质数的连乘积形式，一般先从简单的质数试着分解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/270.json b/MathToF/270.json
new file mode 100644
index 0000000000000000000000000000000000000000..1a206b85283d3fddc8801471b20138fae6a066d6
--- /dev/null
+++ b/MathToF/270.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "拧水龙头是旋转现象.荡秋千的运动是平移"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据平移的意义，在平面内，将一个图形沿某个方向移动一定的距离，这样的图形运动称为平移;根据旋转的意义，在平面内，将一个图形饶一个定点沿某个方向转动一个角度，这样的图形运动称为旋转."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/271.json b/MathToF/271.json
new file mode 100644
index 0000000000000000000000000000000000000000..38eb033e6ec31fdc4864a9e9fb046307280d47d6
--- /dev/null
+++ b/MathToF/271.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "打开水龙头是旋转现象"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在平面内，将一个图形绕一点按某个方向转动一个角度，这样的运动叫作图形的旋转.这个定点叫做旋转中心，转动的角度叫做旋转角."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/272.json b/MathToF/272.json
new file mode 100644
index 0000000000000000000000000000000000000000..99ffb455c5b6361886646e22c485cdaa0bddce92
--- /dev/null
+++ b/MathToF/272.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "7×0=7+0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0乘任何不是0的数都得0，0加任何数仍得任何数，据此进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/273.json b/MathToF/273.json
new file mode 100644
index 0000000000000000000000000000000000000000..15336fb2949b12d9038675b8645f47ecade839dc
--- /dev/null
+++ b/MathToF/273.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "同一物体的形状从不同角度观察到的形状一定相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "对应一般的物体，从不同的位置观察物体，所看到的形状是不同的;但有特殊情况，如果这个物体是正方体，那么从正面、侧面和上面看到的都是一个正方形，即看到的形状一样;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/274.json b/MathToF/274.json
new file mode 100644
index 0000000000000000000000000000000000000000..a43aafc207550246157ab9fae5eb141bb6c75e7b
--- /dev/null
+++ b/MathToF/274.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "面积相等的两个圆，周长一定相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆的面积公式:s=π\\( r^{2} \\)，如果两个圆的面积相等，那么它们的半径也相等;再根据圆的周长公式:c=2πr，它们的周长也相等.由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/275.json b/MathToF/275.json
new file mode 100644
index 0000000000000000000000000000000000000000..7f5db6e5583f801969bca8f037c1dc91b947b475
--- /dev/null
+++ b/MathToF/275.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个梯形的高是6厘米，下底是12厘米，上底是8厘米，这个梯形的面积是120平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据梯形的面积=(上底+下底)×高÷2，代入数据即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/276.json b/MathToF/276.json
new file mode 100644
index 0000000000000000000000000000000000000000..e789459e569b8b841618105198c5ad90b32f05e4
--- /dev/null
+++ b/MathToF/276.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2×6=12，12÷2=6，所以0×3=0，0÷0=3"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据除数不等于0即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/277.json b/MathToF/277.json
new file mode 100644
index 0000000000000000000000000000000000000000..203778cc0ab150823691fa2db250fda2dcd6cd85
--- /dev/null
+++ b/MathToF/277.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "上海华联超市商品打八折出售，就是便宜80%。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "1-80%=20%所以，现价比原价便宜了20%，不是80%。  八折是指现价是原价的80%，把原价看成单位‘1‘，现价比原价便宜的钱数是原价的(1-80%)，注意应用题的理解。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/278.json b/MathToF/278.json
new file mode 100644
index 0000000000000000000000000000000000000000..4ae6c0248257c91e18f9e8dacf00a1249640f8a4
--- /dev/null
+++ b/MathToF/278.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1千米的 \\frac{3}{4}与3千米的 \\frac{1}{4}的长度是相等的"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分别把1千米、3米千看作单位‘1‘，根据一个数乘分数的意义，用乘法分别求出1千米的 \\frac{3}{4}是多少千米、3千米的 \\frac{1}{4}是多少千米，然后进行比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/279.json b/MathToF/279.json
new file mode 100644
index 0000000000000000000000000000000000000000..5b10064d2e6715a6ecfe8714660a163f0609514f
--- /dev/null
+++ b/MathToF/279.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆规的两个脚之间的距离是5厘米，则画出圆的周长是15.7厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据画圆的方法可知这个圆的半径是5厘米，利用圆的周长公式即可计算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/28.json b/MathToF/28.json
new file mode 100644
index 0000000000000000000000000000000000000000..320c4dc5436c23fecf821e520348e7cac5da68cc
--- /dev/null
+++ b/MathToF/28.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{4}{5}和 \\frac{5}{4}的乘积为1，所以 \\frac{4}{5}是倒数， \\frac{5}{4}也是倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义:乘积是1的两个数互为倒数，即可得到答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/280.json b/MathToF/280.json
new file mode 100644
index 0000000000000000000000000000000000000000..f6148146f779f578bc1dbefae86a55e4747ff81b
--- /dev/null
+++ b/MathToF/280.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "245-173+27=245-(173+27)"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "245-173+27从左往右计算，245-(173+27)先算小括号里面的加法，再算括号外面的减法即可求解，."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/281.json b/MathToF/281.json
new file mode 100644
index 0000000000000000000000000000000000000000..49f553f143dd750aab1318be88f1791d887ffadd
--- /dev/null
+++ b/MathToF/281.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "昨天最低气温是-2摄氏度，今天最低气温是-1摄氏度，所以今天比昨天冷"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正数>0>负数，几个负数比较大小时，绝对值越大的负数越小，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/282.json b/MathToF/282.json
new file mode 100644
index 0000000000000000000000000000000000000000..0cc00058417247aaa9130d859787e13e34c7a5c0
--- /dev/null
+++ b/MathToF/282.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1.153里面有153个0.001。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "1.153里面有1153个0.001"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/283.json b/MathToF/283.json
new file mode 100644
index 0000000000000000000000000000000000000000..0e97023c3914f1e24ba2fabf24c2d3549e4749a4
--- /dev/null
+++ b/MathToF/283.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "462-25+75与462-(25+75)的得数相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "462-25+75与462-(25+75)的得数不相等，462-25+75与462-(25-75)相等，所以原说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/284.json b/MathToF/284.json
new file mode 100644
index 0000000000000000000000000000000000000000..e440049aafd174112ab21c2c79468cdbbc315b2c
--- /dev/null
+++ b/MathToF/284.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "男生人数比女生人数少80%，那么男生与女生的比是1:5"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把女生人数看作单位‘1‘，则男生人数是女生人数的(1-80%)，进而根据题意进行比即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/285.json b/MathToF/285.json
new file mode 100644
index 0000000000000000000000000000000000000000..0a8f3485d909617b14925d098947e568c4dd0b6e
--- /dev/null
+++ b/MathToF/285.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "12×25×2=12×(25×2)运用了乘法分配律。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "运用的是乘法结合律"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/286.json b/MathToF/286.json
new file mode 100644
index 0000000000000000000000000000000000000000..5a7aa1a51ad2cb6680a2ab601b8db6199ea37926
--- /dev/null
+++ b/MathToF/286.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "将两个棱长为3厘米的正方体拼成一个长方体，表面积减少18cm2"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "由题意得:减少部分是这个正方体的两个面的面积，由此解答出正确的结果，即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/287.json b/MathToF/287.json
new file mode 100644
index 0000000000000000000000000000000000000000..553559deb4d9ec8e1cfcbba1a49167604b5e17a5
--- /dev/null
+++ b/MathToF/287.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在制作扇形统计图时，总的数量越多，所画的圆就越大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据扇形统计图的特点可知:在制作扇形统计图时，总的数量越多，所画的圆就越大，说法不对。根据扇形统计图的意义，扇形统计图是用整个圆表示总数用圆内各个扇形的大小表示各部分数量占总数的百分数.用整个圆的面积表示总数，用圆的扇形面积表示各部分占总数的百分数。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/288.json b/MathToF/288.json
new file mode 100644
index 0000000000000000000000000000000000000000..a0615260b49a7aea020f64d674b4245bdab7a36e
--- /dev/null
+++ b/MathToF/288.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1.7除以0.3的商是5，余数是2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，被除数=商×除数+余数，可得:被除数-余数=商×除数;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/289.json b/MathToF/289.json
new file mode 100644
index 0000000000000000000000000000000000000000..4f5bd840d4e7c6e928f6715e105d837bd900c9be
--- /dev/null
+++ b/MathToF/289.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小明家在学校东偏南30°的方向上，则学校在小明家西偏北30°的方向上"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据位置的相对性可知，它们的方向相反，角度相等，距离相等，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/29.json b/MathToF/29.json
new file mode 100644
index 0000000000000000000000000000000000000000..e2ba14b1ec1ecbae1d239f82cfc52d26c1db2c80
--- /dev/null
+++ b/MathToF/29.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "表示某地一年中12个月的气温变化情况，用折线统计图比较合适。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据折线统计图的特点可知:表示一年12个月的气温变化情况，应选择折线统计图;  正确.  本题考点:统计图的选择.  解答此题应根据条形、折线、扇形统计图的特点进行解答.  (1)条形统计图的特点:能清楚的表示出数量的多少;  (2)折线统计图的特点:不但可以表示出数量的多少，而且能看出各种数量的增减变化情况;  (3)扇形统计图比较清楚地反映出部分与部分、部分与整体之间的数量关系;据此进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/290.json b/MathToF/290.json
new file mode 100644
index 0000000000000000000000000000000000000000..f957691be341e58fda32f11a1e4994f029533646
--- /dev/null
+++ b/MathToF/290.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为12÷0.3=40，所以12是0.3的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义，因数和倍数是在非0自然数范围内进行研究，以此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/291.json b/MathToF/291.json
new file mode 100644
index 0000000000000000000000000000000000000000..e14da16bff93829c2eeb9b8e3ec6ed1a35db1541
--- /dev/null
+++ b/MathToF/291.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为5×6=30，所以5和6是因数，30是倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/292.json b/MathToF/292.json
new file mode 100644
index 0000000000000000000000000000000000000000..4274ecc7241dc083851a65f59fc0c97a9a19b8f7
--- /dev/null
+++ b/MathToF/292.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根绳子长\\frac{3}{7}米，用去\\frac{1}{7}后，还剩\\frac{2}{7}米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用去\\frac{1}{7}后，还剩下1-\\frac{1}{7}=\\frac{6}{7}，再用乘法求出剩下的米数，从而作出判断。 \\frac{3}{7}×(1-\\frac{1}{7})=\\frac{3}{7}×\\frac{6}{7}=\\frac{18}{49}(米) 故原题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/293.json b/MathToF/293.json
new file mode 100644
index 0000000000000000000000000000000000000000..342a34372bae509167439c112d081f618e70fa84
--- /dev/null
+++ b/MathToF/293.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个乘数的末尾各有一个0，积的末尾至少有两个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "计算整数乘法时，如果被乘数、乘数末尾有0，可以先把0前面的数相乘，然后看被乘数、乘数末尾一共有几个零，就在乘得的数的末尾填写几个0，由此可知，则乘数的末尾有几个0，积的末尾至少有几个0，如230×20=4600，至少有两个零，34×30=1020，末尾有一个零.因此，此说法是正确的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/294.json b/MathToF/294.json
new file mode 100644
index 0000000000000000000000000000000000000000..29b0661e92ecf4bfe3b81d40796c63827ddb58b7
--- /dev/null
+++ b/MathToF/294.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个边长是10厘米的正方形，如果从四个角分别剪去一个边长1厘米的小正方形，那么它的周长变大了"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据正方形的特征，4条边的长度都相等，如果一个角剪去一个边长1厘米的小正方形，因为把剪去部分所显示的边长经过平移，又恢复到原来的形状，所以周长不变.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/295.json b/MathToF/295.json
new file mode 100644
index 0000000000000000000000000000000000000000..672d9a0da38ae746c80cb24f34172f1699414d4f
--- /dev/null
+++ b/MathToF/295.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果两个圆的面积相等，那么这两个圆的周长也相等."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分析:根据圆的面积公式知，两个圆的面积相等，它们的半径就相等，半径相等的圆的周长也相等.据此解答. 解答:根据圆的面积公式知，两个圆的面积相等，它们的半径就相等，半径相等的圆的周长也相等. 所以如果两个圆的面积相等，那么这两个圆的周长也相等. 故答案为:正确. 点评:本题主要考查了学生依据圆面积和周长公式的知识解答问题的能力."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/296.json b/MathToF/296.json
new file mode 100644
index 0000000000000000000000000000000000000000..7e971346c7f84fded1d68685eff45654f857ddeb
--- /dev/null
+++ b/MathToF/296.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{2}{8}和 \\frac{1}{4}大小相等，分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "看分母，去理解意义与分数单位，比较两个分数，首先通分，化为同分母分数即可比较大小，由此逐一判定即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/297.json b/MathToF/297.json
new file mode 100644
index 0000000000000000000000000000000000000000..dc2d9edb913a9e69e237ee8b217605b5cccf55ce
--- /dev/null
+++ b/MathToF/297.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1升水如果用400毫升的纸杯来装，至少需要3只纸杯。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1升=1000毫升 1000÷400=2 (只)…200 (毫升) 2+1=3(只) 因此至少需要三个纸杯，故题目中说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/298.json b/MathToF/298.json
new file mode 100644
index 0000000000000000000000000000000000000000..c7803168c60d6763501e3aa264f41439f5cfe8c9
--- /dev/null
+++ b/MathToF/298.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0×39>0×10"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数乘法的计算方法，分别求出0×39与0×10的结果，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/299.json b/MathToF/299.json
new file mode 100644
index 0000000000000000000000000000000000000000..2f1175a74f7625a7089700ebecf2a9dcc1d02aad
--- /dev/null
+++ b/MathToF/299.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "与十亿位相邻的两个数位是亿位和百亿位。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "数位顺序表为:千亿位、百亿位、十亿位 、亿位、千万位、百万位、十万位、万位、千位、百位、十位。可以发现与十亿位相邻的两个数位是亿位和百亿位，故题干表述正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/3.json b/MathToF/3.json
new file mode 100644
index 0000000000000000000000000000000000000000..172cfb590ddb133b21b6cc3425c95b2519801ed1
--- /dev/null
+++ b/MathToF/3.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "31×69的积大约是2100"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "估算31×69时要把31看作30，69看作70进行估算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/30.json b/MathToF/30.json
new file mode 100644
index 0000000000000000000000000000000000000000..f2439666eb0aa7e3f5a6c84c11b18f75e3e032fd
--- /dev/null
+++ b/MathToF/30.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8×0=0÷8=8÷0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0表示没有，由此可知，0乘任何数得0，0除以一个不为0的数得0，根据除法的意义，0不能做除数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/300.json b/MathToF/300.json
new file mode 100644
index 0000000000000000000000000000000000000000..b68caa267f767ddc279752cf76515b93c50efad5
--- /dev/null
+++ b/MathToF/300.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "25×4÷25×4=100÷100=1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "25×4÷25×4计算顺序为先算25×4，再算除以25，最后乘以4，所以25×4÷25×4=100÷25×4=4×4=16，所以原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/301.json b/MathToF/301.json
new file mode 100644
index 0000000000000000000000000000000000000000..37659ba29e3a4810f9c7560d98fb67475d645963
--- /dev/null
+++ b/MathToF/301.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{1}{3}小时:40分钟化成最简整数比是1:2"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "先把比的前项 \\frac{1}{3}小时化成 \\frac{1}{3}×60=20分钟，再根据比的基本性质，即比的前项和后项同时乘或除以一个相同的数(0除外)比值不变，进而把比化成最简比进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/302.json b/MathToF/302.json
new file mode 100644
index 0000000000000000000000000000000000000000..220bed9ba5abd9c03564ab77e3f7065f15e4ade2
--- /dev/null
+++ b/MathToF/302.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，积一定大于其中一个因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "假设其中的一个因数为0，那么积就不大于其中任一个因数;据此进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/303.json b/MathToF/303.json
new file mode 100644
index 0000000000000000000000000000000000000000..621e2c5a93c82f453e3c2d28c0b00079fc9d9d5e
--- /dev/null
+++ b/MathToF/303.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "下面的图案是经过旋转得到的。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "观察图形，图中所有的蝴蝶大小相同，形状相同、方向相同，是平移得到的，题中说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/304.json b/MathToF/304.json
new file mode 100644
index 0000000000000000000000000000000000000000..c56d89510c437fd18590d30071f95c1be1db2d03
--- /dev/null
+++ b/MathToF/304.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "2.5×3与3×2.5的结果相同，意义也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "2.5×3与3×2.5结果相同，但意义不同，2.5×3表示3个2.5相加的和是多少，3×2.5表示3的2.5倍是多少."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/305.json b/MathToF/305.json
new file mode 100644
index 0000000000000000000000000000000000000000..b7b81fc8cdc4a73658f9473ce7520a022b6f6ca0
--- /dev/null
+++ b/MathToF/305.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{6}{8}和 \\frac{3}{4}大小相等，但分数单位不同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数和分数单位的意义，可知 \\frac{6}{8}表示把单位‘1‘平均分成8份，表示其中的6份，分数单位是 \\frac{1}{8};而 \\frac{3}{4}表示把单位‘1‘平均分成4份，表示其中的3份，分数单位是 \\frac{1}{4};所以它们的单位不同;根据分数的性质，可知 \\frac{6}{8}和 \\frac{3}{4}大小相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/306.json b/MathToF/306.json
new file mode 100644
index 0000000000000000000000000000000000000000..2523689d58001f55111b00e897523a8a80d617e8
--- /dev/null
+++ b/MathToF/306.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "男生人数比女生多 \\frac{3}{5}，则女生人数比男生少 \\frac{3}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "(1)根据‘男生人数比女生人数多 \\frac{3}{5}‘，把女生人数看作单位‘1‘，可知女生人数是5份，男生人数是5+3=8(份);  (2)女生人数比男生人数少几分之几，是把男生人数看作单位‘1‘，用女生人数比男生人数少的份数除以男生的份数，即3÷8= \\frac{3}{8};据此判断得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/307.json b/MathToF/307.json
new file mode 100644
index 0000000000000000000000000000000000000000..b4ae02f5564ba6d4b31414478f575cd4c77a584e
--- /dev/null
+++ b/MathToF/307.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "克、千克、吨每相邻两个单位间的进率都是1000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "常用的质量单位有克、千克、吨，每相邻两个单位间的进率都是1000."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/308.json b/MathToF/308.json
new file mode 100644
index 0000000000000000000000000000000000000000..677afa9e027a38931122ec7380323d7e0910b90c
--- /dev/null
+++ b/MathToF/308.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3.2×0.4÷3.2×0.4=1÷1=1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据乘法的交换律、结合律进行简算即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/309.json b/MathToF/309.json
new file mode 100644
index 0000000000000000000000000000000000000000..92c7e1e01f671a6dee11a8d25a7294ed032d73dd
--- /dev/null
+++ b/MathToF/309.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "车轮的直径一定，车轮的转数和前进的距离成正比"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两种量成不成比例，成什么比例，就看这两种量是否是1相关联;2一种量变化，另一种量也随着变化，变化方向相同或相反;3对应的比值或乘积一定;如果这两种量相关联的量都是变量，且对应的比值一定，就成正比例;如果两种量相关联的量都是变量，且对应的乘积一定，就成反比例;如果是其它的量一定或乘积、比值不一定，就不成比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/31.json b/MathToF/31.json
new file mode 100644
index 0000000000000000000000000000000000000000..0130a2bf37a47fb33d39c663e21ba74e218366fd
--- /dev/null
+++ b/MathToF/31.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三个连续自然数的积一定是6的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "任取几组3个连续非零自然数，求出它们相乘的积，然后分析是答案中的哪个数即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/310.json b/MathToF/310.json
new file mode 100644
index 0000000000000000000000000000000000000000..8b88d56837e39281b9c538cafc76c1c663bca4be
--- /dev/null
+++ b/MathToF/310.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个同样大的小正方形拼成一个长方形.那么，这个长方形周长是一个小正方形周长的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用两个同样大小的正方形拼成一个长方形，拼成后长方形的长是原正方形边长的2倍，宽是原正方形的边长.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/311.json b/MathToF/311.json
new file mode 100644
index 0000000000000000000000000000000000000000..734fcd1f55561ebd531fd0f5e36f645591571280
--- /dev/null
+++ b/MathToF/311.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "π是一个无限不循环小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "无限不循环小数是指小数点后有无限个数位，但没有周期性的重复，圆周率π就是无限不循环小数，因为它的小数点后面没有出现循环的数字，并且它的数位是无限的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/312.json b/MathToF/312.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c5abb5c94360abd26330bff2fed78ab8220f229
--- /dev/null
+++ b/MathToF/312.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲仓库比乙仓库多储存粮食 \\frac{4}{5}吨，乙仓库比甲仓库少储存 \\frac{4}{5}吨"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "\\frac{4}{5}吨是一个具体的数量;甲乙两个仓库存粮的重量差是 \\frac{4}{5}吨;既表示甲仓库比乙仓库多存粮食 \\frac{4}{5}吨，也表示乙仓库比甲仓库少存粮食 \\frac{4}{5}吨."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/313.json b/MathToF/313.json
new file mode 100644
index 0000000000000000000000000000000000000000..058774da1762d6880fd08bfd0bdcafef98560217
--- /dev/null
+++ b/MathToF/313.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一棵小树在太阳的照射下会有影子，在中午，小树的影子最短"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "影子是物体遮住阳光形成的，中午，太阳直射，太阳在树的正上方，影子几乎是一个点;早上和下午，太阳斜射，在太阳下，树的影子是细长的，由此得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/314.json b/MathToF/314.json
new file mode 100644
index 0000000000000000000000000000000000000000..7c49716064f2ae571f811bb8655c2e4dbad76acd
--- /dev/null
+++ b/MathToF/314.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "7个13的和与13的7倍相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "7个13的和与13的7倍表示的意义相同，列式也相同;所以7个13的和与13的7倍的计算结果也相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/315.json b/MathToF/315.json
new file mode 100644
index 0000000000000000000000000000000000000000..3a792771a6828da44f5f604f5bf071f03316655b
--- /dev/null
+++ b/MathToF/315.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5个苹果，小明吃其中的1个，小明吃了这些苹果的 \\frac{1}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的意义解答，把5个苹果看作单位‘1‘，小明吃其中的1个就是吃了其中的一份，所以吃了这些苹果的 \\frac{1}{5}，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/316.json b/MathToF/316.json
new file mode 100644
index 0000000000000000000000000000000000000000..640e6edf45f3f7568fdd25d069ebfeb60e4f1c68
--- /dev/null
+++ b/MathToF/316.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "假分数都比真分数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "假分数就是分子大于或等于分母的分数，假分数大于等于1;真分数是分子小于分母的分数，真分数都小于1，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/317.json b/MathToF/317.json
new file mode 100644
index 0000000000000000000000000000000000000000..f063799152f0798dfd421267ee499f47408517c2
--- /dev/null
+++ b/MathToF/317.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "李师傅加工了一批零件，合格的有100件，不合格的有2件，合格率是98%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先用‘100+2‘求出产品总个数，进而根据公式:合格率= \\frac{合格的零件个数}{零件总个数}×100%，进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/318.json b/MathToF/318.json
new file mode 100644
index 0000000000000000000000000000000000000000..2ec3b91bb49d967fce876f4e15b9d9b7bdcd4f68
--- /dev/null
+++ b/MathToF/318.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小数每两个计数单位间的进率是10。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分析:十进制计数法:就是每相邻两个计数单位之间的进率都是10. 解答:每相邻两个计数单位之间的进率都是10，前提是:两个计数单位是相邻的. 故答案为:×. 点评:此题考查十进制计数法的特征:每相邻两个计数单位之间的进率都是10，注意关键词‘相邻‘."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/319.json b/MathToF/319.json
new file mode 100644
index 0000000000000000000000000000000000000000..a2f9a464b25adeac871b40f9a5f671d1f02f028a
--- /dev/null
+++ b/MathToF/319.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在计算4.6×19+5.4×19 = (4.6+5.4) ×19利用的是乘法分配律。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在计算4.6×19+5.4×19 = (4.6+5.4) ×19利用的是乘法分配律。此题考察乘法分配律和乘法结合律在小数乘法中的应用。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/32.json b/MathToF/32.json
new file mode 100644
index 0000000000000000000000000000000000000000..9799ceeed12929f691ab0967a7c8dea5643e74a9
--- /dev/null
+++ b/MathToF/32.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果甲数的 \\frac{2}{3}大于乙数的 \\frac{3}{4}(甲、乙≠0)，那么甲数小于乙数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先根据甲数的 \\frac{2}{3}大于乙数的 \\frac{3}{4}(甲、乙≠0)，可得甲数× \\frac{2}{3}>乙数× \\frac{3}{4}(甲、乙≠0)，然后根据分数大小比较的方法，判断出 \\frac{2}{3}、 \\frac{3}{4}的大小关系，即可判断出甲数、乙数的大小关系."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/320.json b/MathToF/320.json
new file mode 100644
index 0000000000000000000000000000000000000000..3ca89055605c05520ae50d2f6b79fe1404cd1904
--- /dev/null
+++ b/MathToF/320.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "100与72的差除以4是多少?列式是100-72÷4。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先算出100与72的差是多少，然后用所得的差除以4，列式为:(100-72)÷4，根据此本题错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/321.json b/MathToF/321.json
new file mode 100644
index 0000000000000000000000000000000000000000..c064c3cb13b1e09a970df426c1a28436518a9128
--- /dev/null
+++ b/MathToF/321.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个月里最多只有4个星期。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "每个星期有7天，一个月最多有31天。 31÷7=4(个)…3(天) 故一个月里最多只有4个星期。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/322.json b/MathToF/322.json
new file mode 100644
index 0000000000000000000000000000000000000000..ba1290c331b961461800bfd837d849c3ef144560
--- /dev/null
+++ b/MathToF/322.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "每套西服用布2.8米，30米布最多可以做11套这样的西服"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，知道每套西服用布2.8米，就是求30米里面有多少个2.8米，再根据实际情况进行取舍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/323.json b/MathToF/323.json
new file mode 100644
index 0000000000000000000000000000000000000000..d0554ca11af19b59cc05c6b22bd0c833f2498c23
--- /dev/null
+++ b/MathToF/323.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "妈妈今年40岁，是我的四倍，设我的年龄为 x ， 等量关系式为4=40 x"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "等量关系式两边等量，根据妈妈今年40岁，是我的四倍，可列出4 x=40通过等量关系的选择与对等可得出答案，本题考查的是等量关系与方程。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/324.json b/MathToF/324.json
new file mode 100644
index 0000000000000000000000000000000000000000..65c31a53daa68b9bf39a53dcac7d7414d17169af
--- /dev/null
+++ b/MathToF/324.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "位数多的自然数比位数少的自然数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整数大小的比较方法，位数不同，位数多的数就大;位数相同，左起第一位上的数大的那个数就大;如果左起第一位上的数相同，就比较左起第二位上的数，直到比较出大小为止.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/325.json b/MathToF/325.json
new file mode 100644
index 0000000000000000000000000000000000000000..0cf2e6b8dd6752ad3af68155deac08a2fd58585c
--- /dev/null
+++ b/MathToF/325.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形最多有2个锐角。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个三角形最多有3个锐角"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/326.json b/MathToF/326.json
new file mode 100644
index 0000000000000000000000000000000000000000..1ce8851b95ae2a56f303ce40084f6446949f7553
--- /dev/null
+++ b/MathToF/326.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "与999相邻的两个数是990和1000"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求一个数相邻的数，就是用这个数减去1，得出它前面的数，用这个数加上1，得到它后面的数，从而解决问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/327.json b/MathToF/327.json
new file mode 100644
index 0000000000000000000000000000000000000000..61188bf8208c8cef3d362fea164946b472d02495
--- /dev/null
+++ b/MathToF/327.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为20÷5=4，所以20是倍数，5是因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为20÷5=4，所以说4和5都是20的因数，20是4和5的倍数;不能说成4和5都是因数，20是倍数;约数和倍数是相互依存的，是两个数之间的关系."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/328.json b/MathToF/328.json
new file mode 100644
index 0000000000000000000000000000000000000000..24f6abd8affd4fd5562fec9eec41abba7d9e2c1c
--- /dev/null
+++ b/MathToF/328.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "钟面上分针从3走到11，经过的时间是8分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分针走1大格是5分，分针从钟面上的3走到11，走了8个大格，中间经过了多少分钟，用(11-3)×5=40分解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/329.json b/MathToF/329.json
new file mode 100644
index 0000000000000000000000000000000000000000..8a7a648ada719b4cced0ca3fc626a0da4166253c
--- /dev/null
+++ b/MathToF/329.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "125×32×25=125×8+25×4"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把32看作4×8，根据乘法交换律和结合律可得125×32×25=125×(4×8)×25=(125×8)×(25×4)，所以此题错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/33.json b/MathToF/33.json
new file mode 100644
index 0000000000000000000000000000000000000000..6fb20a202316f9104e7e77089b780486b4497723
--- /dev/null
+++ b/MathToF/33.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "二千六百零九万七千四百，用四舍五入精确到万位是2610"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先根据多位数的写法，写出这个数，省略四舍五入到万，根据千位上数字的大小确定用‘四舍‘法、还是用‘五入‘法.省略尾数后，同时在后面写上‘万‘字."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/330.json b/MathToF/330.json
new file mode 100644
index 0000000000000000000000000000000000000000..b69027b0c703150f197dee39b3afa0bda596692e
--- /dev/null
+++ b/MathToF/330.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "大小两个圆的周长之比是4:1，那么这两个圆的面积之比是4:1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "圆的周长=2πr，所以周长之比=半径之比，由此设两个圆的半径分别为4r，r，根据圆的面积公式s=π\\( r^{2} \\)即可推理解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/331.json b/MathToF/331.json
new file mode 100644
index 0000000000000000000000000000000000000000..878f7ba729a61577676fc4fec89d864b06d24a44
--- /dev/null
+++ b/MathToF/331.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{1}{4}= \\frac{2}{8}，所以 \\frac{1}{4}和 \\frac{2}{8}的分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的基本性质， \\frac{1}{4}的分子和分母同时扩大2倍，就变成 \\frac{2}{8}，所以 \\frac{1}{4}= \\frac{2}{8}，但是 \\frac{1}{4}的分数单位是 \\frac{1}{4}，而 \\frac{2}{8}的分数单位是 \\frac{1}{8}，它们的分数单位不同，由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/332.json b/MathToF/332.json
new file mode 100644
index 0000000000000000000000000000000000000000..6f9fdea1ea620ccf3cc3f2f75ab693ab737d05fc
--- /dev/null
+++ b/MathToF/332.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "为了解一年内月平均气温的变化情况，适合选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/333.json b/MathToF/333.json
new file mode 100644
index 0000000000000000000000000000000000000000..0d6fd71e3a90440d8c47c090c525ab9d66501dd0
--- /dev/null
+++ b/MathToF/333.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个长方形操场画在比例尺是1:400的图上，这个操场的图上面积是实际面积的 \\frac{1}{400}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "假设在图纸上操场的长为8厘米，宽为4厘米，再据‘实际距离=图上距离÷比例尺‘求得实际的长和宽，从而分别求得图上的面积和实际的面积，然后用图上面积除以实际面积，就是图上的面积是实际面积的几分之几."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/334.json b/MathToF/334.json
new file mode 100644
index 0000000000000000000000000000000000000000..710f4306d472f3773ddb1c0fc409d2a4dec582cb
--- /dev/null
+++ b/MathToF/334.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一百一百地数，八百前面第一个数是七百九十，后面第一个数是八百一十。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一百一百地数，八百前面第一个数是七百，后面第一个数是九百，所以题干说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/335.json b/MathToF/335.json
new file mode 100644
index 0000000000000000000000000000000000000000..fe474158f78071f03d678fd60ada43faf84f3b88
--- /dev/null
+++ b/MathToF/335.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "能够清楚地表示出数量增减变化情况的统计图是折线统计图."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据统计图的特点可知:能够清楚地表示出数量增减变化情况的统计图是折线统计图，所以本题说法正确; 正确.  条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/336.json b/MathToF/336.json
new file mode 100644
index 0000000000000000000000000000000000000000..e8008fedb52ae4c8302a2ba46bf04a682d896f21
--- /dev/null
+++ b/MathToF/336.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "五(1)班男生人数占全班人数的 \\frac{2}{5}，五(2)班男生人数也占全班人数的 \\frac{2}{5}，因此这个班的男生人数一样多."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "五(1)班男生人数占全班人数的 \\frac{2}{5}，则 \\frac{2}{5}的单位‘1‘是五(1)班总人数;五(2)班男生人数也占全班人数的 \\frac{2}{5}，则 \\frac{2}{5}的单位‘1‘是五(2)班总人数;两个 \\frac{2}{5}的单位‘1‘不同，所以无法比较这两个班的男生人数多少."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/337.json b/MathToF/337.json
new file mode 100644
index 0000000000000000000000000000000000000000..234dfc1541e41a2275daf28b83582d85fc7e4025
--- /dev/null
+++ b/MathToF/337.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "折线统计图和条形统计图都能清楚的看出数量增减变化的情况"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先要清楚每一种统计图的特点:条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/338.json b/MathToF/338.json
new file mode 100644
index 0000000000000000000000000000000000000000..63635521d8ad168060b3f2867507e6a42d3d78f6
--- /dev/null
+++ b/MathToF/338.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "假分数大于1，真分数小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据真假分数的概念，真分数:分子小于分母，值小于1;假分数:分子大于或等于分母，值大于或等于1;由此解决问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/339.json b/MathToF/339.json
new file mode 100644
index 0000000000000000000000000000000000000000..6f202fbd28a32cb6aef1111adaab5590adfc8789
--- /dev/null
+++ b/MathToF/339.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "所有的自然数都有倒数，并且这些数的倒数都小于1."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分析:直接运用倒数的意义解答.注意0没有倒数. 解答:根据倒数的定义可得:0和任何数相乘都得0，所以0没有倒数，与题意不符. 故答案是:×. 点评:根据题意，找到与题意不符的一个数即可判断正误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/34.json b/MathToF/34.json
new file mode 100644
index 0000000000000000000000000000000000000000..973bee16246a05d2e0f9cec011e1f154d16f2638
--- /dev/null
+++ b/MathToF/34.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "描述某地区一天的气温变化情况，选用条形统计图合适"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/340.json b/MathToF/340.json
new file mode 100644
index 0000000000000000000000000000000000000000..581fa7c2df4d00b526666ea9abf5d29e6846b9f9
--- /dev/null
+++ b/MathToF/340.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方形的一条长加上一条宽的长度，正好是这个长方形周长的一半。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "长方形的周长为为(长+宽)×2，则长加宽即为周长的一半。 故题干描述正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/341.json b/MathToF/341.json
new file mode 100644
index 0000000000000000000000000000000000000000..62a6e34f46ea643b52cbae7800f540eab4c27c3e
--- /dev/null
+++ b/MathToF/341.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相加的和一定小于这两个数相乘的积"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设这两个数分别是10和1;分别计算出这两个数的和与积，然后再进一步判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/342.json b/MathToF/342.json
new file mode 100644
index 0000000000000000000000000000000000000000..16b26d8a9c43865387811f53b67815a6be8066cd
--- /dev/null
+++ b/MathToF/342.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用0，1，2，3，4组成的最小的五位数是12034"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/343.json b/MathToF/343.json
new file mode 100644
index 0000000000000000000000000000000000000000..4ed03886b85595545e073583723ca4cbe5685223
--- /dev/null
+++ b/MathToF/343.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "指南针是我国的四大发明之一，它的指针总是一头指向北方，另一头指向南方"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据指南针的特性:一端指南，一端指北，由此进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/344.json b/MathToF/344.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c283b4bc1c9085adff1294b1f02ff3038ad572d
--- /dev/null
+++ b/MathToF/344.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "6.0和6.00大小相等，计数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数的性质，判断大小，根据一位小数的计数单位是0.1，两位小数的计数单位是0.01解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/345.json b/MathToF/345.json
new file mode 100644
index 0000000000000000000000000000000000000000..8deb9eb82b26ba6566aedc218502bda4006e8b5c
--- /dev/null
+++ b/MathToF/345.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最小的两位数和最大的两位数相差90。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最小的两位数是10，最大的两位数是99，它们的差用99-10即可解答。 99-10=89，所以最小的两位数和最大的两位数相差90的说法是错误的。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/346.json b/MathToF/346.json
new file mode 100644
index 0000000000000000000000000000000000000000..38375feadc3c792f9b3196b37bb92034c76ff6a2
--- /dev/null
+++ b/MathToF/346.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为1.2÷0.6=2，所以1.2是0.6倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义，因数和倍数是在非0自然数范围内进行研究，以此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/347.json b/MathToF/347.json
new file mode 100644
index 0000000000000000000000000000000000000000..1db08cf80e164867bd41f578bc73a5d9cf2ececa
--- /dev/null
+++ b/MathToF/347.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "妈妈买回来5个桃子，爸爸买回来6个桃子，他们一共买回来11个桃子。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "妈妈买回来5个桃子，爸爸买回来6个桃子，他们一共买回来11个桃子。原题说法正确。妈妈买回来的加上爸爸买回来的就是一共买回来的。5+6=11(个)即可解答。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/348.json b/MathToF/348.json
new file mode 100644
index 0000000000000000000000000000000000000000..bc38035730bbcc2ba0b2593327bacf183ce24097
--- /dev/null
+++ b/MathToF/348.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲仓库存粮比乙仓库多 \\frac{1}{5}，乙仓库存粮就比甲仓库少 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "甲比乙多 \\frac{1}{5}，是把乙仓库存粮看成单位‘1‘，甲就是(1+ \\frac{1}{5})，用两数的差除以甲，即可求出乙比甲少几分之几，再与 \\frac{1}{5}比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/349.json b/MathToF/349.json
new file mode 100644
index 0000000000000000000000000000000000000000..1abbf49418a604e9fde1b82f38eaf128846266db
--- /dev/null
+++ b/MathToF/349.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数的因数一定比它的倍数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据‘一个数最大的因数是它本身，最小的倍数是它本身‘进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/35.json b/MathToF/35.json
new file mode 100644
index 0000000000000000000000000000000000000000..a557b51eb5ccd90406def858cc8cd7c29dab1416
--- /dev/null
+++ b/MathToF/35.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根钢管锯成5段要用20分钟，锯成10段要40分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一根钢管锯成5段，锯了:5-1=4次，共用了20分钟，那么锯一次用:20÷4=5(分);锯成10段，锯了:10-1=9次，要用:5×9=45(分钟);据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/350.json b/MathToF/350.json
new file mode 100644
index 0000000000000000000000000000000000000000..730c4f72ad88c95bb6916ef4ea5488c4c16fbb31
--- /dev/null
+++ b/MathToF/350.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小强参加跳绳比赛，1小时跳了98下"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据生活经验、对时间单位和数据大小的认识，可知强参加跳绳比赛，1分钟跳了98下."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/351.json b/MathToF/351.json
new file mode 100644
index 0000000000000000000000000000000000000000..f32a826fb4a922d2e427a1be092d58e2e3aad759
--- /dev/null
+++ b/MathToF/351.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "书店有54本故事书，上午卖出17本，下午卖出16本，现在书店还剩11本故事书。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "原有故事书本数-上午卖出的本数-下午卖出的本数=剩下的本数，据此计算判断即可。 由此可得:54-17-16=21 (本)，所以现在还剩21本故事书。 故题目说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/352.json b/MathToF/352.json
new file mode 100644
index 0000000000000000000000000000000000000000..58eb93ed053bd35191f14c2bb45a64c7aea5e10e
--- /dev/null
+++ b/MathToF/352.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "被除数扩大到原来的5倍，要使商不变，除数必须扩大到原来的5倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，由商不变的性质进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/353.json b/MathToF/353.json
new file mode 100644
index 0000000000000000000000000000000000000000..a0a8bdb66ad5957dcf28bb3a9865dc1cad3d5b47
--- /dev/null
+++ b/MathToF/353.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小华在2014年2月29日的短跑比赛中获第一名"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先判断2014年是平年还是闰年，平年二月28天，而闰年二月有29天，由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/354.json b/MathToF/354.json
new file mode 100644
index 0000000000000000000000000000000000000000..0a700a18fe84ac3165b019c3ee6a6f480bae14c5
--- /dev/null
+++ b/MathToF/354.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分母是9的最简真分数只有6个"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "最简真分数的意义:分子和分母是互质数，并且分子小于分母的分数就是最简真分数，据此找出分母是9的最简真分数，然后数出进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/355.json b/MathToF/355.json
new file mode 100644
index 0000000000000000000000000000000000000000..e9e00d10c19c397434435fbac45d08fcf6f6aa7e
--- /dev/null
+++ b/MathToF/355.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆有无数条对称轴，半圆也有无数条对称轴。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个图形沿一条直线对折，直线两旁的部分能够完全重合，那么这个图形就是轴对称图形，这条直线就是这个图形的对称轴，由此即可解答问题。 根据轴对称图形的定义可知:圆有无数条对称轴，而半圆只有一条对称轴，所以原题说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/356.json b/MathToF/356.json
new file mode 100644
index 0000000000000000000000000000000000000000..779d9eb53c5555657abf0753b8f0696367bb2e3a
--- /dev/null
+++ b/MathToF/356.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求12的 \\frac{3}{4}是多少，列式是 \\frac{3}{4}×12"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数乘法的意义，求12的 \\frac{3}{4}是多少，列式是12× \\frac{3}{4}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/357.json b/MathToF/357.json
new file mode 100644
index 0000000000000000000000000000000000000000..65af6c1fe195f4176e2e90500eed1c233eae4bc0
--- /dev/null
+++ b/MathToF/357.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "上升一定用正数表示，下降一定用负数表示"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题主要用正负数来表示具有意义相反的两种量:如果上升记为负，则下降就记为正，直接得出结论即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/358.json b/MathToF/358.json
new file mode 100644
index 0000000000000000000000000000000000000000..6618293a4cd4d610b0457284e714b657e1dee1aa
--- /dev/null
+++ b/MathToF/358.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在小数的后面去掉一个0，这个数就缩小到原来的十分之一"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "小数的性质:小数的末尾添上‘0‘或去掉‘0‘小数的大小不变;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/359.json b/MathToF/359.json
new file mode 100644
index 0000000000000000000000000000000000000000..769aec275d02dad246249c4c5728eff4edcf0155
--- /dev/null
+++ b/MathToF/359.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母都乘以同一个自然数，分数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的基本性质:分数的分子和分母同时乘或除以一个不为0的数，分数的大小不变;根据分数的基本性质的内容直接进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/36.json b/MathToF/36.json
new file mode 100644
index 0000000000000000000000000000000000000000..a44b51de6033850423dea497f07983ef12fb475a
--- /dev/null
+++ b/MathToF/36.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数是12的倍数，则这个数一定是3和4的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据一个数是12的倍数，一定是4和3的公倍数，因为12是3和4的公倍数，所以一个数如果能被12整除，则这个数一定是4和3的倍数;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/360.json b/MathToF/360.json
new file mode 100644
index 0000000000000000000000000000000000000000..5609a850751bff4443f6cdae3aaa33cc271aa7a3
--- /dev/null
+++ b/MathToF/360.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方形和正方形都是由四条线段组成的"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "由四条线段依次首尾相接围成的封闭图形是四边形，长方形、正方形、平行四边形都是四边形，由此求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/361.json b/MathToF/361.json
new file mode 100644
index 0000000000000000000000000000000000000000..9fcd9893e831c3151e78298d12fd61c473bb85fc
--- /dev/null
+++ b/MathToF/361.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果一个锐角加上一个锐角，那么它们的和一定是一个钝角，如:50゜+60゜=110゜"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据锐角和钝角的定义及分类就可作出正确的判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/362.json b/MathToF/362.json
new file mode 100644
index 0000000000000000000000000000000000000000..db8cc75d5448b0fad2b71b0d79c8658477723629
--- /dev/null
+++ b/MathToF/362.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，其中一个乘数末尾有0，则积的末尾一定有0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设一个数是5或0.3，另一个数是10，求出它们的积，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/363.json b/MathToF/363.json
new file mode 100644
index 0000000000000000000000000000000000000000..41dd98836afd76b12f933dece138bfa7f1bfd5e0
--- /dev/null
+++ b/MathToF/363.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{3}{4}× \\frac{4}{3}=1，所以 \\frac{3}{4}是倒数， \\frac{4}{3}也是倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，由倒数的知识:倒数是相互依存的进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/364.json b/MathToF/364.json
new file mode 100644
index 0000000000000000000000000000000000000000..8e5c482f75f7fa9a02dba7a821309071bf870cb7
--- /dev/null
+++ b/MathToF/364.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果2a=3b(a、b均不为0)，那么a:b=2:3"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比例的基本性质‘两个外项的积等于两个内项的积‘，可把等式为5a=6b，运用比例性质的逆运用，即可得出答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/365.json b/MathToF/365.json
new file mode 100644
index 0000000000000000000000000000000000000000..e16d58d75083fff55d07bd88feecea52a0dc7210
--- /dev/null
+++ b/MathToF/365.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆柱和圆锥的底面积和体积都相等，圆柱的高与圆锥的高的比是3:1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据圆柱的体积=底面积×高，圆锥的体积=底面积×高÷3，所以设圆柱与圆锥的底面积都是S，体积都是V，求出圆柱、圆锥的高，进而求出它们的比值即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/366.json b/MathToF/366.json
new file mode 100644
index 0000000000000000000000000000000000000000..bce997aea665d7c2281255657708926f8f2f3814
--- /dev/null
+++ b/MathToF/366.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数的和不一定是偶数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据奇数、偶数的性质:奇数+奇数=偶数，偶数+偶数=偶数，奇数+偶数=奇数.据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/367.json b/MathToF/367.json
new file mode 100644
index 0000000000000000000000000000000000000000..98c44db85bb1405527e3f866b34630872cc088c6
--- /dev/null
+++ b/MathToF/367.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三位数减三位数差一定是两位数或一位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "举出反例即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/368.json b/MathToF/368.json
new file mode 100644
index 0000000000000000000000000000000000000000..59e0c564ac78dbb469d12edc5cce6c61bd445d97
--- /dev/null
+++ b/MathToF/368.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "成为互质数的两个数不一定是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "公约数只有1的两个数叫做互质数，这两个数可能都是质数，也可能都是合数，也可能是一个质数、一个合数，由此即可得出答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/369.json b/MathToF/369.json
new file mode 100644
index 0000000000000000000000000000000000000000..e27f3da284ebd13728c54461bb339253b7f6416c
--- /dev/null
+++ b/MathToF/369.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个钝角只能分成一个直角和一个锐角"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据锐角、钝角和直角的定义:大于0度小于90度的角叫做锐角;等于90度的角叫做直角;大于90度小于180度的角叫做钝角;由此可知:一个钝角可以分成一个直角和一个锐角，也可以分成两个锐角;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/37.json b/MathToF/37.json
new file mode 100644
index 0000000000000000000000000000000000000000..e7cab5fb2548ecff8099cdc8a81eb622160011c2
--- /dev/null
+++ b/MathToF/37.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个西瓜，小明吃了 \\frac{1}{4}小红吃了剩下的 \\frac{1}{3}，两人吃的西瓜一样多"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把这个西瓜看做单位‘1‘，小明吃了 \\frac{1}{4}，还剩1- \\frac{1}{4}= \\frac{3}{4};小红吃了剩下的 \\frac{1}{3}，即小红吃了整个西瓜的: \\frac{1}{3}× \\frac{3}{4}= \\frac{1}{4}，故两人吃的一样多."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/370.json b/MathToF/370.json
new file mode 100644
index 0000000000000000000000000000000000000000..0e9149026f2bace173af47ccafd74f99b5ddaeca
--- /dev/null
+++ b/MathToF/370.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根木头，要把它平均分成6段，每锯一次要5分钟，锯完一共要花30分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一根木头平均分成6段，共锯了6-1=5次，每锯下一段需要5分钟，锯完一共要花5×5=25(分钟)."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/371.json b/MathToF/371.json
new file mode 100644
index 0000000000000000000000000000000000000000..ba675c6b8dede574182401c7046f89ec49be9716
--- /dev/null
+++ b/MathToF/371.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果x=8y，那么x与y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/372.json b/MathToF/372.json
new file mode 100644
index 0000000000000000000000000000000000000000..4eb6d3ae938a24995388b4b200f2d9fbd671e4c7
--- /dev/null
+++ b/MathToF/372.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.06和0.0600大小相等，计数单位也一样"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "小数是十进制分数的一种特殊表现形式.分母是10、100、1000…的分数可以用小数表示.小数的性质:小数的末尾添上‘0‘或去掉‘0‘小数的大小不变;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/373.json b/MathToF/373.json
new file mode 100644
index 0000000000000000000000000000000000000000..906c9c0cc8e305785d3c248bb029c21bb9b81b8c
--- /dev/null
+++ b/MathToF/373.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "面积相等的两个圆，周长也相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆的面积公式知，两个圆的面积相等，它们的半径就相等，半径相等的圆的周长也相等.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/374.json b/MathToF/374.json
new file mode 100644
index 0000000000000000000000000000000000000000..3285da7a71d7442e4a9a09feac642050f86cce7f
--- /dev/null
+++ b/MathToF/374.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "703×6的积中间有一个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据整数乘法计算方法，求出703×6积即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/375.json b/MathToF/375.json
new file mode 100644
index 0000000000000000000000000000000000000000..5e17b324ea78aa7add7a4eb582faf385e97d88da
--- /dev/null
+++ b/MathToF/375.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用两个完全一样的正方形拼成一个长方形，长方形的面积是正方形面积的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个图形的面积是它所占平面的大小.既然长方形是两个正方形拼成的，所以长方形所占平面的大小，和两个正方形所占平面的大小相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/376.json b/MathToF/376.json
new file mode 100644
index 0000000000000000000000000000000000000000..24ec002cbdfcc02c742c49fe90476ba6b42cd142
--- /dev/null
+++ b/MathToF/376.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3除以0.3的商是3，余数是1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，余数总比除数小，直接判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/377.json b/MathToF/377.json
new file mode 100644
index 0000000000000000000000000000000000000000..de586725174fdd501bea1d6d0d67ba1011d2ed63
--- /dev/null
+++ b/MathToF/377.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个分数相除，商一定比被除数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在分数除法中，当除数小于1时，商大于被除数;当除数等于1时，商等于被除数;当除数大于1时，商小于被除数，(被除数零除外). 所以两个分数相除，只有除数是真分数的时候，商一定大于被除数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/378.json b/MathToF/378.json
new file mode 100644
index 0000000000000000000000000000000000000000..fc66a702cc361d2b3853969d764535164dca69fb
--- /dev/null
+++ b/MathToF/378.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根绳子对折一次，再对折一次，每一段是这绳子的 \\frac{1}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把这根据绳子的长度看作单位‘1‘，把它对折一次，平均分成2段，每段是这根绳子的 \\frac{1}{2};再对折一次，平移分成4段，每段是这根绳子的 \\frac{1}{4}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/379.json b/MathToF/379.json
new file mode 100644
index 0000000000000000000000000000000000000000..b58600d3ec38f08045d55e23d8dbb4a88e6bbb6c
--- /dev/null
+++ b/MathToF/379.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "除以一个不等于0的数，就等于除以这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数除法的计算法则解答即可:除以一个不等于0的数，就等于乘这个数的倒数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/38.json b/MathToF/38.json
new file mode 100644
index 0000000000000000000000000000000000000000..6390333973a7e652e81f71c79775eee5a97b3c7c
--- /dev/null
+++ b/MathToF/38.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "拧开水龙头是平移现象。s"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "拧开水龙头是平移现象。这句话错误。拧开水龙头是旋转现象。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/380.json b/MathToF/380.json
new file mode 100644
index 0000000000000000000000000000000000000000..e603534c6f155c80dfcda246e040a262c46ec0ee
--- /dev/null
+++ b/MathToF/380.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把36分解质因数是:36=2×2×3×3"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分解质因数就是把一个合数写成几个质数相乘的形式，一般先从较小的质数试着分解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/381.json b/MathToF/381.json
new file mode 100644
index 0000000000000000000000000000000000000000..59958dab6fda00765609bbee32c9ddba982772cc
--- /dev/null
+++ b/MathToF/381.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "4.7除以0.6，商是7，余数是5"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，可利用有余数的除法算式 被除数=商×除数+余数进行计算，看结果是否等于4.7，然后再进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/382.json b/MathToF/382.json
new file mode 100644
index 0000000000000000000000000000000000000000..035311843fa674c61e1672818956ba66cdda23c1
--- /dev/null
+++ b/MathToF/382.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "208×72的积比14000大，比16000小"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把算式208×7的积求出来，再进行比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/383.json b/MathToF/383.json
new file mode 100644
index 0000000000000000000000000000000000000000..b1f0b1d3f11e36b5aa2268716e40f6bb764ae403
--- /dev/null
+++ b/MathToF/383.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个圆柱削成最大的圆锥，已知削去体积是2.6立方厘米，那么圆锥体积是1.3立方厘米_"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆锥体的体积是与它等底等高的圆柱体体积的 \\frac{1}{3}，即削去体积占圆柱体体积的 \\frac{2}{3}，可用2.6立方厘米除以 \\frac{2}{3}即可得到圆柱的体积，然后再用圆柱的体积乘 \\frac{1}{3}即可得到最大圆锥的体积，据此解答即可得到答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/384.json b/MathToF/384.json
new file mode 100644
index 0000000000000000000000000000000000000000..46d89bde594a81e2b35c5903168f17c9f30088c9
--- /dev/null
+++ b/MathToF/384.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "六年级1班的男生人数比女生人数多 \\frac{1}{5}，则女生人数比男生人数少 \\frac{1}{6}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "先把女生的人数看成单位‘1‘，那么男生的人数就是1+ \\frac{1}{5}，然后用 \\frac{1}{5}除以男生的人数，就是女生比男生少几分之几."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/385.json b/MathToF/385.json
new file mode 100644
index 0000000000000000000000000000000000000000..e91937bdcb02e8a169968d5ed6471ca6ab2d1321
--- /dev/null
+++ b/MathToF/385.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用两个棱长1厘米的正方体粘合成一个长方体，这个长方体的表面积是12 平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个棱长1厘米的正方体拼组成一个长方体后，表面积比原来两个正方体的表面积之和减少了2个拼接面的面积，据此利用正方体的表面积公式计算即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/386.json b/MathToF/386.json
new file mode 100644
index 0000000000000000000000000000000000000000..756a1ff3370b2dd01958805e2143150fb07795ab
--- /dev/null
+++ b/MathToF/386.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "判断对错  9.6-9.6×0.1 =0×0.1 =0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "[解答]解:9.6-9.6×0.1  =9.6-0.96 =8.64"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/387.json b/MathToF/387.json
new file mode 100644
index 0000000000000000000000000000000000000000..84e36f980461872fad47fc82fde948c73946e85a
--- /dev/null
+++ b/MathToF/387.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一根3米长的铁丝平均分成5段，每段长 \\frac{1}{5}米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用绳子的全长除以平均分的段数，即可求出每段的长度，再与 \\frac{1}{5}米."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/388.json b/MathToF/388.json
new file mode 100644
index 0000000000000000000000000000000000000000..b2884798655b4db15d0619491aec33c1a5878cf8
--- /dev/null
+++ b/MathToF/388.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把单位‘1‘分成8份，表示其中的5份是 \\frac{5}{8}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的意义:把单位‘1‘平均分成若干份，表示其中一份或几份的数;因为题中没有说明‘平均分‘，所以每一份就不一定为 \\frac{1}{8}，那么其中的5份也就不一定是 \\frac{5}{8}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/389.json b/MathToF/389.json
new file mode 100644
index 0000000000000000000000000000000000000000..b54a0dad8d5caa9f285d778337226bde41b5f947
--- /dev/null
+++ b/MathToF/389.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形三个内角的度数比是1:3:6，这个三角形一定是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "三角形的内角度数和为180°，通过三个角的比可求出最大角占内角度数和的几分之几，由此就能求出占比例最大那个角的度数是多少，从而确定它是什么三角形."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/39.json b/MathToF/39.json
new file mode 100644
index 0000000000000000000000000000000000000000..22d1691740ca1a24e7dad1219212fd271e286dc4
--- /dev/null
+++ b/MathToF/39.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算分数除法时，除以一个整数等于乘这个整数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数除法的计算法则进行判断，注意除数不能为0这一条件."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/390.json b/MathToF/390.json
new file mode 100644
index 0000000000000000000000000000000000000000..2149245f560008f1d09ff70bc2c8275f489f6f3a
--- /dev/null
+++ b/MathToF/390.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小女孩看到的茶壶的形状是一样的。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个小女孩在茶壶的两侧，因此她们看到的茶壶的样子是相反，所以本题错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/391.json b/MathToF/391.json
new file mode 100644
index 0000000000000000000000000000000000000000..2d28c141be2d1731c3162f8147155f8334a9a4a3
--- /dev/null
+++ b/MathToF/391.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算904÷34时，把34看做40来试商比较简便"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在计算时，如果把34看作30试商，初商太大;如果把34看作40试商，初商太小;而把34看作35试商，初商正好合适;所以计算904÷34时，把34看作35试商比较简便."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/392.json b/MathToF/392.json
new file mode 100644
index 0000000000000000000000000000000000000000..7eb2f6ab88eff60bf9ce8a4d0ec0c60486f81431
--- /dev/null
+++ b/MathToF/392.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最简分数的分子和分母必须都是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最简分数就是指分子和分母为互质数的分数，也就是分子和分母只有公约数1."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/393.json b/MathToF/393.json
new file mode 100644
index 0000000000000000000000000000000000000000..1ef1fbf4372f1075c146d276587af486add0ca6b
--- /dev/null
+++ b/MathToF/393.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数的和一定大于这两个数的差。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:[错因]:1其中一个加数为0时忽略了 [正确答案]:也有等于的可能，两个数的和大于或等于两个数的差。 "
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/394.json b/MathToF/394.json
new file mode 100644
index 0000000000000000000000000000000000000000..27481fe9bc8884d2d5b6a9e813460e832ec4f0b3
--- /dev/null
+++ b/MathToF/394.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三个连续自然数的和一定是3的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "设三个连续自然数中的第一个为a，由这三个连续的自然数可表示为a、a+1，a+2.其和为:a+(a+1)+(a+2)=3×(a+1)，所以三个连续自然数的和一定是3的倍数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/395.json b/MathToF/395.json
new file mode 100644
index 0000000000000000000000000000000000000000..6e113211cce461ba2743944278de83b8a3655fce
--- /dev/null
+++ b/MathToF/395.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个正方体切成两个相同的长方体后，体积不变，表面积也不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个正方体切成两个大小相等的长方体后，增加了两个面，所以表面积就增加了;而分成的两个长方体所占据空间的大小和就等于原来正方体的体积，所以体积不变，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/396.json b/MathToF/396.json
new file mode 100644
index 0000000000000000000000000000000000000000..ca97d45c7c78fe9d4f678d1b39bbce1f93e5e40c
--- /dev/null
+++ b/MathToF/396.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "309÷3的商是13."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "309÷3的商是103，原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/397.json b/MathToF/397.json
new file mode 100644
index 0000000000000000000000000000000000000000..3ae365d8215b5a503d634e737b7b70748960460d
--- /dev/null
+++ b/MathToF/397.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1除以任何一个不为零的数，就等于这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为一个数与它的倒数的乘积是1，那么1除以这个数就会得到它的倒数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/398.json b/MathToF/398.json
new file mode 100644
index 0000000000000000000000000000000000000000..eb389f4666e201a913daaeb1e95ba54edc1530a6
--- /dev/null
+++ b/MathToF/398.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任意三个连续非0自然数的积一定都是6的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为连续3个自然数中，一定有一个数被3整除，所以一定有因数3;连续3个自然数中至少有1个偶数，所以一定有因数2，相乘起来，就一定被6整除，即是6的倍数;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/399.json b/MathToF/399.json
new file mode 100644
index 0000000000000000000000000000000000000000..4d5f9efc47477f69fe9b77da82fab7c88c5ba0d4
--- /dev/null
+++ b/MathToF/399.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个长方体橡皮泥捏成正方体后，橡皮泥的形状变了，但它所占的空间的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据体积的意义，物体所占空间的大小叫做物体的体积，把长方体形状的橡皮泥无论捏成什么形状，它的体积大小不变.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/4.json b/MathToF/4.json
new file mode 100644
index 0000000000000000000000000000000000000000..839d27f8a4a48fc29601d45040391052a1d7e22c
--- /dev/null
+++ b/MathToF/4.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在2和3之间有9个小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在2和3之间的小数有一位小数、两位小数、三位小数，…，所以应该有无数个小数，由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/40.json b/MathToF/40.json
new file mode 100644
index 0000000000000000000000000000000000000000..e519bc96da19e8727f95f94ac7e494bcef9d2187
--- /dev/null
+++ b/MathToF/40.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "500÷4的商的末尾有两个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "500÷4的商的末尾有没有0，要通过计算最后再确定商的末尾0的个数.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/400.json b/MathToF/400.json
new file mode 100644
index 0000000000000000000000000000000000000000..8c7ee4d9c7a027fd8804177fc8fc659e91e28da3
--- /dev/null
+++ b/MathToF/400.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个小正方体木块，放在桌子上有4个面露在外面"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个小正方体木块，放在桌子上有5个面露在外面，进而进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/401.json b/MathToF/401.json
new file mode 100644
index 0000000000000000000000000000000000000000..1e87948839cb921b60db6a9fc3c14760b7afd004
--- /dev/null
+++ b/MathToF/401.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一辆汽车前5小时行了300千米，后3小时行了180千米，这辆汽车的平均速度是60千米/小时"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一辆汽车前5小时行了300千米，后3小时行了180千米，则5+3小时共行了300+180千米，根据除法的意义，这辆汽车的平均速度是每小时:(300+180)÷(5+3)千米."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/402.json b/MathToF/402.json
new file mode 100644
index 0000000000000000000000000000000000000000..de4cf43980ff6b260c4a38b6066fc7ba181253a7
--- /dev/null
+++ b/MathToF/402.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "每套西服用布2.8米，30米布可以做11套这样的衣服."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先根据需要布的长度=每套需要长度×套数，求出11套衣服，需要布的长度，再与30米比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/403.json b/MathToF/403.json
new file mode 100644
index 0000000000000000000000000000000000000000..92270d7084ae7abda4890f8c8960abbb75861b1e
--- /dev/null
+++ b/MathToF/403.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "锐角小于90度，直角等于90度，钝角大于90度"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "钝角是大于90°且小于180°的角，锐角是大于0°小于90°的角，直角是等于90°的角;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/404.json b/MathToF/404.json
new file mode 100644
index 0000000000000000000000000000000000000000..4bfa30c48871f87f7612dd40da0748eb3c3b62a1
--- /dev/null
+++ b/MathToF/404.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "若a的 \\frac{2}{3}等于b，那么b÷ \\frac{2}{3}=a"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为若a的 \\frac{2}{3}等于b，所以a× \\frac{2}{3}=b，然后根据乘法各部分之间的关系解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/405.json b/MathToF/405.json
new file mode 100644
index 0000000000000000000000000000000000000000..153d3f0223b39be1fc16adbb2eb2f25b377f3d30
--- /dev/null
+++ b/MathToF/405.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为0×13=0，所以13÷0=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0不能做除数，0做除数无意义.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/406.json b/MathToF/406.json
new file mode 100644
index 0000000000000000000000000000000000000000..1da15df75eae594031322f52eb4e6246e9d4ce2e
--- /dev/null
+++ b/MathToF/406.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{4}×4÷ \\frac{3}{4}×4=3÷3=1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "计算 \\frac{3}{4}×4÷ \\frac{3}{4}×4时，根据乘法交换律和结合律计算即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/407.json b/MathToF/407.json
new file mode 100644
index 0000000000000000000000000000000000000000..06ee2047b9affa4a971d9c80e06267eeba463147
--- /dev/null
+++ b/MathToF/407.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果甲数的 \\frac{2}{5}等于乙数的 \\frac{3}{4}(甲数、乙数都大于0)，那么甲数小于乙数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要判断甲、乙两数的大小，根据已知条件甲数的 \\frac{2}{5}等于乙数的 \\frac{3}{4}(甲数、乙数都大于0)，即甲数× \\frac{2}{5}=乙数× \\frac{3}{4}，即甲数=乙数× \\frac{3}{4}× \\frac{5}{2}=乙数× \\frac{15}{8}，由此可以判断甲数>乙数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/408.json b/MathToF/408.json
new file mode 100644
index 0000000000000000000000000000000000000000..e7987c8d642cb505570de29f0f016a071a6e4e2c
--- /dev/null
+++ b/MathToF/408.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "假分数都大于1，真分数都小于1，所以假分数都比真分数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分子大于或等于分母的分数是假分数，分子小于分母的分数是真分数，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/409.json b/MathToF/409.json
new file mode 100644
index 0000000000000000000000000000000000000000..05ffff6bbbb5d2914f0d9d83072353c561bba464
--- /dev/null
+++ b/MathToF/409.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "所有自然数的真分数都小于1，假分数都大于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分子小于分母的分数叫真分数，真分数小于1;分子大于或等于分母的分数为假分数，假分数大于或等于1."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/41.json b/MathToF/41.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c14bf0d6580f805870a59bdcb89f2ddc3d703c8
--- /dev/null
+++ b/MathToF/41.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在0.2的后面添上‘%‘，它就缩小100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在0.2的后面添上‘%‘，这个数就变成0.2%，即0.002，相当于把这个数的小数点向左移动两位，也就是缩小了100倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/410.json b/MathToF/410.json
new file mode 100644
index 0000000000000000000000000000000000000000..4e4b7bc8c301bfd421e9dd18f7c15bacb640b6ed
--- /dev/null
+++ b/MathToF/410.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把6□8估成700，□里填的一般是大于5的数。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "□里也可以填的等于5的数，根据十位上数字的大小来确定是用‘四舍‘、还是用‘五入‘来取近似数"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/411.json b/MathToF/411.json
new file mode 100644
index 0000000000000000000000000000000000000000..5f0b89fa9b75ebdbe0fed3da7ee621dda81cb9fa
--- /dev/null
+++ b/MathToF/411.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果5a=4b，(a、b都不为0)，那么a:b=5:4"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比例的性质，把所给的等式5a=4b，改写成一个外项是a，一个内项是b的比例，则和a相乘的数5就作为比例的另一个外项，和b相乘的数4就作为比例的另一个内项，据此写出比例;再进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/412.json b/MathToF/412.json
new file mode 100644
index 0000000000000000000000000000000000000000..a38dae0c224645f20aaf22ce9a510b380a89fa48
--- /dev/null
+++ b/MathToF/412.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个九位数，它的最高位上是4，最低位上是7，千位上是1，其余各个数位上的数字都是0，这个数是410000007."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分析:根据整数的写法，从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0，写出此数再作判断. 解答:这个数写作:400001007. 故答案为:×. 点评:本题是考查整数的写法，关键是弄清位数及每位上的数字."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/413.json b/MathToF/413.json
new file mode 100644
index 0000000000000000000000000000000000000000..0ae97f2ba949c9b5a4b4dc88b9aa9e1f5f7da562
--- /dev/null
+++ b/MathToF/413.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个三位数的差还是三位数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题考查三位数的计算问题。两个三位数的差不一定是三位数，还有可能是两位数或者一位数甚至0。分别以下列三位数的计算为例，999-100=899，200-189=11，200-198=2，399-399=0。即两个两位数的和在0到899的范围之间，所以两个两位数的和既可能是一位数或者两位数，也可能是三位数，甚至是0。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/414.json b/MathToF/414.json
new file mode 100644
index 0000000000000000000000000000000000000000..29ff3a0be19648779fd4f8daa53a1313bbf3fb12
--- /dev/null
+++ b/MathToF/414.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为3 ÷8= \\frac{3}{8}=3:8，所以除法、分数、比的意义相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "虽然比与分数、除法之间有相等关系，但是它们的意义却不相同."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/415.json b/MathToF/415.json
new file mode 100644
index 0000000000000000000000000000000000000000..ba865bf72f35f4280029f9b7fd8a8a66012df3de
--- /dev/null
+++ b/MathToF/415.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为460÷23=20，560÷28=20，所以说，被除数的末尾有0，商的末尾也一定有0。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "被除数的末尾有0，商的末尾不一定有0。 例:130÷2=65 故题目中说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/416.json b/MathToF/416.json
new file mode 100644
index 0000000000000000000000000000000000000000..9911907b9e67f7d46ae78986c78240c2b941a10f
--- /dev/null
+++ b/MathToF/416.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "十位上是4的两位数一定比十位上是5的两位数大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题考查两个两位数比较大小时先比较十位上的数的大小，十位上的数是4的肯定比十位上是5的数小。故本题不对。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/417.json b/MathToF/417.json
new file mode 100644
index 0000000000000000000000000000000000000000..29be626aeeda372e4622d6ea5046795a6e87a23d
--- /dev/null
+++ b/MathToF/417.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为0乘任何数都得0，所以0除以任何数也都得0。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为0乘以任何数都得0，但0做除数无意义，0不能做除数， 故0乘以任何数都等于0，0除以任何数也等于0的说法是错误的。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/418.json b/MathToF/418.json
new file mode 100644
index 0000000000000000000000000000000000000000..beef699e46129009ca408ca831b25b76152b6f33
--- /dev/null
+++ b/MathToF/418.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求4个5相加的和是多少，列式为5+4=9。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求4个5相加的和是多少，可以列式为:4×5=20或5×4=20。故原题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/419.json b/MathToF/419.json
new file mode 100644
index 0000000000000000000000000000000000000000..d4a68135ee842cc080e56e22b811987b9d0d5586
--- /dev/null
+++ b/MathToF/419.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "反应病人的体温变化情况选用条形统计图比较合适"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/42.json b/MathToF/42.json
new file mode 100644
index 0000000000000000000000000000000000000000..3df0d78199aa85bea96263fccc41e37e172f8daa
--- /dev/null
+++ b/MathToF/42.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个苹果分成三块，笑笑吃了两块，一定吃了这个苹果的三分之二"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的意义:将单位‘1‘平均分成若干份，表示这样一份或几份的数为分数.由于把一个苹果分成3份，没有说明是平均分，所以2份就是这个苹果的三分之二的说法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/420.json b/MathToF/420.json
new file mode 100644
index 0000000000000000000000000000000000000000..8c9db840b5693e7d39fde106c490dd81cb5a3a68
--- /dev/null
+++ b/MathToF/420.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数的公因数的个数是有限的，公倍数的个数是无限的。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "两个数的公因数的个数是有限的，公倍数的个数是无限的。故题干说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/421.json b/MathToF/421.json
new file mode 100644
index 0000000000000000000000000000000000000000..b513f43ab4917339596cf38a1b138bdf4d2cb1c0
--- /dev/null
+++ b/MathToF/421.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一种商品打八折，就是比原价降低80%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "八折是指现价是80%，把原价看成单位‘1‘，现价比原价降低了1-80%=20%，由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/422.json b/MathToF/422.json
new file mode 100644
index 0000000000000000000000000000000000000000..32974d430d365539e93ec4ba32a5f06768b39b79
--- /dev/null
+++ b/MathToF/422.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{4}{5}×20可以表示20个 \\frac{4}{5}是多少，也可以表示求20的 \\frac{4}{5}是多少"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数乘以整数的意义， \\frac{4}{5}×20可以表示20个 \\frac{4}{5}是多少是正确的，但不可以表示20的 \\frac{4}{5}是多少，20的 \\frac{4}{5}是多少，列式为20× \\frac{4}{5}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/423.json b/MathToF/423.json
new file mode 100644
index 0000000000000000000000000000000000000000..eb66e07d1104c45a0f57169b917da89e7fb2c21b
--- /dev/null
+++ b/MathToF/423.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一杯糖水，含糖率为15%，糖占水的 \\frac{3}{17}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "含糖率为15%，即糖水中糖占15%，则水占(1-15%)，进而根据求一个数是另一个数的几分之几，用除法解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/424.json b/MathToF/424.json
new file mode 100644
index 0000000000000000000000000000000000000000..2b585561c8ac149b14de477453ae3edcc44a4c63
--- /dev/null
+++ b/MathToF/424.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任意一个假分数比任意一个真分数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分子小于分母的分数为真分数，真分数<1;分子大于或等于分母的分数为假分数，假分数≥1.所以真分数<假分数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/425.json b/MathToF/425.json
new file mode 100644
index 0000000000000000000000000000000000000000..fead50adad75b6d85cc2adebaea6cf3128b718fd
--- /dev/null
+++ b/MathToF/425.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{2}{5}×9+ \\frac{2}{5}可以运用乘法分配律进行简便计算"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "\\frac{2}{5}×9+ \\frac{2}{5}可以化成 \\frac{2}{5}×9+ \\frac{2}{5}×1，再运用乘法分配律进行简便计算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/426.json b/MathToF/426.json
new file mode 100644
index 0000000000000000000000000000000000000000..5eef19e6d839382c00938cbb0a131eab18db718f
--- /dev/null
+++ b/MathToF/426.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个人上山每小时行3千米，下山每小时行5千米，他的平均速度是每小时行4千米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，把山下到山上的距离看作单位‘1‘，分别求出上山用的时间和下山用的时间，进而根据‘往返总路程÷往返总时间=往返速度‘进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/427.json b/MathToF/427.json
new file mode 100644
index 0000000000000000000000000000000000000000..00f45a629f3a79be5f30a79188b09c169e125c54
--- /dev/null
+++ b/MathToF/427.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "当你看《中国地图》时，你的左边就是地图的西方"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据地图上的方向辨别方法，即‘上北下南，左西右东‘即可进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/428.json b/MathToF/428.json
new file mode 100644
index 0000000000000000000000000000000000000000..08ebff313a00e2d58a65930bbb30d6f79d03cb28
--- /dev/null
+++ b/MathToF/428.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数的和是偶数，两个奇数的积是奇数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据奇数、偶数的性质:奇数+奇数=偶数，奇数×奇数=奇数.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/429.json b/MathToF/429.json
new file mode 100644
index 0000000000000000000000000000000000000000..d58d3f5a52e1e15658ccc8257e857e29a583da22
--- /dev/null
+++ b/MathToF/429.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数的和是320，如果一个加数增加30，另一个加数减少20，那么和是370"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，一个加数增加30，另一个加数减少20，可知增加的比减少的多，多30-20=10，也就是原来的和320加上10即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/43.json b/MathToF/43.json
new file mode 100644
index 0000000000000000000000000000000000000000..8947456142d1afeb9e2236fc058d0c8247b41edd
--- /dev/null
+++ b/MathToF/43.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8只鸽子飞进3个鸽笼，总有一个鸽笼里至少有4只鸽子"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把3个鸽笼看作3个抽屉，把8只鸽子看作8个元素，那么每个抽屉需要放8÷3=2(个)…2(个)，所以每个抽屉需要放2个，剩下的2个不论怎么放，总有一个抽屉里至少有:2+1=3(个)，所以，至少有一个鸽笼要飞进3只鸽子，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/430.json b/MathToF/430.json
new file mode 100644
index 0000000000000000000000000000000000000000..b0adf8bf60e76a462c35e9efd937c81267333868
--- /dev/null
+++ b/MathToF/430.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三位小数比两位小数大。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "三位小数不一定比两位小数大，比如0.70大于0.651。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/431.json b/MathToF/431.json
new file mode 100644
index 0000000000000000000000000000000000000000..24b1693a77385c89541ef70cfe35b8a8c8c10e32
--- /dev/null
+++ b/MathToF/431.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果15a=b(a和b均不为0)，那么a和b成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/432.json b/MathToF/432.json
new file mode 100644
index 0000000000000000000000000000000000000000..b8fa7a642db1c41da5990fc21e393a7ef64a5adb
--- /dev/null
+++ b/MathToF/432.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "由两个三角形拼成的一个大三角形的内角和是360°。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            ""
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/433.json b/MathToF/433.json
new file mode 100644
index 0000000000000000000000000000000000000000..2d034bd09afd81397f700dafd278d924b588ce88
--- /dev/null
+++ b/MathToF/433.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用3、6、0、5组成最大的四位数是6530。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "用3、6、0、5，组成最大的四位数， 故千位应该是四个数中的最大数，百位就是第二大， 依次类推可得，最大的四位数为6530， 故答案为:正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/434.json b/MathToF/434.json
new file mode 100644
index 0000000000000000000000000000000000000000..9181afae63ac685b7641575fb5e5d35f66529958
--- /dev/null
+++ b/MathToF/434.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8个13和13的8倍得数相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据整数乘法的意义，8个13是13×8，13的8倍是13×8，分别求出它们的结果，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/435.json b/MathToF/435.json
new file mode 100644
index 0000000000000000000000000000000000000000..1cd7661aaf6647607a89476c791b51c12697748c
--- /dev/null
+++ b/MathToF/435.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "体积单位比面积单位大，面积单位比长度单位大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "体积单位、面积单位、长度不是同一类单位，不能比较大小， 所以体积单位比面积单位大，面积单位比长度单位大的说法是错误的;"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/436.json b/MathToF/436.json
new file mode 100644
index 0000000000000000000000000000000000000000..4fa7730f3363b2ab29e0964ce863d7249eda7808
--- /dev/null
+++ b/MathToF/436.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把单位‘1‘分成8份，1份占 \\frac{1}{8}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的意义是把单位‘1‘平均分成若干份，表示其中一份或几份的数叫做分数;此题中，单位‘1‘分成8份，没有说明是平均分，所以不能用 \\frac{1}{8}表示."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/437.json b/MathToF/437.json
new file mode 100644
index 0000000000000000000000000000000000000000..d3bcda06adfc17598e491965bd5895ebec37c182
--- /dev/null
+++ b/MathToF/437.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "平均数代表一组数据的平均水平。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "平均数反映了一组数据的平均大小，常用带表示数据的总体平均水平。故题目说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/438.json b/MathToF/438.json
new file mode 100644
index 0000000000000000000000000000000000000000..fedfa919e1688fdf217966c72e2112c946666def
--- /dev/null
+++ b/MathToF/438.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.2的倒数是5，1的倒数是1，0的倒数是0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.求一个数的倒数，把这个数的分子和分母掉换位置即可，1的倒数是1，0没有倒数.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/439.json b/MathToF/439.json
new file mode 100644
index 0000000000000000000000000000000000000000..cd3c6ba5983496107a99b1843805192ceeb425d1
--- /dev/null
+++ b/MathToF/439.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为两个质数一定是互质数，所以是互质数的两个数一定是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在自然数中，除了1和它本身外，没有别的因数的数为质数;除了1和它本身外，还有别的因数的数为合数，公因数只有1的两个数为互质数，由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/44.json b/MathToF/44.json
new file mode 100644
index 0000000000000000000000000000000000000000..96e9cfb50640953205ff292313d60e905d63f6ee
--- /dev/null
+++ b/MathToF/44.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三十亿零二百八十万三千零三 写作:30028003003"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数的写法，从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0，即可写出此数;或根据整数的读法，从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，即可读出此数;然后再判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/440.json b/MathToF/440.json
new file mode 100644
index 0000000000000000000000000000000000000000..b82ef205c74611256d2b8367db31770e38e09089
--- /dev/null
+++ b/MathToF/440.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "98×5-98=(98-98)×5=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "98×5-98根据先算乘法，再算减法的计算顺序求出运算的结果，再与0比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/441.json b/MathToF/441.json
new file mode 100644
index 0000000000000000000000000000000000000000..184ce7c41512f2eac14ef5175af492d7a51943a5
--- /dev/null
+++ b/MathToF/441.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "男生人数比女生人数多 \\frac{1}{5}，女生人数就比男生人数少 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "男生人数比女生人数多 \\frac{1}{5}，将女生当做单位‘1‘，则男生是女生的1+ \\frac{1}{5}=1 \\frac{1}{5};求女生人数就比男生人数少几分之几，即将男生当做单位‘1‘，则女生比男生少 \\frac{1}{5} ÷1 \\frac{1}{5}= \\frac{1}{6}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/442.json b/MathToF/442.json
new file mode 100644
index 0000000000000000000000000000000000000000..f346cda544b5c3fb84ebd7db7fc7ed82133aa519
--- /dev/null
+++ b/MathToF/442.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用钥匙开锁的运动是旋转现象"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "用钥匙开锁，是钥匙在锁芯内绕中心转动，根据旋转的意义，将某个图形，绕一个顶点沿某个方向旋转一个角度，这样的图形运动称为旋转，因此，用钥匙开锁，钥匙实际是在做旋转运动."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/443.json b/MathToF/443.json
new file mode 100644
index 0000000000000000000000000000000000000000..128060cd4a8f45f34af349ac9bc071d2da836411
--- /dev/null
+++ b/MathToF/443.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "北偏西30°，还可以说成西偏北60°"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据同一物体的位置，由于同一观测点叙述方法的不同有两种说法，这两种说的角度和是90度;据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/444.json b/MathToF/444.json
new file mode 100644
index 0000000000000000000000000000000000000000..a9bab2e533623995f45558e7836d50d3e3c58ec5
--- /dev/null
+++ b/MathToF/444.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "余数都不大于商"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，余数总比除数小，由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/445.json b/MathToF/445.json
new file mode 100644
index 0000000000000000000000000000000000000000..858f9bc3ed50c44913d554f1c9264b7fad2926a7
--- /dev/null
+++ b/MathToF/445.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个非零自然数的最小公倍数就是它们的乘积。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            ":互质的两个非零自然数的最小公倍数就是它们的乘积。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/446.json b/MathToF/446.json
new file mode 100644
index 0000000000000000000000000000000000000000..e518eeefcdcff5455ef830a6e5b887cf5ed1b7a3
--- /dev/null
+++ b/MathToF/446.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "傍晚，面对太阳，你的右手边是南方"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据太阳东升西落的自然规律可知，傍晚，面对太阳，面对的是西方，左面是南方，右面是北方，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/447.json b/MathToF/447.json
new file mode 100644
index 0000000000000000000000000000000000000000..2020d3e6857d4092871cb51a5dca13218a4ae972
--- /dev/null
+++ b/MathToF/447.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "算盘上方1颗粒相当于5颗珠子，电子计算器ON/C是开关及清除屏的键"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据算盘的用法，以及电子计算器中按键的功能进行回答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/448.json b/MathToF/448.json
new file mode 100644
index 0000000000000000000000000000000000000000..075eb449eed28479a6aa9238692347585316aef2
--- /dev/null
+++ b/MathToF/448.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "将一个长2毫米的零件画在图纸上长10厘米，这幅图的比例尺是1:50"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比例尺=图上距离:实际距离，可直接求得这幅图的比例尺，再进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/449.json b/MathToF/449.json
new file mode 100644
index 0000000000000000000000000000000000000000..b4b68213e580c46492796b1d1e0476f4ef461d0f
--- /dev/null
+++ b/MathToF/449.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算1000-(800÷16+3)时，先算除法，再算加法，最后算减法。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "如果有括号先算括号里的，如果没有括号，则先算乘除法，再算加减法，所以这个1000-(800÷16+3)式子是先算括号里的除法，再算括号里的加法，最后算括号外的减法，所以这个说法是对的。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/45.json b/MathToF/45.json
new file mode 100644
index 0000000000000000000000000000000000000000..b40fe5e25234b7ce31c5602062fd1f36f3a7dbea
--- /dev/null
+++ b/MathToF/45.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最简分数的分子和分母一定是互质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据最简分数的意义:分子和分母是互质数的分数叫做最简分数，即可知道答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/450.json b/MathToF/450.json
new file mode 100644
index 0000000000000000000000000000000000000000..0f2536459c44519c2adf0c032716c70f7783e827
--- /dev/null
+++ b/MathToF/450.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果a ÷ \\frac{1}{3}=b× \\frac{1}{5}(a，b都大于0)，那么a<b"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据一个不为0的数除以一个小于1的数，得数大于这个数得出:a÷ \\frac{1}{3}>a;  又因为一个不为0的数乘一个小于1的数，得数小于这个数得出:b× \\frac{1}{5}<b;  又因为a ÷ \\frac{1}{3}=b× \\frac{1}{5}，所以a<b.据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/451.json b/MathToF/451.json
new file mode 100644
index 0000000000000000000000000000000000000000..caa371c0e5eec72950bc6c045894c6e5cbd5a9a2
--- /dev/null
+++ b/MathToF/451.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "860÷30=86÷3=28…2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据‘被除数和除数都缩小(或都扩大)相同的倍数，商不变，但余数也随着缩小(或扩大)相同的倍数‘，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/452.json b/MathToF/452.json
new file mode 100644
index 0000000000000000000000000000000000000000..dbe68ef91fe31e153bbf54c2f74e2af1f06739bf
--- /dev/null
+++ b/MathToF/452.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要反映某学生6~13岁的身高与体重的变化情况，应使用折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/453.json b/MathToF/453.json
new file mode 100644
index 0000000000000000000000000000000000000000..6e8c8e329a83ec6b65af80bf8954bcca86e2fdad
--- /dev/null
+++ b/MathToF/453.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8乘23与7的和，积是多少?正确列式是:8×23+7"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先用23加上7求出和，再用8乘上求出的和，由此进行列式，再与8×23+7比较."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/454.json b/MathToF/454.json
new file mode 100644
index 0000000000000000000000000000000000000000..6d8f887c1dfcb76942e6f41ae07bd99b9229ec95
--- /dev/null
+++ b/MathToF/454.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个苹果分成3份，其中的1份是这个苹果的 \\frac{1}{2}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个苹果的质量或体积看作单位‘1‘，把它平均分成3份，每份是这个苹果的 \\frac{1}{3}，若不平均分，则无法确定."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/455.json b/MathToF/455.json
new file mode 100644
index 0000000000000000000000000000000000000000..624011206521494780ec9400b3ef23c856d5823c
--- /dev/null
+++ b/MathToF/455.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个苹果平均分成4份，吃了三块，则吃了苹果的四分之三。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整个苹果占单位‘1‘，共分为4份，吃了三份，三份占四份的，所以本题对。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/456.json b/MathToF/456.json
new file mode 100644
index 0000000000000000000000000000000000000000..f858c2a349169056ce13b40b094f582e533b0554
--- /dev/null
+++ b/MathToF/456.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一本书共有400页，明明如果每天读28页，两周就能全部读完。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两周是14天，28*14=392页，392页<400页，所以两周无法全部读完。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/457.json b/MathToF/457.json
new file mode 100644
index 0000000000000000000000000000000000000000..142fc15ed0f4c5bc8777e1ddb249c1a658d22e2d
--- /dev/null
+++ b/MathToF/457.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "与49999相邻的两个数是49998和500000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "求一个数相邻的数，就是用这个数减去1，得出它前面的数，用这个数加上1，得到它后面的数，从而解决问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/458.json b/MathToF/458.json
new file mode 100644
index 0000000000000000000000000000000000000000..135656202acfd230a3a3e15a00060d56b039b4f2
--- /dev/null
+++ b/MathToF/458.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个长方形长30米，宽20米，它的面积600米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方形的面积=长×宽，代入数据即可解答，注意长度单位和面积单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/459.json b/MathToF/459.json
new file mode 100644
index 0000000000000000000000000000000000000000..cd2f8e7e7cb86cfd11b4a17c18b4a80e331c2c9e
--- /dev/null
+++ b/MathToF/459.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母同时加上一个数(0除外)，分数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的基本性质:分数的分子和分母同时乘或者除以相同的数(0除外)，分数的大小不变，一分数的分子和分母同时加上一个数，结果不一定不变，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/46.json b/MathToF/46.json
new file mode 100644
index 0000000000000000000000000000000000000000..6ac003d110490af77c2a2d303d2ba1afe1f39a0d
--- /dev/null
+++ b/MathToF/46.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相除，商一定小于被除数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个数(不为0)除以大于1的数，商小于这个数(被除数);  一个数(不为0)除以小于1的数，商大于这个数(被除数);  一个数(不为0)除以1，商等于这个数(被除数);  因此两个数相除，商一定小于被除数.此说法是错误的.  错误.  利用两个数相除，除数与商之间的关系解答分情况探讨即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/460.json b/MathToF/460.json
new file mode 100644
index 0000000000000000000000000000000000000000..abc968c7af6b498520834970f524590cdf77c1b5
--- /dev/null
+++ b/MathToF/460.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个非0自然数的积一定是这两个数的公倍数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "两个非0自然数的积分别是两个数的倍数，所以一定是这两个数的公倍数。题中说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/461.json b/MathToF/461.json
new file mode 100644
index 0000000000000000000000000000000000000000..79691b64ca987fd81f8d4b1328acc0e5ec91d1ee
--- /dev/null
+++ b/MathToF/461.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "哪一位上乘得的积满几十，就向前一位进十"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据整数乘法计算方法:哪一位上乘得的积满几十，就向前一位进几即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/462.json b/MathToF/462.json
new file mode 100644
index 0000000000000000000000000000000000000000..1ffdcb7a74b93748b1eed110e9e741c3186e72e7
--- /dev/null
+++ b/MathToF/462.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三角形是轴对称图形，它有3条对称轴"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据对称轴的定义:如果一个图形沿着一条直线对折，两侧的图形能完全重合，这个图形就是轴对称图形.折痕所在的这条直线叫做对称轴."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/463.json b/MathToF/463.json
new file mode 100644
index 0000000000000000000000000000000000000000..01a11771f646cc693ea0b6bd40b3544f6bf0996e
--- /dev/null
+++ b/MathToF/463.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "五年级有女生a人，比男生的2倍少4人，则五年级的男生是(2a-4)人"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "设这个班有男生x人，男生人数的2倍为2x，根据等量关系‘男生人数×2倍-4人=女生的人数‘，由此可得方程:2x-4=a.再解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/464.json b/MathToF/464.json
new file mode 100644
index 0000000000000000000000000000000000000000..9835d627562a4839ad2fd51466c4f9aad7b2f07a
--- /dev/null
+++ b/MathToF/464.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，积一定会比其中每一个乘数都大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "如果其中一个数为1，如10×1=10，并不比10要大。故题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/465.json b/MathToF/465.json
new file mode 100644
index 0000000000000000000000000000000000000000..abfe7e6dfd9b7cb199aff4c044d31932286fd953
--- /dev/null
+++ b/MathToF/465.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最小的质数与最小的奇数的和是2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最小的质数是2，最小的奇数是1，求出它们的和与2进行比较即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/466.json b/MathToF/466.json
new file mode 100644
index 0000000000000000000000000000000000000000..60e4f189b1e3c0f7b17a514b625c5a9fa5efad11
--- /dev/null
+++ b/MathToF/466.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为5×6=30，所以30是倍数，5和6是因数."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:根据因数和倍数的含义，因为5×6=30，所以30是5和6的倍数，5和6是30的因数，不能说哪个数是因数(或倍数)，据此判断即可. 解:因为5×6=30， 所以30是5和6的倍数，5和6是30的因数， 所以题中说法不正确. 故答案为:×."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/467.json b/MathToF/467.json
new file mode 100644
index 0000000000000000000000000000000000000000..fd8f1c1d50755a5a4f450cfb6b84dba5d10aab05
--- /dev/null
+++ b/MathToF/467.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一张长62.8厘米，宽31.4厘米的长方形纸片卷成一个圆柱形纸筒(粘贴处忽略不计)，它的底面半径一定是10厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题有两种情况:(1)卷成的圆柱筒的底面周长是62.8厘米，高是31.4厘米;(2)卷成的圆柱筒底面周长是31.4厘米，高是62.8厘米，由此利用底面周长=2πr分别求出它的底面半径即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/468.json b/MathToF/468.json
new file mode 100644
index 0000000000000000000000000000000000000000..a7ac8d69156c9cf447fc871c42eaf51b8ffa9436
--- /dev/null
+++ b/MathToF/468.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相乘，积一定是小数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个小数相乘，当积末尾的0的个数与因数中的小数位数相同时，积是整数，所以此题错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/469.json b/MathToF/469.json
new file mode 100644
index 0000000000000000000000000000000000000000..9b08b63393212a453b1ffbea1566c535ccfc82c3
--- /dev/null
+++ b/MathToF/469.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "50米跑，小明跑了9秒，小华跑了10秒，小华比小明跑的快"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为速度×时间=路程(一定)，所以速度和时间成反比例，由此可知:50米跑，用时间少的速度快，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/47.json b/MathToF/47.json
new file mode 100644
index 0000000000000000000000000000000000000000..97553787e87825a788ed4cf9bd795ea6125f8f57
--- /dev/null
+++ b/MathToF/47.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个锐角和一个直角可以组成一个钝角"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "大于90度而小于180度的角是钝角，小于90度的角是锐角，直角等于90度.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/470.json b/MathToF/470.json
new file mode 100644
index 0000000000000000000000000000000000000000..c6b2f3d5ce85ab1e1ad6053bd6849476b10bf85e
--- /dev/null
+++ b/MathToF/470.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个圆柱削成一个最大的圆锥体，削去部分体积是圆锥体积的2倍。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "解答:因为等底等高的圆锥体积是圆柱体积的  ，所以削去部分体积是圆锥体积的2倍，因此把一个圆柱削成一个最大的圆锥体，削去部分体积是圆锥体积的2倍。此说法正确。 正确  分析:等底等高的圆锥体积是圆柱体积的  ，所以削去部分体积是圆锥体积的2倍，据此判断。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/471.json b/MathToF/471.json
new file mode 100644
index 0000000000000000000000000000000000000000..ea8149f9a517e1c2da6604e231b60426300bb992
--- /dev/null
+++ b/MathToF/471.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果积的末尾有0，那么相乘的两位数中至少有一个数的末尾有0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在乘法计算过程中，因为5与偶数相乘时积的末尾会有0出现，例如:5×2=10，此时两个因为的末尾都没有0，所以题干陈述错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/472.json b/MathToF/472.json
new file mode 100644
index 0000000000000000000000000000000000000000..93476f705427350670970d85e52086c075fd8043
--- /dev/null
+++ b/MathToF/472.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方形的面积是36平方分米，那么它的边长是9分米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正方形的面积公式:S=\\( a^{2} \\)，所以a= \\frac{}{S}，求出这个正方形的边长，再与9分米作比较，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/473.json b/MathToF/473.json
new file mode 100644
index 0000000000000000000000000000000000000000..66dfd7fe95b4909189445fd25090476d1cb0cf85
--- /dev/null
+++ b/MathToF/473.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3个边长是1厘米的正方形拼成长方形，这个长方形面积是3平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把3个边长是1厘米正方形拼成一个长方形，方法只有一种，然后根据长方形的面积公式解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/474.json b/MathToF/474.json
new file mode 100644
index 0000000000000000000000000000000000000000..50408f852a1ceca558488a7cb2745be6a8810a46
--- /dev/null
+++ b/MathToF/474.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "正方形面积比长方形面积大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题是没有告诉两个图形的边长，没法比较面积的大小，只有在特定的条件下如:周长相等的正方形和长方形，正方形的面积比长方形的面积大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/475.json b/MathToF/475.json
new file mode 100644
index 0000000000000000000000000000000000000000..522a59b2b0623fa5d6dcbc14a9b3fe97270c3f5f
--- /dev/null
+++ b/MathToF/475.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.6小时:30分钟化成最简整数比是5:6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先把比的前项0.6小时化成0.6×60=36分钟，再根据比的基本性质，即比的前项和后项同时乘或除以一个相同的数(0除外)比值不变，进而把比化成最简比进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/476.json b/MathToF/476.json
new file mode 100644
index 0000000000000000000000000000000000000000..fd7e9df777b9b74ff52dea9ab1d1b197b2227793
--- /dev/null
+++ b/MathToF/476.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "若3x=5y，(x，y，不为0)，那么x和y成正比例。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "如果3x=5y，则y:x=3:5=0.6(一定)，x和y成正比例。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/477.json b/MathToF/477.json
new file mode 100644
index 0000000000000000000000000000000000000000..20dac7378ce65966476f469ff1c8bcec76198099
--- /dev/null
+++ b/MathToF/477.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "二年(1)班有女生26人，比男生少9人，二年(1)班共有学生43人"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据‘女生26人，比男生少9人‘，可知男生有26+9=35(人)，因此二年(1)班共有学生26+35，计算出结果即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/478.json b/MathToF/478.json
new file mode 100644
index 0000000000000000000000000000000000000000..5005c37a984d886117271547bd5dcef682e4a178
--- /dev/null
+++ b/MathToF/478.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1.5除以0.2，商是7，余数是1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求商和余数，根据‘被除数÷除数=商…余数‘，代入数值，进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/479.json b/MathToF/479.json
new file mode 100644
index 0000000000000000000000000000000000000000..d2dd1f5316204caf5386d5db7a214a8881eee96f
--- /dev/null
+++ b/MathToF/479.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "‘甲比乙多 \\frac{1}{8}‘，也可以说是‘乙比甲少 \\frac{1}{8}‘"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "甲比乙多 \\frac{1}{8}是把乙数看成单位‘1‘，甲数是(1+ \\frac{1}{8})，用 \\frac{1}{8}除以甲数就是乙数比甲数少几分之几，再与 \\frac{1}{8}比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/48.json b/MathToF/48.json
new file mode 100644
index 0000000000000000000000000000000000000000..9367340c65f553d05063fb1dede96c4463be0748
--- /dev/null
+++ b/MathToF/48.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3除以0.3的商是4，余数是1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，余数总比除数小，直接判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/480.json b/MathToF/480.json
new file mode 100644
index 0000000000000000000000000000000000000000..af974dce2d70465280f5b4b45a608fdbbfaebf2f
--- /dev/null
+++ b/MathToF/480.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为27比24大，所以27的因数比24的因数多"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据求一个数的因数的方法，进行依次列举比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/481.json b/MathToF/481.json
new file mode 100644
index 0000000000000000000000000000000000000000..b1a31282fbb2414010cb82f0d05b1b6a3102b44d
--- /dev/null
+++ b/MathToF/481.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小明家在学校的西面，学校在小明家的东面"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据判定两个物体位置的方法，即一个物体在另一个物体的某个方向，则另一物体就在这个物体的相反方向上，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/482.json b/MathToF/482.json
new file mode 100644
index 0000000000000000000000000000000000000000..a498aed9746bae010724206bafa84b4d293b8644
--- /dev/null
+++ b/MathToF/482.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "正方体棱长扩大到原来的2倍，它的表面积就扩大到原来的8倍，它的体积也扩大到原来的8倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据正方体的特征，6个面都是正方形，6个面的面积都相等，12条棱的长度都相等.正方体的表面积公式是:S=6\\( a^{2} \\)，体积公式是:V=\\( a^{3} \\)，根据因数与积的变化规律解决问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/483.json b/MathToF/483.json
new file mode 100644
index 0000000000000000000000000000000000000000..632fa3d12e1ff82c5948d8eb1e833c4d92c5f753
--- /dev/null
+++ b/MathToF/483.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要表示几年来工业总产值增减变化情况，应选择条形统计图比较合适。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况解答即可。 根据统计图的特点可知:要表示几年来工业总产值增减变化情况，应选择折线统计图比较合适;所以原题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/484.json b/MathToF/484.json
new file mode 100644
index 0000000000000000000000000000000000000000..bd8662004f2a8bb37d8c553a5df23d5253f819f9
--- /dev/null
+++ b/MathToF/484.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个鸡蛋的重量是50克，也就是5%千克"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "百分数是‘表示一个数是另一个数百分之几的数.‘它只能表示两数之间的倍数关系，不能表示某一具体数量;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/485.json b/MathToF/485.json
new file mode 100644
index 0000000000000000000000000000000000000000..6378f4d4b0bfdc7e5f05cb91d944af796256982f
--- /dev/null
+++ b/MathToF/485.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个圆面积相等，那么它们的周长也一定相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆的面积公式:s=π\\( r^{2} \\)，周长公式:c=2πr，两个圆的面积相等，因为圆周率是一定的，两个圆的半径一定相等，所以它们的周长一定相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/486.json b/MathToF/486.json
new file mode 100644
index 0000000000000000000000000000000000000000..d318b39b6fca387fadb4beadc81cf6c4cd144657
--- /dev/null
+++ b/MathToF/486.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{13}{4}- \\frac{13}{4}× \\frac{13}{4}=0× \\frac{13}{4}=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "我们运用分数加减乘除法的计算法则进行计算，按照四则混合运算的顺序进行计算，含两级运算，先做乘除后做加减，计算后在进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/487.json b/MathToF/487.json
new file mode 100644
index 0000000000000000000000000000000000000000..a337afadd1519ea0becbe5613eccb50a5f8fee45
--- /dev/null
+++ b/MathToF/487.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，乘数末尾有几个0，积的末尾就一定有几个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数末尾有0的乘法的计算方法‘先把0前面的数相乘，然后再数数两个因数末尾一共有几个0，就在乘得的积的末尾添上几个0.‘由此可知，如果0前面的数乘得的积的末尾没有0，则积的末尾0的个数与因数末尾0的个数和相等;如果0前面的数乘得的积的末尾有0，则积的末尾0的个数比因数末尾0的个数的和要多."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/488.json b/MathToF/488.json
new file mode 100644
index 0000000000000000000000000000000000000000..124b6c5dfe6ba80c8584f34067b87c61ba05ba37
--- /dev/null
+++ b/MathToF/488.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个自然数比较大小时，位数多的数比较大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "比较两个整数的大小，首先看这两个整数的位数是否相同，如果位数不同，位数多的大于位数少的，如果位数相同，相同数位上大的数就大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/489.json b/MathToF/489.json
new file mode 100644
index 0000000000000000000000000000000000000000..e35c0970e7f6aedac3ee781fc1ba527c5079498c
--- /dev/null
+++ b/MathToF/489.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "69后面的一个数是68"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "68是69前面的数不是后面的数69后面的数是70，不是68"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/49.json b/MathToF/49.json
new file mode 100644
index 0000000000000000000000000000000000000000..cfb03588ece33045970e896d59e0ee2f1816ed7e
--- /dev/null
+++ b/MathToF/49.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以3，余数可能是1或2"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，余数总比除数小，然后列举出所有的余数，继而判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/490.json b/MathToF/490.json
new file mode 100644
index 0000000000000000000000000000000000000000..6d7e272fa9ceb049c8c5de200cc860e487d1c891
--- /dev/null
+++ b/MathToF/490.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要反映某地2004~2008年降水量上升或下降的情况，应绘成折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/491.json b/MathToF/491.json
new file mode 100644
index 0000000000000000000000000000000000000000..10b7946853d85517d3f297749def62f3d7f03b02
--- /dev/null
+++ b/MathToF/491.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数的因数一定比它的倍数小"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据‘一个数最大的因数是它本身，最小的倍数是它本身;进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/492.json b/MathToF/492.json
new file mode 100644
index 0000000000000000000000000000000000000000..fe6c3c7deffbd552633f4aa1a9bcee5b779ba33d
--- /dev/null
+++ b/MathToF/492.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{4}{16}= \\frac{1}{4}，所以 \\frac{4}{16}的分数单位就是 \\frac{1}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "将单位‘1‘平均分成若干份，表示其中这样一份的数为分数单位.由此可知， \\frac{1}{4}的分数单位是 \\frac{1}{4}， \\frac{4}{16}的分数单位是 \\frac{1}{16}，它们的分数单位不同."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/493.json b/MathToF/493.json
new file mode 100644
index 0000000000000000000000000000000000000000..8006894fa8d2f6bccc8c8856f93545cf9a03c807
--- /dev/null
+++ b/MathToF/493.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用6个1平方分米的正方形拼成的长方形，它们的面积相等，周长也相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "6个小正方形拼组长方形有2种不同的拼组方法:(1)一字排列，长方形的长与宽分别是6分米、1分米;(2)2×3排列，长方形的长与宽分别是3分米、2分米，据此分别求出它们的周长和面积即可解答问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/494.json b/MathToF/494.json
new file mode 100644
index 0000000000000000000000000000000000000000..48057926f77c11fd38a8e661faafb31bd6f39d34
--- /dev/null
+++ b/MathToF/494.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1米的 \\frac{3}{10}就是 \\frac{3}{10}米，也就是0.3米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数的意义，1米的 \\frac{3}{10}就是1× \\frac{3}{10}= \\frac{3}{10}米，根据分数与小数的互化， \\frac{3}{10}米=0.3米."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/495.json b/MathToF/495.json
new file mode 100644
index 0000000000000000000000000000000000000000..58d8bd4ddb03a70524d94978b4d8112d1b25f91c
--- /dev/null
+++ b/MathToF/495.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{3}{5}比 \\frac{8}{9}小，所以 \\frac{3}{5}的分数单位比 \\frac{8}{9}的分数单位小"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "将单位‘1‘平均分成若干份，表示其中这样一份的数为分数单位.由此可知， \\frac{3}{5}的分数单位为 \\frac{1}{5}， \\frac{8}{9}的分数单位为 \\frac{1}{9}， \\frac{1}{5}> \\frac{1}{9}，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/496.json b/MathToF/496.json
new file mode 100644
index 0000000000000000000000000000000000000000..ef321144f093ecd2f9019dde4059a472eaeccb8e
--- /dev/null
+++ b/MathToF/496.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "48的24倍与48个24的得数相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "试题分析:要求48的24倍是多少，用48×24即可; 要求48个24是多少，用24×48即可; 分别求出它们的结果，然后再比较判断. 解:48的24倍3是多少，列式48×24=1152; 48个24是多少，24×48=1152; 所以，48的24倍与48个24的得数相同. 故答案为:√."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/497.json b/MathToF/497.json
new file mode 100644
index 0000000000000000000000000000000000000000..9976523d931265d374eec9031d50e0a64e91a05a
--- /dev/null
+++ b/MathToF/497.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "A的 \\frac{1}{4}与B的 \\frac{1}{5}相等(A、B都不为0)，则A与B的比是5:4"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "A的 \\frac{1}{4}与B的 \\frac{1}{5}相等(A、B都不为0)，可知:A× \\frac{1}{4}=B× \\frac{1}{5}，再逆用比例的基本性质(在比例里，两个内项的积等于两个外项的积)解决问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/498.json b/MathToF/498.json
new file mode 100644
index 0000000000000000000000000000000000000000..6ddcae0d492d13cc2a8e18e97cb2f0ab451ee41f
--- /dev/null
+++ b/MathToF/498.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "拧水龙头是平移现象，开关抽屉是旋转现象"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:[错因]:1不能正确区分平移和旋转的概念，2要认真做题哦 [正确答案]:拧水龙头是旋转现象，开关抽屉是平移现象(√) 点评:"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/499.json b/MathToF/499.json
new file mode 100644
index 0000000000000000000000000000000000000000..60564e74a1dcec8c4c3a4a21a4a663aad0c3ad31
--- /dev/null
+++ b/MathToF/499.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根木料长 \\frac{3}{10}米，可以写成30%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "百分数是表示一个数是另一个数的百分之几的数，它只能表示两数的关系，而不能表示一个具体的数，所以百分数不能有单位名称.据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/5.json b/MathToF/5.json
new file mode 100644
index 0000000000000000000000000000000000000000..357c44f82ba43f1ad7b5ab0d855929bb88b14f47
--- /dev/null
+++ b/MathToF/5.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "棱长是6厘米的正方体的表面积和体积相等."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为正方体的表面积和体积单位不相同，没法比较它们的大小，  所以原题说法是错误的.  错误.  正方体的表面积和体积单位不相同，没法比较它们的大小，由此就解决即可.比较两个数的大小必须是统一单位下，面积和体积的单位不同，没法比较."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/50.json b/MathToF/50.json
new file mode 100644
index 0000000000000000000000000000000000000000..1dbaefa04178803ca2c1bb823241753f02418433
--- /dev/null
+++ b/MathToF/50.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "生活中，一般把盈利用正数表示，亏损用负数表示"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先审清题意，明确‘正‘和‘负‘所表示的意义，知道生活中，一般把盈利用正数表示，亏损用负数表示;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/500.json b/MathToF/500.json
new file mode 100644
index 0000000000000000000000000000000000000000..623dcf245c4bb140594a2f85b75a2ee9c2e1054f
--- /dev/null
+++ b/MathToF/500.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "()从同一个方向观察不同的立体图形，看到的形状可能相同。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "从同一个方向观察不同形状的几何体，如观察圆柱体和球体时，看到的形状可能都是圆"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/501.json b/MathToF/501.json
new file mode 100644
index 0000000000000000000000000000000000000000..b99ab8ff5ff6966200ac90604aa2e68862a51211
--- /dev/null
+++ b/MathToF/501.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲数除以一个分数，等于甲数乘这个分数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数除法的计算方法，及乘与除的互逆关系进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/502.json b/MathToF/502.json
new file mode 100644
index 0000000000000000000000000000000000000000..4571c8b6db23da6ab1f6dd7b335ce47473683735
--- /dev/null
+++ b/MathToF/502.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "表示一个星期来气温变化选用条形统计图比较合适"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/503.json b/MathToF/503.json
new file mode 100644
index 0000000000000000000000000000000000000000..2199d89cbfc62a2c645cb79fb00aa8621ce6faca
--- /dev/null
+++ b/MathToF/503.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘(零除外)，一个乘数扩大10倍，另一个乘数也扩大10倍，积扩大20倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据积的变化规律，一个因数不变，另一个因数扩大或缩小几倍(0除外)，积也扩大或缩小相同的倍数;如果两个因数扩大相同的倍数(0除外)，积扩大的倍数就等于两个因数扩大倍数的乘积;两个因数都缩小相同的倍数(0除外)，积缩小的倍数等于两个因数缩小倍数的乘积;由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/504.json b/MathToF/504.json
new file mode 100644
index 0000000000000000000000000000000000000000..7b8a7fc43ebf673a2efe2d9fa55179c0b92bee98
--- /dev/null
+++ b/MathToF/504.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求3个8相加的和是多少?列式是3+8"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数乘法的意义:求几个相同加数的和用乘法计算，求3个8相加的和是多少?列式是8×3，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/505.json b/MathToF/505.json
new file mode 100644
index 0000000000000000000000000000000000000000..e977ed05c296372a384fd550964bec6669836755
--- /dev/null
+++ b/MathToF/505.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "12÷6=2，所以12是倍数，6是因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由因数和倍数的意义可知，当a÷b=c(a、b、c为非0自然数)，我们说a是b的倍数，b是a的因数.由此可见，因数和倍数是相互依存的，不是单独说哪个数是因数，哪个数是倍数.所以本题不能说12是倍数，6是因数.由此可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/506.json b/MathToF/506.json
new file mode 100644
index 0000000000000000000000000000000000000000..14d54ec2083475c86a18f81eb523813262326d2e
--- /dev/null
+++ b/MathToF/506.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分子和分母都是质数的分数，一定是最简分数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分子和分母都是质数的分数，分子和分母不一定互质(当分子和分母都是相同的质数时)，所以这个分数也不一定是最简分数，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/507.json b/MathToF/507.json
new file mode 100644
index 0000000000000000000000000000000000000000..7d70dc2adf1a9396c30e0de016b9a4bf9511436b
--- /dev/null
+++ b/MathToF/507.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任何自然数的倒数都小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.0没有倒数，1的倒数还是1.由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/508.json b/MathToF/508.json
new file mode 100644
index 0000000000000000000000000000000000000000..c177b501d5400714ae095f13dd0f2731051f99a2
--- /dev/null
+++ b/MathToF/508.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母同时乘以任何数，分数大小都不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的基本性质直接进行判断即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/509.json b/MathToF/509.json
new file mode 100644
index 0000000000000000000000000000000000000000..e097b14eaaffdf4479b2a38f6e94c3d3cacf7940
--- /dev/null
+++ b/MathToF/509.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "172×99=172×100-172"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在计算172×99时，把99看作100-1，运用乘法分配律简算，很容易解决."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/51.json b/MathToF/51.json
new file mode 100644
index 0000000000000000000000000000000000000000..3584f9c6319dcdbd9864adc0e81d2b3b47c053b5
--- /dev/null
+++ b/MathToF/51.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "死海低于海平面400米，记作+400米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题应以海平面为标准，超出海平面的米数记为正，低于海平面的米数记为负，直接判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/510.json b/MathToF/510.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c78ea9c9d5cb6ecb0b1a53adea7233815813bc3
--- /dev/null
+++ b/MathToF/510.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "互质的两个数一定都是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据互质数的意义，公因只有1的两个数叫做互质数.1和任何非0自然数是互质数，1既不是质数也不是合数;由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/511.json b/MathToF/511.json
new file mode 100644
index 0000000000000000000000000000000000000000..1ecc25e91e9553e6aa55a99b3198bf39148ac662
--- /dev/null
+++ b/MathToF/511.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在做笔算减法时，哪一位上的数不够减，从前一位上退1当10，再减"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题根据整数减法的运算法则进行分析判断即可:相同数位对齐，从低位减起，哪一位上的数不够减，就从它的前一位退一作十，和本位上的数合并在一起，再减."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/512.json b/MathToF/512.json
new file mode 100644
index 0000000000000000000000000000000000000000..d311a1a6248c16b402e57f9e2b21094274b7610f
--- /dev/null
+++ b/MathToF/512.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "四条边都相等，四个角都是直角的图形是正方形。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据正方形的特征可知:具有四条边都相等且四个角都是直角的四边形为正方形。 故表述正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/513.json b/MathToF/513.json
new file mode 100644
index 0000000000000000000000000000000000000000..715a54da0dd2a38009f6dac755bba212357fb431
--- /dev/null
+++ b/MathToF/513.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "正方形是轴对称图形，它有4条对称轴"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据轴对称图形的概念，即在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是其对称轴，从而可以解答问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/514.json b/MathToF/514.json
new file mode 100644
index 0000000000000000000000000000000000000000..850419be1451509df0b782d847bc0ed6d94005a2
--- /dev/null
+++ b/MathToF/514.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{11}的分子增加6，要使分数的大小不变，分母应增加6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "\\frac{3}{11}的分子增加6，分子变成9(3+6=9)，分子扩大到原来的3倍，根据分数的基本性质，要使分数的大小不变，分母也应扩大到原来的3倍，据此求出分母应增加多少即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/515.json b/MathToF/515.json
new file mode 100644
index 0000000000000000000000000000000000000000..93e662fa53c64379996b2519baefd826d56b72ee
--- /dev/null
+++ b/MathToF/515.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "217÷15=14…7，正确的验算方法可以是(217-7)÷15=14"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据‘被除数÷除数=商…余数‘，可得:被除数=商×除数+余数或商=(被除数-余数)÷除数"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/516.json b/MathToF/516.json
new file mode 100644
index 0000000000000000000000000000000000000000..1fef0188d2cf24922a025cf7124714b4b4823f3a
--- /dev/null
+++ b/MathToF/516.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一件商品打七折销售，就是按原价的30%销售"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为打几折就是指现价是原价的百分之几十，所以一种商品打七折销售，‘七折‘表示现价是原价的70%."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/517.json b/MathToF/517.json
new file mode 100644
index 0000000000000000000000000000000000000000..dc5a2cef6801b30e37966eb42911c4e84127db60
--- /dev/null
+++ b/MathToF/517.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "454999用四舍五入法精确到万位约是46万"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用四舍五入法精确到万位，根据千位上数字的大小来确定用‘四舍‘法、还是用‘五入‘法，454999，千位上是4，用‘四舍‘法，省略尾数后，近似数是45万."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/518.json b/MathToF/518.json
new file mode 100644
index 0000000000000000000000000000000000000000..542606b808e12eb9ac8535500d11aa3db12c4a1d
--- /dev/null
+++ b/MathToF/518.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{25}÷ \\frac{4}{3}和 \\frac{3}{25}× \\frac{3}{4}，它们的结果相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数除法的意义:一个分数除以一个数(0除外)，等于乘这个数的倒数，所以 \\frac{3}{25}÷ \\frac{4}{3}= \\frac{3}{25}× \\frac{3}{4}，因此它们的结果相同."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/519.json b/MathToF/519.json
new file mode 100644
index 0000000000000000000000000000000000000000..3107801a2aeab1ac2f25f4387284733a7e361439
--- /dev/null
+++ b/MathToF/519.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两位数乘一位数，哪一位上乘得的积满几十，就向前一位进几"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "两位数乘一位数时，从个位起，用这个一位数依次去乘这个多位数上的每一位数，乘到哪一位，得数的末尾就和两位数的哪一位对齐;乘积满几十就向前一位进几.依此即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/52.json b/MathToF/52.json
new file mode 100644
index 0000000000000000000000000000000000000000..a8060766c16c3da93603e5707c780944c89a3e8e
--- /dev/null
+++ b/MathToF/52.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1除以一个不为0的数，商等于这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "设这个数为a(a≠0)，则1÷a= \\frac{1}{a}，所以1除于一个不为0的数，商等于这个数的倒数，这种说法正确."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/520.json b/MathToF/520.json
new file mode 100644
index 0000000000000000000000000000000000000000..f709d1ae5f8c7fbab22728411c55515accfa645f
--- /dev/null
+++ b/MathToF/520.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "从左面和从右面看到的图形是一样的"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "例如 从左面看得到从左往右2列正方形的个数依次为2，1;从右面看得到从左往右2列正方形的个数依次为1，2，依此画出图形即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/521.json b/MathToF/521.json
new file mode 100644
index 0000000000000000000000000000000000000000..a9e79a43512e6bc6aa7dfa5f6819163dbfa4c839
--- /dev/null
+++ b/MathToF/521.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "()1张10元可以换1张5元和3张1元."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "1张10元可以换1张5元和5张1元，原说法错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/522.json b/MathToF/522.json
new file mode 100644
index 0000000000000000000000000000000000000000..e107fc452794d4c9982a970970cfcc49f9fa04f9
--- /dev/null
+++ b/MathToF/522.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用一个直角和一个锐角拼出的角一定是钝角。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据钝角、直角、锐角的含义可知:锐角是大于0°小于90°的角;直角是等于90°的角;钝角是大于90°小于180°的角;所以直角+锐角=钝角，据此解答。 根据钝角、直角、锐角的含义可知:一个直角和一个锐角拼出的角一定是钝角。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/523.json b/MathToF/523.json
new file mode 100644
index 0000000000000000000000000000000000000000..476f8e77bcd3b971f78b3dcafef759011c32c3c0
--- /dev/null
+++ b/MathToF/523.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相加，和一定是小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数加法的运算方法，两个小数相加，和不一定是小数，当这两个小数的小数部分的和是整数时，这两个小数的和就是整数，并举例说明即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/524.json b/MathToF/524.json
new file mode 100644
index 0000000000000000000000000000000000000000..885261ab34d0e98af182c290bae100571d03dbd5
--- /dev/null
+++ b/MathToF/524.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数省略万位后面的尾数后约等于19万，这个数最大是189999。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "解:‘四舍‘可知，一个数省略万位后面的尾数后约等于19万，这个数最大是194999。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/525.json b/MathToF/525.json
new file mode 100644
index 0000000000000000000000000000000000000000..92bd679d9adffead508451753d93dfa44fc56fce
--- /dev/null
+++ b/MathToF/525.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "4个小正方体摆放在一起，露在外面的面有14个"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，举出反例，由此即可得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/526.json b/MathToF/526.json
new file mode 100644
index 0000000000000000000000000000000000000000..810083fb43799594e0ab20aa99e613543d858446
--- /dev/null
+++ b/MathToF/526.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形内角度数比是3:2:5，这个三角形是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为三角形的内角和是180度，利用按比例分配的方法求出最大角的度数，即可判定这个三角形的类别."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/527.json b/MathToF/527.json
new file mode 100644
index 0000000000000000000000000000000000000000..4bfd34bc2e5ec429564a6e15432c168de0cb1040
--- /dev/null
+++ b/MathToF/527.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "10÷(0.1+0.2)=10÷0.1+10÷0.2=100+50=150"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在计算10÷(0.1+0.2)时，应先算括号内的，再算括号外的.而原题错用了除法的运算性质，故错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/528.json b/MathToF/528.json
new file mode 100644
index 0000000000000000000000000000000000000000..37f83cb91950f6b793cb5121c72076e608ae6332
--- /dev/null
+++ b/MathToF/528.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "100厘米赛跑中，小明用了19.65秒，小军用了17.74秒，因为19.65>17.74，所以小明跑得快些"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "行驶相同的路程，用的时间越短，则速度越快，因此比较出两人所用时间长短即知谁跑的快."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/529.json b/MathToF/529.json
new file mode 100644
index 0000000000000000000000000000000000000000..0651cba9a4f50e1ceff1d9a389a648ffac91d8d1
--- /dev/null
+++ b/MathToF/529.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要统计出第25至29届奥运会我国获得的金牌数的变化情况，选用条形统计图比较恰当"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/53.json b/MathToF/53.json
new file mode 100644
index 0000000000000000000000000000000000000000..d13a63c32a4222f1468417370e5242d6330ad3b6
--- /dev/null
+++ b/MathToF/53.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最小的偶数是2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据偶数的意义，是2的倍数的数叫做偶数.0是2的倍数，则最小的偶数是0.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/530.json b/MathToF/530.json
new file mode 100644
index 0000000000000000000000000000000000000000..cdaa1d11b03e158a3e77a3c6c49349879c77d1f1
--- /dev/null
+++ b/MathToF/530.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "整数的运算定律在小数运算中同样适用。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整数的运算定律对于小数、分数运算同样适用."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/531.json b/MathToF/531.json
new file mode 100644
index 0000000000000000000000000000000000000000..0f8613f63289b79cc3e27d06d94b8c8d3f7f0b65
--- /dev/null
+++ b/MathToF/531.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "比较两个自然数的大小时，位数少的数就小"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "比较两个整数的大小，首先看这两个整数的位数是否相同，如果位数不同，位数多的大于位数少的，如果位数相同，相同数位上大的数就大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/532.json b/MathToF/532.json
new file mode 100644
index 0000000000000000000000000000000000000000..af2663daf69f38478d24aad0dac66e734447f45c
--- /dev/null
+++ b/MathToF/532.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把3米长的绳子平均分成7份，每份是全长的 \\frac{3}{7}，长 \\frac{1}{7} 米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把3米长的绳子看作单位‘1‘，把它平均分成7份，用单位‘1‘除以分的份数，就是每份占全长的几分之几，总长度除以平均分的份数就是每份的长度，据此求得结果后比较得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/533.json b/MathToF/533.json
new file mode 100644
index 0000000000000000000000000000000000000000..d057c3fe29238c1c9a8183e57214ab52540c2f3b
--- /dev/null
+++ b/MathToF/533.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两位数乘两位数时，因数末尾有几个O，积的末尾就有几个O"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设这两个因数分别是20和50，计算出结果后进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/534.json b/MathToF/534.json
new file mode 100644
index 0000000000000000000000000000000000000000..e0ae7ceae14eeb38f5e75155fef249e6bbbeff12
--- /dev/null
+++ b/MathToF/534.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "第一组同学的平均身高是136厘米，第二组同学的平均身高是138厘米.第一组的善超一定比第二组的李丽矮"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为平均数反映的是一组数据的特征，不是其中每一个数据的特征，它比最小的数大一些，比最大的数小一些，在它们之间;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/535.json b/MathToF/535.json
new file mode 100644
index 0000000000000000000000000000000000000000..d48df20fc6d8d2a29ad69b838b330fbbd0770ad0
--- /dev/null
+++ b/MathToF/535.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用两个同样大小的正方形拼成一个长方形，长方形的周长等于正方形周长的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用两个同样大小的正方形拼成一个长方形，拼成后长方形的长是原正方形边长的2倍，宽是原正方形的边长.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/536.json b/MathToF/536.json
new file mode 100644
index 0000000000000000000000000000000000000000..595fbde32365c4719edb891dd9f87b61d38eb3a3
--- /dev/null
+++ b/MathToF/536.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "10千克增加它的 \\frac{1}{10}后，再减少 \\frac{1}{10}，结果还是10千克"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先把10千克看作单位‘1‘，增加它的 \\frac{1}{10}就是10千克的1+ \\frac{1}{10}= \\frac{11}{10}，依据分数乘法意义，求出增加后的重量，并把此看作单位‘1‘，再减少 \\frac{1}{10}就是后来重量的1- \\frac{1}{10}= \\frac{9}{10}，依据分数乘法意义，求出再减少后的重量，最后与10千克比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/537.json b/MathToF/537.json
new file mode 100644
index 0000000000000000000000000000000000000000..e9c1265a3976f069be88614d68885d99be47d97a
--- /dev/null
+++ b/MathToF/537.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5个5相加是多少，算式是5+5=10"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求5个5相加是多少，用5×5，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/538.json b/MathToF/538.json
new file mode 100644
index 0000000000000000000000000000000000000000..a93cb1af8ac363961e823c4e08cf29516b61faf1
--- /dev/null
+++ b/MathToF/538.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "假分数一定比真分数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分子大于或等于分母的分数为假分数，因此所有的假分数≥1;分子小于分母的分数为真分数，因此所有的真分数<1;由此可知，假分数一定大于真分数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/539.json b/MathToF/539.json
new file mode 100644
index 0000000000000000000000000000000000000000..3e2289e4538c2d8be70c914168572108ea40551e
--- /dev/null
+++ b/MathToF/539.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{1}{a}< \\frac{3}{a}(a≠0)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据同分母分数大小比较方法:分母相同，分子大的分数就大即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/54.json b/MathToF/54.json
new file mode 100644
index 0000000000000000000000000000000000000000..ddc2281c1c03fad2836b3bc49074d9183692aa36
--- /dev/null
+++ b/MathToF/54.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把4个边长是5厘米的正方形拼成一个长方形，它的面积是20平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "4个边长5厘米的正方形拼成一个长方形，无论怎么样拼组，面积不变;长方形的面积是就是4个正方形的面积和，由此求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/540.json b/MathToF/540.json
new file mode 100644
index 0000000000000000000000000000000000000000..5333da86211aa4afad10d98178cd34dc3ca4b670
--- /dev/null
+++ b/MathToF/540.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数相加，和一定是偶数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据偶数与奇数的性质:奇数+奇数=偶数，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/541.json b/MathToF/541.json
new file mode 100644
index 0000000000000000000000000000000000000000..726e90342e94cd5ce9e9f3136162103e89a4e140
--- /dev/null
+++ b/MathToF/541.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为1.2÷0.6=2，所以1.2是0.6的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义，因数和倍数是在非0自然数范围内进行研究，以此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/542.json b/MathToF/542.json
new file mode 100644
index 0000000000000000000000000000000000000000..9cabe633a1c284410d55de6763d67df89b8ae228
--- /dev/null
+++ b/MathToF/542.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在同一个圆中，圆心角的度数越大，扇形面积就越大."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在同一个圆中，扇形的大小与这个扇形的圆心角大小有关，圆心角越大扇形越大，反之亦然;  所以原题说法是正确的.  正确.  在同一个圆里，1°的圆心角的扇形面积占圆面积的  ，90°的圆心角的扇形面积占圆面积的  ，因此同一圆内圆心角的大小决定扇形的大小;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/543.json b/MathToF/543.json
new file mode 100644
index 0000000000000000000000000000000000000000..730aac0e416e5a4caf3ac34d5bab80c463bcbf52
--- /dev/null
+++ b/MathToF/543.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果 \\frac{9}{x}=y(x不为0)，那么x和y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "判断x与y是否成正比例，就看这两种量是否是对应的比值一定，如果是比值一定，就成正比例，如果不是比值一定或比值不一定，就不成正比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/544.json b/MathToF/544.json
new file mode 100644
index 0000000000000000000000000000000000000000..e0f3a7221b1a787db02688280d084dac7bc88e83
--- /dev/null
+++ b/MathToF/544.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "每个圣诞礼盒要装饰用1.2米的丝带，15米长的丝带可以装饰13个这样的礼盒"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "每个礼盒要用1.2米的丝带，根据除法的意义可知15米长的丝带可以装饰15÷1.2个这样的礼盒，求得结果再与13比较得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/545.json b/MathToF/545.json
new file mode 100644
index 0000000000000000000000000000000000000000..94a0209b70d1b31dc56c19e620d97d9c1c4030ff
--- /dev/null
+++ b/MathToF/545.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "真分数都小于1，假分数都大于1."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据真分数及假分数的意义可知，真分数都小于1，假分数大于或等于1，  所以，原题的说法是错误的.  错误.  分子小于分母的分数叫真分数，真分数小于1;分子大于或等于分母的分数为假分数，假分数大于或等于1;据此判断.本题主要考查了真分数及假分数的意义."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/546.json b/MathToF/546.json
new file mode 100644
index 0000000000000000000000000000000000000000..b880ebc5e2bcbbed81cb50b9ec22824623b2c50a
--- /dev/null
+++ b/MathToF/546.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{5}{7}× \\frac{3}{4}表示求 \\frac{5}{7}的 \\frac{3}{4}是多少"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据一个数乘以分数的分数乘法意义可知， \\frac{5}{7}× \\frac{3}{4}表示求 \\frac{5}{7}的 \\frac{3}{4}是多少."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/547.json b/MathToF/547.json
new file mode 100644
index 0000000000000000000000000000000000000000..73804385ff3807d4382aad38823592a9122ee01f
--- /dev/null
+++ b/MathToF/547.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个非零自然数的积，不一定是这两个数的最小公倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "例如6和9这两个非0的自然数，它们的积是6×9=54，54是它们的公倍数，是6的9倍，是9的6倍，但不是它们的最小公倍数，它们的最小公倍数是18;即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/548.json b/MathToF/548.json
new file mode 100644
index 0000000000000000000000000000000000000000..0a5018c96c9c401de99f903e36e5e918b02bf9c9
--- /dev/null
+++ b/MathToF/548.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "每相邻两个面积单位之间的进率是100，两个体积单位之间进率是1000"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "每相邻两个常用的面积单位之间的进率是100;每相邻两个常用的体积单位之间进率是1000.据此判断得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/549.json b/MathToF/549.json
new file mode 100644
index 0000000000000000000000000000000000000000..e844d16ed73ba7b0a69e537b19132f041b234261
--- /dev/null
+++ b/MathToF/549.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任何数除以1都还得任何数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在除法算式里，任何数和1相除都得原数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/55.json b/MathToF/55.json
new file mode 100644
index 0000000000000000000000000000000000000000..b0bab8fcb1474c6573463cd78b5cee8a5e514129
--- /dev/null
+++ b/MathToF/55.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "妈妈准备中饭，择菜用8分钟，洗菜用4分钟，切菜用3分钟，炒菜用5分钟，淘米用2分钟，电饭堡煮饭用20分钟，妈妈做好中饭最快要用42分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "择菜用8分钟，洗菜用4分钟，切菜用3分钟，炒菜用5分钟，完成这些工作一共需要8+4+3+5=20分钟，而电饭堡煮饭用20分钟，所以可以在电饭堡煮饭的20分钟内同时完成择菜、洗菜、切菜和炒菜，这样就可以节省20分钟，所以妈妈做好中饭最快要用2+20=22分钟，由此即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/550.json b/MathToF/550.json
new file mode 100644
index 0000000000000000000000000000000000000000..dbd23a9d4b88dd3a520d2048ad6d20c55cb46cd2
--- /dev/null
+++ b/MathToF/550.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "325-147+153=325-(147+153)"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据计算顺序分别计算出两边的计算结果，再比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/551.json b/MathToF/551.json
new file mode 100644
index 0000000000000000000000000000000000000000..b1cbf6dced9277afcda4ab133dee2f5029befb9d
--- /dev/null
+++ b/MathToF/551.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数乘分数计算公式用字母表示: \\frac{A}{B}× \\frac{D}{C}= \\frac{A×D}{B×C}(B×C不为0)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数乘法的计算法则，两个分数相乘，其积的分子是这两个分数的分子之积，积的分母是这两个分数的分母之积."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/552.json b/MathToF/552.json
new file mode 100644
index 0000000000000000000000000000000000000000..29e97a1cc025e8ae9df8ee329d0848ed963d0a12
--- /dev/null
+++ b/MathToF/552.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3个50连加的和是多少?算式是3+50"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要求3个50连加的和是多少，用50×3，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/553.json b/MathToF/553.json
new file mode 100644
index 0000000000000000000000000000000000000000..8a63af6916c0e35f0b4a5e7fffe1a60c3a7efd9f
--- /dev/null
+++ b/MathToF/553.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "明明做数学题时，做对15题，做错3题，错题占总题量的 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先用‘15+3‘求出数学题的总数量，然后根据求一个数是另一个数的几分之几，用除法解答，进而判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/554.json b/MathToF/554.json
new file mode 100644
index 0000000000000000000000000000000000000000..94dfc4b15048bd2e12326ef84d2ba793aa5d1b94
--- /dev/null
+++ b/MathToF/554.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一条路甲队修了 \\frac{3}{10}千米，也就是30%千米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数即可表示一个分率，也可以表示一个具体数量，即后面可以加单位(表示具体数量)，也可以不加单位(表示一个分率)，而百分数是表示一个分率，即不能在后面加单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/555.json b/MathToF/555.json
new file mode 100644
index 0000000000000000000000000000000000000000..853249459445cc72cc235872d1736f15a5eee448
--- /dev/null
+++ b/MathToF/555.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.3米= \\frac{3}{10}米=30%米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "百分数是‘表示一个数是另一个数的百分之几的数.‘它只能表示两数之间的倍数关系，不能表示某一具体数量，所以， \\frac{3}{10}米就是30%米的表示方法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/556.json b/MathToF/556.json
new file mode 100644
index 0000000000000000000000000000000000000000..959f9ebf3d3ea83f4865636ca2a39af11c40898a
--- /dev/null
+++ b/MathToF/556.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "18是由8个十和1个一组成的。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "18是由1个十和8个一组成的，原题说法错误。   18里面有1个十，8个一，即可判断。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/557.json b/MathToF/557.json
new file mode 100644
index 0000000000000000000000000000000000000000..e7c1089c36526ea4de6feb5da0c7f9f75003fd27
--- /dev/null
+++ b/MathToF/557.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "54+35+46=100+35"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分别计算出左右两边的算式的结果，再比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/558.json b/MathToF/558.json
new file mode 100644
index 0000000000000000000000000000000000000000..c84f2f9c9e511986dba45b9decbc44346852d1e7
--- /dev/null
+++ b/MathToF/558.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一头牛重500千克，2头这样的牛重1吨"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一头牛重500千克，2头这样的牛重就是2个500千克，500×2=1000千克，1000千克=1吨."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/559.json b/MathToF/559.json
new file mode 100644
index 0000000000000000000000000000000000000000..44994673177e2929dc3e525287d9f95cbe5e3d9c
--- /dev/null
+++ b/MathToF/559.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲数的 \\frac{2}{3}等于乙数，这句话用数量关系式表示是乙数× \\frac{2}{3}=甲数_"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的意义，此题是把甲数当做单位‘1‘，即把甲数平均分成3份，其中的两份等于乙数，所以关系式为:甲数× \\frac{2}{3}=乙数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/56.json b/MathToF/56.json
new file mode 100644
index 0000000000000000000000000000000000000000..77cf0a54363340b677876b216a8a6c5931867b09
--- /dev/null
+++ b/MathToF/56.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三位数减三位数，差可能是一位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据减法的运算方法，三位数减三位数，差可能是一位数，举例说明即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/560.json b/MathToF/560.json
new file mode 100644
index 0000000000000000000000000000000000000000..67574d07152c280300ad5b01e722c2540526164a
--- /dev/null
+++ b/MathToF/560.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "700的5倍与70的50倍相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据乘法的意义可知，700的5倍是700×5=3500，70的50倍是70×50=3500，即700的5倍与70的50倍相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/561.json b/MathToF/561.json
new file mode 100644
index 0000000000000000000000000000000000000000..e69f3a1c6b0d0c9d3d648168b1c4613b830c4a91
--- /dev/null
+++ b/MathToF/561.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "位数少的自然数比位数多的自然数小"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整数大小的比较方法，位数不同，位数多的数就大;位数相同，左起第一位上的数大的那个数就大;如果左起第一位上的数相同，就比较左起第二位上的数，直到比较出大小为止.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/562.json b/MathToF/562.json
new file mode 100644
index 0000000000000000000000000000000000000000..3c0bd5fb06bbb12a5d5f1f5d5ca72f5705769ac5
--- /dev/null
+++ b/MathToF/562.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，一个因数不变，另一个因数乘n(n不为0)，积也乘n"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "积的变化规律:一个因数扩大或缩小几倍(0除外)，另一个因数不变，积就扩大或缩小相同的倍数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/563.json b/MathToF/563.json
new file mode 100644
index 0000000000000000000000000000000000000000..2f67ce2c2927ee4aba7f6d9df9f8fe354f253611
--- /dev/null
+++ b/MathToF/563.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个分数大小相等，那么它们的分数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个分数的分数单位看分母，分母是几，分数单位就是几分之一.分数相同，分母不一定相同."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/564.json b/MathToF/564.json
new file mode 100644
index 0000000000000000000000000000000000000000..432e5c4b8ae400ae9895f622234a4df8c6d9539d
--- /dev/null
+++ b/MathToF/564.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数的积一定是奇数，两个偶数的积一定是偶数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据数的奇偶性可知，两个奇数的积一定是奇数，两个偶数的积一定是偶数.  两个偶可表示为2米、2n，则两个数的积是2米×2n=4米n，4米n一定是偶数;  两个奇数可表示为:2n+1.2米+1，两个数的积为:(2n+1)×(2米+1)=4米n+2米+2n+1，仍为奇数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/565.json b/MathToF/565.json
new file mode 100644
index 0000000000000000000000000000000000000000..1b2bea0648546811b297801060afd83bf810e555
--- /dev/null
+++ b/MathToF/565.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "同一个铁丝围成的正方形的面积比长方形的面积大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "设铁丝的长度为20厘米，长方形的长和宽分别为6厘米和4厘米，则正方形的边长为5厘米，利用长方形的面积公式分别求其面积，即可比较面积的大小."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/566.json b/MathToF/566.json
new file mode 100644
index 0000000000000000000000000000000000000000..3b361d9e77eb609a81b08384228db85361f19fe4
--- /dev/null
+++ b/MathToF/566.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "学校的游泳池长35米，明明游了4个来回，他一共游了140米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "游泳池长35米，游4个来回，就是游了8个单程，35*8=280米，原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/567.json b/MathToF/567.json
new file mode 100644
index 0000000000000000000000000000000000000000..c31c62239b4a855e93ac1c0e99175fe7a65f365d
--- /dev/null
+++ b/MathToF/567.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一辆自行车重3吨"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据情景根据生活经验，对质量单位和数据大小的认识，可知计量一辆自行车重用‘千克‘做单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/568.json b/MathToF/568.json
new file mode 100644
index 0000000000000000000000000000000000000000..25af10ffd46e11114867106c71e99ac1e87f080a
--- /dev/null
+++ b/MathToF/568.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "55×40与550×4的计算结果相同。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "55*40=2200，550*4=2200，计算结果相同，原说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/569.json b/MathToF/569.json
new file mode 100644
index 0000000000000000000000000000000000000000..5a7ad04f52476fc2c2f8d70fb124e01d70680369
--- /dev/null
+++ b/MathToF/569.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相除，商一定小于1."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在商非零的除法里，被除数大于除数，商等于1，  被除数小于除数，商小于1，  被除数等于除数，商等于1，  所以两个小数相除，商一定小于1的说法错误;  错误.  根据在商非零的除法里，被除数大于除数，商大于1，被除数小于除数，商小于1，被除数等于除数，商等于1，据此解答.此题考查在商非零的除法里，根据被除数、除数的大小与商的关系."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/57.json b/MathToF/57.json
new file mode 100644
index 0000000000000000000000000000000000000000..83c54fabf868d84e1529d00285903380299ddb02
--- /dev/null
+++ b/MathToF/57.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "不但可以表示出数量的多少，而且能够清楚地表示出数量增减变化的情况，这样的统计图是折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/570.json b/MathToF/570.json
new file mode 100644
index 0000000000000000000000000000000000000000..fa7cafa4bbdead040387769b2b43cd8550df013c
--- /dev/null
+++ b/MathToF/570.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一组数据有6个30、5个31、1个33、2个34，这组数据的平均数是:(30+31+33+34)÷4=32"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先求出一组数据的和，再根据平均数的含义及求平均数的方法除以数据个数6+5+1+2=14，依此即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/571.json b/MathToF/571.json
new file mode 100644
index 0000000000000000000000000000000000000000..6bd9d8a41a13fbea025cf8a8a31ff10223c54498
--- /dev/null
+++ b/MathToF/571.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三角形的面积是与它等底等高的平行四边形面积的一半"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据三角形的面积=底×高÷2，平行四边形的面积=底×高，因为它们等底等高，所以三角形的面积等于和它等底等高的平行四边形面积的一半，由此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/572.json b/MathToF/572.json
new file mode 100644
index 0000000000000000000000000000000000000000..a53b193943a9150f971aa81e37a3c76420c39572
--- /dev/null
+++ b/MathToF/572.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个圆锥形物体放在桌面上，底面朝下，从不同的方位观察，看到的图形都是一样的"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个圆锥形物体放在桌面上，底面朝下，从前、后、左、右看到的形状是三角形;从上面看到的性质是圆形;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/573.json b/MathToF/573.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c36b7ea9c2503aca55c84982008f75b8da209df
--- /dev/null
+++ b/MathToF/573.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "期末考试我们班一定考第一"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据事件的确定性和不确定性进行分析:期末考试我们班可能考第一，属于不确定事件中的可能事件，可能发生，也可能不发生的事件;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/574.json b/MathToF/574.json
new file mode 100644
index 0000000000000000000000000000000000000000..d219d9ca78a2fef7d47bff1f2132ab12568cd243
--- /dev/null
+++ b/MathToF/574.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{4}吨表示1吨的 \\frac{3}{4}，也表示3吨的 \\frac{1}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "\\frac{3}{4}吨表示把1吨平均分成了4份，取其中的3份，所以是1吨的 \\frac{3}{4}，即:1× \\frac{3}{4}= \\frac{3}{4}(吨);也可以表示把3吨平均分成4份，取其中的1份，所以是3吨的 \\frac{1}{4}，即:3× \\frac{1}{4}= \\frac{3}{4}(吨)."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/575.json b/MathToF/575.json
new file mode 100644
index 0000000000000000000000000000000000000000..58880dd131ba781578993135b57925080204f9bb
--- /dev/null
+++ b/MathToF/575.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为5a=6b(a，b不为0)，所以a:b=6:5"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据比例的性质，把所给的等式5a=6b(a和b都不等于0)，改写成一个外项是a，一个内项是b的比例，则和a相乘的数5就作为比例的另一个外项，和b相乘的数6就作为比例的另一个内项，据此写出比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/576.json b/MathToF/576.json
new file mode 100644
index 0000000000000000000000000000000000000000..6bc364964e4c8842acc14fe389bd6f5b998e86be
--- /dev/null
+++ b/MathToF/576.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "2.4和2.40相等，但它们的计数单位却不相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "2.4和2.40在大小上相等，但2.4的计数单位是0.1，表示24个十分之一;而2.40的计数单位是0.01，表示240个百分之一;由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/577.json b/MathToF/577.json
new file mode 100644
index 0000000000000000000000000000000000000000..ff5aa5a6c572de4b7c7af362c01e7c6b6ae17bd7
--- /dev/null
+++ b/MathToF/577.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "9加1大于8加2。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数加法的计算方法分别计算出9加1和8加2的结果，然后再进行比较即可判断。 9+1=10 8+2=10 10=10 所以9加1等于8加2，原题说法错误;"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/578.json b/MathToF/578.json
new file mode 100644
index 0000000000000000000000000000000000000000..652de6913ea52113cde8e01576cecad93f7e9ed7
--- /dev/null
+++ b/MathToF/578.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "北偏东30°，也可以说成东偏北30°"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为东和北之间的夹角是90°，所以90°-30°=60°，即北偏东30°，也可以说成东偏北60°，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/579.json b/MathToF/579.json
new file mode 100644
index 0000000000000000000000000000000000000000..d887d28a94bfb3f7f92c27ce606bd717f9202fa1
--- /dev/null
+++ b/MathToF/579.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "互质的两个数一定都是质数."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据互质数的意义，互质的两个数不一定都是质数，1和任何非0自然数是互质数，1既不是质数也不是合数; 因此互质的两个数一定都是质数，此说法是错误的.  错误.  根据互质数的意义，公因只有1的两个数叫做互质数.1和任何非0自然数是互质数，1既不是质数也不是合数;由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/58.json b/MathToF/58.json
new file mode 100644
index 0000000000000000000000000000000000000000..a4c206f7ea2220640d4bd35a41a5fb113e8ed3c1
--- /dev/null
+++ b/MathToF/58.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "等边三角形一定是锐角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "等边三角形，三个角均为60度，都是锐角，所以等边三角形一定是锐角三角形"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/580.json b/MathToF/580.json
new file mode 100644
index 0000000000000000000000000000000000000000..e404c197c2044ff08bac9dc4d778edf4de2f5f30
--- /dev/null
+++ b/MathToF/580.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "9时15分就是9时1刻"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1刻是15分，9时15分就是9时1刻."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/581.json b/MathToF/581.json
new file mode 100644
index 0000000000000000000000000000000000000000..d49321fbae5394ed57b749a868d71396b60d639a
--- /dev/null
+++ b/MathToF/581.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数的积不一定大于这两个数的和。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "比如1*2=2，1+2=3，2<3，所以两个数的积不一定大于这两个数的和。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/582.json b/MathToF/582.json
new file mode 100644
index 0000000000000000000000000000000000000000..d3101a95f33244c1781b1283adc17d573cda6712
--- /dev/null
+++ b/MathToF/582.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\( a^{2} \\)和2a表示的意义相同，结果也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据平方的定义，乘法的定义即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/583.json b/MathToF/583.json
new file mode 100644
index 0000000000000000000000000000000000000000..e8ec99893bfb8f551c452eb60b590e116c380dc0
--- /dev/null
+++ b/MathToF/583.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个两位数乘10，积就是在这两位数的末尾添一个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，假设这个数是12或30，分别乘上10，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/584.json b/MathToF/584.json
new file mode 100644
index 0000000000000000000000000000000000000000..d339ae0f740feca2f2b1e5b272f8b1370c908cee
--- /dev/null
+++ b/MathToF/584.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为\\( a^{2} \\)表示a×a，2a表示a+a，所以\\( a^{2} \\)一定大于2a"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "为\\( a^{2} \\)=a×a，2a=a+a，当a=2时，\\( a^{2} \\)=\\( 2^{2} \\)=4，2a=2×2=4，此时\\( a^{2} \\)=2a;当a=1时，\\( 1^{2} \\)=1，2×1=2，所以\\( a^{2} \\)小于2a;所以本题的说法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/585.json b/MathToF/585.json
new file mode 100644
index 0000000000000000000000000000000000000000..7bc94bb9216835efd87fcb8185a306de316ff14e
--- /dev/null
+++ b/MathToF/585.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "50里面最多有7个7"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "要求50里面最多有几个7，用50除以7，求得的整数商即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/586.json b/MathToF/586.json
new file mode 100644
index 0000000000000000000000000000000000000000..197873f1bb4f3a79a865694eace7664ed86c3cea
--- /dev/null
+++ b/MathToF/586.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果2a=7b(a不为0)，那么a:b=2:7"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比例的基本性质，把等式2a=7b改写成比例的形式，a:b=7:2，进而判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/587.json b/MathToF/587.json
new file mode 100644
index 0000000000000000000000000000000000000000..5ece7f556593f5cfa423d9168ef2c8a3fe0eca2c
--- /dev/null
+++ b/MathToF/587.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一份稿件5300个字，小红平均每分钟打115个字，她45分钟能把这份稿件打完"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据工作量=工作效率×工作时间，用王平平均每分钟能打的个数乘以45，求出她45分钟能打多少个字;然后把它和5300比较大小，判断出她45分钟能不能把这份稿件打完即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/588.json b/MathToF/588.json
new file mode 100644
index 0000000000000000000000000000000000000000..87321367b060ea6eec3c09187ec93b4a30613aa5
--- /dev/null
+++ b/MathToF/588.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "2.60和2.6大小相等，计数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数的基本性质可知，2.6=2.60，根据小数的意义可知:2.6的计数单位是0.1，2.60的计数单位是0.01，据此分析判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/589.json b/MathToF/589.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c0a7fb77152c651171c533008798c743e9129d9
--- /dev/null
+++ b/MathToF/589.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个长方形长60分米，宽5米，它的面积是300平方米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先把60分米化成6米，再根据长方形的面积=长×宽，求出这个长方形的面积，再与300平方米做比较."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/59.json b/MathToF/59.json
new file mode 100644
index 0000000000000000000000000000000000000000..48a843c0d891bbdc48f743757e83eb2044d608f1
--- /dev/null
+++ b/MathToF/59.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "从13写到20一共有7个数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "从13写到20一共有8个数，原题错误。从13写到20:13、14、15、16、17、18、19、20，一共8个数，即可判断。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/590.json b/MathToF/590.json
new file mode 100644
index 0000000000000000000000000000000000000000..6b44ac84a17a85e7f3bc08ad40e6dc6b2952dcb8
--- /dev/null
+++ b/MathToF/590.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{35}{14}、 \\frac{3}{25}、 \\frac{9}{15}、 \\frac{21}{20}、 \\frac{10}{75}、 \\frac{11}{9}中，最简分数有4个"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据最简分数的意义，分数的分子和分母只有公因数1的分数叫做最简分数.据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/591.json b/MathToF/591.json
new file mode 100644
index 0000000000000000000000000000000000000000..ac0cfcca7a592a99b3718c370a6833dad7762396
--- /dev/null
+++ b/MathToF/591.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "做一套儿童衣服用布1.9米，12.1米布可以做7套这样的衣服"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用布的总长度12.1米除以每套衣服用的长度1.9米，所得的商就是最多可以做的套数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/592.json b/MathToF/592.json
new file mode 100644
index 0000000000000000000000000000000000000000..474a33c5122b1e7c1ced4db9c6006770a7d0c2cc
--- /dev/null
+++ b/MathToF/592.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "大于4.65小于4.68的小数只有4.66和4.67两个。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "大于4.65小于4.68的小数有无数个，所以原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/593.json b/MathToF/593.json
new file mode 100644
index 0000000000000000000000000000000000000000..837a881d007c0d89c7f16efd543578253c9a7cf8
--- /dev/null
+++ b/MathToF/593.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一种盐水，盐占盐水的25%，那么盐和盐水重量的比是1:25"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据‘盐占盐水的25%‘得出盐占25份，盐水就要100份，那么盐和盐水重量的比就是25:100=1:4;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/594.json b/MathToF/594.json
new file mode 100644
index 0000000000000000000000000000000000000000..ace9f7f21a5eb863c33998bb10e2f21ce200a587
--- /dev/null
+++ b/MathToF/594.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个长方形的面积相等，它们的周长也相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方形的周长公式:长方形的周长=(长+宽)×2，如果这两个长方形的长与宽的和相等，那么它们的周长就相等;根据长方形的面积公式:长方形的面积=长×宽，两个长方形的面积相等，说明这两个长方形的长和宽的乘积相等;长和宽的乘积相等，和不一定相等，也就是说两个长方形的面积相等，它们的周长不一定相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/595.json b/MathToF/595.json
new file mode 100644
index 0000000000000000000000000000000000000000..94c7a4837c16ba138b9e381eab7e3d7a9d5bc328
--- /dev/null
+++ b/MathToF/595.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{5}÷( \\frac{1}{9}+ \\frac{25}{3})= \\frac{3}{5}÷ \\frac{1}{9}+ \\frac{3}{5}÷ \\frac{25}{3}= \\frac{3}{5}×9+ \\frac{3}{5}× \\frac{3}{25}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "算式 \\frac{3}{5}÷( \\frac{1}{9}+ \\frac{25}{3})，应先算括号内的，再算括号外的.而原题错用了除法的运算性质，除法的性质应为(a+b)÷c=a÷c+b÷c."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/596.json b/MathToF/596.json
new file mode 100644
index 0000000000000000000000000000000000000000..65fa7fb1df25b2fb74e0a0b95947c22a9a95fc8a
--- /dev/null
+++ b/MathToF/596.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "a、b都不为0，如果a× \\frac{4}{9}=b÷ \\frac{1}{3}，那么a<b"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把等式a× \\frac{4}{9}=b÷ \\frac{1}{3}写成a× \\frac{4}{9}=b÷ \\frac{1}{3}=1，分别求出a、b的值.再进行比较大小."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/597.json b/MathToF/597.json
new file mode 100644
index 0000000000000000000000000000000000000000..b6e24a6d1e2da46852ff77c7f7af30e8951257bd
--- /dev/null
+++ b/MathToF/597.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "读一首古诗《出塞》少于1分钟，做一遍广播体操少于1分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:根据情景根据生活经验，对时间单位和数据大小的认识，可知读一首古诗《出塞》少于1分钟，做一遍广播体操多于1分钟. 解:读一首古诗《出塞》少于1分钟，做一遍广播体操多于1分钟; 故答案为:×."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/598.json b/MathToF/598.json
new file mode 100644
index 0000000000000000000000000000000000000000..ce2e519a7b108d5dc8f3c9b46d60afdb2e7d312a
--- /dev/null
+++ b/MathToF/598.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{8}{16}和 \\frac{1}{2}的大小相等，分数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "\\frac{8}{16}的分子和分母成倍数关系，它们的最大公因数是8，约分后为 \\frac{1}{2}，所以它们大小相等;要求一个分数的分数单位是多少，关键看分母，分母是几，分数单位就是几分之一，则 \\frac{8}{16}的分数单位是 \\frac{1}{16}， \\frac{1}{2}的分数单位是 \\frac{1}{2}，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/599.json b/MathToF/599.json
new file mode 100644
index 0000000000000000000000000000000000000000..c9f1f5e457ddf6a366a6c9f7b0ad364f0c5f332a
--- /dev/null
+++ b/MathToF/599.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小王加工一批零件，有100个合格，2个不合格，那么这批零件的合格率是98%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先用‘100+2‘求出产品总个数，进而根据公式:合格率= \\frac{合格的零件数}{零件总个数}×100%，进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/6.json b/MathToF/6.json
new file mode 100644
index 0000000000000000000000000000000000000000..2c182e0aafa4c8e1204ffb1eb88550e054d44668
--- /dev/null
+++ b/MathToF/6.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以15，商是30，余数是8，这个数是150"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求被除数，根据:被除数=商×除数+余数，解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/60.json b/MathToF/60.json
new file mode 100644
index 0000000000000000000000000000000000000000..ba602489874d3759b2e49fc18c0e5e802e4314ec
--- /dev/null
+++ b/MathToF/60.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "加法只能用减法验算，减法只能用加法验算"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据加、减法之间的关系，加法的验算方法有两种，一个加数=和-另一个加数，也可以运用加法交换律验算;减法的验算方法有两种，减数+差=被减数，被减数-差=减数，"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/600.json b/MathToF/600.json
new file mode 100644
index 0000000000000000000000000000000000000000..12acfdae41331deda38013466c2083f82c899d65
--- /dev/null
+++ b/MathToF/600.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "多位数乘一位数，哪位上乘得的积满几十，就向前一位进几"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据多位数乘一位数计算方法:从多位数个位乘起，哪一位上乘得的积满几十，就要向前一位进几即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/601.json b/MathToF/601.json
new file mode 100644
index 0000000000000000000000000000000000000000..1d8ffc134625ddf0adf81a6f373d4ed4ff1cb718
--- /dev/null
+++ b/MathToF/601.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果x:y+3=18，则x与y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/602.json b/MathToF/602.json
new file mode 100644
index 0000000000000000000000000000000000000000..067288fcdb15a866934ccb624e41f1ee5e9dc4de
--- /dev/null
+++ b/MathToF/602.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "12是4的倍数，8是4的倍数，12与8的和也是4的倍数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "12+8=20，20是4的倍数，所以12是4的倍数，8是4的倍数，12与8的和也是4的倍数的说法是正确的; 故答案为:正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/603.json b/MathToF/603.json
new file mode 100644
index 0000000000000000000000000000000000000000..49a31040ebd59e940bf5c039c95b12d316ed2b36
--- /dev/null
+++ b/MathToF/603.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{33}{100}米=33%米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "百分数是‘表示一个数是另一个数百分之几的数.‘它只能表示两数之间的倍数关系，不能表示某一具体数量，所以 \\frac{33}{100}米=33%米的表示方法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/604.json b/MathToF/604.json
new file mode 100644
index 0000000000000000000000000000000000000000..552d0b4d2830d07add7555459a2c3a2c3f46a610
--- /dev/null
+++ b/MathToF/604.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最大的三位数比最小的三位数大998。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最大三位数的是999，最小三位数是100，它们的差是999-100，据此解答即可。 最大三位数的是999，最小三位数是100， 999-100=899 最大的三位数比最小的三位数大899。 原题说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/605.json b/MathToF/605.json
new file mode 100644
index 0000000000000000000000000000000000000000..177ee7690876f803501dd42e46b753f1c5e362a1
--- /dev/null
+++ b/MathToF/605.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.1和0.9之间的小数有7个"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在0.1和0.9之间，没有说明是几位小数，可以是一位小数、两位小数、三位小数…，所以有无数个小数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/606.json b/MathToF/606.json
new file mode 100644
index 0000000000000000000000000000000000000000..b8ac34c87b5cf4306e1b4ff2a5e0bc87f27f3e98
--- /dev/null
+++ b/MathToF/606.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "58×32的积大约是1800"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "乘法的估算，一般要根据‘四舍五入‘法把因数看作是整十、整百、整千…的数来进行计算，然后按表内乘法的计算方法计算，再在乘积的末尾添上相应的0即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/607.json b/MathToF/607.json
new file mode 100644
index 0000000000000000000000000000000000000000..10ba2884af4141fc7bdb7eeed8bc4b701370be2a
--- /dev/null
+++ b/MathToF/607.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1小时30分:45分化简成最简整数比是2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据比的基本性质作答，即比的前项和后项同时乘一个数或除以一个数(0除外)比值不变."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/608.json b/MathToF/608.json
new file mode 100644
index 0000000000000000000000000000000000000000..d266efc6b9b20756372de21c9a2516379d076665
--- /dev/null
+++ b/MathToF/608.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "等式两边都除以同一个不是0的数，所得的结果仍然是等式"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据等式的性质，可知:等式两边同时乘或除以一个相同的数(0除外)，等式仍然成立."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/609.json b/MathToF/609.json
new file mode 100644
index 0000000000000000000000000000000000000000..0f3da25c2cf13794e397ad471f0211691e5704f5
--- /dev/null
+++ b/MathToF/609.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最小的质数与最小合数的倒数的积是8"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最小的质数是2，2的倒数是 \\frac{1}{2}，最小的合数是4，4的倒数是 \\frac{1}{4}，把它们相乘求出得数即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/61.json b/MathToF/61.json
new file mode 100644
index 0000000000000000000000000000000000000000..3b65dc9e000c3ceaa40ab9c87e29e38cce3e8f32
--- /dev/null
+++ b/MathToF/61.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "六(1)班男生人数比女生人数多 \\frac{1}{4}，女生人数比男生人数少25%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把女生人数看作单位‘1‘，男生人数就是1+ \\frac{1}{4}= \\frac{5}{4}，先求出女生比男生少的人数，再除以男生人数即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/610.json b/MathToF/610.json
new file mode 100644
index 0000000000000000000000000000000000000000..9ad81deb2f3499185488f6f56f2643c70121d65a
--- /dev/null
+++ b/MathToF/610.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "相邻长度单位间的进率是10，相邻面积单位间的进率是100，相邻体积单位间的进率是1000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据计量单位之间的进率，可知相邻的两个长度或人民币单位间的进率是10，相邻的两个面积单位间的进率是100，相邻的两个体积或容积或质量单位间的进率是1000，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/611.json b/MathToF/611.json
new file mode 100644
index 0000000000000000000000000000000000000000..9c195edee0bc5c0392961f4bf68adee574e6a591
--- /dev/null
+++ b/MathToF/611.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "周长是16厘米的正方形，它的面积是16平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据正方形的周长公式可得，边长=周长÷4，再利用正方形的面积=边长×边长，计算即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/612.json b/MathToF/612.json
new file mode 100644
index 0000000000000000000000000000000000000000..df329e394d077238437971d9c714f3b37a49a9bd
--- /dev/null
+++ b/MathToF/612.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "605÷ 5商的十位上是0。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "605÷5=121，商的十位上是2，并不是0。故题干说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/613.json b/MathToF/613.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c57a5823ddc83a97b626d4267fd9067e9f3aba9
--- /dev/null
+++ b/MathToF/613.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数单位相同的分数可以直接相加减。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分数单位相同即分母相同，同分母分数是可以直接相加减的。  理解分数单位的概念及分数加减法的方法即可。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/614.json b/MathToF/614.json
new file mode 100644
index 0000000000000000000000000000000000000000..94016de84f5f9b283cb4fa6aaf43a69e982178d2
--- /dev/null
+++ b/MathToF/614.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "六(2)班有男生20人，女生比男生少 \\frac{1}{5}，那么女生有16人"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先根据题意，把六(2)班男生的人数看作单位‘1‘，则女生占男生的 \\frac{4}{5}(1- \\frac{1}{5}= \\frac{4}{5});然后根据分数乘法的意义，用六(2)班男生的人数乘以女生的人数占男生人数的分率，求出女生有多少人即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/615.json b/MathToF/615.json
new file mode 100644
index 0000000000000000000000000000000000000000..fb80a41abe4340494e580e38c8c3da5ea8f99071
--- /dev/null
+++ b/MathToF/615.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "教室的门高约2米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据生活经验，对长度单位和数据的大小认识，可知计量教室的门高用‘米‘做单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/616.json b/MathToF/616.json
new file mode 100644
index 0000000000000000000000000000000000000000..e51fb0ae02a02231b5296bdb5acaaf3ac7cd21b8
--- /dev/null
+++ b/MathToF/616.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母都乘以一个数(0除外)，分数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数的基本性质的内容，直接进行判断得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/617.json b/MathToF/617.json
new file mode 100644
index 0000000000000000000000000000000000000000..09245e37037d9e029629523349c6ec07b7e1523f
--- /dev/null
+++ b/MathToF/617.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "儿童游动物园应该有成人带领成人门票每人5元，儿童门票每人3元。用20元钱购买门票，除1个成人票外，还可以买5张儿童票。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "本题考查有关动物园买票的问题。已知成人门票每人5元，儿童门票每人3元，总钱数20元，买一张5元成人票，还剩下20-5=15元，15里面有5个3，即可以买5张儿童票。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/618.json b/MathToF/618.json
new file mode 100644
index 0000000000000000000000000000000000000000..81efa27de687438436f2aa57e7e944bb080005bb
--- /dev/null
+++ b/MathToF/618.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果用 n表示自然数，那么偶数可以表示为2n"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据偶数和奇数的意义:整数中，是2的倍数的数是偶数，不是2的倍数的数是奇数，所以如果用n表示自然数，那么偶数可以表示为2n;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/619.json b/MathToF/619.json
new file mode 100644
index 0000000000000000000000000000000000000000..116e22bb9ffdc1308e068ea87ccf34a171b931d4
--- /dev/null
+++ b/MathToF/619.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要统计每天的温度变化最好选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/62.json b/MathToF/62.json
new file mode 100644
index 0000000000000000000000000000000000000000..a300f942e8c1bdc3900e13660bb7f181d5b8577a
--- /dev/null
+++ b/MathToF/62.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3个 \\frac{1}{10}米是 \\frac{3}{10}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据分数乘法的意义可知:3个 \\frac{1}{10}米就是3× \\frac{1}{10}= \\frac{3}{10}米，据此即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/620.json b/MathToF/620.json
new file mode 100644
index 0000000000000000000000000000000000000000..458ec988775985619e7ee9cc2afa982412b927f8
--- /dev/null
+++ b/MathToF/620.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "电子计算器上共有1，2，3，…9这9个数字键。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "计算器上有0~9一共10个数字键.据此解答即可。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/621.json b/MathToF/621.json
new file mode 100644
index 0000000000000000000000000000000000000000..b900fd94a50fbe0da28316ecbf677ede3914cbca
--- /dev/null
+++ b/MathToF/621.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0除以任何不为0的数都得0。(※)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "由于0表示没有，根据除法的意义，除以0除以任何不是0的数都得0"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/622.json b/MathToF/622.json
new file mode 100644
index 0000000000000000000000000000000000000000..a29dcdf0b5575f0c0d04f6d3704f39ff77416020
--- /dev/null
+++ b/MathToF/622.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "围成长方体(不含正方体)的6个面最多有4个面完全相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据长方体的特征，6个面都是长方形(特殊情况有两个相对的面是正方形)，相对的面的面积相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/623.json b/MathToF/623.json
new file mode 100644
index 0000000000000000000000000000000000000000..be54c6adf75133725dab51d81111ca4d4c8a2f2e
--- /dev/null
+++ b/MathToF/623.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个西瓜分成5块，小兰吃了3块，她了这个西瓜的 \\frac{3}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的意义为:将单位‘1‘平均分成若干份，表示这样一份或几份的数为分数.把一个西瓜分成5块，由于没有说明是平均分，则小兰吃了3块，她了这个西瓜的 \\frac{3}{5}的说法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/624.json b/MathToF/624.json
new file mode 100644
index 0000000000000000000000000000000000000000..df85bf3c8739ff3ca1954b40fa2596f6645876e9
--- /dev/null
+++ b/MathToF/624.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在100克的水里加入20克的糖，糖是糖水的 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求一个数是另一个数的几分之几是多少用除法计算，用糖的重量除以糖水的重量即可，糖的重量是20克，糖水的重量是100+20=120克，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/625.json b/MathToF/625.json
new file mode 100644
index 0000000000000000000000000000000000000000..330351d18519bdcdf6e75a3e985a672d479aa3a7
--- /dev/null
+++ b/MathToF/625.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "人的影子在西方，太阳应在西方"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据方向的相对性，人的影子在西，则太阳在东方，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/626.json b/MathToF/626.json
new file mode 100644
index 0000000000000000000000000000000000000000..ee4a8a3a12ea0575f2b82980f9883e50a5c4f2c6
--- /dev/null
+++ b/MathToF/626.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8507是由4个千，5个十和7个一组成的"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据每个数位表示的计数单位即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/627.json b/MathToF/627.json
new file mode 100644
index 0000000000000000000000000000000000000000..13f2b60316cec1d67a41a4430390288bc1aae69f
--- /dev/null
+++ b/MathToF/627.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "百位上的1是百分位上的1的10000倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "百位上的1表示1个百，即100，百分位上的1表示1个百分之一，即0.01，用100除以0.01即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/628.json b/MathToF/628.json
new file mode 100644
index 0000000000000000000000000000000000000000..9b98fdc4268ba03e7e61d7ffd89ce66f92d3dc0b
--- /dev/null
+++ b/MathToF/628.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "{5□ 392}<{}59292，□ 里最大能填8。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "如果 □填8则5839259292，因此 □最大只可以填8。故题干描述正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/629.json b/MathToF/629.json
new file mode 100644
index 0000000000000000000000000000000000000000..260541a0f9b37dcc940b3d43790dc654ade21edd
--- /dev/null
+++ b/MathToF/629.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "估算49×493时，可以把493看作400."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:根据求积的近似数的方法，利用‘四舍五入法‘，把因数看作与它接近的整十数、整百数、…;然后进行口算即可. 解:估算49×493时，可以把493看作500， 所以估算49×493时，可以把493看作400说法错误. 故答案为:×. [点评]此题主要考查积的近似数的求法，利用‘四舍五入法‘，把因数看作与它接近的整十数、整百数、…;然后进行口算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/63.json b/MathToF/63.json
new file mode 100644
index 0000000000000000000000000000000000000000..9907fc7db02438d101016413c6ecabee05bed409
--- /dev/null
+++ b/MathToF/63.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "手拧水龙头运动不属于旋转现象"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "旋转就是围绕着一个中心转动，运动方向发生改变;平移就是直直地移动，移动过程中方向不发生改变.据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/630.json b/MathToF/630.json
new file mode 100644
index 0000000000000000000000000000000000000000..f13e81a1b26dab3e5357d83c39899f6ddc3f55ea
--- /dev/null
+++ b/MathToF/630.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个立方体的表面积是54平方厘米，它的棱长是3厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据正方体的表面积公式:s=6\\( a^{2} \\)，首先用表面积除以6求出一个面的面积，进而求出棱长即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/631.json b/MathToF/631.json
new file mode 100644
index 0000000000000000000000000000000000000000..cd6a601516e382b77f2a2fc86722dd67829046cb
--- /dev/null
+++ b/MathToF/631.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "40克水中加入10克糖，糖占糖水的20%"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "含糖率=糖的重量÷糖水的总重量×100%，糖的重量是10克，糖水的重量是(40+10)克.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/632.json b/MathToF/632.json
new file mode 100644
index 0000000000000000000000000000000000000000..745d21e41ba672a1a0dee7e9304484d2a22fd79c
--- /dev/null
+++ b/MathToF/632.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用一个边长3厘米的正方形纸片剪一个最大的圆，这个圆的周长是9.42厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把一张边长为3厘米的正方形纸片剪成一个最大的圆，则圆的直径为3厘米，再根据圆的周长求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/633.json b/MathToF/633.json
new file mode 100644
index 0000000000000000000000000000000000000000..6064996ea03e49c399e9a797a092643accef7ffd
--- /dev/null
+++ b/MathToF/633.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "画圆时，圆规两脚尖之间的距离是直径."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "[分析]圆的基础知识: 1圆心决定圆的位置，半径决定圆的大小 2圆有无数条半径和直径 3在同圆或等圆中，圆的半径都相同 4过圆心且两个端点都在圆上的线段是直径"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/634.json b/MathToF/634.json
new file mode 100644
index 0000000000000000000000000000000000000000..f7333a3c86728f04ef6f9dd90f6f3ff1d0d514ab
--- /dev/null
+++ b/MathToF/634.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.6和0.60的大小相等，计数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数的基本性质可知，0.6=0.60，根据小数的意义可知:0.6的计数单位是0.1，0.60的计数单位是0.01，据此分析判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/635.json b/MathToF/635.json
new file mode 100644
index 0000000000000000000000000000000000000000..e8ec8ebf49dbda9262ec89f7cf3d11d62dc2e196
--- /dev/null
+++ b/MathToF/635.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1除以一个数(0除外)，所得的商就是这个数的倒数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据倒数的定义，两个数的乘积等于1，则这两个数互为倒数，因此要求一个数的倒数，只要用1除以这个数即可，因此本题是正确的，故本题的答案是正确通过审题，根据倒数的定义，两个数的乘积等于1，则这两个数互为倒数，因此要求一个数的倒数，只要用1除以这个数即可，据此即可解答问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/636.json b/MathToF/636.json
new file mode 100644
index 0000000000000000000000000000000000000000..f9ca4344476a2ba7d34dce04ac78e5a747e05585
--- /dev/null
+++ b/MathToF/636.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方形的周长是5厘米，它的面积是25平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据正方形的周长公式可得:正方形的边长=周长÷4，据此再利用正方形的面积=边长×边长即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/637.json b/MathToF/637.json
new file mode 100644
index 0000000000000000000000000000000000000000..c2561b256ac0c6ec95aa40f95e569104e10e7fb4
--- /dev/null
+++ b/MathToF/637.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最小的奇数是1，最小的偶数是2。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最小的奇数是1，最小的偶数是0，故本题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/638.json b/MathToF/638.json
new file mode 100644
index 0000000000000000000000000000000000000000..e1b92a35cee8fd3f367cd221d48410f0319a164a
--- /dev/null
+++ b/MathToF/638.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "99×97+3可以应用乘法结合律写成99×(97+3)，可以使计算简便"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:乘法结合律为:先乘前两个数，或先乘后两个数，积不变.字母表示为a×b×c=a×(b×c);算式99×97+3是一个乘法和加法的混合运算，按照运算顺序，应该先算乘法再算加法，因此不符合乘法结合律的使用条件，不能应用乘法结合律.据此即可判断. 解:由分析可知:99×97+3不符合乘法结合律的使用条件，不能应用乘法结合律简算， 因此99×97+3≠99×(97+3)， 所以题干说法错误. 故答案为:×."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/639.json b/MathToF/639.json
new file mode 100644
index 0000000000000000000000000000000000000000..051839103b30dfa1de3b390461155cf4ee9d366e
--- /dev/null
+++ b/MathToF/639.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "这个平面图形不能折成一个正方体"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据正方体展开图的11种特征，此图不属于正方体展开图，不能折成一个正方体."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/64.json b/MathToF/64.json
new file mode 100644
index 0000000000000000000000000000000000000000..755428cf5752328e4c5aa6ed7a8d0db82cb22441
--- /dev/null
+++ b/MathToF/64.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个一个的数，与100000相邻的两数是90000和110000"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据相邻的两个自然数相差1，进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/640.json b/MathToF/640.json
new file mode 100644
index 0000000000000000000000000000000000000000..a7eed71b5d601c4aeaf74505eadb77cbcb08d9c0
--- /dev/null
+++ b/MathToF/640.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "21÷3商是6，余数是3。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "21÷3=7，所以21可以整除3，没有余数。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/641.json b/MathToF/641.json
new file mode 100644
index 0000000000000000000000000000000000000000..559802b8336af62f9ec81ea66a475bb9434a7980
--- /dev/null
+++ b/MathToF/641.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{5}{4}×0.8=1，所以 \\frac{5}{4}和0.8互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/642.json b/MathToF/642.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c323795c11ab0bc75e5d13da16f5c8058d5bad8
--- /dev/null
+++ b/MathToF/642.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3□268≈3万，用四舍五入法，□中最大可填4"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "3口268≈3万，显然是用‘四舍‘法求出的近似数，所以空格里可以填0、1、2、3、4，最大填4.据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/643.json b/MathToF/643.json
new file mode 100644
index 0000000000000000000000000000000000000000..1dcc7e19a61d5f4e9369eed6a659b64f16c8ca7e
--- /dev/null
+++ b/MathToF/643.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "按规律填数，2、4、8、14、22、，括号里填30"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由所给数列中的数得出:数列中的数依次增加2、4、6、8、10;  据此写数即可判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/644.json b/MathToF/644.json
new file mode 100644
index 0000000000000000000000000000000000000000..03e9f6ea10a5b1722d563b7d31ad8ad033ae054f
--- /dev/null
+++ b/MathToF/644.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "x=0.6是方程9x-3x=4.2的解"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要想知道x=0.6是否是方程9x-3x=4.2的解，把x=0.6代入方程9x-3x=4.2中，进行验证，看看方程左边是否等于右边."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/645.json b/MathToF/645.json
new file mode 100644
index 0000000000000000000000000000000000000000..78209b4fbf11c6aec27ecce6ace0f14781afcd42
--- /dev/null
+++ b/MathToF/645.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为17÷4=4…1，所以170÷40=40…10"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法算式中:被除数=商×除数+余数，进行计算后即可进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/646.json b/MathToF/646.json
new file mode 100644
index 0000000000000000000000000000000000000000..b99dd859b928876ad43e50f62aa5994614ae6946
--- /dev/null
+++ b/MathToF/646.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求8个3相加是多少的算式是8+3。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "8个3相加就是8+8+8，用乘法表示为8×3或3×8，所以题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/647.json b/MathToF/647.json
new file mode 100644
index 0000000000000000000000000000000000000000..d31363650dc1e5a46931df27f2d4c55da3e2062c
--- /dev/null
+++ b/MathToF/647.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "去掉0.52的小数点，所得的数是原来的100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把0.52的小数点去掉，就是把它的小数点向右移动两位，根据小数点的移动与小数大小的变化规律可知小数点向右移动两位，扩大了100倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/648.json b/MathToF/648.json
new file mode 100644
index 0000000000000000000000000000000000000000..0019ed0c6bee072d80f4e0714bc5b27994d3e222
--- /dev/null
+++ b/MathToF/648.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算13.2×5.5+4.5×13.2时，运用乘法分配律计算简便"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "试题分析:根据乘法分配律简便计算. 解:13.2×5.5+4.5×13.2 =13.2×(5.5+4.5) =13.2×10 =132 运用了乘法分配律. 故答案为:√. [点评]考查了运算定律与简便运算，四则混合运算.注意运算顺序和运算法则，灵活运用所学的运算定律简便计算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/649.json b/MathToF/649.json
new file mode 100644
index 0000000000000000000000000000000000000000..5e7e0685c15914f81cd75949e941040d099b7ff4
--- /dev/null
+++ b/MathToF/649.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形和一个平行四边形的底相等，三角形的高是平行四边形高的2倍，这个三角形和平行四边形的面积相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据三角形和平行四边形的面积公式可得:三角形的面积=底×高÷2;平行四边形的面积=底×高，由此即可进行比较，解答问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/65.json b/MathToF/65.json
new file mode 100644
index 0000000000000000000000000000000000000000..d24a87a3fc576301f3ac72053de1114be43750ee
--- /dev/null
+++ b/MathToF/65.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "37减16的差乘12，积是多少?列式是(37-16)×12"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，先算37减16的差，所得的差再乘12，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/650.json b/MathToF/650.json
new file mode 100644
index 0000000000000000000000000000000000000000..19de851446c0285202239fd95e82428e0d2d40d9
--- /dev/null
+++ b/MathToF/650.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "25是23和24之间的数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "25是24后面的整数，所以不是23和24之间的数，原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/651.json b/MathToF/651.json
new file mode 100644
index 0000000000000000000000000000000000000000..b387aac492c816a21f6f820f57097843aa4d5b09
--- /dev/null
+++ b/MathToF/651.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "100-67+33=100-100=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数四则混合运算的方法计算出结果再进行判断即可，100-67+33=33+33=66"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/652.json b/MathToF/652.json
new file mode 100644
index 0000000000000000000000000000000000000000..20d841915b91bfe26d219f4bc7a7395ef80af5a2
--- /dev/null
+++ b/MathToF/652.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要使□51×4的积是三位数，□里最大填2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，把2代入到□51×4可得，251×4=1004，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/653.json b/MathToF/653.json
new file mode 100644
index 0000000000000000000000000000000000000000..10310c31c0da8f8ac921abceda41292bb28d8cd6
--- /dev/null
+++ b/MathToF/653.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算200×4时，可以先算2×4=8，再在得数后面添写两个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "计算200×4时，把200看作2个百，先算2×4=8，也就是得8个百，再在得数后面添写两个0，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/654.json b/MathToF/654.json
new file mode 100644
index 0000000000000000000000000000000000000000..75438815a85011e784922f5551a6ad65859d1ff6
--- /dev/null
+++ b/MathToF/654.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个苹果分成4份，每份占这个苹果的 \\frac{1}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个苹果平均分成4份，求每份占总数的多少，平均分的是单位‘1‘，求的是分率;用除法计算.  但是本题没有‘平均‘两个字，因此说法错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/655.json b/MathToF/655.json
new file mode 100644
index 0000000000000000000000000000000000000000..7da87f50cede59db3b00b919fd008ada9cec52c5
--- /dev/null
+++ b/MathToF/655.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "80乘75的得数的最高位是百位。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "80*75=6000，最高位是千位，原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/656.json b/MathToF/656.json
new file mode 100644
index 0000000000000000000000000000000000000000..0912064d352aabaaa95e94b8842e0d136fe9aac3
--- /dev/null
+++ b/MathToF/656.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "483-(83+17)=483-83+17"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个数减去两个数的和，可以用这个数分别减去这两个数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/657.json b/MathToF/657.json
new file mode 100644
index 0000000000000000000000000000000000000000..daca5ec930d5c0f27b230906748ab7625b63f51c
--- /dev/null
+++ b/MathToF/657.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1的倒数是它本身"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "此题利用倒数的定义:若两个数的乘积是1，我们就称这两个数互为倒数;求一个数(0除外)的倒数，只要把这个数的分子和分母调换位置;即可求出答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/658.json b/MathToF/658.json
new file mode 100644
index 0000000000000000000000000000000000000000..80de738b0465334594bb5212ffd3e14db1b26fce
--- /dev/null
+++ b/MathToF/658.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "人的影子在西方，太阳应该在东方"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "人的影子在西，则太阳在东方，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/659.json b/MathToF/659.json
new file mode 100644
index 0000000000000000000000000000000000000000..93246d1d17ddefb74dea3f6a13ea0d30d21b72dd
--- /dev/null
+++ b/MathToF/659.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在制作扇形统计图时，总的数量越多，所画的圆就越大."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据扇形统计图的特点可知:在制作扇形统计图时，总的数量越多，所画的圆就越大，说法错误;  错误.  扇形统计图是用整个圆表示总数用圆内各个扇形的大小表示各部分数量占总数的百分数.用整个圆的面积表示总数(单位1)，用圆的扇形面积表示各部分占总数的百分数;据此判断即可.此题考查扇形统计图的意义.扇形统计图可以很清楚的表示出各部分数量同总数之间的关系."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/66.json b/MathToF/66.json
new file mode 100644
index 0000000000000000000000000000000000000000..bdab834d5abcc2f44478cdf554c855d1463db298
--- /dev/null
+++ b/MathToF/66.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用2、9、3、0组成的一个最小的四位数是2390"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "用2、9、3、0组成最小的四位数，最高位(千位)为2，百位为0，十位为3，个位为9;进而得出该数为2039."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/660.json b/MathToF/660.json
new file mode 100644
index 0000000000000000000000000000000000000000..132e0f48e5cb87671e26a5ec87277e38eff10240
--- /dev/null
+++ b/MathToF/660.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "与20最接近的两位小数是19.99和20.01"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "两位小数是小数部分有2位的小数，两位小数的计数单位是0.01，所以与20最接近的两位小数是20-0.01=19.99和20+0.01=20.01;由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/661.json b/MathToF/661.json
new file mode 100644
index 0000000000000000000000000000000000000000..46a5757f31a2028b1495d60169e855b44cbc7bfd
--- /dev/null
+++ b/MathToF/661.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个两位数与10相乘，可以直接在这个两位数的后面添加一个0，得到的数就是它们的积"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据整数乘法的计算法则计算即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/662.json b/MathToF/662.json
new file mode 100644
index 0000000000000000000000000000000000000000..a2c161e5ad03091dc5f4f226a4484096167e4069
--- /dev/null
+++ b/MathToF/662.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体的面中可能有正方形，正方体的面中不可能有长方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "长方体的面中可能有正方形，正方体的每个面都是正方形，所以正方体的面中不可能有长方形，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/663.json b/MathToF/663.json
new file mode 100644
index 0000000000000000000000000000000000000000..9fb9a1815187354a698ae360ff66576e3edd0aed
--- /dev/null
+++ b/MathToF/663.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方形和正方形的周长相等，长方形的面积比正方形的面积大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正方形和长方形的周长相等，正方形的面积比长方形的面积大.可以通过举例证明，如它们的周长都是24厘米，长方形的长是8厘米，宽是4厘米;正方形的边长是6厘米;"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/664.json b/MathToF/664.json
new file mode 100644
index 0000000000000000000000000000000000000000..8a0a44d8a207db810fa6f59a4d5d51f5d34ed1f4
--- /dev/null
+++ b/MathToF/664.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数在省略亿位后面的尾数后约是35亿，这个数最大是3499999999。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "(1) 当这个数采用‘五入‘法得到35亿时，这个数的亿位上的数是5-1=4，千万位上的数大于或等于5，最大是9，因此，这个数最大是3499999999。 (2) 当这个数采用‘四舍‘法得到35亿时，这个数的亿位上的数是5，千万位上的数小于5，最大是4，因此，这个数最大是3549999999。 因此，这个数最大为3549999999，所以此题错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/665.json b/MathToF/665.json
new file mode 100644
index 0000000000000000000000000000000000000000..a31c8d663e874b3f0af58857123c9294b15130d8
--- /dev/null
+++ b/MathToF/665.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "口4×口8的积的个位上的数字一定是2."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "口4×口8，个位上4×8=32，所以，所得的积的个位数是2. 解:4×8=32，32的个位上是2;所以口4×口8的积的个位上的数字一定是2. 故答案为:正确."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/666.json b/MathToF/666.json
new file mode 100644
index 0000000000000000000000000000000000000000..f6906e2ee47198ea04900be521dbbe61fba3dc3f
--- /dev/null
+++ b/MathToF/666.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一张长方形的纸对折3次得到的图形是整张纸的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把这张长方形纸对折1次，这张正方形纸被平均分成了2份，每份是这张正方形纸的 \\frac{1}{2};对折2次，被平均分成了4份，每份是这张正方形纸的 \\frac{1}{4};对折3次，被平均分成了8份，每份是这张正方形纸的 \\frac{1}{8}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/667.json b/MathToF/667.json
new file mode 100644
index 0000000000000000000000000000000000000000..530d02c967d62594fc6bf1321ab6eb99a86158a3
--- /dev/null
+++ b/MathToF/667.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.1是1的十分之一，是0.01的10倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "将1分成十等份，根据分数的意义，其中的一份为1的 \\frac{1}{10}，也可用小数表示为0.1，所以0.1是1的十分之一;0.1÷0.01=10，即0.1是0.01的10倍，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/668.json b/MathToF/668.json
new file mode 100644
index 0000000000000000000000000000000000000000..f347e8d62db5b994ab27ebc5f2fbef9a395d8bcd
--- /dev/null
+++ b/MathToF/668.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用棱长1厘米的小正方体摆一个大正方体，至少要8个小正方体"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为用棱长1厘米的小正方体摆成‘稍大一些‘的正方体，所以稍大一些的正方体棱长是>1厘米的整数; 所以稍大一些的正方体棱长是2厘米;继而根据‘正方体的体积=棱\\( 长^{3} \\)‘分别计算出棱长是2厘米和棱长是1厘米的大、小正方体体积，然后用‘大正方体的体积÷小正方体的体积‘即可得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/669.json b/MathToF/669.json
new file mode 100644
index 0000000000000000000000000000000000000000..7988bb7d97eeb4ace0dc495cfb73cf6689b4a868
--- /dev/null
+++ b/MathToF/669.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在0.32的末尾添上一个‘0‘，这个数就扩大到原数的10倍。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            ""
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/67.json b/MathToF/67.json
new file mode 100644
index 0000000000000000000000000000000000000000..472f5115c9bdeae82790d52e574db734d946b7d4
--- /dev/null
+++ b/MathToF/67.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "456-(123+156)=456-156-123"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "利用减法的简便运算，456-(123+156)=456-156-123即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/670.json b/MathToF/670.json
new file mode 100644
index 0000000000000000000000000000000000000000..ca8980c1c4fa6edeb5f23dc32605471bfd80b0f8
--- /dev/null
+++ b/MathToF/670.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "无限小数比有限小数大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析: 点评:这类题目都是不确定的。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/671.json b/MathToF/671.json
new file mode 100644
index 0000000000000000000000000000000000000000..b519c8b7e952932f22b9b521247e366d73f351c9
--- /dev/null
+++ b/MathToF/671.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在一次射击训练中，小明有10发子弹射中目标，有2发子弹没有射中，命中率是80%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "命中率=命中子弹数÷发射子弹数×100%，小明打了10+2发子弹，10发命中，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/672.json b/MathToF/672.json
new file mode 100644
index 0000000000000000000000000000000000000000..1edddc17f8e29ff05ab3bf4040b0237b14e4d2b2
--- /dev/null
+++ b/MathToF/672.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小明和小军比赛跑步，小明用了 \\frac{1}{2}分钟，小军用了 \\frac{1}{5}分钟，小明跑得快"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "小明和小军比赛跑步，说明路程相同，谁用的时间少，谁的速度就快，比较 \\frac{1}{2}分钟与 \\frac{1}{5}分钟时间的大小即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/673.json b/MathToF/673.json
new file mode 100644
index 0000000000000000000000000000000000000000..53db16b2d1529cb1e119018a381fd0898df7472b
--- /dev/null
+++ b/MathToF/673.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "700÷400与70÷40的商和余数相同。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "700÷400=1…300 70÷40=1…30 故题目中说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/674.json b/MathToF/674.json
new file mode 100644
index 0000000000000000000000000000000000000000..166e327bb867aa58bf13c6d563032bdeba426a61
--- /dev/null
+++ b/MathToF/674.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在一副条形统计图里，直条越宽，表示数量越多"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据条形统计图的意义和特点:条形统计图是用一个单位长度表示一定的数量，根据数量的多少画成长短不同的直条，然后把这些直条按照一定的顺序排列起来;即条形统计图是用长短不同、宽窄一致的直条表示数量，所以条形统计图的直条越宽表示的数越大，说法错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/675.json b/MathToF/675.json
new file mode 100644
index 0000000000000000000000000000000000000000..86d1ffd1f56f8f1f32dd48fb4f2d6769b7622c44
--- /dev/null
+++ b/MathToF/675.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{4}{9}× \\frac{3}{4}÷ \\frac{4}{9}× \\frac{3}{4}=1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "按照从左到右顺序，求出算式的值，再与1比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/676.json b/MathToF/676.json
new file mode 100644
index 0000000000000000000000000000000000000000..a50f44a7786871ec2ddd3913ddb5af33d6d135ef
--- /dev/null
+++ b/MathToF/676.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为10÷0.5=20，所以说10能被0.5整除"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "整除是指一个整数除以另一个不是0的整数，得到的商是整数，而没有余数，我们就说第一个整数能被第二个整数整除，第二个整数能整除第一个整数;根据整除的意义，直接进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/677.json b/MathToF/677.json
new file mode 100644
index 0000000000000000000000000000000000000000..9eaec30c05f1a23fffca130a5c2f318265cbaaa3
--- /dev/null
+++ b/MathToF/677.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆周率是一个无限不循环的小数，我们计算时一般近似取3.14"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆周率的含义:圆的周长和它直径的比值叫圆周率，它是一个无限不循环小数，用π表示，π=3.1415926…，我们计算时一般近似取3.14;进而得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/678.json b/MathToF/678.json
new file mode 100644
index 0000000000000000000000000000000000000000..8885db36e2be70d733bfb1410eb3f3c193f3dae5
--- /dev/null
+++ b/MathToF/678.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果甲数、乙数都大于0，而且甲数的 \\frac{1}{3}<乙数的 \\frac{1}{3}，那么乙数一定大于甲数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据两个大于0的数相乘，如果其中一个因数相同，则另一因数大的积就大，反之，积大的另一个因数就大;由此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/679.json b/MathToF/679.json
new file mode 100644
index 0000000000000000000000000000000000000000..da01455cf680a51ea2613023be750560e011ae3c
--- /dev/null
+++ b/MathToF/679.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个加数的十位上是4，另一个加数的十位上是6，和的十位上肯定是0。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据加法的计算方法，当一个加数的十位上是4，另一个加数的十位上是6，和的十位上不一定是0，例如145+267=412，和的十位上是1。该题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/68.json b/MathToF/68.json
new file mode 100644
index 0000000000000000000000000000000000000000..65b7f73bb2ef62e4debaf0cc442d5c7c1145f8de
--- /dev/null
+++ b/MathToF/68.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以4，余数可能是1、2、3、4。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据余数总比除数小，除数是4，余数可以是1、2、3，不能是4，所以题干中说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/680.json b/MathToF/680.json
new file mode 100644
index 0000000000000000000000000000000000000000..d1de730161cbe8eab83577399b27b3a5bfeba3c4
--- /dev/null
+++ b/MathToF/680.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把3筐苹果，平均分给7个教学班，每班分得总数的 \\frac{3}{7}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求每班分得这些苹果的几分之几，就是把这些苹果的总筐数看作单位‘1‘，平均分为7份，求一份是这些苹果的总筐数的几分之几，用1÷7解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/681.json b/MathToF/681.json
new file mode 100644
index 0000000000000000000000000000000000000000..0d84271f0c80e6c587fbcbca54c80febd745dbdd
--- /dev/null
+++ b/MathToF/681.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1除以任何数所得的商就是这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数，1的倒数是1，0没有倒数.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/682.json b/MathToF/682.json
new file mode 100644
index 0000000000000000000000000000000000000000..56461865336bd7067ad26a47d8b33f4c11b669c3
--- /dev/null
+++ b/MathToF/682.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数单位是\\frac{1}{9}的最大真分数是\\frac{8}{9}，最小假分数是\\frac{10}{9}。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数单位是\\frac{1}{9}的最大真分数是\\frac{8}{9}，最小假分数是\\frac{9}{9}。故题干说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/683.json b/MathToF/683.json
new file mode 100644
index 0000000000000000000000000000000000000000..244a796cad3c3def438037b43ef8553853561dc5
--- /dev/null
+++ b/MathToF/683.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "56是由6个十和5个一组成的。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据整数的数位顺序可知，从右边起第一位是个位，个位上的数表示几个一，第二位是十位，十位上的数表示几个十，据此解答。 56是由6个一和5个十组成的，本题说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/684.json b/MathToF/684.json
new file mode 100644
index 0000000000000000000000000000000000000000..2e20bad9f0d0e50f4ffc8033ef7193e9b847be78
--- /dev/null
+++ b/MathToF/684.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个圆柱的侧面积相等，它们的底面周长也一定相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            ":两个圆柱的侧面积相等，但高不一定相等，所以底面周长也不一定相等。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/685.json b/MathToF/685.json
new file mode 100644
index 0000000000000000000000000000000000000000..49e0f216505bf99def029e09083909f46021b7b8
--- /dev/null
+++ b/MathToF/685.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "乙数相当于甲数的，单位‘1‘的量是乙数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:乙数相当于甲数的，是把甲数看作单位‘1‘，把甲数平均分成6份，甲数是6份，乙数是其中的5份，乙数相当于甲数的. 解:乙数相当于甲数的，是把甲数看作单位‘1‘; 所以乙数相当于甲数的，单位‘1‘的量是乙数说法错误. 故答案为:×."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/686.json b/MathToF/686.json
new file mode 100644
index 0000000000000000000000000000000000000000..8b15aa5d021b37d87be7f9a3781e113ab97e3709
--- /dev/null
+++ b/MathToF/686.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "原来有12个萝卜，小兔吃了7个萝卜，还剩6个萝卜。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意可知，用萝卜原来的个数-小兔吃了的个数=剩下的个数，据此列式解答。 12-7=5(个)，还剩5个萝卜，原题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/687.json b/MathToF/687.json
new file mode 100644
index 0000000000000000000000000000000000000000..195d3c57ae08222845c23317c966ad8a5a3e04ab
--- /dev/null
+++ b/MathToF/687.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一组数据中，最中间的那个数就是该组数据的中位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "中位数:将数据按照从小到大或从大到小的顺序排列，如果数据个数是奇数，则处于最中间位置的数就是这组数据的中位数;如果数据个数是偶数，则中间两个数据的平均数是这组数据的中位数;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/688.json b/MathToF/688.json
new file mode 100644
index 0000000000000000000000000000000000000000..fbc06a044e5f687f20e29b9728ed45e3285af73f
--- /dev/null
+++ b/MathToF/688.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "除以一个不为零的数，等于乘以这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分数除法的计算法则是:甲数除以乙数(0除外)，等于甲数乘乙数的倒数，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/689.json b/MathToF/689.json
new file mode 100644
index 0000000000000000000000000000000000000000..a51fdd3e161426af9ac5f00e802dd1af15d36230
--- /dev/null
+++ b/MathToF/689.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "65×23与42×35的积，末尾都是0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "直接求出两个因数的末位数字的积，依此即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/69.json b/MathToF/69.json
new file mode 100644
index 0000000000000000000000000000000000000000..69089851bad2a17fb89854f6a4554cd2f1455a70
--- /dev/null
+++ b/MathToF/69.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "18×0=18÷0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先根据整数乘除法运算的计算法则和整数除法有意义的条件求出两个算式的结果，依此即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/690.json b/MathToF/690.json
new file mode 100644
index 0000000000000000000000000000000000000000..f590847cab92ec695922c3d2a34ed475baa3aaf8
--- /dev/null
+++ b/MathToF/690.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "男生人数比女生多 \\frac{1}{5}.也可以说女生人数比男生少 \\frac{1}{6}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "先把女生的人数看成单位‘1‘，那么男生的人数就是1+ \\frac{1}{5}，然后用 \\frac{1}{5}除以男生的人数，就是女生比男生少几分之几."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/691.json b/MathToF/691.json
new file mode 100644
index 0000000000000000000000000000000000000000..a7422e59b35c65ad01a982b530c0b5501df76296
--- /dev/null
+++ b/MathToF/691.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "45除以6，商是7，余数是5"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据:被除数=商×除数+余数，解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/692.json b/MathToF/692.json
new file mode 100644
index 0000000000000000000000000000000000000000..2765b6d4061a13f6c7409508a24250f726640866
--- /dev/null
+++ b/MathToF/692.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "329□810≈330万，□中最小只能填5"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "329□810≈330万，显然是用‘五入‘法求出的近似数，所以□中最小填5.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/693.json b/MathToF/693.json
new file mode 100644
index 0000000000000000000000000000000000000000..9de1c6fa8862876a9e14b01de3d6683b7b856ac5
--- /dev/null
+++ b/MathToF/693.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果游戏规则是公平的，那么无论操作几次，都无法分出输赢"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "理解游戏规则的公平性的含义:游戏规则公平性，是指各方获胜的可能性一样大，如剪子、包袱、锤，还有投硬币，都能分成输赢;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/694.json b/MathToF/694.json
new file mode 100644
index 0000000000000000000000000000000000000000..369611bb3a8dfe0d9270c4dae778fcf975ed0831
--- /dev/null
+++ b/MathToF/694.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "300与0相乘，积仍然是300。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "任何数同0相乘都得0"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/695.json b/MathToF/695.json
new file mode 100644
index 0000000000000000000000000000000000000000..beb3e6618e6cc0f4cf7e32b29629d96ee0c84d45
--- /dev/null
+++ b/MathToF/695.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "做乘法时，哪一位上乘的积满几十，就向前一位进几"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据整数乘法的计算法则进行解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/696.json b/MathToF/696.json
new file mode 100644
index 0000000000000000000000000000000000000000..dc42c3436b2b93495251261c5064ddb5aa35c27c
--- /dev/null
+++ b/MathToF/696.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形的三个内角度数比是1:2:1，这个三角形是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "三角形的内角和为180°，进一步直接利用按比例分配分别求出三种情况下份数最大的角，然后根据三角形的分类进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/697.json b/MathToF/697.json
new file mode 100644
index 0000000000000000000000000000000000000000..28c68ed8f8ef714a0991f338b8f73f92bf6f4606
--- /dev/null
+++ b/MathToF/697.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1.50和1.5的大小相等，计数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "1.5和1.50在大小上相等，但1.5的计数单位是0.1，表示15个十分之一;而1.50的计数单位是0.01，表示150个百分之一;由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/698.json b/MathToF/698.json
new file mode 100644
index 0000000000000000000000000000000000000000..cddd332e34be22857e399aecc1c0f181fb247308
--- /dev/null
+++ b/MathToF/698.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要反映某地区一年内各月份的降水量变化情况，应绘制折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/699.json b/MathToF/699.json
new file mode 100644
index 0000000000000000000000000000000000000000..65e0ce3653d656ce903f5b60b0ce467a0641bb8f
--- /dev/null
+++ b/MathToF/699.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "比10小的一位数有9个。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "比10小的一位数有0、1、2、3、4、5、6、7、8、9一共是10个，所以是错的。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/7.json b/MathToF/7.json
new file mode 100644
index 0000000000000000000000000000000000000000..0af06ba32d68c0d36e819bb5a07e469ef553fee2
--- /dev/null
+++ b/MathToF/7.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{4}{8}= \\frac{1}{2}，所以 \\frac{4}{8}和 \\frac{1}{2}的分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数单位的意义为:将单位‘1‘平均分成若干份，表示其中这样一份的数，为分数单位.则 \\frac{4}{8}的分数单位是 \\frac{1}{8}， \\frac{1}{2}的分数单位是 \\frac{1}{2}，它们的分数单位不同."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/70.json b/MathToF/70.json
new file mode 100644
index 0000000000000000000000000000000000000000..fbacbe69a6b99d6fdc7eea5c1f380138be71d59e
--- /dev/null
+++ b/MathToF/70.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一组数据的平均数、中位数一定只有一个"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1将数据按大小顺序排列起来，把中间数据(或中间两数据的平均数)叫做中位数，  2一组数据的总和除以这组数据个数所得到的商叫这组数据的平均数;可举例说明比较容易理解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/700.json b/MathToF/700.json
new file mode 100644
index 0000000000000000000000000000000000000000..3f553d79d56c24b8ae82c77715fde97fc9ffb5ca
--- /dev/null
+++ b/MathToF/700.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "去掉0.480的小数点后得到的数是原数的1000倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把0.480的小数点去掉，就是把它的小数点向右移动三位，根据小数点的移动与小数大小的变化规律可知小数点向右移动三位，扩大了1000倍"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/701.json b/MathToF/701.json
new file mode 100644
index 0000000000000000000000000000000000000000..98816f547bbb40093e32d20754d012c6efc22714
--- /dev/null
+++ b/MathToF/701.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果5x=y，那么y和x成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/702.json b/MathToF/702.json
new file mode 100644
index 0000000000000000000000000000000000000000..516b566b32e819eeaef213728c434c47fc73eb20
--- /dev/null
+++ b/MathToF/702.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一辆自行车608元，一台电风扇197元，妈妈带了800元，刚好够了"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先根据整数加法的运算方法，用一辆自行车的价格加上一台电风扇的价格，求出一辆自行车和一台电风扇一共需要多少钱;然后把它和妈妈带的钱比较大小，判断出够不够即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/703.json b/MathToF/703.json
new file mode 100644
index 0000000000000000000000000000000000000000..3e49915f6919a12a39638c91a2e343644ffe35a5
--- /dev/null
+++ b/MathToF/703.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{5}{7}、 \\frac{8}{9}、 \\frac{14}{13}和 \\frac{9}{15}都不能化成有限小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先，要把分数化成最简分数，再根据一个最简分数，如果分母中除了2与5以外，不含有其它的质因数，这个分数就能化成有限小数;如果分母中含有2与5以外的质因数，这个分数就不能化成有限小数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/704.json b/MathToF/704.json
new file mode 100644
index 0000000000000000000000000000000000000000..fc2de89bbc25729228196306186ae9b2c9203e1a
--- /dev/null
+++ b/MathToF/704.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个苹果分给5个小朋友吃，每人吃了这个苹果的 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个苹果看作单位‘1‘，把它平均分成5份，每份是这个苹果的 \\frac{1}{5}，即平均每人吃这个苹果的 \\frac{1}{5}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/705.json b/MathToF/705.json
new file mode 100644
index 0000000000000000000000000000000000000000..20723f9d6cace100453b8cc5962bf3d55d6f0f88
--- /dev/null
+++ b/MathToF/705.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除9，余数可能是8，7，6，5，4，3，2，1中任意一个数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据余数的性质，余数小于除数，即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/706.json b/MathToF/706.json
new file mode 100644
index 0000000000000000000000000000000000000000..5568908b58568e3047a93e39a17c3dbf8e8f2100
--- /dev/null
+++ b/MathToF/706.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "秒针在钟面上走一圈是60秒，也就是1分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "秒针在钟面上走一圈，走过了12大格.每一大格是5秒，所以共走过5×12=60(秒)，即1分钟."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/707.json b/MathToF/707.json
new file mode 100644
index 0000000000000000000000000000000000000000..3ca852f97b14e57dffa3631e684853036ed4f964
--- /dev/null
+++ b/MathToF/707.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "37是37的倍数，37是37的约数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为一个数的最小的因数是1，最大的因数是它本身，一个数最小的倍数是它本身，没有最大的倍数;可以得出:37是37的倍数，37是37的约数;进而得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/708.json b/MathToF/708.json
new file mode 100644
index 0000000000000000000000000000000000000000..7d81571147ed8b3324ed8135afafb7fdd6248ed8
--- /dev/null
+++ b/MathToF/708.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{1}{2}=0.5=50%，所以 \\frac{1}{2}米=0.5米=50%米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "百分数是‘表示一个数是另一个数百分之几的数.‘它只能表示两数之间的倍数关系，不能表示某一具体数量，所以， \\frac{1}{2}米=0.5米=50%米的表示方法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/709.json b/MathToF/709.json
new file mode 100644
index 0000000000000000000000000000000000000000..51b2af65b069dd8378142eca657cb854ff5073c2
--- /dev/null
+++ b/MathToF/709.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把线段比例尺 改写成数值比例尺是1:6000000"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据线段比例尺的意义，即图上距离1厘米表示实际距离30千米，再据‘比例尺=图上距离:实际距离‘即可将线段比例尺转化成数值比例尺."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/71.json b/MathToF/71.json
new file mode 100644
index 0000000000000000000000000000000000000000..18433d86bc8f3b9eebe0679a610981cb6f270217
--- /dev/null
+++ b/MathToF/71.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "'四成'就是十分之四，也就是40%"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为表示一个数是另一个数的十分之几的数叫做成数，所以四成= \\frac{4}{10}=0.4=40%，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/710.json b/MathToF/710.json
new file mode 100644
index 0000000000000000000000000000000000000000..08eedb55a34717aad489cb1e8124aa6c6d0cb9a4
--- /dev/null
+++ b/MathToF/710.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，一个因数末尾有0，它们积的末尾就一定有0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设这两个数分别是10与5，或10与0.5;分别求出它们的乘积，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/711.json b/MathToF/711.json
new file mode 100644
index 0000000000000000000000000000000000000000..0253d7071c88140c8240fdd844075ddb039bcbaf
--- /dev/null
+++ b/MathToF/711.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "65×28与56×82的积的末尾一定都是0。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "56×82=4592，积的末尾不是0"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/712.json b/MathToF/712.json
new file mode 100644
index 0000000000000000000000000000000000000000..74369475435325cedeb3e0130bc7ebba9c737806
--- /dev/null
+++ b/MathToF/712.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "890+90=800。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "890+90=980，890-90=800。 所以原题计算错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/713.json b/MathToF/713.json
new file mode 100644
index 0000000000000000000000000000000000000000..9fd64487d2a36a0720d33f84902ad5fbceeaa409
--- /dev/null
+++ b/MathToF/713.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1千克的\\frac{3}{4}和3千克的\\frac{1}{4}一样多。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1× \\frac{3}{4}=\\frac{3}{4}(千克);3× \\frac{1}{4}=\\frac{3}{4}(千克);因为\\frac{3}{4}=\\frac{3}{4}，所以1千克\\frac{3}{4}的和3千克的\\frac{1}{4}一样多。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/714.json b/MathToF/714.json
new file mode 100644
index 0000000000000000000000000000000000000000..0ef9b537858ae60c3c4a5351e0d3cfb853e07668
--- /dev/null
+++ b/MathToF/714.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个自然数(0除外)的积不一定是这两个数的公倍数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个非0的自然数，如1和2、2和3或者6和9…，它们的积一定是它们的公倍数是正确的;故原题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/715.json b/MathToF/715.json
new file mode 100644
index 0000000000000000000000000000000000000000..c63049844d836f05d08de181c5a274380474dad4
--- /dev/null
+++ b/MathToF/715.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两根同样长的绳子，第一根用去 \\frac{1}{5}米，第二根用去 \\frac{1}{5}，第二根用去的长"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由于不知道这两根绳子具体长度，所以无法确定哪根用去的长:  如果两根绳子同长1米，则第二根用去了1× \\frac{1}{5}= \\frac{1}{5}米，即两根用去的同样长.  如两根绳子的长多于1米，则第二根用去的多于 \\frac{1}{5}米，即第二根用去的长.  如两根绳子的长少于1米，则第二根用去的少于 \\frac{1}{5}米，即第一根用去的长."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/716.json b/MathToF/716.json
new file mode 100644
index 0000000000000000000000000000000000000000..1e8dcdd3c7919c64a58fdbc22e1292e77e5d93fa
--- /dev/null
+++ b/MathToF/716.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为12÷0.6=20，所以说12是0.6的20倍，12能被0.6整除"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "整除:是指一个整数除以另一个不是0的整数，得到的商是整数，而没有余数，我们就说第一个整数能被第二个整数整除，第二个整数能整除第一个整数;根据整除的意义，可知12÷0.6=20不是整除算式，因为除数是小数，不是整数，所以不能说12能被0.6整除，可以说12是0.6的20倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/717.json b/MathToF/717.json
new file mode 100644
index 0000000000000000000000000000000000000000..4c2fa077a8e13545859ed2dd01c5711c11270997
--- /dev/null
+++ b/MathToF/717.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一幢7层楼每层的高度是相同的，小宁从底层走到三楼要用40秒，那么走到顶层需要140秒"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，小宁从底层走到三楼要用40秒，也就是从一楼到三楼，走了3-1=2层楼梯，用了40秒，可以求出每走一层楼梯的时间，那么走到顶层需要的时间，走的楼梯层数是7-1=6层，然后再乘上每层楼梯的时间即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/718.json b/MathToF/718.json
new file mode 100644
index 0000000000000000000000000000000000000000..ac89a70959caedb9127b04728f8127036a62b468
--- /dev/null
+++ b/MathToF/718.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果两个圆的直径比是2:3，那么它们的面积比是4:9"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "设大圆的直径为3r，则小圆的直径为2r，分别代入圆的面积公式，表示出各自的面积，即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/719.json b/MathToF/719.json
new file mode 100644
index 0000000000000000000000000000000000000000..33034c7366a5d217e36a0a58b7f646cd7f515aca
--- /dev/null
+++ b/MathToF/719.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "75的20倍是150."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "75的20倍是75*20=1500，所以这句话是错的。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/72.json b/MathToF/72.json
new file mode 100644
index 0000000000000000000000000000000000000000..29a61a80820d322be5d7f1336fd8a803b1ad3849
--- /dev/null
+++ b/MathToF/72.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最简分数的分子和分母没有公约数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最简分数的意义:分子和分母是互质数的分数叫做最简分数，互质数是只有公约数1的两个数，据此分子解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/720.json b/MathToF/720.json
new file mode 100644
index 0000000000000000000000000000000000000000..242be6d60c087132f95d688d1d3b0302648a6903
--- /dev/null
+++ b/MathToF/720.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "4800÷900=480÷90=48÷9"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据‘被除数和除数都缩小(或都扩大)相同的倍数(0除外)，商不变‘，进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/721.json b/MathToF/721.json
new file mode 100644
index 0000000000000000000000000000000000000000..aa11c3f7bb069762ededb921c7a67c262ff4a56d
--- /dev/null
+++ b/MathToF/721.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "梨树是桃树的 \\frac{3}{5}，杏树是桃树的20%，杏树的棵数是梨树的 \\frac{2}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把桃树的棵数看作单位‘1‘，梨树的棵数占 \\frac{3}{5}，杏树的棵数占20%，求杏树的棵数是梨树的几分之几，杏树的棵数用除以梨树的棵数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/722.json b/MathToF/722.json
new file mode 100644
index 0000000000000000000000000000000000000000..627c20091b855567fb0eb1020db71bc6ca5f80f5
--- /dev/null
+++ b/MathToF/722.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘的积是0，则至少有一个因数是0"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在乘法里，零和任何数相乘都得零，依此即可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/723.json b/MathToF/723.json
new file mode 100644
index 0000000000000000000000000000000000000000..77052bbe3f453ad7a5d4b52d399d597bad58b23f
--- /dev/null
+++ b/MathToF/723.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8.4和8.400的大小相等，但计数单位不同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据小数的性质和小数的计数单位进行解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/724.json b/MathToF/724.json
new file mode 100644
index 0000000000000000000000000000000000000000..42cab8da269a381bec90df3a6018a5e6221476aa
--- /dev/null
+++ b/MathToF/724.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "A÷16的商一定比A÷24的商大.(A是一个非零的自然数)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据商的变化规律知:被除数相同(0除外)除数越大，商就越小，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/725.json b/MathToF/725.json
new file mode 100644
index 0000000000000000000000000000000000000000..dc30b98656cec00fc8d700512cf2fe516aba462e
--- /dev/null
+++ b/MathToF/725.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "高斌同学每天做作业的时间大约是90分钟"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据生活经验、对时间单位大小的认识，做作业的时间大约是90分钟."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/726.json b/MathToF/726.json
new file mode 100644
index 0000000000000000000000000000000000000000..af1892c5d02c810f680b37f7d17b96edafd8ebae
--- /dev/null
+++ b/MathToF/726.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "五(2)班有女生25人，比男生的2倍少27人，则五(2)班女生比男生人数多"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，可用25加27计算出男生的2倍是多少，然后再用男生的2倍除以2即可得到男生的人数，最后再用男、女生的人数相比较后再判断即可.男生人数:(25+27)÷2 =52÷2 =26(人)，26人>25人，五(2)班的女生比男生人数少. "
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/727.json b/MathToF/727.json
new file mode 100644
index 0000000000000000000000000000000000000000..49873f33e99db94a0387abe5bb31b97e5eb26892
--- /dev/null
+++ b/MathToF/727.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算器上的ON/C是开关及清屏键"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在计算器上ON/C键是开关及清屏键;CE键是清除键.据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/728.json b/MathToF/728.json
new file mode 100644
index 0000000000000000000000000000000000000000..8e3347c2566acc8ce84ea193b869d826a599e2b5
--- /dev/null
+++ b/MathToF/728.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三角形的面积是同底等高的平行四边形的面积的一半"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据‘平行四边形的面积=底×高和三角形的面积=底×高÷2‘进行推导，得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/729.json b/MathToF/729.json
new file mode 100644
index 0000000000000000000000000000000000000000..3d28b72fc1a2fdacfa239ea403e6bea53e608058
--- /dev/null
+++ b/MathToF/729.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "乙数是甲数的 \\frac{2}{3}，甲乙两数的比是3:2"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据‘乙数是甲数的 \\frac{2}{3}‘得出乙数=甲数× \\frac{2}{3}，再逆用比例的基本性质得出乙数与甲数的比."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/73.json b/MathToF/73.json
new file mode 100644
index 0000000000000000000000000000000000000000..b449a5b775df66121641fe94ba67190eab5d3cd6
--- /dev/null
+++ b/MathToF/73.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "人民币的单位是元、角、分。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据常识可知，人民币的单位有元、角、分。据此解答即可。 人民币的单位是元、角、分，这句话是正确的。 故答案为:√。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/730.json b/MathToF/730.json
new file mode 100644
index 0000000000000000000000000000000000000000..35a27c1c3bbf1824201844685107111d3de66880
--- /dev/null
+++ b/MathToF/730.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "(546+207)-(346+207)=(546-346)+(207+207)"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据一个数减去两个数的和等于这个数连续减去这两个数，即(546+207)-(346+207)=546+207-346-207，然后根据整数的加减混合运算的顺序适当变换判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/731.json b/MathToF/731.json
new file mode 100644
index 0000000000000000000000000000000000000000..4edafa9682ed9d544599a2300238a0f04cb02507
--- /dev/null
+++ b/MathToF/731.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果 \\frac{10}{x}=y，则x与y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "判断两个相关联的量之间成什么比例，就看这两个量是对应的比值一定，还是对应的乘积一定;如果是比值一定，就成正比例;如果是乘积一定，则成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/732.json b/MathToF/732.json
new file mode 100644
index 0000000000000000000000000000000000000000..3fdd8fd5b07765fbc578ed88ad0df76d57be5f57
--- /dev/null
+++ b/MathToF/732.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "27个篮球，每6个装一筐，可以装4筐，还剩3个。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "用篮球的总数除以每筐装的篮球个数，得到的商就是装的筐数，余数就是剩下的个数，即27÷6=4(筐)…3(个)，所以此题正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/733.json b/MathToF/733.json
new file mode 100644
index 0000000000000000000000000000000000000000..372b7bdb1cbea399004f36fccb6849803ee5ce13
--- /dev/null
+++ b/MathToF/733.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体的面中可能有正方形，正方体的面中不可能有长方形."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "长方体的面中可能有正方形，正方体的每个面都是正方形，所以正方体的面中不可能有长方形，所以本题说法正确. 正确.  长方体的面中可能有正方形，正方体的每个面都是正方形，所以正方体的面中不可能有长方形，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/734.json b/MathToF/734.json
new file mode 100644
index 0000000000000000000000000000000000000000..4a4d7b53b5dc438caa97df0df2a7a9bef6b8a46a
--- /dev/null
+++ b/MathToF/734.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个长方形和一个正方形的周长相等，那么长方形的面积较大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正方形和长方形的周长相等，正方形的面积比长方形的面积大.可以通过举例证明，如它们的周长都是24厘米，长方形的长是8厘米，宽是4厘米;正方形的边长是6厘米;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/735.json b/MathToF/735.json
new file mode 100644
index 0000000000000000000000000000000000000000..9a5365235b217173690d878c91cc5f876d58df41
--- /dev/null
+++ b/MathToF/735.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "妈妈要买一台电扇(245元)，电饭煲(187元)，带400元钱就够了"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据加法的意义，将电扇单价与电饭煲单价相加，即得买这两件商品共需多少钱，然后用所需钱数与所带钱数比较，即得是否够用."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/736.json b/MathToF/736.json
new file mode 100644
index 0000000000000000000000000000000000000000..bb60640bbd115712c87bda47700cec444699cad4
--- /dev/null
+++ b/MathToF/736.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲数是乙数的 \\frac{3}{5}，那么乙数比甲数少 \\frac{2}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先根据题意，把乙数看作单位‘1‘，则甲数是 \\frac{3}{5}，然后把甲数看作单位‘1‘，根据求一个数比另一个数多(或少)几分之几，用除法解答，用甲乙两数的差除以甲数，求出乙数比甲数少几分之几即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/737.json b/MathToF/737.json
new file mode 100644
index 0000000000000000000000000000000000000000..25af24e181840eb2b73871208059b44f7b036de6
--- /dev/null
+++ b/MathToF/737.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "个位上和十位上数字相同的两位数有9个。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "要求个位上的数字和十位上的数字相同的数，例如:11、22、33…都是个位和十位数字相同的两位数。据此解答即可。 个位上的数字和十位上的数字相同的数有:11、22、33、44、55、66、77、88、99，共9个，原说法正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/738.json b/MathToF/738.json
new file mode 100644
index 0000000000000000000000000000000000000000..9d26f90f0f1fbae7efa21a4eaeca1808e06323b6
--- /dev/null
+++ b/MathToF/738.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8个82连加的和是100"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "8个82可以写成加法算式:82+82+82+…+82(共8个82)，也可以写成乘法算式82×8，求出这个积与100比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/739.json b/MathToF/739.json
new file mode 100644
index 0000000000000000000000000000000000000000..dce6550aa7b0417a519d6fd2075fbdabe1946042
--- /dev/null
+++ b/MathToF/739.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一辆自行车a元，三辆自行车就是a+3元"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据总价=单价×数量，三辆自行车就是3a，所以原题说法错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/74.json b/MathToF/74.json
new file mode 100644
index 0000000000000000000000000000000000000000..3126c646bc18301149e241a3bd1f9c75715237ae
--- /dev/null
+++ b/MathToF/74.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{2}{5}×3和3× \\frac{2}{5}的计算结果相同，所以它们表示的意义也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "\\frac{2}{5}×3属于分数乘整数，表示求3个 \\frac{2}{5}是多少;而3× \\frac{2}{5}属于一个数乘分数，表示求3的 \\frac{2}{5}是多少;所以它们虽然计算结果相同，但是它们表示的意义却不相同."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/740.json b/MathToF/740.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c1af37f6761ca0876be55f55589781507480fa0
--- /dev/null
+++ b/MathToF/740.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一只钟敲6下用5秒，敲12下用10秒"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为钟敲6下用去5秒，也就是说6-1=5个间隔敲了5秒，由此求出一个间隔所用的时间;而钟敲12下，中间的间隔数是12-1个，用间隔数(12-1)乘一个间隔所用的时间就是敲12下用去的时间."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/741.json b/MathToF/741.json
new file mode 100644
index 0000000000000000000000000000000000000000..6255a44c1d4aa073404957ee138b3b0350e159ff
--- /dev/null
+++ b/MathToF/741.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个因数扩大为原来的100倍，另一个因数不变，积也扩大为原来的100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "积的变化规律:一个因数扩大或缩小几倍(0除外)，另一个因数不变，积就扩大或缩小相同的倍数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/742.json b/MathToF/742.json
new file mode 100644
index 0000000000000000000000000000000000000000..7f9bbdcbc89ac3172b0ac5039fba0094709887c5
--- /dev/null
+++ b/MathToF/742.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个长方体中，可能有4个面是正方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方体的特征:6个面都是长方形(特殊情况有两个相对的面是正方形)，相对的面的面积相等，12条棱分为互相平行的3组，每组4条棱的相等相等，有8个顶点.据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/743.json b/MathToF/743.json
new file mode 100644
index 0000000000000000000000000000000000000000..f7461a4571c63043f948c94697a7269ea4000866
--- /dev/null
+++ b/MathToF/743.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为\\( 2^{2} \\)=2×2，所以\\( a^{2} \\)=2a"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为2×a表示a个2相加的和是多少，2×a=2a;进而进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/744.json b/MathToF/744.json
new file mode 100644
index 0000000000000000000000000000000000000000..c26bdf015a65ba2e274072c2253405bf1c2d2e3e
--- /dev/null
+++ b/MathToF/744.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个两位数乘20，那么积的末尾只有一个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先假设这个两位数是65，求出20×65的积是多少，确定积的末尾有几个0.再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/745.json b/MathToF/745.json
new file mode 100644
index 0000000000000000000000000000000000000000..1d11f067273cc59b7130ee4cfbe1e6678c649c3c
--- /dev/null
+++ b/MathToF/745.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两位数乘两位数，积一定是四位数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两位数乘两位数，积可能是三位数，比如11*11=121。所以原说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/746.json b/MathToF/746.json
new file mode 100644
index 0000000000000000000000000000000000000000..7950f547d96ac72dc3d7d487dee1c00323ece29d
--- /dev/null
+++ b/MathToF/746.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任何自然数的倒数都小于1( 判断对错 )"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.0没有倒数，1的倒数还是1.由此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/747.json b/MathToF/747.json
new file mode 100644
index 0000000000000000000000000000000000000000..a7e6d1b9f1d9d43e955f9fa5a681916eb3389ebf
--- /dev/null
+++ b/MathToF/747.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母都乘或除以20，分数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分数的基本性质是:分数的分子和分母同时乘或除以一个相同的数(0除外)，分数的大小不变，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/748.json b/MathToF/748.json
new file mode 100644
index 0000000000000000000000000000000000000000..a1723ce265762fb1ce703f1beccdd772bbe94d5a
--- /dev/null
+++ b/MathToF/748.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在一天的时间里，钟面上的时针正好走一圈"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一天是24小时，钟面上的时针走1圈是12小时，正好走2圈."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/749.json b/MathToF/749.json
new file mode 100644
index 0000000000000000000000000000000000000000..4ff09d23f6490ecff7c0e154556fb6cf83f0e674
--- /dev/null
+++ b/MathToF/749.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果要形象地表示某病人的体温变化情况，最好选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "首先要清楚每一种统计图的特点:条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/75.json b/MathToF/75.json
new file mode 100644
index 0000000000000000000000000000000000000000..ea303f53c6f78e973e1057e3434517717cac7dac
--- /dev/null
+++ b/MathToF/75.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "10是倍数，5是因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/750.json b/MathToF/750.json
new file mode 100644
index 0000000000000000000000000000000000000000..5aa07858604d64db7a1080c15e93fa61501d2736
--- /dev/null
+++ b/MathToF/750.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "‘□□□×□‘如果第一个乘数中间有0，那么积中间一定也有0;如果第一个乘数末尾有0，那么积末尾一定也有0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设两个因数分别是102与6，120与6，分别求出它们的乘积，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/751.json b/MathToF/751.json
new file mode 100644
index 0000000000000000000000000000000000000000..88ae8f1ce2ef56d94dbf600c6e6e721144cb7841
--- /dev/null
+++ b/MathToF/751.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一只小鸡捉一条虫子大约用5分钟，三只小鸡捉3条虫子，大约需要15分钟。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一只小鸡捉一条虫子大约用5分钟，三只小鸡捉3条虫子，每只小鸡还是捉一条虫子，所以还是需要5分钟。 一只小鸡捉一条虫子大约用5分钟，三只小鸡捉3条虫子，大约需要5分钟，原题说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/752.json b/MathToF/752.json
new file mode 100644
index 0000000000000000000000000000000000000000..f4f701c59fa2d7ffe2c39fe05c24bfb0f847dbd4
--- /dev/null
+++ b/MathToF/752.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个非0的自然数的乘积一定是它们的公倍数(判断正误)"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "例如6和9这两个非0的自然数，它们的积是6×9=54，54是它们的公倍数，是6的9倍，是9的6倍，但不是它们的最小公倍数，它们的最小公倍数是18;即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/753.json b/MathToF/753.json
new file mode 100644
index 0000000000000000000000000000000000000000..f0a73588418f9563fbccb43d325c488d6af958e2
--- /dev/null
+++ b/MathToF/753.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "12和18的公因数既是12的因数，又是18的因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先要理解公因数的意义，两个数公有的因数叫做这两个数的公因数;据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/754.json b/MathToF/754.json
new file mode 100644
index 0000000000000000000000000000000000000000..13061951ea28be139c4ab53d3d938889af3b58ea
--- /dev/null
+++ b/MathToF/754.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把15个苹果平均分成5份，每份是3个苹果，占整体的 \\frac{3}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把这15个苹果看作单位‘1‘，把它平均分成5份，每份是它的 \\frac{1}{5}，根据整数除法的意义，每份是15÷5=3(个)苹果，或根据分数乘法的意义，每份是15× \\frac{1}{5}=3(个)苹果."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/755.json b/MathToF/755.json
new file mode 100644
index 0000000000000000000000000000000000000000..d6233aa77a4298dd3aa1ada6f149c1c24b4304ae
--- /dev/null
+++ b/MathToF/755.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一块饼分成5块，小明吃了1块，吃了这块饼的 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的意义，把一个蛋糕看作单位‘1‘，把它平均分成5份，每份就是这个蛋糕的五分之一.本题中，把一块蛋糕分成5份，每份是这块蛋糕的多少不一定，因为不是平均分的，无法确定，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/756.json b/MathToF/756.json
new file mode 100644
index 0000000000000000000000000000000000000000..0b184d4a4c337469b0300ac101c88c4d72ffb664
--- /dev/null
+++ b/MathToF/756.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为1×0=0，所以1÷0=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0不能做除数，0做除数无意义.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/757.json b/MathToF/757.json
new file mode 100644
index 0000000000000000000000000000000000000000..2d7e342d1df8843bc041bcbbc520ff507f1e3e99
--- /dev/null
+++ b/MathToF/757.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "10个10是100，所以10个 \\frac{1}{10}是 \\frac{1}{100}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数乘整数的意义与整数乘法的意义相同，都表示求几个相同加数的和的简便运算.所以求10个 \\frac{1}{10}列式为: \\frac{1}{10}×10=1，也可以根据‘十进制‘计数法，10个十分之一是一.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/758.json b/MathToF/758.json
new file mode 100644
index 0000000000000000000000000000000000000000..114175cf8d83eb21771a8464a5053af29014cd56
--- /dev/null
+++ b/MathToF/758.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以它的倒数等于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.可以通过举例证明."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/759.json b/MathToF/759.json
new file mode 100644
index 0000000000000000000000000000000000000000..1f454a5f0a8665f7c23e686b02b8d05f19629dd5
--- /dev/null
+++ b/MathToF/759.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一组数据的平均数一定是这组数据中的其中一个"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一组数据的总和除以这组数据个数所得到的商叫这组数据的平均数;可举例说明比较容易理解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/76.json b/MathToF/76.json
new file mode 100644
index 0000000000000000000000000000000000000000..8551d28b2b24a313947b1d3b15c8dac3e53cb6d3
--- /dev/null
+++ b/MathToF/76.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.3与0.300的大小相等，计数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "小数的性质:小数的末尾添上‘0‘或去掉‘0‘小数的大小不变;  根据小数的基本性质可知，0.3=0.300，根据小数的意义可知:0.3的计数单位是0.01，0.300的计数单位是0.001，据此分析判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/760.json b/MathToF/760.json
new file mode 100644
index 0000000000000000000000000000000000000000..6e54dc67c031e6d0b9839f72c658ca770e2e1427
--- /dev/null
+++ b/MathToF/760.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把 \\frac{9}{10}米长的铁丝平均分成3段，每段长 \\frac{1}{3}米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意列式，可得 \\frac{9}{10}÷ 3=\\frac{9}{10}× \\frac{1}{3}=\\frac{3}{10}(米)，所以每段长 \\frac{3}{10}米，故本题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/761.json b/MathToF/761.json
new file mode 100644
index 0000000000000000000000000000000000000000..ba231f3ddd89b52ce57ce3df213f1dbd634d33e5
--- /dev/null
+++ b/MathToF/761.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用0、1、5、9四个数字组成的四位数中，最小的是1059"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/762.json b/MathToF/762.json
new file mode 100644
index 0000000000000000000000000000000000000000..20edc9f5ac51a6fe69863f32d515df323fda2ffc
--- /dev/null
+++ b/MathToF/762.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在一次摸球活动中，每次都把摸到的球放回盒子中，小明一共摸了 3次，因为只有1次摸到红球，有2次摸到白球，所以盒子中白球的个数一定比红球多。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "思路分析:这是一道可能性的题，仔细分析得出，盒子中白球的个数不一定比红球多。 名师详解:仔细分析得出，盒子中白球的个数不一定比红球多。所以是×。 易错提示:出错不多，注意的是，盒子中白球的个数不一定比红球多。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/763.json b/MathToF/763.json
new file mode 100644
index 0000000000000000000000000000000000000000..0b7dd9fee5a7535b6d566e74ff39d13166dbf98f
--- /dev/null
+++ b/MathToF/763.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.13÷0.4的商是0.3，余数是0.1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在有余数的除法中，被除数=商×除数+余数，可得:余数=被除数-商×除数;据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/764.json b/MathToF/764.json
new file mode 100644
index 0000000000000000000000000000000000000000..b2248bb1d86a5be369cec419a827fa39c0bef2ee
--- /dev/null
+++ b/MathToF/764.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆的半径扩大到原来的2倍，周长也扩大为原来的2倍。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "圆的周长为2πr，当半径扩大到原来的2倍时，周长则变为4πr，也扩大为原来的2倍，所以原说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/765.json b/MathToF/765.json
new file mode 100644
index 0000000000000000000000000000000000000000..44f4d2f3055406762fef6a90e224f5bcbfd0a649
--- /dev/null
+++ b/MathToF/765.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "从家到学校，小兰用了10分钟，小明用了12分钟，小兰和小明的速度比是5:6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把从家到学校的路程看作单位‘1‘，根据‘路程÷时间=速度‘分别求出小明和小兰的速度，进而根据题意求比即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/766.json b/MathToF/766.json
new file mode 100644
index 0000000000000000000000000000000000000000..ed05f1479f1875d5aac307165ee934e161fa0d7a
--- /dev/null
+++ b/MathToF/766.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{17}× \\frac{1}{8}÷ \\frac{3}{17}× \\frac{1}{8}=1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数的四则混合运算规律，除以一个分数等于乘这个分数的倒数，分子分母约分，然后分子分母分别相乘，即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/767.json b/MathToF/767.json
new file mode 100644
index 0000000000000000000000000000000000000000..20a8bf0630c9cf0f8e327e76d8b4bf3cafd8a6a6
--- /dev/null
+++ b/MathToF/767.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "至少4个完全一样的正方形才能拼成一个大正方形。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "要求所得到的正方形最小，则每条边长是由两个小正方形的边长组成。 要组成新的大正方形至少要小正方形:2×2=4(个)。 如图: 所以原题说法正确。 故答案为:√。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/768.json b/MathToF/768.json
new file mode 100644
index 0000000000000000000000000000000000000000..88cca3aad180be61637ad55097d1242b2b07244b
--- /dev/null
+++ b/MathToF/768.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "403×79的乘积大约是32000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据估算的方法，403估算时看作400，79估算时看作80，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/769.json b/MathToF/769.json
new file mode 100644
index 0000000000000000000000000000000000000000..137d79b78e72eb1f53cb3da20a0c6c59f1ca9e07
--- /dev/null
+++ b/MathToF/769.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以6，商是24，余数是3，这个数是147"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据在有余数的除法算式中，被除数=商×除数+余数，据此解答即可得到答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/77.json b/MathToF/77.json
new file mode 100644
index 0000000000000000000000000000000000000000..df25b4b5317efb2904b9617ff57a818ce05ddd82
--- /dev/null
+++ b/MathToF/77.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小刚的生日正好是在2月30日。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            " 平年二月份有28天，闰年二月份有29天.  错误。  闰年二月份有29天，平年二月份有28天，不论是平年还是闰年二月份都不会有30  天，由此做出判断。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/770.json b/MathToF/770.json
new file mode 100644
index 0000000000000000000000000000000000000000..606d31ef4fa28537e3fcf52c2ef1c1897c765164
--- /dev/null
+++ b/MathToF/770.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方体纸盒放在桌面上，露在外面的面有5个"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把一个小正方体纸盒放在桌子上，只有底面看不见，有5个面露在外面，据此进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/771.json b/MathToF/771.json
new file mode 100644
index 0000000000000000000000000000000000000000..056b169fdc63f6997ee50ca958a629f245620462
--- /dev/null
+++ b/MathToF/771.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个质数一定是互质数，但互质的两个数不一定是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "互质数是只有公因数1的两个数，两个质数只含有公因数1，所以一定是互质数，只要是只有公因数1的两个数就是互质数，所以互质的两个数不一定是质数，可以举例证明，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/772.json b/MathToF/772.json
new file mode 100644
index 0000000000000000000000000000000000000000..3cc94bb0350b4c63cb89797e6cbd5bf0101e175c
--- /dev/null
+++ b/MathToF/772.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为0表示什么也没有，所以在306÷3=102中，可以把102中间的0省略不写。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0虽然表示某个数位上一个计数单位也没有，但它同时也起占位作用，不能随便舍弃。原说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/773.json b/MathToF/773.json
new file mode 100644
index 0000000000000000000000000000000000000000..089f3238e39915478dacd9ea326a2f473509d29f
--- /dev/null
+++ b/MathToF/773.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "既能表示出数量多少，又能表示出数量增减变化的情况，应选用折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/774.json b/MathToF/774.json
new file mode 100644
index 0000000000000000000000000000000000000000..35a639683132983c0ad6b647d60bb1d6c5673145
--- /dev/null
+++ b/MathToF/774.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "x=24是方程3x+8=80的解。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把x=24代入方程，看方程两边是否相等即可，根据此判断即可。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/775.json b/MathToF/775.json
new file mode 100644
index 0000000000000000000000000000000000000000..348a591b539707440f9e46c3bc74bcfcc4dffa19
--- /dev/null
+++ b/MathToF/775.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数单位相同的分数才能相加减"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数单位相同的分数，也就是同分母分数，所以可以相加减;异分母分数，通分后也可以相加减."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/776.json b/MathToF/776.json
new file mode 100644
index 0000000000000000000000000000000000000000..92a8d1a39163d967a1fd2868f146ca3e47bf118c
--- /dev/null
+++ b/MathToF/776.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三个连续自然数中，一定有一个是3的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据3的倍数的特征，各位上的数字之和是3的倍数，这个数一定是3的倍数，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/777.json b/MathToF/777.json
new file mode 100644
index 0000000000000000000000000000000000000000..70439ce7088b734603cb4c2539746e909037273f
--- /dev/null
+++ b/MathToF/777.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根绳子长 0.9米，可以写成90%米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "百分数是‘表示一个数是另一个数百分之几的数.‘它只能表示两数之间的倍数关系，不能表示某一具体数量，所以，一根绳子长 0.9米，可以写成90%米的表示方法是错误的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/778.json b/MathToF/778.json
new file mode 100644
index 0000000000000000000000000000000000000000..8fcd0c55b63385a7f3446b4467e84aad0ff14948
--- /dev/null
+++ b/MathToF/778.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{1}{2}= \\frac{2}{4}，所以 \\frac{1}{2}和 \\frac{2}{4}的分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "判定一个分数的单位看分母，分母是几，分数单位就是几分之一."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/779.json b/MathToF/779.json
new file mode 100644
index 0000000000000000000000000000000000000000..3fbf3e6831035111f5815949a68048c8095a1c58
--- /dev/null
+++ b/MathToF/779.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "37是37的因数，37是37的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个数的因数是有限的，其中最大的因数是它本身，一个数的倍数的个数是无限的，其中最小的倍数是它本身，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/78.json b/MathToF/78.json
new file mode 100644
index 0000000000000000000000000000000000000000..5513380401045674194f284250c1407f3e164541
--- /dev/null
+++ b/MathToF/78.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "箱子中装有红、蓝、绿、白5种颜色的球共30个，任意摸出1个，摸出球的颜色有5种可能"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "试题分析:此题考查了简单事件发生的可能性求解，应明确:箱子里有几种颜色的球，任意摸出1个，摸出的颜色就有几种可能."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/780.json b/MathToF/780.json
new file mode 100644
index 0000000000000000000000000000000000000000..66869e70dfbe954248b5d2d5c2aa9a7c1a30be15
--- /dev/null
+++ b/MathToF/780.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2×2=\\( 2^{2} \\) ， 所以2×a=\\( a^{2} \\) ."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由分析知:2×a=2a;  \\( a^{2} \\)=a×a;  所以2×a≠\\( a^{2} \\) .  错误.  因为2×a表示a个2相加的和是多少，2×a=2a;进而进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/781.json b/MathToF/781.json
new file mode 100644
index 0000000000000000000000000000000000000000..930df87cfd4c1445daeea4ef5007663066b4551e
--- /dev/null
+++ b/MathToF/781.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三角形和平行四边形不是等底等高的时候，三角形的面积也有可能是平行四边形的面积的一半"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "本题根据三角形的面积和平行四边形面积公式，通过举例子即可作出判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/782.json b/MathToF/782.json
new file mode 100644
index 0000000000000000000000000000000000000000..e8246839dc15ba207801a1024406bdcad7005a28
--- /dev/null
+++ b/MathToF/782.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "136003600是由1个亿、3600个万、3600个一组成的"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "将136003600分成三级，个级、万级和亿级，亿级上的数表示有几个亿，万级上的数表示有几个万，个位上的数表示有几个一，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/783.json b/MathToF/783.json
new file mode 100644
index 0000000000000000000000000000000000000000..84a04d6a9f00802b83a62d7220ab2ea9c61bb1ff
--- /dev/null
+++ b/MathToF/783.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个小数的小数点先向右移动两位，再向左移动一位，这个小数就扩大了10倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个小数的小数点先向右移动两位，就是扩大为原数的100倍，再向左移动一位，就是缩小为得到的数的 \\frac{1}{10}倍，即把原数扩大了100× \\frac{1}{10}=10倍.据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/784.json b/MathToF/784.json
new file mode 100644
index 0000000000000000000000000000000000000000..6f78165bf6eaa1c743729d26c15d9fb3b9120d8c
--- /dev/null
+++ b/MathToF/784.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{4}{6}和 \\frac{8}{12}的大小相等，所以它们的分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "判定一个分数的单位看分母，分母是几，分数单位就是几分之一."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/785.json b/MathToF/785.json
new file mode 100644
index 0000000000000000000000000000000000000000..3745fbebf2430bb9bf5033dbfc75e08b23f3416b
--- /dev/null
+++ b/MathToF/785.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{5}{4}× \\frac{4}{3}× \\frac{3}{5}=1，所以 \\frac{5}{4}、 \\frac{4}{3}、 \\frac{3}{5} 互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义，乘积是1的两个数互为倒数.倒数是对两个数而言，如果两个数的乘积是1，那么这两个数互为倒数.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/786.json b/MathToF/786.json
new file mode 100644
index 0000000000000000000000000000000000000000..5784ddd438ac524dc95a2f64ede0d9df60e10cbb
--- /dev/null
+++ b/MathToF/786.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形，它的三个内角度数的比是1:5:6，这个三角形是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "三角形的内角和为180°，根据最大角占180°的几分之几，直接计算出最大角的度数，再根据三角形的分类判断即可得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/787.json b/MathToF/787.json
new file mode 100644
index 0000000000000000000000000000000000000000..004204a93cdc329717f6793fdca3b49038a5374b
--- /dev/null
+++ b/MathToF/787.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3.596精确到百分位是3.6。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "3.596精确到百分位是3.60，所以原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/788.json b/MathToF/788.json
new file mode 100644
index 0000000000000000000000000000000000000000..e11287a313d4e4154e65f225e4df7b8900bc9b44
--- /dev/null
+++ b/MathToF/788.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "课桌的高度大约是80万米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据生活经验、对长度单位和数据大小的认识，可知计量课桌的高度用‘厘米‘做单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/789.json b/MathToF/789.json
new file mode 100644
index 0000000000000000000000000000000000000000..8cfc130913001845b576010cdecff3d948b9eeca
--- /dev/null
+++ b/MathToF/789.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把8个苹果平均分给4个小朋友，其中3个小朋友得到这些苹果的 \\frac{3}{8}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把这些苹果的个数看作单位‘1‘，把它平均分成4份，每份是这些苹果的 \\frac{1}{4}，即每个小朋友分得这些苹果的 \\frac{1}{4}，3个小月友分得3个 \\frac{1}{4}，即分得这些苹果的 \\frac{3}{4}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/79.json b/MathToF/79.json
new file mode 100644
index 0000000000000000000000000000000000000000..188c74a3e5063ccd99b8ea23e21282b4cb0387f4
--- /dev/null
+++ b/MathToF/79.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三个连续自然数的乘积一定是6的倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "任取几组3个连续非零自然数，求出它们相乘的积，然后分析是答案中的哪个数即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/790.json b/MathToF/790.json
new file mode 100644
index 0000000000000000000000000000000000000000..01c7aef50f8267f9801dfad984f950c9b8689a05
--- /dev/null
+++ b/MathToF/790.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体中不可能有正方形的面"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方体的特征，6个面都是长方形(特殊情况有两个相对的面是正方形)，相对面的面积相等.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/791.json b/MathToF/791.json
new file mode 100644
index 0000000000000000000000000000000000000000..8db5c4d941625119a0c491af4d7903100af4b540
--- /dev/null
+++ b/MathToF/791.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果一个长方体的棱长总和为60厘米，那么这个长方体相交于一个顶点的三条棱的长度之和是10厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方体的特征，长方体的12条棱分为互相平行的3组，每组4条棱的长度相等，相交于一个顶点的三条棱的长度分别叫做长方体的长、宽、高，用棱长总和除以4求出长、宽、高的和，然后与10厘米进行比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/792.json b/MathToF/792.json
new file mode 100644
index 0000000000000000000000000000000000000000..4bc5d7609c3b326514c4722787c15d2f75935c68
--- /dev/null
+++ b/MathToF/792.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子和分母都乘以或除以相同的数，分数的大小不变。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分子和分母扩大或缩小相同倍数，分数的大小不改变考察约分和通分后，分数的大小不发生改变"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/793.json b/MathToF/793.json
new file mode 100644
index 0000000000000000000000000000000000000000..057f3d26dfceadcc6ab6884a1f1253b5d853f666
--- /dev/null
+++ b/MathToF/793.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "49×22的得数比800大，比1000小。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "49*22>1000，所以原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/794.json b/MathToF/794.json
new file mode 100644
index 0000000000000000000000000000000000000000..f05d226084c8cd41a4d0c1f512b924697dd33493
--- /dev/null
+++ b/MathToF/794.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一件商品打九折出售，就是按原价的90%出售，也就是比原价低10%"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把原价看作单位‘1‘，打九折，就是按原价的90%出售，即比原价降低了(1-90%)，解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/795.json b/MathToF/795.json
new file mode 100644
index 0000000000000000000000000000000000000000..d13fa9c487a6ce2990b141b233204b876d8f3c89
--- /dev/null
+++ b/MathToF/795.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个自然数比较，位数多的数比位数少的数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "整数大小的比较方法，位数不同，位数多的数就大;位数相同，左起第一位上的数大的那个数就大;如果左起第一位上的数相同，就比较左起第二位上的数，直到比较出大小为止.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/796.json b/MathToF/796.json
new file mode 100644
index 0000000000000000000000000000000000000000..03c2c4ba907391f086ca6803ad7ca19a5ad1bcb9
--- /dev/null
+++ b/MathToF/796.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在同一个圆内，圆心角越大，扇形也就越大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在同一个圆中，扇形的大小与这个扇形的圆心角的大小有关，圆心角越大，扇形也就越大。由此可知答案。 考点:扇形的大小与圆心角的关系 总结:本题主要考查扇形的大小与圆心角的关系"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/797.json b/MathToF/797.json
new file mode 100644
index 0000000000000000000000000000000000000000..e651e0dfb0300baddadd9cbb5a5ecad5b95454cd
--- /dev/null
+++ b/MathToF/797.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个奇数的和一定是偶数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据奇数和偶数的性质:两个偶数的和或差仍是偶数，两个奇数的和或差也是偶数，奇数和偶数的和或差是奇数;进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/798.json b/MathToF/798.json
new file mode 100644
index 0000000000000000000000000000000000000000..b31217640f4fdec9812152a36bc26b6def3dc824
--- /dev/null
+++ b/MathToF/798.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "封闭图形一周的长度，就是这个图形的周长"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据周长的定义知道，围成封闭图形的所有边的总长度就是它的周长，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/799.json b/MathToF/799.json
new file mode 100644
index 0000000000000000000000000000000000000000..5e1e9b9e563c0d68d3c9e2b15f799c6a94446d3c
--- /dev/null
+++ b/MathToF/799.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要表示某地一年月平均气温变化情况应绘制折线统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/8.json b/MathToF/8.json
new file mode 100644
index 0000000000000000000000000000000000000000..5af8b5e739444f83043bb60e0348633e0761f6f7
--- /dev/null
+++ b/MathToF/8.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "平年第二季度与闰年第二季度的天数不相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "第二季度是4月、5月、6月这三个月，无论平年还是闰年，这三个月的天数都是一样的，所以无论是平年还是闰年第二季度的天数也都是一样的."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/80.json b/MathToF/80.json
new file mode 100644
index 0000000000000000000000000000000000000000..6f40b011bd8d3baed3195cec77b0cae63417ba03
--- /dev/null
+++ b/MathToF/80.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数单位相同的分数才能直接相加减。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分数相同的分数就是同分母分数，计算同分母分数时分母不变，只把分子相加减，因此本题正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/800.json b/MathToF/800.json
new file mode 100644
index 0000000000000000000000000000000000000000..cc9128f7cb5475755ae4eb3710bb720a5c3a6982
--- /dev/null
+++ b/MathToF/800.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在8897、6998、6123、7003四个数中，7003最接近7000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分别求出各个数与7000的差，差最小的数就和7000最接近.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/801.json b/MathToF/801.json
new file mode 100644
index 0000000000000000000000000000000000000000..1da851f0bda5941b4d97fc6556e2ad97f257a5c6
--- /dev/null
+++ b/MathToF/801.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2×6=12，所以12的因数只有2和6"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由题意可知:12的因数有:1、2、3、4、6、12;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/802.json b/MathToF/802.json
new file mode 100644
index 0000000000000000000000000000000000000000..3b7f5d7d3c1a714ed2e7308843daf1c36f53b954
--- /dev/null
+++ b/MathToF/802.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算乘数中间有0的乘法时，可以直接把0去掉。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "乘数中间有0时，这个0也要乘，与0相乘时，如果有进位数一定要加上进位数;如果没有进位数，就写0占位。 故此题说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/803.json b/MathToF/803.json
new file mode 100644
index 0000000000000000000000000000000000000000..64665a51d5d6f52c182a5446aac73afce07493c1
--- /dev/null
+++ b/MathToF/803.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一年中有6个大月、6个小月"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一年中有7个大月，4个小月，2月不是大月也不是小月."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/804.json b/MathToF/804.json
new file mode 100644
index 0000000000000000000000000000000000000000..12ecf9ea5fb7ac112a38c7a67a71903611087df9
--- /dev/null
+++ b/MathToF/804.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根绳子先对折一次，再对折一次，每一小段的长是这根绳子的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "对折2次，将绳子平均分成了4段.每段是这根绳子的 \\frac{1}{4}，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/805.json b/MathToF/805.json
new file mode 100644
index 0000000000000000000000000000000000000000..e5b930d7383cd5d6acf5a967707d13e769b9abdc
--- /dev/null
+++ b/MathToF/805.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小李家在小张家的北面，那么小张家在小李家的南面"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "小李家在小张家的北面，是以小张家为观测点，小张家在小李家的什么方向，是以小李家家为观测点，那么小张家在小李家的南面."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/806.json b/MathToF/806.json
new file mode 100644
index 0000000000000000000000000000000000000000..b0dd63b833bd65571cc68094fc6fbb2bc7f4338c
--- /dev/null
+++ b/MathToF/806.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三位数乘一位数，三位数的末尾有0，积的末尾就一定有0;三位数中间有0，积的中间也就一定有0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，假设三位数是105，一位数是5，或三位数是103，一位数是2，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/807.json b/MathToF/807.json
new file mode 100644
index 0000000000000000000000000000000000000000..965b66863d9f47078f196312632853c2d2fcd672
--- /dev/null
+++ b/MathToF/807.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形有一个角是锐角，那么这个三角形是锐角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据锐角三角形的意义，即可进行判断，有一个角是锐角，另外两个角可能是直角或者钝角，则这个三角形为直角三角形或钝角三角形，所以原说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/808.json b/MathToF/808.json
new file mode 100644
index 0000000000000000000000000000000000000000..f52c618972cfc819259cab261b1a013a1cf278f1
--- /dev/null
+++ b/MathToF/808.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把12分解质因数是:12=1×2×2×3"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分解质因数就是把一个合数写成几个质数的连乘形式，由此定义即可进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/809.json b/MathToF/809.json
new file mode 100644
index 0000000000000000000000000000000000000000..a7c66f17c2de76d6907be42b56428d3edc8ff1d3
--- /dev/null
+++ b/MathToF/809.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "张师傅加工了98个零件，全部合格，零件的合格率是98%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "合格率即合格零件个数占生产零件总个数的百分之几，根据‘合格率= \\frac{合格产品数}{产品总数}×100%‘，列出算式即可得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/81.json b/MathToF/81.json
new file mode 100644
index 0000000000000000000000000000000000000000..7a623c7e28c46a9b77352eb36fe11af49c4ccc10
--- /dev/null
+++ b/MathToF/81.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "已知5x-3y=0，那么x与y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "判断两个量是否成比例，就看这两种量是否是对应的乘积(商)一定，如果是乘积(商)一定，就成反(正)比例，如果不是乘积(商)一定或乘积(商)不一定，就不成比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/810.json b/MathToF/810.json
new file mode 100644
index 0000000000000000000000000000000000000000..7fc2ea52a028bf98cd08cd18b8ba381eae2051a3
--- /dev/null
+++ b/MathToF/810.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在100克水中放入5克盐，那么盐水的含盐率就是5%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "含盐率，即盐水中盐的重量占盐水重量的百分之几，计算公式为: \\frac{盐的重量}{盐水的重量}×100%，由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/811.json b/MathToF/811.json
new file mode 100644
index 0000000000000000000000000000000000000000..378e9cd01d4d7610d175236ea9ca3f677cfdcd67
--- /dev/null
+++ b/MathToF/811.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "用一张边长12.56分米的正方形纸卷成一个圆柱形纸筒，卷成的圆柱形纸筒的底面半径最大是2分米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆柱的特征，圆柱的侧面展开是一个长方形(正方形是特殊的长方形)，这个长方形的长等于圆柱的底面周长，根据圆的周长公式:c=2πr，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/812.json b/MathToF/812.json
new file mode 100644
index 0000000000000000000000000000000000000000..93f93f768b87e24e32dfba36676360f2b32358ff
--- /dev/null
+++ b/MathToF/812.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "西安大雁塔高六十四米，‘六十四‘写作‘604‘。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "六十四写作64，所以原说法错误"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/813.json b/MathToF/813.json
new file mode 100644
index 0000000000000000000000000000000000000000..65571c4cb94ec14b861a791269547b6ce671d2de
--- /dev/null
+++ b/MathToF/813.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{3}{8}+ \\frac{5}{8}× \\frac{3}{4}=1× \\frac{3}{4}= \\frac{3}{4}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "按照先算乘法，再算加法的顺序，求出题干中算式的值，再与 \\frac{3}{4}比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/814.json b/MathToF/814.json
new file mode 100644
index 0000000000000000000000000000000000000000..357c892e0b0200e7f225be7fa1ebdafc2af5ab9f
--- /dev/null
+++ b/MathToF/814.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数除法法则:除以一个数等于乘以这个数的倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数除法的计算法则是:甲数除以乙数(0除外)，等于甲数乘乙数的倒数，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/815.json b/MathToF/815.json
new file mode 100644
index 0000000000000000000000000000000000000000..3da8a180d00e5cdfae37fc46644d4254047bd677
--- /dev/null
+++ b/MathToF/815.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数除以4，商是3，余数是5，这个数是17。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "解答根据题意可知要求被除数可以列式4×3+5=17考察在有余数的除法中如何求被除数，根据被除数=商×除数+余数进行计算。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/816.json b/MathToF/816.json
new file mode 100644
index 0000000000000000000000000000000000000000..c6e6042c1cf912b7c2fff2ec415f299530845529
--- /dev/null
+++ b/MathToF/816.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "和10万相邻的两个数99999与100001"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "和100000相邻的两个数分别比100000多1和少1，即100000+1，100000-1，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/817.json b/MathToF/817.json
new file mode 100644
index 0000000000000000000000000000000000000000..82c7579a223301bf4d2947fceb39a6d6670efc79
--- /dev/null
+++ b/MathToF/817.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把70.2的小数点先向左移动三位，再向右移动两位，结果是7.02"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把70.2的小数点先向左移动三位，再向右移动两位，相当于把这个数的小数点向左移动了一位，是7.02;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/818.json b/MathToF/818.json
new file mode 100644
index 0000000000000000000000000000000000000000..380dcd1771aae37fcd632d68beb7f1df61ee81be
--- /dev/null
+++ b/MathToF/818.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1米的 \\frac{7}{8}和7米的 \\frac{1}{8}一样长"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数乘法的意义:求一个数的几分之几是多少，就用这个数乘几分之几列式计算;所以用1乘 \\frac{7}{8}求出1米的 \\frac{7}{8}是多少米，再用7乘 \\frac{1}{8}求出7米的 \\frac{1}{8}是多少米.然后比较大小即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/819.json b/MathToF/819.json
new file mode 100644
index 0000000000000000000000000000000000000000..79d08f807c19dc7d702b7c62c163aaa53c203d99
--- /dev/null
+++ b/MathToF/819.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在100克的水中加入10克的糖，糖占糖水的10%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "100克水中加入10克糖，则糖水为100+10(克)，用糖的量除以糖水的量，求出糖占糖水的百分比，再与10%比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/82.json b/MathToF/82.json
new file mode 100644
index 0000000000000000000000000000000000000000..29896a1b54b110d7c7bb6a4c72a932d605d692a8
--- /dev/null
+++ b/MathToF/82.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.1和0.2之间有10个小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数比较大小的方法，可得大于0.1小于0.2两位小数有9个:0.11，0.12，0.13，…，0.18，0.19，还有三位小数，四位小数等等，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/820.json b/MathToF/820.json
new file mode 100644
index 0000000000000000000000000000000000000000..0dab3f97ebd03f891b95172b05fee743ad9d5944
--- /dev/null
+++ b/MathToF/820.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相除，商一定小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据在商非零的除法里，被除数大于除数，商大于1，被除数小于除数，商小于1，被除数等于除数，商等于1，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/821.json b/MathToF/821.json
new file mode 100644
index 0000000000000000000000000000000000000000..4e13388ade0e8ce062325388bac382dc090b99f5
--- /dev/null
+++ b/MathToF/821.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆有无数条对称轴。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "圆的直径是圆对称轴，圆的直径有无数条，由此可知答案。 考点:圆的对称性。 总结:本题主要考察圆的对称性的掌握情况。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/822.json b/MathToF/822.json
new file mode 100644
index 0000000000000000000000000000000000000000..95ab31c0ddd570b5200e83f6d2f92cfc71b37e5e
--- /dev/null
+++ b/MathToF/822.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一段1米长的铁丝用去 \\frac{1}{5}，再接上 \\frac{1}{5}米，现在的长度和原来相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把铁丝长度看作单位‘1‘，用去 \\frac{1}{5}就剩余1- \\frac{1}{5}= \\frac{4}{5}，先运用分数乘法意义，求出剩余的长度，再加 \\frac{1}{5}米，求出铁丝现在的长度，最后与原来长度比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/823.json b/MathToF/823.json
new file mode 100644
index 0000000000000000000000000000000000000000..34848accabde1239401072acd2b8e52efc2441ea
--- /dev/null
+++ b/MathToF/823.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个圆柱削成一个最大的圆锥，这个圆柱的体积是圆锥体积的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为等底等高的圆柱的体积是圆锥的体积的3倍，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/824.json b/MathToF/824.json
new file mode 100644
index 0000000000000000000000000000000000000000..73eb5a2da5018e8511d130b3d4da1b5fc2bd339a
--- /dev/null
+++ b/MathToF/824.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数的最小倍数就是它本身"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，对各选项进行依次分析、进而得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/825.json b/MathToF/825.json
new file mode 100644
index 0000000000000000000000000000000000000000..e02e91837fecf349a4198d2d8a424555a76b9421
--- /dev/null
+++ b/MathToF/825.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "男生人数比女生人数多 \\frac{1}{4}，女生人数比男生人数少 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "本题中两个分数的单位‘1‘是不同的，可根据‘男生人数比女生人数多 \\frac{1}{4}‘求得女生人数比男生人数少几分之几，再与 \\frac{1}{5}比较即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/826.json b/MathToF/826.json
new file mode 100644
index 0000000000000000000000000000000000000000..7686943e4ad7f08ebad93cf2df3ad315b291068b
--- /dev/null
+++ b/MathToF/826.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "71里面最多有18个4"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要求71里面最多有几个4，用71除以4所得的整数商，即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/827.json b/MathToF/827.json
new file mode 100644
index 0000000000000000000000000000000000000000..cf8d951cd8ca4112a86a84f003d4427c88f4bb85
--- /dev/null
+++ b/MathToF/827.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{1}{3}+ \\frac{2}{3}× \\frac{4}{5}=( \\frac{1}{3}+ \\frac{2}{3})× \\frac{4}{5}=1× \\frac{4}{5}= \\frac{4}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "按照先算乘法，再算加法的顺序，求出题干中算式的值，最后与 \\frac{4}{5}比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/828.json b/MathToF/828.json
new file mode 100644
index 0000000000000000000000000000000000000000..50efa4bafa468e3fed59c3bffb0c592d61862829
--- /dev/null
+++ b/MathToF/828.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个偶数的和一定是偶数，那么两个奇数的和一定是奇数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据偶数与奇数的性质:奇数+奇数=偶数，偶数+偶数=偶数，奇数+偶数=奇数.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/829.json b/MathToF/829.json
new file mode 100644
index 0000000000000000000000000000000000000000..87eed3905b61eb14f8aabcfb5218113cad383e3a
--- /dev/null
+++ b/MathToF/829.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把如图的线段比例尺改写成数值比例尺是1:40000"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据线段比例尺的意义，即图上距离1厘米表示实际距离40千米，再据‘比例尺=图上距离:实际距离，即可将线段比例尺转化成数值比例尺."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/83.json b/MathToF/83.json
new file mode 100644
index 0000000000000000000000000000000000000000..06be7ba1191a74e31ec52c9e996077c1605b4e09
--- /dev/null
+++ b/MathToF/83.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{4}{5}× \\frac{1}{2}× \\frac{5}{2}=1，所 \\frac{4}{5}、 \\frac{1}{2}和 \\frac{5}{2}互为倒数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据倒数的意义:乘积是1的两个数互为倒数.说明互为倒数的是两个数，不是三个数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/830.json b/MathToF/830.json
new file mode 100644
index 0000000000000000000000000000000000000000..fd5ecac0d673426bbaa35ddb14e60684dfa3f39c
--- /dev/null
+++ b/MathToF/830.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "25×25-5和25×(25-5)的计算结果一样"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "25×25-5先算乘法，再算减法;25×(25-5)先算减法，再算乘法，分别求出它们的结果，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/831.json b/MathToF/831.json
new file mode 100644
index 0000000000000000000000000000000000000000..17f23b78b145c970828fa12a5677631befb45727
--- /dev/null
+++ b/MathToF/831.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任何数的倒数都比这个数本身大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "设一个数是a，根据互为倒数的两个数的乘积是1，用1除以a，即可求出它的倒数，然后分三种情况比较大小即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/832.json b/MathToF/832.json
new file mode 100644
index 0000000000000000000000000000000000000000..eb9c6eb556769abe734f0ae5cd0ad20be0481ff5
--- /dev/null
+++ b/MathToF/832.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "24× □7的积最大是2328。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "当□=9的时候，24× □7最大，24*97=2328。正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/833.json b/MathToF/833.json
new file mode 100644
index 0000000000000000000000000000000000000000..86689c7b86673ad2e9d9e0558b515611a361d0ce
--- /dev/null
+++ b/MathToF/833.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘的积一定大于这两个数相加的和"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题可以利用赋值法，举例子解答.比如2*2=4，2+2=4，所以不是两个数相乘的积一定大于这两个数相加的和，也有可能小于或等于"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/834.json b/MathToF/834.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c6e3c59bcf55c70f95d9b93d1d2d3a8e57f1b72
--- /dev/null
+++ b/MathToF/834.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形的三个内角的度数比是2:3:5，这个三角形一定是直角三角形."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "5+3+2=10，  最大的角:180°×  =90°，所以这个三角形是直角三角形.  正确.  因为三角形的内角度数和是180°，三角形的最大的角的度数占内角度数和的  ，根据一个数乘分数的意义，求出最大角，进而判断即可.解答此题应明确三角形的内角度数的和是180°，求出最大的角的度数，然后根据三角形的分类判定类型."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/835.json b/MathToF/835.json
new file mode 100644
index 0000000000000000000000000000000000000000..1540f82ff49e3a4c44153e6a6e5c2297e42be5b0
--- /dev/null
+++ b/MathToF/835.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "判断对错。 最大的三位数比最小的三位数大998。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最大三位数的是999，最小三位数是100，它们的差是999-100，据此解答即可。 最大三位数的是999，最小三位数是100， 999-100=899 最大的三位数比最小的三位数大899。 原题说法错误。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/836.json b/MathToF/836.json
new file mode 100644
index 0000000000000000000000000000000000000000..750b8f212d0dcd3eee15ea857ba01c6287daeab0
--- /dev/null
+++ b/MathToF/836.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个圆柱削成一个和它等底等高的圆锥，削去部分的体积是圆锥体积的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "圆柱的体积等于与它等底等高的圆锥的体积的3倍，那么削去部分的体积就应该是圆柱体体积的 \\frac{2}{3}，即削去部分的体积是圆锥体积的2倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/837.json b/MathToF/837.json
new file mode 100644
index 0000000000000000000000000000000000000000..48956484f642e66d3223cb7590d55170d345d570
--- /dev/null
+++ b/MathToF/837.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小数2.52中，两个2表示的意义相同。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个2表示的意义相同，一个是个位上的2，一个是百分位上的2."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/838.json b/MathToF/838.json
new file mode 100644
index 0000000000000000000000000000000000000000..89a2e55d2e9bf6b07dcbf7b9ab5c8646afeedc6f
--- /dev/null
+++ b/MathToF/838.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果a÷0.98=b÷1(a、b都不等于零)，那么a<b"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "因为a÷0.98=b÷1，所以a÷0.98=b，又因为a、b都不等于零且0.98a，所以b>a."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/839.json b/MathToF/839.json
new file mode 100644
index 0000000000000000000000000000000000000000..8ca65f9cf9cceadaaf983bb6f801175b008e6248
--- /dev/null
+++ b/MathToF/839.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求10的5倍是多少，列式为10÷5"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "[解答]解:应为乘法计算  [分析]求一个数的几倍是多少，就用这个数乘几."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/84.json b/MathToF/84.json
new file mode 100644
index 0000000000000000000000000000000000000000..495ff908c0306151d93e88cb83cfdf500539e547
--- /dev/null
+++ b/MathToF/84.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "判断对错。 用一个直角和一个锐角拼出的角一定是钝角。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据钝角、直角、锐角的含义可知:锐角是大于0°小于90°的角;直角是等于90°的角;钝角是大于90°小于180°的角;所以直角+锐角=钝角，据此解答。 根据钝角、直角、锐角的含义可知:一个直角和一个锐角拼出的角一定是钝角。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/840.json b/MathToF/840.json
new file mode 100644
index 0000000000000000000000000000000000000000..ebe194e8eb429d3874a8f19951e177d72035f3ce
--- /dev/null
+++ b/MathToF/840.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "口3×口7的积的个位数字一定是1."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "口3×口7积的个位数字，是口3与口7个位数3×7的积个位数，然后再进一步解答即可. 解:3×7=21;21的个位数是1;那么，口3×口7积的个位数字一定是1. 故答案为:正确."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/841.json b/MathToF/841.json
new file mode 100644
index 0000000000000000000000000000000000000000..16881e9003ad8b8c7dfc2fc708d93a92c0f3b1fa
--- /dev/null
+++ b/MathToF/841.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "396×7的积大约是2800"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据整数估算方法，把数看成最接近它的整十、整百数…"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/842.json b/MathToF/842.json
new file mode 100644
index 0000000000000000000000000000000000000000..2c691d1ffd157dc561cdf5d7201745aa6d3db0f0
--- /dev/null
+++ b/MathToF/842.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5620÷70=562÷7，因为562除以7的商是80，余数是2，所以5620除以70的商也是80，余数是2"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在有余数的除法算式中，被除数和除数同时扩大或缩小相同的倍数(0除外)，商不变;但余数也要同时扩大或缩小相同的倍数;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/843.json b/MathToF/843.json
new file mode 100644
index 0000000000000000000000000000000000000000..95eaef3a30035d006310a473be40a36797b80ef5
--- /dev/null
+++ b/MathToF/843.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任意两个奇数的和，一定是偶数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据奇数、偶数的性质:奇数+奇数=偶数，奇数+偶数=奇数，偶数+偶数=偶数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/844.json b/MathToF/844.json
new file mode 100644
index 0000000000000000000000000000000000000000..f179f96bf093866d231f2b02e16a3a9738d1982a
--- /dev/null
+++ b/MathToF/844.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "将54999四舍五入到万位时约是6万"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把54999四舍五入到万位就是省略‘万‘后面的尾数求它的近似数，要把万位的下一位千位上的数进行四舍五入，再在数的后面写上‘万‘字."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/845.json b/MathToF/845.json
new file mode 100644
index 0000000000000000000000000000000000000000..932c924335fb4e09387bb4c433539bfc1d59cfc0
--- /dev/null
+++ b/MathToF/845.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8个球队进行循环比赛(每两个球队都要比赛一次)，一共要进行16场比赛。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "8×(8-1)÷2=56÷2=28(场)。所以一共要进行28场比赛。  错误.  本题考点:握手问题.  在循环赛制中，参赛人数和比赛场数的关系为:比赛场数=参赛人数×(参赛人数-1)÷2.  8支球队举行比赛，若每个球队与其他队比赛(8-1)场，则两队之间比赛两场，由于是单循环比赛，则共比赛 8×(8-1)÷2场."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/846.json b/MathToF/846.json
new file mode 100644
index 0000000000000000000000000000000000000000..3018d9e275052521e09e81a9226a38aa9b15f062
--- /dev/null
+++ b/MathToF/846.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算:1- \\frac{4}{7}+ \\frac{3}{7}=1-( \\frac{4}{7}+ \\frac{3}{7})=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，由运算顺序就可以判断出结果的正误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/847.json b/MathToF/847.json
new file mode 100644
index 0000000000000000000000000000000000000000..d0c92ea97a17ab8fc02596d1b3ddaf9801172d8f
--- /dev/null
+++ b/MathToF/847.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1头牛重250千克，4头牛约重1吨"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1头牛重250千克，4头牛约重就是4个250千克，是1000千克=1吨."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/848.json b/MathToF/848.json
new file mode 100644
index 0000000000000000000000000000000000000000..62ce5baf1452047c64e151aa03d0c3e43f68f977
--- /dev/null
+++ b/MathToF/848.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一瓶可乐3元，32元最多可以买11瓶。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "几倍和大约几倍的问题 根据除法笔算方法，先计算:32÷3=10(瓶)…2(元);即32是3的10倍多一些，买不了11瓶，据此判断即可。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/849.json b/MathToF/849.json
new file mode 100644
index 0000000000000000000000000000000000000000..98b5e73899ebef19472fae1f277cecbb1f6b7863
--- /dev/null
+++ b/MathToF/849.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "四位数减三位数，所得的差一定是三位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "举反例进行判断，例如1000-999."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/85.json b/MathToF/85.json
new file mode 100644
index 0000000000000000000000000000000000000000..55bf68718726725ac5b5c1706e173f60a7180db4
--- /dev/null
+++ b/MathToF/85.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个西瓜分成6块，小刚吃了2块，吃了这个西瓜的 \\frac{2}{6}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个西瓜分成6份，而不是‘平均分成6份‘，根据分数的意义可知，必须得是‘平均分‘，所以题干说法错误，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/850.json b/MathToF/850.json
new file mode 100644
index 0000000000000000000000000000000000000000..8b85b48e0f0de1c5bc1730f4592c3c8e873fb9d7
--- /dev/null
+++ b/MathToF/850.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方体的棱长之和是96厘米，它的表面积是96平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "解答此题应该先求棱长，用棱长和除以12即得棱长，再根据正方体的表面积=棱长×棱长×6，代入公式计算即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/851.json b/MathToF/851.json
new file mode 100644
index 0000000000000000000000000000000000000000..1fb528a19bc915b92bf16348070a6eed39234302
--- /dev/null
+++ b/MathToF/851.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在有余数的除法中，被除数和除数同时扩大相同的倍数，商和余数都不变。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            ""
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/852.json b/MathToF/852.json
new file mode 100644
index 0000000000000000000000000000000000000000..5e3cb934265b823486cbac1ce979f0706e054465
--- /dev/null
+++ b/MathToF/852.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个圆的面积相等，周长也一定相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆的面积公式:s=π\\( r^{2} \\)，周长公式:c=2πr，如果两个圆的面积相等，又因为圆周率是一定的，所以两个圆的半径一定相等，所以它们的周长一定相等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/853.json b/MathToF/853.json
new file mode 100644
index 0000000000000000000000000000000000000000..9c4c874acdea76d1866e7972fee3384c5e13e3eb
--- /dev/null
+++ b/MathToF/853.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "2.7+1.3-2.7+1.3=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "按照从左向右的顺序进行计算，计算出结果，与原题比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/854.json b/MathToF/854.json
new file mode 100644
index 0000000000000000000000000000000000000000..94d834af035fd51e4de839a1cdb34a1dd1059c53
--- /dev/null
+++ b/MathToF/854.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "有一个角是60°的等腰三角形一定是等边三角形."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "假设已知度数的角是底角， 则另一个底角也是60°，  于是求得顶角为180°-60°×2=60°，  所以这个三角形是等边三角形;  假设这个角是顶角，  则每个底角的度数为(180°-60°)÷2=60°，  所以这个三角形是等边三角形.  正确.  由等腰三角形的特点可知:等腰三角形的两个底角相等，再据三角形的内角和是180度，即可求得三角形的另外两个角的度数，从而判定这个等腰三角形是否是等边三角形."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/855.json b/MathToF/855.json
new file mode 100644
index 0000000000000000000000000000000000000000..ab90d885d6c364d0d2dae8adb75d73c885a74c49
--- /dev/null
+++ b/MathToF/855.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{2}{8}和 \\frac{1}{4}的大小相等，所以它们的分数单位相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "判定一个分数的单位看分母，分母是几，分数单位就是几分之一."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/856.json b/MathToF/856.json
new file mode 100644
index 0000000000000000000000000000000000000000..046e2ab637d847e68d2eb7bb04d6c0d20073cfdb
--- /dev/null
+++ b/MathToF/856.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个平行四边形框架可拉成长方形框架"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "1因为平行四边形具有易变性，所以可以把将一个平行四边形拉成长方形，因为四边长度不变，可知周长不变;底边不变，高变长，可知面积变大，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/857.json b/MathToF/857.json
new file mode 100644
index 0000000000000000000000000000000000000000..6c796efa6bc821c2f5969f4c9aaacf39abe0be42
--- /dev/null
+++ b/MathToF/857.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "只能用条形统计图来表示病人体温的变化情况"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/858.json b/MathToF/858.json
new file mode 100644
index 0000000000000000000000000000000000000000..b47a09eb7452e31bcf40df3d691151969e61fa6f
--- /dev/null
+++ b/MathToF/858.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个数，个位上是最小的质数，十位上是最小的偶数，百位上是最小的合数，这个数是421。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最小的质数是2，最小的偶数是0，最小的合数是4，所以这个数是402。 故题目中说法错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/859.json b/MathToF/859.json
new file mode 100644
index 0000000000000000000000000000000000000000..62e1b0f69a5aed2ae81b27ea1bf161da9acad631
--- /dev/null
+++ b/MathToF/859.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "长方体的6个面中不可能有正方形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方体的特征，6个面都是长方形(特殊情况有两个相对的面是正方形)，相对面的面积相等.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/86.json b/MathToF/86.json
new file mode 100644
index 0000000000000000000000000000000000000000..c5feb2e38bbfdf47ac5b10ce09315fc53c26387e
--- /dev/null
+++ b/MathToF/86.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "每头水牛350千克，三头这样的水牛大约1吨重"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据每头水牛的重量乘数量即可估算出3头水牛的总重量，把350千克看作400进行估算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/860.json b/MathToF/860.json
new file mode 100644
index 0000000000000000000000000000000000000000..90687690c621f78e8c31509a4a9d8e042fea9ab3
--- /dev/null
+++ b/MathToF/860.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3个外形、颜色都相同的小球，有一个与另外两个质量不同，用天平称1次，保证能把它找出来。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "任意选两个小球，天平两边各放一个，如果天平平衡，剩下的一个是质量不同的，如果不平衡，无法判断天平上哪一个是次品。 3个外形、颜色都相同的小球，有一个与另外两个质量不同，用天平称1次，保证能把它找出来，这个说法是错误的。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/861.json b/MathToF/861.json
new file mode 100644
index 0000000000000000000000000000000000000000..5bbf7578526d4f642e11ef8b6be715736959ac05
--- /dev/null
+++ b/MathToF/861.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在100克水中加入2克盐，这种盐水的含盐率是2%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在100克水中加入2克盐，这种盐水的含盐率是2%，说法错误，含盐率应为: \\frac{2}{2+100}×100%≈2.0%;据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/862.json b/MathToF/862.json
new file mode 100644
index 0000000000000000000000000000000000000000..51fc159dd99ebe3df239e082e0311dea6b4b6ea8
--- /dev/null
+++ b/MathToF/862.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个物体如个从正面、侧面和上面三个不同的角度去观察，所看到的图形一定各不相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题考查图形的三视图，要注意特殊图形:如正方体、球体，从正面、侧面、上面观察看到的图形都一样，据此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/863.json b/MathToF/863.json
new file mode 100644
index 0000000000000000000000000000000000000000..a8fc4d1e650575fa69aa457f0220ab756c6f9b5c
--- /dev/null
+++ b/MathToF/863.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1米的 \\frac{3}{5}就等于3米的 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据分数的意义可知，1米的 \\frac{3}{5}是1× \\frac{3}{5}= \\frac{3}{5}米，3米的 \\frac{1}{5}是3× \\frac{1}{5}= \\frac{3}{5}米，即1米的 \\frac{3}{5}就等于3米的 \\frac{1}{5}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/864.json b/MathToF/864.json
new file mode 100644
index 0000000000000000000000000000000000000000..b8fe7d59cd69cd8c92fcc59aad373afee49a9ac9
--- /dev/null
+++ b/MathToF/864.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "真分数的倒数一定大于1，假分数的倒数一定小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "真分数:是指分子小于分母的分数;假分数:是指分子大于或等于分母的分数;再根据乘积是1的两个数互为倒数，所以用1除以一个真分数就得一个假分数，这个假分数一定大于1;用1除以一个假分数就得一个真分数或得1，这个分数是小于或等于1;据此进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/865.json b/MathToF/865.json
new file mode 100644
index 0000000000000000000000000000000000000000..e0f47acd6789b51a52bfbb77bd22add006c15408
--- /dev/null
+++ b/MathToF/865.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把0.7、 \\frac{9}{10}、0.25、 \\frac{43}{100}、 \\frac{7}{25}这5个数把它们从大到小的顺序排列是 \\frac{9}{10}、0.7、 \\frac{43}{100}、 \\frac{7}{25}、0.25"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "首先根据分数和小数之间互化的方法，把其中的分数都化成小数;然后根据小数大小比较的方法，把0.7、 \\frac{9}{10}、0.25、 \\frac{43}{100}、 \\frac{7}{25}这5个数按从大到小的顺序排列即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/866.json b/MathToF/866.json
new file mode 100644
index 0000000000000000000000000000000000000000..d4fb09c214944452dfcbf0a10383622c05210b3d
--- /dev/null
+++ b/MathToF/866.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任意一个带分数都一定大于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "带分数由两部分组成，整数部分和分数部分，整数部分最小是1，分数部分再小也大于0，因此，任意一个带分数都一定大于1."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/867.json b/MathToF/867.json
new file mode 100644
index 0000000000000000000000000000000000000000..45c7097f6d10cc1b02f2d5f6f21ac44b0489efa9
--- /dev/null
+++ b/MathToF/867.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "( \\frac{5}{6}- \\frac{5}{6}× \\frac{8}{15})÷1 \\frac{7}{9}=(0× \\frac{8}{15})÷1 \\frac{7}{9}=0÷1 \\frac{7}{9}=0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，应先算小括号里面的乘法，再算小括号里面的减法，最后算除法，然后再进一步解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/868.json b/MathToF/868.json
new file mode 100644
index 0000000000000000000000000000000000000000..6f094baf779426711416a1272a46b0c92b1165a4
--- /dev/null
+++ b/MathToF/868.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "画圆时，圆规两脚间的距离是半径的长度"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据圆的画法:明确画圆时圆规两脚间的距离就是圆的半径;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/869.json b/MathToF/869.json
new file mode 100644
index 0000000000000000000000000000000000000000..0dd448d2b37b8f449996a805cdd7b1d26a845dc9
--- /dev/null
+++ b/MathToF/869.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小于0.9而大于0.7的小数只有0.8"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意，只要小数的整数部分是0，十分位上数是7或8，不论小数是几位小数都符合要求."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/87.json b/MathToF/87.json
new file mode 100644
index 0000000000000000000000000000000000000000..500a695ef557e60eec9f0c14cd44f1ca08f71c4f
--- /dev/null
+++ b/MathToF/87.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "三位数减三位数差一定是三位数。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "如两个三位数分别为:150，100。则150-100=50，其差50是两位数，故题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/870.json b/MathToF/870.json
new file mode 100644
index 0000000000000000000000000000000000000000..3322308c976ff2c1115b330f384aceccdd63e358
--- /dev/null
+++ b/MathToF/870.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "全班人数一定，出勤人数和缺勤人数成反比例."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为出勤人数+缺勤人数=全班的人数(一定)， 即出勤人数与缺勤人数的和一定，既不符合正比例的意义，也不符合反比例的意义，  所以全班人数一定，出勤人数和缺勤人数不成反比例;  错误.  判断出勤人数和缺勤人数是否成反比例，就看这两种量是否是对应的乘积一定，如果是乘积一定，就成反比例，如果不是乘积一定或乘积不一定，就不成反比例."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/871.json b/MathToF/871.json
new file mode 100644
index 0000000000000000000000000000000000000000..785361ecc3705300f47bb7e08b768d864dee575e
--- /dev/null
+++ b/MathToF/871.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{9}{12}和 \\frac{3}{4}的大小相等，所以他们的分数单位也相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个分数的分母是几，它的分数单位就是几分之一，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/872.json b/MathToF/872.json
new file mode 100644
index 0000000000000000000000000000000000000000..12d2f39b1954c575e27b14708e9982fd3d2dd8e6
--- /dev/null
+++ b/MathToF/872.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "成为互质数的两个数，一定都是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "公约数只有1的两个数叫做互质数，这两个数可能都是质数，也可能都是合数，也可能是一个质数、一个合数，由此即可得出答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/873.json b/MathToF/873.json
new file mode 100644
index 0000000000000000000000000000000000000000..0247ef4b1314b41398a445873fbfe26bcc368c81
--- /dev/null
+++ b/MathToF/873.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "男生人数比女生多 \\frac{1}{5}，那么女生人数比男生少 \\frac{1}{5}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "男生人数比女生人数多 \\frac{1}{5}，是女生人数为单位‘1‘，男生是女生的1 + \\frac{1}{5}= \\frac{6}{5};女生人数比男生人数少多少，是将男生人数做为单位‘1‘，即( \\frac{6}{5}-1)÷ \\frac{6}{5}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/874.json b/MathToF/874.json
new file mode 100644
index 0000000000000000000000000000000000000000..7f883dc19b03e81be7f11ede662031ee8600dacd
--- /dev/null
+++ b/MathToF/874.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一袋苹果重5千克，200袋这样的苹果重1吨"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一袋苹果重5千克，200袋这样的苹果重200个5千克，即5×200，然后再化成吨进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/875.json b/MathToF/875.json
new file mode 100644
index 0000000000000000000000000000000000000000..ca4645a9c46e2aa70398f9b9e8705d3a209f7e1f
--- /dev/null
+++ b/MathToF/875.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "无限小数比有限小数大."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "[解答]解:无限小数，例如0.45547855…，有限小数，如1.9678; 0.45547855…<1.9678; 故答案为:错误. [分析]首先明确无限小数和有限小数的意义:小数部分的位数是有限的小数，叫做有限小数.像如1.9678是一个有限小数;小数部分的位数是无限的小数叫做无限小数;例如0.45547855…就是一个无限小数;进而举例进行分析即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/876.json b/MathToF/876.json
new file mode 100644
index 0000000000000000000000000000000000000000..5ffc26a622212362c4aeedf323bd3599cb236150
--- /dev/null
+++ b/MathToF/876.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个正方形，周长是12米，面积是 \\frac{4}{121}平方米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据正方形的周长公式:C=4a，可知a=C÷4，已知周长是12米，可求出边长是多少，再根据正方形的面积公式:S=\\( a^{2} \\)，可求出正方形的面积是多少，然后再进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/877.json b/MathToF/877.json
new file mode 100644
index 0000000000000000000000000000000000000000..b39451996403425b9ebe120b6936a275db42cca9
--- /dev/null
+++ b/MathToF/877.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最大三位数比最小的三位数多100"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "最小三位数是100，最大三位数的是999，它们的差是999-100，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/878.json b/MathToF/878.json
new file mode 100644
index 0000000000000000000000000000000000000000..7db449fac93499b58a2a925a26c4ca11a0f01874
--- /dev/null
+++ b/MathToF/878.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "10名同学进行乒乓球赛，如果每2名同学之间都进行一场比赛，一共要进行20场比赛"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据题意可知，每2名同学之间都进行一场比赛，即进行循环赛，则每人都要和其他10-1=9人进行比赛，所以10人参加比赛的场数为10×9=90场，由于比赛是在两人之间进行的，所以一共要进行90÷2=45场比赛."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/879.json b/MathToF/879.json
new file mode 100644
index 0000000000000000000000000000000000000000..477695626e36cf76c52c4e08bfe2ac51b1523087
--- /dev/null
+++ b/MathToF/879.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3.58-(1.5+2.8×4)与(3.58-1.5+2.8)×4的结果相同。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数四则混合运算的顺序，分别求出3.58-(1.5+2.8×4)与(3.58-1.5+2.8)×4的结果，再比较解答。 3.58-(1.5+2.8×4) =3.58-(1.5+11.2) =3.58-12.7 =-9.12; (3.58-1.5+2.8)×4 =(2.08+2.8)×4 =4.88×4 =19.52; -9.12<19.52; 所以，3.58-(1.5+2.8×4)<(3.58-1.5+2.8)×4。 故答案为:×。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/88.json b/MathToF/88.json
new file mode 100644
index 0000000000000000000000000000000000000000..8b318ba681acfd95d8ac99a97a9969a7d5b73675
--- /dev/null
+++ b/MathToF/88.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小明看一本书，第一天看了全书的 \\frac{1}{2}，第二天接着看了全书的 \\frac{2}{3}，刚好看完"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "将全部页数当作单位‘1‘，第一天看了全书的 \\frac{1}{2}，则还剩下全部的1- \\frac{1}{2}= \\frac{1}{2}，如果第二天全部看完，应看了全部的 \\frac{1}{2}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/880.json b/MathToF/880.json
new file mode 100644
index 0000000000000000000000000000000000000000..b196119a8d6513b48e52e26ab3d48e70855de732
--- /dev/null
+++ b/MathToF/880.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个正方形的面积相等，它们的周长也一定相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "正方形的面积=边长×边长，两个正方形的面积相等，所以两个正方形的边长就一定相等，则两个正方形的周长就相等，所以题干的说法是正确的。正确  两个正方形的面积相等，两个正方形的边长就一定相等，则两个正方形的周长就相等，由此得出判断。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/881.json b/MathToF/881.json
new file mode 100644
index 0000000000000000000000000000000000000000..50a643222e9a56f94e6b2e55b66c165420bee2ee
--- /dev/null
+++ b/MathToF/881.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3.8和3.80大小相等，计数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "3.8和3.80在大小上相等，但3.8的计数单位是0.1，表示38个十分之一;而3.80的计数单位是0.01，表示380个百分之一;由此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/882.json b/MathToF/882.json
new file mode 100644
index 0000000000000000000000000000000000000000..44348a8b859c2fac75cff210c64e6986209f38b9
--- /dev/null
+++ b/MathToF/882.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个连续自然数的和是奇数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据自然数的排列规律:偶数、奇数、偶数、奇数…;再根据偶数和奇数的性质，奇数+偶数=奇数，偶数+偶数=偶数，奇数+奇数=偶数，据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/883.json b/MathToF/883.json
new file mode 100644
index 0000000000000000000000000000000000000000..3ef0dc055ce1d3f968fe9734a6e674d7e4beb7fd
--- /dev/null
+++ b/MathToF/883.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆有无数条对称轴，圆环也有无数条对称轴"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个图形沿一条直线对折，直线两旁的部分能够完全重合，那么这个图形就是轴对称图形，这条直线就是这个图形的对称轴，由此即可解答问题."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/884.json b/MathToF/884.json
new file mode 100644
index 0000000000000000000000000000000000000000..7be69602fa3f7c9d5f5b5c71d82b7ac819f3dbd0
--- /dev/null
+++ b/MathToF/884.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把9个桃分给3个小朋友，每个小朋友分得这些桃的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把9个桃分给3个小朋友，而不是平均分给3个小朋友，不能根据除法的意义或者分数的意义进行求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/885.json b/MathToF/885.json
new file mode 100644
index 0000000000000000000000000000000000000000..72fba40cf219994a50d9a4b3dca486a0633e940e
--- /dev/null
+++ b/MathToF/885.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "扇形的圆心角度数越大，说明这一部分占总量的百分比就越大。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "扇形统计图中表示某部分的扇形占整体的百分之几，其圆心角就是占圆周角(360°)的百分之几。扇形的圆心角度数越大，说明这一部分占总量的百分比就越大。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/886.json b/MathToF/886.json
new file mode 100644
index 0000000000000000000000000000000000000000..8ab90b5cffda697909997e3cd677ad9690cfeb17
--- /dev/null
+++ b/MathToF/886.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "科技书有48本，比故事书少 \\frac{1}{4}，求故事书的本数就是求48本的(1- \\frac{1}{4})是多少"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "科技书有48本，比故事书少 \\frac{1}{4}，即将故事书的本数当作单位‘1‘，科技书是故事书的1- \\frac{1}{4}，即是已知故事书的1- \\frac{1}{4}是48本，求故事书是多少，用除法:48÷(1- \\frac{1}{4})."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/887.json b/MathToF/887.json
new file mode 100644
index 0000000000000000000000000000000000000000..a3cf9f6a43ec66ff5a2e9d7c94e74e939f6ede39
--- /dev/null
+++ b/MathToF/887.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "桔子产量的 \\frac{4}{5}等于苹果的产量，是把苹果的产量看作单位‘1‘的量"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据判断单位‘1‘的方法:一般是把‘比、占、是、相当于‘后面的量看作单位‘1‘，即分数‘的‘字前面的量看作单位‘1‘，进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/888.json b/MathToF/888.json
new file mode 100644
index 0000000000000000000000000000000000000000..23f17f64eec13ae6df5961479447f41cf323f25c
--- /dev/null
+++ b/MathToF/888.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "从上午8:30开始，经过4小时30分，是下午1时30分"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "上午8:30就是8时30分，用8时30分加4时30分就是结束的时间."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/889.json b/MathToF/889.json
new file mode 100644
index 0000000000000000000000000000000000000000..262d3689746564bf7a545263e14d6052a10b328d
--- /dev/null
+++ b/MathToF/889.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分子和分母是两个不同的质数，这个分数一定是最简分数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "分子与分母只有公因数1即分子与分母互质的分数为最简分数.两个不同的质数一定互质，所以分子和分母是两个不同的质数，这个分数一定是最简分数，正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/89.json b/MathToF/89.json
new file mode 100644
index 0000000000000000000000000000000000000000..a410114dde316f4f6bd583223a365b39f832d03a
--- /dev/null
+++ b/MathToF/89.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个七位数比较大小，若百万位上的数字相同，则比较十万位上的数字"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "比较两个整数的大小，首先看这两个整数的位数是否相同，如果位数不同，位数多的大于位数少的，如果位数相同，相同数位上大的数就大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/890.json b/MathToF/890.json
new file mode 100644
index 0000000000000000000000000000000000000000..b25510edb32164731da1697395d787f80ae43bc9
--- /dev/null
+++ b/MathToF/890.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个棱长是5厘米的立方体拼成一个长方体，这个长方体的表面积比这两个立方体的表面积之和要小"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据两个正方体拼组一个长方体的特点可知，拼组后的表面积正好减少了原来正方体的2个面的面积，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/891.json b/MathToF/891.json
new file mode 100644
index 0000000000000000000000000000000000000000..e99c58705931eff86918a6f0727a273aaf83a832
--- /dev/null
+++ b/MathToF/891.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘的积一定大于两个数相加的和。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "可以举反例来解答，如1×1=1，1+1=2，因为1<2，故原题干错误。  解答此题要知道:要知道特别的情况，可以举反例来解答此题。注意有关0与1的情况。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/892.json b/MathToF/892.json
new file mode 100644
index 0000000000000000000000000000000000000000..d6d9d33b28604a0bb15fcf6cece34a686daf12db
--- /dev/null
+++ b/MathToF/892.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "由6个一百万和3个十组成的数写作:600030"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "这是一个七位数，最高位百万位上是6，十位上是3，写这个数时，从高位到低位，一级一级地写，哪一个数位上一个计数单位也没有，就在那个数位上写0;据此写出."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/893.json b/MathToF/893.json
new file mode 100644
index 0000000000000000000000000000000000000000..747daac7f62e5c89fbd909ee6059f8d9dcf8693a
--- /dev/null
+++ b/MathToF/893.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一组数据的平均数是72，这组数据中最大的数一定比72小"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为在一组数中有最大的数，也有最小的数，根据平均数的含义:平均数是指在一组数据中所有数据之和再除以数据的个数;所以平均数比最大的数小，比最小的数大;进而得出结论."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/894.json b/MathToF/894.json
new file mode 100644
index 0000000000000000000000000000000000000000..ffd6afc82c1214db34dcf3942e1feff2dd7ff878
--- /dev/null
+++ b/MathToF/894.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，一个因数乘2，另一个因数乘2，积也乘2."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分析:两个因数相乘，一个因数乘2，另一个因数乘2，即一个因数扩大2倍，另一个因数扩大2倍，根据积的变化规律可知，积应扩大2×2=4倍，即积乘4. 解答:两个数相乘，一个因数乘2，另一个因数乘2，积乘4; 故答案为:×. 点评:积的变化规律有:一个因数扩大n倍，另一个因数不变，则积也扩大n倍.一个因数扩大n倍，另一个因数扩大m倍，则积也扩大m×n倍，一个因数扩大n倍，另一个因数缩小n倍，则积不变等."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/895.json b/MathToF/895.json
new file mode 100644
index 0000000000000000000000000000000000000000..78ff7278d7cdf0bccc281755a6a280bb7902d57c
--- /dev/null
+++ b/MathToF/895.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "27里面有3个9。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据‘三九二十七‘的乘法口诀，解答此题即可。 27÷9=3 所以27里面有3个9。 故答案为:√。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/896.json b/MathToF/896.json
new file mode 100644
index 0000000000000000000000000000000000000000..0f9a3944e4d205b24baea0903878dcfe8fe5a2f2
--- /dev/null
+++ b/MathToF/896.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把两个完全一样的正方形拼成一个长方形，拼成的长方形的周长是原来每个正方形周长的2倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "两个大小一样的长方形拼成一个大长方形时，有两种情况:以长边相连或以宽边相连，所以拼成后的大长方形的周长都比原来的两个长方形的周长之和减少了2条长或2条宽的长度，据此即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/897.json b/MathToF/897.json
new file mode 100644
index 0000000000000000000000000000000000000000..9128b5e12b3b4baff8f373ef6a8e21d69a638414
--- /dev/null
+++ b/MathToF/897.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "王师傅今天加工零件60个，比昨天多加工 \\frac{1}{5}，昨天加工多少个?应列式为:60÷(1+ \\frac{1}{5})"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把昨天加工的数量看成单位‘1‘，今天加工的数量是昨天的(1+ \\frac{1}{5})，它对应的数量是60个，由此用除法求出昨天加工的数量."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/898.json b/MathToF/898.json
new file mode 100644
index 0000000000000000000000000000000000000000..09ef5aec51e3c9c49afa33bb2a726286f3a9acab
--- /dev/null
+++ b/MathToF/898.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "爸爸走路速度很快，1分钟可以走1千米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据情景根据生活经验，对长度单位和数据大小的认识，可知爸爸走路速度很快，1分钟可以走60米."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/899.json b/MathToF/899.json
new file mode 100644
index 0000000000000000000000000000000000000000..b187decd0c14703ae3b287ef63e8adea6a21aff5
--- /dev/null
+++ b/MathToF/899.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{2}{3}和 \\frac{8}{12}的大小相等，分数单位也相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "比较两个分数的大小，首先通分，化为同分母分数即可比较大小;再看分母确定分数单位."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/9.json b/MathToF/9.json
new file mode 100644
index 0000000000000000000000000000000000000000..5095dbe4ae32fe156eaa7121d3fd4af7f1ff06d0
--- /dev/null
+++ b/MathToF/9.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲数的 \\frac{1}{2}和乙数的 \\frac{1}{4}相等，甲数是乙数的50%"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "由题意可知:甲数× \\frac{1}{2}=乙数× \\frac{1}{4}，于是逆运用比例的基本性质，即两内项之积等于两外项之积，即可求出两个数的比，问题即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/90.json b/MathToF/90.json
new file mode 100644
index 0000000000000000000000000000000000000000..668e39908ecb5a8cc25570e87a79318a3a5206d7
--- /dev/null
+++ b/MathToF/90.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "与100000相邻的两个自然数是99999和100001"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "和100000相邻的两个数分别比100000多1和少1，即100000+1，100000-1，然后再进一步解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/900.json b/MathToF/900.json
new file mode 100644
index 0000000000000000000000000000000000000000..e40fd97d391ebc036501725de020e201d929ea45
--- /dev/null
+++ b/MathToF/900.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "有两块花布，第一块比第二块长20%，第二块就比第一块短20%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "第一块比第二块长20%，即第一块长度是第二块的1+20%，则第二块比第一块短20%÷(1+20%)."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/901.json b/MathToF/901.json
new file mode 100644
index 0000000000000000000000000000000000000000..a29af64d6b6fe7e320f08ea1f37a9142a2c20e6e
--- /dev/null
+++ b/MathToF/901.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "不改变0.7的值，改写成以千分之一为计数单位的数是0.007。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "以千分之一为计数单位是以三位小数（0.001）为计数单位，则0.7以千分之一为计数单位为0.700."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/902.json b/MathToF/902.json
new file mode 100644
index 0000000000000000000000000000000000000000..fc60812d70f8165b2552ed341f17d8debe3f4a33
--- /dev/null
+++ b/MathToF/902.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "比例尺 \\frac{1}{20000}读作二万分之一"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "比例尺是一个比，比的读法应该是谁比谁，虽然此题比例尺和二万分之一相等，但是表示的意义不一样，所以错."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/903.json b/MathToF/903.json
new file mode 100644
index 0000000000000000000000000000000000000000..af39d65bbfade6d8f21a20dfc32dd88ec5a5748f
--- /dev/null
+++ b/MathToF/903.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小强和爸、妈一起吃了一个大西瓜，小强吃了这个西瓜的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "将单位‘1‘平均分成若干份，表示这样一份或几份的数为分数.小强和爸、妈一起吃了一个大西瓜，由于没有说明是平均分成，根据分数的意义，小强吃了这个西瓜的 \\frac{1}{3}的说法错误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/904.json b/MathToF/904.json
new file mode 100644
index 0000000000000000000000000000000000000000..e3a8d402136f40753d62ea7b47392f1b0be3d7bc
--- /dev/null
+++ b/MathToF/904.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "48里最多有5个9"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据48÷9=5…3可知48里最多有5个9。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/905.json b/MathToF/905.json
new file mode 100644
index 0000000000000000000000000000000000000000..d9f7cc27f435fb35d6385bc5ddb4bb7cda92609e
--- /dev/null
+++ b/MathToF/905.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小数除小数，商一定是小数."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "小数除小数，如果将除数小数点去掉后，除数能整除被除数，则商为整数，如:0.2÷0.05=20÷5=4;如果将除数小数点去掉后，除数不能整除被除数，则商为小数，如:0.2÷0.5=0.4."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/906.json b/MathToF/906.json
new file mode 100644
index 0000000000000000000000000000000000000000..325f4301a4fa53563959f83528ac900b8b63ed00
--- /dev/null
+++ b/MathToF/906.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2×5=10，所以10是倍数，5是因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数与倍数的意义，如果非零的自然数甲数是非零的自然数乙数的倍数，那么乙数就是甲数的因数.因数和倍数是相互依存的，不能单独存在.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/907.json b/MathToF/907.json
new file mode 100644
index 0000000000000000000000000000000000000000..cb7752a89f49784b795e546b5ce450aeb5ee99b1
--- /dev/null
+++ b/MathToF/907.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "直径为20厘米的圆的周长与两个直径为10厘米的圆的周长之和相等，直径为20厘米的圆的面积与两个直径为10厘米的圆的面积之和也相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "利用圆的周长公式，分别算出直径是20厘米的圆的周长以及两个直径是10厘米的圆的周长之和，再进行比较即可;再分别求出半径，再根据圆的面积公式S=π\\( r^{2} \\)，列出算式，分别算出这三个圆的面积，再进行比较.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/908.json b/MathToF/908.json
new file mode 100644
index 0000000000000000000000000000000000000000..b816ec1e1ee0399f2f1ed0fcc501a8a0e994ca6a
--- /dev/null
+++ b/MathToF/908.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个乘数的末尾有两个0，那么积的末尾最多有两个0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "一个乘数的末尾有两个0，那么积的末尾0的个数还可能是三个、四个…因另一个乘数的末尾也可能有0.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/909.json b/MathToF/909.json
new file mode 100644
index 0000000000000000000000000000000000000000..e25b5d4aed8a93f28285dfa56d38f748e362cbdc
--- /dev/null
+++ b/MathToF/909.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "读数和写数都应从个位起。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "整数的写法:从高位到低位，一级一级地写，哪一个数位上一个计数单位也没有，就在那个数位上写0; 整数的读法:从高位到低位，一级一级地读，每一级末尾的0都不读出来，其它数位连续几个0都只读一个零。 读数和写数都要从最高位起。原题说法错误。 故答案为:×"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/91.json b/MathToF/91.json
new file mode 100644
index 0000000000000000000000000000000000000000..1d3031a7e95b8c22c88c5605816375db1b00f7f5
--- /dev/null
+++ b/MathToF/91.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "\\frac{5}{9}×12=12× \\frac{5}{9}"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据乘法交换律:交换两个因数的位置，积不变，直接判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/910.json b/MathToF/910.json
new file mode 100644
index 0000000000000000000000000000000000000000..5a82dffbac45ccbf9256f69ee63611440b92713e
--- /dev/null
+++ b/MathToF/910.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲所在小组的平均身高是1.56米，乙所在小组的平均身高是1.48米，甲一定比乙高。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "平均数只反映了一组数据的平均大小，并不能反映具体甲乙个人的身高。故题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/911.json b/MathToF/911.json
new file mode 100644
index 0000000000000000000000000000000000000000..ace985352e7118078ad60a5af603b4ee8befd6ad
--- /dev/null
+++ b/MathToF/911.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "周长相等的长方形、正方形和圆，圆的面积最大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "长方形的周长=2(a+b)，正方形的周长=4a，圆的周长=2πr，再设它们的周长为c，推导出各边与周长的关系来利用面积公式判断大小."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/912.json b/MathToF/912.json
new file mode 100644
index 0000000000000000000000000000000000000000..44377f97e070dcf6d3ed1f3f5d2f57b9a71d03da
--- /dev/null
+++ b/MathToF/912.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "16的因数只有1、2、4、8四个数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据找一个数因数的方法，列举出16的因数，即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/913.json b/MathToF/913.json
new file mode 100644
index 0000000000000000000000000000000000000000..c59562fd30990ff63bf801302f198c09dcbbede3
--- /dev/null
+++ b/MathToF/913.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算96÷4+54×5，可以同时计算96÷4和54×5"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "96÷4+54×5是除法和乘法算式中间用加法相连，可以先同时计算除法和乘法，再算加法."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/914.json b/MathToF/914.json
new file mode 100644
index 0000000000000000000000000000000000000000..9f57b9fec1d0c3e54305961024d11346a8be56c0
--- /dev/null
+++ b/MathToF/914.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "甲数与乙数的比是5:3，乙数比甲数少40%"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "甲数与乙数的比是5:3，设甲数是5，那么乙数就是3;求出两个数的差，然后用差除以甲数即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/915.json b/MathToF/915.json
new file mode 100644
index 0000000000000000000000000000000000000000..4a93409e0f8be16b35ad59d90a5a6ffd52c5fccb
--- /dev/null
+++ b/MathToF/915.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个完全一样的正方体拼成一个长方体，拼成的长方体的表面积比原来两个正方体的表面积之和减少了"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个正方体有六个面，两个有12个面，拼成长方体后少了两个面，还剩10个面."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/916.json b/MathToF/916.json
new file mode 100644
index 0000000000000000000000000000000000000000..b916184cf9200052623633741f103a34152d8e71
--- /dev/null
+++ b/MathToF/916.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "3厘米是 \\frac{3}{10}米，也就是0.3米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "低级单位厘米化高级单位米除以进率100，根据分数与除法的关系，结果可以用分数表示，即 \\frac{3}{100}米;用小数表示是0.03米."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/917.json b/MathToF/917.json
new file mode 100644
index 0000000000000000000000000000000000000000..9abd3d5ce0cf95546419cb42475bd829f382fb68
--- /dev/null
+++ b/MathToF/917.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "梯形的面积是平行四边形的一半。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据梯形的面积的推导过程，只有平行四边形的底等于梯形的上下底之和且等高时，梯形的面积才是平行四边形面积的一半。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/918.json b/MathToF/918.json
new file mode 100644
index 0000000000000000000000000000000000000000..2cf64472c46f59b3561c83701a39dab6c55d83ea
--- /dev/null
+++ b/MathToF/918.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个数相乘，一个乘数扩大4倍，另一个乘数缩小4倍，它们的积不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个因数缩小(或扩大)若干倍，另一个因数扩大(或缩小)相同的倍数，积不变;据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/919.json b/MathToF/919.json
new file mode 100644
index 0000000000000000000000000000000000000000..c20689448618a981feec2e572bf5e7303871053c
--- /dev/null
+++ b/MathToF/919.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8960440000省略亿位后面的尾数约为89亿"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "省略亿位后面的尾数求近似数，根据千万位上数字的大小确定用‘四舍‘法、还是用‘五入‘法.8960440000，千万位上是6大于5，所以用‘五入‘法.即8960440000≈90亿."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/92.json b/MathToF/92.json
new file mode 100644
index 0000000000000000000000000000000000000000..dd47be5eb90d6b60505aa7540e608b3d603e1d2a
--- /dev/null
+++ b/MathToF/92.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "圆的直径和正方形边长相等，那么圆的周长大于正方形的周长"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据圆的周长公式C=πd、正方形的周长公式C=4a，分别求得它们的周长后比较判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/920.json b/MathToF/920.json
new file mode 100644
index 0000000000000000000000000000000000000000..e23b1879dfa1cc767447b1d5fa0766432cc898ac
--- /dev/null
+++ b/MathToF/920.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.58读作:零点五十八"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "小数的读法:整数部分按整数的读法去读，再读点，小数部分是几就读几.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/921.json b/MathToF/921.json
new file mode 100644
index 0000000000000000000000000000000000000000..52a4913958af6e850b4a570eeb1e1a73ea579a20
--- /dev/null
+++ b/MathToF/921.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "303×7得积是三位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "三位数乘一位数的积是三位数或四位数，根据整数乘法的计算法则，算出303×7的积进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/922.json b/MathToF/922.json
new file mode 100644
index 0000000000000000000000000000000000000000..a3ff9aad2bdcae72bf32fd229e13531c2f51aabb
--- /dev/null
+++ b/MathToF/922.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "120÷3=12÷3=4"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由题意可知:被除数缩小10倍，除数不变，商也缩小10倍，由此判断得出答案即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/923.json b/MathToF/923.json
new file mode 100644
index 0000000000000000000000000000000000000000..36a8a875f528ef0bfcb03077d988c7ff60db3e91
--- /dev/null
+++ b/MathToF/923.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "正方形的四条边相等，四个角都是直角"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据正方形的性质:四个角都是直角，四条边都相等;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/924.json b/MathToF/924.json
new file mode 100644
index 0000000000000000000000000000000000000000..6242c1a39de6fb0b6d017c34fd0459d136852767
--- /dev/null
+++ b/MathToF/924.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在5的后面添上‘%‘，这个数缩小100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "在5后面添上‘%‘，相当于把小数点向左移动了两位，原数就缩小100倍."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/925.json b/MathToF/925.json
new file mode 100644
index 0000000000000000000000000000000000000000..42aea8140d2595f77999c8a9073324ebe707a437
--- /dev/null
+++ b/MathToF/925.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个苹果分成5份，每份是这个苹果的 \\frac{1}{3}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把一个苹果分成5份，只有当平均分时，每份才是这个苹果的 \\frac{1}{5}."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/926.json b/MathToF/926.json
new file mode 100644
index 0000000000000000000000000000000000000000..b8a9b67212abce00e4a087f7a49e11a213d7d331
--- /dev/null
+++ b/MathToF/926.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "4300000改写成用‘万‘作单位的数是430万"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把4300000改写成用‘万‘作单位的数，把个级里4个0去掉同时在后面写上‘万‘字.据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/927.json b/MathToF/927.json
new file mode 100644
index 0000000000000000000000000000000000000000..19e6eba9affcc9606eb2aacb2f97a1ceee74b2dc
--- /dev/null
+++ b/MathToF/927.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为10÷2=5，所以，10是倍数，2和5都是因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;进行解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/928.json b/MathToF/928.json
new file mode 100644
index 0000000000000000000000000000000000000000..c7d8236f93e82599f8ccfd0a37678a12ecfd8b6f
--- /dev/null
+++ b/MathToF/928.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "任何一个梯形都可以分成两个完全一样的三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据梯形的定义可知，只有一组对边平行的四边行叫梯形，由于梯形上下底的长度不等，所以不能分成两个完全一样的三角形.由此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/929.json b/MathToF/929.json
new file mode 100644
index 0000000000000000000000000000000000000000..064bf7d55afd6de87c1173545d8689c4e5c498a6
--- /dev/null
+++ b/MathToF/929.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "除0外的任何自然数的倒数都小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "0除外的自然数分为两种:1和大于1的数，1的倒数等于1，大于1的倒数都是真分数，真分数都小于1，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/93.json b/MathToF/93.json
new file mode 100644
index 0000000000000000000000000000000000000000..be18c5d131a8268bf005884df31386d62477e006
--- /dev/null
+++ b/MathToF/93.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.15除以0.04的商是3，余数也是3"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据有余除法中被除数、除数、商与余数之间的关系可知，余数=被除数-商×除数，由此即能求出0.15÷0.04，商是3，余数是多少."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/930.json b/MathToF/930.json
new file mode 100644
index 0000000000000000000000000000000000000000..859eb820d7c27c57f1c4fb0eb113c73076939a8f
--- /dev/null
+++ b/MathToF/930.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把一个长方形的长扩大若干倍，宽缩小相同的倍数，它的面积不变."
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据长方形的面积计算公式S=ab列式解答，得出答案后进行解答即可"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/931.json b/MathToF/931.json
new file mode 100644
index 0000000000000000000000000000000000000000..b41bc72144039051412c853cb1c59ea47ba94aec
--- /dev/null
+++ b/MathToF/931.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "275与125的差乘它们的和，积是多少?列式为275-125×(275+125)"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "求积是多少，第一个因数是275减去125的差，第二个因数是275加上125的和，然后相乘即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/932.json b/MathToF/932.json
new file mode 100644
index 0000000000000000000000000000000000000000..dedb0300961469736212e0db947141b48e8d029b
--- /dev/null
+++ b/MathToF/932.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "跑步比赛，跑完5圈小李用了3分钟，小华用了4分钟，小李和小华的速度比是3:4"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把5圈的路程看作单位‘1‘，根据‘路程÷时间=速度‘分别求出小亮和小丽的速度，进而根据题意求比即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/933.json b/MathToF/933.json
new file mode 100644
index 0000000000000000000000000000000000000000..56e8112c68092e050442dfa02b125d4068242192
--- /dev/null
+++ b/MathToF/933.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个三角形的三个内角度数之比为3:2:1，这个三角形一定是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把‘一个三角形三个内角度数比是1:2:3‘理解为三个内角度数分别占三角形内角和的 \\frac{1}{1+2+3}、 \\frac{2}{1+2+3}、 \\frac{3}{1+2+3}，把三角形的内角和180°看作单位‘1‘，根据一个数乘分数意义，用乘法分别求出三个角，然后根据三角形的分类，进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/934.json b/MathToF/934.json
new file mode 100644
index 0000000000000000000000000000000000000000..4dcc3f82fc110a8ff350ff342da0bcafeb8b2ba5
--- /dev/null
+++ b/MathToF/934.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "第一个因数中间有0，积中间也一定有0，被除数中间有0，商中间也一定有0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题可用例举法证明，如106×2=212，第一个因数中间有0，积中间没有零;208÷4=52，被除数中间有0，商中间没有0."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/935.json b/MathToF/935.json
new file mode 100644
index 0000000000000000000000000000000000000000..1ec8accc0afa42c1cef798af5a06178b6192677a
--- /dev/null
+++ b/MathToF/935.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "电梯的升降是平移现象。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "平移:在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。 电梯的升降是平移现象。 故原题说法正确。 故答案为:√。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/936.json b/MathToF/936.json
new file mode 100644
index 0000000000000000000000000000000000000000..13cc1eacb059d0ac9ac73c34961d853aa0a626c0
--- /dev/null
+++ b/MathToF/936.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果一个正方形的周长是20厘米，它的边长就是10厘米。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "正方形的周长 四条边长度的和，是正方形的周长，如果周长是20厘米，它的边长要用周长除以4，所以边长为20÷4=5(厘米);据此判断即可。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/937.json b/MathToF/937.json
new file mode 100644
index 0000000000000000000000000000000000000000..2da36863313638fc75e33645a3df54375c6986ee
--- /dev/null
+++ b/MathToF/937.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "测量病人体温变化情况应选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/938.json b/MathToF/938.json
new file mode 100644
index 0000000000000000000000000000000000000000..03a445c06bbcee1b181e5fee7fe923f3899bd616
--- /dev/null
+++ b/MathToF/938.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "真分数都小于1，假分数都不小于1"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据真分数和假分数的意义，真分数的分子小于分母，假分数的分子大于或等于分母，即可得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/939.json b/MathToF/939.json
new file mode 100644
index 0000000000000000000000000000000000000000..833914aa18390a44082b98011ff8e443e01ca058
--- /dev/null
+++ b/MathToF/939.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个小数相除的商一定是小数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据小数除法的计算法则，先移动除数的小数点，使它变成整数，除数的小数点向右移动几位，被除数的小数点也向右移动相同的位数，然后按照除数是整数的除法进行计算.可以通过举例证明."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/94.json b/MathToF/94.json
new file mode 100644
index 0000000000000000000000000000000000000000..d29a3e521a2a80f6c879ac0512659f001b27a5f8
--- /dev/null
+++ b/MathToF/94.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "7克食盐溶解于m克水中，盐水的浓度是 \\frac{7}{m}%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "含盐率=盐的重量÷盐水的重量×100%，盐有7克，盐水有(7+m)克，代入公式，解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/940.json b/MathToF/940.json
new file mode 100644
index 0000000000000000000000000000000000000000..5b4a4964f05d077f971d01f9de263f08cb1ee069
--- /dev/null
+++ b/MathToF/940.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "中位数就是一组数据的平均数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "平均数和中位数是两种不相同的统计量，平均数的求法是:用所有数据相加的总和除以数据的个数;中位数的求法:将数据按照大小顺序排列，如果数据个数是奇数，则处于最中间的数就是这组数据的中位数，如果数据个数是偶数，则中间两个数的平均数就是这组数据的中位数;据此进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/941.json b/MathToF/941.json
new file mode 100644
index 0000000000000000000000000000000000000000..3b5e8e8c4d4a2645a48370ba2711bca2c6ac5d5c
--- /dev/null
+++ b/MathToF/941.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "72×16的积与16×72的积相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "72*16=1152，16*72=1152，原说法正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/942.json b/MathToF/942.json
new file mode 100644
index 0000000000000000000000000000000000000000..ff4b2b624289eedec4f6e81acf6d90886dc7d5e2
--- /dev/null
+++ b/MathToF/942.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "昨天的最低气温是-5摄氏度，今天最低气温比昨天最低气温上升了1摄氏度，今天的最低气温是-4摄氏度"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据题意，昨天的最低气温是-5摄氏度，今天最低气温比昨天最低气温上升了1摄氏度，求今天的最低气温就是求比-5摄氏度多1摄氏度是多少，用加法计算即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/943.json b/MathToF/943.json
new file mode 100644
index 0000000000000000000000000000000000000000..0300f0e7752de7517efe684467d40ea38f6ec6dd
--- /dev/null
+++ b/MathToF/943.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "19×27的个位一定是3"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "本题根据整数乘法的运算法则分析判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/944.json b/MathToF/944.json
new file mode 100644
index 0000000000000000000000000000000000000000..1744d427418efbec1b63ce4c362b0f4aaffeeed7
--- /dev/null
+++ b/MathToF/944.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最简分数的分子、分母一定都是质数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "在分数中，分子与分母只有公因数1的分数为最简分数.即只要分子与分母互质，这个分数即为最简分数，最简分数的分子、分母不一定都是质数，如 \\frac{8}{9}，分子与分母都为合数，但8与9互质， \\frac{8}{9}为最简分数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/945.json b/MathToF/945.json
new file mode 100644
index 0000000000000000000000000000000000000000..6c578c7e5ebda31f3d1445aa22f3ba173aea5ce2
--- /dev/null
+++ b/MathToF/945.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个长方体的棱长总和是24分米，相交于一个顶点的三条棱的长度和是8分米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据长方体的特征，长方体的12条棱中互相平行的一组4条棱的长度相等，长方体的棱长总和=(长+宽+高)×4，相交于一个顶点的三条棱的长度和即(长+宽+高)的值，由此用棱长总和除以4即可得到相交于一个顶点的三条棱的长度和，再判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/946.json b/MathToF/946.json
new file mode 100644
index 0000000000000000000000000000000000000000..a12b70c81c2169d72b73da3fe1af744c2005c110
--- /dev/null
+++ b/MathToF/946.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "冬冬发现自己的影子在东面，那么现在太阳在西面_"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "发现自己的影子在东面，说明是下午，太阳在西方，下午面对太阳，也就是面对西方，我们的影子就在东方，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/947.json b/MathToF/947.json
new file mode 100644
index 0000000000000000000000000000000000000000..760f252b77226f73a0601082d3121e08e4774f14
--- /dev/null
+++ b/MathToF/947.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "85乘23与77的和，积是多少?正确列式是:85×23+77()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            ""
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/948.json b/MathToF/948.json
new file mode 100644
index 0000000000000000000000000000000000000000..771f17abf073c641698e8c829cb5d97c0abd2cbc
--- /dev/null
+++ b/MathToF/948.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "判断。 周长相等的长方形和正方形，它们的面积相等。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为两个数的和为定值，只有两个数相同时他们的积最大，所以正方形的面积要大于长方形。因此当长方形正方形周长相等的这时候，正方形的面积最大。故题干描述错误。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/949.json b/MathToF/949.json
new file mode 100644
index 0000000000000000000000000000000000000000..829b71d04bb0b25e30389276ffa3306a89e7ed7c
--- /dev/null
+++ b/MathToF/949.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在一张长10厘米、宽8厘米的长方形纸上画一个最大的圆，这个圆的半径是5厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "长方形中最大圆的直径应等于长方形的宽，长方形的宽已知，于是可以求出圆的半径."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/95.json b/MathToF/95.json
new file mode 100644
index 0000000000000000000000000000000000000000..b233e798412a213706593999591ac888270e781e
--- /dev/null
+++ b/MathToF/95.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小刚做一篇数学题，做对了20道，做错了2道，错误率是10%"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先用‘20+2‘求出全班总人数，进而根据‘错误率= \\frac{做错的题目的个数}{总个数}×100%;代入数值，解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/950.json b/MathToF/950.json
new file mode 100644
index 0000000000000000000000000000000000000000..f9ce17c396a526595c8786449c20bb53a0151b0c
--- /dev/null
+++ b/MathToF/950.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "5个7相加的和是多少?算式为:5+7=12"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "5个7相加的和是多少?算式为:5+7=12，这句话是错误的。求几个几相加是多少这样的题应该用乘法计算。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/951.json b/MathToF/951.json
new file mode 100644
index 0000000000000000000000000000000000000000..66fd228f5f421a276e06c50dd3572d91f7bcc1a9
--- /dev/null
+++ b/MathToF/951.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "分数的分子、分母同时乘任意数，分数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "分数的性质是:分数的分子和分母同时加上、减去、乘上或除以一个相同的数(0除外)，分数的大小不变;据此进行判断得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/952.json b/MathToF/952.json
new file mode 100644
index 0000000000000000000000000000000000000000..fe4ef560f72a62619563999f89b8e491f7fc83d2
--- /dev/null
+++ b/MathToF/952.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "若要反映陆良县上半年各月月平均温度变化情况应选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/953.json b/MathToF/953.json
new file mode 100644
index 0000000000000000000000000000000000000000..8e0fcb04ae24987b879f637e212ec4d3976fdd6e
--- /dev/null
+++ b/MathToF/953.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "求一个数是另一个数的几倍用乘法计算"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "要求一个数是另一个数的几倍，也就是求一个数里包含几个另一个数，用除法进行解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/954.json b/MathToF/954.json
new file mode 100644
index 0000000000000000000000000000000000000000..c84f1d1f6cdbaea53fb3eb51f64dd54ab1c02de0
--- /dev/null
+++ b/MathToF/954.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "406×7的积是三位数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "此题可以用估算的方法解答，把406看作400，因为400×7=2800，所以406×7的积一定是四位数."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/955.json b/MathToF/955.json
new file mode 100644
index 0000000000000000000000000000000000000000..09be32ff77723d21bd88261527756948b53c5643
--- /dev/null
+++ b/MathToF/955.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个袋中有2个红球，3个白球，要使口袋里摸到红球的可能性是1/4，口袋里可以再放1个红球和6个白球"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据可能性的求法:即求一个数是另一个数的几分之几用除法解答，然后解答进行比较即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/956.json b/MathToF/956.json
new file mode 100644
index 0000000000000000000000000000000000000000..1a60ed237d67349caaaa55c8aa15ab9ac802d193
--- /dev/null
+++ b/MathToF/956.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为2×5=10，所以5是因数，10是倍数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据因数和倍数的意义:如果数a能被数b整除(b≠0)，a就叫做b的倍数，b就叫做a的因数;据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/957.json b/MathToF/957.json
new file mode 100644
index 0000000000000000000000000000000000000000..90ebd2a88c1088821c93d04274caf47776b126cd
--- /dev/null
+++ b/MathToF/957.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个连续自然数的积一定是合数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "当两个连续自然数分别是1和2时，它们的积是2，但2是质数，而不是合数;据此判断得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/958.json b/MathToF/958.json
new file mode 100644
index 0000000000000000000000000000000000000000..98ca8f6fbca30b0c1a2781b164f39247a79a9b06
--- /dev/null
+++ b/MathToF/958.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果x=8÷y，那么x与y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "依据反比例的意义可知:若两个相关联量的乘积一定，则这两个两成反比例，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/959.json b/MathToF/959.json
new file mode 100644
index 0000000000000000000000000000000000000000..02d6a6ceea42dda66c57fc8b170641a62f6e662f
--- /dev/null
+++ b/MathToF/959.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "34×58+34×42=(58+42)×34=100×34=3400"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "由于58+42=100，根据乘法分配律可知，34×58+34×42可按乘法分配律计算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/96.json b/MathToF/96.json
new file mode 100644
index 0000000000000000000000000000000000000000..5dc6bf1f7a76f9d9b88f2efe6f6ee9ecd55e1b89
--- /dev/null
+++ b/MathToF/96.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "五(1)班和五(2)班的女生都占本班人数的 \\frac{4}{7}，所以这两个班的女生人数相等"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据‘两个班的女生人本班人数的 \\frac{4}{7}‘，知分别把两个的人数看做单位‘1‘，虽然分率相等，但不能确定两个班的女生人数相等;据此进行判."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/960.json b/MathToF/960.json
new file mode 100644
index 0000000000000000000000000000000000000000..132b18ef14026c1cd7817b3dec92085f9f41c155
--- /dev/null
+++ b/MathToF/960.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "2.73去掉小数点后所得的数是原数的100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "2.73去掉小数点后是273，也就是小数点向右移动了两位，根据小数点位置移动引起数的大小变化规律，所以这个数就扩大100倍;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/961.json b/MathToF/961.json
new file mode 100644
index 0000000000000000000000000000000000000000..d1f7039f2b6d8e5ba62f070b9fe300f9413e4add
--- /dev/null
+++ b/MathToF/961.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "去掉0.01的小数点，所得到的数是原数的100倍"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据小数点位置移动引起数的大小变化规律可知:去掉0.01的小数点，相当于把0.01的小数点向右移动了两位，所得到的数是原数的100倍;由此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/962.json b/MathToF/962.json
new file mode 100644
index 0000000000000000000000000000000000000000..cead88ea6c4064247b827d90a411636c1c8fda29
--- /dev/null
+++ b/MathToF/962.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个圆柱体和一个圆锥体的底面积比是2:3，高的比是7:5，则圆锥与圆柱的体积比是14:5"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据圆柱的体积公式V=sh，圆锥的体积公式V= \\frac{1}{3}sh，得出圆锥与圆柱的体积比= \\frac{1}{3}圆锥与圆柱的面积比×圆锥与圆柱的高的比，由此得出答案."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/963.json b/MathToF/963.json
new file mode 100644
index 0000000000000000000000000000000000000000..5e623219798d915f3b8d0b2ebdfd09b342a844ce
--- /dev/null
+++ b/MathToF/963.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一根绳子长6米，第一次用去 \\frac{1}{3}，第二次用去 \\frac{1}{3}米;还剩 3 \\frac{2}{3}米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "把绳子长度看作单位‘1‘，先依据分数乘法意义，求出第一次用去长度，再根据剩余长度=总长度-第一次用去长度-第二次用去长度，求出剩余长度，最后与3 \\frac{2}{3}米比较即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/964.json b/MathToF/964.json
new file mode 100644
index 0000000000000000000000000000000000000000..26635783fb49f0ecb8323d043161ef6125efa6fc
--- /dev/null
+++ b/MathToF/964.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个苹果重200千克"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据生活经验、对质量单位和数据大小的认识，可知计量一个苹果质量，应用质量单位，结合数据可知:应用‘克‘做单位;据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/965.json b/MathToF/965.json
new file mode 100644
index 0000000000000000000000000000000000000000..6c40cdc163b9857838d5a3a2a22d1eca45172546
--- /dev/null
+++ b/MathToF/965.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "汽车行驶时，车轮的运动属于旋转，车身的运动属于平移"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心.所以，它并不一定是绕某个轴的;然后 根据平移与旋转定义判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/966.json b/MathToF/966.json
new file mode 100644
index 0000000000000000000000000000000000000000..49d56367bd13d6609602b85c34d7760aed7670ca
--- /dev/null
+++ b/MathToF/966.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "0.001扩大到原数的100倍是0.1"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "0.001扩大到原数的100倍，即0.001的小数点向右移动两位，为0.1;据此判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/967.json b/MathToF/967.json
new file mode 100644
index 0000000000000000000000000000000000000000..f347e5885a052dfe9776304a9c37d4094067a329
--- /dev/null
+++ b/MathToF/967.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "704÷6商的最高位是百位，而且中间没有0。()"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "704÷6=117...2，最高位是百位，中间没有0，所以原说法正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/968.json b/MathToF/968.json
new file mode 100644
index 0000000000000000000000000000000000000000..16a4342d68f1985a3e060203132fe2a0a3351e27
--- /dev/null
+++ b/MathToF/968.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要清楚看出滁州市近十年来国民生产总值的增长变化情况，最好选用条形统计图"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/969.json b/MathToF/969.json
new file mode 100644
index 0000000000000000000000000000000000000000..f465d192d14b2e1664c3d1e2ed3bd4198be190f4
--- /dev/null
+++ b/MathToF/969.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果一个三角形的三个内角的度数比是4:5:9，这个三角形是直角三角形"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "由题意可得:三角形中最大的角占内角和的 \\frac{9}{4+5+9}，把三角形的内角和180°看作单位‘1‘，根据一个数乘分数意义，用乘法分别求出最大的角，然后根据三角形的分类，进行判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/97.json b/MathToF/97.json
new file mode 100644
index 0000000000000000000000000000000000000000..6be1045680802e7e290ebfd033e57ae201d0ad0d
--- /dev/null
+++ b/MathToF/97.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "兰兰看一本书，第一天看了10页，第二天看了20页，第三天应该从第30页看起"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "先求出看的页数，再看时的页数应从已看页数加1页始看起.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/970.json b/MathToF/970.json
new file mode 100644
index 0000000000000000000000000000000000000000..44adddc515e76d8a01a23747bca955ed1857dc37
--- /dev/null
+++ b/MathToF/970.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "某一天测得哈尔滨的最低气温是-10摄氏度，苏州的最低气温是5摄氏度，那么这一天这两个城市的最低气温相差了15摄氏度"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "这是一道有关温度的正负数的运算题目，要想求-10摄氏度比5摄氏度低多少摄氏度，即求二者之差."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/971.json b/MathToF/971.json
new file mode 100644
index 0000000000000000000000000000000000000000..09c1fa9f8aee69fedb7dc3857776fe38b9829c86
--- /dev/null
+++ b/MathToF/971.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "要反映数量的增减变化情况，用扇形统计图比较合适"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "条形统计图能很容易看出数量的多少;折线统计图不仅容易看出数量的多少，而且能反映数量的增减变化情况;扇形统计图能反映部分与整体的关系;由此根据情况选择即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/972.json b/MathToF/972.json
new file mode 100644
index 0000000000000000000000000000000000000000..3e87ac24ff7154f181e2665c6fed8200132a0aaf
--- /dev/null
+++ b/MathToF/972.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "1除以任何数都得任何数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "1是被除数，所以举一个1除以2的反例即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/973.json b/MathToF/973.json
new file mode 100644
index 0000000000000000000000000000000000000000..b2fce4037066364a9964754974ed2230e5c4b745
--- /dev/null
+++ b/MathToF/973.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "在计算7200÷90时，把被除数和除数末尾的0都去掉，商不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "商不变的性质:在除法里，被除数和除数同时扩大或缩小相同的倍数(0除外)，商不变;据此解答"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/974.json b/MathToF/974.json
new file mode 100644
index 0000000000000000000000000000000000000000..e6359bd74282629438cd0c09acc8b817689f5180
--- /dev/null
+++ b/MathToF/974.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一扇门高2米"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据生活经验、对长度单位和数据大小的认识，可知计量一扇门高2用‘米‘做单位;据此得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/975.json b/MathToF/975.json
new file mode 100644
index 0000000000000000000000000000000000000000..92c7eb780af9cf9e3c3064eac0abd00d3ad986f0
--- /dev/null
+++ b/MathToF/975.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为12÷3=4，所以12是倍数，3是因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "由因数和倍数的意义可知，当a÷b=c(a、b、c为非0自然数)，我们说a是b的倍数，b是a的因数.由此可见，因数和倍数是相互依存的，不是单独说哪个数是因数，哪个数是倍数.所以本题不能说12是倍数，3是因数.由此可求解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/976.json b/MathToF/976.json
new file mode 100644
index 0000000000000000000000000000000000000000..1c64826f24853b11e2ac65c1c6cad09df2c7b741
--- /dev/null
+++ b/MathToF/976.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "两个两个地数，10后面的一个数是11。"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:[错因]:1读题不够仔细， [正确答案]:12(√) 点评:"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/977.json b/MathToF/977.json
new file mode 100644
index 0000000000000000000000000000000000000000..20948b8e03dbf1427f6cffaa301f324182f3b6b5
--- /dev/null
+++ b/MathToF/977.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "每相邻两个质量单位之间的进率是1000"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "常用的质量单位有吨、千克、克，相邻两个单位间的进率是1000，即1吨=1000千克，1千克=1000克."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/978.json b/MathToF/978.json
new file mode 100644
index 0000000000000000000000000000000000000000..bfe60e16673c0ebb8bc93a74af4d619a4a1ee55c
--- /dev/null
+++ b/MathToF/978.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "37是37的倍数，37是37的因数"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "一个数的因数是有限的，其中最大的因数是它本身，一个数的倍数的个数是无限的，其中最小的倍数是它本身，据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/979.json b/MathToF/979.json
new file mode 100644
index 0000000000000000000000000000000000000000..cd50eafb730bbccc98d814c64ede2975e913f62d
--- /dev/null
+++ b/MathToF/979.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "小亚家住在5楼，从1楼到2楼要走16级台阶(相邻楼层之间的台阶数相同)，小亚回家要走64级台阶。…()"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "从1楼到5楼要走5-1=4层楼梯，每层楼梯有16个台阶，所以16*4=64级台阶，说法正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/98.json b/MathToF/98.json
new file mode 100644
index 0000000000000000000000000000000000000000..b5255f5950845fb683fc95541be20e314c6a5799
--- /dev/null
+++ b/MathToF/98.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果乘数的中间有0，那么积的中间不一定有0。"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "101×5=505，505中间有1个0; 205×3=615，615中间没有0; 所以因数的中间有0，积的中间可能有0，也可能没有0。 故此题正确。"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/980.json b/MathToF/980.json
new file mode 100644
index 0000000000000000000000000000000000000000..3dade8e155aa1aa8a745bf26b95ebdf1e9631288
--- /dev/null
+++ b/MathToF/980.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "54×80与540×8的计算结果相同"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据积的变化规律:两数相乘，一个因数扩大若干倍(0除外)，另一个因数缩小相同的倍数，积不变."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/981.json b/MathToF/981.json
new file mode 100644
index 0000000000000000000000000000000000000000..95fd7a587ff728116470bd9bb1ec21d35b929545
--- /dev/null
+++ b/MathToF/981.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "8个形状大小相同的球，其中一个比较轻，用天平称，至少称3次才能保证找到这个较轻的球"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "8个球分成3、3、2，进行天平称量，先把是3个球的两组放在天平上称量，1如果平衡，较轻的球就在2个球的那组，然后把2个球放在天平上，找出较轻的;如果不平衡，找出较轻的一组，2然后拿出较轻组其中的两个进行称量，如果平衡，剩下的一个就是较轻的球，如果不平衡，位置较高的一个就是较轻的球."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/982.json b/MathToF/982.json
new file mode 100644
index 0000000000000000000000000000000000000000..04e3478f469ab9fc8c046408126634037ec73fc8
--- /dev/null
+++ b/MathToF/982.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个小数的小数点先向右移动两位，再向左移动两位，小数的大小不变"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据小数点位置移动引起数的大小变化规律可知:一个小数的小数点先向右移动两位再向左移动两位，相当于把这个小数的小数点没有移动，所以小数的大小不变."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/983.json b/MathToF/983.json
new file mode 100644
index 0000000000000000000000000000000000000000..2235ff1f9d6e5fe4ff1668feedcb2898474b1d1c
--- /dev/null
+++ b/MathToF/983.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为6×5=30，所以60×5=300"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "先判断出因数是怎样变化的，再根据因数的变化，找出积的变化，进而得解."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/984.json b/MathToF/984.json
new file mode 100644
index 0000000000000000000000000000000000000000..508d1d4a3e331f41616e65ee013540786214f0d7
--- /dev/null
+++ b/MathToF/984.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "100米跑比赛，小明用了16.7秒，小华用了17.2秒，小明跑的快"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "本题为时间的比较，用的时间越少说明跑的越快;比较两个小数的大小，先看它们的整数部分，整数大的那个数就大;如果整数部分相同，十分位大的那个数就大.如果十分位上的那个数也相同，百分位上的数大的那个数就大，依此类推."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/985.json b/MathToF/985.json
new file mode 100644
index 0000000000000000000000000000000000000000..831a4f1e02cec1271a05331ded8d4d7407e944cf
--- /dev/null
+++ b/MathToF/985.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "比较两个自然数的大小，位数多的数比较大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据整数比较大小的方法:比较两个整数的大小，要看它们的位数，位数多的数就大，如果位数相同，相同数位上的数大的那个数就大."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/986.json b/MathToF/986.json
new file mode 100644
index 0000000000000000000000000000000000000000..a3b79cf53e764937127137d3c5ea8c416690bbbb
--- /dev/null
+++ b/MathToF/986.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "( \\frac{13}{11}+ \\frac{7}{9})-( \\frac{13}{11}- \\frac{7}{9})=( \\frac{13}{11}- \\frac{13}{11})-( \\frac{7}{9}- \\frac{7}{9})"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据分数四则混合运算的顺序，先去括号再进行计算."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/987.json b/MathToF/987.json
new file mode 100644
index 0000000000000000000000000000000000000000..244632c2580181c9002e9fb6e1f16a65a10f24a6
--- /dev/null
+++ b/MathToF/987.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "因为 \\frac{x}{3}= \\frac{y}{4}，所以x和y成正比例"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "依据正比例的意义，即若两个相关联量的比值一定，则这两个量成正比例，据此即可进行判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/988.json b/MathToF/988.json
new file mode 100644
index 0000000000000000000000000000000000000000..9fc9149faef3f58e935a548acb466379677d3a6b
--- /dev/null
+++ b/MathToF/988.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "2个棱长1厘米的正方体拼成一个长方体，长方体的表面积是12平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "试题分析:2个棱长1厘米的正方体拼成一个长方体后，表面积减少了2个小正方体的面的面积，则拼组后的长方体的表面积就是12-2=10个小正方体的面的面积，由此计算出长方体的表面积即可判断. 解:(6×2-2)×1×1， =10×1， =10(平方厘米); 答长方体的表面积是10平方厘米，所以原题说法错误. 故答案为:×. [点评]抓住拼组方法，得出表面积减少情况，计算出拼组后的表面积即可判断正误."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/989.json b/MathToF/989.json
new file mode 100644
index 0000000000000000000000000000000000000000..42d1ef34c6ee5918d7b67e36289bb26c923b9b88
--- /dev/null
+++ b/MathToF/989.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "明明家在丽丽家的东南面，丽丽家在明明家的西南面"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据方向的相对性，东南和西北相对，据此分析解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/99.json b/MathToF/99.json
new file mode 100644
index 0000000000000000000000000000000000000000..2a2d748826c14972954a8d078e4bf98b93426058
--- /dev/null
+++ b/MathToF/99.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "最小的质数的倒数比最小的合数的倒数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "根据倒数的意义:乘积是1的两个数互为倒数.最小的质数是2，最小的合数是4，求一个大于1的自然数的倒数，用1除以这个数即可.据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/990.json b/MathToF/990.json
new file mode 100644
index 0000000000000000000000000000000000000000..21c3a58b89336b6c3e6599cccab9c70b63fc6d4a
--- /dev/null
+++ b/MathToF/990.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "把三个棱长为1厘米的正方体木块拼成一个长方体，这个长方体的表面积比三个正方体的表面积之和减少了3平方厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "3个小正方体拼成一个长方体只有一种拼组方法:一字排列法，拼组后长方体的表面积比原来减少了4个小正方体的面的面积，据此即可解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/991.json b/MathToF/991.json
new file mode 100644
index 0000000000000000000000000000000000000000..782e1e03f5a12bd08e26c00e526be8ee9b191dc4
--- /dev/null
+++ b/MathToF/991.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "一个苹果分给2个小朋友，每人分得这个苹果的 \\frac{1}{2}"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "因为不是平均分的，所以无法知道分得几分之几，据此判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/992.json b/MathToF/992.json
new file mode 100644
index 0000000000000000000000000000000000000000..56a27a8784d42ce2f2466b72c1f29823f865421e
--- /dev/null
+++ b/MathToF/992.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "如果一个正方形的周长是40厘米，它的边长就是20厘米"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "根据正方形的边长=正方形的周长÷4计算并判断即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/993.json b/MathToF/993.json
new file mode 100644
index 0000000000000000000000000000000000000000..98530cc97964eff506aa183e748d61f02d90f7c4
--- /dev/null
+++ b/MathToF/993.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "几成就是百分之几百"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "几成就是十分之几，即百分之几十，据此解答即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/994.json b/MathToF/994.json
new file mode 100644
index 0000000000000000000000000000000000000000..99f38af51dde9bc73e4af55220a946b10cda46d7
--- /dev/null
+++ b/MathToF/994.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "白球有6个，红球有4个，任意摸一个，摸出白球的可能性小"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "有6个白球，4个红球，每个球被摸到的机会相等，所以不需要计算即可解答，因为6>4，所以从袋子里摸一个球，摸到白球的可能性大，摸到红球的可能性小;据此解答."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/995.json b/MathToF/995.json
new file mode 100644
index 0000000000000000000000000000000000000000..8a99846bc294ddf405cba40221f006c08c8eb438
--- /dev/null
+++ b/MathToF/995.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "9.6-9.6×0.1 =0×0.1 =0"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "[解答]解:9.6-9.6×0.1  =9.6-0.96 =8.64"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/996.json b/MathToF/996.json
new file mode 100644
index 0000000000000000000000000000000000000000..578c2240d188e0bd11b901bd45bc7d37a0dc8b83
--- /dev/null
+++ b/MathToF/996.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "判断对错. 无限小数比有限小数大."
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "[解答]解:无限小数，例如0.45547855…，有限小数，如1.9678; 0.45547855…<1.9678; 故答案为:错误. [分析]首先明确无限小数和有限小数的意义:小数部分的位数是有限的小数，叫做有限小数.像如1.9678是一个有限小数;小数部分的位数是无限的小数叫做无限小数;例如0.45547855…就是一个无限小数;进而举例进行分析即可."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/997.json b/MathToF/997.json
new file mode 100644
index 0000000000000000000000000000000000000000..378d777ffc96995542de69feb196175ef6002fce
--- /dev/null
+++ b/MathToF/997.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "循环小数都是无限小数，无限小数比有限小数大"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "本题考查的学生对无限小数概念的掌握情况，无限小数包括循环小数和无限不循环小数，无限小数不一定都比有限小数大，如:2.4>1.666…;由此即可判断."
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/998.json b/MathToF/998.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c50821808f7fc2370d4ab6c19d85e0a88d3df6c
--- /dev/null
+++ b/MathToF/998.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "a和 b的最大公因数是1，那么这两个数的最小公倍数是 ab"
+    },
+    "quest_ref": {
+        "texts": [
+            "True"
+        ],
+        "analyses": [
+            "a和 b的最大公因数是1，说明这两个数是互质数，而两个互质数的最小公倍数是它们的乘积，所以原题的这种说法是正确的 故答案为:正确"
+        ]
+    }
+}
\ No newline at end of file
diff --git a/MathToF/999.json b/MathToF/999.json
new file mode 100644
index 0000000000000000000000000000000000000000..ba8d80f761c7d2d6dd50f99f246589219a5fb3c0
--- /dev/null
+++ b/MathToF/999.json
@@ -0,0 +1,14 @@
+{
+    "qtype": "JUDGE",
+    "quest_stem": {
+        "text": "计算25×5×75×5时，可以依据乘法分配律简算，写成(25+75)×5.()"
+    },
+    "quest_ref": {
+        "texts": [
+            "False"
+        ],
+        "analyses": [
+            "把算式25×5×75×5连乘的形式，而(25+75)×5，是运用乘法的分配律写成25×5+75×5，再比较即可"
+        ]
+    }
+}
\ No newline at end of file